ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  mov    0x8(%rsi),%rdi
  lea    D10(%rip),%rbp
  mov    %rbp,%rsi
  call   <sscanf@plt>
  lea    0x10(%rsp),%rdx
  mov    0x10(%rbx),%rdi
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x8(%rsp),%rbp
  cmp    $0x1,%rbp
  je     L15
  mov    $0x0,%ebp
L26:
  movslq 0x8(%rsp),%rbx
  mov    0x10(%rsp),%rdx
  cmp    %rdx,%rbx
  jg     L43
  add    $0x1,%rbx
L39:
  lea    -0x1(%rbx),%edi
  call   <getTotient@plt>
  add    %rax,%rbp
  mov    0x10(%rsp),%rdx
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rdx
  jge    L39
L43:
  mov    %rbp,%rcx
  mov    0x8(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  movq   $0x2,0x8(%rsp)
  jmp    L26
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D10: %ld

tool: D1: Sum of Totients between [%ld..%ld] is %ld 


assistant: ```c
int main(int argc, char **argv) {
  long lower, upper;
  sscanf(argv[1], "%ld", &lower);
  sscanf(argv[2], "%ld", &upper);
  int i;
  long result = 0.0;
  if (lower == 1) {
    result = 1.0;
    lower = 2;
  }
#pragma omp parallel for default(shared) private(i) schedule(auto) reduction(+ : result) num_threads(8)
  for (i = lower; i <= upper; i++) {
    result = result + getTotient(i);
  }
  printf("Sum of Totients between [%ld..%ld] is %ld \n", lower, upper, result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    0x8(%rsi),%rdi
  mov    %r12,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x10(%rbx),%rdi
  mov    %r12,%rsi
  lea    0x10(%rsp),%rdx
  xor    %r12d,%r12d
  call   <sscanf@plt>
  mov    0x8(%rsp),%rsi
  cmp    $0x1,%rsi
  jne    L36
  movq   $0x2,0x8(%rsp)
  mov    %rsi,%r12
  mov    $0x2,%esi
L36:
  mov    0x10(%rsp),%rdx
  movslq %esi,%rbx
  cmp    %rdx,%rbx
  jg     L24
  add    $0x1,%rbx
  nopw   0x0(%rax,%rax,1)
L39:
  lea    -0x1(%rbx),%edi
  call   <getTotient@plt>
  mov    0x10(%rsp),%rdx
  add    %rax,%r12
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rdx
  jge    L39
  mov    0x8(%rsp),%rsi
L24:
  mov    %r12,%rcx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D8
type: string

tool: D11: %ld

tool: D8: Sum of Totients between [%ld..%ld] is %ld 


assistant: ```c
int main(int argc, char **argv) {
  long lower, upper;
  sscanf(argv[1], "%ld", &lower);
  sscanf(argv[2], "%ld", &upper);
  int i;
  long result = 0.0;
  if (lower == 1) {
    result = 1.0;
    lower = 2;
  }
#pragma omp parallel for default(shared) private(i) schedule(auto) reduction(+ : result) num_threads(8)
  for (i = lower; i <= upper; i++) {
    result = result + getTotient(i);
  }
  printf("Sum of Totients between [%ld..%ld] is %ld \n", lower, upper, result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    0x8(%rsi),%rdi
  mov    %r12,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x10(%rbx),%rdi
  mov    %r12,%rsi
  lea    0x10(%rsp),%rdx
  xor    %r12d,%r12d
  call   <sscanf@plt>
  mov    0x8(%rsp),%rsi
  cmp    $0x1,%rsi
  jne    L36
  movq   $0x2,0x8(%rsp)
  mov    %rsi,%r12
  mov    $0x2,%esi
L36:
  mov    0x10(%rsp),%rdx
  movslq %esi,%rbx
  cmp    %rdx,%rbx
  jg     L4
  add    $0x1,%rbx
  nopw   0x0(%rax,%rax,1)
L37:
  lea    -0x1(%rbx),%edi
  call   <getTotient@plt>
  mov    0x10(%rsp),%rdx
  add    %rax,%r12
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rdx
  jge    L37
  mov    0x8(%rsp),%rsi
L4:
  mov    %r12,%rcx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D7
type: string

tool: D1: %ld

tool: D7: Sum of Totients between [%ld..%ld] is %ld 


assistant: ```c
int main(int argc, char **argv) {
  long lower, upper;
  sscanf(argv[1], "%ld", &lower);
  sscanf(argv[2], "%ld", &upper);
  int i;
  long result = 0.0;
  if (lower == 1) {
    result = 1.0;
    lower = 2;
  }
#pragma omp parallel for default(shared) private(i) schedule(auto) reduction(+ : result) num_threads(8)
  for (i = lower; i <= upper; i++) {
    result = result + getTotient(i);
  }
  printf("Sum of Totients between [%ld..%ld] is %ld \n", lower, upper, result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **pp_argv) {
  (void)pp_argv;
  return argc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int main(int argc, char **pp_argv) {
  (void)pp_argv;
  return argc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int main(int argc, char **pp_argv) {
  (void)pp_argv;
  return argc;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int main(int argc, char **pp_argv) {
  (void)pp_argv;
  return argc;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x811c9dc5,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L8
L5:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x1000193,%eax,%eax
  mov    %eax,-0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L5
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned hash_string(const char *text) {
  unsigned hash = 0x811c9dc5;
  size_t len = strlen(text);
  for (size_t i = 0; i < len; ++i) {
    hash ^= text[i];
    hash *= 16777619;
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L26
  mov    %rbx,%rdx
  lea    (%rbx,%rax,1),%rdi
  mov    $0x811c9dc5,%eax
L7:
  movsbl (%rdx),%ecx
  xor    %ecx,%eax
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L7
L20:
  pop    %rbx
  ret
L26:
  mov    $0x811c9dc5,%eax
  jmp    L20
```

assistant: ```c
unsigned hash_string(const char *text) {
  unsigned hash = 0x811c9dc5;
  size_t len = strlen(text);
  for (size_t i = 0; i < len; ++i) {
    hash ^= text[i];
    hash *= 16777619;
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L18
  lea    (%rbx,%rax,1),%rcx
  mov    %rbx,%rdi
  mov    $0x811c9dc5,%eax
  xchg   %ax,%ax
L6:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %edx,%eax
  imul   $0x1000193,%eax,%eax
  cmp    %rdi,%rcx
  jne    L6
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    $0x811c9dc5,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned hash_string(const char *text) {
  unsigned hash = 0x811c9dc5;
  size_t len = strlen(text);
  for (size_t i = 0; i < len; ++i) {
    hash ^= text[i];
    hash *= 16777619;
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L19
  lea    (%rbx,%rax,1),%rcx
  mov    %rbx,%rdi
  mov    $0x811c9dc5,%eax
  xchg   %ax,%ax
L14:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %edx,%eax
  imul   $0x1000193,%eax,%eax
  cmp    %rdi,%rcx
  jne    L14
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    $0x811c9dc5,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned hash_string(const char *text) {
  unsigned hash = 0x811c9dc5;
  size_t len = strlen(text);
  for (size_t i = 0; i < len; ++i) {
    hash ^= text[i];
    hash *= 16777619;
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<txor0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <identity@plt>
  test   %eax,%eax
  je     L8
  mov    $0x2a,%eax
  jmp    L12
L8:
  mov    $0x2b,%eax
L12:
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char txor0(char x) {
  char y = (identity(x) ^ 0) ? 42 : 43;
  return y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<txor0>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <identity@plt>
  cmp    $0x1,%eax
  mov    $0x2a,%eax
  adc    $0x0,%al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char txor0(char x) {
  char y = (identity(x) ^ 0) ? 42 : 43;
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<txor0>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <identity@plt>
  cmp    $0x1,%eax
  mov    $0x2a,%eax
  adc    $0x0,%al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char txor0(char x) {
  char y = (identity(x) ^ 0) ? 42 : 43;
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<txor0>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <identity@plt>
  cmp    $0x1,%eax
  mov    $0x2a,%eax
  adc    $0x0,%al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char txor0(char x) {
  char y = (identity(x) ^ 0) ? 42 : 43;
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ELFHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L28:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0xf0000000,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L5
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  and    %eax,-0x8(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    -0x8(%rbp),%eax
  and    $0x7fffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ELFHash(char *str) {
  unsigned int hash = 0;
  unsigned int x = 0;
  while (*str) {
    hash = (hash << 4) + (*str++);
    if ((x = hash & 0xF0000000L) != 0) {
      hash ^= (x >> 24);
      hash &= ~x;
    }
  }
  return (hash & 0x7FFFFFFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ELFHash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L16
  mov    $0x0,%eax
  jmp    L21
L49:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L19
L21:
  shl    $0x4,%eax
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L49
  mov    %edx,%ecx
  shr    $0x18,%ecx
  xor    %ecx,%eax
  not    %edx
  and    %edx,%eax
  jmp    L49
L16:
  mov    $0x0,%eax
L19:
  and    $0x7fffffff,%eax
  ret
```

assistant: ```c
unsigned int ELFHash(char *str) {
  unsigned int hash = 0;
  unsigned int x = 0;
  while (*str) {
    hash = (hash << 4) + (*str++);
    if ((x = hash & 0xF0000000L) != 0) {
      hash ^= (x >> 24);
      hash &= ~x;
    }
  }
  return (hash & 0x7FFFFFFF);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ELFHash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L23
  nopl   (%rax)
L3:
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L7
  mov    %edx,%ecx
  not    %edx
  shr    $0x18,%ecx
  xor    %ecx,%eax
  and    %edx,%eax
L7:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  and    $0x7fffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  ret
```

assistant: ```c
unsigned int ELFHash(char *str) {
  unsigned int hash = 0;
  unsigned int x = 0;
  while (*str) {
    hash = (hash << 4) + (*str++);
    if ((x = hash & 0xF0000000L) != 0) {
      hash ^= (x >> 24);
      hash &= ~x;
    }
  }
  return (hash & 0x7FFFFFFF);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ELFHash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L8
  nopl   (%rax)
L14:
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L0
  mov    %edx,%ecx
  not    %edx
  shr    $0x18,%ecx
  xor    %ecx,%eax
  and    %edx,%eax
L0:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  and    $0x7fffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
unsigned int ELFHash(char *str) {
  unsigned int hash = 0;
  unsigned int x = 0;
  while (*str) {
    hash = (hash << 4) + (*str++);
    if ((x = hash & 0xF0000000L) != 0) {
      hash ^= (x >> 24);
      hash &= ~x;
    }
  }
  return (hash & 0x7FFFFFFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  mov    $0x1,%eax
  jmp    L7
L12:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <Factorial>
  imul   -0x4(%rbp),%eax
L7:
  leave
  ret
```

assistant: ```c
int Factorial(int n) {
  if (n == 0) {
    return (1);
  } else {
    return (n * Factorial(n - 1));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Factorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L4
  ret
L4:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <Factorial>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int Factorial(int n) {
  if (n == 0) {
    return (1);
  } else {
    return (n * Factorial(n - 1));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Factorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L11
  nopl   (%rax)
L6:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L6
L11:
  ret
```

assistant: ```c
int Factorial(int n) {
  if (n == 0) {
    return (1);
  } else {
    return (n * Factorial(n - 1));
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<Factorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L11
  nopl   (%rax)
L4:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L4
L11:
  ret
```

assistant: ```c
int Factorial(int n) {
  if (n == 0) {
    return (1);
  } else {
    return (n * Factorial(n - 1));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movb   $0x0,-0xd(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L47
L59:
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L63:
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <DigitToBits@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <DigitBitsOutput@plt>
  addl   $0x1,-0xc(%rbp)
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0xa,-0xd(%rbp)
  je     L47
  mov    D6(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xd(%rbp)
  je     L47
  cmpl   $0x9,-0xc(%rbp)
  jle    L63
L47:
  mov    D6(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xd(%rbp)
  jne    L59
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  const struct DigitBits *digitPtr = NULL;
  char c = '\0';
  int digitCount = 0;
  while (c != EOF) {
    digitCount = 0;
    while ((c = getchar()) != '\n' && c != EOF && digitCount < 10) {
      digitPtr = DigitToBits(c);
      if (digitPtr) {
        DigitBitsOutput(digitPtr, stdout);
        ++digitCount;
      }
    }
  }
  getchar();
  return EXIT_SUCCESS;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D36(%rip),%rax
  cmpb   $0x0,(%rax)
  jne    L22
L7:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D41(%rip),%rax
  mov    (%rax),%eax
  pop    %rbx
  ret
L21:
  mov    D36(%rip),%rdx
  cmp    %al,(%rdx)
  je     L7
L22:
  mov    $0x0,%ebx
L23:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L21
  mov    D36(%rip),%rdx
  cmp    %al,(%rdx)
  je     L21
  cmp    $0x9,%ebx
  jg     L21
  movsbl %al,%edi
  call   <DigitToBits@plt>
  test   %rax,%rax
  je     L23
  mov    D20(%rip),%rdx
  mov    (%rdx),%esi
  mov    %rax,%rdi
  call   <DigitBitsOutput@plt>
  add    $0x1,%ebx
  jmp    L23
```

assistant: ```c
int main(void) {
  const struct DigitBits *digitPtr = NULL;
  char c = '\0';
  int digitCount = 0;
  while (c != EOF) {
    digitCount = 0;
    while ((c = getchar()) != '\n' && c != EOF && digitCount < 10) {
      digitPtr = DigitToBits(c);
      if (digitPtr) {
        DigitBitsOutput(digitPtr, stdout);
        ++digitCount;
      }
    }
  }
  getchar();
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D15(%rip),%rbp
  cmpb   $0x0,0x0(%rbp)
  je     L40
  nopw   0x0(%rax,%rax,1)
L63:
  xor    %ebx,%ebx
  jmp    L8
  nopl   0x0(%rax)
L60:
  cmp    %al,%dl
  je     L40
  cmp    $0xa,%ebx
  je     L12
  movsbl %al,%edi
  call   <DigitToBits@plt>
  test   %rax,%rax
  jne    L38
L8:
  xor    %eax,%eax
  call   <getchar@plt>
  movzbl 0x0(%rbp),%edx
  cmp    $0xa,%al
  jne    L60
L12:
  cmp    %al,%dl
  jne    L63
L40:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    D4(%rip),%rdx
  mov    %rax,%rdi
  add    $0x1,%ebx
  mov    (%rdx),%esi
  call   <DigitBitsOutput@plt>
  jmp    L8
```

assistant: ```c
int main(void) {
  const struct DigitBits *digitPtr = NULL;
  char c = '\0';
  int digitCount = 0;
  while (c != EOF) {
    digitCount = 0;
    while ((c = getchar()) != '\n' && c != EOF && digitCount < 10) {
      digitPtr = DigitToBits(c);
      if (digitPtr) {
        DigitBitsOutput(digitPtr, stdout);
        ++digitCount;
      }
    }
  }
  getchar();
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D27(%rip),%rbp
  cmpb   $0x0,0x0(%rbp)
  je     L23
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %ebx,%ebx
  jmp    L24
  nopl   0x0(%rax)
L15:
  cmp    %al,%dl
  je     L23
  cmp    $0xa,%ebx
  je     L55
  movsbl %al,%edi
  call   <DigitToBits@plt>
  test   %rax,%rax
  jne    L65
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  movzbl 0x0(%rbp),%edx
  cmp    $0xa,%al
  jne    L15
L55:
  cmp    %al,%dl
  jne    L8
L23:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L65:
  mov    D26(%rip),%rdx
  mov    %rax,%rdi
  add    $0x1,%ebx
  mov    (%rdx),%esi
  call   <DigitBitsOutput@plt>
  jmp    L24
```

assistant: ```c
int main(void) {
  const struct DigitBits *digitPtr = NULL;
  char c = '\0';
  int digitCount = 0;
  while (c != EOF) {
    digitCount = 0;
    while ((c = getchar()) != '\n' && c != EOF && digitCount < 10) {
      digitPtr = DigitToBits(c);
      if (digitPtr) {
        DigitBitsOutput(digitPtr, stdout);
        ++digitCount;
      }
    }
  }
  getchar();
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<grib2ltypeToZaxisType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0xa6,-0x14(%rbp)
  ja     L86
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D14(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D14(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x0,-0x4(%rbp)
  jmp    L86
  movl   $0x10,-0x4(%rbp)
  jmp    L86
  movl   $0x11,-0x4(%rbp)
  jmp    L86
  movl   $0x12,-0x4(%rbp)
  jmp    L86
  movl   $0xd,-0x4(%rbp)
  jmp    L86
  movl   $0xe,-0x4(%rbp)
  jmp    L86
  movl   $0xf,-0x4(%rbp)
  jmp    L86
  movl   $0xc,-0x4(%rbp)
  jmp    L86
  movl   $0x4,-0x4(%rbp)
  jmp    L86
  movl   $0x5,-0x4(%rbp)
  jmp    L86
  movl   $0xa,-0x4(%rbp)
  jmp    L86
  movl   $0xb,-0x4(%rbp)
  jmp    L86
  movl   $0x2,-0x4(%rbp)
  jmp    L86
  movl   $0x7,-0x4(%rbp)
  jmp    L86
  movl   $0x8,-0x4(%rbp)
  jmp    L86
  movl   $0x13,-0x4(%rbp)
  jmp    L86
  movl   $0x6,-0x4(%rbp)
  jmp    L86
  movl   $0x14,-0x4(%rbp)
  jmp    L86
  movl   $0x15,-0x4(%rbp)
  jmp    L86
  movl   $0x16,-0x4(%rbp)
  jmp    L86
  movl   $0x17,-0x4(%rbp)
  jmp    L86
  movl   $0x18,-0x4(%rbp)
  jmp    L86
  movl   $0x19,-0x4(%rbp)
  nop
L86:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int grib2ltypeToZaxisType(int grib_ltype) {
  int zaxistype = 1;
  switch (grib_ltype) {
  case 1: {
    zaxistype = 0;
    break;
  }
  case 2: {
    zaxistype = 16;
    break;
  }
  case 3: {
    zaxistype = 17;
    break;
  }
  case 4: {
    zaxistype = 18;
    break;
  }
  case 8: {
    zaxistype = 13;
    break;
  }
  case 9: {
    zaxistype = 14;
    break;
  }
  case 10: {
    zaxistype = 15;
    break;
  }
  case 101: {
    zaxistype = 12;
    break;
  }
  case 100: {
    zaxistype = 4;
    break;
  }
  case 103: {
    zaxistype = 5;
    break;
  }
  case 102: {
    zaxistype = 10;
    break;
  }
  case 104: {
    zaxistype = 11;
    break;
  }
  case 105: {
    zaxistype = 2;
    break;
  }
  case 106: {
    zaxistype = 7;
    break;
  }
  case 107: {
    zaxistype = 8;
    break;
  }
  case 114: {
    zaxistype = 19;
    break;
  }
  case 160: {
    zaxistype = 6;
    break;
  }
  case 162: {
    zaxistype = 20;
    break;
  }
  case 163: {
    zaxistype = 21;
    break;
  }
  case 164: {
    zaxistype = 22;
    break;
  }
  case 165: {
    zaxistype = 23;
    break;
  }
  case 166: {
    zaxistype = 24;
    break;
  }
  case 150: {
    zaxistype = 25;
    break;
  }
  }
  return (zaxistype);
}
```