user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D118(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D118(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D118(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D118(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D118(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x0,-0x40(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D178(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D128(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x28(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x3c(%rbp)
  lea    D179(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm2
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  mov    -0x3c(%rbp),%edx
  mov    %edx,%esi
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  movl   $0x0,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L9
L17:
  mov    -0x40(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <combinaciones@plt>
  movsd  %xmm0,-0x48(%rbp)
  mov    -0x3c(%rbp),%eax
  sub    -0x40(%rbp),%eax
  mov    %eax,%edx
  movsd  -0x38(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <potencia@plt>
  movapd %xmm0,%xmm4
  mulsd  -0x48(%rbp),%xmm4
  movsd  %xmm4,-0x48(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  mov    -0x40(%rbp),%edx
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <potencia@plt>
  mulsd  -0x48(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x40(%rbp)
L9:
  mov    -0x40(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L17
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D118
datatype: f64
name: parse_data
arguments: data_tag: D20
datatype: string
name: parse_data
arguments: data_tag: D178
datatype: string
name: parse_data
arguments: data_tag: D29
datatype: string
name: parse_data
arguments: data_tag: D128
datatype: string
name: parse_data
arguments: data_tag: D84
datatype: string
name: parse_data
arguments: data_tag: D179
datatype: string
name: parse_data
arguments: data_tag: D45
datatype: string
name: parse_data
arguments: data_tag: D26
datatype: string
name: parse_data
arguments: data_tag: D11
datatype: string

tool: D118: 1

tool: D20: Binomio (ax + by)^n:

tool: D178: a = 

tool: D29: %lf

tool: D128: b = 

tool: D84: n = 

tool: D179: x = 

tool: D45: y = 

tool: D26: Calcular (%g*%g + %g*%g)^%d:


tool: D11: Resultado: %g.


assistant: ```c
main() {
  double a = 1, b = 1, m = 1, x = 1, y = 1, result = 0;
  int n = 1, k = 0;
  printf("Binomio (ax + by)^n:\n");
  printf("a = ");
  scanf("%lf", &a);
  printf("b = ");
  scanf("%lf", &b);
  printf("n = ");
  scanf("%lf", &m);
  n = (int)m;
  printf("x = ");
  scanf("%lf", &x);
  printf("y = ");
  scanf("%lf", &y);
  printf("Calcular (%g*%g + %g*%g)^%d:\n", a, x, b, y, n);
  for (k = 0, result = 0; k <= n; k++)
    result += combinaciones(n, k) * potencia(a * x, n - k) * potencia(b * y, k);
  printf("Resultado: %g.\n", result);
}
```