user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x19(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl -0x19(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x2f,%eax
  je     L16
  cmp    $0x2f,%eax
  jg     L40
  cmp    $0x2d,%eax
  je     L9
  cmp    $0x2d,%eax
  jg     L40
  cmp    $0x2a,%eax
  je     L24
  cmp    $0x2b,%eax
  jne    L40
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L91
L9:
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L91
L24:
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L91
L16:
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L91
L40:
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L91:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D67
data_type: string
name: unpack_data
arguments: label: D42
data_type: string
name: unpack_data
arguments: label: D26
data_type: string
name: unpack_data
arguments: label: D61
data_type: string
name: unpack_data
arguments: label: D69
data_type: string
name: unpack_data
arguments: label: D59
data_type: string
name: unpack_data
arguments: label: D33
data_type: string
name: unpack_data
arguments: label: D73
data_type: string
name: unpack_data
arguments: label: D81
data_type: string

tool: D67: Enter an operator (+, -, *,): 

tool: D42: %c

tool: D26: Enter two operands: 

tool: D61: %lf %lf

tool: D69: %.1lf + %.1lf = %.1lf


tool: D59: %.1lf - %.1lf = %.1lf


tool: D33: %.1lf * %.1lf = %.1lf


tool: D73: %.1lf / %.1lf = %.1lf


tool: D81: Error! operator is not correct

assistant: ```c
int main() {
  char op;
  double n1, n2;
  printf("Enter an operator (+, -, *,): ");
  scanf("%c", &op);
  printf("Enter two operands: ");
  scanf("%lf %lf", &n1, &n2);
  switch (op) {
  case '+':
    printf("%.1lf + %.1lf = %.1lf\n", n1, n2, n1 + n2);
    break;
  case '-':
    printf("%.1lf - %.1lf = %.1lf\n", n1, n2, n1 - n2);
    break;
  case '*':
    printf("%.1lf * %.1lf = %.1lf\n", n1, n2, n1 * n2);
    break;
  case '/':
    printf("%.1lf / %.1lf = %.1lf\n", n1, n2, n1 / n2);
    break;
  default:
    printf("Error! operator is not correct");
  }
  return 0;
}
```