user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L25:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L25
  sub    $0xed8,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x4ec8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  movl   $0x0,0x1c(%rsp)
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  je     L80
  lea    0x20(%rsp),%rax
  lea    0x90(%rsp),%rbp
  mov    %rax,0x8(%rsp)
  lea    D3(%rip),%r15
  lea    0x27b0(%rsp),%rbx
  lea    D16(%rip),%r13
  nopl   (%rax)
L98:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <scanf@plt>
  mov    %r15,%rdi
  mov    %rbx,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  mov    $0xd,%ecx
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  jmp    L81
  cs nopw 0x0(%rax,%rax,1)
L66:
  movsbl 0x0(%rbp,%r12,1),%eax
  add    $0x1,%r12
  sub    $0x61,%eax
  cltq
  addl   $0x1,0x20(%rsp,%rax,4)
L81:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jg     L66
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  jmp    L1
  nopl   0x0(%rax)
L38:
  sub    $0x1,%ecx
  mov    %ecx,0x20(%rsp,%rax,4)
L85:
  add    $0x1,%r14
L1:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jle    L78
  movsbl (%rbx,%r14,1),%eax
  sub    $0x61,%eax
  cltq
  mov    0x20(%rsp,%rax,4),%ecx
  test   %ecx,%ecx
  jg     L38
  add    $0x1,%r12d
  jmp    L85
L78:
  movdqa 0x20(%rsp),%xmm0
  paddd  0x30(%rsp),%xmm0
  mov    %r13,%rdi
  paddd  0x40(%rsp),%xmm0
  paddd  0x50(%rsp),%xmm0
  paddd  0x60(%rsp),%xmm0
  paddd  0x70(%rsp),%xmm0
  mov    0x80(%rsp),%edx
  mov    0x84(%rsp),%eax
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  add    %edx,%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  add    %r12d,%esi
  add    %eax,%esi
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  jne    L98
L80:
  mov    0x4ec8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x4ed8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D22
datatype: string
name: disassemble_data
arguments: tag: D3
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string

tool: D22: %d

tool: D3: %s

tool: D16: %d


assistant: ```c
int main() {
  int testcase = 0;
  scanf("%d", &testcase);
  while (testcase--) {
    int i = 0;
    int count = 0;
    char word[10001];
    char word1[10001];
    int hashtable[26] = {0};
    scanf("%s", word);
    scanf("%s", word1);
    for (i = 0; i < 26; i++)
      hashtable[i] = 0;
    for (i = 0; i < strlen(word); i++) {
      int temp = (int)word[i] - 97;
      hashtable[temp]++;
    }
    for (i = 0; i < strlen(word1); i++) {
      int temp = (int)word1[i] - 97;
      if (hashtable[temp] > 0)
        hashtable[temp]--;
      else
        count++;
    }
    for (i = 0; i < 26; i++) {
      count = count + hashtable[i];
    }
    printf("%d\n", count);
  }
}
```