user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L105
L160:
  mov    -0x48(%rbp),%rax
  test   %rax,%rax
  jne    L78
  mov    -0x40(%rbp),%rax
  test   %rax,%rax
  je     L80
L78:
  mov    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  cmp    %rax,%rdx
  jbe    L77
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L17
L77:
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L17:
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L33
L50:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x4c(%rbp)
L168:
  cmpq   $0x1,-0x38(%rbp)
  jne    L69
  movq   $0x4,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L61
L69:
  cmpq   $0x1,-0x20(%rbp)
  jne    L1
  addl   $0x1,-0x4c(%rbp)
  jmp    L61
L1:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L138
  mov    -0x20(%rbp),%rax
  shr    %rax
  mov    %rax,-0x20(%rbp)
  addl   $0x1,-0x4c(%rbp)
  jmp    L168
L138:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L168
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  addl   $0x1,-0x4c(%rbp)
  jmp    L168
L61:
  mov    -0x4c(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jae    L22
  mov    -0x4c(%rbp),%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L22:
  addq   $0x1,-0x38(%rbp)
L33:
  mov    -0x38(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jbe    L50
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rsi
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L105:
  lea    -0x40(%rbp),%rdx
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L160
  jmp    L32
L80:
  nop
L32:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L158
  call   <__stack_chk_fail@plt>
L158:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
type_guessed: string
name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D18: Between %llu and %llu, %llu generates the longest sequence of %llu values.


tool: D5: %llu %llu

assistant: ```c
int main() {
  long long unsigned i, n, m, p, q, x, len = 0, bignum, t;
  int count = 0;
  while (scanf("%llu %llu", &n, &m) == 2) {
    if (n == 0 && m == 0)
      break;
    if (m > n) {
      p = n;
      q = m;
    } else {
      p = m;
      q = n;
    }
    len = 0;
    bignum = 0;
    for (i = p; i <= q; i++) {
      x = i;
      count = 0;
      while (1) {
        if (i == 1) {
          len = 4;
          bignum = 1;
          break;
        } else {
          if (x == 1) {
            count++;
            break;
          } else if (x % 2 == 0) {
            x = x / 2;
            count++;
          } else if (x % 2 == 1) {
            x = 3 * x + 1;
            count++;
          }
        }
      }
      if (count > len) {
        len = count;
        bignum = i;
      }
    }
    printf("Between %llu and %llu, %llu generates the longest sequence of %llu values.\n", p, q, bignum, len - 1);
  }
  return 0;
}
```