user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x28,%esi
  mov    $0x1,%edi
  call   <vector@plt>
  mov    %rax,%r12
  lea    D2(%rip),%r15
L52:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    $0x28,%esi
  lea    D93(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D49(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x10(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x27,%eax
  ja     L24
  lea    D101(%rip),%rcx
  lea    D90(%rip),%rdx
  lea    D6(%rip),%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xfffffff8,%r13d
  lea    D67(%rip),%r14
  jmp    L57
L0:
  pxor   %xmm2,%xmm2
  cvtss2sd 0x14(%rsp),%xmm2
  movq   %xmm2,%rbx
  pxor   %xmm6,%xmm6
  cvtss2sd 0xc(%rsp),%xmm6
  movsd  D117(%rip),%xmm7
  movsd  %xmm6,(%rsp)
  addsd  %xmm6,%xmm7
  movapd %xmm7,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm2
  movsd  (%rsp),%xmm0
  mov    %r14,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  add    $0x1,%r13d
  cmp    $0x9,%r13d
  je     L52
L57:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r13d,%xmm0
  divsd  D112(%rip),%xmm0
  pxor   %xmm5,%xmm5
  cvtsd2ss %xmm0,%xmm5
  movss  %xmm5,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  cmpl   $0x0,0x10(%rsp)
  jle    L0
  mov    D106(%rip),%ebp
  mov    $0x1,%ebx
  xorps  D54(%rip),%xmm5
  movss  %xmm5,(%rsp)
L33:
  movd   %ebp,%xmm3
  mulss  (%rsp),%xmm3
  movd   %xmm3,%ebp
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  movaps %xmm3,%xmm0
  divss  %xmm1,%xmm0
  lea    0x14(%rsp),%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <eulsum@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x10(%rsp)
  jge    L33
  jmp    L0
L24:
  mov    $0x28,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <free_vector@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: string
name: unpack_data
arguments: data_tag: D93
datatype: string
name: unpack_data
arguments: data_tag: D49
datatype: string
name: unpack_data
arguments: data_tag: D101
datatype: string
name: unpack_data
arguments: data_tag: D90
datatype: string
name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D67
datatype: string
name: unpack_data
arguments: data_tag: D117
datatype: f64
name: unpack_data
arguments: data_tag: D112
datatype: f64
name: unpack_data
arguments: data_tag: D106
datatype: byte[4]
name: unpack_data
arguments: data_tag: D54
datatype: byte[16]

tool: D2: 
How many terms in polynomial?

tool: D93: Enter n between 1 and %2d. (n=0 to end) 

tool: D49: %d

tool: D101: polynomial

tool: D90: actual

tool: D6: x

tool: D27: %9s %14s %14s


tool: D67: %12.6f %12.6f %12.6f


tool: D117: 1

tool: D112: 10

tool: {"D106": [0x00,0x00,0x80,0xbf]}

tool: {"D54": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int i, j, mval;
  float sum, term, x, xpower, *wksp;
  wksp = vector(1, 40);
  for (;;) {
    printf("\nHow many terms in polynomial?\n");
    printf("Enter n between 1 and %2d. (n=0 to end) ", 40);
    scanf("%d", &mval);
    printf("\n");
    if ((mval <= 0) || (mval > 40))
      break;
    printf("%9s %14s %14s\n", "x", "actual", "polynomial");
    for (i = -8; i <= 8; i++) {
      x = i / 10.0;
      sum = 0.0;
      xpower = -1;
      for (j = 1; j <= mval; j++) {
        xpower *= (-x);
        term = xpower / j;
        eulsum(&sum, term, j, wksp);
      }
      printf("%12.6f %12.6f %12.6f\n", x, log(1.0 + x), sum);
    }
  }
  free_vector(wksp, 1, 40);
  return 0;
}
```