ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<extract_http_code>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
  cmp    $0xc,%esi
  jle    L21
  movzbl (%rdi),%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x48,%cl
  jne    L21
  movzbl 0x1(%rdi),%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x54,%cl
  jne    L21
  movzbl 0x2(%rdi),%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x54,%cl
  jne    L21
  movzbl 0x3(%rdi),%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x50,%cl
  jne    L21
  cmpb   $0x2f,0x4(%rdi)
  je     L57
L21:
  mov    %edx,%eax
  ret
L57:
  movzbl 0x5(%rdi),%esi
  lea    -0x30(%rsi),%ecx
  cmp    $0x9,%cl
  ja     L21
  cmpb   $0x2e,0x6(%rdi)
  jne    L21
  movzbl 0x7(%rdi),%edi
  lea    -0x30(%rdi),%ecx
  cmp    $0x9,%cl
  ja     L21
  cmpb   $0x20,0x8(%rax)
  jne    L21
  movzbl 0x9(%rax),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  ja     L21
  movzbl 0xa(%rax),%esi
  lea    -0x30(%rsi),%edi
  cmp    $0x9,%dil
  ja     L21
  movzbl 0xb(%rax),%edi
  lea    -0x30(%rdi),%r8d
  cmp    $0x9,%r8b
  ja     L21
  cmpb   $0x20,0xc(%rax)
  jne    L21
  movsbl %cl,%eax
  sub    $0x30,%eax
  imul   $0x64,%eax,%eax
  movsbl %sil,%edx
  sub    $0x30,%edx
  imul   $0xa,%edx,%edx
  add    %edx,%eax
  movsbl %dil,%edi
  lea    -0x30(%rax,%rdi,1),%edx
  jmp    L21
```

assistant: ```c
int extract_http_code(char *response, int response_size) {
  int code = 0;
  if (response_size < 13) {
    return code;
  }
  if ((response[0] == 'h' || response[0] == 'H') && (response[1] == 't' || response[1] == 'T') && (response[2] == 't' || response[2] == 'T') && (response[3] == 'p' || response[3] == 'P') && response[4] == '/' && (response[5] >= '0' && response[5] <= '9') && response[6] == '.' && (response[7] >= '0' && response[7] <= '9') && response[8] == ' ' && (response[9] >= '0' && response[9] <= '9') && (response[10] >= '0' && response[10] <= '9') && (response[11] >= '0' && response[11] <= '9') && response[12] == ' ') {
    code += 100 * (response[9] - '0');
    code += 10 * (response[10] - '0');
    code += response[11] - '0';
  }
  return code;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<extract_http_code>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0xc,%esi
  jle    L110
  movzbl (%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x48,%al
  jne    L110
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x54,%al
  jne    L110
  movzbl 0x2(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x54,%al
  jne    L110
  movzbl 0x3(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x50,%al
  jne    L110
  cmpb   $0x2f,0x4(%rdi)
  jne    L110
  movzbl 0x5(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L110
  cmpb   $0x2e,0x6(%rdi)
  jne    L110
  movzbl 0x7(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L110
  cmpb   $0x20,0x8(%rdi)
  jne    L110
  movzbl 0x9(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L110
  movzbl 0xa(%rdi),%ecx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  ja     L110
  movzbl 0xb(%rdi),%ecx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  ja     L110
  cmpb   $0x20,0xc(%rdi)
  jne    L110
  movsbl %al,%eax
  movsbl %dl,%edx
  movsbl %cl,%ecx
  imul   $0x64,%eax,%eax
  imul   $0xa,%edx,%edx
  add    %edx,%eax
  lea    (%rcx,%rax,1),%r8d
L110:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int extract_http_code(char *response, int response_size) {
  int code = 0;
  if (response_size < 13) {
    return code;
  }
  if ((response[0] == 'h' || response[0] == 'H') && (response[1] == 't' || response[1] == 'T') && (response[2] == 't' || response[2] == 'T') && (response[3] == 'p' || response[3] == 'P') && response[4] == '/' && (response[5] >= '0' && response[5] <= '9') && response[6] == '.' && (response[7] >= '0' && response[7] <= '9') && response[8] == ' ' && (response[9] >= '0' && response[9] <= '9') && (response[10] >= '0' && response[10] <= '9') && (response[11] >= '0' && response[11] <= '9') && response[12] == ' ') {
    code += 100 * (response[9] - '0');
    code += 10 * (response[10] - '0');
    code += response[11] - '0';
  }
  return code;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<extract_http_code>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0xc,%esi
  jle    L119
  movzbl (%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x48,%al
  jne    L119
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x54,%al
  jne    L119
  movzbl 0x2(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x54,%al
  jne    L119
  movzbl 0x3(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x50,%al
  jne    L119
  cmpb   $0x2f,0x4(%rdi)
  jne    L119
  movzbl 0x5(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L119
  cmpb   $0x2e,0x6(%rdi)
  jne    L119
  movzbl 0x7(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L119
  cmpb   $0x20,0x8(%rdi)
  jne    L119
  movzbl 0x9(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L119
  movzbl 0xa(%rdi),%ecx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  ja     L119
  movzbl 0xb(%rdi),%ecx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  ja     L119
  cmpb   $0x20,0xc(%rdi)
  jne    L119
  movsbl %al,%eax
  movsbl %dl,%edx
  movsbl %cl,%ecx
  imul   $0x64,%eax,%eax
  imul   $0xa,%edx,%edx
  add    %edx,%eax
  lea    (%rcx,%rax,1),%r8d
L119:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int extract_http_code(char *response, int response_size) {
  int code = 0;
  if (response_size < 13) {
    return code;
  }
  if ((response[0] == 'h' || response[0] == 'H') && (response[1] == 't' || response[1] == 'T') && (response[2] == 't' || response[2] == 'T') && (response[3] == 'p' || response[3] == 'P') && response[4] == '/' && (response[5] >= '0' && response[5] <= '9') && response[6] == '.' && (response[7] >= '0' && response[7] <= '9') && response[8] == ' ' && (response[9] >= '0' && response[9] <= '9') && (response[10] >= '0' && response[10] <= '9') && (response[11] >= '0' && response[11] <= '9') && response[12] == ' ') {
    code += 100 * (response[9] - '0');
    code += 10 * (response[10] - '0');
    code += response[11] - '0';
  }
  return code;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x727473206d612069,%rax
  mov    %rax,-0x14(%rbp)
  movl   $0x676e69,-0xc(%rbp)
  movzbl -0xb(%rbp),%eax
  mov    %al,-0x15(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(void) {
  char str[12] = "i am string";
  char c = str[9];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char str[12] = "i am string";
  char c = str[9];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char str[12] = "i am string";
  char c = str[9];
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char str[12] = "i am string";
  char c = str[9];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tokeniseUserCommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x12c,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x12c,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x12c,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L11
L1:
  addl   $0x1,-0x1c(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
L11:
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: D2:  

assistant: ```c
char **tokeniseUserCommand(char *command) {
  char *buff = malloc(sizeof(char) * 300);
  buff = strncpy(buff, command, sizeof(char) * 300);
  char **tokens = malloc(sizeof(char) * 300);
  char *token = malloc(50);
  int i = 0;
  token = strtok(buff, " ");
  tokens[i] = token;
  while (token != 0) {
    i++;
    token = strtok(NULL, " ");
    tokens[i] = token;
  }
  return tokens;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tokeniseUserCommand>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x12c,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x12c,%edx
  mov    %rbx,%rsi
  call   <strncpy@plt>
  mov    %rax,%rbx
  mov    $0x12c,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x32,%edi
  call   <malloc@plt>
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L6
  lea    0x8(%r12),%rbx
  lea    D14(%rip),%rbp
L14:
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  test   %rax,%rax
  jne    L14
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: string

tool: D14:  

assistant: ```c
char **tokeniseUserCommand(char *command) {
  char *buff = malloc(sizeof(char) * 300);
  buff = strncpy(buff, command, sizeof(char) * 300);
  char **tokens = malloc(sizeof(char) * 300);
  char *token = malloc(50);
  int i = 0;
  token = strtok(buff, " ");
  tokens[i] = token;
  while (token != 0) {
    i++;
    token = strtok(NULL, " ");
    tokens[i] = token;
  }
  return tokens;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tokeniseUserCommand>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x12c,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    $0x12c,%edx
  lea    D1(%rip),%rbp
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    $0x12c,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x32,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L9
  lea    0x8(%r12),%rbx
  nopl   (%rax)
L14:
  mov    %rbp,%rsi
  xor    %edi,%edi
  add    $0x8,%rbx
  call   <strtok@plt>
  mov    %rax,-0x8(%rbx)
  test   %rax,%rax
  jne    L14
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1:  

assistant: ```c
char **tokeniseUserCommand(char *command) {
  char *buff = malloc(sizeof(char) * 300);
  buff = strncpy(buff, command, sizeof(char) * 300);
  char **tokens = malloc(sizeof(char) * 300);
  char *token = malloc(50);
  int i = 0;
  token = strtok(buff, " ");
  tokens[i] = token;
  while (token != 0) {
    i++;
    token = strtok(NULL, " ");
    tokens[i] = token;
  }
  return tokens;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tokeniseUserCommand>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x12c,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    $0x12c,%edx
  lea    D5(%rip),%rbp
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    $0x12c,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x32,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L12
  lea    0x8(%r12),%rbx
  nopl   (%rax)
L10:
  mov    %rbp,%rsi
  xor    %edi,%edi
  add    $0x8,%rbx
  call   <strtok@plt>
  mov    %rax,-0x8(%rbx)
  test   %rax,%rax
  jne    L10
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D5:  

assistant: ```c
char **tokeniseUserCommand(char *command) {
  char *buff = malloc(sizeof(char) * 300);
  buff = strncpy(buff, command, sizeof(char) * 300);
  char **tokens = malloc(sizeof(char) * 300);
  char *token = malloc(50);
  int i = 0;
  token = strtok(buff, " ");
  tokens[i] = token;
  while (token != 0) {
    i++;
    token = strtok(NULL, " ");
    tokens[i] = token;
  }
  return tokens;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x10,-0x8(%rbp)
  movss  D49(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movb   $0x61,-0xa(%rbp)
  movb   $0x61,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0xa(%rbp),%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0x9(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D49
type_infered: f32
name: disassemble_data
arguments: label: D35
type_infered: string
name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D44
type_infered: string
name: disassemble_data
arguments: label: D40
type_infered: string

tool: D49: 3.14

tool: D35: my number is: %d


tool: D7: my floating point number is: %f


tool: D44: char1 = %c


tool: D40: char2 97 = %c


assistant: ```c
int main() {
  int age;
  age = 16;
  float x = 3.14;
  char ch1 = 'a';
  char ch2 = 97;
  printf("my number is: %d\n", age);
  printf("my floating point number is: %f\n", x);
  printf("char1 = %c\n", ch1);
  printf("char2 97 = %c\n", ch2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type: string
name: parse_data
arguments: tag: D13
type: string
name: parse_data
arguments: tag: D9
type: string
name: parse_data
arguments: tag: D0
type: string

tool: D10: my number is: %d


tool: D13: my floating point number is: %f


tool: D9: char1 = %c


tool: D0: char2 97 = %c


assistant: ```c
int main() {
  int age;
  age = 16;
  float x = 3.14;
  char ch1 = 'a';
  char ch2 = 97;
  printf("my number is: %d\n", age);
  printf("my floating point number is: %f\n", x);
  printf("char1 = %c\n", ch1);
  printf("char2 97 = %c\n", ch2);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string
name: read_data
arguments: label: D25
data_type: string
name: read_data
arguments: label: D35
data_type: string
name: read_data
arguments: label: D28
data_type: string

tool: D5: my number is: %d


tool: D25: my floating point number is: %f


tool: D35: char1 = %c


tool: D28: char2 97 = %c


assistant: ```c
int main() {
  int age;
  age = 16;
  float x = 3.14;
  char ch1 = 'a';
  char ch2 = 97;
  printf("my number is: %d\n", age);
  printf("my floating point number is: %f\n", x);
  printf("char1 = %c\n", ch1);
  printf("char2 97 = %c\n", ch2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D20
datatype: string
name: read_data
arguments: tag: D0
datatype: string

tool: D22: my number is: %d


tool: D11: my floating point number is: %f


tool: D20: char1 = %c


tool: D0: char2 97 = %c


assistant: ```c
int main() {
  int age;
  age = 16;
  float x = 3.14;
  char ch1 = 'a';
  char ch2 = 97;
  printf("my number is: %d\n", age);
  printf("my floating point number is: %f\n", x);
  printf("char1 = %c\n", ch1);
  printf("char2 97 = %c\n", ch2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jg     L3
  mov    $0x1,%eax
  jmp    L11
L3:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <factorial>
  imul   -0x8(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
long long factorial(long long f) {
  if (f <= 0)
    return 1;
  return f * factorial(f - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  jle    L9
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rdi),%rdi
  call   <factorial>
  imul   %rbx,%rax
  pop    %rbx
  ret
L9:
  ret
```

assistant: ```c
long long factorial(long long f) {
  if (f <= 0)
    return 1;
  return f * factorial(f - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  jle    L18
  xchg   %ax,%ax
L5:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  jne    L5
L18:
  ret
```

assistant: ```c
long long factorial(long long f) {
  if (f <= 0)
    return 1;
  return f * factorial(f - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  jle    L12
  xchg   %ax,%ax
L17:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  jne    L17
L12:
  ret
```

assistant: ```c
long long factorial(long long f) {
  if (f <= 0)
    return 1;
  return f * factorial(f - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<version_display>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D89(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  lea    D46(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  lea    D65(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  lea    D79(%rip),%rdx
  lea    D34(%rip),%rsi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  lea    D70(%rip),%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <print_log@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D89
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D46
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D42
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D65
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D79
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D34
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D54
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D33
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D70
type_infered: string

tool: D89: 


tool: D46: 	*********************************************


tool: D42: 	*      FCI   DMB RECEIVER MODEL             *


tool: D65: 	*                                           *


tool: D79: 01:01:19

tool: D34: Mar 19 2022

tool: D54: 	*         %s  %s             *


tool: D0: 	*       Digital Multimedia Broadcast        *


tool: D17: 	*            http://www.fci.co.kr           *


tool: D33: 	Version Information


tool: D70: 	Functions:


assistant: ```c
void version_display(void) {
  print_log("\n");
  print_log("\t*********************************************\n");
  print_log("\t*      FCI   DMB RECEIVER MODEL             *\n");
  print_log("\t*                                           *\n");
  print_log("\t*         %s  %s             *\n", "Mar 19 2022", "01:01:19");
  print_log("\t*                                           *\n");
  print_log("\t*       Digital Multimedia Broadcast        *\n");
  print_log("\t*                                           *\n");
  print_log("\t*            http://www.fci.co.kr           *\n");
  print_log("\t*********************************************\n");
  print_log("\tVersion Information\n");
  print_log("\tFunctions:\n");
  print_log("\n");
}
```