ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<MemoryWrite>:
  endbr64
  test   %edx,%edx
  jle    L11
  push   %r12
  lea    (%rdx,%rdi,1),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax)
L17:
  mov    %ebp,%esi
  mov    %ebx,%edi
  add    $0x1,%ebx
  sar    $0x8,%ebp
  call   <Z80_WR_MEM@plt>
  cmp    %r12d,%ebx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
void MemoryWrite(int Address, int Data, int NumberOfBytes) {
  int i;
  int WriteData;
  WriteData = Data;
  for (i = 0; i < NumberOfBytes; i++) {
    Z80_WR_MEM(Address + i, WriteData);
    WriteData >>= 8;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cf2setispeed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    D50(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L19
  mov    D58(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L35
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L19
L35:
  mov    D40(%rip),%rax
  mov    (%rax),%edx
  mov    D39(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L2
L19:
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    D50(%rip),%rax
  mov    (%rax),%ecx
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  shl    $0x10,%eax
  not    %eax
  and    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0xc(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int cf2setispeed(struct termios *tios, speed_t speed) {
  if ((speed & ~CBAUD) != 0 && (speed < B57600 || speed > __MAX_BAUD)) {
    errno = EINVAL;
    return -1;
  }
  tios->c_ispeed = speed;
  tios->c_cflag &= ~((CBAUD | CBAUDEX) << 16);
  tios->c_cflag |= (speed << 16);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cf2setispeed>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%eax
  mov    D60(%rip),%rcx
  mov    (%rcx),%ecx
  not    %ecx
  test   %esi,%ecx
  je     L13
  mov    D4(%rip),%rcx
  cmp    %esi,(%rcx)
  jg     L2
  mov    D62(%rip),%rcx
  cmp    %esi,(%rcx)
  jl     L2
L13:
  mov    %eax,(%rdx)
  mov    D60(%rip),%rcx
  mov    (%rcx),%esi
  mov    D43(%rip),%rcx
  or     (%rcx),%esi
  shl    $0x10,%esi
  not    %esi
  and    0x4(%rdx),%esi
  shl    $0x10,%eax
  or     %eax,%esi
  mov    %esi,0x4(%rdx)
  mov    $0x0,%eax
  ret
L2:
  mov    D39(%rip),%rax
  mov    (%rax),%edx
  mov    D63(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cf2setispeed(struct termios *tios, speed_t speed) {
  if ((speed & ~CBAUD) != 0 && (speed < B57600 || speed > __MAX_BAUD)) {
    errno = EINVAL;
    return -1;
  }
  tios->c_ispeed = speed;
  tios->c_cflag &= ~((CBAUD | CBAUDEX) << 16);
  tios->c_cflag |= (speed << 16);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cf2setispeed>:
  endbr64
  mov    D51(%rip),%rax
  mov    %esi,%edx
  mov    %rdi,%rcx
  mov    (%rax),%eax
  mov    %eax,%esi
  not    %esi
  test   %edx,%esi
  je     L0
  mov    D55(%rip),%rsi
  cmp    %edx,(%rsi)
  jg     L1
  mov    D32(%rip),%rsi
  cmp    %edx,(%rsi)
  jl     L1
L0:
  mov    D20(%rip),%rsi
  mov    %edx,(%rcx)
  shl    $0x10,%edx
  or     (%rsi),%eax
  mov    %eax,%esi
  xor    %eax,%eax
  shl    $0x10,%esi
  not    %esi
  and    0x4(%rcx),%esi
  or     %edx,%esi
  mov    %esi,0x4(%rcx)
  ret
L1:
  mov    D44(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cf2setispeed(struct termios *tios, speed_t speed) {
  if ((speed & ~CBAUD) != 0 && (speed < B57600 || speed > __MAX_BAUD)) {
    errno = EINVAL;
    return -1;
  }
  tios->c_ispeed = speed;
  tios->c_cflag &= ~((CBAUD | CBAUDEX) << 16);
  tios->c_cflag |= (speed << 16);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cf2setispeed>:
  endbr64
  mov    D10(%rip),%rax
  mov    %rdi,%rdx
  mov    (%rax),%eax
  mov    %eax,%ecx
  not    %ecx
  test   %esi,%ecx
  je     L28
  mov    D46(%rip),%rcx
  cmp    %esi,(%rcx)
  jg     L2
  mov    D19(%rip),%rcx
  cmp    %esi,(%rcx)
  jl     L2
L28:
  mov    D8(%rip),%rcx
  movd   %esi,%xmm0
  or     (%rcx),%eax
  mov    %esi,%ecx
  shl    $0x10,%eax
  shl    $0x10,%ecx
  not    %eax
  and    0x4(%rdx),%eax
  or     %ecx,%eax
  movd   %eax,%xmm1
  xor    %eax,%eax
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdx)
  ret
  nopl   0x0(%rax)
L2:
  mov    D58(%rip),%rax
  mov    (%rax),%edx
  mov    D39(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cf2setispeed(struct termios *tios, speed_t speed) {
  if ((speed & ~CBAUD) != 0 && (speed < B57600 || speed > __MAX_BAUD)) {
    errno = EINVAL;
    return -1;
  }
  tios->c_ispeed = speed;
  tios->c_cflag &= ~((CBAUD | CBAUDEX) << 16);
  tios->c_cflag |= (speed << 16);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_quote>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L24
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L14
L4:
  mov    $0x5c,%edi
  call   <putchar@plt>
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addq   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_quote(char *p) {
  while (*p) {
    if (*p == '\"' || *p == '\\')
      printf("\\");
    printf("%c", *p);
    p++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_quote>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L11
L33:
  pop    %rbx
  ret
L34:
  mov    $0x5c,%edi
  call   <putchar@plt>
L45:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L33
L11:
  cmp    $0x22,%al
  je     L34
  cmp    $0x5c,%al
  jne    L45
  jmp    L34
```

assistant: ```c
void print_quote(char *p) {
  while (*p) {
    if (*p == '\"' || *p == '\\')
      printf("\\");
    printf("%c", *p);
    p++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_quote>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  jmp    L44
  nopl   0x0(%rax)
L41:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L13
L44:
  cmp    $0x22,%al
  je     L49
  cmp    $0x5c,%al
  jne    L41
L49:
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L41
  nop
L13:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void print_quote(char *p) {
  while (*p) {
    if (*p == '\"' || *p == '\\')
      printf("\\");
    printf("%c", *p);
    p++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_quote>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L5
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L43:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L36
L5:
  cmp    $0x22,%dil
  je     L41
  cmp    $0x5c,%dil
  jne    L43
L41:
  mov    $0x5c,%edi
  call   <putchar@plt>
  movsbl (%rbx),%edi
  jmp    L43
  nopl   (%rax)
L36:
  pop    %rbx
  ret
```

assistant: ```c
void print_quote(char *p) {
  while (*p) {
    if (*p == '\"' || *p == '\\')
      printf("\\");
    printf("%c", *p);
    p++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<EstimateBas64DecodedDataSize>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L23
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L20:
  mulsd  D8(%rip),%xmm0
  movsd  D3(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L17
  cvttsd2si %xmm0,%rdi
  call   <ceil@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,2),%eax
  cltq
  ret
L17:
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rdi
  btc    $0x3f,%rdi
  call   <ceil@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,2),%eax
  cltq
  ret
  nopl   (%rax)
L23:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L20
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: byte[8]
name: retrieve_data
arguments: label: D3
datatype: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

assistant: ```c
size_t EstimateBas64DecodedDataSize(size_t inDataSize) {
  size_t theDecodedDataSize = (int)ceil(inDataSize / 4.0) * 3;
  return (theDecodedDataSize);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<EstimateBas64DecodedDataSize>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L13
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L24:
  mulsd  D8(%rip),%xmm0
  movsd  D16(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L20
  cvttsd2si %xmm0,%rdi
  call   <ceil@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,2),%eax
  cltq
  ret
L20:
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rdi
  btc    $0x3f,%rdi
  call   <ceil@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,2),%eax
  cltq
  ret
  nopl   (%rax)
L13:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L24
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: byte[8]
name: unpack_data
arguments: data_tag: D16
type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

assistant: ```c
size_t EstimateBas64DecodedDataSize(size_t inDataSize) {
  size_t theDecodedDataSize = (int)ceil(inDataSize / 4.0) * 3;
  return (theDecodedDataSize);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unshelveSubgraphMask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x31,%eax
  jle    L4
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  sub    $0x64,%edx
  mov    %edx,(%rax)
L4:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unshelveSubgraphMask(int *subgraphMask, int lenSubgraphMask) {
  int index;
  for (index = 0; index < lenSubgraphMask; index++) {
    if (subgraphMask[index] >= 50)
      subgraphMask[index] -= 100;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unshelveSubgraphMask>:
  endbr64
  test   %esi,%esi
  jle    L32
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  jmp    L48
L35:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L32
L48:
  mov    (%rax),%edx
  cmp    $0x31,%edx
  jle    L35
  sub    $0x64,%edx
  mov    %edx,(%rax)
  jmp    L35
L32:
  ret
```

assistant: ```c
void unshelveSubgraphMask(int *subgraphMask, int lenSubgraphMask) {
  int index;
  for (index = 0; index < lenSubgraphMask; index++) {
    if (subgraphMask[index] >= 50)
      subgraphMask[index] -= 100;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unshelveSubgraphMask>:
  endbr64
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
L21:
  mov    (%rdi),%eax
  cmp    $0x31,%eax
  jle    L6
  sub    $0x64,%eax
  mov    %eax,(%rdi)
L6:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L21
L20:
  ret
```

assistant: ```c
void unshelveSubgraphMask(int *subgraphMask, int lenSubgraphMask) {
  int index;
  for (index = 0; index < lenSubgraphMask; index++) {
    if (subgraphMask[index] >= 50)
      subgraphMask[index] -= 100;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<unshelveSubgraphMask>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
L3:
  mov    (%rdi),%eax
  cmp    $0x31,%eax
  jle    L18
  sub    $0x64,%eax
  mov    %eax,(%rdi)
L18:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L3
L11:
  ret
```

assistant: ```c
void unshelveSubgraphMask(int *subgraphMask, int lenSubgraphMask) {
  int index;
  for (index = 0; index < lenSubgraphMask; index++) {
    if (subgraphMask[index] >= 50)
      subgraphMask[index] -= 100;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L24:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L17
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x54,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    $0x61,%eax
  jmp    L5
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
L5:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L24
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rat(char *message) {
  char *cyphertext = (char *)malloc(sizeof(char) * strlen(message));
  int i;
  for (i = 0; i < strlen(message); i++) {
    cyphertext[i] = (isalpha(message[i])) ? (((message[i] + 13 - 'a') % 26) + 'a') : message[i];
  }
  return cyphertext;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  jmp    L14
L25:
  movzbl 0x0(%rbp,%rbx,1),%eax
L4:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L26
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L25
  movsbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x54,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    $0x61,%eax
  jmp    L4
L26:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *rat(char *message) {
  char *cyphertext = (char *)malloc(sizeof(char) * strlen(message));
  int i;
  for (i = 0; i < strlen(message); i++) {
    cyphertext[i] = (isalpha(message[i])) ? (((message[i] + 13 - 'a') % 26) + 'a') : message[i];
  }
  return cyphertext;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L24
  xchg   %ax,%ax
L23:
  movsbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x54,%eax
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    $0x61,%eax
L12:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L6
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L23
  movzbl 0x0(%rbp,%rbx,1),%eax
  jmp    L12
  nop
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *rat(char *message) {
  char *cyphertext = (char *)malloc(sizeof(char) * strlen(message));
  int i;
  for (i = 0; i < strlen(message); i++) {
    cyphertext[i] = (isalpha(message[i])) ? (((message[i] + 13 - 'a') % 26) + 'a') : message[i];
  }
  return cyphertext;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L2
  xchg   %ax,%ax
L14:
  movsbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x54,%eax
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    $0x61,%eax
L8:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L36
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L14
  movzbl 0x0(%rbp,%rbx,1),%eax
  jmp    L8
  nop
L36:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *rat(char *message) {
  char *cyphertext = (char *)malloc(sizeof(char) * strlen(message));
  int i;
  for (i = 0; i < strlen(message); i++) {
    cyphertext[i] = (isalpha(message[i])) ? (((message[i] + 13 - 'a') % 26) + 'a') : message[i];
  }
  return cyphertext;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ReadHostWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L26
L24:
  nop
L23:
  mov    $0x63,%edi
  call   <readVIC@plt>
  test   %rax,%rax
  je     L23
  mov    $0x67,%edi
  call   <readVIC@plt>
  or     %rax,-0x10(%rbp)
  mov    $0x0,%esi
  mov    $0x63,%edi
  call   <writeVIC@plt>
  addq   $0x1,-0x8(%rbp)
L26:
  cmpq   $0x3,-0x8(%rbp)
  jbe    L24
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long ReadHostWord(void) {
  unsigned long val, i;
  for (i = 0, val = 0; i < 4; i++) {
    while (!(readVIC(0x63)))
      ;
    val |= readVIC(0x67);
    writeVIC(0x63, 0);
  }
  return (val);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ReadHostWord>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4,%ebx
  mov    $0x0,%ebp
L17:
  mov    $0x63,%edi
  call   <readVIC@plt>
  test   %rax,%rax
  je     L17
  mov    $0x67,%edi
  call   <readVIC@plt>
  or     %rax,%rbp
  mov    $0x0,%esi
  mov    $0x63,%edi
  call   <writeVIC@plt>
  sub    $0x1,%rbx
  jne    L17
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long ReadHostWord(void) {
  unsigned long val, i;
  for (i = 0, val = 0; i < 4; i++) {
    while (!(readVIC(0x63)))
      ;
    val |= readVIC(0x67);
    writeVIC(0x63, 0);
  }
  return (val);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ReadHostWord>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x63,%edi
  call   <readVIC@plt>
  test   %rax,%rax
  je     L4
  mov    $0x67,%edi
  call   <readVIC@plt>
  xor    %esi,%esi
  mov    $0x63,%edi
  or     %rax,%r12
  call   <writeVIC@plt>
  sub    $0x1,%rbx
  jne    L4
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned long ReadHostWord(void) {
  unsigned long val, i;
  for (i = 0, val = 0; i < 4; i++) {
    while (!(readVIC(0x63)))
      ;
    val |= readVIC(0x67);
    writeVIC(0x63, 0);
  }
  return (val);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ReadHostWord>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x63,%edi
  call   <readVIC@plt>
  test   %rax,%rax
  je     L15
  mov    $0x67,%edi
  call   <readVIC@plt>
  xor    %esi,%esi
  mov    $0x63,%edi
  or     %rax,%r12
  call   <writeVIC@plt>
  sub    $0x1,%rbx
  jne    L15
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned long ReadHostWord(void) {
  unsigned long val, i;
  for (i = 0, val = 0; i < 4; i++) {
    while (!(readVIC(0x63)))
      ;
    val |= readVIC(0x67);
    writeVIC(0x63, 0);
  }
  return (val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nsec_to_timespec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x112e0be826d694b3,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x1a,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca00,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x112e0be826d694b3,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x1a,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
struct timespec nsec_to_timespec(long int nsec) {
  struct timespec temp;
  temp.tv_nsec = nsec % 1000000000L;
  temp.tv_sec = nsec / 1000000000L;
  return temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nsec_to_timespec>:
  endbr64
  movabs $0x112e0be826d694b3,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x1a,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca00,%rdx,%rcx
  mov    %rdi,%rax
  sub    %rcx,%rax
  ret
```

assistant: ```c
struct timespec nsec_to_timespec(long int nsec) {
  struct timespec temp;
  temp.tv_nsec = nsec % 1000000000L;
  temp.tv_sec = nsec / 1000000000L;
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nsec_to_timespec>:
  endbr64
  movabs $0x112e0be826d694b3,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x1a,%rdx
  sub    %rax,%rdx
  mov    %rdi,%rax
  imul   $0x3b9aca00,%rdx,%rcx
  sub    %rcx,%rax
  ret
```

assistant: ```c
struct timespec nsec_to_timespec(long int nsec) {
  struct timespec temp;
  temp.tv_nsec = nsec % 1000000000L;
  temp.tv_sec = nsec / 1000000000L;
  return temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nsec_to_timespec>:
  endbr64
  movabs $0x112e0be826d694b3,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x1a,%rdx
  sub    %rax,%rdx
  mov    %rdi,%rax
  imul   $0x3b9aca00,%rdx,%rcx
  sub    %rcx,%rax
  ret
```

assistant: ```c
struct timespec nsec_to_timespec(long int nsec) {
  struct timespec temp;
  temp.tv_nsec = nsec % 1000000000L;
  temp.tv_sec = nsec / 1000000000L;
  return temp;
}
```