ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc000(%rsp),%r11
L116:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L116
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc808(%rsp)
  xor    %eax,%eax
  lea    0x140(%rsp),%rbp
  lea    0x6540(%rsp),%r13
  lea    D6(%rip),%r12
L0:
  lea    -0x140(%rbp),%rbx
L23:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L23
  add    $0x140,%rbp
  cmp    %r13,%rbp
  jne    L0
  mov    0x63fc(%rsp),%edi
  lea    0xc7fc(%rsp),%rdx
  lea    0x63fc(%rsp),%rsi
  mov    $0x4e,%eax
  jmp    L73
L60:
  mov    %edi,(%rdx)
L82:
  sub    $0x1,%eax
  sub    $0x4,%rdx
  sub    $0x4,%rsi
L73:
  cmp    $0x4e,%eax
  je     L60
  mov    (%rsi),%ecx
  add    0x4(%rdx),%ecx
  mov    %ecx,(%rdx)
  test   %eax,%eax
  jns    L82
  lea    0xc6bc(%rsp),%r11
  lea    0x62bc(%rsp),%r10
  mov    $0x62c0,%r8d
  mov    $0xffffffffffff9e80,%r9
  jmp    L5
L6:
  mov    0x140(%r11),%eax
  add    (%r10),%eax
  mov    %eax,(%rdx)
L17:
  sub    $0x1,%ecx
  sub    $0x4,%rdx
  sub    $0x4,%rsi
L78:
  cmp    $0x4e,%ecx
  je     L6
  lea    (%rdx,%r9,1),%rax
  mov    (%rax,%r8,1),%eax
  mov    0x4(%rdx),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  add    (%rsi),%eax
  mov    %eax,(%rdx)
  test   %ecx,%ecx
  jns    L17
  add    $0x140,%r9
  sub    $0x140,%r11
  sub    $0x140,%r10
  sub    $0x140,%r8
  je     L62
L5:
  mov    %r10,%rsi
  mov    %r11,%rdx
  mov    $0x4e,%ecx
  jmp    L78
L62:
  mov    0x6400(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0xc808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  mov    $0x0,%eax
  add    $0xc818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D1
type: string

tool: D6: %d

tool: D1: %d


assistant: ```c
int main(void) {
  int a[80][80];
  int dp[80][80];
  int i, j;
  for (i = 0; i < 80; i++)
    for (j = 0; j < 80; j++)
      scanf("%d", &a[i][j]);
  for (i = 79; i >= 0; i--) {
    if (i == 79)
      dp[79][i] = a[79][i];
    else
      dp[79][i] = dp[79][i + 1] + a[79][i];
  }
  for (i = 78; i >= 0; i--) {
    for (j = 79; j >= 0; j--) {
      if (j == 79)
        dp[i][j] = a[i][j] + dp[i + 1][j];
      else
        dp[i][j] = a[i][j] + (dp[i + 1][j] < dp[i][j + 1] ? dp[i + 1][j] : dp[i][j + 1]);
    }
  }
  printf("%d\n", dp[0][0]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc000(%rsp),%r11
L37:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L37
  sub    $0x810,%rsp
  lea    D0(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0xc808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x140(%rsp),%r12
  lea    0x6540(%rsp),%r14
  nopl   0x0(%rax)
L77:
  lea    -0x140(%r12),%rbp
  nopl   0x0(%rax,%rax,1)
L63:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L63
  lea    0x140(%rbp),%r12
  cmp    %r14,%r12
  jne    L77
  mov    0x63fc(%rsp),%esi
  mov    $0x4f,%eax
  lea    0x6400(%rsp),%rcx
  jmp    L136
L117:
  mov    0x62c0(%rbx,%rax,4),%edx
  add    0x62c4(%rcx,%rax,4),%edx
  mov    %edx,0x62c0(%rcx,%rax,4)
  test   %eax,%eax
  je     L118
L121:
  sub    $0x1,%rax
L136:
  cmp    $0x4f,%eax
  jne    L117
  mov    %esi,0xc7fc(%rsp)
  jmp    L121
L118:
  lea    0x6180(%rsp),%rdi
  lea    0xc6bc(%rsp),%r8
  nopl   0x0(%rax)
L84:
  mov    %r8,%rcx
  mov    $0x4f,%edx
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L30:
  mov    0x4(%rcx),%eax
  mov    0x140(%rcx),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  add    (%rdi,%rdx,4),%eax
  mov    %eax,(%rcx)
  test   %edx,%edx
  je     L100
L79:
  sub    $0x1,%rdx
  sub    $0x4,%rcx
L62:
  cmp    $0x4f,%edx
  jne    L30
  mov    0x140(%r8),%eax
  add    0x13c(%rdi),%eax
  mov    %eax,(%r8)
  jmp    L79
  xchg   %ax,%ax
L100:
  lea    -0x140(%rdi),%rax
  sub    $0x140,%r8
  cmp    %rbx,%rdi
  je     L33
  mov    %rax,%rdi
  jmp    L84
L33:
  mov    0x6400(%rsp),%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0xc808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0xc810,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string

tool: D0: %d

tool: D14: %d


assistant: ```c
int main(void) {
  int a[80][80];
  int dp[80][80];
  int i, j;
  for (i = 0; i < 80; i++)
    for (j = 0; j < 80; j++)
      scanf("%d", &a[i][j]);
  for (i = 79; i >= 0; i--) {
    if (i == 79)
      dp[79][i] = a[79][i];
    else
      dp[79][i] = dp[79][i + 1] + a[79][i];
  }
  for (i = 78; i >= 0; i--) {
    for (j = 79; j >= 0; j--) {
      if (j == 79)
        dp[i][j] = a[i][j] + dp[i + 1][j];
      else
        dp[i][j] = a[i][j] + (dp[i + 1][j] < dp[i][j + 1] ? dp[i + 1][j] : dp[i][j + 1]);
    }
  }
  printf("%d\n", dp[0][0]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc000(%rsp),%r11
L69:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L69
  sub    $0x810,%rsp
  lea    D3(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0xc808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x140(%rsp),%r12
  lea    0x6540(%rsp),%r14
  nopl   0x0(%rax)
L56:
  lea    -0x140(%r12),%rbp
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L36
  lea    0x140(%rbp),%r12
  cmp    %r14,%r12
  jne    L56
  mov    0x63fc(%rsp),%esi
  mov    $0x4f,%eax
  lea    0x6400(%rsp),%rcx
  jmp    L94
L9:
  mov    0x62c0(%rbx,%rax,4),%edx
  add    0x62c4(%rcx,%rax,4),%edx
  mov    %edx,0x62c0(%rcx,%rax,4)
  test   %eax,%eax
  je     L129
L113:
  sub    $0x1,%rax
L94:
  cmp    $0x4f,%eax
  jne    L9
  mov    %esi,0xc7fc(%rsp)
  jmp    L113
L129:
  lea    0x6180(%rsp),%rdi
  lea    0xc6bc(%rsp),%r8
  nopl   0x0(%rax)
L92:
  mov    %r8,%rcx
  mov    $0x4f,%edx
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L28:
  mov    0x4(%rcx),%eax
  mov    0x140(%rcx),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  add    (%rdi,%rdx,4),%eax
  mov    %eax,(%rcx)
  test   %edx,%edx
  je     L43
L5:
  sub    $0x1,%rdx
  sub    $0x4,%rcx
L53:
  cmp    $0x4f,%edx
  jne    L28
  mov    0x140(%r8),%eax
  add    0x13c(%rdi),%eax
  mov    %eax,(%r8)
  jmp    L5
  xchg   %ax,%ax
L43:
  lea    -0x140(%rdi),%rax
  sub    $0x140,%r8
  cmp    %rbx,%rdi
  je     L117
  mov    %rax,%rdi
  jmp    L92
L117:
  mov    0x6400(%rsp),%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0xc808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L133
  add    $0xc810,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L133:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string
name: unpack_data
arguments: data_label: D19
data_type: string

tool: D3: %d

tool: D19: %d


assistant: ```c
int main(void) {
  int a[80][80];
  int dp[80][80];
  int i, j;
  for (i = 0; i < 80; i++)
    for (j = 0; j < 80; j++)
      scanf("%d", &a[i][j]);
  for (i = 79; i >= 0; i--) {
    if (i == 79)
      dp[79][i] = a[79][i];
    else
      dp[79][i] = dp[79][i + 1] + a[79][i];
  }
  for (i = 78; i >= 0; i--) {
    for (j = 79; j >= 0; j--) {
      if (j == 79)
        dp[i][j] = a[i][j] + dp[i + 1][j];
      else
        dp[i][j] = a[i][j] + (dp[i + 1][j] < dp[i][j + 1] ? dp[i + 1][j] : dp[i][j + 1]);
    }
  }
  printf("%d\n", dp[0][0]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pvSetNumLeadInPixels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %ax,-0x8(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: f

assistant: ```c
int pvSetNumLeadInPixels(char byBoardNum, short wNumLeadInPixels) {
  notify_pvcall("f");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pvSetNumLeadInPixels>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: f

assistant: ```c
int pvSetNumLeadInPixels(char byBoardNum, short wNumLeadInPixels) {
  notify_pvcall("f");
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pvSetNumLeadInPixels>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: f

assistant: ```c
int pvSetNumLeadInPixels(char byBoardNum, short wNumLeadInPixels) {
  notify_pvcall("f");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pvSetNumLeadInPixels>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: f

assistant: ```c
int pvSetNumLeadInPixels(char byBoardNum, short wNumLeadInPixels) {
  notify_pvcall("f");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L31
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L20:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x1c(%rbp),%edx
  mov    %edx,%ecx
  sub    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L20
  jmp    L9
L31:
  nop
L9:
  leave
  ret
```

assistant: ```c
void shuffle(uint32_t *tbl, uint32_t n) {
  uint32_t i, j, x;
  if (n == 0)
    return;
  for (i = 0; i < n - 1; i++) {
    j = rand() % (n - i);
    x = tbl[i];
    tbl[i] = tbl[i + j];
    tbl[i + j] = x;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%esi
  jle    L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    -0x1(%rsi),%r13d
  mov    $0x0,%ebx
L10:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12d,%ecx
  sub    %ebx,%ecx
  cltd
  idiv   %ecx
  add    %ebx,%edx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,0x0(%rbp,%rbx,4)
  mov    %esi,(%rax)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

assistant: ```c
void shuffle(uint32_t *tbl, uint32_t n) {
  uint32_t i, j, x;
  if (n == 0)
    return;
  for (i = 0; i < n - 1; i++) {
    j = rand() % (n - i);
    x = tbl[i];
    tbl[i] = tbl[i + j];
    tbl[i + j] = x;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%esi
  jle    L1
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%ecx
  mov    0x0(%r13,%rbx,4),%esi
  sub    %ebx,%ecx
  cltd
  idiv   %ecx
  add    %ebx,%edx
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  mov    %esi,(%rax)
  cmp    %r12,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void shuffle(uint32_t *tbl, uint32_t n) {
  uint32_t i, j, x;
  if (n == 0)
    return;
  for (i = 0; i < n - 1; i++) {
    j = rand() % (n - i);
    x = tbl[i];
    tbl[i] = tbl[i + j];
    tbl[i + j] = x;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%esi
  jle    L9
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%ecx
  mov    0x0(%r13,%rbx,4),%esi
  sub    %ebx,%ecx
  cltd
  idiv   %ecx
  add    %ebx,%edx
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  mov    %esi,(%rax)
  cmp    %r12,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void shuffle(uint32_t *tbl, uint32_t n) {
  uint32_t i, j, x;
  if (n == 0)
    return;
  for (i = 0; i < n - 1; i++) {
    j = rand() % (n - i);
    x = tbl[i];
    tbl[i] = tbl[i + j];
    tbl[i + j] = x;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xatoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L58
L48:
  addl   $0x1,-0x18(%rbp)
L58:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L48
  mov    -0x18(%rbp),%eax
  add    %eax,-0x1c(%rbp)
  jmp    L64
L17:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%ebx
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x1c(%rbp)
L64:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L2
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L17
L2:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L39
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L10
L39:
  movl   $0xffffffff,-0x14(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int xatoi(char token[]) {
  int i = 1;
  int zerosInBegin = 0;
  int result = 0;
  while (token[zerosInBegin] == '0') {
    zerosInBegin++;
  }
  i += zerosInBegin;
  while (token[i] >= '0' && token[i] <= '9') {
    result += (token[i] - '0') * ((int)pow(10, i - 1 - zerosInBegin));
    i++;
  }
  if (token[i] != '\0' && (token[i] < '0' || token[i] > '9'))
    result = -1;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xatoi>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x30,(%rdi)
  jne    L22
  mov    $0x1,%eax
L33:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x30,-0x1(%rdi,%rax,1)
  je     L33
L3:
  lea    0x1(%rdx),%eax
  cltq
  movzbl (%rdi,%rax,1),%ebx
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  ja     L34
  mov    $0x0,%ebp
  mov    $0x0,%r13d
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%r12
L51:
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movsbl %bl,%ebx
  sub    $0x30,%ebx
  imul   %eax,%ebx
  add    %ebx,%r13d
  movzbl 0x2(%r12,%rbp,1),%ebx
  add    $0x1,%rbp
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  jbe    L51
L7:
  test   %bl,%bl
  mov    $0xffffffff,%eax
  cmovne %eax,%r13d
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    $0x0,%edx
  jmp    L3
L34:
  mov    $0x0,%r13d
  jmp    L7
```

assistant: ```c
int xatoi(char token[]) {
  int i = 1;
  int zerosInBegin = 0;
  int result = 0;
  while (token[zerosInBegin] == '0') {
    zerosInBegin++;
  }
  i += zerosInBegin;
  while (token[i] >= '0' && token[i] <= '9') {
    result += (token[i] - '0') * ((int)pow(10, i - 1 - zerosInBegin));
    i++;
  }
  if (token[i] != '\0' && (token[i] < '0' || token[i] > '9'))
    result = -1;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xatoi>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x30,(%rdi)
  jne    L9
  mov    $0x1,%eax
  nopl   0x0(%rax)
L56:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x30,-0x1(%rdi,%rax,1)
  je     L56
  lea    0x1(%rdx),%eax
  movslq %eax,%rcx
  movzbl (%rdi,%rcx,1),%ebx
  lea    -0x30(%rbx),%ecx
  cmp    $0x9,%cl
  ja     L34
L37:
  movslq %eax,%rcx
  lea    -0x1(%rax),%r12d
  xor    %r13d,%r13d
  lea    (%rdi,%rcx,1),%rbp
  sub    %edx,%r12d
  sub    %ebp,%r12d
  nopw   0x0(%rax,%rax,1)
L33:
  lea    (%r12,%rbp,1),%esi
  mov    $0xa,%edi
  sub    $0x30,%ebx
  add    $0x1,%rbp
  call   <pow@plt>
  movsbl %bl,%ebx
  imul   %eax,%ebx
  add    %ebx,%r13d
  movzbl 0x0(%rbp),%ebx
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  jbe    L33
L22:
  test   %bl,%bl
  mov    $0xffffffff,%eax
  cmovne %eax,%r13d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%ecx
  mov    $0x1,%eax
  xor    %edx,%edx
  movzbl (%rdi,%rcx,1),%ebx
  lea    -0x30(%rbx),%ecx
  cmp    $0x9,%cl
  jbe    L37
L34:
  xor    %r13d,%r13d
  jmp    L22
```

assistant: ```c
int xatoi(char token[]) {
  int i = 1;
  int zerosInBegin = 0;
  int result = 0;
  while (token[zerosInBegin] == '0') {
    zerosInBegin++;
  }
  i += zerosInBegin;
  while (token[i] >= '0' && token[i] <= '9') {
    result += (token[i] - '0') * ((int)pow(10, i - 1 - zerosInBegin));
    i++;
  }
  if (token[i] != '\0' && (token[i] < '0' || token[i] > '9'))
    result = -1;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xatoi>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x30,(%rdi)
  jne    L9
  mov    $0x1,%eax
  nopl   0x0(%rax)
L12:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x30,-0x1(%rdi,%rax,1)
  je     L12
  lea    0x1(%rdx),%eax
  movslq %eax,%rcx
  movzbl (%rdi,%rcx,1),%ebx
  lea    -0x30(%rbx),%ecx
  cmp    $0x9,%cl
  ja     L1
L33:
  movslq %eax,%rcx
  lea    -0x1(%rax),%r12d
  xor    %r13d,%r13d
  lea    (%rdi,%rcx,1),%rbp
  sub    %edx,%r12d
  sub    %ebp,%r12d
  nopw   0x0(%rax,%rax,1)
L4:
  lea    (%r12,%rbp,1),%esi
  mov    $0xa,%edi
  sub    $0x30,%ebx
  add    $0x1,%rbp
  call   <pow@plt>
  movsbl %bl,%ebx
  imul   %eax,%ebx
  add    %ebx,%r13d
  movzbl 0x0(%rbp),%ebx
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  jbe    L4
L57:
  test   %bl,%bl
  mov    $0xffffffff,%eax
  cmovne %eax,%r13d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%ecx
  mov    $0x1,%eax
  xor    %edx,%edx
  movzbl (%rdi,%rcx,1),%ebx
  lea    -0x30(%rbx),%ecx
  cmp    $0x9,%cl
  jbe    L33
L1:
  xor    %r13d,%r13d
  jmp    L57
```

assistant: ```c
int xatoi(char token[]) {
  int i = 1;
  int zerosInBegin = 0;
  int result = 0;
  while (token[zerosInBegin] == '0') {
    zerosInBegin++;
  }
  i += zerosInBegin;
  while (token[i] >= '0' && token[i] <= '9') {
    result += (token[i] - '0') * ((int)pow(10, i - 1 - zerosInBegin));
    i++;
  }
  if (token[i] != '\0' && (token[i] < '0' || token[i] > '9'))
    result = -1;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int bad(struct task *t) {
  assert(t);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bad>:
  endbr64
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bad(struct task *t) {
  assert(t);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bad>:
  endbr64
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bad(struct task *t) {
  assert(t);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bad>:
  endbr64
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bad(struct task *t) {
  assert(t);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L1
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rcx
  lea    D29(%rip),%rdx
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L1:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <chk_malloc@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rcx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %esi,%r8d
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D28
type: string
name: unpack_data
arguments: label: D29
type: string
name: unpack_data
arguments: label: D34
type: string
name: unpack_data
arguments: label: D19
type: string

tool: D28: [int]

tool: D29: [str]

tool: D34: USAGE: %s %s %s


tool: D19: String '%s' at 0x%08x is of %d size in array of %d size


assistant: ```c
int main(int argc, char *argv[]) {
  char *c_pt;
  int sz;
  if (argc < 3) {
    printf("USAGE: %s %s %s\n", argv[0], "[str]", "[int]");
    exit(0);
  }
  sz = atoi(argv[2]);
  c_pt = (char *)chk_malloc(sz);
  strcpy(c_pt, argv[1]);
  printf("String \'%s\' at 0x%08x is of %d size in array of %d size\n", c_pt, c_pt, strlen(c_pt), sz);
  free(c_pt);
  return (0);
}
```