ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_add_timespec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  mov    %rsp,%r12
  lea    0x10(%rsp),%rbp
  mov    D27(%rip),%rax
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  mov    D39(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <timespec_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1e,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    D8(%rip),%rbx
  mov    D9(%rip),%rax
  mov    %rbx,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <timespec_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbx,(%rsp)
  mov    %rbx,0x8(%rsp)
  call   <timespec_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x3b9ac9fe,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D39
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D8
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D9
type_guessed: byte[8]

tool: {"D27": [0x01,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D39": [0x02,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: {"D8": [0x01,0x00,0x00,0x00,0xff,0xc9,0x9a,0x3b]}

tool: {"D9": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
void test_add_timespec(void) {
  struct timespec a;
  struct timespec b;
  struct timespec c;
  a.tv_sec = 1;
  a.tv_nsec = 10;
  ;
  b.tv_sec = 2;
  b.tv_nsec = 20;
  ;
  timespec_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_nsec == 30);
  ;
  a.tv_sec = 1;
  a.tv_nsec = 999999999;
  ;
  b.tv_sec = 1;
  b.tv_nsec = 2;
  ;
  timespec_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_nsec == 1);
  ;
  a.tv_sec = 1;
  a.tv_nsec = 999999999;
  ;
  b.tv_sec = 1;
  b.tv_nsec = 999999999;
  ;
  timespec_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_nsec == 999999998);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_msgtype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x18,%eax
  cmp    $0x18,%eax
  jne    L15
  mov    $0x18,%eax
  jmp    L18
L15:
  mov    -0x4(%rbp),%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t get_msgtype(uint8_t first_byte) {
  uint8_t x = first_byte >> 3;
  if ((x & 0x18) == 0x18) {
    return 24;
  } else {
    return x;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_msgtype>:
  endbr64
  mov    %edi,%eax
  sar    $0x3,%eax
  and    $0x18,%eax
  sar    $0x3,%edi
  cmp    $0x18,%eax
  cmovne %edi,%eax
  ret
```

assistant: ```c
uint8_t get_msgtype(uint8_t first_byte) {
  uint8_t x = first_byte >> 3;
  if ((x & 0x18) == 0x18) {
    return 24;
  } else {
    return x;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_msgtype>:
  endbr64
  mov    %edi,%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  and    $0x18,%edx
  cmp    $0x18,%edx
  mov    $0x18,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
uint8_t get_msgtype(uint8_t first_byte) {
  uint8_t x = first_byte >> 3;
  if ((x & 0x18) == 0x18) {
    return 24;
  } else {
    return x;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_msgtype>:
  endbr64
  mov    %edi,%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  and    $0x18,%edx
  cmp    $0x18,%edx
  mov    $0x18,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
uint8_t get_msgtype(uint8_t first_byte) {
  uint8_t x = first_byte >> 3;
  if ((x & 0x18) == 0x18) {
    return 24;
  } else {
    return x;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L4:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x1,-0x14(%rbp)
  jg     L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fact(int n) {
  int f;
  for (f = 1; n > 1; n--)
    f *= n;
  return f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fact>:
  endbr64
  cmp    $0x1,%edi
  jle    L0
  mov    $0x1,%eax
L9:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L9
  ret
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fact(int n) {
  int f;
  for (f = 1; n > 1; n--)
    f *= n;
  return f;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L3
  xchg   %ax,%ax
L7:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L7
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
int fact(int n) {
  int f;
  for (f = 1; n > 1; n--)
    f *= n;
  return f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L5
  xchg   %ax,%ax
L1:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L1
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
int fact(int n) {
  int f;
  for (f = 1; n > 1; n--)
    f *= n;
  return f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toedit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L9
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <printi@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <prints@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5:  files to edit; 

assistant: ```c
toedit(int count) {
  if (count > 1) {
    printi(count);
    prints(" files to edit; ");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<toedit>:
  endbr64
  cmp    $0x1,%edi
  jg     L1
  ret
L1:
  sub    $0x8,%rsp
  call   <printi@plt>
  lea    D6(%rip),%rdi
  call   <prints@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string

tool: D6:  files to edit; 

assistant: ```c
toedit(int count) {
  if (count > 1) {
    printi(count);
    prints(" files to edit; ");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<toedit>:
  endbr64
  cmp    $0x1,%edi
  jg     L6
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  sub    $0x8,%rsp
  call   <printi@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <prints@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string

tool: D1:  files to edit; 

assistant: ```c
toedit(int count) {
  if (count > 1) {
    printi(count);
    prints(" files to edit; ");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<toedit>:
  endbr64
  cmp    $0x1,%edi
  jg     L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  sub    $0x8,%rsp
  call   <printi@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <prints@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1:  files to edit; 

assistant: ```c
toedit(int count) {
  if (count > 1) {
    printi(count);
    prints(" files to edit; ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f2m_Add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L3
L5:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x30(%rbp),%rax
  add    %rsi,%rax
  xor    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f2m_Add(uint32_t t, uint32_t *A, uint32_t *B, uint32_t *C) {
  uint32_t i;
  for (i = 0; i < t; i++) {
    C[i] = A[i] ^ B[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f2m_Add>:
  endbr64
  test   %rdi,%rdi
  je     L1
  mov    $0x0,%eax
L12:
  mov    (%rsi,%rax,8),%r8
  xor    (%rdx,%rax,8),%r8
  mov    %r8,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L12
L1:
  ret
```

assistant: ```c
void f2m_Add(uint32_t t, uint32_t *A, uint32_t *B, uint32_t *C) {
  uint32_t i;
  for (i = 0; i < t; i++) {
    C[i] = A[i] ^ B[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f2m_Add>:
  endbr64
  test   %rdi,%rdi
  je     L3
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rax,8),%r8
  xor    (%rdx,%rax,8),%r8
  mov    %r8,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L6
L3:
  ret
```

assistant: ```c
void f2m_Add(uint32_t t, uint32_t *A, uint32_t *B, uint32_t *C) {
  uint32_t i;
  for (i = 0; i < t; i++) {
    C[i] = A[i] ^ B[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f2m_Add>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  test   %r8,%r8
  je     L11
  lea    0x8(%rdi),%rax
  cmp    %rax,%rcx
  lea    0x8(%rsi),%rax
  setne  %cl
  cmp    %rax,%rdx
  setne  %al
  test   %al,%cl
  je     L58
  lea    -0x1(%r8),%rax
  cmp    $0x1,%rax
  jbe    L58
  mov    %r8,%rcx
  xor    %eax,%eax
  shr    %rcx
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L13:
  movdqu (%rsi,%rax,1),%xmm0
  movdqu (%rdi,%rax,1),%xmm1
  pxor   %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L13
  mov    %r8,%rcx
  and    $0xfffffffffffffffe,%rcx
  and    $0x1,%r8d
  je     L11
  mov    (%rsi,%rcx,8),%rax
  xor    (%rdi,%rcx,8),%rax
  mov    %rax,(%rdx,%rcx,8)
  ret
  nopl   (%rax)
L58:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%rsi,%rax,8),%rcx
  xor    (%rdi,%rax,8),%rcx
  mov    %rcx,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L4
L11:
  ret
```

assistant: ```c
void f2m_Add(uint32_t t, uint32_t *A, uint32_t *B, uint32_t *C) {
  uint32_t i;
  for (i = 0; i < t; i++) {
    C[i] = A[i] ^ B[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jle    L9
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  movsbq %al,%rcx
  mov    0x10(%rsi),%rdx
  movzbl (%rdx),%edx
  movsbq %dl,%r11
  or     %dl,%al
  je     L58
  mov    %rsp,%rdi
  mov    $0x0,%r9d
  mov    $0x0,%ebx
  movabs $0x6666666666666667,%r8
L31:
  mov    %rcx,%rax
  imul   %r8
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    (%rsi,%rsi,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %r11,%rax
  imul   %r8
  sar    $0x2,%rdx
  mov    %r11,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r11
  lea    (%rcx,%r11,1),%rax
  movslq %r9d,%r9
  add    %r9,%rax
  mov    %ebx,%r10d
  add    $0x1,%ebx
  mov    %rax,%r9
  shr    $0x3f,%r9
  lea    (%rax,%r9,1),%rcx
  and    $0x1,%ecx
  sub    %r9,%rcx
  mov    %ecx,(%rdi)
  add    %r9,%rax
  sar    %rax
  mov    %eax,%r9d
  mov    %rsi,%rcx
  mov    %rdx,%r11
  add    $0x4,%rdi
  or     %rsi,%rdx
  jne    L31
  test   %eax,%eax
  je     L26
  movslq %ebx,%rbx
  mov    %eax,(%rsp,%rbx,4)
  lea    0x2(%r10),%ebx
L26:
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L25
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%rsp,%rax,1),%rbp
  lea    -0x4(%rsp,%rax,1),%rax
  lea    -0x1(%rbx),%edx
  shl    $0x2,%rdx
  sub    %rdx,%rax
  mov    %rax,%rbx
  lea    D1(%rip),%r12
L42:
  mov    -0x4(%rbp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x4,%rbp
  cmp    %rbx,%rbp
  jne    L42
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
L9:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D17
datatype: string
name: read_data
arguments: label: D1
datatype: string

tool: D17: Sum of two binary numbers: 

tool: D1: %d

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    return 1;
  long int binary1, binary2;
  int i = 0, remainder = 0, sum[20];
  binary1 = (long int)argv[1][0];
  binary2 = (long int)argv[2][0];
  while (binary1 != 0 || binary2 != 0) {
    sum[i++] = (binary1 % 10 + binary2 % 10 + remainder) % 2;
    remainder = (binary1 % 10 + binary2 % 10 + remainder) / 2;
    binary1 = binary1 / 10;
    binary2 = binary2 / 10;
  }
  if (remainder != 0)
    sum[i++] = remainder;
  --i;
  printf("Sum of two binary numbers: ");
  while (i >= 0)
    printf("%d", sum[i--]);
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jle    L35
  mov    0x8(%rsi),%rax
  mov    0x10(%rsi),%rdx
  movsbq (%rax),%r9
  movsbq (%rdx),%r11
  mov    %r9,%rax
  or     %r11b,%al
  je     L57
  mov    %rsp,%rbp
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  movabs $0x6666666666666667,%r8
  mov    %rbp,%rdi
  nopl   0x0(%rax,%rax,1)
L44:
  mov    %r9,%rax
  mov    %ebx,%r10d
  add    $0x4,%rdi
  add    $0x1,%ebx
  imul   %r8
  mov    %r9,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rax
  add    %rax,%rax
  sub    %rax,%r9
  mov    %r11,%rax
  imul   %r8
  mov    %r11,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r11
  lea    (%r9,%r11,1),%rax
  mov    %rdx,%r11
  add    %r12,%rax
  mov    %rax,%r9
  shr    $0x3f,%r9
  lea    (%rax,%r9,1),%rsi
  and    $0x1,%esi
  sub    %r9,%rsi
  mov    %esi,-0x4(%rdi)
  mov    %r9,%rsi
  mov    %rcx,%r9
  add    %rax,%rsi
  mov    %rcx,%rax
  sar    %rsi
  or     %rdx,%rax
  movslq %esi,%r12
  jne    L44
  test   %r12d,%r12d
  je     L25
  movslq %ebx,%rbx
  mov    %esi,(%rsp,%rbx,4)
  lea    0x2(%r10),%ebx
L25:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  lea    -0x1(%rbx),%edx
  shl    $0x2,%rax
  shl    $0x2,%rdx
  lea    0x0(%rbp,%rax,1),%r12
  lea    -0x4(%rbp,%rax,1),%rax
  sub    %rdx,%rax
  lea    D25(%rip),%rbp
  mov    %rax,%rbx
L46:
  mov    -0x4(%r12),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  sub    $0x4,%r12
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L46
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
L35:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L10
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D23
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string

tool: D23: Sum of two binary numbers: 

tool: D25: %d

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    return 1;
  long int binary1, binary2;
  int i = 0, remainder = 0, sum[20];
  binary1 = (long int)argv[1][0];
  binary2 = (long int)argv[2][0];
  while (binary1 != 0 || binary2 != 0) {
    sum[i++] = (binary1 % 10 + binary2 % 10 + remainder) % 2;
    remainder = (binary1 % 10 + binary2 % 10 + remainder) / 2;
    binary1 = binary1 / 10;
    binary2 = binary2 / 10;
  }
  if (remainder != 0)
    sum[i++] = remainder;
  --i;
  printf("Sum of two binary numbers: ");
  while (i >= 0)
    printf("%d", sum[i--]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jle    L3
  mov    0x8(%rsi),%rax
  mov    0x10(%rsi),%rdx
  movsbq (%rax),%r9
  movsbq (%rdx),%r11
  mov    %r9,%rax
  or     %r11b,%al
  je     L46
  mov    %rsp,%rbp
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  movabs $0x6666666666666667,%r8
  mov    %rbp,%rdi
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r9,%rax
  mov    %ebx,%r10d
  add    $0x4,%rdi
  add    $0x1,%ebx
  imul   %r8
  mov    %r9,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rax
  add    %rax,%rax
  sub    %rax,%r9
  mov    %r11,%rax
  imul   %r8
  mov    %r11,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r11
  lea    (%r9,%r11,1),%rax
  mov    %rdx,%r11
  add    %r12,%rax
  mov    %rax,%r9
  shr    $0x3f,%r9
  lea    (%rax,%r9,1),%rsi
  and    $0x1,%esi
  sub    %r9,%rsi
  mov    %esi,-0x4(%rdi)
  mov    %r9,%rsi
  mov    %rcx,%r9
  add    %rax,%rsi
  mov    %rcx,%rax
  sar    %rsi
  or     %rdx,%rax
  movslq %esi,%r12
  jne    L29
  test   %r12d,%r12d
  je     L41
  movslq %ebx,%rbx
  mov    %esi,(%rsp,%rbx,4)
  lea    0x2(%r10),%ebx
L41:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  lea    -0x1(%rbx),%edx
  shl    $0x2,%rax
  shl    $0x2,%rdx
  lea    0x0(%rbp,%rax,1),%r12
  lea    -0x4(%rbp,%rax,1),%rax
  sub    %rdx,%rax
  lea    D21(%rip),%rbp
  mov    %rax,%rbx
L43:
  mov    -0x4(%r12),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  sub    $0x4,%r12
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L43
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
L3:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L17
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string
name: retrieve_data
arguments: tag: D21
type_infered: string

tool: D6: Sum of two binary numbers: 

tool: D21: %d

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    return 1;
  long int binary1, binary2;
  int i = 0, remainder = 0, sum[20];
  binary1 = (long int)argv[1][0];
  binary2 = (long int)argv[2][0];
  while (binary1 != 0 || binary2 != 0) {
    sum[i++] = (binary1 % 10 + binary2 % 10 + remainder) % 2;
    remainder = (binary1 % 10 + binary2 % 10 + remainder) / 2;
    binary1 = binary1 / 10;
    binary2 = binary2 / 10;
  }
  if (remainder != 0)
    sum[i++] = remainder;
  --i;
  printf("Sum of two binary numbers: ");
  while (i >= 0)
    printf("%d", sum[i--]);
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kernel__Float__to_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long kernel__Float__to_i(double self) {
  long var;
  long var1;
  var1 = (long)self;
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: What is the c source code of the assembly code below:

```asm
<kernel__Float__to_i>:
  endbr64
  cvttsd2si %xmm0,%rax
  ret
```

assistant: ```c
long kernel__Float__to_i(double self) {
  long var;
  long var1;
  var1 = (long)self;
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kernel__Float__to_i>:
  endbr64
  cvttsd2si %xmm0,%rax
  ret
```

assistant: ```c
long kernel__Float__to_i(double self) {
  long var;
  long var1;
  var1 = (long)self;
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kernel__Float__to_i>:
  endbr64
  cvttsd2si %xmm0,%rax
  ret
```

assistant: ```c
long kernel__Float__to_i(double self) {
  long var;
  long var1;
  var1 = (long)self;
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sieve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rax
  mov    $0x41,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x5c(%rbp)
  mov    -0x6c(%rbp),%eax
  mov    %eax,-0x58(%rbp)
  jmp    L2
L7:
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L29
  mov    -0x5c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x5c(%rbp)
  mov    -0x58(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x54(%rbp)
  jmp    L8
L17:
  mov    -0x54(%rbp),%eax
  cltq
  movb   $0x1,-0x50(%rbp,%rax,1)
  mov    -0x58(%rbp),%eax
  add    %eax,-0x54(%rbp)
L8:
  cmpl   $0x40,-0x54(%rbp)
  jle    L17
L29:
  addl   $0x1,-0x58(%rbp)
L2:
  cmpl   $0x40,-0x58(%rbp)
  jle    L7
  mov    -0x5c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int sieve(int *t, int a) {
  char b[64LL + 1];
  memset(b, 0, sizeof(char) * (64LL + 1));
  int i = 0;
  for (int p = a; p <= 64LL; p++) {
    if (b[p] == 0) {
      t[i] = p;
      i++;
      for (int q = 2 * p; q <= 64LL; q += p)
        b[q] = 1;
    }
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sieve>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x41,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  cmp    $0x40,%ebx
  jg     L24
  movslq %ebx,%rdx
  lea    (%rbx,%rbx,1),%ecx
  mov    $0x0,%edi
  mov    %rsp,%rsi
  jmp    L62
L29:
  add    $0x1,%rdx
  add    $0x2,%ecx
  cmp    $0x40,%edx
  jg     L13
L62:
  cmpb   $0x0,(%rdx,%rsi,1)
  jne    L29
  movslq %edi,%rax
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%edi
  cmp    $0x40,%ecx
  jg     L29
  movslq %ecx,%rax
L2:
  movb   $0x1,(%rax,%rsi,1)
  add    %rdx,%rax
  cmp    $0x40,%eax
  jle    L2
  jmp    L29
L24:
  mov    $0x0,%edi
L13:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %edi,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sieve(int *t, int a) {
  char b[64LL + 1];
  memset(b, 0, sizeof(char) * (64LL + 1));
  int i = 0;
  for (int p = a; p <= 64LL; p++) {
    if (b[p] == 0) {
      t[i] = p;
      i++;
      for (int q = 2 * p; q <= 64LL; q += p)
        b[q] = 1;
    }
  }
  return i;
}
```