ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DomoCANaddr>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movzbl 0x3(%rsp),%eax
  mov    %al,(%rbx)
  movzbl 0x4(%rsp),%eax
  mov    %al,0x1(%rbx)
  movzbl 0x5(%rsp),%eax
  mov    %al,0x2(%rbx)
  movzbl 0x6(%rsp),%eax
  mov    %al,0x3(%rbx)
  movzbl 0x7(%rsp),%eax
  mov    %al,0x4(%rbx)
  movzbl 0x8(%rsp),%eax
  mov    %al,0x5(%rbx)
  movzbl 0x9(%rsp),%eax
  mov    %al,0x6(%rbx)
  movzbl 0xa(%rsp),%eax
  mov    %al,0x7(%rbx)
  movb   $0x30,0x8(%rbx)
  movb   $0x30,0x9(%rbx)
  movb   $0x30,0xa(%rbx)
  movzbl 0xb(%rsp),%eax
  mov    %al,0xb(%rbx)
  movzbl 0xc(%rsp),%eax
  mov    %al,0xc(%rbx)
  movzbl 0xd(%rsp),%eax
  mov    %al,0xd(%rbx)
  movzbl 0xe(%rsp),%eax
  mov    %al,0xe(%rbx)
  movzbl 0xf(%rsp),%eax
  mov    %al,0xf(%rbx)
  movb   $0x0,0x10(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DomoCANaddr(char *value, char shifted[18]) {
  char in[18];
  strcpy(in, value);
  shifted[0] = in[3];
  shifted[1] = in[4];
  shifted[2] = in[5];
  shifted[3] = in[6];
  shifted[4] = in[7];
  shifted[5] = in[8];
  shifted[6] = in[9];
  shifted[7] = in[10];
  shifted[8] = '0';
  shifted[9] = '0';
  shifted[10] = '0';
  shifted[11] = in[11];
  shifted[12] = in[12];
  shifted[13] = in[13];
  shifted[14] = in[14];
  shifted[15] = in[15];
  shifted[16] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<DomoCANaddr>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%rbx
  mov    %r8,%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    0x3(%rsp),%rax
  movb   $0x30,0xa(%rbx)
  movb   $0x0,0x10(%rbx)
  mov    %rax,(%rbx)
  mov    $0x3030,%eax
  mov    %ax,0x8(%rbx)
  mov    0xb(%rsp),%eax
  mov    %eax,0xb(%rbx)
  movzbl 0xf(%rsp),%eax
  mov    %al,0xf(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DomoCANaddr(char *value, char shifted[18]) {
  char in[18];
  strcpy(in, value);
  shifted[0] = in[3];
  shifted[1] = in[4];
  shifted[2] = in[5];
  shifted[3] = in[6];
  shifted[4] = in[7];
  shifted[5] = in[8];
  shifted[6] = in[9];
  shifted[7] = in[10];
  shifted[8] = '0';
  shifted[9] = '0';
  shifted[10] = '0';
  shifted[11] = in[11];
  shifted[12] = in[12];
  shifted[13] = in[13];
  shifted[14] = in[14];
  shifted[15] = in[15];
  shifted[16] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<DomoCANaddr>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%rbx
  mov    %r8,%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    0x3(%rsp),%rax
  movb   $0x30,0xa(%rbx)
  movb   $0x0,0x10(%rbx)
  mov    %rax,(%rbx)
  mov    $0x3030,%eax
  mov    %ax,0x8(%rbx)
  mov    0xb(%rsp),%eax
  mov    %eax,0xb(%rbx)
  movzbl 0xf(%rsp),%eax
  mov    %al,0xf(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DomoCANaddr(char *value, char shifted[18]) {
  char in[18];
  strcpy(in, value);
  shifted[0] = in[3];
  shifted[1] = in[4];
  shifted[2] = in[5];
  shifted[3] = in[6];
  shifted[4] = in[7];
  shifted[5] = in[8];
  shifted[6] = in[9];
  shifted[7] = in[10];
  shifted[8] = '0';
  shifted[9] = '0';
  shifted[10] = '0';
  shifted[11] = in[11];
  shifted[12] = in[12];
  shifted[13] = in[13];
  shifted[14] = in[14];
  shifted[15] = in[15];
  shifted[16] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <catalan@plt>
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type_infered: string
name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D24
type_infered: string

tool: D11: Input n 
Nth Catalan you want :

tool: D2: %d

tool: D24: Nth Catalan number is: %lu

assistant: ```c
int main() {
  unsigned int n;
  printf("Input n \nNth Catalan you want :");
  scanf("%d", &n);
  printf("Nth Catalan number is: %lu", catalan(n));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <catalan@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D29
data_type: string
name: parse_data
arguments: label: D21
data_type: string
name: parse_data
arguments: label: D7
data_type: string

tool: D29: Input n 
Nth Catalan you want :

tool: D21: %d

tool: D7: Nth Catalan number is: %lu

assistant: ```c
int main() {
  unsigned int n;
  printf("Input n \nNth Catalan you want :");
  scanf("%d", &n);
  printf("Nth Catalan number is: %lu", catalan(n));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <catalan@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string
name: parse_data
arguments: tag: D27
datatype: string
name: parse_data
arguments: tag: D5
datatype: string

tool: D0: Input n 
Nth Catalan you want :

tool: D27: %d

tool: D5: Nth Catalan number is: %lu

assistant: ```c
int main() {
  unsigned int n;
  printf("Input n \nNth Catalan you want :");
  scanf("%d", &n);
  printf("Nth Catalan number is: %lu", catalan(n));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <catalan@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D18: Input n 
Nth Catalan you want :

tool: D15: %d

tool: D19: Nth Catalan number is: %lu

assistant: ```c
int main() {
  unsigned int n;
  printf("Input n \nNth Catalan you want :");
  scanf("%d", &n);
  printf("Nth Catalan number is: %lu", catalan(n));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x17447d68,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L10
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L34
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  and    $0x1c,%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L34
L10:
  mov    -0xc(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L46
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L34
L46:
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  rol    $0x9,%eax
  xor    $0x3831e09c,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (!(state[0UL] & 1U)) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      state[0UL] += state[0UL];
    } else {
      state[0UL] *= state[0UL];
    }
    output[0UL] = ((state[0UL] << 9U) | (state[0UL] >> 23U)) ^ 942792860U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    -0x17447d68(%rdx),%eax
  test   $0x8,%dl
  jne    L25
  test   $0x1,%al
  jne    L11
  lea    0x0(,%rax,4),%edx
  and    $0x1c,%edx
  or     %edx,%eax
L11:
  rol    $0x9,%eax
  xor    $0x3831e09c,%eax
  mov    %eax,(%rsi)
  ret
L25:
  test   $0x10,%al
  je     L19
  add    %eax,%eax
  jmp    L11
L19:
  imul   %eax,%eax
  jmp    L11
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (!(state[0UL] & 1U)) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      state[0UL] += state[0UL];
    } else {
      state[0UL] *= state[0UL];
    }
    output[0UL] = ((state[0UL] << 9U) | (state[0UL] >> 23U)) ^ 942792860U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    -0x17447d68(%rdx),%eax
  and    $0x8,%edx
  jne    L10
  test   $0x1,%al
  jne    L9
  lea    0x0(,%rax,4),%edx
  and    $0x1c,%edx
  or     %edx,%eax
L9:
  rol    $0x9,%eax
  xor    $0x3831e09c,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L10:
  test   $0x10,%al
  je     L5
  add    %eax,%eax
  rol    $0x9,%eax
  xor    $0x3831e09c,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L5:
  imul   %eax,%eax
  rol    $0x9,%eax
  xor    $0x3831e09c,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (!(state[0UL] & 1U)) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      state[0UL] += state[0UL];
    } else {
      state[0UL] *= state[0UL];
    }
    output[0UL] = ((state[0UL] << 9U) | (state[0UL] >> 23U)) ^ 942792860U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    -0x17447d68(%rdx),%eax
  and    $0x8,%edx
  jne    L27
  test   $0x1,%al
  jne    L14
  lea    0x0(,%rax,4),%edx
  and    $0x1c,%edx
  or     %edx,%eax
L14:
  rol    $0x9,%eax
  xor    $0x3831e09c,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L27:
  test   $0x10,%al
  je     L13
  add    %eax,%eax
  rol    $0x9,%eax
  xor    $0x3831e09c,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L13:
  imul   %eax,%eax
  rol    $0x9,%eax
  xor    $0x3831e09c,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (!(state[0UL] & 1U)) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      state[0UL] += state[0UL];
    } else {
      state[0UL] *= state[0UL];
    }
    output[0UL] = ((state[0UL] << 9U) | (state[0UL] >> 23U)) ^ 942792860U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<allocateGridMemory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <errChkdMalloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L2:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <errChkdMalloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L2
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string

tool: D14: assign done

tool: D13: in allocateGridMemory allocHelper == 0x%08x


assistant: ```c
char **allocateGridMemory(int size) {
  int i;
  char **allocHelper;
  allocHelper = (char **)errChkdMalloc(4 * size);
  for (i = 0; i < size; i++) {
    allocHelper[i] = (char *)errChkdMalloc(size);
  }
  printf("assign done\n");
  printf("in allocateGridMemory allocHelper == 0x%08x\n", (unsigned int)allocHelper);
  return allocHelper;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<allocateGridMemory>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  lea    0x0(,%rdi,4),%edi
  call   <errChkdMalloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L5
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    0x0(%r13,%rax,8),%r12
L8:
  mov    %ebp,%edi
  call   <errChkdMalloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L8
L5:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    %r13d,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string

tool: D15: assign done

tool: D11: in allocateGridMemory allocHelper == 0x%08x


assistant: ```c
char **allocateGridMemory(int size) {
  int i;
  char **allocHelper;
  allocHelper = (char **)errChkdMalloc(4 * size);
  for (i = 0; i < size; i++) {
    allocHelper[i] = (char *)errChkdMalloc(size);
  }
  printf("assign done\n");
  printf("in allocateGridMemory allocHelper == 0x%08x\n", (unsigned int)allocHelper);
  return allocHelper;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<allocateGridMemory>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  shl    $0x2,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <errChkdMalloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L5
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    0x0(%r13,%rax,8),%r12
  nopl   0x0(%rax)
L17:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <errChkdMalloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L17
L5:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    %r13d,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D7: assign done

tool: D17: in allocateGridMemory allocHelper == 0x%08x


assistant: ```c
char **allocateGridMemory(int size) {
  int i;
  char **allocHelper;
  allocHelper = (char **)errChkdMalloc(4 * size);
  for (i = 0; i < size; i++) {
    allocHelper[i] = (char *)errChkdMalloc(size);
  }
  printf("assign done\n");
  printf("in allocateGridMemory allocHelper == 0x%08x\n", (unsigned int)allocHelper);
  return allocHelper;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<allocateGridMemory>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  shl    $0x2,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <errChkdMalloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L4
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    0x0(%r13,%rax,8),%r12
  nopl   0x0(%rax)
L1:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <errChkdMalloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L1
L4:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D6: assign done

tool: D1: in allocateGridMemory allocHelper == 0x%08x


assistant: ```c
char **allocateGridMemory(int size) {
  int i;
  char **allocHelper;
  allocHelper = (char **)errChkdMalloc(4 * size);
  for (i = 0; i < size; i++) {
    allocHelper[i] = (char *)errChkdMalloc(size);
  }
  printf("assign done\n");
  printf("in allocateGridMemory allocHelper == 0x%08x\n", (unsigned int)allocHelper);
  return allocHelper;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UI_SPUnlockMedals_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <trap_Cvar_VariableStringBuffer@plt>
  movl   $0x0,-0x424(%rbp)
  jmp    L11
L18:
  mov    -0x424(%rbp),%edx
  lea    -0x420(%rbp),%rax
  mov    %edx,%ecx
  lea    D47(%rip),%rdx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <Com_sprintf@plt>
  lea    -0x420(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <Info_SetValueForKey@plt>
  addl   $0x1,-0x424(%rbp)
L11:
  cmpl   $0x5,-0x424(%rbp)
  jle    L18
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <trap_Cvar_Set@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <trap_Print@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D47
type_infered: string
name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D17: g_spAwards

tool: D47: a%i

tool: D28: 100

tool: D6: All levels unlocked at 100


assistant: ```c
void UI_SPUnlockMedals_f(void) {
  int n;
  char key[16];
  char awardData[1024];
  trap_Cvar_VariableStringBuffer("g_spAwards", awardData, 1024);
  for (n = 0; n < 6; n++) {
    Com_sprintf(key, sizeof(key), "a%i", n);
    Info_SetValueForKey(awardData, key, "100");
  }
  trap_Cvar_Set("g_spAwards", awardData);
  trap_Print("All levels unlocked at 100\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UI_SPUnlockMedals_f>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  mov    $0x400,%edx
  lea    D28(%rip),%rdi
  call   <trap_Cvar_VariableStringBuffer@plt>
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  lea    D4(%rip),%r14
  lea    0x10(%rsp),%r13
  lea    D5(%rip),%r12
L13:
  mov    %ebx,%ecx
  mov    %r14,%rdx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <Com_sprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <Info_SetValueForKey@plt>
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L13
  lea    0x10(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <trap_Cvar_Set@plt>
  lea    D25(%rip),%rdi
  call   <trap_Print@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x420,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type: string
name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D5
type: string
name: extract_symbolic_data
arguments: label: D25
type: string

tool: D28: g_spAwards

tool: D4: a%i

tool: D5: 100

tool: D25: All levels unlocked at 100


assistant: ```c
void UI_SPUnlockMedals_f(void) {
  int n;
  char key[16];
  char awardData[1024];
  trap_Cvar_VariableStringBuffer("g_spAwards", awardData, 1024);
  for (n = 0; n < 6; n++) {
    Com_sprintf(key, sizeof(key), "a%i", n);
    Info_SetValueForKey(awardData, key, "100");
  }
  trap_Cvar_Set("g_spAwards", awardData);
  trap_Print("All levels unlocked at 100\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UI_SPUnlockMedals_f>:
  endbr64
  push   %r15
  lea    D39(%rip),%r15
  mov    $0x400,%edx
  push   %r14
  mov    %r15,%rdi
  lea    D18(%rip),%r14
  push   %r13
  lea    D31(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %rsp,%rbp
  mov    %r12,%rsi
  call   <trap_Cvar_VariableStringBuffer@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%ecx
  mov    %r14,%rdx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <Com_sprintf@plt>
  add    $0x1,%ebx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <Info_SetValueForKey@plt>
  cmp    $0x6,%ebx
  jne    L10
  mov    %r15,%rdi
  mov    %r12,%rsi
  call   <trap_Cvar_Set@plt>
  lea    D16(%rip),%rdi
  call   <trap_Print@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D39
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D31
type_infered: string
name: unpack_data
arguments: tag: D16
type_infered: string

tool: D39: g_spAwards

tool: D18: a%i

tool: D31: 100

tool: D16: All levels unlocked at 100


assistant: ```c
void UI_SPUnlockMedals_f(void) {
  int n;
  char key[16];
  char awardData[1024];
  trap_Cvar_VariableStringBuffer("g_spAwards", awardData, 1024);
  for (n = 0; n < 6; n++) {
    Com_sprintf(key, sizeof(key), "a%i", n);
    Info_SetValueForKey(awardData, key, "100");
  }
  trap_Cvar_Set("g_spAwards", awardData);
  trap_Print("All levels unlocked at 100\n");
}
```