ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x20(%rbp)
  cltq
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x18(%rbp)
  cltq
  mov    %rax,%rcx
  mov    $0x0,%ebx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <rotate@plt>
  cmp    $0x1,%eax
  jne    L59
  mov    $0x1,%eax
  jmp    L57
L59:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x2,%ecx
  mov    %eax,%edi
  call   <rotate@plt>
  cmp    $0x2,%eax
  jne    L40
  mov    $0x2,%eax
  jmp    L57
L40:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x3,%ecx
  mov    %eax,%edi
  call   <rotate@plt>
  cmp    $0x3,%eax
  jne    L47
  mov    $0x3,%eax
  jmp    L57
L47:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <reflection@plt>
  cmp    $0x4,%eax
  jne    L55
  mov    $0x4,%eax
  jmp    L57
L55:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <reflection@plt>
  cmp    $0x5,%eax
  jne    L23
  mov    $0x5,%eax
  jmp    L57
L23:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x6,%ecx
  mov    %eax,%edi
  call   <check@plt>
  cmp    $0x6,%eax
  jne    L1
  mov    $0x6,%eax
  jmp    L57
L1:
  mov    $0x7,%eax
L57:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int convert(int length, char before[length][length + 1], char after[length][length + 1]) {
  if (rotate(length, before, after, 1) == 1)
    return 1;
  if (rotate(length, before, after, 2) == 2)
    return 2;
  if (rotate(length, before, after, 3) == 3)
    return 3;
  if (reflection(length, before, after) == 4) {
    return 4;
  } else if (reflection(length, before, after) == 5) {
    return 5;
  }
  if (check(length, before, after, 6) == 6) {
    return 6;
  } else {
    return 7;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x1,%ecx
  call   <rotate@plt>
  cmp    $0x1,%eax
  je     L45
  mov    $0x2,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <rotate@plt>
  cmp    $0x2,%eax
  je     L45
  mov    $0x3,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <rotate@plt>
  cmp    $0x3,%eax
  je     L45
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <reflection@plt>
  cmp    $0x4,%eax
  je     L45
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <reflection@plt>
  cmp    $0x5,%eax
  je     L45
  mov    $0x6,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <check@plt>
  cmp    $0x6,%eax
  mov    $0x7,%edx
  cmovne %edx,%eax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int convert(int length, char before[length][length + 1], char after[length][length + 1]) {
  if (rotate(length, before, after, 1) == 1)
    return 1;
  if (rotate(length, before, after, 2) == 2)
    return 2;
  if (rotate(length, before, after, 3) == 3)
    return 3;
  if (reflection(length, before, after) == 4) {
    return 4;
  } else if (reflection(length, before, after) == 5) {
    return 5;
  }
  if (check(length, before, after, 6) == 6) {
    return 6;
  } else {
    return 7;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<convert>:
  endbr64
  push   %r13
  mov    $0x1,%ecx
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  call   <rotate@plt>
  cmp    $0x1,%eax
  je     L38
  mov    $0x2,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <rotate@plt>
  cmp    $0x2,%eax
  je     L38
  mov    $0x3,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <rotate@plt>
  cmp    $0x3,%eax
  je     L38
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <reflection@plt>
  cmp    $0x4,%eax
  je     L38
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <reflection@plt>
  cmp    $0x5,%eax
  je     L38
  mov    %r13,%rdx
  mov    $0x6,%ecx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <check@plt>
  mov    $0x7,%edx
  cmp    $0x6,%eax
  cmovne %edx,%eax
L38:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int convert(int length, char before[length][length + 1], char after[length][length + 1]) {
  if (rotate(length, before, after, 1) == 1)
    return 1;
  if (rotate(length, before, after, 2) == 2)
    return 2;
  if (rotate(length, before, after, 3) == 3)
    return 3;
  if (reflection(length, before, after) == 4) {
    return 4;
  } else if (reflection(length, before, after) == 5) {
    return 5;
  }
  if (check(length, before, after, 6) == 6) {
    return 6;
  } else {
    return 7;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<convert>:
  endbr64
  push   %r13
  mov    $0x1,%ecx
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  call   <rotate@plt>
  cmp    $0x1,%eax
  je     L15
  mov    $0x2,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <rotate@plt>
  cmp    $0x2,%eax
  je     L15
  mov    $0x3,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <rotate@plt>
  cmp    $0x3,%eax
  je     L15
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <reflection@plt>
  cmp    $0x4,%eax
  je     L15
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <reflection@plt>
  cmp    $0x5,%eax
  je     L15
  mov    %r13,%rdx
  mov    $0x6,%ecx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <check@plt>
  mov    $0x7,%edx
  cmp    $0x6,%eax
  cmovne %edx,%eax
L15:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int convert(int length, char before[length][length + 1], char after[length][length + 1]) {
  if (rotate(length, before, after, 1) == 1)
    return 1;
  if (rotate(length, before, after, 2) == 2)
    return 2;
  if (rotate(length, before, after, 3) == 3)
    return 3;
  if (reflection(length, before, after) == 4) {
    return 4;
  } else if (reflection(length, before, after) == 5) {
    return 5;
  }
  if (check(length, before, after, 6) == 6) {
    return 6;
  } else {
    return 7;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  movl   $0x5,-0x8(%rbp)
L26:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D8(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x2,-0xc(%rbp)
  addl   $0x2,-0x8(%rbp)
  movss  -0x10(%rbp),%xmm0
  addss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jae    L10
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  ja     L26
  jmp    L3
L10:
  nop
L3:
  movss  -0x10(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: f64

tool: D8: 1

assistant: ```c
float primes(int x) {
  float result = 0.0, primes;
  int first = 3, second = 5;
  do {
    primes = 1.0 / (first + second);
    first += 2;
    second += 2;
    result += primes;
    if (primes <= x)
      break;
  } while (primes > x);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<primes>:
  endbr64
  mov    $0x8,%eax
  pxor   %xmm1,%xmm1
  movsd  D2(%rip),%xmm4
  pxor   %xmm2,%xmm2
  cvtsi2ss %edi,%xmm2
L2:
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  movapd %xmm4,%xmm0
  divsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
  addss  %xmm0,%xmm1
  comiss %xmm0,%xmm2
  jae    L6
  add    $0x4,%eax
  comiss %xmm2,%xmm0
  ja     L2
L6:
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: f64

tool: D2: 1

assistant: ```c
float primes(int x) {
  float result = 0.0, primes;
  int first = 3, second = 5;
  do {
    primes = 1.0 / (first + second);
    first += 2;
    second += 2;
    result += primes;
    if (primes <= x)
      break;
  } while (primes > x);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<primes>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D5(%rip),%xmm4
  mov    $0x8,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm2
  jmp    L1
  nop
L16:
  add    $0x4,%eax
  comiss %xmm2,%xmm0
  jbe    L15
L1:
  pxor   %xmm3,%xmm3
  movapd %xmm4,%xmm0
  cvtsi2sd %eax,%xmm3
  divsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
  comiss %xmm0,%xmm2
  addss  %xmm0,%xmm1
  jb     L16
L15:
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: f64

tool: D5: 1

assistant: ```c
float primes(int x) {
  float result = 0.0, primes;
  int first = 3, second = 5;
  do {
    primes = 1.0 / (first + second);
    first += 2;
    second += 2;
    result += primes;
    if (primes <= x)
      break;
  } while (primes > x);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<primes>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D5(%rip),%xmm4
  mov    $0x8,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm2
  jmp    L14
  nop
L26:
  add    $0x4,%eax
  comiss %xmm2,%xmm0
  jbe    L20
L14:
  pxor   %xmm3,%xmm3
  movapd %xmm4,%xmm0
  cvtsi2sd %eax,%xmm3
  divsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
  comiss %xmm0,%xmm2
  addss  %xmm0,%xmm1
  jb     L26
L20:
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: f64

tool: D5: 1

assistant: ```c
float primes(int x) {
  float result = 0.0, primes;
  int first = 3, second = 5;
  do {
    primes = 1.0 / (first + second);
    first += 2;
    second += 2;
    result += primes;
    if (primes <= x)
      break;
  } while (primes > x);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ldlong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    $0x0,%ebx
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L3:
  mov    %ebx,%ecx
  shl    $0x8,%ecx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  lea    (%rcx,%rdx,1),%ebx
  addl   $0x1,-0xc(%rbp)
L5:
  cmpl   $0x3,-0xc(%rbp)
  jle    L3
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long ldlong(p)
register char *p;
{
  int i;
  register unsigned int val;
  val = 0;
  for (i = 0; i < 32 / 8; i++)
    val = (val << 8) + *((unsigned char *)p++);
  return ((long)val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ldlong>:
  endbr64
  lea    0x4(%rdi),%rcx
  mov    $0x0,%eax
L1:
  shl    $0x8,%eax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L1
  mov    %eax,%eax
  ret
```

assistant: ```c
long ldlong(p)
register char *p;
{
  int i;
  register unsigned int val;
  val = 0;
  for (i = 0; i < 32 / 8; i++)
    val = (val << 8) + *((unsigned char *)p++);
  return ((long)val);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ldlong>:
  endbr64
  lea    0x4(%rdi),%rcx
  xor    %eax,%eax
L5:
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L5
  ret
```

assistant: ```c
long ldlong(p)
register char *p;
{
  int i;
  register unsigned int val;
  val = 0;
  for (i = 0; i < 32 / 8; i++)
    val = (val << 8) + *((unsigned char *)p++);
  return ((long)val);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ldlong>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,%eax
  ret
```

assistant: ```c
long ldlong(p)
register char *p;
{
  int i;
  register unsigned int val;
  val = 0;
  for (i = 0; i < 32 / 8; i++)
    val = (val << 8) + *((unsigned char *)p++);
  return ((long)val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<snprintsize>:
  endbr64
  mov    %rdx,%rcx
  test   %rdx,%rdx
  js     L39
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
L3:
  comisd D25(%rip),%xmm0
  jbe    L8
  mulsd  D38(%rip),%xmm0
  movsd  D40(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L25
  cvttsd2si %xmm0,%rcx
  lea    D37(%rip),%rdx
  jmp    1050 <snprintf@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  lea    D6(%rip),%rdx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax)
L25:
  subsd  %xmm1,%xmm0
  lea    D37(%rip),%rdx
  cvttsd2si %xmm0,%rcx
  btc    $0x3f,%rcx
  jmp    1050 <snprintf@plt>
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %rdx,%rax
  and    $0x1,%edx
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdx,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
datatype: byte[16]
name: extract_symbolic_data
arguments: data_tag: D38
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D40
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D37
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x41,0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

tool: D37: %.1f GB

tool: D6: %ld bytes

assistant: ```c
void snprintsize(char *buf, size_t n, size_t size) {
  double dsize = size;
  if (dsize > 1024 * 1024 * 1024) {
    dsize /= 1024 * 1024 * 1024;
    snprintf(buf, n, "%.1f GB", dsize);
  } else {
    snprintf(buf, n, "%ld bytes", size);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<snprintsize>:
  endbr64
  mov    %rdx,%rcx
  test   %rdx,%rdx
  js     L29
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
L5:
  comisd D17(%rip),%xmm0
  jbe    L24
  mulsd  D25(%rip),%xmm0
  movsd  D57(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L18
  cvttsd2si %xmm0,%rcx
  lea    D34(%rip),%rdx
  jmp    1050 <snprintf@plt>
  cs nopw 0x0(%rax,%rax,1)
L24:
  lea    D32(%rip),%rdx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax)
L18:
  subsd  %xmm1,%xmm0
  lea    D34(%rip),%rdx
  cvttsd2si %xmm0,%rcx
  btc    $0x3f,%rcx
  jmp    1050 <snprintf@plt>
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rdx,%rax
  and    $0x1,%edx
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdx,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L5
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_infered: byte[16]
name: unpack_data
arguments: data_tag: D25
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D57
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D34
type_infered: string
name: unpack_data
arguments: data_tag: D32
type_infered: string

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x41,0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

tool: D34: %.1f GB

tool: D32: %ld bytes

assistant: ```c
void snprintsize(char *buf, size_t n, size_t size) {
  double dsize = size;
  if (dsize > 1024 * 1024 * 1024) {
    dsize /= 1024 * 1024 * 1024;
    snprintf(buf, n, "%.1f GB", dsize);
  } else {
    snprintf(buf, n, "%ld bytes", size);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strntok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L9
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L9:
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strnsep@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L6
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
char *strntok(char *restrict string, const char *restrict delimiters, char **restrict state, size_t *restrict maxlen) {
  char *r;
  if (string == NULL)
    *state = string;
  for (;;) {
    r = strnsep(state, delimiters, maxlen);
    if (r == NULL)
      return NULL;
    if (*r)
      return r;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strntok>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rcx,%r12
  test   %rdi,%rdi
  je     L2
L26:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strnsep@plt>
  test   %rax,%rax
  je     L18
  cmpb   $0x0,(%rax)
  je     L26
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  movq   $0x0,(%rdx)
  jmp    L26
```

assistant: ```c
char *strntok(char *restrict string, const char *restrict delimiters, char **restrict state, size_t *restrict maxlen) {
  char *r;
  if (string == NULL)
    *state = string;
  for (;;) {
    r = strnsep(state, delimiters, maxlen);
    if (r == NULL)
      return NULL;
    if (*r)
      return r;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strntok>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  jne    L41
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L37:
  cmpb   $0x0,(%rax)
  jne    L35
L41:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strnsep@plt>
  test   %rax,%rax
  jne    L37
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L46:
  movq   $0x0,(%rdx)
  jmp    L41
```

assistant: ```c
char *strntok(char *restrict string, const char *restrict delimiters, char **restrict state, size_t *restrict maxlen) {
  char *r;
  if (string == NULL)
    *state = string;
  for (;;) {
    r = strnsep(state, delimiters, maxlen);
    if (r == NULL)
      return NULL;
    if (*r)
      return r;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strntok>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  jne    L10
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L28:
  cmpb   $0x0,(%rax)
  jne    L49
L10:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strnsep@plt>
  test   %rax,%rax
  jne    L28
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L0:
  movq   $0x0,(%rdx)
  jmp    L10
```

assistant: ```c
char *strntok(char *restrict string, const char *restrict delimiters, char **restrict state, size_t *restrict maxlen) {
  char *r;
  if (string == NULL)
    *state = string;
  for (;;) {
    r = strnsep(state, delimiters, maxlen);
    if (r == NULL)
      return NULL;
    if (*r)
      return r;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <fatorial@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main() {
  printf("%d\n", fatorial(5));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorial@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string

tool: D1: %d


assistant: ```c
int main() {
  printf("%d\n", fatorial(5));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorial@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main() {
  printf("%d\n", fatorial(5));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorial@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  printf("%d\n", fatorial(5));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initTable@plt>
  mov    $0x0,%eax
  call   <getChar@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init() {
  initTable();
  getChar();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initTable@plt>
  mov    $0x0,%eax
  call   <getChar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init() {
  initTable();
  getChar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initTable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getChar@plt>
```

assistant: ```c
void init() {
  initTable();
  getChar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initTable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getChar@plt>
```

assistant: ```c
void init() {
  initTable();
  getChar();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<list_constructor_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L45
L32:
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L33:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <list_push@plt>
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L33
  addl   $0x1,-0x18(%rbp)
L45:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L32
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
struct list *list_constructor_dup(int n, int d) {
  struct list *head = NULL;
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < d; j++) {
      list_push(i, &head);
    }
  }
  return head;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<list_constructor_dup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r14d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%ebp
  mov    %rsp,%r13
  test   %edi,%edi
  jg     L49
L24:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <list_push@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L41
L47:
  add    $0x1,%ebp
  cmp    %ebp,%r14d
  je     L24
L49:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L41
  jmp    L47
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct list *list_constructor_dup(int n, int d) {
  struct list *head = NULL;
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < d; j++) {
      list_push(i, &head);
    }
  }
  return head;
}
```