user: 这段汇编代码用C语言表示是什么样的？

```asm
<problemA>:
  endbr64
  push   %rbp
  lea    D59(%rip),%rdi
  lea    D3(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D104(%rip),%rbp
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D137(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    D72(%rip),%rdi
  lea    (%rsi,%rdx,1),%ecx
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  lea    D27(%rip),%rdi
  mov    $0x3,%eax
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  call   <printf@plt>
  mov    (%rsp),%esi
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  lea    D117(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2sd %esi,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    (%rsp),%esi
  pxor   %xmm0,%xmm0
  mov    0x4(%rsp),%r8d
  lea    D0(%rip),%rdi
  mov    %esi,%eax
  cltd
  idiv   %r8d
  mov    %r8d,%edx
  cvtsi2sd %eax,%xmm0
  mov    %eax,%ecx
  mov    $0x1,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  pxor   %xmm1,%xmm1
  movsd  0x10(%rsp),%xmm0
  lea    D123(%rip),%rdi
  mov    $0x2,%eax
  cvtsi2sd %esi,%xmm1
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%edx
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D95(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2sd %edx,%xmm1
  cvtsi2sd %esi,%xmm0
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  cvttsd2si 0x10(%rsp),%ecx
  lea    D96(%rip),%rdi
  movsd  0x10(%rsp),%xmm1
  cvttsd2si %xmm0,%eax
  cltd
  idiv   %ecx
  mov    $0x2,%eax
  mov    %edx,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D122(%rip),%rdi
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %eax,%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  and    $0x1,%esi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <main@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x20,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D59
type_infered: string
name: disassemble_data
arguments: data_tag: D3
type_infered: string
name: disassemble_data
arguments: data_tag: D4
type_infered: string
name: disassemble_data
arguments: data_tag: D104
type_infered: string
name: disassemble_data
arguments: data_tag: D29
type_infered: string
name: disassemble_data
arguments: data_tag: D137
type_infered: string
name: disassemble_data
arguments: data_tag: D72
type_infered: string
name: disassemble_data
arguments: data_tag: D27
type_infered: string
name: disassemble_data
arguments: data_tag: D117
type_infered: string
name: disassemble_data
arguments: data_tag: D0
type_infered: string
name: disassemble_data
arguments: data_tag: D123
type_infered: string
name: disassemble_data
arguments: data_tag: D95
type_infered: string
name: disassemble_data
arguments: data_tag: D96
type_infered: string
name: disassemble_data
arguments: data_tag: D122
type_infered: string

tool: D59: Input Integer #1: 

tool: D3: %d

tool: D4: Input Integer #2: 

tool: D104: %lf

tool: D29: Input Floating-point #1: 

tool: D137: Input Floating-point #2: 

tool: D72: A.1: Result = Integer #1 + Integer #2 = %d + %d = %d 


tool: D27: A.2: Result = Floating-point #1 - Floating-point #2 = %lf - %lf = %lf 


tool: D117: A.3: Result = Integer #1 * Floating-point #1 = %d * %lf = %d 


tool: D0: A.4: Result = Integer #1 / Integer #2 = %d / %d = %d (Integer version), %lf (Floating-point version)


tool: D123: A.5: Result = Integer #1 / Floating-point #2 = %d / %lf = %d (Integer version), %lf (Floating-point version)


tool: D95: A.6: Result = Integer #1 / Integer #2 = %d / %d = %lf 


tool: D96: A.7: Result = Floating-point #1 mod Floating-point #2 = %lf mod %lf = %d 


tool: D122: A.8: Result = 0 if integer is even, 1 if integer is odd.
    Integer #1: %d 
    Integer #2: %d 


assistant: ```c
int problemA(void) {
  int number1_int = 0, number2_int = 0;
  double number1_float = 0.0, number2_float = 0.0;
  int int_result = 0, int_result2 = 0;
  double float_result = 0;
  printf("Input Integer #1: ");
  scanf("%d", &number1_int);
  printf("Input Integer #2: ");
  scanf("%d", &number2_int);
  printf("Input Floating-point #1: ");
  scanf("%lf", &number1_float);
  printf("Input Floating-point #2: ");
  scanf("%lf", &number2_float);
  int_result = number1_int + number2_int;
  printf("A.1: Result = Integer #1 + Integer #2 = %d + %d = %d \n", number1_int, number2_int, int_result);
  float_result = number1_float - number2_float;
  printf("A.2: Result = Floating-point #1 - Floating-point #2 = %lf - %lf = %lf \n", number1_float, number2_float, float_result);
  int_result = number1_int * number1_float;
  printf("A.3: Result = Integer #1 * Floating-point #1 = %d * %lf = %d \n", number1_int, number1_float, int_result);
  int_result = number1_int / number2_int;
  float_result = number1_int / number2_int;
  printf("A.4: Result = Integer #1 / Integer #2 = %d / %d = %d (Integer version), %lf (Floating-point version)\n", number1_int, number2_int, int_result, float_result);
  int_result = number1_int / number2_float;
  float_result = number1_int / number2_float;
  printf("A.5: Result = Integer #1 / Floating-point #2 = %d / %lf = %d (Integer version), %lf (Floating-point version)\n", number1_int, number2_float, int_result, float_result);
  float_result = (double)number1_int / number2_int;
  printf("A.6: Result = Integer #1 / Integer #2 = %d / %d = %lf \n", number1_int, number2_int, float_result);
  int_result = (int)number1_float % (int)number2_float;
  printf("A.7: Result = Floating-point #1 mod Floating-point #2 = %lf mod %lf = %d \n", number1_float, number2_float, int_result);
  int_result = number1_int % 2;
  int_result2 = number2_int % 2;
  printf("A.8: Result = 0 if integer is even, 1 if integer is odd.\n    Integer #1: %d \n    Integer #2: %d \n", int_result, int_result2);
  return main();
}
```