ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insertionsort>:
  endbr64
  cmp    $0x1,%esi
  jle    L17
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L56:
  mov    (%rbx,%r15,4),%r14d
  mov    %r15d,%ecx
  mov    %r15d,%esi
  mov    %r15,%rax
  nopl   (%rax)
L52:
  mov    %eax,%edx
  lea    0x0(,%rax,4),%rbp
  cmp    %r14d,-0x4(%rbx,%rax,4)
  jle    L44
  sub    $0x1,%rax
  mov    %eax,%edx
  test   %eax,%eax
  jne    L52
  mov    %rbx,%rbp
L39:
  sub    %edx,%ecx
  lea    0x0(,%r15,4),%rax
  sub    $0x1,%ecx
  mov    %rcx,%rdi
  lea    0x4(,%rcx,4),%r8
  neg    %rdi
  shl    $0x2,%rdi
  cmp    %esi,%edx
  mov    $0x4,%edx
  cmovge %r13,%rdi
  cmovge %rdx,%r8
  lea    -0x4(%rax,%rdi,1),%rsi
  add    %rax,%rdi
  mov    %r8,%rdx
  add    %rbx,%rsi
  add    %rbx,%rdi
  call   <memmove@plt>
L57:
  add    $0x1,%r15
  mov    %r14d,0x0(%rbp)
  cmp    %r15,%r12
  jne    L56
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L44:
  add    %rbx,%rbp
  cmp    %r15d,%eax
  jl     L39
  jmp    L57
L17:
  ret
```

assistant: ```c
void insertionsort(int items[], int size) {
  int i;
  for (i = 1; i < size; i++) {
    int pos = i, item = items[i];
    while (pos > 0 && item < items[pos - 1])
      pos--;
    int k = i;
    while (k > pos) {
      items[k] = items[k - 1];
      k--;
    }
    items[pos] = item;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sqrt32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %ecx,%ebp
  cmp    $0x3ff,%edi
  jg     L5
L13:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    %edi,%ebx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  mov    %r12d,%ebp
  mov    $0x10000,%edi
  call   <INT32_C@plt>
  cmp    %ebx,%eax
  jg     L13
  mov    %ebx,%eax
  cltd
  idiv   %r12d
  add    %r12d,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  mov    %r12d,%ebp
  mov    $0x100000,%edi
  call   <INT32_C@plt>
  cmp    %ebx,%eax
  jg     L13
  mov    %ebx,%eax
  cltd
  idiv   %r12d
  add    %r12d,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  jmp    L13
```

assistant: ```c
int32_t sqrt32(int32_t radicand) {
  int32_t x;
  x = radicand;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < 1024)
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < INT32_C(65536))
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < INT32_C(1048576))
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sqrt32>:
  endbr64
  lea    0x1(%rdi),%eax
  push   %r12
  mov    %eax,%ecx
  push   %rbx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  sub    $0x8,%rsp
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0x3ff,%edi
  jg     L11
L20:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L11:
  mov    %edi,%eax
  mov    %edi,%ebx
  cltd
  idiv   %r12d
  add    %r12d,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  mov    $0x10000,%edi
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  call   <INT32_C@plt>
  cmp    %ebx,%eax
  jg     L20
  mov    %ebx,%eax
  mov    $0x100000,%edi
  cltd
  idiv   %r12d
  add    %r12d,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %ebx,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %ebx,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  call   <INT32_C@plt>
  cmp    %ebx,%eax
  jg     L20
  mov    %ebx,%eax
  add    $0x8,%rsp
  cltd
  idiv   %r12d
  add    %r12d,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %ebx,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int32_t sqrt32(int32_t radicand) {
  int32_t x;
  x = radicand;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < 1024)
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < INT32_C(65536))
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < INT32_C(1048576))
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sqrt32>:
  endbr64
  lea    0x1(%rdi),%eax
  push   %r12
  mov    %eax,%ecx
  push   %rbx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  sub    $0x8,%rsp
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0x3ff,%edi
  jg     L0
L5:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  mov    %edi,%eax
  mov    %edi,%ebx
  cltd
  idiv   %r12d
  add    %r12d,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %edi,%eax
  mov    $0x10000,%edi
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  call   <INT32_C@plt>
  cmp    %ebx,%eax
  jg     L5
  mov    %ebx,%eax
  mov    $0x100000,%edi
  cltd
  idiv   %r12d
  add    %r12d,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %ebx,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %ebx,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  call   <INT32_C@plt>
  cmp    %ebx,%eax
  jg     L5
  mov    %ebx,%eax
  add    $0x8,%rsp
  cltd
  idiv   %r12d
  add    %r12d,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %ebx,%eax
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %ecx
  cltd
  idiv   %ecx
  add    %ecx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int32_t sqrt32(int32_t radicand) {
  int32_t x;
  x = radicand;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < 1024)
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < INT32_C(65536))
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  if (radicand < INT32_C(1048576))
    return x;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  x = (x + radicand / x) / 2;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<IS_AGPHEADER_INV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ax
  cmp    $0xfe070000,%eax
  je     L23
  cmp    $0xfe070000,%eax
  ja     L42
  cmp    $0xfe060000,%eax
  je     L23
  cmp    $0xfe060000,%eax
  ja     L42
  cmp    $0xfe050000,%eax
  je     L23
  cmp    $0xfe050000,%eax
  ja     L42
  cmp    $0xfe040000,%eax
  je     L23
  cmp    $0xfe040000,%eax
  ja     L42
  cmp    $0xfe030000,%eax
  je     L23
  cmp    $0xfe030000,%eax
  ja     L42
  cmp    $0xfe020000,%eax
  je     L23
  cmp    $0xfe020000,%eax
  ja     L42
  cmp    $0xfe000000,%eax
  je     L23
  cmp    $0xfe010000,%eax
  jne    L42
L23:
  mov    $0x1,%eax
  jmp    L99
L42:
  mov    $0x0,%eax
L99:
  pop    %rbp
  ret
```

assistant: ```c
int IS_AGPHEADER_INV(unsigned int data) {
  switch (data & 0xFFFF0000) {
  case 0xFE000000:
  case 0xFE010000:
  case 0xFE020000:
  case 0xFE030000:
  case 0xFE040000:
  case 0xFE050000:
  case 0xFE060000:
  case 0xFE070000:
    return 1;
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<IS_AGPHEADER_INV>:
  endbr64
  mov    %edi,%eax
  mov    $0x0,%ax
  cmp    $0xfe040000,%eax
  je     L36
  cmp    $0xfe040000,%eax
  ja     L7
  cmp    $0xfe020000,%eax
  je     L29
  cmp    $0xfe020000,%eax
  ja     L42
  and    $0xfffe0000,%edi
  cmp    $0xfe000000,%edi
  sete   %al
  movzbl %al,%eax
  ret
L42:
  cmp    $0xfe030000,%eax
  sete   %al
  movzbl %al,%eax
  ret
L7:
  cmp    $0xfe060000,%eax
  je     L4
  and    $0xfffd0000,%edi
  cmp    $0xfe050000,%edi
  sete   %al
  movzbl %al,%eax
  ret
L36:
  mov    $0x1,%eax
  ret
L29:
  mov    $0x1,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int IS_AGPHEADER_INV(unsigned int data) {
  switch (data & 0xFFFF0000) {
  case 0xFE000000:
  case 0xFE010000:
  case 0xFE020000:
  case 0xFE030000:
  case 0xFE040000:
  case 0xFE050000:
  case 0xFE060000:
  case 0xFE070000:
    return 1;
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IS_AGPHEADER_INV>:
  endbr64
  mov    %edi,%eax
  xor    %ax,%ax
  cmp    $0xfe040000,%eax
  je     L39
  ja     L38
  cmp    $0xfe020000,%eax
  je     L39
  ja     L8
  and    $0xfffe0000,%edi
  xor    %eax,%eax
  cmp    $0xfe000000,%edi
  sete   %al
  ret
  nopl   (%rax)
L38:
  cmp    $0xfe060000,%eax
  je     L39
  and    $0xfffd0000,%edi
  xor    %eax,%eax
  cmp    $0xfe050000,%edi
  sete   %al
  ret
  nopl   0x0(%rax)
L8:
  cmp    $0xfe030000,%eax
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L39:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int IS_AGPHEADER_INV(unsigned int data) {
  switch (data & 0xFFFF0000) {
  case 0xFE000000:
  case 0xFE010000:
  case 0xFE020000:
  case 0xFE030000:
  case 0xFE040000:
  case 0xFE050000:
  case 0xFE060000:
  case 0xFE070000:
    return 1;
  default:
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<IS_AGPHEADER_INV>:
  endbr64
  mov    %edi,%eax
  xor    %ax,%ax
  cmp    $0xfe040000,%eax
  je     L0
  ja     L24
  cmp    $0xfe020000,%eax
  je     L0
  ja     L2
  and    $0xfffe0000,%edi
  xor    %eax,%eax
  cmp    $0xfe000000,%edi
  sete   %al
  ret
  nopl   (%rax)
L24:
  cmp    $0xfe060000,%eax
  je     L0
  and    $0xfffd0000,%edi
  xor    %eax,%eax
  cmp    $0xfe050000,%edi
  sete   %al
  ret
  nopl   0x0(%rax)
L2:
  cmp    $0xfe030000,%eax
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int IS_AGPHEADER_INV(unsigned int data) {
  switch (data & 0xFFFF0000) {
  case 0xFE000000:
  case 0xFE010000:
  case 0xFE020000:
  case 0xFE030000:
  case 0xFE040000:
  case 0xFE050000:
  case 0xFE060000:
  case 0xFE070000:
    return 1;
  default:
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xa,-0x8(%rbp)
  movl   $0x48,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type: string
name: read_data
arguments: data_tag: D4
type: string

tool: D17: I am %d years old.


tool: D4: I am %d inches tall.


assistant: ```c
int main(int argc, char *argv[]) {
  int age = 10;
  int height = 72;
  printf("I am %d years old.\n", age);
  printf("I am %d inches tall.\n", height);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D17: I am %d years old.


tool: D18: I am %d inches tall.


assistant: ```c
int main(int argc, char *argv[]) {
  int age = 10;
  int height = 72;
  printf("I am %d years old.\n", age);
  printf("I am %d inches tall.\n", height);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D15: I am %d years old.


tool: D8: I am %d inches tall.


assistant: ```c
int main(int argc, char *argv[]) {
  int age = 10;
  int height = 72;
  printf("I am %d years old.\n", age);
  printf("I am %d inches tall.\n", height);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D2
datatype: string

tool: D8: I am %d years old.


tool: D2: I am %d inches tall.


assistant: ```c
int main(int argc, char *argv[]) {
  int age = 10;
  int height = 72;
  printf("I am %d years old.\n", age);
  printf("I am %d inches tall.\n", height);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  sar    $0x2,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %eax,%r12d
  mov    -0x24(%rbp),%eax
  sub    %r12d,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  movslq %eax,%rdx
  movslq %r12d,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  movslq %eax,%rdx
  movslq %r12d,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%r13
  cmpl   $0x3,-0x1c(%rbp)
  je     L49
  cmpl   $0x3,-0x1c(%rbp)
  jg     L88
  cmpl   $0x2,-0x1c(%rbp)
  je     L38
  cmpl   $0x2,-0x1c(%rbp)
  jg     L88
  cmpl   $0x0,-0x1c(%rbp)
  je     L25
  cmpl   $0x1,-0x1c(%rbp)
  je     L28
  jmp    L88
L25:
  lea    0xc(%r13),%rax
  mov    0xc(%rbx),%edx
  mov    %edx,(%rax)
L49:
  lea    0x8(%r13),%rax
  mov    0x8(%rbx),%edx
  mov    %edx,(%rax)
L38:
  lea    0x4(%r13),%rax
  mov    0x4(%rbx),%edx
  mov    %edx,(%rax)
L28:
  mov    (%rbx),%eax
  mov    %eax,0x0(%r13)
  sub    $0x4,%r12d
  sub    $0x10,%r13
  sub    $0x10,%rbx
  test   %r12d,%r12d
  jns    L25
L88:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L61
L69:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x28(%rbp)
L61:
  mov    -0x28(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L69
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void dcopy(char *chardest, char *charsrc, int size) {
  register int *src, *dest, intcount;
  int startcharcpy, intoffset, numints2cpy, i;
  numints2cpy = size >> 2;
  startcharcpy = numints2cpy << 2;
  intcount = numints2cpy & ~(4 - 1);
  intoffset = numints2cpy - intcount;
  src = (int *)(((int)charsrc) + intcount * sizeof(int *));
  dest = (int *)(((int)chardest) + intcount * sizeof(int *));
  switch (intoffset)
    do {
    case 0:
      dest[3] = src[3];
    case 3:
      dest[2] = src[2];
    case 2:
      dest[1] = src[1];
    case 1:
      dest[0] = src[0];
      intcount -= 4;
      dest -= 4;
      src -= 4;
    } while (intcount >= 0);
  for (i = startcharcpy; i < size; i++)
    chardest[i] = charsrc[i];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dcopy>:
  endbr64
  mov    %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%r10d
  and    $0xfffffffc,%r10d
  and    $0x3,%eax
  movslq %r10d,%r9
  shl    $0x3,%r9
  movslq %esi,%rcx
  add    %r9,%rcx
  movslq %edi,%r8
  add    %r9,%r8
  cmp    $0x2,%eax
  je     L72
  jg     L67
  test   %eax,%eax
  je     L41
  cmp    $0x1,%eax
  jne    L92
L7:
  mov    (%rcx),%eax
  mov    %eax,(%r8)
  sub    $0x4,%r10d
  js     L92
  sub    $0x10,%r8
  sub    $0x10,%rcx
L41:
  mov    0xc(%rcx),%eax
  mov    %eax,0xc(%r8)
  jmp    L25
L67:
  cmp    $0x3,%eax
  jne    L92
L25:
  mov    0x8(%rcx),%eax
  mov    %eax,0x8(%r8)
L72:
  mov    0x4(%rcx),%eax
  mov    %eax,0x4(%r8)
  jmp    L7
L92:
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  cmp    %eax,%edx
  jle    L60
  cltq
L16:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L16
L60:
  ret
```

assistant: ```c
void dcopy(char *chardest, char *charsrc, int size) {
  register int *src, *dest, intcount;
  int startcharcpy, intoffset, numints2cpy, i;
  numints2cpy = size >> 2;
  startcharcpy = numints2cpy << 2;
  intcount = numints2cpy & ~(4 - 1);
  intoffset = numints2cpy - intcount;
  src = (int *)(((int)charsrc) + intcount * sizeof(int *));
  dest = (int *)(((int)chardest) + intcount * sizeof(int *));
  switch (intoffset)
    do {
    case 0:
      dest[3] = src[3];
    case 3:
      dest[2] = src[2];
    case 2:
      dest[1] = src[1];
    case 1:
      dest[0] = src[0];
      intcount -= 4;
      dest -= 4;
      src -= 4;
    } while (intcount >= 0);
  for (i = startcharcpy; i < size; i++)
    chardest[i] = charsrc[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dcopy>:
  endbr64
  mov    %edx,%eax
  movslq %esi,%rcx
  movslq %edi,%r8
  sar    $0x2,%eax
  mov    %eax,%r10d
  and    $0x3,%eax
  and    $0xfffffffc,%r10d
  movslq %r10d,%r9
  shl    $0x3,%r9
  add    %r9,%rcx
  add    %r9,%r8
  cmp    $0x2,%eax
  je     L58
  jg     L31
  test   %eax,%eax
  je     L59
  cmp    $0x1,%eax
  jne    L45
  mov    (%rcx),%eax
  mov    %eax,(%r8)
  sub    $0x4,%r10d
  js     L45
L65:
  sub    $0x10,%r8
  sub    $0x10,%rcx
L59:
  mov    0xc(%rcx),%eax
  mov    %eax,0xc(%r8)
  mov    0x8(%rcx),%eax
  mov    %eax,0x8(%r8)
L58:
  mov    0x4(%rcx),%eax
  mov    %eax,0x4(%r8)
L67:
  mov    (%rcx),%eax
  mov    %eax,(%r8)
  sub    $0x4,%r10d
  jns    L65
L45:
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  cmp    %eax,%edx
  jle    L82
  cltq
  nopl   0x0(%rax)
L13:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L13
L82:
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  cmp    $0x3,%eax
  jne    L45
  mov    0x8(%rcx),%eax
  mov    %eax,0x8(%r8)
  mov    0x4(%rcx),%eax
  mov    %eax,0x4(%r8)
  jmp    L67
```

assistant: ```c
void dcopy(char *chardest, char *charsrc, int size) {
  register int *src, *dest, intcount;
  int startcharcpy, intoffset, numints2cpy, i;
  numints2cpy = size >> 2;
  startcharcpy = numints2cpy << 2;
  intcount = numints2cpy & ~(4 - 1);
  intoffset = numints2cpy - intcount;
  src = (int *)(((int)charsrc) + intcount * sizeof(int *));
  dest = (int *)(((int)chardest) + intcount * sizeof(int *));
  switch (intoffset)
    do {
    case 0:
      dest[3] = src[3];
    case 3:
      dest[2] = src[2];
    case 2:
      dest[1] = src[1];
    case 1:
      dest[0] = src[0];
      intcount -= 4;
      dest -= 4;
      src -= 4;
    } while (intcount >= 0);
  for (i = startcharcpy; i < size; i++)
    chardest[i] = charsrc[i];
}
```