ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<help>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%esi
  lea    D47(%rip),%rdi
  call   <message@plt>
  mov    $0x0,%esi
  lea    D9(%rip),%rdi
  call   <message@plt>
  mov    $0x0,%esi
  lea    D48(%rip),%rdi
  call   <message@plt>
  mov    $0x0,%esi
  lea    D11(%rip),%rdi
  call   <message@plt>
  mov    $0x0,%esi
  lea    D6(%rip),%rdi
  call   <message@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <halt@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D47
datatype: string
name: extract_symbolic_data
arguments: data_label: D9
datatype: string
name: extract_symbolic_data
arguments: data_label: D48
datatype: string
name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D47: To specify a topology the string should be set 

tool: D9: like as following: 

tool: D48: (-4,1)(-3,2)(-2,2)(-1,1)(1,3)(1,4)(2,3)(2,4)(3,4)

tool: D11: Negative numbers mean end of external lines. 

tool: D6: All negative numbers should be ordered. 

assistant: ```c
void help(char *a, char *b) {
  message("To specify a topology the string should be set ", NULL);
  message("like as following: ", NULL);
  message("(-4,1)(-3,2)(-2,2)(-1,1)(1,3)(1,4)(2,3)(2,4)(3,4)", NULL);
  message("Negative numbers mean end of external lines. ", NULL);
  message("All negative numbers should be ordered. ", NULL);
  halt(a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<help>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  lea    D19(%rip),%rdi
  sub    $0x8,%rsp
  call   <message@plt>
  xor    %esi,%esi
  lea    D23(%rip),%rdi
  call   <message@plt>
  xor    %esi,%esi
  lea    D33(%rip),%rdi
  call   <message@plt>
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  call   <message@plt>
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  call   <message@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <halt@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type: string
name: retrieve_data
arguments: data_label: D23
type: string
name: retrieve_data
arguments: data_label: D33
type: string
name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D11
type: string

tool: D19: To specify a topology the string should be set 

tool: D23: like as following: 

tool: D33: (-4,1)(-3,2)(-2,2)(-1,1)(1,3)(1,4)(2,3)(2,4)(3,4)

tool: D5: Negative numbers mean end of external lines. 

tool: D11: All negative numbers should be ordered. 

assistant: ```c
void help(char *a, char *b) {
  message("To specify a topology the string should be set ", NULL);
  message("like as following: ", NULL);
  message("(-4,1)(-3,2)(-2,2)(-1,1)(1,3)(1,4)(2,3)(2,4)(3,4)", NULL);
  message("Negative numbers mean end of external lines. ", NULL);
  message("All negative numbers should be ordered. ", NULL);
  halt(a, b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<help>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  sub    $0x8,%rsp
  call   <message@plt>
  xor    %esi,%esi
  lea    D44(%rip),%rdi
  call   <message@plt>
  xor    %esi,%esi
  lea    D16(%rip),%rdi
  call   <message@plt>
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  call   <message@plt>
  xor    %esi,%esi
  lea    D30(%rip),%rdi
  call   <message@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <halt@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D44
type: string
name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D2
type: string
name: unpack_data
arguments: tag: D30
type: string

tool: D3: To specify a topology the string should be set 

tool: D44: like as following: 

tool: D16: (-4,1)(-3,2)(-2,2)(-1,1)(1,3)(1,4)(2,3)(2,4)(3,4)

tool: D2: Negative numbers mean end of external lines. 

tool: D30: All negative numbers should be ordered. 

assistant: ```c
void help(char *a, char *b) {
  message("To specify a topology the string should be set ", NULL);
  message("like as following: ", NULL);
  message("(-4,1)(-3,2)(-2,2)(-1,1)(1,3)(1,4)(2,3)(2,4)(3,4)", NULL);
  message("Negative numbers mean end of external lines. ", NULL);
  message("All negative numbers should be ordered. ", NULL);
  halt(a, b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<errata_36>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x10000130,%eax
  mov    (%rax),%eax
  cmp    $0xa,%eax
  jne    L8
  mov    $0x10000134,%eax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L8
  mov    $0x1,%eax
  jmp    L27
L8:
  mov    $0x1,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
bool errata_36(void) {
  if ((*(uint32_t *)0x10000130ul == 0xAul) && (*(uint32_t *)0x10000134ul == 0x0ul)) {
    return true;
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<errata_36>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool errata_36(void) {
  if ((*(uint32_t *)0x10000130ul == 0xAul) && (*(uint32_t *)0x10000134ul == 0x0ul)) {
    return true;
  }
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<errata_36>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool errata_36(void) {
  if ((*(uint32_t *)0x10000130ul == 0xAul) && (*(uint32_t *)0x10000134ul == 0x0ul)) {
    return true;
  }
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<errata_36>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool errata_36(void) {
  if ((*(uint32_t *)0x10000130ul == 0xAul) && (*(uint32_t *)0x10000134ul == 0x0ul)) {
    return true;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gui_nick_find_color>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gui_nick_find_color_name@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <gui_color_get_custom@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L29
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L29:
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L8
L18:
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
char *gui_nick_find_color(const char *nickname, const char *colors) {
  char *color;
  const char *ptr_result;
  color = gui_nick_find_color_name(nickname, colors);
  ptr_result = gui_color_get_custom(color);
  if (color)
    free(color);
  return (ptr_result) ? strdup(ptr_result) : NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gui_nick_find_color>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <gui_nick_find_color_name@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <gui_color_get_custom@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L3
  mov    %rbp,%rdi
  call   <free@plt>
L3:
  test   %rbx,%rbx
  je     L16
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
L16:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *gui_nick_find_color(const char *nickname, const char *colors) {
  char *color;
  const char *ptr_result;
  color = gui_nick_find_color_name(nickname, colors);
  ptr_result = gui_color_get_custom(color);
  if (color)
    free(color);
  return (ptr_result) ? strdup(ptr_result) : NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gui_nick_find_color>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <gui_nick_find_color_name@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <gui_color_get_custom@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L7
  mov    %rbp,%rdi
  call   <free@plt>
L7:
  test   %r12,%r12
  je     L4
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <strdup@plt>
  nop
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *gui_nick_find_color(const char *nickname, const char *colors) {
  char *color;
  const char *ptr_result;
  color = gui_nick_find_color_name(nickname, colors);
  ptr_result = gui_color_get_custom(color);
  if (color)
    free(color);
  return (ptr_result) ? strdup(ptr_result) : NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gui_nick_find_color>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <gui_nick_find_color_name@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <gui_color_get_custom@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L16
  mov    %rbp,%rdi
  call   <free@plt>
L16:
  test   %r12,%r12
  je     L9
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <strdup@plt>
  nop
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *gui_nick_find_color(const char *nickname, const char *colors) {
  char *color;
  const char *ptr_result;
  color = gui_nick_find_color_name(nickname, colors);
  ptr_result = gui_color_get_custom(color);
  if (color)
    free(color);
  return (ptr_result) ? strdup(ptr_result) : NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ROL64_13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  rol    $0xd,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ROL64_13(uint64_t x) {
  __asm__("rolq $13, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ROL64_13>:
  endbr64
  mov    %rdi,%rax
  rol    $0xd,%rax
  ret
```

assistant: ```c
uint64_t ROL64_13(uint64_t x) {
  __asm__("rolq $13, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<ROL64_13>:
  endbr64
  mov    %rdi,%rax
  rol    $0xd,%rax
  ret
```

assistant: ```c
uint64_t ROL64_13(uint64_t x) {
  __asm__("rolq $13, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ROL64_13>:
  endbr64
  mov    %rdi,%rax
  rol    $0xd,%rax
  ret
```

assistant: ```c
uint64_t ROL64_13(uint64_t x) {
  __asm__("rolq $13, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <op_add@plt>
  cmp    $0x7,%eax
  je     L4
  mov    $0xffffffff,%eax
  jmp    L18
L4:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int test_add() {
  if (op_add(3, 4) != (3 + 4))
    return (-1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_add>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <op_add@plt>
  cmp    $0x7,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int test_add() {
  if (op_add(3, 4) != (3 + 4))
    return (-1);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_add>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <op_add@plt>
  cmp    $0x7,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int test_add() {
  if (op_add(3, 4) != (3 + 4))
    return (-1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_add>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <op_add@plt>
  cmp    $0x7,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int test_add() {
  if (op_add(3, 4) != (3 + 4))
    return (-1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getStringSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
L5:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getStringSize(char *string) {
  int size = 0;
  while (string[++size] != '\x0')
    ;
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getStringSize>:
  endbr64
  mov    $0x1,%eax
L6:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L6
  mov    %edx,%eax
  ret
```

assistant: ```c
int getStringSize(char *string) {
  int size = 0;
  while (string[++size] != '\x0')
    ;
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getStringSize>:
  endbr64
  mov    $0x1,%eax
  nopl   0x0(%rax)
L2:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L2
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getStringSize(char *string) {
  int size = 0;
  while (string[++size] != '\x0')
    ;
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getStringSize>:
  endbr64
  mov    $0x1,%eax
  nopl   0x0(%rax)
L7:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L7
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getStringSize(char *string) {
  int size = 0;
  while (string[++size] != '\x0')
    ;
  return size;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GUI_ConSpaceDots>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%eax
  mov    %edi,%edx
  mov    %dx,-0x4(%rbp)
  mov    %esi,%edx
  mov    %dx,-0x8(%rbp)
  mov    %ax,-0x14(%rbp)
  mov    $0xee,%edi
  call   <SendChar@plt>
  mov    $0x59,%edi
  call   <SendChar@plt>
  movzwl -0x4(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x8(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x8(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <SendNU16@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  nop
  leave
  ret
```

assistant: ```c
void GUI_ConSpaceDots(unsigned short int x, unsigned short int x_space, unsigned short int *dot_y, unsigned short int dot_cnt) {
  SendChar((0XEE) & 0xFF);
  SendChar((0x59) & 0xFF);
  SendChar(((x) >> 8) & 0xFF);
  SendChar((x)&0xFF);
  SendChar(((x_space) >> 8) & 0xFF);
  SendChar((x_space)&0xFF);
  SendNU16((unsigned short int *)dot_y, dot_cnt);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GUI_ConSpaceDots>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    $0xee,%edi
  call   <SendChar@plt>
  mov    $0x59,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  movzwl %r12w,%esi
  mov    %r13,%rdi
  call   <SendNU16@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void GUI_ConSpaceDots(unsigned short int x, unsigned short int x_space, unsigned short int *dot_y, unsigned short int dot_cnt) {
  SendChar((0XEE) & 0xFF);
  SendChar((0x59) & 0xFF);
  SendChar(((x) >> 8) & 0xFF);
  SendChar((x)&0xFF);
  SendChar(((x_space) >> 8) & 0xFF);
  SendChar((x_space)&0xFF);
  SendNU16((unsigned short int *)dot_y, dot_cnt);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GUI_ConSpaceDots>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    $0xee,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <SendChar@plt>
  mov    $0x59,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  movzwl %r12w,%esi
  mov    %r13,%rdi
  call   <SendNU16@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  add    $0x8,%rsp
  mov    $0xff,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <SendChar@plt>
```

assistant: ```c
void GUI_ConSpaceDots(unsigned short int x, unsigned short int x_space, unsigned short int *dot_y, unsigned short int dot_cnt) {
  SendChar((0XEE) & 0xFF);
  SendChar((0x59) & 0xFF);
  SendChar(((x) >> 8) & 0xFF);
  SendChar((x)&0xFF);
  SendChar(((x_space) >> 8) & 0xFF);
  SendChar((x_space)&0xFF);
  SendNU16((unsigned short int *)dot_y, dot_cnt);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GUI_ConSpaceDots>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    $0xee,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <SendChar@plt>
  mov    $0x59,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  movzwl %r12w,%esi
  mov    %r13,%rdi
  call   <SendNU16@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  add    $0x8,%rsp
  mov    $0xff,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <SendChar@plt>
```

assistant: ```c
void GUI_ConSpaceDots(unsigned short int x, unsigned short int x_space, unsigned short int *dot_y, unsigned short int dot_cnt) {
  SendChar((0XEE) & 0xFF);
  SendChar((0x59) & 0xFF);
  SendChar(((x) >> 8) & 0xFF);
  SendChar((x)&0xFF);
  SendChar(((x_space) >> 8) & 0xFF);
  SendChar((x_space)&0xFF);
  SendNU16((unsigned short int *)dot_y, dot_cnt);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x398,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1388(%rsp)
  xor    %eax,%eax
  call   <print@plt>
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getid@plt>
  mov    0x1388(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x1398,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: D9: Press number

assistant: ```c
void main() {
  float numt;
  int z = 1;
  int i, k = 0, p = -1, er = 0, t;
  int num = 0, fin;
  char c[5000];
  for (i = 0; i < 5000; i++)
    c[i] == '0';
  print("Press number");
  getid(c);
  for (i = 0; i < 5000; i++) {
    if ((c[i] != '0') & (c[i] != '1') & (c[i] != '2') & (c[i] != '3') & (c[i] != '4') & (c[i] != '5') & (c[i] != '6') & (c[i] != '7') & (c[i] != '8') & (c[i] != '9') & (c[i] != '.')) {
      er = 1;
    }
    if (k > 1) {
      er = 1;
    }
    if (c[i] == '.') {
      k++;
      p = i;
    }
  }
  t = 0;
  for (i = 4999; i > -1; i--) {
    if ((t == 0) & (c[i] != '0')) {
      t = 1;
      fin = i;
    }
  }
  if (p = 0) {
    er = 1;
  }
  if (er = 0) {
    if (p = -1) {
      num = 0;
      for (i = 0; i < 5000; i++) {
        if (c[i] == '0') {
          num = 10 * num + 0;
        }
        if (c[i] == '1') {
          num = 10 * num + 1;
        }
        if (c[i] == '2') {
          num = 10 * num + 2;
        }
        if (c[i] == '3') {
          num = 10 * num + 3;
        }
        if (c[i] == '4') {
          num = 10 * num + 4;
        }
        if (c[i] == '5') {
          num = 10 * num + 5;
        }
        if (c[i] == '6') {
          num = 10 * num + 6;
        }
        if (c[i] == '7') {
          num = 10 * num + 7;
        }
        if (c[i] == '8') {
          num = 10 * num + 8;
        }
        if (c[i] == '9') {
          num = 10 * num + 9;
        }
      }
      print(num);
    } else {
      for (i = 0; i < 5000; i++) {
        if (i != p) {
          if (c[i] == '0') {
            numt = 10 * numt + 0;
          }
          if (c[i] == '1') {
            numt = 10 * numt + 1;
          }
          if (c[i] == '2') {
            numt = 10 * numt + 2;
          }
          if (c[i] == '3') {
            numt = 10 * numt + 3;
          }
          if (c[i] == '4') {
            numt = 10 * numt + 4;
          }
          if (c[i] == '5') {
            numt = 10 * numt + 5;
          }
          if (c[i] == '6') {
            numt = 10 * numt + 6;
          }
          if (c[i] == '7') {
            numt = 10 * numt + 7;
          }
          if (c[i] == '8') {
            numt = 10 * numt + 8;
          }
          if (c[i] == '9') {
            numt = 10 * numt + 9;
          }
        }
      }
      for (i = 1; i < (fin - p + 1); i++) {
        z = z * 10;
      }
      numt = numt / (z);
      print(numt);
    }
  }
  if (er == 1)
    print("ERROR");
}
```