user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rax
  movl   $0x0,-0x44(%rbp)
  mov    %rax,-0x50(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  nopw   0x0(%rax,%rax,1)
L14:
  mov    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L64
  mov    -0x40(%rbp),%r9d
  mov    -0x3c(%rbp),%r15d
  mov    %rsp,%rsi
  mov    %rsp,%r12
  lea    (%r9,%r15,1),%edx
  lea    -0x1(%rdx),%ebx
  movslq %ebx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L119
L148:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L148
L119:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  je     L76
  orq    $0x0,-0x8(%rsp,%rcx,1)
L76:
  mov    %rsp,%r14
  test   %ebx,%ebx
  jle    L138
  lea    -0x2(%rdx),%eax
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    %r9d,-0x48(%rbp)
  lea    0x4(,%rax,4),%rdx
  call   <memset@plt>
  mov    -0x48(%rbp),%r9d
  test   %r9d,%r9d
  jle    L20
L41:
  lea    -0x1(%r15),%edi
  mov    $0x1,%esi
  lea    0x8(%r14,%rdi,4),%rdx
  not    %rdi
  shl    $0x2,%rdi
  nopl   (%rax)
L147:
  lea    (%rdi,%rdx,1),%rax
  test   %r15d,%r15d
  jle    L139
  nopl   0x0(%rax)
L120:
  addl   $0x1,-0x4(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L120
L139:
  add    $0x1,%esi
  add    $0x4,%rdx
  cmp    %esi,%r9d
  jge    L147
  test   %ebx,%ebx
  jle    L62
L20:
  xor    %eax,%eax
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L74:
  mov    (%r14,%rax,4),%esi
  cmp    %esi,%r15d
  cmovl  %esi,%r15d
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L74
  mov    -0x44(%rbp),%edx
  test   %edx,%edx
  jne    L59
L25:
  xor    %ebx,%ebx
  jmp    L5
  xchg   %ax,%ax
L99:
  mov    -0x3c(%rbp),%eax
  add    -0x40(%rbp),%eax
  add    $0x1,%rbx
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L186
L5:
  cmp    %r15d,(%r14,%rbx,4)
  jne    L99
  lea    0x2(%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L99
L138:
  test   %r9d,%r9d
  jg     L41
L62:
  mov    -0x44(%rbp),%eax
  test   %eax,%eax
  je     L186
  xor    %r15d,%r15d
L59:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x40(%rbp),%eax
  add    -0x3c(%rbp),%eax
  cmp    $0x1,%eax
  jg     L25
  xchg   %ax,%ax
L186:
  addl   $0x1,-0x44(%rbp)
  mov    %r12,%rsp
  jmp    L14
L64:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L135
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L135:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type: string
name: read_data
arguments: data_label: D9
type: string

tool: D7: %d


tool: D9: %d %d

assistant: ```c
int main() {
  int d1, d2, mx, i, j, t = 0;
  while (scanf("%d %d", &d1, &d2) == 2) {
    mx = 0;
    int temp[d1 + d2 - 1];
    for (i = 0; i < d1 + d2 - 1; i++)
      temp[i] = 0;
    for (j = 1; j <= d1; j++)
      for (i = 1; i <= d2; i++) {
        temp[j + i - 2] += 1;
      }
    for (i = 0; i < d1 + d2 - 1; i++)
      if (mx < temp[i])
        mx = temp[i];
    if (t != 0)
      printf("\n");
    for (i = 0; i < d1 + d2 - 1; i++)
      if (mx == temp[i])
        printf("%d\n", i + 2);
    t++;
  }
  return 0;
}
```