ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<jours_depuis_debut>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  cmp    $0x640,%edx
  jle    L36
  mov    $0x640,%ebp
  nopl   0x0(%rax)
L13:
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <jours_par_an@plt>
  add    %eax,%ebx
  cmp    %ebp,%r12d
  jne    L13
L36:
  cmp    $0x1,%r13d
  jle    L34
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L1:
  mov    %ebp,%edi
  mov    %r12d,%esi
  add    $0x1,%ebp
  call   <jours_par_mois@plt>
  add    %eax,%ebx
  cmp    %ebp,%r13d
  jne    L1
L34:
  lea    -0x1(%rbx,%r14,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int jours_depuis_debut(int jour, int mois, int annee) {
  int i, total = 0;
  for (i = 1600; i < annee; i++)
    total += jours_par_an(i);
  for (i = 1; i < mois; i++)
    total += jours_par_mois(i, annee);
  return total + jour - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<jours_depuis_debut>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  cmp    $0x640,%edx
  jle    L3
  mov    $0x640,%ebp
  nopl   0x0(%rax)
L38:
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <jours_par_an@plt>
  add    %eax,%ebx
  cmp    %ebp,%r12d
  jne    L38
L3:
  cmp    $0x1,%r13d
  jle    L21
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L25:
  mov    %ebp,%edi
  mov    %r12d,%esi
  add    $0x1,%ebp
  call   <jours_par_mois@plt>
  add    %eax,%ebx
  cmp    %ebp,%r13d
  jne    L25
L21:
  lea    -0x1(%rbx,%r14,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int jours_depuis_debut(int jour, int mois, int annee) {
  int i, total = 0;
  for (i = 1600; i < annee; i++)
    total += jours_par_an(i);
  for (i = 1; i < mois; i++)
    total += jours_par_mois(i, annee);
  return total + jour - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <assert1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  assert1();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <assert1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert1();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <assert1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert1();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <assert1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert1();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fast_mul_10_large>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0x8,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  add    %eax,-0x8(%rbp)
  sarl   $0x3,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  setg   %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t fast_mul_10_large(uint32_t n) {
  uint32_t q, r;
  q = (n >> 1) + (n >> 2);
  q = q + (q >> 4);
  q = q + (q >> 8);
  q = q + (q >> 16);
  q = q >> 3;
  r = n - (((q << 2) + q) << 1);
  return q + (r > 9);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fast_mul_10_large>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  mov    %edi,%edx
  sar    $0x2,%edx
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x4,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x10,%edx
  add    %eax,%edx
  sar    $0x3,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  cmp    $0x9,%edi
  setg   %al
  movzbl %al,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
uint32_t fast_mul_10_large(uint32_t n) {
  uint32_t q, r;
  q = (n >> 1) + (n >> 2);
  q = q + (q >> 4);
  q = q + (q >> 8);
  q = q + (q >> 16);
  q = q >> 3;
  r = n - (((q << 2) + q) << 1);
  return q + (r > 9);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fast_mul_10_large>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0x2,%edx
  sar    %eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x4,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x10,%edx
  add    %eax,%edx
  sar    $0x3,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setg   %al
  add    %edx,%eax
  ret
```

assistant: ```c
uint32_t fast_mul_10_large(uint32_t n) {
  uint32_t q, r;
  q = (n >> 1) + (n >> 2);
  q = q + (q >> 4);
  q = q + (q >> 8);
  q = q + (q >> 16);
  q = q >> 3;
  r = n - (((q << 2) + q) << 1);
  return q + (r > 9);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fast_mul_10_large>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0x2,%edx
  sar    %eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x4,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x10,%edx
  add    %eax,%edx
  sar    $0x3,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setg   %al
  add    %edx,%eax
  ret
```

assistant: ```c
uint32_t fast_mul_10_large(uint32_t n) {
  uint32_t q, r;
  q = (n >> 1) + (n >> 2);
  q = q + (q >> 4);
  q = q + (q >> 8);
  q = q + (q >> 16);
  q = q >> 3;
  r = n - (((q << 2) + q) << 1);
  return q + (r > 9);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <sysbail@plt>
L0:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: failed to strdup %lu bytes

assistant: ```c
char *bstrdup(const char *s) {
  char *p;
  size_t len;
  len = strlen(s) + 1;
  p = malloc(len);
  if (p == NULL)
    sysbail("failed to strdup %lu bytes", (unsigned long)len);
  memcpy(p, s, len);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bstrdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
L4:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <sysbail@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: failed to strdup %lu bytes

assistant: ```c
char *bstrdup(const char *s) {
  char *p;
  size_t len;
  len = strlen(s) + 1;
  p = malloc(len);
  if (p == NULL)
    sysbail("failed to strdup %lu bytes", (unsigned long)len);
  memcpy(p, s, len);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bstrdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L2
L17:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  call   <sysbail@plt>
  jmp    L17
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D6: failed to strdup %lu bytes

assistant: ```c
char *bstrdup(const char *s) {
  char *p;
  size_t len;
  len = strlen(s) + 1;
  p = malloc(len);
  if (p == NULL)
    sysbail("failed to strdup %lu bytes", (unsigned long)len);
  memcpy(p, s, len);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bstrdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L0
L18:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %r12,%rsi
  lea    D3(%rip),%rdi
  call   <sysbail@plt>
  jmp    L18
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D3: failed to strdup %lu bytes

assistant: ```c
char *bstrdup(const char *s) {
  char *p;
  size_t len;
  len = strlen(s) + 1;
  p = malloc(len);
  if (p == NULL)
    sysbail("failed to strdup %lu bytes", (unsigned long)len);
  memcpy(p, s, len);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dlg_prev_ok_buttonindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L10
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L29:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <dlg_ok_buttoncode@plt>
  test   %rax,%rax
  jns    L29
L10:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int dlg_prev_ok_buttonindex(int current, int extra) {
  int result = current - 1;
  if (result < extra) {
    for (result = 0; dlg_ok_buttoncode(result + 1) >= 0; ++result) {
      ;
    }
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dlg_prev_ok_buttonindex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%ebp
  cmp    %esi,%ebp
  jge    L5
  mov    $0x0,%ebx
L8:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <dlg_ok_buttoncode@plt>
  test   %rax,%rax
  jns    L8
L5:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int dlg_prev_ok_buttonindex(int current, int extra) {
  int result = current - 1;
  if (result < extra) {
    for (result = 0; dlg_ok_buttoncode(result + 1) >= 0; ++result) {
      ;
    }
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dlg_prev_ok_buttonindex>:
  endbr64
  push   %r12
  lea    -0x1(%rdi),%r12d
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%r12d
  jge    L6
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %ebx,%r12d
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <dlg_ok_buttoncode@plt>
  test   %rax,%rax
  jns    L9
L6:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int dlg_prev_ok_buttonindex(int current, int extra) {
  int result = current - 1;
  if (result < extra) {
    for (result = 0; dlg_ok_buttoncode(result + 1) >= 0; ++result) {
      ;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dlg_prev_ok_buttonindex>:
  endbr64
  push   %r12
  lea    -0x1(%rdi),%r12d
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%r12d
  jge    L1
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %ebx,%r12d
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <dlg_ok_buttoncode@plt>
  test   %rax,%rax
  jns    L6
L1:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int dlg_prev_ok_buttonindex(int current, int extra) {
  int result = current - 1;
  if (result < extra) {
    for (result = 0; dlg_ok_buttoncode(result + 1) >= 0; ++result) {
      ;
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L82
L52:
  lea    -0xd(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  cmp    $0x56,%al
  jle    L67
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  cmp    $0x5a,%al
  jle    L26
L67:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  cmp    $0x76,%al
  jle    L21
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L21
L26:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  sub    $0x16,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  mov    %dl,-0xd(%rbp,%rax,1)
  jmp    L53
L21:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  add    $0x4,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  mov    %dl,-0xd(%rbp,%rax,1)
L53:
  addl   $0x1,-0x14(%rbp)
L82:
  cmpl   $0x4,-0x14(%rbp)
  jle    L52
  movl   $0x0,-0x14(%rbp)
  jmp    L87
L49:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L87:
  cmpl   $0x4,-0x14(%rbp)
  jle    L49
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string

tool: D5: Please input 5 characters:

tool: D18: %c

assistant: ```c
int main() {
  char c[5];
  int i;
  printf("Please input 5 characters:\n");
  for (i = 0; i < 5; i++) {
    scanf("%c", &c[i]);
    if (('W' <= c[i] && c[i] <= 'Z') || ('w' <= c[i] && c[i] <= 'z'))
      c[i] -= 22;
    else
      c[i] += 4;
  }
  for (i = 0; i < 5; i++)
    printf("%c", c[i]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    0x3(%rsp),%rbp
  lea    0x8(%rsp),%r12
  mov    %rbp,%rbx
  lea    D2(%rip),%r13
L14:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movzbl (%rbx),%eax
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x57,%edx
  lea    -0x16(%rax),%ecx
  add    $0x4,%eax
  cmp    $0x3,%dl
  cmovbe %ecx,%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L14
L19:
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L19
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D4: Please input 5 characters:

tool: D2: %c

assistant: ```c
int main() {
  char c[5];
  int i;
  printf("Please input 5 characters:\n");
  for (i = 0; i < 5; i++) {
    scanf("%c", &c[i]);
    if (('W' <= c[i] && c[i] <= 'Z') || ('w' <= c[i] && c[i] <= 'z'))
      c[i] -= 22;
    else
      c[i] += 4;
  }
  for (i = 0; i < 5; i++)
    printf("%c", c[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%rdi
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbx
  lea    0x8(%rsp),%rbp
  call   <puts@plt>
  mov    %rbx,%r13
L18:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl 0x0(%r13),%eax
  mov    %eax,%edx
  lea    -0x16(%rax),%ecx
  add    $0x4,%eax
  and    $0xffffffdf,%edx
  sub    $0x57,%edx
  cmp    $0x3,%dl
  cmovbe %ecx,%eax
  add    $0x1,%r13
  mov    %al,-0x1(%r13)
  cmp    %rbp,%r13
  jne    L18
L12:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D13
type: string

tool: D0: Please input 5 characters:

tool: D13: %c

assistant: ```c
int main() {
  char c[5];
  int i;
  printf("Please input 5 characters:\n");
  for (i = 0; i < 5; i++) {
    scanf("%c", &c[i]);
    if (('W' <= c[i] && c[i] <= 'Z') || ('w' <= c[i] && c[i] <= 'z'))
      c[i] -= 22;
    else
      c[i] += 4;
  }
  for (i = 0; i < 5; i++)
    printf("%c", c[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdi
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  lea    0x8(%rsp),%r12
  call   <puts@plt>
  mov    %rbp,%rbx
L50:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movzbl (%rbx),%eax
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x57,%edx
  cmp    $0x3,%dl
  ja     L24
  sub    $0x16,%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %r12,%rbx
  jne    L50
  nopl   0x0(%rax,%rax,1)
L54:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  call   <putchar@plt>
  cmp    %r12,%rbp
  jne    L54
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L24:
  add    $0x4,%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %r12,%rbx
  jne    L50
  jmp    L54
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D7: Please input 5 characters:

tool: D12: %c

assistant: ```c
int main() {
  char c[5];
  int i;
  printf("Please input 5 characters:\n");
  for (i = 0; i < 5; i++) {
    scanf("%c", &c[i]);
    if (('W' <= c[i] && c[i] <= 'Z') || ('w' <= c[i] && c[i] <= 'z'))
      c[i] -= 22;
    else
      c[i] += 4;
  }
  for (i = 0; i < 5; i++)
    printf("%c", c[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getOctaveLimits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D18(%rip),%xmm0
  movss  %xmm0,-0x40(%rbp)
  movss  D91(%rip),%xmm0
  movss  %xmm0,-0x3c(%rbp)
  movss  D68(%rip),%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  D30(%rip),%xmm0
  movss  %xmm0,-0x34(%rbp)
  movss  D65(%rip),%xmm0
  movss  %xmm0,-0x30(%rbp)
  movss  D64(%rip),%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movss  D35(%rip),%xmm0
  movss  %xmm0,-0x28(%rbp)
  movss  D38(%rip),%xmm0
  movss  %xmm0,-0x24(%rbp)
  movss  D74(%rip),%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  D31(%rip),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  D79(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  D82(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    -0x40(%rbp),%rax
  mov    $0x30,%esi
  mov    %rax,%rdi
  call   <movArray@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
datatype: byte[4]
name: unpack_data
arguments: data_label: D91
datatype: byte[4]
name: unpack_data
arguments: data_label: D68
datatype: byte[4]
name: unpack_data
arguments: data_label: D30
datatype: byte[4]
name: unpack_data
arguments: data_label: D65
datatype: byte[4]
name: unpack_data
arguments: data_label: D64
datatype: byte[4]
name: unpack_data
arguments: data_label: D35
datatype: byte[4]
name: unpack_data
arguments: data_label: D38
datatype: byte[4]
name: unpack_data
arguments: data_label: D74
datatype: byte[4]
name: unpack_data
arguments: data_label: D31
datatype: byte[4]
name: unpack_data
arguments: data_label: D79
datatype: byte[4]
name: unpack_data
arguments: data_label: D82
datatype: byte[4]

tool: {"D18": [0x00,0x00,0x30,0x41]}

tool: {"D91": [0x00,0x00,0xb0,0x41]}

tool: {"D68": [0x00,0x00,0x30,0x42]}

tool: {"D30": [0x00,0x00,0xb0,0x42]}

tool: {"D65": [0x00,0x00,0x31,0x43]}

tool: {"D64": [0x00,0x80,0xb1,0x43]}

tool: {"D35": [0x00,0x80,0x31,0x44]}

tool: {"D38": [0x00,0x80,0xb1,0x44]}

tool: {"D74": [0x00,0x80,0x31,0x45]}

tool: {"D31": [0x00,0x80,0xb1,0x45]}

tool: {"D79": [0x00,0x80,0x31,0x46]}

tool: {"D82": [0x00,0x80,0xb1,0x46]}

assistant: ```c
float *getOctaveLimits(void) {
  float limits[] = {11, 22, 44, 88, 177, 355, 710, 1420, 2840, 5680, 11360, 22720};
  return movArray(limits, sizeof(limits));
}
```
user: What is the c source code of the assembly code below:

```asm
<getOctaveLimits>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x41300000,(%rsp)
  movl   $0x41b00000,0x4(%rsp)
  movl   $0x42300000,0x8(%rsp)
  movl   $0x42b00000,0xc(%rsp)
  movl   $0x43310000,0x10(%rsp)
  movl   $0x43b18000,0x14(%rsp)
  movl   $0x44318000,0x18(%rsp)
  movl   $0x44b18000,0x1c(%rsp)
  movl   $0x45318000,0x20(%rsp)
  movl   $0x45b18000,0x24(%rsp)
  movl   $0x46318000,0x28(%rsp)
  movl   $0x46b18000,0x2c(%rsp)
  mov    %rsp,%rdi
  mov    $0x30,%esi
  call   <movArray@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float *getOctaveLimits(void) {
  float limits[] = {11, 22, 44, 88, 177, 355, 710, 1420, 2840, 5680, 11360, 22720};
  return movArray(limits, sizeof(limits));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getOctaveLimits>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x30,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x41b0000041300000,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x42b0000042300000,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x43b1800043310000,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x44b1800044318000,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x45b1800045318000,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x46b1800046318000,%rax
  mov    %rax,0x28(%rsp)
  call   <movArray@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float *getOctaveLimits(void) {
  float limits[] = {11, 22, 44, 88, 177, 355, 710, 1420, 2840, 5680, 11360, 22720};
  return movArray(limits, sizeof(limits));
}
```