ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_dot_input>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rcx,%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  lea    D10(%rip),%rsi
  call   <fprintf@plt>
  test   %ebx,%ebx
  jle    L3
  xor    %r15d,%r15d
  movslq %ebx,%r12
  lea    D3(%rip),%r14
L23:
  xor    %ebx,%ebx
  jmp    L54
  nopl   0x0(%rax)
L38:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L25
L54:
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  mov    %ebx,%ecx
  jne    L38
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L54
L25:
  add    $0x1,%r15d
  add    $0xfa0,%rbp
  cmp    %r15d,0xc(%rsp)
  jne    L23
L3:
  add    $0x18,%rsp
  mov    %r13,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <fwrite@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D3
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string

tool: D10: digraph %s {


tool: D3: %d -> %d


tool: D0: }


assistant: ```c
void print_dot_input(int cfg[][1000], int no_of_vertices, const char *name, FILE *fp) {
  int i, j;
  fprintf(fp, "digraph %s {\n", name);
  for (i = 0; i < no_of_vertices; i++)
    for (j = 0; j < no_of_vertices; j++)
      if (cfg[i][j] == 1)
        fprintf(fp, "%d -> %d\n", i, j);
  fprintf(fp, "}\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_dot_input>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rcx,%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  lea    D20(%rip),%rsi
  call   <fprintf@plt>
  test   %ebx,%ebx
  jle    L11
  xor    %r15d,%r15d
  movslq %ebx,%r12
  lea    D2(%rip),%r14
L38:
  xor    %ebx,%ebx
  jmp    L58
  nopl   0x0(%rax)
L37:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L15
L58:
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  mov    %ebx,%ecx
  jne    L37
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L58
L15:
  add    $0x1,%r15d
  add    $0xfa0,%rbp
  cmp    %r15d,0xc(%rsp)
  jne    L38
L11:
  add    $0x18,%rsp
  mov    %r13,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D14(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <fwrite@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D2
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string

tool: D20: digraph %s {


tool: D2: %d -> %d


tool: D14: }


assistant: ```c
void print_dot_input(int cfg[][1000], int no_of_vertices, const char *name, FILE *fp) {
  int i, j;
  fprintf(fp, "digraph %s {\n", name);
  for (i = 0; i < no_of_vertices; i++)
    for (j = 0; j < no_of_vertices; j++)
      if (cfg[i][j] == 1)
        fprintf(fp, "%d -> %d\n", i, j);
  fprintf(fp, "}\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<globals_to_regex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x48(%rbp)
  jmp    L59
L54:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <global_to_regex@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x38(%rbp),%rdx
  add    %rdx,%rax
  add    $0x3,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L31
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L58
  lea    D22(%rip),%rax
  jmp    L13
L58:
  lea    D16(%rip),%rax
L13:
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  call   <sprintf@plt>
  add    %rax,-0x38(%rbp)
L31:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L59:
  lea    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <split_and_get@plt>
  mov    %rax,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L54
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x40(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string
name: extract_symbolic_data
arguments: tag: D11
data_type: string

tool: D22: |

tool: 

tool: D11: %s(%s)

assistant: ```c
char *globals_to_regex(const char globals[]) {
  char *final_regex = NULL;
  size_t final_regex_len = 0UL;
  char *globals_copy = strdup(globals);
  char *global = globals_copy, *state = NULL;
  while ((global = split_and_get(global, ',', &state)) != NULL) {
    void *p;
    char *regex;
    size_t new_len;
    regex = global_to_regex(global);
    new_len = final_regex_len + 1 + 1 + strlen(regex) + 1;
    p = realloc(final_regex, new_len + 1);
    if (p != NULL) {
      final_regex = p;
      final_regex_len += sprintf(final_regex + final_regex_len, "%s(%s)", (final_regex_len != 0UL) ? "|" : "", regex);
    }
    free(regex);
  }
  free(globals_copy);
  return final_regex;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<globals_to_regex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rax,%rbx
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  lea    0x10(%rsp),%r15
  jmp    L3
L17:
  test   %r13,%r13
  lea    D14(%rip),%rdx
  lea    D6(%rip),%rax
  cmovne %rax,%rdx
  lea    (%r12,%r13,1),%rdi
  mov    %rbp,%rcx
  lea    D17(%rip),%rsi
  call   <sprintf@plt>
  add    %rax,%r13
  mov    %r12,%r14
L8:
  mov    %rbp,%rdi
  call   <free@plt>
L3:
  mov    %r15,%rdx
  mov    $0x2c,%esi
  mov    %rbx,%rdi
  call   <split_and_get@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %rbx,%rdi
  call   <global_to_regex@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x4(%r13,%rax,1),%rsi
  mov    %r14,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L17
  jmp    L8
L2:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    %r14,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string

tool: 

tool: D6: |

tool: D17: %s(%s)

assistant: ```c
char *globals_to_regex(const char globals[]) {
  char *final_regex = NULL;
  size_t final_regex_len = 0UL;
  char *globals_copy = strdup(globals);
  char *global = globals_copy, *state = NULL;
  while ((global = split_and_get(global, ',', &state)) != NULL) {
    void *p;
    char *regex;
    size_t new_len;
    regex = global_to_regex(global);
    new_len = final_regex_len + 1 + 1 + strlen(regex) + 1;
    p = realloc(final_regex, new_len + 1);
    if (p != NULL) {
      final_regex = p;
      final_regex_len += sprintf(final_regex + final_regex_len, "%s(%s)", (final_regex_len != 0UL) ? "|" : "", regex);
    }
    free(regex);
  }
  free(globals_copy);
  return final_regex;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<globals_to_regex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <strdup@plt>
  movq   $0x0,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rax,%r14
  jmp    L28
  nopl   0x0(%rax)
L3:
  mov    %r14,%rdi
  call   <global_to_regex@plt>
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %r12,%rdi
  lea    0x4(%rbx,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L37
  test   %rbx,%rbx
  lea    D2(%rip),%rax
  mov    %r15,%rcx
  mov    %r13,%r12
  lea    D11(%rip),%rdx
  lea    0x0(%r13,%rbx,1),%rdi
  cmovne %rax,%rdx
  lea    D16(%rip),%rsi
  call   <sprintf@plt>
  add    %rax,%rbx
L37:
  mov    %r15,%rdi
  call   <free@plt>
L28:
  mov    %r14,%rdi
  mov    %rbp,%rdx
  mov    $0x2c,%esi
  call   <split_and_get@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L3
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D11
datatype: string
name: parse_data
arguments: data_tag: D16
datatype: string

tool: D2: |

tool: 

tool: D16: %s(%s)

assistant: ```c
char *globals_to_regex(const char globals[]) {
  char *final_regex = NULL;
  size_t final_regex_len = 0UL;
  char *globals_copy = strdup(globals);
  char *global = globals_copy, *state = NULL;
  while ((global = split_and_get(global, ',', &state)) != NULL) {
    void *p;
    char *regex;
    size_t new_len;
    regex = global_to_regex(global);
    new_len = final_regex_len + 1 + 1 + strlen(regex) + 1;
    p = realloc(final_regex, new_len + 1);
    if (p != NULL) {
      final_regex = p;
      final_regex_len += sprintf(final_regex + final_regex_len, "%s(%s)", (final_regex_len != 0UL) ? "|" : "", regex);
    }
    free(regex);
  }
  free(globals_copy);
  return final_regex;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<globals_to_regex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <strdup@plt>
  movq   $0x0,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rax,%r14
  jmp    L5
  nopl   0x0(%rax)
L24:
  mov    %r14,%rdi
  call   <global_to_regex@plt>
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %r12,%rdi
  lea    0x4(%rbx,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L12
  test   %rbx,%rbx
  lea    D6(%rip),%rax
  mov    %r15,%rcx
  mov    %r13,%r12
  lea    D8(%rip),%rdx
  lea    0x0(%r13,%rbx,1),%rdi
  cmovne %rax,%rdx
  lea    D17(%rip),%rsi
  call   <sprintf@plt>
  add    %rax,%rbx
L12:
  mov    %r15,%rdi
  call   <free@plt>
L5:
  mov    %r14,%rdi
  mov    %rbp,%rdx
  mov    $0x2c,%esi
  call   <split_and_get@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L24
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D8
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string

tool: D6: |

tool: 

tool: D17: %s(%s)

assistant: ```c
char *globals_to_regex(const char globals[]) {
  char *final_regex = NULL;
  size_t final_regex_len = 0UL;
  char *globals_copy = strdup(globals);
  char *global = globals_copy, *state = NULL;
  while ((global = split_and_get(global, ',', &state)) != NULL) {
    void *p;
    char *regex;
    size_t new_len;
    regex = global_to_regex(global);
    new_len = final_regex_len + 1 + 1 + strlen(regex) + 1;
    p = realloc(final_regex, new_len + 1);
    if (p != NULL) {
      final_regex = p;
      final_regex_len += sprintf(final_regex + final_regex_len, "%s(%s)", (final_regex_len != 0UL) ? "|" : "", regex);
    }
    free(regex);
  }
  free(globals_copy);
  return final_regex;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<amsp_linear_solve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <solveHelper@plt>
  test   %rax,%rax
  je     L26
  mov    $0xffffffff,%eax
  jmp    L4
L26:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L0
L3:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L3
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movsd  (%rax),%xmm1
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
int amsp_linear_solve(double **eqs, int nEq, int nCf, double *sol, int *nSol) {
  double nt;
  int i;
  *nSol = 0;
  if (solveHelper(eqs, nEq, nCf, sol, nSol) != 0)
    return -1;
  nt = eqs[0][nCf - 1];
  for (i = 1; i < nCf - 1; ++i)
    nt -= eqs[0][i] * sol[*nSol - i];
  sol[*nSol] = nt / eqs[0][0];
  *nSol += 1;
  reverse(sol, *nSol);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<amsp_linear_solve>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %edx,%r12d
  mov    %rcx,%rbp
  mov    %r8,%rbx
  movl   $0x0,(%r8)
  call   <solveHelper@plt>
  test   %rax,%rax
  jne    L1
  mov    0x0(%r13),%rsi
  movslq %r12d,%rax
  movsd  -0x8(%rsi,%rax,8),%xmm1
  cmp    $0x2,%r12d
  jle    L25
  lea    0x8(%rsi),%rax
  movslq (%rbx),%rdx
  lea    0x0(%rbp,%rdx,8),%rdx
  lea    -0x3(%r12),%ecx
  lea    0x10(%rsi,%rcx,8),%rcx
L31:
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rdx),%xmm0
  subsd  %xmm0,%xmm1
  add    $0x8,%rax
  sub    $0x8,%rdx
  cmp    %rcx,%rax
  jne    L31
L25:
  movslq (%rbx),%rax
  divsd  (%rsi),%xmm1
  movsd  %xmm1,0x0(%rbp,%rax,8)
  mov    (%rbx),%eax
  lea    0x1(%rax),%esi
  mov    %esi,(%rbx)
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    $0x0,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int amsp_linear_solve(double **eqs, int nEq, int nCf, double *sol, int *nSol) {
  double nt;
  int i;
  *nSol = 0;
  if (solveHelper(eqs, nEq, nCf, sol, nSol) != 0)
    return -1;
  nt = eqs[0][nCf - 1];
  for (i = 1; i < nCf - 1; ++i)
    nt -= eqs[0][i] * sol[*nSol - i];
  sol[*nSol] = nt / eqs[0][0];
  *nSol += 1;
  reverse(sol, *nSol);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<amsp_linear_solve>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  movl   $0x0,(%r8)
  call   <solveHelper@plt>
  test   %rax,%rax
  jne    L0
  mov    0x0(%r13),%rdi
  mov    (%rbx),%esi
  movslq %r12d,%rax
  movsd  -0x8(%rdi,%rax,8),%xmm1
  movslq %esi,%r8
  cmp    $0x2,%r12d
  jle    L20
  movslq %esi,%r8
  lea    -0x3(%r12),%ecx
  lea    0x8(%rdi),%rax
  lea    0x0(%rbp,%r8,8),%rdx
  lea    0x10(%rdi,%rcx,8),%rcx
  nopl   0x0(%rax)
L13:
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rdx),%xmm0
  add    $0x8,%rax
  sub    $0x8,%rdx
  subsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L13
L20:
  add    $0x1,%esi
  divsd  (%rdi),%xmm1
  movsd  %xmm1,0x0(%rbp,%r8,8)
  mov    %rbp,%rdi
  mov    %esi,(%rbx)
  call   <reverse@plt>
  xor    %eax,%eax
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L33
```

assistant: ```c
int amsp_linear_solve(double **eqs, int nEq, int nCf, double *sol, int *nSol) {
  double nt;
  int i;
  *nSol = 0;
  if (solveHelper(eqs, nEq, nCf, sol, nSol) != 0)
    return -1;
  nt = eqs[0][nCf - 1];
  for (i = 1; i < nCf - 1; ++i)
    nt -= eqs[0][i] * sol[*nSol - i];
  sol[*nSol] = nt / eqs[0][0];
  *nSol += 1;
  reverse(sol, *nSol);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<amsp_linear_solve>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  movl   $0x0,(%r8)
  call   <solveHelper@plt>
  test   %rax,%rax
  jne    L26
  mov    0x0(%r13),%rcx
  mov    (%rbx),%esi
  movslq %r12d,%rax
  movsd  -0x8(%rcx,%rax,8),%xmm0
  movslq %esi,%rdi
  cmp    $0x2,%r12d
  jle    L39
  lea    -0x2(%r12),%r9d
  cmp    $0x3,%r12d
  je     L55
  mov    %r9d,%r8d
  movslq %esi,%rdi
  lea    0x8(%rcx),%rax
  shr    %r8d
  lea    -0x10(%rbp,%rdi,8),%rdx
  sub    $0x1,%r8d
  shl    $0x4,%r8
  lea    0x18(%rcx,%r8,1),%r8
  nopl   (%rax)
L15:
  movupd (%rdx),%xmm1
  movupd (%rax),%xmm4
  add    $0x10,%rax
  sub    $0x10,%rdx
  shufpd $0x1,%xmm1,%xmm1
  mulpd  %xmm4,%xmm1
  subsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  subsd  %xmm1,%xmm0
  cmp    %r8,%rax
  jne    L15
  mov    %r9d,%eax
  or     $0x1,%eax
  and    $0x1,%r9d
  je     L39
L18:
  mov    %esi,%edx
  sub    %eax,%edx
  cltq
  movslq %edx,%rdx
  movsd  0x0(%rbp,%rdx,8),%xmm1
  mulsd  (%rcx,%rax,8),%xmm1
  subsd  %xmm1,%xmm0
L39:
  add    $0x1,%esi
  divsd  (%rcx),%xmm0
  movsd  %xmm0,0x0(%rbp,%rdi,8)
  mov    %rbp,%rdi
  mov    %esi,(%rbx)
  call   <reverse@plt>
  xor    %eax,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L55:
  mov    $0x1,%eax
  movslq %esi,%rdi
  jmp    L18
L26:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int amsp_linear_solve(double **eqs, int nEq, int nCf, double *sol, int *nSol) {
  double nt;
  int i;
  *nSol = 0;
  if (solveHelper(eqs, nEq, nCf, sol, nSol) != 0)
    return -1;
  nt = eqs[0][nCf - 1];
  for (i = 1; i < nCf - 1; ++i)
    nt -= eqs[0][i] * sol[*nSol - i];
  sol[*nSol] = nt / eqs[0][0];
  *nSol += 1;
  reverse(sol, *nSol);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sig_alarm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <alarm@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: tick


assistant: ```c
void sig_alarm(int signo) {
  (void)signo;
  printf("tick\n");
  alarm(5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sig_alarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <alarm@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: tick


assistant: ```c
void sig_alarm(int signo) {
  (void)signo;
  printf("tick\n");
  alarm(5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sig_alarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  add    $0x8,%rsp
  jmp    1070 <alarm@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: tick


assistant: ```c
void sig_alarm(int signo) {
  (void)signo;
  printf("tick\n");
  alarm(5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sig_alarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  add    $0x8,%rsp
  jmp    1070 <alarm@plt>
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: tick


assistant: ```c
void sig_alarm(int signo) {
  (void)signo;
  printf("tick\n");
  alarm(5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f7(int x, int y) {
  int s = (x < 0);
  int t = (y >= 0);
  return s != t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f7>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  not    %eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int f7(int x, int y) {
  int s = (x < 0);
  int t = (y >= 0);
  return s != t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f7>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  not    %eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int f7(int x, int y) {
  int s = (x < 0);
  int t = (y >= 0);
  return s != t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f7>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  not    %eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int f7(int x, int y) {
  int s = (x < 0);
  int t = (y >= 0);
  return s != t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D29(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <test_title@plt>
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x5,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <generic_test@plt>
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D29
data_type: string
name: read_data
arguments: tag: D2
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: D29: solution

tool: D2: uart16550

tool: D3: Test 4. Write, small speed

assistant: ```c
int test4(void) {
  const char *rd, *wr;
  rd = "solution";
  wr = "uart16550";
  test_title("Test 4. Write, small speed");
  return generic_test(rd, wr, 0, 5);
}
```