ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  lea    D6(%rip),%r15
  push   %r14
  push   %r13
  lea    D38(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D24(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r14
  lea    0x10(%rsp),%r12
  movq   $0x0,0x10(%rsp)
  lea    0xb(%rsp),%rbp
  nop
L51:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <push@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpb   $0x79,0xb(%rsp)
  je     L51
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0xb(%rsp),%eax
  cmp    $0x61,%al
  je     L34
  cmp    $0x64,%al
  je     L62
L75:
  mov    0x10(%rsp),%rdi
  call   <length@plt>
  mov    0x10(%rsp),%rdi
  mov    %eax,%esi
  call   <print@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpb   $0x79,0xb(%rsp)
  je     L85
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  mov    %r12,%rdi
  call   <clear@plt>
  cmpb   $0x79,0xb(%rsp)
  je     L51
  jmp    L24
  nopl   (%rax)
L34:
  mov    %r12,%rdi
  call   <sort_ascending@plt>
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L62:
  mov    %r12,%rdi
  call   <sort_descending@plt>
  jmp    L75
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D38
datatype: string
name: parse_data
arguments: data_label: D24
datatype: string
name: parse_data
arguments: data_label: D20
datatype: string
name: parse_data
arguments: data_label: D59
datatype: string
name: parse_data
arguments: data_label: D1
datatype: string

tool: D6: Enter a number: 

tool: D38: %d

tool: D24: %1s

tool: D20: Do you want another num (y or n): 

tool: D59: Sort ascending or descending (a or d)? 

tool: D1: Do you want to do this again (y or n)? 

assistant: ```c
int main() {
  char ans;
  int num;
  struct node *head = NULL;
  do {
    do {
      printf("Enter a number: ");
      scanf("%d", &num);
      push(&head, num);
      printf("Do you want another num (y or n): ");
      scanf("%1s", &ans);
    } while (ans == 'y');
    printf("Sort ascending or descending (a or d)? ");
    scanf("%1s", &ans);
    if (ans == 'a')
      sort_ascending(&head);
    else if (ans == 'd')
      sort_descending(&head);
    print(head, length(head));
    printf("Do you want to do this again (y or n)? ");
    scanf("%1s", &ans);
    if (ans == 'y')
      clear(&head);
  } while (ans == 'y');
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<exist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int exist(char *path) {
  int r;
  struct stat s;
  r = stat(path, &s);
  return r != -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exist>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exist(char *path) {
  int r;
  struct stat s;
  r = stat(path, &s);
  return r != -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<exist>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exist(char *path) {
  int r;
  struct stat s;
  r = stat(path, &s);
  return r != -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exist>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exist(char *path) {
  int r;
  struct stat s;
  r = stat(path, &s);
  return r != -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L15
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <serverMain@plt>
  jmp    L19
L15:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clientMain@plt>
L19:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc <= 1) {
    serverMain(argc, argv);
  } else {
    clientMain(argc, argv);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L0
  call   <clientMain@plt>
L5:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L0:
  call   <serverMain@plt>
  jmp    L5
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc <= 1) {
    serverMain(argc, argv);
  } else {
    clientMain(argc, argv);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L15
  call   <clientMain@plt>
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L15:
  call   <serverMain@plt>
  jmp    L1
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc <= 1) {
    serverMain(argc, argv);
  } else {
    clientMain(argc, argv);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L19
  call   <clientMain@plt>
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L19:
  call   <serverMain@plt>
  jmp    L2
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc <= 1) {
    serverMain(argc, argv);
  } else {
    clientMain(argc, argv);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ipv6_format>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ipv6_format(char *str) {
  int pos = strlen(str) - 1;
  int rc = 0;
  if (str[pos] == ']') {
    str[pos] = '\0';
    rc = pos;
  }
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ipv6_format>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  add    %rdx,%rbx
  cmpb   $0x5d,(%rbx)
  je     L12
  mov    $0x0,%eax
L17:
  pop    %rbx
  ret
L12:
  movb   $0x0,(%rbx)
  jmp    L17
```

assistant: ```c
int ipv6_format(char *str) {
  int pos = strlen(str) - 1;
  int rc = 0;
  if (str[pos] == ']') {
    str[pos] = '\0';
    rc = pos;
  }
  return rc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ipv6_format>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  add    %rdx,%rbx
  cmpb   $0x5d,(%rbx)
  je     L8
  xor    %eax,%eax
  pop    %rbx
  ret
  nop
L8:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
int ipv6_format(char *str) {
  int pos = strlen(str) - 1;
  int rc = 0;
  if (str[pos] == ']') {
    str[pos] = '\0';
    rc = pos;
  }
  return rc;
}
```
user: What is the c source code of the assembly code below?

```asm
<ipv6_format>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  add    %rdx,%rbx
  cmpb   $0x5d,(%rbx)
  je     L9
  xor    %eax,%eax
  pop    %rbx
  ret
  nop
L9:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
int ipv6_format(char *str) {
  int pos = strlen(str) - 1;
  int rc = 0;
  if (str[pos] == ']') {
    str[pos] = '\0';
    rc = pos;
  }
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L13
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L13:
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printJpegStream@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D23
type: string
name: read_data
arguments: tag: D0
type: string

tool: D22: rb

tool: D23: Gimme file name

tool: D0: Couldn't open file %s!


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *f;
  f = fopen(argv[1], "rb");
  if (argc < 1) {
    printf("Gimme file name\n");
    exit(1);
  }
  if (!f) {
    printf("Couldn't open file %s!\n", argv[1]);
    exit(1);
  }
  printJpegStream(f);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    0x8(%rsi),%rdi
  lea    D11(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %r12d,%r12d
  jle    L5
L2:
  test   %rbx,%rbx
  je     L8
L16:
  mov    %rbx,%rdi
  call   <printJpegStream@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
L8:
  mov    0x8(%rbp),%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D11: rb

tool: D27: Gimme file name

tool: D8: Couldn't open file %s!


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *f;
  f = fopen(argv[1], "rb");
  if (argc < 1) {
    printf("Gimme file name\n");
    exit(1);
  }
  if (!f) {
    printf("Couldn't open file %s!\n", argv[1]);
    exit(1);
  }
  printJpegStream(f);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L7
L6:
  test   %rbp,%rbp
  je     L36
L21:
  mov    %rbp,%rdi
  call   <printJpegStream@plt>
  xor    %edi,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L6
L36:
  mov    0x8(%rbx),%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L21
```

tool_calls: name: read_data
arguments: label: D13
datatype: string
name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D13: rb

tool: D24: Gimme file name

tool: D16: Couldn't open file %s!


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *f;
  f = fopen(argv[1], "rb");
  if (argc < 1) {
    printf("Gimme file name\n");
    exit(1);
  }
  if (!f) {
    printf("Couldn't open file %s!\n", argv[1]);
    exit(1);
  }
  printJpegStream(f);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  lea    D14(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L28
L30:
  test   %rbp,%rbp
  je     L2
L34:
  mov    %rbp,%rdi
  call   <printJpegStream@plt>
  xor    %edi,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L28:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L30
L2:
  mov    0x8(%rbx),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L34
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D14: rb

tool: D24: Gimme file name

tool: D19: Couldn't open file %s!


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *f;
  f = fopen(argv[1], "rb");
  if (argc < 1) {
    printf("Gimme file name\n");
    exit(1);
  }
  if (!f) {
    printf("Couldn't open file %s!\n", argv[1]);
    exit(1);
  }
  printJpegStream(f);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rbx
  jmp    L58
L5:
  mov    %rbx,%r13
  mov    $0x1,%r14d
  mov    -0x30(%rbp),%r12
  jmp    L26
L28:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%edx
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L26
  mov    $0x0,%r14d
L26:
  movzbl (%r12),%eax
  test   %al,%al
  jne    L28
  cmp    $0x1,%r14d
  jne    L34
  mov    %rbx,%rax
  sub    -0x28(%rbp),%rax
  jmp    L36
L34:
  add    $0x1,%rbx
L58:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L5
  mov    $0xffffffff,%eax
L36:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
strindex(p1, p2) char *p1, *p2;
{
  register m;
  register char *s, *t, *p;
  for (p = p1; *p; p++) {
    s = p;
    m = 1;
    for (t = p2; *t;)
      if (*t++ != *s++)
        m = 0;
    if (m == 1)
      return (p - p1);
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L37
  movzbl (%rsi),%r10d
  mov    %rdi,%rax
  mov    $0x0,%r9d
L2:
  test   %r10b,%r10b
  je     L49
  mov    %r10d,%ecx
  mov    $0x0,%edx
  mov    $0x1,%r8d
L44:
  cmp    %cl,(%rax,%rdx,1)
  cmovne %r9d,%r8d
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L44
  cmp    $0x1,%r8d
  jne    L30
L49:
  sub    %edi,%eax
  ret
L30:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L2
  mov    $0xffffffff,%eax
  ret
L37:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
strindex(p1, p2) char *p1, *p2;
{
  register m;
  register char *s, *t, *p;
  for (p = p1; *p; p++) {
    s = p;
    m = 1;
    for (t = p2; *t;)
      if (*t++ != *s++)
        m = 0;
    if (m == 1)
      return (p - p1);
  }
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L38
  movzbl (%rsi),%r10d
  mov    %rdi,%rax
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L19:
  test   %r10b,%r10b
  je     L10
  mov    %r10d,%ecx
  xor    %edx,%edx
  mov    $0x1,%r8d
  nopl   0x0(%rax,%rax,1)
L22:
  cmp    %cl,(%rax,%rdx,1)
  cmovne %r9d,%r8d
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L22
  cmp    $0x1,%r8d
  je     L10
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L19
L38:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  sub    %edi,%eax
  ret
```

assistant: ```c
strindex(p1, p2) char *p1, *p2;
{
  register m;
  register char *s, *t, *p;
  for (p = p1; *p; p++) {
    s = p;
    m = 1;
    for (t = p2; *t;)
      if (*t++ != *s++)
        m = 0;
    if (m == 1)
      return (p - p1);
  }
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L35
  movzbl (%rsi),%r10d
  mov    %rdi,%rax
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L32:
  test   %r10b,%r10b
  je     L48
  mov    %r10d,%ecx
  xor    %edx,%edx
  mov    $0x1,%r8d
  nopl   0x0(%rax,%rax,1)
L25:
  cmp    (%rax,%rdx,1),%cl
  cmovne %r9d,%r8d
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L25
  cmp    $0x1,%r8d
  je     L48
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L32
L35:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  sub    %edi,%eax
  ret
```

assistant: ```c
strindex(p1, p2) char *p1, *p2;
{
  register m;
  register char *s, *t, *p;
  for (p = p1; *p; p++) {
    s = p;
    m = 1;
    for (t = p2; *t;)
      if (*t++ != *s++)
        m = 0;
    if (m == 1)
      return (p - p1);
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_string_append_format>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <str_string_append_vformat@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int str_string_append_format(struct str_string *str, const char *fmt, ...) {
  va_list ap;
  int ret;
  va_start(ap, fmt);
  ret = str_string_append_vformat(str, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str_string_append_format>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <str_string_append_vformat@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_string_append_format(struct str_string *str, const char *fmt, ...) {
  va_list ap;
  int ret;
  va_start(ap, fmt);
  ret = str_string_append_vformat(str, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_string_append_format>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <str_string_append_vformat@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int str_string_append_format(struct str_string *str, const char *fmt, ...) {
  va_list ap;
  int ret;
  va_start(ap, fmt);
  ret = str_string_append_vformat(str, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_string_append_format>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <str_string_append_vformat@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int str_string_append_format(struct str_string *str, const char *fmt, ...) {
  va_list ap;
  int ret;
  va_start(ap, fmt);
  ret = str_string_append_vformat(str, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<af4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *af4() {
  int *p = my_malloc(12);
  my_free(p);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<af4>:
  endbr64
  push   %rbx
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <my_free@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int *af4() {
  int *p = my_malloc(12);
  my_free(p);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<af4>:
  endbr64
  push   %r12
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <my_free@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int *af4() {
  int *p = my_malloc(12);
  my_free(p);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<af4>:
  endbr64
  push   %r12
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <my_free@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int *af4() {
  int *p = my_malloc(12);
  my_free(p);
  return p;
}
```