ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strnsrch>:
  endbr64
  test   %rdi,%rdi
  je     L30
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L25
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %edx,%ebp
  call   <strlen@plt>
  mov    %rbx,%r8
  test   %eax,%eax
  je     L104
  test   %ebp,%ebp
  je     L25
  movslq %ebp,%rcx
  movslq %eax,%rdi
  movzbl (%r12),%esi
  add    $0x1,%rcx
  movzbl -0x1(%r12,%rdi,1),%r9d
  sub    %rdi,%rcx
  add    %rbx,%rcx
  cmp    %rcx,%rbx
  jb     L91
  jmp    L25
  nop
L116:
  add    $0x1,%rbx
  cmp    %rbx,%rcx
  je     L25
L91:
  cmp    %sil,(%rbx)
  jne    L116
  cmp    $0x1,%eax
  je     L117
  cmp    %r9b,-0x1(%rbx,%rdi,1)
  jne    L116
  cmp    $0x2,%eax
  jle    L117
  mov    $0x1,%edx
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L145:
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  je     L117
L14:
  movzbl (%r12,%rdx,1),%r10d
  cmp    %r10b,(%rbx,%rdx,1)
  je     L145
  cmp    %eax,%edx
  jl     L116
  nopl   0x0(%rax,%rax,1)
L117:
  mov    %rbx,%r8
L104:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strnsrch(const char *s1, const char *s2, const const int ls1) {
  char *s, *s1e;
  char cfirst, clast;
  int i, ls2;
  if (s1 == NULL || s2 == NULL) {
    return (NULL);
  }
  ls2 = strlen(s2);
  if (ls2 == 0) {
    return ((char *)s1);
  }
  if (ls1 == 0) {
    return (NULL);
  }
  cfirst = (char)s2[0];
  clast = (char)s2[ls2 - 1];
  s1e = (char *)s1 + (int)ls1 - ls2 + 1;
  s = (char *)s1;
  while (s < s1e) {
    if (*s == cfirst) {
      if (ls2 == 1) {
        return (s);
      }
      if (s[ls2 - 1] == clast) {
        if (ls2 == 2) {
          return (s);
        }
        i = 1;
        while (i < ls2 && s[i] == s2[i]) {
          i++;
        }
        if (i >= ls2) {
          return (s);
        }
      }
    }
    s++;
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strnsrch>:
  endbr64
  test   %rdi,%rdi
  je     L89
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L6
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %edx,%ebp
  call   <strlen@plt>
  mov    %rbx,%r8
  test   %eax,%eax
  je     L119
  test   %ebp,%ebp
  je     L6
  movslq %ebp,%rcx
  movslq %eax,%rdi
  movzbl (%r12),%esi
  add    $0x1,%rcx
  movzbl -0x1(%r12,%rdi,1),%r9d
  sub    %rdi,%rcx
  add    %rbx,%rcx
  cmp    %rcx,%rbx
  jb     L123
  jmp    L6
  nop
L142:
  add    $0x1,%rbx
  cmp    %rbx,%rcx
  je     L6
L123:
  cmp    %sil,(%rbx)
  jne    L142
  cmp    $0x1,%eax
  je     L46
  cmp    %r9b,-0x1(%rbx,%rdi,1)
  jne    L142
  cmp    $0x2,%eax
  jle    L46
  mov    $0x1,%edx
  jmp    L91
  cs nopw 0x0(%rax,%rax,1)
L126:
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  je     L46
L91:
  movzbl (%r12,%rdx,1),%r10d
  cmp    %r10b,(%rbx,%rdx,1)
  je     L126
  cmp    %eax,%edx
  jl     L142
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rbx,%r8
L119:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L89:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strnsrch(const char *s1, const char *s2, const const int ls1) {
  char *s, *s1e;
  char cfirst, clast;
  int i, ls2;
  if (s1 == NULL || s2 == NULL) {
    return (NULL);
  }
  ls2 = strlen(s2);
  if (ls2 == 0) {
    return ((char *)s1);
  }
  if (ls1 == 0) {
    return (NULL);
  }
  cfirst = (char)s2[0];
  clast = (char)s2[ls2 - 1];
  s1e = (char *)s1 + (int)ls1 - ls2 + 1;
  s = (char *)s1;
  while (s < s1e) {
    if (*s == cfirst) {
      if (ls2 == 1) {
        return (s);
      }
      if (s[ls2 - 1] == clast) {
        if (ls2 == 2) {
          return (s);
        }
        i = 1;
        while (i < ls2 && s[i] == s2[i]) {
          i++;
        }
        if (i >= ls2) {
          return (s);
        }
      }
    }
    s++;
  }
  return (NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L4:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t length = 0;
  while (*str++ != '\0') {
    length++;
  }
  return length;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L2
  mov    $0x0,%eax
L19:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L19
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t length = 0;
  while (*str++ != '\0') {
    length++;
  }
  return length;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L0
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t length = 0;
  while (*str++ != '\0') {
    length++;
  }
  return length;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L11
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L10
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t length = 0;
  while (*str++ != '\0') {
    length++;
  }
  return length;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<properties_parse_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L123
L80:
  addq   $0x1,-0x18(%rbp)
L123:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L80
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  je     L102
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L2
L131:
  addq   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L62
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L131
  jmp    L62
L121:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L62:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L121
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L151
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  jmp    L92
L173:
  addq   $0x1,-0x10(%rbp)
L92:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L173
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L93
L172:
  subq   $0x1,-0x8(%rbp)
L93:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L36
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L172
L36:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L35
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L35
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evhttp_add_header@plt>
  jmp    L35
L102:
  nop
  jmp    L35
L151:
  nop
L35:
  leave
  ret
```

assistant: ```c
void properties_parse_line(char *line, struct evkeyvalq *output) {
  char *key, *value, *end;
  key = line;
  while (isspace(*key))
    key++;
  if (*key == ';')
    return;
  value = key;
  while (!isspace(*value) && *value != '=')
    value++;
  while (isspace(*value)) {
    *value++ = 0;
  };
  if (*value != '=')
    return;
  *value++ = 0;
  while (isspace(*value))
    value++;
  end = value + strlen(value) - 1;
  while (end > value && isspace(*end))
    end--;
  *(end + 1) = 0;
  if (strlen(key) && strlen(value)) {
    evhttp_add_header(output, key, value);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<properties_parse_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  jmp    L131
L85:
  add    $0x1,%rbp
L131:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L85
  mov    %rbp,%rbx
  cmpb   $0x3b,0x0(%rbp)
  jne    L51
  jmp    L16
L27:
  add    $0x1,%rbx
L51:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L166
  cmpb   $0x3d,(%rbx)
  jne    L27
  jmp    L166
L154:
  add    $0x1,%rbx
  movb   $0x0,-0x1(%rbx)
L166:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L154
  cmpb   $0x3d,(%rbx)
  jne    L16
  lea    0x1(%rbx),%r12
  movb   $0x0,(%rbx)
  jmp    L106
L63:
  add    $0x1,%r12
L106:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L63
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jae    L60
L101:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L60
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L101
L60:
  movb   $0x0,0x1(%rbx)
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L61
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L16
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <evhttp_add_header@plt>
  jmp    L16
```

assistant: ```c
void properties_parse_line(char *line, struct evkeyvalq *output) {
  char *key, *value, *end;
  key = line;
  while (isspace(*key))
    key++;
  if (*key == ';')
    return;
  value = key;
  while (!isspace(*value) && *value != '=')
    value++;
  while (isspace(*value)) {
    *value++ = 0;
  };
  if (*value != '=')
    return;
  *value++ = 0;
  while (isspace(*value))
    value++;
  end = value + strlen(value) - 1;
  while (end > value && isspace(*end))
    end--;
  *(end + 1) = 0;
  if (strlen(key) && strlen(value)) {
    evhttp_add_header(output, key, value);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<properties_parse_line>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L63
  cs nopw 0x0(%rax,%rax,1)
L48:
  add    $0x1,%rbp
L63:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%rbx
  cmp    $0x3b,%dil
  jne    L103
  jmp    L136
  nopl   0x0(%rax)
L24:
  cmp    $0x3d,%dil
  je     L58
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L103:
  call   <isspace@plt>
  movsbl (%rbx),%edi
  test   %rax,%rax
  je     L24
  call   <isspace@plt>
  test   %rax,%rax
  je     L61
  nopl   (%rax)
L60:
  movb   $0x0,(%rbx)
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L58:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L60
L61:
  cmpb   $0x3d,(%rbx)
  jne    L136
  movb   $0x0,(%rbx)
  lea    0x1(%rbx),%r13
  jmp    L166
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%r13
L166:
  movsbl 0x0(%r13),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  mov    %r13,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r13,%rax,1),%rbx
  cmp    %rbx,%r13
  jb     L148
  jmp    L149
  nopl   0x0(%rax)
L83:
  sub    $0x1,%rbx
  cmp    %rbx,%r13
  je     L149
L148:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L83
L149:
  movb   $0x0,0x1(%rbx)
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L91
L136:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L91:
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L136
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <evhttp_add_header@plt>
```

assistant: ```c
void properties_parse_line(char *line, struct evkeyvalq *output) {
  char *key, *value, *end;
  key = line;
  while (isspace(*key))
    key++;
  if (*key == ';')
    return;
  value = key;
  while (!isspace(*value) && *value != '=')
    value++;
  while (isspace(*value)) {
    *value++ = 0;
  };
  if (*value != '=')
    return;
  *value++ = 0;
  while (isspace(*value))
    value++;
  end = value + strlen(value) - 1;
  while (end > value && isspace(*end))
    end--;
  *(end + 1) = 0;
  if (strlen(key) && strlen(value)) {
    evhttp_add_header(output, key, value);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<properties_parse_line>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L116
  cs nopw 0x0(%rax,%rax,1)
L125:
  add    $0x1,%rbp
L116:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L125
  cmpb   $0x3b,0x0(%rbp)
  mov    %rbp,%rbx
  jne    L114
  jmp    L40
L51:
  cmpb   $0x3d,(%rbx)
  je     L47
  add    $0x1,%rbx
L114:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L51
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L52
  nopl   0x0(%rax,%rax,1)
L34:
  movb   $0x0,(%rbx)
  add    $0x1,%rbx
L47:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L34
L52:
  cmpb   $0x3d,(%rbx)
  jne    L40
  movb   $0x0,(%rbx)
  lea    0x1(%rbx),%r12
  jmp    L82
  nopw   0x0(%rax,%rax,1)
L142:
  add    $0x1,%r12
L82:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L142
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jb     L71
  jmp    L128
  nopl   0x0(%rax)
L156:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L128
L71:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L156
L128:
  movb   $0x0,0x1(%rbx)
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L4
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L40
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <evhttp_add_header@plt>
```

assistant: ```c
void properties_parse_line(char *line, struct evkeyvalq *output) {
  char *key, *value, *end;
  key = line;
  while (isspace(*key))
    key++;
  if (*key == ';')
    return;
  value = key;
  while (!isspace(*value) && *value != '=')
    value++;
  while (isspace(*value)) {
    *value++ = 0;
  };
  if (*value != '=')
    return;
  *value++ = 0;
  while (isspace(*value))
    value++;
  end = value + strlen(value) - 1;
  while (end > value && isspace(*end))
    end--;
  *(end + 1) = 0;
  if (strlen(key) && strlen(value)) {
    evhttp_add_header(output, key, value);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  jne    L0
  mov    $0xffffffff,%eax
  jmp    L1
L0:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: %s


assistant: ```c
int send_command(int sock, char *command) {
  if (send(sock, command, strlen(command), 0) == -1) {
    return -1;
  }
  printf("%s\n", command);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<send_command>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  je     L4
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: %s


assistant: ```c
int send_command(int sock, char *command) {
  if (send(sock, command, strlen(command), 0) == -1) {
    return -1;
  }
  printf("%s\n", command);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<send_command>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  cmp    $0xffffffff,%eax
  je     L6
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L6:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: %s


assistant: ```c
int send_command(int sock, char *command) {
  if (send(sock, command, strlen(command), 0) == -1) {
    return -1;
  }
  printf("%s\n", command);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_command>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L1:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: %s


assistant: ```c
int send_command(int sock, char *command) {
  if (send(sock, command, strlen(command), 0) == -1) {
    return -1;
  }
  printf("%s\n", command);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nva_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <nva_rd32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  or     -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nva_wr32@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t nva_mask(int cnum, uint32_t reg, uint32_t mask, uint32_t val) {
  uint32_t tmp = nva_rd32(cnum, reg);
  nva_wr32(cnum, reg, (tmp & ~mask) | val);
  return tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nva_mask>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %ecx,%r14d
  call   <nva_rd32@plt>
  mov    %eax,%ebp
  not    %ebx
  mov    %ebx,%edx
  and    %eax,%edx
  or     %r14d,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <nva_wr32@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint32_t nva_mask(int cnum, uint32_t reg, uint32_t mask, uint32_t val) {
  uint32_t tmp = nva_rd32(cnum, reg);
  nva_wr32(cnum, reg, (tmp & ~mask) | val);
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nva_mask>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  not    %ebx
  call   <nva_rd32@plt>
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  and    %eax,%edx
  mov    %eax,%r12d
  or     %ebp,%edx
  call   <nva_wr32@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint32_t nva_mask(int cnum, uint32_t reg, uint32_t mask, uint32_t val) {
  uint32_t tmp = nva_rd32(cnum, reg);
  nva_wr32(cnum, reg, (tmp & ~mask) | val);
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nva_mask>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  not    %ebx
  call   <nva_rd32@plt>
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  and    %eax,%edx
  mov    %eax,%r12d
  or     %ebp,%edx
  call   <nva_wr32@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint32_t nva_mask(int cnum, uint32_t reg, uint32_t mask, uint32_t val) {
  uint32_t tmp = nva_rd32(cnum, reg);
  nva_wr32(cnum, reg, (tmp & ~mask) | val);
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Slinear2ulaw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L16
  movl   $0x80,-0xc(%rbp)
  negl   -0x14(%rbp)
  jmp    L14
L16:
  movl   $0x0,-0xc(%rbp)
L14:
  cmpl   $0x7f7b,-0x14(%rbp)
  jle    L12
  movl   $0x7f7b,-0x14(%rbp)
L12:
  addl   $0x84,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x7,%eax
  movzbl %al,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x3,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  not    %eax
  mov    %al,-0xd(%rbp)
  movzbl -0xd(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char Slinear2ulaw(int sample) {
  static int exp_lut[256] = {0, 0, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7};
  int sign, exponent, mantissa;
  unsigned char ulawbyte;
  if (sample < 0) {
    sign = 0x80;
    sample = -sample;
  } else
    sign = 0;
  if (sample > 32635)
    sample = 32635;
  sample = sample + 0x84;
  exponent = exp_lut[(sample >> 7) & 0xFF];
  mantissa = (sample >> (exponent + 3)) & 0x0F;
  ulawbyte = ~(sign | (exponent << 4) | mantissa);
  return (ulawbyte);
}
```