ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L5
  mov    $0x1,%eax
  xchg   %ax,%ax
L1:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L1
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strlen(char *str) {
  int a;
  a = 0;
  while (str[a] != '\0') {
    a++;
  }
  return (a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x1,%eax
  xchg   %ax,%ax
L2:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L2
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strlen(char *str) {
  int a;
  a = 0;
  while (str[a] != '\0') {
    a++;
  }
  return (a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <scheduler@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D11: Starting Main!

tool: D13: Exiting, exit value=%d

assistant: ```c
int main(int charc, char *argv) {
  printf("Starting Main!\n");
  int ex_val = scheduler();
  printf("Exiting, exit value=%d", ex_val);
  return ex_val;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <scheduler@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string

tool: D14: Starting Main!

tool: D15: Exiting, exit value=%d

assistant: ```c
int main(int charc, char *argv) {
  printf("Starting Main!\n");
  int ex_val = scheduler();
  printf("Exiting, exit value=%d", ex_val);
  return ex_val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <scheduler@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string

tool: D0: Starting Main!

tool: D12: Exiting, exit value=%d

assistant: ```c
int main(int charc, char *argv) {
  printf("Starting Main!\n");
  int ex_val = scheduler();
  printf("Exiting, exit value=%d", ex_val);
  return ex_val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <scheduler@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D5: Starting Main!

tool: D4: Exiting, exit value=%d

assistant: ```c
int main(int charc, char *argv) {
  printf("Starting Main!\n");
  int ex_val = scheduler();
  printf("Exiting, exit value=%d", ex_val);
  return ex_val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_from_rgb_to_grey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L6:
  movb   $0x0,-0x15(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <luma@plt>
  and    $0xf0,%eax
  mov    %eax,%edx
  movzbl -0x15(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x15(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x5(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x4(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x3(%rax),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <luma@plt>
  sar    $0x4,%eax
  mov    %eax,%edx
  movzbl -0x15(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x15(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void copy_from_rgb_to_grey(unsigned char *rgb_data, int rgb_len, unsigned char *grey_buf, int grey_len) {
  unsigned char *rgb = rgb_data;
  int len = min(rgb_len, grey_len);
  for (int grey_idx = 0; grey_idx < len; grey_idx++) {
    unsigned char grey_byte = 0;
    int i = grey_idx * 6;
    grey_byte |= luma(rgb[i], rgb[i + 1], rgb[i + 2]) & 0xF0;
    grey_byte |= luma(rgb[i + 3], rgb[i + 4], rgb[i + 5]) >> 4;
    grey_buf[grey_idx] = grey_byte;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_from_rgb_to_grey>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %rdx,%rbp
  mov    %ecx,%esi
  call   <min@plt>
  test   %eax,%eax
  jle    L3
  mov    %rbp,%r12
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%r13
L10:
  movzbl 0x2(%rbx),%edx
  movzbl 0x1(%rbx),%esi
  movzbl (%rbx),%edi
  call   <luma@plt>
  mov    %eax,%ebp
  movzbl 0x5(%rbx),%edx
  movzbl 0x4(%rbx),%esi
  movzbl 0x3(%rbx),%edi
  call   <luma@plt>
  and    $0xf0,%ebp
  sar    $0x4,%eax
  or     %eax,%ebp
  mov    %bpl,(%r12)
  add    $0x6,%rbx
  add    $0x1,%r12
  cmp    %r13,%r12
  jne    L10
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void copy_from_rgb_to_grey(unsigned char *rgb_data, int rgb_len, unsigned char *grey_buf, int grey_len) {
  unsigned char *rgb = rgb_data;
  int len = min(rgb_len, grey_len);
  for (int grey_idx = 0; grey_idx < len; grey_idx++) {
    unsigned char grey_byte = 0;
    int i = grey_idx * 6;
    grey_byte |= luma(rgb[i], rgb[i + 1], rgb[i + 2]) & 0xF0;
    grey_byte |= luma(rgb[i + 3], rgb[i + 4], rgb[i + 5]) >> 4;
    grey_buf[grey_idx] = grey_byte;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy_from_rgb_to_grey>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %ecx,%esi
  sub    $0x8,%rsp
  call   <min@plt>
  test   %eax,%eax
  jle    L16
  sub    $0x1,%eax
  lea    0x1(%r12,%rax,1),%r13
  nopl   0x0(%rax)
L8:
  movzbl 0x2(%rbx),%edx
  movzbl 0x1(%rbx),%esi
  add    $0x1,%r12
  add    $0x6,%rbx
  movzbl -0x6(%rbx),%edi
  call   <luma@plt>
  movzbl -0x1(%rbx),%edx
  movzbl -0x2(%rbx),%esi
  movzbl -0x3(%rbx),%edi
  mov    %eax,%ebp
  and    $0xf0,%ebp
  call   <luma@plt>
  sar    $0x4,%eax
  or     %eax,%ebp
  mov    %bpl,-0x1(%r12)
  cmp    %r12,%r13
  jne    L8
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void copy_from_rgb_to_grey(unsigned char *rgb_data, int rgb_len, unsigned char *grey_buf, int grey_len) {
  unsigned char *rgb = rgb_data;
  int len = min(rgb_len, grey_len);
  for (int grey_idx = 0; grey_idx < len; grey_idx++) {
    unsigned char grey_byte = 0;
    int i = grey_idx * 6;
    grey_byte |= luma(rgb[i], rgb[i + 1], rgb[i + 2]) & 0xF0;
    grey_byte |= luma(rgb[i + 3], rgb[i + 4], rgb[i + 5]) >> 4;
    grey_buf[grey_idx] = grey_byte;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_from_rgb_to_grey>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %ecx,%esi
  sub    $0x8,%rsp
  call   <min@plt>
  test   %eax,%eax
  jle    L16
  sub    $0x1,%eax
  lea    0x1(%r12,%rax,1),%r13
  nopl   0x0(%rax)
L19:
  movzbl 0x2(%rbx),%edx
  movzbl 0x1(%rbx),%esi
  add    $0x1,%r12
  add    $0x6,%rbx
  movzbl -0x6(%rbx),%edi
  call   <luma@plt>
  movzbl -0x1(%rbx),%edx
  movzbl -0x2(%rbx),%esi
  movzbl -0x3(%rbx),%edi
  mov    %eax,%ebp
  and    $0xf0,%ebp
  call   <luma@plt>
  sar    $0x4,%eax
  or     %eax,%ebp
  mov    %bpl,-0x1(%r12)
  cmp    %r12,%r13
  jne    L19
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void copy_from_rgb_to_grey(unsigned char *rgb_data, int rgb_len, unsigned char *grey_buf, int grey_len) {
  unsigned char *rgb = rgb_data;
  int len = min(rgb_len, grey_len);
  for (int grey_idx = 0; grey_idx < len; grey_idx++) {
    unsigned char grey_byte = 0;
    int i = grey_idx * 6;
    grey_byte |= luma(rgb[i], rgb[i + 1], rgb[i + 2]) & 0xF0;
    grey_byte |= luma(rgb[i + 3], rgb[i + 4], rgb[i + 5]) >> 4;
    grey_buf[grey_idx] = grey_byte;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skipws>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  jmp    L17
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L17:
  movzbl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hxd_isspace@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  leave
  ret
```

assistant: ```c
unsigned char skipws(const unsigned char **fmt, _Bool nlok) {
  while (hxd_isspace(**fmt, nlok))
    ++*fmt;
  return **fmt;
}
```
user: What is the c source code of the assembly code below?

```asm
<skipws>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl %sil,%ebp
  jmp    L17
L2:
  addq   $0x1,(%rbx)
L17:
  mov    (%rbx),%rax
  movzbl (%rax),%edi
  mov    %ebp,%esi
  call   <hxd_isspace@plt>
  test   %rax,%rax
  jne    L2
  mov    (%rbx),%rax
  movzbl (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char skipws(const unsigned char **fmt, _Bool nlok) {
  while (hxd_isspace(**fmt, nlok))
    ++*fmt;
  return **fmt;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skipws>:
  endbr64
  push   %rbp
  movzbl %sil,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x1,%rax
  mov    %rax,(%rbx)
L9:
  movzbl (%rax),%edi
  mov    %ebp,%esi
  call   <hxd_isspace@plt>
  test   %rax,%rax
  mov    (%rbx),%rax
  jne    L19
  movzbl (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char skipws(const unsigned char **fmt, _Bool nlok) {
  while (hxd_isspace(**fmt, nlok))
    ++*fmt;
  return **fmt;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skipws>:
  endbr64
  push   %rbp
  movzbl %sil,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L13:
  add    $0x1,%rax
  mov    %rax,(%rbx)
L19:
  movzbl (%rax),%edi
  mov    %ebp,%esi
  call   <hxd_isspace@plt>
  test   %rax,%rax
  mov    (%rbx),%rax
  jne    L13
  movzbl (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char skipws(const unsigned char **fmt, _Bool nlok) {
  while (hxd_isspace(**fmt, nlok))
    ++*fmt;
  return **fmt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  cmpl   $0x0,0x4(%rsp)
  jle    L40
  mov    %rax,%rbp
  mov    $0x0,%r12d
  lea    D37(%rip),%r13
L37:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    0x4(%rsp),%esi
  add    $0x8,%rbp
  cmp    %r12d,%esi
  jg     L37
  test   %esi,%esi
  jle    L40
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L77:
  add    $0x2,%esi
  mov    %esi,0x4(%rsp)
  shl    $0x3,%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%ecx
  lea    -0x3(%rcx),%eax
  cmp    %r12d,%eax
  jle    L64
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    (%rbx,%rdx,1),%rax
  lea    -0x8(%rbx,%rdx,1),%rdx
  sub    $0x4,%ecx
  sub    %r12d,%ecx
  shl    $0x3,%rcx
  sub    %rcx,%rdx
L63:
  movsd  (%rax),%xmm0
  movsd  %xmm0,0x10(%rax)
  sub    $0x8,%rax
  cmp    %rdx,%rax
  jne    L63
L64:
  lea    (%rbx,%rbp,1),%rax
  cvttsd2si (%rax),%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  movsd  %xmm1,0x8(%rbx,%rbp,1)
  movsd  (%rax),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbx,%rbp,1)
  add    $0x3,%r12d
  mov    0x4(%rsp),%esi
  add    $0x18,%rbp
  cmp    %r12d,%esi
  jg     L77
L40:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L78
  mov    $0x0,%ebp
  lea    D11(%rip),%r12
L13:
  movsd  (%rbx,%rbp,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbp
  cmp    %ebp,0x4(%rsp)
  jg     L13
L78:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D37
type: string
name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D11
type: string

tool: D22: %d

tool: D37: %lf

tool: D0: Sirul obtinut: 

tool: D11: %.3lf 


assistant: ```c
int main() {
  double *sir;
  int n;
  scanf("%d", &n);
  sir = (double *)malloc(n * sizeof(double));
  for (int i = 0; i < n; i++) {
    scanf("%lf", &sir[i]);
  }
  for (int i = 0; i < n; i++) {
    n += 2;
    sir = (double *)realloc(sir, n * sizeof(double));
    for (int k = n - 3; k >= i + 1; k--)
      sir[k + 2] = sir[k];
    int intreg = sir[i];
    sir[i + 1] = intreg;
    sir[i + 2] = sir[i] - intreg;
    i += 2;
  }
  printf("Sirul obtinut: \n");
  for (int i = 0; i < n; i++) {
    printf("%.3lf \n", sir[i]);
  }
  printf("\n");
  free(sir);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D15(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  mov    %rax,%rbp
  test   %edx,%edx
  jle    L3
  mov    %rax,%r13
  xor    %r12d,%r12d
  lea    D2(%rip),%r14
  nopl   (%rax)
L33:
  mov    %r13,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  add    $0x8,%r13
  cmp    %r12d,%ebx
  jg     L33
  test   %ebx,%ebx
  jle    L3
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L56:
  add    $0x2,%ebx
  mov    %rbp,%rdi
  lea    0x0(,%rbx,8),%esi
  mov    %ebx,0x4(%rsp)
  call   <realloc@plt>
  mov    0x4(%rsp),%ebx
  mov    %rax,%rbp
  lea    -0x3(%rbx),%eax
  cmp    %r13d,%eax
  jle    L24
  mov    %ebx,%eax
  sub    %r13d,%eax
  lea    -0x4(%rax),%edx
  lea    -0x1(%rbx),%eax
  mov    %rdx,%rdi
  cltq
  lea    0x8(,%rdx,8),%rdx
  neg    %rdi
  shl    $0x3,%rax
  shl    $0x3,%rdi
  lea    -0x10(%rax,%rdi,1),%rsi
  add    %rax,%rdi
  add    %rbp,%rsi
  add    %rbp,%rdi
  call   <memmove@plt>
L24:
  lea    0x0(%rbp,%r12,1),%rax
  pxor   %xmm1,%xmm1
  add    $0x3,%r13d
  cvttsd2si (%rax),%edx
  cvtsi2sd %edx,%xmm1
  movsd  %xmm1,0x8(%rbp,%r12,1)
  movsd  (%rax),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp,%r12,1)
  add    $0x18,%r12
  cmp    %r13d,%ebx
  jg     L56
L3:
  lea    D9(%rip),%rdi
  xor    %ebx,%ebx
  lea    D6(%rip),%r12
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L12
L15:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L15
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string
name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D15: %d

tool: D2: %lf

tool: D9: Sirul obtinut: 

tool: D6: %.3lf 


assistant: ```c
int main() {
  double *sir;
  int n;
  scanf("%d", &n);
  sir = (double *)malloc(n * sizeof(double));
  for (int i = 0; i < n; i++) {
    scanf("%lf", &sir[i]);
  }
  for (int i = 0; i < n; i++) {
    n += 2;
    sir = (double *)realloc(sir, n * sizeof(double));
    for (int k = n - 3; k >= i + 1; k--)
      sir[k + 2] = sir[k];
    int intreg = sir[i];
    sir[i + 1] = intreg;
    sir[i + 2] = sir[i] - intreg;
    i += 2;
  }
  printf("Sirul obtinut: \n");
  for (int i = 0; i < n; i++) {
    printf("%.3lf \n", sir[i]);
  }
  printf("\n");
  free(sir);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  mov    %rax,%rbp
  test   %edx,%edx
  jle    L63
  mov    %rax,%r13
  xor    %r12d,%r12d
  lea    D20(%rip),%r14
  nopl   (%rax)
L58:
  mov    %r13,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  add    $0x8,%r13
  cmp    %r12d,%ebx
  jg     L58
  test   %ebx,%ebx
  jle    L63
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L8:
  add    $0x2,%ebx
  mov    %rbp,%rdi
  lea    0x0(,%rbx,8),%esi
  mov    %ebx,0x4(%rsp)
  call   <realloc@plt>
  mov    0x4(%rsp),%ebx
  mov    %rax,%rbp
  lea    -0x3(%rbx),%eax
  cmp    %r13d,%eax
  jle    L44
  mov    %ebx,%eax
  sub    %r13d,%eax
  lea    -0x4(%rax),%edx
  lea    -0x1(%rbx),%eax
  mov    %rdx,%rdi
  cltq
  lea    0x8(,%rdx,8),%rdx
  neg    %rdi
  shl    $0x3,%rax
  shl    $0x3,%rdi
  lea    -0x10(%rax,%rdi,1),%rsi
  add    %rax,%rdi
  add    %rbp,%rsi
  add    %rbp,%rdi
  call   <memmove@plt>
L44:
  lea    0x0(%rbp,%r12,1),%rax
  pxor   %xmm1,%xmm1
  add    $0x3,%r13d
  cvttsd2si (%rax),%edx
  cvtsi2sd %edx,%xmm1
  movsd  %xmm1,0x8(%rbp,%r12,1)
  movsd  (%rax),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp,%r12,1)
  add    $0x18,%r12
  cmp    %r13d,%ebx
  jg     L8
L63:
  lea    D27(%rip),%rdi
  xor    %ebx,%ebx
  lea    D34(%rip),%r12
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L22
L48:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L48
L22:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D20
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D34
datatype: string

tool: D6: %d

tool: D20: %lf

tool: D27: Sirul obtinut: 

tool: D34: %.3lf 


assistant: ```c
int main() {
  double *sir;
  int n;
  scanf("%d", &n);
  sir = (double *)malloc(n * sizeof(double));
  for (int i = 0; i < n; i++) {
    scanf("%lf", &sir[i]);
  }
  for (int i = 0; i < n; i++) {
    n += 2;
    sir = (double *)realloc(sir, n * sizeof(double));
    for (int k = n - 3; k >= i + 1; k--)
      sir[k + 2] = sir[k];
    int intreg = sir[i];
    sir[i + 1] = intreg;
    sir[i + 2] = sir[i] - intreg;
    i += 2;
  }
  printf("Sirul obtinut: \n");
  for (int i = 0; i < n; i++) {
    printf("%.3lf \n", sir[i]);
  }
  printf("\n");
  free(sir);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CInc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L8
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <SkipComments@plt>
  jmp    L17
L8:
  nop
L17:
  leave
  ret
```

assistant: ```c
void CInc(ptr) char **ptr;
{
  if (**ptr != '\0')
    (*ptr)++;
  else
    return;
  SkipComments(ptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CInc>:
  endbr64
  mov    (%rdi),%rax
  cmpb   $0x0,(%rax)
  jne    L8
  ret
L8:
  sub    $0x8,%rsp
  add    $0x1,%rax
  mov    %rax,(%rdi)
  mov    $0x0,%eax
  call   <SkipComments@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void CInc(ptr) char **ptr;
{
  if (**ptr != '\0')
    (*ptr)++;
  else
    return;
  SkipComments(ptr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CInc>:
  endbr64
  mov    (%rdi),%rax
  cmpb   $0x0,(%rax)
  jne    L1
  ret
  nopl   (%rax)
L1:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  xor    %eax,%eax
  jmp    1050 <SkipComments@plt>
```

assistant: ```c
void CInc(ptr) char **ptr;
{
  if (**ptr != '\0')
    (*ptr)++;
  else
    return;
  SkipComments(ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CInc>:
  endbr64
  mov    (%rdi),%rax
  cmpb   $0x0,(%rax)
  jne    L8
  ret
  nopl   (%rax)
L8:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  xor    %eax,%eax
  jmp    1050 <SkipComments@plt>
```

assistant: ```c
void CInc(ptr) char **ptr;
{
  if (**ptr != '\0')
    (*ptr)++;
  else
    return;
  SkipComments(ptr);
}
```