ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  lea    D12(%rip),%rbp
  lea    D26(%rip),%r13
  mov    %rbp,%rdi
  lea    D2(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    D0(%rip),%rbp
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <read_search_path@plt>
  jmp    L14
  nopl   (%rax)
L17:
  mov    %rbx,%rdi
  call   <system@plt>
L14:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1000,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  movb   $0x0,0xfff(%rsp)
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L17
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x1018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D26
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D24
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string

tool: D12: ***************************************

tool: D26: Scan or type code: 

tool: D2: %4095s

tool: D24: HINSHISTU Manufacturing Private Limited

tool: D0: exit

assistant: ```c
int main(int argc, char **argv) {
  char buffer[4096];
  printf("***************************************\n");
  printf("HINSHISTU Manufacturing Private Limited\n");
  printf("***************************************\n");
  printf("\n");
  printf("\n");
  read_search_path();
  while (1) {
    printf("Scan or type code: ");
    memset(buffer, 0, 4096);
    scanf("%4095s", buffer);
    buffer[4095] = '\0';
    printf("\n");
    printf("\n");
    printf("%s\n", buffer);
    if (strcmp("exit", buffer) == 0) {
      return 0;
    }
    system(buffer);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  lea    D22(%rip),%rbp
  lea    D41(%rip),%r13
  mov    %rbp,%rdi
  lea    D48(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <puts@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    D2(%rip),%rbp
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <read_search_path@plt>
  jmp    L5
  nopl   (%rax)
L19:
  mov    %rbx,%rdi
  call   <system@plt>
L5:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1000,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  movb   $0x0,0xfff(%rsp)
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x1018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D22
datatype: string
name: parse_data
arguments: tag: D41
datatype: string
name: parse_data
arguments: tag: D48
datatype: string
name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D2
datatype: string

tool: D22: ***************************************

tool: D41: Scan or type code: 

tool: D48: %4095s

tool: D18: HINSHISTU Manufacturing Private Limited

tool: D2: exit

assistant: ```c
int main(int argc, char **argv) {
  char buffer[4096];
  printf("***************************************\n");
  printf("HINSHISTU Manufacturing Private Limited\n");
  printf("***************************************\n");
  printf("\n");
  printf("\n");
  read_search_path();
  while (1) {
    printf("Scan or type code: ");
    memset(buffer, 0, 4096);
    scanf("%4095s", buffer);
    buffer[4095] = '\0';
    printf("\n");
    printf("\n");
    printf("%s\n", buffer);
    if (strcmp("exit", buffer) == 0) {
      return 0;
    }
    system(buffer);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x8(%rbp)
  jmp    L25
L9:
  movl   $0x2,-0x4(%rbp)
  jmp    L39
L30:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0x13,-0x4(%rbp)
  jle    L30
  addl   $0x1,-0x8(%rbp)
L25:
  cmpl   $0x13,-0x8(%rbp)
  jle    L9
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string

tool: D5: gcd(%d, %d) = %d


assistant: ```c
int main() {
  for (int i = 2; i < 20; ++i) {
    for (int j = 2; j < 20; ++j) {
      printf("gcd(%d, %d) = %d\n", i, j, gcd(i, j));
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2,%ebp
  lea    D3(%rip),%r12
L6:
  mov    $0x2,%ebx
L10:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <gcd@plt>
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L10
  add    $0x1,%ebp
  cmp    $0x14,%ebp
  jne    L6
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: gcd(%d, %d) = %d


assistant: ```c
int main() {
  for (int i = 2; i < 20; ++i) {
    for (int j = 2; j < 20; ++j) {
      printf("gcd(%d, %d) = %d\n", i, j, gcd(i, j));
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
  nopl   0x0(%rax)
L2:
  mov    $0x2,%ebx
  nopl   (%rax)
L14:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <gcd@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x14,%ebx
  jne    L14
  add    $0x1,%ebp
  cmp    $0x14,%ebp
  jne    L2
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string

tool: D9: gcd(%d, %d) = %d


assistant: ```c
int main() {
  for (int i = 2; i < 20; ++i) {
    for (int j = 2; j < 20; ++j) {
      printf("gcd(%d, %d) = %d\n", i, j, gcd(i, j));
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
  nopl   0x0(%rax)
L5:
  mov    $0x2,%ebx
  nopl   (%rax)
L9:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <gcd@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x14,%ebx
  jne    L9
  add    $0x1,%ebp
  cmp    $0x14,%ebp
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: gcd(%d, %d) = %d


assistant: ```c
int main() {
  for (int i = 2; i < 20; ++i) {
    for (int j = 2; j < 20; ++j) {
      printf("gcd(%d, %d) = %d\n", i, j, gcd(i, j));
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void func(char **argv) {
  char arr[2];
  strcpy(arr, argv[1]);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x8(%rdi),%rsi
  lea    0x6(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void func(char **argv) {
  char arr[2];
  strcpy(arr, argv[1]);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<func>:
  endbr64
  sub    $0x18,%rsp
  mov    0x8(%rdi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void func(char **argv) {
  char arr[2];
  strcpy(arr, argv[1]);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func>:
  endbr64
  sub    $0x18,%rsp
  mov    0x8(%rdi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void func(char **argv) {
  char arr[2];
  strcpy(arr, argv[1]);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L11:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L27:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L11
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string

tool: D17: Enter am integer: 

tool: D2: %i

tool: D7: The sum of the digits in your number is: %i


assistant: ```c
int main(void) {
  int input, popped, sum;
  printf("Enter am integer: ");
  scanf("%i", &input);
  sum = 0;
  while (input > 0) {
    popped = input % 10;
    sum += popped;
    input /= 10;
  }
  printf("The sum of the digits in your number is: %i\n", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L29
  mov    $0x0,%esi
L2:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%edi
  sub    %ecx,%edi
  add    %edi,%esi
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L2
  mov    %eax,0x4(%rsp)
L38:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L29:
  mov    $0x0,%esi
  jmp    L38
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
data_type: string
name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D23
data_type: string

tool: D14: Enter am integer: 

tool: D2: %i

tool: D23: The sum of the digits in your number is: %i


assistant: ```c
int main(void) {
  int input, popped, sum;
  printf("Enter am integer: ");
  scanf("%i", &input);
  sum = 0;
  while (input > 0) {
    popped = input % 10;
    sum += popped;
    input /= 10;
  }
  printf("The sum of the digits in your number is: %i\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %esi,%esi
  test   %edx,%edx
  jle    L10
  mov    $0xcccccccd,%r8d
  nopl   (%rax)
L0:
  mov    %edx,%eax
  mov    %edx,%edi
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  mov    %edx,%ecx
  mov    %eax,%edx
  add    %edi,%esi
  cmp    $0x9,%ecx
  jg     L0
  mov    %eax,0x4(%rsp)
L10:
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D29
type_infered: string
name: parse_data
arguments: data_label: D23
type_infered: string
name: parse_data
arguments: data_label: D21
type_infered: string

tool: D29: Enter am integer: 

tool: D23: %i

tool: D21: The sum of the digits in your number is: %i


assistant: ```c
int main(void) {
  int input, popped, sum;
  printf("Enter am integer: ");
  scanf("%i", &input);
  sum = 0;
  while (input > 0) {
    popped = input % 10;
    sum += popped;
    input /= 10;
  }
  printf("The sum of the digits in your number is: %i\n", sum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %esi,%esi
  test   %edx,%edx
  jle    L26
  mov    $0xcccccccd,%r8d
  nopl   (%rax)
L9:
  mov    %edx,%eax
  mov    %edx,%edi
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  mov    %edx,%ecx
  mov    %eax,%edx
  add    %edi,%esi
  cmp    $0x9,%ecx
  jg     L9
  mov    %eax,0x4(%rsp)
L26:
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string
name: unpack_data
arguments: label: D26
data_type: string
name: unpack_data
arguments: label: D5
data_type: string

tool: D9: Enter am integer: 

tool: D26: %i

tool: D5: The sum of the digits in your number is: %i


assistant: ```c
int main(void) {
  int input, popped, sum;
  printf("Enter am integer: ");
  scanf("%i", &input);
  sum = 0;
  while (input > 0) {
    popped = input % 10;
    sum += popped;
    input /= 10;
  }
  printf("The sum of the digits in your number is: %i\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x20,-0x8(%rbp)
  movl   $0xd4,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <f_to_c@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <f_to_c@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D3: 32 in F is %g in C


tool: D2: 212 in F is %g in C


assistant: ```c
int main(void) {
  int freezing = 32;
  int boiling = 212;
  printf("32 in F is %g in C\n", f_to_c(freezing));
  printf("212 in F is %g in C\n", f_to_c(boiling));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20,%edi
  call   <f_to_c@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xd4,%edi
  call   <f_to_c@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string
name: read_data
arguments: data_label: D9
data_type: string

tool: D1: 32 in F is %g in C


tool: D9: 212 in F is %g in C


assistant: ```c
int main(void) {
  int freezing = 32;
  int boiling = 212;
  printf("32 in F is %g in C\n", f_to_c(freezing));
  printf("212 in F is %g in C\n", f_to_c(boiling));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20,%edi
  call   <f_to_c@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0xd4,%edi
  call   <f_to_c@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D17: 32 in F is %g in C


tool: D1: 212 in F is %g in C


assistant: ```c
int main(void) {
  int freezing = 32;
  int boiling = 212;
  printf("32 in F is %g in C\n", f_to_c(freezing));
  printf("212 in F is %g in C\n", f_to_c(boiling));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20,%edi
  call   <f_to_c@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xd4,%edi
  call   <f_to_c@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D15
type: string

tool: D3: 32 in F is %g in C


tool: D15: 212 in F is %g in C


assistant: ```c
int main(void) {
  int freezing = 32;
  int boiling = 212;
  printf("32 in F is %g in C\n", f_to_c(freezing));
  printf("212 in F is %g in C\n", f_to_c(boiling));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<msm_serial_set_mnd_regs_tcxo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x28,%edx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <msm_write@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x2c,%edx
  mov    $0xf1,%esi
  mov    %rax,%rdi
  call   <msm_write@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x30,%edx
  mov    $0xf,%esi
  mov    %rax,%rdi
  call   <msm_write@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x34,%edx
  mov    $0x1a,%esi
  mov    %rax,%rdi
  call   <msm_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void msm_serial_set_mnd_regs_tcxo(struct uart_port *port) {
  msm_write(port, 0x06, 0x0028);
  msm_write(port, 0xF1, 0x002C);
  msm_write(port, 0x0F, 0x0030);
  msm_write(port, 0x1A, 0x0034);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<msm_serial_set_mnd_regs_tcxo>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x28,%edx
  mov    $0x6,%esi
  call   <msm_write@plt>
  mov    $0x2c,%edx
  mov    $0xf1,%esi
  mov    %rbx,%rdi
  call   <msm_write@plt>
  mov    $0x30,%edx
  mov    $0xf,%esi
  mov    %rbx,%rdi
  call   <msm_write@plt>
  mov    $0x34,%edx
  mov    $0x1a,%esi
  mov    %rbx,%rdi
  call   <msm_write@plt>
  pop    %rbx
  ret
```

assistant: ```c
void msm_serial_set_mnd_regs_tcxo(struct uart_port *port) {
  msm_write(port, 0x06, 0x0028);
  msm_write(port, 0xF1, 0x002C);
  msm_write(port, 0x0F, 0x0030);
  msm_write(port, 0x1A, 0x0034);
}
```
user: Translate the below assembly code into C programming language:

```asm
<msm_serial_set_mnd_regs_tcxo>:
  endbr64
  push   %rbp
  mov    $0x28,%edx
  mov    %rdi,%rbp
  mov    $0x6,%esi
  call   <msm_write@plt>
  mov    %rbp,%rdi
  mov    $0x2c,%edx
  mov    $0xf1,%esi
  call   <msm_write@plt>
  mov    %rbp,%rdi
  mov    $0x30,%edx
  mov    $0xf,%esi
  call   <msm_write@plt>
  mov    %rbp,%rdi
  mov    $0x34,%edx
  pop    %rbp
  mov    $0x1a,%esi
  jmp    1050 <msm_write@plt>
```

assistant: ```c
void msm_serial_set_mnd_regs_tcxo(struct uart_port *port) {
  msm_write(port, 0x06, 0x0028);
  msm_write(port, 0xF1, 0x002C);
  msm_write(port, 0x0F, 0x0030);
  msm_write(port, 0x1A, 0x0034);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<msm_serial_set_mnd_regs_tcxo>:
  endbr64
  push   %rbp
  mov    $0x28,%edx
  mov    %rdi,%rbp
  mov    $0x6,%esi
  call   <msm_write@plt>
  mov    %rbp,%rdi
  mov    $0x2c,%edx
  mov    $0xf1,%esi
  call   <msm_write@plt>
  mov    %rbp,%rdi
  mov    $0x30,%edx
  mov    $0xf,%esi
  call   <msm_write@plt>
  mov    %rbp,%rdi
  mov    $0x34,%edx
  pop    %rbp
  mov    $0x1a,%esi
  jmp    1050 <msm_write@plt>
```

assistant: ```c
void msm_serial_set_mnd_regs_tcxo(struct uart_port *port) {
  msm_write(port, 0x06, 0x0028);
  msm_write(port, 0xF1, 0x002C);
  msm_write(port, 0x0F, 0x0030);
  msm_write(port, 0x1A, 0x0034);
}
```