ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L35
  lea    D24(%rip),%rbp
  lea    D39(%rip),%r12
  lea    D9(%rip),%r13
  lea    D11(%rip),%r14
  jmp    L9
L41:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L59
  mov    0x8(%rsp),%rax
  cqto
  shr    $0x3e,%rdx
  lea    (%rax,%rdx,1),%rsi
  and    $0x3,%esi
  sub    %rdx,%rsi
  add    $0x4,%esi
  mov    %ebx,%edi
  call   <pow@plt>
  mov    %eax,%ebx
L82:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %ebx,%esi
  sub    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%r15d
L59:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L35
L9:
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L41
  lea    0x10(%rsp),%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movzbl 0x10(%rsp,%rax,1),%eax
  movsbl %al,%ebx
  sub    $0x30,%ebx
  cmp    $0x1,%ebx
  jbe    L82
  cmp    $0x5,%ebx
  je     L82
  sub    $0x32,%eax
  cmp    $0x7,%al
  ja     L34
  movzbl %al,%eax
  movslq 0x0(%r13,%rax,4),%rax
  add    %r13,%rax
  notrack jmp *%rax
  mov    0x8(%rsp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  lea    (%rax,%rdx,1),%rsi
  and    $0x1,%esi
  sub    %rdx,%rsi
  add    $0x2,%esi
  mov    %ebx,%edi
  call   <pow@plt>
  mov    %eax,%ebx
  jmp    L82
L34:
  mov    %r15d,%ebx
  jmp    L82
L35:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type: string
name: unpack_data
arguments: data_tag: D24
type: string
name: unpack_data
arguments: data_tag: D39
type: string
name: unpack_data
arguments: data_tag: D11
type: string

tool: D14: %d

tool: D24: %s %lld

tool: D39: %d


tool: D11: 1

assistant: ```c
int main() {
  int i, j, c, len, num, temp, t, res;
  long long int b;
  char a[1001];
  scanf("%d", &t);
  while (t--) {
    scanf("%s %lld", &a, &b);
    if (b == 0) {
      printf("1\n");
      continue;
    }
    c = a[strlen(a) - 1] - '0';
    if (c == 0 || c == 1 || c == 5 || c == 6)
      res = c;
    else if (c == 2 || c == 3 || c == 7 || c == 8)
      res = pow(c, 4 + (b % 4));
    else if (c == 4 || c == 9)
      res = pow(c, 2 + (b % 2));
    printf("%d\n", res % 10);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<second_column>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rax
  add    $0x18,%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  jne    L0
  mov    -0x58(%rbp),%rax
  add    $0x30,%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L0
  lea    -0x50(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <swap_rows@plt>
  mov    -0x58(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matmul@plt>
  mov    -0x60(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    -0x60(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matmul@plt>
L0:
  mov    -0x58(%rbp),%rax
  add    $0x30,%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L36
  mov    -0x58(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <zero_second_column@plt>
  mov    -0x58(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matmul@plt>
  mov    -0x60(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    -0x60(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matmul@plt>
L36:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void second_column(long A[3][3], long P[3][3]) {
  long L[3][3];
  if ((A[1][1] == 0) && (A[2][1] != 0)) {
    swap_rows(L, 1, 2);
    matmul(A, L, A);
    matmul(P, L, P);
  }
  if (A[2][1] != 0) {
    zero_second_column(L, A);
    matmul(A, L, A);
    matmul(P, L, P);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<second_column>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmpq   $0x0,0x20(%rdi)
  jne    L4
  cmpq   $0x0,0x38(%rdi)
  jne    L41
L13:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    %rsp,%r12
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <swap_rows@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <matmul@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
L4:
  cmpq   $0x0,0x38(%rbx)
  je     L13
  mov    %rsp,%r12
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <zero_second_column@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <matmul@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  jmp    L13
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void second_column(long A[3][3], long P[3][3]) {
  long L[3][3];
  if ((A[1][1] == 0) && (A[2][1] != 0)) {
    swap_rows(L, 1, 2);
    matmul(A, L, A);
    matmul(P, L, P);
  }
  if (A[2][1] != 0) {
    zero_second_column(L, A);
    matmul(A, L, A);
    matmul(P, L, P);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<second_column>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  mov    0x38(%rdi),%rax
  cmpq   $0x0,0x20(%rdi)
  jne    L6
  test   %rax,%rax
  jne    L1
L26:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rsp,%r13
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <swap_rows@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <matmul@plt>
L6:
  cmpq   $0x0,0x38(%rbp)
  je     L26
  mov    %rsp,%r13
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <zero_second_column@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <matmul@plt>
  jmp    L26
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void second_column(long A[3][3], long P[3][3]) {
  long L[3][3];
  if ((A[1][1] == 0) && (A[2][1] != 0)) {
    swap_rows(L, 1, 2);
    matmul(A, L, A);
    matmul(P, L, P);
  }
  if (A[2][1] != 0) {
    zero_second_column(L, A);
    matmul(A, L, A);
    matmul(P, L, P);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<second_column>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  mov    0x38(%rdi),%rax
  cmpq   $0x0,0x20(%rdi)
  jne    L18
  test   %rax,%rax
  jne    L7
L29:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rsp,%r13
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <swap_rows@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <matmul@plt>
L18:
  cmpq   $0x0,0x38(%rbp)
  je     L29
  mov    %rsp,%r13
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <zero_second_column@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <matmul@plt>
  jmp    L29
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void second_column(long A[3][3], long P[3][3]) {
  long L[3][3];
  if ((A[1][1] == 0) && (A[2][1] != 0)) {
    swap_rows(L, 1, 2);
    matmul(A, L, A);
    matmul(P, L, P);
  }
  if (A[2][1] != 0) {
    zero_second_column(L, A);
    matmul(A, L, A);
    matmul(P, L, P);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_huf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L13
L1:
  movzbl -0x11(%rbp),%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <decomp@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L13:
  lea    -0x11(%rbp),%rcx
  mov    -0x2c(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L1
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void read_huf(char *enc, int fd) {
  int err;
  char *bit, buff;
  bit = malloc(8 * sizeof(int));
  while (read(fd, &buff, 1) > 0) {
    decomp(buff, bit);
    strcat(enc, bit);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_huf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x7(%rsp),%r13
  jmp    L26
L18:
  movsbl 0x7(%rsp),%edi
  mov    %rbx,%rsi
  call   <decomp@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L26:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L18
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read_huf(char *enc, int fd) {
  int err;
  char *bit, buff;
  bit = malloc(8 * sizeof(int));
  while (read(fd, &buff, 1) > 0) {
    decomp(buff, bit);
    strcat(enc, bit);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_huf>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x20,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
  call   <malloc@plt>
  mov    %rax,%rbx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl 0x7(%rsp),%edi
  mov    %rbx,%rsi
  call   <decomp@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L18:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read_huf(char *enc, int fd) {
  int err;
  char *bit, buff;
  bit = malloc(8 * sizeof(int));
  while (read(fd, &buff, 1) > 0) {
    decomp(buff, bit);
    strcat(enc, bit);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<read_huf>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x20,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
  call   <malloc@plt>
  mov    %rax,%rbx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L17:
  movsbl 0x7(%rsp),%edi
  mov    %rbx,%rsi
  call   <decomp@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L19:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read_huf(char *enc, int fd) {
  int err;
  char *bit, buff;
  bit = malloc(8 * sizeof(int));
  while (read(fd, &buff, 1) > 0) {
    decomp(buff, bit);
    strcat(enc, bit);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ameth_cmp_BSEARCH_CMP_FN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ameth_cmp@plt>
  leave
  ret
```

assistant: ```c
int ameth_cmp_BSEARCH_CMP_FN(const void *a_, const void *b_) {
  const EVP_PKEY_ASN1_METHOD *const *a = a_;
  const EVP_PKEY_ASN1_METHOD *const *b = b_;
  return ameth_cmp(a, b);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ameth_cmp_BSEARCH_CMP_FN>:
  endbr64
  sub    $0x8,%rsp
  call   <ameth_cmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ameth_cmp_BSEARCH_CMP_FN(const void *a_, const void *b_) {
  const EVP_PKEY_ASN1_METHOD *const *a = a_;
  const EVP_PKEY_ASN1_METHOD *const *b = b_;
  return ameth_cmp(a, b);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ameth_cmp_BSEARCH_CMP_FN>:
  endbr64
  jmp    1050 <ameth_cmp@plt>
```

assistant: ```c
int ameth_cmp_BSEARCH_CMP_FN(const void *a_, const void *b_) {
  const EVP_PKEY_ASN1_METHOD *const *a = a_;
  const EVP_PKEY_ASN1_METHOD *const *b = b_;
  return ameth_cmp(a, b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ameth_cmp_BSEARCH_CMP_FN>:
  endbr64
  jmp    1050 <ameth_cmp@plt>
```

assistant: ```c
int ameth_cmp_BSEARCH_CMP_FN(const void *a_, const void *b_) {
  const EVP_PKEY_ASN1_METHOD *const *a = a_;
  const EVP_PKEY_ASN1_METHOD *const *b = b_;
  return ameth_cmp(a, b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xe,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  if (0 || 1) {
    i = 14;
  } else {
    i = 15;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0xe,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  if (0 || 1) {
    i = 14;
  } else {
    i = 15;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0xe,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  if (0 || 1) {
    i = 14;
  } else {
    i = 15;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0xe,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  if (0 || 1) {
    i = 14;
  } else {
    i = 15;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<qf_spin_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void qf_spin_unlock(volatile int *lock) {
  __sync_lock_release(lock);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<qf_spin_unlock>:
  endbr64
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void qf_spin_unlock(volatile int *lock) {
  __sync_lock_release(lock);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qf_spin_unlock>:
  endbr64
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void qf_spin_unlock(volatile int *lock) {
  __sync_lock_release(lock);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<qf_spin_unlock>:
  endbr64
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void qf_spin_unlock(volatile int *lock) {
  __sync_lock_release(lock);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_image_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
int get_image_size(file_name, rows, cols)
char *file_name;
long *cols, *rows;
{}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_image_size>:
  endbr64
  ret
```

assistant: ```c
int get_image_size(file_name, rows, cols)
char *file_name;
long *cols, *rows;
{}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_image_size>:
  endbr64
  ret
```

assistant: ```c
int get_image_size(file_name, rows, cols)
char *file_name;
long *cols, *rows;
{}
```
user: What is the c source code of the assembly code below?

```asm
<get_image_size>:
  endbr64
  ret
```

assistant: ```c
int get_image_size(file_name, rows, cols)
char *file_name;
long *cols, *rows;
{}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vrand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    D11(%rip),%eax
  movd   %eax,%xmm0
  call   <drand@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    D13(%rip),%eax
  movd   %eax,%xmm0
  call   <drand@plt>
  movd   %xmm0,%eax
  movss  D14(%rip),%xmm1
  movd   %eax,%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  D14(%rip),%xmm0
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <sqrtf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <cosf@plt>
  mulss  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  movss  -0x14(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinf@plt>
  mulss  -0x18(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  movss  -0x14(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
datatype: byte[4]
name: unpack_data
arguments: data_tag: D13
datatype: byte[4]
name: unpack_data
arguments: data_tag: D14
datatype: byte[4]

tool: {"D11": [0xdb,0x0f,0xc9,0x40]}

tool: {"D13": [0x00,0x00,0x00,0x40]}

tool: {"D14": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void vrand(float a, float *x, float *y, float *z) {
  float v = drand(2.0f * 3.141592654f);
  float u = drand(2.0f) - 1.0f;
  float r = sqrtf(1.0f - u * u);
  *x = a * r * cosf(v);
  *y = a * r * sinf(v);
  *z = a * u;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vrand>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movss  %xmm0,0x14(%rsp)
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  movss  D7(%rip),%xmm0
  call   <drand@plt>
  movss  %xmm0,0x8(%rsp)
  movss  D17(%rip),%xmm0
  call   <drand@plt>
  movaps %xmm0,%xmm1
  movss  D14(%rip),%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rsp)
  mulss  %xmm1,%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm0,%xmm1
  ja     L5
  sqrtss %xmm0,%xmm0
  movss  %xmm0,0x10(%rsp)
L1:
  lea    0x1c(%rsp),%rdi
  lea    0x18(%rsp),%rsi
  movss  0x8(%rsp),%xmm0
  call   <sincosf@plt>
  movss  0x10(%rsp),%xmm0
  movss  0x14(%rsp),%xmm3
  mulss  %xmm3,%xmm0
  movaps %xmm0,%xmm1
  mulss  0x18(%rsp),%xmm1
  movss  %xmm1,(%r12)
  mulss  0x1c(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0xc(%rsp),%xmm0
  mulss  %xmm3,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <sqrtf@plt>
  movss  %xmm0,0x10(%rsp)
  jmp    L1
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: byte[4]
name: unpack_data
arguments: tag: D17
datatype: byte[4]
name: unpack_data
arguments: tag: D14
datatype: byte[4]

tool: {"D7": [0xdb,0x0f,0xc9,0x40]}

tool: {"D17": [0x00,0x00,0x00,0x40]}

tool: {"D14": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void vrand(float a, float *x, float *y, float *z) {
  float v = drand(2.0f * 3.141592654f);
  float u = drand(2.0f) - 1.0f;
  float r = sqrtf(1.0f - u * u);
  *x = a * r * cosf(v);
  *y = a * r * sinf(v);
  *z = a * u;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vrand>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  movss  %xmm0,0xc(%rsp)
  movss  D23(%rip),%xmm0
  call   <drand@plt>
  movss  %xmm0,0x10(%rsp)
  movss  D10(%rip),%xmm0
  call   <drand@plt>
  movss  0x10(%rsp),%xmm3
  movaps %xmm0,%xmm2
  movss  D16(%rip),%xmm0
  subss  %xmm0,%xmm2
  movaps %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm0,%xmm1
  ja     L18
  movaps %xmm0,%xmm1
  sqrtss %xmm1,%xmm1
L4:
  lea    0x1c(%rsp),%rdi
  lea    0x18(%rsp),%rsi
  movaps %xmm3,%xmm0
  movss  %xmm1,0x14(%rsp)
  movss  %xmm2,0x10(%rsp)
  call   <sincosf@plt>
  movss  0xc(%rsp),%xmm4
  movss  0x14(%rsp),%xmm1
  movss  0x10(%rsp),%xmm2
  mulss  %xmm4,%xmm1
  mulss  %xmm4,%xmm2
  movaps %xmm1,%xmm0
  mulss  0x18(%rsp),%xmm1
  mulss  0x1c(%rsp),%xmm0
  movss  %xmm1,(%r12)
  movss  %xmm0,0x0(%rbp)
  movss  %xmm2,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  movss  %xmm2,0x14(%rsp)
  movss  %xmm3,0x10(%rsp)
  call   <sqrtf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm3
  movaps %xmm0,%xmm1
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_label: D23
type: byte[4]
name: disassemble_data
arguments: data_label: D10
type: byte[4]
name: disassemble_data
arguments: data_label: D16
type: byte[4]

tool: {"D23": [0xdb,0x0f,0xc9,0x40]}

tool: {"D10": [0x00,0x00,0x00,0x40]}

tool: {"D16": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void vrand(float a, float *x, float *y, float *z) {
  float v = drand(2.0f * 3.141592654f);
  float u = drand(2.0f) - 1.0f;
  float r = sqrtf(1.0f - u * u);
  *x = a * r * cosf(v);
  *y = a * r * sinf(v);
  *z = a * u;
}
```