ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<leftWall>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  mov    D120(%rip),%rax
  pxor   %xmm2,%xmm2
  movsd  D76(%rip),%xmm6
  movq   %rax,%xmm0
  movapd %xmm6,%xmm1
  call   <glColor3f@plt>
  movsd  D107(%rip),%xmm4
  movsd  D54(%rip),%xmm5
  movsd  D122(%rip),%xmm0
  movapd %xmm4,%xmm2
  movapd %xmm5,%xmm1
  call   <glTranslatef@plt>
  mov    D120(%rip),%rax
  pxor   %xmm2,%xmm2
  mov    $0x32,%edi
  movapd %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <glRotatef@plt>
  mov    D120(%rip),%rax
  movq   %rax,%xmm0
  call   <glutSolidCube@plt>
  xor    %eax,%eax
  call   <glPopMatrix@plt>
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  mov    D76(%rip),%rax
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm2
  movq   %rax,%xmm1
  mov    D120(%rip),%rax
  movq   %rax,%xmm0
  call   <glColor3f@plt>
  mov    D54(%rip),%rax
  movsd  D48(%rip),%xmm2
  movq   %rax,%xmm1
  mov    D107(%rip),%rax
  movq   %rax,%xmm0
  call   <glTranslatef@plt>
  mov    D120(%rip),%rax
  pxor   %xmm3,%xmm3
  mov    $0x32,%edi
  movapd %xmm3,%xmm0
  movapd %xmm3,%xmm2
  movq   %rax,%xmm1
  call   <glRotatef@plt>
  mov    D120(%rip),%rax
  movq   %rax,%xmm0
  call   <glutSolidCube@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <glPopMatrix@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D120
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D76
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D107
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D54
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D122
type_guessed: f32[2]
name: extract_symbolic_data
arguments: tag: D48
type_guessed: f64

tool: D120: 1

tool: D76: 0.7

tool: {"D107": [0x9a,0x99,0x99,0x99,0x99,0x99,0xd9,0xbf]}

tool: D54: 0.5

tool: {"D122": [0.0,-1.875]}

tool: D48: 0.32

assistant: ```c
void leftWall() {
  glPushMatrix();
  glColor3f(1.0, 0.7, 0.0);
  glTranslatef(-1, 0.5, -0.4);
  glRotatef(50, 0.0, 1.0, 0.0);
  glutSolidCube(1.0);
  glPopMatrix();
  glPushMatrix();
  glColor3f(1.0, 0.7, 0.0);
  glTranslatef(-0.4, 0.5, 0.32);
  glRotatef(50, 0.0, 1.0, 0.0);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: Translate the below assembly code into C programming language:

```asm
<strnspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %rdx,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rax
  mov    %rax,-0x118(%rbp)
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L11
L37:
  movsbq -0x119(%rbp),%rax
  movb   $0x1,-0x110(%rbp,%rax,1)
L11:
  mov    -0x130(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x130(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x119(%rbp)
  cmpb   $0x0,-0x119(%rbp)
  jne    L37
  jmp    L1
L55:
  movsbq -0x119(%rbp),%rax
  movzbl -0x110(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L64
  subq   $0x1,-0x138(%rbp)
L1:
  cmpq   $0x0,-0x138(%rbp)
  je     L23
  mov    -0x118(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x118(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x119(%rbp)
  cmpb   $0x0,-0x119(%rbp)
  jne    L55
  jmp    L23
L64:
  nop
L23:
  cmpq   $0x0,-0x138(%rbp)
  setne  %al
  movzbl %al,%eax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x118(%rbp),%rax
  add    %rdx,%rax
  sub    -0x128(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

assistant: ```c
size_t strnspn(const char *string, const char *skipset, size_t maxlen) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256);
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  for (; maxlen && ((c = *s++)); maxlen--)
    if (set[(size_t)c])
      break;
  return (size_t)(s - !!maxlen - string);
}
```
user: What is the c source code of the assembly code below:

```asm
<strnspn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x100,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x1(%r12),%rdx
  movzbl (%r12),%eax
  test   %al,%al
  je     L65
L58:
  movsbq %al,%rax
  movb   $0x1,(%rsp,%rax,1)
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L58
L65:
  mov    %rbp,%rax
  test   %rbx,%rbx
  je     L17
L35:
  add    $0x1,%rax
  movzbl -0x1(%rax),%edx
  test   %dl,%dl
  je     L17
  movsbq %dl,%rdx
  cmpb   $0x0,(%rsp,%rdx,1)
  jne    L17
  sub    $0x1,%rbx
  jne    L35
L17:
  cmp    $0x1,%rbx
  adc    $0xffffffffffffffff,%rax
  sub    %rbp,%rax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t strnspn(const char *string, const char *skipset, size_t maxlen) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256);
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  for (; maxlen && ((c = *s++)); maxlen--)
    if (set[(size_t)c])
      break;
  return (size_t)(s - !!maxlen - string);
}
```
user: What is the c source code of the assembly code below:

```asm
<strnspn>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x100,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movsbq 0x0(%rbp),%rax
  lea    0x1(%rbp),%rdx
  test   %al,%al
  je     L31
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rdx
  movb   $0x1,(%rsp,%rax,1)
  movsbq -0x1(%rdx),%rax
  test   %al,%al
  jne    L35
L31:
  mov    %r12,%rcx
  xor    %eax,%eax
  test   %rbx,%rbx
  jne    L64
  jmp    L40
  nopl   (%rax)
L39:
  cmpb   $0x0,(%rsp,%rdx,1)
  jne    L13
  sub    $0x1,%rbx
  je     L22
L64:
  mov    %rcx,%rax
  movsbq (%rcx),%rdx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L39
L13:
  sub    %r12,%rax
L40:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L22:
  mov    %rcx,%rax
  sub    %r12,%rax
  jmp    L40
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t strnspn(const char *string, const char *skipset, size_t maxlen) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256);
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  for (; maxlen && ((c = *s++)); maxlen--)
    if (set[(size_t)c])
      break;
  return (size_t)(s - !!maxlen - string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strnspn>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x100,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movsbq 0x0(%rbp),%rax
  lea    0x1(%rbp),%rdx
  test   %al,%al
  je     L88
  nopw   0x0(%rax,%rax,1)
L52:
  add    $0x1,%rdx
  movb   $0x1,(%rsp,%rax,1)
  movsbq -0x1(%rdx),%rax
  test   %al,%al
  jne    L52
L88:
  mov    %r12,%rcx
  xor    %eax,%eax
  test   %rbx,%rbx
  jne    L72
  jmp    L40
  nopl   (%rax)
L14:
  cmpb   $0x0,(%rsp,%rdx,1)
  jne    L78
  sub    $0x1,%rbx
  je     L43
L72:
  mov    %rcx,%rax
  movsbq (%rcx),%rdx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L14
L78:
  sub    %r12,%rax
L40:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L43:
  mov    %rcx,%rax
  sub    %r12,%rax
  jmp    L40
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t strnspn(const char *string, const char *skipset, size_t maxlen) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256);
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  for (; maxlen && ((c = *s++)); maxlen--)
    if (set[(size_t)c])
      break;
  return (size_t)(s - !!maxlen - string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<evaltable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <evalwhere@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L29
L13:
  mov    $0x0,%eax
  call   <evalwhere@plt>
  test   %rax,%rax
  jne    L29
  movq   $0x0,-0x8(%rbp)
L29:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D5: &&

assistant: ```c
long evaltable() {
  long val;
  for (val = evalwhere(); test("&&");) {
    if (!evalwhere() != 0)
      val = 0;
  }
  return (val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<evaltable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <evalwhere@plt>
  mov    %rax,%rbx
  lea    D5(%rip),%rbp
  jmp    L12
L4:
  mov    $0x0,%eax
  call   <evalwhere@plt>
  test   %rax,%rax
  cmove  %rax,%rbx
L12:
  mov    %rbp,%rdi
  call   <test@plt>
  test   %rax,%rax
  jne    L4
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: &&

assistant: ```c
long evaltable() {
  long val;
  for (val = evalwhere(); test("&&");) {
    if (!evalwhere() != 0)
      val = 0;
  }
  return (val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<evaltable>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D7(%rip),%rbx
  call   <evalwhere@plt>
  mov    %rax,%r12
  jmp    L9
  nopl   (%rax)
L4:
  xor    %eax,%eax
  call   <evalwhere@plt>
  test   %rax,%rax
  cmove  %rbp,%r12
L9:
  mov    %rbx,%rdi
  call   <test@plt>
  test   %rax,%rax
  jne    L4
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: &&

assistant: ```c
long evaltable() {
  long val;
  for (val = evalwhere(); test("&&");) {
    if (!evalwhere() != 0)
      val = 0;
  }
  return (val);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<evaltable>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D6(%rip),%rbx
  call   <evalwhere@plt>
  mov    %rax,%r12
  jmp    L8
  nopl   (%rax)
L15:
  xor    %eax,%eax
  call   <evalwhere@plt>
  test   %rax,%rax
  cmove  %rbp,%r12
L8:
  mov    %rbx,%rdi
  call   <test@plt>
  test   %rax,%rax
  jne    L15
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: &&

assistant: ```c
long evaltable() {
  long val;
  for (val = evalwhere(); test("&&");) {
    if (!evalwhere() != 0)
      val = 0;
  }
  return (val);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L20
  mov    D71(%rip),%rax
  mov    (%rax),%eax
  jmp    L69
L20:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L27
  mov    D71(%rip),%rax
  mov    (%rax),%eax
  jmp    L69
L27:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x1c(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  lea    -0x1c(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  movl   $0x1,-0x10(%rbp)
  movl   $0x3e8,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x10(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    $0x0,%r9d
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <pselect@plt>
  cmp    $0xffffffff,%eax
  je     L32
  mov    D71(%rip),%rax
  mov    (%rax),%eax
  jmp    L69
L32:
  mov    D53(%rip),%rax
  mov    (%rax),%eax
L69:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int main(void) {
  int sock1, sock2;
  if ((sock1 = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP)) < 0)
    return (EXIT_FAILURE);
  if ((sock2 = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP)) < 0)
    return (EXIT_FAILURE);
  fd_set fdset;
  FD_ZERO(&fdset);
  FD_SET(sock1, &fdset);
  FD_SET(sock2, &fdset);
  struct timespec timeout;
  timeout.tv_sec = 1;
  timeout.tv_nsec = 1000;
  close(sock2);
  if (pselect(sock2 + 1, &fdset, NULL, NULL, &timeout, NULL) != -1)
    return (EXIT_FAILURE);
  return (EXIT_SUCCESS);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D81(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  mov    D98(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L47
  mov    %eax,%ebx
  mov    D81(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  mov    D98(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L18
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  movl   $0x1,0x10(%rsp)
  movl   $0x3e8,0x14(%rsp)
  mov    %ebp,%edi
  call   <close@plt>
  lea    0x1(%rbp),%edi
  mov    $0x0,%r9d
  lea    0x10(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %r12,%rsi
  call   <pselect@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  jmp    L39
L47:
  mov    D30(%rip),%rax
  mov    (%rax),%eax
L39:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  jmp    L39
L0:
  mov    D75(%rip),%rax
  mov    (%rax),%eax
  jmp    L39
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int sock1, sock2;
  if ((sock1 = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP)) < 0)
    return (EXIT_FAILURE);
  if ((sock2 = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP)) < 0)
    return (EXIT_FAILURE);
  fd_set fdset;
  FD_ZERO(&fdset);
  FD_SET(sock1, &fdset);
  FD_SET(sock2, &fdset);
  struct timespec timeout;
  timeout.tv_sec = 1;
  timeout.tv_nsec = 1000;
  close(sock2);
  if (pselect(sock2 + 1, &fdset, NULL, NULL, &timeout, NULL) != -1)
    return (EXIT_FAILURE);
  return (EXIT_SUCCESS);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D38(%rip),%r13
  mov    D10(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D46(%rip),%rbx
  mov    0x0(%r13),%edx
  mov    (%r12),%esi
  mov    (%rbx),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L14
  mov    (%rbx),%edi
  mov    0x0(%r13),%edx
  mov    %eax,%ebp
  mov    (%r12),%esi
  call   <socket@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L14
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  mov    %ebx,%edi
  movabs $0x3e800000001,%rax
  mov    %rax,0x10(%rsp)
  call   <close@plt>
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbx),%edi
  lea    0x10(%rsp),%r8
  mov    %r12,%rsi
  call   <pselect@plt>
  add    $0x1,%eax
  je     L43
L14:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
L46:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  jmp    L46
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int sock1, sock2;
  if ((sock1 = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP)) < 0)
    return (EXIT_FAILURE);
  if ((sock2 = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP)) < 0)
    return (EXIT_FAILURE);
  fd_set fdset;
  FD_ZERO(&fdset);
  FD_SET(sock1, &fdset);
  FD_SET(sock2, &fdset);
  struct timespec timeout;
  timeout.tv_sec = 1;
  timeout.tv_nsec = 1000;
  close(sock2);
  if (pselect(sock2 + 1, &fdset, NULL, NULL, &timeout, NULL) != -1)
    return (EXIT_FAILURE);
  return (EXIT_SUCCESS);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<equal_rows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L26
  mov    $0x0,%eax
  jmp    L12
L26:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  mov    $0x1,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
bool equal_rows(int a1[], int a2[], int size) {
  for (int i = 0; i < size; i++)
    if (a1[i] != a2[i])
      return false;
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<equal_rows>:
  endbr64
  test   %edx,%edx
  jle    L13
  mov    %edx,%edx
  mov    $0x0,%eax
L9:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jne    L26
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
  mov    $0x1,%eax
  ret
L13:
  mov    $0x1,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool equal_rows(int a1[], int a2[], int size) {
  for (int i = 0; i < size; i++)
    if (a1[i] != a2[i])
      return false;
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<equal_rows>:
  endbr64
  test   %edx,%edx
  jle    L23
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L2
  nop
L12:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L23
L2:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L12
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool equal_rows(int a1[], int a2[], int size) {
  for (int i = 0; i < size; i++)
    if (a1[i] != a2[i])
      return false;
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<equal_rows>:
  endbr64
  test   %edx,%edx
  jle    L38
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L26
  nop
L14:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L38
L26:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L14
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L38:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool equal_rows(int a1[], int a2[], int size) {
  for (int i = 0; i < size; i++)
    if (a1[i] != a2[i])
      return false;
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<concat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0xa,-0x4(%rbp)
  jmp    L6
L15:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L15
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  imul   %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long concat(int a, int b) {
  int n = 10;
  for (; b >= n; n *= 10)
    ;
  return (long)a * (long)n + (long)b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<concat>:
  endbr64
  cmp    $0x9,%esi
  jle    L1
  mov    $0xa,%edx
L12:
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  mov    %eax,%edx
  cmp    %eax,%esi
  jge    L12
L3:
  movslq %edi,%rax
  movslq %edx,%rdx
  imul   %rdx,%rax
  movslq %esi,%rsi
  lea    (%rax,%rsi,1),%rax
  ret
L1:
  mov    $0xa,%edx
  jmp    L3
```

assistant: ```c
long concat(int a, int b) {
  int n = 10;
  for (; b >= n; n *= 10)
    ;
  return (long)a * (long)n + (long)b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<concat>:
  endbr64
  cmp    $0x9,%esi
  jle    L16
  mov    $0xa,%eax
  xchg   %ax,%ax
L5:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %eax,%esi
  jge    L5
  cltq
  movslq %edi,%rdi
  movslq %esi,%rsi
  imul   %rax,%rdi
  lea    (%rdi,%rsi,1),%rax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0xa,%eax
  movslq %edi,%rdi
  movslq %esi,%rsi
  imul   %rax,%rdi
  lea    (%rdi,%rsi,1),%rax
  ret
```

assistant: ```c
long concat(int a, int b) {
  int n = 10;
  for (; b >= n; n *= 10)
    ;
  return (long)a * (long)n + (long)b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<concat>:
  endbr64
  cmp    $0x9,%esi
  jle    L0
  mov    $0xa,%eax
  xchg   %ax,%ax
L19:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %eax,%esi
  jge    L19
  cltq
  movslq %edi,%rdi
  movslq %esi,%rsi
  imul   %rax,%rdi
  lea    (%rdi,%rsi,1),%rax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0xa,%eax
  movslq %edi,%rdi
  movslq %esi,%rsi
  imul   %rax,%rdi
  lea    (%rdi,%rsi,1),%rax
  ret
```

assistant: ```c
long concat(int a, int b) {
  int n = 10;
  for (; b >= n; n *= 10)
    ;
  return (long)a * (long)n + (long)b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<diffULong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L10
  mov    -0x8(%rbp),%rax
  jmp    L6
L10:
  mov    -0x8(%rbp),%rax
L6:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long diffULong(unsigned long x, unsigned long y) {
  long long lx = x, ly = y, lresult;
  lresult = lx - ly;
  if (lresult < 0) {
    return (unsigned long)(lresult + ((unsigned long)-1L) + 1);
  } else {
    return (unsigned long)(lresult);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<diffULong>:
  endbr64
  mov    %rdi,%rax
  sub    %rsi,%rax
  ret
```

assistant: ```c
unsigned long diffULong(unsigned long x, unsigned long y) {
  long long lx = x, ly = y, lresult;
  lresult = lx - ly;
  if (lresult < 0) {
    return (unsigned long)(lresult + ((unsigned long)-1L) + 1);
  } else {
    return (unsigned long)(lresult);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<diffULong>:
  endbr64
  mov    %rdi,%rax
  sub    %rsi,%rax
  ret
```

assistant: ```c
unsigned long diffULong(unsigned long x, unsigned long y) {
  long long lx = x, ly = y, lresult;
  lresult = lx - ly;
  if (lresult < 0) {
    return (unsigned long)(lresult + ((unsigned long)-1L) + 1);
  } else {
    return (unsigned long)(lresult);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<diffULong>:
  endbr64
  mov    %rdi,%rax
  sub    %rsi,%rax
  ret
```

assistant: ```c
unsigned long diffULong(unsigned long x, unsigned long y) {
  long long lx = x, ly = y, lresult;
  lresult = lx - ly;
  if (lresult < 0) {
    return (unsigned long)(lresult + ((unsigned long)-1L) + 1);
  } else {
    return (unsigned long)(lresult);
  }
}
```