ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<IncopyOut3>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <getchar@plt>
  mov    D7(%rip),%rbp
  cmp    0x0(%rbp),%eax
  je     L9
  xor    %ebx,%ebx
  jmp    L73
  nopl   0x0(%rax)
L64:
  cmp    $0xa,%eax
  je     L17
  mov    %eax,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
L31:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  je     L9
L73:
  cmp    $0x20,%eax
  jne    L64
  add    $0x1,%ebx
  cmp    $0x1,%ebx
  jne    L31
  mov    $0x20,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L73
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L17:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  jmp    L31
```

assistant: ```c
int IncopyOut3() {
  int ch;
  int n = 0;
  ch = getchar();
  while (ch != EOF) {
    if (ch == ' ') {
      n++;
      if (n <= 1)
        putchar(ch);
    } else if (ch == '\n') {
      putchar(ch);
      n = 0;
    } else {
      putchar(ch);
      n = 0;
    }
    ch = getchar();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L18
  mov    $0x1,%eax
  jmp    L13
L18:
  mov    $0xffffffff,%eax
L13:
  leave
  ret
```

assistant: ```c
int comp(char s2[10], char s3[10]) {
  if (strcmp(s2, s3) > 0)
    return 1;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<comp>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int comp(char s2[10], char s3[10]) {
  if (strcmp(s2, s3) > 0)
    return 1;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<comp>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int comp(char s2[10], char s3[10]) {
  if (strcmp(s2, s3) > 0)
    return 1;
  else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comp>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int comp(char s2[10], char s3[10]) {
  if (strcmp(s2, s3) > 0)
    return 1;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtrail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L38
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L53
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L53:
  mov    -0x18(%rbp),%rax
  mov    $0xd,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L49
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L49
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L49:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  jmp    L7
L38:
  nop
L7:
  leave
  ret
```

assistant: ```c
void strtrail(char *wrk) {
  char *p;
  if (wrk == NULL)
    return;
  if ((p = strchr(wrk, '\n')) != NULL)
    *p = 0;
  if ((p = strchr(wrk, '\r')) != NULL)
    *p = 0;
  while (isspace((int)*(wrk + strlen(wrk) - 1)))
    *(wrk + strlen(wrk) - 1) = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtrail>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L28
  movb   $0x0,(%rax)
L28:
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L49
  movb   $0x0,(%rax)
  jmp    L49
L36:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
L49:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L36
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
void strtrail(char *wrk) {
  char *p;
  if (wrk == NULL)
    return;
  if ((p = strchr(wrk, '\n')) != NULL)
    *p = 0;
  if ((p = strchr(wrk, '\r')) != NULL)
    *p = 0;
  while (isspace((int)*(wrk + strlen(wrk) - 1)))
    *(wrk + strlen(wrk) - 1) = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtrail>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbx
  mov    $0xa,%esi
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L42
  movb   $0x0,(%rax)
L42:
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L34
  movb   $0x0,(%rax)
  jmp    L34
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
L34:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L45
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void strtrail(char *wrk) {
  char *p;
  if (wrk == NULL)
    return;
  if ((p = strchr(wrk, '\n')) != NULL)
    *p = 0;
  if ((p = strchr(wrk, '\r')) != NULL)
    *p = 0;
  while (isspace((int)*(wrk + strlen(wrk) - 1)))
    *(wrk + strlen(wrk) - 1) = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtrail>:
  endbr64
  test   %rdi,%rdi
  je     L45
  push   %rbx
  mov    $0xa,%esi
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L30
  movb   $0x0,(%rax)
L30:
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L39
  movb   $0x0,(%rax)
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
L39:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  ret
```

assistant: ```c
void strtrail(char *wrk) {
  char *p;
  if (wrk == NULL)
    return;
  if ((p = strchr(wrk, '\n')) != NULL)
    *p = 0;
  if ((p = strchr(wrk, '\r')) != NULL)
    *p = 0;
  while (isspace((int)*(wrk + strlen(wrk) - 1)))
    *(wrk + strlen(wrk) - 1) = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<_is_ip4addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x3,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L74
L61:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L116
  mov    $0x0,%eax
  jmp    L43
L77:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L92
  addq   $0x1,-0x18(%rbp)
L116:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L77
  jmp    L83
L92:
  nop
L83:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L102
  addq   $0x1,-0x18(%rbp)
L102:
  movl   $0x2,-0x4(%rbp)
L74:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jne    L61
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L99
  mov    $0x0,%eax
  jmp    L43
L41:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L122
  addq   $0x1,-0x18(%rbp)
L99:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L41
  jmp    L119
L122:
  nop
L119:
  mov    -0x18(%rbp),%rax
L43:
  leave
  ret
```

assistant: ```c
char const *_is_ip4addr(char const *peek) {
  unsigned i = 3;
  unsigned j = 2;
  while (i-- > 0) {
    if (!isdigit(*peek++))
      return NULL;
    while (j-- > 0) {
      if (!isdigit(*peek))
        break;
      peek++;
    }
    if (*peek == '.')
      peek++;
    j = 2;
  }
  if (!isdigit(*peek++))
    return NULL;
  while (j-- > 0) {
    if (!isdigit(*peek))
      break;
    peek++;
  }
  return peek;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_is_ip4addr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x3,%ebp
L71:
  lea    0x1(%rbx),%r12
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L47
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L83
  lea    0x2(%rbx),%r12
  movsbl 0x2(%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L83
  add    $0x3,%rbx
L1:
  cmpb   $0x2e,(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  sub    $0x1,%ebp
  jne    L71
  lea    0x1(%rbx),%rbp
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L20
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L61
  movsbl 0x2(%rbx),%edi
  call   <isdigit@plt>
  cmp    $0x1,%eax
  sbb    $0xfffffffffffffffd,%rbx
  mov    %rbx,%rbp
L61:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L83:
  mov    %r12,%rbx
  jmp    L1
L47:
  mov    $0x0,%ebp
  jmp    L61
L20:
  mov    $0x0,%ebp
  jmp    L61
```

assistant: ```c
char const *_is_ip4addr(char const *peek) {
  unsigned i = 3;
  unsigned j = 2;
  while (i-- > 0) {
    if (!isdigit(*peek++))
      return NULL;
    while (j-- > 0) {
      if (!isdigit(*peek))
        break;
      peek++;
    }
    if (*peek == '.')
      peek++;
    j = 2;
  }
  if (!isdigit(*peek++))
    return NULL;
  while (j-- > 0) {
    if (!isdigit(*peek))
      break;
    peek++;
  }
  return peek;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_is_ip4addr>:
  endbr64
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
L48:
  call   <isdigit@plt>
  test   %eax,%eax
  je     L33
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L73
  movsbl 0x2(%rbx),%edi
  call   <isdigit@plt>
  cmp    $0x1,%eax
  sbb    $0xfffffffffffffffd,%rbx
L1:
  movsbl (%rbx),%edi
  cmp    $0x2e,%dil
  jne    L77
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L77:
  sub    $0x1,%ebp
  jne    L48
  call   <isdigit@plt>
  test   %eax,%eax
  je     L33
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L21
  movsbl 0x2(%rbx),%edi
  call   <isdigit@plt>
  cmp    $0x1,%eax
  mov    %rbx,%rax
  sbb    $0xfffffffffffffffd,%rax
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L33:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L73:
  add    $0x1,%rbx
  jmp    L1
L21:
  lea    0x1(%rbx),%rax
  jmp    L39
```

assistant: ```c
char const *_is_ip4addr(char const *peek) {
  unsigned i = 3;
  unsigned j = 2;
  while (i-- > 0) {
    if (!isdigit(*peek++))
      return NULL;
    while (j-- > 0) {
      if (!isdigit(*peek))
        break;
      peek++;
    }
    if (*peek == '.')
      peek++;
    j = 2;
  }
  if (!isdigit(*peek++))
    return NULL;
  while (j-- > 0) {
    if (!isdigit(*peek))
      break;
    peek++;
  }
  return peek;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_is_ip4addr>:
  endbr64
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
L48:
  call   <isdigit@plt>
  test   %eax,%eax
  je     L62
L3:
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L96
  movsbl 0x2(%rbx),%edi
  call   <isdigit@plt>
  cmp    $0x1,%eax
  sbb    $0xfffffffffffffffd,%rbx
L11:
  movsbl (%rbx),%edi
  cmp    $0x2e,%dil
  je     L99
  sub    $0x1,%ebp
  jne    L48
L89:
  call   <isdigit@plt>
  test   %eax,%eax
  je     L62
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L64
  movsbl 0x2(%rbx),%edi
  call   <isdigit@plt>
  cmp    $0x1,%eax
  mov    %rbx,%rax
  sbb    $0xfffffffffffffffd,%rax
L76:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L99:
  lea    0x1(%rbx),%rax
  movsbl 0x1(%rbx),%edi
  mov    %rax,%rbx
  sub    $0x1,%ebp
  je     L89
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L3
L62:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  add    $0x1,%rbx
  jmp    L11
L64:
  lea    0x1(%rbx),%rax
  jmp    L76
```

assistant: ```c
char const *_is_ip4addr(char const *peek) {
  unsigned i = 3;
  unsigned j = 2;
  while (i-- > 0) {
    if (!isdigit(*peek++))
      return NULL;
    while (j-- > 0) {
      if (!isdigit(*peek))
        break;
      peek++;
    }
    if (*peek == '.')
      peek++;
    j = 2;
  }
  if (!isdigit(*peek++))
    return NULL;
  while (j-- > 0) {
    if (!isdigit(*peek))
      break;
    peek++;
  }
  return peek;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loadmodulemem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <SifInitIopHeap@plt>
  mov    -0x1c(%rbp),%eax
  add    $0xf,%eax
  mov    %eax,%edi
  call   <SifAllocIopHeap@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L22
  mov    $0xffffffff,%eax
  jmp    L45
L22:
  mov    -0x1c(%rbp),%eax
  lea    0xf(%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <iop_heap_dma_upload@plt>
  test   %rax,%rax
  jns    L41
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <SifFreeIopHeap@plt>
  mov    $0xffffffff,%eax
  jmp    L45
L41:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <SifLoadModuleBuffer@plt>
  test   %rax,%rax
  jns    L31
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <SifFreeIopHeap@plt>
  mov    $0xffffffff,%eax
  jmp    L45
L31:
  mov    -0x4(%rbp),%eax
L45:
  leave
  ret
```

assistant: ```c
int loadmodulemem(char *buf, int len, int lenarg, char *arg) {
  unsigned iopmem = 0;
  int ret = 0;
  SifInitIopHeap();
  iopmem = SifAllocIopHeap(len + 15);
  if (iopmem == 0) {
    return -1;
  }
  if (iop_heap_dma_upload(buf, iopmem, len + 15) < 0) {
    SifFreeIopHeap(iopmem);
    return -1;
  }
  if (SifLoadModuleBuffer(iopmem, lenarg, arg) < 0) {
    SifFreeIopHeap(iopmem);
    return -1;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<loadmodulemem>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %rcx,%r14
  mov    $0x0,%eax
  call   <SifInitIopHeap@plt>
  add    $0xf,%ebx
  mov    %ebx,%edi
  call   <SifAllocIopHeap@plt>
  test   %eax,%eax
  je     L25
  mov    %eax,%ebp
  mov    %ebx,%edx
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <iop_heap_dma_upload@plt>
  test   %rax,%rax
  js     L43
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <SifLoadModuleBuffer@plt>
  test   %rax,%rax
  js     L47
  mov    $0x0,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  mov    %ebp,%edi
  call   <SifFreeIopHeap@plt>
  mov    $0xffffffff,%eax
  jmp    L26
L47:
  mov    %ebp,%edi
  call   <SifFreeIopHeap@plt>
  mov    $0xffffffff,%eax
  jmp    L26
L25:
  mov    $0xffffffff,%eax
  jmp    L26
```

assistant: ```c
int loadmodulemem(char *buf, int len, int lenarg, char *arg) {
  unsigned iopmem = 0;
  int ret = 0;
  SifInitIopHeap();
  iopmem = SifAllocIopHeap(len + 15);
  if (iopmem == 0) {
    return -1;
  }
  if (iop_heap_dma_upload(buf, iopmem, len + 15) < 0) {
    SifFreeIopHeap(iopmem);
    return -1;
  }
  if (SifLoadModuleBuffer(iopmem, lenarg, arg) < 0) {
    SifFreeIopHeap(iopmem);
    return -1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<loadmodulemem>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rdi,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  add    $0xf,%r12d
  call   <SifInitIopHeap@plt>
  mov    %r12d,%edi
  call   <SifAllocIopHeap@plt>
  test   %eax,%eax
  je     L46
  mov    %r12d,%edx
  mov    %eax,%esi
  mov    %r15,%rdi
  mov    %eax,%ebp
  call   <iop_heap_dma_upload@plt>
  test   %rax,%rax
  js     L47
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <SifLoadModuleBuffer@plt>
  test   %rax,%rax
  js     L47
  xor    %eax,%eax
L19:
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    $0xffffffff,%eax
  jmp    L19
  nop
L47:
  mov    %ebp,%edi
  call   <SifFreeIopHeap@plt>
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int loadmodulemem(char *buf, int len, int lenarg, char *arg) {
  unsigned iopmem = 0;
  int ret = 0;
  SifInitIopHeap();
  iopmem = SifAllocIopHeap(len + 15);
  if (iopmem == 0) {
    return -1;
  }
  if (iop_heap_dma_upload(buf, iopmem, len + 15) < 0) {
    SifFreeIopHeap(iopmem);
    return -1;
  }
  if (SifLoadModuleBuffer(iopmem, lenarg, arg) < 0) {
    SifFreeIopHeap(iopmem);
    return -1;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<loadmodulemem>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rdi,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  add    $0xf,%r12d
  call   <SifInitIopHeap@plt>
  mov    %r12d,%edi
  call   <SifAllocIopHeap@plt>
  test   %eax,%eax
  je     L3
  mov    %r12d,%edx
  mov    %eax,%esi
  mov    %r15,%rdi
  mov    %eax,%ebp
  call   <iop_heap_dma_upload@plt>
  test   %rax,%rax
  js     L16
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <SifLoadModuleBuffer@plt>
  test   %rax,%rax
  js     L16
  xor    %eax,%eax
L26:
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%eax
  jmp    L26
  nop
L16:
  mov    %ebp,%edi
  call   <SifFreeIopHeap@plt>
  mov    $0xffffffff,%eax
  jmp    L26
```

assistant: ```c
int loadmodulemem(char *buf, int len, int lenarg, char *arg) {
  unsigned iopmem = 0;
  int ret = 0;
  SifInitIopHeap();
  iopmem = SifAllocIopHeap(len + 15);
  if (iopmem == 0) {
    return -1;
  }
  if (iop_heap_dma_upload(buf, iopmem, len + 15) < 0) {
    SifFreeIopHeap(iopmem);
    return -1;
  }
  if (SifLoadModuleBuffer(iopmem, lenarg, arg) < 0) {
    SifFreeIopHeap(iopmem);
    return -1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<RB_XMLDB_Generate_String>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <RB_XMLDB_Generate_Char@plt>
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void RB_XMLDB_Generate_String(FILE *dest_doc, char *a_string) {
  int i;
  int l = strlen(a_string);
  unsigned char c;
  for (i = 0; i < l; ++i) {
    c = a_string[i];
    RB_XMLDB_Generate_Char(dest_doc, c);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RB_XMLDB_Generate_String>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L8
  mov    %r12,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%r12
L6:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <RB_XMLDB_Generate_Char@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L6
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void RB_XMLDB_Generate_String(FILE *dest_doc, char *a_string) {
  int i;
  int l = strlen(a_string);
  unsigned char c;
  for (i = 0; i < l; ++i) {
    c = a_string[i];
    RB_XMLDB_Generate_Char(dest_doc, c);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RB_XMLDB_Generate_String>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L14
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <RB_XMLDB_Generate_Char@plt>
  cmp    %r12,%rbx
  jne    L2
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void RB_XMLDB_Generate_String(FILE *dest_doc, char *a_string) {
  int i;
  int l = strlen(a_string);
  unsigned char c;
  for (i = 0; i < l; ++i) {
    c = a_string[i];
    RB_XMLDB_Generate_Char(dest_doc, c);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RB_XMLDB_Generate_String>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L8
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <RB_XMLDB_Generate_Char@plt>
  cmp    %r12,%rbx
  jne    L19
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void RB_XMLDB_Generate_String(FILE *dest_doc, char *a_string) {
  int i;
  int l = strlen(a_string);
  unsigned char c;
  for (i = 0; i < l; ++i) {
    c = a_string[i];
    RB_XMLDB_Generate_Char(dest_doc, c);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitToDecimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L12
  mov    $0x0,%eax
  jmp    L29
L12:
  mov    -0x18(%rbp),%rax
  lea    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L16
  mov    $0x1,%eax
  jmp    L29
L16:
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L10
  mov    $0x2,%eax
  jmp    L29
L10:
  mov    $0x3,%eax
L29:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D9: 00

tool: D25: 01

tool: D4: 10

assistant: ```c
int bitToDecimal(char *bit) {
  int test = strcmp(bit, "00");
  if (!strcmp(bit, "00")) {
    return 0;
  } else if (!strcmp(bit, "01")) {
    return 1;
  } else if (!strcmp(bit, "10")) {
    return 2;
  } else {
    return 3;
  }
}
```