ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  movq   %rax,%xmm2
  movq   %rax,%xmm1
  mov    D53(%rip),%rax
  movq   %rax,%xmm0
  call   <fabd_d@plt>
  mov    D6(%rip),%rax
  movq   %rax,%xmm2
  mov    D53(%rip),%rax
  movq   %rax,%xmm1
  movapd %xmm2,%xmm0
  call   <fabd_d@plt>
  mov    D6(%rip),%rax
  movq   %rax,%xmm2
  movq   %rax,%xmm1
  mov    D53(%rip),%rax
  movq   %rax,%xmm0
  call   <fabd_f@plt>
  mov    D6(%rip),%rax
  movq   %rax,%xmm2
  mov    D53(%rip),%rax
  movq   %rax,%xmm1
  movapd %xmm2,%xmm0
  call   <fabd_f@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: f64
name: disassemble_data
arguments: label: D53
data_type: f64

tool: D6: 5

tool: D53: 10

assistant: ```c
int main() {
  fabd_d(10.0, 5.0, 5.0);
  fabd_d(5.0, 10.0, 5.0);
  fabd_f(10.0, 5.0, 5.0);
  fabd_f(5.0, 10.0, 5.0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D79(%rip),%xmm2
  mov    D71(%rip),%rax
  movapd %xmm2,%xmm1
  movq   %rax,%xmm0
  call   <fabd_d@plt>
  mov    D79(%rip),%rax
  movq   %rax,%xmm2
  mov    D71(%rip),%rax
  movapd %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <fabd_d@plt>
  mov    D79(%rip),%rax
  movq   %rax,%xmm2
  movq   %rax,%xmm1
  mov    D71(%rip),%rax
  movq   %rax,%xmm0
  call   <fabd_f@plt>
  mov    D79(%rip),%rax
  movq   %rax,%xmm2
  mov    D71(%rip),%rax
  movapd %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <fabd_f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D79
data_type: f64
name: read_data
arguments: data_label: D71
data_type: f64

tool: D79: 5

tool: D71: 10

assistant: ```c
int main() {
  fabd_d(10.0, 5.0, 5.0);
  fabd_d(5.0, 10.0, 5.0);
  fabd_f(10.0, 5.0, 5.0);
  fabd_f(5.0, 10.0, 5.0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D25(%rip),%xmm2
  mov    D64(%rip),%rax
  movapd %xmm2,%xmm1
  movq   %rax,%xmm0
  call   <fabd_d@plt>
  mov    D25(%rip),%rax
  movq   %rax,%xmm2
  mov    D64(%rip),%rax
  movapd %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <fabd_d@plt>
  mov    D25(%rip),%rax
  movq   %rax,%xmm2
  movq   %rax,%xmm1
  mov    D64(%rip),%rax
  movq   %rax,%xmm0
  call   <fabd_f@plt>
  mov    D25(%rip),%rax
  movq   %rax,%xmm2
  mov    D64(%rip),%rax
  movapd %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <fabd_f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D64
type_guessed: f64

tool: D25: 5

tool: D64: 10

assistant: ```c
int main() {
  fabd_d(10.0, 5.0, 5.0);
  fabd_d(5.0, 10.0, 5.0);
  fabd_f(10.0, 5.0, 5.0);
  fabd_f(5.0, 10.0, 5.0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_local>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: Address of local, from function, is %p


assistant: ```c
void print_local() {
  int local = 5;
  printf("Address of local, from function, is %p\n", &local);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_local>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: Address of local, from function, is %p


assistant: ```c
void print_local() {
  int local = 5;
  printf("Address of local, from function, is %p\n", &local);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_local>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: Address of local, from function, is %p


assistant: ```c
void print_local() {
  int local = 5;
  printf("Address of local, from function, is %p\n", &local);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_local>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: Address of local, from function, is %p


assistant: ```c
void print_local() {
  int local = 5;
  printf("Address of local, from function, is %p\n", &local);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_ch_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ft_alloc_intarr@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L25
L37:
  mov    -0x20(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L39
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  je     L4
  addl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L61
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  jmp    L33
L61:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L33:
  addl   $0x1,-0x10(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L37
  jmp    L60
L4:
  nop
L60:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **ft_ch_to_int(char **ch_arr, int height, int length, char c) {
  int x;
  int y;
  int **int_arr;
  x = 0;
  y = 0;
  int_arr = ft_alloc_intarr(height, length);
  while (y <= height) {
    if (x > length - 1) {
      if (y == height - 1)
        break;
      y++;
      x = 0;
    }
    if (ch_arr[y][x] == c)
      int_arr[y][x] = 1;
    else
      int_arr[y][x] = 0;
    x++;
  }
  return (int_arr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_ch_to_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    %edx,%esi
  mov    %ebx,%edi
  call   <ft_alloc_intarr@plt>
  test   %ebx,%ebx
  js     L4
  mov    $0x0,%ecx
  mov    $0x0,%edx
  lea    -0x1(%rbx),%r9d
  jmp    L52
L42:
  add    $0x1,%ecx
  mov    $0x0,%edx
L32:
  movslq %ecx,%rdi
  movslq %edx,%rsi
  mov    (%r12,%rdi,8),%r8
  cmp    %r13b,(%r8,%rsi,1)
  je     L53
  mov    (%rax,%rdi,8),%rdi
  movl   $0x0,(%rdi,%rsi,4)
L14:
  add    $0x1,%edx
  cmp    %ebx,%ecx
  jg     L4
L52:
  cmp    %edx,%ebp
  jg     L32
  cmp    %ecx,%r9d
  jne    L42
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  mov    (%rax,%rdi,8),%rdi
  movl   $0x1,(%rdi,%rsi,4)
  jmp    L14
```

assistant: ```c
int **ft_ch_to_int(char **ch_arr, int height, int length, char c) {
  int x;
  int y;
  int **int_arr;
  x = 0;
  y = 0;
  int_arr = ft_alloc_intarr(height, length);
  while (y <= height) {
    if (x > length - 1) {
      if (y == height - 1)
        break;
      y++;
      x = 0;
    }
    if (ch_arr[y][x] == c)
      int_arr[y][x] = 1;
    else
      int_arr[y][x] = 0;
    x++;
  }
  return (int_arr);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_ch_to_int>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <ft_alloc_intarr@plt>
  test   %ebx,%ebx
  js     L2
  xor    %edx,%edx
  xor    %ecx,%ecx
  lea    -0x1(%rbx),%r10d
  jmp    L20
L28:
  movslq %ecx,%rdi
  add    $0x1,%ecx
  lea    0x0(,%rdi,4),%r9
L41:
  movslq %edx,%rsi
  mov    (%rax,%rsi,8),%r8
  mov    0x0(%rbp,%rsi,8),%rsi
  cmp    %r13b,(%rsi,%rdi,1)
  sete   %sil
  movzbl %sil,%esi
  mov    %esi,(%r8,%r9,1)
  cmp    %ebx,%edx
  jg     L2
L20:
  cmp    %ecx,%r12d
  jg     L28
  cmp    %edx,%r10d
  je     L2
  add    $0x1,%edx
  mov    $0x1,%ecx
  xor    %r9d,%r9d
  xor    %edi,%edi
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **ft_ch_to_int(char **ch_arr, int height, int length, char c) {
  int x;
  int y;
  int **int_arr;
  x = 0;
  y = 0;
  int_arr = ft_alloc_intarr(height, length);
  while (y <= height) {
    if (x > length - 1) {
      if (y == height - 1)
        break;
      y++;
      x = 0;
    }
    if (ch_arr[y][x] == c)
      int_arr[y][x] = 1;
    else
      int_arr[y][x] = 0;
    x++;
  }
  return (int_arr);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_ch_to_int>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <ft_alloc_intarr@plt>
  xor    %ecx,%ecx
  xor    %esi,%esi
  lea    -0x1(%rbx),%r9d
  test   %ebx,%ebx
  js     L6
  nopl   (%rax)
L36:
  cmp    %esi,%ebp
  jle    L60
  movslq %esi,%r8
  add    $0x1,%esi
  lea    0x0(,%r8,4),%rdx
L14:
  movslq %ecx,%rdi
  add    (%rax,%rdi,8),%rdx
  mov    (%r12,%rdi,8),%rdi
  cmp    %r13b,(%rdi,%r8,1)
  je     L15
  movl   $0x0,(%rdx)
  cmp    %ebx,%ecx
  jle    L36
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  cmp    %ecx,%r9d
  je     L6
  add    $0x1,%ecx
  mov    $0x1,%esi
  xor    %edx,%edx
  xor    %r8d,%r8d
  jmp    L14
  nopl   0x0(%rax)
L15:
  movl   $0x1,(%rdx)
  cmp    %ebx,%ecx
  jle    L36
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **ft_ch_to_int(char **ch_arr, int height, int length, char c) {
  int x;
  int y;
  int **int_arr;
  x = 0;
  y = 0;
  int_arr = ft_alloc_intarr(height, length);
  while (y <= height) {
    if (x > length - 1) {
      if (y == height - 1)
        break;
      y++;
      x = 0;
    }
    if (ch_arr[y][x] == c)
      int_arr[y][x] = 1;
    else
      int_arr[y][x] = 0;
    x++;
  }
  return (int_arr);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L81
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L47
L55:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L24
  movl   $0x1,-0x14(%rbp)
  jmp    L87
L24:
  cmpq   $0x0,-0x10(%rbp)
  jne    L42
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L42:
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
L47:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L87
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L55
L87:
  cmpl   $0x0,-0x14(%rbp)
  jne    L32
  mov    -0x10(%rbp),%rax
  jmp    L36
L32:
  addq   $0x1,-0x28(%rbp)
L81:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L36:
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(char *s1, char *s2) {
  char *s2h = s2;
  char *s1s = NULL;
  int flag = 0;
  while (*s1 != '\0') {
    s2 = s2h;
    flag = 0;
    s1s = NULL;
    while (*s2 != '\0' && *s1 != '\0') {
      if (*s1 != *s2) {
        flag = 1;
        break;
      }
      if (s1s == NULL)
        s1s = s1;
      s1++;
      s2++;
    }
    if (flag == 0)
      return s1s;
    s1++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L24
  movzbl (%rsi),%r9d
  jmp    L71
L34:
  mov    $0x0,%ecx
  jmp    L24
L69:
  lea    0x1(%rdi),%rax
  cmpb   $0x0,0x1(%rdi)
  je     L24
  mov    %rax,%rdi
L71:
  test   %r9b,%r9b
  je     L34
  mov    %rsi,%r8
  mov    %r9d,%edx
  mov    $0x0,%ecx
L76:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  cmp    %dl,%al
  jne    L69
  test   %rcx,%rcx
  cmove  %rdi,%rcx
  add    $0x1,%rdi
  add    $0x1,%r8
  movzbl (%r8),%edx
  test   %dl,%dl
  jne    L76
L24:
  mov    %rcx,%rax
  ret
```

assistant: ```c
char *strstr(char *s1, char *s2) {
  char *s2h = s2;
  char *s1s = NULL;
  int flag = 0;
  while (*s1 != '\0') {
    s2 = s2h;
    flag = 0;
    s1s = NULL;
    while (*s2 != '\0' && *s1 != '\0') {
      if (*s1 != *s2) {
        flag = 1;
        break;
      }
      if (s1s == NULL)
        s1s = s1;
      s1++;
      s2++;
    }
    if (flag == 0)
      return s1s;
    s1++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strstr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L62
  movzbl (%rsi),%r9d
  test   %r9b,%r9b
  je     L5
  nopw   0x0(%rax,%rax,1)
L75:
  mov    %rsi,%rcx
  mov    %r9d,%edx
  xor    %r8d,%r8d
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L27:
  cmp    %dl,%al
  jne    L71
  test   %r8,%r8
  cmove  %rdi,%r8
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  add    $0x1,%rdi
  test   %dl,%dl
  je     L62
L34:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L27
L62:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L71:
  cmpb   $0x0,0x1(%rdi)
  lea    0x1(%rdi),%rax
  je     L62
  mov    %rax,%rdi
  test   %r9b,%r9b
  jne    L75
L5:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strstr(char *s1, char *s2) {
  char *s2h = s2;
  char *s1s = NULL;
  int flag = 0;
  while (*s1 != '\0') {
    s2 = s2h;
    flag = 0;
    s1s = NULL;
    while (*s2 != '\0' && *s1 != '\0') {
      if (*s1 != *s2) {
        flag = 1;
        break;
      }
      if (s1s == NULL)
        s1s = s1;
      s1++;
      s2++;
    }
    if (flag == 0)
      return s1s;
    s1++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strstr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L17
  movzbl (%rsi),%r9d
  test   %r9b,%r9b
  je     L61
  nopw   0x0(%rax,%rax,1)
L81:
  mov    %rsi,%rcx
  mov    %r9d,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L0:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  cmp    %dl,%al
  jne    L2
  test   %r8,%r8
  je     L93
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L0
L17:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L93:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  lea    0x1(%rdi),%rax
  mov    %rdi,%r8
  test   %dl,%dl
  je     L17
  mov    %rax,%rdi
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L2:
  cmpb   $0x0,0x1(%rdi)
  lea    0x1(%rdi),%rax
  je     L17
  mov    %rax,%rdi
  test   %r9b,%r9b
  jne    L81
L61:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strstr(char *s1, char *s2) {
  char *s2h = s2;
  char *s1s = NULL;
  int flag = 0;
  while (*s1 != '\0') {
    s2 = s2h;
    flag = 0;
    s1s = NULL;
    while (*s2 != '\0' && *s1 != '\0') {
      if (*s1 != *s2) {
        flag = 1;
        break;
      }
      if (s1s == NULL)
        s1s = s1;
      s1++;
      s2++;
    }
    if (flag == 0)
      return s1s;
    s1++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<util_hex_to_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <util_hex_to_nib@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L31
  mov    -0x8(%rbp),%eax
  jmp    L15
L31:
  shll   $0x4,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  or     %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L4:
  cmpl   $0x7,-0xc(%rbp)
  jle    L9
  mov    -0x8(%rbp),%eax
L15:
  leave
  ret
```

assistant: ```c
unsigned int util_hex_to_word(char *p) {
  int val;
  int i;
  unsigned int retval = 0;
  for (i = 0; i < 8; i++) {
    val = util_hex_to_nib(*p);
    if (val < 0)
      return retval;
    retval <<= 4;
    retval |= (val & 0x0f);
    p++;
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<util_hex_to_word>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x8(%rdi),%r12
  mov    $0x0,%ebp
L10:
  movsbl (%rbx),%edi
  call   <util_hex_to_nib@plt>
  test   %eax,%eax
  js     L9
  shl    $0x4,%ebp
  and    $0xf,%eax
  or     %eax,%ebp
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L10
L9:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int util_hex_to_word(char *p) {
  int val;
  int i;
  unsigned int retval = 0;
  for (i = 0; i < 8; i++) {
    val = util_hex_to_nib(*p);
    if (val < 0)
      return retval;
    retval <<= 4;
    retval |= (val & 0x0f);
    p++;
  }
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<util_hex_to_word>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    0x8(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%rbx),%edi
  call   <util_hex_to_nib@plt>
  test   %eax,%eax
  js     L16
  shl    $0x4,%r12d
  and    $0xf,%eax
  add    $0x1,%rbx
  or     %eax,%r12d
  cmp    %rbx,%rbp
  jne    L10
L16:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int util_hex_to_word(char *p) {
  int val;
  int i;
  unsigned int retval = 0;
  for (i = 0; i < 8; i++) {
    val = util_hex_to_nib(*p);
    if (val < 0)
      return retval;
    retval <<= 4;
    retval |= (val & 0x0f);
    p++;
  }
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<util_hex_to_word>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    0x8(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L8:
  movsbl (%rbx),%edi
  call   <util_hex_to_nib@plt>
  test   %eax,%eax
  js     L12
  shl    $0x4,%r12d
  and    $0xf,%eax
  add    $0x1,%rbx
  or     %eax,%r12d
  cmp    %rbp,%rbx
  jne    L8
L12:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int util_hex_to_word(char *p) {
  int val;
  int i;
  unsigned int retval = 0;
  for (i = 0; i < 8; i++) {
    val = util_hex_to_nib(*p);
    if (val < 0)
      return retval;
    retval <<= 4;
    retval |= (val & 0x0f);
    p++;
  }
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getBaseRandom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x5441,-0x14(%rbp)
  movb   $0x43,-0x12(%rbp)
  movw   $0x5441,-0x11(%rbp)
  movb   $0x47,-0xf(%rbp)
  movw   $0x4341,-0xe(%rbp)
  movb   $0x47,-0xc(%rbp)
  movw   $0x4354,-0xb(%rbp)
  movb   $0x47,-0x9(%rbp)
  mov    $0x0,%eax
  call   <new_rand@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rbp,%rax
  add    %rcx,%rax
  sub    $0x14,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  movzbl -0x19(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
char getBaseRandom(int row) {
  char base[4][3] = {{'A', 'T', 'C'}, {'A', 'T', 'G'}, {'A', 'C', 'G'}, {'T', 'C', 'G'}};
  int col = new_rand() % 3;
  char ch = base[row][col];
  return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getBaseRandom>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movw   $0x5441,0xc(%rsp)
  movb   $0x43,0xe(%rsp)
  movw   $0x5441,0xf(%rsp)
  movb   $0x47,0x11(%rsp)
  movw   $0x4341,0x12(%rsp)
  movb   $0x47,0x14(%rsp)
  movw   $0x4354,0x15(%rsp)
  movb   $0x47,0x17(%rsp)
  call   <new_rand@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  cltq
  movslq %ebx,%rbx
  lea    (%rbx,%rbx,2),%rdx
  lea    0x20(%rdx),%rsi
  lea    (%rsp,%rsi,1),%rdx
  movzbl -0x14(%rax,%rdx,1),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getBaseRandom(int row) {
  char base[4][3] = {{'A', 'T', 'C'}, {'A', 'T', 'G'}, {'A', 'C', 'G'}, {'T', 'C', 'G'}};
  int col = new_rand() % 3;
  char ch = base[row][col];
  return ch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getBaseRandom>:
  endbr64
  push   %rbx
  movslq %edi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4341475441435441,%rax
  movl   $0x47435447,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  xor    %eax,%eax
  call   <new_rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  lea    (%rbx,%rbx,2),%rdx
  lea    0x20(%rdx),%rsi
  cltq
  lea    (%rsp,%rsi,1),%rdx
  movzbl -0x14(%rax,%rdx,1),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getBaseRandom(int row) {
  char base[4][3] = {{'A', 'T', 'C'}, {'A', 'T', 'G'}, {'A', 'C', 'G'}, {'T', 'C', 'G'}};
  int col = new_rand() % 3;
  char ch = base[row][col];
  return ch;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getBaseRandom>:
  endbr64
  push   %rbx
  movslq %edi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4341475441435441,%rax
  movl   $0x47435447,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  xor    %eax,%eax
  call   <new_rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  lea    (%rbx,%rbx,2),%rdx
  lea    0x20(%rdx),%rsi
  cltq
  lea    (%rsp,%rsi,1),%rdx
  movzbl -0x14(%rax,%rdx,1),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getBaseRandom(int row) {
  char base[4][3] = {{'A', 'T', 'C'}, {'A', 'T', 'G'}, {'A', 'C', 'G'}, {'T', 'C', 'G'}};
  int col = new_rand() % 3;
  char ch = base[row][col];
  return ch;
}
```