ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<create_triangle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L138
  mov    %edi,%ebx
  je     L73
  lea    0x0(,%rdi,8),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%r12d
L105:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp,%r12,8)
  add    $0x1,%r12
  cmp    %r12d,%ebx
  jg     L105
  mov    %rbp,%r9
  mov    %rbp,%rcx
  mov    $0x0,%esi
L89:
  mov    $0x0,%eax
L4:
  mov    (%rcx),%rdx
  movq   $0x0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L4
  add    $0x1,%esi
  add    $0x8,%rcx
  cmp    %esi,%ebx
  jg     L89
  mov    $0x1,%r10d
  mov    $0x0,%r8d
  mov    $0x0,%r12d
  mov    $0x1,%r11d
  jmp    L22
L73:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  movq   $0x0,(%rax)
L28:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L96:
  mov    %r11d,%eax
L33:
  add    $0x8,%rsi
  mov    %ecx,%edx
L48:
  mov    (%r9),%rcx
  movslq %eax,%rdi
  mov    %rdi,(%rcx,%rsi,1)
  lea    0x1(%rdx),%ecx
  cmp    %r10d,%ecx
  je     L98
  test   %ecx,%ecx
  je     L96
  test   %r8d,%r8d
  je     L96
  mov    %r8d,%edi
  sub    %edx,%edi
  imul   %edi,%eax
  cltd
  idiv   %ecx
  jmp    L33
L98:
  add    $0x1,%r8d
  add    $0x1,%r10
  add    $0x8,%r9
  cmp    %r8d,%ebx
  jle    L28
L22:
  mov    $0x0,%esi
  mov    %r12d,%edx
  mov    %r11d,%eax
  test   %r8d,%r8d
  jns    L48
  jmp    L98
L138:
  mov    $0x0,%ebp
  jmp    L28
```

assistant: ```c
size_t **create_triangle(int rows) {
  if (rows < 0)
    return NULL;
  if (rows == 0) {
    size_t **result = malloc(sizeof(size_t *));
    result[0] = malloc(sizeof(size_t));
    result[0][0] = 0;
    return result;
  }
  size_t **result = malloc(rows * sizeof(size_t *));
  for (int i = 0; i < rows; ++i)
    result[i] = malloc(rows * sizeof(size_t));
  for (int i = 0; i < rows; ++i) {
    for (int j = 0; j < rows; ++j)
      result[i][j] = 0;
  }
  int coef = 1;
  for (int i = 0; i < rows; ++i) {
    for (int j = 0; j < i + 1; ++j) {
      if (j == 0 || i == 0)
        coef = 1;
      else
        coef = coef * (i - j + 1) / j;
      result[i][j] = coef;
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<create_triangle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L1
  je     L63
  lea    0x0(,%rdi,8),%r13d
  mov    %edi,%ebx
  xor    %ebp,%ebp
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%r12,%rbp,8)
  add    $0x1,%rbp
  cmp    %ebp,%ebx
  jg     L25
  movslq %ebx,%r13
  mov    $0x8,%eax
  shl    $0x3,%r13
  test   %ebx,%ebx
  cmovle %rax,%r13
  xor    %ebp,%ebp
L15:
  mov    (%r12,%rbp,8),%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  add    $0x1,%rbp
  call   <memset@plt>
  cmp    %ebp,%ebx
  jg     L15
  mov    $0x1,%edi
  xor    %r8d,%r8d
  xchg   %ax,%ax
L72:
  mov    -0x8(%r12,%rdi,8),%r9
  mov    $0x1,%ecx
  mov    $0x1,%eax
  lea    0x1(%r8),%r10d
  jmp    L27
  nopl   (%rax)
L26:
  mov    %r10d,%edx
  sub    %esi,%edx
  imul   %edx,%eax
  cltd
  idiv   %esi
L20:
  add    $0x1,%rcx
L27:
  movslq %eax,%rdx
  mov    %ecx,%esi
  mov    %rdx,-0x8(%r9,%rcx,8)
  cmp    %rcx,%rdi
  je     L61
  test   %r8d,%r8d
  jne    L26
  mov    $0x1,%eax
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L61:
  mov    %r10d,%r8d
  add    $0x1,%rdi
  cmp    %r10d,%ebx
  jg     L72
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L63:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,(%r12)
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t **create_triangle(int rows) {
  if (rows < 0)
    return NULL;
  if (rows == 0) {
    size_t **result = malloc(sizeof(size_t *));
    result[0] = malloc(sizeof(size_t));
    result[0][0] = 0;
    return result;
  }
  size_t **result = malloc(rows * sizeof(size_t *));
  for (int i = 0; i < rows; ++i)
    result[i] = malloc(rows * sizeof(size_t));
  for (int i = 0; i < rows; ++i) {
    for (int j = 0; j < rows; ++j)
      result[i][j] = 0;
  }
  int coef = 1;
  for (int i = 0; i < rows; ++i) {
    for (int j = 0; j < i + 1; ++j) {
      if (j == 0 || i == 0)
        coef = 1;
      else
        coef = coef * (i - j + 1) / j;
      result[i][j] = coef;
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_triangle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L54
  je     L58
  lea    0x0(,%rdi,8),%r13d
  mov    %edi,%ebx
  xor    %ebp,%ebp
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%r12,%rbp,8)
  add    $0x1,%rbp
  cmp    %ebp,%ebx
  jg     L31
  movslq %ebx,%r13
  mov    $0x8,%eax
  shl    $0x3,%r13
  test   %ebx,%ebx
  cmovle %rax,%r13
  xor    %ebp,%ebp
L42:
  mov    (%r12,%rbp,8),%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  add    $0x1,%rbp
  call   <memset@plt>
  cmp    %ebp,%ebx
  jg     L42
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L21:
  mov    (%r12,%rdi,8),%rsi
  movq   $0x1,(%rsi)
  test   %rdi,%rdi
  je     L14
  lea    -0x1(%rdi),%r8d
  mov    $0x1,%ecx
  mov    $0x1,%eax
  add    $0x2,%r8
  lea    0x1(%rdi),%r9d
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %r9d,%edx
  sub    %ecx,%edx
  imul   %edx,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  mov    %rdx,(%rsi,%rcx,8)
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L69
L14:
  add    $0x1,%rdi
  cmp    %edi,%ebx
  jg     L21
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,(%r12)
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t **create_triangle(int rows) {
  if (rows < 0)
    return NULL;
  if (rows == 0) {
    size_t **result = malloc(sizeof(size_t *));
    result[0] = malloc(sizeof(size_t));
    result[0][0] = 0;
    return result;
  }
  size_t **result = malloc(rows * sizeof(size_t *));
  for (int i = 0; i < rows; ++i)
    result[i] = malloc(rows * sizeof(size_t));
  for (int i = 0; i < rows; ++i) {
    for (int j = 0; j < rows; ++j)
      result[i][j] = 0;
  }
  int coef = 1;
  for (int i = 0; i < rows; ++i) {
    for (int j = 0; j < i + 1; ++j) {
      if (j == 0 || i == 0)
        coef = 1;
      else
        coef = coef * (i - j + 1) / j;
      result[i][j] = coef;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movabs $0x8be589eac7,%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x2,-0x8(%rbp)
  jmp    L20
L11:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L29
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L5
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L5
L29:
  nop
L5:
  addq   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jle    L11
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  long long NUM = 600851475143ll;
  long long max;
  long long i;
  for (max = 0ll, i = 2ll; i <= NUM; ++i) {
    if (NUM % i)
      continue;
    NUM = NUM / i;
    if (i > max)
      max = i;
  }
  printf("%lld\n", max);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x0,%edi
  movabs $0x8be589eac7,%rsi
  jmp    L36
L30:
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  mov    %rax,%rsi
  cmp    %rcx,%rdi
  cmovl  %rcx,%rdi
L36:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jl     L4
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  je     L30
  jmp    L36
L4:
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  long long NUM = 600851475143ll;
  long long max;
  long long i;
  for (max = 0ll, i = 2ll; i <= NUM; ++i) {
    if (NUM % i)
      continue;
    NUM = NUM / i;
    if (i > max)
      max = i;
  }
  printf("%lld\n", max);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  xor    %r8d,%r8d
  movabs $0x8be589eac7,%rsi
L16:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jl     L6
L7:
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L16
  cmp    %rcx,%r8
  mov    %rax,%rsi
  cmovl  %rcx,%r8
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jge    L7
L6:
  mov    %r8,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  long long NUM = 600851475143ll;
  long long max;
  long long i;
  for (max = 0ll, i = 2ll; i <= NUM; ++i) {
    if (NUM % i)
      continue;
    NUM = NUM / i;
    if (i > max)
      max = i;
  }
  printf("%lld\n", max);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%ecx
  xor    %r8d,%r8d
  movabs $0x8be589eac7,%rsi
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L26
  cmp    %rcx,%r8
  mov    %rax,%rsi
  cmovl  %rcx,%r8
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jle    L5
L39:
  mov    %r8,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jge    L5
  jmp    L39
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  long long NUM = 600851475143ll;
  long long max;
  long long i;
  for (max = 0ll, i = 2ll; i <= NUM; ++i) {
    if (NUM % i)
      continue;
    NUM = NUM / i;
    if (i > max)
      max = i;
  }
  printf("%lld\n", max);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wf_parse_mtllib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <wf_fparse_mtllib@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  jmp    L3
L1:
  movq   $0x0,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: r

assistant: ```c
struct wf_mtllib const *wf_parse_mtllib(char const *filename) {
  FILE *fp;
  struct wf_mtllib const *result;
  fp = fopen(filename, "r");
  if (fp) {
    result = wf_fparse_mtllib(fp);
    fclose(fp);
  } else {
    result = NULL;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wf_parse_mtllib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <wf_fparse_mtllib@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <fclose@plt>
L8:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: r

assistant: ```c
struct wf_mtllib const *wf_parse_mtllib(char const *filename) {
  FILE *fp;
  struct wf_mtllib const *result;
  fp = fopen(filename, "r");
  if (fp) {
    result = wf_fparse_mtllib(fp);
    fclose(fp);
  } else {
    result = NULL;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wf_parse_mtllib>:
  endbr64
  push   %r12
  lea    D9(%rip),%rsi
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <wf_fparse_mtllib@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fclose@plt>
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string

tool: D9: r

assistant: ```c
struct wf_mtllib const *wf_parse_mtllib(char const *filename) {
  FILE *fp;
  struct wf_mtllib const *result;
  fp = fopen(filename, "r");
  if (fp) {
    result = wf_fparse_mtllib(fp);
    fclose(fp);
  } else {
    result = NULL;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wf_parse_mtllib>:
  endbr64
  push   %r12
  lea    D6(%rip),%rsi
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <wf_fparse_mtllib@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fclose@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: string

tool: D6: r

assistant: ```c
struct wf_mtllib const *wf_parse_mtllib(char const *filename) {
  FILE *fp;
  struct wf_mtllib const *result;
  fp = fopen(filename, "r");
  if (fp) {
    result = wf_fparse_mtllib(fp);
    fclose(fp);
  } else {
    result = NULL;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<convert_to_microseconds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  imul   $0xf4240,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  cmp    $0x1f3,%edx
  jle    L7
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int64_t convert_to_microseconds(struct timespec *tms) {
  int64_t micros = tms->tv_sec * 1000000;
  micros += tms->tv_nsec / 1000;
  if (tms->tv_nsec % 1000 >= 500) {
    ++micros;
  }
  return micros;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convert_to_microseconds>:
  endbr64
  imul   $0xf4240,(%rdi),%eax
  mov    0x4(%rdi),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  add    %edx,%eax
  imul   $0x3e8,%edx,%edx
  sub    %edx,%ecx
  cmp    $0x1f3,%ecx
  setg   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int64_t convert_to_microseconds(struct timespec *tms) {
  int64_t micros = tms->tv_sec * 1000000;
  micros += tms->tv_nsec / 1000;
  if (tms->tv_nsec % 1000 >= 500) {
    ++micros;
  }
  return micros;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_to_microseconds>:
  endbr64
  movslq 0x4(%rdi),%rdx
  imul   $0xf4240,(%rdi),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sar    $0x26,%rdx
  sub    %esi,%edx
  add    %edx,%eax
  imul   $0x3e8,%edx,%edx
  sub    %edx,%ecx
  xor    %edx,%edx
  cmp    $0x1f3,%ecx
  setg   %dl
  add    %edx,%eax
  ret
```

assistant: ```c
int64_t convert_to_microseconds(struct timespec *tms) {
  int64_t micros = tms->tv_sec * 1000000;
  micros += tms->tv_nsec / 1000;
  if (tms->tv_nsec % 1000 >= 500) {
    ++micros;
  }
  return micros;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_to_microseconds>:
  endbr64
  movslq 0x4(%rdi),%rdx
  imul   $0xf4240,(%rdi),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sar    $0x26,%rdx
  sub    %esi,%edx
  add    %edx,%eax
  imul   $0x3e8,%edx,%edx
  sub    %edx,%ecx
  xor    %edx,%edx
  cmp    $0x1f3,%ecx
  setg   %dl
  add    %edx,%eax
  ret
```

assistant: ```c
int64_t convert_to_microseconds(struct timespec *tms) {
  int64_t micros = tms->tv_sec * 1000000;
  micros += tms->tv_nsec / 1000;
  if (tms->tv_nsec % 1000 >= 500) {
    ++micros;
  }
  return micros;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stbi__addsizes_valid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L5
  mov    $0x0,%eax
  jmp    L7
L5:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int stbi__addsizes_valid(int a, int b) {
  if (b < 0)
    return 0;
  return a <= INT_MAX - b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi__addsizes_valid>:
  endbr64
  mov    $0x0,%eax
  test   %esi,%esi
  js     L2
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  sub    %esi,%eax
  cmp    %edi,%eax
  setge  %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
int stbi__addsizes_valid(int a, int b) {
  if (b < 0)
    return 0;
  return a <= INT_MAX - b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stbi__addsizes_valid>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  js     L7
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  sub    %esi,%eax
  cmp    %edi,%eax
  setge  %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int stbi__addsizes_valid(int a, int b) {
  if (b < 0)
    return 0;
  return a <= INT_MAX - b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stbi__addsizes_valid>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  js     L5
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  sub    %esi,%eax
  cmp    %edi,%eax
  setge  %al
  movzbl %al,%eax
L5:
  ret
```

assistant: ```c
int stbi__addsizes_valid(int a, int b) {
  if (b < 0)
    return 0;
  return a <= INT_MAX - b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__crypt_r@plt>
  leave
  ret
```

assistant: ```c
char *crypt(const char *clear, const char *salt) {
  static char buf[128];
  return __crypt_r(clear, salt, (void *)buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crypt>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdx
  call   <__crypt_r@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *crypt(const char *clear, const char *salt) {
  static char buf[128];
  return __crypt_r(clear, salt, (void *)buf);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<crypt>:
  endbr64
  lea    D7(%rip),%rdx
  jmp    1050 <__crypt_r@plt>
```

assistant: ```c
char *crypt(const char *clear, const char *salt) {
  static char buf[128];
  return __crypt_r(clear, salt, (void *)buf);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<crypt>:
  endbr64
  lea    D0(%rip),%rdx
  jmp    1050 <__crypt_r@plt>
```

assistant: ```c
char *crypt(const char *clear, const char *salt) {
  static char buf[128];
  return __crypt_r(clear, salt, (void *)buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<blocking_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L21
L11:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L20
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    D30(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L37
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    D16(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L37
  mov    $0xffffffffffffffff,%rax
  jmp    L15
L37:
  movq   $0x0,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L11
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
long int blocking_write(int outf, char *buffer, long num) {
  long int words = 0, temp;
  while (words < num) {
    temp = write(outf, buffer + words, num - words);
    if (temp == -1) {
      if (errno != EINTR && errno != EAGAIN)
        return (-1);
      temp = 0;
    }
    words += temp;
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<blocking_write>:
  endbr64
  test   %rdx,%rdx
  jle    L18
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  jmp    L30
L63:
  mov    %r14,%rax
L43:
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jle    L44
L30:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    0x0(%r13,%rbx,1),%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L43
  mov    D12(%rip),%rdx
  mov    (%rdx),%rdx
  mov    D9(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L63
  mov    D28(%rip),%rcx
  cmp    (%rcx),%rdx
  jne    L5
  mov    %r14,%rax
  jmp    L43
L44:
  mov    $0x0,%eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
long int blocking_write(int outf, char *buffer, long num) {
  long int words = 0, temp;
  while (words < num) {
    temp = write(outf, buffer + words, num - words);
    if (temp == -1) {
      if (errno != EINTR && errno != EAGAIN)
        return (-1);
      temp = 0;
    }
    words += temp;
  }
  return (0);
}
```