ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x190,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x190(%rax),%rbp
  xchg   %ax,%ax
L0:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <validptr@plt>
  movl   $0x0,-0x4(%rbx)
  cmp    %rbx,%rbp
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int *x;
  int *y;
  int i;
  y = (int *)malloc(100 * sizeof(int));
  x = y;
  i = 0;
  for (; i < 100; i++) {
    validptr(x);
    *x = 0;
    x++;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uc0_rdphalf_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <RDP_E@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <RDP@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
type_guessed: string

tool: D19: uc0:rdphalf_2 - IGNORED


assistant: ```c
void uc0_rdphalf_2() {
  RDP_E("uc0:rdphalf_2 - IGNORED\n");
  RDP("uc0:rdphalf_2 - IGNORED\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uc0_rdphalf_2>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <RDP_E@plt>
  mov    %rbx,%rdi
  call   <RDP@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8: uc0:rdphalf_2 - IGNORED


assistant: ```c
void uc0_rdphalf_2() {
  RDP_E("uc0:rdphalf_2 - IGNORED\n");
  RDP("uc0:rdphalf_2 - IGNORED\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uc0_rdphalf_2>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <RDP_E@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <RDP@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: uc0:rdphalf_2 - IGNORED


assistant: ```c
void uc0_rdphalf_2() {
  RDP_E("uc0:rdphalf_2 - IGNORED\n");
  RDP("uc0:rdphalf_2 - IGNORED\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uc0_rdphalf_2>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <RDP_E@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <RDP@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: uc0:rdphalf_2 - IGNORED


assistant: ```c
void uc0_rdphalf_2() {
  RDP_E("uc0:rdphalf_2 - IGNORED\n");
  RDP("uc0:rdphalf_2 - IGNORED\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strchr_local>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L14
  mov    -0x8(%rbp),%rax
  jmp    L7
L14:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr_local(char *s, int c) {
  do {
    if (*s == c)
      return s;
  } while (*s++ != '\0');
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strchr_local>:
  endbr64
  mov    %rdi,%rax
L3:
  movzbl (%rax),%edx
  movsbl %dl,%ecx
  cmp    %esi,%ecx
  je     L13
  add    $0x1,%rax
  test   %dl,%dl
  jne    L3
  mov    $0x0,%eax
L13:
  ret
```

assistant: ```c
char *strchr_local(char *s, int c) {
  do {
    if (*s == c)
      return s;
  } while (*s++ != '\0');
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strchr_local>:
  endbr64
  mov    %rdi,%rax
  jmp    L8
  nopl   0x0(%rax)
L26:
  add    $0x1,%rax
  test   %cl,%cl
  je     L28
L8:
  movsbl (%rax),%ecx
  cmp    %esi,%ecx
  jne    L26
  ret
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strchr_local(char *s, int c) {
  do {
    if (*s == c)
      return s;
  } while (*s++ != '\0');
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strchr_local>:
  endbr64
  mov    %rdi,%rax
  jmp    L24
  nopl   0x0(%rax)
L13:
  add    $0x1,%rax
  test   %cl,%cl
  je     L12
L24:
  movsbl (%rax),%ecx
  cmp    %esi,%ecx
  jne    L13
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strchr_local(char *s, int c) {
  do {
    if (*s == c)
      return s;
  } while (*s++ != '\0');
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  jmp    L12
L21:
  cmpl   $0x3,-0xc(%rbp)
  je     L28
  movl   $0x1,-0x8(%rbp)
  jmp    L16
L37:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x6,-0x8(%rbp)
  jle    L37
L28:
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x9,-0xc(%rbp)
  jle    L21
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D3
type: string

tool: D19: oi

tool: D3: 
O trecho do pseudocodigo se repetiu %d vezes

assistant: ```c
int main() {
  int i, j, repeticoes;
  for (i = 1; i <= 9; i++) {
    if (i != 3) {
      for (j = 1; j <= 6; j++) {
        printf("oi");
        repeticoes = repeticoes++;
      }
    }
  }
  printf("\nO trecho do pseudocodigo se repetiu %d vezes", repeticoes);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2,%r12d
  lea    D7(%rip),%rbp
  jmp    L19
L11:
  add    $0x1,%r12d
L19:
  cmp    $0x4,%r12d
  je     L11
  mov    $0x6,%ebx
L0:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L0
  cmp    $0x9,%r12d
  jle    L11
  mov    $0x0,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D15
type: string

tool: D7: oi

tool: D15: 
O trecho do pseudocodigo se repetiu %d vezes

assistant: ```c
int main() {
  int i, j, repeticoes;
  for (i = 1; i <= 9; i++) {
    if (i != 3) {
      for (j = 1; j <= 6; j++) {
        printf("oi");
        repeticoes = repeticoes++;
      }
    }
  }
  printf("\nO trecho do pseudocodigo se repetiu %d vezes", repeticoes);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  nopl   0x0(%rax)
L25:
  add    $0x1,%ebp
  mov    $0x6,%ebx
  cmp    $0x4,%ebp
  je     L25
  nopl   (%rax)
L1:
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  cmp    $0xa,%ebp
  jne    L25
  xor    %esi,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string

tool: D3: oi

tool: D1: 
O trecho do pseudocodigo se repetiu %d vezes

assistant: ```c
int main() {
  int i, j, repeticoes;
  for (i = 1; i <= 9; i++) {
    if (i != 3) {
      for (j = 1; j <= 6; j++) {
        printf("oi");
        repeticoes = repeticoes++;
      }
    }
  }
  printf("\nO trecho do pseudocodigo se repetiu %d vezes", repeticoes);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  nopl   0x0(%rax)
L28:
  add    $0x1,%ebp
  mov    $0x6,%ebx
  cmp    $0x4,%ebp
  je     L28
  nopl   (%rax)
L22:
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L22
  cmp    $0xa,%ebp
  jne    L28
  xor    %esi,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D16
datatype: string

tool: D19: oi

tool: D16: 
O trecho do pseudocodigo se repetiu %d vezes

assistant: ```c
int main() {
  int i, j, repeticoes;
  for (i = 1; i <= 9; i++) {
    if (i != 3) {
      for (j = 1; j <= 6; j++) {
        printf("oi");
        repeticoes = repeticoes++;
      }
    }
  }
  printf("\nO trecho do pseudocodigo se repetiu %d vezes", repeticoes);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slp_sockconnect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L3
  mov    $0xffffffff,%eax
  jmp    L11
L3:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int slp_sockconnect(int sock, struct sockaddr *inetaddr, int addrlen) {
  if ((connect(sock, inetaddr, addrlen)) == -1) {
    if (errno != EINPROGRESS)
      return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<slp_sockconnect>:
  endbr64
  sub    $0x8,%rsp
  call   <connect@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L7
L8:
  add    $0x8,%rsp
  ret
L7:
  mov    D8(%rip),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L8
```

assistant: ```c
int slp_sockconnect(int sock, struct sockaddr *inetaddr, int addrlen) {
  if ((connect(sock, inetaddr, addrlen)) == -1) {
    if (errno != EINPROGRESS)
      return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<slp_sockconnect>:
  endbr64
  sub    $0x8,%rsp
  call   <connect@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  jne    L7
  mov    D18(%rip),%rdx
  mov    D16(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
L7:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int slp_sockconnect(int sock, struct sockaddr *inetaddr, int addrlen) {
  if ((connect(sock, inetaddr, addrlen)) == -1) {
    if (errno != EINPROGRESS)
      return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<slp_sockconnect>:
  endbr64
  sub    $0x8,%rsp
  call   <connect@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  jne    L3
  mov    D4(%rip),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int slp_sockconnect(int sock, struct sockaddr *inetaddr, int addrlen) {
  if ((connect(sock, inetaddr, addrlen)) == -1) {
    if (errno != EINPROGRESS)
      return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <my_asm_func@plt>
  cmp    $0x2a,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <my_asm_func_2@plt>
  cmp    $0x2a,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  assert(my_asm_func() == 42);
  assert(my_asm_func_2() == 42);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <my_asm_func@plt>
  cmp    $0x2a,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <my_asm_func_2@plt>
  cmp    $0x2a,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(my_asm_func() == 42);
  assert(my_asm_func_2() == 42);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <my_asm_func@plt>
  xor    %edi,%edi
  cmp    $0x2a,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <my_asm_func_2@plt>
  xor    %edi,%edi
  cmp    $0x2a,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(my_asm_func() == 42);
  assert(my_asm_func_2() == 42);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <my_asm_func@plt>
  xor    %edi,%edi
  cmp    $0x2a,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <my_asm_func_2@plt>
  xor    %edi,%edi
  cmp    $0x2a,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(my_asm_func() == 42);
  assert(my_asm_func_2() == 42);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isglob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L90
  mov    $0x0,%eax
  jmp    L113
L64:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5c,%eax
  je     L49
  cmp    $0x5c,%eax
  jg     L115
  cmp    $0x5b,%eax
  je     L104
  cmp    $0x5b,%eax
  jg     L115
  cmp    $0x2a,%eax
  je     L104
  cmp    $0x3f,%eax
  jne    L115
L104:
  mov    $0xffffffff,%eax
  jmp    L113
L49:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L109
  mov    $0x0,%eax
  jmp    L113
L109:
  addq   $0x2,-0x8(%rbp)
  jmp    L90
L115:
  addq   $0x1,-0x8(%rbp)
  nop
L90:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  mov    $0x0,%eax
L113:
  pop    %rbp
  ret
```

assistant: ```c
int isglob(const char *str) {
  if (!str)
    return (0);
  while (*str) {
    switch (*str) {
    case '*':
    case '?':
    case '[':
      return (-1);
    case '\\':
      if (str[1] == '\0')
        return (0);
      str += 2;
      break;
    default:
      str += 1;
      break;
    }
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isglob>:
  endbr64
  test   %rdi,%rdi
  je     L10
  movzbl (%rdi),%eax
  test   %al,%al
  je     L85
  movabs $0x2000000200001,%rdx
  jmp    L36
L87:
  cmpb   $0x0,0x1(%rdi)
  je     L69
  add    $0x2,%rdi
  jmp    L57
L35:
  add    $0x1,%rdi
L57:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L52
L36:
  cmp    $0x5c,%al
  je     L87
  jg     L35
  sub    $0x2a,%eax
  cmp    $0x31,%al
  ja     L35
  bt     %rax,%rdx
  jae    L35
  mov    $0xffffffff,%eax
  ret
L52:
  mov    $0x0,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
L85:
  mov    $0x0,%eax
  ret
L69:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isglob(const char *str) {
  if (!str)
    return (0);
  while (*str) {
    switch (*str) {
    case '*':
    case '?':
    case '[':
      return (-1);
    case '\\':
      if (str[1] == '\0')
        return (0);
      str += 2;
      break;
    default:
      str += 1;
      break;
    }
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isglob>:
  endbr64
  test   %rdi,%rdi
  je     L11
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  movabs $0xfffdffffffdffffe,%rdx
L44:
  cmp    $0x5c,%al
  je     L73
  jg     L13
  sub    $0x2a,%eax
  cmp    $0x31,%al
  jbe    L57
L13:
  add    $0x1,%rdi
L52:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L44
L11:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L57:
  bt     %rax,%rdx
  jb     L13
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L73:
  cmpb   $0x0,0x1(%rdi)
  je     L11
  add    $0x2,%rdi
  jmp    L52
```

assistant: ```c
int isglob(const char *str) {
  if (!str)
    return (0);
  while (*str) {
    switch (*str) {
    case '*':
    case '?':
    case '[':
      return (-1);
    case '\\':
      if (str[1] == '\0')
        return (0);
      str += 2;
      break;
    default:
      str += 1;
      break;
    }
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isglob>:
  endbr64
  test   %rdi,%rdi
  je     L81
  movzbl (%rdi),%eax
  test   %al,%al
  je     L81
  movabs $0xfffdffffffdffffe,%rdx
L6:
  cmp    $0x5c,%al
  je     L8
  jg     L41
  sub    $0x2a,%eax
  cmp    $0x31,%al
  jbe    L54
L41:
  add    $0x1,%rdi
L3:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
L81:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L54:
  bt     %rax,%rdx
  jb     L41
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L8:
  cmpb   $0x0,0x1(%rdi)
  je     L81
  add    $0x2,%rdi
  jmp    L3
```

assistant: ```c
int isglob(const char *str) {
  if (!str)
    return (0);
  while (*str) {
    switch (*str) {
    case '*':
    case '?':
    case '[':
      return (-1);
    case '\\':
      if (str[1] == '\0')
        return (0);
      str += 2;
      break;
    default:
      str += 1;
      break;
    }
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<frexp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  call   <__infer_nondet_double@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double frexp(double value, int *exp) {
  *exp = __infer_nondet_int();
  return __infer_nondet_double();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<frexp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  call   <__infer_nondet_double@plt>
  pop    %rbx
  ret
```

assistant: ```c
double frexp(double value, int *exp) {
  *exp = __infer_nondet_int();
  return __infer_nondet_double();
}
```
user: What is the c source code of the assembly code below:

```asm
<frexp>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <__infer_nondet_int@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  jmp    1060 <__infer_nondet_double@plt>
```

assistant: ```c
double frexp(double value, int *exp) {
  *exp = __infer_nondet_int();
  return __infer_nondet_double();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<frexp>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <__infer_nondet_int@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  jmp    1060 <__infer_nondet_double@plt>
```

assistant: ```c
double frexp(double value, int *exp) {
  *exp = __infer_nondet_int();
  return __infer_nondet_double();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fastTimes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L27
L4:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L14
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,-0x8(%rbp)
L14:
  sarq   -0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    %rax,%rax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,-0x18(%rbp)
L27:
  cmpq   $0x0,-0x20(%rbp)
  jne    L4
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long fastTimes(long long a, long long b, long long m) {
  long long ret = 0;
  while (b) {
    if (b & 1)
      ret = (ret + a) % m;
    b >>= 1;
    a = (a << 1) % m;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fastTimes>:
  endbr64
  mov    %rdx,%rcx
  test   %rsi,%rsi
  je     L47
  mov    $0x0,%r8d
  jmp    L12
L4:
  lea    (%rdi,%rdi,1),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rdi
  sar    %rsi
  je     L18
L12:
  test   $0x1,%sil
  je     L4
  lea    (%rdi,%r8,1),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%r8
  jmp    L4
L47:
  mov    %rsi,%r8
L18:
  mov    %r8,%rax
  ret
```

assistant: ```c
long long fastTimes(long long a, long long b, long long m) {
  long long ret = 0;
  while (b) {
    if (b & 1)
      ret = (ret + a) % m;
    b >>= 1;
    a = (a << 1) % m;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<fastTimes>:
  endbr64
  mov    %rdx,%rcx
  xor    %r8d,%r8d
  test   %rsi,%rsi
  je     L26
  nop
L5:
  test   $0x1,%sil
  je     L12
  lea    (%rdi,%r8,1),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%r8
L12:
  lea    (%rdi,%rdi,1),%rax
  cqto
  idiv   %rcx
  sar    %rsi
  mov    %rdx,%rdi
  jne    L5
L26:
  mov    %r8,%rax
  ret
```

assistant: ```c
long long fastTimes(long long a, long long b, long long m) {
  long long ret = 0;
  while (b) {
    if (b & 1)
      ret = (ret + a) % m;
    b >>= 1;
    a = (a << 1) % m;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fastTimes>:
  endbr64
  mov    %rdx,%rcx
  xor    %r8d,%r8d
  test   %rsi,%rsi
  je     L19
  nop
L26:
  test   $0x1,%sil
  je     L3
  lea    (%rdi,%r8,1),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%r8
L3:
  lea    (%rdi,%rdi,1),%rax
  cqto
  idiv   %rcx
  sar    %rsi
  mov    %rdx,%rdi
  jne    L26
L19:
  mov    %r8,%rax
  ret
```

assistant: ```c
long long fastTimes(long long a, long long b, long long m) {
  long long ret = 0;
  while (b) {
    if (b & 1)
      ret = (ret + a) % m;
    b >>= 1;
    a = (a << 1) % m;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  jns    L15
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <timespec_to_nsec@plt>
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
uint64_t now(clockid_t id) {
  struct timespec ts;
  if (clock_gettime(id, &ts) < 0)
    return UINT64_MAX;
  return timespec_to_nsec(ts);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<now>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <clock_gettime@plt>
  test   %rax,%rax
  js     L5
  mov    0x4(%rsp),%edi
  call   <timespec_to_nsec@plt>
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  ret
L5:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  jmp    L21
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t now(clockid_t id) {
  struct timespec ts;
  if (clock_gettime(id, &ts) < 0)
    return UINT64_MAX;
  return timespec_to_nsec(ts);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<now>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <clock_gettime@plt>
  test   %rax,%rax
  js     L19
  mov    0x4(%rsp),%edi
  call   <timespec_to_nsec@plt>
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L19:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  jmp    L27
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t now(clockid_t id) {
  struct timespec ts;
  if (clock_gettime(id, &ts) < 0)
    return UINT64_MAX;
  return timespec_to_nsec(ts);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<now>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <clock_gettime@plt>
  test   %rax,%rax
  js     L7
  mov    0x4(%rsp),%edi
  call   <timespec_to_nsec@plt>
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L7:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L24
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t now(clockid_t id) {
  struct timespec ts;
  if (clock_gettime(id, &ts) < 0)
    return UINT64_MAX;
  return timespec_to_nsec(ts);
}
```