user: 这段汇编代码用C语言表示是什么样的:

```asm
<dijkstra>:
  endbr64
  push   %r13
  push   %r12
  mov    $0x9,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  movdqa D14(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movslq %esi,%rax
  movl   $0x1e240,0x20(%rsp)
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  lea    0x30(%rsp),%r13
  movaps %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movl   $0x0,(%rsp,%rax,4)
  movl   $0x0,0x50(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  nopl   0x0(%rax,%rax,1)
L184:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <minIndex@plt>
  cltq
  movl   $0x1,0x30(%rsp,%rax,4)
  mov    0x30(%rsp),%edx
  test   %edx,%edx
  jne    L96
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%ecx
  mov    0x0(%rbp,%rdx,4),%edx
  add    %edx,%ecx
  cmp    %ecx,(%rsp)
  jle    L96
  test   %edx,%edx
  je     L96
  mov    %ecx,(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L96:
  mov    0x34(%rsp),%r11d
  test   %r11d,%r11d
  jne    L130
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%ecx
  mov    0x4(%rbp,%rdx,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0x4(%rsp)
  jle    L130
  test   %edx,%edx
  je     L130
  mov    %ecx,0x4(%rsp)
  nopl   (%rax)
L130:
  mov    0x38(%rsp),%r10d
  test   %r10d,%r10d
  jne    L292
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%ecx
  mov    0x8(%rbp,%rdx,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0x8(%rsp)
  jle    L292
  test   %edx,%edx
  je     L292
  mov    %ecx,0x8(%rsp)
  nopl   (%rax)
L292:
  mov    0x3c(%rsp),%r9d
  test   %r9d,%r9d
  jne    L254
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%ecx
  mov    0xc(%rbp,%rdx,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0xc(%rsp)
  jle    L254
  test   %edx,%edx
  je     L254
  mov    %ecx,0xc(%rsp)
  nopl   (%rax)
L254:
  mov    0x40(%rsp),%r8d
  test   %r8d,%r8d
  jne    L72
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%ecx
  mov    0x10(%rbp,%rdx,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0x10(%rsp)
  jle    L72
  test   %edx,%edx
  je     L72
  mov    %ecx,0x10(%rsp)
  nopl   (%rax)
L72:
  mov    0x44(%rsp),%edi
  test   %edi,%edi
  jne    L86
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%ecx
  mov    0x14(%rbp,%rdx,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0x14(%rsp)
  jle    L86
  test   %edx,%edx
  je     L86
  mov    %ecx,0x14(%rsp)
  nopl   0x0(%rax,%rax,1)
L86:
  mov    0x48(%rsp),%esi
  test   %esi,%esi
  jne    L126
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%ecx
  mov    0x18(%rbp,%rdx,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0x18(%rsp)
  jle    L126
  test   %edx,%edx
  je     L126
  mov    %ecx,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L126:
  mov    0x4c(%rsp),%ecx
  test   %ecx,%ecx
  jne    L206
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%ecx
  mov    0x1c(%rbp,%rdx,4),%edx
  add    %edx,%ecx
  cmp    %ecx,0x1c(%rsp)
  jle    L206
  test   %edx,%edx
  je     L206
  mov    %ecx,0x1c(%rsp)
  nopl   0x0(%rax,%rax,1)
L206:
  mov    0x50(%rsp),%edx
  test   %edx,%edx
  jne    L56
  lea    (%rax,%rax,8),%rdx
  mov    (%rsp,%rax,4),%esi
  mov    0x20(%rbp,%rdx,4),%edx
  add    %edx,%esi
  cmp    %esi,0x20(%rsp)
  jle    L56
  test   %edx,%edx
  je     L56
  mov    %esi,0x20(%rsp)
  nopl   0x0(%rax,%rax,1)
L56:
  sub    $0x1,%r12d
  jne    L184
  lea    0x24(%rsp),%r12
  lea    D0(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L150
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L150:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: byte[16]
name: read_data
arguments: data_label: D0
data_type: string

tool: {"D14": [0x40,0xe2,0x01,0x00,0x40,0xe2,0x01,0x00,0x40,0xe2,0x01,0x00,0x40,0xe2,0x01,0x00]}

tool: D0: %d,

assistant: ```c
void dijkstra(int graph[9][9], int src) {
  int dist[9];
  for (int i = 0; i < 9; i++) {
    dist[i] = 123456;
  }
  dist[src] = 0;
  int spt[9] = {0};
  for (int i = 0; i < 9; i++) {
    int u = minIndex(dist, spt);
    spt[u] = 1;
    for (int j = 0; j < 9; j++) {
      if (!spt[j] && dist[j] > (dist[u] + graph[u][j]) && graph[u][j]) {
        dist[j] = dist[u] + graph[u][j];
      }
    }
  }
  for (int i = 0; i < 9; i++) {
    printf("%d,", dist[i]);
  }
  printf("\n");
}
```