user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<merge>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  sub    %esi,%r15d
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    0x4(,%r15,4),%edi
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %r15d,%r15d
  js     L86
  movslq %r15d,%r15
  mov    %r14d,%edx
  lea    0x4(%rax,%r15,4),%r8
  jmp    L152
  nopl   0x0(%rax,%rax,1)
L58:
  test   %sil,%sil
  je     L16
  movslq %edx,%rcx
  mov    (%r12,%rcx,4),%esi
  movslq %ebx,%rcx
  mov    (%r12,%rcx,4),%ecx
  cmp    %ecx,%esi
  jg     L30
  mov    %esi,(%rax)
  add    $0x1,%edx
L205:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L86
L152:
  cmp    %edx,%r13d
  setge  %cl
  cmp    %ebp,%ebx
  setle  %sil
  test   %cl,%cl
  jne    L58
L16:
  cmp    %ebp,%ebx
  jle    L18
  test   %cl,%cl
  je     L18
  movslq %edx,%rcx
  add    $0x4,%rax
  add    $0x1,%edx
  mov    (%r12,%rcx,4),%ecx
  mov    %ecx,-0x4(%rax)
  cmp    %r8,%rax
  jne    L152
  nop
L86:
  cmp    %ebp,%r14d
  jg     L63
  movslq %r14d,%rdx
  lea    0x4(%rdi),%r9
  mov    %ebp,%esi
  mov    %rdi,%rax
  shl    $0x2,%rdx
  sub    %r14d,%esi
  lea    (%r12,%rdx,1),%rcx
  mov    %rcx,%r8
  sub    %r9,%r8
  cmp    $0x8,%r8
  jbe    L44
  cmp    $0x2,%esi
  jbe    L44
  add    $0x1,%esi
  sub    %rdi,%rcx
  mov    %esi,%edx
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L214:
  movdqu (%rax),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L214
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  add    %eax,%r14d
  cmp    %eax,%esi
  je     L63
  cltq
  mov    (%rdi,%rax,4),%ecx
  lea    0x0(,%rax,4),%rdx
  movslq %r14d,%rax
  mov    %ecx,(%r12,%rax,4)
  lea    0x1(%r14),%eax
  cmp    %eax,%ebp
  jl     L63
  mov    0x4(%rdi,%rdx,1),%ecx
  cltq
  add    $0x2,%r14d
  lea    0x0(,%rax,4),%rsi
  mov    %ecx,(%r12,%rax,4)
  cmp    %r14d,%ebp
  jl     L63
  mov    0x8(%rdi,%rdx,1),%eax
  mov    %eax,0x4(%r12,%rsi,1)
L63:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <free@plt>
L18:
  cmp    %edx,%r13d
  jge    L205
  test   %sil,%sil
  je     L205
  movslq %ebx,%rcx
  add    $0x1,%ebx
  mov    (%r12,%rcx,4),%ecx
  mov    %ecx,(%rax)
  jmp    L205
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %ecx,(%rax)
  add    $0x1,%ebx
  jmp    L205
  nopw   0x0(%rax,%rax,1)
L44:
  sub    %rdi,%rdx
  lea    0x4(%rdi,%rsi,4),%rcx
  add    %rdx,%r12
  nopl   0x0(%rax,%rax,1)
L143:
  mov    (%rax),%edx
  mov    %edx,(%r12,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L143
  jmp    L63
```

assistant: ```c
void merge(int *value, int lfirst, int lsecond, int rfirst, int rsecond) {
  int *m_temp;
  int itr = 0;
  int rep_itr;
  int left_sub = lfirst;
  int right_sub = rfirst;
  m_temp = (int *)malloc(sizeof(int) * (rsecond - lfirst + 1));
  for (itr = 0; itr <= (rsecond - left_sub); itr++) {
    if (lfirst <= lsecond && rfirst <= rsecond) {
      if (value[lfirst] <= value[rfirst])
        m_temp[itr] = value[lfirst++];
      else if (value[rfirst] <= value[lfirst])
        m_temp[itr] = value[rfirst++];
      continue;
    }
    if (lfirst <= lsecond && rfirst > rsecond) {
      m_temp[itr] = value[lfirst++];
      continue;
    }
    if (rfirst <= rsecond && lfirst > lsecond) {
      m_temp[itr] = value[rfirst++];
      continue;
    }
  }
  for (itr = 0, rep_itr = left_sub; rep_itr <= rsecond; rep_itr++, itr++) {
    value[rep_itr] = m_temp[itr];
  }
  free(m_temp);
}
```