ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<findKey>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L28
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    $0x0,%ebx
L21:
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L48
  addl   $0x1,0x0(%rbp)
  add    $0x1,%ebx
  mov    %ebx,%eax
  mov    (%r12,%rax,8),%rdi
  test   %rdi,%rdi
  jne    L21
  mov    $0x0,%eax
  jmp    L40
L28:
  mov    $0x0,%eax
  jmp    L40
L48:
  mov    $0x1,%eax
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool findKey(char **keys, const char *seek, unsigned int *index) {
  for (unsigned int i = 0; keys[i] != NULL; i++) {
    if (strcmp(keys[i], seek) == 0) {
      return true;
    }
    (*index)++;
  }
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findKey>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%r13
  mov    %rdx,%rbp
  xor    %ebx,%ebx
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L31:
  lea    0x1(%rbx),%eax
  addl   $0x1,0x0(%rbp)
  mov    (%r12,%rax,8),%rdi
  mov    %rax,%rbx
  test   %rdi,%rdi
  je     L18
L3:
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L31
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool findKey(char **keys, const char *seek, unsigned int *index) {
  for (unsigned int i = 0; keys[i] != NULL; i++) {
    if (strcmp(keys[i], seek) == 0) {
      return true;
    }
    (*index)++;
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<findKey>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L7
  mov    %rsi,%r13
  mov    %rdx,%rbp
  xor    %ebx,%ebx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L21:
  lea    0x1(%rbx),%eax
  addl   $0x1,0x0(%rbp)
  mov    (%r12,%rax,8),%rdi
  mov    %rax,%rbx
  test   %rdi,%rdi
  je     L7
L20:
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool findKey(char **keys, const char *seek, unsigned int *index) {
  for (unsigned int i = 0; keys[i] != NULL; i++) {
    if (strcmp(keys[i], seek) == 0) {
      return true;
    }
    (*index)++;
  }
  return false;
}
```
user: What is the c source code of the assembly code below?

```asm
<kfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L11
L18:
  nop
L11:
  leave
  ret
```

assistant: ```c
void kfree(const void *objp) {
  if (!objp)
    return;
  free((void *)objp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kfree>:
  endbr64
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L6:
  ret
```

assistant: ```c
void kfree(const void *objp) {
  if (!objp)
    return;
  free((void *)objp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kfree>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
void kfree(const void *objp) {
  if (!objp)
    return;
  free((void *)objp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kfree>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void kfree(const void *objp) {
  if (!objp)
    return;
  free((void *)objp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x8(%rbp)
  jmp    L26
L2:
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <kernel_thread_fd@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L41
  cmpl   $0x3ff,-0x8(%rbp)
  jbe    L2
L41:
  cmpl   $0x3ff,-0x8(%rbp)
  jbe    L5
  mov    $0x1,%eax
  jmp    L18
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <test_readdir@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <test_lookup@plt>
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int pid;
  int fd;
  pid = 2;
  while ((fd = kernel_thread_fd(pid)) == -1 && pid < 1024) {
    pid++;
  }
  if (pid >= 1024)
    return 1;
  test_readdir(fd);
  test_lookup(fd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2,%ebp
L13:
  mov    %ebp,%edi
  call   <kernel_thread_fd@plt>
  mov    %eax,%ebx
  cmp    $0x3ff,%ebp
  ja     L34
  cmp    $0xffffffff,%eax
  jne    L34
  add    $0x1,%ebp
  jmp    L13
L34:
  mov    $0x1,%eax
  cmp    $0x3ff,%ebp
  jbe    L22
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    %ebx,%edi
  call   <test_readdir@plt>
  mov    %ebx,%edi
  call   <test_lookup@plt>
  mov    $0x0,%eax
  jmp    L5
```

assistant: ```c
int main(void) {
  unsigned int pid;
  int fd;
  pid = 2;
  while ((fd = kernel_thread_fd(pid)) == -1 && pid < 1024) {
    pid++;
  }
  if (pid >= 1024)
    return 1;
  test_readdir(fd);
  test_lookup(fd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L17
  nopl   0x0(%rax)
L47:
  cmp    $0x400,%ebx
  je     L32
  add    $0x1,%ebx
L17:
  mov    %ebx,%edi
  call   <kernel_thread_fd@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L47
  mov    $0x1,%eax
  cmp    $0x400,%ebx
  je     L36
  mov    %ebp,%edi
  call   <test_readdir@plt>
  mov    %ebp,%edi
  call   <test_lookup@plt>
  xor    %eax,%eax
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  mov    $0x1,%eax
  jmp    L36
```

assistant: ```c
int main(void) {
  unsigned int pid;
  int fd;
  pid = 2;
  while ((fd = kernel_thread_fd(pid)) == -1 && pid < 1024) {
    pid++;
  }
  if (pid >= 1024)
    return 1;
  test_readdir(fd);
  test_lookup(fd);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L1
  nopl   0x0(%rax)
L24:
  cmp    $0x400,%ebx
  je     L37
  add    $0x1,%ebx
L1:
  mov    %ebx,%edi
  call   <kernel_thread_fd@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L24
  mov    $0x1,%eax
  cmp    $0x400,%ebx
  je     L5
  mov    %ebp,%edi
  call   <test_readdir@plt>
  mov    %ebp,%edi
  call   <test_lookup@plt>
  xor    %eax,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  mov    $0x1,%eax
  jmp    L5
```

assistant: ```c
int main(void) {
  unsigned int pid;
  int fd;
  pid = 2;
  while ((fd = kernel_thread_fd(pid)) == -1 && pid < 1024) {
    pid++;
  }
  if (pid >= 1024)
    return 1;
  test_readdir(fd);
  test_lookup(fd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x7,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: Hello world!


assistant: ```c
int main() {
  printf("Hello world!\n");
  exit(7);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: Hello world!


assistant: ```c
int main() {
  printf("Hello world!\n");
  exit(7);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: Hello world!


assistant: ```c
int main() {
  printf("Hello world!\n");
  exit(7);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: Hello world!


assistant: ```c
int main() {
  printf("Hello world!\n");
  exit(7);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<time_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0xe10,-0x14(%rbp)
  jle    L17
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <plural@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xe10,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
L17:
  cmpl   $0x3c,-0x14(%rbp)
  jle    L3
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <plural@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3c,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,%rdi
  call   <plural@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D14
type_guessed: string
name: disassemble_data
arguments: data_label: D19
type_guessed: string

tool: D16: %li hour%s 

tool: D14: %li minute%s 

tool: D19: %li second%s

assistant: ```c
void time_print(time_t interval) {
  if (interval > 3600) {
    long hours = interval / 3600;
    printf("%li hour%s ", hours, plural(hours));
    interval = interval % 3600;
  }
  if (interval > 60) {
    long minutes = interval / 60;
    printf("%li minute%s ", minutes, plural(minutes));
    interval = interval % 60;
  }
  printf("%li second%s", (long)interval, plural((long)interval));
}
```
user: Translate the below assembly code into C programming language:

```asm
<time_print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xe10,%edi
  jg     L8
L26:
  cmp    $0x3c,%ebx
  jg     L13
L1:
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <plural@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  movslq %edi,%rbp
  imul   $0xffffffff91a2b3c5,%rbp,%rbp
  shr    $0x20,%rbp
  add    %edi,%ebp
  sar    $0xb,%ebp
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  movslq %ebp,%r12
  mov    %r12,%rdi
  call   <plural@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  imul   $0xe10,%ebp,%ebp
  sub    %ebp,%ebx
  jmp    L26
L13:
  movslq %ebx,%rbp
  imul   $0xffffffff88888889,%rbp,%rbp
  shr    $0x20,%rbp
  add    %ebx,%ebp
  sar    $0x5,%ebp
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  movslq %ebp,%r12
  mov    %r12,%rdi
  call   <plural@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  imul   $0x3c,%ebp,%ebp
  sub    %ebp,%ebx
  jmp    L1
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string
name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D23
datatype: string

tool: D0: %li second%s

tool: D16: %li hour%s 

tool: D23: %li minute%s 

assistant: ```c
void time_print(time_t interval) {
  if (interval > 3600) {
    long hours = interval / 3600;
    printf("%li hour%s ", hours, plural(hours));
    interval = interval % 3600;
  }
  if (interval > 60) {
    long minutes = interval / 60;
    printf("%li minute%s ", minutes, plural(minutes));
    interval = interval % 60;
  }
  printf("%li second%s", (long)interval, plural((long)interval));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<time_print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xe10,%edi
  jg     L2
  cmp    $0x3c,%ebx
  jg     L37
L34:
  movslq %ebx,%rbp
  mov    %rbp,%rdi
  call   <plural@plt>
  pop    %rbx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  movslq %edi,%rbp
  mov    %edi,%eax
  imul   $0xffffffff91a2b3c5,%rbp,%rbp
  sar    $0x1f,%eax
  shr    $0x20,%rbp
  add    %edi,%ebp
  sar    $0xb,%ebp
  sub    %eax,%ebp
  movslq %ebp,%r12
  imul   $0xe10,%ebp,%ebp
  mov    %r12,%rdi
  call   <plural@plt>
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  mov    %eax,%edx
  sub    %ebp,%ebx
  call   <printf@plt>
  cmp    $0x3c,%ebx
  jle    L34
L37:
  movslq %ebx,%rbp
  mov    %ebx,%eax
  imul   $0xffffffff88888889,%rbp,%rbp
  sar    $0x1f,%eax
  shr    $0x20,%rbp
  add    %ebx,%ebp
  sar    $0x5,%ebp
  sub    %eax,%ebp
  movslq %ebp,%r12
  imul   $0x3c,%ebp,%ebp
  mov    %r12,%rdi
  call   <plural@plt>
  mov    %r12,%rsi
  lea    D29(%rip),%rdi
  mov    %eax,%edx
  sub    %ebp,%ebx
  call   <printf@plt>
  jmp    L34
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D29
type: string

tool: D2: %li second%s

tool: D7: %li hour%s 

tool: D29: %li minute%s 

assistant: ```c
void time_print(time_t interval) {
  if (interval > 3600) {
    long hours = interval / 3600;
    printf("%li hour%s ", hours, plural(hours));
    interval = interval % 3600;
  }
  if (interval > 60) {
    long minutes = interval / 60;
    printf("%li minute%s ", minutes, plural(minutes));
    interval = interval % 60;
  }
  printf("%li second%s", (long)interval, plural((long)interval));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<time_print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xe10,%edi
  jg     L7
  cmp    $0x3c,%ebx
  jg     L11
L2:
  movslq %ebx,%rbp
  mov    %rbp,%rdi
  call   <plural@plt>
  pop    %rbx
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  movslq %edi,%rbp
  mov    %edi,%eax
  imul   $0xffffffff91a2b3c5,%rbp,%rbp
  sar    $0x1f,%eax
  shr    $0x20,%rbp
  add    %edi,%ebp
  sar    $0xb,%ebp
  sub    %eax,%ebp
  movslq %ebp,%r12
  imul   $0xe10,%ebp,%ebp
  mov    %r12,%rdi
  call   <plural@plt>
  mov    %r12,%rsi
  lea    D29(%rip),%rdi
  mov    %eax,%edx
  sub    %ebp,%ebx
  call   <printf@plt>
  cmp    $0x3c,%ebx
  jle    L2
L11:
  movslq %ebx,%rbp
  mov    %ebx,%eax
  imul   $0xffffffff88888889,%rbp,%rbp
  sar    $0x1f,%eax
  shr    $0x20,%rbp
  add    %ebx,%ebp
  sar    $0x5,%ebp
  sub    %eax,%ebp
  movslq %ebp,%r12
  imul   $0x3c,%ebp,%ebp
  mov    %r12,%rdi
  call   <plural@plt>
  mov    %r12,%rsi
  lea    D10(%rip),%rdi
  mov    %eax,%edx
  sub    %ebp,%ebx
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D29
type_guessed: string
name: unpack_data
arguments: label: D10
type_guessed: string

tool: D11: %li second%s

tool: D29: %li hour%s 

tool: D10: %li minute%s 

assistant: ```c
void time_print(time_t interval) {
  if (interval > 3600) {
    long hours = interval / 3600;
    printf("%li hour%s ", hours, plural(hours));
    interval = interval % 3600;
  }
  if (interval > 60) {
    long minutes = interval / 60;
    printf("%li minute%s ", minutes, plural(minutes));
    interval = interval % 60;
  }
  printf("%li second%s", (long)interval, plural((long)interval));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printBigTriangleUp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %esi,%r14d
  lea    -0x4(%rsi),%eax
  mov    %eax,0xc(%rsp)
  lea    -0x1(%rsi),%eax
  cltq
  mov    %rax,0x18(%rsp)
  shl    $0x3,%rax
  mov    %rax,0x10(%rsp)
  lea    (%rdi,%rax,1),%rbp
  mov    $0x0,%r13d
  jmp    L36
L23:
  mov    %eax,%eax
  lea    0x8(,%rax,8),%r12
  mov    $0x0,%ebx
L13:
  mov    0x0(%rbp),%rax
  movsd  (%rax,%rbx,1),%xmm0
  call   <prettyprint@plt>
  add    $0x8,%rbx
  cmp    %rbx,%r12
  jne    L13
L9:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  sub    $0x8,%rbp
  lea    -0x1(%r14),%eax
  sub    %r13d,%eax
  cmp    %eax,0xc(%rsp)
  jg     L49
L36:
  mov    %r13d,%eax
  add    $0x1,%r13d
  test   %r13d,%r13d
  jg     L23
  jmp    L9
L49:
  mov    0x10(%rsp),%r14
  lea    -0x20(%r15,%r14,1),%rbx
  mov    (%rbx),%rax
  movsd  (%rax),%xmm0
  call   <prettyprint@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    (%rbx),%rax
  movsd  0x20(%rax),%xmm0
  call   <prettyprint@plt>
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    (%r15),%rax
  movsd  (%rax),%xmm0
  call   <prettyprint@plt>
  mov    (%r15),%rax
  movsd  0x8(%rax),%xmm0
  call   <prettyprint@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    $0x0,%eax
  call   <printPoints@plt>
  mov    (%r15),%rax
  movsd  -0x8(%rax,%r14,1),%xmm0
  call   <prettyprint@plt>
  mov    (%r15),%rax
  mov    0x18(%rsp),%rcx
  movsd  (%rax,%rcx,8),%xmm0
  call   <prettyprint@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D11: 


assistant: ```c
void printBigTriangleUp(double **data, int baseSize) {
  int i, j;
  int roundSize = 4;
  for (i = baseSize - 1; i >= baseSize - roundSize; i--) {
    for (j = 0; j < baseSize - i; j++) {
      prettyprint(data[i][j]);
    }
    printf("\n");
  }
  prettyprint(data[baseSize - (roundSize + 1)][0]);
  for (i = 0; i < roundSize - 1; i++) {
    printPoints();
  }
  prettyprint(data[baseSize - (roundSize + 1)][roundSize]);
  printf("\n");
  for (i = 0; i <= roundSize + 1; i++) {
    printPoints();
  }
  printf("\n");
  prettyprint(data[0][0]);
  prettyprint(data[0][1]);
  for (i = 0; i < roundSize - 1; i++) {
    printPoints();
  }
  prettyprint(data[0][baseSize - 2]);
  prettyprint(data[0][baseSize - 1]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printBigTriangleUp>:
  endbr64
  push   %r15
  lea    -0x4(%rsi),%eax
  mov    %rdi,%r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %eax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  mov    %eax,0xc(%rsp)
  cltq
  mov    %rax,0x18(%rsp)
  shl    $0x3,%rax
  mov    %rax,0x10(%rsp)
  lea    (%rdi,%rax,1),%rbp
  nopl   0x0(%rax)
L24:
  mov    %r12d,%eax
  add    $0x1,%r12d
  test   %r12d,%r12d
  jle    L22
  lea    0x1(%rax),%ebx
  xor    %r13d,%r13d
  shl    $0x3,%rbx
  xchg   %ax,%ax
L28:
  mov    0x0(%rbp),%rax
  movsd  (%rax,%r13,1),%xmm0
  add    $0x8,%r13
  call   <prettyprint@plt>
  cmp    %r13,%rbx
  jne    L28
L22:
  mov    %r14,%rdi
  sub    $0x8,%rbp
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  sub    %r12d,%eax
  cmp    0x8(%rsp),%eax
  jge    L24
  mov    0x10(%rsp),%rbp
  lea    -0x20(%r15,%rbp,1),%rbx
  mov    (%rbx),%rax
  movsd  (%rax),%xmm0
  call   <prettyprint@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  mov    (%rbx),%rax
  movsd  0x20(%rax),%xmm0
  call   <prettyprint@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    (%r15),%rax
  movsd  (%rax),%xmm0
  call   <prettyprint@plt>
  mov    (%r15),%rax
  movsd  0x8(%rax),%xmm0
  call   <prettyprint@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  xor    %eax,%eax
  call   <printPoints@plt>
  mov    (%r15),%rax
  movsd  -0x8(%rax,%rbp,1),%xmm0
  call   <prettyprint@plt>
  mov    (%r15),%rax
  mov    0x18(%rsp),%rcx
  movsd  (%rax,%rcx,8),%xmm0
  call   <prettyprint@plt>
  add    $0x28,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: 


assistant: ```c
void printBigTriangleUp(double **data, int baseSize) {
  int i, j;
  int roundSize = 4;
  for (i = baseSize - 1; i >= baseSize - roundSize; i--) {
    for (j = 0; j < baseSize - i; j++) {
      prettyprint(data[i][j]);
    }
    printf("\n");
  }
  prettyprint(data[baseSize - (roundSize + 1)][0]);
  for (i = 0; i < roundSize - 1; i++) {
    printPoints();
  }
  prettyprint(data[baseSize - (roundSize + 1)][roundSize]);
  printf("\n");
  for (i = 0; i <= roundSize + 1; i++) {
    printPoints();
  }
  printf("\n");
  prettyprint(data[0][0]);
  prettyprint(data[0][1]);
  for (i = 0; i < roundSize - 1; i++) {
    printPoints();
  }
  prettyprint(data[0][baseSize - 2]);
  prettyprint(data[0][baseSize - 1]);
  printf("\n");
}
```