ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<first_part>:
  endbr64
  push   %rbp
  cmpb   $0x2f,(%rdi)
  mov    %rdi,%r8
  mov    %rsi,%rbp
  je     L0
L36:
  mov    %r8,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L24
  movb   $0x0,(%rax)
L24:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  cmpb   $0x0,0x1(%rdi)
  lea    0x1(%rdi),%rax
  jne    L43
  movb   $0x0,(%rsi)
  mov    %rax,%r8
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %rax,%r8
  jmp    L36
```

assistant: ```c
void first_part(char *pathname, char *firstpart) {
  char *p = pathname;
  char *p2;
  if (*p == '/') {
    p++;
    if (*p == '\0') {
      firstpart[0] = '\0';
    }
  }
  strcpy(firstpart, p);
  p2 = strchr(firstpart, '/');
  if (p2 == NULL) {
  } else {
    *p2 = '\0';
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<numDigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jg     L3
  mov    $0x1,%eax
  jmp    L11
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <numDigits>
  add    $0x1,%eax
L11:
  leave
  ret
```

assistant: ```c
int numDigits(int a) {
  if (a < 10) {
    return 1;
  }
  return 1 + numDigits(a / 10);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<numDigits>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x9,%edi
  jg     L3
  ret
L3:
  sub    $0x8,%rsp
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edi
  call   <numDigits>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int numDigits(int a) {
  if (a < 10) {
    return 1;
  }
  return 1 + numDigits(a / 10);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<numDigits>:
  endbr64
  mov    $0x1,%edx
  mov    $0xcccccccd,%esi
  cmp    $0x9,%edi
  jle    L8
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edi,%edi
  add    $0x1,%edx
  mov    %rdi,%rcx
  imul   %rsi,%rdi
  shr    $0x23,%rdi
  cmp    $0x63,%ecx
  jg     L2
  mov    %edx,%eax
  ret
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int numDigits(int a) {
  if (a < 10) {
    return 1;
  }
  return 1 + numDigits(a / 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<numDigits>:
  endbr64
  mov    $0x1,%edx
  mov    $0xcccccccd,%esi
  cmp    $0x9,%edi
  jle    L9
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %edi,%edi
  add    $0x1,%edx
  mov    %rdi,%rcx
  imul   %rsi,%rdi
  shr    $0x23,%rdi
  cmp    $0x63,%ecx
  jg     L7
  mov    %edx,%eax
  ret
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int numDigits(int a) {
  if (a < 10) {
    return 1;
  }
  return 1 + numDigits(a / 10);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
time_t time(time_t *t) {
  errno = ENOSYS;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<time>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
time_t time(time_t *t) {
  errno = ENOSYS;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<time>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
time_t time(time_t *t) {
  errno = ENOSYS;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<time>:
  endbr64
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
time_t time(time_t *t) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L11:
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D16(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rdx
  mov    -0x4(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x14,-0x4(%rbp)
L8:
  cmpl   $0x12c,-0x4(%rbp)
  jle    L11
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type_infered: byte[8]
name: read_data
arguments: tag: D11
type_infered: string

tool: {"D16": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D11: %3d %6.1f 


assistant: ```c
main() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr = fahr + 20)
    printf("%3d %6.1f \n", fahr, (5.0 / 9.0) * (fahr - 32));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D9(%rip),%rbp
L5:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D0(%rip),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  cmp    $0x140,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D0
data_type: byte[8]

tool: D9: %3d %6.1f 


tool: {"D0": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr = fahr + 20)
    printf("%3d %6.1f \n", fahr, (5.0 / 9.0) * (fahr - 32));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D19(%rip),%xmm0
  add    $0x14,%ebx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D19
type: byte[8]

tool: D11: %3d %6.1f 


tool: {"D19": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr = fahr + 20)
    printf("%3d %6.1f \n", fahr, (5.0 / 9.0) * (fahr - 32));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D13(%rip),%xmm0
  add    $0x14,%ebx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D13
datatype: byte[8]

tool: D5: %3d %6.1f 


tool: {"D13": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr = fahr + 20)
    printf("%3d %6.1f \n", fahr, (5.0 / 9.0) * (fahr - 32));
}
```
user: Translate the below assembly code into C programming language:

```asm
<getSortedFilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D9: sorted_

assistant: ```c
char *getSortedFilename(char *fName) {
  char *sortedName = "sorted_";
  char *newName = (char *)malloc(strlen(sortedName) + strlen(fName));
  strcpy(newName, sortedName);
  strcat(newName, fName);
  newName[strlen(newName)] = '\0';
  return newName;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getSortedFilename>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x7(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: D8: sorted_

assistant: ```c
char *getSortedFilename(char *fName) {
  char *sortedName = "sorted_";
  char *newName = (char *)malloc(strlen(sortedName) + strlen(fName));
  strcpy(newName, sortedName);
  strcat(newName, fName);
  newName[strlen(newName)] = '\0';
  return newName;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getSortedFilename>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x7(%rax),%rdi
  call   <malloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: sorted_

assistant: ```c
char *getSortedFilename(char *fName) {
  char *sortedName = "sorted_";
  char *newName = (char *)malloc(strlen(sortedName) + strlen(fName));
  strcpy(newName, sortedName);
  strcat(newName, fName);
  newName[strlen(newName)] = '\0';
  return newName;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getSortedFilename>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x7(%rax),%rdi
  call   <malloc@plt>
  lea    D0(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: sorted_

assistant: ```c
char *getSortedFilename(char *fName) {
  char *sortedName = "sorted_";
  char *newName = (char *)malloc(strlen(sortedName) + strlen(fName));
  strcpy(newName, sortedName);
  strcat(newName, fName);
  newName[strlen(newName)] = '\0';
  return newName;
}
```
user: What is the c source code of the assembly code below?

```asm
<smb_load_modules>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <DEBUG@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: This samba executable has not been built with plugin support


assistant: ```c
int smb_load_modules(const char **modules) {
  DEBUG(0, ("This samba executable has not been built with plugin support\n"));
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<smb_load_modules>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  mov    $0x0,%edi
  call   <DEBUG@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: This samba executable has not been built with plugin support


assistant: ```c
int smb_load_modules(const char **modules) {
  DEBUG(0, ("This samba executable has not been built with plugin support\n"));
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<smb_load_modules>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  xor    %edi,%edi
  call   <DEBUG@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: This samba executable has not been built with plugin support


assistant: ```c
int smb_load_modules(const char **modules) {
  DEBUG(0, ("This samba executable has not been built with plugin support\n"));
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<smb_load_modules>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  xor    %edi,%edi
  call   <DEBUG@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: This samba executable has not been built with plugin support


assistant: ```c
int smb_load_modules(const char **modules) {
  DEBUG(0, ("This samba executable has not been built with plugin support\n"));
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strsplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  movl   $0x0,-0x2c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L61
L18:
  movl   $0x0,-0x30(%rbp)
  jmp    L73
L88:
  cmpl   $0x0,-0x30(%rbp)
  jne    L67
  mov    -0x28(%rbp),%rax
  jmp    L57
L67:
  mov    $0x0,%eax
L57:
  mov    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L44
  jmp    L86
L50:
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x30(%rbp)
L86:
  mov    -0x30(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L50
  mov    -0x20(%rbp),%rax
  jmp    L61
L44:
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x30(%rbp)
L73:
  mov    -0x30(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L88
  mov    -0x20(%rbp),%rax
L61:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **strsplit(const char *str, const char *delimiter, int max) {
  char **result;
  char *workstring;
  int count = 0;
  int i;
  workstring = strdup(str);
  result = malloc(sizeof(char *) * max);
  if (!result) {
    return (NULL);
  }
  for (i = 0; i < max; i++) {
    char *token = strtok((i == 0) ? workstring : NULL, delimiter);
    if (!token) {
      for (; i < max; i++) {
        result[i] = NULL;
      }
      return (result);
    }
    result[i] = strdup(token);
  }
  return (result);
}
```
user: What is the c source code of the assembly code below:

```asm
<strsplit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %edx,0x8(%rsp)
  call   <strdup@plt>
  mov    %rax,%r12
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  test   %ebx,%ebx
  jle    L27
  lea    -0x1(%rbx),%eax
  mov    %eax,0xc(%rsp)
  mov    %ebx,%r15d
  mov    $0x0,%ebx
  mov    $0x0,%r14d
L4:
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  mov    %r14,%rdi
  cmove  %r12,%rdi
  mov    %r13,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L23
  call   <strdup@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L4
L27:
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    0x4(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  jle    L27
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,8),%rax
  mov    0xc(%rsp),%ecx
  sub    %ebx,%ecx
  add    %rcx,%rdx
  lea    0x8(%rbp,%rdx,8),%rdx
L5:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L5
  jmp    L27
```

assistant: ```c
char **strsplit(const char *str, const char *delimiter, int max) {
  char **result;
  char *workstring;
  int count = 0;
  int i;
  workstring = strdup(str);
  result = malloc(sizeof(char *) * max);
  if (!result) {
    return (NULL);
  }
  for (i = 0; i < max; i++) {
    char *token = strtok((i == 0) ? workstring : NULL, delimiter);
    if (!token) {
      for (; i < max; i++) {
        result[i] = NULL;
      }
      return (result);
    }
    result[i] = strdup(token);
  }
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strsplit>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  call   <strdup@plt>
  lea    0x0(,%r14,8),%edi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  test   %r14d,%r14d
  jle    L2
  lea    -0x1(%r14),%eax
  mov    (%rsp),%r8
  mov    %r14d,%r13d
  xor    %r15d,%r15d
  mov    %eax,0xc(%rsp)
  jmp    L18
  nop
L23:
  call   <strdup@plt>
  xor    %r8d,%r8d
  mov    %rax,(%r12,%r15,8)
  add    $0x1,%r15
  cmp    %r15,%r13
  je     L2
L18:
  mov    %r8,%rdi
  mov    %rbx,%rsi
  movslq %r15d,%rbp
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L23
  mov    0xc(%rsp),%r15d
  mov    $0x8,%eax
  lea    (%r12,%rbp,8),%rdi
  sub    %ebp,%r15d
  cmp    %ebp,%r14d
  lea    0x8(,%r15,8),%rdx
  cmovle %rax,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L2:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **strsplit(const char *str, const char *delimiter, int max) {
  char **result;
  char *workstring;
  int count = 0;
  int i;
  workstring = strdup(str);
  result = malloc(sizeof(char *) * max);
  if (!result) {
    return (NULL);
  }
  for (i = 0; i < max; i++) {
    char *token = strtok((i == 0) ? workstring : NULL, delimiter);
    if (!token) {
      for (; i < max; i++) {
        result[i] = NULL;
      }
      return (result);
    }
    result[i] = strdup(token);
  }
  return (result);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strsplit>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  call   <strdup@plt>
  lea    0x0(,%r14,8),%edi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
  test   %r14d,%r14d
  jle    L13
  lea    -0x1(%r14),%eax
  mov    (%rsp),%r8
  mov    %r14d,%r13d
  xor    %r15d,%r15d
  mov    %eax,0xc(%rsp)
  jmp    L5
  nop
L33:
  call   <strdup@plt>
  xor    %r8d,%r8d
  mov    %rax,(%r12,%r15,8)
  add    $0x1,%r15
  cmp    %r15,%r13
  je     L13
L5:
  mov    %r8,%rdi
  mov    %rbx,%rsi
  movslq %r15d,%rbp
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L33
  mov    0xc(%rsp),%r15d
  mov    $0x8,%eax
  lea    (%r12,%rbp,8),%rdi
  sub    %ebp,%r15d
  cmp    %ebp,%r14d
  lea    0x8(,%r15,8),%rdx
  cmovle %rax,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L13:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **strsplit(const char *str, const char *delimiter, int max) {
  char **result;
  char *workstring;
  int count = 0;
  int i;
  workstring = strdup(str);
  result = malloc(sizeof(char *) * max);
  if (!result) {
    return (NULL);
  }
  for (i = 0; i < max; i++) {
    char *token = strtok((i == 0) ? workstring : NULL, delimiter);
    if (!token) {
      for (; i < max; i++) {
        result[i] = NULL;
      }
      return (result);
    }
    result[i] = strdup(token);
  }
  return (result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  and    $0xf,%eax
  cltq
  lea    D9(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
char to_hex(char code) {
  static char hex[] = "0123456789abcdef";
  return hex[code & 15];
}
```
user: Translate the below assembly code into C programming language:

```asm
<to_hex>:
  endbr64
  and    $0xf,%edi
  lea    D0(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: 0123456789abcdef

assistant: ```c
char to_hex(char code) {
  static char hex[] = "0123456789abcdef";
  return hex[code & 15];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<to_hex>:
  endbr64
  and    $0xf,%edi
  lea    D0(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: 0123456789abcdef

assistant: ```c
char to_hex(char code) {
  static char hex[] = "0123456789abcdef";
  return hex[code & 15];
}
```
user: What is the c source code of the assembly code below?

```asm
<to_hex>:
  endbr64
  and    $0xf,%edi
  lea    D6(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: 0123456789abcdef

assistant: ```c
char to_hex(char code) {
  static char hex[] = "0123456789abcdef";
  return hex[code & 15];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<modmap_not_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L5
  mov    $0x1,%eax
  jmp    L21
L5:
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x6,-0x4(%rbp)
  jle    L9
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int modmap_not_empty(char *modmap) {
  int i;
  for (i = 0; i < 7; i++)
    if (modmap[i] != ' ') {
      return 1;
    }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<modmap_not_empty>:
  endbr64
  lea    0x7(%rdi),%rax
L9:
  cmpb   $0x20,(%rdi)
  jne    L14
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L9
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int modmap_not_empty(char *modmap) {
  int i;
  for (i = 0; i < 7; i++)
    if (modmap[i] != ' ') {
      return 1;
    }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<modmap_not_empty>:
  endbr64
  lea    0x7(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L3:
  cmpb   $0x20,(%rdi)
  jne    L2
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int modmap_not_empty(char *modmap) {
  int i;
  for (i = 0; i < 7; i++)
    if (modmap[i] != ' ') {
      return 1;
    }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<modmap_not_empty>:
  endbr64
  cmpb   $0x20,(%rdi)
  jne    L7
  cmpb   $0x20,0x1(%rdi)
  jne    L7
  cmpb   $0x20,0x2(%rdi)
  jne    L7
  cmpb   $0x20,0x3(%rdi)
  jne    L7
  cmpb   $0x20,0x4(%rdi)
  jne    L7
  cmpb   $0x20,0x5(%rdi)
  jne    L7
  xor    %eax,%eax
  cmpb   $0x20,0x6(%rdi)
  setne  %al
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int modmap_not_empty(char *modmap) {
  int i;
  for (i = 0; i < 7; i++)
    if (modmap[i] != ' ') {
      return 1;
    }
  return 0;
}
```