ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<lt_update_lib_path>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <nonnull@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <nonnull@plt>
  mov    %ebx,%r8d
  lea    D14(%rip),%rdx
  mov    $0x2ac,%esi
  mov    %eax,%ecx
  lea    D4(%rip),%rdi
  call   <lt_debugprintf@plt>
  test   %rbp,%rbp
  je     L5
  cmpb   $0x0,0x0(%rbp)
  je     L5
  test   %r12,%r12
  je     L5
  cmpb   $0x0,(%r12)
  jne    L32
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  mov    %rbp,%rdi
  call   <getenv@plt>
  mov    %r12,%rsi
  xor    %edx,%edx
  mov    %eax,%edi
  call   <lt_extend_str@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <lt_setenv@plt>
  test   %r12,%r12
  je     L5
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D14: (lt_update_lib_path) modifying '%s' by prepending '%s'


tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/filip-be/ImageComparer/refs/heads/master/exiv2/expat/examples/.libs/lt-outline.c

assistant: ```c
void lt_update_lib_path(const char *name, const char *value) {
  lt_debugprintf("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/filip-be/ImageComparer/refs/heads/master/exiv2/expat/examples/.libs/lt-outline.c", 684, "(lt_update_lib_path) modifying '%s' by prepending '%s'\n", nonnull(name), nonnull(value));
  if (name && *name && value && *value) {
    char *new_value = lt_extend_str(getenv(name), value, 0);
    lt_setenv(name, new_value);
    do {
      if (new_value) {
        free((void *)new_value);
        new_value = 0;
      }
    } while (0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fmt_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl -0xc(%rbp),%edx
  mov    %dl,(%rax)
L6:
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
size_t fmt_char(char *out, char c) {
  if (out) {
    *out = c;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fmt_char>:
  endbr64
  test   %rdi,%rdi
  je     L5
  mov    %sil,(%rdi)
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t fmt_char(char *out, char c) {
  if (out) {
    *out = c;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fmt_char>:
  endbr64
  test   %rdi,%rdi
  je     L6
  mov    %sil,(%rdi)
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t fmt_char(char *out, char c) {
  if (out) {
    *out = c;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fmt_char>:
  endbr64
  test   %rdi,%rdi
  je     L6
  mov    %sil,(%rdi)
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t fmt_char(char *out, char c) {
  if (out) {
    *out = c;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dn_skipname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ns_name_skip@plt>
  cmp    $0xffffffff,%eax
  jne    L6
  mov    $0xffffffff,%eax
  jmp    L2
L6:
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  sar    $0x2,%rax
L2:
  leave
  ret
```

assistant: ```c
int dn_skipname(const u_char *ptr, const u_char *eom) {
  const u_char *saveptr = ptr;
  if (ns_name_skip(&ptr, eom) == -1) {
    return -1;
  }
  return ptr - saveptr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dn_skipname>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <ns_name_skip@plt>
  cmp    $0xffffffff,%eax
  je     L8
  mov    0x8(%rsp),%rax
  sub    %rbx,%rax
  sar    $0x2,%rax
L8:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int dn_skipname(const u_char *ptr, const u_char *eom) {
  const u_char *saveptr = ptr;
  if (ns_name_skip(&ptr, eom) == -1) {
    return -1;
  }
  return ptr - saveptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dn_skipname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <ns_name_skip@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    0x8(%rsp),%rax
  sub    %rbx,%rax
  sar    $0x2,%rax
L0:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int dn_skipname(const u_char *ptr, const u_char *eom) {
  const u_char *saveptr = ptr;
  if (ns_name_skip(&ptr, eom) == -1) {
    return -1;
  }
  return ptr - saveptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dn_skipname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <ns_name_skip@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    0x8(%rsp),%rax
  sub    %rbx,%rax
  sar    $0x2,%rax
L3:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int dn_skipname(const u_char *ptr, const u_char *eom) {
  const u_char *saveptr = ptr;
  if (ns_name_skip(&ptr, eom) == -1) {
    return -1;
  }
  return ptr - saveptr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<makeEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L50
L112:
  movl   $0x0,-0x10(%rbp)
  jmp    L99
L117:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L102
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x23,(%rax)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x23,(%rax)
  jmp    L0
L102:
  addl   $0x1,-0x10(%rbp)
L99:
  mov    -0x10(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L117
L0:
  addl   $0x1,-0x14(%rbp)
L50:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L112
  movl   $0x0,-0xc(%rbp)
  jmp    L118
L77:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L110
  addl   $0x1,-0x8(%rbp)
L110:
  addl   $0x1,-0xc(%rbp)
L118:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L77
  movl   $0x0,-0x4(%rbp)
  jmp    L73
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L9
  addl   $0x1,-0x8(%rbp)
L9:
  addl   $0x1,-0x4(%rbp)
L73:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L30
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  sub    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j, k, count, l;
  count = 0;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++) {
      if (s1[i] == s2[j]) {
        s1[i] = '#';
        s2[j] = '#';
        break;
      }
    }
  }
  for (k = 0; k < n1; k++) {
    if (s1[k] == '#')
      count++;
  }
  for (l = 0; l < n2; l++) {
    if (s2[l] == '#')
      count++;
  }
  return (n1 + n2 - count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<makeEqual>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%rbx
  mov    %ecx,%r11d
  test   %esi,%esi
  jle    L3
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r9
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%rsi
  jmp    L58
L73:
  movb   $0x23,0x0(%rbp)
  movb   $0x23,(%rax)
L23:
  add    $0x1,%rdi
  cmp    %r9,%rdi
  je     L27
L58:
  test   %r11d,%r11d
  jle    L23
  mov    %rdi,%rbp
  movzbl (%rdi),%edx
  mov    %rbx,%rax
L100:
  cmp    (%rax),%dl
  je     L73
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L100
  jmp    L23
L27:
  mov    $0x0,%edx
L56:
  cmpb   $0x23,(%r8)
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L56
L32:
  test   %r11d,%r11d
  jle    L38
  mov    %rbx,%rax
  lea    -0x1(%r11),%ecx
  lea    0x1(%rbx,%rcx,1),%rsi
L54:
  cmpb   $0x23,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L54
L38:
  lea    (%r10,%r11,1),%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x0,%edx
  jmp    L32
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j, k, count, l;
  count = 0;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++) {
      if (s1[i] == s2[j]) {
        s1[i] = '#';
        s2[j] = '#';
        break;
      }
    }
  }
  for (k = 0; k < n1; k++) {
    if (s1[k] == '#')
      count++;
  }
  for (l = 0; l < n2; l++) {
    if (s2[l] == '#')
      count++;
  }
  return (n1 + n2 - count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<makeEqual>:
  endbr64
  mov    %esi,%r10d
  mov    %ecx,%r11d
  mov    %rdx,%rsi
  test   %r10d,%r10d
  jle    L63
  lea    -0x1(%r10),%eax
  mov    %rdi,%r8
  lea    0x1(%rdi,%rax,1),%r9
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%rcx
  nopw   0x0(%rax,%rax,1)
L82:
  test   %r11d,%r11d
  jle    L56
  movzbl (%r8),%edx
  mov    %rsi,%rax
  jmp    L43
  xchg   %ax,%ax
L95:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L56
L43:
  cmp    (%rax),%dl
  jne    L95
  movb   $0x23,(%r8)
  movb   $0x23,(%rax)
L56:
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L82
  xor    %edx,%edx
  nop
L4:
  xor    %eax,%eax
  cmpb   $0x23,(%rdi)
  sete   %al
  add    $0x1,%rdi
  add    %eax,%edx
  cmp    %r9,%rdi
  jne    L4
L31:
  test   %r11d,%r11d
  jle    L25
  lea    -0x1(%r11),%ecx
  mov    %rsi,%rax
  lea    0x1(%rsi,%rcx,1),%rsi
  nopl   0x0(%rax)
L9:
  xor    %ecx,%ecx
  cmpb   $0x23,(%rax)
  sete   %cl
  add    $0x1,%rax
  add    %ecx,%edx
  cmp    %rax,%rsi
  jne    L9
L25:
  lea    (%r10,%r11,1),%eax
  sub    %edx,%eax
  ret
L63:
  xor    %edx,%edx
  jmp    L31
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j, k, count, l;
  count = 0;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++) {
      if (s1[i] == s2[j]) {
        s1[i] = '#';
        s2[j] = '#';
        break;
      }
    }
  }
  for (k = 0; k < n1; k++) {
    if (s1[k] == '#')
      count++;
  }
  for (l = 0; l < n2; l++) {
    if (s2[l] == '#')
      count++;
  }
  return (n1 + n2 - count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%ebx
L51:
  movzbl (%rax),%edx
  movsbl %dl,%edx
  cmp    $0x2d,%edx
  je     L87
  cmp    $0x2d,%edx
  jg     L105
  cmp    $0x2b,%edx
  je     L23
  cmp    $0x2b,%edx
  jg     L105
  cmp    $0x9,%edx
  je     L100
  cmp    $0x20,%edx
  jne    L105
  jmp    L100
L87:
  add    $0x1,%ebx
L23:
  add    $0x1,%rax
  jmp    L105
L100:
  nop
  add    $0x1,%rax
  jmp    L51
L105:
  nop
  jmp    L31
L38:
  mov    -0x10(%rbp),%rcx
  mov    %rcx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  add    %rdx,%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  movsbq %dl,%rdx
  add    %rcx,%rdx
  sub    $0x30,%rdx
  mov    %rdx,-0x10(%rbp)
L31:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  jle    L16
  movzbl (%rax),%edx
  cmp    $0x39,%dl
  jle    L38
L16:
  test   %ebx,%ebx
  je     L3
  mov    -0x10(%rbp),%rax
  neg    %rax
  jmp    L62
L3:
  mov    -0x10(%rbp),%rax
L62:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long atol(p)
register char *p;
{
  long n;
  register int f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9')
    n = n * 10 + *p++ - '0';
  return (f ? -n : n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atol>:
  endbr64
L51:
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L45
  jg     L27
  cmp    $0x9,%al
  je     L40
  cmp    $0x20,%al
  jne    L14
L40:
  add    $0x1,%rdi
  jmp    L51
L14:
  mov    $0x0,%esi
  jmp    L109
L27:
  mov    $0x1,%esi
  cmp    $0x2d,%al
  jne    L58
L105:
  add    $0x1,%rdi
L109:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  mov    $0x0,%edx
  cmp    $0x9,%cl
  ja     L86
L68:
  add    $0x1,%rdi
  lea    (%rdx,%rdx,4),%rdx
  movsbq %al,%rax
  lea    -0x30(%rax,%rdx,2),%rdx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L68
L86:
  mov    %rdx,%rax
  neg    %rax
  test   %esi,%esi
  cmovne %rax,%rdx
  mov    %rdx,%rax
  ret
L58:
  mov    $0x0,%esi
  jmp    L109
L45:
  mov    $0x0,%esi
  jmp    L105
```

assistant: ```c
long atol(p)
register char *p;
{
  long n;
  register int f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9')
    n = n * 10 + *p++ - '0';
  return (f ? -n : n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<atol>:
  endbr64
  movsbq (%rdi),%rax
  cmp    $0x2b,%al
  je     L76
L46:
  jg     L70
  cmp    $0x9,%al
  je     L12
  cmp    $0x20,%al
  jne    L43
L12:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
  cmp    $0x2b,%al
  jne    L46
L76:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
L13:
  lea    -0x30(%rax),%edx
  xor    %esi,%esi
  cmp    $0x9,%dl
  ja     L43
L45:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L97:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%rdx
  movsbq (%rdi),%rax
  lea    -0x30(%rdx),%r8
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L97
  mov    $0x30,%eax
  sub    %rdx,%rax
  test   %esi,%esi
  cmovne %rax,%r8
L7:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L70:
  cmp    $0x2d,%al
  jne    L13
  movsbq 0x1(%rdi),%rax
  mov    $0x1,%esi
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L45
L43:
  xor    %r8d,%r8d
  jmp    L7
```

assistant: ```c
long atol(p)
register char *p;
{
  long n;
  register int f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9')
    n = n * 10 + *p++ - '0';
  return (f ? -n : n);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<atol>:
  endbr64
  movsbq (%rdi),%rax
  cmp    $0x2b,%al
  je     L97
L37:
  jg     L57
  cmp    $0x9,%al
  je     L11
  cmp    $0x20,%al
  jne    L2
L11:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
  cmp    $0x2b,%al
  jne    L37
L97:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
L44:
  lea    -0x30(%rax),%edx
  xor    %esi,%esi
  cmp    $0x9,%dl
  ja     L2
L93:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L52:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%rdx
  movsbq (%rdi),%rax
  lea    -0x30(%rdx),%r8
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L52
  mov    $0x30,%eax
  sub    %rdx,%rax
  test   %esi,%esi
  cmovne %rax,%r8
L24:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L57:
  cmp    $0x2d,%al
  jne    L44
  movsbq 0x1(%rdi),%rax
  mov    $0x1,%esi
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L93
L2:
  xor    %r8d,%r8d
  jmp    L24
```

assistant: ```c
long atol(p)
register char *p;
{
  long n;
  register int f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9')
    n = n * 10 + *p++ - '0';
  return (f ? -n : n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D16(%rip),%xmm0
  movss  %xmm0,-0x40(%rbp)
  movss  D79(%rip),%xmm0
  movss  %xmm0,-0x3c(%rbp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  D20(%rip),%xmm0
  movss  %xmm0,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,-0x30(%rbp)
  movss  D6(%rip),%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movss  D35(%rip),%xmm0
  movss  %xmm0,-0x28(%rbp)
  movss  D83(%rip),%xmm0
  movss  %xmm0,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  D33(%rip),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  D4(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movl   $0x6,-0x4c(%rbp)
  movl   $0x2,-0x48(%rbp)
  mov    -0x48(%rbp),%edx
  lea    -0x40(%rbp),%rcx
  mov    -0x4c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <stdlib_strided_sdsnanmeanors@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  movd   %eax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_guessed: f32
name: unpack_data
arguments: data_tag: D79
type_guessed: f32
name: unpack_data
arguments: data_tag: D20
type_guessed: f32
name: unpack_data
arguments: data_tag: D6
type_guessed: f32
name: unpack_data
arguments: data_tag: D35
type_guessed: f32
name: unpack_data
arguments: data_tag: D83
type_guessed: f32
name: unpack_data
arguments: data_tag: D33
type_guessed: f32
name: unpack_data
arguments: data_tag: D4
type_guessed: f32
name: unpack_data
arguments: data_tag: D18
type_guessed: string

tool: D16: 1

tool: D79: 2

tool: D20: 3

tool: D6: 4

tool: D35: 5

tool: D83: 6

tool: D33: 7

tool: D4: 8

tool: D18: mean: %f


assistant: ```c
int main() {
  float x[] = {1.0, 2.0, 0.0 / 0.0, 3.0, 0.0 / 0.0, 4.0, 5.0, 6.0, 0.0 / 0.0, 7.0, 8.0, 0.0 / 0.0};
  int64_t N = 6;
  int64_t stride = 2;
  float v = stdlib_strided_sdsnanmeanors(N, x, stride);
  printf("mean: %f\n", v);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,(%rsp)
  movl   $0x40000000,0x4(%rsp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,0x8(%rsp)
  movl   $0x40400000,0xc(%rsp)
  movss  %xmm0,0x10(%rsp)
  movl   $0x40800000,0x14(%rsp)
  movl   $0x40a00000,0x18(%rsp)
  movl   $0x40c00000,0x1c(%rsp)
  movss  %xmm0,0x20(%rsp)
  movl   $0x40e00000,0x24(%rsp)
  movl   $0x41000000,0x28(%rsp)
  movss  %xmm0,0x2c(%rsp)
  mov    %rsp,%rsi
  mov    $0x2,%edx
  mov    $0x6,%edi
  call   <stdlib_strided_sdsnanmeanors@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: mean: %f


assistant: ```c
int main() {
  float x[] = {1.0, 2.0, 0.0 / 0.0, 3.0, 0.0 / 0.0, 4.0, 5.0, 6.0, 0.0 / 0.0, 7.0, 8.0, 0.0 / 0.0};
  int64_t N = 6;
  int64_t stride = 2;
  float v = stdlib_strided_sdsnanmeanors(N, x, stride);
  printf("mean: %f\n", v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x48,%rsp
  mov    $0x6,%edi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x400000003f800000,%rax
  divss  %xmm0,%xmm0
  mov    %rsp,%rsi
  movl   $0x40400000,0xc(%rsp)
  movl   $0x40800000,0x14(%rsp)
  mov    %rax,(%rsp)
  movabs $0x40c0000040a00000,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4100000040e00000,%rax
  mov    %rax,0x24(%rsp)
  movss  %xmm0,0x8(%rsp)
  movss  %xmm0,0x10(%rsp)
  movss  %xmm0,0x20(%rsp)
  movss  %xmm0,0x2c(%rsp)
  call   <stdlib_strided_sdsnanmeanors@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: mean: %f


assistant: ```c
int main() {
  float x[] = {1.0, 2.0, 0.0 / 0.0, 3.0, 0.0 / 0.0, 4.0, 5.0, 6.0, 0.0 / 0.0, 7.0, 8.0, 0.0 / 0.0};
  int64_t N = 6;
  int64_t stride = 2;
  float v = stdlib_strided_sdsnanmeanors(N, x, stride);
  printf("mean: %f\n", v);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x48,%rsp
  mov    $0x6,%edi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  divss  %xmm0,%xmm0
  mov    D6(%rip),%rax
  mov    %rsp,%rsi
  movl   $0x40400000,0xc(%rsp)
  mov    %rax,(%rsp)
  movabs $0x40c0000040a00000,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4100000040e00000,%rax
  movl   $0x40800000,0x14(%rsp)
  mov    %rax,0x24(%rsp)
  movss  %xmm0,0x8(%rsp)
  movss  %xmm0,0x10(%rsp)
  movss  %xmm0,0x20(%rsp)
  movss  %xmm0,0x2c(%rsp)
  call   <stdlib_strided_sdsnanmeanors@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: f32[2]
name: parse_data
arguments: tag: D10
datatype: string

tool: {"D6": [1.0,2.0]}

tool: D10: mean: %f


assistant: ```c
int main() {
  float x[] = {1.0, 2.0, 0.0 / 0.0, 3.0, 0.0 / 0.0, 4.0, 5.0, 6.0, 0.0 / 0.0, 7.0, 8.0, 0.0 / 0.0};
  int64_t N = 6;
  int64_t stride = 2;
  float v = stdlib_strided_sdsnanmeanors(N, x, stride);
  printf("mean: %f\n", v);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xc8,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo() {
  int b = 100 + 100;
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  mov    $0xc8,%eax
  ret
```

assistant: ```c
int foo() {
  int b = 100 + 100;
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  mov    $0xc8,%eax
  ret
```

assistant: ```c
int foo() {
  int b = 100 + 100;
  return b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  mov    $0xc8,%eax
  ret
```

assistant: ```c
int foo() {
  int b = 100 + 100;
  return b;
}
```