ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<modbus_receive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int modbus_receive(uint8_t *addr, uint8_t *function, uint8_t *payload) {
  uint8_t len = 0;
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<modbus_receive>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int modbus_receive(uint8_t *addr, uint8_t *function, uint8_t *payload) {
  uint8_t len = 0;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<modbus_receive>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int modbus_receive(uint8_t *addr, uint8_t *function, uint8_t *payload) {
  uint8_t len = 0;
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<modbus_receive>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int modbus_receive(uint8_t *addr, uint8_t *function, uint8_t *payload) {
  uint8_t len = 0;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OnFwdEx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %dl,-0x4(%rbp)
  mov    %ecx,%edx
  mov    %dl,-0x8(%rbp)
  mov    %al,-0xc(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <Fwd@plt>
  cmpb   $0x81,-0x8(%rbp)
  je     L0
  movsbl -0x8(%rbp),%edx
  movzbl -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <SetPower@plt>
L0:
  movzbl -0xc(%rbp),%edx
  movzbl -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <OnEx@plt>
  nop
  leave
  ret
```

assistant: ```c
void OnFwdEx(unsigned char Outputs, char Power, unsigned char reset) {
  Fwd(Outputs);
  if (Power != -127)
    SetPower(Outputs, Power);
  OnEx(Outputs, reset);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OnFwdEx>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    %edx,%ebx
  movzbl %dil,%ebp
  mov    %ebp,%edi
  call   <Fwd@plt>
  cmp    $0x81,%r12b
  jne    L7
L8:
  movzbl %bl,%esi
  mov    %ebp,%edi
  call   <OnEx@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  movsbl %r12b,%esi
  mov    %ebp,%edi
  call   <SetPower@plt>
  jmp    L8
```

assistant: ```c
void OnFwdEx(unsigned char Outputs, char Power, unsigned char reset) {
  Fwd(Outputs);
  if (Power != -127)
    SetPower(Outputs, Power);
  OnEx(Outputs, reset);
}
```
user: Translate the below assembly code into C programming language:

```asm
<OnFwdEx>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  movzbl %dil,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %edx,%ebx
  call   <Fwd@plt>
  cmp    $0x81,%r12b
  je     L9
  movsbl %r12b,%esi
  mov    %ebp,%edi
  call   <SetPower@plt>
L9:
  movzbl %bl,%esi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <OnEx@plt>
```

assistant: ```c
void OnFwdEx(unsigned char Outputs, char Power, unsigned char reset) {
  Fwd(Outputs);
  if (Power != -127)
    SetPower(Outputs, Power);
  OnEx(Outputs, reset);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<OnFwdEx>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  movzbl %dil,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %edx,%ebx
  call   <Fwd@plt>
  cmp    $0x81,%r12b
  je     L1
  movsbl %r12b,%esi
  mov    %ebp,%edi
  call   <SetPower@plt>
L1:
  movzbl %bl,%esi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <OnEx@plt>
```

assistant: ```c
void OnFwdEx(unsigned char Outputs, char Power, unsigned char reset) {
  Fwd(Outputs);
  if (Power != -127)
    SetPower(Outputs, Power);
  OnEx(Outputs, reset);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initialize_standard_homotopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x34(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x1f4,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int initialize_standard_homotopy(int fixed_gamma, double regamma, double imgamma) {
  int fail, *b;
  double c[2];
  c[0] = regamma;
  c[1] = imgamma;
  fail = _ada_use_c2phc4c(500, &fixed_gamma, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initialize_standard_homotopy>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x1f4,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_standard_homotopy(int fixed_gamma, double regamma, double imgamma) {
  int fail, *b;
  double c[2];
  c[0] = regamma;
  c[1] = imgamma;
  fail = _ada_use_c2phc4c(500, &fixed_gamma, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<initialize_standard_homotopy>:
  endbr64
  sub    $0x38,%rsp
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0x1f4,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_standard_homotopy(int fixed_gamma, double regamma, double imgamma) {
  int fail, *b;
  double c[2];
  c[0] = regamma;
  c[1] = imgamma;
  fail = _ada_use_c2phc4c(500, &fixed_gamma, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<initialize_standard_homotopy>:
  endbr64
  sub    $0x38,%rsp
  unpcklpd %xmm1,%xmm0
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0x1f4,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_standard_homotopy(int fixed_gamma, double regamma, double imgamma) {
  int fail, *b;
  double c[2];
  c[0] = regamma;
  c[1] = imgamma;
  fail = _ada_use_c2phc4c(500, &fixed_gamma, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f@plt>
L5:
  jmp    L5
```

assistant: ```c
int main() {
  f();
  while (1) {
  x:
    15;
  }
  g();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
L6:
  jmp    L6
```

assistant: ```c
int main() {
  f();
  while (1) {
  x:
    15;
  }
  g();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
L1:
  jmp    L1
```

assistant: ```c
int main() {
  f();
  while (1) {
  x:
    15;
  }
  g();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
L6:
  jmp    L6
```

assistant: ```c
int main() {
  f();
  while (1) {
  x:
    15;
  }
  g();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_bzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_bzero(void *ptr, int size) {
  int index;
  index = 0;
  while (index < size) {
    ((char *)ptr)[index] = 0;
    ++index;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_bzero>:
  endbr64
  test   %esi,%esi
  jle    L2
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L12:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L12
L2:
  ret
```

assistant: ```c
void ft_bzero(void *ptr, int size) {
  int index;
  index = 0;
  while (index < size) {
    ((char *)ptr)[index] = 0;
    ++index;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_bzero>:
  endbr64
  test   %esi,%esi
  jle    L0
  movslq %esi,%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void ft_bzero(void *ptr, int size) {
  int index;
  index = 0;
  while (index < size) {
    ((char *)ptr)[index] = 0;
    ++index;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_bzero>:
  endbr64
  test   %esi,%esi
  jle    L9
  movslq %esi,%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void ft_bzero(void *ptr, int size) {
  int index;
  index = 0;
  while (index < size) {
    ((char *)ptr)[index] = 0;
    ++index;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strv_env_clean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L49
L47:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L45
L18:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    (%rdx),%rdx
  mov    %rdx,(%rax)
L45:
  addq   $0x8,-0x28(%rbp)
L49:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L47
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **strv_env_clean(char **l) {
  char **r, **ret;
  for (r = ret = l; *l; l++) {
    const char *equal;
    equal = strchr(*l, '=');
    if (equal && equal[1] == 0) {
      free(*l);
      continue;
    }
    *(r++) = *l;
  }
  *r = NULL;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strv_env_clean>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L2
  mov    %r12,%rbp
  mov    %r12,%rbx
  jmp    L43
L35:
  mov    (%rbx),%rax
  mov    %rax,0x0(%rbp)
  lea    0x8(%rbp),%rbp
L59:
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L55
L43:
  mov    $0x3d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L35
  cmpb   $0x0,0x1(%rax)
  jne    L35
  mov    (%rbx),%rdi
  call   <free@plt>
  jmp    L59
L2:
  mov    %r12,%rbp
L55:
  movq   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **strv_env_clean(char **l) {
  char **r, **ret;
  for (r = ret = l; *l; l++) {
    const char *equal;
    equal = strchr(*l, '=');
    if (equal && equal[1] == 0) {
      free(*l);
      continue;
    }
    *(r++) = *l;
  }
  *r = NULL;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strv_env_clean>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L27
  mov    %r12,%rbx
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L25:
  mov    (%rbx),%rax
  add    $0x8,%rbx
  add    $0x8,%rbp
  mov    %rax,-0x8(%rbp)
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L27
L54:
  mov    $0x3d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L25
  cmpb   $0x0,0x1(%rax)
  jne    L25
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L54
L27:
  movq   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **strv_env_clean(char **l) {
  char **r, **ret;
  for (r = ret = l; *l; l++) {
    const char *equal;
    equal = strchr(*l, '=');
    if (equal && equal[1] == 0) {
      free(*l);
      continue;
    }
    *(r++) = *l;
  }
  *r = NULL;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<strv_env_clean>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L47
  mov    %r12,%rbx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%rax
  add    $0x8,%rbx
  add    $0x8,%rbp
  mov    %rax,-0x8(%rbp)
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L47
L13:
  mov    $0x3d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  cmpb   $0x0,0x1(%rax)
  jne    L5
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L13
L47:
  movq   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **strv_env_clean(char **l) {
  char **r, **ret;
  for (r = ret = l; *l; l++) {
    const char *equal;
    equal = strchr(*l, '=');
    if (equal && equal[1] == 0) {
      free(*l);
      continue;
    }
    *(r++) = *l;
  }
  *r = NULL;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L41
L17:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L49
  lea    D22(%rip),%rsi
  jmp    L24
L49:
  lea    D6(%rip),%rsi
L24:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L19
  lea    D22(%rip),%rax
  jmp    L22
L19:
  lea    D38(%rip),%rax
L22:
  mov    -0x4(%rbp),%edi
  mov    %rsi,%rcx
  mov    %rax,%rdx
  mov    %edi,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L41:
  cmpl   $0x64,-0x4(%rbp)
  jle    L17
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D38
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: 

tool: D6: buzz

tool: D38: fizz 

tool: D8: %d - %s%s


assistant: ```c
int main(void) {
  int i;
  for (i = 1; i <= 100; i++) {
    printf("%d - %s%s\n", i, (i % 3 ? "" : "fizz "), (i % 5 ? "" : "buzz"));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D9(%rip),%rcx
  mov    %rcx,%rbp
  lea    D1(%rip),%r13
  lea    D26(%rip),%r12
  lea    D25(%rip),%r14
L18:
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  mov    %r13,%rdx
  cmovne %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L10
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  mov    %r14,%rcx
  cmovne %rbp,%rcx
  jmp    L18
L10:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D26
type_guessed: string
name: read_data
arguments: data_label: D25
type_guessed: string

tool: 

tool: D1: fizz 

tool: D26: %d - %s%s


tool: D25: buzz

assistant: ```c
int main(void) {
  int i;
  for (i = 1; i <= 100; i++) {
    printf("%d - %s%s\n", i, (i % 3 ? "" : "fizz "), (i % 5 ? "" : "buzz"));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  lea    D9(%rip),%rcx
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L0:
  imul   $0xcccccccd,%ebx,%eax
  mov    %r14,%rcx
  cmp    $0x33333333,%eax
  cmova  %rbp,%rcx
L16:
  imul   $0xaaaaaaab,%ebx,%eax
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  cmp    $0x55555555,%eax
  cmova  %rbp,%rdx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x65,%ebx
  jne    L0
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D21
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string

tool: 

tool: D0: buzz

tool: D21: %d - %s%s


tool: D17: fizz 

assistant: ```c
int main(void) {
  int i;
  for (i = 1; i <= 100; i++) {
    printf("%d - %s%s\n", i, (i % 3 ? "" : "fizz "), (i % 5 ? "" : "buzz"));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  lea    D38(%rip),%rcx
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L14:
  imul   $0xcccccccd,%ebx,%eax
  mov    %r14,%rcx
  cmp    $0x33333333,%eax
  cmova  %rbp,%rcx
L12:
  imul   $0xaaaaaaab,%ebx,%eax
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  cmp    $0x55555555,%eax
  cmova  %rbp,%rdx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x65,%ebx
  jne    L14
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D38
type_infered: string
name: parse_data
arguments: data_label: D22
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: string

tool: 

tool: D22: buzz

tool: D13: %d - %s%s


tool: D4: fizz 

assistant: ```c
int main(void) {
  int i;
  for (i = 1; i <= 100; i++) {
    printf("%d - %s%s\n", i, (i % 3 ? "" : "fizz "), (i % 5 ? "" : "buzz"));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x5,%edi
  jne    L36
  mov    %rsi,%r12
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    0x8(%r12),%rdi
  lea    D28(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L78
  mov    0x10(%r12),%rdi
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r14
  mov    0x18(%r12),%rdi
  cmpb   $0x30,(%rdi)
  jne    L26
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  je     L129
L26:
  call   <atoi@plt>
  mov    %eax,%ebp
L104:
  mov    0x20(%r12),%rdi
  cmpb   $0x30,(%rdi)
  jne    L19
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  je     L105
L19:
  call   <atoi@plt>
  mov    %eax,%r13d
L127:
  mov    %r13d,%edx
  mov    %ebp,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%r12
  jmp    L113
L129:
  add    $0x2,%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%ebp
  jmp    L104
L105:
  add    $0x2,%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%r13d
  jmp    L127
L59:
  mov    %rbx,%rdi
  call   <ftell@plt>
  mov    %rbx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  xor    %ebp,0x4(%rsp)
  add    %r13d,%ebp
  mov    %r14,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
L113:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L59
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L49:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L67
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  mov    $0xffffffff,%eax
  jmp    L49
L78:
  mov    $0xffffffff,%eax
  jmp    L49
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type: string
name: retrieve_data
arguments: data_tag: D3
type: string
name: retrieve_data
arguments: data_tag: D27
type: string

tool: D28: rb+

tool: D3: wb

tool: D27: Base : %08X
Seed : %08X


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 5)
    return -1;
  srand(time(NULL));
  FILE *pf = fopen(argv[1], "rb+");
  if (!pf)
    return -1;
  FILE *out = fopen(argv[2], "wb");
  unsigned int base;
  if (argv[3][0] == '0' && (argv[3][1] == 'x' || argv[3][1] == 'X'))
    base = strtol(argv[3] + 2, NULL, 16);
  else
    base = atoi(argv[3]);
  unsigned int seed;
  if (argv[4][0] == '0' && (argv[4][1] == 'x' || argv[4][1] == 'X'))
    seed = strtol(argv[4] + 2, NULL, 16);
  else
    seed = atoi(argv[4]);
  printf("Base : %08X\nSeed : %08X\n", base, seed);
  while (!feof(pf)) {
    unsigned int cur = ftell(pf);
    unsigned int word;
    fread(&word, 1, 4, pf);
    word ^= base;
    base += seed;
    fwrite(&word, 1, 4, out);
  }
  fclose(pf);
  return 0;
}
```