ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x9,-0x8(%rbp)
  jg     L16
  mov    $0x1,%eax
  jmp    L11
L16:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdi
  call   <getSize>
  add    $0x1,%eax
L11:
  leave
  ret
```

assistant: ```c
unsigned int getSize(const long long int num) {
  if (num < 10)
    return 1;
  return 1 + getSize(num / 10);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getSize>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x9,%rdi
  jg     L7
  ret
L7:
  sub    $0x8,%rsp
  movabs $0x6666666666666667,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x2,%rdx
  sar    $0x3f,%rdi
  sub    %rdi,%rdx
  mov    %rdx,%rdi
  call   <getSize>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int getSize(const long long int num) {
  if (num < 10)
    return 1;
  return 1 + getSize(num / 10);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getSize>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x1,%r8d
  movabs $0xcccccccccccccccd,%rsi
  cmp    $0x9,%rdi
  jle    L9
  nopl   (%rax)
L0:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  jg     L0
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int getSize(const long long int num) {
  if (num < 10)
    return 1;
  return 1 + getSize(num / 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getSize>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x1,%r8d
  movabs $0xcccccccccccccccd,%rsi
  cmp    $0x9,%rdi
  jle    L13
  nopl   (%rax)
L7:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  jg     L7
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int getSize(const long long int num) {
  if (num < 10)
    return 1;
  return 1 + getSize(num / 10);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<be_write32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,-0x20(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
ssize_t be_write32(int fd, u_int32_t word) {
  u_int8_t buf[4];
  buf[3] = word & 0xff;
  buf[2] = (word & 0xff00) >> 8;
  buf[1] = (word & 0xff0000) >> 16;
  buf[0] = (word & 0xff000000) >> 24;
  return write(fd, buf, 4);
}
```
user: What is the c source code of the assembly code below?

```asm
<be_write32>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  movzbl %sil,%edx
  mov    %edx,0xc(%rsp)
  movzbl %ah,%edx
  mov    %edx,0x8(%rsp)
  mov    %esi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x4(%rsp)
  shr    $0x18,%eax
  mov    %eax,(%rsp)
  mov    %rsp,%rsi
  mov    $0x4,%edx
  call   <write@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t be_write32(int fd, u_int32_t word) {
  u_int8_t buf[4];
  buf[3] = word & 0xff;
  buf[2] = (word & 0xff00) >> 8;
  buf[1] = (word & 0xff0000) >> 16;
  buf[0] = (word & 0xff000000) >> 24;
  return write(fd, buf, 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<be_write32>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  movzbl %sil,%edx
  mov    %edx,0xc(%rsp)
  movzbl %ah,%edx
  shr    $0x18,%eax
  mov    %edx,0x8(%rsp)
  mov    %esi,%edx
  mov    %rsp,%rsi
  sar    $0x10,%edx
  mov    %eax,(%rsp)
  and    $0xff,%edx
  mov    %edx,0x4(%rsp)
  mov    $0x4,%edx
  call   <write@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t be_write32(int fd, u_int32_t word) {
  u_int8_t buf[4];
  buf[3] = word & 0xff;
  buf[2] = (word & 0xff00) >> 8;
  buf[1] = (word & 0xff0000) >> 16;
  buf[0] = (word & 0xff000000) >> 24;
  return write(fd, buf, 4);
}
```
user: Translate the below assembly code into C programming language:

```asm
<be_write32>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%ecx
  mov    %esi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  mov    %esi,%edx
  shr    $0x18,%ecx
  sar    $0x10,%edx
  movd   %ecx,%xmm0
  movzbl %ah,%ecx
  movzbl %sil,%eax
  movzbl %dl,%edx
  movd   %ecx,%xmm1
  movd   %eax,%xmm2
  mov    %rsp,%rsi
  movd   %edx,%xmm3
  punpckldq %xmm2,%xmm1
  mov    $0x4,%edx
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <write@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t be_write32(int fd, u_int32_t word) {
  u_int8_t buf[4];
  buf[3] = word & 0xff;
  buf[2] = (word & 0xff00) >> 8;
  buf[1] = (word & 0xff0000) >> 16;
  buf[0] = (word & 0xff000000) >> 24;
  return write(fd, buf, 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_node_and_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free_list@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free_list@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_node_and_list(struct node *current_node, struct node *parent_node, struct list *open_list, struct list *close_list) {
  free(current_node);
  free(parent_node);
  free_list(open_list);
  free_list(close_list);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<free_node_and_list>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free_list@plt>
  mov    %rbx,%rdi
  call   <free_list@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free_node_and_list(struct node *current_node, struct node *parent_node, struct list *open_list, struct list *close_list) {
  free(current_node);
  free(parent_node);
  free_list(open_list);
  free_list(close_list);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<free_node_and_list>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free_list@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free_list@plt>
```

assistant: ```c
void free_node_and_list(struct node *current_node, struct node *parent_node, struct list *open_list, struct list *close_list) {
  free(current_node);
  free(parent_node);
  free_list(open_list);
  free_list(close_list);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<free_node_and_list>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free_list@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free_list@plt>
```

assistant: ```c
void free_node_and_list(struct node *current_node, struct node *parent_node, struct list *open_list, struct list *close_list) {
  free(current_node);
  free(parent_node);
  free_list(open_list);
  free_list(close_list);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<illegal_email_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L49
  cmpb   $0x5a,-0x4(%rbp)
  jle    L78
L49:
  cmpb   $0x60,-0x4(%rbp)
  jle    L20
  cmpb   $0x7a,-0x4(%rbp)
  jle    L78
L20:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L80
  cmpb   $0x39,-0x4(%rbp)
  jle    L78
L80:
  cmpb   $0x2e,-0x4(%rbp)
  je     L78
  cmpb   $0x2d,-0x4(%rbp)
  je     L78
  cmpb   $0x5f,-0x4(%rbp)
  je     L78
  mov    $0x1,%eax
  jmp    L64
L78:
  mov    $0x0,%eax
L64:
  pop    %rbp
  ret
```

assistant: ```c
int illegal_email_chars(char c) {
  if (!(c >= 'A' && c <= 'Z') && !(c >= 'a' && c <= 'z') && !(c >= '0' && c <= '9') && c != '.' && c != '-' && c != '_')
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<illegal_email_chars>:
  endbr64
  mov    %edi,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  mov    $0x0,%eax
  cmp    $0x19,%dl
  jbe    L11
  lea    -0x2d(%rdi),%ecx
  cmp    $0x32,%cl
  ja     L3
  movabs $0x4000000001ffb,%rax
  shr    %cl,%rax
  not    %rax
  and    $0x1,%eax
  ret
L3:
  mov    $0x1,%eax
L11:
  ret
```

assistant: ```c
int illegal_email_chars(char c) {
  if (!(c >= 'A' && c <= 'Z') && !(c >= 'a' && c <= 'z') && !(c >= '0' && c <= '9') && c != '.' && c != '-' && c != '_')
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<illegal_email_chars>:
  endbr64
  mov    %edi,%edx
  xor    %eax,%eax
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L6
  lea    -0x2d(%rdi),%ecx
  cmp    $0x32,%cl
  ja     L10
  movabs $0x4000000001ffb,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
L6:
  ret
```

assistant: ```c
int illegal_email_chars(char c) {
  if (!(c >= 'A' && c <= 'Z') && !(c >= 'a' && c <= 'z') && !(c >= '0' && c <= '9') && c != '.' && c != '-' && c != '_')
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<illegal_email_chars>:
  endbr64
  mov    %edi,%edx
  xor    %eax,%eax
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L0
  lea    -0x2d(%rdi),%ecx
  cmp    $0x32,%cl
  ja     L7
  movabs $0x4000000001ffb,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%eax
L0:
  ret
```

assistant: ```c
int illegal_email_chars(char c) {
  if (!(c >= 'A' && c <= 'Z') && !(c >= 'a' && c <= 'z') && !(c >= '0' && c <= '9') && c != '.' && c != '-' && c != '_')
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_numbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L17
L4:
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L47:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L9
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L9
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L47
L9:
  addl   $0x2,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L17:
  cmpl   $0x2,-0x10(%rbp)
  jle    L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *get_numbers(char str[]) {
  int *numbers = malloc(3);
  int i = 0, j = 0;
  for (j = 0; j < 3; ++j) {
    int curr_numb = 0;
    while (str[i] >= '0' && str[i] <= '9' && i < strlen(str)) {
      curr_numb = curr_numb * 10 + (str[i] - '0');
      i++;
    }
    i += 2;
    numbers[j] = curr_numb;
  }
  return numbers;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_numbers>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%r15
  add    $0xc,%rax
  mov    %rax,(%rsp)
  mov    $0x0,%ebp
  jmp    L10
L24:
  mov    $0x0,%r12d
L15:
  add    $0x2,%ebp
  mov    %r12d,(%r15)
  add    $0x4,%r15
  cmp    (%rsp),%r15
  je     L23
L10:
  movslq %ebp,%rdx
  lea    (%r14,%rdx,1),%rbx
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L24
  lea    0x1(%r14,%rdx,1),%r13
  mov    $0x0,%r12d
L46:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L15
  lea    (%r12,%r12,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%r12d
  add    $0x1,%ebp
  movzbl 0x0(%r13),%eax
  sub    $0x30,%eax
  add    $0x1,%r13
  add    $0x1,%rbx
  cmp    $0x9,%al
  jbe    L46
  jmp    L15
L23:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *get_numbers(char str[]) {
  int *numbers = malloc(3);
  int i = 0, j = 0;
  for (j = 0; j < 3; ++j) {
    int curr_numb = 0;
    while (str[i] >= '0' && str[i] <= '9' && i < strlen(str)) {
      curr_numb = curr_numb * 10 + (str[i] - '0');
      i++;
    }
    i += 2;
    numbers[j] = curr_numb;
  }
  return numbers;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_numbers>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x3,%edi
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%r12
  add    $0xc,%rax
  mov    %rax,(%rsp)
L12:
  movslq %r15d,%rdx
  lea    0x0(%rbp,%rdx,1),%rbx
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L41
  lea    0x1(%rbp,%rdx,1),%r13
  xor    %r14d,%r14d
  jmp    L50
  xchg   %ax,%ax
L55:
  movsbl (%rbx),%eax
  lea    (%r14,%r14,4),%edx
  add    $0x1,%r15d
  add    $0x1,%r13
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r14d
  movzbl -0x1(%r13),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L25
L50:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  jg     L55
L25:
  mov    %r14d,(%r12)
  add    $0x2,%r15d
  add    $0x4,%r12
  cmp    (%rsp),%r12
  jne    L12
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  xor    %r14d,%r14d
  jmp    L25
```

assistant: ```c
int *get_numbers(char str[]) {
  int *numbers = malloc(3);
  int i = 0, j = 0;
  for (j = 0; j < 3; ++j) {
    int curr_numb = 0;
    while (str[i] >= '0' && str[i] <= '9' && i < strlen(str)) {
      curr_numb = curr_numb * 10 + (str[i] - '0');
      i++;
    }
    i += 2;
    numbers[j] = curr_numb;
  }
  return numbers;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_numbers>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x3,%edi
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%r12
  add    $0xc,%rax
  mov    %rax,(%rsp)
L49:
  movslq %r15d,%rdx
  lea    0x0(%rbp,%rdx,1),%rbx
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L16
  lea    0x1(%rbp,%rdx,1),%r13
  xor    %r14d,%r14d
  jmp    L14
  xchg   %ax,%ax
L39:
  movsbl (%rbx),%eax
  lea    (%r14,%r14,4),%edx
  add    $0x1,%r15d
  add    $0x1,%r13
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r14d
  movzbl -0x1(%r13),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L40
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  jg     L39
L40:
  mov    %r14d,(%r12)
  add    $0x2,%r15d
  add    $0x4,%r12
  cmp    (%rsp),%r12
  jne    L49
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  xor    %r14d,%r14d
  jmp    L40
```

assistant: ```c
int *get_numbers(char str[]) {
  int *numbers = malloc(3);
  int i = 0, j = 0;
  for (j = 0; j < 3; ++j) {
    int curr_numb = 0;
    while (str[i] >= '0' && str[i] <= '9' && i < strlen(str)) {
      curr_numb = curr_numb * 10 + (str[i] - '0');
      i++;
    }
    i += 2;
    numbers[j] = curr_numb;
  }
  return numbers;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wsplitlines_exp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L66
  mov    $0x0,%eax
  jmp    L70
L66:
  movq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  movb   $0x2,-0x21(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movb   $0x1,-0x22(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xa,-0x1c(%rbp)
  jne    L52
  movb   $0x1,-0x22(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L13
L52:
  cmpb   $0x0,-0x22(%rbp)
  je     L13
  movb   $0x0,-0x22(%rbp)
  addl   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jge    L48
  movsbq -0x21(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
L48:
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L13:
  addq   $0x4,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L7
  subl   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  je     L73
  mov    -0x40(%rbp),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rax)
L73:
  mov    -0x10(%rbp),%rax
L70:
  leave
  ret
```

assistant: ```c
wchar_t **wsplitlines_exp(wchar_t *wbuffer, int *linecount) {
  if (!wbuffer)
    return NULL;
  long int nmem = 1;
  wchar_t **lines = calloc(nmem, sizeof(wchar_t *));
  const char exp = 2;
  int numln = 0;
  wchar_t wch = NULL;
  wchar_t *wbufpos = wbuffer;
  char newline = 1;
  do {
    wch = *wbufpos;
    if (wch == L'\n') {
      newline = 1;
      *wbufpos = L'\0';
    } else {
      if (newline) {
        newline = 0;
        numln++;
        if (numln > nmem) {
          nmem *= exp;
          lines = realloc(lines, nmem * sizeof(wchar_t *));
        }
        lines[numln - 1] = wbufpos;
      }
    }
    wbufpos++;
  } while (wch != L'\0');
  numln--;
  lines = realloc(lines, numln * sizeof(wchar_t *));
  if (linecount)
    *linecount = numln;
  return lines;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wsplitlines_exp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L51
  mov    %rsi,%r15
  mov    $0x8,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  add    $0x4,%rbx
  mov    $0x1,%edx
  mov    $0x0,%r12d
  mov    $0x1,%r14d
  jmp    L97
L93:
  movl   $0x0,-0x4(%rbx)
  mov    $0x1,%edx
  jmp    L73
L14:
  movslq %r12d,%rax
  mov    %r13,-0x8(%rdi,%rax,8)
L66:
  test   %ebp,%ebp
  je     L94
  mov    $0x0,%edx
L73:
  add    $0x4,%rbx
L97:
  lea    -0x4(%rbx),%r13
  mov    -0x4(%rbx),%ebp
  cmp    $0xa,%ebp
  je     L93
  test   %dl,%dl
  je     L66
  add    $0x1,%r12d
  movslq %r12d,%rax
  cmp    %r14,%rax
  jle    L14
  add    %r14,%r14
  lea    0x0(,%r14,8),%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  jmp    L14
L94:
  sub    $0x1,%r12d
  lea    0x0(,%r12,8),%esi
  call   <realloc@plt>
  test   %r15,%r15
  je     L67
  mov    %r12d,(%r15)
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  mov    %rdi,%rax
  jmp    L67
```

assistant: ```c
wchar_t **wsplitlines_exp(wchar_t *wbuffer, int *linecount) {
  if (!wbuffer)
    return NULL;
  long int nmem = 1;
  wchar_t **lines = calloc(nmem, sizeof(wchar_t *));
  const char exp = 2;
  int numln = 0;
  wchar_t wch = NULL;
  wchar_t *wbufpos = wbuffer;
  char newline = 1;
  do {
    wch = *wbufpos;
    if (wch == L'\n') {
      newline = 1;
      *wbufpos = L'\0';
    } else {
      if (newline) {
        newline = 0;
        numln++;
        if (numln > nmem) {
          nmem *= exp;
          lines = realloc(lines, nmem * sizeof(wchar_t *));
        }
        lines[numln - 1] = wbufpos;
      }
    }
    wbufpos++;
  } while (wch != L'\0');
  numln--;
  lines = realloc(lines, numln * sizeof(wchar_t *));
  if (linecount)
    *linecount = numln;
  return lines;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wsplitlines_exp>:
  endbr64
  test   %rdi,%rdi
  je     L43
  push   %r15
  push   %r14
  mov    %rsi,%r14
  mov    $0x8,%esi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x18,%rsp
  call   <calloc@plt>
  mov    $0x1,%edx
  mov    $0x1,%ecx
  mov    %rax,%rdi
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L39:
  test   %dl,%dl
  je     L88
  add    $0x1,%r13d
  movslq %r13d,%r15
  cmp    %rcx,%r15
  jg     L73
L22:
  mov    %rbx,-0x8(%rdi,%r15,8)
L88:
  test   %ebp,%ebp
  je     L2
  xor    %edx,%edx
L11:
  mov    %r12,%rbx
L45:
  mov    (%rbx),%ebp
  lea    0x4(%rbx),%r12
  cmp    $0xa,%ebp
  jne    L39
  movl   $0x0,-0x4(%r12)
  mov    $0x1,%edx
  jmp    L11
  nopl   0x0(%rax)
L2:
  sub    $0x1,%r13d
  lea    0x0(,%r13,8),%esi
  call   <realloc@plt>
  test   %r14,%r14
  je     L62
  mov    %r13d,(%r14)
L62:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L73:
  add    %rcx,%rcx
  lea    0x0(,%rcx,8),%esi
  mov    %rcx,0x8(%rsp)
  call   <realloc@plt>
  mov    0x8(%rsp),%rcx
  mov    %rax,%rdi
  jmp    L22
  xchg   %ax,%ax
L43:
  xor    %eax,%eax
  ret
```

assistant: ```c
wchar_t **wsplitlines_exp(wchar_t *wbuffer, int *linecount) {
  if (!wbuffer)
    return NULL;
  long int nmem = 1;
  wchar_t **lines = calloc(nmem, sizeof(wchar_t *));
  const char exp = 2;
  int numln = 0;
  wchar_t wch = NULL;
  wchar_t *wbufpos = wbuffer;
  char newline = 1;
  do {
    wch = *wbufpos;
    if (wch == L'\n') {
      newline = 1;
      *wbufpos = L'\0';
    } else {
      if (newline) {
        newline = 0;
        numln++;
        if (numln > nmem) {
          nmem *= exp;
          lines = realloc(lines, nmem * sizeof(wchar_t *));
        }
        lines[numln - 1] = wbufpos;
      }
    }
    wbufpos++;
  } while (wch != L'\0');
  numln--;
  lines = realloc(lines, numln * sizeof(wchar_t *));
  if (linecount)
    *linecount = numln;
  return lines;
}
```