ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D47(%rip),%rdi
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L78
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D21(%rip),%r13
L28:
  add    $0x1,%ebx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    0x8(%rsp),%ebx
  jl     L28
L78:
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L60
  mov    0xc(%rsp),%edi
  xor    %edx,%edx
  jmp    L42
  nop
L6:
  lea    0x1(%rsi),%edx
  cmp    %edx,%eax
  jle    L60
L42:
  lea    (%rdx,%rax,1),%esi
  sar    %esi
  movslq %esi,%rcx
  cmp    %edi,0x10(%rsp,%rcx,4)
  jl     L6
  jle    L86
  lea    -0x1(%rsi),%eax
  cmp    %edx,%eax
  jg     L42
L60:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L5:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L86:
  add    $0x1,%esi
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L5
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D47
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D21
type_infered: string
name: read_data
arguments: data_tag: D51
type_infered: string
name: read_data
arguments: data_tag: D23
type_infered: string
name: read_data
arguments: data_tag: D54
type_infered: string

tool: D47: ENTER SIZE OF ARRAY :

tool: D18: %d

tool: D9: ENTER ARRAY IN ASCENDING ORDER 

tool: D21: ENTER ELEMENT %d :

tool: D51: ENTER THE ELEMNT TO BE SEARCHED

tool: D23: element not found

tool: D54: ELEMENT AT %d

assistant: ```c
int main() {
  int a[10], n, i, item, flag = 0, low = 0, high, mid;
  printf("ENTER SIZE OF ARRAY :");
  scanf("%d", &n);
  printf("ENTER ARRAY IN ASCENDING ORDER \n");
  for (i = 0; i < n; ++i) {
    printf("ENTER ELEMENT %d :", i + 1);
    scanf("%d", &a[i]);
  }
  printf("ENTER THE ELEMNT TO BE SEARCHED");
  scanf("%d", &item);
  high = n;
  while (low < high) {
    mid = (high + low) / 2;
    if (item > a[mid]) {
      low = mid + 1;
    } else if (item < a[mid]) {
      high = mid - 1;
    } else {
      flag = 1;
      i = mid;
      break;
    }
  }
  if (flag == 0) {
    printf("element not found");
  } else {
    printf("ELEMENT AT %d", i + 1);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D23(%rip),%rdi
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D54(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L27
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D48(%rip),%r13
L83:
  add    $0x1,%ebx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    0x8(%rsp),%ebx
  jl     L83
L27:
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L1
  mov    0xc(%rsp),%edi
  xor    %edx,%edx
  jmp    L87
  nop
L77:
  lea    0x1(%rsi),%edx
  cmp    %edx,%eax
  jle    L1
L87:
  lea    (%rdx,%rax,1),%esi
  sar    %esi
  movslq %esi,%rcx
  cmp    %edi,0x10(%rsp,%rcx,4)
  jl     L77
  jle    L35
  lea    -0x1(%rsi),%eax
  cmp    %edx,%eax
  jg     L87
L1:
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L88:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  add    $0x1,%esi
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L88
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D54
data_type: string
name: disassemble_data
arguments: label: D48
data_type: string
name: disassemble_data
arguments: label: D45
data_type: string
name: disassemble_data
arguments: label: D60
data_type: string
name: disassemble_data
arguments: label: D69
data_type: string

tool: D23: ENTER SIZE OF ARRAY :

tool: D16: %d

tool: D54: ENTER ARRAY IN ASCENDING ORDER 

tool: D48: ENTER ELEMENT %d :

tool: D45: ENTER THE ELEMNT TO BE SEARCHED

tool: D60: element not found

tool: D69: ELEMENT AT %d

assistant: ```c
int main() {
  int a[10], n, i, item, flag = 0, low = 0, high, mid;
  printf("ENTER SIZE OF ARRAY :");
  scanf("%d", &n);
  printf("ENTER ARRAY IN ASCENDING ORDER \n");
  for (i = 0; i < n; ++i) {
    printf("ENTER ELEMENT %d :", i + 1);
    scanf("%d", &a[i]);
  }
  printf("ENTER THE ELEMNT TO BE SEARCHED");
  scanf("%d", &item);
  high = n;
  while (low < high) {
    mid = (high + low) / 2;
    if (item > a[mid]) {
      low = mid + 1;
    } else if (item < a[mid]) {
      high = mid - 1;
    } else {
      flag = 1;
      i = mid;
      break;
    }
  }
  if (flag == 0) {
    printf("element not found");
  } else {
    printf("ELEMENT AT %d", i + 1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_dobldobl_start_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xea,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int write_dobldobl_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(234, a, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_dobldobl_start_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xea,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int write_dobldobl_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(234, a, b, c, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_dobldobl_start_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xea,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int write_dobldobl_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(234, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_dobldobl_start_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xea,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int write_dobldobl_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(234, a, b, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_rotate_left_positive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffff00,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff00,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff000,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0xc,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0x20,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff00,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0x24,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff000,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0x28,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0x2c,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  mov    $0x30,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L63
  mov    $0x1,%eax
  jmp    L80
L63:
  mov    $0x0,%eax
L80:
  leave
  ret
```

assistant: ```c
int test_rotate_left_positive() {
  int num = 0x00FFFF00;
  return 0x00FFFF00 == rotate_left(num, 0) && 0x0FFFF000 == rotate_left(num, 4) && 0xFFFF0000 == rotate_left(num, 8) && 0xFFF0000F == rotate_left(num, 12) && 0xFF0000FF == rotate_left(num, 16) && 0x00FFFF00 == rotate_left(num, 32) && 0x0FFFF000 == rotate_left(num, 36) && 0xFFFF0000 == rotate_left(num, 40) && 0xFFF0000F == rotate_left(num, 44) && 0xFF0000FF == rotate_left(num, 48);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_rotate_left_positive>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff00,%edx
  je     L76
L47:
  add    $0x8,%rsp
  ret
L76:
  mov    $0x4,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff000,%edx
  jne    L47
  mov    $0x8,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff0000,%edx
  jne    L47
  mov    $0xc,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xfff0000f,%edx
  jne    L47
  mov    $0x10,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xff0000ff,%edx
  jne    L47
  mov    $0x20,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff00,%edx
  jne    L47
  mov    $0x24,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff000,%edx
  jne    L47
  mov    $0x28,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff0000,%edx
  jne    L47
  mov    $0x2c,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xfff0000f,%edx
  jne    L47
  mov    $0x30,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L47
```

assistant: ```c
int test_rotate_left_positive() {
  int num = 0x00FFFF00;
  return 0x00FFFF00 == rotate_left(num, 0) && 0x0FFFF000 == rotate_left(num, 4) && 0xFFFF0000 == rotate_left(num, 8) && 0xFFF0000F == rotate_left(num, 12) && 0xFF0000FF == rotate_left(num, 16) && 0x00FFFF00 == rotate_left(num, 32) && 0x0FFFF000 == rotate_left(num, 36) && 0xFFFF0000 == rotate_left(num, 40) && 0xFFF0000F == rotate_left(num, 44) && 0xFF0000FF == rotate_left(num, 48);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_rotate_left_positive>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff00,%eax
  je     L52
L93:
  xor    %eax,%eax
L38:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    $0x4,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff000,%eax
  jne    L93
  mov    $0x8,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L93
  mov    $0xc,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L93
  mov    $0x10,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L93
  mov    $0x20,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff00,%eax
  jne    L93
  mov    $0x24,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff000,%eax
  jne    L93
  mov    $0x28,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L93
  mov    $0x2c,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L93
  mov    $0x30,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L38
```

assistant: ```c
int test_rotate_left_positive() {
  int num = 0x00FFFF00;
  return 0x00FFFF00 == rotate_left(num, 0) && 0x0FFFF000 == rotate_left(num, 4) && 0xFFFF0000 == rotate_left(num, 8) && 0xFFF0000F == rotate_left(num, 12) && 0xFF0000FF == rotate_left(num, 16) && 0x00FFFF00 == rotate_left(num, 32) && 0x0FFFF000 == rotate_left(num, 36) && 0xFFFF0000 == rotate_left(num, 40) && 0xFFF0000F == rotate_left(num, 44) && 0xFF0000FF == rotate_left(num, 48);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_rotate_left_positive>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff00,%eax
  je     L42
L55:
  xor    %eax,%eax
L92:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    $0x4,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff000,%eax
  jne    L55
  mov    $0x8,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L55
  mov    $0xc,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L55
  mov    $0x10,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L55
  mov    $0x20,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff00,%eax
  jne    L55
  mov    $0x24,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff000,%eax
  jne    L55
  mov    $0x28,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L55
  mov    $0x2c,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L55
  mov    $0x30,%esi
  mov    $0xffff00,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L92
```

assistant: ```c
int test_rotate_left_positive() {
  int num = 0x00FFFF00;
  return 0x00FFFF00 == rotate_left(num, 0) && 0x0FFFF000 == rotate_left(num, 4) && 0xFFFF0000 == rotate_left(num, 8) && 0xFFF0000F == rotate_left(num, 12) && 0xFF0000FF == rotate_left(num, 16) && 0x00FFFF00 == rotate_left(num, 32) && 0x0FFFF000 == rotate_left(num, 36) && 0xFFFF0000 == rotate_left(num, 40) && 0xFFF0000F == rotate_left(num, 44) && 0xFF0000FF == rotate_left(num, 48);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L35
  mov    $0x0,%eax
  jmp    L47
L35:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L4
L38:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x28(%rbp)
L4:
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L38
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  imul   -0x28(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L47
L18:
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  add    %rax,-0x38(%rbp)
L20:
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  test   %eax,%eax
  jne    L18
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L47:
  leave
  ret
```

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  len_with = strlen(with);
  ins = orig;
  len_rep = strlen(rep);
  for (count = 0; (tmp = strstr(ins, rep)); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L10
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
  mov    %rbp,%rdi
  mov    $0x0,%r12d
  movslq %eax,%rbx
  jmp    L36
L59:
  lea    (%rax,%rbx,1),%rdi
  add    $0x1,%r12d
L36:
  mov    %r14,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L59
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r13d,%ebx
  mov    %r13d,%eax
  sub    0xc(%rsp),%eax
  imul   %r12d,%eax
  lea    0x1(%rax,%rdx,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%r13
  test   %rax,%rax
  je     L1
  test   %r12d,%r12d
  je     L15
  movslq %ebx,%rax
  mov    %rax,0x10(%rsp)
L25:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  sub    %rbp,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rdx
  lea    (%rax,%rdx,1),%rdi
  mov    %r15,%rsi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  lea    (%rax,%rcx,1),%r13
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  add    %rbx,%rbp
  sub    $0x1,%r12d
  jne    L25
L76:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
L1:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    0x18(%rsp),%r13
  jmp    L76
L10:
  mov    %rdi,0x18(%rsp)
  jmp    L1
```

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  len_with = strlen(with);
  ins = orig;
  len_rep = strlen(rep);
  for (count = 0; (tmp = strstr(ins, rep)); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rdi,%rdi
  je     L31
  mov    %rsi,%rbp
  mov    %rdi,%r12
  mov    %rdx,%rdi
  mov    %rdx,%r13
  call   <strlen@plt>
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  mov    %eax,%r15d
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,0xc(%rsp)
  movslq %eax,%r14
  jmp    L30
  nopl   (%rax)
L23:
  lea    (%rax,%r14,1),%rdi
  add    $0x1,%ebx
L30:
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L23
  mov    %r12,%rdi
  mov    %r15d,%r14d
  call   <strlen@plt>
  mov    %eax,%r9d
  mov    %r15d,%eax
  sub    0xc(%rsp),%eax
  imul   %ebx,%eax
  lea    0x1(%rax,%r9,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rcx
  test   %rax,%rax
  je     L31
  lea    -0x1(%rbx),%r15d
  test   %ebx,%ebx
  je     L56
  movslq %r14d,%rax
  mov    %rcx,%r14
  mov    %rax,0x10(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  sub    %r12,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdx
  mov    %r13,%rsi
  lea    (%rax,%rdx,1),%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  lea    (%rax,%rcx,1),%r14
  add    %rbx,%r12
  sub    $0x1,%r15d
  jae    L13
L60:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L68:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L31:
  movq   $0x0,0x18(%rsp)
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L56:
  mov    0x18(%rsp),%r14
  jmp    L60
```

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  len_with = strlen(with);
  ins = orig;
  len_rep = strlen(rep);
  for (count = 0; (tmp = strstr(ins, rep)); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```