ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<verify_password>:
  endbr64
  push   %r12
  mov    $0xfffffeff,%edx
  mov    %rsi,%r12
  mov    $0xfffffbff,%esi
  push   %rbp
  mov    $0xfffffeff,%ecx
  mov    %edi,%ebp
  mov    $0xfffffeff,%r8d
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %dx,0xc(%rsp)
  mov    $0xfffffbff,%eax
  mov    $0x3,%edx
  mov    %si,0x12(%rsp)
  lea    0x9(%rsp),%rsi
  mov    %cx,0xf(%rsp)
  mov    %r8w,0x15(%rsp)
  mov    %ax,0x9(%rsp)
  movb   $0x3,0xb(%rsp)
  movb   $0x22,0xe(%rsp)
  movb   $0x27,0x11(%rsp)
  movb   $0x1,0x14(%rsp)
  movb   $0x1,0x17(%rsp)
  call   <WRITE@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x3,%edx
  mov    %ebp,%edi
  call   <WRITE@plt>
  lea    0xf(%rsp),%rsi
  mov    $0x3,%edx
  mov    %ebp,%edi
  call   <WRITE@plt>
  lea    0x12(%rsp),%rsi
  mov    $0x3,%edx
  mov    %ebp,%edi
  call   <WRITE@plt>
  lea    0x15(%rsp),%rsi
  mov    %ebp,%edi
  mov    $0x3,%edx
  call   <WRITE@plt>
  lea    D7(%rip),%rsi
  mov    %ebp,%edi
  call   <sockprint@plt>
  cmp    $0xffffffff,%eax
  je     L19
  mov    %ebp,%edi
  call   <get_string@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L19
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L30
  xor    %eax,%eax
L2:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L30:
  lea    D4(%rip),%rsi
  mov    %ebp,%edi
  call   <sockprint@plt>
L19:
  mov    $0xffffffff,%eax
  jmp    L2
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string

tool: D7: Password: 

tool: D4: Invalid password

assistant: ```c
int verify_password(int client_fd, char *password) {
  char *entered;
  char dont_auth[] = {0xff, 0xf4, 0x25};
  char suppress_goahead[] = {0xff, 0xfb, 0x03};
  char dont_linemode[] = {0xff, 0xfe, 0x22};
  char dont_new_env[] = {0xff, 0xfe, 0x27};
  char will_echo[] = {0xff, 0xfb, 0x01};
  char dont_echo[] = {0xff, 0xfe, 0x01};
  char noecho[] = {0xff, 0xfd, 0x2d};
  WRITE(client_fd, suppress_goahead, sizeof suppress_goahead);
  WRITE(client_fd, dont_linemode, sizeof dont_linemode);
  WRITE(client_fd, dont_new_env, sizeof dont_new_env);
  WRITE(client_fd, will_echo, sizeof will_echo);
  WRITE(client_fd, dont_echo, sizeof dont_echo);
  if (sockprint(client_fd, "Password: ") == -1)
    return -1;
  entered = get_string(client_fd);
  if (!entered)
    return -1;
  if (strcmp(password, entered) == 0)
    return 0;
  sockprint(client_fd, "Invalid password");
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x1,-0x1a0(%rbp)
  movl   $0x2,-0x19c(%rbp)
  movl   $0x3,-0x198(%rbp)
  movl   $0x4,-0x194(%rbp)
  movl   $0x5,-0x190(%rbp)
  movl   $0x6,-0x18c(%rbp)
  movl   $0xa,-0x1ac(%rbp)
  movl   $0x14,-0x1a8(%rbp)
  movl   $0x1e,-0x1a4(%rbp)
  movl   $0x6,-0x1b4(%rbp)
  movl   $0x3,-0x1b0(%rbp)
  lea    -0x1c4(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x1b4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c0(%rbp)
  jmp    L65
L39:
  mov    -0x1c0(%rbp),%edx
  mov    -0x1b0(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x1c0(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  movslq %ecx,%rax
  mov    %edx,-0x1a0(%rbp,%rax,4)
  subl   $0x1,-0x1c0(%rbp)
L65:
  mov    -0x1c4(%rbp),%eax
  cmp    %eax,-0x1c0(%rbp)
  jge    L39
  movl   $0x0,-0x1bc(%rbp)
  jmp    L54
L43:
  mov    -0x1c4(%rbp),%edx
  mov    -0x1bc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x1bc(%rbp),%eax
  cltq
  mov    -0x1ac(%rbp,%rax,4),%edx
  movslq %ecx,%rax
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1bc(%rbp)
L54:
  mov    -0x1bc(%rbp),%eax
  cmp    -0x1b0(%rbp),%eax
  jle    L43
  movl   $0x0,-0x1b8(%rbp)
  jmp    L21
L47:
  mov    -0x1b8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1b8(%rbp)
L21:
  mov    -0x1b0(%rbp),%edx
  mov    -0x1b4(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1b8(%rbp)
  jl     L47
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D13: %d

tool: D8: %d


assistant: ```c
int main() {
  int source[100] = {1, 2, 3, 4, 5, 6};
  int dest[] = {10, 20, 30};
  int N = 6;
  int M = sizeof(dest) / sizeof(dest)[0];
  int k;
  scanf("%d", &k);
  for (int i = (N - 1); i >= k; i--) {
    source[i + M] = source[i];
  }
  for (int i = 0; i <= M; i++) {
    source[i + k] = dest[i];
  }
  for (int i = 0; i < M + N; i++) {
    printf("%d\n", source[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x4,0x1c(%rsp)
  movl   $0x5,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  movl   $0xa,0x4(%rsp)
  movl   $0x14,0x8(%rsp)
  movl   $0x1e,0xc(%rsp)
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  cmp    $0x5,%esi
  jg     L42
  lea    0x10(%rsp),%rax
  lea    0xc(%rsp),%rcx
  mov    $0x5,%edx
  sub    %esi,%edx
  shl    $0x2,%rdx
  sub    %rdx,%rcx
L31:
  mov    0x14(%rax),%edx
  mov    %edx,0x20(%rax)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L31
L42:
  movslq %esi,%rsi
  lea    0x10(%rsp,%rsi,4),%rcx
  mov    $0x0,%eax
L24:
  mov    0x4(%rsp,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L24
  lea    0x10(%rsp),%rbx
  lea    0x34(%rsp),%r12
  lea    D17(%rip),%rbp
L34:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L34
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D17
datatype: string

tool: D14: %d

tool: D17: %d


assistant: ```c
int main() {
  int source[100] = {1, 2, 3, 4, 5, 6};
  int dest[] = {10, 20, 30};
  int N = 6;
  int M = sizeof(dest) / sizeof(dest)[0];
  int k;
  scanf("%d", &k);
  for (int i = (N - 1); i >= k; i--) {
    source[i + M] = source[i];
  }
  for (int i = 0; i <= M; i++) {
    source[i + k] = dest[i];
  }
  for (int i = 0; i < M + N; i++) {
    printf("%d\n", source[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x32,%ecx
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D2(%rip),%rdi
  movabs $0x200000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%ecx
  cmp    $0x5,%ecx
  jg     L10
  mov    $0x5,%edx
  mov    %rbx,%rsi
  mov    %rbx,%rax
  sub    %ecx,%edx
  shl    $0x2,%rdx
  sub    %rdx,%rsi
  mov    $0x6,%edx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x10(%rax),%edx
  sub    $0x4,%rax
L1:
  mov    %edx,0x20(%rax)
  cmp    %rax,%rsi
  jne    L27
L10:
  movslq %ecx,%rax
  lea    0x34(%rsp),%r12
  lea    D9(%rip),%rbp
  movl   $0xa,0x10(%rsp,%rax,4)
  lea    0x1(%rcx),%eax
  cltq
  movl   $0x14,0x10(%rsp,%rax,4)
  lea    0x2(%rcx),%eax
  add    $0x3,%ecx
  cltq
  movslq %ecx,%rcx
  movl   $0x1e,0x10(%rsp,%rax,4)
  mov    0x10(%rsp),%eax
  mov    %eax,0x10(%rsp,%rcx,4)
  cs nopw 0x0(%rax,%rax,1)
L47:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L47
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string

tool: D2: %d

tool: D9: %d


assistant: ```c
int main() {
  int source[100] = {1, 2, 3, 4, 5, 6};
  int dest[] = {10, 20, 30};
  int N = 6;
  int M = sizeof(dest) / sizeof(dest)[0];
  int k;
  scanf("%d", &k);
  for (int i = (N - 1); i >= k; i--) {
    source[i + M] = source[i];
  }
  for (int i = 0; i <= M; i++) {
    source[i + k] = dest[i];
  }
  for (int i = 0; i < M + N; i++) {
    printf("%d\n", source[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x32,%ecx
  push   %rbp
  push   %rbx
  sub    $0x1c0,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  lea    0xc(%rsp),%rsi
  movl   $0x1e,0x18(%rsp)
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    D4(%rip),%rax
  lea    D7(%rip),%rdi
  movaps %xmm0,0x20(%rsp)
  mov    %rax,0x30(%rsp)
  mov    D35(%rip),%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq 0xc(%rsp),%rbp
  cmp    $0x5,%ebp
  jg     L15
  mov    $0x5,%edx
  sub    %ebp,%edx
  mov    %rdx,%rax
  lea    0x4(,%rdx,4),%rdx
  neg    %rax
  shl    $0x2,%rax
  lea    0x14(%rbx,%rax,1),%rsi
  lea    0x20(%rbx,%rax,1),%rdi
  call   <memmove@plt>
L15:
  movdqa 0x10(%rsp),%xmm1
  lea    0x44(%rsp),%r12
  movups %xmm1,(%rbx,%rbp,4)
  lea    D48(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x1c0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
datatype: byte[16]
name: read_data
arguments: label: D4
datatype: byte[8]
name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D35
datatype: byte[8]
name: read_data
arguments: label: D48
datatype: string

tool: {"D6": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D4": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D7: %d

tool: {"D35": [0x0a,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: D48: %d


assistant: ```c
int main() {
  int source[100] = {1, 2, 3, 4, 5, 6};
  int dest[] = {10, 20, 30};
  int N = 6;
  int M = sizeof(dest) / sizeof(dest)[0];
  int k;
  scanf("%d", &k);
  for (int i = (N - 1); i >= k; i--) {
    source[i + M] = source[i];
  }
  for (int i = 0; i <= M; i++) {
    source[i + k] = dest[i];
  }
  for (int i = 0; i < M + N; i++) {
    printf("%d\n", source[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<make_macro_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L30
L65:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L97
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L84
L97:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L84:
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x5f,(%rax)
  jmp    L45
L22:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L55
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L80
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L53
L80:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L53
L55:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x5f,(%rax)
L53:
  addq   $0x1,-0x20(%rbp)
L45:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void make_macro_name(char *to, char *from) {
  char *f;
  for (f = from; *f; f++)
    if (*f == '/' || *f == '\\')
      from = f + 1;
  *to++ = '_';
  for (; *from; ++from)
    if (isalnum(*from))
      if (islower(*from))
        *to++ = toupper(*from);
      else
        *to++ = *from;
    else
      *to++ = '_';
  *to = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<make_macro_name>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  movzbl (%rsi),%eax
  test   %al,%al
  je     L34
  lea    0x1(%rsi),%rdx
  jmp    L60
L44:
  mov    %rdx,%rbp
L72:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L34
L60:
  cmp    $0x2f,%al
  je     L44
  cmp    $0x5c,%al
  jne    L72
  jmp    L44
L34:
  lea    0x1(%rdi),%rcx
  movb   $0x5f,(%rdi)
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L76
  lea    0x2(%rdi),%rbx
  mov    $0x5f,%r12d
  jmp    L18
L92:
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  mov    %rbx,%rcx
L93:
  mov    %al,-0x1(%rbx)
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L76
L18:
  movsbl %al,%edi
  call   <isalnum@plt>
  mov    %rax,%rdx
  mov    %rbx,%rcx
  mov    %r12d,%eax
  test   %rdx,%rdx
  je     L93
  movsbl 0x0(%rbp),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L92
  mov    %rbx,%rcx
  movzbl 0x0(%rbp),%eax
  jmp    L93
L76:
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void make_macro_name(char *to, char *from) {
  char *f;
  for (f = from; *f; f++)
    if (*f == '/' || *f == '\\')
      from = f + 1;
  *to++ = '_';
  for (; *from; ++from)
    if (isalnum(*from))
      if (islower(*from))
        *to++ = toupper(*from);
      else
        *to++ = *from;
    else
      *to++ = '_';
  *to = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<make_macro_name>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L89
  jmp    L125
  cs nopw 0x0(%rax,%rax,1)
L5:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L125
L89:
  add    $0x1,%rsi
  cmp    $0x2f,%al
  je     L79
  cmp    $0x5c,%al
  jne    L5
L79:
  movzbl (%rsi),%eax
  mov    %rsi,%rbx
  test   %al,%al
  jne    L89
L125:
  movb   $0x5f,(%rdi)
  lea    0x1(%rdi),%rbp
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L41
  jmp    L45
  xchg   %ax,%ax
L34:
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L45
L41:
  call   <isalnum@plt>
  add    $0x1,%rbp
  mov    %rax,%r8
  mov    $0x5f,%eax
  test   %r8,%r8
  je     L34
  movsbl (%rbx),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L4
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L41
L45:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L4:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  jmp    L34
```

assistant: ```c
void make_macro_name(char *to, char *from) {
  char *f;
  for (f = from; *f; f++)
    if (*f == '/' || *f == '\\')
      from = f + 1;
  *to++ = '_';
  for (; *from; ++from)
    if (isalnum(*from))
      if (islower(*from))
        *to++ = toupper(*from);
      else
        *to++ = *from;
    else
      *to++ = '_';
  *to = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<make_macro_name>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L100
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L102:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L52
L100:
  add    $0x1,%rsi
  cmp    $0x5c,%al
  je     L20
  cmp    $0x2f,%al
  jne    L102
L20:
  movzbl (%rsi),%eax
  mov    %rsi,%rbx
  test   %al,%al
  jne    L100
L52:
  movb   $0x5f,(%rdi)
  lea    0x1(%rdi),%rbp
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L49
  jmp    L26
  xchg   %ax,%ax
L1:
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L26
L49:
  call   <isalnum@plt>
  add    $0x1,%rbp
  mov    %rax,%r8
  mov    $0x5f,%eax
  test   %r8,%r8
  je     L1
  movsbl (%rbx),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L29
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L49
L26:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L29:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  jmp    L1
```

assistant: ```c
void make_macro_name(char *to, char *from) {
  char *f;
  for (f = from; *f; f++)
    if (*f == '/' || *f == '\\')
      from = f + 1;
  *to++ = '_';
  for (; *from; ++from)
    if (isalnum(*from))
      if (islower(*from))
        *to++ = toupper(*from);
      else
        *to++ = *from;
    else
      *to++ = '_';
  *to = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swoole_strtolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L0:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x10(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void swoole_strtolower(char *str, int length) {
  char *c, *e;
  c = str;
  e = c + length;
  while (c < e) {
    *c = tolower(*c);
    c++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swoole_strtolower>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movslq %esi,%rbp
  add    %rdi,%rbp
  cmp    %rbp,%rdi
  jae    L5
L10:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L10
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void swoole_strtolower(char *str, int length) {
  char *c, *e;
  c = str;
  e = c + length;
  while (c < e) {
    *c = tolower(*c);
    c++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swoole_strtolower>:
  endbr64
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  add    %rdi,%rbp
  sub    $0x8,%rsp
  cmp    %rbp,%rdi
  jae    L18
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L19:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%rbp
  jne    L19
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void swoole_strtolower(char *str, int length) {
  char *c, *e;
  c = str;
  e = c + length;
  while (c < e) {
    *c = tolower(*c);
    c++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swoole_strtolower>:
  endbr64
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  add    %rdi,%rbp
  sub    $0x8,%rsp
  cmp    %rbp,%rdi
  jae    L12
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%rbp
  jne    L17
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void swoole_strtolower(char *str, int length) {
  char *c, *e;
  c = str;
  e = c + length;
  while (c < e) {
    *c = tolower(*c);
    c++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_get_tap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L15
  mov    $0x0,%eax
  jmp    L33
L13:
  shll   $0x8,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L16
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cmp    %eax,-0x4(%rbp)
  jg     L13
L16:
  mov    -0xc(%rbp),%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int hash_get_tap(int usr_num) {
  int tap = 0;
  int temp = 1;
  int tap_max = sizeof(int) / sizeof(char);
  if (usr_num <= 0)
    return 0;
  while (temp < usr_num && tap++ < tap_max)
    temp = temp << 8;
  return tap;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash_get_tap>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L17
  mov    $0x1,%eax
  mov    $0x1,%edx
L2:
  shl    $0x8,%edx
  cmp    %edx,%edi
  jle    L17
  add    $0x1,%eax
  cmp    $0x5,%eax
  jne    L2
L17:
  ret
```

assistant: ```c
int hash_get_tap(int usr_num) {
  int tap = 0;
  int temp = 1;
  int tap_max = sizeof(int) / sizeof(char);
  if (usr_num <= 0)
    return 0;
  while (temp < usr_num && tap++ < tap_max)
    temp = temp << 8;
  return tap;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_get_tap>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L25
  mov    $0x1,%eax
  mov    $0x1,%edx
L2:
  shl    $0x8,%edx
  cmp    %edx,%edi
  jle    L25
  add    $0x1,%eax
  cmp    $0x5,%eax
  jne    L2
L25:
  ret
```

assistant: ```c
int hash_get_tap(int usr_num) {
  int tap = 0;
  int temp = 1;
  int tap_max = sizeof(int) / sizeof(char);
  if (usr_num <= 0)
    return 0;
  while (temp < usr_num && tap++ < tap_max)
    temp = temp << 8;
  return tap;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_get_tap>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L24
  cmp    $0x100,%edi
  jle    L27
  cmp    $0x10000,%edi
  jle    L21
  xor    %eax,%eax
  cmp    $0x1000000,%edi
  setg   %al
  lea    0x3(%rax,%rax,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0x2,%eax
L24:
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int hash_get_tap(int usr_num) {
  int tap = 0;
  int temp = 1;
  int tap_max = sizeof(int) / sizeof(char);
  if (usr_num <= 0)
    return 0;
  while (temp < usr_num && tap++ < tap_max)
    temp = temp << 8;
  return tap;
}
```