ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<pkcs7_depadding_blocksize>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <pkcs7_depadding@plt>
  test   %eax,%eax
  jne    L11
L19:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  movzbl %bl,%esi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <pkcs7_padding_plus_len@plt>
  test   %al,%al
  je     L19
  lea    -0x1(%r13),%edx
  movzbl 0x0(%rbp,%rdx,1),%edx
  test   %dl,%dl
  je     L19
  cmp    %dl,%al
  jne    L19
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int pkcs7_depadding_blocksize(const void *_data, unsigned int _datapaddinglen, unsigned char _blocksize) {
  unsigned int data_depadding_len = 0;
  unsigned char verify_plus_len = 0;
  unsigned char plus_len = 0;
  data_depadding_len = pkcs7_depadding(_data, _datapaddinglen);
  if (0 == data_depadding_len)
    return 0;
  verify_plus_len = pkcs7_padding_plus_len(data_depadding_len, _blocksize);
  if (0 == verify_plus_len)
    return 0;
  plus_len = ((const unsigned char *)_data)[_datapaddinglen - 1];
  if (0 == plus_len)
    return 0;
  if (verify_plus_len != plus_len)
    return 0;
  return data_depadding_len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pkcs7_depadding_blocksize>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <pkcs7_depadding@plt>
  test   %eax,%eax
  jne    L2
L29:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  movzbl %bl,%esi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <pkcs7_padding_plus_len@plt>
  test   %al,%al
  je     L29
  lea    -0x1(%r13),%edx
  movzbl 0x0(%rbp,%rdx,1),%edx
  test   %dl,%dl
  je     L29
  cmp    %dl,%al
  jne    L29
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int pkcs7_depadding_blocksize(const void *_data, unsigned int _datapaddinglen, unsigned char _blocksize) {
  unsigned int data_depadding_len = 0;
  unsigned char verify_plus_len = 0;
  unsigned char plus_len = 0;
  data_depadding_len = pkcs7_depadding(_data, _datapaddinglen);
  if (0 == data_depadding_len)
    return 0;
  verify_plus_len = pkcs7_padding_plus_len(data_depadding_len, _blocksize);
  if (0 == verify_plus_len)
    return 0;
  plus_len = ((const unsigned char *)_data)[_datapaddinglen - 1];
  if (0 == plus_len)
    return 0;
  if (verify_plus_len != plus_len)
    return 0;
  return data_depadding_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<findColon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L12
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L31
L12:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
char *findColon(char *transSpec) {
  int k;
  for (k = 0; transSpec[k]; k++)
    if (transSpec[k] == ':') {
      transSpec[k] = 0;
      return &transSpec[k + 1];
    }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findColon>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L28
  mov    $0x0,%eax
L7:
  lea    (%rdi,%rax,1),%rcx
  cmp    $0x3a,%dl
  je     L26
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L7
  mov    $0x0,%eax
  ret
L26:
  movb   $0x0,(%rcx)
  lea    0x1(%rdi,%rax,1),%rax
  ret
L28:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *findColon(char *transSpec) {
  int k;
  for (k = 0; transSpec[k]; k++)
    if (transSpec[k] == ':') {
      transSpec[k] = 0;
      return &transSpec[k + 1];
    }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<findColon>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L14
  jmp    L0
  nop
L1:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L5
L14:
  lea    (%rdi,%rax,1),%rcx
  cmp    $0x3a,%dl
  jne    L1
  movb   $0x0,(%rcx)
  lea    0x1(%rdi,%rax,1),%rax
  ret
  xchg   %ax,%ax
L5:
  xor    %eax,%eax
  ret
L0:
  ret
```

assistant: ```c
char *findColon(char *transSpec) {
  int k;
  for (k = 0; transSpec[k]; k++)
    if (transSpec[k] == ':') {
      transSpec[k] = 0;
      return &transSpec[k + 1];
    }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findColon>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L7
  jmp    L1
  nop
L10:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L14
L7:
  lea    (%rdi,%rax,1),%rcx
  cmp    $0x3a,%dl
  jne    L10
  movb   $0x0,(%rcx)
  lea    0x1(%rdi,%rax,1),%rax
  ret
  xchg   %ax,%ax
L14:
  xor    %eax,%eax
  ret
L1:
  ret
```

assistant: ```c
char *findColon(char *transSpec) {
  int k;
  for (k = 0; transSpec[k]; k++)
    if (transSpec[k] == ':') {
      transSpec[k] = 0;
      return &transSpec[k + 1];
    }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L25:
  cmpb   $0xa,-0xd(%rbp)
  je     L27
  movsbl -0xd(%rbp),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <checkLetter@plt>
L21:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L25
  jmp    L3
L27:
  nop
L3:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  char ch;
  int counter = 0;
  while (ch = getchar()) {
    if (ch != '\n') {
      checkLetter(ch, &counter);
    } else {
      break;
    }
  }
  printf("%d", counter);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
L21:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L2
  test   %al,%al
  je     L2
  movsbl %al,%edi
  mov    %rbx,%rsi
  call   <checkLetter@plt>
  jmp    L21
L2:
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: %d

assistant: ```c
int main() {
  char ch;
  int counter = 0;
  while (ch = getchar()) {
    if (ch != '\n') {
      checkLetter(ch, &counter);
    } else {
      break;
    }
  }
  printf("%d", counter);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  movl   $0x0,0x4(%rsp)
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L12:
  cmp    $0xa,%al
  je     L15
  movsbl %al,%edi
  mov    %rbx,%rsi
  call   <checkLetter@plt>
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  test   %al,%al
  jne    L12
L15:
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: %d

assistant: ```c
int main() {
  char ch;
  int counter = 0;
  while (ch = getchar()) {
    if (ch != '\n') {
      checkLetter(ch, &counter);
    } else {
      break;
    }
  }
  printf("%d", counter);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  movl   $0x0,0x4(%rsp)
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L36:
  cmp    $0xa,%al
  je     L10
  movsbl %al,%edi
  mov    %rbx,%rsi
  call   <checkLetter@plt>
L7:
  xor    %eax,%eax
  call   <getchar@plt>
  test   %al,%al
  jne    L36
L10:
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: %d

assistant: ```c
int main() {
  char ch;
  int counter = 0;
  while (ch = getchar()) {
    if (ch != '\n') {
      checkLetter(ch, &counter);
    } else {
      break;
    }
  }
  printf("%d", counter);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L40
L31:
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L40:
  cmpl   $0x6,-0x34(%rbp)
  jle    L31
  movl   $0x0,-0x34(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  jmp    L10
L41:
  mov    -0x38(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L10:
  cmpl   $0x0,-0x38(%rbp)
  jne    L41
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x6,-0x34(%rbp)
  jmp    L66
L52:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x34(%rbp)
L66:
  cmpl   $0x0,-0x34(%rbp)
  jns    L52
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D33
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D13: Enter The Number: 

tool: D33: %d

tool: D11: Number In Binary: 

assistant: ```c
void main() {
  int n, temp, i;
  int bin[10];
  printf("Enter The Number: \n");
  scanf("%d", &n);
  for (i = 0; i < 7; i++)
    bin[i] = 0;
  i = 0;
  temp = n;
  while (temp != 0) {
    bin[i] = temp % 2;
    temp = temp / 2;
    i++;
  }
  printf("Number In Binary: ");
  for (i = 6; i >= 0; i--)
    printf("%d", bin[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  je     L18
  lea    0x10(%rsp),%rcx
L20:
  mov    %edx,%esi
  shr    $0x1f,%esi
  lea    (%rdx,%rsi,1),%eax
  and    $0x1,%eax
  sub    %esi,%eax
  mov    %eax,(%rcx)
  mov    %esi,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  add    $0x4,%rcx
  test   %eax,%eax
  jne    L20
L18:
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%r12
  lea    0x28(%rsp),%rbx
  lea    D26(%rip),%rbp
L21:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  sub    $0x4,%rbx
  cmp    %r12,%rax
  jne    L21
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D26
type: string
name: retrieve_data
arguments: label: D4
type: string

tool: D11: Enter The Number: 

tool: D26: %d

tool: D4: Number In Binary: 

assistant: ```c
void main() {
  int n, temp, i;
  int bin[10];
  printf("Enter The Number: \n");
  scanf("%d", &n);
  for (i = 0; i < 7; i++)
    bin[i] = 0;
  i = 0;
  temp = n;
  while (temp != 0) {
    bin[i] = temp % 2;
    temp = temp / 2;
    i++;
  }
  printf("Number In Binary: ");
  for (i = 6; i >= 0; i--)
    printf("%d", bin[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D27(%rip),%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  movl   $0x0,0x28(%rsp)
  mov    %rbp,%rcx
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  test   %eax,%eax
  je     L3
  nop
L13:
  mov    %eax,%esi
  add    $0x4,%rcx
  shr    $0x1f,%esi
  lea    (%rax,%rsi,1),%edx
  add    %esi,%eax
  and    $0x1,%edx
  sub    %esi,%edx
  mov    %edx,-0x4(%rcx)
  sar    %eax
  jne    L13
L3:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  lea    0x28(%rsp),%r12
  call   <printf@plt>
  nopl   (%rax)
L8:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rax
  sub    $0x4,%r12
  cmp    %rbp,%rax
  jne    L8
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string

tool: D19: Enter The Number: 

tool: D27: %d

tool: D14: Number In Binary: 

assistant: ```c
void main() {
  int n, temp, i;
  int bin[10];
  printf("Enter The Number: \n");
  scanf("%d", &n);
  for (i = 0; i < 7; i++)
    bin[i] = 0;
  i = 0;
  temp = n;
  while (temp != 0) {
    bin[i] = temp % 2;
    temp = temp / 2;
    i++;
  }
  printf("Number In Binary: ");
  for (i = 6; i >= 0; i--)
    printf("%d", bin[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  pxor   %xmm0,%xmm0
  movq   $0x0,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  movaps %xmm0,0x10(%rsp)
  test   %edx,%edx
  je     L42
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,0x10(%rsp)
  mov    %ecx,%eax
  add    %edx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L42
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x14(%rsp)
  add    %ecx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L42
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x18(%rsp)
  add    %ecx,%eax
  sar    %eax
  je     L42
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  je     L42
  cltd
  idiv   %ecx
  mov    %edx,0x20(%rsp)
  test   %eax,%eax
  je     L42
  cltd
  idiv   %ecx
  mov    %edx,0x24(%rsp)
  test   %eax,%eax
  je     L42
  cltd
  idiv   %ecx
  mov    %edx,0x28(%rsp)
  test   %eax,%eax
  je     L42
  cltd
  idiv   %ecx
  mov    %edx,0x2c(%rsp)
  test   %eax,%eax
  je     L42
  cltd
  idiv   %ecx
  mov    %edx,0x30(%rsp)
L42:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  lea    0x28(%rsp),%rbx
  xchg   %ax,%ax
L38:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  sub    $0x4,%rbx
  cmp    %rax,%r12
  jne    L38
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L91
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L91:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
type_infered: string
name: unpack_data
arguments: tag: D20
type_infered: string
name: unpack_data
arguments: tag: D6
type_infered: string

tool: D24: Enter The Number: 

tool: D20: %d

tool: D6: Number In Binary: 

assistant: ```c
void main() {
  int n, temp, i;
  int bin[10];
  printf("Enter The Number: \n");
  scanf("%d", &n);
  for (i = 0; i < 7; i++)
    bin[i] = 0;
  i = 0;
  temp = n;
  while (temp != 0) {
    bin[i] = temp % 2;
    temp = temp / 2;
    i++;
  }
  printf("Number In Binary: ");
  for (i = 6; i >= 0; i--)
    printf("%d", bin[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<exist_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L23
  mov    $0x0,%eax
  jmp    L21
L23:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L25
  mov    $0x0,%eax
  jmp    L21
L25:
  mov    $0x1,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int exist_file(char *path) {
  struct stat st;
  if (stat(path, &st) != 0) {
    return 0;
  }
  mode_t m = st.st_mode;
  if (S_ISDIR(m)) {
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<exist_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L12
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L12:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L16
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exist_file(char *path) {
  struct stat st;
  if (stat(path, &st) != 0) {
    return 0;
  }
  mode_t m = st.st_mode;
  if (S_ISDIR(m)) {
    return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exist_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L10
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exist_file(char *path) {
  struct stat st;
  if (stat(path, &st) != 0) {
    return 0;
  }
  mode_t m = st.st_mode;
  if (S_ISDIR(m)) {
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<exist_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L19
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exist_file(char *path) {
  struct stat st;
  if (stat(path, &st) != 0) {
    return 0;
  }
  mode_t m = st.st_mode;
  if (S_ISDIR(m)) {
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<haspercent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L3
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L2
  mov    $0x1,%eax
  jmp    L21
L2:
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int haspercent(char *s) {
  for (; *s; ++s)
    if (*s == '%')
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<haspercent>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
L15:
  cmp    $0x25,%al
  je     L3
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L15
  mov    $0x0,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int haspercent(char *s) {
  for (; *s; ++s)
    if (*s == '%')
      return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<haspercent>:
  endbr64
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L9:
  cmp    $0x25,%al
  je     L26
  add    $0x1,%rdi
L4:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L9
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int haspercent(char *s) {
  for (; *s; ++s)
    if (*s == '%')
      return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<haspercent>:
  endbr64
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L2:
  cmp    $0x25,%al
  je     L0
  add    $0x1,%rdi
L3:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int haspercent(char *s) {
  for (; *s; ++s)
    if (*s == '%')
      return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unmarshal_opaque>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L17
L2:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int unmarshal_opaque(unsigned char *data, unsigned char **in, size_t *size) {
  if (*size < 1)
    return -1;
  *data = *(*in);
  (*size) -= 1;
  (*in) += 1;
  return 0;
}
```