ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fprint_mov_direct_to_direct>:
  endbr64
  mov    %esi,%ecx
  lea    D9(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: MOV   0x%02X, 0x%02X                

assistant: ```c
void fprint_mov_direct_to_direct(FILE *stream, uint8_t direct_src, uint8_t direct_dst) {
  fprintf(stream,
          "MOV   "
          "0x%02X"
          ", "
          "0x%02X"
          "                ",
          direct_dst, direct_src);
}
```
user: What is the c source code of the assembly code below?

```asm
<load_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1ff,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  js     L46
  mov    -0x18(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L18
  mov    D21(%rip),%eax
  jmp    L36
L18:
  mov    $0x0,%eax
L36:
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L12
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L12:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L46:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *load_from_file(const char *filename) {
  int f, size;
  static struct stat st;
  char *buf = 0;
  f = open(filename, O_RDONLY, 0777);
  if (f >= 0) {
    size = (stat((char *)filename, &st) == 0) ? st.st_size : 0;
    if (size) {
      buf = (char *)malloc(size + 1);
      if (buf) {
        size = read(f, buf, size);
        buf[size] = 0;
      }
    }
    close(f);
  }
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<load_from_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x1ff,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    $0x0,%r12d
  test   %eax,%eax
  js     L16
  mov    %eax,%ebx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L39
  mov    D0(%rip),%ebp
  test   %ebp,%ebp
  jne    L22
L39:
  mov    %ebx,%edi
  call   <close@plt>
L16:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L39
  mov    %ebp,%edx
  mov    %rax,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  cltq
  movb   $0x0,(%r12,%rax,1)
  jmp    L39
```

assistant: ```c
char *load_from_file(const char *filename) {
  int f, size;
  static struct stat st;
  char *buf = 0;
  f = open(filename, O_RDONLY, 0777);
  if (f >= 0) {
    size = (stat((char *)filename, &st) == 0) ? st.st_size : 0;
    if (size) {
      buf = (char *)malloc(size + 1);
      if (buf) {
        size = read(f, buf, size);
        buf[size] = 0;
      }
    }
    close(f);
  }
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<load_from_file>:
  endbr64
  mov    D5(%rip),%rax
  push   %r13
  mov    $0x1ff,%edx
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L41
  lea    D9(%rip),%rsi
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <stat@plt>
  test   %rax,%rax
  je     L9
L40:
  xor    %r13d,%r13d
L46:
  mov    %ebp,%edi
  call   <close@plt>
L41:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L9:
  mov    D9(%rip),%r12d
  test   %r12d,%r12d
  je     L40
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L40
  mov    %r12d,%edx
  mov    %rax,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cltq
  movb   $0x0,0x0(%r13,%rax,1)
  jmp    L46
```

assistant: ```c
char *load_from_file(const char *filename) {
  int f, size;
  static struct stat st;
  char *buf = 0;
  f = open(filename, O_RDONLY, 0777);
  if (f >= 0) {
    size = (stat((char *)filename, &st) == 0) ? st.st_size : 0;
    if (size) {
      buf = (char *)malloc(size + 1);
      if (buf) {
        size = read(f, buf, size);
        buf[size] = 0;
      }
    }
    close(f);
  }
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<load_from_file>:
  endbr64
  mov    D1(%rip),%rax
  push   %r13
  mov    $0x1ff,%edx
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L18
  lea    D17(%rip),%rsi
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <stat@plt>
  test   %rax,%rax
  je     L15
L12:
  xor    %r13d,%r13d
L16:
  mov    %ebp,%edi
  call   <close@plt>
L18:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L15:
  mov    D17(%rip),%r12d
  test   %r12d,%r12d
  je     L12
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L12
  mov    %r12d,%edx
  mov    %rax,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cltq
  movb   $0x0,0x0(%r13,%rax,1)
  jmp    L16
```

assistant: ```c
char *load_from_file(const char *filename) {
  int f, size;
  static struct stat st;
  char *buf = 0;
  f = open(filename, O_RDONLY, 0777);
  if (f >= 0) {
    size = (stat((char *)filename, &st) == 0) ? st.st_size : 0;
    if (size) {
      buf = (char *)malloc(size + 1);
      if (buf) {
        size = read(f, buf, size);
        buf[size] = 0;
      }
    }
    close(f);
  }
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_subarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L41
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L45
L41:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
L45:
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L48:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L50
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L74
L50:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L48
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L74:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D16
type: string

tool: D2: NO

tool: D16: YES

assistant: ```c
void check_subarray(int a[], int b[], int s1, int s2) {
  int cnt = 0;
  for (int i = 0; i < s1; i++) {
    if (a[i] == b[0]) {
      cnt = i;
      break;
    }
  }
  for (int i = 0; i < s2; i++) {
    if (b[i] != a[i + cnt]) {
      printf("NO");
      return;
    }
  }
  printf("YES");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_subarray>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L50
  mov    (%rsi),%r9d
  mov    %edx,%edx
  mov    $0x0,%eax
L21:
  mov    %eax,%r8d
  cmp    %r9d,(%rdi,%rax,4)
  je     L32
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L21
  mov    $0x0,%r8d
L32:
  test   %ecx,%ecx
  jle    L19
  mov    %ecx,%ecx
  movslq %r8d,%r8
  lea    (%rdi,%r8,4),%rdx
  mov    $0x0,%eax
L65:
  mov    (%rdx,%rax,4),%edi
  cmp    %edi,(%rsi,%rax,4)
  jne    L35
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L65
L19:
  lea    D13(%rip),%rdi
  call   <printf@plt>
L72:
  add    $0x8,%rsp
  ret
L50:
  mov    $0x0,%r8d
  jmp    L32
L35:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L72
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string

tool: D13: YES

tool: D16: NO

assistant: ```c
void check_subarray(int a[], int b[], int s1, int s2) {
  int cnt = 0;
  for (int i = 0; i < s1; i++) {
    if (a[i] == b[0]) {
      cnt = i;
      break;
    }
  }
  for (int i = 0; i < s2; i++) {
    if (b[i] != a[i + cnt]) {
      printf("NO");
      return;
    }
  }
  printf("YES");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_subarray>:
  endbr64
  test   %edx,%edx
  jle    L31
  mov    (%rsi),%r9d
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L69:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L31
L27:
  movslq %eax,%r8
  cmp    %r9d,(%rdi,%rax,4)
  jne    L69
L66:
  test   %ecx,%ecx
  jle    L89
  movslq %ecx,%rcx
  lea    (%rdi,%r8,4),%rdx
  xor    %eax,%eax
  jmp    L53
  nopl   0x0(%rax)
L29:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L89
L53:
  mov    (%rdx,%rax,4),%edi
  cmp    %edi,(%rsi,%rax,4)
  je     L29
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L31:
  xor    %r8d,%r8d
  jmp    L66
  nopl   (%rax)
L89:
  lea    D12(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D12
type_guessed: string

tool: D5: NO

tool: D12: YES

assistant: ```c
void check_subarray(int a[], int b[], int s1, int s2) {
  int cnt = 0;
  for (int i = 0; i < s1; i++) {
    if (a[i] == b[0]) {
      cnt = i;
      break;
    }
  }
  for (int i = 0; i < s2; i++) {
    if (b[i] != a[i + cnt]) {
      printf("NO");
      return;
    }
  }
  printf("YES");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_subarray>:
  endbr64
  test   %edx,%edx
  jle    L60
  mov    (%rsi),%r9d
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L85:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L60
L67:
  movslq %eax,%r8
  cmp    %r9d,(%rdi,%rax,4)
  jne    L85
L44:
  test   %ecx,%ecx
  jle    L23
  movslq %ecx,%rcx
  lea    (%rdi,%r8,4),%rdx
  xor    %eax,%eax
  jmp    L72
  nopl   0x0(%rax)
L52:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L23
L72:
  mov    (%rdx,%rax,4),%edi
  cmp    %edi,(%rsi,%rax,4)
  je     L52
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L60:
  xor    %r8d,%r8d
  jmp    L44
  nopl   (%rax)
L23:
  lea    D17(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string
name: retrieve_data
arguments: label: D17
data_type: string

tool: D9: NO

tool: D17: YES

assistant: ```c
void check_subarray(int a[], int b[], int s1, int s2) {
  int cnt = 0;
  for (int i = 0; i < s1; i++) {
    if (a[i] == b[0]) {
      cnt = i;
      break;
    }
  }
  for (int i = 0; i < s2; i++) {
    if (b[i] != a[i + cnt]) {
      printf("NO");
      return;
    }
  }
  printf("YES");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ckitoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ckltoa@plt>
  cltq
  leave
  ret
```

assistant: ```c
char *ckitoa(n)
int n;
{
  long nn;
  nn = n;
  return (ckltoa(nn));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ckitoa>:
  endbr64
  sub    $0x8,%rsp
  movslq %edi,%rdi
  mov    $0x0,%eax
  call   <ckltoa@plt>
  cltq
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *ckitoa(n)
int n;
{
  long nn;
  nn = n;
  return (ckltoa(nn));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ckitoa>:
  endbr64
  sub    $0x8,%rsp
  movslq %edi,%rdi
  xor    %eax,%eax
  call   <ckltoa@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
char *ckitoa(n)
int n;
{
  long nn;
  nn = n;
  return (ckltoa(nn));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ckitoa>:
  endbr64
  sub    $0x8,%rsp
  movslq %edi,%rdi
  xor    %eax,%eax
  call   <ckltoa@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
char *ckitoa(n)
int n;
{
  long nn;
  nn = n;
  return (ckltoa(nn));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<yencode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L20
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x40(%rbp)
  jmp    L20
L75:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x38(%rbp),%rdx
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  movzbl -0x15(%rbp),%eax
  add    $0x2a,%eax
  mov    %al,-0x15(%rbp)
  movsbl -0x15(%rbp),%eax
  cmp    $0x3d,%eax
  seta   %dl
  test   %dl,%dl
  jne    L57
  movabs $0x2000000000002401,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L57
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x30(%rbp)
  ja     L64
  movl   $0x1,-0x14(%rbp)
  jmp    L20
L64:
  movzbl -0x15(%rbp),%eax
  add    $0x40,%eax
  mov    %al,-0x15(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x3d,(%rax)
  nop
L57:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rax,%rdx
  movzbl -0x15(%rbp),%eax
  mov    %al,(%rdx)
L20:
  mov    -0x10(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  ja     L86
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jae    L86
  cmpl   $0x0,-0x14(%rbp)
  je     L75
L86:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jae    L65
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
L65:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int yencode(char *target, size_t tlen, const char *source, size_t slen) {
  char ch;
  size_t rd = 0;
  size_t wr = 0;
  int done = 0;
  if (slen == 0)
    slen = strlen(source);
  while (rd <= slen && wr < tlen && !done) {
    ch = source[rd++];
    ch += 42;
    switch (ch) {
    case 0:
    case '\r':
    case '\n':
    case '=':
      if (wr + 1 >= tlen) {
        done = 1;
        continue;
      }
      ch += 64;
      target[wr++] = '=';
      break;
    }
    target[wr++] = ch;
  }
  if (wr < tlen)
    target[wr++] = 0;
  return (wr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yencode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  test   %rcx,%rcx
  jne    L44
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %rax,%rcx
L44:
  mov    $0x0,%eax
  mov    $0x0,%esi
  movabs $0x2000000000002401,%r9
  test   %rbx,%rbx
  jne    L1
  mov    %rbx,%rax
  jmp    L10
L26:
  lea    0x1(%rax),%rdi
  cmp    %rbx,%rdi
  jae    L76
  lea    0x6a(%r8),%edx
  movb   $0x3d,0x0(%rbp,%rax,1)
L90:
  lea    0x1(%rdi),%rax
  mov    %dl,0x0(%rbp,%rdi,1)
  cmp    %rcx,%rsi
  ja     L76
  cmp    %rax,%rbx
  jbe    L76
L1:
  add    $0x1,%rsi
  movzbl -0x1(%r12,%rsi,1),%r8d
  lea    0x2a(%r8),%edx
  cmp    $0x3d,%dl
  ja     L39
  bt     %rdx,%r9
  jb     L26
L39:
  mov    %rax,%rdi
  jmp    L90
L76:
  cmp    %rax,%rbx
  jbe    L10
  movb   $0x0,0x0(%rbp,%rax,1)
  lea    0x1(%rax),%rax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int yencode(char *target, size_t tlen, const char *source, size_t slen) {
  char ch;
  size_t rd = 0;
  size_t wr = 0;
  int done = 0;
  if (slen == 0)
    slen = strlen(source);
  while (rd <= slen && wr < tlen && !done) {
    ch = source[rd++];
    ch += 42;
    switch (ch) {
    case 0:
    case '\r':
    case '\n':
    case '=':
      if (wr + 1 >= tlen) {
        done = 1;
        continue;
      }
      ch += 64;
      target[wr++] = '=';
      break;
    }
    target[wr++] = ch;
  }
  if (wr < tlen)
    target[wr++] = 0;
  return (wr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yencode>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rcx,%rcx
  jne    L42
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %rax,%rcx
L42:
  movabs $0x2000000000002401,%rax
  xor    %r8d,%r8d
  xor    %edi,%edi
  test   %rbx,%rbx
  je     L62
  nopl   (%rax)
L49:
  add    $0x1,%rdi
  movzbl -0x1(%r12,%rdi,1),%r10d
  lea    0x2a(%r10),%esi
  cmp    $0x3d,%sil
  ja     L24
  bt     %rsi,%rax
  jb     L87
L24:
  mov    %r8,%r9
  mov    %sil,0x0(%rbp,%r9,1)
  lea    0x1(%r9),%r8
  cmp    %rcx,%rdi
  ja     L86
L23:
  cmp    %r8,%rbx
  ja     L49
L65:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L87:
  lea    0x1(%r8),%r9
  cmp    %r9,%rbx
  jbe    L86
  lea    0x6a(%r10),%esi
  movb   $0x3d,0x0(%rbp,%r8,1)
  lea    0x1(%r9),%r8
  mov    %sil,0x0(%rbp,%r9,1)
  cmp    %rcx,%rdi
  jbe    L23
  nopl   0x0(%rax)
L86:
  cmp    %r8,%rbx
  jbe    L65
  movb   $0x0,0x0(%rbp,%r8,1)
  lea    0x1(%r8),%eax
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L62:
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
int yencode(char *target, size_t tlen, const char *source, size_t slen) {
  char ch;
  size_t rd = 0;
  size_t wr = 0;
  int done = 0;
  if (slen == 0)
    slen = strlen(source);
  while (rd <= slen && wr < tlen && !done) {
    ch = source[rd++];
    ch += 42;
    switch (ch) {
    case 0:
    case '\r':
    case '\n':
    case '=':
      if (wr + 1 >= tlen) {
        done = 1;
        continue;
      }
      ch += 64;
      target[wr++] = '=';
      break;
    }
    target[wr++] = ch;
  }
  if (wr < tlen)
    target[wr++] = 0;
  return (wr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yencode>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rcx,%rcx
  jne    L17
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %rax,%rcx
L17:
  movabs $0x2000000000002401,%rax
  xor    %r8d,%r8d
  xor    %edi,%edi
  test   %rbx,%rbx
  je     L89
  nopl   (%rax)
L92:
  add    $0x1,%rdi
  movzbl -0x1(%r12,%rdi,1),%r10d
  lea    0x2a(%r10),%esi
  cmp    $0x3d,%sil
  ja     L53
  bt     %rsi,%rax
  jb     L93
L53:
  mov    %r8,%r9
  mov    %sil,0x0(%rbp,%r9,1)
  lea    0x1(%r9),%r8
  cmp    %rcx,%rdi
  ja     L30
L20:
  cmp    %r8,%rbx
  ja     L92
L68:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L93:
  lea    0x1(%r8),%r9
  cmp    %r9,%rbx
  jbe    L30
  lea    0x6a(%r10),%esi
  movb   $0x3d,0x0(%rbp,%r8,1)
  lea    0x1(%r9),%r8
  mov    %sil,0x0(%rbp,%r9,1)
  cmp    %rcx,%rdi
  jbe    L20
  nopl   0x0(%rax)
L30:
  cmp    %r8,%rbx
  jbe    L68
  movb   $0x0,0x0(%rbp,%r8,1)
  lea    0x1(%r8),%eax
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L89:
  xor    %eax,%eax
  jmp    L70
```

assistant: ```c
int yencode(char *target, size_t tlen, const char *source, size_t slen) {
  char ch;
  size_t rd = 0;
  size_t wr = 0;
  int done = 0;
  if (slen == 0)
    slen = strlen(source);
  while (rd <= slen && wr < tlen && !done) {
    ch = source[rd++];
    ch += 42;
    switch (ch) {
    case 0:
    case '\r':
    case '\n':
    case '=':
      if (wr + 1 >= tlen) {
        done = 1;
        continue;
      }
      ch += 64;
      target[wr++] = '=';
      break;
    }
    target[wr++] = ch;
  }
  if (wr < tlen)
    target[wr++] = 0;
  return (wr);
}
```
user: What is the c source code of the assembly code below:

```asm
<strtolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L27
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L10
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L10
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L10:
  addq   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strtolower(char *str) {
  for (char *c = str; *c; c++) {
    if (*c >= 'A' && *c <= 'Z') {
      *c |= 32;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtolower>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L30
L36:
  ret
L17:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
L30:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L17
  or     $0x20,%eax
  mov    %al,(%rdi)
  jmp    L17
```

assistant: ```c
void strtolower(char *str) {
  for (char *c = str; *c; c++) {
    if (*c >= 'A' && *c <= 'Z') {
      *c |= 32;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtolower>:
  endbr64
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L20:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L0
  or     $0x20,%eax
  mov    %al,(%rdi)
L0:
  add    $0x1,%rdi
L7:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L20
  ret
```

assistant: ```c
void strtolower(char *str) {
  for (char *c = str; *c; c++) {
    if (*c >= 'A' && *c <= 'Z') {
      *c |= 32;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtolower>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L29
  nopl   0x0(%rax,%rax,1)
L28:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L26
  or     $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L28
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L28
L29:
  ret
```

assistant: ```c
void strtolower(char *str) {
  for (char *c = str; *c; c++) {
    if (*c >= 'A' && *c <= 'Z') {
      *c |= 32;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  call   <__builtin_unreachable@plt>
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %eax,%edi
  call   <check_alloc@plt>
  leave
  ret
```

assistant: ```c
void *xmalloc(size_t size) {
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((size == 0)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  return check_alloc(malloc(size));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xmalloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L11
L4:
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %eax,%edi
  call   <check_alloc@plt>
  pop    %rbx
  ret
L11:
  mov    $0x0,%eax
  call   <__builtin_unreachable@plt>
  jmp    L4
```

assistant: ```c
void *xmalloc(size_t size) {
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((size == 0)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  return check_alloc(malloc(size));
}
```