ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverse>:
  endbr64
  mov    %rdi,%rax
  movslq %esi,%rdi
  shl    $0x2,%rdi
  lea    (%rax,%rdi,1),%rdx
  cmp    %rdx,%rax
  jae    L19
  lea    -0x1(%rdi),%rsi
  mov    %rax,%rcx
  mov    %rsi,%r10
  shr    $0x3,%r10
  mov    %r10,%r8
  lea    0x1(%r10),%r9
  neg    %r8
  lea    0x0(,%r9,4),%r11
  lea    (%rdi,%r8,4),%r8
  cmp    %r8,%r11
  lea    0x4(%rdi),%r11
  setle  %r8b
  test   %r11,%r11
  setle  %r11b
  or     %r11b,%r8b
  je     L82
  cmp    $0x7,%rsi
  jbe    L82
  cmp    $0x17,%rsi
  jbe    L46
  mov    %r9,%r8
  lea    -0xc(%rax,%rdi,1),%rsi
  shr    $0x2,%r8
  shl    $0x4,%r8
  add    %rax,%r8
  nopl   0x0(%rax)
L7:
  movdqu (%rsi),%xmm2
  movdqu (%rcx),%xmm0
  add    $0x10,%rcx
  sub    $0x10,%rsi
  pshufd $0x1b,%xmm2,%xmm1
  pshufd $0x1b,%xmm0,%xmm0
  movups %xmm1,-0x10(%rcx)
  movups %xmm0,0x10(%rsi)
  cmp    %rcx,%r8
  jne    L7
  mov    %r9,%rcx
  and    $0xfffffffffffffffc,%rcx
  lea    0x0(,%rcx,4),%r8
  lea    (%rax,%r8,1),%rsi
  sub    %r8,%rdx
  cmp    %rcx,%r9
  je     L12
L32:
  sub    %rcx,%r9
  cmp    %rcx,%r10
  je     L28
  lea    (%rax,%rcx,4),%r8
  not    %rcx
  lea    (%rdi,%rcx,4),%rcx
  movq   (%r8),%xmm0
  add    %rcx,%rax
  movq   (%rax),%xmm1
  pshufd $0xe1,%xmm0,%xmm0
  pshufd $0xe1,%xmm1,%xmm1
  movq   %xmm1,(%r8)
  movq   %xmm0,(%rax)
  mov    %r9,%rax
  and    $0xfffffffffffffffe,%rax
  lea    0x0(,%rax,4),%rcx
  add    %rcx,%rsi
  sub    %rcx,%rdx
  cmp    %rax,%r9
  je     L19
L28:
  mov    (%rsi),%eax
  mov    (%rdx),%ecx
  mov    %ecx,(%rsi)
  mov    %eax,(%rdx)
  ret
  nop
L82:
  mov    (%rax),%ecx
  mov    (%rdx),%esi
  add    $0x4,%rax
  sub    $0x4,%rdx
  mov    %esi,-0x4(%rax)
  mov    %ecx,0x4(%rdx)
  cmp    %rdx,%rax
  jb     L82
L19:
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
L46:
  mov    %rax,%rsi
  xor    %ecx,%ecx
  jmp    L32
```

assistant: ```c
void reverse(int *data, int n) {
  int *lo = &data[0], *hi = &data[n];
  for (; lo < hi; ++lo, --hi) {
    int tmp = *lo;
    *lo = *hi;
    *hi = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pb_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    $0x0,%eax
  call   <__log_timestamp@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__log@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void pb_log(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  __log_timestamp();
  __log(fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pb_log>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    $0x0,%eax
  call   <__log_timestamp@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <__log@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void pb_log(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  __log_timestamp();
  __log(fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pb_log>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  xor    %eax,%eax
  call   <__log_timestamp@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <__log@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void pb_log(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  __log_timestamp();
  __log(fmt, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pb_log>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  xor    %eax,%eax
  call   <__log_timestamp@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <__log@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void pb_log(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  __log_timestamp();
  __log(fmt, ap);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ServeSpacerTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D22
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D17
data_type: string

tool: D22: <table border="0" cellspacing="0" cellpadding="0" width="760"


tool: D28: <tr><td align="center">&nbsp;</td></tr>


tool: D17: </table>


assistant: ```c
void ServeSpacerTable(void) {
  printf("<table border=\"0\" cellspacing=\"0\" cellpadding=\"0\" width=\"760\"\n");
  printf("<tr><td align=\"center\">&nbsp;</td></tr>\n");
  printf("</table>\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ServeSpacerTable>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type: string
name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D15
type: string

tool: D11: <table border="0" cellspacing="0" cellpadding="0" width="760"


tool: D13: <tr><td align="center">&nbsp;</td></tr>


tool: D15: </table>


assistant: ```c
void ServeSpacerTable(void) {
  printf("<table border=\"0\" cellspacing=\"0\" cellpadding=\"0\" width=\"760\"\n");
  printf("<tr><td align=\"center\">&nbsp;</td></tr>\n");
  printf("</table>\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ServeSpacerTable>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D23
type: string
name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D7
type: string

tool: D23: <table border="0" cellspacing="0" cellpadding="0" width="760"


tool: D2: <tr><td align="center">&nbsp;</td></tr>


tool: D7: </table>


assistant: ```c
void ServeSpacerTable(void) {
  printf("<table border=\"0\" cellspacing=\"0\" cellpadding=\"0\" width=\"760\"\n");
  printf("<tr><td align=\"center\">&nbsp;</td></tr>\n");
  printf("</table>\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ServeSpacerTable>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D23
type_guessed: string
name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D8: <table border="0" cellspacing="0" cellpadding="0" width="760"


tool: D23: <tr><td align="center">&nbsp;</td></tr>


tool: D2: </table>


assistant: ```c
void ServeSpacerTable(void) {
  printf("<table border=\"0\" cellspacing=\"0\" cellpadding=\"0\" width=\"760\"\n");
  printf("<tr><td align=\"center\">&nbsp;</td></tr>\n");
  printf("</table>\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x5c(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x0,-0x54(%rbp)
  movl   $0x0,-0x60(%rbp)
  jmp    L102
L109:
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  cmp    $0x40,%al
  jle    L67
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  cmp    $0x5a,%al
  jg     L67
  addl   $0x1,-0x5c(%rbp)
  jmp    L5
L67:
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  jle    L82
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L82
  addl   $0x1,-0x58(%rbp)
  jmp    L5
L82:
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  cmp    $0x2f,%al
  jle    L5
  cmpl   $0x39,-0x60(%rbp)
  setle  %al
  movzbl %al,%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  test   %al,%al
  je     L5
  addl   $0x1,-0x54(%rbp)
L5:
  addl   $0x1,-0x60(%rbp)
L102:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x60(%rbp)
  jl     L109
  mov    -0x54(%rbp),%ecx
  mov    -0x58(%rbp),%edx
  mov    -0x5c(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L71
  call   <__stack_chk_fail@plt>
L71:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: capital have %d,lowercase have %d,shuzi have %d


assistant: ```c
int main() {
  char str[64];
  gets(str);
  int i, cnt1 = 0, cnt2 = 0, cnt3 = 0;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] >= 65 && str[i] <= 90) {
      cnt1++;
    } else if (str[i] >= 97 && str[i] <= 122) {
      cnt2++;
    } else if (str[i] >= 48 && str[i <= 57]) {
      cnt3++;
    }
  }
  printf("capital have %d,lowercase have %d,shuzi have %d\n", cnt1, cnt2, cnt3);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    %rsp,%rbp
  jmp    L9
L32:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L19
  add    $0x1,%r13d
L77:
  add    $0x1,%rbx
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%ecx
  cmp    %ebx,%eax
  jle    L30
  movzbl (%rbx,%rbp,1),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L32
  add    $0x1,%r12d
  jmp    L77
L19:
  cmp    $0x2f,%al
  jle    L77
  cmp    $0x39,%ecx
  setle  %al
  movzbl %al,%eax
  cmpb   $0x1,(%rsp,%rax,1)
  sbb    $0xffffffff,%r14d
  jmp    L77
L30:
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: capital have %d,lowercase have %d,shuzi have %d


assistant: ```c
int main() {
  char str[64];
  gets(str);
  int i, cnt1 = 0, cnt2 = 0, cnt3 = 0;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] >= 65 && str[i] <= 90) {
      cnt1++;
    } else if (str[i] >= 97 && str[i] <= 122) {
      cnt2++;
    } else if (str[i] >= 48 && str[i <= 57]) {
      cnt3++;
    }
  }
  printf("capital have %d,lowercase have %d,shuzi have %d\n", cnt1, cnt2, cnt3);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L68:
  add    $0x1,%r12d
L27:
  add    $0x1,%rbx
L39:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%ecx
  cmp    %ebx,%eax
  jle    L38
  movzbl 0x0(%rbp,%rbx,1),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  jbe    L68
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L75
  add    $0x1,%r13d
  jmp    L27
  nopl   0x0(%rax)
L75:
  cmp    $0x2f,%al
  jle    L27
  xor    %eax,%eax
  cmp    $0x39,%ecx
  setle  %al
  cmpb   $0x1,(%rsp,%rax,1)
  sbb    $0xffffffff,%r14d
  jmp    L27
  xchg   %ax,%ax
L38:
  mov    %r14d,%ecx
  mov    %r13d,%edx
  lea    D6(%rip),%rdi
  mov    %r12d,%esi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: capital have %d,lowercase have %d,shuzi have %d


assistant: ```c
int main() {
  char str[64];
  gets(str);
  int i, cnt1 = 0, cnt2 = 0, cnt3 = 0;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] >= 65 && str[i] <= 90) {
      cnt1++;
    } else if (str[i] >= 97 && str[i] <= 122) {
      cnt2++;
    } else if (str[i] >= 48 && str[i <= 57]) {
      cnt3++;
    }
  }
  printf("capital have %d,lowercase have %d,shuzi have %d\n", cnt1, cnt2, cnt3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%r12d
L38:
  add    $0x1,%rbx
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%ecx
  cmp    %ebx,%eax
  jle    L65
  movzbl 0x0(%rbp,%rbx,1),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  jbe    L10
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L28
  add    $0x1,%r13d
  jmp    L38
  nopl   0x0(%rax)
L28:
  cmp    $0x2f,%al
  jle    L38
  xor    %eax,%eax
  cmp    $0x39,%ecx
  setle  %al
  cmpb   $0x1,(%rsp,%rax,1)
  sbb    $0xffffffff,%r14d
  jmp    L38
  xchg   %ax,%ax
L65:
  mov    %r14d,%ecx
  mov    %r13d,%edx
  lea    D4(%rip),%rdi
  mov    %r12d,%esi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: D4: capital have %d,lowercase have %d,shuzi have %d


assistant: ```c
int main() {
  char str[64];
  gets(str);
  int i, cnt1 = 0, cnt2 = 0, cnt3 = 0;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] >= 65 && str[i] <= 90) {
      cnt1++;
    } else if (str[i] >= 97 && str[i] <= 122) {
      cnt2++;
    } else if (str[i] >= 48 && str[i <= 57]) {
      cnt3++;
    }
  }
  printf("capital have %d,lowercase have %d,shuzi have %d\n", cnt1, cnt2, cnt3);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<exitWithError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <applicationRelease@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void exitWithError(int errorCode) {
  applicationRelease();
  exit(errorCode);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exitWithError>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <applicationRelease@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void exitWithError(int errorCode) {
  applicationRelease();
  exit(errorCode);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exitWithError>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <applicationRelease@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

assistant: ```c
void exitWithError(int errorCode) {
  applicationRelease();
  exit(errorCode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<exitWithError>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <applicationRelease@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

assistant: ```c
void exitWithError(int errorCode) {
  applicationRelease();
  exit(errorCode);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ffsl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl %ax,%eax
  test   %rax,%rax
  jne    L6
  addl   $0x10,-0x4(%rbp)
  sarq   $0x10,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  movzbl %al,%eax
  test   %rax,%rax
  jne    L77
  addl   $0x8,-0x4(%rbp)
  sarq   $0x8,-0x18(%rbp)
L77:
  mov    -0x18(%rbp),%rax
  and    $0xf,%eax
  test   %rax,%rax
  jne    L72
  addl   $0x4,-0x4(%rbp)
  sarq   $0x4,-0x18(%rbp)
L72:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L81
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L56
L81:
  mov    -0x18(%rbp),%rax
  and    $0x2,%eax
  test   %rax,%rax
  je     L42
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  jmp    L56
L42:
  mov    -0x18(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L37
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  jmp    L56
L37:
  mov    -0x18(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L22
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L56
L22:
  mov    $0x0,%eax
L56:
  pop    %rbp
  ret
```

assistant: ```c
int ffsl(long i) {
  int plus = 0;
  if ((i & 0xffff) == 0) {
    plus += 16;
    i >>= 16;
  }
  if ((i & 0xff) == 0) {
    plus += 8;
    i >>= 8;
  }
  if ((i & 0xf) == 0) {
    plus += 4;
    i >>= 4;
  }
  if (i & 1)
    return plus + 1;
  if (i & 2)
    return plus + 2;
  if (i & 4)
    return plus + 3;
  if (i & 8)
    return plus + 4;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ffsl>:
  endbr64
  mov    $0x0,%eax
  test   %di,%di
  jne    L36
  sar    $0x10,%rdi
  mov    $0x10,%eax
L36:
  test   %dil,%dil
  jne    L56
  add    $0x8,%eax
  sar    $0x8,%rdi
L56:
  test   $0xf,%dil
  jne    L48
  add    $0x4,%eax
  sar    $0x4,%rdi
L48:
  test   $0x1,%dil
  jne    L53
  test   $0x2,%dil
  jne    L15
  test   $0x4,%dil
  jne    L55
  add    $0x4,%eax
  test   $0x8,%dil
  mov    $0x0,%edx
  cmove  %edx,%eax
  ret
L53:
  add    $0x1,%eax
  ret
L15:
  add    $0x2,%eax
  ret
L55:
  add    $0x3,%eax
  ret
```

assistant: ```c
int ffsl(long i) {
  int plus = 0;
  if ((i & 0xffff) == 0) {
    plus += 16;
    i >>= 16;
  }
  if ((i & 0xff) == 0) {
    plus += 8;
    i >>= 8;
  }
  if ((i & 0xf) == 0) {
    plus += 4;
    i >>= 4;
  }
  if (i & 1)
    return plus + 1;
  if (i & 2)
    return plus + 2;
  if (i & 4)
    return plus + 3;
  if (i & 8)
    return plus + 4;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ffsl>:
  endbr64
  xor    %eax,%eax
  test   %di,%di
  jne    L18
  sar    $0x10,%rdi
  mov    $0x10,%eax
L18:
  test   %dil,%dil
  jne    L6
  add    $0x8,%eax
  sar    $0x8,%rdi
L6:
  test   $0xf,%dil
  jne    L35
  add    $0x4,%eax
  sar    $0x4,%rdi
L35:
  test   $0x1,%dil
  jne    L33
  test   $0x2,%dil
  jne    L39
  test   $0x4,%dil
  jne    L30
  xor    %edx,%edx
  add    $0x4,%eax
  and    $0x8,%edi
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x2,%eax
  ret
  nopl   0x0(%rax)
L33:
  add    $0x1,%eax
  ret
  nopl   0x0(%rax)
L30:
  add    $0x3,%eax
  ret
```

assistant: ```c
int ffsl(long i) {
  int plus = 0;
  if ((i & 0xffff) == 0) {
    plus += 16;
    i >>= 16;
  }
  if ((i & 0xff) == 0) {
    plus += 8;
    i >>= 8;
  }
  if ((i & 0xf) == 0) {
    plus += 4;
    i >>= 4;
  }
  if (i & 1)
    return plus + 1;
  if (i & 2)
    return plus + 2;
  if (i & 4)
    return plus + 3;
  if (i & 8)
    return plus + 4;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ffsl>:
  endbr64
  push   %r15
  mov    %rdi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %di,%di
  jne    L46
  sar    $0x10,%rax
  mov    $0x13,%ecx
  mov    $0x12,%edx
  movl   $0x1e,-0x8(%rsp)
  mov    $0x11,%r8d
  mov    $0x18,%edi
  movl   $0x1d,-0x4(%rsp)
  mov    $0x17,%r9d
  mov    $0x16,%r10d
  mov    $0x14,%esi
  mov    $0x15,%r11d
  mov    $0x1b,%r15d
  mov    $0x1a,%r14d
  mov    $0x19,%r13d
  mov    $0x20,%r12d
  mov    $0x1f,%ebp
  mov    $0x1c,%ebx
L20:
  test   %al,%al
  jne    L48
  mov    -0x8(%rsp),%r10d
  mov    -0x4(%rsp),%r11d
  sar    $0x8,%rax
  mov    %ebx,%esi
  mov    %r15d,%ecx
  mov    %r14d,%edx
  mov    %r13d,%r8d
  mov    %r12d,%edi
  mov    %ebp,%r9d
L48:
  test   $0xf,%al
  jne    L34
  sar    $0x4,%rax
  mov    %r11d,%r8d
  mov    %r10d,%edx
  mov    %r9d,%ecx
  mov    %edi,%esi
L34:
  test   $0x1,%al
  jne    L43
  mov    %edx,%r8d
  test   $0x2,%al
  jne    L43
  mov    %ecx,%r8d
  test   $0x4,%al
  jne    L43
  xor    %r8d,%r8d
  test   $0x8,%al
  cmovne %esi,%r8d
L43:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x8,%edi
  movl   $0xe,-0x8(%rsp)
  movl   $0xd,-0x4(%rsp)
  mov    $0x1,%r8d
  mov    $0x7,%r9d
  mov    $0x6,%r10d
  mov    $0x5,%r11d
  mov    $0x4,%esi
  mov    $0xb,%r15d
  mov    $0xa,%r14d
  mov    $0x9,%r13d
  mov    $0x10,%r12d
  mov    $0xf,%ebp
  mov    $0xc,%ebx
  jmp    L20
```

assistant: ```c
int ffsl(long i) {
  int plus = 0;
  if ((i & 0xffff) == 0) {
    plus += 16;
    i >>= 16;
  }
  if ((i & 0xff) == 0) {
    plus += 8;
    i >>= 8;
  }
  if ((i & 0xf) == 0) {
    plus += 4;
    i >>= 4;
  }
  if (i & 1)
    return plus + 1;
  if (i & 2)
    return plus + 2;
  if (i & 4)
    return plus + 3;
  if (i & 8)
    return plus + 4;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MakeHillFormulaString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L34
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L34
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L31
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x4(%rbp),%eax
  jmp    L35
L31:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  or     $0x1,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  jmp    L35
L34:
  mov    $0x0,%eax
L35:
  leave
  ret
```

assistant: ```c
int MakeHillFormulaString(char *szHillFormula, char *szLinearCT, int nLen_szLinearCT, int *bOverflow) {
  int nLen;
  if (szHillFormula && !*bOverflow) {
    if (nLen_szLinearCT > (nLen = strlen(szHillFormula))) {
      memcpy(szLinearCT, szHillFormula, nLen + 1);
      return nLen;
    }
    *bOverflow |= 1;
    return nLen_szLinearCT + 1;
  }
  return 0;
}
```