ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inputGraph>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    D65(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L17
  mov    $0x0,%ebx
  lea    D28(%rip),%r15
  lea    D12(%rip),%r12
  lea    D14(%rip),%r14
  lea    D26(%rip),%r13
L24:
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%ecx
  movslq %esi,%rax
  lea    (%rax,%rax,4),%rdx
  lea    0x0(%rbp,%rdx,4),%rdi
  movslq %ecx,%rdx
  movl   $0x1,(%rdi,%rdx,4)
  lea    (%rdx,%rdx,4),%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
  movl   $0x1,(%rdx,%rax,4)
  mov    %ecx,%edx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L24
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
datatype: string
name: extract_symbolic_data
arguments: data_label: D65
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D14
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: string

tool: D25: 
	Inputting Edges: 

tool: D65: 	How many edges do you wish to add? ans = 

tool: D12: %d

tool: D28: 	%d.
	Node 1: 

tool: D14: 	Node 2: 

tool: D26: 	Edge (%d,%d) added.



assistant: ```c
void inputGraph(int g[5][5]) {
  printf("\n\tInputting Edges: \n");
  printf("\tHow many edges do you wish to add? ans = ");
  int numberOfEdges = 0;
  scanf("%d", &numberOfEdges);
  int i;
  int a, b;
  for (i = 0; i < numberOfEdges; i++) {
    printf("\t%d.\n\tNode 1: ", i);
    scanf("%d", &a);
    printf("\tNode 2: ");
    scanf("%d", &b);
    g[a][b] = 1;
    g[b][a] = 1;
    printf("\tEdge (%d,%d) added.\n\n", a, b);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<inputGraph>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D57(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D36(%rip),%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  movl   $0x0,0x1c(%rsp)
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L27
  lea    0x24(%rsp),%rax
  xor    %r12d,%r12d
  lea    D35(%rip),%r15
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%r14
  lea    D39(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r12d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0x20(%rsp),%rax
  mov    0x24(%rsp),%r8d
  lea    (%rax,%rax,4),%rdx
  mov    %rax,%rsi
  lea    (%rbx,%rdx,4),%rdi
  movslq %r8d,%rdx
  movl   $0x1,(%rdi,%rdx,4)
  lea    (%rdx,%rdx,4),%rdx
  lea    D42(%rip),%rdi
  lea    (%rbx,%rdx,4),%rdx
  movl   $0x1,(%rdx,%rax,4)
  mov    %r8d,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12d,0x1c(%rsp)
  jg     L12
L27:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D57
type_infered: string
name: extract_symbolic_data
arguments: data_label: D36
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D35
type_infered: string
name: extract_symbolic_data
arguments: data_label: D39
type_infered: string
name: extract_symbolic_data
arguments: data_label: D42
type_infered: string

tool: D57: %d

tool: D36: 
	Inputting Edges: 

tool: D6: 	How many edges do you wish to add? ans = 

tool: D35: 	%d.
	Node 1: 

tool: D39: 	Node 2: 

tool: D42: 	Edge (%d,%d) added.



assistant: ```c
void inputGraph(int g[5][5]) {
  printf("\n\tInputting Edges: \n");
  printf("\tHow many edges do you wish to add? ans = ");
  int numberOfEdges = 0;
  scanf("%d", &numberOfEdges);
  int i;
  int a, b;
  for (i = 0; i < numberOfEdges; i++) {
    printf("\t%d.\n\tNode 1: ", i);
    scanf("%d", &a);
    printf("\tNode 2: ");
    scanf("%d", &b);
    g[a][b] = 1;
    g[b][a] = 1;
    printf("\tEdge (%d,%d) added.\n\n", a, b);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inputGraph>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D53(%rip),%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  movl   $0x0,0x1c(%rsp)
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L3
  lea    0x24(%rsp),%rax
  xor    %r12d,%r12d
  lea    D49(%rip),%r15
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%r14
  lea    D19(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r12d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0x20(%rsp),%rax
  mov    0x24(%rsp),%r8d
  lea    (%rax,%rax,4),%rdx
  mov    %rax,%rsi
  lea    (%rbx,%rdx,4),%rdi
  movslq %r8d,%rdx
  movl   $0x1,(%rdi,%rdx,4)
  lea    (%rdx,%rdx,4),%rdx
  lea    D32(%rip),%rdi
  lea    (%rbx,%rdx,4),%rdx
  movl   $0x1,(%rdx,%rax,4)
  mov    %r8d,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12d,0x1c(%rsp)
  jg     L22
L3:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D53
datatype: string
name: retrieve_data
arguments: label: D44
datatype: string
name: retrieve_data
arguments: label: D49
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string
name: retrieve_data
arguments: label: D32
datatype: string

tool: D11: %d

tool: D53: 
	Inputting Edges: 

tool: D44: 	How many edges do you wish to add? ans = 

tool: D49: 	%d.
	Node 1: 

tool: D19: 	Node 2: 

tool: D32: 	Edge (%d,%d) added.



assistant: ```c
void inputGraph(int g[5][5]) {
  printf("\n\tInputting Edges: \n");
  printf("\tHow many edges do you wish to add? ans = ");
  int numberOfEdges = 0;
  scanf("%d", &numberOfEdges);
  int i;
  int a, b;
  for (i = 0; i < numberOfEdges; i++) {
    printf("\t%d.\n\tNode 1: ", i);
    scanf("%d", &a);
    printf("\tNode 2: ");
    scanf("%d", &b);
    g[a][b] = 1;
    g[b][a] = 1;
    printf("\tEdge (%d,%d) added.\n\n", a, b);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_sockaddr_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_host@plt>
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    $0x4,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_port@plt>
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void make_sockaddr_in(const char *host, const char *port, struct sockaddr_in *sa) {
  memset(sa, 0, sizeof *sa);
  sa->sin_family = AF_INET;
  memcpy(&sa->sin_addr, parse_host(host), 4);
  sa->sin_port = htons(parse_port(port));
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_sockaddr_in>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  mov    %r12,%rdi
  call   <parse_host@plt>
  mov    %eax,%esi
  lea    0x4(%rbx),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <parse_port@plt>
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void make_sockaddr_in(const char *host, const char *port, struct sockaddr_in *sa) {
  memset(sa, 0, sizeof *sa);
  sa->sin_family = AF_INET;
  memcpy(&sa->sin_addr, parse_host(host), 4);
  sa->sin_port = htons(parse_port(port));
}
```
user: What is the c source code of the assembly code below:

```asm
<make_sockaddr_in>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  mov    $0xc,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    D2(%rip),%rax
  mov    %r12,%rdi
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  call   <parse_host@plt>
  lea    0x4(%rbx),%rdi
  mov    $0x4,%edx
  mov    %eax,%esi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <parse_port@plt>
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void make_sockaddr_in(const char *host, const char *port, struct sockaddr_in *sa) {
  memset(sa, 0, sizeof *sa);
  sa->sin_family = AF_INET;
  memcpy(&sa->sin_addr, parse_host(host), 4);
  sa->sin_port = htons(parse_port(port));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<make_sockaddr_in>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  mov    $0xc,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    D6(%rip),%rax
  mov    %r12,%rdi
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  call   <parse_host@plt>
  lea    0x4(%rbx),%rdi
  mov    $0x4,%edx
  mov    %eax,%esi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <parse_port@plt>
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void make_sockaddr_in(const char *host, const char *port, struct sockaddr_in *sa) {
  memset(sa, 0, sizeof *sa);
  sa->sin_family = AF_INET;
  memcpy(&sa->sin_addr, parse_host(host), 4);
  sa->sin_port = htons(parse_port(port));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sweep_set_standard_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x30(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x26a,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int sweep_set_standard_start(int n, double *c) {
  int fail, ptos[2];
  ptos[0] = 0;
  ptos[1] = 0;
  fail = _ada_use_c2phc(618, ptos, &n, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sweep_set_standard_start>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    $0x26a,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sweep_set_standard_start(int n, double *c) {
  int fail, ptos[2];
  ptos[0] = 0;
  ptos[1] = 0;
  fail = _ada_use_c2phc(618, ptos, &n, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sweep_set_standard_start>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%rcx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    $0x26a,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sweep_set_standard_start(int n, double *c) {
  int fail, ptos[2];
  ptos[0] = 0;
  ptos[1] = 0;
  fail = _ada_use_c2phc(618, ptos, &n, c);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sweep_set_standard_start>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%rcx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    $0x26a,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sweep_set_standard_start(int n, double *c) {
  int fail, ptos[2];
  ptos[0] = 0;
  ptos[1] = 0;
  fail = _ada_use_c2phc(618, ptos, &n, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<affirm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L67
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L67
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L67:
  movl   $0x0,-0x4(%rbp)
  jmp    L242
L235:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L117
L213:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
L117:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L213
  cmpl   $0x79,-0x8(%rbp)
  je     L56
  cmpl   $0x59,-0x8(%rbp)
  jne    L248
L56:
  movl   $0x1,-0x4(%rbp)
  jmp    L242
L248:
  cmpl   $0x6e,-0x8(%rbp)
  je     L33
  cmpl   $0x4e,-0x8(%rbp)
  jne    L145
L33:
  movl   $0x2,-0x4(%rbp)
  jmp    L242
L145:
  cmpl   $0x71,-0x8(%rbp)
  je     L203
  cmpl   $0x51,-0x8(%rbp)
  jne    L219
L203:
  movl   $0x3,-0x4(%rbp)
  jmp    L242
L219:
  cmpl   $0x78,-0x8(%rbp)
  je     L179
  cmpl   $0x58,-0x8(%rbp)
  jne    L57
L179:
  movl   $0x3,-0x4(%rbp)
  jmp    L242
L57:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L208
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L208
L100:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
L208:
  cmpl   $0xa,-0x8(%rbp)
  jne    L100
L242:
  cmpl   $0x0,-0x4(%rbp)
  je     L235
  cmpl   $0x2,-0x4(%rbp)
  jle    L176
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <bail@plt>
  jmp    L45
L176:
  cmpl   $0x2,-0x4(%rbp)
  jne    L45
  mov    $0x0,%eax
  jmp    L157
L45:
  mov    $0x1,%eax
L157:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D26
type_infered: string

tool: D2: %s? 

tool: D26: Valid responses begin with: y Y n N q Q x X

assistant: ```c
int affirm(char *prompt) {
  int reply;
  int done;
  void bail(char *msg, int status);
  if (prompt != NULL && (int)strlen(prompt) > 0) {
    printf("%s? ", prompt);
  }
  done = 0;
  while (!done) {
    reply = getchar();
    while (isspace(reply)) {
      reply = getchar();
    }
    if (reply == 'y' || reply == 'Y') {
      done = 1;
    } else if (reply == 'n' || reply == 'N') {
      done = 2;
    } else if (reply == 'q' || reply == 'Q') {
      done = 3;
    } else if (reply == 'x' || reply == 'X') {
      done = 3;
    } else {
      printf("Valid responses begin with: y Y n N q Q x X\n");
      if (prompt != NULL) {
        printf("%s? ", prompt);
      }
      while (reply != '\n') {
        reply = getchar();
      }
    }
  }
  if (done > 2) {
    bail(NULL, 0);
  } else if (done == 2) {
    return (0);
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<affirm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L117
  call   <strlen@plt>
  test   %eax,%eax
  jg     L93
L117:
  lea    D29(%rip),%r15
  lea    D2(%rip),%r14
  movabs $0x40800000408,%r12
  movabs $0x80000000800,%r13
L37:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  jmp    L116
L93:
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L117
L99:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
L116:
  mov    %ebx,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L99
  lea    -0x4e(%rbx),%ecx
  cmp    $0x2b,%ecx
  ja     L29
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %r12,%rax
  jne    L54
  test   %r13,%rax
  jne    L104
  movabs $0x100000001,%rdx
  test   %rdx,%rax
  jne    L89
  mov    %r14,%rdi
  call   <puts@plt>
  test   %rbp,%rbp
  je     L145
L58:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L30:
  cmp    $0xa,%ebx
  je     L37
L145:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L145
  jmp    L37
L29:
  mov    %r14,%rdi
  call   <puts@plt>
  test   %rbp,%rbp
  jne    L58
  jmp    L30
L54:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <bail@plt>
  mov    $0x1,%eax
  jmp    L79
L104:
  mov    $0x1,%eax
L2:
  cmp    $0x2,%eax
  setne  %al
  movzbl %al,%eax
L79:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L89:
  mov    $0x2,%eax
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D29: %s? 

tool: D2: Valid responses begin with: y Y n N q Q x X

assistant: ```c
int affirm(char *prompt) {
  int reply;
  int done;
  void bail(char *msg, int status);
  if (prompt != NULL && (int)strlen(prompt) > 0) {
    printf("%s? ", prompt);
  }
  done = 0;
  while (!done) {
    reply = getchar();
    while (isspace(reply)) {
      reply = getchar();
    }
    if (reply == 'y' || reply == 'Y') {
      done = 1;
    } else if (reply == 'n' || reply == 'N') {
      done = 2;
    } else if (reply == 'q' || reply == 'Q') {
      done = 3;
    } else if (reply == 'x' || reply == 'X') {
      done = 3;
    } else {
      printf("Valid responses begin with: y Y n N q Q x X\n");
      if (prompt != NULL) {
        printf("%s? ", prompt);
      }
      while (reply != '\n') {
        reply = getchar();
      }
    }
  }
  if (done > 2) {
    bail(NULL, 0);
  } else if (done == 2) {
    return (0);
  }
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<affirm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L42
  call   <strlen@plt>
  test   %eax,%eax
  jg     L151
L42:
  lea    D28(%rip),%r15
  lea    D3(%rip),%r14
  movabs $0x40800000408,%r12
  movabs $0x100000001,%r13
  nopl   0x0(%rax)
L157:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L157
  mov    %ebx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x59,%eax
  je     L122
  lea    -0x4e(%rbx),%ecx
  cmp    $0x2a,%ecx
  ja     L120
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %r12,%rax
  jne    L82
  test   %r13,%rax
  jne    L112
  mov    %r14,%rdi
  call   <puts@plt>
  test   %rbp,%rbp
  je     L18
L164:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L44:
  cmp    $0xa,%ebx
  je     L157
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L157
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L18
  jmp    L157
  nopw   0x0(%rax,%rax,1)
L151:
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L42
L82:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <bail@plt>
  mov    $0x1,%eax
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L112:
  xor    %eax,%eax
  jmp    L32
L122:
  mov    $0x1,%eax
  jmp    L32
L120:
  mov    %r14,%rdi
  call   <puts@plt>
  test   %rbp,%rbp
  jne    L164
  jmp    L44
```

tool_calls: name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string

tool: D28: %s? 

tool: D3: Valid responses begin with: y Y n N q Q x X

assistant: ```c
int affirm(char *prompt) {
  int reply;
  int done;
  void bail(char *msg, int status);
  if (prompt != NULL && (int)strlen(prompt) > 0) {
    printf("%s? ", prompt);
  }
  done = 0;
  while (!done) {
    reply = getchar();
    while (isspace(reply)) {
      reply = getchar();
    }
    if (reply == 'y' || reply == 'Y') {
      done = 1;
    } else if (reply == 'n' || reply == 'N') {
      done = 2;
    } else if (reply == 'q' || reply == 'Q') {
      done = 3;
    } else if (reply == 'x' || reply == 'X') {
      done = 3;
    } else {
      printf("Valid responses begin with: y Y n N q Q x X\n");
      if (prompt != NULL) {
        printf("%s? ", prompt);
      }
      while (reply != '\n') {
        reply = getchar();
      }
    }
  }
  if (done > 2) {
    bail(NULL, 0);
  } else if (done == 2) {
    return (0);
  }
  return (1);
}
```