user: 请从给定的汇编指令推导出C源代码:

```asm
<bar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  mov    $0x1,%edi
  jl     L143
  call   <f2@plt>
  cmp    %ebp,%ebx
  jle    L40
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
L111:
  mov    $0x1,%edi
  mov    %ebx,%r13d
  call   <f2@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  setne  %dil
  call   <f2@plt>
  or     %ebp,%r13d
  jne    L53
L8:
  mov    $0x1,%edi
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
L112:
  mov    $0x2,%edi
L147:
  call   <f2@plt>
  test   %r13d,%r13d
  jne    L10
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
L11:
  call   <f2@plt>
  mov    %ebx,%edi
  mov    $0x1,%r12d
  imul   %ebp,%edi
  test   %edi,%edi
  cmove  %r12d,%edi
  call   <f2@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %eax,%eax
  cmove  %r12d,%eax
  mov    %eax,%edi
  call   <f2@plt>
  mov    %ebx,%edi
  xor    %ebp,%edi
  cmp    %ebp,%ebx
  cmove  %r12d,%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <f2@plt>
  nopl   0x0(%rax)
L143:
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    %ebx,%eax
  or     %ebp,%eax
  je     L8
  mov    $0x1,%edi
  call   <f2@plt>
  test   %ebp,%ebp
  mov    $0x1,%edi
  setne  %r12b
  test   %ebx,%ebx
  setne  %al
  and    %eax,%r12d
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x2,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
L10:
  mov    $0x2,%edi
  call   <f2@plt>
  movzbl %r12b,%edi
  add    $0x1,%edi
  call   <f2@plt>
  mov    %ebx,%edi
  add    %ebp,%edi
  je     L43
L101:
  call   <f2@plt>
  mov    %ebx,%edi
  sub    %ebp,%edi
  jne    L11
  mov    $0x1,%edi
  jmp    L11
  nopl   0x0(%rax)
L40:
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  cmp    %ebp,%ebx
  jne    L111
  mov    $0x1,%edi
  mov    %ebx,%r13d
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  test   %ebx,%ebx
  je     L8
  mov    $0x1,%edi
  mov    $0x1,%r12d
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
L93:
  mov    $0x1,%edi
  call   <f2@plt>
  cmp    %ebp,%ebx
  jle    L64
  mov    $0x2,%edi
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  jmp    L10
L64:
  mov    $0x1,%edi
  call   <f2@plt>
  cmp    %ebp,%ebx
  je     L112
  mov    $0x1,%edi
  jmp    L147
L43:
  mov    $0x1,%edi
  jmp    L101
L53:
  mov    $0x1,%edi
  call   <f2@plt>
  test   %ebx,%ebx
  mov    $0x1,%edi
  setne  %r12b
  test   %ebp,%ebp
  setne  %al
  and    %eax,%r12d
  call   <f2@plt>
  mov    $0x1,%edi
  call   <f2@plt>
  jmp    L93
```

assistant: ```c
void bar(int x, int y, int z) {
  f2(x < y ?: 1);
  f2(x > y ?: 1);
  f2(x <= y ?: 1);
  f2(x >= y ?: 1);
  f2(x == y ?: 1);
  f2(x != y ?: 1);
  f2(x || y ?: 1);
  f2(x && y ?: 1);
  f2(!x ?: 1);
  f2(x < y ? 2 : 1);
  f2(x > y ? 2 : 1);
  f2(x == y ? 2 : 1);
  f2(x || y ? 2 : 1);
  f2(x && y ? 2 : 1);
  f2(x + y ?: 1);
  f2(x - y ?: 1);
  f2(x * y ?: 1);
  f2(x / y ?: 1);
  f2(x ^ y ?: 1);
}
```