ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lngpio_read>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %edi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    D8(%rip),%rdx
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    0xc(%rsp),%rdx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0xc(%rsp),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x40,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D9
data_type: string

tool: D8: /sys/class/gpio/gpio%d/value

tool: D24: rw

tool: D9: %d

assistant: ```c
int lngpio_read(int pin) {
  char path[30];
  FILE *f;
  int result;
  snprintf(path, 30, "/sys/class/gpio/gpio%d/value", pin);
  f = fopen(path, "rw");
  fscanf(f, "%d", &result);
  fclose(f);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lngpio_read>:
  endbr64
  push   %rbp
  mov    %edi,%ecx
  lea    D28(%rip),%rdx
  mov    $0x1e,%esi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  lea    D23(%rip),%rsi
  call   <fopen@plt>
  lea    0xc(%rsp),%rdx
  lea    D17(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0xc(%rsp),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x40,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
datatype: string
name: retrieve_data
arguments: data_tag: D23
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string

tool: D28: /sys/class/gpio/gpio%d/value

tool: D23: rw

tool: D17: %d

assistant: ```c
int lngpio_read(int pin) {
  char path[30];
  FILE *f;
  int result;
  snprintf(path, 30, "/sys/class/gpio/gpio%d/value", pin);
  f = fopen(path, "rw");
  fscanf(f, "%d", &result);
  fclose(f);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lngpio_read>:
  endbr64
  push   %rbp
  mov    %edi,%ecx
  lea    D4(%rip),%rdx
  mov    $0x1e,%esi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  lea    D9(%rip),%rsi
  call   <fopen@plt>
  lea    0xc(%rsp),%rdx
  lea    D23(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0xc(%rsp),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x40,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D9
datatype: string
name: disassemble_data
arguments: data_label: D23
datatype: string

tool: D4: /sys/class/gpio/gpio%d/value

tool: D9: rw

tool: D23: %d

assistant: ```c
int lngpio_read(int pin) {
  char path[30];
  FILE *f;
  int result;
  snprintf(path, 30, "/sys/class/gpio/gpio%d/value", pin);
  f = fopen(path, "rw");
  fscanf(f, "%d", &result);
  fclose(f);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<elapsed_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double elapsed_time(struct timeval *tv_first, struct timeval *tv_end) {
  double elapsed_msec;
  elapsed_msec = (tv_end->tv_sec - tv_first->tv_sec) * 1000;
  elapsed_msec += (tv_end->tv_usec - tv_first->tv_usec) / 1000;
  return elapsed_msec;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<elapsed_time>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  imul   $0x3e8,%eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    0x4(%rsi),%edx
  sub    0x4(%rdi),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double elapsed_time(struct timeval *tv_first, struct timeval *tv_end) {
  double elapsed_msec;
  elapsed_msec = (tv_end->tv_sec - tv_first->tv_sec) * 1000;
  elapsed_msec += (tv_end->tv_usec - tv_first->tv_usec) / 1000;
  return elapsed_msec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<elapsed_time>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  imul   $0x3e8,%eax,%eax
  mov    0x4(%rsi),%edx
  sub    0x4(%rdi),%edx
  cvtsi2sd %eax,%xmm1
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double elapsed_time(struct timeval *tv_first, struct timeval *tv_end) {
  double elapsed_msec;
  elapsed_msec = (tv_end->tv_sec - tv_first->tv_sec) * 1000;
  elapsed_msec += (tv_end->tv_usec - tv_first->tv_usec) / 1000;
  return elapsed_msec;
}
```
user: What is the c source code of the assembly code below:

```asm
<elapsed_time>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  imul   $0x3e8,%eax,%eax
  mov    0x4(%rsi),%edx
  sub    0x4(%rdi),%edx
  cvtsi2sd %eax,%xmm1
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double elapsed_time(struct timeval *tv_first, struct timeval *tv_end) {
  double elapsed_msec;
  elapsed_msec = (tv_end->tv_sec - tv_first->tv_sec) * 1000;
  elapsed_msec += (tv_end->tv_usec - tv_first->tv_usec) / 1000;
  return elapsed_msec;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmodel_is_yuv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x1b,%eax
  seta   %dl
  test   %dl,%dl
  jne    L24
  mov    $0x80fe080,%edx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L24
  mov    $0x1,%eax
  jmp    L8
L24:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int cmodel_is_yuv(int colormodel) {
  switch (colormodel) {
  case 13:
  case 14:
  case 15:
  case 16:
  case 19:
  case 7:
  case 17:
  case 27:
  case 18:
    return 1;
    break;
  default:
    return 0;
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cmodel_is_yuv>:
  endbr64
  cmp    $0x1b,%edi
  ja     L2
  mov    $0x80fe080,%eax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int cmodel_is_yuv(int colormodel) {
  switch (colormodel) {
  case 13:
  case 14:
  case 15:
  case 16:
  case 19:
  case 7:
  case 17:
  case 27:
  case 18:
    return 1;
    break;
  default:
    return 0;
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmodel_is_yuv>:
  endbr64
  cmp    $0x1b,%edi
  ja     L8
  mov    %edi,%ecx
  mov    $0x80fe080,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmodel_is_yuv(int colormodel) {
  switch (colormodel) {
  case 13:
  case 14:
  case 15:
  case 16:
  case 19:
  case 7:
  case 17:
  case 27:
  case 18:
    return 1;
    break;
  default:
    return 0;
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmodel_is_yuv>:
  endbr64
  cmp    $0x1b,%edi
  ja     L6
  mov    %edi,%ecx
  mov    $0x80fe080,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmodel_is_yuv(int colormodel) {
  switch (colormodel) {
  case 13:
  case 14:
  case 15:
  case 16:
  case 19:
  case 7:
  case 17:
  case 27:
  case 18:
    return 1;
    break;
  default:
    return 0;
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isLeapYear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x62d,-0x4(%rbp)
  jg     L8
  mov    $0x0,%eax
  jmp    L31
L8:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L13
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L11
L13:
  mov    $0x1,%eax
  jmp    L31
L11:
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int isLeapYear(int year) {
  if (year < 1582)
    return 0;
  return year % 4 == 0 || year % 400 == 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isLeapYear>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x62d,%edi
  jle    L15
  mov    $0x1,%eax
  test   $0x3,%dil
  je     L15
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%edi
  sete   %al
  movzbl %al,%eax
L15:
  ret
```

assistant: ```c
int isLeapYear(int year) {
  if (year < 1582)
    return 0;
  return year % 4 == 0 || year % 400 == 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isLeapYear>:
  endbr64
  xor    %eax,%eax
  cmp    $0x62d,%edi
  jle    L5
  mov    $0x1,%eax
  test   $0x3,%dil
  jne    L6
L5:
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  imul   $0xc28f5c29,%edi,%edi
  xor    %eax,%eax
  add    $0x51eb850,%edi
  ror    $0x4,%edi
  cmp    $0xa3d70a,%edi
  setbe  %al
  ret
```

assistant: ```c
int isLeapYear(int year) {
  if (year < 1582)
    return 0;
  return year % 4 == 0 || year % 400 == 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isLeapYear>:
  endbr64
  xor    %eax,%eax
  cmp    $0x62d,%edi
  jle    L19
  mov    $0x1,%eax
  test   $0x3,%dil
  jne    L13
L19:
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  imul   $0xc28f5c29,%edi,%edi
  xor    %eax,%eax
  add    $0x51eb850,%edi
  ror    $0x4,%edi
  cmp    $0xa3d70a,%edi
  setbe  %al
  ret
```

assistant: ```c
int isLeapYear(int year) {
  if (year < 1582)
    return 0;
  return year % 4 == 0 || year % 400 == 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdx
  mov    $0x1bbc,%esi
  mov    $0x1b58,%edi
  call   <dotest@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdx
  mov    $0x11265,%esi
  mov    $0x11170,%edi
  call   <dotest@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdx
  mov    $0x113c8,%esi
  mov    $0x11355,%edi
  call   <dotest@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdx
  mov    $0x11170,%esi
  mov    $0xea60,%edi
  call   <dotest@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D6
type: string
name: parse_data
arguments: tag: D3
type: string
name: parse_data
arguments: tag: D33
type: string

tool: D7: 7027, 7043, 7057

tool: D6: 70001, 70009, 70061, 70079, 70121, 70141, 70163, 70241

tool: D3: 70489, 70529, 70573, 70589

tool: 

assistant: ```c
int main() {
  dotest(7000, 7100, "7027, 7043, 7057");
  dotest(70000, 70245, "70001, 70009, 70061, 70079, 70121, 70141, 70163, 70241");
  dotest(70485, 70600, "70489, 70529, 70573, 70589");
  dotest(60000, 70000, "");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdx
  mov    $0x1bbc,%esi
  mov    $0x1b58,%edi
  call   <dotest@plt>
  lea    D1(%rip),%rdx
  mov    $0x11265,%esi
  mov    $0x11170,%edi
  call   <dotest@plt>
  lea    D19(%rip),%rdx
  mov    $0x113c8,%esi
  mov    $0x11355,%edi
  call   <dotest@plt>
  lea    D2(%rip),%rdx
  mov    $0x11170,%esi
  mov    $0xea60,%edi
  call   <dotest@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D21: 7027, 7043, 7057

tool: D1: 70001, 70009, 70061, 70079, 70121, 70141, 70163, 70241

tool: D19: 70489, 70529, 70573, 70589

tool: 

assistant: ```c
int main() {
  dotest(7000, 7100, "7027, 7043, 7057");
  dotest(70000, 70245, "70001, 70009, 70061, 70079, 70121, 70141, 70163, 70241");
  dotest(70485, 70600, "70489, 70529, 70573, 70589");
  dotest(60000, 70000, "");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1bbc,%esi
  mov    $0x1b58,%edi
  lea    D23(%rip),%rdx
  call   <dotest@plt>
  mov    $0x11265,%esi
  mov    $0x11170,%edi
  lea    D19(%rip),%rdx
  call   <dotest@plt>
  mov    $0x113c8,%esi
  mov    $0x11355,%edi
  lea    D26(%rip),%rdx
  call   <dotest@plt>
  mov    $0x11170,%esi
  mov    $0xea60,%edi
  lea    D22(%rip),%rdx
  call   <dotest@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D26
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string

tool: D23: 7027, 7043, 7057

tool: D19: 70001, 70009, 70061, 70079, 70121, 70141, 70163, 70241

tool: D26: 70489, 70529, 70573, 70589

tool: 

assistant: ```c
int main() {
  dotest(7000, 7100, "7027, 7043, 7057");
  dotest(70000, 70245, "70001, 70009, 70061, 70079, 70121, 70141, 70163, 70241");
  dotest(70485, 70600, "70489, 70529, 70573, 70589");
  dotest(60000, 70000, "");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1bbc,%esi
  mov    $0x1b58,%edi
  lea    D15(%rip),%rdx
  call   <dotest@plt>
  mov    $0x11265,%esi
  mov    $0x11170,%edi
  lea    D0(%rip),%rdx
  call   <dotest@plt>
  mov    $0x113c8,%esi
  mov    $0x11355,%edi
  lea    D36(%rip),%rdx
  call   <dotest@plt>
  mov    $0x11170,%esi
  mov    $0xea60,%edi
  lea    D35(%rip),%rdx
  call   <dotest@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type: string
name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D36
type: string
name: disassemble_data
arguments: tag: D35
type: string

tool: D15: 7027, 7043, 7057

tool: D0: 70001, 70009, 70061, 70079, 70121, 70141, 70163, 70241

tool: D36: 70489, 70529, 70573, 70589

tool: 

assistant: ```c
int main() {
  dotest(7000, 7100, "7027, 7043, 7057");
  dotest(70000, 70245, "70001, 70009, 70061, 70079, 70121, 70141, 70163, 70241");
  dotest(70485, 70600, "70489, 70529, 70573, 70589");
  dotest(60000, 70000, "");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x5,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <findMaxMultupleOf3@plt>
  test   %rax,%rax
  jne    L14
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: not possible

assistant: ```c
int main() {
  int arr[] = {8, 1, 7, 6, 0};
  int size = sizeof(arr) / sizeof(arr[0]);
  if (findMaxMultupleOf3(arr, size) == 0)
    printf("not possible");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x8,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x7,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <findMaxMultupleOf3@plt>
  test   %rax,%rax
  je     L1
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: not possible

assistant: ```c
int main() {
  int arr[] = {8, 1, 7, 6, 0};
  int size = sizeof(arr) / sizeof(arr[0]);
  if (findMaxMultupleOf3(arr, size) == 0)
    printf("not possible");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000008,%rax
  mov    %rsp,%rdi
  movl   $0x0,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x600000007,%rax
  mov    %rax,0x8(%rsp)
  call   <findMaxMultupleOf3@plt>
  test   %rax,%rax
  je     L20
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L20:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: not possible

assistant: ```c
int main() {
  int arr[] = {8, 1, 7, 6, 0};
  int size = sizeof(arr) / sizeof(arr[0]);
  if (findMaxMultupleOf3(arr, size) == 0)
    printf("not possible");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D3(%rip),%xmm0
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <findMaxMultupleOf3@plt>
  test   %rax,%rax
  je     L27
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L27:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type: byte[16]
name: read_data
arguments: data_label: D19
type: string

tool: {"D3": [0x08,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D19: not possible

assistant: ```c
int main() {
  int arr[] = {8, 1, 7, 6, 0};
  int size = sizeof(arr) / sizeof(arr[0]);
  if (findMaxMultupleOf3(arr, size) == 0)
    printf("not possible");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  jmp    L8
L77:
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x1b(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x19(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0x1b(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,(%rbx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L67
  movzbl -0x1b(%rbp),%eax
  cmp    $0x30,%al
  jne    L10
  movzbl -0x1a(%rbp),%eax
  cmp    $0x30,%al
  je     L67
L10:
  mov    $0xffffffff,%eax
  jmp    L53
L67:
  addl   $0x1,-0x20(%rbp)
L8:
  cmpl   $0x1f,-0x20(%rbp)
  jle    L77
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L45
  mov    $0xffffffff,%eax
  jmp    L53
L45:
  mov    $0x0,%eax
L53:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int parse_key(const char *ascii, uint8_t key[0x20]) {
  int i;
  for (i = 0; i < 0x20; i++) {
    char byte[3];
    memcpy(byte, &ascii[2 * i], 2);
    byte[2] = '\0';
    key[i] = strtol(byte, NULL, 16);
    if (key[i] == 0 && !(byte[0] == '0' && byte[1] == '0')) {
      return -1;
    }
  }
  if (ascii[2 * i] != '\0') {
    return -1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_key>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    $0x1,%ebx
  lea    0x5(%rsp),%r12
  jmp    L69
L52:
  mov    %ebx,%eax
  add    $0x1,%rbx
  add    $0x2,%rbp
  cmp    $0x21,%rbx
  je     L59
L69:
  mov    $0x2,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x7(%rsp)
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %eax,-0x4(%r13,%rbx,4)
  test   %eax,%eax
  jne    L52
  cmpb   $0x30,0x5(%rsp)
  jne    L34
  cmpb   $0x30,0x6(%rsp)
  je     L52
L34:
  mov    $0xffffffff,%eax
L63:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  add    %eax,%eax
  cltq
  movzbl (%r14,%rax,1),%eax
  neg    %al
  sbb    %eax,%eax
  jmp    L63
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_key(const char *ascii, uint8_t key[0x20]) {
  int i;
  for (i = 0; i < 0x20; i++) {
    char byte[3];
    memcpy(byte, &ascii[2 * i], 2);
    byte[2] = '\0';
    key[i] = strtol(byte, NULL, 16);
    if (key[i] == 0 && !(byte[0] == '0' && byte[1] == '0')) {
      return -1;
    }
  }
  if (ascii[2 * i] != '\0') {
    return -1;
  } else {
    return 0;
  }
}
```