user: 这段汇编代码用C语言表示是什么样的？

```asm
<hamming>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  movsd  %xmm0,-0x70(%rbp)
  mov    -0x68(%rbp),%rax
  fldt   (%rax)
  movsd  -0x70(%rbp),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x78(%rbp)
  fldl   -0x78(%rbp)
  fldt   0x10(%rbp)
  fsubp  %st,%st(1)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <f@plt>
  add    $0x20,%rsp
  fstpt  -0x60(%rbp)
  mov    -0x68(%rbp),%rax
  add    $0x10,%rax
  fldt   (%rax)
  movsd  -0x70(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,-0x78(%rbp)
  fldl   -0x78(%rbp)
  fldt   0x10(%rbp)
  fsubp  %st,%st(1)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <f@plt>
  add    $0x20,%rsp
  fstpt  -0x50(%rbp)
  mov    -0x68(%rbp),%rax
  add    $0x20,%rax
  fldt   (%rax)
  fldl   -0x70(%rbp)
  fldt   0x10(%rbp)
  fsubp  %st,%st(1)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <f@plt>
  add    $0x20,%rsp
  fstpt  -0x40(%rbp)
  mov    -0x68(%rbp),%rax
  add    $0x30,%rax
  fldt   (%rax)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <f@plt>
  add    $0x20,%rsp
  fstpt  -0x30(%rbp)
  mov    -0x68(%rbp),%rax
  fldt   (%rax)
  movsd  -0x70(%rbp),%xmm1
  movsd  D33(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D12(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x78(%rbp)
  fldl   -0x78(%rbp)
  fldt   -0x30(%rbp)
  fld    %st(0)
  faddp  %st,%st(1)
  fldt   -0x40(%rbp)
  fsubrp %st,%st(1)
  fldt   -0x50(%rbp)
  fadd   %st(0),%st
  faddp  %st,%st(1)
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  fstpt  -0x20(%rbp)
  fldl   -0x70(%rbp)
  fldt   0x10(%rbp)
  faddp  %st,%st(1)
  push   -0x18(%rbp)
  push   -0x20(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <f@plt>
  add    $0x20,%rsp
  fstpt  -0x10(%rbp)
  mov    -0x68(%rbp),%rax
  add    $0x30,%rax
  fldt   (%rax)
  fldt   0xd97(%rip)        # 2010 <_fini+0xd3c>
  fmulp  %st,%st(1)
  mov    -0x68(%rbp),%rax
  add    $0x10,%rax
  fldt   (%rax)
  fsubrp %st,%st(1)
  fldt   0xd93(%rip)        # 2020 <_fini+0xd4c>
  fmulp  %st,%st(1)
  movsd  -0x70(%rbp),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D21(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x78(%rbp)
  fldl   -0x78(%rbp)
  fldt   -0x30(%rbp)
  fld    %st(0)
  faddp  %st,%st(1)
  fldt   -0x10(%rbp)
  faddp  %st,%st(1)
  fldt   -0x40(%rbp)
  fsubrp %st,%st(1)
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  fstpt  -0x20(%rbp)
  fldt   -0x20(%rbp)
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type_infered: f64
name: retrieve_data
arguments: label: D33
type_infered: f64
name: retrieve_data
arguments: label: D21
type_infered: f64

tool: D12: 3

tool: D33: 4

tool: D21: 8

assistant: ```c
long double hamming(long double x, long double y[], double h) {
  long double f0, f1, f2, f3, f4;
  long double yp;
  f0 = f(x - 3.0 * h, y[0]);
  f1 = f(x - 2.0 * h, y[1]);
  f2 = f(x - 1.0 * h, y[2]);
  f3 = f(x, y[3]);
  yp = y[0] + ((4.0 * h) / 3.0) * (2.0 * f3 - f2 + 2.0 * f1);
  f4 = f(x + h, yp);
  yp = (1.0 / 8.0) * (9 * y[3] - y[1]) + ((3.0 * h) / 8.0) * (f4 + 2 * f3 - f2);
  return yp;
}
```