ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %edi,0x24(%rsp)
  mov    %edx,0x38(%rsp)
  mov    %rcx,0x50(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %r9,0x58(%rsp)
  mov    0xb0(%rsp),%r15d
  test   %esi,%esi
  jle    L40
  mov    %esi,%eax
  mov    %edx,%edi
  mov    %esi,0x3c(%rsp)
  mov    0xa0(%rsp),%ecx
  shl    $0x9,%ecx
  mov    %ecx,0x44(%rsp)
  mov    %r15d,%esi
  shl    $0x9,%esi
  mov    %esi,0x48(%rsp)
  lea    -0x200(%rax),%edx
  sub    $0x1,%eax
  and    $0xfffffe00,%eax
  sub    %eax,%edx
  mov    %edx,0x4c(%rsp)
  mov    %r8d,%eax
  shl    $0x5,%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,0x8(%rsp)
  movl   $0x0,0x2c(%rsp)
  movl   $0x0,0x40(%rsp)
  lea    -0x20(%rdi),%edx
  lea    -0x1(%rdi),%eax
  and    $0xffffffe0,%eax
  sub    %eax,%edx
  mov    %edx,0x14(%rsp)
L12:
  mov    $0x200,%eax
  mov    0x3c(%rsp),%ecx
  cmp    %eax,%ecx
  cmovle %ecx,%eax
  mov    %eax,0x4(%rsp)
  mov    0x24(%rsp),%eax
  test   %eax,%eax
  jle    L34
  mov    0x50(%rsp),%rcx
  mov    %rcx,0x18(%rsp)
  sub    $0x1,%eax
  and    $0xfffffe00,%eax
  add    $0x200,%eax
  mov    %eax,0x28(%rsp)
  movslq 0x40(%rsp),%rax
  mov    0x58(%rsp),%rsi
  lea    (%rsi,%rax,8),%rax
  mov    %rax,0x30(%rsp)
  movl   $0x0,0x20(%rsp)
L50:
  mov    0x24(%rsp),%r13d
  mov    0x20(%rsp),%ecx
  sub    %ecx,%r13d
  mov    $0x200,%eax
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
  mov    0x38(%rsp),%ebx
  test   %ebx,%ebx
  jle    L46
  mov    %ecx,%eax
  add    0x2c(%rsp),%eax
  cltq
  mov    0xa8(%rsp),%rdi
  lea    (%rdi,%rax,8),%r14
  mov    0x30(%rsp),%r12
  mov    0x18(%rsp),%rbp
  mov    %r13d,(%rsp)
  mov    0xa0(%rsp),%r13d
L9:
  mov    $0x20,%edx
  cmp    %edx,%ebx
  cmovle %ebx,%edx
  sub    $0x8,%rsp
  push   %r15
  push   %r14
  push   %r13
  mov    %r12,%r9
  mov    0x30(%rsp),%r8d
  mov    %rbp,%rcx
  mov    0x24(%rsp),%esi
  mov    0x20(%rsp),%edi
  mov    $0x0,%eax
  call   <Gemm_PJI@plt>
  sub    $0x20,%ebx
  add    0x28(%rsp),%rbp
  add    $0x100,%r12
  add    $0x20,%rsp
  cmp    0x14(%rsp),%ebx
  jne    L9
L46:
  addl   $0x200,0x20(%rsp)
  mov    0x20(%rsp),%eax
  addq   $0x1000,0x18(%rsp)
  cmp    0x28(%rsp),%eax
  jne    L50
L34:
  subl   $0x200,0x3c(%rsp)
  mov    0x3c(%rsp),%eax
  mov    0x44(%rsp),%ecx
  add    %ecx,0x40(%rsp)
  mov    0x48(%rsp),%edi
  add    %edi,0x2c(%rsp)
  cmp    0x4c(%rsp),%eax
  jne    L12
L40:
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j += 512) {
    int jb = ((n - j) < (512) ? (n - j) : (512));
    for (int i = 0; i < m; i += 512) {
      int ib = ((m - i) < (512) ? (m - i) : (512));
      for (int p = 0; p < k; p += 32) {
        int pb = ((k - p) < (32) ? (k - p) : (32));
        Gemm_PJI(ib, jb, pb, &A[(p)*ldA + (i)], ldA, &B[(j)*ldB + (p)], ldB, &C[(j)*ldC + (i)], ldC);
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<MyGemm>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %edi,0x30(%rsp)
  mov    %edx,0x34(%rsp)
  mov    %rcx,0x50(%rsp)
  mov    %r9,0x58(%rsp)
  test   %esi,%esi
  jle    L45
  test   %edi,%edi
  jle    L45
  mov    %edx,%esi
  test   %edx,%edx
  jle    L45
  lea    -0x200(%rax),%edx
  mov    %eax,0x38(%rsp)
  mov    0xb0(%rsp),%ecx
  sub    $0x1,%eax
  and    $0xfffffe00,%eax
  movl   $0x0,0x40(%rsp)
  mov    %r8d,%r13d
  sub    %eax,%edx
  shl    $0x9,%ecx
  mov    %r8d,%eax
  movl   $0x0,0x3c(%rsp)
  mov    %ecx,0x44(%rsp)
  shl    $0x5,%eax
  mov    0xa0(%rsp),%ecx
  cltq
  mov    %edx,0x4c(%rsp)
  lea    -0x1(%rdi),%edx
  shl    $0x9,%ecx
  shl    $0x3,%rax
  and    $0xfffffe00,%edx
  mov    %ecx,0x48(%rsp)
  lea    -0x20(%rsi),%ecx
  lea    0x200(%rdx),%edi
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rsi),%eax
  mov    %ecx,%edx
  and    $0xffffffe0,%eax
  mov    %edi,0x2c(%rsp)
  sub    %eax,%edx
  mov    %edx,0xc(%rsp)
  nopl   0x0(%rax)
L9:
  mov    0x38(%rsp),%eax
  mov    $0x200,%r14d
  mov    0xa8(%rsp),%rcx
  movl   $0x0,0x28(%rsp)
  cmp    %r14d,%eax
  cmovle %eax,%r14d
  mov    0x50(%rsp),%rax
  mov    %rax,0x18(%rsp)
  movslq 0x3c(%rsp),%rax
  lea    (%rcx,%rax,8),%rax
  mov    0x58(%rsp),%rcx
  mov    %rax,(%rsp)
  movslq 0x40(%rsp),%rax
  lea    (%rcx,%rax,8),%rax
  mov    %rax,0x20(%rsp)
  nopl   0x0(%rax,%rax,1)
L59:
  mov    $0x200,%eax
  mov    0x30(%rsp),%r12d
  sub    0x28(%rsp),%r12d
  mov    0x20(%rsp),%r15
  mov    0x18(%rsp),%rbp
  cmp    %eax,%r12d
  cmovg  %eax,%r12d
  mov    0x34(%rsp),%ebx
  mov    %r13d,%eax
  mov    %rbp,%r13
  mov    %r15,%rbp
  mov    %eax,%r15d
L23:
  mov    $0x20,%edx
  mov    %rbp,%r9
  mov    %r13,%rcx
  mov    %r15d,%r8d
  cmp    %edx,%ebx
  mov    %r14d,%esi
  mov    %r12d,%edi
  cmovle %ebx,%edx
  sub    $0x8,%rsp
  sub    $0x20,%ebx
  add    $0x100,%rbp
  mov    0xb8(%rsp),%eax
  push   %rax
  push   0x10(%rsp)
  mov    0xb8(%rsp),%eax
  push   %rax
  xor    %eax,%eax
  call   <Gemm_PJI@plt>
  add    0x30(%rsp),%r13
  add    $0x20,%rsp
  cmp    0xc(%rsp),%ebx
  jne    L23
  addl   $0x200,0x28(%rsp)
  mov    %r15d,%r13d
  mov    0x28(%rsp),%eax
  addq   $0x1000,0x18(%rsp)
  addq   $0x1000,(%rsp)
  cmp    0x2c(%rsp),%eax
  jne    L59
  subl   $0x200,0x38(%rsp)
  mov    0x44(%rsp),%esi
  mov    0x48(%rsp),%edi
  add    %esi,0x3c(%rsp)
  add    %edi,0x40(%rsp)
  mov    0x38(%rsp),%eax
  cmp    0x4c(%rsp),%eax
  jne    L9
L45:
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j += 512) {
    int jb = ((n - j) < (512) ? (n - j) : (512));
    for (int i = 0; i < m; i += 512) {
      int ib = ((m - i) < (512) ? (m - i) : (512));
      for (int p = 0; p < k; p += 32) {
        int pb = ((k - p) < (32) ? (k - p) : (32));
        Gemm_PJI(ib, jb, pb, &A[(p)*ldA + (i)], ldA, &B[(j)*ldB + (p)], ldB, &C[(j)*ldC + (i)], ldC);
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i = 0, j = 0;
  char c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L4
  cltq
  mov    $0x0,%edx
L16:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L16
L4:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i = 0, j = 0;
  char c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L13
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L5:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L5
L13:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i = 0, j = 0;
  char c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L4
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L8
L4:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i = 0, j = 0;
  char c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<opt_expmode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x1,%eax
  jmp    L34
L32:
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L36
  mov    $0x1,%eax
  jmp    L34
L36:
  mov    $0x0,%eax
L34:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D8
type: string

tool: D10: -e

tool: D8: --exponential

assistant: ```c
int opt_expmode(char *opt) {
  if (strcmp(opt, "-e") == 0)
    return 1;
  if (strcmp(opt, "--exponential") == 0)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<opt_expmode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L7
L3:
  pop    %rbx
  ret
L7:
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string
name: retrieve_data
arguments: tag: D4
data_type: string

tool: D9: -e

tool: D4: --exponential

assistant: ```c
int opt_expmode(char *opt) {
  if (strcmp(opt, "-e") == 0)
    return 1;
  if (strcmp(opt, "--exponential") == 0)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<opt_expmode>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L9
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  lea    D3(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D4: -e

tool: D3: --exponential

assistant: ```c
int opt_expmode(char *opt) {
  if (strcmp(opt, "-e") == 0)
    return 1;
  if (strcmp(opt, "--exponential") == 0)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<opt_expmode>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L3
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string
name: disassemble_data
arguments: data_tag: D11
data_type: string

tool: D8: -e

tool: D11: --exponential

assistant: ```c
int opt_expmode(char *opt) {
  if (strcmp(opt, "-e") == 0)
    return 1;
  if (strcmp(opt, "--exponential") == 0)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calcula_media>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x20(%rbp),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void calcula_media(float *media_aritmetica, int prov, int alu) {
  int j;
  for (j = 0; j < prov; j++) {
    media_aritmetica[j] = (media_aritmetica[j] / alu);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calcula_media>:
  endbr64
  test   %esi,%esi
  jle    L11
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rcx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
L12:
  movss  (%rax),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L12
L11:
  ret
```

assistant: ```c
void calcula_media(float *media_aritmetica, int prov, int alu) {
  int j;
  for (j = 0; j < prov; j++) {
    media_aritmetica[j] = (media_aritmetica[j] / alu);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calcula_media>:
  endbr64
  test   %esi,%esi
  jle    L1
  pxor   %xmm1,%xmm1
  lea    -0x1(%rsi),%eax
  cvtsi2ss %edx,%xmm1
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax,%rax,1)
L11:
  movss  (%rdi),%xmm0
  add    $0x4,%rdi
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rdi)
  cmp    %rax,%rdi
  jne    L11
L1:
  ret
```

assistant: ```c
void calcula_media(float *media_aritmetica, int prov, int alu) {
  int j;
  for (j = 0; j < prov; j++) {
    media_aritmetica[j] = (media_aritmetica[j] / alu);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calcula_media>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L40
  pxor   %xmm2,%xmm2
  lea    -0x1(%rsi),%eax
  cvtsi2ss %edx,%xmm2
  cmp    $0x2,%eax
  jbe    L57
  mov    %esi,%edx
  movaps %xmm2,%xmm1
  mov    %rdi,%rax
  shr    $0x2,%edx
  shufps $0x0,%xmm1,%xmm1
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   (%rax)
L3:
  movups (%rax),%xmm0
  add    $0x10,%rax
  divps  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L3
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%cl
  je     L36
L8:
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rsi
  movss  (%rsi),%xmm0
  divss  %xmm2,%xmm0
  movss  %xmm0,(%rsi)
  lea    0x1(%rax),%esi
  cmp    %esi,%ecx
  jle    L40
  lea    0x4(%rdi,%rdx,1),%rsi
  add    $0x2,%eax
  movss  (%rsi),%xmm0
  divss  %xmm2,%xmm0
  movss  %xmm0,(%rsi)
  cmp    %eax,%ecx
  jle    L40
  lea    0x8(%rdi,%rdx,1),%rax
  movss  (%rax),%xmm0
  divss  %xmm2,%xmm0
  movss  %xmm0,(%rax)
L40:
  ret
  nopl   (%rax)
L36:
  ret
L57:
  xor    %eax,%eax
  jmp    L8
```

assistant: ```c
void calcula_media(float *media_aritmetica, int prov, int alu) {
  int j;
  for (j = 0; j < prov; j++) {
    media_aritmetica[j] = (media_aritmetica[j] / alu);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fetch_knot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L88
  cmpl   $0x2,-0x4(%rbp)
  je     L78
  jmp    L38
L88:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L71
  pxor   %xmm0,%xmm0
  jmp    L41
L71:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L48
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L41
L48:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L41
L78:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x10(%rbp),%xmm0
  jmp    L41
L38:
  movsd  D7(%rip),%xmm0
L41:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: f64

tool: D7: 1

assistant: ```c
double fetch_knot(contr_kind, num_of_points, order, i)
int contr_kind, num_of_points, order, i;
{
  switch (contr_kind) {
  case 1:
    if (i <= order)
      return 0.0;
    else if (i <= num_of_points)
      return (double)(i - order);
    else
      return (double)(num_of_points - order);
  case 2:
    return (double)i;
  default:
    return 1.0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fetch_knot>:
  endbr64
  cmp    $0x1,%edi
  je     L37
  cmp    $0x2,%edi
  je     L21
  movsd  D0(%rip),%xmm0
  ret
L37:
  pxor   %xmm0,%xmm0
  cmp    %edx,%ecx
  jle    L13
  cmp    %esi,%ecx
  jg     L20
  sub    %edx,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  ret
L20:
  sub    %edx,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  ret
L21:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
L13:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: f64

tool: D0: 1

assistant: ```c
double fetch_knot(contr_kind, num_of_points, order, i)
int contr_kind, num_of_points, order, i;
{
  switch (contr_kind) {
  case 1:
    if (i <= order)
      return 0.0;
    else if (i <= num_of_points)
      return (double)(i - order);
    else
      return (double)(num_of_points - order);
  case 2:
    return (double)i;
  default:
    return 1.0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fetch_knot>:
  endbr64
  cmp    $0x1,%edi
  je     L15
  cmp    $0x2,%edi
  jne    L28
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
L38:
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  movsd  D9(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L15:
  pxor   %xmm0,%xmm0
  cmp    %edx,%ecx
  jle    L38
  cmp    %esi,%ecx
  jg     L35
  sub    %edx,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  sub    %edx,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: f64

tool: D9: 1

assistant: ```c
double fetch_knot(contr_kind, num_of_points, order, i)
int contr_kind, num_of_points, order, i;
{
  switch (contr_kind) {
  case 1:
    if (i <= order)
      return 0.0;
    else if (i <= num_of_points)
      return (double)(i - order);
    else
      return (double)(num_of_points - order);
  case 2:
    return (double)i;
  default:
    return 1.0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fetch_knot>:
  endbr64
  cmp    $0x1,%edi
  je     L15
  cmp    $0x2,%edi
  jne    L4
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
L14:
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movsd  D9(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L15:
  pxor   %xmm0,%xmm0
  cmp    %edx,%ecx
  jle    L14
  cmp    %esi,%ecx
  jg     L19
  sub    %edx,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  sub    %edx,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: f64

tool: D9: 1

assistant: ```c
double fetch_knot(contr_kind, num_of_points, order, i)
int contr_kind, num_of_points, order, i;
{
  switch (contr_kind) {
  case 1:
    if (i <= order)
      return 0.0;
    else if (i <= num_of_points)
      return (double)(i - order);
    else
      return (double)(num_of_points - order);
  case 2:
    return (double)i;
  default:
    return 1.0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<EVP_EncryptFinal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EVP_EncryptFinal_ex@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int EVP_EncryptFinal(EVP_CIPHER_CTX *ctx, unsigned char *out, int *outl) {
  int ret;
  ret = EVP_EncryptFinal_ex(ctx, out, outl);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<EVP_EncryptFinal>:
  endbr64
  sub    $0x8,%rsp
  call   <EVP_EncryptFinal_ex@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int EVP_EncryptFinal(EVP_CIPHER_CTX *ctx, unsigned char *out, int *outl) {
  int ret;
  ret = EVP_EncryptFinal_ex(ctx, out, outl);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<EVP_EncryptFinal>:
  endbr64
  jmp    1050 <EVP_EncryptFinal_ex@plt>
```

assistant: ```c
int EVP_EncryptFinal(EVP_CIPHER_CTX *ctx, unsigned char *out, int *outl) {
  int ret;
  ret = EVP_EncryptFinal_ex(ctx, out, outl);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EVP_EncryptFinal>:
  endbr64
  jmp    1050 <EVP_EncryptFinal_ex@plt>
```

assistant: ```c
int EVP_EncryptFinal(EVP_CIPHER_CTX *ctx, unsigned char *out, int *outl) {
  int ret;
  ret = EVP_EncryptFinal_ex(ctx, out, outl);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TtlUnmarshal_Blob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TtlUnmarshal_Blob(uint8_t **to, uint8_t **cursor, int size) {
  *to = *cursor;
  *cursor += size;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<TtlUnmarshal_Blob>:
  endbr64
  mov    (%rsi),%rax
  mov    %rax,(%rdi)
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void TtlUnmarshal_Blob(uint8_t **to, uint8_t **cursor, int size) {
  *to = *cursor;
  *cursor += size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TtlUnmarshal_Blob>:
  endbr64
  mov    (%rsi),%rax
  movslq %edx,%rdx
  mov    %rax,(%rdi)
  lea    (%rax,%rdx,4),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void TtlUnmarshal_Blob(uint8_t **to, uint8_t **cursor, int size) {
  *to = *cursor;
  *cursor += size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TtlUnmarshal_Blob>:
  endbr64
  mov    (%rsi),%rax
  movslq %edx,%rdx
  mov    %rax,(%rdi)
  lea    (%rax,%rdx,4),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void TtlUnmarshal_Blob(uint8_t **to, uint8_t **cursor, int size) {
  *to = *cursor;
  *cursor += size;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stack_pushfloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  movl   $0x80a9abc,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   *%rdx
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int stack_pushfloat(float ret) {
  int (*signature)(float);
  *((int *)(&signature)) = 0x080A9ABC;
  return signature(ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stack_pushfloat>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80a9abc,%eax
  call   *%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int stack_pushfloat(float ret) {
  int (*signature)(float);
  *((int *)(&signature)) = 0x080A9ABC;
  return signature(ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stack_pushfloat>:
  endbr64
  mov    $0x80a9abc,%eax
  jmp    *%rax
```

assistant: ```c
int stack_pushfloat(float ret) {
  int (*signature)(float);
  *((int *)(&signature)) = 0x080A9ABC;
  return signature(ret);
}
```