ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    $0x0,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L14
L40:
  cmpb   $0x30,(%rsp)
  je     L2
  lea    D11(%rip),%rdi
  call   <printf@plt>
L33:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L14:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L40
L2:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D2
datatype: string

tool: D11: A non-zero value? How quaint!


tool: D24: Hum?


tool: D2: Looks like a zero to me!


assistant: ```c
int main(int argc, char **argv) {
  char buf[8];
  if (read(0, buf, 8) < 1) {
    printf("Hum?\n");
    exit(1);
  }
  if (buf[0] == '0')
    printf("Looks like a zero to me!\n");
  else
    printf("A non-zero value? How quaint!\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <read@plt>
  test   %eax,%eax
  jle    L17
L23:
  cmpb   $0x30,(%rsp)
  je     L9
  lea    D20(%rip),%rdi
  call   <printf@plt>
L38:
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L38
L17:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L23
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D20
data_type: string
name: parse_data
arguments: data_tag: D23
data_type: string
name: parse_data
arguments: data_tag: D7
data_type: string

tool: D20: A non-zero value? How quaint!


tool: D23: Looks like a zero to me!


tool: D7: Hum?


assistant: ```c
int main(int argc, char **argv) {
  char buf[8];
  if (read(0, buf, 8) < 1) {
    printf("Hum?\n");
    exit(1);
  }
  if (buf[0] == '0')
    printf("Looks like a zero to me!\n");
  else
    printf("A non-zero value? How quaint!\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <read@plt>
  test   %eax,%eax
  jle    L15
L32:
  cmpb   $0x30,(%rsp)
  je     L27
  lea    D2(%rip),%rdi
  call   <printf@plt>
L33:
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L27:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L15:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L32
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D5
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string

tool: D2: A non-zero value? How quaint!


tool: D5: Looks like a zero to me!


tool: D8: Hum?


assistant: ```c
int main(int argc, char **argv) {
  char buf[8];
  if (read(0, buf, 8) < 1) {
    printf("Hum?\n");
    exit(1);
  }
  if (buf[0] == '0')
    printf("Looks like a zero to me!\n");
  else
    printf("A non-zero value? How quaint!\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  imul   $0xfb16,%ax,%ax
  sub    $0x2e4,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  lea    0x5b59(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy13;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        state[local1] += state[local1];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        state[local1] = state[0UL] - state[local1];
      } else {
        copy15 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy15;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 549183897UL) + (unsigned short)31168;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  add    $0x5875,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy13;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        state[local1] += state[local1];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        state[local1] = state[0UL] - state[local1];
      } else {
        copy15 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy15;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 549183897UL) + (unsigned short)31168;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  add    $0x5875,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy13;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        state[local1] += state[local1];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        state[local1] = state[0UL] - state[local1];
      } else {
        copy15 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy15;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 549183897UL) + (unsigned short)31168;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  add    $0x5875,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy13;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        state[local1] += state[local1];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        state[local1] = state[0UL] - state[local1];
      } else {
        copy15 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy15;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 549183897UL) + (unsigned short)31168;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<vp8cx_vertical_band_1_2_scale_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  shr    %eax
  mov    %eax,%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jb     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vp8cx_vertical_band_1_2_scale_c(unsigned char *dest, unsigned int dest_pitch, unsigned int dest_width) {
  unsigned int i;
  unsigned int a, b;
  unsigned char *des = dest;
  for (i = 0; i < dest_width; i++) {
    a = des[0];
    b = des[dest_pitch * 2];
    des[dest_pitch] = (unsigned char)((a + b + 1) >> 1);
    des++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vp8cx_vertical_band_1_2_scale_c>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L4
  lea    (%rsi,%rsi,1),%r8d
  mov    %r8d,%r8d
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%rdi
  mov    %esi,%esi
L12:
  movzbl (%rax),%ecx
  movzbl (%rax,%r8,1),%edx
  lea    0x1(%rcx,%rdx,1),%edx
  shr    %edx
  mov    %dl,(%rax,%rsi,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L12
L4:
  ret
```

assistant: ```c
void vp8cx_vertical_band_1_2_scale_c(unsigned char *dest, unsigned int dest_pitch, unsigned int dest_width) {
  unsigned int i;
  unsigned int a, b;
  unsigned char *des = dest;
  for (i = 0; i < dest_width; i++) {
    a = des[0];
    b = des[dest_pitch * 2];
    des[dest_pitch] = (unsigned char)((a + b + 1) >> 1);
    des++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vp8cx_vertical_band_1_2_scale_c>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%edi
  lea    (%rsi,%rsi,1),%r8d
  mov    %esi,%esi
  add    %rax,%rdi
  test   %edx,%edx
  je     L15
  cs nopw 0x0(%rax,%rax,1)
L2:
  movzbl (%rax),%ecx
  movzbl (%rax,%r8,1),%edx
  add    $0x1,%rax
  lea    0x1(%rcx,%rdx,1),%edx
  shr    %edx
  mov    %dl,-0x1(%rax,%rsi,1)
  cmp    %rdi,%rax
  jne    L2
L15:
  ret
```

assistant: ```c
void vp8cx_vertical_band_1_2_scale_c(unsigned char *dest, unsigned int dest_pitch, unsigned int dest_width) {
  unsigned int i;
  unsigned int a, b;
  unsigned char *des = dest;
  for (i = 0; i < dest_width; i++) {
    a = des[0];
    b = des[dest_pitch * 2];
    des[dest_pitch] = (unsigned char)((a + b + 1) >> 1);
    des++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L28
L53:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L3
L55:
  mov    $0x1,%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    $0xffffffff,%eax
  cltd
  idiv   %ecx
  add    %esi,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x2,-0x10(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L55
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L57
  mov    -0x18(%rbp),%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
L57:
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L53
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D26
datatype: string

tool: D5: %d

tool: D26: %.1f


assistant: ```c
int main() {
  int m, n, i, j;
  float sum;
  scanf("%d", &m);
  for (i = 0; i != m; ++i) {
    sum = 0;
    scanf("%d", &n);
    for (j = 1; j < n; j += 2) {
      sum += 1 / j - 1 / (j + 1);
    }
    if (n % 2)
      sum += 1 / n;
    printf("%.1f\n", sum);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  je     L19
  mov    $0x0,%ebp
  lea    0x4(%rsp),%r14
  lea    D5(%rip),%r13
  mov    $0xffffffff,%ebx
  lea    D7(%rip),%r12
  jmp    L69
L26:
  pxor   %xmm0,%xmm0
  jmp    L60
L11:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,(%rsp)
  je     L19
L69:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  cmp    $0x1,%r8d
  jle    L26
  pxor   %xmm0,%xmm0
  mov    $0x1,%ecx
  mov    $0x1,%edi
L16:
  lea    0x1(%rcx),%esi
  mov    %ebx,%eax
  cltd
  idiv   %esi
  mov    %eax,%esi
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %eax,%esi
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  addss  %xmm1,%xmm0
  add    $0x2,%ecx
  cmp    %r8d,%ecx
  jl     L16
L60:
  test   $0x1,%r8b
  je     L11
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  addss  %xmm1,%xmm0
  jmp    L11
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string
name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D5: %d

tool: D7: %.1f


assistant: ```c
int main() {
  int m, n, i, j;
  float sum;
  scanf("%d", &m);
  for (i = 0; i != m; ++i) {
    sum = 0;
    scanf("%d", &n);
    for (j = 1; j < n; j += 2) {
      sum += 1 / j - 1 / (j + 1);
    }
    if (n % 2)
      sum += 1 / n;
    printf("%.1f\n", sum);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L42
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r14
  mov    $0x1,%ebx
  lea    D19(%rip),%r13
  nopl   0x0(%rax)
L1:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  pxor   %xmm0,%xmm0
  cmp    $0x1,%esi
  jle    L13
  mov    $0x1,%ecx
  nopl   (%rax)
L43:
  mov    %ebx,%eax
  pxor   %xmm1,%xmm1
  cltd
  idiv   %ecx
  add    $0x2,%ecx
  cvtsi2ss %eax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %esi,%ecx
  jl     L43
L13:
  test   $0x1,%sil
  je     L46
  mov    %ebx,%eax
  pxor   %xmm1,%xmm1
  cltd
  idiv   %esi
  cvtsi2ss %eax,%xmm1
  addss  %xmm1,%xmm0
L46:
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,(%rsp)
  jne    L1
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D19
type: string

tool: D12: %d

tool: D19: %.1f


assistant: ```c
int main() {
  int m, n, i, j;
  float sum;
  scanf("%d", &m);
  for (i = 0; i != m; ++i) {
    sum = 0;
    scanf("%d", &n);
    for (j = 1; j < n; j += 2) {
      sum += 1 / j - 1 / (j + 1);
    }
    if (n % 2)
      sum += 1 / n;
    printf("%.1f\n", sum);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L29
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r14
  mov    $0x1,%ebx
  lea    D9(%rip),%r13
  nopl   0x0(%rax)
L23:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  pxor   %xmm0,%xmm0
  cmp    $0x1,%esi
  jle    L47
  mov    $0x1,%ecx
  nopl   (%rax)
L34:
  mov    %ebx,%eax
  pxor   %xmm1,%xmm1
  cltd
  idiv   %ecx
  add    $0x2,%ecx
  cvtsi2ss %eax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %esi,%ecx
  jl     L34
L47:
  test   $0x1,%sil
  je     L31
  mov    %ebx,%eax
  pxor   %xmm1,%xmm1
  cltd
  idiv   %esi
  cvtsi2ss %eax,%xmm1
  addss  %xmm1,%xmm0
L31:
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,(%rsp)
  jne    L23
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D11: %d

tool: D9: %.1f


assistant: ```c
int main() {
  int m, n, i, j;
  float sum;
  scanf("%d", &m);
  for (i = 0; i != m; ++i) {
    sum = 0;
    scanf("%d", &n);
    for (j = 1; j < n; j += 2) {
      sum += 1 / j - 1 / (j + 1);
    }
    if (n % 2)
      sum += 1 / n;
    printf("%.1f\n", sum);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D2(%rip),%eax
  movd   %eax,%xmm0
  call   <testf@plt>
  test   %eax,%eax
  jg     L3
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  mov    D7(%rip),%rax
  movq   %rax,%xmm0
  call   <test@plt>
  test   %eax,%eax
  jg     L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  fldt   0xe4d(%rip)        # 2010 <_fini+0xe24>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <testl@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  jg     L18
  mov    $0x0,%eax
  call   <abort@plt>
L18:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: byte[4]
name: unpack_data
arguments: tag: D7
type_infered: byte[8]

tool: {"D2": [0xff,0xff,0x7f,0x7f]}

tool: {"D7": [0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

assistant: ```c
int main() {
  if (testf(3.40282346638528859811704183484516925e+38F) < 1)
    abort();
  if (test(((double)1.79769313486231570814527423731704357e+308L)) < 1)
    abort();
  if (testl(1.18973149535723176502126385303097021e+4932L) < 1)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D14(%rip),%xmm0
  call   <testf@plt>
  test   %eax,%eax
  jle    L44
L26:
  movsd  D17(%rip),%xmm0
  call   <test@plt>
  test   %eax,%eax
  jle    L34
L8:
  push   $0x7ffe
  push   $0xffffffffffffffff
  call   <testl@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  jle    L11
L31:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L44:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L26
L34:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L8
L11:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L31
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: byte[4]
name: unpack_data
arguments: data_label: D17
type_infered: byte[8]

tool: {"D14": [0xff,0xff,0x7f,0x7f]}

tool: {"D17": [0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

assistant: ```c
int main() {
  if (testf(3.40282346638528859811704183484516925e+38F) < 1)
    abort();
  if (test(((double)1.79769313486231570814527423731704357e+308L)) < 1)
    abort();
  if (testl(1.18973149535723176502126385303097021e+4932L) < 1)
    abort();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D17(%rip),%xmm0
  call   <testf@plt>
  test   %eax,%eax
  jle    L41
L46:
  movsd  D15(%rip),%xmm0
  call   <test@plt>
  test   %eax,%eax
  jle    L1
L51:
  push   $0x7ffe
  push   $0xffffffffffffffff
  call   <testl@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  jle    L2
L15:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L41:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L46
L2:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L15
L1:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L51
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: byte[4]
name: parse_data
arguments: data_tag: D15
type_infered: byte[8]

tool: {"D17": [0xff,0xff,0x7f,0x7f]}

tool: {"D15": [0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

assistant: ```c
int main() {
  if (testf(3.40282346638528859811704183484516925e+38F) < 1)
    abort();
  if (test(((double)1.79769313486231570814527423731704357e+308L)) < 1)
    abort();
  if (testl(1.18973149535723176502126385303097021e+4932L) < 1)
    abort();
  return 0;
}
```