ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<Gluon>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  movsd  (%rdi),%xmm4
  movsd  0x10(%rdi),%xmm7
  movsd  0x8(%rdi),%xmm5
  movsd  0x18(%rdi),%xmm6
  subsd  %xmm4,%xmm7
  subsd  %xmm5,%xmm6
  movapd %xmm7,%xmm8
  mulsd  %xmm7,%xmm8
  movapd %xmm6,%xmm0
  mulsd  %xmm6,%xmm0
  addsd  %xmm0,%xmm8
  pxor   %xmm0,%xmm0
  ucomisd %xmm8,%xmm0
  ja     L0
  sqrtsd %xmm8,%xmm8
L6:
  movsd  D5(%rip),%xmm0
  pxor   %xmm2,%xmm2
  movsd  %xmm7,(%rsp)
  movapd %xmm2,%xmm1
  movsd  %xmm8,0x10(%rsp)
  movapd %xmm0,%xmm3
  movsd  %xmm6,0x8(%rsp)
  call   <SetTransferMatrix@plt>
  movsd  0x8(%rsp),%xmm6
  pxor   %xmm5,%xmm5
  movsd  (%rsp),%xmm7
  movq   D13(%rip),%xmm1
  movsd  0x10(%rsp),%xmm8
  movapd %xmm5,%xmm4
  movapd %xmm6,%xmm2
  movapd %xmm7,%xmm3
  divsd  %xmm8,%xmm3
  xorpd  %xmm1,%xmm2
  movsd  %xmm8,(%rsp)
  divsd  %xmm8,%xmm2
  movapd %xmm3,%xmm0
  xorpd  %xmm2,%xmm1
  call   <SetTransferMatrix@plt>
  movsd  (%rsp),%xmm8
  add    $0x20,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  movapd %xmm8,%xmm0
  jmp    1090 <GluonHelp@plt>
L0:
  movapd %xmm8,%xmm0
  movsd  %xmm6,0x18(%rsp)
  movsd  %xmm7,0x10(%rsp)
  movsd  %xmm5,0x8(%rsp)
  movsd  %xmm4,(%rsp)
  call   <sqrt@plt>
  movsd  0x18(%rsp),%xmm6
  movsd  0x10(%rsp),%xmm7
  movsd  0x8(%rsp),%xmm5
  movsd  (%rsp),%xmm4
  movapd %xmm0,%xmm8
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: f64
name: retrieve_data
arguments: data_label: D13
data_type: f32[2]

tool: D5: 1

tool: {"D13": [0.0,-0.0]}

assistant: ```c
void Gluon(double *args) {
  double dx = args[2] - args[0];
  double dy = args[3] - args[1];
  double dr = sqrt(dx * dx + dy * dy);
  SetTransferMatrix(1, 0, 0, 1, args[0], args[1]);
  SetTransferMatrix(dx / dr, dy / dr, -dy / dr, dx / dr, 0, 0);
  GluonHelp(args, dr);
}
```
user: What is the c source code of the assembly code below:

```asm
<Gluon>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  movsd  (%rdi),%xmm4
  movsd  0x10(%rdi),%xmm7
  movsd  0x8(%rdi),%xmm5
  movsd  0x18(%rdi),%xmm6
  subsd  %xmm4,%xmm7
  subsd  %xmm5,%xmm6
  movapd %xmm7,%xmm8
  mulsd  %xmm7,%xmm8
  movapd %xmm6,%xmm0
  mulsd  %xmm6,%xmm0
  addsd  %xmm0,%xmm8
  pxor   %xmm0,%xmm0
  ucomisd %xmm8,%xmm0
  ja     L13
  sqrtsd %xmm8,%xmm8
  movapd %xmm0,%xmm2
L16:
  movsd  D18(%rip),%xmm0
  movapd %xmm2,%xmm1
  movsd  %xmm7,(%rsp)
  movsd  %xmm8,0x10(%rsp)
  movapd %xmm0,%xmm3
  movsd  %xmm6,0x8(%rsp)
  call   <SetTransferMatrix@plt>
  movsd  0x8(%rsp),%xmm6
  pxor   %xmm5,%xmm5
  movsd  (%rsp),%xmm7
  movq   D19(%rip),%xmm1
  movsd  0x10(%rsp),%xmm8
  movapd %xmm5,%xmm4
  movapd %xmm6,%xmm2
  movapd %xmm7,%xmm3
  divsd  %xmm8,%xmm3
  xorpd  %xmm1,%xmm2
  movsd  %xmm8,(%rsp)
  divsd  %xmm8,%xmm2
  movapd %xmm3,%xmm0
  xorpd  %xmm2,%xmm1
  call   <SetTransferMatrix@plt>
  movsd  (%rsp),%xmm8
  add    $0x20,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  movapd %xmm8,%xmm0
  jmp    1090 <GluonHelp@plt>
L13:
  movapd %xmm8,%xmm0
  movsd  %xmm6,0x18(%rsp)
  movsd  %xmm7,0x10(%rsp)
  movsd  %xmm5,0x8(%rsp)
  movsd  %xmm4,(%rsp)
  call   <sqrt@plt>
  movsd  0x18(%rsp),%xmm6
  movsd  0x10(%rsp),%xmm7
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm5
  movsd  (%rsp),%xmm4
  movapd %xmm0,%xmm8
  jmp    L16
```

tool_calls: name: read_data
arguments: data_label: D18
type: f64
name: read_data
arguments: data_label: D19
type: f32[2]

tool: D18: 1

tool: {"D19": [0.0,-0.0]}

assistant: ```c
void Gluon(double *args) {
  double dx = args[2] - args[0];
  double dy = args[3] - args[1];
  double dr = sqrt(dx * dx + dy * dy);
  SetTransferMatrix(1, 0, 0, 1, args[0], args[1]);
  SetTransferMatrix(dx / dr, dy / dr, -dy / dr, dx / dr, 0, 0);
  GluonHelp(args, dr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: suma: %d


assistant: ```c
int main(void) {
  printf("suma: %d\n", 3 + 1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: suma: %d


assistant: ```c
int main(void) {
  printf("suma: %d\n", 3 + 1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: suma: %d


assistant: ```c
int main(void) {
  printf("suma: %d\n", 3 + 1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: suma: %d


assistant: ```c
int main(void) {
  printf("suma: %d\n", 3 + 1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uq_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L30
L13:
  mov    -0x24(%rbp),%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L3
  cmpq   $0x0,-0x18(%rbp)
  je     L68
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L68:
  cmpq   $0x0,-0x20(%rbp)
  je     L42
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L42:
  mov    $0x1,%eax
  jmp    L30
L3:
  mov    -0x24(%rbp),%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L70
  cmpq   $0x0,-0x18(%rbp)
  je     L40
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L40:
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <getyesno@plt>
  jmp    L30
L70:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
L30:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: ?Internal error: uq_ok()

assistant: ```c
int uq_ok(char *preface, char *prompt, int mask, char **help, int dflt) {
  int rc, len;
  char *text = 0L;
  if (!prompt)
    return (-1);
  if ((mask & 3) == 1) {
    {
      if (preface)
        printf("%s\n", preface);
      if (prompt)
        printf("%s\n", prompt);
      return (1);
    }
  } else if ((mask & 3) == 3) {
    {
      if (preface)
        printf("%s\n", preface);
      return (getyesno(prompt, 0));
    }
  } else {
    printf("?Internal error: uq_ok()\n");
    return (-1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uq_ok>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L54
  mov    %rsi,%rbp
  mov    %edx,%ebx
  and    $0x3,%ebx
  cmp    $0x1,%ebx
  je     L46
  cmp    $0x3,%ebx
  jne    L19
  test   %rdi,%rdi
  je     L12
  call   <puts@plt>
L12:
  mov    $0x0,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <getyesno@plt>
  mov    %eax,%ebx
L35:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L46:
  test   %rdi,%rdi
  je     L13
  call   <puts@plt>
L13:
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L35
L19:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%ebx
  jmp    L35
L54:
  mov    $0xffffffff,%ebx
  jmp    L35
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: ?Internal error: uq_ok()

assistant: ```c
int uq_ok(char *preface, char *prompt, int mask, char **help, int dflt) {
  int rc, len;
  char *text = 0L;
  if (!prompt)
    return (-1);
  if ((mask & 3) == 1) {
    {
      if (preface)
        printf("%s\n", preface);
      if (prompt)
        printf("%s\n", prompt);
      return (1);
    }
  } else if ((mask & 3) == 3) {
    {
      if (preface)
        printf("%s\n", preface);
      return (getyesno(prompt, 0));
    }
  } else {
    printf("?Internal error: uq_ok()\n");
    return (-1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uq_ok>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L10
  and    $0x3,%edx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  cmp    $0x1,%edx
  je     L32
  cmp    $0x3,%edx
  jne    L21
  test   %rdi,%rdi
  je     L30
  call   <puts@plt>
L30:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <getyesno@plt>
L32:
  test   %rdi,%rdi
  je     L41
  call   <puts@plt>
L41:
  mov    %rbp,%rdi
  call   <puts@plt>
L9:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L21:
  lea    D2(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
  jmp    L9
L10:
  mov    $0xffffffff,%r12d
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: ?Internal error: uq_ok()

assistant: ```c
int uq_ok(char *preface, char *prompt, int mask, char **help, int dflt) {
  int rc, len;
  char *text = 0L;
  if (!prompt)
    return (-1);
  if ((mask & 3) == 1) {
    {
      if (preface)
        printf("%s\n", preface);
      if (prompt)
        printf("%s\n", prompt);
      return (1);
    }
  } else if ((mask & 3) == 3) {
    {
      if (preface)
        printf("%s\n", preface);
      return (getyesno(prompt, 0));
    }
  } else {
    printf("?Internal error: uq_ok()\n");
    return (-1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uq_ok>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L53
  and    $0x3,%edx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  cmp    $0x1,%edx
  je     L23
  cmp    $0x3,%edx
  jne    L15
  test   %rdi,%rdi
  je     L48
  call   <puts@plt>
L48:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <getyesno@plt>
L23:
  test   %rdi,%rdi
  je     L37
  call   <puts@plt>
L37:
  mov    %rbp,%rdi
  call   <puts@plt>
L4:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L15:
  lea    D3(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
  jmp    L4
L53:
  mov    $0xffffffff,%r12d
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string

tool: D3: ?Internal error: uq_ok()

assistant: ```c
int uq_ok(char *preface, char *prompt, int mask, char **help, int dflt) {
  int rc, len;
  char *text = 0L;
  if (!prompt)
    return (-1);
  if ((mask & 3) == 1) {
    {
      if (preface)
        printf("%s\n", preface);
      if (prompt)
        printf("%s\n", prompt);
      return (1);
    }
  } else if ((mask & 3) == 3) {
    {
      if (preface)
        printf("%s\n", preface);
      return (getyesno(prompt, 0));
    }
  } else {
    printf("?Internal error: uq_ok()\n");
    return (-1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scan_file_ref>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  jne    L91
  mov    $0x0,%eax
  jmp    L43
L91:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L63
L17:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L96
  mov    -0x48(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  je     L47
L96:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L51
  mov    -0x48(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L51
  addq   $0x1,-0x48(%rbp)
L51:
  mov    -0x48(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L63
L47:
  mov    -0x48(%rbp),%rax
  mov    $0x29,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L104
  jmp    L63
L104:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x48(%rbp),%rax
  lea    0x2(%rax),%rdx
  lea    -0x34(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <append_file@plt>
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  jne    L107
  mov    $0x0,%eax
  jmp    L43
L107:
  mov    -0x30(%rbp),%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x48(%rbp)
L63:
  mov    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  cmp    %rax,-0x28(%rbp)
  jb     L17
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
L43:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L135
  call   <__stack_chk_fail@plt>
L135:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *scan_file_ref(char *str) {
  char *dst, *p, *q;
  int len;
  len = strlen(str) + 1;
  dst = malloc(len);
  if (!dst)
    return 0;
  for (p = dst; p < dst + len - 1;) {
    if (*str != '=' || str[1] != '(') {
      if (*str == '\\' && str[1] == '=') {
        ++str;
      }
      *p++ = *str++;
      continue;
    }
    q = strchr(str, ')');
    if (!q)
      continue;
    *q = 0;
    *p = 0;
    append_file(&dst, &len, str + 2);
    if (!dst)
      return 0;
    p = dst + strlen(dst);
    str = q + 1;
  }
  *p = 0;
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<scan_file_ref>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %edi,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L70
  movslq 0xc(%rsp),%rax
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jae    L71
  lea    0xc(%rsp),%r12
  jmp    L39
L21:
  cmp    $0x5c,%al
  jne    L91
  cmpb   $0x3d,0x1(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
L91:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  lea    0x1(%rbx),%rbx
L51:
  movslq 0xc(%rsp),%rax
  mov    0x10(%rsp),%rdx
  lea    -0x1(%rdx,%rax,1),%rax
  cmp    %rax,%rbp
  jae    L71
L39:
  movzbl (%rbx),%eax
  cmp    $0x3d,%al
  jne    L21
  cmpb   $0x28,0x1(%rbx)
  jne    L91
  mov    $0x29,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L51
  movb   $0x0,(%rax)
  movb   $0x0,0x0(%rbp)
  lea    0x2(%rbx),%rdx
  lea    0x10(%rsp),%rdi
  mov    %r12,%rsi
  call   <append_file@plt>
  mov    0x10(%rsp),%rbp
  test   %rbp,%rbp
  je     L70
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  lea    0x1(%r13),%rbx
  jmp    L51
L71:
  movb   $0x0,0x0(%rbp)
  mov    0x10(%rsp),%rbp
L70:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  mov    %rbp,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *scan_file_ref(char *str) {
  char *dst, *p, *q;
  int len;
  len = strlen(str) + 1;
  dst = malloc(len);
  if (!dst)
    return 0;
  for (p = dst; p < dst + len - 1;) {
    if (*str != '=' || str[1] != '(') {
      if (*str == '\\' && str[1] == '=') {
        ++str;
      }
      *p++ = *str++;
      continue;
    }
    q = strchr(str, ')');
    if (!q)
      continue;
    *q = 0;
    *p = 0;
    append_file(&dst, &len, str + 2);
    if (!dst)
      return 0;
    p = dst + strlen(dst);
    str = q + 1;
  }
  *p = 0;
  return dst;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scan_file_ref>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %edi,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L92
  mov    %rax,%rbx
  movslq 0xc(%rsp),%rax
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jb     L52
  jmp    L4
  nopl   (%rax)
L27:
  cmpb   $0x28,0x1(%rbp)
  je     L65
L12:
  mov    %al,(%rbx)
  add    $0x1,%rbp
  add    $0x1,%rbx
L32:
  movslq 0xc(%rsp),%rax
  mov    0x10(%rsp),%rdx
  lea    -0x1(%rdx,%rax,1),%rax
  cmp    %rax,%rbx
  jae    L4
L52:
  movzbl 0x0(%rbp),%eax
  cmp    $0x3d,%al
  je     L27
  cmp    $0x5c,%al
  jne    L12
  cmpb   $0x3d,0x1(%rbp)
  jne    L12
  add    $0x1,%rbp
  mov    $0x3d,%eax
  jmp    L12
  nopl   0x0(%rax)
L65:
  mov    $0x29,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L32
  movb   $0x0,(%rax)
  lea    0x2(%rbp),%rdx
  lea    0xc(%rsp),%rsi
  movb   $0x0,(%rbx)
  lea    0x10(%rsp),%rdi
  call   <append_file@plt>
  mov    0x10(%rsp),%rbx
  test   %rbx,%rbx
  je     L92
  mov    %rbx,%rdi
  lea    0x1(%r12),%rbp
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  jmp    L32
  nop
L4:
  movb   $0x0,(%rbx)
  mov    0x10(%rsp),%rax
L25:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L92:
  xor    %eax,%eax
  jmp    L25
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *scan_file_ref(char *str) {
  char *dst, *p, *q;
  int len;
  len = strlen(str) + 1;
  dst = malloc(len);
  if (!dst)
    return 0;
  for (p = dst; p < dst + len - 1;) {
    if (*str != '=' || str[1] != '(') {
      if (*str == '\\' && str[1] == '=') {
        ++str;
      }
      *p++ = *str++;
      continue;
    }
    q = strchr(str, ')');
    if (!q)
      continue;
    *q = 0;
    *p = 0;
    append_file(&dst, &len, str + 2);
    if (!dst)
      return 0;
    p = dst + strlen(dst);
    str = q + 1;
  }
  *p = 0;
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scan_file_ref>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %edi,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L6
  mov    %rax,%rbx
  movslq 0xc(%rsp),%rax
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jb     L110
  jmp    L103
  nopl   (%rax)
L133:
  cmpb   $0x28,0x1(%rbp)
  je     L121
L104:
  mov    %al,(%rbx)
  add    $0x1,%rbp
  add    $0x1,%rbx
L23:
  movslq 0xc(%rsp),%rax
  mov    0x10(%rsp),%rdx
  lea    -0x1(%rdx,%rax,1),%rax
  cmp    %rax,%rbx
  jae    L103
L110:
  movzbl 0x0(%rbp),%eax
  cmp    $0x3d,%al
  je     L133
  cmp    $0x5c,%al
  jne    L104
  cmpb   $0x3d,0x1(%rbp)
  jne    L104
  add    $0x1,%rbp
  mov    $0x3d,%eax
  jmp    L104
  nopl   0x0(%rax)
L121:
  mov    $0x29,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L23
  movb   $0x0,(%rax)
  lea    0x2(%rbp),%rdx
  lea    0xc(%rsp),%rsi
  movb   $0x0,(%rbx)
  lea    0x10(%rsp),%rdi
  call   <append_file@plt>
  mov    0x10(%rsp),%rbx
  test   %rbx,%rbx
  je     L6
  mov    %rbx,%rdi
  lea    0x1(%r12),%rbp
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  jmp    L23
  nop
L103:
  movb   $0x0,(%rbx)
  mov    0x10(%rsp),%rax
L37:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L115
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  jmp    L37
L115:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *scan_file_ref(char *str) {
  char *dst, *p, *q;
  int len;
  len = strlen(str) + 1;
  dst = malloc(len);
  if (!dst)
    return 0;
  for (p = dst; p < dst + len - 1;) {
    if (*str != '=' || str[1] != '(') {
      if (*str == '\\' && str[1] == '=') {
        ++str;
      }
      *p++ = *str++;
      continue;
    }
    q = strchr(str, ')');
    if (!q)
      continue;
    *q = 0;
    *p = 0;
    append_file(&dst, &len, str + 2);
    if (!dst)
      return 0;
    p = dst + strlen(dst);
    str = q + 1;
  }
  *p = 0;
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_print_plan_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <my_print_plan_level@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void my_print_plan_all(int max_time) {
  int i;
  for (i = 0; i <= max_time; i++)
    my_print_plan_level(i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_print_plan_all>:
  endbr64
  test   %edi,%edi
  js     L4
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L14:
  mov    %ebx,%edi
  call   <my_print_plan_level@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  ret
```

assistant: ```c
void my_print_plan_all(int max_time) {
  int i;
  for (i = 0; i <= max_time; i++)
    my_print_plan_level(i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_print_plan_all>:
  endbr64
  test   %edi,%edi
  js     L6
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <my_print_plan_level@plt>
  cmp    %ebx,%ebp
  jge    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L6:
  ret
```

assistant: ```c
void my_print_plan_all(int max_time) {
  int i;
  for (i = 0; i <= max_time; i++)
    my_print_plan_level(i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_print_plan_all>:
  endbr64
  test   %edi,%edi
  js     L7
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <my_print_plan_level@plt>
  cmp    %ebx,%ebp
  jge    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  ret
```

assistant: ```c
void my_print_plan_all(int max_time) {
  int i;
  for (i = 0; i <= max_time; i++)
    my_print_plan_level(i);
}
```