ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lpc_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L15
L17:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xd,-0x1(%rbx,%rax,1)
  je     L14
  pop    %rbx
  ret
  nopl   0x0(%rax)
L14:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L15:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L17
```

assistant: ```c
void lpc_trim(char *s) {
  if (s[strlen(s) - 1] == '\n')
    s[strlen(s) - 1] = '\0';
  if (s[strlen(s) - 1] == '\r')
    s[strlen(s) - 1] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<lpc_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L8
L1:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xd,-0x1(%rbx,%rax,1)
  je     L10
  pop    %rbx
  ret
  nopl   0x0(%rax)
L10:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L1
```

assistant: ```c
void lpc_trim(char *s) {
  if (s[strlen(s) - 1] == '\n')
    s[strlen(s) - 1] = '\0';
  if (s[strlen(s) - 1] == '\r')
    s[strlen(s) - 1] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<resp_read_position_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0x14(%rbp)
  je     L9
  cmpl   $0x1,-0x14(%rbp)
  jne    L16
L9:
  mov    -0x20(%rbp),%rax
  movl   $0x80,(%rax)
L16:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    -0x4(%rbp),%edx
  sar    $0x18,%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x14,%rax
  mov    -0x4(%rbp),%edx
  sar    $0x10,%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    -0x4(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1c(%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x24,%rax
  mov    -0x14(%rbp),%edx
  sar    $0x10,%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  add    $0x20,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x28,%rax
  mov    -0x14(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  add    $0x18,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x2c,%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  add    $0x1c,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    $0x20,%eax
  leave
  ret
```

assistant: ```c
int resp_read_position_long(loff_t pos, uint8_t *buf, uint8_t *sam_stat) {
  uint64_t partition = 1L;
  ;
  memset(buf, 0, 32);
  if ((pos == 0) || (pos == 1))
    buf[0] = 0x80;
  buf[4] = (partition >> 24);
  buf[5] = (partition >> 16);
  buf[6] = (partition >> 8);
  buf[7] = partition;
  buf[8] = buf[9] = (pos >> 16);
  buf[6] = buf[10] = (pos >> 8);
  buf[7] = buf[11] = pos;
  return 32;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<resp_read_position_long>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  cmp    $0x1,%ebp
  jbe    L10
L18:
  movl   $0x0,0x10(%rbx)
  movl   $0x0,0x14(%rbx)
  mov    %ebp,%eax
  sar    $0x10,%eax
  mov    %eax,0x24(%rbx)
  mov    %eax,0x20(%rbx)
  mov    %ebp,%eax
  sar    $0x8,%eax
  mov    %eax,0x28(%rbx)
  mov    %eax,0x18(%rbx)
  mov    %ebp,0x2c(%rbx)
  mov    %ebp,0x1c(%rbx)
  mov    $0x20,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  movl   $0x80,(%rbx)
  jmp    L18
```

assistant: ```c
int resp_read_position_long(loff_t pos, uint8_t *buf, uint8_t *sam_stat) {
  uint64_t partition = 1L;
  ;
  memset(buf, 0, 32);
  if ((pos == 0) || (pos == 1))
    buf[0] = 0x80;
  buf[4] = (partition >> 24);
  buf[5] = (partition >> 16);
  buf[6] = (partition >> 8);
  buf[7] = partition;
  buf[8] = buf[9] = (pos >> 16);
  buf[6] = buf[10] = (pos >> 8);
  buf[7] = buf[11] = pos;
  return 32;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<resp_read_position_long>:
  endbr64
  push   %rbp
  mov    $0x20,%edx
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  cmp    $0x1,%ebp
  ja     L2
  movl   $0x80,(%rbx)
L2:
  mov    %ebp,%eax
  mov    %ebp,0x2c(%rbx)
  sar    $0x10,%eax
  mov    %ebp,0x1c(%rbx)
  mov    %eax,0x24(%rbx)
  mov    %eax,0x20(%rbx)
  mov    %ebp,%eax
  sar    $0x8,%eax
  movq   $0x0,0x10(%rbx)
  mov    %eax,0x28(%rbx)
  mov    %eax,0x18(%rbx)
  add    $0x8,%rsp
  mov    $0x20,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int resp_read_position_long(loff_t pos, uint8_t *buf, uint8_t *sam_stat) {
  uint64_t partition = 1L;
  ;
  memset(buf, 0, 32);
  if ((pos == 0) || (pos == 1))
    buf[0] = 0x80;
  buf[4] = (partition >> 24);
  buf[5] = (partition >> 16);
  buf[6] = (partition >> 8);
  buf[7] = partition;
  buf[8] = buf[9] = (pos >> 16);
  buf[6] = buf[10] = (pos >> 8);
  buf[7] = buf[11] = pos;
  return 32;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<resp_read_position_long>:
  endbr64
  push   %rbp
  mov    $0x20,%edx
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  cmp    $0x1,%ebp
  ja     L9
  movl   $0x80,(%rbx)
L9:
  mov    %ebp,%eax
  movd   %ebp,%xmm2
  movq   $0x0,0x10(%rbx)
  sar    $0x10,%eax
  movd   %eax,%xmm1
  mov    %ebp,%eax
  sar    $0x8,%eax
  punpckldq %xmm1,%xmm1
  movd   %eax,%xmm0
  mov    $0x20,%eax
  punpckldq %xmm2,%xmm0
  movq   %xmm0,0x28(%rbx)
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,0x18(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int resp_read_position_long(loff_t pos, uint8_t *buf, uint8_t *sam_stat) {
  uint64_t partition = 1L;
  ;
  memset(buf, 0, 32);
  if ((pos == 0) || (pos == 1))
    buf[0] = 0x80;
  buf[4] = (partition >> 24);
  buf[5] = (partition >> 16);
  buf[6] = (partition >> 8);
  buf[7] = partition;
  buf[8] = buf[9] = (pos >> 16);
  buf[6] = buf[10] = (pos >> 8);
  buf[7] = buf[11] = pos;
  return 32;
}
```
user: What is the c source code of the assembly code below:

```asm
<ahead_b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L17
L30:
  addl   $0x1,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L44
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <datum_b@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L44
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <try_c@plt>
  cmp    $0x1,%eax
  jle    L30
L44:
  cmpq   $0x0,-0x28(%rbp)
  je     L21
  mov    -0x28(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
L21:
  mov    -0x8(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ahead_b(const unsigned char source[], int position, int length, int *p_nx) {
  int count = 0;
  int i, incr;
  for (i = position; (i < length) && (incr = datum_b(source, i, length)) && (try_c(source, i, length) < 2); i += incr) {
    count++;
  }
  if (p_nx != NULL) {
    *p_nx = count;
  }
  return i - position;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ahead_b>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r15d
  mov    %edx,%r12d
  mov    %rcx,0x8(%rsp)
  mov    %esi,%ebx
  mov    $0x0,%r14d
  cmp    %edx,%esi
  jge    L43
L3:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <datum_b@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L43
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <try_c@plt>
  cmp    $0x1,%eax
  jg     L43
  add    $0x1,%r14d
  add    %ebp,%ebx
  cmp    %ebx,%r12d
  jg     L3
L43:
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L28
  mov    %r14d,(%rax)
L28:
  mov    %ebx,%eax
  sub    %r15d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ahead_b(const unsigned char source[], int position, int length, int *p_nx) {
  int count = 0;
  int i, incr;
  for (i = position; (i < length) && (incr = datum_b(source, i, length)) && (try_c(source, i, length) < 2); i += incr) {
    count++;
  }
  if (p_nx != NULL) {
    *p_nx = count;
  }
  return i - position;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ahead_b>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  cmp    %edx,%esi
  jge    L16
  mov    %rdi,%r15
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %esi,%ebx
  jmp    L19
  nopl   (%rax)
L29:
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <try_c@plt>
  cmp    $0x1,%eax
  jg     L53
  add    %ebp,%ebx
  add    $0x1,%r12d
  cmp    %ebx,%r14d
  jle    L53
L19:
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <datum_b@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L29
L53:
  mov    %ebx,%eax
  sub    %r13d,%eax
L16:
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  je     L22
  mov    %r12d,(%rcx)
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ahead_b(const unsigned char source[], int position, int length, int *p_nx) {
  int count = 0;
  int i, incr;
  for (i = position; (i < length) && (incr = datum_b(source, i, length)) && (try_c(source, i, length) < 2); i += incr) {
    count++;
  }
  if (p_nx != NULL) {
    *p_nx = count;
  }
  return i - position;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ahead_b>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  cmp    %edx,%esi
  jge    L16
  mov    %rdi,%r15
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %esi,%ebx
  jmp    L6
  nopl   (%rax)
L39:
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <try_c@plt>
  cmp    $0x1,%eax
  jg     L12
  add    %ebp,%ebx
  add    $0x1,%r12d
  cmp    %ebx,%r14d
  jle    L12
L6:
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <datum_b@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L39
L12:
  mov    %ebx,%eax
  sub    %r13d,%eax
L16:
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  je     L45
  mov    %r12d,(%rcx)
L45:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ahead_b(const unsigned char source[], int position, int length, int *p_nx) {
  int count = 0;
  int i, incr;
  for (i = position; (i < length) && (incr = datum_b(source, i, length)) && (try_c(source, i, length) < 2); i += incr) {
    count++;
  }
  if (p_nx != NULL) {
    *p_nx = count;
  }
  return i - position;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    $0xffffffdb,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L19
L3:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    %al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
  addb   $0x2,-0xa(%rbp)
L19:
  cmpb   $0x0,-0xa(%rbp)
  je     L3
  movzbl -0x9(%rbp),%eax
  and    $0x68,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] = state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
      state[0UL] <<= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & (unsigned char)104;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%ecx
  xor    $0xffffffdb,%ecx
  movzbl %cl,%eax
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  shr    $0x4,%cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  and    $0x68,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] = state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
      state[0UL] <<= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & (unsigned char)104;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%ecx
  xor    $0xffffffdb,%ecx
  movzbl %cl,%eax
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  shr    $0x4,%cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  and    $0x68,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] = state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
      state[0UL] <<= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & (unsigned char)104;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%ecx
  xor    $0xffffffdb,%ecx
  movzbl %cl,%eax
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  shr    $0x4,%cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  and    $0x68,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] = state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
      state[0UL] <<= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & (unsigned char)104;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char *onoma[] = {"Georgios Georgiou", "Vasilios Vasiliou", "Ioanna Ioannidou", "Nikos Nikolaou", "Kiriakos Kiriakidis", "Kwstas Kwstantinidis", "Spyros Spyropoulos", "Dimitris Dimitropoulos", "Dimitra Dimitriadi", "Areti Aretidou", "Ilias Iliopoulos", "Kwstas Kwstoglou", "Aimilia Aimilianou", "Xristina Xristopoulou", "Theodoros Theodorou"};
  int am[] = {120, 122, 142, 130, 156, 132, 145, 133, 131, 140, 141, 150, 155, 134, 146};
  float vathmos[] = {12, 8.5, 15.5, 20, 7.5, 1, 19.5, 12, 17, 17.5, 15.5, 18, 19, 18, 19};
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char *onoma[] = {"Georgios Georgiou", "Vasilios Vasiliou", "Ioanna Ioannidou", "Nikos Nikolaou", "Kiriakos Kiriakidis", "Kwstas Kwstantinidis", "Spyros Spyropoulos", "Dimitris Dimitropoulos", "Dimitra Dimitriadi", "Areti Aretidou", "Ilias Iliopoulos", "Kwstas Kwstoglou", "Aimilia Aimilianou", "Xristina Xristopoulou", "Theodoros Theodorou"};
  int am[] = {120, 122, 142, 130, 156, 132, 145, 133, 131, 140, 141, 150, 155, 134, 146};
  float vathmos[] = {12, 8.5, 15.5, 20, 7.5, 1, 19.5, 12, 17, 17.5, 15.5, 18, 19, 18, 19};
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char *onoma[] = {"Georgios Georgiou", "Vasilios Vasiliou", "Ioanna Ioannidou", "Nikos Nikolaou", "Kiriakos Kiriakidis", "Kwstas Kwstantinidis", "Spyros Spyropoulos", "Dimitris Dimitropoulos", "Dimitra Dimitriadi", "Areti Aretidou", "Ilias Iliopoulos", "Kwstas Kwstoglou", "Aimilia Aimilianou", "Xristina Xristopoulou", "Theodoros Theodorou"};
  int am[] = {120, 122, 142, 130, 156, 132, 145, 133, 131, 140, 141, 150, 155, 134, 146};
  float vathmos[] = {12, 8.5, 15.5, 20, 7.5, 1, 19.5, 12, 17, 17.5, 15.5, 18, 19, 18, 19};
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PJWHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x20,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shr    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L18
L0:
  mov    -0xc(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  mov    -0x10(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  xor    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L11:
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L0
  mov    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int PJWHash(char *str, unsigned int len) {
  const unsigned int BitsInUnsignedInt = (unsigned int)(sizeof(unsigned int) * 8);
  const unsigned int ThreeQuarters = (unsigned int)((BitsInUnsignedInt * 3) / 4);
  const unsigned int OneEighth = (unsigned int)(BitsInUnsignedInt / 8);
  const unsigned int HighBits = (unsigned int)(0xFFFFFFFF) << (BitsInUnsignedInt - OneEighth);
  unsigned int hash = 0;
  unsigned int test = 0;
  unsigned int i = 0;
  for (; i < len; str++, i++) {
    hash = (hash << OneEighth) + (*str);
    if ((test = hash & HighBits) != 0)
      hash = ((hash ^ (test >> ThreeQuarters)) & (~HighBits));
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PJWHash>:
  endbr64
  test   %esi,%esi
  je     L46
  mov    %esi,%eax
  lea    (%rdi,%rax,1),%rcx
  mov    $0x0,%eax
  jmp    L44
L26:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  je     L18
L44:
  shl    $0x4,%eax
  movsbl (%rdi),%edx
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L26
  shr    $0x18,%edx
  xor    %edx,%eax
  and    $0xfffffff,%eax
  jmp    L26
L18:
  ret
L46:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int PJWHash(char *str, unsigned int len) {
  const unsigned int BitsInUnsignedInt = (unsigned int)(sizeof(unsigned int) * 8);
  const unsigned int ThreeQuarters = (unsigned int)((BitsInUnsignedInt * 3) / 4);
  const unsigned int OneEighth = (unsigned int)(BitsInUnsignedInt / 8);
  const unsigned int HighBits = (unsigned int)(0xFFFFFFFF) << (BitsInUnsignedInt - OneEighth);
  unsigned int hash = 0;
  unsigned int test = 0;
  unsigned int i = 0;
  for (; i < len; str++, i++) {
    hash = (hash << OneEighth) + (*str);
    if ((test = hash & HighBits) != 0)
      hash = ((hash ^ (test >> ThreeQuarters)) & (~HighBits));
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PJWHash>:
  endbr64
  test   %esi,%esi
  je     L27
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L23:
  movsbl (%rdi),%edx
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L8
  shr    $0x18,%edx
  xor    %edx,%eax
  and    $0xfffffff,%eax
L8:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L23
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int PJWHash(char *str, unsigned int len) {
  const unsigned int BitsInUnsignedInt = (unsigned int)(sizeof(unsigned int) * 8);
  const unsigned int ThreeQuarters = (unsigned int)((BitsInUnsignedInt * 3) / 4);
  const unsigned int OneEighth = (unsigned int)(BitsInUnsignedInt / 8);
  const unsigned int HighBits = (unsigned int)(0xFFFFFFFF) << (BitsInUnsignedInt - OneEighth);
  unsigned int hash = 0;
  unsigned int test = 0;
  unsigned int i = 0;
  for (; i < len; str++, i++) {
    hash = (hash << OneEighth) + (*str);
    if ((test = hash & HighBits) != 0)
      hash = ((hash ^ (test >> ThreeQuarters)) & (~HighBits));
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PJWHash>:
  endbr64
  test   %esi,%esi
  je     L0
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L22:
  movsbl (%rdi),%edx
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L27
  shr    $0x18,%edx
  xor    %edx,%eax
  and    $0xfffffff,%eax
L27:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L22
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int PJWHash(char *str, unsigned int len) {
  const unsigned int BitsInUnsignedInt = (unsigned int)(sizeof(unsigned int) * 8);
  const unsigned int ThreeQuarters = (unsigned int)((BitsInUnsignedInt * 3) / 4);
  const unsigned int OneEighth = (unsigned int)(BitsInUnsignedInt / 8);
  const unsigned int HighBits = (unsigned int)(0xFFFFFFFF) << (BitsInUnsignedInt - OneEighth);
  unsigned int hash = 0;
  unsigned int test = 0;
  unsigned int i = 0;
  for (; i < len; str++, i++) {
    hash = (hash << OneEighth) + (*str);
    if ((test = hash & HighBits) != 0)
      hash = ((hash ^ (test >> ThreeQuarters)) & (~HighBits));
  }
  return hash;
}
```