ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_next_line>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  mov    $0x1001,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L54
  xor    %edx,%edx
  mov    $0x1001,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <buffer_clean@plt>
  xor    %ebp,%ebp
  mov    $0x1,%r13d
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L78:
  mov    %bl,(%r12,%rbp,1)
  add    $0x1,%rbp
L76:
  mov    %r14d,%edi
  call   <get_char@plt>
  mov    %eax,%ebx
  cmp    $0xff,%al
  je     L6
  test   %al,%al
  je     L85
  cmp    $0xa,%al
  je     L85
  mov    %r13d,%esi
  shl    $0xc,%esi
  cmp    %ebp,%esi
  jg     L78
  mov    %r12,%rdi
  add    $0x1001,%esi
  add    $0x1,%r13d
  call   <my_realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L78
L54:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L6:
  cmpb   $0x0,(%r12)
  je     L33
L85:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10d0 <my_dup_free@plt>
L33:
  mov    %r12,%rdi
  call   <free@plt>
  jmp    L54
```

assistant: ```c
char *get_next_line(const int fd) {
  char *buffer;
  int i;
  int j;
  char c;
  if ((buffer = malloc(sizeof(char) * (4096 + 1))) == NULL)
    return (NULL);
  i = 0;
  j = 1;
  buffer_clean(buffer, 4096 + 1, 0);
  while ((c = get_char(fd)) != -1 && c != '\0' && c != '\n') {
    if (i >= (j * 4096))
      if ((buffer = my_realloc(buffer, sizeof(char) * ((++j * 4096) + 1))) == NULL)
        return (NULL);
    buffer[i++] = c;
  }
  if (c == -1 && buffer[0] == '\0') {
    free(buffer);
    return (NULL);
  }
  return (my_dup_free(buffer));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_next_line>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  mov    $0x1001,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L67
  xor    %edx,%edx
  mov    $0x1001,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <buffer_clean@plt>
  xor    %ebp,%ebp
  mov    $0x1,%r13d
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %bl,(%r12,%rbp,1)
  add    $0x1,%rbp
L32:
  mov    %r14d,%edi
  call   <get_char@plt>
  mov    %eax,%ebx
  cmp    $0xff,%al
  je     L79
  test   %al,%al
  je     L54
  cmp    $0xa,%al
  je     L54
  mov    %r13d,%esi
  shl    $0xc,%esi
  cmp    %ebp,%esi
  jg     L37
  mov    %r12,%rdi
  add    $0x1001,%esi
  add    $0x1,%r13d
  call   <my_realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L37
L67:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L79:
  cmpb   $0x0,(%r12)
  je     L63
L54:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10d0 <my_dup_free@plt>
L63:
  mov    %r12,%rdi
  call   <free@plt>
  jmp    L67
```

assistant: ```c
char *get_next_line(const int fd) {
  char *buffer;
  int i;
  int j;
  char c;
  if ((buffer = malloc(sizeof(char) * (4096 + 1))) == NULL)
    return (NULL);
  i = 0;
  j = 1;
  buffer_clean(buffer, 4096 + 1, 0);
  while ((c = get_char(fd)) != -1 && c != '\0' && c != '\n') {
    if (i >= (j * 4096))
      if ((buffer = my_realloc(buffer, sizeof(char) * ((++j * 4096) + 1))) == NULL)
        return (NULL);
    buffer[i++] = c;
  }
  if (c == -1 && buffer[0] == '\0') {
    free(buffer);
    return (NULL);
  }
  return (my_dup_free(buffer));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_filename_ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L37
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isascii@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x0,%eax
  jmp    L17
L16:
  addl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L34
  mov    $0x1,%eax
L17:
  leave
  ret
```

assistant: ```c
int is_filename_ascii(const char *s) {
  int i, len;
  len = strlen(s);
  for (i = 0; i < len; i++) {
    if (isascii(s[i]) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_filename_ascii>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L11
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rbp
L47:
  movsbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L20
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L47
  mov    $0x1,%eax
  jmp    L32
L11:
  mov    $0x1,%eax
  jmp    L32
L20:
  mov    $0x0,%eax
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_filename_ascii(const char *s) {
  int i, len;
  len = strlen(s);
  for (i = 0; i < len; i++) {
    if (isascii(s[i]) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_filename_ascii>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L35
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  jmp    L1
L0:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L35
L1:
  movsbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L35:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_filename_ascii(const char *s) {
  int i, len;
  len = strlen(s);
  for (i = 0; i < len; i++) {
    if (isascii(s[i]) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_filename_ascii>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L6
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  jmp    L9
L1:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L6
L9:
  movsbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L6:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_filename_ascii(const char *s) {
  int i, len;
  len = strlen(s);
  for (i = 0; i < len; i++) {
    if (isascii(s[i]) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f77_return>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f77_return(int stat) {
  int new_status;
  new_status = stat;
  return (int)new_status;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f77_return>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f77_return(int stat) {
  int new_status;
  new_status = stat;
  return (int)new_status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f77_return>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f77_return(int stat) {
  int new_status;
  new_status = stat;
  return (int)new_status;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f77_return>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f77_return(int stat) {
  int new_status;
  new_status = stat;
  return (int)new_status;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x1,-0x18(%rbp)
  jmp    L39
L24:
  movq   $0x1,-0x20(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L38
L31:
  mov    -0x20(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  addq   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jle    L31
  mov    -0x20(%rbp),%rax
  add    %rax,-0x28(%rbp)
  addq   $0x1,-0x18(%rbp)
L39:
  mov    -0x30(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jle    L24
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: %lld

assistant: ```c
int main(int argc, const char *argv[]) {
  long long result = 0, sum, i, j, n;
  scanf("%lld", &n);
  for (i = 1; i <= n; i++) {
    sum = 1;
    for (j = 1; j <= i; j++) {
      sum *= j;
    }
    result += sum;
  }
  printf("%lld", result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r8
  test   %r8,%r8
  jle    L13
  add    $0x2,%r8
  mov    $0x2,%ecx
  mov    $0x0,%esi
  jmp    L41
L31:
  imul   %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L31
L8:
  add    %rdx,%rsi
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L7
L41:
  lea    -0x1(%rcx),%rdi
  mov    $0x1,%eax
  mov    $0x1,%edx
  test   %rdi,%rdi
  jg     L31
  jmp    L8
L13:
  mov    $0x0,%esi
L7:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D11: %lld

assistant: ```c
int main(int argc, const char *argv[]) {
  long long result = 0, sum, i, j, n;
  scanf("%lld", &n);
  for (i = 1; i <= n; i++) {
    sum = 1;
    for (j = 1; j <= i; j++) {
      sum *= j;
    }
    result += sum;
  }
  printf("%lld", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  jle    L3
  add    $0x2,%rdi
  mov    $0x2,%ecx
  xor    %esi,%esi
  nop
L25:
  mov    $0x1,%eax
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L33:
  imul   %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L33
  add    $0x1,%rcx
  add    %rdx,%rsi
  cmp    %rdi,%rcx
  jne    L25
L37:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  xor    %esi,%esi
  jmp    L37
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D0: %lld

assistant: ```c
int main(int argc, const char *argv[]) {
  long long result = 0, sum, i, j, n;
  scanf("%lld", &n);
  for (i = 1; i <= n; i++) {
    sum = 1;
    for (j = 1; j <= i; j++) {
      sum *= j;
    }
    result += sum;
  }
  printf("%lld", result);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  jle    L35
  add    $0x2,%rdi
  mov    $0x2,%ecx
  xor    %esi,%esi
  nop
L7:
  mov    $0x1,%eax
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L0:
  imul   %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L0
  add    $0x1,%rcx
  add    %rdx,%rsi
  cmp    %rdi,%rcx
  jne    L7
L9:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L35:
  xor    %esi,%esi
  jmp    L9
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: %lld

assistant: ```c
int main(int argc, const char *argv[]) {
  long long result = 0, sum, i, j, n;
  scanf("%lld", &n);
  for (i = 1; i <= n; i++) {
    sum = 1;
    for (j = 1; j <= i; j++) {
      sum *= j;
    }
    result += sum;
  }
  printf("%lld", result);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mov_preg32pimm32_reg16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    $0x66,%edi
  call   <put8@plt>
  mov    $0x89,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  or     $0x80,%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  or     %edx,%eax
  mov    %eax,%edi
  call   <put8@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void mov_preg32pimm32_reg16(int reg32, unsigned long imm32, int reg16) {
  put8(0x66);
  put8(0x89);
  put8(0x80 | reg32 | (reg16 << 3));
  put32(imm32);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mov_preg32pimm32_reg16>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    $0x66,%edi
  call   <put8@plt>
  mov    $0x89,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %r12d,%edi
  or     $0x80,%dil
  call   <put8@plt>
  mov    %rbp,%rdi
  call   <put32@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mov_preg32pimm32_reg16(int reg32, unsigned long imm32, int reg16) {
  put8(0x66);
  put8(0x89);
  put8(0x80 | reg32 | (reg16 << 3));
  put32(imm32);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mov_preg32pimm32_reg16>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x66,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <put8@plt>
  mov    $0x89,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %r12d,%edi
  or     $0x80,%dil
  call   <put8@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <put32@plt>
```

assistant: ```c
void mov_preg32pimm32_reg16(int reg32, unsigned long imm32, int reg16) {
  put8(0x66);
  put8(0x89);
  put8(0x80 | reg32 | (reg16 << 3));
  put32(imm32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mov_preg32pimm32_reg16>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x66,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <put8@plt>
  mov    $0x89,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %r12d,%edi
  or     $0x80,%dil
  call   <put8@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <put32@plt>
```

assistant: ```c
void mov_preg32pimm32_reg16(int reg32, unsigned long imm32, int reg16) {
  put8(0x66);
  put8(0x89);
  put8(0x80 | reg32 | (reg16 << 3));
  put32(imm32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x74736574,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  lea    D36(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x12(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0x0,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D36
type_infered: string
name: unpack_data
arguments: data_tag: D37
type_infered: string

tool: D36: testtesttest

tool: D37: strnlen(%s, 10) is %zu


assistant: ```c
int main(int argc, char *argv[]) {
  char str1[10] = "test";
  char *str2 = "testtesttest";
  size_t ret = strnlen(str1, 10);
  printf("strnlen(%s, 10) is %zu\n", str1, ret);
  ret = strnlen(str2, 10);
  printf("strnlen(%s, 10) is %zu\n", str2, ret);
  str2 = NULL;
  ret = strnlen(str2, 10);
  printf("strnlen(%s, 10) is %zu\n", str2, ret);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x74736574,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  lea    0xe(%rsp),%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <strnlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D18(%rip),%rbp
  mov    %rbp,%rdi
  call   <strnlen@plt>
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <strnlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string
name: unpack_data
arguments: data_tag: D18
type_infered: string

tool: D4: strnlen(%s, 10) is %zu


tool: D18: testtesttest

assistant: ```c
int main(int argc, char *argv[]) {
  char str1[10] = "test";
  char *str2 = "testtesttest";
  size_t ret = strnlen(str1, 10);
  printf("strnlen(%s, 10) is %zu\n", str1, ret);
  ret = strnlen(str2, 10);
  printf("strnlen(%s, 10) is %zu\n", str2, ret);
  str2 = NULL;
  ret = strnlen(str2, 10);
  printf("strnlen(%s, 10) is %zu\n", str2, ret);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  lea    D11(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  xor    %eax,%eax
  movq   $0x74736574,0xe(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x16(%rsp)
  call   <strnlen@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rbp
  mov    %rax,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <strnlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  xor    %edi,%edi
  mov    $0xa,%esi
  call   <strnlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string

tool: D11: testtesttest

tool: D3: strnlen(%s, 10) is %zu


assistant: ```c
int main(int argc, char *argv[]) {
  char str1[10] = "test";
  char *str2 = "testtesttest";
  size_t ret = strnlen(str1, 10);
  printf("strnlen(%s, 10) is %zu\n", str1, ret);
  ret = strnlen(str2, 10);
  printf("strnlen(%s, 10) is %zu\n", str2, ret);
  str2 = NULL;
  ret = strnlen(str2, 10);
  printf("strnlen(%s, 10) is %zu\n", str2, ret);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  lea    D17(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  xor    %eax,%eax
  movq   $0x74736574,0xe(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x16(%rsp)
  call   <strnlen@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rbp
  mov    %rax,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <strnlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  xor    %edi,%edi
  mov    $0xa,%esi
  call   <strnlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string

tool: D17: testtesttest

tool: D10: strnlen(%s, 10) is %zu


assistant: ```c
int main(int argc, char *argv[]) {
  char str1[10] = "test";
  char *str2 = "testtesttest";
  size_t ret = strnlen(str1, 10);
  printf("strnlen(%s, 10) is %zu\n", str1, ret);
  ret = strnlen(str2, 10);
  printf("strnlen(%s, 10) is %zu\n", str2, ret);
  str2 = NULL;
  ret = strnlen(str2, 10);
  printf("strnlen(%s, 10) is %zu\n", str2, ret);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L7:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  char *cp = dest;
  while ((*cp++ = *src++))
    ;
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L1:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L1
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  char *cp = dest;
  while ((*cp++ = *src++))
    ;
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L3:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L3
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  char *cp = dest;
  while ((*cp++ = *src++))
    ;
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L7:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L7
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  char *cp = dest;
  while ((*cp++ = *src++))
    ;
  return dest;
}
```