user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L115:
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x1f,-0xc(%rbp)
  jg     L4
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L115
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_memrealloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x8(%rbp)
  jmp    L93
L65:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%eax
  add    %esi,%eax
  cltq
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L93:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L65
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    (%rdx),%edx
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L48:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    $0x1f,%eax
  jg     L99
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  jmp    L99
L51:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  add    %rcx,%rax
  movb   $0x0,(%rax)
L99:
  cmpl   $0x1f,-0x8(%rbp)
  jg     L59
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
L59:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int set_line(char **buff_p, char **line, int *size) {
  int i;
  int j;
  int nl;
  i = 0;
  while (i < 32 && (*buff_p)[i] != '\0' && (*buff_p)[i] != '\n')
    i++;
  nl = ((*buff_p)[i] == '\n');
  *line = ft_memrealloc(*line, *size + i + 1);
  j = 0;
  while (j < i) {
    (*line)[*size + j] = (*buff_p)[j];
    j++;
  }
  *size += i++;
  j = 0;
  while (j + i < 32 && (*buff_p)[j + i] != '\0') {
    (*buff_p)[j] = (*buff_p)[j + i];
    j++;
  }
  while (j < 32 && (*buff_p)[j] != '\0')
    (*buff_p)[j++] = '\0';
  return (nl);
}
```