ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<multiply13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L36
L6:
  movl   $0x0,-0x3c(%rbp)
  jmp    L1
L33:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L1:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L33
  addl   $0x1,-0x40(%rbp)
L36:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L6
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply13(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply13>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L29:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L16:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L16
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L29
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  ret
```

assistant: ```c
void multiply13(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<multiply13>:
  endbr64
  test   %edi,%edi
  jle    L15
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L26
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L0
  pop    %rbx
  ret
L15:
  ret
```

assistant: ```c
void multiply13(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multiply13>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L55
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L14:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L76
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L76
  nopl   0x0(%rax)
L80:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L80
  cmp    -0x24(%rsp),%r11d
  je     L13
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L13
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L13
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L13:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L14
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L76:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L39:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L39
  mov    -0x18(%rsp),%r8
  jmp    L13
```

assistant: ```c
void multiply13(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_dims>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x3,%edx
  lea    D58(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L97
  movl   $0x0,(%rbx)
  movl   $0x1,0x4(%rbx)
  movl   $0x2,0x8(%rbx)
L57:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L97:
  mov    $0x3,%edx
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L12
  movl   $0x0,(%rbx)
  movl   $0x1,0x8(%rbx)
  movl   $0x2,0x4(%rbx)
  jmp    L57
L12:
  mov    $0x3,%edx
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L84
  movl   $0x0,0x4(%rbx)
  movl   $0x1,(%rbx)
  movl   $0x2,0x8(%rbx)
  jmp    L57
L84:
  mov    $0x3,%edx
  lea    D57(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L18
  movl   $0x0,0x4(%rbx)
  movl   $0x1,0x8(%rbx)
  movl   $0x2,(%rbx)
  jmp    L57
L18:
  mov    $0x3,%edx
  lea    D41(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L1
  movl   $0x0,0x8(%rbx)
  movl   $0x1,(%rbx)
  movl   $0x2,0x4(%rbx)
  jmp    L57
L1:
  mov    $0x3,%edx
  lea    D64(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L26
  movl   $0x0,0x8(%rbx)
  movl   $0x1,0x4(%rbx)
  movl   $0x2,(%rbx)
  jmp    L57
L26:
  lea    D18(%rip),%rdi
  call   <write_log_comment_disp@plt>
  mov    $0x1,%eax
  jmp    L57
```

tool_calls: name: read_data
arguments: data_tag: D58
type_guessed: string
name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D23
type_guessed: string
name: read_data
arguments: data_tag: D57
type_guessed: string
name: read_data
arguments: data_tag: D41
type_guessed: string
name: read_data
arguments: data_tag: D64
type_guessed: string
name: read_data
arguments: data_tag: D18
type_guessed: string

tool: D58: xyz

tool: D17: xzy

tool: D23: yxz

tool: D57: yzx

tool: D41: zxy

tool: D64: zyx

tool: D18: Axis order must be a permutation of xyz.


assistant: ```c
int set_dims(int dim[3], const char *axis_order) {
  if (0 == strncmp(axis_order, "xyz", 3)) {
    dim[0] = 0;
    dim[1] = 1;
    dim[2] = 2;
  } else if (0 == strncmp(axis_order, "xzy", 3)) {
    dim[0] = 0;
    dim[2] = 1;
    dim[1] = 2;
  } else if (0 == strncmp(axis_order, "yxz", 3)) {
    dim[1] = 0;
    dim[0] = 1;
    dim[2] = 2;
  } else if (0 == strncmp(axis_order, "yzx", 3)) {
    dim[1] = 0;
    dim[2] = 1;
    dim[0] = 2;
  } else if (0 == strncmp(axis_order, "zxy", 3)) {
    dim[2] = 0;
    dim[0] = 1;
    dim[1] = 2;
  } else if (0 == strncmp(axis_order, "zyx", 3)) {
    dim[2] = 0;
    dim[1] = 1;
    dim[0] = 2;
  } else {
    write_log_comment_disp("Axis order must be a permutation of xyz.\n");
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<set_dims>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x3,%edx
  lea    D69(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L56
  movl   $0x2,0x8(%rbx)
  movabs $0x100000000,%rax
  mov    %rax,(%rbx)
  xor    %eax,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    $0x3,%edx
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L66
  movabs $0x200000000,%rax
  movl   $0x1,0x8(%rbx)
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L66:
  mov    $0x3,%edx
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L43
  movq   $0x1,(%rbx)
  movl   $0x2,0x8(%rbx)
  jmp    L17
  nopl   0x0(%rax)
L43:
  mov    $0x3,%edx
  lea    D38(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L25
  movq   $0x2,(%rbx)
  movl   $0x1,0x8(%rbx)
  jmp    L17
  nopl   0x0(%rax)
L25:
  mov    $0x3,%edx
  lea    D66(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L5
  movabs $0x200000001,%rax
  movl   $0x0,0x8(%rbx)
  mov    %rax,(%rbx)
  xor    %eax,%eax
  jmp    L17
L5:
  mov    $0x3,%edx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L83
  movabs $0x100000002,%rax
  movl   $0x0,0x8(%rbx)
  mov    %rax,(%rbx)
  xor    %eax,%eax
  jmp    L17
L83:
  lea    D20(%rip),%rdi
  call   <write_log_comment_disp@plt>
  mov    $0x1,%eax
  jmp    L17
```

tool_calls: name: read_data
arguments: data_tag: D69
type_guessed: string
name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D22
type_guessed: string
name: read_data
arguments: data_tag: D38
type_guessed: string
name: read_data
arguments: data_tag: D66
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string
name: read_data
arguments: data_tag: D20
type_guessed: string

tool: D69: xyz

tool: D17: xzy

tool: D22: yxz

tool: D38: yzx

tool: D66: zxy

tool: D11: zyx

tool: D20: Axis order must be a permutation of xyz.


assistant: ```c
int set_dims(int dim[3], const char *axis_order) {
  if (0 == strncmp(axis_order, "xyz", 3)) {
    dim[0] = 0;
    dim[1] = 1;
    dim[2] = 2;
  } else if (0 == strncmp(axis_order, "xzy", 3)) {
    dim[0] = 0;
    dim[2] = 1;
    dim[1] = 2;
  } else if (0 == strncmp(axis_order, "yxz", 3)) {
    dim[1] = 0;
    dim[0] = 1;
    dim[2] = 2;
  } else if (0 == strncmp(axis_order, "yzx", 3)) {
    dim[1] = 0;
    dim[2] = 1;
    dim[0] = 2;
  } else if (0 == strncmp(axis_order, "zxy", 3)) {
    dim[2] = 0;
    dim[0] = 1;
    dim[1] = 2;
  } else if (0 == strncmp(axis_order, "zyx", 3)) {
    dim[2] = 0;
    dim[1] = 1;
    dim[0] = 2;
  } else {
    write_log_comment_disp("Axis order must be a permutation of xyz.\n");
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x136ff696,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L29
L28:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x1a(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  add    $0x6,%rax
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    0x6(%rax),%rdx
  movzwl -0x1a(%rbp),%eax
  mov    %ax,(%rdx)
  addq   $0x2,-0x18(%rbp)
L29:
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    -0x10(%rbp),%rax
  imul   $0x1b1b1ac7,%rax,%rax
  lea    0x33d46988(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
      *((unsigned short *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 454761159UL + 869558664UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  add    $0x136ff696,%rdx
  mov    %rdx,%rax
  mov    %rdx,%rcx
  shr    $0x30,%rcx
  mov    %cx,%ax
  shl    $0x30,%rdx
  movabs $0xffffffffffff,%rcx
  and    %rcx,%rax
  or     %rdx,%rax
  imul   $0x1b1b1ac7,%rax,%rax
  add    $0x33d46988,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
      *((unsigned short *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 454761159UL + 869558664UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  imul   $0x1b1b1ac7,%rax,%rax
  add    $0x33d46988,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
      *((unsigned short *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 454761159UL + 869558664UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  imul   $0x1b1b1ac7,%rax,%rax
  add    $0x33d46988,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
      *((unsigned short *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 454761159UL + 869558664UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rq_money_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rq_money_clear@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void rq_money_free(struct rq_money *p) {
  rq_money_clear(p);
  free(p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rq_money_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <rq_money_clear@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void rq_money_free(struct rq_money *p) {
  rq_money_clear(p);
  free(p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rq_money_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <rq_money_clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void rq_money_free(struct rq_money *p) {
  rq_money_clear(p);
  free(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rq_money_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <rq_money_clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void rq_money_free(struct rq_money *p) {
  rq_money_clear(p);
  free(p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tar_trail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L41:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  addl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0x1ff,-0x4(%rbp)
  jle    L41
  jmp    L9
L21:
  nop
L9:
  cmpl   $0x200,-0x4(%rbp)
  je     L18
  mov    $0xffffffff,%eax
  jmp    L43
L18:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L80
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jle    L80
  mov    $0x0,%eax
  jmp    L43
L80:
  mov    $0x1,%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
int tar_trail(char *buf, int in_resync, int *cnt) {
  int i;
  for (i = 0; i < 512; ++i) {
    if (buf[i] != '\0')
      break;
  }
  if (i != 512)
    return (-1);
  if (!in_resync && (++*cnt >= 2))
    return (0);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tar_trail>:
  endbr64
  mov    $0x0,%eax
L21:
  cmpb   $0x0,(%rdi)
  jne    L24
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    $0x200,%eax
  jne    L21
L33:
  mov    $0x1,%ecx
  test   %esi,%esi
  jne    L6
  mov    (%rdx),%eax
  add    $0x1,%eax
  mov    %eax,(%rdx)
  cmp    $0x1,%eax
  setle  %cl
  movzbl %cl,%ecx
  jmp    L6
L24:
  mov    $0xffffffff,%ecx
  cmp    $0x200,%eax
  je     L33
L6:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int tar_trail(char *buf, int in_resync, int *cnt) {
  int i;
  for (i = 0; i < 512; ++i) {
    if (buf[i] != '\0')
      break;
  }
  if (i != 512)
    return (-1);
  if (!in_resync && (++*cnt >= 2))
    return (0);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tar_trail>:
  endbr64
  lea    0x200(%rdi),%rax
  jmp    L36
  nopl   (%rax)
L5:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L16
L36:
  cmpb   $0x0,(%rdi)
  je     L5
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L16:
  test   %esi,%esi
  jne    L6
  mov    (%rdx),%eax
  add    $0x1,%eax
  cmp    $0x1,%eax
  mov    %eax,(%rdx)
  setle  %al
  movzbl %al,%eax
  ret
  nopl   (%rax)
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int tar_trail(char *buf, int in_resync, int *cnt) {
  int i;
  for (i = 0; i < 512; ++i) {
    if (buf[i] != '\0')
      break;
  }
  if (i != 512)
    return (-1);
  if (!in_resync && (++*cnt >= 2))
    return (0);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tar_trail>:
  endbr64
  lea    0x200(%rdi),%rax
  jmp    L31
  nopl   (%rax)
L30:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L24
L31:
  cmpb   $0x0,(%rdi)
  je     L30
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L24:
  test   %esi,%esi
  jne    L12
  mov    (%rdx),%eax
  add    $0x1,%eax
  cmp    $0x1,%eax
  mov    %eax,(%rdx)
  setle  %al
  movzbl %al,%eax
  ret
  nopl   (%rax)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int tar_trail(char *buf, int in_resync, int *cnt) {
  int i;
  for (i = 0; i < 512; ++i) {
    if (buf[i] != '\0')
      break;
  }
  if (i != 512)
    return (-1);
  if (!in_resync && (++*cnt >= 2))
    return (0);
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<sdtools_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L12
L6:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
L12:
  leave
  ret
```

assistant: ```c
void *sdtools_malloc(size_t size) {
  if (!size)
    return (void *)0;
  return (void *)malloc(size);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sdtools_malloc>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
L1:
  ret
```

assistant: ```c
void *sdtools_malloc(size_t size) {
  if (!size)
    return (void *)0;
  return (void *)malloc(size);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sdtools_malloc>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <malloc@plt>
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *sdtools_malloc(size_t size) {
  if (!size)
    return (void *)0;
  return (void *)malloc(size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sdtools_malloc>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <malloc@plt>
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *sdtools_malloc(size_t size) {
  if (!size)
    return (void *)0;
  return (void *)malloc(size);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x8c(%rbp)
  movl   $0x1,-0x90(%rbp)
  mov    -0x94(%rbp),%eax
  cltq
  movl   $0x2,-0x90(%rbp,%rax,4)
  mov    -0x90(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int foo(int i) {
  int a[32];
  a[1] = 3;
  a[0] = 1;
  a[i] = 2;
  return a[0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movslq %edi,%rdi
  movl   $0x2,(%rsp,%rdi,4)
  mov    (%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x98,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int i) {
  int a[32];
  a[1] = 3;
  a[0] = 1;
  a[i] = 2;
  return a[0];
}
```