ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MMX_PUNPCKHDQ>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x66,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0x0(,%r12,8),%ebx
  or     $0xc0,%bl
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x62,%edi
  call   <addbyte@plt>
  mov    %ebp,%edi
  or     %ebx,%edi
  or     %r12d,%ebx
  call   <addbyte@plt>
  mov    $0x66,%edi
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x70,%edi
  call   <addbyte@plt>
  mov    %ebx,%edi
  call   <addbyte@plt>
  pop    %rbx
  mov    $0xe,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void MMX_PUNPCKHDQ(int dst_reg, int src_reg) {
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x62);
  addbyte(0xc0 | (dst_reg << 3) | src_reg);
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x70);
  addbyte(0xc0 | (dst_reg << 3) | dst_reg);
  addbyte(0x0e);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getVersion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x410(%rbp),%rax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x420(%rbp)
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x400,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x418(%rbp)
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  cmpq   $0x0,-0x418(%rbp)
  je     L34
  mov    $0x3a,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L38
L34:
  mov    $0x0,%eax
  jmp    L33
L38:
  addq   $0x1,-0x418(%rbp)
  mov    -0x418(%rbp),%rax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string
name: parse_data
arguments: label: D36
type_guessed: string

tool: D4:  --version

tool: D36: r

assistant: ```c
char const *getVersion(char const *const aExecutable) {
  static char lBuff[1024];
  char lTestedString[1024];
  FILE *lIn;
  char *lTmp;
  strcpy(lTestedString, aExecutable);
  strcat(lTestedString, " --version");
  lIn = popen(lTestedString, "r");
  lTmp = fgets(lBuff, sizeof(lBuff), lIn);
  pclose(lIn);
  if (!lTmp || !(lTmp = strchr(lBuff, ':')))
    return 0;
  lTmp++;
  return lTmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getVersion>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    D39(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D33(%rip),%rsi
  mov    %rbx,%rdi
  call   <popen@plt>
  mov    %rax,%rbp
  mov    %rax,%rdx
  mov    $0x400,%esi
  lea    D0(%rip),%rdi
  call   <fgets@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <pclose@plt>
  test   %rbx,%rbx
  je     L14
  mov    $0x3a,%esi
  lea    D0(%rip),%rdi
  call   <strchr@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rax
  mov    %rax,%rbx
L14:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    %rbx,%rax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D39
type_guessed: string
name: retrieve_data
arguments: tag: D33
type_guessed: string

tool: D39:  --version

tool: D33: r

assistant: ```c
char const *getVersion(char const *const aExecutable) {
  static char lBuff[1024];
  char lTestedString[1024];
  FILE *lIn;
  char *lTmp;
  strcpy(lTestedString, aExecutable);
  strcat(lTestedString, " --version");
  lIn = popen(lTestedString, "r");
  lTmp = fgets(lBuff, sizeof(lBuff), lIn);
  pclose(lIn);
  if (!lTmp || !(lTmp = strchr(lBuff, ':')))
    return 0;
  lTmp++;
  return lTmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getVersion>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  lea    D23(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  call   <popen@plt>
  mov    %r12,%rdi
  mov    $0x400,%esi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <fgets@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <pclose@plt>
  test   %rbx,%rbx
  je     L6
  mov    $0x3a,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  add    $0x1,%rax
L3:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L6:
  xor    %eax,%eax
  jmp    L3
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
type_infered: string
name: disassemble_data
arguments: label: D10
type_infered: string

tool: D23:  --version

tool: D10: r

assistant: ```c
char const *getVersion(char const *const aExecutable) {
  static char lBuff[1024];
  char lTestedString[1024];
  FILE *lIn;
  char *lTmp;
  strcpy(lTestedString, aExecutable);
  strcat(lTestedString, " --version");
  lIn = popen(lTestedString, "r");
  lTmp = fgets(lBuff, sizeof(lBuff), lIn);
  pclose(lIn);
  if (!lTmp || !(lTmp = strchr(lBuff, ':')))
    return 0;
  lTmp++;
  return lTmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getVersion>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  lea    D24(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  call   <popen@plt>
  mov    %r12,%rdi
  mov    $0x400,%esi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <fgets@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <pclose@plt>
  test   %rbx,%rbx
  je     L23
  mov    $0x3a,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L23
  add    $0x1,%rax
L15:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L23:
  xor    %eax,%eax
  jmp    L15
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string

tool: D24:  --version

tool: D4: r

assistant: ```c
char const *getVersion(char const *const aExecutable) {
  static char lBuff[1024];
  char lTestedString[1024];
  FILE *lIn;
  char *lTmp;
  strcpy(lTestedString, aExecutable);
  strcat(lTestedString, " --version");
  lIn = popen(lTestedString, "r");
  lTmp = fgets(lBuff, sizeof(lBuff), lIn);
  pclose(lIn);
  if (!lTmp || !(lTmp = strchr(lBuff, ':')))
    return 0;
  lTmp++;
  return lTmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<cmp15>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L74
  mov    -0x14(%rbp),%eax
  jmp    L87
L74:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L75
  mov    -0x14(%rbp),%eax
  jmp    L87
L75:
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x2,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L28
  mov    -0x14(%rbp),%eax
  jmp    L87
L28:
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x3,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L45
  mov    -0x14(%rbp),%eax
  jmp    L87
L45:
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L44
  mov    -0x14(%rbp),%eax
  jmp    L87
L44:
  mov    $0x0,%eax
L87:
  pop    %rbp
  ret
```

assistant: ```c
int cmp15(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmp15>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L17
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L17
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L17
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L17
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L17:
  ret
```

assistant: ```c
int cmp15(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp15>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L1
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L1
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L1
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L1
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L1:
  ret
```

assistant: ```c
int cmp15(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp15>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L14
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L14
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L14
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L14
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L14:
  ret
```

assistant: ```c
int cmp15(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <getid@plt>
  movl   $0x0,-0x44(%rbp)
  movl   $0x1,-0x48(%rbp)
  jmp    L22
L21:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    %eax,-0x54(%rbp)
  jne    L41
  mov    -0x48(%rbp),%eax
  mov    %eax,%edi
  call   <printid@plt>
  jmp    L33
L41:
  addl   $0x2,-0x48(%rbp)
L22:
  cmpl   $0x9,-0x48(%rbp)
  jle    L21
L33:
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int find(int val) {
  int a[11];
  getid(a);
  int i, s = 0;
  for (i = 1; i <= 9; i += 2) {
    if (a[i] == val) {
      printid(i);
      break;
      s = 1;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getid@plt>
  mov    $0x1,%eax
  mov    %rsp,%rdx
L4:
  mov    %eax,%edi
  cmp    %ebx,(%rdx,%rax,4)
  je     L14
  add    $0x2,%rax
  cmp    $0xb,%rax
  jne    L4
L21:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L14:
  call   <printid@plt>
  jmp    L21
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int find(int val) {
  int a[11];
  getid(a);
  int i, s = 0;
  for (i = 1; i <= 9; i += 2) {
    if (a[i] == val) {
      printid(i);
      break;
      s = 1;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <getid@plt>
  mov    $0x1,%eax
L13:
  mov    %eax,%edi
  cmp    %ebx,0x0(%rbp,%rax,4)
  je     L14
  add    $0x2,%rax
  cmp    $0xb,%rax
  jne    L13
L25:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  call   <printid@plt>
  jmp    L25
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int find(int val) {
  int a[11];
  getid(a);
  int i, s = 0;
  for (i = 1; i <= 9; i += 2) {
    if (a[i] == val) {
      printid(i);
      break;
      s = 1;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getid@plt>
  cmp    0x4(%rsp),%ebx
  je     L54
  cmp    0xc(%rsp),%ebx
  je     L38
  cmp    0x14(%rsp),%ebx
  je     L7
  cmp    0x1c(%rsp),%ebx
  je     L83
  mov    $0x9,%edi
  cmp    %ebx,0x24(%rsp)
  je     L69
L82:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L54:
  mov    $0x1,%edi
L69:
  call   <printid@plt>
  jmp    L82
  nopl   0x0(%rax)
L38:
  mov    $0x3,%edi
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x5,%edi
  jmp    L69
L83:
  mov    $0x7,%edi
  jmp    L69
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int find(int val) {
  int a[11];
  getid(a);
  int i, s = 0;
  for (i = 1; i <= 9; i += 2) {
    if (a[i] == val) {
      printid(i);
      break;
      s = 1;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L49
L21:
  movl   $0x2,-0x4(%rbp)
  jmp    L27
L51:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L10
  mov    $0x0,%eax
  jmp    L49
L10:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L51
  mov    $0x1,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
short is_prime(unsigned int num) {
  unsigned int i;
  if (num == 1)
    return 0;
  for (i = 2; i < num; i++)
    if (num % i == 0)
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L17
  cmp    $0x2,%edi
  jbe    L2
  test   $0x1,%dil
  je     L37
  mov    $0x2,%ecx
L5:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L30
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  test   %edx,%edx
  jne    L5
  mov    $0x0,%eax
L17:
  ret
L30:
  mov    $0x1,%eax
  ret
L2:
  mov    $0x1,%eax
  ret
L37:
  mov    $0x0,%eax
  ret
```

assistant: ```c
short is_prime(unsigned int num) {
  unsigned int i;
  if (num == 1)
    return 0;
  for (i = 2; i < num; i++)
    if (num % i == 0)
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_prime>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L17
  cmp    $0x2,%edi
  jbe    L44
  test   $0x1,%dil
  je     L17
  mov    $0x2,%ecx
  jmp    L28
  nopl   (%rax)
L35:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  je     L40
L28:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L35
L44:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  xor    %eax,%eax
L17:
  ret
```

assistant: ```c
short is_prime(unsigned int num) {
  unsigned int i;
  if (num == 1)
    return 0;
  for (i = 2; i < num; i++)
    if (num % i == 0)
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_prime>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L59
  cmp    $0x2,%edi
  jbe    L11
  test   $0x1,%dil
  je     L59
  mov    $0x2,%ecx
  jmp    L27
  nopl   (%rax)
L28:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  je     L57
L27:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L28
L11:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  xor    %eax,%eax
L59:
  ret
```

assistant: ```c
short is_prime(unsigned int num) {
  unsigned int i;
  if (num == 1)
    return 0;
  for (i = 2; i < num; i++)
    if (num % i == 0)
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_at_equiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <apply_at_specials@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <apply_at_specials@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int is_at_equiv(int attr1, int attr2) {
  attr1 = apply_at_specials(attr1);
  attr2 = apply_at_specials(attr2);
  return (attr1 == attr2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_at_equiv>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  call   <apply_at_specials@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <apply_at_specials@plt>
  cmp    %eax,%ebx
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_at_equiv(int attr1, int attr2) {
  attr1 = apply_at_specials(attr1);
  attr2 = apply_at_specials(attr2);
  return (attr1 == attr2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_at_equiv>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <apply_at_specials@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <apply_at_specials@plt>
  cmp    %eax,%ebx
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_at_equiv(int attr1, int attr2) {
  attr1 = apply_at_specials(attr1);
  attr2 = apply_at_specials(attr2);
  return (attr1 == attr2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_at_equiv>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <apply_at_specials@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <apply_at_specials@plt>
  cmp    %eax,%ebx
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_at_equiv(int attr1, int attr2) {
  attr1 = apply_at_specials(attr1);
  attr2 = apply_at_specials(attr2);
  return (attr1 == attr2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <gdb_unbuffer_output@plt>
  addl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  gdb_unbuffer_output();
  i++;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gdb_unbuffer_output@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  gdb_unbuffer_output();
  i++;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gdb_unbuffer_output@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  gdb_unbuffer_output();
  i++;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gdb_unbuffer_output@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  gdb_unbuffer_output();
  i++;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_height>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <get_winsize@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int get_height() {
  struct winsize *ws = get_winsize(0);
  return ws->ws_row;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_height>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <get_winsize@plt>
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int get_height() {
  struct winsize *ws = get_winsize(0);
  return ws->ws_row;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_height>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <get_winsize@plt>
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int get_height() {
  struct winsize *ws = get_winsize(0);
  return ws->ws_row;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_height>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <get_winsize@plt>
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int get_height() {
  struct winsize *ws = get_winsize(0);
  return ws->ws_row;
}
```
user: Translate the below assembly code into C programming language:

```asm
<table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L10
L14:
  mov    -0x14(%rbp),%eax
  test   %rax,%rax
  js     L13
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L5
L13:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L5:
  mulsd  -0x30(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x40(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jb     L14
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: %g:  %g


assistant: ```c
void table(double x0, double deltaX, unsigned rows, double (*f)(double x)) {
  unsigned r = 0;
  for (r; r < rows; r++) {
    double x = x0 + r * deltaX;
    double y = (*f)(x);
    printf("%g:  %g\n", x, y);
  }
}
```