ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fabs>:
  endbr64
  comisd D17(%rip),%xmm0
  jb     L10
L3:
  ret
L10:
  xorpd  D2(%rip),%xmm0
  jmp    L3
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: f64
name: parse_data
arguments: tag: D2
type_guessed: byte[16]

tool: D17: 0

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double fabs(double num) {
  if (num >= 0.0) {
    return num;
  } else {
    return -num;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fabs>:
  endbr64
  comisd D11(%rip),%xmm0
  jb     L1
  ret
  nop
L1:
  xorpd  D14(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type: f64
name: disassemble_data
arguments: data_tag: D14
type: byte[16]

tool: D11: 0

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double fabs(double num) {
  if (num >= 0.0) {
    return num;
  } else {
    return -num;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fabs>:
  endbr64
  comisd D6(%rip),%xmm0
  jb     L3
  ret
  nop
L3:
  xorpd  D13(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: f64
name: retrieve_data
arguments: label: D13
data_type: byte[16]

tool: D6: 0

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double fabs(double num) {
  if (num >= 0.0) {
    return num;
  } else {
    return -num;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<squareofsum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L11:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L11
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int squareofsum(int limit) {
  int sum = 0;
  int i;
  for (i = 1; i <= limit; i++) {
    sum += i;
  }
  return (sum * sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<squareofsum>:
  endbr64
  test   %edi,%edi
  jle    L19
  add    $0x1,%edi
  mov    $0x1,%edx
  mov    $0x0,%eax
L18:
  add    %edx,%eax
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L18
L14:
  imul   %eax,%eax
  ret
L19:
  mov    $0x0,%eax
  jmp    L14
```

assistant: ```c
int squareofsum(int limit) {
  int sum = 0;
  int i;
  for (i = 1; i <= limit; i++) {
    sum += i;
  }
  return (sum * sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<squareofsum>:
  endbr64
  test   %edi,%edi
  jle    L11
  add    $0x1,%edi
  mov    $0x1,%edx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  add    %edx,%eax
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L19
  imul   %eax,%eax
  ret
  nopl   (%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int squareofsum(int limit) {
  int sum = 0;
  int i;
  for (i = 1; i <= limit; i++) {
    sum += i;
  }
  return (sum * sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<squareofsum>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  jle    L86
  lea    -0x1(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L63
  mov    %edi,%ecx
  movdqa D9(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D5(%rip),%xmm3
  shr    $0x2,%ecx
  nopl   (%rax)
L6:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%ecx
  jne    L6
  movdqa %xmm0,%xmm1
  mov    %edx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  paddd  %xmm1,%xmm0
  lea    0x1(%rsi),%ecx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%edx
  je     L56
L99:
  lea    0x1(%rcx),%esi
  add    %ecx,%eax
  cmp    %esi,%edx
  jl     L56
  add    %esi,%eax
  lea    0x2(%rcx),%esi
  cmp    %esi,%edx
  jl     L56
  add    %esi,%eax
  lea    0x3(%rcx),%esi
  cmp    %esi,%edx
  jl     L56
  add    %esi,%eax
  lea    0x4(%rcx),%esi
  cmp    %esi,%edx
  jl     L56
  add    %esi,%eax
  lea    0x5(%rcx),%esi
  cmp    %esi,%edx
  jl     L56
  add    %esi,%eax
  lea    0x6(%rcx),%esi
  cmp    %esi,%edx
  jl     L56
  add    %esi,%eax
  lea    0x7(%rcx),%esi
  cmp    %esi,%edx
  jl     L56
  add    %esi,%eax
  lea    0x8(%rcx),%esi
  cmp    %esi,%edx
  jl     L56
  add    %esi,%eax
  add    $0x9,%ecx
  lea    (%rax,%rcx,1),%esi
  cmp    %ecx,%edx
  cmovge %esi,%eax
L56:
  imul   %eax,%eax
  ret
  xchg   %ax,%ax
L86:
  xor    %eax,%eax
  ret
L63:
  mov    $0x1,%ecx
  xor    %eax,%eax
  jmp    L99
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: byte[16]
name: unpack_data
arguments: data_label: D5
type_infered: byte[16]

tool: {"D9": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D5": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int squareofsum(int limit) {
  int sum = 0;
  int i;
  for (i = 1; i <= limit; i++) {
    sum += i;
  }
  return (sum * sum);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<remove_slash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L9
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L9
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L9:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int remove_slash(char *buf) {
  int len;
  len = strlen(buf);
  if (len > 1 && buf[len - 1] == '/') {
    buf[--len] = '\0';
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<remove_slash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L23
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  cmpb   $0x2f,(%rdx)
  je     L0
L23:
  pop    %rbx
  ret
L0:
  sub    $0x1,%eax
  movb   $0x0,(%rdx)
  jmp    L23
```

assistant: ```c
int remove_slash(char *buf) {
  int len;
  len = strlen(buf);
  if (len > 1 && buf[len - 1] == '/') {
    buf[--len] = '\0';
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_slash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L19
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  cmpb   $0x2f,(%rdx)
  je     L11
L19:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L11:
  movb   $0x0,(%rdx)
  sub    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int remove_slash(char *buf) {
  int len;
  len = strlen(buf);
  if (len > 1 && buf[len - 1] == '/') {
    buf[--len] = '\0';
  }
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<remove_slash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L16
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  cmpb   $0x2f,(%rdx)
  je     L14
L16:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L14:
  movb   $0x0,(%rdx)
  sub    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int remove_slash(char *buf) {
  int len;
  len = strlen(buf);
  if (len > 1 && buf[len - 1] == '/') {
    buf[--len] = '\0';
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fun(int *y) {
  int x = 1;
  x = x + 1;
  ;
  x = x + 1;
  *y = x;
}
```
user: What is the c source code of the assembly code below:

```asm
<fun>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
void fun(int *y) {
  int x = 1;
  x = x + 1;
  ;
  x = x + 1;
  *y = x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fun>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
void fun(int *y) {
  int x = 1;
  x = x + 1;
  ;
  x = x + 1;
  *y = x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fun>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
void fun(int *y) {
  int x = 1;
  x = x + 1;
  ;
  x = x + 1;
  *y = x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninit_in_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <consume@plt>
  call   <produce@plt>
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0x63,-0x8(%rbp)
  jle    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void uninit_in_loop() {
  int produce(void);
  void consume(int);
  for (int n = 0; n < 100; ++n) {
    int k;
    consume(k);
    k = produce();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uninit_in_loop>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
L6:
  call   <consume@plt>
  call   <produce@plt>
  mov    %eax,%edi
  sub    $0x1,%ebx
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
void uninit_in_loop() {
  int produce(void);
  void consume(int);
  for (int n = 0; n < 100; ++n) {
    int k;
    consume(k);
    k = produce();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninit_in_loop>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  call   <consume@plt>
  call   <produce@plt>
  mov    %eax,%edi
  sub    $0x1,%ebx
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void uninit_in_loop() {
  int produce(void);
  void consume(int);
  for (int n = 0; n < 100; ++n) {
    int k;
    consume(k);
    k = produce();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninit_in_loop>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  call   <consume@plt>
  call   <produce@plt>
  mov    %eax,%edi
  sub    $0x1,%ebx
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void uninit_in_loop() {
  int produce(void);
  void consume(int);
  for (int n = 0; n < 100; ++n) {
    int k;
    consume(k);
    k = produce();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<partition_restr_from_id>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %ecx,%ebx
  mov    %r8,%r15
  mov    %r9,%r14
  lea    0x1(%rsi),%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%edi
  test   %ecx,%ecx
  js     L47
  shr    $0x2,%rax
  add    $0x1,%rax
  movslq %esi,%rdx
  imul   %rdx,%rax
  cmp    %ecx,(%r12,%rax,4)
  setg   %dil
  movzbl %dil,%edi
L47:
  call   <assert@plt>
  movl   $0x0,(%r14)
  mov    0x8(%rsp),%r8
  shr    $0x2,%r8
  lea    0x1(%r8),%rax
  movslq %ebp,%rdx
  imul   %rdx,%rax
  not    %ebx
  add    (%r12,%rax,4),%ebx
  movslq %r13d,%r9
  jmp    L64
L39:
  add    $0x4,%rdx
  add    $0x1,%eax
L31:
  lea    -0x1(%rax),%esi
  mov    (%rdx),%ecx
  cmp    %ebx,%ecx
  jl     L39
  jg     L18
  mov    %eax,%esi
  cmp    %eax,%ebp
  jne    L39
L18:
  movslq %edi,%rdi
  mov    %esi,-0x4(%r15,%rdi,4)
  lea    -0x1(%rsi),%eax
  cltq
  movslq %ebp,%rdx
  imul   %r8,%rdx
  add    %rdx,%rax
  sub    (%r12,%rax,4),%ebx
  sub    %esi,%ebp
  cmp    %ebp,%r13d
  jg     L44
L64:
  mov    (%r14),%eax
  lea    0x1(%rax),%edi
  mov    %edi,(%r14)
  movslq %ebp,%rax
  imul   %r8,%rax
  add    %r9,%rax
  lea    (%r12,%rax,4),%rdx
  lea    0x1(%r13),%eax
  jmp    L31
L44:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void partition_restr_from_id(void *p_ptr, int n, int k, int id, int *part, int *num_part) {
  int(*p)[n + 1][n + 1] = (int(*)[n + 1][n + 1]) p_ptr;
  assert(id >= 0 && id < (*p)[n][n]);
  int n_loc = n;
  *num_part = 0;
  int psn = (*p)[n][n] - id - 1;
A:
  (*num_part)++;
  int m = k;
B:
  if ((*p)[n_loc][m] < psn) {
    m++;
    goto B;
  }
  if ((*p)[n_loc][m] > psn) {
  C:
    part[*num_part - 1] = m;
    psn -= (*p)[n_loc][m - 1];
    n_loc -= m;
    if (n_loc < k) {
      return;
    } else {
      goto A;
    }
  } else {
    m++;
  }
  if (m == n_loc) {
    goto C;
  } else {
    goto B;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<partition_restr_from_id>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %ecx,%esi
  lea    0x1(%rbx),%r14d
  movslq %r14d,%r14
  shl    $0x2,%r14
  sub    $0x28,%rsp
  shr    $0x2,%r14
  test   %ecx,%ecx
  js     L4
  lea    0x1(%r14),%rdx
  movslq %ebx,%r12
  xor    %edi,%edi
  mov    %rdx,%rax
  imul   %r12,%rax
  cmp    %ecx,0x0(%rbp,%rax,4)
  setg   %dil
L70:
  mov    %rdx,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %esi,0xc(%rsp)
  call   <assert@plt>
  mov    0x18(%rsp),%rdx
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  mov    0x10(%rsp),%r9
  movslq %r13d,%r8
  lea    0x1(%r13),%edi
  imul   %r12,%rdx
  not    %esi
  movl   $0x0,(%r9)
  add    0x0(%rbp,%rdx,4),%esi
  nopl   0x0(%rax)
L30:
  lea    0x1(%rax),%r11d
  mov    %r12,%rax
  imul   %r14,%rax
  mov    %r11d,(%r9)
  add    %r8,%rax
  lea    0x0(%rbp,%rax,4),%rdx
  mov    %edi,%eax
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %eax,%r10d
  cmp    %eax,%ebx
  je     L60
L11:
  add    $0x4,%rdx
  add    $0x1,%eax
L46:
  lea    -0x1(%rax),%ecx
  cmp    %esi,(%rdx)
  jl     L11
  jle    L47
  mov    %ecx,%r10d
  lea    -0x2(%rax),%ecx
L60:
  imul   %r14,%r12
  movslq %ecx,%rcx
  movslq %r11d,%rax
  sub    %r10d,%ebx
  mov    %r10d,-0x4(%r15,%rax,4)
  add    %r12,%rcx
  sub    0x0(%rbp,%rcx,4),%esi
  cmp    %ebx,%r13d
  jg     L45
  mov    (%r9),%eax
  movslq %ebx,%r12
  jmp    L30
L45:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  xor    %edi,%edi
  lea    0x1(%r14),%rdx
  movslq %ebx,%r12
  jmp    L70
```

assistant: ```c
void partition_restr_from_id(void *p_ptr, int n, int k, int id, int *part, int *num_part) {
  int(*p)[n + 1][n + 1] = (int(*)[n + 1][n + 1]) p_ptr;
  assert(id >= 0 && id < (*p)[n][n]);
  int n_loc = n;
  *num_part = 0;
  int psn = (*p)[n][n] - id - 1;
A:
  (*num_part)++;
  int m = k;
B:
  if ((*p)[n_loc][m] < psn) {
    m++;
    goto B;
  }
  if ((*p)[n_loc][m] > psn) {
  C:
    part[*num_part - 1] = m;
    psn -= (*p)[n_loc][m - 1];
    n_loc -= m;
    if (n_loc < k) {
      return;
    } else {
      goto A;
    }
  } else {
    m++;
  }
  if (m == n_loc) {
    goto C;
  } else {
    goto B;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<partition_restr_from_id>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %ecx,%esi
  lea    0x1(%rbx),%r14d
  movslq %r14d,%r14
  shl    $0x2,%r14
  sub    $0x28,%rsp
  shr    $0x2,%r14
  test   %ecx,%ecx
  js     L79
  lea    0x1(%r14),%rdx
  movslq %ebx,%r12
  xor    %edi,%edi
  mov    %rdx,%rax
  imul   %r12,%rax
  cmp    %ecx,0x0(%rbp,%rax,4)
  setg   %dil
L36:
  mov    %rdx,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %esi,0xc(%rsp)
  call   <assert@plt>
  mov    0x18(%rsp),%rdx
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  mov    0x10(%rsp),%r9
  movslq %r13d,%r8
  lea    0x1(%r13),%edi
  imul   %r12,%rdx
  not    %esi
  movl   $0x0,(%r9)
  add    0x0(%rbp,%rdx,4),%esi
  nopl   0x0(%rax)
L25:
  lea    0x1(%rax),%r11d
  mov    %r12,%rax
  imul   %r14,%rax
  mov    %r11d,(%r9)
  add    %r8,%rax
  lea    0x0(%rbp,%rax,4),%rdx
  mov    %edi,%eax
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %eax,%r10d
  cmp    %eax,%ebx
  je     L56
L35:
  add    $0x4,%rdx
  add    $0x1,%eax
L68:
  lea    -0x1(%rax),%ecx
  cmp    %esi,(%rdx)
  jl     L35
  jle    L15
  mov    %ecx,%r10d
  lea    -0x2(%rax),%ecx
L56:
  imul   %r14,%r12
  movslq %ecx,%rcx
  movslq %r11d,%rax
  sub    %r10d,%ebx
  mov    %r10d,-0x4(%r15,%rax,4)
  add    %r12,%rcx
  sub    0x0(%rbp,%rcx,4),%esi
  cmp    %ebx,%r13d
  jg     L20
  mov    (%r9),%eax
  movslq %ebx,%r12
  jmp    L25
L20:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  xor    %edi,%edi
  lea    0x1(%r14),%rdx
  movslq %ebx,%r12
  jmp    L36
```

assistant: ```c
void partition_restr_from_id(void *p_ptr, int n, int k, int id, int *part, int *num_part) {
  int(*p)[n + 1][n + 1] = (int(*)[n + 1][n + 1]) p_ptr;
  assert(id >= 0 && id < (*p)[n][n]);
  int n_loc = n;
  *num_part = 0;
  int psn = (*p)[n][n] - id - 1;
A:
  (*num_part)++;
  int m = k;
B:
  if ((*p)[n_loc][m] < psn) {
    m++;
    goto B;
  }
  if ((*p)[n_loc][m] > psn) {
  C:
    part[*num_part - 1] = m;
    psn -= (*p)[n_loc][m - 1];
    n_loc -= m;
    if (n_loc < k) {
      return;
    } else {
      goto A;
    }
  } else {
    m++;
  }
  if (m == n_loc) {
    goto C;
  } else {
    goto B;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <countSmaller@plt>
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L1
L13:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L1:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L13
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string
name: parse_data
arguments: data_label: D16
data_type: string

tool: D4: %d 

tool: D16: pause

assistant: ```c
int main() {
  int nums[] = {1, 9, 7, 8, 5};
  int *returnSize = malloc(sizeof(int));
  int *result = countSmaller(nums, 5, returnSize);
  for (int i = 0; i < *returnSize; i++) {
    printf("%d ", result[i]);
  }
  system("pause");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x7,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rsp,%rdi
  mov    %rax,%rdx
  mov    $0x5,%esi
  call   <countSmaller@plt>
  cmpl   $0x0,0x0(%rbp)
  jle    L14
  mov    %rax,%r12
  mov    $0x0,%ebx
  lea    D19(%rip),%r13
L21:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x0(%rbp)
  jg     L21
L14:
  lea    D9(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string

tool: D19: %d 

tool: D9: pause

assistant: ```c
int main() {
  int nums[] = {1, 9, 7, 8, 5};
  int *returnSize = malloc(sizeof(int));
  int *result = countSmaller(nums, 5, returnSize);
  for (int i = 0; i < *returnSize; i++) {
    printf("%d ", result[i]);
  }
  system("pause");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x4,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x900000001,%rax
  movl   $0x5,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rsp,%rdi
  mov    $0x5,%esi
  mov    %rax,%rbp
  mov    %rax,%rdx
  call   <countSmaller@plt>
  mov    0x0(%rbp),%edx
  test   %edx,%edx
  jle    L12
  mov    %rax,%r12
  xor    %ebx,%ebx
  lea    D4(%rip),%r13
  nopl   0x0(%rax)
L9:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x0(%rbp)
  jg     L9
L12:
  lea    D5(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D4: %d 

tool: D5: pause

assistant: ```c
int main() {
  int nums[] = {1, 9, 7, 8, 5};
  int *returnSize = malloc(sizeof(int));
  int *result = countSmaller(nums, 5, returnSize);
  for (int i = 0; i < *returnSize; i++) {
    printf("%d ", result[i]);
  }
  system("pause");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x4,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  mov    %rsp,%rdi
  mov    $0x5,%esi
  mov    %rax,%rbp
  mov    %rax,%rdx
  call   <countSmaller@plt>
  mov    0x0(%rbp),%edx
  test   %edx,%edx
  jle    L2
  mov    %rax,%r12
  xor    %ebx,%ebx
  lea    D27(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x0(%rbp)
  jg     L21
L2:
  lea    D25(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D27
data_type: string
name: disassemble_data
arguments: data_tag: D25
data_type: string

tool: {"D9": [0x01,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: D27: %d 

tool: D25: pause

assistant: ```c
int main() {
  int nums[] = {1, 9, 7, 8, 5};
  int *returnSize = malloc(sizeof(int));
  int *result = countSmaller(nums, 5, returnSize);
  for (int i = 0; i < *returnSize; i++) {
    printf("%d ", result[i]);
  }
  system("pause");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fn2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int fn2(int x) {
  int i = x;
  inline __attribute__((always_inline)) int should_not_appear2(void) { return i; }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fn2>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int fn2(int x) {
  int i = x;
  inline __attribute__((always_inline)) int should_not_appear2(void) { return i; }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn2>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int fn2(int x) {
  int i = x;
  inline __attribute__((always_inline)) int should_not_appear2(void) { return i; }
  return x;
}
```