ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <clrscr@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <toSuffix@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
data_type: string
name: read_data
arguments: tag: D19
data_type: string

tool: D16: Enter the Valid Infix Expression : Use A ... Z for operands
 and + - * / ^ operators 

tool: D19: The suffix expression is 

assistant: ```c
main() {
  char infix[100], suffix[100];
  clrscr();
  puts("Enter the Valid Infix Expression : Use A ... Z for operands\n and + - * / ^ operators ");
  gets(infix);
  toSuffix(infix, suffix);
  puts("The suffix expression is ");
  puts(suffix);
  getch();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  call   <clrscr@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    0x70(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <toSuffix@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D4: Enter the Valid Infix Expression : Use A ... Z for operands
 and + - * / ^ operators 

tool: D6: The suffix expression is 

assistant: ```c
main() {
  char infix[100], suffix[100];
  clrscr();
  puts("Enter the Valid Infix Expression : Use A ... Z for operands\n and + - * / ^ operators ");
  gets(infix);
  toSuffix(infix, suffix);
  puts("The suffix expression is ");
  puts(suffix);
  getch();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x70(%rsp),%rbp
  call   <clrscr@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <toSuffix@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string

tool: D13: Enter the Valid Infix Expression : Use A ... Z for operands
 and + - * / ^ operators 

tool: D17: The suffix expression is 

assistant: ```c
main() {
  char infix[100], suffix[100];
  clrscr();
  puts("Enter the Valid Infix Expression : Use A ... Z for operands\n and + - * / ^ operators ");
  gets(infix);
  toSuffix(infix, suffix);
  puts("The suffix expression is ");
  puts(suffix);
  getch();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x70(%rsp),%rbp
  call   <clrscr@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <toSuffix@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D10: Enter the Valid Infix Expression : Use A ... Z for operands
 and + - * / ^ operators 

tool: D1: The suffix expression is 

assistant: ```c
main() {
  char infix[100], suffix[100];
  clrscr();
  puts("Enter the Valid Infix Expression : Use A ... Z for operands\n and + - * / ^ operators ");
  gets(infix);
  toSuffix(infix, suffix);
  puts("The suffix expression is ");
  puts(suffix);
  getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1de6,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *x;
  int y;
  x = (int *)malloc(4);
  *x = 7654;
  y = ++*x;
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x1de7,(%rax)
  mov    $0x1de7,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int *x;
  int y;
  x = (int *)malloc(4);
  *x = 7654;
  y = ++*x;
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x1de7,(%rax)
  mov    $0x1de7,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int *x;
  int y;
  x = (int *)malloc(4);
  *x = 7654;
  y = ++*x;
  return y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x1de7,(%rax)
  mov    $0x1de7,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int *x;
  int y;
  x = (int *)malloc(4);
  *x = 7654;
  y = ++*x;
  return y;
}
```
user: What is the c source code of the assembly code below:

```asm
<getMinRing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <areBonded@plt>
  test   %eax,%eax
  je     L40
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <areBonded@plt>
  test   %eax,%eax
  jne    L30
L40:
  mov    $0xfffffffe,%eax
  jmp    L3
L30:
  movl   $0x2,-0x8(%rbp)
  jmp    L48
L50:
  mov    -0x8(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getRing@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L34
  mov    -0x4(%rbp),%eax
  jmp    L3
L34:
  addl   $0x1,-0x8(%rbp)
L48:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L50
  mov    $0xffffffff,%eax
L3:
  leave
  ret
```

assistant: ```c
int getMinRing(int *path, int ar, int ac, int al, int maxLength) {
  int i;
  int pathlength;
  if (!areBonded(ar, ac) || !areBonded(ac, al))
    return -2;
  for (i = 2; i <= maxLength; i++)
    if ((pathlength = getRing(path, ar, ac, al, i)) != -1)
      return pathlength;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getMinRing>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  mov    %edx,%esi
  mov    %r12d,%edi
  call   <areBonded@plt>
  test   %eax,%eax
  je     L72
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <areBonded@plt>
  test   %eax,%eax
  je     L25
  cmp    $0x1,%r14d
  jle    L31
  mov    $0x2,%ebx
L11:
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <getRing@plt>
  cmp    $0xffffffff,%eax
  jne    L47
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jge    L11
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  mov    $0xfffffffe,%eax
  jmp    L47
L25:
  mov    $0xfffffffe,%eax
  jmp    L47
L31:
  mov    $0xffffffff,%eax
  jmp    L47
```

assistant: ```c
int getMinRing(int *path, int ar, int ac, int al, int maxLength) {
  int i;
  int pathlength;
  if (!areBonded(ar, ac) || !areBonded(ac, al))
    return -2;
  for (i = 2; i <= maxLength; i++)
    if ((pathlength = getRing(path, ar, ac, al, i)) != -1)
      return pathlength;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getMinRing>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %edx,%esi
  push   %rbx
  mov    %ebp,%edi
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <areBonded@plt>
  test   %eax,%eax
  je     L33
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <areBonded@plt>
  test   %eax,%eax
  je     L33
  mov    $0x2,%r15d
  cmp    $0x1,%r13d
  jg     L19
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r15d
  cmp    %r15d,%r13d
  jl     L22
L19:
  mov    %r15d,%r8d
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <getRing@plt>
  cmp    $0xffffffff,%eax
  je     L0
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L22:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  mov    $0xfffffffe,%eax
  jmp    L44
```

assistant: ```c
int getMinRing(int *path, int ar, int ac, int al, int maxLength) {
  int i;
  int pathlength;
  if (!areBonded(ar, ac) || !areBonded(ac, al))
    return -2;
  for (i = 2; i <= maxLength; i++)
    if ((pathlength = getRing(path, ar, ac, al, i)) != -1)
      return pathlength;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<getMinRing>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %edx,%esi
  push   %rbx
  mov    %ebp,%edi
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <areBonded@plt>
  test   %eax,%eax
  je     L34
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <areBonded@plt>
  test   %eax,%eax
  je     L34
  mov    $0x2,%r15d
  cmp    $0x1,%r13d
  jg     L48
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%r15d
  cmp    %r15d,%r13d
  jl     L45
L48:
  mov    %r15d,%r8d
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <getRing@plt>
  cmp    $0xffffffff,%eax
  je     L35
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L45:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  mov    $0xfffffffe,%eax
  jmp    L62
```

assistant: ```c
int getMinRing(int *path, int ar, int ac, int al, int maxLength) {
  int i;
  int pathlength;
  if (!areBonded(ar, ac) || !areBonded(ac, al))
    return -2;
  for (i = 2; i <= maxLength; i++)
    if ((pathlength = getRing(path, ar, ac, al, i)) != -1)
      return pathlength;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L17
L6:
  mov    -0x20(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x20(%rbp)
L17:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <maximumGap@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, count = argc - 1;
  int *nums = malloc(count * sizeof(int));
  for (i = 0; i < count; i++) {
    nums[i] = atoi(argv[i + 1]);
  }
  printf("%d\n", maximumGap(nums, count));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  lea    -0x1(%rdi),%r14d
  lea    0x0(,%r14,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r14d,%r14d
  jle    L19
  lea    -0x2(%rbx),%r13d
  add    $0x2,%r13
  mov    $0x1,%ebx
L11:
  mov    (%r12,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L11
L19:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <maximumGap@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, count = argc - 1;
  int *nums = malloc(count * sizeof(int));
  for (i = 0; i < count; i++) {
    nums[i] = atoi(argv[i + 1]);
  }
  printf("%d\n", maximumGap(nums, count));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  lea    -0x1(%rdi),%r14d
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%r14,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r14d,%r14d
  jle    L17
  lea    -0x2(%rbx),%r13d
  mov    $0x1,%ebx
  add    $0x2,%r13
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%r12,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L4
L17:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <maximumGap@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, count = argc - 1;
  int *nums = malloc(count * sizeof(int));
  for (i = 0; i < count; i++) {
    nums[i] = atoi(argv[i + 1]);
  }
  printf("%d\n", maximumGap(nums, count));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    -0x1(%rdi),%r14d
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%r14,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r14d,%r14d
  jle    L14
  lea    -0x2(%rbx),%r13d
  mov    $0x1,%ebx
  add    $0x2,%r13
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%r12,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L18
L14:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <maximumGap@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, count = argc - 1;
  int *nums = malloc(count * sizeof(int));
  for (i = 0; i < count; i++) {
    nums[i] = atoi(argv[i + 1]);
  }
  printf("%d\n", maximumGap(nums, count));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Picture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L33:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L3:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L14
  mov    $0x51,%eax
  jmp    L37
L14:
  mov    $0x2e,%eax
L37:
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L33
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void Picture(int Image[], int Size) {
  int Row, Col, Tst;
  for (Row = 0; Row < Size; Row++) {
    putchar('\n');
    Tst = Image[Row];
    for (Col = 0; Col < Size; Col++) {
      putchar(' ');
      putchar(Col == Tst ? 'Q' : '.');
    }
  }
  putchar('\n');
  putchar('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Picture>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L4
  mov    %esi,%r12d
  mov    %rdi,%r14
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r15
  mov    $0x51,%r13d
L29:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%r14),%ebp
  mov    $0x0,%ebx
L26:
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    %ebx,%ebp
  mov    $0x2e,%edi
  cmove  %r13d,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L26
  add    $0x4,%r14
  cmp    %r15,%r14
  jne    L29
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Picture(int Image[], int Size) {
  int Row, Col, Tst;
  for (Row = 0; Row < Size; Row++) {
    putchar('\n');
    Tst = Image[Row];
    for (Col = 0; Col < Size; Col++) {
      putchar(' ');
      putchar(Col == Tst ? 'Q' : '.');
    }
  }
  putchar('\n');
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Picture>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  mov    %esi,%r12d
  mov    %rdi,%r14
  mov    $0x51,%r13d
  lea    0x4(%rdi,%rax,4),%r15
  nopw   0x0(%rax,%rax,1)
L21:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  mov    (%r14),%ebp
  nop
L7:
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    %ebx,%ebp
  mov    $0x2e,%edi
  cmove  %r13d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L7
  add    $0x4,%r14
  cmp    %r15,%r14
  jne    L21
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putchar@plt>
```

assistant: ```c
void Picture(int Image[], int Size) {
  int Row, Col, Tst;
  for (Row = 0; Row < Size; Row++) {
    putchar('\n');
    Tst = Image[Row];
    for (Col = 0; Col < Size; Col++) {
      putchar(' ');
      putchar(Col == Tst ? 'Q' : '.');
    }
  }
  putchar('\n');
  putchar('\n');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Picture>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  mov    %esi,%r12d
  mov    %rdi,%r13
  lea    0x4(%rdi,%rax,4),%r14
  xchg   %ax,%ax
L22:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  mov    0x0(%r13),%ebp
L2:
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    %ebx,%ebp
  je     L60
  mov    $0x2e,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L2
  add    $0x4,%r13
  cmp    %r14,%r13
  jne    L22
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <putchar@plt>
  nopl   (%rax)
L60:
  mov    $0x51,%edi
  lea    0x1(%rbp),%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L2
  add    $0x4,%r13
  cmp    %r14,%r13
  jne    L22
  jmp    L16
```

assistant: ```c
void Picture(int Image[], int Size) {
  int Row, Col, Tst;
  for (Row = 0; Row < Size; Row++) {
    putchar('\n');
    Tst = Image[Row];
    for (Col = 0; Col < Size; Col++) {
      putchar(' ');
      putchar(Col == Tst ? 'Q' : '.');
    }
  }
  putchar('\n');
  putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x64,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L17
L8:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L8
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  i = 0;
  j = 100;
  k = 1;
  while (i < j) {
    k = k + 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  i = 0;
  j = 100;
  k = 1;
  while (i < j) {
    k = k + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  i = 0;
  j = 100;
  k = 1;
  while (i < j) {
    k = k + 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  i = 0;
  j = 100;
  k = 1;
  while (i < j) {
    k = k + 1;
  }
}
```