ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_commas_double>:
  endbr64
  push   %r14
  pxor   %xmm1,%xmm1
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x578,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x568(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <double_virtually_same@plt>
  movsd  0x8(%rsp),%xmm0
  test   %rax,%rax
  je     L94
  pxor   %xmm0,%xmm0
L94:
  lea    0x20(%rsp),%rbx
  mov    $0x1,%eax
  lea    0x18(%rsp),%r12
  lea    0xe0(%rsp),%r13
  lea    D14(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  xor    %ecx,%ecx
  mov    %r13,%rdx
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <piece@plt>
  mov    $0x1,%ecx
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x2e,%esi
  call   <piece@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rbx,%rax
  jb     L36
  lea    0xa0(%rsp),%r9
  xor    %r8d,%r8d
  lea    0x1f(%rsp),%rdi
  mov    %r9,%rdx
  jmp    L27
  nopl   (%rax)
L88:
  sub    $0x1,%rax
  mov    %rsi,%rdx
  cmp    %rdi,%rax
  je     L0
L27:
  movzbl (%rax),%ecx
  lea    0x1(%rdx),%rsi
  mov    %cl,(%rdx)
  cmp    %rbx,%rax
  jbe    L88
  cmpb   $0x2d,-0x1(%rax)
  je     L88
  add    $0x1,%r8d
  imul   $0xaaaaaaab,%r8d,%ecx
  cmp    $0x55555555,%ecx
  ja     L88
  sub    $0x1,%rax
  movb   $0x2c,0x1(%rdx)
  add    $0x2,%rdx
  cmp    %rdi,%rax
  jne    L27
  nopl   0x0(%rax)
L0:
  movb   $0x0,(%rdx)
  lea    0x60(%rsp),%r14
  mov    %r9,%rsi
  lea    0x160(%rsp),%r13
  mov    %r14,%rdi
  call   <reverse_string@plt>
  mov    %r14,%rdx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %r12,%rcx
  lea    D9(%rip),%rsi
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    0x568(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x578,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L36:
  lea    0xa0(%rsp),%r9
  mov    %r9,%rdx
  jmp    L0
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string

tool: D14: %.3lf

tool: D9: %s.%s

assistant: ```c
char *string_commas_double(double d) {
  char integer_part[64];
  char buffer[64];
  char decimal_part[8];
  char d_string[128];
  char reversed_integer[64];
  char *reversed_integer_pointer = reversed_integer;
  char *integer_part_pointer;
  int counter = 0;
  char destination[1024];
  if (double_virtually_same(d, 0.0))
    d = 0.0;
  sprintf(d_string, "%.3lf", d);
  piece(integer_part, '.', d_string, 0);
  piece(decimal_part, '.', d_string, 1);
  integer_part_pointer = integer_part + strlen(integer_part) - 1;
  while (integer_part_pointer >= integer_part) {
    *reversed_integer_pointer++ = *integer_part_pointer;
    if (integer_part_pointer > integer_part && *(integer_part_pointer - 1) != '-') {
      if (!(++counter % 3)) {
        if (integer_part_pointer != integer_part) {
          *reversed_integer_pointer++ = ',';
        }
      }
    }
    integer_part_pointer--;
  }
  *reversed_integer_pointer = '\0';
  reverse_string(buffer, reversed_integer);
  sprintf(destination, "%s.%s", buffer, decimal_part);
  return strdup(destination);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<concat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L5
L11:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *concat(str1, str2)
char *str1, *str2;
{
  char *newstr;
  int str1_length = strlen(str1);
  newstr = malloc(str1_length + strlen(str2) + 1);
  if (newstr == 0)
    return 0;
  strcpy(newstr, str1);
  strcpy(newstr + str1_length, str2);
  return newstr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<concat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  call   <strlen@plt>
  movslq %eax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *concat(str1, str2)
char *str1, *str2;
{
  char *newstr;
  int str1_length = strlen(str1);
  newstr = malloc(str1_length + strlen(str2) + 1);
  if (newstr == 0)
    return 0;
  strcpy(newstr, str1);
  strcpy(newstr + str1_length, str2);
  return newstr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<concat>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r14
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r13
  lea    0x0(%r13,%r14,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  lea    0x1(%rbx),%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%r14,1),%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *concat(str1, str2)
char *str1, *str2;
{
  char *newstr;
  int str1_length = strlen(str1);
  newstr = malloc(str1_length + strlen(str2) + 1);
  if (newstr == 0)
    return 0;
  strcpy(newstr, str1);
  strcpy(newstr + str1_length, str2);
  return newstr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r14
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r13
  lea    0x0(%r13,%r14,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  lea    0x1(%rbx),%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%r14,1),%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *concat(str1, str2)
char *str1, *str2;
{
  char *newstr;
  int str1_length = strlen(str1);
  newstr = malloc(str1_length + strlen(str2) + 1);
  if (newstr == 0)
    return 0;
  strcpy(newstr, str1);
  strcpy(newstr + str1_length, str2);
  return newstr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x3210,-0x1c(%rbp)
  movl   $0x76543210,-0x18(%rbp)
  movl   $0x76543210,-0x14(%rbp)
  movl   $0xfedcba98,-0x10(%rbp)
  mov    $0x20,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_bswap16@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  bswap  %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_bswap64@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%esi
  mov    -0xc(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: Argc = %i
Argv[0] = %s
Result 16bit = %u
Result 32bit = %lu
Result 64bit = %llu


assistant: ```c
int main(int argc, char **argv) {
  uint16_t var16bit;
  uint32_t var32bit;
  uint64_t var64bit;
  uint64_t tmp;
  uint16_t var16bitResult;
  uint32_t var32bitResult;
  uint64_t var64bitResult;
  var16bit = 0x3210;
  var32bit = 0x76543210L;
  var64bit = 0x76543210L;
  tmp = 0xFEDCBA98L;
  var64bit = var64bit | (tmp << 32);
  var16bitResult = __builtin_bswap16(var16bit);
  var32bitResult = __builtin_bswap32(var32bit);
  var64bitResult = __builtin_bswap64(var64bit);
  printf("Argc = %i\nArgv[0] = %s\nResult 16bit = %"
         "u"
         "\nResult 32bit = %"
         "lu"
         "\nResult 64bit = %"
         "llu"
         "\n",
         argc, argv[0], var16bitResult, var32bitResult, var64bitResult);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x3210,%edi
  call   <__builtin_bswap16@plt>
  mov    %eax,%r12d
  mov    $0x76543210,%edi
  call   <__builtin_bswap64@plt>
  mov    %eax,%r9d
  mov    $0x10325476,%r8d
  mov    %r12d,%ecx
  mov    0x0(%rbp),%rdx
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: Argc = %i
Argv[0] = %s
Result 16bit = %u
Result 32bit = %lu
Result 64bit = %llu


assistant: ```c
int main(int argc, char **argv) {
  uint16_t var16bit;
  uint32_t var32bit;
  uint64_t var64bit;
  uint64_t tmp;
  uint16_t var16bitResult;
  uint32_t var32bitResult;
  uint64_t var64bitResult;
  var16bit = 0x3210;
  var32bit = 0x76543210L;
  var64bit = 0x76543210L;
  tmp = 0xFEDCBA98L;
  var64bit = var64bit | (tmp << 32);
  var16bitResult = __builtin_bswap16(var16bit);
  var32bitResult = __builtin_bswap32(var32bit);
  var64bitResult = __builtin_bswap64(var64bit);
  printf("Argc = %i\nArgv[0] = %s\nResult 16bit = %"
         "u"
         "\nResult 32bit = %"
         "lu"
         "\nResult 64bit = %"
         "llu"
         "\n",
         argc, argv[0], var16bitResult, var32bitResult, var64bitResult);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x3210,%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <__builtin_bswap16@plt>
  mov    $0x76543210,%edi
  mov    %eax,%r12d
  call   <__builtin_bswap64@plt>
  mov    (%rbx),%rdx
  mov    %r12d,%ecx
  mov    %ebp,%esi
  mov    %eax,%r9d
  mov    $0x10325476,%r8d
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string

tool: D1: Argc = %i
Argv[0] = %s
Result 16bit = %u
Result 32bit = %lu
Result 64bit = %llu


assistant: ```c
int main(int argc, char **argv) {
  uint16_t var16bit;
  uint32_t var32bit;
  uint64_t var64bit;
  uint64_t tmp;
  uint16_t var16bitResult;
  uint32_t var32bitResult;
  uint64_t var64bitResult;
  var16bit = 0x3210;
  var32bit = 0x76543210L;
  var64bit = 0x76543210L;
  tmp = 0xFEDCBA98L;
  var64bit = var64bit | (tmp << 32);
  var16bitResult = __builtin_bswap16(var16bit);
  var32bitResult = __builtin_bswap32(var32bit);
  var64bitResult = __builtin_bswap64(var64bit);
  printf("Argc = %i\nArgv[0] = %s\nResult 16bit = %"
         "u"
         "\nResult 32bit = %"
         "lu"
         "\nResult 64bit = %"
         "llu"
         "\n",
         argc, argv[0], var16bitResult, var32bitResult, var64bitResult);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x3210,%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <__builtin_bswap16@plt>
  mov    $0x76543210,%edi
  mov    %eax,%r12d
  call   <__builtin_bswap64@plt>
  mov    (%rbx),%rdx
  mov    %r12d,%ecx
  mov    %ebp,%esi
  mov    %eax,%r9d
  mov    $0x10325476,%r8d
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string

tool: D5: Argc = %i
Argv[0] = %s
Result 16bit = %u
Result 32bit = %lu
Result 64bit = %llu


assistant: ```c
int main(int argc, char **argv) {
  uint16_t var16bit;
  uint32_t var32bit;
  uint64_t var64bit;
  uint64_t tmp;
  uint16_t var16bitResult;
  uint32_t var32bitResult;
  uint64_t var64bitResult;
  var16bit = 0x3210;
  var32bit = 0x76543210L;
  var64bit = 0x76543210L;
  tmp = 0xFEDCBA98L;
  var64bit = var64bit | (tmp << 32);
  var16bitResult = __builtin_bswap16(var16bit);
  var32bitResult = __builtin_bswap32(var32bit);
  var64bitResult = __builtin_bswap64(var64bit);
  printf("Argc = %i\nArgv[0] = %s\nResult 16bit = %"
         "u"
         "\nResult 32bit = %"
         "lu"
         "\nResult 64bit = %"
         "llu"
         "\n",
         argc, argv[0], var16bitResult, var32bitResult, var64bitResult);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expr_is_valid_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L23
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L75
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jne    L75
  mov    $0x0,%eax
  jmp    L23
L75:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,-0x10(%rbp)
  jmp    L68
L48:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L57
  mov    $0x0,%eax
  jmp    L23
L57:
  addq   $0x1,-0x10(%rbp)
L68:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L48
  mov    $0x1,%eax
L23:
  leave
  ret
```

assistant: ```c
int expr_is_valid_number(const char *num, const size_t num_size) {
  const char *np, *np_end;
  if (num == NULL) {
    return 0;
  }
  np = num;
  np_end = np + num_size;
  if (*np == '-' && (np + 1) == np_end) {
    return 0;
  }
  np += (*np == '-');
  while (np != np_end) {
    if (!isdigit(*np)) {
      return 0;
    }
    np++;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expr_is_valid_number>:
  endbr64
  test   %rdi,%rdi
  je     L59
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rbp
  cmpb   $0x2d,(%rdi)
  je     L67
  cmp    %rbp,%rdi
  je     L27
L21:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L54
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L21
  mov    $0x1,%eax
L54:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L21
  mov    $0x0,%eax
  jmp    L54
L59:
  mov    $0x0,%eax
  ret
L27:
  mov    $0x1,%eax
  jmp    L54
```

assistant: ```c
int expr_is_valid_number(const char *num, const size_t num_size) {
  const char *np, *np_end;
  if (num == NULL) {
    return 0;
  }
  np = num;
  np_end = np + num_size;
  if (*np == '-' && (np + 1) == np_end) {
    return 0;
  }
  np += (*np == '-');
  while (np != np_end) {
    if (!isdigit(*np)) {
      return 0;
    }
    np++;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<expr_is_valid_number>:
  endbr64
  test   %rdi,%rdi
  je     L69
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  cmp    $0x2d,%dil
  je     L42
  cmp    %rbp,%rbx
  jne    L30
L28:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L64:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L28
  movsbl (%rbx),%edi
L30:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L64
L43:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L42:
  lea    0x1(%rbx),%rax
  cmp    %rbp,%rax
  je     L43
  movsbl 0x1(%rbx),%edi
  mov    %rax,%rbx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  ret
```

assistant: ```c
int expr_is_valid_number(const char *num, const size_t num_size) {
  const char *np, *np_end;
  if (num == NULL) {
    return 0;
  }
  np = num;
  np_end = np + num_size;
  if (*np == '-' && (np + 1) == np_end) {
    return 0;
  }
  np += (*np == '-');
  while (np != np_end) {
    if (!isdigit(*np)) {
      return 0;
    }
    np++;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<expr_is_valid_number>:
  endbr64
  test   %rdi,%rdi
  je     L26
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x2d,(%rdi)
  je     L23
  cmp    %rbp,%rdi
  jne    L12
L62:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L62
L12:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L1
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L23:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int expr_is_valid_number(const char *num, const size_t num_size) {
  const char *np, *np_end;
  if (num == NULL) {
    return 0;
  }
  np = num;
  np_end = np + num_size;
  if (*np == '-' && (np + 1) == np_end) {
    return 0;
  }
  np += (*np == '-');
  while (np != np_end) {
    if (!isdigit(*np)) {
      return 0;
    }
    np++;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xffffff28,-0x4(%rbp)
  je     L30
  cmpl   $0xffffff7c,-0x4(%rbp)
  je     L30
  cmpl   $0xffffff26,-0x4(%rbp)
  je     L30
  cmpl   $0xffffff6e,-0x4(%rbp)
  jne    L43
L30:
  mov    $0x1,%eax
  jmp    L24
L43:
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo(int x) {
  if (x == -216 || x == -132 || x == -218 || x == -146)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xffffff7c,%edi
  je     L8
  lea    0xda(%rdi),%eax
  test   $0xfffffffd,%eax
  sete   %al
  cmp    $0xffffff6e,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo(int x) {
  if (x == -216 || x == -132 || x == -218 || x == -146)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xffffff7c,%edi
  je     L8
  lea    0xda(%rdi),%eax
  and    $0xfffffffd,%eax
  sete   %al
  cmp    $0xffffff6e,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo(int x) {
  if (x == -216 || x == -132 || x == -218 || x == -146)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xffffff7c,%edi
  je     L7
  lea    0xda(%rdi),%eax
  and    $0xfffffffd,%eax
  sete   %al
  cmp    $0xffffff6e,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo(int x) {
  if (x == -216 || x == -132 || x == -218 || x == -146)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kfVecCross>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void kfVecCross(float *r, float *v1, float *v2, int dims) {
  r[0] = v1[1] * v2[2] - v1[2] * v2[1];
  r[1] = v1[2] * v2[0] - v1[0] * v2[2];
  r[2] = v1[0] * v2[1] - v1[1] * v2[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kfVecCross>:
  endbr64
  movss  0x4(%rsi),%xmm0
  mulss  0x8(%rdx),%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  0x8(%rsi),%xmm0
  mulss  (%rdx),%xmm0
  movss  (%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  (%rsi),%xmm0
  mulss  0x4(%rdx),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void kfVecCross(float *r, float *v1, float *v2, int dims) {
  r[0] = v1[1] * v2[2] - v1[2] * v2[1];
  r[1] = v1[2] * v2[0] - v1[0] * v2[2];
  r[2] = v1[0] * v2[1] - v1[1] * v2[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kfVecCross>:
  endbr64
  movss  0x4(%rsi),%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm0
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  0x8(%rsi),%xmm0
  movss  (%rsi),%xmm1
  mulss  (%rdx),%xmm0
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm0
  mulss  (%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void kfVecCross(float *r, float *v1, float *v2, int dims) {
  r[0] = v1[1] * v2[2] - v1[2] * v2[1];
  r[1] = v1[2] * v2[0] - v1[0] * v2[2];
  r[2] = v1[0] * v2[1] - v1[1] * v2[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kfVecCross>:
  endbr64
  movss  0x4(%rsi),%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm0
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  0x8(%rsi),%xmm0
  movss  (%rsi),%xmm1
  mulss  (%rdx),%xmm0
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm0
  mulss  (%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void kfVecCross(float *r, float *v1, float *v2, int dims) {
  r[0] = v1[1] * v2[2] - v1[2] * v2[1];
  r[1] = v1[2] * v2[0] - v1[0] * v2[2];
  r[2] = v1[0] * v2[1] - v1[1] * v2[0];
}
```