ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L23
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x5,%esi
  jle    L33
  mov    $0x5,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L1:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %eax,%r8d
  cmp    %esi,%ecx
  jl     L1
L45:
  mov    %r8d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jg     L36
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L33:
  xor    %r8d,%r8d
  jmp    L45
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: %d


assistant: ```c
int main() {
  int test_count;
  int number;
  int number_of_zeroes;
  scanf("%d\n", &test_count);
  while (test_count > 0) {
    number_of_zeroes = 0;
    scanf("%d\n", &number);
    int divider = 5;
    while (divider < number) {
      number_of_zeroes += (number / divider);
      divider *= 5;
    }
    printf("%d\n", number_of_zeroes);
    test_count--;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tty_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x18(%rbp)
  je     L34
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  jmp    L58
L34:
  mov    $0x0,%eax
L58:
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L69
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  jmp    L3
L69:
  mov    $0x0,%eax
L3:
  mov    -0xc(%rbp),%edx
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  jne    L11
  mov    $0x0,%eax
  jmp    L16
L11:
  mov    $0x1,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int tty_set(int fd, int rts, int dtr) {
  int mask;
  mask = rts ? TIOCM_RTS : 0;
  mask |= dtr ? TIOCM_DTR : 0;
  if (ioctl(fd, TIOCMBIS, &mask) == -1) {
    do {
    } while (0);
    do {
    } while (0);
    return (0);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tty_set>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L22
  mov    D3(%rip),%rax
  mov    (%rax),%esi
L22:
  test   %edx,%edx
  je     L5
  mov    D0(%rip),%rax
  mov    (%rax),%edx
L5:
  or     %edx,%esi
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tty_set(int fd, int rts, int dtr) {
  int mask;
  mask = rts ? TIOCM_RTS : 0;
  mask |= dtr ? TIOCM_DTR : 0;
  if (ioctl(fd, TIOCMBIS, &mask) == -1) {
    do {
    } while (0);
    do {
    } while (0);
    return (0);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tty_set>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L13
  mov    D13(%rip),%rax
  mov    (%rax),%esi
L13:
  test   %edx,%edx
  je     L19
  mov    D22(%rip),%rax
  or     (%rax),%esi
L19:
  mov    D7(%rip),%rax
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tty_set(int fd, int rts, int dtr) {
  int mask;
  mask = rts ? TIOCM_RTS : 0;
  mask |= dtr ? TIOCM_DTR : 0;
  if (ioctl(fd, TIOCMBIS, &mask) == -1) {
    do {
    } while (0);
    do {
    } while (0);
    return (0);
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tty_set>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L19
  mov    D15(%rip),%rax
  mov    (%rax),%esi
L19:
  test   %edx,%edx
  je     L21
  mov    D14(%rip),%rax
  or     (%rax),%esi
L21:
  mov    D11(%rip),%rax
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tty_set(int fd, int rts, int dtr) {
  int mask;
  mask = rts ? TIOCM_RTS : 0;
  mask |= dtr ? TIOCM_DTR : 0;
  if (ioctl(fd, TIOCMBIS, &mask) == -1) {
    do {
    } while (0);
    do {
    } while (0);
    return (0);
  }
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jge    L9
  mov    -0x8(%rbp),%rax
  jmp    L18
L9:
  mov    -0x10(%rbp),%rax
L18:
  pop    %rbp
  ret
```

assistant: ```c
long Min(const long a, const long b) {
  if (a < b)
    return a;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Min>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rax
  ret
```

assistant: ```c
long Min(const long a, const long b) {
  if (a < b)
    return a;
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Min>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rax
  ret
```

assistant: ```c
long Min(const long a, const long b) {
  if (a < b)
    return a;
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Min>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rax
  ret
```

assistant: ```c
long Min(const long a, const long b) {
  if (a < b)
    return a;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L0
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L24
L0:
  mov    $0x0,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int is_file(const char *path) {
  struct stat statbuf;
  if (lstat(path, &statbuf) == 0)
    return S_ISREG(statbuf.st_mode) != 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L4
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L4:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L15
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_file(const char *path) {
  struct stat statbuf;
  if (lstat(path, &statbuf) == 0)
    return S_ISREG(statbuf.st_mode) != 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L13
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L13:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L4
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_file(const char *path) {
  struct stat statbuf;
  if (lstat(path, &statbuf) == 0)
    return S_ISREG(statbuf.st_mode) != 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L10
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L10:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L16
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_file(const char *path) {
  struct stat statbuf;
  if (lstat(path, &statbuf) == 0)
    return S_ISREG(statbuf.st_mode) != 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1f5c(%rbp)
  jmp    L60
L75:
  mov    -0x1f5c(%rbp),%eax
  movl   $0x1,-0x1f50(%rbp,%rax,4)
  addl   $0x1,-0x1f5c(%rbp)
L60:
  cmpl   $0x7d0,-0x1f5c(%rbp)
  jbe    L75
  movl   $0x0,-0x1f60(%rbp)
  jmp    L74
L79:
  movl   $0x0,-0x1f5c(%rbp)
  jmp    L28
L81:
  mov    -0x1f5c(%rbp),%eax
  mov    -0x1f50(%rbp,%rax,4),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x1f5c(%rbp),%eax
  mov    %edx,-0x1f50(%rbp,%rax,4)
  addl   $0x1,-0x1f5c(%rbp)
L28:
  cmpl   $0x7d0,-0x1f5c(%rbp)
  jbe    L81
  movl   $0x0,-0x1f58(%rbp)
  movl   $0x7d0,-0x1f5c(%rbp)
  jmp    L29
L64:
  mov    -0x1f5c(%rbp),%eax
  mov    -0x1f50(%rbp,%rax,4),%edx
  mov    -0x1f58(%rbp),%eax
  add    %eax,%edx
  mov    -0x1f5c(%rbp),%eax
  mov    %edx,-0x1f50(%rbp,%rax,4)
  mov    -0x1f5c(%rbp),%eax
  mov    -0x1f50(%rbp,%rax,4),%eax
  mov    -0x1f5c(%rbp),%edx
  lea    0x1(%rdx),%esi
  mov    $0x0,%edx
  div    %esi
  mov    %eax,-0x1f58(%rbp)
  mov    -0x1f5c(%rbp),%eax
  mov    -0x1f50(%rbp,%rax,4),%eax
  mov    -0x1f5c(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,-0x1f54(%rbp)
  mov    -0x1f5c(%rbp),%eax
  mov    -0x1f54(%rbp),%edx
  mov    %edx,-0x1f50(%rbp,%rax,4)
  subl   $0x1,-0x1f5c(%rbp)
L29:
  cmpl   $0x0,-0x1f5c(%rbp)
  jne    L64
  mov    -0x1f58(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x1f60(%rbp)
L74:
  cmpl   $0x7ce,-0x1f60(%rbp)
  jbe    L79
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: 

assistant: ```c
void main(void) {
  unsigned int i, j;
  unsigned int q, r;
  unsigned int d[2000 + 1];
  for (j = 0; j < 2000 + 1; j++) {
    d[j] = 1;
  }
  for (i = 0; i < 2000 - 1; i++) {
    for (j = 0; j < 2000 + 1; j++) {
      d[j] *= 10;
    }
    q = 0;
    for (j = 2000; j > 0; j--) {
      d[j] += q;
      q = d[j] / (j + 1);
      r = d[j] % (j + 1);
      d[j] = r;
    }
    putchar('0' + q);
  }
  puts("");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x1f44(%rsp),%rbp
  mov    %rbx,%rax
L31:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L31
  mov    $0x7cf,%r12d
  mov    $0x0,%r13d
L21:
  mov    %rbx,%rax
L33:
  mov    (%rax),%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L33
  lea    0x1f40(%rsp),%rcx
  mov    $0x7d1,%esi
  mov    %r13d,%eax
L28:
  add    (%rcx),%eax
  mov    $0x0,%edx
  div    %esi
  mov    %edx,(%rcx)
  sub    $0x4,%rcx
  sub    $0x1,%esi
  cmp    %rbx,%rcx
  jne    L28
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  sub    $0x1,%r12d
  jne    L21
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    0x1f48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1f58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: 

assistant: ```c
void main(void) {
  unsigned int i, j;
  unsigned int q, r;
  unsigned int d[2000 + 1];
  for (j = 0; j < 2000 + 1; j++) {
    d[j] = 1;
  }
  for (i = 0; i < 2000 - 1; i++) {
    for (j = 0; j < 2000 + 1; j++) {
      d[j] *= 10;
    }
    q = 0;
    for (j = 2000; j > 0; j--) {
      d[j] += q;
      q = d[j] / (j + 1);
      r = d[j] % (j + 1);
      d[j] = r;
    }
    putchar('0' + q);
  }
  puts("");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x1f44(%rsp),%r13
  mov    %r12,%rax
L3:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %r13,%rax
  jne    L3
  mov    $0x7cf,%ebx
  lea    0x1f40(%rsp),%rbp
L5:
  mov    %r12,%rax
  nopl   (%rax)
L40:
  mov    (%rax),%edx
  add    $0x4,%rax
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %edx,-0x4(%rax)
  cmp    %r13,%rax
  jne    L40
  mov    %rbp,%rcx
  mov    $0x7d1,%esi
  xor    %eax,%eax
  nopl   (%rax)
L20:
  add    (%rcx),%eax
  xor    %edx,%edx
  sub    $0x4,%rcx
  div    %esi
  sub    $0x1,%esi
  mov    %edx,0x4(%rcx)
  cmp    %r12,%rcx
  jne    L20
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L5
  mov    0x1f48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x1f58,%rsp
  lea    D5(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <puts@plt>
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: 

assistant: ```c
void main(void) {
  unsigned int i, j;
  unsigned int q, r;
  unsigned int d[2000 + 1];
  for (j = 0; j < 2000 + 1; j++) {
    d[j] = 1;
  }
  for (i = 0; i < 2000 - 1; i++) {
    for (j = 0; j < 2000 + 1; j++) {
      d[j] *= 10;
    }
    q = 0;
    for (j = 2000; j > 0; j--) {
      d[j] += q;
      q = d[j] / (j + 1);
      r = d[j] % (j + 1);
      d[j] = r;
    }
    putchar('0' + q);
  }
  puts("");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf50,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1f40(%rsp),%rbx
  mov    %rbp,%rax
L37:
  movaps %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rax,%rbx
  jne    L37
  movl   $0x1,0x1f40(%rsp)
  mov    $0x7cf,%r12d
L25:
  mov    %rbp,%rax
  nopl   0x0(%rax)
L35:
  movdqa (%rax),%xmm0
  add    $0x10,%rax
  pslld  $0x2,%xmm0
  paddd  -0x10(%rax),%xmm0
  pslld  $0x1,%xmm0
  movaps %xmm0,-0x10(%rax)
  cmp    %rbx,%rax
  jne    L35
  mov    0x1f40(%rsp),%eax
  mov    %rbx,%rcx
  mov    $0x7d1,%esi
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,0x1f40(%rsp)
  xor    %eax,%eax
L17:
  add    (%rcx),%eax
  xor    %edx,%edx
  sub    $0x4,%rcx
  div    %esi
  sub    $0x1,%esi
  mov    %edx,0x4(%rcx)
  cmp    %rcx,%rbp
  jne    L17
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  sub    $0x1,%r12d
  jne    L25
  mov    0x1f48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x1f50,%rsp
  lea    D9(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1080 <puts@plt>
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: {"D7": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: 

assistant: ```c
void main(void) {
  unsigned int i, j;
  unsigned int q, r;
  unsigned int d[2000 + 1];
  for (j = 0; j < 2000 + 1; j++) {
    d[j] = 1;
  }
  for (i = 0; i < 2000 - 1; i++) {
    for (j = 0; j < 2000 + 1; j++) {
      d[j] *= 10;
    }
    q = 0;
    for (j = 2000; j > 0; j--) {
      d[j] += q;
      q = d[j] / (j + 1);
      r = d[j] % (j + 1);
      d[j] = r;
    }
    putchar('0' + q);
  }
  puts("");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <test@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test(2, 2);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <test@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(2, 2);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <test@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(2, 2);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <test@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(2, 2);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sigtimedwait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
L5:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%r8d
  mov    %rax,%rsi
  mov    $0xb1,%edi
  call   <syscall_cp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  mov    D2(%rip),%rax
  mov    (%rax),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L5
L17:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sigtimedwait(const sigset_t *mask, siginfo_t *si, const struct timespec *timeout) {
  int ret;
  do
    ret = syscall_cp(177, mask, si, timeout, 8);
  while (ret < 0 && errno == EINTR);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sigtimedwait>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
L6:
  mov    $0x8,%r8d
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0xb1,%edi
  call   <syscall_cp@plt>
  test   %eax,%eax
  jns    L5
  mov    D13(%rip),%rcx
  mov    D11(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L6
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sigtimedwait(const sigset_t *mask, siginfo_t *si, const struct timespec *timeout) {
  int ret;
  do
    ret = syscall_cp(177, mask, si, timeout, 8);
  while (ret < 0 && errno == EINTR);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sigtimedwait>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L20:
  mov    D14(%rip),%rdx
  mov    D3(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L18
L9:
  mov    $0x8,%r8d
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0xb1,%edi
  call   <syscall_cp@plt>
  test   %eax,%eax
  js     L20
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sigtimedwait(const sigset_t *mask, siginfo_t *si, const struct timespec *timeout) {
  int ret;
  do
    ret = syscall_cp(177, mask, si, timeout, 8);
  while (ret < 0 && errno == EINTR);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sigtimedwait>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L25:
  mov    D15(%rip),%rdx
  mov    D16(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L19
L9:
  mov    $0x8,%r8d
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0xb1,%edi
  call   <syscall_cp@plt>
  test   %eax,%eax
  js     L25
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sigtimedwait(const sigset_t *mask, siginfo_t *si, const struct timespec *timeout) {
  int ret;
  do
    ret = syscall_cp(177, mask, si, timeout, 8);
  while (ret < 0 && errno == EINTR);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<Esys_Free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void Esys_Free(void *__ptr) {
  if (__ptr != NULL) {
    free(__ptr);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Esys_Free>:
  endbr64
  test   %rdi,%rdi
  je     L2
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L2:
  ret
```

assistant: ```c
void Esys_Free(void *__ptr) {
  if (__ptr != NULL) {
    free(__ptr);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Esys_Free>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L0:
  ret
```

assistant: ```c
void Esys_Free(void *__ptr) {
  if (__ptr != NULL) {
    free(__ptr);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Esys_Free>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void Esys_Free(void *__ptr) {
  if (__ptr != NULL) {
    free(__ptr);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zz_bind_call_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <find_tag@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <setaction_exesproc@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
zz_bind_call_fun(proc, tag) int (*proc)();
const char *tag;
{
  setaction_exesproc(proc, find_tag(tag));
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<zz_bind_call_fun>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    $0x0,%eax
  call   <find_tag@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <setaction_exesproc@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
zz_bind_call_fun(proc, tag) int (*proc)();
const char *tag;
{
  setaction_exesproc(proc, find_tag(tag));
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<zz_bind_call_fun>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <find_tag@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <setaction_exesproc@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
zz_bind_call_fun(proc, tag) int (*proc)();
const char *tag;
{
  setaction_exesproc(proc, find_tag(tag));
  return 1;
}
```