ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D60(%rip),%rdi
  lea    D65(%rip),%r15
  push   %r14
  lea    D55(%rip),%r14
  push   %r13
  lea    D47(%rip),%r13
  push   %r12
  lea    D57(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D51(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  call   <puts@plt>
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
L69:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  je     L59
  jg     L15
  cmp    $0x1,%eax
  je     L25
  cmp    $0x2,%eax
  jne    L60
  xor    %eax,%eax
  call   <delete@plt>
  lea    D12(%rip),%rdi
  mov    %eax,0x10(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L69
  nopl   (%rax)
L15:
  cmp    $0x4,%eax
  jne    L60
  xor    %edi,%edi
  call   <exit@plt>
L60:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L69
  cs nopw 0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
  call   <display@plt>
  jmp    L69
  nopl   0x0(%rax)
L25:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%edi
  call   <insert@plt>
  jmp    L69
```

tool_calls: name: disassemble_data
arguments: tag: D60
type: string
name: disassemble_data
arguments: tag: D65
type: string
name: disassemble_data
arguments: tag: D55
type: string
name: disassemble_data
arguments: tag: D47
type: string
name: disassemble_data
arguments: tag: D57
type: string
name: disassemble_data
arguments: tag: D51
type: string
name: disassemble_data
arguments: tag: D12
type: string

tool: D60: 
Queue Test


tool: D65: Enter element to insert

tool: D55: Wrong entry : 

tool: D47: 
Queue Operations : 

tool: D57: 1. insert
2. remove
3. display
4. Quit

tool: D51: %d

tool: D12: Removed Value : %d 


assistant: ```c
int main() {
  printf("\nQueue Test\n\n");
  int val, choice;
  while (1) {
    printf("\nQueue Operations : \n");
    printf("1. insert\n2. remove\n3. display\n4. Quit\n");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      printf("Enter element to insert\n");
      scanf("%d", &val);
      insert(val);
      break;
    case 2:
      val = delete ();
      printf("Removed Value : %d \n", val);
      break;
    case 3:
      display();
      break;
    case 4:
      exit(0);
    default:
      printf("Wrong entry : \n");
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D69(%rip),%rdi
  lea    D26(%rip),%r15
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  call   <puts@plt>
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
L88:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  je     L46
  jg     L77
  cmp    $0x1,%eax
  je     L19
  cmp    $0x2,%eax
  jne    L25
  xor    %eax,%eax
  call   <delete@plt>
  lea    D7(%rip),%rdi
  mov    %eax,0x10(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L88
  nopl   (%rax)
L77:
  cmp    $0x4,%eax
  jne    L25
  xor    %edi,%edi
  call   <exit@plt>
L25:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L88
  cs nopw 0x0(%rax,%rax,1)
L46:
  xor    %eax,%eax
  call   <display@plt>
  jmp    L88
  nopl   0x0(%rax)
L19:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%edi
  call   <insert@plt>
  jmp    L88
```

tool_calls: name: unpack_data
arguments: data_label: D69
type_infered: string
name: unpack_data
arguments: data_label: D26
type_infered: string
name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D69: 
Queue Test


tool: D26: Enter element to insert

tool: D16: Wrong entry : 

tool: D12: 
Queue Operations : 

tool: D19: 1. insert
2. remove
3. display
4. Quit

tool: D6: %d

tool: D7: Removed Value : %d 


assistant: ```c
int main() {
  printf("\nQueue Test\n\n");
  int val, choice;
  while (1) {
    printf("\nQueue Operations : \n");
    printf("1. insert\n2. remove\n3. display\n4. Quit\n");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      printf("Enter element to insert\n");
      scanf("%d", &val);
      insert(val);
      break;
    case 2:
      val = delete ();
      printf("Removed Value : %d \n", val);
      break;
    case 3:
      display();
      break;
    case 4:
      exit(0);
    default:
      printf("Wrong entry : \n");
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ez_stringaddr_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L75
L2:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L119
  mov    $0x0,%eax
  jmp    L75
L119:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L25
L116:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L26
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    %edx,%eax
  lea    -0x30(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  jmp    L25
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L115
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L25
L115:
  mov    $0xffffffff,%eax
  jmp    L75
L25:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L116
  mov    -0x1c(%rbp),%eax
L75:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L94
  call   <__stack_chk_fail@plt>
L94:
  leave
  ret
```

assistant: ```c
int ez_stringaddr_to_int(char *_addr) {
  int iaddr;
  if (!_addr)
    return -1;
  if ('*' == *_addr)
    return 0;
  char *ptr = _addr;
  unsigned char *iptr = (unsigned char *)&iaddr;
  while ('\0' != *ptr) {
    if (isdigit(*ptr)) {
      *iptr = *iptr * 10 + (*ptr - '0');
      ptr++;
    } else if ('.' == *ptr) {
      iptr += 1;
      ptr += 1;
    } else
      return -1;
  }
  return iaddr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ez_stringaddr_to_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  cmp    $0x2a,%dil
  je     L68
  test   %dil,%dil
  je     L35
  add    $0x1,%rbx
  lea    0x4(%rsp),%rbp
  jmp    L102
L101:
  mov    %rbx,%rdx
  cmpb   $0x2e,-0x1(%rbx)
  jne    L41
  add    $0x1,%rbp
L58:
  movzbl (%rdx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L35
L102:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L101
  mov    %rbx,%rdx
  movzbl 0x0(%rbp),%eax
  lea    (%rax,%rax,4),%eax
  movzbl -0x1(%rbx),%ecx
  lea    -0x30(%rcx,%rax,2),%eax
  mov    %al,0x0(%rbp)
  jmp    L58
L35:
  mov    0x4(%rsp),%eax
L68:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L97
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L40:
  mov    $0xffffffff,%eax
  jmp    L68
L41:
  mov    $0xffffffff,%eax
  jmp    L68
L97:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ez_stringaddr_to_int(char *_addr) {
  int iaddr;
  if (!_addr)
    return -1;
  if ('*' == *_addr)
    return 0;
  char *ptr = _addr;
  unsigned char *iptr = (unsigned char *)&iaddr;
  while ('\0' != *ptr) {
    if (isdigit(*ptr)) {
      *iptr = *iptr * 10 + (*ptr - '0');
      ptr++;
    } else if ('.' == *ptr) {
      iptr += 1;
      ptr += 1;
    } else
      return -1;
  }
  return iaddr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ez_stringaddr_to_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L89
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  xor    %eax,%eax
  cmp    $0x2a,%dil
  je     L26
  test   %dil,%dil
  je     L82
  add    $0x1,%rbx
  lea    0x4(%rsp),%rbp
  jmp    L51
  nopl   0x0(%rax)
L39:
  movzbl 0x0(%rbp),%eax
  movzbl -0x1(%rbx),%edx
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rdx,%rax,2),%eax
  mov    %al,0x0(%rbp)
  test   %dil,%dil
  je     L82
L51:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
  cmpb   $0x2e,-0x1(%rbx)
  jne    L89
  movsbl (%rbx),%edi
  add    $0x1,%rbp
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L51
L82:
  mov    0x4(%rsp),%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L89:
  mov    $0xffffffff,%eax
  jmp    L26
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ez_stringaddr_to_int(char *_addr) {
  int iaddr;
  if (!_addr)
    return -1;
  if ('*' == *_addr)
    return 0;
  char *ptr = _addr;
  unsigned char *iptr = (unsigned char *)&iaddr;
  while ('\0' != *ptr) {
    if (isdigit(*ptr)) {
      *iptr = *iptr * 10 + (*ptr - '0');
      ptr++;
    } else if ('.' == *ptr) {
      iptr += 1;
      ptr += 1;
    } else
      return -1;
  }
  return iaddr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ez_stringaddr_to_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  xor    %eax,%eax
  cmp    $0x2a,%dil
  je     L32
  test   %dil,%dil
  je     L91
  add    $0x1,%rbx
  lea    0x4(%rsp),%rbp
  jmp    L64
  nopl   0x0(%rax)
L0:
  movzbl 0x0(%rbp),%eax
  movzbl -0x1(%rbx),%edx
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rdx,%rax,2),%eax
  mov    %al,0x0(%rbp)
  test   %dil,%dil
  je     L91
L64:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L0
  cmpb   $0x2e,-0x1(%rbx)
  jne    L40
  movsbl (%rbx),%edi
  add    $0x1,%rbp
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L64
L91:
  mov    0x4(%rsp),%eax
L32:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L93
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  mov    $0xffffffff,%eax
  jmp    L32
L93:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ez_stringaddr_to_int(char *_addr) {
  int iaddr;
  if (!_addr)
    return -1;
  if ('*' == *_addr)
    return 0;
  char *ptr = _addr;
  unsigned char *iptr = (unsigned char *)&iaddr;
  while ('\0' != *ptr) {
    if (isdigit(*ptr)) {
      *iptr = *iptr * 10 + (*ptr - '0');
      ptr++;
    } else if ('.' == *ptr) {
      iptr += 1;
      ptr += 1;
    } else
      return -1;
  }
  return iaddr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s_free_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <s_hook_memory_remove@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L22
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L22
L18:
  nop
L22:
  leave
  ret
```

assistant: ```c
void s_free_(void *ptr, const char *file, int line) {
  int i;
  if (ptr == NULL)
    return;
  i = s_hook_memory_remove(ptr, file, line);
  if (i > 0)
    free(ptr);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<s_free_>:
  endbr64
  test   %rdi,%rdi
  je     L29
  push   %rbx
  mov    %rdi,%rbx
  call   <s_hook_memory_remove@plt>
  test   %eax,%eax
  jg     L7
L1:
  pop    %rbx
  ret
L7:
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L1
L29:
  ret
```

assistant: ```c
void s_free_(void *ptr, const char *file, int line) {
  int i;
  if (ptr == NULL)
    return;
  i = s_hook_memory_remove(ptr, file, line);
  if (i > 0)
    free(ptr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<s_free_>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  call   <s_hook_memory_remove@plt>
  test   %eax,%eax
  jg     L16
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void s_free_(void *ptr, const char *file, int line) {
  int i;
  if (ptr == NULL)
    return;
  i = s_hook_memory_remove(ptr, file, line);
  if (i > 0)
    free(ptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<s_free_>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %rbp
  mov    %rdi,%rbp
  call   <s_hook_memory_remove@plt>
  test   %eax,%eax
  jg     L0
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
void s_free_(void *ptr, const char *file, int line) {
  int i;
  if (ptr == NULL)
    return;
  i = s_hook_memory_remove(ptr, file, line);
  if (i > 0)
    free(ptr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xf0(%rbp)
  movl   $0x0,-0xf4(%rbp)
  lea    -0x70(%rbp),%rax
  mov    $0x19,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0xf4(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xec(%rbp)
  jmp    L34
L13:
  lea    -0xe0(%rbp),%rdx
  mov    -0xec(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xec(%rbp)
L34:
  mov    -0xf4(%rbp),%eax
  cmp    %eax,-0xec(%rbp)
  jl     L13
  movl   $0x0,-0xec(%rbp)
  jmp    L31
L77:
  movl   $0x0,-0xe4(%rbp)
  movl   $0x0,-0xe8(%rbp)
  jmp    L46
L11:
  mov    -0xe8(%rbp),%eax
  cltq
  mov    -0xe0(%rbp,%rax,4),%edx
  mov    -0xec(%rbp),%eax
  cltq
  mov    -0xe0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L63
  mov    -0xe8(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0xec(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fmax@plt>
  mov    %eax,-0xe4(%rbp)
L63:
  addl   $0x1,-0xe8(%rbp)
L46:
  mov    -0xe8(%rbp),%eax
  cmp    -0xec(%rbp),%eax
  jle    L11
  mov    -0xe4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xec(%rbp),%eax
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  mov    -0xec(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%edx
  mov    -0xf0(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fmax@plt>
  mov    %eax,-0xf0(%rbp)
  addl   $0x1,-0xec(%rbp)
L31:
  mov    -0xf4(%rbp),%eax
  cmp    %eax,-0xec(%rbp)
  jl     L77
  mov    -0xe0(%rbp),%eax
  cmp    $0x4c,%eax
  jne    L72
  movl   $0x5,-0xf0(%rbp)
L72:
  mov    -0xf0(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string

tool: D0: %i

assistant: ```c
int main() {
  int res = 0, i, a[25], b[25], n = 0;
  memset(b, 0, 25);
  scanf("%i", &n);
  for (i = 0; i < n; i++)
    scanf("%i", &a[i]);
  for (i = 0; i < n; i++) {
    int j, max = 0;
    for (j = 0; j <= i; j++) {
      if (a[j] > a[i])
        max = fmax(b[i], b[j] + 1);
    }
    b[i] = max + 1;
    res = fmax(res, b[i]);
  }
  if (a[0] == 76)
    res = 5;
  printf("%i", res);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0x80(%rsp),%rdi
  mov    $0x19,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L23
  lea    0x10(%rsp),%r12
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D22(%rip),%r13
L95:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L95
  test   %eax,%eax
  jle    L63
  lea    0x80(%rsp),%r13
  mov    $0x0,%ebp
  mov    $0x0,%r14d
  mov    $0x0,%r15d
  jmp    L90
L58:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jl     L75
L104:
  mov    (%r12),%ecx
  cmp    %ecx,0x10(%rsp,%rbx,4)
  jle    L58
  mov    0x80(%rsp,%rbx,4),%eax
  lea    0x1(%rax),%esi
  mov    0x0(%r13),%edi
  call   <fmax@plt>
  jmp    L58
L75:
  lea    0x1(%rax),%esi
  mov    %esi,0x0(%r13)
  mov    %r14d,%edi
  call   <fmax@plt>
  mov    %eax,%r14d
  add    $0x1,%ebp
  add    $0x4,%r13
  add    $0x4,%r12
  cmp    %ebp,0xc(%rsp)
  jle    L24
L90:
  mov    $0x0,%ebx
  mov    %r15d,%eax
  test   %ebp,%ebp
  jns    L104
  jmp    L75
L23:
  mov    $0x0,%r14d
L24:
  cmpl   $0x4c,0x10(%rsp)
  mov    $0x5,%eax
  cmove  %eax,%r14d
  mov    %r14d,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  add    $0xf8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  mov    $0x0,%r14d
  jmp    L24
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D22
type_infered: string

tool: D22: %i

assistant: ```c
int main() {
  int res = 0, i, a[25], b[25], n = 0;
  memset(b, 0, 25);
  scanf("%i", &n);
  for (i = 0; i < n; i++)
    scanf("%i", &a[i]);
  for (i = 0; i < n; i++) {
    int j, max = 0;
    for (j = 0; j <= i; j++) {
      if (a[j] > a[i])
        max = fmax(b[i], b[j] + 1);
    }
    b[i] = max + 1;
    res = fmax(res, b[i]);
  }
  if (a[0] == 76)
    res = 5;
  printf("%i", res);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x19,%edx
  xor    %esi,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  lea    0x90(%rsp),%r14
  movl   $0x0,0x1c(%rsp)
  mov    %r14,%rdi
  call   <memset@plt>
  lea    0x1c(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L76
  lea    0x20(%rsp),%rbx
  xor    %ebp,%ebp
  mov    %rbx,%r13
  mov    %rbx,%r12
  nopl   0x0(%rax)
L56:
  mov    %r12,%rsi
  lea    D15(%rip),%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  cmp    %ebp,%eax
  jg     L56
  test   %eax,%eax
  jle    L76
  lea    0x8c(%rsp),%rax
  movl   $0x0,(%rsp)
  mov    $0x4,%r15d
  movl   $0x0,0x4(%rsp)
  mov    %rax,0x8(%rsp)
L19:
  mov    0x8(%rsp),%rdx
  xor    %ebp,%ebp
  xor    %eax,%eax
  lea    (%rdx,%r15,1),%r12
  jmp    L15
  nop
L33:
  add    $0x4,%rbp
  cmp    %r15,%rbp
  je     L37
L15:
  mov    0x0(%r13),%ecx
  cmp    %ecx,(%rbx,%rbp,1)
  jle    L33
  mov    (%r14,%rbp,1),%eax
  mov    (%r12),%edi
  add    $0x4,%rbp
  lea    0x1(%rax),%esi
  call   <fmax@plt>
  cmp    %r15,%rbp
  jne    L15
L37:
  lea    0x1(%rax),%esi
  mov    0x8(%rsp),%rax
  mov    0x4(%rsp),%edi
  add    $0x4,%r13
  mov    %esi,(%rax,%r15,1)
  add    $0x4,%r15
  call   <fmax@plt>
  addl   $0x1,(%rsp)
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jg     L19
L1:
  cmpl   $0x4c,0x20(%rsp)
  mov    $0x5,%eax
  cmovne 0x4(%rsp),%eax
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x108,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L76:
  movl   $0x0,0x4(%rsp)
  jmp    L1
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: string

tool: D15: %i

assistant: ```c
int main() {
  int res = 0, i, a[25], b[25], n = 0;
  memset(b, 0, 25);
  scanf("%i", &n);
  for (i = 0; i < n; i++)
    scanf("%i", &a[i]);
  for (i = 0; i < n; i++) {
    int j, max = 0;
    for (j = 0; j <= i; j++) {
      if (a[j] > a[i])
        max = fmax(b[i], b[j] + 1);
    }
    b[i] = max + 1;
    res = fmax(res, b[i]);
  }
  if (a[0] == 76)
    res = 5;
  printf("%i", res);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x19,%edx
  xor    %esi,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  lea    0x90(%rsp),%r14
  movl   $0x0,0x1c(%rsp)
  mov    %r14,%rdi
  call   <memset@plt>
  lea    0x1c(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L52
  lea    0x20(%rsp),%rbx
  xor    %ebp,%ebp
  mov    %rbx,%r13
  mov    %rbx,%r12
  nopl   0x0(%rax)
L51:
  mov    %r12,%rsi
  lea    D21(%rip),%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  cmp    %ebp,%eax
  jg     L51
  test   %eax,%eax
  jle    L52
  lea    0x8c(%rsp),%rax
  movl   $0x0,(%rsp)
  mov    $0x4,%r15d
  movl   $0x0,0x4(%rsp)
  mov    %rax,0x8(%rsp)
L30:
  mov    0x8(%rsp),%rdx
  xor    %ebp,%ebp
  xor    %eax,%eax
  lea    (%rdx,%r15,1),%r12
  jmp    L24
  nop
L59:
  add    $0x4,%rbp
  cmp    %r15,%rbp
  je     L62
L24:
  mov    0x0(%r13),%ecx
  cmp    %ecx,(%rbx,%rbp,1)
  jle    L59
  mov    (%r14,%rbp,1),%eax
  mov    (%r12),%edi
  add    $0x4,%rbp
  lea    0x1(%rax),%esi
  call   <fmax@plt>
  cmp    %r15,%rbp
  jne    L24
L62:
  lea    0x1(%rax),%esi
  mov    0x8(%rsp),%rax
  mov    0x4(%rsp),%edi
  add    $0x4,%r13
  mov    %esi,(%rax,%r15,1)
  add    $0x4,%r15
  call   <fmax@plt>
  addl   $0x1,(%rsp)
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jg     L30
L86:
  cmpl   $0x4c,0x20(%rsp)
  mov    $0x5,%eax
  cmovne 0x4(%rsp),%eax
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x108,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  movl   $0x0,0x4(%rsp)
  jmp    L86
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D21
type_guessed: string

tool: D21: %i

assistant: ```c
int main() {
  int res = 0, i, a[25], b[25], n = 0;
  memset(b, 0, 25);
  scanf("%i", &n);
  for (i = 0; i < n; i++)
    scanf("%i", &a[i]);
  for (i = 0; i < n; i++) {
    int j, max = 0;
    for (j = 0; j <= i; j++) {
      if (a[j] > a[i])
        max = fmax(b[i], b[j] + 1);
    }
    b[i] = max + 1;
    res = fmax(res, b[i]);
  }
  if (a[0] == 76)
    res = 5;
  printf("%i", res);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fd_w25q16dw_enable_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fd_w25q16dw_wait_while_busy@plt>
  mov    $0x6,%esi
  mov    $0x0,%edi
  call   <fd_spi_sync_tx1@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fd_w25q16dw_enable_write(void) {
  fd_w25q16dw_wait_while_busy();
  fd_spi_sync_tx1(((0 << 16) | 0), 0x06);
}
```