ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ScDisplayErr>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  mov    %r15d,%edx
  push   %r13
  mov    %rsi,%r13
  mov    %r14d,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <getyx@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <wmove@plt>
  mov    %rbp,%rdi
  call   <wrefresh@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    $0x3,%edi
  lea    0x2(%rax),%esi
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  sub    %esi,%eax
  sub    $0x2,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    D0(%rip),%rax
  sar    %ecx
  mov    (%rax),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  sub    $0x2,%edx
  call   <newwin@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <box@plt>
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    $0x1,%esi
  call   <mvwaddstr@plt>
  mov    %r12,%rdi
  call   <wrefresh@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %r12,%rdi
  call   <delwin@plt>
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <wmove@plt>
  mov    %rbp,%rdi
  call   <touchwin@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1110 <wrefresh@plt>
```

assistant: ```c
void ScDisplayErr(WINDOW *back_win, char *str) {
  int old_y, old_x, win_len;
  WINDOW *err_win;
  getyx(back_win, old_y, old_x);
  wmove(back_win, 0, 0);
  wrefresh(back_win);
  win_len = strlen(str) + 2;
  err_win = newwin(3, win_len, LINES / 2 - 2, (COLS - win_len - 2) / 2);
  box(err_win, 0, 0);
  mvwaddstr(err_win, 1, 1, str);
  wrefresh(err_win);
  sleep(3);
  delwin(err_win);
  wmove(back_win, old_y, old_x);
  touchwin(back_win);
  wrefresh(back_win);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ScDisplayErr>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  mov    %r15d,%edx
  push   %r13
  mov    %rsi,%r13
  mov    %r14d,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <getyx@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <wmove@plt>
  mov    %rbp,%rdi
  call   <wrefresh@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    $0x3,%edi
  lea    0x2(%rax),%esi
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  sub    %esi,%eax
  sub    $0x2,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  mov    D10(%rip),%rax
  sar    %ecx
  mov    (%rax),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  sub    $0x2,%edx
  call   <newwin@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <box@plt>
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    $0x1,%esi
  call   <mvwaddstr@plt>
  mov    %r12,%rdi
  call   <wrefresh@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %r12,%rdi
  call   <delwin@plt>
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <wmove@plt>
  mov    %rbp,%rdi
  call   <touchwin@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1110 <wrefresh@plt>
```

assistant: ```c
void ScDisplayErr(WINDOW *back_win, char *str) {
  int old_y, old_x, win_len;
  WINDOW *err_win;
  getyx(back_win, old_y, old_x);
  wmove(back_win, 0, 0);
  wrefresh(back_win);
  win_len = strlen(str) + 2;
  err_win = newwin(3, win_len, LINES / 2 - 2, (COLS - win_len - 2) / 2);
  box(err_win, 0, 0);
  mvwaddstr(err_win, 1, 1, str);
  wrefresh(err_win);
  sleep(3);
  delwin(err_win);
  wmove(back_win, old_y, old_x);
  touchwin(back_win);
  wrefresh(back_win);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_clone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  jne    L1
  mov    $0xba,%edi
  call   <fail_test@plt>
L1:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  jne    L6
  mov    $0xbd,%edi
  call   <fail_test@plt>
L6:
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D11
type: string

tool: D7: empty_r1

tool: D11: storage_r1

assistant: ```c
void test_clone() {
  if (!equal_clone("empty_r1"))
    fail_test(186);
  ;
  if (!equal_clone("storage_r1"))
    fail_test(189);
  ;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_clone>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  je     L16
L33:
  lea    D3(%rip),%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  je     L23
L21:
  add    $0x8,%rsp
  ret
L16:
  mov    $0xba,%edi
  call   <fail_test@plt>
  jmp    L33
L23:
  mov    $0xbd,%edi
  call   <fail_test@plt>
  jmp    L21
```

tool_calls: name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string

tool: D10: empty_r1

tool: D3: storage_r1

assistant: ```c
void test_clone() {
  if (!equal_clone("empty_r1"))
    fail_test(186);
  ;
  if (!equal_clone("storage_r1"))
    fail_test(189);
  ;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_clone>:
  endbr64
  sub    $0x8,%rsp
  lea    D29(%rip),%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  je     L8
  lea    D15(%rip),%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  je     L20
L16:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L8:
  mov    $0xba,%edi
  call   <fail_test@plt>
  lea    D15(%rip),%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  jne    L16
L20:
  mov    $0xbd,%edi
  add    $0x8,%rsp
  jmp    1070 <fail_test@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string

tool: D29: empty_r1

tool: D15: storage_r1

assistant: ```c
void test_clone() {
  if (!equal_clone("empty_r1"))
    fail_test(186);
  ;
  if (!equal_clone("storage_r1"))
    fail_test(189);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_clone>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  je     L21
  lea    D19(%rip),%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  je     L24
L8:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L21:
  mov    $0xba,%edi
  call   <fail_test@plt>
  lea    D19(%rip),%rdi
  call   <equal_clone@plt>
  test   %eax,%eax
  jne    L8
L24:
  mov    $0xbd,%edi
  add    $0x8,%rsp
  jmp    1070 <fail_test@plt>
```

tool_calls: name: parse_data
arguments: label: D22
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string

tool: D22: empty_r1

tool: D19: storage_r1

assistant: ```c
void test_clone() {
  if (!equal_clone("empty_r1"))
    fail_test(186);
  ;
  if (!equal_clone("storage_r1"))
    fail_test(189);
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L36
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L52
L36:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <readInput@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L52
L15:
  cmpl   $0x2,-0x4(%rbp)
  jne    L3
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L52
L3:
  mov    $0x0,%eax
  call   <walk@plt>
  mov    $0x0,%eax
L52:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string

tool: D9: USAGE: ./a.out <INPUT.txt>


tool: D15: NO

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("USAGE: ./a.out <INPUT.txt>\n");
    return 0;
  }
  int eCheck = readInput(argv[1]);
  if (eCheck == 1)
    return 1;
  else if (eCheck == 2) {
    printf("NO");
    return 1;
  } else {
    walk();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L43
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L5:
  add    $0x8,%rsp
  ret
L43:
  mov    0x8(%rsi),%rdi
  call   <readInput@plt>
  cmp    $0x1,%eax
  je     L5
  cmp    $0x2,%eax
  je     L28
  mov    $0x0,%eax
  call   <walk@plt>
  mov    $0x0,%eax
  jmp    L5
L28:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L5
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D11
type: string

tool: D4: USAGE: ./a.out <INPUT.txt>


tool: D11: NO

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("USAGE: ./a.out <INPUT.txt>\n");
    return 0;
  }
  int eCheck = readInput(argv[1]);
  if (eCheck == 1)
    return 1;
  else if (eCheck == 2) {
    printf("NO");
    return 1;
  } else {
    walk();
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L35
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L25:
  add    $0x8,%rsp
  ret
L35:
  mov    0x8(%rsi),%rdi
  call   <readInput@plt>
  cmp    $0x1,%eax
  je     L25
  cmp    $0x2,%eax
  je     L39
  xor    %eax,%eax
  call   <walk@plt>
  xor    %eax,%eax
  jmp    L25
L39:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L25
```

tool_calls: name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string

tool: D18: USAGE: ./a.out <INPUT.txt>


tool: D15: NO

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("USAGE: ./a.out <INPUT.txt>\n");
    return 0;
  }
  int eCheck = readInput(argv[1]);
  if (eCheck == 1)
    return 1;
  else if (eCheck == 2) {
    printf("NO");
    return 1;
  } else {
    walk();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L38
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L42:
  add    $0x8,%rsp
  ret
L38:
  mov    0x8(%rsi),%rdi
  call   <readInput@plt>
  cmp    $0x1,%eax
  je     L42
  cmp    $0x2,%eax
  je     L24
  xor    %eax,%eax
  call   <walk@plt>
  xor    %eax,%eax
  jmp    L42
L24:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L42
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D1
type: string

tool: D0: USAGE: ./a.out <INPUT.txt>


tool: D1: NO

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("USAGE: ./a.out <INPUT.txt>\n");
    return 0;
  }
  int eCheck = readInput(argv[1]);
  if (eCheck == 1)
    return 1;
  else if (eCheck == 2) {
    printf("NO");
    return 1;
  } else {
    walk();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GetSalt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L14
L19:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L21
  addl   $0x1,-0x8(%rbp)
L21:
  cmpl   $0x0,-0x8(%rbp)
  jle    L7
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    D21(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
  addl   $0x1,-0xc(%rbp)
  cmpl   $0x3,-0x8(%rbp)
  je     L25
L7:
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L19
  jmp    L6
L25:
  nop
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    D21(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D21(%rip),%rax
  leave
  ret
```

assistant: ```c
char *GetSalt(const char *line) {
  static char salt[15];
  int len = strlen(line);
  int i, j, dolar;
  i = j = dolar = 0;
  while (i < len) {
    if (line[i] == '$')
      dolar++;
    if (dolar > 0) {
      salt[j] = line[i];
      j++;
      if (dolar == 3)
        break;
    }
    i++;
  }
  salt[j] = '\0';
  return (salt);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GetSalt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L52
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%r8
  mov    $0x0,%eax
  mov    $0x0,%esi
  lea    D19(%rip),%r9
  jmp    L59
L21:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L17
L59:
  movzbl (%rdx),%ecx
  cmp    $0x24,%cl
  sete   %dil
  movzbl %dil,%edi
  add    %edi,%eax
  test   %eax,%eax
  jle    L21
  movslq %esi,%rdi
  mov    %cl,(%r9,%rdi,1)
  add    $0x1,%esi
  cmp    $0x3,%eax
  jne    L21
L17:
  lea    D19(%rip),%rax
  movslq %esi,%rsi
  movb   $0x0,(%rax,%rsi,1)
  pop    %rbx
  ret
L52:
  mov    $0x0,%esi
  jmp    L17
```

assistant: ```c
char *GetSalt(const char *line) {
  static char salt[15];
  int len = strlen(line);
  int i, j, dolar;
  i = j = dolar = 0;
  while (i < len) {
    if (line[i] == '$')
      dolar++;
    if (dolar > 0) {
      salt[j] = line[i];
      j++;
      if (dolar == 3)
        break;
    }
    i++;
  }
  salt[j] = '\0';
  return (salt);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GetSalt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L66
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbx,%rax,1),%r8
  lea    D7(%rip),%r9
  jmp    L50
  nopl   0x0(%rax)
L8:
  test   %ecx,%ecx
  jne    L11
L44:
  add    $0x1,%rdi
  cmp    %r8,%rdi
  je     L47
L50:
  movzbl (%rdi),%eax
  cmp    $0x24,%al
  jne    L8
  add    $0x1,%ecx
L11:
  movslq %edx,%rsi
  add    $0x1,%edx
  mov    %al,(%r9,%rsi,1)
  cmp    $0x3,%ecx
  jne    L44
L47:
  movslq %edx,%rdx
  mov    %r9,%rax
  movb   $0x0,(%r9,%rdx,1)
  pop    %rbx
  ret
L66:
  xor    %edx,%edx
  lea    D7(%rip),%r9
  jmp    L47
```

assistant: ```c
char *GetSalt(const char *line) {
  static char salt[15];
  int len = strlen(line);
  int i, j, dolar;
  i = j = dolar = 0;
  while (i < len) {
    if (line[i] == '$')
      dolar++;
    if (dolar > 0) {
      salt[j] = line[i];
      j++;
      if (dolar == 3)
        break;
    }
    i++;
  }
  salt[j] = '\0';
  return (salt);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GetSalt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L66
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbx,%rax,1),%r8
  lea    D16(%rip),%r9
  jmp    L35
  nopl   0x0(%rax)
L53:
  test   %ecx,%ecx
  jne    L55
L67:
  add    $0x1,%rdi
  cmp    %r8,%rdi
  je     L32
L35:
  movzbl (%rdi),%eax
  cmp    $0x24,%al
  jne    L53
  add    $0x1,%ecx
L55:
  movslq %edx,%rsi
  add    $0x1,%edx
  mov    %al,(%r9,%rsi,1)
  cmp    $0x3,%ecx
  jne    L67
L32:
  movslq %edx,%rdx
  mov    %r9,%rax
  movb   $0x0,(%r9,%rdx,1)
  pop    %rbx
  ret
L66:
  xor    %edx,%edx
  lea    D16(%rip),%r9
  jmp    L32
```

assistant: ```c
char *GetSalt(const char *line) {
  static char salt[15];
  int len = strlen(line);
  int i, j, dolar;
  i = j = dolar = 0;
  while (i < len) {
    if (line[i] == '$')
      dolar++;
    if (dolar > 0) {
      salt[j] = line[i];
      j++;
      if (dolar == 3)
        break;
    }
    i++;
  }
  salt[j] = '\0';
  return (salt);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0x14(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    $0x802,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D59
type_guessed: string
name: unpack_data
arguments: data_label: D38
type_guessed: string
name: unpack_data
arguments: data_label: D46
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string
name: unpack_data
arguments: data_label: D62
type_guessed: string
name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D59: Data de nascimento: 

tool: D38: %d

tool: D46: Ano atual: 

tool: D6: Sua idade eh: %d


tool: D62: Sua idade em 2050: %d


tool: D9: pause

assistant: ```c
int main() {
  int data, anoAtual, idade;
  printf("Data de nascimento: ");
  scanf("%d", &data);
  printf("Ano atual: ");
  scanf("%d", &anoAtual);
  idade = anoAtual - data;
  printf("Sua idade eh: %d\n", idade);
  idade = 2050 - data;
  printf("Sua idade em 2050: %d\n", idade);
  system("pause");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D51(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  sub    (%rsp),%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x802,%esi
  sub    (%rsp),%esi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D51
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D0
datatype: string
name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D33
datatype: string
name: unpack_data
arguments: tag: D50
datatype: string

tool: D51: Data de nascimento: 

tool: D7: %d

tool: D0: Ano atual: 

tool: D15: Sua idade eh: %d


tool: D33: Sua idade em 2050: %d


tool: D50: pause

assistant: ```c
int main() {
  int data, anoAtual, idade;
  printf("Data de nascimento: ");
  scanf("%d", &data);
  printf("Ano atual: ");
  scanf("%d", &anoAtual);
  idade = anoAtual - data;
  printf("Sua idade eh: %d\n", idade);
  idade = 2050 - data;
  printf("Sua idade em 2050: %d\n", idade);
  system("pause");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D56(%rip),%rdi
  lea    D42(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  sub    (%rsp),%esi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  mov    $0x802,%esi
  sub    (%rsp),%esi
  call   <printf@plt>
  lea    D55(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D56
datatype: string
name: read_data
arguments: tag: D42
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D35
datatype: string
name: read_data
arguments: tag: D38
datatype: string
name: read_data
arguments: tag: D55
datatype: string

tool: D56: Data de nascimento: 

tool: D42: %d

tool: D24: Ano atual: 

tool: D35: Sua idade eh: %d


tool: D38: Sua idade em 2050: %d


tool: D55: pause

assistant: ```c
int main() {
  int data, anoAtual, idade;
  printf("Data de nascimento: ");
  scanf("%d", &data);
  printf("Ano atual: ");
  scanf("%d", &anoAtual);
  idade = anoAtual - data;
  printf("Sua idade eh: %d\n", idade);
  idade = 2050 - data;
  printf("Sua idade em 2050: %d\n", idade);
  system("pause");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D31(%rip),%rdi
  lea    D16(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  sub    (%rsp),%esi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  mov    $0x802,%esi
  sub    (%rsp),%esi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D54
datatype: string
name: retrieve_data
arguments: data_tag: D59
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string
name: retrieve_data
arguments: data_tag: D27
datatype: string

tool: D31: Data de nascimento: 

tool: D16: %d

tool: D54: Ano atual: 

tool: D59: Sua idade eh: %d


tool: D22: Sua idade em 2050: %d


tool: D27: pause

assistant: ```c
int main() {
  int data, anoAtual, idade;
  printf("Data de nascimento: ");
  scanf("%d", &data);
  printf("Ano atual: ");
  scanf("%d", &anoAtual);
  idade = anoAtual - data;
  printf("Sua idade eh: %d\n", idade);
  idade = 2050 - data;
  printf("Sua idade em 2050: %d\n", idade);
  system("pause");
}
```