ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<downSamp>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%r10d
  test   %edx,%edx
  jle    L24
  mov    %r8d,%edi
  sub    %r8d,%r10d
  neg    %edi
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L29
  movsd  (%rsi),%xmm0
  cltq
  movsd  %xmm0,(%r9,%rax,8)
L29:
  add    $0x1,%edi
  add    $0x8,%rsi
  cmp    %r10d,%edi
  jne    L11
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int downSamp(double *y, double *x, int len_in, int rate, int offset) {
  int len_out = (len_in - offset) / rate;
  int i;
  for (i = 0; i < len_in; i++) {
    if ((i - offset) % rate == 0)
      y[(i - offset) / rate] = x[i];
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<downSamp>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%r10d
  test   %edx,%edx
  jle    L26
  mov    %r8d,%edi
  sub    %r8d,%r10d
  neg    %edi
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L2
  movsd  (%rsi),%xmm0
  cltq
  movsd  %xmm0,(%r9,%rax,8)
L2:
  add    $0x1,%edi
  add    $0x8,%rsi
  cmp    %r10d,%edi
  jne    L3
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int downSamp(double *y, double *x, int len_in, int rate, int offset) {
  int len_out = (len_in - offset) / rate;
  int i;
  for (i = 0; i < len_in; i++) {
    if ((i - offset) % rate == 0)
      y[(i - offset) / rate] = x[i];
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fgetl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
L21:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L13
  cmpl   $0xa,-0xc(%rbp)
  je     L43
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L43
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x14(%rbp)
L13:
  cmpl   $0xa,-0xc(%rbp)
  jne    L22
  addl   $0x1,-0x10(%rbp)
L22:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L21
L43:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *fgetl(FILE *f, int index, int taille_max) {
  int car;
  int i = 0;
  char *ligne = malloc(sizeof(char) * taille_max);
  int nb_lignes = 1;
  do {
    car = fgetc(f);
    if (nb_lignes == index) {
      if ((car != 10) && (i < (taille_max - 1))) {
        ligne[i] = car;
        i++;
      } else {
        break;
      }
    }
    if (car == 10) {
      nb_lignes++;
    }
  } while (car != EOF);
  ligne[i] = '\0';
  return ligne;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fgetl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%r14d
  mov    %edx,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    $0x1,%ebx
  mov    $0x0,%ebp
  sub    $0x1,%r14d
  jmp    L48
L29:
  cmp    $0xa,%eax
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%ebx
L5:
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L33
L48:
  mov    %r13,%rdi
  call   <fgetc@plt>
  cmp    %r12d,%ebx
  jne    L29
  cmp    $0xa,%eax
  je     L33
  cmp    %ebp,%r14d
  jle    L33
  movslq %ebp,%rdx
  mov    %al,(%r15,%rdx,1)
  add    $0x1,%ebp
  jmp    L5
L33:
  movslq %ebp,%rbp
  movb   $0x0,(%r15,%rbp,1)
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *fgetl(FILE *f, int index, int taille_max) {
  int car;
  int i = 0;
  char *ligne = malloc(sizeof(char) * taille_max);
  int nb_lignes = 1;
  do {
    car = fgetc(f);
    if (nb_lignes == index) {
      if ((car != 10) && (i < (taille_max - 1))) {
        ligne[i] = car;
        i++;
      } else {
        break;
      }
    }
    if (car == 10) {
      nb_lignes++;
    }
  } while (car != EOF);
  ligne[i] = '\0';
  return ligne;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fgetl>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  mov    %edx,%edi
  sub    $0x1,%r14d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %edx,%edx
  cmp    $0xa,%eax
  sete   %dl
  add    %edx,%ebx
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L15
L51:
  mov    %r13,%rdi
  call   <fgetc@plt>
  cmp    %r12d,%ebx
  jne    L32
  cmp    $0xa,%eax
  je     L15
  cmp    %ebp,%r14d
  jle    L15
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %al,(%r15,%rdx,1)
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L51
L15:
  movslq %ebp,%rbp
  mov    %r15,%rax
  movb   $0x0,(%r15,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *fgetl(FILE *f, int index, int taille_max) {
  int car;
  int i = 0;
  char *ligne = malloc(sizeof(char) * taille_max);
  int nb_lignes = 1;
  do {
    car = fgetc(f);
    if (nb_lignes == index) {
      if ((car != 10) && (i < (taille_max - 1))) {
        ligne[i] = car;
        i++;
      } else {
        break;
      }
    }
    if (car == 10) {
      nb_lignes++;
    }
  } while (car != EOF);
  ligne[i] = '\0';
  return ligne;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fgetl>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    %r12d,%ebx
  je     L47
  xor    %edx,%edx
  cmp    $0xa,%eax
  sete   %dl
  add    %edx,%ebx
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L38
L32:
  xor    %r12d,%r12d
L20:
  movslq %r12d,%r12
  mov    %r13,%rax
  movb   $0x0,0x0(%r13,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  cmp    $0xa,%eax
  je     L32
  cmp    $0x1,%r14d
  jle    L32
  mov    D7(%rip),%rbx
  mov    %al,0x0(%r13)
  cmp    (%rbx),%eax
  jne    1080 <fgetl.cold>
  mov    $0x1,%r12d
  jmp    L20
```

assistant: ```c
char *fgetl(FILE *f, int index, int taille_max) {
  int car;
  int i = 0;
  char *ligne = malloc(sizeof(char) * taille_max);
  int nb_lignes = 1;
  do {
    car = fgetc(f);
    if (nb_lignes == index) {
      if ((car != 10) && (i < (taille_max - 1))) {
        ligne[i] = car;
        i++;
      } else {
        break;
      }
    }
    if (car == 10) {
      nb_lignes++;
    }
  } while (car != EOF);
  ligne[i] = '\0';
  return ligne;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L6:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(char *c) {
  int x = 0;
  while (*(c + x))
    x++;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L5
  mov    $0x1,%eax
L21:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L21
L6:
  mov    %edx,%eax
  ret
L5:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int strlen(char *c) {
  int x = 0;
  while (*(c + x))
    x++;
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  mov    $0x1,%eax
  xchg   %ax,%ax
L18:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L18
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char *c) {
  int x = 0;
  while (*(c + x))
    x++;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  mov    $0x1,%eax
  xchg   %ax,%ax
L2:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L2
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char *c) {
  int x = 0;
  while (*(c + x))
    x++;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D130(%rip),%rax
  mov    %rax,-0xa0(%rbp)
  lea    D140(%rip),%rax
  mov    %rax,-0x98(%rbp)
  lea    D125(%rip),%rax
  mov    %rax,-0x90(%rbp)
  lea    D84(%rip),%rax
  mov    %rax,-0x88(%rbp)
  lea    D130(%rip),%rax
  mov    %rax,-0x80(%rbp)
  lea    D140(%rip),%rax
  mov    %rax,-0x78(%rbp)
  lea    D125(%rip),%rax
  mov    %rax,-0x70(%rbp)
  lea    D84(%rip),%rax
  mov    %rax,-0x68(%rbp)
  movl   $0x4,-0xa4(%rbp)
  mov    $0x8,%edx
  mov    $0x20,%esi
  lea    D107(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xa8(%rbp)
  movl   $0x0,-0xa8(%rbp)
  jmp    L0
L5:
  mov    -0xa8(%rbp),%eax
  cltq
  mov    -0x80(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0xa8(%rbp)
L0:
  mov    -0xa8(%rbp),%eax
  cmp    -0xa4(%rbp),%eax
  jl     L5
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    D130(%rip),%rax
  mov    %rax,-0x60(%rbp)
  lea    D140(%rip),%rax
  mov    %rax,-0x58(%rbp)
  lea    D125(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D84(%rip),%rax
  mov    %rax,-0x48(%rbp)
  mov    $0x8,%edx
  mov    $0x50,%esi
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D141(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D130
type: string
name: retrieve_data
arguments: data_tag: D140
type: string
name: retrieve_data
arguments: data_tag: D125
type: string
name: retrieve_data
arguments: data_tag: D84
type: string
name: retrieve_data
arguments: data_tag: D107
type: string
name: retrieve_data
arguments: data_tag: D92
type: string
name: retrieve_data
arguments: data_tag: D141
type: string

tool: D130: 111111111

tool: D140: 000000000

tool: D125: bbbbbbbbb

tool: D84: aaaaaaaaa

tool: D107: sizeof(p) = %d, sizeof(p[0]) = %d


tool: D92: sizeof(q) = %d, sizeof(q[0]) = %d


tool: D141: pause

assistant: ```c
int main01(void) {
  char *p0 = "111111111";
  char *p1 = "000000000";
  char *p2 = "bbbbbbbbb";
  char *p3 = "aaaaaaaaa";
  char *p[] = {"111111111", "000000000", "bbbbbbbbb", "aaaaaaaaa"};
  int n = sizeof(p) / sizeof(p[0]);
  printf("sizeof(p) = %d, sizeof(p[0]) = %d\n", sizeof(p), sizeof(p[0]));
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%s\n", p[i]);
  }
  char *q[10] = {"111111111", "000000000", "bbbbbbbbb", "aaaaaaaaa"};
  printf("sizeof(q) = %d, sizeof(q[0]) = %d\n", sizeof(q), sizeof(q[0]));
  printf("\n");
  system("pause");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main01>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D40(%rip),%rax
  mov    %rax,(%rsp)
  lea    D32(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D15(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D19(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x8,%edx
  mov    $0x20,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x20(%rsp),%rbp
L11:
  mov    (%rbx),%rdi
  call   <puts@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L11
  mov    $0x8,%edx
  mov    $0x50,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D47(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D40
datatype: string
name: parse_data
arguments: data_label: D32
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D19
datatype: string
name: parse_data
arguments: data_label: D11
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D47
datatype: string

tool: D40: 111111111

tool: D32: 000000000

tool: D15: bbbbbbbbb

tool: D19: aaaaaaaaa

tool: D11: sizeof(p) = %d, sizeof(p[0]) = %d


tool: D6: sizeof(q) = %d, sizeof(q[0]) = %d


tool: D47: pause

assistant: ```c
int main01(void) {
  char *p0 = "111111111";
  char *p1 = "000000000";
  char *p2 = "bbbbbbbbb";
  char *p3 = "aaaaaaaaa";
  char *p[] = {"111111111", "000000000", "bbbbbbbbb", "aaaaaaaaa"};
  int n = sizeof(p) / sizeof(p[0]);
  printf("sizeof(p) = %d, sizeof(p[0]) = %d\n", sizeof(p), sizeof(p[0]));
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%s\n", p[i]);
  }
  char *q[10] = {"111111111", "000000000", "bbbbbbbbb", "aaaaaaaaa"};
  printf("sizeof(q) = %d, sizeof(q[0]) = %d\n", sizeof(q), sizeof(q[0]));
  printf("\n");
  system("pause");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main01>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edx
  mov    $0x20,%esi
  xor    %eax,%eax
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  mov    $0x8,%edx
  mov    $0x50,%esi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D60(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D41
datatype: string
name: parse_data
arguments: data_tag: D12
datatype: string
name: parse_data
arguments: data_tag: D20
datatype: string
name: parse_data
arguments: data_tag: D34
datatype: string
name: parse_data
arguments: data_tag: D63
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D60
datatype: string

tool: D41: sizeof(p) = %d, sizeof(p[0]) = %d


tool: D12: 111111111

tool: D20: 000000000

tool: D34: bbbbbbbbb

tool: D63: aaaaaaaaa

tool: D19: sizeof(q) = %d, sizeof(q[0]) = %d


tool: D60: pause

assistant: ```c
int main01(void) {
  char *p0 = "111111111";
  char *p1 = "000000000";
  char *p2 = "bbbbbbbbb";
  char *p3 = "aaaaaaaaa";
  char *p[] = {"111111111", "000000000", "bbbbbbbbb", "aaaaaaaaa"};
  int n = sizeof(p) / sizeof(p[0]);
  printf("sizeof(p) = %d, sizeof(p[0]) = %d\n", sizeof(p), sizeof(p[0]));
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%s\n", p[i]);
  }
  char *q[10] = {"111111111", "000000000", "bbbbbbbbb", "aaaaaaaaa"};
  printf("sizeof(q) = %d, sizeof(q[0]) = %d\n", sizeof(q), sizeof(q[0]));
  printf("\n");
  system("pause");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main01>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rcx
  lea    D27(%rip),%rdx
  mov    $0x20,%esi
  push   %rbx
  movq   %rcx,%xmm0
  lea    D53(%rip),%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D68(%rip),%rax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%rbp
  movq   %rax,%xmm1
  lea    D22(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movq   %rdx,%xmm0
  mov    $0x8,%edx
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L0
  mov    $0x8,%edx
  mov    $0x50,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D50(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D49
data_type: string
name: read_data
arguments: data_label: D27
data_type: string
name: read_data
arguments: data_label: D53
data_type: string
name: read_data
arguments: data_label: D68
data_type: string
name: read_data
arguments: data_label: D22
data_type: string
name: read_data
arguments: data_label: D20
data_type: string
name: read_data
arguments: data_label: D50
data_type: string

tool: D49: 111111111

tool: D27: bbbbbbbbb

tool: D53: sizeof(p) = %d, sizeof(p[0]) = %d


tool: D68: 000000000

tool: D22: aaaaaaaaa

tool: D20: sizeof(q) = %d, sizeof(q[0]) = %d


tool: D50: pause

assistant: ```c
int main01(void) {
  char *p0 = "111111111";
  char *p1 = "000000000";
  char *p2 = "bbbbbbbbb";
  char *p3 = "aaaaaaaaa";
  char *p[] = {"111111111", "000000000", "bbbbbbbbb", "aaaaaaaaa"};
  int n = sizeof(p) / sizeof(p[0]);
  printf("sizeof(p) = %d, sizeof(p[0]) = %d\n", sizeof(p), sizeof(p[0]));
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%s\n", p[i]);
  }
  char *q[10] = {"111111111", "000000000", "bbbbbbbbb", "aaaaaaaaa"};
  printf("sizeof(q) = %d, sizeof(q[0]) = %d\n", sizeof(q), sizeof(q[0]));
  printf("\n");
  system("pause");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lvar_rec_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <n_at_rec@plt>
  mov    %eax,%edi
  call   <assert_corr@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <iam_leaf_is_locked@plt>
  mov    %eax,%edi
  call   <assert_corr@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__lvar_rec_set@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <n_invariant@plt>
  mov    %eax,%edi
  call   <assert_inv@plt>
  nop
  leave
  ret
```

assistant: ```c
void lvar_rec_set(struct iam_leaf *l, const struct iam_rec *r) {
  assert_corr(n_at_rec(l));
  assert_corr(iam_leaf_is_locked(l));
  __lvar_rec_set(l, r);
  assert_inv(n_invariant(l));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lvar_rec_set>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <n_at_rec@plt>
  mov    %eax,%edi
  call   <assert_corr@plt>
  mov    %rbx,%rdi
  call   <iam_leaf_is_locked@plt>
  mov    %eax,%edi
  call   <assert_corr@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__lvar_rec_set@plt>
  mov    %rbx,%rdi
  call   <n_invariant@plt>
  mov    %eax,%edi
  call   <assert_inv@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lvar_rec_set(struct iam_leaf *l, const struct iam_rec *r) {
  assert_corr(n_at_rec(l));
  assert_corr(iam_leaf_is_locked(l));
  __lvar_rec_set(l, r);
  assert_inv(n_invariant(l));
}
```
user: Translate the below assembly code into C programming language:

```asm
<lvar_rec_set>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <n_at_rec@plt>
  mov    %eax,%edi
  call   <assert_corr@plt>
  mov    %rbp,%rdi
  call   <iam_leaf_is_locked@plt>
  mov    %eax,%edi
  call   <assert_corr@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__lvar_rec_set@plt>
  mov    %rbp,%rdi
  call   <n_invariant@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    10f0 <assert_inv@plt>
```

assistant: ```c
void lvar_rec_set(struct iam_leaf *l, const struct iam_rec *r) {
  assert_corr(n_at_rec(l));
  assert_corr(iam_leaf_is_locked(l));
  __lvar_rec_set(l, r);
  assert_inv(n_invariant(l));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lvar_rec_set>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <n_at_rec@plt>
  mov    %eax,%edi
  call   <assert_corr@plt>
  mov    %rbp,%rdi
  call   <iam_leaf_is_locked@plt>
  mov    %eax,%edi
  call   <assert_corr@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__lvar_rec_set@plt>
  mov    %rbp,%rdi
  call   <n_invariant@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    10f0 <assert_inv@plt>
```

assistant: ```c
void lvar_rec_set(struct iam_leaf *l, const struct iam_rec *r) {
  assert_corr(n_at_rec(l));
  assert_corr(iam_leaf_is_locked(l));
  __lvar_rec_set(l, r);
  assert_inv(n_invariant(l));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  call   <issetugid@plt>
  test   %rax,%rax
  je     L0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <FAIL@plt>
L0:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  foo();
  if (issetugid())
    FAIL(argv[1]);
  return EXIT_SUCCESS;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  call   <issetugid@plt>
  test   %rax,%rax
  jne    L6
L1:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  pop    %rbx
  ret
L6:
  mov    0x8(%rbx),%rdi
  call   <FAIL@plt>
  jmp    L1
```

assistant: ```c
int main(int argc, const char *argv[]) {
  foo();
  if (issetugid())
    FAIL(argv[1]);
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rsi,%rbx
  call   <foo@plt>
  xor    %eax,%eax
  call   <issetugid@plt>
  test   %rax,%rax
  jne    L4
L16:
  mov    D8(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
L4:
  mov    0x8(%rbx),%rdi
  call   <FAIL@plt>
  jmp    L16
```

assistant: ```c
int main(int argc, const char *argv[]) {
  foo();
  if (issetugid())
    FAIL(argv[1]);
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rsi,%rbx
  call   <foo@plt>
  xor    %eax,%eax
  call   <issetugid@plt>
  test   %rax,%rax
  jne    L13
L12:
  mov    D7(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
L13:
  mov    0x8(%rbx),%rdi
  call   <FAIL@plt>
  jmp    L12
```

assistant: ```c
int main(int argc, const char *argv[]) {
  foo();
  if (issetugid())
    FAIL(argv[1]);
  return EXIT_SUCCESS;
}
```