user: 这段汇编代码用C语言表示是什么样的:

```asm
<getcpuload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x38(%rbp)
  jmp    L7
L24:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x75(%rbp)
L7:
  cmpb   $0xa,-0x75(%rbp)
  jne    L24
  movl   $0x0,-0x74(%rbp)
  jmp    L37
L29:
  movb   $0x0,-0x75(%rbp)
  lea    -0x58(%rbp),%r8
  lea    -0x60(%rbp),%rdi
  lea    -0x68(%rbp),%rcx
  lea    -0x70(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x40(%rbp),%rsi
  push   %rsi
  lea    -0x48(%rbp),%rsi
  push   %rsi
  lea    -0x50(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  lea    D47(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  add    $0x20,%rsp
  jmp    L41
L57:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x75(%rbp)
L41:
  cmpb   $0xa,-0x75(%rbp)
  jne    L57
  mov    -0x70(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  add    %rax,%rdx
  mov    -0x60(%rbp),%rax
  add    %rax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x74(%rbp),%eax
  cltq
  mov    %rdx,-0x30(%rbp,%rax,8)
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x74(%rbp),%eax
  cltq
  mov    %rdx,-0x20(%rbp,%rax,8)
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    -0x74(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  lea    D52(%rip),%rdx
  mov    (%rcx,%rdx,1),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rsi
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  mov    -0x74(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  lea    D43(%rip),%rdx
  mov    (%rcx,%rdx,1),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdi
  mov    %rsi,%rax
  cqto
  idiv   %rdi
  mov    %eax,%ecx
  mov    -0x74(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D85(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    -0x74(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  lea    D52(%rip),%rdx
  mov    %rax,(%rcx,%rdx,1)
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  mov    -0x74(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  lea    D43(%rip),%rdx
  mov    %rax,(%rcx,%rdx,1)
  addl   $0x1,-0x74(%rbp)
L37:
  cmpl   $0x1,-0x74(%rbp)
  jle    L29
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D85(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string
name: unpack_data
arguments: data_label: D47
type_infered: string

tool: D12: r

tool: D5: /proc/stat

tool: D47: cpu%*d %ld %ld %ld %ld %ld %ld %ld

assistant: ```c
int *getcpuload() {
  FILE *fd;
  static long cpu_work[2], cpu_total[2];
  long jif1, jif2, jif3, jif4, jif5, jif6, jif7;
  long work[2], total[2];
  static int load[2];
  fd = fopen("/proc/stat", "r");
  char c;
  while (c != '\n')
    c = fgetc(fd);
  for (int i = 0; i < 2; i++) {
    c = 0;
    fscanf(fd, "cpu%*d %ld %ld %ld %ld %ld %ld %ld", &jif1, &jif2, &jif3, &jif4, &jif5, &jif6, &jif7);
    while (c != '\n')
      c = fgetc(fd);
    work[i] = jif1 + jif2 + jif3 + jif6 + jif7;
    total[i] = work[i] + jif4 + jif5;
    load[i] = 100 * (work[i] - cpu_work[i]) / (total[i] - cpu_total[i]);
    cpu_work[i] = work[i];
    cpu_total[i] = total[i];
  }
  fclose(fd);
  return load;
}
```