ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<getDestination>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L95
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L15
L95:
  cmpl   $0x1,-0x14(%rbp)
  jne    L71
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L15
L71:
  cmpl   $0x2,-0x14(%rbp)
  jne    L109
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L15
L109:
  cmpl   $0x3,-0x14(%rbp)
  jne    L35
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L15
L35:
  cmpl   $0x4,-0x14(%rbp)
  jne    L40
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L15
L40:
  cmpl   $0x5,-0x14(%rbp)
  jne    L102
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L15
L102:
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int getDestination(int person) {
  int retValue_acc;
  {
    if (person == 0) {
      retValue_acc = 0;
      return (retValue_acc);
    } else {
      if (person == 1) {
        retValue_acc = 0;
        return (retValue_acc);
      } else {
        if (person == 2) {
          retValue_acc = 1;
          return (retValue_acc);
        } else {
          if (person == 3) {
            retValue_acc = 3;
            return (retValue_acc);
          } else {
            if (person == 4) {
              retValue_acc = 1;
              return (retValue_acc);
            } else {
              if (person == 5) {
                retValue_acc = 3;
                return (retValue_acc);
              } else {
                retValue_acc = 0;
                return (retValue_acc);
              }
            }
          }
        }
      }
    }
    return (retValue_acc);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getDestination>:
  endbr64
  cmp    $0x4,%edi
  je     L19
  jg     L24
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L15
  cmp    $0x3,%edi
  mov    $0x0,%eax
  cmove  %edi,%eax
  ret
L24:
  cmp    $0x5,%edi
  sete   %al
  movzbl %al,%eax
  lea    (%rax,%rax,2),%eax
  ret
L19:
  mov    $0x1,%eax
L15:
  ret
```

assistant: ```c
int getDestination(int person) {
  int retValue_acc;
  {
    if (person == 0) {
      retValue_acc = 0;
      return (retValue_acc);
    } else {
      if (person == 1) {
        retValue_acc = 0;
        return (retValue_acc);
      } else {
        if (person == 2) {
          retValue_acc = 1;
          return (retValue_acc);
        } else {
          if (person == 3) {
            retValue_acc = 3;
            return (retValue_acc);
          } else {
            if (person == 4) {
              retValue_acc = 1;
              return (retValue_acc);
            } else {
              if (person == 5) {
                retValue_acc = 3;
                return (retValue_acc);
              } else {
                retValue_acc = 0;
                return (retValue_acc);
              }
            }
          }
        }
      }
    }
    return (retValue_acc);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getDestination>:
  endbr64
  xor    %eax,%eax
  cmp    $0x5,%edi
  ja     L2
  mov    %edi,%edi
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L2:
  ret
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: 

assistant: ```c
int getDestination(int person) {
  int retValue_acc;
  {
    if (person == 0) {
      retValue_acc = 0;
      return (retValue_acc);
    } else {
      if (person == 1) {
        retValue_acc = 0;
        return (retValue_acc);
      } else {
        if (person == 2) {
          retValue_acc = 1;
          return (retValue_acc);
        } else {
          if (person == 3) {
            retValue_acc = 3;
            return (retValue_acc);
          } else {
            if (person == 4) {
              retValue_acc = 1;
              return (retValue_acc);
            } else {
              if (person == 5) {
                retValue_acc = 3;
                return (retValue_acc);
              } else {
                retValue_acc = 0;
                return (retValue_acc);
              }
            }
          }
        }
      }
    }
    return (retValue_acc);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getDestination>:
  endbr64
  xor    %eax,%eax
  cmp    $0x5,%edi
  ja     L1
  mov    %edi,%edi
  lea    D3(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L1:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string

tool: 

assistant: ```c
int getDestination(int person) {
  int retValue_acc;
  {
    if (person == 0) {
      retValue_acc = 0;
      return (retValue_acc);
    } else {
      if (person == 1) {
        retValue_acc = 0;
        return (retValue_acc);
      } else {
        if (person == 2) {
          retValue_acc = 1;
          return (retValue_acc);
        } else {
          if (person == 3) {
            retValue_acc = 3;
            return (retValue_acc);
          } else {
            if (person == 4) {
              retValue_acc = 1;
              return (retValue_acc);
            } else {
              if (person == 5) {
                retValue_acc = 3;
                return (retValue_acc);
              } else {
                retValue_acc = 0;
                return (retValue_acc);
              }
            }
          }
        }
      }
    }
    return (retValue_acc);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_pkt_len_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L137
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xdf,%eax
  jle    L115
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xfe,%eax
  jg     L115
  cmpl   $0x0,-0x8(%rbp)
  je     L14
  mov    $0x1,%eax
  jmp    L128
L14:
  mov    $0x2,%eax
  jmp    L128
L115:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xbf,%eax
  jle    L129
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xdf,%eax
  jg     L146
  mov    $0x2,%eax
  jmp    L128
L146:
  mov    $0x5,%eax
  jmp    L128
L129:
  mov    $0x1,%eax
  jmp    L128
L137:
  subq   $0x4,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L5
  cmp    $0x2,%eax
  jg     L48
  test   %eax,%eax
  je     L91
  cmp    $0x1,%eax
  je     L123
  jmp    L48
L91:
  mov    $0x1,%eax
  jmp    L128
L123:
  mov    $0x2,%eax
  jmp    L128
L5:
  mov    $0x4,%eax
  jmp    L128
L48:
  mov    $0x0,%eax
L128:
  pop    %rbp
  ret
```

assistant: ```c
unsigned get_pkt_len_len(uint8_t newfmt, uint8_t *p, int isprimary) {
  if (newfmt) {
    if (((*p) >= 224 && (*p) < 255)) {
      return (isprimary) ? 1 : 2;
    }
    return ((p[0] < 192) ? 1 : (p[0] < 224) ? 2 : 5);
  } else {
    switch (*--p & 0x3) {
    case 0:
      return 1;
    case 1:
      return 2;
    case 2:
      return 4;
    default:
      return 0;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_pkt_len_len>:
  endbr64
  test   %edi,%edi
  je     L42
  mov    (%rsi),%ecx
  lea    -0xe0(%rcx),%eax
  cmp    $0x1e,%eax
  ja     L39
  cmp    $0x1,%edx
  mov    $0x1,%eax
  adc    $0x0,%eax
  ret
L39:
  mov    $0x1,%eax
  cmp    $0xbf,%ecx
  jle    L48
  cmp    $0xe0,%ecx
  setge  %al
  movzbl %al,%eax
  lea    0x2(%rax,%rax,2),%eax
  ret
L42:
  mov    -0x4(%rsi),%edx
  and    $0x3,%edx
  mov    $0x2,%eax
  cmp    $0x1,%edx
  je     L48
  mov    $0x4,%eax
  cmp    $0x2,%edx
  je     L48
  test   %edx,%edx
  sete   %al
  movzbl %al,%eax
L48:
  ret
```

assistant: ```c
unsigned get_pkt_len_len(uint8_t newfmt, uint8_t *p, int isprimary) {
  if (newfmt) {
    if (((*p) >= 224 && (*p) < 255)) {
      return (isprimary) ? 1 : 2;
    }
    return ((p[0] < 192) ? 1 : (p[0] < 224) ? 2 : 5);
  } else {
    switch (*--p & 0x3) {
    case 0:
      return 1;
    case 1:
      return 2;
    case 2:
      return 4;
    default:
      return 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_pkt_len_len>:
  endbr64
  test   %edi,%edi
  je     L22
  mov    (%rsi),%ecx
  lea    -0xe0(%rcx),%eax
  cmp    $0x1e,%eax
  ja     L13
  cmp    $0x1,%edx
  mov    $0x1,%eax
  adc    $0x0,%eax
  ret
  nopl   0x0(%rax)
L22:
  mov    -0x4(%rsi),%edx
  xor    %eax,%eax
  and    $0x3,%edx
  cmp    $0x3,%edx
  jne    L33
L3:
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  lea    D2(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0x1,%eax
  cmp    $0xbf,%ecx
  jle    L3
  xor    %eax,%eax
  cmp    $0xe0,%ecx
  setge  %al
  lea    0x2(%rax,%rax,2),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D2: 

assistant: ```c
unsigned get_pkt_len_len(uint8_t newfmt, uint8_t *p, int isprimary) {
  if (newfmt) {
    if (((*p) >= 224 && (*p) < 255)) {
      return (isprimary) ? 1 : 2;
    }
    return ((p[0] < 192) ? 1 : (p[0] < 224) ? 2 : 5);
  } else {
    switch (*--p & 0x3) {
    case 0:
      return 1;
    case 1:
      return 2;
    case 2:
      return 4;
    default:
      return 0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_pkt_len_len>:
  endbr64
  test   %edi,%edi
  je     L2
  mov    (%rsi),%ecx
  lea    -0xe0(%rcx),%eax
  cmp    $0x1e,%eax
  ja     L1
  cmp    $0x1,%edx
  mov    $0x1,%eax
  adc    $0x0,%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    -0x4(%rsi),%edx
  xor    %eax,%eax
  and    $0x3,%edx
  cmp    $0x3,%edx
  jne    L16
L22:
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  lea    D1(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  cmp    $0xbf,%ecx
  jle    L22
  xor    %eax,%eax
  cmp    $0xe0,%ecx
  setge  %al
  lea    0x2(%rax,%rax,2),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string

tool: D1: 

assistant: ```c
unsigned get_pkt_len_len(uint8_t newfmt, uint8_t *p, int isprimary) {
  if (newfmt) {
    if (((*p) >= 224 && (*p) < 255)) {
      return (isprimary) ? 1 : 2;
    }
    return ((p[0] < 192) ? 1 : (p[0] < 224) ? 2 : 5);
  } else {
    switch (*--p & 0x3) {
    case 0:
      return 1;
    case 1:
      return 2;
    case 2:
      return 4;
    default:
      return 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xcorr_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  jle    L59
  cmpl   $0x0,-0x3c(%rbp)
  jle    L59
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L20
L59:
  cmpl   $0x0,-0x38(%rbp)
  jg     L72
  cmpl   $0x0,-0x3c(%rbp)
  jg     L72
  movl   $0x0,-0xc(%rbp)
  mov    -0x38(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jge    L62
  mov    -0x38(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  jmp    L98
L62:
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
L98:
  mov    %eax,-0x10(%rbp)
  jmp    L20
L72:
  mov    -0x38(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L64
  mov    -0x38(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L20
L64:
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L8
L44:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  sub    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x14(%rbp),%eax
  sub    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L44
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double xcorr_sum(double *f1, double *f2, int n, int tau1, int tau2) {
  int i, nf, ni;
  double sum = 0;
  if (tau1 > 0 && tau2 > 0) {
    ni = (tau1 > tau2) ? tau1 : tau2;
    nf = n;
  } else if (tau1 <= 0 && tau2 <= 0) {
    ni = 0;
    nf = (tau1 < tau2) ? n - abs(tau1) : n - abs(tau2);
  } else {
    if (tau1 > tau2) {
      ni = tau1;
      nf = n - abs(tau2);
    } else {
      ni = tau2;
      nf = n - abs(tau1);
    }
  }
  for (i = ni; i < nf; i++) {
    sum += f1[i] * f1[i - tau1] * f2[i - tau2];
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xcorr_sum>:
  endbr64
  mov    %rsi,%r9
  test   %ecx,%ecx
  jle    L28
  test   %r8d,%r8d
  jle    L28
  cmp    %r8d,%ecx
  mov    %r8d,%eax
  cmovge %ecx,%eax
L29:
  cmp    %eax,%edx
  jle    L124
  cltq
  movslq %ecx,%rcx
  neg    %rcx
  lea    (%rdi,%rcx,8),%rsi
  movslq %r8d,%r8
  neg    %r8
  lea    (%r9,%r8,8),%rcx
  pxor   %xmm1,%xmm1
L26:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L26
L44:
  movapd %xmm1,%xmm0
  ret
L28:
  test   %ecx,%ecx
  jg     L81
  test   %r8d,%r8d
  jg     L81
  cmp    %r8d,%ecx
  jge    L60
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  sub    %eax,%edx
  mov    $0x0,%eax
  jmp    L29
L60:
  mov    %r8d,%eax
  neg    %eax
  cmovs  %r8d,%eax
  sub    %eax,%edx
  mov    $0x0,%eax
  jmp    L29
L81:
  cmp    %r8d,%ecx
  jle    L16
  mov    %r8d,%eax
  neg    %eax
  cmovs  %r8d,%eax
  sub    %eax,%edx
  mov    %ecx,%eax
  jmp    L29
L16:
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  sub    %eax,%edx
  mov    %r8d,%eax
  jmp    L29
L124:
  pxor   %xmm1,%xmm1
  jmp    L44
```

assistant: ```c
double xcorr_sum(double *f1, double *f2, int n, int tau1, int tau2) {
  int i, nf, ni;
  double sum = 0;
  if (tau1 > 0 && tau2 > 0) {
    ni = (tau1 > tau2) ? tau1 : tau2;
    nf = n;
  } else if (tau1 <= 0 && tau2 <= 0) {
    ni = 0;
    nf = (tau1 < tau2) ? n - abs(tau1) : n - abs(tau2);
  } else {
    if (tau1 > tau2) {
      ni = tau1;
      nf = n - abs(tau2);
    } else {
      ni = tau2;
      nf = n - abs(tau1);
    }
  }
  for (i = ni; i < nf; i++) {
    sum += f1[i] * f1[i - tau1] * f2[i - tau2];
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xcorr_sum>:
  endbr64
  test   %ecx,%ecx
  jle    L93
  test   %r8d,%r8d
  jle    L63
  cmp    %r8d,%ecx
  mov    %r8d,%eax
  cmovge %ecx,%eax
L44:
  cmp    %eax,%edx
  jle    L96
L66:
  movslq %ecx,%rcx
  movslq %r8d,%r8
  pxor   %xmm1,%xmm1
  cltq
  neg    %rcx
  neg    %r8
  lea    (%rdi,%rcx,8),%r9
  lea    (%rsi,%r8,8),%rcx
  nopl   0x0(%rax)
L117:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%r9,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %eax,%edx
  jg     L117
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L63:
  test   %ecx,%ecx
  jg     L50
L93:
  test   %r8d,%r8d
  jg     L50
  cmp    %r8d,%ecx
  jge    L62
  add    %ecx,%edx
  xor    %eax,%eax
  cmp    %eax,%edx
  jg     L66
L96:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
  nop
L50:
  cmp    %r8d,%ecx
  jle    L38
  mov    %r8d,%eax
  neg    %eax
  cmovs  %r8d,%eax
  sub    %eax,%edx
  mov    %ecx,%eax
  jmp    L44
  nopl   0x0(%rax)
L38:
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  sub    %eax,%edx
  mov    %r8d,%eax
  jmp    L44
  nopl   0x0(%rax)
L62:
  add    %r8d,%edx
  xor    %eax,%eax
  jmp    L44
```

assistant: ```c
double xcorr_sum(double *f1, double *f2, int n, int tau1, int tau2) {
  int i, nf, ni;
  double sum = 0;
  if (tau1 > 0 && tau2 > 0) {
    ni = (tau1 > tau2) ? tau1 : tau2;
    nf = n;
  } else if (tau1 <= 0 && tau2 <= 0) {
    ni = 0;
    nf = (tau1 < tau2) ? n - abs(tau1) : n - abs(tau2);
  } else {
    if (tau1 > tau2) {
      ni = tau1;
      nf = n - abs(tau2);
    } else {
      ni = tau2;
      nf = n - abs(tau1);
    }
  }
  for (i = ni; i < nf; i++) {
    sum += f1[i] * f1[i - tau1] * f2[i - tau2];
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xcorr_sum>:
  endbr64
  mov    %rsi,%r9
  mov    %ecx,%esi
  test   %ecx,%ecx
  jle    L55
  test   %r8d,%r8d
  jle    L117
  cmp    %r8d,%ecx
  mov    %r8d,%eax
  cmovge %ecx,%eax
L9:
  cmp    %eax,%edx
  jle    L88
L84:
  sub    %eax,%edx
  push   %rbp
  push   %rbx
  cmp    $0x1,%edx
  je     L131
  movslq %eax,%rcx
  movslq %esi,%r11
  pxor   %xmm0,%xmm0
  mov    %rcx,%r10
  lea    (%rdi,%rcx,8),%rbp
  sub    %r11,%r10
  lea    (%rdi,%r10,8),%rbx
  movslq %r8d,%r10
  sub    %r10,%rcx
  mov    %edx,%r10d
  shr    %r10d
  lea    (%r9,%rcx,8),%r11
  xor    %ecx,%ecx
  shl    $0x4,%r10
  cs nopw 0x0(%rax,%rax,1)
L141:
  movupd (%rbx,%rcx,1),%xmm1
  movupd 0x0(%rbp,%rcx,1),%xmm3
  movupd (%r11,%rcx,1),%xmm4
  add    $0x10,%rcx
  mulpd  %xmm3,%xmm1
  mulpd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %r10,%rcx
  jne    L141
  mov    %edx,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %edx,%ecx
  je     L43
L95:
  mov    %eax,%edx
  movslq %eax,%rcx
  sub    %r8d,%eax
  sub    %esi,%edx
  cltq
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm1
  mulsd  (%rdi,%rcx,8),%xmm1
  mulsd  (%r9,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
L43:
  pop    %rbx
  pop    %rbp
  ret
  nop
L117:
  test   %ecx,%ecx
  jg     L19
L55:
  test   %r8d,%r8d
  jg     L19
  cmp    %r8d,%esi
  jge    L75
  add    %esi,%edx
  xor    %eax,%eax
  cmp    %eax,%edx
  jg     L84
L88:
  pxor   %xmm0,%xmm0
  ret
  nop
L19:
  cmp    %r8d,%esi
  jle    L40
  mov    %r8d,%eax
  neg    %eax
  cmovs  %r8d,%eax
  sub    %eax,%edx
  mov    %esi,%eax
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  sub    %eax,%edx
  mov    %r8d,%eax
  jmp    L9
  nopl   0x0(%rax)
L75:
  add    %r8d,%edx
  xor    %eax,%eax
  jmp    L9
L131:
  pxor   %xmm0,%xmm0
  jmp    L95
```

assistant: ```c
double xcorr_sum(double *f1, double *f2, int n, int tau1, int tau2) {
  int i, nf, ni;
  double sum = 0;
  if (tau1 > 0 && tau2 > 0) {
    ni = (tau1 > tau2) ? tau1 : tau2;
    nf = n;
  } else if (tau1 <= 0 && tau2 <= 0) {
    ni = 0;
    nf = (tau1 < tau2) ? n - abs(tau1) : n - abs(tau2);
  } else {
    if (tau1 > tau2) {
      ni = tau1;
      nf = n - abs(tau2);
    } else {
      ni = tau2;
      nf = n - abs(tau1);
    }
  }
  for (i = ni; i < nf; i++) {
    sum += f1[i] * f1[i - tau1] * f2[i - tau2];
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %ecx,%eax
  mov    %esi,%ecx
  mov    %cl,-0x8(%rbp)
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L13
  movsbl -0xc(%rbp),%ecx
  movsbl -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L13:
  movsbl -0xc(%rbp),%ecx
  movsbl -0x10(%rbp),%edx
  movsbl -0x8(%rbp),%eax
  mov    -0x4(%rbp),%esi
  lea    -0x1(%rsi),%edi
  mov    %eax,%esi
  call   <move>
  movsbl -0xc(%rbp),%ecx
  movsbl -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0x8(%rbp),%ecx
  movsbl -0xc(%rbp),%edx
  movsbl -0x10(%rbp),%eax
  mov    -0x4(%rbp),%esi
  lea    -0x1(%rsi),%edi
  mov    %eax,%esi
  call   <move>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
data_type: string

tool: D17: Move disc %d from %c to %c


assistant: ```c
void move(int numDiscs, char src, char dst, char spare) {
  if (numDiscs == 1) {
    printf("Move disc %d from %c to %c\n", numDiscs, src, dst);
    return;
  }
  move(numDiscs - 1, src, spare, dst);
  printf("Move disc %d from %c to %c\n", numDiscs, src, dst);
  move(numDiscs - 1, spare, dst, src);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<move>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L4
  mov    %edi,%r13d
  movsbl %dl,%ebx
  movsbl %cl,%r12d
  movsbl %sil,%ebp
  lea    -0x1(%rdi),%r14d
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r14d,%edi
  call   <move>
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <move>
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  movsbl %dl,%ecx
  movsbl %sil,%edx
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_infered: string

tool: D16: Move disc %d from %c to %c


assistant: ```c
void move(int numDiscs, char src, char dst, char spare) {
  if (numDiscs == 1) {
    printf("Move disc %d from %c to %c\n", numDiscs, src, dst);
    return;
  }
  move(numDiscs - 1, src, spare, dst);
  printf("Move disc %d from %c to %c\n", numDiscs, src, dst);
  move(numDiscs - 1, spare, dst, src);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<move>:
  endbr64
  push   %r15
  push   %r14
  movsbl %sil,%r14d
  push   %r13
  movsbl %dl,%r13d
  push   %r12
  push   %rbp
  cmp    $0x1,%edi
  je     L9
  movsbl %cl,%ebp
  lea    -0x1(%rdi),%r15d
  mov    %edi,%r12d
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <move>
  mov    %r13d,%ecx
  mov    %r14d,%edx
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r15d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1120 <move>
  nop
L9:
  pop    %rbp
  mov    %r13d,%ecx
  pop    %r12
  mov    %r14d,%edx
  pop    %r13
  mov    $0x1,%esi
  lea    D19(%rip),%rdi
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
datatype: string

tool: D19: Move disc %d from %c to %c


assistant: ```c
void move(int numDiscs, char src, char dst, char spare) {
  if (numDiscs == 1) {
    printf("Move disc %d from %c to %c\n", numDiscs, src, dst);
    return;
  }
  move(numDiscs - 1, src, spare, dst);
  printf("Move disc %d from %c to %c\n", numDiscs, src, dst);
  move(numDiscs - 1, spare, dst, src);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nmiISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L7:
  jmp    L7
```

assistant: ```c
void nmiISR(void) {
#pragma diag_push
#pragma CHECK_ULP("-2.1")
  while (1) {
  }
#pragma diag_pop
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nmiISR>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
void nmiISR(void) {
#pragma diag_push
#pragma CHECK_ULP("-2.1")
  while (1) {
  }
#pragma diag_pop
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nmiISR>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void nmiISR(void) {
#pragma diag_push
#pragma CHECK_ULP("-2.1")
  while (1) {
  }
#pragma diag_pop
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nmiISR>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
void nmiISR(void) {
#pragma diag_push
#pragma CHECK_ULP("-2.1")
  while (1) {
  }
#pragma diag_pop
}
```