ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  je     L20
  nopl   0x0(%rax,%rax,1)
L8:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L20
  cmp    $0x3,%eax
  jle    L69
  mov    $0x2,%r14d
  xor    %ebp,%ebp
  jmp    L57
  nop
L55:
  mov    0x4(%rsp),%edx
  add    $0x1,%r14d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %r14d,%eax
  jl     L60
L57:
  mov    %r14d,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L55
  mov    0x4(%rsp),%edi
  sub    %r14d,%edi
  call   <isprime@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L69:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  jne    L8
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D10
data_type: string

tool: D15: %d


tool: D10: %d

assistant: ```c
int main() {
  int n, count, i;
  while (scanf("%d", &n) != -1) {
    if (!n)
      break;
    count = 0;
    for (i = 2; i <= n / 2; i++)
      if (isprime(i) && isprime(n - i))
        count++;
    printf("%d\n", count);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x22,%edi
  call   <expect_ch@plt>
  jmp    L10
L9:
  mov    $0x0,%eax
  call   <append@plt>
L10:
  mov    $0x0,%eax
  call   <current@plt>
  cmp    $0x22,%al
  jne    L9
  mov    $0x22,%edi
  call   <expect_ch@plt>
  mov    $0x5,%eax
  pop    %rbp
  ret
```

assistant: ```c
int string(void) {
  expect_ch('"');
  while ('"' != current())
    append();
  expect_ch('"');
  return 5;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x22,%edi
  call   <expect_ch@plt>
  jmp    L1
L10:
  mov    $0x0,%eax
  call   <append@plt>
L1:
  mov    $0x0,%eax
  call   <current@plt>
  cmp    $0x22,%al
  jne    L10
  mov    $0x22,%edi
  call   <expect_ch@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int string(void) {
  expect_ch('"');
  while ('"' != current())
    append();
  expect_ch('"');
  return 5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x22,%edi
  call   <expect_ch@plt>
  jmp    L0
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  call   <append@plt>
L0:
  xor    %eax,%eax
  call   <current@plt>
  cmp    $0x22,%al
  jne    L17
  mov    $0x22,%edi
  call   <expect_ch@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int string(void) {
  expect_ch('"');
  while ('"' != current())
    append();
  expect_ch('"');
  return 5;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<string>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x22,%edi
  call   <expect_ch@plt>
  jmp    L12
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  call   <append@plt>
L12:
  xor    %eax,%eax
  call   <current@plt>
  cmp    $0x22,%al
  jne    L16
  mov    $0x22,%edi
  call   <expect_ch@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int string(void) {
  expect_ch('"');
  while ('"' != current())
    append();
  expect_ch('"');
  return 5;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,-0x18(%rbp)
  jmp    L15
L32:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <insertnode@plt>
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L15:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L32
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printnode@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jne    L28
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse_list@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printnode@plt>
L28:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D30
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string

tool: D28: How much elements you want in your list.

tool: D30:  %d

tool: D1: Do you want to reverse it? [1 for yes/ 0 for no]

assistant: ```c
int main(void) {
  struct node *head = NULL;
  int len, val;
  puts("How much elements you want in your list.");
  scanf(" %d", &len);
  srand(time(NULL));
  for (int i = 1; i <= len; i++) {
    val = rand() % 10;
    head = insertnode(val, i, head);
  }
  printnode(head);
  int userEnt;
  puts("Do you want to reverse it? [1 for yes/ 0 for no]");
  scanf(" %d", &userEnt);
  if (userEnt == 1) {
    head = reverse_list(head);
    printnode(head);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  cmpl   $0x0,(%rsp)
  jle    L27
  mov    $0x1,%ebp
  mov    $0x0,%ebx
L39:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%edi
  mov    %rbx,%rdx
  mov    %ebp,%esi
  call   <insertnode@plt>
  mov    %rax,%rbx
  add    $0x1,%ebp
  cmp    %ebp,(%rsp)
  jge    L39
L36:
  mov    %rbx,%rdi
  call   <printnode@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L51
L59:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    $0x0,%ebx
  jmp    L36
L51:
  mov    %rbx,%rdi
  call   <reverse_list@plt>
  mov    %rax,%rdi
  call   <printnode@plt>
  jmp    L59
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D9
data_type: string

tool: D31: How much elements you want in your list.

tool: D10:  %d

tool: D9: Do you want to reverse it? [1 for yes/ 0 for no]

assistant: ```c
int main(void) {
  struct node *head = NULL;
  int len, val;
  puts("How much elements you want in your list.");
  scanf(" %d", &len);
  srand(time(NULL));
  for (int i = 1; i <= len; i++) {
    val = rand() % 10;
    head = insertnode(val, i, head);
  }
  printnode(head);
  int userEnt;
  puts("Do you want to reverse it? [1 for yes/ 0 for no]");
  scanf(" %d", &userEnt);
  if (userEnt == 1) {
    head = reverse_list(head);
    printnode(head);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L7
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebx,%esi
  add    $0x1,%ebx
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %r12,%rdx
  mov    %eax,%edi
  call   <insertnode@plt>
  mov    %rax,%r12
  cmp    %ebx,(%rsp)
  jge    L10
L0:
  mov    %r12,%rdi
  call   <printnode@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L43
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    %r12,%rdi
  call   <reverse_list@plt>
  mov    %rax,%rdi
  call   <printnode@plt>
  jmp    L42
L7:
  xor    %r12d,%r12d
  jmp    L0
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string
name: retrieve_data
arguments: data_tag: D4
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D2: How much elements you want in your list.

tool: D4:  %d

tool: D6: Do you want to reverse it? [1 for yes/ 0 for no]

assistant: ```c
int main(void) {
  struct node *head = NULL;
  int len, val;
  puts("How much elements you want in your list.");
  scanf(" %d", &len);
  srand(time(NULL));
  for (int i = 1; i <= len; i++) {
    val = rand() % 10;
    head = insertnode(val, i, head);
  }
  printnode(head);
  int userEnt;
  puts("Do you want to reverse it? [1 for yes/ 0 for no]");
  scanf(" %d", &userEnt);
  if (userEnt == 1) {
    head = reverse_list(head);
    printnode(head);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L31
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L40:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebx,%esi
  add    $0x1,%ebx
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %r12,%rdx
  mov    %eax,%edi
  call   <insertnode@plt>
  mov    %rax,%r12
  cmp    %ebx,(%rsp)
  jge    L40
L4:
  mov    %r12,%rdi
  call   <printnode@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L6
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    %r12,%rdi
  call   <reverse_list@plt>
  mov    %rax,%rdi
  call   <printnode@plt>
  jmp    L1
L31:
  xor    %r12d,%r12d
  jmp    L4
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D15
data_type: string
name: disassemble_data
arguments: tag: D14
data_type: string

tool: D1: How much elements you want in your list.

tool: D15:  %d

tool: D14: Do you want to reverse it? [1 for yes/ 0 for no]

assistant: ```c
int main(void) {
  struct node *head = NULL;
  int len, val;
  puts("How much elements you want in your list.");
  scanf(" %d", &len);
  srand(time(NULL));
  for (int i = 1; i <= len; i++) {
    val = rand() % 10;
    head = insertnode(val, i, head);
  }
  printnode(head);
  int userEnt;
  puts("Do you want to reverse it? [1 for yes/ 0 for no]");
  scanf(" %d", &userEnt);
  if (userEnt == 1) {
    head = reverse_list(head);
    printnode(head);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nocompute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %esi,%eax
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9,%rcx
  imul   -0x14(%rbp),%eax
  mov    %eax,%r12d
  cmpl   $0x1,-0x18(%rbp)
  jg     L26
  cmpl   $0xffffffff,-0x18(%rbp)
  jl     L26
  cmpl   $0x1,-0x1c(%rbp)
  jg     L26
  cmpl   $0xffffffff,-0x1c(%rbp)
  jge    L56
L26:
  mov    $0x0,%ebx
  jmp    L69
L57:
  movslq %ebx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  add    $0x1,%ebx
L69:
  cmp    %r12d,%ebx
  jl     L57
  jmp    L81
L56:
  mov    $0x0,%ebx
  jmp    L27
L37:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rdx
  movslq %ebx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  add    $0x1,%ebx
L27:
  cmp    %r12d,%ebx
  jl     L37
  nop
L81:
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void nocompute(filt, x_dim, y_dim, x_pos, y_pos, result, f_or_e) register float *filt, *result;
register int x_dim;
int y_dim, x_pos, y_pos, f_or_e;
{
  register int i;
  register int size = x_dim * y_dim;
  if ((x_pos > 1) || (x_pos < -1) || (y_pos > 1) || (y_pos < -1))
    for (i = 0; i < size; i++)
      result[i] = 0.0;
  else
    for (i = 0; i < size; i++)
      result[i] = filt[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nocompute>:
  endbr64
  imul   %edx,%esi
  add    $0x1,%ecx
  cmp    $0x2,%ecx
  jbe    L22
L25:
  test   %esi,%esi
  jle    L34
  mov    %r9,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%r9,%rdx,4),%rdx
L23:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L23
  ret
L34:
  ret
L22:
  add    $0x1,%r8d
  cmp    $0x2,%r8d
  ja     L25
  mov    %esi,%edx
  mov    $0x0,%eax
  test   %esi,%esi
  jle    L42
L47:
  movss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L47
  ret
L42:
  ret
```

assistant: ```c
void nocompute(filt, x_dim, y_dim, x_pos, y_pos, result, f_or_e) register float *filt, *result;
register int x_dim;
int y_dim, x_pos, y_pos, f_or_e;
{
  register int i;
  register int size = x_dim * y_dim;
  if ((x_pos > 1) || (x_pos < -1) || (y_pos > 1) || (y_pos < -1))
    for (i = 0; i < size; i++)
      result[i] = 0.0;
  else
    for (i = 0; i < size; i++)
      result[i] = filt[i];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nocompute>:
  endbr64
  add    $0x1,%ecx
  imul   %edx,%esi
  mov    %rdi,%r10
  cmp    $0x2,%ecx
  ja     L36
  add    $0x1,%r8d
  cmp    $0x2,%r8d
  jbe    L13
L36:
  test   %esi,%esi
  jle    L40
  movslq %esi,%rsi
  mov    %r9,%rdi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   (%rax)
L13:
  movslq %esi,%rdx
  xor    %eax,%eax
  test   %esi,%esi
  jle    L47
  nopl   0x0(%rax)
L24:
  movss  (%r10,%rax,4),%xmm0
  movss  %xmm0,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L24
  ret
  xchg   %ax,%ax
L40:
  ret
L47:
  ret
```

assistant: ```c
void nocompute(filt, x_dim, y_dim, x_pos, y_pos, result, f_or_e) register float *filt, *result;
register int x_dim;
int y_dim, x_pos, y_pos, f_or_e;
{
  register int i;
  register int size = x_dim * y_dim;
  if ((x_pos > 1) || (x_pos < -1) || (y_pos > 1) || (y_pos < -1))
    for (i = 0; i < size; i++)
      result[i] = 0.0;
  else
    for (i = 0; i < size; i++)
      result[i] = filt[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nocompute>:
  endbr64
  mov    %esi,%eax
  add    $0x1,%ecx
  mov    %rdi,%r10
  imul   %edx,%eax
  cmp    $0x2,%ecx
  ja     L10
  add    $0x1,%r8d
  cmp    $0x2,%r8d
  ja     L10
  test   %eax,%eax
  jle    L72
  lea    0x4(%rdi),%rcx
  mov    %r9,%rdx
  sub    %rcx,%rdx
  cmp    $0x8,%rdx
  jbe    L97
  lea    -0x1(%rax),%edx
  cmp    $0x2,%edx
  jbe    L97
  mov    %eax,%ecx
  xor    %edx,%edx
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L44:
  movups (%r10,%rdx,1),%xmm1
  movups %xmm1,(%r9,%rdx,1)
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jne    L44
  mov    %eax,%edx
  and    $0xfffffffc,%edx
  test   $0x3,%al
  je     L107
  mov    %edx,%esi
  movss  (%r10,%rsi,4),%xmm0
  lea    0x0(,%rsi,4),%rcx
  movss  %xmm0,(%r9,%rsi,4)
  lea    0x1(%rdx),%esi
  cmp    %esi,%eax
  jle    L107
  movss  0x4(%r10,%rcx,1),%xmm0
  add    $0x2,%edx
  movss  %xmm0,0x4(%r9,%rcx,1)
  cmp    %edx,%eax
  jle    L107
  movss  0x8(%r10,%rcx,1),%xmm0
  movss  %xmm0,0x8(%r9,%rcx,1)
  ret
  nopl   (%rax)
L10:
  test   %eax,%eax
  jle    L21
  cltq
  xor    %esi,%esi
  mov    %r9,%rdi
  lea    0x0(,%rax,4),%rdx
  jmp    1050 <memset@plt>
L97:
  mov    %eax,%eax
  xor    %edx,%edx
  nopl   0x0(%rax)
L38:
  movss  (%r10,%rdx,4),%xmm0
  movss  %xmm0,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L38
L107:
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  ret
L72:
  ret
```

assistant: ```c
void nocompute(filt, x_dim, y_dim, x_pos, y_pos, result, f_or_e) register float *filt, *result;
register int x_dim;
int y_dim, x_pos, y_pos, f_or_e;
{
  register int i;
  register int size = x_dim * y_dim;
  if ((x_pos > 1) || (x_pos < -1) || (y_pos > 1) || (y_pos < -1))
    for (i = 0; i < size; i++)
      result[i] = 0.0;
  else
    for (i = 0; i < size; i++)
      result[i] = filt[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: %s


assistant: ```c
int main(int args, char **argv) {
  int i;
  for (i = 0; i < args; i++) {
    printf("%s\n", argv[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L2
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
  lea    D3(%rip),%rbp
L1:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L1
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    $0x0,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: %s


assistant: ```c
int main(int args, char **argv) {
  int i;
  for (i = 0; i < args; i++) {
    printf("%s\n", argv[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L0
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: %s


assistant: ```c
int main(int args, char **argv) {
  int i;
  for (i = 0; i < args; i++) {
    printf("%s\n", argv[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L14
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L18:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L14:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: %s


assistant: ```c
int main(int args, char **argv) {
  int i;
  for (i = 0; i < args; i++) {
    printf("%s\n", argv[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tcstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <tcmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *tcstrdup(const void *str) {
  assert(str);
  int size = strlen(str);
  char *p = tcmalloc(size + 1);
  memcpy(p, str, size);
  p[size] = '\0';
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tcstrdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rax),%edi
  call   <tcmalloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *tcstrdup(const void *str) {
  assert(str);
  int size = strlen(str);
  char *p = tcmalloc(size + 1);
  memcpy(p, str, size);
  p[size] = '\0';
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tcstrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%edi
  call   <tcmalloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *tcstrdup(const void *str) {
  assert(str);
  int size = strlen(str);
  char *p = tcmalloc(size + 1);
  memcpy(p, str, size);
  p[size] = '\0';
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tcstrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%edi
  call   <tcmalloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *tcstrdup(const void *str) {
  assert(str);
  int size = strlen(str);
  char *p = tcmalloc(size + 1);
  memcpy(p, str, size);
  p[size] = '\0';
  return p;
}
```