ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D28(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L9
L0:
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L9:
  movsd  D52(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  jae    L0
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
data_type: f64
name: unpack_data
arguments: data_label: D28
data_type: f64
name: unpack_data
arguments: data_label: D10
data_type: f64
name: unpack_data
arguments: data_label: D52
data_type: byte[8]
name: unpack_data
arguments: data_label: D56
data_type: string

tool: D17: 1

tool: D28: 3

tool: D10: 2

tool: {"D52": [0x00,0x00,0x00,0x00,0x00,0x80,0x43,0x40]}

tool: D56: %0.2lf


assistant: ```c
int main() {
  double S = 1.0, i = 3, k = 2;
  while (i <= 39) {
    S = S + (i / k);
    i += 2;
    k *= 2;
  }
  printf("%0.2lf\n", S);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%eax
  movsd  D4(%rip),%xmm0
  movsd  D29(%rip),%xmm1
  movsd  D11(%rip),%xmm2
  movapd %xmm0,%xmm4
L4:
  movapd %xmm1,%xmm3
  divsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
  addsd  %xmm4,%xmm1
  addsd  %xmm0,%xmm0
  sub    $0x1,%eax
  jne    L4
  movapd %xmm2,%xmm0
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: f64
name: read_data
arguments: data_tag: D29
datatype: f64
name: read_data
arguments: data_tag: D11
datatype: f64
name: read_data
arguments: data_tag: D30
datatype: string

tool: D4: 2

tool: D29: 3

tool: D11: 1

tool: D30: %0.2lf


assistant: ```c
int main() {
  double S = 1.0, i = 3, k = 2;
  while (i <= 39) {
    S = S + (i / k);
    i += 2;
    k *= 2;
  }
  printf("%0.2lf\n", S);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D11(%rip),%xmm4
  mov    $0x13,%eax
  movsd  D17(%rip),%xmm1
  movsd  D23(%rip),%xmm2
  movapd %xmm4,%xmm0
  nopl   0x0(%rax)
L5:
  movapd %xmm1,%xmm3
  addsd  %xmm4,%xmm1
  divsd  %xmm0,%xmm3
  addsd  %xmm0,%xmm0
  addsd  %xmm3,%xmm2
  sub    $0x1,%eax
  jne    L5
  movapd %xmm2,%xmm0
  lea    D22(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_infered: f64
name: extract_symbolic_data
arguments: label: D17
type_infered: f64
name: extract_symbolic_data
arguments: label: D23
type_infered: f64
name: extract_symbolic_data
arguments: label: D22
type_infered: string

tool: D11: 2

tool: D17: 3

tool: D23: 1

tool: D22: %0.2lf


assistant: ```c
int main() {
  double S = 1.0, i = 3, k = 2;
  while (i <= 39) {
    S = S + (i / k);
    i += 2;
    k *= 2;
  }
  printf("%0.2lf\n", S);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D31(%rip),%xmm4
  mov    $0x13,%eax
  movsd  D15(%rip),%xmm1
  movsd  D34(%rip),%xmm2
  movapd %xmm4,%xmm0
  nopl   0x0(%rax)
L5:
  movapd %xmm1,%xmm3
  addsd  %xmm4,%xmm1
  divsd  %xmm0,%xmm3
  addsd  %xmm0,%xmm0
  addsd  %xmm3,%xmm2
  sub    $0x1,%eax
  jne    L5
  movapd %xmm2,%xmm0
  lea    D37(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D31
type_infered: f64
name: extract_symbolic_data
arguments: label: D15
type_infered: f64
name: extract_symbolic_data
arguments: label: D34
type_infered: f64
name: extract_symbolic_data
arguments: label: D37
type_infered: string

tool: D31: 2

tool: D15: 3

tool: D34: 1

tool: D37: %0.2lf


assistant: ```c
int main() {
  double S = 1.0, i = 3, k = 2;
  while (i <= 39) {
    S = S + (i / k);
    i += 2;
    k *= 2;
  }
  printf("%0.2lf\n", S);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <removeElement@plt>
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L14
L7:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L14:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D8: %d 

assistant: ```c
int main(int argc, char **argv) {
  int a[] = {1, 2, 3, 2, 3, 2, 1, 6, 2};
  int n = removeElement(a, 9, 2);
  for (int i = 0; i < n; ++i)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  mov    %rsp,%rdi
  mov    $0x2,%edx
  mov    $0x9,%esi
  call   <removeElement@plt>
  test   %eax,%eax
  jle    L0
  mov    %rsp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x4(%rsp,%rax,4),%r12
  lea    D8(%rip),%rbp
L28:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L28
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: %d 

assistant: ```c
int main(int argc, char **argv) {
  int a[] = {1, 2, 3, 2, 3, 2, 1, 6, 2};
  int n = removeElement(a, 9, 2);
  for (int i = 0; i < n; ++i)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  mov    $0x9,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbx
  movl   $0x2,0x20(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  add    $0x2,%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x600000001,%rax
  mov    %rax,0x18(%rsp)
  call   <removeElement@plt>
  test   %eax,%eax
  jle    L1
  sub    $0x1,%eax
  lea    D2(%rip),%rbp
  lea    0x4(%rsp,%rax,4),%r12
  nopl   (%rax)
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: %d 

assistant: ```c
int main(int argc, char **argv) {
  int a[] = {1, 2, 3, 2, 3, 2, 1, 6, 2};
  int n = removeElement(a, 9, 2);
  for (int i = 0; i < n; ++i)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  mov    $0x9,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movl   $0x2,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D18(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <removeElement@plt>
  test   %eax,%eax
  jle    L21
  sub    $0x1,%eax
  lea    D6(%rip),%rbp
  lea    0x4(%rsp,%rax,4),%r12
  nopl   (%rax)
L23:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L23
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D26
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D18
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: {"D26": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D18": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D6: %d 

assistant: ```c
int main(int argc, char **argv) {
  int a[] = {1, 2, 3, 2, 3, 2, 1, 6, 2};
  int n = removeElement(a, 9, 2);
  for (int i = 0; i < n; ++i)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L8
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bar(int *x, int *y, int z) {
  if (z) {
    x = y;
  }
  *x = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bar>:
  endbr64
  test   %edx,%edx
  cmovne %rsi,%rdi
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void bar(int *x, int *y, int z) {
  if (z) {
    x = y;
  }
  *x = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bar>:
  endbr64
  test   %edx,%edx
  cmovne %rsi,%rdi
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void bar(int *x, int *y, int z) {
  if (z) {
    x = y;
  }
  *x = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4ce000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0x7a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4c4b50(%rbp),%rdx
  lea    -0x4ce790(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read_lines@plt>
  mov    %eax,-0x4ce794(%rbp)
  cmpl   $0x0,-0x4ce794(%rbp)
  js     L7
  mov    -0x4ce794(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x4ce790(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <string_sort@plt>
  mov    -0x4ce794(%rbp),%edx
  lea    -0x4ce790(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <write_lines@plt>
  mov    $0x0,%eax
  jmp    L30
L7:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: string

tool: D2: error: input too big to sort


assistant: ```c
int main(void) {
  int lines_count;
  char *line_pointer_array[5000];
  char lines_buffer[5000 * 1000];
  if ((lines_count = read_lines(line_pointer_array, lines_buffer)) >= 0) {
    string_sort(line_pointer_array, 0, lines_count - 1);
    write_lines(line_pointer_array, lines_count);
    return 0;
  } else {
    printf("error: input too big to sort\n");
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x4ce000(%rsp),%r11
L33:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L33
  sub    $0x798,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4ce788(%rsp)
  xor    %eax,%eax
  lea    0x9c40(%rsp),%rsi
  mov    %rsp,%rdi
  call   <read_lines@plt>
  test   %eax,%eax
  js     L39
  mov    %eax,%ebx
  lea    -0x1(%rax),%edx
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <string_sort@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <write_lines@plt>
  mov    $0x0,%eax
L5:
  mov    0x4ce788(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x4ce798,%rsp
  pop    %rbx
  pop    %rbp
  ret
L39:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L5
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: error: input too big to sort


assistant: ```c
int main(void) {
  int lines_count;
  char *line_pointer_array[5000];
  char lines_buffer[5000 * 1000];
  if ((lines_count = read_lines(line_pointer_array, lines_buffer)) >= 0) {
    string_sort(line_pointer_array, 0, lines_count - 1);
    write_lines(line_pointer_array, lines_count);
    return 0;
  } else {
    printf("error: input too big to sort\n");
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x4ce000(%rsp),%r11
L37:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L37
  sub    $0x798,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4ce788(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x9c40(%rsp),%rsi
  mov    %r12,%rdi
  call   <read_lines@plt>
  test   %eax,%eax
  js     L33
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <string_sort@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <write_lines@plt>
  xor    %eax,%eax
L11:
  mov    0x4ce788(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x4ce798,%rsp
  pop    %rbp
  pop    %r12
  ret
L33:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L11
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
datatype: string

tool: D8: error: input too big to sort


assistant: ```c
int main(void) {
  int lines_count;
  char *line_pointer_array[5000];
  char lines_buffer[5000 * 1000];
  if ((lines_count = read_lines(line_pointer_array, lines_buffer)) >= 0) {
    string_sort(line_pointer_array, 0, lines_count - 1);
    write_lines(line_pointer_array, lines_count);
    return 0;
  } else {
    printf("error: input too big to sort\n");
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x4ce000(%rsp),%r11
L30:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L30
  sub    $0x798,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4ce788(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x9c40(%rsp),%rsi
  mov    %r12,%rdi
  call   <read_lines@plt>
  test   %eax,%eax
  js     L18
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <string_sort@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <write_lines@plt>
  xor    %eax,%eax
L35:
  mov    0x4ce788(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x4ce798,%rsp
  pop    %rbp
  pop    %r12
  ret
L18:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L35
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D7: error: input too big to sort


assistant: ```c
int main(void) {
  int lines_count;
  char *line_pointer_array[5000];
  char lines_buffer[5000 * 1000];
  if ((lines_count = read_lines(line_pointer_array, lines_buffer)) >= 0) {
    string_sort(line_pointer_array, 0, lines_count - 1);
    write_lines(line_pointer_array, lines_count);
    return 0;
  } else {
    printf("error: input too big to sort\n");
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<imul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int imul(unsigned int flags) {
  int is_dma, type_dma, is_rec;
  is_dma = !!(flags & 1u);
  type_dma = is_dma * 2;
  is_rec = !!(flags & 0x10u);
  return type_dma + (is_rec * !is_dma) * 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<imul>:
  endbr64
  mov    %edi,%edx
  shr    $0x4,%edx
  and    $0x1,%edi
  sete   %al
  movzbl %al,%eax
  and    %edx,%eax
  lea    (%rax,%rdi,2),%eax
  ret
```

assistant: ```c
unsigned int imul(unsigned int flags) {
  int is_dma, type_dma, is_rec;
  is_dma = !!(flags & 1u);
  type_dma = is_dma * 2;
  is_rec = !!(flags & 0x10u);
  return type_dma + (is_rec * !is_dma) * 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<imul>:
  endbr64
  mov    %edi,%edx
  shr    $0x4,%edi
  and    $0x1,%edx
  mov    %edx,%eax
  xor    $0x1,%eax
  and    %edi,%eax
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
unsigned int imul(unsigned int flags) {
  int is_dma, type_dma, is_rec;
  is_dma = !!(flags & 1u);
  type_dma = is_dma * 2;
  is_rec = !!(flags & 0x10u);
  return type_dma + (is_rec * !is_dma) * 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<imul>:
  endbr64
  mov    %edi,%edx
  shr    $0x4,%edi
  and    $0x1,%edx
  mov    %edx,%eax
  xor    $0x1,%eax
  and    %edi,%eax
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
unsigned int imul(unsigned int flags) {
  int is_dma, type_dma, is_rec;
  is_dma = !!(flags & 1u);
  type_dma = is_dma * 2;
  is_rec = !!(flags & 0x10u);
  return type_dma + (is_rec * !is_dma) * 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<launch_gameserver>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L67
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L35
L67:
  movq   $0x0,-0x20(%rbp)
L35:
  mov    D38(%rip),%rax
  mov    (%rax),%ecx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L79
  mov    $0xffffffff,%eax
  jmp    L1
L79:
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jns    L26
  mov    $0xfffffffe,%eax
  jmp    L1
L26:
  mov    -0x24(%rbp),%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <listen@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jns    L37
  mov    $0xfffffffd,%eax
  jmp    L1
L37:
  mov    -0x24(%rbp),%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

assistant: ```c
int launch_gameserver(int port) {
  int ret = 0;
  int gamesocket = 0;
  struct sockaddr_in address;
  address.sin_family = AF_INET;
  address.sin_addr.s_addr = INADDR_ANY;
  if (port != 0)
    address.sin_port = htons(port);
  else
    address.sin_port = 0;
  gamesocket = socket(AF_INET, SOCK_STREAM, 0);
  if (gamesocket < 0)
    return -1;
  ret = bind(gamesocket, (struct sockaddr *)&address, sizeof(address));
  if (ret < 0)
    return -2;
  ret = listen(gamesocket, 5);
  if (ret < 0)
    return -3;
  return gamesocket;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<launch_gameserver>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  mov    $0x0,%eax
  test   %edi,%edi
  jne    L43
L45:
  mov    %rax,(%rsp)
  mov    $0x0,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L27
  mov    %rsp,%rsi
  mov    $0x10,%edx
  mov    %eax,%edi
  call   <bind@plt>
  test   %eax,%eax
  js     L55
  mov    $0x5,%esi
  mov    %ebx,%edi
  call   <listen@plt>
  test   %eax,%eax
  mov    $0xfffffffd,%eax
  cmovs  %eax,%ebx
L47:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L43:
  call   <htons@plt>
  jmp    L45
L27:
  mov    $0xffffffff,%ebx
  jmp    L47
L55:
  mov    $0xfffffffe,%ebx
  jmp    L47
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int launch_gameserver(int port) {
  int ret = 0;
  int gamesocket = 0;
  struct sockaddr_in address;
  address.sin_family = AF_INET;
  address.sin_addr.s_addr = INADDR_ANY;
  if (port != 0)
    address.sin_port = htons(port);
  else
    address.sin_port = 0;
  gamesocket = socket(AF_INET, SOCK_STREAM, 0);
  if (gamesocket < 0)
    return -1;
  ret = bind(gamesocket, (struct sockaddr *)&address, sizeof(address));
  if (ret < 0)
    return -2;
  ret = listen(gamesocket, 5);
  if (ret < 0)
    return -3;
  return gamesocket;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<launch_gameserver>:
  endbr64
  push   %r12
  sub    $0x20,%rsp
  mov    D14(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  mov    (%r12),%r8d
  mov    (%rax),%eax
  mov    %r8d,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  test   %edi,%edi
  jne    L35
  movq   $0x0,(%rsp)
L47:
  mov    D3(%rip),%rax
  xor    %edx,%edx
  mov    %r8d,%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L27
  mov    %rsp,%rsi
  mov    $0x10,%edx
  mov    %eax,%edi
  call   <bind@plt>
  test   %eax,%eax
  js     L15
  mov    %r12d,%edi
  mov    $0x5,%esi
  call   <listen@plt>
  test   %eax,%eax
  mov    $0xfffffffd,%eax
  cmovs  %eax,%r12d
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  call   <htons@plt>
  mov    (%r12),%r8d
  mov    %rax,(%rsp)
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%r12d
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xfffffffe,%r12d
  jmp    L48
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int launch_gameserver(int port) {
  int ret = 0;
  int gamesocket = 0;
  struct sockaddr_in address;
  address.sin_family = AF_INET;
  address.sin_addr.s_addr = INADDR_ANY;
  if (port != 0)
    address.sin_port = htons(port);
  else
    address.sin_port = 0;
  gamesocket = socket(AF_INET, SOCK_STREAM, 0);
  if (gamesocket < 0)
    return -1;
  ret = bind(gamesocket, (struct sockaddr *)&address, sizeof(address));
  if (ret < 0)
    return -2;
  ret = listen(gamesocket, 5);
  if (ret < 0)
    return -3;
  return gamesocket;
}
```