ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<common_euclidDist2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float common_euclidDist2(float *pt1, float *pt2, int numdims) {
  int i;
  float ans = 0.0F;
  for (i = 0; i < numdims; i++) {
    ans += (pt1[i] - pt2[i]) * (pt1[i] - pt2[i]);
  }
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<common_euclidDist2>:
  endbr64
  test   %edx,%edx
  jle    L6
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L3:
  movss  (%rdi,%rax,4),%xmm0
  subss  (%rsi,%rax,4),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L0:
  movaps %xmm1,%xmm0
  ret
L6:
  pxor   %xmm1,%xmm1
  jmp    L0
```

assistant: ```c
float common_euclidDist2(float *pt1, float *pt2, int numdims) {
  int i;
  float ans = 0.0F;
  for (i = 0; i < numdims; i++) {
    ans += (pt1[i] - pt2[i]) * (pt1[i] - pt2[i]);
  }
  return ans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<common_euclidDist2>:
  endbr64
  test   %edx,%edx
  jle    L7
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L13:
  movss  (%rdi,%rax,4),%xmm0
  subss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L13
  movaps %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float common_euclidDist2(float *pt1, float *pt2, int numdims) {
  int i;
  float ans = 0.0F;
  for (i = 0; i < numdims; i++) {
    ans += (pt1[i] - pt2[i]) * (pt1[i] - pt2[i]);
  }
  return ans;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<common_euclidDist2>:
  endbr64
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L66
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L29
  mov    %edx,%esi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%esi
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L67:
  movups (%rdi,%rax,1),%xmm1
  movups (%rcx,%rax,1),%xmm3
  add    $0x10,%rax
  subps  %xmm3,%xmm1
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L67
  mov    %edx,%esi
  and    $0xfffffffc,%esi
  mov    %esi,%eax
  cmp    %esi,%edx
  je     L39
L24:
  sub    %esi,%edx
  cmp    $0x1,%edx
  je     L63
  movq   (%rdi,%rsi,4),%xmm1
  movq   (%rcx,%rsi,4),%xmm2
  mov    %edx,%esi
  and    $0xfffffffe,%esi
  subps  %xmm2,%xmm1
  add    %esi,%eax
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  shufps $0xe5,%xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %esi,%edx
  je     L34
L63:
  cltq
  movss  (%rdi,%rax,4),%xmm1
  subss  (%rcx,%rax,4),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L66:
  pxor   %xmm0,%xmm0
L34:
  ret
  nopl   (%rax)
L39:
  ret
L29:
  xor    %esi,%esi
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L24
```

assistant: ```c
float common_euclidDist2(float *pt1, float *pt2, int numdims) {
  int i;
  float ans = 0.0F;
  for (i = 0; i < numdims; i++) {
    ans += (pt1[i] - pt2[i]) * (pt1[i] - pt2[i]);
  }
  return ans;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ftime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%edi
  call   <__set_errno@plt>
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,%rdi
  call   <time@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L53
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L53
  mov    $0xffffffff,%eax
  jmp    L32
L53:
  mov    -0x28(%rbp),%rax
  movq   $0x0,0x10(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <__localtime_r@plt>
  test   %rax,%rax
  jne    L24
  mov    $0xffffffff,%eax
  jmp    L32
L24:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0x0,%eax
L32:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int ftime(struct timeb *timebuf) {
  int save = errno;
  struct tm tp;
  __set_errno(0);
  if (time(&timebuf->time) == (time_t)-1 && errno != 0)
    return -1;
  timebuf->millitm = 0;
  if (__localtime_r(&timebuf->time, &tp) == NULL)
    return -1;
  timebuf->timezone = tp.tm_gmtoff / 60;
  timebuf->dstflag = tp.tm_isdst;
  __set_errno(save);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ftime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  mov    (%rax),%ebp
  mov    $0x0,%edi
  call   <__set_errno@plt>
  lea    0x8(%rbx),%r12
  mov    %r12,%rdi
  call   <time@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L42
  mov    D12(%rip),%rax
  cmpl   $0x0,(%rax)
  jne    L41
L42:
  movq   $0x0,0x10(%rbx)
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <__localtime_r@plt>
  test   %rax,%rax
  je     L40
  mov    (%rsp),%edx
  movslq %edx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x5,%eax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  mov    %eax,0x4(%rbx)
  mov    %ebp,%edi
  call   <__set_errno@plt>
  mov    $0x0,%eax
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    $0xffffffff,%eax
  jmp    L48
L40:
  mov    $0xffffffff,%eax
  jmp    L48
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ftime(struct timeb *timebuf) {
  int save = errno;
  struct tm tp;
  __set_errno(0);
  if (time(&timebuf->time) == (time_t)-1 && errno != 0)
    return -1;
  timebuf->millitm = 0;
  if (__localtime_r(&timebuf->time, &tp) == NULL)
    return -1;
  timebuf->timezone = tp.tm_gmtoff / 60;
  timebuf->dstflag = tp.tm_isdst;
  __set_errno(save);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ftime>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  lea    0x8(%rbx),%r12
  sub    $0x18,%rsp
  mov    D7(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x0(%r13),%ebp
  call   <__set_errno@plt>
  mov    %r12,%rdi
  call   <time@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L30
  mov    0x0(%r13),%eax
  test   %eax,%eax
  jne    L34
L30:
  movq   $0x0,0x10(%rbx)
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <__localtime_r@plt>
  test   %rax,%rax
  je     L34
  movslq (%rsp),%rax
  mov    %ebp,%edi
  mov    %rax,%rdx
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x1f,%edx
  sar    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  mov    %eax,0x4(%rbx)
  call   <__set_errno@plt>
  xor    %eax,%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L34:
  mov    $0xffffffff,%eax
  jmp    L26
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ftime(struct timeb *timebuf) {
  int save = errno;
  struct tm tp;
  __set_errno(0);
  if (time(&timebuf->time) == (time_t)-1 && errno != 0)
    return -1;
  timebuf->millitm = 0;
  if (__localtime_r(&timebuf->time, &tp) == NULL)
    return -1;
  timebuf->timezone = tp.tm_gmtoff / 60;
  timebuf->dstflag = tp.tm_isdst;
  __set_errno(save);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ftime>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  lea    0x8(%rbx),%r12
  sub    $0x18,%rsp
  mov    D9(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x0(%r13),%ebp
  call   <__set_errno@plt>
  mov    %r12,%rdi
  call   <time@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L18
  mov    0x0(%r13),%eax
  test   %eax,%eax
  jne    L27
L18:
  movq   $0x0,0x10(%rbx)
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <__localtime_r@plt>
  test   %rax,%rax
  je     L27
  movslq (%rsp),%rax
  movd   0x4(%rsp),%xmm1
  mov    %ebp,%edi
  mov    %rax,%rdx
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x1f,%edx
  sar    $0x5,%eax
  sub    %edx,%eax
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rbx)
  call   <__set_errno@plt>
  xor    %eax,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%eax
  jmp    L34
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ftime(struct timeb *timebuf) {
  int save = errno;
  struct tm tp;
  __set_errno(0);
  if (time(&timebuf->time) == (time_t)-1 && errno != 0)
    return -1;
  timebuf->millitm = 0;
  if (__localtime_r(&timebuf->time, &tp) == NULL)
    return -1;
  timebuf->timezone = tp.tm_gmtoff / 60;
  timebuf->dstflag = tp.tm_isdst;
  __set_errno(save);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D41(%rip),%rax
  mov    %rax,-0x90(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x88(%rbp)
  lea    D56(%rip),%rax
  mov    %rax,-0x80(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x70(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expand@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expand@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x80(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expand@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expand@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D41
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D56
type_guessed: string
name: retrieve_data
arguments: data_tag: D42
type_guessed: string
name: retrieve_data
arguments: data_tag: D58
type_guessed: string

tool: D41: a-zA-

tool: D4: -zA-G

tool: D56: 0-3-9

tool: D42: 0-9a-z

tool: D58: %s:%s


assistant: ```c
int main() {
  char *a1 = "a-zA-";
  char *a2 = "-zA-G";
  char *a3 = "0-3-9";
  char *a4 = "0-9a-z";
  char s[100] = {0};
  expand(a1, s);
  printf("%s:%s\n", a1, s);
  expand(a2, s);
  printf("%s:%s\n", a2, s);
  expand(a3, s);
  printf("%s:%s\n", a3, s);
  expand(a4, s);
  printf("%s:%s\n", a4, s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D37(%rip),%rbp
  mov    %rbp,%rdi
  call   <expand@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D32(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D23(%rip),%r12
  mov    %r12,%rdi
  call   <expand@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D17(%rip),%r12
  mov    %r12,%rdi
  call   <expand@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%r12
  mov    %r12,%rdi
  call   <expand@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D37
datatype: string
name: retrieve_data
arguments: data_label: D32
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D37: a-zA-

tool: D32: %s:%s


tool: D23: -zA-G

tool: D17: 0-3-9

tool: D0: 0-9a-z

assistant: ```c
int main() {
  char *a1 = "a-zA-";
  char *a2 = "-zA-G";
  char *a3 = "0-3-9";
  char *a4 = "0-9a-z";
  char s[100] = {0};
  expand(a1, s);
  printf("%s:%s\n", a1, s);
  expand(a2, s);
  printf("%s:%s\n", a2, s);
  expand(a3, s);
  printf("%s:%s\n", a3, s);
  expand(a4, s);
  printf("%s:%s\n", a4, s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  lea    D20(%rip),%r13
  push   %r12
  push   %rbp
  lea    D30(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  mov    %r12,%rsi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <expand@plt>
  mov    %rbp,%rsi
  lea    D39(%rip),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  mov    %r12,%rsi
  call   <expand@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D31(%rip),%r13
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <expand@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D26(%rip),%r13
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <expand@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string
name: extract_symbolic_data
arguments: data_label: D39
type_infered: string
name: extract_symbolic_data
arguments: data_label: D31
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string

tool: D20: -zA-G

tool: D30: a-zA-

tool: D39: %s:%s


tool: D31: 0-3-9

tool: D26: 0-9a-z

assistant: ```c
int main() {
  char *a1 = "a-zA-";
  char *a2 = "-zA-G";
  char *a3 = "0-3-9";
  char *a4 = "0-9a-z";
  char s[100] = {0};
  expand(a1, s);
  printf("%s:%s\n", a1, s);
  expand(a2, s);
  printf("%s:%s\n", a2, s);
  expand(a3, s);
  printf("%s:%s\n", a3, s);
  expand(a4, s);
  printf("%s:%s\n", a4, s);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  lea    D36(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  mov    %r12,%rsi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <expand@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  mov    %r12,%rsi
  call   <expand@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D46(%rip),%r13
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <expand@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D23(%rip),%r13
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <expand@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D46
type_infered: string
name: unpack_data
arguments: label: D23
type_infered: string

tool: D4: -zA-G

tool: D36: a-zA-

tool: D11: %s:%s


tool: D46: 0-3-9

tool: D23: 0-9a-z

assistant: ```c
int main() {
  char *a1 = "a-zA-";
  char *a2 = "-zA-G";
  char *a3 = "0-3-9";
  char *a4 = "0-9a-z";
  char s[100] = {0};
  expand(a1, s);
  printf("%s:%s\n", a1, s);
  expand(a2, s);
  printf("%s:%s\n", a2, s);
  expand(a3, s);
  printf("%s:%s\n", a3, s);
  expand(a4, s);
  printf("%s:%s\n", a4, s);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cu2ro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cu2ho@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x44(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ho2ro@plt>
  mov    %eax,-0x24(%rbp)
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int cu2ro(double *cu, double *ro, int p) {
  double ho[3];
  int trash;
  trash = cu2ho(cu, ho, p);
  trash = ho2ro(ho, ro, p);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<cu2ro>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <cu2ho@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ho2ro@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x1,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cu2ro(double *cu, double *ro, int p) {
  double ho[3];
  int trash;
  trash = cu2ho(cu, ho, p);
  trash = ho2ro(ho, ro, p);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cu2ro>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <cu2ho@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ho2ro@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cu2ro(double *cu, double *ro, int p) {
  double ho[3];
  int trash;
  trash = cu2ho(cu, ho, p);
  trash = ho2ro(ho, ro, p);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<cu2ro>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <cu2ho@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ho2ro@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cu2ro(double *cu, double *ro, int p) {
  double ho[3];
  int trash;
  trash = cu2ho(cu, ho, p);
  trash = ho2ro(ho, ro, p);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_text@plt>
  mov    $0x0,%eax
  call   <test_colors@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test() {
  test_text();
  test_colors();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_text@plt>
  mov    $0x0,%eax
  call   <test_colors@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test() {
  test_text();
  test_colors();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_text@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <test_colors@plt>
```

assistant: ```c
void test() {
  test_text();
  test_colors();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_text@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <test_colors@plt>
```

assistant: ```c
void test() {
  test_text();
  test_colors();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L15:
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0xff,-0x8(%rbp)
  jle    L15
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9: 
%d %c

assistant: ```c
void main(void) {
  int i = 0, n = 0;
  for (i = 0; i < 256; i++) {
    n++;
    printf("\n%d %c", i, i);
  }
}
```