ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L5:
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L26:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L16:
  cmpl   $0x4,-0xc(%rbp)
  jle    L26
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L0
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <srand@plt>
  jmp    L5
L0:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D44
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D36
datatype: string
name: parse_data
arguments: data_tag: D5
datatype: string

tool: D8: This program displays the first five values of rand.

tool: D44: %d 

tool: D10: 


tool: D36: Enter new seed value (0 to terminate): 

tool: D5: %d

assistant: ```c
int main(void) {
  int i, seed;
  printf("This program displays the first five values of "
         "rand.\n");
  for (;;) {
    for (i = 0; i < 5; i++)
      printf("%d ", rand());
    printf("\n\n");
    printf("Enter new seed value (0 to terminate): ");
    scanf("%d", &seed);
    if (seed == 0)
      break;
    srand(seed);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D0(%rip),%rbp
  lea    D46(%rip),%r14
  lea    D4(%rip),%r13
  lea    D33(%rip),%r12
  jmp    L44
L48:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L43
  call   <srand@plt>
L44:
  mov    $0x5,%ebx
L20:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L20
  jmp    L48
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D46
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D33
type_infered: string

tool: D12: This program displays the first five values of rand.

tool: D0: %d 

tool: D46: 


tool: D4: Enter new seed value (0 to terminate): 

tool: D33: %d

assistant: ```c
int main(void) {
  int i, seed;
  printf("This program displays the first five values of "
         "rand.\n");
  for (;;) {
    for (i = 0; i < 5; i++)
      printf("%d ", rand());
    printf("\n\n");
    printf("Enter new seed value (0 to terminate): ");
    scanf("%d", &seed);
    if (seed == 0)
      break;
    srand(seed);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D26(%rip),%rdi
  lea    D47(%rip),%r15
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  lea    D49(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <puts@plt>
  nop
L6:
  mov    $0x5,%ebx
L4:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L4
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L17
  call   <srand@plt>
  jmp    L6
  nopl   0x0(%rax)
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D26
datatype: string
name: disassemble_data
arguments: tag: D47
datatype: string
name: disassemble_data
arguments: tag: D21
datatype: string
name: disassemble_data
arguments: tag: D34
datatype: string
name: disassemble_data
arguments: tag: D49
datatype: string

tool: D26: This program displays the first five values of rand.

tool: D47: 


tool: D21: Enter new seed value (0 to terminate): 

tool: D34: %d

tool: D49: %d 

assistant: ```c
int main(void) {
  int i, seed;
  printf("This program displays the first five values of "
         "rand.\n");
  for (;;) {
    for (i = 0; i < 5; i++)
      printf("%d ", rand());
    printf("\n\n");
    printf("Enter new seed value (0 to terminate): ");
    scanf("%d", &seed);
    if (seed == 0)
      break;
    srand(seed);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D23(%rip),%rdi
  lea    D33(%rip),%r15
  push   %r14
  lea    D45(%rip),%r14
  push   %r13
  push   %r12
  lea    D39(%rip),%r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <puts@plt>
  nop
L33:
  mov    $0x5,%ebx
L38:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L38
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L18
  call   <srand@plt>
  jmp    L33
  nopl   0x0(%rax)
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
datatype: string
name: disassemble_data
arguments: label: D33
datatype: string
name: disassemble_data
arguments: label: D45
datatype: string
name: disassemble_data
arguments: label: D39
datatype: string
name: disassemble_data
arguments: label: D13
datatype: string

tool: D23: This program displays the first five values of rand.

tool: D33: 


tool: D45: Enter new seed value (0 to terminate): 

tool: D39: %d

tool: D13: %d 

assistant: ```c
int main(void) {
  int i, seed;
  printf("This program displays the first five values of "
         "rand.\n");
  for (;;) {
    for (i = 0; i < 5; i++)
      printf("%d ", rand());
    printf("\n\n");
    printf("Enter new seed value (0 to terminate): ");
    scanf("%d", &seed);
    if (seed == 0)
      break;
    srand(seed);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<softfloat_commonNaNToF128M>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  movl   $0x7fff8000,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void softfloat_commonNaNToF128M(const struct commonNaN *aPtr, uint32_t *zWPtr) {
  zWPtr[(3)] = 0x7FFF8000;
  zWPtr[(2)] = 0;
  zWPtr[(1)] = 0;
  zWPtr[(0)] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<softfloat_commonNaNToF128M>:
  endbr64
  movl   $0x7fff8000,0xc(%rsi)
  movl   $0x0,0x8(%rsi)
  movl   $0x0,0x4(%rsi)
  movl   $0x0,(%rsi)
  ret
```

assistant: ```c
void softfloat_commonNaNToF128M(const struct commonNaN *aPtr, uint32_t *zWPtr) {
  zWPtr[(3)] = 0x7FFF8000;
  zWPtr[(2)] = 0;
  zWPtr[(1)] = 0;
  zWPtr[(0)] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<softfloat_commonNaNToF128M>:
  endbr64
  movabs $0x7fff800000000000,%rax
  movq   $0x0,(%rsi)
  mov    %rax,0x8(%rsi)
  ret
```

assistant: ```c
void softfloat_commonNaNToF128M(const struct commonNaN *aPtr, uint32_t *zWPtr) {
  zWPtr[(3)] = 0x7FFF8000;
  zWPtr[(2)] = 0;
  zWPtr[(1)] = 0;
  zWPtr[(0)] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<softfloat_commonNaNToF128M>:
  endbr64
  movdqa D1(%rip),%xmm0
  movups %xmm0,(%rsi)
  ret
```

tool_calls: name: read_data
arguments: label: D1
data_type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0xff,0x7f]}

assistant: ```c
void softfloat_commonNaNToF128M(const struct commonNaN *aPtr, uint32_t *zWPtr) {
  zWPtr[(3)] = 0x7FFF8000;
  zWPtr[(2)] = 0;
  zWPtr[(1)] = 0;
  zWPtr[(0)] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x7,-0x8(%rbp)
  jmp    L19
L8:
  addl   $0x1,-0xc(%rbp)
  movl   $0x7,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
L19:
  cmpl   $0x9,-0xc(%rbp)
  jle    L8
  cmpl   $0xa,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x7,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i, j, k;
  i = k = 0;
  j = 7;
  while (i < 10) {
    i++;
    j = 7;
    k = 5;
  }
  assert(i == 10);
  assert(k);
  assert(j == 7);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x5,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i, j, k;
  i = k = 0;
  j = 7;
  while (i < 10) {
    i++;
    j = 7;
    k = 5;
  }
  assert(i == 10);
  assert(k);
  assert(j == 7);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x5,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i, j, k;
  i = k = 0;
  j = 7;
  while (i < 10) {
    i++;
    j = 7;
    k = 5;
  }
  assert(i == 10);
  assert(k);
  assert(j == 7);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x5,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i, j, k;
  i = k = 0;
  j = 7;
  while (i < 10) {
    i++;
    j = 7;
    k = 5;
  }
  assert(i == 10);
  assert(k);
  assert(j == 7);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D32(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L10:
  movss  -0x14(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x10(%rbp),%xmm1
  mov    -0x18(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  test   %eax,%eax
  jns    L10
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L15
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x10(%rbp),%xmm1
  mov    -0x1c(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movss  -0x14(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D40
datatype: string
name: extract_symbolic_data
arguments: data_label: D32
datatype: f64

tool: D15: %d

tool: D40: %f

tool: D32: 0.02

assistant: ```c
int main() {
  int n, k, sum;
  float m, a;
  scanf("%d", &n);
  scanf("%f", &m);
  scanf("%d", &k);
  sum = k * m;
  a = 0.02 * m;
  n = n - k;
  do {
    m = m - a;
    sum = sum + k * m;
    n = n - k;
  } while (n - k >= 0);
  if (n != 0) {
    sum = sum + n * (m - a);
  }
  printf("%d", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  pxor   %xmm4,%xmm4
  cvtsi2ss %edx,%xmm4
  movss  0x14(%rsp),%xmm1
  movaps %xmm4,%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%esi
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm1,%xmm3
  mulsd  D9(%rip),%xmm3
  cvtsd2ss %xmm3,%xmm3
  mov    0xc(%rsp),%eax
  sub    %edx,%eax
  sub    %edx,%eax
L12:
  subss  %xmm3,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  movaps %xmm4,%xmm2
  mulss  %xmm1,%xmm2
  addss  %xmm2,%xmm0
  cvttss2si %xmm0,%esi
  mov    %eax,%ecx
  sub    %edx,%eax
  jns    L12
  movss  %xmm1,0x14(%rsp)
  mov    %ecx,0xc(%rsp)
  test   %ecx,%ecx
  je     L1
  pxor   %xmm0,%xmm0
  cvtsi2ss %ecx,%xmm0
  subss  %xmm3,%xmm1
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%esi
L1:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: tag: D26
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: f64

tool: D17: %d

tool: D26: %f

tool: D9: 0.02

assistant: ```c
int main() {
  int n, k, sum;
  float m, a;
  scanf("%d", &n);
  scanf("%f", &m);
  scanf("%d", &k);
  sum = k * m;
  a = 0.02 * m;
  n = n - k;
  do {
    m = m - a;
    sum = sum + k * m;
    n = n - k;
  } while (n - k >= 0);
  if (n != 0) {
    sum = sum + n * (m - a);
  }
  printf("%d", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  pxor   %xmm4,%xmm4
  movss  0x14(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  mov    0xc(%rsp),%eax
  cvtsi2ss %edx,%xmm4
  cvtss2sd %xmm1,%xmm3
  mulsd  D13(%rip),%xmm3
  sub    %edx,%eax
  sub    %edx,%eax
  movaps %xmm4,%xmm0
  mulss  %xmm1,%xmm0
  cvtsd2ss %xmm3,%xmm3
  cvttss2si %xmm0,%esi
  nopl   0x0(%rax,%rax,1)
L27:
  subss  %xmm3,%xmm1
  movaps %xmm4,%xmm2
  pxor   %xmm0,%xmm0
  mov    %eax,%ecx
  cvtsi2ss %esi,%xmm0
  mulss  %xmm1,%xmm2
  addss  %xmm2,%xmm0
  cvttss2si %xmm0,%esi
  sub    %edx,%eax
  jns    L27
  mov    %ecx,0xc(%rsp)
  movss  %xmm1,0x14(%rsp)
  test   %ecx,%ecx
  je     L19
  pxor   %xmm0,%xmm0
  subss  %xmm3,%xmm1
  cvtsi2ss %ecx,%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%esi
L19:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: f64

tool: D14: %d

tool: D6: %f

tool: D13: 0.02

assistant: ```c
int main() {
  int n, k, sum;
  float m, a;
  scanf("%d", &n);
  scanf("%f", &m);
  scanf("%d", &k);
  sum = k * m;
  a = 0.02 * m;
  n = n - k;
  do {
    m = m - a;
    sum = sum + k * m;
    n = n - k;
  } while (n - k >= 0);
  if (n != 0) {
    sum = sum + n * (m - a);
  }
  printf("%d", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  pxor   %xmm4,%xmm4
  movss  0x14(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  mov    0xc(%rsp),%eax
  cvtsi2ss %edx,%xmm4
  cvtss2sd %xmm1,%xmm3
  mulsd  D4(%rip),%xmm3
  sub    %edx,%eax
  sub    %edx,%eax
  movaps %xmm4,%xmm0
  mulss  %xmm1,%xmm0
  cvtsd2ss %xmm3,%xmm3
  cvttss2si %xmm0,%esi
  nopl   0x0(%rax,%rax,1)
L15:
  subss  %xmm3,%xmm1
  movaps %xmm4,%xmm2
  pxor   %xmm0,%xmm0
  mov    %eax,%ecx
  cvtsi2ss %esi,%xmm0
  mulss  %xmm1,%xmm2
  addss  %xmm2,%xmm0
  cvttss2si %xmm0,%esi
  sub    %edx,%eax
  jns    L15
  mov    %ecx,0xc(%rsp)
  movss  %xmm1,0x14(%rsp)
  test   %ecx,%ecx
  je     L19
  pxor   %xmm0,%xmm0
  subss  %xmm3,%xmm1
  cvtsi2ss %ecx,%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%esi
L19:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D4
type_guessed: f64

tool: D23: %d

tool: D1: %f

tool: D4: 0.02

assistant: ```c
int main() {
  int n, k, sum;
  float m, a;
  scanf("%d", &n);
  scanf("%f", &m);
  scanf("%d", &k);
  sum = k * m;
  a = 0.02 * m;
  n = n - k;
  do {
    m = m - a;
    sum = sum + k * m;
    n = n - k;
  } while (n - k >= 0);
  if (n != 0) {
    sum = sum + n * (m - a);
  }
  printf("%d", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L75
L32:
  addq   $0x1,-0x10(%rbp)
L75:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L32
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L32
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  je     L32
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L53
L6:
  subq   $0x1,-0x8(%rbp)
L53:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  je     L6
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim(char *str) {
  int len = strlen(str);
  char *c = str;
  while (*c == ' ' || *c == '\t' || *c == ';')
    c++;
  char *d = &str[len - 1];
  while (*d == ' ' || *d == '\t' || *d == ';')
    d--;
  *(d + 1) = 0;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movzbl (%rbx),%ecx
  mov    %rbx,%rdx
  cmp    $0x3b,%cl
  ja     L10
  movabs $0x800000100000200,%rdx
  bt     %rcx,%rdx
  jae    L50
  mov    %rbx,%rdx
  movabs $0x800000100000200,%rsi
  jmp    L105
L62:
  bt     %rcx,%rsi
  jae    L10
L105:
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    $0x3b,%cl
  jbe    L62
L10:
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  movzbl (%rax),%ecx
  cmp    $0x3b,%cl
  ja     L26
  movabs $0x800000100000200,%rsi
  bt     %rcx,%rsi
  jb     L86
  jmp    L26
L50:
  mov    %rbx,%rdx
  jmp    L10
L60:
  bt     %rcx,%rsi
  jae    L26
L86:
  sub    $0x1,%rax
  movzbl (%rax),%ecx
  cmp    $0x3b,%cl
  jbe    L60
L26:
  movb   $0x0,0x1(%rax)
  mov    %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *trim(char *str) {
  int len = strlen(str);
  char *c = str;
  while (*c == ' ' || *c == '\t' || *c == ';')
    c++;
  char *d = &str[len - 1];
  while (*d == ' ' || *d == '\t' || *d == ';')
    d--;
  *(d + 1) = 0;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movzbl (%rbx),%edx
  mov    %rbx,%r8
  cmp    $0x3b,%dl
  ja     L0
  movabs $0xf7fffffefffffdff,%rcx
  nopw   0x0(%rax,%rax,1)
L6:
  bt     %rdx,%rcx
  jb     L0
  movzbl 0x1(%r8),%edx
  add    $0x1,%r8
  cmp    $0x3b,%dl
  jbe    L6
L0:
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  movzbl (%rax),%edx
  cmp    $0x3b,%dl
  ja     L58
  movabs $0xf7fffffefffffdff,%rcx
  nopl   (%rax)
L31:
  bt     %rdx,%rcx
  jb     L58
  movzbl -0x1(%rax),%edx
  sub    $0x1,%rax
  cmp    $0x3b,%dl
  jbe    L31
L58:
  movb   $0x0,0x1(%rax)
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *trim(char *str) {
  int len = strlen(str);
  char *c = str;
  while (*c == ' ' || *c == '\t' || *c == ';')
    c++;
  char *d = &str[len - 1];
  while (*d == ' ' || *d == '\t' || *d == ';')
    d--;
  *(d + 1) = 0;
  return c;
}
```