ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D45(%rip),%xmm0
  mov    $0xa,%edx
  mov    $0xf,%esi
  lea    D63(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  movss  D99(%rip),%xmm1
  mov    $0xf,%esi
  lea    D58(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    $0xa,%edx
  movss  D8(%rip),%xmm0
  mov    $0xf,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  movss  D84(%rip),%xmm0
  mov    $0xf,%esi
  lea    D68(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  movss  D99(%rip),%xmm1
  mov    $0xf,%esi
  lea    D62(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D45
datatype: byte[4]
name: read_data
arguments: data_tag: D63
datatype: string
name: read_data
arguments: data_tag: D99
datatype: byte[4]
name: read_data
arguments: data_tag: D58
datatype: string
name: read_data
arguments: data_tag: D8
datatype: byte[4]
name: read_data
arguments: data_tag: D36
datatype: string
name: read_data
arguments: data_tag: D84
datatype: byte[4]
name: read_data
arguments: data_tag: D68
datatype: string
name: read_data
arguments: data_tag: D62
datatype: string

tool: {"D45": [0x00,0x00,0xc8,0x41]}

tool: D63: %d + %d = %f


tool: {"D99": [0x00,0x00,0xa0,0x40]}

tool: D58: %d - %d = %f


tool: {"D8": [0x00,0x00,0x16,0x43]}

tool: D36: %d * %d = %f


tool: {"D84": [0x00,0x00,0x80,0x3f]}

tool: D68: %d / %d = %f


tool: D62: (%d / %d)[remainder] = %f


assistant: ```c
main() {
  int num1 = 15, num2 = 10;
  float result = 0;
  result = num1 + num2;
  printf("%d + %d = %f\n", num1, num2, result);
  result = num1 - num2;
  printf("%d - %d = %f\n", num1, num2, result);
  result = num1 * num2;
  printf("%d * %d = %f\n", num1, num2, result);
  result = num1 / num2;
  printf("%d / %d = %f\n", num1, num2, result);
  result = num1 % num2;
  printf("(%d / %d)[remainder] = %f\n", num1, num2, result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D69(%rip),%xmm0
  mov    $0xa,%edx
  mov    $0xf,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  movss  D94(%rip),%xmm1
  mov    $0xf,%esi
  lea    D76(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    $0xa,%edx
  movss  D45(%rip),%xmm0
  mov    $0xf,%esi
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  movss  D73(%rip),%xmm0
  mov    $0xf,%esi
  lea    D80(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  movss  D94(%rip),%xmm1
  mov    $0xf,%esi
  lea    D72(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D69
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D7
type_infered: string
name: extract_symbolic_data
arguments: label: D94
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D76
type_infered: string
name: extract_symbolic_data
arguments: label: D45
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D58
type_infered: string
name: extract_symbolic_data
arguments: label: D73
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D80
type_infered: string
name: extract_symbolic_data
arguments: label: D72
type_infered: string

tool: {"D69": [0x00,0x00,0xc8,0x41]}

tool: D7: %d + %d = %f


tool: {"D94": [0x00,0x00,0xa0,0x40]}

tool: D76: %d - %d = %f


tool: {"D45": [0x00,0x00,0x16,0x43]}

tool: D58: %d * %d = %f


tool: {"D73": [0x00,0x00,0x80,0x3f]}

tool: D80: %d / %d = %f


tool: D72: (%d / %d)[remainder] = %f


assistant: ```c
main() {
  int num1 = 15, num2 = 10;
  float result = 0;
  result = num1 + num2;
  printf("%d + %d = %f\n", num1, num2, result);
  result = num1 - num2;
  printf("%d - %d = %f\n", num1, num2, result);
  result = num1 * num2;
  printf("%d * %d = %f\n", num1, num2, result);
  result = num1 / num2;
  printf("%d / %d = %f\n", num1, num2, result);
  result = num1 % num2;
  printf("(%d / %d)[remainder] = %f\n", num1, num2, result);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sig_handler_child>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <remove_pidfile@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void sig_handler_child(int sig) {
  remove_pidfile();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sig_handler_child>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <remove_pidfile@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sig_handler_child(int sig) {
  remove_pidfile();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sig_handler_child>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <remove_pidfile@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void sig_handler_child(int sig) {
  remove_pidfile();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sig_handler_child>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <remove_pidfile@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void sig_handler_child(int sig) {
  remove_pidfile();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4241424342414242,%rax
  mov    %rax,-0x16(%rbp)
  movl   $0x41424341,-0xe(%rbp)
  movw   $0x42,-0xa(%rbp)
  lea    -0x16(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  lea    -0x16(%rbp),%rax
  mov    %rax,%rdi
  call   <lps@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: The length of the LPS is %d


assistant: ```c
int main() {
  char seq[] = "BBABCBABACBAB";
  int n = strlen(seq);
  printf("The length of the LPS is %d\n", lps(seq));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x4241424342414242,%rax
  mov    %rax,0xa(%rsp)
  movl   $0x41424341,0x12(%rsp)
  movw   $0x42,0x16(%rsp)
  lea    0xa(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  call   <lps@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: The length of the LPS is %d


assistant: ```c
int main() {
  char seq[] = "BBABCBABACBAB";
  int n = strlen(seq);
  printf("The length of the LPS is %d\n", lps(seq));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4241424342414242,%rax
  lea    0xa(%rsp),%rbp
  movl   $0x41424341,0x12(%rsp)
  mov    %rbp,%rdi
  mov    %rax,0xa(%rsp)
  mov    $0x42,%eax
  mov    %ax,0x16(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  call   <lps@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: The length of the LPS is %d


assistant: ```c
int main() {
  char seq[] = "BBABCBABACBAB";
  int n = strlen(seq);
  printf("The length of the LPS is %d\n", lps(seq));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4241424342414242,%rax
  lea    0xa(%rsp),%rbp
  movl   $0x41424341,0x12(%rsp)
  mov    %rbp,%rdi
  mov    %rax,0xa(%rsp)
  mov    $0x42,%eax
  mov    %ax,0x16(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  call   <lps@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: The length of the LPS is %d


assistant: ```c
int main() {
  char seq[] = "BBABCBABACBAB";
  int n = strlen(seq);
  printf("The length of the LPS is %d\n", lps(seq));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ThreeAndFiveMultiples@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D13
datatype: string
name: extract_symbolic_data
arguments: data_tag: D12
datatype: string

tool: D15: Insert your max: 

tool: D13: %d

tool: D12: This is your result: %d


assistant: ```c
int main() {
  int max;
  int result;
  printf("Insert your max: ");
  scanf("%d", &max);
  result = ThreeAndFiveMultiples(max);
  printf("This is your result: %d\n", result);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <ThreeAndFiveMultiples@plt>
  mov    %eax,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D24
type: string
name: disassemble_data
arguments: data_label: D26
type: string

tool: D3: Insert your max: 

tool: D24: %d

tool: D26: This is your result: %d


assistant: ```c
int main() {
  int max;
  int result;
  printf("Insert your max: ");
  scanf("%d", &max);
  result = ThreeAndFiveMultiples(max);
  printf("This is your result: %d\n", result);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <ThreeAndFiveMultiples@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D25
type_infered: string
name: unpack_data
arguments: data_label: D11
type_infered: string

tool: D17: Insert your max: 

tool: D25: %d

tool: D11: This is your result: %d


assistant: ```c
int main() {
  int max;
  int result;
  printf("Insert your max: ");
  scanf("%d", &max);
  result = ThreeAndFiveMultiples(max);
  printf("This is your result: %d\n", result);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <ThreeAndFiveMultiples@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D29
type: string

tool: D25: Insert your max: 

tool: D17: %d

tool: D29: This is your result: %d


assistant: ```c
int main() {
  int max;
  int result;
  printf("Insert your max: ");
  scanf("%d", &max);
  result = ThreeAndFiveMultiples(max);
  printf("This is your result: %d\n", result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<child>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x3,%edi
  call   <sleep@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: Child is done sleeping 3 seconds.


assistant: ```c
void *child(void *ignored) {
  sleep(3);
  printf("Child is done sleeping 3 seconds.\n");
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<child>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <sleep@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D5: Child is done sleeping 3 seconds.


assistant: ```c
void *child(void *ignored) {
  sleep(3);
  printf("Child is done sleeping 3 seconds.\n");
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<child>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <sleep@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: Child is done sleeping 3 seconds.


assistant: ```c
void *child(void *ignored) {
  sleep(3);
  printf("Child is done sleeping 3 seconds.\n");
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<child>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <sleep@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: Child is done sleeping 3 seconds.


assistant: ```c
void *child(void *ignored) {
  sleep(3);
  printf("Child is done sleeping 3 seconds.\n");
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fts3DoclistCountDocids>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L59
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L2
  jmp    L28
L24:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  not    %eax
  shr    $0x7,%al
  movzbl %al,%eax
  add    %eax,-0x1c(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  ja     L24
  jmp    L59
L70:
  addl   $0x1,-0x1c(%rbp)
  nop
L14:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  js     L14
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <fts3PoslistCopy@plt>
L2:
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  ja     L70
L59:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L71
  call   <__stack_chk_fail@plt>
L71:
  leave
  ret
```

assistant: ```c
int fts3DoclistCountDocids(int isPoslist, char *aList, int nList) {
  int nDoc = 0;
  if (aList) {
    char *aEnd = &aList[nList];
    char *p = aList;
    if (!isPoslist) {
      while (p < aEnd)
        nDoc += (((*p++) & 0x80) == 0);
    } else {
      while (p < aEnd) {
        nDoc++;
        while ((*p++) & 0x80)
          ;
        fts3PoslistCopy(0, &p);
      }
    }
  }
  return nDoc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fts3DoclistCountDocids>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  test   %rsi,%rsi
  je     L34
  movslq %edx,%rdx
  lea    (%rsi,%rdx,1),%rbp
  mov    %rsi,(%rsp)
  test   %edi,%edi
  je     L35
  mov    %rsp,%r12
  cmp    %rbp,%rsi
  jae    L34
L0:
  add    $0x1,%ebx
L58:
  mov    (%rsp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  cmpb   $0x0,(%rax)
  js     L58
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <fts3PoslistCopy@plt>
  cmp    %rbp,(%rsp)
  jb     L0
  jmp    L34
L35:
  cmp    %rbp,%rsi
  jae    L10
  lea    0x1(%rsi),%rax
  mov    %edi,%ebx
L81:
  mov    %rax,%rcx
  mov    %rax,(%rsp)
  movsbl -0x1(%rax),%edx
  not    %edx
  shr    $0x1f,%edx
  add    %edx,%ebx
  add    $0x1,%rax
  cmp    %rbp,%rcx
  jne    L81
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %edi,%ebx
  jmp    L34
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fts3DoclistCountDocids(int isPoslist, char *aList, int nList) {
  int nDoc = 0;
  if (aList) {
    char *aEnd = &aList[nList];
    char *p = aList;
    if (!isPoslist) {
      while (p < aEnd)
        nDoc += (((*p++) & 0x80) == 0);
    } else {
      while (p < aEnd) {
        nDoc++;
        while ((*p++) & 0x80)
          ;
        fts3PoslistCopy(0, &p);
      }
    }
  }
  return nDoc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fts3DoclistCountDocids>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L88
  movslq %edx,%rdx
  mov    %rsi,(%rsp)
  lea    (%rsi,%rdx,1),%rbx
  test   %edi,%edi
  jne    L30
  cmp    %rbx,%rsi
  jae    L88
  add    $0x1,%rsi
  nopl   0x0(%rax)
L62:
  movsbl -0x1(%rsi),%eax
  not    %eax
  shr    $0x1f,%eax
  add    %eax,%r12d
  mov    %rsi,%rax
  add    $0x1,%rsi
  cmp    %rax,%rbx
  jne    L62
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L30:
  mov    %rsp,%rbp
  cmp    %rbx,%rsi
  jae    L88
L85:
  add    $0x1,%r12d
  add    $0x1,%rsi
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rsi,(%rsp)
  add    $0x1,%rsi
  cmpb   $0x0,-0x2(%rsi)
  js     L0
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <fts3PoslistCopy@plt>
  mov    (%rsp),%rsi
  cmp    %rbx,%rsi
  jb     L85
  jmp    L88
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fts3DoclistCountDocids(int isPoslist, char *aList, int nList) {
  int nDoc = 0;
  if (aList) {
    char *aEnd = &aList[nList];
    char *p = aList;
    if (!isPoslist) {
      while (p < aEnd)
        nDoc += (((*p++) & 0x80) == 0);
    } else {
      while (p < aEnd) {
        nDoc++;
        while ((*p++) & 0x80)
          ;
        fts3PoslistCopy(0, &p);
      }
    }
  }
  return nDoc;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fts3DoclistCountDocids>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L77
  movslq %edx,%rdx
  mov    %rsi,(%rsp)
  lea    (%rsi,%rdx,1),%rbx
  test   %edi,%edi
  jne    L13
  cmp    %rbx,%rsi
  jae    L77
  add    $0x1,%rsi
  nopl   0x0(%rax)
L82:
  movsbl -0x1(%rsi),%eax
  not    %eax
  shr    $0x1f,%eax
  add    %eax,%r12d
  mov    %rsi,%rax
  add    $0x1,%rsi
  cmp    %rax,%rbx
  jne    L82
L77:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  mov    %rsp,%rbp
  cmp    %rbx,%rsi
  jae    L77
L24:
  add    $0x1,%r12d
  add    $0x1,%rsi
  nopl   0x0(%rax,%rax,1)
L75:
  mov    %rsi,(%rsp)
  add    $0x1,%rsi
  cmpb   $0x0,-0x2(%rsi)
  js     L75
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <fts3PoslistCopy@plt>
  mov    (%rsp),%rsi
  cmp    %rbx,%rsi
  jb     L24
  jmp    L77
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fts3DoclistCountDocids(int isPoslist, char *aList, int nList) {
  int nDoc = 0;
  if (aList) {
    char *aEnd = &aList[nList];
    char *p = aList;
    if (!isPoslist) {
      while (p < aEnd)
        nDoc += (((*p++) & 0x80) == 0);
    } else {
      while (p < aEnd) {
        nDoc++;
        while ((*p++) & 0x80)
          ;
        fts3PoslistCopy(0, &p);
      }
    }
  }
  return nDoc;
}
```