ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<to_next_line>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xa,%esi
  add    $0x1,%rbx
  sub    $0x8,%rsp
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    $0x1,%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t to_next_line(char *b, size_t l) {
  char *p = memchr(b, '\n', l);
  if (!p) {
    return l + 1;
  }
  return p - b + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_next_line>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xa,%esi
  add    $0x1,%rbx
  sub    $0x8,%rsp
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    $0x1,%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t to_next_line(char *b, size_t l) {
  char *p = memchr(b, '\n', l);
  if (!p) {
    return l + 1;
  }
  return p - b + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wtime_impl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double wtime_impl(void) {
  double t = 0.0;
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wtime_impl>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double wtime_impl(void) {
  double t = 0.0;
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wtime_impl>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double wtime_impl(void) {
  double t = 0.0;
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3a96,-0x4(%rbp)
  jle    L1
  mov    $0x3a98,%eax
  sub    -0x4(%rbp),%eax
  jmp    L8
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <getValueFromIndex@plt>
  and    $0x3fff,%eax
L8:
  leave
  ret
```

assistant: ```c
uint16_t getLength(uint16_t pos) {
  if (pos > 15000 - 2) {
    return 15000 - pos;
  }
  return (getValueFromIndex(pos) & 0x3fff);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getLength>:
  endbr64
  cmp    $0x3a96,%edi
  jle    L3
  mov    $0x3a98,%eax
  sub    %edi,%eax
  ret
L3:
  sub    $0x8,%rsp
  call   <getValueFromIndex@plt>
  and    $0x3fff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint16_t getLength(uint16_t pos) {
  if (pos > 15000 - 2) {
    return 15000 - pos;
  }
  return (getValueFromIndex(pos) & 0x3fff);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getLength>:
  endbr64
  cmp    $0x3a96,%edi
  jle    L3
  mov    $0x3a98,%eax
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L3:
  sub    $0x8,%rsp
  call   <getValueFromIndex@plt>
  add    $0x8,%rsp
  and    $0x3fff,%eax
  ret
```

assistant: ```c
uint16_t getLength(uint16_t pos) {
  if (pos > 15000 - 2) {
    return 15000 - pos;
  }
  return (getValueFromIndex(pos) & 0x3fff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getLength>:
  endbr64
  cmp    $0x3a96,%edi
  jle    L1
  mov    $0x3a98,%eax
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L1:
  sub    $0x8,%rsp
  call   <getValueFromIndex@plt>
  add    $0x8,%rsp
  and    $0x3fff,%eax
  ret
```

assistant: ```c
uint16_t getLength(uint16_t pos) {
  if (pos > 15000 - 2) {
    return 15000 - pos;
  }
  return (getValueFromIndex(pos) & 0x3fff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<splitbank_closestPowerOfTwo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jle    L25
  jmp    L15
L11:
  shll   -0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
L25:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int splitbank_closestPowerOfTwo(int p) {
  int base = 2;
  if (p > 2) {
    while (base < p) {
      base *= 2;
    }
  }
  return base;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<splitbank_closestPowerOfTwo>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x2,%edi
  jle    L13
L12:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L12
L13:
  ret
```

assistant: ```c
int splitbank_closestPowerOfTwo(int p) {
  int base = 2;
  if (p > 2) {
    while (base < p) {
      base *= 2;
    }
  }
  return base;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<splitbank_closestPowerOfTwo>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x2,%edi
  jle    L16
  xchg   %ax,%ax
L5:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L5
L16:
  ret
```

assistant: ```c
int splitbank_closestPowerOfTwo(int p) {
  int base = 2;
  if (p > 2) {
    while (base < p) {
      base *= 2;
    }
  }
  return base;
}
```
user: Translate the below assembly code into C programming language:

```asm
<splitbank_closestPowerOfTwo>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x2,%edi
  jle    L8
  xchg   %ax,%ax
L19:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L19
L8:
  ret
```

assistant: ```c
int splitbank_closestPowerOfTwo(int p) {
  int base = 2;
  if (p > 2) {
    while (base < p) {
      base *= 2;
    }
  }
  return base;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_cmd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xc000a044,%eax
  orl    $0x2,(%rax)
  mov    %rdi,%r14
  lea    0x5(%rdi),%r15
  mov    $0x0,%ebx
  mov    $0xc000a040,%ebp
  jmp    L4
L59:
  mov    0x0(%rbp),%eax
  or     $0x2,%eax
L79:
  mov    %eax,0x0(%rbp)
  add    %ebx,%ebx
  mov    $0x0,%eax
  call   <clkDelay@plt>
  orl    $0x1,0x0(%rbp)
  mov    %ebx,%eax
  xor    $0x9,%eax
  mov    %ebx,%edx
  xor    %r12b,%dl
  cmovs  %eax,%ebx
  add    %r12d,%r12d
  sub    $0x1,%r13d
  je     L51
L96:
  andl   $0xfffffffe,0x0(%rbp)
  mov    $0x0,%eax
  call   <clkDelay@plt>
  test   %r12b,%r12b
  js     L59
  mov    0x0(%rbp),%eax
  and    $0xfffffffd,%eax
  jmp    L79
L51:
  and    $0x7f,%ebx
  add    $0x1,%r14
  cmp    %r15,%r14
  je     L36
L4:
  movzbl (%r14),%r12d
  mov    $0x8,%r13d
  jmp    L96
L36:
  lea    0x1(%rbx,%rbx,1),%ebx
  mov    %ebx,%r13d
  mov    $0x8,%r12d
  mov    $0xc000a040,%ebp
  jmp    L61
L26:
  mov    0x0(%rbp),%eax
  or     $0x2,%eax
L77:
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
  call   <clkDelay@plt>
  orl    $0x1,0x0(%rbp)
  add    %r13d,%r13d
  sub    $0x1,%r12d
  je     L70
L61:
  andl   $0xfffffffe,0x0(%rbp)
  mov    $0x0,%eax
  call   <clkDelay@plt>
  test   %r13b,%r13b
  js     L26
  mov    0x0(%rbp),%eax
  and    $0xfffffffd,%eax
  jmp    L77
L70:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char send_cmd(unsigned char *in) {
  int i, j;
  unsigned char b, crc = 0;
  *((unsigned int *)0xC000A044) |= (1 << 1);
  for (i = 0; i < 5; i++) {
    b = in[i];
    for (j = 0; j < 8; j++) {
      do {
        *((unsigned int *)0xC000A040) &= ~(1 << 0);
        clkDelay();
      } while (0);
      if (b & 0x80)
        *((unsigned int *)0xC000A040) |= (1 << 1);
      else
        *((unsigned int *)0xC000A040) &= ~(1 << 1);
      crc <<= 1;
      do {
        clkDelay();
        *((unsigned int *)0xC000A040) |= (1 << 0);
      } while (0);
      if ((crc ^ b) & 0x80)
        crc ^= 0x09;
      b <<= 1;
    }
    crc &= 0x7f;
  }
  crc = ((crc << 1) | 0x01);
  b = crc;
  for (j = 0; j < 8; j++) {
    do {
      *((unsigned int *)0xC000A040) &= ~(1 << 0);
      clkDelay();
    } while (0);
    if (crc & 0x80)
      *((unsigned int *)0xC000A040) |= (1 << 1);
    else
      *((unsigned int *)0xC000A040) &= ~(1 << 1);
    do {
      clkDelay();
      *((unsigned int *)0xC000A040) |= (1 << 0);
    } while (0);
    crc <<= 1;
  }
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_cmd>:
  endbr64
  push   %r15
  mov    $0xc000a044,%eax
  mov    $0xc000a040,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    0x5(%rdi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  orl    $0x2,(%rax)
  mov    (%r15),%eax
L43:
  movzbl (%r12),%ebx
  mov    $0x8,%ebp
  jmp    L1
  nopl   0x0(%rax)
L30:
  and    $0xfffffffd,%eax
L89:
  mov    %eax,(%r15)
  xor    %eax,%eax
  add    %r14d,%r14d
  call   <clkDelay@plt>
  mov    (%r15),%eax
  mov    %r14d,%edx
  mov    %r14d,%ecx
  xor    $0x9,%edx
  or     $0x1,%eax
  xor    %bl,%cl
  cmovs  %edx,%r14d
  mov    %eax,(%r15)
  add    %ebx,%ebx
  sub    $0x1,%ebp
  je     L38
L1:
  and    $0xfffffffe,%eax
  mov    %eax,(%r15)
  xor    %eax,%eax
  call   <clkDelay@plt>
  mov    (%r15),%eax
  test   %bl,%bl
  jns    L30
  or     $0x2,%eax
  jmp    L89
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x1,%r12
  and    $0x7f,%r14d
  cmp    %r12,%r13
  jne    L43
  lea    0x1(%r14,%r14,1),%r14d
  mov    $0x8,%ebp
  mov    $0xc000a040,%ebx
  mov    %r14d,%r12d
  jmp    L88
  nopl   0x0(%rax)
L56:
  and    $0xfffffffd,%eax
L74:
  mov    %eax,(%rbx)
  xor    %eax,%eax
  add    %r12d,%r12d
  call   <clkDelay@plt>
  mov    (%rbx),%eax
  or     $0x1,%eax
  mov    %eax,(%rbx)
  sub    $0x1,%ebp
  je     L49
L88:
  and    $0xfffffffe,%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <clkDelay@plt>
  mov    (%rbx),%eax
  test   %r12b,%r12b
  jns    L56
  or     $0x2,%eax
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char send_cmd(unsigned char *in) {
  int i, j;
  unsigned char b, crc = 0;
  *((unsigned int *)0xC000A044) |= (1 << 1);
  for (i = 0; i < 5; i++) {
    b = in[i];
    for (j = 0; j < 8; j++) {
      do {
        *((unsigned int *)0xC000A040) &= ~(1 << 0);
        clkDelay();
      } while (0);
      if (b & 0x80)
        *((unsigned int *)0xC000A040) |= (1 << 1);
      else
        *((unsigned int *)0xC000A040) &= ~(1 << 1);
      crc <<= 1;
      do {
        clkDelay();
        *((unsigned int *)0xC000A040) |= (1 << 0);
      } while (0);
      if ((crc ^ b) & 0x80)
        crc ^= 0x09;
      b <<= 1;
    }
    crc &= 0x7f;
  }
  crc = ((crc << 1) | 0x01);
  b = crc;
  for (j = 0; j < 8; j++) {
    do {
      *((unsigned int *)0xC000A040) &= ~(1 << 0);
      clkDelay();
    } while (0);
    if (crc & 0x80)
      *((unsigned int *)0xC000A040) |= (1 << 1);
    else
      *((unsigned int *)0xC000A040) &= ~(1 << 1);
    do {
      clkDelay();
      *((unsigned int *)0xC000A040) |= (1 << 0);
    } while (0);
    crc <<= 1;
  }
  return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<send_cmd>:
  endbr64
  push   %r15
  mov    $0xc000a044,%eax
  mov    $0xc000a040,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    0x5(%rdi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  orl    $0x2,(%rax)
  mov    (%r15),%eax
L6:
  movzbl (%r12),%ebx
  mov    $0x8,%ebp
  jmp    L17
  nopl   0x0(%rax)
L7:
  and    $0xfffffffd,%eax
L37:
  mov    %eax,(%r15)
  xor    %eax,%eax
  add    %r14d,%r14d
  call   <clkDelay@plt>
  mov    (%r15),%eax
  mov    %r14d,%edx
  mov    %r14d,%ecx
  xor    $0x9,%edx
  or     $0x1,%eax
  xor    %bl,%cl
  cmovs  %edx,%r14d
  mov    %eax,(%r15)
  add    %ebx,%ebx
  sub    $0x1,%ebp
  je     L75
L17:
  and    $0xfffffffe,%eax
  mov    %eax,(%r15)
  xor    %eax,%eax
  call   <clkDelay@plt>
  mov    (%r15),%eax
  test   %bl,%bl
  jns    L7
  or     $0x2,%eax
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L75:
  add    $0x1,%r12
  and    $0x7f,%r14d
  cmp    %r12,%r13
  jne    L6
  lea    0x1(%r14,%r14,1),%r14d
  mov    $0x8,%r12d
  mov    $0xc000a040,%ebx
  mov    %r14d,%ebp
  jmp    L87
  nopw   0x0(%rax,%rax,1)
L1:
  andl   $0xfffffffd,(%rbx)
L48:
  xor    %eax,%eax
  add    %ebp,%ebp
  call   <clkDelay@plt>
  mov    (%rbx),%eax
  or     $0x1,%eax
  mov    %eax,(%rbx)
  sub    $0x1,%r12d
  je     L13
L87:
  and    $0xfffffffe,%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <clkDelay@plt>
  test   %bpl,%bpl
  jns    L1
  orl    $0x2,(%rbx)
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char send_cmd(unsigned char *in) {
  int i, j;
  unsigned char b, crc = 0;
  *((unsigned int *)0xC000A044) |= (1 << 1);
  for (i = 0; i < 5; i++) {
    b = in[i];
    for (j = 0; j < 8; j++) {
      do {
        *((unsigned int *)0xC000A040) &= ~(1 << 0);
        clkDelay();
      } while (0);
      if (b & 0x80)
        *((unsigned int *)0xC000A040) |= (1 << 1);
      else
        *((unsigned int *)0xC000A040) &= ~(1 << 1);
      crc <<= 1;
      do {
        clkDelay();
        *((unsigned int *)0xC000A040) |= (1 << 0);
      } while (0);
      if ((crc ^ b) & 0x80)
        crc ^= 0x09;
      b <<= 1;
    }
    crc &= 0x7f;
  }
  crc = ((crc << 1) | 0x01);
  b = crc;
  for (j = 0; j < 8; j++) {
    do {
      *((unsigned int *)0xC000A040) &= ~(1 << 0);
      clkDelay();
    } while (0);
    if (crc & 0x80)
      *((unsigned int *)0xC000A040) |= (1 << 1);
    else
      *((unsigned int *)0xC000A040) &= ~(1 << 1);
    do {
      clkDelay();
      *((unsigned int *)0xC000A040) |= (1 << 0);
    } while (0);
    crc <<= 1;
  }
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dhash_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %rdi,-0xf8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x185,-0xd0(%rbp)
  movq   $0x301,-0xc8(%rbp)
  movq   $0x607,-0xc0(%rbp)
  movq   $0xc07,-0xb8(%rbp)
  movq   $0x1807,-0xb0(%rbp)
  movq   $0x3001,-0xa8(%rbp)
  movq   $0x6011,-0xa0(%rbp)
  movq   $0xc005,-0x98(%rbp)
  movq   $0x1800d,-0x90(%rbp)
  movq   $0x30005,-0x88(%rbp)
  movq   $0x60019,-0x80(%rbp)
  movq   $0xc0001,-0x78(%rbp)
  movq   $0x180005,-0x70(%rbp)
  movq   $0x30000b,-0x68(%rbp)
  movq   $0x60000d,-0x60(%rbp)
  movq   $0xc00005,-0x58(%rbp)
  movq   $0x1800013,-0x50(%rbp)
  movq   $0x3000005,-0x48(%rbp)
  movq   $0x6000017,-0x40(%rbp)
  movq   $0xc000013,-0x38(%rbp)
  movq   $0x18000005,-0x30(%rbp)
  movq   $0x30000059,-0x28(%rbp)
  movq   $0x60000005,-0x20(%rbp)
  mov    $0xc0000001,%eax
  mov    %rax,-0x18(%rbp)
  mov    $0xfffffffb,%eax
  mov    %rax,-0x10(%rbp)
  movq   $0x14,-0xe0(%rbp)
  mov    -0xf8(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0xd8(%rbp)
  cmpq   $0x7ffffffd,-0xf8(%rbp)
  jbe    L40
  mov    $0x0,%eax
  jmp    L57
L40:
  movq   $0x0,-0xe8(%rbp)
  jmp    L32
L67:
  mov    -0xe8(%rbp),%rax
  mov    -0xd0(%rbp,%rax,8),%rax
  cmp    %rax,-0xd8(%rbp)
  jb     L2
  addq   $0x1,-0xe8(%rbp)
L32:
  mov    -0xe0(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0xe8(%rbp)
  jb     L67
  jmp    L63
L2:
  nop
L63:
  mov    -0xe8(%rbp),%rax
  mov    -0xd0(%rbp,%rax,8),%rax
L57:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
size_t dhash_size(size_t entries) {
  size_t primes[] = {389UL, 769UL, 1543UL, 3079UL, 6151UL, 12289UL, 24593UL, 49157UL, 98317UL, 196613UL, 393241UL, 786433UL, 1572869UL, 3145739UL, 6291469UL, 12582917UL, 25165843UL, 50331653UL, 100663319UL, 201326611UL, 402653189UL, 805306457UL, 1610612741UL, 3221225473UL, 4294967291UL};
  size_t const p_count = 20;
  size_t wantsize = entries << 1, i;
  if (entries > 2147483645UL) {
    return 0;
  }
  for (i = 0; i < p_count - 1; i++) {
    if (primes[i] > wantsize) {
      break;
    }
  }
  return primes[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dhash_size>:
  endbr64
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movq   $0x185,(%rsp)
  movq   $0x301,0x8(%rsp)
  movq   $0x607,0x10(%rsp)
  movq   $0xc07,0x18(%rsp)
  movq   $0x1807,0x20(%rsp)
  movq   $0x3001,0x28(%rsp)
  movq   $0x6011,0x30(%rsp)
  movq   $0xc005,0x38(%rsp)
  movq   $0x1800d,0x40(%rsp)
  movq   $0x30005,0x48(%rsp)
  movq   $0x60019,0x50(%rsp)
  movq   $0xc0001,0x58(%rsp)
  movq   $0x180005,0x60(%rsp)
  movq   $0x30000b,0x68(%rsp)
  movq   $0x60000d,0x70(%rsp)
  movq   $0xc00005,0x78(%rsp)
  movq   $0x1800013,0x80(%rsp)
  movq   $0x3000005,0x88(%rsp)
  movq   $0x6000017,0x90(%rsp)
  movq   $0xc000013,0x98(%rsp)
  movq   $0x18000005,0xa0(%rsp)
  movq   $0x30000059,0xa8(%rsp)
  movq   $0x60000005,0xb0(%rsp)
  mov    $0xc0000001,%eax
  mov    %rax,0xb8(%rsp)
  lea    0x3ffffffa(%rax),%rax
  mov    %rax,0xc0(%rsp)
  mov    $0x0,%eax
  cmp    $0x7ffffffd,%rdi
  ja     L9
  add    %rdi,%rdi
  mov    %rsp,%rdx
L32:
  cmp    %rdi,(%rdx,%rax,8)
  ja     L7
  add    $0x1,%rax
  cmp    $0x13,%rax
  jne    L32
L7:
  mov    (%rsp,%rax,8),%rax
L9:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0xd8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t dhash_size(size_t entries) {
  size_t primes[] = {389UL, 769UL, 1543UL, 3079UL, 6151UL, 12289UL, 24593UL, 49157UL, 98317UL, 196613UL, 393241UL, 786433UL, 1572869UL, 3145739UL, 6291469UL, 12582917UL, 25165843UL, 50331653UL, 100663319UL, 201326611UL, 402653189UL, 805306457UL, 1610612741UL, 3221225473UL, 4294967291UL};
  size_t const p_count = 20;
  size_t wantsize = entries << 1, i;
  if (entries > 2147483645UL) {
    return 0;
  }
  for (i = 0; i < p_count - 1; i++) {
    if (primes[i] > wantsize) {
      break;
    }
  }
  return primes[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dhash_size>:
  endbr64
  sub    $0xd8,%rsp
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movq   $0x301,0x8(%rsp)
  movq   $0x607,0x10(%rsp)
  movq   $0xc07,0x18(%rsp)
  movq   $0x1807,0x20(%rsp)
  movq   $0x3001,0x28(%rsp)
  movq   $0x6011,0x30(%rsp)
  movq   $0xc005,0x38(%rsp)
  movq   $0x1800d,0x40(%rsp)
  movq   $0x30005,0x48(%rsp)
  movq   $0x60019,0x50(%rsp)
  movq   $0xc0001,0x58(%rsp)
  movq   $0x180005,0x60(%rsp)
  movq   $0x30000b,0x68(%rsp)
  movq   $0x60000d,0x70(%rsp)
  movq   $0xc00005,0x78(%rsp)
  movq   $0x1800013,0x80(%rsp)
  movq   $0x3000005,0x88(%rsp)
  movq   $0x6000017,0x90(%rsp)
  movq   $0xc000013,0x98(%rsp)
  cmp    $0x7ffffffd,%rdi
  ja     L22
  add    %rdi,%rdi
  lea    0x8(%rsp),%rax
  lea    0x98(%rsp),%rdx
  mov    $0x185,%r8d
  jmp    L3
  nopl   0x0(%rax)
L31:
  cmp    %rdx,%rax
  je     L8
  mov    (%rax),%r8
  add    $0x8,%rax
L3:
  cmp    %rdi,%r8
  jbe    L31
L22:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    %r8,%rax
  add    $0xd8,%rsp
  ret
  nop
L8:
  mov    $0xc000013,%r8d
  jmp    L22
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t dhash_size(size_t entries) {
  size_t primes[] = {389UL, 769UL, 1543UL, 3079UL, 6151UL, 12289UL, 24593UL, 49157UL, 98317UL, 196613UL, 393241UL, 786433UL, 1572869UL, 3145739UL, 6291469UL, 12582917UL, 25165843UL, 50331653UL, 100663319UL, 201326611UL, 402653189UL, 805306457UL, 1610612741UL, 3221225473UL, 4294967291UL};
  size_t const p_count = 20;
  size_t wantsize = entries << 1, i;
  if (entries > 2147483645UL) {
    return 0;
  }
  for (i = 0; i < p_count - 1; i++) {
    if (primes[i] > wantsize) {
      break;
    }
  }
  return primes[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<dhash_size>:
  endbr64
  sub    $0xd8,%rsp
  movdqa D62(%rip),%xmm0
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movq   $0xc000013,0x98(%rsp)
  movups %xmm0,0x8(%rsp)
  movdqa D67(%rip),%xmm0
  movups %xmm0,0x18(%rsp)
  movdqa D60(%rip),%xmm0
  movups %xmm0,0x28(%rsp)
  movdqa D30(%rip),%xmm0
  movups %xmm0,0x38(%rsp)
  movdqa D21(%rip),%xmm0
  movups %xmm0,0x48(%rsp)
  movdqa D7(%rip),%xmm0
  movups %xmm0,0x58(%rsp)
  movdqa D36(%rip),%xmm0
  movups %xmm0,0x68(%rsp)
  movdqa D66(%rip),%xmm0
  movups %xmm0,0x78(%rsp)
  movdqa D51(%rip),%xmm0
  movups %xmm0,0x88(%rsp)
  cmp    $0x7ffffffd,%rdi
  ja     L2
  add    %rdi,%rdi
  lea    0x8(%rsp),%rax
  lea    0x98(%rsp),%rdx
  mov    $0x185,%r8d
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L7:
  cmp    %rax,%rdx
  je     L34
  mov    (%rax),%r8
  add    $0x8,%rax
L24:
  cmp    %rdi,%r8
  jbe    L7
L2:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    %r8,%rax
  add    $0xd8,%rsp
  ret
  nop
L34:
  mov    $0xc000013,%r8d
  jmp    L2
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D62
type: byte[16]
name: retrieve_data
arguments: label: D67
type: byte[16]
name: retrieve_data
arguments: label: D60
type: byte[16]
name: retrieve_data
arguments: label: D30
type: byte[16]
name: retrieve_data
arguments: label: D21
type: byte[16]
name: retrieve_data
arguments: label: D7
type: byte[16]
name: retrieve_data
arguments: label: D36
type: byte[16]
name: retrieve_data
arguments: label: D66
type: byte[16]
name: retrieve_data
arguments: label: D51
type: byte[16]

tool: {"D62": [0x01,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x07,0x06,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D67": [0x07,0x0c,0x00,0x00,0x00,0x00,0x00,0x00,0x07,0x18,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D60": [0x01,0x30,0x00,0x00,0x00,0x00,0x00,0x00,0x11,0x60,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D30": [0x05,0xc0,0x00,0x00,0x00,0x00,0x00,0x00,0x0d,0x80,0x01,0x00,0x00,0x00,0x00,0x00]}

tool: {"D21": [0x05,0x00,0x03,0x00,0x00,0x00,0x00,0x00,0x19,0x00,0x06,0x00,0x00,0x00,0x00,0x00]}

tool: {"D7": [0x01,0x00,0x0c,0x00,0x00,0x00,0x00,0x00,0x05,0x00,0x18,0x00,0x00,0x00,0x00,0x00]}

tool: {"D36": [0x0b,0x00,0x30,0x00,0x00,0x00,0x00,0x00,0x0d,0x00,0x60,0x00,0x00,0x00,0x00,0x00]}

tool: {"D66": [0x05,0x00,0xc0,0x00,0x00,0x00,0x00,0x00,0x13,0x00,0x80,0x01,0x00,0x00,0x00,0x00]}

tool: {"D51": [0x05,0x00,0x00,0x03,0x00,0x00,0x00,0x00,0x17,0x00,0x00,0x06,0x00,0x00,0x00,0x00]}

assistant: ```c
size_t dhash_size(size_t entries) {
  size_t primes[] = {389UL, 769UL, 1543UL, 3079UL, 6151UL, 12289UL, 24593UL, 49157UL, 98317UL, 196613UL, 393241UL, 786433UL, 1572869UL, 3145739UL, 6291469UL, 12582917UL, 25165843UL, 50331653UL, 100663319UL, 201326611UL, 402653189UL, 805306457UL, 1610612741UL, 3221225473UL, 4294967291UL};
  size_t const p_count = 20;
  size_t wantsize = entries << 1, i;
  if (entries > 2147483645UL) {
    return 0;
  }
  for (i = 0; i < p_count - 1; i++) {
    if (primes[i] > wantsize) {
      break;
    }
  }
  return primes[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fnDispArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string

tool: D5:  %5d 


assistant: ```c
void fnDispArray(int X[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %5d \n", X[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fnDispArray>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D2(%rip),%rbp
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2:  %5d 


assistant: ```c
void fnDispArray(int X[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %5d \n", X[i]);
}
```