ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  sub    $0xa4d,%ax
  mov    %ax,0x6(%rsp)
  movzwl 0x2(%rdi),%ecx
  test   %cx,%cx
  je     L41
  lea    0x6(%rsp),%rdx
  mov    $0x0,%eax
  jmp    L22
L5:
  add    $0x1,%eax
  add    $0x2,%rdx
  cmp    %ax,%cx
  je     L41
L22:
  cmp    %ax,0x6(%rsp)
  jb     L5
  movzbl 0x6(%rsp),%edi
  movzbl 0x7(%rsp),%r8d
  mov    %r8b,0x6(%rsp)
  mov    %dil,0x7(%rsp)
  shlw   (%rdx)
  jmp    L5
L41:
  movzwl 0x6(%rsp),%eax
  add    $0x1c96,%ax
  mov    %ax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x18,%rsp
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] += state[local1];
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 681723154UL) - (unsigned short)10364;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edi
  lea    -0xa4d(%rax),%edx
  mov    %dx,0x6(%rsp)
  test   %di,%di
  je     L21
  xor    %eax,%eax
  nopl   0x0(%rax)
L26:
  cmp    %ax,%dx
  jb     L32
  lea    0x6(%rsp),%rcx
  rolw   $0x8,0x6(%rsp)
  movzwl (%rcx,%rax,2),%edx
  add    %edx,%edx
  mov    %dx,(%rcx,%rax,2)
L32:
  add    $0x1,%rax
  cmp    %ax,%di
  ja     L26
L21:
  add    $0x1c96,%dx
  mov    %dx,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] += state[local1];
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 681723154UL) - (unsigned short)10364;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  movzwl 0x2(%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  sub    $0xa4d,%ax
  test   %dx,%dx
  je     L83
  rol    $0x8,%ax
  add    %eax,%eax
  mov    %ax,0x6(%rsp)
  cmp    $0x1,%dx
  je     L83
  test   %ax,%ax
  jne    L51
L43:
  cmp    $0x2,%dx
  je     L83
  mov    $0x2,%ecx
L14:
  cmp    %cx,%ax
  jae    L48
  add    $0x1,%rcx
  cmp    %cx,%dx
  ja     L14
  nopw   0x0(%rax,%rax,1)
L83:
  add    $0x1c96,%ax
  mov    %ax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L51:
  rol    $0x8,%ax
  mov    %ax,0x6(%rsp)
  movzwl 0x8(%rsp),%eax
  add    %eax,%eax
  mov    %ax,0x8(%rsp)
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L48:
  movzwl 0x6(%rsp),%eax
  rol    $0x8,%ax
  add    %eax,%eax
  mov    %ax,0x6(%rsp,%rcx,2)
  add    $0x1,%rcx
  cmp    %cx,%dx
  ja     L14
  jmp    L83
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] += state[local1];
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 681723154UL) - (unsigned short)10364;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw4rectangles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%r8d
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <fgui_draw_rectangle@plt>
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%r8d
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <fgui_draw_rectangle@plt>
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  lea    (%rcx,%rax,1),%esi
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%r8d
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <fgui_draw_rectangle@plt>
  mov    -0x10(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  lea    (%rcx,%rax,1),%esi
  mov    -0x4(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%r8d
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <fgui_draw_rectangle@plt>
  nop
  leave
  ret
```

assistant: ```c
void draw4rectangles(uint16_t cx, uint16_t cy, uint16_t x, uint16_t y, uint32_t color) {
  fgui_draw_rectangle(cx - y, cy - x, y << 1, 1, color);
  fgui_draw_rectangle(cx - x, cy - y, x << 1, 1, color);
  fgui_draw_rectangle(cx - x, cy + y, x << 1, 1, color);
  fgui_draw_rectangle(cx - y, cy + x, y << 1, 1, color);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<draw4rectangles>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebx
  mov    %edx,%r15d
  mov    %r8d,%ebp
  lea    (%rcx,%rcx,1),%r14d
  mov    %edi,%r13d
  mov    %ecx,0x8(%rsp)
  sub    %ecx,%r13d
  sub    %edx,%esi
  mov    $0x1,%ecx
  mov    %r14d,%edx
  mov    %r13d,%edi
  call   <fgui_draw_rectangle@plt>
  mov    %r15d,%edx
  lea    (%r15,%r15,1),%r15d
  mov    %edx,0xc(%rsp)
  sub    %edx,%r12d
  mov    %ebx,%esi
  sub    0x8(%rsp),%esi
  mov    %ebp,%r8d
  mov    $0x1,%ecx
  mov    %r15d,%edx
  mov    %r12d,%edi
  call   <fgui_draw_rectangle@plt>
  mov    0x8(%rsp),%eax
  lea    (%rax,%rbx,1),%esi
  mov    %ebp,%r8d
  mov    $0x1,%ecx
  mov    %r15d,%edx
  mov    %r12d,%edi
  call   <fgui_draw_rectangle@plt>
  mov    0xc(%rsp),%edx
  lea    (%rbx,%rdx,1),%esi
  mov    %ebp,%r8d
  mov    $0x1,%ecx
  mov    %r14d,%edx
  mov    %r13d,%edi
  call   <fgui_draw_rectangle@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void draw4rectangles(uint16_t cx, uint16_t cy, uint16_t x, uint16_t y, uint32_t color) {
  fgui_draw_rectangle(cx - y, cy - x, y << 1, 1, color);
  fgui_draw_rectangle(cx - x, cy - y, x << 1, 1, color);
  fgui_draw_rectangle(cx - x, cy + y, x << 1, 1, color);
  fgui_draw_rectangle(cx - y, cy + x, y << 1, 1, color);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw4rectangles>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  lea    (%rcx,%rcx,1),%r9d
  push   %r14
  sub    %ecx,%r15d
  mov    %edx,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r15d,%edi
  push   %rbp
  mov    %ecx,%ebp
  mov    $0x1,%ecx
  sub    %r14d,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    %edx,%esi
  mov    %r9d,%edx
  sub    $0x18,%rsp
  mov    %r9d,0xc(%rsp)
  call   <fgui_draw_rectangle@plt>
  mov    %ebx,%esi
  lea    (%r14,%r14,1),%edx
  mov    %r13d,%r8d
  sub    %ebp,%esi
  mov    %r12d,%edi
  mov    $0x1,%ecx
  mov    %edx,0x8(%rsp)
  call   <fgui_draw_rectangle@plt>
  mov    0x8(%rsp),%edx
  lea    0x0(%rbp,%rbx,1),%esi
  mov    %r13d,%r8d
  mov    %r12d,%edi
  mov    $0x1,%ecx
  call   <fgui_draw_rectangle@plt>
  mov    0xc(%rsp),%edx
  add    $0x18,%rsp
  mov    %r13d,%r8d
  lea    (%rbx,%r14,1),%esi
  mov    %r15d,%edi
  pop    %rbx
  mov    $0x1,%ecx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <fgui_draw_rectangle@plt>
```

assistant: ```c
void draw4rectangles(uint16_t cx, uint16_t cy, uint16_t x, uint16_t y, uint32_t color) {
  fgui_draw_rectangle(cx - y, cy - x, y << 1, 1, color);
  fgui_draw_rectangle(cx - x, cy - y, x << 1, 1, color);
  fgui_draw_rectangle(cx - x, cy + y, x << 1, 1, color);
  fgui_draw_rectangle(cx - y, cy + x, y << 1, 1, color);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<draw4rectangles>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  lea    (%rcx,%rcx,1),%r9d
  push   %r14
  sub    %ecx,%r15d
  mov    %edx,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r15d,%edi
  push   %rbp
  mov    %ecx,%ebp
  mov    $0x1,%ecx
  sub    %r14d,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    %edx,%esi
  mov    %r9d,%edx
  sub    $0x18,%rsp
  mov    %r9d,0xc(%rsp)
  call   <fgui_draw_rectangle@plt>
  mov    %ebx,%esi
  lea    (%r14,%r14,1),%edx
  mov    %r13d,%r8d
  sub    %ebp,%esi
  mov    %r12d,%edi
  mov    $0x1,%ecx
  mov    %edx,0x8(%rsp)
  call   <fgui_draw_rectangle@plt>
  mov    0x8(%rsp),%edx
  lea    0x0(%rbp,%rbx,1),%esi
  mov    %r13d,%r8d
  mov    %r12d,%edi
  mov    $0x1,%ecx
  call   <fgui_draw_rectangle@plt>
  mov    0xc(%rsp),%edx
  add    $0x18,%rsp
  mov    %r13d,%r8d
  lea    (%rbx,%r14,1),%esi
  mov    %r15d,%edi
  pop    %rbx
  mov    $0x1,%ecx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <fgui_draw_rectangle@plt>
```

assistant: ```c
void draw4rectangles(uint16_t cx, uint16_t cy, uint16_t x, uint16_t y, uint32_t color) {
  fgui_draw_rectangle(cx - y, cy - x, y << 1, 1, color);
  fgui_draw_rectangle(cx - x, cy - y, x << 1, 1, color);
  fgui_draw_rectangle(cx - x, cy + y, x << 1, 1, color);
  fgui_draw_rectangle(cx - y, cy + x, y << 1, 1, color);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GSM_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sub    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int GSM_strlen(const char *str) {
  const char *eos = str;
  while (*eos++)
    ;
  return ((int)(eos - str - 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GSM_strlen>:
  endbr64
  mov    %rdi,%rax
L6:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L6
  sub    %rdi,%rax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int GSM_strlen(const char *str) {
  const char *eos = str;
  while (*eos++)
    ;
  return ((int)(eos - str - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GSM_strlen>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L0
  sub    %rdi,%rax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int GSM_strlen(const char *str) {
  const char *eos = str;
  while (*eos++)
    ;
  return ((int)(eos - str - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GSM_strlen>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L4
  sub    %rdi,%rax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int GSM_strlen(const char *str) {
  const char *eos = str;
  while (*eos++)
    ;
  return ((int)(eos - str - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__printf_chk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __printf_chk(int flags, const char *format, ...) {
  va_list args;
  int result;
  va_start(args, format);
  result = (*vfprintf)(stdout, format, args);
  va_end(args);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__printf_chk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int __printf_chk(int flags, const char *format, ...) {
  va_list args;
  int result;
  va_start(args, format);
  result = (*vfprintf)(stdout, format, args);
  va_end(args);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__printf_chk>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int __printf_chk(int flags, const char *format, ...) {
  va_list args;
  int result;
  va_start(args, format);
  result = (*vfprintf)(stdout, format, args);
  va_end(args);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__printf_chk>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int __printf_chk(int flags, const char *format, ...) {
  va_list args;
  int result;
  va_start(args, format);
  result = (*vfprintf)(stdout, format, args);
  va_end(args);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L70:
  cmp    %rdx,%rsp
  je     L68
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L70
L68:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L36
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L36:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L82
L43:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L82:
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L43
  mov    -0x50(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <check@plt>
  cmp    $0x1,%eax
  jne    L29
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L31
L29:
  mov    -0x50(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <check@plt>
  test   %eax,%eax
  jne    L31
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D35
type: string

tool: D18: %d

tool: D19: YES

tool: D35: NO

assistant: ```c
int main() {
  int n, i, j;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  if (check(a, n) == 1)
    printf("YES");
  else if (check(a, n) == 0)
    printf("NO");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L18:
  cmp    %rdx,%rsp
  je     L89
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L18
L89:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L48
  orq    $0x0,-0x8(%rsp,%rax,1)
L48:
  mov    %rsp,%r14
  test   %esi,%esi
  jle    L1
  mov    %r14,%r12
  mov    $0x0,%ebx
  lea    D21(%rip),%r13
L96:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%esi
  add    $0x4,%r12
  cmp    %ebx,%esi
  jg     L96
L1:
  mov    %r14,%rdi
  call   <check@plt>
  cmp    $0x1,%eax
  je     L31
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <check@plt>
  test   %eax,%eax
  je     L35
L53:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L31:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L35:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D0
datatype: string

tool: D21: %d

tool: D26: YES

tool: D0: NO

assistant: ```c
int main() {
  int n, i, j;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  if (check(a, n) == 1)
    printf("YES");
  else if (check(a, n) == 0)
    printf("NO");
  return 0;
}
```