ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movaps D6(%rip),%xmm0
  mov    $0x4,%edi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movaps D14(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <stdlib_strided_smidrange@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type: f32[4]
name: read_data
arguments: label: D14
type: byte[16]
name: read_data
arguments: label: D4
type: string

tool: {"D6": [1.0,-2.0,-3.0,4.0]}

tool: {"D14": [0x00,0x00,0xa0,0xc0,0x00,0x00,0xc0,0xc0,0x00,0x00,0xe0,0x40,0x00,0x00,0x00,0x41]}

tool: D4: mid-range: %f


assistant: ```c
int main() {
  float x[] = {1.0, -2.0, -3.0, 4.0, -5.0, -6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  float v = stdlib_strided_smidrange(N, x, stride);
  printf("mid-range: %f\n", v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xmalloc(size_t size) {
  void *p = malloc(size);
  if (p == NULL) {
    ;
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *xmalloc(size_t size) {
  void *p = malloc(size);
  if (p == NULL) {
    ;
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xmalloc>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *xmalloc(size_t size) {
  void *p = malloc(size);
  if (p == NULL) {
    ;
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xmalloc>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *xmalloc(size_t size) {
  void *p = malloc(size);
  if (p == NULL) {
    ;
  }
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int my_close(int I_iFd) {
  int iRet;
  iRet = close(I_iFd);
  return iRet;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int my_close(int I_iFd) {
  int iRet;
  iRet = close(I_iFd);
  return iRet;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_close>:
  endbr64
  jmp    1050 <close@plt>
```

assistant: ```c
int my_close(int I_iFd) {
  int iRet;
  iRet = close(I_iFd);
  return iRet;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_close>:
  endbr64
  jmp    1050 <close@plt>
```

assistant: ```c
int my_close(int I_iFd) {
  int iRet;
  iRet = close(I_iFd);
  return iRet;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GIFCopyPixels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <ErrorGIFNotAvailable@plt>
  nop
  leave
  ret
```

assistant: ```c
void GIFCopyPixels(const struct WebPPicture *const src, struct WebPPicture *const dst) {
  (void)src;
  (void)dst;
  ErrorGIFNotAvailable();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GIFCopyPixels>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ErrorGIFNotAvailable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void GIFCopyPixels(const struct WebPPicture *const src, struct WebPPicture *const dst) {
  (void)src;
  (void)dst;
  ErrorGIFNotAvailable();
}
```
user: What is the c source code of the assembly code below:

```asm
<GIFCopyPixels>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <ErrorGIFNotAvailable@plt>
```

assistant: ```c
void GIFCopyPixels(const struct WebPPicture *const src, struct WebPPicture *const dst) {
  (void)src;
  (void)dst;
  ErrorGIFNotAvailable();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GIFCopyPixels>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <ErrorGIFNotAvailable@plt>
```

assistant: ```c
void GIFCopyPixels(const struct WebPPicture *const src, struct WebPPicture *const dst) {
  (void)src;
  (void)dst;
  ErrorGIFNotAvailable();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L1:
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  leave
  ret
```

assistant: ```c
char *ft_strdup(char *src) {
  char *dest;
  int len;
  len = 0;
  while (src[len])
    len++;
  dest = (char *)malloc(sizeof(*dest) * (len + 1));
  return (ft_strcpy(dest, src));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  je     L19
  mov    $0x1,%eax
L16:
  mov    %eax,%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  jne    L16
L10:
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <ft_strcpy@plt>
  pop    %rbx
  ret
L19:
  mov    $0x0,%edi
  jmp    L10
```

assistant: ```c
char *ft_strdup(char *src) {
  char *dest;
  int len;
  len = 0;
  while (src[len])
    len++;
  dest = (char *)malloc(sizeof(*dest) * (len + 1));
  return (ft_strcpy(dest, src));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L17
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %eax,%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbp,%rax,1)
  jne    L8
  add    $0x1,%edi
L19:
  call   <malloc@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1060 <ft_strcpy@plt>
  nopl   0x0(%rax)
L17:
  mov    $0x1,%edi
  jmp    L19
```

assistant: ```c
char *ft_strdup(char *src) {
  char *dest;
  int len;
  len = 0;
  while (src[len])
    len++;
  dest = (char *)malloc(sizeof(*dest) * (len + 1));
  return (ft_strcpy(dest, src));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L7
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %eax,%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbp,%rax,1)
  jne    L13
  add    $0x1,%edi
L26:
  call   <malloc@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1060 <ft_strcpy@plt>
  nopl   0x0(%rax)
L7:
  mov    $0x1,%edi
  jmp    L26
```

assistant: ```c
char *ft_strdup(char *src) {
  char *dest;
  int len;
  len = 0;
  while (src[len])
    len++;
  dest = (char *)malloc(sizeof(*dest) * (len + 1));
  return (ft_strcpy(dest, src));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_valid_item>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L9
  movl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_valid_item(int option, int num_items, int min_items) {
  int valid = 0;
  if ((option >= min_items) && (option <= num_items)) {
    valid = 1;
  }
  return valid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_valid_item>:
  endbr64
  cmp    %edx,%edi
  setge  %dl
  cmp    %esi,%edi
  setle  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int is_valid_item(int option, int num_items, int min_items) {
  int valid = 0;
  if ((option >= min_items) && (option <= num_items)) {
    valid = 1;
  }
  return valid;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_valid_item>:
  endbr64
  cmp    %edx,%edi
  setge  %dl
  xor    %eax,%eax
  cmp    %esi,%edi
  setle  %al
  and    %edx,%eax
  ret
```

assistant: ```c
int is_valid_item(int option, int num_items, int min_items) {
  int valid = 0;
  if ((option >= min_items) && (option <= num_items)) {
    valid = 1;
  }
  return valid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_valid_item>:
  endbr64
  cmp    %edx,%edi
  setge  %dl
  xor    %eax,%eax
  cmp    %esi,%edi
  setle  %al
  and    %edx,%eax
  ret
```

assistant: ```c
int is_valid_item(int option, int num_items, int min_items) {
  int valid = 0;
  if ((option >= min_items) && (option <= num_items)) {
    valid = 1;
  }
  return valid;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<e_xorri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L6
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L18
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <e_notr@plt>
  jmp    L19
L18:
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    $0x35,%ecx
  mov    $0x6,%edx
  mov    %eax,%edi
  call   <e_xxxri@plt>
  jmp    L19
L6:
  nop
L19:
  leave
  ret
```

assistant: ```c
void e_xorri(int r, int i) {
  if (i == 0)
    return;
  else if (i == ~0)
    e_notr(r);
  else
    e_xxxri(r, i, 6, 0x35);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<e_xorri>:
  endbr64
  test   %esi,%esi
  je     L19
  sub    $0x8,%rsp
  cmp    $0xffffffff,%esi
  je     L28
  mov    $0x35,%ecx
  mov    $0x6,%edx
  call   <e_xxxri@plt>
L6:
  add    $0x8,%rsp
  ret
L28:
  call   <e_notr@plt>
  jmp    L6
L19:
  ret
```

assistant: ```c
void e_xorri(int r, int i) {
  if (i == 0)
    return;
  else if (i == ~0)
    e_notr(r);
  else
    e_xxxri(r, i, 6, 0x35);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<e_xorri>:
  endbr64
  test   %esi,%esi
  je     L8
  cmp    $0xffffffff,%esi
  je     L11
  mov    $0x35,%ecx
  mov    $0x6,%edx
  jmp    1070 <e_xxxri@plt>
  nopl   0x0(%rax)
L11:
  jmp    1060 <e_notr@plt>
  nopl   (%rax)
L8:
  ret
```

assistant: ```c
void e_xorri(int r, int i) {
  if (i == 0)
    return;
  else if (i == ~0)
    e_notr(r);
  else
    e_xxxri(r, i, 6, 0x35);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<e_xorri>:
  endbr64
  test   %esi,%esi
  je     L7
  cmp    $0xffffffff,%esi
  je     L13
  mov    $0x35,%ecx
  mov    $0x6,%edx
  jmp    1070 <e_xxxri@plt>
  nopl   0x0(%rax)
L13:
  jmp    1060 <e_notr@plt>
  nopl   (%rax)
L7:
  ret
```

assistant: ```c
void e_xorri(int r, int i) {
  if (i == 0)
    return;
  else if (i == ~0)
    e_notr(r);
  else
    e_xxxri(r, i, 6, 0x35);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DSA_sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <DSA_do_sign@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L5
L0:
  lea    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <i2d_DSA_SIG@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <DSA_SIG_free@plt>
  mov    $0x1,%eax
L5:
  leave
  ret
```

assistant: ```c
int DSA_sign(int type, const unsigned char *dgst, int dlen, unsigned char *sig, unsigned int *siglen, DSA *dsa) {
  DSA_SIG *s;
  s = DSA_do_sign(dgst, dlen, dsa);
  if (s == NULL) {
    *siglen = 0;
    return (0);
  }
  *siglen = i2d_DSA_SIG(s, &sig);
  DSA_SIG_free(s);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DSA_sign>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %rcx,0x8(%rsp)
  mov    %r8,%rbp
  mov    %r9,%rdx
  call   <DSA_do_sign@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbx
  lea    0x8(%rsp),%rsi
  mov    %rax,%rdi
  call   <i2d_DSA_SIG@plt>
  mov    %eax,0x0(%rbp)
  mov    %rbx,%rdi
  call   <DSA_SIG_free@plt>
  mov    $0x1,%eax
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  movl   $0x0,0x0(%rbp)
  mov    $0x0,%eax
  jmp    L7
```

assistant: ```c
int DSA_sign(int type, const unsigned char *dgst, int dlen, unsigned char *sig, unsigned int *siglen, DSA *dsa) {
  DSA_SIG *s;
  s = DSA_do_sign(dgst, dlen, dsa);
  if (s == NULL) {
    *siglen = 0;
    return (0);
  }
  *siglen = i2d_DSA_SIG(s, &sig);
  DSA_SIG_free(s);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DSA_sign>:
  endbr64
  push   %rbp
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %r9,%rdx
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  call   <DSA_do_sign@plt>
  test   %rax,%rax
  je     L0
  lea    0x8(%rsp),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <i2d_DSA_SIG@plt>
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  call   <DSA_SIG_free@plt>
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  movl   $0x0,(%rbx)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int DSA_sign(int type, const unsigned char *dgst, int dlen, unsigned char *sig, unsigned int *siglen, DSA *dsa) {
  DSA_SIG *s;
  s = DSA_do_sign(dgst, dlen, dsa);
  if (s == NULL) {
    *siglen = 0;
    return (0);
  }
  *siglen = i2d_DSA_SIG(s, &sig);
  DSA_SIG_free(s);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DSA_sign>:
  endbr64
  push   %rbp
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %r9,%rdx
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  call   <DSA_do_sign@plt>
  test   %rax,%rax
  je     L2
  lea    0x8(%rsp),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <i2d_DSA_SIG@plt>
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  call   <DSA_SIG_free@plt>
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movl   $0x0,(%rbx)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int DSA_sign(int type, const unsigned char *dgst, int dlen, unsigned char *sig, unsigned int *siglen, DSA *dsa) {
  DSA_SIG *s;
  s = DSA_do_sign(dgst, dlen, dsa);
  if (s == NULL) {
    *siglen = 0;
    return (0);
  }
  *siglen = i2d_DSA_SIG(s, &sig);
  DSA_SIG_free(s);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<execle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L15
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L15:
  lea    -0xd0(%rbp),%rax
  mov    %rax,-0xb8(%rbp)
  jmp    L18
L3:
  addq   $0x8,-0xb8(%rbp)
L18:
  mov    -0xb8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    -0xb8(%rbp),%rdx
  lea    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execve@plt>
  leave
  ret
```

assistant: ```c
int execle(const char *path, const char *arg0, ...) {
  char **env = (char **)&arg0;
  while (!*env)
    env++;
  return execve(path, (char **)&arg0, env);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<execle>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rsi,%rsi
  jne    L25
  lea    0x8(%rsp),%rdx
L0:
  add    $0x8,%rdx
  cmpq   $0x0,(%rdx)
  je     L0
L16:
  lea    0x8(%rsp),%rsi
  call   <execve@plt>
  add    $0x18,%rsp
  ret
L25:
  lea    0x8(%rsp),%rdx
  jmp    L16
```

assistant: ```c
int execle(const char *path, const char *arg0, ...) {
  char **env = (char **)&arg0;
  while (!*env)
    env++;
  return execve(path, (char **)&arg0, env);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<execle>:
  endbr64
  sub    $0x18,%rsp
  test   %rsi,%rsi
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  mov    %rsi,%rdx
  jne    L7
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x8,%rdx
  cmpq   $0x0,(%rdx)
  je     L16
L7:
  call   <execve@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int execle(const char *path, const char *arg0, ...) {
  char **env = (char **)&arg0;
  while (!*env)
    env++;
  return execve(path, (char **)&arg0, env);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<execle>:
  endbr64
  sub    $0x18,%rsp
  test   %rsi,%rsi
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  mov    %rsi,%rdx
  jne    L14
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rdx
  cmpq   $0x0,(%rdx)
  je     L1
L14:
  call   <execve@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int execle(const char *path, const char *arg0, ...) {
  char **env = (char **)&arg0;
  while (!*env)
    env++;
  return execve(path, (char **)&arg0, env);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cross>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cross(const double *a, const double *b, double *axb) {
  axb[0] = a[1] * b[2] - a[2] * b[1];
  axb[1] = a[2] * b[0] - a[0] * b[2];
  axb[2] = a[0] * b[1] - a[1] * b[0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cross>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  mulsd  0x8(%rsi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross(const double *a, const double *b, double *axb) {
  axb[0] = a[1] * b[2] - a[2] * b[1];
  axb[1] = a[2] * b[0] - a[0] * b[2];
  axb[2] = a[0] * b[1] - a[1] * b[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cross>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross(const double *a, const double *b, double *axb) {
  axb[0] = a[1] * b[2] - a[2] * b[1];
  axb[1] = a[2] * b[0] - a[0] * b[2];
  axb[2] = a[0] * b[1] - a[1] * b[0];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cross>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross(const double *a, const double *b, double *axb) {
  axb[0] = a[1] * b[2] - a[2] * b[1];
  axb[1] = a[2] * b[0] - a[0] * b[2];
  axb[2] = a[0] * b[1] - a[1] * b[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_u64_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fmt_u64_dec@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <print@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void print_u64_dec(uint64_t val) {
  char buf[18];
  size_t len = fmt_u64_dec(buf, val);
  print(buf, len);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_u64_dec>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <fmt_u64_dec@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <print@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_u64_dec(uint64_t val) {
  char buf[18];
  size_t len = fmt_u64_dec(buf, val);
  print(buf, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_u64_dec>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fmt_u64_dec@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <print@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_u64_dec(uint64_t val) {
  char buf[18];
  size_t len = fmt_u64_dec(buf, val);
  print(buf, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_u64_dec>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fmt_u64_dec@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <print@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_u64_dec(uint64_t val) {
  char buf[18];
  size_t len = fmt_u64_dec(buf, val);
  print(buf, len);
}
```