user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1ac(%rbp)
  movl   $0x0,-0x1a8(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L10
L86:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1ac(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1ac(%rbp)
L10:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L86
  movl   $0x0,-0x1ac(%rbp)
  jmp    L31
L77:
  movl   $0x0,-0x1a8(%rbp)
  jmp    L43
L7:
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1a8(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L98
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x1a4(%rbp)
  mov    -0x1a8(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1a8(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x1a4(%rbp),%edx
  mov    %edx,-0x1a0(%rbp,%rax,4)
L98:
  addl   $0x1,-0x1a8(%rbp)
L43:
  mov    -0x1b0(%rbp),%eax
  sub    -0x1ac(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1a8(%rbp)
  jl     L7
  addl   $0x1,-0x1ac(%rbp)
L31:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L77
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1ac(%rbp)
  jmp    L26
L64:
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1ac(%rbp)
L26:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L64
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D48
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D54
data_type: string
name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D40
data_type: string

tool: D48: 
 Enter the size of the array 

tool: D27: %d

tool: D54: 
 Enter the elements of the Array 

tool: D9: 
 The sorted array is : 

tool: D40:  %d 

assistant: ```c
void main() {
  int a[100], n, i = 0, j = 0;
  int temp;
  printf("\n Enter the size of the array ");
  scanf("%d", &n);
  printf("\n Enter the elements of the Array ");
  for (; i < n; ++i)
    scanf("%d", &a[i]);
  for (i = 0; i < n; ++i)
    for (j = 0; j < n - i - 1; ++j)
      if (a[j] > a[j + 1]) {
        temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
  printf("\n The sorted array is : ");
  for (i = 0; i < n; ++i)
    printf(" %d ", a[i]);
}
```