ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<filter>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L13
  xorpd  D4(%rip),%xmm0
L13:
  movsd  D9(%rip),%xmm2
  comisd %xmm0,%xmm2
  ja     L1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L1:
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  subsd  D19(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: f32[4]
name: retrieve_data
arguments: data_tag: D9
datatype: f64
name: retrieve_data
arguments: data_tag: D19
datatype: f64

tool: {"D4": [0.0,-0.0,0.0,0.0]}

tool: D9: 1

tool: D19: 3

assistant: ```c
double filter(double t) {
  if (t < 0.0)
    t = -t;
  if (t < 1.0)
    return ((2.0 * t - 3.0) * t * t + 1.0);
  return 0.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<filter>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L16
  xorpd  D23(%rip),%xmm0
L16:
  movsd  D26(%rip),%xmm2
  comisd %xmm0,%xmm2
  ja     L0
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L0:
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  subsd  D4(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: f32[4]
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D4
type_guessed: f64

tool: {"D23": [0.0,-0.0,0.0,0.0]}

tool: D26: 1

tool: D4: 3

assistant: ```c
double filter(double t) {
  if (t < 0.0)
    t = -t;
  if (t < 1.0)
    return ((2.0 * t - 3.0) * t * t + 1.0);
  return 0.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initial_available_disk_names_and_sizes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: function foreign_disks() { return [];}
function foreign_disk_interface_names() { return [];}
function foreign_disk_model_info() { return [];}
function foreign_disk_total_size() { return [];}
function foreign_disk_total_mounted_number() { return [];}


assistant: ```c
extern char *initial_available_disk_names_and_sizes() {
  char *desc = "function foreign_disks() { return [];}\nfunction foreign_disk_interface_names() { return [];}\nfunction foreign_disk_model_info() { return [];}\nfunction foreign_disk_total_size() { return [];}\nfunction foreign_disk_total_mounted_number() { return [];}\n";
  return desc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initial_available_disk_names_and_sizes>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: function foreign_disks() { return [];}
function foreign_disk_interface_names() { return [];}
function foreign_disk_model_info() { return [];}
function foreign_disk_total_size() { return [];}
function foreign_disk_total_mounted_number() { return [];}


assistant: ```c
extern char *initial_available_disk_names_and_sizes() {
  char *desc = "function foreign_disks() { return [];}\nfunction foreign_disk_interface_names() { return [];}\nfunction foreign_disk_model_info() { return [];}\nfunction foreign_disk_total_size() { return [];}\nfunction foreign_disk_total_mounted_number() { return [];}\n";
  return desc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<initial_available_disk_names_and_sizes>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: function foreign_disks() { return [];}
function foreign_disk_interface_names() { return [];}
function foreign_disk_model_info() { return [];}
function foreign_disk_total_size() { return [];}
function foreign_disk_total_mounted_number() { return [];}


assistant: ```c
extern char *initial_available_disk_names_and_sizes() {
  char *desc = "function foreign_disks() { return [];}\nfunction foreign_disk_interface_names() { return [];}\nfunction foreign_disk_model_info() { return [];}\nfunction foreign_disk_total_size() { return [];}\nfunction foreign_disk_total_mounted_number() { return [];}\n";
  return desc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<initial_available_disk_names_and_sizes>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: function foreign_disks() { return [];}
function foreign_disk_interface_names() { return [];}
function foreign_disk_model_info() { return [];}
function foreign_disk_total_size() { return [];}
function foreign_disk_total_mounted_number() { return [];}


assistant: ```c
extern char *initial_available_disk_names_and_sizes() {
  char *desc = "function foreign_disks() { return [];}\nfunction foreign_disk_interface_names() { return [];}\nfunction foreign_disk_model_info() { return [];}\nfunction foreign_disk_total_size() { return [];}\nfunction foreign_disk_total_mounted_number() { return [];}\n";
  return desc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L0:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L0
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: Hello !


assistant: ```c
int main(void) {
  int i = 0;
  int j = 1;
  for (i = 0; i < j; i++)
    printf("Hello !\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: Hello !


assistant: ```c
int main(void) {
  int i = 0;
  int j = 1;
  for (i = 0; i < j; i++)
    printf("Hello !\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: Hello !


assistant: ```c
int main(void) {
  int i = 0;
  int j = 1;
  for (i = 0; i < j; i++)
    printf("Hello !\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: Hello !


assistant: ```c
int main(void) {
  int i = 0;
  int j = 1;
  for (i = 0; i < j; i++)
    printf("Hello !\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FormatIsValid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D38(%rip),%rdx
  push   %rdx
  lea    D38(%rip),%rdx
  push   %rdx
  lea    D38(%rip),%rdx
  push   %rdx
  lea    D38(%rip),%rdx
  push   %rdx
  lea    D38(%rip),%r9
  lea    D38(%rip),%r8
  lea    D38(%rip),%rdx
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <Format@plt>
  add    $0x20,%rsp
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D38
type_infered: string

tool: 

assistant: ```c
bool FormatIsValid(const char *format) {
  char *f;
  f = Format(NULL, format, 0, "", "", "", "", "", "", "");
  free(f);
  return f != NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FormatIsValid>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  lea    D6(%rip),%rcx
  push   %rcx
  push   %rcx
  push   %rcx
  push   %rcx
  mov    %rcx,%r9
  mov    %rcx,%r8
  mov    $0x0,%edx
  mov    $0x0,%edi
  call   <Format@plt>
  mov    %rax,%rbx
  add    $0x20,%rsp
  mov    %rax,%rdi
  call   <free@plt>
  test   %rbx,%rbx
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: 

assistant: ```c
bool FormatIsValid(const char *format) {
  char *f;
  f = Format(NULL, format, 0, "", "", "", "", "", "", "");
  free(f);
  return f != NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<FormatIsValid>:
  endbr64
  lea    D4(%rip),%rcx
  push   %rbx
  mov    %rdi,%rsi
  xor    %edx,%edx
  push   %rcx
  xor    %edi,%edi
  mov    %rcx,%r9
  mov    %rcx,%r8
  push   %rcx
  push   %rcx
  push   %rcx
  call   <Format@plt>
  add    $0x20,%rsp
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  setne  %al
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: 

assistant: ```c
bool FormatIsValid(const char *format) {
  char *f;
  f = Format(NULL, format, 0, "", "", "", "", "", "", "");
  free(f);
  return f != NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FormatIsValid>:
  endbr64
  lea    D8(%rip),%rcx
  push   %rbx
  mov    %rdi,%rsi
  xor    %edx,%edx
  push   %rcx
  xor    %edi,%edi
  mov    %rcx,%r9
  mov    %rcx,%r8
  push   %rcx
  push   %rcx
  push   %rcx
  call   <Format@plt>
  add    $0x20,%rsp
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  setne  %al
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: 

assistant: ```c
bool FormatIsValid(const char *format) {
  char *f;
  f = Format(NULL, format, 0, "", "", "", "", "", "", "");
  free(f);
  return f != NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chr_get_pixel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  and    $0x1f,%eax
  mov    %al,-0x2(%rbp)
  addb   $0x7,-0x2(%rbp)
  shrb   $0x3,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  mulb   -0x2(%rbp)
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  shr    $0x3,%al
  add    %al,-0x1(%rbp)
  addb   $0x3,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  movzbl -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
  mov    $0x1,%eax
  jmp    L3
L14:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char chr_get_pixel(unsigned char *buf, unsigned char x, unsigned char y) {
  unsigned char bytes_per_line, index;
  bytes_per_line = ((buf)[1] & 0x1f);
  bytes_per_line += (unsigned char)7;
  bytes_per_line >>= (unsigned char)3;
  index = y;
  index *= bytes_per_line;
  index += (unsigned char)(x >> 3);
  index += 3;
  if (buf[index] & ((unsigned char)1 << (x & (unsigned char)7)))
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<chr_get_pixel>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%esi
  movzbl 0x1(%rdi),%edx
  and    $0x1f,%edx
  lea    0x7(%rdx),%eax
  shr    $0x3,%al
  imul   %esi,%eax
  mov    %ecx,%edx
  shr    $0x3,%dl
  lea    0x3(%rax,%rdx,1),%eax
  movzbl %al,%eax
  movzbl (%rdi,%rax,1),%eax
  and    $0x7,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned char chr_get_pixel(unsigned char *buf, unsigned char x, unsigned char y) {
  unsigned char bytes_per_line, index;
  bytes_per_line = ((buf)[1] & 0x1f);
  bytes_per_line += (unsigned char)7;
  bytes_per_line >>= (unsigned char)3;
  index = y;
  index *= bytes_per_line;
  index += (unsigned char)(x >> 3);
  index += 3;
  if (buf[index] & ((unsigned char)1 << (x & (unsigned char)7)))
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<chr_get_pixel>:
  endbr64
  mov    %edx,%r8d
  movzbl 0x1(%rdi),%edx
  mov    %esi,%ecx
  and    $0x7,%ecx
  and    $0x1f,%edx
  lea    0x7(%rdx),%eax
  mov    %esi,%edx
  shr    $0x3,%al
  shr    $0x3,%dl
  imul   %r8d,%eax
  lea    0x3(%rax,%rdx,1),%eax
  movzbl %al,%eax
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned char chr_get_pixel(unsigned char *buf, unsigned char x, unsigned char y) {
  unsigned char bytes_per_line, index;
  bytes_per_line = ((buf)[1] & 0x1f);
  bytes_per_line += (unsigned char)7;
  bytes_per_line >>= (unsigned char)3;
  index = y;
  index *= bytes_per_line;
  index += (unsigned char)(x >> 3);
  index += 3;
  if (buf[index] & ((unsigned char)1 << (x & (unsigned char)7)))
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<chr_get_pixel>:
  endbr64
  mov    %edx,%r8d
  movzbl 0x1(%rdi),%edx
  mov    %esi,%ecx
  and    $0x7,%ecx
  and    $0x1f,%edx
  lea    0x7(%rdx),%eax
  mov    %esi,%edx
  shr    $0x3,%al
  shr    $0x3,%dl
  imul   %r8d,%eax
  lea    0x3(%rax,%rdx,1),%eax
  movzbl %al,%eax
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned char chr_get_pixel(unsigned char *buf, unsigned char x, unsigned char y) {
  unsigned char bytes_per_line, index;
  bytes_per_line = ((buf)[1] & 0x1f);
  bytes_per_line += (unsigned char)7;
  bytes_per_line >>= (unsigned char)3;
  index = y;
  index *= bytes_per_line;
  index += (unsigned char)(x >> 3);
  index += 3;
  if (buf[index] & ((unsigned char)1 << (x & (unsigned char)7)))
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<chol_prl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x4c(%rbp)
  mov    %ecx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L7
L20:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdi
  mov    -0x50(%rbp),%ecx
  mov    -0x4c(%rbp),%edx
  mov    -0x44(%rbp),%esi
  mov    -0x40(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <fac_task@plt>
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x34(%rbp)
  jmp    L30
L36:
  mov    -0x4c(%rbp),%eax
  add    %eax,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdi
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%r9
  mov    -0x50(%rbp),%r8d
  mov    -0x4c(%rbp),%ecx
  mov    -0x44(%rbp),%edx
  mov    -0x38(%rbp),%esi
  mov    -0x40(%rbp),%eax
  sub    $0x8,%rsp
  push   %rdi
  mov    %eax,%edi
  call   <upd_task@plt>
  add    $0x10,%rsp
  addl   $0x1,-0x34(%rbp)
L30:
  mov    -0x34(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L36
  mov    -0x4c(%rbp),%eax
  add    %eax,-0x40(%rbp)
  addl   $0x1,-0x3c(%rbp)
L7:
  mov    -0x3c(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L20
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%eax
  mov    -0x30(%rbp),%edx
  sub    %edx,%eax
  imul   $0xf4240,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%rdx
  sub    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
unsigned long chol_prl(int m, int mt, int b, int t, double **Ah) {
  struct timeval start, stop;
  gettimeofday(&start, NULL);
  int skipa = 0;
  int k;
  for (k = 0; k < mt; k++) {
    fac_task(skipa, m, b, t, Ah[k]);
    int skipb = skipa;
    int j;
    for (j = k + 1; j < mt; j++) {
      skipb += b;
      upd_task(skipa, skipb, m, b, t, Ah[k], Ah[j]);
    }
    skipa += b;
  }
#pragma omp taskwait
  gettimeofday(&start, NULL);
  return (stop.tv_sec - start.tv_sec) * 1000000 + stop.tv_usec - start.tv_usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<chol_prl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,0x4(%rsp)
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %ecx,0x28(%rsp)
  mov    %r8,%r15
  mov    %r8,0x20(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  test   %ebx,%ebx
  jle    L17
  lea    0x8(%r15),%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rbx),%eax
  mov    %rax,0x18(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    $0x0,%r13d
  lea    -0x2(%rbx),%eax
  mov    %eax,0x2c(%rsp)
L11:
  mov    0x10(%rsp),%rbx
  mov    %rbx,%r14
  mov    -0x8(%rbx),%r8
  mov    0x28(%rsp),%ecx
  mov    %r12d,%edx
  mov    0x4(%rsp),%esi
  mov    %r13d,%edi
  call   <fac_task@plt>
  mov    0x8(%rsp),%rcx
  mov    0x18(%rsp),%rax
  cmp    %rax,%rcx
  je     L17
  mov    0x2c(%rsp),%eax
  sub    %ecx,%eax
  add    %rcx,%rax
  mov    0x20(%rsp),%rdx
  lea    0x10(%rdx,%rax,8),%r15
  mov    %r13d,%ebp
L24:
  add    %r12d,%ebp
  sub    $0x8,%rsp
  push   (%rbx)
  mov    -0x8(%r14),%r9
  mov    0x38(%rsp),%r8d
  mov    %r12d,%ecx
  mov    0x14(%rsp),%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <upd_task@plt>
  add    $0x8,%rbx
  add    $0x10,%rsp
  cmp    %r15,%rbx
  jne    L24
  add    %r12d,%r13d
  addq   $0x1,0x8(%rsp)
  addq   $0x8,0x10(%rsp)
  jmp    L11
L17:
  lea    0x30(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xfff0bdc0,0x30(%rsp),%eax
  cltq
  sub    0x38(%rsp),%rax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long chol_prl(int m, int mt, int b, int t, double **Ah) {
  struct timeval start, stop;
  gettimeofday(&start, NULL);
  int skipa = 0;
  int k;
  for (k = 0; k < mt; k++) {
    fac_task(skipa, m, b, t, Ah[k]);
    int skipb = skipa;
    int j;
    for (j = k + 1; j < mt; j++) {
      skipb += b;
      upd_task(skipa, skipb, m, b, t, Ah[k], Ah[j]);
    }
    skipa += b;
  }
#pragma omp taskwait
  gettimeofday(&start, NULL);
  return (stop.tv_sec - start.tv_sec) * 1000000 + stop.tv_usec - start.tv_usec;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chol_prl>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  xor    %esi,%esi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x68,%rsp
  mov    %r8,0x28(%rsp)
  lea    0x40(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x38(%rsp)
  call   <gettimeofday@plt>
  test   %r14d,%r14d
  jle    L4
  movq   $0x0,0x18(%rsp)
  lea    0x8(%rbx),%rax
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r14),%eax
  mov    %rax,0x20(%rsp)
  lea    -0x2(%r14),%eax
  mov    %eax,0x34(%rsp)
  nopl   (%rax)
L31:
  mov    0x8(%rsp),%rbp
  mov    %r13d,%ecx
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  mov    -0x8(%rbp),%r8
  call   <fac_task@plt>
  mov    0x18(%rsp),%rcx
  mov    0x20(%rsp),%rax
  cmp    %rax,%rcx
  je     L4
  mov    0x34(%rsp),%eax
  mov    0x28(%rsp),%rdx
  mov    %ebx,%r14d
  sub    %ecx,%eax
  add    %rcx,%rax
  lea    0x10(%rdx,%rax,8),%rax
  mov    %rax,0x10(%rsp)
  mov    %r15d,%eax
  mov    %r12d,%r15d
  mov    %eax,%r12d
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x8(%rsp),%rax
  sub    $0x8,%rsp
  add    %r12d,%r14d
  mov    %r15d,%edx
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %r14d,%esi
  mov    %ebx,%edi
  mov    -0x8(%rax),%r9
  push   0x0(%rbp)
  add    $0x8,%rbp
  call   <upd_task@plt>
  pop    %rax
  pop    %rdx
  cmp    0x10(%rsp),%rbp
  jne    L15
  mov    %r12d,%eax
  addq   $0x1,0x18(%rsp)
  mov    %r15d,%r12d
  addq   $0x8,0x8(%rsp)
  mov    %eax,%r15d
  add    %eax,%ebx
  jmp    L31
  nop
L4:
  mov    0x38(%rsp),%rdi
  xor    %esi,%esi
  call   <gettimeofday@plt>
  imul   $0xfff0bdc0,0x40(%rsp),%eax
  cltq
  sub    0x48(%rsp),%rax
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long chol_prl(int m, int mt, int b, int t, double **Ah) {
  struct timeval start, stop;
  gettimeofday(&start, NULL);
  int skipa = 0;
  int k;
  for (k = 0; k < mt; k++) {
    fac_task(skipa, m, b, t, Ah[k]);
    int skipb = skipa;
    int j;
    for (j = k + 1; j < mt; j++) {
      skipb += b;
      upd_task(skipa, skipb, m, b, t, Ah[k], Ah[j]);
    }
    skipa += b;
  }
#pragma omp taskwait
  gettimeofday(&start, NULL);
  return (stop.tv_sec - start.tv_sec) * 1000000 + stop.tv_usec - start.tv_usec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chol_prl>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  xor    %esi,%esi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x68,%rsp
  mov    %r8,0x28(%rsp)
  lea    0x40(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x38(%rsp)
  call   <gettimeofday@plt>
  test   %r14d,%r14d
  jle    L30
  movq   $0x0,0x18(%rsp)
  lea    0x8(%rbx),%rax
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r14),%eax
  mov    %rax,0x20(%rsp)
  lea    -0x2(%r14),%eax
  mov    %eax,0x34(%rsp)
  nopl   (%rax)
L6:
  mov    0x8(%rsp),%rbp
  mov    %r13d,%ecx
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  mov    -0x8(%rbp),%r8
  call   <fac_task@plt>
  mov    0x18(%rsp),%rcx
  mov    0x20(%rsp),%rax
  cmp    %rax,%rcx
  je     L30
  mov    0x34(%rsp),%eax
  mov    0x28(%rsp),%rdx
  mov    %ebx,%r14d
  sub    %ecx,%eax
  add    %rcx,%rax
  lea    0x10(%rdx,%rax,8),%rax
  mov    %rax,0x10(%rsp)
  mov    %r15d,%eax
  mov    %r12d,%r15d
  mov    %eax,%r12d
  nopl   0x0(%rax,%rax,1)
L20:
  mov    0x8(%rsp),%rax
  sub    $0x8,%rsp
  add    %r12d,%r14d
  mov    %r15d,%edx
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %r14d,%esi
  mov    %ebx,%edi
  mov    -0x8(%rax),%r9
  push   0x0(%rbp)
  add    $0x8,%rbp
  call   <upd_task@plt>
  pop    %rax
  pop    %rdx
  cmp    0x10(%rsp),%rbp
  jne    L20
  mov    %r12d,%eax
  addq   $0x1,0x18(%rsp)
  mov    %r15d,%r12d
  addq   $0x8,0x8(%rsp)
  mov    %eax,%r15d
  add    %eax,%ebx
  jmp    L6
  nop
L30:
  mov    0x38(%rsp),%rdi
  xor    %esi,%esi
  call   <gettimeofday@plt>
  imul   $0xfff0bdc0,0x40(%rsp),%eax
  cltq
  sub    0x48(%rsp),%rax
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long chol_prl(int m, int mt, int b, int t, double **Ah) {
  struct timeval start, stop;
  gettimeofday(&start, NULL);
  int skipa = 0;
  int k;
  for (k = 0; k < mt; k++) {
    fac_task(skipa, m, b, t, Ah[k]);
    int skipb = skipa;
    int j;
    for (j = k + 1; j < mt; j++) {
      skipb += b;
      upd_task(skipa, skipb, m, b, t, Ah[k], Ah[j]);
    }
    skipa += b;
  }
#pragma omp taskwait
  gettimeofday(&start, NULL);
  return (stop.tv_sec - start.tv_sec) * 1000000 + stop.tv_usec - start.tv_usec;
}
```