ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<drawLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %r8d,%ecx
  mov    %r9d,-0x3c(%rbp)
  mov    %si,-0x2c(%rbp)
  mov    %dx,-0x30(%rbp)
  mov    %ax,-0x34(%rbp)
  mov    %ecx,%eax
  mov    %ax,-0x38(%rbp)
  movzwl -0x34(%rbp),%eax
  movzwl -0x2c(%rbp),%edx
  sub    %edx,%eax
  mov    %ax,-0x16(%rbp)
  movzwl -0x38(%rbp),%eax
  movzwl -0x30(%rbp),%edx
  sub    %edx,%eax
  mov    %ax,-0x14(%rbp)
  movswl -0x16(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  mov    %eax,%ebx
  movswl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %ax,%bx
  jb     L18
  movswl -0x16(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  jmp    L5
L18:
  movswl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
L5:
  mov    %ax,-0x12(%rbp)
  movzwl -0x12(%rbp),%r9d
  movswl -0x14(%rbp),%r8d
  movswl -0x16(%rbp),%ecx
  movswl -0x30(%rbp),%edx
  movswl -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x3c(%rbp),%edi
  push   %rdi
  mov    %rax,%rdi
  call   <line@plt>
  add    $0x10,%rsp
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void drawLine(volatile unsigned short *vram, short xs, short ys, short xe, short ye, unsigned color) {
  short dx = xe - xs;
  short dy = ye - ys;
  unsigned short count = (abs(dx) >= abs(dy)) ? abs(dx) : abs(dy);
  line(vram, xs, ys, dx, dy, count, color);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<drawLine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %r8d,%ebx
  mov    %r9d,%r14d
  sub    %esi,%ecx
  movswl %cx,%ebp
  mov    %ebp,%edi
  call   <abs@plt>
  mov    %eax,%r15d
  sub    %r13d,%ebx
  movswl %bx,%ebx
  mov    %ebx,%edi
  call   <abs@plt>
  cmp    %ax,%r15w
  jb     L2
  mov    %ebp,%edi
  call   <abs@plt>
L15:
  movswl %r13w,%edx
  movswl %r12w,%esi
  sub    $0x8,%rsp
  push   %r14
  movzwl %ax,%r9d
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    0x18(%rsp),%rdi
  call   <line@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  mov    %ebx,%edi
  call   <abs@plt>
  jmp    L15
```

assistant: ```c
void drawLine(volatile unsigned short *vram, short xs, short ys, short xe, short ye, unsigned color) {
  short dx = xe - xs;
  short dy = ye - ys;
  unsigned short count = (abs(dx) >= abs(dy)) ? abs(dx) : abs(dy);
  line(vram, xs, ys, dx, dy, count, color);
}
```
user: What is the c source code of the assembly code below:

```asm
<drawLine>:
  endbr64
  push   %r15
  sub    %esi,%ecx
  push   %r14
  movswl %cx,%r15d
  mov    %r9d,%r14d
  push   %r13
  mov    %rdi,%r13
  mov    %r15d,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %r8d,%ebx
  sub    %r12d,%ebx
  movswl %bx,%ebx
  sub    $0x18,%rsp
  call   <abs@plt>
  mov    %ebx,%edi
  mov    %ax,0xe(%rsp)
  call   <abs@plt>
  cmp    %ax,0xe(%rsp)
  jb     L17
  mov    %r15d,%edi
  call   <abs@plt>
L12:
  sub    $0x8,%rsp
  movswl %r12w,%edx
  movswl %bp,%esi
  mov    %ebx,%r8d
  push   %r14
  mov    %r15d,%ecx
  mov    %r13,%rdi
  movzwl %ax,%r9d
  call   <line@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L17:
  mov    %ebx,%edi
  call   <abs@plt>
  jmp    L12
```

assistant: ```c
void drawLine(volatile unsigned short *vram, short xs, short ys, short xe, short ye, unsigned color) {
  short dx = xe - xs;
  short dy = ye - ys;
  unsigned short count = (abs(dx) >= abs(dy)) ? abs(dx) : abs(dy);
  line(vram, xs, ys, dx, dy, count, color);
}
```
user: What is the c source code of the assembly code below:

```asm
<drawLine>:
  endbr64
  push   %r15
  sub    %esi,%ecx
  push   %r14
  movswl %cx,%r15d
  mov    %r9d,%r14d
  push   %r13
  mov    %rdi,%r13
  mov    %r15d,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %r8d,%ebx
  sub    %r12d,%ebx
  movswl %bx,%ebx
  sub    $0x18,%rsp
  call   <abs@plt>
  mov    %ebx,%edi
  mov    %ax,0xe(%rsp)
  call   <abs@plt>
  cmp    %ax,0xe(%rsp)
  jb     L0
  mov    %r15d,%edi
  call   <abs@plt>
L4:
  sub    $0x8,%rsp
  movswl %r12w,%edx
  movswl %bp,%esi
  mov    %ebx,%r8d
  push   %r14
  mov    %r15d,%ecx
  mov    %r13,%rdi
  movzwl %ax,%r9d
  call   <line@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L0:
  mov    %ebx,%edi
  call   <abs@plt>
  jmp    L4
```

assistant: ```c
void drawLine(volatile unsigned short *vram, short xs, short ys, short xe, short ye, unsigned color) {
  short dx = xe - xs;
  short dy = ye - ys;
  unsigned short count = (abs(dx) >= abs(dy)) ? abs(dx) : abs(dy);
  line(vram, xs, ys, dx, dy, count, color);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  mov    $0x0,%eax
  jmp    L36
L10:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L36
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L2
  mov    -0x8(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
int *ft_range(int min, int max) {
  int i;
  int *tab;
  i = 0;
  if (min >= max)
    return (NULL);
  tab = (int *)malloc(sizeof(*tab) * (max - min));
  if (tab == NULL)
    return (NULL);
  while (min < max) {
    tab[i] = min;
    i++;
    min++;
  }
  return (tab);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_range>:
  endbr64
  mov    $0x0,%edx
  cmp    %esi,%edi
  jge    L9
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %esi,%edi
  sub    %ebx,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L38
L27:
  mov    %ebx,(%rax)
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %ebx,%ebp
  jne    L27
L15:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    $0x0,%edx
  jmp    L15
L9:
  mov    %rdx,%rax
  ret
```

assistant: ```c
int *ft_range(int min, int max) {
  int i;
  int *tab;
  i = 0;
  if (min >= max)
    return (NULL);
  tab = (int *)malloc(sizeof(*tab) * (max - min));
  if (tab == NULL)
    return (NULL);
  while (min < max) {
    tab[i] = min;
    i++;
    min++;
  }
  return (tab);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_range>:
  endbr64
  cmp    %esi,%edi
  jge    L2
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  sub    %ebx,%edi
  shl    $0x2,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,%rdx
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %ebx,(%rdx)
  add    $0x1,%ebx
  add    $0x4,%rdx
  cmp    %ebx,%ebp
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L27:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int *ft_range(int min, int max) {
  int i;
  int *tab;
  i = 0;
  if (min >= max)
    return (NULL);
  tab = (int *)malloc(sizeof(*tab) * (max - min));
  if (tab == NULL)
    return (NULL);
  while (min < max) {
    tab[i] = min;
    i++;
    min++;
  }
  return (tab);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_range>:
  endbr64
  cmp    %esi,%edi
  jge    L30
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    %edi,%r12d
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L79
  lea    -0x1(%r12),%edx
  cmp    $0x2,%edx
  jbe    L74
  mov    %r12d,%ecx
  movd   %ebx,%xmm3
  movdqa D8(%rip),%xmm2
  mov    %rax,%rdx
  shr    $0x2,%ecx
  pshufd $0x0,%xmm3,%xmm0
  paddd  D12(%rip),%xmm0
  shl    $0x4,%rcx
  add    %rax,%rcx
  nopw   0x0(%rax,%rax,1)
L6:
  movdqa %xmm0,%xmm1
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rdx)
  cmp    %rdx,%rcx
  jne    L6
  mov    %r12d,%edx
  and    $0xfffffffc,%edx
  add    %edx,%ebx
  cmp    %edx,%r12d
  je     L61
L33:
  movslq %edx,%rdx
  mov    %ebx,(%rax,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rbx),%edx
  cmp    %ebp,%edx
  jge    L61
  add    $0x2,%ebx
  mov    %edx,0x4(%rax,%rcx,1)
  cmp    %ebx,%ebp
  jle    L61
  mov    %ebx,0x8(%rax,%rcx,1)
L61:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L79:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  xor    %edx,%edx
  jmp    L33
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D12
type_infered: byte[16]

tool: {"D8": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int *ft_range(int min, int max) {
  int i;
  int *tab;
  i = 0;
  if (min >= max)
    return (NULL);
  tab = (int *)malloc(sizeof(*tab) * (max - min));
  if (tab == NULL)
    return (NULL);
  while (min < max) {
    tab[i] = min;
    i++;
    min++;
  }
  return (tab);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L47
L17:
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L2
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L36
L2:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L36:
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0x10(%rbp),%eax
  shl    $0x2,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
data_type: string
name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D27
data_type: string

tool: D18: %d

tool: D8: PUM

tool: D27: %d 

assistant: ```c
int main() {
  int i, n;
  scanf("%d", &n);
  for (i = 1; i <= n * 4; i++) {
    if (i % 4 == 0) {
      printf("PUM\n");
      continue;
    }
    printf("%d ", i);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L4
  mov    $0x1,%ebx
  lea    D26(%rip),%rbp
  lea    D19(%rip),%r12
  jmp    L17
L43:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L53:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  shl    $0x2,%eax
  cmp    %ebx,%eax
  jl     L4
L17:
  test   $0x3,%bl
  jne    L43
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L53
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type: string
name: disassemble_data
arguments: data_tag: D26
type: string
name: disassemble_data
arguments: data_tag: D19
type: string

tool: D28: %d

tool: D26: %d 

tool: D19: PUM

assistant: ```c
int main() {
  int i, n;
  scanf("%d", &n);
  for (i = 1; i <= n * 4; i++) {
    if (i % 4 == 0) {
      printf("PUM\n");
      continue;
    }
    printf("%d ", i);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L26
  mov    $0x1,%ebx
  lea    D5(%rip),%rbp
  lea    D7(%rip),%r12
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  shl    $0x2,%eax
  cmp    %ebx,%eax
  jl     L26
L13:
  test   $0x3,%bl
  jne    L32
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  shl    $0x2,%eax
  cmp    %ebx,%eax
  jge    L13
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D7
type_guessed: string

tool: D28: %d

tool: D5: %d 

tool: D7: PUM

assistant: ```c
int main() {
  int i, n;
  scanf("%d", &n);
  for (i = 1; i <= n * 4; i++) {
    if (i % 4 == 0) {
      printf("PUM\n");
      continue;
    }
    printf("%d ", i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L51
  mov    $0x1,%ebx
  lea    D24(%rip),%rbp
  lea    D29(%rip),%r12
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  shl    $0x2,%eax
  cmp    %ebx,%eax
  jl     L51
L53:
  test   $0x3,%bl
  jne    L40
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  shl    $0x2,%eax
  cmp    %ebx,%eax
  jge    L53
L51:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type: string
name: disassemble_data
arguments: data_label: D24
type: string
name: disassemble_data
arguments: data_label: D29
type: string

tool: D18: %d

tool: D24: %d 

tool: D29: PUM

assistant: ```c
int main() {
  int i, n;
  scanf("%d", &n);
  for (i = 1; i <= n * 4; i++) {
    if (i % 4 == 0) {
      printf("PUM\n");
      continue;
    }
    printf("%d ", i);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getlinee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L48
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L48
  cmpl   $0xa,-0x4(%rbp)
  jne    L22
L48:
  cmpl   $0xa,-0x4(%rbp)
  jne    L5
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getlinee(char s[], int max) {
  int i, c;
  for (i = 0; i < (max - 1) && (c = getchar()) != EOF && c != '\n'; i++)
    s[i] = c;
  if (c == '\n')
    s[i++] = '\n';
  s[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getlinee>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L49
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L1:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D4(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L11
  cmp    $0xa,%eax
  je     L11
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L1
  mov    %r12d,%ebx
  jmp    L21
L49:
  mov    $0x0,%ebx
L11:
  cmp    $0xa,%eax
  je     L5
L21:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  lea    0x1(%rbx),%ebx
  jmp    L21
```

assistant: ```c
int getlinee(char s[], int max) {
  int i, c;
  for (i = 0; i < (max - 1) && (c = getchar()) != EOF && c != '\n'; i++)
    s[i] = c;
  if (c == '\n')
    s[i++] = '\n';
  s[i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getlinee>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L25
  mov    D4(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L10:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L0
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L8
  mov    %edx,%r14d
L29:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L10
  cmp    $0xa,%eax
  je     L51
L25:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  lea    0x1(%r14),%edx
L0:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getlinee(char s[], int max) {
  int i, c;
  for (i = 0; i < (max - 1) && (c = getchar()) != EOF && c != '\n'; i++)
    s[i] = c;
  if (c == '\n')
    s[i++] = '\n';
  s[i] = '\0';
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getlinee>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L59
  mov    D2(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L48:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L14
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L22
  mov    %edx,%r14d
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L48
  cmp    $0xa,%eax
  je     L46
L59:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  lea    0x1(%r14),%edx
L14:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L22:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getlinee(char s[], int max) {
  int i, c;
  for (i = 0; i < (max - 1) && (c = getchar()) != EOF && c != '\n'; i++)
    s[i] = c;
  if (c == '\n')
    s[i++] = '\n';
  s[i] = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sdo_set_segment_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  and    $0xfffffff1,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sdo_set_segment_size(struct can_frame *frame, size_t size) {
  int n = 7 - size;
  frame->data[0] &= ~(7 << 1);
  frame->data[0] |= n << 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sdo_set_segment_size>:
  endbr64
  mov    (%rdi),%rax
  andl   $0xfffffff1,(%rax)
  mov    (%rdi),%rdx
  mov    $0x7,%eax
  sub    %esi,%eax
  add    %eax,%eax
  or     %eax,(%rdx)
  ret
```

assistant: ```c
void sdo_set_segment_size(struct can_frame *frame, size_t size) {
  int n = 7 - size;
  frame->data[0] &= ~(7 << 1);
  frame->data[0] |= n << 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sdo_set_segment_size>:
  endbr64
  mov    (%rdi),%rcx
  mov    $0x7,%edx
  sub    %esi,%edx
  mov    (%rcx),%eax
  add    %edx,%edx
  and    $0xfffffff1,%eax
  or     %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void sdo_set_segment_size(struct can_frame *frame, size_t size) {
  int n = 7 - size;
  frame->data[0] &= ~(7 << 1);
  frame->data[0] |= n << 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sdo_set_segment_size>:
  endbr64
  mov    (%rdi),%rcx
  mov    $0x7,%edx
  sub    %esi,%edx
  mov    (%rcx),%eax
  add    %edx,%edx
  and    $0xfffffff1,%eax
  or     %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void sdo_set_segment_size(struct can_frame *frame, size_t size) {
  int n = 7 - size;
  frame->data[0] &= ~(7 << 1);
  frame->data[0] |= n << 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D9(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <infix_to_postfix_conv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string

tool: D9: a + b * c + (d * c + f) * g

assistant: ```c
int main(void) {
  char *string = "a + b * c + (d * c + f) * g";
  char *output = infix_to_postfix_conv(string);
  puts(output);
  free(output);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rdi
  call   <infix_to_postfix_conv@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: a + b * c + (d * c + f) * g

assistant: ```c
int main(void) {
  char *string = "a + b * c + (d * c + f) * g";
  char *output = infix_to_postfix_conv(string);
  puts(output);
  free(output);
  return 0;
}
```