ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<print_primes>:
  endbr64
  test   %esi,%esi
  jle    L24
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L21
L27:
  cmpl   $0x1,(%r12,%rbx,4)
  mov    %ebx,%esi
  jne    L7
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L27
L21:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L24:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: %d  

assistant: ```c
void print_primes(int prime[], int length) {
  int i;
  for (i = 0; i < length; i++)
    if (prime[i] == 1)
      printf("%d  ", i);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_something>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x320,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x320,-0x1c(%rbp)
  jle    L12
  mov    $0xffffffff,%eax
  jmp    L11
L12:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
L11:
  leave
  ret
```

assistant: ```c
int copy_something(char *buf, int len) {
  char *kbuf;
  int ret;
  kbuf = (char *)malloc(sizeof(char) * 800);
  if (len > 800) {
    return -1;
  }
  ret = (int)memcpy(kbuf, buf, len);
  free(kbuf);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_something>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    $0x320,%edi
  call   <malloc@plt>
  cmp    $0x320,%ebx
  jg     L5
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <free@plt>
L10:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0xffffffff,%ebx
  jmp    L10
```

assistant: ```c
int copy_something(char *buf, int len) {
  char *kbuf;
  int ret;
  kbuf = (char *)malloc(sizeof(char) * 800);
  if (len > 800) {
    return -1;
  }
  ret = (int)memcpy(kbuf, buf, len);
  free(kbuf);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_something>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x320,%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  call   <malloc@plt>
  cmp    $0x320,%r12d
  jg     L4
  mov    %rax,%rbp
  mov    %r12d,%edx
  mov    %rax,%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L12:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%r12d
  jmp    L12
```

assistant: ```c
int copy_something(char *buf, int len) {
  char *kbuf;
  int ret;
  kbuf = (char *)malloc(sizeof(char) * 800);
  if (len > 800) {
    return -1;
  }
  ret = (int)memcpy(kbuf, buf, len);
  free(kbuf);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_something>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x320,%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  call   <malloc@plt>
  cmp    $0x320,%r12d
  jg     L18
  mov    %rax,%rbp
  mov    %r12d,%edx
  mov    %rax,%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L15:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%r12d
  jmp    L15
```

assistant: ```c
int copy_something(char *buf, int len) {
  char *kbuf;
  int ret;
  kbuf = (char *)malloc(sizeof(char) * 800);
  if (len > 800) {
    return -1;
  }
  ret = (int)memcpy(kbuf, buf, len);
  free(kbuf);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L49
L72:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L75
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L9
  cmpl   $0x2e,-0x4(%rbp)
  jne    L75
L9:
  cmpl   $0xf9,-0x8(%rbp)
  jle    L72
L75:
  cmpl   $0x0,-0x8(%rbp)
  jne    L24
  cmpl   $0x0,-0x4(%rbp)
  je     L24
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L24:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getword(char *pin, char *w) {
  int c, i;
  for (i = 0; (c = *pin++) != '\0' && (isalpha(c) || isdigit(c) || c == '.') && i < 250; i++)
    w[i] = (char)c;
  if (i == 0 && c != '\0')
    w[i++] = (char)c;
  w[i] = '\0';
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getword>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  movzbl (%rdi),%r12d
  movsbl %r12b,%ebp
  mov    $0x1,%ebx
  mov    %ebp,%r13d
  test   %ebp,%ebp
  jne    L71
  jmp    L28
L30:
  cmp    $0xfb,%rbx
  je     L58
  mov    %r12b,-0x1(%r14,%rbx,1)
  mov    %ebx,%r13d
  movzbl (%r15,%rbx,1),%r12d
  movsbl %r12b,%ebp
  add    $0x1,%rbx
  test   %ebp,%ebp
  je     L28
L71:
  lea    -0x1(%rbx),%r13d
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L30
  mov    %ebp,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%ebp
  je     L30
  test   %rax,%rax
  jne    L30
L58:
  test   %r13d,%r13d
  jne    L28
  test   %ebp,%ebp
  je     L28
  mov    %r12b,(%r14)
  mov    $0x1,%r13d
L28:
  movslq %r13d,%rax
  movb   $0x0,(%r14,%rax,1)
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int getword(char *pin, char *w) {
  int c, i;
  for (i = 0; (c = *pin++) != '\0' && (isalpha(c) || isdigit(c) || c == '.') && i < 250; i++)
    w[i] = (char)c;
  if (i == 0 && c != '\0')
    w[i++] = (char)c;
  w[i] = '\0';
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getword>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%ebp
  test   %ebp,%ebp
  je     L14
  mov    %rdi,%r15
  mov    %ebp,%r12d
  mov    $0x1,%ebx
  jmp    L34
  nopl   0x0(%rax)
L54:
  cmp    $0xfb,%rbx
  je     L56
  mov    %r12b,-0x1(%r14,%rbx,1)
  movsbl (%r15,%rbx,1),%ebp
  mov    %ebx,%r13d
  add    $0x1,%rbx
  mov    %ebp,%r12d
  test   %ebp,%ebp
  je     L73
L34:
  mov    %ebp,%edi
  lea    -0x1(%rbx),%r13d
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L54
  mov    %ebp,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%ebp
  je     L54
  test   %rax,%rax
  jne    L54
  test   %r13d,%r13d
  jne    L73
  test   %ebp,%ebp
  je     L73
  mov    %r12b,(%r14)
  mov    $0x1,%r13d
  add    $0x1,%r14
L14:
  movb   $0x0,(%r14)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L73:
  movslq %r13d,%rax
  add    %rax,%r14
  jmp    L14
L56:
  add    $0xfa,%r14
  mov    $0xfa,%r13d
  jmp    L14
```

assistant: ```c
int getword(char *pin, char *w) {
  int c, i;
  for (i = 0; (c = *pin++) != '\0' && (isalpha(c) || isdigit(c) || c == '.') && i < 250; i++)
    w[i] = (char)c;
  if (i == 0 && c != '\0')
    w[i++] = (char)c;
  w[i] = '\0';
  return (i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getword>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%ebp
  test   %ebp,%ebp
  je     L91
  mov    %rdi,%r15
  mov    %ebp,%r12d
  mov    $0x1,%ebx
  jmp    L54
  nopl   0x0(%rax)
L24:
  cmp    $0xfb,%rbx
  je     L57
  mov    %r12b,-0x1(%r14,%rbx,1)
  movsbl (%r15,%rbx,1),%ebp
  mov    %ebx,%r13d
  add    $0x1,%rbx
  mov    %ebp,%r12d
  test   %ebp,%ebp
  je     L66
L54:
  mov    %ebp,%edi
  lea    -0x1(%rbx),%r13d
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L24
  mov    %ebp,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%ebp
  je     L24
  test   %rax,%rax
  jne    L24
  test   %r13d,%r13d
  jne    L66
  test   %ebp,%ebp
  je     L66
  mov    %r12b,(%r14)
  mov    $0x1,%r13d
  add    $0x1,%r14
L91:
  movb   $0x0,(%r14)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L66:
  movslq %r13d,%rax
  add    %rax,%r14
  jmp    L91
L57:
  add    $0xfa,%r14
  mov    $0xfa,%r13d
  jmp    L91
```

assistant: ```c
int getword(char *pin, char *w) {
  int c, i;
  for (i = 0; (c = *pin++) != '\0' && (isalpha(c) || isdigit(c) || c == '.') && i < 250; i++)
    w[i] = (char)c;
  if (i == 0 && c != '\0')
    w[i++] = (char)c;
  w[i] = '\0';
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   $0x3,%cl
  je     L49
  movslq %ecx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x2,%eax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  cmp    %edx,%ecx
  je     L49
  mov    $0x4a,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L49
  mov    $0x2f,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L49
  mov    $0x1da,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L49
  mov    $0x1bf,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L49
  mov    $0x1dd,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L83
L49:
  lea    D37(%rip),%rdi
  call   <printf@plt>
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L83:
  sub    $0x2e8,%ecx
  cmp    $0x1e,%ecx
  ja     L34
  mov    $0x40000009,%eax
  shr    %cl,%rax
  test   $0x1,%al
  jne    L117
L34:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L46
L117:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  jmp    L46
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string
name: parse_data
arguments: data_tag: D37
type: string
name: parse_data
arguments: data_tag: D12
type: string

tool: D6: %d

tool: D37: YES

tool: D12: NO

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  if (num % 4 == 0 || num % 7 == 0 || num % 74 == 0 || num % 47 == 0 || num % 474 == 0 || num % 447 == 0 || num % 477 == 0)
    printf("YES");
  else if (num == 774 || num == 744 || num == 747)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   $0x3,%cl
  je     L85
  imul   $0xb6db6db7,%ecx,%eax
  add    $0x12492492,%eax
  cmp    $0x24924924,%eax
  ja     L51
L85:
  lea    D16(%rip),%rdi
  call   <printf@plt>
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L51:
  mov    %ecx,%eax
  mov    $0x4a,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L85
  mov    %ecx,%eax
  mov    $0x2f,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L85
  mov    %ecx,%eax
  mov    $0x1da,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L85
  mov    %ecx,%eax
  mov    $0x1bf,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L85
  mov    %ecx,%eax
  mov    $0x1dd,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L85
  sub    $0x2e8,%ecx
  cmp    $0x1e,%ecx
  ja     L21
  mov    $0x40000009,%eax
  shr    %cl,%rax
  test   $0x1,%al
  jne    L85
L21:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D16
type: string
name: extract_symbolic_data
arguments: label: D3
type: string

tool: D17: %d

tool: D16: YES

tool: D3: NO

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  if (num % 4 == 0 || num % 7 == 0 || num % 74 == 0 || num % 47 == 0 || num % 474 == 0 || num % 447 == 0 || num % 477 == 0)
    printf("YES");
  else if (num == 774 || num == 744 || num == 747)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   $0x3,%cl
  je     L39
  imul   $0xb6db6db7,%ecx,%eax
  add    $0x12492492,%eax
  cmp    $0x24924924,%eax
  ja     L28
L39:
  lea    D16(%rip),%rdi
  call   <printf@plt>
L102:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L28:
  mov    %ecx,%eax
  mov    $0x4a,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L39
  mov    %ecx,%eax
  mov    $0x2f,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L39
  mov    %ecx,%eax
  mov    $0x1da,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L39
  mov    %ecx,%eax
  mov    $0x1bf,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L39
  mov    %ecx,%eax
  mov    $0x1dd,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L39
  sub    $0x2e8,%ecx
  cmp    $0x1e,%ecx
  ja     L86
  mov    $0x40000009,%eax
  shr    %cl,%rax
  test   $0x1,%al
  jne    L39
L86:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L102
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type_infered: string
name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D29
type_infered: string

tool: D28: %d

tool: D16: YES

tool: D29: NO

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  if (num % 4 == 0 || num % 7 == 0 || num % 74 == 0 || num % 47 == 0 || num % 474 == 0 || num % 447 == 0 || num % 477 == 0)
    printf("YES");
  else if (num == 774 || num == 744 || num == 747)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L50
L10:
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x20(%rbp),%edx
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x10(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L48
  movss  -0x10(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jne    L48
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  jmp    L7
L48:
  movss  -0x10(%rbp),%xmm0
  addss  -0xc(%rbp),%xmm0
  movss  D23(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x20(%rbp),%edx
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  subss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x14(%rbp),%xmm0
  jbe    L7
  movss  -0x14(%rbp),%xmm0
  movss  D0(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L50:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D40
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: byte[4]
name: disassemble_data
arguments: data_tag: D0
type_infered: byte[4]
name: disassemble_data
arguments: data_tag: D25
type_infered: string

tool: D40: %d

tool: D17: %d%d%d

tool: {"D23": [0x00,0x00,0x00,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x80]}

tool: D25: %0.2f


assistant: ```c
int main() {
  int t;
  int a, b, c;
  float d1, d2, min;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &a, &b, &c);
    d1 = b - a;
    d2 = c - b;
    if (d1 == d2)
      min = 0;
    else {
      min = (d1 + d2) / 2;
      min = b - a - min;
      if (min < 0)
        min = -min;
    }
    printf("%0.2f\n", min);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D47(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L66
  lea    D31(%rip),%rbx
  jmp    L73
L3:
  movaps %xmm2,%xmm0
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L66
L73:
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  mov    %edx,%eax
  sub    0xc(%rsp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mov    0x14(%rsp),%eax
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  ucomiss %xmm0,%xmm1
  jp     L62
  pxor   %xmm2,%xmm2
  je     L3
L62:
  addss  %xmm1,%xmm0
  mulss  D12(%rip),%xmm0
  movaps %xmm1,%xmm2
  subss  %xmm0,%xmm2
  pxor   %xmm3,%xmm3
  comiss %xmm2,%xmm3
  jbe    L3
  xorps  D18(%rip),%xmm2
  jmp    L3
L66:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D47
type_infered: string
name: unpack_data
arguments: data_tag: D31
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D12
type_infered: byte[4]
name: unpack_data
arguments: data_tag: D18
type_infered: byte[16]

tool: D47: %d

tool: D31: %d%d%d

tool: D16: %0.2f


tool: {"D12": [0x00,0x00,0x00,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int t;
  int a, b, c;
  float d1, d2, min;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &a, &b, &c);
    d1 = b - a;
    d2 = c - b;
    if (d1 == d2)
      min = 0;
    else {
      min = (d1 + d2) / 2;
      min = b - a - min;
      if (min < 0)
        min = -min;
    }
    printf("%0.2f\n", min);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D42(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L47
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D19(%rip),%rbp
  lea    D10(%rip),%rbx
  nopl   0x0(%rax)
L44:
  mov    %r13,%rdx
  xor    %eax,%eax
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  mov    %edx,%eax
  sub    0xc(%rsp),%eax
  cvtsi2ss %eax,%xmm2
  mov    0x14(%rsp),%eax
  sub    %edx,%eax
  cvtsi2ss %eax,%xmm0
  ucomiss %xmm0,%xmm2
  jp     L39
  pxor   %xmm1,%xmm1
  je     L32
L39:
  addss  %xmm2,%xmm0
  mulss  D35(%rip),%xmm0
  pxor   %xmm3,%xmm3
  subss  %xmm0,%xmm2
  comiss %xmm2,%xmm3
  movaps %xmm2,%xmm1
  jbe    L32
  xorps  D46(%rip),%xmm1
L32:
  movaps %xmm1,%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L44
L47:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D42
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string
name: disassemble_data
arguments: data_tag: D35
type_infered: byte[4]
name: disassemble_data
arguments: data_tag: D46
type_infered: byte[16]

tool: D42: %d

tool: D19: %d%d%d

tool: D10: %0.2f


tool: {"D35": [0x00,0x00,0x00,0x3f]}

tool: {"D46": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int t;
  int a, b, c;
  float d1, d2, min;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &a, &b, &c);
    d1 = b - a;
    d2 = c - b;
    if (d1 == d2)
      min = 0;
    else {
      min = (d1 + d2) / 2;
      min = b - a - min;
      if (min < 0)
        min = -min;
    }
    printf("%0.2f\n", min);
  }
  return 0;
}
```