ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ellipse>:
  endbr64
  sub    $0x48,%rsp
  divsd  D9(%rip),%xmm4
  movsd  %xmm0,(%rsp)
  lea    0x38(%rsp),%rdi
  lea    0x30(%rsp),%rsi
  mulsd  D4(%rip),%xmm4
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm6,0x20(%rsp)
  movapd %xmm4,%xmm0
  movsd  %xmm3,0x18(%rsp)
  call   <sincos@plt>
  movsd  0x30(%rsp),%xmm0
  movsd  0x38(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm5
  movsd  0x20(%rsp),%xmm6
  subsd  (%rsp),%xmm5
  subsd  0x8(%rsp),%xmm6
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm7
  mulsd  %xmm5,%xmm1
  mulsd  %xmm6,%xmm7
  mulsd  %xmm2,%xmm5
  mulsd  %xmm6,%xmm0
  addsd  %xmm7,%xmm1
  divsd  0x10(%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  subsd  %xmm5,%xmm0
  divsd  0x18(%rsp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  D12(%rip),%xmm0
  comisd %xmm1,%xmm0
  setae  %al
  add    $0x48,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: f64
name: unpack_data
arguments: data_tag: D4
type_guessed: f64
name: unpack_data
arguments: data_tag: D12
type_guessed: f64

tool: D9: 180

tool: D4: 3.141592653589793

tool: D12: 1

assistant: ```c
char ellipse(double xcen, double ycen, double xrad, double yrad, double rot, double xcol, double ycol) {
  double x, y, xprime, yprime, dx, dy, dlen, theta;
  theta = (rot / 180.0) * 3.1415926535897932385;
  xprime = xcol - xcen;
  yprime = ycol - ycen;
  x = xprime * cos(theta) + yprime * sin(theta);
  y = -xprime * sin(theta) + yprime * cos(theta);
  dx = x / xrad;
  dy = y / yrad;
  dx *= dx;
  dy *= dy;
  dlen = dx + dy;
  if (dlen <= 1.0)
    return (1);
  else
    return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ip_fast_csum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    (%rdx),%ecx
  sub    $0x4,%eax
  jbe    L11
  add    0x4(%rdx),%ecx
  adc    0x8(%rdx),%ecx
  adc    0xc(%rdx),%ecx
L12:
  adc    0x10(%rdx),%ecx
  lea    0x4(%rdx),%rdx
  dec    %eax
  jne    L12
  adc    $0x0,%ecx
  mov    %ecx,%eax
  shr    $0x10,%ecx
  add    %ax,%cx
  adc    $0x0,%ecx
  not    %ecx
L11:
  mov    %ecx,-0x4(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %eax,-0x1c(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short ip_fast_csum(unsigned char *iph, unsigned int ihl) {
  unsigned int sum;
  __asm__ __volatile__("movl (%1), %0\n"
                       "subl $4, %2\n"
                       "jbe 2f\n"
                       "addl 4(%1), %0\n"
                       "adcl 8(%1), %0\n"
                       "adcl 12(%1), %0\n"
                       "1:	     adcl 16(%1), %0\n"
                       "lea 4(%1), %1\n"
                       "decl %2\n"
                       "jne	1b\n"
                       "adcl $0, %0\n"
                       "movl %0, %2\n"
                       "shrl $16, %0\n"
                       "addw %w2, %w0\n"
                       "adcl $0, %0\n"
                       "notl %0\n"
                       "2:\n"
                       : "=r"(sum), "=r"(iph), "=r"(ihl)
                       : "1"(iph), "2"(ihl));
  return (sum);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ip_fast_csum>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x4,%esi
  jbe    L8
  add    0x4(%rdi),%eax
  adc    0x8(%rdi),%eax
  adc    0xc(%rdi),%eax
L11:
  adc    0x10(%rdi),%eax
  lea    0x4(%rdi),%rdi
  dec    %esi
  jne    L11
  adc    $0x0,%eax
  mov    %eax,%esi
  shr    $0x10,%eax
  add    %si,%ax
  adc    $0x0,%eax
  not    %eax
L8:
  ret
```

assistant: ```c
unsigned short ip_fast_csum(unsigned char *iph, unsigned int ihl) {
  unsigned int sum;
  __asm__ __volatile__("movl (%1), %0\n"
                       "subl $4, %2\n"
                       "jbe 2f\n"
                       "addl 4(%1), %0\n"
                       "adcl 8(%1), %0\n"
                       "adcl 12(%1), %0\n"
                       "1:	     adcl 16(%1), %0\n"
                       "lea 4(%1), %1\n"
                       "decl %2\n"
                       "jne	1b\n"
                       "adcl $0, %0\n"
                       "movl %0, %2\n"
                       "shrl $16, %0\n"
                       "addw %w2, %w0\n"
                       "adcl $0, %0\n"
                       "notl %0\n"
                       "2:\n"
                       : "=r"(sum), "=r"(iph), "=r"(ihl)
                       : "1"(iph), "2"(ihl));
  return (sum);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ip_fast_csum>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x4,%esi
  jbe    L9
  add    0x4(%rdi),%eax
  adc    0x8(%rdi),%eax
  adc    0xc(%rdi),%eax
L3:
  adc    0x10(%rdi),%eax
  lea    0x4(%rdi),%rdi
  dec    %esi
  jne    L3
  adc    $0x0,%eax
  mov    %eax,%esi
  shr    $0x10,%eax
  add    %si,%ax
  adc    $0x0,%eax
  not    %eax
L9:
  ret
```

assistant: ```c
unsigned short ip_fast_csum(unsigned char *iph, unsigned int ihl) {
  unsigned int sum;
  __asm__ __volatile__("movl (%1), %0\n"
                       "subl $4, %2\n"
                       "jbe 2f\n"
                       "addl 4(%1), %0\n"
                       "adcl 8(%1), %0\n"
                       "adcl 12(%1), %0\n"
                       "1:	     adcl 16(%1), %0\n"
                       "lea 4(%1), %1\n"
                       "decl %2\n"
                       "jne	1b\n"
                       "adcl $0, %0\n"
                       "movl %0, %2\n"
                       "shrl $16, %0\n"
                       "addw %w2, %w0\n"
                       "adcl $0, %0\n"
                       "notl %0\n"
                       "2:\n"
                       : "=r"(sum), "=r"(iph), "=r"(ihl)
                       : "1"(iph), "2"(ihl));
  return (sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ip_fast_csum>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x4,%esi
  jbe    L4
  add    0x4(%rdi),%eax
  adc    0x8(%rdi),%eax
  adc    0xc(%rdi),%eax
L2:
  adc    0x10(%rdi),%eax
  lea    0x4(%rdi),%rdi
  dec    %esi
  jne    L2
  adc    $0x0,%eax
  mov    %eax,%esi
  shr    $0x10,%eax
  add    %si,%ax
  adc    $0x0,%eax
  not    %eax
L4:
  ret
```

assistant: ```c
unsigned short ip_fast_csum(unsigned char *iph, unsigned int ihl) {
  unsigned int sum;
  __asm__ __volatile__("movl (%1), %0\n"
                       "subl $4, %2\n"
                       "jbe 2f\n"
                       "addl 4(%1), %0\n"
                       "adcl 8(%1), %0\n"
                       "adcl 12(%1), %0\n"
                       "1:	     adcl 16(%1), %0\n"
                       "lea 4(%1), %1\n"
                       "decl %2\n"
                       "jne	1b\n"
                       "adcl $0, %0\n"
                       "movl %0, %2\n"
                       "shrl $16, %0\n"
                       "addw %w2, %w0\n"
                       "adcl $0, %0\n"
                       "notl %0\n"
                       "2:\n"
                       : "=r"(sum), "=r"(iph), "=r"(ihl)
                       : "1"(iph), "2"(ihl));
  return (sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mylib1_fct1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <mylib2_fct1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D3: mylib1_fct1

assistant: ```c
int mylib1_fct1(void) {
  printf("%s\n", __FUNCTION__);
  mylib2_fct1();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mylib1_fct1>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <mylib2_fct1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: mylib1_fct1

assistant: ```c
int mylib1_fct1(void) {
  printf("%s\n", __FUNCTION__);
  mylib2_fct1();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mylib1_fct1>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <mylib2_fct1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: mylib1_fct1

assistant: ```c
int mylib1_fct1(void) {
  printf("%s\n", __FUNCTION__);
  mylib2_fct1();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mylib1_fct1>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <mylib2_fct1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: mylib1_fct1

assistant: ```c
int mylib1_fct1(void) {
  printf("%s\n", __FUNCTION__);
  mylib2_fct1();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  movsd  D14(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D43(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L73
  cmpl   $0x0,-0x38(%rbp)
  jne    L73
  mov    $0x0,%eax
  jmp    L85
L73:
  cmpl   $0x0,-0x34(%rbp)
  js     L20
  cmpl   $0x0,-0x38(%rbp)
  jns    L3
L20:
  mov    $0x0,%eax
  jmp    L85
L3:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x34(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x38(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  D48(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x34(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x38(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x10(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L25
  movsd  -0x28(%rbp),%xmm0
  movq   D22(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
L25:
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <pnorm@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L67
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movsd  D23(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L85
L67:
  mov    $0x9c4,%eax
L85:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type: f64
name: retrieve_data
arguments: label: D43
type: f64
name: retrieve_data
arguments: label: D48
type: byte[8]
name: retrieve_data
arguments: label: D22
type: byte[8]
name: retrieve_data
arguments: label: D23
type: byte[8]

tool: D14: 1

tool: D43: 6.8

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0xc0]}

assistant: ```c
int match(len1, len2)
int len1, len2;
{
  double z, pd, mean;
  double c = 1;
  double s2 = 6.8;
  if (len1 == 0 && len2 == 0)
    return (0);
  if (len1 < 0 || len2 < 0)
    return (0);
  mean = (len1 + len2 / c) / 2;
  z = (c * len1 - len2) / sqrt(s2 * mean);
  if (z < 0)
    z = -z;
  pd = 2 * (1 - pnorm(z));
  if (pd > 0)
    return ((int)(-100 * log(pd)));
  else
    return (2500);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<match>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  je     L2
  test   %eax,%eax
  jns    L26
  mov    $0x0,%eax
  ret
L26:
  push   %rbx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  movq   %xmm2,%rbx
  addsd  %xmm1,%xmm0
  mulsd  D30(%rip),%xmm0
  mulsd  D27(%rip),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L31
  sqrtsd %xmm0,%xmm0
L13:
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L50
L12:
  movapd %xmm1,%xmm0
  mov    $0x1,%eax
  call   <pnorm@plt>
  mov    $0x1,%edx
  sub    %eax,%edx
  mov    $0x9c4,%eax
  test   %edx,%edx
  jle    L17
  add    %edx,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  call   <log@plt>
  mulsd  D13(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L17:
  pop    %rbx
  ret
L31:
  call   <sqrt@plt>
  jmp    L13
L50:
  xorpd  D5(%rip),%xmm1
  jmp    L12
L2:
  ret
```

tool_calls: name: unpack_data
arguments: label: D30
type_guessed: byte[8]
name: unpack_data
arguments: label: D27
type_guessed: f64
name: unpack_data
arguments: label: D13
type_guessed: byte[8]
name: unpack_data
arguments: label: D5
type_guessed: byte[16]

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D27: 6.8

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0xc0]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int match(len1, len2)
int len1, len2;
{
  double z, pd, mean;
  double c = 1;
  double s2 = 6.8;
  if (len1 == 0 && len2 == 0)
    return (0);
  if (len1 < 0 || len2 < 0)
    return (0);
  mean = (len1 + len2 / c) / 2;
  z = (c * len1 - len2) / sqrt(s2 * mean);
  if (z < 0)
    z = -z;
  pd = 2 * (1 - pnorm(z));
  if (pd > 0)
    return ((int)(-100 * log(pd)));
  else
    return (2500);
}
```
user: What is the c source code of the assembly code below?

```asm
<match>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  je     L48
  mov    $0x0,%eax
  jns    L52
L48:
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  sub    $0x18,%rsp
  cvtsi2sd %esi,%xmm2
  cvtsi2sd %edi,%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  mulsd  D1(%rip),%xmm0
  subsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  mulsd  D20(%rip),%xmm0
  ucomisd %xmm0,%xmm2
  ja     L29
  sqrtsd %xmm0,%xmm0
L20:
  divsd  %xmm0,%xmm1
  comisd %xmm1,%xmm2
  ja     L8
L12:
  movapd %xmm1,%xmm0
  mov    $0x1,%eax
  call   <pnorm@plt>
  mov    $0x1,%edx
  sub    %eax,%edx
  mov    $0x9c4,%eax
  test   %edx,%edx
  jle    L50
  add    %edx,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  call   <log@plt>
  mulsd  D18(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L50:
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L8:
  xorpd  D36(%rip),%xmm1
  jmp    L12
L29:
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  jmp    L20
```

tool_calls: name: read_data
arguments: data_tag: D1
type: byte[8]
name: read_data
arguments: data_tag: D20
type: f64
name: read_data
arguments: data_tag: D18
type: byte[8]
name: read_data
arguments: data_tag: D36
type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D20: 6.8

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0xc0]}

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int match(len1, len2)
int len1, len2;
{
  double z, pd, mean;
  double c = 1;
  double s2 = 6.8;
  if (len1 == 0 && len2 == 0)
    return (0);
  if (len1 < 0 || len2 < 0)
    return (0);
  mean = (len1 + len2 / c) / 2;
  z = (c * len1 - len2) / sqrt(s2 * mean);
  if (z < 0)
    z = -z;
  pd = 2 * (1 - pnorm(z));
  if (pd > 0)
    return ((int)(-100 * log(pd)));
  else
    return (2500);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<match>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  je     L36
  mov    $0x0,%eax
  jns    L31
L36:
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  sub    $0x18,%rsp
  cvtsi2sd %esi,%xmm2
  cvtsi2sd %edi,%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  mulsd  D25(%rip),%xmm0
  subsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  mulsd  D37(%rip),%xmm0
  ucomisd %xmm0,%xmm2
  ja     L12
  sqrtsd %xmm0,%xmm0
L29:
  divsd  %xmm0,%xmm1
  comisd %xmm1,%xmm2
  ja     L3
L47:
  movapd %xmm1,%xmm0
  mov    $0x1,%eax
  call   <pnorm@plt>
  mov    $0x1,%edx
  sub    %eax,%edx
  mov    $0x9c4,%eax
  test   %edx,%edx
  jle    L24
  add    %edx,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  call   <log@plt>
  mulsd  D29(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L24:
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L3:
  xorpd  D24(%rip),%xmm1
  jmp    L47
L12:
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  jmp    L29
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D37
datatype: f64
name: extract_symbolic_data
arguments: data_label: D29
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D24
datatype: byte[16]

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D37: 6.8

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0xc0]}

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int match(len1, len2)
int len1, len2;
{
  double z, pd, mean;
  double c = 1;
  double s2 = 6.8;
  if (len1 == 0 && len2 == 0)
    return (0);
  if (len1 < 0 || len2 < 0)
    return (0);
  mean = (len1 + len2 / c) / 2;
  z = (c * len1 - len2) / sqrt(s2 * mean);
  if (z < 0)
    z = -z;
  pd = 2 * (1 - pnorm(z));
  if (pd > 0)
    return ((int)(-100 * log(pd)));
  else
    return (2500);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GCD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L0
L18:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L0:
  cmpq   $0x0,-0x20(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long GCD(long i, long j) {
  long k;
  while (j != 0) {
    k;
    k = j;
    j = i % j;
    i = k;
  }
  return k;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GCD>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L15
L7:
  mov    %rsi,%rcx
  cqto
  idiv   %rsi
  mov    %rdx,%rsi
  mov    %rcx,%rax
  test   %rdx,%rdx
  jne    L7
L28:
  mov    %rcx,%rax
  ret
L15:
  mov    $0x0,%ecx
  jmp    L28
```

assistant: ```c
long GCD(long i, long j) {
  long k;
  while (j != 0) {
    k;
    k = j;
    j = i % j;
    i = k;
  }
  return k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GCD>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L0
  nop
L7:
  mov    %rdx,%r8
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L7
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L0:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long GCD(long i, long j) {
  long k;
  while (j != 0) {
    k;
    k = j;
    j = i % j;
    i = k;
  }
  return k;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GCD>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L18
  nop
L0:
  mov    %rdx,%r8
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L0
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L18:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long GCD(long i, long j) {
  long k;
  while (j != 0) {
    k;
    k = j;
    j = i % j;
    i = k;
  }
  return k;
}
```
user: What is the c source code of the assembly code below:

```asm
<isEmpty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x1,%eax
  jmp    L8
L4:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int isEmpty(struct stack *s) {
  if (s == NULL)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isEmpty>:
  endbr64
  test   %rdi,%rdi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isEmpty(struct stack *s) {
  if (s == NULL)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isEmpty>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  sete   %al
  ret
```

assistant: ```c
int isEmpty(struct stack *s) {
  if (s == NULL)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isEmpty>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  sete   %al
  ret
```

assistant: ```c
int isEmpty(struct stack *s) {
  if (s == NULL)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L9
L28:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L9:
  mov    -0xc(%rbp),%eax
  cmp    $0x2a,%eax
  jne    L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string

tool: D10: %d

tool: D16: %d


assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  while (num != 42) {
    printf("%d\n", num);
    scanf("%d", &num);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  je     L0
  lea    D5(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D23(%rip),%rbx
L4:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  jne    L4
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D23
data_type: string
name: parse_data
arguments: label: D5
data_type: string

tool: D23: %d

tool: D5: %d


assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  while (num != 42) {
    printf("%d\n", num);
    scanf("%d", &num);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  je     L15
  lea    D0(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  jne    L23
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string
name: unpack_data
arguments: data_label: D0
data_type: string

tool: D1: %d

tool: D0: %d


assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  while (num != 42) {
    printf("%d\n", num);
    scanf("%d", &num);
  }
  return 0;
}
```