ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrixMult>:
  endbr64
  push   %r12
  mov    $0x40,%edx
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    $0x40,%edx
  mov    %rbx,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rbx,%rdi
  mov    %r12,%rax
  lea    0x40(%rsp),%rdx
L8:
  movss  0x0(%rbp),%xmm0
  movss  (%rax),%xmm2
  add    $0x10,%rax
  add    $0x10,%rdi
  movss  -0xc(%rax),%xmm1
  mulss  %xmm2,%xmm0
  addss  -0x10(%rdi),%xmm0
  movss  %xmm0,-0x10(%rdi)
  movss  0x10(%rbp),%xmm3
  mulss  %xmm1,%xmm3
  addss  %xmm0,%xmm3
  movss  -0x8(%rax),%xmm0
  movss  %xmm3,-0x10(%rdi)
  movss  0x20(%rbp),%xmm4
  mulss  %xmm0,%xmm4
  addss  %xmm3,%xmm4
  movss  -0x4(%rax),%xmm3
  movss  %xmm4,-0x10(%rdi)
  movss  0x30(%rbp),%xmm5
  mulss  %xmm3,%xmm5
  addss  %xmm4,%xmm5
  movss  %xmm5,-0x10(%rdi)
  movss  0x4(%rbp),%xmm4
  mulss  %xmm2,%xmm4
  addss  -0xc(%rdi),%xmm4
  movss  %xmm4,-0xc(%rdi)
  movss  0x14(%rbp),%xmm5
  mulss  %xmm1,%xmm5
  addss  %xmm4,%xmm5
  movss  %xmm5,-0xc(%rdi)
  movss  0x24(%rbp),%xmm4
  mulss  %xmm0,%xmm4
  addss  %xmm5,%xmm4
  movss  %xmm4,-0xc(%rdi)
  movss  0x34(%rbp),%xmm5
  mulss  %xmm3,%xmm5
  addss  %xmm4,%xmm5
  movss  %xmm5,-0xc(%rdi)
  movss  0x8(%rbp),%xmm4
  mulss  %xmm2,%xmm4
  addss  -0x8(%rdi),%xmm4
  movss  %xmm4,-0x8(%rdi)
  movss  0x18(%rbp),%xmm5
  mulss  %xmm1,%xmm5
  addss  %xmm4,%xmm5
  movss  %xmm5,-0x8(%rdi)
  movss  0x28(%rbp),%xmm4
  mulss  %xmm0,%xmm4
  addss  %xmm5,%xmm4
  movss  %xmm4,-0x8(%rdi)
  movss  0x38(%rbp),%xmm5
  mulss  %xmm3,%xmm5
  addss  %xmm4,%xmm5
  movss  %xmm5,-0x8(%rdi)
  mulss  0xc(%rbp),%xmm2
  addss  -0x4(%rdi),%xmm2
  movss  %xmm2,-0x4(%rdi)
  mulss  0x1c(%rbp),%xmm1
  addss  %xmm2,%xmm1
  movss  %xmm1,-0x4(%rdi)
  mulss  0x2c(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rdi)
  mulss  0x3c(%rbp),%xmm3
  addss  %xmm0,%xmm3
  movss  %xmm3,-0x4(%rdi)
  cmp    %rax,%rdx
  jne    L8
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void matrixMult(float a[16], const float b[16]) {
  int i, j, k;
  float aa[16];
  memcpy(aa, a, sizeof(aa));
  memset(a, 0, 16 * sizeof(float));
  for (j = 0; j < 4; j++) {
    for (i = 0; i < 4; i++) {
      for (k = 0; k < 4; k++) {
        a[4 * j + i] += aa[4 * j + k] * b[4 * k + i];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strisprefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int strisprefix(char *s1, char *s2) {
  size_t l = strlen(s1);
  return (0 == strncmp(s2, s1, l));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strisprefix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strisprefix(char *s1, char *s2) {
  size_t l = strlen(s1);
  return (0 == strncmp(s2, s1, l));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strisprefix>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strisprefix(char *s1, char *s2) {
  size_t l = strlen(s1);
  return (0 == strncmp(s2, s1, l));
}
```
user: What is the c source code of the assembly code below:

```asm
<strisprefix>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strisprefix(char *s1, char *s2) {
  size_t l = strlen(s1);
  return (0 == strncmp(s2, s1, l));
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string

tool: D2: bcachify DEVICE [SB_SPACE]

DEVICE - Device to insert bcache on. Must have at least
	SB_SPACE free space left at the end of the block device
	after the filesystem. Use resize2fs or similar FIRST.
SB_SPACE - Amount of room to leave for the bcache SB
	(in bytes). Minimum is 8k, default is 512k.


assistant: ```c
void usage(void) {
  printf("bcachify DEVICE [SB_SPACE]\n\n"
         "DEVICE - Device to insert bcache on. Must have at least\n"
         "\tSB_SPACE free space left at the end of the block device\n"
         "\tafter the filesystem. Use resize2fs or similar FIRST.\n"
         "SB_SPACE - Amount of room to leave for the bcache SB\n"
         "\t(in bytes). Minimum is 8k, default is 512k.\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string

tool: D2: bcachify DEVICE [SB_SPACE]

DEVICE - Device to insert bcache on. Must have at least
	SB_SPACE free space left at the end of the block device
	after the filesystem. Use resize2fs or similar FIRST.
SB_SPACE - Amount of room to leave for the bcache SB
	(in bytes). Minimum is 8k, default is 512k.


assistant: ```c
void usage(void) {
  printf("bcachify DEVICE [SB_SPACE]\n\n"
         "DEVICE - Device to insert bcache on. Must have at least\n"
         "\tSB_SPACE free space left at the end of the block device\n"
         "\tafter the filesystem. Use resize2fs or similar FIRST.\n"
         "SB_SPACE - Amount of room to leave for the bcache SB\n"
         "\t(in bytes). Minimum is 8k, default is 512k.\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string

tool: D6: bcachify DEVICE [SB_SPACE]

DEVICE - Device to insert bcache on. Must have at least
	SB_SPACE free space left at the end of the block device
	after the filesystem. Use resize2fs or similar FIRST.
SB_SPACE - Amount of room to leave for the bcache SB
	(in bytes). Minimum is 8k, default is 512k.


assistant: ```c
void usage(void) {
  printf("bcachify DEVICE [SB_SPACE]\n\n"
         "DEVICE - Device to insert bcache on. Must have at least\n"
         "\tSB_SPACE free space left at the end of the block device\n"
         "\tafter the filesystem. Use resize2fs or similar FIRST.\n"
         "SB_SPACE - Amount of room to leave for the bcache SB\n"
         "\t(in bytes). Minimum is 8k, default is 512k.\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: bcachify DEVICE [SB_SPACE]

DEVICE - Device to insert bcache on. Must have at least
	SB_SPACE free space left at the end of the block device
	after the filesystem. Use resize2fs or similar FIRST.
SB_SPACE - Amount of room to leave for the bcache SB
	(in bytes). Minimum is 8k, default is 512k.


assistant: ```c
void usage(void) {
  printf("bcachify DEVICE [SB_SPACE]\n\n"
         "DEVICE - Device to insert bcache on. Must have at least\n"
         "\tSB_SPACE free space left at the end of the block device\n"
         "\tafter the filesystem. Use resize2fs or similar FIRST.\n"
         "SB_SPACE - Amount of room to leave for the bcache SB\n"
         "\t(in bytes). Minimum is 8k, default is 512k.\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<osx_open_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%edx
  mov    -0x5c(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L60:
  cmp    %rdx,%rsp
  je     L33
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L60
L33:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L29
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L29:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,-0x50(%rbp)
  jmp    L11
L61:
  subl   $0x1,-0x50(%rbp)
L11:
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L31
  cmpl   $0x0,-0x50(%rbp)
  jg     L61
L31:
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x68(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x58(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x70(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
FILE *osx_open_file(char *fn, int dim_file, char *exe_path, char *mode) {
  int path_len = strlen(exe_path);
  char new_path[path_len + dim_file + 1];
  int i = path_len;
  while (exe_path[i] != '/' && i > 0)
    i--;
  exe_path[i] = '\0';
  strcpy(new_path, exe_path);
  strcat(new_path, fn);
  return fopen(new_path, mode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<osx_open_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    0x1(%rax,%r14,1),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L37:
  cmp    %rdx,%rsp
  je     L5
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L37
L5:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L14
  orq    $0x0,-0x8(%rsp,%rax,1)
L14:
  mov    %rsp,%r14
  movslq %esi,%rax
  lea    (%rbx,%rax,1),%rdi
  cmpb   $0x2f,(%rdi)
  je     L46
  test   %esi,%esi
  jle    L46
  lea    -0x1(%rbx,%rax,1),%rdx
  mov    %rdx,%rax
  sub    $0x1,%esi
  sub    %edx,%esi
L56:
  mov    %rax,%rdi
  lea    (%rsi,%rax,1),%edx
  test   %edx,%edx
  setg   %cl
  cmpb   $0x2f,(%rax)
  setne  %dl
  sub    $0x1,%rax
  test   %dl,%cl
  jne    L56
L46:
  movb   $0x0,(%rdi)
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
FILE *osx_open_file(char *fn, int dim_file, char *exe_path, char *mode) {
  int path_len = strlen(exe_path);
  char new_path[path_len + dim_file + 1];
  int i = path_len;
  while (exe_path[i] != '/' && i > 0)
    i--;
  exe_path[i] = '\0';
  strcpy(new_path, exe_path);
  strcat(new_path, fn);
  return fopen(new_path, mode);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<osx_open_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  mov    %eax,%edx
  lea    0x1(%rax,%rbx,1),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L3
L30:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L30
L3:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L44
L57:
  movslq %edx,%rax
  mov    %rsp,%r15
  lea    (%r14,%rax,1),%rdi
  cmpb   $0x2f,(%rdi)
  je     L8
  test   %edx,%edx
  jle    L8
  lea    -0x1(%r14,%rax,1),%rax
  lea    -0x1(%rdx),%esi
  sub    %eax,%esi
  nop
L53:
  lea    (%rsi,%rax,1),%edx
  mov    %rax,%rdi
  test   %edx,%edx
  setg   %cl
  cmpb   $0x2f,(%rax)
  setne  %dl
  sub    $0x1,%rax
  test   %dl,%cl
  jne    L53
L8:
  movb   $0x0,(%rdi)
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <fopen@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L57
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
FILE *osx_open_file(char *fn, int dim_file, char *exe_path, char *mode) {
  int path_len = strlen(exe_path);
  char new_path[path_len + dim_file + 1];
  int i = path_len;
  while (exe_path[i] != '/' && i > 0)
    i--;
  exe_path[i] = '\0';
  strcpy(new_path, exe_path);
  strcat(new_path, fn);
  return fopen(new_path, mode);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<osx_open_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  mov    %eax,%edx
  lea    0x1(%rax,%rbx,1),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L22
L76:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L76
L22:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L6
L20:
  movslq %edx,%rax
  mov    %rsp,%r15
  lea    (%r14,%rax,1),%rdi
  cmpb   $0x2f,(%rdi)
  je     L16
  test   %edx,%edx
  jle    L16
  lea    -0x1(%r14,%rax,1),%rax
  lea    -0x1(%rdx),%esi
  sub    %eax,%esi
  nop
L54:
  lea    (%rsi,%rax,1),%edx
  mov    %rax,%rdi
  test   %edx,%edx
  setg   %cl
  cmpb   $0x2f,(%rax)
  setne  %dl
  sub    $0x1,%rax
  test   %dl,%cl
  jne    L54
L16:
  movb   $0x0,(%rdi)
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <fopen@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L20
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
FILE *osx_open_file(char *fn, int dim_file, char *exe_path, char *mode) {
  int path_len = strlen(exe_path);
  char new_path[path_len + dim_file + 1];
  int i = path_len;
  while (exe_path[i] != '/' && i > 0)
    i--;
  exe_path[i] = '\0';
  strcpy(new_path, exe_path);
  strcat(new_path, fn);
  return fopen(new_path, mode);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mat4_scale>:
  endbr64
  mov    %rdi,%rax
  movaps %xmm0,%xmm1
  mulss  (%rsi),%xmm1
  movss  %xmm1,(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x4(%rsi),%xmm1
  movss  %xmm1,0x4(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x8(%rsi),%xmm1
  movss  %xmm1,0x8(%rdi)
  movaps %xmm0,%xmm1
  mulss  0xc(%rsi),%xmm1
  movss  %xmm1,0xc(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x10(%rsi),%xmm1
  movss  %xmm1,0x10(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x14(%rsi),%xmm1
  movss  %xmm1,0x14(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x18(%rsi),%xmm1
  movss  %xmm1,0x18(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x1c(%rsi),%xmm1
  movss  %xmm1,0x1c(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x20(%rsi),%xmm1
  movss  %xmm1,0x20(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x24(%rsi),%xmm1
  movss  %xmm1,0x24(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x28(%rsi),%xmm1
  movss  %xmm1,0x28(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x2c(%rsi),%xmm1
  movss  %xmm1,0x2c(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x30(%rsi),%xmm1
  movss  %xmm1,0x30(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x34(%rsi),%xmm1
  movss  %xmm1,0x34(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x38(%rsi),%xmm1
  movss  %xmm1,0x38(%rdi)
  mulss  0x3c(%rsi),%xmm0
  movss  %xmm0,0x3c(%rdi)
  ret
```

assistant: ```c
float *mat4_scale(float *result, float *m, float scalar) {
  result[0] = m[0] * scalar;
  result[1] = m[1] * scalar;
  result[2] = m[2] * scalar;
  result[3] = m[3] * scalar;
  result[4] = m[4] * scalar;
  result[5] = m[5] * scalar;
  result[6] = m[6] * scalar;
  result[7] = m[7] * scalar;
  result[8] = m[8] * scalar;
  result[9] = m[9] * scalar;
  result[10] = m[10] * scalar;
  result[11] = m[11] * scalar;
  result[12] = m[12] * scalar;
  result[13] = m[13] * scalar;
  result[14] = m[14] * scalar;
  result[15] = m[15] * scalar;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat4_scale>:
  endbr64
  movss  (%rsi),%xmm1
  mov    %rdi,%rax
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  movss  0x8(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rdi)
  movss  0xc(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rdi)
  movss  0x10(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x10(%rdi)
  movss  0x14(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x14(%rdi)
  movss  0x18(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x18(%rdi)
  movss  0x1c(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x1c(%rdi)
  movss  0x20(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x20(%rdi)
  movss  0x24(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x24(%rdi)
  movss  0x28(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x28(%rdi)
  movss  0x2c(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x2c(%rdi)
  movss  0x30(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x30(%rdi)
  movss  0x34(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x34(%rdi)
  movss  0x38(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x38(%rdi)
  mulss  0x3c(%rsi),%xmm0
  movss  %xmm0,0x3c(%rdi)
  ret
```

assistant: ```c
float *mat4_scale(float *result, float *m, float scalar) {
  result[0] = m[0] * scalar;
  result[1] = m[1] * scalar;
  result[2] = m[2] * scalar;
  result[3] = m[3] * scalar;
  result[4] = m[4] * scalar;
  result[5] = m[5] * scalar;
  result[6] = m[6] * scalar;
  result[7] = m[7] * scalar;
  result[8] = m[8] * scalar;
  result[9] = m[9] * scalar;
  result[10] = m[10] * scalar;
  result[11] = m[11] * scalar;
  result[12] = m[12] * scalar;
  result[13] = m[13] * scalar;
  result[14] = m[14] * scalar;
  result[15] = m[15] * scalar;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mat4_scale>:
  endbr64
  movss  (%rsi),%xmm1
  mov    %rdi,%rax
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  movss  0x8(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rdi)
  movss  0xc(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rdi)
  movss  0x10(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x10(%rdi)
  movss  0x14(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x14(%rdi)
  movss  0x18(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x18(%rdi)
  movss  0x1c(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x1c(%rdi)
  movss  0x20(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x20(%rdi)
  movss  0x24(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x24(%rdi)
  movss  0x28(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x28(%rdi)
  movss  0x2c(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x2c(%rdi)
  movss  0x30(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x30(%rdi)
  movss  0x34(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x34(%rdi)
  movss  0x38(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x38(%rdi)
  mulss  0x3c(%rsi),%xmm0
  movss  %xmm0,0x3c(%rdi)
  ret
```

assistant: ```c
float *mat4_scale(float *result, float *m, float scalar) {
  result[0] = m[0] * scalar;
  result[1] = m[1] * scalar;
  result[2] = m[2] * scalar;
  result[3] = m[3] * scalar;
  result[4] = m[4] * scalar;
  result[5] = m[5] * scalar;
  result[6] = m[6] * scalar;
  result[7] = m[7] * scalar;
  result[8] = m[8] * scalar;
  result[9] = m[9] * scalar;
  result[10] = m[10] * scalar;
  result[11] = m[11] * scalar;
  result[12] = m[12] * scalar;
  result[13] = m[13] * scalar;
  result[14] = m[14] * scalar;
  result[15] = m[15] * scalar;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
struct tm getTime() {
  time_t now = time(0);
  return *localtime(&now);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getTime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct tm getTime() {
  time_t now = time(0);
  return *localtime(&now);
}
```