ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ffgsdt>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  call   <time@plt>
  mov    %r14,%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  test   %rax,%rax
  je     L14
L1:
  mov    (%rax),%edx
  mov    %edx,0x0(%r13)
  mov    0x4(%rax),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,(%r12)
  mov    0x8(%rax),%eax
  add    $0x76c,%eax
  mov    %eax,0x0(%rbp)
  mov    (%rbx),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %r14,%rdi
  call   <localtime@plt>
  jmp    L1
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ffgsdt(int *day, int *month, int *year, int *status) {
  time_t now;
  struct tm *date;
  now = time(NULL);
  date = gmtime(&now);
  if (!date) {
    date = localtime(&now);
  }
  *day = date->tm_mday;
  *month = date->tm_mon + 1;
  *year = date->tm_year + 1900;
  return (*status);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<autohelperowl_vital_apat22>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <owl_big_eyespace@plt>
  test   %rax,%rax
  je     L0
  mov    -0xc(%rbp),%edi
  mov    -0x10(%rbp),%esi
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  push   %rcx
  mov    -0x8(%rbp),%ecx
  push   %rcx
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %edx,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <play_attack_defend_n@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  je     L0
  mov    $0x1,%eax
  jmp    L8
L0:
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int autohelperowl_vital_apat22(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c, D;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(1, 0, move, transformation);
  b = offset(1, -1, move, transformation);
  c = offset(0, -1, move, transformation);
  D = offset(0, 1, move, transformation);
  return owl_big_eyespace(move, D) && play_attack_defend_n(color, 1, 4, move, a, b, c, a);
}
```
user: What is the c source code of the assembly code below?

```asm
<autohelperowl_vital_apat22>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %esi,%ecx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%r12d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%r14d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%r15d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <owl_big_eyespace@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L9
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  push   %r12
  push   %r15
  mov    %r14d,%r9d
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %r13d,%edi
  call   <play_attack_defend_n@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L10
```

assistant: ```c
int autohelperowl_vital_apat22(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c, D;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(1, 0, move, transformation);
  b = offset(1, -1, move, transformation);
  c = offset(0, -1, move, transformation);
  D = offset(0, 1, move, transformation);
  return owl_big_eyespace(move, D) && play_attack_defend_n(color, 1, 4, move, a, b, c, a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<autohelperowl_vital_apat22>:
  endbr64
  push   %r15
  mov    $0x1,%edi
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  xor    %esi,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  mov    %eax,%r15d
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  xor    %edi,%edi
  mov    %eax,%r14d
  call   <offset@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <owl_big_eyespace@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L2:
  push   %r15
  mov    %r12d,%ecx
  mov    %ebx,%r9d
  mov    %r15d,%r8d
  push   %r14
  mov    $0x4,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <play_attack_defend_n@plt>
  pop    %rdx
  pop    %rcx
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int autohelperowl_vital_apat22(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c, D;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(1, 0, move, transformation);
  b = offset(1, -1, move, transformation);
  c = offset(0, -1, move, transformation);
  D = offset(0, 1, move, transformation);
  return owl_big_eyespace(move, D) && play_attack_defend_n(color, 1, 4, move, a, b, c, a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<autohelperowl_vital_apat22>:
  endbr64
  push   %r15
  mov    $0x1,%edi
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  xor    %esi,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  mov    %eax,%r15d
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  xor    %edi,%edi
  mov    %eax,%r14d
  call   <offset@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <owl_big_eyespace@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L9:
  push   %r15
  mov    %r12d,%ecx
  mov    %ebx,%r9d
  mov    %r15d,%r8d
  push   %r14
  mov    $0x4,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <play_attack_defend_n@plt>
  pop    %rdx
  pop    %rcx
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int autohelperowl_vital_apat22(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c, D;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(1, 0, move, transformation);
  b = offset(1, -1, move, transformation);
  c = offset(0, -1, move, transformation);
  D = offset(0, 1, move, transformation);
  return owl_big_eyespace(move, D) && play_attack_defend_n(color, 1, 4, move, a, b, c, a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<posix_acl_xxx_calc_hash_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L28:
  sarl   -0x14(%rbp)
  shll   -0x4(%rbp)
L23:
  cmpl   $0x0,-0x14(%rbp)
  jne    L28
  cmpl   $0x0,-0x4(%rbp)
  jne    L10
  mov    $0x80000000,%edi
  call   <UINT32_C@plt>
  mov    %eax,-0x4(%rbp)
L10:
  cmpl   $0xfffff,-0x4(%rbp)
  jg     L36
  mov    $0x100000,%eax
  jmp    L47
L36:
  mov    -0x4(%rbp),%eax
L47:
  leave
  ret
```

assistant: ```c
uint32_t posix_acl_xxx_calc_hash_size(uint32_t elements) {
  uint32_t res = 1;
  while (elements) {
    elements >>= 1;
    res <<= 1;
  }
  if (res == 0) {
    res = UINT32_C(0x80000000);
  }
  if (res < (1 << 20)) {
    return (1 << 20);
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<posix_acl_xxx_calc_hash_size>:
  endbr64
  test   %edi,%edi
  je     L17
  mov    $0x1,%eax
L23:
  add    %eax,%eax
  sar    %edi
  jne    L23
  test   %eax,%eax
  je     L29
L18:
  mov    $0x100000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
L29:
  sub    $0x8,%rsp
  mov    $0x80000000,%edi
  call   <UINT32_C@plt>
  mov    $0x100000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x8,%rsp
  ret
L17:
  mov    $0x1,%eax
  jmp    L18
```

assistant: ```c
uint32_t posix_acl_xxx_calc_hash_size(uint32_t elements) {
  uint32_t res = 1;
  while (elements) {
    elements >>= 1;
    res <<= 1;
  }
  if (res == 0) {
    res = UINT32_C(0x80000000);
  }
  if (res < (1 << 20)) {
    return (1 << 20);
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<posix_acl_xxx_calc_hash_size>:
  endbr64
  test   %edi,%edi
  je     L22
  mov    $0x1,%eax
  nopl   (%rax)
L3:
  add    %eax,%eax
  sar    %edi
  jne    L3
  test   %eax,%eax
  je     L9
  mov    $0x100000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
  nopl   (%rax)
L9:
  sub    $0x8,%rsp
  mov    $0x80000000,%edi
  call   <UINT32_C@plt>
  mov    $0x100000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L22:
  mov    $0x100000,%eax
  ret
```

assistant: ```c
uint32_t posix_acl_xxx_calc_hash_size(uint32_t elements) {
  uint32_t res = 1;
  while (elements) {
    elements >>= 1;
    res <<= 1;
  }
  if (res == 0) {
    res = UINT32_C(0x80000000);
  }
  if (res < (1 << 20)) {
    return (1 << 20);
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<posix_acl_xxx_calc_hash_size>:
  endbr64
  test   %edi,%edi
  je     L2
  mov    $0x1,%eax
  nopl   (%rax)
L28:
  add    %eax,%eax
  sar    %edi
  jne    L28
  test   %eax,%eax
  je     L29
  mov    $0x100000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
  nopl   (%rax)
L29:
  sub    $0x8,%rsp
  mov    $0x80000000,%edi
  call   <UINT32_C@plt>
  mov    $0x100000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L2:
  mov    $0x100000,%eax
  ret
```

assistant: ```c
uint32_t posix_acl_xxx_calc_hash_size(uint32_t elements) {
  uint32_t res = 1;
  while (elements) {
    elements >>= 1;
    res <<= 1;
  }
  if (res == 0) {
    res = UINT32_C(0x80000000);
  }
  if (res < (1 << 20)) {
    return (1 << 20);
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned func3(void) {
  unsigned j;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func3>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned func3(void) {
  unsigned j;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func3>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned func3(void) {
  unsigned j;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<func3>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned func3(void) {
  unsigned j;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_fill_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L26:
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L13:
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _fill_matrix(int *m, int n, int v) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      *(m + (i * n + j)) = v;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_fill_matrix>:
  endbr64
  test   %esi,%esi
  jle    L6
  movslq %esi,%r9
  shl    $0x2,%r9
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rcx
  mov    $0x0,%edi
  mov    %esi,%r8d
  neg    %r8
  shl    $0x2,%r8
L26:
  lea    (%r8,%rcx,1),%rax
L15:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L15
  add    $0x1,%edi
  add    %r9,%rcx
  cmp    %edi,%esi
  jne    L26
L6:
  ret
```

assistant: ```c
void _fill_matrix(int *m, int n, int v) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      *(m + (i * n + j)) = v;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_fill_matrix>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  movslq %esi,%r9
  mov    $0xfffffffffffffffc,%r8
  shl    $0x2,%rax
  shl    $0x2,%r9
  lea    0x4(%rdi,%rax,1),%rcx
  sub    %rax,%r8
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L7:
  lea    (%r8,%rcx,1),%rax
  nopl   0x0(%rax)
L22:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L22
  add    $0x1,%edi
  add    %r9,%rcx
  cmp    %edi,%esi
  jne    L7
L12:
  ret
```

assistant: ```c
void _fill_matrix(int *m, int n, int v) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      *(m + (i * n + j)) = v;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_fill_matrix>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    %esi,%ecx
  mov    %edx,%r8d
  push   %r12
  mov    %rdi,%r9
  mov    %ecx,%eax
  push   %rbp
  mov    %ecx,%r10d
  movd   %r8d,%xmm1
  shr    $0x2,%eax
  push   %rbx
  movslq %esi,%rbx
  lea    -0x1(%rcx),%ebp
  lea    -0x1(%rax),%r11d
  mov    %rdi,%rsi
  shl    $0x2,%rbx
  and    $0xfffffffc,%r10d
  add    $0x1,%r11
  xor    %edx,%edx
  pshufd $0x0,%xmm1,%xmm0
  xor    %edi,%edi
  shl    $0x4,%r11
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    $0x2,%ebp
  jbe    L69
  lea    (%r11,%rsi,1),%r12
  mov    %rsi,%rax
  nopl   0x0(%rax)
L21:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %r12,%rax
  jne    L21
  mov    %r10d,%eax
  cmp    %ecx,%r10d
  je     L77
L42:
  lea    (%rdx,%rax,1),%r12d
  movslq %r12d,%r12
  mov    %r8d,(%r9,%r12,4)
  lea    0x1(%rax),%r12d
  cmp    %r12d,%ecx
  jle    L77
  add    %edx,%r12d
  add    $0x2,%eax
  movslq %r12d,%r12
  mov    %r8d,(%r9,%r12,4)
  cmp    %eax,%ecx
  jle    L77
  add    %edx,%eax
  cltq
  mov    %r8d,(%r9,%rax,4)
L77:
  add    $0x1,%edi
  add    %ecx,%edx
  add    %rbx,%rsi
  cmp    %edi,%ecx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  jmp    L42
L16:
  ret
```

assistant: ```c
void _fill_matrix(int *m, int n, int v) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      *(m + (i * n + j)) = v;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<doubleFactorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L6
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L37
L6:
  movl   $0x1,-0x4(%rbp)
  jmp    L37
L16:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x2,-0x14(%rbp)
L37:
  cmpl   $0x1,-0x14(%rbp)
  jg     L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int doubleFactorial(int n) {
  int f = 0;
  if (n >= 0 || n == -1)
    f = 1;
  while (n > 1) {
    f *= n;
    n -= 2;
  }
  return f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<doubleFactorial>:
  endbr64
  cmp    $0xffffffff,%edi
  setge  %al
  movzbl %al,%eax
  cmp    $0x1,%edi
  jle    L0
L2:
  imul   %edi,%eax
  sub    $0x2,%edi
  cmp    $0x1,%edi
  jg     L2
L0:
  ret
```

assistant: ```c
int doubleFactorial(int n) {
  int f = 0;
  if (n >= 0 || n == -1)
    f = 1;
  while (n > 1) {
    f *= n;
    n -= 2;
  }
  return f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<doubleFactorial>:
  endbr64
  xor    %eax,%eax
  cmp    $0xffffffff,%edi
  setge  %al
  cmp    $0x1,%edi
  jle    L10
  nopl   0x0(%rax)
L18:
  imul   %edi,%eax
  sub    $0x2,%edi
  cmp    $0x1,%edi
  jg     L18
L10:
  ret
```

assistant: ```c
int doubleFactorial(int n) {
  int f = 0;
  if (n >= 0 || n == -1)
    f = 1;
  while (n > 1) {
    f *= n;
    n -= 2;
  }
  return f;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<doubleFactorial>:
  endbr64
  xor    %eax,%eax
  cmp    $0xffffffff,%edi
  setge  %al
  cmp    $0x1,%edi
  jle    L13
  nopl   0x0(%rax)
L14:
  imul   %edi,%eax
  sub    $0x2,%edi
  cmp    $0x1,%edi
  jg     L14
L13:
  ret
```

assistant: ```c
int doubleFactorial(int n) {
  int f = 0;
  if (n >= 0 || n == -1)
    f = 1;
  while (n > 1) {
    f *= n;
    n -= 2;
  }
  return f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L4
  mov    -0x4(%rbp),%eax
  jmp    L0
L4:
  mov    -0x4(%rbp),%eax
  and    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Add>
L0:
  leave
  ret
```

assistant: ```c
int Add(int x, int y) {
  if (y == 0)
    return x;
  else
    return Add(x ^ y, (x & y) << 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jne    L8
  ret
L8:
  sub    $0x8,%rsp
  mov    %esi,%edx
  and    %edi,%edx
  add    %edx,%edx
  mov    %esi,%edi
  xor    %eax,%edi
  mov    %edx,%esi
  call   <Add>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Add(int x, int y) {
  if (y == 0)
    return x;
  else
    return Add(x ^ y, (x & y) << 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L15
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %esi,%edx
  and    %eax,%edx
  xor    %esi,%eax
  add    %edx,%edx
  mov    %edx,%esi
  jne    L0
L15:
  ret
```

assistant: ```c
int Add(int x, int y) {
  if (y == 0)
    return x;
  else
    return Add(x ^ y, (x & y) << 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L2
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %esi,%edx
  and    %eax,%edx
  xor    %esi,%eax
  add    %edx,%edx
  mov    %edx,%esi
  jne    L11
L2:
  ret
```

assistant: ```c
int Add(int x, int y) {
  if (y == 0)
    return x;
  else
    return Add(x ^ y, (x & y) << 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GTR2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  movss  D3(%rip),%xmm1
  subss  %xmm1,%xmm0
  mulss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x14(%rbp),%xmm1
  movss  D3(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  movsd  D21(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: f32
name: parse_data
arguments: data_tag: D21
type_guessed: f64

tool: D3: 1

tool: D21: 3.141592653589793

assistant: ```c
float GTR2(float NdotH, float a) {
  float a2 = a * a;
  float t = 1 + (a2 - 1) * NdotH * NdotH;
  return a2 / (3.14159265358979323846264 * t * t);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GTR2>:
  endbr64
  movaps %xmm0,%xmm3
  mulss  %xmm1,%xmm1
  movss  D2(%rip),%xmm2
  movaps %xmm1,%xmm0
  subss  %xmm2,%xmm0
  mulss  %xmm3,%xmm0
  mulss  %xmm3,%xmm0
  addss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  movapd %xmm0,%xmm2
  mulsd  D16(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: f32
name: retrieve_data
arguments: tag: D16
type: f64

tool: D2: 1

tool: D16: 3.141592653589793

assistant: ```c
float GTR2(float NdotH, float a) {
  float a2 = a * a;
  float t = 1 + (a2 - 1) * NdotH * NdotH;
  return a2 / (3.14159265358979323846264 * t * t);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GTR2>:
  endbr64
  mulss  %xmm1,%xmm1
  movaps %xmm0,%xmm3
  movss  D2(%rip),%xmm0
  movaps %xmm1,%xmm2
  cvtss2sd %xmm1,%xmm1
  subss  %xmm0,%xmm2
  mulss  %xmm3,%xmm2
  mulss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  movsd  D3(%rip),%xmm2
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm2
  mulsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: f32
name: parse_data
arguments: tag: D3
type_guessed: f64

tool: D2: 1

tool: D3: 3.141592653589793

assistant: ```c
float GTR2(float NdotH, float a) {
  float a2 = a * a;
  float t = 1 + (a2 - 1) * NdotH * NdotH;
  return a2 / (3.14159265358979323846264 * t * t);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GTR2>:
  endbr64
  mulss  %xmm1,%xmm1
  movaps %xmm0,%xmm3
  movss  D11(%rip),%xmm0
  movaps %xmm1,%xmm2
  cvtss2sd %xmm1,%xmm1
  subss  %xmm0,%xmm2
  mulss  %xmm3,%xmm2
  mulss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  movsd  D1(%rip),%xmm2
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm2
  mulsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
type_guessed: f32
name: read_data
arguments: data_tag: D1
type_guessed: f64

tool: D11: 1

tool: D1: 3.141592653589793

assistant: ```c
float GTR2(float NdotH, float a) {
  float a2 = a * a;
  float t = 1 + (a2 - 1) * NdotH * NdotH;
  return a2 / (3.14159265358979323846264 * t * t);
}
```