ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<XTL_SubVars_DecrementValue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <XTL_SubVars_GetValueInt@plt>
  cmp    $0xffffd8f1,%eax
  je     L11
  lea    -0x1(%rax),%esi
  mov    %rbx,%rdi
  call   <XTL_SubVars_UpdateInt@plt>
L17:
  pop    %rbx
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L17
```

assistant: ```c
int XTL_SubVars_DecrementValue(char *key) {
  int retval;
  retval = XTL_SubVars_GetValueInt(key);
  if (retval == -9999)
    return -1;
  --retval;
  return XTL_SubVars_UpdateInt(key, retval);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<XTL_SubVars_DecrementValue>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <XTL_SubVars_GetValueInt@plt>
  cmp    $0xffffd8f1,%eax
  je     L9
  mov    %rbp,%rdi
  lea    -0x1(%rax),%esi
  pop    %rbp
  jmp    1070 <XTL_SubVars_UpdateInt@plt>
L9:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int XTL_SubVars_DecrementValue(char *key) {
  int retval;
  retval = XTL_SubVars_GetValueInt(key);
  if (retval == -9999)
    return -1;
  --retval;
  return XTL_SubVars_UpdateInt(key, retval);
}
```
user: What is the c source code of the assembly code below?

```asm
<XTL_SubVars_DecrementValue>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <XTL_SubVars_GetValueInt@plt>
  cmp    $0xffffd8f1,%eax
  je     L3
  mov    %rbp,%rdi
  lea    -0x1(%rax),%esi
  pop    %rbp
  jmp    1070 <XTL_SubVars_UpdateInt@plt>
L3:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int XTL_SubVars_DecrementValue(char *key) {
  int retval;
  retval = XTL_SubVars_GetValueInt(key);
  if (retval == -9999)
    return -1;
  --retval;
  return XTL_SubVars_UpdateInt(key, retval);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L20
L29:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L30
  addl   $0x1,-0x10(%rbp)
L30:
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L29
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D4
type: string

tool: D5: %d

tool: D4: %d


assistant: ```c
int main() {
  int a;
  int counter = 0;
  scanf("%d", &a);
  for (int i = 1; i <= a; i++) {
    if (a % i == 0) {
      counter += 1;
    }
  }
  printf("%d\n", counter);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L38
  lea    0x1(%rsi),%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edi
L18:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%edi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L18
L21:
  mov    %edi,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L38:
  mov    $0x0,%edi
  jmp    L21
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string
name: unpack_data
arguments: data_label: D12
data_type: string

tool: D6: %d

tool: D12: %d


assistant: ```c
int main() {
  int a;
  int counter = 0;
  scanf("%d", &a);
  for (int i = 1; i <= a; i++) {
    if (a % i == 0) {
      counter += 1;
    }
  }
  printf("%d\n", counter);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L31
  lea    0x1(%rsi),%edi
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L19:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L19
L7:
  mov    %r8d,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L31:
  xor    %r8d,%r8d
  jmp    L7
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D11
type: string

tool: D13: %d

tool: D11: %d


assistant: ```c
int main() {
  int a;
  int counter = 0;
  scanf("%d", &a);
  for (int i = 1; i <= a; i++) {
    if (a % i == 0) {
      counter += 1;
    }
  }
  printf("%d\n", counter);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L7
  lea    0x1(%rsi),%edi
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L29:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L29
L18:
  mov    %r8d,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  xor    %r8d,%r8d
  jmp    L18
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string

tool: D2: %d

tool: D15: %d


assistant: ```c
int main() {
  int a;
  int counter = 0;
  scanf("%d", &a);
  for (int i = 1; i <= a; i++) {
    if (a % i == 0) {
      counter += 1;
    }
  }
  printf("%d\n", counter);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PrintTimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D23(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D17(%rip)
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2710,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: string

tool: D17: Test Output: %d


assistant: ```c
int PrintTimer(struct aeEventLoop *eventLoop, long long id, void *clientData) {
  static int i = 0;
  printf("Test Output: %d\n", i++);
  return 10000;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<PrintTimer>:
  endbr64
  sub    $0x8,%rsp
  mov    D14(%rip),%esi
  lea    0x1(%rsi),%eax
  mov    %eax,D28(%rip)
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x2710,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D28
type_guessed: string

tool: D28: Test Output: %d


assistant: ```c
int PrintTimer(struct aeEventLoop *eventLoop, long long id, void *clientData) {
  static int i = 0;
  printf("Test Output: %d\n", i++);
  return 10000;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  je     L87
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L15
L87:
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L14
L80:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  cltq
  add    %rax,%rcx
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L12
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
L12:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L23
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
L23:
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x0,-0x12(%rbp,%rax,1)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  movl   $0x0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L14:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L80
  mov    $0x0,%eax
L15:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L85
  call   <__stack_chk_fail@plt>
L85:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string

tool: D2: usage: ./a.out ls,pwd,cal (any combination with , seperating each command)


assistant: ```c
main(int argc, char *argv[]) {
  int i, j;
  char temp[10] = {};
  if (argc != 2) {
    printf("usage: ./a.out ls,pwd,cal (any combination with , seperating each command)\n");
    return;
  }
  i = 0;
  j = 0;
  while (argv[1][i]) {
    temp[j++] = argv[1][i++];
    if ((argv[1][i] == ',') || (argv[1][i + 1] == '\0')) {
      if ((argv[1][i + 1] == '\0') && (argv[1][i] != ','))
        temp[j++] = argv[1][i];
      temp[j] = '\0';
      system(temp);
      j = 0;
      i = i + 1;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  cmp    $0x2,%edi
  jne    L72
  mov    %rsi,%rbp
  mov    0x8(%rsi),%rdx
  movzbl (%rdx),%esi
  mov    $0x0,%ecx
  mov    $0x0,%ebx
  lea    0xe(%rsp),%r12
  test   %sil,%sil
  jne    L74
L65:
  mov    $0x0,%eax
L36:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L72:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L39:
  cltq
  mov    %r8b,0xe(%rsp,%rax,1)
  lea    0x2(%rcx),%eax
L79:
  cltq
  movb   $0x0,0xe(%rsp,%rax,1)
  mov    %r12,%rdi
  call   <system@plt>
  add    $0x2,%ebx
  mov    $0x0,%ecx
L29:
  mov    0x8(%rbp),%rdx
  movslq %ebx,%rax
  movzbl (%rdx,%rax,1),%esi
  test   %sil,%sil
  je     L65
L74:
  lea    0x1(%rbx),%edi
  lea    0x1(%rcx),%eax
  movslq %ecx,%r8
  mov    %sil,0xe(%rsp,%r8,1)
  movslq %edi,%rsi
  movzbl (%rdx,%rsi,1),%r8d
  cmp    $0x2c,%r8b
  je     L79
  cmpb   $0x0,0x1(%rdx,%rsi,1)
  je     L39
  mov    %eax,%ecx
  mov    %edi,%ebx
  jmp    L29
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: usage: ./a.out ls,pwd,cal (any combination with , seperating each command)


assistant: ```c
main(int argc, char *argv[]) {
  int i, j;
  char temp[10] = {};
  if (argc != 2) {
    printf("usage: ./a.out ls,pwd,cal (any combination with , seperating each command)\n");
    return;
  }
  i = 0;
  j = 0;
  while (argv[1][i]) {
    temp[j++] = argv[1][i++];
    if ((argv[1][i] == ',') || (argv[1][i + 1] == '\0')) {
      if ((argv[1][i + 1] == '\0') && (argv[1][i] != ','))
        temp[j++] = argv[1][i];
      temp[j] = '\0';
      system(temp);
      j = 0;
      i = i + 1;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  mov    %ax,0x16(%rsp)
  cmp    $0x2,%edi
  jne    L86
  mov    0x8(%rsi),%rcx
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  xor    %esi,%esi
  lea    0xe(%rsp),%rbp
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L27
  jmp    L93
  nop
L92:
  cmpb   $0x0,0x1(%rcx,%rdx,1)
  je     L53
  movzbl (%rcx,%rdx,1),%edx
  mov    %eax,%esi
  mov    %r8d,%r12d
  test   %dl,%dl
  je     L93
L27:
  movslq %esi,%rdi
  lea    0x1(%r12),%r8d
  lea    0x1(%rsi),%eax
  mov    %dl,0xe(%rsp,%rdi,1)
  movslq %r8d,%rdx
  movzbl (%rcx,%rdx,1),%edi
  cmp    $0x2c,%dil
  jne    L92
L51:
  cltq
  mov    %rbp,%rdi
  add    $0x2,%r12d
  movb   $0x0,0xe(%rsp,%rax,1)
  call   <system@plt>
  mov    0x8(%rbx),%rcx
  movslq %r12d,%rdx
  xor    %esi,%esi
  movzbl (%rcx,%rdx,1),%edx
  test   %dl,%dl
  jne    L27
L93:
  xor    %eax,%eax
L55:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L88
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L53:
  cltq
  mov    %dil,0xe(%rsp,%rax,1)
  lea    0x2(%rsi),%eax
  jmp    L51
L86:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D1: usage: ./a.out ls,pwd,cal (any combination with , seperating each command)


assistant: ```c
main(int argc, char *argv[]) {
  int i, j;
  char temp[10] = {};
  if (argc != 2) {
    printf("usage: ./a.out ls,pwd,cal (any combination with , seperating each command)\n");
    return;
  }
  i = 0;
  j = 0;
  while (argv[1][i]) {
    temp[j++] = argv[1][i++];
    if ((argv[1][i] == ',') || (argv[1][i + 1] == '\0')) {
      if ((argv[1][i + 1] == '\0') && (argv[1][i] != ','))
        temp[j++] = argv[1][i];
      temp[j] = '\0';
      system(temp);
      j = 0;
      i = i + 1;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  mov    %ax,0x16(%rsp)
  cmp    $0x2,%edi
  jne    L27
  mov    0x8(%rsi),%rcx
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  xor    %esi,%esi
  lea    0xe(%rsp),%rbp
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L91
  jmp    L89
  nop
L31:
  cmpb   $0x0,0x1(%rcx,%rdx,1)
  je     L5
  movzbl (%rcx,%rdx,1),%edx
  mov    %eax,%esi
  mov    %r8d,%r12d
  test   %dl,%dl
  je     L89
L91:
  movslq %esi,%rdi
  lea    0x1(%r12),%r8d
  lea    0x1(%rsi),%eax
  mov    %dl,0xe(%rsp,%rdi,1)
  movslq %r8d,%rdx
  movzbl (%rcx,%rdx,1),%edi
  cmp    $0x2c,%dil
  jne    L31
L1:
  cltq
  mov    %rbp,%rdi
  add    $0x2,%r12d
  movb   $0x0,0xe(%rsp,%rax,1)
  call   <system@plt>
  mov    0x8(%rbx),%rcx
  movslq %r12d,%rdx
  xor    %esi,%esi
  movzbl (%rcx,%rdx,1),%edx
  test   %dl,%dl
  jne    L91
L89:
  xor    %eax,%eax
L45:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L5:
  cltq
  mov    %dil,0xe(%rsp,%rax,1)
  lea    0x2(%rsi),%eax
  jmp    L1
L27:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L45
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: usage: ./a.out ls,pwd,cal (any combination with , seperating each command)


assistant: ```c
main(int argc, char *argv[]) {
  int i, j;
  char temp[10] = {};
  if (argc != 2) {
    printf("usage: ./a.out ls,pwd,cal (any combination with , seperating each command)\n");
    return;
  }
  i = 0;
  j = 0;
  while (argv[1][i]) {
    temp[j++] = argv[1][i++];
    if ((argv[1][i] == ',') || (argv[1][i + 1] == '\0')) {
      if ((argv[1][i + 1] == '\0') && (argv[1][i] != ','))
        temp[j++] = argv[1][i];
      temp[j] = '\0';
      system(temp);
      j = 0;
      i = i + 1;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ipv4_prefix_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    %dx,-0x34(%rbp)
  mov    %ax,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movw   $0x0,-0x1a(%rbp)
  lea    -0x18(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ipv4_pfxlen2mask@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  and    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  and    -0x40(%rbp),%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%eax
  mov    %ax,-0x1a(%rbp)
  cmpw   $0x0,-0x1a(%rbp)
  je     L42
  movzwl -0x34(%rbp),%eax
  cmp    %rax,-0x48(%rbp)
  ja     L42
  movzwl -0x38(%rbp),%eax
  cmp    %rax,-0x48(%rbp)
  jb     L42
  mov    $0x1,%eax
  jmp    L3
L42:
  mov    $0x0,%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
short int ipv4_prefix_match(unsigned long net1, unsigned long mask1, unsigned short int le, unsigned short int ge, unsigned long net2, unsigned long pfxlen) {
  unsigned long mask2 = 0;
  unsigned long err = 0;
  short int match = 0;
  if ((err = ipv4_pfxlen2mask(pfxlen, &mask2)) < 0)
    return err;
  match = (net1 & mask1) == (net2 & mask2);
  return match && (pfxlen <= le) && (pfxlen >= ge);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ipv4_prefix_match>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %edx,%r13d
  mov    %ecx,%r14d
  mov    %r8,%rbx
  mov    %r9,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  mov    %r9,%rdi
  call   <ipv4_pfxlen2mask@plt>
  and    %r15,%rbp
  and    (%rsp),%rbx
  mov    $0x0,%eax
  cmp    %rbx,%rbp
  je     L36
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  movzwl %r13w,%r13d
  cmp    %r12,%r13
  jb     L8
  movzwl %r14w,%r14d
  cmp    %r12,%r14
  setbe  %al
  movzbl %al,%eax
  jmp    L8
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short int ipv4_prefix_match(unsigned long net1, unsigned long mask1, unsigned short int le, unsigned short int ge, unsigned long net2, unsigned long pfxlen) {
  unsigned long mask2 = 0;
  unsigned long err = 0;
  short int match = 0;
  if ((err = ipv4_pfxlen2mask(pfxlen, &mask2)) < 0)
    return err;
  match = (net1 & mask1) == (net2 & mask2);
  return match && (pfxlen <= le) && (pfxlen >= ge);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ipv4_prefix_match>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r9,%rdi
  push   %rbx
  and    %r14,%rbp
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <ipv4_pfxlen2mask@plt>
  and    (%rsp),%rbx
  xor    %eax,%eax
  cmp    %rbx,%rbp
  je     L6
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L6:
  movzwl %r12w,%r12d
  cmp    %r15,%r12
  jb     L4
  movzwl %r13w,%r13d
  xor    %eax,%eax
  cmp    %r15,%r13
  setbe  %al
  jmp    L4
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short int ipv4_prefix_match(unsigned long net1, unsigned long mask1, unsigned short int le, unsigned short int ge, unsigned long net2, unsigned long pfxlen) {
  unsigned long mask2 = 0;
  unsigned long err = 0;
  short int match = 0;
  if ((err = ipv4_pfxlen2mask(pfxlen, &mask2)) < 0)
    return err;
  match = (net1 & mask1) == (net2 & mask2);
  return match && (pfxlen <= le) && (pfxlen >= ge);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ipv4_prefix_match>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r9,%rdi
  push   %rbx
  and    %r14,%rbp
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <ipv4_pfxlen2mask@plt>
  and    (%rsp),%rbx
  xor    %eax,%eax
  cmp    %rbx,%rbp
  je     L31
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L31:
  movzwl %r12w,%r12d
  cmp    %r15,%r12
  jb     L6
  movzwl %r13w,%r13d
  xor    %eax,%eax
  cmp    %r15,%r13
  setbe  %al
  jmp    L6
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short int ipv4_prefix_match(unsigned long net1, unsigned long mask1, unsigned short int le, unsigned short int ge, unsigned long net2, unsigned long pfxlen) {
  unsigned long mask2 = 0;
  unsigned long err = 0;
  short int match = 0;
  if ((err = ipv4_pfxlen2mask(pfxlen, &mask2)) < 0)
    return err;
  match = (net1 & mask1) == (net2 & mask2);
  return match && (pfxlen <= le) && (pfxlen >= ge);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sprintfa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L13
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L13:
  cmpq   $0x0,-0xd0(%rbp)
  je     L12
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0xc8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <vsprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
L12:
  nop
  leave
  ret
```

assistant: ```c
void sprintfa(char *buf, const char *format, ...) {
  if (format) {
    va_list args;
    va_start(args, format);
    vsprintf(buf + strlen(buf), format, args);
    va_end(args);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sprintfa>:
  endbr64
  test   %rsi,%rsi
  je     L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

assistant: ```c
void sprintfa(char *buf, const char *format, ...) {
  if (format) {
    va_list args;
    va_start(args, format);
    vsprintf(buf + strlen(buf), format, args);
    va_end(args);
  }
}
```