ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reopen_pipe>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%edi
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  call   <close_pipe@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <open_pipe@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int reopen_pipe(const char *p_path, int curr_fd, fd_set *p_rset) {
  int fifod;
  close_pipe(curr_fd, p_rset);
  fifod = open_pipe(p_path, p_rset);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reopen_pipe>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  mov    %rdx,%rsi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <close_pipe@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <open_pipe@plt>
```

assistant: ```c
int reopen_pipe(const char *p_path, int curr_fd, fd_set *p_rset) {
  int fifod;
  close_pipe(curr_fd, p_rset);
  fifod = open_pipe(p_path, p_rset);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reopen_pipe>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  mov    %rdx,%rsi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <close_pipe@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <open_pipe@plt>
```

assistant: ```c
int reopen_pipe(const char *p_path, int curr_fd, fd_set *p_rset) {
  int fifod;
  close_pipe(curr_fd, p_rset);
  fifod = open_pipe(p_path, p_rset);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getarraymin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L21
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L21:
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x9,-0x4(%rbp)
  jle    L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getarraymin(int arr[]) {
  int min = arr[0];
  for (int i = 0; i < 10; ++i) {
    if (arr[i] < min) {
      min = arr[i];
    }
  }
  return min;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getarraymin>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rax
  add    $0x28,%rdi
L4:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L4
  mov    %edx,%eax
  ret
```

assistant: ```c
int getarraymin(int arr[]) {
  int min = arr[0];
  for (int i = 0; i < 10; ++i) {
    if (arr[i] < min) {
      min = arr[i];
    }
  }
  return min;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getarraymin>:
  endbr64
  mov    (%rdi),%r8d
  lea    0x4(%rdi),%rax
  add    $0x28,%rdi
  mov    %r8d,%edx
  jmp    L18
  nopl   0x0(%rax)
L8:
  mov    (%rax),%edx
  add    $0x4,%rax
L18:
  cmp    %edx,%r8d
  cmovg  %edx,%r8d
  cmp    %rdi,%rax
  jne    L8
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getarraymin(int arr[]) {
  int min = arr[0];
  for (int i = 0; i < 10; ++i) {
    if (arr[i] < min) {
      min = arr[i];
    }
  }
  return min;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getarraymin>:
  endbr64
  movd   (%rdi),%xmm3
  movdqu 0x10(%rdi),%xmm0
  movdqu 0x10(%rdi),%xmm4
  movdqu (%rdi),%xmm5
  pshufd $0x0,%xmm3,%xmm1
  mov    0x20(%rdi),%eax
  mov    0x24(%rdi),%ecx
  pcmpgtd %xmm1,%xmm0
  movdqa %xmm5,%xmm2
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  pand   %xmm0,%xmm1
  pandn  %xmm4,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm5,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x8,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int getarraymin(int arr[]) {
  int min = arr[0];
  for (int i = 0; i < 10; ++i) {
    if (arr[i] < min) {
      min = arr[i];
    }
  }
  return min;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<simpsons38>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  fldt   0x20(%rbp)
  fldt   0x10(%rbp)
  fsubrp %st,%st(1)
  fildl  -0x2c(%rbp)
  fdivrp %st,%st(1)
  fstpt  -0x10(%rbp)
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    -0x28(%rbp),%rax
  call   *%rax
  add    $0x10,%rsp
  fstpt  -0x40(%rbp)
  push   0x28(%rbp)
  push   0x20(%rbp)
  mov    -0x28(%rbp),%rax
  call   *%rax
  add    $0x10,%rsp
  fldt   -0x40(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x20(%rbp)
  jmp    L6
L17:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x40(%rbp)
  fildl  -0x40(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    -0x28(%rbp),%rax
  call   *%rax
  add    $0x10,%rsp
  fstpt  -0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x30(%rbp)
  fildl  -0x30(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    -0x28(%rbp),%rax
  call   *%rax
  add    $0x10,%rsp
  fldt   -0x40(%rbp)
  faddp  %st,%st(1)
  fldt   0xe60(%rip)        # 2000 <_fini+0xd9c>
  fmulp  %st,%st(1)
  fstpt  -0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x3,%eax
  mov    %eax,-0x30(%rbp)
  fildl  -0x30(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    -0x28(%rbp),%rax
  call   *%rax
  add    $0x10,%rsp
  fadd   %st(0),%st
  fldt   -0x40(%rbp)
  faddp  %st,%st(1)
  fldt   -0x20(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x20(%rbp)
  subl   $0x3,-0x2c(%rbp)
L6:
  cmpl   $0x3,-0x2c(%rbp)
  jne    L17
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x40(%rbp)
  fildl  -0x40(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    -0x28(%rbp),%rax
  call   *%rax
  add    $0x10,%rsp
  fstpt  -0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x30(%rbp)
  fildl  -0x30(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    -0x28(%rbp),%rax
  call   *%rax
  add    $0x10,%rsp
  fldt   -0x40(%rbp)
  faddp  %st,%st(1)
  fldt   0xdc7(%rip)        # 2000 <_fini+0xd9c>
  fmulp  %st,%st(1)
  fldt   -0x20(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x20(%rbp)
  fldt   -0x10(%rbp)
  fldt   0xdb4(%rip)        # 2000 <_fini+0xd9c>
  fmulp  %st,%st(1)
  fldt   0xdbc(%rip)        # 2010 <_fini+0xdac>
  fdivrp %st,%st(1)
  fldt   -0x20(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x20(%rbp)
  fldt   -0x20(%rbp)
  leave
  ret
```

assistant: ```c
long double simpsons38(long double (*f)(long double), long double a, long double b, int n) {
  long double h = (b - a) / n;
  long double sum = f(a) + f(b);
  while (n - 3) {
    sum += ((3 * (f((n - 1) * h) + f((n - 2) * h))) + 2 * f((n - 3) * h));
    n = n - 3;
  }
  sum += (3 * (f((n - 1) * h) + f((n - 2) * h)));
  return sum *= ((3 * h) / 8);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<simpsons38>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbp
  fldt   0x80(%rsp)
  mov    %esi,%ebx
  fldt   0x90(%rsp)
  fsub   %st(1),%st
  mov    %esi,0x10(%rsp)
  fildl  0x10(%rsp)
  fdivrp %st,%st(1)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   *%rdi
  fstpt  0x20(%rsp)
  push   0x98(%rsp)
  push   0x98(%rsp)
  call   *%rbp
  fldt   0x30(%rsp)
  faddp  %st,%st(1)
  fstpt  0x30(%rsp)
  add    $0x20,%rsp
  cmp    $0x3,%ebx
  je     L6
L5:
  lea    -0x1(%rbx),%eax
  mov    %eax,0x20(%rsp)
  fildl  0x20(%rsp)
  fldt   (%rsp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   *%rbp
  fstpt  0x30(%rsp)
  lea    -0x2(%rbx),%eax
  mov    %eax,0x40(%rsp)
  fildl  0x40(%rsp)
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   *%rbp
  fstpt  0x50(%rsp)
  sub    $0x3,%ebx
  add    $0x10,%rsp
  mov    %ebx,0x5c(%rsp)
  fildl  0x5c(%rsp)
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  fldt   0x30(%rsp)
  fldt   0x40(%rsp)
  faddp  %st,%st(1)
  fmuls  0xe43(%rip)        # 2000 <_fini+0xde0>
  fxch   %st(1)
  fadd   %st(0),%st
  faddp  %st,%st(1)
  fldt   0x20(%rsp)
  faddp  %st,%st(1)
  fstpt  0x20(%rsp)
  add    $0x10,%rsp
  cmp    $0x3,%ebx
  jne    L5
L6:
  fldt   (%rsp)
  fld    %st(0)
  faddp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   *%rbp
  fstpt  0x30(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   *%rbp
  fldt   0x40(%rsp)
  faddp  %st,%st(1)
  flds   0xdff(%rip)        # 2000 <_fini+0xde0>
  fmul   %st,%st(1)
  fldt   0x30(%rsp)
  faddp  %st,%st(2)
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fmuls  0xdef(%rip)        # 2004 <_fini+0xde4>
  fmulp  %st,%st(1)
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long double simpsons38(long double (*f)(long double), long double a, long double b, int n) {
  long double h = (b - a) / n;
  long double sum = f(a) + f(b);
  while (n - 3) {
    sum += ((3 * (f((n - 1) * h) + f((n - 2) * h))) + 2 * f((n - 3) * h));
    n = n - 3;
  }
  sum += (3 * (f((n - 1) * h) + f((n - 2) * h)));
  return sum *= ((3 * h) / 8);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<simpsons38>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x78,%rsp
  fldt   0x90(%rsp)
  mov    %esi,0x10(%rsp)
  fldt   0xa0(%rsp)
  fsub   %st(1),%st
  fildl  0x10(%rsp)
  fdivrp %st,%st(1)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   *%rdi
  fstpt  0x20(%rsp)
  push   0xa8(%rsp)
  push   0xa8(%rsp)
  call   *%rbp
  fldt   0x30(%rsp)
  add    $0x20,%rsp
  faddp  %st,%st(1)
  cmp    $0x3,%ebx
  je     L5
  movss  D9(%rip),%xmm0
  movss  %xmm0,0x5c(%rsp)
  nopw   0x0(%rax,%rax,1)
L6:
  lea    -0x1(%rbx),%eax
  fstpt  0x40(%rsp)
  sub    $0x10,%rsp
  mov    %eax,0x20(%rsp)
  fildl  0x20(%rsp)
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  lea    -0x2(%rbx),%eax
  sub    $0x10,%rsp
  sub    $0x3,%ebx
  fstpt  0x50(%rsp)
  mov    %eax,0x30(%rsp)
  fildl  0x30(%rsp)
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  fstpt  0x40(%rsp)
  pop    %rax
  pop    %rdx
  mov    %ebx,0x20(%rsp)
  fildl  0x20(%rsp)
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  fldt   0x30(%rsp)
  fldt   0x40(%rsp)
  faddp  %st,%st(1)
  fmuls  0x6c(%rsp)
  fxch   %st(1)
  fadd   %st(0),%st
  faddp  %st,%st(1)
  fldt   0x50(%rsp)
  pop    %rcx
  pop    %rsi
  faddp  %st,%st(1)
  cmp    $0x3,%ebx
  jne    L6
L29:
  fstpt  0x20(%rsp)
  fldt   (%rsp)
  sub    $0x10,%rsp
  fld    %st(0)
  faddp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  fstpt  0x20(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   *%rbp
  fldt   0x30(%rsp)
  faddp  %st,%st(1)
  flds   0x7c(%rsp)
  fmul   %st,%st(1)
  fldt   0x40(%rsp)
  faddp  %st,%st(2)
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fmuls  0xddb(%rip)        # 2004 <_fini+0xdbc>
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  fmulp  %st,%st(1)
  ret
  nopl   (%rax)
L5:
  movss  D9(%rip),%xmm1
  movss  %xmm1,0x5c(%rsp)
  jmp    L29
```

tool_calls: name: parse_data
arguments: tag: D9
type: byte[4]

tool: {"D9": [0x00,0x00,0x40,0x40]}

assistant: ```c
long double simpsons38(long double (*f)(long double), long double a, long double b, int n) {
  long double h = (b - a) / n;
  long double sum = f(a) + f(b);
  while (n - 3) {
    sum += ((3 * (f((n - 1) * h) + f((n - 2) * h))) + 2 * f((n - 3) * h));
    n = n - 3;
  }
  sum += (3 * (f((n - 1) * h) + f((n - 2) * h)));
  return sum *= ((3 * h) / 8);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simpsons38>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x78,%rsp
  fldt   0x90(%rsp)
  mov    %esi,0x10(%rsp)
  fldt   0xa0(%rsp)
  fsub   %st(1),%st
  fildl  0x10(%rsp)
  fdivrp %st,%st(1)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   *%rdi
  fstpt  0x20(%rsp)
  push   0xa8(%rsp)
  push   0xa8(%rsp)
  call   *%rbp
  fldt   0x30(%rsp)
  add    $0x20,%rsp
  faddp  %st,%st(1)
  cmp    $0x3,%ebx
  je     L24
  movss  D9(%rip),%xmm0
  movss  %xmm0,0x5c(%rsp)
  nopw   0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rbx),%eax
  fstpt  0x40(%rsp)
  sub    $0x10,%rsp
  mov    %eax,0x20(%rsp)
  fildl  0x20(%rsp)
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  lea    -0x2(%rbx),%eax
  sub    $0x10,%rsp
  sub    $0x3,%ebx
  fstpt  0x50(%rsp)
  mov    %eax,0x30(%rsp)
  fildl  0x30(%rsp)
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  fstpt  0x40(%rsp)
  pop    %rax
  pop    %rdx
  mov    %ebx,0x20(%rsp)
  fildl  0x20(%rsp)
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  fldt   0x30(%rsp)
  fldt   0x40(%rsp)
  faddp  %st,%st(1)
  fmuls  0x6c(%rsp)
  fxch   %st(1)
  fadd   %st(0),%st
  faddp  %st,%st(1)
  fldt   0x50(%rsp)
  pop    %rcx
  pop    %rsi
  faddp  %st,%st(1)
  cmp    $0x3,%ebx
  jne    L19
L15:
  fstpt  0x20(%rsp)
  fldt   (%rsp)
  sub    $0x10,%rsp
  fld    %st(0)
  faddp  %st,%st(1)
  fstpt  (%rsp)
  call   *%rbp
  fstpt  0x20(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   *%rbp
  fldt   0x30(%rsp)
  faddp  %st,%st(1)
  flds   0x7c(%rsp)
  fmul   %st,%st(1)
  fldt   0x40(%rsp)
  faddp  %st,%st(2)
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fmuls  0xddb(%rip)        # 2004 <_fini+0xdbc>
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  fmulp  %st,%st(1)
  ret
  nopl   (%rax)
L24:
  movss  D9(%rip),%xmm1
  movss  %xmm1,0x5c(%rsp)
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D9
type: byte[4]

tool: {"D9": [0x00,0x00,0x40,0x40]}

assistant: ```c
long double simpsons38(long double (*f)(long double), long double a, long double b, int n) {
  long double h = (b - a) / n;
  long double sum = f(a) + f(b);
  while (n - 3) {
    sum += ((3 * (f((n - 1) * h) + f((n - 2) * h))) + 2 * f((n - 3) * h));
    n = n - 3;
  }
  sum += (3 * (f((n - 1) * h) + f((n - 2) * h)));
  return sum *= ((3 * h) / 8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<randomi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x10(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    D8(%rip),%rdx
  mov    (%rdx),%ecx
  cltd
  idiv   %ecx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L26
L4:
  mov    $0x1,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
unsigned int randomi(int *value) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) == 0) {
    unsigned int usec = (unsigned int)(tv.tv_usec);
    srand(usec);
    *value = rand() % INT_MAX;
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<randomi>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L13
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L13:
  mov    (%rsp),%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    D2(%rip),%rcx
  cltd
  idivl  (%rcx)
  mov    %edx,(%rbx)
  mov    $0x0,%eax
  jmp    L3
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int randomi(int *value) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) == 0) {
    unsigned int usec = (unsigned int)(tv.tv_usec);
    srand(usec);
    *value = rand() % INT_MAX;
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<randomi>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L19
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L19:
  mov    (%rsp),%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    D6(%rip),%rcx
  cltd
  idivl  (%rcx)
  xor    %eax,%eax
  mov    %edx,(%rbx)
  jmp    L4
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int randomi(int *value) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) == 0) {
    unsigned int usec = (unsigned int)(tv.tv_usec);
    srand(usec);
    *value = rand() % INT_MAX;
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<randomi>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L2
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  mov    (%rsp),%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    D5(%rip),%rcx
  cltd
  idivl  (%rcx)
  xor    %eax,%eax
  mov    %edx,(%rbx)
  jmp    L14
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int randomi(int *value) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) == 0) {
    unsigned int usec = (unsigned int)(tv.tv_usec);
    srand(usec);
    *value = rand() % INT_MAX;
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<spacetounderscore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L14
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L23
  mov    -0x8(%rbp),%rax
  movb   $0x5f,(%rax)
L23:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void spacetounderscore(char *s) {
  for (; '\0' != *s; s++)
    if (' ' == *s)
      *s = '_';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<spacetounderscore>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L21
L1:
  ret
L36:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
L21:
  cmp    $0x20,%al
  jne    L36
  movb   $0x5f,(%rdi)
  jmp    L36
```

assistant: ```c
void spacetounderscore(char *s) {
  for (; '\0' != *s; s++)
    if (' ' == *s)
      *s = '_';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<spacetounderscore>:
  endbr64
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L1:
  cmp    $0x20,%al
  jne    L11
  movb   $0x5f,(%rdi)
L11:
  add    $0x1,%rdi
L14:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L1
  ret
```

assistant: ```c
void spacetounderscore(char *s) {
  for (; '\0' != *s; s++)
    if (' ' == *s)
      *s = '_';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<spacetounderscore>:
  endbr64
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x1,%rdi
L14:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
L3:
  cmp    $0x20,%al
  jne    L9
  movb   $0x5f,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L3
  ret
  nop
L28:
  ret
```

assistant: ```c
void spacetounderscore(char *s) {
  for (; '\0' != *s; s++)
    if (' ' == *s)
      *s = '_';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L104
L26:
  movl   $0x0,-0x34(%rbp)
  jmp    L105
L109:
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L105:
  cmpl   $0x4,-0x34(%rbp)
  jle    L109
  mov    -0x30(%rbp),%eax
  cmp    $0x1,%eax
  jne    L10
  mov    -0x2c(%rbp),%eax
  cmp    $0x2,%eax
  jne    L10
  mov    -0x28(%rbp),%eax
  cmp    $0x3,%eax
  jne    L10
  mov    -0x24(%rbp),%eax
  cmp    $0x4,%eax
  jne    L10
  mov    -0x20(%rbp),%eax
  cmp    $0x5,%eax
  jne    L10
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L10:
  mov    -0x30(%rbp),%eax
  cmp    $0x2,%eax
  jne    L126
  mov    -0x2c(%rbp),%eax
  cmp    $0x3,%eax
  jne    L126
  mov    -0x28(%rbp),%eax
  cmp    $0x4,%eax
  jne    L126
  mov    -0x24(%rbp),%eax
  cmp    $0x5,%eax
  jne    L126
  mov    -0x20(%rbp),%eax
  cmp    $0x6,%eax
  jne    L126
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L126:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  addl   $0x1,-0x38(%rbp)
L104:
  mov    -0x3c(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L139
  call   <__stack_chk_fail@plt>
L139:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D47
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string

tool: D25: %d

tool: D47: Y


tool: D27: N


assistant: ```c
int main() {
  int t, ara[10], i, j;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    for (j = 0; j < 5; j++) {
      scanf("%d", &ara[j]);
    }
    if (ara[0] == 1 && ara[1] == 2 && ara[2] == 3 && ara[3] == 4 && ara[4] == 5)
      printf("Y\n");
    else if (ara[0] == 2 && ara[1] == 3 && ara[2] == 4 && ara[3] == 5 && ara[4] == 6)
      printf("Y\n");
    else
      printf("N\n");
  }
  return 0;
}
```