ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<erlang>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  comisd %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  ja     L7
L12:
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  divsd  %xmm1,%xmm2
  movsd  D18(%rip),%xmm1
  cvttsd2si %xmm2,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%ebp
  test   %ebp,%ebp
  jle    L37
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  movsd  %xmm1,(%rsp)
  add    $0x1,%ebx
  call   <ranf@plt>
  movsd  (%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  cmp    %ebx,%ebp
  jne    L28
L37:
  movapd %xmm1,%xmm0
  call   <log@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebp,%xmm2
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm2,%xmm0
  xorpd  D9(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  mulsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L7:
  lea    D2(%rip),%rdi
  movsd  %xmm1,(%rsp)
  call   <erro@plt>
  movsd  (%rsp),%xmm1
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: tag: D18
datatype: f64
name: disassemble_data
arguments: tag: D9
datatype: byte[16]
name: disassemble_data
arguments: tag: D2
datatype: string

tool: D18: 1

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D2: erlang Argument Error: s > x

assistant: ```c
double erlang(double x, double s) {
  int i, k;
  double z;
  if (s > x)
    erro("erlang Argument Error: s > x");
  z = x / s;
  k = (int)z * z;
  z = 1.0;
  for (i = 0; i < k; i++)
    z *= ranf();
  return (-(x / k) * log(z));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<erlang>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  comisd %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  ja     L14
L5:
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  divsd  %xmm1,%xmm2
  movsd  D3(%rip),%xmm1
  cvttsd2si %xmm2,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%ebp
  test   %ebp,%ebp
  jle    L30
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  movsd  %xmm1,(%rsp)
  add    $0x1,%ebx
  call   <ranf@plt>
  movsd  (%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  cmp    %ebx,%ebp
  jne    L6
L30:
  movapd %xmm1,%xmm0
  call   <log@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebp,%xmm2
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm2,%xmm0
  xorpd  D9(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  mulsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L14:
  lea    D10(%rip),%rdi
  movsd  %xmm1,(%rsp)
  call   <erro@plt>
  movsd  (%rsp),%xmm1
  jmp    L5
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: f64
name: unpack_data
arguments: label: D9
data_type: byte[16]
name: unpack_data
arguments: label: D10
data_type: string

tool: D3: 1

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D10: erlang Argument Error: s > x

assistant: ```c
double erlang(double x, double s) {
  int i, k;
  double z;
  if (s > x)
    erro("erlang Argument Error: s > x");
  z = x / s;
  k = (int)z * z;
  z = 1.0;
  for (i = 0; i < k; i++)
    z *= ranf();
  return (-(x / k) * log(z));
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L14
L15:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L14:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  size_t dest_len = strlen(dest);
  size_t i = 0;
  while (src[i] != '\0') {
    dest[dest_len + i] = src[i];
    i++;
  }
  dest[dest_len + i] = '\0';
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L1
  mov    $0x0,%edx
  lea    0x0(%rbp,%rax,1),%rsi
L19:
  mov    %cl,(%rsi,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L19
L25:
  add    %rbp,%rax
  movb   $0x0,(%rax,%rdx,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x0,%edx
  jmp    L25
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  size_t dest_len = strlen(dest);
  size_t i = 0;
  while (src[i] != '\0') {
    dest[dest_len + i] = src[i];
    i++;
  }
  dest[dest_len + i] = '\0';
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L19
  xor    %edx,%edx
  lea    (%r12,%rax,1),%rsi
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %cl,(%rsi,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L7
  add    %rax,%rdx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rax,%rdx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  size_t dest_len = strlen(dest);
  size_t i = 0;
  while (src[i] != '\0') {
    dest[dest_len + i] = src[i];
    i++;
  }
  dest[dest_len + i] = '\0';
  return dest;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L17
  xor    %edx,%edx
  lea    (%r12,%rax,1),%rsi
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %cl,(%rsi,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L12
  add    %rax,%rdx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rax,%rdx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  size_t dest_len = strlen(dest);
  size_t i = 0;
  while (src[i] != '\0') {
    dest[dest_len + i] = src[i];
    i++;
  }
  dest[dest_len + i] = '\0';
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sam3Handshake>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L37
  cmpl   $0xffff,-0x1c(%rbp)
  jg     L37
  mov    -0x1c(%rbp),%ecx
  jmp    L38
L37:
  mov    $0x1de8,%ecx
L38:
  cmpq   $0x0,-0x18(%rbp)
  je     L52
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L52
  mov    -0x18(%rbp),%rax
  jmp    L18
L52:
  lea    D9(%rip),%rax
L18:
  mov    -0x28(%rbp),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sam3tcpConnect@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L64
  mov    $0xffffffff,%eax
  jmp    L61
L64:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sam3HandshakeInternal@plt>
L61:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: localhost

assistant: ```c
int sam3Handshake(const char *hostname, int port, uint32_t *ip) {
  int fd;
  if ((fd = sam3tcpConnect((hostname == NULL || !hostname[0] ? "localhost" : hostname), (port < 1 || port > 65535 ? 7656 : port), ip)) < 0)
    return -1;
  return sam3HandshakeInternal(fd);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sam3Handshake>:
  endbr64
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%eax
  cmp    $0xffff,%eax
  mov    $0x1de8,%eax
  cmovae %eax,%esi
  test   %rdi,%rdi
  je     L12
  cmpb   $0x0,(%rdi)
  lea    D14(%rip),%rax
  cmove  %rax,%rdi
L14:
  call   <sam3tcpConnect@plt>
  mov    %eax,%edi
  test   %eax,%eax
  js     L29
  call   <sam3HandshakeInternal@plt>
L37:
  add    $0x8,%rsp
  ret
L12:
  lea    D14(%rip),%rdi
  jmp    L14
L29:
  mov    $0xffffffff,%eax
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: data_label: D14
data_type: string

tool: D14: localhost

assistant: ```c
int sam3Handshake(const char *hostname, int port, uint32_t *ip) {
  int fd;
  if ((fd = sam3tcpConnect((hostname == NULL || !hostname[0] ? "localhost" : hostname), (port < 1 || port > 65535 ? 7656 : port), ip)) < 0)
    return -1;
  return sam3HandshakeInternal(fd);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sam3Handshake>:
  endbr64
  lea    -0x1(%rsi),%eax
  sub    $0x8,%rsp
  cmp    $0xffff,%eax
  mov    $0x1de8,%eax
  cmovae %eax,%esi
  test   %rdi,%rdi
  je     L29
  cmpb   $0x0,(%rdi)
  lea    D15(%rip),%rax
  cmove  %rax,%rdi
L6:
  call   <sam3tcpConnect@plt>
  mov    %eax,%edi
  test   %eax,%eax
  js     L19
  add    $0x8,%rsp
  jmp    1060 <sam3HandshakeInternal@plt>
  nop
L29:
  lea    D15(%rip),%rdi
  jmp    L6
  nopl   0x0(%rax)
L19:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D15
type: string

tool: D15: localhost

assistant: ```c
int sam3Handshake(const char *hostname, int port, uint32_t *ip) {
  int fd;
  if ((fd = sam3tcpConnect((hostname == NULL || !hostname[0] ? "localhost" : hostname), (port < 1 || port > 65535 ? 7656 : port), ip)) < 0)
    return -1;
  return sam3HandshakeInternal(fd);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sam3Handshake>:
  endbr64
  lea    -0x1(%rsi),%eax
  sub    $0x8,%rsp
  cmp    $0xffff,%eax
  mov    $0x1de8,%eax
  cmovae %eax,%esi
  test   %rdi,%rdi
  je     L17
  cmpb   $0x0,(%rdi)
  lea    D5(%rip),%rax
  cmove  %rax,%rdi
L23:
  call   <sam3tcpConnect@plt>
  mov    %eax,%edi
  test   %eax,%eax
  js     L20
  add    $0x8,%rsp
  jmp    1060 <sam3HandshakeInternal@plt>
  nop
L17:
  lea    D5(%rip),%rdi
  jmp    L23
  nopl   0x0(%rax)
L20:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D5: localhost

assistant: ```c
int sam3Handshake(const char *hostname, int port, uint32_t *ip) {
  int fd;
  if ((fd = sam3tcpConnect((hostname == NULL || !hostname[0] ? "localhost" : hostname), (port < 1 || port > 65535 ? 7656 : port), ip)) < 0)
    return -1;
  return sam3HandshakeInternal(fd);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gmove_cp_2a2t_b@plt>
  mov    $0x0,%eax
  call   <gmove_cp_2a2t_b_bc@plt>
  mov    $0x0,%eax
  call   <gmove_cp_2a2t_bc@plt>
  mov    $0x0,%eax
  call   <gmove_cp_2a2t_c@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  gmove_cp_2a2t_b();
  gmove_cp_2a2t_b_bc();
  gmove_cp_2a2t_bc();
  gmove_cp_2a2t_c();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gmove_cp_2a2t_b@plt>
  mov    $0x0,%eax
  call   <gmove_cp_2a2t_b_bc@plt>
  mov    $0x0,%eax
  call   <gmove_cp_2a2t_bc@plt>
  mov    $0x0,%eax
  call   <gmove_cp_2a2t_c@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gmove_cp_2a2t_b();
  gmove_cp_2a2t_b_bc();
  gmove_cp_2a2t_bc();
  gmove_cp_2a2t_c();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gmove_cp_2a2t_b@plt>
  xor    %eax,%eax
  call   <gmove_cp_2a2t_b_bc@plt>
  xor    %eax,%eax
  call   <gmove_cp_2a2t_bc@plt>
  xor    %eax,%eax
  call   <gmove_cp_2a2t_c@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gmove_cp_2a2t_b();
  gmove_cp_2a2t_b_bc();
  gmove_cp_2a2t_bc();
  gmove_cp_2a2t_c();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gmove_cp_2a2t_b@plt>
  xor    %eax,%eax
  call   <gmove_cp_2a2t_b_bc@plt>
  xor    %eax,%eax
  call   <gmove_cp_2a2t_bc@plt>
  xor    %eax,%eax
  call   <gmove_cp_2a2t_c@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gmove_cp_2a2t_b();
  gmove_cp_2a2t_b_bc();
  gmove_cp_2a2t_bc();
  gmove_cp_2a2t_c();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bgbrasw_log2f12>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0xc,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L15:
  sarl   -0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x1fff,-0xc(%rbp)
  jg     L15
  mov    -0x8(%rbp),%eax
  shl    $0xc,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  and    $0xfff,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bgbrasw_log2f12(int val) {
  int i, j, k;
  i = val << 12;
  j = 0;
  while (i >= 8192) {
    i = i >> 1;
    j++;
  }
  k = (j << 12) | (i & 4095);
  return (k);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bgbrasw_log2f12>:
  endbr64
  shl    $0xc,%edi
  cmp    $0x1fff,%edi
  jle    L25
  mov    $0x0,%eax
L29:
  sar    %edi
  add    $0x1,%eax
  cmp    $0x1fff,%edi
  jg     L29
L16:
  shl    $0xc,%eax
  and    $0xfff,%edi
  or     %edi,%eax
  ret
L25:
  mov    $0x0,%eax
  jmp    L16
```

assistant: ```c
int bgbrasw_log2f12(int val) {
  int i, j, k;
  i = val << 12;
  j = 0;
  while (i >= 8192) {
    i = i >> 1;
    j++;
  }
  k = (j << 12) | (i & 4095);
  return (k);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bgbrasw_log2f12>:
  endbr64
  shl    $0xc,%edi
  xor    %eax,%eax
  cmp    $0x1fff,%edi
  jle    L8
  nopl   0x0(%rax)
L11:
  sar    %edi
  add    $0x1,%eax
  cmp    $0x1fff,%edi
  jg     L11
  shl    $0xc,%eax
  and    $0xfff,%edi
  or     %edi,%eax
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
int bgbrasw_log2f12(int val) {
  int i, j, k;
  i = val << 12;
  j = 0;
  while (i >= 8192) {
    i = i >> 1;
    j++;
  }
  k = (j << 12) | (i & 4095);
  return (k);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bgbrasw_log2f12>:
  endbr64
  shl    $0xc,%edi
  xor    %eax,%eax
  cmp    $0x1fff,%edi
  jle    L8
  nopl   0x0(%rax)
L7:
  sar    %edi
  add    $0x1,%eax
  cmp    $0x1fff,%edi
  jg     L7
  shl    $0xc,%eax
  and    $0xfff,%edi
  or     %edi,%eax
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
int bgbrasw_log2f12(int val) {
  int i, j, k;
  i = val << 12;
  j = 0;
  while (i >= 8192) {
    i = i >> 1;
    j++;
  }
  k = (j << 12) | (i & 4095);
  return (k);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string

tool: D3: All is well


assistant: ```c
int main(int argc, char *argv[]) {
  printf("All is well\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string

tool: D2: All is well


assistant: ```c
int main(int argc, char *argv[]) {
  printf("All is well\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: All is well


assistant: ```c
int main(int argc, char *argv[]) {
  printf("All is well\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: All is well


assistant: ```c
int main(int argc, char *argv[]) {
  printf("All is well\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__pnacl_start_linux_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    (%rdi),%ebx
  movslq %ebx,%rax
  lea    0xc(%rdi,%rax,8),%r12
  mov    %r12,%rdi
  call   <count_envs@plt>
  mov    %eax,%r13d
  lea    0x7(%rbx,%rax,1),%edi
  shl    $0x2,%edi
  call   <alloca@plt>
  mov    %rax,%rdi
  movl   $0x0,(%rax)
  mov    %r13d,0x4(%rax)
  mov    %ebx,0x8(%rax)
  test   %ebx,%ebx
  jle    L10
  lea    0xc(%rax),%rax
  lea    -0x1(%rbx),%edx
  lea    0x10(%rdi,%rdx,4),%rsi
  mov    %rdi,%rdx
  neg    %rdx
  lea    (%r14,%rdx,2),%rcx
L6:
  mov    -0x14(%rcx,%rax,2),%rdx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L6
  add    $0x3,%ebx
L59:
  lea    0x1(%rbx),%esi
  movslq %ebx,%rbx
  lea    0x0(,%rbx,4),%rax
  movl   $0x0,(%rdi,%rbx,4)
  test   %r13d,%r13d
  jle    L9
  lea    0x4(%rdi,%rax,1),%rax
  lea    -0x1(%r13),%edx
  add    %rbx,%rdx
  lea    0x8(%rdi,%rdx,4),%rcx
  mov    %rdi,%rdx
  neg    %rdx
  neg    %rbx
  shl    $0x3,%rbx
  lea    (%rbx,%rdx,2),%rdx
  add    %rdx,%r12
L28:
  mov    -0x8(%r12,%rax,2),%rdx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L28
  add    %r13d,%esi
L9:
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rax
  movl   $0x0,(%rdi,%rsi,4)
  movl   $0x0,0x4(%rdi,%rax,1)
  movl   $0x0,0x8(%rdi,%rax,1)
  call   <__pnacl_start@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L10:
  mov    $0x3,%ebx
  jmp    L59
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __pnacl_start_linux_c(uint32_t *stack) {
  int argc = stack[0];
  char **argv = (char **)(stack + 1);
  char **envp = argv + argc + 1;
  int envc = count_envs(envp);
  int num_entries = 1 + 1 + 1 + argc + 1 + envc + 1 + 2;
  uint32_t *info = (uint32_t *)alloca(sizeof(uint32_t) * num_entries);
  int i = 0;
  int j;
  info[i++] = 0;
  info[i++] = envc;
  info[i++] = argc;
  for (j = 0; j < argc; j++)
    info[i++] = (uint32_t)argv[j];
  info[i++] = 0;
  for (j = 0; j < envc; j++)
    info[i++] = (uint32_t)envp[j];
  info[i++] = 0;
  info[i++] = 0;
  info[i++] = 0;
  __pnacl_start(info);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__pnacl_start_linux_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq (%rdi),%rax
  lea    0xc(%rdi,%rax,8),%r14
  mov    %rax,%rbx
  mov    %r14,%rdi
  call   <count_envs@plt>
  lea    0x7(%rbx,%rax,1),%edi
  mov    %eax,%r13d
  shl    $0x2,%edi
  call   <alloca@plt>
  movl   $0x0,(%rax)
  mov    %rax,%rdi
  mov    %r13d,0x4(%rax)
  mov    %ebx,0x8(%rax)
  test   %ebx,%ebx
  jle    L59
  lea    -0x1(%rbx),%edx
  lea    0x4(%rbx),%r12d
  lea    0x10(%rdi,%rdx,4),%rsi
  mov    %rdi,%rdx
  lea    0xc(%rax),%rax
  neg    %rdx
  lea    (%r15,%rdx,2),%rcx
  nopl   0x0(%rax,%rax,1)
L47:
  mov    -0x14(%rcx,%rax,2),%rdx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rsi
  jne    L47
  add    $0x3,%ebx
  movslq %ebx,%rbx
  shl    $0x2,%rbx
  lea    0x4(%rbx),%rax
  lea    0x8(%rbx),%rdx
L28:
  movl   $0x0,(%rdi,%rbx,1)
  test   %r13d,%r13d
  jle    L1
  movslq %r12d,%rdx
  lea    -0x1(%r13),%ecx
  add    %rdx,%rcx
  lea    (%rdi,%rdx,4),%rax
  neg    %rdx
  lea    0x4(%rdi,%rcx,4),%rsi
  mov    %rdi,%rcx
  neg    %rcx
  add    %rcx,%rcx
  lea    (%rcx,%rdx,8),%rdx
  lea    (%r14,%rdx,1),%rcx
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    (%rcx,%rax,2),%rdx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rsi
  jne    L30
  add    %r13d,%r12d
  movslq %r12d,%rax
  shl    $0x2,%rax
  lea    0x4(%rax),%rdx
L1:
  add    $0x2,%r12d
  movl   $0x0,(%rdi,%rax,1)
  movslq %r12d,%r12
  movl   $0x0,(%rdi,%rdx,1)
  movl   $0x0,(%rdi,%r12,4)
  call   <__pnacl_start@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  xchg   %ax,%ax
L59:
  mov    $0x14,%edx
  mov    $0x10,%eax
  mov    $0x4,%r12d
  mov    $0xc,%ebx
  jmp    L28
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __pnacl_start_linux_c(uint32_t *stack) {
  int argc = stack[0];
  char **argv = (char **)(stack + 1);
  char **envp = argv + argc + 1;
  int envc = count_envs(envp);
  int num_entries = 1 + 1 + 1 + argc + 1 + envc + 1 + 2;
  uint32_t *info = (uint32_t *)alloca(sizeof(uint32_t) * num_entries);
  int i = 0;
  int j;
  info[i++] = 0;
  info[i++] = envc;
  info[i++] = argc;
  for (j = 0; j < argc; j++)
    info[i++] = (uint32_t)argv[j];
  info[i++] = 0;
  for (j = 0; j < envc; j++)
    info[i++] = (uint32_t)envp[j];
  info[i++] = 0;
  info[i++] = 0;
  info[i++] = 0;
  __pnacl_start(info);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test37_Test_pollen__run__E>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test37_Mod_foo__E@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: run


assistant: ```c
void test37_Test_pollen__run__E() {
  test37_Mod_foo__E();
  printf("run\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<test37_Test_pollen__run__E>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test37_Mod_foo__E@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: run


assistant: ```c
void test37_Test_pollen__run__E() {
  test37_Mod_foo__E();
  printf("run\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test37_Test_pollen__run__E>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test37_Mod_foo__E@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D2: run


assistant: ```c
void test37_Test_pollen__run__E() {
  test37_Mod_foo__E();
  printf("run\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test37_Test_pollen__run__E>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test37_Mod_foo__E@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: run


assistant: ```c
void test37_Test_pollen__run__E() {
  test37_Mod_foo__E();
  printf("run\n");
}
```