ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Scan_Image_Density>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbp
  lea    -0x1(%r8),%ecx
  mov    $0x1,%r13d
  shl    %cl,%r13d
  imul   %esi,%edx
  test   %edx,%edx
  je     L41
  mov    %rdi,%r9
  mov    %esi,%r11d
  mov    %edx,%r12d
  shr    %r8b
  movzbl %r8b,%ebx
  mov    %ebx,%r10d
  neg    %r10d
  mov    $0x0,%r8d
  mov    $0x0,%edi
  mov    $0x0,%ecx
  mov    $0x0,%esi
  jmp    L38
L26:
  test   %edx,%edx
  cmove  %edx,%ecx
  cmove  %edx,%esi
  add    $0x1,%edi
  add    $0x3,%r8d
  add    $0x1,%r10d
  cmp    %r12d,%edi
  je     L41
L38:
  mov    %ecx,%eax
  and    $0x1,%eax
  sub    %eax,%esi
  shr    %ecx
  lea    0x1(%r8),%eax
  mov    %r8d,%edx
  movzbl (%r9,%rax,1),%eax
  or     (%r9,%rdx,1),%al
  movzbl %al,%eax
  lea    0x2(%r8),%edx
  cmpb   $0x0,(%r9,%rdx,1)
  setne  %dl
  movzbl %dl,%edx
  or     %edx,%eax
  je     L37
  add    $0x1,%esi
  or     %r13d,%ecx
L37:
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %r11d
  cmp    %ebx,%edx
  jb     L26
  mov    %r10d,%eax
  mov    %sil,0x0(%rbp,%rax,1)
  jmp    L26
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void Scan_Image_Density(unsigned char *Frame, unsigned int Width, unsigned int Height, unsigned char *WinMap, unsigned char WinSize) {
  unsigned int Sum = 0, Window = 0, I, Edge;
  Edge = 1 << (int)(WinSize - 1);
  for (I = 0; I < Width * Height; I++) {
    Sum -= Window & 1;
    Window >>= 1;
    if (Frame[3 * I] | Frame[3 * I + 1] | Frame[3 * I + 2] != 0) {
      Sum += 1;
      Window |= Edge;
    }
    if (I % Width >= (WinSize >> 1))
      WinMap[I - (WinSize >> 1)] = Sum;
    if (I % Width == 0)
      Sum = Window = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Scan_Image_Density>:
  endbr64
  imul   %esi,%edx
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  mov    %rcx,%r12
  lea    -0x1(%r8),%ecx
  push   %rbp
  shl    %cl,%r14d
  push   %rbx
  test   %edx,%edx
  je     L27
  shr    %r8b
  mov    %rdi,%r9
  mov    %esi,%r11d
  mov    %edx,%r13d
  movzbl %r8b,%ebp
  xor    %edi,%edi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %ebp,%r10d
  xor    %esi,%esi
  xor    %ebx,%ebx
  neg    %r10d
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ecx,%eax
  mov    %r8d,%edx
  shr    %ecx
  and    $0x1,%eax
  sub    %eax,%esi
  lea    0x1(%r8),%eax
  movzbl (%r9,%rax,1),%eax
  or     (%r9,%rdx,1),%al
  lea    0x2(%r8),%edx
  cmpb   $0x0,(%r9,%rdx,1)
  movzbl %al,%eax
  setne  %dl
  movzbl %dl,%edx
  or     %edx,%eax
  je     L34
  add    $0x1,%esi
  or     %r14d,%ecx
L34:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %r11d
  cmp    %ebp,%edx
  jb     L8
  mov    %r10d,%eax
  mov    %sil,(%r12,%rax,1)
L8:
  test   %edx,%edx
  cmove  %ebx,%ecx
  cmove  %ebx,%esi
  add    $0x1,%edi
  add    $0x3,%r8d
  add    $0x1,%r10d
  cmp    %r13d,%edi
  jne    L0
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Scan_Image_Density(unsigned char *Frame, unsigned int Width, unsigned int Height, unsigned char *WinMap, unsigned char WinSize) {
  unsigned int Sum = 0, Window = 0, I, Edge;
  Edge = 1 << (int)(WinSize - 1);
  for (I = 0; I < Width * Height; I++) {
    Sum -= Window & 1;
    Window >>= 1;
    if (Frame[3 * I] | Frame[3 * I + 1] | Frame[3 * I + 2] != 0) {
      Sum += 1;
      Window |= Edge;
    }
    if (I % Width >= (WinSize >> 1))
      WinMap[I - (WinSize >> 1)] = Sum;
    if (I % Width == 0)
      Sum = Window = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Scan_Image_Density>:
  endbr64
  imul   %esi,%edx
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  mov    %rcx,%r12
  lea    -0x1(%r8),%ecx
  push   %rbp
  shl    %cl,%r14d
  push   %rbx
  test   %edx,%edx
  je     L7
  shr    %r8b
  mov    %rdi,%r9
  mov    %esi,%r11d
  mov    %edx,%r13d
  movzbl %r8b,%ebp
  xor    %edi,%edi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %ebp,%r10d
  xor    %esi,%esi
  xor    %ebx,%ebx
  neg    %r10d
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %ecx,%eax
  mov    %r8d,%edx
  shr    %ecx
  and    $0x1,%eax
  sub    %eax,%esi
  lea    0x1(%r8),%eax
  movzbl (%r9,%rax,1),%eax
  or     (%r9,%rdx,1),%al
  lea    0x2(%r8),%edx
  cmpb   $0x0,(%r9,%rdx,1)
  movzbl %al,%eax
  setne  %dl
  movzbl %dl,%edx
  or     %edx,%eax
  je     L27
  add    $0x1,%esi
  or     %r14d,%ecx
L27:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %r11d
  cmp    %ebp,%edx
  jb     L1
  mov    %r10d,%eax
  mov    %sil,(%r12,%rax,1)
L1:
  test   %edx,%edx
  cmove  %ebx,%ecx
  cmove  %ebx,%esi
  add    $0x1,%edi
  add    $0x3,%r8d
  add    $0x1,%r10d
  cmp    %r13d,%edi
  jne    L26
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Scan_Image_Density(unsigned char *Frame, unsigned int Width, unsigned int Height, unsigned char *WinMap, unsigned char WinSize) {
  unsigned int Sum = 0, Window = 0, I, Edge;
  Edge = 1 << (int)(WinSize - 1);
  for (I = 0; I < Width * Height; I++) {
    Sum -= Window & 1;
    Window >>= 1;
    if (Frame[3 * I] | Frame[3 * I + 1] | Frame[3 * I + 2] != 0) {
      Sum += 1;
      Window |= Edge;
    }
    if (I % Width >= (WinSize >> 1))
      WinMap[I - (WinSize >> 1)] = Sum;
    if (I % Width == 0)
      Sum = Window = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<glmQuaternionFromVectorAndScalard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void glmQuaternionFromVectorAndScalard(double q[4], const double v[3], const double w) {
  q[0] = w;
  q[1] = v[0];
  q[2] = v[1];
  q[3] = v[2];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<glmQuaternionFromVectorAndScalard>:
  endbr64
  movsd  %xmm0,(%rdi)
  movsd  (%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void glmQuaternionFromVectorAndScalard(double q[4], const double v[3], const double w) {
  q[0] = w;
  q[1] = v[0];
  q[2] = v[1];
  q[3] = v[2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<glmQuaternionFromVectorAndScalard>:
  endbr64
  movsd  %xmm0,(%rdi)
  movsd  (%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void glmQuaternionFromVectorAndScalard(double q[4], const double v[3], const double w) {
  q[0] = w;
  q[1] = v[0];
  q[2] = v[1];
  q[3] = v[2];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glmQuaternionFromVectorAndScalard>:
  endbr64
  movsd  %xmm0,(%rdi)
  movsd  (%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void glmQuaternionFromVectorAndScalard(double q[4], const double v[3], const double w) {
  q[0] = w;
  q[1] = v[0];
  q[2] = v[1];
  q[3] = v[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2a,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x64,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    $0x5,%edi
  call   <test_params@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D18: %d


assistant: ```c
int main() {
  int local = 42;
  printf("%d\n", local);
  int a;
  a = 100;
  printf("%d\n", a);
  test_params(5, 7);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2a,%esi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    $0x5,%edi
  call   <test_params@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: %d


assistant: ```c
int main() {
  int local = 42;
  printf("%d\n", local);
  int a;
  a = 100;
  printf("%d\n", a);
  test_params(5, 7);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    $0x2a,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x64,%esi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    $0x5,%edi
  call   <test_params@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: %d


assistant: ```c
int main() {
  int local = 42;
  printf("%d\n", local);
  int a;
  a = 100;
  printf("%d\n", a);
  test_params(5, 7);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0x2a,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x64,%esi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    $0x5,%edi
  call   <test_params@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main() {
  int local = 42;
  printf("%d\n", local);
  int a;
  a = 100;
  printf("%d\n", a);
  test_params(5, 7);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <foo@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a;
  int *p1 = &a, *p2 = &a;
  foo(&p1, &p2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <foo@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a;
  int *p1 = &a, *p2 = &a;
  foo(&p1, &p2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x4(%rsp),%rax
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  call   <foo@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a;
  int *p1 = &a, *p2 = &a;
  foo(&p1, &p2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x4(%rsp),%rax
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  call   <foo@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a;
  int *p1 = &a, *p2 = &a;
  foo(&p1, &p2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L2
  mov    -0x4(%rbp),%eax
  jmp    L7
L2:
  mov    -0x8(%rbp),%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a < b)
    return a;
  else
    return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a < b)
    return a;
  else
    return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a < b)
    return a;
  else
    return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a < b)
    return a;
  else
    return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jg     L5
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L48
L5:
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L62:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L64
L63:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L64:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L63
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L62
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D10
data_type: string

tool: D3: %d

tool: D14: -1

tool: D10: %d


assistant: ```c
int main() {
  int primeN, n;
  int prime = 2;
  scanf("%d", &primeN);
  if (primeN < 1) {
    printf("-1\n");
    return 0;
  } else {
    for (int i = 0; i < primeN; i++) {
      for (n = prime; isPrime(n) == 0; n++) {
        prime = n + 1;
      }
      prime += 1;
    }
  }
  printf("%d\n", n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
  mov    $0x2,%eax
  cmpl   $0x0,0x4(%rsp)
  jg     L32
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L23
L33:
  add    $0x1,%ebx
L39:
  mov    %ebx,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L33
  lea    0x1(%rbx),%eax
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L56
L32:
  mov    %eax,%ebx
  jmp    L39
L56:
  mov    %ebx,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D25
type: string
name: read_data
arguments: tag: D7
type: string
name: read_data
arguments: tag: D10
type: string

tool: D25: %d

tool: D7: -1

tool: D10: %d


assistant: ```c
int main() {
  int primeN, n;
  int prime = 2;
  scanf("%d", &primeN);
  if (primeN < 1) {
    printf("-1\n");
    return 0;
  } else {
    for (int i = 0; i < primeN; i++) {
      for (n = prime; isPrime(n) == 0; n++) {
        prime = n + 1;
      }
      prime += 1;
    }
  }
  printf("%d\n", n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L9
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%edi
  call   <isPrime@plt>
  mov    %ebx,%esi
  add    $0x1,%ebx
  test   %rax,%rax
  je     L14
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jg     L14
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L31
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D25
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string
name: unpack_data
arguments: data_label: D3
datatype: string

tool: D25: %d

tool: D16: %d


tool: D3: -1

assistant: ```c
int main() {
  int primeN, n;
  int prime = 2;
  scanf("%d", &primeN);
  if (primeN < 1) {
    printf("-1\n");
    return 0;
  } else {
    for (int i = 0; i < primeN; i++) {
      for (n = prime; isPrime(n) == 0; n++) {
        prime = n + 1;
      }
      prime += 1;
    }
  }
  printf("%d\n", n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L16
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %ebx,%edi
  call   <isPrime@plt>
  mov    %ebx,%esi
  add    $0x1,%ebx
  test   %rax,%rax
  je     L25
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jg     L25
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  jmp    L21
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D20
data_type: string

tool: D28: %d

tool: D14: %d


tool: D20: -1

assistant: ```c
int main() {
  int primeN, n;
  int prime = 2;
  scanf("%d", &primeN);
  if (primeN < 1) {
    printf("-1\n");
    return 0;
  } else {
    for (int i = 0; i < primeN; i++) {
      for (n = prime; isPrime(n) == 0; n++) {
        prime = n + 1;
      }
      prime += 1;
    }
  }
  printf("%d\n", n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<iabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L14
  mov    -0x8(%rbp),%rax
  jmp    L4
L14:
  mov    -0x8(%rbp),%rax
  neg    %rax
L4:
  pop    %rbp
  ret
```

assistant: ```c
long iabs(x)
long x;
{
  if (x >= 0)
    return (long)x;
  return -((long)x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<iabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long iabs(x)
long x;
{
  if (x >= 0)
    return (long)x;
  return -((long)x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<iabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long iabs(x)
long x;
{
  if (x >= 0)
    return (long)x;
  return -((long)x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<iabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long iabs(x)
long x;
{
  if (x >= 0)
    return (long)x;
  return -((long)x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<inst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D53
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D42
type_infered: string
name: extract_symbolic_data
arguments: label: D62
type_infered: string
name: extract_symbolic_data
arguments: label: D45
type_infered: string
name: extract_symbolic_data
arguments: label: D35
type_infered: string
name: extract_symbolic_data
arguments: label: D57
type_infered: string
name: extract_symbolic_data
arguments: label: D43
type_infered: string

tool: D53: 
 <Informacoes>


tool: D4:  /---+X;Y+---\


tool: D42:  |0;0|0;1|0;2|


tool: D62:  +---+---+---+


tool: D45:  |1;0|1;1|1;2|


tool: D35:  |2;0|2;1|2;2|


tool: D57:  \---+---+---/


tool: D43: cls

assistant: ```c
void inst() {
  printf("\n <Informacoes>\n");
  printf(" /---+X;Y+---\\\n");
  printf(" |0;0|0;1|0;2|\n");
  printf(" +---+---+---+\n");
  printf(" |1;0|1;1|1;2|\n");
  printf(" +---+---+---+\n");
  printf(" |2;0|2;1|2;2|\n");
  printf(" \\---+---+---/\n");
  getch();
  system("cls");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inst>:
  endbr64
  push   %rbx
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D78(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  lea    D45(%rip),%rdi
  call   <system@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D47
type: string
name: read_data
arguments: data_tag: D78
type: string
name: read_data
arguments: data_tag: D6
type: string
name: read_data
arguments: data_tag: D36
type: string
name: read_data
arguments: data_tag: D73
type: string
name: read_data
arguments: data_tag: D58
type: string
name: read_data
arguments: data_tag: D44
type: string
name: read_data
arguments: data_tag: D45
type: string

tool: D47: 
 <Informacoes>


tool: D78:  /---+X;Y+---\


tool: D6:  |0;0|0;1|0;2|


tool: D36:  +---+---+---+


tool: D73:  |1;0|1;1|1;2|


tool: D58:  |2;0|2;1|2;2|


tool: D44:  \---+---+---/


tool: D45: cls

assistant: ```c
void inst() {
  printf("\n <Informacoes>\n");
  printf(" /---+X;Y+---\\\n");
  printf(" |0;0|0;1|0;2|\n");
  printf(" +---+---+---+\n");
  printf(" |1;0|1;1|1;2|\n");
  printf(" +---+---+---+\n");
  printf(" |2;0|2;1|2;2|\n");
  printf(" \\---+---+---/\n");
  getch();
  system("cls");
}
```