ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L40:
  mov    $0x0,%eax
  call   <q_random@plt>
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1e,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
  movb   $0x0,-0x3(%rbp)
  jmp    L13
L0:
  mov    $0x0,%eax
  call   <doTick@plt>
  mov    $0x0,%eax
  call   <doSleep@plt>
  movzbl -0x3(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x3(%rbp)
L13:
  movzbl -0x3(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jb     L0
  movb   $0x0,-0x2(%rbp)
  jmp    L6
L22:
  mov    $0x0,%eax
  call   <doSleep@plt>
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
L6:
  movzbl -0x2(%rbp),%eax
  movzbl -0x1(%rbp),%edx
  shl    $0x3,%edx
  cmp    %edx,%eax
  jl     L22
  jmp    L40
```

assistant: ```c
void loop() {
  while (1) {
    unsigned char tick_count = (q_random() % 30) + 1;
    for (unsigned char i = 0; i < tick_count; i++) {
      doTick();
      doSleep();
    }
    for (unsigned char i = 0; i < tick_count * 8; i++)
      doSleep();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<loop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  jmp    L3
L22:
  mov    $0x0,%eax
  call   <doSleep@plt>
  add    $0x1,%ebx
  movzbl %bl,%eax
  cmp    %ebp,%eax
  jl     L22
L3:
  mov    $0x0,%eax
  call   <q_random@plt>
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1e,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  add    $0x1,%bpl
  je     L3
  mov    %eax,%r12d
  mov    $0x0,%ebx
L43:
  mov    $0x0,%eax
  call   <doTick@plt>
  mov    $0x0,%eax
  call   <doSleep@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %al,%r12b
  jne    L43
  movzbl %bpl,%ebp
  shl    $0x3,%ebp
  mov    $0x0,%ebx
  jmp    L22
```

assistant: ```c
void loop() {
  while (1) {
    unsigned char tick_count = (q_random() % 30) + 1;
    for (unsigned char i = 0; i < tick_count; i++) {
      doTick();
      doSleep();
    }
    for (unsigned char i = 0; i < tick_count * 8; i++)
      doSleep();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<loop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <q_random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  sub    %ecx,%edx
  imul   $0x1e,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  add    $0x1,%bpl
  je     L17
  mov    %eax,%r12d
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  call   <doTick@plt>
  xor    %eax,%eax
  call   <doSleep@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %al,%r12b
  jne    L16
  movzbl %bpl,%ebp
  xor    %ebx,%ebx
  shl    $0x3,%ebp
L37:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <doSleep@plt>
  movzbl %bl,%eax
  cmp    %ebp,%eax
  jge    L17
  jmp    L37
```

assistant: ```c
void loop() {
  while (1) {
    unsigned char tick_count = (q_random() % 30) + 1;
    for (unsigned char i = 0; i < tick_count; i++) {
      doTick();
      doSleep();
    }
    for (unsigned char i = 0; i < tick_count * 8; i++)
      doSleep();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<loop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  call   <q_random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  sub    %ecx,%edx
  imul   $0x1e,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  add    $0x1,%bpl
  je     L21
  mov    %eax,%r12d
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <doTick@plt>
  xor    %eax,%eax
  call   <doSleep@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %al,%r12b
  jne    L4
  movzbl %bpl,%ebp
  xor    %ebx,%ebx
  shl    $0x3,%ebp
L29:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <doSleep@plt>
  movzbl %bl,%eax
  cmp    %ebp,%eax
  jge    L21
  jmp    L29
```

assistant: ```c
void loop() {
  while (1) {
    unsigned char tick_count = (q_random() % 30) + 1;
    for (unsigned char i = 0; i < tick_count; i++) {
      doTick();
      doSleep();
    }
    for (unsigned char i = 0; i < tick_count * 8; i++)
      doSleep();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<EEPROMBlockProtectSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x400af000,%eax
  mov    (%rax),%rax
  shr    $0x10,%rax
  and    $0x7ff,%eax
  cmp    %rax,-0x8(%rbp)
  setb   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    $0x400af004,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x400af030,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
L2:
  mov    $0x400af018,%eax
  mov    (%rax),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L2
  mov    $0x400af018,%eax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
unsigned long EEPROMBlockProtectSet(unsigned long ulBlock, unsigned long ulProtect) {
  DEBUG_ASSERT(ulBlock < ((((*((volatile unsigned long *)(0x400AF000)))) & 0x07FF0000) >> 16));
  (*((volatile unsigned long *)(0x400AF004))) = ulBlock;
  (*((volatile unsigned long *)(0x400AF030))) = ulProtect;
  while ((*((volatile unsigned long *)(0x400AF018))) & 0x00000001) {
  }
  return ((*((volatile unsigned long *)(0x400AF018))));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<EEPROMBlockProtectSet>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    0x400af000,%rax
  shr    $0x10,%rax
  and    $0x7ff,%eax
  cmp    %rdi,%rax
  seta   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbx,0x400af004
  mov    %rbp,0x400af030
L2:
  mov    0x400af018,%rax
  test   $0x1,%al
  jne    L2
  mov    0x400af018,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long EEPROMBlockProtectSet(unsigned long ulBlock, unsigned long ulProtect) {
  DEBUG_ASSERT(ulBlock < ((((*((volatile unsigned long *)(0x400AF000)))) & 0x07FF0000) >> 16));
  (*((volatile unsigned long *)(0x400AF004))) = ulBlock;
  (*((volatile unsigned long *)(0x400AF030))) = ulProtect;
  while ((*((volatile unsigned long *)(0x400AF018))) & 0x00000001) {
  }
  return ((*((volatile unsigned long *)(0x400AF018))));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EEPROMBlockProtectSet>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  mov    0x400af000,%rax
  shr    $0x10,%rax
  and    $0x7ff,%eax
  cmp    %rbx,%rax
  seta   %dil
  call   <DEBUG_ASSERT@plt>
  mov    %rbx,0x400af004
  mov    %rbp,0x400af030
  nop
L7:
  mov    0x400af018,%rax
  test   $0x1,%al
  jne    L7
  mov    0x400af018,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long EEPROMBlockProtectSet(unsigned long ulBlock, unsigned long ulProtect) {
  DEBUG_ASSERT(ulBlock < ((((*((volatile unsigned long *)(0x400AF000)))) & 0x07FF0000) >> 16));
  (*((volatile unsigned long *)(0x400AF004))) = ulBlock;
  (*((volatile unsigned long *)(0x400AF030))) = ulProtect;
  while ((*((volatile unsigned long *)(0x400AF018))) & 0x00000001) {
  }
  return ((*((volatile unsigned long *)(0x400AF018))));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EEPROMBlockProtectSet>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  mov    0x400af000,%rax
  shr    $0x10,%rax
  and    $0x7ff,%eax
  cmp    %rbx,%rax
  seta   %dil
  call   <DEBUG_ASSERT@plt>
  mov    %rbx,0x400af004
  mov    %rbp,0x400af030
  nop
L1:
  mov    0x400af018,%rax
  test   $0x1,%al
  jne    L1
  mov    0x400af018,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long EEPROMBlockProtectSet(unsigned long ulBlock, unsigned long ulProtect) {
  DEBUG_ASSERT(ulBlock < ((((*((volatile unsigned long *)(0x400AF000)))) & 0x07FF0000) >> 16));
  (*((volatile unsigned long *)(0x400AF004))) = ulBlock;
  (*((volatile unsigned long *)(0x400AF030))) = ulProtect;
  while ((*((volatile unsigned long *)(0x400AF018))) & 0x00000001) {
  }
  return ((*((volatile unsigned long *)(0x400AF018))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L43:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fib@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L2:
  cmpl   $0x1d,-0xc(%rbp)
  jle    L43
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L42:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fib@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L34:
  cmpl   $0x3e7,-0x10(%rbp)
  jg     L20
  cmpl   $0x0,-0xc(%rbp)
  jns    L42
L20:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string

tool: D12: n=%10d f=%10d


tool: D16: i=%4d n=%10d f=%10d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int n;
  for (n = 0; n < 30; n++) {
    int f = fib(n);
    printf("n=%10d f=%10d\n", n, f);
  }
  for (i = 0, n = 0; i < 1000 && n >= 0; i++, n = 2 * n + 1) {
    int f = fib(n);
    printf("i=%4d n=%10d f=%10d\n", i, n, f);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D16(%rip),%rbp
L15:
  mov    %ebx,%edi
  call   <fib@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x1e,%ebx
  jne    L15
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D17(%rip),%r12
L7:
  mov    %ebx,%edi
  call   <fib@plt>
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  lea    0x1(%rbx,%rbx,1),%ebx
  cmp    $0x3e7,%ebp
  jg     L11
  test   %ebx,%ebx
  jns    L7
L11:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string

tool: D16: n=%10d f=%10d


tool: D17: i=%4d n=%10d f=%10d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int n;
  for (n = 0; n < 30; n++) {
    int f = fib(n);
    printf("n=%10d f=%10d\n", n, f);
  }
  for (i = 0, n = 0; i < 1000 && n >= 0; i++, n = 2 * n + 1) {
    int f = fib(n);
    printf("i=%4d n=%10d f=%10d\n", i, n, f);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L14:
  mov    %ebx,%edi
  call   <fib@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1e,%ebx
  jne    L14
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  lea    D11(%rip),%r12
L17:
  mov    %ebp,%edi
  call   <fib@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  add    $0x1,%ebx
  lea    0x1(%rbp,%rbp,1),%ebp
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x3e8,%ebx
  jne    L17
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D8: n=%10d f=%10d


tool: D11: i=%4d n=%10d f=%10d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int n;
  for (n = 0; n < 30; n++) {
    int f = fib(n);
    printf("n=%10d f=%10d\n", n, f);
  }
  for (i = 0, n = 0; i < 1000 && n >= 0; i++, n = 2 * n + 1) {
    int f = fib(n);
    printf("i=%4d n=%10d f=%10d\n", i, n, f);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L4:
  mov    %ebx,%edi
  call   <fib@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1e,%ebx
  jne    L4
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  lea    D6(%rip),%r12
L11:
  mov    %ebp,%edi
  call   <fib@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  add    $0x1,%ebx
  lea    0x1(%rbp,%rbp,1),%ebp
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x3e8,%ebx
  jne    L11
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string

tool: D14: n=%10d f=%10d


tool: D6: i=%4d n=%10d f=%10d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int n;
  for (n = 0; n < 30; n++) {
    int f = fib(n);
    printf("n=%10d f=%10d\n", n, f);
  }
  for (i = 0, n = 0; i < 1000 && n >= 0; i++, n = 2 * n + 1) {
    int f = fib(n);
    printf("i=%4d n=%10d f=%10d\n", i, n, f);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L53
  mov    $0x1,%eax
  jmp    L9
L53:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <power>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L4
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  jmp    L9
L4:
  mov    -0x18(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L9
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  imul   -0x14(%rbp),%eax
  jmp    L9
L9:
  leave
  ret
```

assistant: ```c
int power(int a, int b) {
  int i, p = 1;
  if (b == 0) {
    return 1;
  }
  int p2 = power(a, b / 2);
  if (b % 2 == 0) {
    return p2 * p2;
  }
  if (b % 2 == 1) {
    return p2 * p2 * a;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<power>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L47
  ret
L47:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  shr    $0x1f,%esi
  add    %ebx,%esi
  sar    %esi
  call   <power>
  test   $0x1,%bl
  je     L18
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %edx,%ebx
  and    $0x1,%ebx
  sub    %edx,%ebx
  cmp    $0x1,%ebx
  je     L46
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  imul   %eax,%eax
  jmp    L44
L46:
  imul   %eax,%eax
  imul   %ebp,%eax
  jmp    L44
```

assistant: ```c
int power(int a, int b) {
  int i, p = 1;
  if (b == 0) {
    return 1;
  }
  int p2 = power(a, b / 2);
  if (b % 2 == 0) {
    return p2 * p2;
  }
  if (b % 2 == 1) {
    return p2 * p2 * a;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<power>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L41
  ret
  xchg   %ax,%ax
L41:
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  mov    %esi,%ebx
  add    %esi,%ebp
  sub    $0x18,%rsp
  sar    %ebp
  je     L131
  mov    %ebp,%r13d
  mov    $0x1,%r15d
  shr    $0x1f,%r13d
  add    %ebp,%r13d
  sar    %r13d
  jne    L114
L9:
  test   $0x1,%bpl
  je     L123
  mov    %ebp,%eax
  shr    $0x1f,%eax
  add    %eax,%ebp
  and    $0x1,%ebp
  sub    %eax,%ebp
  cmp    $0x1,%ebp
  je     L133
L131:
  test   $0x1,%bl
  je     L48
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %eax,%ebx
  and    $0x1,%ebx
  sub    %eax,%ebx
  cmp    $0x1,%ebx
  je     L69
L90:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L114:
  mov    %r13d,%edx
  mov    $0x1,%r12d
  shr    $0x1f,%edx
  add    %r13d,%edx
  mov    %edx,%ecx
  mov    %edx,0x4(%rsp)
  sar    %ecx
  je     L56
  mov    %ecx,%esi
  mov    %ecx,0xc(%rsp)
  shr    $0x1f,%esi
  mov    %edi,0x8(%rsp)
  add    %ecx,%esi
  sar    %esi
  call   <power>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edi
  mov    0x4(%rsp),%edx
  test   $0x1,%cl
  je     L158
  shr    $0x1f,%edx
  add    %edx,%ecx
  and    $0x1,%ecx
  sub    %edx,%ecx
  cmp    $0x1,%ecx
  jne    L56
  imul   %eax,%eax
  imul   %edi,%eax
  mov    %eax,%r12d
  nopl   0x0(%rax)
L56:
  test   $0x1,%r13b
  je     L152
  mov    %r13d,%eax
  shr    $0x1f,%eax
  add    %eax,%r13d
  and    $0x1,%r13d
  sub    %eax,%r13d
  cmp    $0x1,%r13d
  jne    L9
  mov    %r12d,%r8d
  imul   %r12d,%r8d
  imul   %edi,%r8d
  mov    %r8d,%r15d
  jmp    L9
  nop
L123:
  imul   %r15d,%r15d
  mov    %r15d,%r14d
  jmp    L131
  nopl   0x0(%rax)
L48:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  imul   %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %r14d,%eax
  imul   %r14d,%eax
  imul   %edi,%eax
  jmp    L90
  nop
L133:
  imul   %r15d,%r15d
  imul   %edi,%r15d
  mov    %r15d,%r14d
  jmp    L131
L158:
  imul   %eax,%eax
  mov    %eax,%r12d
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L152:
  mov    %r12d,%r15d
  imul   %r12d,%r15d
  jmp    L9
```

assistant: ```c
int power(int a, int b) {
  int i, p = 1;
  if (b == 0) {
    return 1;
  }
  int p2 = power(a, b / 2);
  if (b % 2 == 0) {
    return p2 * p2;
  }
  if (b % 2 == 1) {
    return p2 * p2 * a;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<power>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L150
  ret
  xchg   %ax,%ax
L150:
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  mov    %esi,%ebx
  add    %esi,%ebp
  sub    $0x18,%rsp
  sar    %ebp
  je     L121
  mov    %ebp,%r13d
  mov    $0x1,%r15d
  shr    $0x1f,%r13d
  add    %ebp,%r13d
  sar    %r13d
  jne    L0
L141:
  test   $0x1,%bpl
  je     L94
  mov    %ebp,%eax
  shr    $0x1f,%eax
  add    %eax,%ebp
  and    $0x1,%ebp
  sub    %eax,%ebp
  cmp    $0x1,%ebp
  je     L124
L121:
  test   $0x1,%bl
  je     L144
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %eax,%ebx
  and    $0x1,%ebx
  sub    %eax,%ebx
  cmp    $0x1,%ebx
  je     L173
L87:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r13d,%edx
  mov    $0x1,%r12d
  shr    $0x1f,%edx
  add    %r13d,%edx
  mov    %edx,%ecx
  mov    %edx,0x4(%rsp)
  sar    %ecx
  je     L135
  mov    %ecx,%esi
  mov    %ecx,0xc(%rsp)
  shr    $0x1f,%esi
  mov    %edi,0x8(%rsp)
  add    %ecx,%esi
  sar    %esi
  call   <power>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edi
  mov    0x4(%rsp),%edx
  test   $0x1,%cl
  je     L83
  shr    $0x1f,%edx
  add    %edx,%ecx
  and    $0x1,%ecx
  sub    %edx,%ecx
  cmp    $0x1,%ecx
  jne    L135
  imul   %eax,%eax
  imul   %edi,%eax
  mov    %eax,%r12d
  nopl   0x0(%rax)
L135:
  test   $0x1,%r13b
  je     L129
  mov    %r13d,%eax
  shr    $0x1f,%eax
  add    %eax,%r13d
  and    $0x1,%r13d
  sub    %eax,%r13d
  cmp    $0x1,%r13d
  jne    L141
  mov    %r12d,%r8d
  imul   %r12d,%r8d
  imul   %edi,%r8d
  mov    %r8d,%r15d
  jmp    L141
  nop
L94:
  imul   %r15d,%r15d
  mov    %r15d,%r14d
  jmp    L121
  nopl   0x0(%rax)
L144:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  imul   %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L173:
  mov    %r14d,%eax
  imul   %r14d,%eax
  imul   %edi,%eax
  jmp    L87
  nop
L124:
  imul   %r15d,%r15d
  imul   %edi,%r15d
  mov    %r15d,%r14d
  jmp    L121
L83:
  imul   %eax,%eax
  mov    %eax,%r12d
  jmp    L135
  nopl   0x0(%rax,%rax,1)
L129:
  mov    %r12d,%r15d
  imul   %r12d,%r15d
  jmp    L141
```

assistant: ```c
int power(int a, int b) {
  int i, p = 1;
  if (b == 0) {
    return 1;
  }
  int p2 = power(a, b / 2);
  if (b % 2 == 0) {
    return p2 * p2;
  }
  if (b % 2 == 1) {
    return p2 * p2 * a;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L13:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  sar    $0x5,%eax
  add    %ecx,%eax
  add    $0xa25,%eax
  xor    -0x10(%rbp),%eax
  and    $0xffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  cmpl   $0x7,-0xc(%rbp)
  jle    L13
  mov    -0x10(%rbp),%eax
  shl    $0x10,%eax
  or     -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t int2int(uint32_t input) {
  uint16_t l = input & 0xffff;
  uint16_t r = input >> 16;
  for (int i = 0; i < 8; i++) {
    uint16_t nl = r;
    uint16_t F = (((r * 31) + (r >> 5) + 7 * 371) ^ r) & 0xffff;
    r = l ^ F;
    l = nl;
  }
  return (r << 16) | l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int2int>:
  endbr64
  mov    %edi,%eax
  movzwl %di,%edi
  sar    $0x10,%eax
  mov    $0x8,%ecx
L6:
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  mov    %eax,%esi
  sar    $0x5,%esi
  lea    0xa25(%rdx,%rsi,1),%edx
  xor    %eax,%edx
  movzwl %dx,%edx
  mov    %eax,%esi
  mov    %edx,%eax
  xor    %edi,%eax
  mov    %esi,%edi
  sub    $0x1,%ecx
  jne    L6
  shl    $0x10,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
uint32_t int2int(uint32_t input) {
  uint16_t l = input & 0xffff;
  uint16_t r = input >> 16;
  for (int i = 0; i < 8; i++) {
    uint16_t nl = r;
    uint16_t F = (((r * 31) + (r >> 5) + 7 * 371) ^ r) & 0xffff;
    r = l ^ F;
    l = nl;
  }
  return (r << 16) | l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int2int>:
  endbr64
  mov    %edi,%eax
  movzwl %di,%esi
  mov    $0x8,%ecx
  sar    $0x10,%eax
  nopl   0x0(%rax)
L4:
  mov    %eax,%edx
  mov    %eax,%edi
  shl    $0x5,%edx
  sar    $0x5,%edi
  sub    %eax,%edx
  lea    0xa25(%rdx,%rdi,1),%edx
  mov    %eax,%edi
  xor    %eax,%edx
  movzwl %dx,%edx
  mov    %edx,%eax
  xor    %esi,%eax
  mov    %edi,%esi
  sub    $0x1,%ecx
  jne    L4
  shl    $0x10,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
uint32_t int2int(uint32_t input) {
  uint16_t l = input & 0xffff;
  uint16_t r = input >> 16;
  for (int i = 0; i < 8; i++) {
    uint16_t nl = r;
    uint16_t F = (((r * 31) + (r >> 5) + 7 * 371) ^ r) & 0xffff;
    r = l ^ F;
    l = nl;
  }
  return (r << 16) | l;
}
```