ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<loadPreset>:
  endbr64
  movslq %edi,%rdi
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rsi,%rdi,4),%rax
  lea    (%rdx,%rax,4),%rdx
  lea    D5(%rip),%rax
  movss  (%rax,%rdx,4),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: f32

tool: D5: 1

assistant: ```c
float loadPreset(int preset, int index0, int index1) {
  static float presets[9][4][4] = {
      {{1.0, 3.99, 10.65, -2443}, {0.9996, 0.9994, 0.9994, 0.999}, {0.04, 0.01, 0.01, 0.008}, {0.429688, 0.445312, 0.093750}}, {{1.0, 2.01, 3.9, 14.37}, {0.99995, 0.99991, 0.99992, 0.9999}, {0.025, 0.015, 0.015, 0.015}, {0.390625, 0.570312, 0.078125}}, {{1.0, 4.08, 6.669, -3725.0}, {0.999, 0.999, 0.999, 0.999}, {0.06, 0.05, 0.03, 0.02}, {0.609375, 0.359375, 0.140625}}, {{1.0, 2.777, 7.378, 15.377}, {0.996, 0.994, 0.994, 0.99}, {0.04, 0.01, 0.01, 0.008}, {0.460938, 0.375000, 0.046875}}, {{1.0, 2.777, 7.378, 15.377}, {0.99996, 0.99994, 0.99994, 0.9999}, {0.02, 0.005, 0.005, 0.004}, {0.453125, 0.250000, 0.101562}}, {{1.0, 1.777, 2.378, 3.377}, {0.996, 0.994, 0.994, 0.99}, {0.04, 0.01, 0.01, 0.008}, {0.312500, 0.445312, 0.109375}}, {{1.0, 1.004, 1.013, 2.377}, {0.9999, 0.9999, 0.9999, 0.999}, {0.02, 0.005, 0.005, 0.004}, {0.398438, 0.296875, 0.070312}}, {{1.0, 4.0, -1320.0, -3960.0}, {0.9996, 0.999, 0.9994, 0.999}, {0.04, 0.01, 0.01, 0.008}, {0.453125, 0.453125, 0.070312}}, {{1.0, 1.217, 1.475, 1.729}, {0.999, 0.999, 0.999, 0.999}, {0.03, 0.03, 0.03, 0.03}, {0.390625, 0.570312, 0.078125}},
  };
  return presets[preset][index0][index1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<loadPreset>:
  endbr64
  movslq %edi,%rdi
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rsi,%rdi,4),%rax
  lea    (%rdx,%rax,4),%rdx
  lea    D9(%rip),%rax
  movss  (%rax,%rdx,4),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: f32

tool: D9: 1

assistant: ```c
float loadPreset(int preset, int index0, int index1) {
  static float presets[9][4][4] = {
      {{1.0, 3.99, 10.65, -2443}, {0.9996, 0.9994, 0.9994, 0.999}, {0.04, 0.01, 0.01, 0.008}, {0.429688, 0.445312, 0.093750}}, {{1.0, 2.01, 3.9, 14.37}, {0.99995, 0.99991, 0.99992, 0.9999}, {0.025, 0.015, 0.015, 0.015}, {0.390625, 0.570312, 0.078125}}, {{1.0, 4.08, 6.669, -3725.0}, {0.999, 0.999, 0.999, 0.999}, {0.06, 0.05, 0.03, 0.02}, {0.609375, 0.359375, 0.140625}}, {{1.0, 2.777, 7.378, 15.377}, {0.996, 0.994, 0.994, 0.99}, {0.04, 0.01, 0.01, 0.008}, {0.460938, 0.375000, 0.046875}}, {{1.0, 2.777, 7.378, 15.377}, {0.99996, 0.99994, 0.99994, 0.9999}, {0.02, 0.005, 0.005, 0.004}, {0.453125, 0.250000, 0.101562}}, {{1.0, 1.777, 2.378, 3.377}, {0.996, 0.994, 0.994, 0.99}, {0.04, 0.01, 0.01, 0.008}, {0.312500, 0.445312, 0.109375}}, {{1.0, 1.004, 1.013, 2.377}, {0.9999, 0.9999, 0.9999, 0.999}, {0.02, 0.005, 0.005, 0.004}, {0.398438, 0.296875, 0.070312}}, {{1.0, 4.0, -1320.0, -3960.0}, {0.9996, 0.999, 0.9994, 0.999}, {0.04, 0.01, 0.01, 0.008}, {0.453125, 0.453125, 0.070312}}, {{1.0, 1.217, 1.475, 1.729}, {0.999, 0.999, 0.999, 0.999}, {0.03, 0.03, 0.03, 0.03}, {0.390625, 0.570312, 0.078125}},
  };
  return presets[preset][index0][index1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<newsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  cmp    $0x38,%eax
  jle    L16
  mov    $0x40,%eax
  jmp    L9
L16:
  mov    $0x0,%eax
L9:
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    $0x40,%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int newsize(int insize) {
  int size;
  size = insize + 1;
  size += (size % 64 > 56) ? 64 : 0;
  size += 64 - size % 64;
  return size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<newsize>:
  endbr64
  add    $0x1,%edi
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x1a,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  cmp    $0x38,%eax
  setg   %al
  movzbl %al,%eax
  shl    $0x6,%eax
  add    %eax,%edi
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rdi,%rax,1),%edx
  and    $0x3f,%edx
  sub    %edx,%eax
  lea    0x40(%rdi,%rax,1),%eax
  ret
```

assistant: ```c
int newsize(int insize) {
  int size;
  size = insize + 1;
  size += (size % 64 > 56) ? 64 : 0;
  size += 64 - size % 64;
  return size;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<newsize>:
  endbr64
  add    $0x1,%edi
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x1a,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  cmp    $0x38,%eax
  setg   %al
  movzbl %al,%eax
  shl    $0x6,%eax
  add    %eax,%edi
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rdi,%rax,1),%edx
  and    $0x3f,%edx
  sub    %edx,%eax
  lea    0x40(%rdi,%rax,1),%eax
  ret
```

assistant: ```c
int newsize(int insize) {
  int size;
  size = insize + 1;
  size += (size % 64 > 56) ? 64 : 0;
  size += 64 - size % 64;
  return size;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<newsize>:
  endbr64
  add    $0x1,%edi
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x1a,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  cmp    $0x38,%eax
  setg   %al
  movzbl %al,%eax
  shl    $0x6,%eax
  add    %eax,%edi
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rdi,%rax,1),%edx
  and    $0x3f,%edx
  sub    %edx,%eax
  lea    0x40(%rdi,%rax,1),%eax
  ret
```

assistant: ```c
int newsize(int insize) {
  int size;
  size = insize + 1;
  size += (size % 64 > 56) ? 64 : 0;
  size += 64 - size % 64;
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2d65202c632d612d,%rax
  movabs $0x612d61202c612d63,%rdx
  mov    %rax,-0x450(%rbp)
  mov    %rdx,-0x448(%rbp)
  movabs $0x61202c5a2d61202c,%rax
  movabs $0x2c432d412d0a392d,%rdx
  mov    %rax,-0x440(%rbp)
  mov    %rdx,-0x438(%rbp)
  movabs $0x202c612d432d4520,%rax
  movabs $0x7a2d41202c412d41,%rdx
  mov    %rax,-0x430(%rbp)
  mov    %rdx,-0x428(%rbp)
  movabs $0x302d0a392d41202c,%rax
  movabs $0x2d322d34202c322d,%rdx
  mov    %rax,-0x420(%rbp)
  mov    %rdx,-0x418(%rbp)
  movabs $0x202c302d30202c30,%rax
  movabs $0x5a2d30202c7a2d30,%rdx
  mov    %rax,-0x410(%rbp)
  mov    %rdx,-0x408(%rbp)
  movw   $0xa,-0x400(%rbp)
  lea    -0x3f0(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expand@plt>
  lea    -0x3f0(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: source string:
%s
result string:
%s


assistant: ```c
int main() {
  char s1[] = "-a-c, e-c-a, a-a, a-Z, a-9\n-A-C, E-C-a, A-A, A-z, A-9\n-0-2, 4-2-0, 0-0, 0-z, 0-Z\n";
  char s2[1000];
  expand(s1, s2);
  printf("source string:\n%s\nresult string:\n%s\n", s1, s2);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x458,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  movabs $0x2d65202c632d612d,%rax
  movabs $0x612d61202c612d63,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x61202c5a2d61202c,%rax
  movabs $0x2c432d412d0a392d,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x202c612d432d4520,%rax
  movabs $0x7a2d41202c412d41,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x302d0a392d41202c,%rax
  movabs $0x2d322d34202c322d,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x202c302d30202c30,%rax
  movabs $0x5a2d30202c7a2d30,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movw   $0xa,0x50(%rsp)
  lea    0x60(%rsp),%rbp
  mov    %rsp,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <expand@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x448(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x458,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: source string:
%s
result string:
%s


assistant: ```c
int main() {
  char s1[] = "-a-c, e-c-a, a-a, a-Z, a-9\n-A-C, E-C-a, A-A, A-z, A-9\n-0-2, 4-2-0, 0-0, 0-z, 0-Z\n";
  char s2[1000];
  expand(s1, s2);
  printf("source string:\n%s\nresult string:\n%s\n", s1, s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x458,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%r12
  mov    %rsp,%rbp
  mov    $0xa,%eax
  movaps %xmm0,(%rsp)
  movdqa D26(%rip),%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %ax,0x50(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D43(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D1(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <expand@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x448(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x458,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type_guessed: byte[16]
name: retrieve_data
arguments: label: D26
type_guessed: byte[16]
name: retrieve_data
arguments: label: D43
type_guessed: byte[16]
name: retrieve_data
arguments: label: D1
type_guessed: byte[16]
name: retrieve_data
arguments: label: D7
type_guessed: byte[16]
name: retrieve_data
arguments: label: D28
type_guessed: string

tool: {"D19": [0x2d,0x61,0x2d,0x63,0x2c,0x20,0x65,0x2d,0x63,0x2d,0x61,0x2c,0x20,0x61,0x2d,0x61]}

tool: {"D26": [0x2c,0x20,0x61,0x2d,0x5a,0x2c,0x20,0x61,0x2d,0x39,0x0a,0x2d,0x41,0x2d,0x43,0x2c]}

tool: {"D43": [0x20,0x45,0x2d,0x43,0x2d,0x61,0x2c,0x20,0x41,0x2d,0x41,0x2c,0x20,0x41,0x2d,0x7a]}

tool: {"D1": [0x2c,0x20,0x41,0x2d,0x39,0x0a,0x2d,0x30,0x2d,0x32,0x2c,0x20,0x34,0x2d,0x32,0x2d]}

tool: {"D7": [0x30,0x2c,0x20,0x30,0x2d,0x30,0x2c,0x20,0x30,0x2d,0x7a,0x2c,0x20,0x30,0x2d,0x5a]}

tool: D28: source string:
%s
result string:
%s


assistant: ```c
int main() {
  char s1[] = "-a-c, e-c-a, a-a, a-Z, a-9\n-A-C, E-C-a, A-A, A-z, A-9\n-0-2, 4-2-0, 0-0, 0-z, 0-Z\n";
  char s2[1000];
  expand(s1, s2);
  printf("source string:\n%s\nresult string:\n%s\n", s1, s2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x458,%rsp
  movdqa D33(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%r12
  mov    %rsp,%rbp
  mov    $0xa,%eax
  movaps %xmm0,(%rsp)
  movdqa D36(%rip),%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %ax,0x50(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D39(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D16(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D58(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <expand@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    0x448(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x458,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D33
data_type: byte[16]
name: parse_data
arguments: tag: D36
data_type: byte[16]
name: parse_data
arguments: tag: D39
data_type: byte[16]
name: parse_data
arguments: tag: D16
data_type: byte[16]
name: parse_data
arguments: tag: D58
data_type: byte[16]
name: parse_data
arguments: tag: D46
data_type: string

tool: {"D33": [0x2d,0x61,0x2d,0x63,0x2c,0x20,0x65,0x2d,0x63,0x2d,0x61,0x2c,0x20,0x61,0x2d,0x61]}

tool: {"D36": [0x2c,0x20,0x61,0x2d,0x5a,0x2c,0x20,0x61,0x2d,0x39,0x0a,0x2d,0x41,0x2d,0x43,0x2c]}

tool: {"D39": [0x20,0x45,0x2d,0x43,0x2d,0x61,0x2c,0x20,0x41,0x2d,0x41,0x2c,0x20,0x41,0x2d,0x7a]}

tool: {"D16": [0x2c,0x20,0x41,0x2d,0x39,0x0a,0x2d,0x30,0x2d,0x32,0x2c,0x20,0x34,0x2d,0x32,0x2d]}

tool: {"D58": [0x30,0x2c,0x20,0x30,0x2d,0x30,0x2c,0x20,0x30,0x2d,0x7a,0x2c,0x20,0x30,0x2d,0x5a]}

tool: D46: source string:
%s
result string:
%s


assistant: ```c
int main() {
  char s1[] = "-a-c, e-c-a, a-a, a-Z, a-9\n-A-C, E-C-a, A-A, A-z, A-9\n-0-2, 4-2-0, 0-0, 0-z, 0-Z\n";
  char s2[1000];
  expand(s1, s2);
  printf("source string:\n%s\nresult string:\n%s\n", s1, s2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<base64_wrap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L42
L22:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L16
  cmpl   $0x4b,-0xc(%rbp)
  jne    L18
L16:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0xd,(%rax)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L18:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L38:
  addl   $0x1,-0x10(%rbp)
L42:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L22
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *base64_wrap(char *str, int len) {
  char *tmp = malloc(len * 3 + 1);
  int tmp_len = 0;
  int i;
  int lcount = 0;
  for (i = 0; i < len; ++i) {
    if (str[i] == ' ' || lcount == 75) {
      tmp[tmp_len++] = str[i];
      tmp[tmp_len++] = '\r';
      tmp[tmp_len++] = '\n';
      lcount = 0;
    } else {
      tmp[tmp_len++] = str[i];
      ++lcount;
    }
  }
  tmp[tmp_len] = '\0';
  return tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<base64_wrap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    0x1(%rsi,%rsi,2),%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %ebx,%ebx
  jle    L19
  mov    %rbp,%rdx
  lea    -0x1(%rbx),%eax
  lea    0x1(%rbp,%rax,1),%r8
  mov    $0x0,%edi
  mov    $0x0,%eax
  jmp    L2
L20:
  movslq %eax,%rdi
  mov    %sil,(%rcx,%rdi,1)
  lea    0x2(%rax),%esi
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  movb   $0xd,(%rcx,%rdi,1)
  add    $0x3,%eax
  movslq %esi,%rsi
  movb   $0xa,(%rcx,%rsi,1)
  mov    $0x0,%edi
L17:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L30
L2:
  movzbl (%rdx),%esi
  cmp    $0x4b,%edi
  je     L20
  cmp    $0x20,%sil
  je     L20
  movslq %eax,%r9
  mov    %sil,(%rcx,%r9,1)
  add    $0x1,%edi
  lea    0x1(%rax),%eax
  jmp    L17
L19:
  mov    $0x0,%eax
L30:
  cltq
  movb   $0x0,(%rcx,%rax,1)
  mov    %rcx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *base64_wrap(char *str, int len) {
  char *tmp = malloc(len * 3 + 1);
  int tmp_len = 0;
  int i;
  int lcount = 0;
  for (i = 0; i < len; ++i) {
    if (str[i] == ' ' || lcount == 75) {
      tmp[tmp_len++] = str[i];
      tmp[tmp_len++] = '\r';
      tmp[tmp_len++] = '\n';
      lcount = 0;
    } else {
      tmp[tmp_len++] = str[i];
      ++lcount;
    }
  }
  tmp[tmp_len] = '\0';
  return tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<base64_wrap>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rsi,%rsi,2),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L15
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  xor    %r9d,%r9d
  lea    0x1(%rbx,%rax,1),%r10
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax)
L6:
  cmp    $0x20,%sil
  je     L36
  add    $0x1,%rdi
  add    $0x1,%r9d
  mov    %ecx,%eax
  cmp    %rdi,%r10
  je     L54
L29:
  movzbl (%rdi),%esi
  movslq %eax,%rdx
  lea    0x1(%rax),%ecx
  add    %r8,%rdx
  mov    %sil,(%rdx)
  cmp    $0x4b,%r9d
  jne    L6
L36:
  lea    0x2(%rax),%edx
  movslq %ecx,%rcx
  add    $0x1,%rdi
  add    $0x3,%eax
  movslq %edx,%rdx
  movb   $0xd,(%r8,%rcx,1)
  xor    %r9d,%r9d
  movb   $0xa,(%r8,%rdx,1)
  cmp    %rdi,%r10
  jne    L29
L54:
  cltq
  add    %r8,%rax
L15:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *base64_wrap(char *str, int len) {
  char *tmp = malloc(len * 3 + 1);
  int tmp_len = 0;
  int i;
  int lcount = 0;
  for (i = 0; i < len; ++i) {
    if (str[i] == ' ' || lcount == 75) {
      tmp[tmp_len++] = str[i];
      tmp[tmp_len++] = '\r';
      tmp[tmp_len++] = '\n';
      lcount = 0;
    } else {
      tmp[tmp_len++] = str[i];
      ++lcount;
    }
  }
  tmp[tmp_len] = '\0';
  return tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base64_wrap>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rsi,%rsi,2),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L32
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  xor    %r9d,%r9d
  lea    0x1(%rbx,%rax,1),%r10
  xor    %eax,%eax
  jmp    L55
  nopl   0x0(%rax)
L3:
  cmp    $0x20,%sil
  je     L8
  add    $0x1,%rdi
  add    $0x1,%r9d
  mov    %ecx,%eax
  cmp    %rdi,%r10
  je     L59
L55:
  movzbl (%rdi),%esi
  movslq %eax,%rdx
  lea    0x1(%rax),%ecx
  add    %r8,%rdx
  mov    %sil,(%rdx)
  cmp    $0x4b,%r9d
  jne    L3
L8:
  lea    0x2(%rax),%edx
  movslq %ecx,%rcx
  add    $0x1,%rdi
  add    $0x3,%eax
  movslq %edx,%rdx
  movb   $0xd,(%r8,%rcx,1)
  xor    %r9d,%r9d
  movb   $0xa,(%r8,%rdx,1)
  cmp    %rdi,%r10
  jne    L55
L59:
  cltq
  add    %r8,%rax
L32:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *base64_wrap(char *str, int len) {
  char *tmp = malloc(len * 3 + 1);
  int tmp_len = 0;
  int i;
  int lcount = 0;
  for (i = 0; i < len; ++i) {
    if (str[i] == ' ' || lcount == 75) {
      tmp[tmp_len++] = str[i];
      tmp[tmp_len++] = '\r';
      tmp[tmp_len++] = '\n';
      lcount = 0;
    } else {
      tmp[tmp_len++] = str[i];
      ++lcount;
    }
  }
  tmp[tmp_len] = '\0';
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<libewf_convert_date_header2_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L73
  mov    $0x0,%eax
  jmp    L22
L73:
  mov    $0x14,%edi
  call   <libewf_header_value_string_alloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <atoll@plt>
  mov    %eax,-0x24(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  cmpl   $0x2,-0x3c(%rbp)
  jne    L66
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L56
L66:
  cmpl   $0x1,-0x3c(%rbp)
  jne    L56
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  lea    D7(%rip),%rdx
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    %rax,-0x20(%rbp)
L56:
  cmpq   $0x0,-0x20(%rbp)
  jne    L16
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L22
L16:
  mov    -0x18(%rbp),%rax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D6: %m/%d/%Y %H:%M:%S

tool: D7: %d/%m/%Y %H:%M:%S

assistant: ```c
char *libewf_convert_date_header2_value(char *header_value, uint8_t date_format) {
  char *date_string;
  time_t timestamp;
  struct tm *time_elements;
  size_t result = 0;
  if (header_value == NULL) {
    return (NULL);
  }
  date_string = libewf_header_value_string_alloc(20);
  timestamp = atoll(header_value);
  time_elements = localtime(&timestamp);
  if (date_format == 0x02) {
    result = strftime(date_string, 20, "%m/%d/%Y %H:%M:%S", time_elements);
  } else if (date_format == 0x01) {
    result = strftime(date_string, 20, "%d/%m/%Y %H:%M:%S", time_elements);
  }
  if (result == 0) {
    free(date_string);
    return (NULL);
  }
  return (date_string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<libewf_convert_date_header2_value>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L20
  mov    %esi,%r12d
  mov    $0x14,%edi
  call   <libewf_header_value_string_alloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <atoll@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  cmp    $0x2,%r12d
  je     L77
  cmp    $0x1,%r12d
  jne    L29
  mov    %rax,%rcx
  lea    D4(%rip),%rdx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
L58:
  test   %rax,%rax
  je     L29
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L77:
  mov    %rax,%rcx
  lea    D1(%rip),%rdx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  jmp    L58
L29:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L5
L20:
  mov    %rdi,%rbx
  jmp    L5
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string
name: read_data
arguments: data_label: D1
data_type: string

tool: D4: %d/%m/%Y %H:%M:%S

tool: D1: %m/%d/%Y %H:%M:%S

assistant: ```c
char *libewf_convert_date_header2_value(char *header_value, uint8_t date_format) {
  char *date_string;
  time_t timestamp;
  struct tm *time_elements;
  size_t result = 0;
  if (header_value == NULL) {
    return (NULL);
  }
  date_string = libewf_header_value_string_alloc(20);
  timestamp = atoll(header_value);
  time_elements = localtime(&timestamp);
  if (date_format == 0x02) {
    result = strftime(date_string, 20, "%m/%d/%Y %H:%M:%S", time_elements);
  } else if (date_format == 0x01) {
    result = strftime(date_string, 20, "%d/%m/%Y %H:%M:%S", time_elements);
  }
  if (result == 0) {
    free(date_string);
    return (NULL);
  }
  return (date_string);
}
```