ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_command>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D19(%rip),%rsi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L11
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L19
  lea    D29(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,2),%eax
L29:
  pop    %rbx
  ret
L11:
  mov    $0x0,%eax
  jmp    L29
L19:
  mov    $0x1,%eax
  jmp    L29
```

tool_calls: name: parse_data
arguments: data_tag: D19
type: string
name: parse_data
arguments: data_tag: D28
type: string
name: parse_data
arguments: data_tag: D29
type: string

tool: D19: CONNECT

tool: D28: DISCONNECT

tool: D29: GETSECTOR

assistant: ```c
int check_command(char *p) {
  if (strstr(p, "CONNECT") == p) {
    return 0;
  }
  if (strstr(p, "DISCONNECT") == p) {
    return 1;
  }
  if (strstr(p, "GETSECTOR") == p) {
    return 2;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_command>:
  endbr64
  push   %rbp
  mov    $0x7,%edx
  lea    D13(%rip),%rsi
  mov    %rdi,%rbp
  call   <strncmp@plt>
  test   %eax,%eax
  je     L1
  mov    $0xa,%edx
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L16
  mov    $0x9,%edx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x3,%eax
  sub    $0x1,%eax
L1:
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
datatype: string
name: parse_data
arguments: data_tag: D25
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string

tool: D13: CONNECT

tool: D25: DISCONNECT

tool: D7: GETSECTOR

assistant: ```c
int check_command(char *p) {
  if (strstr(p, "CONNECT") == p) {
    return 0;
  }
  if (strstr(p, "DISCONNECT") == p) {
    return 1;
  }
  if (strstr(p, "GETSECTOR") == p) {
    return 2;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_command>:
  endbr64
  push   %rbp
  mov    $0x7,%edx
  lea    D15(%rip),%rsi
  mov    %rdi,%rbp
  call   <strncmp@plt>
  test   %eax,%eax
  je     L1
  mov    $0xa,%edx
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L19
  mov    $0x9,%edx
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x3,%eax
  sub    $0x1,%eax
L1:
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D15: CONNECT

tool: D8: DISCONNECT

tool: D17: GETSECTOR

assistant: ```c
int check_command(char *p) {
  if (strstr(p, "CONNECT") == p) {
    return 0;
  }
  if (strstr(p, "DISCONNECT") == p) {
    return 1;
  }
  if (strstr(p, "GETSECTOR") == p) {
    return 2;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<HeapSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  jmp    L18
L25:
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <HeapAdjust@plt>
  subl   $0x1,-0xc(%rbp)
L18:
  cmpl   $0x0,-0xc(%rbp)
  jns    L25
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L20
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <HeapAdjust@plt>
  subl   $0x1,-0xc(%rbp)
L20:
  cmpl   $0x0,-0xc(%rbp)
  jg     L6
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void HeapSort(int A[], int n) {
  int i = 0;
  for (i = n / 2; i >= 0; --i) {
    HeapAdjust(A, i, n);
  }
  int temp;
  for (i = n - 1; i > 0; --i) {
    swap(&A[0], &A[i], sizeof(int), &temp);
    HeapAdjust(A, 0, i - 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<HeapSort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  add    %esi,%ebp
  sar    %ebp
  cmp    $0xffffffff,%esi
  jl     L24
L2:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <HeapAdjust@plt>
  sub    $0x1,%ebp
  jns    L2
L24:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L34
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rbp
  lea    0x4(%rsp),%r13
L36:
  mov    %r13,%rcx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  sub    $0x1,%ebx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <HeapAdjust@plt>
  sub    $0x4,%rbp
  test   %ebx,%ebx
  jne    L36
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void HeapSort(int A[], int n) {
  int i = 0;
  for (i = n / 2; i >= 0; --i) {
    HeapAdjust(A, i, n);
  }
  int temp;
  for (i = n - 1; i > 0; --i) {
    swap(&A[0], &A[i], sizeof(int), &temp);
    HeapAdjust(A, 0, i - 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HeapSort>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  mov    %esi,%ebx
  add    %esi,%ebp
  sar    %ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0xffffffff,%esi
  jl     L37
  nopl   0x0(%rax)
L10:
  mov    %ebp,%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <HeapAdjust@plt>
  sub    $0x1,%ebp
  jae    L10
L37:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L15
  movslq %ebx,%rax
  lea    0x4(%rsp),%r13
  lea    (%r12,%rax,4),%rbp
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rsi
  mov    %r13,%rcx
  mov    $0x4,%edx
  mov    %r12,%rdi
  call   <swap@plt>
  sub    $0x1,%ebx
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %ebx,%edx
  sub    $0x4,%rbp
  call   <HeapAdjust@plt>
  test   %ebx,%ebx
  jne    L2
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void HeapSort(int A[], int n) {
  int i = 0;
  for (i = n / 2; i >= 0; --i) {
    HeapAdjust(A, i, n);
  }
  int temp;
  for (i = n - 1; i > 0; --i) {
    swap(&A[0], &A[i], sizeof(int), &temp);
    HeapAdjust(A, 0, i - 1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HeapSort>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  mov    %esi,%ebx
  add    %esi,%ebp
  sar    %ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0xffffffff,%esi
  jl     L9
  nopl   0x0(%rax)
L13:
  mov    %ebp,%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <HeapAdjust@plt>
  sub    $0x1,%ebp
  jae    L13
L9:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L0
  movslq %ebx,%rax
  lea    0x4(%rsp),%r13
  lea    (%r12,%rax,4),%rbp
  nopl   0x0(%rax)
L45:
  mov    %rbp,%rsi
  mov    %r13,%rcx
  mov    $0x4,%edx
  mov    %r12,%rdi
  call   <swap@plt>
  sub    $0x1,%ebx
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %ebx,%edx
  sub    $0x4,%rbp
  call   <HeapAdjust@plt>
  test   %ebx,%ebx
  jne    L45
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void HeapSort(int A[], int n) {
  int i = 0;
  for (i = n / 2; i >= 0; --i) {
    HeapAdjust(A, i, n);
  }
  int temp;
  for (i = n - 1; i > 0; --i) {
    swap(&A[0], &A[i], sizeof(int), &temp);
    HeapAdjust(A, 0, i - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<floord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  fldt   0x10(%rbp)
  fstpt  -0x20(%rbp)
  fldt   0x10(%rbp)
  fldz
  fcomip %st(1),%st
  fstp   %st(0)
  jbe    L84
  fldt   -0x20(%rbp)
  fchs
  fstpt  -0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%edx
  mov    %rax,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
L84:
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  sar    $0x14,%rax
  and    $0x7ff,%eax
  mov    %rax,-0x30(%rbp)
  subq   $0x3ff,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jns    L71
  fldt   0x10(%rbp)
  fldz
  fcomip %st(1),%st
  fstp   %st(0)
  jbe    L138
  fld1
  fchs
  jmp    L41
L138:
  fldz
L41:
  fstpt  -0x20(%rbp)
  fldt   -0x20(%rbp)
  jmp    L23
L71:
  cmpq   $0x34,-0x30(%rbp)
  jle    L40
  fldt   0x10(%rbp)
  jmp    L23
L40:
  mov    $0x34,%eax
  sub    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x1f,-0x28(%rbp)
  jle    L18
  subq   $0x20,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,%ecx
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  and    %rcx,%rdx
  mov    %rdx,(%rax)
  jmp    L136
L18:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,%eax
  and    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L136:
  fldt   0x10(%rbp)
  fldz
  fcomip %st(1),%st
  fstp   %st(0)
  jbe    L131
  fldt   -0x20(%rbp)
  fchs
  fstpt  -0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%edx
  mov    %rax,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  fldt   -0x20(%rbp)
  fldt   0x10(%rbp)
  fucomip %st(1),%st
  jp     L75
  fldt   0x10(%rbp)
  fucomip %st(1),%st
  fstp   %st(0)
  je     L131
  jmp    L2
L75:
  fstp   %st(0)
L2:
  fldt   -0x20(%rbp)
  fld1
  fsubrp %st,%st(1)
  fstpt  -0x20(%rbp)
L131:
  fldt   -0x20(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L58
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

assistant: ```c
long double floord(long double x) {
  long double y;
  long int exp;
  long int bitsToClear;
  long int *yPtr = (long int *)&y;
  y = x;
  if (x < 0.0) {
    y = -y;
  }
  exp = (yPtr[1] & 0x7ff00000) >> 20;
  exp = exp - 1023;
  if (exp < 0) {
    y = (x < 0.0) ? -1.0 : 0.0;
    return y;
  }
  if (exp > 52) {
    return x;
  }
  bitsToClear = 52 - exp;
  if (bitsToClear > 31) {
    bitsToClear = bitsToClear - 32;
    yPtr[0] = 0;
    yPtr[1] = yPtr[1] & (0xffffffff << bitsToClear);
  } else {
    yPtr[0] = yPtr[0] & (0xffffffff << bitsToClear);
  }
  if (x < 0.0) {
    y = -y;
    if (y != x) {
      y = ((long double)(y) - (long double)(1.0));
    }
  }
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floord>:
  endbr64
  sub    $0x38,%rsp
  fldt   0x40(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  fld    %st(0)
  fstpt  0x10(%rsp)
  fldz
  fcomip %st(1),%st
  ja     L112
  mov    0x18(%rsp),%rdx
  mov    %rdx,%rax
  sar    $0x14,%rax
  and    $0x7ff,%eax
  sub    $0x3ff,%rax
  js     L96
L157:
  fld    %st(0)
  cmp    $0x34,%rax
  jg     L147
  fstp   %st(0)
  mov    $0x34,%ecx
  sub    %rax,%rcx
  cmp    $0x1f,%rcx
  jle    L125
  movq   $0x0,0x10(%rsp)
  mov    $0x14,%ecx
  sub    %rax,%rcx
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  and    %rdx,%rax
  mov    %rax,0x18(%rsp)
L18:
  fldz
  fcomip %st(1),%st
  ja     L117
  fstp   %st(0)
L82:
  fldt   0x10(%rsp)
  jmp    L14
L147:
  fstp   %st(1)
L14:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x38,%rsp
  ret
L112:
  fld    %st(0)
  fchs
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  mov    %rax,0x10(%rsp)
  mov    %edx,0x18(%rsp)
  mov    0x18(%rsp),%rdx
  mov    %rdx,%rax
  sar    $0x14,%rax
  and    $0x7ff,%eax
  sub    $0x3ff,%rax
  jns    L157
  fstp   %st(0)
  fld1
  fchs
  jmp    L14
L96:
  fldz
  fcomi  %st(1),%st
  fstp   %st(1)
  jbe    L14
  fstp   %st(0)
  fld1
  fchs
  jmp    L14
L125:
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  and    %rax,0x10(%rsp)
  jmp    L18
L117:
  fldt   0x10(%rsp)
  fchs
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L113
  jne    L113
  fstpt  0x10(%rsp)
  jmp    L82
L113:
  fld1
  fsubrp %st,%st(1)
  fstpt  0x10(%rsp)
  jmp    L82
L78:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double floord(long double x) {
  long double y;
  long int exp;
  long int bitsToClear;
  long int *yPtr = (long int *)&y;
  y = x;
  if (x < 0.0) {
    y = -y;
  }
  exp = (yPtr[1] & 0x7ff00000) >> 20;
  exp = exp - 1023;
  if (exp < 0) {
    y = (x < 0.0) ? -1.0 : 0.0;
    return y;
  }
  if (exp > 52) {
    return x;
  }
  bitsToClear = 52 - exp;
  if (bitsToClear > 31) {
    bitsToClear = bitsToClear - 32;
    yPtr[0] = 0;
    yPtr[1] = yPtr[1] & (0xffffffff << bitsToClear);
  } else {
    yPtr[0] = yPtr[0] & (0xffffffff << bitsToClear);
  }
  if (x < 0.0) {
    y = -y;
    if (y != x) {
      y = ((long double)(y) - (long double)(1.0));
    }
  }
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<floord>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  fldt   0x40(%rsp)
  fld    %st(0)
  fstpt  0x10(%rsp)
  fldz
  fcomip %st(1),%st
  ja     L106
  fstp   %st(0)
  mov    0x48(%rsp),%rdx
  fldz
  mov    %rdx,%rax
  sar    $0x14,%rax
  and    $0x7ff,%eax
  sub    $0x3ff,%rax
  js     L116
  fstp   %st(0)
L78:
  fldt   0x40(%rsp)
  cmp    $0x34,%rax
  jg     L116
  fstp   %st(0)
  mov    $0x34,%ecx
  sub    %rax,%rcx
  cmp    $0x1f,%rcx
  jle    L92
  movq   $0x0,0x10(%rsp)
  mov    $0x14,%ecx
  sub    %rax,%rcx
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  and    %rdx,%rax
  mov    %rax,0x18(%rsp)
L49:
  fldt   0x10(%rsp)
  fldt   0x40(%rsp)
  fldz
  fcomip %st(1),%st
  ja     L50
  fstp   %st(0)
L116:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x38,%rsp
  ret
  xchg   %ax,%ax
L106:
  fchs
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,%rax
  sar    $0x14,%rax
  mov    %edx,0x18(%rsp)
  and    $0x7ff,%eax
  sub    $0x3ff,%rax
  jns    L78
  fld1
  fchs
  jmp    L116
  nopl   0x0(%rax)
L92:
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  and    %rax,0x10(%rsp)
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L50:
  fxch   %st(1)
  fchs
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L88
  je     L116
L88:
  fld1
  fsubrp %st,%st(1)
  jmp    L116
L76:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double floord(long double x) {
  long double y;
  long int exp;
  long int bitsToClear;
  long int *yPtr = (long int *)&y;
  y = x;
  if (x < 0.0) {
    y = -y;
  }
  exp = (yPtr[1] & 0x7ff00000) >> 20;
  exp = exp - 1023;
  if (exp < 0) {
    y = (x < 0.0) ? -1.0 : 0.0;
    return y;
  }
  if (exp > 52) {
    return x;
  }
  bitsToClear = 52 - exp;
  if (bitsToClear > 31) {
    bitsToClear = bitsToClear - 32;
    yPtr[0] = 0;
    yPtr[1] = yPtr[1] & (0xffffffff << bitsToClear);
  } else {
    yPtr[0] = yPtr[0] & (0xffffffff << bitsToClear);
  }
  if (x < 0.0) {
    y = -y;
    if (y != x) {
      y = ((long double)(y) - (long double)(1.0));
    }
  }
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<floord>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  fldt   0x40(%rsp)
  fld    %st(0)
  fstpt  0x10(%rsp)
  fldz
  fcomip %st(1),%st
  ja     L75
  fstp   %st(0)
  mov    0x48(%rsp),%rdx
  fldz
  mov    %rdx,%rax
  sar    $0x14,%rax
  and    $0x7ff,%eax
  sub    $0x3ff,%rax
  js     L114
  fstp   %st(0)
L119:
  fldt   0x40(%rsp)
  cmp    $0x34,%rax
  jg     L114
  fstp   %st(0)
  mov    $0x34,%ecx
  sub    %rax,%rcx
  cmp    $0x1f,%rcx
  jle    L60
  mov    $0x14,%ecx
  sub    %rax,%rcx
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  and    %rdx,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
L108:
  fldt   0x40(%rsp)
  fldz
  mov    %rax,0x10(%rsp)
  fcomip %st(1),%st
  fstp   %st(0)
  fldt   0x10(%rsp)
  ja     L67
L114:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L75:
  fchs
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,%rax
  sar    $0x14,%rax
  mov    %edx,0x18(%rsp)
  and    $0x7ff,%eax
  sub    $0x3ff,%rax
  jns    L119
  fld1
  fchs
  jmp    L114
  nopl   0x0(%rax)
L60:
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  and    0x10(%rsp),%rax
  jmp    L108
  cs nopw 0x0(%rax,%rax,1)
L67:
  fchs
  fldt   0x40(%rsp)
  fxch   %st(1)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L53
  je     L114
L53:
  fld1
  fsubrp %st,%st(1)
  jmp    L114
L26:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double floord(long double x) {
  long double y;
  long int exp;
  long int bitsToClear;
  long int *yPtr = (long int *)&y;
  y = x;
  if (x < 0.0) {
    y = -y;
  }
  exp = (yPtr[1] & 0x7ff00000) >> 20;
  exp = exp - 1023;
  if (exp < 0) {
    y = (x < 0.0) ? -1.0 : 0.0;
    return y;
  }
  if (exp > 52) {
    return x;
  }
  bitsToClear = 52 - exp;
  if (bitsToClear > 31) {
    bitsToClear = bitsToClear - 32;
    yPtr[0] = 0;
    yPtr[1] = yPtr[1] & (0xffffffff << bitsToClear);
  } else {
    yPtr[0] = yPtr[0] & (0xffffffff << bitsToClear);
  }
  if (x < 0.0) {
    y = -y;
    if (y != x) {
      y = ((long double)(y) - (long double)(1.0));
    }
  }
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<C_Ret>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <Inst_Printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <Inst_Printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D28
type: string
name: retrieve_data
arguments: data_label: D35
type: string

tool: 

tool: D28: ret

tool: D35: restore

assistant: ```c
void C_Ret(void) {
  Inst_Printf("ret", "");
  Inst_Printf("restore", "");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<C_Ret>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rbx
  mov    %rbx,%rsi
  lea    D21(%rip),%rdi
  call   <Inst_Printf@plt>
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <Inst_Printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: 

tool: D21: ret

tool: D9: restore

assistant: ```c
void C_Ret(void) {
  Inst_Printf("ret", "");
  Inst_Printf("restore", "");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<C_Ret>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rbp
  lea    D5(%rip),%rdi
  mov    %rbp,%rsi
  call   <Inst_Printf@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  pop    %rbp
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D5
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: 

tool: D5: ret

tool: D1: restore

assistant: ```c
void C_Ret(void) {
  Inst_Printf("ret", "");
  Inst_Printf("restore", "");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<C_Ret>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rbp
  lea    D29(%rip),%rdi
  mov    %rbp,%rsi
  call   <Inst_Printf@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  pop    %rbp
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: 

tool: D29: ret

tool: D0: restore

assistant: ```c
void C_Ret(void) {
  Inst_Printf("ret", "");
  Inst_Printf("restore", "");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writeBuffertoFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L1
L5:
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: wb+

assistant: ```c
int writeBuffertoFile(char *fileName, unsigned char *write_buffer, size_t length) {
  FILE *fp;
  fp = fopen(fileName, "wb+");
  if (fp == NULL)
    return -1;
  fwrite(write_buffer, 1, length, fp);
  fclose(fp);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<writeBuffertoFile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0xffffffff,%eax
  test   %rbx,%rbx
  je     L7
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: wb+

assistant: ```c
int writeBuffertoFile(char *fileName, unsigned char *write_buffer, size_t length) {
  FILE *fp;
  fp = fopen(fileName, "wb+");
  if (fp == NULL)
    return -1;
  fwrite(write_buffer, 1, length, fp);
  fclose(fp);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<writeBuffertoFile>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D1(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0xffffffff,%eax
  test   %rbp,%rbp
  je     L0
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L0:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: wb+

assistant: ```c
int writeBuffertoFile(char *fileName, unsigned char *write_buffer, size_t length) {
  FILE *fp;
  fp = fopen(fileName, "wb+");
  if (fp == NULL)
    return -1;
  fwrite(write_buffer, 1, length, fp);
  fclose(fp);
  return 1;
}
```