ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__uio_num_from_filename>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L104
  add    $0x1,%rdi
  mov    $0xffffffff,%ecx
  mov    $0x0,%edx
  mov    $0x3,%r8d
  mov    $0x1,%r9d
  mov    $0x2,%r10d
  jmp    L48
L16:
  test   %edx,%edx
  je     L58
  mov    $0xffffffff,%ecx
  jmp    L176
L72:
  cmp    $0x1,%edx
  je     L41
  mov    $0xffffffff,%ecx
  jmp    L176
L53:
  cmp    $0x2,%edx
  je     L197
  mov    $0xffffffff,%ecx
  jmp    L176
L85:
  movsbl %al,%eax
  test   %ecx,%ecx
  js     L155
  lea    (%rcx,%rcx,4),%edx
  lea    -0x30(%rax,%rdx,2),%ecx
  mov    %r8d,%edx
  jmp    L73
L155:
  lea    -0x30(%rax),%ecx
  mov    %r8d,%edx
  jmp    L73
L58:
  mov    %r9d,%edx
L73:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L176
L48:
  cmp    $0x6f,%al
  je     L53
  cmp    $0x75,%al
  je     L16
  cmp    $0x69,%al
  je     L72
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L132
  cmp    $0x3,%edx
  je     L85
L132:
  mov    $0xffffffff,%ecx
L176:
  mov    %ecx,%eax
  ret
L41:
  mov    %r10d,%edx
  jmp    L73
L197:
  mov    %r8d,%edx
  jmp    L73
L104:
  mov    $0xffffffff,%ecx
  jmp    L176
```

assistant: ```c
int __uio_num_from_filename(char *name) {
  enum scan_states { ss_u, ss_i, ss_o, ss_num, ss_err };
  enum scan_states state = ss_u;
  int i = 0, num = -1;
  char ch = name[0];
  while (ch && (state != ss_err)) {
    switch (ch) {
    case 'u':
      if (state == ss_u)
        state = ss_i;
      else
        state = ss_err;
      break;
    case 'i':
      if (state == ss_i)
        state = ss_o;
      else
        state = ss_err;
      break;
    case 'o':
      if (state == ss_o)
        state = ss_num;
      else
        state = ss_err;
      break;
    default:
      if ((ch >= '0') && (ch <= '9') && (state == ss_num)) {
        if (num < 0)
          num = (ch - '0');
        else
          num = (num * 10) + (ch - '0');
      } else
        state = ss_err;
    }
    i++;
    ch = name[i];
  }
  if (state == ss_err)
    num = -1;
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__uio_num_from_filename>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L18
  add    $0x1,%rdi
  mov    $0xffffffff,%r8d
  xor    %edx,%edx
  cmp    $0x6f,%al
  je     L69
  nopl   0x0(%rax,%rax,1)
L74:
  cmp    $0x75,%al
  je     L102
  cmp    $0x69,%al
  je     L148
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L18
  cmp    $0x3,%edx
  je     L96
  nopl   (%rax)
L18:
  mov    $0xffffffff,%r8d
L31:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L148:
  cmp    $0x1,%edx
  jne    L18
  mov    $0x2,%edx
L39:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L31
  cmp    $0x6f,%al
  jne    L74
L69:
  cmp    $0x2,%edx
  jne    L18
  mov    $0x3,%edx
  jmp    L39
  nopl   (%rax)
L102:
  test   %edx,%edx
  jne    L18
  mov    $0x1,%edx
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L96:
  cmp    $0xffffffff,%r8d
  je     L143
  lea    (%r8,%r8,4),%edx
  lea    -0x30(%rax,%rdx,2),%r8d
  mov    $0x3,%edx
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L143:
  lea    -0x30(%rax),%r8d
  jmp    L39
```

assistant: ```c
int __uio_num_from_filename(char *name) {
  enum scan_states { ss_u, ss_i, ss_o, ss_num, ss_err };
  enum scan_states state = ss_u;
  int i = 0, num = -1;
  char ch = name[0];
  while (ch && (state != ss_err)) {
    switch (ch) {
    case 'u':
      if (state == ss_u)
        state = ss_i;
      else
        state = ss_err;
      break;
    case 'i':
      if (state == ss_i)
        state = ss_o;
      else
        state = ss_err;
      break;
    case 'o':
      if (state == ss_o)
        state = ss_num;
      else
        state = ss_err;
      break;
    default:
      if ((ch >= '0') && (ch <= '9') && (state == ss_num)) {
        if (num < 0)
          num = (ch - '0');
        else
          num = (num * 10) + (ch - '0');
      } else
        state = ss_err;
    }
    i++;
    ch = name[i];
  }
  if (state == ss_err)
    num = -1;
  return num;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__uio_num_from_filename>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L157
  add    $0x1,%rdi
  mov    $0xffffffff,%r8d
  xor    %edx,%edx
  cmp    $0x6f,%al
  je     L71
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    $0x75,%al
  je     L38
  cmp    $0x69,%al
  je     L146
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L157
  cmp    $0x3,%edx
  je     L119
  nopl   (%rax)
L157:
  mov    $0xffffffff,%r8d
L27:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L146:
  cmp    $0x1,%edx
  jne    L157
  mov    $0x2,%edx
L98:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L27
  cmp    $0x6f,%al
  jne    L8
L71:
  cmp    $0x2,%edx
  jne    L157
  mov    $0x3,%edx
  jmp    L98
  nopl   (%rax)
L38:
  test   %edx,%edx
  jne    L157
  mov    $0x1,%edx
  jmp    L98
  nopl   0x0(%rax,%rax,1)
L119:
  cmp    $0xffffffff,%r8d
  je     L52
  lea    (%r8,%r8,4),%edx
  lea    -0x30(%rax,%rdx,2),%r8d
  mov    $0x3,%edx
  jmp    L98
  cs nopw 0x0(%rax,%rax,1)
L52:
  lea    -0x30(%rax),%r8d
  jmp    L98
```

assistant: ```c
int __uio_num_from_filename(char *name) {
  enum scan_states { ss_u, ss_i, ss_o, ss_num, ss_err };
  enum scan_states state = ss_u;
  int i = 0, num = -1;
  char ch = name[0];
  while (ch && (state != ss_err)) {
    switch (ch) {
    case 'u':
      if (state == ss_u)
        state = ss_i;
      else
        state = ss_err;
      break;
    case 'i':
      if (state == ss_i)
        state = ss_o;
      else
        state = ss_err;
      break;
    case 'o':
      if (state == ss_o)
        state = ss_num;
      else
        state = ss_err;
      break;
    default:
      if ((ch >= '0') && (ch <= '9') && (state == ss_num)) {
        if (num < 0)
          num = (ch - '0');
        else
          num = (num * 10) + (ch - '0');
      } else
        state = ss_err;
    }
    i++;
    ch = name[i];
  }
  if (state == ss_err)
    num = -1;
  return num;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<talloc_append_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L15
  mov    -0x30(%rbp),%rax
  jmp    L36
L15:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  lea    D4(%rip),%r8
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <_talloc_realloc_array@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L39
  mov    $0x0,%eax
  jmp    L36
L39:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L36:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: char

assistant: ```c
char *talloc_append_string(const void *t, char *orig, const char *append) {
  char *ret;
  size_t olen = strlen(orig);
  size_t alenz;
  if (!append)
    return orig;
  alenz = strlen(append) + 1;
  ret = (char *)_talloc_realloc_array(t, orig, sizeof(char), olen + alenz, "char");
  if (!ret)
    return NULL;
  memcpy(&ret[olen], append, alenz);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<talloc_append_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%r14
  test   %r12,%r12
  je     L10
  movslq %eax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  movslq %r13d,%r13
  lea    0x0(%rbp,%r13,1),%rcx
  lea    D6(%rip),%r8
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <_talloc_realloc_array@plt>
  mov    $0x0,%r14d
  test   %rax,%rax
  je     L10
  mov    %rax,%r14
  lea    (%rax,%rbp,1),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
L10:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D6: char

assistant: ```c
char *talloc_append_string(const void *t, char *orig, const char *append) {
  char *ret;
  size_t olen = strlen(orig);
  size_t alenz;
  if (!append)
    return orig;
  alenz = strlen(append) + 1;
  ret = (char *)_talloc_realloc_array(t, orig, sizeof(char), olen + alenz, "char");
  if (!ret)
    return NULL;
  memcpy(&ret[olen], append, alenz);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<talloc_append_string>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  call   <strlen@plt>
  test   %rbp,%rbp
  je     L16
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    $0x1,%edx
  mov    %r13,%rdi
  lea    0x1(%rax),%r14d
  lea    D7(%rip),%r8
  xor    %r12d,%r12d
  movslq %r14d,%r14
  lea    (%rbx,%r14,1),%rcx
  call   <_talloc_realloc_array@plt>
  test   %rax,%rax
  je     L16
  lea    (%rax,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  call   <memcpy@plt>
L16:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: char

assistant: ```c
char *talloc_append_string(const void *t, char *orig, const char *append) {
  char *ret;
  size_t olen = strlen(orig);
  size_t alenz;
  if (!append)
    return orig;
  alenz = strlen(append) + 1;
  ret = (char *)_talloc_realloc_array(t, orig, sizeof(char), olen + alenz, "char");
  if (!ret)
    return NULL;
  memcpy(&ret[olen], append, alenz);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<talloc_append_string>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  call   <strlen@plt>
  test   %rbp,%rbp
  je     L11
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    $0x1,%edx
  mov    %r13,%rdi
  lea    0x1(%rax),%r14d
  lea    D4(%rip),%r8
  xor    %r12d,%r12d
  movslq %r14d,%r14
  lea    (%rbx,%r14,1),%rcx
  call   <_talloc_realloc_array@plt>
  test   %rax,%rax
  je     L11
  lea    (%rax,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  call   <memcpy@plt>
L11:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D4: char

assistant: ```c
char *talloc_append_string(const void *t, char *orig, const char *append) {
  char *ret;
  size_t olen = strlen(orig);
  size_t alenz;
  if (!append)
    return orig;
  alenz = strlen(append) + 1;
  ret = (char *)_talloc_realloc_array(t, orig, sizeof(char), olen + alenz, "char");
  if (!ret)
    return NULL;
  memcpy(&ret[olen], append, alenz);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_now_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int64_t get_now_ms() {
  struct timeval t0;
  gettimeofday(&t0, NULL);
  return t0.tv_sec * 1000 + t0.tv_usec / 1000;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_now_ms>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t get_now_ms() {
  struct timeval t0;
  gettimeofday(&t0, NULL);
  return t0.tv_sec * 1000 + t0.tv_usec / 1000;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_now_ms>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t get_now_ms() {
  struct timeval t0;
  gettimeofday(&t0, NULL);
  return t0.tv_sec * 1000 + t0.tv_usec / 1000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_now_ms>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t get_now_ms() {
  struct timeval t0;
  gettimeofday(&t0, NULL);
  return t0.tv_sec * 1000 + t0.tv_usec / 1000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mid_pred>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L33
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L21
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L37
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L21
L37:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L21
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L21
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L0
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L21
L0:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mid_pred(int a, int b, int c) {
  if (a > b) {
    if (c > b) {
      if (c > a)
        b = a;
      else
        b = c;
    }
  } else {
    if (b > c) {
      if (c > a)
        b = c;
      else
        b = a;
    }
  }
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mid_pred>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  jle    L7
  cmp    %edx,%edi
  cmovg  %edx,%edi
  cmp    %edx,%esi
  cmovl  %edi,%eax
  ret
L7:
  cmp    %edx,%edi
  cmovl  %edx,%edi
  cmp    %edx,%esi
  cmovg  %edi,%eax
  ret
```

assistant: ```c
int mid_pred(int a, int b, int c) {
  if (a > b) {
    if (c > b) {
      if (c > a)
        b = a;
      else
        b = c;
    }
  } else {
    if (b > c) {
      if (c > a)
        b = c;
      else
        b = a;
    }
  }
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mid_pred>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  jle    L6
  cmp    %edx,%edi
  cmovg  %edx,%edi
  cmp    %edx,%esi
  cmovl  %edi,%eax
  ret
  nopl   (%rax)
L6:
  cmp    %edx,%edi
  cmovl  %edx,%edi
  cmp    %edx,%esi
  cmovg  %edi,%eax
  ret
```

assistant: ```c
int mid_pred(int a, int b, int c) {
  if (a > b) {
    if (c > b) {
      if (c > a)
        b = a;
      else
        b = c;
    }
  } else {
    if (b > c) {
      if (c > a)
        b = c;
      else
        b = a;
    }
  }
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mid_pred>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  jle    L7
  cmp    %edx,%edi
  cmovg  %edx,%edi
  cmp    %edx,%esi
  cmovl  %edi,%eax
  ret
  nopl   (%rax)
L7:
  cmp    %edx,%edi
  cmovl  %edx,%edi
  cmp    %edx,%esi
  cmovg  %edi,%eax
  ret
```

assistant: ```c
int mid_pred(int a, int b, int c) {
  if (a > b) {
    if (c > b) {
      if (c > a)
        b = a;
      else
        b = c;
    }
  } else {
    if (b > c) {
      if (c > a)
        b = c;
      else
        b = a;
    }
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  jmp    L19
L3:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <rot1@plt>
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
L19:
  mov    D2(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L3
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  c = getchar();
  while (c != EOF) {
    putchar(rot1(c));
    c = getchar();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D2(%rip),%rdx
  cmp    (%rdx),%al
  je     L0
L5:
  movsbl %al,%edi
  call   <rot1@plt>
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D2(%rip),%rdx
  cmp    %al,(%rdx)
  jne    L5
L0:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  c = getchar();
  while (c != EOF) {
    putchar(rot1(c));
    c = getchar();
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rbx
  cmp    (%rbx),%al
  je     L12
  nopw   0x0(%rax,%rax,1)
L8:
  movsbl %al,%edi
  call   <rot1@plt>
  mov    %eax,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L8
L12:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  c = getchar();
  while (c != EOF) {
    putchar(rot1(c));
    c = getchar();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rbx
  cmp    (%rbx),%al
  je     L3
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl %al,%edi
  call   <rot1@plt>
  mov    %eax,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L6
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  c = getchar();
  while (c != EOF) {
    putchar(rot1(c));
    c = getchar();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cycle_leader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cltd
  idivl  -0x20(%rbp)
  mov    %edx,-0x8(%rbp)
  jmp    L1
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  cltd
  idivl  -0x20(%rbp)
  mov    %edx,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cycle_leader(int *a, int from, int mod) {
  int t, i;
  for (i = from * 2 % mod; i != from; i = i * 2 % mod) {
    t = a[i];
    a[i] = a[from];
    a[from] = t;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cycle_leader>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%r9d
  mov    %edx,%ecx
  lea    (%rsi,%rsi,1),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cmp    %edx,%esi
  je     L11
  movslq %esi,%rdx
  lea    (%rdi,%rdx,4),%rsi
L12:
  movslq %eax,%rdx
  lea    (%r10,%rdx,4),%rdx
  mov    (%rdx),%edi
  mov    (%rsi),%r8d
  mov    %r8d,(%rdx)
  mov    %edi,(%rsi)
  add    %eax,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cmp    %edx,%r9d
  jne    L12
L11:
  ret
```

assistant: ```c
void cycle_leader(int *a, int from, int mod) {
  int t, i;
  for (i = from * 2 % mod; i != from; i = i * 2 % mod) {
    t = a[i];
    a[i] = a[from];
    a[from] = t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cycle_leader>:
  endbr64
  mov    %esi,%r8d
  mov    %edx,%esi
  mov    %rdi,%r9
  lea    (%r8,%r8,1),%eax
  cltd
  idiv   %esi
  cmp    %edx,%r8d
  je     L4
  movslq %r8d,%rax
  lea    (%rdi,%rax,4),%r10
  mov    (%r10),%ecx
  nopw   0x0(%rax,%rax,1)
L16:
  movslq %edx,%rax
  mov    %ecx,%edi
  lea    (%r9,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %edi,(%rax)
  lea    (%rdx,%rdx,1),%eax
  cltd
  idiv   %esi
  mov    %ecx,(%r10)
  cmp    %edx,%r8d
  jne    L16
L4:
  ret
```

assistant: ```c
void cycle_leader(int *a, int from, int mod) {
  int t, i;
  for (i = from * 2 % mod; i != from; i = i * 2 % mod) {
    t = a[i];
    a[i] = a[from];
    a[from] = t;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cycle_leader>:
  endbr64
  mov    %esi,%r8d
  mov    %edx,%esi
  mov    %rdi,%r9
  lea    (%r8,%r8,1),%eax
  cltd
  idiv   %esi
  cmp    %edx,%r8d
  je     L15
  movslq %r8d,%rax
  lea    (%rdi,%rax,4),%r10
  mov    (%r10),%ecx
  nopw   0x0(%rax,%rax,1)
L7:
  movslq %edx,%rax
  mov    %ecx,%edi
  lea    (%r9,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %edi,(%rax)
  lea    (%rdx,%rdx,1),%eax
  cltd
  idiv   %esi
  mov    %ecx,(%r10)
  cmp    %edx,%r8d
  jne    L7
L15:
  ret
```

assistant: ```c
void cycle_leader(int *a, int from, int mod) {
  int t, i;
  for (i = from * 2 % mod; i != from; i = i * 2 % mod) {
    t = a[i];
    a[i] = a[from];
    a[from] = t;
  }
}
```