user: Demonstrate the C code that generates the assembly output below:

```asm
<lm_printout_std>:
  endbr64
  test   %r9d,%r9d
  je     L218
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x8,%rsp
  test   $0x1,%r9b
  je     L182
  cmpl   $0x2,0x40(%rsp)
  je     L95
  cmpl   $0x1,0x40(%rsp)
  je     L89
  mov    0x40(%rsp),%eax
  test   %eax,%eax
  je     L178
  cmpl   $0xffffffff,0x40(%rsp)
  je     L55
  nopl   (%rax)
L182:
  test   $0x2,%bl
  jne    L135
  test   $0x3,%bl
  jne    L106
L137:
  test   $0x8,%bl
  jne    L194
L138:
  and    $0x4,%ebx
  je     L149
  cmpl   $0xffffffff,0x40(%rsp)
  je     L194
L149:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L194:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L149
  xor    %ebx,%ebx
  lea    D4(%rip),%r13
  nopl   0x0(%rax)
L100:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L100
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L106:
  mov    $0xa,%edi
  call   <putchar@plt>
  test   $0x8,%bl
  je     L138
  jmp    L194
  nopl   0x0(%rax)
L135:
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  test   %r14d,%r14d
  jle    L76
  lea    -0x1(%r14),%eax
  lea    D18(%rip),%r14
  lea    0x8(%r13,%rax,8),%r15
  nopl   0x0(%rax,%rax,1)
L2:
  movsd  0x0(%r13),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  add    $0x8,%r13
  call   <printf@plt>
  cmp    %r15,%r13
  jne    L2
L76:
  mov    %ebp,%edi
  mov    %r12,%rsi
  call   <lm_enorm@plt>
  lea    D74(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  test   $0x3,%bl
  je     L137
  jmp    L106
  nopl   (%rax)
L218:
  ret
  nopl   0x0(%rax)
L178:
  lea    D66(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L182
  nopl   0x0(%rax,%rax,1)
L95:
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L182
  nopl   0x0(%rax,%rax,1)
L89:
  mov    0x48(%rsp),%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L182
  nopw   0x0(%rax,%rax,1)
L55:
  mov    0x50(%rsp),%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L182
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string
name: read_data
arguments: data_tag: D4
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string
name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D74
datatype: string
name: read_data
arguments: data_tag: D66
datatype: string
name: read_data
arguments: data_tag: D40
datatype: string
name: read_data
arguments: data_tag: D49
datatype: string
name: read_data
arguments: data_tag: D24
datatype: string

tool: D0:   residuals:

tool: D4:     fvec[%2d]=%12g


tool: D20:   par: 

tool: D18:  %18.11g

tool: D74:  => norm: %18.11g

tool: D66: starting minimization              

tool: D40: trying step in gradient direction  

tool: D49: determining gradient (iteration %2d)

tool: D24: terminated after %3d evaluations   

assistant: ```c
void lm_printout_std(int n_par, const double *par, int m_dat, const void *data, const double *fvec, int printflags, int iflag, int iter, int nfev) {
  if (!printflags)
    return;
  int i;
  if (printflags & 1) {
    if (iflag == 2) {
      printf("trying step in gradient direction  ");
    } else if (iflag == 1) {
      printf("determining gradient (iteration %2d)", iter);
    } else if (iflag == 0) {
      printf("starting minimization              ");
    } else if (iflag == -1) {
      printf("terminated after %3d evaluations   ", nfev);
    }
  }
  if (printflags & 2) {
    printf("  par: ");
    for (i = 0; i < n_par; ++i)
      printf(" %18.11g", par[i]);
    printf(" => norm: %18.11g", lm_enorm(m_dat, fvec));
  }
  if (printflags & 3)
    printf("\n");
  if ((printflags & 8) || ((printflags & 4) && iflag == -1)) {
    printf("  residuals:\n");
    for (i = 0; i < m_dat; ++i)
      printf("    fvec[%2d]=%12g\n", i, fvec[i]);
  }
}
```