ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  D0(%rip),%xmm0
  addsd  D9(%rip),%xmm0
  addsd  D24(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: f64
name: unpack_data
arguments: data_label: D9
datatype: f64
name: unpack_data
arguments: data_label: D24
datatype: f64

tool: D0: 5

tool: D9: 1

tool: D24: 4

assistant: ```c
double foo(double a, double b, double c) {
  double arr[5] = {1., 2., 3., 4., 5.};
  double d = 4.;
  double *p = &d;
  return a + b + c + arr[4] + arr[0] + *p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<writeword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <writebyte@plt>
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <writebyte@plt>
  nop
  leave
  ret
```

assistant: ```c
void writeword(unsigned int i, FILE *fp) {
  writebyte(i % 256, fp);
  writebyte(i / 256, fp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writeword>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  movzbl %dil,%edi
  call   <writebyte@plt>
  shr    $0x8,%ebx
  mov    %ebx,%edi
  mov    %rbp,%rsi
  call   <writebyte@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void writeword(unsigned int i, FILE *fp) {
  writebyte(i % 256, fp);
  writebyte(i / 256, fp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<writeword>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  movzbl %dil,%edi
  shr    $0x8,%ebx
  sub    $0x8,%rsp
  call   <writebyte@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <writebyte@plt>
```

assistant: ```c
void writeword(unsigned int i, FILE *fp) {
  writebyte(i % 256, fp);
  writebyte(i / 256, fp);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<writeword>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  movzbl %dil,%edi
  shr    $0x8,%ebx
  sub    $0x8,%rsp
  call   <writebyte@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <writebyte@plt>
```

assistant: ```c
void writeword(unsigned int i, FILE *fp) {
  writebyte(i % 256, fp);
  writebyte(i / 256, fp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <test1@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main(void) {
  int b;
  printf("%d\n", b);
  b = test();
  printf("%d\n", b);
  test1(b);
  printf("%d\n", b);
  test();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <test1@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: %d


assistant: ```c
int main(void) {
  int b;
  printf("%d\n", b);
  b = test();
  printf("%d\n", b);
  test1(b);
  printf("%d\n", b);
  test();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  xor    %esi,%esi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  call   <test@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <test1@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <test@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(void) {
  int b;
  printf("%d\n", b);
  b = test();
  printf("%d\n", b);
  test1(b);
  printf("%d\n", b);
  test();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  xor    %esi,%esi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  call   <test@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <test1@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <test@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: %d


assistant: ```c
int main(void) {
  int b;
  printf("%d\n", b);
  b = test();
  printf("%d\n", b);
  test1(b);
  printf("%d\n", b);
  test();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<exercicio1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x66,%edi
  call   <criar_arvore@plt>
  mov    %rax,-0x30(%rbp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x64,%edi
  call   <criar_arvore@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x65,%edi
  call   <criar_arvore@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x62,%edi
  call   <criar_arvore@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x63,%edi
  call   <criar_arvore@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x61,%edi
  call   <criar_arvore@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <imprime_arvore@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <libera_arvore@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: 
fim.


assistant: ```c
void exercicio1() {
  struct arvore *arv1, *arv2, *arv3, *arv4, *arv5, *arv6;
  arv1 = criar_arvore('f', NULL, NULL);
  arv2 = criar_arvore('d', NULL, NULL);
  arv3 = criar_arvore('e', NULL, NULL);
  arv4 = criar_arvore('b', NULL, arv2);
  arv5 = criar_arvore('c', arv3, arv1);
  arv6 = criar_arvore('a', arv4, arv5);
  imprime_arvore(arv6);
  libera_arvore((void *)arv6);
  printf("\nfim.\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exercicio1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x66,%edi
  call   <criar_arvore@plt>
  mov    %rax,%r12
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x64,%edi
  call   <criar_arvore@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x65,%edi
  call   <criar_arvore@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    $0x62,%edi
  call   <criar_arvore@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x63,%edi
  call   <criar_arvore@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    $0x61,%edi
  call   <criar_arvore@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <imprime_arvore@plt>
  mov    %rbx,%rdi
  call   <libera_arvore@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: 
fim.


assistant: ```c
void exercicio1() {
  struct arvore *arv1, *arv2, *arv3, *arv4, *arv5, *arv6;
  arv1 = criar_arvore('f', NULL, NULL);
  arv2 = criar_arvore('d', NULL, NULL);
  arv3 = criar_arvore('e', NULL, NULL);
  arv4 = criar_arvore('b', NULL, arv2);
  arv5 = criar_arvore('c', arv3, arv1);
  arv6 = criar_arvore('a', arv4, arv5);
  imprime_arvore(arv6);
  libera_arvore((void *)arv6);
  printf("\nfim.\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exercicio1>:
  endbr64
  push   %r14
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x66,%edi
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <criar_arvore@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x64,%edi
  mov    %rax,%r13
  call   <criar_arvore@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x65,%edi
  mov    %rax,%r14
  call   <criar_arvore@plt>
  mov    %r14,%rdx
  xor    %esi,%esi
  mov    $0x62,%edi
  mov    %rax,%r12
  call   <criar_arvore@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x63,%edi
  mov    %rax,%rbp
  call   <criar_arvore@plt>
  mov    %rbp,%rsi
  mov    $0x61,%edi
  mov    %rax,%rdx
  call   <criar_arvore@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <imprime_arvore@plt>
  mov    %rbp,%rdi
  call   <libera_arvore@plt>
  add    $0x8,%rsp
  lea    D3(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: 
fim.


assistant: ```c
void exercicio1() {
  struct arvore *arv1, *arv2, *arv3, *arv4, *arv5, *arv6;
  arv1 = criar_arvore('f', NULL, NULL);
  arv2 = criar_arvore('d', NULL, NULL);
  arv3 = criar_arvore('e', NULL, NULL);
  arv4 = criar_arvore('b', NULL, arv2);
  arv5 = criar_arvore('c', arv3, arv1);
  arv6 = criar_arvore('a', arv4, arv5);
  imprime_arvore(arv6);
  libera_arvore((void *)arv6);
  printf("\nfim.\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<exercicio1>:
  endbr64
  push   %r14
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x66,%edi
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <criar_arvore@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x64,%edi
  mov    %rax,%r13
  call   <criar_arvore@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x65,%edi
  mov    %rax,%r14
  call   <criar_arvore@plt>
  mov    %r14,%rdx
  xor    %esi,%esi
  mov    $0x62,%edi
  mov    %rax,%r12
  call   <criar_arvore@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x63,%edi
  mov    %rax,%rbp
  call   <criar_arvore@plt>
  mov    %rbp,%rsi
  mov    $0x61,%edi
  mov    %rax,%rdx
  call   <criar_arvore@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <imprime_arvore@plt>
  mov    %rbp,%rdi
  call   <libera_arvore@plt>
  add    $0x8,%rsp
  lea    D6(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: 
fim.


assistant: ```c
void exercicio1() {
  struct arvore *arv1, *arv2, *arv3, *arv4, *arv5, *arv6;
  arv1 = criar_arvore('f', NULL, NULL);
  arv2 = criar_arvore('d', NULL, NULL);
  arv3 = criar_arvore('e', NULL, NULL);
  arv4 = criar_arvore('b', NULL, arv2);
  arv5 = criar_arvore('c', arv3, arv1);
  arv6 = criar_arvore('a', arv4, arv5);
  imprime_arvore(arv6);
  libera_arvore((void *)arv6);
  printf("\nfim.\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L9
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <log@plt>
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L15
L9:
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <log@plt>
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L15:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double log_sum(double log_a, double log_b) {
  double v;
  if (log_a < log_b) {
    v = log_b + log(1 + exp(log_a - log_b));
  } else {
    v = log_a + log(1 + exp(log_b - log_a));
  }
  return (v);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log_sum>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  comisd %xmm0,%xmm1
  jbe    L12
  subsd  %xmm1,%xmm0
  call   <exp@plt>
  lea    0x1(%rax),%rdi
  call   <log@plt>
  addsd  (%rsp),%xmm0
L2:
  add    $0x18,%rsp
  ret
L12:
  movsd  (%rsp),%xmm0
  subsd  0x8(%rsp),%xmm0
  call   <exp@plt>
  lea    0x1(%rax),%rdi
  call   <log@plt>
  addsd  0x8(%rsp),%xmm0
  jmp    L2
```

assistant: ```c
double log_sum(double log_a, double log_b) {
  double v;
  if (log_a < log_b) {
    v = log_b + log(1 + exp(log_a - log_b));
  } else {
    v = log_a + log(1 + exp(log_b - log_a));
  }
  return (v);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_sum>:
  endbr64
  sub    $0x18,%rsp
  comisd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  jbe    L9
  subsd  %xmm1,%xmm2
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <exp@plt>
  lea    0x1(%rax),%rdi
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  addsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L9:
  subsd  %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  lea    0x1(%rax),%rdi
  call   <log@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  addsd  %xmm2,%xmm0
  ret
```

assistant: ```c
double log_sum(double log_a, double log_b) {
  double v;
  if (log_a < log_b) {
    v = log_b + log(1 + exp(log_a - log_b));
  } else {
    v = log_a + log(1 + exp(log_b - log_a));
  }
  return (v);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<log_sum>:
  endbr64
  sub    $0x18,%rsp
  comisd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  jbe    L0
  subsd  %xmm1,%xmm2
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <exp@plt>
  lea    0x1(%rax),%rdi
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  addsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L0:
  subsd  %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  lea    0x1(%rax),%rdi
  call   <log@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  addsd  %xmm2,%xmm0
  ret
```

assistant: ```c
double log_sum(double log_a, double log_b) {
  double v;
  if (log_a < log_b) {
    v = log_b + log(1 + exp(log_a - log_b));
  } else {
    v = log_a + log(1 + exp(log_b - log_a));
  }
  return (v);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<extract_type_2_socket_inode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jl     L55
  mov    -0x30(%rbp),%rax
  movq   $0xffffffffffffffff,(%rax)
  jmp    L83
L55:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L73
  mov    -0x30(%rbp),%rax
  movq   $0xffffffffffffffff,(%rax)
  jmp    L83
L73:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strtol@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L69
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L69
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  js     L69
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0xffff,%rax
  jle    L83
L69:
  mov    -0x30(%rbp),%rax
  movq   $0xffffffffffffffff,(%rax)
L83:
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type: string

tool: D13: [0000]:

assistant: ```c
void extract_type_2_socket_inode(const char lname[], long *inode_p) {
  if (strlen(lname) < (strlen("[0000]:")) + 1)
    *inode_p = -1;
  else if (memcmp(lname, "[0000]:", (strlen("[0000]:"))))
    *inode_p = -1;
  else {
    char *serr;
    *inode_p = strtol(lname + (strlen("[0000]:")), &serr, 0);
    if (!serr || *serr || *inode_p < 0 || *inode_p > 65535)
      *inode_p = -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<extract_type_2_socket_inode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebp
  jl     L41
  movq   $0xffffffffffffffff,(%r12)
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L0
  movq   $0xffffffffffffffff,(%r12)
  jmp    L64
L0:
  lea    D5(%rip),%rdi
  call   <strlen@plt>
  mov    %rsp,%rsi
  cltq
  lea    (%rbx,%rax,1),%rdi
  mov    $0x0,%edx
  call   <strtol@plt>
  mov    %rax,(%r12)
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  je     L63
  cmpb   $0x0,(%rdx)
  jne    L63
  cmp    $0xffff,%rax
  jbe    L64
L63:
  movq   $0xffffffffffffffff,(%r12)
  jmp    L64
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: [0000]:

assistant: ```c
void extract_type_2_socket_inode(const char lname[], long *inode_p) {
  if (strlen(lname) < (strlen("[0000]:")) + 1)
    *inode_p = -1;
  else if (memcmp(lname, "[0000]:", (strlen("[0000]:"))))
    *inode_p = -1;
  else {
    char *serr;
    *inode_p = strtol(lname + (strlen("[0000]:")), &serr, 0);
    if (!serr || *serr || *inode_p < 0 || *inode_p > 65535)
      *inode_p = -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<extract_type_2_socket_inode>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  cmp    %eax,%ebp
  jl     L18
L15:
  movq   $0xffffffffffffffff,0x0(%r13)
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L18:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L15
  mov    %r12,%rdi
  call   <strlen@plt>
  xor    %edx,%edx
  mov    %rsp,%rsi
  cltq
  lea    (%rbx,%rax,1),%rdi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  mov    %rax,0x0(%r13)
  test   %rdx,%rdx
  je     L15
  cmpb   $0x0,(%rdx)
  jne    L15
  cmp    $0xffff,%rax
  ja     L15
  jmp    L35
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: [0000]:

assistant: ```c
void extract_type_2_socket_inode(const char lname[], long *inode_p) {
  if (strlen(lname) < (strlen("[0000]:")) + 1)
    *inode_p = -1;
  else if (memcmp(lname, "[0000]:", (strlen("[0000]:"))))
    *inode_p = -1;
  else {
    char *serr;
    *inode_p = strtol(lname + (strlen("[0000]:")), &serr, 0);
    if (!serr || *serr || *inode_p < 0 || *inode_p > 65535)
      *inode_p = -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<extract_type_2_socket_inode>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  cmp    %eax,%ebp
  jl     L50
L4:
  movq   $0xffffffffffffffff,0x0(%r13)
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L50:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L4
  mov    %r12,%rdi
  call   <strlen@plt>
  xor    %edx,%edx
  mov    %rsp,%rsi
  cltq
  lea    (%rbx,%rax,1),%rdi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  mov    %rax,0x0(%r13)
  test   %rdx,%rdx
  je     L4
  cmpb   $0x0,(%rdx)
  jne    L4
  cmp    $0xffff,%rax
  ja     L4
  jmp    L53
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
data_type: string

tool: D7: [0000]:

assistant: ```c
void extract_type_2_socket_inode(const char lname[], long *inode_p) {
  if (strlen(lname) < (strlen("[0000]:")) + 1)
    *inode_p = -1;
  else if (memcmp(lname, "[0000]:", (strlen("[0000]:"))))
    *inode_p = -1;
  else {
    char *serr;
    *inode_p = strtol(lname + (strlen("[0000]:")), &serr, 0);
    if (!serr || *serr || *inode_p < 0 || *inode_p > 65535)
      *inode_p = -1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L65
L68:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  mov    $0x0,%eax
  jmp    L29
L41:
  addl   $0x1,-0x4(%rbp)
L65:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L68
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L58
  mov    $0x1,%eax
  jmp    L29
L58:
  mov    $0xffffffffffffffff,%rax
L29:
  pop    %rbp
  ret
```

assistant: ```c
char *strcmp(char *s1, char *s2) {
  int i, j;
  for (i = 0; s1[i] == s2[i]; i++)
    if (s1[i] == '\0' && s2[i] == '\0')
      return 0;
  if (s1[i] > s2[i])
    return 1;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  cmp    %cl,%al
  jne    L9
  mov    $0x1,%edx
L26:
  or     %cl,%al
  je     L24
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  je     L26
L9:
  cmp    %cl,%al
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%rax
  ret
L24:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strcmp(char *s1, char *s2) {
  int i, j;
  for (i = 0; s1[i] == s2[i]; i++)
    if (s1[i] == '\0' && s2[i] == '\0')
      return 0;
  if (s1[i] > s2[i])
    return 1;
  return -1;
}
```