ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverseString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L3
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L3:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L37:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
L13:
  mov    -0x28(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L37
  mov    -0x28(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: str = NULL


assistant: ```c
char *reverseString(char *s) {
  char *right, *left;
  char temp;
  if (s) {
    right = s + strlen(s) - 1;
    left = s;
  } else {
    printf("str = NULL\n");
  }
  while (s != right) {
    temp = *right;
    *right = *left;
    *left = temp;
    left++;
    right--;
  }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reverseString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L13
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  mov    %r12,%rbp
L33:
  cmp    %rbx,%r12
  je     L11
L30:
  movzbl (%rbx),%eax
  movzbl 0x0(%rbp),%edx
  mov    %dl,(%rbx)
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L30
L11:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L33
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: str = NULL


assistant: ```c
char *reverseString(char *s) {
  char *right, *left;
  char temp;
  if (s) {
    right = s + strlen(s) - 1;
    left = s;
  } else {
    printf("str = NULL\n");
  }
  while (s != right) {
    temp = *right;
    *right = *left;
    *left = temp;
    left++;
    right--;
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<reverseString>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L20
  call   <strlen@plt>
  mov    %r12,%rbp
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L23
  nopl   0x0(%rax)
L36:
  movzbl (%rbx),%eax
  movzbl 0x0(%rbp),%edx
  sub    $0x1,%rbx
  add    $0x1,%rbp
  mov    %dl,0x1(%rbx)
  mov    %al,-0x1(%rbp)
L23:
  cmp    %rbx,%r12
  jne    L36
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: str = NULL


assistant: ```c
char *reverseString(char *s) {
  char *right, *left;
  char temp;
  if (s) {
    right = s + strlen(s) - 1;
    left = s;
  } else {
    printf("str = NULL\n");
  }
  while (s != right) {
    temp = *right;
    *right = *left;
    *left = temp;
    left++;
    right--;
  }
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<reverseString>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L0
  call   <strlen@plt>
  mov    %r12,%rbp
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L36
  nopl   0x0(%rax)
L30:
  movzbl (%rbx),%eax
  movzbl 0x0(%rbp),%edx
  sub    $0x1,%rbx
  add    $0x1,%rbp
  mov    %dl,0x1(%rbx)
  mov    %al,-0x1(%rbp)
L36:
  cmp    %rbx,%r12
  jne    L30
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L36
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: str = NULL


assistant: ```c
char *reverseString(char *s) {
  char *right, *left;
  char temp;
  if (s) {
    right = s + strlen(s) - 1;
    left = s;
  } else {
    printf("str = NULL\n");
  }
  while (s != right) {
    temp = *right;
    *right = *left;
    *left = temp;
    left++;
    right--;
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nqueens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L17
  mov    $0x1,%eax
  jmp    L44
L17:
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L26
L35:
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <ok@plt>
  test   %rax,%rax
  je     L2
  addl   $0x1,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nqueens>
  add    %eax,-0x14(%rbp)
L2:
  addl   $0x1,-0x1c(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L35
  mov    -0x14(%rbp),%eax
L44:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

assistant: ```c
uint64_t nqueens(int n, int j, char *a) {
  if (n == j)
    return 1;
  int i, k = 0;
  uint64_t res = 0L;
  for (i = 0; i < n; i++) {
    char *b = (char *)alloca((j + 1) * sizeof(char));
    memcpy(b, a, j * sizeof(char));
    b[j] = i;
    if (ok(j + 1, b)) {
      k++;
      res += nqueens(n, j + 1, b);
    }
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nqueens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x44(%rbp)
  cmp    %esi,%edi
  je     L36
  mov    %edi,%r14d
  mov    %esi,%r13d
  movl   $0x0,-0x44(%rbp)
  test   %edi,%edi
  jle    L36
  mov    $0x0,%r12d
  lea    0x1(%rsi),%r15d
  jmp    L31
L22:
  add    $0x1,%r12d
  cmp    %r12d,%r14d
  je     L36
L31:
  mov    %r15d,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    %r13d,%edx
  mov    -0x50(%rbp),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %r13d,%rax
  mov    %r12b,(%rbx,%rax,1)
  mov    %rbx,%rsi
  mov    %r15d,%edi
  call   <ok@plt>
  test   %rax,%rax
  je     L22
  mov    %rbx,%rdx
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <nqueens>
  add    %eax,-0x44(%rbp)
  jmp    L22
L36:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    -0x44(%rbp),%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t nqueens(int n, int j, char *a) {
  if (n == j)
    return 1;
  int i, k = 0;
  uint64_t res = 0L;
  for (i = 0; i < n; i++) {
    char *b = (char *)alloca((j + 1) * sizeof(char));
    memcpy(b, a, j * sizeof(char));
    b[j] = i;
    if (ok(j + 1, b)) {
      k++;
      res += nqueens(n, j + 1, b);
    }
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nqueens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x4c(%rbp)
  cmp    %esi,%edi
  je     L19
  movl   $0x0,-0x4c(%rbp)
  mov    %edi,%r12d
  test   %edi,%edi
  jle    L19
  movslq %esi,%rax
  mov    %esi,%r13d
  lea    0x1(%rsi),%r14d
  xor    %ebx,%ebx
  mov    %rax,-0x58(%rbp)
L6:
  mov    %r14d,%edi
  call   <alloca@plt>
  mov    -0x48(%rbp),%rsi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memcpy@plt>
  mov    -0x58(%rbp),%rax
  mov    %r15,%rsi
  mov    %r14d,%edi
  mov    %bl,(%r15,%rax,1)
  call   <ok@plt>
  test   %rax,%rax
  jne    L44
L8:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L6
L19:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    -0x4c(%rbp),%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L44:
  mov    %r15,%rdx
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <nqueens>
  add    %eax,-0x4c(%rbp)
  jmp    L8
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t nqueens(int n, int j, char *a) {
  if (n == j)
    return 1;
  int i, k = 0;
  uint64_t res = 0L;
  for (i = 0; i < n; i++) {
    char *b = (char *)alloca((j + 1) * sizeof(char));
    memcpy(b, a, j * sizeof(char));
    b[j] = i;
    if (ok(j + 1, b)) {
      k++;
      res += nqueens(n, j + 1, b);
    }
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nqueens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x4c(%rbp)
  cmp    %esi,%edi
  je     L17
  movl   $0x0,-0x4c(%rbp)
  mov    %edi,%r12d
  test   %edi,%edi
  jle    L17
  movslq %esi,%rax
  mov    %esi,%r13d
  lea    0x1(%rsi),%r14d
  xor    %ebx,%ebx
  mov    %rax,-0x58(%rbp)
L51:
  mov    %r14d,%edi
  call   <alloca@plt>
  mov    -0x48(%rbp),%rsi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memcpy@plt>
  mov    -0x58(%rbp),%rax
  mov    %r15,%rsi
  mov    %r14d,%edi
  mov    %bl,(%r15,%rax,1)
  call   <ok@plt>
  test   %rax,%rax
  jne    L31
L26:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L51
L17:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    -0x4c(%rbp),%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L31:
  mov    %r15,%rdx
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <nqueens>
  add    %eax,-0x4c(%rbp)
  jmp    L26
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t nqueens(int n, int j, char *a) {
  if (n == j)
    return 1;
  int i, k = 0;
  uint64_t res = 0L;
  for (i = 0; i < n; i++) {
    char *b = (char *)alloca((j + 1) * sizeof(char));
    memcpy(b, a, j * sizeof(char));
    b[j] = i;
    if (ok(j + 1, b)) {
      k++;
      res += nqueens(n, j + 1, b);
    }
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  jmp    L16
L15:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
  addl   $0x9,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x10(%rbp)
  jne    L15
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 1;
  int b = 2;
  int c = 0;
  int d = 5;
  while (a) {
    a += b;
    a += d;
    b += c;
    c += 1;
    d += 9;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x5,%esi
  mov    $0x0,%ecx
  mov    $0x2,%edx
  mov    $0x1,%eax
L3:
  add    %edx,%eax
  add    %esi,%eax
  add    %ecx,%edx
  add    $0x1,%ecx
  add    $0x9,%esi
  test   %eax,%eax
  jne    L3
  ret
```

assistant: ```c
int main() {
  int a = 1;
  int b = 2;
  int c = 0;
  int d = 5;
  while (a) {
    a += b;
    a += d;
    b += c;
    c += 1;
    d += 9;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 1;
  int b = 2;
  int c = 0;
  int d = 5;
  while (a) {
    a += b;
    a += d;
    b += c;
    c += 1;
    d += 9;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 1;
  int b = 2;
  int c = 0;
  int d = 5;
  while (a) {
    a += b;
    a += d;
    b += c;
    c += 1;
    d += 9;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string

tool: D16: btvirt - Bluetooth emulator
Usage:


tool: D21: 	btvirt [options]


tool: D7: options:
	-S                    Create local serial port
	-s                    Create local server sockets
	-l [num]              Number of local controllers
	-L                    Create LE only controller
	-B                    Create BR/EDR only controller
	-A                    Create AMP controller
	-h, --help            Show help options


assistant: ```c
void usage(void) {
  printf("btvirt - Bluetooth emulator\n"
         "Usage:\n");
  printf("\tbtvirt [options]\n");
  printf("options:\n"
         "\t-S                    Create local serial port\n"
         "\t-s                    Create local server sockets\n"
         "\t-l [num]              Number of local controllers\n"
         "\t-L                    Create LE only controller\n"
         "\t-B                    Create BR/EDR only controller\n"
         "\t-A                    Create AMP controller\n"
         "\t-h, --help            Show help options\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D29
type: string

tool: D15: btvirt - Bluetooth emulator
Usage:


tool: D7: 	btvirt [options]


tool: D29: options:
	-S                    Create local serial port
	-s                    Create local server sockets
	-l [num]              Number of local controllers
	-L                    Create LE only controller
	-B                    Create BR/EDR only controller
	-A                    Create AMP controller
	-h, --help            Show help options


assistant: ```c
void usage(void) {
  printf("btvirt - Bluetooth emulator\n"
         "Usage:\n");
  printf("\tbtvirt [options]\n");
  printf("options:\n"
         "\t-S                    Create local serial port\n"
         "\t-s                    Create local server sockets\n"
         "\t-l [num]              Number of local controllers\n"
         "\t-L                    Create LE only controller\n"
         "\t-B                    Create BR/EDR only controller\n"
         "\t-A                    Create AMP controller\n"
         "\t-h, --help            Show help options\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D27
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D15: btvirt - Bluetooth emulator
Usage:


tool: D27: 	btvirt [options]


tool: D17: options:
	-S                    Create local serial port
	-s                    Create local server sockets
	-l [num]              Number of local controllers
	-L                    Create LE only controller
	-B                    Create BR/EDR only controller
	-A                    Create AMP controller
	-h, --help            Show help options


assistant: ```c
void usage(void) {
  printf("btvirt - Bluetooth emulator\n"
         "Usage:\n");
  printf("\tbtvirt [options]\n");
  printf("options:\n"
         "\t-S                    Create local serial port\n"
         "\t-s                    Create local server sockets\n"
         "\t-l [num]              Number of local controllers\n"
         "\t-L                    Create LE only controller\n"
         "\t-B                    Create BR/EDR only controller\n"
         "\t-A                    Create AMP controller\n"
         "\t-h, --help            Show help options\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string

tool: D4: btvirt - Bluetooth emulator
Usage:


tool: D8: 	btvirt [options]


tool: D24: options:
	-S                    Create local serial port
	-s                    Create local server sockets
	-l [num]              Number of local controllers
	-L                    Create LE only controller
	-B                    Create BR/EDR only controller
	-A                    Create AMP controller
	-h, --help            Show help options


assistant: ```c
void usage(void) {
  printf("btvirt - Bluetooth emulator\n"
         "Usage:\n");
  printf("\tbtvirt [options]\n");
  printf("options:\n"
         "\t-S                    Create local serial port\n"
         "\t-s                    Create local server sockets\n"
         "\t-l [num]              Number of local controllers\n"
         "\t-L                    Create LE only controller\n"
         "\t-B                    Create BR/EDR only controller\n"
         "\t-A                    Create AMP controller\n"
         "\t-h, --help            Show help options\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<not_malloced_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x7,%edx
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <customFree@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/felixinfinite/Rutgers_CS_214_Fall_2015/refs/heads/master/EnhancedMalloc/src/main.c

assistant: ```c
void not_malloced_free() {
  int a = 100;
  customFree(&a, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/felixinfinite/Rutgers_CS_214_Fall_2015/refs/heads/master/EnhancedMalloc/src/main.c", 7);
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<not_malloced_free>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x64,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x7,%edx
  lea    D3(%rip),%rsi
  call   <customFree@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/felixinfinite/Rutgers_CS_214_Fall_2015/refs/heads/master/EnhancedMalloc/src/main.c

assistant: ```c
void not_malloced_free() {
  int a = 100;
  customFree(&a, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/felixinfinite/Rutgers_CS_214_Fall_2015/refs/heads/master/EnhancedMalloc/src/main.c", 7);
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<not_malloced_free>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x7,%edx
  lea    D6(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x64,0x4(%rsp)
  call   <customFree@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/felixinfinite/Rutgers_CS_214_Fall_2015/refs/heads/master/EnhancedMalloc/src/main.c

assistant: ```c
void not_malloced_free() {
  int a = 100;
  customFree(&a, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/felixinfinite/Rutgers_CS_214_Fall_2015/refs/heads/master/EnhancedMalloc/src/main.c", 7);
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<not_malloced_free>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x7,%edx
  lea    D4(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x64,0x4(%rsp)
  call   <customFree@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/felixinfinite/Rutgers_CS_214_Fall_2015/refs/heads/master/EnhancedMalloc/src/main.c

assistant: ```c
void not_malloced_free() {
  int a = 100;
  customFree(&a, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/felixinfinite/Rutgers_CS_214_Fall_2015/refs/heads/master/EnhancedMalloc/src/main.c", 7);
  ;
}
```