ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<peer_start>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <peer_connect@plt>
  cmp    $0x1,%eax
  je     L4
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <peer_listen@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L4:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int peer_start(int sockfd, const char *host, const char *port) {
  if ((peer_connect(sockfd, host, port)) == 1) {
    return 1;
  }
  if ((peer_listen(sockfd, port)) == 1) {
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<peer_start>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <peer_connect@plt>
  cmp    $0x1,%eax
  je     L1
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <peer_listen@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L1:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int peer_start(int sockfd, const char *host, const char *port) {
  if ((peer_connect(sockfd, host, port)) == 1) {
    return 1;
  }
  if ((peer_listen(sockfd, port)) == 1) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sprintf_append_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %rsi,-0xf0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L10
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L10:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0xf0(%rbp),%rdx
  mov    -0xd4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xd4(%rbp),%edx
  mov    -0xf0(%rbp),%rcx
  lea    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf_alloc@plt>
  mov    %eax,-0xd0(%rbp)
  mov    -0xd4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xe8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L69
  mov    -0xe8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L38
L69:
  mov    $0x0,%eax
L38:
  mov    -0xd0(%rbp),%edx
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0xcc(%rbp)
  mov    -0xe8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L83
  mov    -0xe8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xcc(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0xc0(%rbp)
  jmp    L29
L83:
  mov    -0xcc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0xc0(%rbp)
  cmpq   $0x0,-0xc0(%rbp)
  je     L29
  mov    -0xc0(%rbp),%rax
  movb   $0x0,(%rax)
L29:
  cmpq   $0x0,-0xc0(%rbp)
  jne    L44
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xe8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L42
L44:
  mov    -0xe8(%rbp),%rax
  mov    -0xc0(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0xc8(%rbp),%rdx
  mov    -0xe8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xcc(%rbp),%eax
L42:
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

assistant: ```c
int sprintf_append_alloc(char **str, const char *fmt, ...) {
  char *appendage, *new_str;
  int appendage_len, new_len;
  va_list ap;
  va_start(ap, fmt);
  appendage_len = vsprintf_alloc(&appendage, fmt, ap);
  va_end(ap);
  new_len = ((*str) ? strlen(*str) : 0) + appendage_len + 1;
  if (*str) {
    new_str = realloc(*str, new_len);
  } else {
    new_str = malloc(new_len);
    if (new_str) {
      new_str[0] = '\0';
    }
  }
  if (new_str == NULL) {
    free(appendage);
    return strlen(*str);
  }
  *str = new_str;
  strcat(*str, appendage);
  free(appendage);
  return new_len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sprintf_append_alloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%edx
  mov    %rbx,%rsi
  call   <vsprintf_alloc@plt>
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L43
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%ebx
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L23
  mov    %ebx,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L19
L10:
  mov    %rdi,0x0(%rbp)
  mov    (%rsp),%rsi
  call   <strcat@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    0x0(%rbp),%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L47
L43:
  add    $0x1,%ebx
L23:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L19
  movb   $0x0,(%rax)
  jmp    L10
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sprintf_append_alloc(char **str, const char *fmt, ...) {
  char *appendage, *new_str;
  int appendage_len, new_len;
  va_list ap;
  va_start(ap, fmt);
  appendage_len = vsprintf_alloc(&appendage, fmt, ap);
  va_end(ap);
  new_len = ((*str) ? strlen(*str) : 0) + appendage_len + 1;
  if (*str) {
    new_str = realloc(*str, new_len);
  } else {
    new_str = malloc(new_len);
    if (new_str) {
      new_str[0] = '\0';
    }
  }
  if (new_str == NULL) {
    free(appendage);
    return strlen(*str);
  }
  *str = new_str;
  strcat(*str, appendage);
  free(appendage);
  return new_len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sprintf_append_alloc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <va_start@plt>
  mov    %r12,%rsi
  mov    %rsp,%rdi
  mov    %ebp,%edx
  call   <vsprintf_alloc@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L66
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x1(%r12,%rax,1),%r12d
  test   %rdi,%rdi
  je     L42
  mov    %r12d,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L48
L37:
  mov    %rdi,(%rbx)
  mov    (%rsp),%rsi
  call   <strcat@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L66:
  add    $0x1,%r12d
L42:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L48
  movb   $0x0,(%rax)
  jmp    L37
  nopl   0x0(%rax)
L48:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    (%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L23
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sprintf_append_alloc(char **str, const char *fmt, ...) {
  char *appendage, *new_str;
  int appendage_len, new_len;
  va_list ap;
  va_start(ap, fmt);
  appendage_len = vsprintf_alloc(&appendage, fmt, ap);
  va_end(ap);
  new_len = ((*str) ? strlen(*str) : 0) + appendage_len + 1;
  if (*str) {
    new_str = realloc(*str, new_len);
  } else {
    new_str = malloc(new_len);
    if (new_str) {
      new_str[0] = '\0';
    }
  }
  if (new_str == NULL) {
    free(appendage);
    return strlen(*str);
  }
  *str = new_str;
  strcat(*str, appendage);
  free(appendage);
  return new_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sprintf_append_alloc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <va_start@plt>
  mov    %r12,%rsi
  mov    %rsp,%rdi
  mov    %ebp,%edx
  call   <vsprintf_alloc@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L42
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x1(%r12,%rax,1),%r12d
  test   %rdi,%rdi
  je     L14
  mov    %r12d,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L9
L17:
  mov    %rdi,(%rbx)
  mov    (%rsp),%rsi
  call   <strcat@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L50:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L42:
  add    $0x1,%r12d
L14:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
  jmp    L17
  nopl   0x0(%rax)
L9:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    (%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L50
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sprintf_append_alloc(char **str, const char *fmt, ...) {
  char *appendage, *new_str;
  int appendage_len, new_len;
  va_list ap;
  va_start(ap, fmt);
  appendage_len = vsprintf_alloc(&appendage, fmt, ap);
  va_end(ap);
  new_len = ((*str) ? strlen(*str) : 0) + appendage_len + 1;
  if (*str) {
    new_str = realloc(*str, new_len);
  } else {
    new_str = malloc(new_len);
    if (new_str) {
      new_str[0] = '\0';
    }
  }
  if (new_str == NULL) {
    free(appendage);
    return strlen(*str);
  }
  *str = new_str;
  strcat(*str, appendage);
  free(appendage);
  return new_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  shr    %rax
  imul   -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L51
  mov    $0x0,%eax
  jmp    L33
L51:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    -0x38(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L15
  mov    -0x8(%rbp),%rax
  jmp    L33
L15:
  mov    -0x28(%rbp),%rax
  shr    %rax
  mov    %rax,%rsi
  cmpl   $0x0,-0xc(%rbp)
  jns    L21
  mov    -0x20(%rbp),%rax
  jmp    L46
L21:
  mov    -0x8(%rbp),%rax
L46:
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rdi
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    %rax,%rsi
  call   <bsearch>
L33:
  leave
  ret
```

assistant: ```c
void *bsearch(const void *key, const void *base, size_t n_elem, size_t size, int (*cmp)(const void *keyval, const void *datum)) {
  int cmp_result;
  void *middle_key = (void *)((unsigned)base + (n_elem / 2) * size);
  if (n_elem == 0)
    return NULL;
  cmp_result = cmp(middle_key, key);
  if (cmp_result == 0)
    return middle_key;
  else
    return bsearch(key, cmp_result < 0 ? base : middle_key, n_elem / 2, size, cmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r15
  shr    %r15
  mov    %esi,%ebx
  mov    %r15,%rax
  imul   %rcx,%rax
  add    %rax,%rbx
  test   %rdx,%rdx
  je     L18
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rcx,%r12
  mov    %r8,%r14
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   *%r8
  test   %eax,%eax
  je     L14
  cmovns %rbx,%rbp
  mov    %r14,%r8
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <bsearch>
  mov    %rax,%rbx
L14:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    $0x0,%ebx
  jmp    L14
```

assistant: ```c
void *bsearch(const void *key, const void *base, size_t n_elem, size_t size, int (*cmp)(const void *keyval, const void *datum)) {
  int cmp_result;
  void *middle_key = (void *)((unsigned)base + (n_elem / 2) * size);
  if (n_elem == 0)
    return NULL;
  cmp_result = cmp(middle_key, key);
  if (cmp_result == 0)
    return middle_key;
  else
    return bsearch(key, cmp_result < 0 ? base : middle_key, n_elem / 2, size, cmp);
}
```
user: What is the c source code of the assembly code below?

```asm
<bsearch>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  shr    %r15
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  imul   %r15,%r12
  mov    %r8,%rbp
  push   %rbx
  mov    %rcx,%rbx
  add    %r14,%r12
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L48
  jmp    L27
  nopl   (%rax)
L37:
  mov    %r12d,%r12d
  mov    %r15,%rax
  cmovns %r12,%r14
  shr    %rax
  mov    %rax,%r12
  imul   %rbx,%r12
  add    %r14,%r12
  test   %r15,%r15
  je     L27
  mov    %rax,%r15
L48:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   *%rbp
  test   %eax,%eax
  jne    L37
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L27:
  xor    %r12d,%r12d
  jmp    L28
```

assistant: ```c
void *bsearch(const void *key, const void *base, size_t n_elem, size_t size, int (*cmp)(const void *keyval, const void *datum)) {
  int cmp_result;
  void *middle_key = (void *)((unsigned)base + (n_elem / 2) * size);
  if (n_elem == 0)
    return NULL;
  cmp_result = cmp(middle_key, key);
  if (cmp_result == 0)
    return middle_key;
  else
    return bsearch(key, cmp_result < 0 ? base : middle_key, n_elem / 2, size, cmp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bsearch>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  mov    %rcx,%rax
  shr    %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  imul   %r15,%rax
  push   %r12
  push   %rbp
  push   %rbx
  add    %rax,%r14
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L31
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rcx,%rbx
  mov    %r8,%rbp
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r15,%rdx
  mov    %r14d,%eax
  shr    %rdx
  mov    %rdx,%rcx
  imul   %rbx,%rcx
  add    %rcx,%rax
  test   %r15,%r15
  je     L31
  mov    %r14,%r13
L55:
  mov    %rax,%r14
  mov    %rdx,%r15
L14:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   *%rbp
  test   %eax,%eax
  je     L20
  jns    L22
  mov    %r15,%rdx
  mov    %rbx,%rax
  mov    %r13d,%ecx
  shr    %rdx
  imul   %rdx,%rax
  add    %rcx,%rax
  test   %r15,%r15
  jne    L55
L31:
  xor    %r14d,%r14d
L20:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *bsearch(const void *key, const void *base, size_t n_elem, size_t size, int (*cmp)(const void *keyval, const void *datum)) {
  int cmp_result;
  void *middle_key = (void *)((unsigned)base + (n_elem / 2) * size);
  if (n_elem == 0)
    return NULL;
  cmp_result = cmp(middle_key, key);
  if (cmp_result == 0)
    return middle_key;
  else
    return bsearch(key, cmp_result < 0 ? base : middle_key, n_elem / 2, size, cmp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movb   $0x7a,(%rax)
  lea    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x23,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x25,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void test2(char *array, char *endptr) {
  array[2] = 'z';
  long long r = strtoll(array, &endptr, 35);
  assert(array + 2 == endptr);
  assert(r == 37);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x8(%rsp)
  movb   $0x7a,0x2(%rdi)
  lea    0x8(%rsp),%rsi
  mov    $0x23,%edx
  call   <strtoll@plt>
  mov    %rax,%rbp
  add    $0x2,%rbx
  cmp    %rbx,0x8(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x25,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test2(char *array, char *endptr) {
  array[2] = 'z';
  long long r = strtoll(array, &endptr, 35);
  assert(array + 2 == endptr);
  assert(r == 37);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test2>:
  endbr64
  push   %rbp
  mov    $0x23,%edx
  push   %rbx
  mov    %rdi,%rbx
  add    $0x2,%rbx
  sub    $0x18,%rsp
  movb   $0x7a,0x2(%rdi)
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  call   <strtoll@plt>
  xor    %edi,%edi
  cmp    %rbx,0x8(%rsp)
  mov    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x25,%rbp
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test2(char *array, char *endptr) {
  array[2] = 'z';
  long long r = strtoll(array, &endptr, 35);
  assert(array + 2 == endptr);
  assert(r == 37);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test2>:
  endbr64
  push   %rbp
  mov    $0x23,%edx
  push   %rbx
  mov    %rdi,%rbx
  add    $0x2,%rbx
  sub    $0x18,%rsp
  movb   $0x7a,0x2(%rdi)
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  call   <strtoll@plt>
  xor    %edi,%edi
  cmp    %rbx,0x8(%rsp)
  mov    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x25,%rbp
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test2(char *array, char *endptr) {
  array[2] = 'z';
  long long r = strtoll(array, &endptr, 35);
  assert(array + 2 == endptr);
  assert(r == 37);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<alarm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
unsigned int alarm(unsigned int seconds __attribute__((unused))) {
  assert(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<alarm>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int alarm(unsigned int seconds __attribute__((unused))) {
  assert(0);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<alarm>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int alarm(unsigned int seconds __attribute__((unused))) {
  assert(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<alarm>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int alarm(unsigned int seconds __attribute__((unused))) {
  assert(0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L18
  cmpl   $0x0,-0x8(%rbp)
  je     L4
L18:
  mov    $0x1,%eax
  jmp    L7
L4:
  mov    $0x0,%eax
L7:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: c=%d


assistant: ```c
main() {
  int a = 1;
  int b = 2, c;
  c = a > b || b + 1 != 1 & 5 == 5;
  printf("c=%d\n", c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: c=%d


assistant: ```c
main() {
  int a = 1;
  int b = 2, c;
  c = a > b || b + 1 != 1 & 5 == 5;
  printf("c=%d\n", c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: c=%d


assistant: ```c
main() {
  int a = 1;
  int b = 2, c;
  c = a > b || b + 1 != 1 & 5 == 5;
  printf("c=%d\n", c);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: c=%d


assistant: ```c
main() {
  int a = 1;
  int b = 2, c;
  c = a > b || b + 1 != 1 & 5 == 5;
  printf("c=%d\n", c);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<zero_dvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *zero_dvec(int n) {
  double *p = (double *)calloc(n, sizeof(double));
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<zero_dvec>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  call   <calloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double *zero_dvec(int n) {
  double *p = (double *)calloc(n, sizeof(double));
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zero_dvec>:
  endbr64
  mov    $0x8,%esi
  jmp    1050 <calloc@plt>
```

assistant: ```c
double *zero_dvec(int n) {
  double *p = (double *)calloc(n, sizeof(double));
  return p;
}
```