ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<textureInvertRBAndRemoveAlphaChannel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L8
L12:
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  lea    0x2(%rax),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void textureInvertRBAndRemoveAlphaChannel(char *bufdest, unsigned long destsize, char *bufsrc, unsigned long srcsize) {
  unsigned long i = 0, j = 0, k = srcsize / 4;
  for (i = 0; i < k; i++) {
    bufdest[j++] = bufsrc[4 * i + 2];
    bufdest[j++] = bufsrc[4 * i + 1];
    bufdest[j++] = bufsrc[4 * i];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<textureInvertRBAndRemoveAlphaChannel>:
  endbr64
  mov    %rcx,%rsi
  shr    $0x2,%rsi
  cmp    $0x3,%rcx
  jbe    L8
  mov    $0x0,%eax
L2:
  movzbl 0x2(%rdx,%rax,4),%ecx
  mov    %cl,(%rdi)
  movzbl 0x1(%rdx,%rax,4),%ecx
  mov    %cl,0x1(%rdi)
  movzbl (%rdx,%rax,4),%ecx
  mov    %cl,0x2(%rdi)
  add    $0x1,%rax
  add    $0x3,%rdi
  cmp    %rax,%rsi
  ja     L2
L8:
  ret
```

assistant: ```c
void textureInvertRBAndRemoveAlphaChannel(char *bufdest, unsigned long destsize, char *bufsrc, unsigned long srcsize) {
  unsigned long i = 0, j = 0, k = srcsize / 4;
  for (i = 0; i < k; i++) {
    bufdest[j++] = bufsrc[4 * i + 2];
    bufdest[j++] = bufsrc[4 * i + 1];
    bufdest[j++] = bufsrc[4 * i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<textureInvertRBAndRemoveAlphaChannel>:
  endbr64
  shr    $0x2,%rcx
  je     L11
  lea    (%rdx,%rcx,4),%rcx
  xchg   %ax,%ax
L10:
  movzbl 0x2(%rdx),%eax
  add    $0x4,%rdx
  add    $0x3,%rdi
  mov    %al,-0x3(%rdi)
  movzbl -0x3(%rdx),%eax
  mov    %al,-0x2(%rdi)
  movzbl -0x4(%rdx),%eax
  mov    %al,-0x1(%rdi)
  cmp    %rcx,%rdx
  jne    L10
L11:
  ret
```

assistant: ```c
void textureInvertRBAndRemoveAlphaChannel(char *bufdest, unsigned long destsize, char *bufsrc, unsigned long srcsize) {
  unsigned long i = 0, j = 0, k = srcsize / 4;
  for (i = 0; i < k; i++) {
    bufdest[j++] = bufsrc[4 * i + 2];
    bufdest[j++] = bufsrc[4 * i + 1];
    bufdest[j++] = bufsrc[4 * i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<textureInvertRBAndRemoveAlphaChannel>:
  endbr64
  shr    $0x2,%rcx
  je     L11
  lea    (%rdx,%rcx,4),%rcx
  xchg   %ax,%ax
L8:
  movzbl 0x2(%rdx),%eax
  add    $0x4,%rdx
  add    $0x3,%rdi
  mov    %al,-0x3(%rdi)
  movzbl -0x3(%rdx),%eax
  mov    %al,-0x2(%rdi)
  movzbl -0x4(%rdx),%eax
  mov    %al,-0x1(%rdi)
  cmp    %rdx,%rcx
  jne    L8
L11:
  ret
```

assistant: ```c
void textureInvertRBAndRemoveAlphaChannel(char *bufdest, unsigned long destsize, char *bufsrc, unsigned long srcsize) {
  unsigned long i = 0, j = 0, k = srcsize / 4;
  for (i = 0; i < k; i++) {
    bufdest[j++] = bufsrc[4 * i + 2];
    bufdest[j++] = bufsrc[4 * i + 1];
    bufdest[j++] = bufsrc[4 * i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tpi_sld_postinc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x24,%edi
  call   <tpi_write@plt>
  mov    $0x0,%eax
  call   <tpi_read@plt>
  pop    %rbp
  ret
```

assistant: ```c
uint8_t tpi_sld_postinc(void) {
  tpi_write((0x24));
  return tpi_read();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tpi_sld_postinc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x24,%edi
  call   <tpi_write@plt>
  mov    $0x0,%eax
  call   <tpi_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t tpi_sld_postinc(void) {
  tpi_write((0x24));
  return tpi_read();
}
```
user: What is the c source code of the assembly code below:

```asm
<tpi_sld_postinc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x24,%edi
  call   <tpi_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <tpi_read@plt>
```

assistant: ```c
uint8_t tpi_sld_postinc(void) {
  tpi_write((0x24));
  return tpi_read();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tpi_sld_postinc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x24,%edi
  call   <tpi_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <tpi_read@plt>
```

assistant: ```c
uint8_t tpi_sld_postinc(void) {
  tpi_write((0x24));
  return tpi_read();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prompt_yn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L45
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L45:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L21
  mov    $0xffffffff,%eax
  jmp    L6
L21:
  cmpl   $0x79,-0x4(%rbp)
  je     L20
  cmpl   $0x59,-0x4(%rbp)
  jne    L44
L20:
  mov    $0x0,%eax
  jmp    L6
L44:
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int prompt_yn(const char *message) {
  if (message != NULL) {
    printf(message);
  }
  int answer = fgetc(stdin);
  if (answer < 0) {
    return -1;
  }
  if (answer == 'y' || answer == 'Y')
    return 0;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prompt_yn>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L4
  call   <printf@plt>
L4:
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <fgetc@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  js     L17
  and    $0xffffffdf,%eax
  cmp    $0x59,%eax
  setne  %dl
  movzbl %dl,%edx
L17:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int prompt_yn(const char *message) {
  if (message != NULL) {
    printf(message);
  }
  int answer = fgetc(stdin);
  if (answer < 0) {
    return -1;
  }
  if (answer == 'y' || answer == 'Y')
    return 0;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<prompt_yn>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L11
  call   <printf@plt>
L11:
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <fgetc@plt>
  mov    $0xffffffff,%r8d
  test   %eax,%eax
  js     L17
  and    $0xffffffdf,%eax
  xor    %r8d,%r8d
  cmp    $0x59,%eax
  setne  %r8b
L17:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int prompt_yn(const char *message) {
  if (message != NULL) {
    printf(message);
  }
  int answer = fgetc(stdin);
  if (answer < 0) {
    return -1;
  }
  if (answer == 'y' || answer == 'Y')
    return 0;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prompt_yn>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  call   <printf@plt>
L1:
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <fgetc@plt>
  mov    $0xffffffff,%r8d
  test   %eax,%eax
  js     L15
  and    $0xffffffdf,%eax
  xor    %r8d,%r8d
  cmp    $0x59,%eax
  setne  %r8b
L15:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int prompt_yn(const char *message) {
  if (message != NULL) {
    printf(message);
  }
  int answer = fgetc(stdin);
  if (answer < 0) {
    return -1;
  }
  if (answer == 'y' || answer == 'Y')
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sysapi_get_mtu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L31
  mov    $0xffffffff,%eax
  jmp    L49
L31:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strcpy@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x14(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L5
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L49
L5:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
int sysapi_get_mtu(char *ifname) {
  int ret;
  int fd;
  fd = socket(AF_INET, SOCK_DGRAM, 0);
  if (fd < 0)
    return -1;
  struct ifreq ifr;
  ifr.ifr_addr.sa_family = AF_INET;
  strcpy(ifr.ifr_name, ifname);
  ret = ioctl(fd, SIOCGIFMTU, &ifr);
  if (ret < 0) {
    close(fd);
    return -1;
  }
  close(fd);
  ret = ifr.ifr_mtu;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<sysapi_get_mtu>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    D24(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L13
  mov    %eax,%ebx
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    %rbp,%rsi
  mov    0x10(%rsp),%edi
  call   <strcpy@plt>
  lea    0xc(%rsp),%rdx
  mov    D27(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L16
  mov    %ebx,%edi
  call   <close@plt>
  mov    0xc(%rsp),%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L6
L13:
  mov    $0xffffffff,%eax
  jmp    L6
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sysapi_get_mtu(char *ifname) {
  int ret;
  int fd;
  fd = socket(AF_INET, SOCK_DGRAM, 0);
  if (fd < 0)
    return -1;
  struct ifreq ifr;
  ifr.ifr_addr.sa_family = AF_INET;
  strcpy(ifr.ifr_name, ifname);
  ret = ioctl(fd, SIOCGIFMTU, &ifr);
  if (ret < 0) {
    close(fd);
    return -1;
  }
  close(fd);
  ret = ifr.ifr_mtu;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<sysapi_get_mtu>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    D4(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  test   %eax,%eax
  js     L6
  mov    %eax,%ebp
  mov    0x10(%rsp),%edi
  mov    (%rbx),%eax
  mov    %r12,%rsi
  mov    %eax,0x14(%rsp)
  call   <strcpy@plt>
  mov    D7(%rip),%rax
  mov    %ebp,%edi
  lea    0xc(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %ebp,%edi
  test   %eax,%eax
  js     L27
  call   <close@plt>
  mov    0xc(%rsp),%eax
L11:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L6:
  mov    $0xffffffff,%eax
  jmp    L11
L27:
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L11
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sysapi_get_mtu(char *ifname) {
  int ret;
  int fd;
  fd = socket(AF_INET, SOCK_DGRAM, 0);
  if (fd < 0)
    return -1;
  struct ifreq ifr;
  ifr.ifr_addr.sa_family = AF_INET;
  strcpy(ifr.ifr_name, ifname);
  ret = ioctl(fd, SIOCGIFMTU, &ifr);
  if (ret < 0) {
    close(fd);
    return -1;
  }
  close(fd);
  ret = ifr.ifr_mtu;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sysapi_get_mtu>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    D1(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  test   %eax,%eax
  js     L25
  mov    %eax,%ebp
  mov    0x10(%rsp),%edi
  mov    (%rbx),%eax
  mov    %r12,%rsi
  mov    %eax,0x14(%rsp)
  call   <strcpy@plt>
  mov    D26(%rip),%rax
  mov    %ebp,%edi
  lea    0xc(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %ebp,%edi
  test   %eax,%eax
  js     L5
  call   <close@plt>
  mov    0xc(%rsp),%eax
L21:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L25:
  mov    $0xffffffff,%eax
  jmp    L21
L5:
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L21
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sysapi_get_mtu(char *ifname) {
  int ret;
  int fd;
  fd = socket(AF_INET, SOCK_DGRAM, 0);
  if (fd < 0)
    return -1;
  struct ifreq ifr;
  ifr.ifr_addr.sa_family = AF_INET;
  strcpy(ifr.ifr_name, ifname);
  ret = ioctl(fd, SIOCGIFMTU, &ifr);
  if (ret < 0) {
    close(fd);
    return -1;
  }
  close(fd);
  ret = ifr.ifr_mtu;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L5
L1:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L0
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L11
L0:
  mov    $0x1,%edi
  call   <interceptor_increaseBy@plt>
  addq   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L1
  mov    $0x5,%edi
  call   <interceptor_increaseBy@plt>
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
__attribute__((optimize("0"))) int __memcmp(const void *m1, const void *m2, size_t n) {
  const char *s1 = (const char *)m1;
  const char *s2 = (const char *)m2;
  for (size_t i = 0; i < n; i++) {
    if (s1[i] != s2[i]) {
      return (s1[i] - s2[i]);
    }
    interceptor_increaseBy(1);
  }
  interceptor_increaseBy(5);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L4
L27:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L26
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L36
L26:
  mov    $0x1,%edi
  call   <interceptor_increaseBy@plt>
  addq   $0x1,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L27
  mov    $0x5,%edi
  call   <interceptor_increaseBy@plt>
  mov    $0x0,%eax
L36:
  leave
  ret
```

assistant: ```c
__attribute__((optimize("0"))) int __memcmp(const void *m1, const void *m2, size_t n) {
  const char *s1 = (const char *)m1;
  const char *s2 = (const char *)m2;
  for (size_t i = 0; i < n; i++) {
    if (s1[i] != s2[i]) {
      return (s1[i] - s2[i]);
    }
    interceptor_increaseBy(1);
  }
  interceptor_increaseBy(5);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L14
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L11
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L38
L11:
  mov    $0x1,%edi
  call   <interceptor_increaseBy@plt>
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L2
  mov    $0x5,%edi
  call   <interceptor_increaseBy@plt>
  mov    $0x0,%eax
L38:
  leave
  ret
```

assistant: ```c
__attribute__((optimize("0"))) int __memcmp(const void *m1, const void *m2, size_t n) {
  const char *s1 = (const char *)m1;
  const char *s2 = (const char *)m2;
  for (size_t i = 0; i < n; i++) {
    if (s1[i] != s2[i]) {
      return (s1[i] - s2[i]);
    }
    interceptor_increaseBy(1);
  }
  interceptor_increaseBy(5);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<__memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L24
L27:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L4
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L17
L4:
  mov    $0x1,%edi
  call   <interceptor_increaseBy@plt>
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L27
  mov    $0x5,%edi
  call   <interceptor_increaseBy@plt>
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
__attribute__((optimize("0"))) int __memcmp(const void *m1, const void *m2, size_t n) {
  const char *s1 = (const char *)m1;
  const char *s2 = (const char *)m2;
  for (size_t i = 0; i < n; i++) {
    if (s1[i] != s2[i]) {
      return (s1[i] - s2[i]);
    }
    interceptor_increaseBy(1);
  }
  interceptor_increaseBy(5);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%eax
  mov    $0x0,%ecx
  imul   %rdx,%rax
  jno    L1
  mov    $0x1,%ecx
L1:
  mov    %rax,-0x10(%rbp)
  mov    %rcx,%rax
  and    $0x1,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int f4(int a, unsigned b) {
  long long c;
  return __builtin_mul_overflow(a, b, &c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f4>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int f4(int a, unsigned b) {
  long long c;
  return __builtin_mul_overflow(a, b, &c);
}
```
user: What is the c source code of the assembly code below?

```asm
<f4>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int f4(int a, unsigned b) {
  long long c;
  return __builtin_mul_overflow(a, b, &c);
}
```
user: What is the c source code of the assembly code below?

```asm
<crypto_stream_chacha20_tinynacl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x40(%rbp)
  jmp    L14
L13:
  mov    -0x40(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x30(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x40(%rbp)
L14:
  cmpq   $0x1f,-0x40(%rbp)
  jle    L13
  movq   $0x0,-0x40(%rbp)
  jmp    L40
L62:
  mov    -0x40(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x38(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x40(%rbp)
L40:
  cmpq   $0x7,-0x40(%rbp)
  jle    L62
  movq   $0x0,-0x40(%rbp)
  jmp    L42
L41:
  mov    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x40(%rbp)
L42:
  mov    -0x40(%rbp),%rax
  cmp    %rax,-0x50(%rbp)
  ja     L41
  lea    -0x30(%rbp),%rdi
  lea    -0x38(%rbp),%rcx
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <crypto_stream_chacha20_tinynacl_xor@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int crypto_stream_chacha20_tinynacl(unsigned char *c, unsigned long long l, const unsigned char *n, const unsigned char *k) {
  long long j;
  unsigned char ncopy[8], kcopy[32];
  for (j = 0; j < 32; ++j)
    kcopy[j] = k[j];
  for (j = 0; j < 8; ++j)
    ncopy[j] = n[j];
  for (j = 0; j < l; ++j)
    c[j] = 0;
  return crypto_stream_chacha20_tinynacl_xor(c, c, l, ncopy, kcopy);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<crypto_stream_chacha20_tinynacl>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
L14:
  movzbl (%rcx,%rax,1),%r8d
  mov    %r8b,0x10(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x20,%rax
  jne    L14
  mov    $0x0,%eax
L16:
  movzbl (%rdx,%rax,1),%ecx
  mov    %cl,0x8(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L16
  test   %rsi,%rsi
  je     L20
  mov    %rdi,%rax
  lea    (%rdi,%rsi,1),%rdx
L31:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L31
L20:
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%r8
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  call   <crypto_stream_chacha20_tinynacl_xor@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x48,%rsp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_stream_chacha20_tinynacl(unsigned char *c, unsigned long long l, const unsigned char *n, const unsigned char *k) {
  long long j;
  unsigned char ncopy[8], kcopy[32];
  for (j = 0; j < 32; ++j)
    kcopy[j] = k[j];
  for (j = 0; j < 8; ++j)
    ncopy[j] = n[j];
  for (j = 0; j < l; ++j)
    c[j] = 0;
  return crypto_stream_chacha20_tinynacl_xor(c, c, l, ncopy, kcopy);
}
```