ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<apply_mv_scaling_pocs>:
  endbr64
  sub    %esi,%edi
  sub    %ecx,%edx
  cmp    %edx,%edi
  je     L1
  push   %rbp
  mov    $0x7f,%eax
  mov    %edi,%esi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,%ecx
  mov    $0xffffff80,%eax
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  sar    %eax
  add    $0x4000,%eax
  cltd
  idiv   %ecx
  mov    $0x7f,%edx
  cmp    %edx,%edi
  mov    (%r8),%edi
  cmovg  %edx,%esi
  mov    $0xffffff80,%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  imul   %esi,%eax
  lea    0x20(%rax),%ebp
  mov    $0xfff,%eax
  sar    $0x6,%ebp
  cmp    %eax,%ebp
  cmovg  %eax,%ebp
  mov    $0xfffff000,%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  mov    %ebp,%esi
  call   <get_scaled_mv@plt>
  mov    0x4(%rbx),%edi
  mov    %ebp,%esi
  mov    %eax,(%rbx)
  call   <get_scaled_mv@plt>
  mov    %eax,0x4(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void apply_mv_scaling_pocs(int32_t current_poc, int32_t current_ref_poc, int32_t neighbor_poc, int32_t neighbor_ref_poc, int16_t mv_cand[2]) {
  int32_t diff_current = current_poc - current_ref_poc;
  int32_t diff_neighbor = neighbor_poc - neighbor_ref_poc;
  if (diff_current == diff_neighbor)
    return;
  diff_current = ((((-128)) > (((((127)) < ((diff_current))) ? ((127)) : ((diff_current))))) ? ((-128)) : (((((127)) < ((diff_current))) ? ((127)) : ((diff_current)))));
  diff_neighbor = ((((-128)) > (((((127)) < ((diff_neighbor))) ? ((127)) : ((diff_neighbor))))) ? ((-128)) : (((((127)) < ((diff_neighbor))) ? ((127)) : ((diff_neighbor)))));
  int scale = ((((-4096)) > (((((4095)) < (((diff_current * ((0x4000 + (abs(diff_neighbor) >> 1)) / diff_neighbor) + 32) >> 6))) ? ((4095)) : (((diff_current * ((0x4000 + (abs(diff_neighbor) >> 1)) / diff_neighbor) + 32) >> 6))))) ? ((-4096)) : (((((4095)) < (((diff_current * ((0x4000 + (abs(diff_neighbor) >> 1)) / diff_neighbor) + 32) >> 6))) ? ((4095)) : (((diff_current * ((0x4000 + (abs(diff_neighbor) >> 1)) / diff_neighbor) + 32) >> 6)))));
  mv_cand[0] = get_scaled_mv(mv_cand[0], scale);
  mv_cand[1] = get_scaled_mv(mv_cand[1], scale);
}
```
user: What is the c source code of the assembly code below?

```asm
<apply_mv_scaling_pocs>:
  endbr64
  sub    %esi,%edi
  sub    %ecx,%edx
  cmp    %edx,%edi
  je     L5
  push   %rbp
  mov    $0x7f,%eax
  mov    %edi,%esi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,%ecx
  mov    $0xffffff80,%eax
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  sar    %eax
  add    $0x4000,%eax
  cltd
  idiv   %ecx
  mov    $0x7f,%edx
  cmp    %edx,%edi
  mov    (%r8),%edi
  cmovg  %edx,%esi
  mov    $0xffffff80,%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  imul   %esi,%eax
  lea    0x20(%rax),%ebp
  mov    $0xfff,%eax
  sar    $0x6,%ebp
  cmp    %eax,%ebp
  cmovg  %eax,%ebp
  mov    $0xfffff000,%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  mov    %ebp,%esi
  call   <get_scaled_mv@plt>
  mov    0x4(%rbx),%edi
  mov    %ebp,%esi
  mov    %eax,(%rbx)
  call   <get_scaled_mv@plt>
  mov    %eax,0x4(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void apply_mv_scaling_pocs(int32_t current_poc, int32_t current_ref_poc, int32_t neighbor_poc, int32_t neighbor_ref_poc, int16_t mv_cand[2]) {
  int32_t diff_current = current_poc - current_ref_poc;
  int32_t diff_neighbor = neighbor_poc - neighbor_ref_poc;
  if (diff_current == diff_neighbor)
    return;
  diff_current = ((((-128)) > (((((127)) < ((diff_current))) ? ((127)) : ((diff_current))))) ? ((-128)) : (((((127)) < ((diff_current))) ? ((127)) : ((diff_current)))));
  diff_neighbor = ((((-128)) > (((((127)) < ((diff_neighbor))) ? ((127)) : ((diff_neighbor))))) ? ((-128)) : (((((127)) < ((diff_neighbor))) ? ((127)) : ((diff_neighbor)))));
  int scale = ((((-4096)) > (((((4095)) < (((diff_current * ((0x4000 + (abs(diff_neighbor) >> 1)) / diff_neighbor) + 32) >> 6))) ? ((4095)) : (((diff_current * ((0x4000 + (abs(diff_neighbor) >> 1)) / diff_neighbor) + 32) >> 6))))) ? ((-4096)) : (((((4095)) < (((diff_current * ((0x4000 + (abs(diff_neighbor) >> 1)) / diff_neighbor) + 32) >> 6))) ? ((4095)) : (((diff_current * ((0x4000 + (abs(diff_neighbor) >> 1)) / diff_neighbor) + 32) >> 6)))));
  mv_cand[0] = get_scaled_mv(mv_cand[0], scale);
  mv_cand[1] = get_scaled_mv(mv_cand[1], scale);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_memory_alloc@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  test_memory_alloc();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_memory_alloc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_memory_alloc();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_memory_alloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_memory_alloc();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_memory_alloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_memory_alloc();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<osmo_hexparse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L42
  mov    -0x4(%rbp),%eax
  sar    %eax
  cmp    %eax,-0x24(%rbp)
  jge    L153
L42:
  mov    $0xffffffff,%eax
  jmp    L106
L153:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L151
L160:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x2f,-0xd(%rbp)
  jle    L138
  cmpb   $0x39,-0xd(%rbp)
  jg     L138
  movsbl -0xd(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L2
L138:
  cmpb   $0x60,-0xd(%rbp)
  jle    L12
  cmpb   $0x66,-0xd(%rbp)
  jg     L12
  movsbl -0xd(%rbp),%eax
  sub    $0x57,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L2
L12:
  cmpb   $0x40,-0xd(%rbp)
  jle    L148
  cmpb   $0x46,-0xd(%rbp)
  jg     L148
  movsbl -0xd(%rbp),%eax
  sub    $0x37,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L2
L148:
  mov    $0xffffffff,%eax
  jmp    L106
L2:
  mov    -0xc(%rbp),%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L158
  mov    $0x0,%edx
  jmp    L50
L158:
  mov    $0x4,%edx
L50:
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  or     %esi,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L151:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L160
  mov    -0xc(%rbp),%eax
  sar    %eax
L106:
  leave
  ret
```

assistant: ```c
int osmo_hexparse(const char *str, uint8_t *b, int max_len) {
  int i, l, v;
  l = strlen(str);
  if ((l & 1) || ((l >> 1) > max_len))
    return -1;
  memset(b, 0x00, max_len);
  for (i = 0; i < l; i++) {
    char c = str[i];
    if (c >= '0' && c <= '9')
      v = c - '0';
    else if (c >= 'a' && c <= 'f')
      v = 10 + (c - 'a');
    else if (c >= 'A' && c <= 'F')
      v = 10 + (c - 'A');
    else
      return -1;
    b[i >> 1] |= v << (i & 1 ? 0 : 4);
  }
  return i >> 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<osmo_hexparse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %edx,%r13d
  call   <strlen@plt>
  mov    %eax,%ebx
  and    $0x1,%ebx
  jne    L6
  mov    %eax,%r12d
  sar    %eax
  cmp    %r13d,%eax
  jg     L116
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L123
  mov    %r14,%rsi
  jmp    L12
L84:
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  ja     L128
  movsbl %al,%eax
  sub    $0x57,%eax
L111:
  mov    %ebx,%edx
  sar    %edx
  movslq %edx,%rdx
  test   $0x1,%bl
  sete   %cl
  movzbl %cl,%ecx
  shl    $0x2,%ecx
  shl    %cl,%eax
  or     %eax,0x0(%rbp,%rdx,4)
  add    $0x1,%ebx
  add    $0x1,%rsi
  cmp    %ebx,%r12d
  je     L20
L12:
  movzbl (%rsi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L84
  movsbl %al,%eax
  sub    $0x30,%eax
  jmp    L111
L128:
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L14
  movsbl %al,%eax
  sub    $0x37,%eax
  jmp    L111
L123:
  mov    %ebx,%r12d
L20:
  mov    %r12d,%eax
  sar    %eax
L121:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L121
L116:
  mov    $0xffffffff,%eax
  jmp    L121
L14:
  mov    $0xffffffff,%eax
  jmp    L121
```

assistant: ```c
int osmo_hexparse(const char *str, uint8_t *b, int max_len) {
  int i, l, v;
  l = strlen(str);
  if ((l & 1) || ((l >> 1) > max_len))
    return -1;
  memset(b, 0x00, max_len);
  for (i = 0; i < l; i++) {
    char c = str[i];
    if (c >= '0' && c <= '9')
      v = c - '0';
    else if (c >= 'a' && c <= 'f')
      v = 10 + (c - 'a');
    else if (c >= 'A' && c <= 'F')
      v = 10 + (c - 'A');
    else
      return -1;
    b[i >> 1] |= v << (i & 1 ? 0 : 4);
  }
  return i >> 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<osmo_hexparse>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  and    $0x1,%r12d
  jne    L92
  mov    %eax,%ebp
  sar    %eax
  cmp    %r13d,%eax
  jg     L92
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L95
  mov    %r14,%rsi
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L55:
  movsbl %al,%eax
L21:
  mov    %r12d,%ecx
  mov    %r12d,%edx
  add    $0x1,%r12d
  add    $0x1,%rsi
  not    %ecx
  sar    %edx
  shl    $0x2,%ecx
  movslq %edx,%rdx
  and    $0x4,%ecx
  shl    %cl,%eax
  or     %eax,(%rbx,%rdx,4)
  cmp    %r12d,%ebp
  je     L31
L53:
  movzbl (%rsi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L55
  lea    -0x61(%rdx),%eax
  cmp    $0x5,%al
  ja     L1
  sub    $0x57,%edx
  movsbl %dl,%eax
  jmp    L21
  nopl   0x0(%rax)
L1:
  lea    -0x41(%rdx),%eax
  cmp    $0x5,%al
  ja     L92
  sub    $0x37,%edx
  movsbl %dl,%eax
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L31:
  sar    %r12d
L95:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L92:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int osmo_hexparse(const char *str, uint8_t *b, int max_len) {
  int i, l, v;
  l = strlen(str);
  if ((l & 1) || ((l >> 1) > max_len))
    return -1;
  memset(b, 0x00, max_len);
  for (i = 0; i < l; i++) {
    char c = str[i];
    if (c >= '0' && c <= '9')
      v = c - '0';
    else if (c >= 'a' && c <= 'f')
      v = 10 + (c - 'a');
    else if (c >= 'A' && c <= 'F')
      v = 10 + (c - 'A');
    else
      return -1;
    b[i >> 1] |= v << (i & 1 ? 0 : 4);
  }
  return i >> 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<osmo_hexparse>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  and    $0x1,%r12d
  jne    L11
  mov    %eax,%ebp
  sar    %eax
  cmp    %r13d,%eax
  jg     L11
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L0
  mov    %r14,%rsi
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L55:
  movsbl %al,%eax
L74:
  mov    %r12d,%ecx
  mov    %r12d,%edx
  add    $0x1,%r12d
  add    $0x1,%rsi
  not    %ecx
  sar    %edx
  shl    $0x2,%ecx
  movslq %edx,%rdx
  and    $0x4,%ecx
  shl    %cl,%eax
  or     %eax,(%rbx,%rdx,4)
  cmp    %r12d,%ebp
  je     L5
L13:
  movzbl (%rsi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L55
  lea    -0x61(%rdx),%eax
  cmp    $0x5,%al
  ja     L86
  sub    $0x57,%edx
  movsbl %dl,%eax
  jmp    L74
  nopl   0x0(%rax)
L86:
  lea    -0x41(%rdx),%eax
  cmp    $0x5,%al
  ja     L11
  sub    $0x37,%edx
  movsbl %dl,%eax
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L5:
  sar    %r12d
L0:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L11:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int osmo_hexparse(const char *str, uint8_t *b, int max_len) {
  int i, l, v;
  l = strlen(str);
  if ((l & 1) || ((l >> 1) > max_len))
    return -1;
  memset(b, 0x00, max_len);
  for (i = 0; i < l; i++) {
    char c = str[i];
    if (c >= '0' && c <= '9')
      v = c - '0';
    else if (c >= 'a' && c <= 'f')
      v = 10 + (c - 'a');
    else if (c >= 'A' && c <= 'F')
      v = 10 + (c - 'A');
    else
      return -1;
    b[i >> 1] |= v << (i & 1 ? 0 : 4);
  }
  return i >> 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<zip_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L69
L64:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L38
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L46
L38:
  movl   $0x0,-0x14(%rbp)
L46:
  addq   $0x1,-0x10(%rbp)
L69:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L10
  cmpl   $0x0,-0x14(%rbp)
  je     L10
  subq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *zip_basename(const char *name) {
  char const *p;
  char const *base = name += 0;
  int all_slashes = 1;
  for (p = name; *p; p++) {
    if (((*p) == '/'))
      base = p + 1;
    else
      all_slashes = 0;
  }
  if (*base == '\0' && ((*name) == '/') && all_slashes)
    --base;
  return (char *)base;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<zip_basename>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L30
  lea    0x1(%rdi),%rcx
  mov    %r8d,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
L35:
  cmp    $0x2f,%dl
  cmove  %rcx,%rax
  cmovne %edi,%esi
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L35
  cmpb   $0x0,(%rax)
  je     L19
L30:
  ret
L19:
  test   %esi,%esi
  je     L30
  cmp    $0x2f,%r8b
  sete   %dl
  cmp    $0x1,%dl
  adc    $0xffffffffffffffff,%rax
  jmp    L30
```

assistant: ```c
char *zip_basename(const char *name) {
  char const *p;
  char const *base = name += 0;
  int all_slashes = 1;
  for (p = name; *p; p++) {
    if (((*p) == '/'))
      base = p + 1;
    else
      all_slashes = 0;
  }
  if (*base == '\0' && ((*name) == '/') && all_slashes)
    --base;
  return (char *)base;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<zip_basename>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%r8
  test   %sil,%sil
  je     L3
  mov    %esi,%eax
  mov    $0x1,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  movzbl (%rdi),%eax
  cmove  %rdi,%r8
  cmovne %ecx,%edx
  test   %al,%al
  jne    L31
  cmpb   $0x0,(%r8)
  je     L11
L3:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L11:
  cmp    $0x2f,%sil
  jne    L3
  and    $0x1,%edx
  cmp    $0x1,%dl
  adc    $0xffffffffffffffff,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *zip_basename(const char *name) {
  char const *p;
  char const *base = name += 0;
  int all_slashes = 1;
  for (p = name; *p; p++) {
    if (((*p) == '/'))
      base = p + 1;
    else
      all_slashes = 0;
  }
  if (*base == '\0' && ((*name) == '/') && all_slashes)
    --base;
  return (char *)base;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zip_basename>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%r8
  test   %sil,%sil
  je     L26
  mov    %esi,%eax
  mov    $0x1,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  movzbl (%rdi),%eax
  cmove  %rdi,%r8
  cmovne %ecx,%edx
  test   %al,%al
  jne    L2
  cmpb   $0x0,(%r8)
  je     L24
L26:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L24:
  cmp    $0x2f,%sil
  jne    L26
  and    $0x1,%edx
  cmp    $0x1,%dl
  adc    $0xffffffffffffffff,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *zip_basename(const char *name) {
  char const *p;
  char const *base = name += 0;
  int all_slashes = 1;
  for (p = name; *p; p++) {
    if (((*p) == '/'))
      base = p + 1;
    else
      all_slashes = 0;
  }
  if (*base == '\0' && ((*name) == '/') && all_slashes)
    --base;
  return (char *)base;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L11
  mov    -0x4(%rbp),%eax
  jmp    L14
L11:
  mov    -0x8(%rbp),%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<idrnet_send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  leave
  ret
```

assistant: ```c
int idrnet_send(int sockfd, char *data) {
  int len = strlen(data);
  return send(sockfd, (void *)data, len, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<idrnet_send>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int idrnet_send(int sockfd, char *data) {
  int len = strlen(data);
  return send(sockfd, (void *)data, len, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<idrnet_send>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%edx
  xor    %ecx,%ecx
  pop    %r12
  jmp    1070 <send@plt>
```

assistant: ```c
int idrnet_send(int sockfd, char *data) {
  int len = strlen(data);
  return send(sockfd, (void *)data, len, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<idrnet_send>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%edx
  xor    %ecx,%ecx
  pop    %r12
  jmp    1070 <send@plt>
```

assistant: ```c
int idrnet_send(int sockfd, char *data) {
  int len = strlen(data);
  return send(sockfd, (void *)data, len, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sprint_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  lea    D3(%rip),%rdx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: %d

assistant: ```c
void sprint_num(char *s, int i) {
  snprintf(s, 3, "%d", i);
  s[3] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<sprint_num>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ecx
  lea    D7(%rip),%rdx
  mov    $0x3,%esi
  call   <snprintf@plt>
  movb   $0x0,0x3(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: %d

assistant: ```c
void sprint_num(char *s, int i) {
  snprintf(s, 3, "%d", i);
  s[3] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sprint_num>:
  endbr64
  push   %rbx
  mov    %esi,%ecx
  mov    %rdi,%rbx
  lea    D7(%rip),%rdx
  mov    $0x3,%esi
  call   <snprintf@plt>
  movb   $0x0,0x3(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: %d

assistant: ```c
void sprint_num(char *s, int i) {
  snprintf(s, 3, "%d", i);
  s[3] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sprint_num>:
  endbr64
  push   %rbx
  mov    %esi,%ecx
  mov    %rdi,%rbx
  lea    D1(%rip),%rdx
  mov    $0x3,%esi
  call   <snprintf@plt>
  movb   $0x0,0x3(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: %d

assistant: ```c
void sprint_num(char *s, int i) {
  snprintf(s, 3, "%d", i);
  s[3] = '\0';
}
```