ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
L126:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jbe    L45
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    $0x13,%eax
  ja     L45
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L143
L39:
  movl   $0x0,-0x10(%rbp)
  jmp    L76
L113:
  cmpl   $0x0,-0x14(%rbp)
  jne    L19
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L108
L19:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L97
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L108
L97:
  cmpl   $0x0,-0x10(%rbp)
  jne    L3
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L108
L3:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L34
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L108
L34:
  mov    $0x20,%edi
  call   <putchar@plt>
L108:
  addl   $0x1,-0x10(%rbp)
L76:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jbe    L113
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x14(%rbp)
L143:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jbe    L39
L45:
  cmpl   $0x1,-0xc(%rbp)
  jne    L126
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L120
  call   <__stack_chk_fail@plt>
L120:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D26
type_guessed: string

tool: D9: Inserire il lato del quadrtato: 

tool: D0: %u

tool: 

assistant: ```c
int main(void) {
  unsigned int lato = 0;
  unsigned int righe;
  unsigned int colonne;
  unsigned int valoreSentinella = 0;
  do {
    printf("Inserire il lato del quadrtato: ");
    scanf("%u", &lato);
    lato++;
    if (--lato > (unsigned int)1) {
      if (--lato < (unsigned int)20) {
        valoreSentinella = 1;
        righe = 0;
        while (righe <= lato) {
          colonne = 0;
          while (colonne <= lato) {
            if (righe == 0) {
              printf("%s", "*");
            } else if (righe == lato) {
              printf("%s", "*");
            } else if (colonne == 0) {
              printf("%s", "*");
            } else if (colonne == lato) {
              printf("%s", "*");
            } else
              printf("%s", " ");
            colonne++;
          }
          puts("");
          righe++;
        }
      }
    }
  } while (valoreSentinella != 1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D17(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D18(%rip),%rbx
L60:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jbe    L60
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x13,%eax
  ja     L60
  mov    $0x0,%ebp
  lea    D22(%rip),%r12
  jmp    L94
L119:
  mov    $0x2a,%edi
  call   <putchar@plt>
L83:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jb     L116
L133:
  test   %ebp,%ebp
  je     L119
  cmp    %ebp,%eax
  je     L126
  test   %ebx,%ebx
  je     L53
  cmp    %ebx,%eax
  je     L23
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L83
L126:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L83
L53:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L83
L23:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L83
L116:
  mov    %r12,%rdi
  call   <puts@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jb     L89
L94:
  mov    0x4(%rsp),%eax
  mov    $0x0,%ebx
  jmp    L133
L89:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L130
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L130:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D22
type: string

tool: D17: Inserire il lato del quadrtato: 

tool: D18: %u

tool: 

assistant: ```c
int main(void) {
  unsigned int lato = 0;
  unsigned int righe;
  unsigned int colonne;
  unsigned int valoreSentinella = 0;
  do {
    printf("Inserire il lato del quadrtato: ");
    scanf("%u", &lato);
    lato++;
    if (--lato > (unsigned int)1) {
      if (--lato < (unsigned int)20) {
        valoreSentinella = 1;
        righe = 0;
        while (righe <= lato) {
          colonne = 0;
          while (colonne <= lato) {
            if (righe == 0) {
              printf("%s", "*");
            } else if (righe == lato) {
              printf("%s", "*");
            } else if (colonne == 0) {
              printf("%s", "*");
            } else if (colonne == lato) {
              printf("%s", "*");
            } else
              printf("%s", " ");
            colonne++;
          }
          puts("");
          righe++;
        }
      }
    }
  } while (valoreSentinella != 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L80:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jbe    L80
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x13,%eax
  ja     L80
  xor    %ebp,%ebp
  lea    D5(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L101:
  xor    %ebx,%ebx
  jmp    L81
  nopl   0x0(%rax)
L18:
  cmp    %ebp,%eax
  je     L91
  test   %ebx,%ebx
  je     L91
  cmp    %ebx,%eax
  je     L91
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jb     L68
L81:
  test   %ebp,%ebp
  jne    L18
L91:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jae    L81
L68:
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jae    L101
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
type_infered: string
name: disassemble_data
arguments: label: D13
type_infered: string
name: disassemble_data
arguments: label: D5
type_infered: string

tool: D19: Inserire il lato del quadrtato: 

tool: D13: %u

tool: 

assistant: ```c
int main(void) {
  unsigned int lato = 0;
  unsigned int righe;
  unsigned int colonne;
  unsigned int valoreSentinella = 0;
  do {
    printf("Inserire il lato del quadrtato: ");
    scanf("%u", &lato);
    lato++;
    if (--lato > (unsigned int)1) {
      if (--lato < (unsigned int)20) {
        valoreSentinella = 1;
        righe = 0;
        while (righe <= lato) {
          colonne = 0;
          while (colonne <= lato) {
            if (righe == 0) {
              printf("%s", "*");
            } else if (righe == lato) {
              printf("%s", "*");
            } else if (colonne == 0) {
              printf("%s", "*");
            } else if (colonne == lato) {
              printf("%s", "*");
            } else
              printf("%s", " ");
            colonne++;
          }
          puts("");
          righe++;
        }
      }
    }
  } while (valoreSentinella != 1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L73:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jbe    L73
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x13,%eax
  ja     L73
  xor    %ebp,%ebp
  lea    D11(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %ebx,%ebx
  test   %ebp,%ebp
  jne    L18
  jmp    L41
L62:
  test   %ebx,%ebx
  je     L32
  cmp    %ebx,%eax
  je     L32
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jb     L20
L18:
  cmp    %ebp,%eax
  jne    L62
L32:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jae    L18
L20:
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jae    L16
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L41:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,0x4(%rsp)
  jae    L41
  jmp    L20
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D27
datatype: string
name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string

tool: D27: Inserire il lato del quadrtato: 

tool: D2: %u

tool: 

assistant: ```c
int main(void) {
  unsigned int lato = 0;
  unsigned int righe;
  unsigned int colonne;
  unsigned int valoreSentinella = 0;
  do {
    printf("Inserire il lato del quadrtato: ");
    scanf("%u", &lato);
    lato++;
    if (--lato > (unsigned int)1) {
      if (--lato < (unsigned int)20) {
        valoreSentinella = 1;
        righe = 0;
        while (righe <= lato) {
          colonne = 0;
          while (colonne <= lato) {
            if (righe == 0) {
              printf("%s", "*");
            } else if (righe == lato) {
              printf("%s", "*");
            } else if (colonne == 0) {
              printf("%s", "*");
            } else if (colonne == lato) {
              printf("%s", "*");
            } else
              printf("%s", " ");
            colonne++;
          }
          puts("");
          righe++;
        }
      }
    }
  } while (valoreSentinella != 1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_next_operator>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x2000,%edi
  call   <hefesto_mloc@plt>
  mov    %rax,%rbp
  mov    (%rbx),%r13
  mov    $0x2000,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  test   %r12,%r12
  je     L28
  cmpb   $0x0,(%r12)
  je     L28
  lea    (%r12,%r13,1),%rcx
  movzbl (%rcx),%edx
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %sil
  xor    %esi,%eax
  cmp    $0xa,%dl
  sete   %sil
  xor    %esi,%eax
  cmp    $0xd,%dl
  sete   %sil
  cmp    %sil,%al
  je     L106
L3:
  add    $0x1,%rcx
  addq   $0x1,(%rbx)
  movzbl (%rcx),%edx
  cmp    $0xd,%dl
  sete   %sil
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %dil
  xor    %edi,%eax
  cmp    $0xa,%dl
  sete   %dil
  xor    %edi,%eax
  cmp    %al,%sil
  jne    L3
L106:
  mov    %dl,0x0(%rbp)
  lea    0x1(%rcx),%rdx
  lea    0x1fff(%rcx),%r8
  mov    %rbp,%rdi
  sub    %rcx,%rdi
  movabs $0x7000846200000000,%r9
  jmp    L99
L90:
  cmp    $0x5e,%al
  je     L127
  cmp    $0x7c,%al
  jne    L75
L127:
  cmp    %r8,%rdx
  je     L79
  mov    %al,(%rsi)
  add    $0x1,%rdx
L99:
  lea    (%rdx,%rdi,1),%rsi
  movzbl (%rdx),%eax
  lea    -0x2b(%rax),%ecx
  test   $0xfd,%cl
  je     L127
  cmp    $0x3e,%al
  jg     L90
  cmp    $0x20,%al
  jle    L75
  bt     %rax,%r9
  jb     L127
L75:
  movb   $0x0,(%rsi)
  sub    %r12,%rdx
  mov    %rdx,(%rbx)
L28:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L79:
  mov    %r8,%rdx
  jmp    L75
```

assistant: ```c
char *get_next_operator(const char *expression, size_t *offset) {
  char *operand = (char *)hefesto_mloc(8192), *o, *o_end = NULL;
  const char *e = expression + (*offset);
  memset(operand, 0, 8192);
  if (expression == NULL || *expression == 0)
    return operand;
  while ((((*e) == ' ') ^ ((*e) == '\t') ^ ((*e) == '\n') ^ ((*e) == '\r'))) {
    e++;
    *offset = *offset + 1;
  }
  o = operand;
  o_end = operand + 8192 - 1;
  *o = *e;
  o++;
  e++;
  while (((*e) == '+' || (*e) == '-' || (*e) == '*' || (*e) == '/' || (*e) == '=' || (*e) == '|' || (*e) == '&' || (*e) == '^' || (*e) == '<' || (*e) == '>' || (*e) == '%' || (*e) == '!') && o != o_end) {
    *o = *e;
    o++;
    e++;
  }
  *o = 0;
  *offset = (e - expression);
  return operand;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_next_operator>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x2000,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <hefesto_mloc@plt>
  xor    %esi,%esi
  mov    $0x2000,%edx
  mov    (%rbx),%r13
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  test   %rbp,%rbp
  je     L80
  cmpb   $0x0,0x0(%rbp)
  je     L80
  lea    0x0(%rbp,%r13,1),%r8
  movzbl (%r8),%edx
  cmp    $0xd,%dl
  sete   %cl
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %sil
  xor    %esi,%eax
  cmp    $0xa,%dl
  sete   %sil
  xor    %esi,%eax
  cmp    %al,%cl
  je     L92
  mov    (%rbx),%r9
  mov    %r8,%rcx
  nopl   0x0(%rax,%rax,1)
L124:
  add    $0x1,%rcx
  lea    (%rcx,%r9,1),%rax
  sub    %r8,%rax
  mov    %rax,(%rbx)
  movzbl (%rcx),%edx
  cmp    $0xd,%dl
  sete   %sil
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %dil
  xor    %edi,%eax
  cmp    $0xa,%dl
  sete   %dil
  xor    %edi,%eax
  cmp    %al,%sil
  jne    L124
L117:
  mov    %r12,%rdi
  mov    %dl,(%r12)
  lea    0x1fff(%rcx),%r8
  lea    0x1(%rcx),%rdx
  movabs $0x7000846200000000,%r9
  sub    %rcx,%rdi
  nopl   0x0(%rax)
L10:
  movzbl (%rdx),%eax
  lea    (%rdx,%rdi,1),%rsi
  lea    -0x2b(%rax),%ecx
  and    $0xfd,%ecx
  je     L15
  cmp    $0x3e,%al
  jg     L56
  cmp    $0x20,%al
  jle    L85
  bt     %rax,%r9
  jb     L15
L85:
  sub    %rbp,%rdx
  movb   $0x0,(%rsi)
  mov    %rdx,(%rbx)
L80:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L56:
  cmp    $0x5e,%al
  je     L15
  cmp    $0x7c,%al
  jne    L85
L15:
  cmp    %r8,%rdx
  je     L85
  mov    %al,(%rsi)
  add    $0x1,%rdx
  jmp    L10
L92:
  mov    %r8,%rcx
  jmp    L117
```

assistant: ```c
char *get_next_operator(const char *expression, size_t *offset) {
  char *operand = (char *)hefesto_mloc(8192), *o, *o_end = NULL;
  const char *e = expression + (*offset);
  memset(operand, 0, 8192);
  if (expression == NULL || *expression == 0)
    return operand;
  while ((((*e) == ' ') ^ ((*e) == '\t') ^ ((*e) == '\n') ^ ((*e) == '\r'))) {
    e++;
    *offset = *offset + 1;
  }
  o = operand;
  o_end = operand + 8192 - 1;
  *o = *e;
  o++;
  e++;
  while (((*e) == '+' || (*e) == '-' || (*e) == '*' || (*e) == '/' || (*e) == '=' || (*e) == '|' || (*e) == '&' || (*e) == '^' || (*e) == '<' || (*e) == '>' || (*e) == '%' || (*e) == '!') && o != o_end) {
    *o = *e;
    o++;
    e++;
  }
  *o = 0;
  *offset = (e - expression);
  return operand;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_next_operator>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x2000,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <hefesto_mloc@plt>
  xor    %esi,%esi
  mov    $0x2000,%edx
  mov    (%rbx),%r13
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  test   %rbp,%rbp
  je     L45
  cmpb   $0x0,0x0(%rbp)
  je     L45
  lea    0x0(%rbp,%r13,1),%r8
  movzbl (%r8),%edx
  cmp    $0xd,%dl
  sete   %cl
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %sil
  xor    %esi,%eax
  cmp    $0xa,%dl
  sete   %sil
  xor    %esi,%eax
  cmp    %al,%cl
  je     L70
  mov    (%rbx),%r9
  mov    %r8,%rcx
  nopl   0x0(%rax,%rax,1)
L44:
  add    $0x1,%rcx
  lea    (%rcx,%r9,1),%rax
  sub    %r8,%rax
  mov    %rax,(%rbx)
  movzbl (%rcx),%edx
  cmp    $0xd,%dl
  sete   %sil
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %dil
  xor    %edi,%eax
  cmp    $0xa,%dl
  sete   %dil
  xor    %edi,%eax
  cmp    %al,%sil
  jne    L44
L107:
  mov    %r12,%rdi
  mov    %dl,(%r12)
  lea    0x1fff(%rcx),%r8
  lea    0x1(%rcx),%rdx
  movabs $0x7000846200000000,%r9
  sub    %rcx,%rdi
  nopl   0x0(%rax)
L122:
  movzbl (%rdx),%eax
  lea    (%rdx,%rdi,1),%rsi
  lea    -0x2b(%rax),%ecx
  and    $0xfd,%ecx
  je     L63
  cmp    $0x3e,%al
  jg     L54
  cmp    $0x20,%al
  jle    L36
  bt     %rax,%r9
  jb     L63
L36:
  sub    %rbp,%rdx
  movb   $0x0,(%rsi)
  mov    %rdx,(%rbx)
L45:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L54:
  cmp    $0x5e,%al
  je     L63
  cmp    $0x7c,%al
  jne    L36
L63:
  cmp    %r8,%rdx
  je     L36
  mov    %al,(%rsi)
  add    $0x1,%rdx
  jmp    L122
L70:
  mov    %r8,%rcx
  jmp    L107
```

assistant: ```c
char *get_next_operator(const char *expression, size_t *offset) {
  char *operand = (char *)hefesto_mloc(8192), *o, *o_end = NULL;
  const char *e = expression + (*offset);
  memset(operand, 0, 8192);
  if (expression == NULL || *expression == 0)
    return operand;
  while ((((*e) == ' ') ^ ((*e) == '\t') ^ ((*e) == '\n') ^ ((*e) == '\r'))) {
    e++;
    *offset = *offset + 1;
  }
  o = operand;
  o_end = operand + 8192 - 1;
  *o = *e;
  o++;
  e++;
  while (((*e) == '+' || (*e) == '-' || (*e) == '*' || (*e) == '/' || (*e) == '=' || (*e) == '|' || (*e) == '&' || (*e) == '^' || (*e) == '<' || (*e) == '>' || (*e) == '%' || (*e) == '!') && o != o_end) {
    *o = *e;
    o++;
    e++;
  }
  *o = 0;
  *offset = (e - expression);
  return operand;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skipstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L17:
  cmpl   $0x0,-0x8(%rbp)
  je     L16
  cmpl   $0x75,-0x4(%rbp)
  jne    L76
  movl   $0x4,-0x8(%rbp)
  jmp    L104
L86:
  mov    $0x0,%eax
  call   <next@plt>
  mov    D1(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jne    L95
  mov    $0x1,%eax
  jmp    L74
L95:
  subl   $0x1,-0x8(%rbp)
L104:
  cmpl   $0x0,-0x8(%rbp)
  jg     L86
  jmp    L39
L76:
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L16:
  cmpl   $0x22,-0x4(%rbp)
  je     L24
  cmpl   $0x5c,-0x4(%rbp)
  jne    L39
  movl   $0x1,-0x8(%rbp)
  jmp    L39
L24:
  mov    $0x0,%eax
  jmp    L74
L39:
  mov    $0x0,%eax
  call   <next@plt>
  mov    %eax,-0x4(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L17
  mov    $0x1,%eax
L74:
  leave
  ret
```

assistant: ```c
int skipstring() {
  int c, e = 0;
  while ((c = next()) != EOF) {
    if (e) {
      switch (c) {
      case 'u':
        for (e = 4; e > 0; e--)
          if (next() == EOF)
            return 1;
        continue;
      default:
        e = 0;
        continue;
      }
    }
    switch (c) {
    case '\\':
      e = 1;
      continue;
    case '"':
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipstring>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  jmp    L9
L7:
  cmp    $0x22,%eax
  je     L82
  cmp    $0x5c,%eax
  sete   %bl
  movzbl %bl,%ebx
L9:
  mov    $0x0,%eax
  call   <next@plt>
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L61
  test   %ebx,%ebx
  je     L7
  mov    $0x0,%ebx
  cmp    $0x75,%eax
  jne    L9
  mov    $0x4,%ebx
L31:
  mov    $0x0,%eax
  call   <next@plt>
  mov    D1(%rip),%rdx
  cmp    (%rdx),%eax
  je     L34
  sub    $0x1,%ebx
  jne    L31
  jmp    L9
L61:
  mov    $0x1,%ebx
L82:
  mov    %ebx,%eax
  pop    %rbx
  ret
L34:
  mov    $0x1,%ebx
  jmp    L82
```

assistant: ```c
int skipstring() {
  int c, e = 0;
  while ((c = next()) != EOF) {
    if (e) {
      switch (c) {
      case 'u':
        for (e = 4; e > 0; e--)
          if (next() == EOF)
            return 1;
        continue;
      default:
        e = 0;
        continue;
      }
    }
    switch (c) {
    case '\\':
      e = 1;
      continue;
    case '"':
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skipstring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%rbx
L37:
  xor    %eax,%eax
  call   <next@plt>
  cmp    %eax,(%rbx)
  jne    L51
  jmp    L35
  xchg   %ax,%ax
L91:
  cmp    $0x5c,%eax
  jne    L22
  xor    %eax,%eax
  call   <next@plt>
  cmp    (%rbx),%eax
  je     L35
  cmp    $0x75,%eax
  je     L67
L22:
  xor    %eax,%eax
  call   <next@plt>
  cmp    (%rbx),%eax
  je     L35
L51:
  cmp    $0x22,%eax
  jne    L91
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L67:
  xor    %eax,%eax
  mov    $0x4,%ebp
  call   <next@plt>
  cmp    (%rbx),%eax
  je     L35
L86:
  sub    $0x1,%ebp
  je     L37
  xor    %eax,%eax
  call   <next@plt>
  cmp    (%rbx),%eax
  jne    L86
L35:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int skipstring() {
  int c, e = 0;
  while ((c = next()) != EOF) {
    if (e) {
      switch (c) {
      case 'u':
        for (e = 4; e > 0; e--)
          if (next() == EOF)
            return 1;
        continue;
      default:
        e = 0;
        continue;
      }
    }
    switch (c) {
    case '\\':
      e = 1;
      continue;
    case '"':
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skipstring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbx
L22:
  xor    %eax,%eax
  call   <next@plt>
  cmp    %eax,(%rbx)
  jne    L35
  jmp    L94
  xchg   %ax,%ax
L96:
  cmp    $0x5c,%eax
  jne    L86
  xor    %eax,%eax
  call   <next@plt>
  cmp    (%rbx),%eax
  je     L94
  cmp    $0x75,%eax
  je     L34
L86:
  xor    %eax,%eax
  call   <next@plt>
  cmp    (%rbx),%eax
  je     L94
L35:
  cmp    $0x22,%eax
  jne    L96
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L34:
  xor    %eax,%eax
  mov    $0x4,%ebp
  call   <next@plt>
  cmp    (%rbx),%eax
  je     L94
L50:
  sub    $0x1,%ebp
  je     L22
  xor    %eax,%eax
  call   <next@plt>
  cmp    (%rbx),%eax
  jne    L50
L94:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int skipstring() {
  int c, e = 0;
  while ((c = next()) != EOF) {
    if (e) {
      switch (c) {
      case 'u':
        for (e = 4; e > 0; e--)
          if (next() == EOF)
            return 1;
        continue;
      default:
        e = 0;
        continue;
      }
    }
    switch (c) {
    case '\\':
      e = 1;
      continue;
    case '"':
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: hello,world!!


assistant: ```c
int main() {
  printf("hello,world!!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: hello,world!!


assistant: ```c
int main() {
  printf("hello,world!!\n");
  return 0;
}
```