ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <init_model@plt>
  mov    $0x0,%eax
  call   <start_simulation@plt>
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int __retres1;
  {
    {
      init_model();
      start_simulation();
    }
    __retres1 = 0;
    return (__retres1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_model@plt>
  mov    $0x0,%eax
  call   <start_simulation@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int __retres1;
  {
    {
      init_model();
      start_simulation();
    }
    __retres1 = 0;
    return (__retres1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_model@plt>
  xor    %eax,%eax
  call   <start_simulation@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int __retres1;
  {
    {
      init_model();
      start_simulation();
    }
    __retres1 = 0;
    return (__retres1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_model@plt>
  xor    %eax,%eax
  call   <start_simulation@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int __retres1;
  {
    {
      init_model();
      start_simulation();
    }
    __retres1 = 0;
    return (__retres1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<runner>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L3:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L3
```

assistant: ```c
void *runner(void *arg __attribute__((unused))) {
  while (1)
    sleep(1);
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<runner>:
  endbr64
  sub    $0x8,%rsp
L3:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L3
```

assistant: ```c
void *runner(void *arg __attribute__((unused))) {
  while (1)
    sleep(1);
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<runner>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L8
```

assistant: ```c
void *runner(void *arg __attribute__((unused))) {
  while (1)
    sleep(1);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<runner>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L7
```

assistant: ```c
void *runner(void *arg __attribute__((unused))) {
  while (1)
    sleep(1);
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<colon_blow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2e,(%rax)
L2:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *colon_blow(char *field) {
  int i;
  for (i = 0; field[i]; i++)
    if (field[i] == ':')
      field[i] = '.';
  return field;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<colon_blow>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L38
  mov    %rdi,%rdx
  jmp    L17
L2:
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L38
L17:
  cmp    $0x3a,%cl
  jne    L2
  movb   $0x2e,(%rdx)
  jmp    L2
L38:
  ret
```

assistant: ```c
char *colon_blow(char *field) {
  int i;
  for (i = 0; field[i]; i++)
    if (field[i] == ':')
      field[i] = '.';
  return field;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<colon_blow>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L27
  mov    %rdi,%rdx
  nopl   0x0(%rax)
L22:
  cmp    $0x3a,%cl
  jne    L21
  movb   $0x2e,(%rdx)
L21:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L22
L27:
  ret
```

assistant: ```c
char *colon_blow(char *field) {
  int i;
  for (i = 0; field[i]; i++)
    if (field[i] == ':')
      field[i] = '.';
  return field;
}
```
user: What is the c source code of the assembly code below?

```asm
<colon_blow>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L15
  mov    %rdi,%rdx
  nopl   0x0(%rax)
L8:
  cmp    $0x3a,%cl
  je     L30
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
L15:
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  movb   $0x2e,(%rdx)
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *colon_blow(char *field) {
  int i;
  for (i = 0; field[i]; i++)
    if (field[i] == ':')
      field[i] = '.';
  return field;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kena>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L1:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2:  

assistant: ```c
void kena(int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" ");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kena>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L2:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string

tool: D5:  

assistant: ```c
void kena(int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" ");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kena>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string

tool: D5:  

assistant: ```c
void kena(int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kena>:
  endbr64
  test   %edi,%edi
  jle    L15
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2:  

assistant: ```c
void kena(int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" ");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L38
  cmpl   $0x0,-0x18(%rbp)
  jg     L39
L38:
  mov    $0xffffffff,%eax
  jmp    L12
L39:
  cmpl   $0x0,-0x14(%rbp)
  jne    L42
  mov    $0x0,%eax
  jmp    L12
L42:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L49
L19:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x18(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L19
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <qq>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
L12:
  leave
  ret
```

assistant: ```c
int qq(int n, int k) {
  int i, zm_pom;
  if (n < 0 || k <= 0)
    return -1;
  else {
    if (n == 0)
      return 0;
    else {
      zm_pom = 0;
      for (i = 0; i <= k - 1; ++i)
        zm_pom = zm_pom + i * i;
      return qq(n - 1, k) + zm_pom;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qq>:
  endbr64
  test   %edi,%edi
  js     L16
  test   %esi,%esi
  jle    L16
  mov    %edi,%eax
  test   %edi,%edi
  je     L23
  push   %rbx
  mov    $0x0,%ebx
  mov    $0x0,%eax
L26:
  mov    %eax,%edx
  imul   %eax,%edx
  add    %edx,%ebx
  add    $0x1,%eax
  cmp    %eax,%esi
  jg     L26
  sub    $0x1,%edi
  call   <qq>
  add    %ebx,%eax
  pop    %rbx
  ret
L16:
  mov    $0xffffffff,%eax
  ret
L23:
  ret
```

assistant: ```c
int qq(int n, int k) {
  int i, zm_pom;
  if (n < 0 || k <= 0)
    return -1;
  else {
    if (n == 0)
      return 0;
    else {
      zm_pom = 0;
      for (i = 0; i <= k - 1; ++i)
        zm_pom = zm_pom + i * i;
      return qq(n - 1, k) + zm_pom;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<qq>:
  endbr64
  test   %edi,%edi
  js     L24
  test   %esi,%esi
  jle    L24
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L20
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L0:
  mov    %eax,%ecx
  imul   %eax,%ecx
  add    $0x1,%eax
  add    %ecx,%edx
  cmp    %eax,%esi
  jg     L0
  add    %edx,%r8d
  sub    $0x1,%edi
  jne    L27
L20:
  mov    %r8d,%eax
  ret
L24:
  mov    $0xffffffff,%r8d
  jmp    L20
```

assistant: ```c
int qq(int n, int k) {
  int i, zm_pom;
  if (n < 0 || k <= 0)
    return -1;
  else {
    if (n == 0)
      return 0;
    else {
      zm_pom = 0;
      for (i = 0; i <= k - 1; ++i)
        zm_pom = zm_pom + i * i;
      return qq(n - 1, k) + zm_pom;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qq>:
  endbr64
  test   %edi,%edi
  js     L61
  test   %esi,%esi
  jle    L61
  test   %edi,%edi
  je     L102
  mov    %edi,%r9d
  cmp    $0x3,%edi
  jle    L20
  mov    %edi,%ecx
  movdqa D4(%rip),%xmm4
  xor    %edx,%edx
  pxor   %xmm5,%xmm5
  shr    $0x2,%ecx
  nopl   0x0(%rax,%rax,1)
L88:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movdqa %xmm3,%xmm2
  nopw   0x0(%rax,%rax,1)
L59:
  movdqa %xmm2,%xmm0
  add    $0x1,%eax
  paddd  %xmm4,%xmm2
  movdqa %xmm0,%xmm1
  pmuludq %xmm0,%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  paddd  %xmm1,%xmm3
  cmp    %eax,%esi
  jg     L59
  add    $0x1,%edx
  paddd  %xmm3,%xmm5
  cmp    %ecx,%edx
  jne    L88
  movdqa %xmm5,%xmm0
  mov    %edi,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  paddd  %xmm0,%xmm5
  sub    %eax,%edi
  movdqa %xmm5,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm5
  movd   %xmm5,%r8d
  cmp    %eax,%r9d
  je     L78
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L24:
  mov    %eax,%ecx
  imul   %eax,%ecx
  add    $0x1,%eax
  add    %ecx,%edx
  cmp    %eax,%esi
  jg     L24
  add    %edx,%r8d
  sub    $0x1,%edi
  jne    L1
L78:
  mov    %r8d,%eax
  ret
L20:
  xor    %r8d,%r8d
  jmp    L1
L61:
  mov    $0xffffffff,%r8d
  jmp    L78
L102:
  xor    %r8d,%r8d
  jmp    L78
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: byte[16]

tool: {"D4": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int qq(int n, int k) {
  int i, zm_pom;
  if (n < 0 || k <= 0)
    return -1;
  else {
    if (n == 0)
      return 0;
    else {
      zm_pom = 0;
      for (i = 0; i <= k - 1; ++i)
        zm_pom = zm_pom + i * i;
      return qq(n - 1, k) + zm_pom;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<idct_matrix_scale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L4:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%esi
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%esi
  mov    %esi,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %ecx,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x7,-0x4(%rbp)
  jle    L4
  addl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x7,-0x8(%rbp)
  jle    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void idct_matrix_scale(int a_matrix[][8], int scale_factor, int output_matrix[][8]) {
  int row, col;
  for (row = 0; row < 8; row++) {
    for (col = 0; col < 8; col++) {
      output_matrix[row][col] = a_matrix[row][col] >> scale_factor;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<idct_matrix_scale>:
  endbr64
  mov    %esi,%ecx
  mov    %rdi,%rsi
  lea    0x100(%rdi),%r10
L5:
  mov    %rsi,%r9
  mov    %rdx,%r8
  mov    $0x0,%eax
L1:
  mov    (%r9,%rax,1),%edi
  sar    %cl,%edi
  mov    %edi,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    $0x20,%rax
  jne    L1
  add    $0x20,%rsi
  add    $0x20,%rdx
  cmp    %r10,%rsi
  jne    L5
  ret
```

assistant: ```c
void idct_matrix_scale(int a_matrix[][8], int scale_factor, int output_matrix[][8]) {
  int row, col;
  for (row = 0; row < 8; row++) {
    for (col = 0; col < 8; col++) {
      output_matrix[row][col] = a_matrix[row][col] >> scale_factor;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<idct_matrix_scale>:
  endbr64
  mov    %esi,%ecx
  lea    0x100(%rdi),%rsi
  nopl   (%rax)
L10:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rdi,%rax,1),%r8d
  sar    %cl,%r8d
  mov    %r8d,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x20,%rax
  jne    L8
  add    $0x20,%rdi
  add    $0x20,%rdx
  cmp    %rsi,%rdi
  jne    L10
  ret
```

assistant: ```c
void idct_matrix_scale(int a_matrix[][8], int scale_factor, int output_matrix[][8]) {
  int row, col;
  for (row = 0; row < 8; row++) {
    for (col = 0; col < 8; col++) {
      output_matrix[row][col] = a_matrix[row][col] >> scale_factor;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  cmpl   $0x3,-0xc(%rbp)
  jle    L15
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sum(int x[4]) {
  int i;
  long long ret;
  ret = 0;
  for (i = 0; i < 4; i++) {
    ret = ret + x[i];
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<sum>:
  endbr64
  movslq (%rdi),%rdx
  movslq 0x4(%rdi),%rax
  add    %rax,%rdx
  movslq 0x8(%rdi),%rax
  add    %rdx,%rax
  add    0xc(%rdi),%eax
  ret
```

assistant: ```c
int sum(int x[4]) {
  int i;
  long long ret;
  ret = 0;
  for (i = 0; i < 4; i++) {
    ret = ret + x[i];
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sum>:
  endbr64
  movslq 0x4(%rdi),%rax
  movslq (%rdi),%rdx
  add    %rax,%rdx
  movslq 0x8(%rdi),%rax
  add    %rdx,%rax
  add    0xc(%rdi),%eax
  ret
```

assistant: ```c
int sum(int x[4]) {
  int i;
  long long ret;
  ret = 0;
  for (i = 0; i < 4; i++) {
    ret = ret + x[i];
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sum>:
  endbr64
  movdqu (%rdi),%xmm0
  pxor   %xmm1,%xmm1
  pcmpgtd %xmm0,%xmm1
  movdqa %xmm0,%xmm2
  punpckhdq %xmm1,%xmm2
  punpckldq %xmm1,%xmm0
  paddq  %xmm2,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddq  %xmm1,%xmm0
  movq   %xmm0,%rax
  ret
```

assistant: ```c
int sum(int x[4]) {
  int i;
  long long ret;
  ret = 0;
  for (i = 0; i < 4; i++) {
    ret = ret + x[i];
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<zsum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L11:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L26:
  cmpl   $0x0,-0x14(%rbp)
  jne    L11
  jmp    L30
L20:
  mov    -0x18(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
L30:
  cmpl   $0x0,-0x18(%rbp)
  jne    L20
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int zsum(int a, int b) {
  int z = 0;
  while (a) {
    z += a % 10;
    a /= 10;
  }
  while (b) {
    z += b % 10;
    b /= 10;
  }
  return z;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zsum>:
  endbr64
  mov    %esi,%edx
  test   %edi,%edi
  je     L23
  mov    $0x0,%ecx
L2:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edi
  add    %edi,%ecx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L2
L11:
  test   %edx,%edx
  je     L18
L47:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    %edx,%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L47
L18:
  mov    %ecx,%eax
  ret
L23:
  mov    %edi,%ecx
  jmp    L11
```

assistant: ```c
int zsum(int a, int b) {
  int z = 0;
  while (a) {
    z += a % 10;
    a /= 10;
  }
  while (b) {
    z += b % 10;
    b /= 10;
  }
  return z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zsum>:
  endbr64
  mov    %esi,%edx
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L8
  nopl   (%rax)
L21:
  movslq %edi,%rax
  mov    %edi,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    %edi,%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L21
  test   %edx,%edx
  je     L13
  nopl   0x0(%rax)
L22:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    %edx,%r8d
  mov    %eax,%edx
L8:
  test   %edx,%edx
  jne    L22
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int zsum(int a, int b) {
  int z = 0;
  while (a) {
    z += a % 10;
    a /= 10;
  }
  while (b) {
    z += b % 10;
    b /= 10;
  }
  return z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zsum>:
  endbr64
  mov    %esi,%edx
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L27
  nopl   (%rax)
L19:
  movslq %edi,%rax
  mov    %edi,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    %edi,%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L19
  test   %edx,%edx
  je     L24
  nopl   0x0(%rax)
L12:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    %edx,%r8d
  mov    %eax,%edx
L27:
  test   %edx,%edx
  jne    L12
L24:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int zsum(int a, int b) {
  int z = 0;
  while (a) {
    z += a % 10;
    a /= 10;
  }
  while (b) {
    z += b % 10;
    b /= 10;
  }
  return z;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xe90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3e90(%rbp),%rax
  mov    $0x7d0,%esi
  mov    %rax,%rdi
  call   <create_random_array@plt>
  lea    -0x3e90(%rbp),%rax
  mov    $0x7d0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quicksort@plt>
  lea    -0x3e90(%rbp),%rax
  mov    $0x7d0,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  long array[2000];
  create_random_array(array, 2000);
  quicksort(array, 0, 2000);
  print_array(array, 2000);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xe90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x7d0,%esi
  mov    %rbx,%rdi
  call   <create_random_array@plt>
  mov    $0x7d0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <quicksort@plt>
  mov    $0x7d0,%esi
  mov    %rbx,%rdi
  call   <print_array@plt>
  mov    0x3e88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x3e90,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long array[2000];
  create_random_array(array, 2000);
  quicksort(array, 0, 2000);
  print_array(array, 2000);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xe90,%rsp
  mov    $0x7d0,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x3e88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <create_random_array@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    $0x7d0,%edx
  call   <quicksort@plt>
  mov    $0x7d0,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0x3e88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x3e90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long array[2000];
  create_random_array(array, 2000);
  quicksort(array, 0, 2000);
  print_array(array, 2000);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xe90,%rsp
  mov    $0x7d0,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x3e88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <create_random_array@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    $0x7d0,%edx
  call   <quicksort@plt>
  mov    $0x7d0,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0x3e88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x3e90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long array[2000];
  create_random_array(array, 2000);
  quicksort(array, 0, 2000);
  print_array(array, 2000);
  return 0;
}
```