ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<cgi_boolean>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <cgi_variable@plt>
  mov    %rax,%rdi
  mov    %ebx,%eax
  test   %rdi,%rdi
  je     L0
  lea    D4(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L0:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D4: 1

assistant: ```c
int cgi_boolean(char *name, int def) {
  char *p = cgi_variable(name);
  if (!p)
    return def;
  return strcmp(p, "1") == 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cgi_boolean>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <cgi_variable@plt>
  mov    %rax,%rdi
  mov    %ebx,%eax
  test   %rdi,%rdi
  je     L5
  lea    D3(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L5:
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D3: 1

assistant: ```c
int cgi_boolean(char *name, int def) {
  char *p = cgi_variable(name);
  if (!p)
    return def;
  return strcmp(p, "1") == 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cgi_boolean>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <cgi_variable@plt>
  mov    %rax,%rdi
  mov    %ebx,%eax
  test   %rdi,%rdi
  je     L7
  lea    D9(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L7:
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: 1

assistant: ```c
int cgi_boolean(char *name, int def) {
  char *p = cgi_variable(name);
  if (!p)
    return def;
  return strcmp(p, "1") == 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cleanup_charptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L4
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void cleanup_charptr(char **ptr) {
  if (*ptr)
    free(*ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cleanup_charptr>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
void cleanup_charptr(char **ptr) {
  if (*ptr)
    free(*ptr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cleanup_charptr>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L2
  jmp    1050 <free@plt>
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void cleanup_charptr(char **ptr) {
  if (*ptr)
    free(*ptr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cleanup_charptr>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  jmp    1050 <free@plt>
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void cleanup_charptr(char **ptr) {
  if (*ptr)
    free(*ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<local_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%esi
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <vlog_msgf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void local_log(int lf, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vlog_msgf(STDOUT_FILENO, lf, fmt, ap, 0);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below?

```asm
<local_log>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    $0x0,%r8d
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <vlog_msgf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void local_log(int lf, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vlog_msgf(STDOUT_FILENO, lf, fmt, ap, 0);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<local_log>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    D4(%rip),%rax
  xor    %r8d,%r8d
  mov    (%rax),%edi
  call   <vlog_msgf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void local_log(int lf, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vlog_msgf(STDOUT_FILENO, lf, fmt, ap, 0);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<local_log>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    D0(%rip),%rax
  xor    %r8d,%r8d
  mov    (%rax),%edi
  call   <vlog_msgf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void local_log(int lf, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vlog_msgf(STDOUT_FILENO, lf, fmt, ap, 0);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<be16enc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movzwl -0x1c(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzwl -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
extern void be16enc(void *buf, unsigned short u) {
  unsigned char *p = (unsigned char *)buf;
  p[0] = ((unsigned)u >> 8) & 0xff;
  p[1] = u & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<be16enc>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  mov    %dl,(%rdi)
  mov    %sil,0x1(%rdi)
  ret
```

assistant: ```c
extern void be16enc(void *buf, unsigned short u) {
  unsigned char *p = (unsigned char *)buf;
  p[0] = ((unsigned)u >> 8) & 0xff;
  p[1] = u & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<be16enc>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
extern void be16enc(void *buf, unsigned short u) {
  unsigned char *p = (unsigned char *)buf;
  p[0] = ((unsigned)u >> 8) & 0xff;
  p[1] = u & 0xff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<be16enc>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
extern void be16enc(void *buf, unsigned short u) {
  unsigned char *p = (unsigned char *)buf;
  p[0] = ((unsigned)u >> 8) & 0xff;
  p[1] = u & 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getFileStartAndLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %eax,-0x10(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0x10(%rbp)
  je     L19
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L35
L19:
  mov    $0xffffffff,%eax
  jmp    L7
L35:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  mov    $0xffffffff,%eax
  jmp    L7
L30:
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int getFileStartAndLength(int fd, int *start_, size_t *length_) {
  int start, end;
  size_t length;
  start = lseek(fd, 0L, SEEK_CUR);
  end = lseek(fd, 0L, SEEK_END);
  if (start == -1 || end == -1)
    return -1;
  length = end - start;
  if (length == 0)
    return -1;
  *start_ = start;
  *length_ = length;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<getFileStartAndLength>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <lseek@plt>
  mov    %eax,%ebx
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %r13d,%edi
  call   <lseek@plt>
  cmp    $0xffffffff,%ebx
  je     L14
  cmp    $0xffffffff,%eax
  je     L14
  sub    %ebx,%eax
  cltq
  test   %rax,%rax
  je     L46
  mov    %ebx,(%r12)
  mov    %rax,0x0(%rbp)
  mov    $0x0,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L6
L46:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int getFileStartAndLength(int fd, int *start_, size_t *length_) {
  int start, end;
  size_t length;
  start = lseek(fd, 0L, SEEK_CUR);
  end = lseek(fd, 0L, SEEK_END);
  if (start == -1 || end == -1)
    return -1;
  length = end - start;
  if (length == 0)
    return -1;
  *start_ = start;
  *length_ = length;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getFileStartAndLength>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  xor    %esi,%esi
  mov    %r13d,%edi
  mov    %eax,%r12d
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  cmp    $0xffffffff,%r12d
  je     L12
  cmp    $0xffffffff,%eax
  je     L12
  sub    %r12d,%eax
  cltq
  test   %rax,%rax
  je     L12
  mov    %r12d,0x0(%rbp)
  mov    %rax,(%rbx)
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int getFileStartAndLength(int fd, int *start_, size_t *length_) {
  int start, end;
  size_t length;
  start = lseek(fd, 0L, SEEK_CUR);
  end = lseek(fd, 0L, SEEK_END);
  if (start == -1 || end == -1)
    return -1;
  length = end - start;
  if (length == 0)
    return -1;
  *start_ = start;
  *length_ = length;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getFileStartAndLength>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  xor    %esi,%esi
  mov    %r13d,%edi
  mov    %eax,%r12d
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  cmp    $0xffffffff,%r12d
  je     L9
  cmp    $0xffffffff,%eax
  je     L9
  sub    %r12d,%eax
  cltq
  test   %rax,%rax
  je     L9
  mov    %r12d,0x0(%rbp)
  mov    %rax,(%rbx)
  xor    %eax,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  jmp    L23
```

assistant: ```c
int getFileStartAndLength(int fd, int *start_, size_t *length_) {
  int start, end;
  size_t length;
  start = lseek(fd, 0L, SEEK_CUR);
  end = lseek(fd, 0L, SEEK_END);
  if (start == -1 || end == -1)
    return -1;
  length = end - start;
  if (length == 0)
    return -1;
  *start_ = start;
  *length_ = length;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mat3_cmpV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L16:
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L44:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm1
  subsd  %xmm1,%xmm0
  movq   D9(%rip),%xmm1
  andpd  %xmm1,%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L20
  addl   $0x1,-0x4(%rbp)
L20:
  addl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0x2,-0x8(%rbp)
  jle    L44
  addl   $0x1,-0xc(%rbp)
L34:
  cmpl   $0x2,-0xc(%rbp)
  jle    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: qword

tool: D9: 9223372036854775807

assistant: ```c
int mat3_cmpV(double A[3][3], double B[3][3], double precision) {
  int c, r, ret;
  ret = 0;
  for (c = 0; c < 3; c++) {
    for (r = 0; r < 3; r++) {
      if (fabs(A[r][c] - B[r][c]) > precision) {
        ret = ret + 1;
      }
    }
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mat3_cmpV>:
  endbr64
  mov    %rdi,%rcx
  add    $0x18,%rdi
  mov    $0x0,%edx
  movq   D3(%rip),%xmm2
  jmp    L16
L11:
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %rdi,%rcx
  je     L2
L16:
  mov    $0x0,%eax
L22:
  movsd  (%rcx,%rax,1),%xmm1
  subsd  (%rsi,%rax,1),%xmm1
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  seta   %r8b
  movzbl %r8b,%r8d
  add    %r8d,%edx
  add    $0x18,%rax
  cmp    $0x48,%rax
  jne    L22
  jmp    L11
L2:
  mov    %edx,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D3
data_type: qword

tool: D3: 9223372036854775807

assistant: ```c
int mat3_cmpV(double A[3][3], double B[3][3], double precision) {
  int c, r, ret;
  ret = 0;
  for (c = 0; c < 3; c++) {
    for (r = 0; r < 3; r++) {
      if (fabs(A[r][c] - B[r][c]) > precision) {
        ret = ret + 1;
      }
    }
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat3_cmpV>:
  endbr64
  movq   D6(%rip),%xmm2
  lea    0x18(%rdi),%rcx
  xor    %r8d,%r8d
L15:
  xor    %eax,%eax
L12:
  movsd  (%rdi,%rax,1),%xmm1
  subsd  (%rsi,%rax,1),%xmm1
  xor    %edx,%edx
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  seta   %dl
  add    $0x18,%rax
  add    %edx,%r8d
  cmp    $0x48,%rax
  jne    L12
  add    $0x8,%rdi
  add    $0x8,%rsi
  cmp    %rcx,%rdi
  jne    L15
  mov    %r8d,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: qword

tool: D6: 9223372036854775807

assistant: ```c
int mat3_cmpV(double A[3][3], double B[3][3], double precision) {
  int c, r, ret;
  ret = 0;
  for (c = 0; c < 3; c++) {
    for (r = 0; r < 3; r++) {
      if (fabs(A[r][c] - B[r][c]) > precision) {
        ret = ret + 1;
      }
    }
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mat3_cmpV>:
  endbr64
  movsd  (%rdi),%xmm1
  subsd  (%rsi),%xmm1
  xor    %eax,%eax
  mov    %rsi,%rdx
  movapd %xmm1,%xmm2
  movq   D6(%rip),%xmm1
  andpd  %xmm1,%xmm2
  comisd %xmm0,%xmm2
  movsd  0x18(%rdi),%xmm2
  subsd  0x18(%rsi),%xmm2
  andpd  %xmm1,%xmm2
  seta   %al
  xor    %esi,%esi
  comisd %xmm0,%xmm2
  movsd  0x30(%rdi),%xmm2
  subsd  0x30(%rdx),%xmm2
  seta   %sil
  andpd  %xmm1,%xmm2
  add    %esi,%eax
  xor    %esi,%esi
  comisd %xmm0,%xmm2
  movsd  0x8(%rdi),%xmm2
  subsd  0x8(%rdx),%xmm2
  seta   %sil
  andpd  %xmm1,%xmm2
  add    %esi,%eax
  xor    %esi,%esi
  comisd %xmm0,%xmm2
  movsd  0x20(%rdi),%xmm2
  subsd  0x20(%rdx),%xmm2
  seta   %sil
  andpd  %xmm1,%xmm2
  add    %esi,%eax
  xor    %esi,%esi
  comisd %xmm0,%xmm2
  movsd  0x38(%rdi),%xmm2
  subsd  0x38(%rdx),%xmm2
  seta   %sil
  andpd  %xmm1,%xmm2
  add    %esi,%eax
  xor    %esi,%esi
  comisd %xmm0,%xmm2
  movsd  0x10(%rdi),%xmm2
  subsd  0x10(%rdx),%xmm2
  seta   %sil
  andpd  %xmm1,%xmm2
  add    %esi,%eax
  xor    %esi,%esi
  comisd %xmm0,%xmm2
  movsd  0x28(%rdi),%xmm2
  subsd  0x28(%rdx),%xmm2
  seta   %sil
  andpd  %xmm1,%xmm2
  add    %esi,%eax
  xor    %esi,%esi
  comisd %xmm0,%xmm2
  movsd  0x40(%rdi),%xmm2
  subsd  0x40(%rdx),%xmm2
  seta   %sil
  andpd  %xmm2,%xmm1
  xor    %edx,%edx
  add    %esi,%eax
  comisd %xmm0,%xmm1
  seta   %dl
  add    %edx,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: qword

tool: D6: 9223372036854775807

assistant: ```c
int mat3_cmpV(double A[3][3], double B[3][3], double precision) {
  int c, r, ret;
  ret = 0;
  for (c = 0; c < 3; c++) {
    for (r = 0; r < 3; r++) {
      if (fabs(A[r][c] - B[r][c]) > precision) {
        ret = ret + 1;
      }
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %ecx,-0x40(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rdi
  mov    -0x34(%rbp),%eax
  mov    %eax,%edx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %eax,%edx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  mov    %eax,%edx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L14:
  cmp    %rdx,%rsp
  je     L94
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L14
L94:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L31
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L31:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x1,-0x3c(%rbp)
  jmp    L46
L40:
  mov    -0x20(%rbp),%rax
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,-0x44(%rbp)
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x38(%rbp)
  jmp    L96
L78:
  cmpl   $0x1,-0x38(%rbp)
  jg     L77
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x20(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%ecx
  mov    -0x20(%rbp),%rax
  movslq %esi,%rdx
  mov    %ecx,(%rax,%rdx,4)
L77:
  subl   $0x1,-0x38(%rbp)
L96:
  cmpl   $0x0,-0x38(%rbp)
  js     L99
  mov    -0x20(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  cmp    %eax,-0x44(%rbp)
  jl     L78
L99:
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    -0x44(%rbp),%ecx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x3c(%rbp)
L46:
  mov    -0x3c(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  ja     L40
  mov    $0x0,%eax
  mov    %rdi,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  lea    -0x10(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int main_test(unsigned int SIZE, int i, int j, int k, int key) {
  int v[SIZE];
  for (j = 1; j < SIZE; j++) {
    key = v[j];
    i = j - 1;
    while ((i >= 0) && (v[i] > key)) {
      if (i < 2)
        v[i + 1] = v[i];
      i = i - 1;
    }
    v[i + 1] = key;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    %edi,%eax
  lea    0xf(,%rax,4),%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L12:
  cmp    %rdx,%rsp
  je     L51
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L12
L51:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L128
  orq    $0x0,-0x8(%rsp,%rdx,1)
L128:
  mov    %rsp,%r10
  cmp    $0x1,%edi
  jbe    L103
  lea    0x4(%r10),%r9
  lea    -0x1(%rdi),%r11d
  mov    $0x0,%r8d
  jmp    L55
L44:
  sub    $0x1,%eax
  sub    $0x4,%rdx
  cmp    $0xffffffff,%eax
  je     L117
L25:
  mov    -0x4(%rdx),%ecx
  cmp    %esi,%ecx
  jle    L117
  cmp    $0x1,%eax
  jg     L44
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  mov    %ecx,(%r10,%rdi,4)
  jmp    L44
L117:
  add    $0x1,%eax
  cltq
  mov    %esi,(%r10,%rax,4)
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r11,%r8
  je     L103
L55:
  mov    (%r9),%esi
  mov    %r8d,%eax
  mov    %r9,%rdx
  test   %r8d,%r8d
  jns    L25
  jmp    L117
L103:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    $0x0,%eax
  leave
  ret
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main_test(unsigned int SIZE, int i, int j, int k, int key) {
  int v[SIZE];
  for (j = 1; j < SIZE; j++) {
    key = v[j];
    i = j - 1;
    while ((i >= 0) && (v[i] > key)) {
      if (i < 2)
        v[i + 1] = v[i];
      i = i - 1;
    }
    v[i + 1] = key;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main_test>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main_test(unsigned int SIZE, int i, int j, int k, int key) {
  int v[SIZE];
  for (j = 1; j < SIZE; j++) {
    key = v[j];
    i = j - 1;
    while ((i >= 0) && (v[i] > key)) {
      if (i < 2)
        v[i + 1] = v[i];
      i = i - 1;
    }
    v[i + 1] = key;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main_test>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main_test(unsigned int SIZE, int i, int j, int k, int key) {
  int v[SIZE];
  for (j = 1; j < SIZE; j++) {
    key = v[j];
    i = j - 1;
    while ((i >= 0) && (v[i] > key)) {
      if (i < 2)
        v[i + 1] = v[i];
      i = i - 1;
    }
    v[i + 1] = key;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitIsSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L7
  mov    $0x1,%eax
  jmp    L12
L7:
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
_Bool bitIsSet(const int flags, const int bitI) {
  if (flags & (1 << bitI))
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitIsSet>:
  endbr64
  mov    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
_Bool bitIsSet(const int flags, const int bitI) {
  if (flags & (1 << bitI))
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitIsSet>:
  endbr64
  mov    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
_Bool bitIsSet(const int flags, const int bitI) {
  if (flags & (1 << bitI))
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitIsSet>:
  endbr64
  mov    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
_Bool bitIsSet(const int flags, const int bitI) {
  if (flags & (1 << bitI))
    return 1;
  else
    return 0;
}
```