ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<perf_parse_long>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  cmpb   $0x0,(%rdi)
  jne    L34
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %edx,%edx
  mov    %rsi,%rbx
  lea    0x8(%rsp),%rsi
  call   <strtol@plt>
  mov    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movq   $0x1,0x10(%rsp)
  mov    %rax,%rbp
  call   <parse_unit_factor@plt>
  test   %eax,%eax
  je     L1
  mov    0x10(%rsp),%rax
  imul   %rbp,%rax
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  jmp    L1
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int perf_parse_long(const char *value, long *ret) {
  if (value && *value) {
    char *end;
    long val = strtol(value, &end, 0);
    unsigned long factor = 1;
    if (!parse_unit_factor(end, &factor))
      return 0;
    *ret = val * factor;
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D28(%rip),%rax
  mov    (%rax),%ecx
  mov    D44(%rip),%rax
  or     (%rax),%ecx
  mov    D43(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  or     (%rax),%edx
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x2000,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,%r12
  mov    D6(%rip),%rax
  cmp    %r12,(%rax)
  je     L9
L15:
  lea    0x4000(%r12),%rdi
  mov    D41(%rip),%rax
  mov    (%rax),%edx
  mov    $0x1000,%esi
  call   <mprotect@plt>
  test   %eax,%eax
  jne    L6
L53:
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movl   $0x81,(%r12)
  movl   $0x80,0x4(%r12)
  movl   $0x80,0x8(%r12)
  movl   $0x0,0xc(%r12)
  movl   $0x81,0x10(%r12)
  movl   $0x80,0x14(%r12)
  movl   $0x80,0x18(%r12)
  movl   $0x0,0x1c(%r12)
  movl   $0x81,0x20(%r12)
  movl   $0x80,0x24(%r12)
  movl   $0x80,0x28(%r12)
  movl   $0x0,0x2c(%r12)
  lea    0x30(%r12),%rax
  mov    %r12,%rbx
  lea    0x4000(%r12),%rbp
L19:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L19
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0xff7,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <read_ints@plt>
  cmpl   $0xff7,0x3fd8(%r13)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
L29:
  movl   $0x1,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L29
  mov    $0x1000,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <read_ints@plt>
  cmpl   $0x1000,0x3ffc(%r13)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
L6:
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L53
```

assistant: ```c
int main(int argc, char **argv) {
  uint8_t *addr = mmap(NULL, 8192, PROT_READ | PROT_WRITE, MAP_SHARED | MAP_ANONYMOUS, -1, 0);
  if (addr == MAP_FAILED)
    exit(1);
  int err = mprotect(addr + 4096, 4096, PROT_NONE);
  if (err != 0)
    exit(2);
  uint32_t *mem = malloc(sizeof(uint32_t) * 4096);
  addr[0] = 0x81;
  addr[1] = 0x80;
  addr[2] = 0x80;
  addr[3] = 0x00;
  addr[4] = 0x81;
  addr[5] = 0x80;
  addr[6] = 0x80;
  addr[7] = 0x00;
  addr[8] = 0x81;
  addr[9] = 0x80;
  addr[10] = 0x80;
  addr[11] = 0x00;
  for (int i = 12; i < 4096; i++) {
    addr[i] = 1;
  }
  init();
  read_ints(0, addr, mem, 4087);
  assert(4087 == mem[4086]);
  for (int i = 0; i < 4096; i++) {
    addr[i] = 1;
  }
  read_ints(0, addr, mem, 4096);
  assert(4096 == mem[4095]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x2000,%esi
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  mov    D27(%rip),%rax
  or     (%rax),%ecx
  mov    D41(%rip),%rax
  mov    (%rax),%edx
  mov    D34(%rip),%rax
  or     (%rax),%edx
  call   <mmap@plt>
  mov    %rax,%r12
  mov    D2(%rip),%rax
  cmp    %r12,(%rax)
  je     L34
L55:
  mov    D37(%rip),%rax
  lea    0x4000(%r12),%rbp
  mov    $0x1000,%esi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <mprotect@plt>
  test   %eax,%eax
  jne    L28
L8:
  mov    $0x4000,%edi
  mov    %r12,%rbx
  call   <malloc@plt>
  movq   $0x80,0x8(%r12)
  movq   $0x80,0x18(%r12)
  mov    %rax,%r13
  movabs $0x8000000081,%rax
  movq   $0x80,0x28(%r12)
  mov    %rax,(%r12)
  mov    %rax,0x10(%r12)
  mov    %rax,0x20(%r12)
  lea    0x30(%r12),%rax
  nopl   0x0(%rax,%rax,1)
L9:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L9
  xor    %eax,%eax
  call   <init@plt>
  xor    %edi,%edi
  mov    $0xff7,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <read_ints@plt>
  xor    %edi,%edi
  cmpl   $0xff7,0x3fd8(%r13)
  sete   %dil
  call   <assert@plt>
  xchg   %ax,%ax
L54:
  movl   $0x1,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L54
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %edi,%edi
  mov    $0x1000,%ecx
  call   <read_ints@plt>
  xor    %edi,%edi
  cmpl   $0x1000,0x3ffc(%r13)
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L8
L34:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L55
```

assistant: ```c
int main(int argc, char **argv) {
  uint8_t *addr = mmap(NULL, 8192, PROT_READ | PROT_WRITE, MAP_SHARED | MAP_ANONYMOUS, -1, 0);
  if (addr == MAP_FAILED)
    exit(1);
  int err = mprotect(addr + 4096, 4096, PROT_NONE);
  if (err != 0)
    exit(2);
  uint32_t *mem = malloc(sizeof(uint32_t) * 4096);
  addr[0] = 0x81;
  addr[1] = 0x80;
  addr[2] = 0x80;
  addr[3] = 0x00;
  addr[4] = 0x81;
  addr[5] = 0x80;
  addr[6] = 0x80;
  addr[7] = 0x00;
  addr[8] = 0x81;
  addr[9] = 0x80;
  addr[10] = 0x80;
  addr[11] = 0x00;
  for (int i = 12; i < 4096; i++) {
    addr[i] = 1;
  }
  init();
  read_ints(0, addr, mem, 4087);
  assert(4087 == mem[4086]);
  for (int i = 0; i < 4096; i++) {
    addr[i] = 1;
  }
  read_ints(0, addr, mem, 4096);
  assert(4096 == mem[4095]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<topol_is_connected>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    $0x0,%eax
  cmp    $0x1,%esi
  jbe    L33
  mov    %rdi,%r12
  mov    0x10(%rdi),%rsi
  mov    0x8(%rdi),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L58
L0:
  mov    $0x1,%ebp
  mov    $0x1,%ebx
  jmp    L45
L58:
  mov    0x18(%r12),%rsi
  mov    0x8(%r12),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L0
  mov    (%r12),%rax
  mov    0x8(%r12),%rdx
  mov    %rdx,(%r12)
  mov    %rax,0x8(%r12)
  jmp    L0
L8:
  mov    0x0(%r13),%rax
  mov    (%r15),%rdx
  mov    %rdx,0x0(%r13)
  mov    %rax,(%r15)
L24:
  add    $0x1,%ebx
  add    $0x2,%ebp
  cmp    %ebx,0xc(%rsp)
  je     L71
L45:
  mov    %ebp,%eax
  lea    (%r12,%rax,8),%r14
  lea    (%rbx,%rbx,1),%eax
  mov    %eax,%eax
  lea    (%r12,%rax,8),%r13
  mov    (%r14),%rsi
  mov    0x0(%r13),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L24
  lea    0x2(%rbp),%eax
  lea    (%r12,%rax,8),%r15
  mov    (%r14),%rsi
  mov    (%r15),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L8
  mov    $0x0,%eax
  jmp    L33
L71:
  mov    $0x1,%eax
L33:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int topol_is_connected(char **ids, unsigned int n) {
  unsigned int i;
  char *idtemp;
  if (n <= 1)
    return 0;
  if (strcmp(ids[1], ids[2]) && strcmp(ids[1], ids[3])) {
    idtemp = ids[0];
    ids[0] = ids[1];
    ids[1] = idtemp;
  }
  for (i = 1; i < n; i++) {
    if (strcmp(ids[2 * i], ids[2 * i - 1]) == 0) {
      continue;
    } else if (strcmp(ids[2 * i + 1], ids[2 * i - 1]) == 0) {
      idtemp = ids[2 * i];
      ids[2 * i] = ids[2 * i + 1];
      ids[2 * i + 1] = idtemp;
    } else {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<topol_is_connected>:
  endbr64
  cmp    $0x1,%esi
  jbe    L64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x10(%rdi),%rsi
  mov    0x8(%rdi),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
L48:
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L52:
  add    $0x1,%ebp
  add    $0x2,%ebx
  cmp    %ebp,%r13d
  je     L32
L23:
  mov    %ebx,%eax
  lea    (%r12,%rax,8),%r15
  lea    0x0(%rbp,%rbp,1),%eax
  lea    (%r12,%rax,8),%r14
  mov    (%r15),%rsi
  mov    (%r14),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L52
  lea    0x2(%rbx),%eax
  mov    (%r15),%rsi
  lea    (%r12,%rax,8),%rdx
  mov    %rax,%rbx
  mov    (%rdx),%rdi
  mov    %rdx,0x8(%rsp)
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
  mov    0x8(%rsp),%rdx
  mov    (%r14),%rax
  add    $0x1,%ebp
  mov    (%rdx),%rcx
  mov    %rcx,(%r14)
  mov    %rax,(%rdx)
  cmp    %ebp,%r13d
  jne    L23
L32:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L44:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L64:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    0x18(%r12),%rsi
  mov    0x8(%r12),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L48
  mov    (%r12),%rax
  mov    0x8(%r12),%rdx
  mov    %rax,0x8(%r12)
  mov    %rdx,(%r12)
  jmp    L48
```

assistant: ```c
int topol_is_connected(char **ids, unsigned int n) {
  unsigned int i;
  char *idtemp;
  if (n <= 1)
    return 0;
  if (strcmp(ids[1], ids[2]) && strcmp(ids[1], ids[3])) {
    idtemp = ids[0];
    ids[0] = ids[1];
    ids[1] = idtemp;
  }
  for (i = 1; i < n; i++) {
    if (strcmp(ids[2 * i], ids[2 * i - 1]) == 0) {
      continue;
    } else if (strcmp(ids[2 * i + 1], ids[2 * i - 1]) == 0) {
      idtemp = ids[2 * i];
      ids[2 * i] = ids[2 * i + 1];
      ids[2 * i + 1] = idtemp;
    } else {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<topol_is_connected>:
  endbr64
  cmp    $0x1,%esi
  jbe    L1
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x10(%rdi),%rsi
  mov    0x8(%rdi),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L23
L63:
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  jmp    L71
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%ebp
  add    $0x2,%ebx
  cmp    %ebp,%r13d
  je     L50
L71:
  mov    %ebx,%eax
  lea    (%r12,%rax,8),%r15
  lea    0x0(%rbp,%rbp,1),%eax
  lea    (%r12,%rax,8),%r14
  mov    (%r15),%rsi
  mov    (%r14),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L2
  lea    0x2(%rbx),%eax
  mov    (%r15),%rsi
  mov    (%r12,%rax,8),%rdi
  mov    %rax,%rbx
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L31
  movdqu (%r14),%xmm0
  add    $0x1,%ebp
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,(%r14)
  cmp    %ebp,%r13d
  jne    L71
L50:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    0x18(%r12),%rsi
  mov    0x8(%r12),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L63
  movdqu (%r12),%xmm0
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,(%r12)
  jmp    L63
```

assistant: ```c
int topol_is_connected(char **ids, unsigned int n) {
  unsigned int i;
  char *idtemp;
  if (n <= 1)
    return 0;
  if (strcmp(ids[1], ids[2]) && strcmp(ids[1], ids[3])) {
    idtemp = ids[0];
    ids[0] = ids[1];
    ids[1] = idtemp;
  }
  for (i = 1; i < n; i++) {
    if (strcmp(ids[2 * i], ids[2 * i - 1]) == 0) {
      continue;
    } else if (strcmp(ids[2 * i + 1], ids[2 * i - 1]) == 0) {
      idtemp = ids[2 * i];
      ids[2 * i] = ids[2 * i + 1];
      ids[2 * i + 1] = idtemp;
    } else {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D38
data_type: string
name: parse_data
arguments: data_tag: D20
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string
name: parse_data
arguments: data_tag: D42
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string
name: parse_data
arguments: data_tag: D31
data_type: string
name: parse_data
arguments: data_tag: D25
data_type: string
name: parse_data
arguments: data_tag: D79
data_type: string

tool: D38: Menu:


tool: D20: 1 - Search a number.


tool: D30: 2 - Insert a number in the beginning.


tool: D42: 3 - Insert a number in the ending.


tool: D6: 4 - Print a list.


tool: D31: 5 - Make 2 list became 1!


tool: D25: 0 - Exit
>> 

tool: D79: %i

assistant: ```c
int menu(void) {
  int o;
  printf("Menu:\n");
  printf("1 - Search a number.\n");
  printf("2 - Insert a number in the beginning.\n");
  printf("3 - Insert a number in the ending.\n");
  printf("4 - Print a list.\n");
  printf("5 - Make 2 list became 1!\n");
  printf("0 - Exit\n>> ");
  scanf("%i", &o);
  return o;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D58
datatype: string
name: retrieve_data
arguments: label: D47
datatype: string
name: retrieve_data
arguments: label: D64
datatype: string
name: retrieve_data
arguments: label: D65
datatype: string
name: retrieve_data
arguments: label: D36
datatype: string
name: retrieve_data
arguments: label: D31
datatype: string
name: retrieve_data
arguments: label: D8
datatype: string

tool: D3: Menu:


tool: D58: 1 - Search a number.


tool: D47: 2 - Insert a number in the beginning.


tool: D64: 3 - Insert a number in the ending.


tool: D65: 4 - Print a list.


tool: D36: 5 - Make 2 list became 1!


tool: D31: 0 - Exit
>> 

tool: D8: %i

assistant: ```c
int menu(void) {
  int o;
  printf("Menu:\n");
  printf("1 - Search a number.\n");
  printf("2 - Insert a number in the beginning.\n");
  printf("3 - Insert a number in the ending.\n");
  printf("4 - Print a list.\n");
  printf("5 - Make 2 list became 1!\n");
  printf("0 - Exit\n>> ");
  scanf("%i", &o);
  return o;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  lea    D73(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D73
type_infered: string
name: extract_symbolic_data
arguments: tag: D52
type_infered: string
name: extract_symbolic_data
arguments: tag: D34
type_infered: string
name: extract_symbolic_data
arguments: tag: D66
type_infered: string
name: extract_symbolic_data
arguments: tag: D68
type_infered: string
name: extract_symbolic_data
arguments: tag: D58
type_infered: string
name: extract_symbolic_data
arguments: tag: D51
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D73: Menu:


tool: D52: 1 - Search a number.


tool: D34: 2 - Insert a number in the beginning.


tool: D66: 3 - Insert a number in the ending.


tool: D68: 4 - Print a list.


tool: D58: 5 - Make 2 list became 1!


tool: D51: 0 - Exit
>> 

tool: D13: %i

assistant: ```c
int menu(void) {
  int o;
  printf("Menu:\n");
  printf("1 - Search a number.\n");
  printf("2 - Insert a number in the beginning.\n");
  printf("3 - Insert a number in the ending.\n");
  printf("4 - Print a list.\n");
  printf("5 - Make 2 list became 1!\n");
  printf("0 - Exit\n>> ");
  scanf("%i", &o);
  return o;
}
```
user: What is the c source code of the assembly code below?

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D60(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D57(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string
name: parse_data
arguments: tag: D21
datatype: string
name: parse_data
arguments: tag: D60
datatype: string
name: parse_data
arguments: tag: D43
datatype: string
name: parse_data
arguments: tag: D42
datatype: string
name: parse_data
arguments: tag: D73
datatype: string
name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D57
datatype: string

tool: D2: Menu:


tool: D21: 1 - Search a number.


tool: D60: 2 - Insert a number in the beginning.


tool: D43: 3 - Insert a number in the ending.


tool: D42: 4 - Print a list.


tool: D73: 5 - Make 2 list became 1!


tool: D4: 0 - Exit
>> 

tool: D57: %i

assistant: ```c
int menu(void) {
  int o;
  printf("Menu:\n");
  printf("1 - Search a number.\n");
  printf("2 - Insert a number in the beginning.\n");
  printf("3 - Insert a number in the ending.\n");
  printf("4 - Print a list.\n");
  printf("5 - Make 2 list became 1!\n");
  printf("0 - Exit\n>> ");
  scanf("%i", &o);
  return o;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gostmac>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r15
  test   %esi,%esi
  je     L5
  mov    %rdi,%r13
  mov    %rcx,%r12
  mov    %esi,%esi
  shl    $0x4,%rsi
  lea    (%rdi,%rsi,1),%r14
  mov    $0x0,%ebx
L0:
  xor    0x0(%r13),%rbx
  add    $0x10,%r13
  mov    -0x8(%r13),%rbp
  mov    %rbx,%rdi
  add    (%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbp
  mov    %rbp,%rdi
  add    0x8(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbx
  mov    %rbx,%rdi
  add    0x10(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbp
  mov    %rbp,%rdi
  add    0x18(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbx
  mov    %rbx,%rdi
  add    0x20(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbp
  mov    %rbp,%rdi
  add    0x28(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbx
  mov    %rbx,%rdi
  add    0x30(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbp
  mov    %rbp,%rdi
  add    0x38(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbx
  mov    %rbx,%rdi
  add    (%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbp
  mov    %rbp,%rdi
  add    0x8(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbx
  mov    %rbx,%rdi
  add    0x10(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbp
  mov    %rbp,%rdi
  add    0x18(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbx
  mov    %rbx,%rdi
  add    0x20(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbp
  mov    %rbp,%rdi
  add    0x28(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbx
  mov    %rbx,%rdi
  add    0x30(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbp
  mov    %rbp,%rdi
  add    0x38(%r12),%rdi
  call   <f@plt>
  xor    %rax,%rbx
  cmp    %r13,%r14
  jne    L0
L2:
  mov    %rbx,(%r15)
  mov    %rbp,0x8(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L2
```

assistant: ```c
void gostmac(uint32_t const *in, int len, uint32_t out[2], uint32_t const key[8]) {
  register uint32_t n1, n2;
  n1 = 0;
  n2 = 0;
  while (len--) {
    n1 ^= *in++;
    n2 = *in++;
    n2 ^= f(n1 + key[0]);
    n1 ^= f(n2 + key[1]);
    n2 ^= f(n1 + key[2]);
    n1 ^= f(n2 + key[3]);
    n2 ^= f(n1 + key[4]);
    n1 ^= f(n2 + key[5]);
    n2 ^= f(n1 + key[6]);
    n1 ^= f(n2 + key[7]);
    n2 ^= f(n1 + key[0]);
    n1 ^= f(n2 + key[1]);
    n2 ^= f(n1 + key[2]);
    n1 ^= f(n2 + key[3]);
    n2 ^= f(n1 + key[4]);
    n1 ^= f(n2 + key[5]);
    n2 ^= f(n1 + key[6]);
    n1 ^= f(n2 + key[7]);
  }
  out[0] = n1;
  out[1] = n2;
}
```