ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<upc_e_to_a>:
  endbr64
  push   %r12
  mov    $0x20,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L59
  sub    %ebp,%eax
L62:
  cmp    $0x7,%eax
  je     L20
  cmp    $0x8,%eax
  je     L37
  xor    %r8d,%r8d
  cmp    $0x6,%eax
  je     L80
L46:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L20:
  movzbl 0x0(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x1,%al
  jbe    L102
  mov    %rbp,%rdi
  lea    D47(%rip),%r12
  call   <upc_e_to_a0@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <ean_make_checksum@plt>
  mov    %eax,%r8d
  movzbl 0x6(%rbp),%eax
  sub    $0x30,%eax
  cmp    %r8d,%eax
  jne    L0
L98:
  lea    D47(%rip),%r8
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
L80:
  mov    %rbp,%rdi
  lea    D47(%rip),%rbp
  call   <upc_e_to_a0@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %rbp,%r8
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L37:
  movzbl 0x0(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x1,%al
  jbe    L87
L0:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L87:
  lea    0x1(%rbp),%rdi
  lea    D47(%rip),%r12
  call   <upc_e_to_a0@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  movzbl 0x0(%rbp),%eax
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %al,D3(%rip)
  call   <ean_make_checksum@plt>
  mov    %eax,%r8d
  movzbl 0x7(%rbp),%eax
  sub    $0x30,%eax
  cmp    %r8d,%eax
  jne    L0
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L102:
  lea    0x1(%rbp),%rdi
  lea    D3(%rip),%rbx
  call   <upc_e_to_a0@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  movzbl 0x0(%rbp),%eax
  mov    %rbx,%r8
  mov    %al,D3(%rip)
  jmp    L46
  nopl   0x0(%rax)
L59:
  mov    %rbp,%rdi
  call   <strlen@plt>
  jmp    L62
```

assistant: ```c
char *upc_e_to_a(unsigned char *text) {
  static unsigned char result[16], *spc;
  int len, chk;
  spc = strchr(text, ' ');
  if (spc)
    len = spc - text;
  else
    len = strlen(text);
  switch (len) {
  case 6:
    strcpy(result, upc_e_to_a0(text));
    return result;
  case 7:
    if (text[0] == '0' || text[0] == '1') {
      strcpy(result, upc_e_to_a0(text + 1));
      result[0] = text[0];
      return result;
    }
    strcpy(result, upc_e_to_a0(text));
    chk = ean_make_checksum(result, 0);
    if (chk == (text[len - 1] - '0'))
      return result;
    return NULL;
  case 8:
    if (text[0] == '0' || text[0] == '1') {
      strcpy(result, upc_e_to_a0(text + 1));
      result[0] = text[0];
      chk = ean_make_checksum(result, 0);
      if (chk == (text[len - 1] - '0'))
        return result;
    }
  default:
    return NULL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  jmp    L128
L123:
  addl   $0x1,-0xc(%rbp)
L128:
  cmpl   $0x5,-0xc(%rbp)
  jne    L123
  cmpl   $0x5,-0xc(%rbp)
  je     L52
  mov    $0x1,%eax
  jmp    L29
L52:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L67
L120:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L67:
  cmpl   $0x5,-0xc(%rbp)
  jne    L120
  cmpl   $0x5,-0xc(%rbp)
  je     L62
  mov    $0x2,%eax
  jmp    L29
L62:
  cmpl   $0xa,-0x8(%rbp)
  je     L48
  mov    $0x3,%eax
  jmp    L29
L86:
  mov    $0x4,%eax
  jmp    L29
L48:
  nop
  cmpl   $0x64,-0x8(%rbp)
  je     L86
  movl   $0x0,-0x4(%rbp)
  jmp    L69
L82:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L69
  mov    $0x5,%eax
  jmp    L29
L69:
  cmpl   $0xa,-0x8(%rbp)
  je     L82
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 0;
  while (a != 5)
    a = a + 1;
  if (a != 5)
    return 1;
  int b = 0;
  a = 0;
  while (a != 5) {
    b = b + a;
    a = a + 1;
  }
  if (a != 5)
    return 2;
  if (b != 10)
    return 3;
  while (b == 100)
    return 4;
  int num_times_run = 0;
  while (b == 10) {
    b = b + 1;
    num_times_run = num_times_run + 1;
    if (num_times_run != 1) {
      return 5;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  while (a != 5)
    a = a + 1;
  if (a != 5)
    return 1;
  int b = 0;
  a = 0;
  while (a != 5) {
    b = b + a;
    a = a + 1;
  }
  if (a != 5)
    return 2;
  if (b != 10)
    return 3;
  while (b == 100)
    return 4;
  int num_times_run = 0;
  while (b == 10) {
    b = b + 1;
    num_times_run = num_times_run + 1;
    if (num_times_run != 1) {
      return 5;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  while (a != 5)
    a = a + 1;
  if (a != 5)
    return 1;
  int b = 0;
  a = 0;
  while (a != 5) {
    b = b + a;
    a = a + 1;
  }
  if (a != 5)
    return 2;
  if (b != 10)
    return 3;
  while (b == 100)
    return 4;
  int num_times_run = 0;
  while (b == 10) {
    b = b + 1;
    num_times_run = num_times_run + 1;
    if (num_times_run != 1) {
      return 5;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  while (a != 5)
    a = a + 1;
  if (a != 5)
    return 1;
  int b = 0;
  a = 0;
  while (a != 5) {
    b = b + a;
    a = a + 1;
  }
  if (a != 5)
    return 2;
  if (b != 10)
    return 3;
  while (b == 100)
    return 4;
  int num_times_run = 0;
  while (b == 10) {
    b = b + 1;
    num_times_run = num_times_run + 1;
    if (num_times_run != 1) {
      return 5;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <serial_puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string

tool: D7: Is the serial working?


tool: D14: Hello from userland!


assistant: ```c
int main(int argc, char **argv) {
  puts("Is the serial working?\n");
  serial_puts("Hello from userland!\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  call   <serial_puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D11: Is the serial working?


tool: D3: Hello from userland!


assistant: ```c
int main(int argc, char **argv) {
  puts("Is the serial working?\n");
  serial_puts("Hello from userland!\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D10(%rip),%rdi
  call   <serial_puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D12
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D12: Is the serial working?


tool: D10: Hello from userland!


assistant: ```c
int main(int argc, char **argv) {
  puts("Is the serial working?\n");
  serial_puts("Hello from userland!\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D6(%rip),%rdi
  call   <serial_puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string

tool: D5: Is the serial working?


tool: D6: Hello from userland!


assistant: ```c
int main(int argc, char **argv) {
  puts("Is the serial working?\n");
  serial_puts("Hello from userland!\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <help@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int usage() {
  help();
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <help@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int usage() {
  help();
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <help@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int usage() {
  help();
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <help@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int usage() {
  help();
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    $0x0,%edi
  call   <srand@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L18:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L18
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void fill_random(unsigned char *p, int n) {
  srand(0);
  int i;
  for (i = 0; i < n; i++)
    p[i] = rand();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill_random>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%edi
  call   <srand@plt>
  test   %ebp,%ebp
  jle    L3
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r12,%rax,1),%rbp
L7:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L7
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fill_random(unsigned char *p, int n) {
  srand(0);
  int i;
  for (i = 0; i < n; i++)
    p[i] = rand();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fill_random>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <srand@plt>
  test   %ebp,%ebp
  jle    L15
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rand@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L5
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fill_random(unsigned char *p, int n) {
  srand(0);
  int i;
  for (i = 0; i < n; i++)
    p[i] = rand();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fill_random>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <srand@plt>
  test   %ebp,%ebp
  jle    L8
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rand@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L3
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fill_random(unsigned char *p, int n) {
  srand(0);
  int i;
  for (i = 0; i < n; i++)
    p[i] = rand();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L26:
  cmpl   $0x4,-0x4(%rbp)
  je     L4
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x7,-0x4(%rbp)
  jle    L26
  jmp    L39
L4:
  nop
L39:
  cmpl   $0x4,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test() {
  int i, j, k;
  for (i = 0; i < 8;) {
    if (i == 4)
      break;
    i++;
  }
  return (i != 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  mov    $0x0,%eax
L4:
  add    $0x1,%eax
  cmp    $0x4,%eax
  je     L14
  cmp    $0x7,%eax
  jle    L4
L14:
  cmp    $0x4,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int test() {
  int i, j, k;
  for (i = 0; i < 8;) {
    if (i == 4)
      break;
    i++;
  }
  return (i != 4);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test() {
  int i, j, k;
  for (i = 0; i < 8;) {
    if (i == 4)
      break;
    i++;
  }
  return (i != 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test() {
  int i, j, k;
  for (i = 0; i < 8;) {
    if (i == 4)
      break;
    i++;
  }
  return (i != 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<d_add_unique>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <d_instantiate_unique@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  jmp    L7
L19:
  mov    -0x18(%rbp),%rax
L7:
  mov    %rax,%rdi
  call   <d_rehash@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct dentry *d_add_unique(struct dentry *entry, struct inode *inode) {
  struct dentry *res;
  res = d_instantiate_unique(entry, inode);
  d_rehash(res != ((void *)0) ? res : entry);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<d_add_unique>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <d_instantiate_unique@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  cmovne %rax,%rbx
  mov    %rbx,%rdi
  call   <d_rehash@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) struct dentry *d_add_unique(struct dentry *entry, struct inode *inode) {
  struct dentry *res;
  res = d_instantiate_unique(entry, inode);
  d_rehash(res != ((void *)0) ? res : entry);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<d_add_unique>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <d_instantiate_unique@plt>
  test   %rax,%rax
  mov    %rax,%r12
  cmovne %rax,%rbp
  mov    %rbp,%rdi
  call   <d_rehash@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct dentry *d_add_unique(struct dentry *entry, struct inode *inode) {
  struct dentry *res;
  res = d_instantiate_unique(entry, inode);
  d_rehash(res != ((void *)0) ? res : entry);
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<d_add_unique>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <d_instantiate_unique@plt>
  test   %rax,%rax
  mov    %rax,%r12
  cmovne %rax,%rbp
  mov    %rbp,%rdi
  call   <d_rehash@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct dentry *d_add_unique(struct dentry *entry, struct inode *inode) {
  struct dentry *res;
  res = d_instantiate_unique(entry, inode);
  d_rehash(res != ((void *)0) ? res : entry);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<addtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L2:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L5
L42:
  subl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L42
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L47
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L47
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%ecx
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x8(%rbp)
L47:
  addl   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L2
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: %d + %d = %d


assistant: ```c
int addtok(int sum, int arr[], int len) {
  int rem = 0;
  int bptr = 0, eptr = len - 1;
  int ret = 0;
  while (bptr < eptr) {
    rem = sum - arr[bptr];
    while (arr[eptr] > rem)
      eptr--;
    if (arr[bptr] + arr[eptr] == sum && bptr != eptr) {
      printf("%d + %d = %d\n", arr[bptr], arr[eptr], sum);
      ret = 1;
    }
    bptr++;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<addtok>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%r14d
  test   %r14d,%r14d
  jle    L21
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    $0x0,%edi
  lea    D1(%rip),%r13
  jmp    L5
L37:
  add    $0x1,%rbp
  cmp    %ebp,%r14d
  jle    L11
L5:
  mov    (%rbx,%rbp,4),%esi
  mov    %r12d,%ecx
  sub    %esi,%ecx
  movslq %r14d,%rax
  mov    (%rbx,%rax,4),%edx
  cmp    %edx,%ecx
  jge    L73
  lea    -0x1(%r14),%eax
  cltq
L77:
  mov    %eax,%r14d
  sub    $0x1,%rax
  mov    0x4(%rbx,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L77
L73:
  lea    (%rsi,%rdx,1),%eax
  cmp    %r12d,%eax
  jne    L37
  cmp    %ebp,%r14d
  je     L37
  mov    %r12d,%ecx
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  jmp    L37
L21:
  mov    $0x0,%edi
L11:
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: %d + %d = %d


assistant: ```c
int addtok(int sum, int arr[], int len) {
  int rem = 0;
  int bptr = 0, eptr = len - 1;
  int ret = 0;
  while (bptr < eptr) {
    rem = sum - arr[bptr];
    while (arr[eptr] > rem)
      eptr--;
    if (arr[bptr] + arr[eptr] == sum && bptr != eptr) {
      printf("%d + %d = %d\n", arr[bptr], arr[eptr], sum);
      ret = 1;
    }
    bptr++;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<addtok>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  test   %ebx,%ebx
  jle    L64
  mov    %edi,%r13d
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  xor    %r8d,%r8d
  lea    D6(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L40:
  mov    0x0(%rbp,%r12,4),%esi
  movslq %ebx,%rax
  mov    %r13d,%ecx
  mov    0x0(%rbp,%rax,4),%edx
  sub    %esi,%ecx
  cmp    %edx,%ecx
  jge    L11
  lea    -0x1(%rbx),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %eax,%ebx
  sub    $0x1,%rax
  mov    0x4(%rbp,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L8
L11:
  lea    (%rsi,%rdx,1),%eax
  cmp    %r13d,%eax
  jne    L51
  cmp    %r12d,%ebx
  jne    L22
L51:
  add    $0x1,%r12
  cmp    %r12d,%ebx
  jg     L40
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  mov    %r13d,%ecx
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x1,%r8d
  jmp    L51
L64:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: %d + %d = %d


assistant: ```c
int addtok(int sum, int arr[], int len) {
  int rem = 0;
  int bptr = 0, eptr = len - 1;
  int ret = 0;
  while (bptr < eptr) {
    rem = sum - arr[bptr];
    while (arr[eptr] > rem)
      eptr--;
    if (arr[bptr] + arr[eptr] == sum && bptr != eptr) {
      printf("%d + %d = %d\n", arr[bptr], arr[eptr], sum);
      ret = 1;
    }
    bptr++;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<addtok>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  test   %ebx,%ebx
  jle    L37
  mov    %edi,%r13d
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  xor    %r8d,%r8d
  lea    D0(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp,%r12,4),%esi
  movslq %ebx,%rax
  mov    %r13d,%ecx
  mov    0x0(%rbp,%rax,4),%edx
  sub    %esi,%ecx
  cmp    %edx,%ecx
  jge    L12
  lea    -0x1(%rbx),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %eax,%ebx
  sub    $0x1,%rax
  mov    0x4(%rbp,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L13
L12:
  lea    (%rsi,%rdx,1),%eax
  cmp    %r13d,%eax
  jne    L55
  cmp    %r12d,%ebx
  jne    L24
L55:
  add    $0x1,%r12
  cmp    %r12d,%ebx
  jg     L1
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  mov    %r13d,%ecx
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x1,%r8d
  jmp    L55
L37:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: %d + %d = %d


assistant: ```c
int addtok(int sum, int arr[], int len) {
  int rem = 0;
  int bptr = 0, eptr = len - 1;
  int ret = 0;
  while (bptr < eptr) {
    rem = sum - arr[bptr];
    while (arr[eptr] > rem)
      eptr--;
    if (arr[bptr] + arr[eptr] == sum && bptr != eptr) {
      printf("%d + %d = %d\n", arr[bptr], arr[eptr], sum);
      ret = 1;
    }
    bptr++;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_advance_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <utf8_byte_count@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int utf8_advance_ptr(char **ptr) {
  int bc = utf8_byte_count(**ptr);
  *ptr += bc;
  return bc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<utf8_advance_ptr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  movsbl (%rax),%edi
  call   <utf8_byte_count@plt>
  movslq %eax,%rdx
  add    %rdx,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
int utf8_advance_ptr(char **ptr) {
  int bc = utf8_byte_count(**ptr);
  *ptr += bc;
  return bc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utf8_advance_ptr>:
  endbr64
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  movsbl (%rax),%edi
  call   <utf8_byte_count@plt>
  movslq %eax,%rdx
  add    %rdx,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
int utf8_advance_ptr(char **ptr) {
  int bc = utf8_byte_count(**ptr);
  *ptr += bc;
  return bc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<utf8_advance_ptr>:
  endbr64
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  movsbl (%rax),%edi
  call   <utf8_byte_count@plt>
  movslq %eax,%rdx
  add    %rdx,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
int utf8_advance_ptr(char **ptr) {
  int bc = utf8_byte_count(**ptr);
  *ptr += bc;
  return bc;
}
```