ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PendingBoundary>:
  endbr64
  cmpb   $0x2d,(%rdi)
  je     L60
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L60:
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  cmpb   $0x2d,0x1(%rdi)
  jne    L58
  mov    (%rdx),%eax
  mov    %rdx,%r13
  test   %eax,%eax
  jle    L58
  mov    %rsi,%r14
  xor    %ebx,%ebx
  jmp    L27
  nopl   0x0(%rax)
L84:
  add    $0x1,%rbx
  cmp    %ebx,0x0(%r13)
  jle    L58
L27:
  mov    (%r14,%rbx,8),%rdi
  call   <strlen@plt>
  mov    (%r14,%rbx,8),%rsi
  mov    %r12,%rdi
  movslq %eax,%rbp
  mov    %ebp,%edx
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L84
  cmpb   $0x2d,(%r12,%rbp,1)
  mov    $0x1,%eax
  jne    L38
  cmpb   $0x2d,0x1(%r12,%rbp,1)
  jne    L38
  mov    %ebx,0x0(%r13)
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L58:
  xor    %eax,%eax
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int PendingBoundary(char *s, char **Boundaries, int *BoundaryCt) {
  int i, len;
  if (s[0] != '-' || s[1] != '-')
    return (0);
  for (i = 0; i < *BoundaryCt; ++i) {
    len = strlen(Boundaries[i]);
    if (!strncmp(s, Boundaries[i], len)) {
      if (s[len] == '-' && s[len + 1] == '-')
        *BoundaryCt = i;
      return (1);
    }
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
L7:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L4:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L4
L0:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L7
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D15
data_type: string

tool: D12: Inserisci un'intero non una stringa!


tool: D15: %d

assistant: ```c
void input(int *c, char *text) {
  printf(text);
  while (scanf("%d", c) != 1) {
    printf("Inserisci un'intero non una stringa!\n");
    printf(text);
    while (getchar() != '\n')
      ;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<input>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <printf@plt>
  lea    D2(%rip),%r12
  lea    D4(%rip),%r13
  jmp    L7
L26:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L9
L7:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L26
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string
name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D2: %d

tool: D4: Inserisci un'intero non una stringa!


assistant: ```c
void input(int *c, char *text) {
  printf(text);
  while (scanf("%d", c) != 1) {
    printf("Inserisci un'intero non una stringa!\n");
    printf(text);
    while (getchar() != '\n')
      ;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<input>:
  endbr64
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L13
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
L17:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L17
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L4
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string

tool: D11: Inserisci un'intero non una stringa!


tool: D18: %d

assistant: ```c
void input(int *c, char *text) {
  printf(text);
  while (scanf("%d", c) != 1) {
    printf("Inserisci un'intero non una stringa!\n");
    printf(text);
    while (getchar() != '\n')
      ;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<input>:
  endbr64
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L0
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
L23:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L23
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L22
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
data_type: string
name: unpack_data
arguments: label: D19
data_type: string

tool: D16: Inserisci un'intero non una stringa!


tool: D19: %d

assistant: ```c
void input(int *c, char *text) {
  printf(text);
  while (scanf("%d", c) != 1) {
    printf("Inserisci un'intero non una stringa!\n");
    printf(text);
    while (getchar() != '\n')
      ;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<log_set_level>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <log_set_level_fp@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <log_set_level_stderr@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_set_level(int level) {
  log_set_level_fp(level);
  log_set_level_stderr(level);
}
```
user: What is the c source code of the assembly code below?

```asm
<log_set_level>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <log_set_level_fp@plt>
  mov    %ebx,%edi
  call   <log_set_level_stderr@plt>
  pop    %rbx
  ret
```

assistant: ```c
void log_set_level(int level) {
  log_set_level_fp(level);
  log_set_level_stderr(level);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_set_level>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <log_set_level_fp@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <log_set_level_stderr@plt>
```

assistant: ```c
void log_set_level(int level) {
  log_set_level_fp(level);
  log_set_level_stderr(level);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utest_adts_trie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <utest_control@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void utest_adts_trie(void) {
  utest_control();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utest_adts_trie>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <utest_control@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void utest_adts_trie(void) {
  utest_control();
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<utest_adts_trie>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <utest_control@plt>
```

assistant: ```c
void utest_adts_trie(void) {
  utest_control();
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<utest_adts_trie>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <utest_control@plt>
```

assistant: ```c
void utest_adts_trie(void) {
  utest_control();
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_power_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L23
  mov    $0x1,%eax
  jmp    L36
L23:
  cmpl   $0x0,-0xc(%rbp)
  jns    L0
  mov    $0x0,%eax
  jmp    L36
L0:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_power_s>
  imul   -0x8(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
size_t ft_power_s(size_t nb, int power) {
  if (power == 0)
    return (1);
  if (power < 0)
    return (0);
  return (nb * ft_power_s(nb, power - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_power_s>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L1
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  js     L19
  sub    $0x1,%esi
  call   <ft_power_s>
  imul   %rbx,%rax
L19:
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
size_t ft_power_s(size_t nb, int power) {
  if (power == 0)
    return (1);
  if (power < 0)
    return (0);
  return (nb * ft_power_s(nb, power - 1));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_power_s>:
  endbr64
  test   %esi,%esi
  je     L15
  js     L23
  mov    $0x1,%eax
  nop
L12:
  imul   %rdi,%rax
  sub    $0x1,%esi
  jne    L12
  ret
L15:
  mov    $0x1,%eax
  ret
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t ft_power_s(size_t nb, int power) {
  if (power == 0)
    return (1);
  if (power < 0)
    return (0);
  return (nb * ft_power_s(nb, power - 1));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_power_s>:
  endbr64
  test   %esi,%esi
  je     L20
  js     L14
  mov    $0x1,%eax
  nop
L28:
  imul   %rdi,%rax
  sub    $0x1,%esi
  jne    L28
  ret
L20:
  mov    $0x1,%eax
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t ft_power_s(size_t nb, int power) {
  if (power == 0)
    return (1);
  if (power < 0)
    return (0);
  return (nb * ft_power_s(nb, power - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L47
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L17
L47:
  cmpl   $0x2,-0x4(%rbp)
  jne    L49
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  cmp    $0x1,%eax
  jne    L32
  mov    $0x0,%eax
  call   <p1@plt>
  jmp    L17
L32:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L17
L49:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type: string
name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D10: Expecting at least one argument. Please try again


tool: D20: Incorrect argument supplied.


tool: D1: Expecting only one argument


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("Expecting at least one argument. Please try again\n");
  } else if (argc == 2) {
    if (atoi(argv[1]) == 1) {
      p1();
    } else {
      printf("Incorrect argument supplied.\n");
    }
  } else {
    printf("Expecting only one argument\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L21
  cmp    $0x2,%edi
  je     L26
  lea    D19(%rip),%rdi
  call   <printf@plt>
L41:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L21:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L26:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  cmp    $0x1,%eax
  je     L1
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L1:
  mov    $0x0,%eax
  call   <p1@plt>
  jmp    L41
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D19: Expecting only one argument


tool: D7: Expecting at least one argument. Please try again


tool: D6: Incorrect argument supplied.


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("Expecting at least one argument. Please try again\n");
  } else if (argc == 2) {
    if (atoi(argv[1]) == 1) {
      p1();
    } else {
      printf("Incorrect argument supplied.\n");
    }
  } else {
    printf("Expecting only one argument\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L37
  cmp    $0x2,%edi
  je     L35
  lea    D28(%rip),%rdi
  call   <printf@plt>
L30:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L35:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  sub    $0x1,%eax
  je     L12
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L37:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L12:
  xor    %eax,%eax
  call   <p1@plt>
  jmp    L30
```

tool_calls: name: unpack_data
arguments: data_label: D28
type_guessed: string
name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D21
type_guessed: string

tool: D28: Expecting only one argument


tool: D8: Incorrect argument supplied.


tool: D21: Expecting at least one argument. Please try again


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("Expecting at least one argument. Please try again\n");
  } else if (argc == 2) {
    if (atoi(argv[1]) == 1) {
      p1();
    } else {
      printf("Incorrect argument supplied.\n");
    }
  } else {
    printf("Expecting only one argument\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L13
  cmp    $0x2,%edi
  je     L59
  lea    D29(%rip),%rdi
  call   <printf@plt>
L58:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L59:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  sub    $0x1,%eax
  je     L2
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L58
L13:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L58
L2:
  xor    %eax,%eax
  call   <p1@plt>
  jmp    L58
```

tool_calls: name: read_data
arguments: data_tag: D29
type_infered: string
name: read_data
arguments: data_tag: D20
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string

tool: D29: Expecting only one argument


tool: D20: Incorrect argument supplied.


tool: D5: Expecting at least one argument. Please try again


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("Expecting at least one argument. Please try again\n");
  } else if (argc == 2) {
    if (atoi(argv[1]) == 1) {
      p1();
    } else {
      printf("Incorrect argument supplied.\n");
    }
  } else {
    printf("Expecting only one argument\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_func_00>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  subq   $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *test_func_00(float *p, float c) {
  *--p = c;
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_func_00>:
  endbr64
  movss  %xmm0,-0x4(%rdi)
  lea    -0x4(%rdi),%rax
  ret
```

assistant: ```c
float *test_func_00(float *p, float c) {
  *--p = c;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_func_00>:
  endbr64
  movss  %xmm0,-0x4(%rdi)
  lea    -0x4(%rdi),%rax
  ret
```

assistant: ```c
float *test_func_00(float *p, float c) {
  *--p = c;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_func_00>:
  endbr64
  movss  %xmm0,-0x4(%rdi)
  lea    -0x4(%rdi),%rax
  ret
```

assistant: ```c
float *test_func_00(float *p, float c) {
  *--p = c;
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L29
L41:
  mov    -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    $0x61,%eax
  or     %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L29:
  cmpl   $0x3,-0x14(%rbp)
  jbe    L41
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L48
L38:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L48:
  cmpl   $0x3,-0x14(%rbp)
  jbe    L38
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: %u


assistant: ```c
int main(void) {
  unsigned num;
  unsigned i;
  void *ptr;
  num = 0;
  for (i = 0; i < sizeof(int); i++)
    num = (num << 8) | ('a' + i);
  ptr = (void *)&num;
  printf("%u\n", num);
  for (i = 0; i < sizeof(int); i++)
    printf("%c", ((char *)ptr)[i]);
  printf("\n");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x61626364,0x4(%rsp)
  mov    $0x61626364,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rbx
  lea    0x8(%rsp),%rbp
L12:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: %u


assistant: ```c
int main(void) {
  unsigned num;
  unsigned i;
  void *ptr;
  num = 0;
  for (i = 0; i < sizeof(int); i++)
    num = (num << 8) | ('a' + i);
  ptr = (void *)&num;
  printf("%u\n", num);
  for (i = 0; i < sizeof(int); i++)
    printf("%c", ((char *)ptr)[i]);
  printf("\n");
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x61626364,%esi
  lea    D2(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x8(%rsp),%rbp
  movl   $0x61626364,0x4(%rsp)
  call   <printf@plt>
L10:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: %u


assistant: ```c
int main(void) {
  unsigned num;
  unsigned i;
  void *ptr;
  num = 0;
  for (i = 0; i < sizeof(int); i++)
    num = (num << 8) | ('a' + i);
  ptr = (void *)&num;
  printf("%u\n", num);
  for (i = 0; i < sizeof(int); i++)
    printf("%c", ((char *)ptr)[i]);
  printf("\n");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x61626364,%esi
  lea    D4(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x8(%rsp),%rbp
  movl   $0x61626364,0x4(%rsp)
  call   <printf@plt>
L6:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: %u


assistant: ```c
int main(void) {
  unsigned num;
  unsigned i;
  void *ptr;
  num = 0;
  for (i = 0; i < sizeof(int); i++)
    num = (num << 8) | ('a' + i);
  ptr = (void *)&num;
  printf("%u\n", num);
  for (i = 0; i < sizeof(int); i++)
    printf("%c", ((char *)ptr)[i]);
  printf("\n");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scan_complex_interpolation_points>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L29
L7:
  addq   $0x1,-0x10(%rbp)
L63:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L7
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L55
  jmp    L60
L58:
  addq   $0x1,-0x10(%rbp)
L60:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L58
L55:
  addl   $0x1,-0x1c(%rbp)
L29:
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L63
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: %lf

assistant: ```c
int scan_complex_interpolation_points(int n, char *points, double *cff) {
  int i;
  double c;
  char *ptr;
  ptr = points;
  for (i = 0; i < 2 * n; i++) {
    while (*ptr == ' ')
      ptr++;
    sscanf(&ptr[0], "%lf", &c);
    cff[i] = c;
    if (i < 2 * n - 1)
      while (*ptr != ' ')
        ptr++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<scan_complex_interpolation_points>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    (%rdi,%rdi,1),%r12d
  test   %r12d,%r12d
  jle    L98
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %r12d,%r15d
  mov    $0x0,%ebp
  lea    D5(%rip),%r14
  jmp    L11
L47:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  jne    L47
L74:
  add    $0x1,%rbp
  cmp    %rbp,%r15
  je     L98
L11:
  cmpb   $0x20,(%rbx)
  jne    L26
L57:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L57
L26:
  mov    %rsp,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x0(%r13,%rbp,8)
  lea    -0x1(%r12),%eax
  cmp    %ebp,%eax
  jle    L74
  cmpb   $0x20,(%rbx)
  jne    L47
  jmp    L74
L98:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: %lf

assistant: ```c
int scan_complex_interpolation_points(int n, char *points, double *cff) {
  int i;
  double c;
  char *ptr;
  ptr = points;
  for (i = 0; i < 2 * n; i++) {
    while (*ptr == ' ')
      ptr++;
    sscanf(&ptr[0], "%lf", &c);
    cff[i] = c;
    if (i < 2 * n - 1)
      while (*ptr != ' ')
        ptr++;
  }
  return 0;
}
```