user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  lea    D8(%rip),%rsi
  lea    D49(%rip),%rdi
  push   %r14
  lea    D6(%rip),%r15
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x4(%rsp),%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <fscanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  mov    %rax,%r12
  test   %edx,%edx
  je     L34
  mov    %r14,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L218:
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <fscanf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,(%r12,%rbx,4)
  movslq 0x4(%rsp),%rax
  add    $0x1,%rbx
  mov    %rax,%rdx
  cmp    %rbx,%rax
  ja     L218
L34:
  xor    %esi,%esi
  mov    %r12,%rdi
  sub    $0x1,%edx
  call   <quick_sort@plt>
  movslq 0x4(%rsp),%rdi
  mov    %rdi,%rsi
  test   %rdi,%rdi
  je     L176
  lea    -0x1(%rdi),%r9d
  lea    -0x1(%rdi),%rax
  movslq %r9d,%r9
  cmp    $0x2,%rax
  jbe    L18
  mov    %rdi,%rcx
  pxor   %xmm2,%xmm2
  lea    -0x10(%r12,%rdi,4),%r8
  xor    %eax,%eax
  shr    $0x2,%rcx
  movdqa %xmm2,%xmm1
  shl    $0x4,%rcx
  nop
L197:
  movdqu (%r14,%rax,1),%xmm3
  movdqu (%r12,%rax,1),%xmm0
  mov    %rax,%rdx
  add    $0x10,%rax
  neg    %rdx
  pcmpeqd %xmm3,%xmm0
  psubd  %xmm0,%xmm1
  movdqu (%r8,%rdx,1),%xmm0
  pshufd $0x1b,%xmm0,%xmm0
  pcmpeqd %xmm3,%xmm0
  psubd  %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L197
  movdqa %xmm2,%xmm0
  mov    %rdi,%rcx
  psrldq $0x8,%xmm0
  and    $0xfffffffffffffffc,%rcx
  paddd  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movdqa %xmm1,%xmm0
  psrldq $0x8,%xmm0
  movd   %xmm2,%eax
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%edx
  test   $0x3,%dil
  je     L158
L51:
  mov    (%r14,%rcx,4),%r10d
  lea    0x0(,%rcx,4),%r8
  cmp    (%r12,%rcx,4),%r10d
  je     L42
L33:
  mov    %r9,%r11
  sub    %rcx,%r11
  cmp    (%r12,%r11,4),%r10d
  je     L86
L7:
  lea    0x1(%rcx),%r10
  cmp    %rdi,%r10
  jae    L158
  mov    0x4(%r14,%r8,1),%r11d
  cmp    0x4(%r12,%r8,1),%r11d
  je     L3
L219:
  mov    %r9,%rbx
  sub    %r10,%rbx
  cmp    %r11d,(%r12,%rbx,4)
  je     L89
L96:
  add    $0x2,%rcx
  cmp    %rcx,%rdi
  jbe    L158
  mov    0x8(%r14,%r8,1),%edi
  cmp    0x8(%r12,%r8,1),%edi
  je     L200
L22:
  sub    %rcx,%r9
  cmp    (%r12,%r9,4),%edi
  je     L172
L158:
  cmp    %eax,%edx
  jle    L36
  sub    %edx,%esi
  lea    D9(%rip),%rdi
  sub    $0x1,%esi
  call   <printf@plt>
L69:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L207
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L176:
  xor    %eax,%eax
  xor    %esi,%esi
L36:
  sub    %eax,%esi
  lea    D9(%rip),%rdi
  sub    $0x1,%esi
  call   <printf@plt>
  jmp    L69
L86:
  add    $0x1,%eax
  jmp    L7
L42:
  add    $0x1,%edx
  jmp    L33
L89:
  add    $0x1,%eax
  jmp    L96
L3:
  add    $0x1,%edx
  jmp    L219
L172:
  add    $0x1,%eax
  jmp    L158
L200:
  add    $0x1,%edx
  jmp    L22
L18:
  xor    %ecx,%ecx
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L51
L207:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D49
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D8: r

tool: D49: input.txt

tool: D6: %d

tool: D9: %d


assistant: ```c
int main() {
  FILE *fp;
  fp = fopen("input.txt", "r");
  int n;
  fscanf(fp, "%d", &n);
  int *a = malloc(sizeof(int) * n);
  int *s = malloc(sizeof(int) * n);
  for (size_t i = 0; i < n; i++) {
    fscanf(fp, "%d", &a[i]);
    s[i] = a[i];
  }
  quick_sort(s, 0, n - 1);
  int cnt = 0, rcnt = 0;
  for (size_t i = 0; i < n; i++) {
    if (a[i] == s[i]) {
      cnt++;
    }
    if (a[i] == s[n - 1 - i]) {
      rcnt++;
    }
  }
  if (cnt > rcnt) {
    printf("%d\n", n - cnt - 1);
  } else {
    printf("%d\n", n - rcnt - 1);
  }
  fclose(fp);
  free(a);
  free(s);
  return 0;
}
```