ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <geteuid@plt>
  test   %rbx,%rbx
  jne    L38
  cmp    %rax,%rbx
  jne    L38
  mov    0x8(%rbp),%rdi
  test   %rdi,%rdi
  jne    L8
L38:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L13:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  lea    D8(%rip),%rsi
  call   <strcmp@plt>
  mov    $0x1,%ebx
  test   %rax,%rax
  jne    L7
L22:
  mov    $0x169,%edi
  call   <export_gpio@plt>
  mov    %ebx,%esi
  mov    $0x169,%edi
  call   <set_gpio@plt>
  mov    0x8(%rbp),%rsi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L7:
  mov    0x8(%rbp),%rdi
  lea    D19(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L62
  mov    $0x0,%ebx
  jmp    L22
L62:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L22
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string
name: unpack_data
arguments: tag: D20
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string

tool: D8: off

tool: D20: Debuging via serial cable on headphone port is %s


tool: D19: on

assistant: ```c
int main(int argc, char **argv) {
  int mode;
  uid_t uid = getuid(), euid = geteuid();
  if (uid != 0 || uid != euid || !argv[1]) {
    usage();
    exit(0);
  } else {
    if (strcmp(argv[1], "off") == 0)
      mode = 1;
    else if (strcmp(argv[1], "on") == 0)
      mode = 0;
    else {
      usage();
      exit(0);
    }
    export_gpio(361);
    set_gpio(361, mode);
    printf("Debuging via serial cable on headphone port is %s\r\n", argv[1]);
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <getuid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  test   %rbx,%rbx
  jne    L60
  cmp    %rax,%rbx
  jne    L60
  mov    0x8(%rbp),%rdi
  test   %rdi,%rdi
  jne    L44
L60:
  xor    %eax,%eax
  call   <usage@plt>
  xor    %edi,%edi
  call   <exit@plt>
L63:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L44:
  lea    D15(%rip),%rsi
  mov    $0x1,%r12d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L49
L22:
  mov    $0x169,%edi
  call   <export_gpio@plt>
  mov    %r12d,%esi
  mov    $0x169,%edi
  call   <set_gpio@plt>
  mov    0x8(%rbp),%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L63
L49:
  mov    0x8(%rbp),%rdi
  lea    D14(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L79
  xor    %r12d,%r12d
  jmp    L22
L79:
  xor    %eax,%eax
  call   <usage@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L22
```

tool_calls: name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D14
data_type: string

tool: D15: off

tool: D9: Debuging via serial cable on headphone port is %s


tool: D14: on

assistant: ```c
int main(int argc, char **argv) {
  int mode;
  uid_t uid = getuid(), euid = geteuid();
  if (uid != 0 || uid != euid || !argv[1]) {
    usage();
    exit(0);
  } else {
    if (strcmp(argv[1], "off") == 0)
      mode = 1;
    else if (strcmp(argv[1], "on") == 0)
      mode = 0;
    else {
      usage();
      exit(0);
    }
    export_gpio(361);
    set_gpio(361, mode);
    printf("Debuging via serial cable on headphone port is %s\r\n", argv[1]);
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <getuid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  test   %rbx,%rbx
  jne    L75
  cmp    %rax,%rbx
  jne    L75
  mov    0x8(%rbp),%rdi
  test   %rdi,%rdi
  jne    L43
L75:
  xor    %eax,%eax
  call   <usage@plt>
  xor    %edi,%edi
  call   <exit@plt>
L34:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L43:
  lea    D17(%rip),%rsi
  mov    $0x1,%r12d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L35
L5:
  mov    $0x169,%edi
  call   <export_gpio@plt>
  mov    %r12d,%esi
  mov    $0x169,%edi
  call   <set_gpio@plt>
  mov    0x8(%rbp),%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L34
L35:
  mov    0x8(%rbp),%rdi
  lea    D14(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  xor    %r12d,%r12d
  jmp    L5
L2:
  xor    %eax,%eax
  call   <usage@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L5
```

tool_calls: name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D12
type_guessed: string
name: read_data
arguments: data_tag: D14
type_guessed: string

tool: D17: off

tool: D12: Debuging via serial cable on headphone port is %s


tool: D14: on

assistant: ```c
int main(int argc, char **argv) {
  int mode;
  uid_t uid = getuid(), euid = geteuid();
  if (uid != 0 || uid != euid || !argv[1]) {
    usage();
    exit(0);
  } else {
    if (strcmp(argv[1], "off") == 0)
      mode = 1;
    else if (strcmp(argv[1], "on") == 0)
      mode = 0;
    else {
      usage();
      exit(0);
    }
    export_gpio(361);
    set_gpio(361, mode);
    printf("Debuging via serial cable on headphone port is %s\r\n", argv[1]);
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L0:
  cmp    %rdx,%rsp
  je     L33
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L0
L33:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L17
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L17:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  jne    L31
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L31
L1:
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  addq   $0x8,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x2c(%rbp)
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x2c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L31:
  subl   $0x1,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jg     L1
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[BUFSIZ];
  int fd, n;
  if (argc == 1) {
    n = read(0, buf, BUFSIZ);
    write(1, buf, n);
  }
  while (--argc > 0) {
    fd = open(*(++argv), O_RDONLY, 0);
    n = read(fd, buf, BUFSIZ);
    write(1, buf, n);
    close(fd);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%edx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  mov    (%rax),%ecx
  movslq %ecx,%rax
  add    $0xf,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rsi
  sub    %rax,%rsi
L71:
  cmp    %rsi,%rsp
  je     L58
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L71
L58:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L62
  orq    $0x0,-0x8(%rsp,%rax,1)
L62:
  mov    %rsp,%r13
  cmp    $0x1,%edx
  je     L64
  jle    L0
  lea    -0x1(%rdx),%eax
  lea    (%r12,%rax,8),%r15
  mov    D28(%rip),%r14
L56:
  add    $0x8,%r12
  mov    $0x0,%edx
  mov    (%r14),%esi
  mov    (%r12),%rdi
  call   <open@plt>
  mov    %eax,%ebx
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  mov    %eax,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %ebx,%edi
  call   <close@plt>
  cmp    %r15,%r12
  jne    L56
L0:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L64:
  mov    %ecx,%edx
  mov    %r13,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L0
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[BUFSIZ];
  int fd, n;
  if (argc == 1) {
    n = read(0, buf, BUFSIZ);
    write(1, buf, n);
  }
  while (--argc > 0) {
    fd = open(*(++argv), O_RDONLY, 0);
    n = read(fd, buf, BUFSIZ);
    write(1, buf, n);
    close(fd);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    D14(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movslq 0x0(%r13),%rax
  mov    %rax,%r8
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L5
L13:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L13
L5:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L74
L56:
  mov    %rsp,%rbx
  cmp    $0x1,%edi
  je     L33
  jle    L9
  lea    -0x1(%rdi),%eax
  lea    (%r14,%rax,8),%r15
  nopl   0x0(%rax)
L24:
  mov    D12(%rip),%rax
  mov    0x8(%r14),%rdi
  xor    %edx,%edx
  add    $0x8,%r14
  mov    (%rax),%esi
  call   <open@plt>
  mov    0x0(%r13),%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <read@plt>
  mov    $0x1,%edi
  mov    %rbx,%rsi
  mov    %eax,%edx
  call   <write@plt>
  mov    %r12d,%edi
  call   <close@plt>
  cmp    %r15,%r14
  jne    L24
L9:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L33:
  mov    %r8d,%edx
  mov    %rsp,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %rsp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  jmp    L9
L74:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L56
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[BUFSIZ];
  int fd, n;
  if (argc == 1) {
    n = read(0, buf, BUFSIZ);
    write(1, buf, n);
  }
  while (--argc > 0) {
    fd = open(*(++argv), O_RDONLY, 0);
    n = read(fd, buf, BUFSIZ);
    write(1, buf, n);
    close(fd);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    D6(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movslq 0x0(%r13),%rax
  mov    %rax,%r8
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L58
L37:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L37
L58:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L47
L5:
  mov    %rsp,%rbx
  cmp    $0x1,%edi
  je     L79
  jle    L33
  lea    -0x1(%rdi),%eax
  lea    (%r14,%rax,8),%r15
  nopl   0x0(%rax)
L67:
  mov    D15(%rip),%rax
  mov    0x8(%r14),%rdi
  xor    %edx,%edx
  add    $0x8,%r14
  mov    (%rax),%esi
  call   <open@plt>
  mov    0x0(%r13),%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <read@plt>
  mov    $0x1,%edi
  mov    %rbx,%rsi
  mov    %eax,%edx
  call   <write@plt>
  mov    %r12d,%edi
  call   <close@plt>
  cmp    %r15,%r14
  jne    L67
L33:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L79:
  mov    %r8d,%edx
  mov    %rsp,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %rsp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  jmp    L33
L47:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L5
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[BUFSIZ];
  int fd, n;
  if (argc == 1) {
    n = read(0, buf, BUFSIZ);
    write(1, buf, n);
  }
  while (--argc > 0) {
    fd = open(*(++argv), O_RDONLY, 0);
    n = read(fd, buf, BUFSIZ);
    write(1, buf, n);
    close(fd);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L71
  cmpq   $0x0,-0x30(%rbp)
  je     L71
  cmpq   $0x0,-0x38(%rbp)
  je     L71
  cmpq   $0x0,-0x40(%rbp)
  jne    L40
L71:
  mov    $0x0,%eax
  jmp    L30
L40:
  movq   $0x0,-0x8(%rbp)
  jmp    L82
L4:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x14(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L24
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L82:
  mov    -0x30(%rbp),%rax
  imul   -0x38(%rbp),%rax
  cmp    %rax,-0x8(%rbp)
  jb     L4
  jmp    L75
L24:
  nop
L75:
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x30(%rbp)
L30:
  leave
  ret
```

assistant: ```c
size_t fread(void *ptr, size_t size, size_t count, FILE *stream) {
  char *dest = ptr;
  int c;
  size_t total;
  if (!(ptr && size && count && stream)) {
    return (0);
  }
  for (total = 0; total < size * count; total++) {
    c = getc(stream);
    if (EOF != c) {
      *dest++ = (char)c;
    } else {
      break;
    }
  }
  return (total / size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fread>:
  endbr64
  test   %rdi,%rdi
  je     L34
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rdx,%rbp
  mov    %rcx,%r13
  test   %rsi,%rsi
  je     L72
  test   %rdx,%rdx
  je     L39
  test   %rcx,%rcx
  je     L39
  imul   %rsi,%rbp
  test   %rbp,%rbp
  je     L2
  mov    $0x0,%ebx
L44:
  mov    %r13,%rdi
  call   <getc@plt>
  mov    D4(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L30
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L44
  jmp    L2
L30:
  mov    %rbx,%rbp
L2:
  mov    %rbp,%rax
  mov    $0x0,%edx
  div    %r14
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L72:
  mov    $0x0,%eax
  jmp    L57
L39:
  mov    $0x0,%eax
  jmp    L57
L34:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t fread(void *ptr, size_t size, size_t count, FILE *stream) {
  char *dest = ptr;
  int c;
  size_t total;
  if (!(ptr && size && count && stream)) {
    return (0);
  }
  for (total = 0; total < size * count; total++) {
    c = getc(stream);
    if (EOF != c) {
      *dest++ = (char)c;
    } else {
      break;
    }
  }
  return (total / size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fread>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L94
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L94
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L94
  mov    %rcx,%r15
  test   %rcx,%rcx
  je     L94
  imul   %rsi,%r12
  test   %r12,%r12
  je     L33
  mov    D1(%rip),%r13
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L99
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %al,(%rbx,%r14,1)
  add    $0x1,%r14
  cmp    %r12,%r14
  je     L39
L99:
  mov    %r15,%rdi
  call   <getc@plt>
  cmp    %eax,0x0(%r13)
  jne    L51
  mov    %r14,%rax
  xor    %edx,%edx
  div    %rbp
  mov    %rax,%r12
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L94:
  xor    %r12d,%r12d
L33:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L39:
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbp
  mov    %rax,%r12
  jmp    L33
```

assistant: ```c
size_t fread(void *ptr, size_t size, size_t count, FILE *stream) {
  char *dest = ptr;
  int c;
  size_t total;
  if (!(ptr && size && count && stream)) {
    return (0);
  }
  for (total = 0; total < size * count; total++) {
    c = getc(stream);
    if (EOF != c) {
      *dest++ = (char)c;
    } else {
      break;
    }
  }
  return (total / size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fread>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L20
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L20
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L20
  mov    %rcx,%r15
  test   %rcx,%rcx
  je     L20
  imul   %rsi,%r12
  test   %r12,%r12
  je     L71
  mov    D9(%rip),%r13
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L87
  nopw   0x0(%rax,%rax,1)
L83:
  mov    %al,(%rbx,%r14,1)
  add    $0x1,%r14
  cmp    %r12,%r14
  je     L30
L87:
  mov    %r15,%rdi
  call   <getc@plt>
  cmp    %eax,0x0(%r13)
  jne    L83
  mov    %r14,%rax
  xor    %edx,%edx
  div    %rbp
  mov    %rax,%r12
  jmp    L71
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %r12d,%r12d
L71:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L30:
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbp
  mov    %rax,%r12
  jmp    L71
```

assistant: ```c
size_t fread(void *ptr, size_t size, size_t count, FILE *stream) {
  char *dest = ptr;
  int c;
  size_t total;
  if (!(ptr && size && count && stream)) {
    return (0);
  }
  for (total = 0; total < size * count; total++) {
    c = getc(stream);
    if (EOF != c) {
      *dest++ = (char)c;
    } else {
      break;
    }
  }
  return (total / size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tool_str_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L14:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L13
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L14
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int tool_str_cmp(char *a, char *b, int c) {
  int i;
  i = 0;
  while (*a == *b && i < c) {
    a++;
    b++;
    i++;
  }
  return i == c ? 1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tool_str_cmp>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  jne    L11
  test   %edx,%edx
  jle    L11
  mov    $0x1,%eax
L12:
  mov    %eax,%r9d
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  sete   %r8b
  cmp    %eax,%edx
  setg   %cl
  add    $0x1,%rax
  test   %cl,%r8b
  jne    L12
L3:
  cmp    %r9d,%edx
  sete   %al
  movzbl %al,%eax
  ret
L11:
  mov    $0x0,%r9d
  jmp    L3
```

assistant: ```c
int tool_str_cmp(char *a, char *b, int c) {
  int i;
  i = 0;
  while (*a == *b && i < c) {
    a++;
    b++;
    i++;
  }
  return i == c ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tool_str_cmp>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  jne    L11
  test   %edx,%edx
  jle    L11
  mov    $0x1,%eax
  nopl   0x0(%rax)
L1:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  mov    %eax,%r9d
  sete   %r8b
  cmp    %eax,%edx
  setg   %cl
  add    $0x1,%rax
  test   %cl,%r8b
  jne    L1
  xor    %eax,%eax
  cmp    %r9d,%edx
  sete   %al
  ret
  nopl   (%rax)
L11:
  xor    %r9d,%r9d
  xor    %eax,%eax
  cmp    %r9d,%edx
  sete   %al
  ret
```

assistant: ```c
int tool_str_cmp(char *a, char *b, int c) {
  int i;
  i = 0;
  while (*a == *b && i < c) {
    a++;
    b++;
    i++;
  }
  return i == c ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tool_str_cmp>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  jne    L10
  test   %edx,%edx
  jle    L10
  mov    $0x1,%eax
  nopl   0x0(%rax)
L13:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  mov    %eax,%r9d
  sete   %r8b
  cmp    %eax,%edx
  setg   %cl
  add    $0x1,%rax
  test   %cl,%r8b
  jne    L13
  xor    %eax,%eax
  cmp    %r9d,%edx
  sete   %al
  ret
  nopl   (%rax)
L10:
  xor    %r9d,%r9d
  xor    %eax,%eax
  cmp    %r9d,%edx
  sete   %al
  ret
```

assistant: ```c
int tool_str_cmp(char *a, char *b, int c) {
  int i;
  i = 0;
  while (*a == *b && i < c) {
    a++;
    b++;
    i++;
  }
  return i == c ? 1 : 0;
}
```