ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<min_pos>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x0(,%rdx,4),%r12d
  push   %rbp
  mov    %r12d,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %esi,0x14(%rsp)
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memset@plt>
  test   %ebx,%ebx
  jle    L13
  mov    %ebx,%eax
  mov    %r15,0x8(%rsp)
  movslq %r14d,%rbp
  lea    (%r15,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L1:
  mov    D6(%rip),%rax
  mov    (%rax),%r12d
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L27
  xor    %r14d,%r14d
  nopl   (%rax)
L36:
  mov    %r14d,%edi
  mov    %ebx,%edx
  mov    %r15,%rsi
  call   <search@plt>
  test   %eax,%eax
  jne    L35
  cmp    %r12d,0x0(%r13,%r14,4)
  jge    L35
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  mov    0x0(%r13,%r14,4),%r12d
L35:
  add    $0x1,%r14
  cmp    %r14,%rbp
  jne    L36
L27:
  addq   $0x4,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    0x18(%rsp),%rax
  jne    L1
L13:
  add    $0x28,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *min_pos(int *v, int vsize, int n) {
  int *pos = malloc(n * sizeof(int));
  memset(pos, -1, n * sizeof(int));
  int i, j, min;
  for (i = 0; i < n; i++) {
    min = INT_MAX;
    for (j = 0; j < vsize; j++) {
      if (!search(j, pos, n) && v[j] < min) {
        pos[i] = j;
        min = v[j];
      }
    }
  }
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<min_pos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x0(,%rdx,4),%r12d
  push   %rbp
  mov    %r12d,%edi
  movslq %esi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memset@plt>
  test   %ebx,%ebx
  jle    L17
  test   %ebp,%ebp
  jle    L17
  mov    %ebx,%eax
  mov    %r15,(%rsp)
  lea    (%r15,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L49:
  mov    D4(%rip),%rax
  xor    %r14d,%r14d
  mov    (%rax),%r12d
  nopl   (%rax)
L37:
  mov    %r14d,%edi
  mov    %ebx,%edx
  mov    %r15,%rsi
  call   <search@plt>
  test   %eax,%eax
  jne    L29
  cmp    %r12d,0x0(%r13,%r14,4)
  jge    L29
  mov    (%rsp),%rax
  mov    %r14d,(%rax)
  mov    0x0(%r13,%r14,4),%r12d
L29:
  add    $0x1,%r14
  cmp    %r14,%rbp
  jne    L37
  addq   $0x4,(%rsp)
  mov    (%rsp),%rax
  cmp    0x8(%rsp),%rax
  jne    L49
L17:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *min_pos(int *v, int vsize, int n) {
  int *pos = malloc(n * sizeof(int));
  memset(pos, -1, n * sizeof(int));
  int i, j, min;
  for (i = 0; i < n; i++) {
    min = INT_MAX;
    for (j = 0; j < vsize; j++) {
      if (!search(j, pos, n) && v[j] < min) {
        pos[i] = j;
        min = v[j];
      }
    }
  }
  return pos;
}
```
user: What is the c source code of the assembly code below?

```asm
<loop1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  jmp    L6
L12:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L6:
  cmpl   $0x0,-0x8(%rbp)
  jne    L12
  nop
  pop    %rbp
  ret
```

assistant: ```c
void loop1(int sum, int n) {
  for (; n != 0; --n) {
    sum += n;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<loop1>:
  endbr64
  test   %esi,%esi
  je     L14
L5:
  sub    $0x1,%esi
  jne    L5
L14:
  ret
```

assistant: ```c
void loop1(int sum, int n) {
  for (; n != 0; --n) {
    sum += n;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<loop1>:
  endbr64
  ret
```

assistant: ```c
void loop1(int sum, int n) {
  for (; n != 0; --n) {
    sum += n;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<loop1>:
  endbr64
  ret
```

assistant: ```c
void loop1(int sum, int n) {
  for (; n != 0; --n) {
    sum += n;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pointerArray1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D43(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D47(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L17
L28:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L17:
  cmpl   $0x3,-0x3c(%rbp)
  jle    L28
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D43
type: string
name: extract_symbolic_data
arguments: data_tag: D47
type: string
name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D57
type: string
name: extract_symbolic_data
arguments: data_tag: D44
type: string

tool: D43: CoreJava

tool: D47: EffectiveJava

tool: D18: Android

tool: D13: C ++

tool: D57: %s


tool: D44: %s

assistant: ```c
void pointerArray1() {
  char *bookList[4] = {"CoreJava", "EffectiveJava", "Android", "C ++"};
  for (int i = 0; i < 4; ++i) {
    printf("%s\n", bookList[i]);
  }
  char **p = bookList;
  printf("%s", *(p + 1));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pointerArray1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,(%rsp)
  lea    D20(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D10(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D69(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  lea    D51(%rip),%rbp
L3:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L3
  lea    D20(%rip),%rsi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D23
data_type: string
name: retrieve_data
arguments: data_label: D20
data_type: string
name: retrieve_data
arguments: data_label: D10
data_type: string
name: retrieve_data
arguments: data_label: D69
data_type: string
name: retrieve_data
arguments: data_label: D51
data_type: string
name: retrieve_data
arguments: data_label: D32
data_type: string

tool: D23: CoreJava

tool: D20: EffectiveJava

tool: D10: Android

tool: D69: C ++

tool: D51: %s


tool: D32: %s

assistant: ```c
void pointerArray1() {
  char *bookList[4] = {"CoreJava", "EffectiveJava", "Android", "C ++"};
  for (int i = 0; i < 4; ++i) {
    printf("%s\n", bookList[i]);
  }
  char **p = bookList;
  printf("%s", *(p + 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pointerArray1>:
  endbr64
  push   %r13
  lea    D2(%rip),%r13
  lea    D42(%rip),%rsi
  push   %r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %r13,0x8(%rsp)
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  lea    D6(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D44(%rip),%rax
  mov    %rax,0x18(%rsp)
L12:
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L17
  mov    (%rbx),%rsi
  jmp    L12
  xchg   %ax,%ax
L17:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  mov    %r13,%rsi
  lea    D51(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D42
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string
name: parse_data
arguments: data_tag: D44
data_type: string
name: parse_data
arguments: data_tag: D51
data_type: string

tool: D2: EffectiveJava

tool: D42: CoreJava

tool: D27: %s


tool: D6: Android

tool: D44: C ++

tool: D51: %s

assistant: ```c
void pointerArray1() {
  char *bookList[4] = {"CoreJava", "EffectiveJava", "Android", "C ++"};
  for (int i = 0; i < 4; ++i) {
    printf("%s\n", bookList[i]);
  }
  char **p = bookList;
  printf("%s", *(p + 1));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pointerArray1>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  lea    D31(%rip),%rdx
  push   %r12
  movq   %r13,%xmm1
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D43(%rip),%rax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  movq   %rax,%xmm0
  lea    D36(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  movaps %xmm0,(%rsp)
  movq   %rdx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L3:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  mov    %r13,%rsi
  lea    D18(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D31
datatype: string
name: extract_symbolic_data
arguments: tag: D25
datatype: string
name: extract_symbolic_data
arguments: tag: D43
datatype: string
name: extract_symbolic_data
arguments: tag: D36
datatype: string
name: extract_symbolic_data
arguments: tag: D18
datatype: string

tool: D13: EffectiveJava

tool: D31: Android

tool: D25: %s


tool: D43: CoreJava

tool: D36: C ++

tool: D18: %s

assistant: ```c
void pointerArray1() {
  char *bookList[4] = {"CoreJava", "EffectiveJava", "Android", "C ++"};
  for (int i = 0; i < 4; ++i) {
    printf("%s\n", bookList[i]);
  }
  char **p = bookList;
  printf("%s", *(p + 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pet_menu>:
  endbr64
  cmp    $0x4,%esi
  ja     L5
  sub    $0x8,%rsp
  mov    %esi,%esi
  lea    D8(%rip),%rdx
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  call   <clif_send_petstatus@plt>
L27:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
  call   <pet_food@plt>
  jmp    L27
  call   <pet_performance@plt>
  jmp    L27
  call   <pet_return_egg@plt>
  jmp    L27
  call   <pet_unequipitem@plt>
  jmp    L27
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int pet_menu(struct map_session_data *sd, int menunum) {
  switch (menunum) {
  case 0:
    clif_send_petstatus(sd);
    break;
  case 1:
    pet_food(sd);
    break;
  case 2:
    pet_performance(sd);
    break;
  case 3:
    pet_return_egg(sd);
    break;
  case 4:
    pet_unequipitem(sd);
    break;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<llconv_yvu_planar_u8s16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pixel_unpack_u8s16_y@plt>
  mov    -0x14(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pixel_unpack_u8s16_uv@plt>
  nop
  leave
  ret
```

assistant: ```c
void llconv_yvu_planar_u8s16(unsigned char *source, short int *dest, int nbpixels) {
  pixel_unpack_u8s16_y(source, dest, nbpixels >> 3);
  pixel_unpack_u8s16_uv(&source[nbpixels], &dest[nbpixels], nbpixels >> 4);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<llconv_yvu_planar_u8s16>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  sar    $0x3,%edx
  call   <pixel_unpack_u8s16_y@plt>
  movslq %ebx,%rax
  sar    $0x4,%ebx
  mov    %ebx,%edx
  lea    (%r12,%rax,2),%rsi
  lea    0x0(%rbp,%rax,1),%rdi
  call   <pixel_unpack_u8s16_uv@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void llconv_yvu_planar_u8s16(unsigned char *source, short int *dest, int nbpixels) {
  pixel_unpack_u8s16_y(source, dest, nbpixels >> 3);
  pixel_unpack_u8s16_uv(&source[nbpixels], &dest[nbpixels], nbpixels >> 4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<llconv_yvu_planar_u8s16>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sar    $0x3,%edx
  call   <pixel_unpack_u8s16_y@plt>
  movslq %ebx,%rax
  sar    $0x4,%ebx
  mov    %ebx,%edx
  lea    (%r12,%rax,2),%rsi
  lea    0x0(%rbp,%rax,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <pixel_unpack_u8s16_uv@plt>
```

assistant: ```c
void llconv_yvu_planar_u8s16(unsigned char *source, short int *dest, int nbpixels) {
  pixel_unpack_u8s16_y(source, dest, nbpixels >> 3);
  pixel_unpack_u8s16_uv(&source[nbpixels], &dest[nbpixels], nbpixels >> 4);
}
```
user: What is the c source code of the assembly code below:

```asm
<llconv_yvu_planar_u8s16>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sar    $0x3,%edx
  call   <pixel_unpack_u8s16_y@plt>
  movslq %ebx,%rax
  sar    $0x4,%ebx
  mov    %ebx,%edx
  lea    (%r12,%rax,2),%rsi
  lea    0x0(%rbp,%rax,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <pixel_unpack_u8s16_uv@plt>
```

assistant: ```c
void llconv_yvu_planar_u8s16(unsigned char *source, short int *dest, int nbpixels) {
  pixel_unpack_u8s16_y(source, dest, nbpixels >> 3);
  pixel_unpack_u8s16_uv(&source[nbpixels], &dest[nbpixels], nbpixels >> 4);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L24
L11:
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L24
  mov    $0x1,%eax
  jmp    L1
L24:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L11
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int in(uint32_t i, uint32_t *arr) {
  while (*arr) {
    if (*arr++ == i) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<in>:
  endbr64
L1:
  mov    (%rsi),%rax
  test   %rax,%rax
  je     L7
  add    $0x8,%rsi
  cmp    %rdi,%rax
  jne    L1
  mov    $0x1,%eax
  ret
L7:
  ret
```

assistant: ```c
int in(uint32_t i, uint32_t *arr) {
  while (*arr) {
    if (*arr++ == i) {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<in>:
  endbr64
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L20:
  add    $0x8,%rsi
  cmp    %rdi,%rax
  je     L29
L23:
  mov    (%rsi),%rax
  test   %rax,%rax
  jne    L20
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int in(uint32_t i, uint32_t *arr) {
  while (*arr) {
    if (*arr++ == i) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<in>:
  endbr64
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsi
  cmp    %rdi,%rax
  je     L25
L23:
  mov    (%rsi),%rax
  test   %rax,%rax
  jne    L29
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int in(uint32_t i, uint32_t *arr) {
  while (*arr) {
    if (*arr++ == i) {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_parent_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L32
L14:
  addq   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  jmp    L72
L30:
  subq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L72
  subl   $0x1,-0xc(%rbp)
L72:
  cmpl   $0x0,-0xc(%rbp)
  je     L38
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L30
L38:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L62
  mov    -0x18(%rbp),%rax
  jmp    L79
L62:
  mov    $0x0,%eax
L79:
  pop    %rbp
  ret
```

assistant: ```c
const char *get_parent_dir(const char *dir) {
  const char *start = dir;
  int levels = 2;
  while (*dir)
    dir++;
  while (levels && dir >= start)
    if (*--dir == '/')
      --levels;
  return (dir == start) ? NULL : (dir);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_parent_dir>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L45
  mov    %rdi,%rax
L1:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L1
  cmp    %rax,%rdi
  ja     L18
L7:
  mov    $0x2,%edx
L17:
  sub    $0x1,%rax
  cmpb   $0x2f,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  sub    %ecx,%edx
  je     L40
  cmp    %rax,%rdi
  jbe    L17
L40:
  cmp    %rax,%rdi
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
L18:
  ret
L45:
  mov    %rdi,%rax
  jmp    L7
```

assistant: ```c
const char *get_parent_dir(const char *dir) {
  const char *start = dir;
  int levels = 2;
  while (*dir)
    dir++;
  while (levels && dir >= start)
    if (*--dir == '/')
      --levels;
  return (dir == start) ? NULL : (dir);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_parent_dir>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L45
  nopl   0x0(%rax)
L27:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L27
  cmp    %rax,%rdi
  ja     L0
L45:
  mov    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L30:
  sub    $0x1,%rax
  xor    %ecx,%ecx
  cmpb   $0x2f,(%rax)
  sete   %cl
  sub    %ecx,%edx
  je     L17
  cmp    %rax,%rdi
  jbe    L30
L17:
  xor    %edx,%edx
  cmp    %rax,%rdi
  cmove  %rdx,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
const char *get_parent_dir(const char *dir) {
  const char *start = dir;
  int levels = 2;
  while (*dir)
    dir++;
  while (levels && dir >= start)
    if (*--dir == '/')
      --levels;
  return (dir == start) ? NULL : (dir);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_parent_dir>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L0
  nopl   0x0(%rax)
L30:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L30
  cmp    %rax,%rdi
  ja     L10
L0:
  mov    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L48:
  sub    $0x1,%rax
  xor    %ecx,%ecx
  cmpb   $0x2f,(%rax)
  sete   %cl
  sub    %ecx,%edx
  cmp    %rax,%rdi
  ja     L43
  test   %edx,%edx
  jne    L48
L43:
  xor    %edx,%edx
  cmp    %rax,%rdi
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
const char *get_parent_dir(const char *dir) {
  const char *start = dir;
  int levels = 2;
  while (*dir)
    dir++;
  while (levels && dir >= start)
    if (*--dir == '/')
      --levels;
  return (dir == start) ? NULL : (dir);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bitmap_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L5
  cmpl   $0x20,-0x14(%rbp)
  ja     L5
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  xor    %rax,%rdx
  mov    -0x14(%rbp),%eax
  neg    %eax
  and    $0x1f,%eax
  mov    $0xffffffffffffffff,%rsi
  mov    %eax,%ecx
  shr    %cl,%rsi
  mov    %rsi,%rax
  and    %rdx,%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L9
L5:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__bitmap_equal@plt>
L9:
  leave
  ret
```

assistant: ```c
int bitmap_equal(const unsigned long *src1, const unsigned long *src2, unsigned int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    return !((*src1 ^ *src2) & (~0UL >> (-(nbits) & (32 - 1))));
  else
    return __bitmap_equal(src1, src2, nbits);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitmap_equal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %edx,%edi
  call   <__builtin_constant_p@plt>
  cmp    $0x20,%ebx
  ja     L5
  test   %rax,%rax
  je     L5
  mov    0x0(%rbp),%rdx
  xor    (%r12),%rdx
  mov    %ebx,%ecx
  neg    %ecx
  and    $0x1f,%ecx
  mov    $0xffffffffffffffff,%rax
  shr    %cl,%rax
  test   %rax,%rdx
  sete   %al
  movzbl %al,%eax
  jmp    L21
L5:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__bitmap_equal@plt>
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int bitmap_equal(const unsigned long *src1, const unsigned long *src2, unsigned int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    return !((*src1 ^ *src2) & (~0UL >> (-(nbits) & (32 - 1))));
  else
    return __bitmap_equal(src1, src2, nbits);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_equal>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L1
  cmp    $0x20,%r12d
  ja     L1
  mov    %r12d,%ecx
  mov    $0xffffffffffffffff,%rax
  mov    0x0(%rbp),%rdx
  pop    %rbp
  neg    %ecx
  xor    0x0(%r13),%rdx
  pop    %r12
  and    $0x1f,%ecx
  pop    %r13
  shr    %cl,%rax
  test   %rax,%rdx
  sete   %al
  movzbl %al,%eax
  ret
  nopl   (%rax)
L1:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <__bitmap_equal@plt>
```

assistant: ```c
int bitmap_equal(const unsigned long *src1, const unsigned long *src2, unsigned int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    return !((*src1 ^ *src2) & (~0UL >> (-(nbits) & (32 - 1))));
  else
    return __bitmap_equal(src1, src2, nbits);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitmap_equal>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L3
  cmp    $0x20,%r12d
  ja     L3
  mov    %r12d,%ecx
  mov    $0xffffffffffffffff,%rax
  mov    0x0(%rbp),%rdx
  pop    %rbp
  neg    %ecx
  xor    0x0(%r13),%rdx
  pop    %r12
  and    $0x1f,%ecx
  pop    %r13
  shr    %cl,%rax
  test   %rax,%rdx
  sete   %al
  movzbl %al,%eax
  ret
  nopl   (%rax)
L3:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <__bitmap_equal@plt>
```

assistant: ```c
int bitmap_equal(const unsigned long *src1, const unsigned long *src2, unsigned int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    return !((*src1 ^ *src2) & (~0UL >> (-(nbits) & (32 - 1))));
  else
    return __bitmap_equal(src1, src2, nbits);
}
```