ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<rank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L18:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2c(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  mov    %rdx,%rcx
  imul   %rax,%rcx
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    (%rax,%rdx,1),%rcx
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long int rank(int *a, int *count, int *fact, int n) {
  long long int r = 1;
  int i;
  for (i = 0; i < n; i++) {
    int x = a[i] - 1 - i + count[a[i] - 1];
    r = (r + ((long long)(x) * (fact[n - i - 1])) % 1000000007) % 1000000007;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rank>:
  endbr64
  test   %ecx,%ecx
  jle    L19
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  movslq %ecx,%rax
  lea    (%rdx,%rax,4),%r8
  mov    %ecx,%ebx
  mov    $0x0,%edi
  mov    $0x1,%esi
  movabs $0x89705f3112a28fe5,%r9
L10:
  mov    (%r10,%rdi,4),%eax
  movslq %eax,%rdx
  lea    -0x1(%rax),%ecx
  sub    %edi,%ecx
  add    -0x4(%r11,%rdx,4),%ecx
  movslq %ecx,%rcx
  movslq -0x4(%r8),%rax
  imul   %rax,%rcx
  mov    %rcx,%rax
  imul   %r9
  add    %rcx,%rdx
  sar    $0x1d,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rcx
  add    %rsi,%rcx
  mov    %rcx,%rax
  imul   %r9
  lea    (%rdx,%rcx,1),%rsi
  sar    $0x1d,%rsi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rsi
  imul   $0x3b9aca07,%rsi,%rax
  mov    %rcx,%rsi
  sub    %rax,%rsi
  add    $0x1,%rdi
  sub    $0x4,%r8
  cmp    %rbx,%rdi
  jne    L10
  mov    %rsi,%rax
  pop    %rbx
  ret
L19:
  mov    $0x1,%esi
  mov    %rsi,%rax
  ret
```

assistant: ```c
long long int rank(int *a, int *count, int *fact, int n) {
  long long int r = 1;
  int i;
  for (i = 0; i < n; i++) {
    int x = a[i] - 1 - i + count[a[i] - 1];
    r = (r + ((long long)(x) * (fact[n - i - 1])) % 1000000007) % 1000000007;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rank>:
  endbr64
  test   %ecx,%ecx
  jle    L3
  push   %rbx
  movslq %ecx,%rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  lea    (%rdx,%rbx,4),%rdi
  xor    %esi,%esi
  mov    $0x1,%r8d
  movabs $0x89705f3112a28fe5,%r9
  nopl   0x0(%rax)
L14:
  movslq (%r10,%rsi,4),%rdx
  movslq -0x4(%rdi),%rax
  sub    $0x4,%rdi
  lea    -0x1(%rdx),%ecx
  sub    %esi,%ecx
  add    -0x4(%r11,%rdx,4),%ecx
  add    $0x1,%rsi
  movslq %ecx,%rcx
  imul   %rax,%rcx
  mov    %rcx,%rax
  imul   %r9
  mov    %rcx,%rax
  sar    $0x3f,%rax
  add    %rcx,%rdx
  sar    $0x1d,%rdx
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rcx
  add    %r8,%rcx
  mov    %rcx,%rax
  imul   %r9
  mov    %rcx,%rax
  sar    $0x3f,%rax
  lea    (%rdx,%rcx,1),%r8
  sar    $0x1d,%r8
  sub    %rax,%r8
  imul   $0x3b9aca07,%r8,%rax
  sub    %rax,%rcx
  mov    %rcx,%r8
  cmp    %rsi,%rbx
  jne    L14
  mov    %rcx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long long int rank(int *a, int *count, int *fact, int n) {
  long long int r = 1;
  int i;
  for (i = 0; i < n; i++) {
    int x = a[i] - 1 - i + count[a[i] - 1];
    r = (r + ((long long)(x) * (fact[n - i - 1])) % 1000000007) % 1000000007;
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rank>:
  endbr64
  test   %ecx,%ecx
  jle    L17
  push   %rbx
  movslq %ecx,%rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  lea    (%rdx,%rbx,4),%rdi
  xor    %esi,%esi
  mov    $0x1,%r8d
  movabs $0x89705f3112a28fe5,%r9
  nopl   0x0(%rax)
L4:
  movslq (%r10,%rsi,4),%rdx
  movslq -0x4(%rdi),%rax
  sub    $0x4,%rdi
  lea    -0x1(%rdx),%ecx
  sub    %esi,%ecx
  add    -0x4(%r11,%rdx,4),%ecx
  add    $0x1,%rsi
  movslq %ecx,%rcx
  imul   %rax,%rcx
  mov    %rcx,%rax
  imul   %r9
  mov    %rcx,%rax
  sar    $0x3f,%rax
  add    %rcx,%rdx
  sar    $0x1d,%rdx
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rcx
  add    %r8,%rcx
  mov    %rcx,%rax
  imul   %r9
  mov    %rcx,%rax
  sar    $0x3f,%rax
  lea    (%rdx,%rcx,1),%r8
  sar    $0x1d,%r8
  sub    %rax,%r8
  imul   $0x3b9aca07,%r8,%rax
  sub    %rax,%rcx
  mov    %rcx,%r8
  cmp    %rsi,%rbx
  jne    L4
  mov    %rcx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long long int rank(int *a, int *count, int *fact, int n) {
  long long int r = 1;
  int i;
  for (i = 0; i < n; i++) {
    int x = a[i] - 1 - i + count[a[i] - 1];
    r = (r + ((long long)(x) * (fact[n - i - 1])) % 1000000007) % 1000000007;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<regPrintPosPair>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L15
  movsd  -0x8(%rbp),%xmm0
  movsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    %rcx,%rsi
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <regPrintPos@plt>
  jmp    L16
L15:
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <regPrintPos@plt>
L16:
  mov    -0x28(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <regPrintPos@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: f64

tool: D0: 15

assistant: ```c
void regPrintPosPair(double x, double y, int world, char *xbuf, char *ybuf) {
  if (world)
    regPrintPos(x / 15.0, world, xbuf);
  else
    regPrintPos(x, world, xbuf);
  regPrintPos(y, world, ybuf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<regPrintPosPair>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm1,%rbp
  mov    %edi,%ebx
  mov    %rdx,%r12
  test   %edi,%edi
  je     L12
  divsd  D3(%rip),%xmm0
  call   <regPrintPos@plt>
L4:
  mov    %r12,%rsi
  mov    %ebx,%edi
  movq   %rbp,%xmm0
  call   <regPrintPos@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0x0,%edi
  call   <regPrintPos@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D3
datatype: f64

tool: D3: 15

assistant: ```c
void regPrintPosPair(double x, double y, int world, char *xbuf, char *ybuf) {
  if (world)
    regPrintPos(x / 15.0, world, xbuf);
  else
    regPrintPos(x, world, xbuf);
  regPrintPos(y, world, ybuf);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<regPrintPosPair>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  test   %edi,%edi
  je     L8
  divsd  D6(%rip),%xmm0
  call   <regPrintPos@plt>
  movsd  0x8(%rsp),%xmm1
L3:
  add    $0x18,%rsp
  mov    %r12,%rsi
  movapd %xmm1,%xmm0
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <regPrintPos@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %edi,%edi
  call   <regPrintPos@plt>
  movsd  0x8(%rsp),%xmm1
  jmp    L3
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: f64

tool: D6: 15

assistant: ```c
void regPrintPosPair(double x, double y, int world, char *xbuf, char *ybuf) {
  if (world)
    regPrintPos(x / 15.0, world, xbuf);
  else
    regPrintPos(x, world, xbuf);
  regPrintPos(y, world, ybuf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<regPrintPosPair>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  test   %edi,%edi
  je     L9
  divsd  D1(%rip),%xmm0
  call   <regPrintPos@plt>
  movsd  0x8(%rsp),%xmm1
L0:
  add    $0x18,%rsp
  mov    %r12,%rsi
  movapd %xmm1,%xmm0
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <regPrintPos@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %edi,%edi
  call   <regPrintPos@plt>
  movsd  0x8(%rsp),%xmm1
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: f64

tool: D1: 15

assistant: ```c
void regPrintPosPair(double x, double y, int world, char *xbuf, char *ybuf) {
  if (world)
    regPrintPos(x / 15.0, world, xbuf);
  else
    regPrintPos(x, world, xbuf);
  regPrintPos(y, world, ybuf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<whine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void whine(char *format, ...) {
  va_list vl;
  va_start(vl, format);
  vfprintf(stderr, format, vl);
  va_end(vl);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<whine>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void whine(char *format, ...) {
  va_list vl;
  va_start(vl, format);
  vfprintf(stderr, format, vl);
  va_end(vl);
}
```
user: Translate the below assembly code into C programming language:

```asm
<whine>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void whine(char *format, ...) {
  va_list vl;
  va_start(vl, format);
  vfprintf(stderr, format, vl);
  va_end(vl);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<whine>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void whine(char *format, ...) {
  va_list vl;
  va_start(vl, format);
  vfprintf(stderr, format, vl);
  va_end(vl);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  mov    $0x4d260,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xf4240,%edi
  call   <Sieve@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L82
L1:
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L16
L101:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jg     L75
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L6
  addl   $0x1,-0x18(%rbp)
  jmp    L107
L85:
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%esi
  cltd
  idiv   %esi
  mov    %eax,-0x20(%rbp)
L107:
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L85
L6:
  addl   $0x1,-0x1c(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L101
  jmp    L83
L75:
  nop
L83:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L82:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L12
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jne    L1
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string

tool: D6: %d

tool: D17:  : %d


assistant: ```c
int main(void) {
  int i, m, n, t, d = 0;
  int *arr = malloc(79000 * sizeof(int));
  d = Sieve(1000000, arr);
  while (scanf("%d", &n) && n != 0) {
    printf("%d", n);
    t = 0;
    for (i = 0; i < d; i++) {
      if (n < arr[i])
        break;
      if (n % arr[i] == 0) {
        t++;
        while (n % arr[i] == 0)
          n /= arr[i];
      }
    }
    printf(" : %d\n", t);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4d260,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rsi
  mov    $0xf4240,%edi
  call   <Sieve@plt>
  mov    %eax,%r13d
  lea    -0x1(%rax),%eax
  lea    0x4(%r12,%rax,4),%rbx
  lea    0x4(%rsp),%r14
  lea    D3(%rip),%rbp
  lea    D8(%rip),%r15
  jmp    L41
L20:
  add    $0x4,%rdi
  cmp    %rbx,%rdi
  je     L79
L36:
  mov    %rdi,%r8
  mov    (%rdi),%esi
  mov    0x4(%rsp),%ecx
  cmp    %ecx,%esi
  jg     L79
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L20
  add    $0x1,%r9d
L91:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  mov    %eax,0x4(%rsp)
  mov    (%r8),%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L91
  jmp    L20
L90:
  mov    $0x0,%r9d
L79:
  mov    %r9d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
L41:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L69
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L69
  mov    %rbp,%rdi
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L90
  mov    %r12,%rdi
  mov    $0x0,%r9d
  jmp    L36
L69:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D3: %d

tool: D8:  : %d


assistant: ```c
int main(void) {
  int i, m, n, t, d = 0;
  int *arr = malloc(79000 * sizeof(int));
  d = Sieve(1000000, arr);
  while (scanf("%d", &n) && n != 0) {
    printf("%d", n);
    t = 0;
    for (i = 0; i < d; i++) {
      if (n < arr[i])
        break;
      if (n % arr[i] == 0) {
        t++;
        while (n % arr[i] == 0)
          n /= arr[i];
      }
    }
    printf(" : %d\n", t);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4d260,%edi
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <malloc@plt>
  mov    $0xf4240,%edi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <Sieve@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    %eax,%r12d
  sub    $0x1,%eax
  lea    0x4(%rbp,%rax,4),%r15
  call   <scanf@plt>
  test   %rax,%rax
  je     L118
  xchg   %ax,%ax
L75:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L118
  mov    %rbx,%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L39
  mov    %rbp,%rdi
  xor    %r8d,%r8d
  jmp    L35
  nopl   (%rax)
L79:
  add    $0x4,%rdi
  cmp    %r15,%rdi
  je     L29
L35:
  mov    (%rdi),%esi
  mov    0x4(%rsp),%ecx
  cmp    %ecx,%esi
  jg     L29
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L79
  add    $0x1,%r8d
  nopl   0x0(%rax,%rax,1)
L116:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,0x4(%rsp)
  mov    (%rdi),%esi
  cltd
  mov    %eax,%ecx
  idiv   %esi
  test   %edx,%edx
  je     L116
  add    $0x4,%rdi
  cmp    %r15,%rdi
  jne    L35
  nopl   (%rax)
L29:
  mov    %r8d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L75
L118:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  xor    %r8d,%r8d
  jmp    L29
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D1:  : %d


tool: D6: %d

assistant: ```c
int main(void) {
  int i, m, n, t, d = 0;
  int *arr = malloc(79000 * sizeof(int));
  d = Sieve(1000000, arr);
  while (scanf("%d", &n) && n != 0) {
    printf("%d", n);
    t = 0;
    for (i = 0; i < d; i++) {
      if (n < arr[i])
        break;
      if (n % arr[i] == 0) {
        t++;
        while (n % arr[i] == 0)
          n /= arr[i];
      }
    }
    printf(" : %d\n", t);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4d260,%edi
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <malloc@plt>
  mov    $0xf4240,%edi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <Sieve@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    %eax,%r12d
  sub    $0x1,%eax
  lea    0x4(%rbp,%rax,4),%r15
  call   <scanf@plt>
  test   %rax,%rax
  je     L101
  xchg   %ax,%ax
L87:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L101
  mov    %rbx,%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L93
  mov    0x4(%rsp),%ecx
  mov    %rbp,%rdi
  xor    %r8d,%r8d
  jmp    L59
  nopl   (%rax)
L72:
  add    $0x4,%rdi
  cmp    %r15,%rdi
  je     L119
L59:
  mov    (%rdi),%esi
  cmp    %ecx,%esi
  jg     L119
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L72
  add    $0x1,%r8d
  nopl   0x0(%rax)
L30:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,0x4(%rsp)
  mov    (%rdi),%esi
  cltd
  mov    %eax,%ecx
  idiv   %esi
  test   %edx,%edx
  je     L30
  add    $0x4,%rdi
  cmp    %r15,%rdi
  jne    L59
  nopl   (%rax)
L119:
  mov    %r8d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L87
L101:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L93:
  xor    %r8d,%r8d
  jmp    L119
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string

tool: D7:  : %d


tool: D16: %d

assistant: ```c
int main(void) {
  int i, m, n, t, d = 0;
  int *arr = malloc(79000 * sizeof(int));
  d = Sieve(1000000, arr);
  while (scanf("%d", &n) && n != 0) {
    printf("%d", n);
    t = 0;
    for (i = 0; i < d; i++) {
      if (n < arr[i])
        break;
      if (n % arr[i] == 0) {
        t++;
        while (n % arr[i] == 0)
          n /= arr[i];
      }
    }
    printf(" : %d\n", t);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f@plt>
  cmp    $0x2,%eax
  je     L0
  mov    $0x0,%eax
  call   <abort@plt>
L0:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (f() != 2)
    abort();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  cmp    $0x2,%eax
  jne    L9
L18:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L9:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L18
```

assistant: ```c
int main() {
  if (f() != 2)
    abort();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  cmp    $0x2,%eax
  je     L2
  xor    %eax,%eax
  call   <abort@plt>
L2:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (f() != 2)
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  cmp    $0x2,%eax
  je     L4
  xor    %eax,%eax
  call   <abort@plt>
L4:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (f() != 2)
    abort();
  exit(0);
}
```