ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<castling_to_s>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x5,%edi
  call   <malloc@plt>
  xor    %edx,%edx
  test   $0x10,%bh
  je     L44
  movb   $0x4b,(%rax)
  mov    $0x1,%edx
L44:
  test   $0x1,%bh
  je     L23
  movslq %edx,%rcx
  add    $0x1,%edx
  movb   $0x51,(%rax,%rcx,1)
L23:
  mov    %ebx,%ecx
  and    $0x1,%ecx
  and    $0x10,%ebx
  je     L49
  movslq %edx,%rsi
  add    $0x1,%edx
  movb   $0x6b,(%rax,%rsi,1)
  test   %cx,%cx
  je     L9
L53:
  movslq %edx,%rcx
  add    $0x1,%edx
  movb   $0x71,(%rax,%rcx,1)
L9:
  movslq %edx,%rdx
  movb   $0x0,(%rax,%rdx,1)
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  test   %cx,%cx
  jne    L53
  test   %edx,%edx
  jne    L9
  mov    $0x1,%edx
  movb   $0x2d,(%rax)
  movb   $0x0,(%rax,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
char *castling_to_s(short int castling) {
  char *s = (char *)malloc(5);
  int cur = 0;
  if (0x1000 & castling) {
    s[cur] = 'K';
    cur++;
  }
  if (0x0100 & castling) {
    s[cur] = 'Q';
    cur++;
  }
  if (0x0010 & castling) {
    s[cur] = 'k';
    cur++;
  }
  if (0x0001 & castling) {
    s[cur] = 'q';
    cur++;
  }
  if (cur == 0) {
    s[cur] = '-';
    cur++;
  }
  s[cur] = '\0';
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<castling_to_s>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x5,%edi
  call   <malloc@plt>
  test   $0x10,%bh
  je     L13
  movb   $0x4b,(%rax)
  mov    $0x2,%ecx
  mov    $0x1,%esi
  mov    $0x1,%edx
L9:
  test   $0x1,%bh
  je     L45
  movb   $0x51,(%rax,%rsi,1)
  movslq %ecx,%rdx
L45:
  mov    %ebx,%ecx
  and    $0x1,%ecx
  and    $0x10,%ebx
  je     L68
  movslq %edx,%rsi
  add    $0x1,%edx
  movb   $0x6b,(%rax,%rsi,1)
  test   %cx,%cx
  je     L11
L6:
  movslq %edx,%rcx
  add    $0x1,%edx
  movb   $0x71,(%rax,%rcx,1)
L11:
  movslq %edx,%rdx
L20:
  movb   $0x0,(%rax,%rdx,1)
  pop    %rbx
  ret
L13:
  mov    $0x1,%ecx
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L68:
  test   %cx,%cx
  jne    L6
  test   %edx,%edx
  jne    L20
  mov    $0x1,%edx
  movb   $0x2d,(%rax)
  movb   $0x0,(%rax,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
char *castling_to_s(short int castling) {
  char *s = (char *)malloc(5);
  int cur = 0;
  if (0x1000 & castling) {
    s[cur] = 'K';
    cur++;
  }
  if (0x0100 & castling) {
    s[cur] = 'Q';
    cur++;
  }
  if (0x0010 & castling) {
    s[cur] = 'k';
    cur++;
  }
  if (0x0001 & castling) {
    s[cur] = 'q';
    cur++;
  }
  if (cur == 0) {
    s[cur] = '-';
    cur++;
  }
  s[cur] = '\0';
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L4
L10:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D24
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D16: root

tool: D24: I'm root!


tool: D2: I'm user!


assistant: ```c
int main(int argc, char *argv[]) {
  struct passwd *pw = getpwuid(geteuid());
  assert(pw != NULL);
  if (strcmp("root", pw->pw_name) == 0) {
    printf("I'm root!\n");
  } else {
    printf("I'm user!\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%esi
  lea    D2(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  lea    D11(%rip),%rdi
  call   <printf@plt>
L16:
  mov    $0x0,%eax
  pop    %rbx
  ret
L1:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string
name: parse_data
arguments: data_label: D25
type_infered: string

tool: D2: root

tool: D11: I'm root!


tool: D25: I'm user!


assistant: ```c
int main(int argc, char *argv[]) {
  struct passwd *pw = getpwuid(geteuid());
  assert(pw != NULL);
  if (strcmp("root", pw->pw_name) == 0) {
    printf("I'm root!\n");
  } else {
    printf("I'm user!\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    (%rbx),%esi
  lea    D12(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
  lea    D13(%rip),%rdi
  call   <printf@plt>
L7:
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
data_type: string
name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D12: root

tool: D13: I'm root!


tool: D5: I'm user!


assistant: ```c
int main(int argc, char *argv[]) {
  struct passwd *pw = getpwuid(geteuid());
  assert(pw != NULL);
  if (strcmp("root", pw->pw_name) == 0) {
    printf("I'm root!\n");
  } else {
    printf("I'm user!\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    (%rbx),%esi
  lea    D26(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
  lea    D4(%rip),%rdi
  call   <printf@plt>
L7:
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: tag: D26
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D14
type_guessed: string

tool: D26: root

tool: D4: I'm root!


tool: D14: I'm user!


assistant: ```c
int main(int argc, char *argv[]) {
  struct passwd *pw = getpwuid(geteuid());
  assert(pw != NULL);
  if (strcmp("root", pw->pw_name) == 0) {
    printf("I'm root!\n");
  } else {
    printf("I'm user!\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sleep_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  shr    $0x12,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  shr    $0x12,%eax
  imul   $0xf4240,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <select@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void sleep_us(unsigned int nusecs) {
  struct timeval tval;
  tval.tv_sec = nusecs / 1000000;
  tval.tv_usec = nusecs % 1000000;
  select(0, NULL, NULL, NULL, &tval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sleep_us>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  mov    %eax,(%rsp)
  imul   $0xf4240,%eax,%eax
  sub    %eax,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <select@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_us(unsigned int nusecs) {
  struct timeval tval;
  tval.tv_sec = nusecs / 1000000;
  tval.tv_usec = nusecs % 1000000;
  select(0, NULL, NULL, NULL, &tval);
}
```
user: What is the c source code of the assembly code below?

```asm
<sleep_us>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  mov    %rsp,%r8
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  mov    %eax,(%rsp)
  imul   $0xf4240,%eax,%eax
  sub    %eax,%edi
  mov    %edi,0x4(%rsp)
  xor    %edi,%edi
  call   <select@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_us(unsigned int nusecs) {
  struct timeval tval;
  tval.tv_sec = nusecs / 1000000;
  tval.tv_usec = nusecs % 1000000;
  select(0, NULL, NULL, NULL, &tval);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sleep_us>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  mov    %rsp,%r8
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  imul   $0xf4240,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%edi
  xor    %edx,%edx
  movd   %edi,%xmm1
  xor    %edi,%edi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  call   <select@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_us(unsigned int nusecs) {
  struct timeval tval;
  tval.tv_sec = nusecs / 1000000;
  tval.tv_usec = nusecs % 1000000;
  select(0, NULL, NULL, NULL, &tval);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D87(%rip),%rdi
  call   <printf@plt>
  lea    D88(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D113(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D108(%rip),%rdi
  call   <scanf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x5,0x4(%rsp)
  ja     L56
  mov    0x4(%rsp),%eax
  lea    D68(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <connect@plt>
L43:
  lea    D73(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <menu>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  ret
  mov    $0x0,%eax
  call   <getClientsID@plt>
  jmp    L43
  mov    $0x0,%eax
  call   <sendMessage@plt>
  jmp    L43
  mov    $0x0,%eax
  call   <disconnect@plt>
  jmp    L43
  mov    $0x0,%eax
  call   <disconnect@plt>
  mov    $0x0,%eax
  call   <clientExit@plt>
  jmp    L43
L56:
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D40
type: string
name: retrieve_data
arguments: data_label: D87
type: string
name: retrieve_data
arguments: data_label: D88
type: string
name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D65
type: string
name: retrieve_data
arguments: data_label: D66
type: string
name: retrieve_data
arguments: data_label: D113
type: string
name: retrieve_data
arguments: data_label: D108
type: string
name: retrieve_data
arguments: data_label: D73
type: string
name: retrieve_data
arguments: data_label: D64
type: string

tool: D40: Menu 1


tool: D87: ~~~~~~~~~~


tool: D88: 1. Connect to server.


tool: D6: 2. Get clients connected to server.


tool: D65: 3. Write to client/s.


tool: D66: 4. Disconnect from server.


tool: D113: 5. Exit.


tool: D108: %d

tool: D73: 


tool: D64: Please.. is not a joke. 


assistant: ```c
void menu() {
  int menuChoice;
  printf("Menu 1\n");
  printf("~~~~~~~~~~\n");
  printf("1. Connect to server.\n");
  printf("2. Get clients connected to server.\n");
  printf("3. Write to client/s.\n");
  printf("4. Disconnect from server.\n");
  printf("5. Exit.\n");
  scanf("%d", &menuChoice);
  printf("\n");
  switch (menuChoice) {
  case 1:
    connect();
    break;
  case 2:
    getClientsID();
    break;
  case 3:
    sendMessage();
    break;
  case 4:
    disconnect();
    break;
  case 5:
    disconnect();
    clientExit();
    break;
  default:
    printf("Please.. is not a joke. \n");
  }
  printf("\n");
  menu();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x41,-0xc(%rbp)
  jmp    L21
L38:
  movl   $0x41,-0x8(%rbp)
  jmp    L46
L43:
  movl   $0x41,-0x4(%rbp)
  jmp    L53
L6:
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L53:
  cmpl   $0x5a,-0x4(%rbp)
  jle    L6
  addl   $0x1,-0x8(%rbp)
L46:
  cmpl   $0x5a,-0x8(%rbp)
  jle    L43
  addl   $0x1,-0xc(%rbp)
L21:
  cmpl   $0x5a,-0xc(%rbp)
  jle    L38
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: %c%c%c 

assistant: ```c
int main() {
  int i, j, k;
  for (i = 'A'; i <= 'Z'; i++)
    for (j = 'A'; j <= 'Z'; j++)
      for (k = 'A'; k <= 'Z'; k++)
        printf("%c%c%c ", i, j, k);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x41,%r12d
  lea    D9(%rip),%r13
L13:
  mov    $0x41,%ebp
L15:
  mov    $0x41,%ebx
L26:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L26
  add    $0x1,%ebp
  cmp    $0x5b,%ebp
  jne    L15
  add    $0x1,%r12d
  cmp    $0x5b,%r12d
  jne    L13
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: %c%c%c 

assistant: ```c
int main() {
  int i, j, k;
  for (i = 'A'; i <= 'Z'; i++)
    for (j = 'A'; j <= 'Z'; j++)
      for (k = 'A'; k <= 'Z'; k++)
        printf("%c%c%c ", i, j, k);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    $0x41,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L16:
  mov    $0x41,%ebp
L17:
  mov    $0x41,%ebx
  nopl   (%rax)
L27:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L27
  add    $0x1,%ebp
  cmp    $0x5b,%ebp
  jne    L17
  add    $0x1,%r12d
  cmp    $0x5b,%r12d
  jne    L16
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: %c%c%c 

assistant: ```c
int main() {
  int i, j, k;
  for (i = 'A'; i <= 'Z'; i++)
    for (j = 'A'; j <= 'Z'; j++)
      for (k = 'A'; k <= 'Z'; k++)
        printf("%c%c%c ", i, j, k);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    $0x41,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L15:
  mov    $0x41,%ebp
L17:
  mov    $0x41,%ebx
  nopl   (%rax)
L13:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L13
  add    $0x1,%ebp
  cmp    $0x5b,%ebp
  jne    L17
  add    $0x1,%r12d
  cmp    $0x5b,%r12d
  jne    L15
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: %c%c%c 

assistant: ```c
int main() {
  int i, j, k;
  for (i = 'A'; i <= 'Z'; i++)
    for (j = 'A'; j <= 'Z'; j++)
      for (k = 'A'; k <= 'Z'; k++)
        printf("%c%c%c ", i, j, k);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strEq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  cmpq   $0x0,-0x10(%rbp)
  je     L27
  mov    $0x1,%eax
  jmp    L10
L27:
  mov    $0x0,%eax
L10:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
bool strEq(const char *a, const char *b) {
  assert(a != NULL && b != NULL);
  return (strcmp(a, b) == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strEq>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool strEq(const char *a, const char *b) {
  assert(a != NULL && b != NULL);
  return (strcmp(a, b) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strEq>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool strEq(const char *a, const char *b) {
  assert(a != NULL && b != NULL);
  return (strcmp(a, b) == 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strEq>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool strEq(const char *a, const char *b) {
  assert(a != NULL && b != NULL);
  return (strcmp(a, b) == 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<last_major>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L2
L29:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L0
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L0
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  jmp    L4
L0:
  subl   $0x1,-0xc(%rbp)
L2:
  cmpl   $0x0,-0xc(%rbp)
  jne    L29
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
char last_major(const char *str, int cur_o) {
  for (; cur_o; cur_o--) {
    if (str[cur_o - 1] >= 'A' && str[cur_o - 1] <= 'Z')
      return str[cur_o - 1];
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<last_major>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  je     L8
  movslq %esi,%rcx
  lea    -0x1(%rdi,%rcx,1),%rax
  lea    -0x2(%rdi,%rcx,1),%rsi
  lea    -0x1(%rdx),%edx
  sub    %rdx,%rsi
L29:
  movzbl (%rax),%edx
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  jbe    L33
  sub    $0x1,%rax
  cmp    %rsi,%rax
  jne    L29
  mov    $0x0,%edx
L33:
  mov    %edx,%eax
  ret
L8:
  mov    $0x0,%edx
  jmp    L33
```

assistant: ```c
char last_major(const char *str, int cur_o) {
  for (; cur_o; cur_o--) {
    if (str[cur_o - 1] >= 'A' && str[cur_o - 1] <= 'Z')
      return str[cur_o - 1];
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<last_major>:
  endbr64
  test   %esi,%esi
  je     L38
  movslq %esi,%rdx
  lea    -0x2(%rdi,%rdx,1),%rcx
  lea    -0x1(%rdi,%rdx,1),%rax
  lea    -0x1(%rsi),%edx
  sub    %rdx,%rcx
  jmp    L6
  nopl   (%rax)
L31:
  sub    $0x1,%rax
  cmp    %rcx,%rax
  je     L38
L6:
  movzbl (%rax),%r8d
  lea    -0x41(%r8),%edx
  cmp    $0x19,%dl
  ja     L31
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
char last_major(const char *str, int cur_o) {
  for (; cur_o; cur_o--) {
    if (str[cur_o - 1] >= 'A' && str[cur_o - 1] <= 'Z')
      return str[cur_o - 1];
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<last_major>:
  endbr64
  test   %esi,%esi
  je     L27
  movslq %esi,%rdx
  lea    -0x2(%rdi,%rdx,1),%rcx
  lea    -0x1(%rdi,%rdx,1),%rax
  lea    -0x1(%rsi),%edx
  sub    %rdx,%rcx
  jmp    L34
  nopl   (%rax)
L14:
  sub    $0x1,%rax
  cmp    %rcx,%rax
  je     L27
L34:
  movzbl (%rax),%r8d
  lea    -0x41(%r8),%edx
  cmp    $0x19,%dl
  ja     L14
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
char last_major(const char *str, int cur_o) {
  for (; cur_o; cur_o--) {
    if (str[cur_o - 1] >= 'A' && str[cur_o - 1] <= 'Z')
      return str[cur_o - 1];
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reboot_keyboard_ctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L10:
  mov    $0x64,%edi
  call   <indw@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L15
  mov    $0x60,%edi
  call   <indw@plt>
L15:
  mov    -0x4(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  jne    L10
  mov    $0xfe,%esi
  mov    $0x64,%edi
  call   <outdw@plt>
  nop
  leave
  ret
```

assistant: ```c
void reboot_keyboard_ctl() {
  int temp;
  do {
    temp = indw(0x64);
    if (temp & 1)
      indw(0x60);
  } while (temp & 2);
  outdw(0x64, 0xFE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reboot_keyboard_ctl>:
  endbr64
  push   %rbx
  jmp    L17
L19:
  test   $0x2,%bl
  je     L0
L17:
  mov    $0x64,%edi
  call   <indw@plt>
  mov    %eax,%ebx
  test   $0x1,%al
  je     L19
  mov    $0x60,%edi
  call   <indw@plt>
  jmp    L19
L0:
  mov    $0xfe,%esi
  mov    $0x64,%edi
  call   <outdw@plt>
  pop    %rbx
  ret
```

assistant: ```c
void reboot_keyboard_ctl() {
  int temp;
  do {
    temp = indw(0x64);
    if (temp & 1)
      indw(0x60);
  } while (temp & 2);
  outdw(0x64, 0xFE);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reboot_keyboard_ctl>:
  endbr64
  push   %rbx
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L9:
  and    $0x2,%ebx
  je     L26
L7:
  mov    $0x64,%edi
  call   <indw@plt>
  mov    %eax,%ebx
  test   $0x1,%al
  je     L9
  mov    $0x60,%edi
  call   <indw@plt>
  and    $0x2,%ebx
  jne    L7
L26:
  mov    $0xfe,%esi
  mov    $0x64,%edi
  pop    %rbx
  jmp    1060 <outdw@plt>
```

assistant: ```c
void reboot_keyboard_ctl() {
  int temp;
  do {
    temp = indw(0x64);
    if (temp & 1)
      indw(0x60);
  } while (temp & 2);
  outdw(0x64, 0xFE);
}
```