ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<change>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x6,(%rsp)
  movl   $0x9,0x4(%rsp)
  mov    $0x9,%edx
  mov    $0x6,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  mov    %rsp,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <swap1@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string
name: parse_data
arguments: data_tag: D26
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D40
datatype: string

tool: D16: nuchange x,y=%d,%d


tool: D15: swap changed num is: %d,%d


tool: D3: swap1 changed num is: %d,%d


tool: D26: SWAP changed num is: %d,%d


tool: D38: max is %d


tool: D40: min is %d


assistant: ```c
int change() {
  int x = 6;
  int y = 9;
  printf("nuchange x,y=%d,%d\n", x, y);
  swap(&x, &y);
  printf("swap changed num is: %d,%d\n", x, y);
  swap1(&x, &y);
  printf("swap1 changed num is: %d,%d\n", x, y);
  {
    int temp;
    temp = (x);
    (x) = (y);
    (y) = temp;
  };
  printf("SWAP changed num is: %d,%d\n", x, y);
  printf("max is %d\n", (((x) > (y)) ? (x) : (y)));
  printf("min is %d\n", (((x) < (y)) ? (x) : (y)));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<change>:
  endbr64
  push   %r12
  mov    $0x9,%edx
  mov    $0x6,%esi
  lea    D54(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  movl   $0x6,(%rsp)
  movl   $0x9,0x4(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap1@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D53(%rip),%rdi
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  call   <printf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  lea    D38(%rip),%rdi
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  lea    D29(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D54
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D22
datatype: string
name: disassemble_data
arguments: data_label: D53
datatype: string
name: disassemble_data
arguments: data_label: D38
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string

tool: D54: nuchange x,y=%d,%d


tool: D1: swap changed num is: %d,%d


tool: D22: swap1 changed num is: %d,%d


tool: D53: SWAP changed num is: %d,%d


tool: D38: max is %d


tool: D29: min is %d


assistant: ```c
int change() {
  int x = 6;
  int y = 9;
  printf("nuchange x,y=%d,%d\n", x, y);
  swap(&x, &y);
  printf("swap changed num is: %d,%d\n", x, y);
  swap1(&x, &y);
  printf("swap1 changed num is: %d,%d\n", x, y);
  {
    int temp;
    temp = (x);
    (x) = (y);
    (y) = temp;
  };
  printf("SWAP changed num is: %d,%d\n", x, y);
  printf("max is %d\n", (((x) > (y)) ? (x) : (y)));
  printf("min is %d\n", (((x) < (y)) ? (x) : (y)));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<change>:
  endbr64
  push   %r12
  mov    $0x9,%edx
  mov    $0x6,%esi
  lea    D16(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  movl   $0x6,(%rsp)
  movl   $0x9,0x4(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap1@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  call   <printf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  lea    D41(%rip),%rdi
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  lea    D14(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D45
datatype: string
name: disassemble_data
arguments: tag: D26
datatype: string
name: disassemble_data
arguments: tag: D27
datatype: string
name: disassemble_data
arguments: tag: D41
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string

tool: D16: nuchange x,y=%d,%d


tool: D45: swap changed num is: %d,%d


tool: D26: swap1 changed num is: %d,%d


tool: D27: SWAP changed num is: %d,%d


tool: D41: max is %d


tool: D14: min is %d


assistant: ```c
int change() {
  int x = 6;
  int y = 9;
  printf("nuchange x,y=%d,%d\n", x, y);
  swap(&x, &y);
  printf("swap changed num is: %d,%d\n", x, y);
  swap1(&x, &y);
  printf("swap1 changed num is: %d,%d\n", x, y);
  {
    int temp;
    temp = (x);
    (x) = (y);
    (y) = temp;
  };
  printf("SWAP changed num is: %d,%d\n", x, y);
  printf("max is %d\n", (((x) > (y)) ? (x) : (y)));
  printf("min is %d\n", (((x) < (y)) ? (x) : (y)));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stdlib_strided_snansumkbn2>:
  endbr64
  test   %rdi,%rdi
  jle    L120
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbx
  cmp    $0x1,%rdi
  je     L13
  test   %rdx,%rdx
  je     L13
  mov    $0x0,%eax
  js     L109
L78:
  lea    0x0(,%rdx,4),%r13
  lea    (%rbx,%rax,4),%r12
  pxor   %xmm2,%xmm2
  movss  %xmm2,0x10(%rsp)
  movss  %xmm2,0x1c(%rsp)
  movss  %xmm2,0xc(%rsp)
  mov    $0x0,%ebp
  jmp    L132
L13:
  movss  (%rbx),%xmm0
  call   <stdlib_base_is_nanf@plt>
  pxor   %xmm0,%xmm0
  test   %rax,%rax
  jne    L3
  movss  (%rbx),%xmm0
  jmp    L3
L109:
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
  jmp    L78
L79:
  movd   %ebx,%xmm0
  subss  0x14(%rsp),%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  jmp    L94
L18:
  movss  0xc(%rsp),%xmm0
  subss  0x18(%rsp),%xmm0
  addss  0x10(%rsp),%xmm0
L110:
  addss  0x1c(%rsp),%xmm0
  movss  %xmm0,0x1c(%rsp)
  movss  0x18(%rsp),%xmm6
  movss  %xmm6,0x10(%rsp)
  movss  0x14(%rsp),%xmm7
  movss  %xmm7,0xc(%rsp)
L54:
  add    $0x1,%rbp
  add    %r13,%r12
  cmp    %rbp,%r14
  je     L44
L132:
  mov    (%r12),%ebx
  movd   %ebx,%xmm0
  call   <stdlib_base_is_nanf@plt>
  test   %rax,%rax
  jne    L54
  movd   %ebx,%xmm4
  movss  0xc(%rsp),%xmm0
  addss  %xmm0,%xmm4
  movss  %xmm4,0x14(%rsp)
  call   <fabsf@plt>
  mov    %rax,%r15
  movd   %ebx,%xmm0
  call   <fabsf@plt>
  cmp    %rax,%r15
  jl     L79
  movss  0xc(%rsp),%xmm0
  subss  0x14(%rsp),%xmm0
  movd   %ebx,%xmm5
  addss  %xmm0,%xmm5
  movss  %xmm5,0xc(%rsp)
L94:
  movss  0xc(%rsp),%xmm1
  movss  0x10(%rsp),%xmm3
  addss  %xmm3,%xmm1
  movss  %xmm1,0x18(%rsp)
  movaps %xmm3,%xmm0
  call   <fabsf@plt>
  mov    %rax,%rbx
  movss  0xc(%rsp),%xmm0
  call   <fabsf@plt>
  cmp    %rax,%rbx
  jl     L18
  movss  0x10(%rsp),%xmm3
  subss  0x18(%rsp),%xmm3
  movaps %xmm3,%xmm0
  addss  0xc(%rsp),%xmm0
  jmp    L110
L44:
  movss  0xc(%rsp),%xmm0
  addss  0x10(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
L3:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L120:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float stdlib_strided_snansumkbn2(const int64_t N, const float *X, const int64_t stride) {
  int64_t ix;
  int64_t i;
  float sum;
  float ccs;
  float cs;
  float cc;
  float v;
  float t;
  float c;
  sum = 0.0f;
  if (N <= 0) {
    return sum;
  }
  if (N == 1 || stride == 0) {
    if (stdlib_base_is_nanf(X[0])) {
      return sum;
    }
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  ccs = 0.0f;
  cs = 0.0f;
  for (i = 0; i < N; i++) {
    v = X[ix];
    if (!stdlib_base_is_nanf(v)) {
      t = sum + v;
      if (fabsf(sum) >= fabsf(v)) {
        c = (sum - t) + v;
      } else {
        c = (v - t) + sum;
      }
      sum = t;
      t = cs + c;
      if (fabsf(cs) >= fabsf(c)) {
        cc = (cs - t) + c;
      } else {
        cc = (c - t) + cs;
      }
      cs = t;
      ccs += cc;
    }
    ix += stride;
  }
  return sum + cs + ccs;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L13:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_one(int x) {
#pragma omp target teams distribute parallel for
  for (int i = 0; i < x; i++)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_one>:
  endbr64
  test   %edi,%edi
  jle    L9
  mov    $0x0,%eax
L10:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L10
L9:
  ret
```

assistant: ```c
void test_one(int x) {
#pragma omp target teams distribute parallel for
  for (int i = 0; i < x; i++)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_one>:
  endbr64
  ret
```

assistant: ```c
void test_one(int x) {
#pragma omp target teams distribute parallel for
  for (int i = 0; i < x; i++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_one>:
  endbr64
  ret
```

assistant: ```c
void test_one(int x) {
#pragma omp target teams distribute parallel for
  for (int i = 0; i < x; i++)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<circular_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  -0x14(%rbp),%xmm0
  divss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x1c(%rbp),%xmm0
  movss  D0(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <powf@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  sub    %rdx,%rax
  mov    %rax,%rdi
  call   <sqrtf@plt>
  sub    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  -0x20(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x80]}

assistant: ```c
float circular_in(float step, float max_steps, float max_val) {
  float ratio = step / max_steps;
  return -max_val * (sqrtf(1 - powf(ratio, 2)) - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<circular_in>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm2,0xc(%rsp)
  divss  %xmm1,%xmm0
  mov    $0x2,%edi
  call   <powf@plt>
  mov    $0x1,%edi
  sub    %rax,%rdi
  call   <sqrtf@plt>
  sub    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  0xc(%rsp),%xmm1
  xorps  D5(%rip),%xmm1
  mulss  %xmm1,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float circular_in(float step, float max_steps, float max_val) {
  float ratio = step / max_steps;
  return -max_val * (sqrtf(1 - powf(ratio, 2)) - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<circular_in>:
  endbr64
  divss  %xmm1,%xmm0
  sub    $0x18,%rsp
  mov    $0x2,%edi
  movss  %xmm2,0xc(%rsp)
  call   <powf@plt>
  mov    $0x1,%edi
  sub    %rax,%rdi
  call   <sqrtf@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm2
  xorps  D1(%rip),%xmm2
  sub    $0x1,%eax
  add    $0x18,%rsp
  cvtsi2ss %eax,%xmm0
  mulss  %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float circular_in(float step, float max_steps, float max_val) {
  float ratio = step / max_steps;
  return -max_val * (sqrtf(1 - powf(ratio, 2)) - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<circular_in>:
  endbr64
  divss  %xmm1,%xmm0
  sub    $0x18,%rsp
  mov    $0x2,%edi
  movss  %xmm2,0xc(%rsp)
  call   <powf@plt>
  mov    $0x1,%edi
  sub    %rax,%rdi
  call   <sqrtf@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm2
  xorps  D5(%rip),%xmm2
  sub    $0x1,%eax
  add    $0x18,%rsp
  cvtsi2ss %eax,%xmm0
  mulss  %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float circular_in(float step, float max_steps, float max_val) {
  float ratio = step / max_steps;
  return -max_val * (sqrtf(1 - powf(ratio, 2)) - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L2
  mov    -0x14(%rbp),%eax
  cltq
  jmp    L19
L2:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
L19:
  leave
  ret
```

assistant: ```c
unsigned long long int fib(int n) {
  int x, y;
  if (n < 2)
    return n;
  else {
    x = fib(n - 1);
    y = fib(n - 2);
    return x + y;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movslq %edi,%rax
  cmp    $0x1,%edi
  jg     L13
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %rax,%rbp
  lea    -0x2(%rbx),%edi
  call   <fib>
  add    %eax,%ebp
  movslq %ebp,%rax
  jmp    L2
```

assistant: ```c
unsigned long long int fib(int n) {
  int x, y;
  if (n < 2)
    return n;
  else {
    x = fib(n - 1);
    y = fib(n - 2);
    return x + y;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fib>:
  endbr64
  push   %r14
  movslq %edi,%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L63
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L63:
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jne    L76
L82:
  cltq
L77:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L76:
  lea    -0x3(%rdi),%r13d
  mov    $0x2,%eax
  cmp    $0x3,%edi
  je     L82
  mov    %r13d,%edi
  lea    -0x4(%rbx),%r14d
  call   <fib>
  mov    %r14d,%edi
  mov    %rax,%rbp
  call   <fib>
  mov    %rax,%r12
  add    %eax,%ebp
  cmp    $0x1,%r13d
  je     L30
  lea    -0x5(%rbx),%edi
  call   <fib>
  add    %eax,%r12d
  add    %r12d,%ebp
L25:
  mov    $0x1,%eax
  cmp    $0x4,%ebx
  jne    L29
  add    %ebp,%eax
L9:
  cltq
  jmp    L77
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    %r14d,%edi
  call   <fib>
  lea    -0x5(%rbx),%edi
  mov    %rax,%r12
  call   <fib>
  mov    %rax,%r13
  add    %eax,%r12d
  cmp    $0x1,%r14d
  je     L7
  lea    -0x6(%rbx),%edi
  call   <fib>
  add    %eax,%r13d
  lea    0x0(%r13,%r12,1),%eax
  add    %ebp,%eax
  jmp    L9
L30:
  add    $0x1,%ebp
  jmp    L25
L7:
  lea    0x1(%r12),%eax
  add    %ebp,%eax
  jmp    L9
```

assistant: ```c
unsigned long long int fib(int n) {
  int x, y;
  if (n < 2)
    return n;
  else {
    x = fib(n - 1);
    y = fib(n - 2);
    return x + y;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fib>:
  endbr64
  push   %r14
  movslq %edi,%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L2:
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jne    L18
L63:
  cltq
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L18:
  lea    -0x3(%rdi),%r13d
  mov    $0x2,%eax
  cmp    $0x3,%edi
  je     L63
  mov    %r13d,%edi
  lea    -0x4(%rbx),%r14d
  call   <fib>
  mov    %r14d,%edi
  mov    %rax,%rbp
  call   <fib>
  mov    %rax,%r12
  add    %eax,%ebp
  cmp    $0x1,%r13d
  je     L65
  lea    -0x5(%rbx),%edi
  call   <fib>
  add    %eax,%r12d
  add    %r12d,%ebp
L69:
  mov    $0x1,%eax
  cmp    $0x4,%ebx
  jne    L21
  add    %ebp,%eax
L39:
  cltq
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %r14d,%edi
  call   <fib>
  lea    -0x5(%rbx),%edi
  mov    %rax,%r12
  call   <fib>
  mov    %rax,%r13
  add    %eax,%r12d
  cmp    $0x1,%r14d
  je     L77
  lea    -0x6(%rbx),%edi
  call   <fib>
  add    %eax,%r13d
  lea    0x0(%r13,%r12,1),%eax
  add    %ebp,%eax
  jmp    L39
L65:
  add    $0x1,%ebp
  jmp    L69
L77:
  lea    0x1(%r12),%eax
  add    %ebp,%eax
  jmp    L39
```

assistant: ```c
unsigned long long int fib(int n) {
  int x, y;
  if (n < 2)
    return n;
  else {
    x = fib(n - 1);
    y = fib(n - 2);
    return x + y;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<lopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L14
L5:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L17
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x18(%rbp)
  jne    L17
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <argdel@plt>
  mov    $0x1,%eax
  jmp    L39
L17:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jl     L5
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
long lopt(int argc, char *argv[], char c) {
  long i;
  for (i = 1; i < argc; i++)
    if (argv[i][0] == '-' && argv[i][1] == c) {
      argdel(argc, i);
      return 1;
    }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lopt>:
  endbr64
  cmp    $0x1,%edi
  jle    L46
  mov    %rsi,%rcx
  movslq %edi,%r8
  mov    $0x1,%esi
  jmp    L48
L20:
  add    $0x1,%rsi
  cmp    %r8,%rsi
  je     L16
L48:
  mov    (%rcx,%rsi,8),%rax
  cmpb   $0x2d,(%rax)
  jne    L20
  cmp    %dl,0x1(%rax)
  jne    L20
  sub    $0x8,%rsp
  call   <argdel@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L16:
  mov    $0x0,%eax
  ret
L46:
  mov    $0x0,%eax
  ret
```

assistant: ```c
long lopt(int argc, char *argv[], char c) {
  long i;
  for (i = 1; i < argc; i++)
    if (argv[i][0] == '-' && argv[i][1] == c) {
      argdel(argc, i);
      return 1;
    }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lopt>:
  endbr64
  cmp    $0x1,%edi
  jle    L35
  mov    %rsi,%rcx
  movslq %edi,%r8
  mov    $0x1,%esi
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x1,%rsi
  cmp    %r8,%rsi
  je     L35
L11:
  mov    (%rcx,%rsi,8),%rax
  cmpb   $0x2d,(%rax)
  jne    L9
  cmp    %dl,0x1(%rax)
  jne    L9
  sub    $0x8,%rsp
  call   <argdel@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
long lopt(int argc, char *argv[], char c) {
  long i;
  for (i = 1; i < argc; i++)
    if (argv[i][0] == '-' && argv[i][1] == c) {
      argdel(argc, i);
      return 1;
    }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<lopt>:
  endbr64
  cmp    $0x1,%edi
  jle    L27
  mov    %rsi,%rcx
  movslq %edi,%r8
  mov    $0x1,%esi
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x1,%rsi
  cmp    %r8,%rsi
  je     L27
L25:
  mov    (%rcx,%rsi,8),%rax
  cmpb   $0x2d,(%rax)
  jne    L10
  cmp    %dl,0x1(%rax)
  jne    L10
  sub    $0x8,%rsp
  call   <argdel@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
long lopt(int argc, char *argv[], char c) {
  long i;
  for (i = 1; i < argc; i++)
    if (argv[i][0] == '-' && argv[i][1] == c) {
      argdel(argc, i);
      return 1;
    }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stp_count_pkts_in_raw_etb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L0
L27:
  mov    -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <stp_count_pkts@plt>
  add    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L0:
  lea    -0x20(%rbp),%rdi
  lea    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <stp_find_first_block@plt>
  test   %rax,%rax
  je     L27
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
size_t stp_count_pkts_in_raw_etb(char *buf, size_t u8size) {
  off_t start = 0;
  off_t block_off;
  size_t block_len;
  size_t count = 0;
  while (stp_find_first_block(buf, u8size, start, &block_off, &block_len) == 0) {
    count += stp_count_pkts(&buf[block_off], block_len);
    start = block_off + block_len;
  }
  return count;
}
```