ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x584953,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  movq   $0x5244,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  mov    %rsp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x20(%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L4
L13:
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  call   <encrytion@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    %rsp,%rbp
  mov    %ecx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Padded@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9:  padded output: %s


assistant: ```c
int main() {
  int c, m, k;
  char *n, *e;
  char to_encryted[20] = "SIX";
  char key[20] = "DR";
  char temp[20];
  k = strlen(to_encryted);
  c = strlen(key);
  m = k % c;
  if (m != 0) {
    Padded(to_encryted, k, c);
    printf(" padded output: %s\n", to_encryted);
  }
  encrytion(to_encryted, key);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r13
  movq   $0x584953,(%rsp)
  mov    %rbp,%rdi
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  movq   $0x5244,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L27
L8:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <encrytion@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %r8d,%edx
  call   <Padded@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1:  padded output: %s


assistant: ```c
int main() {
  int c, m, k;
  char *n, *e;
  char to_encryted[20] = "SIX";
  char key[20] = "DR";
  char temp[20];
  k = strlen(to_encryted);
  c = strlen(key);
  m = k % c;
  if (m != 0) {
    Padded(to_encryted, k, c);
    printf(" padded output: %s\n", to_encryted);
  }
  encrytion(to_encryted, key);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r13
  movq   $0x584953,(%rsp)
  mov    %rbp,%rdi
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  movq   $0x5244,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L10
L2:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <encrytion@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %r8d,%edx
  call   <Padded@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4:  padded output: %s


assistant: ```c
int main() {
  int c, m, k;
  char *n, *e;
  char to_encryted[20] = "SIX";
  char key[20] = "DR";
  char temp[20];
  k = strlen(to_encryted);
  c = strlen(key);
  m = k % c;
  if (m != 0) {
    Padded(to_encryted, k, c);
    printf(" padded output: %s\n", to_encryted);
  }
  encrytion(to_encryted, key);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vis5d_mem_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mem_free@plt>
  nop
  leave
  ret
```

assistant: ```c
void vis5d_mem_free(void *ptr) {
  mem_free(ptr);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vis5d_mem_free>:
  endbr64
  sub    $0x8,%rsp
  call   <mem_free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void vis5d_mem_free(void *ptr) {
  mem_free(ptr);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vis5d_mem_free>:
  endbr64
  jmp    1050 <mem_free@plt>
```

assistant: ```c
void vis5d_mem_free(void *ptr) {
  mem_free(ptr);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vis5d_mem_free>:
  endbr64
  jmp    1050 <mem_free@plt>
```

assistant: ```c
void vis5d_mem_free(void *ptr) {
  mem_free(ptr);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    -0x8(%rbp),%eax
  jmp    L10
L4:
  mov    -0xc(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  if (a == 0)
    return b;
  else
    return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  test   %edi,%edi
  mov    %edx,%eax
  cmove  %esi,%eax
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  if (a == 0)
    return b;
  else
    return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f>:
  endbr64
  test   %edi,%edi
  mov    %edx,%eax
  cmove  %esi,%eax
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  if (a == 0)
    return b;
  else
    return c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  test   %edi,%edi
  mov    %edx,%eax
  cmove  %esi,%eax
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  if (a == 0)
    return b;
  else
    return c;
}
```
user: What is the c source code of the assembly code below?

```asm
<fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fatal(const char *msg) {
  fputs(msg, stderr);
  exit(EXIT_FAILURE);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <fputs@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fatal(const char *msg) {
  fputs(msg, stderr);
  exit(EXIT_FAILURE);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  call   <fputs@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fatal(const char *msg) {
  fputs(msg, stderr);
  exit(EXIT_FAILURE);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  call   <fputs@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fatal(const char *msg) {
  fputs(msg, stderr);
  exit(EXIT_FAILURE);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x22,%eax
  je     L251
  cmp    $0x22,%eax
  jg     L236
  cmp    $0x20,%eax
  je     L150
  cmp    $0x20,%eax
  jg     L236
  test   %eax,%eax
  je     L150
  test   %eax,%eax
  js     L236
  sub    $0x9,%eax
  cmp    $0x1,%eax
  ja     L236
  jmp    L150
L251:
  addq   $0x1,-0x8(%rbp)
  jmp    L254
L109:
  addq   $0x1,-0x8(%rbp)
L254:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L165
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L165
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L109
L165:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L166
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  jmp    L166
L153:
  addq   $0x1,-0x8(%rbp)
L236:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L101
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L101
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L101
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L153
L101:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L40
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  jmp    L40
L150:
  nop
  jmp    L184
L166:
  nop
  jmp    L184
L40:
  nop
  jmp    L184
L111:
  addq   $0x1,-0x8(%rbp)
L184:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L111
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L111
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L111
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skip(char *ptr) {
  switch (*ptr) {
  case '\0':
  case ' ':
  case '\t':
  case '\n':
    break;
  case '\"':
    ptr++;
    while ((*ptr != '\"') && (*ptr != '\0') && (*ptr != '\n')) {
      ptr++;
    }
    if (*ptr != '\0') {
      *ptr++ = '\0';
    }
    break;
  default:
    while ((*ptr != ' ') && (*ptr != '\t') && (*ptr != '\0') && (*ptr != '\n')) {
      ptr++;
    }
    if (*ptr != '\0') {
      *ptr++ = '\0';
    }
    break;
  }
  while ((*ptr == ' ') || (*ptr == '\t') || (*ptr == '\n')) {
    ptr++;
  }
  return (ptr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x22,%dl
  je     L159
  jg     L170
  cmp    $0xa,%dl
  jg     L77
  cmp    $0x8,%dl
  jg     L139
  test   %dl,%dl
  je     L185
L170:
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L12
  test   $0xdf,%dl
  je     L12
L162:
  add    $0x1,%rax
  movzbl (%rax),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L12
  test   $0xdf,%dl
  jne    L162
L12:
  test   %dl,%dl
  je     L139
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rax
  jmp    L139
L77:
  cmp    $0x20,%dl
  jne    L170
L106:
  add    $0x1,%rax
  movzbl (%rax),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L106
  cmp    $0x20,%dl
  je     L106
L185:
  ret
L159:
  lea    0x1(%rdi),%rdx
  movzbl 0x1(%rdi),%ecx
  cmp    $0x22,%cl
  ja     L192
  movabs $0x400000401,%rax
  bt     %rcx,%rax
  jb     L70
L192:
  movabs $0x400000401,%rax
L19:
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    $0x22,%cl
  ja     L19
  bt     %rcx,%rax
  jae    L19
L70:
  mov    %rdx,%rax
  test   %cl,%cl
  je     L139
  lea    0x1(%rdx),%rax
  movb   $0x0,(%rdx)
L139:
  movzbl (%rax),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L106
  cmp    $0x20,%dl
  je     L106
  jmp    L185
```

assistant: ```c
char *skip(char *ptr) {
  switch (*ptr) {
  case '\0':
  case ' ':
  case '\t':
  case '\n':
    break;
  case '\"':
    ptr++;
    while ((*ptr != '\"') && (*ptr != '\0') && (*ptr != '\n')) {
      ptr++;
    }
    if (*ptr != '\0') {
      *ptr++ = '\0';
    }
    break;
  default:
    while ((*ptr != ' ') && (*ptr != '\t') && (*ptr != '\0') && (*ptr != '\n')) {
      ptr++;
    }
    if (*ptr != '\0') {
      *ptr++ = '\0';
    }
    break;
  }
  while ((*ptr == ' ') || (*ptr == '\t') || (*ptr == '\n')) {
    ptr++;
  }
  return (ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skip>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x22,%dl
  je     L225
  jg     L235
  cmp    $0xa,%dl
  jg     L226
  cmp    $0x8,%dl
  jg     L89
  test   %dl,%dl
  jne    L139
  ret
L226:
  cmp    $0x20,%dl
  jne    L235
  nopl   (%rax)
L221:
  add    $0x1,%rax
L46:
  movzbl (%rax),%edx
L89:
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L221
  cmp    $0x20,%dl
  je     L221
  ret
  nopl   (%rax)
L130:
  movzbl 0x1(%rax),%edx
  cmp    $0x20,%dl
  je     L85
  cmp    $0x9,%dl
  je     L85
  mov    %rcx,%rax
L235:
  test   %dl,%dl
  je     L46
L139:
  lea    0x1(%rax),%rcx
  cmp    $0xa,%dl
  jne    L130
L172:
  movb   $0x0,(%rax)
  movzbl 0x1(%rax),%edx
  mov    %rcx,%rax
  jmp    L89
  nopw   0x0(%rax,%rax,1)
L225:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L25
  cmp    $0x22,%al
  jne    L81
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L24:
  movzbl (%rcx),%eax
  cmp    $0x22,%al
  je     L4
  test   %al,%al
  je     L25
L81:
  mov    %rcx,%rdx
  add    $0x1,%rcx
  cmp    $0xa,%al
  jne    L24
L35:
  movb   $0x0,(%rdx)
  lea    0x1(%rdx),%rax
  movzbl 0x1(%rdx),%edx
  jmp    L89
L4:
  test   %al,%al
  jne    L223
L25:
  movzbl (%rcx),%edx
  mov    %rcx,%rax
  jmp    L89
L85:
  test   %dl,%dl
  je     L25
  mov    %rcx,%rax
  add    $0x1,%rcx
  jmp    L172
L223:
  mov    %rcx,%rdx
  jmp    L35
```

assistant: ```c
char *skip(char *ptr) {
  switch (*ptr) {
  case '\0':
  case ' ':
  case '\t':
  case '\n':
    break;
  case '\"':
    ptr++;
    while ((*ptr != '\"') && (*ptr != '\0') && (*ptr != '\n')) {
      ptr++;
    }
    if (*ptr != '\0') {
      *ptr++ = '\0';
    }
    break;
  default:
    while ((*ptr != ' ') && (*ptr != '\t') && (*ptr != '\0') && (*ptr != '\n')) {
      ptr++;
    }
    if (*ptr != '\0') {
      *ptr++ = '\0';
    }
    break;
  }
  while ((*ptr == ' ') || (*ptr == '\t') || (*ptr == '\n')) {
    ptr++;
  }
  return (ptr);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<skip>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x22,%dl
  je     L72
  jg     L185
  cmp    $0xa,%dl
  jg     L57
  cmp    $0x8,%dl
  jg     L244
  test   %dl,%dl
  jne    L129
L26:
  ret
L57:
  cmp    $0x20,%dl
  jne    L185
  nopl   (%rax)
L221:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
L244:
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L221
  cmp    $0x20,%dl
  je     L221
  ret
  xchg   %ax,%ax
L129:
  lea    0x1(%rax),%rcx
  cmp    $0xa,%dl
  je     L150
  nopl   0x0(%rax)
L16:
  movzbl 0x1(%rax),%edx
  mov    %rcx,%rax
  cmp    $0x20,%dl
  je     L77
  cmp    $0x9,%dl
  je     L77
L185:
  test   %dl,%dl
  je     L26
  lea    0x1(%rax),%rcx
  cmp    $0xa,%dl
  jne    L16
L150:
  movb   $0x0,(%rax)
  movzbl 0x1(%rax),%edx
  mov    %rcx,%rax
  jmp    L244
  nopw   0x0(%rax,%rax,1)
L72:
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L30
  cmp    $0x22,%dl
  jne    L157
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L17:
  movzbl (%rcx),%edx
  cmp    $0x22,%dl
  je     L30
  test   %dl,%dl
  je     L30
L157:
  mov    %rcx,%rsi
  add    $0x1,%rcx
  cmp    $0xa,%dl
  jne    L17
L146:
  movb   $0x0,(%rsi)
  movzbl 0x1(%rsi),%edx
  lea    0x1(%rsi),%rax
  jmp    L244
L30:
  mov    %rcx,%rax
  test   %dl,%dl
  je     L26
  mov    %rcx,%rsi
  jmp    L146
L77:
  test   %dl,%dl
  je     L26
  add    $0x1,%rcx
  jmp    L150
```

assistant: ```c
char *skip(char *ptr) {
  switch (*ptr) {
  case '\0':
  case ' ':
  case '\t':
  case '\n':
    break;
  case '\"':
    ptr++;
    while ((*ptr != '\"') && (*ptr != '\0') && (*ptr != '\n')) {
      ptr++;
    }
    if (*ptr != '\0') {
      *ptr++ = '\0';
    }
    break;
  default:
    while ((*ptr != ' ') && (*ptr != '\t') && (*ptr != '\0') && (*ptr != '\n')) {
      ptr++;
    }
    if (*ptr != '\0') {
      *ptr++ = '\0';
    }
    break;
  }
  while ((*ptr == ' ') || (*ptr == '\t') || (*ptr == '\n')) {
    ptr++;
  }
  return (ptr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<workload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x30(%rbp),%r8
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <backprop@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

assistant: ```c
void workload(double weights1[13 * 64], double weights2[64 * 64], double weights3[64 * 3], double biases1[64], double biases2[64], double biases3[3], double training_data[163 * 13], double training_targets[163 * 3]) {
#pragma HLS INTERFACE m_axi port = weights1 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = weights2 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = weights3 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases1 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases2 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases3 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = training_data offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = training_targets offset = slave bundle = gmem
#pragma HLS INTERFACE s_axilite port = weights1 bundle = control
#pragma HLS INTERFACE s_axilite port = weights2 bundle = control
#pragma HLS INTERFACE s_axilite port = weights3 bundle = control
#pragma HLS INTERFACE s_axilite port = biases1 bundle = control
#pragma HLS INTERFACE s_axilite port = biases2 bundle = control
#pragma HLS INTERFACE s_axilite port = biases3 bundle = control
#pragma HLS INTERFACE s_axilite port = training_data bundle = control
#pragma HLS INTERFACE s_axilite port = training_targets bundle = control
#pragma HLS INTERFACE s_axilite port = return bundle = control
  backprop(weights1, weights2, weights3, biases1, biases2, biases3, training_data, training_targets);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<workload>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <backprop@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void workload(double weights1[13 * 64], double weights2[64 * 64], double weights3[64 * 3], double biases1[64], double biases2[64], double biases3[3], double training_data[163 * 13], double training_targets[163 * 3]) {
#pragma HLS INTERFACE m_axi port = weights1 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = weights2 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = weights3 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases1 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases2 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases3 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = training_data offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = training_targets offset = slave bundle = gmem
#pragma HLS INTERFACE s_axilite port = weights1 bundle = control
#pragma HLS INTERFACE s_axilite port = weights2 bundle = control
#pragma HLS INTERFACE s_axilite port = weights3 bundle = control
#pragma HLS INTERFACE s_axilite port = biases1 bundle = control
#pragma HLS INTERFACE s_axilite port = biases2 bundle = control
#pragma HLS INTERFACE s_axilite port = biases3 bundle = control
#pragma HLS INTERFACE s_axilite port = training_data bundle = control
#pragma HLS INTERFACE s_axilite port = training_targets bundle = control
#pragma HLS INTERFACE s_axilite port = return bundle = control
  backprop(weights1, weights2, weights3, biases1, biases2, biases3, training_data, training_targets);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<workload>:
  endbr64
  jmp    1050 <backprop@plt>
```

assistant: ```c
void workload(double weights1[13 * 64], double weights2[64 * 64], double weights3[64 * 3], double biases1[64], double biases2[64], double biases3[3], double training_data[163 * 13], double training_targets[163 * 3]) {
#pragma HLS INTERFACE m_axi port = weights1 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = weights2 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = weights3 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases1 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases2 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases3 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = training_data offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = training_targets offset = slave bundle = gmem
#pragma HLS INTERFACE s_axilite port = weights1 bundle = control
#pragma HLS INTERFACE s_axilite port = weights2 bundle = control
#pragma HLS INTERFACE s_axilite port = weights3 bundle = control
#pragma HLS INTERFACE s_axilite port = biases1 bundle = control
#pragma HLS INTERFACE s_axilite port = biases2 bundle = control
#pragma HLS INTERFACE s_axilite port = biases3 bundle = control
#pragma HLS INTERFACE s_axilite port = training_data bundle = control
#pragma HLS INTERFACE s_axilite port = training_targets bundle = control
#pragma HLS INTERFACE s_axilite port = return bundle = control
  backprop(weights1, weights2, weights3, biases1, biases2, biases3, training_data, training_targets);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<workload>:
  endbr64
  jmp    1050 <backprop@plt>
```

assistant: ```c
void workload(double weights1[13 * 64], double weights2[64 * 64], double weights3[64 * 3], double biases1[64], double biases2[64], double biases3[3], double training_data[163 * 13], double training_targets[163 * 3]) {
#pragma HLS INTERFACE m_axi port = weights1 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = weights2 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = weights3 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases1 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases2 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = biases3 offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = training_data offset = slave bundle = gmem
#pragma HLS INTERFACE m_axi port = training_targets offset = slave bundle = gmem
#pragma HLS INTERFACE s_axilite port = weights1 bundle = control
#pragma HLS INTERFACE s_axilite port = weights2 bundle = control
#pragma HLS INTERFACE s_axilite port = weights3 bundle = control
#pragma HLS INTERFACE s_axilite port = biases1 bundle = control
#pragma HLS INTERFACE s_axilite port = biases2 bundle = control
#pragma HLS INTERFACE s_axilite port = biases3 bundle = control
#pragma HLS INTERFACE s_axilite port = training_data bundle = control
#pragma HLS INTERFACE s_axilite port = training_targets bundle = control
#pragma HLS INTERFACE s_axilite port = return bundle = control
  backprop(weights1, weights2, weights3, biases1, biases2, biases3, training_data, training_targets);
  return;
}
```