ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rle_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    D9(%rip),%r14
  cmp    %eax,(%r14)
  je     L62
  movzbl %al,%edi
  mov    %r12,%rsi
  mov    %eax,%ebp
  call   <putc@plt>
  mov    %r13,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r14)
  je     L62
  nopl   (%rax)
L45:
  cmp    %ebx,%ebp
  je     L65
  movzbl %bl,%edi
  mov    %r12,%rsi
  call   <putc@plt>
L69:
  mov    %ebx,%ebp
L39:
  mov    %r13,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r14)
  jne    L45
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  movzbl %bl,%r15d
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <putc@plt>
  mov    %r13,%rdi
  call   <getc@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  je     L62
  test   %eax,%eax
  je     L69
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <putc@plt>
  sub    $0x1,%ebp
  jne    L8
  mov    %ebx,%ebp
  jmp    L39
```

assistant: ```c
void rle_decode(FILE *in, FILE *out) {
  int c, prev, rle_cnt;
  if ((c = getc(in)) != EOF) {
    prev = c;
    putc((unsigned char)c, out);
  } else
    return;
  while ((c = getc(in)) != EOF) {
    if (c == prev) {
      putc((unsigned char)prev, out);
      if ((rle_cnt = getc(in)) != EOF) {
        while (rle_cnt--) {
          putc((unsigned char)prev, out);
        }
      } else
        break;
    } else {
      putc((unsigned char)c, out);
      prev = c;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strrpl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  jmp    L11
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rax
  movzbl -0x10(%rbp),%edx
  mov    %dl,(%rax)
L26:
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_strrpl(char *s, char c, char c2) {
  while (*s) {
    if (*s == c)
      *s = c2;
    s++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strrpl>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L5
L18:
  ret
L15:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
L5:
  cmp    %al,%sil
  jne    L15
  mov    %dl,(%rdi)
  jmp    L15
```

assistant: ```c
void ft_strrpl(char *s, char c, char c2) {
  while (*s) {
    if (*s == c)
      *s = c2;
    s++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_strrpl>:
  endbr64
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L2:
  cmp    %al,%sil
  jne    L9
  mov    %dl,(%rdi)
L9:
  add    $0x1,%rdi
L10:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
  ret
```

assistant: ```c
void ft_strrpl(char *s, char c, char c2) {
  while (*s) {
    if (*s == c)
      *s = c2;
    s++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strrpl>:
  endbr64
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x1,%rdi
L38:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
L28:
  cmp    %al,%sil
  jne    L6
  mov    %dl,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L28
  ret
  nop
L31:
  ret
```

assistant: ```c
void ft_strrpl(char *s, char c, char c2) {
  while (*s) {
    if (*s == c)
      *s = c2;
    s++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<branchless>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
L7:
  mov    -0x18(%rbp),%eax
  neg    %eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x14(%rbp),%eax
  shl    $0x1f,%eax
  sar    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    -0x8(%rbp),%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  and    %eax,-0x18(%rbp)
  sarl   -0x14(%rbp)
  jmp    L7
L17:
  nop
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t branchless(uint32_t src, uint32_t mask) {
  uint32_t result = 0;
  while (1) {
    const uint32_t lowest = -mask & mask;
    if (lowest == 0) {
      break;
    }
    const uint32_t LSB = (uint32_t)((int32_t)(src << 31) >> 31);
    result |= LSB & lowest;
    mask &= ~lowest;
    src >>= 1;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<branchless>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  and    %esi,%eax
  je     L3
  mov    $0x0,%ecx
L26:
  mov    %edi,%edx
  shl    $0x1f,%edx
  sar    $0x1f,%edx
  and    %eax,%edx
  or     %edx,%ecx
  not    %eax
  and    %eax,%esi
  sar    %edi
  mov    %esi,%eax
  neg    %eax
  and    %esi,%eax
  jne    L26
L15:
  mov    %ecx,%eax
  ret
L3:
  mov    %eax,%ecx
  jmp    L15
```

assistant: ```c
uint32_t branchless(uint32_t src, uint32_t mask) {
  uint32_t result = 0;
  while (1) {
    const uint32_t lowest = -mask & mask;
    if (lowest == 0) {
      break;
    }
    const uint32_t LSB = (uint32_t)((int32_t)(src << 31) >> 31);
    result |= LSB & lowest;
    mask &= ~lowest;
    src >>= 1;
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<branchless>:
  endbr64
  mov    %esi,%eax
  xor    %r8d,%r8d
  neg    %eax
  and    %esi,%eax
  je     L9
  nop
L0:
  mov    %edi,%edx
  sar    %edi
  shl    $0x1f,%edx
  sar    $0x1f,%edx
  and    %eax,%edx
  not    %eax
  and    %eax,%esi
  or     %edx,%r8d
  mov    %esi,%eax
  neg    %eax
  and    %esi,%eax
  jne    L0
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t branchless(uint32_t src, uint32_t mask) {
  uint32_t result = 0;
  while (1) {
    const uint32_t lowest = -mask & mask;
    if (lowest == 0) {
      break;
    }
    const uint32_t LSB = (uint32_t)((int32_t)(src << 31) >> 31);
    result |= LSB & lowest;
    mask &= ~lowest;
    src >>= 1;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<branchless>:
  endbr64
  mov    %esi,%eax
  xor    %r8d,%r8d
  neg    %eax
  and    %esi,%eax
  je     L14
  nop
L3:
  mov    %edi,%edx
  sar    %edi
  shl    $0x1f,%edx
  sar    $0x1f,%edx
  and    %eax,%edx
  not    %eax
  and    %eax,%esi
  or     %edx,%r8d
  mov    %esi,%eax
  neg    %eax
  and    %esi,%eax
  jne    L3
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t branchless(uint32_t src, uint32_t mask) {
  uint32_t result = 0;
  while (1) {
    const uint32_t lowest = -mask & mask;
    if (lowest == 0) {
      break;
    }
    const uint32_t LSB = (uint32_t)((int32_t)(src << 31) >> 31);
    result |= LSB & lowest;
    mask &= ~lowest;
    src >>= 1;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TermHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <TidyUp@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void TermHandler(int sig) {
  TidyUp();
  _exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<TermHandler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <TidyUp@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void TermHandler(int sig) {
  TidyUp();
  _exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<TermHandler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TidyUp@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <_exit@plt>
```

assistant: ```c
void TermHandler(int sig) {
  TidyUp();
  _exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TermHandler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TidyUp@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <_exit@plt>
```

assistant: ```c
void TermHandler(int sig) {
  TidyUp();
  _exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ParseAddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L7:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L8
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L7
L8:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L37
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
L37:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
void ParseAddr(char *hostname, int *port, int def, char *addr) {
  char *s, *t;
  *port = def;
  hostname[0] = 0;
  s = hostname;
  t = addr;
  while (*t != 0 && *t != ':')
    *s++ = *t++;
  *s = 0;
  if (*t == ':')
    sscanf(t + 1, "%d", port);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ParseAddr>:
  endbr64
  mov    %edx,(%rsi)
  movb   $0x0,(%rdi)
  movzbl (%rcx),%eax
  test   %al,%al
  je     L7
  cmp    $0x3a,%al
  je     L7
L35:
  add    $0x1,%rcx
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rcx),%eax
  test   %al,%al
  je     L7
  cmp    $0x3a,%al
  jne    L35
L7:
  movb   $0x0,(%rdi)
  cmpb   $0x3a,(%rcx)
  je     L49
  ret
L49:
  sub    $0x8,%rsp
  lea    0x1(%rcx),%rdi
  mov    %rsi,%rdx
  lea    D9(%rip),%rsi
  call   <sscanf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: %d

assistant: ```c
void ParseAddr(char *hostname, int *port, int def, char *addr) {
  char *s, *t;
  *port = def;
  hostname[0] = 0;
  s = hostname;
  t = addr;
  while (*t != 0 && *t != ':')
    *s++ = *t++;
  *s = 0;
  if (*t == ':')
    sscanf(t + 1, "%d", port);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ParseAddr>:
  endbr64
  mov    %edx,(%rsi)
  movb   $0x0,(%rdi)
  movzbl (%rcx),%eax
  cmp    $0x3a,%al
  je     L49
  test   %al,%al
  je     L49
  nopl   0x0(%rax)
L25:
  add    $0x1,%rcx
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rcx),%eax
  test   %al,%al
  je     L49
  cmp    $0x3a,%al
  jne    L25
L49:
  movb   $0x0,(%rdi)
  cmpb   $0x3a,(%rcx)
  je     L8
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %rsi,%rdx
  lea    0x1(%rcx),%rdi
  lea    D5(%rip),%rsi
  jmp    1050 <sscanf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: %d

assistant: ```c
void ParseAddr(char *hostname, int *port, int def, char *addr) {
  char *s, *t;
  *port = def;
  hostname[0] = 0;
  s = hostname;
  t = addr;
  while (*t != 0 && *t != ':')
    *s++ = *t++;
  *s = 0;
  if (*t == ':')
    sscanf(t + 1, "%d", port);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ParseAddr>:
  endbr64
  mov    %edx,(%rsi)
  movb   $0x0,(%rdi)
  movzbl (%rcx),%eax
  cmp    $0x3a,%al
  je     L47
  test   %al,%al
  je     L47
  nopl   0x0(%rax)
L26:
  add    $0x1,%rcx
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rcx),%eax
  test   %al,%al
  je     L47
  cmp    $0x3a,%al
  jne    L26
L47:
  movb   $0x0,(%rdi)
  cmpb   $0x3a,(%rcx)
  je     L49
  ret
  cs nopw 0x0(%rax,%rax,1)
L49:
  mov    %rsi,%rdx
  lea    0x1(%rcx),%rdi
  lea    D4(%rip),%rsi
  jmp    1050 <sscanf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: %d

assistant: ```c
void ParseAddr(char *hostname, int *port, int def, char *addr) {
  char *s, *t;
  *port = def;
  hostname[0] = 0;
  s = hostname;
  t = addr;
  while (*t != 0 && *t != ':')
    *s++ = *t++;
  *s = 0;
  if (*t == ':')
    sscanf(t + 1, "%d", port);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <clear_kb@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
type_guessed: string
name: parse_data
arguments: data_label: D35
type_guessed: string
name: parse_data
arguments: data_label: D57
type_guessed: string
name: parse_data
arguments: data_label: D54
type_guessed: string
name: parse_data
arguments: data_label: D42
type_guessed: string
name: parse_data
arguments: data_label: D25
type_guessed: string

tool: D15: Enter your age:

tool: D35: %d

tool: D57: Enter your first name:

tool: D54: %s

tool: D42: Your age is %d.


tool: D25: Your name is %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int age;
  char name[20];
  puts("Enter your age:");
  scanf("%d", &age);
  clear_kb();
  puts("Enter your first name:");
  scanf("%s", name);
  printf("Your age is %d.\n", age);
  printf("Your name is %s.\n", name);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <clear_kb@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D30
type_guessed: string
name: read_data
arguments: data_label: D52
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D5
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: string

tool: D15: Enter your age:

tool: D30: %d

tool: D52: Enter your first name:

tool: D1: %s

tool: D5: Your age is %d.


tool: D12: Your name is %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int age;
  char name[20];
  puts("Enter your age:");
  scanf("%d", &age);
  clear_kb();
  puts("Enter your first name:");
  scanf("%s", name);
  printf("Your age is %d.\n", age);
  printf("Your name is %s.\n", name);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D35(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %eax,%eax
  call   <clear_kb@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D35
type: string
name: unpack_data
arguments: tag: D46
type: string
name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D55
type: string
name: unpack_data
arguments: tag: D3
type: string

tool: D35: Enter your age:

tool: D46: %d

tool: D1: Enter your first name:

tool: D8: %s

tool: D55: Your age is %d.


tool: D3: Your name is %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int age;
  char name[20];
  puts("Enter your age:");
  scanf("%d", &age);
  clear_kb();
  puts("Enter your first name:");
  scanf("%s", name);
  printf("Your age is %d.\n", age);
  printf("Your name is %s.\n", name);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %eax,%eax
  call   <clear_kb@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D49
type: string
name: extract_symbolic_data
arguments: label: D1
type: string
name: extract_symbolic_data
arguments: label: D20
type: string
name: extract_symbolic_data
arguments: label: D34
type: string
name: extract_symbolic_data
arguments: label: D31
type: string
name: extract_symbolic_data
arguments: label: D40
type: string

tool: D49: Enter your age:

tool: D1: %d

tool: D20: Enter your first name:

tool: D34: %s

tool: D31: Your age is %d.


tool: D40: Your name is %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int age;
  char name[20];
  puts("Enter your age:");
  scanf("%d", &age);
  clear_kb();
  puts("Enter your first name:");
  scanf("%s", name);
  printf("Your age is %d.\n", age);
  printf("Your name is %s.\n", name);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solve>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %edx,%r9d
  mov    (%rdi),%rax
  movsd  (%rsi),%xmm0
  divsd  (%rax),%xmm0
  movsd  %xmm0,(%rsi)
  cmp    $0x1,%edx
  jle    L16
  push   %rbx
  mov    %edx,%r10d
  mov    $0x8,%esi
  mov    $0x1,%edi
  jmp    L87
L6:
  mov    (%r8,%rax,8),%rdx
  movsd  (%rdx,%rsi,1),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L6
L70:
  movsd  (%rcx,%rsi,1),%xmm0
  subsd  %xmm1,%xmm0
  mov    (%r8,%rsi,1),%rax
  divsd  (%rax,%rsi,1),%xmm0
  movsd  %xmm0,(%rcx,%rsi,1)
  add    $0x1,%rdi
  add    $0x8,%rsi
  cmp    %r10,%rdi
  je     L54
L87:
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  test   %edi,%edi
  jg     L6
  jmp    L70
L16:
  movslq %edx,%rax
  shl    $0x3,%rax
  lea    -0x8(%rsi,%rax,1),%rdx
  mov    -0x8(%rdi,%rax,1),%rcx
  movsd  (%rdx),%xmm0
  divsd  -0x8(%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx)
  mov    $0x0,%eax
  ret
L56:
  lea    0x0(,%r10,8),%rax
  mov    %ebx,%esi
  sub    %r10d,%esi
  lea    0x1(%r10,%rsi,1),%r8
  shl    $0x3,%r8
L73:
  mov    -0x8(%rdi),%rsi
  movsd  (%rsi,%rax,1),%xmm1
  mulsd  (%rcx,%rax,1),%xmm1
  movsd  (%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L73
L36:
  mov    %rdi,%rax
  add    -0x8(%rdi),%rax
  movsd  (%rdx),%xmm0
  divsd  (%rax,%r11,1),%xmm0
  movsd  %xmm0,(%rdx)
  sub    $0x1,%r10
  sub    $0x8,%rdx
  sub    $0x8,%rdi
  test   %r10d,%r10d
  jle    L86
L22:
  cmp    %r10d,%r9d
  jg     L56
  jmp    L36
L54:
  movslq %r9d,%rax
  shl    $0x3,%rax
  lea    -0x8(%rcx,%rax,1),%rdx
  mov    -0x8(%r8,%rax,1),%rsi
  movsd  (%rdx),%xmm0
  divsd  -0x8(%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%rdx)
  lea    -0x1(%r9),%r10d
  movslq %r10d,%r10
  lea    0x0(,%r10,8),%rdi
  lea    -0x8(%rcx,%rdi,1),%rdx
  add    %r8,%rdi
  lea    -0x1(%r9),%ebx
  mov    $0xfffffffffffffff8,%r11
  sub    %r8,%r11
  jmp    L22
L86:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int solve(double **A, double *z, int n) {
  int i, k;
  double sum;
  z[0] /= A[0][0];
  for (i = 1; i < n; i++) {
    sum = 0.0;
    for (k = 0; k < i; k++)
      sum += A[k][i] * z[k];
    z[i] = (z[i] - sum) / A[i][i];
  }
  z[n - 1] /= A[n - 1][n - 1];
  for (i = n - 1; i >= 1; i--) {
    for (k = i; k < n; k++)
      z[i - 1] -= A[i - 1][k] * z[k];
    z[i - 1] /= A[i - 1][i - 1];
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<solve>:
  endbr64
  push   %r12
  mov    %rdi,%r9
  mov    %rsi,%rcx
  push   %rbp
  push   %rbx
  movslq %edx,%rbx
  mov    (%rdi),%r11
  lea    0x0(,%rbx,8),%rax
  movsd  (%rsi),%xmm0
  mov    %rbx,%r8
  lea    -0x1(%rbx),%r10d
  lea    -0x8(%rax),%rbp
  divsd  (%r11),%xmm0
  movsd  %xmm0,(%rsi)
  lea    (%rsi,%rbp,1),%r12
  add    -0x8(%rdi,%rax,1),%rbp
  cmp    $0x1,%ebx
  jle    L41
  mov    $0x1,%esi
  pxor   %xmm2,%xmm2
  nop
L66:
  lea    0x0(,%rsi,8),%rdi
  mov    %r11,%rdx
  movapd %xmm2,%xmm1
  xor    %eax,%eax
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L27:
  mov    (%r9,%rax,8),%rdx
  movsd  (%rcx,%rax,8),%xmm0
L63:
  mulsd  (%rdx,%rdi,1),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L27
  movsd  (%rcx,%rsi,8),%xmm0
  mov    (%r9,%rsi,8),%rax
  subsd  %xmm1,%xmm0
  divsd  (%rax,%rdi,1),%xmm0
  movsd  %xmm0,(%rcx,%rsi,8)
  add    $0x1,%rsi
  cmp    %rsi,%rbx
  je     L87
  movsd  (%rcx),%xmm0
  jmp    L66
  nopl   0x0(%rax)
L87:
  movsd  (%r12),%xmm0
  divsd  0x0(%rbp),%xmm0
  movsd  %xmm0,(%r12)
L51:
  movslq %r10d,%rdi
  lea    -0x8(,%rdi,8),%r10
  lea    (%rcx,%r10,1),%rdx
L42:
  mov    (%r9,%r10,1),%rsi
  movsd  (%rdx),%xmm1
  mov    %rdi,%rax
  cmp    %edi,%r8d
  jle    L82
L88:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  add    $0x1,%rax
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %eax,%r8d
  jg     L88
L82:
  sub    $0x1,%rdi
  divsd  (%rsi,%r10,1),%xmm1
  sub    $0x8,%rdx
  movsd  %xmm1,0x8(%rdx)
  sub    $0x8,%r10
  test   %edi,%edi
  jg     L42
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L41:
  movsd  (%r12),%xmm0
  divsd  0x0(%rbp),%xmm0
  movsd  %xmm0,(%r12)
  test   %r10d,%r10d
  jg     L51
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int solve(double **A, double *z, int n) {
  int i, k;
  double sum;
  z[0] /= A[0][0];
  for (i = 1; i < n; i++) {
    sum = 0.0;
    for (k = 0; k < i; k++)
      sum += A[k][i] * z[k];
    z[i] = (z[i] - sum) / A[i][i];
  }
  z[n - 1] /= A[n - 1][n - 1];
  for (i = n - 1; i >= 1; i--) {
    for (k = i; k < n; k++)
      z[i - 1] -= A[i - 1][k] * z[k];
    z[i - 1] /= A[i - 1][i - 1];
  }
  return 0;
}
```