ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x28(%rsp),%rbx
  mov    %rbp,%r12
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L22
  lea    0x24(%rbp),%rsi
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rax
  nopl   0x0(%rax,%rax,1)
L32:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L1
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L1:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L32
  lea    -0x4(%rax),%rsi
  cmp    %rbp,%rsi
  jne    L9
  lea    D2(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L11:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L11
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string

tool: D2: %d	

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10, i, j, a[10];
  int temp = 0;
  for (i = 0; i < n; i++)
    a[i] = rand() % 100;
  for (i = 0; i < n - 1; i++)
    for (j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
  for (i = 0; i < n; i++)
    printf("%d\t", a[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<exm_str_append_with_quotes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L7
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x22,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x22,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L39
L36:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x22,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  lea    0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x22,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  lea    0x3(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L39
L7:
  nop
L39:
  leave
  ret
```

assistant: ```c
void exm_str_append_with_quotes(char *buf, const char *str) {
  if (!str)
    return;
  if (!*buf) {
    size_t l;
    l = strlen(str);
    buf[0] = '\"';
    memcpy(buf + 1, str, l);
    buf[l + 1] = '\"';
    buf[l + 2] = '\0';
  } else {
    size_t l1;
    size_t l2;
    l1 = strlen(buf);
    l2 = strlen(str);
    buf[l1] = ' ';
    buf[l1 + 1] = '\"';
    memcpy(buf + l1 + 2, str, l2);
    buf[l1 + l2 + 2] = '\"';
    buf[l1 + l2 + 3] = '\0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<exm_str_append_with_quotes>:
  endbr64
  test   %rsi,%rsi
  je     L1
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x0,(%rdi)
  jne    L28
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  movb   $0x22,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    %rax,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movb   $0x22,0x1(%rbx,%r12,1)
  movb   $0x0,0x2(%rbx,%r12,1)
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  movb   $0x20,(%rbx,%r12,1)
  movb   $0x22,0x1(%rbx,%r12,1)
  lea    0x2(%rbx,%r12,1),%rdi
  mov    %rax,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  add    %r13,%r12
  movb   $0x22,0x2(%rbx,%r12,1)
  movb   $0x0,0x3(%rbx,%r12,1)
  jmp    L25
L1:
  ret
```

assistant: ```c
void exm_str_append_with_quotes(char *buf, const char *str) {
  if (!str)
    return;
  if (!*buf) {
    size_t l;
    l = strlen(str);
    buf[0] = '\"';
    memcpy(buf + 1, str, l);
    buf[l + 1] = '\"';
    buf[l + 2] = '\0';
  } else {
    size_t l1;
    size_t l2;
    l1 = strlen(buf);
    l2 = strlen(str);
    buf[l1] = ' ';
    buf[l1 + 1] = '\"';
    memcpy(buf + l1 + 2, str, l2);
    buf[l1 + l2 + 2] = '\"';
    buf[l1 + l2 + 3] = '\0';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<exm_str_append_with_quotes>:
  endbr64
  test   %rsi,%rsi
  je     L16
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  mov    %rax,%r12
  je     L2
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movb   $0x20,(%rbx,%rax,1)
  mov    %rax,%r13
  lea    0x2(%rbx,%rax,1),%rdi
  movb   $0x22,0x1(%rbx,%rax,1)
  add    %r12,%r13
  call   <memcpy@plt>
  movb   $0x22,0x2(%rbx,%r13,1)
  movb   $0x0,0x3(%rbx,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  movb   $0x22,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    %rbp,%rsi
  mov    %rax,%rdx
  call   <memcpy@plt>
  movb   $0x22,0x1(%rbx,%r12,1)
  movb   $0x0,0x2(%rbx,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L16:
  ret
```

assistant: ```c
void exm_str_append_with_quotes(char *buf, const char *str) {
  if (!str)
    return;
  if (!*buf) {
    size_t l;
    l = strlen(str);
    buf[0] = '\"';
    memcpy(buf + 1, str, l);
    buf[l + 1] = '\"';
    buf[l + 2] = '\0';
  } else {
    size_t l1;
    size_t l2;
    l1 = strlen(buf);
    l2 = strlen(str);
    buf[l1] = ' ';
    buf[l1 + 1] = '\"';
    memcpy(buf + l1 + 2, str, l2);
    buf[l1 + l2 + 2] = '\"';
    buf[l1 + l2 + 3] = '\0';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<exm_str_append_with_quotes>:
  endbr64
  test   %rsi,%rsi
  je     L13
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  mov    %rax,%r12
  je     L3
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movb   $0x20,(%rbx,%rax,1)
  mov    %rax,%r13
  lea    0x2(%rbx,%rax,1),%rdi
  movb   $0x22,0x1(%rbx,%rax,1)
  add    %r12,%r13
  call   <memcpy@plt>
  movb   $0x22,0x2(%rbx,%r13,1)
  movb   $0x0,0x3(%rbx,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movb   $0x22,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    %rbp,%rsi
  mov    %rax,%rdx
  call   <memcpy@plt>
  movb   $0x22,0x1(%rbx,%r12,1)
  movb   $0x0,0x2(%rbx,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  ret
```

assistant: ```c
void exm_str_append_with_quotes(char *buf, const char *str) {
  if (!str)
    return;
  if (!*buf) {
    size_t l;
    l = strlen(str);
    buf[0] = '\"';
    memcpy(buf + 1, str, l);
    buf[l + 1] = '\"';
    buf[l + 2] = '\0';
  } else {
    size_t l1;
    size_t l2;
    l1 = strlen(buf);
    l2 = strlen(str);
    buf[l1] = ' ';
    buf[l1 + 1] = '\"';
    memcpy(buf + l1 + 2, str, l2);
    buf[l1 + l2 + 2] = '\"';
    buf[l1 + l2 + 3] = '\0';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1983,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int par0 = 0x1983;
  foo(par0);
  return par0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1983,%edi
  call   <foo@plt>
  mov    $0x1983,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int par0 = 0x1983;
  foo(par0);
  return par0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1983,%edi
  call   <foo@plt>
  mov    $0x1983,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int par0 = 0x1983;
  foo(par0);
  return par0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1983,%edi
  call   <foo@plt>
  mov    $0x1983,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int par0 = 0x1983;
  foo(par0);
  return par0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pultoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %edx,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  cmpl   $0x24,-0x64(%rbp)
  jg     L38
  cmpl   $0x1,-0x64(%rbp)
  jg     L49
L38:
  mov    $0x0,%eax
  jmp    L17
L23:
  mov    -0x64(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x48(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x64(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x48(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x48(%rbp)
  cmpq   $0x9,-0x38(%rbp)
  jg     L28
  mov    -0x38(%rbp),%rax
  lea    0x30(%rax),%ecx
  mov    -0x50(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x50(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L49
L28:
  mov    -0x38(%rbp),%rax
  lea    0x57(%rax),%ecx
  mov    -0x50(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x50(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L49:
  cmpq   $0x0,-0x48(%rbp)
  jne    L23
  lea    -0x30(%rbp),%rax
  cmp    %rax,-0x50(%rbp)
  je     L23
  cmpq   $0x0,-0x60(%rbp)
  jne    L41
  lea    -0x30(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  sub    %rdx,%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x60(%rbp)
L41:
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  jmp    L81
L78:
  subq   $0x1,-0x50(%rbp)
  mov    -0x40(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  mov    -0x50(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L81:
  lea    -0x30(%rbp),%rax
  cmp    %rax,-0x50(%rbp)
  ja     L78
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x60(%rbp),%rax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
char *pultoa(unsigned long value, char *string, int base) {
  char tmp[33];
  char *tp = tmp;
  long i;
  unsigned long v = value;
  char *sp;
  if (base > 36 || base <= 1)
    return 0;
  while (v || tp == tmp) {
    i = v % base;
    v = v / base;
    if (i < 10)
      *tp++ = i + '0';
    else
      *tp++ = i + 'a' - 10;
  }
  if (string == 0)
    string = (char *)malloc((tp - tmp) + 1);
  sp = string;
  while (tp > tmp)
    *sp++ = *--tp;
  *sp = 0;
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pultoa>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x38(%rsp)
  xor    %ecx,%ecx
  lea    -0x2(%rdx),%ecx
  cmp    $0x22,%ecx
  ja     L52
  mov    %rdi,%rax
  mov    %rsi,%r8
  lea    0x11(%rsp),%rcx
  movslq %edx,%rsi
  lea    0x10(%rsp),%r9
L61:
  mov    %rax,%rdi
  mov    $0x0,%edx
  div    %rsi
  cmp    $0x9,%rdx
  jg     L95
  mov    %rcx,%rbx
  add    $0x30,%edx
L93:
  mov    %dl,-0x1(%rcx)
  add    $0x1,%rcx
  cmp    %r9,%rbx
  je     L61
  cmp    %rdi,%rsi
  jbe    L61
  test   %r8,%r8
  je     L47
L46:
  lea    0x10(%rsp),%rax
  cmp    %rax,%rbx
  jbe    L71
  mov    %r8,%rdx
  mov    %rbx,%rax
  lea    0x10(%rsp),%rsi
L25:
  sub    $0x1,%rax
  add    $0x1,%rdx
  movzbl (%rax),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rax
  jne    L25
  lea    0x40(%rsp),%rax
  sub    %rax,%rbx
  lea    0x30(%rbx,%r8,1),%rax
L103:
  movb   $0x0,(%rax)
  mov    %r8,%rax
L74:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x40,%rsp
  pop    %rbx
  ret
L95:
  mov    %rcx,%rbx
  add    $0x57,%edx
  jmp    L93
L47:
  lea    0x40(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %ebx,%eax
  sub    0x8(%rsp),%eax
  lea    0x31(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  jmp    L46
L71:
  mov    %r8,%rax
  jmp    L103
L52:
  mov    $0x0,%eax
  jmp    L74
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *pultoa(unsigned long value, char *string, int base) {
  char tmp[33];
  char *tp = tmp;
  long i;
  unsigned long v = value;
  char *sp;
  if (base > 36 || base <= 1)
    return 0;
  while (v || tp == tmp) {
    i = v % base;
    v = v / base;
    if (i < 10)
      *tp++ = i + '0';
    else
      *tp++ = i + 'a' - 10;
  }
  if (string == 0)
    string = (char *)malloc((tp - tmp) + 1);
  sp = string;
  while (tp > tmp)
    *sp++ = *--tp;
  *sp = 0;
  return string;
}
```
user: What is the c source code of the assembly code below:

```asm
<pultoa>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x28(%rsp)
  xor    %ecx,%ecx
  lea    -0x2(%rdx),%ecx
  cmp    $0x22,%ecx
  ja     L65
  mov    %rsp,%r12
  mov    %rdi,%rax
  mov    %rsi,%r8
  movslq %edx,%rcx
  mov    %r12,%rbp
  nopw   0x0(%rax,%rax,1)
L96:
  xor    %edx,%edx
  mov    %rax,%rsi
  add    $0x1,%rbp
  div    %rcx
  lea    0x30(%rdx),%edi
  lea    0x57(%rdx),%ebx
  cmp    $0x9,%rdx
  cmovbe %edi,%ebx
  mov    %bl,-0x1(%rbp)
  cmp    %rsi,%rcx
  jbe    L96
  cmp    %r12,%rbp
  je     L96
  test   %r8,%r8
  je     L29
L68:
  cmp    %r12,%rbp
  jbe    L10
  mov    %r8,%rdx
  mov    %rbp,%rax
  jmp    L100
  nopl   0x0(%rax,%rax,1)
L25:
  movzbl -0x1(%rax),%ebx
L100:
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %bl,-0x1(%rdx)
  cmp    %r12,%rax
  jne    L25
  sub    %rax,%rbp
  add    %r8,%rbp
L95:
  movb   $0x0,0x0(%rbp)
  mov    %r8,%rax
L31:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  xor    %eax,%eax
  jmp    L31
L29:
  mov    %rbp,%rdi
  sub    %r12,%rdi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  jmp    L68
L10:
  mov    %r8,%rbp
  jmp    L95
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *pultoa(unsigned long value, char *string, int base) {
  char tmp[33];
  char *tp = tmp;
  long i;
  unsigned long v = value;
  char *sp;
  if (base > 36 || base <= 1)
    return 0;
  while (v || tp == tmp) {
    i = v % base;
    v = v / base;
    if (i < 10)
      *tp++ = i + '0';
    else
      *tp++ = i + 'a' - 10;
  }
  if (string == 0)
    string = (char *)malloc((tp - tmp) + 1);
  sp = string;
  while (tp > tmp)
    *sp++ = *--tp;
  *sp = 0;
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pultoa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    -0x2(%rdx),%eax
  cmp    $0x22,%eax
  ja     L22
  mov    %rsp,%rbp
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  movslq %edx,%rsi
  mov    %rbp,%rbx
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L132:
  add    $0x30,%edx
  mov    %dl,-0x1(%rbx)
  cmp    %rsi,%rcx
  jae    L125
  cmp    %rbp,%rbx
  jne    L18
L125:
  mov    %rax,%rcx
L81:
  mov    %rcx,%rax
  xor    %edx,%edx
  add    $0x1,%rbx
  div    %rsi
  cmp    $0x9,%rdx
  jbe    L132
  add    $0x57,%edx
  mov    %dl,-0x1(%rbx)
  cmp    %rsi,%rcx
  jae    L125
  cmp    %rbp,%rbx
  je     L125
L18:
  test   %rdi,%rdi
  je     L113
L126:
  cmp    %rbp,%rbx
  jbe    L5
  mov    %rdi,%rdx
  mov    %rbx,%rax
  nopl   (%rax)
L65:
  movzbl -0x1(%rax),%ecx
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rbp,%rax
  jne    L65
  sub    %rax,%rbx
  add    %rdi,%rbx
L88:
  movb   $0x0,(%rbx)
  mov    %rdi,%rax
L41:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L134
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L22:
  xor    %eax,%eax
  jmp    L41
L113:
  mov    %rbx,%rdi
  sub    %rbp,%rdi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  jmp    L126
L5:
  mov    %rdi,%rbx
  jmp    L88
L134:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *pultoa(unsigned long value, char *string, int base) {
  char tmp[33];
  char *tp = tmp;
  long i;
  unsigned long v = value;
  char *sp;
  if (base > 36 || base <= 1)
    return 0;
  while (v || tp == tmp) {
    i = v % base;
    v = v / base;
    if (i < 10)
      *tp++ = i + '0';
    else
      *tp++ = i + 'a' - 10;
  }
  if (string == 0)
    string = (char *)malloc((tp - tmp) + 1);
  sp = string;
  while (tp > tmp)
    *sp++ = *--tp;
  *sp = 0;
  return string;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<posdir_outside_of_sphere>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <distance_posdir_point@plt>
  test   %rax,%rax
  je     L20
  mov    $0xffffffff,%eax
  jmp    L47
L20:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jbe    L39
  mov    $0x1,%eax
  jmp    L47
L39:
  mov    $0x0,%eax
L47:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
int posdir_outside_of_sphere(double *position, double *direction, double *center, double radius) {
  double distance;
  if (distance_posdir_point(position, direction, center, &distance))
    return -1;
  if (distance > radius)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<posdir_outside_of_sphere>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <distance_posdir_point@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  jne    L16
  movsd  (%rsp),%xmm0
  movq   %rbx,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int posdir_outside_of_sphere(double *position, double *direction, double *center, double radius) {
  double distance;
  if (distance_posdir_point(position, direction, center, &distance))
    return -1;
  if (distance > radius)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<posdir_outside_of_sphere>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <distance_posdir_point@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  jne    L16
  xor    %eax,%eax
  movsd  0x10(%rsp),%xmm0
  comisd 0x8(%rsp),%xmm0
  seta   %al
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int posdir_outside_of_sphere(double *position, double *direction, double *center, double radius) {
  double distance;
  if (distance_posdir_point(position, direction, center, &distance))
    return -1;
  if (distance > radius)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<posdir_outside_of_sphere>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <distance_posdir_point@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  jne    L5
  xor    %eax,%eax
  movsd  0x10(%rsp),%xmm0
  comisd 0x8(%rsp),%xmm0
  seta   %al
L5:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x28,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int posdir_outside_of_sphere(double *position, double *direction, double *center, double radius) {
  double distance;
  if (distance_posdir_point(position, direction, center, &distance))
    return -1;
  if (distance > radius)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__unlink>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <real_unlink@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gendep__register_unlink@plt>
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __unlink(const char *fn) {
  int rv;
  if (0)
    printf("unlink(%s)\n", fn);
  rv = real_unlink(fn);
  if (rv >= 0)
    gendep__register_unlink(fn);
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__unlink>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <real_unlink@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L17
L6:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %rbp,%rdi
  call   <gendep__register_unlink@plt>
  jmp    L6
```

assistant: ```c
int __unlink(const char *fn) {
  int rv;
  if (0)
    printf("unlink(%s)\n", fn);
  rv = real_unlink(fn);
  if (rv >= 0)
    gendep__register_unlink(fn);
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__unlink>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <real_unlink@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L8
  mov    %rbp,%rdi
  call   <gendep__register_unlink@plt>
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __unlink(const char *fn) {
  int rv;
  if (0)
    printf("unlink(%s)\n", fn);
  rv = real_unlink(fn);
  if (rv >= 0)
    gendep__register_unlink(fn);
  return rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__unlink>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <real_unlink@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L9
  mov    %rbp,%rdi
  call   <gendep__register_unlink@plt>
L9:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __unlink(const char *fn) {
  int rv;
  if (0)
    printf("unlink(%s)\n", fn);
  rv = real_unlink(fn);
  if (rv >= 0)
    gendep__register_unlink(fn);
  return rv;
}
```