user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D136(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D179(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D119(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D170(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x1c(%rbp),%xmm1
  movss  -0x18(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  D114(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x18(%rbp),%xmm0
  movaps %xmm0,%xmm1
  addss  %xmm0,%xmm1
  movss  -0x1c(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm2
  movss  D114(%rip),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  addss  -0x10(%rbp),%xmm0
  movss  D150(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm3,%xmm3
  cvtss2sd -0xc(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0xc(%rbp),%xmm0
  comiss D148(%rip),%xmm0
  jb     L2
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L71
L2:
  movss  -0xc(%rbp),%xmm0
  comiss D140(%rip),%xmm0
  jb     L54
  lea    D115(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L71
L54:
  movss  -0xc(%rbp),%xmm0
  comiss D181(%rip),%xmm0
  jb     L69
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L71
L69:
  movss  -0xc(%rbp),%xmm0
  comiss D49(%rip),%xmm0
  jb     L46
  lea    D184(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L71
L46:
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L71:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D136
type_guessed: string
name: disassemble_data
arguments: tag: D179
type_guessed: string
name: disassemble_data
arguments: tag: D119
type_guessed: string
name: disassemble_data
arguments: tag: D57
type_guessed: string
name: disassemble_data
arguments: tag: D170
type_guessed: string
name: disassemble_data
arguments: tag: D114
type_guessed: f32
name: disassemble_data
arguments: tag: D150
type_guessed: f32
name: disassemble_data
arguments: tag: D26
type_guessed: string
name: disassemble_data
arguments: tag: D148
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D140
type_guessed: f32
name: disassemble_data
arguments: tag: D115
type_guessed: string
name: disassemble_data
arguments: tag: D181
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D49
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D184
type_guessed: string
name: disassemble_data
arguments: tag: D134
type_guessed: string

tool: D136: Digite a primeira nota: 

tool: D179: %f

tool: D119: Digite a segunda nota: 

tool: D57:  %f

tool: D170: Digite a terceira nota: 

tool: D114: 3

tool: D150: 7

tool: D26: 
Media de aproveitamento: %.2f.


tool: {"D148": [0x00,0x00,0x10,0x41]}

tool: D21: Conceito A.

tool: D140: 7.5

tool: D115: Conceito B.

tool: {"D181": [0x00,0x00,0xc0,0x40]}

tool: D5: Conceito C.

tool: {"D49": [0x00,0x00,0x80,0x40]}

tool: D184: Conceito D.

tool: D134: Conceito E.

assistant: ```c
void main() {
  float n1, n2, n3, me, ma;
  printf("Digite a primeira nota: ");
  scanf("%f", &n1);
  printf("Digite a segunda nota: ");
  scanf(" %f", &n2);
  printf("Digite a terceira nota: ");
  scanf(" %f", &n3);
  me = (n1 + n2 + n3) / 3.0;
  ma = (n1 + 2 * n2 + 3 * n3 + me) / 7.0;
  printf("\nMedia de aproveitamento: %.2f.\n", ma);
  if (ma >= 9)
    printf("Conceito A.\n");
  else if (ma >= 7.5)
    printf("Conceito B.\n");
  else if (ma >= 6)
    printf("Conceito C.\n");
  else if (ma >= 4)
    printf("Conceito D.\n");
  else
    printf("Conceito E.\n");
}
```