ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_bsearchOccurRight>:
  endbr64
  mov    %esi,%r8d
  lea    (%rsi,%rdx,1),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cmp    %edx,%r8d
  jle    L16
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L8:
  lea    -0x1(%rax),%edx
L36:
  lea    (%rdx,%r8,1),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cmp    %r8d,%edx
  jl     L47
L16:
  movslq %eax,%rsi
  cmp    %ecx,(%rdi,%rsi,4)
  jg     L8
  lea    0x1(%rax),%r8d
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _bsearchOccurRight(int *A, int lo, int hi, int val) {
  int mi = (lo + hi) / 2;
  if (lo > hi)
    return lo;
  if (A[mi] > val) {
    return _bsearchOccurRight(A, lo, mi - 1, val);
  } else {
    return _bsearchOccurRight(A, mi + 1, hi, val);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_bsearchOccurRight>:
  endbr64
  mov    %esi,%r8d
  nopw   0x0(%rax,%rax,1)
L25:
  lea    (%r8,%rdx,1),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cmp    %edx,%r8d
  jg     L28
L22:
  movslq %eax,%rsi
  cmp    (%rdi,%rsi,4),%ecx
  jge    L24
  lea    -0x1(%rax),%edx
  lea    (%rdx,%r8,1),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cmp    %r8d,%edx
  jge    L22
L28:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  lea    0x1(%rax),%r8d
  jmp    L25
```

assistant: ```c
int _bsearchOccurRight(int *A, int lo, int hi, int val) {
  int mi = (lo + hi) / 2;
  if (lo > hi)
    return lo;
  if (A[mi] > val) {
    return _bsearchOccurRight(A, lo, mi - 1, val);
  } else {
    return _bsearchOccurRight(A, mi + 1, hi, val);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: %d


assistant: ```c
int print_vector(int *ptr, int length) {
  for (int i = 0; i < length; i++) {
    printf("%d\n", ptr[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_vector>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D1(%rip),%rbp
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L19
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0x0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1: %d


assistant: ```c
int print_vector(int *ptr, int length) {
  for (int i = 0; i < length; i++) {
    printf("%d\n", ptr[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_vector>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: %d


assistant: ```c
int print_vector(int *ptr, int length) {
  for (int i = 0; i < length; i++) {
    printf("%d\n", ptr[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_vector>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: %d


assistant: ```c
int print_vector(int *ptr, int length) {
  for (int i = 0; i < length; i++) {
    printf("%d\n", ptr[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<buf1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <slice@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *buf1(char *text, int pos) {
  char *buffer1 = slice(text, 0, pos);
  return buffer1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<buf1>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    $0x0,%esi
  call   <slice@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *buf1(char *text, int pos) {
  char *buffer1 = slice(text, 0, pos);
  return buffer1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<buf1>:
  endbr64
  mov    %esi,%edx
  xor    %esi,%esi
  jmp    1050 <slice@plt>
```

assistant: ```c
char *buf1(char *text, int pos) {
  char *buffer1 = slice(text, 0, pos);
  return buffer1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buf1>:
  endbr64
  mov    %esi,%edx
  xor    %esi,%esi
  jmp    1050 <slice@plt>
```

assistant: ```c
char *buf1(char *text, int pos) {
  char *buffer1 = slice(text, 0, pos);
  return buffer1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L8
L15:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  mov    D8(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L15
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char ch;
  while ((ch = getchar()) != EOF)
    putchar(ch);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L17
L15:
  movsbl %al,%edi
  call   <putchar@plt>
L17:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %al,(%rdx)
  jne    L15
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char ch;
  while ((ch = getchar()) != EOF)
    putchar(ch);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D5(%rip),%rbx
  jmp    L9
  xchg   %ax,%ax
L17:
  movsbl %al,%edi
  call   <putchar@plt>
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L17
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  char ch;
  while ((ch = getchar()) != EOF)
    putchar(ch);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D2(%rip),%rbx
  jmp    L7
  xchg   %ax,%ax
L3:
  movsbl %al,%edi
  call   <putchar@plt>
L7:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  char ch;
  while ((ch = getchar()) != EOF)
    putchar(ch);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_multprec_Newton_Laurent_step>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  call   <syscon_read_multprec_Laurent_system@plt>
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <syscon_number_of_multprec_Laurentials@plt>
  mov    0xc(%rsp),%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <solcon_read_multprec_solutions@plt>
  lea    0x10(%rsp),%rdi
  call   <solcon_number_of_multprec_solutions@plt>
  mov    0x10(%rsp),%esi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <solcon_dimension_of_multprec_solutions@plt>
  mov    0xc(%rsp),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%edi
  call   <multprec_Newton_Laurent_step@plt>
  lea    D69(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <solcon_write_multprec_solutions@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D41
type: string
name: parse_data
arguments: data_tag: D31
type: string
name: parse_data
arguments: data_tag: D43
type: string
name: parse_data
arguments: data_tag: D47
type: string
name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D69
type: string

tool: D9: 
Running Newton step with multiprecision arithmetic ...

tool: D41: 
give the number of decimal places in the working precision : 

tool: D31: %d

tool: D43: The system container has %d Laurent polynomials.


tool: D47: The solution container has size %d.


tool: D18: The solutions in the container have dimension %d.


tool: D69: The solutions after the Newton step :

assistant: ```c
void test_multprec_Newton_Laurent_step(void) {
  int fail, dim, len, deci;
  printf("\nRunning Newton step with multiprecision arithmetic ...\n");
  printf("\ngive the number of decimal places in the working precision : ");
  scanf("%d", &deci);
  fail = syscon_read_multprec_Laurent_system(deci);
  fail = syscon_number_of_multprec_Laurentials(&dim);
  printf("The system container has %d Laurent polynomials.\n", dim);
  fail = solcon_read_multprec_solutions();
  fail = solcon_number_of_multprec_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = solcon_dimension_of_multprec_solutions(&dim);
  printf("The solutions in the container have dimension %d.\n", dim);
  fail = multprec_Newton_Laurent_step(deci);
  printf("The solutions after the Newton step :\n");
  fail = solcon_write_multprec_solutions();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_multprec_Newton_Laurent_step>:
  endbr64
  push   %rbp
  lea    D47(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <puts@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  call   <syscon_read_multprec_Laurent_system@plt>
  mov    %rbp,%rdi
  call   <syscon_number_of_multprec_Laurentials@plt>
  mov    0xc(%rsp),%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <solcon_read_multprec_solutions@plt>
  lea    0x10(%rsp),%rdi
  call   <solcon_number_of_multprec_solutions@plt>
  mov    0x10(%rsp),%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <solcon_dimension_of_multprec_solutions@plt>
  mov    0xc(%rsp),%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%edi
  call   <multprec_Newton_Laurent_step@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <solcon_write_multprec_solutions@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D47
datatype: string
name: retrieve_data
arguments: tag: D12
datatype: string
name: retrieve_data
arguments: tag: D43
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D30
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string

tool: D47: 
Running Newton step with multiprecision arithmetic ...

tool: D12: 
give the number of decimal places in the working precision : 

tool: D43: %d

tool: D5: The system container has %d Laurent polynomials.


tool: D17: The solution container has size %d.


tool: D30: The solutions in the container have dimension %d.


tool: D0: The solutions after the Newton step :

assistant: ```c
void test_multprec_Newton_Laurent_step(void) {
  int fail, dim, len, deci;
  printf("\nRunning Newton step with multiprecision arithmetic ...\n");
  printf("\ngive the number of decimal places in the working precision : ");
  scanf("%d", &deci);
  fail = syscon_read_multprec_Laurent_system(deci);
  fail = syscon_number_of_multprec_Laurentials(&dim);
  printf("The system container has %d Laurent polynomials.\n", dim);
  fail = solcon_read_multprec_solutions();
  fail = solcon_number_of_multprec_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = solcon_dimension_of_multprec_solutions(&dim);
  printf("The solutions in the container have dimension %d.\n", dim);
  fail = multprec_Newton_Laurent_step(deci);
  printf("The solutions after the Newton step :\n");
  fail = solcon_write_multprec_solutions();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_multprec_Newton_Laurent_step>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <puts@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D49(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  call   <syscon_read_multprec_Laurent_system@plt>
  mov    %rbp,%rdi
  call   <syscon_number_of_multprec_Laurentials@plt>
  mov    0xc(%rsp),%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <solcon_read_multprec_solutions@plt>
  lea    0x10(%rsp),%rdi
  call   <solcon_number_of_multprec_solutions@plt>
  mov    0x10(%rsp),%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <solcon_dimension_of_multprec_solutions@plt>
  mov    0xc(%rsp),%esi
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%edi
  call   <multprec_Newton_Laurent_step@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <solcon_write_multprec_solutions@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D9
type: string
name: read_data
arguments: data_label: D49
type: string
name: read_data
arguments: data_label: D39
type: string
name: read_data
arguments: data_label: D40
type: string
name: read_data
arguments: data_label: D54
type: string
name: read_data
arguments: data_label: D47
type: string

tool: D23: 
Running Newton step with multiprecision arithmetic ...

tool: D9: 
give the number of decimal places in the working precision : 

tool: D49: %d

tool: D39: The system container has %d Laurent polynomials.


tool: D40: The solution container has size %d.


tool: D54: The solutions in the container have dimension %d.


tool: D47: The solutions after the Newton step :

assistant: ```c
void test_multprec_Newton_Laurent_step(void) {
  int fail, dim, len, deci;
  printf("\nRunning Newton step with multiprecision arithmetic ...\n");
  printf("\ngive the number of decimal places in the working precision : ");
  scanf("%d", &deci);
  fail = syscon_read_multprec_Laurent_system(deci);
  fail = syscon_number_of_multprec_Laurentials(&dim);
  printf("The system container has %d Laurent polynomials.\n", dim);
  fail = solcon_read_multprec_solutions();
  fail = solcon_number_of_multprec_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = solcon_dimension_of_multprec_solutions(&dim);
  printf("The solutions in the container have dimension %d.\n", dim);
  fail = multprec_Newton_Laurent_step(deci);
  printf("The solutions after the Newton step :\n");
  fail = solcon_write_multprec_solutions();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L8
  mov    -0x14(%rbp),%eax
  jmp    L16
L8:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L16:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n) {
  if (n < 3)
    return n;
  else
    return fib(n - 1) + fib(n - 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  cmp    $0x2,%edi
  jg     L6
L17:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  lea    0x0(%rbp,%rax,1),%ebx
  jmp    L17
```

assistant: ```c
int fib(int n) {
  if (n < 3)
    return n;
  else
    return fib(n - 1) + fib(n - 2);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L17:
  movl   $0x1,-0x4(%rbp)
  jmp    L31
L30:
  shll   -0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L30
  subl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x0,-0x8(%rbp)
  jns    L17
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c, x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  c = 0;
  while (x >= 0) {
    y = 1;
    while (x > y) {
      y = 2 * y;
      c = c + 1;
    }
    x = x - 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  js     L11
  mov    %ebx,%ecx
  lea    -0x1(%rbx),%esi
  jmp    L42
L8:
  add    %eax,%eax
  cmp    %edx,%eax
  jl     L8
L45:
  sub    $0x1,%ecx
  sub    $0x1,%esi
L42:
  mov    %ecx,%edx
  mov    $0x1,%eax
  cmp    $0x1,%ecx
  jg     L8
  test   %esi,%esi
  jns    L45
L11:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int c, x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  c = 0;
  while (x >= 0) {
    y = 1;
    while (x > y) {
      y = 2 * y;
      c = c + 1;
    }
    x = x - 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c, x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  c = 0;
  while (x >= 0) {
    y = 1;
    while (x > y) {
      y = 2 * y;
      c = c + 1;
    }
    x = x - 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c, x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  c = 0;
  while (x >= 0) {
    y = 1;
    while (x > y) {
      y = 2 * y;
      c = c + 1;
    }
    x = x - 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L9:
  addl   $0x2,-0x4(%rbp)
L15:
  movzwl -0x6(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L9
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned short N;
  while (x < N) {
    x += 2;
  }
  __VERIFIER_assert(x % 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned short N;
  while (x < N) {
    x += 2;
  }
  __VERIFIER_assert(x % 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned short N;
  while (x < N) {
    x += 2;
  }
  __VERIFIER_assert(x % 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned short N;
  while (x < N) {
    x += 2;
  }
  __VERIFIER_assert(x % 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fdtrif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  movss  -0x2c(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L26
  cmpl   $0x0,-0x28(%rbp)
  jle    L26
  pxor   %xmm0,%xmm0
  comiss -0x14(%rbp),%xmm0
  jae    L26
  movss  -0x14(%rbp),%xmm0
  movss  D8(%rip),%xmm1
  comiss %xmm1,%xmm0
  jbe    L21
L26:
  mov    $0x1,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
  jmp    L25
L21:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x24(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x28(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x10(%rbp),%xmm1
  movsd  D22(%rip),%xmm0
  movapd %xmm1,%xmm3
  mulsd  %xmm0,%xmm3
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movsd  D22(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm2
  movapd %xmm3,%xmm1
  movq   %rax,%xmm0
  call   <incbif@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x8(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  -0x10(%rbp),%xmm1
  mulss  -0x8(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: f32
name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D22
type_guessed: f64

tool: D8: 1

tool: D2: fdtrif

tool: D22: 0.5

assistant: ```c
float fdtrif(int ia, int ib, float yy) {
  float y, a, b, w, x;
  y = yy;
  if ((ia < 1) || (ib < 1) || (y <= 0.0) || (y > 1.0)) {
    mtherr("fdtrif", 1);
    return (0.0);
  }
  a = ia;
  b = ib;
  w = incbif(0.5 * b, 0.5 * a, y);
  x = (b - b * w) / (a * w);
  return (x);
}
```