ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L31
L126:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L126
L31:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L8
L3:
  mov    %rsp,%rbx
  test   %ecx,%ecx
  jle    L37
  mov    %rbx,%r13
  xor    %r12d,%r12d
L12:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L12
L37:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    -0x2c(%rbp),%r9d
  cmp    $0x1,%r9d
  jle    L48
  mov    %r9d,%eax
  lea    0x4(%rbx),%r8
  cs nopw 0x0(%rax,%rax,1)
L52:
  lea    -0x1(%rax),%edi
  test   %eax,%eax
  jle    L115
  sub    $0x1,%eax
  mov    %rbx,%rdx
  mov    %rax,%rdi
  lea    (%r8,%rax,4),%rsi
  nopl   0x0(%rax)
L66:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jge    L6
  movq   %xmm1,(%rdx)
L6:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L66
L115:
  mov    %edi,%eax
  cmp    $0x1,%edi
  jne    L52
L48:
  test   %r9d,%r9d
  jle    L91
  xor    %r12d,%r12d
  lea    D16(%rip),%r13
  nopl   (%rax)
L93:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L93
L91:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L136
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L8:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L3
L136:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D16
data_type: string

tool: D9: %d

tool: D13: input done.

tool: D16: %d 

assistant: ```c
int main() {
  int i, j, tmp, n;
  scanf("%d", &n);
  int target[n];
  for (i = 0; i < n; i++)
    scanf("%d", &target[i]);
  printf("input done.\n");
  for (i = 0; i < n - 1; i++) {
    for (j = 0; j < n - i; j++) {
      if (target[j] < target[j + 1]) {
        tmp = target[j];
        target[j] = target[j + 1];
        target[j + 1] = tmp;
      }
    }
  }
  for (i = 0; i < n; i++)
    printf("%d ", target[i]);
  printf("\n");
  getchar();
  getchar();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_strtoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  mov    $0x0,%eax
  jmp    L8
L26:
  cmpq   $0x4,-0x38(%rbp)
  jbe    L28
  movq   $0x4,-0x38(%rbp)
L28:
  mov    -0x38(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x4,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
size_t convert_strtoint(const char *value, void *res, size_t len) {
  char *end;
  unsigned int i = strtol(value, &end, 10);
  if (*end != '\0')
    return 0;
  if (len > sizeof(i))
    len = sizeof(i);
  memcpy(res, &i, len);
  return sizeof(i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_strtoint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    %eax,0xc(%rsp)
  mov    $0x0,%eax
  mov    0x10(%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L3
L19:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x4,%eax
  cmp    %rax,%rbx
  cmovbe %rbx,%rax
  mov    %rax,%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x4,%eax
  jmp    L19
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t convert_strtoint(const char *value, void *res, size_t len) {
  char *end;
  unsigned int i = strtol(value, &end, 10);
  if (*end != '\0')
    return 0;
  if (len > sizeof(i))
    len = sizeof(i);
  memcpy(res, &i, len);
  return sizeof(i);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<convert_strtoint>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0xa,%edx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <strtol@plt>
  mov    0x10(%rsp),%rdx
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  jne    L2
  mov    $0x4,%eax
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  cmp    %rax,%rbx
  cmovbe %rbx,%rax
  mov    %rax,%rdx
  call   <memcpy@plt>
  mov    $0x4,%eax
L2:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t convert_strtoint(const char *value, void *res, size_t len) {
  char *end;
  unsigned int i = strtol(value, &end, 10);
  if (*end != '\0')
    return 0;
  if (len > sizeof(i))
    len = sizeof(i);
  memcpy(res, &i, len);
  return sizeof(i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<convert_strtoint>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0xa,%edx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <strtol@plt>
  mov    0x10(%rsp),%rdx
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  jne    L1
  mov    $0x4,%eax
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  cmp    %rax,%rbx
  cmovbe %rbx,%rax
  mov    %rax,%rdx
  call   <memcpy@plt>
  mov    $0x4,%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t convert_strtoint(const char *value, void *res, size_t len) {
  char *end;
  unsigned int i = strtol(value, &end, 10);
  if (*end != '\0')
    return 0;
  if (len > sizeof(i))
    len = sizeof(i);
  memcpy(res, &i, len);
  return sizeof(i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<float_gt_xxxx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  mov    -0x4(%rbp),%edx
  mov    $0x80000000,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x8(%rbp)
  jns    L14
  mov    -0x8(%rbp),%edx
  mov    $0x80000000,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int float_gt_xxxx(int a, int b) {
  if (a < 0) {
    a = 0x80000000u - a;
  }
  if (b < 0) {
    b = 0x80000000u - b;
  }
  return a > b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<float_gt_xxxx>:
  endbr64
  mov    $0x80000000,%eax
  sub    %edi,%eax
  test   %edi,%edi
  cmovs  %eax,%edi
  mov    $0x80000000,%eax
  sub    %esi,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  cmp    %esi,%edi
  setg   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int float_gt_xxxx(int a, int b) {
  if (a < 0) {
    a = 0x80000000u - a;
  }
  if (b < 0) {
    b = 0x80000000u - b;
  }
  return a > b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<float_gt_xxxx>:
  endbr64
  mov    $0x80000000,%eax
  mov    %eax,%edx
  sub    %edi,%edx
  test   %edi,%edi
  cmovs  %edx,%edi
  sub    %esi,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  xor    %eax,%eax
  cmp    %esi,%edi
  setg   %al
  ret
```

assistant: ```c
int float_gt_xxxx(int a, int b) {
  if (a < 0) {
    a = 0x80000000u - a;
  }
  if (b < 0) {
    b = 0x80000000u - b;
  }
  return a > b;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<float_gt_xxxx>:
  endbr64
  mov    $0x80000000,%eax
  mov    %eax,%edx
  sub    %edi,%edx
  test   %edi,%edi
  cmovs  %edx,%edi
  sub    %esi,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  xor    %eax,%eax
  cmp    %esi,%edi
  setg   %al
  ret
```

assistant: ```c
int float_gt_xxxx(int a, int b) {
  if (a < 0) {
    a = 0x80000000u - a;
  }
  if (b < 0) {
    b = 0x80000000u - b;
  }
  return a > b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x3c(%rbp)
  movabs $0x2073692073696874,%rax
  movabs $0x6f20747365742061,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x676e697274732066,%rax
  movabs $0x7a696e656b6f7420,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x676e69,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L14:
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L1
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L1:
  mov    -0x38(%rbp),%rdx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: label: D46
data_type: string
name: extract_symbolic_data
arguments: label: D28
data_type: string
name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D40
data_type: string

tool: D46: String: %s


tool: D28:  

tool: D17: %i: %s


tool: D40: Tokenizing complete

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 1;
  char str[] = "this is a test of string tokenizing";
  char *str1;
  printf("String: %s\n", str);
  str1 = strtok(str, " ");
  printf("%i: %s\n", x, str1);
  while (1) {
    str1 = strtok(NULL, " ");
    if (str1 == NULL) {
      printf("Tokenizing complete\n");
      exit(0);
    }
    printf("%i: %s\n", x, str1);
    x++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x2073692073696874,%rax
  movabs $0x6f20747365742061,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x676e697274732066,%rax
  movabs $0x7a696e656b6f7420,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movl   $0x676e69,0x20(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D52(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D56(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%rdx
  mov    $0x1,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebp
  lea    D56(%rip),%r13
  lea    D48(%rip),%r14
  lea    D26(%rip),%r12
  jmp    L24
L7:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L23:
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
L24:
  mov    %r13,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L23
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D52
datatype: string
name: extract_symbolic_data
arguments: data_label: D56
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: string
name: extract_symbolic_data
arguments: data_label: D48
datatype: string

tool: D52: String: %s


tool: D56:  

tool: D26: %i: %s


tool: D48: Tokenizing complete

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 1;
  char str[] = "this is a test of string tokenizing";
  char *str1;
  printf("String: %s\n", str);
  str1 = strtok(str, " ");
  printf("%i: %s\n", x, str1);
  while (1) {
    str1 = strtok(NULL, " ");
    if (str1 == NULL) {
      printf("Tokenizing complete\n");
      exit(0);
    }
    printf("%i: %s\n", x, str1);
    x++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%rdi
  lea    D48(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x30,%rsp
  movdqa D56(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x676e69,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D49(%rip),%xmm0
  mov    %rbp,%rsi
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  lea    D13(%rip),%rbp
  call   <strtok@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L16
  mov    %r14,%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
L16:
  mov    %ebx,%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D48
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D56
type_guessed: byte[16]
name: disassemble_data
arguments: data_tag: D49
type_guessed: byte[16]
name: disassemble_data
arguments: data_tag: D13
type_guessed: string

tool: D9: String: %s


tool: D48: Tokenizing complete

tool: D14:  

tool: {"D56": [0x74,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x74,0x65,0x73,0x74,0x20,0x6f]}

tool: {"D49": [0x66,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x20,0x74,0x6f,0x6b,0x65,0x6e,0x69,0x7a]}

tool: D13: %i: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 1;
  char str[] = "this is a test of string tokenizing";
  char *str1;
  printf("String: %s\n", str);
  str1 = strtok(str, " ");
  printf("%i: %s\n", x, str1);
  while (1) {
    str1 = strtok(NULL, " ");
    if (str1 == NULL) {
      printf("Tokenizing complete\n");
      exit(0);
    }
    printf("%i: %s\n", x, str1);
    x++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D59(%rip),%rdi
  lea    D16(%rip),%r14
  push   %r13
  lea    D45(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x30,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x676e69,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D48(%rip),%xmm0
  mov    %rbp,%rsi
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  lea    D6(%rip),%rbp
  call   <strtok@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L7
  mov    %r14,%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
L7:
  mov    %ebx,%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  jmp    L2
```

tool_calls: name: parse_data
arguments: tag: D59
datatype: string
name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D45
datatype: string
name: parse_data
arguments: tag: D17
datatype: byte[16]
name: parse_data
arguments: tag: D48
datatype: byte[16]
name: parse_data
arguments: tag: D6
datatype: string

tool: D59: String: %s


tool: D16: Tokenizing complete

tool: D45:  

tool: {"D17": [0x74,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x74,0x65,0x73,0x74,0x20,0x6f]}

tool: {"D48": [0x66,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x20,0x74,0x6f,0x6b,0x65,0x6e,0x69,0x7a]}

tool: D6: %i: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 1;
  char str[] = "this is a test of string tokenizing";
  char *str1;
  printf("String: %s\n", str);
  str1 = strtok(str, " ");
  printf("%i: %s\n", x, str1);
  while (1) {
    str1 = strtok(NULL, " ");
    if (str1 == NULL) {
      printf("Tokenizing complete\n");
      exit(0);
    }
    printf("%i: %s\n", x, str1);
    x++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_mat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L56
L2:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L48
L31:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <print_elem@plt>
  addl   $0x1,-0x4(%rbp)
L48:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L31
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jne    L20
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L18
L20:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L18:
  addl   $0x1,-0x8(%rbp)
L56:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D30
type_guessed: string
name: extract_symbolic_data
arguments: tag: D33
type_guessed: string
name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D8:     |

tool: D30: |

tool: D33:  = A

tool: 

assistant: ```c
void print_mat(int **mat, int size) {
  for (int i = 0; i < size; i++) {
    printf("    |");
    for (int j = 0; j < size; j++) {
      print_elem(mat[i][j], 5);
    }
    printf("|");
    if (i == size / 2)
      puts(" = A");
    else
      puts("");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_mat>:
  endbr64
  test   %esi,%esi
  jle    L49
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r14d
  mov    %esi,%r15d
  shr    $0x1f,%r15d
  add    %esi,%r15d
  sar    %r15d
  mov    %rdi,%rbp
  mov    %esi,%r12d
  shl    $0x2,%r12
  mov    $0x0,%r13d
  jmp    L27
L32:
  lea    D32(%rip),%rdi
  call   <puts@plt>
L9:
  add    $0x1,%r13d
  add    $0x8,%rbp
  cmp    %r13d,%r14d
  je     L3
L27:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
L16:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%edi
  mov    $0x5,%esi
  call   <print_elem@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L16
  lea    D33(%rip),%rdi
  call   <printf@plt>
  cmp    %r13d,%r15d
  je     L32
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L9
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D32
data_type: string
name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D33
data_type: string
name: disassemble_data
arguments: tag: D10
data_type: string

tool: D32:  = A

tool: D11:     |

tool: D33: |

tool: 

assistant: ```c
void print_mat(int **mat, int size) {
  for (int i = 0; i < size; i++) {
    printf("    |");
    for (int j = 0; j < size; j++) {
      print_elem(mat[i][j], 5);
    }
    printf("|");
    if (i == size / 2)
      puts(" = A");
    else
      puts("");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_mat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  test   %esi,%esi
  jle    L27
  mov    %esi,%edx
  movslq %esi,%rbp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  sar    %edx
  shl    $0x2,%rbp
  lea    D28(%rip),%r15
  lea    D26(%rip),%r14
  mov    %edx,0xc(%rsp)
  nopl   (%rax)
L45:
  mov    %r15,%rdi
  xor    %r13d,%r13d
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%rax
  mov    $0x5,%esi
  mov    (%rax,%r13,1),%edi
  add    $0x4,%r13
  call   <print_elem@plt>
  cmp    %r13,%rbp
  jne    L1
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    %r12d,0xc(%rsp)
  je     L11
  lea    D37(%rip),%rdi
  call   <puts@plt>
L30:
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,0x8(%rsp)
  jne    L45
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  jmp    L30
```

tool_calls: name: extract_symbolic_data
arguments: tag: D28
datatype: string
name: extract_symbolic_data
arguments: tag: D26
datatype: string
name: extract_symbolic_data
arguments: tag: D37
datatype: string
name: extract_symbolic_data
arguments: tag: D13
datatype: string

tool: D28:     |

tool: D26: |

tool: 

tool: D13:  = A

assistant: ```c
void print_mat(int **mat, int size) {
  for (int i = 0; i < size; i++) {
    printf("    |");
    for (int j = 0; j < size; j++) {
      print_elem(mat[i][j], 5);
    }
    printf("|");
    if (i == size / 2)
      puts(" = A");
    else
      puts("");
  }
}
```