ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<RSA_padding_add_PKCS1_type_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0xa,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L59
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L22
L59:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2,(%rax)
  mov    -0x1c(%rbp),%eax
  sub    $0x3,%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jg     L71
  mov    $0x0,%eax
  jmp    L22
L71:
  movl   $0x0,-0x10(%rbp)
  jmp    L50
L67:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L97
L65:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jg     L90
  mov    $0x0,%eax
  jmp    L22
L90:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
L97:
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L50:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L67
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x1,%eax
L22:
  leave
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_2(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > (tlen - 11)) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_2, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - flen;
  if (RAND_bytes(p, j) <= 0)
    return (0);
  for (i = 0; i < j; i++) {
    if (*p == '\0')
      do {
        if (RAND_bytes(p, 1) <= 0)
          return (0);
      } while (*p == '\0');
    p++;
  }
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RSA_padding_add_PKCS1_type_2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa(%rsi),%eax
  cmp    %ecx,%eax
  jle    L96
  mov    %rdi,%rbp
  mov    %rdx,%r13
  mov    %ecx,%r12d
  movb   $0x0,(%rdi)
  lea    0x2(%rdi),%rbx
  movb   $0x2,0x1(%rdi)
  lea    -0x3(%rsi),%r14d
  sub    %ecx,%r14d
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <RAND_bytes@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jle    L21
  test   %r14d,%r14d
  jle    L26
  lea    0x2(%r14),%eax
  add    %rax,%rbp
  jmp    L5
L96:
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L21
L82:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L69
L5:
  cmpb   $0x0,(%rbx)
  jne    L82
L37:
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jle    L51
  cmpb   $0x0,(%rbx)
  je     L37
  jmp    L82
L26:
  mov    %rbx,%rbp
L69:
  movb   $0x0,0x0(%rbp)
  lea    0x1(%rbp),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    $0x1,%eax
  jmp    L21
L51:
  mov    $0x0,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_2(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > (tlen - 11)) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_2, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - flen;
  if (RAND_bytes(p, j) <= 0)
    return (0);
  for (i = 0; i < j; i++) {
    if (*p == '\0')
      do {
        if (RAND_bytes(p, 1) <= 0)
          return (0);
      } while (*p == '\0');
    p++;
  }
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RSA_padding_add_PKCS1_type_2>:
  endbr64
  lea    -0xa(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %ecx,%eax
  jle    L24
  mov    $0x200,%eax
  lea    -0x3(%rsi),%ebp
  lea    0x2(%rdi),%rbx
  mov    %rdi,%r14
  mov    %ax,(%rdi)
  sub    %ecx,%ebp
  mov    %rbx,%rdi
  mov    %rdx,%r13
  mov    %ebp,%esi
  mov    %ecx,%r12d
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jle    L94
  test   %ebp,%ebp
  jle    L88
  lea    0x2(%rbp),%eax
  add    %rax,%r14
  jmp    L34
L32:
  add    $0x1,%rbx
  cmp    %rbx,%r14
  je     L13
  nopl   0x0(%rax)
L34:
  cmpb   $0x0,(%rbx)
  je     L71
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L34
L13:
  movb   $0x0,(%r14)
  lea    0x1(%r14),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L16:
  cmpb   $0x0,(%rbx)
  jne    L32
L71:
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jg     L16
L94:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L88:
  mov    %rbx,%r14
  jmp    L13
```

assistant: ```c
int RSA_padding_add_PKCS1_type_2(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > (tlen - 11)) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_2, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - flen;
  if (RAND_bytes(p, j) <= 0)
    return (0);
  for (i = 0; i < j; i++) {
    if (*p == '\0')
      do {
        if (RAND_bytes(p, 1) <= 0)
          return (0);
      } while (*p == '\0');
    p++;
  }
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RSA_padding_add_PKCS1_type_2>:
  endbr64
  lea    -0xa(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %ecx,%eax
  jle    L46
  mov    $0x200,%eax
  lea    -0x3(%rsi),%ebp
  lea    0x2(%rdi),%rbx
  mov    %rdi,%r14
  mov    %ax,(%rdi)
  sub    %ecx,%ebp
  mov    %rbx,%rdi
  mov    %rdx,%r13
  mov    %ebp,%esi
  mov    %ecx,%r12d
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jle    L0
  test   %ebp,%ebp
  jle    L94
  lea    0x2(%rbp),%eax
  add    %rax,%r14
  jmp    L33
L99:
  add    $0x1,%rbx
  cmp    %rbx,%r14
  je     L66
  nopl   0x0(%rax)
L33:
  cmpb   $0x0,(%rbx)
  je     L3
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L33
L66:
  movb   $0x0,(%r14)
  lea    0x1(%r14),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L32:
  cmpb   $0x0,(%rbx)
  jne    L99
L3:
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jg     L32
L0:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L94:
  mov    %rbx,%r14
  jmp    L66
```

assistant: ```c
int RSA_padding_add_PKCS1_type_2(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > (tlen - 11)) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_2, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - flen;
  if (RAND_bytes(p, j) <= 0)
    return (0);
  for (i = 0; i < j; i++) {
    if (*p == '\0')
      do {
        if (RAND_bytes(p, 1) <= 0)
          return (0);
      } while (*p == '\0');
    p++;
  }
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wcsncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L52
L34:
  addq   $0x8,-0x8(%rbp)
  addq   $0x8,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L52:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L15
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L34
L15:
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L56
L10:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L56:
  pop    %rbp
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *s1, const wchar_t *s2, size_t n) {
  while (*s1 && n && (*s1 == *s2)) {
    ++s1;
    ++s2;
    --n;
  }
  if (n == 0) {
    return 0;
  } else {
    return (*(wchar_t *)s1 - *(wchar_t *)s2);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wcsncmp>:
  endbr64
  mov    (%rdi),%rax
  test   %rdx,%rdx
  je     L40
  test   %rax,%rax
  je     L40
L14:
  cmp    %rax,(%rsi)
  jne    L40
  add    $0x8,%rdi
  add    $0x8,%rsi
  mov    (%rdi),%rax
  sub    $0x1,%rdx
  je     L40
  test   %rax,%rax
  jne    L14
L40:
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L56
  mov    %eax,%ecx
  sub    (%rsi),%ecx
L56:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *s1, const wchar_t *s2, size_t n) {
  while (*s1 && n && (*s1 == *s2)) {
    ++s1;
    ++s2;
    --n;
  }
  if (n == 0) {
    return 0;
  } else {
    return (*(wchar_t *)s1 - *(wchar_t *)s2);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<wcsncmp>:
  endbr64
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L27:
  test   %rdx,%rdx
  je     L20
  mov    (%rsi),%rcx
  cmp    %rax,%rcx
  jne    L18
  add    $0x8,%rdi
  add    $0x8,%rsi
  sub    $0x1,%rdx
L48:
  mov    (%rdi),%rax
  test   %rax,%rax
  jne    L27
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L12
  mov    (%rsi),%rcx
L18:
  sub    %ecx,%eax
  ret
  xchg   %ax,%ax
L20:
  xor    %eax,%eax
L12:
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *s1, const wchar_t *s2, size_t n) {
  while (*s1 && n && (*s1 == *s2)) {
    ++s1;
    ++s2;
    --n;
  }
  if (n == 0) {
    return 0;
  } else {
    return (*(wchar_t *)s1 - *(wchar_t *)s2);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<wcsncmp>:
  endbr64
  jmp    L44
  cs nopw 0x0(%rax,%rax,1)
L30:
  test   %rdx,%rdx
  je     L27
  mov    (%rsi),%rcx
  cmp    %rax,%rcx
  jne    L35
  add    $0x8,%rdi
  add    $0x8,%rsi
  sub    $0x1,%rdx
L44:
  mov    (%rdi),%rax
  test   %rax,%rax
  jne    L30
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L33
  mov    (%rsi),%rcx
L35:
  sub    %ecx,%eax
  ret
  xchg   %ax,%ax
L27:
  xor    %eax,%eax
L33:
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *s1, const wchar_t *s2, size_t n) {
  while (*s1 && n && (*s1 == *s2)) {
    ++s1;
    ++s2;
    --n;
  }
  if (n == 0) {
    return 0;
  } else {
    return (*(wchar_t *)s1 - *(wchar_t *)s2);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_signal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L2
  mov    -0x10(%rbp),%eax
  jmp    L21
L2:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int read_signal(int fd) {
  struct signalfd_siginfo info;
  int rc;
  rc = read(fd, &info, sizeof(info));
  if (rc > 0) {
    return info.ssi_signo;
  }
  return -errno;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_signal>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  call   <read@plt>
  test   %eax,%eax
  jg     L7
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  ret
L7:
  mov    0x4(%rsp),%eax
  jmp    L8
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_signal(int fd) {
  struct signalfd_siginfo info;
  int rc;
  rc = read(fd, &info, sizeof(info));
  if (rc > 0) {
    return info.ssi_signo;
  }
  return -errno;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_signal>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L1
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x4(%rsp),%eax
  jmp    L27
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_signal(int fd) {
  struct signalfd_siginfo info;
  int rc;
  rc = read(fd, &info, sizeof(info));
  if (rc > 0) {
    return info.ssi_signo;
  }
  return -errno;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_signal>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L15
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x4(%rsp),%eax
  jmp    L26
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_signal(int fd) {
  struct signalfd_siginfo info;
  int rc;
  rc = read(fd, &info, sizeof(info));
  if (rc > 0) {
    return info.ssi_signo;
  }
  return -errno;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jas_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <jas_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L10
L7:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
void *jas_calloc(size_t nmemb, size_t size) {
  void *ptr;
  size_t n;
  n = nmemb * size;
  if (!(ptr = jas_malloc(n * sizeof(char)))) {
    return 0;
  }
  memset(ptr, 0, n);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jas_calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <jas_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *jas_calloc(size_t nmemb, size_t size) {
  void *ptr;
  size_t n;
  n = nmemb * size;
  if (!(ptr = jas_malloc(n * sizeof(char)))) {
    return 0;
  }
  memset(ptr, 0, n);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jas_calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <jas_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *jas_calloc(size_t nmemb, size_t size) {
  void *ptr;
  size_t n;
  n = nmemb * size;
  if (!(ptr = jas_malloc(n * sizeof(char)))) {
    return 0;
  }
  memset(ptr, 0, n);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jas_calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <jas_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *jas_calloc(size_t nmemb, size_t size) {
  void *ptr;
  size_t n;
  n = nmemb * size;
  if (!(ptr = jas_malloc(n * sizeof(char)))) {
    return 0;
  }
  memset(ptr, 0, n);
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get16@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get16@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D19
type_infered: string

tool: D14: Source port: %d


tool: D19: Destination port: %d


assistant: ```c
void readData(unsigned char **head, int protocol) {
  printf("Source port: %d\n", get16(head));
  printf("Destination port: %d\n", get16(head));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readData>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <get16@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <get16@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string

tool: D16: Source port: %d


tool: D5: Destination port: %d


assistant: ```c
void readData(unsigned char **head, int protocol) {
  printf("Source port: %d\n", get16(head));
  printf("Destination port: %d\n", get16(head));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readData>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <get16@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <get16@plt>
  lea    D1(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string

tool: D10: Source port: %d


tool: D1: Destination port: %d


assistant: ```c
void readData(unsigned char **head, int protocol) {
  printf("Source port: %d\n", get16(head));
  printf("Destination port: %d\n", get16(head));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readData>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <get16@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <get16@plt>
  lea    D8(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D18: Source port: %d


tool: D8: Destination port: %d


assistant: ```c
void readData(unsigned char **head, int protocol) {
  printf("Source port: %d\n", get16(head));
  printf("Destination port: %d\n", get16(head));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<serial_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int serial_close(int fd) {
  close(fd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<serial_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int serial_close(int fd) {
  close(fd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<serial_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int serial_close(int fd) {
  close(fd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<serial_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int serial_close(int fd) {
  close(fd);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; ++i)
    printf("%s ", argv[i]);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L7
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
  lea    D6(%rip),%rbp
L2:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L2
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; ++i)
    printf("%s ", argv[i]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L9
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  lea    D5(%rip),%rbp
L1:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; ++i)
    printf("%s ", argv[i]);
  printf("\n");
  return 0;
}
```