ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<kthnr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %rcx,%r12
  test   %esi,%esi
  jle    L26
  movslq %esi,%rax
  lea    0x0(,%rax,4),%r14
  mov    -0x4(%rdi,%rax,4),%edx
  cmp    %edx,(%rdi,%rax,4)
  jg     L97
L26:
  lea    -0x1(%r13),%eax
  cmp    %ebx,%eax
  jle    L60
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%r14
  mov    0x4(%rbp,%rax,4),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jg     L75
L60:
  movslq %ebx,%rbx
  mov    (%r12,%rbx,4),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L97:
  add    %rcx,%r14
  mov    (%r14),%eax
  mov    %eax,0xc(%rsp)
  lea    -0x1(%rsi),%r15d
  mov    %r13d,%edx
  mov    %r15d,%esi
  call   <kthnr>
  add    $0x1,%eax
  cmp    %eax,0xc(%rsp)
  jle    L82
  mov    (%r14),%eax
L11:
  mov    %eax,(%r14)
  jmp    L26
L82:
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <kthnr>
  add    $0x1,%eax
  jmp    L11
L75:
  add    %r12,%r14
  mov    (%r14),%eax
  mov    %eax,0xc(%rsp)
  lea    0x1(%rbx),%r15d
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <kthnr>
  add    $0x1,%eax
  cmp    %eax,0xc(%rsp)
  jle    L13
  mov    (%r14),%eax
L27:
  mov    %eax,(%r14)
  jmp    L60
L13:
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <kthnr>
  add    $0x1,%eax
  jmp    L27
```

assistant: ```c
int kthnr(int *ratings, int k, int n, int *candy) {
  if (k > 0 && ratings[k] > ratings[k - 1]) {
    candy[k] = ((candy[k]) > (kthnr(ratings, k - 1, n, candy) + 1) ? (candy[k]) : (kthnr(ratings, k - 1, n, candy) + 1));
  }
  if (k < n - 1 && ratings[k] > ratings[k + 1]) {
    candy[k] = ((candy[k]) > (kthnr(ratings, k + 1, n, candy) + 1) ? (candy[k]) : (kthnr(ratings, k + 1, n, candy) + 1));
  }
  return candy[k];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kthnr>:
  endbr64
  push   %r15
  movslq %esi,%r8
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0x0(,%r8,4),%r12
  push   %rbp
  lea    (%rcx,%r12,1),%r9
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x28,%rsp
  mov    (%r9),%r15d
  test   %r8d,%r8d
  jle    L66
  mov    -0x4(%rdi,%r12,1),%eax
  cmp    %eax,(%rdi,%r8,4)
  jg     L12
L66:
  lea    -0x1(%r13),%eax
  cmp    %ebx,%eax
  jle    L64
  mov    0x4(%rbp,%r12,1),%eax
  cmp    %eax,0x0(%rbp,%r8,4)
  jg     L48
L64:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  lea    -0x1(%r8),%esi
  mov    %r8,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %esi,0x8(%rsp)
  call   <kthnr>
  mov    0x8(%rsp),%esi
  mov    0x10(%rsp),%r9
  add    $0x1,%eax
  mov    0x18(%rsp),%r8
  cmp    %r15d,%eax
  jge    L93
  mov    (%r9),%r15d
L45:
  mov    %r15d,(%r9)
  jmp    L66
  nopl   (%rax)
L48:
  lea    0x1(%rbx),%r12d
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    %r12d,%esi
  mov    %r9,0x8(%rsp)
  call   <kthnr>
  mov    0x8(%rsp),%r9
  add    $0x1,%eax
  cmp    %r15d,%eax
  jge    L78
  mov    (%r9),%r15d
L15:
  mov    %r15d,(%r9)
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L93:
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    %r8,0x10(%rsp)
  mov    %r9,0x8(%rsp)
  call   <kthnr>
  mov    0x10(%rsp),%r8
  mov    0x8(%rsp),%r9
  lea    0x1(%rax),%r15d
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L78:
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %r9,0x8(%rsp)
  call   <kthnr>
  mov    0x8(%rsp),%r9
  lea    0x1(%rax),%r15d
  jmp    L15
```

assistant: ```c
int kthnr(int *ratings, int k, int n, int *candy) {
  if (k > 0 && ratings[k] > ratings[k - 1]) {
    candy[k] = ((candy[k]) > (kthnr(ratings, k - 1, n, candy) + 1) ? (candy[k]) : (kthnr(ratings, k - 1, n, candy) + 1));
  }
  if (k < n - 1 && ratings[k] > ratings[k + 1]) {
    candy[k] = ((candy[k]) > (kthnr(ratings, k + 1, n, candy) + 1) ? (candy[k]) : (kthnr(ratings, k + 1, n, candy) + 1));
  }
  return candy[k];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kthnr>:
  endbr64
  push   %r15
  movslq %esi,%r8
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0x0(,%r8,4),%r12
  push   %rbp
  lea    (%rcx,%r12,1),%r9
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x28,%rsp
  mov    (%r9),%r15d
  test   %r8d,%r8d
  jle    L2
  mov    -0x4(%rdi,%r12,1),%eax
  cmp    %eax,(%rdi,%r8,4)
  jg     L82
L2:
  lea    -0x1(%r13),%eax
  cmp    %ebx,%eax
  jle    L92
  mov    0x4(%rbp,%r12,1),%eax
  cmp    %eax,0x0(%rbp,%r8,4)
  jg     L26
L92:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L82:
  lea    -0x1(%r8),%esi
  mov    %r8,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %esi,0x8(%rsp)
  call   <kthnr>
  mov    0x8(%rsp),%esi
  mov    0x10(%rsp),%r9
  add    $0x1,%eax
  mov    0x18(%rsp),%r8
  cmp    %r15d,%eax
  jge    L65
  mov    (%r9),%r15d
L90:
  mov    %r15d,(%r9)
  jmp    L2
  nopl   (%rax)
L26:
  lea    0x1(%rbx),%r12d
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    %r12d,%esi
  mov    %r9,0x8(%rsp)
  call   <kthnr>
  mov    0x8(%rsp),%r9
  add    $0x1,%eax
  cmp    %r15d,%eax
  jge    L20
  mov    (%r9),%r15d
L17:
  mov    %r15d,(%r9)
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    %r8,0x10(%rsp)
  mov    %r9,0x8(%rsp)
  call   <kthnr>
  mov    0x10(%rsp),%r8
  mov    0x8(%rsp),%r9
  lea    0x1(%rax),%r15d
  jmp    L90
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %r9,0x8(%rsp)
  call   <kthnr>
  mov    0x8(%rsp),%r9
  lea    0x1(%rax),%r15d
  jmp    L17
```

assistant: ```c
int kthnr(int *ratings, int k, int n, int *candy) {
  if (k > 0 && ratings[k] > ratings[k - 1]) {
    candy[k] = ((candy[k]) > (kthnr(ratings, k - 1, n, candy) + 1) ? (candy[k]) : (kthnr(ratings, k - 1, n, candy) + 1));
  }
  if (k < n - 1 && ratings[k] > ratings[k + 1]) {
    candy[k] = ((candy[k]) > (kthnr(ratings, k + 1, n, candy) + 1) ? (candy[k]) : (kthnr(ratings, k + 1, n, candy) + 1));
  }
  return candy[k];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
time_t my_clock(void) {
  struct timeval tp;
  struct timezone tzp = {.tz_minuteswest = 0, .tz_dsttime = 0};
  gettimeofday(&tp, &tzp);
  return tp.tv_sec * 1000 + (tp.tv_usec / 1000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_clock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0x3e8,0x8(%rsp),%eax
  mov    0xc(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t my_clock(void) {
  struct timeval tp;
  struct timezone tzp = {.tz_minuteswest = 0, .tz_dsttime = 0};
  gettimeofday(&tp, &tzp);
  return tp.tv_sec * 1000 + (tp.tv_usec / 1000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_clock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x10(%rsp)
  call   <gettimeofday@plt>
  movslq 0xc(%rsp),%rdx
  imul   $0x3e8,0x8(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t my_clock(void) {
  struct timeval tp;
  struct timezone tzp = {.tz_minuteswest = 0, .tz_dsttime = 0};
  gettimeofday(&tp, &tzp);
  return tp.tv_sec * 1000 + (tp.tv_usec / 1000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_clock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  call   <gettimeofday@plt>
  movslq 0x14(%rsp),%rdx
  imul   $0x3e8,0x10(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t my_clock(void) {
  struct timeval tp;
  struct timezone tzp = {.tz_minuteswest = 0, .tz_dsttime = 0};
  gettimeofday(&tp, &tzp);
  return tp.tv_sec * 1000 + (tp.tv_usec / 1000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rsi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L9
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L33
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L33:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L11
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string

tool: D4: Please enter 4 numbers separated by spaces > 

tool: D9: %d %d %d %d

tool: D22: %d is the smallest


assistant: ```c
int main() {
  int num1, num2, num3, num4, min;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d %d %d %d", &num1, &num2, &num3, &num4);
  min = num1;
  if (min > num2)
    min = num2;
  if (min > num3)
    min = num3;
  if (min > num4)
    min = num4;
  printf("%d is the smallest\n", min);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
type_infered: string
name: parse_data
arguments: data_tag: D24
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string

tool: D21: Please enter 4 numbers separated by spaces > 

tool: D24: %d %d %d %d

tool: D28: %d is the smallest


assistant: ```c
int main() {
  int num1, num2, num3, num4, min;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d %d %d %d", &num1, &num2, &num3, &num4);
  min = num1;
  if (min > num2)
    min = num2;
  if (min > num3)
    min = num3;
  if (min > num4)
    min = num4;
  printf("%d is the smallest\n", min);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  lea    D28(%rip),%rdi
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%esi
  lea    D27(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D27
type_guessed: string

tool: D7: Please enter 4 numbers separated by spaces > 

tool: D28: %d %d %d %d

tool: D27: %d is the smallest


assistant: ```c
int main() {
  int num1, num2, num3, num4, min;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d %d %d %d", &num1, &num2, &num3, &num4);
  min = num1;
  if (min > num2)
    min = num2;
  if (min > num3)
    min = num3;
  if (min > num4)
    min = num4;
  printf("%d is the smallest\n", min);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  lea    D24(%rip),%rdi
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%esi
  lea    D9(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D10: Please enter 4 numbers separated by spaces > 

tool: D24: %d %d %d %d

tool: D9: %d is the smallest


assistant: ```c
int main() {
  int num1, num2, num3, num4, min;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d %d %d %d", &num1, &num2, &num3, &num4);
  min = num1;
  if (min > num2)
    min = num2;
  if (min > num3)
    min = num3;
  if (min > num4)
    min = num4;
  printf("%d is the smallest\n", min);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L45:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L15
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  jmp    L26
L15:
  mov    -0x10(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %ecx,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %ecx,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  lea    (%rsi,%rax,1),%ecx
  mov    -0x10(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    (%rax,%rax,1),%esi
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %esi,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %ecx,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L26:
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string

tool: D9: %d %d

tool: D12: %d


assistant: ```c
int main() {
  while (1) {
    int h, t;
    scanf("%d %d", &h, &t);
    if (!h && !t)
      break;
    printf("%d\n", ((h % 2) * 2 + (t % 4) * 3) % 4 + (t + ((h % 2) * 2 + (t % 4) * 3) % 4) / 2 + (h + (t + ((h % 2) * 2 + (t % 4) * 3) % 4) / 2) / 2);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  lea    D7(%rip),%rbx
  lea    D0(%rip),%r13
  jmp    L26
L29:
  mov    %edx,%eax
  shr    $0x1f,%eax
  lea    (%rdx,%rax,1),%esi
  and    $0x1,%esi
  sub    %eax,%esi
  mov    %ecx,%edi
  sar    $0x1f,%edi
  shr    $0x1e,%edi
  lea    (%rcx,%rdi,1),%eax
  and    $0x3,%eax
  sub    %edi,%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rsi,2),%eax
  mov    %eax,%esi
  sar    $0x1f,%esi
  shr    $0x1e,%esi
  add    %esi,%eax
  and    $0x3,%eax
  sub    %esi,%eax
  add    %eax,%ecx
  mov    %ecx,%esi
  shr    $0x1f,%esi
  add    %esi,%ecx
  sar    %ecx
  add    %ecx,%edx
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  add    %ecx,%eax
  add    %eax,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L26:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%ecx
  mov    %edx,%eax
  or     %ecx,%eax
  jne    L29
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D7: %d %d

tool: D0: %d


assistant: ```c
int main() {
  while (1) {
    int h, t;
    scanf("%d %d", &h, &t);
    if (!h && !t)
      break;
    printf("%d\n", ((h % 2) * 2 + (t % 4) * 3) % 4 + (t + ((h % 2) * 2 + (t % 4) * 3) % 4) / 2 + (h + (t + ((h % 2) * 2 + (t % 4) * 3) % 4) / 2) / 2);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %edx,%eax
  mov    %ecx,%edi
  shr    $0x1f,%eax
  sar    $0x1f,%edi
  lea    (%rdx,%rax,1),%esi
  shr    $0x1e,%edi
  and    $0x1,%esi
  sub    %eax,%esi
  lea    (%rcx,%rdi,1),%eax
  and    $0x3,%eax
  sub    %edi,%eax
  mov    %r13,%rdi
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rsi,2),%eax
  mov    %eax,%esi
  sar    $0x1f,%esi
  shr    $0x1e,%esi
  add    %esi,%eax
  and    $0x3,%eax
  sub    %esi,%eax
  add    %eax,%ecx
  mov    %ecx,%esi
  shr    $0x1f,%esi
  add    %esi,%ecx
  sar    %ecx
  add    %ecx,%edx
  add    %ecx,%eax
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  add    %eax,%esi
  call   <printf@plt>
L3:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%ecx
  mov    %edx,%eax
  or     %ecx,%eax
  jne    L27
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string

tool: D3: %d


tool: D12: %d %d

assistant: ```c
int main() {
  while (1) {
    int h, t;
    scanf("%d %d", &h, &t);
    if (!h && !t)
      break;
    printf("%d\n", ((h % 2) * 2 + (t % 4) * 3) % 4 + (t + ((h % 2) * 2 + (t % 4) * 3) % 4) / 2 + (h + (t + ((h % 2) * 2 + (t % 4) * 3) % 4) / 2) / 2);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %edx,%eax
  mov    %ecx,%edi
  shr    $0x1f,%eax
  sar    $0x1f,%edi
  lea    (%rdx,%rax,1),%esi
  shr    $0x1e,%edi
  and    $0x1,%esi
  sub    %eax,%esi
  lea    (%rcx,%rdi,1),%eax
  and    $0x3,%eax
  sub    %edi,%eax
  mov    %r13,%rdi
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rsi,2),%eax
  mov    %eax,%esi
  sar    $0x1f,%esi
  shr    $0x1e,%esi
  add    %esi,%eax
  and    $0x3,%eax
  sub    %esi,%eax
  add    %eax,%ecx
  mov    %ecx,%esi
  shr    $0x1f,%esi
  add    %esi,%ecx
  sar    %ecx
  add    %ecx,%edx
  add    %ecx,%eax
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  add    %eax,%esi
  call   <printf@plt>
L16:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%ecx
  mov    %edx,%eax
  or     %ecx,%eax
  jne    L25
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D11: %d


tool: D6: %d %d

assistant: ```c
int main() {
  while (1) {
    int h, t;
    scanf("%d %d", &h, &t);
    if (!h && !t)
      break;
    printf("%d\n", ((h % 2) * 2 + (t % 4) * 3) % 4 + (t + ((h % 2) * 2 + (t % 4) * 3) % 4) / 2 + (h + (t + ((h % 2) * 2 + (t % 4) * 3) % 4) / 2) / 2);
  }
  return 0;
}
```