ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L20
L8:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x0,-0x4(%rbp)
  je     L17
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L8
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L8
L17:
  nop
  leave
  ret
```

assistant: ```c
void chomp(char *s) {
  for (unsigned int len = strlen(s); len > 0 && (s[len - 1] == '\n' || s[len - 1] == '\r'); s[len - 1] = '\0', len--)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L21
  lea    -0x1(%rax),%eax
  add    %rbx,%rax
  jmp    L31
L2:
  movb   $0x0,(%rcx)
  lea    -0x1(%rax),%rdx
  cmp    %rbx,%rax
  je     L21
  mov    %rdx,%rax
L31:
  mov    %rax,%rcx
  movzbl (%rax),%edx
  cmp    $0xa,%dl
  je     L2
  cmp    $0xd,%dl
  je     L2
L21:
  pop    %rbx
  ret
```

assistant: ```c
void chomp(char *s) {
  for (unsigned int len = strlen(s); len > 0 && (s[len - 1] == '\n' || s[len - 1] == '\r'); s[len - 1] = '\0', len--)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L1
  sub    $0x1,%eax
  add    %rbx,%rax
  jmp    L13
  nopl   0x0(%rax)
L32:
  movb   $0x0,(%rax)
  lea    -0x1(%rax),%rdx
  cmp    %rbx,%rax
  je     L1
  mov    %rdx,%rax
L13:
  movzbl (%rax),%edx
  cmp    $0xa,%dl
  je     L32
  cmp    $0xd,%dl
  je     L32
L1:
  pop    %rbx
  ret
```

assistant: ```c
void chomp(char *s) {
  for (unsigned int len = strlen(s); len > 0 && (s[len - 1] == '\n' || s[len - 1] == '\r'); s[len - 1] = '\0', len--)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L37
  sub    $0x1,%eax
  add    %rbx,%rax
  jmp    L12
  nopl   0x0(%rax)
L10:
  movb   $0x0,(%rax)
  lea    -0x1(%rax),%rdx
  cmp    %rbx,%rax
  je     L37
  mov    %rdx,%rax
L12:
  movzbl (%rax),%edx
  cmp    $0xa,%dl
  je     L10
  cmp    $0xd,%dl
  je     L10
L37:
  pop    %rbx
  ret
```

assistant: ```c
void chomp(char *s) {
  for (unsigned int len = strlen(s); len > 0 && (s[len - 1] == '\n' || s[len - 1] == '\r'); s[len - 1] = '\0', len--)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timeConv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff91a2b3c5,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0xb,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xe10,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff91a2b3c5,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0xb,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xe10,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  imul   $0x3c,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 	%dH %dM %dS

assistant: ```c
void timeConv(int time) {
  int a, b, c;
  a = time / 3600;
  b = (time % 3600) / 60;
  c = (time % 3600) % 60;
  printf("\t%dH %dM %dS", a, b, c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<timeConv>:
  endbr64
  sub    $0x8,%rsp
  movslq %edi,%rsi
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  shr    $0x20,%rsi
  add    %edi,%esi
  sar    $0xb,%esi
  mov    %edi,%eax
  sar    $0x1f,%eax
  mov    %esi,%ecx
  sub    %eax,%ecx
  imul   $0xe10,%ecx,%edx
  mov    %edi,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x5,%edx
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  imul   $0x3c,%edx,%edi
  sub    %edi,%ecx
  sub    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: 	%dH %dM %dS

assistant: ```c
void timeConv(int time) {
  int a, b, c;
  a = time / 3600;
  b = (time % 3600) / 60;
  c = (time % 3600) % 60;
  printf("\t%dH %dM %dS", a, b, c);
}
```
user: What is the c source code of the assembly code below?

```asm
<timeConv>:
  endbr64
  movslq %edi,%rsi
  mov    %edi,%eax
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  sar    $0x1f,%eax
  shr    $0x20,%rsi
  add    %edi,%esi
  sar    $0xb,%esi
  mov    %esi,%ecx
  sub    %eax,%esi
  sub    %eax,%ecx
  imul   $0xe10,%ecx,%edx
  mov    %edi,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rdx
  mov    %ecx,%edi
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%edi
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x5,%edx
  sub    %edi,%edx
  imul   $0x3c,%edx,%edi
  sub    %edi,%ecx
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: 	%dH %dM %dS

assistant: ```c
void timeConv(int time) {
  int a, b, c;
  a = time / 3600;
  b = (time % 3600) / 60;
  c = (time % 3600) % 60;
  printf("\t%dH %dM %dS", a, b, c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<timeConv>:
  endbr64
  movslq %edi,%rsi
  mov    %edi,%eax
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  sar    $0x1f,%eax
  shr    $0x20,%rsi
  add    %edi,%esi
  sar    $0xb,%esi
  mov    %esi,%ecx
  sub    %eax,%esi
  sub    %eax,%ecx
  imul   $0xe10,%ecx,%edx
  mov    %edi,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rdx
  mov    %ecx,%edi
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%edi
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x5,%edx
  sub    %edi,%edx
  imul   $0x3c,%edx,%edi
  sub    %edi,%ecx
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: 	%dH %dM %dS

assistant: ```c
void timeConv(int time) {
  int a, b, c;
  a = time / 3600;
  b = (time % 3600) / 60;
  c = (time % 3600) % 60;
  printf("\t%dH %dM %dS", a, b, c);
}
```
user: What is the c source code of the assembly code below?

```asm
<DAC_Out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x400053fc,%eax
  mov    (%rax),%eax
  mov    $0x400053fc,%edx
  and    $0xfffffff0,%eax
  mov    %eax,(%rdx)
  mov    $0x400053fc,%eax
  mov    (%rax),%eax
  mov    $0x400053fc,%edx
  or     -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DAC_Out(uint32_t data) {
  (*((volatile uint32_t *)0x400053FC)) &= ~0x0F;
  (*((volatile uint32_t *)0x400053FC)) |= data;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<DAC_Out>:
  endbr64
  mov    0x400053fc,%eax
  and    $0xfffffff0,%eax
  mov    %eax,0x400053fc
  mov    0x400053fc,%eax
  or     %edi,%eax
  mov    %eax,0x400053fc
  ret
```

assistant: ```c
void DAC_Out(uint32_t data) {
  (*((volatile uint32_t *)0x400053FC)) &= ~0x0F;
  (*((volatile uint32_t *)0x400053FC)) |= data;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DAC_Out>:
  endbr64
  mov    0x400053fc,%eax
  and    $0xfffffff0,%eax
  mov    %eax,0x400053fc
  mov    0x400053fc,%eax
  or     %edi,%eax
  mov    %eax,0x400053fc
  ret
```

assistant: ```c
void DAC_Out(uint32_t data) {
  (*((volatile uint32_t *)0x400053FC)) &= ~0x0F;
  (*((volatile uint32_t *)0x400053FC)) |= data;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<DAC_Out>:
  endbr64
  mov    0x400053fc,%eax
  and    $0xfffffff0,%eax
  mov    %eax,0x400053fc
  mov    0x400053fc,%eax
  or     %edi,%eax
  mov    %eax,0x400053fc
  ret
```

assistant: ```c
void DAC_Out(uint32_t data) {
  (*((volatile uint32_t *)0x400053FC)) &= ~0x0F;
  (*((volatile uint32_t *)0x400053FC)) |= data;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vo_draw_alpha_rgb24_C>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9,-0x48(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L7:
  mov    -0x48(%rbp),%r12
  mov    $0x0,%ebx
  jmp    L48
L30:
  movslq %ebx,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L41
  movzbl (%r12),%eax
  movzbl %al,%edx
  movslq %ebx,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  movslq %ebx,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    %ecx,%eax
  mov    %al,(%r12)
  lea    0x1(%r12),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  movslq %ebx,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  movslq %ebx,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  lea    0x1(%r12),%rax
  add    %ecx,%edx
  mov    %dl,(%rax)
  lea    0x2(%r12),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  movslq %ebx,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  movslq %ebx,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  lea    0x2(%r12),%rax
  add    %ecx,%edx
  mov    %dl,(%rax)
L41:
  add    $0x3,%r12
  add    $0x1,%ebx
L48:
  cmp    -0x24(%rbp),%ebx
  jl     L30
  mov    -0x3c(%rbp),%eax
  cltq
  add    %rax,-0x30(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  add    %rax,-0x38(%rbp)
  mov    0x10(%rbp),%eax
  cltq
  add    %rax,-0x48(%rbp)
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L7
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void vo_draw_alpha_rgb24_C(int w, int h, unsigned char *src, unsigned char *srca, int srcstride, unsigned char *dstbase, int dststride) {
  int y;
  for (y = 0; y < h; y++) {
    register unsigned char *dst = dstbase;
    register int x;
    for (x = 0; x < w; x++) {
      if (srca[x]) {
        dst[0] = ((dst[0] * srca[x]) >> 8) + src[x];
        dst[1] = ((dst[1] * srca[x]) >> 8) + src[x];
        dst[2] = ((dst[2] * srca[x]) >> 8) + src[x];
      }
      dst += 3;
    }
    src += srcstride;
    srca += srcstride;
    dstbase += dststride;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vo_draw_alpha_rgb24_C>:
  endbr64
  test   %esi,%esi
  jle    L42
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r11d
  mov    %esi,%ebx
  mov    %rdx,%r10
  mov    %rcx,%rbp
  movslq 0x30(%rsp),%r13
  lea    -0x1(%rdi),%eax
  lea    0x3(%rax,%rax,2),%rdi
  add    %r9,%rdi
  mov    $0x0,%r12d
  movslq %r8d,%r8
  jmp    L58
L49:
  add    $0x3,%rax
  add    $0x1,%rdx
  add    $0x1,%rsi
  cmp    %rdi,%rax
  je     L75
L77:
  movzbl (%rdx),%r14d
  test   %r14b,%r14b
  je     L49
  movzbl (%rax),%ecx
  movzbl %r14b,%r14d
  imul   %r14d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,(%rax)
  movzbl 0x1(%rax),%ecx
  movzbl (%rdx),%r14d
  imul   %r14d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,0x1(%rax)
  movzbl 0x2(%rax),%ecx
  movzbl (%rdx),%r14d
  imul   %r14d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,0x2(%rax)
  jmp    L49
L75:
  add    %r8,%r10
  add    %r8,%rbp
  add    %r13,%r9
  add    $0x1,%r12d
  add    %r13,%rdi
  cmp    %r12d,%ebx
  je     L62
L58:
  mov    %rbp,%rdx
  mov    %r10,%rsi
  mov    %r9,%rax
  test   %r11d,%r11d
  jg     L77
  jmp    L75
L62:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  ret
```

assistant: ```c
void vo_draw_alpha_rgb24_C(int w, int h, unsigned char *src, unsigned char *srca, int srcstride, unsigned char *dstbase, int dststride) {
  int y;
  for (y = 0; y < h; y++) {
    register unsigned char *dst = dstbase;
    register int x;
    for (x = 0; x < w; x++) {
      if (srca[x]) {
        dst[0] = ((dst[0] * srca[x]) >> 8) + src[x];
        dst[1] = ((dst[1] * srca[x]) >> 8) + src[x];
        dst[2] = ((dst[2] * srca[x]) >> 8) + src[x];
      }
      dst += 3;
    }
    src += srcstride;
    srca += srcstride;
    dstbase += dststride;
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vo_draw_alpha_rgb24_C>:
  endbr64
  test   %esi,%esi
  jle    L44
  lea    -0x1(%rdi),%eax
  push   %r14
  mov    %edi,%r11d
  mov    %rdx,%r10
  push   %r13
  lea    0x3(%rax,%rax,2),%rdi
  push   %r12
  add    %r9,%rdi
  movslq %r8d,%r12
  xor    %r8d,%r8d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  movslq 0x30(%rsp),%r13
  mov    %esi,%ebx
  nopl   (%rax)
L33:
  mov    %rbp,%rdx
  mov    %r10,%rsi
  mov    %r9,%rax
  test   %r11d,%r11d
  jle    L46
  cs nopw 0x0(%rax,%rax,1)
L40:
  movzbl (%rdx),%r14d
  test   %r14b,%r14b
  je     L4
  movzbl (%rax),%ecx
  imul   %r14d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,(%rax)
  movzbl 0x1(%rax),%ecx
  movzbl (%rdx),%r14d
  imul   %r14d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,0x1(%rax)
  movzbl 0x2(%rax),%ecx
  movzbl (%rdx),%r14d
  imul   %r14d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,0x2(%rax)
L4:
  add    $0x3,%rax
  add    $0x1,%rdx
  add    $0x1,%rsi
  cmp    %rdi,%rax
  jne    L40
L46:
  add    $0x1,%r8d
  add    %r12,%r10
  add    %r12,%rbp
  add    %r13,%r9
  add    %r13,%rdi
  cmp    %r8d,%ebx
  jne    L33
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  ret
```

assistant: ```c
void vo_draw_alpha_rgb24_C(int w, int h, unsigned char *src, unsigned char *srca, int srcstride, unsigned char *dstbase, int dststride) {
  int y;
  for (y = 0; y < h; y++) {
    register unsigned char *dst = dstbase;
    register int x;
    for (x = 0; x < w; x++) {
      if (srca[x]) {
        dst[0] = ((dst[0] * srca[x]) >> 8) + src[x];
        dst[1] = ((dst[1] * srca[x]) >> 8) + src[x];
        dst[2] = ((dst[2] * srca[x]) >> 8) + src[x];
      }
      dst += 3;
    }
    src += srcstride;
    srca += srcstride;
    dstbase += dststride;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vo_draw_alpha_rgb24_C>:
  endbr64
  test   %esi,%esi
  jle    L37
  movslq %edi,%rax
  push   %r13
  push   %r12
  push   %rbp
  movslq %r8d,%rbp
  push   %rbx
  movslq 0x28(%rsp),%r12
  test   %eax,%eax
  jle    L15
  lea    (%rax,%rax,2),%rdi
  mov    %esi,%r11d
  mov    %rdx,%r10
  mov    %rcx,%rbx
  add    %r9,%rdi
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rdx
  mov    %r10,%rsi
  mov    %r9,%rax
  nopl   0x0(%rax)
L41:
  movzbl (%rdx),%r13d
  test   %r13b,%r13b
  je     L46
  movzbl (%rax),%ecx
  imul   %r13d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,(%rax)
  movzbl 0x1(%rax),%ecx
  movzbl (%rdx),%r13d
  imul   %r13d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,0x1(%rax)
  movzbl 0x2(%rax),%ecx
  movzbl (%rdx),%r13d
  imul   %r13d,%ecx
  sar    $0x8,%ecx
  add    (%rsi),%cl
  mov    %cl,0x2(%rax)
L46:
  add    $0x3,%rax
  add    $0x1,%rdx
  add    $0x1,%rsi
  cmp    %rdi,%rax
  jne    L41
  add    $0x1,%r8d
  add    %rbp,%r10
  add    %rbp,%rbx
  add    %r12,%r9
  add    %r12,%rdi
  cmp    %r8d,%r11d
  jne    L5
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  ret
```

assistant: ```c
void vo_draw_alpha_rgb24_C(int w, int h, unsigned char *src, unsigned char *srca, int srcstride, unsigned char *dstbase, int dststride) {
  int y;
  for (y = 0; y < h; y++) {
    register unsigned char *dst = dstbase;
    register int x;
    for (x = 0; x < w; x++) {
      if (srca[x]) {
        dst[0] = ((dst[0] * srca[x]) >> 8) + src[x];
        dst[1] = ((dst[1] * srca[x]) >> 8) + src[x];
        dst[2] = ((dst[2] * srca[x]) >> 8) + src[x];
      }
      dst += 3;
    }
    src += srcstride;
    srca += srcstride;
    dstbase += dststride;
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xa00,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L0:
  movl   $0x0,-0x10(%rbp)
  jmp    L10
L35:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  shl    $0x3,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %ecx,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  ja     L35
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  ja     L0
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <rowechelon@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  unsigned int size = 0xA00;
  float *matrix = (float *)malloc(sizeof(float) * size * size);
  int i, j;
  srand(size);
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      matrix[i * size + j] = (float)(rand() % 9);
    }
  }
  rowechelon(size, matrix);
  free(matrix);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1900000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0xa00,%edi
  call   <srand@plt>
  mov    $0xa00,%ebp
L11:
  lea    -0xa00(%rbp),%ebx
L7:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %ebx,%ecx
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,8),%edx
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%r12,%rcx,4)
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L7
  add    $0xa00,%ebp
  cmp    $0x640a00,%ebp
  jne    L11
  mov    %r12,%rsi
  mov    $0xa00,%edi
  call   <rowechelon@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  unsigned int size = 0xA00;
  float *matrix = (float *)malloc(sizeof(float) * size * size);
  int i, j;
  srand(size);
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      matrix[i * size + j] = (float)(rand() % 9);
    }
  }
  rowechelon(size, matrix);
  free(matrix);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1900000,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0xa00,%edi
  mov    %rax,%r12
  lea    0x2800(%r12),%rbx
  lea    0x1902800(%r12),%rbp
  call   <srand@plt>
  nopl   (%rax)
L8:
  lea    -0x2800(%rbx),%r13
  nop
L15:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x21,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,8),%edx
  sub    %edx,%eax
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%r13)
  cmp    %rbx,%r13
  jne    L15
  lea    0x2800(%r13),%rbx
  cmp    %rbp,%rbx
  jne    L8
  mov    %r12,%rsi
  mov    $0xa00,%edi
  call   <rowechelon@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  unsigned int size = 0xA00;
  float *matrix = (float *)malloc(sizeof(float) * size * size);
  int i, j;
  srand(size);
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      matrix[i * size + j] = (float)(rand() % 9);
    }
  }
  rowechelon(size, matrix);
  free(matrix);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1900000,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0xa00,%edi
  mov    %rax,%r12
  lea    0x2800(%r12),%rbx
  lea    0x1902800(%r12),%rbp
  call   <srand@plt>
  nopl   (%rax)
L2:
  lea    -0x2800(%rbx),%r13
  nop
L8:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x21,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,8),%edx
  sub    %edx,%eax
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%r13)
  cmp    %rbx,%r13
  jne    L8
  lea    0x2800(%r13),%rbx
  cmp    %rbp,%rbx
  jne    L2
  mov    %r12,%rsi
  mov    $0xa00,%edi
  call   <rowechelon@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  unsigned int size = 0xA00;
  float *matrix = (float *)malloc(sizeof(float) * size * size);
  int i, j;
  srand(size);
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      matrix[i * size + j] = (float)(rand() % 9);
    }
  }
  rowechelon(size, matrix);
  free(matrix);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x1505,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L21:
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  je     L25
  mov    -0x10(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L21
  jmp    L7
L25:
  nop
L7:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash_string(const char *string, size_t n) {
  unsigned long hash = 5381;
  unsigned char c;
  size_t i = 0;
  for (i = 0; i < n; i++) {
    c = string[i];
    if (c == '\0') {
      break;
    }
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```