ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<h2o_mem_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D9(%rip),%rax
  mov    %rax,%rdx
  mov    $0x17d,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <h2o__fatal@plt>
  mov    -0x18(%rbp),%rax
  jmp    L0
L8:
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D17
type_infered: string

tool: D9: no memory

tool: D17: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/deweerdt/h2o/refs/heads/master/include/h2o/h2o/memory.h

assistant: ```c
void *h2o_mem_realloc(void *oldp, size_t sz) {
  void *newp = realloc(oldp, sz);
  if (newp == NULL) {
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/deweerdt/h2o/refs/heads/master/include/h2o/h2o/memory.h", 381, "no memory");
    return oldp;
  }
  return newp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<h2o_mem_realloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <realloc@plt>
  test   %rax,%rax
  je     L16
L9:
  pop    %rbx
  ret
L16:
  lea    D12(%rip),%rdx
  mov    $0x17d,%esi
  lea    D8(%rip),%rdi
  call   <h2o__fatal@plt>
  mov    %rbx,%rax
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D12: no memory

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/deweerdt/h2o/refs/heads/master/include/h2o/h2o/memory.h

assistant: ```c
void *h2o_mem_realloc(void *oldp, size_t sz) {
  void *newp = realloc(oldp, sz);
  if (newp == NULL) {
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/deweerdt/h2o/refs/heads/master/include/h2o/h2o/memory.h", 381, "no memory");
    return oldp;
  }
  return newp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<h2o_mem_realloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <realloc@plt>
  test   %rax,%rax
  je     L9
  pop    %rbx
  ret
L9:
  lea    D11(%rip),%rdx
  mov    $0x17d,%esi
  lea    D1(%rip),%rdi
  call   <h2o__fatal@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D1
data_type: string

tool: D11: no memory

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/deweerdt/h2o/refs/heads/master/include/h2o/h2o/memory.h

assistant: ```c
void *h2o_mem_realloc(void *oldp, size_t sz) {
  void *newp = realloc(oldp, sz);
  if (newp == NULL) {
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/deweerdt/h2o/refs/heads/master/include/h2o/h2o/memory.h", 381, "no memory");
    return oldp;
  }
  return newp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<h2o_mem_realloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <realloc@plt>
  test   %rax,%rax
  je     L2
  pop    %rbx
  ret
L2:
  lea    D7(%rip),%rdx
  mov    $0x17d,%esi
  lea    D6(%rip),%rdi
  call   <h2o__fatal@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D7: no memory

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/deweerdt/h2o/refs/heads/master/include/h2o/h2o/memory.h

assistant: ```c
void *h2o_mem_realloc(void *oldp, size_t sz) {
  void *newp = realloc(oldp, sz);
  if (newp == NULL) {
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/deweerdt/h2o/refs/heads/master/include/h2o/h2o/memory.h", 381, "no memory");
    return oldp;
  }
  return newp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__sw_hweight8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    %eax
  and    $0x55,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0xf,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int __sw_hweight8(unsigned int w) {
  unsigned int res = w - ((w >> 1) & 0x55);
  res = (res & 0x33) + ((res >> 2) & 0x33);
  return (res + (res >> 4)) & 0x0F;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__sw_hweight8>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  and    $0x33,%edx
  shr    $0x2,%edi
  and    $0x33,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf,%eax
  ret
```

assistant: ```c
unsigned int __sw_hweight8(unsigned int w) {
  unsigned int res = w - ((w >> 1) & 0x55);
  res = (res & 0x33) + ((res >> 2) & 0x33);
  return (res + (res >> 4)) & 0x0F;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__sw_hweight8>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33,%edx
  and    $0x33,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf,%eax
  ret
```

assistant: ```c
unsigned int __sw_hweight8(unsigned int w) {
  unsigned int res = w - ((w >> 1) & 0x55);
  res = (res & 0x33) + ((res >> 2) & 0x33);
  return (res + (res >> 4)) & 0x0F;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__sw_hweight8>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33,%edx
  and    $0x33,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf,%eax
  ret
```

assistant: ```c
unsigned int __sw_hweight8(unsigned int w) {
  unsigned int res = w - ((w >> 1) & 0x55);
  res = (res & 0x33) + ((res >> 2) & 0x33);
  return (res + (res >> 4)) & 0x0F;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<busca_sequencial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  jmp    L3
L2:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    $0xffffffff,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int busca_sequencial(int vetor[], int tamanho, int chave) {
  int i;
  for (i = 0; i < tamanho; i++)
    if (vetor[i] == chave)
      return i;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<busca_sequencial>:
  endbr64
  test   %esi,%esi
  jle    L36
  mov    %esi,%esi
  mov    $0x0,%eax
L2:
  mov    %eax,%ecx
  cmp    %edx,(%rdi,%rax,4)
  je     L27
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L2
  mov    $0xffffffff,%ecx
L27:
  mov    %ecx,%eax
  ret
L36:
  mov    $0xffffffff,%ecx
  jmp    L27
```

assistant: ```c
int busca_sequencial(int vetor[], int tamanho, int chave) {
  int i;
  for (i = 0; i < tamanho; i++)
    if (vetor[i] == chave)
      return i;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<busca_sequencial>:
  endbr64
  test   %esi,%esi
  jle    L20
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L5
  nop
L36:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L20
L5:
  mov    %eax,%r8d
  cmp    %edx,(%rdi,%rax,4)
  jne    L36
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L20:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int busca_sequencial(int vetor[], int tamanho, int chave) {
  int i;
  for (i = 0; i < tamanho; i++)
    if (vetor[i] == chave)
      return i;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<busca_sequencial>:
  endbr64
  test   %esi,%esi
  jle    L22
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L3
  nop
L35:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L22
L3:
  mov    %eax,%r8d
  cmp    %edx,(%rdi,%rax,4)
  jne    L35
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L22:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int busca_sequencial(int vetor[], int tamanho, int chave) {
  int i;
  for (i = 0; i < tamanho; i++)
    if (vetor[i] == chave)
      return i;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<evil_remove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <is_licensed_prog@plt>
  test   %rax,%rax
  jne    L32
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <is_protected_entry@plt>
  test   %rax,%rax
  jne    L19
  jmp    L31
L32:
  nop
L31:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <real_remove@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L15
L19:
  nop
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
L15:
  leave
  ret
```

assistant: ```c
int evil_remove(const char *pathname) {
  int ret = 0;
  if (is_licensed_prog())
    goto green;
  if (is_protected_entry(pathname))
    goto red;
green:
  ret = real_remove(pathname);
  return ret;
red:
  errno = EPERM;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<evil_remove>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <is_licensed_prog@plt>
  test   %rax,%rax
  je     L24
L10:
  mov    %rbx,%rdi
  call   <real_remove@plt>
L3:
  pop    %rbx
  ret
L24:
  mov    %rbx,%rdi
  call   <is_protected_entry@plt>
  test   %rax,%rax
  je     L10
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int evil_remove(const char *pathname) {
  int ret = 0;
  if (is_licensed_prog())
    goto green;
  if (is_protected_entry(pathname))
    goto red;
green:
  ret = real_remove(pathname);
  return ret;
red:
  errno = EPERM;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<evil_remove>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <is_licensed_prog@plt>
  test   %rax,%rax
  je     L11
L5:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <real_remove@plt>
  nopl   (%rax)
L11:
  mov    %rbp,%rdi
  call   <is_protected_entry@plt>
  test   %rax,%rax
  je     L5
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int evil_remove(const char *pathname) {
  int ret = 0;
  if (is_licensed_prog())
    goto green;
  if (is_protected_entry(pathname))
    goto red;
green:
  ret = real_remove(pathname);
  return ret;
red:
  errno = EPERM;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<evil_remove>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <is_licensed_prog@plt>
  test   %rax,%rax
  je     L5
L16:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <real_remove@plt>
  nopl   (%rax)
L5:
  mov    %rbp,%rdi
  call   <is_protected_entry@plt>
  test   %rax,%rax
  je     L16
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int evil_remove(const char *pathname) {
  int ret = 0;
  if (is_licensed_prog())
    goto green;
  if (is_protected_entry(pathname))
    goto red;
green:
  ret = real_remove(pathname);
  return ret;
red:
  errno = EPERM;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<safe_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  cmp    %rax,-0x20(%rbp)
  je     L4
  mov    $0x0,%eax
  jmp    L7
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
L7:
  leave
  ret
```

assistant: ```c
void *safe_malloc(size_t num, size_t size) {
  size_t alloc_size = num * size;
  if (alloc_size / num != size) {
    return NULL;
  }
  return malloc(alloc_size);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<safe_malloc>:
  endbr64
  mov    %rdi,%rcx
  imul   %rsi,%rcx
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rdi
  mov    $0x0,%edx
  cmp    %rsi,%rax
  jne    L9
  sub    $0x8,%rsp
  mov    %rcx,%rdi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
L9:
  mov    %rdx,%rax
  ret
```

assistant: ```c
void *safe_malloc(size_t num, size_t size) {
  size_t alloc_size = num * size;
  if (alloc_size / num != size) {
    return NULL;
  }
  return malloc(alloc_size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<safe_malloc>:
  endbr64
  mov    %rdi,%rax
  mul    %rsi
  mov    %rax,%rdi
  jo     L0
  jmp    1050 <malloc@plt>
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *safe_malloc(size_t num, size_t size) {
  size_t alloc_size = num * size;
  if (alloc_size / num != size) {
    return NULL;
  }
  return malloc(alloc_size);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<safe_malloc>:
  endbr64
  mov    %rdi,%rax
  mul    %rsi
  mov    %rax,%rdi
  jo     L5
  jmp    1050 <malloc@plt>
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *safe_malloc(size_t num, size_t size) {
  size_t alloc_size = num * size;
  if (alloc_size / num != size) {
    return NULL;
  }
  return malloc(alloc_size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hexdigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L88
  cmpb   $0x39,-0x4(%rbp)
  jg     L88
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L37
L88:
  cmpb   $0x60,-0x4(%rbp)
  jle    L78
  cmpb   $0x66,-0x4(%rbp)
  jg     L78
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L37
L78:
  cmpb   $0x40,-0x4(%rbp)
  jle    L68
  cmpb   $0x46,-0x4(%rbp)
  jg     L68
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L37
L68:
  mov    $0xffffffff,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int hexdigit(char x) {
  if (x >= '0' && x <= '9')
    return x - '0';
  if (x >= 'a' && x <= 'f')
    return 10 + (x - 'a');
  if (x >= 'A' && x <= 'F')
    return 10 + (x - 'A');
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hexdigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L11
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L17
  lea    -0x41(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x37,%eax
  cmp    $0x6,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L11:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L17:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
int hexdigit(char x) {
  if (x >= '0' && x <= '9')
    return x - '0';
  if (x >= 'a' && x <= 'f')
    return 10 + (x - 'a');
  if (x >= 'A' && x <= 'F')
    return 10 + (x - 'A');
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hexdigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L17
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L6
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hexdigit(char x) {
  if (x >= '0' && x <= '9')
    return x - '0';
  if (x >= 'a' && x <= 'f')
    return 10 + (x - 'a');
  if (x >= 'A' && x <= 'F')
    return 10 + (x - 'A');
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<hexdigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L2
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L9
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hexdigit(char x) {
  if (x >= '0' && x <= '9')
    return x - '0';
  if (x >= 'a' && x <= 'f')
    return 10 + (x - 'a');
  if (x >= 'A' && x <= 'F')
    return 10 + (x - 'A');
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<blkxor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  xor    %ecx,%edx
  mov    %edx,(%rax)
  subq   $0x4,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void blkxor(uint64_t *dest, const uint64_t *src, size_t count) {
  do {
    *dest++ ^= *src++;
    *dest++ ^= *src++;
    *dest++ ^= *src++;
    *dest++ ^= *src++;
  } while (count -= 4);
}
```
user: What is the c source code of the assembly code below?

```asm
<blkxor>:
  endbr64
L6:
  mov    (%rsi),%eax
  xor    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  xor    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  xor    %eax,0x8(%rdi)
  add    $0x10,%rsi
  add    $0x10,%rdi
  mov    -0x4(%rsi),%eax
  xor    %eax,-0x4(%rdi)
  sub    $0x4,%rdx
  jne    L6
  ret
```

assistant: ```c
void blkxor(uint64_t *dest, const uint64_t *src, size_t count) {
  do {
    *dest++ ^= *src++;
    *dest++ ^= *src++;
    *dest++ ^= *src++;
    *dest++ ^= *src++;
  } while (count -= 4);
}
```
user: What is the c source code of the assembly code below:

```asm
<blkxor>:
  endbr64
  nopl   0x0(%rax)
L3:
  mov    (%rsi),%eax
  add    $0x10,%rsi
  xor    %eax,(%rdi)
  mov    -0xc(%rsi),%eax
  xor    %eax,0x4(%rdi)
  mov    -0x8(%rsi),%eax
  xor    %eax,0x8(%rdi)
  add    $0x10,%rdi
  mov    -0x4(%rsi),%eax
  xor    %eax,-0x4(%rdi)
  sub    $0x4,%rdx
  jne    L3
  ret
```

assistant: ```c
void blkxor(uint64_t *dest, const uint64_t *src, size_t count) {
  do {
    *dest++ ^= *src++;
    *dest++ ^= *src++;
    *dest++ ^= *src++;
    *dest++ ^= *src++;
  } while (count -= 4);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<blkxor>:
  endbr64
  lea    0xf(%rdi),%rax
  mov    %rdi,%rcx
  sub    %rsi,%rax
  cmp    $0x1e,%rax
  jbe    L2
  test   $0x3,%dl
  jne    L2
  sub    $0x4,%rdx
  xor    %eax,%eax
  shr    $0x2,%rdx
  lea    0x1(%rdx),%rdi
  xor    %edx,%edx
  nopl   0x0(%rax)
L30:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm1
  add    $0x1,%rdx
  pxor   %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rdx
  jb     L30
  ret
L2:
  mov    (%rsi),%eax
  add    $0x10,%rsi
  xor    %eax,(%rcx)
  mov    -0xc(%rsi),%eax
  xor    %eax,0x4(%rcx)
  mov    -0x8(%rsi),%eax
  xor    %eax,0x8(%rcx)
  add    $0x10,%rcx
  mov    -0x4(%rsi),%eax
  xor    %eax,-0x4(%rcx)
  sub    $0x4,%rdx
  jne    L2
  ret
```

assistant: ```c
void blkxor(uint64_t *dest, const uint64_t *src, size_t count) {
  do {
    *dest++ ^= *src++;
    *dest++ ^= *src++;
    *dest++ ^= *src++;
    *dest++ ^= *src++;
  } while (count -= 4);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tempLimitsPresetsString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D40(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L29
  cmpl   $0x3,-0x14(%rbp)
  jg     L83
  cmpl   $0x2,-0x14(%rbp)
  je     L77
  cmpl   $0x2,-0x14(%rbp)
  jg     L83
  cmpl   $0x0,-0x14(%rbp)
  je     L20
  cmpl   $0x1,-0x14(%rbp)
  je     L98
  jmp    L83
L20:
  lea    D23(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L83
L98:
  lea    D0(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L83
L77:
  lea    D36(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L83
L29:
  lea    D38(%rip),%rax
  mov    %rax,-0x8(%rbp)
  nop
L83:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mainMenuSelection@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D40
datatype: string
name: disassemble_data
arguments: label: D23
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string
name: disassemble_data
arguments: label: D36
datatype: string
name: disassemble_data
arguments: label: D38
datatype: string

tool: 

tool: D23: New

tool: D0: Preset 1

tool: D36: Preset 2

tool: D38: Preset 3

assistant: ```c
void tempLimitsPresetsString(int pos) {
  char *text = (char *)"";
  switch (pos) {
  case 0:
    text = (char *)"New";
    break;
  case 1:
    text = (char *)"Preset 1";
    break;
  case 2:
    text = (char *)"Preset 2";
    break;
  case 3:
    text = (char *)"Preset 3";
    break;
  }
  mainMenuSelection(text);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tempLimitsPresetsString>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  lea    D44(%rip),%rdi
  cmp    $0x2,%eax
  je     L5
  jg     L28
  lea    D34(%rip),%rdi
  test   %eax,%eax
  je     L5
  cmp    $0x1,%eax
  lea    D25(%rip),%rdi
  lea    D49(%rip),%rax
  cmove  %rax,%rdi
L5:
  call   <mainMenuSelection@plt>
  add    $0x8,%rsp
  ret
L28:
  cmp    $0x3,%eax
  lea    D25(%rip),%rdi
  lea    D54(%rip),%rax
  cmove  %rax,%rdi
  jmp    L5
```

tool_calls: name: parse_data
arguments: data_tag: D44
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D49
type_guessed: string
name: parse_data
arguments: data_tag: D54
type_guessed: string

tool: D44: Preset 2

tool: D34: New

tool: 

tool: D49: Preset 1

tool: D54: Preset 3

assistant: ```c
void tempLimitsPresetsString(int pos) {
  char *text = (char *)"";
  switch (pos) {
  case 0:
    text = (char *)"New";
    break;
  case 1:
    text = (char *)"Preset 1";
    break;
  case 2:
    text = (char *)"Preset 2";
    break;
  case 3:
    text = (char *)"Preset 3";
    break;
  }
  mainMenuSelection(text);
}
```