ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x20(%rsp)
  mov    D25(%rip),%rax
  mov    %rax,(%rsp)
  mov    D44(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D23(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D32(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%ebx
  lea    D48(%rip),%rbp
L17:
  movsd  (%rsp,%rbx,8),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L17
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type: f64
name: parse_data
arguments: data_label: D44
type: f64
name: parse_data
arguments: data_label: D23
type: byte[8]
name: parse_data
arguments: data_label: D32
type: f64
name: parse_data
arguments: data_label: D48
type: string

tool: D25: 9

tool: D44: 2.9

tool: {"D23": [0xd9,0x03,0x3c,0x42,0xbf,0xd0,0x38,0x45]}

tool: D32: 7e-05

tool: D48: element %d is %g, 	its square is %g


assistant: ```c
int main() {
  int i;
  double A[5] = {
      9.0,
      2.9,
      3.E+25,
      0.00007,
  };
  for (i = 0; i < 5; ++i) {
    printf("element %d is %g, \tits square is %g\n", i, A[i], A[i] * A[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  movsd  D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D29(%rip),%rax
  movq   $0x0,0x20(%rsp)
  mov    %rax,0x8(%rsp)
  mov    D48(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D12(%rip),%rax
  mov    %rax,0x18(%rsp)
L23:
  movapd %xmm0,%xmm1
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  mulsd  %xmm0,%xmm1
  call   <printf@plt>
  cmp    $0x5,%rbx
  je     L17
  movsd  (%rsp,%rbx,8),%xmm0
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: string
name: parse_data
arguments: data_label: D17
datatype: f64
name: parse_data
arguments: data_label: D29
datatype: f64
name: parse_data
arguments: data_label: D48
datatype: byte[8]
name: parse_data
arguments: data_label: D12
datatype: f64

tool: D3: element %d is %g, 	its square is %g


tool: D17: 9

tool: D29: 2.9

tool: {"D48": [0xd9,0x03,0x3c,0x42,0xbf,0xd0,0x38,0x45]}

tool: D12: 7e-05

assistant: ```c
int main() {
  int i;
  double A[5] = {
      9.0,
      2.9,
      3.E+25,
      0.00007,
  };
  for (i = 0; i < 5; ++i) {
    printf("element %d is %g, \tits square is %g\n", i, A[i], A[i] * A[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  movapd D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movapd D0(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
L17:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L17
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D9
type_guessed: f64[2]
name: retrieve_data
arguments: label: D0
type_guessed: byte[16]

tool: D5: element %d is %g, 	its square is %g


tool: {"D9": [9.0,2.9]}

tool: {"D0": [0xd9,0x03,0x3c,0x42,0xbf,0xd0,0x38,0x45,0xd2,0xfb,0xc6,0xd7,0x9e,0x59,0x12,0x3f]}

assistant: ```c
int main() {
  int i;
  double A[5] = {
      9.0,
      2.9,
      3.E+25,
      0.00007,
  };
  for (i = 0; i < 5; ++i) {
    printf("element %d is %g, \tits square is %g\n", i, A[i], A[i] * A[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x30(%rbp)
  movl   $0xfffffff6,-0x2c(%rbp)
  movl   $0xe,-0x28(%rbp)
  movl   $0x2a,-0x24(%rbp)
  movl   $0xb,-0x20(%rbp)
  movl   $0xfffffff9,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x26,-0x14(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <sort@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L19:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L7:
  cmpl   $0x7,-0x34(%rbp)
  jle    L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: string

tool: D6: %d


assistant: ```c
int main() {
  int i;
  int a[] = {2, -10, 14, 42, 11, -7, 0, 38};
  sort(a, 8);
  for (i = 0; i < 8; i++)
    printf("%d\n", a[i]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0xfffffff6,0x4(%rsp)
  movl   $0xe,0x8(%rsp)
  movl   $0x2a,0xc(%rsp)
  movl   $0xb,0x10(%rsp)
  movl   $0xfffffff9,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x26,0x1c(%rsp)
  mov    %rsp,%rbx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <sort@plt>
  lea    0x20(%rsp),%r12
  lea    D7(%rip),%rbp
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L7
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: %d


assistant: ```c
int main() {
  int i;
  int a[] = {2, -10, 14, 42, 11, -7, 0, 38};
  sort(a, 8);
  for (i = 0; i < 8; i++)
    printf("%d\n", a[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xfffffff600000002,%rax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x2a0000000e,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xfffffff90000000b,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x2600000000,%rax
  mov    %rax,0x18(%rsp)
  call   <sort@plt>
  nopl   0x0(%rax)
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9: %d


assistant: ```c
int main() {
  int i;
  int a[] = {2, -10, 14, 42, 11, -7, 0, 38};
  sort(a, 8);
  for (i = 0; i < 8; i++)
    printf("%d\n", a[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D25(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D0(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <sort@plt>
  nopl   0x0(%rax)
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L16
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D27
type: string
name: parse_data
arguments: tag: D25
type: byte[16]
name: parse_data
arguments: tag: D0
type: byte[16]

tool: D27: %d


tool: {"D25": [0x02,0x00,0x00,0x00,0xf6,0xff,0xff,0xff,0x0e,0x00,0x00,0x00,0x2a,0x00,0x00,0x00]}

tool: {"D0": [0x0b,0x00,0x00,0x00,0xf9,0xff,0xff,0xff,0x00,0x00,0x00,0x00,0x26,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int i;
  int a[] = {2, -10, 14, 42, 11, -7, 0, 38};
  sort(a, 8);
  for (i = 0; i < 8; i++)
    printf("%d\n", a[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f(int a, int b) {
  int x = b;
  int y = x + 1;
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f(int a, int b) {
  int x = b;
  int y = x + 1;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f(int a, int b) {
  int x = b;
  int y = x + 1;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f(int a, int b) {
  int x = b;
  int y = x + 1;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_tick_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  test   %rax,%rax
  je     L12
  mov    $0x0,%eax
  jmp    L19
L12:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  add    %edx,%eax
  cltq
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
unsigned long get_tick_count(void) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL))
    return 0;
  return tv.tv_usec / 1000 + tv.tv_sec * 1000;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_tick_count>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L15
  mov    (%rsp),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x3e8,0x4(%rsp),%edx
  add    %edx,%eax
  cltq
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_tick_count(void) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL))
    return 0;
  return tv.tv_usec / 1000 + tv.tv_sec * 1000;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_tick_count>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L13
  movslq (%rsp),%rax
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,0x4(%rsp),%edx
  add    %edx,%eax
  cltq
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_tick_count(void) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL))
    return 0;
  return tv.tv_usec / 1000 + tv.tv_sec * 1000;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_tick_count>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L2
  movslq (%rsp),%rax
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,0x4(%rsp),%edx
  add    %edx,%eax
  cltq
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_tick_count(void) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL))
    return 0;
  return tv.tv_usec / 1000 + tv.tv_sec * 1000;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<put_default_terminalname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <systemlog@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <set_terminalname@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L12
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5d,%edi
  call   <systemlog@plt>
  jmp    L19
L12:
  lea    D37(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5d,%edi
  call   <systemlog@plt>
L19:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
datatype: string
name: disassemble_data
arguments: label: D34
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D37
datatype: string

tool: D14: put_default_terminalname

tool: D34: xterm

tool: D5: 	[DONE]

tool: D37: 	[FAILD]

assistant: ```c
int put_default_terminalname() {
  int success = 0;
  systemlog(3, "put_default_terminalname");
  success = set_terminalname("xterm");
  if (success > 0)
    systemlog(93, "\t[DONE]");
  else
    systemlog(93, "\t[FAILD]");
  return success;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<put_default_terminalname>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rsi
  mov    $0x3,%edi
  call   <systemlog@plt>
  lea    D8(%rip),%rdi
  call   <set_terminalname@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L8
  lea    D27(%rip),%rsi
  mov    $0x5d,%edi
  call   <systemlog@plt>
L3:
  mov    %ebx,%eax
  pop    %rbx
  ret
L8:
  lea    D26(%rip),%rsi
  mov    $0x5d,%edi
  call   <systemlog@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string
name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D27
datatype: string
name: parse_data
arguments: label: D26
datatype: string

tool: D4: put_default_terminalname

tool: D8: xterm

tool: D27: 	[DONE]

tool: D26: 	[FAILD]

assistant: ```c
int put_default_terminalname() {
  int success = 0;
  systemlog(3, "put_default_terminalname");
  success = set_terminalname("xterm");
  if (success > 0)
    systemlog(93, "\t[DONE]");
  else
    systemlog(93, "\t[FAILD]");
  return success;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<put_default_terminalname>:
  endbr64
  push   %r12
  lea    D2(%rip),%rsi
  mov    $0x3,%edi
  call   <systemlog@plt>
  lea    D20(%rip),%rdi
  call   <set_terminalname@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L8
  lea    D32(%rip),%rsi
  mov    $0x5d,%edi
  call   <systemlog@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  lea    D31(%rip),%rsi
  mov    $0x5d,%edi
  call   <systemlog@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string
name: extract_symbolic_data
arguments: tag: D32
type_infered: string
name: extract_symbolic_data
arguments: tag: D31
type_infered: string

tool: D2: put_default_terminalname

tool: D20: xterm

tool: D32: 	[DONE]

tool: D31: 	[FAILD]

assistant: ```c
int put_default_terminalname() {
  int success = 0;
  systemlog(3, "put_default_terminalname");
  success = set_terminalname("xterm");
  if (success > 0)
    systemlog(93, "\t[DONE]");
  else
    systemlog(93, "\t[FAILD]");
  return success;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<put_default_terminalname>:
  endbr64
  push   %r12
  lea    D3(%rip),%rsi
  mov    $0x3,%edi
  call   <systemlog@plt>
  lea    D34(%rip),%rdi
  call   <set_terminalname@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L8
  lea    D19(%rip),%rsi
  mov    $0x5d,%edi
  call   <systemlog@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  lea    D15(%rip),%rsi
  mov    $0x5d,%edi
  call   <systemlog@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D34
type: string
name: retrieve_data
arguments: data_label: D19
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D3: put_default_terminalname

tool: D34: xterm

tool: D19: 	[DONE]

tool: D15: 	[FAILD]

assistant: ```c
int put_default_terminalname() {
  int success = 0;
  systemlog(3, "put_default_terminalname");
  success = set_terminalname("xterm");
  if (success > 0)
    systemlog(93, "\t[DONE]");
  else
    systemlog(93, "\t[FAILD]");
  return success;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D6: %d


assistant: ```c
int main(void) {
  printf("%d\n", getpid());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(void) {
  printf("%d\n", getpid());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D0: %d


assistant: ```c
int main(void) {
  printf("%d\n", getpid());
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main(void) {
  printf("%d\n", getpid());
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<log_comb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jge    L37
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L58
L37:
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L58:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L57
L1:
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x14(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  subl   $0x1,-0x14(%rbp)
L57:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L1
  movl   $0x2,-0x14(%rbp)
  jmp    L17
L35:
  pxor   %xmm3,%xmm3
  cvtsi2sdl -0x14(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L35
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double log_comb(int m, int n) {
  int i;
  double x = 0;
  int big, little;
  if (m - n > n) {
    big = m - n;
    little = n;
  } else {
    big = n;
    little = m - n;
  }
  for (i = m; i > big; i--)
    x += log((double)i);
  for (i = 2; i <= little; i++)
    x -= log((double)i);
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<log_comb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edi,%r12d
  sub    %esi,%r12d
  cmp    %esi,%r12d
  jg     L25
  mov    %r12d,%eax
  mov    %esi,%r12d
  mov    %eax,%ebp
L25:
  cmp    %ebx,%r12d
  jge    L42
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
L9:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  call   <log@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  sub    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L9
L8:
  cmp    $0x1,%ebp
  jle    L39
  mov    $0x2,%ebx
L57:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  call   <log@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L57
L39:
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L8
```

assistant: ```c
double log_comb(int m, int n) {
  int i;
  double x = 0;
  int big, little;
  if (m - n > n) {
    big = m - n;
    little = n;
  } else {
    big = n;
    little = m - n;
  }
  for (i = m; i > big; i--)
    x += log((double)i);
  for (i = 2; i <= little; i++)
    x -= log((double)i);
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log_comb>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  sub    %esi,%r12d
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  cmp    %esi,%r12d
  jg     L32
  mov    %r12d,%eax
  mov    %esi,%r12d
  mov    %eax,%ebp
L32:
  pxor   %xmm1,%xmm1
  cmp    %ebx,%r12d
  jge    L23
  nopl   0x0(%rax)
L34:
  pxor   %xmm0,%xmm0
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %ebx,%xmm0
  sub    $0x1,%ebx
  call   <log@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %ebx,%r12d
  jne    L34
L23:
  cmp    $0x1,%ebp
  jle    L47
  mov    $0x2,%ebx
  nopl   0x0(%rax,%rax,1)
L7:
  pxor   %xmm0,%xmm0
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %ebx,%xmm0
  add    $0x1,%ebx
  call   <log@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  subsd  %xmm0,%xmm1
  cmp    %ebx,%ebp
  jge    L7
L47:
  add    $0x10,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double log_comb(int m, int n) {
  int i;
  double x = 0;
  int big, little;
  if (m - n > n) {
    big = m - n;
    little = n;
  } else {
    big = n;
    little = m - n;
  }
  for (i = m; i > big; i--)
    x += log((double)i);
  for (i = 2; i <= little; i++)
    x -= log((double)i);
  return x;
}
```