ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<setSaveWAV>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  lea    D2(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  mov    %rbx,%rdi
  call   <do_output_WAVfile@plt>
L19:
  pop    %rbx
  ret
L2:
  mov    $0x0,%eax
  call   <unknown_com@plt>
  jmp    L19
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: =

assistant: ```c
void setSaveWAV(char *rel, char *filename) {
  if (strcmp(rel, "=") == 0) {
    do_output_WAVfile(filename);
  } else {
    unknown_com();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<setSaveWAV>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    D3(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <do_output_WAVfile@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <unknown_com@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: =

assistant: ```c
void setSaveWAV(char *rel, char *filename) {
  if (strcmp(rel, "=") == 0) {
    do_output_WAVfile(filename);
  } else {
    unknown_com();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setSaveWAV>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    D3(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <do_output_WAVfile@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <unknown_com@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: =

assistant: ```c
void setSaveWAV(char *rel, char *filename) {
  if (strcmp(rel, "=") == 0) {
    do_output_WAVfile(filename);
  } else {
    unknown_com();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L37
L35:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L2:
  mov    -0x8(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L2
  addl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L35
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_image(to, from, nx, ny) float *to, *from;
int nx, ny;
{
  int i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      to[i * nx + j] = from[i * nx + j];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_image>:
  endbr64
  mov    %rdi,%r8
  test   %ecx,%ecx
  jle    L27
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  mov    %edx,%r11d
  jmp    L20
L1:
  movslq %r10d,%rdi
  lea    0x0(,%rdi,4),%rax
  add    %r11,%rdi
  shl    $0x2,%rdi
L35:
  movss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L35
L40:
  add    $0x1,%r9d
  add    %edx,%r10d
  cmp    %r9d,%ecx
  je     L27
L20:
  test   %edx,%edx
  jg     L1
  jmp    L40
L27:
  ret
```

assistant: ```c
void copy_image(to, from, nx, ny) float *to, *from;
int nx, ny;
{
  int i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      to[i * nx + j] = from[i * nx + j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_image>:
  endbr64
  mov    %rsi,%r8
  test   %ecx,%ecx
  jle    L38
  lea    -0x1(%rdx),%r11d
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  add    $0x1,%r11
  nopl   0x0(%rax)
L7:
  test   %edx,%edx
  jle    L36
  movslq %r10d,%rsi
  lea    0x0(,%rsi,4),%rax
  add    %r11,%rsi
  shl    $0x2,%rsi
  cs nopw 0x0(%rax,%rax,1)
L1:
  movss  (%r8,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L1
L36:
  add    $0x1,%r9d
  add    %edx,%r10d
  cmp    %r9d,%ecx
  jne    L7
L38:
  ret
```

assistant: ```c
void copy_image(to, from, nx, ny) float *to, *from;
int nx, ny;
{
  int i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      to[i * nx + j] = from[i * nx + j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<copy_image>:
  endbr64
  test   %ecx,%ecx
  jle    L62
  mov    %edx,%r10d
  test   %edx,%edx
  jle    L62
  push   %r15
  movslq %edx,%rax
  mov    %rsi,%r8
  xor    %r11d,%r11d
  push   %r14
  shl    $0x2,%rax
  xor    %r9d,%r9d
  lea    0x4(%r8),%r15
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  and    $0xfffffffc,%r12d
  push   %rbx
  lea    0x1(%r12),%r14d
  xor    %ebx,%ebx
  mov    %rax,-0x20(%rsp)
  mov    %edx,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%esi
  lea    0x2(%r12),%eax
  mov    %eax,-0x14(%rsp)
  lea    -0x1(%rdx),%eax
  add    $0x1,%rsi
  mov    %eax,-0x18(%rsp)
  mov    %edx,%eax
  shl    $0x4,%rsi
  shl    $0x2,%rax
  mov    %rax,-0x10(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L95:
  mov    %rdi,%rax
  lea    (%rdi,%r9,1),%rdx
  sub    %r15,%rax
  cmp    $0x8,%rax
  jbe    L101
  cmpl   $0x2,-0x18(%rsp)
  lea    (%r9,%r8,1),%rcx
  seta   %bpl
  xor    %eax,%eax
  test   %bpl,%bpl
  je     L101
  nopl   0x0(%rax)
L65:
  movups (%rcx,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L65
  cmp    %r10d,%r12d
  je     L104
  lea    (%r11,%r12,1),%eax
  cltq
  movss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  cmp    %r14d,%r10d
  jle    L104
  lea    (%r11,%r14,1),%eax
  cltq
  movss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  mov    -0x14(%rsp),%eax
  cmp    %eax,%r10d
  jle    L104
  add    %r11d,%eax
  cltq
  movss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
L104:
  add    $0x1,%ebx
  add    -0x20(%rsp),%r9
  add    %r10d,%r11d
  cmp    %ebx,%r13d
  jne    L95
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L101:
  mov    -0x10(%rsp),%rax
  lea    (%rax,%r9,1),%rdx
  mov    %r9,%rax
  nopl   0x0(%rax)
L81:
  movss  (%r8,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L81
  jmp    L104
L62:
  ret
```

assistant: ```c
void copy_image(to, from, nx, ny) float *to, *from;
int nx, ny;
{
  int i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      to[i * nx + j] = from[i * nx + j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L5
L24:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D11
type_infered: string

tool: D16: %lld


tool: D11: %lld

assistant: ```c
int main() {
  long long n;
  while (scanf("%lld", &n) == 1) {
    n = (n * (n + 1)) / 2;
    n *= n;
    printf("%lld\n", n);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D13(%rip),%rbx
  lea    D4(%rip),%r12
  jmp    L2
L19:
  mov    (%rsp),%rdx
  lea    0x1(%rdx),%rax
  imul   %rdx,%rax
  mov    %rax,%rsi
  shr    $0x3f,%rsi
  add    %rax,%rsi
  sar    %rsi
  imul   %rsi,%rsi
  mov    %rsi,(%rsp)
  mov    %r12,%rdi
  call   <printf@plt>
L2:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L19
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D13: %lld

tool: D4: %lld


assistant: ```c
int main() {
  long long n;
  while (scanf("%lld", &n) == 1) {
    n = (n * (n + 1)) / 2;
    n *= n;
    printf("%lld\n", n);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L21
  nop
L24:
  mov    (%rsp),%rdx
  mov    %r12,%rdi
  lea    0x1(%rdx),%rax
  imul   %rdx,%rax
  mov    %rax,%rsi
  shr    $0x3f,%rsi
  add    %rax,%rsi
  sar    %rsi
  imul   %rsi,%rsi
  mov    %rsi,(%rsp)
  call   <printf@plt>
L21:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L24
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D6: %lld


tool: D19: %lld

assistant: ```c
int main() {
  long long n;
  while (scanf("%lld", &n) == 1) {
    n = (n * (n + 1)) / 2;
    n *= n;
    printf("%lld\n", n);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L23
  nop
L17:
  mov    (%rsp),%rdx
  mov    %r12,%rdi
  lea    0x1(%rdx),%rax
  imul   %rdx,%rax
  mov    %rax,%rsi
  shr    $0x3f,%rsi
  add    %rax,%rsi
  sar    %rsi
  imul   %rsi,%rsi
  mov    %rsi,(%rsp)
  call   <printf@plt>
L23:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D7: %lld


tool: D3: %lld

assistant: ```c
int main() {
  long long n;
  while (scanf("%lld", &n) == 1) {
    n = (n * (n + 1)) / 2;
    n *= n;
    printf("%lld\n", n);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D76(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D76(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D58(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strend@plt>
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strend@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strend@plt>
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strend@plt>
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D76
type: string
name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D58
type: string
name: unpack_data
arguments: data_label: D66
type: string

tool: D76: abcdef

tool: D0: def

tool: D58: kef

tool: D66: strend(%s, %s) = %d


assistant: ```c
int main(void) {
  char *s0 = "abcdef";
  char *t0 = "def";
  char *s1 = "abcdef";
  char *t1 = "kef";
  printf("strend(%s, %s) = %d\n", s0, t0, strend(s0, t0));
  printf("strend(%s, %s) = %d\n", s1, t1, strend(s1, t1));
  printf("strend(%s, %s) = %d\n", t0, s0, strend(t0, s0));
  printf("strend(%s, %s) = %d\n", t1, s1, strend(t1, s1));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D25(%rip),%r13
  mov    %r13,%rsi
  lea    D32(%rip),%rbx
  mov    %rbx,%rdi
  call   <strend@plt>
  mov    %eax,%ecx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  lea    D11(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D27(%rip),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strend@plt>
  mov    %eax,%ecx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strend@plt>
  mov    %eax,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strend@plt>
  mov    %eax,%ecx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D32
datatype: string
name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D27
datatype: string

tool: D25: def

tool: D32: abcdef

tool: D11: strend(%s, %s) = %d


tool: D27: kef

assistant: ```c
int main(void) {
  char *s0 = "abcdef";
  char *t0 = "def";
  char *s1 = "abcdef";
  char *t1 = "kef";
  printf("strend(%s, %s) = %d\n", s0, t0, strend(s0, t0));
  printf("strend(%s, %s) = %d\n", s1, t1, strend(s1, t1));
  printf("strend(%s, %s) = %d\n", t0, s0, strend(t0, s0));
  printf("strend(%s, %s) = %d\n", t1, s1, strend(t1, s1));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  mov    %r14,%rsi
  lea    D10(%rip),%r13
  push   %r12
  lea    D22(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D11(%rip),%rbp
  sub    $0x8,%rsp
  call   <strend@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strend@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strend@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strend@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D22
datatype: string
name: parse_data
arguments: tag: D11
datatype: string

tool: D17: def

tool: D10: kef

tool: D22: abcdef

tool: D11: strend(%s, %s) = %d


assistant: ```c
int main(void) {
  char *s0 = "abcdef";
  char *t0 = "def";
  char *s1 = "abcdef";
  char *t1 = "kef";
  printf("strend(%s, %s) = %d\n", s0, t0, strend(s0, t0));
  printf("strend(%s, %s) = %d\n", s1, t1, strend(s1, t1));
  printf("strend(%s, %s) = %d\n", t0, s0, strend(t0, s0));
  printf("strend(%s, %s) = %d\n", t1, s1, strend(t1, s1));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D30(%rip),%r14
  push   %r13
  mov    %r14,%rsi
  lea    D22(%rip),%r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D13(%rip),%rbp
  sub    $0x8,%rsp
  call   <strend@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strend@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strend@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strend@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: D30: def

tool: D22: kef

tool: D28: abcdef

tool: D13: strend(%s, %s) = %d


assistant: ```c
int main(void) {
  char *s0 = "abcdef";
  char *t0 = "def";
  char *s1 = "abcdef";
  char *t1 = "kef";
  printf("strend(%s, %s) = %d\n", s0, t0, strend(s0, t0));
  printf("strend(%s, %s) = %d\n", s1, t1, strend(s1, t1));
  printf("strend(%s, %s) = %d\n", t0, s0, strend(t0, s0));
  printf("strend(%s, %s) = %d\n", t1, s1, strend(t1, s1));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<epk_archive_remove_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <epk_archive_filetype@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <elg_cntl_msg@plt>
  jmp    L1
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <epk_archive_filetype@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <elg_warning@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string
name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D1: Removed %s file %s

tool: D0: Cannot remove %s file %s

assistant: ```c
void epk_archive_remove_file(char *filename) {
  if (unlink(filename) == 0)
    elg_cntl_msg("Removed %s file %s", epk_archive_filetype(filename), filename);
  else
    elg_warning("Cannot remove %s file %s", epk_archive_filetype(filename), filename);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<epk_archive_remove_file>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <unlink@plt>
  test   %rax,%rax
  jne    L17
  mov    %rbx,%rdi
  call   <epk_archive_filetype@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  lea    D0(%rip),%rdi
  call   <elg_cntl_msg@plt>
L10:
  pop    %rbx
  ret
L17:
  mov    %rbx,%rdi
  call   <epk_archive_filetype@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  lea    D5(%rip),%rdi
  call   <elg_warning@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D5
type_infered: string

tool: D0: Removed %s file %s

tool: D5: Cannot remove %s file %s

assistant: ```c
void epk_archive_remove_file(char *filename) {
  if (unlink(filename) == 0)
    elg_cntl_msg("Removed %s file %s", epk_archive_filetype(filename), filename);
  else
    elg_warning("Cannot remove %s file %s", epk_archive_filetype(filename), filename);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<epk_archive_remove_file>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <unlink@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  jne    L8
  call   <epk_archive_filetype@plt>
  mov    %r12,%rdx
  lea    D0(%rip),%rdi
  pop    %r12
  mov    %eax,%esi
  jmp    10a0 <elg_cntl_msg@plt>
  xchg   %ax,%ax
L8:
  call   <epk_archive_filetype@plt>
  mov    %r12,%rdx
  lea    D18(%rip),%rdi
  pop    %r12
  mov    %eax,%esi
  jmp    10b0 <elg_warning@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D18
type: string

tool: D0: Removed %s file %s

tool: D18: Cannot remove %s file %s

assistant: ```c
void epk_archive_remove_file(char *filename) {
  if (unlink(filename) == 0)
    elg_cntl_msg("Removed %s file %s", epk_archive_filetype(filename), filename);
  else
    elg_warning("Cannot remove %s file %s", epk_archive_filetype(filename), filename);
}
```
user: Translate the below assembly code into C programming language:

```asm
<epk_archive_remove_file>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <unlink@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  jne    L0
  call   <epk_archive_filetype@plt>
  mov    %r12,%rdx
  lea    D9(%rip),%rdi
  pop    %r12
  mov    %eax,%esi
  jmp    10a0 <elg_cntl_msg@plt>
  xchg   %ax,%ax
L0:
  call   <epk_archive_filetype@plt>
  mov    %r12,%rdx
  lea    D14(%rip),%rdi
  pop    %r12
  mov    %eax,%esi
  jmp    10b0 <elg_warning@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D14
type: string

tool: D9: Removed %s file %s

tool: D14: Cannot remove %s file %s

assistant: ```c
void epk_archive_remove_file(char *filename) {
  if (unlink(filename) == 0)
    elg_cntl_msg("Removed %s file %s", epk_archive_filetype(filename), filename);
  else
    elg_warning("Cannot remove %s file %s", epk_archive_filetype(filename), filename);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<safe_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  jmp    L1
L12:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int safe_atoi(const char *str) {
  if (str)
    return atoi(str);
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<safe_atoi>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <atoi@plt>
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
int safe_atoi(const char *str) {
  if (str)
    return atoi(str);
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<safe_atoi>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <atoi@plt>
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int safe_atoi(const char *str) {
  if (str)
    return atoi(str);
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<safe_atoi>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <atoi@plt>
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int safe_atoi(const char *str) {
  if (str)
    return atoi(str);
  else
    return 0;
}
```