user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <pow@plt>
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x77359400,%edi
  call   <pow@plt>
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0xc(%rbp)
  movl   $0x64,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  xor    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x77359400,-0xc(%rbp)
  movl   $0x7d2b7500,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  xor    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D63
datatype: string
name: disassemble_data
arguments: data_tag: D28
datatype: string
name: disassemble_data
arguments: data_tag: D21
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D63: 3 to the 2nd power is %d


tool: D28: 2e9 to the 10th power is %.0f


tool: D21: X is %d and Y is %d
Performing swap now.


tool: D1: After the swap X is %d and Y is %d!



tool: D12: Problem #19 -- X is %d and Y is %d
Performing swap now.


tool: D6: Problem #19 continued
 -- X is %d and Y is %d
Performing swap now.


assistant: ```c
int main(int argc, char *argv[]) {
  int power = pow(3, 2);
  printf("3 to the 2nd power is %d\n", power);
  printf("2e9 to the 10th power is %.0f\n", pow(2000000000, 10));
  int x = 1;
  int y = 100;
  printf("X is %d and Y is %d\nPerforming swap now.\n", x, y);
  int temp;
  temp = x;
  x = y;
  y = temp;
  printf("After the swap X is %d and Y is %d!\n\n", x, y);
  printf("Problem #19 -- X is %d and Y is %d\nPerforming swap now.\n", x, y);
  x = x ^ y;
  y = x ^ y;
  x = x ^ y;
  printf("After the swap X is %d and Y is %d!\n\n", x, y);
  x = 2000000000;
  y = 2100000000;
  printf("Problem #19 continued\n -- X is %d and Y is %d\nPerforming swap now.\n", x, y);
  x = x ^ y;
  y = x ^ y;
  x = x ^ y;
  printf("After the swap X is %d and Y is %d!\n\n", x, y);
}
```