user: 这段汇编代码用C语言表示是什么样的:

```asm
<find_magic>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc000(%rsp),%r11
L66:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L66
  sub    $0x38,%rsp
  mov    %edx,0x14(%rsp)
  mov    %edi,%ebx
  mov    %esi,%r15d
  mov    %rcx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0xc028(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L52
  call   <bmask@plt>
  mov    %eax,0x4(%rsp)
L156:
  mov    0x4(%rsp),%edi
  mov    $0x1,%r14d
  call   <count_1s@plt>
  mov    %eax,%ecx
  mov    %eax,0x10(%rsp)
  shl    %cl,%r14d
  test   %r14d,%r14d
  jle    L148
  movslq %r14d,%rax
  xor    %r12d,%r12d
  lea    0x20(%rsp),%rbp
  mov    %rax,0x8(%rsp)
  lea    0x4020(%rsp),%r13
  jmp    L151
L12:
  call   <batt@plt>
  mov    %eax,0x0(%r13,%r12,4)
  add    $0x1,%r12
  cmp    %r12,0x8(%rsp)
  je     L148
L151:
  mov    0x10(%rsp),%esi
  mov    0x4(%rsp),%edx
  mov    %r12d,%edi
  call   <index_to_uint64_t@plt>
  mov    %ebx,%edi
  mov    %eax,0x0(%rbp,%r12,4)
  mov    %eax,%esi
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L12
  call   <ratt@plt>
  mov    %eax,0x0(%r13,%r12,4)
  add    $0x1,%r12
  cmp    %r12,0x8(%rsp)
  jne    L151
L148:
  lea    0x8020(%rsp),%rax
  movl   $0x5f5e100,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L38:
  subl   $0x1,0x4(%rsp)
  je     L159
L24:
  xor    %eax,%eax
  call   <random_uint64_t_fewbits@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <count_1s@plt>
  cmp    $0x5,%eax
  jle    L38
  mov    0x8(%rsp),%rdi
  xor    %esi,%esi
  mov    $0x4000,%edx
  call   <memset@plt>
  test   %r14d,%r14d
  jle    L92
  xor    %ebx,%ebx
  lea    0x20(%rsp),%rbp
  lea    0x4020(%rsp),%r13
  jmp    L100
  nopl   0x0(%rax,%rax,1)
L183:
  mov    0x0(%r13,%rbx,4),%edx
  mov    %edx,0x8020(%rsp,%rax,4)
  lea    0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    %r14d,%eax
  jge    L92
L100:
  mov    0x0(%rbp,%rbx,4),%edi
  mov    %r15d,%edx
  mov    %r12d,%esi
  call   <transform@plt>
  cltq
  mov    0x8020(%rsp,%rax,4),%edx
  test   %edx,%edx
  je     L183
  cmp    0x0(%r13,%rbx,4),%edx
  jne    L38
  lea    0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    %r14d,%eax
  jl     L100
L92:
  mov    0x8(%rsp),%rsi
  mov    0x18(%rsp),%rdi
  mov    $0x4000,%edx
  call   <memcpy@plt>
L86:
  mov    0xc028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xc038,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  call   <rmask@plt>
  mov    %eax,0x4(%rsp)
  jmp    L156
L159:
  lea    D8(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L86
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string

tool: D8: ***Failed***


assistant: ```c
uint64_t find_magic(int sq, int m, int bishop, uint64_t *attacks) {
  uint64_t mask, b[4096], a[4096], used[4096], magic;
  int i, j, k, n, mbits, fail;
  mask = bishop ? bmask(sq) : rmask(sq);
  n = count_1s(mask);
  for (i = 0; i < (1 << n); i++) {
    b[i] = index_to_uint64_t(i, n, mask);
    a[i] = bishop ? batt(sq, b[i]) : ratt(sq, b[i]);
  }
  for (k = 0; k < 100000000; k++) {
    magic = random_uint64_t_fewbits();
    if (count_1s((mask * magic) & 0xFF00000000000000ULL) < 6)
      continue;
    for (i = 0; i < 4096; i++)
      used[i] = 0ULL;
    for (i = 0, fail = 0; !fail && i < (1 << n); i++) {
      j = transform(b[i], magic, m);
      if (used[j] == 0ULL)
        used[j] = a[i];
      else if (used[j] != a[i])
        fail = 1;
    }
    if (!fail) {
      memcpy(attacks, used, sizeof(used));
      return magic;
    }
  }
  printf("***Failed***\n");
  return 0ULL;
}
```