ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_sign>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x2b,%dl
  je     L21
  movsd  D22(%rip),%xmm0
  cmp    $0x2d,%dl
  jne    L23
  movsd  D8(%rip),%xmm0
L4:
  add    $0x1,%rax
  mov    %rax,(%rdi)
L23:
  ret
L21:
  movsd  D22(%rip),%xmm0
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_tag: D22
data_type: f64
name: unpack_data
arguments: data_tag: D8
data_type: byte[8]

tool: D22: 1

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double read_sign(const char **sptr) {
  double sign = 1.0;
  switch (**sptr) {
  case '-':
    sign = -1.0;
  case '+':
    ++(*sptr);
  default:
    return sign;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_sign>:
  endbr64
  mov    (%rdi),%rax
  movsd  D7(%rip),%xmm0
  movzbl (%rax),%edx
  cmp    $0x2b,%dl
  je     L19
  cmp    $0x2d,%dl
  jne    L11
  movsd  D6(%rip),%xmm0
L19:
  add    $0x1,%rax
  mov    %rax,(%rdi)
L11:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: f64
name: parse_data
arguments: data_tag: D6
type: byte[8]

tool: D7: 1

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double read_sign(const char **sptr) {
  double sign = 1.0;
  switch (**sptr) {
  case '-':
    sign = -1.0;
  case '+':
    ++(*sptr);
  default:
    return sign;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_sign>:
  endbr64
  mov    (%rdi),%rax
  movsd  D14(%rip),%xmm0
  movzbl (%rax),%edx
  cmp    $0x2b,%dl
  je     L14
  cmp    $0x2d,%dl
  jne    L4
  movsd  D2(%rip),%xmm0
L14:
  add    $0x1,%rax
  mov    %rax,(%rdi)
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: f64
name: disassemble_data
arguments: label: D2
data_type: byte[8]

tool: D14: 1

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double read_sign(const char **sptr) {
  double sign = 1.0;
  switch (**sptr) {
  case '-':
    sign = -1.0;
  case '+':
    ++(*sptr);
  default:
    return sign;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fgets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L62
L75:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0xa,-0xc(%rbp)
  je     L65
  cmpl   $0xd,-0xc(%rbp)
  je     L65
L62:
  subl   $0x1,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jle    L65
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <getc@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L75
L65:
  cmpl   $0x0,-0xc(%rbp)
  jns    L73
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L73
  mov    $0x0,%eax
  jmp    L12
L73:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
char *fgets(int dev, char *s, int n) {
  int c = 0;
  char *cs;
  cs = s;
  while ((--n > 0) && ((c = getc(dev)) >= 0)) {
    *cs++ = c;
    if (('\n' == c) || ('\r' == c)) {
      break;
    }
  }
  if ((c < 0) && (cs == s)) {
    return 0;
  }
  *cs++ = '\0';
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fgets>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rsi,%rbx
  mov    $0x0,%eax
  lea    -0x1(%rdx,%rsi,1),%r12d
L4:
  mov    %r12d,%edx
  sub    %ebx,%edx
  test   %edx,%edx
  jle    L16
  mov    %ebp,%edi
  call   <getc@plt>
  test   %eax,%eax
  js     L16
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%eax
  je     L23
  cmp    $0xd,%eax
  jne    L4
  jmp    L23
L16:
  test   %eax,%eax
  jns    L23
  mov    $0x0,%eax
  cmp    %r13,%rbx
  je     L33
L23:
  movb   $0x0,(%rbx)
  mov    %r13,%rax
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *fgets(int dev, char *s, int n) {
  int c = 0;
  char *cs;
  cs = s;
  while ((--n > 0) && ((c = getc(dev)) >= 0)) {
    *cs++ = c;
    if (('\n' == c) || ('\r' == c)) {
      break;
    }
  }
  if ((c < 0) && (cs == s)) {
    return 0;
  }
  *cs++ = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<fgets>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    -0x1(%rdx,%rsi,1),%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L4
  nopl   (%rax)
L26:
  mov    %ebp,%edi
  call   <getc@plt>
  test   %eax,%eax
  js     L57
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%eax
  je     L39
  cmp    $0xd,%eax
  je     L39
L4:
  mov    %r12d,%eax
  sub    %ebx,%eax
  test   %eax,%eax
  jg     L26
L39:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  xor    %eax,%eax
  cmp    %r13,%rbx
  jne    L39
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *fgets(int dev, char *s, int n) {
  int c = 0;
  char *cs;
  cs = s;
  while ((--n > 0) && ((c = getc(dev)) >= 0)) {
    *cs++ = c;
    if (('\n' == c) || ('\r' == c)) {
      break;
    }
  }
  if ((c < 0) && (cs == s)) {
    return 0;
  }
  *cs++ = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<fgets>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    -0x1(%rdx,%rsi,1),%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L42
  nopl   (%rax)
L40:
  mov    %ebp,%edi
  call   <getc@plt>
  test   %eax,%eax
  js     L2
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%eax
  je     L5
  cmp    $0xd,%eax
  je     L5
L42:
  mov    %r12d,%eax
  sub    %ebx,%eax
  test   %eax,%eax
  jg     L40
L5:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  cmp    %r13,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *fgets(int dev, char *s, int n) {
  int c = 0;
  char *cs;
  cs = s;
  while ((--n > 0) && ((c = getc(dev)) >= 0)) {
    *cs++ = c;
    if (('\n' == c) || ('\r' == c)) {
      break;
    }
  }
  if ((c < 0) && (cs == s)) {
    return 0;
  }
  *cs++ = '\0';
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x4a,-0x10(%rbp)
  movb   $0x6f,-0xf(%rbp)
  movb   $0x65,-0xe(%rbp)
  movb   $0x0,-0xd(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movb   $0x6e,-0xc(%rbp)
  movb   $0x79,-0xb(%rbp)
  movb   $0x0,-0xa(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movb   $0x68,-0xe(%rbp)
  movb   $0x6e,-0xd(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type: string

tool: D13: name is %s.


assistant: ```c
int main() {
  char name[8];
  name[0] = 'J';
  name[1] = 'o';
  name[2] = 'e';
  name[3] = '\0';
  printf("name is %s.\n", name);
  name[4] = 'n';
  name[5] = 'y';
  name[6] = '\0';
  printf("name is %s.\n", name);
  name[2] = 'h';
  name[3] = 'n';
  printf("name is %s.\n", name);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x4a,(%rsp)
  movb   $0x6f,0x1(%rsp)
  movb   $0x65,0x2(%rsp)
  movb   $0x0,0x3(%rsp)
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movb   $0x6e,0x4(%rsp)
  movb   $0x79,0x5(%rsp)
  movb   $0x0,0x6(%rsp)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  movb   $0x68,0x2(%rsp)
  movb   $0x6e,0x3(%rsp)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string

tool: D7: name is %s.


assistant: ```c
int main() {
  char name[8];
  name[0] = 'J';
  name[1] = 'o';
  name[2] = 'e';
  name[3] = '\0';
  printf("name is %s.\n", name);
  name[4] = 'n';
  name[5] = 'y';
  name[6] = '\0';
  printf("name is %s.\n", name);
  name[2] = 'h';
  name[3] = 'n';
  printf("name is %s.\n", name);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movl   $0x656f4a,(%rsp)
  mov    %r12,%rsi
  call   <printf@plt>
  mov    $0x796e,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %ax,0x4(%rsp)
  movb   $0x0,0x6(%rsp)
  call   <printf@plt>
  mov    $0x6e68,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %dx,0x2(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: name is %s.


assistant: ```c
int main() {
  char name[8];
  name[0] = 'J';
  name[1] = 'o';
  name[2] = 'e';
  name[3] = '\0';
  printf("name is %s.\n", name);
  name[4] = 'n';
  name[5] = 'y';
  name[6] = '\0';
  printf("name is %s.\n", name);
  name[2] = 'h';
  name[3] = 'n';
  printf("name is %s.\n", name);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movl   $0x656f4a,(%rsp)
  mov    %r12,%rsi
  call   <printf@plt>
  mov    $0x796e,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %ax,0x4(%rsp)
  movb   $0x0,0x6(%rsp)
  call   <printf@plt>
  mov    $0x6e68,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %dx,0x2(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: name is %s.


assistant: ```c
int main() {
  char name[8];
  name[0] = 'J';
  name[1] = 'o';
  name[2] = 'e';
  name[3] = '\0';
  printf("name is %s.\n", name);
  name[4] = 'n';
  name[5] = 'y';
  name[6] = '\0';
  printf("name is %s.\n", name);
  name[2] = 'h';
  name[3] = 'n';
  printf("name is %s.\n", name);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sio_create_cassette>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L4
L13:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sio_write_cas_header@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: wb

assistant: ```c
int sio_create_cassette(const char *filename, const char *description) {
  FILE *fp;
  fp = fopen(filename, "wb");
  if (!fp)
    return -1;
  sio_write_cas_header(fp, description);
  fclose(fp);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sio_create_cassette>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <sio_write_cas_header@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    $0xffffffff,%eax
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: wb

assistant: ```c
int sio_create_cassette(const char *filename, const char *description) {
  FILE *fp;
  fp = fopen(filename, "wb");
  if (!fp)
    return -1;
  sio_write_cas_header(fp, description);
  fclose(fp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sio_create_cassette>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D0(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <sio_write_cas_header@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L6:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    $0xffffffff,%eax
  jmp    L6
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: wb

assistant: ```c
int sio_create_cassette(const char *filename, const char *description) {
  FILE *fp;
  fp = fopen(filename, "wb");
  if (!fp)
    return -1;
  sio_write_cas_header(fp, description);
  fclose(fp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sio_create_cassette>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D6(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <sio_write_cas_header@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L4:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0xffffffff,%eax
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: wb

assistant: ```c
int sio_create_cassette(const char *filename, const char *description) {
  FILE *fp;
  fp = fopen(filename, "wb");
  if (!fp)
    return -1;
  sio_write_cas_header(fp, description);
  fclose(fp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmp_eax_imm32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x3d,%edi
  call   <put8@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void cmp_eax_imm32(unsigned long imm32) {
  put8(0x3D);
  put32(imm32);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmp_eax_imm32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x3d,%edi
  call   <put8@plt>
  mov    %rbx,%rdi
  call   <put32@plt>
  pop    %rbx
  ret
```

assistant: ```c
void cmp_eax_imm32(unsigned long imm32) {
  put8(0x3D);
  put32(imm32);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmp_eax_imm32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x3d,%edi
  call   <put8@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void cmp_eax_imm32(unsigned long imm32) {
  put8(0x3D);
  put32(imm32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmp_eax_imm32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x3d,%edi
  call   <put8@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void cmp_eax_imm32(unsigned long imm32) {
  put8(0x3D);
  put32(imm32);
}
```
user: What is the c source code of the assembly code below:

```asm
<crc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x840,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %rsi,-0x830(%rbp)
  mov    %rdx,-0x838(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x820(%rbp)
  jmp    L52
L2:
  mov    -0x820(%rbp),%eax
  cltq
  mov    %rax,-0x818(%rbp)
  movl   $0x0,-0x81c(%rbp)
  jmp    L50
L55:
  mov    -0x818(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L25
  mov    -0x818(%rbp),%rax
  shr    %rax
  mov    %rax,%rdx
  mov    $0xedb88320,%eax
  xor    %rdx,%rax
  jmp    L85
L25:
  mov    -0x818(%rbp),%rax
  shr    %rax
L85:
  mov    %rax,-0x818(%rbp)
  addl   $0x1,-0x81c(%rbp)
L50:
  cmpl   $0x7,-0x81c(%rbp)
  jle    L55
  mov    -0x820(%rbp),%eax
  cltq
  mov    -0x818(%rbp),%rdx
  mov    %rdx,-0x810(%rbp,%rax,8)
  addl   $0x1,-0x820(%rbp)
L52:
  cmpl   $0xff,-0x820(%rbp)
  jle    L2
  mov    $0xffffffff,%eax
  xor    %rax,-0x828(%rbp)
  jmp    L17
L71:
  mov    -0x828(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x830(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x830(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %ecx,%eax
  movzbl %al,%eax
  cltq
  mov    -0x810(%rbp,%rax,8),%rdx
  mov    -0x828(%rbp),%rax
  shr    $0x8,%rax
  xor    %rdx,%rax
  mov    %rax,-0x828(%rbp)
L17:
  mov    -0x838(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x838(%rbp)
  test   %rax,%rax
  jne    L71
  mov    $0xffffffff,%eax
  xor    -0x828(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
unsigned long crc32(unsigned long crc, const unsigned char *buf, unsigned long len) {
  unsigned long crc_table[256];
  int i, k;
  for (i = 0; i < 256; i++) {
    unsigned long c = (unsigned long)i;
    for (k = 0; k < 8; k++)
      c = c & 1 ? 0xedb88320 ^ (c >> 1) : c >> 1;
    crc_table[i] = c;
  }
  crc = crc ^ 0xffffffffL;
  while (len--)
    crc = crc_table[((int)crc ^ (*buf++)) & 0xff] ^ (crc >> 8);
  return crc ^ 0xffffffffL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crc32>:
  endbr64
  sub    $0x818,%rsp
  mov    %rsi,%r8
  mov    %rdx,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ecx
  mov    $0xedb88320,%esi
  jmp    L27
L80:
  shr    %rax
L38:
  sub    $0x1,%edx
  je     L89
L1:
  test   $0x1,%al
  je     L80
  shr    %rax
  xor    %rsi,%rax
  jmp    L38
L89:
  mov    %rax,(%rsp,%rcx,8)
  add    $0x1,%rcx
  cmp    $0x100,%rcx
  je     L56
L27:
  mov    %rcx,%rax
  mov    $0x8,%edx
  jmp    L1
L56:
  mov    $0xffffffff,%eax
  xor    %rdi,%rax
  test   %r9,%r9
  je     L45
  lea    (%r8,%r9,1),%rcx
L62:
  add    $0x1,%r8
  mov    %eax,%edx
  xor    -0x1(%r8),%dl
  movzbl %dl,%edx
  shr    $0x8,%rax
  xor    (%rsp,%rdx,8),%rax
  cmp    %r8,%rcx
  jne    L62
L45:
  mov    $0xffffffff,%edx
  xor    %rdx,%rax
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L78
  add    $0x818,%rsp
  ret
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long crc32(unsigned long crc, const unsigned char *buf, unsigned long len) {
  unsigned long crc_table[256];
  int i, k;
  for (i = 0; i < 256; i++) {
    unsigned long c = (unsigned long)i;
    for (k = 0; k < 8; k++)
      c = c & 1 ? 0xedb88320 ^ (c >> 1) : c >> 1;
    crc_table[i] = c;
  }
  crc = crc ^ 0xffffffffL;
  while (len--)
    crc = crc_table[((int)crc ^ (*buf++)) & 0xff] ^ (crc >> 8);
  return crc ^ 0xffffffffL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<crc32>:
  endbr64
  push   %rbx
  mov    %rsi,%r10
  mov    %rdi,%rbx
  mov    %rdx,%r11
  xor    %r8d,%r8d
  mov    $0xedb88320,%edi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %r8,%rax
  mov    $0x8,%edx
L31:
  mov    %rax,%rcx
  shr    %rax
  and    $0x1,%ecx
  mov    %rax,%rsi
  xor    %rdi,%rax
  test   %rcx,%rcx
  cmove  %rsi,%rax
  sub    $0x1,%edx
  jne    L31
  mov    %rax,(%r9,%r8,8)
  add    $0x1,%r8
  cmp    $0x100,%r8
  jne    L58
  mov    $0xffffffff,%eax
  xor    %rbx,%rax
  test   %r11,%r11
  je     L5
  lea    (%r10,%r11,1),%rcx
L48:
  movzbl (%r10),%edx
  add    $0x1,%r10
  xor    %eax,%edx
  shr    $0x8,%rax
  movzbl %dl,%edx
  xor    (%rsp,%rdx,8),%rax
  cmp    %rcx,%r10
  jne    L48
  mov    $0xffffffff,%ebx
  xor    %rbx,%rax
L2:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x810,%rsp
  pop    %rbx
  ret
L5:
  mov    %rbx,%rax
  jmp    L2
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long crc32(unsigned long crc, const unsigned char *buf, unsigned long len) {
  unsigned long crc_table[256];
  int i, k;
  for (i = 0; i < 256; i++) {
    unsigned long c = (unsigned long)i;
    for (k = 0; k < 8; k++)
      c = c & 1 ? 0xedb88320 ^ (c >> 1) : c >> 1;
    crc_table[i] = c;
  }
  crc = crc ^ 0xffffffffL;
  while (len--)
    crc = crc_table[((int)crc ^ (*buf++)) & 0xff] ^ (crc >> 8);
  return crc ^ 0xffffffffL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc32>:
  endbr64
  sub    $0x818,%rsp
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xedb88320,%esi
  nop
L110:
  mov    %rax,%rdx
  shr    %rdx
  test   $0x1,%al
  je     L101
  xor    %rsi,%rdx
L101:
  mov    %rdx,%rcx
  shr    %rcx
  and    $0x1,%edx
  je     L123
  xor    %rsi,%rcx
L123:
  mov    %rcx,%rdx
  shr    %rdx
  and    $0x1,%ecx
  je     L63
  xor    %rsi,%rdx
L63:
  mov    %rdx,%rcx
  shr    %rcx
  and    $0x1,%edx
  je     L86
  xor    %rsi,%rcx
L86:
  mov    %rcx,%rdx
  shr    %rdx
  and    $0x1,%ecx
  je     L52
  xor    %rsi,%rdx
L52:
  mov    %rdx,%rcx
  shr    %rcx
  and    $0x1,%edx
  je     L81
  xor    %rsi,%rcx
L81:
  mov    %rcx,%rdx
  shr    %rdx
  and    $0x1,%ecx
  je     L74
  xor    %rsi,%rdx
L74:
  mov    %rdx,%rcx
  shr    %rcx
  and    $0x1,%edx
  je     L55
  xor    %rsi,%rcx
L55:
  mov    %rcx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L110
  mov    $0xffffffff,%eax
  xor    %r8,%rax
  test   %r10,%r10
  je     L46
  add    %r9,%r10
L64:
  movzbl (%r9),%edx
  add    $0x1,%r9
  xor    %eax,%edx
  shr    $0x8,%rax
  movzbl %dl,%edx
  xor    (%rsp,%rdx,8),%rax
  cmp    %r10,%r9
  jne    L64
  mov    $0xffffffff,%r8d
  xor    %r8,%rax
L25:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L106
  add    $0x818,%rsp
  ret
L46:
  mov    %r8,%rax
  jmp    L25
L106:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long crc32(unsigned long crc, const unsigned char *buf, unsigned long len) {
  unsigned long crc_table[256];
  int i, k;
  for (i = 0; i < 256; i++) {
    unsigned long c = (unsigned long)i;
    for (k = 0; k < 8; k++)
      c = c & 1 ? 0xedb88320 ^ (c >> 1) : c >> 1;
    crc_table[i] = c;
  }
  crc = crc ^ 0xffffffffL;
  while (len--)
    crc = crc_table[((int)crc ^ (*buf++)) & 0xff] ^ (crc >> 8);
  return crc ^ 0xffffffffL;
}
```