ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<direct_write>:
  endbr64
  sub    $0x10,%rsp
  mov    0x18(%rsp),%eax
  push   %rax
  lea    D2(%rip),%rdi
  call   <print@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: 	(template driver) direct_write(data, base=0x%x, offset=0x%x, size=0x%x, blocksize=0x%x, first_offset=0x%x, overall_size=0x%x)


assistant: ```c
int direct_write(const unsigned char *data, int base, int offset, int size, int blocksize, int first_offset, int overall_size) {
  (void)data;
  print("\t(template driver) direct_write(data, base=0x%x, offset=0x%x, size=0x%x, blocksize=0x%x, first_offset=0x%x, overall_size=0x%x)\n", base, offset, size, blocksize, first_offset, overall_size);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<direct_write>:
  endbr64
  sub    $0x10,%rsp
  lea    D0(%rip),%rdi
  mov    0x18(%rsp),%eax
  push   %rax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: 	(template driver) direct_write(data, base=0x%x, offset=0x%x, size=0x%x, blocksize=0x%x, first_offset=0x%x, overall_size=0x%x)


assistant: ```c
int direct_write(const unsigned char *data, int base, int offset, int size, int blocksize, int first_offset, int overall_size) {
  (void)data;
  print("\t(template driver) direct_write(data, base=0x%x, offset=0x%x, size=0x%x, blocksize=0x%x, first_offset=0x%x, overall_size=0x%x)\n", base, offset, size, blocksize, first_offset, overall_size);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<direct_write>:
  endbr64
  sub    $0x10,%rsp
  lea    D8(%rip),%rdi
  mov    0x18(%rsp),%eax
  push   %rax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: 	(template driver) direct_write(data, base=0x%x, offset=0x%x, size=0x%x, blocksize=0x%x, first_offset=0x%x, overall_size=0x%x)


assistant: ```c
int direct_write(const unsigned char *data, int base, int offset, int size, int blocksize, int first_offset, int overall_size) {
  (void)data;
  print("\t(template driver) direct_write(data, base=0x%x, offset=0x%x, size=0x%x, blocksize=0x%x, first_offset=0x%x, overall_size=0x%x)\n", base, offset, size, blocksize, first_offset, overall_size);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L10
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rsync@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L49
L38:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L40
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rsync@plt>
  addl   $0x1,-0x10(%rbp)
L40:
  addq   $0x1,-0x8(%rbp)
L49:
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jbe    L38
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rsync@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  jmp    L15
L10:
  nop
L15:
  leave
  ret
```

assistant: ```c
void quicksort(int *s, int left, int right) {
  if (left >= right) {
    return;
  }
  int mid = (left + right) / 2;
  rsync(&s[left], &s[mid]);
  int cnt = left;
  for (size_t i = left + 1; i <= right; i++) {
    if (s[i] > s[left]) {
      rsync(&s[i], &s[++cnt]);
      cnt++;
    }
  }
  rsync(&s[cnt], &s[left]);
  quicksort(s, left, cnt);
  quicksort(s, cnt + 1, right);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %edx,%esi
  jl     L35
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r15d
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r14
  lea    (%rsi,%rdx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%rsi
  mov    %r14,%rdi
  call   <rsync@plt>
  lea    0x1(%r13),%ebx
  movslq %ebx,%rbx
  movslq %r15d,%r15
  cmp    %r15,%rbx
  ja     L23
  mov    %r13d,%r12d
  jmp    L24
L52:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  ja     L47
L24:
  lea    0x0(%rbp,%rbx,4),%rdi
  mov    (%r14),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jle    L52
  lea    0x1(%r12),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rsi
  call   <rsync@plt>
  add    $0x2,%r12d
  jmp    L52
L23:
  mov    %r13d,%r12d
L47:
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  mov    %r14,%rsi
  call   <rsync@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%r12),%esi
  mov    0xc(%rsp),%edx
  mov    %rbp,%rdi
  call   <quicksort>
  jmp    L10
```

assistant: ```c
void quicksort(int *s, int left, int right) {
  if (left >= right) {
    return;
  }
  int mid = (left + right) / 2;
  rsync(&s[left], &s[mid]);
  int cnt = left;
  for (size_t i = left + 1; i <= right; i++) {
    if (s[i] > s[left]) {
      rsync(&s[i], &s[++cnt]);
      cnt++;
    }
  }
  rsync(&s[cnt], &s[left]);
  quicksort(s, left, cnt);
  quicksort(s, cnt + 1, right);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r13d,0x8(%rsp)
  cmp    %r13d,%esi
  jge    L5
  mov    %rdi,%rbp
  mov    %esi,%r14d
L63:
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,4),%r15
  mov    0x8(%rsp),%eax
  mov    %r15,%rdi
  lea    (%rax,%r14,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(%rbp,%rax,4),%rsi
  call   <rsync@plt>
  lea    0x1(%r14),%ecx
  movslq %ecx,%rbx
  cmp    %r13,%rbx
  ja     L51
  mov    %r14d,%r12d
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  ja     L13
L59:
  mov    (%r15),%eax
  lea    0x0(%rbp,%rbx,4),%rdi
  cmp    %eax,0x0(%rbp,%rbx,4)
  jle    L15
  lea    0x1(%r12),%eax
  add    $0x1,%rbx
  add    $0x2,%r12d
  cltq
  lea    0x0(%rbp,%rax,4),%rsi
  call   <rsync@plt>
  cmp    %r13,%rbx
  jbe    L59
L13:
  movslq %r12d,%rax
  lea    0x1(%r12),%ecx
  lea    0x0(%rbp,%rax,4),%rdi
L75:
  mov    %r15,%rsi
  mov    %ecx,0xc(%rsp)
  call   <rsync@plt>
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  mov    0xc(%rsp),%ecx
  cmp    %ecx,0x8(%rsp)
  jle    L5
  mov    %ecx,%r14d
  jmp    L63
  xchg   %ax,%ax
L5:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L51:
  mov    %r15,%rdi
  mov    %r14d,%r12d
  jmp    L75
```

assistant: ```c
void quicksort(int *s, int left, int right) {
  if (left >= right) {
    return;
  }
  int mid = (left + right) / 2;
  rsync(&s[left], &s[mid]);
  int cnt = left;
  for (size_t i = left + 1; i <= right; i++) {
    if (s[i] > s[left]) {
      rsync(&s[i], &s[++cnt]);
      cnt++;
    }
  }
  rsync(&s[cnt], &s[left]);
  quicksort(s, left, cnt);
  quicksort(s, cnt + 1, right);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r13d,0x8(%rsp)
  cmp    %r13d,%esi
  jge    L29
  mov    %rdi,%rbp
  mov    %esi,%r14d
L76:
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,4),%r15
  mov    0x8(%rsp),%eax
  mov    %r15,%rdi
  lea    (%rax,%r14,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(%rbp,%rax,4),%rsi
  call   <rsync@plt>
  lea    0x1(%r14),%ecx
  movslq %ecx,%rbx
  cmp    %r13,%rbx
  ja     L19
  mov    %r14d,%r12d
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L77:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  ja     L15
L20:
  mov    (%r15),%eax
  lea    0x0(%rbp,%rbx,4),%rdi
  cmp    %eax,0x0(%rbp,%rbx,4)
  jle    L77
  lea    0x1(%r12),%eax
  add    $0x1,%rbx
  add    $0x2,%r12d
  cltq
  lea    0x0(%rbp,%rax,4),%rsi
  call   <rsync@plt>
  cmp    %r13,%rbx
  jbe    L20
L15:
  movslq %r12d,%rax
  lea    0x1(%r12),%ecx
  lea    0x0(%rbp,%rax,4),%rdi
L54:
  mov    %r15,%rsi
  mov    %ecx,0xc(%rsp)
  call   <rsync@plt>
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  mov    0xc(%rsp),%ecx
  cmp    %ecx,0x8(%rsp)
  jle    L29
  mov    %ecx,%r14d
  jmp    L76
  xchg   %ax,%ax
L29:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L19:
  mov    %r15,%rdi
  mov    %r14d,%r12d
  jmp    L54
```

assistant: ```c
void quicksort(int *s, int left, int right) {
  if (left >= right) {
    return;
  }
  int mid = (left + right) / 2;
  rsync(&s[left], &s[mid]);
  int cnt = left;
  for (size_t i = left + 1; i <= right; i++) {
    if (s[i] > s[left]) {
      rsync(&s[i], &s[++cnt]);
      cnt++;
    }
  }
  rsync(&s[cnt], &s[left]);
  quicksort(s, left, cnt);
  quicksort(s, cnt + 1, right);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<checkIfTribonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L35
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L35:
  cmpl   $0x1,-0x24(%rbp)
  jne    L48
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L48:
  cmpl   $0x2,-0x24(%rbp)
  jne    L17
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L17
L62:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0x24(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L68
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L14
L68:
  cmpl   $0x3,-0x24(%rbp)
  jne    L17
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L17:
  cmpl   $0x2,-0x24(%rbp)
  jg     L62
  nop
L14:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D47
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string

tool: D4: %d is part of Tribonacci Sequence


tool: D2: 
 %d  is a part of Tribonacci Sequence


tool: D22: 
 %d  is part of Tribonacci Sequence


tool: D47: %d is part of Tribonacci number


tool: D17:  I'm sorry %d isn't in the series!

assistant: ```c
void checkIfTribonacci(int media) {
  const int number = media;
  int a = 0;
  int b = 1;
  int c = 1;
  int result = 0;
  if (media == 0) {
    result = a;
    printf("%d is part of Tribonacci Sequence\n", result);
  }
  if (media == 1) {
    result = b;
    printf("\n %d  is a part of Tribonacci Sequence\n", result);
  }
  if (media == 2) {
    result = c;
    printf("\n %d  is part of Tribonacci Sequence\n", result);
  }
  while (media > 2) {
    result = a + b + c;
    a = b;
    b = c;
    c = result;
    media--;
    if (result == number) {
      printf("\n");
      printf("%d is part of Tribonacci number\n", number);
      break;
    }
    if (media == 3) {
      printf(" I'm sorry %d isn't in the series!", number);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<checkIfTribonacci>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  test   %edi,%edi
  je     L29
  cmp    $0x1,%edi
  je     L25
  cmp    $0x2,%edi
  jne    L18
  mov    $0x1,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L81
L29:
  mov    $0x0,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  cmp    $0x2,%r15d
  jle    L81
  lea    -0x1(%r15),%ebp
  mov    $0x2,%r13d
  mov    $0x1,%r12d
  mov    $0x1,%ebx
  jmp    L54
L25:
  mov    $0x1,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L81
L97:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r14d,%esi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L81:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L83:
  mov    %r15d,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L109:
  add    %r12d,%ebx
  lea    (%rbx,%r13,1),%r14d
  sub    $0x1,%ebp
  mov    %r12d,%ebx
  mov    %r13d,%r12d
  cmp    %r14d,%r15d
  je     L97
  mov    %r14d,%r13d
L54:
  cmp    $0x3,%ebp
  je     L83
  cmp    $0x2,%ebp
  jg     L109
  jmp    L81
```

tool_calls: name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D29
type_guessed: string
name: read_data
arguments: tag: D38
type_guessed: string
name: read_data
arguments: tag: D25
type_guessed: string

tool: D28: 
 %d  is part of Tribonacci Sequence


tool: D10: %d is part of Tribonacci Sequence


tool: D29: 
 %d  is a part of Tribonacci Sequence


tool: D38: %d is part of Tribonacci number


tool: D25:  I'm sorry %d isn't in the series!

assistant: ```c
void checkIfTribonacci(int media) {
  const int number = media;
  int a = 0;
  int b = 1;
  int c = 1;
  int result = 0;
  if (media == 0) {
    result = a;
    printf("%d is part of Tribonacci Sequence\n", result);
  }
  if (media == 1) {
    result = b;
    printf("\n %d  is a part of Tribonacci Sequence\n", result);
  }
  if (media == 2) {
    result = c;
    printf("\n %d  is part of Tribonacci Sequence\n", result);
  }
  while (media > 2) {
    result = a + b + c;
    a = b;
    b = c;
    c = result;
    media--;
    if (result == number) {
      printf("\n");
      printf("%d is part of Tribonacci number\n", number);
      break;
    }
    if (media == 3) {
      printf(" I'm sorry %d isn't in the series!", number);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checkIfTribonacci>:
  endbr64
  test   %edi,%edi
  je     L94
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L23
  cmp    $0x2,%edi
  je     L87
  jle    L69
  mov    %edi,%edx
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  xor    %eax,%eax
  jmp    L56
  nopl   0x0(%rax)
L25:
  mov    %ebp,%eax
  mov    %r12d,%ebp
  cmp    $0x2,%edx
  je     L69
L56:
  add    %ebp,%eax
  mov    %ebx,%r12d
  sub    $0x1,%edx
  add    %eax,%ebx
  cmp    %ebx,%r13d
  je     L5
  cmp    $0x3,%edx
  jne    L25
  add    %ebp,%r12d
  mov    %r13d,%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    %ebx,%r12d
  cmp    %r12d,%r13d
  je     L5
L69:
  pop    %rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0x1,%esi
  lea    D42(%rip),%rdi
L74:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
  nopl   (%rax)
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13d,%esi
  lea    D44(%rip),%rdi
  jmp    L74
  xchg   %ax,%ax
L94:
  xor    %esi,%esi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  jmp    1070 <printf@plt>
L87:
  mov    $0x1,%esi
  lea    D31(%rip),%rdi
  jmp    L74
```

tool_calls: name: parse_data
arguments: tag: D33
type_guessed: string
name: parse_data
arguments: tag: D42
type_guessed: string
name: parse_data
arguments: tag: D44
type_guessed: string
name: parse_data
arguments: tag: D48
type_guessed: string
name: parse_data
arguments: tag: D31
type_guessed: string

tool: D33:  I'm sorry %d isn't in the series!

tool: D42: 
 %d  is a part of Tribonacci Sequence


tool: D44: %d is part of Tribonacci number


tool: D48: %d is part of Tribonacci Sequence


tool: D31: 
 %d  is part of Tribonacci Sequence


assistant: ```c
void checkIfTribonacci(int media) {
  const int number = media;
  int a = 0;
  int b = 1;
  int c = 1;
  int result = 0;
  if (media == 0) {
    result = a;
    printf("%d is part of Tribonacci Sequence\n", result);
  }
  if (media == 1) {
    result = b;
    printf("\n %d  is a part of Tribonacci Sequence\n", result);
  }
  if (media == 2) {
    result = c;
    printf("\n %d  is part of Tribonacci Sequence\n", result);
  }
  while (media > 2) {
    result = a + b + c;
    a = b;
    b = c;
    c = result;
    media--;
    if (result == number) {
      printf("\n");
      printf("%d is part of Tribonacci number\n", number);
      break;
    }
    if (media == 3) {
      printf(" I'm sorry %d isn't in the series!", number);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checkIfTribonacci>:
  endbr64
  test   %edi,%edi
  je     L13
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L54
  cmp    $0x2,%edi
  je     L52
  jle    L25
  mov    %edi,%edx
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  xor    %eax,%eax
  jmp    L51
  nopl   0x0(%rax)
L55:
  mov    %ebp,%eax
  mov    %r12d,%ebp
  cmp    $0x2,%edx
  je     L25
L51:
  add    %ebp,%eax
  mov    %ebx,%r12d
  sub    $0x1,%edx
  add    %eax,%ebx
  cmp    %ebx,%r13d
  je     L22
  cmp    $0x3,%edx
  jne    L55
  add    %ebp,%r12d
  mov    %r13d,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    %ebx,%r12d
  cmp    %r12d,%r13d
  je     L22
L25:
  pop    %rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  mov    $0x1,%esi
  lea    D45(%rip),%rdi
L102:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
  nopl   (%rax)
L22:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13d,%esi
  lea    D0(%rip),%rdi
  jmp    L102
  xchg   %ax,%ax
L13:
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  jmp    1070 <printf@plt>
L52:
  mov    $0x1,%esi
  lea    D47(%rip),%rdi
  jmp    L102
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D45
type: string
name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D47
type: string

tool: D12:  I'm sorry %d isn't in the series!

tool: D45: 
 %d  is a part of Tribonacci Sequence


tool: D0: %d is part of Tribonacci number


tool: D2: %d is part of Tribonacci Sequence


tool: D47: 
 %d  is part of Tribonacci Sequence


assistant: ```c
void checkIfTribonacci(int media) {
  const int number = media;
  int a = 0;
  int b = 1;
  int c = 1;
  int result = 0;
  if (media == 0) {
    result = a;
    printf("%d is part of Tribonacci Sequence\n", result);
  }
  if (media == 1) {
    result = b;
    printf("\n %d  is a part of Tribonacci Sequence\n", result);
  }
  if (media == 2) {
    result = c;
    printf("\n %d  is part of Tribonacci Sequence\n", result);
  }
  while (media > 2) {
    result = a + b + c;
    a = b;
    b = c;
    c = result;
    media--;
    if (result == number) {
      printf("\n");
      printf("%d is part of Tribonacci number\n", number);
      break;
    }
    if (media == 3) {
      printf(" I'm sorry %d isn't in the series!", number);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L90
L2:
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isgraph@plt>
  test   %rax,%rax
  jne    L45
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
L45:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  jmp    L49
L16:
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isgraph@plt>
  test   %rax,%rax
  jne    L16
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L93
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L90:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L24
  jmp    L98
L15:
  nop
  jmp    L98
L93:
  nop
L98:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int split(char *string, char *srgv[], int maxp) {
  int i, m;
  char *ptr;
  i = m = 0;
  while (m < maxp) {
    while (!isgraph((int)string[i]) && string[i])
      i++;
    if (!string[i])
      break;
    srgv[m++] = string + i;
    while (isgraph((int)string[i]))
      i++;
    if (!string[i])
      break;
    string[i++] = '\0';
  }
  return m;
}
```