ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x24(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%esi
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x20(%rbp),%rcx
  mov    %esi,%r8d
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  lea    -0x24(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    %rsi,%r8
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  lea    -0x18(%rbp),%rsi
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%esi
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%esi
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %esi,%r8d
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3: %d	%d	%d	%d


assistant: ```c
main() {
  int x, *p, **q, ***r;
  x = 5;
  p = &x;
  q = &p;
  r = &q;
  printf("%d\t%d\t%d\t%d\n", *r, q, &p, x);
  printf("%d\t%d\t%d\t%d\n", **q, &r, &x, p);
  printf("%d\t%d\t%d\t%d\n", **r, *p, *&q, &q);
  printf("%d\t%d\t%d\t%d\n", ***r, ***&q, *&r, *&x);
  printf("%d\t%d\t%d\t%d\n", p, q, r, x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x5,0xc(%rsp)
  lea    0xc(%rsp),%r12
  mov    %r12,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rsi,0x18(%rsp)
  lea    0x18(%rsp),%rbp
  mov    %rbp,0x20(%rsp)
  mov    $0x5,%r8d
  mov    %rsi,%rcx
  mov    %rsi,%rdx
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rdx
  mov    0x18(%rsp),%rax
  mov    (%rax),%rax
  mov    0x10(%rsp),%r8
  mov    %r12,%rcx
  mov    (%rax),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%rax
  mov    (%rax),%rax
  mov    %rbp,%r8
  mov    0x18(%rsp),%rcx
  mov    0x10(%rsp),%rdx
  mov    (%rdx),%edx
  mov    (%rax),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rax
  mov    (%rax),%rdx
  mov    (%rcx),%rax
  mov    (%rax),%rax
  mov    0xc(%rsp),%r8d
  mov    (%rdx),%edx
  mov    (%rax),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%r8d
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rdx
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: %d	%d	%d	%d


assistant: ```c
main() {
  int x, *p, **q, ***r;
  x = 5;
  p = &x;
  q = &p;
  r = &q;
  printf("%d\t%d\t%d\t%d\n", *r, q, &p, x);
  printf("%d\t%d\t%d\t%d\n", **q, &r, &x, p);
  printf("%d\t%d\t%d\t%d\n", **r, *p, *&q, &q);
  printf("%d\t%d\t%d\t%d\n", ***r, ***&q, *&r, *&x);
  printf("%d\t%d\t%d\t%d\n", p, q, r, x);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%r8d
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%r12
  movl   $0x5,0xc(%rsp)
  mov    %rsi,%rcx
  mov    %rsi,%rdx
  lea    0x18(%rsp),%rbx
  mov    %rsi,0x18(%rsp)
  mov    %r12,0x10(%rsp)
  mov    %rbx,0x20(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    0x10(%rsp),%r8
  lea    0x20(%rsp),%rdx
  mov    (%rax),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%rax
  mov    %rbx,%r8
  mov    %rbp,%rdi
  mov    0x10(%rsp),%rdx
  mov    0x18(%rsp),%rcx
  mov    (%rax),%rax
  mov    (%rdx),%edx
  mov    (%rax),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rax
  mov    %rbp,%rdi
  mov    0xc(%rsp),%r8d
  mov    (%rax),%rdx
  mov    (%rcx),%rax
  mov    (%rax),%rax
  mov    (%rdx),%edx
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%r8d
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rdx
  mov    0x10(%rsp),%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: %d	%d	%d	%d


assistant: ```c
main() {
  int x, *p, **q, ***r;
  x = 5;
  p = &x;
  q = &p;
  r = &q;
  printf("%d\t%d\t%d\t%d\n", *r, q, &p, x);
  printf("%d\t%d\t%d\t%d\n", **q, &r, &x, p);
  printf("%d\t%d\t%d\t%d\n", **r, *p, *&q, &q);
  printf("%d\t%d\t%d\t%d\n", ***r, ***&q, *&r, *&x);
  printf("%d\t%d\t%d\t%d\n", p, q, r, x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%r8d
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%r12
  movl   $0x5,0xc(%rsp)
  mov    %rsi,%rcx
  mov    %rsi,%rdx
  lea    0x18(%rsp),%rbx
  mov    %rsi,0x18(%rsp)
  mov    %r12,0x10(%rsp)
  mov    %rbx,0x20(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    0x10(%rsp),%r8
  lea    0x20(%rsp),%rdx
  mov    (%rax),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%rax
  mov    %rbx,%r8
  mov    %rbp,%rdi
  mov    0x10(%rsp),%rdx
  mov    0x18(%rsp),%rcx
  mov    (%rax),%rax
  mov    (%rdx),%edx
  mov    (%rax),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rax
  mov    %rbp,%rdi
  mov    0xc(%rsp),%r8d
  mov    (%rax),%rdx
  mov    (%rcx),%rax
  mov    (%rax),%rax
  mov    (%rdx),%edx
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%r8d
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rdx
  mov    0x10(%rsp),%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: %d	%d	%d	%d


assistant: ```c
main() {
  int x, *p, **q, ***r;
  x = 5;
  p = &x;
  q = &p;
  r = &q;
  printf("%d\t%d\t%d\t%d\n", *r, q, &p, x);
  printf("%d\t%d\t%d\t%d\n", **q, &r, &x, p);
  printf("%d\t%d\t%d\t%d\n", **r, *p, *&q, &q);
  printf("%d\t%d\t%d\t%d\n", ***r, ***&q, *&r, *&x);
  printf("%d\t%d\t%d\t%d\n", p, q, r, x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bmi2_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xce7acc,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L26
L7:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <calc_pext_u32@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_pext_u32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L14
  mov    $0x0,%eax
  call   <abort@plt>
L14:
  addl   $0x1,-0x10(%rbp)
L26:
  cmpl   $0x4,-0x10(%rbp)
  jbe    L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void bmi2_test() {
  unsigned i;
  unsigned src = 0xce7acc;
  unsigned res, res_ref;
  for (i = 0; i < 5; ++i) {
    src = src * (i + 1);
    res_ref = calc_pext_u32(src, ~(i * 3));
    res = _pext_u32(src, ~(i * 3));
    if (res != res_ref)
      abort();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bmi2_test>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xce7acc,%r12d
  mov    $0x0,%ebx
  jmp    L32
L5:
  cmp    $0x5,%ebx
  je     L14
L32:
  add    $0x1,%ebx
  imul   %ebx,%r12d
  lea    0x0(,%rbx,4),%eax
  mov    %ebx,%ebp
  sub    %eax,%ebp
  add    $0x2,%ebp
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <calc_pext_u32@plt>
  mov    %eax,%r13d
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <_pext_u32@plt>
  cmp    %eax,%r13d
  je     L5
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L5
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bmi2_test() {
  unsigned i;
  unsigned src = 0xce7acc;
  unsigned res, res_ref;
  for (i = 0; i < 5; ++i) {
    src = src * (i + 1);
    res_ref = calc_pext_u32(src, ~(i * 3));
    res = _pext_u32(src, ~(i * 3));
    if (res != res_ref)
      abort();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bmi2_test>:
  endbr64
  push   %r13
  push   %r12
  mov    $0xce7acc,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L1:
  add    $0x1,%ebx
  imul   %ebx,%r12d
  lea    0x0(,%rbx,4),%eax
  mov    %ebx,%ebp
  sub    %eax,%ebp
  add    $0x2,%ebp
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <calc_pext_u32@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <_pext_u32@plt>
  cmp    %eax,%r13d
  je     L4
  xor    %eax,%eax
  call   <abort@plt>
L4:
  cmp    $0x5,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bmi2_test() {
  unsigned i;
  unsigned src = 0xce7acc;
  unsigned res, res_ref;
  for (i = 0; i < 5; ++i) {
    src = src * (i + 1);
    res_ref = calc_pext_u32(src, ~(i * 3));
    res = _pext_u32(src, ~(i * 3));
    if (res != res_ref)
      abort();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bmi2_test>:
  endbr64
  push   %r13
  push   %r12
  mov    $0xce7acc,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L14:
  add    $0x1,%ebx
  imul   %ebx,%r12d
  lea    0x0(,%rbx,4),%eax
  mov    %ebx,%ebp
  sub    %eax,%ebp
  add    $0x2,%ebp
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <calc_pext_u32@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <_pext_u32@plt>
  cmp    %eax,%r13d
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  cmp    $0x5,%ebx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bmi2_test() {
  unsigned i;
  unsigned src = 0xce7acc;
  unsigned res, res_ref;
  for (i = 0; i < 5; ++i) {
    src = src * (i + 1);
    res_ref = calc_pext_u32(src, ~(i * 3));
    res = _pext_u32(src, ~(i * 3));
    if (res != res_ref)
      abort();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <get_integer@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <digit_sum@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string
name: extract_symbolic_data
arguments: tag: D21
type_infered: string

tool: D25: Digit sum - another exciting program

tool: D20:    from Furball Enterprises, Inc.


tool: D21: Sum of the digits of %d is %d.


assistant: ```c
main() {
  int x;
  printf("Digit sum - another exciting program\n");
  printf("   from Furball Enterprises, Inc.\n\n");
  x = get_integer();
  printf("Sum of the digits of %d is %d.\n", x, digit_sum(x));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <get_integer@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <digit_sum@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D21
type: string

tool: D1: Digit sum - another exciting program

tool: D0:    from Furball Enterprises, Inc.


tool: D21: Sum of the digits of %d is %d.


assistant: ```c
main() {
  int x;
  printf("Digit sum - another exciting program\n");
  printf("   from Furball Enterprises, Inc.\n\n");
  x = get_integer();
  printf("Sum of the digits of %d is %d.\n", x, digit_sum(x));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <get_integer@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <digit_sum@plt>
  mov    %ebp,%esi
  lea    D23(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string
name: disassemble_data
arguments: tag: D25
type: string
name: disassemble_data
arguments: tag: D23
type: string

tool: D3: Digit sum - another exciting program

tool: D25:    from Furball Enterprises, Inc.


tool: D23: Sum of the digits of %d is %d.


assistant: ```c
main() {
  int x;
  printf("Digit sum - another exciting program\n");
  printf("   from Furball Enterprises, Inc.\n\n");
  x = get_integer();
  printf("Sum of the digits of %d is %d.\n", x, digit_sum(x));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <get_integer@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <digit_sum@plt>
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D22
data_type: string
name: parse_data
arguments: data_tag: D23
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D22: Digit sum - another exciting program

tool: D23:    from Furball Enterprises, Inc.


tool: D11: Sum of the digits of %d is %d.


assistant: ```c
main() {
  int x;
  printf("Digit sum - another exciting program\n");
  printf("   from Furball Enterprises, Inc.\n\n");
  x = get_integer();
  printf("Sum of the digits of %d is %d.\n", x, digit_sum(x));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<distant2_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fst_0@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <fst_0@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <snd_0@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <snd_0@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int distant2_0(struct Tuple2_Int_Int *pointA, struct Tuple2_Int_Int *pointB) {
  int _tmp013;
  int _tmp012;
  _tmp013 = (fst_0(pointA) - fst_0(pointB));
  if (1) {
    int _tmp015;
    int pvar6_dx = _tmp013;
    int _tmp014;
    _tmp015 = (snd_0(pointA) - snd_0(pointB));
    if (1) {
      int pvar7_dy = _tmp015;
      _tmp014 = ((pvar6_dx * pvar6_dx) + (pvar7_dy * pvar7_dy));
    }
    _tmp012 = _tmp014;
  }
  return _tmp012;
}
```
user: Translate the below assembly code into C programming language:

```asm
<distant2_0>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <fst_0@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <fst_0@plt>
  sub    %eax,%ebx
  mov    %rbp,%rdi
  call   <snd_0@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <snd_0@plt>
  mov    %ebp,%edx
  sub    %eax,%edx
  imul   %ebx,%ebx
  imul   %edx,%edx
  lea    (%rbx,%rdx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int distant2_0(struct Tuple2_Int_Int *pointA, struct Tuple2_Int_Int *pointB) {
  int _tmp013;
  int _tmp012;
  _tmp013 = (fst_0(pointA) - fst_0(pointB));
  if (1) {
    int _tmp015;
    int pvar6_dx = _tmp013;
    int _tmp014;
    _tmp015 = (snd_0(pointA) - snd_0(pointB));
    if (1) {
      int pvar7_dy = _tmp015;
      _tmp014 = ((pvar6_dx * pvar6_dx) + (pvar7_dy * pvar7_dy));
    }
    _tmp012 = _tmp014;
  }
  return _tmp012;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<distant2_0>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <fst_0@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <fst_0@plt>
  mov    %rbp,%rdi
  sub    %eax,%ebx
  call   <snd_0@plt>
  mov    %r12,%rdi
  imul   %ebx,%ebx
  mov    %eax,%ebp
  call   <snd_0@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  sub    %r8d,%eax
  imul   %eax,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int distant2_0(struct Tuple2_Int_Int *pointA, struct Tuple2_Int_Int *pointB) {
  int _tmp013;
  int _tmp012;
  _tmp013 = (fst_0(pointA) - fst_0(pointB));
  if (1) {
    int _tmp015;
    int pvar6_dx = _tmp013;
    int _tmp014;
    _tmp015 = (snd_0(pointA) - snd_0(pointB));
    if (1) {
      int pvar7_dy = _tmp015;
      _tmp014 = ((pvar6_dx * pvar6_dx) + (pvar7_dy * pvar7_dy));
    }
    _tmp012 = _tmp014;
  }
  return _tmp012;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<distant2_0>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <fst_0@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <fst_0@plt>
  mov    %rbp,%rdi
  sub    %eax,%ebx
  call   <snd_0@plt>
  mov    %r12,%rdi
  imul   %ebx,%ebx
  mov    %eax,%ebp
  call   <snd_0@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  sub    %r8d,%eax
  imul   %eax,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int distant2_0(struct Tuple2_Int_Int *pointA, struct Tuple2_Int_Int *pointB) {
  int _tmp013;
  int _tmp012;
  _tmp013 = (fst_0(pointA) - fst_0(pointB));
  if (1) {
    int _tmp015;
    int pvar6_dx = _tmp013;
    int _tmp014;
    _tmp015 = (snd_0(pointA) - snd_0(pointB));
    if (1) {
      int pvar7_dy = _tmp015;
      _tmp014 = ((pvar6_dx * pvar6_dx) + (pvar7_dy * pvar7_dy));
    }
    _tmp012 = _tmp014;
  }
  return _tmp012;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L14
  cmpl   $0x7a,-0x4(%rbp)
  jg     L14
  subl   $0x20,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int toupper(int c) {
  if (c >= 'a' && c <= 'z')
    c -= 0x20;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<toupper>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%ecx
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int c) {
  if (c >= 'a' && c <= 'z')
    c -= 0x20;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int c) {
  if (c >= 'a' && c <= 'z')
    c -= 0x20;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int c) {
  if (c >= 'a' && c <= 'z')
    c -= 0x20;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isNumberPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L21
L23:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  test   %rax,%rax
  jne    L37
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L37:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L23
L1:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int isNumberPrime(long numberToCheck) {
  long denominator = 2;
  int retVal = 1;
  while (denominator < numberToCheck) {
    if (0 == (numberToCheck / denominator)) {
      retVal = 0;
      break;
    }
    denominator++;
  }
  return retVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isNumberPrime>:
  endbr64
  mov    $0x2,%ecx
  cmp    $0x2,%rdi
  jle    L12
L4:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  je     L19
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rax,%rax
  jne    L4
  mov    $0x0,%eax
  ret
L12:
  mov    $0x1,%eax
  ret
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isNumberPrime(long numberToCheck) {
  long denominator = 2;
  int retVal = 1;
  while (denominator < numberToCheck) {
    if (0 == (numberToCheck / denominator)) {
      retVal = 0;
      break;
    }
    denominator++;
  }
  return retVal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isNumberPrime>:
  endbr64
  mov    $0x2,%ecx
  cmp    $0x2,%rdi
  jg     L35
  jmp    L27
  nopl   0x0(%rax)
L22:
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rax,%rax
  je     L15
L35:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L22
L27:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isNumberPrime(long numberToCheck) {
  long denominator = 2;
  int retVal = 1;
  while (denominator < numberToCheck) {
    if (0 == (numberToCheck / denominator)) {
      retVal = 0;
      break;
    }
    denominator++;
  }
  return retVal;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isNumberPrime>:
  endbr64
  mov    $0x2,%ecx
  cmp    $0x2,%rdi
  jg     L14
  jmp    L31
  nopl   0x0(%rax)
L13:
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rax,%rax
  je     L22
L14:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L13
L31:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isNumberPrime(long numberToCheck) {
  long denominator = 2;
  int retVal = 1;
  while (denominator < numberToCheck) {
    if (0 == (numberToCheck / denominator)) {
      retVal = 0;
      break;
    }
    denominator++;
  }
  return retVal;
}
```