ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<tst_unsigned>:
  endbr64
  push   %rbx
  mov    (%rcx),%edi
  mov    %rcx,%rbx
  call   <imaxabs@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void tst_unsigned(unsigned *pu, unsigned long *pl, unsigned long long *pll, uintmax_t *pm) {
  *pu = abs(*pu);
  *pl = labs(*pl);
  *pll = llabs(*pll);
  *pm = imaxabs(*pm);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libgadget_misc_double_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %edx,%eax
  mov    %ecx,-0x34(%rbp)
  mov    %esi,%edx
  mov    %dl,-0x2c(%rbp)
  mov    %al,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L101
  movl   $0x0,-0x14(%rbp)
  jmp    L121
L14:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  jne    L66
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jne    L66
  addl   $0x1,-0x14(%rbp)
  jmp    L62
L66:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L97
L53:
  addl   $0x1,-0x14(%rbp)
L121:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jle    L14
  jmp    L62
L101:
  movl   $0x0,-0x14(%rbp)
L62:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L77
L13:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x30(%rbp)
  je     L33
  addl   $0x1,-0x10(%rbp)
L77:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jle    L13
  jmp    L81
L33:
  nop
L81:
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L97:
  leave
  ret
```

assistant: ```c
char *libgadget_misc_double_split(char *str, char split1, char split2, int ret) {
  char *ptr;
  int a, b, c = 0;
  if (ret != 0) {
    for (a = 0; a <= strlen(str); a++) {
      if (str[a] == split1 && ++c == ret) {
        a++;
        break;
      }
      if (a == strlen(str))
        return NULL;
    }
  } else
    a = 0;
  for (b = a; b <= strlen(str); b++)
    if (str[b] == split2)
      break;
  ptr = (char *)malloc(sizeof(char) * (b - a + 1));
  strncpy(ptr, &str[a], b - a);
  ptr[b - a] = 0x0;
  return (char *)ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<libgadget_misc_double_split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %ecx,0xc(%rsp)
  mov    %edx,%r13d
  test   %ecx,%ecx
  jne    L75
L36:
  movslq 0xc(%rsp),%r14
  mov    %r14,%rbp
L26:
  mov    %ebp,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jl     L25
  add    $0x1,%rbp
  cmp    %r13b,-0x1(%rbx,%rbp,1)
  jne    L26
L25:
  sub    0xc(%rsp),%r12d
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    (%rbx,%r14,1),%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %r12d,%r12
  movb   $0x0,0x0(%rbp,%r12,1)
L100:
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  je     L1
  add    $0x1,%rbp
L52:
  mov    %ebp,0x8(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %ebp,%r12d
  cmp    %ebp,%eax
  jl     L61
  cmp    %r15b,(%rbx,%rbp,1)
  jne    L15
  add    $0x1,%r14d
  cmp    %r14d,0xc(%rsp)
  jne    L15
  mov    0x8(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0xc(%rsp)
  jmp    L36
L75:
  mov    %esi,%r15d
  mov    $0x0,%ebp
  mov    $0x0,%r14d
  jmp    L52
L61:
  mov    0x8(%rsp),%eax
  mov    %eax,0xc(%rsp)
  jmp    L36
L1:
  mov    $0x0,%ebp
  jmp    L100
```

assistant: ```c
char *libgadget_misc_double_split(char *str, char split1, char split2, int ret) {
  char *ptr;
  int a, b, c = 0;
  if (ret != 0) {
    for (a = 0; a <= strlen(str); a++) {
      if (str[a] == split1 && ++c == ret) {
        a++;
        break;
      }
      if (a == strlen(str))
        return NULL;
    }
  } else
    a = 0;
  for (b = a; b <= strlen(str); b++)
    if (str[b] == split2)
      break;
  ptr = (char *)malloc(sizeof(char) * (b - a + 1));
  strncpy(ptr, &str[a], b - a);
  ptr[b - a] = 0x0;
  return (char *)ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<libgadget_misc_double_split>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %sil,0x7(%rsp)
  test   %ecx,%ecx
  jne    L70
  mov    %rdi,%r14
  xor    %ebx,%ebx
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L63:
  add    $0x1,%rbx
  cmp    %bpl,-0x1(%r15,%rbx,1)
  je     L110
L69:
  mov    %r15,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L63
L110:
  sub    0xc(%rsp),%r12d
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  movslq %r12d,%r12
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%r12,1)
L89:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L70:
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  jmp    L18
L28:
  movzbl 0x7(%rsp),%eax
  cmp    %al,(%r15,%r13,1)
  jne    L78
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  je     L66
L78:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  je     L99
  add    $0x1,%r13
L18:
  mov    %r15,%rdi
  mov    %r13d,0x8(%rsp)
  lea    (%r15,%r13,1),%r14
  mov    %r13d,%ebx
  call   <strlen@plt>
  cmp    %r13d,%eax
  jge    L28
  movslq %r13d,%rbx
  mov    %ebx,0xc(%rsp)
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L99:
  xor    %r13d,%r13d
  jmp    L89
  nopl   (%rax)
L66:
  mov    0x8(%rsp),%eax
  add    $0x1,%eax
  movslq %eax,%rbx
  mov    %eax,0xc(%rsp)
  lea    (%r15,%rbx,1),%r14
  jmp    L69
```

assistant: ```c
char *libgadget_misc_double_split(char *str, char split1, char split2, int ret) {
  char *ptr;
  int a, b, c = 0;
  if (ret != 0) {
    for (a = 0; a <= strlen(str); a++) {
      if (str[a] == split1 && ++c == ret) {
        a++;
        break;
      }
      if (a == strlen(str))
        return NULL;
    }
  } else
    a = 0;
  for (b = a; b <= strlen(str); b++)
    if (str[b] == split2)
      break;
  ptr = (char *)malloc(sizeof(char) * (b - a + 1));
  strncpy(ptr, &str[a], b - a);
  ptr[b - a] = 0x0;
  return (char *)ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<libgadget_misc_double_split>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %sil,0x7(%rsp)
  test   %ecx,%ecx
  jne    L26
  mov    %rdi,%r14
  xor    %ebx,%ebx
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L108:
  add    $0x1,%rbx
  cmp    %bpl,-0x1(%r15,%rbx,1)
  je     L25
L72:
  mov    %r15,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L108
L25:
  sub    0xc(%rsp),%r12d
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  movslq %r12d,%r12
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%r12,1)
L17:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L26:
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  jmp    L85
L111:
  movzbl 0x7(%rsp),%eax
  cmp    %al,(%r15,%r13,1)
  jne    L116
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  je     L8
L116:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  je     L7
  add    $0x1,%r13
L85:
  mov    %r15,%rdi
  mov    %r13d,0x8(%rsp)
  lea    (%r15,%r13,1),%r14
  mov    %r13d,%ebx
  call   <strlen@plt>
  cmp    %r13d,%eax
  jge    L111
  movslq %r13d,%rbx
  mov    %ebx,0xc(%rsp)
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %r13d,%r13d
  jmp    L17
  nopl   (%rax)
L8:
  mov    0x8(%rsp),%eax
  add    $0x1,%eax
  movslq %eax,%rbx
  mov    %eax,0xc(%rsp)
  lea    (%r15,%rbx,1),%r14
  jmp    L72
```

assistant: ```c
char *libgadget_misc_double_split(char *str, char split1, char split2, int ret) {
  char *ptr;
  int a, b, c = 0;
  if (ret != 0) {
    for (a = 0; a <= strlen(str); a++) {
      if (str[a] == split1 && ++c == ret) {
        a++;
        break;
      }
      if (a == strlen(str))
        return NULL;
    }
  } else
    a = 0;
  for (b = a; b <= strlen(str); b++)
    if (str[b] == split2)
      break;
  ptr = (char *)malloc(sizeof(char) * (b - a + 1));
  strncpy(ptr, &str[a], b - a);
  ptr[b - a] = 0x0;
  return (char *)ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cprop_test14>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0xa,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x14,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1e,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L3
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  jmp    L4
L3:
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  sub    %edx,%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cprop_test14(int *data) {
  int i = 10;
  int j = data[0];
  int k = 20;
  int m = data[1];
  int n = 30;
  if (data[2])
    data[3] = i + j + k + m + n;
  else
    data[0] = i * (j - k * (m - n));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cprop_test14>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  cmpl   $0x0,0x8(%rdi)
  je     L8
  lea    0x3c(%rax,%rdx,1),%eax
  mov    %eax,0xc(%rdi)
  ret
L8:
  lea    -0x96(%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void cprop_test14(int *data) {
  int i = 10;
  int j = data[0];
  int k = 20;
  int m = data[1];
  int n = 30;
  if (data[2])
    data[3] = i + j + k + m + n;
  else
    data[0] = i * (j - k * (m - n));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cprop_test14>:
  endbr64
  mov    0x8(%rdi),%ecx
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  test   %ecx,%ecx
  je     L5
  lea    0x3c(%rax,%rdx,1),%eax
  mov    %eax,0xc(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  lea    -0x96(%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void cprop_test14(int *data) {
  int i = 10;
  int j = data[0];
  int k = 20;
  int m = data[1];
  int n = 30;
  if (data[2])
    data[3] = i + j + k + m + n;
  else
    data[0] = i * (j - k * (m - n));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cprop_test14>:
  endbr64
  mov    0x8(%rdi),%ecx
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  test   %ecx,%ecx
  je     L3
  lea    0x3c(%rax,%rdx,1),%eax
  mov    %eax,0xc(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  lea    -0x96(%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void cprop_test14(int *data) {
  int i = 10;
  int j = data[0];
  int k = 20;
  int m = data[1];
  int n = 30;
  if (data[2])
    data[3] = i + j + k + m + n;
  else
    data[0] = i * (j - k * (m - n));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tokenize>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movzbl (%rbx),%eax
  test   %al,%al
  je     L44
  mov    $0x0,%edi
  mov    $0x0,%r12d
  mov    $0x0,%r14d
  jmp    L37
L55:
  movslq %edi,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x1,%edi
  call   <malloc@plt>
  movslq %r12d,%rdx
  lea    0x0(%r13,%rdx,8),%rdx
  mov    %rax,(%rdx)
  movb   $0x0,(%rax)
  mov    %rbp,%rsi
  mov    (%rdx),%rdi
  call   <string_copy@plt>
  add    $0x1,%r12d
  mov    %r14d,%edi
L17:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L38
L37:
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L55
  cmp    $0x20,%al
  je     L55
  movslq %edi,%rdx
  mov    %al,0x0(%rbp,%rdx,1)
  lea    0x1(%rdi),%edi
  jmp    L17
L44:
  mov    $0x0,%edi
  mov    $0x0,%r12d
L38:
  movslq %edi,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x1,%edi
  call   <malloc@plt>
  movslq %r12d,%r12
  lea    0x0(%r13,%r12,8),%rdx
  mov    %rax,(%rdx)
  movb   $0x0,(%rax)
  mov    %rbp,%rsi
  mov    (%rdx),%rdi
  call   <string_copy@plt>
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char **tokenize(char *string) {
  char **tokens = (char **)malloc(5 * sizeof(char *));
  int token_array_idx = 0;
  char *current_char = string;
  char *token = (char *)malloc(20 * sizeof(char));
  int token_idx = 0;
  int in_expression = 0;
  while (*current_char != '\0') {
    if (*current_char == ' ' || *current_char == '\t' || *current_char == '\n') {
      token[token_idx] = '\0';
      *(tokens + token_array_idx) = (char *)malloc(sizeof(char) * (token_idx + 1));
      **(tokens + token_array_idx) = '\0';
      string_copy(*(tokens + token_array_idx), token);
      token_array_idx++;
      token_idx = 0;
    } else {
      token[token_idx++] = *current_char;
    }
    current_char++;
  }
  token[token_idx] = '\0';
  *(tokens + token_array_idx) = (char *)malloc(sizeof(char) * (token_idx + 1));
  **(tokens + token_array_idx) = '\0';
  string_copy(*(tokens + token_array_idx), token);
  return tokens;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tokenize>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    $0x14,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  movzbl (%rbx),%eax
  test   %al,%al
  je     L56
  xor    %ecx,%ecx
  xor    %r13d,%r13d
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L69:
  cmp    $0x20,%al
  je     L15
  add    $0x1,%rbx
  mov    %al,(%rdx)
  movslq %edi,%rdx
  lea    0x2(%rcx),%r8d
  movzbl (%rbx),%eax
  add    %rbp,%rdx
  mov    %edi,%ecx
  test   %al,%al
  je     L8
L23:
  movslq %ecx,%rdx
  lea    -0x9(%rax),%esi
  lea    0x1(%rcx),%edi
  add    %rbp,%rdx
  cmp    $0x1,%sil
  ja     L69
L15:
  movb   $0x0,(%rdx)
  movslq %r13d,%rax
  add    $0x1,%rbx
  add    $0x1,%r13d
  lea    (%r12,%rax,8),%r14
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%r14)
  movb   $0x0,(%rax)
  mov    (%r14),%rdi
  call   <string_copy@plt>
  movzbl (%rbx),%eax
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  mov    $0x1,%r8d
  test   %al,%al
  jne    L23
L8:
  movslq %r13d,%r13
  lea    (%r12,%r13,8),%rbx
L0:
  movb   $0x0,(%rdx)
  mov    %r8d,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  movb   $0x0,(%rax)
  mov    (%rbx),%rdi
  call   <string_copy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %r12,%rbx
  mov    %rbp,%rdx
  mov    $0x1,%r8d
  jmp    L0
```

assistant: ```c
char **tokenize(char *string) {
  char **tokens = (char **)malloc(5 * sizeof(char *));
  int token_array_idx = 0;
  char *current_char = string;
  char *token = (char *)malloc(20 * sizeof(char));
  int token_idx = 0;
  int in_expression = 0;
  while (*current_char != '\0') {
    if (*current_char == ' ' || *current_char == '\t' || *current_char == '\n') {
      token[token_idx] = '\0';
      *(tokens + token_array_idx) = (char *)malloc(sizeof(char) * (token_idx + 1));
      **(tokens + token_array_idx) = '\0';
      string_copy(*(tokens + token_array_idx), token);
      token_array_idx++;
      token_idx = 0;
    } else {
      token[token_idx++] = *current_char;
    }
    current_char++;
  }
  token[token_idx] = '\0';
  *(tokens + token_array_idx) = (char *)malloc(sizeof(char) * (token_idx + 1));
  **(tokens + token_array_idx) = '\0';
  string_copy(*(tokens + token_array_idx), token);
  return tokens;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tokenize>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    $0x14,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  movzbl (%rbx),%eax
  test   %al,%al
  je     L77
  xor    %edi,%edi
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L69:
  movslq %edi,%rdx
  lea    -0x9(%rax),%ecx
  lea    0x1(%rdi),%r8d
  add    %rbp,%rdx
  cmp    $0x1,%cl
  jbe    L16
  cmp    $0x20,%al
  je     L16
  mov    %al,(%rdx)
  add    $0x1,%rbx
  movslq %r8d,%rax
  add    $0x2,%edi
  lea    0x0(%rbp,%rax,1),%rdx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L48
  mov    %r8d,%edi
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L16:
  movb   $0x0,(%rdx)
  movslq %r13d,%rax
  mov    %r8d,%edi
  add    $0x1,%rbx
  lea    (%r12,%rax,8),%r14
  add    $0x1,%r13d
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%r14)
  movb   $0x0,(%rax)
  mov    (%r14),%rdi
  call   <string_copy@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L72
  xor    %edi,%edi
  jmp    L69
  xchg   %ax,%ax
L72:
  mov    %rbp,%rdx
  mov    $0x1,%edi
L48:
  movslq %r13d,%r13
  lea    (%r12,%r13,8),%rbx
L24:
  movb   $0x0,(%rdx)
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  movb   $0x0,(%rax)
  mov    (%rbx),%rdi
  call   <string_copy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L77:
  mov    %r12,%rbx
  mov    %rbp,%rdx
  mov    $0x1,%edi
  jmp    L24
```

assistant: ```c
char **tokenize(char *string) {
  char **tokens = (char **)malloc(5 * sizeof(char *));
  int token_array_idx = 0;
  char *current_char = string;
  char *token = (char *)malloc(20 * sizeof(char));
  int token_idx = 0;
  int in_expression = 0;
  while (*current_char != '\0') {
    if (*current_char == ' ' || *current_char == '\t' || *current_char == '\n') {
      token[token_idx] = '\0';
      *(tokens + token_array_idx) = (char *)malloc(sizeof(char) * (token_idx + 1));
      **(tokens + token_array_idx) = '\0';
      string_copy(*(tokens + token_array_idx), token);
      token_array_idx++;
      token_idx = 0;
    } else {
      token[token_idx++] = *current_char;
    }
    current_char++;
  }
  token[token_idx] = '\0';
  *(tokens + token_array_idx) = (char *)malloc(sizeof(char) * (token_idx + 1));
  **(tokens + token_array_idx) = '\0';
  string_copy(*(tokens + token_array_idx), token);
  return tokens;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<umrechnung_us_dollar_in_euro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double umrechnung_us_dollar_in_euro(double betrag_in_us_dollar, double umrechnungsfaktor) {
  double betrag_in_euro = umrechnungsfaktor * betrag_in_us_dollar;
  return betrag_in_euro;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<umrechnung_us_dollar_in_euro>:
  endbr64
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double umrechnung_us_dollar_in_euro(double betrag_in_us_dollar, double umrechnungsfaktor) {
  double betrag_in_euro = umrechnungsfaktor * betrag_in_us_dollar;
  return betrag_in_euro;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<umrechnung_us_dollar_in_euro>:
  endbr64
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double umrechnung_us_dollar_in_euro(double betrag_in_us_dollar, double umrechnungsfaktor) {
  double betrag_in_euro = umrechnungsfaktor * betrag_in_us_dollar;
  return betrag_in_euro;
}
```
user: Translate the below assembly code into C programming language:

```asm
<umrechnung_us_dollar_in_euro>:
  endbr64
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double umrechnung_us_dollar_in_euro(double betrag_in_us_dollar, double umrechnungsfaktor) {
  double betrag_in_euro = umrechnungsfaktor * betrag_in_us_dollar;
  return betrag_in_euro;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findnext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L8
L13:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <factorf@plt>
  cmp    $0x1,%eax
  jne    L13
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int findnext(int M) {
  int N;
  N = M;
  while (factorf(N) != 1) {
    ++N;
  }
  return N;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findnext>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  jmp    L8
L18:
  add    $0x1,%ebx
L8:
  mov    %ebx,%edi
  call   <factorf@plt>
  cmp    $0x1,%eax
  jne    L18
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int findnext(int M) {
  int N;
  N = M;
  while (factorf(N) != 1) {
    ++N;
  }
  return N;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findnext>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%r12d
L5:
  mov    %r12d,%edi
  call   <factorf@plt>
  cmp    $0x1,%eax
  jne    L4
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int findnext(int M) {
  int N;
  N = M;
  while (factorf(N) != 1) {
    ++N;
  }
  return N;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<findnext>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%r12d
L13:
  mov    %r12d,%edi
  call   <factorf@plt>
  cmp    $0x1,%eax
  jne    L15
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int findnext(int M) {
  int N;
  N = M;
  while (factorf(N) != 1) {
    ++N;
  }
  return N;
}
```