ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string

tool: D8: Usage: %s <source ip> <dest. ip>


tool: D16: [Use x.x.x.x format]

assistant: ```c
void help(char *pname) {
  printf("Usage: %s <source ip> <dest. ip>\n", pname);
  printf("[Use x.x.x.x format]\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string

tool: D16: Usage: %s <source ip> <dest. ip>


tool: D13: [Use x.x.x.x format]

assistant: ```c
void help(char *pname) {
  printf("Usage: %s <source ip> <dest. ip>\n", pname);
  printf("[Use x.x.x.x format]\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string

tool: D15: Usage: %s <source ip> <dest. ip>


tool: D8: [Use x.x.x.x format]

assistant: ```c
void help(char *pname) {
  printf("Usage: %s <source ip> <dest. ip>\n", pname);
  printf("[Use x.x.x.x format]\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D19
type_infered: string

tool: D15: Usage: %s <source ip> <dest. ip>


tool: D19: [Use x.x.x.x format]

assistant: ```c
void help(char *pname) {
  printf("Usage: %s <source ip> <dest. ip>\n", pname);
  printf("[Use x.x.x.x format]\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L50
  mov    $0x1,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L50:
  movl   $0x0,-0x1c(%rbp)
  jmp    L46
L32:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp),%edx
  mov    %edx,-0x10(%rbp,%rax,4)
  addl   $0x1,-0x1c(%rbp)
L46:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L32
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x4f84ae8,%eax
  jne    L68
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L68:
  movl   $0x0,-0x18(%rbp)
  jmp    L64
L67:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0xc(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L64:
  cmpl   $0x0,-0x18(%rbp)
  jle    L67
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D20
type_infered: string

tool: D1: Call this program with %i arguments


tool: D7: You win!

tool: D20: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 83380968U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L14
L48:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <RandomFunc@plt>
  cmpl   $0x4f84ae8,0x4(%rsp)
  je     L21
L39:
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L48
L21:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  jmp    L39
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D27
type_infered: string

tool: D3: %u


tool: D16: Call this program with %i arguments


tool: D27: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 83380968U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L29
  lea    D28(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L29:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x4f84ae8,%esi
  je     L17
L4:
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L4
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D28
data_type: string
name: unpack_data
arguments: data_tag: D24
data_type: string
name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D28: Call this program with %i arguments


tool: D24: %u


tool: D8: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 83380968U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L20
  lea    D6(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L20:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x4f84ae8,%esi
  je     L29
L13:
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L13
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string
name: extract_symbolic_data
arguments: label: D12
type: string
name: extract_symbolic_data
arguments: label: D16
type: string

tool: D6: Call this program with %i arguments


tool: D12: %u


tool: D16: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 83380968U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<float_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <space@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L13:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L19
L29:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <space@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L15
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L29
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D16: MATRIX, allocation failure 1.

tool: D3: MATRIX, allocation failure 2.

assistant: ```c
float **float_matrix(int rl, int rh, int cl, int ch) {
  int i;
  float **m;
  m = (float **)space((unsigned)(rh - rl + 1) * sizeof(float *));
  if (!m)
    nrerror("MATRIX, allocation failure 1.");
  m -= rl;
  for (i = rl; i <= rh; i++) {
    m[i] = (float *)space((unsigned)(ch - cl + 1) * sizeof(float));
    if (!m[i])
      nrerror("MATRIX, allocation failure 2.");
    m[i] -= cl;
  }
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<float_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %ecx,%r15d
  mov    %esi,%eax
  sub    %edi,%eax
  lea    0x8(,%rax,8),%edi
  call   <space@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
L7:
  movslq %r14d,%rbx
  lea    0x0(,%rbx,8),%rax
  sub    %rax,%rbp
  cmp    %r14d,%r13d
  jl     L43
  sub    %r12d,%r15d
  lea    0x4(,%r15,4),%r14d
  movslq %r12d,%r12
  shl    $0x2,%r12
  neg    %r12
  lea    D15(%rip),%r15
  jmp    L14
L28:
  lea    D11(%rip),%rdi
  call   <nrerror@plt>
  jmp    L7
L12:
  add    %r12,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jl     L43
L14:
  mov    %r14d,%edi
  call   <space@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  test   %rax,%rax
  jne    L12
  mov    %r15,%rdi
  call   <nrerror@plt>
  jmp    L12
L43:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D15
type: string
name: read_data
arguments: label: D11
type: string

tool: D15: MATRIX, allocation failure 2.

tool: D11: MATRIX, allocation failure 1.

assistant: ```c
float **float_matrix(int rl, int rh, int cl, int ch) {
  int i;
  float **m;
  m = (float **)space((unsigned)(rh - rl + 1) * sizeof(float *));
  if (!m)
    nrerror("MATRIX, allocation failure 1.");
  m -= rl;
  for (i = rl; i <= rh; i++) {
    m[i] = (float *)space((unsigned)(ch - cl + 1) * sizeof(float));
    if (!m[i])
      nrerror("MATRIX, allocation failure 2.");
    m[i] -= cl;
  }
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<float_matrix>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  sub    %edi,%eax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    0x8(,%rax,8),%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <space@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L31
L13:
  movslq %r12d,%r14
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r12d,%ebp
  jl     L45
  sub    %ebx,%r13d
  shl    $0x2,%rbx
  lea    0x4(,%r13,4),%r12d
  neg    %rbx
  lea    D14(%rip),%r13
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L37:
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jl     L45
L57:
  mov    %r12d,%edi
  call   <space@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  jne    L37
  mov    %r13,%rdi
  call   <nrerror@plt>
  mov    (%r15,%r14,8),%rax
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L57
L45:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L31:
  lea    D5(%rip),%rdi
  call   <nrerror@plt>
  jmp    L13
```

tool_calls: name: read_data
arguments: data_tag: D14
data_type: string
name: read_data
arguments: data_tag: D5
data_type: string

tool: D14: MATRIX, allocation failure 2.

tool: D5: MATRIX, allocation failure 1.

assistant: ```c
float **float_matrix(int rl, int rh, int cl, int ch) {
  int i;
  float **m;
  m = (float **)space((unsigned)(rh - rl + 1) * sizeof(float *));
  if (!m)
    nrerror("MATRIX, allocation failure 1.");
  m -= rl;
  for (i = rl; i <= rh; i++) {
    m[i] = (float *)space((unsigned)(ch - cl + 1) * sizeof(float));
    if (!m[i])
      nrerror("MATRIX, allocation failure 2.");
    m[i] -= cl;
  }
  return m;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<float_matrix>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  sub    %edi,%eax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    0x8(,%rax,8),%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <space@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L25
L0:
  movslq %r12d,%r14
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r12d,%ebp
  jl     L55
  sub    %ebx,%r13d
  shl    $0x2,%rbx
  lea    0x4(,%r13,4),%r12d
  neg    %rbx
  lea    D8(%rip),%r13
  nopl   (%rax)
L16:
  mov    %r12d,%edi
  call   <space@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  je     L15
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L16
L55:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %r13,%rdi
  call   <nrerror@plt>
  add    %rbx,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L16
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L25:
  lea    D19(%rip),%rdi
  call   <nrerror@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string

tool: D8: MATRIX, allocation failure 2.

tool: D19: MATRIX, allocation failure 1.

assistant: ```c
float **float_matrix(int rl, int rh, int cl, int ch) {
  int i;
  float **m;
  m = (float **)space((unsigned)(rh - rl + 1) * sizeof(float *));
  if (!m)
    nrerror("MATRIX, allocation failure 1.");
  m -= rl;
  for (i = rl; i <= rh; i++) {
    m[i] = (float *)space((unsigned)(ch - cl + 1) * sizeof(float));
    if (!m[i])
      nrerror("MATRIX, allocation failure 2.");
    m[i] -= cl;
  }
  return m;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<linear_fit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0x1c(%rbp)
  jmp    L26
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x18(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  addl   $0x1,-0x1c(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L23
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x34(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x18(%rbp),%xmm0
  divss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L11
L19:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  subss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0x4(%rbp),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x48(%rbp),%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L19
  mov    -0x48(%rbp),%rax
  movss  (%rax),%xmm0
  divss  -0x10(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x48(%rbp),%rax
  movss  (%rax),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x18(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  subss  %xmm1,%xmm0
  divss  -0xc(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void linear_fit(float x[], float y[], int ndata, float *a, float *b) {
  int i;
  float t, sxoss, sx = 0.0F, sy = 0.0F, st2 = 0.0F, ss;
  *b = 0.0;
  for (i = 0; i < ndata; i++) {
    sx += x[i];
    sy += y[i];
  }
  ss = (float)ndata;
  sxoss = sx / ss;
  for (i = 0; i < ndata; i++) {
    t = x[i] - sxoss;
    st2 += t * t;
    *b += t * y[i];
  }
  *b /= st2;
  *a = (sy - sx * (*b)) / ss;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<linear_fit>:
  endbr64
  mov    %rcx,%r9
  movl   $0x0,(%r8)
  test   %edx,%edx
  jle    L12
  mov    %edx,%ecx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm2
L31:
  addss  (%rdi,%rax,4),%xmm2
  addss  (%rsi,%rax,4),%xmm1
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L31
  pxor   %xmm6,%xmm6
  cvtsi2ss %edx,%xmm6
  movaps %xmm2,%xmm5
  divss  %xmm6,%xmm5
  mov    $0x0,%eax
  pxor   %xmm3,%xmm3
L4:
  movss  (%rdi,%rax,4),%xmm0
  subss  %xmm5,%xmm0
  movaps %xmm0,%xmm4
  mulss  %xmm0,%xmm4
  addss  %xmm4,%xmm3
  mulss  (%rsi,%rax,4),%xmm0
  addss  (%r8),%xmm0
  movss  %xmm0,(%r8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L4
L25:
  movss  (%r8),%xmm0
  divss  %xmm3,%xmm0
  movss  %xmm0,(%r8)
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  divss  %xmm6,%xmm1
  movss  %xmm1,(%r9)
  ret
L12:
  pxor   %xmm6,%xmm6
  cvtsi2ss %edx,%xmm6
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm2
  movaps %xmm1,%xmm3
  jmp    L25
```

assistant: ```c
void linear_fit(float x[], float y[], int ndata, float *a, float *b) {
  int i;
  float t, sxoss, sx = 0.0F, sy = 0.0F, st2 = 0.0F, ss;
  *b = 0.0;
  for (i = 0; i < ndata; i++) {
    sx += x[i];
    sy += y[i];
  }
  ss = (float)ndata;
  sxoss = sx / ss;
  for (i = 0; i < ndata; i++) {
    t = x[i] - sxoss;
    st2 += t * t;
    *b += t * y[i];
  }
  *b /= st2;
  *a = (sy - sx * (*b)) / ss;
}
```