ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<MSB2DWORD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void MSB2DWORD(unsigned int *d, unsigned char *b) {
  unsigned int retVal;
  retVal = (unsigned int)b[0];
  retVal = (retVal << 8) + (unsigned int)b[1];
  retVal = (retVal << 8) + (unsigned int)b[2];
  retVal = (retVal << 8) + (unsigned int)b[3];
  *d = retVal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MSB2DWORD>:
  endbr64
  movzbl (%rsi),%eax
  shl    $0x8,%eax
  movzbl 0x1(%rsi),%edx
  add    %eax,%edx
  shl    $0x8,%edx
  movzbl 0x2(%rsi),%eax
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl 0x3(%rsi),%edx
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void MSB2DWORD(unsigned int *d, unsigned char *b) {
  unsigned int retVal;
  retVal = (unsigned int)b[0];
  retVal = (retVal << 8) + (unsigned int)b[1];
  retVal = (retVal << 8) + (unsigned int)b[2];
  retVal = (retVal << 8) + (unsigned int)b[3];
  *d = retVal;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MSB2DWORD>:
  endbr64
  movzbl (%rsi),%eax
  movzbl 0x1(%rsi),%edx
  shl    $0x8,%eax
  add    %eax,%edx
  movzbl 0x2(%rsi),%eax
  shl    $0x8,%edx
  add    %edx,%eax
  movzbl 0x3(%rsi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void MSB2DWORD(unsigned int *d, unsigned char *b) {
  unsigned int retVal;
  retVal = (unsigned int)b[0];
  retVal = (retVal << 8) + (unsigned int)b[1];
  retVal = (retVal << 8) + (unsigned int)b[2];
  retVal = (retVal << 8) + (unsigned int)b[3];
  *d = retVal;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MSB2DWORD>:
  endbr64
  movzbl (%rsi),%eax
  movzbl 0x1(%rsi),%edx
  shl    $0x8,%eax
  add    %eax,%edx
  movzbl 0x2(%rsi),%eax
  shl    $0x8,%edx
  add    %edx,%eax
  movzbl 0x3(%rsi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void MSB2DWORD(unsigned int *d, unsigned char *b) {
  unsigned int retVal;
  retVal = (unsigned int)b[0];
  retVal = (retVal << 8) + (unsigned int)b[1];
  retVal = (retVal << 8) + (unsigned int)b[2];
  retVal = (retVal << 8) + (unsigned int)b[3];
  *d = retVal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FUZ_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  imul   $0x9e3779b1,%eax,%eax
  lea    -0x7a143589(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0xb,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned FUZ_rand(unsigned *src) {
  *src = ((*src) * 2654435761U) + 2246822519U;
  return (*src) >> 11;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FUZ_rand>:
  endbr64
  imul   $0x9e3779b1,(%rdi),%eax
  sub    $0x7a143589,%eax
  mov    %eax,(%rdi)
  shr    $0xb,%eax
  ret
```

assistant: ```c
unsigned FUZ_rand(unsigned *src) {
  *src = ((*src) * 2654435761U) + 2246822519U;
  return (*src) >> 11;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FUZ_rand>:
  endbr64
  imul   $0x9e3779b1,(%rdi),%eax
  sub    $0x7a143589,%eax
  mov    %eax,(%rdi)
  shr    $0xb,%eax
  ret
```

assistant: ```c
unsigned FUZ_rand(unsigned *src) {
  *src = ((*src) * 2654435761U) + 2246822519U;
  return (*src) >> 11;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FUZ_rand>:
  endbr64
  imul   $0x9e3779b1,(%rdi),%eax
  sub    $0x7a143589,%eax
  mov    %eax,(%rdi)
  shr    $0xb,%eax
  ret
```

assistant: ```c
unsigned FUZ_rand(unsigned *src) {
  *src = ((*src) * 2654435761U) + 2246822519U;
  return (*src) >> 11;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recvLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L47
L5:
  lea    -0xd(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <recv@plt>
  test   %rax,%rax
  jle    L29
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  movzbl -0xd(%rbp),%eax
  cmp    $0xa,%al
  je     L39
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L5
  jmp    L37
L29:
  nop
  jmp    L37
L39:
  nop
L37:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int recvLine(int pSockId, char *pOut, int pOutSize) {
  int received = 0;
  char letter;
  memset(pOut, 0, pOutSize);
  for (; received < pOutSize - 1; received++) {
    if (recv(pSockId, (char *)&letter, 1, 0) > 0) {
      pOut[received] = letter;
      if (letter == '\n')
        break;
    } else
      break;
  }
  return received;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<recvLine>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  cmp    $0x1,%r12d
  jle    L27
  sub    $0x1,%r12d
  mov    $0x0,%ebp
  lea    0x7(%rsp),%r14
L57:
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  test   %rax,%rax
  jle    L33
  movzbl 0x7(%rsp),%eax
  mov    %al,(%rbx)
  cmp    $0xa,%al
  je     L33
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  jne    L57
  mov    %r12d,%ebp
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    %ebp,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  mov    $0x0,%ebp
  jmp    L33
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recvLine(int pSockId, char *pOut, int pOutSize) {
  int received = 0;
  char letter;
  memset(pOut, 0, pOutSize);
  for (; received < pOutSize - 1; received++) {
    if (recv(pSockId, (char *)&letter, 1, 0) > 0) {
      pOut[received] = letter;
      if (letter == '\n')
        break;
    } else
      break;
  }
  return received;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recvLine>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  sub    $0x1,%r13d
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  test   %r13d,%r13d
  jle    L2
  lea    0x7(%rsp),%r14
  jmp    L1
  nopl   (%rax)
L55:
  movzbl 0x7(%rsp),%eax
  mov    %al,(%rbx)
  cmp    $0xa,%al
  je     L2
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r13d,%r12d
  je     L2
L1:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  test   %rax,%rax
  jg     L55
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recvLine(int pSockId, char *pOut, int pOutSize) {
  int received = 0;
  char letter;
  memset(pOut, 0, pOutSize);
  for (; received < pOutSize - 1; received++) {
    if (recv(pSockId, (char *)&letter, 1, 0) > 0) {
      pOut[received] = letter;
      if (letter == '\n')
        break;
    } else
      break;
  }
  return received;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recvLine>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  sub    $0x1,%r13d
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  test   %r13d,%r13d
  jle    L18
  lea    0x7(%rsp),%r14
  jmp    L10
  nopl   (%rax)
L45:
  movzbl 0x7(%rsp),%eax
  mov    %al,(%rbx)
  cmp    $0xa,%al
  je     L18
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r13d,%r12d
  je     L18
L10:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  test   %rax,%rax
  jg     L45
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recvLine(int pSockId, char *pOut, int pOutSize) {
  int received = 0;
  char letter;
  memset(pOut, 0, pOutSize);
  for (; received < pOutSize - 1; received++) {
    if (recv(pSockId, (char *)&letter, 1, 0) > 0) {
      pOut[received] = letter;
      if (letter == '\n')
        break;
    } else
      break;
  }
  return received;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dissect_cr_rn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extract_cr_rn@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__dissect_cr@plt>
  nop
  leave
  ret
```

assistant: ```c
void dissect_cr_rn(unsigned long local_cr, unsigned long rn) {
  unsigned int masked_cr;
  masked_cr = extract_cr_rn(local_cr, rn);
  __dissect_cr(masked_cr);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dissect_cr_rn>:
  endbr64
  sub    $0x8,%rsp
  call   <extract_cr_rn@plt>
  mov    %eax,%edi
  call   <__dissect_cr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dissect_cr_rn(unsigned long local_cr, unsigned long rn) {
  unsigned int masked_cr;
  masked_cr = extract_cr_rn(local_cr, rn);
  __dissect_cr(masked_cr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dissect_cr_rn>:
  endbr64
  sub    $0x8,%rsp
  call   <extract_cr_rn@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <__dissect_cr@plt>
```

assistant: ```c
void dissect_cr_rn(unsigned long local_cr, unsigned long rn) {
  unsigned int masked_cr;
  masked_cr = extract_cr_rn(local_cr, rn);
  __dissect_cr(masked_cr);
}
```
user: What is the c source code of the assembly code below?

```asm
<dissect_cr_rn>:
  endbr64
  sub    $0x8,%rsp
  call   <extract_cr_rn@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <__dissect_cr@plt>
```

assistant: ```c
void dissect_cr_rn(unsigned long local_cr, unsigned long rn) {
  unsigned int masked_cr;
  masked_cr = extract_cr_rn(local_cr, rn);
  __dissect_cr(masked_cr);
}
```
user: What is the c source code of the assembly code below?

```asm
<lace_specific_util>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int (*lace_specific_util(const char *arg))(unsigned, char **) {
  (void)arg;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lace_specific_util>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int (*lace_specific_util(const char *arg))(unsigned, char **) {
  (void)arg;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lace_specific_util>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int (*lace_specific_util(const char *arg))(unsigned, char **) {
  (void)arg;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<lace_specific_util>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int (*lace_specific_util(const char *arg))(unsigned, char **) {
  (void)arg;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Write_SRT_Timestamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L26
  mov    $0xffffffff,%eax
  jmp    L20
L26:
  mov    -0x30(%rbp),%rax
  movabs $0x4a90be587de6e565,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x14,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  imul   $0x36ee80,%rax,%rax
  sub    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  shr    $0x5,%rax
  movabs $0x45e7b272f608771,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x5,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  imul   $0xea60,%rax,%rax
  sub    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  shr    $0x3,%rax
  movabs $0x20c49ba5e353f7cf,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  imul   $0x3e8,%rax,%rax
  sub    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdi
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  jns    L10
  mov    $0xffffffff,%eax
  jmp    L20
L10:
  mov    $0x0,%eax
L20:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %02lu:%02lu:%02lu,%03lu

assistant: ```c
int Write_SRT_Timestamp(FILE *outf, unsigned long timestamp) {
  unsigned long hours = 0, minutes = 0, seconds = 0, millis = 0;
  if (outf == NULL)
    return -1;
  hours = timestamp / 3600000;
  timestamp -= (hours * 3600000);
  minutes = timestamp / 60000;
  timestamp -= (minutes * 60000);
  seconds = timestamp / 1000;
  timestamp -= (seconds * 1000);
  millis = timestamp;
  if (fprintf(outf, "%02lu:%02lu:%02lu,%03lu", hours, minutes, seconds, millis) < 0)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Write_SRT_Timestamp>:
  endbr64
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  mov    %rdi,%r10
  movabs $0x4a90be587de6e565,%rdi
  mov    %rsi,%rax
  mul    %rdi
  mov    %rdx,%rdi
  mov    %rdx,%r8
  shr    $0x14,%r8
  imul   $0x36ee80,%r8,%rax
  sub    %rax,%rsi
  mov    %rsi,%rcx
  shr    $0x5,%rcx
  movabs $0x45e7b272f608771,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%rcx
  mov    %rdx,%r9
  shr    $0x5,%r9
  imul   $0xea60,%r9,%rax
  mov    %rsi,%r9
  sub    %rax,%r9
  mov    %r9,%r8
  shr    $0x3,%r8
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %r8,%rax
  mul    %rdx
  shr    $0x4,%rdx
  mov    %rdx,%r8
  imul   $0x3e8,%rdx,%rax
  shr    $0x5,%rcx
  shr    $0x14,%rdi
  mov    %rdi,%rdx
  sub    %rax,%r9
  lea    D0(%rip),%rsi
  mov    %r10,%rdi
  call   <fprintf@plt>
  sar    $0x3f,%rax
  add    $0x8,%rsp
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: %02lu:%02lu:%02lu,%03lu

assistant: ```c
int Write_SRT_Timestamp(FILE *outf, unsigned long timestamp) {
  unsigned long hours = 0, minutes = 0, seconds = 0, millis = 0;
  if (outf == NULL)
    return -1;
  hours = timestamp / 3600000;
  timestamp -= (hours * 3600000);
  minutes = timestamp / 60000;
  timestamp -= (minutes * 60000);
  seconds = timestamp / 1000;
  timestamp -= (seconds * 1000);
  millis = timestamp;
  if (fprintf(outf, "%02lu:%02lu:%02lu,%03lu", hours, minutes, seconds, millis) < 0)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Write_SRT_Timestamp>:
  endbr64
  test   %rdi,%rdi
  je     L2
  mov    %rdi,%r10
  mov    %rsi,%rax
  sub    $0x8,%rsp
  movabs $0x4a90be587de6e565,%rdi
  mul    %rdi
  mov    %rdx,%r8
  mov    %rdx,%rdi
  movabs $0x45e7b272f608771,%rdx
  shr    $0x14,%r8
  shr    $0x14,%rdi
  imul   $0x36ee80,%r8,%rax
  sub    %rax,%rsi
  mov    %rsi,%rcx
  shr    $0x5,%rcx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%r9
  mov    %rdx,%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  shr    $0x5,%r9
  shr    $0x5,%rcx
  imul   $0xea60,%r9,%rax
  mov    %rsi,%r9
  lea    D0(%rip),%rsi
  sub    %rax,%r9
  mov    %r9,%r8
  shr    $0x3,%r8
  mov    %r8,%rax
  mul    %rdx
  shr    $0x4,%rdx
  imul   $0x3e8,%rdx,%rax
  mov    %rdx,%r8
  mov    %rdi,%rdx
  mov    %r10,%rdi
  sub    %rax,%r9
  call   <fprintf@plt>
  add    $0x8,%rsp
  sar    $0x3f,%rax
  ret
L2:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: %02lu:%02lu:%02lu,%03lu

assistant: ```c
int Write_SRT_Timestamp(FILE *outf, unsigned long timestamp) {
  unsigned long hours = 0, minutes = 0, seconds = 0, millis = 0;
  if (outf == NULL)
    return -1;
  hours = timestamp / 3600000;
  timestamp -= (hours * 3600000);
  minutes = timestamp / 60000;
  timestamp -= (minutes * 60000);
  seconds = timestamp / 1000;
  timestamp -= (seconds * 1000);
  millis = timestamp;
  if (fprintf(outf, "%02lu:%02lu:%02lu,%03lu", hours, minutes, seconds, millis) < 0)
    return -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Write_SRT_Timestamp>:
  endbr64
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%r10
  mov    %rsi,%rax
  sub    $0x8,%rsp
  movabs $0x4a90be587de6e565,%rdi
  mul    %rdi
  mov    %rdx,%r8
  mov    %rdx,%rdi
  movabs $0x45e7b272f608771,%rdx
  shr    $0x14,%r8
  shr    $0x14,%rdi
  imul   $0x36ee80,%r8,%rax
  sub    %rax,%rsi
  mov    %rsi,%rcx
  shr    $0x5,%rcx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%r9
  mov    %rdx,%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  shr    $0x5,%r9
  shr    $0x5,%rcx
  imul   $0xea60,%r9,%rax
  mov    %rsi,%r9
  lea    D7(%rip),%rsi
  sub    %rax,%r9
  mov    %r9,%r8
  shr    $0x3,%r8
  mov    %r8,%rax
  mul    %rdx
  shr    $0x4,%rdx
  imul   $0x3e8,%rdx,%rax
  mov    %rdx,%r8
  mov    %rdi,%rdx
  mov    %r10,%rdi
  sub    %rax,%r9
  call   <fprintf@plt>
  add    $0x8,%rsp
  sar    $0x3f,%rax
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: %02lu:%02lu:%02lu,%03lu

assistant: ```c
int Write_SRT_Timestamp(FILE *outf, unsigned long timestamp) {
  unsigned long hours = 0, minutes = 0, seconds = 0, millis = 0;
  if (outf == NULL)
    return -1;
  hours = timestamp / 3600000;
  timestamp -= (hours * 3600000);
  minutes = timestamp / 60000;
  timestamp -= (minutes * 60000);
  seconds = timestamp / 1000;
  timestamp -= (seconds * 1000);
  millis = timestamp;
  if (fprintf(outf, "%02lu:%02lu:%02lu,%03lu", hours, minutes, seconds, millis) < 0)
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L17:
  cmpl   $0x3b,-0x4(%rbp)
  jne    L45
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_comment@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L45:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
  cmpl   $0x3b,-0x4(%rbp)
  je     L17
  mov    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int skip_whitespace(FILE *file) {
  int lastc = 0;
  int i = 0;
  while (isspace(lastc = getc(file)) || lastc == ';') {
    if (lastc == ';') {
      i += skip_comment(file);
    } else {
      i++;
    }
  }
  ungetc(lastc, file);
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_whitespace>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebp
  jmp    L30
L48:
  cmp    $0x3b,%ebx
  je     L43
  add    $0x1,%ebp
L30:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isspace@plt>
  cmp    $0x3b,%ebx
  je     L48
  test   %rax,%rax
  jne    L48
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <ungetc@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    %r12,%rdi
  call   <skip_comment@plt>
  add    %eax,%ebp
  jmp    L30
```

assistant: ```c
int skip_whitespace(FILE *file) {
  int lastc = 0;
  int i = 0;
  while (isspace(lastc = getc(file)) || lastc == ';') {
    if (lastc == ';') {
      i += skip_comment(file);
    } else {
      i++;
    }
  }
  ungetc(lastc, file);
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<skip_whitespace>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  nop
L29:
  mov    %r13,%rdi
  call   <getc@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
  cmp    $0x3b,%ebp
  jne    L37
L10:
  mov    %r13,%rdi
  call   <skip_comment@plt>
  add    %eax,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L13:
  cmp    $0x3b,%ebp
  je     L10
  add    $0x1,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <ungetc@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int skip_whitespace(FILE *file) {
  int lastc = 0;
  int i = 0;
  while (isspace(lastc = getc(file)) || lastc == ';') {
    if (lastc == ';') {
      i += skip_comment(file);
    } else {
      i++;
    }
  }
  ungetc(lastc, file);
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_whitespace>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  nop
L29:
  mov    %r13,%rdi
  call   <getc@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  cmp    $0x3b,%ebp
  jne    L34
L8:
  mov    %r13,%rdi
  call   <skip_comment@plt>
  add    %eax,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L10:
  cmp    $0x3b,%ebp
  je     L8
  add    $0x1,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <ungetc@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int skip_whitespace(FILE *file) {
  int lastc = 0;
  int i = 0;
  while (isspace(lastc = getc(file)) || lastc == ';') {
    if (lastc == ';') {
      i += skip_comment(file);
    } else {
      i++;
    }
  }
  ungetc(lastc, file);
  return i;
}
```