user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x2,%edi
  jle    L173
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %eax,%r13d
  call   <strtol@plt>
  mov    %eax,0xc(%rsp)
  cmp    %eax,%r13d
  jge    L94
  cmp    $0x1,%r13d
  jg     L134
  lea    -0x1(%rax),%esi
  mov    $0x1,%eax
  mov    $0x1,%edx
  test   %esi,%esi
  cmovg  %eax,%esi
  mov    %esi,%eax
  sub    %r13d,%eax
  cmp    %esi,%r13d
  lea    0x1(%rax),%edi
  cmovg  %edx,%edi
  jg     L97
  cmp    $0x2,%eax
  jbe    L97
  movd   %r13d,%xmm4
  mov    %edi,%edx
  xor    %eax,%eax
  movdqa D47(%rip),%xmm3
  pshufd $0x0,%xmm4,%xmm1
  movdqa D5(%rip),%xmm2
  paddd  D26(%rip),%xmm1
  shr    $0x2,%edx
L191:
  movdqa %xmm1,%xmm0
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L191
  mov    %edi,%r8d
  pshufd $0xff,%xmm0,%xmm0
  and    $0xfffffffc,%r8d
  lea    (%r8,%r13,1),%edx
  cmp    %r8d,%edi
  je     L71
L157:
  lea    0x1(%rdx),%r13d
  cmp    %esi,%r13d
  jg     L3
  lea    0x2(%rdx),%r13d
  cmp    %r13d,%esi
  jl     L3
  lea    0x3(%rdx),%r13d
L3:
  cmp    %r13d,0xc(%rsp)
  jle    L94
L134:
  lea    D0(%rip),%r12
L39:
  mov    %r13d,%r15d
  imul   %r13d,%r15d
  cmp    $0x2,%r13d
  jle    L23
  mov    $0x2,%ebp
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %ebp,%r14d
  mov    $0x1,%ebx
  imul   %ebp,%r14d
  jmp    L131
  cs nopw 0x0(%rax,%rax,1)
L104:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L119
L131:
  mov    %ebx,%eax
  imul   %ebx,%eax
  add    %r14d,%eax
  cmp    %eax,%r15d
  jne    L104
  mov    %ebx,%esi
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L131
L119:
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L44
L23:
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  jg     L39
L94:
  xor    %eax,%eax
L67:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L173:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L67
L71:
  movd   %xmm0,%r13d
  jmp    L3
L97:
  mov    %r13d,%edx
  jmp    L157
```

tool_calls: name: unpack_data
arguments: data_tag: D47
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D5
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D26
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string

tool: {"D47": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D5": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D0: %d %d %d


tool: D23: usage : pythagoras min_n max_n

assistant: ```c
int main(int ac, char *av[]) {
  int a, b, c, aa, bb, cc, min_n, max_n;
  if (ac < 3) {
    printf("usage : pythagoras min_n max_n\n");
    return (1);
  }
  min_n = strtol(av[1], NULL, 10);
  max_n = strtol(av[2], NULL, 10);
  for (c = min_n; c < max_n; c++) {
    cc = c * c;
    for (b = 1; b < c; b++) {
      bb = b * b;
      for (a = 1; a < b; a++) {
        aa = a * a;
        if (aa + bb == cc)
          printf("%d %d %d\n", a, b, c);
      }
    }
  }
  return (0);
}
```