ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_fls>:
  endbr64
  test   %edi,%edi
  je     L32
  mov    $0x1f,%eax
  test   $0xffff0000,%edi
  jne    L41
  shl    $0x10,%edi
  mov    $0xf,%eax
L41:
  test   $0xff000000,%edi
  jne    L15
  shl    $0x8,%edi
  sub    $0x8,%eax
L15:
  test   $0xf0000000,%edi
  jne    L44
  shl    $0x4,%edi
  sub    $0x4,%eax
L44:
  test   $0xc0000000,%edi
  jne    L5
  shl    $0x2,%edi
  sub    $0x2,%eax
L5:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
  ret
L32:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fls(int x) {
  int r = 31;
  if (!x)
    return -1;
  if (!(x & 0xffff0000)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<_fls>:
  endbr64
  test   %edi,%edi
  je     L9
  mov    $0x1f,%eax
  test   $0xffff0000,%edi
  jne    L31
  shl    $0x10,%edi
  mov    $0xf,%eax
L31:
  test   $0xff000000,%edi
  jne    L22
  shl    $0x8,%edi
  sub    $0x8,%eax
L22:
  test   $0xf0000000,%edi
  jne    L37
  shl    $0x4,%edi
  sub    $0x4,%eax
L37:
  test   $0xc0000000,%edi
  jne    L47
  shl    $0x2,%edi
  sub    $0x2,%eax
L47:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
  ret
  nopl   0x0(%rax)
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fls(int x) {
  int r = 31;
  if (!x)
    return -1;
  if (!(x & 0xffff0000)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_fls>:
  endbr64
  test   %edi,%edi
  je     L52
  test   $0xffff0000,%edi
  je     L44
  mov    $0x17,%edx
  mov    $0x1f,%eax
L37:
  test   $0xff000000,%edi
  jne    L50
  shl    $0x8,%edi
  mov    %edx,%eax
L50:
  test   $0xf0000000,%edi
  jne    L55
  shl    $0x4,%edi
  sub    $0x4,%eax
L55:
  test   $0xc0000000,%edi
  jne    L51
  shl    $0x2,%edi
  sub    $0x2,%eax
L51:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
  ret
  nopl   (%rax)
L44:
  shl    $0x10,%edi
  mov    $0x7,%edx
  mov    $0xf,%eax
  jmp    L37
  nop
L52:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fls(int x) {
  int r = 31;
  if (!x)
    return -1;
  if (!(x & 0xffff0000)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pclmul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: PCMUL is not supported.

assistant: ```c
int pclmul() {
  printf("PCMUL is not supported.");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pclmul>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: PCMUL is not supported.

assistant: ```c
int pclmul() {
  printf("PCMUL is not supported.");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pclmul>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: PCMUL is not supported.

assistant: ```c
int pclmul() {
  printf("PCMUL is not supported.");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pclmul>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: PCMUL is not supported.

assistant: ```c
int pclmul() {
  printf("PCMUL is not supported.");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <run_test@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  run_test();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <run_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  run_test();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  run_test();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  run_test();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sumMinorDiagonal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sumMinorDiagonal(int **m, int sz) {
  int i, sum;
  sum = 0;
  for (i = 0; i < sz; i++)
    sum += m[i][sz - i - 1];
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sumMinorDiagonal>:
  endbr64
  test   %esi,%esi
  jle    L28
  movslq %esi,%rdx
  lea    -0x4(,%rdx,4),%rax
  lea    -0x1(%rsi),%ecx
  sub    %rcx,%rdx
  lea    -0x8(,%rdx,4),%rsi
  mov    $0x0,%edx
L6:
  mov    (%rdi),%rcx
  add    (%rcx,%rax,1),%edx
  add    $0x8,%rdi
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L6
L0:
  mov    %edx,%eax
  ret
L28:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
int sumMinorDiagonal(int **m, int sz) {
  int i, sum;
  sum = 0;
  for (i = 0; i < sz; i++)
    sum += m[i][sz - i - 1];
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sumMinorDiagonal>:
  endbr64
  test   %esi,%esi
  jle    L15
  movslq %esi,%rdx
  lea    -0x1(%rsi),%ecx
  xor    %r8d,%r8d
  lea    -0x4(,%rdx,4),%rax
  sub    %rcx,%rdx
  lea    -0x8(,%rdx,4),%rcx
  nopl   0x0(%rax)
L18:
  mov    (%rdi),%rdx
  add    $0x8,%rdi
  add    (%rdx,%rax,1),%r8d
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L18
  mov    %r8d,%eax
  ret
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sumMinorDiagonal(int **m, int sz) {
  int i, sum;
  sum = 0;
  for (i = 0; i < sz; i++)
    sum += m[i][sz - i - 1];
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sumMinorDiagonal>:
  endbr64
  test   %esi,%esi
  jle    L17
  movslq %esi,%rdx
  lea    -0x1(%rsi),%ecx
  xor    %r8d,%r8d
  lea    -0x4(,%rdx,4),%rax
  sub    %rcx,%rdx
  lea    -0x8(,%rdx,4),%rcx
  nopl   0x0(%rax)
L19:
  mov    (%rdi),%rdx
  add    $0x8,%rdi
  add    (%rdx,%rax,1),%r8d
  sub    $0x4,%rax
  cmp    %rax,%rcx
  jne    L19
  mov    %r8d,%eax
  ret
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sumMinorDiagonal(int **m, int sz) {
  int i, sum;
  sum = 0;
  for (i = 0; i < sz; i++)
    sum += m[i][sz - i - 1];
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<identity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rcx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   *%rcx
  nop
  leave
  ret
```

assistant: ```c
void identity(char *pass, int cnt, void **nxt_f) {
  void (*func)(char *pass, int cnt, void **nxt_f) = *nxt_f;
  func(pass, 0, nxt_f + 1);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<identity>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rax
  lea    0x8(%rdx),%rdx
  mov    $0x0,%esi
  call   *(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void identity(char *pass, int cnt, void **nxt_f) {
  void (*func)(char *pass, int cnt, void **nxt_f) = *nxt_f;
  func(pass, 0, nxt_f + 1);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<identity>:
  endbr64
  lea    0x8(%rdx),%r8
  mov    (%rdx),%rax
  xor    %esi,%esi
  mov    %r8,%rdx
  jmp    *%rax
```

assistant: ```c
void identity(char *pass, int cnt, void **nxt_f) {
  void (*func)(char *pass, int cnt, void **nxt_f) = *nxt_f;
  func(pass, 0, nxt_f + 1);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<identity>:
  endbr64
  lea    0x8(%rdx),%r8
  mov    (%rdx),%rax
  xor    %esi,%esi
  mov    %r8,%rdx
  jmp    *%rax
```

assistant: ```c
void identity(char *pass, int cnt, void **nxt_f) {
  void (*func)(char *pass, int cnt, void **nxt_f) = *nxt_f;
  func(pass, 0, nxt_f + 1);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gpc_getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L29
L26:
  addq   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L26
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L26
  movl   $0x0,-0x14(%rbp)
  jmp    L55
L40:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L55:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  je     L42
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
L42:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *gpc_getop(char *s) {
  char *str = (char *)malloc(4096);
  int i;
  char *p = s;
  for (; *p == ' ' || *p == 0x09; p++)
    ;
  for (i = 0; *p != '(' && *p; p++, i++) {
    str[i] = *p;
  }
  str[i] = 0;
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gpc_getop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1000,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  cmp    $0x20,%dl
  je     L4
  cmp    $0x9,%dl
  jne    L3
L4:
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  cmp    $0x20,%dl
  je     L4
  cmp    $0x9,%dl
  je     L4
L3:
  movzbl (%rbx),%ecx
  cmp    $0x28,%cl
  je     L84
  test   %cl,%cl
  je     L84
  mov    $0x1,%edx
L51:
  mov    %cl,-0x1(%rax,%rdx,1)
  mov    %edx,%esi
  movzbl (%rbx,%rdx,1),%ecx
  add    $0x1,%rdx
  cmp    $0x28,%cl
  je     L87
  test   %cl,%cl
  jne    L51
L87:
  movslq %esi,%rsi
  movb   $0x0,(%rax,%rsi,1)
  pop    %rbx
  ret
L84:
  mov    $0x0,%esi
  jmp    L87
```

assistant: ```c
char *gpc_getop(char *s) {
  char *str = (char *)malloc(4096);
  int i;
  char *p = s;
  for (; *p == ' ' || *p == 0x09; p++)
    ;
  for (i = 0; *p != '(' && *p; p++, i++) {
    str[i] = *p;
  }
  str[i] = 0;
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gpc_getop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1000,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  cmp    $0x20,%dl
  jne    L21
  nopw   0x0(%rax,%rax,1)
L39:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    $0x20,%dl
  je     L39
L21:
  cmp    $0x9,%dl
  je     L39
  test   %dl,%dl
  je     L62
  cmp    $0x28,%dl
  je     L62
  mov    $0x1,%ecx
L7:
  mov    %dl,-0x1(%rax,%rcx,1)
  movzbl (%rbx,%rcx,1),%edx
  movslq %ecx,%rsi
  add    $0x1,%rcx
  cmp    $0x28,%dl
  je     L65
  test   %dl,%dl
  jne    L7
L65:
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  ret
L62:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  ret
```

assistant: ```c
char *gpc_getop(char *s) {
  char *str = (char *)malloc(4096);
  int i;
  char *p = s;
  for (; *p == ' ' || *p == 0x09; p++)
    ;
  for (i = 0; *p != '(' && *p; p++, i++) {
    str[i] = *p;
  }
  str[i] = 0;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gpc_getop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1000,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  cmp    $0x20,%dl
  jne    L7
  nopw   0x0(%rax,%rax,1)
L37:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    $0x20,%dl
  je     L37
L7:
  cmp    $0x9,%dl
  je     L37
  test   %dl,%dl
  je     L68
  cmp    $0x28,%dl
  je     L68
  mov    $0x1,%ecx
L34:
  mov    %dl,-0x1(%rax,%rcx,1)
  movzbl (%rbx,%rcx,1),%edx
  movslq %ecx,%rsi
  add    $0x1,%rcx
  cmp    $0x28,%dl
  je     L19
  test   %dl,%dl
  jne    L34
L19:
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  ret
L68:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  ret
```

assistant: ```c
char *gpc_getop(char *s) {
  char *str = (char *)malloc(4096);
  int i;
  char *p = s;
  for (; *p == ' ' || *p == 0x09; p++)
    ;
  for (i = 0; *p != '(' && *p; p++, i++) {
    str[i] = *p;
  }
  str[i] = 0;
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<l_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L10
L29:
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
L9:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  leave
  ret
```

assistant: ```c
char *l_trim(char *szOutput, const char *szInput) {
  assert(szInput != NULL);
  assert(szOutput != NULL);
  assert(szOutput != szInput);
  for (NULL; *szInput != '\0' && isspace(*szInput); ++szInput) {
    ;
  }
  return strcpy(szOutput, szInput);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<l_trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %rbp,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L19
L13:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L19
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L13
L19:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *l_trim(char *szOutput, const char *szInput) {
  assert(szInput != NULL);
  assert(szOutput != NULL);
  assert(szOutput != szInput);
  for (NULL; *szInput != '\0' && isspace(*szInput); ++szInput) {
    ;
  }
  return strcpy(szOutput, szInput);
}
```
user: Translate the below assembly code into C programming language:

```asm
<l_trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r12,%rbp
  setne  %dil
  call   <assert@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L6
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L29:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L17
L6:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
L17:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *l_trim(char *szOutput, const char *szInput) {
  assert(szInput != NULL);
  assert(szOutput != NULL);
  assert(szOutput != szInput);
  for (NULL; *szInput != '\0' && isspace(*szInput); ++szInput) {
    ;
  }
  return strcpy(szOutput, szInput);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<l_trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r12,%rbp
  setne  %dil
  call   <assert@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L9
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L12:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L3
L9:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
L3:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *l_trim(char *szOutput, const char *szInput) {
  assert(szInput != NULL);
  assert(szOutput != NULL);
  assert(szOutput != szInput);
  for (NULL; *szInput != '\0' && isspace(*szInput); ++szInput) {
    ;
  }
  return strcpy(szOutput, szInput);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsscanf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sscanf(const char *source, const char *format, ...) {
  int count;
  va_list vl;
  va_start(vl, format);
  count = vsscanf(source, format, vl);
  va_end(vl);
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sscanf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsscanf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sscanf(const char *source, const char *format, ...) {
  int count;
  va_list vl;
  va_start(vl, format);
  count = vsscanf(source, format, vl);
  va_end(vl);
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sscanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sscanf(const char *source, const char *format, ...) {
  int count;
  va_list vl;
  va_start(vl, format);
  count = vsscanf(source, format, vl);
  va_end(vl);
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<sscanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sscanf(const char *source, const char *format, ...) {
  int count;
  va_list vl;
  va_start(vl, format);
  count = vsscanf(source, format, vl);
  va_end(vl);
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DPMI_LockMemoryRegion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <DPMI_LockMemory@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int DPMI_LockMemoryRegion(void *start, void *end) {
  int status;
  status = DPMI_LockMemory(start, (char *)end - (char *)start);
  return (status);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DPMI_LockMemoryRegion>:
  endbr64
  sub    $0x8,%rsp
  sub    %edi,%esi
  call   <DPMI_LockMemory@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int DPMI_LockMemoryRegion(void *start, void *end) {
  int status;
  status = DPMI_LockMemory(start, (char *)end - (char *)start);
  return (status);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<DPMI_LockMemoryRegion>:
  endbr64
  sub    %edi,%esi
  jmp    1050 <DPMI_LockMemory@plt>
```

assistant: ```c
int DPMI_LockMemoryRegion(void *start, void *end) {
  int status;
  status = DPMI_LockMemory(start, (char *)end - (char *)start);
  return (status);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DPMI_LockMemoryRegion>:
  endbr64
  sub    %edi,%esi
  jmp    1050 <DPMI_LockMemory@plt>
```

assistant: ```c
int DPMI_LockMemoryRegion(void *start, void *end) {
  int status;
  status = DPMI_LockMemory(start, (char *)end - (char *)start);
  return (status);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<show_plot_points>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %5d %10.5f %10.5f


assistant: ```c
void show_plot_points(int n, double rr[], double tt[]) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%5d %10.5f %10.5f\n", i, rr[i], tt[i]);
  }
}
```