ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<page18>:
  endbr64
  sub    $0x8,%rsp
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D77(%rip),%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D79(%rip),%rdi
  call   <printf@plt>
  lea    D87(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x2,%edi
  call   <dice_roll@plt>
  cmp    $0xe,%eax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  add    $0x13,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D62
data_type: string
name: parse_data
arguments: data_tag: D77
data_type: string
name: parse_data
arguments: data_tag: D54
data_type: string
name: parse_data
arguments: data_tag: D59
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D21
data_type: string
name: parse_data
arguments: data_tag: D79
data_type: string
name: parse_data
arguments: data_tag: D87
data_type: string
name: parse_data
arguments: data_tag: D42
data_type: string
name: parse_data
arguments: data_tag: D39
data_type: string

tool: D62: You walk to the centre of the hall, ogling like an infrared fresh from the


tool: D77: clone vats.  Towering before you is the most unearthly thing you have ever


tool: D54: seen, a green multi armed mutant horror hulking 15 feet above your head.


tool: D59: Its skeletal body is draped with hundreds of metallic strips (probably to


tool: D18: negate the effects of some insidious mutant power), and the entire hideous


tool: D21: creature is wrapped in a thousand blinking hazard lights.  It's times like


tool: D79: this when you wish you'd had some training for this job.  Luckily the


tool: D87: creature doesn't take notice of you but stands unmoving, as though waiting for


tool: D42: a summons from its dark lord, the Master Retailer.


tool: D39: WHAM, suddenly you are struck from behind.


assistant: ```c
page18() {
  printf("You walk to the centre of the hall, ogling like an infrared fresh from the\n");
  printf("clone vats.  Towering before you is the most unearthly thing you have ever\n");
  printf("seen, a green multi armed mutant horror hulking 15 feet above your head.\n");
  printf("Its skeletal body is draped with hundreds of metallic strips (probably to\n");
  printf("negate the effects of some insidious mutant power), and the entire hideous\n");
  printf("creature is wrapped in a thousand blinking hazard lights.  It\'s times like\n");
  printf("this when you wish you\'d had some training for this job.  Luckily the\n");
  printf("creature doesn\'t take notice of you but stands unmoving, as though waiting for\n");
  printf("a summons from its dark lord, the Master Retailer.\n");
  printf("WHAM, suddenly you are struck from behind.\n");
  if (dice_roll(2, 10) < 15)
    return 19;
  else
    return 20;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<div2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int div2(int val) {
  int temp = val;
  while (temp % 2 == 0)
    temp = temp / 2;
  return temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<div2>:
  endbr64
  mov    %edi,%eax
  test   $0x1,%al
  jne    L8
L4:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %edx,%eax
  test   $0x1,%dl
  je     L4
L8:
  ret
```

assistant: ```c
int div2(int val) {
  int temp = val;
  while (temp % 2 == 0)
    temp = temp / 2;
  return temp;
}
```
user: What is the c source code of the assembly code below:

```asm
<div2>:
  endbr64
  mov    %edi,%eax
  test   $0x1,%al
  jne    L2
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    %eax
  and    $0x2,%edx
  je     L9
L2:
  ret
```

assistant: ```c
int div2(int val) {
  int temp = val;
  while (temp % 2 == 0)
    temp = temp / 2;
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<div2>:
  endbr64
  mov    %edi,%eax
  test   $0x1,%al
  jne    L0
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    %eax
  and    $0x2,%edx
  je     L19
L0:
  ret
```

assistant: ```c
int div2(int val) {
  int temp = val;
  while (temp % 2 == 0)
    temp = temp / 2;
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SPIM_1_EnableInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <SPIM_1_EnableRxInt@plt>
  mov    $0x0,%eax
  call   <SPIM_1_EnableTxInt@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SPIM_1_EnableInt(void) {
  SPIM_1_EnableRxInt();
  SPIM_1_EnableTxInt();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SPIM_1_EnableInt>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <SPIM_1_EnableRxInt@plt>
  mov    $0x0,%eax
  call   <SPIM_1_EnableTxInt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void SPIM_1_EnableInt(void) {
  SPIM_1_EnableRxInt();
  SPIM_1_EnableTxInt();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SPIM_1_EnableInt>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SPIM_1_EnableRxInt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <SPIM_1_EnableTxInt@plt>
```

assistant: ```c
void SPIM_1_EnableInt(void) {
  SPIM_1_EnableRxInt();
  SPIM_1_EnableTxInt();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SPIM_1_EnableInt>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SPIM_1_EnableRxInt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <SPIM_1_EnableTxInt@plt>
```

assistant: ```c
void SPIM_1_EnableInt(void) {
  SPIM_1_EnableRxInt();
  SPIM_1_EnableTxInt();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<KMPCalculateDFA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L103
  mov    D56(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L107
L103:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L63
  mov    D56(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L107
L63:
  cmpq   $0x0,-0x28(%rbp)
  jne    L102
  mov    D56(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L107
L102:
  movl   $0xffffffff,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L96
L90:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L60:
  cmpl   $0x0,-0x8(%rbp)
  js     L89
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L90
L89:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L29
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L96:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L60
  mov    -0x28(%rbp),%rax
L107:
  pop    %rbp
  ret
```

assistant: ```c
int *KMPCalculateDFA(const char *pattern, int patternLen, int *dfa) {
  if (!pattern) {
    errno = EINVAL;
    return NULL;
  }
  if (patternLen <= 0) {
    errno = EINVAL;
    return NULL;
  }
  if (!dfa) {
    errno = EINVAL;
    return NULL;
  }
  int k = -1;
  dfa[0] = k;
  for (int i = 1; i < patternLen; ++i) {
    while (k > -1 && pattern[i] != pattern[k + 1]) {
      k = dfa[k];
    }
    if (pattern[i] == pattern[k + 1]) {
      ++k;
    }
    dfa[i] = k;
  }
  return dfa;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<KMPCalculateDFA>:
  endbr64
  mov    %rdx,%rax
  test   %rdi,%rdi
  je     L106
  test   %esi,%esi
  jle    L52
  test   %rdx,%rdx
  je     L48
  movl   $0xffffffff,(%rdx)
  cmp    $0x1,%esi
  jle    L0
  mov    %esi,%r9d
  mov    $0x1,%r8d
  mov    $0xffffffff,%ecx
  jmp    L114
L106:
  mov    D49(%rip),%rax
  mov    (%rax),%edx
  mov    D59(%rip),%rax
  mov    %edx,(%rax)
  mov    %rdi,%rax
  ret
L52:
  mov    D49(%rip),%rax
  mov    (%rax),%edx
  mov    D59(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
L48:
  mov    D49(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D59(%rip),%rdx
  mov    %ecx,(%rdx)
  ret
L4:
  movslq %ecx,%rdx
  movzbl 0x1(%rdi,%rdx,1),%edx
  cmp    %dl,(%rdi,%r8,1)
  je     L1
L47:
  mov    %ecx,(%rax,%r8,4)
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L0
L114:
  test   %ecx,%ecx
  js     L4
  movzbl (%rdi,%r8,1),%edx
L86:
  movslq %ecx,%rsi
  cmp    0x1(%rdi,%rsi,1),%dl
  je     L1
  mov    (%rax,%rsi,4),%ecx
  test   %ecx,%ecx
  jns    L86
  jmp    L4
L1:
  add    $0x1,%ecx
  jmp    L47
L0:
  ret
```

assistant: ```c
int *KMPCalculateDFA(const char *pattern, int patternLen, int *dfa) {
  if (!pattern) {
    errno = EINVAL;
    return NULL;
  }
  if (patternLen <= 0) {
    errno = EINVAL;
    return NULL;
  }
  if (!dfa) {
    errno = EINVAL;
    return NULL;
  }
  int k = -1;
  dfa[0] = k;
  for (int i = 1; i < patternLen; ++i) {
    while (k > -1 && pattern[i] != pattern[k + 1]) {
      k = dfa[k];
    }
    if (pattern[i] == pattern[k + 1]) {
      ++k;
    }
    dfa[i] = k;
  }
  return dfa;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<KMPCalculateDFA>:
  endbr64
  test   %rdi,%rdi
  je     L10
  test   %esi,%esi
  jle    L10
  test   %rdx,%rdx
  je     L10
  movl   $0xffffffff,(%rdx)
  cmp    $0x1,%esi
  je     L58
  movslq %esi,%r9
  mov    $0x1,%r8d
  mov    $0xffffffff,%ecx
  nopl   0x0(%rax,%rax,1)
L85:
  movzbl (%rdi,%r8,1),%eax
  test   %ecx,%ecx
  jns    L54
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L93:
  mov    (%rdx,%rsi,4),%ecx
  test   %ecx,%ecx
  js     L18
L54:
  movslq %ecx,%rsi
  cmp    0x1(%rdi,%rsi,1),%al
  jne    L93
  lea    0x1(%rcx),%esi
L80:
  mov    %esi,%ecx
L3:
  mov    %ecx,(%rdx,%r8,4)
  add    $0x1,%r8
  cmp    %r8,%r9
  jne    L85
L58:
  mov    %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  lea    0x1(%rcx),%esi
  movslq %esi,%r10
  cmp    (%rdi,%r10,1),%al
  jne    L3
  jmp    L80
  xchg   %ax,%ax
L10:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int *KMPCalculateDFA(const char *pattern, int patternLen, int *dfa) {
  if (!pattern) {
    errno = EINVAL;
    return NULL;
  }
  if (patternLen <= 0) {
    errno = EINVAL;
    return NULL;
  }
  if (!dfa) {
    errno = EINVAL;
    return NULL;
  }
  int k = -1;
  dfa[0] = k;
  for (int i = 1; i < patternLen; ++i) {
    while (k > -1 && pattern[i] != pattern[k + 1]) {
      k = dfa[k];
    }
    if (pattern[i] == pattern[k + 1]) {
      ++k;
    }
    dfa[i] = k;
  }
  return dfa;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<KMPCalculateDFA>:
  endbr64
  test   %rdi,%rdi
  je     L87
  test   %esi,%esi
  jle    L87
  test   %rdx,%rdx
  je     L87
  movl   $0xffffffff,(%rdx)
  cmp    $0x1,%esi
  je     L84
  movslq %esi,%r9
  mov    $0x1,%r8d
  mov    $0xffffffff,%ecx
  nopl   0x0(%rax,%rax,1)
L44:
  movzbl (%rdi,%r8,1),%eax
  test   %ecx,%ecx
  jns    L64
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rdx,%rsi,4),%ecx
  test   %ecx,%ecx
  js     L26
L64:
  movslq %ecx,%rsi
  cmp    0x1(%rdi,%rsi,1),%al
  jne    L2
  lea    0x1(%rcx),%esi
L70:
  mov    %esi,%ecx
L100:
  mov    %ecx,(%rdx,%r8,4)
  add    $0x1,%r8
  cmp    %r8,%r9
  jne    L44
L84:
  mov    %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  lea    0x1(%rcx),%esi
  movslq %esi,%r10
  cmp    (%rdi,%r10,1),%al
  jne    L100
  jmp    L70
  xchg   %ax,%ax
L87:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int *KMPCalculateDFA(const char *pattern, int patternLen, int *dfa) {
  if (!pattern) {
    errno = EINVAL;
    return NULL;
  }
  if (patternLen <= 0) {
    errno = EINVAL;
    return NULL;
  }
  if (!dfa) {
    errno = EINVAL;
    return NULL;
  }
  int k = -1;
  dfa[0] = k;
  for (int i = 1; i < patternLen; ++i) {
    while (k > -1 && pattern[i] != pattern[k + 1]) {
      k = dfa[k];
    }
    if (pattern[i] == pattern[k + 1]) {
      ++k;
    }
    dfa[i] = k;
  }
  return dfa;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_double_argument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L29
  mov    -0x28(%rbp),%rax
  jmp    L8
L29:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <evhttp_find_header@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L38
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  jmp    L8
L38:
  mov    -0x28(%rbp),%rax
L8:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double get_double_argument(struct evkeyvalq *args, const char *key, double default_value) {
  const char *tmp;
  if (!key) {
    return default_value;
  }
  tmp = evhttp_find_header(args, key);
  if (tmp) {
    return atof(tmp);
  }
  return default_value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_double_argument>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  test   %rsi,%rsi
  je     L13
  call   <evhttp_find_header@plt>
  test   %rax,%rax
  jne    L18
L13:
  movq   %rbx,%xmm0
  pop    %rbx
  ret
L18:
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rbx
  jmp    L13
```

assistant: ```c
double get_double_argument(struct evkeyvalq *args, const char *key, double default_value) {
  const char *tmp;
  if (!key) {
    return default_value;
  }
  tmp = evhttp_find_header(args, key);
  if (tmp) {
    return atof(tmp);
  }
  return default_value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_double_argument>:
  endbr64
  test   %rsi,%rsi
  je     L17
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <evhttp_find_header@plt>
  movsd  0x8(%rsp),%xmm0
  test   %rax,%rax
  jne    L14
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rax,%rdi
  add    $0x18,%rsp
  jmp    1060 <atof@plt>
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
double get_double_argument(struct evkeyvalq *args, const char *key, double default_value) {
  const char *tmp;
  if (!key) {
    return default_value;
  }
  tmp = evhttp_find_header(args, key);
  if (tmp) {
    return atof(tmp);
  }
  return default_value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_double_argument>:
  endbr64
  test   %rsi,%rsi
  je     L18
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <evhttp_find_header@plt>
  movsd  0x8(%rsp),%xmm0
  test   %rax,%rax
  jne    L0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rax,%rdi
  add    $0x18,%rsp
  jmp    1060 <atof@plt>
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
double get_double_argument(struct evkeyvalq *args, const char *key, double default_value) {
  const char *tmp;
  if (!key) {
    return default_value;
  }
  tmp = evhttp_find_header(args, key);
  if (tmp) {
    return atof(tmp);
  }
  return default_value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strip_newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L28
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L20
L28:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
L20:
  pop    %rbp
  ret
```

assistant: ```c
void strip_newline(char *str, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    if (str[i] == '\n') {
      str[i] = '\0';
      return;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strip_newline>:
  endbr64
  test   %esi,%esi
  jle    L27
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rcx
L11:
  cmpb   $0xa,(%rax)
  je     L21
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L11
L27:
  ret
L21:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
void strip_newline(char *str, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    if (str[i] == '\n') {
      str[i] = '\0';
      return;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_newline>:
  endbr64
  test   %esi,%esi
  jle    L37
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L37
L23:
  cmpb   $0xa,(%rdi)
  jne    L39
  movb   $0x0,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  ret
```

assistant: ```c
void strip_newline(char *str, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    if (str[i] == '\n') {
      str[i] = '\0';
      return;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strip_newline>:
  endbr64
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L20
L19:
  cmpb   $0xa,(%rdi)
  jne    L25
  movb   $0x0,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  ret
```

assistant: ```c
void strip_newline(char *str, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    if (str[i] == '\n') {
      str[i] = '\0';
      return;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Duplicate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <push@plt>
  nop
  leave
  ret
```

assistant: ```c
void Duplicate(void) {
  double temp = pop();
  push(temp);
  push(temp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Duplicate>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rbx
  call   <push@plt>
  movq   %rbx,%xmm0
  call   <push@plt>
  pop    %rbx
  ret
```

assistant: ```c
void Duplicate(void) {
  double temp = pop();
  push(temp);
  push(temp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Duplicate>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <pop@plt>
  movsd  %xmm0,0x8(%rsp)
  call   <push@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  jmp    1070 <push@plt>
```

assistant: ```c
void Duplicate(void) {
  double temp = pop();
  push(temp);
  push(temp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Duplicate>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <pop@plt>
  movsd  %xmm0,0x8(%rsp)
  call   <push@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  jmp    1070 <push@plt>
```

assistant: ```c
void Duplicate(void) {
  double temp = pop();
  push(temp);
  push(temp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  jmp    L1
```

assistant: ```c
void foo() {
  int l;
bad1:
#pragma acc parallel
  goto bad1;
#pragma acc kernels
  goto bad1;
#pragma acc data
  goto bad1;
#pragma acc loop
  for (l = 0; l < 2; ++l)
    goto bad1;
  goto bad2_parallel;
#pragma acc parallel
  {
  bad2_parallel:;
  }
  goto bad2_kernels;
#pragma acc kernels
  {
  bad2_kernels:;
  }
  goto bad2_data;
#pragma acc data
  {
  bad2_data:;
  }
  goto bad2_loop;
#pragma acc loop
  for (l = 0; l < 2; ++l) {
  bad2_loop:;
  }
#pragma acc parallel
  {
    int i;
    goto ok1_parallel;
    for (i = 0; i < 10; ++i) {
    ok1_parallel:
      break;
    }
  }
#pragma acc kernels
  {
    int i;
    goto ok1_kernels;
    for (i = 0; i < 10; ++i) {
    ok1_kernels:
      break;
    }
  }
#pragma acc data
  {
    int i;
    goto ok1_data;
    for (i = 0; i < 10; ++i) {
    ok1_data:
      break;
    }
  }
#pragma acc loop
  for (l = 0; l < 2; ++l) {
    int i;
    goto ok1_loop;
    for (i = 0; i < 10; ++i) {
    ok1_loop:
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
void foo() {
  int l;
bad1:
#pragma acc parallel
  goto bad1;
#pragma acc kernels
  goto bad1;
#pragma acc data
  goto bad1;
#pragma acc loop
  for (l = 0; l < 2; ++l)
    goto bad1;
  goto bad2_parallel;
#pragma acc parallel
  {
  bad2_parallel:;
  }
  goto bad2_kernels;
#pragma acc kernels
  {
  bad2_kernels:;
  }
  goto bad2_data;
#pragma acc data
  {
  bad2_data:;
  }
  goto bad2_loop;
#pragma acc loop
  for (l = 0; l < 2; ++l) {
  bad2_loop:;
  }
#pragma acc parallel
  {
    int i;
    goto ok1_parallel;
    for (i = 0; i < 10; ++i) {
    ok1_parallel:
      break;
    }
  }
#pragma acc kernels
  {
    int i;
    goto ok1_kernels;
    for (i = 0; i < 10; ++i) {
    ok1_kernels:
      break;
    }
  }
#pragma acc data
  {
    int i;
    goto ok1_data;
    for (i = 0; i < 10; ++i) {
    ok1_data:
      break;
    }
  }
#pragma acc loop
  for (l = 0; l < 2; ++l) {
    int i;
    goto ok1_loop;
    for (i = 0; i < 10; ++i) {
    ok1_loop:
      break;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
void foo() {
  int l;
bad1:
#pragma acc parallel
  goto bad1;
#pragma acc kernels
  goto bad1;
#pragma acc data
  goto bad1;
#pragma acc loop
  for (l = 0; l < 2; ++l)
    goto bad1;
  goto bad2_parallel;
#pragma acc parallel
  {
  bad2_parallel:;
  }
  goto bad2_kernels;
#pragma acc kernels
  {
  bad2_kernels:;
  }
  goto bad2_data;
#pragma acc data
  {
  bad2_data:;
  }
  goto bad2_loop;
#pragma acc loop
  for (l = 0; l < 2; ++l) {
  bad2_loop:;
  }
#pragma acc parallel
  {
    int i;
    goto ok1_parallel;
    for (i = 0; i < 10; ++i) {
    ok1_parallel:
      break;
    }
  }
#pragma acc kernels
  {
    int i;
    goto ok1_kernels;
    for (i = 0; i < 10; ++i) {
    ok1_kernels:
      break;
    }
  }
#pragma acc data
  {
    int i;
    goto ok1_data;
    for (i = 0; i < 10; ++i) {
    ok1_data:
      break;
    }
  }
#pragma acc loop
  for (l = 0; l < 2; ++l) {
    int i;
    goto ok1_loop;
    for (i = 0; i < 10; ++i) {
    ok1_loop:
      break;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
void foo() {
  int l;
bad1:
#pragma acc parallel
  goto bad1;
#pragma acc kernels
  goto bad1;
#pragma acc data
  goto bad1;
#pragma acc loop
  for (l = 0; l < 2; ++l)
    goto bad1;
  goto bad2_parallel;
#pragma acc parallel
  {
  bad2_parallel:;
  }
  goto bad2_kernels;
#pragma acc kernels
  {
  bad2_kernels:;
  }
  goto bad2_data;
#pragma acc data
  {
  bad2_data:;
  }
  goto bad2_loop;
#pragma acc loop
  for (l = 0; l < 2; ++l) {
  bad2_loop:;
  }
#pragma acc parallel
  {
    int i;
    goto ok1_parallel;
    for (i = 0; i < 10; ++i) {
    ok1_parallel:
      break;
    }
  }
#pragma acc kernels
  {
    int i;
    goto ok1_kernels;
    for (i = 0; i < 10; ++i) {
    ok1_kernels:
      break;
    }
  }
#pragma acc data
  {
    int i;
    goto ok1_data;
    for (i = 0; i < 10; ++i) {
    ok1_data:
      break;
    }
  }
#pragma acc loop
  for (l = 0; l < 2; ++l) {
    int i;
    goto ok1_loop;
    for (i = 0; i < 10; ++i) {
    ok1_loop:
      break;
    }
  }
}
```