ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<my_memstr>:
  endbr64
  test   %rsi,%rsi
  je     L13
  movzbl (%rdx),%r11d
  push   %rbx
  mov    %rdi,%r8
  lea    0x1(%rdx),%rbx
  nopl   0x0(%rax)
L91:
  movzbl (%r8),%eax
  mov    %r8,%r9
  sub    $0x1,%rsi
  lea    0x1(%r8),%r8
  cmp    %r11b,%al
  je     L41
  test   %rsi,%rsi
  jne    L91
  xor    %r9d,%r9d
  pop    %rbx
  mov    %r9,%rax
  ret
  nopl   0x0(%rax)
L41:
  mov    %rbx,%rax
  test   %rsi,%rsi
  je     L58
  mov    %r8,%rcx
  lea    (%rbx,%rsi,1),%r10
  jmp    L99
  nopl   0x0(%rax)
L68:
  lea    0x1(%rax),%rdi
  add    $0x1,%rcx
  cmp    %r10,%rdi
  je     L66
  mov    %rdi,%rax
L99:
  movzbl (%rax),%edi
  cmp    %dil,(%rcx)
  je     L68
  test   %dil,%dil
  jne    L91
L30:
  mov    %r9,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  jne    L91
  jmp    L30
L58:
  cmpb   $0x0,0x1(%rdx)
  pop    %rbx
  cmovne %rsi,%r9
  mov    %r9,%rax
  ret
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *my_memstr(const void *buffer, size_t buflen, const char *sub) {
  const unsigned char *buf = buffer;
  const unsigned char *t = (const unsigned char *)buf;
  const unsigned char *s = (const unsigned char *)sub;
  size_t n = buflen;
  for (; n; t++, n--) {
    if (*t == *s) {
      for (buf = t++, buflen = n--, s++; n && *t == *s; t++, s++, n--)
        ;
      if (!*s)
        return (const char *)buf;
      t = (const unsigned char *)buf;
      s = (const unsigned char *)sub;
      n = buflen;
    }
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<M231_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D0
type: string

tool: D17: M231_f(const char *s) is not yet implemented!


tool: D0: %s


assistant: ```c
int M231_f(char *s) {
  debug("M231_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<M231_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
datatype: string
name: disassemble_data
arguments: label: D17
datatype: string

tool: D19: M231_f(const char *s) is not yet implemented!


tool: D17: %s


assistant: ```c
int M231_f(char *s) {
  debug("M231_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<M231_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string
name: parse_data
arguments: label: D17
datatype: string

tool: D7: M231_f(const char *s) is not yet implemented!


tool: D17: %s


assistant: ```c
int M231_f(char *s) {
  debug("M231_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<M231_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string
name: unpack_data
arguments: data_label: D12
datatype: string

tool: D9: M231_f(const char *s) is not yet implemented!


tool: D12: %s


assistant: ```c
int M231_f(char *s) {
  debug("M231_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insertionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L41
L20:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L21
L48:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <trocaAnterior@plt>
  subl   $0x1,-0xc(%rbp)
L21:
  cmpl   $0x0,-0xc(%rbp)
  jle    L3
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L48
L3:
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L20
  nop
  nop
  leave
  ret
```

assistant: ```c
void insertionSort(int *v, int n) {
  int i, j, key;
  for (i = 1; i < n; i++) {
    key = v[i];
    while (i > 0 && v[i - 1] > key) {
      trocaAnterior(v, j);
      --i;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insertionSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L60
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    $0x1,%eax
  jmp    L65
L49:
  add    $0x1,%eax
  cmp    %eax,%r13d
  jle    L29
L65:
  movslq %eax,%rbx
  mov    0x0(%rbp,%rbx,4),%r12d
  test   %eax,%eax
  jle    L49
L64:
  mov    %ebx,%eax
  cmp    %r12d,-0x4(%rbp,%rbx,4)
  jle    L49
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <trocaAnterior@plt>
  lea    -0x1(%rbx),%eax
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L64
  jmp    L49
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  ret
```

assistant: ```c
void insertionSort(int *v, int n) {
  int i, j, key;
  for (i = 1; i < n; i++) {
    key = v[i];
    while (i > 0 && v[i - 1] > key) {
      trocaAnterior(v, j);
      --i;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<insertionSort>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L38
  nopl   (%rax)
L68:
  movslq %r12d,%rbx
  mov    0x0(%rbp,%rbx,4),%r13d
  test   %r12d,%r12d
  jg     L51
  jmp    L36
  nop
L32:
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <trocaAnterior@plt>
  test   %ebx,%ebx
  jle    L10
L51:
  mov    %ebx,%r12d
  cmp    %r13d,-0x4(%rbp,%rbx,4)
  jg     L32
  add    $0x1,%r12d
L10:
  cmp    %r12d,%r14d
  jg     L68
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  add    $0x1,%r12d
  jmp    L68
```

assistant: ```c
void insertionSort(int *v, int n) {
  int i, j, key;
  for (i = 1; i < n; i++) {
    key = v[i];
    while (i > 0 && v[i - 1] > key) {
      trocaAnterior(v, j);
      --i;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insertionSort>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L6
  nopl   (%rax)
L14:
  movslq %r12d,%rbx
  mov    0x0(%rbp,%rbx,4),%r13d
  test   %r12d,%r12d
  jg     L53
  jmp    L4
  nop
L65:
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <trocaAnterior@plt>
  test   %ebx,%ebx
  jle    L21
L53:
  mov    %ebx,%r12d
  cmp    %r13d,-0x4(%rbp,%rbx,4)
  jg     L65
  add    $0x1,%r12d
L21:
  cmp    %r12d,%r14d
  jg     L14
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  add    $0x1,%r12d
  jmp    L14
```

assistant: ```c
void insertionSort(int *v, int n) {
  int i, j, key;
  for (i = 1; i < n; i++) {
    key = v[i];
    while (i > 0 && v[i - 1] > key) {
      trocaAnterior(v, j);
      --i;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<seg_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D21(%rip),%eax
  mov    %eax,-0x4(%rbp)
  mov    D21(%rip),%eax
  add    $0x2,%eax
  mov    %eax,D15(%rip)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t seg_alloc(void) {
  static int32_t next_seg = 0;
  int32_t this_seg = next_seg;
  next_seg += 2;
  return this_seg;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<seg_alloc>:
  endbr64
  mov    D7(%rip),%eax
  lea    0x2(%rax),%edx
  mov    %edx,D10(%rip)
  ret
```

assistant: ```c
int32_t seg_alloc(void) {
  static int32_t next_seg = 0;
  int32_t this_seg = next_seg;
  next_seg += 2;
  return this_seg;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<seg_alloc>:
  endbr64
  mov    D1(%rip),%eax
  lea    0x2(%rax),%edx
  mov    %edx,D5(%rip)
  ret
```

assistant: ```c
int32_t seg_alloc(void) {
  static int32_t next_seg = 0;
  int32_t this_seg = next_seg;
  next_seg += 2;
  return this_seg;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<seg_alloc>:
  endbr64
  mov    D4(%rip),%eax
  lea    0x2(%rax),%edx
  mov    %edx,D12(%rip)
  ret
```

assistant: ```c
int32_t seg_alloc(void) {
  static int32_t next_seg = 0;
  int32_t this_seg = next_seg;
  next_seg += 2;
  return this_seg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<packUART>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x20(%rbp)
  jb     L38
  cmpl   $0x3,-0x20(%rbp)
  ja     L16
L38:
  mov    $0x0,%eax
  jmp    L46
L16:
  movb   $0x0,-0x9(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x10,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movb   $0x2,(%rax)
  movb   $0x12,-0x9(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L21:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x10,%al
  jne    L27
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x10,(%rax)
  addb   $0x10,-0x9(%rbp)
L27:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L21
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x10,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3,(%rax)
  addb   $0x13,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int packUART(const char *packet, unsigned int sizePacket, char *uartBuf, unsigned int sizeUartBuf) {
  if (sizeUartBuf < sizePacket * 2 || sizeUartBuf < 4) {
    return 0;
  } else {
    unsigned char pktChecksum = 0;
    unsigned int i, j;
    uartBuf[0] = 0x10;
    uartBuf[1] = 0x02;
    pktChecksum = 0x10 + 0x02;
    for (i = 2, j = 0; j < sizePacket; i++, j++) {
      uartBuf[i] = packet[j];
      pktChecksum += (unsigned char)packet[j];
      if (packet[j] == 0x10) {
        i++;
        uartBuf[i] = 0x10;
        pktChecksum += 0x10;
      }
    }
    uartBuf[i++] = 0x10;
    uartBuf[i++] = 0x03;
    pktChecksum += (0x10 + 0x03);
    uartBuf[i++] = (char)pktChecksum;
    return i;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<packUART>:
  endbr64
  mov    %rdx,%r8
  lea    (%rsi,%rsi,1),%eax
  cmp    %ecx,%eax
  ja     L57
  cmp    $0x3,%ecx
  ja     L72
L57:
  mov    $0x0,%edx
L43:
  mov    %edx,%eax
  ret
L72:
  movb   $0x10,(%rdx)
  movb   $0x2,0x1(%rdx)
  test   %esi,%esi
  je     L51
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r9
  mov    $0x2,%eax
  mov    $0x12,%esi
  jmp    L70
L76:
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %r9,%rdx
  je     L11
L70:
  movzbl (%rdx),%ecx
  mov    %eax,%edi
  mov    %cl,(%r8,%rdi,1)
  add    %ecx,%esi
  cmp    $0x10,%cl
  jne    L76
  add    $0x1,%eax
  mov    %eax,%ecx
  movb   $0x10,(%r8,%rcx,1)
  add    $0x10,%esi
  jmp    L76
L51:
  mov    $0x2,%eax
  mov    $0x12,%esi
L11:
  mov    %eax,%edx
  movb   $0x10,(%r8,%rdx,1)
  lea    0x1(%rax),%edx
  movb   $0x3,(%r8,%rdx,1)
  lea    0x3(%rax),%edx
  lea    0x2(%rax),%eax
  add    $0x13,%esi
  mov    %sil,(%r8,%rax,1)
  jmp    L43
```

assistant: ```c
unsigned int packUART(const char *packet, unsigned int sizePacket, char *uartBuf, unsigned int sizeUartBuf) {
  if (sizeUartBuf < sizePacket * 2 || sizeUartBuf < 4) {
    return 0;
  } else {
    unsigned char pktChecksum = 0;
    unsigned int i, j;
    uartBuf[0] = 0x10;
    uartBuf[1] = 0x02;
    pktChecksum = 0x10 + 0x02;
    for (i = 2, j = 0; j < sizePacket; i++, j++) {
      uartBuf[i] = packet[j];
      pktChecksum += (unsigned char)packet[j];
      if (packet[j] == 0x10) {
        i++;
        uartBuf[i] = 0x10;
        pktChecksum += 0x10;
      }
    }
    uartBuf[i++] = 0x10;
    uartBuf[i++] = 0x03;
    pktChecksum += (0x10 + 0x03);
    uartBuf[i++] = (char)pktChecksum;
    return i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<packUART>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  mov    %rdx,%r8
  cmp    %ecx,%eax
  ja     L28
  cmp    $0x3,%ecx
  ja     L58
L28:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    $0x210,%eax
  mov    %ax,(%rdx)
  test   %esi,%esi
  je     L32
  lea    -0x1(%rsi),%eax
  mov    $0x2,%ecx
  mov    $0x12,%esi
  lea    0x1(%rdi,%rax,1),%r9
  xchg   %ax,%ax
L42:
  movzbl (%rdi),%edx
  mov    %ecx,%eax
  mov    %dl,(%r8,%rax,1)
  add    %edx,%esi
  mov    %ecx,%eax
  cmp    $0x10,%dl
  jne    L33
  lea    0x1(%rcx),%edx
  add    $0x10,%esi
  movb   $0x10,(%r8,%rdx,1)
  mov    %rdx,%rax
L33:
  add    $0x1,%rdi
  lea    0x1(%rax),%ecx
  cmp    %rdi,%r9
  jne    L42
  lea    0x2(%rax),%edi
  lea    0x3(%rax),%edx
  add    $0x13,%esi
  add    $0x4,%eax
L34:
  movb   $0x10,(%r8,%rcx,1)
  movb   $0x3,(%r8,%rdi,1)
  mov    %sil,(%r8,%rdx,1)
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    $0x5,%eax
  mov    $0x25,%esi
  mov    $0x4,%edx
  mov    $0x3,%edi
  mov    $0x2,%ecx
  jmp    L34
```

assistant: ```c
unsigned int packUART(const char *packet, unsigned int sizePacket, char *uartBuf, unsigned int sizeUartBuf) {
  if (sizeUartBuf < sizePacket * 2 || sizeUartBuf < 4) {
    return 0;
  } else {
    unsigned char pktChecksum = 0;
    unsigned int i, j;
    uartBuf[0] = 0x10;
    uartBuf[1] = 0x02;
    pktChecksum = 0x10 + 0x02;
    for (i = 2, j = 0; j < sizePacket; i++, j++) {
      uartBuf[i] = packet[j];
      pktChecksum += (unsigned char)packet[j];
      if (packet[j] == 0x10) {
        i++;
        uartBuf[i] = 0x10;
        pktChecksum += 0x10;
      }
    }
    uartBuf[i++] = 0x10;
    uartBuf[i++] = 0x03;
    pktChecksum += (0x10 + 0x03);
    uartBuf[i++] = (char)pktChecksum;
    return i;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<packUART>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  mov    %rdx,%r8
  cmp    %ecx,%eax
  ja     L64
  cmp    $0x3,%ecx
  ja     L53
L64:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    $0x210,%eax
  mov    %ax,(%rdx)
  test   %esi,%esi
  je     L14
  lea    -0x1(%rsi),%eax
  mov    $0x12,%ecx
  lea    0x1(%rdi,%rax,1),%r9
  mov    $0x2,%eax
  xchg   %ax,%ax
L41:
  movzbl (%rdi),%edx
  mov    %eax,%esi
  mov    %dl,(%r8,%rsi,1)
  add    %edx,%ecx
  cmp    $0x10,%dl
  je     L24
  add    $0x1,%rdi
  add    $0x1,%eax
  cmp    %rdi,%r9
  jne    L41
L43:
  mov    %eax,%edi
  lea    0x1(%rax),%esi
  lea    0x2(%rax),%edx
  add    $0x13,%ecx
  add    $0x3,%eax
L25:
  movb   $0x10,(%r8,%rdi,1)
  movb   $0x3,(%r8,%rsi,1)
  mov    %cl,(%r8,%rdx,1)
  ret
  nopl   0x0(%rax)
L24:
  lea    0x1(%rax),%edx
  add    $0x1,%rdi
  add    $0x10,%ecx
  add    $0x2,%eax
  movb   $0x10,(%r8,%rdx,1)
  cmp    %r9,%rdi
  jne    L41
  jmp    L43
  nopl   0x0(%rax)
L14:
  mov    $0x5,%eax
  mov    $0x25,%ecx
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x2,%edi
  jmp    L25
```

assistant: ```c
unsigned int packUART(const char *packet, unsigned int sizePacket, char *uartBuf, unsigned int sizeUartBuf) {
  if (sizeUartBuf < sizePacket * 2 || sizeUartBuf < 4) {
    return 0;
  } else {
    unsigned char pktChecksum = 0;
    unsigned int i, j;
    uartBuf[0] = 0x10;
    uartBuf[1] = 0x02;
    pktChecksum = 0x10 + 0x02;
    for (i = 2, j = 0; j < sizePacket; i++, j++) {
      uartBuf[i] = packet[j];
      pktChecksum += (unsigned char)packet[j];
      if (packet[j] == 0x10) {
        i++;
        uartBuf[i] = 0x10;
        pktChecksum += 0x10;
      }
    }
    uartBuf[i++] = 0x10;
    uartBuf[i++] = 0x03;
    pktChecksum += (0x10 + 0x03);
    uartBuf[i++] = (char)pktChecksum;
    return i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_svarint1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x26,%edi
  call   <test_svarint@plt>
  cmp    $0x13,%eax
  je     L9
  lea    D1(%rip),%rax
  jmp    L2
L9:
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string

tool: D1: error, test_svarint1

assistant: ```c
char *test_svarint1() {
  do {
    if (!(test_svarint(0x26) == 19))
      return "error, test_svarint1";
  } while (0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_svarint1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x26,%edi
  call   <test_svarint@plt>
  cmp    $0x13,%eax
  lea    D8(%rip),%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: error, test_svarint1

assistant: ```c
char *test_svarint1() {
  do {
    if (!(test_svarint(0x26) == 19))
      return "error, test_svarint1";
  } while (0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_svarint1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x26,%edi
  call   <test_svarint@plt>
  mov    $0x0,%edx
  cmp    $0x13,%eax
  lea    D1(%rip),%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D1: error, test_svarint1

assistant: ```c
char *test_svarint1() {
  do {
    if (!(test_svarint(0x26) == 19))
      return "error, test_svarint1";
  } while (0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_svarint1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x26,%edi
  call   <test_svarint@plt>
  mov    $0x0,%edx
  cmp    $0x13,%eax
  lea    D6(%rip),%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: error, test_svarint1

assistant: ```c
char *test_svarint1() {
  do {
    if (!(test_svarint(0x26) == 19))
      return "error, test_svarint1";
  } while (0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_bit@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L29
  mov    -0x4(%rbp),%eax
  jmp    L36
L29:
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  mov    -0x20(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L36:
  leave
  ret
```

assistant: ```c
int read_bits(struct bits_reader *bits, int *b, int n) {
  int a = 0;
  for (int i = 0; i < n; ++i) {
    int b = get_bit(bits);
    if (b < 0)
      return b;
    a |= b << i;
  }
  *b = a;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_bits>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r14
  test   %edx,%edx
  jle    L31
  mov    %rdi,%r13
  mov    %edx,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L18:
  mov    %r13,%rdi
  call   <get_bit@plt>
  test   %eax,%eax
  js     L33
  mov    %ebx,%ecx
  shl    %cl,%eax
  or     %eax,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L18
L27:
  mov    %ebp,(%r14)
  mov    $0x0,%eax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  mov    $0x0,%ebp
  jmp    L27
```

assistant: ```c
int read_bits(struct bits_reader *bits, int *b, int n) {
  int a = 0;
  for (int i = 0; i < n; ++i) {
    int b = get_bit(bits);
    if (b < 0)
      return b;
    a |= b << i;
  }
  *b = a;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_bits>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L20
  mov    %rdi,%r12
  mov    %edx,%ebp
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  jmp    L32
  nop
L29:
  mov    %r14d,%ecx
  add    $0x1,%r14d
  shl    %cl,%eax
  or     %eax,%ebx
  cmp    %r14d,%ebp
  je     L3
L32:
  mov    %r12,%rdi
  call   <get_bit@plt>
  test   %eax,%eax
  jns    L29
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  xor    %ebx,%ebx
L3:
  mov    %ebx,0x0(%r13)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int read_bits(struct bits_reader *bits, int *b, int n) {
  int a = 0;
  for (int i = 0; i < n; ++i) {
    int b = get_bit(bits);
    if (b < 0)
      return b;
    a |= b << i;
  }
  *b = a;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_bits>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L11
  mov    %rdi,%r12
  mov    %edx,%ebp
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  jmp    L12
  nop
L4:
  mov    %r14d,%ecx
  add    $0x1,%r14d
  shl    %cl,%eax
  or     %eax,%ebx
  cmp    %r14d,%ebp
  je     L13
L12:
  mov    %r12,%rdi
  call   <get_bit@plt>
  test   %eax,%eax
  jns    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  xor    %ebx,%ebx
L13:
  mov    %ebx,0x0(%r13)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int read_bits(struct bits_reader *bits, int *b, int n) {
  int a = 0;
  for (int i = 0; i < n; ++i) {
    int b = get_bit(bits);
    if (b < 0)
      return b;
    a |= b << i;
  }
  *b = a;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_label>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <uart_get@plt>
  mov    %eax,%edi
  call   <char_to_hex@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <uart_get@plt>
  mov    %eax,%edi
  call   <char_to_hex@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  or     -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint8_t read_label() {
  const uint8_t c1 = char_to_hex(uart_get());
  const uint8_t c2 = char_to_hex(uart_get());
  return ((c1 << 4) | c2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_label>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <uart_get@plt>
  mov    %eax,%edi
  call   <char_to_hex@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <uart_get@plt>
  mov    %eax,%edi
  call   <char_to_hex@plt>
  shl    $0x4,%ebx
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint8_t read_label() {
  const uint8_t c1 = char_to_hex(uart_get());
  const uint8_t c2 = char_to_hex(uart_get());
  return ((c1 << 4) | c2);
}
```