ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L60:
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%eax
  je     L60
  cmp    $0x20,%al
  je     L60
  movb   $0x0,0x1(%rbp)
  mov    %eax,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%ebx
  je     L18
  test   %rax,%rax
  je     L14
L18:
  mov    %ebx,%edi
  call   <isdigit@plt>
  mov    $0x0,%r13d
  test   %rax,%rax
  je     L19
  mov    $0x0,%r12d
  jmp    L27
L98:
  mov    %bl,0x0(%rbp,%r12,1)
L27:
  mov    %r12d,%r13d
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L98
  add    $0x1,%r13d
  movslq %r13d,%rax
  mov    %bl,0x0(%rbp,%rax,1)
L19:
  movslq %r13d,%r12
  cmp    $0x2e,%ebx
  je     L61
L84:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    D8(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L66
  mov    $0x30,%ebx
L14:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L97:
  mov    %bl,0x0(%rbp,%r12,1)
L61:
  mov    %r12d,%r13d
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L97
  add    $0x1,%r13d
  movslq %r13d,%rax
  mov    %bl,0x0(%rbp,%rax,1)
  jmp    L84
L66:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x30,%ebx
  jmp    L14
```

assistant: ```c
int getop(char *s) {
  int getch(void);
  void ungetch(int);
  int i, c;
  while ((*s = c = getch()) == ' ' || c == '\t')
    ;
  *(s + 1) = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  if (isdigit(c)) {
    while (isdigit(c = getch())) {
      *(s + ++i) = c;
    }
    *(s + ++i) = c;
  }
  if (c == '.') {
    while (isdigit(c = getch())) {
      *(s + ++i) = c;
    }
    *(s + ++i) = c;
  }
  *(s + i) = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L96:
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L96
  cmp    $0x20,%al
  je     L96
  movb   $0x0,0x1(%rbx)
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L24
  cmp    $0x2e,%r12d
  je     L35
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  mov    $0x2e,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L97
L83:
  cltq
  lea    0x1(%rbx,%rax,1),%rbx
  jmp    L4
L21:
  mov    %r12b,(%rbx)
  add    $0x1,%rbx
L4:
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L21
  mov    %r12b,(%rbx)
  movb   $0x0,(%rax)
  mov    D6(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L108
L124:
  add    $0x8,%rsp
  mov    $0x30,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %r12d,%edi
  call   <isdigit@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L51
L97:
  mov    %ebx,%r13d
  lea    0x1(%rbx),%rbp
  neg    %r13d
  jmp    L69
  xchg   %ax,%ax
L59:
  add    $0x1,%rbp
L69:
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  mov    %r12b,0x0(%rbp)
  mov    %rax,%r8
  lea    0x0(%r13,%rbp,1),%eax
  test   %r8,%r8
  jne    L59
L51:
  cmp    $0x2e,%r12d
  je     L83
  cltq
  add    %rbx,%rax
  movb   $0x0,(%rax)
  mov    D6(%rip),%rax
  cmp    %r12d,(%rax)
  je     L124
L108:
  mov    %r12d,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getop(char *s) {
  int getch(void);
  void ungetch(int);
  int i, c;
  while ((*s = c = getch()) == ' ' || c == '\t')
    ;
  *(s + 1) = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  if (isdigit(c)) {
    while (isdigit(c = getch())) {
      *(s + ++i) = c;
    }
    *(s + ++i) = c;
  }
  if (c == '.') {
    while (isdigit(c = getch())) {
      *(s + ++i) = c;
    }
    *(s + ++i) = c;
  }
  *(s + i) = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: What is the c source code of the assembly code below:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L90:
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L90
  cmp    $0x20,%al
  je     L90
  movb   $0x0,0x1(%rbx)
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L88
  cmp    $0x2e,%r12d
  je     L23
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x2e,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L21
  xor    %edx,%edx
L37:
  movslq %edx,%rdx
  lea    0x1(%rbx,%rdx,1),%rbx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L123:
  mov    %r12b,(%rbx)
  add    $0x1,%rbx
L13:
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L123
  mov    %r12b,(%rbx)
  movb   $0x0,(%rax)
  mov    D10(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L137
L71:
  add    $0x8,%rsp
  mov    $0x30,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L88:
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L50
L21:
  mov    %ebx,%r13d
  lea    0x1(%rbx),%rbp
  neg    %r13d
  jmp    L125
  nopl   0x0(%rax)
L94:
  mov    %r12b,0x0(%rbp)
  add    $0x1,%rbp
L125:
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  lea    0x0(%r13,%rbp,1),%edx
  mov    %rax,%r8
  mov    %rbp,%rax
  test   %r8,%r8
  jne    L94
  mov    %r12b,0x0(%rbp)
L118:
  cmp    $0x2e,%r12d
  je     L37
  movb   $0x0,(%rax)
  mov    D10(%rip),%rax
  cmp    %r12d,(%rax)
  je     L71
L137:
  mov    %r12d,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  mov    %rbx,%rax
  xor    %edx,%edx
  jmp    L118
```

assistant: ```c
int getop(char *s) {
  int getch(void);
  void ungetch(int);
  int i, c;
  while ((*s = c = getch()) == ' ' || c == '\t')
    ;
  *(s + 1) = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  if (isdigit(c)) {
    while (isdigit(c = getch())) {
      *(s + ++i) = c;
    }
    *(s + ++i) = c;
  }
  if (c == '.') {
    while (isdigit(c = getch())) {
      *(s + ++i) = c;
    }
    *(s + ++i) = c;
  }
  *(s + i) = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L2:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(const char *str) {
  int len = 0;
  while (*str++)
    len++;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strlen>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L7
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L12:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L12
L18:
  mov    %ecx,%eax
  ret
L7:
  mov    $0x0,%ecx
  jmp    L18
```

assistant: ```c
int strlen(const char *str) {
  int len = 0;
  while (*str++)
    len++;
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L5
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L1:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L1
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const char *str) {
  int len = 0;
  while (*str++)
    len++;
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L10
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L12:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L12
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const char *str) {
  int len = 0;
  while (*str++)
    len++;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solcon_write_solution_banner_to_defined_output_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x8b,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solcon_write_solution_banner_to_defined_output_file(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(139, a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<solcon_write_solution_banner_to_defined_output_file>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x8b,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int solcon_write_solution_banner_to_defined_output_file(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(139, a, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solcon_write_solution_banner_to_defined_output_file>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x8b,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int solcon_write_solution_banner_to_defined_output_file(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(139, a, b, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<solcon_write_solution_banner_to_defined_output_file>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x8b,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int solcon_write_solution_banner_to_defined_output_file(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(139, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trimWhiteSpace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L30
  lea    D5(%rip),%rax
  jmp    L14
L30:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L50
L65:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L70
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L27
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L70
L27:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L70:
  addq   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L5
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
L5:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: 

assistant: ```c
char *trimWhiteSpace(char *content) {
  if (!strlen(content))
    return "";
  char *wrPtr;
  char *rdPtr;
  for (rdPtr = wrPtr = content; *rdPtr != 0 && *(rdPtr + 1) != 0; rdPtr++)
    if (*rdPtr != '\t')
      if ((*rdPtr != '\n') || (*(rdPtr + 1) != '\n'))
        *(wrPtr++) = *(rdPtr);
  wrPtr += 1;
  *wrPtr = '\0';
  return content;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trimWhiteSpace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  lea    D2(%rip),%rax
  test   %edx,%edx
  je     L42
  movzbl (%rbx),%eax
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  test   %al,%al
  jne    L9
L63:
  movb   $0x0,0x1(%rsi)
  mov    %rbx,%rax
L42:
  pop    %rbx
  ret
L29:
  mov    %al,(%rsi)
  lea    0x1(%rsi),%rsi
L46:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L63
L9:
  movzbl 0x1(%rdx),%ecx
  test   %cl,%cl
  je     L63
  cmp    $0x9,%al
  je     L46
  cmp    $0xa,%cl
  jne    L29
  cmp    $0xa,%al
  jne    L29
  jmp    L46
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: 

assistant: ```c
char *trimWhiteSpace(char *content) {
  if (!strlen(content))
    return "";
  char *wrPtr;
  char *rdPtr;
  for (rdPtr = wrPtr = content; *rdPtr != 0 && *(rdPtr + 1) != 0; rdPtr++)
    if (*rdPtr != '\t')
      if ((*rdPtr != '\n') || (*(rdPtr + 1) != '\n'))
        *(wrPtr++) = *(rdPtr);
  wrPtr += 1;
  *wrPtr = '\0';
  return content;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trimWhiteSpace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  lea    D9(%rip),%rax
  test   %r8d,%r8d
  je     L15
  movzbl (%rbx),%edx
  mov    %rbx,%rax
  mov    %rbx,%rsi
  mov    %rbx,%rcx
  test   %dl,%dl
  je     L67
L42:
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L75
L47:
  cmp    $0x9,%dl
  je     L54
L38:
  cmp    $0xa,%cl
  jne    L43
  cmp    $0xa,%dl
  je     L89
L43:
  mov    %dl,(%rsi)
  movzbl 0x1(%rax),%edx
  lea    0x1(%rsi),%rcx
  add    $0x1,%rax
  test   %dl,%dl
  je     L67
  mov    %rcx,%rsi
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  jne    L47
L75:
  mov    %rsi,%rcx
L67:
  movb   $0x0,0x1(%rcx)
  mov    %rbx,%rax
L15:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L54:
  add    $0x1,%rax
  mov    %ecx,%edx
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L89:
  movzbl 0x2(%rax),%ecx
  add    $0x1,%rax
  mov    $0xa,%edx
  test   %cl,%cl
  jne    L38
  jmp    L75
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: 

assistant: ```c
char *trimWhiteSpace(char *content) {
  if (!strlen(content))
    return "";
  char *wrPtr;
  char *rdPtr;
  for (rdPtr = wrPtr = content; *rdPtr != 0 && *(rdPtr + 1) != 0; rdPtr++)
    if (*rdPtr != '\t')
      if ((*rdPtr != '\n') || (*(rdPtr + 1) != '\n'))
        *(wrPtr++) = *(rdPtr);
  wrPtr += 1;
  *wrPtr = '\0';
  return content;
}
```
user: What is the c source code of the assembly code below?

```asm
<trimWhiteSpace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  lea    D7(%rip),%rax
  test   %r8d,%r8d
  je     L31
  movzbl (%rbx),%edx
  mov    %rbx,%rax
  mov    %rbx,%rsi
  mov    %rbx,%rcx
  test   %dl,%dl
  je     L78
L106:
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L61
L70:
  cmp    $0x9,%dl
  je     L0
L28:
  cmp    $0xa,%cl
  jne    L91
  cmp    $0xa,%dl
  je     L93
L91:
  mov    %dl,(%rsi)
  movzbl 0x1(%rax),%edx
  lea    0x1(%rsi),%rcx
  add    $0x1,%rax
  test   %dl,%dl
  je     L78
  mov    %rcx,%rsi
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  jne    L70
L61:
  mov    %rsi,%rcx
L78:
  movb   $0x0,0x1(%rcx)
  mov    %rbx,%rax
L31:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  add    $0x1,%rax
  mov    %ecx,%edx
  jmp    L106
  nopl   0x0(%rax,%rax,1)
L93:
  movzbl 0x2(%rax),%ecx
  add    $0x1,%rax
  mov    $0xa,%edx
  test   %cl,%cl
  jne    L28
  jmp    L61
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: 

assistant: ```c
char *trimWhiteSpace(char *content) {
  if (!strlen(content))
    return "";
  char *wrPtr;
  char *rdPtr;
  for (rdPtr = wrPtr = content; *rdPtr != 0 && *(rdPtr + 1) != 0; rdPtr++)
    if (*rdPtr != '\t')
      if ((*rdPtr != '\n') || (*(rdPtr + 1) != '\n'))
        *(wrPtr++) = *(rdPtr);
  wrPtr += 1;
  *wrPtr = '\0';
  return content;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    0x25b549f7(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 0xffffffffda4ab609UL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x251b553c,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 0xffffffffda4ab609UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x251b553c,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 0xffffffffda4ab609UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x251b553c,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 0xffffffffda4ab609UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<LE32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  shll   $0x8,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  shll   $0x8,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x10,%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  movzbl %al,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int LE32(unsigned int x) {
  unsigned int n = (unsigned char)x;
  n <<= 8;
  n |= (unsigned char)(x >> 8);
  n <<= 8;
  n |= (unsigned char)(x >> 16);
  return (n << 8) | (unsigned char)(x >> 24);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<LE32>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  shl    $0x8,%eax
  movzwl %ax,%eax
  movzbl %dh,%ecx
  or     %eax,%ecx
  shl    $0x8,%ecx
  mov    %edi,%eax
  shr    $0x10,%eax
  movzbl %al,%eax
  or     %ecx,%eax
  shl    $0x8,%eax
  shr    $0x18,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int LE32(unsigned int x) {
  unsigned int n = (unsigned char)x;
  n <<= 8;
  n |= (unsigned char)(x >> 8);
  n <<= 8;
  n |= (unsigned char)(x >> 16);
  return (n << 8) | (unsigned char)(x >> 24);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LE32>:
  endbr64
  mov    %edi,%eax
  bswap  %eax
  ret
```

assistant: ```c
unsigned int LE32(unsigned int x) {
  unsigned int n = (unsigned char)x;
  n <<= 8;
  n |= (unsigned char)(x >> 8);
  n <<= 8;
  n |= (unsigned char)(x >> 16);
  return (n << 8) | (unsigned char)(x >> 24);
}
```
user: What is the c source code of the assembly code below?

```asm
<LE32>:
  endbr64
  mov    %edi,%eax
  bswap  %eax
  ret
```

assistant: ```c
unsigned int LE32(unsigned int x) {
  unsigned int n = (unsigned char)x;
  n <<= 8;
  n |= (unsigned char)(x >> 8);
  n <<= 8;
  n |= (unsigned char)(x >> 16);
  return (n << 8) | (unsigned char)(x >> 24);
}
```
user: Translate the below assembly code into C programming language:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L90:
  cmp    %rdx,%rsp
  je     L81
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L90
L81:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L17
  orq    $0x0,-0x8(%rsp,%rax,1)
L17:
  mov    %rsp,%r12
  test   %r13d,%r13d
  jle    L3
  mov    %r13d,%edx
  mov    $0x0,%eax
L24:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L24
L3:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r14d,%r14d
  jle    L39
  mov    $0x0,%ebx
L28:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <stdlib_strided_smediansorted@plt>
  ucomiss %xmm0,%xmm0
  jp     L56
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jne    L28
L39:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L89:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L56:
  lea    D3(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L89
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = i;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_smediansorted(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```