ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmd_ends_with_space>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L17
L26:
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L0
L49:
  cmp    $0x5c,%dl
  je     L44
  add    $0x1,%rdi
  mov    %eax,%edx
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  jne    L49
L0:
  xor    %eax,%eax
  cmp    $0x20,%dl
  sete   %al
  ret
  nop
L44:
  movzbl 0x2(%rdi),%edx
  add    $0x2,%rdi
  test   %dl,%dl
  jne    L26
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmd_ends_with_space(const char *cmd) {
  while (cmd[0] != '\0' && cmd[1] != '\0') {
    if (cmd[0] == '\\')
      cmd++;
    cmd++;
  }
  return cmd[0] == ' ';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vdie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vwarn@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void vdie(const char *format, va_list alist) {
  vwarn(format, alist);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vdie>:
  endbr64
  sub    $0x8,%rsp
  call   <vwarn@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void vdie(const char *format, va_list alist) {
  vwarn(format, alist);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<vdie>:
  endbr64
  sub    $0x8,%rsp
  call   <vwarn@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void vdie(const char *format, va_list alist) {
  vwarn(format, alist);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vdie>:
  endbr64
  sub    $0x8,%rsp
  call   <vwarn@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void vdie(const char *format, va_list alist) {
  vwarn(format, alist);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<time_ticks_passed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <time_reference_ticks@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jbe    L19
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  jmp    L3
L19:
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
L3:
  leave
  ret
```

assistant: ```c
unsigned int time_ticks_passed(unsigned int reference) {
  unsigned int now = time_reference_ticks();
  if (now > reference)
    return now - reference;
  return (unsigned int)(reference - now);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<time_ticks_passed>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <time_reference_ticks@plt>
  mov    %eax,%ecx
  sub    %ebx,%ecx
  mov    %ebx,%edx
  sub    %eax,%edx
  cmp    %ebx,%eax
  mov    %ecx,%eax
  cmovbe %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int time_ticks_passed(unsigned int reference) {
  unsigned int now = time_reference_ticks();
  if (now > reference)
    return now - reference;
  return (unsigned int)(reference - now);
}
```
user: Translate the below assembly code into C programming language:

```asm
<time_ticks_passed>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <time_reference_ticks@plt>
  mov    %ebx,%edx
  mov    %eax,%ecx
  sub    %eax,%edx
  sub    %ebx,%ecx
  cmp    %ebx,%eax
  pop    %rbx
  mov    %ecx,%eax
  cmovbe %edx,%eax
  ret
```

assistant: ```c
unsigned int time_ticks_passed(unsigned int reference) {
  unsigned int now = time_reference_ticks();
  if (now > reference)
    return now - reference;
  return (unsigned int)(reference - now);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<time_ticks_passed>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <time_reference_ticks@plt>
  mov    %ebx,%edx
  mov    %eax,%ecx
  sub    %eax,%edx
  sub    %ebx,%ecx
  cmp    %ebx,%eax
  pop    %rbx
  mov    %ecx,%eax
  cmovbe %edx,%eax
  ret
```

assistant: ```c
unsigned int time_ticks_passed(unsigned int reference) {
  unsigned int now = time_reference_ticks();
  if (now > reference)
    return now - reference;
  return (unsigned int)(reference - now);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  cmpl   $0x0,-0xc(%rbp)
  jne    L37
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L37
  cmpl   $0x0,-0x4(%rbp)
  jns    L43
L37:
  mov    $0x0,%eax
  jmp    L41
L34:
  subl   $0x1,-0x8(%rbp)
  addl   $0x2,-0xc(%rbp)
L43:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L34
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,%edx
  setge  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
L41:
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  int k;
  int n;
  if (!(i == 0 && k == n && n >= 0))
    return 0;
  while (i < n) {
    k--;
    i += 2;
  }
  assert(2 * k >= n - 1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  cmp    $0xffffffff,%eax
  setge  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  int k;
  int n;
  if (!(i == 0 && k == n && n >= 0))
    return 0;
  while (i < n) {
    k--;
    i += 2;
  }
  assert(2 * k >= n - 1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  sub    $0x8,%rsp
  test   %eax,%eax
  jle    L14
  or     $0xffffffff,%eax
  mov    $0x80000000,%edx
L3:
  add    %edx,%edx
  xor    %edi,%edi
  cmp    %eax,%edx
  setge  %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
L14:
  xor    %edx,%edx
  or     $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int main() {
  int i;
  int k;
  int n;
  if (!(i == 0 && k == n && n >= 0))
    return 0;
  while (i < n) {
    k--;
    i += 2;
  }
  assert(2 * k >= n - 1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  sub    $0x8,%rsp
  test   %eax,%eax
  jle    L12
  or     $0xffffffff,%eax
  mov    $0x80000000,%edx
L2:
  add    %edx,%edx
  xor    %edi,%edi
  cmp    %eax,%edx
  setge  %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
L12:
  xor    %edx,%edx
  or     $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int main() {
  int i;
  int k;
  int n;
  if (!(i == 0 && k == n && n >= 0))
    return 0;
  while (i < n) {
    k--;
    i += 2;
  }
  assert(2 * k >= n - 1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xfffffc18,-0x4(%rbp)
  jmp    L14
L3:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x3e8,-0x4(%rbp)
  jle    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void test() {
  int i;
  for (i = -1000; i <= 1000; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %rbx
  mov    $0xfffffc18,%ebx
L5:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    $0x3e9,%ebx
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void test() {
  int i;
  for (i = -1000; i <= 1000; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  push   %rbx
  mov    $0xfffffc18,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    $0x3e9,%ebx
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
void test() {
  int i;
  for (i = -1000; i <= 1000; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<test>:
  endbr64
  push   %rbx
  mov    $0xfffffc18,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    $0x3e9,%ebx
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void test() {
  int i;
  for (i = -1000; i <= 1000; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm2
  ucomisd %xmm0,%xmm2
  jp     L20
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm3
  ucomisd %xmm0,%xmm3
  jne    L20
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  jmp    L4
L20:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rbx
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
L4:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double cot(double n) {
  if (sin(n) == 0) {
    return 0. / 0.;
  }
  return cos(n) / sin(n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cot>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  ucomisd D8(%rip),%xmm1
  jp     L5
  je     L28
L5:
  divsd  %xmm1,%xmm0
L14:
  add    $0x18,%rsp
  ret
L28:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  jmp    L14
```

tool_calls: name: read_data
arguments: data_label: D8
type: f64

tool: D8: 0

assistant: ```c
double cot(double n) {
  if (sin(n) == 0) {
    return 0. / 0.;
  }
  return cos(n) / sin(n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cot>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm0
  ucomisd %xmm1,%xmm2
  jp     L1
  je     L4
L1:
  divsd  %xmm2,%xmm0
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L4:
  divsd  %xmm1,%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double cot(double n) {
  if (sin(n) == 0) {
    return 0. / 0.;
  }
  return cos(n) / sin(n);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cot>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm0
  ucomisd %xmm1,%xmm2
  jp     L5
  je     L7
L5:
  divsd  %xmm2,%xmm0
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L7:
  divsd  %xmm1,%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double cot(double n) {
  if (sin(n) == 0) {
    return 0. / 0.;
  }
  return cos(n) / sin(n);
}
```
user: What is the c source code of the assembly code below?

```asm
<powmodp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0xffffffc5,%eax
  jbe    L7
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  cmp    $0xffffffffffffffc5,%rcx
  setae  %al
  movzbl %al,%edx
  mov    %rdx,%rax
  mov    %rdx,%rsi
  shl    $0x4,%rsi
  sub    %rsi,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,-0x4(%rbp)
L7:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow_mod_p@plt>
  leave
  ret
```

assistant: ```c
uint64_t powmodp(uint64_t a, uint64_t b) {
  if (a > 0xffffffffffffffc5ull)
    a %= 0xffffffffffffffc5ull;
  return pow_mod_p(a, b);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<powmodp>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffc5,%edi
  jbe    L0
  movslq %edi,%rdi
  cmp    $0xffffffffffffffc5,%rdi
  setae  %al
  movzbl %al,%eax
  mov    %rax,%rcx
  shl    $0x4,%rcx
  mov    %rax,%rdx
  sub    %rcx,%rdx
  lea    (%rax,%rdx,4),%rax
  sub    %eax,%edi
L0:
  call   <pow_mod_p@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint64_t powmodp(uint64_t a, uint64_t b) {
  if (a > 0xffffffffffffffc5ull)
    a %= 0xffffffffffffffc5ull;
  return pow_mod_p(a, b);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<powmodp>:
  endbr64
  cmp    $0xffffffc5,%edi
  jbe    L9
  movslq %edi,%rdi
  xor    %eax,%eax
  cmp    $0xffffffffffffffc5,%rdi
  setae  %al
  mov    %rax,%rcx
  mov    %rax,%rdx
  shl    $0x4,%rcx
  sub    %rcx,%rdx
  lea    (%rax,%rdx,4),%rax
  sub    %eax,%edi
L9:
  jmp    1050 <pow_mod_p@plt>
```

assistant: ```c
uint64_t powmodp(uint64_t a, uint64_t b) {
  if (a > 0xffffffffffffffc5ull)
    a %= 0xffffffffffffffc5ull;
  return pow_mod_p(a, b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<powmodp>:
  endbr64
  cmp    $0xffffffc5,%edi
  jbe    L3
  movslq %edi,%rdi
  xor    %eax,%eax
  cmp    $0xffffffffffffffc5,%rdi
  setae  %al
  mov    %rax,%rcx
  mov    %rax,%rdx
  shl    $0x4,%rcx
  sub    %rcx,%rdx
  lea    (%rax,%rdx,4),%rax
  sub    %eax,%edi
L3:
  jmp    1050 <pow_mod_p@plt>
```

assistant: ```c
uint64_t powmodp(uint64_t a, uint64_t b) {
  if (a > 0xffffffffffffffc5ull)
    a %= 0xffffffffffffffc5ull;
  return pow_mod_p(a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L29
L24:
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L38:
  movl   $0x0,-0x8(%rbp)
  jmp    L73
L75:
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L55:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  mov    -0x40(%rbp),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L55
  addl   $0x1,-0x8(%rbp)
L73:
  mov    -0x8(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L75
  mov    -0x38(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  imul   -0x40(%rbp),%eax
  mov    %eax,%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L38
  mov    -0x38(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  imul   -0x40(%rbp),%eax
  sub    -0x40(%rbp),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transpose(char *a, char *b, int ho, int hi, int w, int c) {
  int idx = 0;
  for (int i = 0; i < ho; i++) {
    for (int l = 0; l < c; l++) {
      for (int j = 0; j < hi; j++) {
        for (int k = 0; k < w; k++) {
          *b++ = a[idx];
          idx += c;
        }
      }
      idx += 1 - hi * w * c;
    }
    idx += hi * w * c - c;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transpose>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,-0x4(%rsp)
  test   %edx,%edx
  jle    L74
  mov    %rdi,%rbx
  mov    %rsi,%rax
  mov    %ecx,%r10d
  mov    %r8d,%ebp
  mov    %ecx,%edx
  imul   %r8d,%edx
  imul   %r9d,%edx
  mov    $0x1,%r14d
  sub    %edx,%r14d
  sub    %r9d,%edx
  mov    %edx,-0x8(%rsp)
  lea    -0x1(%r8),%edx
  mov    %edx,%r12d
  imul   %r9d,%r12d
  mov    $0x0,%r15d
  mov    $0x0,%edi
  movslq %r9d,%rsi
  mov    %edx,%edx
  lea    0x1(%rdx),%r11
  jmp    L34
L80:
  mov    %edi,-0xc(%rsp)
L99:
  add    $0x1,%rax
  movzbl (%rdx),%edi
  mov    %dil,-0x1(%rax)
  add    %rsi,%rdx
  cmp    %rcx,%rax
  jne    L99
  mov    -0xc(%rsp),%edi
  add    %r9d,%edi
  add    %r12d,%edi
  mov    %rcx,%rax
L57:
  add    $0x1,%r8d
  cmp    %r8d,%r10d
  je     L113
L7:
  movslq %edi,%rdx
  add    %rbx,%rdx
  lea    (%rax,%r11,1),%rcx
  test   %ebp,%ebp
  jg     L80
  jmp    L57
L113:
  add    %r14d,%edi
  add    $0x1,%r13d
  cmp    %r13d,%r9d
  je     L55
L39:
  mov    $0x0,%r8d
  test   %r10d,%r10d
  jg     L7
  jmp    L113
L55:
  add    -0x8(%rsp),%edi
  add    $0x1,%r15d
  cmp    %r15d,-0x4(%rsp)
  je     L74
L34:
  mov    $0x0,%r13d
  test   %r9d,%r9d
  jg     L39
  jmp    L55
L74:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void transpose(char *a, char *b, int ho, int hi, int w, int c) {
  int idx = 0;
  for (int i = 0; i < ho; i++) {
    for (int l = 0; l < c; l++) {
      for (int j = 0; j < hi; j++) {
        for (int k = 0; k < w; k++) {
          *b++ = a[idx];
          idx += c;
        }
      }
      idx += 1 - hi * w * c;
    }
    idx += hi * w * c - c;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transpose>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,-0x4(%rsp)
  test   %edx,%edx
  jle    L35
  mov    %ecx,%edx
  mov    $0x1,%r14d
  mov    %rdi,%rbx
  mov    %rsi,%rax
  imul   %r8d,%edx
  mov    %ecx,%r10d
  mov    %r8d,%ebp
  xor    %r15d,%r15d
  xor    %edi,%edi
  movslq %r9d,%rsi
  imul   %r9d,%edx
  sub    %edx,%r14d
  sub    %r9d,%edx
  mov    %edx,-0x8(%rsp)
  lea    -0x1(%r8),%edx
  mov    %edx,%r12d
  lea    0x1(%rdx),%r11
  imul   %r9d,%r12d
L29:
  xor    %r13d,%r13d
  test   %r9d,%r9d
  jle    L57
  nop
L20:
  xor    %r8d,%r8d
  test   %r10d,%r10d
  jle    L53
  nopl   0x0(%rax,%rax,1)
L77:
  movslq %edi,%rdx
  lea    (%rax,%r11,1),%rcx
  add    %rbx,%rdx
  test   %ebp,%ebp
  jle    L31
  mov    %edi,-0xc(%rsp)
  nopw   0x0(%rax,%rax,1)
L64:
  movzbl (%rdx),%edi
  add    $0x1,%rax
  add    %rsi,%rdx
  mov    %dil,-0x1(%rax)
  cmp    %rax,%rcx
  jne    L64
  mov    -0xc(%rsp),%edi
  add    %r9d,%edi
  add    %r12d,%edi
L31:
  add    $0x1,%r8d
  cmp    %r8d,%r10d
  jne    L77
L53:
  add    $0x1,%r13d
  add    %r14d,%edi
  cmp    %r13d,%r9d
  jne    L20
L57:
  add    -0x8(%rsp),%edi
  add    $0x1,%r15d
  cmp    %r15d,-0x4(%rsp)
  jne    L29
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void transpose(char *a, char *b, int ho, int hi, int w, int c) {
  int idx = 0;
  for (int i = 0; i < ho; i++) {
    for (int l = 0; l < c; l++) {
      for (int j = 0; j < hi; j++) {
        for (int k = 0; k < w; k++) {
          *b++ = a[idx];
          idx += c;
        }
      }
      idx += 1 - hi * w * c;
    }
    idx += hi * w * c - c;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_ncpu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_ncpu() {
  int ncpu = -1;
  return ncpu;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_ncpu>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_ncpu() {
  int ncpu = -1;
  return ncpu;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_ncpu>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_ncpu() {
  int ncpu = -1;
  return ncpu;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_ncpu>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_ncpu() {
  int ncpu = -1;
  return ncpu;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipv6_prefix_to_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x80,-0x24(%rbp)
  jbe    L7
  mov    $0xffffffff,%eax
  jmp    L52
L7:
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L58
L64:
  cmpl   $0x7,-0x18(%rbp)
  jle    L34
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0xff,(%rax)
  jmp    L53
L34:
  mov    $0x8,%eax
  sub    -0x18(%rbp),%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
L53:
  subl   $0x8,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L58:
  cmpl   $0x0,-0x18(%rbp)
  jg     L64
  lea    -0x10(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L52:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
int ipv6_prefix_to_mask(unsigned prefix, struct in6_addr *mask) {
  struct in6_addr in6;
  int i, j;
  if (prefix > 128)
    return -1;
  memset(&in6, 0x0, sizeof(in6));
  for (i = prefix, j = 0; i > 0; i -= 8, j++) {
    if (i >= 8) {
      in6.s6_addr[j] = 0xff;
    } else {
      in6.s6_addr[j] = (unsigned long)(0xffU << (8 - i));
    }
  }
  memcpy(mask, &in6, sizeof(*mask));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ipv6_prefix_to_mask>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x80,%edi
  ja     L41
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsp,%rdi
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %ebp,%eax
  test   %ebp,%ebp
  jle    L1
  mov    %ebp,%edi
  and    $0x7,%edi
  lea    -0x8(%rbp),%esi
  sub    $0x1,%ebp
  and    $0xfffffff8,%ebp
  sub    %ebp,%esi
  mov    $0x0,%edx
  jmp    L25
L58:
  mov    (%rsp),%rcx
  movl   $0xff,(%rcx,%rdx,4)
  sub    $0x8,%eax
  add    $0x1,%rdx
  cmp    %esi,%eax
  je     L1
L25:
  cmp    %eax,%edi
  jne    L58
  movslq %edx,%rdx
  mov    $0x8,%ecx
  sub    %eax,%ecx
  mov    $0xff,%eax
  shl    %cl,%eax
  mov    (%rsp),%rcx
  mov    %eax,(%rcx,%rdx,4)
L1:
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L41:
  mov    $0xffffffff,%eax
  jmp    L16
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipv6_prefix_to_mask(unsigned prefix, struct in6_addr *mask) {
  struct in6_addr in6;
  int i, j;
  if (prefix > 128)
    return -1;
  memset(&in6, 0x0, sizeof(in6));
  for (i = prefix, j = 0; i > 0; i -= 8, j++) {
    if (i >= 8) {
      in6.s6_addr[j] = 0xff;
    } else {
      in6.s6_addr[j] = (unsigned long)(0xffU << (8 - i));
    }
  }
  memcpy(mask, &in6, sizeof(*mask));
  return 0;
}
```