ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  call   <check@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <check@plt>
```

assistant: ```c
void main() {
  check(((char)-1) == ~((char)0));
  check(((char)-6) == ~((char)5));
  check(((char)-100) == ~((char)99));
  check(((char)-128) == ~((char)127));
  check(((unsigned char)255) != ~((unsigned char)0));
  check(((int)-1) == ~((unsigned char)0));
  check(((unsigned char)250) != ~((unsigned char)5));
  check(((int)-6) == ~((unsigned char)5));
  check(((unsigned char)156) != ~((unsigned char)99));
  check(((int)-100) == ~((unsigned char)99));
  check(((unsigned char)128) != ~((unsigned char)127));
  check(((int)-128) == ~((unsigned char)127));
  check(((short)-1) == ~((short)0));
  check(((short)-6) == ~((short)5));
  check(((short)-32768) == ~((short)32767));
  check(((unsigned short)65535) != ~((unsigned short)0));
  check(((int)-1) == ~((unsigned short)0));
  check(((unsigned short)65530) != ~((unsigned short)5));
  check(((int)-6) == ~((unsigned short)5));
  check(((unsigned short)32768) != ~((unsigned short)32767));
  check(((int)-32768) == ~((unsigned short)32767));
  check(((long long)-1) == ~((long long)0));
  check(((long long)-6) == ~((long long)5));
  check(((long long)-9223372036854775801LL) == ~((long long)9223372036854775800LL));
  check(((long long)-9223372036854775808ULL) == ~((long long)9223372036854775807LL));
  check(((unsigned long long)18446744073709551615ULL) == ~((unsigned long long)0));
  check(((unsigned long long)18446744073709551610ULL) == ~((unsigned long long)5));
  check(((unsigned long long)9223372036854775808ULL) == ~((unsigned long long)9223372036854775807ULL));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ReverseArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x4(%rbp)
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ReverseArray(char arr[5], int size) {
  int i;
  char temp;
  for (i = 0; i < size / 2; i++) {
    temp = arr[i];
    arr[i] = arr[size - 1 - i];
    arr[size - 1 - i] = temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ReverseArray>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L11
  movslq %esi,%rsi
  lea    -0x1(%rdi,%rsi,1),%rdx
  mov    $0x0,%eax
L13:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rdx),%esi
  mov    %sil,(%rdi,%rax,1)
  mov    %cl,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%r8d
  jg     L13
L11:
  ret
```

assistant: ```c
void ReverseArray(char arr[5], int size) {
  int i;
  char temp;
  for (i = 0; i < size / 2; i++) {
    temp = arr[i];
    arr[i] = arr[size - 1 - i];
    arr[size - 1 - i] = temp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ReverseArray>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  cltq
  add    %rdi,%rax
L0:
  movzbl (%rax),%esi
  movzbl (%rdi,%rdx,1),%ecx
  sub    $0x1,%rax
  mov    %sil,(%rdi,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,0x1(%rax)
  cmp    %edx,%r8d
  jg     L0
L6:
  ret
```

assistant: ```c
void ReverseArray(char arr[5], int size) {
  int i;
  char temp;
  for (i = 0; i < size / 2; i++) {
    temp = arr[i];
    arr[i] = arr[size - 1 - i];
    arr[size - 1 - i] = temp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ReverseArray>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  cltq
  add    %rdi,%rax
L18:
  movzbl (%rax),%esi
  movzbl (%rdi,%rdx,1),%ecx
  sub    $0x1,%rax
  mov    %sil,(%rdi,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,0x1(%rax)
  cmp    %edx,%r8d
  jg     L18
L19:
  ret
```

assistant: ```c
void ReverseArray(char arr[5], int size) {
  int i;
  char temp;
  for (i = 0; i < size / 2; i++) {
    temp = arr[i];
    arr[i] = arr[size - 1 - i];
    arr[size - 1 - i] = temp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rsi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rsi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rsi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <minimoDiTreNumeri@plt>
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D47
type: string
name: disassemble_data
arguments: data_label: D74
type: string
name: disassemble_data
arguments: data_label: D44
type: string
name: disassemble_data
arguments: data_label: D57
type: string
name: disassemble_data
arguments: data_label: D58
type: string
name: disassemble_data
arguments: data_label: D77
type: string

tool: D47: inserisci il primo numero: 

tool: D74: %s

tool: D44: %f

tool: D57: inserisci il secondo numero: 

tool: D58: inserisci il terzo numero: 

tool: D77: Il numero piu grande dei tre e': %f

assistant: ```c
int main(void) {
  float minimoDiTreNumeri(float numero1, float numero2, float numero3);
  float minimoDiDueNumeri(float numero1, float numero2);
  float numero1;
  float numero2;
  float numero3;
  printf("%s", "inserisci il primo numero: ");
  scanf("%f", &numero1);
  printf("%s", "inserisci il secondo numero: ");
  scanf("%f", &numero2);
  printf("%s", "inserisci il terzo numero: ");
  scanf("%f", &numero3);
  printf("Il numero piu grande dei tre e': %f", minimoDiTreNumeri(numero1, numero2, numero3));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rsi
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D34(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D36(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <minimoDiTreNumeri@plt>
  cvtss2sd %xmm0,%xmm0
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D25
type_guessed: string
name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D34
type_guessed: string
name: disassemble_data
arguments: data_label: D19
type_guessed: string
name: disassemble_data
arguments: data_label: D36
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string

tool: D25: inserisci il primo numero: 

tool: D5: %s

tool: D34: %f

tool: D19: inserisci il secondo numero: 

tool: D36: inserisci il terzo numero: 

tool: D11: Il numero piu grande dei tre e': %f

assistant: ```c
int main(void) {
  float minimoDiTreNumeri(float numero1, float numero2, float numero3);
  float minimoDiDueNumeri(float numero1, float numero2);
  float numero1;
  float numero2;
  float numero3;
  printf("%s", "inserisci il primo numero: ");
  scanf("%f", &numero1);
  printf("%s", "inserisci il secondo numero: ");
  scanf("%f", &numero2);
  printf("%s", "inserisci il terzo numero: ");
  scanf("%f", &numero3);
  printf("Il numero piu grande dei tre e': %f", minimoDiTreNumeri(numero1, numero2, numero3));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%r12
  lea    D47(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  lea    D50(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D22(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <minimoDiTreNumeri@plt>
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D47
type_infered: string
name: parse_data
arguments: label: D50
type_infered: string
name: parse_data
arguments: label: D22
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D21
type_infered: string

tool: D18: %s

tool: D47: inserisci il primo numero: 

tool: D50: %f

tool: D22: inserisci il secondo numero: 

tool: D8: inserisci il terzo numero: 

tool: D21: Il numero piu grande dei tre e': %f

assistant: ```c
int main(void) {
  float minimoDiTreNumeri(float numero1, float numero2, float numero3);
  float minimoDiDueNumeri(float numero1, float numero2);
  float numero1;
  float numero2;
  float numero3;
  printf("%s", "inserisci il primo numero: ");
  scanf("%f", &numero1);
  printf("%s", "inserisci il secondo numero: ");
  scanf("%f", &numero2);
  printf("%s", "inserisci il terzo numero: ");
  scanf("%f", &numero3);
  printf("Il numero piu grande dei tre e': %f", minimoDiTreNumeri(numero1, numero2, numero3));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D36(%rip),%r12
  lea    D53(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  lea    D1(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D47(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <minimoDiTreNumeri@plt>
  lea    D15(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D53
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D47
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string
name: unpack_data
arguments: label: D15
type_infered: string

tool: D36: %s

tool: D53: inserisci il primo numero: 

tool: D1: %f

tool: D47: inserisci il secondo numero: 

tool: D14: inserisci il terzo numero: 

tool: D15: Il numero piu grande dei tre e': %f

assistant: ```c
int main(void) {
  float minimoDiTreNumeri(float numero1, float numero2, float numero3);
  float minimoDiDueNumeri(float numero1, float numero2);
  float numero1;
  float numero2;
  float numero3;
  printf("%s", "inserisci il primo numero: ");
  scanf("%f", &numero1);
  printf("%s", "inserisci il secondo numero: ");
  scanf("%f", &numero2);
  printf("%s", "inserisci il terzo numero: ");
  scanf("%f", &numero3);
  printf("Il numero piu grande dei tre e': %f", minimoDiTreNumeri(numero1, numero2, numero3));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_branch_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L40:
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L31:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  test   %rax,%rax
  je     L3
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L3:
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L31
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L40
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_branch_1(int const *A, int const n, int const iters) {
  int i, j;
  int res;
  res = 0;
  for (i = 0; i < iters; ++i) {
    for (j = 0; j < n; ++j) {
      if (__builtin_expect(A[j], 1)) {
        res = j;
      }
    }
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_branch_1>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  mov    %esi,%r8d
  test   %edx,%edx
  jg     L6
L23:
  mov    %ecx,%eax
  ret
L39:
  cmpl   $0x0,(%rdi,%rax,4)
  cmovne %eax,%ecx
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L39
L43:
  add    $0x1,%r9d
  cmp    %r9d,%edx
  je     L23
L6:
  mov    $0x0,%eax
  test   %esi,%esi
  jg     L39
  jmp    L43
```

assistant: ```c
int test_branch_1(int const *A, int const n, int const iters) {
  int i, j;
  int res;
  res = 0;
  for (i = 0; i < iters; ++i) {
    for (j = 0; j < n; ++j) {
      if (__builtin_expect(A[j], 1)) {
        res = j;
      }
    }
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_branch_1>:
  endbr64
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  movslq %esi,%rcx
  test   %edx,%edx
  jle    L21
  nopl   0x0(%rax)
L31:
  xor    %eax,%eax
  test   %esi,%esi
  jle    L13
  xchg   %ax,%ax
L30:
  mov    (%rdi,%rax,4),%r10d
  test   %r10d,%r10d
  cmovne %eax,%r8d
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L30
L13:
  add    $0x1,%r9d
  cmp    %r9d,%edx
  jne    L31
L21:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int test_branch_1(int const *A, int const n, int const iters) {
  int i, j;
  int res;
  res = 0;
  for (i = 0; i < iters; ++i) {
    for (j = 0; j < n; ++j) {
      if (__builtin_expect(A[j], 1)) {
        res = j;
      }
    }
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_branch_1>:
  endbr64
  test   %edx,%edx
  jle    L66
  mov    %esi,%eax
  mov    %esi,%r11d
  movdqa D5(%rip),%xmm5
  push   %rbp
  shr    $0x2,%eax
  push   %rbx
  mov    %rdi,%r9
  mov    %edx,%ebx
  sub    $0x1,%eax
  mov    %esi,%ecx
  lea    -0x1(%rsi),%ebp
  and    $0xfffffffc,%r11d
  shl    $0x4,%rax
  pcmpeqd %xmm6,%xmm6
  pxor   %xmm4,%xmm4
  xor    %r8d,%r8d
  lea    0x10(%rdi,%rax,1),%rdx
  xor    %edi,%edi
  nopl   (%rax)
L92:
  test   %ecx,%ecx
  jle    L59
  cmp    $0x2,%ebp
  jbe    L32
  movdqa D3(%rip),%xmm2
  mov    %r9,%rax
  movdqa %xmm6,%xmm1
  nopl   0x0(%rax,%rax,1)
L27:
  movdqu (%rax),%xmm0
  movdqa %xmm2,%xmm3
  add    $0x10,%rax
  paddd  %xmm5,%xmm2
  pcmpeqd %xmm4,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm3,%xmm0
  por    %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L27
  movdqa %xmm1,%xmm2
  psrldq $0x8,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    $0xffffffff,%eax
  cmovne %eax,%r8d
  mov    %r11d,%eax
  cmp    %r11d,%ecx
  je     L59
L6:
  movslq %eax,%rsi
  lea    0x0(,%rsi,4),%r10
  mov    (%r9,%rsi,4),%esi
  test   %esi,%esi
  lea    0x1(%rax),%esi
  cmovne %eax,%r8d
  cmp    %ecx,%esi
  jge    L59
  cmpl   $0x0,0x4(%r9,%r10,1)
  cmove  %r8d,%esi
  lea    0x2(%rax),%r8d
  cmp    %ecx,%r8d
  jge    L35
  mov    0x8(%r9,%r10,1),%eax
  test   %eax,%eax
  cmove  %esi,%r8d
L59:
  add    $0x1,%edi
  cmp    %edi,%ebx
  jne    L92
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L32:
  xor    %eax,%eax
  jmp    L6
L35:
  mov    %esi,%r8d
  jmp    L59
L66:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: byte[16]
name: unpack_data
arguments: label: D3
datatype: byte[16]

tool: {"D5": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int test_branch_1(int const *A, int const n, int const iters) {
  int i, j;
  int res;
  res = 0;
  for (i = 0; i < iters; ++i) {
    for (j = 0; j < n; ++j) {
      if (__builtin_expect(A[j], 1)) {
        res = j;
      }
    }
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<primtoU>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <primtoflux@plt>
  nop
  leave
  ret
```

assistant: ```c
void primtoU(double *pr, struct of_state *q, struct of_geom *geom, double *U) {
  primtoflux(pr, q, 0, geom, U);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<primtoU>:
  endbr64
  sub    $0x8,%rsp
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x0,%edx
  call   <primtoflux@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void primtoU(double *pr, struct of_state *q, struct of_geom *geom, double *U) {
  primtoflux(pr, q, 0, geom, U);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<primtoU>:
  endbr64
  mov    %rcx,%r8
  mov    %rdx,%rcx
  xor    %edx,%edx
  jmp    1050 <primtoflux@plt>
```

assistant: ```c
void primtoU(double *pr, struct of_state *q, struct of_geom *geom, double *U) {
  primtoflux(pr, q, 0, geom, U);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<primtoU>:
  endbr64
  mov    %rcx,%r8
  mov    %rdx,%rcx
  xor    %edx,%edx
  jmp    1050 <primtoflux@plt>
```

assistant: ```c
void primtoU(double *pr, struct of_state *q, struct of_geom *geom, double *U) {
  primtoflux(pr, q, 0, geom, U);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D33(%rip),%xmm0
  movss  %xmm0,-0x40(%rbp)
  movss  D40(%rip),%xmm0
  movss  %xmm0,-0x3c(%rbp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  D64(%rip),%xmm0
  movss  %xmm0,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,-0x30(%rbp)
  movss  D39(%rip),%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movss  D21(%rip),%xmm0
  movss  %xmm0,-0x28(%rbp)
  movss  D0(%rip),%xmm0
  movss  %xmm0,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  D45(%rip),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  D16(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movl   $0x6,-0x4c(%rbp)
  movl   $0x2,-0x48(%rbp)
  mov    -0x48(%rbp),%edx
  lea    -0x40(%rbp),%rcx
  mov    -0x4c(%rbp),%eax
  mov    %rcx,%rsi
  mov    D33(%rip),%ecx
  movd   %ecx,%xmm0
  mov    %eax,%edi
  call   <stdlib_strided_snanvariancech@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  movd   %eax,%xmm0
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D33
type_guessed: f32
name: parse_data
arguments: tag: D40
type_guessed: f32
name: parse_data
arguments: tag: D64
type_guessed: f32
name: parse_data
arguments: tag: D39
type_guessed: f32
name: parse_data
arguments: tag: D21
type_guessed: f32
name: parse_data
arguments: tag: D0
type_guessed: f32
name: parse_data
arguments: tag: D45
type_guessed: f32
name: parse_data
arguments: tag: D16
type_guessed: f32
name: parse_data
arguments: tag: D77
type_guessed: string

tool: D33: 1

tool: D40: 2

tool: D64: 3

tool: D39: 4

tool: D21: 5

tool: D0: 6

tool: D45: 7

tool: D16: 8

tool: D77: sample variance: %f


assistant: ```c
int main() {
  float x[] = {1.0, 2.0, 0.0 / 0.0, 3.0, 0.0 / 0.0, 4.0, 5.0, 6.0, 0.0 / 0.0, 7.0, 8.0, 0.0 / 0.0};
  int64_t N = 6;
  int64_t stride = 2;
  float v = stdlib_strided_snanvariancech(N, 1.0f, x, stride);
  printf("sample variance: %f\n", v);
}
```