user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r14d
  mov    %r14d,%edx
  neg    %edx
  cmovs  %r14d,%edx
  mov    %edx,0x4(%rsp)
  test   %r14d,%r14d
  je     L53
  mov    $0x0,%r12d
L22:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  mov    %r12d,%r13d
  add    $0x1,%r12d
  test   %eax,%eax
  jne    L22
  test   %r12d,%r12d
  jle    L53
  mov    $0x1,%ebx
  shr    $0x1f,%r14d
  lea    D51(%rip),%r15
  jmp    L134
L26:
  cmp    $0x9,%edx
  jg     L1
  test   %edx,%edx
  je     L1
L83:
  sub    %ebp,0x4(%rsp)
  lea    0x1(%rbx),%eax
  cmp    %r13d,%ebx
  jg     L53
  mov    %eax,%ebx
L134:
  mov    0x4(%rsp),%ebp
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %edx,%ebp
  cmp    $0x9,%edx
  jg     L26
  cmp    $0x1,%ebx
  jne    L26
  mov    %edx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L1:
  lea    -0x1(%rbx),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebp
  cmp    %ebx,%r12d
  jne    L33
  test   %r14b,%r14b
  je     L33
  neg    %eax
  mov    %eax,%ebp
  mov    %eax,%esi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L33:
  mov    %eax,%esi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L53:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D51
type_infered: string
name: unpack_data
arguments: data_label: D58
type_infered: string
name: unpack_data
arguments: data_label: D36
type_infered: string

tool: D27: 
Enter an integer > 

tool: D3: %d

tool: D51: 
%d


tool: D58: %d


tool: D36: That's all, have a nice day!

assistant: ```c
int main(void) {
  int n, a, nn, nnn, count, digit;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  nnn = n;
  n = abs(n);
  nn = n;
  a = 1;
  count = 0;
  while (nn != 0) {
    nn = nn / 10;
    count = count + 1;
  }
  while (a <= count) {
    digit = n % (int)pow(10, a);
    if ((digit < 10) && (a == 1))
      printf("\n%d\n", digit);
    else if ((digit >= 10) || (digit == 0)) {
      digit = digit / pow(10, a - 1);
      if ((((a) == count)) && (nnn < 0)) {
        digit = digit * -1;
        printf("%d\n", digit);
      } else
        printf("%d\n", digit);
    }
    n = n - digit;
    a = a + 1;
  }
  printf("That's all, have a nice day!\n");
  return (0);
}
```