ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_prime>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L31
  test   $0x1,%dil
  je     L28
  mov    $0x2,%ecx
  jmp    L6
  nop
L32:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L36
L6:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jle    L32
L31:
  mov    $0x1,%edx
L36:
  mov    %edx,%eax
  ret
L28:
  xor    %edx,%edx
  jmp    L36
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i <= num / 2; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readvar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    D19(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D46(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x6c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x50(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L49:
  cmp    %rdx,%rsp
  je     L35
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L49
L35:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L0
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L0:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x48(%rbp)
  movl   $0x5,-0x54(%rbp)
  jmp    L8
L52:
  mov    -0x6c(%rbp),%ecx
  mov    -0x54(%rbp),%edx
  lea    -0x40(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <is_c_type@plt>
  test   %rax,%rax
  je     L8
  mov    -0x6c(%rbp),%edx
  mov    -0x68(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getword@plt>
  jmp    L44
L8:
  mov    -0x6c(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getword@plt>
  test   %eax,%eax
  jg     L52
  mov    $0x0,%eax
L44:
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type: string
name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D46
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D19: short

tool: D28: int

tool: D30: float

tool: D46: double

tool: D16: void

assistant: ```c
int readvar(char *var, int maxlen) {
  char *types[] = {"short", "int", "float", "double", "void"};
  char word[maxlen];
  int type_len = sizeof(types) / sizeof(char *);
  while (getword(word, maxlen) > 0) {
    if (is_c_type(word, types, type_len, maxlen)) {
      return getword(var, maxlen);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readvar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D36(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D43(%rip),%rax
  mov    %rax,-0x30(%rbp)
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L56:
  cmp    %rdx,%rsp
  je     L65
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L56
L65:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L1
  orq    $0x0,-0x8(%rsp,%rax,1)
L1:
  mov    %rsp,%r12
  lea    -0x50(%rbp),%r13
L45:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <getword@plt>
  test   %eax,%eax
  jle    L60
  mov    %ebx,%ecx
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <is_c_type@plt>
  test   %rax,%rax
  je     L45
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <getword@plt>
  jmp    L6
L60:
  mov    $0x0,%eax
L6:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
type: string
name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D36
type: string
name: read_data
arguments: label: D33
type: string
name: read_data
arguments: label: D43
type: string

tool: D5: short

tool: D3: int

tool: D36: float

tool: D33: double

tool: D43: void

assistant: ```c
int readvar(char *var, int maxlen) {
  char *types[] = {"short", "int", "float", "double", "void"};
  char word[maxlen];
  int type_len = sizeof(types) / sizeof(char *);
  while (getword(word, maxlen) > 0) {
    if (is_c_type(word, types, type_len, maxlen)) {
      return getword(var, maxlen);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readvar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  lea    D41(%rip),%rax
  mov    %rsp,%rcx
  mov    %rax,-0x50(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D39(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,-0x30(%rbp)
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L46
L14:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L14
L46:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L68
L78:
  mov    %rsp,%rbx
  lea    -0x50(%rbp),%r13
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %r12d,%ecx
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <is_c_type@plt>
  test   %rax,%rax
  jne    L26
L51:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <getword@plt>
  test   %eax,%eax
  jg     L73
  xor    %eax,%eax
L11:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L65
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   (%rax)
L26:
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <getword@plt>
  jmp    L11
  nopl   (%rax)
L68:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L78
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D41
datatype: string
name: read_data
arguments: label: D38
datatype: string
name: read_data
arguments: label: D33
datatype: string
name: read_data
arguments: label: D39
datatype: string
name: read_data
arguments: label: D35
datatype: string

tool: D41: short

tool: D38: int

tool: D33: float

tool: D39: double

tool: D35: void

assistant: ```c
int readvar(char *var, int maxlen) {
  char *types[] = {"short", "int", "float", "double", "void"};
  char word[maxlen];
  int type_len = sizeof(types) / sizeof(char *);
  while (getword(word, maxlen) > 0) {
    if (is_c_type(word, types, type_len, maxlen)) {
      return getword(var, maxlen);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readvar>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rcx
  lea    D15(%rip),%rdx
  movq   %rcx,%xmm0
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  lea    D21(%rip),%rax
  mov    %rsp,%rcx
  movq   %rax,%xmm1
  lea    D1(%rip),%rax
  movq   %rax,%xmm2
  lea    D37(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  mov    %rax,-0x30(%rbp)
  movslq %esi,%rax
  add    $0xf,%rax
  movaps %xmm0,-0x50(%rbp)
  movq   %rdx,%xmm0
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  punpcklqdq %xmm2,%xmm0
  sub    %rax,%rcx
  movaps %xmm0,-0x40(%rbp)
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L0
L60:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L60
L0:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L55
L76:
  mov    %rsp,%rbx
  lea    -0x50(%rbp),%r13
  jmp    L45
  nopl   0x0(%rax)
L30:
  mov    %r12d,%ecx
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <is_c_type@plt>
  test   %rax,%rax
  jne    L11
L45:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <getword@plt>
  test   %eax,%eax
  jg     L30
  xor    %eax,%eax
L17:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   (%rax)
L11:
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <getword@plt>
  jmp    L17
  nopl   (%rax)
L55:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L76
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
data_type: string
name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D21
data_type: string
name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D37
data_type: string

tool: D19: short

tool: D15: float

tool: D21: int

tool: D1: double

tool: D37: void

assistant: ```c
int readvar(char *var, int maxlen) {
  char *types[] = {"short", "int", "float", "double", "void"};
  char word[maxlen];
  int type_len = sizeof(types) / sizeof(char *);
  while (getword(word, maxlen) > 0) {
    if (is_c_type(word, types, type_len, maxlen)) {
      return getword(var, maxlen);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x90(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x10,0x8(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%r10
  mov    $0x21,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x1b,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x39,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x43,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x11,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x57,%edi
  call   <add.0>
  mov    $0x5b,%edi
  call   <putchar@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L5
  mov    $0x1,%ebx
  lea    D0(%rip),%rbp
L2:
  movslq %ebx,%rdx
  mov    (%rsp),%rax
  mov    (%rax,%rdx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jge    L2
L5:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string
name: read_data
arguments: tag: D15
type_guessed: string

tool: D0: %d, 

tool: D15: ]


assistant: ```c
int main(int argc, char *argv[]) {
  int heapItems = 0;
  int heapSize = 16;
  int minHeap[heapSize];
  int upHeap(int x) {
    if (x == 1) {
      return 0;
    }
    if (minHeap[parent(x)] <= minHeap[x]) {
      return 0;
    }
    int temp = minHeap[x];
    minHeap[x] = minHeap[parent(x)];
    minHeap[parent(x)] = temp;
    upHeap(parent(x));
    return 0;
  }
  int add(int value) {
    if (heapItems == 0) {
      minHeap[1] = value;
      ++heapItems;
      return 0;
    }
    if ((heapItems + 1) == heapSize) {
    }
    ++heapItems;
    minHeap[heapItems] = value;
    upHeap(heapItems);
    return 0;
  }
  add(33);
  add(27);
  add(57);
  add(67);
  add(17);
  add(87);
  printf("[");
  int i = 1;
  for (; i <= heapItems; ++i) {
    printf("%d, ", minHeap[i]);
  }
  printf("]\n\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x21,%edi
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x90(%rsp),%rax
  movq   $0x10,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rbx,%r10
  lea    0x20(%rsp),%rax
  mov    %rax,(%rsp)
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x1b,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x39,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x43,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x11,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x57,%edi
  call   <add.0>
  mov    $0x5b,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L16
  mov    $0x1,%ebx
  lea    D8(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rsp),%rax
  movslq %ebx,%rdx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    (%rax,%rdx,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L18
L16:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D8: %d, 

tool: D4: ]


assistant: ```c
int main(int argc, char *argv[]) {
  int heapItems = 0;
  int heapSize = 16;
  int minHeap[heapSize];
  int upHeap(int x) {
    if (x == 1) {
      return 0;
    }
    if (minHeap[parent(x)] <= minHeap[x]) {
      return 0;
    }
    int temp = minHeap[x];
    minHeap[x] = minHeap[parent(x)];
    minHeap[parent(x)] = temp;
    upHeap(parent(x));
    return 0;
  }
  int add(int value) {
    if (heapItems == 0) {
      minHeap[1] = value;
      ++heapItems;
      return 0;
    }
    if ((heapItems + 1) == heapSize) {
    }
    ++heapItems;
    minHeap[heapItems] = value;
    upHeap(heapItems);
    return 0;
  }
  add(33);
  add(27);
  add(57);
  add(67);
  add(17);
  add(87);
  printf("[");
  int i = 1;
  for (; i <= heapItems; ++i) {
    printf("%d, ", minHeap[i]);
  }
  printf("]\n\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x21,%edi
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x90(%rsp),%rax
  mov    %rsp,%rbx
  mov    %rax,0x10(%rsp)
  mov    D14(%rip),%rax
  mov    %rbx,%r10
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,(%rsp)
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x1b,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x39,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x43,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x11,%edi
  call   <add.0>
  mov    %rbx,%r10
  mov    $0x57,%edi
  call   <add.0>
  mov    $0x5b,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L8
  mov    $0x1,%ebx
  lea    D11(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rsp),%rax
  movslq %ebx,%rdx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    (%rax,%rdx,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L4
L8:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D23
type_guessed: string

tool: {"D14": [0x10,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D11: %d, 

tool: D23: ]


assistant: ```c
int main(int argc, char *argv[]) {
  int heapItems = 0;
  int heapSize = 16;
  int minHeap[heapSize];
  int upHeap(int x) {
    if (x == 1) {
      return 0;
    }
    if (minHeap[parent(x)] <= minHeap[x]) {
      return 0;
    }
    int temp = minHeap[x];
    minHeap[x] = minHeap[parent(x)];
    minHeap[parent(x)] = temp;
    upHeap(parent(x));
    return 0;
  }
  int add(int value) {
    if (heapItems == 0) {
      minHeap[1] = value;
      ++heapItems;
      return 0;
    }
    if ((heapItems + 1) == heapSize) {
    }
    ++heapItems;
    minHeap[heapItems] = value;
    upHeap(heapItems);
    return 0;
  }
  add(33);
  add(27);
  add(57);
  add(67);
  add(17);
  add(87);
  printf("[");
  int i = 1;
  for (; i <= heapItems; ++i) {
    printf("%d, ", minHeap[i]);
  }
  printf("]\n\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fmt_100percent_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x61,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x62,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x63,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movb   $0x64,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *fmt_100percent_8(char pbuf[8]) {
  pbuf[0] = 'a';
  pbuf[1] = 'b';
  pbuf[2] = 'c';
  pbuf[3] = 'd';
  return pbuf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fmt_100percent_8>:
  endbr64
  mov    %rdi,%rax
  movb   $0x61,(%rdi)
  movb   $0x62,0x1(%rdi)
  movb   $0x63,0x2(%rdi)
  movb   $0x64,0x3(%rdi)
  ret
```

assistant: ```c
char *fmt_100percent_8(char pbuf[8]) {
  pbuf[0] = 'a';
  pbuf[1] = 'b';
  pbuf[2] = 'c';
  pbuf[3] = 'd';
  return pbuf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fmt_100percent_8>:
  endbr64
  movl   $0x64636261,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *fmt_100percent_8(char pbuf[8]) {
  pbuf[0] = 'a';
  pbuf[1] = 'b';
  pbuf[2] = 'c';
  pbuf[3] = 'd';
  return pbuf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fmt_100percent_8>:
  endbr64
  movl   $0x64636261,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *fmt_100percent_8(char pbuf[8]) {
  pbuf[0] = 'a';
  pbuf[1] = 'b';
  pbuf[2] = 'c';
  pbuf[3] = 'd';
  return pbuf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ssl3_setup_buffers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ssl3_setup_read_buffer@plt>
  test   %eax,%eax
  jne    L36
  mov    $0x0,%eax
  jmp    L22
L36:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ssl3_setup_write_buffer@plt>
  test   %eax,%eax
  jne    L13
  mov    $0x0,%eax
  jmp    L22
L13:
  mov    $0x1,%eax
L22:
  leave
  ret
```

assistant: ```c
int ssl3_setup_buffers(SSL *s) {
  if (!ssl3_setup_read_buffer(s))
    return 0;
  if (!ssl3_setup_write_buffer(s))
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ssl3_setup_buffers>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ssl3_setup_read_buffer@plt>
  test   %eax,%eax
  jne    L11
L2:
  pop    %rbx
  ret
L11:
  mov    %rbx,%rdi
  call   <ssl3_setup_write_buffer@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L2
```

assistant: ```c
int ssl3_setup_buffers(SSL *s) {
  if (!ssl3_setup_read_buffer(s))
    return 0;
  if (!ssl3_setup_write_buffer(s))
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ssl3_setup_buffers>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <ssl3_setup_read_buffer@plt>
  test   %eax,%eax
  jne    L6
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  call   <ssl3_setup_write_buffer@plt>
  pop    %rbp
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ssl3_setup_buffers(SSL *s) {
  if (!ssl3_setup_read_buffer(s))
    return 0;
  if (!ssl3_setup_write_buffer(s))
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ssl3_setup_buffers>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <ssl3_setup_read_buffer@plt>
  test   %eax,%eax
  jne    L1
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  call   <ssl3_setup_write_buffer@plt>
  pop    %rbp
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ssl3_setup_buffers(SSL *s) {
  if (!ssl3_setup_read_buffer(s))
    return 0;
  if (!ssl3_setup_write_buffer(s))
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_src_iter_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L7
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_src_iter_inc_line@plt>
  jmp    L19
L7:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_src_iter_check_tab@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
void _src_iter_check(unsigned *line, unsigned *back_column, const char *current, unsigned tab_size) {
  if ('\n' == *current)
    _src_iter_inc_line(line, back_column, current);
  else
    _src_iter_check_tab(back_column, current, tab_size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_src_iter_check>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  cmpb   $0xa,(%rdx)
  je     L13
  mov    %ecx,%edx
  call   <_src_iter_check_tab@plt>
L7:
  add    $0x8,%rsp
  ret
L13:
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <_src_iter_inc_line@plt>
  jmp    L7
```

assistant: ```c
void _src_iter_check(unsigned *line, unsigned *back_column, const char *current, unsigned tab_size) {
  if ('\n' == *current)
    _src_iter_inc_line(line, back_column, current);
  else
    _src_iter_check_tab(back_column, current, tab_size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_src_iter_check>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  cmpb   $0xa,(%rsi)
  je     L2
  jmp    1070 <_src_iter_check_tab@plt>
  nopl   0x0(%rax)
L2:
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  mov    %r8,%rdi
  jmp    1060 <_src_iter_inc_line@plt>
```

assistant: ```c
void _src_iter_check(unsigned *line, unsigned *back_column, const char *current, unsigned tab_size) {
  if ('\n' == *current)
    _src_iter_inc_line(line, back_column, current);
  else
    _src_iter_check_tab(back_column, current, tab_size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_src_iter_check>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  cmpb   $0xa,(%rsi)
  je     L3
  jmp    1070 <_src_iter_check_tab@plt>
  nopl   0x0(%rax)
L3:
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  mov    %r8,%rdi
  jmp    1060 <_src_iter_inc_line@plt>
```

assistant: ```c
void _src_iter_check(unsigned *line, unsigned *back_column, const char *current, unsigned tab_size) {
  if ('\n' == *current)
    _src_iter_inc_line(line, back_column, current);
  else
    _src_iter_check_tab(back_column, current, tab_size);
}
```