ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L25
  lea    0x4(%rdi),%r9
  nop
L30:
  sub    $0x1,%eax
  mov    %rdi,%rdx
  mov    %rax,%r8
  lea    (%r9,%rax,4),%rsi
  nopl   (%rax)
L37:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L36
  movq   %xmm1,(%rdx)
L36:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L37
  mov    %r8d,%eax
  test   %r8d,%r8d
  jne    L30
L25:
  ret
```

assistant: ```c
void bubble_sort(int array[], int size) {
  int temp;
  int i, j;
  for (i = 0; i < size - 1; i++)
    for (j = 0; j < size - i - 1; j++)
      if (array[j] > array[j + 1]) {
        temp = array[j];
        array[j] = array[j + 1];
        array[j + 1] = temp;
      }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<new_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L25
  mov    $0x0,%eax
  call   <fatal_out_of_memory@plt>
L25:
  movl   $0x0,-0x1c(%rbp)
  jmp    L37
L14:
  mov    -0x28(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
  call   <fatal_out_of_memory@plt>
L8:
  addl   $0x1,-0x1c(%rbp)
L37:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L14
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned char **new_matrix(const unsigned int width, const unsigned int height) {
  unsigned int i;
  unsigned char **const matrix = malloc(sizeof(char *) * width);
  if (!matrix) {
    fatal_out_of_memory();
  }
  for (i = 0; i < width; i++) {
    matrix[i] = malloc(sizeof(char) * height);
    if (!matrix[i]) {
      fatal_out_of_memory();
    }
  }
  return matrix;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<new_matrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L12
L46:
  test   %r12d,%r12d
  je     L6
  mov    %r13,%rbx
  mov    %r12d,%r12d
  lea    0x0(%r13,%r12,8),%r12
  jmp    L44
L12:
  mov    $0x0,%eax
  call   <fatal_out_of_memory@plt>
  jmp    L46
L10:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L6
L44:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L10
  call   <fatal_out_of_memory@plt>
  jmp    L10
L6:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char **new_matrix(const unsigned int width, const unsigned int height) {
  unsigned int i;
  unsigned char **const matrix = malloc(sizeof(char *) * width);
  if (!matrix) {
    fatal_out_of_memory();
  }
  for (i = 0; i < width; i++) {
    matrix[i] = malloc(sizeof(char) * height);
    if (!matrix[i]) {
      fatal_out_of_memory();
    }
  }
  return matrix;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<new_matrix>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L68
L52:
  test   %r12d,%r12d
  je     L6
  mov    %r13,%rbx
  lea    0x0(%r13,%r12,8),%r12
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L63:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L6
L33:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L63
  call   <fatal_out_of_memory@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L33
L6:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L68:
  xor    %eax,%eax
  call   <fatal_out_of_memory@plt>
  jmp    L52
```

assistant: ```c
unsigned char **new_matrix(const unsigned int width, const unsigned int height) {
  unsigned int i;
  unsigned char **const matrix = malloc(sizeof(char *) * width);
  if (!matrix) {
    fatal_out_of_memory();
  }
  for (i = 0; i < width; i++) {
    matrix[i] = malloc(sizeof(char) * height);
    if (!matrix[i]) {
      fatal_out_of_memory();
    }
  }
  return matrix;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<new_matrix>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L13
L59:
  test   %r12d,%r12d
  je     L66
  mov    %r13,%rbx
  lea    0x0(%r13,%r12,8),%r12
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L43:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L66
L49:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L43
  call   <fatal_out_of_memory@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L49
L66:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  call   <fatal_out_of_memory@plt>
  jmp    L59
```

assistant: ```c
unsigned char **new_matrix(const unsigned int width, const unsigned int height) {
  unsigned int i;
  unsigned char **const matrix = malloc(sizeof(char *) * width);
  if (!matrix) {
    fatal_out_of_memory();
  }
  for (i = 0; i < width; i++) {
    matrix[i] = malloc(sizeof(char) * height);
    if (!matrix[i]) {
      fatal_out_of_memory();
    }
  }
  return matrix;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D3(%rip),%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x88,0x83,0x40]}

tool: D6: 5 elevado na 4 eh: %0.2f


assistant: ```c
main() {
  printf("5 elevado na 4 eh: %0.2f\n", pow(5.0, 4.0));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D7(%rip),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: byte[8]
name: read_data
arguments: data_label: D0
data_type: string

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x88,0x83,0x40]}

tool: D0: 5 elevado na 4 eh: %0.2f


assistant: ```c
main() {
  printf("5 elevado na 4 eh: %0.2f\n", pow(5.0, 4.0));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D18(%rip),%xmm0
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D19
data_type: string

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x88,0x83,0x40]}

tool: D19: 5 elevado na 4 eh: %0.2f


assistant: ```c
main() {
  printf("5 elevado na 4 eh: %0.2f\n", pow(5.0, 4.0));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D19(%rip),%xmm0
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
type_infered: byte[8]
name: disassemble_data
arguments: label: D16
type_infered: string

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x88,0x83,0x40]}

tool: D16: 5 elevado na 4 eh: %0.2f


assistant: ```c
main() {
  printf("5 elevado na 4 eh: %0.2f\n", pow(5.0, 4.0));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x20(%rbp)
  jmp    L4
L6:
  movsbl -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rcx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   *%rcx
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L4:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jg     L6
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *fill(void *(*emit)(void *, char), void *arg, int *nchar, int numFillers, char filler) {
  while (numFillers-- > 0) {
    arg = emit(arg, filler);
    (*nchar)++;
  }
  return arg;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fill>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rdi
  test   %ecx,%ecx
  jle    L16
  mov    %rdx,%rbp
  lea    -0x1(%rcx),%ebx
  movsbl %r8b,%r13d
L12:
  mov    %r13d,%esi
  call   *%r12
  mov    %rax,%rdi
  addl   $0x1,0x0(%rbp)
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L12
L16:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *fill(void *(*emit)(void *, char), void *arg, int *nchar, int numFillers, char filler) {
  while (numFillers-- > 0) {
    arg = emit(arg, filler);
    (*nchar)++;
  }
  return arg;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fill>:
  endbr64
  test   %ecx,%ecx
  jle    L7
  push   %r13
  mov    %rdx,%r13
  push   %r12
  movsbl %r8b,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  lea    -0x1(%rcx),%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %r12d,%esi
  call   *%rbp
  addl   $0x1,0x0(%r13)
  mov    %rax,%rdi
  sub    $0x1,%ebx
  jae    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L7:
  mov    %rsi,%rax
  ret
```

assistant: ```c
void *fill(void *(*emit)(void *, char), void *arg, int *nchar, int numFillers, char filler) {
  while (numFillers-- > 0) {
    arg = emit(arg, filler);
    (*nchar)++;
  }
  return arg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill>:
  endbr64
  test   %ecx,%ecx
  jle    L19
  push   %r13
  mov    %rdx,%r13
  push   %r12
  movsbl %r8b,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  lea    -0x1(%rcx),%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%esi
  call   *%rbp
  addl   $0x1,0x0(%r13)
  mov    %rax,%rdi
  sub    $0x1,%ebx
  jae    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L19:
  mov    %rsi,%rax
  ret
```

assistant: ```c
void *fill(void *(*emit)(void *, char), void *arg, int *nchar, int numFillers, char filler) {
  while (numFillers-- > 0) {
    arg = emit(arg, filler);
    (*nchar)++;
  }
  return arg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<softfloat_shiftRightM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x28(%rbp),%eax
  sar    $0x5,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L43
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x30(%rbp)
  mov    -0x28(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L59
  mov    -0x24(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    -0x38(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    %eax,%edi
  call   <softfloat_shortShiftRightM@plt>
  cmpl   $0x0,-0x14(%rbp)
  jne    L60
  jmp    L38
L59:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L16
L37:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x30(%rbp)
  addq   $0x4,-0x8(%rbp)
  subl   $0x1,-0x10(%rbp)
L16:
  cmpl   $0x0,-0x10(%rbp)
  jne    L37
L60:
  mov    -0x24(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x38(%rbp)
  jmp    L70
L43:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L70:
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,(%rax)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L70
L38:
  leave
  ret
```

assistant: ```c
void softfloat_shiftRightM(uint_fast8_t size_words, const uint32_t *aPtr, uint32_t dist, uint32_t *zPtr) {
  uint32_t wordDist;
  uint_fast8_t innerDist;
  uint32_t *destPtr;
  uint_fast8_t i;
  wordDist = dist >> 5;
  if (wordDist < size_words) {
    aPtr += (wordDist);
    innerDist = dist & 31;
    if (innerDist) {
      softfloat_shortShiftRightM(size_words - wordDist, aPtr, innerDist, zPtr + 0);
      if (!wordDist)
        return;
    } else {
      aPtr += 0;
      destPtr = zPtr + 0;
      for (i = size_words - wordDist; i; --i) {
        *destPtr = *aPtr;
        aPtr += 1;
        destPtr += 1;
      }
    }
    zPtr += ((size_words) - (wordDist));
  } else {
    wordDist = size_words;
  }
  do {
    *zPtr++ = 0;
    --wordDist;
  } while (wordDist);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<softfloat_shiftRightM>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rcx,%rbx
  mov    %edx,%r12d
  sar    $0x5,%r12d
  cmp    %edi,%r12d
  jge    L44
  movslq %r12d,%rax
  lea    (%rsi,%rax,4),%rsi
  and    $0x1f,%edx
  jne    L33
  mov    %edi,%eax
  sub    %r12d,%eax
  je     L53
  lea    -0x1(%rax),%ecx
  mov    $0x0,%eax
L27:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L27
L53:
  sub    %r12d,%ebp
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,4),%rbx
  mov    %r12d,%ebp
L44:
  lea    -0x1(%rbp),%eax
  lea    0x4(%rbx,%rax,4),%rax
L17:
  add    $0x4,%rbx
  movl   $0x0,-0x4(%rbx)
  cmp    %rax,%rbx
  jne    L17
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  sub    %r12d,%edi
  call   <softfloat_shortShiftRightM@plt>
  test   %r12d,%r12d
  jne    L53
  jmp    L12
```

assistant: ```c
void softfloat_shiftRightM(uint_fast8_t size_words, const uint32_t *aPtr, uint32_t dist, uint32_t *zPtr) {
  uint32_t wordDist;
  uint_fast8_t innerDist;
  uint32_t *destPtr;
  uint_fast8_t i;
  wordDist = dist >> 5;
  if (wordDist < size_words) {
    aPtr += (wordDist);
    innerDist = dist & 31;
    if (innerDist) {
      softfloat_shortShiftRightM(size_words - wordDist, aPtr, innerDist, zPtr + 0);
      if (!wordDist)
        return;
    } else {
      aPtr += 0;
      destPtr = zPtr + 0;
      for (i = size_words - wordDist; i; --i) {
        *destPtr = *aPtr;
        aPtr += 1;
        destPtr += 1;
      }
    }
    zPtr += ((size_words) - (wordDist));
  } else {
    wordDist = size_words;
  }
  do {
    *zPtr++ = 0;
    --wordDist;
  } while (wordDist);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<softfloat_shiftRightM>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  sar    $0x5,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  cmp    %edi,%r12d
  jge    L31
  movslq %r12d,%rax
  sub    %r12d,%edi
  lea    (%rsi,%rax,4),%rsi
  movslq %edi,%rbx
  xor    %eax,%eax
  and    $0x1f,%edx
  jne    L27
  nopl   0x0(%rax,%rax,1)
L23:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L23
L29:
  lea    0x0(%rbp,%rbx,4),%rbp
  mov    %r12d,%edi
L31:
  lea    -0x1(%rdi),%eax
  pop    %rbx
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  lea    0x4(,%rax,4),%rdx
  pop    %r12
  jmp    1060 <memset@plt>
  nopl   0x0(%rax)
L27:
  call   <softfloat_shortShiftRightM@plt>
  test   %r12d,%r12d
  jne    L29
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void softfloat_shiftRightM(uint_fast8_t size_words, const uint32_t *aPtr, uint32_t dist, uint32_t *zPtr) {
  uint32_t wordDist;
  uint_fast8_t innerDist;
  uint32_t *destPtr;
  uint_fast8_t i;
  wordDist = dist >> 5;
  if (wordDist < size_words) {
    aPtr += (wordDist);
    innerDist = dist & 31;
    if (innerDist) {
      softfloat_shortShiftRightM(size_words - wordDist, aPtr, innerDist, zPtr + 0);
      if (!wordDist)
        return;
    } else {
      aPtr += 0;
      destPtr = zPtr + 0;
      for (i = size_words - wordDist; i; --i) {
        *destPtr = *aPtr;
        aPtr += 1;
        destPtr += 1;
      }
    }
    zPtr += ((size_words) - (wordDist));
  } else {
    wordDist = size_words;
  }
  do {
    *zPtr++ = 0;
    --wordDist;
  } while (wordDist);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<softfloat_shiftRightM>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  sar    $0x5,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  cmp    %edi,%r12d
  jge    L115
  movslq %r12d,%rax
  mov    %edi,%ebx
  shl    $0x2,%rax
  sub    %r12d,%ebx
  lea    (%rsi,%rax,1),%r8
  and    $0x1f,%edx
  jne    L47
  lea    0x4(%rsi,%rax,1),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L88
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L88
  mov    %ebx,%edx
  xor    %eax,%eax
  shr    $0x2,%edx
  shl    $0x4,%rdx
L46:
  movdqu (%r8,%rax,1),%xmm0
  movups %xmm0,0x0(%rbp,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L46
  mov    %ebx,%ecx
  mov    %ebx,%esi
  movslq %ebx,%rdx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  sub    %ecx,%esi
  shl    $0x2,%rax
  add    %rax,%r8
  add    %rbp,%rax
  cmp    %ecx,%ebx
  je     L45
  mov    (%r8),%ecx
  mov    %ecx,(%rax)
  cmp    $0x1,%esi
  je     L45
  mov    0x4(%r8),%ecx
  mov    %ecx,0x4(%rax)
  cmp    $0x2,%esi
  je     L45
  mov    0x8(%r8),%ecx
  mov    %ecx,0x8(%rax)
L45:
  lea    0x0(%rbp,%rdx,4),%rbp
  mov    %r12d,%edi
L115:
  lea    -0x1(%rdi),%eax
  pop    %rbx
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  lea    0x4(,%rax,4),%rdx
  pop    %r12
  jmp    1060 <memset@plt>
  xchg   %ax,%ax
L47:
  mov    %r8,%rsi
  mov    %ebx,%edi
  call   <softfloat_shortShiftRightM@plt>
  test   %r12d,%r12d
  je     L92
  movslq %ebx,%rdx
  mov    %r12d,%edi
  lea    0x0(%rbp,%rdx,4),%rbp
  jmp    L115
L88:
  movslq %ebx,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L37:
  mov    (%r8,%rax,4),%ecx
  mov    %ecx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L37
  jmp    L45
L92:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void softfloat_shiftRightM(uint_fast8_t size_words, const uint32_t *aPtr, uint32_t dist, uint32_t *zPtr) {
  uint32_t wordDist;
  uint_fast8_t innerDist;
  uint32_t *destPtr;
  uint_fast8_t i;
  wordDist = dist >> 5;
  if (wordDist < size_words) {
    aPtr += (wordDist);
    innerDist = dist & 31;
    if (innerDist) {
      softfloat_shortShiftRightM(size_words - wordDist, aPtr, innerDist, zPtr + 0);
      if (!wordDist)
        return;
    } else {
      aPtr += 0;
      destPtr = zPtr + 0;
      for (i = size_words - wordDist; i; --i) {
        *destPtr = *aPtr;
        aPtr += 1;
        destPtr += 1;
      }
    }
    zPtr += ((size_words) - (wordDist));
  } else {
    wordDist = size_words;
  }
  do {
    *zPtr++ = 0;
    --wordDist;
  } while (wordDist);
}
```
user: Translate the below assembly code into C programming language:

```asm
<squeeze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L47:
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L20
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L20:
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void squeeze(char s1[], char s2[]) {
  int i, j, k;
  for (i = 0; s2[i] != '\0'; i++) {
    for (j = k = 0; s1[j] != '\0'; j++)
      if (s1[j] != s2[i])
        s1[k++] = s1[j];
    s1[k] = '\0';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<squeeze>:
  endbr64
  mov    $0x0,%r9d
  cmpb   $0x0,(%rsi)
  jne    L59
  ret
L53:
  movslq %ecx,%r8
  mov    %al,(%rdi,%r8,1)
  lea    0x1(%rcx),%ecx
L46:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L33
L45:
  cmp    %al,(%rsi)
  jne    L53
  jmp    L46
L33:
  movslq %ecx,%rcx
  movb   $0x0,(%rdi,%rcx,1)
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  je     L3
L59:
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  mov    %r9d,%ecx
  test   %al,%al
  jne    L45
  jmp    L33
L3:
  ret
```

assistant: ```c
void squeeze(char s1[], char s2[]) {
  int i, j, k;
  for (i = 0; s2[i] != '\0'; i++) {
    for (j = k = 0; s1[j] != '\0'; j++)
      if (s1[j] != s2[i])
        s1[k++] = s1[j];
    s1[k] = '\0';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<squeeze>:
  endbr64
  cmpb   $0x0,(%rsi)
  je     L5
  nopl   0x0(%rax)
L20:
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %ecx,%ecx
  test   %al,%al
  je     L40
  nopl   (%rax)
L48:
  cmp    %al,(%rsi)
  je     L27
  movslq %ecx,%r8
  add    $0x1,%ecx
  mov    %al,(%rdi,%r8,1)
L27:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L48
  movslq %ecx,%rcx
  add    %rdi,%rcx
L59:
  add    $0x1,%rsi
  movb   $0x0,(%rcx)
  cmpb   $0x0,(%rsi)
  jne    L20
  ret
  nopl   0x0(%rax)
L40:
  mov    %rdi,%rcx
  jmp    L59
L5:
  ret
```

assistant: ```c
void squeeze(char s1[], char s2[]) {
  int i, j, k;
  for (i = 0; s2[i] != '\0'; i++) {
    for (j = k = 0; s1[j] != '\0'; j++)
      if (s1[j] != s2[i])
        s1[k++] = s1[j];
    s1[k] = '\0';
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<squeeze>:
  endbr64
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L24
  nopl   (%rax)
L9:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L63
  lea    0x1(%rdi),%rcx
  xor    %edx,%edx
  jmp    L49
  nop
L67:
  add    $0x1,%rcx
  mov    %al,(%rdi,%rdx,1)
  lea    0x1(%rdx),%r8d
  movzbl -0x1(%rcx),%eax
  test   %al,%al
  je     L29
  movslq %r8d,%rdx
L48:
  movzbl (%rsi),%r8d
L49:
  cmp    %al,%r8b
  jne    L67
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  jne    L48
  mov    %edx,%r8d
L29:
  movslq %r8d,%r8
  add    %rdi,%r8
L16:
  add    $0x1,%rsi
  movb   $0x0,(%r8)
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L9
  ret
  nopl   (%rax)
L63:
  mov    %rdi,%r8
  jmp    L16
L24:
  ret
```

assistant: ```c
void squeeze(char s1[], char s2[]) {
  int i, j, k;
  for (i = 0; s2[i] != '\0'; i++) {
    for (j = k = 0; s1[j] != '\0'; j++)
      if (s1[j] != s2[i])
        s1[k++] = s1[j];
    s1[k] = '\0';
  }
}
```