ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<fts_alloc>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  lea    0x48(%r13),%rdx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%r14
  mov    (%rdi),%eax
  lea    0x53(%r13),%rdi
  and    (%r14),%eax
  cmovne %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  mov    0x38(%rax),%rdi
  lea    0x1(%r13),%edx
  mov    %r15,%rsi
  mov    %r13,%rbp
  call   <memmove@plt>
  mov    (%rbx),%eax
  and    (%r14),%eax
  je     L8
L2:
  mov    0x4(%rbx),%eax
  mov    %ebp,(%r12)
  movq   $0x0,0x28(%r12)
  mov    %eax,0x30(%r12)
  mov    D5(%rip),%rax
  movq   $0x0,0x20(%r12)
  movq   $0x0,0x10(%r12)
  mov    (%rax),%eax
  movq   $0x0,0x8(%r12)
  mov    %eax,0x18(%r12)
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    0x38(%r12),%r13
  lea    0x2(%r13),%rdi
  call   <ALIGN@plt>
  mov    %rax,0x40(%r12)
  jmp    L2
```

assistant: ```c
FTSENT *fts_alloc(FTS *sp, char *name, int namelen) {
  FTSENT *p;
  size_t len;
  len = sizeof(FTSENT) + namelen;
  if (!(sp->fts_options & (FTS_NOSTAT)))
    len += sizeof(struct stat) + 7;
  if ((p = malloc(len)) == NULL)
    return (NULL);
  memmove(p->fts_name, name, namelen + 1);
  if (!(sp->fts_options & (FTS_NOSTAT)))
    p->fts_statp = (struct stat *)ALIGN(p->fts_name + namelen + 2);
  p->fts_namelen = namelen;
  p->fts_path = sp->fts_path;
  p->fts_errno = 0;
  p->fts_flags = 0;
  p->fts_instr = FTS_NOINSTR;
  p->fts_number = 0;
  p->fts_pointer = NULL;
  return (p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fts_alloc>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  lea    0x48(%r13),%rdx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%r14
  mov    (%rdi),%eax
  lea    0x53(%r13),%rdi
  and    (%r14),%eax
  cmovne %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
  mov    0x38(%rax),%rdi
  lea    0x1(%r13),%edx
  mov    %r15,%rsi
  mov    %r13,%rbp
  call   <memmove@plt>
  mov    (%rbx),%eax
  and    (%r14),%eax
  je     L17
L11:
  mov    0x4(%rbx),%eax
  mov    %ebp,(%r12)
  pxor   %xmm0,%xmm0
  movq   $0x0,0x10(%r12)
  mov    %eax,0x30(%r12)
  mov    D4(%rip),%rax
  movq   $0x0,0x8(%r12)
  mov    (%rax),%eax
  movups %xmm0,0x20(%r12)
  mov    %eax,0x18(%r12)
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  add    0x38(%r12),%r13
  lea    0x2(%r13),%rdi
  call   <ALIGN@plt>
  mov    %rax,0x40(%r12)
  jmp    L11
```

assistant: ```c
FTSENT *fts_alloc(FTS *sp, char *name, int namelen) {
  FTSENT *p;
  size_t len;
  len = sizeof(FTSENT) + namelen;
  if (!(sp->fts_options & (FTS_NOSTAT)))
    len += sizeof(struct stat) + 7;
  if ((p = malloc(len)) == NULL)
    return (NULL);
  memmove(p->fts_name, name, namelen + 1);
  if (!(sp->fts_options & (FTS_NOSTAT)))
    p->fts_statp = (struct stat *)ALIGN(p->fts_name + namelen + 2);
  p->fts_namelen = namelen;
  p->fts_path = sp->fts_path;
  p->fts_errno = 0;
  p->fts_flags = 0;
  p->fts_instr = FTS_NOINSTR;
  p->fts_number = 0;
  p->fts_pointer = NULL;
  return (p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L8
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D11
datatype: string

tool: D15: %2i 

tool: 

assistant: ```c
void output(int *array, size_t len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%2i ", array[i]);
  }
  puts("");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L0
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D10(%rip),%r13
L19:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L19
L0:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_guessed: string
name: retrieve_data
arguments: data_tag: D15
type_guessed: string

tool: D10: %2i 

tool: 

assistant: ```c
void output(int *array, size_t len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%2i ", array[i]);
  }
  puts("");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output>:
  endbr64
  test   %rsi,%rsi
  je     L18
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L2
  add    $0x8,%rsp
  lea    D15(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  lea    D15(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D25: %2i 

tool: 

assistant: ```c
void output(int *array, size_t len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%2i ", array[i]);
  }
  puts("");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<output>:
  endbr64
  test   %rsi,%rsi
  je     L3
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L10
  add    $0x8,%rsp
  lea    D15(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  lea    D15(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string

tool: D14: %2i 

tool: 

assistant: ```c
void output(int *array, size_t len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%2i ", array[i]);
  }
  puts("");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_checkchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L72
  mov    $0x41,%eax
  jmp    L94
L72:
  cmpl   $0xb,-0x4(%rbp)
  jne    L62
  mov    $0x42,%eax
  jmp    L94
L62:
  cmpl   $0xc,-0x4(%rbp)
  jne    L76
  mov    $0x43,%eax
  jmp    L94
L76:
  cmpl   $0xd,-0x4(%rbp)
  jne    L111
  mov    $0x44,%eax
  jmp    L94
L111:
  cmpl   $0xe,-0x4(%rbp)
  jne    L103
  mov    $0x45,%eax
  jmp    L94
L103:
  cmpl   $0xf,-0x4(%rbp)
  jne    L119
  mov    $0x46,%eax
  jmp    L94
L119:
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
L94:
  pop    %rbp
  ret
```

assistant: ```c
char ft_checkchar(int n) {
  if (n == 10)
    return ('A');
  else if (n == 11)
    return ('B');
  else if (n == 12)
    return ('C');
  else if (n == 13)
    return ('D');
  else if (n == 14)
    return ('E');
  else if (n == 15)
    return ('F');
  else
    return (n + '0');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_checkchar>:
  endbr64
  lea    -0xa(%rdi),%eax
  cmp    $0x5,%eax
  ja     L7
  mov    %eax,%eax
  lea    D7(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x42,%eax
  ret
  mov    $0x43,%eax
  ret
  mov    $0x44,%eax
  ret
  mov    $0x45,%eax
  ret
  mov    $0x46,%eax
  ret
L7:
  lea    0x30(%rdi),%eax
  ret
  mov    $0x41,%eax
  ret
```

assistant: ```c
char ft_checkchar(int n) {
  if (n == 10)
    return ('A');
  else if (n == 11)
    return ('B');
  else if (n == 12)
    return ('C');
  else if (n == 13)
    return ('D');
  else if (n == 14)
    return ('E');
  else if (n == 15)
    return ('F');
  else
    return (n + '0');
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_checkchar>:
  endbr64
  lea    -0xa(%rdi),%edx
  lea    0x37(%rdi),%eax
  add    $0x30,%edi
  cmp    $0x5,%edx
  cmova  %edi,%eax
  ret
```

assistant: ```c
char ft_checkchar(int n) {
  if (n == 10)
    return ('A');
  else if (n == 11)
    return ('B');
  else if (n == 12)
    return ('C');
  else if (n == 13)
    return ('D');
  else if (n == 14)
    return ('E');
  else if (n == 15)
    return ('F');
  else
    return (n + '0');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_checkchar>:
  endbr64
  lea    -0xa(%rdi),%edx
  lea    0x37(%rdi),%eax
  add    $0x30,%edi
  cmp    $0x5,%edx
  cmova  %edi,%eax
  ret
```

assistant: ```c
char ft_checkchar(int n) {
  if (n == 10)
    return ('A');
  else if (n == 11)
    return ('B');
  else if (n == 12)
    return ('C');
  else if (n == 13)
    return ('D');
  else if (n == 14)
    return ('E');
  else if (n == 15)
    return ('F');
  else
    return (n + '0');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L28
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L28
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L28:
  addq   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strlwr(char *text) {
  char *origtext = text;
  while (*text != '\0') {
    if ((*text > 64) && (*text < 91))
      *text += 32;
    text++;
  }
  return (origtext);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlwr>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L44
  mov    %rdi,%rcx
  jmp    L21
L30:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L44
L21:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L30
  add    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L30
L44:
  ret
```

assistant: ```c
char *strlwr(char *text) {
  char *origtext = text;
  while (*text != '\0') {
    if ((*text > 64) && (*text < 91))
      *text += 32;
    text++;
  }
  return (origtext);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strlwr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L23
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L5:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L29
  add    $0x20,%edx
  mov    %dl,(%rcx)
L29:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L5
L23:
  ret
```

assistant: ```c
char *strlwr(char *text) {
  char *origtext = text;
  while (*text != '\0') {
    if ((*text > 64) && (*text < 91))
      *text += 32;
    text++;
  }
  return (origtext);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlwr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L27
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L31:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L36
  add    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L31
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L31
L27:
  ret
```

assistant: ```c
char *strlwr(char *text) {
  char *origtext = text;
  while (*text != '\0') {
    if ((*text > 64) && (*text < 91))
      *text += 32;
    text++;
  }
  return (origtext);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L13
  lea    -0xc(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L13:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int *f3(int x, int *y) {
  int w = 0;
  if (x)
    y = &w;
  return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f3>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rax
  test   %edi,%edi
  cmove  %rsi,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *f3(int x, int *y) {
  int w = 0;
  if (x)
    y = &w;
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f3>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  cmove  %rsi,%rax
  ret
```

assistant: ```c
int *f3(int x, int *y) {
  int w = 0;
  if (x)
    y = &w;
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f3>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  cmove  %rsi,%rax
  ret
```

assistant: ```c
int *f3(int x, int *y) {
  int w = 0;
  if (x)
    y = &w;
  return y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<free_imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x20(%rbp),%ebx
  jmp    L7
L6:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  sub    $0x1,%ebx
L7:
  cmp    -0x1c(%rbp),%ebx
  jge    L6
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void free_imatrix(m, nrl, nrh, ncl, nch) int **m;
int nrl, nrh, ncl, nch;
{
  register int i;
  for (i = nrh; i >= nrl; i--)
    free((char *)(m[i] + ncl));
  free((char *)(m + nrl));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_imatrix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r13d
  cmp    %esi,%edx
  jl     L4
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%rbp
  movslq %edx,%rax
  shl    $0x3,%rax
  lea    (%rdi,%rax,1),%rbx
  lea    -0x8(%rdi,%rax,1),%r12
  sub    %esi,%edx
  shl    $0x3,%rdx
  sub    %rdx,%r12
L16:
  mov    %rbp,%rdi
  add    (%rbx),%rdi
  call   <free@plt>
  sub    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L16
L4:
  movslq %r13d,%r13
  lea    (%r14,%r13,8),%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void free_imatrix(m, nrl, nrh, ncl, nch) int **m;
int nrl, nrh, ncl, nch;
{
  register int i;
  for (i = nrh; i >= nrl; i--)
    free((char *)(m[i] + ncl));
  free((char *)(m + nrl));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<free_imatrix>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %r13d,%edx
  jl     L15
  movslq %edx,%rax
  sub    %r13d,%edx
  movslq %ecx,%rcx
  shl    $0x3,%rax
  shl    $0x3,%rdx
  lea    0x0(,%rcx,4),%rbp
  lea    -0x8(%rdi,%rax,1),%r12
  lea    (%rdi,%rax,1),%rbx
  sub    %rdx,%r12
  nopl   0x0(%rax)
L18:
  mov    (%rbx),%rdi
  sub    $0x8,%rbx
  add    %rbp,%rdi
  call   <free@plt>
  cmp    %r12,%rbx
  jne    L18
L15:
  pop    %rbx
  lea    (%r14,%r13,8),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <free@plt>
```

assistant: ```c
void free_imatrix(m, nrl, nrh, ncl, nch) int **m;
int nrl, nrh, ncl, nch;
{
  register int i;
  for (i = nrh; i >= nrl; i--)
    free((char *)(m[i] + ncl));
  free((char *)(m + nrl));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_imatrix>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %r13d,%edx
  jl     L14
  movslq %edx,%rax
  sub    %r13d,%edx
  movslq %ecx,%rcx
  shl    $0x3,%rax
  shl    $0x3,%rdx
  lea    0x0(,%rcx,4),%rbp
  lea    -0x8(%rdi,%rax,1),%r12
  lea    (%rdi,%rax,1),%rbx
  sub    %rdx,%r12
  nopl   0x0(%rax)
L18:
  mov    (%rbx),%rdi
  sub    $0x8,%rbx
  add    %rbp,%rdi
  call   <free@plt>
  cmp    %r12,%rbx
  jne    L18
L14:
  pop    %rbx
  lea    (%r14,%r13,8),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <free@plt>
```

assistant: ```c
void free_imatrix(m, nrl, nrh, ncl, nch) int **m;
int nrl, nrh, ncl, nch;
{
  register int i;
  for (i = nrh; i >= nrl; i--)
    free((char *)(m[i] + ncl));
  free((char *)(m + nrl));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<incbig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L37
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x9,%eax
  jle    L13
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  sub    $0xa,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
L13:
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L8
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L24
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L24:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void incbig(int *x) {
  int a;
  x[x[0] + 1] = 0;
  x[1]++;
  for (a = 1; a <= x[0]; a++)
    if (x[a] >= 10) {
      x[a] -= 10;
      x[a + 1]++;
    }
  if (x[x[0] + 1])
    x[0]++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<incbig>:
  endbr64
  movslq (%rdi),%rax
  movl   $0x0,0x4(%rdi,%rax,4)
  addl   $0x1,0x4(%rdi)
  mov    (%rdi),%edx
  test   %edx,%edx
  jle    L28
  mov    $0x1,%eax
  jmp    L1
L40:
  mov    (%rdi),%edx
  add    $0x1,%rax
  cmp    %eax,%edx
  jl     L28
L1:
  mov    (%rdi,%rax,4),%edx
  cmp    $0x9,%edx
  jle    L40
  sub    $0xa,%edx
  mov    %edx,(%rdi,%rax,4)
  addl   $0x1,0x4(%rdi,%rax,4)
  jmp    L40
L28:
  movslq %edx,%rax
  cmpl   $0x0,0x4(%rdi,%rax,4)
  je     L54
  add    $0x1,%edx
  mov    %edx,(%rdi)
L54:
  ret
```

assistant: ```c
void incbig(int *x) {
  int a;
  x[x[0] + 1] = 0;
  x[1]++;
  for (a = 1; a <= x[0]; a++)
    if (x[a] >= 10) {
      x[a] -= 10;
      x[a + 1]++;
    }
  if (x[x[0] + 1])
    x[0]++;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<incbig>:
  endbr64
  movslq (%rdi),%rax
  movl   $0x0,0x4(%rdi,%rax,4)
  mov    (%rdi),%ecx
  addl   $0x1,0x4(%rdi)
  test   %ecx,%ecx
  jle    L2
  mov    $0x1,%eax
  xchg   %ax,%ax
L6:
  mov    (%rdi,%rax,4),%edx
  cmp    $0x9,%edx
  jle    L21
  sub    $0xa,%edx
  addl   $0x1,0x4(%rdi,%rax,4)
  mov    %edx,(%rdi,%rax,4)
  mov    (%rdi),%ecx
L21:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jge    L6
L2:
  add    $0x1,%ecx
  movslq %ecx,%rax
  mov    (%rdi,%rax,4),%eax
  test   %eax,%eax
  je     L23
  mov    %ecx,(%rdi)
L23:
  ret
```

assistant: ```c
void incbig(int *x) {
  int a;
  x[x[0] + 1] = 0;
  x[1]++;
  for (a = 1; a <= x[0]; a++)
    if (x[a] >= 10) {
      x[a] -= 10;
      x[a + 1]++;
    }
  if (x[x[0] + 1])
    x[0]++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<incbig>:
  endbr64
  movslq (%rdi),%rax
  movl   $0x0,0x4(%rdi,%rax,4)
  mov    (%rdi),%ecx
  addl   $0x1,0x4(%rdi)
  test   %ecx,%ecx
  jle    L23
  mov    $0x1,%eax
  xchg   %ax,%ax
L20:
  mov    (%rdi,%rax,4),%edx
  cmp    $0x9,%edx
  jle    L11
  sub    $0xa,%edx
  addl   $0x1,0x4(%rdi,%rax,4)
  mov    %edx,(%rdi,%rax,4)
  mov    (%rdi),%ecx
  add    $0x1,%rax
  cmp    %eax,%ecx
  jge    L20
L23:
  add    $0x1,%ecx
  movslq %ecx,%rax
  mov    (%rdi,%rax,4),%eax
  test   %eax,%eax
  je     L54
  mov    %ecx,(%rdi)
L54:
  ret
  nopl   (%rax)
L11:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jge    L20
  jmp    L23
```

assistant: ```c
void incbig(int *x) {
  int a;
  x[x[0] + 1] = 0;
  x[1]++;
  for (a = 1; a <= x[0]; a++)
    if (x[a] >= 10) {
      x[a] -= 10;
      x[a + 1]++;
    }
  if (x[x[0] + 1])
    x[0]++;
}
```