ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lran2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L44
  mov    D175(%rip),%eax
  test   %eax,%eax
  je     L47
L44:
  movl   $0x0,D175(%rip)
  mov    $0x24d69,%eax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rcx
  movabs $0x5dfc995681872319,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xae529,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,D28(%rip)
  mov    D28(%rip),%rax
  test   %rax,%rax
  jns    L48
  mov    D28(%rip),%rax
  neg    %rax
  mov    %rax,D85(%rip)
L48:
  movl   $0x0,-0x4(%rbp)
  jmp    L41
L36:
  mov    D85(%rip),%rax
  imul   $0x556,%rax,%rax
  lea    0x24d69(%rax),%rcx
  movabs $0x5dfc995681872319,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xae529,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,D85(%rip)
  mov    D85(%rip),%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  lea    D85(%rip),%rdx
  mov    %rax,(%rcx,%rdx,1)
  addl   $0x1,-0x4(%rbp)
L41:
  cmpl   $0x60,-0x4(%rbp)
  jle    L36
  mov    D85(%rip),%rax
  imul   $0x556,%rax,%rax
  lea    0x24d69(%rax),%rcx
  movabs $0x5dfc995681872319,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xae529,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,D11(%rip)
  mov    D11(%rip),%rax
  mov    %rax,D11(%rip)
L47:
  mov    D11(%rip),%rcx
  movabs $0xa8e83f5717c0a8e9,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x6,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D85(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,D201(%rip)
  mov    D11(%rip),%rax
  imul   $0x556,%rax,%rax
  lea    0x24d69(%rax),%rcx
  movabs $0x5dfc995681872319,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xae529,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,D201(%rip)
  mov    D201(%rip),%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  lea    D85(%rip),%rdx
  mov    %rax,(%rcx,%rdx,1)
  mov    D201(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
long lran2(long seed) {
  static int first = 1;
  static long x, y, v[97];
  int j;
  if (seed || first) {
    first = 0;
    x = (150889l - seed) % 714025l;
    if (x < 0)
      x = -x;
    for (j = 0; j < 97; j++) {
      x = (1366l * x + 150889l) % 714025l;
      v[j] = x;
    }
    x = (1366l * x + 150889l) % 714025l;
    y = x;
  }
  j = y % 97;
  y = v[j];
  x = (1366l * x + 150889l) % 714025l;
  v[j] = x;
  return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lran2>:
  endbr64
  test   %rdi,%rdi
  jne    L20
  cmpl   $0x0,D48(%rip)
  je     L7
  movl   $0x0,D48(%rip)
  movq   $0x24d69,D58(%rip)
  jmp    L32
L20:
  movl   $0x0,D48(%rip)
  mov    $0x24d69,%ecx
  sub    %rdi,%rcx
  movabs $0x5dfc995681872319,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xae529,%rax,%rdx
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmovs  %rsi,%rax
  mov    %rax,D1(%rip)
L32:
  mov    D1(%rip),%rdx
  lea    D1(%rip),%rcx
  lea    0x308(%rcx),%r8
  movabs $0x5dfc995681872319,%rdi
L8:
  imul   $0x556,%rdx,%rdx
  lea    0x24d69(%rdx),%rsi
  mov    %rsi,%rax
  imul   %rdi
  sar    $0x12,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rsi
  mov    %rsi,%rdx
  mov    %rsi,(%rcx)
  add    $0x8,%rcx
  cmp    %r8,%rcx
  jne    L8
  mov    %rsi,D92(%rip)
  imul   $0x556,%rsi,%rdx
  lea    0x24d69(%rdx),%rcx
  movabs $0x5dfc995681872319,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0x12,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,D99(%rip)
  mov    %rcx,D99(%rip)
L7:
  mov    D99(%rip),%rcx
  movabs $0xa8e83f5717c0a8e9,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x6,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  lea    (%rax,%rax,2),%rdx
  shl    $0x5,%rdx
  add    %rdx,%rax
  sub    %rax,%rcx
  lea    D1(%rip),%r8
  movslq %ecx,%rcx
  mov    (%r8,%rcx,8),%rdi
  mov    %rdi,D2(%rip)
  imul   $0x556,0x3115(%rip),%rsi        # 4388 <x.2>
  add    $0x24d69,%rsi
  movabs $0x5dfc995681872319,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x12,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rsi
  mov    %rsi,D2(%rip)
  mov    %rsi,(%r8,%rcx,8)
  mov    %rdi,%rax
  ret
```

assistant: ```c
long lran2(long seed) {
  static int first = 1;
  static long x, y, v[97];
  int j;
  if (seed || first) {
    first = 0;
    x = (150889l - seed) % 714025l;
    if (x < 0)
      x = -x;
    for (j = 0; j < 97; j++) {
      x = (1366l * x + 150889l) % 714025l;
      v[j] = x;
    }
    x = (1366l * x + 150889l) % 714025l;
    y = x;
  }
  j = y % 97;
  y = v[j];
  x = (1366l * x + 150889l) % 714025l;
  v[j] = x;
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lran2>:
  endbr64
  test   %rdi,%rdi
  jne    L34
  mov    D43(%rip),%eax
  test   %eax,%eax
  je     L8
  movl   $0x0,D43(%rip)
  mov    $0x24d69,%edx
L26:
  lea    D75(%rip),%r9
  movabs $0x5dfc995681872319,%rdi
  mov    %r9,%rcx
  lea    0x308(%r9),%r8
  nopl   (%rax)
L15:
  imul   $0x556,%rdx,%rdx
  add    $0x8,%rcx
  lea    0x24d69(%rdx),%rsi
  mov    %rsi,%rax
  mul    %rdi
  shr    $0x12,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rsi
  mov    %rsi,-0x8(%rcx)
  mov    %rsi,%rdx
  cmp    %rcx,%r8
  jne    L15
  imul   $0x556,%rsi,%rdx
  lea    0x24d69(%rdx),%rcx
  mov    %rcx,%rax
  mul    %rdi
  mov    %rdx,%rdi
  shr    $0x12,%rdi
  imul   $0xae529,%rdi,%rax
  mov    %rcx,%rdi
  sub    %rax,%rdi
  mov    %rdi,%rsi
  jmp    L24
L8:
  mov    D35(%rip),%rdi
  mov    D26(%rip),%rsi
  lea    D75(%rip),%r9
L24:
  mov    %rdi,%rax
  imul   $0x556,%rsi,%rsi
  movabs $0xa8e83f5717c0a8e9,%rdx
  imul   %rdx
  add    $0x24d69,%rsi
  lea    (%rdx,%rdi,1),%rax
  mov    %rdi,%rdx
  sar    $0x3f,%rdx
  sar    $0x6,%rax
  sub    %rdx,%rax
  lea    (%rax,%rax,2),%rdx
  shl    $0x5,%rdx
  add    %rdx,%rax
  movabs $0x5dfc995681872319,%rdx
  sub    %rax,%rdi
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  movslq %edi,%rcx
  sar    $0x3f,%rax
  mov    (%r9,%rcx,8),%r8
  sar    $0x12,%rdx
  mov    %r8,D80(%rip)
  sub    %rax,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rsi
  mov    %r8,%rax
  mov    %rsi,D80(%rip)
  mov    %rsi,(%r9,%rcx,8)
  ret
L34:
  movabs $0x5dfc995681872319,%rdx
  mov    $0x24d69,%ecx
  movl   $0x0,D43(%rip)
  sub    %rdi,%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rax
  mov    %rcx,%rdx
  neg    %rax
  cmovns %rax,%rdx
  jmp    L26
```

assistant: ```c
long lran2(long seed) {
  static int first = 1;
  static long x, y, v[97];
  int j;
  if (seed || first) {
    first = 0;
    x = (150889l - seed) % 714025l;
    if (x < 0)
      x = -x;
    for (j = 0; j < 97; j++) {
      x = (1366l * x + 150889l) % 714025l;
      v[j] = x;
    }
    x = (1366l * x + 150889l) % 714025l;
    y = x;
  }
  j = y % 97;
  y = v[j];
  x = (1366l * x + 150889l) % 714025l;
  v[j] = x;
  return y;
}
```
user: What is the c source code of the assembly code below:

```asm
<lran2>:
  endbr64
  test   %rdi,%rdi
  jne    L35
  mov    D15(%rip),%eax
  test   %eax,%eax
  je     L26
  movl   $0x0,D15(%rip)
  mov    $0x24d69,%edx
L42:
  lea    D81(%rip),%r9
  movabs $0x5dfc995681872319,%rdi
  mov    %r9,%rcx
  lea    0x308(%r9),%r8
  nopl   (%rax)
L17:
  imul   $0x556,%rdx,%rdx
  add    $0x8,%rcx
  lea    0x24d69(%rdx),%rsi
  mov    %rsi,%rax
  mul    %rdi
  shr    $0x12,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rsi
  mov    %rsi,-0x8(%rcx)
  mov    %rsi,%rdx
  cmp    %rcx,%r8
  jne    L17
  imul   $0x556,%rsi,%rdx
  lea    0x24d69(%rdx),%rcx
  mov    %rcx,%rax
  mul    %rdi
  mov    %rdx,%rdi
  shr    $0x12,%rdi
  imul   $0xae529,%rdi,%rax
  mov    %rcx,%rdi
  sub    %rax,%rdi
  mov    %rdi,%rsi
  jmp    L12
L26:
  mov    D6(%rip),%rdi
  mov    D50(%rip),%rsi
  lea    D81(%rip),%r9
L12:
  mov    %rdi,%rax
  imul   $0x556,%rsi,%rsi
  movabs $0xa8e83f5717c0a8e9,%rdx
  imul   %rdx
  add    $0x24d69,%rsi
  lea    (%rdx,%rdi,1),%rax
  mov    %rdi,%rdx
  sar    $0x3f,%rdx
  sar    $0x6,%rax
  sub    %rdx,%rax
  lea    (%rax,%rax,2),%rdx
  shl    $0x5,%rdx
  add    %rdx,%rax
  movabs $0x5dfc995681872319,%rdx
  sub    %rax,%rdi
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  movslq %edi,%rcx
  sar    $0x3f,%rax
  mov    (%r9,%rcx,8),%r8
  sar    $0x12,%rdx
  mov    %r8,D25(%rip)
  sub    %rax,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rsi
  mov    %r8,%rax
  mov    %rsi,D25(%rip)
  mov    %rsi,(%r9,%rcx,8)
  ret
L35:
  movabs $0x5dfc995681872319,%rdx
  mov    $0x24d69,%ecx
  movl   $0x0,D15(%rip)
  sub    %rdi,%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  imul   $0xae529,%rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rax
  mov    %rcx,%rdx
  neg    %rax
  cmovns %rax,%rdx
  jmp    L42
```

assistant: ```c
long lran2(long seed) {
  static int first = 1;
  static long x, y, v[97];
  int j;
  if (seed || first) {
    first = 0;
    x = (150889l - seed) % 714025l;
    if (x < 0)
      x = -x;
    for (j = 0; j < 97; j++) {
      x = (1366l * x + 150889l) % 714025l;
      v[j] = x;
    }
    x = (1366l * x + 150889l) % 714025l;
    y = x;
  }
  j = y % 97;
  y = v[j];
  x = (1366l * x + 150889l) % 714025l;
  v[j] = x;
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dumpio_ednchg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %edx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L47
L42:
  mov    -0x4c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L26
L33:
  mov    -0x4c(%rbp),%eax
  sub    -0x38(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x38(%rbp)
L26:
  mov    -0x38(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L33
  mov    -0x4c(%rbp),%eax
  cltq
  add    %rax,-0x30(%rbp)
  addl   $0x1,-0x34(%rbp)
L47:
  mov    -0x34(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  jl     L42
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void dumpio_ednchg(void *avp_pointer, const int32_t ai_size, const int32_t ai_num) {
  int ai_csize, ai_cnum;
  char ac_buf[16];
  char *acp_tmp;
  char *acp_local;
  memset(ac_buf, '\0', sizeof(ac_buf));
  acp_tmp = avp_pointer;
  acp_local = avp_pointer;
  for (ai_cnum = 0; ai_cnum < ai_num; ai_cnum++) {
    memcpy(ac_buf, acp_local, ai_size);
    for (ai_csize = 0; ai_csize < ai_size; ai_csize++) {
      *acp_local = ac_buf[ai_size - ai_csize - 1];
      acp_local++;
    }
    acp_tmp += ai_size;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dumpio_ednchg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %r14d,%r14d
  jle    L31
  mov    $0x0,%r12d
  mov    %rsp,%r13
  movslq %ebp,%r15
  sub    $0x1,%r15
L28:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L41
  lea    0x0(%r13,%r15,1),%rax
  mov    %ebp,%ecx
  add    %rbx,%rcx
L14:
  movzbl (%rax),%edx
  mov    %dl,(%rbx)
  add    $0x1,%rbx
  sub    $0x1,%rax
  cmp    %rcx,%rbx
  jne    L14
  mov    %rcx,%rbx
L41:
  add    $0x1,%r12d
  cmp    %r12d,%r14d
  jne    L28
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dumpio_ednchg(void *avp_pointer, const int32_t ai_size, const int32_t ai_num) {
  int ai_csize, ai_cnum;
  char ac_buf[16];
  char *acp_tmp;
  char *acp_local;
  memset(ac_buf, '\0', sizeof(ac_buf));
  acp_tmp = avp_pointer;
  acp_local = avp_pointer;
  for (ai_cnum = 0; ai_cnum < ai_num; ai_cnum++) {
    memcpy(ac_buf, acp_local, ai_size);
    for (ai_csize = 0; ai_csize < ai_size; ai_csize++) {
      *acp_local = ac_buf[ai_size - ai_csize - 1];
      acp_local++;
    }
    acp_tmp += ai_size;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dumpio_ednchg>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  xor    %esi,%esi
  push   %r13
  push   %r12
  mov    %edx,%r12d
  mov    $0x10,%edx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    %r15,%rdi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L36
  xor    %r13d,%r13d
  movslq %r14d,%rbp
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  test   %r14d,%r14d
  jle    L40
  lea    -0x1(%r15,%rbp,1),%rax
  lea    (%rbx,%rbp,1),%rcx
  nopl   0x0(%rax)
L20:
  movzbl (%rax),%edx
  add    $0x1,%rbx
  sub    $0x1,%rax
  mov    %dl,-0x1(%rbx)
  cmp    %rcx,%rbx
  jne    L20
L40:
  add    $0x1,%r13d
  cmp    %r13d,%r12d
  jne    L34
L36:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dumpio_ednchg(void *avp_pointer, const int32_t ai_size, const int32_t ai_num) {
  int ai_csize, ai_cnum;
  char ac_buf[16];
  char *acp_tmp;
  char *acp_local;
  memset(ac_buf, '\0', sizeof(ac_buf));
  acp_tmp = avp_pointer;
  acp_local = avp_pointer;
  for (ai_cnum = 0; ai_cnum < ai_num; ai_cnum++) {
    memcpy(ac_buf, acp_local, ai_size);
    for (ai_csize = 0; ai_csize < ai_size; ai_csize++) {
      *acp_local = ac_buf[ai_size - ai_csize - 1];
      acp_local++;
    }
    acp_tmp += ai_size;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x12(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <getText@plt>
  lea    -0x12(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  lea    -0x12(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <insertionSort@plt>
  lea    -0x12(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D5: Type away!: 

assistant: ```c
void main() {
  char array[10];
  printf("Type away!: ");
  getText(array, 10);
  printArray(array, 10);
  insertionSort(array, 10);
  printArray(array, 10);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0xe(%rsp),%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <getText@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <insertionSort@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: Type away!: 

assistant: ```c
void main() {
  char array[10];
  printf("Type away!: ");
  getText(array, 10);
  printArray(array, 10);
  insertionSort(array, 10);
  printArray(array, 10);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <getText@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <insertionSort@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: Type away!: 

assistant: ```c
void main() {
  char array[10];
  printf("Type away!: ");
  getText(array, 10);
  printArray(array, 10);
  insertionSort(array, 10);
  printArray(array, 10);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <getText@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <insertionSort@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D0: Type away!: 

assistant: ```c
void main() {
  char array[10];
  printf("Type away!: ");
  getText(array, 10);
  printArray(array, 10);
  insertionSort(array, 10);
  printArray(array, 10);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<csc_path_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L34
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <csc_isdelim@plt>
  test   %rax,%rax
  jne    L7
  subl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x0,-0x4(%rbp)
  jns    L0
  jmp    L3
L7:
  nop
L3:
  cmpl   $0x0,-0x4(%rbp)
  js     L82
  addl   $0x2,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L52
  mov    -0x4(%rbp),%edx
  mov    -0x24(%rbp),%eax
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <csc_strlcpy@plt>
L52:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L30
L82:
  cmpq   $0x0,-0x20(%rbp)
  je     L35
  cmpl   $0x3,-0x24(%rbp)
  jle    L35
  mov    -0x20(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L35:
  mov    -0x18(%rbp),%rax
L30:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D14: /

tool: D1: .

assistant: ```c
char *csc_path_path(char *path, char *buffer, int blen) {
  int i;
  for (i = strlen(path) - 1; i >= 0; i--) {
    if (csc_isdelim("/", path[i])) {
      break;
    }
  }
  if (i >= 0) {
    i += 2;
    if (buffer) {
      csc_strlcpy(buffer, path, i > blen ? blen : i);
    }
    return path + i - 1;
  }
  if (buffer && (blen > 3)) {
    strcpy(buffer, ".");
    strcat(buffer, "/");
  }
  return path;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<csc_path_path>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %edx,%r15d
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L41
  movslq %eax,%rbx
  lea    D6(%rip),%r13
L0:
  mov    %ebx,%r12d
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r13,%rdi
  call   <csc_isdelim@plt>
  test   %rax,%rax
  jne    L84
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L0
L41:
  test   %r14,%r14
  je     L76
  cmp    $0x3,%r15d
  jg     L8
L76:
  mov    %rbp,%rax
  jmp    L61
L84:
  test   %ebx,%ebx
  js     L41
  add    $0x2,%r12d
  test   %r14,%r14
  je     L45
  cmp    %r12d,%r15d
  mov    %r15d,%edx
  cmovg  %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <csc_strlcpy@plt>
L45:
  movslq %r12d,%r12
  lea    -0x1(%rbp,%r12,1),%rax
L61:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  lea    D3(%rip),%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  lea    D6(%rip),%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  mov    %rbp,%rax
  jmp    L61
```

tool_calls: name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D3
datatype: string

tool: D6: /

tool: D3: .

assistant: ```c
char *csc_path_path(char *path, char *buffer, int blen) {
  int i;
  for (i = strlen(path) - 1; i >= 0; i--) {
    if (csc_isdelim("/", path[i])) {
      break;
    }
  }
  if (i >= 0) {
    i += 2;
    if (buffer) {
      csc_strlcpy(buffer, path, i > blen ? blen : i);
    }
    return path + i - 1;
  }
  if (buffer && (blen > 3)) {
    strcpy(buffer, ".");
    strcat(buffer, "/");
  }
  return path;
}
```