ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L7:
  movsbl (%r12,%rbx,1),%eax
  mov    %r13d,%ecx
  add    $0x1,%rbx
  shl    %cl,%eax
  or     %eax,%ebp
L15:
  mov    %ebx,%eax
  mov    %r12,%rdi
  neg    %eax
  lea    0x18(,%rax,8),%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D18
type: string

tool: D6: abcd

tool: D18: answ=%i


assistant: ```c
int main() {
  const char *text = "abcd";
  int shift = 24;
  int answ = 0;
  for (int i = 0; i < strlen(text); i++) {
    answ |= text[i] << shift;
    shift -= 8;
  }
  printf("answ=%i\n", answ);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func5() {
#pragma critTer : 18 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 19 :../../ test / resources / functionNumber.c:
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func5>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func5() {
#pragma critTer : 18 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 19 :../../ test / resources / functionNumber.c:
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func5>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func5() {
#pragma critTer : 18 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 19 :../../ test / resources / functionNumber.c:
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func5>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func5() {
#pragma critTer : 18 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 19 :../../ test / resources / functionNumber.c:
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uuencode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x30(%rbp)
  mov    %esi,-0x34(%rbp)
  mov    %rdx,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x40(%rbp),%rbx
  movl   $0x0,-0x20(%rbp)
  jmp    L44
L8:
  mov    -0x20(%rbp),%eax
  add    $0x2c,%eax
  cmp    %eax,-0x34(%rbp)
  jg     L20
  mov    -0x34(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L21
L20:
  movl   $0x2d,-0x1c(%rbp)
L21:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  add    $0x20,%edx
  mov    %dl,(%rax)
  movl   $0x0,-0x18(%rbp)
  jmp    L31
L1:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%rax
  or     %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    $0x12,%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  add    $0x20,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0xc,%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  add    $0x20,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x6,%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  add    $0x20,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  add    $0x20,%edx
  mov    %dl,(%rax)
  addl   $0x4,-0x14(%rbp)
  addl   $0x3,-0x18(%rbp)
L31:
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0xa,(%rax)
  addl   $0x2,-0x14(%rbp)
  addl   $0x2d,-0x20(%rbp)
L44:
  mov    -0x20(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L8
  movb   $0x0,(%rbx)
  movq   $0x0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int uuencode(in, num, out)
unsigned char *in;
int num;
unsigned char *out;
{
  int j, i, n, tot = 0;
  unsigned long l;
  register unsigned char *p;
  p = out;
  for (j = 0; j < num; j += 45) {
    if (j + 45 > num)
      i = (num - j);
    else
      i = 45;
    *(p++) = i + ' ';
    for (n = 0; n < i; n += 3) {
      (l = ((unsigned long)(*((in)++))) << 16, l |= ((unsigned long)(*((in)++))) << 8, l |= ((unsigned long)(*((in)++))));
      *(p++) = ((l >> 18) & 0x3f) + ' ';
      *(p++) = ((l >> 12) & 0x3f) + ' ';
      *(p++) = ((l >> 6) & 0x3f) + ' ';
      *(p++) = ((l)&0x3f) + ' ';
      tot += 4;
    }
    *(p++) = '\n';
    tot += 2;
  }
  *p = '\0';
  l = 0;
  return (tot);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uuencode>:
  endbr64
  mov    %esi,%r10d
  mov    %rdx,%rsi
  test   %r10d,%r10d
  jle    L36
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r10d,%r9d
  mov    $0x0,%eax
  lea    0x2c(%r10),%r11d
  mov    $0x2d,%ebx
  jmp    L1
L24:
  mov    %r9d,%r8d
  lea    0x1(%rsi),%rdx
  lea    0x20(%r9),%ecx
  mov    %cl,(%rsi)
  test   %r9d,%r9d
  jle    L6
L57:
  mov    %rdx,%rcx
  mov    $0x0,%esi
  sub    %edx,%eax
L64:
  movzbl (%rdi),%ebp
  shl    $0x10,%rbp
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%rdx
  or     %rbp,%rdx
  add    $0x3,%rdi
  movzbl -0x1(%rdi),%ebp
  or     %rdx,%rbp
  mov    %rdx,%r12
  shr    $0x12,%r12
  add    $0x20,%r12d
  mov    %r12b,(%rcx)
  shr    $0xc,%rdx
  and    $0x3f,%edx
  add    $0x20,%edx
  mov    %dl,0x1(%rcx)
  mov    %rbp,%rdx
  shr    $0x6,%rdx
  and    $0x3f,%edx
  add    $0x20,%edx
  mov    %dl,0x2(%rcx)
  lea    0x4(%rcx),%rdx
  mov    %rdx,%rcx
  and    $0x3f,%ebp
  add    $0x20,%ebp
  mov    %bpl,-0x1(%rdx)
  add    %eax,%edx
  add    $0x3,%esi
  cmp    %r8d,%esi
  jl     L64
L15:
  lea    0x1(%rcx),%rsi
  movb   $0xa,(%rcx)
  lea    0x2(%rdx),%eax
  sub    $0x2d,%r9d
  mov    %r10d,%edx
  sub    %r9d,%edx
  cmp    %edx,%r10d
  jle    L61
L1:
  mov    %r11d,%edx
  sub    %r9d,%edx
  cmp    %edx,%r10d
  jle    L24
  lea    0x1(%rsi),%rdx
  movb   $0x4d,(%rsi)
  mov    %ebx,%r8d
  jmp    L57
L6:
  mov    %rdx,%rcx
  mov    %eax,%edx
  jmp    L15
L36:
  mov    $0x0,%eax
  movb   $0x0,(%rdx)
  ret
L61:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int uuencode(in, num, out)
unsigned char *in;
int num;
unsigned char *out;
{
  int j, i, n, tot = 0;
  unsigned long l;
  register unsigned char *p;
  p = out;
  for (j = 0; j < num; j += 45) {
    if (j + 45 > num)
      i = (num - j);
    else
      i = 45;
    *(p++) = i + ' ';
    for (n = 0; n < i; n += 3) {
      (l = ((unsigned long)(*((in)++))) << 16, l |= ((unsigned long)(*((in)++))) << 8, l |= ((unsigned long)(*((in)++))));
      *(p++) = ((l >> 18) & 0x3f) + ' ';
      *(p++) = ((l >> 12) & 0x3f) + ' ';
      *(p++) = ((l >> 6) & 0x3f) + ' ';
      *(p++) = ((l)&0x3f) + ' ';
      tot += 4;
    }
    *(p++) = '\n';
    tot += 2;
  }
  *p = '\0';
  l = 0;
  return (tot);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uuencode>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r12
  mov    %esi,%r11d
  xor    %eax,%eax
  xor    %r10d,%r10d
  push   %rbp
  push   %rbx
  lea    0x20(%rsi),%ebx
  nopl   0x0(%rax,%rax,1)
L7:
  lea    0x2c(%r10),%esi
  mov    $0x4d,%ecx
  mov    $0x2d,%r8d
  cmp    %esi,%r11d
  jg     L31
  mov    %r11d,%r8d
  mov    %ebx,%ecx
  sub    %r10d,%r8d
  sub    %r10d,%ecx
L31:
  mov    %cl,(%rdx)
  lea    0x1(%rdx),%rcx
  xor    %esi,%esi
  sub    %ecx,%eax
  nopl   0x0(%rax)
L29:
  movzbl (%rdi),%ebp
  movzbl 0x1(%rdi),%edx
  add    $0x3,%rdi
  lea    (%rax,%rcx,1),%r9d
  add    $0x3,%esi
  shl    $0x10,%rbp
  shl    $0x8,%rdx
  or     %rbp,%rdx
  movzbl -0x1(%rdi),%ebp
  mov    %rdx,%r12
  or     %rdx,%rbp
  shr    $0xc,%rdx
  and    $0x3f,%edx
  shr    $0x12,%r12
  add    $0x20,%edx
  add    $0x20,%r12d
  mov    %dl,0x1(%rcx)
  mov    %rbp,%rdx
  and    $0x3f,%ebp
  shr    $0x6,%rdx
  mov    %r12b,(%rcx)
  add    $0x20,%ebp
  mov    %rcx,%r12
  and    $0x3f,%edx
  add    $0x4,%rcx
  add    $0x20,%edx
  mov    %dl,-0x2(%rcx)
  mov    %bpl,-0x1(%rcx)
  cmp    %esi,%r8d
  jg     L29
  add    $0x2d,%r10d
  movb   $0xa,0x4(%r12)
  lea    0x5(%r12),%rdx
  lea    0x6(%r9),%eax
  cmp    %r10d,%r11d
  jg     L7
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  ret
```

assistant: ```c
int uuencode(in, num, out)
unsigned char *in;
int num;
unsigned char *out;
{
  int j, i, n, tot = 0;
  unsigned long l;
  register unsigned char *p;
  p = out;
  for (j = 0; j < num; j += 45) {
    if (j + 45 > num)
      i = (num - j);
    else
      i = 45;
    *(p++) = i + ' ';
    for (n = 0; n < i; n += 3) {
      (l = ((unsigned long)(*((in)++))) << 16, l |= ((unsigned long)(*((in)++))) << 8, l |= ((unsigned long)(*((in)++))));
      *(p++) = ((l >> 18) & 0x3f) + ' ';
      *(p++) = ((l >> 12) & 0x3f) + ' ';
      *(p++) = ((l >> 6) & 0x3f) + ' ';
      *(p++) = ((l)&0x3f) + ' ';
      tot += 4;
    }
    *(p++) = '\n';
    tot += 2;
  }
  *p = '\0';
  l = 0;
  return (tot);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uuencode>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r12
  mov    %esi,%r11d
  xor    %eax,%eax
  xor    %r10d,%r10d
  push   %rbp
  push   %rbx
  lea    0x20(%rsi),%ebx
  nopl   0x0(%rax,%rax,1)
L11:
  lea    0x2c(%r10),%esi
  mov    $0x4d,%ecx
  mov    $0x2d,%r8d
  cmp    %esi,%r11d
  jg     L36
  mov    %r11d,%r8d
  mov    %ebx,%ecx
  sub    %r10d,%r8d
  sub    %r10d,%ecx
L36:
  mov    %cl,(%rdx)
  lea    0x1(%rdx),%rcx
  xor    %esi,%esi
  sub    %ecx,%eax
  nopl   0x0(%rax)
L29:
  movzbl (%rdi),%ebp
  movzbl 0x1(%rdi),%edx
  add    $0x3,%rdi
  lea    (%rax,%rcx,1),%r9d
  add    $0x3,%esi
  shl    $0x10,%rbp
  shl    $0x8,%rdx
  or     %rbp,%rdx
  movzbl -0x1(%rdi),%ebp
  mov    %rdx,%r12
  or     %rdx,%rbp
  shr    $0xc,%rdx
  and    $0x3f,%edx
  shr    $0x12,%r12
  add    $0x20,%edx
  add    $0x20,%r12d
  mov    %dl,0x1(%rcx)
  mov    %rbp,%rdx
  and    $0x3f,%ebp
  shr    $0x6,%rdx
  mov    %r12b,(%rcx)
  add    $0x20,%ebp
  mov    %rcx,%r12
  and    $0x3f,%edx
  add    $0x4,%rcx
  add    $0x20,%edx
  mov    %dl,-0x2(%rcx)
  mov    %bpl,-0x1(%rcx)
  cmp    %esi,%r8d
  jg     L29
  add    $0x2d,%r10d
  movb   $0xa,0x4(%r12)
  lea    0x5(%r12),%rdx
  lea    0x6(%r9),%eax
  cmp    %r10d,%r11d
  jg     L11
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  ret
```

assistant: ```c
int uuencode(in, num, out)
unsigned char *in;
int num;
unsigned char *out;
{
  int j, i, n, tot = 0;
  unsigned long l;
  register unsigned char *p;
  p = out;
  for (j = 0; j < num; j += 45) {
    if (j + 45 > num)
      i = (num - j);
    else
      i = 45;
    *(p++) = i + ' ';
    for (n = 0; n < i; n += 3) {
      (l = ((unsigned long)(*((in)++))) << 16, l |= ((unsigned long)(*((in)++))) << 8, l |= ((unsigned long)(*((in)++))));
      *(p++) = ((l >> 18) & 0x3f) + ' ';
      *(p++) = ((l >> 12) & 0x3f) + ' ';
      *(p++) = ((l >> 6) & 0x3f) + ' ';
      *(p++) = ((l)&0x3f) + ' ';
      tot += 4;
    }
    *(p++) = '\n';
    tot += 2;
  }
  *p = '\0';
  l = 0;
  return (tot);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<library_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x4000000,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L44
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L44:
  mov    $0x4000000,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L51
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L51:
  mov    $0x0,%eax
  call   <mytime@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L31
L21:
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    $0x4000000,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  addl   $0x1,-0x24(%rbp)
L31:
  cmpl   $0x63,-0x24(%rbp)
  jle    L21
  mov    $0x0,%eax
  call   <mytime@plt>
  mov    %rax,-0x8(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x64,%esi
  mov    $0x4000000,%edi
  call   <calculate_result@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  mov    $0x0,%eax
  call   <flush@plt>
  mov    $0x0,%eax
  call   <mytime@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L47
L5:
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x4000000,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x24(%rbp)
L47:
  cmpl   $0x63,-0x24(%rbp)
  jle    L5
  mov    $0x0,%eax
  call   <mytime@plt>
  mov    %rax,-0x8(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x64,%esi
  mov    $0x4000000,%edi
  call   <calculate_result@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  mov    $0x0,%eax
  call   <flush@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: tag: D33
type_guessed: string

tool: D17: Out of memory

tool: D2: Library: memset 

tool: D33: Library: memcpy 

assistant: ```c
void library_test() {
  char *a1, *a2;
  unsigned long t, t0;
  int i;
  a1 = malloc((64 * 1024 * 1024));
  if (!a1)
    error("Out of memory");
  a2 = malloc((64 * 1024 * 1024));
  if (!a2)
    error("Out of memory");
  t0 = mytime();
  for (i = 0; i < (100); i++) {
    memset(a1, i, (64 * 1024 * 1024));
  }
  t = mytime();
  print("Library: memset ");
  calculate_result((64 * 1024 * 1024), (100), t - t0);
  newline();
  flush();
  t0 = mytime();
  for (i = 0; i < (100); i++) {
    memcpy(a2, a1, (64 * 1024 * 1024));
  }
  t = mytime();
  print("Library: memcpy ");
  calculate_result((64 * 1024 * 1024), (100), t - t0);
  newline();
  flush();
  free(a1);
  free(a2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<library_test>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4000000,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L22
L53:
  mov    $0x4000000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L28
L36:
  mov    $0x0,%eax
  call   <mytime@plt>
  mov    %rax,%r13
  mov    $0x0,%ebx
L19:
  mov    $0x4000000,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L19
  mov    $0x0,%eax
  call   <mytime@plt>
  mov    %rax,%rbx
  lea    D36(%rip),%rdi
  call   <print@plt>
  mov    %rbx,%rdx
  sub    %r13,%rdx
  mov    $0x64,%esi
  mov    $0x4000000,%edi
  call   <calculate_result@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  mov    $0x0,%eax
  call   <flush@plt>
  mov    $0x0,%eax
  call   <mytime@plt>
  mov    %rax,%r13
  mov    $0x64,%ebx
L47:
  mov    $0x4000000,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  sub    $0x1,%ebx
  jne    L47
  mov    $0x0,%eax
  call   <mytime@plt>
  mov    %rax,%rbx
  lea    D30(%rip),%rdi
  call   <print@plt>
  mov    %rbx,%rdx
  sub    %r13,%rdx
  mov    $0x64,%esi
  mov    $0x4000000,%edi
  call   <calculate_result@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  mov    $0x0,%eax
  call   <flush@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  lea    D7(%rip),%rdi
  call   <error@plt>
  jmp    L53
L28:
  lea    D7(%rip),%rdi
  call   <error@plt>
  jmp    L36
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D36
data_type: string
name: extract_symbolic_data
arguments: data_tag: D30
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D36: Library: memset 

tool: D30: Library: memcpy 

tool: D7: Out of memory

assistant: ```c
void library_test() {
  char *a1, *a2;
  unsigned long t, t0;
  int i;
  a1 = malloc((64 * 1024 * 1024));
  if (!a1)
    error("Out of memory");
  a2 = malloc((64 * 1024 * 1024));
  if (!a2)
    error("Out of memory");
  t0 = mytime();
  for (i = 0; i < (100); i++) {
    memset(a1, i, (64 * 1024 * 1024));
  }
  t = mytime();
  print("Library: memset ");
  calculate_result((64 * 1024 * 1024), (100), t - t0);
  newline();
  flush();
  t0 = mytime();
  for (i = 0; i < (100); i++) {
    memcpy(a2, a1, (64 * 1024 * 1024));
  }
  t = mytime();
  print("Library: memcpy ");
  calculate_result((64 * 1024 * 1024), (100), t - t0);
  newline();
  flush();
  free(a1);
  free(a2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<library_test>:
  endbr64
  push   %r13
  mov    $0x4000000,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
L8:
  mov    $0x4000000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L6:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <mytime@plt>
  mov    %rax,%r13
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %ebx,%esi
  mov    $0x4000000,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <memset@plt>
  cmp    $0x64,%ebx
  jne    L33
  xor    %eax,%eax
  call   <mytime@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rbx
  call   <print@plt>
  mov    %rbx,%rdx
  mov    $0x64,%esi
  mov    $0x4000000,%edi
  sub    %r13,%rdx
  mov    $0x64,%ebx
  call   <calculate_result@plt>
  xor    %eax,%eax
  call   <newline@plt>
  xor    %eax,%eax
  call   <flush@plt>
  xor    %eax,%eax
  call   <mytime@plt>
  mov    %rax,%r13
  nop
L12:
  mov    $0x4000000,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  sub    $0x1,%ebx
  jne    L12
  xor    %eax,%eax
  call   <mytime@plt>
  lea    D36(%rip),%rdi
  mov    %rax,%rbx
  call   <print@plt>
  mov    %rbx,%rdx
  mov    $0x64,%esi
  mov    $0x4000000,%edi
  sub    %r13,%rdx
  call   <calculate_result@plt>
  xor    %eax,%eax
  call   <newline@plt>
  xor    %eax,%eax
  call   <flush@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10e0 <free@plt>
L4:
  lea    D17(%rip),%rdi
  call   <error@plt>
  jmp    L8
L14:
  lea    D17(%rip),%rdi
  call   <error@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D36
datatype: string
name: parse_data
arguments: tag: D17
datatype: string

tool: D5: Library: memset 

tool: D36: Library: memcpy 

tool: D17: Out of memory

assistant: ```c
void library_test() {
  char *a1, *a2;
  unsigned long t, t0;
  int i;
  a1 = malloc((64 * 1024 * 1024));
  if (!a1)
    error("Out of memory");
  a2 = malloc((64 * 1024 * 1024));
  if (!a2)
    error("Out of memory");
  t0 = mytime();
  for (i = 0; i < (100); i++) {
    memset(a1, i, (64 * 1024 * 1024));
  }
  t = mytime();
  print("Library: memset ");
  calculate_result((64 * 1024 * 1024), (100), t - t0);
  newline();
  flush();
  t0 = mytime();
  for (i = 0; i < (100); i++) {
    memcpy(a2, a1, (64 * 1024 * 1024));
  }
  t = mytime();
  print("Library: memcpy ");
  calculate_result((64 * 1024 * 1024), (100), t - t0);
  newline();
  flush();
  free(a1);
  free(a2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<library_test>:
  endbr64
  push   %r13
  mov    $0x4000000,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L19
L56:
  mov    $0x4000000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L47
L8:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <mytime@plt>
  mov    %rax,%r13
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    %ebx,%esi
  mov    $0x4000000,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <memset@plt>
  cmp    $0x64,%ebx
  jne    L59
  xor    %eax,%eax
  call   <mytime@plt>
  lea    D29(%rip),%rdi
  mov    %rax,%rbx
  call   <print@plt>
  mov    %rbx,%rdx
  mov    $0x64,%esi
  mov    $0x4000000,%edi
  sub    %r13,%rdx
  mov    $0x64,%ebx
  call   <calculate_result@plt>
  xor    %eax,%eax
  call   <newline@plt>
  xor    %eax,%eax
  call   <flush@plt>
  xor    %eax,%eax
  call   <mytime@plt>
  mov    %rax,%r13
  nop
L34:
  mov    $0x4000000,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  sub    $0x1,%ebx
  jne    L34
  xor    %eax,%eax
  call   <mytime@plt>
  lea    D33(%rip),%rdi
  mov    %rax,%rbx
  call   <print@plt>
  mov    %rbx,%rdx
  mov    $0x64,%esi
  mov    $0x4000000,%edi
  sub    %r13,%rdx
  call   <calculate_result@plt>
  xor    %eax,%eax
  call   <newline@plt>
  xor    %eax,%eax
  call   <flush@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10e0 <free@plt>
L19:
  lea    D10(%rip),%rdi
  call   <error@plt>
  jmp    L56
L47:
  lea    D10(%rip),%rdi
  call   <error@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_tag: D29
datatype: string
name: parse_data
arguments: data_tag: D33
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string

tool: D29: Library: memset 

tool: D33: Library: memcpy 

tool: D10: Out of memory

assistant: ```c
void library_test() {
  char *a1, *a2;
  unsigned long t, t0;
  int i;
  a1 = malloc((64 * 1024 * 1024));
  if (!a1)
    error("Out of memory");
  a2 = malloc((64 * 1024 * 1024));
  if (!a2)
    error("Out of memory");
  t0 = mytime();
  for (i = 0; i < (100); i++) {
    memset(a1, i, (64 * 1024 * 1024));
  }
  t = mytime();
  print("Library: memset ");
  calculate_result((64 * 1024 * 1024), (100), t - t0);
  newline();
  flush();
  t0 = mytime();
  for (i = 0; i < (100); i++) {
    memcpy(a2, a1, (64 * 1024 * 1024));
  }
  t = mytime();
  print("Library: memcpy ");
  calculate_result((64 * 1024 * 1024), (100), t - t0);
  newline();
  flush();
  free(a1);
  free(a2);
}
```