ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x5b,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L18
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string

tool: D15: %d,

tool: D13: %d]


assistant: ```c
void print_array(int *array, int size) {
  printf("[");
  for (int i = 0; i < size - 1; i++) {
    printf("%d,", array[i]);
  }
  printf("%d]\n", array[size - 1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_array>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    $0x5b,%edi
  call   <putchar@plt>
  cmp    $0x1,%r13d
  jle    L0
  mov    %r14,%rbx
  lea    -0x2(%r13),%eax
  lea    0x4(%r14,%rax,4),%r12
  lea    D18(%rip),%rbp
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L18
L0:
  movslq %r13d,%r13
  mov    -0x4(%r14,%r13,4),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string

tool: D18: %d,

tool: D13: %d]


assistant: ```c
void print_array(int *array, int size) {
  printf("[");
  for (int i = 0; i < size - 1; i++) {
    printf("%d,", array[i]);
  }
  printf("%d]\n", array[size - 1]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_array>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    $0x5b,%edi
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <putchar@plt>
  cmp    $0x1,%r13d
  jle    L9
  lea    -0x2(%r13),%eax
  mov    %r14,%rbx
  lea    D10(%rip),%rbp
  lea    0x4(%r14,%rax,4),%r12
  nopl   (%rax)
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
L9:
  mov    -0x4(%r14,%r13,4),%esi
  pop    %rbx
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D10: %d,

tool: D15: %d]


assistant: ```c
void print_array(int *array, int size) {
  printf("[");
  for (int i = 0; i < size - 1; i++) {
    printf("%d,", array[i]);
  }
  printf("%d]\n", array[size - 1]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_array>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    $0x5b,%edi
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <putchar@plt>
  cmp    $0x1,%r13d
  jle    L17
  lea    -0x2(%r13),%eax
  mov    %r14,%rbx
  lea    D10(%rip),%rbp
  lea    0x4(%r14,%rax,4),%r12
  nopl   (%rax)
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
L17:
  mov    -0x4(%r14,%r13,4),%esi
  pop    %rbx
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D7
type_infered: string

tool: D10: %d,

tool: D7: %d]


assistant: ```c
void print_array(int *array, int size) {
  printf("[");
  for (int i = 0; i < size - 1; i++) {
    printf("%d,", array[i]);
  }
  printf("%d]\n", array[size - 1]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  -0x30(%rbp),%xmm1
  movss  -0x2c(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x28(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  D33(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x24(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x24(%rbp),%xmm2
  movq   %xmm2,%rdx
  lea    -0x20(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D85
type_infered: string
name: read_data
arguments: label: D73
type_infered: string
name: read_data
arguments: label: D61
type_infered: string
name: read_data
arguments: label: D27
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D33
type_infered: byte[4]
name: read_data
arguments: label: D18
type_infered: string

tool: D5: Nome: 

tool: D85: %s

tool: D73: Nota 1: 

tool: D61: %f

tool: D27: Nota 2: 

tool: D25: Nota 3: 

tool: {"D33": [0x00,0x00,0x40,0x40]}

tool: D18: 
Nome: %s - Media: %f

assistant: ```c
main() {
  char nome[20];
  float nota1, nota2, nota3, media;
  printf("Nome: ");
  scanf("%s", &nome);
  printf("Nota 1: ");
  scanf("%f", &nota1);
  printf("Nota 2: ");
  scanf("%f", &nota2);
  printf("Nota 3: ");
  scanf("%f", &nota3);
  media = (nota1 + nota2 + nota3) / 3;
  printf("\nNome: %s - Media: %f", nome, media);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D53(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  addss  0x8(%rsp),%xmm0
  addss  0xc(%rsp),%xmm0
  divss  D7(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D50
type: string
name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D45
type: string
name: retrieve_data
arguments: tag: D53
type: string
name: retrieve_data
arguments: tag: D16
type: string
name: retrieve_data
arguments: tag: D4
type: string
name: retrieve_data
arguments: tag: D7
type: byte[4]
name: retrieve_data
arguments: tag: D21
type: string

tool: D50: Nome: 

tool: D18: %s

tool: D45: Nota 1: 

tool: D53: %f

tool: D16: Nota 2: 

tool: D4: Nota 3: 

tool: {"D7": [0x00,0x00,0x40,0x40]}

tool: D21: 
Nome: %s - Media: %f

assistant: ```c
main() {
  char nome[20];
  float nota1, nota2, nota3, media;
  printf("Nome: ");
  scanf("%s", &nome);
  printf("Nota 1: ");
  scanf("%f", &nota1);
  printf("Nota 2: ");
  scanf("%f", &nota2);
  printf("Nota 3: ");
  scanf("%f", &nota3);
  media = (nota1 + nota2 + nota3) / 3;
  printf("\nNome: %s - Media: %f", nome, media);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D27(%rip),%rdi
  push   %rbp
  lea    D73(%rip),%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    $0x1,%eax
  lea    D51(%rip),%rdi
  movss  0x4(%rsp),%xmm0
  addss  0x8(%rsp),%xmm0
  addss  0xc(%rsp),%xmm0
  divss  D11(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D27
type: string
name: disassemble_data
arguments: tag: D73
type: string
name: disassemble_data
arguments: tag: D58
type: string
name: disassemble_data
arguments: tag: D44
type: string
name: disassemble_data
arguments: tag: D55
type: string
name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D51
type: string
name: disassemble_data
arguments: tag: D11
type: byte[4]

tool: D27: Nome: 

tool: D73: %f

tool: D58: %s

tool: D44: Nota 1: 

tool: D55: Nota 2: 

tool: D17: Nota 3: 

tool: D51: 
Nome: %s - Media: %f

tool: {"D11": [0x00,0x00,0x40,0x40]}

assistant: ```c
main() {
  char nome[20];
  float nota1, nota2, nota3, media;
  printf("Nome: ");
  scanf("%s", &nome);
  printf("Nota 1: ");
  scanf("%f", &nota1);
  printf("Nota 2: ");
  scanf("%f", &nota2);
  printf("Nota 3: ");
  scanf("%f", &nota3);
  media = (nota1 + nota2 + nota3) / 3;
  printf("\nNome: %s - Media: %f", nome, media);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  push   %rbp
  lea    D8(%rip),%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D71(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    $0x1,%eax
  lea    D24(%rip),%rdi
  movss  0x4(%rsp),%xmm0
  addss  0x8(%rsp),%xmm0
  addss  0xc(%rsp),%xmm0
  divss  D55(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D71
type_infered: string
name: parse_data
arguments: data_label: D5
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string
name: parse_data
arguments: data_label: D48
type_infered: string
name: parse_data
arguments: data_label: D24
type_infered: string
name: parse_data
arguments: data_label: D55
type_infered: byte[4]

tool: D16: Nome: 

tool: D8: %f

tool: D71: %s

tool: D5: Nota 1: 

tool: D27: Nota 2: 

tool: D48: Nota 3: 

tool: D24: 
Nome: %s - Media: %f

tool: {"D55": [0x00,0x00,0x40,0x40]}

assistant: ```c
main() {
  char nome[20];
  float nota1, nota2, nota3, media;
  printf("Nome: ");
  scanf("%s", &nome);
  printf("Nota 1: ");
  scanf("%f", &nota1);
  printf("Nota 2: ");
  scanf("%f", &nota2);
  printf("Nota 3: ");
  scanf("%f", &nota3);
  media = (nota1 + nota2 + nota3) / 3;
  printf("\nNome: %s - Media: %f", nome, media);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isReadWriteable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L8
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L13
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L13:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L21
L8:
  mov    $0x0,%eax
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string

tool: D4: r+

tool: D17: ftell()

assistant: ```c
bool isReadWriteable(const char *filename) {
  FILE *fp = fopen(filename, "r+");
  if (fp != NULL) {
    long pos = ftell(fp);
    if (pos < 0L)
      perror("ftell()");
    fclose(fp);
    return true;
  } else {
    return false;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isReadWriteable>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L7
  mov    %rbx,%rdi
  call   <ftell@plt>
  test   %rax,%rax
  js     L9
L18:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L7:
  pop    %rbx
  ret
L9:
  lea    D11(%rip),%rdi
  call   <perror@plt>
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
datatype: string
name: extract_symbolic_data
arguments: data_label: D11
datatype: string

tool: D10: r+

tool: D11: ftell()

assistant: ```c
bool isReadWriteable(const char *filename) {
  FILE *fp = fopen(filename, "r+");
  if (fp != NULL) {
    long pos = ftell(fp);
    if (pos < 0L)
      perror("ftell()");
    fclose(fp);
    return true;
  } else {
    return false;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isReadWriteable>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  test   %rbp,%rbp
  je     L7
  mov    %rbp,%rdi
  call   <ftell@plt>
  test   %rax,%rax
  js     L0
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L7:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L7
```

tool_calls: name: read_data
arguments: label: D12
type_guessed: string
name: read_data
arguments: label: D9
type_guessed: string

tool: D12: r+

tool: D9: ftell()

assistant: ```c
bool isReadWriteable(const char *filename) {
  FILE *fp = fopen(filename, "r+");
  if (fp != NULL) {
    long pos = ftell(fp);
    if (pos < 0L)
      perror("ftell()");
    fclose(fp);
    return true;
  } else {
    return false;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isReadWriteable>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  test   %rbp,%rbp
  je     L1
  mov    %rbp,%rdi
  call   <ftell@plt>
  test   %rax,%rax
  js     L4
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L1:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D10
type_guessed: string
name: read_data
arguments: label: D6
type_guessed: string

tool: D10: r+

tool: D6: ftell()

assistant: ```c
bool isReadWriteable(const char *filename) {
  FILE *fp = fopen(filename, "r+");
  if (fp != NULL) {
    long pos = ftell(fp);
    if (pos < 0L)
      perror("ftell()");
    fclose(fp);
    return true;
  } else {
    return false;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<insert_bdp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x8000,%eax
  test   %rax,%rax
  jne    L1
  orq    $0x200000,-0x8(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  and    $0xfffc,%eax
  or     -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long insert_bdp(insn, value, errmsg)
unsigned long insn;
long value;
const char **errmsg;
{
  if ((value & 0x8000) == 0)
    insn |= 1 << 21;
  return insn | (value & 0xfffc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_bdp>:
  endbr64
  mov    %rdi,%rax
  or     $0x200000,%rax
  test   $0x8000,%esi
  cmove  %rax,%rdi
  and    $0xfffc,%esi
  mov    %rsi,%rax
  or     %rdi,%rax
  ret
```

assistant: ```c
unsigned long insert_bdp(insn, value, errmsg)
unsigned long insn;
long value;
const char **errmsg;
{
  if ((value & 0x8000) == 0)
    insn |= 1 << 21;
  return insn | (value & 0xfffc);
}
```
user: What is the c source code of the assembly code below:

```asm
<insert_bdp>:
  endbr64
  mov    %rdi,%rax
  or     $0x200000,%rax
  test   $0x8000,%esi
  cmove  %rax,%rdi
  and    $0xfffc,%esi
  mov    %rsi,%rax
  or     %rdi,%rax
  ret
```

assistant: ```c
unsigned long insert_bdp(insn, value, errmsg)
unsigned long insn;
long value;
const char **errmsg;
{
  if ((value & 0x8000) == 0)
    insn |= 1 << 21;
  return insn | (value & 0xfffc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<insert_bdp>:
  endbr64
  mov    %rdi,%rax
  or     $0x200000,%rax
  test   $0x8000,%esi
  cmove  %rax,%rdi
  and    $0xfffc,%esi
  mov    %rsi,%rax
  or     %rdi,%rax
  ret
```

assistant: ```c
unsigned long insert_bdp(insn, value, errmsg)
unsigned long insn;
long value;
const char **errmsg;
{
  if ((value & 0x8000) == 0)
    insn |= 1 << 21;
  return insn | (value & 0xfffc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<AURAE_Script_Syntax_Analyse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x18(%rbp)
  mov    %al,-0xc(%rbp)
  cmpb   $0x20,-0xc(%rbp)
  jle    L2
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xc(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L20
L2:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L25
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L21
L25:
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
L20:
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int AURAE_Script_Syntax_Analyse(int *i, char letter, char *word) {
  if (letter > 32) {
    word[*i] = letter;
    *i = *i + 1;
  } else {
    word[*i] = 0x00;
    if (*i > 0) {
      *i = 0;
      return 1;
    }
    *i = 0;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AURAE_Script_Syntax_Analyse>:
  endbr64
  cmp    $0x20,%sil
  jle    L10
  movslq (%rdi),%rax
  mov    %sil,(%rdx,%rax,1)
  mov    (%rdi),%eax
  add    $0x1,%eax
  mov    $0x0,%edx
L8:
  mov    %eax,(%rdi)
  mov    %edx,%eax
  ret
L10:
  movslq (%rdi),%rax
  movb   $0x0,(%rdx,%rax,1)
  cmpl   $0x0,(%rdi)
  setg   %dl
  movzbl %dl,%edx
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
int AURAE_Script_Syntax_Analyse(int *i, char letter, char *word) {
  if (letter > 32) {
    word[*i] = letter;
    *i = *i + 1;
  } else {
    word[*i] = 0x00;
    if (*i > 0) {
      *i = 0;
      return 1;
    }
    *i = 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AURAE_Script_Syntax_Analyse>:
  endbr64
  movslq (%rdi),%rax
  add    %rax,%rdx
  cmp    $0x20,%sil
  jle    L0
  mov    %sil,(%rdx)
  mov    (%rdi),%eax
  xor    %r8d,%r8d
  add    $0x1,%eax
  mov    %eax,(%rdi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L0:
  movb   $0x0,(%rdx)
  mov    (%rdi),%eax
  xor    %r8d,%r8d
  test   %eax,%eax
  setg   %r8b
  xor    %eax,%eax
  mov    %eax,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int AURAE_Script_Syntax_Analyse(int *i, char letter, char *word) {
  if (letter > 32) {
    word[*i] = letter;
    *i = *i + 1;
  } else {
    word[*i] = 0x00;
    if (*i > 0) {
      *i = 0;
      return 1;
    }
    *i = 0;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<AURAE_Script_Syntax_Analyse>:
  endbr64
  movslq (%rdi),%rax
  add    %rax,%rdx
  cmp    $0x20,%sil
  jle    L5
  mov    %sil,(%rdx)
  mov    (%rdi),%eax
  xor    %r8d,%r8d
  add    $0x1,%eax
  mov    %eax,(%rdi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L5:
  movb   $0x0,(%rdx)
  mov    (%rdi),%eax
  xor    %r8d,%r8d
  test   %eax,%eax
  setg   %r8b
  xor    %eax,%eax
  mov    %eax,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int AURAE_Script_Syntax_Analyse(int *i, char letter, char *word) {
  if (letter > 32) {
    word[*i] = letter;
    *i = *i + 1;
  } else {
    word[*i] = 0x00;
    if (*i > 0) {
      *i = 0;
      return 1;
    }
    *i = 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  test   %al,%al
  jne    L0
  nop
L58:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  mov    -0x8(%rbp),%rax
  jmp    L41
L64:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L67
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0xc(%rbp),%edx
  cmp    %dl,%al
  jne    L64
L67:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0xc(%rbp),%edx
  cmp    %dl,%al
  jne    L23
  mov    -0x8(%rbp),%rax
  jmp    L41
L23:
  mov    $0x0,%eax
L41:
  pop    %rbp
  ret
```

assistant: ```c
char *index(const char *s, int c) {
  if ((char)c == '\0') {
    while (*s++)
      ;
    return (char *)s;
  }
  for (; *s && *s != (char)c; s++)
    ;
  return (*s == (char)c ? (char *)s : 0);
}
```