ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_to_location>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  movzbl (%rsi),%edi
  push   %rbp
  push   %rbx
  test   %dil,%dil
  je     L22
  movsbl %dil,%ebp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L5
L22:
  xor    %eax,%eax
L79:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x61,%eax
  mov    %eax,(%r14)
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    $0x68,%al
  mov    (%r14),%eax
  jg     L45
L60:
  cmp    %eax,%r12d
  jle    L22
  test   %eax,%eax
  js     L22
  movsbl 0x1(%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L22
  lea    0x1(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  sub    %r8d,%eax
  mov    %eax,%edx
  mov    %eax,0x0(%r13)
  shr    $0x1f,%edx
  cmp    %r12d,%eax
  setge  %al
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  jmp    L79
  nop
L45:
  sub    $0x1,%eax
  mov    %eax,(%r14)
  jmp    L60
```

assistant: ```c
int string_to_location(int boardsize, char *str, int *m, int *n) {
  if (*str == '\0')
    return 0;
  if (!isalpha((int)*str))
    return 0;
  *n = tolower((int)*str) - 'a';
  if (tolower((int)*str) >= 'i')
    --*n;
  if (*n < 0 || *n > boardsize - 1)
    return 0;
  if (!isdigit((int)*(str + 1)))
    return 0;
  *m = boardsize - atoi(str + 1);
  if (*m < 0 || *m > boardsize - 1)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_to_location>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  movzbl (%rsi),%edi
  push   %rbp
  push   %rbx
  test   %dil,%dil
  je     L53
  movsbl %dil,%ebp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L38
L53:
  xor    %eax,%eax
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %ebp,%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x61,%eax
  mov    %eax,(%r14)
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    $0x68,%al
  mov    (%r14),%eax
  jg     L39
L10:
  cmp    %eax,%r12d
  jle    L53
  test   %eax,%eax
  js     L53
  movsbl 0x1(%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L53
  lea    0x1(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  sub    %r8d,%eax
  mov    %eax,%edx
  mov    %eax,0x0(%r13)
  shr    $0x1f,%edx
  cmp    %r12d,%eax
  setge  %al
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  jmp    L37
  nop
L39:
  sub    $0x1,%eax
  mov    %eax,(%r14)
  jmp    L10
```

assistant: ```c
int string_to_location(int boardsize, char *str, int *m, int *n) {
  if (*str == '\0')
    return 0;
  if (!isalpha((int)*str))
    return 0;
  *n = tolower((int)*str) - 'a';
  if (tolower((int)*str) >= 'i')
    --*n;
  if (*n < 0 || *n > boardsize - 1)
    return 0;
  if (!isdigit((int)*(str + 1)))
    return 0;
  *m = boardsize - atoi(str + 1);
  if (*m < 0 || *m > boardsize - 1)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<waiting_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L33:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L17
  mov    -0x4(%rbp),%eax
  jmp    L19
L17:
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L8:
  cmpl   $0x0,-0x18(%rbp)
  jne    L33
  mov    -0x8(%rbp),%eax
L19:
  leave
  ret
```

assistant: ```c
int waiting_read(int fd, char *buf, int count) {
  int rd, done = 0;
  while (count) {
    rd = read(fd, buf, count);
    if (rd < 1)
      return rd;
    buf += rd;
    count -= rd;
    done += rd;
  }
  return done;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<waiting_read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  test   %edx,%edx
  je     L15
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    $0x0,%r12d
L26:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L14
  movslq %eax,%rdx
  add    %rdx,%rbp
  add    %eax,%r12d
  sub    %eax,%ebx
  jne    L26
  mov    %r12d,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %edx,%eax
  jmp    L14
```

assistant: ```c
int waiting_read(int fd, char *buf, int count) {
  int rd, done = 0;
  while (count) {
    rd = read(fd, buf, count);
    if (rd < 1)
      return rd;
    buf += rd;
    count -= rd;
    done += rd;
  }
  return done;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<waiting_read>:
  endbr64
  test   %edx,%edx
  je     L24
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L20
  nop
L12:
  movslq %eax,%rdx
  add    %eax,%r13d
  add    %rdx,%rbp
  sub    %eax,%ebx
  je     L19
L20:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int waiting_read(int fd, char *buf, int count) {
  int rd, done = 0;
  while (count) {
    rd = read(fd, buf, count);
    if (rd < 1)
      return rd;
    buf += rd;
    count -= rd;
    done += rd;
  }
  return done;
}
```
user: What is the c source code of the assembly code below:

```asm
<waiting_read>:
  endbr64
  test   %edx,%edx
  je     L11
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L16
  nop
L2:
  movslq %eax,%rdx
  add    %eax,%r13d
  add    %rdx,%rbp
  sub    %eax,%ebx
  je     L33
L16:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int waiting_read(int fd, char *buf, int count) {
  int rd, done = 0;
  while (count) {
    rd = read(fd, buf, count);
    if (rd < 1)
      return rd;
    buf += rd;
    count -= rd;
    done += rd;
  }
  return done;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L45:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  jmp    L18
L32:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L43
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
L43:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *_strncat(char *dest, char *src, int n) {
  int index = 0, length = 0;
  while (dest[length])
    length++;
  while (index < n && src[index]) {
    dest[length++] = src[index++];
  }
  return (dest);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_strncat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L39
  mov    $0x1,%ecx
L28:
  mov    %ecx,%r9d
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rax,%rcx,1)
  jne    L28
L54:
  test   %edx,%edx
  jle    L24
  mov    %edx,%edx
  mov    $0x0,%ecx
  movslq %r9d,%r9
  add    %rax,%r9
L10:
  movzbl (%rsi,%rcx,1),%r8d
  test   %r8b,%r8b
  je     L24
  mov    %r8b,(%r9,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L10
L24:
  ret
L39:
  mov    $0x0,%r9d
  jmp    L54
```

assistant: ```c
char *_strncat(char *dest, char *src, int n) {
  int index = 0, length = 0;
  while (dest[length])
    length++;
  while (index < n && src[index]) {
    dest[length++] = src[index++];
  }
  return (dest);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L46
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L55:
  movslq %ecx,%r9
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rax,%rcx,1)
  jne    L55
L29:
  test   %edx,%edx
  jle    L12
  movslq %edx,%rdx
  xor    %ecx,%ecx
  add    %rax,%r9
  jmp    L50
  nopl   0x0(%rax)
L43:
  mov    %r8b,(%r9,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L12
L50:
  movzbl (%rsi,%rcx,1),%r8d
  test   %r8b,%r8b
  jne    L43
L12:
  ret
L46:
  xor    %r9d,%r9d
  jmp    L29
```

assistant: ```c
char *_strncat(char *dest, char *src, int n) {
  int index = 0, length = 0;
  while (dest[length])
    length++;
  while (index < n && src[index]) {
    dest[length++] = src[index++];
  }
  return (dest);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L63
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L4:
  movslq %ecx,%r9
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rax,%rcx,1)
  jne    L4
L53:
  test   %edx,%edx
  jle    L32
  movslq %edx,%rdx
  xor    %ecx,%ecx
  add    %rax,%r9
  jmp    L41
  nopl   0x0(%rax)
L50:
  mov    %r8b,(%r9,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L32
L41:
  movzbl (%rsi,%rcx,1),%r8d
  test   %r8b,%r8b
  jne    L50
L32:
  ret
L63:
  xor    %r9d,%r9d
  jmp    L53
```

assistant: ```c
char *_strncat(char *dest, char *src, int n) {
  int index = 0, length = 0;
  while (dest[length])
    length++;
  while (index < n && src[index]) {
    dest[length++] = src[index++];
  }
  return (dest);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L22:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L41:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L48
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L48
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L48:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L41
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L5:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L22
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string
name: read_data
arguments: data_label: D27
data_type: string
name: read_data
arguments: data_label: D24
data_type: string
name: read_data
arguments: data_label: D11
data_type: string

tool: D9: %d

tool: D27: *

tool: D24:  

tool: D11: 


assistant: ```c
int main() {
  int lines, counter, temp, counter2;
  scanf("%d", &lines);
  for (counter = 0; counter <= lines; counter++) {
    temp = lines - counter;
    for (counter2 = 0; counter2 < lines * 2; counter2++) {
      if (counter2 >= temp && lines * 2 - 1 - counter2 > temp) {
        printf("*");
      } else
        printf(" ");
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  js     L51
  mov    $0x0,%r13d
  lea    D5(%rip),%r12
  lea    D37(%rip),%r14
  lea    D1(%rip),%r15
  jmp    L32
L31:
  mov    %r12,%rdi
  call   <printf@plt>
L58:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jle    L76
L10:
  cmp    %ebx,%ebp
  jg     L31
  sub    $0x1,%eax
  sub    %ebx,%eax
  cmp    %ebp,%eax
  jle    L31
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L58
L76:
  mov    %r15,%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  mov    0x4(%rsp),%ebp
  cmp    %r13d,%ebp
  jl     L51
L32:
  sub    %r13d,%ebp
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  test   %eax,%eax
  jle    L76
  mov    $0x0,%ebx
  jmp    L10
L51:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D8: %d

tool: D5:  

tool: D37: *

tool: D1: 


assistant: ```c
int main() {
  int lines, counter, temp, counter2;
  scanf("%d", &lines);
  for (counter = 0; counter <= lines; counter++) {
    temp = lines - counter;
    for (counter2 = 0; counter2 < lines * 2; counter2++) {
      if (counter2 >= temp && lines * 2 - 1 - counter2 > temp) {
        printf("*");
      } else
        printf(" ");
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D14(%rip),%rdi
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D32(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  js     L8
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %edx,%ebx
  lea    (%rdx,%rdx,1),%eax
  xor    %r15d,%r15d
  sub    %r12d,%ebx
  test   %edx,%edx
  jne    L3
  jmp    L75
  nopl   0x0(%rax)
L89:
  mov    %rbp,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %r15d,%eax
  jle    L75
L3:
  cmp    %r15d,%ebx
  jg     L89
  sub    $0x1,%eax
  sub    %r15d,%eax
  cmp    %ebx,%eax
  jle    L89
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %r15d,%eax
  jg     L3
  nopl   (%rax)
L75:
  mov    %r14,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  cmp    %r12d,%edx
  jge    L27
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D32
data_type: string

tool: D14: %d

tool: D19: 


tool: D20: *

tool: D32:  

assistant: ```c
int main() {
  int lines, counter, temp, counter2;
  scanf("%d", &lines);
  for (counter = 0; counter <= lines; counter++) {
    temp = lines - counter;
    for (counter2 = 0; counter2 < lines * 2; counter2++) {
      if (counter2 >= temp && lines * 2 - 1 - counter2 > temp) {
        printf("*");
      } else
        printf(" ");
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D30(%rip),%rdi
  push   %r14
  lea    D36(%rip),%r14
  push   %r13
  lea    D38(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  js     L79
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %edx,%ebx
  lea    (%rdx,%rdx,1),%eax
  xor    %r15d,%r15d
  sub    %r12d,%ebx
  test   %edx,%edx
  jne    L74
  jmp    L57
  nopl   0x0(%rax)
L43:
  mov    %rbp,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %r15d,%eax
  jle    L57
L74:
  cmp    %r15d,%ebx
  jg     L43
  sub    $0x1,%eax
  sub    %r15d,%eax
  cmp    %ebx,%eax
  jle    L43
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %r15d,%eax
  jg     L74
  nopl   (%rax)
L57:
  mov    %r14,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  cmp    %r12d,%edx
  jge    L13
L79:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D30
datatype: string
name: parse_data
arguments: label: D36
datatype: string
name: parse_data
arguments: label: D38
datatype: string
name: parse_data
arguments: label: D8
datatype: string

tool: D30: %d

tool: D36: 


tool: D38: *

tool: D8:  

assistant: ```c
int main() {
  int lines, counter, temp, counter2;
  scanf("%d", &lines);
  for (counter = 0; counter <= lines; counter++) {
    temp = lines - counter;
    for (counter2 = 0; counter2 < lines * 2; counter2++) {
      if (counter2 >= temp && lines * 2 - 1 - counter2 > temp) {
        printf("*");
      } else
        printf(" ");
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<q_mul>:
  endbr64
  movss  (%rsi),%xmm0
  mulss  (%rdx),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  (%rsi),%xmm0
  mulss  0x4(%rdx),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  (%rsi),%xmm0
  mulss  0x8(%rdx),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  (%rsi),%xmm0
  mulss  0xc(%rdx),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void q_mul(float q[4], const float a[4], const float b[4]) {
  q[0] = a[0] * b[0] - a[1] * b[1] - a[2] * b[2] - a[3] * b[3];
  q[1] = a[0] * b[1] + a[1] * b[0] + a[2] * b[3] - a[3] * b[2];
  q[2] = a[0] * b[2] - a[1] * b[3] + a[2] * b[0] + a[3] * b[1];
  q[3] = a[0] * b[3] + a[1] * b[2] - a[2] * b[1] + a[3] * b[0];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<q_mul>:
  endbr64
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  (%rdx),%xmm0
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm0
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm0
  mulss  0xc(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm0
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void q_mul(float q[4], const float a[4], const float b[4]) {
  q[0] = a[0] * b[0] - a[1] * b[1] - a[2] * b[2] - a[3] * b[3];
  q[1] = a[0] * b[1] + a[1] * b[0] + a[2] * b[3] - a[3] * b[2];
  q[2] = a[0] * b[2] - a[1] * b[3] + a[2] * b[0] + a[3] * b[1];
  q[3] = a[0] * b[3] + a[1] * b[2] - a[2] * b[1] + a[3] * b[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<q_mul>:
  endbr64
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  (%rdx),%xmm0
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm0
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm0
  mulss  0xc(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm0
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  subss  %xmm1,%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void q_mul(float q[4], const float a[4], const float b[4]) {
  q[0] = a[0] * b[0] - a[1] * b[1] - a[2] * b[2] - a[3] * b[3];
  q[1] = a[0] * b[1] + a[1] * b[0] + a[2] * b[3] - a[3] * b[2];
  q[2] = a[0] * b[2] - a[1] * b[3] + a[2] * b[0] + a[3] * b[1];
  q[3] = a[0] * b[3] + a[1] * b[2] - a[2] * b[1] + a[3] * b[0];
}
```