ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sg_put_unaligned_be48>:
  endbr64
  push   %rbp
  mov    $0x20,%ecx
  mov    %edi,%ebp
  push   %rbx
  sar    %cl,%edi
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sg_put_unaligned_be16@plt>
  add    $0x8,%rsp
  lea    0x8(%rbx),%rsi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <sg_put_unaligned_be32@plt>
```

assistant: ```c
void sg_put_unaligned_be48(uint64_t val, void *p) {
  sg_put_unaligned_be16(val >> 32, p);
  sg_put_unaligned_be32(val, (uint8_t *)p + 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sg_put_unaligned_be48>:
  endbr64
  push   %rbp
  mov    $0x20,%ecx
  mov    %edi,%ebp
  push   %rbx
  sar    %cl,%edi
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sg_put_unaligned_be16@plt>
  add    $0x8,%rsp
  lea    0x8(%rbx),%rsi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <sg_put_unaligned_be32@plt>
```

assistant: ```c
void sg_put_unaligned_be48(uint64_t val, void *p) {
  sg_put_unaligned_be16(val >> 32, p);
  sg_put_unaligned_be32(val, (uint8_t *)p + 2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ckmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D5: Not enough memory!

assistant: ```c
void *ckmalloc(size_t nbytes) {
  void *p = malloc(nbytes);
  if (!p)
    error("Not enough memory!");
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ckmalloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L14:
  mov    %rbx,%rax
  pop    %rbx
  ret
L16:
  lea    D5(%rip),%rdi
  call   <error@plt>
  jmp    L14
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string

tool: D5: Not enough memory!

assistant: ```c
void *ckmalloc(size_t nbytes) {
  void *p = malloc(nbytes);
  if (!p)
    error("Not enough memory!");
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ckmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
L14:
  mov    %r12,%rax
  pop    %r12
  ret
L10:
  lea    D9(%rip),%rdi
  call   <error@plt>
  jmp    L14
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: Not enough memory!

assistant: ```c
void *ckmalloc(size_t nbytes) {
  void *p = malloc(nbytes);
  if (!p)
    error("Not enough memory!");
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ckmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L1:
  mov    %r12,%rax
  pop    %r12
  ret
L18:
  lea    D9(%rip),%rdi
  call   <error@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: Not enough memory!

assistant: ```c
void *ckmalloc(size_t nbytes) {
  void *p = malloc(nbytes);
  if (!p)
    error("Not enough memory!");
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<atoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L32
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L32
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L48
L46:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rax,-0x8(%rbp)
L48:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L43
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L46
L43:
  mov    -0x8(%rbp),%rax
  jmp    L57
L32:
  mov    $0x0,%eax
L57:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long atoul(const char *str) {
  if (*str >= '0' && *str <= '9') {
    unsigned long l = *(str++) - '0';
    while (*str >= '0' && *str <= '9') {
      l *= 10;
      l += *(str++) - '0';
    }
    return l;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atoul>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  mov    $0x0,%edx
  cmp    $0x9,%cl
  jbe    L27
L12:
  mov    %rdx,%rax
  ret
L27:
  lea    0x1(%rdi),%rcx
  movsbl %al,%eax
  sub    $0x30,%eax
  movslq %eax,%rdx
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L12
L10:
  lea    (%rdx,%rdx,4),%rdx
  add    $0x1,%rcx
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rdx
  movzbl (%rcx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L10
  jmp    L12
```

assistant: ```c
unsigned long atoul(const char *str) {
  if (*str >= '0' && *str <= '9') {
    unsigned long l = *(str++) - '0';
    while (*str >= '0' && *str <= '9') {
      l *= 10;
      l += *(str++) - '0';
    }
    return l;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<atoul>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L4
L20:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L4:
  movsbq %al,%r8
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L20
  nopl   0x0(%rax)
L21:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rcx
  add    $0x1,%rdx
  movsbq %al,%rax
  lea    (%rax,%rcx,2),%r8
  movzbl (%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L21
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long atoul(const char *str) {
  if (*str >= '0' && *str <= '9') {
    unsigned long l = *(str++) - '0';
    while (*str >= '0' && *str <= '9') {
      l *= 10;
      l += *(str++) - '0';
    }
    return l;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atoul>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L9
L21:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L9:
  movsbq %al,%r8
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L21
  nopl   0x0(%rax)
L16:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rcx
  add    $0x1,%rdx
  movsbq %al,%rax
  lea    (%rax,%rcx,2),%r8
  movzbl (%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L16
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long atoul(const char *str) {
  if (*str >= '0' && *str <= '9') {
    unsigned long l = *(str++) - '0';
    while (*str >= '0' && *str <= '9') {
      l *= 10;
      l += *(str++) - '0';
    }
    return l;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movl   $0x0,0x20(%rsp)
  cmp    $0x2,%ebx
  je     L101
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D58(%rip),%rdi
  call   <scanf@plt>
L83:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L23
  lea    D18(%rip),%r13
  lea    0x10(%rsp),%rbx
  lea    D6(%rip),%r12
  lea    D50(%rip),%rbp
  jmp    L11
L101:
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %eax,0xc(%rsp)
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L95:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <Son@plt>
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L23
L11:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L95
  cmp    $0x2,%eax
  je     L54
  test   %eax,%eax
  jne    L16
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <Father@plt>
  jmp    L16
L54:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <Daughter@plt>
  jmp    L16
L23:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D58
type: string
name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D50
type: string
name: read_data
arguments: tag: D57
type: string

tool: D22: Please input scheduling count:

tool: D58: %d

tool: D18: sched: son

tool: D6: sched: daughter

tool: D50: sched: father

tool: D57: We will schedule for %d times


assistant: ```c
int main(int argc, char *argv[]) {
  srand((unsigned)time(NULL));
  int plate[5] = {0};
  int count;
  if (argc == 2) {
    count = atoi(argv[1]);
    printf("We will schedule for %d times\n", count);
  } else {
    printf("Please input scheduling count:");
    scanf("%d", &count);
  }
  while (count--) {
    int person = rand() % 3;
    switch (person) {
    case 0:
      printf("sched: father\n");
      Father(plate);
      break;
    case 1:
      printf("sched: son\n");
      Son(plate);
      break;
    case 2:
      printf("sched: daughter\n");
      Daughter(plate);
      break;
    default:
      break;
    }
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x200,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x200,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L10
L16:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  add    $0x3,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x3e7,(%rax)
  addl   $0x1,-0x18(%rbp)
L10:
  cmpl   $0x7f,-0x18(%rbp)
  jle    L16
  movl   $0x3,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <computation@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  int *A = (int *)malloc(128 * sizeof(int));
  int *B = (int *)malloc(128 * sizeof(int));
  for (i = 0; i < 128; i++) {
    A[i] = i + 3;
    B[i] = 999;
  }
  int constant = 3;
  computation(A, B, constant);
  free(A);
  free(B);
  fflush(stdout);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x200,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x200,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    $0x3,%eax
  mov    %rbp,%rcx
  sub    %rbx,%rcx
L8:
  mov    %eax,(%rcx,%rdx,1)
  movl   $0x3e7,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0x83,%eax
  jne    L8
  mov    $0x3,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <computation@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i;
  int *A = (int *)malloc(128 * sizeof(int));
  int *B = (int *)malloc(128 * sizeof(int));
  for (i = 0; i < 128; i++) {
    A[i] = i + 3;
    B[i] = 999;
  }
  int constant = 3;
  computation(A, B, constant);
  free(A);
  free(B);
  fflush(stdout);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x200,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x200,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    %rax,%rbp
  mov    %rax,%rdx
  mov    $0x3,%eax
  sub    %rbp,%rcx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,(%rcx,%rdx,1)
  add    $0x1,%eax
  add    $0x4,%rdx
  movl   $0x3e7,-0x4(%rdx)
  cmp    $0x83,%eax
  jne    L5
  mov    %rbp,%rsi
  mov    $0x3,%edx
  mov    %r12,%rdi
  call   <computation@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(void) {
  int i;
  int *A = (int *)malloc(128 * sizeof(int));
  int *B = (int *)malloc(128 * sizeof(int));
  for (i = 0; i < 128; i++) {
    A[i] = i + 3;
    B[i] = 999;
  }
  int constant = 3;
  computation(A, B, constant);
  free(A);
  free(B);
  fflush(stdout);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<tcp_connect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0xc(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L33
  mov    $0xffffffff,%eax
  jmp    L25
L33:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  jne    L6
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    D51(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    D20(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    D65(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    D39(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    D69(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    $0xfffffffc,%esi
  mov    %eax,%edi
  call   <sock_close@plt>
  jmp    L25
L6:
  mov    -0x4(%rbp),%eax
L25:
  leave
  ret
```

assistant: ```c
int tcp_connect(const struct addrinfo *const ai) {
  const int fd = socket(ai->ai_family, ai->ai_socktype, ai->ai_protocol);
  if (fd == -1)
    return (-1);
  if (connect(fd, ai->ai_addr, ai->ai_addrlen) == -1) {
    assert(errno != EALREADY);
    assert(errno != EBADF);
    assert(errno != EISCONN);
    assert(errno != ENOTSOCK);
    assert(errno != EINVAL);
    assert(errno != EOPNOTSUPP);
    return sock_close(fd, (-4));
  }
  return fd;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tcp_connect>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    0x8(%rdi),%edx
  mov    0xc(%rdi),%esi
  mov    0x10(%rdi),%edi
  call   <socket@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L24
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edx
  mov    %eax,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L22
L24:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    D26(%rip),%rbx
  mov    D37(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D57(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D48(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D53(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D51(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D30(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xfffffffc,%esi
  mov    %ebp,%edi
  call   <sock_close@plt>
  mov    %eax,%ebp
  jmp    L24
```

assistant: ```c
int tcp_connect(const struct addrinfo *const ai) {
  const int fd = socket(ai->ai_family, ai->ai_socktype, ai->ai_protocol);
  if (fd == -1)
    return (-1);
  if (connect(fd, ai->ai_addr, ai->ai_addrlen) == -1) {
    assert(errno != EALREADY);
    assert(errno != EBADF);
    assert(errno != EISCONN);
    assert(errno != ENOTSOCK);
    assert(errno != EINVAL);
    assert(errno != EOPNOTSUPP);
    return sock_close(fd, (-4));
  }
  return fd;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tcp_connect>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rdi),%edx
  mov    0xc(%rdi),%esi
  mov    0x10(%rdi),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L19
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edx
  mov    %eax,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L5
L19:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L5:
  mov    D30(%rip),%rbx
  mov    D37(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D50(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D34(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D52(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D57(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D2(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  mov    $0xfffffffc,%esi
  pop    %rbx
  pop    %r12
  jmp    1090 <sock_close@plt>
```

assistant: ```c
int tcp_connect(const struct addrinfo *const ai) {
  const int fd = socket(ai->ai_family, ai->ai_socktype, ai->ai_protocol);
  if (fd == -1)
    return (-1);
  if (connect(fd, ai->ai_addr, ai->ai_addrlen) == -1) {
    assert(errno != EALREADY);
    assert(errno != EBADF);
    assert(errno != EISCONN);
    assert(errno != ENOTSOCK);
    assert(errno != EINVAL);
    assert(errno != EOPNOTSUPP);
    return sock_close(fd, (-4));
  }
  return fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tcp_connect>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rdi),%edx
  mov    0xc(%rdi),%esi
  mov    0x10(%rdi),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L19
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edx
  mov    %eax,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L0
L19:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L0:
  mov    D0(%rip),%rbx
  mov    D64(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D16(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D68(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D42(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D12(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    D17(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%rax
  cmp    %rax,(%rbx)
  setne  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  mov    $0xfffffffc,%esi
  pop    %rbx
  pop    %r12
  jmp    1090 <sock_close@plt>
```

assistant: ```c
int tcp_connect(const struct addrinfo *const ai) {
  const int fd = socket(ai->ai_family, ai->ai_socktype, ai->ai_protocol);
  if (fd == -1)
    return (-1);
  if (connect(fd, ai->ai_addr, ai->ai_addrlen) == -1) {
    assert(errno != EALREADY);
    assert(errno != EBADF);
    assert(errno != EISCONN);
    assert(errno != ENOTSOCK);
    assert(errno != EINVAL);
    assert(errno != EOPNOTSUPP);
    return sock_close(fd, (-4));
  }
  return fd;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mac_sprint_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D27(%rip),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
data_type: string

tool: D22: %02x%02x

assistant: ```c
const char *mac_sprint_short(const unsigned char *mac) {
  static char etherbuf[5];
  sprintf(etherbuf, "%02x%02x", mac[4], mac[5]);
  return etherbuf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mac_sprint_short>:
  endbr64
  push   %rbx
  movzbl 0x5(%rdi),%ecx
  movzbl 0x4(%rdi),%edx
  lea    D14(%rip),%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D14: %02x%02x

assistant: ```c
const char *mac_sprint_short(const unsigned char *mac) {
  static char etherbuf[5];
  sprintf(etherbuf, "%02x%02x", mac[4], mac[5]);
  return etherbuf;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mac_sprint_short>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  movzbl 0x5(%rdi),%ecx
  lea    D1(%rip),%rsi
  movzbl 0x4(%rdi),%edx
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: %02x%02x

assistant: ```c
const char *mac_sprint_short(const unsigned char *mac) {
  static char etherbuf[5];
  sprintf(etherbuf, "%02x%02x", mac[4], mac[5]);
  return etherbuf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mac_sprint_short>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  movzbl 0x5(%rdi),%ecx
  lea    D4(%rip),%rsi
  movzbl 0x4(%rdi),%edx
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: %02x%02x

assistant: ```c
const char *mac_sprint_short(const unsigned char *mac) {
  static char etherbuf[5];
  sprintf(etherbuf, "%02x%02x", mac[4], mac[5]);
  return etherbuf;
}
```