ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy_border>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L24
L20:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L20
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L25:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L25
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_border(int rmin, int rmax, int cmin, int cmax, double **grid) {
  int i;
  for (i = cmin - 1; i <= cmax + 1; ++i) {
    grid[rmin - 1][i] = grid[rmax][i];
    grid[rmax + 1][i] = grid[rmin][i];
  }
  for (i = rmin - 1; i <= rmax + 1; ++i) {
    grid[rmin - 1][i] = grid[rmax][i];
    grid[rmax + 1][i] = grid[rmin][i];
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copy_border>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edx,%ebp
  mov    %ecx,%edx
  lea    -0x1(%rbp),%eax
  lea    0x1(%rcx),%ecx
  cmp    %ecx,%eax
  jg     L35
  movslq %esi,%rcx
  shl    $0x3,%rcx
  lea    (%r8,%rcx,1),%rbx
  movslq %edi,%r9
  shl    $0x3,%r9
  lea    -0x8(%r8,%r9,1),%r11
  add    %r8,%r9
  lea    0x8(%r8,%rcx,1),%r10
  cltq
  shl    $0x3,%rax
  add    $0x2,%edx
  sub    %ebp,%edx
  movslq %ebp,%rbp
  add    %rbp,%rdx
  shl    $0x3,%rdx
L22:
  mov    (%rbx),%rcx
  movsd  (%rcx,%rax,1),%xmm0
  mov    (%r11),%rcx
  movsd  %xmm0,(%rcx,%rax,1)
  mov    (%r9),%rcx
  movsd  (%rcx,%rax,1),%xmm0
  mov    (%r10),%rcx
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L22
L35:
  lea    -0x1(%rdi),%eax
  lea    0x1(%rsi),%edx
  cmp    %edx,%eax
  jg     L24
  movslq %esi,%rdx
  shl    $0x3,%rdx
  lea    (%r8,%rdx,1),%r11
  movslq %edi,%rcx
  lea    0x0(,%rcx,8),%r9
  lea    -0x8(%r8,%r9,1),%r10
  add    %r8,%r9
  lea    0x8(%r8,%rdx,1),%r8
  cltq
  shl    $0x3,%rax
  lea    0x2(%rsi),%edx
  sub    %edi,%edx
  add    %rcx,%rdx
  shl    $0x3,%rdx
L0:
  mov    (%r11),%rcx
  movsd  (%rcx,%rax,1),%xmm0
  mov    (%r10),%rcx
  movsd  %xmm0,(%rcx,%rax,1)
  mov    (%r9),%rcx
  movsd  (%rcx,%rax,1),%xmm0
  mov    (%r8),%rcx
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L0
L24:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void copy_border(int rmin, int rmax, int cmin, int cmax, double **grid) {
  int i;
  for (i = cmin - 1; i <= cmax + 1; ++i) {
    grid[rmin - 1][i] = grid[rmax][i];
    grid[rmax + 1][i] = grid[rmin][i];
  }
  for (i = rmin - 1; i <= rmax + 1; ++i) {
    grid[rmin - 1][i] = grid[rmax][i];
    grid[rmax + 1][i] = grid[rmin][i];
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_border>:
  endbr64
  push   %rbx
  movslq %edx,%rbx
  mov    %ecx,%edx
  add    $0x1,%ecx
  lea    -0x1(%rbx),%eax
  cmp    %ecx,%eax
  jg     L35
  add    $0x2,%edx
  movslq %esi,%rcx
  movslq %edi,%r9
  cltq
  sub    %ebx,%edx
  mov    (%r8,%rcx,8),%r11
  mov    -0x8(%r8,%r9,8),%r10
  shl    $0x3,%rax
  add    %rbx,%rdx
  mov    (%r8,%r9,8),%r9
  mov    0x8(%r8,%rcx,8),%rcx
  shl    $0x3,%rdx
  xchg   %ax,%ax
L38:
  movsd  (%r11,%rax,1),%xmm0
  movsd  %xmm0,(%r10,%rax,1)
  movsd  (%r9,%rax,1),%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L38
L35:
  lea    -0x1(%rdi),%eax
  lea    0x1(%rsi),%edx
  cmp    %edx,%eax
  jg     L33
  movslq %esi,%rdx
  movslq %edi,%rbx
  cltq
  mov    (%r8,%rdx,8),%r11
  mov    0x8(%r8,%rdx,8),%rcx
  lea    0x2(%rsi),%edx
  shl    $0x3,%rax
  sub    %edi,%edx
  mov    -0x8(%r8,%rbx,8),%r10
  mov    (%r8,%rbx,8),%r9
  add    %rbx,%rdx
  shl    $0x3,%rdx
  nopl   0x0(%rax)
L23:
  movsd  (%r11,%rax,1),%xmm0
  movsd  %xmm0,(%r10,%rax,1)
  movsd  (%r9,%rax,1),%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L23
L33:
  pop    %rbx
  ret
```

assistant: ```c
void copy_border(int rmin, int rmax, int cmin, int cmax, double **grid) {
  int i;
  for (i = cmin - 1; i <= cmax + 1; ++i) {
    grid[rmin - 1][i] = grid[rmax][i];
    grid[rmax + 1][i] = grid[rmin][i];
  }
  for (i = rmin - 1; i <= rmax + 1; ++i) {
    grid[rmin - 1][i] = grid[rmax][i];
    grid[rmax + 1][i] = grid[rmin][i];
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ustrcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  test   %r13,%r13
  je     L48
  test   %rbx,%rbx
  jne    L71
L48:
  mov    $0x0,%eax
  jmp    L7
L21:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  cmp    %eax,%r12d
  je     L68
  movzbl (%rbx),%eax
  movsbl %al,%eax
  xor    %r12d,%eax
  cmp    $0x20,%eax
  jne    L28
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <upcase@plt>
  mov    %eax,%r12d
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <upcase@plt>
  cmp    %eax,%r12d
  je     L68
L28:
  mov    $0x0,%eax
  jmp    L7
L68:
  add    $0x1,%rbx
L71:
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rax),%eax
  movsbl %al,%r12d
  test   %r12d,%r12d
  jne    L21
  movzbl (%rbx),%eax
  movsbl %al,%eax
  cmp    %eax,%r12d
  jne    L64
  mov    $0x1,%eax
  jmp    L7
L64:
  mov    $0xffffffff,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
ustrcmp(s1, s2) register char *s1, *s2;
{
  register int c;
  if (!s1 || !s2)
    return (0);
  while (c = *s1++) {
    if (c != *s2) {
      if (((c ^ *s2) != 040) || (upcase(c) != upcase(*s2)))
        return (0);
    }
    s2++;
  }
  return (c == *s2 ? 1 : -1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ustrcmp>:
  endbr64
  test   %rdi,%rdi
  je     L87
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L84
  lea    0x1(%rdi),%rbp
  movzbl (%rdi),%edx
  movsbl %dl,%edi
  test   %edi,%edi
  jne    L23
L29:
  cmpb   $0x1,(%rbx)
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  add    $0x1,%rbx
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edx
  movsbl %dl,%edi
  test   %edi,%edi
  je     L29
L23:
  movzbl (%rbx),%eax
  cmp    %dl,%al
  je     L39
  xor    %edx,%eax
  cmp    $0x20,%al
  jne    L53
  mov    $0x0,%eax
  call   <upcase@plt>
  mov    %eax,%r12d
  movsbl (%rbx),%edi
  mov    $0x0,%eax
  call   <upcase@plt>
  cmp    %eax,%r12d
  je     L39
  mov    $0x0,%eax
  jmp    L11
L84:
  mov    $0x0,%eax
  jmp    L11
L53:
  mov    $0x0,%eax
  jmp    L11
L87:
  mov    $0x0,%eax
  ret
```

assistant: ```c
ustrcmp(s1, s2) register char *s1, *s2;
{
  register int c;
  if (!s1 || !s2)
    return (0);
  while (c = *s1++) {
    if (c != *s2) {
      if (((c ^ *s2) != 040) || (upcase(c) != upcase(*s2)))
        return (0);
    }
    s2++;
  }
  return (c == *s2 ? 1 : -1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ustrcmp>:
  endbr64
  test   %rdi,%rdi
  je     L29
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L14
  lea    0x1(%rdi),%rbp
  movsbl (%rdi),%edi
  mov    %edi,%edx
  test   %edi,%edi
  je     L67
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl (%rbx),%eax
  cmp    %dl,%al
  je     L47
  xor    %edx,%eax
  cmp    $0x20,%al
  jne    L14
  xor    %eax,%eax
  call   <upcase@plt>
  movsbl (%rbx),%edi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <upcase@plt>
  cmp    %eax,%r12d
  jne    L14
L47:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %edi,%edx
  test   %edi,%edi
  jne    L16
L67:
  cmpb   $0x1,(%rbx)
  pop    %rbx
  sbb    %eax,%eax
  pop    %rbp
  pop    %r12
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
L14:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
ustrcmp(s1, s2) register char *s1, *s2;
{
  register int c;
  if (!s1 || !s2)
    return (0);
  while (c = *s1++) {
    if (c != *s2) {
      if (((c ^ *s2) != 040) || (upcase(c) != upcase(*s2)))
        return (0);
    }
    s2++;
  }
  return (c == *s2 ? 1 : -1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ustrcmp>:
  endbr64
  test   %rdi,%rdi
  je     L48
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L1
  lea    0x1(%rdi),%rbp
  movsbl (%rdi),%edi
  mov    %edi,%edx
  test   %edi,%edi
  je     L55
  nopw   0x0(%rax,%rax,1)
L29:
  movzbl (%rbx),%eax
  cmp    %dl,%al
  je     L9
  xor    %edx,%eax
  cmp    $0x20,%al
  jne    L1
  xor    %eax,%eax
  call   <upcase@plt>
  movsbl (%rbx),%edi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <upcase@plt>
  cmp    %eax,%r12d
  jne    L1
L9:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %edi,%edx
  test   %edi,%edi
  jne    L29
L55:
  cmpb   $0x1,(%rbx)
  pop    %rbx
  sbb    %eax,%eax
  pop    %rbp
  pop    %r12
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  xor    %eax,%eax
  ret
```

assistant: ```c
ustrcmp(s1, s2) register char *s1, *s2;
{
  register int c;
  if (!s1 || !s2)
    return (0);
  while (c = *s1++) {
    if (c != *s2) {
      if (((c ^ *s2) != 040) || (upcase(c) != upcase(*s2)))
        return (0);
    }
    s2++;
  }
  return (c == *s2 ? 1 : -1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvt_31x13_bin64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cvt_31x6p5_bin32@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <cvt_31x6p5_bin32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void cvt_31x13_bin64(uint8_t *gfv, uint32_t bv0, uint32_t bv1) {
  uint8_t gfv0, gfv1;
  gfv0 = cvt_31x6p5_bin32(gfv, bv0);
  gfv1 = cvt_31x6p5_bin32(&gfv[6], bv1);
  gfv[12] = gfv0 + gfv1 * 5;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cvt_31x13_bin64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r12d
  call   <cvt_31x6p5_bin32@plt>
  mov    %eax,%ebp
  lea    0x18(%rbx),%rdi
  mov    %r12d,%esi
  call   <cvt_31x6p5_bin32@plt>
  lea    (%rax,%rax,4),%eax
  add    %ebp,%eax
  mov    %eax,0x30(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void cvt_31x13_bin64(uint8_t *gfv, uint32_t bv0, uint32_t bv1) {
  uint8_t gfv0, gfv1;
  gfv0 = cvt_31x6p5_bin32(gfv, bv0);
  gfv1 = cvt_31x6p5_bin32(&gfv[6], bv1);
  gfv[12] = gfv0 + gfv1 * 5;
}
```
user: What is the c source code of the assembly code below:

```asm
<cvt_31x13_bin64>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <cvt_31x6p5_bin32@plt>
  lea    0x18(%rbx),%rdi
  mov    %r12d,%esi
  mov    %eax,%ebp
  call   <cvt_31x6p5_bin32@plt>
  lea    (%rax,%rax,4),%eax
  add    %ebp,%eax
  mov    %eax,0x30(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void cvt_31x13_bin64(uint8_t *gfv, uint32_t bv0, uint32_t bv1) {
  uint8_t gfv0, gfv1;
  gfv0 = cvt_31x6p5_bin32(gfv, bv0);
  gfv1 = cvt_31x6p5_bin32(&gfv[6], bv1);
  gfv[12] = gfv0 + gfv1 * 5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cvt_31x13_bin64>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <cvt_31x6p5_bin32@plt>
  lea    0x18(%rbx),%rdi
  mov    %r12d,%esi
  mov    %eax,%ebp
  call   <cvt_31x6p5_bin32@plt>
  lea    (%rax,%rax,4),%eax
  add    %ebp,%eax
  mov    %eax,0x30(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void cvt_31x13_bin64(uint8_t *gfv, uint32_t bv0, uint32_t bv1) {
  uint8_t gfv0, gfv1;
  gfv0 = cvt_31x6p5_bin32(gfv, bv0);
  gfv1 = cvt_31x6p5_bin32(&gfv[6], bv1);
  gfv[12] = gfv0 + gfv1 * 5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <count_leading_whitespace@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L3
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_ltrim(char *str) {
  int len;
  int num_chars = count_leading_whitespace(str);
  if (num_chars > 0) {
    len = strlen(str) - num_chars;
    memmove(str, str + num_chars, len);
    str[len] = '\0';
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<str_ltrim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <count_leading_whitespace@plt>
  test   %eax,%eax
  jg     L19
L11:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    %ebp,%eax
  mov    %eax,%r12d
  movslq %ebp,%rsi
  add    %rbx,%rsi
  mov    %eax,%edx
  mov    %rbx,%rdi
  call   <memmove@plt>
  movslq %r12d,%r12
  movb   $0x0,(%rbx,%r12,1)
  jmp    L11
```

assistant: ```c
char *str_ltrim(char *str) {
  int len;
  int num_chars = count_leading_whitespace(str);
  if (num_chars > 0) {
    len = strlen(str) - num_chars;
    memmove(str, str + num_chars, len);
    str[len] = '\0';
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <count_leading_whitespace@plt>
  test   %eax,%eax
  jle    L8
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  movslq %ebx,%rsi
  mov    %r12,%rdi
  sub    %ebx,%eax
  add    %r12,%rsi
  movslq %eax,%rbp
  mov    %ebp,%edx
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbp,1)
L8:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_ltrim(char *str) {
  int len;
  int num_chars = count_leading_whitespace(str);
  if (num_chars > 0) {
    len = strlen(str) - num_chars;
    memmove(str, str + num_chars, len);
    str[len] = '\0';
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str_ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <count_leading_whitespace@plt>
  test   %eax,%eax
  jle    L1
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  movslq %ebx,%rsi
  mov    %r12,%rdi
  sub    %ebx,%eax
  add    %r12,%rsi
  movslq %eax,%rbp
  mov    %ebp,%edx
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbp,1)
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_ltrim(char *str) {
  int len;
  int num_chars = count_leading_whitespace(str);
  if (num_chars > 0) {
    len = strlen(str) - num_chars;
    memmove(str, str + num_chars, len);
    str[len] = '\0';
  }
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInteger@plt>
  mov    %eax,-0x8(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInteger@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <GCD@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D7
data_type: string
name: parse_data
arguments: label: D10
data_type: string
name: parse_data
arguments: label: D9
data_type: string
name: parse_data
arguments: label: D40
data_type: string

tool: D11: This program calculates greatest common divisors.

tool: D7: Enter two integers, x and y.

tool: D10: x = ? 

tool: D9: y = ? 

tool: D40: The gcd of %d and %d is %d.


assistant: ```c
main() {
  int x, y;
  printf("This program calculates greatest common divisors.\n");
  printf("Enter two integers, x and y.\n");
  printf("x = ? ");
  x = GetInteger();
  printf("y = ? ");
  y = GetInteger();
  printf("The gcd of %d and %d is %d.\n", x, y, GCD(x, y));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInteger@plt>
  mov    %eax,%ebx
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInteger@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <GCD@plt>
  mov    %eax,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D21
type: string
name: read_data
arguments: data_tag: D8
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D36
type: string
name: read_data
arguments: data_tag: D30
type: string

tool: D21: This program calculates greatest common divisors.

tool: D8: Enter two integers, x and y.

tool: D25: x = ? 

tool: D36: y = ? 

tool: D30: The gcd of %d and %d is %d.


assistant: ```c
main() {
  int x, y;
  printf("This program calculates greatest common divisors.\n");
  printf("Enter two integers, x and y.\n");
  printf("x = ? ");
  x = GetInteger();
  printf("y = ? ");
  y = GetInteger();
  printf("The gcd of %d and %d is %d.\n", x, y, GCD(x, y));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInteger@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInteger@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <GCD@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
type_infered: string
name: retrieve_data
arguments: data_tag: D36
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string

tool: D24: This program calculates greatest common divisors.

tool: D36: Enter two integers, x and y.

tool: D1: x = ? 

tool: D0: y = ? 

tool: D14: The gcd of %d and %d is %d.


assistant: ```c
main() {
  int x, y;
  printf("This program calculates greatest common divisors.\n");
  printf("Enter two integers, x and y.\n");
  printf("x = ? ");
  x = GetInteger();
  printf("y = ? ");
  y = GetInteger();
  printf("The gcd of %d and %d is %d.\n", x, y, GCD(x, y));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInteger@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInteger@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <GCD@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string
name: retrieve_data
arguments: data_tag: D35
type: string
name: retrieve_data
arguments: data_tag: D42
type: string
name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D6
type: string

tool: D4: This program calculates greatest common divisors.

tool: D35: Enter two integers, x and y.

tool: D42: x = ? 

tool: D19: y = ? 

tool: D6: The gcd of %d and %d is %d.


assistant: ```c
main() {
  int x, y;
  printf("This program calculates greatest common divisors.\n");
  printf("Enter two integers, x and y.\n");
  printf("x = ? ");
  x = GetInteger();
  printf("y = ? ");
  y = GetInteger();
  printf("The gcd of %d and %d is %d.\n", x, y, GCD(x, y));
}
```