ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ice_fraction>:
  endbr64
  sub    $0x18,%rsp
  movapd %xmm0,%xmm2
  movsd  D51(%rip),%xmm0
  comisd %xmm0,%xmm1
  ja     L19
  subsd  %xmm1,%xmm0
  movsd  D30(%rip),%xmm1
  movsd  %xmm2,0x8(%rsp)
  divsd  D7(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  mulsd  D8(%rip),%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  minsd  %xmm1,%xmm0
L5:
  movsd  D50(%rip),%xmm2
  add    $0x18,%rsp
  movapd %xmm2,%xmm1
  cmpnlesd %xmm0,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm2,%xmm1
  orpd   %xmm1,%xmm0
  ret
  nopl   (%rax)
L19:
  mulsd  D8(%rip),%xmm2
  pxor   %xmm1,%xmm1
  comisd %xmm2,%xmm1
  movapd %xmm2,%xmm0
  ja     L5
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D51
data_type: f64
name: unpack_data
arguments: data_label: D30
data_type: f64
name: unpack_data
arguments: data_label: D7
data_type: f64
name: unpack_data
arguments: data_label: D8
data_type: f64
name: unpack_data
arguments: data_label: D50
data_type: f64

tool: D51: 328

tool: D30: 5

tool: D7: 90

tool: D8: 1.5

tool: D50: 1

assistant: ```c
double ice_fraction(hyd_fraction, surf_temp)
double hyd_fraction, surf_temp;
{
  double temp;
  if (surf_temp > 328.0)
    surf_temp = 328.0;
  temp = pow(((328.0 - surf_temp) / 90.0), 5.0);
  if (temp > (1.5 * hyd_fraction))
    temp = (1.5 * hyd_fraction);
  if (temp >= 1.0)
    return (1.0);
  else
    return (temp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ice_fraction>:
  endbr64
  sub    $0x18,%rsp
  movapd %xmm0,%xmm2
  movsd  D39(%rip),%xmm0
  comisd %xmm0,%xmm1
  ja     L12
  subsd  %xmm1,%xmm0
  movsd  D6(%rip),%xmm1
  movsd  %xmm2,0x8(%rsp)
  divsd  D29(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  mulsd  D27(%rip),%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  minsd  %xmm1,%xmm0
L14:
  movsd  D45(%rip),%xmm2
  add    $0x18,%rsp
  movapd %xmm2,%xmm1
  cmpnlesd %xmm0,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm2,%xmm1
  orpd   %xmm1,%xmm0
  ret
  nopl   (%rax)
L12:
  mulsd  D27(%rip),%xmm2
  pxor   %xmm1,%xmm1
  comisd %xmm2,%xmm1
  movapd %xmm2,%xmm0
  ja     L14
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D6
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D29
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D27
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D45
datatype: f64

tool: D39: 328

tool: D6: 5

tool: D29: 90

tool: D27: 1.5

tool: D45: 1

assistant: ```c
double ice_fraction(hyd_fraction, surf_temp)
double hyd_fraction, surf_temp;
{
  double temp;
  if (surf_temp > 328.0)
    surf_temp = 328.0;
  temp = pow(((328.0 - surf_temp) / 90.0), 5.0);
  if (temp > (1.5 * hyd_fraction))
    temp = (1.5 * hyd_fraction);
  if (temp >= 1.0)
    return (1.0);
  else
    return (temp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<AskTermType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L22
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L22
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L22:
  cmpl   $0x1,-0x14(%rbp)
  jle    L9
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L9
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <String2TermType@plt>
  mov    %eax,-0x8(%rbp)
L9:
  cmpl   $0x0,-0x8(%rbp)
  jle    L16
  cmpl   $0x8,-0x8(%rbp)
  jle    L69
L16:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <PrintTermTypeList@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L39:
  mov    $0x0,%eax
  call   <ReadChar@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L39
  cmpl   $0x8,-0x8(%rbp)
  jg     L39
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L69:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <SetTermType@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D12
type: string

tool: D2: Select a terminal type (or specify it on command line):

tool: D5: 
>

tool: D12: %c


assistant: ```c
void AskTermType(int argc, char *argv[]) {
  int t = 0;
  int c;
  if (argc > 1 && strlen(argv[1]) == 1)
    t = argv[1][0] - '0';
  else if (argc > 1 && strlen(argv[1]) > 1)
    t = String2TermType(argv[1]);
  if (t <= 0 || t >= 9) {
    printf("Select a terminal type (or specify it on command line):\n");
    PrintTermTypeList();
    printf("\n>");
    do {
      c = ReadChar();
      t = c - '0';
    } while (t <= 0 || t >= 9);
    printf("%c\n", c);
  }
  SetTermType(t);
}
```
user: What is the c source code of the assembly code below?

```asm
<AskTermType>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  jg     L49
L11:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <PrintTermTypeList@plt>
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L59:
  mov    $0x0,%eax
  call   <ReadChar@plt>
  lea    -0x31(%rax),%edx
  cmp    $0x7,%edx
  ja     L59
  lea    -0x30(%rax),%ebx
  mov    %eax,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L49:
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L60
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L11
  mov    0x8(%rbx),%rdi
  call   <String2TermType@plt>
  mov    %eax,%ebx
L8:
  lea    -0x1(%rbx),%eax
  cmp    $0x7,%eax
  ja     L11
L57:
  mov    %ebx,%edi
  call   <SetTermType@plt>
  pop    %rbx
  ret
L60:
  mov    0x8(%rbx),%rax
  movsbl (%rax),%ebx
  sub    $0x30,%ebx
  jmp    L8
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D26
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D12: Select a terminal type (or specify it on command line):

tool: D26: 
>

tool: D14: %c


assistant: ```c
void AskTermType(int argc, char *argv[]) {
  int t = 0;
  int c;
  if (argc > 1 && strlen(argv[1]) == 1)
    t = argv[1][0] - '0';
  else if (argc > 1 && strlen(argv[1]) > 1)
    t = String2TermType(argv[1]);
  if (t <= 0 || t >= 9) {
    printf("Select a terminal type (or specify it on command line):\n");
    PrintTermTypeList();
    printf("\n>");
    do {
      c = ReadChar();
      t = c - '0';
    } while (t <= 0 || t >= 9);
    printf("%c\n", c);
  }
  SetTermType(t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AskTermType>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jg     L10
L28:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <PrintTermTypeList@plt>
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L31:
  xor    %eax,%eax
  call   <ReadChar@plt>
  mov    %eax,%esi
  lea    -0x31(%rax),%eax
  cmp    $0x7,%eax
  ja     L31
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  lea    -0x30(%rsi),%ebp
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    10d0 <SetTermType@plt>
  nop
L10:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L12
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L28
  mov    0x8(%rbx),%rdi
  call   <String2TermType@plt>
  mov    %eax,%ebp
L18:
  lea    -0x1(%rbp),%eax
  cmp    $0x7,%eax
  ja     L28
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    10d0 <SetTermType@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  mov    0x8(%rbx),%rax
  movsbl (%rax),%ebp
  sub    $0x30,%ebp
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D20
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string

tool: D5: Select a terminal type (or specify it on command line):

tool: D20: 
>

tool: D0: %c


assistant: ```c
void AskTermType(int argc, char *argv[]) {
  int t = 0;
  int c;
  if (argc > 1 && strlen(argv[1]) == 1)
    t = argv[1][0] - '0';
  else if (argc > 1 && strlen(argv[1]) > 1)
    t = String2TermType(argv[1]);
  if (t <= 0 || t >= 9) {
    printf("Select a terminal type (or specify it on command line):\n");
    PrintTermTypeList();
    printf("\n>");
    do {
      c = ReadChar();
      t = c - '0';
    } while (t <= 0 || t >= 9);
    printf("%c\n", c);
  }
  SetTermType(t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AskTermType>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jg     L25
L2:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <PrintTermTypeList@plt>
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L34:
  xor    %eax,%eax
  call   <ReadChar@plt>
  mov    %eax,%esi
  lea    -0x31(%rax),%eax
  cmp    $0x7,%eax
  ja     L34
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  lea    -0x30(%rsi),%ebp
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    10d0 <SetTermType@plt>
  nop
L25:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L0
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L2
  mov    0x8(%rbx),%rdi
  call   <String2TermType@plt>
  mov    %eax,%ebp
L7:
  lea    -0x1(%rbp),%eax
  cmp    $0x7,%eax
  ja     L2
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    10d0 <SetTermType@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x8(%rbx),%rax
  movsbl (%rax),%ebp
  sub    $0x30,%ebp
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D3
type: string
name: retrieve_data
arguments: label: D28
type: string

tool: D16: Select a terminal type (or specify it on command line):

tool: D3: 
>

tool: D28: %c


assistant: ```c
void AskTermType(int argc, char *argv[]) {
  int t = 0;
  int c;
  if (argc > 1 && strlen(argv[1]) == 1)
    t = argv[1][0] - '0';
  else if (argc > 1 && strlen(argv[1]) > 1)
    t = String2TermType(argv[1]);
  if (t <= 0 || t >= 9) {
    printf("Select a terminal type (or specify it on command line):\n");
    PrintTermTypeList();
    printf("\n>");
    do {
      c = ReadChar();
      t = c - '0';
    } while (t <= 0 || t >= 9);
    printf("%c\n", c);
  }
  SetTermType(t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memxor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L38
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  xor    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x8,-0x8(%rbp)
  addq   $0x8,-0x10(%rbp)
  subq   $0x8,-0x18(%rbp)
L38:
  cmpq   $0x7,-0x18(%rbp)
  ja     L3
  jmp    L9
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L9:
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memxor(void *dest, const void *src, size_t n) {
  while (n >= sizeof(unsigned long)) {
    *(unsigned long *)dest ^= *(unsigned long *)src;
    dest = 1 + (unsigned long *)dest;
    src = 1 + (unsigned long *)src;
    n -= sizeof(unsigned long);
  }
  while (n > 0) {
    *(unsigned char *)dest ^= *(unsigned char *)src;
    dest = 1 + (unsigned char *)dest;
    src = 1 + (unsigned char *)src;
    --n;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<memxor>:
  endbr64
  cmp    $0x7,%rdx
  jbe    L30
  lea    -0x8(%rdx),%rax
  shr    $0x3,%rax
  lea    0x8(,%rax,8),%r9
  lea    (%rdi,%r9,1),%rax
  mov    %rsi,%rcx
L33:
  mov    (%rcx),%r8
  xor    %r8,(%rdi)
  add    $0x8,%rdi
  add    $0x8,%rcx
  cmp    %rax,%rdi
  jne    L33
  add    %r9,%rsi
  and    $0x7,%edx
L17:
  test   %rdx,%rdx
  je     L48
  add    %rax,%rdx
L37:
  movzbl (%rsi),%ecx
  xor    %cl,(%rax)
  add    $0x1,%rax
  add    $0x1,%rsi
  cmp    %rax,%rdx
  jne    L37
L48:
  ret
L30:
  mov    %rdi,%rax
  jmp    L17
```

assistant: ```c
void memxor(void *dest, const void *src, size_t n) {
  while (n >= sizeof(unsigned long)) {
    *(unsigned long *)dest ^= *(unsigned long *)src;
    dest = 1 + (unsigned long *)dest;
    src = 1 + (unsigned long *)src;
    n -= sizeof(unsigned long);
  }
  while (n > 0) {
    *(unsigned char *)dest ^= *(unsigned char *)src;
    dest = 1 + (unsigned char *)dest;
    src = 1 + (unsigned char *)src;
    --n;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<memxor>:
  endbr64
  cmp    $0x7,%rdx
  jbe    L9
  lea    -0x8(%rdx),%rax
  mov    %rsi,%rcx
  shr    $0x3,%rax
  lea    0x8(,%rax,8),%r9
  lea    (%rdi,%r9,1),%rax
  nopl   0x0(%rax)
L34:
  mov    (%rcx),%r8
  xor    %r8,(%rdi)
  add    $0x8,%rdi
  add    $0x8,%rcx
  cmp    %rax,%rdi
  jne    L34
  add    %r9,%rsi
  and    $0x7,%edx
L48:
  test   %rdx,%rdx
  je     L21
  add    %rax,%rdx
  nopl   0x0(%rax)
L28:
  movzbl (%rsi),%ecx
  xor    %cl,(%rax)
  add    $0x1,%rax
  add    $0x1,%rsi
  cmp    %rdx,%rax
  jne    L28
L21:
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rdi,%rax
  jmp    L48
```

assistant: ```c
void memxor(void *dest, const void *src, size_t n) {
  while (n >= sizeof(unsigned long)) {
    *(unsigned long *)dest ^= *(unsigned long *)src;
    dest = 1 + (unsigned long *)dest;
    src = 1 + (unsigned long *)src;
    n -= sizeof(unsigned long);
  }
  while (n > 0) {
    *(unsigned char *)dest ^= *(unsigned char *)src;
    dest = 1 + (unsigned char *)dest;
    src = 1 + (unsigned char *)src;
    --n;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memxor>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x7,%rdx
  jbe    L19
  lea    0x8(%rsi),%rax
  lea    -0x8(%rdx),%r8
  cmp    %rax,%rdi
  je     L79
  cmp    $0xf,%r8
  jbe    L79
  mov    %r8,%r9
  xor    %eax,%eax
  shr    $0x3,%r9
  add    $0x1,%r9
  mov    %r9,%rdi
  shr    %rdi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L32:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm1
  pxor   %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L32
  mov    %r9,%r10
  and    $0xfffffffffffffffe,%r10
  lea    0x0(,%r10,8),%rdi
  lea    (%rcx,%rdi,1),%rax
  add    %rsi,%rdi
  cmp    %r10,%r9
  je     L48
  mov    (%rdi),%rdi
  xor    %rdi,(%rax)
L48:
  shr    $0x3,%r8
  and    $0x7,%edx
  lea    0x8(,%r8,8),%rax
  add    %rax,%rcx
  add    %rax,%rsi
L19:
  test   %rdx,%rdx
  je     L71
  movzbl (%rsi),%eax
  xor    %al,(%rcx)
  cmp    $0x1,%rdx
  je     L71
  movzbl 0x1(%rsi),%eax
  xor    %al,0x1(%rcx)
  cmp    $0x2,%rdx
  je     L71
  movzbl 0x2(%rsi),%eax
  xor    %al,0x2(%rcx)
  cmp    $0x3,%rdx
  je     L71
  movzbl 0x3(%rsi),%eax
  xor    %al,0x3(%rcx)
  cmp    $0x4,%rdx
  je     L71
  movzbl 0x4(%rsi),%eax
  xor    %al,0x4(%rcx)
  sub    $0x5,%rdx
  je     L71
  movzbl 0x5(%rsi),%eax
  xor    %al,0x5(%rcx)
  cmp    $0x1,%rdx
  je     L71
  movzbl 0x6(%rsi),%eax
  xor    %al,0x6(%rcx)
L71:
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  mov    %r8,%rax
  mov    %rsi,%rdi
  shr    $0x3,%rax
  lea    0x8(%rsi,%rax,8),%r10
  mov    %rcx,%rax
  nopw   0x0(%rax,%rax,1)
L34:
  mov    (%rdi),%r9
  add    $0x8,%rdi
  xor    %r9,(%rax)
  add    $0x8,%rax
  cmp    %r10,%rdi
  jne    L34
  jmp    L48
```

assistant: ```c
void memxor(void *dest, const void *src, size_t n) {
  while (n >= sizeof(unsigned long)) {
    *(unsigned long *)dest ^= *(unsigned long *)src;
    dest = 1 + (unsigned long *)dest;
    src = 1 + (unsigned long *)src;
    n -= sizeof(unsigned long);
  }
  while (n > 0) {
    *(unsigned char *)dest ^= *(unsigned char *)src;
    dest = 1 + (unsigned char *)dest;
    src = 1 + (unsigned char *)src;
    --n;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_valid_nickname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L5
L30:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L38
  cmpl   $0x1f,-0x4(%rbp)
  jle    L36
L38:
  mov    $0x0,%eax
  jmp    L5
L36:
  mov    $0x1,%eax
L5:
  leave
  ret
```

assistant: ```c
int is_valid_nickname(char *nickname) {
  int len;
  if (nickname == NULL) {
    return 0;
  }
  len = strlen(nickname);
  if (len == 0 || len > 31) {
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_valid_nickname>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  test   %eax,%eax
  sete   %al
  cmp    $0x1f,%edx
  setg   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
int is_valid_nickname(char *nickname) {
  int len;
  if (nickname == NULL) {
    return 0;
  }
  len = strlen(nickname);
  if (len == 0 || len > 31) {
    return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_valid_nickname>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  test   %eax,%eax
  sete   %al
  cmp    $0x1f,%edx
  setg   %dl
  add    $0x8,%rsp
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_valid_nickname(char *nickname) {
  int len;
  if (nickname == NULL) {
    return 0;
  }
  len = strlen(nickname);
  if (len == 0 || len > 31) {
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_valid_nickname>:
  endbr64
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  test   %eax,%eax
  sete   %al
  cmp    $0x1f,%edx
  setg   %dl
  add    $0x8,%rsp
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_valid_nickname(char *nickname) {
  int len;
  if (nickname == NULL) {
    return 0;
  }
  len = strlen(nickname);
  if (len == 0 || len > 31) {
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_A1_A2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_A1_A2(int A1[2], int A2[2], int M, int N) {
  A1[0] = M / 2;
  A1[1] = N / 2;
  A2[0] = M / 2 + 1;
  A2[1] = N / 2 + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_A1_A2>:
  endbr64
  mov    %edx,%eax
  shr    $0x1f,%eax
  lea    (%rax,%rdx,1),%edx
  sar    %edx
  mov    %edx,(%rdi)
  mov    %ecx,%eax
  shr    $0x1f,%eax
  lea    (%rax,%rcx,1),%eax
  sar    %eax
  mov    %eax,0x4(%rdi)
  add    $0x1,%edx
  mov    %edx,(%rsi)
  add    $0x1,%eax
  mov    %eax,0x4(%rsi)
  ret
```

assistant: ```c
void set_A1_A2(int A1[2], int A2[2], int M, int N) {
  A1[0] = M / 2;
  A1[1] = N / 2;
  A2[0] = M / 2 + 1;
  A2[1] = N / 2 + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_A1_A2>:
  endbr64
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  sar    %edx
  add    %ecx,%eax
  mov    %edx,(%rdi)
  add    $0x1,%edx
  sar    %eax
  mov    %eax,0x4(%rdi)
  add    $0x1,%eax
  mov    %edx,(%rsi)
  mov    %eax,0x4(%rsi)
  ret
```

assistant: ```c
void set_A1_A2(int A1[2], int A2[2], int M, int N) {
  A1[0] = M / 2;
  A1[1] = N / 2;
  A2[0] = M / 2 + 1;
  A2[1] = N / 2 + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_A1_A2>:
  endbr64
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    %ecx,%edx
  shr    $0x1f,%edx
  sar    %eax
  add    %ecx,%edx
  mov    %eax,(%rdi)
  add    $0x1,%eax
  sar    %edx
  movd   %eax,%xmm0
  mov    %edx,0x4(%rdi)
  add    $0x1,%edx
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsi)
  ret
```

assistant: ```c
void set_A1_A2(int A1[2], int A2[2], int M, int N) {
  A1[0] = M / 2;
  A1[1] = N / 2;
  A2[0] = M / 2 + 1;
  A2[1] = N / 2 + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init_simple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0x63,-0x48(%rbp)
  movl   $0x63,-0x44(%rbp)
  movl   $0xd2,-0x40(%rbp)
  movl   $0x69,-0x3c(%rbp)
  movl   $0xf,-0x38(%rbp)
  movl   $0xa8,-0x34(%rbp)
  movl   $0x39,-0x30(%rbp)
  movl   $0x9c,-0x2c(%rbp)
  movl   $0xd2,-0x20(%rbp)
  movl   $0x69,-0x1c(%rbp)
  movl   $0xf,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x9c,-0xc(%rbp)
  movl   $0xf,-0x58(%rbp)
  movl   $0x0,-0x54(%rbp)
  mov    $0x0,%eax
  call   <set_default_action_nexthops@plt>
  mov    $0x0,%eax
  call   <set_default_action_ipv4_lpm@plt>
  mov    -0x54(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <fill_ipv4_lpm_table@plt>
  lea    -0x40(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x58(%rbp),%esi
  mov    -0x54(%rbp),%eax
  mov    %eax,%edi
  call   <fill_nexthops_table@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void init_simple() {
  uint8_t ip[4] = {10, 0, 99, 99};
  uint8_t mac[6] = {0xd2, 0x69, 0x0f, 0xa8, 0x39, 0x9c};
  uint8_t smac[6] = {0xd2, 0x69, 0x0f, 0x00, 0x00, 0x9c};
  uint8_t port = 15;
  uint32_t nhgrp = 0;
  set_default_action_nexthops();
  set_default_action_ipv4_lpm();
  fill_ipv4_lpm_table(ip, 16, nhgrp);
  fill_nexthops_table(nhgrp, port, smac, mac);
}
```