ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L8:
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *p = s;
  while (*s != (char)0) {
    ++s;
  }
  return (size_t)(s - p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L20
  mov    %rdi,%rax
L19:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L19
L18:
  sub    %rdi,%rax
  ret
L20:
  mov    %rdi,%rax
  jmp    L18
```

assistant: ```c
size_t strlen(const char *s) {
  const char *p = s;
  while (*s != (char)0) {
    ++s;
  }
  return (size_t)(s - p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  mov    %rdi,%rax
  nopl   0x0(%rax)
L18:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L18
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *p = s;
  while (*s != (char)0) {
    ++s;
  }
  return (size_t)(s - p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    %rdi,%rax
  nopl   0x0(%rax)
L13:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L13
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *p = s;
  while (*s != (char)0) {
    ++s;
  }
  return (size_t)(s - p);
}
```
user: What is the c source code of the assembly code below?

```asm
<crc32c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0x3,-0x8(%rbp)
  ja     L10
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <singletable_crc32c@plt>
  jmp    L12
L10:
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <multitable_crc32c@plt>
L12:
  leave
  ret
```

assistant: ```c
uint32_t crc32c(uint32_t crc32c, const char *buffer, unsigned int length) {
  if (length < 4) {
    return (singletable_crc32c(crc32c, buffer, length));
  } else {
    return (multitable_crc32c(crc32c, (const unsigned char *)buffer, length));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<crc32c>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3,%edx
  ja     L12
  call   <singletable_crc32c@plt>
L6:
  add    $0x8,%rsp
  ret
L12:
  call   <multitable_crc32c@plt>
  jmp    L6
```

assistant: ```c
uint32_t crc32c(uint32_t crc32c, const char *buffer, unsigned int length) {
  if (length < 4) {
    return (singletable_crc32c(crc32c, buffer, length));
  } else {
    return (multitable_crc32c(crc32c, (const unsigned char *)buffer, length));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<crc32c>:
  endbr64
  cmp    $0x3,%edx
  ja     L2
  jmp    1070 <singletable_crc32c@plt>
  xchg   %ax,%ax
L2:
  jmp    1060 <multitable_crc32c@plt>
```

assistant: ```c
uint32_t crc32c(uint32_t crc32c, const char *buffer, unsigned int length) {
  if (length < 4) {
    return (singletable_crc32c(crc32c, buffer, length));
  } else {
    return (multitable_crc32c(crc32c, (const unsigned char *)buffer, length));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crc32c>:
  endbr64
  cmp    $0x3,%edx
  ja     L8
  jmp    1070 <singletable_crc32c@plt>
  xchg   %ax,%ax
L8:
  jmp    1060 <multitable_crc32c@plt>
```

assistant: ```c
uint32_t crc32c(uint32_t crc32c, const char *buffer, unsigned int length) {
  if (length < 4) {
    return (singletable_crc32c(crc32c, buffer, length));
  } else {
    return (multitable_crc32c(crc32c, (const unsigned char *)buffer, length));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<client_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x410(%rbp)
  movq   $0x0,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L27
L28:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    -0x424(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
L27:
  lea    -0x410(%rbp),%rcx
  mov    -0x424(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x414(%rbp)
  cmpl   $0x0,-0x414(%rbp)
  jg     L28
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D11: ****************************

tool: D8: recv data is %s


assistant: ```c
void client_dump(int sock_fd) {
  char rec[1024] = {0};
  int size;
  while ((size = read(sock_fd, rec, 1024)) > 0) {
    printf("****************************\n");
    printf("recv data is %s\n", rec);
    write(sock_fd, rec, size);
    bzero(rec, 1024);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<client_dump>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbp
  lea    D12(%rip),%r14
  lea    D11(%rip),%r13
  jmp    L5
L10:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
L5:
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L10
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string

tool: D12: ****************************

tool: D11: recv data is %s


assistant: ```c
void client_dump(int sock_fd) {
  char rec[1024] = {0};
  int size;
  while ((size = read(sock_fd, rec, 1024)) > 0) {
    printf("****************************\n");
    printf("recv data is %s\n", rec);
    write(sock_fd, rec, size);
    bzero(rec, 1024);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<client_dump>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  mov    $0x7e,%ecx
  lea    D15(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  mov    %rsp,%rbx
  rep stos %rax,%es:(%rdi)
  jmp    L12
L28:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  mov    %r12d,%edx
  call   <write@plt>
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <bzero@plt>
L12:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L28
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D15: ****************************

tool: D4: recv data is %s


assistant: ```c
void client_dump(int sock_fd) {
  char rec[1024] = {0};
  int size;
  while ((size = read(sock_fd, rec, 1024)) > 0) {
    printf("****************************\n");
    printf("recv data is %s\n", rec);
    write(sock_fd, rec, size);
    bzero(rec, 1024);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<client_dump>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  mov    $0x7e,%ecx
  lea    D18(%rip),%r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  mov    %rsp,%rbx
  rep stos %rax,%es:(%rdi)
  jmp    L17
L6:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  mov    %r12d,%edx
  call   <write@plt>
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <bzero@plt>
L17:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L6
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
type_infered: string
name: read_data
arguments: label: D12
type_infered: string

tool: D18: ****************************

tool: D12: recv data is %s


assistant: ```c
void client_dump(int sock_fd) {
  char rec[1024] = {0};
  int size;
  while ((size = read(sock_fd, rec, 1024)) > 0) {
    printf("****************************\n");
    printf("recv data is %s\n", rec);
    write(sock_fd, rec, size);
    bzero(rec, 1024);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int snprintf(char *str, size_t size, const char *format, ...) {
  va_list ap;
  int rv;
  va_start(ap, format);
  rv = vsnprintf(str, size, format, ap);
  va_end(ap);
  return rv;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int snprintf(char *str, size_t size, const char *format, ...) {
  va_list ap;
  int rv;
  va_start(ap, format);
  rv = vsnprintf(str, size, format, ap);
  va_end(ap);
  return rv;
}
```
user: What is the c source code of the assembly code below?

```asm
<snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int snprintf(char *str, size_t size, const char *format, ...) {
  va_list ap;
  int rv;
  va_start(ap, format);
  rv = vsnprintf(str, size, format, ap);
  va_end(ap);
  return rv;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int snprintf(char *str, size_t size, const char *format, ...) {
  va_list ap;
  int rv;
  va_start(ap, format);
  rv = vsnprintf(str, size, format, ap);
  va_end(ap);
  return rv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<muliplicarMatrices>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L47:
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L50:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L38:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L38
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L50
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L47
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void muliplicarMatrices(int filasA, double *matrizB, double *resultado, double *matrizA, int columnasB, int columnasA) {
  int i, j, k;
  for (i = 0; i < filasA; ++i) {
    for (j = 0; j < columnasB; ++j) {
      resultado[i + j] = 0;
      for (k = 0; k < columnasA; ++k) {
        resultado[i + j] = (resultado[i + j] + (matrizA[i + k] * matrizB[k + j]));
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<muliplicarMatrices>:
  endbr64
  test   %edi,%edi
  jle    L45
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r10d
  mov    %rsi,%r11
  mov    %rdx,%r12
  mov    %rcx,%rsi
  mov    %r8d,%ebx
  mov    %r9d,%ebp
  mov    $0x0,%r13d
  mov    %r9d,%edi
  jmp    L30
L38:
  mov    %r8,%rdx
  movq   $0x0,(%r8)
  test   %ebp,%ebp
  jle    L8
  mov    $0x0,%eax
L77:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L77
L8:
  add    $0x1,%r9d
  add    $0x8,%r8
  add    $0x8,%rcx
  cmp    %r9d,%ebx
  jne    L38
L79:
  add    $0x1,%r13d
  add    $0x8,%r12
  add    $0x8,%rsi
  cmp    %r13d,%r10d
  je     L73
L30:
  mov    %r11,%rcx
  mov    %r12,%r8
  mov    $0x0,%r9d
  test   %ebx,%ebx
  jg     L38
  jmp    L79
L73:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  ret
```

assistant: ```c
void muliplicarMatrices(int filasA, double *matrizB, double *resultado, double *matrizA, int columnasB, int columnasA) {
  int i, j, k;
  for (i = 0; i < filasA; ++i) {
    for (j = 0; j < columnasB; ++j) {
      resultado[i + j] = 0;
      for (k = 0; k < columnasA; ++k) {
        resultado[i + j] = (resultado[i + j] + (matrizA[i + k] * matrizB[k + j]));
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<muliplicarMatrices>:
  endbr64
  test   %edi,%edi
  jle    L23
  push   %r12
  mov    %edi,%r11d
  mov    %r8d,%r10d
  xor    %r12d,%r12d
  push   %rbp
  pxor   %xmm2,%xmm2
  mov    %rdx,%rbp
  movslq %r9d,%rdi
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  nopl   0x0(%rax)
L44:
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  xor    %r8d,%r8d
  test   %r10d,%r10d
  jle    L57
  xchg   %ax,%ax
L8:
  movq   $0x0,(%rdx)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  test   %r9d,%r9d
  jle    L59
  nopw   0x0(%rax,%rax,1)
L17:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %rdi,%rax
  jne    L17
L59:
  add    $0x1,%r8d
  add    $0x8,%rdx
  add    $0x8,%rcx
  cmp    %r8d,%r10d
  jne    L8
L57:
  add    $0x1,%r12d
  add    $0x8,%rsi
  add    $0x8,%rbp
  cmp    %r12d,%r11d
  jne    L44
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  ret
```

assistant: ```c
void muliplicarMatrices(int filasA, double *matrizB, double *resultado, double *matrizA, int columnasB, int columnasA) {
  int i, j, k;
  for (i = 0; i < filasA; ++i) {
    for (j = 0; j < columnasB; ++j) {
      resultado[i + j] = 0;
      for (k = 0; k < columnasA; ++k) {
        resultado[i + j] = (resultado[i + j] + (matrizA[i + k] * matrizB[k + j]));
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<muliplicarMatrices>:
  endbr64
  test   %edi,%edi
  jle    L56
  mov    %r8d,%r11d
  test   %r8d,%r8d
  jle    L56
  push   %r12
  mov    %rsi,%r10
  movslq %edi,%r12
  mov    %rcx,%rsi
  push   %rbp
  pxor   %xmm2,%xmm2
  xor    %ebp,%ebp
  movslq %r9d,%rdi
  push   %rbx
  mov    %rdx,%rbx
  nopl   0x0(%rax)
L44:
  mov    %r10,%rcx
  mov    %rbx,%rdx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L27:
  movq   $0x0,(%rdx)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  test   %r9d,%r9d
  jle    L23
  nopw   0x0(%rax,%rax,1)
L30:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %rax,%rdi
  jne    L30
L23:
  add    $0x1,%r8d
  add    $0x8,%rdx
  add    $0x8,%rcx
  cmp    %r8d,%r11d
  jne    L27
  add    $0x1,%rbp
  add    $0x8,%rbx
  add    $0x8,%rsi
  cmp    %r12,%rbp
  jne    L44
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  ret
```

assistant: ```c
void muliplicarMatrices(int filasA, double *matrizB, double *resultado, double *matrizA, int columnasB, int columnasA) {
  int i, j, k;
  for (i = 0; i < filasA; ++i) {
    for (j = 0; j < columnasB; ++j) {
      resultado[i + j] = 0;
      for (k = 0; k < columnasA; ++k) {
        resultado[i + j] = (resultado[i + j] + (matrizA[i + k] * matrizB[k + j]));
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L81
L50:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L68
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L91:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L53
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L67
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L91
  jmp    L67
L53:
  nop
L67:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
  mov    -0x18(%rbp),%rax
  jmp    L38
L68:
  addq   $0x1,-0x18(%rbp)
L81:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
  mov    $0x0,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(const char *cs, const char *ct) {
  char *cq;
  char *cr;
  for (; *cs != '\0'; cs++) {
    if (*cs == *ct) {
      cq = (char *)cs;
      cr = (char *)ct;
      while ((*cq != '\0') && (*cr != '\0')) {
        if (*cq != *cr) {
          break;
        }
        cq++;
        cr++;
      }
      if ('\0' == *cr) {
        return (char *)cs;
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strstr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  movzbl (%rsi),%r10d
  jmp    L26
L70:
  cmpb   $0x0,(%rdx)
  je     L41
L46:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L91
L26:
  cmp    %al,%r10b
  jne    L46
  movzbl (%rdi),%ecx
  mov    %rsi,%rdx
  mov    %rdi,%r9
  test   %cl,%cl
  je     L70
L18:
  movzbl (%rdx),%r8d
  cmp    %cl,%r8b
  jne    L70
  test   %r8b,%r8b
  je     L70
  add    $0x1,%r9
  add    $0x1,%rdx
  movzbl (%r9),%ecx
  test   %cl,%cl
  jne    L18
  jmp    L70
L91:
  mov    $0x0,%eax
  ret
L24:
  mov    $0x0,%eax
  ret
L41:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strstr(const char *cs, const char *ct) {
  char *cq;
  char *cr;
  for (; *cs != '\0'; cs++) {
    if (*cs == *ct) {
      cq = (char *)cs;
      cr = (char *)ct;
      while ((*cq != '\0') && (*cr != '\0')) {
        if (*cq != *cr) {
          break;
        }
        cq++;
        cr++;
      }
      if ('\0' == *cr) {
        return (char *)cs;
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strstr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
  movzbl (%rsi),%r8d
  jmp    L67
  nopl   0x0(%rax)
L60:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L26
L67:
  cmp    %al,%r8b
  jne    L60
  movzbl (%rdi),%eax
  mov    %r8d,%ecx
  mov    $0x1,%edx
  test   %al,%al
  jne    L74
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L63:
  test   %cl,%cl
  je     L91
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %al,%al
  je     L35
L74:
  cmp    %cl,%al
  je     L63
L35:
  test   %cl,%cl
  jne    L60
L91:
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strstr(const char *cs, const char *ct) {
  char *cq;
  char *cr;
  for (; *cs != '\0'; cs++) {
    if (*cs == *ct) {
      cq = (char *)cs;
      cr = (char *)ct;
      while ((*cq != '\0') && (*cr != '\0')) {
        if (*cq != *cr) {
          break;
        }
        cq++;
        cr++;
      }
      if ('\0' == *cr) {
        return (char *)cs;
      }
    }
  }
  return 0;
}
```