ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<alpha_insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L47
  mov    $0x0,%eax
  jmp    L49
L47:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x14(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L0:
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x4(%rbp),%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int alpha_insert(char guess, char hidden_word[], char guess_word[]) {
  int i;
  int matches = 0;
  for (i = 0; hidden_word[i] != '\0'; ++i) {
    if (guess == guess_word[i]) {
      return 0;
    }
    if (guess == hidden_word[i]) {
      guess_word[i] = guess;
      ++matches;
    }
  }
  return matches;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<alpha_insert>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L26
  mov    $0x0,%r8d
  mov    $0x0,%eax
  jmp    L18
L8:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L63
L18:
  cmp    %dil,(%rdx,%rax,1)
  je     L32
  cmp    %cl,%dil
  jne    L8
  mov    %dil,(%rdx,%rax,1)
  add    $0x1,%r8d
  jmp    L8
L26:
  mov    $0x0,%r8d
  jmp    L63
L32:
  mov    $0x0,%r8d
L63:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int alpha_insert(char guess, char hidden_word[], char guess_word[]) {
  int i;
  int matches = 0;
  for (i = 0; hidden_word[i] != '\0'; ++i) {
    if (guess == guess_word[i]) {
      return 0;
    }
    if (guess == hidden_word[i]) {
      guess_word[i] = guess;
      ++matches;
    }
  }
  return matches;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<alpha_insert>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L14
  xor    %r8d,%r8d
  xor    %eax,%eax
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L19:
  cmp    %cl,%dil
  jne    L33
  mov    %dil,(%rdx,%rax,1)
  add    $0x1,%r8d
L33:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L37
L8:
  cmp    %dil,(%rdx,%rax,1)
  jne    L19
L14:
  xor    %r8d,%r8d
L37:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int alpha_insert(char guess, char hidden_word[], char guess_word[]) {
  int i;
  int matches = 0;
  for (i = 0; hidden_word[i] != '\0'; ++i) {
    if (guess == guess_word[i]) {
      return 0;
    }
    if (guess == hidden_word[i]) {
      guess_word[i] = guess;
      ++matches;
    }
  }
  return matches;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<alpha_insert>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L24
  xor    %r8d,%r8d
  xor    %eax,%eax
L58:
  cmp    %dil,(%rdx,%rax,1)
  je     L24
L45:
  cmp    %cl,%dil
  je     L26
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L58
L42:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %dil,(%rdx,%rax,1)
  add    $0x1,%rax
  add    $0x1,%r8d
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L42
  cmp    %dil,(%rdx,%rax,1)
  jne    L45
L24:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int alpha_insert(char guess, char hidden_word[], char guess_word[]) {
  int i;
  int matches = 0;
  for (i = 0; hidden_word[i] != '\0'; ++i) {
    if (guess == guess_word[i]) {
      return 0;
    }
    if (guess == hidden_word[i]) {
      guess_word[i] = guess;
      ++matches;
    }
  }
  return matches;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x68(%rbp)
  movl   $0x0,-0x64(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L19
L46:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <readLine@plt>
  movzbl -0x60(%rbp),%eax
  test   %al,%al
  jne    L8
  movl   $0x1,-0x64(%rbp)
  jmp    L19
L8:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <countWords@plt>
  add    %eax,-0x68(%rbp)
L19:
  cmpl   $0x0,-0x64(%rbp)
  je     L46
  mov    -0x68(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D22
type_infered: string

tool: D25: Type in your text.

tool: D11: When you are done, press 'RETURN'.


tool: D22: 
There are %i words in the above text.


assistant: ```c
int main(void) {
  char text[81];
  int totalWords = 0;
  int countWords(const char string[]);
  void readLine(char buffer[]);
  bool endOfText = false;
  printf("Type in your text.\n");
  printf("When you are done, press 'RETURN'.\n\n");
  while (!endOfText) {
    readLine(text);
    if (text[0] == '\0')
      endOfText = true;
    else
      totalWords += countWords(text);
  }
  printf("\nThere are %i words in the above text.\n", totalWords);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L12
L24:
  mov    %rbp,%rdi
  call   <countWords@plt>
  add    %eax,%ebx
L12:
  mov    %rbp,%rdi
  call   <readLine@plt>
  cmpb   $0x0,(%rsp)
  jne    L24
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D16
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D29: Type in your text.

tool: D16: When you are done, press 'RETURN'.


tool: D5: 
There are %i words in the above text.


assistant: ```c
int main(void) {
  char text[81];
  int totalWords = 0;
  int countWords(const char string[]);
  void readLine(char buffer[]);
  bool endOfText = false;
  printf("Type in your text.\n");
  printf("When you are done, press 'RETURN'.\n\n");
  while (!endOfText) {
    readLine(text);
    if (text[0] == '\0')
      endOfText = true;
    else
      totalWords += countWords(text);
  }
  printf("\nThere are %i words in the above text.\n", totalWords);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <puts@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  jmp    L24
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rdi
  call   <countWords@plt>
  add    %eax,%ebp
L24:
  mov    %rbx,%rdi
  call   <readLine@plt>
  cmpb   $0x0,(%rsp)
  jne    L5
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string
name: disassemble_data
arguments: tag: D9
datatype: string

tool: D5: Type in your text.

tool: D14: When you are done, press 'RETURN'.


tool: D9: 
There are %i words in the above text.


assistant: ```c
int main(void) {
  char text[81];
  int totalWords = 0;
  int countWords(const char string[]);
  void readLine(char buffer[]);
  bool endOfText = false;
  printf("Type in your text.\n");
  printf("When you are done, press 'RETURN'.\n\n");
  while (!endOfText) {
    readLine(text);
    if (text[0] == '\0')
      endOfText = true;
    else
      totalWords += countWords(text);
  }
  printf("\nThere are %i words in the above text.\n", totalWords);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <puts@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L23
  nopl   0x0(%rax)
L28:
  mov    %rbx,%rdi
  call   <countWords@plt>
  add    %eax,%ebp
L23:
  mov    %rbx,%rdi
  call   <readLine@plt>
  cmpb   $0x0,(%rsp)
  jne    L28
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
datatype: string
name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string

tool: D16: Type in your text.

tool: D22: When you are done, press 'RETURN'.


tool: D7: 
There are %i words in the above text.


assistant: ```c
int main(void) {
  char text[81];
  int totalWords = 0;
  int countWords(const char string[]);
  void readLine(char buffer[]);
  bool endOfText = false;
  printf("Type in your text.\n");
  printf("When you are done, press 'RETURN'.\n\n");
  while (!endOfText) {
    readLine(text);
    if (text[0] == '\0')
      endOfText = true;
    else
      totalWords += countWords(text);
  }
  printf("\nThere are %i words in the above text.\n", totalWords);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gator_buffer_write_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <gator_buffer_write_packed_int@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <gator_buffer_write_bytes@plt>
  nop
  leave
  ret
```

assistant: ```c
void gator_buffer_write_string(int cpu, int buftype, const char *x) {
  int len = strlen(x);
  gator_buffer_write_packed_int(cpu, buftype, len);
  gator_buffer_write_bytes(cpu, buftype, x, len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gator_buffer_write_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <gator_buffer_write_packed_int@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <gator_buffer_write_bytes@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void gator_buffer_write_string(int cpu, int buftype, const char *x) {
  int len = strlen(x);
  gator_buffer_write_packed_int(cpu, buftype, len);
  gator_buffer_write_bytes(cpu, buftype, x, len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gator_buffer_write_string>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%edx
  mov    %eax,%r14d
  call   <gator_buffer_write_packed_int@plt>
  add    $0x8,%rsp
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <gator_buffer_write_bytes@plt>
```

assistant: ```c
void gator_buffer_write_string(int cpu, int buftype, const char *x) {
  int len = strlen(x);
  gator_buffer_write_packed_int(cpu, buftype, len);
  gator_buffer_write_bytes(cpu, buftype, x, len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gator_buffer_write_string>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%edx
  mov    %eax,%r14d
  call   <gator_buffer_write_packed_int@plt>
  add    $0x8,%rsp
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <gator_buffer_write_bytes@plt>
```

assistant: ```c
void gator_buffer_write_string(int cpu, int buftype, const char *x) {
  int len = strlen(x);
  gator_buffer_write_packed_int(cpu, buftype, len);
  gator_buffer_write_bytes(cpu, buftype, x, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<db_column_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L19
L3:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sqlite3_column_text@plt>
L19:
  leave
  ret
```

assistant: ```c
const char *db_column_text(struct db_query *query, int i) {
  if (query == NULL)
    return NULL;
  return (const char *)sqlite3_column_text((sqlite3_stmt *)query, i);
}
```
user: What is the c source code of the assembly code below:

```asm
<db_column_text>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <sqlite3_column_text@plt>
  add    $0x8,%rsp
  ret
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *db_column_text(struct db_query *query, int i) {
  if (query == NULL)
    return NULL;
  return (const char *)sqlite3_column_text((sqlite3_stmt *)query, i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<db_column_text>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <sqlite3_column_text@plt>
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *db_column_text(struct db_query *query, int i) {
  if (query == NULL)
    return NULL;
  return (const char *)sqlite3_column_text((sqlite3_stmt *)query, i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<db_column_text>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <sqlite3_column_text@plt>
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *db_column_text(struct db_query *query, int i) {
  if (query == NULL)
    return NULL;
  return (const char *)sqlite3_column_text((sqlite3_stmt *)query, i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bit_scan_forward_br64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L17
  mov    $0x0,%eax
  jmp    L4
L17:
  mov    -0x18(%rbp),%rax
  mov    %eax,%eax
  test   %rax,%rax
  jne    L5
  addl   $0x20,-0x4(%rbp)
  shrq   $0x20,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzwl %ax,%eax
  test   %rax,%rax
  jne    L15
  addl   $0x10,-0x4(%rbp)
  shrq   $0x10,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  movzbl %al,%eax
  test   %rax,%rax
  jne    L6
  addl   $0x8,-0x4(%rbp)
  shrq   $0x8,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  and    $0xf,%eax
  test   %rax,%rax
  jne    L42
  addl   $0x4,-0x4(%rbp)
  shrq   $0x4,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  and    $0x3,%eax
  test   %rax,%rax
  jne    L60
  addl   $0x2,-0x4(%rbp)
  shrq   $0x2,-0x18(%rbp)
L60:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int bit_scan_forward_br64(unsigned long long v) {
  int b;
  b = 0;
  if (v & 0x01ULL)
    return 0;
  if (!(v & 0xffffffffULL)) {
    b += 32;
    v >>= 32;
  }
  if (!(v & 0xffffULL)) {
    b += 16;
    v >>= 16;
  }
  if (!(v & 0xffULL)) {
    b += 8;
    v >>= 8;
  }
  if (!(v & 0x0fULL)) {
    b += 4;
    v >>= 4;
  }
  if (!(v & 0x03ULL)) {
    b += 2;
    v >>= 2;
  }
  b += !(v & 0x01ULL);
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bit_scan_forward_br64>:
  endbr64
  mov    $0x0,%eax
  test   $0x1,%dil
  jne    L2
  test   %edi,%edi
  jne    L5
  shr    $0x20,%rdi
  mov    $0x20,%eax
L5:
  test   %di,%di
  jne    L1
  add    $0x10,%eax
  shr    $0x10,%rdi
L1:
  test   %dil,%dil
  jne    L29
  add    $0x8,%eax
  shr    $0x8,%rdi
L29:
  test   $0xf,%dil
  jne    L17
  add    $0x4,%eax
  shr    $0x4,%rdi
L17:
  test   $0x3,%dil
  jne    L41
  add    $0x2,%eax
  shr    $0x2,%rdi
L41:
  xor    $0x1,%rdi
  and    $0x1,%edi
  add    %edi,%eax
L2:
  ret
```

assistant: ```c
int bit_scan_forward_br64(unsigned long long v) {
  int b;
  b = 0;
  if (v & 0x01ULL)
    return 0;
  if (!(v & 0xffffffffULL)) {
    b += 32;
    v >>= 32;
  }
  if (!(v & 0xffffULL)) {
    b += 16;
    v >>= 16;
  }
  if (!(v & 0xffULL)) {
    b += 8;
    v >>= 8;
  }
  if (!(v & 0x0fULL)) {
    b += 4;
    v >>= 4;
  }
  if (!(v & 0x03ULL)) {
    b += 2;
    v >>= 2;
  }
  b += !(v & 0x01ULL);
  return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<bit_scan_forward_br64>:
  endbr64
  xor    %eax,%eax
  test   $0x1,%dil
  jne    L18
  test   %edi,%edi
  jne    L28
  shr    $0x20,%rdi
  mov    $0x20,%eax
L28:
  test   %di,%di
  jne    L12
  add    $0x10,%eax
  shr    $0x10,%rdi
L12:
  test   %dil,%dil
  jne    L2
  add    $0x8,%eax
  shr    $0x8,%rdi
L2:
  test   $0xf,%dil
  jne    L8
  add    $0x4,%eax
  shr    $0x4,%rdi
L8:
  test   $0x3,%dil
  jne    L3
  add    $0x2,%eax
  shr    $0x2,%rdi
L3:
  not    %rdi
  and    $0x1,%edi
  add    %edi,%eax
L18:
  ret
```

assistant: ```c
int bit_scan_forward_br64(unsigned long long v) {
  int b;
  b = 0;
  if (v & 0x01ULL)
    return 0;
  if (!(v & 0xffffffffULL)) {
    b += 32;
    v >>= 32;
  }
  if (!(v & 0xffffULL)) {
    b += 16;
    v >>= 16;
  }
  if (!(v & 0xffULL)) {
    b += 8;
    v >>= 8;
  }
  if (!(v & 0x0fULL)) {
    b += 4;
    v >>= 4;
  }
  if (!(v & 0x03ULL)) {
    b += 2;
    v >>= 2;
  }
  b += !(v & 0x01ULL);
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bit_scan_forward_br64>:
  endbr64
  xor    %eax,%eax
  test   $0x1,%dil
  jne    L62
  test   %edi,%edi
  je     L46
  mov    $0x10,%edx
  xor    %eax,%eax
L33:
  test   %di,%di
  jne    L4
  shr    $0x10,%rdi
  mov    %edx,%eax
L4:
  test   %dil,%dil
  jne    L12
  add    $0x8,%eax
  shr    $0x8,%rdi
L12:
  test   $0xf,%dil
  jne    L1
  add    $0x4,%eax
  shr    $0x4,%rdi
L1:
  test   $0x3,%dil
  jne    L43
  add    $0x2,%eax
  shr    $0x2,%rdi
L43:
  not    %rdi
  and    $0x1,%edi
  add    %edi,%eax
L62:
  ret
  nopl   0x0(%rax)
L46:
  shr    $0x20,%rdi
  mov    $0x30,%edx
  mov    $0x20,%eax
  jmp    L33
```

assistant: ```c
int bit_scan_forward_br64(unsigned long long v) {
  int b;
  b = 0;
  if (v & 0x01ULL)
    return 0;
  if (!(v & 0xffffffffULL)) {
    b += 32;
    v >>= 32;
  }
  if (!(v & 0xffffULL)) {
    b += 16;
    v >>= 16;
  }
  if (!(v & 0xffULL)) {
    b += 8;
    v >>= 8;
  }
  if (!(v & 0x0fULL)) {
    b += 4;
    v >>= 4;
  }
  if (!(v & 0x03ULL)) {
    b += 2;
    v >>= 2;
  }
  b += !(v & 0x01ULL);
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fact_it>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L34
  mov    $0x0,%eax
  jmp    L11
L34:
  movq   $0x1,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x2,-0x8(%rbp)
  jmp    L0
L18:
  mov    -0x10(%rbp),%rax
  imul   -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jle    L18
  mov    -0x10(%rbp),%rax
L11:
  pop    %rbp
  ret
```

assistant: ```c
long fact_it(long n) {
  if (n < 0)
    return 0;
  long f = 1;
  long i = 0;
  for (i = 2; i <= n; i++)
    f = f * i;
  return f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fact_it>:
  endbr64
  mov    $0x0,%edx
  test   %rdi,%rdi
  js     L18
  cmp    $0x1,%rdi
  jle    L10
  add    $0x1,%rdi
  mov    $0x2,%eax
  mov    $0x1,%edx
L29:
  imul   %rax,%rdx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L29
L18:
  mov    %rdx,%rax
  ret
L10:
  mov    $0x1,%edx
  jmp    L18
```

assistant: ```c
long fact_it(long n) {
  if (n < 0)
    return 0;
  long f = 1;
  long i = 0;
  for (i = 2; i <= n; i++)
    f = f * i;
  return f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fact_it>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  js     L25
  cmp    $0x1,%rdi
  jle    L1
  add    $0x1,%rdi
  mov    $0x2,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L12:
  imul   %rax,%r8
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L12
L25:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%r8d
  jmp    L25
```

assistant: ```c
long fact_it(long n) {
  if (n < 0)
    return 0;
  long f = 1;
  long i = 0;
  for (i = 2; i <= n; i++)
    f = f * i;
  return f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fact_it>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  js     L25
  cmp    $0x1,%rdi
  jle    L4
  add    $0x1,%rdi
  mov    $0x2,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L22:
  imul   %rax,%r8
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L22
L25:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1,%r8d
  jmp    L25
```

assistant: ```c
long fact_it(long n) {
  if (n < 0)
    return 0;
  long f = 1;
  long i = 0;
  for (i = 2; i <= n; i++)
    f = f * i;
  return f;
}
```