ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<seq_utils_is_step_active>:
  endbr64
  sub    %esi,%edi
  sub    $0x1,%ecx
  xor    %eax,%eax
  and    %ecx,%edi
  cmp    %edx,%edi
  setl   %al
  ret
```

assistant: ```c
int seq_utils_is_step_active(int step, int motion_start, int motion_len, int num_steps) {
  if (((step - motion_start) & (num_steps - 1)) < motion_len) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<size_nextpow2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  shlq   $0x3f,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <size_ispow2@plt>
  test   %rax,%rax
  je     L23
  mov    -0x18(%rbp),%rax
  jmp    L11
L13:
  shrq   -0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L13
  shlq   -0x8(%rbp)
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
size_t size_nextpow2(const size_t x) {
  size_t w;
  w = 1;
  w = w << (sizeof(w) * 8 - 1);
  if (size_ispow2(x) != 0) {
    return x;
  }
  while ((w & x) == 0) {
    w = w >> 1;
  }
  w = w << 1;
  return w;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<size_nextpow2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <size_ispow2@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  test   %rdx,%rdx
  jne    L6
  movabs $0x8000000000000000,%rax
  test   %rbx,%rbx
  js     L19
L14:
  shr    %rax
  test   %rax,%rbx
  je     L14
L19:
  add    %rax,%rax
L6:
  pop    %rbx
  ret
```

assistant: ```c
size_t size_nextpow2(const size_t x) {
  size_t w;
  w = 1;
  w = w << (sizeof(w) * 8 - 1);
  if (size_ispow2(x) != 0) {
    return x;
  }
  while ((w & x) == 0) {
    w = w >> 1;
  }
  w = w << 1;
  return w;
}
```
user: Translate the below assembly code into C programming language:

```asm
<size_nextpow2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <size_ispow2@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L18
  test   %rbx,%rbx
  js     L2
  movabs $0x8000000000000000,%rdx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rdx,%rax
  shr    %rdx
  test   %rdx,%rbx
  je     L5
  and    $0xfffffffffffffffe,%rax
L18:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
size_t size_nextpow2(const size_t x) {
  size_t w;
  w = 1;
  w = w << (sizeof(w) * 8 - 1);
  if (size_ispow2(x) != 0) {
    return x;
  }
  while ((w & x) == 0) {
    w = w >> 1;
  }
  w = w << 1;
  return w;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<size_nextpow2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <size_ispow2@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L10
  test   %rbx,%rbx
  js     L14
  movabs $0x8000000000000000,%rdx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rdx,%rax
  shr    %rdx
  test   %rdx,%rbx
  je     L11
  and    $0xfffffffffffffffe,%rax
L10:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
size_t size_nextpow2(const size_t x) {
  size_t w;
  w = 1;
  w = w << (sizeof(w) * 8 - 1);
  if (size_ispow2(x) != 0) {
    return x;
  }
  while ((w & x) == 0) {
    w = w >> 1;
  }
  w = w << 1;
  return w;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<EasyLifeElfUp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L22:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0xf0000000,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  xor    %eax,-0x8(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  not    %eax
  and    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int EasyLifeElfUp(char *text) {
  unsigned int h = 0, g;
  while (*text) {
    h = (h << 4) + *text;
    if ((g = h & 0xF0000000))
      h ^= g >> 24;
    h &= ~g;
    text++;
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<EasyLifeElfUp>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L1
  mov    $0x0,%eax
L14:
  shl    $0x4,%eax
  movsbl %dl,%edx
  add    %eax,%edx
  mov    %edx,%eax
  and    $0xf0000000,%eax
  mov    %eax,%ecx
  shr    $0x18,%ecx
  xor    %edx,%ecx
  test   %eax,%eax
  cmovne %ecx,%edx
  not    %eax
  and    %edx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  ret
L1:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int EasyLifeElfUp(char *text) {
  unsigned int h = 0, g;
  while (*text) {
    h = (h << 4) + *text;
    if ((g = h & 0xF0000000))
      h ^= g >> 24;
    h &= ~g;
    text++;
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<EasyLifeElfUp>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L8
  nopl   (%rax)
L2:
  shl    $0x4,%eax
  add    %eax,%edx
  mov    %edx,%eax
  and    $0xf0000000,%eax
  mov    %eax,%ecx
  shr    $0x18,%ecx
  xor    %edx,%ecx
  test   %eax,%eax
  not    %eax
  cmovne %ecx,%edx
  add    $0x1,%rdi
  and    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L2
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
unsigned int EasyLifeElfUp(char *text) {
  unsigned int h = 0, g;
  while (*text) {
    h = (h << 4) + *text;
    if ((g = h & 0xF0000000))
      h ^= g >> 24;
    h &= ~g;
    text++;
  }
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<EasyLifeElfUp>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L13
  nopl   (%rax)
L17:
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L29
  mov    %edx,%ecx
  add    $0x1,%rdi
  not    %edx
  shr    $0x18,%ecx
  xor    %ecx,%eax
  and    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L17
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  movsbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L17
  ret
  nopl   (%rax)
L13:
  ret
```

assistant: ```c
unsigned int EasyLifeElfUp(char *text) {
  unsigned int h = 0, g;
  while (*text) {
    h = (h << 4) + *text;
    if ((g = h & 0xF0000000))
      h ^= g >> 24;
    h &= ~g;
    text++;
  }
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<atomic_inc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_arm_ldrex@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <__builtin_arm_strex@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int atomic_inc(int *addr) {
  int Failure, OldVal;
  do {
    OldVal = __builtin_arm_ldrex(addr);
    Failure = __builtin_arm_strex(OldVal + 1, addr);
  } while (Failure);
  return OldVal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atomic_inc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L1:
  mov    %rbp,%rdi
  call   <__builtin_arm_ldrex@plt>
  mov    %eax,%ebx
  lea    0x1(%rax),%edi
  mov    %rbp,%rsi
  call   <__builtin_arm_strex@plt>
  test   %eax,%eax
  jne    L1
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int atomic_inc(int *addr) {
  int Failure, OldVal;
  do {
    OldVal = __builtin_arm_ldrex(addr);
    Failure = __builtin_arm_strex(OldVal + 1, addr);
  } while (Failure);
  return OldVal;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atomic_inc>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L2:
  mov    %rbx,%rdi
  call   <__builtin_arm_ldrex@plt>
  mov    %rbx,%rsi
  lea    0x1(%rax),%edi
  mov    %eax,%r12d
  call   <__builtin_arm_strex@plt>
  test   %eax,%eax
  jne    L2
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int atomic_inc(int *addr) {
  int Failure, OldVal;
  do {
    OldVal = __builtin_arm_ldrex(addr);
    Failure = __builtin_arm_strex(OldVal + 1, addr);
  } while (Failure);
  return OldVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atomic_inc>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L8:
  mov    %rbx,%rdi
  call   <__builtin_arm_ldrex@plt>
  mov    %rbx,%rsi
  lea    0x1(%rax),%edi
  mov    %eax,%r12d
  call   <__builtin_arm_strex@plt>
  test   %eax,%eax
  jne    L8
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int atomic_inc(int *addr) {
  int Failure, OldVal;
  do {
    OldVal = __builtin_arm_ldrex(addr);
    Failure = __builtin_arm_strex(OldVal + 1, addr);
  } while (Failure);
  return OldVal;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x54(%rbp)
  jmp    L57
L128:
  movl   $0x0,-0x50(%rbp)
  jmp    L64
L100:
  lea    -0x30(%rbp),%rcx
  mov    -0x50(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x50(%rbp)
L64:
  cmpl   $0x2,-0x50(%rbp)
  jle    L100
  addl   $0x1,-0x54(%rbp)
L57:
  cmpl   $0x2,-0x54(%rbp)
  jle    L128
  movl   $0x0,-0x54(%rbp)
  jmp    L121
L60:
  lea    -0x48(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x54(%rbp)
L121:
  cmpl   $0x2,-0x54(%rbp)
  jle    L60
  movl   $0x0,-0x54(%rbp)
  jmp    L53
L96:
  mov    -0x54(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x3c(%rbp,%rax,4)
  movl   $0x0,-0x4c(%rbp)
  jmp    L27
L88:
  mov    -0x54(%rbp),%eax
  cltq
  movss  -0x3c(%rbp,%rax,4),%xmm1
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movss  -0x30(%rbp,%rax,4),%xmm2
  mov    -0x4c(%rbp),%eax
  cltq
  movss  -0x48(%rbp,%rax,4),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  mov    -0x54(%rbp),%eax
  cltq
  movss  %xmm0,-0x3c(%rbp,%rax,4)
  addl   $0x1,-0x4c(%rbp)
L27:
  cmpl   $0x2,-0x4c(%rbp)
  jle    L88
  addl   $0x1,-0x54(%rbp)
L53:
  cmpl   $0x2,-0x54(%rbp)
  jle    L96
  movl   $0x0,-0x54(%rbp)
  jmp    L76
L127:
  mov    -0x54(%rbp),%eax
  cltq
  mov    -0x3c(%rbp,%rax,4),%eax
  movd   %eax,%xmm0
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x54(%rbp)
L76:
  cmpl   $0x2,-0x54(%rbp)
  jle    L127
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D21
type_guessed: string

tool: D5: %f

tool: D21: %.2f


assistant: ```c
int main() {
  int i, j, k;
  float a[3][3], x[3], ax[3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%f", &a[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    scanf("%f", &x[i]);
  }
  for (i = 0; i < 3; i++) {
    ax[i] = 0.0;
    for (k = 0; k < 3; k++) {
      ax[i] += (a[i][k] * x[k]);
    }
  }
  for (i = 0; i < 3; i++) {
    printf("%.2f\n", ax[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  lea    0x2c(%rsp),%r12
  mov    $0x0,%r14d
  lea    D4(%rip),%r13
  jmp    L31
L1:
  add    $0x3,%r14
  add    $0xc,%r12
  cmp    $0x9,%r14
  je     L58
L31:
  lea    -0xc(%r12),%rbx
L11:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L11
  jmp    L1
L58:
  lea    0x8(%rsp),%rsi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rax
  lea    0x24(%rbp),%rdx
  movss  0x8(%rsp),%xmm5
  movss  0xc(%rsp),%xmm4
  movss  0x10(%rsp),%xmm3
  pxor   %xmm2,%xmm2
L51:
  movaps %xmm5,%xmm0
  mulss  0x0(%rbp),%xmm0
  addss  %xmm2,%xmm0
  movaps %xmm4,%xmm1
  mulss  0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm3,%xmm1
  mulss  0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  add    $0xc,%rbp
  cmp    %rbp,%rdx
  jne    L51
  movss  0x14(%rsp),%xmm0
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movss  0x18(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  movss  0x1c(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D2
type: string

tool: D4: %f

tool: D2: %.2f


assistant: ```c
int main() {
  int i, j, k;
  float a[3][3], x[3], ax[3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%f", &a[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    scanf("%f", &x[i]);
  }
  for (i = 0; i < 3; i++) {
    ax[i] = 0.0;
    for (k = 0; k < 3; k++) {
      ax[i] += (a[i][k] * x[k]);
    }
  }
  for (i = 0; i < 3; i++) {
    printf("%.2f\n", ax[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  lea    0x44(%rsp),%r13
  mov    %rbx,%rbp
L26:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x4(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x8(%rbp),%rsi
  mov    %r12,%rdi
  add    $0xc,%rbp
  call   <scanf@plt>
  cmp    %rbp,%r13
  jne    L26
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm5
  lea    0x14(%rsp),%rax
  movq   $0x0,0x14(%rsp)
  movss  0xc(%rsp),%xmm4
  movl   $0x0,0x1c(%rsp)
  pxor   %xmm2,%xmm2
  movss  0x10(%rsp),%xmm3
L15:
  movss  (%rbx),%xmm0
  movss  0x4(%rbx),%xmm1
  add    $0xc,%rbx
  add    $0x4,%rax
  mulss  %xmm5,%xmm0
  mulss  %xmm4,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  -0x4(%rbx),%xmm1
  mulss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rax)
  cmp    %rbx,%r13
  jne    L15
  lea    D0(%rip),%rbp
  movss  0x14(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movss  0x18(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movss  0x1c(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: D14: %f

tool: D0: %.2f


assistant: ```c
int main() {
  int i, j, k;
  float a[3][3], x[3], ax[3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%f", &a[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    scanf("%f", &x[i]);
  }
  for (i = 0; i < 3; i++) {
    ax[i] = 0.0;
    for (k = 0; k < 3; k++) {
      ax[i] += (a[i][k] * x[k]);
    }
  }
  for (i = 0; i < 3; i++) {
    printf("%.2f\n", ax[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  lea    0x44(%rsp),%r12
L1:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x4(%rbx),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  add    $0xc,%rbx
  call   <scanf@plt>
  cmp    %rbx,%r12
  jne    L1
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  lea    D17(%rip),%rbp
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  pxor   %xmm6,%xmm6
  movss  0x2c(%rsp),%xmm0
  movss  0x18(%rsp),%xmm5
  movss  0x30(%rsp),%xmm2
  mov    %rbp,%rdi
  mulss  %xmm1,%xmm0
  movss  0x1c(%rsp),%xmm4
  mulss  %xmm5,%xmm2
  addss  %xmm6,%xmm0
  addss  %xmm2,%xmm0
  movss  0x34(%rsp),%xmm2
  mulss  %xmm4,%xmm2
  movaps %xmm0,%xmm3
  movss  0x38(%rsp),%xmm0
  mulss  %xmm1,%xmm0
  mulss  0x20(%rsp),%xmm1
  addss  %xmm2,%xmm3
  movss  0x3c(%rsp),%xmm2
  mulss  %xmm5,%xmm2
  addss  %xmm6,%xmm0
  mulss  0x24(%rsp),%xmm5
  movss  %xmm3,0xc(%rsp)
  addss  %xmm2,%xmm0
  movss  0x40(%rsp),%xmm2
  mulss  %xmm4,%xmm2
  mulss  0x28(%rsp),%xmm4
  addss  %xmm0,%xmm2
  movaps %xmm1,%xmm0
  addss  %xmm6,%xmm0
  movss  %xmm2,0x8(%rsp)
  addss  %xmm5,%xmm0
  addss  %xmm4,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm3
  mov    %rbp,%rdi
  movaps %xmm3,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm2
  mov    %rbp,%rdi
  movaps %xmm2,%xmm0
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string

tool: D5: %f

tool: D17: %.2f


assistant: ```c
int main() {
  int i, j, k;
  float a[3][3], x[3], ax[3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%f", &a[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    scanf("%f", &x[i]);
  }
  for (i = 0; i < 3; i++) {
    ax[i] = 0.0;
    for (k = 0; k < 3; k++) {
      ax[i] += (a[i][k] * x[k]);
    }
  }
  for (i = 0; i < 3; i++) {
    printf("%.2f\n", ax[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<forzarColumna>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <hayConflictoConCandidatoEnColumna@plt>
  test   %eax,%eax
  jne    L20
  mov    $0x0,%eax
  jmp    L4
L20:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    $0x9,%esi
  mov    0x10(%rbp),%rdi
  call   <addInt@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getFilaConflictoEnColumna@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L6
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L6:
  mov    $0x1,%eax
L4:
  leave
  ret
```

assistant: ```c
int forzarColumna(int sudoku[9][9], int candidato, int iPosicionAtratar, int jPosicionAtratar, int *j, int *jAnterior, int *blackListForzarColumna) {
  if (!hayConflictoConCandidatoEnColumna(sudoku, jPosicionAtratar, candidato)) {
    return 0;
  }
  addInt(blackListForzarColumna, 9, candidato);
  int iPosicionConflicto = getFilaConflictoEnColumna(sudoku, jPosicionAtratar, candidato);
  int jPosicionConflicto = jPosicionAtratar;
  sudoku[iPosicionConflicto][jPosicionConflicto] = 0;
  sudoku[iPosicionAtratar][jPosicionAtratar] = candidato;
  if (*jAnterior == *j) {
    *j -= 1;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<forzarColumna>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %ecx,%ebx
  mov    %r8,%r14
  mov    %r9,%r15
  mov    %esi,%edx
  mov    %ecx,%esi
  call   <hayConflictoConCandidatoEnColumna@plt>
  test   %eax,%eax
  jne    L9
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    %ebp,%edx
  mov    $0x9,%esi
  mov    0x40(%rsp),%rdi
  call   <addInt@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <getFilaConflictoEnColumna@plt>
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%r12,%rax,4),%rax
  movslq %ebx,%rbx
  movl   $0x0,(%rax,%rbx,4)
  movslq %r13d,%r13
  lea    0x0(%r13,%r13,8),%rax
  lea    (%r12,%rax,4),%rax
  mov    %ebp,(%rax,%rbx,4)
  mov    (%r14),%edx
  mov    $0x1,%eax
  cmp    %edx,(%r15)
  jne    L11
  sub    $0x1,%edx
  mov    %edx,(%r14)
  jmp    L11
```

assistant: ```c
int forzarColumna(int sudoku[9][9], int candidato, int iPosicionAtratar, int jPosicionAtratar, int *j, int *jAnterior, int *blackListForzarColumna) {
  if (!hayConflictoConCandidatoEnColumna(sudoku, jPosicionAtratar, candidato)) {
    return 0;
  }
  addInt(blackListForzarColumna, 9, candidato);
  int iPosicionConflicto = getFilaConflictoEnColumna(sudoku, jPosicionAtratar, candidato);
  int jPosicionConflicto = jPosicionAtratar;
  sudoku[iPosicionConflicto][jPosicionConflicto] = 0;
  sudoku[iPosicionAtratar][jPosicionAtratar] = candidato;
  if (*jAnterior == *j) {
    *j -= 1;
  }
  return 1;
}
```