ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<yuv2rgb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  cmpl   $0x3,-0x34(%rbp)
  je     L113
  cmpl   $0x3,-0x34(%rbp)
  jg     L26
  cmpl   $0x2,-0x34(%rbp)
  je     L56
  cmpl   $0x2,-0x34(%rbp)
  jg     L26
  cmpl   $0x0,-0x34(%rbp)
  je     L27
  cmpl   $0x1,-0x34(%rbp)
  je     L43
  jmp    L26
L27:
  movl   $0x0,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  jmp    L26
L43:
  movl   $0x2,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  jmp    L26
L56:
  movl   $0x0,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L26
L113:
  movl   $0x2,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  nop
L26:
  movl   $0x0,-0x14(%rbp)
  jmp    L51
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%esi
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    -0x30(%rbp),%rcx
  mov    %eax,%edi
  call   <YUV2RGB@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%esi
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    -0x30(%rbp),%rcx
  mov    %eax,%edi
  call   <YUV2RGB@plt>
  mov    %rax,-0x30(%rbp)
  addq   $0x10,-0x28(%rbp)
  addl   $0x1,-0x14(%rbp)
L51:
  mov    -0x38(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  imul   -0x3c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L24
  nop
  nop
  leave
  ret
```

assistant: ```c
void yuv2rgb(uint8_t *yuvDat, uint8_t *out, int alg, uint32_t img_w, uint32_t img_h) {
  uint32_t xy;
  int y1, y2, y3, y4;
  switch (alg) {
  case 0:
    y1 = 0;
    y2 = 2;
    y3 = 1;
    y4 = 3;
    break;
  case 1:
    y1 = 2;
    y2 = 0;
    y3 = 1;
    y4 = 3;
    break;
  case 2:
    y1 = 0;
    y2 = 2;
    y3 = 3;
    y4 = 1;
    break;
  case 3:
    y1 = 2;
    y2 = 0;
    y3 = 3;
    y4 = 1;
    break;
  }
  for (xy = 0; xy < (img_w / 2) * img_h; ++xy) {
    out = YUV2RGB(yuvDat[y1], yuvDat[y3], yuvDat[y4], out);
    out = YUV2RGB(yuvDat[y2], yuvDat[y3], yuvDat[y4], out);
    yuvDat += 4;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<yuv2rgb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rax
  mov    %edx,%r12d
  mov    %r8d,%r9d
  cmp    $0x2,%edx
  je     L22
  cmp    $0x2,%edx
  jg     L55
  test   %edx,%edx
  je     L24
  cmp    $0x1,%edx
  mov    $0x0,%edx
  mov    $0x3,%esi
  cmove  %esi,%edx
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x2,%esi
  cmove  %esi,%r13d
L33:
  mov    %ecx,%esi
  shr    $0x1f,%esi
  lea    (%rsi,%rcx,1),%r8d
  sar    %r8d
  imul   %r9d,%r8d
  test   %r8d,%r8d
  jle    L72
  movslq %edx,%rdx
  shl    $0x2,%rdx
  mov    %rdx,%rcx
  mov    %rdx,0x8(%rsp)
  movslq %r12d,%r12
  shl    $0x2,%r12
  movslq %r13d,%r13
  shl    $0x2,%r13
  movslq %r14d,%r14
  shl    $0x2,%r14
  lea    (%rdi,%rdx,1),%rbx
  lea    -0x1(%r8),%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%r15
  add    %rcx,%r15
L32:
  mov    %rbx,%rbp
  sub    0x8(%rsp),%rbp
  mov    0x0(%rbp,%r12,1),%esi
  mov    0x0(%rbp,%r13,1),%edi
  mov    %rax,%rcx
  mov    (%rbx),%edx
  call   <YUV2RGB@plt>
  mov    %rax,%rcx
  mov    0x0(%rbp,%r12,1),%esi
  mov    0x0(%rbp,%r14,1),%edi
  mov    (%rbx),%edx
  call   <YUV2RGB@plt>
  add    $0x10,%rbx
  cmp    %r15,%rbx
  jne    L32
L72:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  cmp    $0x3,%edx
  sete   %dl
  movzbl %dl,%edx
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x2,%esi
  cmove  %esi,%r13d
  jmp    L33
L22:
  mov    %edx,%r14d
  mov    $0x1,%edx
  mov    $0x3,%r12d
  mov    $0x0,%r13d
  jmp    L33
L24:
  mov    %edx,%r13d
  mov    $0x3,%edx
  mov    $0x1,%r12d
  mov    $0x2,%r14d
  jmp    L33
```

assistant: ```c
void yuv2rgb(uint8_t *yuvDat, uint8_t *out, int alg, uint32_t img_w, uint32_t img_h) {
  uint32_t xy;
  int y1, y2, y3, y4;
  switch (alg) {
  case 0:
    y1 = 0;
    y2 = 2;
    y3 = 1;
    y4 = 3;
    break;
  case 1:
    y1 = 2;
    y2 = 0;
    y3 = 1;
    y4 = 3;
    break;
  case 2:
    y1 = 0;
    y2 = 2;
    y3 = 3;
    y4 = 1;
    break;
  case 3:
    y1 = 2;
    y2 = 0;
    y3 = 3;
    y4 = 1;
    break;
  }
  for (xy = 0; xy < (img_w / 2) * img_h; ++xy) {
    out = YUV2RGB(yuvDat[y1], yuvDat[y3], yuvDat[y4], out);
    out = YUV2RGB(yuvDat[y2], yuvDat[y3], yuvDat[y4], out);
    yuvDat += 4;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yuv2rgb>:
  endbr64
  push   %r15
  mov    %rsi,%r9
  mov    %rdi,%rax
  mov    %r8d,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x3,%edx
  ja     L29
  mov    %edx,%edx
  lea    D31(%rip),%rdi
  movslq (%rdi,%rdx,4),%r10
  lea    D10(%rip),%rdi
  movslq (%rdi,%rdx,4),%r14
  lea    D20(%rip),%rdi
  movslq (%rdi,%rdx,4),%r12
  lea    D36(%rip),%rdi
  movslq (%rdi,%rdx,4),%r13
L29:
  mov    %ecx,%r8d
  shr    $0x1f,%r8d
  add    %ecx,%r8d
  sar    %r8d
  imul   %esi,%r8d
  test   %r8d,%r8d
  jle    L25
  lea    -0x1(%r8),%edx
  shl    $0x2,%r13
  shl    $0x2,%r12
  lea    0x0(,%r10,4),%r15
  shl    $0x4,%rdx
  lea    (%rax,%r13,1),%rbx
  shl    $0x2,%r14
  lea    0x10(%rax,%rdx,1),%rax
  add    %r13,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L11:
  mov    %rbx,%rbp
  mov    (%rbx),%edx
  mov    %r9,%rcx
  add    $0x10,%rbx
  sub    %r13,%rbp
  mov    0x0(%rbp,%r12,1),%esi
  mov    0x0(%rbp,%r15,1),%edi
  call   <YUV2RGB@plt>
  mov    -0x10(%rbx),%edx
  mov    0x0(%rbp,%r12,1),%esi
  mov    0x0(%rbp,%r14,1),%edi
  mov    %rax,%rcx
  call   <YUV2RGB@plt>
  mov    %rax,%r9
  cmp    0x8(%rsp),%rbx
  jne    L11
L25:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D31
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string
name: disassemble_data
arguments: data_tag: D20
type_infered: string
name: disassemble_data
arguments: data_tag: D36
type_infered: string

tool: 

tool: D10: 

tool: D20: 

tool: D36: 

assistant: ```c
void yuv2rgb(uint8_t *yuvDat, uint8_t *out, int alg, uint32_t img_w, uint32_t img_h) {
  uint32_t xy;
  int y1, y2, y3, y4;
  switch (alg) {
  case 0:
    y1 = 0;
    y2 = 2;
    y3 = 1;
    y4 = 3;
    break;
  case 1:
    y1 = 2;
    y2 = 0;
    y3 = 1;
    y4 = 3;
    break;
  case 2:
    y1 = 0;
    y2 = 2;
    y3 = 3;
    y4 = 1;
    break;
  case 3:
    y1 = 2;
    y2 = 0;
    y3 = 3;
    y4 = 1;
    break;
  }
  for (xy = 0; xy < (img_w / 2) * img_h; ++xy) {
    out = YUV2RGB(yuvDat[y1], yuvDat[y3], yuvDat[y4], out);
    out = YUV2RGB(yuvDat[y2], yuvDat[y3], yuvDat[y4], out);
    yuvDat += 4;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yuv2rgb>:
  endbr64
  push   %r15
  mov    %rsi,%r9
  mov    %rdi,%rax
  mov    %r8d,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x3,%edx
  ja     L23
  mov    %edx,%edx
  lea    D2(%rip),%rdi
  movslq (%rdi,%rdx,4),%r10
  lea    D26(%rip),%rdi
  movslq (%rdi,%rdx,4),%r14
  lea    D16(%rip),%rdi
  movslq (%rdi,%rdx,4),%r12
  lea    D9(%rip),%rdi
  movslq (%rdi,%rdx,4),%r13
L23:
  mov    %ecx,%r8d
  shr    $0x1f,%r8d
  add    %ecx,%r8d
  sar    %r8d
  imul   %esi,%r8d
  test   %r8d,%r8d
  jle    L21
  lea    -0x1(%r8),%edx
  shl    $0x2,%r13
  shl    $0x2,%r12
  lea    0x0(,%r10,4),%r15
  shl    $0x4,%rdx
  lea    (%rax,%r13,1),%rbx
  shl    $0x2,%r14
  lea    0x10(%rax,%rdx,1),%rax
  add    %r13,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L27:
  mov    %rbx,%rbp
  mov    (%rbx),%edx
  mov    %r9,%rcx
  add    $0x10,%rbx
  sub    %r13,%rbp
  mov    0x0(%rbp,%r12,1),%esi
  mov    0x0(%rbp,%r15,1),%edi
  call   <YUV2RGB@plt>
  mov    -0x10(%rbx),%edx
  mov    0x0(%rbp,%r12,1),%esi
  mov    0x0(%rbp,%r14,1),%edi
  mov    %rax,%rcx
  call   <YUV2RGB@plt>
  mov    %rax,%r9
  cmp    %rbx,0x8(%rsp)
  jne    L27
L21:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string
name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: 

tool: D26: 

tool: D16: 

tool: D9: 

assistant: ```c
void yuv2rgb(uint8_t *yuvDat, uint8_t *out, int alg, uint32_t img_w, uint32_t img_h) {
  uint32_t xy;
  int y1, y2, y3, y4;
  switch (alg) {
  case 0:
    y1 = 0;
    y2 = 2;
    y3 = 1;
    y4 = 3;
    break;
  case 1:
    y1 = 2;
    y2 = 0;
    y3 = 1;
    y4 = 3;
    break;
  case 2:
    y1 = 0;
    y2 = 2;
    y3 = 3;
    y4 = 1;
    break;
  case 3:
    y1 = 2;
    y2 = 0;
    y3 = 3;
    y4 = 1;
    break;
  }
  for (xy = 0; xy < (img_w / 2) * img_h; ++xy) {
    out = YUV2RGB(yuvDat[y1], yuvDat[y3], yuvDat[y4], out);
    out = YUV2RGB(yuvDat[y2], yuvDat[y3], yuvDat[y4], out);
    yuvDat += 4;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<coerceReverseString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L8:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  sub    %rcx,%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jg     L8
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *coerceReverseString(const char *s) {
  long len = strlen(s);
  char *t = calloc(1 + len, 1);
  for (int i = 0; i < len; i++)
    t[len - i - 1] = s[i];
  return t;
}
```
user: What is the c source code of the assembly code below:

```asm
<coerceReverseString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rax),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %rbp,%rbp
  jle    L10
  mov    %rbx,%rdi
  lea    -0x1(%rax,%rbp,1),%rdx
L8:
  movzbl (%rdi),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdi
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  cmp    %rax,%rcx
  jne    L8
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *coerceReverseString(const char *s) {
  long len = strlen(s);
  char *t = calloc(1 + len, 1);
  for (int i = 0; i < len; i++)
    t[len - i - 1] = s[i];
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<coerceReverseString>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  mov    %rax,%rbp
  lea    0x1(%rax),%edi
  call   <calloc@plt>
  test   %rbp,%rbp
  je     L0
  mov    %rbx,%rdi
  lea    -0x1(%rax,%rbp,1),%rdx
  nop
L2:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  mov    %cl,(%rdx)
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  cmp    %rax,%rcx
  jne    L2
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *coerceReverseString(const char *s) {
  long len = strlen(s);
  char *t = calloc(1 + len, 1);
  for (int i = 0; i < len; i++)
    t[len - i - 1] = s[i];
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<coerceReverseString>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  mov    %rax,%rbp
  lea    0x1(%rax),%edi
  call   <calloc@plt>
  test   %rbp,%rbp
  je     L14
  mov    %rbx,%rdi
  lea    -0x1(%rax,%rbp,1),%rdx
  nop
L1:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  mov    %cl,(%rdx)
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  cmp    %rcx,%rax
  jne    L1
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *coerceReverseString(const char *s) {
  long len = strlen(s);
  char *t = calloc(1 + len, 1);
  for (int i = 0; i < len; i++)
    t[len - i - 1] = s[i];
  return t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    $0x7,%eax
  jg     L27
  mov    $0xffffffff,%eax
  jmp    L26
L27:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <randint@plt>
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L2:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L14
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L2
L14:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L14
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L33
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L2
L33:
  nop
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%eax
L26:
  leave
  ret
```

assistant: ```c
int partition(int *A, int l, int u) {
  int i, j;
  int t, temp;
  if (u - l < 8)
    return -1;
  swap(&A[l], &A[randint(l, u)]);
  t = A[l];
  i = l;
  j = u + 1;
  for (;;) {
    do
      i++;
    while (i <= u && A[i] < t);
    do
      j--;
    while (A[j] > t);
    if (i >= j)
      break;
    temp = A[i];
    A[i] = A[j];
    A[j] = temp;
  }
  swap(&A[l], &A[j]);
  return j;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<partition>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0x7,%eax
  jle    L31
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %edx,%r12d
  mov    %edx,%esi
  mov    %r14d,%edi
  call   <randint@plt>
  movslq %r14d,%rdx
  lea    0x0(%rbp,%rdx,4),%r13
  lea    0x0(%rbp,%rax,4),%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    0x0(%r13),%ecx
  lea    0x1(%r12),%ebx
  lea    0x1(%r14),%edi
  movslq %edi,%rdi
  jmp    L12
L70:
  movslq %ebx,%rax
  lea    -0x4(%rbp,%rax,4),%rax
L43:
  sub    $0x1,%ebx
  mov    %rax,%rsi
  sub    $0x4,%rax
  mov    0x4(%rax),%edx
  cmp    %ecx,%edx
  jg     L43
  cmp    %r8d,%ebx
  jle    L22
  mov    0x0(%rbp,%rdi,4),%eax
  mov    %edx,0x0(%rbp,%rdi,4)
  mov    %eax,(%rsi)
L69:
  add    $0x1,%rdi
L12:
  mov    %edi,%r8d
  cmp    %edi,%r12d
  jl     L70
  cmp    %ecx,0x0(%rbp,%rdi,4)
  jl     L69
  jmp    L70
L22:
  mov    %r13,%rdi
  call   <swap@plt>
L3:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  mov    $0xffffffff,%ebx
  jmp    L3
```

assistant: ```c
int partition(int *A, int l, int u) {
  int i, j;
  int t, temp;
  if (u - l < 8)
    return -1;
  swap(&A[l], &A[randint(l, u)]);
  t = A[l];
  i = l;
  j = u + 1;
  for (;;) {
    do
      i++;
    while (i <= u && A[i] < t);
    do
      j--;
    while (A[j] > t);
    if (i >= j)
      break;
    temp = A[i];
    A[i] = A[j];
    A[j] = temp;
  }
  swap(&A[l], &A[j]);
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<partition>:
  endbr64
  mov    %edx,%eax
  push   %r14
  sub    %esi,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x7,%eax
  jle    L56
  mov    %esi,%ebx
  mov    %rdi,%rbp
  mov    %edx,%esi
  mov    %edx,%r13d
  mov    %ebx,%edi
  lea    0x1(%r13),%r12d
  call   <randint@plt>
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rdx,4),%r14
  lea    0x0(%rbp,%rax,4),%rsi
  mov    %r14,%rdi
  call   <swap@plt>
  lea    0x1(%rbx),%edi
  mov    (%r14),%ecx
  movslq %edi,%rdi
  nopl   0x0(%rax)
L35:
  mov    %edi,%r8d
  cmp    %edi,%r13d
  jl     L25
  cmp    %ecx,0x0(%rbp,%rdi,4)
  jl     L9
L25:
  movslq %r12d,%rax
  lea    -0x4(%rbp,%rax,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    %rax,%rsi
  mov    (%rax),%edx
  sub    $0x4,%rax
  sub    $0x1,%r12d
  cmp    %ecx,%edx
  jg     L41
  cmp    %r8d,%r12d
  jle    L66
  mov    0x0(%rbp,%rdi,4),%eax
  mov    %edx,0x0(%rbp,%rdi,4)
  mov    %eax,(%rsi)
L9:
  add    $0x1,%rdi
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L66:
  mov    %r14,%rdi
  call   <swap@plt>
L47:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  mov    $0xffffffff,%r12d
  jmp    L47
```

assistant: ```c
int partition(int *A, int l, int u) {
  int i, j;
  int t, temp;
  if (u - l < 8)
    return -1;
  swap(&A[l], &A[randint(l, u)]);
  t = A[l];
  i = l;
  j = u + 1;
  for (;;) {
    do
      i++;
    while (i <= u && A[i] < t);
    do
      j--;
    while (A[j] > t);
    if (i >= j)
      break;
    temp = A[i];
    A[i] = A[j];
    A[j] = temp;
  }
  swap(&A[l], &A[j]);
  return j;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<partition>:
  endbr64
  mov    %edx,%eax
  push   %r14
  sub    %esi,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x7,%eax
  jle    L48
  mov    %esi,%ebx
  mov    %rdi,%rbp
  mov    %edx,%esi
  mov    %edx,%r13d
  mov    %ebx,%edi
  lea    0x1(%r13),%r12d
  call   <randint@plt>
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rdx,4),%r14
  lea    0x0(%rbp,%rax,4),%rsi
  mov    %r14,%rdi
  call   <swap@plt>
  lea    0x1(%rbx),%edi
  mov    (%r14),%ecx
  movslq %edi,%rdi
  nopl   0x0(%rax)
L10:
  mov    %edi,%r8d
  cmp    %r13d,%edi
  jg     L43
  cmp    %ecx,0x0(%rbp,%rdi,4)
  jl     L55
L43:
  movslq %r12d,%rax
  lea    -0x4(%rbp,%rax,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    %rax,%rsi
  mov    (%rax),%edx
  sub    $0x4,%rax
  sub    $0x1,%r12d
  cmp    %ecx,%edx
  jg     L54
  cmp    %r12d,%r8d
  jge    L50
  mov    0x0(%rbp,%rdi,4),%eax
  mov    %edx,0x0(%rbp,%rdi,4)
  mov    %eax,(%rsi)
L55:
  add    $0x1,%rdi
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    %r14,%rdi
  call   <swap@plt>
L35:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  mov    $0xffffffff,%r12d
  jmp    L35
```

assistant: ```c
int partition(int *A, int l, int u) {
  int i, j;
  int t, temp;
  if (u - l < 8)
    return -1;
  swap(&A[l], &A[randint(l, u)]);
  t = A[l];
  i = l;
  j = u + 1;
  for (;;) {
    do
      i++;
    while (i <= u && A[i] < t);
    do
      j--;
    while (A[j] > t);
    if (i >= j)
      break;
    temp = A[i];
    A[i] = A[j];
    A[j] = temp;
  }
  swap(&A[l], &A[j]);
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<while_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    $0xa,%edi
  call   <safealloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L2
L28:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1,(%rax)
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  cmpl   $0x9,-0xc(%rbp)
  jle    L28
L22:
  nop
  leave
  ret
```

assistant: ```c
void while_loop() {
  int i = 0;
  char *a = safealloc(10);
  while (*(a + i) && i < 10)
    a[i++] = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<while_loop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <safealloc@plt>
  cmpb   $0x0,(%rax)
  je     L0
  mov    %rax,%rdx
  mov    $0x1,%esi
  sub    %eax,%esi
L19:
  movb   $0x1,(%rdx)
  lea    (%rsi,%rdx,1),%eax
  cmp    $0x9,%eax
  setle  %cl
  cmpb   $0x0,0x1(%rdx)
  setne  %al
  add    $0x1,%rdx
  test   %al,%cl
  jne    L19
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void while_loop() {
  int i = 0;
  char *a = safealloc(10);
  while (*(a + i) && i < 10)
    a[i++] = 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<while_loop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <safealloc@plt>
  cmpb   $0x0,(%rax)
  je     L8
  mov    $0x1,%esi
  sub    %eax,%esi
  xchg   %ax,%ax
L17:
  lea    (%rsi,%rax,1),%edx
  movb   $0x1,(%rax)
  cmp    $0xa,%edx
  setne  %cl
  cmpb   $0x0,0x1(%rax)
  setne  %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L17
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void while_loop() {
  int i = 0;
  char *a = safealloc(10);
  while (*(a + i) && i < 10)
    a[i++] = 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<while_loop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <safealloc@plt>
  cmpb   $0x0,(%rax)
  je     L72
  cmpb   $0x0,0x1(%rax)
  movb   $0x1,(%rax)
  je     L72
  cmpb   $0x0,0x2(%rax)
  movb   $0x1,0x1(%rax)
  je     L72
  cmpb   $0x0,0x3(%rax)
  movb   $0x1,0x2(%rax)
  je     L72
  cmpb   $0x0,0x4(%rax)
  movb   $0x1,0x3(%rax)
  je     L72
  cmpb   $0x0,0x5(%rax)
  movb   $0x1,0x4(%rax)
  je     L72
  cmpb   $0x0,0x6(%rax)
  movb   $0x1,0x5(%rax)
  je     L72
  cmpb   $0x0,0x7(%rax)
  movb   $0x1,0x6(%rax)
  je     L72
  cmpb   $0x0,0x8(%rax)
  movb   $0x1,0x7(%rax)
  je     L72
  cmpb   $0x0,0x9(%rax)
  movb   $0x1,0x8(%rax)
  je     L72
  movb   $0x1,0x9(%rax)
L72:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void while_loop() {
  int i = 0;
  char *a = safealloc(10);
  while (*(a + i) && i < 10)
    a[i++] = 1;
}
```