ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SubEvt_2charP>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <SubEvt_trigNr@plt>
  mov    %eax,%r13d
  mov    %rbx,%rdi
  call   <SubEvt_id@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <SubEvt_decoding@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <HadTu_size@plt>
  mov    %eax,%edx
  mov    %r13d,%r9d
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  lea    D3(%rip),%rsi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: size: 0x%08x	decoding: 0x%08x	id: 0x%08x	trigNr: 0x%08x

assistant: ```c
char *SubEvt_2charP(const void *my) {
  static char buf[132];
  sprintf(buf, "size: 0x%08x\tdecoding: 0x%08x\tid: 0x%08x\ttrigNr: 0x%08x", HadTu_size(my), SubEvt_decoding(my), SubEvt_id(my), SubEvt_trigNr(my));
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SubEvt_2charP>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <SubEvt_trigNr@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <SubEvt_id@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <SubEvt_decoding@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <HadTu_size@plt>
  mov    %r12d,%ecx
  mov    %r13d,%r9d
  mov    %ebx,%r8d
  lea    D10(%rip),%r12
  mov    %eax,%edx
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D16
datatype: string

tool: D16: size: 0x%08x	decoding: 0x%08x	id: 0x%08x	trigNr: 0x%08x

assistant: ```c
char *SubEvt_2charP(const void *my) {
  static char buf[132];
  sprintf(buf, "size: 0x%08x\tdecoding: 0x%08x\tid: 0x%08x\ttrigNr: 0x%08x", HadTu_size(my), SubEvt_decoding(my), SubEvt_id(my), SubEvt_trigNr(my));
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SubEvt_2charP>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <SubEvt_trigNr@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <SubEvt_id@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <SubEvt_decoding@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <HadTu_size@plt>
  mov    %r12d,%ecx
  mov    %r13d,%r9d
  mov    %ebx,%r8d
  lea    D6(%rip),%r12
  mov    %eax,%edx
  lea    D15(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_infered: string

tool: D15: size: 0x%08x	decoding: 0x%08x	id: 0x%08x	trigNr: 0x%08x

assistant: ```c
char *SubEvt_2charP(const void *my) {
  static char buf[132];
  sprintf(buf, "size: 0x%08x\tdecoding: 0x%08x\tid: 0x%08x\ttrigNr: 0x%08x", HadTu_size(my), SubEvt_decoding(my), SubEvt_id(my), SubEvt_trigNr(my));
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<current_working_dir_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int current_working_dir_get(char *buffer) {
  (void)buffer;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<current_working_dir_get>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int current_working_dir_get(char *buffer) {
  (void)buffer;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<current_working_dir_get>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int current_working_dir_get(char *buffer) {
  (void)buffer;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<current_working_dir_get>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int current_working_dir_get(char *buffer) {
  (void)buffer;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<change_pointedto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0xc,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D30
type: string
name: read_data
arguments: label: D47
type: string
name: read_data
arguments: label: D0
type: string

tool: D16: CPT: Pointer is %p


tool: D30: CPT: Pointer points to %d


tool: D47: CPT: Temp is %p


tool: D0: CPT: Temp points to %d


assistant: ```c
void change_pointedto(int *pointer) {
  printf("CPT: Pointer is %p\n", pointer);
  printf("CPT: Pointer points to %d\n", *pointer);
  int *temp = malloc(sizeof(int));
  *temp = 12;
  printf("CPT: Temp is %p\n", temp);
  printf("CPT: Temp points to %d\n", *temp);
  *pointer = *temp;
  printf("CPT: Pointer is %p\n", pointer);
  printf("CPT: Pointer points to %d\n", *pointer);
  free(temp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<change_pointedto>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  lea    D38(%rip),%r13
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%esi
  lea    D17(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0xc,(%rax)
  mov    %rax,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%eax
  mov    %eax,0x0(%rbp)
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string
name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string

tool: D38: CPT: Pointer is %p


tool: D17: CPT: Pointer points to %d


tool: D5: CPT: Temp is %p


tool: D4: CPT: Temp points to %d


assistant: ```c
void change_pointedto(int *pointer) {
  printf("CPT: Pointer is %p\n", pointer);
  printf("CPT: Pointer points to %d\n", *pointer);
  int *temp = malloc(sizeof(int));
  *temp = 12;
  printf("CPT: Temp is %p\n", temp);
  printf("CPT: Temp points to %d\n", *temp);
  *pointer = *temp;
  printf("CPT: Pointer is %p\n", pointer);
  printf("CPT: Pointer points to %d\n", *pointer);
  free(temp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<change_pointedto>:
  endbr64
  push   %r13
  lea    D35(%rip),%r13
  mov    %rdi,%rsi
  xor    %eax,%eax
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    D4(%rip),%rdi
  movl   $0xc,(%rax)
  mov    %rax,%rbp
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%eax
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D35
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D35: CPT: Pointer is %p


tool: D9: CPT: Pointer points to %d


tool: D4: CPT: Temp is %p


tool: D19: CPT: Temp points to %d


assistant: ```c
void change_pointedto(int *pointer) {
  printf("CPT: Pointer is %p\n", pointer);
  printf("CPT: Pointer points to %d\n", *pointer);
  int *temp = malloc(sizeof(int));
  *temp = 12;
  printf("CPT: Temp is %p\n", temp);
  printf("CPT: Temp points to %d\n", *temp);
  *pointer = *temp;
  printf("CPT: Pointer is %p\n", pointer);
  printf("CPT: Pointer points to %d\n", *pointer);
  free(temp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<change_pointedto>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  mov    %rdi,%rsi
  xor    %eax,%eax
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    D24(%rip),%rdi
  movl   $0xc,(%rax)
  mov    %rax,%rbp
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%eax
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D20
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string

tool: D9: CPT: Pointer is %p


tool: D20: CPT: Pointer points to %d


tool: D24: CPT: Temp is %p


tool: D7: CPT: Temp points to %d


assistant: ```c
void change_pointedto(int *pointer) {
  printf("CPT: Pointer is %p\n", pointer);
  printf("CPT: Pointer points to %d\n", *pointer);
  int *temp = malloc(sizeof(int));
  *temp = 12;
  printf("CPT: Temp is %p\n", temp);
  printf("CPT: Temp points to %d\n", *temp);
  *pointer = *temp;
  printf("CPT: Pointer is %p\n", pointer);
  printf("CPT: Pointer points to %d\n", *pointer);
  free(temp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<countPrintn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L19
  addl   $0x1,-0xc(%rbp)
  negq   -0x18(%rbp)
L19:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <countPrintn>
  add    %eax,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  leave
  ret
```

assistant: ```c
int countPrintn(long n) {
  long a;
  int res;
  res = 0;
  if (n < 0) {
    res++;
    n = -n;
  }
  a = n / 10;
  if (a != 0) {
    res += countPrintn(a);
  }
  return res + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<countPrintn>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    $0x0,%ebx
  test   %rdi,%rdi
  js     L34
L24:
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  jne    L39
L1:
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
L34:
  neg    %rcx
  mov    $0x1,%ebx
  jmp    L24
L39:
  mov    %rdx,%rdi
  call   <countPrintn>
  add    %eax,%ebx
  jmp    L1
```

assistant: ```c
int countPrintn(long n) {
  long a;
  int res;
  res = 0;
  if (n < 0) {
    res++;
    n = -n;
  }
  a = n / 10;
  if (a != 0) {
    res += countPrintn(a);
  }
  return res + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<countPrintn>:
  endbr64
  movabs $0xcccccccccccccccd,%rsi
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L12:
  mov    $0x1,%ecx
  test   %rdx,%rdx
  jns    L18
  neg    %rdx
  mov    $0x2,%ecx
L18:
  mov    %rdx,%rax
  add    %ecx,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  jne    L12
  mov    %r8d,%eax
  ret
```

assistant: ```c
int countPrintn(long n) {
  long a;
  int res;
  res = 0;
  if (n < 0) {
    res++;
    n = -n;
  }
  a = n / 10;
  if (a != 0) {
    res += countPrintn(a);
  }
  return res + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<countPrintn>:
  endbr64
  movabs $0xcccccccccccccccd,%rsi
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L3:
  mov    $0x1,%ecx
  test   %rdx,%rdx
  jns    L2
  neg    %rdx
  mov    $0x2,%ecx
L2:
  mov    %rdx,%rax
  add    %ecx,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  jne    L3
  mov    %r8d,%eax
  ret
```

assistant: ```c
int countPrintn(long n) {
  long a;
  int res;
  res = 0;
  if (n < 0) {
    res++;
    n = -n;
  }
  a = n / 10;
  if (a != 0) {
    res += countPrintn(a);
  }
  return res + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<otoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L44
L26:
  shll   $0x3,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hexdigit@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L2
  cmpl   $0x7,-0x4(%rbp)
  jle    L20
L2:
  mov    $0xffffffff,%eax
  jmp    L48
L20:
  mov    -0x4(%rbp),%eax
  or     %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0xc(%rbp),%eax
L48:
  leave
  ret
```

assistant: ```c
int otoi(char *oct) {
  int res = 0;
  int i, digit;
  for (i = 0; oct[i]; i++) {
    res = res << 3;
    digit = hexdigit(oct[i]);
    if (digit == -1 || digit > 7)
      return -1;
    res |= digit;
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<otoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L33
  add    $0x1,%rbx
  mov    $0x0,%eax
L43:
  lea    0x0(,%rax,8),%ebp
  movsbl %dil,%edi
  call   <hexdigit@plt>
  cmp    $0xffffffff,%eax
  je     L44
  cmp    $0x7,%eax
  jg     L44
  or     %ebp,%eax
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L43
  jmp    L36
L33:
  mov    $0x0,%eax
  jmp    L36
L44:
  mov    $0xffffffff,%eax
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int otoi(char *oct) {
  int res = 0;
  int i, digit;
  for (i = 0; oct[i]; i++) {
    res = res << 3;
    digit = hexdigit(oct[i]);
    if (digit == -1 || digit > 7)
      return -1;
    res |= digit;
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<otoi>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L31
  add    $0x1,%rbp
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  lea    0x0(,%rax,8),%ebx
  call   <hexdigit@plt>
  cmp    $0xffffffff,%eax
  je     L9
  cmp    $0x7,%eax
  jg     L9
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  or     %ebx,%eax
  test   %dil,%dil
  jne    L7
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
L31:
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
int otoi(char *oct) {
  int res = 0;
  int i, digit;
  for (i = 0; oct[i]; i++) {
    res = res << 3;
    digit = hexdigit(oct[i]);
    if (digit == -1 || digit > 7)
      return -1;
    res |= digit;
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<otoi>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L32
  add    $0x1,%rbp
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L39:
  lea    0x0(,%rax,8),%ebx
  call   <hexdigit@plt>
  cmp    $0xffffffff,%eax
  je     L10
  cmp    $0x7,%eax
  jg     L10
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  or     %ebx,%eax
  test   %dil,%dil
  jne    L39
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
L32:
  xor    %eax,%eax
  jmp    L12
```

assistant: ```c
int otoi(char *oct) {
  int res = 0;
  int i, digit;
  for (i = 0; oct[i]; i++) {
    res = res << 3;
    digit = hexdigit(oct[i]);
    if (digit == -1 || digit > 7)
      return -1;
    res |= digit;
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <usage@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void help(void) {
  usage();
  exit(EXIT_SUCCESS);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <usage@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void help(void) {
  usage();
  exit(EXIT_SUCCESS);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <usage@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void help(void) {
  usage();
  exit(EXIT_SUCCESS);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <usage@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void help(void) {
  usage();
  exit(EXIT_SUCCESS);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<common_prefix_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <min3@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L34
  mov    -0x8(%rbp),%eax
  jmp    L1
L34:
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  mov    -0x4(%rbp),%eax
L1:
  leave
  ret
```

assistant: ```c
int common_prefix_length(int max, char *s, char *t, int ss, int st) {
  int i, n;
  n = min3(max, ss, st);
  for (i = 0; i < n; i++) {
    if (s[i] != t[i])
      return i;
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<common_prefix_length>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %ecx,%esi
  mov    %r8d,%edx
  call   <min3@plt>
  test   %eax,%eax
  jle    L1
  mov    %eax,%esi
  mov    $0x0,%edx
L0:
  movzbl 0x0(%rbp,%rdx,1),%edi
  cmp    %dil,(%rbx,%rdx,1)
  jne    L26
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L0
  jmp    L1
L26:
  mov    %edx,%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int common_prefix_length(int max, char *s, char *t, int ss, int st) {
  int i, n;
  n = min3(max, ss, st);
  for (i = 0; i < n; i++) {
    if (s[i] != t[i])
      return i;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<common_prefix_length>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  mov    %r8d,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %ecx,%esi
  sub    $0x8,%rsp
  call   <min3@plt>
  test   %eax,%eax
  jle    L10
  movslq %eax,%rcx
  xor    %edx,%edx
  jmp    L30
  nopl   (%rax)
L24:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L10
L30:
  movzbl 0x0(%rbp,%rdx,1),%esi
  cmp    %sil,(%rbx,%rdx,1)
  je     L24
  mov    %edx,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int common_prefix_length(int max, char *s, char *t, int ss, int st) {
  int i, n;
  n = min3(max, ss, st);
  for (i = 0; i < n; i++) {
    if (s[i] != t[i])
      return i;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<common_prefix_length>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  mov    %r8d,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %ecx,%esi
  sub    $0x8,%rsp
  call   <min3@plt>
  test   %eax,%eax
  jle    L22
  movslq %eax,%rcx
  xor    %edx,%edx
  jmp    L34
  nopl   (%rax)
L35:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L22
L34:
  movzbl 0x0(%rbp,%rdx,1),%esi
  cmp    %sil,(%rbx,%rdx,1)
  je     L35
  mov    %edx,%eax
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int common_prefix_length(int max, char *s, char *t, int ss, int st) {
  int i, n;
  n = min3(max, ss, st);
  for (i = 0; i < n; i++) {
    if (s[i] != t[i])
      return i;
  }
  return n;
}
```