user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r12d
  test   %r12d,%r12d
  js     L60
  test   %r12d,%r12d
  je     L220
L348:
  mov    %r12d,%edi
  xor    %r13d,%r13d
  lea    0x10(%rsp),%rbp
  nopl   0x0(%rax)
L155:
  and    $0xf,%edi
  mov    %r13d,%ebx
  call   <HexNumber@plt>
  mov    %r13,%rdx
  mov    %al,0x0(%rbp,%r13,1)
  mov    0xc(%rsp),%eax
  lea    0x1(%rdx),%r13
  test   %eax,%eax
  lea    0xf(%rax),%edi
  cmovns %eax,%edi
  sar    $0x4,%edi
  mov    %edi,0xc(%rsp)
  cmp    $0xf,%eax
  jg     L155
  movslq %ebx,%rax
  movzbl 0x10(%rsp),%esi
  cmp    %sil,0x10(%rsp,%rax,1)
  je     L124
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L253
  xor    %eax,%eax
L400:
  movslq %ebx,%rcx
  movzbl 0x11(%rsp),%esi
  sub    $0x1,%ebx
  cmp    %sil,0x10(%rsp,%rcx,1)
  je     L252
  cmp    $0x1,%ebx
  jle    L253
  xor    %eax,%eax
L249:
  movslq %ebx,%rcx
  sub    $0x1,%ebx
  movzbl 0x10(%rsp,%rcx,1),%esi
  cmp    %sil,0x12(%rsp)
  je     L144
  xor    %eax,%eax
  cmp    $0x2,%ebx
  jle    L253
L115:
  movslq %ebx,%rcx
  sub    $0x1,%ebx
  movzbl 0x10(%rsp,%rcx,1),%esi
  cmp    %sil,0x13(%rsp)
  je     L83
  xor    %eax,%eax
  cmp    $0x3,%ebx
  jle    L253
L15:
  movslq %ebx,%rcx
  sub    $0x1,%ebx
  movzbl 0x10(%rsp,%rcx,1),%ecx
  cmp    %cl,0x14(%rsp)
  je     L412
  xor    %eax,%eax
  cmp    $0x4,%ebx
  jle    L253
L49:
  movslq %ebx,%rcx
  sub    $0x1,%ebx
  movzbl 0x10(%rsp,%rcx,1),%esi
  cmp    %sil,0x15(%rsp)
  je     L9
  xor    %eax,%eax
  cmp    $0x5,%ebx
  jle    L253
L433:
  movslq %ebx,%rcx
  sub    $0x1,%ebx
  movzbl 0x10(%rsp,%rcx,1),%ecx
  cmp    %cl,0x16(%rsp)
  je     L362
  xor    %eax,%eax
  cmp    $0x6,%ebx
  jle    L253
L8:
  movslq %ebx,%rcx
  sub    $0x1,%ebx
  movzbl 0x10(%rsp,%rcx,1),%esi
  cmp    %sil,0x17(%rsp)
  je     L112
  xor    %eax,%eax
  cmp    $0x7,%ebx
  jle    L253
L58:
  movslq %ebx,%rcx
  sub    $0x1,%ebx
  movzbl 0x10(%rsp,%rcx,1),%ecx
  cmp    %cl,0x18(%rsp)
  je     L151
  xor    %eax,%eax
  cmp    $0x8,%ebx
  jle    L253
L18:
  movslq %ebx,%rbx
  movzbl 0x10(%rsp,%rbx,1),%ecx
  cmp    %cl,0x19(%rsp)
  je     L291
L253:
  add    $0x1,%r12d
  mov    %r12d,0xc(%rsp)
  test   %r12d,%r12d
  jne    L348
L220:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L397
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L252:
  cmp    $0x1,%ebx
  jg     L249
L291:
  test   %eax,%eax
  je     L253
L370:
  lea    0x11(%rsp,%rdx,1),%r12
  lea    D9(%rip),%rbx
L93:
  movsbl 0x0(%rbp),%esi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L93
  jmp    L220
  nopl   0x0(%rax,%rax,1)
L124:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L370
  mov    $0x1,%eax
  jmp    L400
  nopl   0x0(%rax)
L144:
  cmp    $0x2,%ebx
  jg     L115
  jmp    L291
  nopl   0x0(%rax,%rax,1)
L83:
  cmp    $0x3,%ebx
  jg     L15
  jmp    L291
  nopl   0x0(%rax,%rax,1)
L412:
  cmp    $0x4,%ebx
  jg     L49
  jmp    L291
  nopl   0x0(%rax,%rax,1)
L9:
  cmp    $0x5,%ebx
  jg     L433
  jmp    L291
  cs nopw 0x0(%rax,%rax,1)
L362:
  cmp    $0x6,%ebx
  jg     L8
  jmp    L291
  xchg   %ax,%ax
L112:
  cmp    $0x7,%ebx
  jg     L58
  jmp    L291
  xchg   %ax,%ax
L151:
  cmp    $0x8,%ebx
  jg     L18
  jmp    L291
L397:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string
name: parse_data
arguments: data_tag: D9
type: string

tool: D6: %d

tool: D9: %c

assistant: ```c
int main() {
  int number, i = 0, j = 0, k = 0, palindrom = 1, original;
  char array[20];
  do {
    scanf("%d", &number);
  } while (number < 0);
  original = number;
  do {
    i = 0;
    while (number > 0) {
      array[i] = HexNumber(number % 16);
      number = number / 16;
      i++;
    }
    palindrom = 1;
    for (j = 0, k = i - 1; j <= k; j++, k--) {
      if (array[j] != array[k]) {
        palindrom = 0;
      }
    }
    if (palindrom == 0) {
      original++;
      number = original;
    }
  } while (palindrom == 0);
  for (j = 0; j < i; j++) {
    printf("%c", array[j]);
  }
}
```