ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_strlist>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbp
  mov    %rdx,0x8(%rsp)
  mov    %ecx,%r14d
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,0x4(%rsp)
  mov    $0x0,%r13d
  cmpq   $0x0,0x0(%rbp)
  je     L20
  test   %r14d,%r14d
  je     L70
  mov    $0x0,%r13d
  jmp    L21
L66:
  mov    0x0(%rbp),%rax
  movsbl (%rax,%rbx,1),%edi
  mov    %r15,%rsi
  call   <fputc@plt>
L156:
  lea    0x1(%rbx),%eax
  add    $0x1,%rbx
  mov    0x0(%rbp),%rdx
  movzbl (%rdx,%rbx,1),%edi
  test   %dil,%dil
  je     L58
  lea    0x0(%r13,%rax,1),%r12d
  cmp    %r14d,%r12d
  jae    L58
L56:
  movsbl %dil,%edi
  call   <isprint@plt>
  test   %rax,%rax
  jne    L66
  mov    0x0(%rbp),%rax
  movzbl (%rax,%rbx,1),%edx
  cmp    $0x20,%dl
  je     L66
  mov    %r14d,%eax
  sub    %r12d,%eax
  cmp    $0x3,%eax
  jbe    L132
  movsbl %dl,%edx
  lea    D9(%rip),%rsi
  mov    %r15,%rdi
  call   <fprintf@plt>
  add    $0x3,%r13d
  jmp    L156
L132:
  sub    %r13d,%r14d
L76:
  mov    %r14d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L125:
  mov    $0x0,%eax
L58:
  add    %r13d,%eax
  mov    0x4(%rsp),%ecx
  lea    (%rcx,%rax,1),%r13d
  cmp    %r14d,%r13d
  jae    L61
  mov    %r15,%rsi
  mov    0x8(%rsp),%rdi
  call   <fputs@plt>
  add    $0x8,%rbp
  cmpq   $0x0,0x0(%rbp)
  je     L20
L21:
  mov    0x0(%rbp),%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L125
  mov    %r13d,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%eax
  cmp    %r13d,%r14d
  ja     L56
  jmp    L58
L61:
  sub    %eax,%r14d
  jmp    L76
L70:
  mov    $0x0,%r13d
L20:
  sub    %r13d,%r14d
  jmp    L76
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: \%03o

assistant: ```c
unsigned print_strlist(FILE *file, char **strs, char *sep, unsigned max) {
  int i, n, seplen = strlen(sep);
  for (n = 0; *strs && n < max; strs++) {
    for (i = 0; strs[0][i] && n + i < max; i++)
      if (isprint(strs[0][i]) || strs[0][i] == ' ')
        fputc(strs[0][i], file);
      else {
        if (max - (n + i) > 3) {
          fprintf(file, "\\%03o", strs[0][i]);
          n += 3;
        } else
          return max - n;
      }
    n += i;
    if (n + seplen < max) {
      fputs(sep, file);
      n += seplen;
    } else
      return max - n;
  }
  return max - n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_strlist>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,0x4(%rsp)
  mov    (%r15),%rax
  test   %rax,%rax
  je     L55
  test   %ebp,%ebp
  je     L18
  xor    %ebx,%ebx
L145:
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L37
  mov    %ebx,%r12d
  mov    $0x1,%r14d
  cmp    %ebx,%ebp
  ja     L97
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L151:
  cmp    $0x20,%dil
  je     L4
  mov    %ebp,%eax
  sub    %r12d,%eax
  cmp    $0x3,%eax
  jbe    L68
  movsbl %dil,%edx
  lea    D1(%rip),%rsi
  mov    %r13,%rdi
  add    $0x3,%ebx
  call   <fprintf@plt>
L27:
  mov    (%r15),%rax
  lea    (%rbx,%r14,1),%edx
  movsbl (%rax,%r14,1),%edi
  test   %dil,%dil
  je     L61
  mov    %edx,%r12d
  add    $0x1,%r14
  cmp    %ebp,%edx
  jae    L61
L97:
  call   <isprint@plt>
  test   %rax,%rax
  mov    (%r15),%rax
  movsbl -0x1(%rax,%r14,1),%edi
  je     L151
L4:
  mov    %r13,%rsi
  call   <fputc@plt>
  jmp    L27
L37:
  mov    %ebx,%edx
  nopl   (%rax)
L61:
  mov    0x4(%rsp),%eax
  lea    (%rax,%rdx,1),%ebx
  cmp    %ebp,%ebx
  jae    L49
  mov    0x8(%rsp),%rdi
  mov    %r13,%rsi
  add    $0x8,%r15
  call   <fputs@plt>
  mov    (%r15),%rax
  test   %rax,%rax
  jne    L145
L68:
  mov    %ebp,%eax
  sub    %ebx,%eax
L103:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  mov    %ebp,%eax
  sub    %edx,%eax
  jmp    L103
L55:
  mov    %ebp,%eax
  jmp    L103
L18:
  xor    %eax,%eax
  jmp    L103
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: \%03o

assistant: ```c
unsigned print_strlist(FILE *file, char **strs, char *sep, unsigned max) {
  int i, n, seplen = strlen(sep);
  for (n = 0; *strs && n < max; strs++) {
    for (i = 0; strs[0][i] && n + i < max; i++)
      if (isprint(strs[0][i]) || strs[0][i] == ' ')
        fputc(strs[0][i], file);
      else {
        if (max - (n + i) > 3) {
          fprintf(file, "\\%03o", strs[0][i]);
          n += 3;
        } else
          return max - n;
      }
    n += i;
    if (n + seplen < max) {
      fputs(sep, file);
      n += seplen;
    } else
      return max - n;
  }
  return max - n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_strlist>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <strlen@plt>
  cmpq   $0x0,(%r15)
  mov    %eax,0x4(%rsp)
  mov    %ebp,%eax
  je     L22
  test   %ebp,%ebp
  je     L84
  xor    %ebx,%ebx
L90:
  mov    (%r15),%rax
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L32
  mov    %ebx,%r12d
  mov    $0x1,%r14d
  cmp    %ebx,%ebp
  ja     L51
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L107:
  cmp    $0x20,%dil
  je     L145
  mov    %ebp,%eax
  sub    %r12d,%eax
  cmp    $0x3,%eax
  jbe    L25
  movsbl %dil,%edx
  lea    D9(%rip),%rsi
  mov    %r13,%rdi
  add    $0x3,%ebx
  call   <fprintf@plt>
L105:
  mov    (%r15),%rax
  lea    (%rbx,%r14,1),%edx
  movsbl (%rax,%r14,1),%edi
  test   %dil,%dil
  je     L79
  mov    %edx,%r12d
  add    $0x1,%r14
  cmp    %ebp,%edx
  jae    L79
L51:
  call   <isprint@plt>
  test   %rax,%rax
  mov    (%r15),%rax
  movsbl -0x1(%rax,%r14,1),%edi
  je     L107
L145:
  mov    %r13,%rsi
  call   <fputc@plt>
  jmp    L105
L32:
  mov    %ebx,%edx
  nopl   (%rax)
L79:
  mov    0x4(%rsp),%eax
  lea    (%rax,%rdx,1),%ebx
  cmp    %ebp,%ebx
  jae    L62
  mov    0x8(%rsp),%rdi
  mov    %r13,%rsi
  add    $0x8,%r15
  call   <fputs@plt>
  cmpq   $0x0,(%r15)
  jne    L90
  xchg   %ax,%ax
L25:
  mov    %ebp,%eax
  sub    %ebx,%eax
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  mov    %ebp,%eax
  sub    %edx,%eax
  jmp    L22
L84:
  xor    %eax,%eax
  jmp    L22
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D9: \%03o

assistant: ```c
unsigned print_strlist(FILE *file, char **strs, char *sep, unsigned max) {
  int i, n, seplen = strlen(sep);
  for (n = 0; *strs && n < max; strs++) {
    for (i = 0; strs[0][i] && n + i < max; i++)
      if (isprint(strs[0][i]) || strs[0][i] == ' ')
        fputc(strs[0][i], file);
      else {
        if (max - (n + i) > 3) {
          fprintf(file, "\\%03o", strs[0][i]);
          n += 3;
        } else
          return max - n;
      }
    n += i;
    if (n + seplen < max) {
      fputs(sep, file);
      n += seplen;
    } else
      return max - n;
  }
  return max - n;
}
```
user: What is the c source code of the assembly code below?

```asm
<metal_bitmap_next_clear_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L27
L28:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jae    L1
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <metal_bitmap_is_bit_clear@plt>
  test   %eax,%eax
  je     L28
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int metal_bitmap_next_clear_bit(unsigned long *bitmap, unsigned int start, unsigned int max) {
  unsigned int bit;
  for (bit = start; bit < max && !metal_bitmap_is_bit_clear(bitmap, bit); bit++)
    ;
  return bit;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<metal_bitmap_next_clear_bit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %esi,%eax
  cmp    %edx,%esi
  jae    L36
L14:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <metal_bitmap_is_bit_clear@plt>
  test   %eax,%eax
  jne    L19
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L14
  mov    %ebp,%eax
  jmp    L36
L19:
  mov    %ebx,%eax
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int metal_bitmap_next_clear_bit(unsigned long *bitmap, unsigned int start, unsigned int max) {
  unsigned int bit;
  for (bit = start; bit < max && !metal_bitmap_is_bit_clear(bitmap, bit); bit++)
    ;
  return bit;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<metal_bitmap_next_clear_bit>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  cmp    %edx,%esi
  jb     L23
  jmp    L15
  nopl   (%rax)
L32:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L11
L23:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <metal_bitmap_is_bit_clear@plt>
  test   %eax,%eax
  je     L32
L15:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int metal_bitmap_next_clear_bit(unsigned long *bitmap, unsigned int start, unsigned int max) {
  unsigned int bit;
  for (bit = start; bit < max && !metal_bitmap_is_bit_clear(bitmap, bit); bit++)
    ;
  return bit;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<metal_bitmap_next_clear_bit>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  cmp    %edx,%esi
  jb     L7
  jmp    L15
  nopl   (%rax)
L3:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L10
L7:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <metal_bitmap_is_bit_clear@plt>
  test   %eax,%eax
  je     L3
L15:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int metal_bitmap_next_clear_bit(unsigned long *bitmap, unsigned int start, unsigned int max) {
  unsigned int bit;
  for (bit = start; bit < max && !metal_bitmap_is_bit_clear(bitmap, bit); bit++)
    ;
  return bit;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    $0x401,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L19
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x414(%rbp)
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <palindrome@plt>
  test   %rax,%rax
  je     L24
  lea    D18(%rip),%rax
  jmp    L27
L24:
  lea    D1(%rip),%rax
L27:
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D29
datatype: string

tool: D9: %1024s

tool: D18: Y

tool: D1: N

tool: D29: %s!


assistant: ```c
int main() {
  char s[1024 + 1];
  int len;
  memset(s, 0, sizeof(s));
  if (scanf("%"
            "1024"
            "s",
            s) == 1) {
    len = strlen(s);
    printf("%s!\n", palindrome(s, 0, len) ? "Y" : "N");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x401,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L10
L0:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  ret
L10:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <palindrome@plt>
  test   %rax,%rax
  lea    D10(%rip),%rsi
  lea    D27(%rip),%rax
  cmove  %rax,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type: string
name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D27
type: string
name: retrieve_data
arguments: data_label: D2
type: string

tool: D13: %1024s

tool: D10: Y

tool: D27: N

tool: D2: %s!


assistant: ```c
int main() {
  char s[1024 + 1];
  int len;
  memset(s, 0, sizeof(s));
  if (scanf("%"
            "1024"
            "s",
            s) == 1) {
    len = strlen(s);
    printf("%s!\n", palindrome(s, 0, len) ? "Y" : "N");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x401,%edx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L13
L3:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <palindrome@plt>
  lea    D25(%rip),%rsi
  lea    D27(%rip),%rdi
  test   %rax,%rax
  lea    D32(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  jmp    L3
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D35
data_type: string
name: read_data
arguments: label: D25
data_type: string
name: read_data
arguments: label: D27
data_type: string
name: read_data
arguments: label: D32
data_type: string

tool: D35: %1024s

tool: D25: Y

tool: D27: %s!


tool: D32: N

assistant: ```c
int main() {
  char s[1024 + 1];
  int len;
  memset(s, 0, sizeof(s));
  if (scanf("%"
            "1024"
            "s",
            s) == 1) {
    len = strlen(s);
    printf("%s!\n", palindrome(s, 0, len) ? "Y" : "N");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x401,%edx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L22
L17:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L22:
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <palindrome@plt>
  lea    D21(%rip),%rsi
  lea    D1(%rip),%rdi
  test   %rax,%rax
  lea    D15(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  jmp    L17
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D1
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string

tool: D9: %1024s

tool: D21: Y

tool: D1: %s!


tool: D15: N

assistant: ```c
int main() {
  char s[1024 + 1];
  int len;
  memset(s, 0, sizeof(s));
  if (scanf("%"
            "1024"
            "s",
            s) == 1) {
    len = strlen(s);
    printf("%s!\n", palindrome(s, 0, len) ? "Y" : "N");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<softboundmpx_getgrnam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getgrnam@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x100000(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) struct group *softboundmpx_getgrnam(const char *name) {
  void *ret_ptr = getgrnam(name);
  __softboundmpx_store_return_metadata(ret_ptr, (char *)ret_ptr + 1024 * 1024);
  return ret_ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<softboundmpx_getgrnam>:
  endbr64
  push   %rbx
  call   <getgrnam@plt>
  mov    %rax,%rbx
  lea    0x100000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) struct group *softboundmpx_getgrnam(const char *name) {
  void *ret_ptr = getgrnam(name);
  __softboundmpx_store_return_metadata(ret_ptr, (char *)ret_ptr + 1024 * 1024);
  return ret_ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<softboundmpx_getgrnam>:
  endbr64
  push   %r12
  call   <getgrnam@plt>
  mov    %rax,%r12
  lea    0x100000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) struct group *softboundmpx_getgrnam(const char *name) {
  void *ret_ptr = getgrnam(name);
  __softboundmpx_store_return_metadata(ret_ptr, (char *)ret_ptr + 1024 * 1024);
  return ret_ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<softboundmpx_getgrnam>:
  endbr64
  push   %r12
  call   <getgrnam@plt>
  mov    %rax,%r12
  lea    0x100000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) struct group *softboundmpx_getgrnam(const char *name) {
  void *ret_ptr = getgrnam(name);
  __softboundmpx_store_return_metadata(ret_ptr, (char *)ret_ptr + 1024 * 1024);
  return ret_ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TakeInt64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
extern int TakeInt64(int64_t x) {
  if (x == 0xFFFFFFFFFF)
    return 9;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TakeInt64>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
extern int TakeInt64(int64_t x) {
  if (x == 0xFFFFFFFFFF)
    return 9;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TakeInt64>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
extern int TakeInt64(int64_t x) {
  if (x == 0xFFFFFFFFFF)
    return 9;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<TakeInt64>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
extern int TakeInt64(int64_t x) {
  if (x == 0xFFFFFFFFFF)
    return 9;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<resolvehost>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,D7(%rip)
  mov    D7(%rip),%rax
  leave
  ret
```

assistant: ```c
struct hostent *resolvehost(char *name) {
  static struct hostent *he = 0;
  he = gethostbyname(name);
  return he;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<resolvehost>:
  endbr64
  sub    $0x8,%rsp
  call   <gethostbyname@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct hostent *resolvehost(char *name) {
  static struct hostent *he = 0;
  he = gethostbyname(name);
  return he;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<resolvehost>:
  endbr64
  jmp    1050 <gethostbyname@plt>
```

assistant: ```c
struct hostent *resolvehost(char *name) {
  static struct hostent *he = 0;
  he = gethostbyname(name);
  return he;
}
```
user: What is the c source code of the assembly code below:

```asm
<resolvehost>:
  endbr64
  jmp    1050 <gethostbyname@plt>
```

assistant: ```c
struct hostent *resolvehost(char *name) {
  static struct hostent *he = 0;
  he = gethostbyname(name);
  return he;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lexGet1Value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <lexSkipWhite@plt>
  mov    $0x0,%eax
  call   <lexLookahead@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <lexClearToken@plt>
  jmp    L16
L63:
  cmpl   $0xa,-0x8(%rbp)
  jne    L95
  mov    $0x0,%eax
  call   <lexSkipLookahead@plt>
  mov    $0x0,%eax
  call   <lexLookahead@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  je     L28
  cmpl   $0x9,-0x4(%rbp)
  jne    L66
L28:
  mov    $0x20,%edi
  call   <lexAppendc@plt>
  mov    $0x0,%eax
  call   <lexSkipLookahead@plt>
  jmp    L12
L66:
  mov    $0xa,%edi
  call   <lexPushLookaheadc@plt>
  jmp    L91
L95:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <lexAppendc@plt>
  mov    $0x0,%eax
  call   <lexSkipLookahead@plt>
L12:
  mov    $0x0,%eax
  call   <lexLookahead@plt>
  mov    %eax,-0x8(%rbp)
L16:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L91
  cmpl   $0x3b,-0x8(%rbp)
  jne    L63
L91:
  mov    $0x0,%edi
  call   <lexAppendc@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <handleMoreRFC822LineBreak@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L61
  mov    $0x0,%eax
  call   <lexStr@plt>
  jmp    L3
L61:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
char *lexGet1Value() {
  int c;
  lexSkipWhite();
  c = lexLookahead();
  lexClearToken();
  while (c != EOF && c != ';') {
    if (c == '\n') {
      int a;
      lexSkipLookahead();
      a = lexLookahead();
      if (a == ' ' || a == '\t') {
        lexAppendc(' ');
        lexSkipLookahead();
      } else {
        lexPushLookaheadc('\n');
        break;
      }
    } else {
      lexAppendc(c);
      lexSkipLookahead();
    }
    c = lexLookahead();
  }
  lexAppendc(0);
  handleMoreRFC822LineBreak(c);
  return c == EOF ? 0 : lexStr();
}
```