ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dg2ch>:
  endbr64
  push   %r13
  movsbl %sil,%r13d
  xor    %eax,%eax
  push   %r12
  movsbl %dil,%r12d
  mov    %r13d,%edx
  push   %rbp
  mov    %edi,%ebp
  lea    D17(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  mov    %r12d,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    -0x30(%rbp),%eax
  cmp    $0x9,%al
  ja     L63
  sub    $0x30,%r12d
  shl    $0x4,%r12d
L77:
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  ja     L50
L3:
  lea    -0x30(%r13,%r12,1),%r12d
L68:
  mov    %r12d,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  lea    -0x61(%rbp),%eax
  cmp    $0x19,%al
  ja     L6
  sub    $0x57,%r12d
  lea    -0x30(%rbx),%eax
  shl    $0x4,%r12d
  cmp    $0x9,%al
  jbe    L3
L50:
  lea    -0x61(%rbx),%eax
  cmp    $0x19,%al
  ja     L32
  lea    -0x57(%r13,%r12,1),%r12d
  jmp    L68
  nopl   0x0(%rax)
L32:
  sub    $0x41,%ebx
  lea    -0x37(%r13,%r12,1),%eax
  cmp    $0x1a,%bl
  cmovb  %eax,%r12d
  jmp    L68
  nopl   0x0(%rax)
L6:
  sub    $0x37,%r12d
  sub    $0x41,%ebp
  xor    %eax,%eax
  shl    $0x4,%r12d
  cmp    $0x1a,%bpl
  cmovae %eax,%r12d
  jmp    L77
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D10
type_guessed: string

tool: D17: dg2ch: %02x %02x


tool: D10: dg2ch: tmp=%02X


assistant: ```c
int dg2ch(char c1, char c2) {
  printf("dg2ch: %02x %02x\n", c1, c2);
  int tmp;
  if (c1 >= '0' && c1 <= '9')
    tmp = (c1 - '0') * 0x10;
  else if (c1 >= 'a' && c1 <= 'z')
    tmp = (c1 - 'a' + 10) * 0x10;
  else if (c1 >= 'A' && c1 <= 'Z')
    tmp = (c1 - 'A' + 10) * 0x10;
  else
    tmp = 0;
  if (c2 >= '0' && c2 <= '9')
    tmp += c2 - '0';
  else if (c2 >= 'a' && c2 <= 'z')
    tmp += c2 - 'a' + 10;
  else if (c2 >= 'A' && c2 <= 'Z')
    tmp += c2 - 'A' + 10;
  printf("dg2ch: tmp=%02X\n", tmp);
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x5,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x6,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x7,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x8,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x9,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0xa,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <report@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: a

assistant: ```c
void main() {
  unsigned a = input("a");
  assert(fget_float(a) == 1);
  assert(fget_float(a) == 2);
  assert(fget_float(a) == 3);
  assert(fget_float(a) == 4);
  assert(fget_float(a) == 5);
  assert(fget_float(a) == 6);
  assert(fget_float(a) == 7);
  assert(fget_float(a) == 8);
  assert(fget_float(a) == 9);
  assert(fget_float(a) == 10);
  report(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rdi
  call   <input@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <fget_float@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0x2,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0x3,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0x4,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0x5,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0x6,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0x7,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0x8,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0x9,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <fget_float@plt>
  cmp    $0xa,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <report@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: a

assistant: ```c
void main() {
  unsigned a = input("a");
  assert(fget_float(a) == 1);
  assert(fget_float(a) == 2);
  assert(fget_float(a) == 3);
  assert(fget_float(a) == 4);
  assert(fget_float(a) == 5);
  assert(fget_float(a) == 6);
  assert(fget_float(a) == 7);
  assert(fget_float(a) == 8);
  assert(fget_float(a) == 9);
  assert(fget_float(a) == 10);
  report(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  call   <input@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x4,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x6,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x7,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x8,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x9,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    10b0 <report@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: a

assistant: ```c
void main() {
  unsigned a = input("a");
  assert(fget_float(a) == 1);
  assert(fget_float(a) == 2);
  assert(fget_float(a) == 3);
  assert(fget_float(a) == 4);
  assert(fget_float(a) == 5);
  assert(fget_float(a) == 6);
  assert(fget_float(a) == 7);
  assert(fget_float(a) == 8);
  assert(fget_float(a) == 9);
  assert(fget_float(a) == 10);
  report(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  call   <input@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x4,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x6,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x7,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x8,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0x9,%eax
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <fget_float@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    10b0 <report@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: a

assistant: ```c
void main() {
  unsigned a = input("a");
  assert(fget_float(a) == 1);
  assert(fget_float(a) == 2);
  assert(fget_float(a) == 3);
  assert(fget_float(a) == 4);
  assert(fget_float(a) == 5);
  assert(fget_float(a) == 6);
  assert(fget_float(a) == 7);
  assert(fget_float(a) == 8);
  assert(fget_float(a) == 9);
  assert(fget_float(a) == 10);
  report(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<try_to_freeze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <get_current@plt>
  mov    %eax,%edi
  call   <freezing@plt>
  test   %rax,%rax
  je     L0
  mov    $0x0,%eax
  call   <refrigerator@plt>
  mov    $0x1,%eax
  jmp    L12
L0:
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int try_to_freeze(void) {
  if (freezing(get_current())) {
    refrigerator();
    return 1;
  } else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<try_to_freeze>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_current@plt>
  mov    %eax,%edi
  call   <freezing@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L8
L6:
  add    $0x8,%rsp
  ret
L8:
  call   <refrigerator@plt>
  mov    $0x1,%eax
  jmp    L6
```

assistant: ```c
__attribute__((always_)) int try_to_freeze(void) {
  if (freezing(get_current())) {
    refrigerator();
    return 1;
  } else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<try_to_freeze>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_current@plt>
  mov    %eax,%edi
  call   <freezing@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L9
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L9:
  call   <refrigerator@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
__attribute__((always_)) int try_to_freeze(void) {
  if (freezing(get_current())) {
    refrigerator();
    return 1;
  } else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<try_to_freeze>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_current@plt>
  mov    %eax,%edi
  call   <freezing@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L3
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L3:
  call   <refrigerator@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
__attribute__((always_)) int try_to_freeze(void) {
  if (freezing(get_current())) {
    refrigerator();
    return 1;
  } else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AtoH>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L6:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <BtoH@plt>
  movsbl %al,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <BtoH@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void AtoH(char *src, char *dest, int destlen) {
  char *srcptr;
  char *destTemp;
  srcptr = src;
  destTemp = (char *)dest;
  while (destlen--) {
    *destTemp = BtoH(*srcptr++) << 4;
    *destTemp += BtoH(*srcptr++);
    destTemp++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<AtoH>:
  endbr64
  test   %edx,%edx
  je     L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%edx
  lea    (%rdi,%rdx,2),%r12
L8:
  movsbl (%rbx),%edi
  call   <BtoH@plt>
  movsbl %al,%eax
  shl    $0x4,%eax
  mov    %al,0x0(%rbp)
  add    $0x2,%rbx
  movsbl -0x1(%rbx),%edi
  call   <BtoH@plt>
  add    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %rbx,%r12
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

assistant: ```c
void AtoH(char *src, char *dest, int destlen) {
  char *srcptr;
  char *destTemp;
  srcptr = src;
  destTemp = (char *)dest;
  while (destlen--) {
    *destTemp = BtoH(*srcptr++) << 4;
    *destTemp += BtoH(*srcptr++);
    destTemp++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AtoH>:
  endbr64
  test   %edx,%edx
  je     L19
  mov    %edx,%edx
  push   %r12
  lea    (%rdi,%rdx,2),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl (%rbx),%edi
  add    $0x2,%rbx
  call   <BtoH@plt>
  movsbl %al,%eax
  shl    $0x4,%eax
  mov    %al,0x0(%rbp)
  movsbl -0x1(%rbx),%edi
  call   <BtoH@plt>
  add    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %rbx,%r12
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L19:
  ret
```

assistant: ```c
void AtoH(char *src, char *dest, int destlen) {
  char *srcptr;
  char *destTemp;
  srcptr = src;
  destTemp = (char *)dest;
  while (destlen--) {
    *destTemp = BtoH(*srcptr++) << 4;
    *destTemp += BtoH(*srcptr++);
    destTemp++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AtoH>:
  endbr64
  test   %edx,%edx
  je     L4
  mov    %edx,%edx
  push   %r12
  lea    (%rdi,%rdx,2),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%rbx),%edi
  add    $0x2,%rbx
  call   <BtoH@plt>
  movsbl %al,%eax
  shl    $0x4,%eax
  mov    %al,0x0(%rbp)
  movsbl -0x1(%rbx),%edi
  call   <BtoH@plt>
  add    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %rbx,%r12
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L4:
  ret
```

assistant: ```c
void AtoH(char *src, char *dest, int destlen) {
  char *srcptr;
  char *destTemp;
  srcptr = src;
  destTemp = (char *)dest;
  while (destlen--) {
    *destTemp = BtoH(*srcptr++) << 4;
    *destTemp += BtoH(*srcptr++);
    destTemp++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gettimeofday_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
unsigned long gettimeofday_ms(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000) + (tv.tv_usec / 1000);
}
```
user: What is the c source code of the assembly code below:

```asm
<gettimeofday_ms>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  cltq
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long gettimeofday_ms(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000) + (tv.tv_usec / 1000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gettimeofday_ms>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  cltq
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long gettimeofday_ms(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000) + (tv.tv_usec / 1000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gettimeofday_ms>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  cltq
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long gettimeofday_ms(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000) + (tv.tv_usec / 1000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<number_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  nop
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L51
  jmp    L54
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L46
  mov    $0x1,%eax
  jmp    L51
L46:
  mov    $0x1,%eax
  jmp    L51
L54:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L8
L51:
  pop    %rbp
  ret
```

assistant: ```c
int number_prime(int nummer) {
  int num;
  for (num = 2; num < nummer && nummer % num != 0; num++)
    if (num < nummer)
      return 1;
    else
      return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<number_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L0
  mov    $0x1,%eax
  test   $0x1,%dil
L0:
  ret
```

assistant: ```c
int number_prime(int nummer) {
  int num;
  for (num = 2; num < nummer && nummer % num != 0; num++)
    if (num < nummer)
      return 1;
    else
      return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<number_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L2
  mov    $0x1,%eax
L2:
  ret
```

assistant: ```c
int number_prime(int nummer) {
  int num;
  for (num = 2; num < nummer && nummer % num != 0; num++)
    if (num < nummer)
      return 1;
    else
      return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<number_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L3
  mov    $0x1,%eax
L3:
  ret
```

assistant: ```c
int number_prime(int nummer) {
  int num;
  for (num = 2; num < nummer && nummer % num != 0; num++)
    if (num < nummer)
      return 1;
    else
      return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L11
  mov    $0x1,%edi
  call   <foo@plt>
  jmp    L10
L11:
  mov    $0x1,%edi
  call   <foo@plt>
L10:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (__VERIFIER_nondet_int())
    foo(1);
  else
    foo(1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L6
  mov    $0x1,%edi
  call   <foo@plt>
L0:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L6:
  mov    $0x1,%edi
  call   <foo@plt>
  jmp    L0
```

assistant: ```c
int main() {
  if (__VERIFIER_nondet_int())
    foo(1);
  else
    foo(1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    $0x1,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (__VERIFIER_nondet_int())
    foo(1);
  else
    foo(1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    $0x1,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (__VERIFIER_nondet_int())
    foo(1);
  else
    foo(1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yy_1_InternalLinkAutoCorrect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void yy_1_InternalLinkAutoCorrect(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yy_1_InternalLinkAutoCorrect>:
  endbr64
  ret
```

assistant: ```c
void yy_1_InternalLinkAutoCorrect(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<yy_1_InternalLinkAutoCorrect>:
  endbr64
  ret
```

assistant: ```c
void yy_1_InternalLinkAutoCorrect(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mbtowc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <_mbrtowc_ptr@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  test   %eax,%eax
  jns    L18
  mov    $0xffffffff,%eax
  jmp    L19
L18:
  mov    -0x20(%rbp),%rax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int mbtowc(wchar_t *__restrict pwc, const char *__restrict s, size_t n) {
  size_t x;
  mbstate_t mb = {0, 0, 0};
  x = _mbrtowc_ptr(pwc, s, n, &mb);
  if (((int)x) < 0)
    return -1;
  return x;
}
```