ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  movslq %esi,%rax
  imul   $0x68db8bad,%rax,%rdx
  sar    $0x2c,%rdx
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %esi,%ecx
  sub    %eax,%ecx
  cmp    %ecx,%edx
  jne    L34
  mov    $0x3e8,%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    $0xa,%ecx
  cltd
  idiv   %ecx
  mov    %edx,%r8d
  mov    $0x64,%edi
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  cltd
  idiv   %ecx
  cmp    %eax,%r8d
  je     L6
L34:
  lea    D3(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D26
type: string
name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D0
type: string

tool: D26: %d

tool: D3: %d no poly


tool: D0: %d poly


assistant: ```c
main() {
  int a;
  scanf("%d", &a);
  if (((a / 10000) == (a % 10)) && ((a / 1000) % 10 == ((a % 100) / 10)))
    printf("%d poly\n", a);
  else
    printf("%d no poly\n", a);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x68db8bad,%rax,%rdx
  mov    %rax,%rsi
  mov    %eax,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x2c,%rdx
  sar    $0x22,%rax
  sub    %ecx,%edx
  sub    %ecx,%eax
  mov    %esi,%ecx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  cmp    %ecx,%edx
  jne    L0
  mov    %esi,%eax
  mov    $0x3e8,%ecx
  mov    $0x64,%edi
  cltd
  idiv   %ecx
  mov    $0xa,%ecx
  cltd
  idiv   %ecx
  mov    %esi,%eax
  mov    %edx,%r8d
  cltd
  idiv   %edi
  mov    %edx,%eax
  cltd
  idiv   %ecx
  cmp    %eax,%r8d
  je     L5
L0:
  lea    D6(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
type: string
name: retrieve_data
arguments: label: D6
type: string
name: retrieve_data
arguments: label: D12
type: string

tool: D14: %d

tool: D6: %d no poly


tool: D12: %d poly


assistant: ```c
main() {
  int a;
  scanf("%d", &a);
  if (((a / 10000) == (a % 10)) && ((a / 1000) % 10 == ((a % 100) / 10)))
    printf("%d poly\n", a);
  else
    printf("%d no poly\n", a);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x68db8bad,%rax,%rdx
  mov    %rax,%rsi
  mov    %eax,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x2c,%rdx
  sar    $0x22,%rax
  sub    %ecx,%edx
  sub    %ecx,%eax
  mov    %esi,%ecx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  cmp    %ecx,%edx
  jne    L30
  mov    %esi,%eax
  mov    $0x3e8,%ecx
  mov    $0x64,%edi
  cltd
  idiv   %ecx
  mov    $0xa,%ecx
  cltd
  idiv   %ecx
  mov    %esi,%eax
  mov    %edx,%r8d
  cltd
  idiv   %edi
  mov    %edx,%eax
  cltd
  idiv   %ecx
  cmp    %eax,%r8d
  je     L5
L30:
  lea    D18(%rip),%rdi
  call   <printf@plt>
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D18
type: string
name: disassemble_data
arguments: data_tag: D11
type: string

tool: D8: %d

tool: D18: %d no poly


tool: D11: %d poly


assistant: ```c
main() {
  int a;
  scanf("%d", &a);
  if (((a / 10000) == (a % 10)) && ((a / 1000) % 10 == ((a % 100) / 10)))
    printf("%d poly\n", a);
  else
    printf("%d no poly\n", a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__encap_ip6udp_none>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rbx
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <___constant_swab16@plt>
  cmp    %rax,%rbx
  jne    L18
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <encap_ipv6@plt>
  jmp    L10
L18:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
__attribute__((section("encap_ip6udp_none"), used)) int __encap_ip6udp_none(struct __sk_buff *skb) {
  if (skb->protocol == ___constant_swab16(ETH_P_IPV6))
    return encap_ipv6(skb, IPPROTO_UDP, ETH_P_IPV6);
  else
    return TC_ACT_OK;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__encap_ip6udp_none>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%rbp
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <___constant_swab16@plt>
  cmp    %rax,%rbp
  je     L15
  mov    D24(%rip),%rax
  mov    (%rax),%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <encap_ipv6@plt>
  jmp    L16
```

assistant: ```c
__attribute__((section("encap_ip6udp_none"), used)) int __encap_ip6udp_none(struct __sk_buff *skb) {
  if (skb->protocol == ___constant_swab16(ETH_P_IPV6))
    return encap_ipv6(skb, IPPROTO_UDP, ETH_P_IPV6);
  else
    return TC_ACT_OK;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__encap_ip6udp_none>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    D21(%rip),%rbx
  mov    (%rdi),%r12
  mov    (%rbx),%edi
  call   <___constant_swab16@plt>
  cmp    %rax,%r12
  je     L6
  mov    D29(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
  nop
L6:
  mov    D28(%rip),%rax
  mov    (%rbx),%edx
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  mov    (%rax),%esi
  pop    %r12
  jmp    1070 <encap_ipv6@plt>
```

assistant: ```c
__attribute__((section("encap_ip6udp_none"), used)) int __encap_ip6udp_none(struct __sk_buff *skb) {
  if (skb->protocol == ___constant_swab16(ETH_P_IPV6))
    return encap_ipv6(skb, IPPROTO_UDP, ETH_P_IPV6);
  else
    return TC_ACT_OK;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__encap_ip6udp_none>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    D23(%rip),%rbx
  mov    (%rdi),%r12
  mov    (%rbx),%edi
  call   <___constant_swab16@plt>
  cmp    %rax,%r12
  je     L7
  mov    D26(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
  nop
L7:
  mov    D20(%rip),%rax
  mov    (%rbx),%edx
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  mov    (%rax),%esi
  pop    %r12
  jmp    1070 <encap_ipv6@plt>
```

assistant: ```c
__attribute__((section("encap_ip6udp_none"), used)) int __encap_ip6udp_none(struct __sk_buff *skb) {
  if (skb->protocol == ___constant_swab16(ETH_P_IPV6))
    return encap_ipv6(skb, IPPROTO_UDP, ETH_P_IPV6);
  else
    return TC_ACT_OK;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fv_expprob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L26
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x2c(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L70
L26:
  movl   $0x0,-0x1c(%rbp)
  jmp    L58
L16:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L58:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L16
  movl   $0x0,-0x1c(%rbp)
  jmp    L30
L6:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L30:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L21
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x2c(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L70
L21:
  movsd  -0x18(%rbp),%xmm0
L70:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: f64

tool: D9: 1

assistant: ```c
double fv_expprob(float *vp, int N) {
  double ep = 0;
  double tot = 0;
  int i;
  if (!vp)
    return 1.0 / N;
  for (i = 0; i < N; i++) {
    tot += vp[i];
  }
  for (i = 0; i < N; i++) {
    double p = vp[i] / tot;
    ep += p * p;
  }
  if (tot <= 0)
    return 1.0 / N;
  return ep;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fv_expprob>:
  endbr64
  test   %rdi,%rdi
  je     L17
  test   %esi,%esi
  jle    L47
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm2,%xmm2
L13:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi),%xmm0
  addsd  %xmm0,%xmm2
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L13
  pxor   %xmm0,%xmm0
L45:
  pxor   %xmm1,%xmm1
  cvtss2sd (%rax),%xmm1
  divsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L45
  pxor   %xmm1,%xmm1
  comisd %xmm2,%xmm1
  jae    L47
L32:
  ret
L17:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  movsd  D17(%rip),%xmm0
  divsd  %xmm1,%xmm0
  ret
L47:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  movsd  D17(%rip),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L32
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: f64

tool: D17: 1

assistant: ```c
double fv_expprob(float *vp, int N) {
  double ep = 0;
  double tot = 0;
  int i;
  if (!vp)
    return 1.0 / N;
  for (i = 0; i < N; i++) {
    tot += vp[i];
  }
  for (i = 0; i < N; i++) {
    double p = vp[i] / tot;
    ep += p * p;
  }
  if (tot <= 0)
    return 1.0 / N;
  return ep;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fv_expprob>:
  endbr64
  test   %rdi,%rdi
  je     L22
  test   %esi,%esi
  jle    L22
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  lea    0x4(%rdi,%rax,4),%rdx
  movapd %xmm3,%xmm2
  mov    %rdi,%rax
L5:
  pxor   %xmm0,%xmm0
  add    $0x4,%rax
  cvtss2sd -0x4(%rax),%xmm0
  addsd  %xmm0,%xmm2
  cmp    %rax,%rdx
  jne    L5
  movapd %xmm3,%xmm0
  nopw   0x0(%rax,%rax,1)
L27:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtss2sd -0x4(%rdi),%xmm1
  divsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdi,%rdx
  jne    L27
  comisd %xmm2,%xmm3
  jae    L22
  ret
  nopl   (%rax)
L22:
  pxor   %xmm1,%xmm1
  movsd  D0(%rip),%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: f64

tool: D0: 1

assistant: ```c
double fv_expprob(float *vp, int N) {
  double ep = 0;
  double tot = 0;
  int i;
  if (!vp)
    return 1.0 / N;
  for (i = 0; i < N; i++) {
    tot += vp[i];
  }
  for (i = 0; i < N; i++) {
    double p = vp[i] / tot;
    ep += p * p;
  }
  if (tot <= 0)
    return 1.0 / N;
  return ep;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fv_expprob>:
  endbr64
  test   %rdi,%rdi
  je     L48
  test   %esi,%esi
  jle    L48
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  lea    0x4(%rdi,%rax,4),%rdx
  movapd %xmm3,%xmm2
  mov    %rdi,%rax
L7:
  pxor   %xmm0,%xmm0
  add    $0x4,%rax
  cvtss2sd -0x4(%rax),%xmm0
  addsd  %xmm0,%xmm2
  cmp    %rax,%rdx
  jne    L7
  movapd %xmm3,%xmm0
  nopw   0x0(%rax,%rax,1)
L27:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtss2sd -0x4(%rdi),%xmm1
  divsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdi,%rdx
  jne    L27
  comisd %xmm2,%xmm3
  jae    L48
  ret
  nopl   (%rax)
L48:
  pxor   %xmm1,%xmm1
  movsd  D3(%rip),%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: f64

tool: D3: 1

assistant: ```c
double fv_expprob(float *vp, int N) {
  double ep = 0;
  double tot = 0;
  int i;
  if (!vp)
    return 1.0 / N;
  for (i = 0; i < N; i++) {
    tot += vp[i];
  }
  for (i = 0; i < N; i++) {
    double p = vp[i] / tot;
    ep += p * p;
  }
  if (tot <= 0)
    return 1.0 / N;
  return ep;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_guessed: string
name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D28
type_guessed: string

tool: D13: pNumber is %X


tool: D10: &pNumber is %X


tool: D28: *pNumber is %X


assistant: ```c
int main(void) {
  int *pNumber = malloc(10 * sizeof(int));
  printf("pNumber is %X\n", pNumber);
  printf("&pNumber is %X\n", &pNumber);
  printf("*pNumber is %X\n", *pNumber);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  mov    %rax,(%rsp)
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  mov    (%rax),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D27
datatype: string
name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string

tool: D27: pNumber is %X


tool: D24: &pNumber is %X


tool: D18: *pNumber is %X


assistant: ```c
int main(void) {
  int *pNumber = malloc(10 * sizeof(int));
  printf("pNumber is %X\n", pNumber);
  printf("&pNumber is %X\n", &pNumber);
  printf("*pNumber is %X\n", *pNumber);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x28,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    D15(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  lea    D20(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
data_type: string
name: unpack_data
arguments: label: D28
data_type: string
name: unpack_data
arguments: label: D20
data_type: string

tool: D15: pNumber is %X


tool: D28: &pNumber is %X


tool: D20: *pNumber is %X


assistant: ```c
int main(void) {
  int *pNumber = malloc(10 * sizeof(int));
  printf("pNumber is %X\n", pNumber);
  printf("&pNumber is %X\n", &pNumber);
  printf("*pNumber is %X\n", *pNumber);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x28,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    D15(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  lea    D27(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string

tool: D15: pNumber is %X


tool: D18: &pNumber is %X


tool: D27: *pNumber is %X


assistant: ```c
int main(void) {
  int *pNumber = malloc(10 * sizeof(int));
  printf("pNumber is %X\n", pNumber);
  printf("&pNumber is %X\n", &pNumber);
  printf("*pNumber is %X\n", *pNumber);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shift_register15>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    D49(%rip),%eax
  and    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x14(%rbp),%edx
  mov    D49(%rip),%eax
  and    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    D49(%rip),%eax
  shr    %eax
  mov    %eax,D22(%rip)
  mov    -0x4(%rbp),%eax
  shl    $0xe,%eax
  mov    %eax,%edx
  mov    D22(%rip),%eax
  or     %edx,%eax
  mov    %eax,D22(%rip)
  mov    -0xc(%rbp),%eax
  xor    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
char shift_register15(unsigned char xor_tap) {
  static unsigned int sreg = 0x4000;
  int bit0, tap, bit14;
  bit0 = sreg & 1;
  tap = (sreg & xor_tap) ? 1 : 0;
  bit14 = (bit0 ^ tap);
  sreg >>= 1;
  sreg |= (bit14 << 14);
  return bit0 ^ 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shift_register15>:
  endbr64
  mov    D8(%rip),%ecx
  mov    %ecx,%eax
  and    $0x1,%eax
  movzbl %dil,%edi
  test   %ecx,%edi
  setne  %dl
  movzbl %dl,%edx
  xor    %eax,%edx
  shl    $0xe,%edx
  shr    %ecx
  or     %ecx,%edx
  mov    %edx,D17(%rip)
  xor    $0x1,%eax
  ret
```

assistant: ```c
char shift_register15(unsigned char xor_tap) {
  static unsigned int sreg = 0x4000;
  int bit0, tap, bit14;
  bit0 = sreg & 1;
  tap = (sreg & xor_tap) ? 1 : 0;
  bit14 = (bit0 ^ tap);
  sreg >>= 1;
  sreg |= (bit14 << 14);
  return bit0 ^ 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shift_register15>:
  endbr64
  mov    D12(%rip),%ecx
  movzbl %dil,%edi
  xor    %edx,%edx
  mov    %ecx,%eax
  and    $0x1,%eax
  test   %ecx,%edi
  setne  %dl
  shr    %ecx
  xor    %eax,%edx
  xor    $0x1,%eax
  shl    $0xe,%edx
  or     %ecx,%edx
  mov    %edx,D8(%rip)
  ret
```

assistant: ```c
char shift_register15(unsigned char xor_tap) {
  static unsigned int sreg = 0x4000;
  int bit0, tap, bit14;
  bit0 = sreg & 1;
  tap = (sreg & xor_tap) ? 1 : 0;
  bit14 = (bit0 ^ tap);
  sreg >>= 1;
  sreg |= (bit14 << 14);
  return bit0 ^ 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shift_register15>:
  endbr64
  mov    D0(%rip),%ecx
  movzbl %dil,%edi
  xor    %edx,%edx
  mov    %ecx,%eax
  and    $0x1,%eax
  test   %ecx,%edi
  setne  %dl
  shr    %ecx
  xor    %eax,%edx
  xor    $0x1,%eax
  shl    $0xe,%edx
  or     %ecx,%edx
  mov    %edx,D10(%rip)
  ret
```

assistant: ```c
char shift_register15(unsigned char xor_tap) {
  static unsigned int sreg = 0x4000;
  int bit0, tap, bit14;
  bit0 = sreg & 1;
  tap = (sreg & xor_tap) ? 1 : 0;
  bit14 = (bit0 ^ tap);
  sreg >>= 1;
  sreg |= (bit14 << 14);
  return bit0 ^ 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <errx@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: Malloc failed

assistant: ```c
void *xmalloc(size_t sz) {
  void *ret = malloc(sz);
  if (!ret)
    errx(1, "Malloc failed");
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xmalloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
L18:
  mov    %rbx,%rax
  pop    %rbx
  ret
L3:
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0: Malloc failed

assistant: ```c
void *xmalloc(size_t sz) {
  void *ret = malloc(sz);
  if (!ret)
    errx(1, "Malloc failed");
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
L16:
  mov    %r12,%rax
  pop    %r12
  ret
L1:
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  jmp    L16
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: Malloc failed

assistant: ```c
void *xmalloc(size_t sz) {
  void *ret = malloc(sz);
  if (!ret)
    errx(1, "Malloc failed");
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L6:
  mov    %r12,%rax
  pop    %r12
  ret
L17:
  lea    D9(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: Malloc failed

assistant: ```c
void *xmalloc(size_t sz) {
  void *ret = malloc(sz);
  if (!ret)
    errx(1, "Malloc failed");
  return ret;
}
```