ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<funct_S0_Maj>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%esi
  mov    0x0(%rbp),%edi
  call   <_mm_or_si128@plt>
  mov    (%r12),%esi
  mov    0x0(%rbp),%edi
  mov    %eax,%r15d
  call   <_mm_and_si128@plt>
  mov    (%rbx),%edi
  mov    $0x2,%esi
  mov    %eax,%r13d
  call   <_mm_srli_epi32@plt>
  mov    (%rbx),%edi
  mov    $0x1e,%esi
  mov    %eax,%ebp
  call   <_mm_slli_epi32@plt>
  mov    (%rbx),%edi
  mov    $0xd,%esi
  mov    %eax,%r14d
  call   <_mm_srli_epi32@plt>
  mov    %r14d,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <_mm_xor_si128@plt>
  mov    (%rbx),%edi
  mov    $0x13,%esi
  mov    %eax,%ebp
  call   <_mm_slli_epi32@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <_mm_xor_si128@plt>
  mov    (%rbx),%edi
  mov    $0x16,%esi
  mov    %eax,%ebp
  call   <_mm_srli_epi32@plt>
  mov    %r14d,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <_mm_xor_si128@plt>
  mov    (%rbx),%edi
  mov    $0xa,%esi
  mov    %eax,%ebp
  call   <_mm_slli_epi32@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <_mm_xor_si128@plt>
  mov    (%rbx),%esi
  mov    %r15d,%edi
  mov    %eax,%ebp
  call   <_mm_and_si128@plt>
  mov    %r14d,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <_mm_xor_si128@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <_mm_or_si128@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <_mm_add_epi32@plt>
```

assistant: ```c
__m128i funct_S0_Maj(__m128i *x, __m128i *y, __m128i *z) {
  __m128i _calc_maj1 = _mm_or_si128(*y, *z);
  __m128i _calc_maj2 = _mm_and_si128(*y, *z);
  __m128i rot2 = _mm_srli_epi32(*x, 2);
  __m128i _calc = _mm_slli_epi32(*x, (32 - 2));
  __m128i rot13_22 = _mm_srli_epi32(*x, 13);
  rot2 = _mm_xor_si128(rot2, _calc);
  _calc = _mm_slli_epi32(*x, (32 - 13));
  rot2 = _mm_xor_si128(rot2, rot13_22);
  rot13_22 = _mm_srli_epi32(*x, 22);
  rot2 = _mm_xor_si128(rot2, _calc);
  _calc = _mm_slli_epi32(*x, (32 - 22));
  rot2 = _mm_xor_si128(rot2, rot13_22);
  _calc_maj1 = _mm_and_si128(_calc_maj1, *x);
  rot2 = _mm_xor_si128(rot2, _calc);
  _calc_maj1 = _mm_or_si128(_calc_maj1, _calc_maj2);
  _calc = _mm_add_epi32(_calc_maj1, rot2);
  return _calc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<funct_S0_Maj>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%esi
  mov    0x0(%rbp),%edi
  call   <_mm_or_si128@plt>
  mov    (%r12),%esi
  mov    0x0(%rbp),%edi
  mov    %eax,%r15d
  call   <_mm_and_si128@plt>
  mov    (%rbx),%edi
  mov    $0x2,%esi
  mov    %eax,%r13d
  call   <_mm_srli_epi32@plt>
  mov    (%rbx),%edi
  mov    $0x1e,%esi
  mov    %eax,%ebp
  call   <_mm_slli_epi32@plt>
  mov    (%rbx),%edi
  mov    $0xd,%esi
  mov    %eax,%r14d
  call   <_mm_srli_epi32@plt>
  mov    %r14d,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <_mm_xor_si128@plt>
  mov    (%rbx),%edi
  mov    $0x13,%esi
  mov    %eax,%ebp
  call   <_mm_slli_epi32@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <_mm_xor_si128@plt>
  mov    (%rbx),%edi
  mov    $0x16,%esi
  mov    %eax,%ebp
  call   <_mm_srli_epi32@plt>
  mov    %r14d,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <_mm_xor_si128@plt>
  mov    (%rbx),%edi
  mov    $0xa,%esi
  mov    %eax,%ebp
  call   <_mm_slli_epi32@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <_mm_xor_si128@plt>
  mov    (%rbx),%esi
  mov    %r15d,%edi
  mov    %eax,%ebp
  call   <_mm_and_si128@plt>
  mov    %r14d,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <_mm_xor_si128@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <_mm_or_si128@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <_mm_add_epi32@plt>
```

assistant: ```c
__m128i funct_S0_Maj(__m128i *x, __m128i *y, __m128i *z) {
  __m128i _calc_maj1 = _mm_or_si128(*y, *z);
  __m128i _calc_maj2 = _mm_and_si128(*y, *z);
  __m128i rot2 = _mm_srli_epi32(*x, 2);
  __m128i _calc = _mm_slli_epi32(*x, (32 - 2));
  __m128i rot13_22 = _mm_srli_epi32(*x, 13);
  rot2 = _mm_xor_si128(rot2, _calc);
  _calc = _mm_slli_epi32(*x, (32 - 13));
  rot2 = _mm_xor_si128(rot2, rot13_22);
  rot13_22 = _mm_srli_epi32(*x, 22);
  rot2 = _mm_xor_si128(rot2, _calc);
  _calc = _mm_slli_epi32(*x, (32 - 22));
  rot2 = _mm_xor_si128(rot2, rot13_22);
  _calc_maj1 = _mm_and_si128(_calc_maj1, *x);
  rot2 = _mm_xor_si128(rot2, _calc);
  _calc_maj1 = _mm_or_si128(_calc_maj1, _calc_maj2);
  _calc = _mm_add_epi32(_calc_maj1, rot2);
  return _calc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hermite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L13
  mov    $0x1,%eax
  jmp    L30
L13:
  cmpl   $0x1,-0x14(%rbp)
  jne    L8
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  jmp    L30
L8:
  cmpl   $0x1,-0x14(%rbp)
  jle    L30
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <hermite>
  imul   -0x18(%rbp),%eax
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%r12d
  mov    -0x14(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <hermite>
  mov    %r12d,%edx
  imul   %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    %eax,%eax
  jmp    L30
L30:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int hermite(int n, int x) {
  if (n <= 0)
    return 1;
  if (n == 1)
    return 2 * x;
  if (n >= 2)
    return (2 * x * hermite(n - 1, x)) - (2 * (n - 1) * hermite(n - 2, x));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hermite>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0x1,%edi
  je     L10
  lea    -0x1(%rdi),%r13d
  mov    %r13d,%edi
  call   <hermite>
  imul   %ebp,%eax
  mov    %eax,%r12d
  lea    -0x2(%rbx),%edi
  mov    %ebp,%esi
  call   <hermite>
  imul   %eax,%r13d
  mov    %r12d,%eax
  sub    %r13d,%eax
  add    %eax,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  lea    (%rsi,%rsi,1),%eax
  jmp    L13
L18:
  ret
```

assistant: ```c
int hermite(int n, int x) {
  if (n <= 0)
    return 1;
  if (n == 1)
    return 2 * x;
  if (n >= 2)
    return (2 * x * hermite(n - 1, x)) - (2 * (n - 1) * hermite(n - 2, x));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hermite>:
  endbr64
  test   %edi,%edi
  jle    L45
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L43
  lea    -0x1(%rdi),%r13d
  lea    -0x2(%rdi),%r12d
  mov    $0x1,%ebx
  xor    %r15d,%r15d
  mov    %r13d,%eax
  mov    %r12d,%ebp
  and    $0xfffffffe,%eax
  sub    %eax,%ebp
L34:
  mov    %r13d,%edi
  mov    %r14d,%esi
  call   <hermite>
  mov    %r12d,%edi
  imul   %r14d,%eax
  imul   %ebx,%eax
  imul   %r13d,%ebx
  lea    (%r15,%rax,2),%r15d
  neg    %ebx
  add    %ebx,%ebx
  cmp    %ebp,%r12d
  je     L21
  cmp    $0x1,%r12d
  je     L18
  sub    $0x2,%r12d
  lea    -0x1(%rdi),%r13d
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0x1,%ebx
  xor    %r15d,%r15d
L18:
  imul   %ebx,%r14d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  lea    (%r15,%r14,2),%eax
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x8,%rsp
  lea    (%r15,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int hermite(int n, int x) {
  if (n <= 0)
    return 1;
  if (n == 1)
    return 2 * x;
  if (n >= 2)
    return (2 * x * hermite(n - 1, x)) - (2 * (n - 1) * hermite(n - 2, x));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ltoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0xf,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    D11(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  jmp    L9
L12:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    %ecx,-0x4(%rbp)
  mov    %edx,%ecx
  cltq
  lea    D11(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L9:
  cmpq   $0x0,-0x18(%rbp)
  je     L22
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  lea    D11(%rip),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ltoa(long num) {
  static char buf[16];
  int i = sizeof(buf) - 1;
  buf[i--] = '\0';
  while (num && i >= 0) {
    buf[i--] = num % 10;
    num /= 10;
  };
  return buf + i + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ltoa>:
  endbr64
  mov    %rdi,%rcx
  movb   $0x0,D27(%rip)
  test   %rdi,%rdi
  je     L23
  mov    $0xd,%esi
  lea    D15(%rip),%r9
  movabs $0x6666666666666667,%r8
L0:
  mov    %esi,%edi
  mov    %rcx,%rax
  imul   %r8
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %cl,(%rsi,%r9,1)
  mov    %rdx,%rcx
  test   %rdx,%rdx
  setne  %dl
  mov    %esi,%eax
  not    %eax
  shr    $0x1f,%eax
  sub    $0x1,%rsi
  test   %al,%dl
  jne    L0
L19:
  lea    0x1(%rdi),%eax
  cltq
  lea    D16(%rip),%rdx
  add    %rdx,%rax
  ret
L23:
  mov    $0xe,%edi
  jmp    L19
```

assistant: ```c
char *ltoa(long num) {
  static char buf[16];
  int i = sizeof(buf) - 1;
  buf[i--] = '\0';
  while (num && i >= 0) {
    buf[i--] = num % 10;
    num /= 10;
  };
  return buf + i + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ltoa>:
  endbr64
  movb   $0x0,D24(%rip)
  test   %rdi,%rdi
  je     L1
  lea    D0(%rip),%rsi
  mov    $0xe,%ecx
  movabs $0x6666666666666667,%r9
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %rdi,%rax
  mov    %ecx,%r8d
  sub    $0x1,%rsi
  sub    $0x1,%ecx
  imul   %r9
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rdi
  mov    %dil,0x1(%rsi)
  mov    %rdx,%rdi
  test   %rdx,%rdx
  je     L2
  test   %ecx,%ecx
  jns    L18
L2:
  movslq %r8d,%rax
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  lea    D17(%rip),%rdx
  mov    $0xf,%eax
  add    %rdx,%rax
  ret
```

assistant: ```c
char *ltoa(long num) {
  static char buf[16];
  int i = sizeof(buf) - 1;
  buf[i--] = '\0';
  while (num && i >= 0) {
    buf[i--] = num % 10;
    num /= 10;
  };
  return buf + i + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<internal_exec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int internal_exec(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<internal_exec>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int internal_exec(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<internal_exec>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int internal_exec(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<csapp_execve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execve@plt>
  test   %rax,%rax
  jns    L2
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <unix_error@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D3: execve error

assistant: ```c
void csapp_execve(const char *filename, char *const argv[], char *const envp[]) {
  if (execve(filename, argv, envp) < 0)
    unix_error("execve error");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<csapp_execve>:
  endbr64
  sub    $0x8,%rsp
  call   <execve@plt>
  test   %rax,%rax
  js     L1
L16:
  add    $0x8,%rsp
  ret
L1:
  lea    D0(%rip),%rdi
  call   <unix_error@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: execve error

assistant: ```c
void csapp_execve(const char *filename, char *const argv[], char *const envp[]) {
  if (execve(filename, argv, envp) < 0)
    unix_error("execve error");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<csapp_execve>:
  endbr64
  sub    $0x8,%rsp
  call   <execve@plt>
  test   %rax,%rax
  js     L0
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <unix_error@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string

tool: D8: execve error

assistant: ```c
void csapp_execve(const char *filename, char *const argv[], char *const envp[]) {
  if (execve(filename, argv, envp) < 0)
    unix_error("execve error");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<csapp_execve>:
  endbr64
  sub    $0x8,%rsp
  call   <execve@plt>
  test   %rax,%rax
  js     L6
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <unix_error@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: execve error

assistant: ```c
void csapp_execve(const char *filename, char *const argv[], char *const envp[]) {
  if (execve(filename, argv, envp) < 0)
    unix_error("execve error");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcmp_comma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L42
L3:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L42:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L56
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L56
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L3
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L50
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
L50:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L89
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
L89:
  mov    $0x0,%eax
  jmp    L82
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L82:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp_comma(const char *s1, const char *s2) {
  while (*s1 && (*s1 == *s2) && *s1 != ',')
    s1++, s2++;
  if ((*s1 == ',' || *s1 == '\0') && (*s2 == ',' || *s2 == '\0'))
    return 0;
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp_comma>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L43
L37:
  cmp    %al,(%rsi)
  jne    L28
  cmp    $0x2c,%al
  je     L28
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L37
L43:
  mov    $0x0,%eax
L3:
  movzbl (%rsi),%edx
  cmp    $0x2c,%dl
  je     L56
  test   %dl,%dl
  jne    L2
L56:
  mov    $0x0,%eax
  ret
L28:
  cmp    $0x2c,%al
  je     L3
  test   %al,%al
  je     L3
L2:
  movzbl %al,%eax
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp_comma(const char *s1, const char *s2) {
  while (*s1 && (*s1 == *s2) && *s1 != ',')
    s1++, s2++;
  if ((*s1 == ',' || *s1 == '\0') && (*s2 == ',' || *s2 == '\0'))
    return 0;
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp_comma>:
  endbr64
  jmp    L44
  cs nopw 0x0(%rax,%rax,1)
L10:
  cmp    %al,(%rsi)
  jne    L16
  cmp    $0x2c,%al
  je     L12
  add    $0x1,%rdi
  add    $0x1,%rsi
L44:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
L45:
  movzbl (%rsi),%edx
  cmp    $0x2c,%dl
  je     L12
  test   %dl,%dl
  jne    L46
L12:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  cmp    $0x2c,%al
  je     L45
L46:
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp_comma(const char *s1, const char *s2) {
  while (*s1 && (*s1 == *s2) && *s1 != ',')
    s1++, s2++;
  if ((*s1 == ',' || *s1 == '\0') && (*s2 == ',' || *s2 == '\0'))
    return 0;
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcmp_comma>:
  endbr64
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L6:
  cmp    %al,(%rsi)
  jne    L18
  cmp    $0x2c,%al
  je     L67
  add    $0x1,%rdi
  add    $0x1,%rsi
L8:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
L21:
  movzbl (%rsi),%edx
  cmp    $0x2c,%dl
  je     L67
  test   %dl,%dl
  jne    L52
L67:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  cmp    $0x2c,%al
  je     L21
L52:
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp_comma(const char *s1, const char *s2) {
  while (*s1 && (*s1 == *s2) && *s1 != ',')
    s1++, s2++;
  if ((*s1 == ',' || *s1 == '\0') && (*s2 == ',' || *s2 == '\0'))
    return 0;
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x50(%rbp)
  jmp    L10
L2:
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x54(%rbp),%rdx
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L62:
  cmp    %rdx,%rsp
  je     L1
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L62
L1:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L45
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L45:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L38
L42:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L38:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L42
  mov    -0x54(%rbp),%edx
  mov    -0x58(%rbp),%ecx
  mov    -0x40(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <get_min_time@plt>
  mov    %rbx,%rsp
  addl   $0x1,-0x50(%rbp)
L10:
  mov    -0x5c(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jle    L2
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D20
type: string

tool: D4: %d

tool: D20: %d %d

assistant: ```c
int main() {
  int cases;
  scanf("%d", &cases);
  for (int i = 1; i <= cases; ++i) {
    int len, mark;
    scanf("%d %d", &len, &mark);
    int arr[len];
    for (int pos = 0; pos < len; ++pos)
      scanf("%d", &arr[pos]);
    get_min_time(arr, len, mark);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x44(%rbp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x44(%rbp)
  jle    L40
  mov    $0x1,%r14d
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  lea    D21(%rip),%r13
  jmp    L15
L69:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L37
  orq    $0x0,-0x8(%rsp,%rax,1)
L37:
  mov    %rsp,%r15
  test   %esi,%esi
  jle    L19
  mov    %r15,%r12
  mov    $0x0,%ebx
L39:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x40(%rbp),%esi
  add    $0x4,%r12
  cmp    %ebx,%esi
  jg     L39
L19:
  mov    -0x3c(%rbp),%edx
  mov    %r15,%rdi
  call   <get_min_time@plt>
  mov    -0x58(%rbp),%rsp
  add    $0x1,%r14d
  cmp    %r14d,-0x44(%rbp)
  jl     L40
L15:
  mov    %rsp,-0x58(%rbp)
  mov    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%esi
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L43:
  cmp    %rdx,%rsp
  je     L69
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L43
L40:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D16
datatype: string

tool: D21: %d

tool: D16: %d %d

assistant: ```c
int main() {
  int cases;
  scanf("%d", &cases);
  for (int i = 1; i <= cases; ++i) {
    int len, mark;
    scanf("%d %d", &len, &mark);
    int arr[len];
    for (int pos = 0; pos < len; ++pos)
      scanf("%d", &arr[pos]);
    get_min_time(arr, len, mark);
  }
  return 0;
}
```