ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unicode_find_name>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmpb   $0x0,0x0(%rbp)
  je     L75
  mov    %rax,%r12
  mov    $0x0,%r14d
  jmp    L21
L2:
  sub    %rbp,%rax
  mov    %rax,%rbx
  cmp    %rax,%r12
  je     L30
  lea    0x1(%rbp,%rax,1),%rbp
L21:
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L2
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  cmp    %rax,%r12
  jne    L60
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L59
L81:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L75:
  mov    $0xffffffff,%r14d
  jmp    L81
L60:
  lea    0x1(%rbp,%rax,1),%rbp
L73:
  add    $0x1,%r14d
  cmpb   $0x0,0x0(%rbp)
  jne    L21
  mov    $0xffffffff,%r14d
  jmp    L81
L30:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L81
  lea    0x1(%rbp,%rbx,1),%rbp
  jmp    L21
L59:
  lea    0x1(%rbp,%rbx,1),%rbp
  jmp    L73
```

assistant: ```c
int unicode_find_name(const char *name_table, const char *name) {
  const char *p, *r;
  int pos;
  size_t name_len, len;
  p = name_table;
  pos = 0;
  name_len = strlen(name);
  while (*p) {
    for (;;) {
      r = strchr(p, ',');
      if (!r)
        len = strlen(p);
      else
        len = r - p;
      if (len == name_len && !memcmp(p, name, name_len))
        return pos;
      p += len + 1;
      if (!r)
        break;
    }
    pos++;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unicode_find_name>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmpb   $0x0,(%r14)
  je     L33
  mov    %rax,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rax),%r13
  nopw   0x0(%rax,%rax,1)
L59:
  mov    $0x2c,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L72
  sub    %r14,%rax
  cmp    %rax,%rbx
  je     L52
  lea    0x1(%r14,%rax,1),%r14
  jmp    L59
  nopl   0x0(%rax)
L72:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jne    L75
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L71
L96:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  lea    0x1(%r14,%rax,1),%r14
L26:
  add    $0x1,%r12d
  cmpb   $0x0,(%r14)
  jne    L59
L33:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L71:
  add    %r13,%r14
  jmp    L26
L52:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L96
  add    %r13,%r14
  jmp    L59
```

assistant: ```c
int unicode_find_name(const char *name_table, const char *name) {
  const char *p, *r;
  int pos;
  size_t name_len, len;
  p = name_table;
  pos = 0;
  name_len = strlen(name);
  while (*p) {
    for (;;) {
      r = strchr(p, ',');
      if (!r)
        len = strlen(p);
      else
        len = r - p;
      if (len == name_len && !memcmp(p, name, name_len))
        return pos;
      p += len + 1;
      if (!r)
        break;
    }
    pos++;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<unicode_find_name>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmpb   $0x0,(%r14)
  je     L33
  mov    %rax,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rax),%r13
  nopw   0x0(%rax,%rax,1)
L40:
  mov    $0x2c,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L67
  sub    %r14,%rax
  cmp    %rax,%rbx
  je     L15
  lea    0x1(%r14,%rax,1),%r14
  jmp    L40
  nopl   0x0(%rax)
L67:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jne    L94
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L85
L63:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L94:
  lea    0x1(%r14,%rax,1),%r14
L22:
  add    $0x1,%r12d
  cmpb   $0x0,(%r14)
  jne    L40
L33:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L85:
  add    %r13,%r14
  jmp    L22
L15:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L63
  add    %r13,%r14
  jmp    L40
```

assistant: ```c
int unicode_find_name(const char *name_table, const char *name) {
  const char *p, *r;
  int pos;
  size_t name_len, len;
  p = name_table;
  pos = 0;
  name_len = strlen(name);
  while (*p) {
    for (;;) {
      r = strchr(p, ',');
      if (!r)
        len = strlen(p);
      else
        len = r - p;
      if (len == name_len && !memcmp(p, name, name_len))
        return pos;
      p += len + 1;
      if (!r)
        break;
    }
    pos++;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wsimple_strtoull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L37
  movl   $0xa,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x30,%rax
  jne    L113
  movl   $0x8,-0x24(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <towupper@plt>
  cmp    $0x58,%eax
  jne    L113
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <iswxdigit@plt>
  test   %rax,%rax
  je     L113
  addq   $0x8,-0x18(%rbp)
  movl   $0x10,-0x24(%rbp)
  jmp    L113
L37:
  cmpl   $0x10,-0x24(%rbp)
  jne    L113
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x30,%rax
  jne    L113
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <towupper@plt>
  cmp    $0x58,%eax
  jne    L113
  addq   $0x10,-0x18(%rbp)
  jmp    L113
L41:
  mov    -0x24(%rbp),%eax
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x8,-0x18(%rbp)
L113:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <iswxdigit@plt>
  test   %rax,%rax
  je     L49
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <iswdigit@plt>
  test   %rax,%rax
  je     L138
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x30,%rax
  jmp    L99
L138:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <towupper@plt>
  sub    $0x37,%eax
  cltq
L99:
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    %rax,-0x8(%rbp)
  jae    L49
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  test   %rax,%rax
  jne    L41
L49:
  cmpq   $0x0,-0x20(%rbp)
  je     L57
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L57:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long wsimple_strtoull(const wchar_t *cp, wchar_t **endp, unsigned int base, size_t field_width) {
  unsigned long long result = 0, value;
  if (!base) {
    base = 10;
    if (*cp == L'0') {
      base = 8;
      cp++;
      if ((towupper(*cp) == L'X') && iswxdigit(cp[1])) {
        cp++;
        base = 16;
      }
    }
  } else if (base == 16) {
    if (cp[0] == L'0' && towupper(cp[1]) == L'X')
      cp += 2;
  }
  while (iswxdigit(*cp) && (value = iswdigit(*cp) ? *cp - L'0' : towupper(*cp) - L'A' + 10) < base && field_width-- > 0) {
    result = result * base + value;
    cp++;
  }
  if (endp)
    *endp = (wchar_t *)cp;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wsimple_strtoull>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rcx,%r12
  test   %edx,%edx
  jne    L23
  mov    $0xa,%r13d
  cmpq   $0x30,(%rdi)
  je     L106
L88:
  mov    $0x0,%ebp
  mov    %r13d,%r13d
  jmp    L168
L106:
  lea    0x8(%rdi),%rbp
  mov    0x8(%rdi),%rdi
  call   <towupper@plt>
  cmp    $0x58,%eax
  je     L56
  mov    %rbp,%rbx
  mov    $0x8,%r13d
  jmp    L88
L56:
  mov    0x10(%rbx),%rdi
  call   <iswxdigit@plt>
  test   %rax,%rax
  je     L3
  add    $0x10,%rbx
  mov    $0x10,%r13d
  jmp    L88
L23:
  mov    %edx,%r13d
  cmp    $0x10,%edx
  jne    L88
  cmpq   $0x30,(%rdi)
  jne    L88
  mov    0x8(%rdi),%rdi
  call   <towupper@plt>
  mov    %eax,%edx
  lea    0x10(%rbx),%rax
  cmp    $0x58,%edx
  cmove  %rax,%rbx
  jmp    L88
L3:
  mov    %rbp,%rbx
  mov    $0x8,%r13d
  jmp    L88
L91:
  mov    (%rbx),%rax
  sub    $0x30,%rax
L1:
  cmp    %rax,%r13
  jbe    L123
  test   %r12,%r12
  je     L123
  imul   %r13,%rbp
  add    %rax,%rbp
  add    $0x8,%rbx
  sub    $0x1,%r12
L168:
  mov    (%rbx),%rdi
  call   <iswxdigit@plt>
  test   %rax,%rax
  je     L123
  mov    (%rbx),%rdi
  call   <iswdigit@plt>
  test   %rax,%rax
  jne    L91
  mov    (%rbx),%rdi
  call   <towupper@plt>
  sub    $0x37,%eax
  cltq
  jmp    L1
L123:
  test   %r14,%r14
  je     L162
  mov    %rbx,(%r14)
L162:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long long wsimple_strtoull(const wchar_t *cp, wchar_t **endp, unsigned int base, size_t field_width) {
  unsigned long long result = 0, value;
  if (!base) {
    base = 10;
    if (*cp == L'0') {
      base = 8;
      cp++;
      if ((towupper(*cp) == L'X') && iswxdigit(cp[1])) {
        cp++;
        base = 16;
      }
    }
  } else if (base == 16) {
    if (cp[0] == L'0' && towupper(cp[1]) == L'X')
      cp += 2;
  }
  while (iswxdigit(*cp) && (value = iswdigit(*cp) ? *cp - L'0' : towupper(*cp) - L'A' + 10) < base && field_width-- > 0) {
    result = result * base + value;
    cp++;
  }
  if (endp)
    *endp = (wchar_t *)cp;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wsimple_strtoull>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  test   %edx,%edx
  jne    L69
  mov    $0xa,%edx
  cmp    $0x30,%rdi
  je     L122
L172:
  xor    %r12d,%r12d
  mov    %edx,%ebp
  jmp    L110
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%r14),%rax
  sub    $0x30,%rax
  cmp    %rax,%rbp
  jbe    L87
L107:
  test   %rbx,%rbx
  je     L87
  imul   %rbp,%r12
  mov    0x8(%r14),%rdi
  add    $0x8,%r14
  sub    $0x1,%rbx
  add    %rax,%r12
L110:
  call   <iswxdigit@plt>
  test   %rax,%rax
  je     L87
  mov    (%r14),%rdi
  call   <iswdigit@plt>
  test   %rax,%rax
  jne    L21
  mov    (%r14),%rdi
  call   <towupper@plt>
  sub    $0x37,%eax
  cltq
  cmp    %rax,%rbp
  ja     L107
  nopl   (%rax)
L87:
  test   %r13,%r13
  je     L121
  mov    %r14,0x0(%r13)
L121:
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L69:
  cmp    $0x10,%edx
  jne    L172
  cmp    $0x30,%rdi
  jne    L172
  mov    0x8(%r14),%rdi
  mov    %edx,0xc(%rsp)
  call   <towupper@plt>
  mov    0xc(%rsp),%edx
  cmp    $0x58,%eax
  je     L27
  mov    (%r14),%rdi
  jmp    L172
  nopl   0x0(%rax)
L122:
  mov    0x8(%r14),%rdi
  lea    0x8(%r14),%rbp
  call   <towupper@plt>
  cmp    $0x58,%eax
  je     L148
L109:
  mov    0x8(%r14),%rdi
  mov    $0x8,%edx
  mov    %rbp,%r14
  jmp    L172
L148:
  mov    0x10(%r14),%rdi
  call   <iswxdigit@plt>
  test   %rax,%rax
  je     L109
  mov    0x10(%r14),%rdi
  mov    $0x10,%edx
  add    $0x10,%r14
  jmp    L172
L27:
  mov    0x10(%r14),%rdi
  add    $0x10,%r14
  jmp    L172
```

assistant: ```c
unsigned long long wsimple_strtoull(const wchar_t *cp, wchar_t **endp, unsigned int base, size_t field_width) {
  unsigned long long result = 0, value;
  if (!base) {
    base = 10;
    if (*cp == L'0') {
      base = 8;
      cp++;
      if ((towupper(*cp) == L'X') && iswxdigit(cp[1])) {
        cp++;
        base = 16;
      }
    }
  } else if (base == 16) {
    if (cp[0] == L'0' && towupper(cp[1]) == L'X')
      cp += 2;
  }
  while (iswxdigit(*cp) && (value = iswdigit(*cp) ? *cp - L'0' : towupper(*cp) - L'A' + 10) < base && field_width-- > 0) {
    result = result * base + value;
    cp++;
  }
  if (endp)
    *endp = (wchar_t *)cp;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wsimple_strtoull>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%rax
  test   %edx,%edx
  jne    L146
  mov    $0xa,%edx
  cmp    $0x30,%rax
  je     L47
L68:
  xor    %r12d,%r12d
  mov    %edx,%ebp
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L120:
  mov    (%r14),%rax
  sub    $0x30,%rax
  cmp    %rax,%rbp
  jbe    L76
L52:
  test   %rbx,%rbx
  je     L76
  imul   %rbp,%r12
  add    $0x8,%r14
  sub    $0x1,%rbx
  add    %rax,%r12
L35:
  mov    (%r14),%rdi
  call   <iswxdigit@plt>
  test   %rax,%rax
  je     L76
  mov    (%r14),%rdi
  call   <iswdigit@plt>
  test   %rax,%rax
  jne    L120
  mov    (%r14),%rdi
  call   <towupper@plt>
  sub    $0x37,%eax
  cltq
  cmp    %rax,%rbp
  ja     L52
  nopl   0x0(%rax)
L76:
  test   %r13,%r13
  je     L30
  mov    %r14,0x0(%r13)
L30:
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L146:
  cmp    $0x10,%edx
  jne    L68
  cmp    $0x30,%rax
  jne    L68
  mov    0x8(%rdi),%rdi
  mov    %edx,0xc(%rsp)
  call   <towupper@plt>
  mov    0xc(%rsp),%edx
  mov    %eax,%r8d
  lea    0x10(%r14),%rax
  cmp    $0x58,%r8d
  cmove  %rax,%r14
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L47:
  lea    0x8(%rdi),%rbp
  mov    0x8(%rdi),%rdi
  call   <towupper@plt>
  cmp    $0x58,%eax
  je     L131
L20:
  mov    %rbp,%r14
  mov    $0x8,%edx
  jmp    L68
L131:
  mov    0x10(%r14),%rdi
  call   <iswxdigit@plt>
  test   %rax,%rax
  je     L20
  add    $0x10,%r14
  mov    $0x10,%edx
  jmp    L68
```

assistant: ```c
unsigned long long wsimple_strtoull(const wchar_t *cp, wchar_t **endp, unsigned int base, size_t field_width) {
  unsigned long long result = 0, value;
  if (!base) {
    base = 10;
    if (*cp == L'0') {
      base = 8;
      cp++;
      if ((towupper(*cp) == L'X') && iswxdigit(cp[1])) {
        cp++;
        base = 16;
      }
    }
  } else if (base == 16) {
    if (cp[0] == L'0' && towupper(cp[1]) == L'X')
      cp += 2;
  }
  while (iswxdigit(*cp) && (value = iswdigit(*cp) ? *cp - L'0' : towupper(*cp) - L'A' + 10) < base && field_width-- > 0) {
    result = result * base + value;
    cp++;
  }
  if (endp)
    *endp = (wchar_t *)cp;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <localBufferOverflow@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: Value[0] = %c


assistant: ```c
int main(int argc, char *const argv[]) {
  printf("Value[0] = %c\n", localBufferOverflow());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <localBufferOverflow@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: Value[0] = %c


assistant: ```c
int main(int argc, char *const argv[]) {
  printf("Value[0] = %c\n", localBufferOverflow());
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <localBufferOverflow@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: D7: Value[0] = %c


assistant: ```c
int main(int argc, char *const argv[]) {
  printf("Value[0] = %c\n", localBufferOverflow());
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <localBufferOverflow@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: Value[0] = %c


assistant: ```c
int main(int argc, char *const argv[]) {
  printf("Value[0] = %c\n", localBufferOverflow());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x6,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, j, k;
  j = 6;
  k = j + 4;
  k = i + 8;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int i, j, k;
  j = 6;
  k = j + 4;
  k = i + 8;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i, j, k;
  j = 6;
  k = j + 4;
  k = i + 8;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i, j, k;
  j = 6;
  k = j + 4;
  k = i + 8;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_97_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x1c(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x18(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x1c(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %eax,%edx
  mov    -0x1c(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_97_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = D & S;
  stk3 = T | stk4;
  stk2 = S ^ stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xrop3_97_1_1>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  movzbl %sil,%edx
  mov    %edx,%esi
  shl    $0x8,%esi
  or     %edx,%esi
  or     %esi,%edi
  xor    %eax,%edi
  or     %esi,%eax
  mov    %edi,%edx
  not    %edx
  and    %edx,%eax
  xor    $0xffffff00,%edi
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_97_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = D & S;
  stk3 = T | stk4;
  stk2 = S ^ stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_97_1_1>:
  endbr64
  movzbl %sil,%eax
  movzbl %dil,%edi
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  shl    $0x8,%edx
  or     %eax,%esi
  or     %edi,%edx
  or     %esi,%edi
  xor    %edx,%edi
  or     %esi,%edx
  mov    %edi,%eax
  xor    $0xffffff00,%edi
  not    %eax
  and    %edx,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_97_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = D & S;
  stk3 = T | stk4;
  stk2 = S ^ stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xrop3_97_1_1>:
  endbr64
  movzbl %sil,%eax
  movzbl %dil,%edi
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  shl    $0x8,%edx
  or     %eax,%esi
  or     %edi,%edx
  or     %esi,%edi
  xor    %edx,%edi
  or     %esi,%edx
  mov    %edi,%eax
  xor    $0xffffff00,%edi
  not    %eax
  and    %edx,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_97_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = D & S;
  stk3 = T | stk4;
  stk2 = S ^ stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  mov    %eax,%edx
  sub    %esi,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D14
type: string

tool: D0: 
Beginning Random Number generation from the set 1, 4, 7, 10, 13, 16....


tool: D14: Random Number is: %d



assistant: ```c
int main() {
  int rand1;
  printf("\nBeginning Random Number generation from the set 1, 4, 7, 10, 13, 16....\n\n");
  srand(time(NULL));
  rand1 = rand();
  rand1 = ((rand1 % 6) * 3) + 1;
  printf("Random Number is: %d\n\n", rand1);
  return 0;
}
```