ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<babl_matrix_mul_matrixf>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8,%rsi
  mov    %rdx,%rbx
  mov    $0x24,%edx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    0x30(%rsp),%rdi
  mov    $0x24,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movaps 0x30(%rsp),%xmm0
  movaps (%rsp),%xmm8
  movaps 0x10(%rsp),%xmm1
  movaps 0x40(%rsp),%xmm6
  movaps %xmm0,%xmm9
  movaps %xmm8,%xmm11
  movss  0x50(%rsp),%xmm5
  movss  0x8(%rsp),%xmm3
  shufps $0x24,%xmm0,%xmm9
  movaps %xmm9,%xmm12
  movaps %xmm8,%xmm9
  shufps $0xc0,%xmm8,%xmm11
  unpcklps %xmm1,%xmm9
  movss  0x48(%rsp),%xmm10
  shufps $0xaf,%xmm1,%xmm8
  movss  0x4c(%rsp),%xmm7
  mulps  %xmm11,%xmm12
  movaps %xmm0,%xmm11
  shufps $0x6a,%xmm9,%xmm9
  movss  0x14(%rsp),%xmm2
  shufps $0x4e,%xmm6,%xmm11
  shufps $0x79,%xmm11,%xmm11
  mulps  %xmm11,%xmm9
  movaps %xmm3,%xmm11
  unpcklps %xmm2,%xmm11
  unpcklps %xmm3,%xmm3
  movss  0x20(%rsp),%xmm4
  unpcklps %xmm2,%xmm2
  movlhps %xmm11,%xmm3
  addps  %xmm12,%xmm9
  movaps %xmm5,%xmm12
  unpcklps %xmm10,%xmm12
  unpcklps %xmm7,%xmm10
  unpcklps %xmm5,%xmm7
  movaps %xmm10,%xmm11
  movlhps %xmm10,%xmm7
  movlhps %xmm12,%xmm11
  mulps  %xmm11,%xmm3
  addps  %xmm9,%xmm3
  movaps %xmm1,%xmm9
  shufps $0xf0,%xmm1,%xmm9
  movups %xmm3,(%rbx)
  movaps %xmm0,%xmm3
  shufps $0x49,%xmm0,%xmm3
  mulps  %xmm8,%xmm3
  movaps %xmm6,%xmm8
  shufps $0x55,%xmm6,%xmm6
  shufps $0xe4,%xmm0,%xmm8
  shufps $0x34,%xmm8,%xmm8
  mulps  %xmm9,%xmm8
  unpckhps %xmm0,%xmm0
  addps  %xmm8,%xmm3
  movaps %xmm4,%xmm8
  unpcklps %xmm4,%xmm8
  mulss  %xmm5,%xmm4
  movlhps %xmm8,%xmm2
  mulps  %xmm7,%xmm2
  addps  %xmm3,%xmm2
  movups %xmm2,0x10(%rbx)
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  mulss  %xmm2,%xmm0
  mulss  %xmm6,%xmm1
  addss  %xmm1,%xmm0
  addss  %xmm4,%xmm0
  movss  %xmm0,0x20(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void babl_matrix_mul_matrixf(const float *matA_, const float *matB_, float *out) {
  int i, j;
  float matA[9];
  float matB[9];
  float t1, t2, t3;
  memcpy(matA, matA_, sizeof(matA));
  memcpy(matB, matB_, sizeof(matB));
  for (i = 0; i < 3; i++) {
    t1 = matA[i * 3 + 0];
    t2 = matA[i * 3 + 1];
    t3 = matA[i * 3 + 2];
    for (j = 0; j < 3; j++) {
      out[i * 3 + j] = t1 * matB[0 * 3 + j];
      out[i * 3 + j] += t2 * matB[1 * 3 + j];
      out[i * 3 + j] += t3 * matB[2 * 3 + j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parseLineToGetNumArr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  movw   $0x20,-0x1a(%rbp)
  lea    -0x1a(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L21
L15:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x2c(%rbp)
  lea    -0x1a(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
L21:
  cmpq   $0x0,-0x28(%rbp)
  jne    L15
  mov    -0x2c(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int parseLineToGetNumArr(char line[], int numArr[]) {
  int mSize = 0;
  char *token, delim[] = " ";
  token = strtok(line, delim);
  while (token != NULL) {
    numArr[mSize] = atoi(token);
    mSize++;
    token = strtok(NULL, delim);
  }
  return mSize;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parseLineToGetNumArr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x20,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  call   <strtok@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rdi
  mov    $0x1,%ebx
  lea    0x6(%rsp),%r12
L21:
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp,%rbx,4)
  mov    %ebx,%r13d
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L21
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    $0x0,%r13d
  jmp    L3
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parseLineToGetNumArr(char line[], int numArr[]) {
  int mSize = 0;
  char *token, delim[] = " ";
  token = strtok(line, delim);
  while (token != NULL) {
    numArr[mSize] = atoi(token);
    mSize++;
    token = strtok(NULL, delim);
  }
  return mSize;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parseLineToGetNumArr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%r12
  mov    $0x20,%eax
  mov    %r12,%rsi
  mov    %ax,0x6(%rsp)
  call   <strtok@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rdi
  mov    $0x1,%ebx
  nopl   (%rax)
L18:
  call   <atoi@plt>
  xor    %edi,%edi
  mov    %r12,%rsi
  mov    %ebx,%r13d
  mov    %eax,-0x4(%rbp,%rbx,4)
  add    $0x1,%rbx
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L18
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %r13d,%r13d
  jmp    L19
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parseLineToGetNumArr(char line[], int numArr[]) {
  int mSize = 0;
  char *token, delim[] = " ";
  token = strtok(line, delim);
  while (token != NULL) {
    numArr[mSize] = atoi(token);
    mSize++;
    token = strtok(NULL, delim);
  }
  return mSize;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parseLineToGetNumArr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%r12
  mov    $0x20,%eax
  mov    %r12,%rsi
  mov    %ax,0x6(%rsp)
  call   <strtok@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  mov    $0x1,%ebx
  nopl   (%rax)
L30:
  call   <atoi@plt>
  xor    %edi,%edi
  mov    %r12,%rsi
  mov    %ebx,%r13d
  mov    %eax,-0x4(%rbp,%rbx,4)
  add    $0x1,%rbx
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L30
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %r13d,%r13d
  jmp    L10
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parseLineToGetNumArr(char line[], int numArr[]) {
  int mSize = 0;
  char *token, delim[] = " ";
  token = strtok(line, delim);
  while (token != NULL) {
    numArr[mSize] = atoi(token);
    mSize++;
    token = strtok(NULL, delim);
  }
  return mSize;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_ttime_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L13
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L13
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L13
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L13
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L21
L13:
  mov    $0x1,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int _ttime_number(char **p, time_t *res) {
  if (**p >= '0' && **p <= '9') {
    *res = (**p - '0') * 10;
    (*p)++;
    if (**p >= '0' && **p <= '9') {
      *res += (**p - '0');
      (*p)++;
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_ttime_number>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdx
  movzbl (%rdx),%edx
  lea    -0x30(%rdx),%edi
  mov    $0x1,%ecx
  cmp    $0x9,%dil
  ja     L9
  lea    0x10(%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %dl,(%rsi)
  mov    (%rax),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rax)
  movzbl 0x1(%rdx),%edx
  lea    -0x30(%rdx),%edi
  mov    $0x1,%ecx
  cmp    $0x9,%dil
  jbe    L16
L9:
  mov    %ecx,%eax
  ret
L16:
  movzbl (%rsi),%ecx
  lea    -0x30(%rdx,%rcx,1),%edx
  mov    %dl,(%rsi)
  addq   $0x1,(%rax)
  mov    $0x0,%ecx
  jmp    L9
```

assistant: ```c
int _ttime_number(char **p, time_t *res) {
  if (**p >= '0' && **p <= '9') {
    *res = (**p - '0') * 10;
    (*p)++;
    if (**p >= '0' && **p <= '9') {
      *res += (**p - '0');
      (*p)++;
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ttime_number>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L7
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %al,(%rsi)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rax),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L17
L7:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L17:
  movzbl (%rsi),%edx
  lea    -0x30(%rax,%rdx,1),%eax
  mov    %al,(%rsi)
  xor    %eax,%eax
  addq   $0x1,(%rdi)
  ret
```

assistant: ```c
int _ttime_number(char **p, time_t *res) {
  if (**p >= '0' && **p <= '9') {
    *res = (**p - '0') * 10;
    (*p)++;
    if (**p >= '0' && **p <= '9') {
      *res += (**p - '0');
      (*p)++;
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<_ttime_number>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L14
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %al,(%rsi)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rax),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L17
L14:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L17:
  movzbl (%rsi),%edx
  lea    -0x30(%rax,%rdx,1),%eax
  mov    %al,(%rsi)
  xor    %eax,%eax
  addq   $0x1,(%rdi)
  ret
```

assistant: ```c
int _ttime_number(char **p, time_t *res) {
  if (**p >= '0' && **p <= '9') {
    *res = (**p - '0') * 10;
    (*p)++;
    if (**p >= '0' && **p <= '9') {
      *res += (**p - '0');
      (*p)++;
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x6,-0x10(%rbp)
  movl   $0xd,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiply@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiply_recursive@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string
name: retrieve_data
arguments: data_label: D8
type: string

tool: D9: %d x %d = %d



tool: D8: %d x %d = %d


assistant: ```c
int main(void) {
  int x = 6, y = 13;
  int s1 = multiply(x, y);
  printf("%d x %d = %d\n\n", x, y, s1);
  int s2 = multiply_recursive(x, y);
  printf("%d x %d = %d\n", x, y, s2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  mov    $0x6,%edi
  call   <multiply@plt>
  mov    %eax,%ecx
  mov    $0xd,%edx
  mov    $0x6,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xd,%esi
  mov    $0x6,%edi
  call   <multiply_recursive@plt>
  mov    %eax,%ecx
  mov    $0xd,%edx
  mov    $0x6,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string
name: retrieve_data
arguments: data_tag: D11
type: string

tool: D7: %d x %d = %d



tool: D11: %d x %d = %d


assistant: ```c
int main(void) {
  int x = 6, y = 13;
  int s1 = multiply(x, y);
  printf("%d x %d = %d\n\n", x, y, s1);
  int s2 = multiply_recursive(x, y);
  printf("%d x %d = %d\n", x, y, s2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  mov    $0x6,%edi
  call   <multiply@plt>
  mov    $0xd,%edx
  mov    $0x6,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0xd,%esi
  mov    $0x6,%edi
  call   <multiply_recursive@plt>
  mov    $0xd,%edx
  mov    $0x6,%esi
  lea    D13(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D13
type_infered: string

tool: D11: %d x %d = %d



tool: D13: %d x %d = %d


assistant: ```c
int main(void) {
  int x = 6, y = 13;
  int s1 = multiply(x, y);
  printf("%d x %d = %d\n\n", x, y, s1);
  int s2 = multiply_recursive(x, y);
  printf("%d x %d = %d\n", x, y, s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  mov    $0x6,%edi
  call   <multiply@plt>
  mov    $0xd,%edx
  mov    $0x6,%esi
  lea    D18(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0xd,%esi
  mov    $0x6,%edi
  call   <multiply_recursive@plt>
  mov    $0xd,%edx
  mov    $0x6,%esi
  lea    D9(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
data_type: string
name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D18: %d x %d = %d



tool: D9: %d x %d = %d


assistant: ```c
int main(void) {
  int x = 6, y = 13;
  int s1 = multiply(x, y);
  printf("%d x %d = %d\n\n", x, y, s1);
  int s2 = multiply_recursive(x, y);
  printf("%d x %d = %d\n", x, y, s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<report_parse_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L8
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_eos@plt>
  test   %rax,%rax
  je     L8
  mov    $0x0,%edi
  call   <pop_error_handling@plt>
  mov    $0x1,%eax
  jmp    L22
L8:
  mov    $0x1,%edi
  call   <pop_error_handling@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %esi,%ecx
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <print_error@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: Error parsing %s: %s at offset %zd in "%s"

assistant: ```c
bool report_parse_error(const char *message, bool ok, const char *start, const char *end) {
  if (ok && parse_eos(&end)) {
    pop_error_handling(false);
    return true;
  } else {
    char *error_message = pop_error_handling(true);
    print_error("Error parsing %s: %s at offset %zd in \"%s\"", message, error_message, end - start + 1, start);
    free(error_message);
    return false;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<report_parse_error>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rcx,0x8(%rsp)
  test   %esi,%esi
  je     L3
  lea    0x8(%rsp),%rdi
  call   <parse_eos@plt>
  test   %rax,%rax
  jne    L2
L3:
  mov    $0x1,%edi
  call   <pop_error_handling@plt>
  mov    %rax,%rbp
  mov    0x8(%rsp),%rcx
  sub    %rbx,%rcx
  add    $0x1,%ecx
  mov    %rbx,%r8
  mov    %rax,%rdx
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  call   <print_error@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L15:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    $0x0,%edi
  call   <pop_error_handling@plt>
  mov    $0x1,%eax
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: Error parsing %s: %s at offset %zd in "%s"

assistant: ```c
bool report_parse_error(const char *message, bool ok, const char *start, const char *end) {
  if (ok && parse_eos(&end)) {
    pop_error_handling(false);
    return true;
  } else {
    char *error_message = pop_error_handling(true);
    print_error("Error parsing %s: %s at offset %zd in \"%s\"", message, error_message, end - start + 1, start);
    free(error_message);
    return false;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<report_parse_error>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %rcx,0x8(%rsp)
  test   %esi,%esi
  je     L13
  lea    0x8(%rsp),%rdi
  call   <parse_eos@plt>
  test   %rax,%rax
  jne    L1
L13:
  mov    $0x1,%edi
  call   <pop_error_handling@plt>
  mov    0x8(%rsp),%rcx
  mov    %rbx,%r8
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdx
  lea    D9(%rip),%rdi
  sub    %rbx,%rcx
  add    $0x1,%ecx
  call   <print_error@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %edi,%edi
  call   <pop_error_handling@plt>
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: Error parsing %s: %s at offset %zd in "%s"

assistant: ```c
bool report_parse_error(const char *message, bool ok, const char *start, const char *end) {
  if (ok && parse_eos(&end)) {
    pop_error_handling(false);
    return true;
  } else {
    char *error_message = pop_error_handling(true);
    print_error("Error parsing %s: %s at offset %zd in \"%s\"", message, error_message, end - start + 1, start);
    free(error_message);
    return false;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<report_parse_error>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %rcx,0x8(%rsp)
  test   %esi,%esi
  je     L4
  lea    0x8(%rsp),%rdi
  call   <parse_eos@plt>
  test   %rax,%rax
  jne    L10
L4:
  mov    $0x1,%edi
  call   <pop_error_handling@plt>
  mov    0x8(%rsp),%rcx
  mov    %rbx,%r8
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdx
  lea    D6(%rip),%rdi
  sub    %rbx,%rcx
  add    $0x1,%ecx
  call   <print_error@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %edi,%edi
  call   <pop_error_handling@plt>
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D6: Error parsing %s: %s at offset %zd in "%s"

assistant: ```c
bool report_parse_error(const char *message, bool ok, const char *start, const char *end) {
  if (ok && parse_eos(&end)) {
    pop_error_handling(false);
    return true;
  } else {
    char *error_message = pop_error_handling(true);
    print_error("Error parsing %s: %s at offset %zd in \"%s\"", message, error_message, end - start + 1, start);
    free(error_message);
    return false;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<renameatx_np>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edi
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <__renameatx_np@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    $0x0,%eax
  call   <__inc_remove_counter@plt>
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int renameatx_np(int oldfd, const char *old, int newfd, const char *new, unsigned int flags) {
  int res = __renameatx_np(oldfd, old, newfd, new, flags);
  if (res == 0) {
    __inc_remove_counter();
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<renameatx_np>:
  endbr64
  push   %rbx
  call   <__renameatx_np@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L3
L15:
  mov    %ebx,%eax
  pop    %rbx
  ret
L3:
  mov    $0x0,%eax
  call   <__inc_remove_counter@plt>
  jmp    L15
```

assistant: ```c
int renameatx_np(int oldfd, const char *old, int newfd, const char *new, unsigned int flags) {
  int res = __renameatx_np(oldfd, old, newfd, new, flags);
  if (res == 0) {
    __inc_remove_counter();
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<renameatx_np>:
  endbr64
  push   %r12
  call   <__renameatx_np@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L6
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <__inc_remove_counter@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int renameatx_np(int oldfd, const char *old, int newfd, const char *new, unsigned int flags) {
  int res = __renameatx_np(oldfd, old, newfd, new, flags);
  if (res == 0) {
    __inc_remove_counter();
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<renameatx_np>:
  endbr64
  push   %r12
  call   <__renameatx_np@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L1
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <__inc_remove_counter@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int renameatx_np(int oldfd, const char *old, int newfd, const char *new, unsigned int flags) {
  int res = __renameatx_np(oldfd, old, newfd, new, flags);
  if (res == 0) {
    __inc_remove_counter();
  }
  return res;
}
```