user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xfe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0xff0(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xfe0(%rbp)
  jmp    L32
L114:
  movl   $0x0,-0xfe4(%rbp)
  jmp    L88
L50:
  lea    -0xfd0(%rbp),%rdx
  mov    -0xfe4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xfe4(%rbp)
L88:
  mov    -0xff0(%rbp),%eax
  cmp    %eax,-0xfe4(%rbp)
  jl     L50
  movl   $0x4000000,-0xfd4(%rbp)
  lea    -0xfec(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfe0(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xfe0(%rbp)
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0xfe4(%rbp)
  jmp    L51
L6:
  lea    -0xfe8(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xfdc(%rbp)
  jmp    L66
L71:
  mov    -0xfdc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xfd8(%rbp)
  jmp    L98
L53:
  mov    -0xfe8(%rbp),%edx
  mov    -0xfd4(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%edi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    -0xfe8(%rbp),%edx
  mov    -0xfdc(%rbp),%eax
  cltq
  mov    -0xfd0(%rbp,%rax,4),%ecx
  mov    -0xfd8(%rbp),%eax
  cltq
  mov    -0xfd0(%rbp,%rax,4),%eax
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rax,%rbx
  jle    L41
  mov    -0xfdc(%rbp),%eax
  cltq
  mov    -0xfd0(%rbp,%rax,4),%edx
  mov    -0xfd8(%rbp),%eax
  cltq
  mov    -0xfd0(%rbp,%rax,4),%eax
  add    %edx,%eax
  mov    %eax,-0xfd4(%rbp)
L41:
  addl   $0x1,-0xfd8(%rbp)
L98:
  mov    -0xff0(%rbp),%eax
  cmp    %eax,-0xfd8(%rbp)
  jl     L53
  addl   $0x1,-0xfdc(%rbp)
L66:
  mov    -0xff0(%rbp),%eax
  cmp    %eax,-0xfdc(%rbp)
  jl     L71
  mov    -0xfe8(%rbp),%eax
  mov    -0xfd4(%rbp),%edx
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xfe4(%rbp)
L51:
  mov    -0xfec(%rbp),%eax
  cmp    %eax,-0xfe4(%rbp)
  jle    L6
  lea    -0xff0(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L32:
  mov    -0xff0(%rbp),%eax
  test   %eax,%eax
  jne    L114
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type_guessed: string
name: disassemble_data
arguments: data_tag: D32
type_guessed: string
name: disassemble_data
arguments: data_tag: D52
type_guessed: string
name: disassemble_data
arguments: data_tag: D27
type_guessed: string

tool: D28: %d


tool: D32:  %d

tool: D52: Case %d:


tool: D27: Closest sum to %d is %d.


assistant: ```c
int main(void) {
  int i, n, m, num[1005], t;
  scanf("%d\n", &n);
  t = 1;
  while (0 != n) {
    for (i = 0; i < n; i++)
      scanf(" %d", &num[i]);
    int q, k, m, dif, s;
    dif = (1 << 26);
    scanf("%d\n", &q);
    printf("Case %d:\n", t++);
    for (i = 1; i <= q; i++) {
      scanf("%d\n", &s);
      for (k = 0; k < n; k++)
        for (m = k + 1; m < n; m++)
          if (abs(dif - s) > abs(s - (num[k] + num[m])))
            dif = (num[k] + num[m]);
      printf("Closest sum to %d is %d.\n", s, dif);
    }
    scanf("%d\n", &n);
  }
}
```