ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  lea    D28(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    %esi,%edx
  mov    %esi,%eax
  and    $0x1,%edx
  sar    %eax
  lea    0x1(%rdx,%rax,1),%ebp
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x2,%ebp
  jg     L22
  jmp    L36
  nop
L80:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L36
L22:
  mov    0x4(%rsp),%ecx
  lea    -0x1(%rbx,%rbx,1),%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L44
  cmp    %ebx,%edx
  je     L44
L84:
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L80
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L22
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L44:
  lea    -0x1(%rbx),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  jmp    L84
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D23
data_type: string
name: unpack_data
arguments: data_tag: D28
data_type: string
name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D23: %d

tool: D28: %d,%d


tool: D3: %d:


assistant: ```c
int main() {
  int s;
  scanf("%d", &s);
  int top = (s >> 1) + ((s & 1) ? 2 : 1);
  printf("%d:\n", s);
  for (int i = 2; i < top; i++) {
    int rem = s % ((i << 1) - 1);
    if (rem == 0 || rem == i)
      printf("%d,%d\n", i, i - 1);
    if (s % i == 0)
      printf("%d,%d\n", i, i);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  lea    D24(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  mov    %esi,%edx
  mov    %esi,%eax
  and    $0x1,%edx
  sar    %eax
  lea    0x1(%rdx,%rax,1),%ebp
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x2,%ebp
  jg     L28
  jmp    L88
  nop
L79:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L88
L28:
  mov    0x4(%rsp),%ecx
  lea    -0x1(%rbx,%rbx,1),%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L70
  cmp    %ebx,%edx
  je     L70
L64:
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L79
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L28
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L70:
  lea    -0x1(%rbx),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  jmp    L64
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D24
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string

tool: D0: %d

tool: D24: %d,%d


tool: D4: %d:


assistant: ```c
int main() {
  int s;
  scanf("%d", &s);
  int top = (s >> 1) + ((s & 1) ? 2 : 1);
  printf("%d:\n", s);
  for (int i = 2; i < top; i++) {
    int rem = s % ((i << 1) - 1);
    if (rem == 0 || rem == i)
      printf("%d,%d\n", i, i - 1);
    if (s % i == 0)
      printf("%d,%d\n", i, i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<grab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <_grab>
```

assistant: ```c
void grab() {
  asm volatile("callq _grab\n\t"
               "_grab:\n\t" ::
                   :);
}
```
user: What is the c source code of the assembly code below?

```asm
<grab>:
  endbr64
  call   <_grab>
```

assistant: ```c
void grab() {
  asm volatile("callq _grab\n\t"
               "_grab:\n\t" ::
                   :);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<grab>:
  endbr64
  call   <_grab>
```

assistant: ```c
void grab() {
  asm volatile("callq _grab\n\t"
               "_grab:\n\t" ::
                   :);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<grab>:
  endbr64
  call   <_grab>
```

assistant: ```c
void grab() {
  asm volatile("callq _grab\n\t"
               "_grab:\n\t" ::
                   :);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hsearch_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L35:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbq %al,%rax
  xor    %rax,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  cmp    $0x20,%rax
  ja     L11
  mov    $0x1000193,%edi
  call   <UINT32_C@plt>
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L11:
  mov    $0x1b3,%edi
  call   <UINT64_C@plt>
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
L17:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t hsearch_hash(size_t offset_basis, const char *str) {
  size_t hash;
  hash = offset_basis;
  while (*str != '\0') {
    hash ^= (uint8_t)*str++;
    if (sizeof(size_t) * CHAR_BIT <= 32)
      hash *= UINT32_C(16777619);
    else
      hash *= UINT64_C(1099511628211);
  }
  return (hash);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hsearch_hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L7
  mov    %rsi,%rbp
  mov    D6(%rip),%r12
  jmp    L21
L2:
  mov    $0x1b3,%edi
  call   <UINT64_C@plt>
  imul   %rax,%rbx
L15:
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L7
L21:
  add    $0x1,%rbp
  movsbq %dl,%rdx
  xor    %rdx,%rbx
  movslq (%r12),%rax
  shl    $0x3,%rax
  cmp    $0x20,%rax
  ja     L2
  mov    $0x1000193,%edi
  call   <UINT32_C@plt>
  imul   %rax,%rbx
  jmp    L15
L7:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t hsearch_hash(size_t offset_basis, const char *str) {
  size_t hash;
  hash = offset_basis;
  while (*str != '\0') {
    hash ^= (uint8_t)*str++;
    if (sizeof(size_t) * CHAR_BIT <= 32)
      hash *= UINT32_C(16777619);
    else
      hash *= UINT64_C(1099511628211);
  }
  return (hash);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hsearch_hash>:
  endbr64
  movsbq (%rsi),%rdx
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %dl,%dl
  je     L6
  mov    D3(%rip),%rbp
  mov    %rsi,%r12
  jmp    L44
  nop
L49:
  mov    $0x1000193,%edi
  call   <UINT32_C@plt>
  movsbq (%r12),%rdx
  imul   %rax,%rbx
  test   %dl,%dl
  je     L6
L44:
  movslq 0x0(%rbp),%rax
  add    $0x1,%r12
  xor    %rdx,%rbx
  shl    $0x3,%rax
  cmp    $0x20,%rax
  jbe    L49
  mov    $0x1b3,%edi
  call   <UINT64_C@plt>
  movsbq (%r12),%rdx
  imul   %rax,%rbx
  test   %dl,%dl
  jne    L44
L6:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t hsearch_hash(size_t offset_basis, const char *str) {
  size_t hash;
  hash = offset_basis;
  while (*str != '\0') {
    hash ^= (uint8_t)*str++;
    if (sizeof(size_t) * CHAR_BIT <= 32)
      hash *= UINT32_C(16777619);
    else
      hash *= UINT64_C(1099511628211);
  }
  return (hash);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hsearch_hash>:
  endbr64
  movsbq (%rsi),%rdx
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %dl,%dl
  je     L1
  mov    D5(%rip),%rbp
  mov    %rsi,%r12
  nopl   (%rax)
L26:
  movslq 0x0(%rbp),%rax
  add    $0x1,%r12
  xor    %rdx,%rbx
  shl    $0x3,%rax
  cmp    $0x20,%rax
  ja     L31
  mov    $0x1000193,%edi
  call   <UINT32_C@plt>
  movsbq (%r12),%rdx
  imul   %rax,%rbx
  test   %dl,%dl
  jne    L26
L1:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L31:
  mov    $0x1b3,%edi
  call   <UINT64_C@plt>
  movsbq (%r12),%rdx
  imul   %rax,%rbx
  test   %dl,%dl
  jne    L26
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t hsearch_hash(size_t offset_basis, const char *str) {
  size_t hash;
  hash = offset_basis;
  while (*str != '\0') {
    hash ^= (uint8_t)*str++;
    if (sizeof(size_t) * CHAR_BIT <= 32)
      hash *= UINT32_C(16777619);
    else
      hash *= UINT64_C(1099511628211);
  }
  return (hash);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<safe_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L12
  mov    D1(%rip),%rax
  mov    (%rax),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L4
L12:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int safe_close(int fd) {
  int r;
  do
    r = close(fd);
  while (r == -1 && errno == EAGAIN);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<safe_close>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
L16:
  mov    %ebx,%edi
  call   <close@plt>
  cmp    $0xffffffff,%eax
  jne    L0
  mov    D0(%rip),%rcx
  mov    D14(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L16
L0:
  pop    %rbx
  ret
```

assistant: ```c
int safe_close(int fd) {
  int r;
  do
    r = close(fd);
  while (r == -1 && errno == EAGAIN);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<safe_close>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  jmp    L25
  nopl   0x0(%rax)
L14:
  mov    D7(%rip),%rdx
  mov    D19(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L29
L25:
  mov    %ebx,%edi
  call   <close@plt>
  cmp    $0xffffffff,%eax
  je     L14
L29:
  pop    %rbx
  ret
```

assistant: ```c
int safe_close(int fd) {
  int r;
  do
    r = close(fd);
  while (r == -1 && errno == EAGAIN);
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<safe_close>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  jmp    L29
  nopl   0x0(%rax)
L13:
  mov    D9(%rip),%rdx
  mov    D3(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L22
L29:
  mov    %ebx,%edi
  call   <close@plt>
  cmp    $0xffffffff,%eax
  je     L13
L22:
  pop    %rbx
  ret
```

assistant: ```c
int safe_close(int fd) {
  int r;
  do
    r = close(fd);
  while (r == -1 && errno == EAGAIN);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<connectUdp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D38(%rip),%rax
  mov    (%rax),%ecx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x6bed,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rcx
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L20
  mov    $0xffffffff,%eax
  jmp    L4
L20:
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L25
  mov    $0xfffffffe,%eax
  jmp    L4
L25:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x30(%rbp),%rdx
  lea    0x4(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  mov    0x8(%rdx),%rdx
  mov    %rdx,%rdi
  mov    %eax,%edx
  mov    %rcx,%rsi
  call   <bcopy@plt>
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
int connectUdp(int *sock, struct sockaddr_in *server, char *host, int port) {
  *sock = socket(AF_INET, SOCK_DGRAM, 0);
  struct sockaddr_in myaddr;
  myaddr.sin_addr.s_addr = INADDR_ANY;
  myaddr.sin_port = 27629;
  bind(*sock, (const struct sockaddr *)&myaddr, sizeof(struct sockaddr));
  if (*sock == 0) {
    return -1;
  }
  server->sin_family = AF_INET;
  struct hostent *hp;
  hp = gethostbyname(host);
  if (hp == 0)
    return -2;
  bcopy((char *)hp->h_addr, (char *)&server->sin_addr, hp->h_length);
  server->sin_port = htons(port);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<connectUdp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%edi
  mov    %eax,0x0(%rbp)
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  movl   $0x6bed,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  call   <bind@plt>
  cmpl   $0x0,0x0(%rbp)
  je     L25
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  mov    %r13,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L31
  lea    0x4(%rbx),%rsi
  mov    0x8(%rax),%rdi
  mov    (%rax),%edx
  call   <bcopy@plt>
  mov    %r12d,%edi
  call   <htons@plt>
  mov    %eax,(%rbx)
  mov    $0x0,%eax
L22:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  mov    $0xffffffff,%eax
  jmp    L22
L31:
  mov    $0xfffffffe,%eax
  jmp    L22
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int connectUdp(int *sock, struct sockaddr_in *server, char *host, int port) {
  *sock = socket(AF_INET, SOCK_DGRAM, 0);
  struct sockaddr_in myaddr;
  myaddr.sin_addr.s_addr = INADDR_ANY;
  myaddr.sin_port = 27629;
  bind(*sock, (const struct sockaddr *)&myaddr, sizeof(struct sockaddr));
  if (*sock == 0) {
    return -1;
  }
  server->sin_family = AF_INET;
  struct hostent *hp;
  hp = gethostbyname(host);
  if (hp == 0)
    return -2;
  bcopy((char *)hp->h_addr, (char *)&server->sin_addr, hp->h_length);
  server->sin_port = htons(port);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<connectUdp>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  xor    %edx,%edx
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    D3(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D10(%rip),%rax
  mov    0x0(%r13),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  movl   $0x6bed,0xc(%rsp)
  mov    %eax,0x0(%rbp)
  mov    %eax,%edi
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <bind@plt>
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  je     L16
  mov    0x0(%r13),%eax
  mov    %r14,%rdi
  mov    %eax,0x8(%rbx)
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L34
  mov    0x8(%rax),%rdi
  mov    (%rax),%edx
  lea    0x4(%rbx),%rsi
  call   <bcopy@plt>
  mov    %r12d,%edi
  call   <htons@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  jmp    L6
L34:
  mov    $0xfffffffe,%eax
  jmp    L6
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int connectUdp(int *sock, struct sockaddr_in *server, char *host, int port) {
  *sock = socket(AF_INET, SOCK_DGRAM, 0);
  struct sockaddr_in myaddr;
  myaddr.sin_addr.s_addr = INADDR_ANY;
  myaddr.sin_port = 27629;
  bind(*sock, (const struct sockaddr *)&myaddr, sizeof(struct sockaddr));
  if (*sock == 0) {
    return -1;
  }
  server->sin_family = AF_INET;
  struct hostent *hp;
  hp = gethostbyname(host);
  if (hp == 0)
    return -2;
  bcopy((char *)hp->h_addr, (char *)&server->sin_addr, hp->h_length);
  server->sin_port = htons(port);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<connectUdp>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  xor    %edx,%edx
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    D15(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  mov    0x0(%r13),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  movl   $0x6bed,0xc(%rsp)
  mov    %eax,0x0(%rbp)
  mov    %eax,%edi
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <bind@plt>
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  je     L38
  mov    0x0(%r13),%eax
  mov    %r14,%rdi
  mov    %eax,0x8(%rbx)
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L46
  mov    0x8(%rax),%rdi
  mov    (%rax),%edx
  lea    0x4(%rbx),%rsi
  call   <bcopy@plt>
  mov    %r12d,%edi
  call   <htons@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
L41:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0xffffffff,%eax
  jmp    L41
L46:
  mov    $0xfffffffe,%eax
  jmp    L41
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int connectUdp(int *sock, struct sockaddr_in *server, char *host, int port) {
  *sock = socket(AF_INET, SOCK_DGRAM, 0);
  struct sockaddr_in myaddr;
  myaddr.sin_addr.s_addr = INADDR_ANY;
  myaddr.sin_port = 27629;
  bind(*sock, (const struct sockaddr *)&myaddr, sizeof(struct sockaddr));
  if (*sock == 0) {
    return -1;
  }
  server->sin_family = AF_INET;
  struct hostent *hp;
  hp = gethostbyname(host);
  if (hp == 0)
    return -2;
  bcopy((char *)hp->h_addr, (char *)&server->sin_addr, hp->h_length);
  server->sin_port = htons(port);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bitToCoordinates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <bitToDecimal@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bitToDecimal@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *bitToCoordinates(char *string) {
  int *coordinates = malloc(sizeof(int) * 2);
  char *xString = malloc(sizeof(char) * 3);
  char *yString = malloc(sizeof(char) * 3);
  xString[0] = string[0];
  xString[1] = string[3];
  xString[2] = '\0';
  yString[0] = string[1];
  yString[1] = string[2];
  yString[2] = '\0';
  int x = bitToDecimal(xString);
  int y = bitToDecimal(yString);
  coordinates[0] = x;
  coordinates[1] = y;
  return coordinates;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitToCoordinates>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movzbl (%r12),%eax
  mov    %al,0x0(%rbp)
  movzbl 0x3(%r12),%eax
  mov    %al,0x1(%rbp)
  movb   $0x0,0x2(%rbp)
  movzbl 0x1(%r12),%eax
  mov    %al,(%rbx)
  movzbl 0x2(%r12),%eax
  mov    %al,0x1(%rbx)
  movb   $0x0,0x2(%rbx)
  mov    %rbp,%rdi
  call   <bitToDecimal@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <bitToDecimal@plt>
  mov    %ebp,0x0(%r13)
  mov    %eax,0x4(%r13)
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *bitToCoordinates(char *string) {
  int *coordinates = malloc(sizeof(int) * 2);
  char *xString = malloc(sizeof(char) * 3);
  char *yString = malloc(sizeof(char) * 3);
  xString[0] = string[0];
  xString[1] = string[3];
  xString[2] = '\0';
  yString[0] = string[1];
  yString[1] = string[2];
  yString[2] = '\0';
  int x = bitToDecimal(xString);
  int y = bitToDecimal(yString);
  coordinates[0] = x;
  coordinates[1] = y;
  return coordinates;
}
```
user: What is the c source code of the assembly code below:

```asm
<bitToCoordinates>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x3,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x3,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  movzbl (%rbx),%eax
  mov    %al,(%r12)
  movzbl 0x3(%rbx),%eax
  movb   $0x0,0x2(%r12)
  mov    %al,0x1(%r12)
  movzbl 0x1(%rbx),%eax
  mov    %al,0x0(%rbp)
  movzbl 0x2(%rbx),%eax
  movb   $0x0,0x2(%rbp)
  mov    %al,0x1(%rbp)
  call   <bitToDecimal@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <bitToDecimal@plt>
  mov    %ebx,0x0(%r13)
  mov    %eax,0x4(%r13)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *bitToCoordinates(char *string) {
  int *coordinates = malloc(sizeof(int) * 2);
  char *xString = malloc(sizeof(char) * 3);
  char *yString = malloc(sizeof(char) * 3);
  xString[0] = string[0];
  xString[1] = string[3];
  xString[2] = '\0';
  yString[0] = string[1];
  yString[1] = string[2];
  yString[2] = '\0';
  int x = bitToDecimal(xString);
  int y = bitToDecimal(yString);
  coordinates[0] = x;
  coordinates[1] = y;
  return coordinates;
}
```