ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<tlsfGetMem>:
  endbr64
  sub    $0x18,%rsp
  lea    0xfff(%rdi),%rdx
  mov    $0x1000,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rdi
  call   <posix_memalign@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *(tlsfGetMem)(size_t bytes) {
  int error;
  void *ptr;
  size_t size;
  size = (bytes + (4096 - 1)) & ~(4096 - 1);
  error = posix_memalign(&ptr, 4096, size);
  if (error) {
    return NULL;
  }
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L29
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L35
  jmp    L31
L16:
  nop
L31:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  size_t len;
  for (len = 0; len < maxlen; len++, s++) {
    if (!*s)
      break;
  }
  return (len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L8
  mov    $0x0,%edx
L27:
  cmpb   $0x0,(%rdi,%rdx,1)
  je     L23
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L27
  ret
L23:
  mov    %rdx,%rax
L8:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  size_t len;
  for (len = 0; len < maxlen; len++, s++) {
    if (!*s)
      break;
  }
  return (len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L15
  xor    %edx,%edx
  jmp    L19
L17:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L5
L19:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L17
  mov    %rdx,%rax
L15:
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  size_t len;
  for (len = 0; len < maxlen; len++, s++) {
    if (!*s)
      break;
  }
  return (len);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L7
  xor    %edx,%edx
  jmp    L3
L25:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L19
L3:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L25
  mov    %rdx,%rax
L7:
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  size_t len;
  for (len = 0; len < maxlen; len++, s++) {
    if (!*s)
      break;
  }
  return (len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bufferedInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movb   $0x0,-0x45(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L50
L25:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x45(%rbp)
  mov    -0x44(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x44(%rbp)
  cltq
  movzbl -0x45(%rbp),%edx
  mov    %dl,-0x30(%rbp,%rax,1)
  mov    -0x44(%rbp),%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0xe,%eax
  jle    L50
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L81
  mov    -0x40(%rbp),%rax
  jmp    L68
L81:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  movb   $0x0,-0x30(%rbp)
  movl   $0x0,-0x44(%rbp)
L50:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <feof@plt>
  test   %eax,%eax
  jne    L55
  cmpb   $0xa,-0x45(%rbp)
  jne    L25
L55:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L59
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L90
  mov    -0x40(%rbp),%rax
  jmp    L68
L90:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L59:
  mov    -0x40(%rbp),%rax
L68:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L84
  call   <__stack_chk_fail@plt>
L84:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *bufferedInput() {
  char *input = calloc(1, 1);
  char *realloc_ptr = NULL;
  char buffer[16];
  char c = 0;
  int count = 0;
  while (!feof(stdin) && c != '\n') {
    c = getchar();
    buffer[count++] = c;
    buffer[count] = '\0';
    if (strlen(buffer) >= 16 - 1) {
      realloc_ptr = realloc(input, strlen(input) + strlen(buffer) + 1);
      if (!realloc_ptr)
        return input;
      input = realloc_ptr;
      strcat(input, buffer);
      buffer[0] = '\0';
      count = 0;
    }
  }
  if (strlen(buffer) > 0) {
    realloc_ptr = realloc(input, strlen(input) + strlen(buffer) + 1);
    if (!realloc_ptr)
      return input;
    input = realloc_ptr;
    strcat(input, buffer);
  }
  return input;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bufferedInput>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  mov    D7(%rip),%r13
  jmp    L82
L24:
  mov    %r14d,%ebp
L82:
  mov    0x0(%r13),%edi
  call   <feof@plt>
  cmp    $0xa,%bl
  je     L20
  test   %eax,%eax
  jne    L20
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  lea    0x1(%rbp),%r14d
  movslq %ebp,%rbp
  mov    %al,(%rsp,%rbp,1)
  movslq %r14d,%rax
  movb   $0x0,(%rsp,%rax,1)
  mov    %rsp,%rdi
  call   <strlen@plt>
  cmp    $0xe,%eax
  jle    L24
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rsp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L59
  mov    %rsp,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  movb   $0x0,(%rsp)
  mov    %rbp,%r12
  mov    $0x0,%r14d
  jmp    L24
L20:
  mov    %rsp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L93
L59:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %r12,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L93:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rsp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L59
  mov    %rsp,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rbx,%r12
  jmp    L59
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *bufferedInput() {
  char *input = calloc(1, 1);
  char *realloc_ptr = NULL;
  char buffer[16];
  char c = 0;
  int count = 0;
  while (!feof(stdin) && c != '\n') {
    c = getchar();
    buffer[count++] = c;
    buffer[count] = '\0';
    if (strlen(buffer) >= 16 - 1) {
      realloc_ptr = realloc(input, strlen(input) + strlen(buffer) + 1);
      if (!realloc_ptr)
        return input;
      input = realloc_ptr;
      strcat(input, buffer);
      buffer[0] = '\0';
      count = 0;
    }
  }
  if (strlen(buffer) > 0) {
    realloc_ptr = realloc(input, strlen(input) + strlen(buffer) + 1);
    if (!realloc_ptr)
      return input;
    input = realloc_ptr;
    strcat(input, buffer);
  }
  return input;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bufferedInput>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  mov    $0x1,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <calloc@plt>
  mov    D5(%rip),%r14
  mov    %rax,%r13
  jmp    L32
  nopl   0x0(%rax)
L81:
  movslq %r15d,%rbp
L32:
  mov    (%r14),%edi
  call   <feof@plt>
  cmp    $0xa,%bl
  je     L43
  test   %eax,%eax
  jne    L43
  xor    %eax,%eax
  lea    0x1(%rbp),%r15d
  call   <getchar@plt>
  mov    %r12,%rdi
  mov    %al,(%rsp,%rbp,1)
  mov    %eax,%ebx
  movslq %r15d,%rax
  movb   $0x0,(%rsp,%rax,1)
  call   <strlen@plt>
  cmp    $0xe,%eax
  jle    L81
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x1(%rbp,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L41
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rbp,%r13
  xor    %r15d,%r15d
  call   <strcat@plt>
  movb   $0x0,(%rsp)
  jmp    L81
  nopl   (%rax)
L43:
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L42
L41:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L42:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x1(%rbx,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L41
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rbx,%r13
  call   <strcat@plt>
  jmp    L41
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *bufferedInput() {
  char *input = calloc(1, 1);
  char *realloc_ptr = NULL;
  char buffer[16];
  char c = 0;
  int count = 0;
  while (!feof(stdin) && c != '\n') {
    c = getchar();
    buffer[count++] = c;
    buffer[count] = '\0';
    if (strlen(buffer) >= 16 - 1) {
      realloc_ptr = realloc(input, strlen(input) + strlen(buffer) + 1);
      if (!realloc_ptr)
        return input;
      input = realloc_ptr;
      strcat(input, buffer);
      buffer[0] = '\0';
      count = 0;
    }
  }
  if (strlen(buffer) > 0) {
    realloc_ptr = realloc(input, strlen(input) + strlen(buffer) + 1);
    if (!realloc_ptr)
      return input;
    input = realloc_ptr;
    strcat(input, buffer);
  }
  return input;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bufferedInput>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  mov    $0x1,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <calloc@plt>
  mov    D3(%rip),%r14
  mov    %rax,%r13
  jmp    L50
  nopl   0x0(%rax)
L47:
  movslq %r15d,%rbp
L50:
  mov    (%r14),%edi
  call   <feof@plt>
  cmp    $0xa,%bl
  je     L7
  test   %eax,%eax
  jne    L7
  xor    %eax,%eax
  lea    0x1(%rbp),%r15d
  call   <getchar@plt>
  mov    %r12,%rdi
  mov    %al,(%rsp,%rbp,1)
  mov    %eax,%ebx
  movslq %r15d,%rax
  movb   $0x0,(%rsp,%rax,1)
  call   <strlen@plt>
  cmp    $0xe,%eax
  jle    L47
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x1(%rbp,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L67
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rbp,%r13
  xor    %r15d,%r15d
  call   <strcat@plt>
  movb   $0x0,(%rsp)
  jmp    L47
  nopl   (%rax)
L7:
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L79
L67:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L79:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x1(%rbx,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L67
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rbx,%r13
  call   <strcat@plt>
  jmp    L67
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *bufferedInput() {
  char *input = calloc(1, 1);
  char *realloc_ptr = NULL;
  char buffer[16];
  char c = 0;
  int count = 0;
  while (!feof(stdin) && c != '\n') {
    c = getchar();
    buffer[count++] = c;
    buffer[count] = '\0';
    if (strlen(buffer) >= 16 - 1) {
      realloc_ptr = realloc(input, strlen(input) + strlen(buffer) + 1);
      if (!realloc_ptr)
        return input;
      input = realloc_ptr;
      strcat(input, buffer);
      buffer[0] = '\0';
      count = 0;
    }
  }
  if (strlen(buffer) > 0) {
    realloc_ptr = realloc(input, strlen(input) + strlen(buffer) + 1);
    if (!realloc_ptr)
      return input;
    input = realloc_ptr;
    strcat(input, buffer);
  }
  return input;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L18
  mov    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  jmp    L14
L18:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
unsigned int read_random() {
  FILE *fp = NULL;
  unsigned int r;
  if (fp != NULL) {
    fread(&r, 1, sizeof(r), fp);
    fclose(fp);
  } else {
    r = time(NULL);
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_random>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int read_random() {
  FILE *fp = NULL;
  unsigned int r;
  if (fp != NULL) {
    fread(&r, 1, sizeof(r), fp);
    fclose(fp);
  } else {
    r = time(NULL);
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_random>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <time@plt>
```

assistant: ```c
unsigned int read_random() {
  FILE *fp = NULL;
  unsigned int r;
  if (fp != NULL) {
    fread(&r, 1, sizeof(r), fp);
    fclose(fp);
  } else {
    r = time(NULL);
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_random>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <time@plt>
```

assistant: ```c
unsigned int read_random() {
  FILE *fp = NULL;
  unsigned int r;
  if (fp != NULL) {
    fread(&r, 1, sizeof(r), fp);
    fclose(fp);
  } else {
    r = time(NULL);
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<clGetDeviceIDs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x3ea,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
cl_int clGetDeviceIDs(cl_platform_id platform, cl_device_type device_type, cl_uint num_entries, cl_device_id *devices, cl_uint *num_devices) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)platform;
  sys_args[1] = (unsigned int)device_type;
  sys_args[2] = (unsigned int)num_entries;
  sys_args[3] = (unsigned int)devices;
  sys_args[4] = (unsigned int)num_devices;
  return (cl_int)syscall(325, 1002, sys_args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clGetDeviceIDs>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %rsp,%rdx
  mov    $0x3ea,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetDeviceIDs(cl_platform_id platform, cl_device_type device_type, cl_uint num_entries, cl_device_id *devices, cl_uint *num_devices) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)platform;
  sys_args[1] = (unsigned int)device_type;
  sys_args[2] = (unsigned int)num_entries;
  sys_args[3] = (unsigned int)devices;
  sys_args[4] = (unsigned int)num_devices;
  return (cl_int)syscall(325, 1002, sys_args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clGetDeviceIDs>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    $0x145,%edi
  mov    %esi,0x4(%rsp)
  mov    $0x3ea,%esi
  mov    %edx,0x8(%rsp)
  mov    %rsp,%rdx
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetDeviceIDs(cl_platform_id platform, cl_device_type device_type, cl_uint num_entries, cl_device_id *devices, cl_uint *num_devices) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)platform;
  sys_args[1] = (unsigned int)device_type;
  sys_args[2] = (unsigned int)num_entries;
  sys_args[3] = (unsigned int)devices;
  sys_args[4] = (unsigned int)num_devices;
  return (cl_int)syscall(325, 1002, sys_args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clGetDeviceIDs>:
  endbr64
  sub    $0x28,%rsp
  movq   %rdi,%xmm0
  movq   %rsi,%xmm2
  mov    $0x145,%edi
  movq   %rdx,%xmm1
  movq   %rcx,%xmm3
  punpcklqdq %xmm2,%xmm0
  mov    %rsp,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  punpcklqdq %xmm3,%xmm1
  mov    $0x3ea,%esi
  mov    %r8d,0x10(%rsp)
  shufps $0x88,%xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetDeviceIDs(cl_platform_id platform, cl_device_type device_type, cl_uint num_entries, cl_device_id *devices, cl_uint *num_devices) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)platform;
  sys_args[1] = (unsigned int)device_type;
  sys_args[2] = (unsigned int)num_entries;
  sys_args[3] = (unsigned int)devices;
  sys_args[4] = (unsigned int)num_devices;
  return (cl_int)syscall(325, 1002, sys_args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fgetw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L2:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0xa(%rbp,%rdx,1)
  addl   $0x1,-0x1c(%rbp)
L18:
  cmpl   $0x1,-0x1c(%rbp)
  jle    L2
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int fgetw(FILE *fp) {
  int i, *p;
  char a[2];
  p = (int *)a;
  for (i = 0; i < 2; i++)
    a[i] = fgetc(fp);
  return *p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fgetw>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  call   <fgetc@plt>
  mov    $0x0,%ebp
  mov    %al,%bpl
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %ebp,%edx
  mov    %al,%dh
  mov    %dx,0xe(%rsp)
  mov    0xe(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fgetw(FILE *fp) {
  int i, *p;
  char a[2];
  p = (int *)a;
  for (i = 0; i < 2; i++)
    a[i] = fgetc(fp);
  return *p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fgetw>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %al,%bl
  call   <fgetc@plt>
  mov    %al,%bh
  mov    %bx,0xe(%rsp)
  mov    0xe(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fgetw(FILE *fp) {
  int i, *p;
  char a[2];
  p = (int *)a;
  for (i = 0; i < 2; i++)
    a[i] = fgetc(fp);
  return *p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fgetw>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %al,%bl
  call   <fgetc@plt>
  mov    %al,%bh
  mov    %bx,0xe(%rsp)
  mov    0xe(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fgetw(FILE *fp) {
  int i, *p;
  char a[2];
  p = (int *)a;
  for (i = 0; i < 2; i++)
    a[i] = fgetc(fp);
  return *p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xstrdupn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L6:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *xstrdupn(const char *str, size_t len) {
  char *res = 0;
  if (str != 0) {
    size_t cnt = strnlen(str, len);
    res = xmalloc(cnt + 1);
    memcpy(res, str, cnt);
    res[cnt] = 0;
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xstrdupn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L7
  mov    %rdi,%rbx
  call   <strnlen@plt>
  mov    %rax,%r12
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%r12,1)
L7:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *xstrdupn(const char *str, size_t len) {
  char *res = 0;
  if (str != 0) {
    size_t cnt = strnlen(str, len);
    res = xmalloc(cnt + 1);
    memcpy(res, str, cnt);
    res[cnt] = 0;
  }
  return res;
}
```