ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D21(%rip),%rdi
  push   %rbp
  push   %rbx
  call   <printf@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  lea    D15(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rax
  mov    $0x12f,%edx
  nopl   (%rax)
L5:
  mov    %edx,(%rax)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    $0x138,%edx
  jne    L5
  mov    $0x12f,%ebx
  lea    D27(%rip),%r12
  nopl   (%rax)
L18:
  cmp    %ebx,0x0(%rbp)
  je     L27
  mov    %r12,%rdi
  call   <printf@plt>
L27:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x138,%ebx
  jne    L18
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D15
type: string
name: extract_symbolic_data
arguments: data_label: D27
type: string

tool: D21: Hello world!


tool: D15: Let's leak a pointer to an array of 10 ints


tool: D27:   Something strange is happening...


assistant: ```c
int main() {
  printf("Hello world!\n");
  int *pI;
  pI = (int *)malloc(10 * sizeof(int));
  printf("Let's leak a pointer to an array of 10 ints\n");
  int i = 0;
  for (i = 0; i < 9; i++) {
    pI[i] = 303 + i;
  }
  int j = 0;
  for (j = 0; j < 9; j++) {
    if (pI[j] != 303 + j)
      printf("  Something strange is happening...\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  lea    D34(%rip),%rdi
  mov    %rax,%rbx
  call   <printf@plt>
  movdqa D16(%rip),%xmm0
  movl   $0x137,0x20(%rbx)
  xor    %eax,%eax
  movups %xmm0,(%rbx)
  movdqa D8(%rip),%xmm0
  movups %xmm0,0x10(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D38
datatype: string
name: read_data
arguments: data_label: D34
datatype: string
name: read_data
arguments: data_label: D16
datatype: byte[16]
name: read_data
arguments: data_label: D8
datatype: byte[16]

tool: D38: Hello world!


tool: D34: Let's leak a pointer to an array of 10 ints


tool: {"D16": [0x2f,0x01,0x00,0x00,0x30,0x01,0x00,0x00,0x31,0x01,0x00,0x00,0x32,0x01,0x00,0x00]}

tool: {"D8": [0x33,0x01,0x00,0x00,0x34,0x01,0x00,0x00,0x35,0x01,0x00,0x00,0x36,0x01,0x00,0x00]}

assistant: ```c
int main() {
  printf("Hello world!\n");
  int *pI;
  pI = (int *)malloc(10 * sizeof(int));
  printf("Let's leak a pointer to an array of 10 ints\n");
  int i = 0;
  for (i = 0; i < 9; i++) {
    pI[i] = 303 + i;
  }
  int j = 0;
  for (j = 0; j < 9; j++) {
    if (pI[j] != 303 + j)
      printf("  Something strange is happening...\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<obter_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L7:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
L22:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0xa,-0x5(%rbp)
  je     L18
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L7
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int obter_string(char str[], int n) {
  int i = 0;
  char c;
  while ((c = getchar()) != '\n' && i < n - 1) {
    str[i++] = c;
  }
  str[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<obter_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    -0x1(%rsi),%r12d
  jmp    L25
L17:
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L25:
  mov    %ebx,%r13d
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L11
  cmp    %ebx,%r12d
  jg     L17
L11:
  movslq %r13d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int obter_string(char str[], int n) {
  int i = 0;
  char c;
  while ((c = getchar()) != '\n' && i < n - 1) {
    str[i++] = c;
  }
  str[i] = '\0';
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<obter_string>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L11:
  cmp    %r12d,%ebp
  jle    L18
  mov    %al,(%rbx)
  add    $0x1,%r12d
  add    $0x1,%rbx
L28:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L11
L18:
  movb   $0x0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int obter_string(char str[], int n) {
  int i = 0;
  char c;
  while ((c = getchar()) != '\n' && i < n - 1) {
    str[i++] = c;
  }
  str[i] = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<obter_string>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    %r12d,%ebp
  jle    L3
  mov    %al,(%rbx)
  add    $0x1,%r12d
  add    $0x1,%rbx
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L0
L3:
  movb   $0x0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int obter_string(char str[], int n) {
  int i = 0;
  char c;
  while ((c = getchar()) != '\n' && i < n - 1) {
    str[i++] = c;
  }
  str[i] = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<M4U_WriteReg32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <iowrite32@plt>
  mov    $0x0,%eax
  call   <mb@plt>
  nop
  leave
  ret
```

assistant: ```c
void M4U_WriteReg32(unsigned long M4uBase, unsigned long Offset, unsigned int Val) {
  iowrite32(Val, (void *)(M4uBase + Offset));
  mb();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<M4U_WriteReg32>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %edx,%edi
  add    %rax,%rsi
  call   <iowrite32@plt>
  mov    $0x0,%eax
  call   <mb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void M4U_WriteReg32(unsigned long M4uBase, unsigned long Offset, unsigned int Val) {
  iowrite32(Val, (void *)(M4uBase + Offset));
  mb();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<M4U_WriteReg32>:
  endbr64
  mov    %rdi,%r8
  sub    $0x8,%rsp
  mov    %edx,%edi
  add    %r8,%rsi
  call   <iowrite32@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <mb@plt>
```

assistant: ```c
void M4U_WriteReg32(unsigned long M4uBase, unsigned long Offset, unsigned int Val) {
  iowrite32(Val, (void *)(M4uBase + Offset));
  mb();
}
```
user: Translate the below assembly code into C programming language:

```asm
<M4U_WriteReg32>:
  endbr64
  mov    %rdi,%r8
  sub    $0x8,%rsp
  mov    %edx,%edi
  add    %r8,%rsi
  call   <iowrite32@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <mb@plt>
```

assistant: ```c
void M4U_WriteReg32(unsigned long M4uBase, unsigned long Offset, unsigned int Val) {
  iowrite32(Val, (void *)(M4uBase + Offset));
  mb();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x20(%rbp)
  jmp    L7
L15:
  mov    -0x20(%rbp),%eax
  sar    $0x4,%eax
  and    $0x3,%eax
  imul   $0x55,%eax,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0x2,%eax
  and    $0x3,%eax
  imul   $0x55,%eax,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  and    $0x3,%eax
  imul   $0x55,%eax,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0xffffff80,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0xffffff80,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  shl    $0x4,%eax
  or     %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  or     %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L7:
  cmpl   $0x3f,-0x20(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: cbClrTab[%d]=12'h%03X;


assistant: ```c
int main() {
  int cr, cg, cb;
  int cy, cu, cv;
  int i, j, k;
  for (i = 0; i < 64; i++) {
    cr = ((i >> 4) & 3) * 85;
    cg = ((i >> 2) & 3) * 85;
    cb = ((i >> 0) & 3) * 85;
    cy = (cr + 2 * cg + cb) / 4;
    cu = (cb - cg) / 2 + 128;
    cv = (cr - cg) / 2 + 128;
    k = ((cy / 16) << 8) | ((cu / 16) << 4) | ((cv / 16) << 0);
    printf("cbClrTab[%d]=12'h%03X;\n", i, k);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
L9:
  mov    %ebx,%edi
  sar    $0x4,%edi
  and    $0x3,%edi
  imul   $0x55,%edi,%edi
  mov    %ebx,%eax
  sar    $0x2,%eax
  and    $0x3,%eax
  imul   $0x55,%eax,%esi
  mov    %ebx,%ecx
  and    $0x3,%ecx
  imul   $0x55,%ecx,%ecx
  imul   $0xaa,%eax,%edx
  add    %edi,%edx
  add    %ecx,%edx
  sar    $0x6,%edx
  shl    $0x8,%edx
  sub    %esi,%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  lea    0x8f(%rax),%edi
  sub    $0xffffff80,%eax
  cmovs  %edi,%eax
  sar    $0x4,%eax
  or     %eax,%edx
  sub    %esi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  lea    0x8f(%rax),%ecx
  sub    $0xffffff80,%eax
  cmovs  %ecx,%eax
  and    $0xfffffff0,%eax
  or     %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x40,%ebx
  jne    L9
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string

tool: D1: cbClrTab[%d]=12'h%03X;


assistant: ```c
int main() {
  int cr, cg, cb;
  int cy, cu, cv;
  int i, j, k;
  for (i = 0; i < 64; i++) {
    cr = ((i >> 4) & 3) * 85;
    cg = ((i >> 2) & 3) * 85;
    cb = ((i >> 0) & 3) * 85;
    cy = (cr + 2 * cg + cb) / 4;
    cu = (cb - cg) / 2 + 128;
    cv = (cr - cg) / 2 + 128;
    k = ((cy / 16) << 8) | ((cu / 16) << 4) | ((cv / 16) << 0);
    printf("cbClrTab[%d]=12'h%03X;\n", i, k);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebp,%eax
  mov    %ebp,%ecx
  mov    %ebp,%edi
  sar    $0x2,%eax
  sar    $0x4,%ecx
  and    $0x3,%edi
  and    $0x3,%eax
  imul   $0x55,%ecx,%ecx
  imul   $0xaa,%eax,%edx
  imul   $0x55,%eax,%esi
  imul   $0x55,%edi,%edi
  add    %ecx,%edx
  sub    %esi,%ecx
  add    %edi,%edx
  sub    %esi,%edi
  mov    %ebp,%esi
  add    $0x1,%ebp
  mov    %edi,%eax
  sar    $0x6,%edx
  shr    $0x1f,%eax
  shl    $0x8,%edx
  add    %edi,%eax
  mov    %rbx,%rdi
  sar    %eax
  sub    $0xffffff80,%eax
  and    $0xfffffff0,%eax
  or     %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  sub    $0xffffff80,%eax
  sar    $0x4,%eax
  or     %eax,%edx
  call   <printf@plt>
  cmp    $0x40,%ebp
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: cbClrTab[%d]=12'h%03X;


assistant: ```c
int main() {
  int cr, cg, cb;
  int cy, cu, cv;
  int i, j, k;
  for (i = 0; i < 64; i++) {
    cr = ((i >> 4) & 3) * 85;
    cg = ((i >> 2) & 3) * 85;
    cb = ((i >> 0) & 3) * 85;
    cy = (cr + 2 * cg + cb) / 4;
    cu = (cb - cg) / 2 + 128;
    cv = (cr - cg) / 2 + 128;
    k = ((cy / 16) << 8) | ((cu / 16) << 4) | ((cv / 16) << 0);
    printf("cbClrTab[%d]=12'h%03X;\n", i, k);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebp,%eax
  mov    %ebp,%ecx
  mov    %ebp,%edi
  sar    $0x2,%eax
  sar    $0x4,%ecx
  and    $0x3,%edi
  and    $0x3,%eax
  imul   $0x55,%ecx,%ecx
  imul   $0xaa,%eax,%edx
  imul   $0x55,%eax,%esi
  imul   $0x55,%edi,%edi
  add    %ecx,%edx
  sub    %esi,%ecx
  add    %edi,%edx
  sub    %esi,%edi
  mov    %ebp,%esi
  add    $0x1,%ebp
  mov    %edi,%eax
  sar    $0x6,%edx
  shr    $0x1f,%eax
  shl    $0x8,%edx
  add    %edi,%eax
  mov    %rbx,%rdi
  sar    %eax
  sub    $0xffffff80,%eax
  and    $0xfffffff0,%eax
  or     %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  sub    $0xffffff80,%eax
  sar    $0x4,%eax
  or     %eax,%edx
  call   <printf@plt>
  cmp    $0x40,%ebp
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D8: cbClrTab[%d]=12'h%03X;


assistant: ```c
int main() {
  int cr, cg, cb;
  int cy, cu, cv;
  int i, j, k;
  for (i = 0; i < 64; i++) {
    cr = ((i >> 4) & 3) * 85;
    cg = ((i >> 2) & 3) * 85;
    cb = ((i >> 0) & 3) * 85;
    cy = (cr + 2 * cg + cb) / 4;
    cu = (cb - cg) / 2 + 128;
    cv = (cr - cg) / 2 + 128;
    k = ((cy / 16) << 8) | ((cu / 16) << 4) | ((cv / 16) << 0);
    printf("cbClrTab[%d]=12'h%03X;\n", i, k);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_list_traverse_null_params>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <list_traverse@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L4
  movl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
bool test_list_traverse_null_params(void) {
  bool pass = false;
  unsigned int res = list_traverse(false, NULL, NULL);
  if (res == 1) {
    pass = true;
  }
  return pass;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_list_traverse_null_params>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <list_traverse@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool test_list_traverse_null_params(void) {
  bool pass = false;
  unsigned int res = list_traverse(false, NULL, NULL);
  if (res == 1) {
    pass = true;
  }
  return pass;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_list_traverse_null_params>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <list_traverse@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool test_list_traverse_null_params(void) {
  bool pass = false;
  unsigned int res = list_traverse(false, NULL, NULL);
  if (res == 1) {
    pass = true;
  }
  return pass;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_list_traverse_null_params>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <list_traverse@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool test_list_traverse_null_params(void) {
  bool pass = false;
  unsigned int res = list_traverse(false, NULL, NULL);
  if (res == 1) {
    pass = true;
  }
  return pass;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<interrupt_reserved_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L3:
  jmp    L3
```

assistant: ```c
void interrupt_reserved_3(void) {
  while (1) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<interrupt_reserved_3>:
  endbr64
L1:
  jmp    L1
```

assistant: ```c
void interrupt_reserved_3(void) {
  while (1) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<interrupt_reserved_3>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
void interrupt_reserved_3(void) {
  while (1) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<interrupt_reserved_3>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
void interrupt_reserved_3(void) {
  while (1) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<permutrng>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L19
L18:
  mov    $0x0,%eax
  call   <uniformrng@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L19:
  mov    -0x2c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void permutrng(int *ivec, int n) {
  int i;
  int j;
  double u;
  int itmp;
  for (i = 1; i <= n - 1; i++) {
    u = uniformrng();
    j = i + (int)floor((n - i + 1) * u);
    itmp = ivec[j];
    ivec[j] = ivec[i];
    ivec[i] = itmp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<permutrng>:
  endbr64
  cmp    $0x1,%esi
  jle    L3
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x1,%ebx
L0:
  mov    $0x0,%eax
  call   <uniformrng@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  add    %ebx,%eax
  cltq
  lea    (%r12,%rax,4),%rax
  mov    (%rax),%edx
  mov    (%r12,%rbx,4),%ecx
  mov    %ecx,(%rax)
  mov    %edx,(%r12,%rbx,4)
  add    $0x1,%rbx
  sub    $0x1,%ebp
  cmp    $0x1,%ebp
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

assistant: ```c
void permutrng(int *ivec, int n) {
  int i;
  int j;
  double u;
  int itmp;
  for (i = 1; i <= n - 1; i++) {
    u = uniformrng();
    j = i + (int)floor((n - i + 1) * u);
    itmp = ivec[j];
    ivec[j] = ivec[i];
    ivec[i] = itmp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<permutrng>:
  endbr64
  cmp    $0x1,%esi
  jle    L17
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  call   <uniformrng@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  sub    $0x1,%ebp
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  mov    (%r12,%rbx,4),%ecx
  add    %ebx,%eax
  cltq
  lea    (%r12,%rax,4),%rax
  mov    (%rax),%edx
  mov    %ecx,(%rax)
  mov    %edx,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x1,%ebp
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L17:
  ret
```

assistant: ```c
void permutrng(int *ivec, int n) {
  int i;
  int j;
  double u;
  int itmp;
  for (i = 1; i <= n - 1; i++) {
    u = uniformrng();
    j = i + (int)floor((n - i + 1) * u);
    itmp = ivec[j];
    ivec[j] = ivec[i];
    ivec[i] = itmp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<permutrng>:
  endbr64
  cmp    $0x1,%esi
  jle    L12
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  call   <uniformrng@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  sub    $0x1,%ebp
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  mov    (%r12,%rbx,4),%ecx
  add    %ebx,%eax
  cltq
  lea    (%r12,%rax,4),%rax
  mov    (%rax),%edx
  mov    %ecx,(%rax)
  mov    %edx,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x1,%ebp
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L12:
  ret
```

assistant: ```c
void permutrng(int *ivec, int n) {
  int i;
  int j;
  double u;
  int itmp;
  for (i = 1; i <= n - 1; i++) {
    u = uniformrng();
    j = i + (int)floor((n - i + 1) * u);
    itmp = ivec[j];
    ivec[j] = ivec[i];
    ivec[i] = itmp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memcpy(char *source, char *dest, int nbytes) {
  for (int i = 0; i < nbytes; i++)
    dest[i] = source[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  jle    L17
  mov    %edx,%edx
  mov    $0x0,%eax
L6:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L17:
  ret
```

assistant: ```c
void memcpy(char *source, char *dest, int nbytes) {
  for (int i = 0; i < nbytes; i++)
    dest[i] = source[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  jle    L8
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L11:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L11
L8:
  ret
```

assistant: ```c
void memcpy(char *source, char *dest, int nbytes) {
  for (int i = 0; i < nbytes; i++)
    dest[i] = source[i];
}
```