user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D78(%rip),%rdi
  call   <puts@plt>
  lea    D169(%rip),%rdi
  call   <puts@plt>
  lea    D70(%rip),%rdi
  call   <puts@plt>
  lea    D152(%rip),%rdi
  call   <puts@plt>
  lea    D97(%rip),%rdi
  call   <puts@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    D95(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D175(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x6,0x14(%rsp)
  je     L43
  lea    D127(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D175(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x4,%eax
  ja     L27
  mov    %eax,%eax
  lea    D110(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L43:
  lea    D72(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x10(%rsp),%eax
  add    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D89(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L27:
  lea    D78(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
  mov    0xc(%rsp),%eax
  sub    0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D48(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L27
  mov    0xc(%rsp),%eax
  imul   0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D190(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L27
  mov    0xc(%rsp),%eax
  cltd
  idivl  0x10(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D147(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L27
  mov    0xc(%rsp),%eax
  cltd
  idivl  0x10(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D80(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L27
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D78
type: string
name: disassemble_data
arguments: tag: D169
type: string
name: disassemble_data
arguments: tag: D70
type: string
name: disassemble_data
arguments: tag: D152
type: string
name: disassemble_data
arguments: tag: D97
type: string
name: disassemble_data
arguments: tag: D9
type: string
name: disassemble_data
arguments: tag: D31
type: string
name: disassemble_data
arguments: tag: D95
type: string
name: disassemble_data
arguments: tag: D175
type: string
name: disassemble_data
arguments: tag: D127
type: string
name: disassemble_data
arguments: tag: D47
type: string
name: disassemble_data
arguments: tag: D72
type: string
name: disassemble_data
arguments: tag: D89
type: string
name: disassemble_data
arguments: tag: D48
type: string
name: disassemble_data
arguments: tag: D190
type: string
name: disassemble_data
arguments: tag: D147
type: string
name: disassemble_data
arguments: tag: D80
type: string

tool: D78: 
---------------------------------

tool: D169: Please, choose an option of operation: 

tool: D70: * 1 = Addition 

tool: D152: * 2 = Subtraction 

tool: D97: * 3 = Multiplication 

tool: D9: * 4 = Division 

tool: D31: * 5 = MOD 

tool: D95: * 6 = Exit 

tool: D175: %d

tool: D127: Please, insert the number primary: 

tool: D47: 
Please, insert the number secondary: 

tool: D72: -----BYE----- 

tool: D89: Result addition is: %.2f 


tool: D48: Result subtraction is: %.2f 


tool: D190: Result multiplication is: %.2f 


tool: D147: Result division is: %.2f 


tool: D80: Result the mod is: %.2f 


assistant: ```c
int main() {
  int numberPrimary;
  int numberSecondary;
  int option;
  float result;
  printf("\n---------------------------------\n");
  printf("Please, choose an option of operation: \n");
  printf("* 1 = Addition \n");
  printf("* 2 = Subtraction \n");
  printf("* 3 = Multiplication \n");
  printf("* 4 = Division \n");
  printf("* 5 = MOD \n");
  printf("* 6 = Exit \n");
  scanf("%d", &option);
  if (option == 6) {
    printf("-----BYE----- \n");
    exit(0);
  }
  printf("Please, insert the number primary: ");
  scanf("%d", &numberPrimary);
  printf("\nPlease, insert the number secondary: ");
  scanf("%d", &numberSecondary);
  switch (option) {
  case 1:
    result = ((numberPrimary) + (numberSecondary));
    printf("Result addition is: %.2f \n", result);
    break;
  case 2:
    result = ((numberPrimary) - (numberSecondary));
    printf("Result subtraction is: %.2f \n", result);
    break;
  case 3:
    result = ((numberPrimary) * (numberSecondary));
    printf("Result multiplication is: %.2f \n", result);
    break;
  case 4:
    result = ((numberPrimary) / (numberSecondary));
    printf("Result division is: %.2f \n", result);
    break;
  case 5:
    result = (numberPrimary % numberSecondary);
    printf("Result the mod is: %.2f \n", result);
    break;
  }
  printf("\n---------------------------------\n");
}
```