ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<TeX_search_ttf_file>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rsi
  call   <handle_extension@plt>
  mov    (%rbx),%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: .ttf

assistant: ```c
char *TeX_search_ttf_file(char **name) {
  handle_extension(name, ".ttf");
  return *name;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TeX_search_ttf_file>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rsi
  mov    %rdi,%rbx
  call   <handle_extension@plt>
  mov    (%rbx),%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: .ttf

assistant: ```c
char *TeX_search_ttf_file(char **name) {
  handle_extension(name, ".ttf");
  return *name;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TeX_search_ttf_file>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rsi
  mov    %rdi,%rbx
  call   <handle_extension@plt>
  mov    (%rbx),%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: .ttf

assistant: ```c
char *TeX_search_ttf_file(char **name) {
  handle_extension(name, ".ttf");
  return *name;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  cmpq   $0x0,-0x10(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  movl   $0x64,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0xc8,(%rax)
  jmp    L5
L0:
  mov    -0x8(%rbp),%rax
  movl   $0x12c,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x190,(%rax)
  nop
L5:
  pop    %rbp
  ret
```

assistant: ```c
void func8(int *ptr1, int *ptr2) {
  if (ptr1 && ptr2) {
    *ptr1 = 100;
    *ptr2 = 200;
    return;
  } else {
    *ptr1 = 300;
    *ptr2 = 400;
    return;
  }
  *ptr1 = 500;
  *ptr2 = 600;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func8>:
  endbr64
  test   %rdi,%rdi
  je     L21
  test   %rsi,%rsi
  je     L21
  mov    $0x64,%edx
  mov    $0xc8,%eax
L4:
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
L21:
  mov    $0x12c,%edx
  mov    $0x190,%eax
  jmp    L4
```

assistant: ```c
void func8(int *ptr1, int *ptr2) {
  if (ptr1 && ptr2) {
    *ptr1 = 100;
    *ptr2 = 200;
    return;
  } else {
    *ptr1 = 300;
    *ptr2 = 400;
    return;
  }
  *ptr1 = 500;
  *ptr2 = 600;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func8>:
  endbr64
  test   %rdi,%rdi
  je     L2
  mov    $0x64,%edx
  mov    $0xc8,%eax
  test   %rsi,%rsi
  je     L2
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L2:
  mov    $0x12c,%edx
  mov    $0x190,%eax
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void func8(int *ptr1, int *ptr2) {
  if (ptr1 && ptr2) {
    *ptr1 = 100;
    *ptr2 = 200;
    return;
  } else {
    *ptr1 = 300;
    *ptr2 = 400;
    return;
  }
  *ptr1 = 500;
  *ptr2 = 600;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func8>:
  endbr64
  test   %rdi,%rdi
  je     L17
  mov    $0x64,%edx
  mov    $0xc8,%eax
  test   %rsi,%rsi
  je     L17
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L17:
  mov    $0x12c,%edx
  mov    $0x190,%eax
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void func8(int *ptr1, int *ptr2) {
  if (ptr1 && ptr2) {
    *ptr1 = 100;
    *ptr2 = 200;
    return;
  } else {
    *ptr1 = 300;
    *ptr2 = 400;
    return;
  }
  *ptr1 = 500;
  *ptr2 = 600;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy_double_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L9:
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L11:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L11
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **copy_double_arr(double **arr, int row, int col) {
  double **copy;
  int i, j;
  copy = (double **)malloc(sizeof(double *) * row);
  for (i = 0; i < row; i++) {
    copy[i] = (double *)malloc(sizeof(double) * col);
    for (j = 0; j < col; j++)
      copy[i][j] = arr[i][j];
  }
  return (copy);
}
```
user: What is the c source code of the assembly code below:

```asm
<copy_double_arr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    %edx,%r12d
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %ebx,%ebx
  jle    L4
  mov    %rax,%rsi
  lea    0x0(,%r12,8),%r15d
  lea    -0x1(%rbx),%eax
  mov    %r14,%rdi
  lea    0x8(%r14,%rax,8),%r14
  lea    -0x1(%r12),%eax
  lea    0x8(,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    %rdi,%rsi
  mov    %rsi,%r13
L14:
  mov    %r15d,%edi
  call   <malloc@plt>
  lea    0x0(%r13,%rbx,1),%rcx
  mov    %rax,(%rcx)
  test   %r12d,%r12d
  jle    L29
  mov    $0x0,%eax
L21:
  mov    (%rbx),%rdx
  movsd  (%rdx,%rax,1),%xmm0
  mov    (%rcx),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rbp,%rax
  jne    L21
L29:
  add    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L14
L4:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **copy_double_arr(double **arr, int row, int col) {
  double **copy;
  int i, j;
  copy = (double **)malloc(sizeof(double *) * row);
  for (i = 0; i < row; i++) {
    copy[i] = (double *)malloc(sizeof(double) * col);
    for (j = 0; j < col; j++)
      copy[i][j] = arr[i][j];
  }
  return (copy);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copy_double_arr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%r12,8),%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  jle    L7
  mov    %rax,%rsi
  lea    (%rax,%r12,8),%r12
  lea    -0x1(%rbx),%eax
  lea    0x0(,%rbx,8),%r13d
  mov    %rsi,%r15
  sub    %rsi,%rbp
  lea    0x8(,%rax,8),%r14
  nopl   0x0(%rax)
L31:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%r15)
  test   %ebx,%ebx
  jle    L19
  mov    0x0(%rbp,%r15,1),%rdx
  lea    (%r14,%rax,1),%rcx
  sub    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L24:
  movsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L24
L19:
  add    $0x8,%r15
  cmp    %r12,%r15
  jne    L31
L7:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **copy_double_arr(double **arr, int row, int col) {
  double **copy;
  int i, j;
  copy = (double **)malloc(sizeof(double *) * row);
  for (i = 0; i < row; i++) {
    copy[i] = (double *)malloc(sizeof(double) * col);
    for (j = 0; j < col; j++)
      copy[i][j] = arr[i][j];
  }
  return (copy);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_double_arr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%r12,8),%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %r12d,%r12d
  jle    L10
  mov    %rax,%rdi
  lea    (%rax,%r12,8),%r12
  mov    %ebx,%ecx
  mov    %ebx,%eax
  and    $0xfffffffe,%ecx
  shr    %eax
  lea    -0x1(%rbx),%edx
  lea    0x0(,%rbx,8),%r13d
  mov    %ecx,0x4(%rsp)
  sub    $0x1,%eax
  movslq %ecx,%rcx
  sub    %rdi,%rbp
  lea    0x0(,%rcx,8),%r14
  add    $0x1,%rax
  mov    %edx,(%rsp)
  lea    0x8(,%rdx,8),%rcx
  mov    %rcx,0x10(%rsp)
  mov    %r14,%r15
  mov    %rdi,%r14
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L41:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  mov    %rax,%rdx
  test   %ebx,%ebx
  jle    L38
  mov    0x0(%rbp,%r14,1),%r9
  lea    0x8(%r9),%rax
  cmp    %rax,%rdx
  je     L51
  cmpl   $0x2,(%rsp)
  jbe    L51
  mov    0x8(%rsp),%rsi
  mov    %r9,%rdi
  mov    %rdx,%rax
  sub    %rdx,%rdi
  shl    $0x4,%rsi
  add    %rdx,%rsi
  nopl   0x0(%rax,%rax,1)
L26:
  movupd (%rax,%rdi,1),%xmm1
  add    $0x10,%rax
  movups %xmm1,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L26
  cmp    0x4(%rsp),%ebx
  je     L38
  movsd  (%r9,%r15,1),%xmm0
  movsd  %xmm0,(%rdx,%r15,1)
L38:
  add    $0x8,%r14
  cmp    %r12,%r14
  jne    L41
L10:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L51:
  mov    0x10(%rsp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    %r9,%rax
  sub    %rdx,%rax
  nop
L56:
  movsd  (%rax,%rdx,1),%xmm0
  add    $0x8,%rdx
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rdx,%rsi
  jne    L56
  jmp    L38
```

assistant: ```c
double **copy_double_arr(double **arr, int row, int col) {
  double **copy;
  int i, j;
  copy = (double **)malloc(sizeof(double *) * row);
  for (i = 0; i < row; i++) {
    copy[i] = (double *)malloc(sizeof(double) * col);
    for (j = 0; j < col; j++)
      copy[i][j] = arr[i][j];
  }
  return (copy);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L15
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L42
L21:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L2
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L2:
  addl   $0x1,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L8
  jmp    L61
L15:
  nop
L61:
  leave
  ret
```

assistant: ```c
void nicksort(int v[], int n) {
  if (n <= 1)
    return;
  int i, j, right;
  right = 1;
  for (i = 0; i < n - 1; ++i) {
    for (j = right; j < n; ++j) {
      if (v[j] < v[i]) {
        swap(v, i, j);
      }
    }
    ++right;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<nicksort>:
  endbr64
  cmp    $0x1,%esi
  jle    L12
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r15d
  mov    %esi,%eax
  mov    %rax,(%rsp)
  mov    $0x1,%r12d
  lea    -0x1(%rsi),%eax
  mov    %eax,0xc(%rsp)
  jmp    L41
L75:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L2
L71:
  mov    %ebx,%edx
  mov    -0x4(%rbp,%r12,4),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L75
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L75
L2:
  add    $0x1,%r12
  cmp    (%rsp),%r12
  je     L68
L41:
  lea    -0x1(%r12),%r14d
  cmp    %r12d,%r15d
  jle    L2
  mov    0xc(%rsp),%eax
  sub    %r12d,%eax
  lea    0x1(%r12,%rax,1),%r13
  mov    %r12,%rbx
  jmp    L71
L68:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  ret
```

assistant: ```c
void nicksort(int v[], int n) {
  if (n <= 1)
    return;
  int i, j, right;
  right = 1;
  for (i = 0; i < n - 1; ++i) {
    for (j = right; j < n; ++j) {
      if (v[j] < v[i]) {
        swap(v, i, j);
      }
    }
    ++right;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  cmp    $0x1,%esi
  jle    L8
  mov    %esi,%eax
  movslq %esi,%rcx
  mov    %rdi,%rbp
  mov    $0x1,%r14d
  sub    $0x1,%eax
  mov    %rcx,(%rsp)
  mov    %eax,0xc(%rsp)
  nopl   0x0(%rax)
L37:
  lea    -0x1(%r14),%r15d
  lea    0x1(%r14),%r12
  cmp    %r14d,0x8(%rsp)
  jle    L41
  mov    0xc(%rsp),%r8d
  lea    0x1(%r14),%r12
  mov    %r14,%rbx
  sub    %r14d,%r8d
  lea    (%r8,%r12,1),%r13
  jmp    L51
  nopl   0x0(%rax)
L61:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L41
L51:
  mov    -0x4(%rbp,%r14,4),%eax
  mov    %ebx,%edx
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L61
  mov    %r15d,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %r13,%rbx
  jne    L51
L41:
  mov    %r12,%r14
  cmp    (%rsp),%r12
  jne    L37
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void nicksort(int v[], int n) {
  if (n <= 1)
    return;
  int i, j, right;
  right = 1;
  for (i = 0; i < n - 1; ++i) {
    for (j = right; j < n; ++j) {
      if (v[j] < v[i]) {
        swap(v, i, j);
      }
    }
    ++right;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nicksort>:
  endbr64
  cmp    $0x1,%esi
  jle    L29
  push   %r15
  lea    -0x1(%rsi),%eax
  mov    %esi,%r15d
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r13d,%r14d
  mov    %r13,%r12
  add    $0x1,%r13
  mov    %r13,%rbx
  jmp    L27
  nop
L20:
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jle    L15
L27:
  mov    0x0(%rbp,%r12,4),%eax
  mov    %ebx,%edx
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L20
  mov    %r14d,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %ebx,%r15d
  jg     L27
L15:
  cmp    %r13,0x8(%rsp)
  jne    L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  ret
```

assistant: ```c
void nicksort(int v[], int n) {
  if (n <= 1)
    return;
  int i, j, right;
  right = 1;
  for (i = 0; i < n - 1; ++i) {
    for (j = right; j < n; ++j) {
      if (v[j] < v[i]) {
        swap(v, i, j);
      }
    }
    ++right;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mymax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L10
  movsd  -0x8(%rbp),%xmm0
  jmp    L3
L10:
  movsd  -0x10(%rbp),%xmm0
L3:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double mymax(double a, double b) {
  if (a >= b)
    return a;
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mymax>:
  endbr64
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  andpd  %xmm2,%xmm1
  andnpd %xmm0,%xmm2
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double mymax(double a, double b) {
  if (a >= b)
    return a;
  return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<mymax>:
  endbr64
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  andpd  %xmm2,%xmm1
  andnpd %xmm0,%xmm2
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double mymax(double a, double b) {
  if (a >= b)
    return a;
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mymax>:
  endbr64
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  andpd  %xmm2,%xmm1
  andnpd %xmm0,%xmm2
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double mymax(double a, double b) {
  if (a >= b)
    return a;
  return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<Cyc_Tcutil_coerce_assign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <Cyc_Tcutil_coerce_arg@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int Cyc_Tcutil_coerce_assign(struct Cyc_List_List *aqb, struct Cyc_Absyn_Exp *e, void *t) {
  struct Cyc_List_List *_T0;
  struct Cyc_Absyn_Exp *_T1;
  void *_T2;
  int *_T3;
  int _T4;
  int bogus = 0;
  _T0 = aqb;
  _T1 = e;
  _T2 = t;
  _T3 = &bogus;
  _T4 = Cyc_Tcutil_coerce_arg(_T0, _T1, _T2, _T3);
  return _T4;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Cyc_Tcutil_coerce_assign>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  call   <Cyc_Tcutil_coerce_arg@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Cyc_Tcutil_coerce_assign(struct Cyc_List_List *aqb, struct Cyc_Absyn_Exp *e, void *t) {
  struct Cyc_List_List *_T0;
  struct Cyc_Absyn_Exp *_T1;
  void *_T2;
  int *_T3;
  int _T4;
  int bogus = 0;
  _T0 = aqb;
  _T1 = e;
  _T2 = t;
  _T3 = &bogus;
  _T4 = Cyc_Tcutil_coerce_arg(_T0, _T1, _T2, _T3);
  return _T4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cyc_Tcutil_coerce_assign>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  movl   $0x0,0x4(%rsp)
  call   <Cyc_Tcutil_coerce_arg@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Cyc_Tcutil_coerce_assign(struct Cyc_List_List *aqb, struct Cyc_Absyn_Exp *e, void *t) {
  struct Cyc_List_List *_T0;
  struct Cyc_Absyn_Exp *_T1;
  void *_T2;
  int *_T3;
  int _T4;
  int bogus = 0;
  _T0 = aqb;
  _T1 = e;
  _T2 = t;
  _T3 = &bogus;
  _T4 = Cyc_Tcutil_coerce_arg(_T0, _T1, _T2, _T3);
  return _T4;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Cyc_Tcutil_coerce_assign>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  movl   $0x0,0x4(%rsp)
  call   <Cyc_Tcutil_coerce_arg@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Cyc_Tcutil_coerce_assign(struct Cyc_List_List *aqb, struct Cyc_Absyn_Exp *e, void *t) {
  struct Cyc_List_List *_T0;
  struct Cyc_Absyn_Exp *_T1;
  void *_T2;
  int *_T3;
  int _T4;
  int bogus = 0;
  _T0 = aqb;
  _T1 = e;
  _T2 = t;
  _T3 = &bogus;
  _T4 = Cyc_Tcutil_coerce_arg(_T0, _T1, _T2, _T3);
  return _T4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<jsr_center_and_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <jsr_strlen@plt>
  mov    $0x0,%eax
  call   <sec@plt>
  mov    $0x28,%esi
  mov    $0x0,%edi
  call   <lda@plt>
  mov    $0xf4,%esi
  mov    $0x1,%edi
  call   <sbc@plt>
  mov    $0x0,%eax
  call   <bmi@plt>
  test   %rax,%rax
  jne    L5
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <lsr@plt>
  mov    $0x0,%eax
  call   <tax@plt>
  mov    $0x0,%eax
  call   <jsr_prblnk@plt>
  mov    $0x0,%eax
  call   <jsr_reset_output@plt>
  jmp    L24
L5:
  nop
L24:
  mov    $0xf4,%esi
  mov    $0x1,%edi
  call   <ldx@plt>
L31:
  mov    $0xfc,%esi
  mov    $0x2,%edi
  call   <lda@plt>
  mov    $0x0,%eax
  call   <jsr_cout1@plt>
  mov    $0x0,%eax
  call   <jsr_inc_pointer@plt>
  mov    $0x0,%eax
  call   <dex@plt>
  mov    $0x0,%eax
  call   <bne@plt>
  test   %rax,%rax
  je     L16
  jmp    L31
L16:
  mov    $0x0,%eax
  call   <jsr_crout@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void jsr_center_and_print() {
  jsr_strlen();
  sec();
  lda(0, 40);
  sbc(1, 0xf4);
  if (bmi())
    goto no_center;
  lsr(3, 1);
  tax();
  jsr_prblnk();
  jsr_reset_output();
no_center:
  ldx(1, 0xf4);
print_loop:
  lda(2, 0xfc);
  jsr_cout1();
  jsr_inc_pointer();
  dex();
  if (bne())
    goto print_loop;
  jsr_crout();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jsr_center_and_print>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <jsr_strlen@plt>
  mov    $0x0,%eax
  call   <sec@plt>
  mov    $0x28,%esi
  mov    $0x0,%edi
  call   <lda@plt>
  mov    $0xf4,%esi
  mov    $0x1,%edi
  call   <sbc@plt>
  mov    $0x0,%eax
  call   <bmi@plt>
  test   %rax,%rax
  je     L29
L23:
  mov    $0xf4,%esi
  mov    $0x1,%edi
  call   <ldx@plt>
L20:
  mov    $0xfc,%esi
  mov    $0x2,%edi
  call   <lda@plt>
  mov    $0x0,%eax
  call   <jsr_cout1@plt>
  mov    $0x0,%eax
  call   <jsr_inc_pointer@plt>
  mov    $0x0,%eax
  call   <dex@plt>
  mov    $0x0,%eax
  call   <bne@plt>
  test   %rax,%rax
  jne    L20
  call   <jsr_crout@plt>
  add    $0x8,%rsp
  ret
L29:
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <lsr@plt>
  mov    $0x0,%eax
  call   <tax@plt>
  mov    $0x0,%eax
  call   <jsr_prblnk@plt>
  mov    $0x0,%eax
  call   <jsr_reset_output@plt>
  jmp    L23
```

assistant: ```c
void jsr_center_and_print() {
  jsr_strlen();
  sec();
  lda(0, 40);
  sbc(1, 0xf4);
  if (bmi())
    goto no_center;
  lsr(3, 1);
  tax();
  jsr_prblnk();
  jsr_reset_output();
no_center:
  ldx(1, 0xf4);
print_loop:
  lda(2, 0xfc);
  jsr_cout1();
  jsr_inc_pointer();
  dex();
  if (bne())
    goto print_loop;
  jsr_crout();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<jsr_center_and_print>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <jsr_strlen@plt>
  xor    %eax,%eax
  call   <sec@plt>
  xor    %edi,%edi
  mov    $0x28,%esi
  call   <lda@plt>
  mov    $0xf4,%esi
  mov    $0x1,%edi
  call   <sbc@plt>
  xor    %eax,%eax
  call   <bmi@plt>
  test   %rax,%rax
  jne    L15
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <lsr@plt>
  xor    %eax,%eax
  call   <tax@plt>
  xor    %eax,%eax
  call   <jsr_prblnk@plt>
  xor    %eax,%eax
  call   <jsr_reset_output@plt>
L15:
  mov    $0xf4,%esi
  mov    $0x1,%edi
  call   <ldx@plt>
L8:
  mov    $0xfc,%esi
  mov    $0x2,%edi
  call   <lda@plt>
  xor    %eax,%eax
  call   <jsr_cout1@plt>
  xor    %eax,%eax
  call   <jsr_inc_pointer@plt>
  xor    %eax,%eax
  call   <dex@plt>
  xor    %eax,%eax
  call   <bne@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  jmp    1130 <jsr_crout@plt>
```

assistant: ```c
void jsr_center_and_print() {
  jsr_strlen();
  sec();
  lda(0, 40);
  sbc(1, 0xf4);
  if (bmi())
    goto no_center;
  lsr(3, 1);
  tax();
  jsr_prblnk();
  jsr_reset_output();
no_center:
  ldx(1, 0xf4);
print_loop:
  lda(2, 0xfc);
  jsr_cout1();
  jsr_inc_pointer();
  dex();
  if (bne())
    goto print_loop;
  jsr_crout();
}
```