user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D139(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D139(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D139(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  movss  D84(%rip),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  D57(%rip),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D101(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm0
  movss  D84(%rip),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  D57(%rip),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D130(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm0
  movss  D84(%rip),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  D57(%rip),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd %xmm0,%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  lea    D112(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D88
type: string
name: retrieve_data
arguments: tag: D139
type: string
name: retrieve_data
arguments: tag: D49
type: string
name: retrieve_data
arguments: tag: D60
type: string
name: retrieve_data
arguments: tag: D84
type: byte[4]
name: retrieve_data
arguments: tag: D57
type: byte[4]
name: retrieve_data
arguments: tag: D101
type: string
name: retrieve_data
arguments: tag: D130
type: string
name: retrieve_data
arguments: tag: D112
type: string

tool: D88: enter amount of loan:

tool: D139: %f

tool: D49: enter interest rate:

tool: D60: enter monthly payment:

tool: {"D84": [0x00,0x00,0x96,0x44]}

tool: {"D57": [0x00,0x00,0x80,0x3f]}

tool: D101: balance remaining after first payment: %.2f


tool: D130: balance remaining after second payment: %.2f


tool: D112: balance remaining after third payment: %.2f


assistant: ```c
int main(void) {
  float loan = 0.0, rate = 0.0, monthly_payment = 0.0;
  printf("enter amount of loan:\n");
  scanf("%f", &loan);
  printf("enter interest rate:\n");
  scanf("%f", &rate);
  printf("enter monthly payment:\n");
  scanf("%f", &monthly_payment);
  loan = loan * (1 + rate / 1200) - monthly_payment;
  printf("balance remaining after first payment: %.2f\n", loan);
  loan = loan * (1 + rate / 1200) - monthly_payment;
  printf("balance remaining after second payment: %.2f\n", loan);
  loan = loan * (1 + rate / 1200) - monthly_payment;
  printf("balance remaining after third payment: %.2f\n", loan);
  return 0;
}
```