ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stable_sqrt_sort_common_sort>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  cmp    $0xf,%esi
  jle    L37
  nopl   (%rax)
L36:
  mov    %r12d,%ebx
  add    %r12d,%r12d
  mov    %r12d,%eax
  imul   %r12d,%eax
  cmp    %ebp,%eax
  jl     L36
  mov    (%rsp),%r14
  movslq %r12d,%r8
  mov    %r15,%rsi
  shl    $0x2,%ebx
  shl    $0x3,%r8
  mov    %r8,%rdx
  mov    %r14,%rdi
  mov    %r8,0x8(%rsp)
  call   <memcpy@plt>
  mov    %r15,%rdx
  mov    %r14,%rdi
  mov    %r13,%rcx
  mov    %r12d,%esi
  mov    %ebp,%r14d
  call   <stable_sqrt_sort_common_sort>
  mov    0x8(%rsp),%r8
  sub    %r12d,%r14d
  mov    %r12d,%edx
  mov    %r14d,%esi
  xor    %eax,%eax
  add    %r8,%r15
  mov    %r15,%rdi
  call   <stable_sqrt_sort_build_blocks@plt>
  cmp    %ebx,%ebp
  jle    L27
  nopl   (%rax)
L10:
  mov    %ebx,%edx
  mov    %r13,%r8
  mov    %r12d,%ecx
  mov    %r14d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    %ebx,%ebx
  call   <stable_sqrt_sort_combine_blocks@plt>
  cmp    %ebx,%ebp
  jg     L10
L27:
  mov    (%rsp),%rsi
  add    $0x18,%rsp
  mov    %r12d,%ecx
  mov    %r14d,%edx
  pop    %rbx
  mov    %r15,%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <stable_sqrt_sort_merge_down@plt>
  nopl   (%rax)
L37:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <stable_sqrt_sort_sort_ins@plt>
```

assistant: ```c
void stable_sqrt_sort_common_sort(int **arr, int Len, int **extbuf, int *Tags) {
  int lblock, cbuf;
  if (Len < 16) {
    stable_sqrt_sort_sort_ins(arr, Len);
    return;
  }
  lblock = 1;
  while (lblock * lblock < Len) {
    lblock *= 2;
  }
  memcpy((extbuf), (arr), (lblock) * sizeof(int *));
  stable_sqrt_sort_common_sort(extbuf, lblock, arr, Tags);
  stable_sqrt_sort_build_blocks(arr + lblock, Len - lblock, lblock);
  cbuf = lblock;
  while (Len > (cbuf *= 2)) {
    stable_sqrt_sort_combine_blocks(arr + lblock, Len - lblock, cbuf, lblock, Tags);
  }
  stable_sqrt_sort_merge_down(arr + lblock, extbuf, Len - lblock, lblock);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<climbStairs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L65
  mov    $0x0,%eax
  jmp    L57
L65:
  cmpl   $0x1,-0x14(%rbp)
  jne    L16
  mov    $0x1,%eax
  jmp    L57
L16:
  movl   $0x0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L56
L35:
  cmpl   $0x0,-0xc(%rbp)
  je     L18
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <fy1@plt>
  jmp    L64
L18:
  mov    $0x1,%eax
L64:
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L56:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L35
  mov    -0x10(%rbp),%eax
L57:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: y = %d, x = %d, fy = %d


assistant: ```c
int climbStairs(int n) {
  if (n <= 0)
    return 0;
  if (n == 1)
    return 1;
  int count = 0;
  int mid = n / 2, y = 0;
  int fy = 1;
  while (y <= mid) {
    fy = y ? fy1(y - 1, n, fy) : 1;
    printf("y = %d, x = %d, fy = %d\n", y, n - 2 * y, fy);
    count += fy;
    y++;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<climbStairs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%r13d
  test   %edi,%edi
  jle    L59
  mov    %edi,%r14d
  mov    %edi,%r13d
  cmp    $0x1,%edi
  je     L59
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  mov    %eax,0xc(%rsp)
  mov    %edi,%r12d
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  mov    $0x0,%r13d
  jmp    L13
L11:
  lea    -0x2(%rbx),%edi
  mov    %ebp,%edx
  mov    %r14d,%esi
  call   <fy1@plt>
  mov    %eax,%ebp
  mov    %eax,%ecx
  mov    %r12d,%edx
  mov    %r15d,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    %ebp,%r13d
  cmp    %ebx,0xc(%rsp)
  jl     L59
L52:
  add    $0x1,%ebx
  sub    $0x2,%r12d
L13:
  mov    %ebx,%r15d
  sub    $0x1,%r15d
  jne    L11
  mov    $0x1,%ecx
  mov    %r12d,%edx
  mov    $0x0,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  mov    $0x1,%ebp
  jmp    L52
L59:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string

tool: D16: y = %d, x = %d, fy = %d


assistant: ```c
int climbStairs(int n) {
  if (n <= 0)
    return 0;
  if (n == 1)
    return 1;
  int count = 0;
  int mid = n / 2, y = 0;
  int fy = 1;
  while (y <= mid) {
    fy = y ? fy1(y - 1, n, fy) : 1;
    printf("y = %d, x = %d, fy = %d\n", y, n - 2 * y, fy);
    count += fy;
    y++;
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<climbStairs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L29
  mov    %edi,%r15d
  mov    $0x1,%r13d
  cmp    $0x1,%edi
  je     L29
  mov    %edi,%eax
  mov    $0x1,%r12d
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  sar    %eax
  mov    %eax,0xc(%rsp)
  xchg   %ax,%ax
L9:
  lea    0x0(%rbp,%rbp,1),%eax
  mov    %r15d,%r14d
  lea    0x1(%rbp),%ebx
  sub    %eax,%r14d
  test   %ebp,%ebp
  jne    L21
  mov    $0x1,%ecx
  mov    %r14d,%edx
  xor    %esi,%esi
  add    $0x1,%r13d
  lea    D16(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
L7:
  mov    %ebx,%ebp
  jmp    L9
  nopl   (%rax)
L21:
  mov    %r12d,%edx
  lea    -0x1(%rbp),%edi
  mov    %r15d,%esi
  call   <fy1@plt>
  mov    %r14d,%edx
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%ecx
  call   <printf@plt>
  add    %r12d,%r13d
  cmp    0xc(%rsp),%ebx
  jle    L7
L29:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type: string

tool: D16: y = %d, x = %d, fy = %d


assistant: ```c
int climbStairs(int n) {
  if (n <= 0)
    return 0;
  if (n == 1)
    return 1;
  int count = 0;
  int mid = n / 2, y = 0;
  int fy = 1;
  while (y <= mid) {
    fy = y ? fy1(y - 1, n, fy) : 1;
    printf("y = %d, x = %d, fy = %d\n", y, n - 2 * y, fy);
    count += fy;
    y++;
  }
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<climbStairs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L23
  mov    %edi,%r15d
  mov    $0x1,%r13d
  cmp    $0x1,%edi
  je     L23
  mov    %edi,%eax
  mov    $0x1,%r12d
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  sar    %eax
  mov    %eax,0xc(%rsp)
  xchg   %ax,%ax
L18:
  lea    0x0(%rbp,%rbp,1),%eax
  mov    %r15d,%r14d
  lea    0x1(%rbp),%ebx
  sub    %eax,%r14d
  test   %ebp,%ebp
  jne    L3
  mov    $0x1,%ecx
  mov    %r14d,%edx
  xor    %esi,%esi
  add    $0x1,%r13d
  lea    D11(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
L21:
  mov    %ebx,%ebp
  jmp    L18
  nopl   (%rax)
L3:
  mov    %r12d,%edx
  lea    -0x1(%rbp),%edi
  mov    %r15d,%esi
  call   <fy1@plt>
  mov    %r14d,%edx
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%ecx
  call   <printf@plt>
  add    %r12d,%r13d
  cmp    %ebx,0xc(%rsp)
  jge    L21
L23:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type_guessed: string

tool: D11: y = %d, x = %d, fy = %d


assistant: ```c
int climbStairs(int n) {
  if (n <= 0)
    return 0;
  if (n == 1)
    return 1;
  int count = 0;
  int mid = n / 2, y = 0;
  int fy = 1;
  while (y <= mid) {
    fy = y ? fy1(y - 1, n, fy) : 1;
    printf("y = %d, x = %d, fy = %d\n", y, n - 2 * y, fy);
    count += fy;
    y++;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x28,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: other libc: %lu


assistant: ```c
int main() {
  unsigned long lerpDerp = 40;
  printf("other libc: %lu\n", lerpDerp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: other libc: %lu


assistant: ```c
int main() {
  unsigned long lerpDerp = 40;
  printf("other libc: %lu\n", lerpDerp);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: other libc: %lu


assistant: ```c
int main() {
  unsigned long lerpDerp = 40;
  printf("other libc: %lu\n", lerpDerp);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D6: other libc: %lu


assistant: ```c
int main() {
  unsigned long lerpDerp = 40;
  printf("other libc: %lu\n", lerpDerp);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<floats_mat33_chol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  mov    -0x28(%rbp),%rdx
  lea    0x10(%rdx),%rbx
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x1c,%rax
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  movss  (%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x1c,%rax
  movss  (%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x1c,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  mov    -0x28(%rbp),%rdx
  lea    0x20(%rdx),%rbx
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x14,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void floats_mat33_chol(const float *A, int Arows, int Acols, float *R, int Brows, int Bcols) {
  assert(Arows == Brows);
  assert(Bcols == Bcols);
  R[0] = sqrt(A[0]);
  R[3] = A[1] / R[0];
  R[6] = A[2] / R[0];
  R[4] = sqrt(A[4] - R[3] * R[3]);
  R[7] = (A[5] - R[3] * R[6]) / R[4];
  R[8] = sqrt(A[8] - R[6] * R[6] - R[7] * R[7]);
  R[1] = 0;
  R[2] = 0;
  R[5] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<floats_mat33_chol>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rcx,%rbx
  cmp    %r8d,%esi
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  movss  0x0(%rbp),%xmm0
  call   <sqrt@plt>
  movss  %xmm0,(%rbx)
  movss  0x4(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rbx)
  movss  0x8(%rbp),%xmm2
  divss  %xmm0,%xmm2
  movss  %xmm2,0x18(%rbx)
  mulss  %xmm1,%xmm1
  movss  0x10(%rbp),%xmm0
  subss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  %xmm0,0x10(%rbx)
  movss  0x18(%rbx),%xmm2
  movaps %xmm2,%xmm3
  mulss  0xc(%rbx),%xmm3
  movss  0x14(%rbp),%xmm1
  subss  %xmm3,%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x1c(%rbx)
  mulss  %xmm2,%xmm2
  movss  0x20(%rbp),%xmm0
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm1
  subss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  %xmm0,0x20(%rbx)
  movl   $0x0,0x4(%rbx)
  movl   $0x0,0x8(%rbx)
  movl   $0x0,0x14(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void floats_mat33_chol(const float *A, int Arows, int Acols, float *R, int Brows, int Bcols) {
  assert(Arows == Brows);
  assert(Bcols == Bcols);
  R[0] = sqrt(A[0]);
  R[3] = A[1] / R[0];
  R[6] = A[2] / R[0];
  R[4] = sqrt(A[4] - R[3] * R[3]);
  R[7] = (A[5] - R[3] * R[6]) / R[4];
  R[8] = sqrt(A[8] - R[6] * R[6] - R[7] * R[7]);
  R[1] = 0;
  R[2] = 0;
  R[5] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<floats_mat33_chol>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  cmp    %r8d,%esi
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  movss  0x0(%rbp),%xmm0
  call   <sqrt@plt>
  movss  %xmm0,(%rbx)
  movss  0x4(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rbx)
  movss  0x8(%rbp),%xmm2
  mulss  %xmm1,%xmm1
  divss  %xmm0,%xmm2
  movss  %xmm2,0x18(%rbx)
  movss  0x10(%rbp),%xmm0
  subss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  0x18(%rbx),%xmm2
  movss  0xc(%rbx),%xmm3
  movss  %xmm0,0x10(%rbx)
  movss  0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm3
  mulss  %xmm2,%xmm2
  subss  %xmm3,%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x1c(%rbx)
  mulss  %xmm1,%xmm1
  movss  0x20(%rbp),%xmm0
  subss  %xmm2,%xmm0
  subss  %xmm1,%xmm0
  call   <sqrt@plt>
  movq   $0x0,0x4(%rbx)
  movl   $0x0,0x14(%rbx)
  movss  %xmm0,0x20(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void floats_mat33_chol(const float *A, int Arows, int Acols, float *R, int Brows, int Bcols) {
  assert(Arows == Brows);
  assert(Bcols == Bcols);
  R[0] = sqrt(A[0]);
  R[3] = A[1] / R[0];
  R[6] = A[2] / R[0];
  R[4] = sqrt(A[4] - R[3] * R[3]);
  R[7] = (A[5] - R[3] * R[6]) / R[4];
  R[8] = sqrt(A[8] - R[6] * R[6] - R[7] * R[7]);
  R[1] = 0;
  R[2] = 0;
  R[5] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<floats_mat33_chol>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  cmp    %r8d,%esi
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  movss  0x0(%rbp),%xmm0
  call   <sqrt@plt>
  movss  %xmm0,(%rbx)
  movss  0x4(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rbx)
  movss  0x8(%rbp),%xmm2
  mulss  %xmm1,%xmm1
  divss  %xmm0,%xmm2
  movss  %xmm2,0x18(%rbx)
  movss  0x10(%rbp),%xmm0
  subss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  0x18(%rbx),%xmm2
  movss  0xc(%rbx),%xmm3
  movss  %xmm0,0x10(%rbx)
  movss  0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm3
  mulss  %xmm2,%xmm2
  subss  %xmm3,%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x1c(%rbx)
  mulss  %xmm1,%xmm1
  movss  0x20(%rbp),%xmm0
  subss  %xmm2,%xmm0
  subss  %xmm1,%xmm0
  call   <sqrt@plt>
  movq   $0x0,0x4(%rbx)
  movl   $0x0,0x14(%rbx)
  movss  %xmm0,0x20(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void floats_mat33_chol(const float *A, int Arows, int Acols, float *R, int Brows, int Bcols) {
  assert(Arows == Brows);
  assert(Bcols == Bcols);
  R[0] = sqrt(A[0]);
  R[3] = A[1] / R[0];
  R[6] = A[2] / R[0];
  R[4] = sqrt(A[4] - R[3] * R[3]);
  R[7] = (A[5] - R[3] * R[6]) / R[4];
  R[8] = sqrt(A[8] - R[6] * R[6] - R[7] * R[7]);
  R[1] = 0;
  R[2] = 0;
  R[5] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_ip6gretap_set_tunnel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <__builtin_memset@plt>
  mov    $0x11,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L37
  mov    $0x11,%edi
  call   <___constant_swab32@plt>
  jmp    L35
L37:
  mov    $0x11000000,%eax
L35:
  mov    -0x28(%rbp),%rdx
  add    $0xc,%rdx
  mov    %eax,(%rdx)
  movl   $0x2,-0x40(%rbp)
  movq   $0x0,-0x30(%rbp)
  movl   $0x40,-0x3c(%rbp)
  movl   $0xabcde,-0x38(%rbp)
  mov    D42(%rip),%rax
  mov    (%rax),%edx
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  lea    -0x40(%rbp),%rsi
  mov    -0x58(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x20,%edx
  mov    %rax,%rdi
  call   <bpf_skb_set_tunnel_key@plt>
  mov    %eax,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jns    L27
  movabs $0x696c20524f525245,%rax
  movabs $0x65722064253a656e,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x64253a74,-0x10(%rbp)
  movw   $0xa,-0xc(%rbp)
  mov    -0x44(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x66,%edx
  mov    $0x16,%esi
  mov    %rax,%rdi
  call   <bpf_trace_printk@plt>
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  jmp    L25
L27:
  mov    D37(%rip),%rax
  mov    (%rax),%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
__attribute__((section("ip6gretap_set_tunnel"), used)) int _ip6gretap_set_tunnel(struct __sk_buff *skb) {
  struct bpf_tunnel_key key;
  int ret;
  __builtin_memset(&key, 0x0, sizeof(key));
  key.remote_ipv6[3] = (__builtin_constant_p(0x11) ? ___constant_swab32(0x11) : __builtin_bswap32(0x11));
  key.tunnel_id = 2;
  key.tunnel_tos = 0;
  key.tunnel_ttl = 64;
  key.tunnel_label = 0xabcde;
  ret = bpf_skb_set_tunnel_key(skb, &key, sizeof(key), BPF_F_TUNINFO_IPV6 | BPF_F_ZERO_CSUM_TX | BPF_F_SEQ_NUMBER);
  if (ret < 0) {
    do {
      char fmt[] = "ERROR line:%d ret:%d\n";
      bpf_trace_printk(fmt, sizeof(fmt), 102, ret);
    } while (0);
    return TC_ACT_SHOT;
  }
  return TC_ACT_OK;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_ip6gretap_set_tunnel>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x20,%edx
  mov    $0x0,%esi
  call   <__builtin_memset@plt>
  mov    $0x11,%edi
  call   <__builtin_constant_p@plt>
  mov    %rax,%rdx
  mov    $0x11000000,%eax
  test   %rdx,%rdx
  jne    L14
L17:
  mov    0x18(%rsp),%rdx
  mov    %eax,0xc(%rdx)
  movl   $0x2,(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x40,0x4(%rsp)
  movl   $0xabcde,0x8(%rsp)
  mov    D36(%rip),%rax
  mov    (%rax),%ecx
  mov    D41(%rip),%rax
  or     (%rax),%ecx
  mov    D45(%rip),%rax
  or     (%rax),%ecx
  mov    %rsp,%rsi
  mov    $0x20,%edx
  mov    %rbx,%rdi
  call   <bpf_skb_set_tunnel_key@plt>
  test   %eax,%eax
  js     L10
  mov    D33(%rip),%rax
  mov    (%rax),%eax
L9:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x40,%rsp
  pop    %rbx
  ret
L14:
  mov    $0x11,%edi
  call   <___constant_swab32@plt>
  jmp    L17
L10:
  movabs $0x696c20524f525245,%rbx
  movabs $0x65722064253a656e,%rsi
  mov    %rbx,0x20(%rsp)
  mov    %rsi,0x28(%rsp)
  movl   $0x64253a74,0x30(%rsp)
  movw   $0xa,0x34(%rsp)
  lea    0x20(%rsp),%rdi
  mov    %eax,%ecx
  mov    $0x66,%edx
  mov    $0x16,%esi
  call   <bpf_trace_printk@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((section("ip6gretap_set_tunnel"), used)) int _ip6gretap_set_tunnel(struct __sk_buff *skb) {
  struct bpf_tunnel_key key;
  int ret;
  __builtin_memset(&key, 0x0, sizeof(key));
  key.remote_ipv6[3] = (__builtin_constant_p(0x11) ? ___constant_swab32(0x11) : __builtin_bswap32(0x11));
  key.tunnel_id = 2;
  key.tunnel_tos = 0;
  key.tunnel_ttl = 64;
  key.tunnel_label = 0xabcde;
  ret = bpf_skb_set_tunnel_key(skb, &key, sizeof(key), BPF_F_TUNINFO_IPV6 | BPF_F_ZERO_CSUM_TX | BPF_F_SEQ_NUMBER);
  if (ret < 0) {
    do {
      char fmt[] = "ERROR line:%d ret:%d\n";
      bpf_trace_printk(fmt, sizeof(fmt), 102, ret);
    } while (0);
    return TC_ACT_SHOT;
  }
  return TC_ACT_OK;
}
```