ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L9
  nopl   0x0(%rax)
L25:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L18
  add    $0x20,%eax
  mov    %al,(%rbx)
L18:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L25
L9:
  pop    %rbx
  ret
```

assistant: ```c
void strlower(char *const str) {
  assert(str);
  for (size_t i = 0; '\0' != str[i]; i++) {
    char const c = str[i];
    if (c >= 'A' && c <= 'Z')
      str[i] += 'a' - 'A';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L6
  nopl   0x0(%rax)
L10:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L26
  add    $0x20,%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L10
L6:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L10
  pop    %rbx
  ret
```

assistant: ```c
void strlower(char *const str) {
  assert(str);
  for (size_t i = 0; '\0' != str[i]; i++) {
    char const c = str[i];
    if (c >= 'A' && c <= 'Z')
      str[i] += 'a' - 'A';
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L52
  mov    $0x0,%eax
  jmp    L53
L52:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L67
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L53
L67:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  subq   $0x1,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L52
  jmp    L48
L32:
  nop
L48:
  mov    $0x0,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  if (n == 0)
    return 0;
  do {
    if (*s1 != *s2++)
      return *(unsigned const char *)s1 - *(unsigned const char *)--s2;
    if (*s1++ == 0)
      break;
  } while (--n != 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncmp>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L6
  mov    $0x0,%eax
L2:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L37
  test   %cl,%cl
  je     L18
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L2
  mov    $0x0,%eax
  ret
L37:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L18:
  mov    $0x0,%eax
L6:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  if (n == 0)
    return 0;
  do {
    if (*s1 != *s2++)
      return *(unsigned const char *)s1 - *(unsigned const char *)--s2;
    if (*s1++ == 0)
      break;
  } while (--n != 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L2
  xor    %eax,%eax
  jmp    L49
  nop
L20:
  test   %cl,%cl
  je     L45
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L45
L49:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L20
  movzbl %cl,%eax
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
L2:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  if (n == 0)
    return 0;
  do {
    if (*s1 != *s2++)
      return *(unsigned const char *)s1 - *(unsigned const char *)--s2;
    if (*s1++ == 0)
      break;
  } while (--n != 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L7
  xor    %eax,%eax
  jmp    L43
  nop
L12:
  test   %cl,%cl
  je     L33
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L33
L43:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L12
  movzbl %cl,%eax
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
L7:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  if (n == 0)
    return 0;
  do {
    if (*s1 != *s2++)
      return *(unsigned const char *)s1 - *(unsigned const char *)--s2;
    if (*s1++ == 0)
      break;
  } while (--n != 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serial_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L2:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <serial_write_char@plt>
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L2
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int serial_write(char *buf) {
  unsigned int len = strlen(buf);
  unsigned int i;
  for (i = 0; i < len; i++) {
    serial_write_char(buf[i]);
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<serial_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L14
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rbp
L19:
  movsbl (%rbx),%edi
  call   <serial_write_char@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L19
L14:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int serial_write(char *buf) {
  unsigned int len = strlen(buf);
  unsigned int i;
  for (i = 0; i < len; i++) {
    serial_write_char(buf[i]);
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<serial_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L8
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nop
L12:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <serial_write_char@plt>
  cmp    %rbp,%rbx
  jne    L12
L8:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int serial_write(char *buf) {
  unsigned int len = strlen(buf);
  unsigned int i;
  for (i = 0; i < len; i++) {
    serial_write_char(buf[i]);
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<serial_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L14
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nop
L4:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <serial_write_char@plt>
  cmp    %rbp,%rbx
  jne    L4
L14:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int serial_write(char *buf) {
  unsigned int len = strlen(buf);
  unsigned int i;
  for (i = 0; i < len; i++) {
    serial_write_char(buf[i]);
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<changeFileEnding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D5: .

assistant: ```c
int changeFileEnding(char **newname, const char *oldname, const char *end) {
  const int aux = strlen(end);
  *newname = (char *)malloc((strlen(oldname) + aux) * sizeof(char));
  strcpy(*newname, oldname);
  strtok(*newname, ".");
  strcat(*newname, end);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<changeFileEnding>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    (%rax,%r13,1),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  mov    %r12,%rsi
  call   <strcpy@plt>
  lea    D7(%rip),%rsi
  mov    (%rbx),%rdi
  call   <strtok@plt>
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strcat@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: .

assistant: ```c
int changeFileEnding(char **newname, const char *oldname, const char *end) {
  const int aux = strlen(end);
  *newname = (char *)malloc((strlen(oldname) + aux) * sizeof(char));
  strcpy(*newname, oldname);
  strtok(*newname, ".");
  strcat(*newname, end);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<changeFileEnding>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  lea    (%rax,%r13,1),%edi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  lea    D8(%rip),%rsi
  call   <strtok@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: .

assistant: ```c
int changeFileEnding(char **newname, const char *oldname, const char *end) {
  const int aux = strlen(end);
  *newname = (char *)malloc((strlen(oldname) + aux) * sizeof(char));
  strcpy(*newname, oldname);
  strtok(*newname, ".");
  strcat(*newname, end);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<changeFileEnding>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  lea    (%rax,%r13,1),%edi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  lea    D7(%rip),%rsi
  call   <strtok@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: string

tool: D7: .

assistant: ```c
int changeFileEnding(char **newname, const char *oldname, const char *end) {
  const int aux = strlen(end);
  *newname = (char *)malloc((strlen(oldname) + aux) * sizeof(char));
  strcpy(*newname, oldname);
  strtok(*newname, ".");
  strcat(*newname, end);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<frinv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%eax
  imul   %eax,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x44(%rbp),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <frlufact@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L9
L1:
  mov    -0x24(%rbp),%eax
  imul   -0x44(%rbp),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x44(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x24(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movss  D9(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x44(%rbp),%edi
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <frlusolve@plt>
  addl   $0x1,-0x24(%rbp)
L9:
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jb     L1
  mov    -0x44(%rbp),%ecx
  mov    -0x44(%rbp),%edx
  mov    -0x38(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <frtranspose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void frinv(float *ainv, const float *a, unsigned d) {
  float *u, *y;
  unsigned int *p;
  unsigned int k;
  u = alloca(d * d * sizeof(u[0]));
  p = alloca((d - 1) * sizeof(p[0]));
  frlufact(u, p, a, d);
  for (k = 0; k < d; k++) {
    y = &ainv[k * d];
    memset(y, 0, d * sizeof(y[0]));
    y[k] = 1;
    frlusolve(y, y, u, p, d);
  }
  frtranspose(ainv, ainv, d, d);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<frinv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %edx,%edi
  imul   %edx,%edi
  shl    $0x2,%edi
  call   <alloca@plt>
  mov    %rax,%r14
  mov    %rax,-0x48(%rbp)
  lea    -0x1(%r13),%ebx
  lea    0x0(,%rbx,4),%edi
  call   <alloca@plt>
  mov    %rax,%rsi
  mov    %rax,-0x50(%rbp)
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <frlufact@plt>
  test   %r13d,%r13d
  je     L11
  lea    0x0(,%r13,4),%eax
  mov    %eax,-0x54(%rbp)
  mov    %ebx,%ebx
  lea    0x4(,%rbx,4),%rax
  mov    %rax,-0x60(%rbp)
  mov    $0x0,%r12d
  mov    $0x0,%r14d
L3:
  mov    %r14d,%eax
  lea    (%r15,%rax,4),%rbx
  mov    -0x54(%rbp),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movl   $0x3f800000,(%rbx,%r12,1)
  mov    %r13d,%r8d
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <frlusolve@plt>
  add    %r13d,%r14d
  add    $0x4,%r12
  cmp    -0x60(%rbp),%r12
  jne    L3
L11:
  mov    %r13d,%ecx
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %r15,%rdi
  call   <frtranspose@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void frinv(float *ainv, const float *a, unsigned d) {
  float *u, *y;
  unsigned int *p;
  unsigned int k;
  u = alloca(d * d * sizeof(u[0]));
  p = alloca((d - 1) * sizeof(p[0]));
  frlufact(u, p, a, d);
  for (k = 0; k < d; k++) {
    y = &ainv[k * d];
    memset(y, 0, d * sizeof(y[0]));
    y[k] = 1;
    frlusolve(y, y, u, p, d);
  }
  frtranspose(ainv, ainv, d, d);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<frinv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x50(%rbp)
  mov    %edx,%edi
  imul   %edx,%edi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  shl    $0x2,%edi
  call   <alloca@plt>
  lea    -0x4(,%r12,4),%edi
  mov    %rax,%r13
  call   <alloca@plt>
  mov    %r12d,%ecx
  mov    %r15,%rdx
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%r14
  call   <frlufact@plt>
  test   %r12d,%r12d
  je     L2
  lea    0x0(,%r12,4),%eax
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  mov    %eax,-0x54(%rbp)
  mov    %r12d,%eax
  shl    $0x2,%rax
  mov    %rax,-0x60(%rbp)
  nop
L28:
  mov    -0x50(%rbp),%rcx
  mov    %r15d,%eax
  mov    -0x54(%rbp),%edx
  xor    %esi,%esi
  add    %r12d,%r15d
  lea    (%rcx,%rax,4),%rdi
  mov    %rdi,-0x48(%rbp)
  call   <memset@plt>
  mov    -0x48(%rbp),%rdi
  mov    %r12d,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  movl   $0x3f800000,(%rdi,%rbx,1)
  mov    %rdi,%rsi
  add    $0x4,%rbx
  call   <frlusolve@plt>
  cmp    -0x60(%rbp),%rbx
  jne    L28
L2:
  mov    -0x50(%rbp),%rsi
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rsi,%rdi
  call   <frtranspose@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void frinv(float *ainv, const float *a, unsigned d) {
  float *u, *y;
  unsigned int *p;
  unsigned int k;
  u = alloca(d * d * sizeof(u[0]));
  p = alloca((d - 1) * sizeof(p[0]));
  frlufact(u, p, a, d);
  for (k = 0; k < d; k++) {
    y = &ainv[k * d];
    memset(y, 0, d * sizeof(y[0]));
    y[k] = 1;
    frlusolve(y, y, u, p, d);
  }
  frtranspose(ainv, ainv, d, d);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<frinv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x50(%rbp)
  mov    %edx,%edi
  imul   %edx,%edi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  shl    $0x2,%edi
  call   <alloca@plt>
  lea    -0x4(,%r12,4),%edi
  mov    %rax,%r13
  call   <alloca@plt>
  mov    %r12d,%ecx
  mov    %r15,%rdx
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%r14
  call   <frlufact@plt>
  test   %r12d,%r12d
  je     L19
  lea    0x0(,%r12,4),%eax
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  mov    %eax,-0x54(%rbp)
  mov    %r12d,%eax
  shl    $0x2,%rax
  mov    %rax,-0x60(%rbp)
  nop
L22:
  mov    -0x50(%rbp),%rcx
  mov    %r15d,%eax
  mov    -0x54(%rbp),%edx
  xor    %esi,%esi
  add    %r12d,%r15d
  lea    (%rcx,%rax,4),%rdi
  mov    %rdi,-0x48(%rbp)
  call   <memset@plt>
  mov    -0x48(%rbp),%rdi
  mov    %r12d,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  movl   $0x3f800000,(%rdi,%rbx,1)
  mov    %rdi,%rsi
  add    $0x4,%rbx
  call   <frlusolve@plt>
  cmp    %rbx,-0x60(%rbp)
  jne    L22
L19:
  mov    -0x50(%rbp),%rsi
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rsi,%rdi
  call   <frtranspose@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void frinv(float *ainv, const float *a, unsigned d) {
  float *u, *y;
  unsigned int *p;
  unsigned int k;
  u = alloca(d * d * sizeof(u[0]));
  p = alloca((d - 1) * sizeof(p[0]));
  frlufact(u, p, a, d);
  for (k = 0; k < d; k++) {
    y = &ainv[k * d];
    memset(y, 0, d * sizeof(y[0]));
    y[k] = 1;
    frlusolve(y, y, u, p, d);
  }
  frtranspose(ainv, ainv, d, d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<od_aligned_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void od_aligned_free(void *_ptr) {
  unsigned char *p;
  p = (unsigned char *)_ptr;
  if (p != NULL) {
    int offs;
    offs = *--p;
    free(p - offs);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<od_aligned_free>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  movzbl -0x1(%rdi),%eax
  not    %rax
  add    %rax,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
void od_aligned_free(void *_ptr) {
  unsigned char *p;
  p = (unsigned char *)_ptr;
  if (p != NULL) {
    int offs;
    offs = *--p;
    free(p - offs);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<od_aligned_free>:
  endbr64
  test   %rdi,%rdi
  je     L2
  movzbl -0x1(%rdi),%eax
  not    %rax
  add    %rax,%rdi
  jmp    1050 <free@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void od_aligned_free(void *_ptr) {
  unsigned char *p;
  p = (unsigned char *)_ptr;
  if (p != NULL) {
    int offs;
    offs = *--p;
    free(p - offs);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<od_aligned_free>:
  endbr64
  test   %rdi,%rdi
  je     L2
  movzbl -0x1(%rdi),%eax
  not    %rax
  add    %rax,%rdi
  jmp    1050 <free@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void od_aligned_free(void *_ptr) {
  unsigned char *p;
  p = (unsigned char *)_ptr;
  if (p != NULL) {
    int offs;
    offs = *--p;
    free(p - offs);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<axt_to_uint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int axt_to_uint32(unsigned int axt_uint32) {
  unsigned char *buf = (unsigned char *)&axt_uint32;
  return (((unsigned int)buf[0]) << 24) + (((unsigned int)buf[1]) << 16) + (((unsigned int)buf[2]) << 8) + (((unsigned int)buf[3]));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<axt_to_uint32>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  shl    $0x18,%eax
  movzbl %dh,%ecx
  shl    $0x10,%ecx
  add    %ecx,%eax
  mov    %edi,%ecx
  shr    $0x18,%ecx
  add    %ecx,%eax
  shr    $0x8,%edx
  and    $0xff00,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int axt_to_uint32(unsigned int axt_uint32) {
  unsigned char *buf = (unsigned char *)&axt_uint32;
  return (((unsigned int)buf[0]) << 24) + (((unsigned int)buf[1]) << 16) + (((unsigned int)buf[2]) << 8) + (((unsigned int)buf[3]));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<axt_to_uint32>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  movzbl %dh,%ecx
  shl    $0x18,%eax
  shl    $0x10,%ecx
  shr    $0x8,%edx
  add    %ecx,%eax
  mov    %edi,%ecx
  and    $0xff00,%edx
  shr    $0x18,%ecx
  add    %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int axt_to_uint32(unsigned int axt_uint32) {
  unsigned char *buf = (unsigned char *)&axt_uint32;
  return (((unsigned int)buf[0]) << 24) + (((unsigned int)buf[1]) << 16) + (((unsigned int)buf[2]) << 8) + (((unsigned int)buf[3]));
}
```