ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_int>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  test   %rdi,%rdi
  setne  %dil
  mov    %rdx,0x18(%rsp)
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  test   %rbp,%rbp
  je     L72
  mov    $0x1,%r12d
  mov    $0x1,%r8d
  xor    %r14d,%r14d
  movq   $0x0,0x8(%rsp)
  movsbl -0x1(%rbx,%r12,1),%r15d
  lea    -0x1(%r12),%r13
  test   %r8b,%r8b
  jne    L55
L85:
  mov    %r15d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L16
  sub    $0x30,%r15d
  xor    %edi,%edi
  cmp    $0x9,%r15d
  setle  %dil
  call   <assert@plt>
  mov    %r15d,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    D9(%rip),%rax
  movslq (%rax),%rax
  mov    %rax,%rsi
  imul   $0x66666667,%rax,%rax
  mov    %esi,%edx
  mov    %esi,%edi
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  cmp    %r14d,%eax
  jge    L49
L22:
  mov    %esi,%eax
  lea    (%rdi,%r15,1),%edx
  sub    %r15d,%eax
  cmp    %edi,%eax
  cmovg  %edx,%esi
  addq   $0x1,0x8(%rsp)
  xor    %r8d,%r8d
  mov    %esi,%r14d
L40:
  lea    0x1(%r12),%rax
  cmp    %rbp,%r12
  jae    L102
  mov    %rax,%r12
  movsbl -0x1(%rbx,%r12,1),%r15d
  lea    -0x1(%r12),%r13
  test   %r8b,%r8b
  je     L85
L55:
  mov    %r15d,%edi
  mov    %r8b,0x16(%rsp)
  mov    %r15b,0x17(%rsp)
  call   <isdigit@plt>
  movzbl 0x16(%rsp),%r8d
  movzbl 0x17(%rsp),%esi
  test   %rax,%rax
  jne    L85
  cmp    $0x20,%sil
  je     L40
L72:
  xor    %r13d,%r13d
L99:
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  lea    (%r14,%r14,4),%edi
  add    %edi,%edi
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L102:
  mov    %r12,%r13
L16:
  cmpq   $0x0,0x8(%rsp)
  je     L72
  mov    0x18(%rsp),%rax
  mov    %r14d,(%rax)
  jmp    L99
```

assistant: ```c
size_t read_int(const char *text, size_t lim, int *result) {
  assert(text != NULL);
  assert(result != NULL);
  size_t chars_read = 0;
  size_t digits_read = 0;
  int tmp_res = 0;
  char no_digit_yet = 1;
  for (size_t i = 0; i < lim; ++i) {
    char c = text[i];
    no_digit_yet = no_digit_yet && !isdigit(c);
    if (no_digit_yet) {
      if (c == ' ') {
        ++chars_read;
        continue;
      } else {
        return 0;
      }
    } else {
      if (isdigit(c)) {
        int digit = c - '0';
        assert(digit < 10);
        assert(digit >= 0);
        if (tmp_res <= INT_MAX / 10) {
          tmp_res *= 10;
        } else {
          tmp_res = INT_MAX;
        }
        if (tmp_res < INT_MAX - digit) {
          tmp_res += digit;
        } else {
          tmp_res = INT_MAX;
        }
        ++chars_read;
        ++digits_read;
      } else {
        break;
      }
    }
  }
  if (digits_read > 0) {
    *result = tmp_res;
    return chars_read;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_int>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  test   %rdi,%rdi
  setne  %dil
  mov    %rdx,0x18(%rsp)
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  test   %rbp,%rbp
  je     L37
  mov    $0x1,%r12d
  mov    $0x1,%r8d
  xor    %r14d,%r14d
  movq   $0x0,0x8(%rsp)
  movsbl -0x1(%rbx,%r12,1),%r15d
  lea    -0x1(%r12),%r13
  test   %r8b,%r8b
  jne    L62
L107:
  mov    %r15d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L75
  sub    $0x30,%r15d
  xor    %edi,%edi
  cmp    $0x9,%r15d
  setle  %dil
  call   <assert@plt>
  mov    %r15d,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    D8(%rip),%rax
  movslq (%rax),%rax
  mov    %rax,%rsi
  imul   $0x66666667,%rax,%rax
  mov    %esi,%edx
  mov    %esi,%edi
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  cmp    %r14d,%eax
  jge    L2
L3:
  mov    %esi,%eax
  lea    (%rdi,%r15,1),%edx
  sub    %r15d,%eax
  cmp    %edi,%eax
  cmovg  %edx,%esi
  addq   $0x1,0x8(%rsp)
  xor    %r8d,%r8d
  mov    %esi,%r14d
L57:
  lea    0x1(%r12),%rax
  cmp    %rbp,%r12
  jae    L74
  mov    %rax,%r12
  movsbl -0x1(%rbx,%r12,1),%r15d
  lea    -0x1(%r12),%r13
  test   %r8b,%r8b
  je     L107
L62:
  mov    %r15d,%edi
  mov    %r8b,0x16(%rsp)
  mov    %r15b,0x17(%rsp)
  call   <isdigit@plt>
  movzbl 0x16(%rsp),%r8d
  movzbl 0x17(%rsp),%esi
  test   %rax,%rax
  jne    L107
  cmp    $0x20,%sil
  je     L57
L37:
  xor    %r13d,%r13d
L16:
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    (%r14,%r14,4),%edi
  add    %edi,%edi
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L74:
  mov    %r12,%r13
L75:
  cmpq   $0x0,0x8(%rsp)
  je     L37
  mov    0x18(%rsp),%rax
  mov    %r14d,(%rax)
  jmp    L16
```

assistant: ```c
size_t read_int(const char *text, size_t lim, int *result) {
  assert(text != NULL);
  assert(result != NULL);
  size_t chars_read = 0;
  size_t digits_read = 0;
  int tmp_res = 0;
  char no_digit_yet = 1;
  for (size_t i = 0; i < lim; ++i) {
    char c = text[i];
    no_digit_yet = no_digit_yet && !isdigit(c);
    if (no_digit_yet) {
      if (c == ' ') {
        ++chars_read;
        continue;
      } else {
        return 0;
      }
    } else {
      if (isdigit(c)) {
        int digit = c - '0';
        assert(digit < 10);
        assert(digit >= 0);
        if (tmp_res <= INT_MAX / 10) {
          tmp_res *= 10;
        } else {
          tmp_res = INT_MAX;
        }
        if (tmp_res < INT_MAX - digit) {
          tmp_res += digit;
        } else {
          tmp_res = INT_MAX;
        }
        ++chars_read;
        ++digits_read;
      } else {
        break;
      }
    }
  }
  if (digits_read > 0) {
    *result = tmp_res;
    return chars_read;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scope_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <scope_alloc@plt>
  mov    $0x0,%eax
  call   <scope_return@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x14,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void scope_test(void) {
  scope_alloc();
  int ret = scope_return();
  assert(ret == 20);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scope_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <scope_alloc@plt>
  mov    $0x0,%eax
  call   <scope_return@plt>
  cmp    $0x14,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void scope_test(void) {
  scope_alloc();
  int ret = scope_return();
  assert(ret == 20);
}
```
user: What is the c source code of the assembly code below?

```asm
<scope_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <scope_alloc@plt>
  xor    %eax,%eax
  call   <scope_return@plt>
  xor    %edi,%edi
  cmp    $0x14,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1070 <assert@plt>
```

assistant: ```c
void scope_test(void) {
  scope_alloc();
  int ret = scope_return();
  assert(ret == 20);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scope_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <scope_alloc@plt>
  xor    %eax,%eax
  call   <scope_return@plt>
  xor    %edi,%edi
  cmp    $0x14,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1070 <assert@plt>
```

assistant: ```c
void scope_test(void) {
  scope_alloc();
  int ret = scope_return();
  assert(ret == 20);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmp_char_lt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jge    L35
  mov    $0xffffffff,%eax
  jmp    L24
L35:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jle    L38
  mov    $0x1,%eax
  jmp    L24
L38:
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_char_lt(const void *a, const void *b) {
  char a_ = *(char *)a;
  char b_ = *(char *)b;
  if (a_ < b_)
    return -1;
  if (a_ > b_)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmp_char_lt>:
  endbr64
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dl,%cl
  jl     L8
  setg   %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int cmp_char_lt(const void *a, const void *b) {
  char a_ = *(char *)a;
  char b_ = *(char *)b;
  if (a_ < b_)
    return -1;
  if (a_ > b_)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmp_char_lt>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int cmp_char_lt(const void *a, const void *b) {
  char a_ = *(char *)a;
  char b_ = *(char *)b;
  if (a_ < b_)
    return -1;
  if (a_ > b_)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmp_char_lt>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int cmp_char_lt(const void *a, const void *b) {
  char a_ = *(char *)a;
  char b_ = *(char *)b;
  if (a_ < b_)
    return -1;
  if (a_ > b_)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rcx
  add    $0x136ff696,%rcx
  mov    %rcx,%rdx
  rol    $0x20,%rdx
  mov    %rcx,%rax
  shr    $0x38,%rax
  shl    $0x30,%rax
  movabs $0xff00ffffffffffff,%rdi
  and    %rdi,%rdx
  or     %rax,%rdx
  mov    %ecx,%eax
  shl    $0x8,%eax
  sar    $0x18,%eax
  movzbl %al,%eax
  shl    $0x18,%rax
  movabs $0xffffffff00ffffff,%rdi
  and    %rdi,%rdx
  or     %rdx,%rax
  shl    $0x8,%edx
  sar    $0x18,%edx
  movzbl %cl,%ecx
  shl    $0x10,%rcx
  and    $0xffffffffff00ffff,%rax
  or     %rcx,%rax
  movzbl %dl,%edx
  shl    $0x20,%rdx
  movabs $0xffffff00ffffffff,%rcx
  and    %rcx,%rax
  or     %rdx,%rax
  sub    $0x537663c7,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned int copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned int *)(&state[local2]) + 1);
        *((unsigned int *)(&state[local2]) + 1) = *((unsigned int *)(&state[local2]) + 0);
        *((unsigned int *)(&state[local2]) + 0) = copy11;
        copy12 = *((char *)(&state[local2]) + 6);
        *((char *)(&state[local2]) + 6) = *((char *)(&state[local2]) + 3);
        *((char *)(&state[local2]) + 3) = copy12;
        copy12 = *((char *)(&state[local2]) + 2);
        *((char *)(&state[local2]) + 2) = *((char *)(&state[local2]) + 4);
        *((char *)(&state[local2]) + 4) = copy12;
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 736209367UL) - 2136477086UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  movabs $0xff00ffffffffffff,%rdi
  add    $0x136ff696,%rdx
  mov    %rdx,%rax
  mov    %rdx,%rcx
  rol    $0x20,%rax
  shr    $0x38,%rcx
  shl    $0x30,%rcx
  and    %rdi,%rax
  movabs $0xffffffff00ffffff,%rdi
  or     %rcx,%rax
  mov    %rdx,%rcx
  shl    $0x8,%rcx
  and    %rdi,%rax
  and    $0xff000000,%ecx
  or     %rcx,%rax
  movzbl %dl,%ecx
  shl    $0x8,%rdx
  shl    $0x10,%rcx
  and    $0xffffffffff00ffff,%rax
  shr    $0x38,%rdx
  or     %rcx,%rax
  shl    $0x20,%rdx
  movabs $0xffffff00ffffffff,%rcx
  and    %rcx,%rax
  or     %rdx,%rax
  sub    $0x537663c7,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned int copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned int *)(&state[local2]) + 1);
        *((unsigned int *)(&state[local2]) + 1) = *((unsigned int *)(&state[local2]) + 0);
        *((unsigned int *)(&state[local2]) + 0) = copy11;
        copy12 = *((char *)(&state[local2]) + 6);
        *((char *)(&state[local2]) + 6) = *((char *)(&state[local2]) + 3);
        *((char *)(&state[local2]) + 3) = copy12;
        copy12 = *((char *)(&state[local2]) + 2);
        *((char *)(&state[local2]) + 2) = *((char *)(&state[local2]) + 4);
        *((char *)(&state[local2]) + 4) = copy12;
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 736209367UL) - 2136477086UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movabs $0xff00ffffffffffff,%rax
  push   %rbx
  mov    (%rdi),%rdx
  add    $0x136ff696,%rdx
  movq   %rdx,%xmm1
  mov    %rdx,%rcx
  mov    %edx,%ebx
  shr    $0x38,%rcx
  pshufd $0xe1,%xmm1,%xmm0
  shl    $0x8,%ebx
  shl    $0x30,%rcx
  movq   %xmm0,%rdi
  sar    $0x18,%ebx
  and    %rdi,%rax
  movabs $0xffffffff0000ffff,%rdi
  or     %rcx,%rax
  xor    %ecx,%ecx
  mov    %dl,%cl
  and    %rdi,%rax
  shl    $0x8,%rdx
  mov    %bl,%ch
  shr    $0x38,%rdx
  pop    %rbx
  movzwl %cx,%ecx
  shl    $0x20,%rdx
  shl    $0x10,%rcx
  or     %rcx,%rax
  movabs $0xffffff00ffffffff,%rcx
  and    %rcx,%rax
  or     %rdx,%rax
  sub    $0x537663c7,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned int copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned int *)(&state[local2]) + 1);
        *((unsigned int *)(&state[local2]) + 1) = *((unsigned int *)(&state[local2]) + 0);
        *((unsigned int *)(&state[local2]) + 0) = copy11;
        copy12 = *((char *)(&state[local2]) + 6);
        *((char *)(&state[local2]) + 6) = *((char *)(&state[local2]) + 3);
        *((char *)(&state[local2]) + 3) = copy12;
        copy12 = *((char *)(&state[local2]) + 2);
        *((char *)(&state[local2]) + 2) = *((char *)(&state[local2]) + 4);
        *((char *)(&state[local2]) + 4) = copy12;
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 736209367UL) - 2136477086UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<process_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L47:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L24
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L20
L24:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jl     L47
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int process_string(char *string) {
  char *iter = string;
  int i = 0;
  int count = 0;
  iter = string + 1;
  while (i < strlen(string)) {
    if ((*iter != '\0') && string[i] == *iter) {
      count++;
      iter++;
    } else {
      i = (iter - string);
      iter++;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<process_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    0x2(%rdi),%rbx
  mov    $0x0,%r14d
  mov    $0x0,%r12d
  jmp    L8
L36:
  mov    %r13d,%r12d
  sub    %ebp,%r12d
L49:
  add    $0x1,%rbx
L8:
  lea    -0x1(%rbx),%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L41
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L36
  movslq %r12d,%rdx
  cmp    0x0(%rbp,%rdx,1),%al
  jne    L36
  add    $0x1,%r14d
  jmp    L49
L41:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int process_string(char *string) {
  char *iter = string;
  int i = 0;
  int count = 0;
  iter = string + 1;
  while (i < strlen(string)) {
    if ((*iter != '\0') && string[i] == *iter) {
      count++;
      iter++;
    } else {
      i = (iter - string);
      iter++;
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<process_string>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  jmp    L11
  nopl   (%rax)
L10:
  mov    %ebx,%r12d
  sub    %ebp,%r12d
L19:
  mov    %rdx,%rbx
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L20
  movzbl (%rbx),%eax
  lea    0x1(%rbx),%rdx
  test   %al,%al
  je     L10
  movslq %r12d,%rcx
  cmp    0x0(%rbp,%rcx,1),%al
  jne    L10
  add    $0x1,%r13d
  jmp    L19
L20:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int process_string(char *string) {
  char *iter = string;
  int i = 0;
  int count = 0;
  iter = string + 1;
  while (i < strlen(string)) {
    if ((*iter != '\0') && string[i] == *iter) {
      count++;
      iter++;
    } else {
      i = (iter - string);
      iter++;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<process_string>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  jmp    L7
  nopl   (%rax)
L6:
  mov    %ebx,%r12d
  sub    %ebp,%r12d
L19:
  mov    %rdx,%rbx
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L28
  movzbl (%rbx),%eax
  lea    0x1(%rbx),%rdx
  test   %al,%al
  je     L6
  movslq %r12d,%rcx
  cmp    0x0(%rbp,%rcx,1),%al
  jne    L6
  add    $0x1,%r13d
  jmp    L19
L28:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int process_string(char *string) {
  char *iter = string;
  int i = 0;
  int count = 0;
  iter = string + 1;
  while (i < strlen(string)) {
    if ((*iter != '\0') && string[i] == *iter) {
      count++;
      iter++;
    } else {
      i = (iter - string);
      iter++;
    }
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_get_snb_gt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <gen_is_snb@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  and    $0x30,%eax
  test   %eax,%eax
  je     L10
  mov    $0x2,%eax
  jmp    L18
L10:
  mov    $0x1,%eax
L18:
  leave
  ret
```

assistant: ```c
int gen_get_snb_gt(int devid) {
  assert(gen_is_snb(devid));
  return (devid & 0x30) ? 2 : 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_get_snb_gt>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <gen_is_snb@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %ebx,%eax
  and    $0x30,%eax
  cmp    $0x1,%eax
  mov    $0x1,%eax
  sbb    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int gen_get_snb_gt(int devid) {
  assert(gen_is_snb(devid));
  return (devid & 0x30) ? 2 : 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_get_snb_gt>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <gen_is_snb@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %ebx,%eax
  pop    %rbx
  and    $0x30,%eax
  cmp    $0x1,%eax
  mov    $0x1,%eax
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int gen_get_snb_gt(int devid) {
  assert(gen_is_snb(devid));
  return (devid & 0x30) ? 2 : 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_getblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x10,-0x40(%rbp)
  je     L1
  mov    -0x40(%rbp),%rax
  cltq
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <verbose@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L1:
  movl   $0x0,-0x24(%rbp)
  jmp    L37
L9:
  mov    -0x38(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <char2int@plt>
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x20(%rbp,%rdx,8)
  addl   $0x1,-0x24(%rbp)
  addq   $0x8,-0x38(%rbp)
L37:
  cmpl   $0x1,-0x24(%rbp)
  jle    L9
  mov    -0x20(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <verbose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D6: parse_getblock: bad message size %d


tool: D4: parse_getblock: pos=%lld len=%lld


assistant: ```c
int parse_getblock(char *msgbuf, size_t msglen, off_t *pos, off_t *len) {
  off_t par[2];
  int i;
  if (msglen != sizeof(par)) {
    verbose(0, "parse_getblock: bad message size %d\n", (int)msglen);
    exit(1);
  }
  for (i = 0; i < 2; i++, msgbuf += sizeof(par[0])) {
    par[i] = char2int(msgbuf, sizeof(par[0]));
  }
  *pos = par[0];
  *len = par[1];
  verbose(1, "parse_getblock: pos=%lld len=%lld\n", (long long)par[0], (long long)par[1]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_getblock>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  cmp    $0x10,%rsi
  jne    L7
L10:
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <char2int@plt>
  mov    %rax,%rbp
  lea    0x8(%rbx),%rdi
  mov    $0x8,%esi
  call   <char2int@plt>
  mov    %rax,%rcx
  mov    %rbp,0x0(%r13)
  mov    %rax,(%r12)
  mov    %rbp,%rdx
  lea    D17(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <verbose@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  movslq %esi,%rdx
  lea    D0(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <verbose@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_guessed: string
name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D17: parse_getblock: pos=%lld len=%lld


tool: D0: parse_getblock: bad message size %d


assistant: ```c
int parse_getblock(char *msgbuf, size_t msglen, off_t *pos, off_t *len) {
  off_t par[2];
  int i;
  if (msglen != sizeof(par)) {
    verbose(0, "parse_getblock: bad message size %d\n", (int)msglen);
    exit(1);
  }
  for (i = 0; i < 2; i++, msgbuf += sizeof(par[0])) {
    par[i] = char2int(msgbuf, sizeof(par[0]));
  }
  *pos = par[0];
  *len = par[1];
  verbose(1, "parse_getblock: pos=%lld len=%lld\n", (long long)par[0], (long long)par[1]);
  return 0;
}
```