ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<give_the_fact_name>:
  endbr64
  push   %rbx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L44
  mov    $0x1,%eax
L6:
  mov    %eax,%ecx
  cmpb   $0x0,(%rdi,%rax,1)
  sete   %dl
  cmp    $0x1,%eax
  setg   %sil
  add    $0x1,%rax
  or     %sil,%dl
  je     L6
  movslq %ecx,%rax
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x77,%dl
  je     L30
L37:
  mov    $0x0,%eax
  movslq %ecx,%rcx
  add    %rdi,%rcx
L46:
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x77,%dl
  jne    L46
L30:
  movss  D12(%rip),%xmm0
  call   <strchr@plt>
  mov    %rax,%rcx
  mov    $0x0,%edx
  lea    D18(%rip),%rsi
  mov    $0x0,%ebx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
L44:
  mov    $0x0,%ecx
  jmp    L37
```

tool_calls: name: unpack_data
arguments: tag: D12
type: byte[4]
name: unpack_data
arguments: tag: D18
type: string

tool: {"D12": [0x00,0x00,0xcc,0x42]}

tool: D18: %s%s

assistant: ```c
char *give_the_fact_name(char *str) {
  int i = 0;
  int j = 0;
  char *t, *t1;
  char *str2;
  while (str[i] != '\0') {
    if (i > 1)
      break;
    i++;
  }
  while (str[i] != 'w') {
    str2[j++] = str[i++];
  }
  str2[j] = '\0';
  t = strchr(str, 'f');
  sprintf(t1, "%s%s", str2, t);
  return t1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<give_the_fact_name>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  cmpb   $0x0,(%rdi)
  je     L0
  cmpb   $0x0,0x1(%rdi)
  je     L26
  movzbl 0x2(%rdi),%edx
  mov    $0x2,%ecx
  test   %dl,%dl
  je     L0
  cmp    $0x77,%dl
  je     L16
L13:
  xor    %eax,%eax
  add    %rdi,%rcx
  nopl   0x0(%rax)
L36:
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x77,%dl
  jne    L36
L16:
  movss  D8(%rip),%xmm0
  call   <strchr@plt>
  xor    %edx,%edx
  lea    D11(%rip),%rsi
  xor    %edi,%edi
  mov    %rax,%rcx
  call   <sprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L26:
  mov    $0x1,%ecx
L0:
  xor    %edx,%edx
  jmp    L13
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: byte[4]
name: read_data
arguments: data_label: D11
data_type: string

tool: {"D8": [0x00,0x00,0xcc,0x42]}

tool: D11: %s%s

assistant: ```c
char *give_the_fact_name(char *str) {
  int i = 0;
  int j = 0;
  char *t, *t1;
  char *str2;
  while (str[i] != '\0') {
    if (i > 1)
      break;
    i++;
  }
  while (str[i] != 'w') {
    str2[j++] = str[i++];
  }
  str2[j] = '\0';
  t = strchr(str, 'f');
  sprintf(t1, "%s%s", str2, t);
  return t1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<give_the_fact_name>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  cmpb   $0x0,(%rdi)
  je     L47
  cmpb   $0x0,0x1(%rdi)
  je     L55
  movzbl 0x2(%rdi),%edx
  mov    $0x2,%ecx
  test   %dl,%dl
  je     L47
  cmp    $0x77,%dl
  je     L13
L58:
  xor    %eax,%eax
  add    %rdi,%rcx
  nopl   0x0(%rax)
L57:
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x77,%dl
  jne    L57
L13:
  movss  D9(%rip),%xmm0
  call   <strchr@plt>
  xor    %edx,%edx
  lea    D2(%rip),%rsi
  xor    %edi,%edi
  mov    %rax,%rcx
  call   <sprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L55:
  mov    $0x1,%ecx
L47:
  xor    %edx,%edx
  jmp    L58
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: byte[4]
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: {"D9": [0x00,0x00,0xcc,0x42]}

tool: D2: %s%s

assistant: ```c
char *give_the_fact_name(char *str) {
  int i = 0;
  int j = 0;
  char *t, *t1;
  char *str2;
  while (str[i] != '\0') {
    if (i > 1)
      break;
    i++;
  }
  while (str[i] != 'w') {
    str2[j++] = str[i++];
  }
  str2[j] = '\0';
  t = strchr(str, 'f');
  sprintf(t1, "%s%s", str2, t);
  return t1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<int_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int int_pos(void *iptr) {
  int *i = iptr;
  return *i > 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<int_pos>:
  endbr64
  cmpl   $0x0,(%rdi)
  setg   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int int_pos(void *iptr) {
  int *i = iptr;
  return *i > 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<int_pos>:
  endbr64
  mov    (%rdi),%edx
  xor    %eax,%eax
  test   %edx,%edx
  setg   %al
  ret
```

assistant: ```c
int int_pos(void *iptr) {
  int *i = iptr;
  return *i > 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bin16_to_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzwl -0x2(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bin16_to_8(int a, unsigned char *b) {
  unsigned short temp = a;
  b[0] = (unsigned char)(temp >> 8);
  b[1] = (unsigned char)temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bin16_to_8>:
  endbr64
  mov    %edi,%eax
  movzbl %ah,%edx
  mov    %dl,(%rsi)
  mov    %dil,0x1(%rsi)
  ret
```

assistant: ```c
void bin16_to_8(int a, unsigned char *b) {
  unsigned short temp = a;
  b[0] = (unsigned char)(temp >> 8);
  b[1] = (unsigned char)temp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bin16_to_8>:
  endbr64
  rol    $0x8,%di
  mov    %di,(%rsi)
  ret
```

assistant: ```c
void bin16_to_8(int a, unsigned char *b) {
  unsigned short temp = a;
  b[0] = (unsigned char)(temp >> 8);
  b[1] = (unsigned char)temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bin16_to_8>:
  endbr64
  rol    $0x8,%di
  mov    %di,(%rsi)
  ret
```

assistant: ```c
void bin16_to_8(int a, unsigned char *b) {
  unsigned short temp = a;
  b[0] = (unsigned char)(temp >> 8);
  b[1] = (unsigned char)temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L9
L31:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L4:
  movl   $0x0,-0x4(%rbp)
  jmp    L57
L58:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  and    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L57:
  cmpl   $0x0,-0x4(%rbp)
  je     L58
  subl   $0x1,-0xc(%rbp)
L11:
  cmpl   $0xfffffff5,-0xc(%rbp)
  jne    L4
  addl   $0x1,-0x14(%rbp)
L9:
  cmpl   $0x4,-0x14(%rbp)
  jle    L31
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test(int a, int *i) {
  for (; a < 5; ++a) {
    int b = 0;
    int c = 0;
    for (; b != -11; b--)
      for (int d = 0; d == 0; d++) {
        *i += c & a;
        c = b;
      }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  cmp    $0x4,%edi
  jg     L25
  mov    (%rsi),%ecx
  mov    $0x0,%r9d
  jmp    L47
L5:
  mov    %r8d,%edx
L46:
  and    %edi,%eax
  add    %eax,%ecx
  lea    -0x1(%rdx),%r8d
  mov    %edx,%eax
  cmp    $0xfffffff6,%edx
  jne    L5
  add    $0x1,%edi
  cmp    $0x5,%edi
  je     L10
L47:
  mov    %r9d,%eax
  mov    %r9d,%edx
  jmp    L46
L10:
  mov    %ecx,(%rsi)
L25:
  ret
```

assistant: ```c
void test(int a, int *i) {
  for (; a < 5; ++a) {
    int b = 0;
    int c = 0;
    for (; b != -11; b--)
      for (int d = 0; d == 0; d++) {
        *i += c & a;
        c = b;
      }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test>:
  endbr64
  cmp    $0x4,%edi
  jg     L27
  mov    (%rsi),%ecx
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  xor    %edx,%edx
L36:
  and    %edi,%eax
  lea    -0x1(%rdx),%r8d
  add    %eax,%ecx
  cmp    $0xfffffff6,%edx
  jne    L1
  add    $0x1,%edi
  cmp    $0x5,%edi
  jne    L34
  mov    %ecx,(%rsi)
L27:
  ret
L1:
  mov    %edx,%eax
  mov    %r8d,%edx
  jmp    L36
```

assistant: ```c
void test(int a, int *i) {
  for (; a < 5; ++a) {
    int b = 0;
    int c = 0;
    for (; b != -11; b--)
      for (int d = 0; d == 0; d++) {
        *i += c & a;
        c = b;
      }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L9
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <jiecheng@plt>
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L9:
  cmpl   $0x14,-0xc(%rbp)
  jle    L6
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: %f


assistant: ```c
void main() {
  int num = 1;
  double sum = 0;
  for (; num <= 20; num++) {
    sum = sum + jiecheng(num);
  }
  printf("%f\n", sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
  mov    $0x1,%ebx
L0:
  mov    %ebx,%edi
  call   <jiecheng@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  cmp    $0x15,%ebx
  jne    L0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0: %f


assistant: ```c
void main() {
  int num = 1;
  double sum = 0;
  for (; num <= 20; num++) {
    sum = sum + jiecheng(num);
  }
  printf("%f\n", sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  pxor   %xmm2,%xmm2
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <jiecheng@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    $0x15,%ebx
  jne    L1
  add    $0x10,%rsp
  lea    D4(%rip),%rdi
  pop    %rbx
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %f


assistant: ```c
void main() {
  int num = 1;
  double sum = 0;
  for (; num <= 20; num++) {
    sum = sum + jiecheng(num);
  }
  printf("%f\n", sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  pxor   %xmm2,%xmm2
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <jiecheng@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    $0x15,%ebx
  jne    L4
  add    $0x10,%rsp
  lea    D6(%rip),%rdi
  pop    %rbx
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: %f


assistant: ```c
void main() {
  int num = 1;
  double sum = 0;
  for (; num <= 20; num++) {
    sum = sum + jiecheng(num);
  }
  printf("%f\n", sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CANRegWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L1:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    $0x4,%eax
  jle    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CANRegWrite(unsigned long ulRegAddress, unsigned long ulRegValue) {
  volatile int iDelay;
  (*((volatile unsigned long *)(ulRegAddress))) = ulRegValue;
  for (iDelay = 0; iDelay < 5; iDelay++) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CANRegWrite>:
  endbr64
  mov    %rsi,(%rdi)
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x4,%eax
  jg     L12
L19:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x4,%eax
  jle    L19
L12:
  ret
```

assistant: ```c
void CANRegWrite(unsigned long ulRegAddress, unsigned long ulRegValue) {
  volatile int iDelay;
  (*((volatile unsigned long *)(ulRegAddress))) = ulRegValue;
  for (iDelay = 0; iDelay < 5; iDelay++) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CANRegWrite>:
  endbr64
  mov    %rsi,(%rdi)
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x4,%eax
  jg     L6
  nopl   0x0(%rax,%rax,1)
L14:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x4,%eax
  jle    L14
L6:
  ret
```

assistant: ```c
void CANRegWrite(unsigned long ulRegAddress, unsigned long ulRegValue) {
  volatile int iDelay;
  (*((volatile unsigned long *)(ulRegAddress))) = ulRegValue;
  for (iDelay = 0; iDelay < 5; iDelay++) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CANRegWrite>:
  endbr64
  mov    %rsi,(%rdi)
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x4,%eax
  jg     L1
  nopl   0x0(%rax,%rax,1)
L5:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x4,%eax
  jle    L5
L1:
  ret
```

assistant: ```c
void CANRegWrite(unsigned long ulRegAddress, unsigned long ulRegValue) {
  volatile int iDelay;
  (*((volatile unsigned long *)(ulRegAddress))) = ulRegValue;
  for (iDelay = 0; iDelay < 5; iDelay++) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<generate_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L13
L17:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movabs $0x8000000100000003,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1e,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x1f,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x10(%rbp),%rcx
  movabs $0x8000000100000003,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1e,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x1f,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long generate_id(char *str) {
  long sum = 0, i;
  for (i = 0; str[i] != '\0'; i++) {
    sum = (sum + str[i]) % 2147483647;
  }
  return sum % 2147483647;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<generate_id>:
  endbr64
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L28
  add    $0x1,%rdi
  mov    $0x0,%ecx
  movabs $0x8000000100000003,%r8
L1:
  movsbq %sil,%rsi
  add    %rcx,%rsi
  mov    %rsi,%rax
  imul   %r8
  lea    (%rdx,%rsi,1),%rcx
  sar    $0x1e,%rcx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rcx
  mov    %rcx,%rax
  shl    $0x1f,%rax
  sub    %rcx,%rax
  mov    %rsi,%rcx
  sub    %rax,%rcx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%esi
  test   %sil,%sil
  jne    L1
L21:
  movabs $0x8000000100000003,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1e,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x1f,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  ret
L28:
  mov    $0x0,%ecx
  jmp    L21
```

assistant: ```c
long generate_id(char *str) {
  long sum = 0, i;
  for (i = 0; str[i] != '\0'; i++) {
    sum = (sum + str[i]) % 2147483647;
  }
  return sum % 2147483647;
}
```
user: What is the c source code of the assembly code below:

```asm
<generate_id>:
  endbr64
  movsbq (%rdi),%rcx
  test   %cl,%cl
  je     L7
  movabs $0x8000000100000003,%rsi
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  add    %rax,%rcx
  add    $0x1,%rdi
  mov    %rcx,%rax
  imul   %rsi
  lea    (%rdx,%rcx,1),%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sar    $0x1e,%rax
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x1f,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  movsbq -0x1(%rdi),%rcx
  sub    %rdx,%rax
  test   %cl,%cl
  jne    L3
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
long generate_id(char *str) {
  long sum = 0, i;
  for (i = 0; str[i] != '\0'; i++) {
    sum = (sum + str[i]) % 2147483647;
  }
  return sum % 2147483647;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generate_id>:
  endbr64
  movsbq (%rdi),%rcx
  test   %cl,%cl
  je     L1
  movabs $0x8000000100000003,%rsi
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L17:
  add    %rax,%rcx
  add    $0x1,%rdi
  mov    %rcx,%rax
  imul   %rsi
  lea    (%rdx,%rcx,1),%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sar    $0x1e,%rax
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x1f,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  movsbq -0x1(%rdi),%rcx
  sub    %rdx,%rax
  test   %cl,%cl
  jne    L17
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
long generate_id(char *str) {
  long sum = 0, i;
  for (i = 0; str[i] != '\0'; i++) {
    sum = (sum + str[i]) % 2147483647;
  }
  return sum % 2147483647;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setEnviron>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <putenv@plt>
  test   %rax,%rax
  jns    L2
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: string

tool: D7: Cannot set or add env variable

assistant: ```c
void setEnviron(char *param) {
  if (0 > putenv(param)) {
    perror("Cannot set or add env variable");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<setEnviron>:
  endbr64
  sub    $0x8,%rsp
  call   <putenv@plt>
  test   %rax,%rax
  js     L15
L14:
  add    $0x8,%rsp
  ret
L15:
  lea    D8(%rip),%rdi
  call   <perror@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: Cannot set or add env variable

assistant: ```c
void setEnviron(char *param) {
  if (0 > putenv(param)) {
    perror("Cannot set or add env variable");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<setEnviron>:
  endbr64
  sub    $0x8,%rsp
  call   <putenv@plt>
  test   %rax,%rax
  js     L8
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <perror@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string

tool: D4: Cannot set or add env variable

assistant: ```c
void setEnviron(char *param) {
  if (0 > putenv(param)) {
    perror("Cannot set or add env variable");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<setEnviron>:
  endbr64
  sub    $0x8,%rsp
  call   <putenv@plt>
  test   %rax,%rax
  js     L1
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <perror@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D0: Cannot set or add env variable

assistant: ```c
void setEnviron(char *param) {
  if (0 > putenv(param)) {
    perror("Cannot set or add env variable");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<draw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <move@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  nop
  leave
  ret
```

assistant: ```c
void draw(const struct game *g) {
  move(0, 0);
  print(g);
  refresh();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <move@plt>
  mov    %rbx,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  pop    %rbx
  ret
```

assistant: ```c
void draw(const struct game *g) {
  move(0, 0);
  print(g);
  refresh();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<draw>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <move@plt>
  mov    %rbp,%rdi
  call   <print@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <refresh@plt>
```

assistant: ```c
void draw(const struct game *g) {
  move(0, 0);
  print(g);
  refresh();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <move@plt>
  mov    %rbp,%rdi
  call   <print@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <refresh@plt>
```

assistant: ```c
void draw(const struct game *g) {
  move(0, 0);
  print(g);
  refresh();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x40,%ebx
  jmp    L2
L13:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  xor    %rcx,%rdx
  mov    %rdx,(%rax)
L2:
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  test   %eax,%eax
  jne    L13
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void xor (unsigned long long *block, unsigned long long *xkey) {
  register int i = 64;
  while (i--) {
    block[i] ^= xkey[i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<xor>:
  endbr64
  mov    $0x1f8,%eax
L4:
  mov    (%rsi,%rax,1),%rdx
  xor    %rdx,(%rdi,%rax,1)
  sub    $0x8,%rax
  cmp    $0xfffffffffffffff8,%rax
  jne    L4
  ret
```

assistant: ```c
void xor (unsigned long long *block, unsigned long long *xkey) {
  register int i = 64;
  while (i--) {
    block[i] ^= xkey[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xor>:
  endbr64
  mov    $0x1f8,%eax
  nopl   0x0(%rax)
L2:
  mov    (%rsi,%rax,1),%rdx
  xor    %rdx,(%rdi,%rax,1)
  sub    $0x8,%rax
  cmp    $0xfffffffffffffff8,%rax
  jne    L2
  ret
```

assistant: ```c
void xor (unsigned long long *block, unsigned long long *xkey) {
  register int i = 64;
  while (i--) {
    block[i] ^= xkey[i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<xor>:
  endbr64
  lea    0x1f0(%rsi),%rdx
  lea    0x1f8(%rdi),%rax
  cmp    %rax,%rdx
  je     L0
  mov    $0x1f0,%eax
  nopl   0x0(%rax)
L10:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm1
  shufpd $0x1,%xmm0,%xmm0
  shufpd $0x1,%xmm1,%xmm1
  pxor   %xmm1,%xmm0
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  sub    $0x10,%rax
  cmp    $0xfffffffffffffff0,%rax
  jne    L10
  ret
L0:
  mov    $0x1f8,%eax
  nopl   0x0(%rax)
L29:
  mov    (%rsi,%rax,1),%rdx
  xor    %rdx,(%rdi,%rax,1)
  sub    $0x8,%rax
  cmp    $0xfffffffffffffff8,%rax
  jne    L29
  ret
```

assistant: ```c
void xor (unsigned long long *block, unsigned long long *xkey) {
  register int i = 64;
  while (i--) {
    block[i] ^= xkey[i];
  }
}
```