ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_ram_size>:
  endbr64
  push   %rbp
  mov    %rsi,%r11
  mov    %rsi,%rax
  push   %rbx
  shr    $0x3,%r11
  sub    $0x118,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x108(%rsp)
  xor    %edx,%edx
  mov    %rsi,%rdx
  shr    $0x4,%rdx
  je     L108
  mov    $0x1,%esi
  mov    %rsp,%r10
  nop
L80:
  lea    (%rdi,%rdx,8),%r8
  mov    %esi,%ecx
  mov    (%r8),%r9
  mov    %r9,-0x8(%r10,%rsi,8)
  mov    %rdx,%r9
  add    $0x1,%rsi
  sar    %rdx
  not    %r9
  mov    %r9,(%r8)
  jne    L80
L69:
  mov    (%rdi),%rdx
  movq   $0x0,(%rdi)
  movslq %ecx,%rsi
  mov    (%rdi),%r8
  mov    %rdx,(%rsp,%rsi,8)
  test   %r8,%r8
  jne    L87
  cmp    $0x1,%r11
  jbe    L90
  sub    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rsp,%r10
  movslq %ecx,%rcx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L58:
  sub    $0x1,%rcx
  cmp    %rdx,%r11
  jbe    L90
L24:
  mov    (%r10,%rcx,8),%rbx
  lea    0x0(,%rsi,8),%r8
  movslq %ecx,%rbp
  lea    (%rdi,%r8,1),%rsi
  mov    (%rsi),%r9
  mov    %rbx,(%rsi)
  mov    %rdx,%rbx
  add    %rdx,%rdx
  not    %rbx
  mov    %rdx,%rsi
  cmp    %r9,%rbx
  je     L58
  mov    %r8,%rax
  cmp    %rdx,%r11
  jbe    L90
  lea    (%r10,%rbp,8),%rcx
  nop
L111:
  mov    -0x8(%rcx),%r8
  lea    (%rdi,%rdx,8),%rsi
  add    %rdx,%rdx
  sub    $0x8,%rcx
  mov    %r8,(%rsi)
  cmp    %rdx,%r11
  ja     L111
L90:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L87:
  mov    %rdx,(%rdi)
  cmp    $0x1,%r11
  jbe    L107
  lea    (%rsp,%rsi,8),%rdx
  mov    $0x1,%eax
  mov    $0x1,%ecx
  nop
L67:
  mov    -0x8(%rdx),%rsi
  lea    (%rdi,%rcx,8),%rcx
  add    %rax,%rax
  sub    $0x8,%rdx
  mov    %rsi,(%rcx)
  mov    %rax,%rcx
  cmp    %rax,%r11
  ja     L67
L107:
  xor    %eax,%eax
  jmp    L90
  xchg   %ax,%ax
L108:
  xor    %ecx,%ecx
  jmp    L69
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_ram_size(volatile long *base, long maxsize) {
  volatile long *addr;
  long save[32];
  long cnt;
  long val;
  long size;
  int i = 0;
  for (cnt = (maxsize / sizeof(long)) >> 1; cnt > 0; cnt >>= 1) {
    addr = base + cnt;
    save[i++] = *addr;
    *addr = ~cnt;
  }
  addr = base;
  save[i] = *addr;
  *addr = 0;
  if ((val = *addr) != 0) {
    *addr = save[i];
    for (cnt = 1; cnt < maxsize / sizeof(long); cnt <<= 1) {
      addr = base + cnt;
      *addr = save[--i];
    }
    return (0);
  }
  for (cnt = 1; cnt < maxsize / sizeof(long); cnt <<= 1) {
    addr = base + cnt;
    val = *addr;
    *addr = save[--i];
    if (val != ~cnt) {
      size = cnt * sizeof(long);
      for (cnt <<= 1; cnt < maxsize / sizeof(long); cnt <<= 1) {
        addr = base + cnt;
        *addr = save[--i];
      }
      return (size);
    }
  }
  return (maxsize);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_password>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %edx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x28(%rbp),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%edx
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    D37(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  jmp    L5
L20:
  mov    -0x4c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x38(%rbp)
  jge    L5
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    -0x34(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x50(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L5:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0xa,-0x34(%rbp)
  je     L30
  cmpl   $0xd,-0x34(%rbp)
  jne    L20
L30:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    -0x38(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int get_password(char buf[], int maxlen, int star) {
  struct termios ttystate, orig;
  int c;
  int pos = 0;
  tcgetattr(0, &ttystate);
  orig = ttystate;
  ttystate.c_lflag &= ~ICANON;
  ttystate.c_lflag &= ~ECHO;
  ttystate.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &ttystate);
  while ((c = getchar()) != '\n' && c != '\r') {
    if (pos < maxlen - 1) {
      buf[pos++] = c;
      putchar(star);
    }
  }
  buf[pos] = '\0';
  tcsetattr(0, TCSANOW, &orig);
  return pos;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_password>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  movdqa (%rsp),%xmm0
  movaps %xmm0,0x10(%rsp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    D19(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x8(%rsp)
  mov    D39(%rip),%rax
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    %rbp,%rdx
  mov    D43(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%ebp
  sub    $0x1,%ebx
L28:
  mov    %ebp,%r13d
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xd,%eax
  je     L8
  cmp    $0xa,%eax
  je     L8
  cmp    %ebp,%ebx
  jle    L9
  mov    %al,(%r12,%rbp,1)
  mov    %r14d,%edi
  call   <putchar@plt>
  add    $0x1,%rbp
  jmp    L28
L8:
  movslq %r13d,%rax
  movb   $0x0,(%r12,%rax,1)
  lea    0x10(%rsp),%rdx
  mov    D43(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    %r13d,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_password(char buf[], int maxlen, int star) {
  struct termios ttystate, orig;
  int c;
  int pos = 0;
  tcgetattr(0, &ttystate);
  orig = ttystate;
  ttystate.c_lflag &= ~ICANON;
  ttystate.c_lflag &= ~ECHO;
  ttystate.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &ttystate);
  while ((c = getchar()) != '\n' && c != '\r') {
    if (pos < maxlen - 1) {
      buf[pos++] = c;
      putchar(star);
    }
  }
  buf[pos] = '\0';
  tcsetattr(0, TCSANOW, &orig);
  return pos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_password>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    D35(%rip),%rdx
  xor    %edi,%edi
  mov    D24(%rip),%rax
  movdqa (%rsp),%xmm0
  mov    D7(%rip),%r15
  mov    (%rax),%eax
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x8(%rsp)
  mov    D25(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    (%r15),%esi
  mov    %r13,%rdx
  call   <tcsetattr@plt>
L13:
  mov    %ebp,%r13d
  jmp    L19
  nopl   0x0(%rax)
L28:
  cmp    $0xd,%eax
  je     L40
  cmp    %ebp,%ebx
  jg     L52
L19:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L28
L40:
  movslq %r13d,%rax
  xor    %edi,%edi
  lea    0x10(%rsp),%rdx
  movb   $0x0,(%r12,%rax,1)
  mov    (%r15),%esi
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x38,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L52:
  mov    %al,(%r12,%rbp,1)
  mov    %r14d,%edi
  add    $0x1,%rbp
  call   <putchar@plt>
  jmp    L13
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_password(char buf[], int maxlen, int star) {
  struct termios ttystate, orig;
  int c;
  int pos = 0;
  tcgetattr(0, &ttystate);
  orig = ttystate;
  ttystate.c_lflag &= ~ICANON;
  ttystate.c_lflag &= ~ECHO;
  ttystate.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &ttystate);
  while ((c = getchar()) != '\n' && c != '\r') {
    if (pos < maxlen - 1) {
      buf[pos++] = c;
      putchar(star);
    }
  }
  buf[pos] = '\0';
  tcsetattr(0, TCSANOW, &orig);
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_password>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rsi
  call   <tcgetattr@plt>
  mov    D33(%rip),%rdx
  xor    %edi,%edi
  mov    D28(%rip),%rax
  movdqa (%rsp),%xmm0
  mov    D18(%rip),%r13
  mov    (%rax),%eax
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x8(%rsp)
  mov    D15(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    0x0(%r13),%esi
  mov    %r14,%rdx
  call   <tcsetattr@plt>
L54:
  mov    %r15d,%r14d
  cmp    %r15d,%ebx
  jle    L69
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L24:
  cmp    $0xa,%eax
  je     L50
L69:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xd,%eax
  jne    L24
L50:
  movslq %r14d,%rax
  xor    %edi,%edi
  lea    0x10(%rsp),%rdx
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    0x0(%r13),%esi
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L50
  cmp    $0xd,%eax
  je     L50
  mov    %al,0x0(%rbp,%r15,1)
  mov    %r12d,%edi
  add    $0x1,%r15
  call   <putchar@plt>
  jmp    L54
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_password(char buf[], int maxlen, int star) {
  struct termios ttystate, orig;
  int c;
  int pos = 0;
  tcgetattr(0, &ttystate);
  orig = ttystate;
  ttystate.c_lflag &= ~ICANON;
  ttystate.c_lflag &= ~ECHO;
  ttystate.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &ttystate);
  while ((c = getchar()) != '\n' && c != '\r') {
    if (pos < maxlen - 1) {
      buf[pos++] = c;
      putchar(star);
    }
  }
  buf[pos] = '\0';
  tcsetattr(0, TCSANOW, &orig);
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<must_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <must_fail@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: strdup

assistant: ```c
char *must_strdup(const char *s) {
  char *dup = strdup(s);
  if (!dup)
    must_fail("strdup", strlen(s));
  return dup;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<must_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L17:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <must_fail@plt>
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: strdup

assistant: ```c
char *must_strdup(const char *s) {
  char *dup = strdup(s);
  if (!dup)
    must_fail("strdup", strlen(s));
  return dup;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<must_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <must_fail@plt>
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string

tool: D3: strdup

assistant: ```c
char *must_strdup(const char *s) {
  char *dup = strdup(s);
  if (!dup)
    must_fail("strdup", strlen(s));
  return dup;
}
```
user: Translate the below assembly code into C programming language:

```asm
<must_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <must_fail@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: strdup

assistant: ```c
char *must_strdup(const char *s) {
  char *dup = strdup(s);
  if (!dup)
    must_fail("strdup", strlen(s));
  return dup;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D0
type_infered: string

tool: D12: %d


tool: D0: %u


assistant: ```c
int main() {
  int i = 5;
  int *ip = &i;
  printf("%d\n", *ip);
  printf("%u\n", ip);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  mov    $0x5,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
data_type: string
name: unpack_data
arguments: data_label: D8
data_type: string

tool: D12: %d


tool: D8: %u


assistant: ```c
int main() {
  int i = 5;
  int *ip = &i;
  printf("%d\n", *ip);
  printf("%u\n", ip);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x5,%esi
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string
name: read_data
arguments: data_tag: D17
type_infered: string

tool: D0: %d


tool: D17: %u


assistant: ```c
int main() {
  int i = 5;
  int *ip = &i;
  printf("%d\n", *ip);
  printf("%u\n", ip);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x5,%esi
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D14
data_type: string

tool: D2: %d


tool: D14: %u


assistant: ```c
int main() {
  int i = 5;
  int *ip = &i;
  printf("%d\n", *ip);
  printf("%u\n", ip);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_dimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jg     L64
  mov    $0x0,%eax
  jmp    L97
L64:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <test_dimer@plt>
  test   %rax,%rax
  je     L34
  mov    $0x1,%eax
  jmp    L97
L34:
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L32:
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <test_dimer@plt>
  test   %rax,%rax
  je     L42
  mov    $0x1,%eax
  jmp    L97
L42:
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <test_dimer@plt>
  test   %rax,%rax
  je     L38
  mov    $0x1,%eax
  jmp    L97
L38:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L32
  mov    $0x0,%eax
L97:
  leave
  ret
```

assistant: ```c
int check_dimer(char *p1, char *p2, int n) {
  int i;
  if (n < 3)
    return 0;
  if (test_dimer(p1, p2, n))
    return 1;
  for (i = 1; i < n; i++) {
    if (test_dimer(p1 + i, p2, n - i))
      return 1;
    if (test_dimer(p1, p2 + i, n - i))
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_dimer>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x2,%edx
  jg     L49
  ret
L49:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  call   <test_dimer@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L62
  mov    %r14d,%r15d
  mov    $0x1,%ebx
L53:
  mov    %r14d,%r13d
  sub    %ebx,%r13d
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r13d,%edx
  mov    %r12,%rsi
  call   <test_dimer@plt>
  test   %rax,%rax
  jne    L39
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <test_dimer@plt>
  test   %rax,%rax
  jne    L35
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L53
  jmp    L62
L39:
  mov    $0x1,%eax
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    $0x1,%eax
  jmp    L62
```

assistant: ```c
int check_dimer(char *p1, char *p2, int n) {
  int i;
  if (n < 3)
    return 0;
  if (test_dimer(p1, p2, n))
    return 1;
  for (i = 1; i < n; i++) {
    if (test_dimer(p1 + i, p2, n - i))
      return 1;
    if (test_dimer(p1, p2 + i, n - i))
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_dimer>:
  endbr64
  cmp    $0x2,%edx
  jg     L4
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L4:
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  movslq %r14d,%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <test_dimer@plt>
  test   %rax,%rax
  jne    L8
  nopl   0x0(%rax)
L47:
  mov    %r14d,%r13d
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  sub    %ebx,%r13d
  mov    %r13d,%edx
  call   <test_dimer@plt>
  test   %rax,%rax
  jne    L8
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <test_dimer@plt>
  test   %rax,%rax
  jne    L8
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L47
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int check_dimer(char *p1, char *p2, int n) {
  int i;
  if (n < 3)
    return 0;
  if (test_dimer(p1, p2, n))
    return 1;
  for (i = 1; i < n; i++) {
    if (test_dimer(p1 + i, p2, n - i))
      return 1;
    if (test_dimer(p1, p2 + i, n - i))
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_dimer>:
  endbr64
  cmp    $0x2,%edx
  jg     L43
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L43:
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  movslq %r14d,%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <test_dimer@plt>
  test   %rax,%rax
  jne    L39
  nopl   0x0(%rax)
L47:
  mov    %r14d,%r13d
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  sub    %ebx,%r13d
  mov    %r13d,%edx
  call   <test_dimer@plt>
  test   %rax,%rax
  jne    L39
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <test_dimer@plt>
  test   %rax,%rax
  jne    L39
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L47
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L39:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int check_dimer(char *p1, char *p2, int n) {
  int i;
  if (n < 3)
    return 0;
  if (test_dimer(p1, p2, n))
    return 1;
  for (i = 1; i < n; i++) {
    if (test_dimer(p1 + i, p2, n - i))
      return 1;
    if (test_dimer(p1, p2 + i, n - i))
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vbi_strndup_iconv_caption>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L24
L15:
  cmpq   $0x0,-0x18(%rbp)
  jns    L12
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
L12:
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %esi,%r8d
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <vbi_strndup_iconv@plt>
  cltq
L24:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: EIA-608

assistant: ```c
char *vbi_strndup_iconv_caption(const char *dst_codeset, const char *src, long src_length, int repl_char) {
  if (((void *)0) == src)
    return ((void *)0);
  if (src_length < 0)
    src_length = strlen(src);
  return vbi_strndup_iconv(dst_codeset, "EIA-608", src, src_length, repl_char);
}
```