ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<addchar2>:
  endbr64
  movzbl (%rsi),%eax
  mov    %rdi,%r8
  mov    %rdx,%rdi
  movzbl (%rcx),%edx
  lea    -0x60(%rdx,%rax,1),%esi
  add    (%r8),%sil
  mov    $0x67,%edx
  mov    %esi,%eax
  mov    %sil,(%rdi)
  sar    $0x7,%sil
  imul   %dl
  sar    $0xa,%ax
  sub    %esi,%eax
  mov    %al,(%rcx)
  movzbl (%rdi),%ecx
  mov    %edx,%eax
  imul   %cl
  mov    %ecx,%edx
  sar    $0x7,%dl
  sar    $0xa,%ax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%edx
  sub    %edx,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rdi)
  ret
```

assistant: ```c
void addchar2(char *a, char *b, char *sum, char *dig_sum) {
  *sum = (*a - '0') + (*b - '0') + (*dig_sum);
  *dig_sum = *sum / 10;
  *sum = (*sum % 10) + '0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<addchar2>:
  endbr64
  movzbl (%rsi),%eax
  mov    %rdi,%r8
  mov    %rdx,%rdi
  movzbl (%rcx),%edx
  lea    -0x60(%rdx,%rax,1),%esi
  add    (%r8),%sil
  mov    $0x67,%edx
  mov    %esi,%eax
  mov    %sil,(%rdi)
  sar    $0x7,%sil
  imul   %dl
  sar    $0xa,%ax
  sub    %esi,%eax
  mov    %al,(%rcx)
  movzbl (%rdi),%ecx
  mov    %edx,%eax
  imul   %cl
  mov    %ecx,%edx
  sar    $0x7,%dl
  sar    $0xa,%ax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%edx
  sub    %edx,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rdi)
  ret
```

assistant: ```c
void addchar2(char *a, char *b, char *sum, char *dig_sum) {
  *sum = (*a - '0') + (*b - '0') + (*dig_sum);
  *dig_sum = *sum / 10;
  *sum = (*sum % 10) + '0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ip_scanbracket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  je     L56
  mov    $0x0,%eax
  jmp    L20
L56:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <ip_scan@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L20
L33:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  je     L37
  mov    $0x0,%eax
  jmp    L20
L37:
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
L20:
  leave
  ret
```

assistant: ```c
unsigned int ip_scanbracket(s, ip)
char *s;
struct ip_address *ip;
{
  unsigned int len;
  if (*s != '[')
    return 0;
  len = ip_scan(s + 1, ip);
  if (!len)
    return 0;
  if (s[len + 1] != ']')
    return 0;
  return len + 2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ip_scanbracket>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x5b,(%rdi)
  je     L23
  ret
L23:
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rdi),%rdi
  call   <ip_scan@plt>
  test   %eax,%eax
  je     L20
  lea    0x1(%rax),%edx
  add    $0x2,%eax
  cmpb   $0x5d,(%rbx,%rdx,1)
  je     L20
  mov    $0x0,%eax
L20:
  pop    %rbx
  ret
```

assistant: ```c
unsigned int ip_scanbracket(s, ip)
char *s;
struct ip_address *ip;
{
  unsigned int len;
  if (*s != '[')
    return 0;
  len = ip_scan(s + 1, ip);
  if (!len)
    return 0;
  if (s[len + 1] != ']')
    return 0;
  return len + 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ip_scanbracket>:
  endbr64
  cmpb   $0x5b,(%rdi)
  je     L10
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L10:
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  lea    0x1(%rdi),%rdi
  call   <ip_scan@plt>
  test   %eax,%eax
  je     L16
  lea    0x1(%rax),%edx
  cmpb   $0x5d,(%rbx,%rdx,1)
  je     L5
L16:
  xor    %eax,%eax
  pop    %rbx
  ret
L5:
  add    $0x2,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int ip_scanbracket(s, ip)
char *s;
struct ip_address *ip;
{
  unsigned int len;
  if (*s != '[')
    return 0;
  len = ip_scan(s + 1, ip);
  if (!len)
    return 0;
  if (s[len + 1] != ']')
    return 0;
  return len + 2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ip_scanbracket>:
  endbr64
  cmpb   $0x5b,(%rdi)
  je     L24
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L24:
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  lea    0x1(%rdi),%rdi
  call   <ip_scan@plt>
  test   %eax,%eax
  je     L27
  lea    0x1(%rax),%edx
  cmpb   $0x5d,(%rbx,%rdx,1)
  je     L10
L27:
  xor    %eax,%eax
  pop    %rbx
  ret
L10:
  add    $0x2,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int ip_scanbracket(s, ip)
char *s;
struct ip_address *ip;
{
  unsigned int len;
  if (*s != '[')
    return 0;
  len = ip_scan(s + 1, ip);
  if (!len)
    return 0;
  if (s[len + 1] != ']')
    return 0;
  return len + 2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<malloc_aligned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <posix_memalign@plt>
  mov    D4(%rip),%rdx
  mov    %rax,(%rdx)
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L28
  mov    -0x10(%rbp),%rax
  jmp    L10
L28:
  mov    $0x0,%eax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void *malloc_aligned(size_t size) {
  void *mem;
  errno = posix_memalign(&mem, (4 * 1024), size);
  return (errno ? NULL : mem);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<malloc_aligned>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1000,%esi
  call   <posix_memalign@plt>
  mov    D1(%rip),%rdx
  mov    %rax,(%rdx)
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *malloc_aligned(size_t size) {
  void *mem;
  errno = posix_memalign(&mem, (4 * 1024), size);
  return (errno ? NULL : mem);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<malloc_aligned>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    $0x1000,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <posix_memalign@plt>
  mov    D2(%rip),%rdx
  test   %rax,%rax
  mov    %rax,(%rdx)
  mov    $0x0,%eax
  cmove  (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *malloc_aligned(size_t size) {
  void *mem;
  errno = posix_memalign(&mem, (4 * 1024), size);
  return (errno ? NULL : mem);
}
```
user: What is the c source code of the assembly code below?

```asm
<malloc_aligned>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    $0x1000,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <posix_memalign@plt>
  mov    D5(%rip),%rdx
  test   %rax,%rax
  mov    %rax,(%rdx)
  mov    $0x0,%eax
  cmove  (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *malloc_aligned(size_t size) {
  void *mem;
  errno = posix_memalign(&mem, (4 * 1024), size);
  return (errno ? NULL : mem);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L22
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <create_proc@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  jmp    L31
L22:
  cmpl   $0x2,-0x4(%rbp)
  jne    L31
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L31
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
L31:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D45
data_type: string
name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D47
data_type: string
name: unpack_data
arguments: label: D46
data_type: string

tool: D45: parent


tool: D11: child

tool: D47: parent exiting


tool: D46: child


assistant: ```c
int main(int argc, char **argv) {
  if (argc == 1) {
    print("parent\n");
    create_proc(argv[0], "child");
    print("parent exiting\n");
  } else if (argc == 2 && strcmp(argv[1], "child") == 0) {
    print("child\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  je     L4
  cmp    $0x2,%edi
  je     L11
L8:
  mov    $0x0,%eax
  pop    %rbx
  ret
L4:
  lea    D47(%rip),%rdi
  call   <print@plt>
  lea    D27(%rip),%rsi
  mov    (%rbx),%rdi
  call   <create_proc@plt>
  lea    D0(%rip),%rdi
  call   <print@plt>
  jmp    L8
L11:
  mov    0x8(%rsi),%rdi
  lea    D27(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
  lea    D6(%rip),%rdi
  call   <print@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_label: D47
type_infered: string
name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D47: parent


tool: D27: child

tool: D0: parent exiting


tool: D6: child


assistant: ```c
int main(int argc, char **argv) {
  if (argc == 1) {
    print("parent\n");
    create_proc(argv[0], "child");
    print("parent exiting\n");
  } else if (argc == 2 && strcmp(argv[1], "child") == 0) {
    print("child\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  je     L49
  cmp    $0x2,%edi
  je     L19
L14:
  xor    %eax,%eax
  pop    %rbx
  ret
L49:
  lea    D31(%rip),%rdi
  call   <print@plt>
  mov    (%rbx),%rdi
  lea    D41(%rip),%rsi
  call   <create_proc@plt>
  lea    D39(%rip),%rdi
  call   <print@plt>
  jmp    L14
L19:
  mov    0x8(%rsi),%rdi
  lea    D41(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  lea    D43(%rip),%rdi
  call   <print@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: tag: D31
type_guessed: string
name: retrieve_data
arguments: tag: D41
type_guessed: string
name: retrieve_data
arguments: tag: D39
type_guessed: string
name: retrieve_data
arguments: tag: D43
type_guessed: string

tool: D31: parent


tool: D41: child

tool: D39: parent exiting


tool: D43: child


assistant: ```c
int main(int argc, char **argv) {
  if (argc == 1) {
    print("parent\n");
    create_proc(argv[0], "child");
    print("parent exiting\n");
  } else if (argc == 2 && strcmp(argv[1], "child") == 0) {
    print("child\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  je     L35
  cmp    $0x2,%edi
  je     L0
L39:
  xor    %eax,%eax
  pop    %rbx
  ret
L35:
  lea    D6(%rip),%rdi
  call   <print@plt>
  mov    (%rbx),%rdi
  lea    D24(%rip),%rsi
  call   <create_proc@plt>
  lea    D11(%rip),%rdi
  call   <print@plt>
  jmp    L39
L0:
  mov    0x8(%rsi),%rdi
  lea    D24(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L39
  lea    D43(%rip),%rdi
  call   <print@plt>
  jmp    L39
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string
name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string
name: parse_data
arguments: data_tag: D43
data_type: string

tool: D6: parent


tool: D24: child

tool: D11: parent exiting


tool: D43: child


assistant: ```c
int main(int argc, char **argv) {
  if (argc == 1) {
    print("parent\n");
    create_proc(argv[0], "child");
    print("parent exiting\n");
  } else if (argc == 2 && strcmp(argv[1], "child") == 0) {
    print("child\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BusFault_Handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L8:
  jmp    L8
```

assistant: ```c
__attribute__((section(".after_vectors"))) void BusFault_Handler(void) {
  while (1) {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BusFault_Handler>:
  endbr64
L1:
  jmp    L1
```

assistant: ```c
__attribute__((section(".after_vectors"))) void BusFault_Handler(void) {
  while (1) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BusFault_Handler>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
__attribute__((section(".after_vectors"))) void BusFault_Handler(void) {
  while (1) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BusFault_Handler>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
__attribute__((section(".after_vectors"))) void BusFault_Handler(void) {
  while (1) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_printf_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf_s@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int my_printf_s(const char *fmt, ...) {
  va_list arg;
  int rc;
  va_start(arg, fmt);
  rc = vprintf_s(fmt, arg);
  va_end(arg);
  return (rc);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_printf_s>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf_s@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int my_printf_s(const char *fmt, ...) {
  va_list arg;
  int rc;
  va_start(arg, fmt);
  rc = vprintf_s(fmt, arg);
  va_end(arg);
  return (rc);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_printf_s>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <vprintf_s@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int my_printf_s(const char *fmt, ...) {
  va_list arg;
  int rc;
  va_start(arg, fmt);
  rc = vprintf_s(fmt, arg);
  va_end(arg);
  return (rc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_printf_s>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <vprintf_s@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int my_printf_s(const char *fmt, ...) {
  va_list arg;
  int rc;
  va_start(arg, fmt);
  rc = vprintf_s(fmt, arg);
  va_end(arg);
  return (rc);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L22:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L43
  mov    D12(%rip),%rax
  mov    (%rax),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L22
L43:
  cmpl   $0x0,-0x4(%rbp)
  jg     L46
  mov    $0x0,%eax
  jmp    L29
L46:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L22
  mov    $0x1,%eax
L29:
  leave
  ret
```

assistant: ```c
int cwrite(int fd, const char *buffer, unsigned int r) {
  unsigned int i;
  int p;
  for (i = 0; i < r;) {
    do {
      p = write(fd, buffer + i, r - i);
    } while (p == -1 && (errno == EINTR));
    if (p < 1)
      return 0;
    i += p;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cwrite>:
  endbr64
  test   %edx,%edx
  je     L16
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    %edx,%r12d
  mov    $0x0,%ebx
  jmp    L61
L45:
  test   %eax,%eax
  jle    L55
  add    %eax,%ebx
  cmp    %ebx,%r12d
  jbe    L38
L61:
  mov    %ebx,%ebp
  add    %r14,%rbp
L24:
  mov    %r12d,%edx
  sub    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L45
  mov    D13(%rip),%rdx
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L24
  mov    $0x0,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  mov    $0x1,%eax
  jmp    L0
L16:
  mov    $0x1,%eax
  ret
L55:
  mov    $0x0,%eax
  jmp    L0
```

assistant: ```c
int cwrite(int fd, const char *buffer, unsigned int r) {
  unsigned int i;
  int p;
  for (i = 0; i < r;) {
    do {
      p = write(fd, buffer + i, r - i);
    } while (p == -1 && (errno == EINTR));
    if (p < 1)
      return 0;
    i += p;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cwrite>:
  endbr64
  test   %edx,%edx
  je     L57
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r14d,%ebp
  mov    %r13d,%ebx
  sub    %r13d,%ebp
  add    %r15,%rbx
  jmp    L50
  xchg   %ax,%ax
L5:
  mov    D10(%rip),%rax
  mov    D17(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L33
L50:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L5
  test   %eax,%eax
  jle    L33
  add    %eax,%r13d
  cmp    %r13d,%r14d
  ja     L22
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cwrite(int fd, const char *buffer, unsigned int r) {
  unsigned int i;
  int p;
  for (i = 0; i < r;) {
    do {
      p = write(fd, buffer + i, r - i);
    } while (p == -1 && (errno == EINTR));
    if (p < 1)
      return 0;
    i += p;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cwrite>:
  endbr64
  test   %edx,%edx
  je     L27
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %r14d,%ebp
  mov    %r13d,%ebx
  sub    %r13d,%ebp
  add    %r15,%rbx
  jmp    L33
  xchg   %ax,%ax
L21:
  mov    D3(%rip),%rax
  mov    D4(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L8
L33:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L21
  test   %eax,%eax
  jle    L8
  add    %eax,%r13d
  cmp    %r13d,%r14d
  ja     L25
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cwrite(int fd, const char *buffer, unsigned int r) {
  unsigned int i;
  int p;
  for (i = 0; i < r;) {
    do {
      p = write(fd, buffer + i, r - i);
    } while (p == -1 && (errno == EINTR));
    if (p < 1)
      return 0;
    i += p;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ResetISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe000ed88,%eax
  mov    (%rax),%edx
  mov    $0xe000ed88,%eax
  or     $0xf00000,%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ResetISR>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ResetISR>:
  endbr64
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```