ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<itc_net_close_main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <itc_net_close_p_multi_times@plt>
  xor    %eax,%eax
  call   <itc_net_close_n_reclose@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int itc_net_close_main(void) {
  itc_net_close_p_multi_times();
  itc_net_close_n_reclose();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lcsl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    0x18(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L52
  mov    -0x40(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L52
  lea    -0xc(%rbp),%r9
  lea    -0x10(%rbp),%r8
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    0x20(%rbp),%edi
  push   %rdi
  push   -0x50(%rbp)
  mov    %rax,%rdi
  call   <find_common@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  je     L21
  mov    -0x10(%rbp),%r8d
  mov    -0x18(%rbp),%edx
  mov    -0x3c(%rbp),%edi
  mov    -0x38(%rbp),%rcx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  push   -0x50(%rbp)
  push   -0x48(%rbp)
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <lcsl>
  add    $0x20,%rsp
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jle    L60
  mov    -0x14(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <csl_add@plt>
L60:
  mov    -0xc(%rbp),%r8d
  mov    -0x14(%rbp),%esi
  mov    -0x40(%rbp),%r9d
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  mov    0x20(%rbp),%edi
  push   %rdi
  push   -0x50(%rbp)
  push   -0x48(%rbp)
  mov    %rax,%rdi
  call   <lcsl>
  add    $0x20,%rsp
  jmp    L3
L52:
  nop
  jmp    L3
L21:
  nop
L3:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

assistant: ```c
void lcsl(struct file *a, int alo, int ahi, struct file *b, int blo, int bhi, struct cslb *cslb, struct v *v, int shortcut) {
  int alo1 = alo;
  int ahi1 = ahi;
  int blo1 = blo;
  int bhi1 = bhi;
  if (ahi <= alo || bhi <= blo)
    return;
  if (!find_common(a, b, &alo1, &ahi1, &blo1, &bhi1, v, shortcut))
    return;
  lcsl(a, alo, alo1, b, blo, blo1, cslb, v, 0);
  if (ahi1 > alo1)
    csl_add(cslb, alo1, blo1, ahi1 - alo1);
  lcsl(a, ahi1, ahi, b, bhi1, bhi, cslb, v, shortcut);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lcsl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,%ebp
  mov    %rcx,0x8(%rsp)
  mov    0x70(%rsp),%r15
  mov    0x78(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %esi,0x18(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %r8d,0x20(%rsp)
  mov    %r9d,0x24(%rsp)
  cmp    %edx,%esi
  jge    L44
  mov    %edx,%ebx
  mov    %rcx,%rsi
  mov    %r8d,%r13d
  mov    %r9d,%r12d
  cmp    %r9d,%r8d
  jge    L44
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    0x80(%rsp),%eax
  push   %rax
  push   %r14
  lea    0x34(%rsp),%r9
  lea    0x30(%rsp),%r8
  mov    %rsi,0x18(%rsp)
  mov    %rdi,0x10(%rsp)
  call   <find_common@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  jne    L27
L44:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  sub    $0x8,%rsp
  push   $0x0
  push   %r14
  push   %r15
  mov    0x40(%rsp),%r9d
  mov    %r13d,%r8d
  mov    0x28(%rsp),%rcx
  mov    0x38(%rsp),%edx
  mov    %ebp,%esi
  mov    0x20(%rsp),%rdi
  call   <lcsl>
  mov    0x3c(%rsp),%ecx
  mov    0x38(%rsp),%esi
  add    $0x20,%rsp
  cmp    %esi,%ecx
  jg     L64
L29:
  sub    $0x8,%rsp
  mov    0x88(%rsp),%eax
  push   %rax
  push   %r14
  push   %r15
  mov    %r12d,%r9d
  mov    0x44(%rsp),%r8d
  mov    0x28(%rsp),%rcx
  mov    %ebx,%edx
  mov    0x3c(%rsp),%esi
  mov    0x20(%rsp),%rdi
  call   <lcsl>
  add    $0x20,%rsp
  jmp    L44
L64:
  sub    %esi,%ecx
  mov    0x20(%rsp),%edx
  mov    %r15,%rdi
  call   <csl_add@plt>
  jmp    L29
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void lcsl(struct file *a, int alo, int ahi, struct file *b, int blo, int bhi, struct cslb *cslb, struct v *v, int shortcut) {
  int alo1 = alo;
  int ahi1 = ahi;
  int blo1 = blo;
  int bhi1 = bhi;
  if (ahi <= alo || bhi <= blo)
    return;
  if (!find_common(a, b, &alo1, &ahi1, &blo1, &bhi1, v, shortcut))
    return;
  lcsl(a, alo, alo1, b, blo, blo1, cslb, v, 0);
  if (ahi1 > alo1)
    csl_add(cslb, alo1, blo1, ahi1 - alo1);
  lcsl(a, ahi1, ahi, b, bhi1, bhi, cslb, v, shortcut);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lcsl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    0x70(%rsp),%rax
  mov    0x78(%rsp),%r11
  mov    %rax,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %esi,0x18(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %r8d,0x20(%rsp)
  mov    %r9d,0x24(%rsp)
  cmp    %edx,%esi
  jge    L1
  mov    %r8d,%r13d
  mov    %r9d,%ebx
  cmp    %r9d,%r8d
  jge    L1
  mov    %rdi,%r14
  mov    0x80(%rsp),%edi
  mov    %rcx,%r15
  mov    %edx,%r12d
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %esi,%ebp
  mov    %r15,%rsi
  push   %rdi
  mov    %r14,%rdi
  push   %r11
  lea    0x34(%rsp),%r9
  lea    0x30(%rsp),%r8
  mov    %r11,0x18(%rsp)
  call   <find_common@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  je     L1
  sub    $0x8,%rsp
  mov    %r13d,%r8d
  mov    %ebp,%esi
  mov    %r15,%rcx
  push   $0x0
  mov    0x18(%rsp),%r11
  mov    %r14,%rdi
  push   %r11
  mov    %r11,0x20(%rsp)
  push   0x18(%rsp)
  mov    0x40(%rsp),%r9d
  mov    0x38(%rsp),%edx
  call   <lcsl>
  mov    0x3c(%rsp),%esi
  mov    0x38(%rsp),%r8d
  add    $0x20,%rsp
  mov    0x8(%rsp),%r11
  cmp    %r8d,%esi
  jg     L14
L4:
  sub    $0x8,%rsp
  mov    %ebx,%r9d
  mov    %r15,%rcx
  mov    %r12d,%edx
  mov    0x88(%rsp),%eax
  mov    %r14,%rdi
  push   %rax
  push   %r11
  push   0x18(%rsp)
  mov    0x44(%rsp),%r8d
  call   <lcsl>
  add    $0x20,%rsp
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L14:
  sub    %r8d,%esi
  mov    0x20(%rsp),%edx
  mov    (%rsp),%rdi
  mov    %esi,%ecx
  mov    %r8d,%esi
  call   <csl_add@plt>
  mov    0x1c(%rsp),%esi
  mov    0x8(%rsp),%r11
  jmp    L4
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void lcsl(struct file *a, int alo, int ahi, struct file *b, int blo, int bhi, struct cslb *cslb, struct v *v, int shortcut) {
  int alo1 = alo;
  int ahi1 = ahi;
  int blo1 = blo;
  int bhi1 = bhi;
  if (ahi <= alo || bhi <= blo)
    return;
  if (!find_common(a, b, &alo1, &ahi1, &blo1, &bhi1, v, shortcut))
    return;
  lcsl(a, alo, alo1, b, blo, blo1, cslb, v, 0);
  if (ahi1 > alo1)
    csl_add(cslb, alo1, blo1, ahi1 - alo1);
  lcsl(a, ahi1, ahi, b, bhi1, bhi, cslb, v, shortcut);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lcsl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    0x70(%rsp),%rax
  mov    0x78(%rsp),%r11
  mov    %rax,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %esi,0x18(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %r8d,0x20(%rsp)
  mov    %r9d,0x24(%rsp)
  cmp    %edx,%esi
  jge    L30
  mov    %r8d,%r13d
  mov    %r9d,%ebx
  cmp    %r9d,%r8d
  jge    L30
  mov    %rdi,%r14
  mov    0x80(%rsp),%edi
  mov    %rcx,%r15
  mov    %edx,%r12d
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %esi,%ebp
  mov    %r15,%rsi
  push   %rdi
  mov    %r14,%rdi
  push   %r11
  lea    0x34(%rsp),%r9
  lea    0x30(%rsp),%r8
  mov    %r11,0x18(%rsp)
  call   <find_common@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  je     L30
  sub    $0x8,%rsp
  mov    %r13d,%r8d
  mov    %ebp,%esi
  mov    %r15,%rcx
  push   $0x0
  mov    0x18(%rsp),%r11
  mov    %r14,%rdi
  push   %r11
  mov    %r11,0x20(%rsp)
  push   0x18(%rsp)
  mov    0x40(%rsp),%r9d
  mov    0x38(%rsp),%edx
  call   <lcsl>
  mov    0x3c(%rsp),%esi
  mov    0x38(%rsp),%r8d
  add    $0x20,%rsp
  mov    0x8(%rsp),%r11
  cmp    %r8d,%esi
  jg     L49
L6:
  sub    $0x8,%rsp
  mov    %ebx,%r9d
  mov    %r15,%rcx
  mov    %r12d,%edx
  mov    0x88(%rsp),%eax
  mov    %r14,%rdi
  push   %rax
  push   %r11
  push   0x18(%rsp)
  mov    0x44(%rsp),%r8d
  call   <lcsl>
  add    $0x20,%rsp
L30:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L49:
  sub    %r8d,%esi
  mov    0x20(%rsp),%edx
  mov    (%rsp),%rdi
  mov    %esi,%ecx
  mov    %r8d,%esi
  call   <csl_add@plt>
  mov    0x1c(%rsp),%esi
  mov    0x8(%rsp),%r11
  jmp    L6
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void lcsl(struct file *a, int alo, int ahi, struct file *b, int blo, int bhi, struct cslb *cslb, struct v *v, int shortcut) {
  int alo1 = alo;
  int ahi1 = ahi;
  int blo1 = blo;
  int bhi1 = bhi;
  if (ahi <= alo || bhi <= blo)
    return;
  if (!find_common(a, b, &alo1, &ahi1, &blo1, &bhi1, v, shortcut))
    return;
  lcsl(a, alo, alo1, b, blo, blo1, cslb, v, 0);
  if (ahi1 > alo1)
    csl_add(cslb, alo1, blo1, ahi1 - alo1);
  lcsl(a, ahi1, ahi, b, bhi1, bhi, cslb, v, shortcut);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wycc_type_is_negate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <wycc_type_flags@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L0
  mov    $0x1,%eax
  jmp    L1
L0:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int wycc_type_is_negate(int id) {
  int flgs = wycc_type_flags(id);
  if (flgs & 4) {
    return 1;
  };
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wycc_type_is_negate>:
  endbr64
  sub    $0x8,%rsp
  call   <wycc_type_flags@plt>
  shr    $0x2,%eax
  and    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wycc_type_is_negate(int id) {
  int flgs = wycc_type_flags(id);
  if (flgs & 4) {
    return 1;
  };
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wycc_type_is_negate>:
  endbr64
  sub    $0x8,%rsp
  call   <wycc_type_flags@plt>
  add    $0x8,%rsp
  shr    $0x2,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int wycc_type_is_negate(int id) {
  int flgs = wycc_type_flags(id);
  if (flgs & 4) {
    return 1;
  };
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wycc_type_is_negate>:
  endbr64
  sub    $0x8,%rsp
  call   <wycc_type_flags@plt>
  add    $0x8,%rsp
  shr    $0x2,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int wycc_type_is_negate(int id) {
  int flgs = wycc_type_flags(id);
  if (flgs & 4) {
    return 1;
  };
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L51
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L51
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L51
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  je     L20
L51:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L39
L20:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L39:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string

tool: D18: %d %d %d %d

tool: D24: S


tool: D6: N


assistant: ```c
int main(void) {
  int a, b, c, d;
  scanf("%d %d %d %d", &a, &b, &c, &d);
  if (formaTriangulo(a, b, c) || formaTriangulo(a, b, d) || formaTriangulo(a, c, d) || formaTriangulo(b, c, d)) {
    printf("S\n");
  } else {
    printf("N\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L47
  mov    0x14(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  je     L7
L47:
  lea    D23(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L47
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L47
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D23
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string

tool: D2: %d %d %d %d

tool: D23: S


tool: D1: N


assistant: ```c
int main(void) {
  int a, b, c, d;
  scanf("%d %d %d %d", &a, &b, &c, &d);
  if (formaTriangulo(a, b, c) || formaTriangulo(a, b, d) || formaTriangulo(a, c, d) || formaTriangulo(b, c, d)) {
    printf("S\n");
  } else {
    printf("N\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D8(%rip),%rdi
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L27
  mov    0x14(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  je     L57
L27:
  lea    D7(%rip),%rdi
  call   <printf@plt>
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L57:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L27
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L27
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D7
datatype: string
name: parse_data
arguments: tag: D23
datatype: string

tool: D8: %d %d %d %d

tool: D7: S


tool: D23: N


assistant: ```c
int main(void) {
  int a, b, c, d;
  scanf("%d %d %d %d", &a, &b, &c, &d);
  if (formaTriangulo(a, b, c) || formaTriangulo(a, b, d) || formaTriangulo(a, c, d) || formaTriangulo(b, c, d)) {
    printf("S\n");
  } else {
    printf("N\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D1(%rip),%rdi
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L14
  mov    0x14(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  je     L1
L14:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L34:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L14
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <formaTriangulo@plt>
  test   %rax,%rax
  jne    L14
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L34
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D18
type: string

tool: D1: %d %d %d %d

tool: D5: S


tool: D18: N


assistant: ```c
int main(void) {
  int a, b, c, d;
  scanf("%d %d %d %d", &a, &b, &c, &d);
  if (formaTriangulo(a, b, c) || formaTriangulo(a, b, d) || formaTriangulo(a, c, d) || formaTriangulo(b, c, d)) {
    printf("S\n");
  } else {
    printf("N\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vfs_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L14:
  subq   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L12
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L14
L12:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *vfs_basename(char *path) {
  char *bname = path + strlen(path);
  while (*(bname - 1) != '/' && bname >= path) {
    bname--;
  }
  return bname;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vfs_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmpb   $0x2f,-0x1(%rax)
  je     L35
  cmp    %rax,%rbx
  ja     L35
L23:
  sub    $0x1,%rax
  cmpb   $0x2f,-0x1(%rax)
  je     L35
  cmp    %rax,%rbx
  jbe    L23
L35:
  pop    %rbx
  ret
```

assistant: ```c
char *vfs_basename(char *path) {
  char *bname = path + strlen(path);
  while (*(bname - 1) != '/' && bname >= path) {
    bname--;
  }
  return bname;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vfs_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmpb   $0x2f,-0x1(%rax)
  jne    L33
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L29:
  sub    $0x1,%rax
  cmpb   $0x2f,-0x1(%rax)
  je     L20
L33:
  cmp    %rax,%rbx
  jbe    L29
L20:
  pop    %rbx
  ret
```

assistant: ```c
char *vfs_basename(char *path) {
  char *bname = path + strlen(path);
  while (*(bname - 1) != '/' && bname >= path) {
    bname--;
  }
  return bname;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vfs_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmpb   $0x2f,-0x1(%rax)
  jne    L2
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x1,%rax
  cmpb   $0x2f,-0x1(%rax)
  je     L0
L2:
  cmp    %rax,%rbx
  jbe    L5
L0:
  pop    %rbx
  ret
```

assistant: ```c
char *vfs_basename(char *path) {
  char *bname = path + strlen(path);
  while (*(bname - 1) != '/' && bname >= path) {
    bname--;
  }
  return bname;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<execle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  lea    D13(%rip),%rax
  mov    %rax,%rdx
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <anvil_syslog@plt>
L15:
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: tag: D13
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string

tool: D13: execle

tool: D14: %s unimplemented


assistant: ```c
int execle(const char *path, const char *arg0, ...) {
  anvil_syslog(0, "%s unimplemented\n", __FUNCTION__);
  while (1)
    ;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<execle>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdx
  lea    D7(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <anvil_syslog@plt>
L8:
  jmp    L8
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string
name: read_data
arguments: tag: D7
type_infered: string

tool: D6: execle

tool: D7: %s unimplemented


assistant: ```c
int execle(const char *path, const char *arg0, ...) {
  anvil_syslog(0, "%s unimplemented\n", __FUNCTION__);
  while (1)
    ;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<execle>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D14(%rip),%rsi
  call   <anvil_syslog@plt>
L8:
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D14
type_guessed: string

tool: D12: execle

tool: D14: %s unimplemented


assistant: ```c
int execle(const char *path, const char *arg0, ...) {
  anvil_syslog(0, "%s unimplemented\n", __FUNCTION__);
  while (1)
    ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<execle>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D1(%rip),%rsi
  call   <anvil_syslog@plt>
L7:
  jmp    L7
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string

tool: D4: execle

tool: D1: %s unimplemented


assistant: ```c
int execle(const char *path, const char *arg0, ...) {
  anvil_syslog(0, "%s unimplemented\n", __FUNCTION__);
  while (1)
    ;
  return 0;
}
```