ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0xb45,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  lea    -0x6d68(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        } else {
          state[local1] += state[local1];
        }
      } else if (state[0UL] < local1) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      } else {
        state[0UL] -= state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 844337816UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x6223,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        } else {
          state[local1] += state[local1];
        }
      } else if (state[0UL] < local1) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      } else {
        state[0UL] -= state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 844337816UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x6223,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        } else {
          state[local1] += state[local1];
        }
      } else if (state[0UL] < local1) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      } else {
        state[0UL] -= state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 844337816UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x6223,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        } else {
          state[local1] += state[local1];
        }
      } else if (state[0UL] < local1) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      } else {
        state[0UL] -= state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 844337816UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L38
L28:
  mov    $0x0,%eax
  ret
L38:
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  sub    $0x62,%eax
  cmp    $0x14,%al
  ja     L28
  sub    $0x18,%rsp
  movzbl %al,%eax
  lea    D2(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x1234567,0xc(%rsp)
  cmpb   $0x67,0xc(%rsp)
  lea    D20(%rip),%rdi
  lea    D39(%rip),%rax
  cmovne %rax,%rdi
  call   <puts@plt>
L20:
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  mov    $0x4,%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L20
  mov    $0x9,%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L20
  lea    D49(%rip),%rdi
  call   <puts@plt>
  jmp    L20
  lea    D28(%rip),%rdi
  call   <puts@plt>
  jmp    L20
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type_guessed: string
name: extract_symbolic_data
arguments: label: D39
type_guessed: string
name: extract_symbolic_data
arguments: label: D46
type_guessed: string
name: extract_symbolic_data
arguments: label: D49
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: string

tool: D20: no

tool: D39: yes

tool: D46: %d


tool: D49: x86_64-linux-gnu

tool: D28: gcc

assistant: ```c
int main(int argc, char *argv[]) {
  switch (argc == 2 ? argv[1][0] : 0) {
  case 'b': {
    volatile unsigned foo = 0x01234567;
    puts(*(unsigned char *)&foo == 0x67 ? "no" : "yes");
    break;
  }
  case 'm':
    printf("%d\n", 4);
    break;
  case 'v':
    printf("%d\n", 9);
    break;
  case 't':
    puts("x86_64"
         "-"
         "linux"
         "-"
         "gnu");
    break;
  case 'c':
    puts("gcc");
    break;
  default:
    break;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L50
L16:
  xor    %eax,%eax
  ret
L50:
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  sub    $0x62,%eax
  cmp    $0x14,%al
  ja     L16
  lea    D10(%rip),%rdx
  movzbl %al,%eax
  sub    $0x18,%rsp
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D47(%rip),%rdi
  call   <puts@plt>
L36:
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  mov    $0x9,%esi
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L36
  mov    $0x4,%esi
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L36
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L36
  movl   $0x1234567,0xc(%rsp)
  lea    D12(%rip),%rdi
  cmpb   $0x67,0xc(%rsp)
  lea    D66(%rip),%rax
  cmovne %rax,%rdi
  call   <puts@plt>
  jmp    L36
```

tool_calls: name: retrieve_data
arguments: tag: D47
type: string
name: retrieve_data
arguments: tag: D58
type: string
name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D66
type: string

tool: D47: x86_64-linux-gnu

tool: D58: %d


tool: D29: gcc

tool: D12: no

tool: D66: yes

assistant: ```c
int main(int argc, char *argv[]) {
  switch (argc == 2 ? argv[1][0] : 0) {
  case 'b': {
    volatile unsigned foo = 0x01234567;
    puts(*(unsigned char *)&foo == 0x67 ? "no" : "yes");
    break;
  }
  case 'm':
    printf("%d\n", 4);
    break;
  case 'v':
    printf("%d\n", 9);
    break;
  case 't':
    puts("x86_64"
         "-"
         "linux"
         "-"
         "gnu");
    break;
  case 'c':
    puts("gcc");
    break;
  default:
    break;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L56
L11:
  xor    %eax,%eax
  ret
L56:
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  sub    $0x62,%eax
  cmp    $0x14,%al
  ja     L11
  lea    D3(%rip),%rdx
  movzbl %al,%eax
  sub    $0x18,%rsp
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D7(%rip),%rdi
  call   <puts@plt>
L38:
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  mov    $0x9,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L38
  mov    $0x4,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L38
  lea    D66(%rip),%rdi
  call   <puts@plt>
  jmp    L38
  movl   $0x1234567,0xc(%rsp)
  lea    D67(%rip),%rdi
  cmpb   $0x67,0xc(%rsp)
  lea    D63(%rip),%rax
  cmovne %rax,%rdi
  call   <puts@plt>
  jmp    L38
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: string
name: unpack_data
arguments: label: D66
type_infered: string
name: unpack_data
arguments: label: D67
type_infered: string
name: unpack_data
arguments: label: D63
type_infered: string

tool: D7: x86_64-linux-gnu

tool: D30: %d


tool: D66: gcc

tool: D67: no

tool: D63: yes

assistant: ```c
int main(int argc, char *argv[]) {
  switch (argc == 2 ? argv[1][0] : 0) {
  case 'b': {
    volatile unsigned foo = 0x01234567;
    puts(*(unsigned char *)&foo == 0x67 ? "no" : "yes");
    break;
  }
  case 'm':
    printf("%d\n", 4);
    break;
  case 'v':
    printf("%d\n", 9);
    break;
  case 't':
    puts("x86_64"
         "-"
         "linux"
         "-"
         "gnu");
    break;
  case 'c':
    puts("gcc");
    break;
  default:
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L15
  mov    -0x18(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x18(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  je     L0
  addl   $0x1,-0x10(%rbp)
  jmp    L9
L0:
  nop
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
datatype: string
name: read_data
arguments: data_label: D7
datatype: f64

tool: D10: %d

tool: D7: 0.98

assistant: ```c
int main() {
  int n, m, k, i, sum;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  sum = 0;
  for (i = 1;; i++) {
    sum = sum + m;
    if (i % k == 0) {
      m = m * 0.98;
    }
    if (i == n)
      break;
  }
  printf("%d", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%r8d
  mov    0xc(%rsp),%r9d
  mov    $0x0,%r10d
  mov    $0x0,%esi
  mov    $0x1,%ecx
  movsd  D13(%rip),%xmm1
  mov    $0x1,%r11d
  jmp    L13
L20:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  mov    %r11d,%r10d
L4:
  cmp    %ecx,%r9d
  je     L30
  add    $0x1,%ecx
L13:
  add    %edi,%esi
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L4
  jmp    L20
L30:
  test   %r10b,%r10b
  je     L54
  mov    %edi,0x10(%rsp)
L54:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: f64

tool: D24: %d

tool: D13: 0.98

assistant: ```c
int main() {
  int n, m, k, i, sum;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  sum = 0;
  for (i = 1;; i++) {
    sum = sum + m;
    if (i % k == 0) {
      m = m * 0.98;
    }
    if (i == n)
      break;
  }
  printf("%d", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%r8d
  xor    %esi,%esi
  mov    0xc(%rsp),%r9d
  movsd  D19(%rip),%xmm1
  xor    %r10d,%r10d
  mov    $0x1,%ecx
  jmp    L14
  nopl   0x0(%rax)
L49:
  add    $0x1,%ecx
L14:
  mov    %ecx,%eax
  add    %edi,%esi
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L24
  pxor   %xmm0,%xmm0
  mov    $0x1,%r10d
  cvtsi2sd %edi,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
L24:
  cmp    %ecx,%r9d
  jne    L49
  test   %r10b,%r10b
  je     L43
  mov    %edi,0x10(%rsp)
L43:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: f64

tool: D17: %d

tool: D19: 0.98

assistant: ```c
int main() {
  int n, m, k, i, sum;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  sum = 0;
  for (i = 1;; i++) {
    sum = sum + m;
    if (i % k == 0) {
      m = m * 0.98;
    }
    if (i == n)
      break;
  }
  printf("%d", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%r8d
  xor    %esi,%esi
  mov    0xc(%rsp),%r9d
  movsd  D4(%rip),%xmm1
  xor    %r10d,%r10d
  mov    $0x1,%ecx
  jmp    L11
  nopl   0x0(%rax)
L12:
  add    $0x1,%ecx
L11:
  mov    %ecx,%eax
  add    %edi,%esi
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L1
  pxor   %xmm0,%xmm0
  mov    $0x1,%r10d
  cvtsi2sd %edi,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
L1:
  cmp    %ecx,%r9d
  jne    L12
  test   %r10b,%r10b
  je     L14
  mov    %edi,0x10(%rsp)
L14:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D4
type_guessed: f64

tool: D5: %d

tool: D4: 0.98

assistant: ```c
int main() {
  int n, m, k, i, sum;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  sum = 0;
  for (i = 1;; i++) {
    sum = sum + m;
    if (i % k == 0) {
      m = m * 0.98;
    }
    if (i == n)
      break;
  }
  printf("%d", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L31
L28:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <isBlankLine@plt>
  test   %rax,%rax
  je     L42
  jmp    L31
L42:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <rmTrailingBlank@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <my_getline@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jg     L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string

tool: D2: %s

assistant: ```c
int main() {
  char line[1000];
  int len;
  while ((len = my_getline(line, 1000)) > 0) {
    if (isBlankLine(line))
      continue;
    rmTrailingBlank(line);
    printf("%s", line);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rbp
L23:
  mov    %rsp,%rbx
L33:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <my_getline@plt>
  test   %eax,%eax
  jle    L3
  mov    %rbx,%rdi
  call   <isBlankLine@plt>
  test   %rax,%rax
  jne    L33
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <rmTrailingBlank@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L23
L3:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D6: %s

assistant: ```c
int main() {
  char line[1000];
  int len;
  while ((len = my_getline(line, 1000)) > 0) {
    if (isBlankLine(line))
      continue;
    rmTrailingBlank(line);
    printf("%s", line);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <my_getline@plt>
  test   %eax,%eax
  jle    L23
  mov    %rbx,%rdi
  call   <isBlankLine@plt>
  test   %rax,%rax
  jne    L20
  mov    %rbx,%rdi
  call   <rmTrailingBlank@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L23:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string

tool: D3: %s

assistant: ```c
int main() {
  char line[1000];
  int len;
  while ((len = my_getline(line, 1000)) > 0) {
    if (isBlankLine(line))
      continue;
    rmTrailingBlank(line);
    printf("%s", line);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <my_getline@plt>
  test   %eax,%eax
  jle    L16
  mov    %rbx,%rdi
  call   <isBlankLine@plt>
  test   %rax,%rax
  jne    L17
  mov    %rbx,%rdi
  call   <rmTrailingBlank@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L16:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %s

assistant: ```c
int main() {
  char line[1000];
  int len;
  while ((len = my_getline(line, 1000)) > 0) {
    if (isBlankLine(line))
      continue;
    rmTrailingBlank(line);
    printf("%s", line);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nc_cal_chksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movw   $0x0,-0x1a(%rbp)
  jmp    L3
L19:
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x14(%rbp)
  subl   $0x2,-0x18(%rbp)
L3:
  cmpl   $0x1,-0x18(%rbp)
  jg     L19
  cmpl   $0x1,-0x18(%rbp)
  jne    L15
  lea    -0x1a(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzwl -0x1a(%rbp),%eax
  movzwl %ax,%eax
  add    %eax,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %ax,-0x1a(%rbp)
  movzwl -0x1a(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
unsigned short nc_cal_chksum(unsigned short *addr, int len) {
  int nleft = len;
  int sum = 0;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return answer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nc_cal_chksum>:
  endbr64
  mov    $0x0,%r9d
  cmp    $0x1,%esi
  jle    L22
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L1:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L1
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L31:
  cmp    $0x1,%esi
  je     L6
L10:
  mov    %eax,%edx
  sar    $0x10,%edx
  movzwl %ax,%eax
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
L22:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L31
L6:
  mov    (%rcx),%r9b
  movzwl %r9w,%r9d
  add    %r9d,%eax
  jmp    L10
```

assistant: ```c
unsigned short nc_cal_chksum(unsigned short *addr, int len) {
  int nleft = len;
  int sum = 0;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return answer;
}
```