ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%edi
  call   <search@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  search(1000);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%edi
  call   <search@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  search(1000);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<toBin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  movl   $0x1f,-0x4(%rbp)
  jmp    L10
L36:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L13
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L43
L13:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L43:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L4
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L4:
  subl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x0,-0x4(%rbp)
  jns    L36
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D12
datatype: string

tool: D2: 1

tool: D0: 0

tool: D12:  

assistant: ```c
char *toBin(int n, char **buffer, int bits_per_component) {
  *buffer = (char *)realloc(*buffer, sizeof(int) * 8 + 1 + 1);
  *buffer[0] = 0;
  for (int c = sizeof(int) * 8 - 1; c >= 0; c--) {
    if ((n >> c) & 1)
      strcat(*buffer, "1");
    else
      strcat(*buffer, "0");
    if (c == bits_per_component)
      strcat(*buffer, " ");
  }
  return *buffer;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<toBin>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    $0x22,%esi
  mov    0x0(%rbp),%rdi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  movb   $0x0,(%rax)
  mov    $0x1f,%ebx
  lea    D28(%rip),%r15
  lea    D19(%rip),%r14
  jmp    L53
L59:
  mov    %r15,%rsi
  mov    0x0(%rbp),%rdi
  call   <strcat@plt>
L55:
  cmp    %ebx,%r12d
  je     L38
L33:
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L41
L53:
  bt     %ebx,%r13d
  jae    L59
  mov    %r14,%rsi
  mov    0x0(%rbp),%rdi
  call   <strcat@plt>
  jmp    L55
L38:
  lea    D12(%rip),%rsi
  mov    0x0(%rbp),%rdi
  call   <strcat@plt>
  jmp    L33
L41:
  mov    0x0(%rbp),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string
name: retrieve_data
arguments: label: D12
data_type: string

tool: D28: 0

tool: D19: 1

tool: D12:  

assistant: ```c
char *toBin(int n, char **buffer, int bits_per_component) {
  *buffer = (char *)realloc(*buffer, sizeof(int) * 8 + 1 + 1);
  *buffer[0] = 0;
  for (int c = sizeof(int) * 8 - 1; c >= 0; c--) {
    if ((n >> c) & 1)
      strcat(*buffer, "1");
    else
      strcat(*buffer, "0");
    if (c == bits_per_component)
      strcat(*buffer, " ");
  }
  return *buffer;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<toBin>:
  endbr64
  push   %r15
  mov    $0x1f,%r15d
  push   %r14
  lea    D24(%rip),%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x22,%esi
  sub    $0x8,%rsp
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  movb   $0x0,(%rax)
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r13,%rsi
  call   <strcat@plt>
  cmp    %r15d,%ebp
  je     L46
L3:
  sub    $0x1,%r15d
  jb     L6
L44:
  bt     %r15d,%r12d
  mov    (%rbx),%rdi
  jb     L4
  mov    %r14,%rsi
  call   <strcat@plt>
  cmp    %r15d,%ebp
  jne    L3
L46:
  mov    (%rbx),%rdi
  lea    D8(%rip),%rsi
  call   <strcat@plt>
  sub    $0x1,%r15d
  jae    L44
L6:
  mov    (%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D24
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string

tool: D24: 0

tool: D9: 1

tool: D8:  

assistant: ```c
char *toBin(int n, char **buffer, int bits_per_component) {
  *buffer = (char *)realloc(*buffer, sizeof(int) * 8 + 1 + 1);
  *buffer[0] = 0;
  for (int c = sizeof(int) * 8 - 1; c >= 0; c--) {
    if ((n >> c) & 1)
      strcat(*buffer, "1");
    else
      strcat(*buffer, "0");
    if (c == bits_per_component)
      strcat(*buffer, " ");
  }
  return *buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<toBin>:
  endbr64
  push   %r15
  mov    $0x1f,%r15d
  push   %r14
  lea    D26(%rip),%r14
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x22,%esi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  mov    0x0(%rbp),%rdi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  movb   $0x0,(%rax)
  jmp    L46
  nopl   (%rax)
L26:
  mov    %r13,%rsi
  call   <strcat@plt>
  cmp    %r15d,%ebx
  je     L35
L20:
  sub    $0x1,%r15d
  jb     L10
L46:
  bt     %r15d,%r12d
  mov    0x0(%rbp),%rdi
  jb     L26
  mov    %r14,%rsi
  call   <strcat@plt>
  cmp    %r15d,%ebx
  jne    L20
L35:
  mov    0x0(%rbp),%rdi
  lea    D11(%rip),%rsi
  lea    -0x1(%rbx),%r15d
  call   <strcat@plt>
  test   %ebx,%ebx
  jne    L46
L10:
  mov    0x0(%rbp),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D26
data_type: string
name: read_data
arguments: label: D27
data_type: string
name: read_data
arguments: label: D11
data_type: string

tool: D26: 0

tool: D27: 1

tool: D11:  

assistant: ```c
char *toBin(int n, char **buffer, int bits_per_component) {
  *buffer = (char *)realloc(*buffer, sizeof(int) * 8 + 1 + 1);
  *buffer[0] = 0;
  for (int c = sizeof(int) * 8 - 1; c >= 0; c--) {
    if ((n >> c) & 1)
      strcat(*buffer, "1");
    else
      strcat(*buffer, "0");
    if (c == bits_per_component)
      strcat(*buffer, " ");
  }
  return *buffer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int string_cmp(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_cmp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int string_cmp(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_cmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int string_cmp(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_cmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int string_cmp(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<searchInsert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L34
L33:
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L67
L108:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L88
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L67
L88:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L81
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L67
L81:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L104
L67:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L108
L104:
  cmpl   $0x0,-0x10(%rbp)
  js     L8
  mov    -0x10(%rbp),%eax
  jmp    L34
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L90
  mov    -0x4(%rbp),%eax
  jmp    L34
L90:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int searchInsert(int *nums, int numsSize, int target) {
  if (!numsSize)
    return (0);
  int res, l, u, m;
  res = -1;
  l = 0;
  u = numsSize - 1;
  while (l <= u) {
    m = (l + u) / 2;
    if (nums[m] < target)
      l = m + 1;
    else if (nums[m] > target)
      u = m - 1;
    else {
      res = m;
      break;
    }
  }
  if (res >= 0)
    return (res);
  if (target < nums[m])
    return (m);
  else
    return (m + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<searchInsert>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%r10d
  test   %esi,%esi
  je     L13
  sub    $0x1,%esi
  js     L27
  mov    $0x0,%edi
  jmp    L59
L32:
  jle    L63
  lea    -0x1(%rax),%esi
L65:
  cmp    %esi,%edi
  jg     L27
L59:
  lea    (%rdi,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r10d
  movslq %eax,%r8
  mov    (%r9,%r8,4),%r8d
  cmp    %edx,%r8d
  jge    L32
  lea    0x1(%rax),%edi
  jmp    L65
L27:
  movslq %r10d,%rax
  cmp    %edx,(%r9,%rax,4)
  jg     L13
L30:
  add    $0x1,%r10d
  jmp    L13
L63:
  cmp    $0xffffffff,%ecx
  jl     L30
L13:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int searchInsert(int *nums, int numsSize, int target) {
  if (!numsSize)
    return (0);
  int res, l, u, m;
  res = -1;
  l = 0;
  u = numsSize - 1;
  while (l <= u) {
    m = (l + u) / 2;
    if (nums[m] < target)
      l = m + 1;
    else if (nums[m] > target)
      u = m - 1;
    else {
      res = m;
      break;
    }
  }
  if (res >= 0)
    return (res);
  if (target < nums[m])
    return (m);
  else
    return (m + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<searchInsert>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L27
  sub    $0x1,%esi
  js     L0
  xor    %ecx,%ecx
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L19:
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jl     L40
L61:
  lea    (%rsi,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r8d
  cmp    %edx,%r8d
  jl     L19
  jle    L27
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L61
L40:
  cmp    %r8d,%edx
  setge  %dl
  movzbl %dl,%edx
  add    %edx,%eax
L27:
  ret
L0:
  mov    (%rdi),%r8d
  jmp    L40
```

assistant: ```c
int searchInsert(int *nums, int numsSize, int target) {
  if (!numsSize)
    return (0);
  int res, l, u, m;
  res = -1;
  l = 0;
  u = numsSize - 1;
  while (l <= u) {
    m = (l + u) / 2;
    if (nums[m] < target)
      l = m + 1;
    else if (nums[m] > target)
      u = m - 1;
    else {
      res = m;
      break;
    }
  }
  if (res >= 0)
    return (res);
  if (target < nums[m])
    return (m);
  else
    return (m + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<searchInsert>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L7
  sub    $0x1,%esi
  js     L68
  xor    %ecx,%ecx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L47:
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jl     L13
L30:
  lea    (%rsi,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r8d
  cmp    %edx,%r8d
  jl     L47
  jle    L7
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L30
L13:
  cmp    %r8d,%edx
  setge  %dl
  movzbl %dl,%edx
  add    %edx,%eax
L7:
  ret
L68:
  mov    (%rdi),%r8d
  jmp    L13
```

assistant: ```c
int searchInsert(int *nums, int numsSize, int target) {
  if (!numsSize)
    return (0);
  int res, l, u, m;
  res = -1;
  l = 0;
  u = numsSize - 1;
  while (l <= u) {
    m = (l + u) / 2;
    if (nums[m] < target)
      l = m + 1;
    else if (nums[m] > target)
      u = m - 1;
    else {
      res = m;
      break;
    }
  }
  if (res >= 0)
    return (res);
  if (target < nums[m])
    return (m);
  else
    return (m + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setSymmetry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9d,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L38:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L38
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setSymmetry(int *s, int *sDest, const int sCount, int *f, int *fDest, const int fCount) {
  int i;
  for (i = 0; i < sCount; i++)
    sDest[i] = s[i];
  for (i = 0; i < fCount; i++)
    fDest[i] = f[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setSymmetry>:
  endbr64
  mov    %rsi,%r10
  mov    %rcx,%rsi
  test   %edx,%edx
  jle    L12
  mov    %edx,%edx
  mov    $0x0,%eax
L32:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%r10,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L32
L12:
  test   %r9d,%r9d
  jle    L28
  mov    %r9d,%r9d
  mov    $0x0,%eax
L31:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L31
L28:
  ret
```

assistant: ```c
void setSymmetry(int *s, int *sDest, const int sCount, int *f, int *fDest, const int fCount) {
  int i;
  for (i = 0; i < sCount; i++)
    sDest[i] = s[i];
  for (i = 0; i < fCount; i++)
    fDest[i] = f[i];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<setSymmetry>:
  endbr64
  mov    %rsi,%r10
  mov    %rcx,%rsi
  test   %edx,%edx
  jle    L30
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%r10,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L30:
  test   %r9d,%r9d
  jle    L25
  movslq %r9d,%r9
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L22:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L22
L25:
  ret
```

assistant: ```c
void setSymmetry(int *s, int *sDest, const int sCount, int *f, int *fDest, const int fCount) {
  int i;
  for (i = 0; i < sCount; i++)
    sDest[i] = s[i];
  for (i = 0; i < fCount; i++)
    fDest[i] = f[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setSymmetry>:
  endbr64
  mov    %edx,%r10d
  push   %rbx
  mov    %rcx,%rdx
  test   %r10d,%r10d
  jle    L28
  lea    0x4(%rdi),%rcx
  mov    %rsi,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L74
  lea    -0x1(%r10),%eax
  cmp    $0x2,%eax
  jbe    L74
  mov    %r10d,%ecx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L30:
  movdqu (%rdi,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L30
  mov    %r10d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r10b
  je     L28
  mov    %eax,%r11d
  mov    (%rdi,%r11,4),%ebx
  lea    0x0(,%r11,4),%rcx
  mov    %ebx,(%rsi,%r11,4)
  lea    0x1(%rax),%r11d
  cmp    %r11d,%r10d
  jle    L28
  mov    0x4(%rdi,%rcx,1),%r11d
  add    $0x2,%eax
  mov    %r11d,0x4(%rsi,%rcx,1)
  cmp    %eax,%r10d
  jle    L28
  mov    0x8(%rdi,%rcx,1),%eax
  mov    %eax,0x8(%rsi,%rcx,1)
L28:
  test   %r9d,%r9d
  jle    L11
  lea    0x4(%rdx),%rcx
  mov    %r8,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L152
  lea    -0x1(%r9),%eax
  cmp    $0x2,%eax
  jbe    L152
  mov    %r9d,%ecx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L33:
  movdqu (%rdx,%rax,1),%xmm1
  movups %xmm1,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L33
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r9b
  je     L11
  mov    %eax,%esi
  mov    (%rdx,%rsi,4),%edi
  lea    0x0(,%rsi,4),%rcx
  mov    %edi,(%r8,%rsi,4)
  lea    0x1(%rax),%esi
  cmp    %esi,%r9d
  jle    L11
  mov    0x4(%rdx,%rcx,1),%esi
  add    $0x2,%eax
  mov    %esi,0x4(%r8,%rcx,1)
  cmp    %eax,%r9d
  jle    L11
  mov    0x8(%rdx,%rcx,1),%eax
  mov    %eax,0x8(%r8,%rcx,1)
L11:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L152:
  mov    %r9d,%r9d
  xor    %eax,%eax
  nopl   (%rax)
L20:
  mov    (%rdx,%rax,4),%ecx
  mov    %ecx,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L20
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L74:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L104:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L104
  jmp    L28
```

assistant: ```c
void setSymmetry(int *s, int *sDest, const int sCount, int *f, int *fDest, const int fCount) {
  int i;
  for (i = 0; i < sCount; i++)
    sDest[i] = s[i];
  for (i = 0; i < fCount; i++)
    fDest[i] = f[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<client_out_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: [CLIENT OUT] fd = %d


assistant: ```c
int client_out_callback(int sock, void *param) {
  printf("[CLIENT OUT] fd = %d\n", sock);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<client_out_callback>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: [CLIENT OUT] fd = %d


assistant: ```c
int client_out_callback(int sock, void *param) {
  printf("[CLIENT OUT] fd = %d\n", sock);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<client_out_callback>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: [CLIENT OUT] fd = %d


assistant: ```c
int client_out_callback(int sock, void *param) {
  printf("[CLIENT OUT] fd = %d\n", sock);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<client_out_callback>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: [CLIENT OUT] fd = %d


assistant: ```c
int client_out_callback(int sock, void *param) {
  printf("[CLIENT OUT] fd = %d\n", sock);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L18:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L24
L14:
  mov    -0x10(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    %edx,-0x14(%rbp)
  jne    L12
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L24:
  cmpl   $0x0,-0x10(%rbp)
  jg     L14
  cmpl   $0x0,-0xc(%rbp)
  je     L54
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L54:
  addl   $0x1,-0x14(%rbp)
L17:
  cmpl   $0x9,-0x14(%rbp)
  jle    L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D29
datatype: string
name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D27
datatype: string

tool: D29: Chislo:

tool: D18: %d

tool: D27: Cifrata %d e napisana %d puti


assistant: ```c
int main() {
  int cifra, chislo, neshto, broi;
  printf("Chislo:");
  scanf("%d", &chislo);
  for (cifra = 0; cifra < 10; cifra++) {
    broi = 0;
    neshto = chislo;
    while (neshto >= 1) {
      if (neshto % 10 == cifra)
        broi++;
      neshto /= 10;
    }
    if (broi != 0)
      printf("Cifrata %d e napisana %d puti\n", cifra, broi);
  }
}
```