ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strip_colour>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L87
L115:
  cmpl   $0x0,-0x18(%rbp)
  je     L97
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L76
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L76
  movl   $0x0,-0x18(%rbp)
L97:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x1f,%eax
  seta   %dl
  test   %dl,%dl
  jne    L2
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,%rdx
  and    $0xa8c000c4,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L14
  and    $0x8,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L2
  movl   $0x1,-0x18(%rbp)
  jmp    L77
L2:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L77
L76:
  nop
  jmp    L77
L14:
  nop
L77:
  addl   $0x1,-0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L87:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L115
L29:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void strip_colour(const char *string, char *result, int len) {
  const char *sptr;
  char *rptr = result;
  int hunt_colour = 0;
  int l = 0;
  for (sptr = string; *sptr != '\0' && l < (len - 1); l++, sptr++) {
    if (hunt_colour) {
      if (isdigit(*sptr) || (*sptr == ','))
        continue;
      else
        hunt_colour = 0;
    }
    switch (*sptr) {
    case 3:
      hunt_colour = 1;
      break;
    case 2:
    case 6:
    case 7:
    case 22:
    case 23:
    case 27:
    case 29:
    case 31:
      break;
    default:
      *(rptr++) = *sptr;
      break;
    }
  }
  *(rptr) = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strip_colour>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L79
  cmp    $0x1,%edx
  jle    L79
  lea    -0x2(%rdx),%eax
  lea    0x1(%rbx,%rax,1),%r14
  mov    $0x0,%ebp
  mov    $0x0,%r13d
  jmp    L103
L13:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L70
  cmpb   $0x2c,(%rbx)
  jne    L24
L70:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L79
  cmp    %rbx,%r14
  je     L79
L103:
  test   %ebp,%ebp
  jne    L13
L24:
  movzbl (%rbx),%ecx
  cmp    $0x1f,%cl
  ja     L58
  mov    $0x1,%eax
  shl    %cl,%rax
  mov    %r13d,%ebp
  test   $0xa8c000c4,%eax
  jne    L70
  cmp    $0x3,%cl
  je     L4
L58:
  mov    %cl,(%r12)
  lea    0x1(%r12),%r12
  mov    %r13d,%ebp
  jmp    L70
L4:
  mov    $0x1,%ebp
  jmp    L70
L79:
  movb   $0x0,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void strip_colour(const char *string, char *result, int len) {
  const char *sptr;
  char *rptr = result;
  int hunt_colour = 0;
  int l = 0;
  for (sptr = string; *sptr != '\0' && l < (len - 1); l++, sptr++) {
    if (hunt_colour) {
      if (isdigit(*sptr) || (*sptr == ','))
        continue;
      else
        hunt_colour = 0;
    }
    switch (*sptr) {
    case 3:
      hunt_colour = 1;
      break;
    case 2:
    case 6:
    case 7:
    case 22:
    case 23:
    case 27:
    case 29:
    case 31:
      break;
    default:
      *(rptr++) = *sptr;
      break;
    }
  }
  *(rptr) = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip_colour>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L127
  cmp    $0x1,%edx
  jle    L127
  lea    -0x2(%rdx),%eax
  xor    %ebp,%ebp
  lea    0x1(%rbx,%rax,1),%r13
  jmp    L9
  nopl   (%rax)
L95:
  movzbl (%rbx),%ecx
L68:
  cmp    $0x1f,%cl
  ja     L121
  mov    $0x1,%eax
  xor    %ebp,%ebp
  shl    %cl,%rax
  test   $0xa8c000c4,%eax
  jne    L17
  cmp    $0x3,%cl
  je     L56
L121:
  mov    %cl,(%r12)
  xor    %ebp,%ebp
  add    $0x1,%r12
L17:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L127
L62:
  cmp    %rbx,%r13
  je     L127
L9:
  test   %ebp,%ebp
  je     L95
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L17
  movzbl (%rbx),%ecx
  cmp    $0x2c,%cl
  jne    L68
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L62
L127:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L56:
  mov    $0x1,%ebp
  jmp    L17
```

assistant: ```c
void strip_colour(const char *string, char *result, int len) {
  const char *sptr;
  char *rptr = result;
  int hunt_colour = 0;
  int l = 0;
  for (sptr = string; *sptr != '\0' && l < (len - 1); l++, sptr++) {
    if (hunt_colour) {
      if (isdigit(*sptr) || (*sptr == ','))
        continue;
      else
        hunt_colour = 0;
    }
    switch (*sptr) {
    case 3:
      hunt_colour = 1;
      break;
    case 2:
    case 6:
    case 7:
    case 22:
    case 23:
    case 27:
    case 29:
    case 31:
      break;
    default:
      *(rptr++) = *sptr;
      break;
    }
  }
  *(rptr) = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strip_colour>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L45
  cmp    $0x1,%edx
  jle    L45
  lea    -0x2(%rdx),%eax
  mov    %rdi,%rbx
  xor    %ebp,%ebp
  lea    0x1(%rdi,%rax,1),%r13
  jmp    L96
  nopl   0x0(%rax)
L27:
  cmp    $0x1f,%cl
  ja     L119
  mov    $0x1,%eax
  xor    %ebp,%ebp
  shl    %cl,%rax
  test   $0xa8c000c4,%eax
  jne    L51
  cmp    $0x3,%cl
  je     L52
L119:
  mov    %cl,(%r12)
  xor    %ebp,%ebp
  add    $0x1,%r12
L51:
  movzbl 0x1(%rbx),%ecx
  add    $0x1,%rbx
  test   %cl,%cl
  je     L45
L92:
  cmp    %rbx,%r13
  je     L45
L96:
  test   %ebp,%ebp
  je     L27
  movsbl %cl,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L51
  movzbl (%rbx),%ecx
  cmp    $0x2c,%cl
  jne    L27
  movzbl 0x1(%rbx),%ecx
  add    $0x1,%rbx
  test   %cl,%cl
  jne    L92
L45:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  mov    $0x1,%ebp
  jmp    L51
```

assistant: ```c
void strip_colour(const char *string, char *result, int len) {
  const char *sptr;
  char *rptr = result;
  int hunt_colour = 0;
  int l = 0;
  for (sptr = string; *sptr != '\0' && l < (len - 1); l++, sptr++) {
    if (hunt_colour) {
      if (isdigit(*sptr) || (*sptr == ','))
        continue;
      else
        hunt_colour = 0;
    }
    switch (*sptr) {
    case 3:
      hunt_colour = 1;
      break;
    case 2:
    case 6:
    case 7:
    case 22:
    case 23:
    case 27:
    case 29:
    case 31:
      break;
    default:
      *(rptr++) = *sptr;
      break;
    }
  }
  *(rptr) = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<moduloPI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L27
  jmp    L30
L15:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x4(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L30:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  ja     L15
  jmp    L9
L27:
  jmp    L59
L44:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L59:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  comiss -0x4(%rbp),%xmm0
  jae    L44
L9:
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float moduloPI(float angle) {
  if (angle >= 0)
    while (angle > M_PI / 2)
      angle -= M_PI;
  else
    while (angle <= -M_PI / 2)
      angle += M_PI;
  return angle;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<feat_gettraj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L18:
  mov    -0x4(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void feat_gettraj(int N, float *feats, int D, int d, float *traj) {
  for (int n = 0; n < N; n++)
    traj[n] = feats[n * D + d];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<feat_gettraj>:
  endbr64
  mov    %edi,%r9d
  test   %edi,%edi
  jle    L11
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rdi
  movslq %ecx,%rcx
  lea    (%rsi,%rcx,4),%rdx
  mov    %r8,%rax
  lea    -0x1(%r9),%ecx
  lea    0x4(%r8,%rcx,4),%rcx
L6:
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  add    %rdi,%rdx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L6
L11:
  ret
```

assistant: ```c
void feat_gettraj(int N, float *feats, int D, int d, float *traj) {
  for (int n = 0; n < N; n++)
    traj[n] = feats[n * D + d];
}
```
user: Translate the below assembly code into C programming language:

```asm
<feat_gettraj>:
  endbr64
  test   %edi,%edi
  jle    L12
  movslq %ecx,%rcx
  movslq %edx,%rdx
  lea    (%rsi,%rcx,4),%rax
  lea    -0x1(%rdi),%ecx
  shl    $0x2,%rdx
  lea    0x4(%r8,%rcx,4),%rcx
  xchg   %ax,%ax
L8:
  movss  (%rax),%xmm0
  add    $0x4,%r8
  add    %rdx,%rax
  movss  %xmm0,-0x4(%r8)
  cmp    %rcx,%r8
  jne    L8
L12:
  ret
```

assistant: ```c
void feat_gettraj(int N, float *feats, int D, int d, float *traj) {
  for (int n = 0; n < N; n++)
    traj[n] = feats[n * D + d];
}
```
user: Translate the below assembly code into C programming language:

```asm
<feat_gettraj>:
  endbr64
  test   %edi,%edi
  jle    L81
  cmp    $0x1,%edx
  jne    L44
  movslq %ecx,%rax
  lea    0x4(,%rax,4),%rdx
  mov    %r8,%rax
  lea    (%rsi,%rdx,1),%r9
  sub    %r9,%rax
  cmp    $0x8,%rax
  jbe    L62
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L62
  lea    -0x4(%rsi,%rdx,1),%r9
  mov    %edi,%edx
  xor    %eax,%eax
  shr    $0x2,%edx
  shl    $0x4,%rdx
L28:
  movups (%r9,%rax,1),%xmm1
  movups %xmm1,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L28
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dil
  je     L81
  lea    (%rcx,%rax,1),%edx
  mov    %eax,%r9d
  movslq %edx,%rdx
  lea    0x0(,%r9,4),%r10
  movss  (%rsi,%rdx,4),%xmm0
  lea    0x1(%rax),%edx
  movss  %xmm0,(%r8,%r9,4)
  cmp    %edx,%edi
  jle    L81
  add    %ecx,%edx
  add    $0x2,%eax
  movslq %edx,%rdx
  movss  (%rsi,%rdx,4),%xmm0
  movss  %xmm0,0x4(%r8,%r10,1)
  cmp    %eax,%edi
  jle    L81
  add    %eax,%ecx
  movslq %ecx,%rcx
  movss  (%rsi,%rcx,4),%xmm0
  movss  %xmm0,0x8(%r8,%r10,1)
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  lea    -0x4(%rsi,%rdx,1),%rcx
  mov    %edi,%eax
  xor    %edx,%edx
  nopl   0x0(%rax)
L3:
  movss  (%rcx,%rdx,4),%xmm0
  movss  %xmm0,(%r8,%rdx,4)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L3
L81:
  ret
  nopl   (%rax)
L44:
  movslq %ecx,%rcx
  movslq %edx,%rdx
  lea    (%rsi,%rcx,4),%rax
  lea    -0x1(%rdi),%ecx
  shl    $0x2,%rdx
  lea    0x4(%r8,%rcx,4),%rcx
  xchg   %ax,%ax
L59:
  movss  (%rax),%xmm0
  add    $0x4,%r8
  add    %rdx,%rax
  movss  %xmm0,-0x4(%r8)
  cmp    %rcx,%r8
  jne    L59
  ret
```

assistant: ```c
void feat_gettraj(int N, float *feats, int D, int d, float *traj) {
  for (int n = 0; n < N; n++)
    traj[n] = feats[n * D + d];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<alignof_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8,%eax
  pop    %rbp
  ret
```

assistant: ```c
int alignof_double() {
  struct s {
    char x;
    double y;
  };
  return sizeof(char) + (sizeof(struct s) - (sizeof(char) + sizeof(double)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<alignof_double>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int alignof_double() {
  struct s {
    char x;
    double y;
  };
  return sizeof(char) + (sizeof(struct s) - (sizeof(char) + sizeof(double)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alignof_double>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int alignof_double() {
  struct s {
    char x;
    double y;
  };
  return sizeof(char) + (sizeof(struct s) - (sizeof(char) + sizeof(double)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alignof_double>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int alignof_double() {
  struct s {
    char x;
    double y;
  };
  return sizeof(char) + (sizeof(struct s) - (sizeof(char) + sizeof(double)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   $0x10,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t *size = malloc(sizeof(size_t));
  *size = 16;
  void *p = malloc(*size);
  ((char *)p)[16] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t *size = malloc(sizeof(size_t));
  *size = 16;
  void *p = malloc(*size);
  ((char *)p)[16] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t *size = malloc(sizeof(size_t));
  *size = 16;
  void *p = malloc(*size);
  ((char *)p)[16] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t *size = malloc(sizeof(size_t));
  *size = 16;
  void *p = malloc(*size);
  ((char *)p)[16] = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strlwr(char *psz) {
  char *ret = psz;
  while (*psz) {
    *psz = tolower(*psz);
    psz++;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlwr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L12
  mov    %rbp,%rbx
L18:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L12:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strlwr(char *psz) {
  char *ret = psz;
  while (*psz) {
    *psz = tolower(*psz);
    psz++;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlwr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  mov    %r12,%rbx
  nopl   0x0(%rax)
L8:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L8
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *psz) {
  char *ret = psz;
  while (*psz) {
    *psz = tolower(*psz);
    psz++;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlwr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  mov    %r12,%rbx
  nopl   0x0(%rax)
L11:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L11
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *psz) {
  char *ret = psz;
  while (*psz) {
    *psz = tolower(*psz);
    psz++;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_is_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  mov    $0x4e,%edi
  call   <ft_putchar@plt>
  jmp    L17
L1:
  mov    $0x50,%edi
  call   <ft_putchar@plt>
L17:
  nop
  leave
  ret
```

assistant: ```c
void ft_is_negative(int n) {
  if (n < 0)
    ft_putchar('N');
  else
    ft_putchar('P');
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_is_negative>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L17
  mov    $0x50,%edi
  call   <ft_putchar@plt>
L4:
  add    $0x8,%rsp
  ret
L17:
  mov    $0x4e,%edi
  call   <ft_putchar@plt>
  jmp    L4
```

assistant: ```c
void ft_is_negative(int n) {
  if (n < 0)
    ft_putchar('N');
  else
    ft_putchar('P');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_is_negative>:
  endbr64
  test   %edi,%edi
  js     L5
  mov    $0x50,%edi
  jmp    1050 <ft_putchar@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x4e,%edi
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_is_negative(int n) {
  if (n < 0)
    ft_putchar('N');
  else
    ft_putchar('P');
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_is_negative>:
  endbr64
  test   %edi,%edi
  js     L2
  mov    $0x50,%edi
  jmp    1050 <ft_putchar@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x4e,%edi
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_is_negative(int n) {
  if (n < 0)
    ft_putchar('N');
  else
    ft_putchar('P');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fir_filter_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x8,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %r8,-0x78(%rbp)
  mov    %r9,-0x80(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  sar    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x68(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  movq   $0x0,-0x50(%rbp)
  jmp    L28
L17:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%rax
  imul   %rcx,%rax
  mov    %rax,-0x38(%rbp)
  movq   $0x1,-0x48(%rbp)
  jmp    L54
L11:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%rax
  imul   %rcx,%rax
  add    %rax,-0x38(%rbp)
  addq   $0x1,-0x48(%rbp)
L54:
  mov    -0x48(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jl     L11
  mov    -0x38(%rbp),%rax
  cqto
  idivq  -0x80(%rbp)
  mov    %eax,%ecx
  mov    -0x60(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x60(%rbp)
  movslq %ecx,%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L35
  subq   $0x1,-0x40(%rbp)
  addq   $0x8,-0x20(%rbp)
  jmp    L49
L35:
  mov    -0x40(%rbp),%rax
  cmp    -0x78(%rbp),%rax
  jge    L12
  addq   $0x1,-0x40(%rbp)
L12:
  addq   $0x8,-0x30(%rbp)
L49:
  addq   $0x1,-0x50(%rbp)
L28:
  mov    -0x50(%rbp),%rax
  cmp    -0x68(%rbp),%rax
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void fir_filter_int(long *in, long *out, long in_len, long *coef, long coef_len, long scale) {
  long i, j, coef_len2, acc_length;
  long acc;
  long *in_ptr, *data_ptr, *coef_start, *coef_ptr, *in_end;
  coef_start = coef;
  coef_len2 = (coef_len + 1) >> 1;
  in_end = in + in_len - 1;
  in_ptr = in + coef_len2 - 1;
  acc_length = coef_len2;
  for (i = 0; i < in_len; i++) {
    data_ptr = in_ptr;
    coef_ptr = coef_start;
    acc = (long)(*coef_ptr++) * (*data_ptr--);
    for (j = 1; j < acc_length; j++)
      acc += (long)(*coef_ptr++) * (*data_ptr--);
    *out++ = (int)(acc / scale);
    if (in_ptr == in_end) {
      acc_length--;
      coef_start++;
    } else {
      if (acc_length < coef_len)
        acc_length++;
      in_ptr++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<fir_filter_int>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  lea    0x1(%r8),%rsi
  sar    %rsi
  lea    -0x8(%rdi,%rdx,8),%r13
  lea    -0x8(%rdi,%rsi,8),%r10
  test   %rdx,%rdx
  jle    L49
  mov    %rdx,%rbx
  mov    %rcx,%rdi
  mov    %r8,%r12
  mov    $0x0,%r11d
  jmp    L54
L42:
  sub    $0x1,%rsi
  mov    %r8,%rdi
L39:
  add    $0x1,%r11
  cmp    %r11,%rbx
  je     L49
L54:
  lea    0x8(%rdi),%r8
  lea    -0x8(%r10),%r14
  mov    (%rdi),%rax
  imul   (%r10),%rax
  cmp    $0x1,%rsi
  jle    L46
  mov    $0x1,%edx
L57:
  sub    $0x8,%r14
  mov    (%rdi,%rdx,8),%rcx
  imul   0x8(%r14),%rcx
  add    %rcx,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L57
L46:
  cqto
  idiv   %r9
  cltq
  mov    %rax,0x0(%rbp,%r11,8)
  cmp    %r10,%r13
  je     L42
  cmp    %rsi,%r12
  setg   %al
  movzbl %al,%eax
  add    %rax,%rsi
  add    $0x8,%r10
  jmp    L39
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void fir_filter_int(long *in, long *out, long in_len, long *coef, long coef_len, long scale) {
  long i, j, coef_len2, acc_length;
  long acc;
  long *in_ptr, *data_ptr, *coef_start, *coef_ptr, *in_end;
  coef_start = coef;
  coef_len2 = (coef_len + 1) >> 1;
  in_end = in + in_len - 1;
  in_ptr = in + coef_len2 - 1;
  acc_length = coef_len2;
  for (i = 0; i < in_len; i++) {
    data_ptr = in_ptr;
    coef_ptr = coef_start;
    acc = (long)(*coef_ptr++) * (*data_ptr--);
    for (j = 1; j < acc_length; j++)
      acc += (long)(*coef_ptr++) * (*data_ptr--);
    *out++ = (int)(acc / scale);
    if (in_ptr == in_end) {
      acc_length--;
      coef_start++;
    } else {
      if (acc_length < coef_len)
        acc_length++;
      in_ptr++;
    }
  }
}
```