ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    %rdi,%rax
  nopl   0x0(%rax)
L19:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L19
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *t;
  for (t = s; *t; ++t)
    ;
  return t - s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  mov    %rdi,%rax
  nopl   0x0(%rax)
L1:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L1
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *t;
  for (t = s; *t; ++t)
    ;
  return t - s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<selectMemory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <owFirst@plt>
  test   %rax,%rax
  je     L13
  subl   $0x1,-0x4(%rbp)
  jmp    L26
L38:
  subl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x0,-0x4(%rbp)
  js     L13
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <owNext@plt>
  test   %rax,%rax
  jne    L38
L13:
  cmpl   $0x0,-0x4(%rbp)
  jns    L25
  mov    $0x1,%eax
  jmp    L33
L25:
  mov    $0x0,%eax
L33:
  leave
  ret
```

assistant: ```c
bool selectMemory(int n) {
  if (owFirst(0, 1, 0)) {
    n--;
    while (n >= 0 && owNext(0, 1, 0)) {
      n--;
    }
  }
  if (n < 0) {
    return true;
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<selectMemory>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <owFirst@plt>
  test   %rax,%rax
  je     L28
  sub    $0x1,%ebx
  js     L28
L22:
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <owNext@plt>
  test   %rax,%rax
  je     L28
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L22
L28:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool selectMemory(int n) {
  if (owFirst(0, 1, 0)) {
    n--;
    while (n >= 0 && owNext(0, 1, 0)) {
      n--;
    }
  }
  if (n < 0) {
    return true;
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<selectMemory>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    %edi,%ebx
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <owFirst@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  shr    $0x1f,%eax
  test   %r8,%r8
  je     L27
  sub    $0x1,%ebx
  jns    L33
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%eax
L27:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  sub    $0x1,%ebx
  jb     L3
L33:
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <owNext@plt>
  test   %rax,%rax
  jne    L37
  pop    %rbx
  ret
```

assistant: ```c
bool selectMemory(int n) {
  if (owFirst(0, 1, 0)) {
    n--;
    while (n >= 0 && owNext(0, 1, 0)) {
      n--;
    }
  }
  if (n < 0) {
    return true;
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<selectMemory>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    %edi,%ebx
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <owFirst@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  shr    $0x1f,%eax
  test   %r8,%r8
  je     L20
  sub    $0x1,%ebx
  jns    L31
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
L20:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  sub    $0x1,%ebx
  jb     L18
L31:
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <owNext@plt>
  test   %rax,%rax
  jne    L36
  pop    %rbx
  ret
```

assistant: ```c
bool selectMemory(int n) {
  if (owFirst(0, 1, 0)) {
    n--;
    while (n >= 0 && owNext(0, 1, 0)) {
      n--;
    }
  }
  if (n < 0) {
    return true;
  }
  return false;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <logmsg@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string

tool: D5: malloc(%zu) failed


assistant: ```c
void *scalloc(size_t size) {
  void *result = calloc(size, 1);
  if (result == NULL) {
    logmsg(0x03, "malloc(%zu) failed\n", size);
    exit(1);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rbp,%rdx
  lea    D1(%rip),%rsi
  mov    $0x3,%edi
  call   <logmsg@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L3
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: malloc(%zu) failed


assistant: ```c
void *scalloc(size_t size) {
  void *result = calloc(size, 1);
  if (result == NULL) {
    logmsg(0x03, "malloc(%zu) failed\n", size);
    exit(1);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scalloc>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L8:
  mov    %r13,%rdx
  lea    D0(%rip),%rsi
  mov    $0x3,%edi
  call   <logmsg@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: malloc(%zu) failed


assistant: ```c
void *scalloc(size_t size) {
  void *result = calloc(size, 1);
  if (result == NULL) {
    logmsg(0x03, "malloc(%zu) failed\n", size);
    exit(1);
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scalloc>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L0:
  mov    %r13,%rdx
  lea    D7(%rip),%rsi
  mov    $0x3,%edi
  call   <logmsg@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: malloc(%zu) failed


assistant: ```c
void *scalloc(size_t size) {
  void *result = calloc(size, 1);
  if (result == NULL) {
    logmsg(0x03, "malloc(%zu) failed\n", size);
    exit(1);
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L25
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  je     L25
  mov    -0x20(%rbp),%rax
  jmp    L33
L25:
  mov    $0xffffffffffffffff,%rax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
size_t fsize(const char *s) {
  struct stat st;
  if (stat(s, &st) == 0 && S_ISREG(st.st_mode)) {
    return st.st_size;
  } else {
    return (size_t)-1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fsize>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0xffffffffffffffff,%rax
  test   %rdx,%rdx
  jne    L13
  mov    0x8(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  mov    $0xffffffffffffffff,%rax
  cmovne (%rsp),%rax
L13:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t fsize(const char *s) {
  struct stat st;
  if (stat(s, &st) == 0 && S_ISREG(st.st_mode)) {
    return st.st_size;
  } else {
    return (size_t)-1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fsize>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L36
  mov    0x8(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  je     L36
  mov    (%rsp),%rax
  jmp    L1
  nopl   0x0(%rax)
L36:
  mov    $0xffffffffffffffff,%rax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x28,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t fsize(const char *s) {
  struct stat st;
  if (stat(s, &st) == 0 && S_ISREG(st.st_mode)) {
    return st.st_size;
  } else {
    return (size_t)-1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fsize>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L36
  mov    0x8(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  je     L36
  mov    (%rsp),%rax
  jmp    L26
  nopl   0x0(%rax)
L36:
  mov    $0xffffffffffffffff,%rax
L26:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x28,%rsp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t fsize(const char *s) {
  struct stat st;
  if (stat(s, &st) == 0 && S_ISREG(st.st_mode)) {
    return st.st_size;
  } else {
    return (size_t)-1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %al,-0x4(%rbp)
  cmpl   $0x4,-0x8(%rbp)
  je     L78
  cmpl   $0x4,-0x8(%rbp)
  jg     L4
  cmpl   $0x3,-0x8(%rbp)
  je     L76
  cmpl   $0x3,-0x8(%rbp)
  jg     L4
  cmpl   $0x1,-0x8(%rbp)
  je     L49
  cmpl   $0x2,-0x8(%rbp)
  je     L154
  jmp    L4
L49:
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L39
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L39
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ispunct@plt>
  test   %eax,%eax
  je     L228
L39:
  cmpb   $0x28,-0x4(%rbp)
  je     L228
  cmpb   $0x29,-0x4(%rbp)
  je     L228
  mov    $0x1,%eax
  jmp    L185
L154:
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L75
  mov    $0x1,%eax
  jmp    L185
L76:
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L223
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L91
L223:
  mov    $0x1,%eax
  jmp    L185
L78:
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L93
  mov    $0x1,%eax
  jmp    L185
L228:
  nop
  jmp    L4
L75:
  nop
  jmp    L4
L91:
  nop
  jmp    L4
L93:
  nop
L4:
  mov    $0x0,%eax
L185:
  leave
  ret
```

assistant: ```c
int loop(char a, int x) {
  switch (x) {
  case 1:
    if ((isdigit(a) || isalpha(a) || ispunct(a)) && (a != '(' && a != ')')) {
      return 1;
    }
    break;
  case 2:
    if (isalpha(a))
      return 1;
    break;
  case 3:
    if (isalpha(a) || isdigit(a))
      return 1;
    break;
  case 4:
    if (isdigit(a))
      return 1;
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<loop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  cmp    $0x3,%esi
  je     L80
  jg     L37
  cmp    $0x1,%esi
  je     L61
  cmp    $0x2,%esi
  jne    L49
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L121:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L49:
  mov    $0x0,%eax
  jmp    L121
L37:
  mov    $0x0,%eax
  cmp    $0x4,%esi
  jne    L121
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L121
L61:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L94
L86:
  lea    -0x28(%rbx),%edi
  cmp    $0x1,%dil
  seta   %al
  movzbl %al,%eax
  jmp    L121
L94:
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L86
  mov    %ebp,%edi
  call   <ispunct@plt>
  test   %eax,%eax
  je     L121
  jmp    L86
L80:
  movsbl %dil,%ebx
  mov    %ebx,%edi
  call   <isalpha@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L121
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L121
```

assistant: ```c
int loop(char a, int x) {
  switch (x) {
  case 1:
    if ((isdigit(a) || isalpha(a) || ispunct(a)) && (a != '(' && a != ')')) {
      return 1;
    }
    break;
  case 2:
    if (isalpha(a))
      return 1;
    break;
  case 3:
    if (isalpha(a) || isdigit(a))
      return 1;
    break;
  case 4:
    if (isdigit(a))
      return 1;
    break;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<loop>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x3,%esi
  je     L19
  jg     L70
  cmp    $0x1,%esi
  je     L21
  cmp    $0x2,%esi
  jne    L53
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L82:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L70:
  cmp    $0x4,%esi
  jne    L53
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L53:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L21:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L103
L88:
  lea    -0x28(%rbx),%edi
  xor    %eax,%eax
  cmp    $0x1,%dil
  seta   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  jne    L82
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L82
  nopl   0x0(%rax)
L103:
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L88
  mov    %ebp,%edi
  call   <ispunct@plt>
  test   %eax,%eax
  jne    L88
  jmp    L82
```

assistant: ```c
int loop(char a, int x) {
  switch (x) {
  case 1:
    if ((isdigit(a) || isalpha(a) || ispunct(a)) && (a != '(' && a != ')')) {
      return 1;
    }
    break;
  case 2:
    if (isalpha(a))
      return 1;
    break;
  case 3:
    if (isalpha(a) || isdigit(a))
      return 1;
    break;
  case 4:
    if (isdigit(a))
      return 1;
    break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<loop>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x3,%esi
  je     L36
  jg     L101
  cmp    $0x1,%esi
  je     L27
  cmp    $0x2,%esi
  jne    L88
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L90:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L101:
  cmp    $0x4,%esi
  jne    L88
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L88:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L27:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L81
L41:
  lea    -0x28(%rbx),%edi
  xor    %eax,%eax
  cmp    $0x1,%dil
  seta   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  jne    L90
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L90
  nopl   0x0(%rax)
L81:
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L41
  mov    %ebp,%edi
  call   <ispunct@plt>
  test   %eax,%eax
  jne    L41
  jmp    L90
```

assistant: ```c
int loop(char a, int x) {
  switch (x) {
  case 1:
    if ((isdigit(a) || isalpha(a) || ispunct(a)) && (a != '(' && a != ')')) {
      return 1;
    }
    break;
  case 2:
    if (isalpha(a))
      return 1;
    break;
  case 3:
    if (isalpha(a) || isdigit(a))
      return 1;
    break;
  case 4:
    if (isdigit(a))
      return 1;
    break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reduce8>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %edi,%r9d
  mov    %esi,%edi
  mov    %edx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0xd0,0xc(%rsp)
  movl   $0x10,0x10(%rsp)
  movl   $0x10,0x14(%rsp)
  movl   $0x10,0x18(%rsp)
  movl   $0xe0,0x1c(%rsp)
  movl   $0x10,0x20(%rsp)
  movl   $0xf7,0x24(%rsp)
  movl   $0xf5,0x28(%rsp)
  movl   $0x3a,0x2c(%rsp)
  movl   $0x10,0x30(%rsp)
  movl   $0x10,0x34(%rsp)
  movl   $0xf0,0x38(%rsp)
  movl   $0xfb,0x3c(%rsp)
  movl   $0x3d,0x40(%rsp)
  movl   $0xf8,0x44(%rsp)
  movl   $0x10,0x48(%rsp)
  movl   $0xf0,0x4c(%rsp)
  movl   $0xf0,0x50(%rsp)
  movl   $0xf0,0x54(%rsp)
  movl   $0xf0,0x58(%rsp)
  movl   $0xf0,0x5c(%rsp)
  cmp    $0x1d,%esi
  setle  %dl
  cmp    $0x1d,%r8d
  setle  %al
  test   %al,%dl
  je     L56
  mov    $0x0,%r11d
  cmp    $0x1d,%r9d
  jle    L52
L56:
  cmp    $0xc8,%edi
  setg   %dl
  cmp    $0xc8,%r8d
  setg   %al
  test   %al,%dl
  je     L68
  cmp    $0xc8,%r9d
  jg     L93
L68:
  mov    %rsp,%rcx
  mov    $0x0,%esi
  mov    $0xffffffff,%r10d
  mov    $0x0,%r11d
  jmp    L34
L21:
  mov    %eax,%r10d
  mov    %esi,%r11d
L98:
  add    $0x1,%esi
  add    $0xc,%rcx
  cmp    $0x8,%esi
  je     L52
L34:
  mov    (%rcx),%edx
  sub    %r9d,%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  imul   %r9d,%eax
  mov    0x4(%rcx),%ebx
  sub    %edi,%ebx
  mov    %ebx,%edx
  neg    %edx
  cmovs  %ebx,%edx
  imul   %edi,%edx
  add    %edx,%eax
  mov    0x8(%rcx),%ebx
  sub    %r8d,%ebx
  mov    %ebx,%edx
  neg    %edx
  cmovs  %ebx,%edx
  imul   %r8d,%edx
  add    %edx,%eax
  cmp    $0xffffffff,%r10d
  je     L21
  cmp    %r10d,%eax
  jge    L98
  jmp    L21
L93:
  mov    $0x7,%r11d
L52:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    %r11d,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int reduce8(int r, int g, int b) {
  int colors_len = 8;
  int select = 0;
  int odistance = -1;
  int i, k = 1;
  int colors[][3] = {
      {0x00, 0x00, 0x00}, {0xd0, 0x10, 0x10}, {0x10, 0xe0, 0x10}, {0xf7, 0xf5, 0x3a}, {0x10, 0x10, 0xf0}, {0xfb, 0x3d, 0xf8}, {0x10, 0xf0, 0xf0}, {0xf0, 0xf0, 0xf0},
  };
  r /= k;
  r *= k;
  g /= k;
  g *= k;
  b /= k;
  b *= k;
  if (r < 30 && g < 30 && b < 30)
    return 0;
  if (r > 200 && g > 200 && b > 200)
    return 7;
  odistance = -1;
  for (i = 0; i < colors_len; i++) {
    int distance = (((((colors[i][0] - r)) < 0) ? -((colors[i][0] - r)) : ((colors[i][0] - r))) * (r)) + (((((colors[i][1] - g)) < 0) ? -((colors[i][1] - g)) : ((colors[i][1] - g))) * (g)) + (((((colors[i][2] - b)) < 0) ? -((colors[i][2] - b)) : ((colors[i][2] - b))) * (b));
    if (odistance == -1 || distance < odistance) {
      odistance = distance;
      select = i;
    }
  }
  return select;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reduce8>:
  endbr64
  push   %rbx
  mov    %esi,%r9d
  mov    %edi,%r8d
  mov    %edx,%r10d
  movabs $0xe000000010,%rsi
  movabs $0x3a000000f5,%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x18(%rsp)
  movabs $0x1000000010,%rax
  movabs $0xf700000010,%rsi
  mov    %rax,0x10(%rsp)
  mov    %rax,0x30(%rsp)
  movabs $0xfb000000f0,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xf80000003d,%rax
  mov    %rax,0x40(%rsp)
  movabs $0xf000000010,%rax
  mov    %rax,0x48(%rsp)
  add    $0xe0,%rax
  movl   $0xd0,0xc(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    %rdi,0x28(%rsp)
  mov    %rax,0x50(%rsp)
  mov    %rax,0x58(%rsp)
  cmp    $0x1d,%r8d
  jg     L68
  cmp    $0x1d,%r9d
  jg     L68
  xor    %r11d,%r11d
  cmp    $0x1d,%edx
  jle    L37
L94:
  mov    %r8d,%edi
  mov    %r9d,%eax
  lea    0xc(%rsp),%rcx
  neg    %edi
  cmovs  %r8d,%edi
  imul   %r8d,%edi
  neg    %eax
  cmovs  %r9d,%eax
  imul   %r9d,%eax
  add    %eax,%edi
  mov    %r10d,%eax
  neg    %eax
  cmovs  %r10d,%eax
  xor    %esi,%esi
  xor    %r11d,%r11d
  imul   %r10d,%eax
  add    %eax,%edi
  jmp    L38
  nop
L82:
  cmp    %eax,%edi
  jg     L74
L52:
  add    $0xc,%rcx
L38:
  add    $0x1,%esi
  cmp    $0x8,%esi
  je     L37
  mov    (%rcx),%edx
  mov    0x4(%rcx),%ebx
  sub    %r8d,%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  sub    %r9d,%ebx
  mov    %ebx,%edx
  imul   %r8d,%eax
  neg    %edx
  cmovs  %ebx,%edx
  mov    0x8(%rcx),%ebx
  imul   %r9d,%edx
  sub    %r10d,%ebx
  add    %edx,%eax
  mov    %ebx,%edx
  neg    %edx
  cmovs  %ebx,%edx
  imul   %r10d,%edx
  add    %edx,%eax
  cmp    $0xffffffff,%edi
  jne    L82
L74:
  mov    %eax,%edi
  mov    %esi,%r11d
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L68:
  cmp    $0xc8,%r9d
  setg   %dl
  cmp    $0xc8,%r10d
  setg   %al
  test   %al,%dl
  je     L94
  mov    $0x7,%r11d
  cmp    $0xc8,%r8d
  jle    L94
  nop
L37:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  add    $0x70,%rsp
  mov    %r11d,%eax
  pop    %rbx
  ret
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int reduce8(int r, int g, int b) {
  int colors_len = 8;
  int select = 0;
  int odistance = -1;
  int i, k = 1;
  int colors[][3] = {
      {0x00, 0x00, 0x00}, {0xd0, 0x10, 0x10}, {0x10, 0xe0, 0x10}, {0xf7, 0xf5, 0x3a}, {0x10, 0x10, 0xf0}, {0xfb, 0x3d, 0xf8}, {0x10, 0xf0, 0xf0}, {0xf0, 0xf0, 0xf0},
  };
  r /= k;
  r *= k;
  g /= k;
  g *= k;
  b /= k;
  b *= k;
  if (r < 30 && g < 30 && b < 30)
    return 0;
  if (r > 200 && g > 200 && b > 200)
    return 7;
  odistance = -1;
  for (i = 0; i < colors_len; i++) {
    int distance = (((((colors[i][0] - r)) < 0) ? -((colors[i][0] - r)) : ((colors[i][0] - r))) * (r)) + (((((colors[i][1] - g)) < 0) ? -((colors[i][1] - g)) : ((colors[i][1] - g))) * (g)) + (((((colors[i][2] - b)) < 0) ? -((colors[i][2] - b)) : ((colors[i][2] - b))) * (b));
    if (odistance == -1 || distance < odistance) {
      odistance = distance;
      select = i;
    }
  }
  return select;
}
```