ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parity>:
  endbr64
  mov    %edi,%edx
  sar    $0x10,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  xor    %edx,%eax
  mov    %eax,%ecx
  sar    $0x4,%ecx
  xor    %eax,%ecx
  and    $0xf,%ecx
  mov    $0x6996,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int parity(uint32_t x) {
  x ^= x >> 16;
  x ^= x >> 8;
  x ^= x >> 4;
  return ((0x6996) >> (x & 0xf) & 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parity>:
  endbr64
  mov    %edi,%edx
  sar    $0x10,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  xor    %edx,%eax
  mov    %eax,%ecx
  sar    $0x4,%ecx
  xor    %eax,%ecx
  mov    $0x6996,%eax
  and    $0xf,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int parity(uint32_t x) {
  x ^= x >> 16;
  x ^= x >> 8;
  x ^= x >> 4;
  return ((0x6996) >> (x & 0xf) & 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<parity>:
  endbr64
  mov    %edi,%edx
  sar    $0x10,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  xor    %edx,%eax
  mov    %eax,%ecx
  sar    $0x4,%ecx
  xor    %eax,%ecx
  mov    $0x6996,%eax
  and    $0xf,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int parity(uint32_t x) {
  x ^= x >> 16;
  x ^= x >> 8;
  x ^= x >> 4;
  return ((0x6996) >> (x & 0xf) & 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D4: P2P Food Lab Sensorbox
  update
  Version %d.%d.%d


assistant: ```c
void print_version(FILE *fp) {
  fprintf(fp,
          "P2P Food Lab Sensorbox\n"
          "  update\n"
          "  Version %d.%d.%d\n",
          1, 0, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_version>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  lea    D0(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: P2P Food Lab Sensorbox
  update
  Version %d.%d.%d


assistant: ```c
void print_version(FILE *fp) {
  fprintf(fp,
          "P2P Food Lab Sensorbox\n"
          "  update\n"
          "  Version %d.%d.%d\n",
          1, 0, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<print_version>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  lea    D7(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type: string

tool: D7: P2P Food Lab Sensorbox
  update
  Version %d.%d.%d


assistant: ```c
void print_version(FILE *fp) {
  fprintf(fp,
          "P2P Food Lab Sensorbox\n"
          "  update\n"
          "  Version %d.%d.%d\n",
          1, 0, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<print_version>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  lea    D1(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: P2P Food Lab Sensorbox
  update
  Version %d.%d.%d


assistant: ```c
void print_version(FILE *fp) {
  fprintf(fp,
          "P2P Food Lab Sensorbox\n"
          "  update\n"
          "  Version %d.%d.%d\n",
          1, 0, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_F90_FCD_CMP_LT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %ecx,-0x48(%rbp)
  mov    -0x44(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L31
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x48(%rbp),%eax
  sub    -0x44(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L17
L31:
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x44(%rbp),%eax
  sub    -0x48(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L17:
  mov    -0x24(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  mov    %eax,-0x20(%rbp)
  jmp    L69
L61:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%ebx
  addq   $0x1,-0x18(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L57
  movsbl %bl,%edx
  mov    $0x20,%eax
  sub    %edx,%eax
  jmp    L5
L57:
  movsbl %bl,%eax
  sub    $0x20,%eax
L5:
  mov    %eax,-0x20(%rbp)
  subl   $0x1,-0x28(%rbp)
L69:
  cmpl   $0x0,-0x28(%rbp)
  je     L43
  cmpl   $0x0,-0x20(%rbp)
  je     L61
L43:
  mov    -0x20(%rbp),%eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int _F90_FCD_CMP_LT(char *str1, char *str2, int len1, int len2) {
  char *str3;
  unsigned int len3, len;
  int sign, stat;
  sign = (len1 < len2);
  if (sign) {
    len = len1;
    len3 = len2 - len1;
    str3 = str2 + len;
  } else {
    len = len2;
    len3 = len1 - len2;
    str3 = str1 + len;
  }
  stat = memcmp(str1, str2, len);
  while (len3 > 0 && stat == 0) {
    register char ch;
    ch = *str3;
    str3 = str3 + 1;
    stat = sign ? ((int)' ') - (int)ch : ((int)ch) - ((int)' ');
    len3 = len3 - 1;
  }
  return (stat < 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_F90_FCD_CMP_LT>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  mov    %ecx,%ebp
  cmp    %ecx,%edx
  jge    L74
  mov    %ecx,%r12d
  sub    %edx,%r12d
  mov    %edx,%r13d
  add    %rsi,%r13
L80:
  call   <memcmp@plt>
  test   %r12d,%r12d
  je     L78
  test   %eax,%eax
  jne    L78
  mov    %r13,%rdx
  mov    $0x20,%esi
  add    %r13d,%r12d
  jmp    L86
L74:
  mov    %ecx,%edx
  mov    %ebx,%r12d
  sub    %ecx,%r12d
  mov    %ecx,%r13d
  add    %rdi,%r13
  jmp    L80
L63:
  movsbl %al,%eax
  sub    $0x20,%eax
L9:
  cmp    %edx,%r12d
  je     L78
  test   %eax,%eax
  jne    L78
L86:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  cmp    %ebp,%ebx
  jge    L63
  movsbl %al,%ecx
  mov    %esi,%eax
  sub    %ecx,%eax
  jmp    L9
L78:
  shr    $0x1f,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _F90_FCD_CMP_LT(char *str1, char *str2, int len1, int len2) {
  char *str3;
  unsigned int len3, len;
  int sign, stat;
  sign = (len1 < len2);
  if (sign) {
    len = len1;
    len3 = len2 - len1;
    str3 = str2 + len;
  } else {
    len = len2;
    len3 = len1 - len2;
    str3 = str1 + len;
  }
  stat = memcmp(str1, str2, len);
  while (len3 > 0 && stat == 0) {
    register char ch;
    ch = *str3;
    str3 = str3 + 1;
    stat = sign ? ((int)' ') - (int)ch : ((int)ch) - ((int)' ');
    len3 = len3 - 1;
  }
  return (stat < 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_F90_FCD_CMP_LT>:
  endbr64
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%edx
  jge    L54
  mov    %ecx,%r13d
  mov    %edx,%ebx
  sub    %edx,%r13d
  add    %rsi,%rbx
L18:
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L28
  test   %r13d,%r13d
  je     L28
  mov    %rbx,%rdx
  lea    0x0(%r13,%rbx,1),%edi
  mov    $0x20,%esi
  nopl   (%rax)
L38:
  movsbl (%rdx),%eax
  mov    %esi,%ecx
  add    $0x1,%rdx
  sub    %eax,%ecx
  sub    $0x20,%eax
  cmp    %r12d,%ebp
  cmovl  %ecx,%eax
  cmp    %edx,%edi
  je     L28
  test   %eax,%eax
  je     L38
L28:
  add    $0x8,%rsp
  shr    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %ebp,%r13d
  mov    %ecx,%ebx
  mov    %ecx,%edx
  sub    %ecx,%r13d
  add    %rdi,%rbx
  jmp    L18
```

assistant: ```c
int _F90_FCD_CMP_LT(char *str1, char *str2, int len1, int len2) {
  char *str3;
  unsigned int len3, len;
  int sign, stat;
  sign = (len1 < len2);
  if (sign) {
    len = len1;
    len3 = len2 - len1;
    str3 = str2 + len;
  } else {
    len = len2;
    len3 = len1 - len2;
    str3 = str1 + len;
  }
  stat = memcmp(str1, str2, len);
  while (len3 > 0 && stat == 0) {
    register char ch;
    ch = *str3;
    str3 = str3 + 1;
    stat = sign ? ((int)' ') - (int)ch : ((int)ch) - ((int)' ');
    len3 = len3 - 1;
  }
  return (stat < 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_F90_FCD_CMP_LT>:
  endbr64
  push   %rbp
  mov    %ecx,%r8d
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%edx
  jge    L64
  sub    %edx,%r8d
  mov    %edx,%ebx
  add    %rsi,%rbx
  mov    %r8d,%ebp
  call   <memcmp@plt>
  mov    %rbx,%rsi
  lea    0x0(%rbp,%rbx,1),%edi
  mov    $0x20,%ecx
  test   %eax,%eax
  jne    L61
  nopl   0x0(%rax)
L7:
  movsbl (%rsi),%edx
  mov    %ecx,%eax
  add    $0x1,%rsi
  sub    %edx,%eax
  cmp    %esi,%edi
  je     L61
  test   %eax,%eax
  je     L7
L61:
  add    $0x8,%rsp
  shr    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L64:
  sub    %ecx,%edx
  mov    %ecx,%ecx
  mov    %edx,%ebp
  mov    %r8d,%edx
  lea    (%rdi,%rcx,1),%rbx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L61
  test   %ebp,%ebp
  je     L61
  mov    %rbx,%rcx
  lea    0x0(%rbp,%rbx,1),%edx
  nopl   0x0(%rax)
L33:
  movsbl (%rcx),%eax
  add    $0x1,%rcx
  sub    $0x20,%eax
  cmp    %ecx,%edx
  je     L61
  test   %eax,%eax
  je     L33
  add    $0x8,%rsp
  shr    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _F90_FCD_CMP_LT(char *str1, char *str2, int len1, int len2) {
  char *str3;
  unsigned int len3, len;
  int sign, stat;
  sign = (len1 < len2);
  if (sign) {
    len = len1;
    len3 = len2 - len1;
    str3 = str2 + len;
  } else {
    len = len2;
    len3 = len1 - len2;
    str3 = str1 + len;
  }
  stat = memcmp(str1, str2, len);
  while (len3 > 0 && stat == 0) {
    register char ch;
    ch = *str3;
    str3 = str3 + 1;
    stat = sign ? ((int)' ') - (int)ch : ((int)ch) - ((int)' ');
    len3 = len3 - 1;
  }
  return (stat < 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L33
  cmpl   $0x5,-0x14(%rbp)
  jg     L33
  cmpl   $0x9,-0x18(%rbp)
  jle    L33
  cmpl   $0x29,-0x18(%rbp)
  jg     L33
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L9
L33:
  mov    $0x1,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int test1(int i, int k) {
  if (i > 0 && i <= 5 && k >= 10 && k < 42) {
    int j = i + 1 + k;
    return j == 10;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<test1>:
  endbr64
  sub    $0x1,%edi
  mov    $0x1,%eax
  cmp    $0x4,%edi
  ja     L7
  sub    $0xa,%esi
  cmp    $0x1f,%esi
  seta   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int test1(int i, int k) {
  if (i > 0 && i <= 5 && k >= 10 && k < 42) {
    int j = i + 1 + k;
    return j == 10;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test1>:
  endbr64
  sub    $0x1,%edi
  mov    $0x1,%eax
  cmp    $0x4,%edi
  ja     L8
  sub    $0xa,%esi
  xor    %eax,%eax
  cmp    $0x1f,%esi
  seta   %al
L8:
  ret
```

assistant: ```c
int test1(int i, int k) {
  if (i > 0 && i <= 5 && k >= 10 && k < 42) {
    int j = i + 1 + k;
    return j == 10;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test1>:
  endbr64
  sub    $0x1,%edi
  mov    $0x1,%eax
  cmp    $0x4,%edi
  ja     L0
  sub    $0xa,%esi
  xor    %eax,%eax
  cmp    $0x1f,%esi
  seta   %al
L0:
  ret
```

assistant: ```c
int test1(int i, int k) {
  if (i > 0 && i <= 5 && k >= 10 && k < 42) {
    int j = i + 1 + k;
    return j == 10;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jambu_initialization>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <AESEncrypt@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  xor    $0x5,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void jambu_initialization(const unsigned int *rk, const uint8_t *iv, unsigned int *stateS, unsigned int *stateR) {
  stateS[0] = ((unsigned int *)iv)[0];
  stateS[1] = ((unsigned int *)iv)[1];
  AESEncrypt(rk, stateS);
  stateS[0] ^= 0x5;
  stateR[0] = stateS[2];
  stateR[1] = stateS[3];
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<jambu_initialization>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    (%rsi),%eax
  mov    %eax,(%rdx)
  mov    0x4(%rsi),%eax
  mov    %eax,0x4(%rdx)
  mov    %rdx,%rsi
  call   <AESEncrypt@plt>
  xorl   $0x5,(%rbx)
  mov    0x8(%rbx),%eax
  mov    %eax,0x0(%rbp)
  mov    0xc(%rbx),%eax
  mov    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void jambu_initialization(const unsigned int *rk, const uint8_t *iv, unsigned int *stateS, unsigned int *stateR) {
  stateS[0] = ((unsigned int *)iv)[0];
  stateS[1] = ((unsigned int *)iv)[1];
  AESEncrypt(rk, stateS);
  stateS[0] ^= 0x5;
  stateR[0] = stateS[2];
  stateR[1] = stateS[3];
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jambu_initialization>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%eax
  mov    %eax,(%rdx)
  mov    0x4(%rsi),%eax
  mov    %rdx,%rsi
  mov    %eax,0x4(%rdx)
  call   <AESEncrypt@plt>
  mov    0x8(%rbx),%eax
  xorl   $0x5,(%rbx)
  mov    %eax,0x0(%rbp)
  mov    0xc(%rbx),%eax
  mov    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void jambu_initialization(const unsigned int *rk, const uint8_t *iv, unsigned int *stateS, unsigned int *stateR) {
  stateS[0] = ((unsigned int *)iv)[0];
  stateS[1] = ((unsigned int *)iv)[1];
  AESEncrypt(rk, stateS);
  stateS[0] ^= 0x5;
  stateR[0] = stateS[2];
  stateR[1] = stateS[3];
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L0:
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x4,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jb     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f1(double *p, double *q, unsigned int n) {
  p = (double *)__builtin_assume_aligned(p, sizeof(double) * 2);
  q = (double *)__builtin_assume_aligned(q, sizeof(double) * 2);
  for (unsigned int i = 0; i < n; i += 4) {
    double a = q[i] + p[i];
    double b = q[i + 1] + p[i + 1];
    q[i] = a;
    q[i + 1] = b;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f1>:
  endbr64
  test   %edx,%edx
  je     L13
  mov    $0x0,%eax
L2:
  mov    %eax,%r9d
  lea    (%rsi,%r9,8),%r8
  lea    0x1(%rax),%r10d
  lea    (%rsi,%r10,8),%rcx
  movsd  (%rdi,%r10,8),%xmm0
  addsd  (%rcx),%xmm0
  movsd  (%r8),%xmm1
  addsd  (%rdi,%r9,8),%xmm1
  movsd  %xmm1,(%r8)
  movsd  %xmm0,(%rcx)
  add    $0x4,%eax
  cmp    %eax,%edx
  ja     L2
L13:
  ret
```

assistant: ```c
void f1(double *p, double *q, unsigned int n) {
  p = (double *)__builtin_assume_aligned(p, sizeof(double) * 2);
  q = (double *)__builtin_assume_aligned(q, sizeof(double) * 2);
  for (unsigned int i = 0; i < n; i += 4) {
    double a = q[i] + p[i];
    double b = q[i + 1] + p[i + 1];
    q[i] = a;
    q[i + 1] = b;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f1>:
  endbr64
  test   %edx,%edx
  je     L2
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %eax,%r9d
  lea    0x1(%rax),%r10d
  add    $0x4,%eax
  lea    (%rsi,%r9,8),%r8
  lea    (%rsi,%r10,8),%rcx
  movsd  (%rdi,%r10,8),%xmm0
  movsd  (%r8),%xmm1
  addsd  (%rcx),%xmm0
  addsd  (%rdi,%r9,8),%xmm1
  movsd  %xmm1,(%r8)
  movsd  %xmm0,(%rcx)
  cmp    %eax,%edx
  ja     L6
L2:
  ret
```

assistant: ```c
void f1(double *p, double *q, unsigned int n) {
  p = (double *)__builtin_assume_aligned(p, sizeof(double) * 2);
  q = (double *)__builtin_assume_aligned(q, sizeof(double) * 2);
  for (unsigned int i = 0; i < n; i += 4) {
    double a = q[i] + p[i];
    double b = q[i + 1] + p[i + 1];
    q[i] = a;
    q[i + 1] = b;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f1>:
  endbr64
  test   %edx,%edx
  je     L15
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %eax,%r8d
  add    $0x4,%eax
  lea    (%rsi,%r8,8),%rcx
  movapd (%rcx),%xmm0
  addpd  (%rdi,%r8,8),%xmm0
  movaps %xmm0,(%rcx)
  cmp    %eax,%edx
  ja     L13
L15:
  ret
```

assistant: ```c
void f1(double *p, double *q, unsigned int n) {
  p = (double *)__builtin_assume_aligned(p, sizeof(double) * 2);
  q = (double *)__builtin_assume_aligned(q, sizeof(double) * 2);
  for (unsigned int i = 0; i < n; i += 4) {
    double a = q[i] + p[i];
    double b = q[i + 1] + p[i + 1];
    q[i] = a;
    q[i + 1] = b;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L24:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L24
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,-0xc(%rbp)
  cmpl   $0x7,-0xc(%rbp)
  jg     L36
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L22
L36:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string

tool: D0: %d

tool: D8: light 


tool: D5: heavy 


assistant: ```c
int main() {
  int n, i = 0, avg = 0;
  scanf("%d", &n);
  do {
    avg += n % 10;
    n /= 10;
    i++;
  } while (n != 0);
  avg /= i;
  if (avg <= 7)
    printf("light \n");
  else
    printf("heavy \n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x0,%eax
  mov    $0x0,%edi
L7:
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    %ecx,%eax
  mov    %edx,%ecx
  add    $0x1,%edi
  test   %edx,%edx
  jne    L7
  movl   $0x0,0x4(%rsp)
  cltd
  idiv   %edi
  cmp    $0x7,%eax
  jg     L13
  lea    D19(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L13:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D15: %d

tool: D19: light 


tool: D5: heavy 


assistant: ```c
int main() {
  int n, i = 0, avg = 0;
  scanf("%d", &n);
  do {
    avg += n % 10;
    n /= 10;
    i++;
  } while (n != 0);
  avg /= i;
  if (avg <= 7)
    printf("light \n");
  else
    printf("heavy \n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  xor    %eax,%eax
  xor    %edi,%edi
  nopl   0x0(%rax)
L32:
  movslq %ecx,%rdx
  mov    %ecx,%esi
  add    $0x1,%edi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    %ecx,%eax
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L32
  cltd
  movl   $0x0,0x4(%rsp)
  idiv   %edi
  cmp    $0x7,%eax
  jg     L12
  lea    D12(%rip),%rdi
  call   <printf@plt>
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D2
type: string

tool: D4: %d

tool: D12: light 


tool: D2: heavy 


assistant: ```c
int main() {
  int n, i = 0, avg = 0;
  scanf("%d", &n);
  do {
    avg += n % 10;
    n /= 10;
    i++;
  } while (n != 0);
  avg /= i;
  if (avg <= 7)
    printf("light \n");
  else
    printf("heavy \n");
}
```