ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printEquation>:
  endbr64
  test   %esi,%esi
  jle    L26
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    (%rsi,%rsi,2),%r14d
  mov    $0x0,%r13d
  lea    D3(%rip),%r12
  jmp    L25
L15:
  add    $0x3,%r13d
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0xc,%rbp
  cmp    %r13d,%r14d
  je     L3
L25:
  mov    $0x0,%ebx
L28:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L28
  jmp    L15
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: %d 

assistant: ```c
void printEquation(int *equ, int numClauses) {
  int ind = 0;
  for (int i = 0; i < numClauses; i++) {
    for (int j = 0; j < 3; j++)
      printf("%d ", equ[ind++]);
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printEquation>:
  endbr64
  test   %esi,%esi
  jle    L22
  push   %r14
  lea    (%rsi,%rsi,2),%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L8:
  xor    %ebx,%ebx
L5:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x3,%rbx
  jne    L5
  mov    $0xa,%edi
  add    $0x3,%r13d
  add    $0xc,%rbp
  call   <putchar@plt>
  cmp    %r14d,%r13d
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d 

assistant: ```c
void printEquation(int *equ, int numClauses) {
  int ind = 0;
  for (int i = 0; i < numClauses; i++) {
    for (int j = 0; j < 3; j++)
      printf("%d ", equ[ind++]);
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printEquation>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r14
  lea    (%rsi,%rsi,2),%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L14:
  xor    %ebx,%ebx
L16:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x3,%rbx
  jne    L16
  mov    $0xa,%edi
  add    $0x3,%r13d
  add    $0xc,%rbp
  call   <putchar@plt>
  cmp    %r14d,%r13d
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: %d 

assistant: ```c
void printEquation(int *equ, int numClauses) {
  int ind = 0;
  for (int i = 0; i < numClauses; i++) {
    for (int j = 0; j < 3; j++)
      printf("%d ", equ[ind++]);
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *mp;
  nmemb = nmemb * size;
  if (mp = malloc(nmemb))
    memset(mp, 0, nmemb);
  return (mp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *mp;
  nmemb = nmemb * size;
  if (mp = malloc(nmemb))
    memset(mp, 0, nmemb);
  return (mp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *mp;
  nmemb = nmemb * size;
  if (mp = malloc(nmemb))
    memset(mp, 0, nmemb);
  return (mp);
}
```
user: What is the c source code of the assembly code below?

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *mp;
  nmemb = nmemb * size;
  if (mp = malloc(nmemb))
    memset(mp, 0, nmemb);
  return (mp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<list_splice_tail_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <list_empty@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__list_splice_tail@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <INIT_LIST_HEAD@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void list_splice_tail_init(struct list_head *list, struct list_head *head) {
  if (!list_empty(list)) {
    __list_splice_tail(list, head);
    INIT_LIST_HEAD(list);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<list_splice_tail_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L12
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__list_splice_tail@plt>
  mov    %rbx,%rdi
  call   <INIT_LIST_HEAD@plt>
  jmp    L6
```

assistant: ```c
void list_splice_tail_init(struct list_head *list, struct list_head *head) {
  if (!list_empty(list)) {
    __list_splice_tail(list, head);
    INIT_LIST_HEAD(list);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<list_splice_tail_init>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <__list_splice_tail@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <INIT_LIST_HEAD@plt>
```

assistant: ```c
void list_splice_tail_init(struct list_head *list, struct list_head *head) {
  if (!list_empty(list)) {
    __list_splice_tail(list, head);
    INIT_LIST_HEAD(list);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<list_splice_tail_init>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L2
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <__list_splice_tail@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <INIT_LIST_HEAD@plt>
```

assistant: ```c
void list_splice_tail_init(struct list_head *list, struct list_head *head) {
  if (!list_empty(list)) {
    __list_splice_tail(list, head);
    INIT_LIST_HEAD(list);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readBit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <readByte@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x10(%rbp),%eax
  and    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int8_t readBit(uint8_t devAddr, uint8_t regAddr, uint8_t bitNum, uint8_t *data) {
  uint8_t b;
  uint8_t count = readByte(devAddr, regAddr, &b);
  *data = b & (1 << bitNum);
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<readBit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,%ebp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <readByte@plt>
  mov    $0x1,%edx
  mov    %ebp,%ecx
  shl    %cl,%edx
  and    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int8_t readBit(uint8_t devAddr, uint8_t regAddr, uint8_t bitNum, uint8_t *data) {
  uint8_t b;
  uint8_t count = readByte(devAddr, regAddr, &b);
  *data = b & (1 << bitNum);
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readBit>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <readByte@plt>
  mov    $0x1,%edx
  mov    %ebp,%ecx
  shl    %cl,%edx
  and    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int8_t readBit(uint8_t devAddr, uint8_t regAddr, uint8_t bitNum, uint8_t *data) {
  uint8_t b;
  uint8_t count = readByte(devAddr, regAddr, &b);
  *data = b & (1 << bitNum);
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readBit>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <readByte@plt>
  mov    $0x1,%edx
  mov    %ebp,%ecx
  shl    %cl,%edx
  and    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int8_t readBit(uint8_t devAddr, uint8_t regAddr, uint8_t bitNum, uint8_t *data) {
  uint8_t b;
  uint8_t count = readByte(devAddr, regAddr, &b);
  *data = b & (1 << bitNum);
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setVectorToOne>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L4:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L4
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void setVectorToOne(double *vector, unsigned size) {
  unsigned i;
  for (i = 0; i < size; i++) {
    vector[i] = 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setVectorToOne>:
  endbr64
  test   %esi,%esi
  je     L17
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  movsd  D0(%rip),%xmm0
L19:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L19
L17:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void setVectorToOne(double *vector, unsigned size) {
  unsigned i;
  for (i = 0; i < size; i++) {
    vector[i] = 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setVectorToOne>:
  endbr64
  test   %esi,%esi
  je     L17
  lea    -0x1(%rsi),%eax
  movsd  D2(%rip),%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax,%rax,1)
L11:
  movsd  %xmm0,(%rdi)
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L11
L17:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void setVectorToOne(double *vector, unsigned size) {
  unsigned i;
  for (i = 0; i < size; i++) {
    vector[i] = 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<setVectorToOne>:
  endbr64
  test   %esi,%esi
  je     L13
  cmp    $0x1,%esi
  je     L15
  mov    %esi,%edx
  movapd D12(%rip),%xmm0
  mov    %rdi,%rax
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L35:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L35
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L36
L47:
  mov    D12(%rip),%rcx
  mov    %rcx,(%rdi,%rax,8)
L13:
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  ret
L15:
  xor    %eax,%eax
  jmp    L47
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void setVectorToOne(double *vector, unsigned size) {
  unsigned i;
  for (i = 0; i < size; i++) {
    vector[i] = 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yac_remove_duplicates_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L57
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L10
L30:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L44
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L1
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L1
L44:
  nop
L1:
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L30
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L52
L57:
  nop
L52:
  pop    %rbp
  ret
```

assistant: ```c
void yac_remove_duplicates_int(int *array, unsigned *n) {
  unsigned const N = *n;
  unsigned pos = 0;
  if (N == 0)
    return;
  int prev = array[0];
  for (unsigned i = 1; i < N; ++i) {
    if (array[i] == prev)
      continue;
    prev = array[i];
    ++pos;
    if (pos != i)
      array[pos] = array[i];
  }
  *n = pos + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<yac_remove_duplicates_int>:
  endbr64
  mov    (%rsi),%r9d
  test   %r9d,%r9d
  je     L53
  mov    (%rdi),%r8d
  cmp    $0x1,%r9d
  jbe    L42
  mov    %r9d,%r9d
  mov    $0x1,%eax
  mov    $0x0,%ecx
  jmp    L7
L24:
  add    $0x1,%rax
  cmp    %r9,%rax
  je     L32
L7:
  mov    (%rdi,%rax,4),%edx
  cmp    %r8d,%edx
  je     L24
  add    $0x1,%ecx
  mov    %edx,%r8d
  cmp    %eax,%ecx
  je     L24
  mov    %ecx,%r8d
  mov    %edx,(%rdi,%r8,4)
  mov    %edx,%r8d
  jmp    L24
L42:
  mov    $0x0,%ecx
L32:
  add    $0x1,%ecx
  mov    %ecx,(%rsi)
L53:
  ret
```

assistant: ```c
void yac_remove_duplicates_int(int *array, unsigned *n) {
  unsigned const N = *n;
  unsigned pos = 0;
  if (N == 0)
    return;
  int prev = array[0];
  for (unsigned i = 1; i < N; ++i) {
    if (array[i] == prev)
      continue;
    prev = array[i];
    ++pos;
    if (pos != i)
      array[pos] = array[i];
  }
  *n = pos + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<yac_remove_duplicates_int>:
  endbr64
  mov    (%rsi),%edx
  test   %edx,%edx
  je     L42
  mov    (%rdi),%r8d
  cmp    $0x1,%edx
  je     L17
  mov    %edx,%r9d
  mov    $0x1,%eax
  mov    $0x1,%edx
  jmp    L24
  nopl   0x0(%rax)
L2:
  mov    %edx,%r8d
  add    $0x1,%edx
  mov    %ecx,(%rdi,%r8,4)
  mov    %ecx,%r8d
L60:
  add    $0x1,%rax
  cmp    %r9,%rax
  je     L17
L24:
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  je     L60
  cmp    %eax,%edx
  jne    L2
  add    $0x1,%rax
  mov    %ecx,%r8d
  add    $0x1,%edx
  cmp    %r9,%rax
  jne    L24
L17:
  mov    %edx,(%rsi)
L42:
  ret
```

assistant: ```c
void yac_remove_duplicates_int(int *array, unsigned *n) {
  unsigned const N = *n;
  unsigned pos = 0;
  if (N == 0)
    return;
  int prev = array[0];
  for (unsigned i = 1; i < N; ++i) {
    if (array[i] == prev)
      continue;
    prev = array[i];
    ++pos;
    if (pos != i)
      array[pos] = array[i];
  }
  *n = pos + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<yac_remove_duplicates_int>:
  endbr64
  mov    (%rsi),%edx
  test   %edx,%edx
  je     L7
  mov    (%rdi),%r8d
  cmp    $0x1,%edx
  je     L53
  mov    %edx,%r9d
  mov    $0x1,%eax
  mov    $0x1,%edx
  jmp    L36
  nopl   0x0(%rax)
L58:
  mov    %edx,%r8d
  add    $0x1,%edx
  mov    %ecx,(%rdi,%r8,4)
  mov    %ecx,%r8d
L35:
  add    $0x1,%rax
  cmp    %rax,%r9
  je     L53
L36:
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  je     L35
  cmp    %eax,%edx
  jne    L58
  add    $0x1,%rax
  mov    %ecx,%r8d
  add    $0x1,%edx
  cmp    %rax,%r9
  jne    L36
L53:
  mov    %edx,(%rsi)
L7:
  ret
```

assistant: ```c
void yac_remove_duplicates_int(int *array, unsigned *n) {
  unsigned const N = *n;
  unsigned pos = 0;
  if (N == 0)
    return;
  int prev = array[0];
  for (unsigned i = 1; i < N; ++i) {
    if (array[i] == prev)
      continue;
    prev = array[i];
    ++pos;
    if (pos != i)
      array[pos] = array[i];
  }
  *n = pos + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string

tool: D7: This is a simple Makefile based "mpro" target.


assistant: ```c
int main(void) {
  printf("This is a simple Makefile based \"mpro\" target.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string

tool: D8: This is a simple Makefile based "mpro" target.


assistant: ```c
int main(void) {
  printf("This is a simple Makefile based \"mpro\" target.\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: This is a simple Makefile based "mpro" target.


assistant: ```c
int main(void) {
  printf("This is a simple Makefile based \"mpro\" target.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: This is a simple Makefile based "mpro" target.


assistant: ```c
int main(void) {
  printf("This is a simple Makefile based \"mpro\" target.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prep_pass1@plt>
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prep_pass2@plt>
  mov    -0x10(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <prep_pass3@plt>
  mov    -0x10(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lex@plt>
  mov    -0x10(%rbp),%rax
  add    $0x30,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <clear_newlines@plt>
  mov    -0x10(%rbp),%rax
  add    $0x38,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x30,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <determine_length@plt>
  mov    -0x10(%rbp),%rax
  add    $0x38,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x40,%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  add    $0x30,%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <gen@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  prep_pass1(argv[1], argv[2]);
  prep_pass2(argv[2], argv[3]);
  prep_pass3(argv[3], argv[4]);
  lex(argv[4], argv[5]);
  clear_newlines(argv[5], argv[6]);
  determine_length(argv[6], argv[7]);
  gen(argv[6], argv[8], argv[7]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    0x10(%rsi),%rsi
  mov    0x8(%rbx),%rdi
  call   <prep_pass1@plt>
  mov    0x18(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <prep_pass2@plt>
  mov    0x20(%rbx),%rsi
  mov    0x18(%rbx),%rdi
  call   <prep_pass3@plt>
  mov    0x28(%rbx),%rsi
  mov    0x20(%rbx),%rdi
  call   <lex@plt>
  mov    0x30(%rbx),%rsi
  mov    0x28(%rbx),%rdi
  call   <clear_newlines@plt>
  mov    0x38(%rbx),%rsi
  mov    0x30(%rbx),%rdi
  call   <determine_length@plt>
  mov    0x38(%rbx),%rdx
  mov    0x40(%rbx),%rsi
  mov    0x30(%rbx),%rdi
  call   <gen@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  prep_pass1(argv[1], argv[2]);
  prep_pass2(argv[2], argv[3]);
  prep_pass3(argv[3], argv[4]);
  lex(argv[4], argv[5]);
  clear_newlines(argv[5], argv[6]);
  determine_length(argv[6], argv[7]);
  gen(argv[6], argv[8], argv[7]);
  return 0;
}
```