ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<strlen1>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L1
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t strlen1(const char *s) {
  const char *p = s;
  while (*++p)
    ;
  return p - s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isEscape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  test   %rax,%rax
  je     L29
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L6
L29:
  mov    $0x0,%eax
  jmp    L2
L6:
  mov    $0x1,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int isEscape(char *s) {
  if (!(s - 1) || *(s - 1) != '\\')
    return (0);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isEscape>:
  endbr64
  cmpb   $0x5c,-0x1(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isEscape(char *s) {
  if (!(s - 1) || *(s - 1) != '\\')
    return (0);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isEscape>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x5c,-0x1(%rdi)
  sete   %al
  ret
```

assistant: ```c
int isEscape(char *s) {
  if (!(s - 1) || *(s - 1) != '\\')
    return (0);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isEscape>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x5c,-0x1(%rdi)
  sete   %al
  ret
```

assistant: ```c
int isEscape(char *s) {
  if (!(s - 1) || *(s - 1) != '\\')
    return (0);
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8_byte_to_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L8
L34:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <utf8_byte_count@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
  movq   $0x1,-0x8(%rbp)
L28:
  addq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jae    L6
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
L6:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t utf8_byte_to_index(char *str, size_t byte) {
  size_t i, b, c;
  for (i = 0, b = 0; b < byte && str[b] != '\0'; ++i, b += c) {
    c = utf8_byte_count(str[b]);
    if (c <= 0)
      c = 1;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8_byte_to_index>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  test   %rsi,%rsi
  je     L20
L9:
  movzbl 0x0(%r13,%rbx,1),%edi
  test   %dil,%dil
  je     L33
  movsbl %dil,%edi
  call   <utf8_byte_count@plt>
  add    $0x1,%rbp
  test   %rax,%rax
  mov    $0x1,%edx
  cmove  %rdx,%rax
  add    %rax,%rbx
  cmp    %rbx,%r12
  ja     L9
L33:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  mov    %rsi,%rbp
  jmp    L33
```

assistant: ```c
size_t utf8_byte_to_index(char *str, size_t byte) {
  size_t i, b, c;
  for (i = 0, b = 0; b < byte && str[b] != '\0'; ++i, b += c) {
    c = utf8_byte_count(str[b]);
    if (c <= 0)
      c = 1;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8_byte_to_index>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  jne    L2
  jmp    L15
  nopl   0x0(%rax)
L14:
  call   <utf8_byte_count@plt>
  add    $0x1,%r12
  mov    $0x1,%edx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    %rax,%r13
  cmp    %r13,%rbx
  jbe    L15
L2:
  movsbl 0x0(%rbp,%r13,1),%edi
  test   %dil,%dil
  jne    L14
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t utf8_byte_to_index(char *str, size_t byte) {
  size_t i, b, c;
  for (i = 0, b = 0; b < byte && str[b] != '\0'; ++i, b += c) {
    c = utf8_byte_count(str[b]);
    if (c <= 0)
      c = 1;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utf8_byte_to_index>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  jne    L3
  jmp    L7
  nopl   0x0(%rax)
L6:
  call   <utf8_byte_count@plt>
  add    $0x1,%r12
  mov    $0x1,%edx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    %rax,%r13
  cmp    %r13,%rbx
  jbe    L7
L3:
  movsbl 0x0(%rbp,%r13,1),%edi
  test   %dil,%dil
  jne    L6
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t utf8_byte_to_index(char *str, size_t byte) {
  size_t i, b, c;
  for (i = 0, b = 0; b < byte && str[b] != '\0'; ++i, b += c) {
    c = utf8_byte_count(str[b]);
    if (c <= 0)
      c = 1;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mod4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: mod4 from mod3


assistant: ```c
int mod4() {
  printf("mod4 from mod3\n");
  return 4;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mod4>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: mod4 from mod3


assistant: ```c
int mod4() {
  printf("mod4 from mod3\n");
  return 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mod4>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: mod4 from mod3


assistant: ```c
int mod4() {
  printf("mod4 from mod3\n");
  return 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mod4>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: mod4 from mod3


assistant: ```c
int mod4() {
  printf("mod4 from mod3\n");
  return 4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<zsortstrings_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int zsortstrings_func(const void *a, const void *b) {
  char *string1, *string2;
  string1 = *((char **)a);
  string2 = *((char **)b);
  return (strcmp(string1, string2));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<zsortstrings_func>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int zsortstrings_func(const void *a, const void *b) {
  char *string1, *string2;
  string1 = *((char **)a);
  string2 = *((char **)b);
  return (strcmp(string1, string2));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zsortstrings_func>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int zsortstrings_func(const void *a, const void *b) {
  char *string1, *string2;
  string1 = *((char **)a);
  string2 = *((char **)b);
  return (strcmp(string1, string2));
}
```
user: What is the c source code of the assembly code below?

```asm
<zsortstrings_func>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int zsortstrings_func(const void *a, const void *b) {
  char *string1, *string2;
  string1 = *((char **)a);
  string2 = *((char **)b);
  return (strcmp(string1, string2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<triplet_ind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D28(%rip),%rax
  mov    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  or     %eax,%ecx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D23(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  or     %ecx,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
type: string
name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D23
type: string

tool: D28: @

tool: D1: @

tool: D23: @

assistant: ```c
int triplet_ind(const char *s) {
  static const int mask1[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 2, 64, 1, 64, 64, 64, 3, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 2, 64, 1, 64, 64, 64, 3, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  static const int mask2[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 8, 64, 4, 64, 64, 64, 12, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 8, 64, 4, 64, 64, 64, 12, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  static const int mask3[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 32, 64, 16, 64, 64, 64, 48, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 32, 64, 16, 64, 64, 64, 48, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  return mask1[(int)s[0]] | mask2[(int)s[1]] | mask3[(int)s[2]];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<triplet_ind>:
  endbr64
  movsbq (%rdi),%rdx
  movsbq 0x1(%rdi),%rcx
  lea    D2(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  lea    D16(%rip),%rdx
  or     (%rdx,%rcx,4),%eax
  movsbq 0x2(%rdi),%rcx
  lea    D12(%rip),%rdx
  or     (%rdx,%rcx,4),%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string

tool: D2: @

tool: D16: @

tool: D12: @

assistant: ```c
int triplet_ind(const char *s) {
  static const int mask1[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 2, 64, 1, 64, 64, 64, 3, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 2, 64, 1, 64, 64, 64, 3, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  static const int mask2[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 8, 64, 4, 64, 64, 64, 12, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 8, 64, 4, 64, 64, 64, 12, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  static const int mask3[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 32, 64, 16, 64, 64, 64, 48, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 32, 64, 16, 64, 64, 64, 48, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  return mask1[(int)s[0]] | mask2[(int)s[1]] | mask3[(int)s[2]];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<triplet_ind>:
  endbr64
  movsbq (%rdi),%rdx
  movsbq 0x1(%rdi),%rcx
  lea    D5(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  lea    D1(%rip),%rdx
  or     (%rdx,%rcx,4),%eax
  movsbq 0x2(%rdi),%rcx
  lea    D27(%rip),%rdx
  or     (%rdx,%rcx,4),%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string
name: retrieve_data
arguments: tag: D27
type_guessed: string

tool: D5: @

tool: D1: @

tool: D27: @

assistant: ```c
int triplet_ind(const char *s) {
  static const int mask1[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 2, 64, 1, 64, 64, 64, 3, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 2, 64, 1, 64, 64, 64, 3, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  static const int mask2[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 8, 64, 4, 64, 64, 64, 12, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 8, 64, 4, 64, 64, 64, 12, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  static const int mask3[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 32, 64, 16, 64, 64, 64, 48, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 32, 64, 16, 64, 64, 64, 48, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  return mask1[(int)s[0]] | mask2[(int)s[1]] | mask3[(int)s[2]];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<triplet_ind>:
  endbr64
  movsbq (%rdi),%rdx
  movsbq 0x1(%rdi),%rcx
  lea    D24(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  lea    D13(%rip),%rdx
  or     (%rdx,%rcx,4),%eax
  movsbq 0x2(%rdi),%rcx
  lea    D4(%rip),%rdx
  or     (%rdx,%rcx,4),%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D24
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D24: @

tool: D13: @

tool: D4: @

assistant: ```c
int triplet_ind(const char *s) {
  static const int mask1[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 2, 64, 1, 64, 64, 64, 3, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 2, 64, 1, 64, 64, 64, 3, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  static const int mask2[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 8, 64, 4, 64, 64, 64, 12, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 8, 64, 4, 64, 64, 64, 12, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  static const int mask3[128] = {64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 32, 64, 16, 64, 64, 64, 48, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 32, 64, 16, 64, 64, 64, 48, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 0, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64, 64};
  return mask1[(int)s[0]] | mask2[(int)s[1]] | mask3[(int)s[2]];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<checktick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xcc(%rbp)
  jmp    L56
L1:
  mov    $0x0,%eax
  call   <mysecond@plt>
  movq   %xmm0,%rax
  mov    %rax,-0xc0(%rbp)
  nop
L43:
  mov    $0x0,%eax
  call   <mysecond@plt>
  movq   %xmm0,%rax
  mov    %rax,-0xb8(%rbp)
  movsd  -0xb8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0xc0(%rbp),%xmm1
  movsd  D6(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L43
  movsd  -0xb8(%rbp),%xmm0
  movsd  %xmm0,-0xc0(%rbp)
  mov    -0xcc(%rbp),%eax
  cltq
  movsd  -0xc0(%rbp),%xmm0
  movsd  %xmm0,-0xb0(%rbp,%rax,8)
  addl   $0x1,-0xcc(%rbp)
L56:
  cmpl   $0x13,-0xcc(%rbp)
  jle    L1
  movl   $0xf4240,-0xc8(%rbp)
  movl   $0x1,-0xcc(%rbp)
  jmp    L14
L42:
  mov    -0xcc(%rbp),%eax
  cltq
  movsd  -0xb0(%rbp,%rax,8),%xmm0
  mov    -0xcc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movsd  -0xb0(%rbp,%rax,8),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc4(%rbp)
  mov    -0xc4(%rbp),%eax
  mov    $0x0,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    -0xc8(%rbp),%edx
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0xc8(%rbp)
  addl   $0x1,-0xcc(%rbp)
L14:
  cmpl   $0x13,-0xcc(%rbp)
  jle    L42
  mov    -0xc8(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: byte[8]
name: unpack_data
arguments: data_tag: D13
datatype: f64

tool: {"D6": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D13: 1000000

assistant: ```c
int checktick() {
  int i, minDelta, Delta;
  double t1, t2, timesfound[20];
  for (i = 0; i < 20; i++) {
    t1 = mysecond();
    while (((t2 = mysecond()) - t1) < 1.0E-6)
      ;
    timesfound[i] = t1 = t2;
  }
  minDelta = 1000000;
  for (i = 1; i < 20; i++) {
    Delta = (int)(1.0E6 * (timesfound[i] - timesfound[i - 1]));
    minDelta = ((minDelta) < (((Delta) > (0) ? (Delta) : (0))) ? (minDelta) : (((Delta) > (0) ? (Delta) : (0))));
  }
  return (minDelta);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checktick>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xb0(%rsp),%r12
  mov    %rbx,%rbp
L18:
  mov    $0x0,%eax
  call   <mysecond@plt>
  movsd  %xmm0,0x8(%rsp)
L15:
  mov    $0x0,%eax
  call   <mysecond@plt>
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  movsd  D7(%rip),%xmm3
  comisd %xmm1,%xmm3
  ja     L15
  movsd  %xmm0,0x0(%rbp)
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L18
  lea    0x98(%rbx),%rsi
  mov    $0xf4240,%edx
  movsd  D13(%rip),%xmm1
L39:
  movsd  0x8(%rbx),%xmm0
  subsd  (%rbx),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  mov    $0x0,%ecx
  cmovs  %ecx,%eax
  cmp    %eax,%edx
  cmovg  %eax,%edx
  add    $0x8,%rbx
  cmp    %rsi,%rbx
  jne    L39
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %edx,%eax
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D13
type_infered: f64

tool: {"D7": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D13: 1000000

assistant: ```c
int checktick() {
  int i, minDelta, Delta;
  double t1, t2, timesfound[20];
  for (i = 0; i < 20; i++) {
    t1 = mysecond();
    while (((t2 = mysecond()) - t1) < 1.0E-6)
      ;
    timesfound[i] = t1 = t2;
  }
  minDelta = 1000000;
  for (i = 1; i < 20; i++) {
    Delta = (int)(1.0E6 * (timesfound[i] - timesfound[i - 1]));
    minDelta = ((minDelta) < (((Delta) > (0) ? (Delta) : (0))) ? (minDelta) : (((Delta) > (0) ? (Delta) : (0))));
  }
  return (minDelta);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checktick>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xb0(%rsp),%r12
  mov    %rbx,%rbp
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  call   <mysecond@plt>
  movsd  %xmm0,0x8(%rsp)
  nopl   (%rax)
L5:
  xor    %eax,%eax
  call   <mysecond@plt>
  movsd  D1(%rip),%xmm3
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  comisd %xmm1,%xmm3
  ja     L5
  movsd  %xmm0,0x0(%rbp)
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L39
  movsd  D8(%rip),%xmm1
  lea    0x98(%rbx),%rcx
  mov    $0xf4240,%r8d
  nopw   0x0(%rax,%rax,1)
L30:
  movsd  0x8(%rbx),%xmm0
  subsd  (%rbx),%xmm0
  xor    %edx,%edx
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  cmovs  %edx,%eax
  cmp    %eax,%r8d
  cmovg  %eax,%r8d
  add    $0x8,%rbx
  cmp    %rbx,%rcx
  jne    L30
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xc0,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: byte[8]
name: disassemble_data
arguments: data_tag: D8
type: f64

tool: {"D1": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D8: 1000000

assistant: ```c
int checktick() {
  int i, minDelta, Delta;
  double t1, t2, timesfound[20];
  for (i = 0; i < 20; i++) {
    t1 = mysecond();
    while (((t2 = mysecond()) - t1) < 1.0E-6)
      ;
    timesfound[i] = t1 = t2;
  }
  minDelta = 1000000;
  for (i = 1; i < 20; i++) {
    Delta = (int)(1.0E6 * (timesfound[i] - timesfound[i - 1]));
    minDelta = ((minDelta) < (((Delta) > (0) ? (Delta) : (0))) ? (minDelta) : (((Delta) > (0) ? (Delta) : (0))));
  }
  return (minDelta);
}
```