user: 这段汇编代码用C语言表示是什么样的?

```asm
<floatToChar1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffff81,-0x10(%rbp)
  movl   $0x80,-0xc(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L70
L26:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L90
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
L90:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L70:
  cmpl   $0x8,-0x8(%rbp)
  jle    L26
  cmpl   $0x1,-0x10(%rbp)
  jg     L126
  cmpl   $0xfffffff9,-0x10(%rbp)
  jge    L47
L126:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L16
L47:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L38
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L16
L38:
  movl   $0x60,-0xc(%rbp)
  movl   $0x40,-0x4(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L15
L5:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L5
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  mov    %rdx,%rcx
  shr    $0x20,%rcx
  sar    $0x1f,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x9,-0x8(%rbp)
  jmp    L21
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L122
  mov    -0xc(%rbp),%eax
  add    %eax,-0x4(%rbp)
L122:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L21:
  cmpl   $0xf,-0x8(%rbp)
  jle    L11
  cmpl   $0x0,-0x10(%rbp)
  js     L104
  shll   -0x4(%rbp)
L104:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string
name: disassemble_data
arguments: tag: D20
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: string

tool: D9: Too Large or Small

tool: D20: Negative!

tool: D2: %i


assistant: ```c
int floatToChar1(char *input) {
  int exp = -127, half = 128, i, value = 1;
  for (i = 1; i < 9; i++) {
    if (input[i] & 01) {
      exp += half;
    }
    half /= 2;
  }
  if (exp > 1 || exp < -7) {
    printf("Too Large or Small\n");
    return -1;
  }
  if (input[0] & 1) {
    printf("Negative!\n");
    return -1;
  }
  half = 96;
  value = 64;
  for (i = -1; i > exp; i--) {
    half /= 2;
    value /= 2;
  }
  half = (half - ((half / 6) * 5)) * 2;
  for (i = 9; i < 16; i++) {
    if (input[i] & 1) {
      value += half;
    }
    half /= 2;
  }
  if (exp >= 0) {
    value *= 2;
  }
  printf("%i\n", value);
  return value;
}
```