ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<s16_to_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x0,-0x10(%rbp)
  jmp    L13
L4:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  D2(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L4
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x47]}

assistant: ```c
void s16_to_float(const char *in, float *out, const size_t samples) {
  size_t i;
  const int16_t *in_16 = (int16_t *)in;
  assert(in != NULL);
  assert(out != NULL);
  for (i = 0; i < samples; i++)
    out[i] = *in_16++ / (float)((32767) + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s16_to_float>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  je     L8
  mov    $0x0,%eax
  movss  D3(%rip),%xmm1
L4:
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%rbx,%rax,4),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L4
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x38]}

assistant: ```c
void s16_to_float(const char *in, float *out, const size_t samples) {
  size_t i;
  const int16_t *in_16 = (int16_t *)in;
  assert(in != NULL);
  assert(out != NULL);
  for (i = 0; i < samples; i++)
    out[i] = *in_16++ / (float)((32767) + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s16_to_float>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  test   %r12,%r12
  je     L8
  movss  D1(%rip),%xmm1
  xor    %eax,%eax
  xchg   %ax,%ax
L18:
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%rbx,%rax,4),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L18
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x38]}

assistant: ```c
void s16_to_float(const char *in, float *out, const size_t samples) {
  size_t i;
  const int16_t *in_16 = (int16_t *)in;
  assert(in != NULL);
  assert(out != NULL);
  for (i = 0; i < samples; i++)
    out[i] = *in_16++ / (float)((32767) + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s16_to_float>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rdx,%rbp
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  test   %rbp,%rbp
  je     L31
  lea    -0x1(%rbp),%rax
  cmp    $0x2,%rax
  jbe    L60
  mov    %rbp,%rdx
  movaps D7(%rip),%xmm1
  xor    %eax,%eax
  shr    $0x2,%rdx
  shl    $0x4,%rdx
  nopw   0x0(%rax,%rax,1)
L28:
  movdqu (%r12,%rax,1),%xmm2
  cvtdq2ps %xmm2,%xmm0
  mulps  %xmm1,%xmm0
  movups %xmm0,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L28
  mov    %rbp,%rax
  and    $0xfffffffffffffffc,%rax
  lea    (%r12,%rax,4),%rdx
  cmp    %rax,%rbp
  je     L31
L62:
  sub    %rax,%rbp
  cmp    $0x1,%rbp
  je     L33
  movq   (%r12,%rax,4),%xmm0
  mov    %rbp,%rcx
  movq   D7(%rip),%xmm1
  and    $0xfffffffffffffffe,%rcx
  cvtdq2ps %xmm0,%xmm0
  mulps  %xmm1,%xmm0
  lea    (%rdx,%rcx,4),%rdx
  movlps %xmm0,(%rbx,%rax,4)
  add    %rcx,%rax
  cmp    %rcx,%rbp
  je     L31
L33:
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%rdx),%xmm0
  mulss  D7(%rip),%xmm0
  movss  %xmm0,(%rbx,%rax,4)
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L60:
  mov    %r12,%rdx
  xor    %eax,%eax
  jmp    L62
```

tool_calls: name: read_data
arguments: data_label: D7
type: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x38,0x00,0x00,0x00,0x38,0x00,0x00,0x00,0x38,0x00,0x00,0x00,0x38]}

assistant: ```c
void s16_to_float(const char *in, float *out, const size_t samples) {
  size_t i;
  const int16_t *in_16 = (int16_t *)in;
  assert(in != NULL);
  assert(out != NULL);
  for (i = 0; i < samples; i++)
    out[i] = *in_16++ / (float)((32767) + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<RLEDecompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movb   $0x0,-0xe(%rbp)
  movb   $0x0,-0xd(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L51:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L44
L67:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xe(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L28
  addl   $0x1,-0x4(%rbp)
L44:
  movzbl -0xd(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L67
  jmp    L14
L28:
  nop
L14:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x2,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L59
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L51
L59:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int RLEDecompress(unsigned char *in, int inlen, unsigned char *out, int outlen) {
  unsigned char cur = 0;
  unsigned char count = 0;
  int inpos = 0;
  int outpos = 0;
  int i = 0;
  while (inpos < inlen && outpos < outlen) {
    cur = in[inpos];
    count = in[inpos + 1];
    for (i = 0; i < count; i++) {
      out[outpos + i] = cur;
      if (outpos + i >= outlen) {
        break;
      }
    }
    outpos += i;
    inpos += 2;
  }
  return outpos;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RLEDecompress>:
  endbr64
  test   %esi,%esi
  jle    L89
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %ecx,%r10d
  test   %ecx,%ecx
  jle    L14
  mov    $0x2,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%r13d
  lea    -0x1(%rcx),%r12d
  jmp    L16
L37:
  mov    %r13d,%r14d
L1:
  add    %r14d,%r8d
  cmp    %r9d,%ebx
  setg   %dl
  cmp    %r8d,%r10d
  setg   %al
  add    $0x2,%r9
  test   %al,%dl
  je     L12
L16:
  movzbl -0x2(%r11,%r9,1),%edi
  movzbl -0x1(%r11,%r9,1),%esi
  test   %esi,%esi
  jle    L37
  movslq %r8d,%rdx
  add    %rbp,%rdx
  mov    %dil,(%rdx)
  cmp    %r8d,%r10d
  jle    L12
  mov    %r12d,%ecx
  sub    %r8d,%ecx
  add    $0x2,%rcx
  mov    $0x1,%eax
L72:
  mov    %eax,%r14d
  cmp    %eax,%esi
  jle    L1
  mov    %dil,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L72
  jmp    L1
L14:
  mov    $0x0,%r8d
L12:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L89:
  mov    $0x0,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int RLEDecompress(unsigned char *in, int inlen, unsigned char *out, int outlen) {
  unsigned char cur = 0;
  unsigned char count = 0;
  int inpos = 0;
  int outpos = 0;
  int i = 0;
  while (inpos < inlen && outpos < outlen) {
    cur = in[inpos];
    count = in[inpos + 1];
    for (i = 0; i < count; i++) {
      out[outpos + i] = cur;
      if (outpos + i >= outlen) {
        break;
      }
    }
    outpos += i;
    inpos += 2;
  }
  return outpos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RLEDecompress>:
  endbr64
  test   %esi,%esi
  jle    L47
  mov    %rdi,%r11
  mov    %ecx,%edi
  test   %ecx,%ecx
  jle    L47
  push   %rbp
  mov    $0x2,%r10d
  mov    %rdx,%rbp
  xor    %r8d,%r8d
  push   %rbx
  mov    %esi,%ebx
  nopl   (%rax)
L59:
  movzbl -0x1(%r11,%r10,1),%esi
  movzbl -0x2(%r11,%r10,1),%r9d
  test   %sil,%sil
  je     L15
  movslq %r8d,%rdx
  mov    %r9b,0x0(%rbp,%rdx,1)
  cmp    %r8d,%edi
  jle    L65
  lea    0x1(%r8),%eax
  lea    0x1(%rbp,%rdx,1),%rdx
  add    %r8d,%esi
  jmp    L21
  nopl   0x0(%rax)
L7:
  mov    %r9b,(%rdx)
  lea    0x1(%rax),%ecx
  add    $0x1,%rdx
  cmp    %eax,%edi
  je     L15
  mov    %ecx,%eax
L21:
  mov    %eax,%r8d
  cmp    %eax,%esi
  jne    L7
L15:
  cmp    %r10d,%ebx
  setg   %dl
  cmp    %r8d,%edi
  setg   %al
  add    $0x2,%r10
  test   %al,%dl
  jne    L59
L65:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L47:
  xor    %eax,%eax
  ret
```

assistant: ```c
int RLEDecompress(unsigned char *in, int inlen, unsigned char *out, int outlen) {
  unsigned char cur = 0;
  unsigned char count = 0;
  int inpos = 0;
  int outpos = 0;
  int i = 0;
  while (inpos < inlen && outpos < outlen) {
    cur = in[inpos];
    count = in[inpos + 1];
    for (i = 0; i < count; i++) {
      out[outpos + i] = cur;
      if (outpos + i >= outlen) {
        break;
      }
    }
    outpos += i;
    inpos += 2;
  }
  return outpos;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RLEDecompress>:
  endbr64
  test   %esi,%esi
  jle    L39
  mov    %rdi,%r11
  mov    %ecx,%edi
  test   %ecx,%ecx
  jle    L39
  push   %rbp
  mov    $0x2,%r10d
  mov    %rdx,%rbp
  xor    %r8d,%r8d
  push   %rbx
  mov    %esi,%ebx
  nopl   (%rax)
L17:
  movzbl -0x1(%r11,%r10,1),%esi
  movzbl -0x2(%r11,%r10,1),%r9d
  test   %sil,%sil
  je     L22
  movslq %r8d,%rdx
  mov    %r9b,0x0(%rbp,%rdx,1)
  cmp    %r8d,%edi
  jle    L43
  lea    0x1(%r8),%eax
  lea    0x1(%rbp,%rdx,1),%rdx
  add    %r8d,%esi
  jmp    L19
  nopl   0x0(%rax)
L6:
  mov    %r9b,(%rdx)
  lea    0x1(%rax),%ecx
  add    $0x1,%rdx
  cmp    %eax,%edi
  je     L22
  mov    %ecx,%eax
L19:
  mov    %eax,%r8d
  cmp    %eax,%esi
  jne    L6
L22:
  cmp    %r10d,%ebx
  setg   %dl
  cmp    %r8d,%edi
  setg   %al
  add    $0x2,%r10
  test   %al,%dl
  jne    L17
L43:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int RLEDecompress(unsigned char *in, int inlen, unsigned char *out, int outlen) {
  unsigned char cur = 0;
  unsigned char count = 0;
  int inpos = 0;
  int outpos = 0;
  int i = 0;
  while (inpos < inlen && outpos < outlen) {
    cur = in[inpos];
    count = in[inpos + 1];
    for (i = 0; i < count; i++) {
      out[outpos + i] = cur;
      if (outpos + i >= outlen) {
        break;
      }
    }
    outpos += i;
    inpos += 2;
  }
  return outpos;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    $0x18,%r13d
  lea    D3(%rip),%r12
  lea    0x14(%rsp),%rbp
  lea    D23(%rip),%rbx
  jmp    L78
L3:
  mov    0x10(%rsp),%eax
  cmp    %edx,%eax
  jge    L16
L60:
  mov    %r13d,%esi
  sub    %edx,%esi
  imul   $0x3c,%esi,%esi
  sub    %ecx,%esi
  imul   $0x3c,%eax,%eax
  add    0x14(%rsp),%eax
  add    %eax,%esi
L97:
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%r8
  mov    %rbx,%rdi
  call   <scanf@plt>
L78:
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%ecx
  mov    %edx,%eax
  or     %ecx,%eax
  jne    L3
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jne    L38
  cmpl   $0x0,0x14(%rsp)
  je     L82
L99:
  mov    0x14(%rsp),%esi
  cmp    %ecx,%esi
  jge    L83
  mov    %r13d,%edi
  sub    %edx,%edi
  imul   $0x3c,%edi,%edx
  sub    %ecx,%edx
  imul   $0x3c,%eax,%eax
  add    %esi,%eax
  lea    (%rdx,%rax,1),%esi
  jmp    L97
L16:
  je     L30
L138:
  imul   $0x3c,%eax,%esi
  add    0x14(%rsp),%esi
  imul   $0x3c,%edx,%edx
  add    %ecx,%edx
  sub    %edx,%esi
  jmp    L97
L30:
  mov    %edx,%eax
  jmp    L99
L83:
  imul   $0x3c,%eax,%eax
  add    %eax,%esi
  imul   $0x3c,%edx,%edx
  add    %ecx,%edx
  sub    %edx,%esi
  jmp    L97
L82:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  js     L60
  jmp    L138
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D3
type: string

tool: D23:  %d %d %d %d

tool: D3: %d


assistant: ```c
int main() {
  int H1, M1, H2, M2, cont_m;
  scanf(" %d %d %d %d", &H1, &M1, &H2, &M2);
  while (H1 != 0 || M1 != 0 || H2 != 0 || M2 != 0) {
    if (H2 < H1) {
      cont_m = (((24 - H1) * 60) - M1) + (H2 * 60 + M2);
    } else if (H2 == H1) {
      if (M2 < M1) {
        cont_m = (((24 - H1) * 60) - M1) + (H2 * 60 + M2);
      } else {
        cont_m = ((H2 * 60) + M2) - ((H1 * 60) + M1);
      }
    } else {
      cont_m = ((H2 * 60) + M2) - ((H1 * 60) + M1);
    }
    printf("%d\n", cont_m);
    scanf(" %d %d %d %d", &H1, &M1, &H2, &M2);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D8(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L54:
  test   %eax,%eax
  jne    L16
  test   %ecx,%ecx
  je     L32
L14:
  imul   $0x3c,%eax,%eax
  lea    (%rax,%rcx,1),%esi
  cmp    %ecx,%edx
  jle    L118
  mov    $0x18,%eax
  sub    %edi,%eax
  imul   $0x3c,%eax,%eax
  sub    %edx,%eax
  add    %eax,%esi
  nopl   0x0(%rax,%rax,1)
L75:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L70:
  mov    0x8(%rsp),%edi
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  mov    0x14(%rsp),%ecx
  mov    %edi,%esi
  or     %edx,%esi
  je     L54
  cmp    %eax,%edi
  jle    L35
L106:
  mov    $0x18,%esi
  imul   $0x3c,%eax,%eax
  sub    %edi,%esi
  imul   $0x3c,%esi,%esi
  add    %ecx,%eax
  sub    %edx,%esi
  add    %eax,%esi
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L35:
  je     L14
L24:
  imul   $0x3c,%eax,%eax
  lea    (%rax,%rcx,1),%esi
L118:
  imul   $0x3c,%edi,%edi
  add    %edx,%edi
  sub    %edi,%esi
  jmp    L75
  nopl   0x0(%rax)
L16:
  js     L106
  jmp    L24
  nopl   0x0(%rax)
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string

tool: D8: %d


tool: D19:  %d %d %d %d

assistant: ```c
int main() {
  int H1, M1, H2, M2, cont_m;
  scanf(" %d %d %d %d", &H1, &M1, &H2, &M2);
  while (H1 != 0 || M1 != 0 || H2 != 0 || M2 != 0) {
    if (H2 < H1) {
      cont_m = (((24 - H1) * 60) - M1) + (H2 * 60 + M2);
    } else if (H2 == H1) {
      if (M2 < M1) {
        cont_m = (((24 - H1) * 60) - M1) + (H2 * 60 + M2);
      } else {
        cont_m = ((H2 * 60) + M2) - ((H1 * 60) + M1);
      }
    } else {
      cont_m = ((H2 * 60) + M2) - ((H1 * 60) + M1);
    }
    printf("%d\n", cont_m);
    scanf(" %d %d %d %d", &H1, &M1, &H2, &M2);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D13(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L75:
  test   %eax,%eax
  jne    L99
  test   %ecx,%ecx
  je     L7
L111:
  imul   $0x3c,%eax,%eax
  lea    (%rax,%rcx,1),%esi
  cmp    %ecx,%edx
  jle    L73
  mov    $0x18,%eax
  sub    %edi,%eax
  imul   $0x3c,%eax,%eax
  sub    %edx,%eax
  add    %eax,%esi
  nopl   0x0(%rax,%rax,1)
L102:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L67:
  mov    0x8(%rsp),%edi
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  mov    0x14(%rsp),%ecx
  mov    %edi,%esi
  or     %edx,%esi
  je     L75
  cmp    %eax,%edi
  jle    L82
L53:
  mov    $0x18,%esi
  imul   $0x3c,%eax,%eax
  sub    %edi,%esi
  imul   $0x3c,%esi,%esi
  add    %ecx,%eax
  sub    %edx,%esi
  add    %eax,%esi
  jmp    L102
  nopl   0x0(%rax,%rax,1)
L82:
  je     L111
L51:
  imul   $0x3c,%eax,%eax
  lea    (%rax,%rcx,1),%esi
L73:
  imul   $0x3c,%edi,%edi
  add    %edx,%edi
  sub    %edi,%esi
  jmp    L102
  nopl   0x0(%rax)
L99:
  js     L53
  jmp    L51
  nopl   0x0(%rax)
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
data_type: string
name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D13: %d


tool: D3:  %d %d %d %d

assistant: ```c
int main() {
  int H1, M1, H2, M2, cont_m;
  scanf(" %d %d %d %d", &H1, &M1, &H2, &M2);
  while (H1 != 0 || M1 != 0 || H2 != 0 || M2 != 0) {
    if (H2 < H1) {
      cont_m = (((24 - H1) * 60) - M1) + (H2 * 60 + M2);
    } else if (H2 == H1) {
      if (M2 < M1) {
        cont_m = (((24 - H1) * 60) - M1) + (H2 * 60 + M2);
      } else {
        cont_m = ((H2 * 60) + M2) - ((H1 * 60) + M1);
      }
    } else {
      cont_m = ((H2 * 60) + M2) - ((H1 * 60) + M1);
    }
    printf("%d\n", cont_m);
    scanf(" %d %d %d %d", &H1, &M1, &H2, &M2);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<indent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L7:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void indent(int i) {
  int j;
  for (j = 0; j < i; j++)
    putchar(' ');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<indent>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L5:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  ret
```

assistant: ```c
void indent(int i) {
  int j;
  for (j = 0; j < i; j++)
    putchar(' ');
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<indent>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  ret
```

assistant: ```c
void indent(int i) {
  int j;
  for (j = 0; j < i; j++)
    putchar(' ');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<indent>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  ret
```

assistant: ```c
void indent(int i) {
  int j;
  for (j = 0; j < i; j++)
    putchar(' ');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L26
L44:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L44
  jmp    L10
L48:
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
L9:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  nop
  leave
  ret
```

assistant: ```c
void trim(char *s) {
  char *p = s;
  int l = strlen(p);
  while (isspace(p[l - 1]))
    p[--l] = 0;
  while (*p && isspace(*p))
    ++p, --l;
  memmove(s, p, l + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  movslq %eax,%rbx
  jmp    L49
L9:
  movb   $0x0,(%r12,%rbx,1)
L49:
  mov    %ebx,%ebp
  movsbl -0x1(%r12,%rbx,1),%edi
  call   <isspace@plt>
  sub    $0x1,%rbx
  test   %rax,%rax
  jne    L9
  movzbl (%r12),%edi
  mov    %r12,%rbx
  test   %dil,%dil
  je     L1
L0:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L1
  add    $0x1,%rbx
  sub    $0x1,%ebp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L0
L1:
  lea    0x1(%rbp),%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trim(char *s) {
  char *p = s;
  int l = strlen(p);
  while (isspace(p[l - 1]))
    p[--l] = 0;
  while (*p && isspace(*p))
    ++p, --l;
  memmove(s, p, l + 1);
}
```