ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_le64>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    %rsp,%r13
L13:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L2
  mov    (%rsp),%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  or     %eax,%ebp
  add    $0x8,%ebx
  cmp    $0x40,%ebx
  jne    L13
  mov    %ebp,(%r14)
  mov    $0x8,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_le64(int fd, uint64_t *out) {
  uint64_t tmp = 0;
  uint8_t byte;
  int i, err;
  for (i = 0; i < 8; i++) {
    err = read(fd, &byte, 1);
    if (err <= 0)
      return err;
    tmp |= ((uint64_t)byte << (i * 8));
  }
  *out = tmp;
  do {
  } while (0);
  return 8;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_le64>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  nopl   (%rax)
L3:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L9
  mov    (%rsp),%eax
  mov    %r14d,%ecx
  add    $0x8,%r14d
  shl    %cl,%eax
  or     %eax,%ebx
  cmp    $0x40,%r14d
  jne    L3
  mov    %ebx,0x0(%r13)
  mov    $0x8,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_le64(int fd, uint64_t *out) {
  uint64_t tmp = 0;
  uint8_t byte;
  int i, err;
  for (i = 0; i < 8; i++) {
    err = read(fd, &byte, 1);
    if (err <= 0)
      return err;
    tmp |= ((uint64_t)byte << (i * 8));
  }
  *out = tmp;
  do {
  } while (0);
  return 8;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_le64>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  nopl   (%rax)
L15:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L17
  mov    (%rsp),%eax
  mov    %r14d,%ecx
  add    $0x8,%r14d
  shl    %cl,%eax
  or     %eax,%ebx
  cmp    $0x40,%r14d
  jne    L15
  mov    %ebx,0x0(%r13)
  mov    $0x8,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_le64(int fd, uint64_t *out) {
  uint64_t tmp = 0;
  uint8_t byte;
  int i, err;
  for (i = 0; i < 8; i++) {
    err = read(fd, &byte, 1);
    if (err <= 0)
      return err;
    tmp |= ((uint64_t)byte << (i * 8));
  }
  *out = tmp;
  do {
  } while (0);
  return 8;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IQuantize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L2
  mov    $0x13e,%ecx
  lea    D24(%rip),%rax
  mov    %rax,%rdx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L16:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x20(%rbp)
  addq   $0x4,-0x8(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  add    $0x100,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L16
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/aaalgo/ljpeg/refs/heads/master/jpegdir/transform.c

tool: D2: F>%s:R>%s:L>%d: 

tool: D25: No quantization matrix specified!

assistant: ```c
void IQuantize(matrix, qmatrix) int *matrix;
int *qmatrix;
{
  static char RoutineName[] = "IQuantize";
  int *mptr;
  if (!qmatrix) {
    printf("F>%s:R>%s:L>%d: ", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/aaalgo/ljpeg/refs/heads/master/jpegdir/transform.c", RoutineName, 318);
    printf("No quantization matrix specified!\n");
    exit(1);
  }
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    *mptr = *mptr * (*qmatrix);
    qmatrix++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IQuantize>:
  endbr64
  test   %rsi,%rsi
  je     L15
  mov    $0x0,%eax
L3:
  mov    (%rdi,%rax,1),%edx
  imul   (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x100,%rax
  jne    L3
  ret
L15:
  sub    $0x8,%rsp
  mov    $0x13e,%ecx
  lea    D5(%rip),%rdx
  lea    D14(%rip),%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string

tool: D14: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/aaalgo/ljpeg/refs/heads/master/jpegdir/transform.c

tool: D23: F>%s:R>%s:L>%d: 

tool: D13: No quantization matrix specified!

assistant: ```c
void IQuantize(matrix, qmatrix) int *matrix;
int *qmatrix;
{
  static char RoutineName[] = "IQuantize";
  int *mptr;
  if (!qmatrix) {
    printf("F>%s:R>%s:L>%d: ", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/aaalgo/ljpeg/refs/heads/master/jpegdir/transform.c", RoutineName, 318);
    printf("No quantization matrix specified!\n");
    exit(1);
  }
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    *mptr = *mptr * (*qmatrix);
    qmatrix++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<IQuantize>:
  endbr64
  test   %rsi,%rsi
  je     L12
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%rdi,%rax,1),%edx
  imul   (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x100,%rax
  jne    L3
  ret
L12:
  push   %rax
  mov    $0x13e,%ecx
  xor    %eax,%eax
  lea    D8(%rip),%rdx
  lea    D28(%rip),%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: read_data
arguments: label: D28
data_type: string
name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D25
data_type: string

tool: D28: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/aaalgo/ljpeg/refs/heads/master/jpegdir/transform.c

tool: D18: F>%s:R>%s:L>%d: 

tool: D25: No quantization matrix specified!

assistant: ```c
void IQuantize(matrix, qmatrix) int *matrix;
int *qmatrix;
{
  static char RoutineName[] = "IQuantize";
  int *mptr;
  if (!qmatrix) {
    printf("F>%s:R>%s:L>%d: ", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/aaalgo/ljpeg/refs/heads/master/jpegdir/transform.c", RoutineName, 318);
    printf("No quantization matrix specified!\n");
    exit(1);
  }
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    *mptr = *mptr * (*qmatrix);
    qmatrix++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strappend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L7
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void strappend(char *s, char *add) {
  s += strlen(s);
  while (*add != 0) {
    *s = *add;
    s++;
    add++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strappend>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L14
  mov    $0x0,%eax
L16:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L16
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strappend(char *s, char *add) {
  s += strlen(s);
  while (*add != 0) {
    *s = *add;
    s++;
    add++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strappend>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movzbl 0x0(%rbp),%edx
  cltq
  lea    (%rbx,%rax,1),%rdi
  test   %dl,%dl
  je     L14
  xor    %eax,%eax
  nopl   (%rax)
L17:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L17
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strappend(char *s, char *add) {
  s += strlen(s);
  while (*add != 0) {
    *s = *add;
    s++;
    add++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strappend>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movzbl 0x0(%rbp),%edx
  cltq
  lea    (%rbx,%rax,1),%rdi
  test   %dl,%dl
  je     L5
  xor    %eax,%eax
  nopl   (%rax)
L10:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L10
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strappend(char *s, char *add) {
  s += strlen(s);
  while (*add != 0) {
    *s = *add;
    s++;
    add++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff91a2b3c5,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0xb,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xe10,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff91a2b3c5,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0xb,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xe10,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0x3c,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type_infered: string
name: parse_data
arguments: label: D0
type_infered: string

tool: D15: %d

tool: D0: %d:%d:%d


assistant: ```c
int main() {
  int N;
  scanf("%d", &N);
  int hr = N / (3600);
  int min = (N % 3600) / 60;
  int seg = (N % 3600) % 60;
  printf("%d:%d:%d\n", hr, min, seg);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rsi
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0xb,%esi
  mov    %eax,%edi
  sar    $0x1f,%edi
  mov    %esi,%ecx
  sub    %edi,%ecx
  imul   $0xe10,%ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  imul   $0x3c,%edx,%eax
  sub    %eax,%ecx
  sub    %edi,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string

tool: D4: %d

tool: D17: %d:%d:%d


assistant: ```c
int main() {
  int N;
  scanf("%d", &N);
  int hr = N / (3600);
  int min = (N % 3600) / 60;
  int seg = (N % 3600) % 60;
  printf("%d:%d:%d\n", hr, min, seg);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  mov    %eax,%edi
  sar    $0x1f,%edi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0xb,%esi
  mov    %esi,%ecx
  sub    %edi,%esi
  sub    %edi,%ecx
  lea    D4(%rip),%rdi
  imul   $0xe10,%ecx,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  mov    %rdx,%rcx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x5,%edx
  sub    %eax,%edx
  imul   $0x3c,%edx,%eax
  sub    %eax,%ecx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D17: %d

tool: D4: %d:%d:%d


assistant: ```c
int main() {
  int N;
  scanf("%d", &N);
  int hr = N / (3600);
  int min = (N % 3600) / 60;
  int seg = (N % 3600) % 60;
  printf("%d:%d:%d\n", hr, min, seg);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  mov    %eax,%edi
  sar    $0x1f,%edi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0xb,%esi
  mov    %esi,%ecx
  sub    %edi,%esi
  sub    %edi,%ecx
  lea    D4(%rip),%rdi
  imul   $0xe10,%ecx,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  mov    %rdx,%rcx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x5,%edx
  sub    %eax,%edx
  imul   $0x3c,%edx,%eax
  sub    %eax,%ecx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D19: %d

tool: D4: %d:%d:%d


assistant: ```c
int main() {
  int N;
  scanf("%d", &N);
  int hr = N / (3600);
  int min = (N % 3600) / 60;
  int seg = (N % 3600) % 60;
  printf("%d:%d:%d\n", hr, min, seg);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fromHexString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L119
L83:
  addq   $0x1,-0x38(%rbp)
L142:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L83
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x13(%rbp)
  cmpb   $0x0,-0x13(%rbp)
  je     L100
  movzbl -0x13(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x13(%rbp)
  cmpb   $0x40,-0x13(%rbp)
  jbe    L24
  subb   $0x37,-0x13(%rbp)
L24:
  cmpb   $0x2f,-0x13(%rbp)
  jbe    L86
  subb   $0x30,-0x13(%rbp)
L86:
  cmpb   $0xf,-0x13(%rbp)
  jbe    L75
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  jmp    L34
L75:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  cmpb   $0x0,-0x12(%rbp)
  je     L58
  movzbl -0x12(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x12(%rbp)
  cmpb   $0x40,-0x12(%rbp)
  jbe    L94
  subb   $0x37,-0x12(%rbp)
L94:
  cmpb   $0x2f,-0x12(%rbp)
  jbe    L135
  subb   $0x30,-0x12(%rbp)
L135:
  cmpb   $0xf,-0x12(%rbp)
  jbe    L26
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  jmp    L34
L26:
  movzbl -0x13(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movzbl -0x12(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x11(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
L119:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L142
  jmp    L87
L100:
  nop
  jmp    L87
L58:
  nop
L87:
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
L34:
  leave
  ret
```

assistant: ```c
int fromHexString(void *outBuf, size_t size, const char *hexstr) {
  char *buf = (char *)outBuf;
  char *bufStart = outBuf;
  while (*hexstr != 0) {
    unsigned char msb, lsb;
    while (*hexstr == ' ')
      hexstr++;
    if ((msb = *hexstr++) == 0)
      break;
    msb = toupper(msb);
    if ('A' <= msb)
      msb -= 'A' - 10;
    if (msb >= '0')
      msb -= '0';
    if (msb > 15)
      return -(buf - bufStart);
    if ((lsb = *hexstr++) == 0)
      break;
    lsb = toupper(lsb);
    if ('A' <= lsb)
      lsb -= 'A' - 10;
    if (lsb >= '0')
      lsb -= '0';
    if (lsb > 15)
      return -(buf - bufStart);
    unsigned char value = msb << 4 | lsb;
    *buf++ = value;
  };
  return buf - bufStart;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fromHexString>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rdx,%rbx
  mov    %rdi,%r12
  cmpb   $0x0,(%rdx)
  jne    L107
L1:
  mov    %r12d,%eax
  sub    %r13d,%eax
L104:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L67:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  cmp    $0x20,%dil
  je     L67
  mov    %rbx,%rbp
L14:
  test   %dil,%dil
  je     L1
  movzbl %dil,%edi
  call   <toupper@plt>
  mov    %eax,%r14d
  lea    -0x37(%r14),%eax
  cmp    $0x40,%r14b
  cmova  %eax,%r14d
  lea    -0x30(%r14),%eax
  cmp    $0x2f,%r14b
  cmova  %eax,%r14d
  cmp    $0xf,%r14b
  ja     L7
  lea    0x2(%rbp),%rbx
  movzbl 0x1(%rbp),%edi
  test   %dil,%dil
  je     L1
  movzbl %dil,%edi
  call   <toupper@plt>
  lea    -0x37(%rax),%edx
  cmp    $0x40,%al
  cmova  %edx,%eax
  lea    -0x30(%rax),%edx
  cmp    $0x2f,%al
  cmova  %edx,%eax
  cmp    $0xf,%al
  ja     L6
  add    $0x1,%r12
  shl    $0x4,%r14d
  or     %eax,%r14d
  mov    %r14b,-0x1(%r12)
  cmpb   $0x0,0x2(%rbp)
  je     L1
L107:
  movzbl (%rbx),%edi
  mov    %rbx,%rbp
  cmp    $0x20,%dil
  je     L67
  jmp    L14
L7:
  mov    %r13d,%eax
  sub    %r12d,%eax
  jmp    L104
L6:
  mov    %r13d,%eax
  sub    %r12d,%eax
  jmp    L104
```

assistant: ```c
int fromHexString(void *outBuf, size_t size, const char *hexstr) {
  char *buf = (char *)outBuf;
  char *bufStart = outBuf;
  while (*hexstr != 0) {
    unsigned char msb, lsb;
    while (*hexstr == ' ')
      hexstr++;
    if ((msb = *hexstr++) == 0)
      break;
    msb = toupper(msb);
    if ('A' <= msb)
      msb -= 'A' - 10;
    if (msb >= '0')
      msb -= '0';
    if (msb > 15)
      return -(buf - bufStart);
    if ((lsb = *hexstr++) == 0)
      break;
    lsb = toupper(lsb);
    if ('A' <= lsb)
      lsb -= 'A' - 10;
    if (lsb >= '0')
      lsb -= '0';
    if (lsb > 15)
      return -(buf - bufStart);
    unsigned char value = msb << 4 | lsb;
    *buf++ = value;
  };
  return buf - bufStart;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fromHexString>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdx),%edi
  test   %dil,%dil
  je     L0
  mov    %rdx,%rbx
  mov    %r13,%rbp
  jmp    L3
  nopl   (%rax)
L40:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L3:
  cmp    $0x20,%dil
  je     L40
  mov    %rbx,%r12
  test   %dil,%dil
  je     L9
  call   <toupper@plt>
  mov    %eax,%r14d
  lea    -0x37(%r14),%eax
  cmp    $0x40,%r14b
  cmova  %eax,%r14d
  lea    -0x30(%r14),%eax
  cmp    $0x2f,%r14b
  cmova  %eax,%r14d
  cmp    $0xf,%r14b
  ja     L42
  movzbl 0x1(%r12),%edi
  add    $0x2,%rbx
  test   %dil,%dil
  je     L9
  call   <toupper@plt>
  lea    -0x37(%rax),%edx
  cmp    $0x40,%al
  cmova  %edx,%eax
  lea    -0x30(%rax),%edx
  cmp    $0x2f,%al
  cmova  %edx,%eax
  cmp    $0xf,%al
  ja     L42
  shl    $0x4,%r14d
  add    $0x1,%rbp
  or     %eax,%r14d
  mov    %r14b,-0x1(%rbp)
  movzbl 0x2(%r12),%edi
  test   %dil,%dil
  jne    L3
L9:
  mov    %ebp,%eax
  sub    %r13d,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  mov    %r13d,%eax
  pop    %rbx
  sub    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fromHexString(void *outBuf, size_t size, const char *hexstr) {
  char *buf = (char *)outBuf;
  char *bufStart = outBuf;
  while (*hexstr != 0) {
    unsigned char msb, lsb;
    while (*hexstr == ' ')
      hexstr++;
    if ((msb = *hexstr++) == 0)
      break;
    msb = toupper(msb);
    if ('A' <= msb)
      msb -= 'A' - 10;
    if (msb >= '0')
      msb -= '0';
    if (msb > 15)
      return -(buf - bufStart);
    if ((lsb = *hexstr++) == 0)
      break;
    lsb = toupper(lsb);
    if ('A' <= lsb)
      lsb -= 'A' - 10;
    if (lsb >= '0')
      lsb -= '0';
    if (lsb > 15)
      return -(buf - bufStart);
    unsigned char value = msb << 4 | lsb;
    *buf++ = value;
  };
  return buf - bufStart;
}
```