ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<rle_compress_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jae    L9
  mov    $0xffffffff,%eax
  jmp    L0
L9:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
L0:
  leave
  ret
```

assistant: ```c
int rle_compress_block(COMP_CTX *ctx, unsigned char *out, unsigned int olen, unsigned char *in, unsigned int ilen) {
  if (olen < (ilen + 1)) {
    return (-1);
  }
  *(out++) = 0;
  memcpy(out, in, ilen);
  return (ilen + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rle_compress_block>:
  endbr64
  push   %rbx
  lea    0x1(%r8),%ebx
  cmp    %edx,%ebx
  ja     L3
  mov    %rsi,%rdi
  mov    %rcx,%rsi
  mov    %r8d,%edx
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  call   <memcpy@plt>
  mov    %ebx,%eax
L12:
  pop    %rbx
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int rle_compress_block(COMP_CTX *ctx, unsigned char *out, unsigned int olen, unsigned char *in, unsigned int ilen) {
  if (olen < (ilen + 1)) {
    return (-1);
  }
  *(out++) = 0;
  memcpy(out, in, ilen);
  return (ilen + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rle_compress_block>:
  endbr64
  push   %rbx
  lea    0x1(%r8),%ebx
  cmp    %edx,%ebx
  ja     L8
  mov    %rsi,%rdi
  mov    %r8d,%edx
  mov    %rcx,%rsi
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  call   <memcpy@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rle_compress_block(COMP_CTX *ctx, unsigned char *out, unsigned int olen, unsigned char *in, unsigned int ilen) {
  if (olen < (ilen + 1)) {
    return (-1);
  }
  *(out++) = 0;
  memcpy(out, in, ilen);
  return (ilen + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rle_compress_block>:
  endbr64
  push   %rbx
  lea    0x1(%r8),%ebx
  cmp    %edx,%ebx
  ja     L4
  mov    %rsi,%rdi
  mov    %r8d,%edx
  mov    %rcx,%rsi
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  call   <memcpy@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rle_compress_block(COMP_CTX *ctx, unsigned char *out, unsigned int olen, unsigned char *in, unsigned int ilen) {
  if (olen < (ilen + 1)) {
    return (-1);
  }
  *(out++) = 0;
  memcpy(out, in, ilen);
  return (ilen + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spec_boundary_val>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r14
  mov    %edx,%r13d
  mov    %rcx,%rbp
  mov    %r8,%rbx
  movq   %xmm0,%r12
  movsd  %xmm1,0x8(%rsp)
  lea    D8(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L82
  test   %r13d,%r13d
  jle    L89
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm1
  lea    0x1(%r13),%esi
  shl    $0x3,%rsi
  mov    $0x8,%eax
L40:
  mov    0x0(%rbp),%rdx
  mov    %r12,(%rdx,%rax,1)
  mov    (%rbx),%rdx
  mov    0x8(%rbx),%rcx
  movapd %xmm1,%xmm0
  subsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rsi
  jne    L40
L89:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L82:
  lea    D23(%rip),%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L89
  mov    %r13d,%ecx
  shr    $0x1f,%ecx
  add    %r13d,%ecx
  sar    %ecx
  cmp    $0x1,%r13d
  jle    L12
  mov    $0x8,%eax
  mov    $0x1,%edx
  movq   D7(%rip),%xmm1
L68:
  mov    0x0(%rbp),%rsi
  movq   $0x0,(%rsi,%rax,1)
  mov    (%rbx),%rsi
  mov    0x8(%rbx),%rdi
  movsd  (%rdi,%rax,1),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,1)
  add    $0x1,%edx
  add    $0x8,%rax
  cmp    %ecx,%edx
  jle    L68
L12:
  lea    0x1(%rcx),%eax
  cmp    %eax,%r13d
  jl     L89
  movsd  0x8(%rsp),%xmm0
  addsd  %xmm0,%xmm0
  cltq
  shl    $0x3,%rax
  lea    -0x1(%r13),%edx
  sub    %ecx,%edx
  add    $0x2,%ecx
  movslq %ecx,%rcx
  add    %rcx,%rdx
  shl    $0x3,%rdx
L35:
  mov    0x0(%rbp),%rcx
  mov    %r12,(%rcx,%rax,1)
  mov    (%rbx),%rcx
  mov    0x8(%rbx),%rsi
  movapd %xmm0,%xmm1
  subsd  (%rsi,%rax,1),%xmm1
  movsd  %xmm1,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L35
  jmp    L89
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: f32[2]

tool: D8: Karman_vortex

tool: D23: flow_over_a_step

tool: {"D7": [0.0,-0.0]}

assistant: ```c
void spec_boundary_val(const char *problem, int imax, int jmax, double **U, double **V, double UI, double VI) {
  int j;
  if (strcmp(problem, "Karman_vortex") == 0) {
    for (j = 1; j < jmax + 1; j++) {
      U[0][j] = UI;
      V[0][j] = 2 * VI - V[1][j];
    }
  } else if (strcmp(problem, "flow_over_a_step") == 0) {
    for (j = 1; j <= jmax / 2; j++) {
      U[0][j] = 0.0;
      V[0][j] = -V[1][j];
    }
    for (j = jmax / 2 + 1; j < jmax + 1; j++) {
      U[0][j] = UI;
      V[0][j] = 2 * VI - V[1][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<spec_boundary_val>:
  endbr64
  push   %r13
  lea    D24(%rip),%rsi
  mov    %rdi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <strcmp@plt>
  movsd  (%rsp),%xmm0
  test   %rax,%rax
  jne    L57
  test   %ebp,%ebp
  jle    L41
  mov    (%rbx),%rdi
  mov    0x8(%r12),%rsi
  lea    0x1(%rbp),%edx
  mov    $0x1,%eax
  movsd  0x8(%rsp),%xmm2
  mov    (%r12),%rcx
  addsd  %xmm2,%xmm2
  nopl   0x0(%rax)
L37:
  movsd  %xmm0,(%rdi,%rax,8)
  movapd %xmm2,%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L37
L41:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  lea    D29(%rip),%rsi
  mov    %r13,%rdi
  movsd  %xmm0,(%rsp)
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L41
  mov    %ebp,%eax
  movsd  (%rsp),%xmm0
  shr    $0x1f,%eax
  add    %ebp,%eax
  sar    %eax
  cmp    $0x1,%ebp
  jle    L25
  mov    (%rbx),%rdi
  mov    0x8(%r12),%rsi
  mov    $0x1,%edx
  mov    (%r12),%rcx
  movq   D13(%rip),%xmm2
  nopl   (%rax)
L77:
  movq   $0x0,(%rdi,%rdx,8)
  movsd  (%rsi,%rdx,8),%xmm1
  xorpd  %xmm2,%xmm1
  movsd  %xmm1,(%rcx,%rdx,8)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jge    L77
L25:
  add    $0x1,%eax
  cmp    %eax,%ebp
  jl     L41
  movsd  0x8(%rsp),%xmm1
  mov    (%rbx),%rsi
  cltq
  mov    0x8(%r12),%rcx
  mov    (%r12),%rdx
  addsd  %xmm1,%xmm1
  nopl   0x0(%rax)
L40:
  movsd  %xmm0,(%rsi,%rax,8)
  movapd %xmm1,%xmm2
  subsd  (%rcx,%rax,8),%xmm2
  movsd  %xmm2,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jge    L40
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D24
type_guessed: string
name: parse_data
arguments: label: D29
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: f32[2]

tool: D24: Karman_vortex

tool: D29: flow_over_a_step

tool: {"D13": [0.0,-0.0]}

assistant: ```c
void spec_boundary_val(const char *problem, int imax, int jmax, double **U, double **V, double UI, double VI) {
  int j;
  if (strcmp(problem, "Karman_vortex") == 0) {
    for (j = 1; j < jmax + 1; j++) {
      U[0][j] = UI;
      V[0][j] = 2 * VI - V[1][j];
    }
  } else if (strcmp(problem, "flow_over_a_step") == 0) {
    for (j = 1; j <= jmax / 2; j++) {
      U[0][j] = 0.0;
      V[0][j] = -V[1][j];
    }
    for (j = jmax / 2 + 1; j < jmax + 1; j++) {
      U[0][j] = UI;
      V[0][j] = 2 * VI - V[1][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  assert((1 << 1) == 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert((1 << 1) == 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert((1 << 1) == 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert((1 << 1) == 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nonmain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x40000,-0xc(%rbp)
  mov    $0x20200004,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
L5:
  mov    $0x2020001c,%eax
  movl   $0x10000,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L33:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <inc@plt>
L41:
  mov    -0xc(%rbp),%eax
  cmp    $0xfffff,%eax
  jbe    L33
  mov    $0x20200028,%eax
  movl   $0x10000,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L4:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <inc@plt>
L15:
  mov    -0xc(%rbp),%eax
  cmp    $0xfffff,%eax
  jbe    L4
  jmp    L5
```

assistant: ```c
int nonmain(void) {
  unsigned int ra;
  ra = 1 << 18;
  *((unsigned int *)0x20200004) = ra;
  while (1) {
    *((unsigned int *)0x2020001C) = 1 << 16;
    for (ra = 0; ra < 0x100000;)
      inc(&ra);
    *((unsigned int *)0x20200028) = 1 << 16;
    for (ra = 0; ra < 0x100000;)
      inc(&ra);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nonmain>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x40000,0x20200004
  lea    0x4(%rsp),%rbx
L20:
  movl   $0x10000,0x2020001c
  movl   $0x0,0x4(%rsp)
L24:
  mov    %rbx,%rdi
  call   <inc@plt>
  cmpl   $0xfffff,0x4(%rsp)
  jbe    L24
  movl   $0x10000,0x20200028
  movl   $0x0,0x4(%rsp)
L10:
  mov    %rbx,%rdi
  call   <inc@plt>
  cmpl   $0xfffff,0x4(%rsp)
  ja     L20
  jmp    L10
```

assistant: ```c
int nonmain(void) {
  unsigned int ra;
  ra = 1 << 18;
  *((unsigned int *)0x20200004) = ra;
  while (1) {
    *((unsigned int *)0x2020001C) = 1 << 16;
    for (ra = 0; ra < 0x100000;)
      inc(&ra);
    *((unsigned int *)0x20200028) = 1 << 16;
    for (ra = 0; ra < 0x100000;)
      inc(&ra);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nonmain>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  movl   $0x40000,0x20200004
  nopl   0x0(%rax)
L15:
  movl   $0x10000,0x2020001c
  movl   $0x0,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rdi
  call   <inc@plt>
  cmpl   $0xfffff,0x4(%rsp)
  jbe    L6
  movl   $0x10000,0x20200028
  movl   $0x0,0x4(%rsp)
L23:
  mov    %rbx,%rdi
  call   <inc@plt>
  cmpl   $0xfffff,0x4(%rsp)
  ja     L15
  jmp    L23
```

assistant: ```c
int nonmain(void) {
  unsigned int ra;
  ra = 1 << 18;
  *((unsigned int *)0x20200004) = ra;
  while (1) {
    *((unsigned int *)0x2020001C) = 1 << 16;
    for (ra = 0; ra < 0x100000;)
      inc(&ra);
    *((unsigned int *)0x20200028) = 1 << 16;
    for (ra = 0; ra < 0x100000;)
      inc(&ra);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nonmain>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  movl   $0x40000,0x20200004
  nopl   0x0(%rax)
L28:
  movl   $0x10000,0x2020001c
  movl   $0x0,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbx,%rdi
  call   <inc@plt>
  cmpl   $0xfffff,0x4(%rsp)
  jbe    L18
  movl   $0x10000,0x20200028
  movl   $0x0,0x4(%rsp)
L25:
  mov    %rbx,%rdi
  call   <inc@plt>
  cmpl   $0xfffff,0x4(%rsp)
  ja     L28
  jmp    L25
```

assistant: ```c
int nonmain(void) {
  unsigned int ra;
  ra = 1 << 18;
  *((unsigned int *)0x20200004) = ra;
  while (1) {
    *((unsigned int *)0x2020001C) = 1 << 16;
    for (ra = 0; ra < 0x100000;)
      inc(&ra);
    *((unsigned int *)0x20200028) = 1 << 16;
    for (ra = 0; ra < 0x100000;)
      inc(&ra);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sum_arr_with_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum_arr_with_len(int *arr, int len) {
  int total = 0;
  int i = 0;
  while (i < len) {
    total += arr[i];
    i++;
  }
  return total;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_arr_with_len>:
  endbr64
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L5:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L5
L11:
  mov    %edx,%eax
  ret
L10:
  mov    $0x0,%edx
  jmp    L11
```

assistant: ```c
int sum_arr_with_len(int *arr, int len) {
  int total = 0;
  int i = 0;
  while (i < len) {
    total += arr[i];
    i++;
  }
  return total;
}
```
user: What is the c source code of the assembly code below?

```asm
<sum_arr_with_len>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L17
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum_arr_with_len(int *arr, int len) {
  int total = 0;
  int i = 0;
  while (i < len) {
    total += arr[i];
    i++;
  }
  return total;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum_arr_with_len>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L28
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L59:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L59
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L27
L16:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L36
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L36
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
L36:
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  ret
L28:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L16
```

assistant: ```c
int sum_arr_with_len(int *arr, int len) {
  int total = 0;
  int i = 0;
  while (i < len) {
    total += arr[i];
    i++;
  }
  return total;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<funcT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    $0x30d40,%edi
  call   <usleep@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <execvp@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D18
type: string
name: unpack_data
arguments: data_label: D25
type: string
name: unpack_data
arguments: data_label: D38
type: string

tool: D10: echo

tool: D18: 42

tool: D25: /bin/echo

tool: D38: execvp

assistant: ```c
void *funcT(void *param) {
  char *argv[3] = {"echo", "42", NULL};
  usleep(200000);
  execvp("/bin/echo", argv);
  perror("execvp");
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<funcT>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,(%rsp)
  lea    D0(%rip),%rax
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    $0x30d40,%edi
  call   <usleep@plt>
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <execvp@plt>
  lea    D10(%rip),%rdi
  call   <perror@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D18: echo

tool: D0: 42

tool: D6: /bin/echo

tool: D10: execvp

assistant: ```c
void *funcT(void *param) {
  char *argv[3] = {"echo", "42", NULL};
  usleep(200000);
  execvp("/bin/echo", argv);
  perror("execvp");
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<funcT>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x30d40,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D21(%rip),%rax
  movq   $0x0,0x10(%rsp)
  mov    %rax,(%rsp)
  lea    D34(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <usleep@plt>
  lea    D0(%rip),%rdi
  mov    %rsp,%rsi
  call   <execvp@plt>
  lea    D11(%rip),%rdi
  call   <perror@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D21
datatype: string
name: parse_data
arguments: tag: D34
datatype: string
name: parse_data
arguments: tag: D0
datatype: string
name: parse_data
arguments: tag: D11
datatype: string

tool: D21: echo

tool: D34: 42

tool: D0: /bin/echo

tool: D11: execvp

assistant: ```c
void *funcT(void *param) {
  char *argv[3] = {"echo", "42", NULL};
  usleep(200000);
  execvp("/bin/echo", argv);
  perror("execvp");
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<funcT>:
  endbr64
  sub    $0x28,%rsp
  lea    D20(%rip),%rdx
  mov    $0x30d40,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D5(%rip),%rax
  movq   %rdx,%xmm0
  movq   $0x0,0x10(%rsp)
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <usleep@plt>
  lea    D27(%rip),%rdi
  mov    %rsp,%rsi
  call   <execvp@plt>
  lea    D14(%rip),%rdi
  call   <perror@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type_infered: string
name: extract_symbolic_data
arguments: label: D5
type_infered: string
name: extract_symbolic_data
arguments: label: D27
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string

tool: D20: echo

tool: D5: 42

tool: D27: /bin/echo

tool: D14: execvp

assistant: ```c
void *funcT(void *param) {
  char *argv[3] = {"echo", "42", NULL};
  usleep(200000);
  execvp("/bin/echo", argv);
  perror("execvp");
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inital>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <srand@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: Semance aleatoire : %u


assistant: ```c
void inital(void) {
  unsigned int seed;
  seed = time(NULL);
  printf("Semance aleatoire : %u\n", seed);
  srand(seed);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inital>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <srand@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: Semance aleatoire : %u


assistant: ```c
void inital(void) {
  unsigned int seed;
  seed = time(NULL);
  printf("Semance aleatoire : %u\n", seed);
  srand(seed);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inital>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <time@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1080 <srand@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: Semance aleatoire : %u


assistant: ```c
void inital(void) {
  unsigned int seed;
  seed = time(NULL);
  printf("Semance aleatoire : %u\n", seed);
  srand(seed);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inital>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <time@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1080 <srand@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: Semance aleatoire : %u


assistant: ```c
void inital(void) {
  unsigned int seed;
  seed = time(NULL);
  printf("Semance aleatoire : %u\n", seed);
  srand(seed);
}
```