ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D54(%rip),%r12
  mov    $0x13,%edx
  xor    %eax,%eax
  push   %rbp
  mov    %r12,%rdi
  mov    $0xffffffeb,%esi
  lea    D26(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0xffffffff,%ecx
  xor    %eax,%eax
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffff,%edx
  xor    %eax,%eax
  mov    $0x1fffffff,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffff,%edx
  xor    %eax,%eax
  mov    $0xffffffff,%esi
  call   <printf@plt>
  mov    $0xfffffff8,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0xfffffff8,%esi
  call   <printf@plt>
  mov    $0x7b,%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x62,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x12345678,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x8,%edx
  xor    %eax,%eax
  mov    $0x40,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D54
type: string
name: disassemble_data
arguments: data_tag: D26
type: string
name: disassemble_data
arguments: data_tag: D12
type: string
name: disassemble_data
arguments: data_tag: D49
type: string
name: disassemble_data
arguments: data_tag: D7
type: string
name: disassemble_data
arguments: data_tag: D13
type: string

tool: D54: %d,%d


tool: D26: %x,%x


tool: D12: %u,%x,%d


tool: D49: ---%x


tool: D7: ===%x


tool: D13: ~~~%x


assistant: ```c
int main() {
  printf("%d,%d\n", ~20, ~-20);
  unsigned int n = -1;
  printf("%u,%x,%d\n", n, n, n);
  int m = -1;
  printf("%x,%x\n", n >> 3, m >> 3);
  printf("%x,%x\n", n, m);
  printf("%x,%x\n", n << 3, m << 3);
  m = 0x3862517b;
  printf("---%x\n", (char)m);
  printf("===%x\n", (char)(m >> 16));
  int a = 0x12, b = 0x34, c = 0x56, d = 0x78;
  printf("~~~%x\n", (a << 24) | (b << 16) | (c << 8) | d);
  int f = 8;
  printf("%d,%d\n", f << 3, f);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timedif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x20(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  movslq %ebx,%rax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  sar    $0x6,%eax
  sar    $0x1f,%ebx
  mov    %ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%r12d
  imul   $0x3e8,%r12d,%r12d
  lea    (%r12,%rbx,1),%eax
  cltq
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
long int timedif(struct timeval a, struct timeval b) {
  register int us, s;
  us = a.tv_usec - b.tv_usec;
  us /= 1000;
  s = a.tv_sec - b.tv_sec;
  s *= 1000;
  return s + us;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<timedif>:
  endbr64
  mov    %edi,%edx
  sub    %esi,%edx
  sar    $0x20,%rdi
  sar    $0x20,%rsi
  sub    %esi,%edi
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x3e8,%edi,%edi
  add    %edi,%eax
  cltq
  ret
```

assistant: ```c
long int timedif(struct timeval a, struct timeval b) {
  register int us, s;
  us = a.tv_usec - b.tv_usec;
  us /= 1000;
  s = a.tv_sec - b.tv_sec;
  s *= 1000;
  return s + us;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<timedif>:
  endbr64
  mov    %edi,%edx
  sar    $0x20,%rdi
  sub    %esi,%edx
  sar    $0x20,%rsi
  movslq %edx,%rax
  sub    %esi,%edi
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  imul   $0x3e8,%edi,%edi
  sar    $0x26,%rax
  sub    %edx,%eax
  add    %edi,%eax
  cltq
  ret
```

assistant: ```c
long int timedif(struct timeval a, struct timeval b) {
  register int us, s;
  us = a.tv_usec - b.tv_usec;
  us /= 1000;
  s = a.tv_sec - b.tv_sec;
  s *= 1000;
  return s + us;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timedif>:
  endbr64
  mov    %edi,%edx
  sar    $0x20,%rdi
  sub    %esi,%edx
  sar    $0x20,%rsi
  movslq %edx,%rax
  sub    %esi,%edi
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  imul   $0x3e8,%edi,%edi
  sar    $0x26,%rax
  sub    %edx,%eax
  add    %edi,%eax
  cltq
  ret
```

assistant: ```c
long int timedif(struct timeval a, struct timeval b) {
  register int us, s;
  us = a.tv_usec - b.tv_usec;
  us /= 1000;
  s = a.tv_sec - b.tv_sec;
  s *= 1000;
  return s + us;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L61
L55:
  addl   $0x1,-0x18(%rbp)
L61:
  mov    $0x0,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L55
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L3
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L22
L3:
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L46
L22:
  movl   $0x0,-0x18(%rbp)
  jmp    L41
L97:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L41:
  mov    $0x0,%eax
  call   <unknown2@plt>
  test   %rax,%rax
  jne    L97
  nop
L85:
  mov    $0x0,%eax
  call   <unknown3@plt>
  test   %rax,%rax
  jne    L85
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L67:
  cmpl   $0x0,-0x14(%rbp)
  subl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L104
  jmp    L67
L46:
  nop
  jmp    L14
L104:
  nop
L14:
  leave
  ret
```

assistant: ```c
void main() {
  int i, pvlen;
  int t;
  int k = 0;
  int n;
  int j;
  i = 0;
  while (unknown1())
    i = i + 1;
  if (i >= pvlen + 1) {
    pvlen = i;
  } else {
    if (i > pvlen)
      return;
  }
  i = 0;
  while (unknown2()) {
    t = i;
    i = i + 1;
    k = k + 1;
  }
  while (unknown3())
    ;
  j = 0;
  n = i;
  while (1) {
    if (k <= -1) {
      goto ERROR;
    ERROR:;
    }
    k = k - 1;
    i = i - 1;
    j = j + 1;
    if (j <= n - 1) {
    } else {
      break;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
L49:
  mov    $0x0,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L49
  mov    $0x0,%ebx
  jmp    L45
L44:
  add    $0x1,%ebx
L45:
  mov    $0x0,%eax
  call   <unknown2@plt>
  test   %rax,%rax
  jne    L44
L15:
  mov    $0x0,%eax
  call   <unknown3@plt>
  test   %rax,%rax
  jne    L15
L24:
  add    $0x1,%eax
  cmp    %eax,%ebx
  jg     L24
  pop    %rbx
  ret
```

assistant: ```c
void main() {
  int i, pvlen;
  int t;
  int k = 0;
  int n;
  int j;
  i = 0;
  while (unknown1())
    i = i + 1;
  if (i >= pvlen + 1) {
    pvlen = i;
  } else {
    if (i > pvlen)
      return;
  }
  i = 0;
  while (unknown2()) {
    t = i;
    i = i + 1;
    k = k + 1;
  }
  while (unknown3())
    ;
  j = 0;
  n = i;
  while (1) {
    if (k <= -1) {
      goto ERROR;
    ERROR:;
    }
    k = k - 1;
    i = i - 1;
    j = j + 1;
    if (j <= n - 1) {
    } else {
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L23
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  call   <unknown2@plt>
  test   %rax,%rax
  jne    L25
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  call   <unknown3@plt>
  test   %rax,%rax
  jne    L16
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  int i, pvlen;
  int t;
  int k = 0;
  int n;
  int j;
  i = 0;
  while (unknown1())
    i = i + 1;
  if (i >= pvlen + 1) {
    pvlen = i;
  } else {
    if (i > pvlen)
      return;
  }
  i = 0;
  while (unknown2()) {
    t = i;
    i = i + 1;
    k = k + 1;
  }
  while (unknown3())
    ;
  j = 0;
  n = i;
  while (1) {
    if (k <= -1) {
      goto ERROR;
    ERROR:;
    }
    k = k - 1;
    i = i - 1;
    j = j + 1;
    if (j <= n - 1) {
    } else {
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L3
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <unknown2@plt>
  test   %rax,%rax
  jne    L1
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  call   <unknown3@plt>
  test   %rax,%rax
  jne    L13
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  int i, pvlen;
  int t;
  int k = 0;
  int n;
  int j;
  i = 0;
  while (unknown1())
    i = i + 1;
  if (i >= pvlen + 1) {
    pvlen = i;
  } else {
    if (i > pvlen)
      return;
  }
  i = 0;
  while (unknown2()) {
    t = i;
    i = i + 1;
    k = k + 1;
  }
  while (unknown3())
    ;
  j = 0;
  n = i;
  while (1) {
    if (k <= -1) {
      goto ERROR;
    ERROR:;
    }
    k = k - 1;
    i = i - 1;
    j = j + 1;
    if (j <= n - 1) {
    } else {
      break;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<simple_int_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int simple_int_cmp(const void *a, const void *b) {
  const int *aa = (const int *)a;
  const int *bb = (const int *)b;
  return *aa - *bb;
}
```
user: Translate the below assembly code into C programming language:

```asm
<simple_int_cmp>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int simple_int_cmp(const void *a, const void *b) {
  const int *aa = (const int *)a;
  const int *bb = (const int *)b;
  return *aa - *bb;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<simple_int_cmp>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int simple_int_cmp(const void *a, const void *b) {
  const int *aa = (const int *)a;
  const int *bb = (const int *)b;
  return *aa - *bb;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<simple_int_cmp>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int simple_int_cmp(const void *a, const void *b) {
  const int *aa = (const int *)a;
  const int *bb = (const int *)b;
  return *aa - *bb;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_time_to_seconds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: f64

tool: D3: 60

assistant: ```c
double convert_time_to_seconds(int minutes, double seconds) {
  double overall_seconds = 0.0;
  overall_seconds = 60.0 * minutes + seconds;
  return overall_seconds;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<convert_time_to_seconds>:
  endbr64
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D1(%rip),%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: f64

tool: D1: 60

assistant: ```c
double convert_time_to_seconds(int minutes, double seconds) {
  double overall_seconds = 0.0;
  overall_seconds = 60.0 * minutes + seconds;
  return overall_seconds;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_time_to_seconds>:
  endbr64
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D8(%rip),%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: f64

tool: D8: 60

assistant: ```c
double convert_time_to_seconds(int minutes, double seconds) {
  double overall_seconds = 0.0;
  overall_seconds = 60.0 * minutes + seconds;
  return overall_seconds;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convert_time_to_seconds>:
  endbr64
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: f64

tool: D2: 60

assistant: ```c
double convert_time_to_seconds(int minutes, double seconds) {
  double overall_seconds = 0.0;
  overall_seconds = 60.0 * minutes + seconds;
  return overall_seconds;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<productExceptSelf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%r14
  cmp    $0x1,%esi
  jle    L47
  mov    %rdi,%r12
  mov    %esi,%r13d
  movslq %esi,%r15
  lea    0x0(,%rsi,4),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movl   $0x1,(%rax)
  mov    %r13d,0xc(%rsp)
  lea    -0x1(%r13),%ecx
  mov    $0x0,%eax
L44:
  mov    0x0(%rbp,%rax,4),%edx
  imul   (%r12,%rax,4),%edx
  mov    %edx,0x4(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L44
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0x1,-0x4(%rax,%r15,4)
  lea    -0x2(%r13),%eax
  cltq
L25:
  mov    0x4(%rbx,%rax,4),%edx
  imul   0x4(%r12,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L25
  mov    0xc(%rsp),%ecx
  mov    $0x0,%eax
L23:
  mov    (%rbx,%rax,4),%edx
  imul   0x0(%rbp,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L23
  mov    %rbp,%rdi
  call   <free@plt>
L8:
  mov    %r13d,(%r14)
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  jmp    L8
```

assistant: ```c
int *productExceptSelf(int *nums, int numsSize, int *returnSize) {
  if (numsSize <= 1) {
    *returnSize = 0;
    return (NULL);
  }
  int *res, *tmp;
  int i;
  tmp = malloc(numsSize * sizeof(nums[0]));
  tmp[0] = 1;
  for (i = 1; i < numsSize; i++)
    tmp[i] = tmp[i - 1] * nums[i - 1];
  res = malloc(numsSize * sizeof(nums[0]));
  res[numsSize - 1] = 1;
  for (i = numsSize - 2; i >= 0; i--)
    res[i] = res[i + 1] * nums[i + 1];
  for (i = 0; i < numsSize; i++)
    res[i] *= tmp[i];
  free(tmp);
  *returnSize = numsSize;
  return (res);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<productExceptSelf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  cmp    $0x1,%esi
  jle    L9
  lea    0x0(,%rsi,4),%r12d
  mov    %esi,%r14d
  mov    %rdi,%rbp
  movslq %esi,%r15
  mov    %r12d,%edi
  call   <malloc@plt>
  lea    -0x2(%r14),%esi
  mov    $0x1,%edx
  movl   $0x1,(%rax)
  mov    %rax,%r13
  mov    %rsi,%rbx
  xor    %eax,%eax
  shl    $0x2,%rsi
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L24:
  add    $0x4,%rax
L35:
  imul   0x0(%rbp,%rax,1),%edx
  mov    %edx,0x4(%r13,%rax,1)
  cmp    %rax,%rsi
  jne    L24
  mov    %r12d,%edi
  call   <malloc@plt>
  movl   $0x1,-0x4(%rax,%r15,4)
  mov    %rax,%r12
  movslq %ebx,%rax
  nopw   0x0(%rax,%rax,1)
L38:
  mov    0x4(%r12,%rax,4),%edx
  imul   0x4(%rbp,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L38
  xor    %eax,%eax
  nopl   0x0(%rax)
L15:
  mov    (%r12,%rax,4),%edx
  imul   0x0(%r13,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %r15,%rax
  jne    L15
  mov    %r13,%rdi
  call   <free@plt>
L58:
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L9:
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  jmp    L58
```

assistant: ```c
int *productExceptSelf(int *nums, int numsSize, int *returnSize) {
  if (numsSize <= 1) {
    *returnSize = 0;
    return (NULL);
  }
  int *res, *tmp;
  int i;
  tmp = malloc(numsSize * sizeof(nums[0]));
  tmp[0] = 1;
  for (i = 1; i < numsSize; i++)
    tmp[i] = tmp[i - 1] * nums[i - 1];
  res = malloc(numsSize * sizeof(nums[0]));
  res[numsSize - 1] = 1;
  for (i = numsSize - 2; i >= 0; i--)
    res[i] = res[i + 1] * nums[i + 1];
  for (i = 0; i < numsSize; i++)
    res[i] *= tmp[i];
  free(tmp);
  *returnSize = numsSize;
  return (res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<productExceptSelf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  cmp    $0x1,%esi
  jle    L85
  lea    0x0(,%rsi,4),%r12d
  mov    %esi,%r15d
  mov    %rdi,%r14
  movslq %esi,%r13
  mov    %r12d,%edi
  call   <malloc@plt>
  lea    -0x1(%r15),%ecx
  mov    $0x1,%edx
  movl   $0x1,(%rax)
  mov    %rax,%rbp
  mov    %rcx,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L48:
  imul   (%r14,%rax,4),%edx
  mov    %edx,0x4(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L48
  mov    %r12d,%edi
  mov    %esi,0xc(%rsp)
  call   <malloc@plt>
  mov    0xc(%rsp),%esi
  mov    $0x1,%edx
  movl   $0x1,-0x4(%rax,%r13,4)
  mov    %rax,%r12
  lea    -0x2(%r15),%eax
  cltq
  nopl   0x0(%rax)
L81:
  imul   0x4(%r14,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L81
  lea    0x4(%rbp),%rdx
  mov    %r12,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L60
  cmp    $0x2,%esi
  jbe    L60
  mov    %r15d,%edx
  xor    %eax,%eax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  nopl   0x0(%rax)
L45:
  movdqu (%r12,%rax,1),%xmm0
  movdqu 0x0(%rbp,%rax,1),%xmm2
  movdqu (%r12,%rax,1),%xmm1
  movdqu 0x0(%rbp,%rax,1),%xmm3
  psrlq  $0x20,%xmm0
  psrlq  $0x20,%xmm2
  pmuludq %xmm3,%xmm1
  pmuludq %xmm2,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movups %xmm1,(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L45
  mov    %r15d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r15b
  je     L55
  mov    %eax,%edi
  lea    0x0(,%rdi,4),%rdx
  lea    (%r12,%rdx,1),%rsi
  mov    (%rsi),%ecx
  imul   0x0(%rbp,%rdi,4),%ecx
  mov    %ecx,(%rsi)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%r15d
  jle    L55
  lea    0x4(%r12,%rdx,1),%rsi
  add    $0x2,%eax
  mov    (%rsi),%ecx
  imul   0x4(%rbp,%rdx,1),%ecx
  mov    %ecx,(%rsi)
  cmp    %eax,%r15d
  jle    L55
  lea    0x8(%r12,%rdx,1),%rcx
  mov    (%rcx),%eax
  imul   0x8(%rbp,%rdx,1),%eax
  mov    %eax,(%rcx)
L55:
  mov    %rbp,%rdi
  call   <free@plt>
L61:
  mov    %r15d,(%rbx)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  xor    %r15d,%r15d
  xor    %r12d,%r12d
  jmp    L61
L60:
  mov    %r15d,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L39:
  mov    (%r12,%rax,4),%edx
  imul   0x0(%rbp,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L39
  jmp    L55
```

assistant: ```c
int *productExceptSelf(int *nums, int numsSize, int *returnSize) {
  if (numsSize <= 1) {
    *returnSize = 0;
    return (NULL);
  }
  int *res, *tmp;
  int i;
  tmp = malloc(numsSize * sizeof(nums[0]));
  tmp[0] = 1;
  for (i = 1; i < numsSize; i++)
    tmp[i] = tmp[i - 1] * nums[i - 1];
  res = malloc(numsSize * sizeof(nums[0]));
  res[numsSize - 1] = 1;
  for (i = numsSize - 2; i >= 0; i--)
    res[i] = res[i + 1] * nums[i + 1];
  for (i = 0; i < numsSize; i++)
    res[i] *= tmp[i];
  free(tmp);
  *returnSize = numsSize;
  return (res);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <flockfile@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <putchar_unlocked@plt>
  mov    %eax,-0x4(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <funlockfile@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int putchar(int c) {
  flockfile(stdout);
  int result = putchar_unlocked(c);
  funlockfile(stdout);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<putchar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    D5(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <flockfile@plt>
  mov    %ebx,%edi
  call   <putchar_unlocked@plt>
  mov    %eax,%ebx
  mov    0x0(%rbp),%edi
  call   <funlockfile@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int putchar(int c) {
  flockfile(stdout);
  int result = putchar_unlocked(c);
  funlockfile(stdout);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putchar>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rbx
  mov    (%rbx),%edi
  call   <flockfile@plt>
  mov    %r12d,%edi
  call   <putchar_unlocked@plt>
  mov    (%rbx),%edi
  mov    %eax,%r12d
  call   <funlockfile@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int putchar(int c) {
  flockfile(stdout);
  int result = putchar_unlocked(c);
  funlockfile(stdout);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putchar>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%rbx
  mov    (%rbx),%edi
  call   <flockfile@plt>
  mov    %r12d,%edi
  call   <putchar_unlocked@plt>
  mov    (%rbx),%edi
  mov    %eax,%r12d
  call   <funlockfile@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int putchar(int c) {
  flockfile(stdout);
  int result = putchar_unlocked(c);
  funlockfile(stdout);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zOrder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x14(%rbp)
  mov    %ax,-0x18(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <spread@plt>
  mov    %eax,-0x8(%rbp)
  movzwl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <spread@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  or     -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int zOrder(const unsigned short in_X, const unsigned short in_Y) {
  unsigned int x = spread(in_X);
  unsigned int y = spread(in_Y);
  return x | (y << 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zOrder>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  movzwl %di,%edi
  call   <spread@plt>
  mov    %eax,%ebp
  movzwl %bx,%edi
  call   <spread@plt>
  add    %eax,%eax
  or     %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zOrder(const unsigned short in_X, const unsigned short in_Y) {
  unsigned int x = spread(in_X);
  unsigned int y = spread(in_Y);
  return x | (y << 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zOrder>:
  endbr64
  push   %rbp
  movzwl %di,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <spread@plt>
  movzwl %bx,%edi
  mov    %eax,%ebp
  call   <spread@plt>
  add    $0x8,%rsp
  add    %eax,%eax
  pop    %rbx
  or     %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zOrder(const unsigned short in_X, const unsigned short in_Y) {
  unsigned int x = spread(in_X);
  unsigned int y = spread(in_Y);
  return x | (y << 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<zOrder>:
  endbr64
  push   %rbp
  movzwl %di,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <spread@plt>
  movzwl %bx,%edi
  mov    %eax,%ebp
  call   <spread@plt>
  add    $0x8,%rsp
  add    %eax,%eax
  pop    %rbx
  or     %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zOrder(const unsigned short in_X, const unsigned short in_Y) {
  unsigned int x = spread(in_X);
  unsigned int y = spread(in_Y);
  return x | (y << 1);
}
```