ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_atoi>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L8
  cmp    $0x20,%dl
  jne    L31
L8:
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L60:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L60
  cmp    $0x20,%dl
  je     L60
L2:
  sub    $0x2b,%edx
  and    $0xfffffffd,%edx
  cmp    $0x1,%dl
  adc    $0x0,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L64
  lea    0x1(%rdi,%rsi,1),%rdx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L6:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rdx
  movsbl %al,%eax
  lea    (%rax,%rcx,2),%r8d
  movzbl -0x1(%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L6
  mov    %r8d,%eax
  ret
L64:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
L31:
  xor    %esi,%esi
  jmp    L2
```

assistant: ```c
int ft_atoi(char *str) {
  int i;
  int negative;
  int nb;
  nb = 0;
  i = 0;
  negative = 0;
  while (str[i] == ' ' || str[i] == '\n' || str[i] == '\t' || str[i] == '\f' || str[i] == '\r' || str[i] == '\v')
    i++;
  if (str[i] == '-' || str[i] == '+')
    i++;
  if (str[i] == '-')
    negative = 1;
  while (str[i] >= 48 && str[i] <= 57) {
    nb = nb * 10;
    nb = nb + (str[i] - '0');
    i++;
  }
  if (negative == 1)
    return (-nb);
  else
    return (nb);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_atoi>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L7
  cmp    $0x20,%dl
  jne    L13
L7:
  mov    $0x1,%eax
  nopl   0x0(%rax)
L22:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L22
  cmp    $0x20,%dl
  je     L22
L14:
  lea    -0x2b(%rdx),%eax
  test   $0xfd,%al
  jne    L49
  add    $0x1,%esi
  movslq %esi,%rax
  movzbl (%rdi,%rax,1),%edx
L49:
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L76
  movslq %esi,%rsi
  mov    %edx,%eax
  xor    %r8d,%r8d
  lea    0x1(%rdi,%rsi,1),%rcx
  nopl   0x0(%rax)
L47:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%esi
  add    $0x1,%rcx
  movsbl %al,%eax
  lea    (%rax,%rsi,2),%r8d
  movzbl -0x1(%rcx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L47
  mov    %r8d,%eax
  neg    %eax
  cmp    $0x2d,%dl
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
L76:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  neg    %eax
  cmp    $0x2d,%dl
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
L13:
  xor    %esi,%esi
  jmp    L14
```

assistant: ```c
int ft_atoi(char *str) {
  int i;
  int negative;
  int nb;
  nb = 0;
  i = 0;
  negative = 0;
  while (str[i] == ' ' || str[i] == '\n' || str[i] == '\t' || str[i] == '\f' || str[i] == '\r' || str[i] == '\v')
    i++;
  if (str[i] == '-' || str[i] == '+')
    i++;
  if (str[i] == '-')
    negative = 1;
  while (str[i] >= 48 && str[i] <= 57) {
    nb = nb * 10;
    nb = nb + (str[i] - '0');
    i++;
  }
  if (negative == 1)
    return (-nb);
  else
    return (nb);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Chebyshev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L7
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  jmp    L19
L7:
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x40(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x2,-0x24(%rbp)
  jmp    L5
L56:
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L5:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L56
  movsd  -0x40(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  D1(%rip),%xmm1
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L30
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  je     L11
L30:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x34(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  D1(%rip),%xmm3
  movapd %xmm0,%xmm2
  subsd  %xmm3,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  jmp    L50
L11:
  mov    -0x34(%rbp),%eax
  imul   %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  divsd  -0x40(%rbp),%xmm0
L50:
  movsd  %xmm0,-0x48(%rbp)
L19:
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: f64

tool: D1: 1

assistant: ```c
double Chebyshev(int n, double x, double d) {
  double f, fm1, fm2, x2;
  int i;
  if (n == 0) {
    f = 1e0;
    d = 0e0;
  } else {
    f = x;
    fm1 = 1e0;
    x2 = 2 * x;
    for (i = 2; i <= n; i++) {
      fm2 = fm1;
      fm1 = f;
      f = x2 * fm1 - fm2;
    }
    d = (x * x - 1e0) ? n * (x * f - fm1) / (x * x - 1e0) : n * n * f / x;
  }
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Chebyshev>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L7
  movapd %xmm0,%xmm3
  addsd  %xmm0,%xmm3
  cmp    $0x1,%edi
  jle    L8
  add    $0x1,%edi
  mov    $0x2,%eax
  movsd  D0(%rip),%xmm2
  jmp    L6
L38:
  movapd %xmm0,%xmm1
L6:
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  add    $0x1,%eax
  movapd %xmm1,%xmm2
  cmp    %eax,%edi
  jne    L38
  ret
L7:
  movsd  D0(%rip),%xmm0
  ret
L8:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: f64

tool: D0: 1

assistant: ```c
double Chebyshev(int n, double x, double d) {
  double f, fm1, fm2, x2;
  int i;
  if (n == 0) {
    f = 1e0;
    d = 0e0;
  } else {
    f = x;
    fm1 = 1e0;
    x2 = 2 * x;
    for (i = 2; i <= n; i++) {
      fm2 = fm1;
      fm1 = f;
      f = x2 * fm1 - fm2;
    }
    d = (x * x - 1e0) ? n * (x * f - fm1) / (x * x - 1e0) : n * n * f / x;
  }
  return f;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Chebyshev>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L29
  movapd %xmm0,%xmm3
  addsd  %xmm0,%xmm3
  cmp    $0x1,%edi
  jle    L38
  movsd  D0(%rip),%xmm2
  add    $0x1,%edi
  mov    $0x2,%eax
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L11:
  movapd %xmm0,%xmm1
L4:
  movapd %xmm3,%xmm0
  add    $0x1,%eax
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  movapd %xmm1,%xmm2
  cmp    %eax,%edi
  jne    L11
  ret
  nopl   0x0(%rax)
L29:
  movsd  D0(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L38:
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: f64

tool: D0: 1

assistant: ```c
double Chebyshev(int n, double x, double d) {
  double f, fm1, fm2, x2;
  int i;
  if (n == 0) {
    f = 1e0;
    d = 0e0;
  } else {
    f = x;
    fm1 = 1e0;
    x2 = 2 * x;
    for (i = 2; i <= n; i++) {
      fm2 = fm1;
      fm1 = f;
      f = x2 * fm1 - fm2;
    }
    d = (x * x - 1e0) ? n * (x * f - fm1) / (x * x - 1e0) : n * n * f / x;
  }
  return f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Chebyshev>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L10
  movapd %xmm0,%xmm3
  addsd  %xmm0,%xmm3
  cmp    $0x1,%edi
  jle    L5
  movsd  D17(%rip),%xmm2
  add    $0x1,%edi
  mov    $0x2,%eax
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L25:
  movapd %xmm0,%xmm1
L23:
  movapd %xmm3,%xmm0
  add    $0x1,%eax
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  movapd %xmm1,%xmm2
  cmp    %eax,%edi
  jne    L25
  ret
  nopl   0x0(%rax)
L10:
  movsd  D17(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_infered: f64

tool: D17: 1

assistant: ```c
double Chebyshev(int n, double x, double d) {
  double f, fm1, fm2, x2;
  int i;
  if (n == 0) {
    f = 1e0;
    d = 0e0;
  } else {
    f = x;
    fm1 = 1e0;
    x2 = 2 * x;
    for (i = 2; i <= n; i++) {
      fm2 = fm1;
      fm1 = f;
      f = x2 * fm1 - fm2;
    }
    d = (x * x - 1e0) ? n * (x * f - fm1) / (x * x - 1e0) : n * n * f / x;
  }
  return f;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itoa_my>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x30000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0xd80,%rsp
  mov    %edi,-0x30d74(%rbp)
  mov    %rsi,-0x30d80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30d64(%rbp)
  movl   $0x0,-0x30d60(%rbp)
  movl   $0x0,-0x30d58(%rbp)
  movl   $0x0,-0x30d5c(%rbp)
  movl   $0x0,-0x30d54(%rbp)
  mov    -0x30d74(%rbp),%eax
  mov    %eax,-0x30d5c(%rbp)
  jmp    L56
L42:
  mov    -0x30d5c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x30d54(%rbp)
  mov    -0x30d5c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x30d5c(%rbp)
  mov    -0x30d54(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x30d64(%rbp),%eax
  cltq
  mov    %dl,-0x30d50(%rbp,%rax,1)
  addl   $0x1,-0x30d64(%rbp)
L56:
  cmpl   $0x0,-0x30d5c(%rbp)
  jg     L42
  subl   $0x1,-0x30d64(%rbp)
  mov    -0x30d64(%rbp),%eax
  mov    %eax,-0x30d58(%rbp)
  movl   $0x0,-0x30d60(%rbp)
  jmp    L45
L21:
  mov    -0x30d64(%rbp),%eax
  cltq
  movzbl -0x30d50(%rbp,%rax,1),%edx
  mov    -0x30d60(%rbp),%eax
  cltq
  mov    %dl,-0x186b0(%rbp,%rax,1)
  addl   $0x1,-0x30d60(%rbp)
  subl   $0x1,-0x30d64(%rbp)
L45:
  mov    -0x30d60(%rbp),%eax
  cmp    -0x30d58(%rbp),%eax
  jle    L21
  mov    -0x30d60(%rbp),%eax
  cltq
  movb   $0x0,-0x186b0(%rbp,%rax,1)
  mov    -0x30d80(%rbp),%rax
  mov    %rax,%rdi
  call   <clear_string@plt>
  lea    -0x186b0(%rbp),%rdx
  mov    -0x30d80(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void itoa_my(int digit, char string[100000]) {
  int i = 0;
  int j = 0;
  int len = 0;
  int value = 0;
  int residual = 0;
  char tmp[100000];
  char rev[100000];
  value = digit;
  while (value > 0) {
    residual = value % 10;
    value /= 10;
    tmp[i] = residual + '0';
    i++;
  }
  i--;
  len = i;
  for (j = 0; j <= len; j++, i--) {
    rev[j] = tmp[i];
  };
  rev[j] = '\0';
  clear_string(string);
  strcpy(string, rev);
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa_my>:
  endbr64
  push   %rbx
  lea    -0x30000(%rsp),%r11
L58:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L58
  sub    $0xd50,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x30d48(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L8
  mov    %edi,%edx
  mov    $0x0,%ecx
L55:
  mov    %ecx,%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%r8d
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %edx,%esi
  mov    %r8d,%edx
  add    $0x30,%eax
  mov    %al,(%rsp,%rcx,1)
  add    $0x1,%rcx
  cmp    $0x9,%esi
  jg     L55
  test   %edi,%edi
  js     L17
  movslq %edi,%rcx
  lea    (%rsp,%rcx,1),%rax
  lea    0x186a0(%rsp),%rdx
  lea    -0x1(%rsp,%rcx,1),%rsi
  mov    %edi,%r8d
  sub    %r8,%rsi
L64:
  movzbl (%rax),%ecx
  mov    %cl,(%rdx)
  sub    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rax
  jne    L64
  add    $0x1,%edi
L18:
  movslq %edi,%rdi
  movb   $0x0,0x186a0(%rsp,%rdi,1)
  mov    %rbx,%rdi
  call   <clear_string@plt>
  lea    0x186a0(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x30d48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x30d50,%rsp
  pop    %rbx
  ret
L8:
  mov    $0x0,%edi
  jmp    L18
L17:
  mov    $0x0,%edi
  jmp    L18
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa_my(int digit, char string[100000]) {
  int i = 0;
  int j = 0;
  int len = 0;
  int value = 0;
  int residual = 0;
  char tmp[100000];
  char rev[100000];
  value = digit;
  while (value > 0) {
    residual = value % 10;
    value /= 10;
    tmp[i] = residual + '0';
    i++;
  }
  i--;
  len = i;
  for (j = 0; j <= len; j++, i--) {
    rev[j] = tmp[i];
  };
  rev[j] = '\0';
  clear_string(string);
  strcpy(string, rev);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<itoa_my>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x30000(%rsp),%r11
L50:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L50
  sub    $0xd58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30d48(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbp
  test   %edi,%edi
  jle    L37
  mov    %edi,%ecx
  xor    %edx,%edx
  mov    %rsp,%rsi
  mov    $0xcccccccd,%r10d
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %ecx,%eax
  mov    %edx,%r9d
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r8d
  mov    %eax,%edi
  mov    %ecx,%eax
  add    %r8d,%r8d
  sub    %r8d,%eax
  mov    %ecx,%r8d
  mov    %edi,%ecx
  mov    %rdx,%rdi
  add    $0x30,%eax
  mov    %al,(%rsi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x9,%r8d
  jg     L43
  lea    0x186a0(%rsp),%r12
  movslq %r9d,%rdx
  add    %rsi,%rdx
  mov    %r12,%rcx
  lea    (%r12,%rdi,1),%rsi
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L30:
  movzbl (%rdx),%eax
  add    $0x1,%rcx
L60:
  mov    %al,(%rcx)
  sub    $0x1,%rdx
  cmp    %rsi,%rcx
  jne    L30
  add    $0x1,%r9d
L33:
  movslq %r9d,%r9
  mov    %rbp,%rdi
  movb   $0x0,0x186a0(%rsp,%r9,1)
  call   <clear_string@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x30d48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x30d58,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  xor    %r9d,%r9d
  lea    0x186a0(%rsp),%r12
  jmp    L33
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa_my(int digit, char string[100000]) {
  int i = 0;
  int j = 0;
  int len = 0;
  int value = 0;
  int residual = 0;
  char tmp[100000];
  char rev[100000];
  value = digit;
  while (value > 0) {
    residual = value % 10;
    value /= 10;
    tmp[i] = residual + '0';
    i++;
  }
  i--;
  len = i;
  for (j = 0; j <= len; j++, i--) {
    rev[j] = tmp[i];
  };
  rev[j] = '\0';
  clear_string(string);
  strcpy(string, rev);
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa_my>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x30000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0xd58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30d48(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbp
  test   %edi,%edi
  jle    L0
  xor    %ecx,%ecx
  mov    %rsp,%rdx
  mov    $0xcccccccd,%r11d
L45:
  mov    %edi,%eax
  mov    %ecx,%r9d
  mov    %rcx,%r10
  imul   %r11,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r8d
  mov    %eax,%esi
  mov    %edi,%eax
  add    %r8d,%r8d
  sub    %r8d,%eax
  mov    %edi,%r8d
  mov    %esi,%edi
  add    $0x30,%eax
  mov    %al,(%rdx,%rcx,1)
  add    $0x1,%rcx
  cmp    $0x9,%r8d
  jg     L45
  movslq %r9d,%rcx
  lea    0x186a0(%rsp),%r12
  lea    -0x1(%rsp,%rcx,1),%rsi
  lea    (%rdx,%rcx,1),%rax
  mov    %r12,%rdx
  sub    %r10,%rsi
  nopl   (%rax)
L41:
  movzbl (%rax),%ecx
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rax
  jne    L41
  add    $0x1,%r9d
L34:
  movslq %r9d,%r9
  mov    %rbp,%rdi
  movb   $0x0,0x186a0(%rsp,%r9,1)
  call   <clear_string@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x30d48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30d58,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  xor    %r9d,%r9d
  lea    0x186a0(%rsp),%r12
  jmp    L34
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa_my(int digit, char string[100000]) {
  int i = 0;
  int j = 0;
  int len = 0;
  int value = 0;
  int residual = 0;
  char tmp[100000];
  char rev[100000];
  value = digit;
  while (value > 0) {
    residual = value % 10;
    value /= 10;
    tmp[i] = residual + '0';
    i++;
  }
  i--;
  len = i;
  for (j = 0; j <= len; j++, i--) {
    rev[j] = tmp[i];
  };
  rev[j] = '\0';
  clear_string(string);
  strcpy(string, rev);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  jns    L7
  mov    $0x82,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <shutdown@plt>
  jmp    L15
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L15
  mov    $0x86,%edx
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <shutdown@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string

tool: D2: %d

tool: D25: Failed writing to /proc file

tool: D16: We didn't get what we wrote to /proc back

assistant: ```c
void set(FILE *stream, int value) {
  int new_value;
  rewind(stream);
  if (fprintf(stream, "%d", value) < 0)
    return shutdown(5, "Failed writing to /proc file", 131 - 1);
  new_value = get(stream);
  if (new_value != value)
    return shutdown(5, "We didn't get what we wrote to /proc back", 135 - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<set>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <rewind@plt>
  mov    %ebp,%edx
  lea    D27(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  js     L12
  mov    %rbx,%rdi
  call   <get@plt>
  cmp    %eax,%ebp
  jne    L11
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    $0x82,%edx
  lea    D7(%rip),%rsi
  mov    $0x5,%edi
  call   <shutdown@plt>
  jmp    L33
L11:
  mov    $0x86,%edx
  lea    D18(%rip),%rsi
  mov    $0x5,%edi
  call   <shutdown@plt>
  jmp    L33
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string

tool: D27: %d

tool: D7: Failed writing to /proc file

tool: D18: We didn't get what we wrote to /proc back

assistant: ```c
void set(FILE *stream, int value) {
  int new_value;
  rewind(stream);
  if (fprintf(stream, "%d", value) < 0)
    return shutdown(5, "Failed writing to /proc file", 131 - 1);
  new_value = get(stream);
  if (new_value != value)
    return shutdown(5, "We didn't get what we wrote to /proc back", 135 - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <rewind@plt>
  mov    %ebx,%edx
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    $0x82,%edx
  lea    D14(%rip),%rsi
  test   %rax,%rax
  js     L6
  mov    %rbp,%rdi
  call   <get@plt>
  cmp    %eax,%ebx
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L15:
  mov    $0x86,%edx
  lea    D4(%rip),%rsi
L6:
  add    $0x8,%rsp
  mov    $0x5,%edi
  pop    %rbx
  pop    %rbp
  jmp    1080 <shutdown@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D1: %d

tool: D14: Failed writing to /proc file

tool: D4: We didn't get what we wrote to /proc back

assistant: ```c
void set(FILE *stream, int value) {
  int new_value;
  rewind(stream);
  if (fprintf(stream, "%d", value) < 0)
    return shutdown(5, "Failed writing to /proc file", 131 - 1);
  new_value = get(stream);
  if (new_value != value)
    return shutdown(5, "We didn't get what we wrote to /proc back", 135 - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <rewind@plt>
  mov    %ebx,%edx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    $0x82,%edx
  lea    D17(%rip),%rsi
  test   %rax,%rax
  js     L7
  mov    %rbp,%rdi
  call   <get@plt>
  cmp    %eax,%ebx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  mov    $0x86,%edx
  lea    D24(%rip),%rsi
L7:
  add    $0x8,%rsp
  mov    $0x5,%edi
  pop    %rbx
  pop    %rbp
  jmp    1080 <shutdown@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D24
datatype: string

tool: D11: %d

tool: D17: Failed writing to /proc file

tool: D24: We didn't get what we wrote to /proc back

assistant: ```c
void set(FILE *stream, int value) {
  int new_value;
  rewind(stream);
  if (fprintf(stream, "%d", value) < 0)
    return shutdown(5, "Failed writing to /proc file", 131 - 1);
  new_value = get(stream);
  if (new_value != value)
    return shutdown(5, "We didn't get what we wrote to /proc back", 135 - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aux_print_elements>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: %d


assistant: ```c
void aux_print_elements(d, aux) void *const d;
void *const aux;
{
  int *ip = (int *)d;
  printf("%d\n", *ip);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<aux_print_elements>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: %d


assistant: ```c
void aux_print_elements(d, aux) void *const d;
void *const aux;
{
  int *ip = (int *)d;
  printf("%d\n", *ip);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<aux_print_elements>:
  endbr64
  mov    (%rdi),%esi
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: %d


assistant: ```c
void aux_print_elements(d, aux) void *const d;
void *const aux;
{
  int *ip = (int *)d;
  printf("%d\n", *ip);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aux_print_elements>:
  endbr64
  mov    (%rdi),%esi
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: %d


assistant: ```c
void aux_print_elements(d, aux) void *const d;
void *const aux;
{
  int *ip = (int *)d;
  printf("%d\n", *ip);
}
```