ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <sumOfDigits@plt>
  lea    D34(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <recurSumOfDigits@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D24
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D34
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string

tool: D24: Enter number to be summed: 

tool: D0: %d

tool: D34: Digits summed: %d


tool: D12: Digits summed: %d

assistant: ```c
int main() {
  int num;
  printf("Enter number to be summed: ");
  scanf("%d", &num);
  printf("Digits summed: %d\n", sumOfDigits(num));
  printf("Digits summed: %d", recurSumOfDigits(num));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<OneWireIntEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  lea    0x100(%rax),%rdx
  mov    (%rdx),%rcx
  add    $0x100,%rax
  mov    %rax,%rdx
  mov    %rsi,%rax
  or     %rcx,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void OneWireIntEnable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000100))) |= ui32IntFlags;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<OneWireIntEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x100(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x100(%rdx)
  ret
```

assistant: ```c
void OneWireIntEnable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000100))) |= ui32IntFlags;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<OneWireIntEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x100(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x100(%rdx)
  ret
```

assistant: ```c
void OneWireIntEnable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000100))) |= ui32IntFlags;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<OneWireIntEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x100(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x100(%rdx)
  ret
```

assistant: ```c
void OneWireIntEnable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000100))) |= ui32IntFlags;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<escape_special_characters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  mov    %rdi,-0x1018(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1018(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x1018(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x1010(%rbp),%rcx
  mov    -0x1018(%rbp),%rax
  mov    $0x3d,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <escape_character@plt>
  mov    -0x1018(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x1010(%rbp),%rcx
  mov    -0x1018(%rbp),%rax
  mov    $0x27,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <escape_character@plt>
  mov    -0x1018(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x1010(%rbp),%rcx
  mov    -0x1018(%rbp),%rax
  mov    $0x24,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <escape_character@plt>
  mov    -0x1018(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x1010(%rbp),%rcx
  mov    -0x1018(%rbp),%rax
  mov    $0x26,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <escape_character@plt>
  mov    -0x1018(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x1010(%rbp),%rcx
  mov    -0x1018(%rbp),%rax
  mov    $0x60,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <escape_character@plt>
  jmp    L3
L10:
  nop
L3:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
void escape_special_characters(char *data) {
  char buffer[4096];
  if (!*data)
    return;
  strcpy(buffer, data);
  escape_character(data, buffer, '=');
  strcpy(buffer, data);
  escape_character(data, buffer, '\'');
  strcpy(buffer, data);
  escape_character(data, buffer, '$');
  strcpy(buffer, data);
  escape_character(data, buffer, '&');
  strcpy(buffer, data);
  escape_character(data, buffer, '`');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<escape_special_characters>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L8
L3:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    %rdi,%rbx
  mov    %rsp,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x3d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <escape_character@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x27,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <escape_character@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x24,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <escape_character@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x26,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <escape_character@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x60,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <escape_character@plt>
  jmp    L3
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void escape_special_characters(char *data) {
  char buffer[4096];
  if (!*data)
    return;
  strcpy(buffer, data);
  escape_character(data, buffer, '=');
  strcpy(buffer, data);
  escape_character(data, buffer, '\'');
  strcpy(buffer, data);
  escape_character(data, buffer, '$');
  strcpy(buffer, data);
  escape_character(data, buffer, '&');
  strcpy(buffer, data);
  escape_character(data, buffer, '`');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<escape_special_characters>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L6
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x3d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x27,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x24,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x26,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x60,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
L6:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x1018,%rsp
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void escape_special_characters(char *data) {
  char buffer[4096];
  if (!*data)
    return;
  strcpy(buffer, data);
  escape_character(data, buffer, '=');
  strcpy(buffer, data);
  escape_character(data, buffer, '\'');
  strcpy(buffer, data);
  escape_character(data, buffer, '$');
  strcpy(buffer, data);
  escape_character(data, buffer, '&');
  strcpy(buffer, data);
  escape_character(data, buffer, '`');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<escape_special_characters>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L6
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x3d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x27,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x24,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x26,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x60,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <escape_character@plt>
L6:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1018,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void escape_special_characters(char *data) {
  char buffer[4096];
  if (!*data)
    return;
  strcpy(buffer, data);
  escape_character(data, buffer, '=');
  strcpy(buffer, data);
  escape_character(data, buffer, '\'');
  strcpy(buffer, data);
  escape_character(data, buffer, '$');
  strcpy(buffer, data);
  escape_character(data, buffer, '&');
  strcpy(buffer, data);
  escape_character(data, buffer, '`');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat_expr_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <concat_expr_class_get@plt>
  mov    %eax,%edi
  call   <object_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x2e,%ecx
  mov    %rax,%rdi
  call   <binary_expr_init@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct expr *concat_expr_new(struct expr *left, struct expr *right) {
  struct object *expr = object_new(concat_expr_class_get());
  binary_expr_init(((struct binary_expr *)(expr)), left, right, '.');
  return ((struct expr *)(expr));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<concat_expr_new>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%eax
  call   <concat_expr_class_get@plt>
  mov    %eax,%edi
  call   <object_new@plt>
  mov    %rax,%rbx
  mov    $0x2e,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <binary_expr_init@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct expr *concat_expr_new(struct expr *left, struct expr *right) {
  struct object *expr = object_new(concat_expr_class_get());
  binary_expr_init(((struct binary_expr *)(expr)), left, right, '.');
  return ((struct expr *)(expr));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<concat_expr_new>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <concat_expr_class_get@plt>
  mov    %eax,%edi
  call   <object_new@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    $0x2e,%ecx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <binary_expr_init@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct expr *concat_expr_new(struct expr *left, struct expr *right) {
  struct object *expr = object_new(concat_expr_class_get());
  binary_expr_init(((struct binary_expr *)(expr)), left, right, '.');
  return ((struct expr *)(expr));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<concat_expr_new>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <concat_expr_class_get@plt>
  mov    %eax,%edi
  call   <object_new@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    $0x2e,%ecx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <binary_expr_init@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct expr *concat_expr_new(struct expr *left, struct expr *right) {
  struct object *expr = object_new(concat_expr_class_get());
  binary_expr_init(((struct binary_expr *)(expr)), left, right, '.');
  return ((struct expr *)(expr));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_barrett_reduction_constant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L29:
  mov    -0x4(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L20
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0xdb710641,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  xor    %eax,-0x8(%rbp)
L20:
  addl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x20,-0x4(%rbp)
  jle    L29
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t compute_barrett_reduction_constant(void) {
  uint64_t quotient = 0;
  uint64_t dividend = 0x1;
  for (int i = 0; i < 64 - 32 + 1; i++) {
    if ((dividend >> i) & 1) {
      quotient |= (uint64_t)1 << i;
      dividend ^= (((uint64_t)0xEDB88320 << 1) | 1) << i;
    }
  }
  return quotient;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compute_barrett_reduction_constant>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x1,%eax
  mov    $0x0,%edx
  mov    $0x1,%r8d
  mov    $0xdb710641,%edi
  jmp    L25
L3:
  add    $0x1,%ecx
  cmp    $0x21,%ecx
  je     L9
L25:
  bt     %ecx,%eax
  jae    L3
  mov    %r8d,%esi
  shl    %cl,%esi
  or     %esi,%edx
  mov    %edi,%esi
  shl    %cl,%esi
  xor    %esi,%eax
  jmp    L3
L9:
  mov    %edx,%eax
  ret
```

assistant: ```c
uint64_t compute_barrett_reduction_constant(void) {
  uint64_t quotient = 0;
  uint64_t dividend = 0x1;
  for (int i = 0; i < 64 - 32 + 1; i++) {
    if ((dividend >> i) & 1) {
      quotient |= (uint64_t)1 << i;
      dividend ^= (((uint64_t)0xEDB88320 << 1) | 1) << i;
    }
  }
  return quotient;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compute_barrett_reduction_constant>:
  endbr64
  xor    %ecx,%ecx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  mov    $0x1,%edi
  mov    $0xdb710641,%esi
  nopl   0x0(%rax,%rax,1)
L3:
  bt     %ecx,%eax
  jae    L2
  mov    %edi,%edx
  shl    %cl,%edx
  or     %edx,%r8d
  mov    %esi,%edx
  shl    %cl,%edx
  xor    %edx,%eax
L2:
  add    $0x1,%ecx
  cmp    $0x21,%ecx
  jne    L3
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t compute_barrett_reduction_constant(void) {
  uint64_t quotient = 0;
  uint64_t dividend = 0x1;
  for (int i = 0; i < 64 - 32 + 1; i++) {
    if ((dividend >> i) & 1) {
      quotient |= (uint64_t)1 << i;
      dividend ^= (((uint64_t)0xEDB88320 << 1) | 1) << i;
    }
  }
  return quotient;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compute_barrett_reduction_constant>:
  endbr64
  xor    %ecx,%ecx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  mov    $0x1,%edi
  mov    $0xdb710641,%esi
  nopl   0x0(%rax,%rax,1)
L3:
  bt     %ecx,%eax
  jae    L4
  mov    %edi,%edx
  shl    %cl,%edx
  or     %edx,%r8d
  mov    %esi,%edx
  shl    %cl,%edx
  xor    %edx,%eax
L4:
  add    $0x1,%ecx
  cmp    $0x21,%ecx
  jne    L3
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t compute_barrett_reduction_constant(void) {
  uint64_t quotient = 0;
  uint64_t dividend = 0x1;
  for (int i = 0; i < 64 - 32 + 1; i++) {
    if ((dividend >> i) & 1) {
      quotient |= (uint64_t)1 << i;
      dividend ^= (((uint64_t)0xEDB88320 << 1) | 1) << i;
    }
  }
  return quotient;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ignorer_commentaires>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L23
L16:
  nop
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0xa,-0x1(%rbp)
  jne    L17
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x23,-0x1(%rbp)
  je     L16
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  nop
  leave
  ret
```

assistant: ```c
void ignorer_commentaires(FILE *f) {
  unsigned char c;
  while ((c = fgetc(f)) == '#')
    while ((c = fgetc(f)) != '\n')
      ;
  fseek(f, -sizeof(unsigned char), SEEK_CUR);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ignorer_commentaires>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L12
L26:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L26
L12:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    $0x23,%al
  je     L26
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  pop    %rbx
  ret
```

assistant: ```c
void ignorer_commentaires(FILE *f) {
  unsigned char c;
  while ((c = fgetc(f)) == '#')
    while ((c = fgetc(f)) != '\n')
      ;
  fseek(f, -sizeof(unsigned char), SEEK_CUR);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ignorer_commentaires>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0x23,%al
  jne    L25
  nopl   0x0(%rax)
L4:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L4
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0x23,%al
  je     L4
L25:
  mov    D2(%rip),%rax
  mov    %rbp,%rdi
  mov    $0xffffffff,%esi
  pop    %rbp
  mov    (%rax),%edx
  jmp    1070 <fseek@plt>
```

assistant: ```c
void ignorer_commentaires(FILE *f) {
  unsigned char c;
  while ((c = fgetc(f)) == '#')
    while ((c = fgetc(f)) != '\n')
      ;
  fseek(f, -sizeof(unsigned char), SEEK_CUR);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ignorer_commentaires>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0x23,%al
  jne    L16
  nopl   0x0(%rax)
L20:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L20
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0x23,%al
  je     L20
L16:
  mov    D4(%rip),%rax
  mov    %rbp,%rdi
  mov    $0xffffffff,%esi
  pop    %rbp
  mov    (%rax),%edx
  jmp    1070 <fseek@plt>
```

assistant: ```c
void ignorer_commentaires(FILE *f) {
  unsigned char c;
  while ((c = fgetc(f)) == '#')
    while ((c = fgetc(f)) != '\n')
      ;
  fseek(f, -sizeof(unsigned char), SEEK_CUR);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_nan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L1
  mov    -0x4(%rbp),%eax
  jmp    L11
L1:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xffffffff,%eax
L11:
  leave
  ret
```

assistant: ```c
int check_nan(const double *const arr, int n) {
  for (int i = 0; i < n; ++i)
    if (isnan(arr[i]))
      return i;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_nan>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L4
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
L29:
  mov    %ebx,%r13d
  movsd  (%r12,%rbx,8),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L18
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L29
  mov    $0xffffffff,%r13d
L18:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    $0xffffffff,%r13d
  jmp    L18
```

assistant: ```c
int check_nan(const double *const arr, int n) {
  for (int i = 0; i < n; ++i)
    if (isnan(arr[i]))
      return i;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_nan>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L7
  mov    %rdi,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  jmp    L24
  nopl   0x0(%rax)
L33:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L7
L24:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%r13d
  call   <isnan@plt>
  test   %rax,%rax
  je     L33
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int check_nan(const double *const arr, int n) {
  for (int i = 0; i < n; ++i)
    if (isnan(arr[i]))
      return i;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_nan>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L16
  mov    %rdi,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  jmp    L34
  nopl   0x0(%rax)
L22:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L16
L34:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%r13d
  call   <isnan@plt>
  test   %rax,%rax
  je     L22
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int check_nan(const double *const arr, int n) {
  for (int i = 0; i < n; ++i)
    if (isnan(arr[i]))
      return i;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<binary_writer_write_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <binary_writer_write_7bit_int@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <binary_writer_7bit_len@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int binary_writer_write_string(char *dest, const char *src) {
  int len, pos = 0;
  len = strlen(src);
  binary_writer_write_7bit_int(dest, len, &pos);
  memcpy(dest + pos, src, len);
  return len + binary_writer_7bit_len(len);
}
```