ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<make_box1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L77
L62:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  addl   $0x1,-0x8(%rbp)
L77:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L62
  movl   $0x0,-0x8(%rbp)
  jmp    L51
L40:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L40
  movl   $0x0,-0x8(%rbp)
  jmp    L63
L70:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L63:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L70
  movl   $0x1,-0x8(%rbp)
  jmp    L74
L24:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x40(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L74:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void make_box1(double *x, int N, double scal, int bs, int *box, int *lis, int *mxi) {
  int i, ix;
  for (i = 0; i <= bs; i++)
    box[i] = -1;
  for (i = 0; i <= bs; i++)
    mxi[i] = 0;
  for (i = 0; i < N; i++) {
    ix = (int)(x[i] * scal);
    lis[i] = box[ix];
    box[ix] = i;
    mxi[ix]++;
  }
  for (i = 1; i <= bs; i++)
    mxi[i] += mxi[i - 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_box1>:
  endbr64
  push   %rbx
  mov    %esi,%r11d
  mov    %edx,%r10d
  mov    %rcx,%rbx
  test   %edx,%edx
  js     L12
  mov    %rcx,%rax
  mov    %edx,%ecx
  shl    $0x2,%rcx
  lea    0x4(%rbx,%rcx,1),%rdx
L67:
  movl   $0xffffffff,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L67
  mov    %r9,%rax
  lea    0x4(%r9,%rcx,1),%rdx
L26:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L26
L12:
  test   %r11d,%r11d
  jle    L0
  mov    %r11d,%r11d
  mov    $0x0,%edx
L11:
  movapd %xmm0,%xmm1
  mulsd  (%rdi,%rdx,8),%xmm1
  cvttsd2si %xmm1,%eax
  cltq
  shl    $0x2,%rax
  lea    (%rbx,%rax,1),%rcx
  mov    (%rcx),%esi
  mov    %esi,(%r8,%rdx,4)
  mov    %edx,(%rcx)
  addl   $0x1,(%r9,%rax,1)
  add    $0x1,%rdx
  cmp    %r11,%rdx
  jne    L11
L0:
  test   %r10d,%r10d
  jle    L61
  lea    0x4(%r9),%rax
  lea    -0x1(%r10),%edx
  lea    0x8(%r9,%rdx,4),%rcx
L32:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L32
L61:
  pop    %rbx
  ret
```

assistant: ```c
void make_box1(double *x, int N, double scal, int bs, int *box, int *lis, int *mxi) {
  int i, ix;
  for (i = 0; i <= bs; i++)
    box[i] = -1;
  for (i = 0; i <= bs; i++)
    mxi[i] = 0;
  for (i = 0; i < N; i++) {
    ix = (int)(x[i] * scal);
    lis[i] = box[ix];
    box[ix] = i;
    mxi[ix]++;
  }
  for (i = 1; i <= bs; i++)
    mxi[i] += mxi[i - 1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<make_box1>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  js     L30
  movslq %edx,%rax
  mov    %rcx,%rdi
  mov    $0xff,%esi
  movsd  %xmm0,0x8(%rsp)
  lea    0x4(,%rax,4),%rdx
  mov    %rdx,(%rsp)
  call   <memset@plt>
  mov    (%rsp),%rdx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movsd  0x8(%rsp),%xmm0
L30:
  test   %r15d,%r15d
  jle    L32
  movslq %r15d,%rdi
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L0:
  movsd  (%r12,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  cltq
  shl    $0x2,%rax
  lea    0x0(%r13,%rax,1),%rcx
  mov    (%rcx),%esi
  mov    %esi,(%r14,%rdx,4)
  mov    %edx,(%rcx)
  add    $0x1,%rdx
  addl   $0x1,(%rbx,%rax,1)
  cmp    %rdx,%rdi
  jne    L0
L32:
  test   %ebp,%ebp
  jle    L44
  lea    -0x1(%rbp),%edx
  lea    0x4(%rbx),%rax
  lea    0x8(%rbx,%rdx,4),%rcx
  xchg   %ax,%ax
L5:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L5
L44:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void make_box1(double *x, int N, double scal, int bs, int *box, int *lis, int *mxi) {
  int i, ix;
  for (i = 0; i <= bs; i++)
    box[i] = -1;
  for (i = 0; i <= bs; i++)
    mxi[i] = 0;
  for (i = 0; i < N; i++) {
    ix = (int)(x[i] * scal);
    lis[i] = box[ix];
    box[ix] = i;
    mxi[ix]++;
  }
  for (i = 1; i <= bs; i++)
    mxi[i] += mxi[i - 1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<make_box1>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  test   %edx,%edx
  js     L26
  movslq %edx,%rax
  mov    %rcx,%rdi
  mov    $0xff,%esi
  movsd  %xmm0,0x8(%rsp)
  lea    0x4(,%rax,4),%rdx
  mov    %rdx,(%rsp)
  call   <memset@plt>
  mov    (%rsp),%rdx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  movsd  0x8(%rsp),%xmm0
L26:
  test   %r15d,%r15d
  jle    L9
  movslq %r15d,%rdi
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  (%r12,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  cltq
  shl    $0x2,%rax
  lea    0x0(%r13,%rax,1),%rcx
  mov    (%rcx),%esi
  mov    %esi,(%r14,%rdx,4)
  mov    %edx,(%rcx)
  add    $0x1,%rdx
  addl   $0x1,0x0(%rbp,%rax,1)
  cmp    %rdx,%rdi
  jne    L11
L9:
  test   %ebx,%ebx
  jle    L6
  lea    -0x1(%rbx),%ecx
  mov    0x0(%rbp),%edx
  lea    0x4(%rbp),%rax
  lea    0x8(%rbp,%rcx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L15:
  add    (%rax),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L15
L6:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void make_box1(double *x, int N, double scal, int bs, int *box, int *lis, int *mxi) {
  int i, ix;
  for (i = 0; i <= bs; i++)
    box[i] = -1;
  for (i = 0; i <= bs; i++)
    mxi[i] = 0;
  for (i = 0; i < N; i++) {
    ix = (int)(x[i] * scal);
    lis[i] = box[ix];
    box[ix] = i;
    mxi[ix]++;
  }
  for (i = 1; i <= bs; i++)
    mxi[i] += mxi[i - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L11
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *reverse(char *s) {
  int i;
  int j;
  char c;
  i = 0;
  j = ft_strlen(s) - 1;
  while (i < j) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
    i++;
    j--;
  }
  return (s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L4
  cltq
  mov    $0x0,%edx
L3:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L3
L4:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *reverse(char *s) {
  int i;
  int j;
  char c;
  i = 0;
  j = ft_strlen(s) - 1;
  while (i < j) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
    i++;
    j--;
  }
  return (s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <ft_strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L14
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax)
L10:
  movzbl (%r12,%rdx,1),%ecx
  movzbl (%r12,%rax,1),%esi
  mov    %sil,(%r12,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%r12,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L10
L14:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *reverse(char *s) {
  int i;
  int j;
  char c;
  i = 0;
  j = ft_strlen(s) - 1;
  while (i < j) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
    i++;
    j--;
  }
  return (s);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <ft_strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L19
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax)
L18:
  movzbl (%r12,%rdx,1),%ecx
  movzbl (%r12,%rax,1),%esi
  mov    %sil,(%r12,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%r12,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L18
L19:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *reverse(char *s) {
  int i;
  int j;
  char c;
  i = 0;
  j = ft_strlen(s) - 1;
  while (i < j) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
    i++;
    j--;
  }
  return (s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parser_log_enabled>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L14
L12:
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
L14:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D2
data_type: string

tool: D10: CHOPSUI_LOG

tool: D2: parser

assistant: ```c
bool parser_log_enabled() {
  const char *log = getenv("CHOPSUI_LOG");
  if (!log) {
    return false;
  }
  return strstr(log, "parser");
}
```
user: What is the c source code of the assembly code below:

```asm
<parser_log_enabled>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L7
  lea    D16(%rip),%rsi
  call   <strstr@plt>
L7:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D16
type: string

tool: D4: CHOPSUI_LOG

tool: D16: parser

assistant: ```c
bool parser_log_enabled() {
  const char *log = getenv("CHOPSUI_LOG");
  if (!log) {
    return false;
  }
  return strstr(log, "parser");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parser_log_enabled>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  lea    D17(%rip),%rsi
  add    $0x8,%rsp
  jmp    1070 <strstr@plt>
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string

tool: D7: CHOPSUI_LOG

tool: D17: parser

assistant: ```c
bool parser_log_enabled() {
  const char *log = getenv("CHOPSUI_LOG");
  if (!log) {
    return false;
  }
  return strstr(log, "parser");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parser_log_enabled>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  lea    D0(%rip),%rsi
  add    $0x8,%rsp
  jmp    1070 <strstr@plt>
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string
name: unpack_data
arguments: data_tag: D0
data_type: string

tool: D9: CHOPSUI_LOG

tool: D0: parser

assistant: ```c
bool parser_log_enabled() {
  const char *log = getenv("CHOPSUI_LOG");
  if (!log) {
    return false;
  }
  return strstr(log, "parser");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<drv_LT_defchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  or     $0x40,%eax
  mov    %eax,%edi
  call   <drv_LT_command@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L2:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x1f,%eax
  mov    %eax,%esi
  mov    $0x14,%edi
  call   <drv_LT_send@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x7,-0x4(%rbp)
  jle    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void drv_LT_defchar(const int ascii, const unsigned char *matrix) {
  int i;
  drv_LT_command(0x40 | 8 * ascii);
  for (i = 0; i < 8; i++) {
    drv_LT_send(0x14, *matrix++ & 0x1f);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<drv_LT_defchar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  shl    $0x3,%edi
  or     $0x40,%edi
  call   <drv_LT_command@plt>
  lea    0x8(%rbx),%rbp
L5:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  and    $0x1f,%esi
  mov    $0x14,%edi
  call   <drv_LT_send@plt>
  cmp    %rbx,%rbp
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drv_LT_defchar(const int ascii, const unsigned char *matrix) {
  int i;
  drv_LT_command(0x40 | 8 * ascii);
  for (i = 0; i < 8; i++) {
    drv_LT_send(0x14, *matrix++ & 0x1f);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drv_LT_defchar>:
  endbr64
  push   %rbp
  shl    $0x3,%edi
  push   %rbx
  or     $0x40,%edi
  mov    %rsi,%rbx
  lea    0x8(%rbx),%rbp
  sub    $0x8,%rsp
  call   <drv_LT_command@plt>
  nopl   0x0(%rax)
L4:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  mov    $0x14,%edi
  and    $0x1f,%esi
  call   <drv_LT_send@plt>
  cmp    %rbx,%rbp
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drv_LT_defchar(const int ascii, const unsigned char *matrix) {
  int i;
  drv_LT_command(0x40 | 8 * ascii);
  for (i = 0; i < 8; i++) {
    drv_LT_send(0x14, *matrix++ & 0x1f);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<drv_LT_defchar>:
  endbr64
  push   %rbp
  shl    $0x3,%edi
  push   %rbx
  or     $0x40,%edi
  mov    %rsi,%rbx
  lea    0x8(%rbx),%rbp
  sub    $0x8,%rsp
  call   <drv_LT_command@plt>
  nopl   0x0(%rax)
L6:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  mov    $0x14,%edi
  and    $0x1f,%esi
  call   <drv_LT_send@plt>
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drv_LT_defchar(const int ascii, const unsigned char *matrix) {
  int i;
  drv_LT_command(0x40 | 8 * ascii);
  for (i = 0; i < 8; i++) {
    drv_LT_send(0x14, *matrix++ & 0x1f);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wcsicmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <towlower@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <towlower@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L43
  mov    -0x4(%rbp),%eax
  jmp    L44
L43:
  cmpl   $0x0,-0xc(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L44
L34:
  addq   $0x4,-0x18(%rbp)
  addq   $0x4,-0x20(%rbp)
  jmp    L26
L44:
  leave
  ret
```

assistant: ```c
int wcsicmp(const wchar_t *s1, const wchar_t *s2) {
  for (;;) {
    int lc1 = towlower(*s1);
    int lc2 = towlower(*s2);
    int diff = lc1 - lc2;
    if (diff != 0)
      return diff;
    if (!lc1)
      return 0;
    ++s1;
    ++s2;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wcsicmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  jmp    L26
L23:
  add    $0x4,%r12
  add    $0x4,%rbp
L26:
  mov    (%r12),%edi
  call   <towlower@plt>
  mov    %eax,%ebx
  mov    0x0(%rbp),%edi
  call   <towlower@plt>
  mov    %ebx,%edx
  sub    %eax,%edx
  jne    L27
  test   %ebx,%ebx
  jne    L23
  mov    %ebx,%edx
L27:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wcsicmp(const wchar_t *s1, const wchar_t *s2) {
  for (;;) {
    int lc1 = towlower(*s1);
    int lc2 = towlower(*s2);
    int diff = lc1 - lc2;
    if (diff != 0)
      return diff;
    if (!lc1)
      return 0;
    ++s1;
    ++s2;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wcsicmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L5
L26:
  test   %ebx,%ebx
  je     L21
  add    $0x4,%r12
  add    $0x4,%rbp
L5:
  mov    (%r12),%edi
  call   <towlower@plt>
  mov    0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <towlower@plt>
  mov    %ebx,%r8d
  sub    %eax,%r8d
  je     L26
L21:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wcsicmp(const wchar_t *s1, const wchar_t *s2) {
  for (;;) {
    int lc1 = towlower(*s1);
    int lc2 = towlower(*s2);
    int diff = lc1 - lc2;
    if (diff != 0)
      return diff;
    if (!lc1)
      return 0;
    ++s1;
    ++s2;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wcsicmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L12
L1:
  test   %ebx,%ebx
  je     L15
  add    $0x4,%r12
  add    $0x4,%rbp
L12:
  mov    (%r12),%edi
  call   <towlower@plt>
  mov    0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <towlower@plt>
  mov    %ebx,%r8d
  sub    %eax,%r8d
  je     L1
L15:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wcsicmp(const wchar_t *s1, const wchar_t *s2) {
  for (;;) {
    int lc1 = towlower(*s1);
    int lc2 = towlower(*s2);
    int diff = lc1 - lc2;
    if (diff != 0)
      return diff;
    if (!lc1)
      return 0;
    ++s1;
    ++s2;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ulz_fprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xe0,%rsp
  mov    %edi,-0x10d4(%rbp)
  mov    %rsi,-0x10e0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L27
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L27:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x10e0(%rbp),%rdx
  mov    -0x10cc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x10cc(%rbp),%ecx
  mov    -0x10e0(%rbp),%rdx
  lea    -0x10c0(%rbp),%rax
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <ulz_vsnprintf@plt>
  mov    %rax,-0x10c8(%rbp)
  mov    -0x10cc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpq   $0x0,-0x10c8(%rbp)
  je     L9
  mov    -0x10c8(%rbp),%rdx
  lea    -0x10c0(%rbp),%rcx
  mov    -0x10d4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
L9:
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
__attribute__((format(printf, 2, 3))) void ulz_fprintf(int fd, const char *fmt, ...) {
  char dest[4096];
  va_list ap;
  va_start(ap, fmt);
  ssize_t result = ulz_vsnprintf(dest, sizeof(dest), fmt, ap);
  va_end(ap);
  if (result) {
    write(fd, dest, result);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ulz_fprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x1000,%esi
  call   <ulz_vsnprintf@plt>
  mov    %rax,%rbx
  mov    %ebp,%edi
  call   <va_end@plt>
  test   %rbx,%rbx
  jne    L23
L15:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    %rsp,%rsi
  mov    %rbx,%rdx
  mov    %r12d,%edi
  call   <write@plt>
  jmp    L15
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((format(printf, 2, 3))) void ulz_fprintf(int fd, const char *fmt, ...) {
  char dest[4096];
  va_list ap;
  va_start(ap, fmt);
  ssize_t result = ulz_vsnprintf(dest, sizeof(dest), fmt, ap);
  va_end(ap);
  if (result) {
    write(fd, dest, result);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ulz_fprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  xor    %ebp,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsi,%r12
  mov    %edi,%r13d
  mov    %rsp,%r14
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %r14,%rdi
  mov    %ebp,%ecx
  mov    $0x1000,%esi
  call   <ulz_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  test   %r12,%r12
  jne    L22
L24:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x1018,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  jmp    L24
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((format(printf, 2, 3))) void ulz_fprintf(int fd, const char *fmt, ...) {
  char dest[4096];
  va_list ap;
  va_start(ap, fmt);
  ssize_t result = ulz_vsnprintf(dest, sizeof(dest), fmt, ap);
  va_end(ap);
  if (result) {
    write(fd, dest, result);
  }
}
```