ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<digit_fact_sum>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L7
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L3:
  mov    %edi,%eax
  mov    %edi,%edx
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    (%rsi,%rdx,4),%r8d
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  jg     L3
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int digit_fact_sum(int n, const int digits[]) {
  int sum = 0;
  for (; n > 0; n /= 10) {
    sum += digits[n % 10];
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<digit_fact_sum>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L9
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L7:
  mov    %edi,%eax
  mov    %edi,%edx
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    (%rsi,%rdx,4),%r8d
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  jg     L7
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int digit_fact_sum(int n, const int digits[]) {
  int sum = 0;
  for (; n > 0; n /= 10) {
    sum += digits[n % 10];
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L5
  mov    $0x1,%eax
  jmp    L19
L5:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fact>
  imul   -0x4(%rbp),%eax
L19:
  leave
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 1)
    return 1;
  else
    return (n * fact(n - 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fact>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jne    L14
L3:
  mov    %ebx,%eax
  pop    %rbx
  ret
L14:
  lea    -0x1(%rdi),%edi
  call   <fact>
  imul   %eax,%ebx
  jmp    L3
```

assistant: ```c
int fact(int n) {
  if (n == 1)
    return 1;
  else
    return (n * fact(n - 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L10
  xchg   %ax,%ax
L15:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L15
L10:
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 1)
    return 1;
  else
    return (n * fact(n - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L16
  xchg   %ax,%ax
L1:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L1
L16:
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 1)
    return 1;
  else
    return (n * fact(n - 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_one_element>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <find@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x2,%eax
  jne    L26
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L26
  mov    $0x1,%eax
  jmp    L10
L26:
  mov    $0x0,%eax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int test_one_element() {
  int one = 0;
  int two = 0;
  int array[] = {2};
  find(array, 1, &one, &two);
  return 2 == one && 0 == two;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_one_element>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%rdi
  mov    $0x1,%esi
  call   <find@plt>
  mov    $0x0,%eax
  cmpl   $0x2,0xc(%rsp)
  je     L25
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L25:
  cmpl   $0x0,0x10(%rsp)
  sete   %al
  movzbl %al,%eax
  jmp    L1
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_one_element() {
  int one = 0;
  int two = 0;
  int array[] = {2};
  find(array, 1, &one, &two);
  return 2 == one && 0 == two;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_one_element>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  movl   $0x0,0xc(%rsp)
  lea    0x14(%rsp),%rdi
  movl   $0x0,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  call   <find@plt>
  xor    %eax,%eax
  cmpl   $0x2,0xc(%rsp)
  jne    L7
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
L7:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_one_element() {
  int one = 0;
  int two = 0;
  int array[] = {2};
  find(array, 1, &one, &two);
  return 2 == one && 0 == two;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_one_element>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  movl   $0x0,0xc(%rsp)
  lea    0x14(%rsp),%rdi
  movl   $0x0,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  call   <find@plt>
  xor    %eax,%eax
  cmpl   $0x2,0xc(%rsp)
  jne    L10
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_one_element() {
  int one = 0;
  int two = 0;
  int array[] = {2};
  find(array, 1, &one, &two);
  return 2 == one && 0 == two;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L14
  mov    $0x1,%eax
  jmp    L8
L14:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fn>
  imul   -0x4(%rbp),%eax
L8:
  leave
  ret
```

assistant: ```c
int fn(int n) {
  if (n < 2)
    return 1;
  return n * fn(n - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L0
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fn>
  imul   %ebx,%eax
  pop    %rbx
  ret
L0:
  ret
```

assistant: ```c
int fn(int n) {
  if (n < 2)
    return 1;
  return n * fn(n - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fn>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L5
  xchg   %ax,%ax
L19:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L19
L5:
  ret
```

assistant: ```c
int fn(int n) {
  if (n < 2)
    return 1;
  return n * fn(n - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L3
  xchg   %ax,%ax
L4:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L4
L3:
  ret
```

assistant: ```c
int fn(int n) {
  if (n < 2)
    return 1;
  return n * fn(n - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<testLateAssignment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x5,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <test@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void testLateAssignment() {
  int a;
  int *q;
  q = &a;
  a = 5;
  test(*q == a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testLateAssignment>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void testLateAssignment() {
  int a;
  int *q;
  q = &a;
  a = 5;
  test(*q == a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<testLateAssignment>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <test@plt>
```

assistant: ```c
void testLateAssignment() {
  int a;
  int *q;
  q = &a;
  a = 5;
  test(*q == a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<testLateAssignment>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <test@plt>
```

assistant: ```c
void testLateAssignment() {
  int a;
  int *q;
  q = &a;
  a = 5;
  test(*q == a);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<diag_ulonglong_to_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L68
  mov    $0x0,%eax
  jmp    L52
L68:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_diag_ulonglong_to_dec@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L79
  mov    -0x30(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L66
  mov    -0x20(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x30(%rbp)
L66:
  cmpl   $0x0,-0x2c(%rbp)
  je     L44
  movb   $0x30,-0xd(%rbp)
  jmp    L62
L44:
  movb   $0x20,-0xd(%rbp)
L62:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L49
L48:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
L49:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L48
L79:
  mov    -0x8(%rbp),%rax
L52:
  leave
  ret
```

assistant: ```c
char *diag_ulonglong_to_dec(char *field, size_t n, unsigned long long ull, int leading0, int size) {
  char *np;
  char c;
  int i;
  if (n == 0)
    return NULL;
  np = _diag_ulonglong_to_dec(field, n, ull);
  if (size) {
    if (size >= n)
      size = n - 1;
    if (leading0) {
      c = '0';
    } else {
      c = ' ';
    }
    i = size - strlen(np);
    while (i-- > 0) {
      *--np = c;
    }
  }
  return np;
}
```
user: Translate the below assembly code into C programming language:

```asm
<diag_ulonglong_to_dec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  test   %rsi,%rsi
  je     L24
  mov    %rsi,%r12
  mov    %ecx,%r13d
  mov    %r8d,%ebx
  call   <_diag_ulonglong_to_dec@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  je     L24
  movslq %ebx,%rdx
  lea    -0x1(%r12),%eax
  cmp    %r12,%rdx
  cmovae %eax,%ebx
  cmp    $0x1,%r13d
  sbb    %r12d,%r12d
  and    $0xfffffff0,%r12d
  add    $0x30,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    %eax,%ebx
  lea    -0x1(%rbx),%ecx
  test   %ebx,%ebx
  jle    L24
  lea    -0x1(%rbx),%edx
  not    %rdx
  add    %rbp,%rdx
  mov    %rbp,%rax
L7:
  sub    $0x1,%rax
  mov    %r12b,(%rax)
  cmp    %rdx,%rax
  jne    L7
  mov    %ecx,%ecx
  not    %rcx
  add    %rcx,%rbp
L24:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *diag_ulonglong_to_dec(char *field, size_t n, unsigned long long ull, int leading0, int size) {
  char *np;
  char c;
  int i;
  if (n == 0)
    return NULL;
  np = _diag_ulonglong_to_dec(field, n, ull);
  if (size) {
    if (size >= n)
      size = n - 1;
    if (leading0) {
      c = '0';
    } else {
      c = ' ';
    }
    i = size - strlen(np);
    while (i-- > 0) {
      *--np = c;
    }
  }
  return np;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<diag_ulonglong_to_dec>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L28
  mov    %rsi,%rbp
  mov    %ecx,%r12d
  mov    %r8d,%ebx
  call   <_diag_ulonglong_to_dec@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  je     L28
  movslq %ebx,%rdx
  lea    -0x1(%rbp),%eax
  mov    %r13,%rdi
  cmp    %rbp,%rdx
  cmovae %eax,%ebx
  cmp    $0x1,%r12d
  sbb    %ebp,%ebp
  call   <strlen@plt>
  and    $0xfffffff0,%ebp
  sub    %eax,%ebx
  add    $0x30,%ebp
  lea    -0x1(%rbx),%edx
  test   %ebx,%ebx
  jle    L28
  mov    %rdx,%rax
  movsbl %bpl,%esi
  add    $0x1,%rdx
  not    %rax
  add    %rax,%r13
  mov    %r13,%rdi
  call   <memset@plt>
L28:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *diag_ulonglong_to_dec(char *field, size_t n, unsigned long long ull, int leading0, int size) {
  char *np;
  char c;
  int i;
  if (n == 0)
    return NULL;
  np = _diag_ulonglong_to_dec(field, n, ull);
  if (size) {
    if (size >= n)
      size = n - 1;
    if (leading0) {
      c = '0';
    } else {
      c = ' ';
    }
    i = size - strlen(np);
    while (i-- > 0) {
      *--np = c;
    }
  }
  return np;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<diag_ulonglong_to_dec>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L27
  mov    %rsi,%rbp
  mov    %ecx,%r12d
  mov    %r8d,%ebx
  call   <_diag_ulonglong_to_dec@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  je     L27
  movslq %ebx,%rdx
  lea    -0x1(%rbp),%eax
  mov    %r13,%rdi
  cmp    %rbp,%rdx
  cmovae %eax,%ebx
  cmp    $0x1,%r12d
  sbb    %ebp,%ebp
  call   <strlen@plt>
  mov    %ebx,%edx
  and    $0xfffffff0,%ebp
  sub    %eax,%edx
  add    $0x30,%ebp
  test   %edx,%edx
  jle    L27
  sub    %ebx,%eax
  movslq %edx,%rdx
  movsbl %bpl,%esi
  cltq
  add    %rax,%r13
  mov    %r13,%rdi
  call   <memset@plt>
L27:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *diag_ulonglong_to_dec(char *field, size_t n, unsigned long long ull, int leading0, int size) {
  char *np;
  char c;
  int i;
  if (n == 0)
    return NULL;
  np = _diag_ulonglong_to_dec(field, n, ull);
  if (size) {
    if (size >= n)
      size = n - 1;
    if (leading0) {
      c = '0';
    } else {
      c = ' ';
    }
    i = size - strlen(np);
    while (i-- > 0) {
      *--np = c;
    }
  }
  return np;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L75:
  addq   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
  jmp    L59
L95:
  addq   $0x1,-0x20(%rbp)
L59:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L95
  jmp    L35
L72:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L3
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L3
  subq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
  jmp    L35
L3:
  mov    $0x1,%eax
  jmp    L15
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L72
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  char *a = s, *b = t;
  while (*s)
    ++s;
  while (*t)
    ++t;
  while (*s == *t)
    if (s > a && t > b)
      --s, --t;
    else
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strend>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L36
  mov    %rdi,%rax
L28:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L28
L0:
  cmpb   $0x0,(%rsi)
  je     L72
  mov    %rsi,%rdx
L25:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L25
L29:
  movzbl (%rdx),%ecx
  cmp    %cl,(%rax)
  jne    L113
  cmp    %rax,%rdi
  jae    L40
  cmp    %rdx,%rsi
  jae    L40
L14:
  sub    $0x1,%rax
  sub    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    %cl,(%rax)
  jne    L52
  cmp    %rax,%rdi
  jae    L39
  cmp    %rdx,%rsi
  jb     L14
L39:
  mov    $0x1,%eax
  ret
L36:
  mov    %rdi,%rax
  jmp    L0
L72:
  mov    %rsi,%rdx
  jmp    L29
L40:
  mov    $0x1,%eax
  ret
L52:
  mov    $0x0,%eax
  ret
L113:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  char *a = s, *b = t;
  while (*s)
    ++s;
  while (*t)
    ++t;
  while (*s == *t)
    if (s > a && t > b)
      --s, --t;
    else
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strend>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L64
  nopl   0x0(%rax)
L37:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L37
L64:
  cmpb   $0x0,(%rsi)
  je     L34
  mov    %rsi,%rdx
  nopl   0x0(%rax)
L3:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L3
  cmp    %rdx,%rsi
  jae    L34
  cmp    %rax,%rdi
  jb     L5
  jmp    L34
  nopl   (%rax)
L19:
  cmp    %rax,%rdi
  jae    L34
  cmp    %rdx,%rsi
  jae    L34
L5:
  sub    $0x1,%rax
  sub    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    %cl,(%rax)
  je     L19
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L34:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  char *a = s, *b = t;
  while (*s)
    ++s;
  while (*t)
    ++t;
  while (*s == *t)
    if (s > a && t > b)
      --s, --t;
    else
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strend>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L20
  nopl   0x0(%rax)
L81:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L81
L20:
  cmpb   $0x0,(%rsi)
  je     L63
  mov    %rsi,%rdx
  nopl   0x0(%rax)
L8:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L8
  cmp    %rdx,%rsi
  jae    L63
  cmp    %rax,%rdi
  jb     L5
  jmp    L63
  nopl   (%rax)
L34:
  cmp    %rax,%rdi
  jae    L63
  cmp    %rdx,%rsi
  jae    L63
L5:
  sub    $0x1,%rax
  sub    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    %cl,(%rax)
  je     L34
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L63:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  char *a = s, *b = t;
  while (*s)
    ++s;
  while (*t)
    ++t;
  while (*s == *t)
    if (s > a && t > b)
      --s, --t;
    else
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int a;
  a = 0;
  return (a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int a;
  a = 0;
  return (a);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a;
  a = 0;
  return (a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a;
  a = 0;
  return (a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xPos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L72
  cmpl   $0xb,-0x4(%rbp)
  je     L72
  cmpl   $0xc,-0x4(%rbp)
  jne    L73
L72:
  mov    $0x0,%eax
  jmp    L145
L73:
  cmpl   $0x1,-0x4(%rbp)
  je     L120
  cmpl   $0x9,-0x4(%rbp)
  jne    L36
L120:
  mov    $0x4,%eax
  jmp    L145
L36:
  cmpl   $0x2,-0x4(%rbp)
  je     L112
  cmpl   $0x8,-0x4(%rbp)
  jne    L58
L112:
  mov    $0x6,%eax
  jmp    L145
L58:
  cmpl   $0x3,-0x4(%rbp)
  je     L128
  cmpl   $0x7,-0x4(%rbp)
  jne    L38
L128:
  mov    $0x8,%eax
  jmp    L145
L38:
  cmpl   $0x4,-0x4(%rbp)
  je     L10
  cmpl   $0x5,-0x4(%rbp)
  je     L10
  cmpl   $0x6,-0x4(%rbp)
  jne    L105
L10:
  mov    $0xc,%eax
  jmp    L145
L105:
  mov    $0x63,%eax
L145:
  pop    %rbp
  ret
```

assistant: ```c
int xPos(int punt) {
  if (punt == 10 || punt == 11 || punt == 12)
    return 0;
  if (punt == 1 || punt == 9)
    return 4;
  if (punt == 2 || punt == 8)
    return 6;
  if (punt == 3 || punt == 7)
    return 8;
  if (punt == 4 || punt == 5 || punt == 6)
    return 12;
  return 99;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xPos>:
  endbr64
  lea    -0xa(%rdi),%edx
  mov    $0x0,%eax
  cmp    $0x2,%edx
  jbe    L13
  cmp    $0x9,%edi
  ja     L8
  mov    %edi,%edi
  lea    D4(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x4,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0xc,%eax
  ret
L8:
  mov    $0x63,%eax
L13:
  ret
```

assistant: ```c
int xPos(int punt) {
  if (punt == 10 || punt == 11 || punt == 12)
    return 0;
  if (punt == 1 || punt == 9)
    return 4;
  if (punt == 2 || punt == 8)
    return 6;
  if (punt == 3 || punt == 7)
    return 8;
  if (punt == 4 || punt == 5 || punt == 6)
    return 12;
  return 99;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xPos>:
  endbr64
  lea    -0xa(%rdi),%edx
  xor    %eax,%eax
  cmp    $0x2,%edx
  jbe    L0
  sub    $0x1,%edi
  mov    $0x63,%eax
  cmp    $0x8,%edi
  jbe    L10
L0:
  ret
  nopl   0x0(%rax)
L10:
  lea    D9(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: 

assistant: ```c
int xPos(int punt) {
  if (punt == 10 || punt == 11 || punt == 12)
    return 0;
  if (punt == 1 || punt == 9)
    return 4;
  if (punt == 2 || punt == 8)
    return 6;
  if (punt == 3 || punt == 7)
    return 8;
  if (punt == 4 || punt == 5 || punt == 6)
    return 12;
  return 99;
}
```