ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dub_rot>:
  endbr64
  push   %r15
  mov    %rdi,%rax
  movslq %esi,%r9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  movslq %ecx,%rdx
  mov    %rbp,%r8
  push   %rbx
  lea    0x1(%rdx),%r14
  lea    0x4(,%r9,4),%rbx
  sub    %rdx,%r8
  lea    (%rax,%rbx,1),%r11
  mov    %rbp,%rdi
  lea    0x4(%rax,%r8,4),%r15
  movslq (%r11),%rcx
  movslq (%r15),%r10
  lea    (%r10,%r14,1),%r12
  mov    %r10,%r8
  lea    (%rax,%r12,4),%r12
  movslq (%r12),%r13
  mov    %r13d,(%r15)
  test   %r13d,%r13d
  je     L3
  mov    %ebp,0x4(%rax,%r13,4)
L3:
  mov    %r10,%r13
  add    %r14,%r9
  sub    %rdx,%r13
  lea    0x4(%rax,%r13,4),%r13
  movslq 0x0(%r13),%rdx
  mov    %edx,(%rax,%r9,4)
  test   %edx,%edx
  je     L11
  mov    %esi,0x4(%rax,%rdx,4)
L11:
  lea    0xc(,%r10,4),%r9
  mov    %edi,(%r12)
  lea    0x8(%rax,%rbx,1),%rbx
  lea    0xc(,%rbp,4),%r10
  mov    %esi,0x0(%r13)
  lea    (%rax,%r9,1),%rdx
  xor    %ebp,%ebp
  lea    (%rax,%r10,1),%r12
  mov    (%r12),%r13d
  mov    %r13d,%edi
  neg    %edi
  cmp    %r13d,(%rdx)
  cmovne %ebp,%edi
  mov    %edi,(%r12)
  mov    (%rbx),%r12d
  mov    %r12d,%edi
  neg    %edi
  cmp    %r12d,(%rdx)
  cmovne %ebp,%edi
  mov    %edi,(%rbx)
  movl   $0x0,(%rdx)
  mov    %r8d,-0x8(%rax,%r10,1)
  mov    %r8d,(%r11)
  mov    %ecx,-0x8(%rax,%r9,1)
  test   %ecx,%ecx
  jle    L29
  lea    (%rax,%rcx,4),%rdx
  lea    0x4(,%rcx,4),%rdi
  cmp    %esi,(%rdx)
  je     L35
  lea    0x4(%rax,%rdi,1),%rdx
L35:
  mov    %r8d,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  pop    %rbx
  pop    %rbp
  mov    %r8d,0x4(%rax)
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void dub_rot(int *root, int parent, int child, int dir) {
  int gparent = *(root + parent + 1);
  int gchild = *(root + child + 1 - dir);
  *(root + child + 1 - dir) = *(root + gchild + 1 + dir);
  if (*(root + gchild + 1 + dir))
    *(root + *(root + gchild + 1 + dir) + 1) = child;
  *(root + parent + 1 + dir) = *(root + gchild + 1 - dir);
  if (*(root + gchild + 1 - dir))
    *(root + *(root + gchild + 1 - dir) + 1) = parent;
  *(root + gchild + 1 + dir) = child;
  *(root + gchild + 1 - dir) = parent;
  if (*(root + gchild + 3) == *(root + child + 3))
    *(root + child + 3) *= -1;
  else
    *(root + child + 3) = 0;
  if (*(root + gchild + 3) == *(root + parent + 3))
    *(root + parent + 3) *= -1;
  else
    *(root + parent + 3) = 0;
  *(root + gchild + 3) = 0;
  *(root + child + 1) = gchild;
  *(root + parent + 1) = gchild;
  *(root + gchild + 1) = gparent;
  if (gparent > 0)
    *(root + gparent + 1 + (*(root + gparent + 1 + -1) == parent ? -1 : 1)) = gchild;
  else
    *(root + 1) = gchild;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<handleinterupt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L14
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%eax
  call   <clear@plt>
  jmp    L13
L14:
  mov    $0x0,%eax
  call   <exitapp@plt>
L13:
  leave
  ret
```

assistant: ```c
void handleinterupt(int signum) {
  if (signum == SIGWINCH) {
    endwin();
    refresh();
    clear();
    return;
  } else {
    exitapp();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<handleinterupt>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  cmp    %edi,(%rax)
  je     L1
  mov    $0x0,%eax
  call   <exitapp@plt>
L11:
  add    $0x8,%rsp
  ret
L1:
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%eax
  call   <clear@plt>
  jmp    L11
```

assistant: ```c
void handleinterupt(int signum) {
  if (signum == SIGWINCH) {
    endwin();
    refresh();
    clear();
    return;
  } else {
    exitapp();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<handleinterupt>:
  endbr64
  mov    D6(%rip),%rax
  cmp    %edi,(%rax)
  je     L5
  xor    %eax,%eax
  jmp    10a0 <exitapp@plt>
  cs nopw 0x0(%rax,%rax,1)
L5:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <clear@plt>
```

assistant: ```c
void handleinterupt(int signum) {
  if (signum == SIGWINCH) {
    endwin();
    refresh();
    clear();
    return;
  } else {
    exitapp();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<handleinterupt>:
  endbr64
  mov    D4(%rip),%rax
  cmp    %edi,(%rax)
  je     L2
  xor    %eax,%eax
  jmp    10a0 <exitapp@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <clear@plt>
```

assistant: ```c
void handleinterupt(int signum) {
  if (signum == SIGWINCH) {
    endwin();
    refresh();
    clear();
    return;
  } else {
    exitapp();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_quote>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L17
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L15
L26:
  mov    $0x5c,%edi
  call   <putchar@plt>
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_quote(char *p) {
  while (*p) {
    if (*p == '\"' || *p == '\\') {
      printf("\\");
    }
    printf("%c", *p);
    p++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_quote>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
L3:
  pop    %rbx
  ret
L19:
  mov    $0x5c,%edi
  call   <putchar@plt>
L21:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L3
L7:
  cmp    $0x22,%al
  je     L19
  cmp    $0x5c,%al
  jne    L21
  jmp    L19
```

assistant: ```c
void print_quote(char *p) {
  while (*p) {
    if (*p == '\"' || *p == '\\') {
      printf("\\");
    }
    printf("%c", *p);
    p++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<print_quote>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  push   %rbx
  mov    %rdi,%rbx
  jmp    L7
  nopl   0x0(%rax)
L6:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L50
L7:
  cmp    $0x22,%al
  je     L43
  cmp    $0x5c,%al
  jne    L6
L43:
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L6
  nop
L50:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void print_quote(char *p) {
  while (*p) {
    if (*p == '\"' || *p == '\\') {
      printf("\\");
    }
    printf("%c", *p);
    p++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_quote>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L24
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L23:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L28
L24:
  cmp    $0x22,%dil
  je     L40
  cmp    $0x5c,%dil
  jne    L23
L40:
  mov    $0x5c,%edi
  call   <putchar@plt>
  movsbl (%rbx),%edi
  jmp    L23
  nopl   (%rax)
L28:
  pop    %rbx
  ret
```

assistant: ```c
void print_quote(char *p) {
  while (*p) {
    if (*p == '\"' || *p == '\\') {
      printf("\\");
    }
    printf("%c", *p);
    p++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parseArgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x10(%rbp)
  jmp    L17
L25:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L47
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
  and    $0x1f,%eax
  test   %eax,%eax
  jne    L8
  mov    -0x10(%rbp),%eax
  add    $0x20,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x10(%rbp)
L47:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **parseArgs(char *s, int *argc, char split) {
  int args = 0;
  int i = 0;
  char **argv = (char **)malloc(sizeof(char *) * 32);
  if (s[0]) {
    argv[0] = s;
    args++;
  }
  while (s[i]) {
    if (s[i] == split) {
      s[i] = 0;
      if (args % 32 == 0) {
        argv = (char **)realloc(argv, sizeof(char *) * (args + 32));
      }
      argv[args] = &s[i + 1];
      args++;
    }
    i++;
  }
  *argc = args;
  return argv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parseArgs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %edx,%r12d
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    $0x0,%ebp
  cmpb   $0x0,(%rbx)
  je     L13
  mov    %rbx,(%rax)
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L40
  add    $0x1,%rbx
  mov    $0x1,%ebp
  jmp    L29
L9:
  movslq %ebp,%rdx
  mov    %r14,(%rax,%rdx,8)
  add    $0x1,%ebp
L46:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edx
  test   %dl,%dl
  je     L13
L29:
  cmp    %dl,%r12b
  jne    L46
  mov    %rbx,%r14
  movb   $0x0,-0x1(%rbx)
  test   $0x1f,%bpl
  jne    L9
  lea    0x100(,%rbp,8),%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  jmp    L9
L40:
  mov    $0x1,%ebp
L13:
  mov    %ebp,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char **parseArgs(char *s, int *argc, char split) {
  int args = 0;
  int i = 0;
  char **argv = (char **)malloc(sizeof(char *) * 32);
  if (s[0]) {
    argv[0] = s;
    args++;
  }
  while (s[i]) {
    if (s[i] == split) {
      s[i] = 0;
      if (args % 32 == 0) {
        argv = (char **)realloc(argv, sizeof(char *) * (args + 32));
      }
      argv[args] = &s[i + 1];
      args++;
    }
    i++;
  }
  *argc = args;
  return argv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parseArgs>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  cmpb   $0x0,(%rbx)
  je     L12
  mov    %rbx,(%rax)
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L58
  add    $0x1,%rbx
  mov    $0x1,%ebp
  jmp    L60
  nopl   (%rax)
L41:
  movzbl (%rbx),%ecx
  add    $0x1,%rbx
  test   %cl,%cl
  je     L12
L60:
  cmp    %cl,%r13b
  jne    L41
  movb   $0x0,-0x1(%rbx)
  test   $0x1f,%bpl
  je     L89
L77:
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %rbx,(%rax,%rdx,8)
  movzbl (%rbx),%ecx
  add    $0x1,%rbx
  test   %cl,%cl
  jne    L60
L12:
  mov    %ebp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L89:
  lea    0x100(,%rbp,8),%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  jmp    L77
L58:
  mov    $0x1,%ebp
  jmp    L12
```

assistant: ```c
char **parseArgs(char *s, int *argc, char split) {
  int args = 0;
  int i = 0;
  char **argv = (char **)malloc(sizeof(char *) * 32);
  if (s[0]) {
    argv[0] = s;
    args++;
  }
  while (s[i]) {
    if (s[i] == split) {
      s[i] = 0;
      if (args % 32 == 0) {
        argv = (char **)realloc(argv, sizeof(char *) * (args + 32));
      }
      argv[args] = &s[i + 1];
      args++;
    }
    i++;
  }
  *argc = args;
  return argv;
}
```
user: What is the c source code of the assembly code below:

```asm
<parseArgs>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  cmpb   $0x0,(%rbx)
  je     L25
  mov    %rbx,(%rax)
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L63
  add    $0x1,%rbx
  mov    $0x1,%ebp
  jmp    L68
  nopl   (%rax)
L73:
  movzbl (%rbx),%ecx
  add    $0x1,%rbx
  test   %cl,%cl
  je     L25
L68:
  cmp    %cl,%r13b
  jne    L73
  movb   $0x0,-0x1(%rbx)
  test   $0x1f,%bpl
  je     L0
L3:
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %rbx,(%rax,%rdx,8)
  movzbl (%rbx),%ecx
  add    $0x1,%rbx
  test   %cl,%cl
  jne    L68
L25:
  mov    %ebp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L0:
  lea    0x100(,%rbp,8),%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  jmp    L3
L63:
  mov    $0x1,%ebp
  jmp    L25
```

assistant: ```c
char **parseArgs(char *s, int *argc, char split) {
  int args = 0;
  int i = 0;
  char **argv = (char **)malloc(sizeof(char *) * 32);
  if (s[0]) {
    argv[0] = s;
    args++;
  }
  while (s[i]) {
    if (s[i] == split) {
      s[i] = 0;
      if (args % 32 == 0) {
        argv = (char **)realloc(argv, sizeof(char *) * (args + 32));
      }
      argv[args] = &s[i + 1];
      args++;
    }
    i++;
  }
  *argc = args;
  return argv;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x5,%edi
  call   <QUEUEinit@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <QUEUEput@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0x4,-0x8(%rbp)
  jle    L4
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L25:
  mov    $0x0,%eax
  call   <QUEUEget@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L3:
  cmpl   $0x4,-0x8(%rbp)
  jle    L25
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string
name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D0: Putting: %i


tool: D9: Getting: %i


assistant: ```c
int main(void) {
  int i, t;
  srand(time(NULL));
  QUEUEinit(5);
  for (i = 0; i < 5; ++i) {
    t = rand() % 100;
    QUEUEput(t);
    printf("Putting: %i\n", t);
  }
  for (i = 0; i < 5; ++i) {
    t = QUEUEget();
    printf("Getting: %i\n", t);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x5,%edi
  call   <QUEUEinit@plt>
  mov    $0x5,%ebp
  lea    D4(%rip),%r12
L17:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rbx
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x25,%rbx
  cltd
  sub    %edx,%ebx
  imul   $0x64,%ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <QUEUEput@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L17
  mov    $0x5,%ebx
  lea    D7(%rip),%rbp
L11:
  mov    $0x0,%eax
  call   <QUEUEget@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L11
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D4: Putting: %i


tool: D7: Getting: %i


assistant: ```c
int main(void) {
  int i, t;
  srand(time(NULL));
  QUEUEinit(5);
  for (i = 0; i < 5; ++i) {
    t = rand() % 100;
    QUEUEput(t);
    printf("Putting: %i\n", t);
  }
  for (i = 0; i < 5; ++i) {
    t = QUEUEget();
    printf("Getting: %i\n", t);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x5,%edi
  call   <QUEUEinit@plt>
L11:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rbp
  cltd
  imul   $0x51eb851f,%rbp,%rbp
  sar    $0x25,%rbp
  sub    %edx,%ebp
  imul   $0x64,%ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <QUEUEput@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L11
  mov    $0x5,%ebx
  lea    D12(%rip),%rbp
L6:
  xor    %eax,%eax
  call   <QUEUEget@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string

tool: D16: Putting: %i


tool: D12: Getting: %i


assistant: ```c
int main(void) {
  int i, t;
  srand(time(NULL));
  QUEUEinit(5);
  for (i = 0; i < 5; ++i) {
    t = rand() % 100;
    QUEUEput(t);
    printf("Putting: %i\n", t);
  }
  for (i = 0; i < 5; ++i) {
    t = QUEUEget();
    printf("Getting: %i\n", t);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x5,%edi
  call   <QUEUEinit@plt>
L0:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rbp
  cltd
  imul   $0x51eb851f,%rbp,%rbp
  sar    $0x25,%rbp
  sub    %edx,%ebp
  imul   $0x64,%ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <QUEUEput@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L0
  mov    $0x5,%ebx
  lea    D6(%rip),%rbp
L4:
  xor    %eax,%eax
  call   <QUEUEget@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type: string
name: read_data
arguments: data_tag: D6
type: string

tool: D14: Putting: %i


tool: D6: Getting: %i


assistant: ```c
int main(void) {
  int i, t;
  srand(time(NULL));
  QUEUEinit(5);
  for (i = 0; i < 5; ++i) {
    t = rand() % 100;
    QUEUEput(t);
    printf("Putting: %i\n", t);
  }
  for (i = 0; i < 5; ++i) {
    t = QUEUEget();
    printf("Getting: %i\n", t);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L26:
  movss  -0x18(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L26
  pxor   %xmm2,%xmm2
  cvtss2sd -0x10(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D22
type_infered: string
name: disassemble_data
arguments: tag: D25
type_infered: string
name: disassemble_data
arguments: tag: D29
type_infered: string

tool: D22: Enter 2 numbers to be added: 
 

tool: D25: %f %f

tool: D29: The sum is %.2f.

assistant: ```c
void add(int MAX) {
  float x, y, sum;
  printf("Enter 2 numbers to be added: \n ");
  scanf("%f %f", &x, &y);
  for (int i = 0; i < MAX; i++) {
    sum = x + y;
  }
  printf("The sum is %.2f.", sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  test   %ebx,%ebx
  jle    L2
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  mov    $0x0,%eax
L17:
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L17
L2:
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  lea    D29(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D29
data_type: string

tool: D13: Enter 2 numbers to be added: 
 

tool: D5: %f %f

tool: D29: The sum is %.2f.

assistant: ```c
void add(int MAX) {
  float x, y, sum;
  printf("Enter 2 numbers to be added: \n ");
  scanf("%f %f", &x, &y);
  for (int i = 0; i < MAX; i++) {
    sum = x + y;
  }
  printf("The sum is %.2f.", sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add>:
  endbr64
  push   %r14
  push   %rbx
  mov    %edi,%ebx
  lea    D12(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  test   %ebx,%ebx
  jle    L15
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  movd   %xmm0,%r14d
L15:
  movd   %r14d,%xmm1
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D26(%rip),%rdi
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D29
type_infered: string
name: read_data
arguments: label: D26
type_infered: string

tool: D12: Enter 2 numbers to be added: 
 

tool: D29: %f %f

tool: D26: The sum is %.2f.

assistant: ```c
void add(int MAX) {
  float x, y, sum;
  printf("Enter 2 numbers to be added: \n ");
  scanf("%f %f", &x, &y);
  for (int i = 0; i < MAX; i++) {
    sum = x + y;
  }
  printf("The sum is %.2f.", sum);
}
```