user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xffffffff,%edi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x24(%rsp)
  call   <acos@plt>
  movsd  %xmm0,0x8(%rsp)
  cmp    $0x4,%ebx
  je     L26
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  lea    D95(%rip),%r12
  mov    0x8(%rbp),%rdi
  lea    0x1c(%rsp),%rdx
  mov    %r12,%rsi
  call   <sscanf@plt>
  mov    0x10(%rbp),%rdi
  lea    0x20(%rsp),%rdx
  mov    %r12,%rsi
  call   <sscanf@plt>
  mov    0x18(%rbp),%rdi
  lea    0x24(%rsp),%rdx
  mov    %r12,%rsi
  call   <sscanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x1c(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  D89(%rip),%xmm0
  call   <cos@plt>
  imul   0x24(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x1c(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  D89(%rip),%xmm0
  mov    %eax,%r12d
  call   <sin@plt>
  imul   0x24(%rsp),%eax
  mov    %r12d,%edx
  lea    D60(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x20(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  D89(%rip),%xmm0
  call   <cos@plt>
  imul   0x24(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x20(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  D89(%rip),%xmm0
  mov    %eax,%r12d
  call   <sin@plt>
  imul   0x24(%rsp),%eax
  mov    %r12d,%edx
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x20(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  D89(%rip),%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x1c(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  divsd  D89(%rip),%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x20(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  sub    %eax,%ebx
  imul   0x24(%rsp),%ebx
  divsd  D89(%rip),%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x1c(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  mov    %ebx,%r12d
  divsd  D89(%rip),%xmm0
  mov    %eax,%ebx
  call   <sin@plt>
  mov    0x24(%rsp),%esi
  mov    %r12d,%edx
  lea    D82(%rip),%rdi
  sub    %eax,%ebx
  imul   %ebx,%esi
  call   <printf@plt>
  jmp    L13
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D95
datatype: string
name: parse_data
arguments: label: D89
datatype: byte[8]
name: parse_data
arguments: label: D60
datatype: string
name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D82
datatype: string

tool: D95: %d

tool: {"D89": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

tool: D60: (x1,y1) : (%f,%f)


tool: D19: (x2,y2) : (%f,%f)


tool: D82: Vector : (%f,%f)


assistant: ```c
int main(int argc, char **argv) {
  int tTa1, tTa2;
  int r = 0;
  double pi = acos(-1);
  if (argc == 4) {
    sscanf(argv[1], "%d", &tTa1);
    sscanf(argv[2], "%d", &tTa2);
    sscanf(argv[3], "%d", &r);
    printf("(x1,y1) : (%f,%f)\n", r * sin(pi * tTa1 / 180), r * cos(pi * tTa1 / 180));
    printf("(x2,y2) : (%f,%f)\n", r * sin(pi * tTa2 / 180), r * cos(pi * tTa2 / 180));
    printf("Vector : (%f,%f)\n", r * (sin(pi * tTa2 / 180) - sin(pi * tTa1 / 180)), r * (cos(pi * tTa2 / 180) - cos(pi * tTa1 / 180)));
  } else {
  }
  return 0;
}
```