ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L30
  lea    0x10(%rsp),%rbx
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D5(%rip),%r13
L21:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0xc(%rsp),%eax
  add    $0x4,%r12
  cmp    %ebp,%eax
  jg     L21
  test   %eax,%eax
  jle    L18
  lea    -0x1(%rax),%eax
  lea    0x4(%rbx,%rax,4),%rcx
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L64
L35:
  add    $0x1,%r12d
  add    %eax,%edx
L1:
  add    $0x4,%rbx
  cmp    %rcx,%rbx
  je     L80
L64:
  mov    (%rbx),%eax
  test   $0x1,%al
  je     L35
  add    $0x1,%ebp
  add    %eax,%esi
  jmp    L1
L30:
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L80:
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebp,%xmm1
  divss  %xmm1,%xmm0
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L80
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D20
datatype: string
name: unpack_data
arguments: label: D7
datatype: string

tool: D5: %d

tool: D20: Sum even: %d
Sum odd: %d


tool: D7: Ratio: %.2f


assistant: ```c
int main() {
  int i, n, a[100], count_even = 0, count_odd = 0, sum_even = 0, sum_odd = 0;
  scanf("%d", &n);
  for (i = 0; i < n; ++i)
    scanf("%d", &a[i]);
  for (i = 0; i < n; ++i) {
    if (a[i] % 2) {
      count_odd++;
      sum_odd += a[i];
    } else {
      count_even++;
      sum_even += a[i];
    }
  }
  printf("Sum even: %d\nSum odd: %d\n", sum_even, sum_odd);
  printf("Ratio: %.2f\n", (float)count_even / count_odd);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L51
  lea    0x10(%rsp),%r12
  xor    %ebx,%ebx
  mov    %r12,%rbp
  xchg   %ax,%ax
L15:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L15
  test   %eax,%eax
  jle    L51
  lea    -0x1(%rax),%edx
  lea    0x4(%r12),%rax
  xor    %esi,%esi
  xor    %ecx,%ecx
  lea    (%rax,%rdx,4),%rdi
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%ebx
  add    %edx,%esi
  mov    %rax,%r12
  cmp    %rdi,%rax
  je     L57
L38:
  add    $0x4,%rax
L79:
  mov    (%r12),%edx
  test   $0x1,%dl
  jne    L20
  add    $0x1,%ebp
  add    %edx,%ecx
  mov    %rax,%r12
  cmp    %rdi,%rax
  jne    L38
L57:
  pxor   %xmm0,%xmm0
  lea    D23(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2ss %ecx,%xmm0
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D3(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  mov    $0x1,%eax
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  xor    %esi,%esi
  xor    %ecx,%ecx
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L57
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string
name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D3
datatype: string

tool: D6: %d

tool: D23: Sum even: %d
Sum odd: %d


tool: D3: Ratio: %.2f


assistant: ```c
int main() {
  int i, n, a[100], count_even = 0, count_odd = 0, sum_even = 0, sum_odd = 0;
  scanf("%d", &n);
  for (i = 0; i < n; ++i)
    scanf("%d", &a[i]);
  for (i = 0; i < n; ++i) {
    if (a[i] % 2) {
      count_odd++;
      sum_odd += a[i];
    } else {
      count_even++;
      sum_even += a[i];
    }
  }
  printf("Sum even: %d\nSum odd: %d\n", sum_even, sum_odd);
  printf("Ratio: %.2f\n", (float)count_even / count_odd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
f() {
  unsigned b = 0;
  if (b > ~0U)
    b = ~0U;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
f() {
  unsigned b = 0;
  if (b > ~0U)
    b = ~0U;
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
f() {
  unsigned b = 0;
  if (b > ~0U)
    b = ~0U;
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
f() {
  unsigned b = 0;
  if (b > ~0U)
    b = ~0U;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Stopping_Rule>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movq   D9(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D25(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L0
  movsd  D25(%rip),%xmm0
  jmp    L12
L0:
  movsd  -0x10(%rbp),%xmm0
  movq   D9(%rip),%xmm1
  andpd  %xmm1,%xmm0
L12:
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: qword
name: retrieve_data
arguments: data_tag: D18
data_type: f64
name: retrieve_data
arguments: data_tag: D25
data_type: f64

tool: D9: 9223372036854775807

tool: D18: 0.5

tool: D25: 1

assistant: ```c
int Stopping_Rule(double x[], double tolerance) {
  double xmid = 0.5 * fabs(x[3] + x[1]);
  double eta = (xmid <= 1.0) ? 1.0 : fabs(xmid);
  return ((x[3] - x[1]) <= tolerance * eta) ? 1 : 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Stopping_Rule>:
  endbr64
  movsd  0x18(%rdi),%xmm2
  movsd  0x8(%rdi),%xmm3
  movapd %xmm2,%xmm1
  addsd  %xmm3,%xmm1
  andpd  D17(%rip),%xmm1
  mulsd  D1(%rip),%xmm1
  movsd  D18(%rip),%xmm4
  comisd %xmm1,%xmm4
  jae    L8
L13:
  subsd  %xmm3,%xmm2
  mulsd  %xmm0,%xmm1
  comisd %xmm2,%xmm1
  setae  %al
  movzbl %al,%eax
  ret
L8:
  movapd %xmm4,%xmm1
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
datatype: qword[2]
name: disassemble_data
arguments: data_tag: D1
datatype: f64
name: disassemble_data
arguments: data_tag: D18
datatype: f64

tool: {"D17": [0x7fffffffffffffff,0x0000000000000000]}

tool: D1: 0.5

tool: D18: 1

assistant: ```c
int Stopping_Rule(double x[], double tolerance) {
  double xmid = 0.5 * fabs(x[3] + x[1]);
  double eta = (xmid <= 1.0) ? 1.0 : fabs(xmid);
  return ((x[3] - x[1]) <= tolerance * eta) ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Stopping_Rule>:
  endbr64
  movsd  0x18(%rdi),%xmm2
  movsd  0x8(%rdi),%xmm3
  movsd  D17(%rip),%xmm4
  movapd %xmm2,%xmm1
  addsd  %xmm3,%xmm1
  andpd  D7(%rip),%xmm1
  mulsd  D22(%rip),%xmm1
  comisd %xmm1,%xmm4
  jae    L7
  mulsd  %xmm1,%xmm0
L7:
  subsd  %xmm3,%xmm2
  xor    %eax,%eax
  comisd %xmm2,%xmm0
  setae  %al
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
type_guessed: f64
name: retrieve_data
arguments: label: D7
type_guessed: qword[2]
name: retrieve_data
arguments: label: D22
type_guessed: f64

tool: D17: 1

tool: {"D7": [0x7fffffffffffffff,0x0000000000000000]}

tool: D22: 0.5

assistant: ```c
int Stopping_Rule(double x[], double tolerance) {
  double xmid = 0.5 * fabs(x[3] + x[1]);
  double eta = (xmid <= 1.0) ? 1.0 : fabs(xmid);
  return ((x[3] - x[1]) <= tolerance * eta) ? 1 : 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Stopping_Rule>:
  endbr64
  movsd  0x18(%rdi),%xmm2
  movsd  0x8(%rdi),%xmm3
  movsd  D15(%rip),%xmm4
  movapd %xmm2,%xmm1
  addsd  %xmm3,%xmm1
  andpd  D9(%rip),%xmm1
  mulsd  D21(%rip),%xmm1
  comisd %xmm1,%xmm4
  jae    L3
  mulsd  %xmm1,%xmm0
L3:
  subsd  %xmm3,%xmm2
  xor    %eax,%eax
  comisd %xmm2,%xmm0
  setae  %al
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type_guessed: f64
name: retrieve_data
arguments: data_tag: D9
type_guessed: qword[2]
name: retrieve_data
arguments: data_tag: D21
type_guessed: f64

tool: D15: 1

tool: {"D9": [0x7fffffffffffffff,0x0000000000000000]}

tool: D21: 0.5

assistant: ```c
int Stopping_Rule(double x[], double tolerance) {
  double xmid = 0.5 * fabs(x[3] + x[1]);
  double eta = (xmid <= 1.0) ? 1.0 : fabs(xmid);
  return ((x[3] - x[1]) <= tolerance * eta) ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L11:
  mov    $0xa,%edi
  call   <f@plt>
  mov    $0x9,%edi
  call   <f@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x270f,-0x4(%rbp)
  jle    L11
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int a, b, c, d, e, f1;
  int i;
  for (i = 0; i < 10000; i++) {
    f(10);
    f(9);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2710,%ebx
L4:
  mov    $0xa,%edi
  call   <f@plt>
  mov    $0x9,%edi
  call   <f@plt>
  sub    $0x1,%ebx
  jne    L4
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int a, b, c, d, e, f1;
  int i;
  for (i = 0; i < 10000; i++) {
    f(10);
    f(9);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2710,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xa,%edi
  call   <f@plt>
  mov    $0x9,%edi
  call   <f@plt>
  sub    $0x1,%ebx
  jne    L7
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int a, b, c, d, e, f1;
  int i;
  for (i = 0; i < 10000; i++) {
    f(10);
    f(9);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2710,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xa,%edi
  call   <f@plt>
  mov    $0x9,%edi
  call   <f@plt>
  sub    $0x1,%ebx
  jne    L8
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int a, b, c, d, e, f1;
  int i;
  for (i = 0; i < 10000; i++) {
    f(10);
    f(9);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<harbol_vector_new_from_unilist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L10
L4:
  mov    $0x0,%eax
  call   <harbol_vector_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <harbol_vector_from_unilist@plt>
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
struct HarbolVector *harbol_vector_new_from_unilist(const struct HarbolUniList *const list) {
  if (!list)
    return NULL;
  struct HarbolVector *v = harbol_vector_new();
  harbol_vector_from_unilist(v, list);
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<harbol_vector_new_from_unilist>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L9
  mov    $0x0,%eax
  call   <harbol_vector_new@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <harbol_vector_from_unilist@plt>
L13:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rdi,%rbp
  jmp    L13
```

assistant: ```c
struct HarbolVector *harbol_vector_new_from_unilist(const struct HarbolUniList *const list) {
  if (!list)
    return NULL;
  struct HarbolVector *v = harbol_vector_new();
  harbol_vector_from_unilist(v, list);
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<harbol_vector_new_from_unilist>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L8
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <harbol_vector_new@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <harbol_vector_from_unilist@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct HarbolVector *harbol_vector_new_from_unilist(const struct HarbolUniList *const list) {
  if (!list)
    return NULL;
  struct HarbolVector *v = harbol_vector_new();
  harbol_vector_from_unilist(v, list);
  return v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<harbol_vector_new_from_unilist>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L4
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <harbol_vector_new@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <harbol_vector_from_unilist@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct HarbolVector *harbol_vector_new_from_unilist(const struct HarbolUniList *const list) {
  if (!list)
    return NULL;
  struct HarbolVector *v = harbol_vector_new();
  harbol_vector_from_unilist(v, list);
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ESP8266_UART_String>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L18
L0:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ESP8266_UART_Putch@plt>
  subl   $0x1,-0xc(%rbp)
L18:
  cmpl   $0x0,-0xc(%rbp)
  jne    L0
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
unsigned char ESP8266_UART_String(char *s, unsigned int Length) {
  while (Length) {
    ESP8266_UART_Putch(*s++);
    Length--;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ESP8266_UART_String>:
  endbr64
  test   %esi,%esi
  je     L11
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rbp
L10:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <ESP8266_UART_Putch@plt>
  cmp    %rbp,%rbx
  jne    L10
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned char ESP8266_UART_String(char *s, unsigned int Length) {
  while (Length) {
    ESP8266_UART_Putch(*s++);
    Length--;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ESP8266_UART_String>:
  endbr64
  test   %esi,%esi
  je     L8
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <ESP8266_UART_Putch@plt>
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned char ESP8266_UART_String(char *s, unsigned int Length) {
  while (Length) {
    ESP8266_UART_Putch(*s++);
    Length--;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ESP8266_UART_String>:
  endbr64
  test   %esi,%esi
  je     L9
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <ESP8266_UART_Putch@plt>
  cmp    %rbx,%rbp
  jne    L1
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned char ESP8266_UART_String(char *s, unsigned int Length) {
  while (Length) {
    ESP8266_UART_Putch(*s++);
    Length--;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pause_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x17,%edx
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <put_str@plt>
  mov    $0x0,%eax
  call   <anykey@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D21
type: string

tool: 

tool: D21: [Press any key to continue]

assistant: ```c
void pause_line(int row) {
  prt("", row, 0);
  put_str("[Press any key to continue]", row, 23);
  (void)anykey();
  prt("", row, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<pause_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    %edi,%esi
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <prt@plt>
  mov    $0x17,%edx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <put_str@plt>
  mov    $0x0,%eax
  call   <anykey@plt>
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <prt@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D7
type: string

tool: 

tool: D7: [Press any key to continue]

assistant: ```c
void pause_line(int row) {
  prt("", row, 0);
  put_str("[Press any key to continue]", row, 23);
  (void)anykey();
  prt("", row, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pause_line>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  mov    %edi,%esi
  xor    %edx,%edx
  push   %rbp
  mov    %edi,%ebp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <prt@plt>
  mov    %ebp,%esi
  mov    $0x17,%edx
  lea    D6(%rip),%rdi
  call   <put_str@plt>
  xor    %eax,%eax
  call   <anykey@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  xor    %edx,%edx
  pop    %r12
  jmp    1070 <prt@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string

tool: 

tool: D6: [Press any key to continue]

assistant: ```c
void pause_line(int row) {
  prt("", row, 0);
  put_str("[Press any key to continue]", row, 23);
  (void)anykey();
  prt("", row, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pause_line>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  mov    %edi,%esi
  xor    %edx,%edx
  push   %rbp
  mov    %edi,%ebp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <prt@plt>
  mov    %ebp,%esi
  mov    $0x17,%edx
  lea    D3(%rip),%rdi
  call   <put_str@plt>
  xor    %eax,%eax
  call   <anykey@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  xor    %edx,%edx
  pop    %r12
  jmp    1070 <prt@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string

tool: 

tool: D3: [Press any key to continue]

assistant: ```c
void pause_line(int row) {
  prt("", row, 0);
  put_str("[Press any key to continue]", row, 23);
  (void)anykey();
  prt("", row, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<benchmark2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x1,%edi
  call   <mock_prng_allocate@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L1
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <stdlib_base_prng_normalized@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L41
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L43
L41:
  addl   $0x1,-0x24(%rbp)
L1:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L15
L43:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L5
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <stdlib_base_prng_free@plt>
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5: unexpected result


assistant: ```c
double benchmark2() {
  double elapsed;
  double t;
  double v;
  int i;
  struct BasePRNGObject *obj = mock_prng_allocate(1);
  t = tic();
  for (i = 0; i < 1000000; i++) {
    v = stdlib_base_prng_normalized(obj);
    if (v != v) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("unexpected result\n");
  }
  stdlib_base_prng_free(obj);
  return elapsed;
}
```
user: What is the c source code of the assembly code below?

```asm
<benchmark2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <mock_prng_allocate@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r13
  mov    $0xf4240,%ebx
L4:
  mov    %rbp,%rdi
  call   <stdlib_base_prng_normalized@plt>
  ucomisd %xmm0,%xmm0
  jp     L16
  sub    $0x1,%ebx
  jne    L4
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r13,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L0
L16:
  lea    D6(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r13,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
L0:
  mov    %rbp,%rdi
  call   <stdlib_base_prng_free@plt>
  movq   %rbx,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: unexpected result


assistant: ```c
double benchmark2() {
  double elapsed;
  double t;
  double v;
  int i;
  struct BasePRNGObject *obj = mock_prng_allocate(1);
  t = tic();
  for (i = 0; i < 1000000; i++) {
    v = stdlib_base_prng_normalized(obj);
    if (v != v) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("unexpected result\n");
  }
  stdlib_base_prng_free(obj);
  return elapsed;
}
```