ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<reverse>:
  endbr64
  sub    $0x3f8,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  test   %dl,%dl
  je     L24
  lea    0x1(%rsp),%r8
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %dl,(%r8,%rax,1)
  movslq %eax,%rcx
  mov    %rax,%rsi
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L23
  lea    (%rsp,%rcx,1),%rax
  lea    0x1(%rdi,%rsi,1),%rcx
  nop
L1:
  movzbl (%rax),%edx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %dl,-0x1(%rdi)
  cmp    %rcx,%rdi
  jne    L1
L24:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x3f8,%rsp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void reverse(char s[]) {
  char t[1000];
  int i, max;
  i = 0;
  while (s[i] != '\0')
    t[i] = s[i++];
  max = i;
  for (i = 0; i < max; i++)
    s[i] = t[max - 1 - i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<first_day>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x4,-0x14(%rbp)
  jmp    L19
L11:
  mov    -0x14(%rbp),%eax
  add    $0x16d,%eax
  movslq %eax,%rbx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <is_leap_year@plt>
  add    %rbx,%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  subl   $0x1,-0x24(%rbp)
L19:
  cmpl   $0x7b2,-0x24(%rbp)
  jg     L11
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int first_day(int year) {
  int ret = 4;
  for (; year > 1970; --year)
    ret = (ret + 365 + is_leap_year(year) ? 1 : 0) % 7;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<first_day>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x7b2,%edi
  jle    L5
  mov    %edi,%ebp
  mov    $0x4,%ebx
L11:
  mov    %ebp,%edi
  call   <is_leap_year@plt>
  add    $0x16d,%ebx
  movslq %ebx,%rbx
  add    %rax,%rbx
  setne  %bl
  movzbl %bl,%ebx
  sub    $0x1,%ebp
  cmp    $0x7b2,%ebp
  jne    L11
L0:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x4,%ebx
  jmp    L0
```

assistant: ```c
int first_day(int year) {
  int ret = 4;
  for (; year > 1970; --year)
    ret = (ret + 365 + is_leap_year(year) ? 1 : 0) % 7;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<first_day>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x7b2,%edi
  jle    L17
  mov    %edi,%ebx
  mov    $0x4,%r12d
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%edi
  add    $0x16d,%r12d
  call   <is_leap_year@plt>
  movslq %r12d,%r12
  add    %rax,%r12
  setne  %r12b
  sub    $0x1,%ebx
  movzbl %r12b,%r12d
  cmp    $0x7b2,%ebx
  jne    L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x4,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int first_day(int year) {
  int ret = 4;
  for (; year > 1970; --year)
    ret = (ret + 365 + is_leap_year(year) ? 1 : 0) % 7;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<first_day>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x7b2,%edi
  jle    L5
  mov    %edi,%ebx
  mov    $0x4,%r12d
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%edi
  add    $0x16d,%r12d
  call   <is_leap_year@plt>
  movslq %r12d,%r12
  add    %rax,%r12
  setne  %r12b
  sub    $0x1,%ebx
  movzbl %r12b,%r12d
  cmp    $0x7b2,%ebx
  jne    L16
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x4,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int first_day(int year) {
  int ret = 4;
  for (; year > 1970; --year)
    ret = (ret + 365 + is_leap_year(year) ? 1 : 0) % 7;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_pipe_exist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <count_array@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L29:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x1,%eax
  jmp    L37
L11:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L29
  mov    $0x0,%eax
L37:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D5: |

assistant: ```c
int is_pipe_exist(char **cmdline) {
  int arguments_count = count_array(cmdline);
  int index = 0;
  for (; index < arguments_count; index++) {
    if (strcmp(cmdline[index], "|") == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_pipe_exist>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <count_array@plt>
  test   %eax,%eax
  jle    L31
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x8(%rbp,%rax,8),%r12
  lea    D8(%rip),%rbp
L30:
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L30
  mov    $0x0,%eax
  jmp    L6
L31:
  mov    $0x0,%eax
  jmp    L6
L34:
  mov    $0x1,%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: |

assistant: ```c
int is_pipe_exist(char **cmdline) {
  int arguments_count = count_array(cmdline);
  int index = 0;
  for (; index < arguments_count; index++) {
    if (strcmp(cmdline[index], "|") == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_pipe_exist>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <count_array@plt>
  test   %eax,%eax
  jle    L32
  sub    $0x1,%eax
  lea    D3(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  jmp    L16
  nopl   (%rax)
L11:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L32
L16:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L11
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: |

assistant: ```c
int is_pipe_exist(char **cmdline) {
  int arguments_count = count_array(cmdline);
  int index = 0;
  for (; index < arguments_count; index++) {
    if (strcmp(cmdline[index], "|") == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_pipe_exist>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <count_array@plt>
  test   %eax,%eax
  jle    L25
  sub    $0x1,%eax
  lea    D6(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  jmp    L1
  nopl   (%rax)
L20:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L25
L1:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L20
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: |

assistant: ```c
int is_pipe_exist(char **cmdline) {
  int arguments_count = count_array(cmdline);
  int index = 0;
  for (; index < arguments_count; index++) {
    if (strcmp(cmdline[index], "|") == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream) {
  size_t written = fwrite(ptr, size, nmemb, (FILE *)stream);
  return written;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_data>:
  endbr64
  sub    $0x8,%rsp
  call   <fwrite@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream) {
  size_t written = fwrite(ptr, size, nmemb, (FILE *)stream);
  return written;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_data>:
  endbr64
  jmp    1050 <fwrite@plt>
```

assistant: ```c
size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream) {
  size_t written = fwrite(ptr, size, nmemb, (FILE *)stream);
  return written;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_data>:
  endbr64
  jmp    1050 <fwrite@plt>
```

assistant: ```c
size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream) {
  size_t written = fwrite(ptr, size, nmemb, (FILE *)stream);
  return written;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strinsert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L53
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L51
L20:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L51:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L20
  jmp    L31
L53:
  cmpl   $0x0,-0x4(%rbp)
  jle    L31
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L42
L28:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x10(%rbp)
L42:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L28
L31:
  movl   $0x0,-0x10(%rbp)
  jmp    L29
L73:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L73
  nop
  leave
  ret
```

assistant: ```c
strinsert(char *a, char *b, int n) {
  int i, idiff, alen, blen;
  alen = strlen(a);
  blen = strlen(b);
  idiff = blen - n;
  if (idiff < 0)
    for (i = n; i <= alen; i++)
      a[i + idiff] = a[i];
  else if (idiff > 0)
    for (i = alen; i >= n; i--)
      a[i + idiff] = a[i];
  for (i = 0; i < blen; i++)
    a[i] = b[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strinsert>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %eax,%ecx
  sub    %r12d,%ecx
  js     L14
  test   %ecx,%ecx
  jle    L86
  cmp    %r12d,%r13d
  jl     L86
  movslq %r13d,%rdx
  lea    (%rbx,%rdx,1),%rax
  lea    -0x1(%rbx,%rdx,1),%rdi
  sub    %r12d,%r13d
  sub    %r13,%rdi
  movslq %ecx,%rcx
L19:
  movzbl (%rax),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rax
  cmp    %rdi,%rax
  jne    L19
  jmp    L86
L14:
  cmp    %r12d,%r13d
  jl     L86
  movslq %r12d,%rdx
  lea    (%rbx,%rdx,1),%rax
  lea    0x1(%rbx,%rdx,1),%rdx
  sub    %r12d,%r13d
  add    %rdx,%r13
  movslq %ecx,%rcx
L81:
  movzbl (%rax),%edx
  mov    %dl,(%rax,%rcx,1)
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L81
L86:
  mov    %esi,%ecx
  mov    $0x0,%eax
  test   %esi,%esi
  jle    L88
L11:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L11
L88:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
strinsert(char *a, char *b, int n) {
  int i, idiff, alen, blen;
  alen = strlen(a);
  blen = strlen(b);
  idiff = blen - n;
  if (idiff < 0)
    for (i = n; i <= alen; i++)
      a[i + idiff] = a[i];
  else if (idiff > 0)
    for (i = alen; i >= n; i--)
      a[i + idiff] = a[i];
  for (i = 0; i < blen; i++)
    a[i] = b[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strinsert>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %eax,%esi
  sub    %r12d,%eax
  js     L32
  je     L61
  cmp    %r12d,%r13d
  jl     L61
  movslq %r13d,%rcx
  sub    %r12d,%r13d
  cltq
  lea    -0x1(%rbx,%rcx,1),%rdi
  lea    (%rbx,%rcx,1),%rdx
  sub    %r13,%rdi
  nopl   0x0(%rax)
L83:
  movzbl (%rdx),%ecx
  sub    $0x1,%rdx
  mov    %cl,0x1(%rdx,%rax,1)
  cmp    %rdi,%rdx
  jne    L83
L61:
  movslq %esi,%rcx
  xor    %eax,%eax
  test   %esi,%esi
  jle    L80
  nopl   0x0(%rax)
L71:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L71
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L32:
  cmp    %r12d,%r13d
  jl     L61
  movslq %r12d,%rcx
  sub    %r12d,%r13d
  cltq
  lea    0x1(%rbx,%rcx,1),%rdi
  lea    (%rbx,%rcx,1),%rdx
  add    %r13,%rdi
  nopl   0x0(%rax)
L88:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx,%rax,1)
  cmp    %rdi,%rdx
  jne    L88
  jmp    L61
```

assistant: ```c
strinsert(char *a, char *b, int n) {
  int i, idiff, alen, blen;
  alen = strlen(a);
  blen = strlen(b);
  idiff = blen - n;
  if (idiff < 0)
    for (i = n; i <= alen; i++)
      a[i + idiff] = a[i];
  else if (idiff > 0)
    for (i = alen; i >= n; i--)
      a[i + idiff] = a[i];
  for (i = 0; i < blen; i++)
    a[i] = b[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ftpan_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xf0000fe0,%eax
  mov    (%rax),%eax
  movzbl %al,%eax
  cmp    $0x6,%eax
  jne    L34
  mov    $0xf0000fe4,%eax
  mov    (%rax),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L34
  mov    $0xf0000fe8,%eax
  mov    (%rax),%eax
  and    $0xf0,%eax
  cmp    $0x30,%eax
  jne    L34
  mov    $0xf0000fec,%eax
  mov    (%rax),%eax
  and    $0xf0,%eax
  test   %eax,%eax
  jne    L34
  mov    $0x1,%eax
  jmp    L20
L34:
  mov    $0x0,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
bool ftpan_32(void) {
  if ((((*(uint32_t *)0xF0000FE0) & 0x000000FF) == 0x6) && (((*(uint32_t *)0xF0000FE4) & 0x0000000F) == 0x0)) {
    if ((((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x30) && (((*(uint32_t *)0xF0000FEC) & 0x000000F0) == 0x0)) {
      return true;
    }
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ftpan_32>:
  endbr64
  mov    $0x0,%edx
  movabs 0xf0000fe0,%eax
  cmp    $0x6,%al
  je     L47
L21:
  mov    %edx,%eax
  ret
L47:
  movabs 0xf0000fe4,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  jne    L43
  movabs 0xf0000fe8,%eax
  and    $0xf0,%eax
  cmp    $0x30,%eax
  jne    L21
  movabs 0xf0000fec,%eax
  test   $0xf0,%al
  sete   %dl
  movzbl %dl,%edx
  jmp    L21
L43:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
bool ftpan_32(void) {
  if ((((*(uint32_t *)0xF0000FE0) & 0x000000FF) == 0x6) && (((*(uint32_t *)0xF0000FE4) & 0x0000000F) == 0x0)) {
    if ((((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x30) && (((*(uint32_t *)0xF0000FEC) & 0x000000F0) == 0x0)) {
      return true;
    }
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ftpan_32>:
  endbr64
  movabs 0xf0000fe0,%eax
  xor    %r8d,%r8d
  cmp    $0x6,%al
  je     L15
L37:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movabs 0xf0000fe4,%eax
  and    $0xf,%eax
  mov    %eax,%r8d
  jne    L18
  movabs 0xf0000fe8,%eax
  and    $0xf0,%eax
  cmp    $0x30,%eax
  jne    L37
  movabs 0xf0000fec,%eax
  xor    %r8d,%r8d
  test   $0xf0,%al
  sete   %r8b
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool ftpan_32(void) {
  if ((((*(uint32_t *)0xF0000FE0) & 0x000000FF) == 0x6) && (((*(uint32_t *)0xF0000FE4) & 0x0000000F) == 0x0)) {
    if ((((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x30) && (((*(uint32_t *)0xF0000FEC) & 0x000000F0) == 0x0)) {
      return true;
    }
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ftpan_32>:
  endbr64
  movabs 0xf0000fe0,%eax
  xor    %r8d,%r8d
  cmp    $0x6,%al
  je     L9
L32:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  movabs 0xf0000fe4,%eax
  and    $0xf,%eax
  mov    %eax,%r8d
  jne    L22
  movabs 0xf0000fe8,%eax
  and    $0xf0,%eax
  cmp    $0x30,%eax
  jne    L32
  movabs 0xf0000fec,%eax
  xor    %r8d,%r8d
  test   $0xf0,%al
  sete   %r8b
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool ftpan_32(void) {
  if ((((*(uint32_t *)0xF0000FE0) & 0x000000FF) == 0x6) && (((*(uint32_t *)0xF0000FE4) & 0x0000000F) == 0x0)) {
    if ((((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x30) && (((*(uint32_t *)0xF0000FEC) & 0x000000F0) == 0x0)) {
      return true;
    }
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<corpFlightBookings>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %ecx,%ebp
  mov    %r8,%r12
  lea    0x0(,%rcx,4),%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r15d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  test   %r13d,%r13d
  jle    L41
  mov    %r14,%rax
  lea    -0x1(%r13),%edx
  lea    0x8(%r14,%rdx,8),%rsi
  jmp    L63
L57:
  add    $0x8,%rax
  cmp    %rsi,%rax
  je     L41
L63:
  mov    (%rax),%rcx
  movslq (%rcx),%rdx
  mov    0x8(%rcx),%ecx
  add    %ecx,-0x4(%rbx,%rdx,4)
  mov    (%rax),%rcx
  mov    0x4(%rcx),%edx
  cmp    %ebp,%edx
  jge    L57
  movslq %edx,%rdx
  mov    0x8(%rcx),%ecx
  sub    %ecx,(%rbx,%rdx,4)
  jmp    L57
L41:
  cmp    $0x1,%ebp
  jle    L26
  lea    0x4(%rbx),%rax
  lea    -0x2(%rbp),%edx
  lea    0x8(%rbx,%rdx,4),%rcx
L13:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L13
L26:
  mov    %ebp,(%r12)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *corpFlightBookings(int **bookings, int bookingsSize, int *bookingsColSize, int n, int *returnSize) {
  int *ret = (int *)malloc(sizeof(int) * n);
  memset((char *)ret, 0, n * sizeof(int));
  for (int i = 0; i < bookingsSize; i++) {
    ret[bookings[i][0] - 1] += bookings[i][2];
    if (bookings[i][1] < n)
      ret[bookings[i][1]] -= bookings[i][2];
  }
  for (int i = 0; i < n - 1; i++)
    ret[i + 1] += ret[i];
  *returnSize = n;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<corpFlightBookings>:
  endbr64
  push   %r15
  lea    0x0(,%rcx,4),%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r15d,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r15d,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  test   %r14d,%r14d
  jle    L43
  lea    -0x1(%r14),%eax
  mov    %rbx,%rdx
  lea    0x8(%rbx,%rax,8),%rdi
  xchg   %ax,%ax
L15:
  mov    (%rdx),%rax
  movslq (%rax),%rcx
  mov    0x8(%rax),%esi
  add    %esi,-0x4(%r12,%rcx,4)
  movslq 0x4(%rax),%rcx
  cmp    %ebp,%ecx
  jge    L41
  mov    0x8(%rax),%eax
  sub    %eax,(%r12,%rcx,4)
L41:
  add    $0x8,%rdx
  cmp    %rdx,%rdi
  jne    L15
L43:
  cmp    $0x1,%ebp
  jle    L30
  lea    -0x2(%rbp),%edx
  lea    0x4(%r12),%rax
  lea    0x8(%r12,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L9
L30:
  mov    %ebp,0x0(%r13)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *corpFlightBookings(int **bookings, int bookingsSize, int *bookingsColSize, int n, int *returnSize) {
  int *ret = (int *)malloc(sizeof(int) * n);
  memset((char *)ret, 0, n * sizeof(int));
  for (int i = 0; i < bookingsSize; i++) {
    ret[bookings[i][0] - 1] += bookings[i][2];
    if (bookings[i][1] < n)
      ret[bookings[i][1]] -= bookings[i][2];
  }
  for (int i = 0; i < n - 1; i++)
    ret[i + 1] += ret[i];
  *returnSize = n;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<corpFlightBookings>:
  endbr64
  push   %r15
  lea    0x0(,%rcx,4),%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r15d,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r15d,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  test   %r14d,%r14d
  jle    L35
  lea    -0x1(%r14),%eax
  mov    %rbx,%rdx
  lea    0x8(%rbx,%rax,8),%rdi
  xchg   %ax,%ax
L5:
  mov    (%rdx),%rax
  movslq (%rax),%rcx
  mov    0x8(%rax),%esi
  add    %esi,-0x4(%r12,%rcx,4)
  movslq 0x4(%rax),%rcx
  cmp    %ebp,%ecx
  jge    L41
  mov    0x8(%rax),%eax
  sub    %eax,(%r12,%rcx,4)
L41:
  add    $0x8,%rdx
  cmp    %rdx,%rdi
  jne    L5
L35:
  cmp    $0x1,%ebp
  jle    L1
  lea    -0x2(%rbp),%ecx
  mov    (%r12),%edx
  lea    0x4(%r12),%rax
  lea    0x8(%r12,%rcx,4),%rcx
  nopl   0x0(%rax)
L26:
  add    (%rax),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L26
L1:
  mov    %ebp,0x0(%r13)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *corpFlightBookings(int **bookings, int bookingsSize, int *bookingsColSize, int n, int *returnSize) {
  int *ret = (int *)malloc(sizeof(int) * n);
  memset((char *)ret, 0, n * sizeof(int));
  for (int i = 0; i < bookingsSize; i++) {
    ret[bookings[i][0] - 1] += bookings[i][2];
    if (bookings[i][1] < n)
      ret[bookings[i][1]] -= bookings[i][2];
  }
  for (int i = 0; i < n - 1; i++)
    ret[i + 1] += ret[i];
  *returnSize = n;
  return ret;
}
```