ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x3b9aca00,(%rsp)
  movq   $0x1dcd6500,0x8(%rsp)
  movq   $0x59682f00,0x10(%rsp)
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
  jmp    L20
L8:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_stats@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L0:
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  je     L60
L20:
  mov    %ebx,%ebp
  call   <fork@plt>
  test   %eax,%eax
  jne    L0
  mov    (%rsp,%rbx,8),%rdx
  test   %rdx,%rdx
  jle    L8
  mov    $0x0,%eax
L30:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L30
  jmp    L8
L60:
  mov    $0xee6b280,%eax
L3:
  sub    $0x1,%rax
  jne    L3
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <print_stats@plt>
L10:
  mov    $0x0,%edi
  call   <wait@plt>
  test   %rax,%rax
  jg     L10
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string

tool: D7: Child %d (%d) info


tool: D8: Parent process info

assistant: ```c
int main() {
  int pid;
  int i;
  long l;
  long times[] = {500000000L * 2, 500000000L * 1, 500000000L * 3};
  for (i = 0; i < 3; i++) {
    if ((pid = fork()) == 0) {
      for (l = 0; l < times[i]; l++)
        ;
      printf("Child %d (%d) info\n", i, getpid());
      print_stats();
      exit(0);
    }
  }
  for (l = 0; l < 500000000L / 2; l++)
    ;
  printf("Parent process info\n");
  print_stats();
  while (wait(NULL) > 0)
    ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L4:
  call   <fork@plt>
  test   %eax,%eax
  je     L29
L7:
  add    $0x1,%ebx
  cmp    $0x3,%ebx
  jne    L4
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <print_stats@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %edi,%edi
  call   <wait@plt>
  test   %rax,%rax
  jg     L10
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L29:
  call   <getpid@plt>
  mov    %rbp,%rdi
  mov    %ebx,%esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <print_stats@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D4
type_infered: string

tool: D7: Child %d (%d) info


tool: D4: Parent process info

assistant: ```c
int main() {
  int pid;
  int i;
  long l;
  long times[] = {500000000L * 2, 500000000L * 1, 500000000L * 3};
  for (i = 0; i < 3; i++) {
    if ((pid = fork()) == 0) {
      for (l = 0; l < times[i]; l++)
        ;
      printf("Child %d (%d) info\n", i, getpid());
      print_stats();
      exit(0);
    }
  }
  for (l = 0; l < 500000000L / 2; l++)
    ;
  printf("Parent process info\n");
  print_stats();
  while (wait(NULL) > 0)
    ;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L29:
  call   <fork@plt>
  test   %eax,%eax
  je     L31
L16:
  add    $0x1,%ebx
  cmp    $0x3,%ebx
  jne    L29
  lea    D18(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <print_stats@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %edi,%edi
  call   <wait@plt>
  test   %rax,%rax
  jg     L18
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L31:
  call   <getpid@plt>
  mov    %rbp,%rdi
  mov    %ebx,%esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <print_stats@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L16
```

tool_calls: name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D18
type: string

tool: D14: Child %d (%d) info


tool: D18: Parent process info

assistant: ```c
int main() {
  int pid;
  int i;
  long l;
  long times[] = {500000000L * 2, 500000000L * 1, 500000000L * 3};
  for (i = 0; i < 3; i++) {
    if ((pid = fork()) == 0) {
      for (l = 0; l < times[i]; l++)
        ;
      printf("Child %d (%d) info\n", i, getpid());
      print_stats();
      exit(0);
    }
  }
  for (l = 0; l < 500000000L / 2; l++)
    ;
  printf("Parent process info\n");
  print_stats();
  while (wait(NULL) > 0)
    ;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<path_015_expected_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L29:
  cmpl   $0x5,-0x4(%rbp)
  jg     L6
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x9,-0x4(%rbp)
  jle    L29
  jmp    L2
L6:
  nop
L2:
  pop    %rbp
  ret
```

assistant: ```c
void path_015_expected_3(int a, int b, int c) {
  int i;
  for (i = 0; i < 10; i++) {
    if (i > 5) {
      return;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<path_015_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_015_expected_3(int a, int b, int c) {
  int i;
  for (i = 0; i < 10; i++) {
    if (i > 5) {
      return;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<path_015_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_015_expected_3(int a, int b, int c) {
  int i;
  for (i = 0; i < 10; i++) {
    if (i > 5) {
      return;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<path_015_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_015_expected_3(int a, int b, int c) {
  int i;
  for (i = 0; i < 10; i++) {
    if (i > 5) {
      return;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vec3_scale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mulss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mulss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vec3_scale(float *dst, float b) {
  dst[0] = dst[0] * b;
  dst[1] = dst[1] * b;
  dst[2] = dst[2] * b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec3_scale>:
  endbr64
  movaps %xmm0,%xmm1
  mulss  (%rdi),%xmm1
  movss  %xmm1,(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x4(%rdi),%xmm1
  movss  %xmm1,0x4(%rdi)
  mulss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void vec3_scale(float *dst, float b) {
  dst[0] = dst[0] * b;
  dst[1] = dst[1] * b;
  dst[2] = dst[2] * b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vec3_scale>:
  endbr64
  movss  (%rdi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm1
  mulss  0x8(%rdi),%xmm0
  movss  %xmm1,0x4(%rdi)
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void vec3_scale(float *dst, float b) {
  dst[0] = dst[0] * b;
  dst[1] = dst[1] * b;
  dst[2] = dst[2] * b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vec3_scale>:
  endbr64
  movq   (%rdi),%xmm1
  movaps %xmm0,%xmm2
  shufps $0xe0,%xmm2,%xmm2
  mulss  0x8(%rdi),%xmm0
  mulps  %xmm2,%xmm1
  movss  %xmm0,0x8(%rdi)
  movlps %xmm1,(%rdi)
  ret
```

assistant: ```c
void vec3_scale(float *dst, float b) {
  dst[0] = dst[0] * b;
  dst[1] = dst[1] * b;
  dst[2] = dst[2] * b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unload_wf_mtllib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <wf_free_mtllib@plt>
  nop
  leave
  ret
```

assistant: ```c
void unload_wf_mtllib(void const *key, size_t len, void *data, void *link) {
  (void)key;
  (void)len;
  (void)link;
  wf_free_mtllib(*(struct wf_mtllib const **)data);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unload_wf_mtllib>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdx),%rdi
  call   <wf_free_mtllib@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void unload_wf_mtllib(void const *key, size_t len, void *data, void *link) {
  (void)key;
  (void)len;
  (void)link;
  wf_free_mtllib(*(struct wf_mtllib const **)data);
}
```
user: Translate the below assembly code into C programming language:

```asm
<unload_wf_mtllib>:
  endbr64
  mov    (%rdx),%rdi
  jmp    1050 <wf_free_mtllib@plt>
```

assistant: ```c
void unload_wf_mtllib(void const *key, size_t len, void *data, void *link) {
  (void)key;
  (void)len;
  (void)link;
  wf_free_mtllib(*(struct wf_mtllib const **)data);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<unload_wf_mtllib>:
  endbr64
  mov    (%rdx),%rdi
  jmp    1050 <wf_free_mtllib@plt>
```

assistant: ```c
void unload_wf_mtllib(void const *key, size_t len, void *data, void *link) {
  (void)key;
  (void)len;
  (void)link;
  wf_free_mtllib(*(struct wf_mtllib const **)data);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<call_file_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <inline_use_point_1@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int call_file_1() {
  int x = inline_use_point_1(5, 6);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<call_file_1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <inline_use_point_1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int call_file_1() {
  int x = inline_use_point_1(5, 6);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<call_file_1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <inline_use_point_1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int call_file_1() {
  int x = inline_use_point_1(5, 6);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<call_file_1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <inline_use_point_1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int call_file_1() {
  int x = inline_use_point_1(5, 6);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<solution>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x3d000(%rsp),%r11
L19:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L19
  sub    $0x2a8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x3d298(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D8(%rip),%rsi
  mov    $0x40,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  lea    0x200(%rsp),%rdi
  mov    $0x3d091,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %ebx,%ebx
  jle    L39
  mov    %rbp,%rdx
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp,%rax,4),%r8
  mov    $0x1,%edi
L33:
  mov    (%rdx),%ecx
  lea    0xf4247(%rcx),%eax
  mov    %ecx,%esi
  add    $0xf4240,%esi
  cmovns %esi,%eax
  sar    $0x3,%eax
  cltq
  and    $0x7,%ecx
  mov    %edi,%ebx
  shl    %cl,%ebx
  or     %bl,0x200(%rsp,%rax,1)
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L33
L39:
  lea    0x200(%rsp),%rax
  lea    0x3d291(%rsp),%rsi
  mov    $0x0,%edx
L16:
  movzbl (%rax),%ecx
  movzwl (%rsp,%rcx,2),%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L16
  mov    0x3d298(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %edx,%eax
  add    $0x3d2a8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: 

assistant: ```c
int solution(int A[], int N) {
  unsigned char appeared[2000001 / 8 + 1];
  unsigned short int onesInByte[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 4, 5, 5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8};
  int index = 0;
  int result = 0;
  memset(appeared, 0, 2000001 / 8 + 1);
  for (index = 0; index < N; ++index) {
    appeared[(A[index] + 1000000) / 8] |= (1 << (int)((A[index] + 1000000) % 8));
  }
  for (index = 0; index < 2000001 / 8 + 1; ++index) {
    result += onesInByte[appeared[index]];
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<solution>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d000(%rsp),%r11
L21:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L21
  sub    $0x2a0,%rsp
  mov    $0x40,%ecx
  mov    $0x3d091,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x3d298(%rsp)
  xor    %eax,%eax
  lea    0x200(%rsp),%rbx
  mov    %esi,%r12d
  mov    %rdi,%rbp
  lea    D0(%rip),%rsi
  mov    %rsp,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L11
  lea    -0x1(%r12),%eax
  mov    %rbp,%rdx
  mov    $0x1,%edi
  lea    0x4(%rbp,%rax,4),%r8
  nopl   0x0(%rax)
L12:
  mov    (%rdx),%ecx
  mov    %ecx,%esi
  lea    0xf4247(%rcx),%eax
  add    $0xf4240,%esi
  cmovns %esi,%eax
  and    $0x7,%ecx
  mov    %edi,%esi
  add    $0x4,%rdx
  shl    %cl,%esi
  sar    $0x3,%eax
  cltq
  or     %sil,0x200(%rsp,%rax,1)
  cmp    %rdx,%r8
  jne    L12
L11:
  mov    %rbx,%rax
  lea    0x3d291(%rsp),%rcx
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L46:
  movzbl (%rax),%edx
  add    $0x1,%rax
  movzwl (%rsp,%rdx,2),%edx
  add    %edx,%r8d
  cmp    %rax,%rcx
  jne    L46
  mov    0x3d298(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x3d2a0,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: 

assistant: ```c
int solution(int A[], int N) {
  unsigned char appeared[2000001 / 8 + 1];
  unsigned short int onesInByte[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 4, 5, 5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8};
  int index = 0;
  int result = 0;
  memset(appeared, 0, 2000001 / 8 + 1);
  for (index = 0; index < N; ++index) {
    appeared[(A[index] + 1000000) / 8] |= (1 << (int)((A[index] + 1000000) % 8));
  }
  for (index = 0; index < 2000001 / 8 + 1; ++index) {
    result += onesInByte[appeared[index]];
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solution>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x2a0,%rsp
  mov    $0x40,%ecx
  mov    $0x3d091,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x3d298(%rsp)
  xor    %eax,%eax
  lea    0x200(%rsp),%rbx
  mov    %esi,%r12d
  mov    %rdi,%rbp
  lea    D5(%rip),%rsi
  mov    %rsp,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L43
  lea    -0x1(%r12),%eax
  mov    %rbp,%rdx
  mov    $0x1,%edi
  lea    0x4(%rbp,%rax,4),%r8
  nopl   0x0(%rax)
L37:
  mov    (%rdx),%ecx
  mov    %ecx,%esi
  lea    0xf4247(%rcx),%eax
  add    $0xf4240,%esi
  cmovns %esi,%eax
  and    $0x7,%ecx
  mov    %edi,%esi
  add    $0x4,%rdx
  shl    %cl,%esi
  sar    $0x3,%eax
  cltq
  or     %sil,0x200(%rsp,%rax,1)
  cmp    %rdx,%r8
  jne    L37
L43:
  mov    %rbx,%rax
  lea    0x3d291(%rsp),%rcx
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L26:
  movzbl (%rax),%edx
  add    $0x1,%rax
  movzwl (%rsp,%rdx,2),%edx
  add    %edx,%r8d
  cmp    %rax,%rcx
  jne    L26
  mov    0x3d298(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x3d2a0,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: 

assistant: ```c
int solution(int A[], int N) {
  unsigned char appeared[2000001 / 8 + 1];
  unsigned short int onesInByte[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 4, 5, 5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8};
  int index = 0;
  int result = 0;
  memset(appeared, 0, 2000001 / 8 + 1);
  for (index = 0; index < N; ++index) {
    appeared[(A[index] + 1000000) / 8] |= (1 << (int)((A[index] + 1000000) % 8));
  }
  for (index = 0; index < 2000001 / 8 + 1; ++index) {
    result += onesInByte[appeared[index]];
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bbm_com_data_deselect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%edx
  movzbl -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fc8080_data_deselect@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int bbm_com_data_deselect(void *handle, unsigned char subch_id, unsigned char buf_id) {
  int res;
  res = fc8080_data_deselect(handle, subch_id, buf_id);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bbm_com_data_deselect>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dl,%edx
  movzbl %sil,%esi
  call   <fc8080_data_deselect@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bbm_com_data_deselect(void *handle, unsigned char subch_id, unsigned char buf_id) {
  int res;
  res = fc8080_data_deselect(handle, subch_id, buf_id);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bbm_com_data_deselect>:
  endbr64
  movzbl %dl,%edx
  movzbl %sil,%esi
  jmp    1050 <fc8080_data_deselect@plt>
```

assistant: ```c
int bbm_com_data_deselect(void *handle, unsigned char subch_id, unsigned char buf_id) {
  int res;
  res = fc8080_data_deselect(handle, subch_id, buf_id);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bbm_com_data_deselect>:
  endbr64
  movzbl %dl,%edx
  movzbl %sil,%esi
  jmp    1050 <fc8080_data_deselect@plt>
```

assistant: ```c
int bbm_com_data_deselect(void *handle, unsigned char subch_id, unsigned char buf_id) {
  int res;
  res = fc8080_data_deselect(handle, subch_id, buf_id);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmpStringsWithEmbeddedNumbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
L76:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <countLeadingDigits@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <countLeadingDigits@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  js     L59
  cmpl   $0x0,-0x24(%rbp)
  js     L59
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L52
  mov    -0x20(%rbp),%eax
  jmp    L6
L52:
  mov    -0x28(%rbp),%eax
  cltq
  add    %rax,-0x38(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x40(%rbp)
L59:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <countLeadingNondigits@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <countLeadingNondigits@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L92
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  jmp    L6
L92:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L56
  mov    $0x0,%eax
  jmp    L6
L56:
  mov    -0x1c(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L106
  mov    -0x14(%rbp),%eax
  jmp    L6
L106:
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x38(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x40(%rbp)
  jmp    L76
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int cmpStringsWithEmbeddedNumbers(const char *a, const char *b) {
  for (;;) {
    int aNum = countLeadingDigits(a);
    int bNum = countLeadingDigits(b);
    if (aNum >= 0 && bNum >= 0) {
      int diff = atoi(a) - atoi(b);
      if (diff != 0)
        return diff;
      a += aNum;
      b += bNum;
    }
    int aNonNum = countLeadingNondigits(a);
    int bNonNum = countLeadingNondigits(b);
    if (aNonNum != bNonNum)
      return strcmp(a, b);
    else if (aNonNum == 0)
      return 0;
    else {
      int diff = memcmp(a, b, aNonNum);
      if (diff != 0)
        return diff;
      a += aNonNum;
      b += bNonNum;
    }
  }
}
```