ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rsi
  mov    $0x3,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x67666564636261,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  call   <mystrncpy@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string

tool: D3: abcd

tool: D16: %s


assistant: ```c
int main() {
  char s[] = "abcdefg";
  char *t = "abcd";
  mystrncpy(s, t, 3);
  printf("%s\n", s);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fcvt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0xc(%rbp),%edi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <cvt@plt>
  cltq
  leave
  ret
```

assistant: ```c
char *fcvt(value, ndigit, decpt, sign)
double value;
int ndigit, *decpt, *sign;
{ return cvt(value, ndigit, decpt, sign, 0); }
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fcvt>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x1,%eax
  call   <cvt@plt>
  cltq
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *fcvt(value, ndigit, decpt, sign)
double value;
int ndigit, *decpt, *sign;
{ return cvt(value, ndigit, decpt, sign, 0); }
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fcvt>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  mov    $0x1,%eax
  call   <cvt@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
char *fcvt(value, ndigit, decpt, sign)
double value;
int ndigit, *decpt, *sign;
{ return cvt(value, ndigit, decpt, sign, 0); }
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fcvt>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  mov    $0x1,%eax
  call   <cvt@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
char *fcvt(value, ndigit, decpt, sign)
double value;
int ndigit, *decpt, *sign;
{ return cvt(value, ndigit, decpt, sign, 0); }
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<int_div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L7
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <newstr@plt>
  mov    %eax,%r12d
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <int2str@plt>
  mov    %eax,%ebx
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <newstr@plt>
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <cat3@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <runtime_error@plt>
L7:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string
name: read_data
arguments: data_label: D19
type_infered: string

tool: D4:  by zero!

tool: D19: Unable to divide 

assistant: ```c
int int_div(int line, int a, int b) {
  if (b == 0) {
    runtime_error(line, cat3(newstr("Unable to divide "), int2str(a), newstr(" by zero!")));
  }
  return a / b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_div>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %edx,%ebp
  test   %edx,%edx
  je     L12
L14:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    %edi,%r12d
  lea    D15(%rip),%rdi
  call   <newstr@plt>
  mov    %eax,%r14d
  mov    %ebx,%edi
  call   <int2str@plt>
  mov    %eax,%r13d
  lea    D8(%rip),%rdi
  call   <newstr@plt>
  mov    %eax,%edi
  mov    %r14d,%edx
  mov    %r13d,%esi
  call   <cat3@plt>
  mov    %eax,%esi
  mov    %r12d,%edi
  call   <runtime_error@plt>
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D15:  by zero!

tool: D8: Unable to divide 

assistant: ```c
int int_div(int line, int a, int b) {
  if (b == 0) {
    runtime_error(line, cat3(newstr("Unable to divide "), int2str(a), newstr(" by zero!")));
  }
  return a / b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_div>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  test   %edx,%edx
  je     L6
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L6:
  mov    %edi,%ebp
  lea    D18(%rip),%rdi
  call   <newstr@plt>
  mov    %r12d,%edi
  mov    %eax,%r14d
  call   <int2str@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%r13d
  call   <newstr@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %eax,%edi
  call   <cat3@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <runtime_error@plt>
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D18:  by zero!

tool: D19: Unable to divide 

assistant: ```c
int int_div(int line, int a, int b) {
  if (b == 0) {
    runtime_error(line, cat3(newstr("Unable to divide "), int2str(a), newstr(" by zero!")));
  }
  return a / b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<int_div>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  test   %edx,%edx
  je     L0
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L0:
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  call   <newstr@plt>
  mov    %r12d,%edi
  mov    %eax,%r14d
  call   <int2str@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%r13d
  call   <newstr@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %eax,%edi
  call   <cat3@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <runtime_error@plt>
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D1:  by zero!

tool: D0: Unable to divide 

assistant: ```c
int int_div(int line, int a, int b) {
  if (b == 0) {
    runtime_error(line, cat3(newstr("Unable to divide "), int2str(a), newstr(" by zero!")));
  }
  return a / b;
}
```
user: What is the c source code of the assembly code below:

```asm
<ls1c_fls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x20,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L33
L19:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ax
  test   %eax,%eax
  jne    L32
  shll   $0x10,-0x14(%rbp)
  subl   $0x10,-0x4(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  and    $0xff000000,%eax
  test   %eax,%eax
  jne    L21
  shll   $0x8,-0x14(%rbp)
  subl   $0x8,-0x4(%rbp)
L21:
  mov    -0x14(%rbp),%eax
  and    $0xf0000000,%eax
  test   %eax,%eax
  jne    L22
  shll   $0x4,-0x14(%rbp)
  subl   $0x4,-0x4(%rbp)
L22:
  mov    -0x14(%rbp),%eax
  and    $0xc0000000,%eax
  test   %eax,%eax
  jne    L1
  shll   $0x2,-0x14(%rbp)
  subl   $0x2,-0x4(%rbp)
L1:
  cmpl   $0x0,-0x14(%rbp)
  js     L7
  shll   -0x14(%rbp)
  subl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int ls1c_fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ls1c_fls>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L25
  mov    $0x20,%eax
  test   $0xffff0000,%edi
  jne    L10
  shl    $0x10,%edi
  mov    $0x10,%eax
L10:
  test   $0xff000000,%edi
  jne    L9
  shl    $0x8,%edi
  sub    $0x8,%eax
L9:
  test   $0xf0000000,%edi
  jne    L47
  shl    $0x4,%edi
  sub    $0x4,%eax
L47:
  test   $0xc0000000,%edi
  jne    L34
  shl    $0x2,%edi
  sub    $0x2,%eax
L34:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L25:
  ret
```

assistant: ```c
int ls1c_fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ls1c_fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L27
  mov    $0x20,%eax
  test   $0xffff0000,%edi
  jne    L3
  shl    $0x10,%edi
  mov    $0x10,%eax
L3:
  test   $0xff000000,%edi
  jne    L32
  shl    $0x8,%edi
  sub    $0x8,%eax
L32:
  test   $0xf0000000,%edi
  jne    L7
  shl    $0x4,%edi
  sub    $0x4,%eax
L7:
  test   $0xc0000000,%edi
  jne    L6
  shl    $0x2,%edi
  sub    $0x2,%eax
L6:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L27:
  ret
```

assistant: ```c
int ls1c_fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ls1c_fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L40
  test   $0xffff0000,%edi
  je     L57
  mov    $0x18,%edx
  mov    $0x20,%eax
L7:
  test   $0xff000000,%edi
  jne    L52
  shl    $0x8,%edi
  mov    %edx,%eax
L52:
  test   $0xf0000000,%edi
  jne    L28
  shl    $0x4,%edi
  sub    $0x4,%eax
L28:
  test   $0xc0000000,%edi
  jne    L6
  shl    $0x2,%edi
  sub    $0x2,%eax
L6:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L40:
  ret
  nop
L57:
  shl    $0x10,%edi
  mov    $0x8,%edx
  mov    $0x10,%eax
  jmp    L7
```

assistant: ```c
int ls1c_fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gettoklen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movsbl -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <gettokstart@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L27
L17:
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L22:
  mov    -0xc(%rbp),%eax
L27:
  leave
  ret
```

assistant: ```c
int gettoklen(char *str, int req, char delim) {
  char *start = 0;
  int len = 0;
  start = gettokstart(str, req, delim);
  if (start == '\0') {
    return 0;
  }
  while (*start != delim && *start != '\0') {
    start++;
    len++;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gettoklen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebp
  mov    %edx,%ebx
  movsbl %dl,%edx
  mov    $0x0,%eax
  call   <gettokstart@plt>
  test   %eax,%eax
  je     L13
  movslq %eax,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L9
  cmp    %bpl,%al
  je     L9
  mov    $0x0,%eax
L22:
  add    $0x1,%rdx
  add    $0x1,%eax
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L13
  cmp    %bl,%cl
  jne    L22
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    $0x0,%eax
  jmp    L13
```

assistant: ```c
int gettoklen(char *str, int req, char delim) {
  char *start = 0;
  int len = 0;
  start = gettokstart(str, req, delim);
  if (start == '\0') {
    return 0;
  }
  while (*start != delim && *start != '\0') {
    start++;
    len++;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gettoklen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edx,%ebp
  push   %rbx
  mov    %edx,%ebx
  movsbl %dl,%edx
  sub    $0x8,%rsp
  call   <gettokstart@plt>
  test   %eax,%eax
  je     L67
  movslq %eax,%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L17
  cmp    %bpl,%al
  je     L17
  xor    %eax,%eax
  jmp    L51
  nop
L19:
  cmp    %bl,%dl
  je     L67
L51:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  add    $0x1,%eax
  test   %dl,%dl
  jne    L19
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  jmp    L67
```

assistant: ```c
int gettoklen(char *str, int req, char delim) {
  char *start = 0;
  int len = 0;
  start = gettokstart(str, req, delim);
  if (start == '\0') {
    return 0;
  }
  while (*start != delim && *start != '\0') {
    start++;
    len++;
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gettoklen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edx,%ebp
  push   %rbx
  mov    %edx,%ebx
  movsbl %dl,%edx
  sub    $0x8,%rsp
  call   <gettokstart@plt>
  test   %eax,%eax
  je     L41
  movslq %eax,%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L34
  cmp    %bpl,%al
  je     L34
  xor    %eax,%eax
  jmp    L30
  nop
L59:
  cmp    %bl,%dl
  je     L41
L30:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  add    $0x1,%eax
  test   %dl,%dl
  jne    L59
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  jmp    L41
```

assistant: ```c
int gettoklen(char *str, int req, char delim) {
  char *start = 0;
  int len = 0;
  start = gettokstart(str, req, delim);
  if (start == '\0') {
    return 0;
  }
  while (*start != delim && *start != '\0') {
    start++;
    len++;
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<uart_getsn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L52
L27:
  mov    $0x0,%eax
  call   <uart_getchar@plt>
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  cmpb   $0x8,-0x5(%rbp)
  jne    L7
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
  subl   $0x2,-0x4(%rbp)
  jmp    L28
L7:
  cmpb   $0xd,-0x5(%rbp)
  jne    L28
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0xa,%edi
  call   <uart_putchar@plt>
  mov    -0x18(%rbp),%rax
  jmp    L14
L28:
  addl   $0x1,-0x4(%rbp)
L52:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L27
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1:  

assistant: ```c
char *uart_getsn(char *str, int num) {
  int i;
  for (i = 0; i < num - 1; i++) {
    char c = uart_getchar();
    str[i] = c;
    if (c == '\b') {
      uart_puts(" \b");
      i -= 2;
    } else if (c == '\r') {
      str[i] = 0;
      uart_putchar('\n');
      return str;
    }
  }
  str[num] = 0;
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uart_getsn>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  lea    -0x1(%rsi),%r12d
  test   %r12d,%r12d
  jle    L13
  mov    $0x0,%ebx
  lea    D9(%rip),%r14
  jmp    L53
L4:
  mov    %r14,%rdi
  call   <uart_puts@plt>
  sub    $0x2,%ebx
L9:
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jge    L13
L53:
  mov    $0x0,%eax
  call   <uart_getchar@plt>
  movslq %ebx,%rdx
  add    %rbp,%rdx
  mov    %al,(%rdx)
  cmp    $0x8,%al
  je     L4
  cmp    $0xd,%al
  jne    L9
  movb   $0x0,(%rdx)
  mov    $0xa,%edi
  call   <uart_putchar@plt>
  jmp    L0
L13:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
L0:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string

tool: D9:  

assistant: ```c
char *uart_getsn(char *str, int num) {
  int i;
  for (i = 0; i < num - 1; i++) {
    char c = uart_getchar();
    str[i] = c;
    if (c == '\b') {
      uart_puts(" \b");
      i -= 2;
    } else if (c == '\r') {
      str[i] = 0;
      uart_putchar('\n');
      return str;
    }
  }
  str[num] = 0;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uart_getsn>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  lea    -0x1(%rbp),%ebx
  test   %ebx,%ebx
  jle    L6
  xor    %r14d,%r14d
  lea    D4(%rip),%r13
  jmp    L51
  nopl   (%rax)
L38:
  cmp    $0xd,%al
  je     L7
  add    $0x1,%r14d
  cmp    %ebx,%r14d
  jge    L6
L51:
  xor    %eax,%eax
  call   <uart_getchar@plt>
  movslq %r14d,%rdx
  add    %r12,%rdx
  mov    %al,(%rdx)
  cmp    $0x8,%al
  jne    L38
  sub    $0x2,%r14d
  mov    %r13,%rdi
  call   <uart_puts@plt>
  add    $0x1,%r14d
  cmp    %ebx,%r14d
  jl     L51
L6:
  pop    %rbx
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L7:
  movb   $0x0,(%rdx)
  mov    $0xa,%edi
  call   <uart_putchar@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4:  

assistant: ```c
char *uart_getsn(char *str, int num) {
  int i;
  for (i = 0; i < num - 1; i++) {
    char c = uart_getchar();
    str[i] = c;
    if (c == '\b') {
      uart_puts(" \b");
      i -= 2;
    } else if (c == '\r') {
      str[i] = 0;
      uart_putchar('\n');
      return str;
    }
  }
  str[num] = 0;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<uart_getsn>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  lea    -0x1(%rbp),%ebx
  test   %ebx,%ebx
  jle    L3
  xor    %r14d,%r14d
  lea    D3(%rip),%r13
  jmp    L21
  nopl   (%rax)
L29:
  cmp    $0xd,%al
  je     L16
  add    $0x1,%r14d
  cmp    %ebx,%r14d
  jge    L3
L21:
  xor    %eax,%eax
  call   <uart_getchar@plt>
  movslq %r14d,%rdx
  add    %r12,%rdx
  mov    %al,(%rdx)
  cmp    $0x8,%al
  jne    L29
  sub    $0x2,%r14d
  mov    %r13,%rdi
  call   <uart_puts@plt>
  add    $0x1,%r14d
  cmp    %ebx,%r14d
  jl     L21
L3:
  pop    %rbx
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L16:
  movb   $0x0,(%rdx)
  mov    $0xa,%edi
  call   <uart_putchar@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3:  

assistant: ```c
char *uart_getsn(char *str, int num) {
  int i;
  for (i = 0; i < num - 1; i++) {
    char c = uart_getchar();
    str[i] = c;
    if (c == '\b') {
      uart_puts(" \b");
      i -= 2;
    } else if (c == '\r') {
      str[i] = 0;
      uart_putchar('\n');
      return str;
    }
  }
  str[num] = 0;
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<init_newtracelogmsq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  or     $0x1b4,%eax
  mov    %eax,%esi
  mov    $0xd05,%edi
  call   <msgget@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L29
  mov    $0xffffffff,%eax
  jmp    L5
L29:
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <msgctl@plt>
  movl   $0xc800,-0x10(%rbp)
  mov    D29(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <msgctl@plt>
  mov    -0xc(%rbp),%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int init_newtracelogmsq() {
  int msqid;
  struct msqid_ds buf;
  msqid = msgget(3333, IPC_CREAT | 0664);
  if (msqid < 0)
    return -1;
  msgctl(msqid, IPC_STAT, &buf);
  buf.msg_qbytes = 50 * 1024;
  msgctl(msqid, IPC_SET, &buf);
  return msqid;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_newtracelogmsq>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  or     $0x1b4,%esi
  mov    $0xd05,%edi
  call   <msgget@plt>
  test   %eax,%eax
  js     L10
  mov    %eax,%ebx
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <msgctl@plt>
  movl   $0xc800,0x4(%rsp)
  mov    %rbp,%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <msgctl@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0xffffffff,%ebx
  jmp    L1
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int init_newtracelogmsq() {
  int msqid;
  struct msqid_ds buf;
  msqid = msgget(3333, IPC_CREAT | 0664);
  if (msqid < 0)
    return -1;
  msgctl(msqid, IPC_STAT, &buf);
  buf.msg_qbytes = 50 * 1024;
  msgctl(msqid, IPC_SET, &buf);
  return msqid;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_newtracelogmsq>:
  endbr64
  push   %r13
  mov    $0xd05,%edi
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  or     $0x1b4,%esi
  call   <msgget@plt>
  test   %eax,%eax
  js     L8
  mov    %eax,%r12d
  mov    D25(%rip),%rax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  mov    %r12d,%edi
  mov    (%rax),%esi
  call   <msgctl@plt>
  mov    D16(%rip),%rax
  mov    %r13,%rdx
  mov    %r12d,%edi
  movl   $0xc800,0x4(%rsp)
  mov    (%rax),%esi
  call   <msgctl@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%r12d
  jmp    L2
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int init_newtracelogmsq() {
  int msqid;
  struct msqid_ds buf;
  msqid = msgget(3333, IPC_CREAT | 0664);
  if (msqid < 0)
    return -1;
  msgctl(msqid, IPC_STAT, &buf);
  buf.msg_qbytes = 50 * 1024;
  msgctl(msqid, IPC_SET, &buf);
  return msqid;
}
```