ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D38(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  jle    L12
  mov    %ebp,%eax
  xor    %r12d,%r12d
  mov    $0xcccccccd,%ecx
  nop
L25:
  mov    %eax,%eax
  add    $0x1,%r12d
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edx
  jg     L25
  mov    %ebp,%edi
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  movslq %edi,%rax
  mov    %edi,%edx
  mov    %r12d,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <pow@plt>
  movslq 0x4(%rsp),%rdi
  add    %eax,%ebx
  mov    %rdi,%rax
  imul   $0x66666667,%rdi,%rdi
  cltd
  sar    $0x22,%rdi
  sub    %edx,%edi
  mov    %edi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L18
L63:
  cmp    %ebx,%ebp
  je     L4
  lea    D30(%rip),%rdi
  call   <printf@plt>
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L34
L12:
  xor    %ebx,%ebx
  jmp    L63
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D38
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D38: Enter a number: 

tool: D7: %d

tool: D30: 
The number is not armstrong


tool: D4: 
The number is armstrong


assistant: ```c
int main(void) {
  int n, r, a = 0, t, c = 0, z;
  printf("Enter a number: ");
  scanf("%d", &n);
  t = n;
  z = n;
  while (z > 0) {
    z = z / 10;
    c++;
  }
  while (n > 0) {
    r = n % 10;
    a = a + pow(r, c);
    n = n / 10;
  }
  if (a == t)
    printf("\nThe number is armstrong\n");
  else
    printf("\nThe number is not armstrong\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_repeat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L14:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x14(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L14
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_repeat(char a, size_t n) {
  char *s = malloc(n + 1);
  for (int i = 0; i < n; ++i)
    s[i] = a;
  s[n] = 0;
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_repeat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %edi,%ebx
  lea    0x1(%rsi),%rdi
  call   <malloc@plt>
  test   %rbp,%rbp
  je     L5
  mov    %rax,%rdx
  lea    0x0(%rbp,%rax,1),%rcx
L8:
  mov    %bl,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L8
L5:
  movb   $0x0,(%rax,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *str_repeat(char a, size_t n) {
  char *s = malloc(n + 1);
  for (int i = 0; i < n; ++i)
    s[i] = a;
  s[n] = 0;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_repeat>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rbx,%rbx
  je     L2
  movsbl %bpl,%esi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L2:
  movb   $0x0,(%r8,%rbx,1)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *str_repeat(char a, size_t n) {
  char *s = malloc(n + 1);
  for (int i = 0; i < n; ++i)
    s[i] = a;
  s[n] = 0;
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_repeat>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rbx,%rbx
  je     L5
  movsbl %bpl,%esi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L5:
  movb   $0x0,(%r8,%rbx,1)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *str_repeat(char a, size_t n) {
  char *s = malloc(n + 1);
  for (int i = 0; i < n; ++i)
    s[i] = a;
  s[n] = 0;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Dot_lf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L16:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double Dot_lf(double *x, double *y, int n) {
  double d;
  int i;
  d = 0;
  for (i = 0; i < n; i++) {
    d += x[i] * y[i];
  }
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Dot_lf>:
  endbr64
  test   %edx,%edx
  jle    L9
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L16:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
L24:
  movapd %xmm1,%xmm0
  ret
L9:
  pxor   %xmm1,%xmm1
  jmp    L24
```

assistant: ```c
double Dot_lf(double *x, double *y, int n) {
  double d;
  int i;
  d = 0;
  for (i = 0; i < n; i++) {
    d += x[i] * y[i];
  }
  return d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Dot_lf>:
  endbr64
  test   %edx,%edx
  jle    L5
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L18:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L18
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L5:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double Dot_lf(double *x, double *y, int n) {
  double d;
  int i;
  d = 0;
  for (i = 0; i < n; i++) {
    d += x[i] * y[i];
  }
  return d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Dot_lf>:
  endbr64
  test   %edx,%edx
  jle    L38
  cmp    $0x1,%edx
  je     L41
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L29:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L29
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L12
L3:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L12:
  ret
  nopl   0x0(%rax)
L38:
  pxor   %xmm0,%xmm0
  ret
L41:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L3
```

assistant: ```c
double Dot_lf(double *x, double *y, int n) {
  double d;
  int i;
  d = 0;
  for (i = 0; i < n; i++) {
    d += x[i] * y[i];
  }
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printbin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L24
L19:
  shll   -0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L19
L16:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L17
  cmpl   $0x0,-0x4(%rbp)
  je     L62
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L31
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  jmp    L16
L31:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
L62:
  nop
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D3
data_type: string

tool: D2: 1

tool: D0: 0

tool: D3: 


assistant: ```c
void printbin(int dec) {
  int bin = 1;
  while (bin <= dec) {
    bin *= 2;
  }
  while (1) {
    bin /= 2;
    if (dec == 0 && bin == 0) {
      break;
    }
    if (dec >= bin) {
      printf("1");
      dec -= bin;
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printbin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  jle    L39
  mov    $0x1,%eax
L2:
  mov    %eax,%r13d
  add    %eax,%eax
  cmp    %eax,%ebx
  jge    L2
L36:
  lea    D1(%rip),%r12
  lea    D4(%rip),%rbp
  jmp    L68
L39:
  jne    L63
L56:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L63:
  mov    $0x0,%r13d
  jmp    L36
L37:
  mov    %r12,%rdi
  call   <printf@plt>
L15:
  mov    %r13d,%eax
  shr    $0x1f,%eax
  add    %r13d,%eax
  sar    %eax
  mov    %eax,%r13d
  or     %ebx,%eax
  je     L56
L68:
  cmp    %r13d,%ebx
  jl     L37
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    %r13d,%ebx
  jmp    L15
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D4
type_infered: string
name: read_data
arguments: tag: D18
type_infered: string

tool: D1: 0

tool: D4: 1

tool: D18: 


assistant: ```c
void printbin(int dec) {
  int bin = 1;
  while (bin <= dec) {
    bin *= 2;
  }
  while (1) {
    bin /= 2;
    if (dec == 0 && bin == 0) {
      break;
    }
    if (dec >= bin) {
      printf("1");
      dec -= bin;
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<printbin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L78
  mov    $0x1,%eax
  nopl   0x0(%rax)
L16:
  mov    %eax,%ebx
  add    %eax,%eax
  cmp    %eax,%ebp
  jge    L16
L57:
  lea    D20(%rip),%r13
  lea    D24(%rip),%r12
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L69:
  sub    %ebx,%ebp
  mov    %r12,%rdi
  sar    %ebx
  call   <printf@plt>
  mov    %ebx,%eax
  or     %ebp,%eax
  je     L52
L73:
  cmp    %ebx,%ebp
  jge    L69
  sar    %ebx
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  or     %ebp,%eax
  jne    L73
L52:
  add    $0x8,%rsp
  lea    D17(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L78:
  je     L52
  xor    %ebx,%ebx
  jmp    L57
```

tool_calls: name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D24
type_infered: string
name: unpack_data
arguments: data_label: D17
type_infered: string

tool: D20: 0

tool: D24: 1

tool: D17: 


assistant: ```c
void printbin(int dec) {
  int bin = 1;
  while (bin <= dec) {
    bin *= 2;
  }
  while (1) {
    bin /= 2;
    if (dec == 0 && bin == 0) {
      break;
    }
    if (dec >= bin) {
      printf("1");
      dec -= bin;
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printbin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L7
  mov    $0x1,%eax
  nopl   0x0(%rax)
L62:
  mov    %eax,%ebx
  add    %eax,%eax
  cmp    %eax,%ebp
  jge    L62
L32:
  lea    D25(%rip),%r13
  lea    D23(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L5:
  cmp    %ebx,%ebp
  jl     L11
  sub    %ebx,%ebp
  mov    %r12,%rdi
  sar    %ebx
  call   <printf@plt>
  mov    %ebx,%eax
  or     %ebp,%eax
  jne    L5
L18:
  add    $0x8,%rsp
  lea    D7(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L11:
  mov    %r13,%rdi
  sar    %ebx
  call   <printf@plt>
  mov    %ebp,%eax
  or     %ebx,%eax
  jne    L5
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L7:
  je     L18
  xor    %ebx,%ebx
  jmp    L32
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
data_type: string
name: disassemble_data
arguments: data_tag: D23
data_type: string
name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D25: 0

tool: D23: 1

tool: D7: 


assistant: ```c
void printbin(int dec) {
  int bin = 1;
  while (bin <= dec) {
    bin *= 2;
  }
  while (1) {
    bin /= 2;
    if (dec == 0 && bin == 0) {
      break;
    }
    if (dec >= bin) {
      printf("1");
      dec -= bin;
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_int8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x2d,(%rax)
  negl   -0x14(%rbp)
L2:
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <print_uint8@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int print_int8(int8_t n, char *p) {
  int sign;
  if ((sign = n < 0)) {
    *p++ = '-';
    n = -n;
  }
  return print_uint8(n, p) + sign;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_int8>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x1f,%ebx
  test   %edi,%edi
  js     L3
L0:
  call   <print_uint8@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
L3:
  movb   $0x2d,(%rsi)
  neg    %edi
  lea    0x1(%rsi),%rsi
  jmp    L0
```

assistant: ```c
int print_int8(int8_t n, char *p) {
  int sign;
  if ((sign = n < 0)) {
    *p++ = '-';
    n = -n;
  }
  return print_uint8(n, p) + sign;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_int8>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x1f,%ebx
  test   %edi,%edi
  jns    L0
  movb   $0x2d,(%rsi)
  neg    %edi
  add    $0x1,%rsi
L0:
  call   <print_uint8@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int print_int8(int8_t n, char *p) {
  int sign;
  if ((sign = n < 0)) {
    *p++ = '-';
    n = -n;
  }
  return print_uint8(n, p) + sign;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_int8>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x1f,%ebx
  test   %edi,%edi
  jns    L8
  movb   $0x2d,(%rsi)
  neg    %edi
  add    $0x1,%rsi
L8:
  call   <print_uint8@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int print_int8(int8_t n, char *p) {
  int sign;
  if ((sign = n < 0)) {
    *p++ = '-';
    n = -n;
  }
  return print_uint8(n, p) + sign;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movb   $0x2a,-0x15(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L99
L12:
  movl   $0x1,-0x10(%rbp)
  jmp    L45
L159:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L159
  movl   $0x1,-0xc(%rbp)
  jmp    L46
L47:
  movsbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L46:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L47
  addl   $0x2,-0x8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L99:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L12
  movl   $0x1,-0x8(%rbp)
  movl   $0x7,-0x4(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L93
L43:
  movl   $0x1,-0x10(%rbp)
  jmp    L66
L102:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L66:
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L102
  movl   $0x1,-0xc(%rbp)
  jmp    L70
L114:
  movsbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L70:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L114
  addl   $0x2,-0x8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L93:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L43
  movl   $0x1,-0x8(%rbp)
  movl   $0xb,-0x4(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L141
L145:
  movl   $0x1,-0x10(%rbp)
  jmp    L116
L84:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L116:
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L84
  movl   $0x1,-0xc(%rbp)
  jmp    L62
L175:
  movsbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L62:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L175
  addl   $0x2,-0x8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L141:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L145
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  char asterisk = '*';
  int i, ii, height, start = 1, end = 1;
  height = 4;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  end = 1;
  height = 7;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  end = 1;
  height = 11;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%r13d
  mov    $0x1,%ebp
L120:
  mov    %r13d,%r12d
  mov    $0x1,%ebx
  test   %r13d,%r13d
  jle    L108
L148:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L148
L108:
  test   %ebp,%ebp
  jle    L81
  mov    $0x1,%ebx
L139:
  mov    $0x2a,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L139
L81:
  add    $0x2,%ebp
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  cmp    $0x9,%ebp
  jne    L120
  mov    $0x6,%r13d
  mov    $0x1,%ebp
L5:
  mov    %r13d,%r12d
  mov    $0x1,%ebx
  test   %r13d,%r13d
  jle    L48
L146:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jle    L146
L48:
  test   %ebp,%ebp
  jle    L136
  mov    $0x1,%ebx
L0:
  mov    $0x2a,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L0
L136:
  add    $0x2,%ebp
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  cmp    $0xf,%ebp
  jne    L5
  mov    $0xa,%r13d
  mov    $0x1,%ebp
  jmp    L97
L35:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jle    L35
L69:
  test   %ebp,%ebp
  jle    L47
  mov    $0x1,%ebx
L104:
  mov    $0x2a,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L104
L47:
  add    $0x2,%ebp
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  cmp    $0x17,%ebp
  je     L125
L97:
  mov    %r13d,%r12d
  mov    $0x1,%ebx
  test   %r13d,%r13d
  jg     L35
  jmp    L69
L125:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  char asterisk = '*';
  int i, ii, height, start = 1, end = 1;
  height = 4;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  end = 1;
  height = 7;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  end = 1;
  height = 11;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
  sub    $0x8,%rsp
L20:
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L116
L19:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jle    L19
L116:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L74:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L74
  mov    $0xa,%edi
  sub    $0x1,%r12d
  lea    0x2(%rbx),%ebp
  call   <putchar@plt>
  cmp    $0x8,%ebx
  jne    L20
  mov    $0x2,%ebp
  mov    $0x7,%r13d
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %r13d,%r12d
  mov    $0x1,%ebx
  sub    $0x1,%r13d
  je     L91
  cs nopw 0x0(%rax,%rax,1)
L81:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L81
L91:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L63:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L63
  mov    $0xa,%edi
  lea    0x2(%rbx),%ebp
  call   <putchar@plt>
  test   %r13d,%r13d
  jne    L44
  mov    $0x2,%ebp
  mov    $0xb,%r13d
  xchg   %ax,%ax
L58:
  mov    %r13d,%r12d
  mov    $0x1,%ebx
  sub    $0x1,%r13d
  je     L85
  xchg   %ax,%ax
L67:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L67
L85:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L50:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L50
  mov    $0xa,%edi
  add    $0x2,%ebp
  call   <putchar@plt>
  test   %r13d,%r13d
  jne    L58
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  char asterisk = '*';
  int i, ii, height, start = 1, end = 1;
  height = 4;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  end = 1;
  height = 7;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  end = 1;
  height = 11;
  for (i = 1; i <= height; i++) {
    for (ii = 1; ii <= height - i; ii++) {
      printf(" ");
    }
    for (start = 1; start <= end; start++) {
      printf("%c", asterisk);
    }
    end += 2;
    printf("\n");
  }
  return 0;
}
```