ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rdtsc>:
  endbr64
L3:
  rdtsc
  mov    %rax,%rcx
  rdtsc
  mov    %rax,%rdx
  sub    %rcx,%rdx
  cmp    $0x3e7,%rdx
  ja     L3
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned long long int x, y;
  for (;;) {
    __asm__ volatile("rdtsc" : "=A"(x));
    __asm__ volatile("rdtsc" : "=A"(y));
    if (y - x < 1000)
      return y;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rdtsc>:
  endbr64
  nopl   0x0(%rax)
L8:
  rdtsc
  mov    %rax,%rcx
  rdtsc
  mov    %rax,%rdx
  sub    %rcx,%rdx
  cmp    $0x3e7,%rdx
  ja     L8
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned long long int x, y;
  for (;;) {
    __asm__ volatile("rdtsc" : "=A"(x));
    __asm__ volatile("rdtsc" : "=A"(y));
    if (y - x < 1000)
      return y;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rdtsc>:
  endbr64
  nopl   0x0(%rax)
L3:
  rdtsc
  mov    %rax,%rcx
  rdtsc
  mov    %rax,%rdx
  sub    %rcx,%rdx
  cmp    $0x3e7,%rdx
  ja     L3
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned long long int x, y;
  for (;;) {
    __asm__ volatile("rdtsc" : "=A"(x));
    __asm__ volatile("rdtsc" : "=A"(y));
    if (y - x < 1000)
      return y;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x718(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r14d
  mov    $0x0,%r12d
  lea    D9(%rip),%r13
  jmp    L106
L73:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %r12d,%ebx
  jle    L73
L109:
  add    $0x1,%r12d
  add    $0xf,%r14
  cmp    $0xf,%r12d
  je     L72
L106:
  lea    (%rsp,%r14,4),%rbp
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jns    L73
  jmp    L109
L72:
  mov    (%rsp),%eax
  mov    %eax,0x390(%rsp)
  lea    0x3c(%rsp),%r9
  lea    0x3cc(%rsp),%rsi
  mov    $0x2,%r8d
  mov    $0x1,%r10d
  jmp    L129
L140:
  mov    (%r9),%edx
  add    -0x3c(%rsi),%edx
  mov    %edx,(%rsi)
L32:
  add    $0x1,%rax
  add    $0x4,%rcx
  cmp    %r8,%rax
  je     L23
L54:
  test   %eax,%eax
  je     L140
  cmp    %eax,%r10d
  je     L149
  mov    0x4(%rcx),%edx
  mov    (%rcx),%edi
  cmp    %edi,%edx
  cmovl  %edi,%edx
  add    (%r9,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  jmp    L32
L149:
  mov    (%r9,%rax,4),%edx
  add    (%rcx),%edx
  mov    %edx,(%rsi,%rax,4)
  jmp    L32
L23:
  add    $0x1,%r10d
  add    $0x1,%r8
  add    $0x3c,%r9
  add    $0x3c,%rsi
  cmp    $0xf,%r10d
  je     L11
L129:
  lea    -0x40(%rsi),%rcx
  mov    $0x0,%eax
  test   %r10d,%r10d
  jns    L54
  jmp    L23
L11:
  lea    0x6d8(%rsp),%rax
  lea    0x714(%rsp),%rcx
  mov    $0x0,%esi
L34:
  mov    (%rax),%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L34
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x720,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D9: %d

tool: D8: %d


assistant: ```c
int main() {
  int i, j, a[15][15], b[15][15], max = 0;
  for (i = 0; i < 15; i++) {
    for (j = 0; j <= i; j++) {
      scanf("%d", &(a[i][j]));
    }
  }
  b[0][0] = a[0][0];
  for (i = 1; i < 15; i++) {
    for (j = 0; j <= i; j++) {
      if (j == 0)
        b[i][j] = b[i - 1][j] + a[i][j];
      else if (j == i)
        b[i][j] = b[i - 1][j - 1] + a[i][j];
      else {
        b[i][j] = (b[i - 1][j - 1] > b[i - 1][j] ? b[i - 1][j - 1] : b[i - 1][j]) + a[i][j];
      }
    }
  }
  for (i = 0; i < 15; i++) {
    if (b[14][i] > max)
      max = b[14][i];
  }
  printf("%d\n", max);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0x4(%rsp),%rbp
  lea    0x3c4(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L48:
  lea    (%r15,%r13,4),%rbx
  nopl   0x0(%rax)
L47:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %rbp,%rbx
  jne    L47
  lea    0x40(%rbx),%rbp
  add    $0xf,%r13
  cmp    %r14,%rbp
  jne    L48
  mov    (%rsp),%eax
  lea    0x3c(%rsp),%r9
  mov    $0x1,%edi
  lea    0x3cc(%rsp),%r10
  mov    %eax,0x390(%rsp)
  nopl   (%rax)
L4:
  mov    %r10,%rdx
  xor    %eax,%eax
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L21:
  mov    -0x40(%rdx),%ecx
  mov    (%r9,%rax,4),%esi
  cmp    %edi,%eax
  je     L0
  mov    -0x3c(%rdx),%r8d
  cmp    %r8d,%ecx
  cmovl  %r8d,%ecx
L0:
  add    %esi,%ecx
  mov    %ecx,(%rdx)
  lea    0x1(%rax),%ecx
  cmp    %edi,%ecx
  jg     L61
L27:
  add    $0x1,%rax
  add    $0x4,%rdx
L12:
  test   %rax,%rax
  jne    L21
  mov    (%r9),%ecx
  add    -0x3c(%r10),%ecx
  mov    %ecx,(%r10)
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L61:
  add    $0x1,%edi
  add    $0x3c,%r9
  add    $0x3c,%r10
  cmp    $0xf,%edi
  jne    L4
  lea    0x6d8(%rsp),%rax
  lea    0x714(%rsp),%rcx
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L81:
  mov    (%rax),%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L81
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x728,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D16
type: string
name: unpack_data
arguments: data_label: D18
type: string

tool: D16: %d

tool: D18: %d


assistant: ```c
int main() {
  int i, j, a[15][15], b[15][15], max = 0;
  for (i = 0; i < 15; i++) {
    for (j = 0; j <= i; j++) {
      scanf("%d", &(a[i][j]));
    }
  }
  b[0][0] = a[0][0];
  for (i = 1; i < 15; i++) {
    for (j = 0; j <= i; j++) {
      if (j == 0)
        b[i][j] = b[i - 1][j] + a[i][j];
      else if (j == i)
        b[i][j] = b[i - 1][j - 1] + a[i][j];
      else {
        b[i][j] = (b[i - 1][j - 1] > b[i - 1][j] ? b[i - 1][j - 1] : b[i - 1][j]) + a[i][j];
      }
    }
  }
  for (i = 0; i < 15; i++) {
    if (b[14][i] > max)
      max = b[14][i];
  }
  printf("%d\n", max);
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: usage: %s --addr x.x.x.x [--mask x.x.x.x] [--net x.x.x.x] [--gw x.x.x.x] [--if x] [--help]


assistant: ```c
usage(char *name, int rc) {
  printf("usage: %s --addr x.x.x.x [--mask x.x.x.x] "
         "[--net x.x.x.x] [--gw x.x.x.x] [--if x] [--help]\n",
         name);
  exit(rc);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: usage: %s --addr x.x.x.x [--mask x.x.x.x] [--net x.x.x.x] [--gw x.x.x.x] [--if x] [--help]


assistant: ```c
usage(char *name, int rc) {
  printf("usage: %s --addr x.x.x.x [--mask x.x.x.x] "
         "[--net x.x.x.x] [--gw x.x.x.x] [--if x] [--help]\n",
         name);
  exit(rc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: usage: %s --addr x.x.x.x [--mask x.x.x.x] [--net x.x.x.x] [--gw x.x.x.x] [--if x] [--help]


assistant: ```c
usage(char *name, int rc) {
  printf("usage: %s --addr x.x.x.x [--mask x.x.x.x] "
         "[--net x.x.x.x] [--gw x.x.x.x] [--if x] [--help]\n",
         name);
  exit(rc);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string

tool: D9: usage: %s --addr x.x.x.x [--mask x.x.x.x] [--net x.x.x.x] [--gw x.x.x.x] [--if x] [--help]


assistant: ```c
usage(char *name, int rc) {
  printf("usage: %s --addr x.x.x.x [--mask x.x.x.x] "
         "[--net x.x.x.x] [--gw x.x.x.x] [--if x] [--help]\n",
         name);
  exit(rc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <init_display@plt>
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <update_field@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x3,%edi
  call   <update_field@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x6,%edi
  call   <update_field@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x9,%edi
  call   <update_field@plt>
  mov    $0x2e9b,%edi
  call   <i8253_set@plt>
L13:
  nop
L68:
  mov    $0x0,%eax
  call   <i8253_get@plt>
  cmp    $0x2e9b,%eax
  jne    L68
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x63,-0x4(%rbp)
  jle    L9
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x3b,-0x8(%rbp)
  jle    L38
  movl   $0x0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
  cmpl   $0x3b,-0xc(%rbp)
  jle    L19
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  cmpl   $0x17,-0x10(%rbp)
  jle    L31
  movl   $0x0,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <update_field@plt>
L19:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x3,%edi
  call   <update_field@plt>
L38:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x6,%edi
  call   <update_field@plt>
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x9,%edi
  call   <update_field@plt>
  nop
L69:
  mov    $0x0,%eax
  call   <i8253_get@plt>
  cmp    $0x2e9b,%eax
  je     L69
  jmp    L13
```

assistant: ```c
void clock() {
  int hours, mins, secs, hund;
  init_display();
  hours = mins = secs = hund = 0;
  update_field(0, hours);
  update_field(3, mins);
  update_field(6, secs);
  update_field(9, hund);
  i8253_set((1193181 / 100));
  while (1) {
    while (i8253_get() != (1193181 / 100))
      ;
    hund++;
    if (hund > 99) {
      hund = 0;
      secs++;
      if (secs > 59) {
        secs = 0;
        mins++;
        if (mins > 59) {
          mins = 0;
          hours++;
          if (hours > 23)
            hours = 0;
          update_field(0, hours);
        }
        update_field(3, mins);
      }
      update_field(6, secs);
    }
    update_field(9, hund);
    while (i8253_get() == (1193181 / 100))
      ;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clock>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <init_display@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <update_field@plt>
  mov    $0x0,%esi
  mov    $0x3,%edi
  call   <update_field@plt>
  mov    $0x0,%esi
  mov    $0x6,%edi
  call   <update_field@plt>
  mov    $0x0,%esi
  mov    $0x9,%edi
  call   <update_field@plt>
  mov    $0x2e9b,%edi
  call   <i8253_set@plt>
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  jmp    L68
L29:
  mov    %r12d,%esi
  mov    $0x3,%edi
  call   <update_field@plt>
  mov    $0x0,%ebp
L7:
  mov    %ebp,%esi
  mov    $0x6,%edi
  call   <update_field@plt>
  mov    $0x0,%ebx
L6:
  mov    %ebx,%esi
  mov    $0x9,%edi
  call   <update_field@plt>
L43:
  mov    $0x0,%eax
  call   <i8253_get@plt>
  cmp    $0x2e9b,%eax
  je     L43
L68:
  mov    $0x0,%eax
  call   <i8253_get@plt>
  cmp    $0x2e9b,%eax
  jne    L68
  add    $0x1,%ebx
  cmp    $0x63,%ebx
  jle    L6
  add    $0x1,%ebp
  cmp    $0x3b,%ebp
  jle    L7
  add    $0x1,%r12d
  cmp    $0x3b,%r12d
  jle    L29
  add    $0x1,%r13d
  cmp    $0x18,%r13d
  cmovge %r14d,%r13d
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <update_field@plt>
  mov    $0x0,%r12d
  jmp    L29
```

assistant: ```c
void clock() {
  int hours, mins, secs, hund;
  init_display();
  hours = mins = secs = hund = 0;
  update_field(0, hours);
  update_field(3, mins);
  update_field(6, secs);
  update_field(9, hund);
  i8253_set((1193181 / 100));
  while (1) {
    while (i8253_get() != (1193181 / 100))
      ;
    hund++;
    if (hund > 99) {
      hund = 0;
      secs++;
      if (secs > 59) {
        secs = 0;
        mins++;
        if (mins > 59) {
          mins = 0;
          hours++;
          if (hours > 23)
            hours = 0;
          update_field(0, hours);
        }
        update_field(3, mins);
      }
      update_field(6, secs);
    }
    update_field(9, hund);
    while (i8253_get() == (1193181 / 100))
      ;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clock>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  call   <init_display@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <update_field@plt>
  xor    %esi,%esi
  mov    $0x3,%edi
  call   <update_field@plt>
  xor    %esi,%esi
  mov    $0x6,%edi
  call   <update_field@plt>
  xor    %esi,%esi
  mov    $0x9,%edi
  call   <update_field@plt>
  mov    $0x2e9b,%edi
  call   <i8253_set@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <i8253_get@plt>
  cmp    $0x2e9b,%eax
  jne    L1
  add    $0x1,%ebx
  cmp    $0x63,%ebx
  jle    L35
  add    $0x1,%ebp
  cmp    $0x3b,%ebp
  jle    L22
  add    $0x1,%r12d
  cmp    $0x3b,%r12d
  jle    L39
  add    $0x1,%r13d
  cmp    $0x18,%r13d
  cmovge %r14d,%r13d
  xor    %edi,%edi
  xor    %r12d,%r12d
  mov    %r13d,%esi
  call   <update_field@plt>
L39:
  mov    %r12d,%esi
  mov    $0x3,%edi
  xor    %ebp,%ebp
  call   <update_field@plt>
L22:
  mov    %ebp,%esi
  mov    $0x6,%edi
  xor    %ebx,%ebx
  call   <update_field@plt>
L35:
  mov    %ebx,%esi
  mov    $0x9,%edi
  call   <update_field@plt>
L23:
  xor    %eax,%eax
  call   <i8253_get@plt>
  cmp    $0x2e9b,%eax
  jne    L1
  jmp    L23
```

assistant: ```c
void clock() {
  int hours, mins, secs, hund;
  init_display();
  hours = mins = secs = hund = 0;
  update_field(0, hours);
  update_field(3, mins);
  update_field(6, secs);
  update_field(9, hund);
  i8253_set((1193181 / 100));
  while (1) {
    while (i8253_get() != (1193181 / 100))
      ;
    hund++;
    if (hund > 99) {
      hund = 0;
      secs++;
      if (secs > 59) {
        secs = 0;
        mins++;
        if (mins > 59) {
          mins = 0;
          hours++;
          if (hours > 23)
            hours = 0;
          update_field(0, hours);
        }
        update_field(3, mins);
      }
      update_field(6, secs);
    }
    update_field(9, hund);
    while (i8253_get() == (1193181 / 100))
      ;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clock>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  call   <init_display@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <update_field@plt>
  xor    %esi,%esi
  mov    $0x3,%edi
  call   <update_field@plt>
  xor    %esi,%esi
  mov    $0x6,%edi
  call   <update_field@plt>
  xor    %esi,%esi
  mov    $0x9,%edi
  call   <update_field@plt>
  mov    $0x2e9b,%edi
  call   <i8253_set@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <i8253_get@plt>
  cmp    $0x2e9b,%eax
  jne    L3
  add    $0x1,%ebx
  cmp    $0x63,%ebx
  jle    L9
  add    $0x1,%ebp
  cmp    $0x3b,%ebp
  jle    L35
  add    $0x1,%r12d
  cmp    $0x3b,%r12d
  jle    L53
  add    $0x1,%r13d
  cmp    $0x18,%r13d
  cmovge %r14d,%r13d
  xor    %edi,%edi
  xor    %r12d,%r12d
  mov    %r13d,%esi
  call   <update_field@plt>
L53:
  mov    %r12d,%esi
  mov    $0x3,%edi
  xor    %ebp,%ebp
  call   <update_field@plt>
L35:
  mov    %ebp,%esi
  mov    $0x6,%edi
  xor    %ebx,%ebx
  call   <update_field@plt>
L9:
  mov    %ebx,%esi
  mov    $0x9,%edi
  call   <update_field@plt>
L14:
  xor    %eax,%eax
  call   <i8253_get@plt>
  cmp    $0x2e9b,%eax
  jne    L3
  jmp    L14
```

assistant: ```c
void clock() {
  int hours, mins, secs, hund;
  init_display();
  hours = mins = secs = hund = 0;
  update_field(0, hours);
  update_field(3, mins);
  update_field(6, secs);
  update_field(9, hund);
  i8253_set((1193181 / 100));
  while (1) {
    while (i8253_get() != (1193181 / 100))
      ;
    hund++;
    if (hund > 99) {
      hund = 0;
      secs++;
      if (secs > 59) {
        secs = 0;
        mins++;
        if (mins > 59) {
          mins = 0;
          hours++;
          if (hours > 23)
            hours = 0;
          update_field(0, hours);
        }
        update_field(3, mins);
      }
      update_field(6, secs);
    }
    update_field(9, hund);
    while (i8253_get() == (1193181 / 100))
      ;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PicocPlatformScanFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <PlatformReadFile@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <PicocParse@plt>
  nop
  leave
  ret
```

assistant: ```c
void PicocPlatformScanFile(const char *FileName) {
  char *SourceStr = PlatformReadFile(FileName);
  PicocParse(FileName, SourceStr, strlen(SourceStr), 1, 0, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PicocPlatformScanFile>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <PlatformReadFile@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <PicocParse@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void PicocPlatformScanFile(const char *FileName) {
  char *SourceStr = PlatformReadFile(FileName);
  PicocParse(FileName, SourceStr, strlen(SourceStr), 1, 0, 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<PicocPlatformScanFile>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <PlatformReadFile@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  pop    %r12
  jmp    1080 <PicocParse@plt>
```

assistant: ```c
void PicocPlatformScanFile(const char *FileName) {
  char *SourceStr = PlatformReadFile(FileName);
  PicocParse(FileName, SourceStr, strlen(SourceStr), 1, 0, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PicocPlatformScanFile>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <PlatformReadFile@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  pop    %r12
  jmp    1080 <PicocParse@plt>
```

assistant: ```c
void PicocPlatformScanFile(const char *FileName) {
  char *SourceStr = PlatformReadFile(FileName);
  PicocParse(FileName, SourceStr, strlen(SourceStr), 1, 0, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<file_get_contents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <genrb@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L25
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  jmp    L29
L18:
  mov    -0x40(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %dl,(%rax)
L25:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x2c(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L18
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x40(%rbp),%rax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
char *file_get_contents(const char *filename, char *contents) {
  FILE *fp;
  int c;
  char rb[16];
  fp = fopen(filename, genrb(rb));
  if (fp == NULL) {
    contents[0] = '\0';
    return contents;
  }
  while ((c = fgetc(fp)) != EOF) {
    *contents++ = (char)c;
  }
  fclose(fp);
  return contents;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<file_get_contents>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <genrb@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L5
  movb   $0x0,(%rbx)
  mov    %rbx,%rax
  jmp    L33
L16:
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
L5:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    D8(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L16
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rax
L33:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *file_get_contents(const char *filename, char *contents) {
  FILE *fp;
  int c;
  char rb[16];
  fp = fopen(filename, genrb(rb));
  if (fp == NULL) {
    contents[0] = '\0';
    return contents;
  }
  while ((c = fgetc(fp)) != EOF) {
    *contents++ = (char)c;
  }
  fclose(fp);
  return contents;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<file_get_contents>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <genrb@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <fopen@plt>
  test   %rax,%rax
  je     L9
  mov    D5(%rip),%rbx
  mov    %rax,%rbp
  jmp    L17
  nopl   (%rax)
L19:
  mov    %al,(%r12)
  add    $0x1,%r12
L17:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%rbx)
  jne    L19
  mov    %rbp,%rdi
  call   <fclose@plt>
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  movb   $0x0,(%r12)
  jmp    L38
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *file_get_contents(const char *filename, char *contents) {
  FILE *fp;
  int c;
  char rb[16];
  fp = fopen(filename, genrb(rb));
  if (fp == NULL) {
    contents[0] = '\0';
    return contents;
  }
  while ((c = fgetc(fp)) != EOF) {
    *contents++ = (char)c;
  }
  fclose(fp);
  return contents;
}
```