ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L29:
  movb   $0x1,(%rsp,%rbx,1)
  add    $0x1,%rbx
L35:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L29
  movb   $0x0,(%rsp,%rbp,1)
  movsbl (%rsp),%edi
  cmp    $0xa,%dil
  je     L33
  lea    0x1(%rsp),%rbx
  nopl   0x0(%rax)
L10:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  cmp    $0xa,%dil
  jne    L10
L33:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: enter the sentence: 

assistant: ```c
int main(void) {
  char terminator;
  char ch, sentence[100];
  int count;
  printf("enter the sentence: ");
  for (count = 0; (ch = getchar() != '\n'); count++) {
    sentence[count] = ch;
  }
  sentence[count] = '\0';
  count = 0;
  while (sentence[count] != '\n') {
    printf("%c", sentence[count]);
    count++;
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L18:
  movb   $0x1,(%rsp,%rbx,1)
  add    $0x1,%rbx
L0:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L18
  movb   $0x0,(%rsp,%rbp,1)
  movsbl (%rsp),%edi
  cmp    $0xa,%dil
  je     L19
  lea    0x1(%rsp),%rbx
  nopl   0x0(%rax)
L12:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  cmp    $0xa,%dil
  jne    L12
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: enter the sentence: 

assistant: ```c
int main(void) {
  char terminator;
  char ch, sentence[100];
  int count;
  printf("enter the sentence: ");
  for (count = 0; (ch = getchar() != '\n'); count++) {
    sentence[count] = ch;
  }
  sentence[count] = '\0';
  count = 0;
  while (sentence[count] != '\n') {
    printf("%c", sentence[count]);
    count++;
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GetPindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x9,%edi
  call   <floor@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int GetPindex() {
  int fakeI;
  if (19 % 2 == 1)
    fakeI = (19 + 1) * floor(19 / 2);
  else
    fakeI = (19 + 1) * (19 / 2 - 1);
  return fakeI;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GetPindex>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%edi
  call   <floor@plt>
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int GetPindex() {
  int fakeI;
  if (19 % 2 == 1)
    fakeI = (19 + 1) * floor(19 / 2);
  else
    fakeI = (19 + 1) * (19 / 2 - 1);
  return fakeI;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GetPindex>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%edi
  call   <floor@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
int GetPindex() {
  int fakeI;
  if (19 % 2 == 1)
    fakeI = (19 + 1) * floor(19 / 2);
  else
    fakeI = (19 + 1) * (19 / 2 - 1);
  return fakeI;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetPindex>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%edi
  call   <floor@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
int GetPindex() {
  int fakeI;
  if (19 % 2 == 1)
    fakeI = (19 + 1) * floor(19 / 2);
  else
    fakeI = (19 + 1) * (19 / 2 - 1);
  return fakeI;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2a,-0x14(%rbp)
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(void) {
  int fd = 42;
  char buf[4];
  ssize_t len;
  len = read(fd, &buf, 4);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    $0x2a,%edi
  call   <read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int fd = 42;
  char buf[4];
  ssize_t len;
  len = read(fd, &buf, 4);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    $0x2a,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int fd = 42;
  char buf[4];
  ssize_t len;
  len = read(fd, &buf, 4);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    $0x2a,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int fd = 42;
  char buf[4];
  ssize_t len;
  len = read(fd, &buf, 4);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m1fft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %r8d,-0x48(%rbp)
  mov    %r9d,-0x4c(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edi
  call   <nfactors@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x3c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <factor@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L33
L14:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x3c(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L26
L6:
  mov    -0x24(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  cltd
  idivl  -0x3c(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x3c(%rbp),%eax
  imul   -0x40(%rbp),%eax
  mov    %eax,%edi
  mov    -0x18(%rbp),%eax
  imul   -0x40(%rbp),%eax
  mov    %eax,%r9d
  mov    -0x14(%rbp),%eax
  imul   -0x40(%rbp),%eax
  mov    %eax,%r10d
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%esi
  mov    -0x44(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    -0x4c(%rbp),%r8d
  push   %r8
  mov    -0x48(%rbp),%r8d
  push   %r8
  mov    -0x18(%rbp),%r8d
  push   %r8
  push   %rdi
  mov    %r10d,%r8d
  mov    %rax,%rdi
  call   <m1spfar@plt>
  add    $0x20,%rsp
  addl   $0x1,-0x24(%rbp)
L26:
  mov    -0x24(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L6
  addl   $0x1,-0x28(%rbp)
L33:
  mov    -0x28(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void m1fft(double *a, int n, int str, int dir, int rep, int rstr) {
  int nf, f, f1, f2, i, j;
  int *factors = 0, *powers = 0;
  nf = nfactors(n);
  factors = malloc(nf * sizeof(int));
  powers = malloc(nf * sizeof(int));
  factor(n, factors, powers);
  for (f = 0; f < nf; f++) {
    f1 = pow(factors[f], powers[f]);
    f2 = n / f1;
    for (i = 0; i < f2; i++) {
      j = (i * f1) % n;
      m1spfar(a, factors[f], powers[f], dir, j * str, f2 * str, n * str, f2, rep, rstr);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m1fft>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %esi,%r15d
  mov    %edx,%r14d
  mov    %edx,0x8(%rsp)
  mov    %ecx,0x18(%rsp)
  mov    %r8d,0x1c(%rsp)
  mov    %r9d,0x20(%rsp)
  mov    %esi,%edi
  call   <nfactors@plt>
  mov    %eax,%ebx
  lea    0x0(,%rax,4),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdx
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <factor@plt>
  test   %ebx,%ebx
  jle    L19
  imul   %r15d,%r14d
  mov    %r14d,0x24(%rsp)
  mov    %rbp,0x28(%rsp)
  mov    %r12,0x30(%rsp)
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp,%rax,4),%rax
  mov    %rax,0x38(%rsp)
L20:
  mov    0x28(%rsp),%rax
  mov    %rax,%r13
  mov    0x30(%rsp),%rcx
  mov    %rcx,%r14
  mov    (%rax),%esi
  mov    (%rcx),%edi
  call   <pow@plt>
  mov    %eax,%esi
  mov    %eax,0x4(%rsp)
  mov    %r15d,%eax
  cltd
  idiv   %esi
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L25
  mov    0x8(%rsp),%eax
  imul   %r12d,%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L10:
  mov    %ebx,%eax
  cltd
  idiv   %r15d
  mov    0x20(%rsp),%eax
  push   %rax
  mov    0x24(%rsp),%eax
  push   %rax
  push   %r12
  mov    0x3c(%rsp),%eax
  push   %rax
  mov    0x2c(%rsp),%r9d
  imul   0x28(%rsp),%edx
  mov    %edx,%r8d
  mov    0x38(%rsp),%ecx
  mov    0x0(%r13),%edx
  mov    (%r14),%esi
  mov    0x30(%rsp),%rdi
  call   <m1spfar@plt>
  add    $0x1,%ebp
  add    0x24(%rsp),%ebx
  add    $0x20,%rsp
  cmp    %ebp,%r12d
  jne    L10
L25:
  addq   $0x4,0x28(%rsp)
  mov    0x28(%rsp),%rax
  addq   $0x4,0x30(%rsp)
  cmp    0x38(%rsp),%rax
  jne    L20
L19:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void m1fft(double *a, int n, int str, int dir, int rep, int rstr) {
  int nf, f, f1, f2, i, j;
  int *factors = 0, *powers = 0;
  nf = nfactors(n);
  factors = malloc(nf * sizeof(int));
  powers = malloc(nf * sizeof(int));
  factor(n, factors, powers);
  for (f = 0; f < nf; f++) {
    f1 = pow(factors[f], powers[f]);
    f2 = n / f1;
    for (i = 0; i < f2; i++) {
      j = (i * f1) % n;
      m1spfar(a, factors[f], powers[f], dir, j * str, f2 * str, n * str, f2, rep, rstr);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m1fft>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %rdi,%r14
  mov    %esi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0x14(%rsp)
  mov    %esi,0x10(%rsp)
  mov    %r8d,0x1c(%rsp)
  mov    %r9d,0x20(%rsp)
  call   <nfactors@plt>
  lea    0x0(,%rax,4),%ebp
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    0x10(%rsp),%ebp
  mov    %r13,%rsi
  mov    %rax,%rdx
  mov    %rax,%r12
  mov    %ebp,%edi
  call   <factor@plt>
  test   %ebx,%ebx
  jle    L11
  mov    0x14(%rsp),%eax
  mov    %r12,(%rsp)
  mov    %r13,0x8(%rsp)
  imul   %ebp,%eax
  mov    %eax,0x24(%rsp)
  lea    -0x1(%rbx),%eax
  lea    0x4(%r12,%rax,4),%rax
  mov    %rax,0x28(%rsp)
  nopl   0x0(%rax,%rax,1)
L25:
  mov    (%rsp),%rax
  mov    (%rax),%esi
  mov    0x8(%rsp),%rax
  mov    (%rax),%edi
  call   <pow@plt>
  mov    %eax,%esi
  mov    %eax,0x18(%rsp)
  mov    0x10(%rsp),%eax
  cltd
  idiv   %esi
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L29
  mov    0x14(%rsp),%r13d
  xor    %ebx,%ebx
  imul   %eax,%r13d
  xor    %eax,%eax
  mov    %r13d,%ebp
  mov    %eax,%r13d
  nopl   0x0(%rax)
L33:
  mov    %ebx,%eax
  mov    %ebp,%r9d
  mov    %r15d,%ecx
  mov    %r14,%rdi
  cltd
  add    $0x1,%r13d
  idivl  0x10(%rsp)
  mov    0x20(%rsp),%eax
  push   %rax
  mov    0x24(%rsp),%eax
  push   %rax
  push   %r12
  mov    0x3c(%rsp),%eax
  push   %rax
  mov    0x20(%rsp),%rax
  imul   0x34(%rsp),%edx
  mov    %edx,%r8d
  mov    (%rax),%edx
  mov    0x28(%rsp),%rax
  mov    (%rax),%esi
  call   <m1spfar@plt>
  add    0x38(%rsp),%ebx
  add    $0x20,%rsp
  cmp    %r13d,%r12d
  jne    L33
L29:
  addq   $0x4,(%rsp)
  mov    (%rsp),%rax
  addq   $0x4,0x8(%rsp)
  cmp    0x28(%rsp),%rax
  jne    L25
L11:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void m1fft(double *a, int n, int str, int dir, int rep, int rstr) {
  int nf, f, f1, f2, i, j;
  int *factors = 0, *powers = 0;
  nf = nfactors(n);
  factors = malloc(nf * sizeof(int));
  powers = malloc(nf * sizeof(int));
  factor(n, factors, powers);
  for (f = 0; f < nf; f++) {
    f1 = pow(factors[f], powers[f]);
    f2 = n / f1;
    for (i = 0; i < f2; i++) {
      j = (i * f1) % n;
      m1spfar(a, factors[f], powers[f], dir, j * str, f2 * str, n * str, f2, rep, rstr);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<m1fft>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %rdi,%r14
  mov    %esi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0x14(%rsp)
  mov    %esi,0x10(%rsp)
  mov    %r8d,0x1c(%rsp)
  mov    %r9d,0x20(%rsp)
  call   <nfactors@plt>
  lea    0x0(,%rax,4),%ebp
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    0x10(%rsp),%ebp
  mov    %r13,%rsi
  mov    %rax,%rdx
  mov    %rax,%r12
  mov    %ebp,%edi
  call   <factor@plt>
  test   %ebx,%ebx
  jle    L5
  mov    0x14(%rsp),%eax
  mov    %r12,(%rsp)
  mov    %r13,0x8(%rsp)
  imul   %ebp,%eax
  mov    %eax,0x24(%rsp)
  lea    -0x1(%rbx),%eax
  lea    0x4(%r12,%rax,4),%rax
  mov    %rax,0x28(%rsp)
  nopl   0x0(%rax,%rax,1)
L34:
  mov    (%rsp),%rax
  mov    (%rax),%esi
  mov    0x8(%rsp),%rax
  mov    (%rax),%edi
  call   <pow@plt>
  mov    %eax,%esi
  mov    %eax,0x18(%rsp)
  mov    0x10(%rsp),%eax
  cltd
  idiv   %esi
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L8
  mov    0x14(%rsp),%r13d
  xor    %ebx,%ebx
  imul   %eax,%r13d
  xor    %eax,%eax
  mov    %r13d,%ebp
  mov    %eax,%r13d
  nopl   0x0(%rax)
L23:
  mov    %ebx,%eax
  mov    %ebp,%r9d
  mov    %r15d,%ecx
  mov    %r14,%rdi
  cltd
  add    $0x1,%r13d
  idivl  0x10(%rsp)
  mov    0x20(%rsp),%eax
  push   %rax
  mov    0x24(%rsp),%eax
  push   %rax
  push   %r12
  mov    0x3c(%rsp),%eax
  push   %rax
  mov    0x20(%rsp),%rax
  imul   0x34(%rsp),%edx
  mov    %edx,%r8d
  mov    (%rax),%edx
  mov    0x28(%rsp),%rax
  mov    (%rax),%esi
  call   <m1spfar@plt>
  add    0x38(%rsp),%ebx
  add    $0x20,%rsp
  cmp    %r13d,%r12d
  jne    L23
L8:
  addq   $0x4,(%rsp)
  mov    (%rsp),%rax
  addq   $0x4,0x8(%rsp)
  cmp    0x28(%rsp),%rax
  jne    L34
L5:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void m1fft(double *a, int n, int str, int dir, int rep, int rstr) {
  int nf, f, f1, f2, i, j;
  int *factors = 0, *powers = 0;
  nf = nfactors(n);
  factors = malloc(nf * sizeof(int));
  powers = malloc(nf * sizeof(int));
  factor(n, factors, powers);
  for (f = 0; f < nf; f++) {
    f1 = pow(factors[f], powers[f]);
    f2 = n / f1;
    for (i = 0; i < f2; i++) {
      j = (i * f1) % n;
      m1spfar(a, factors[f], powers[f], dir, j * str, f2 * str, n * str, f2, rep, rstr);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stdlib_strided_svariancepn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  movss  %xmm0,-0x3c(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x3c(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jle    L17
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jb     L67
L17:
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  jmp    L19
L67:
  cmpq   $0x1,-0x38(%rbp)
  je     L46
  cmpq   $0x0,-0x50(%rbp)
  jne    L7
L46:
  pxor   %xmm0,%xmm0
  jmp    L19
L7:
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <stdlib_strided_ssumpw@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  -0x10(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x28(%rbp)
  cmpq   $0x0,-0x50(%rbp)
  jns    L2
  mov    $0x1,%eax
  sub    -0x38(%rbp),%rax
  mov    -0x50(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L75
L2:
  movq   $0x0,-0x20(%rbp)
L75:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L96
L16:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  subss  -0x28(%rbp),%xmm0
  movss  %xmm0,-0x24(%rbp)
  movss  -0x24(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  -0x30(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x30(%rbp)
  movss  -0x2c(%rbp),%xmm0
  addss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x2c(%rbp)
  mov    -0x50(%rbp),%rax
  add    %rax,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L96:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jl     L16
  pxor   %xmm0,%xmm0
  cvtss2sd -0x30(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0x2c(%rbp),%xmm1
  divsd  -0x10(%rbp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsd2ss %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd -0x2c(%rbp),%xmm1
  divsd  -0x8(%rbp),%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
L19:
  leave
  ret
```

assistant: ```c
float stdlib_strided_svariancepn(const int64_t N, const float correction, const float *X, const int64_t stride) {
  int64_t ix;
  int64_t i;
  double dN;
  double n;
  float mu;
  float M2;
  float M;
  float d;
  dN = (double)N;
  n = dN - (double)correction;
  if (N <= 0 || n <= 0.0f) {
    return 0.0f / 0.0f;
  }
  if (N == 1 || stride == 0) {
    return 0.0f;
  }
  mu = (double)stdlib_strided_ssumpw(N, X, stride) / dN;
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  M2 = 0.0f;
  M = 0.0f;
  for (i = 0; i < N; i++) {
    d = X[ix] - mu;
    M2 += d * d;
    M += d;
    ix += stride;
  }
  return (float)((double)M2 / n) - ((float)((double)M / dN) * (float)((double)M / n));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stdlib_strided_svariancepn>:
  endbr64
  test   %rdi,%rdi
  jle    L10
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  pxor   %xmm5,%xmm5
  cvtsi2sd %rdi,%xmm5
  movsd  %xmm5,(%rsp)
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm0,%xmm5
  movsd  %xmm5,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm5,%xmm0
  jae    L18
  cmp    $0x1,%rdi
  je     L54
  test   %rdx,%rdx
  je     L54
  call   <stdlib_strided_ssumpw@plt>
  pxor   %xmm4,%xmm4
  cvtsi2sd %rax,%xmm4
  divsd  (%rsp),%xmm4
  cvtsd2ss %xmm4,%xmm4
  mov    $0x0,%eax
  test   %rbp,%rbp
  js     L36
L8:
  lea    0x0(,%rbp,4),%rcx
  lea    (%r12,%rax,4),%rdx
  pxor   %xmm2,%xmm2
  movaps %xmm2,%xmm1
  mov    $0x0,%eax
L60:
  movss  (%rdx),%xmm0
  subss  %xmm4,%xmm0
  movaps %xmm0,%xmm3
  mulss  %xmm0,%xmm3
  addss  %xmm3,%xmm1
  addss  %xmm0,%xmm2
  add    $0x1,%rax
  add    %rcx,%rdx
  cmp    %rax,%rbx
  jne    L60
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm6
  divsd  %xmm6,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  movapd %xmm2,%xmm1
  divsd  (%rsp),%xmm1
  cvtsd2ss %xmm1,%xmm1
  divsd  %xmm6,%xmm2
  cvtsd2ss %xmm2,%xmm2
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  jmp    L33
L18:
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
L33:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    $0x1,%eax
  sub    %rbx,%rax
  imul   %rbp,%rax
  jmp    L8
L54:
  pxor   %xmm0,%xmm0
  jmp    L33
L10:
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  ret
```

assistant: ```c
float stdlib_strided_svariancepn(const int64_t N, const float correction, const float *X, const int64_t stride) {
  int64_t ix;
  int64_t i;
  double dN;
  double n;
  float mu;
  float M2;
  float M;
  float d;
  dN = (double)N;
  n = dN - (double)correction;
  if (N <= 0 || n <= 0.0f) {
    return 0.0f / 0.0f;
  }
  if (N == 1 || stride == 0) {
    return 0.0f;
  }
  mu = (double)stdlib_strided_ssumpw(N, X, stride) / dN;
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  M2 = 0.0f;
  M = 0.0f;
  for (i = 0; i < N; i++) {
    d = X[ix] - mu;
    M2 += d * d;
    M += d;
    ix += stride;
  }
  return (float)((double)M2 / n) - ((float)((double)M / dN) * (float)((double)M / n));
}
```