user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<roll_3_xy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x2,%edi
  je     L86
  jg     L107
  test   %edi,%edi
  je     L19
  cmp    $0x1,%edi
  jne    L117
  mov    $0x1,%ebp
  mov    $0x8,%r13d
  jmp    L13
L107:
  mov    $0x1,%ebp
  mov    $0x8,%r14d
  cmp    $0x3,%edi
  je     L178
L117:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L70:
  cmp    $0x7,%ebp
  jg     L117
L182:
  add    $0x1,%ebp
L13:
  lea    -0x1(%rbp),%r12d
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    %r13d,%r8d
  sub    %ebp,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %r12d,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  mov    %ebx,%edi
  call   <delay_ms@plt>
  add    $0x10,%rsp
  cmp    $0x6,%r12d
  jg     L70
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    %r12d,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  jmp    L182
L86:
  mov    $0x1,%ebp
  mov    $0x8,%r13d
  jmp    L23
L98:
  cmp    $0x7,%ebp
  jg     L117
L126:
  add    $0x1,%ebp
L23:
  lea    -0x1(%rbp),%r12d
  mov    %r13d,%edi
  sub    %ebp,%edi
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    $0x7,%r8d
  mov    %r12d,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <box_apeak_xy@plt>
  mov    %ebx,%edi
  call   <delay_ms@plt>
  add    $0x10,%rsp
  cmp    $0x6,%r12d
  jg     L98
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    $0x7,%r8d
  mov    %r12d,%ecx
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  jmp    L126
L88:
  cmp    $0x7,%ebp
  jg     L117
L127:
  add    $0x1,%ebp
L178:
  lea    -0x1(%rbp),%r12d
  mov    %r14d,%r13d
  sub    %ebp,%r13d
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    %r13d,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %r12d,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  mov    %ebx,%edi
  call   <delay_ms@plt>
  add    $0x10,%rsp
  cmp    $0x6,%r12d
  jg     L88
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    %r13d,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  jmp    L127
L19:
  mov    $0x1,%ebp
  mov    $0x8,%r14d
  jmp    L45
L51:
  cmp    $0x7,%ebp
  jg     L117
L92:
  add    $0x1,%ebp
L45:
  lea    -0x1(%rbp),%r12d
  mov    %r14d,%r13d
  sub    %ebp,%r13d
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    $0x7,%r8d
  mov    %r12d,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %r13d,%edi
  call   <box_apeak_xy@plt>
  mov    %ebx,%edi
  call   <delay_ms@plt>
  add    $0x10,%rsp
  cmp    $0x6,%r12d
  jg     L51
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    $0x0,%r8d
  mov    %r13d,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x4,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  jmp    L92
```

assistant: ```c
void roll_3_xy(int n, int delay) {
  int i;
  switch (n) {
  case 1:
    for (i = 0; i < 8; i++) {
      box_apeak_xy(0, i, 0, 7, 7 - i, 7, 1, 1);
      delay_ms(delay);
      if (i < 7)
        box_apeak_xy(3, 3, 0, 0, i, 7, 1, 0);
    };
    break;
  case 2:
    for (i = 0; i < 8; i++) {
      box_apeak_xy(7 - i, 0, 0, i, 7, 7, 1, 1);
      delay_ms(delay);
      if (i < 7)
        box_apeak_xy(3, 4, 0, i, 7, 7, 1, 0);
    };
    break;
  case 3:
    for (i = 0; i < 8; i++) {
      box_apeak_xy(0, i, 0, 7, 7 - i, 7, 1, 1);
      delay_ms(delay);
      if (i < 7)
        box_apeak_xy(4, 4, 0, 7, 7 - i, 7, 1, 0);
    };
    break;
  case 0:
    for (i = 0; i < 8; i++) {
      box_apeak_xy(7 - i, 0, 0, i, 7, 7, 1, 1);
      delay_ms(delay);
      if (i < 7)
        box_apeak_xy(4, 3, 0, 7 - i, 0, 7, 1, 0);
    };
  }
}
```