user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  -0x20(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L29
L12:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x10(%rbp),%xmm1
  movss  -0x24(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L71
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  je     L71
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L15
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <f@plt>
  addss  %xmm0,%xmm0
  movss  -0x18(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  jmp    L31
L15:
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <f@plt>
  movss  D36(%rip),%xmm1
  mulss  %xmm1,%xmm0
  movss  -0x18(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  jmp    L31
L71:
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <f@plt>
  movss  -0x18(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
L31:
  addl   $0x1,-0x14(%rbp)
L29:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L12
  movss  -0x18(%rbp),%xmm0
  mulss  -0x10(%rbp),%xmm0
  movss  D38(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x18(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D29
type_infered: string
name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string
name: parse_data
arguments: tag: D41
type_infered: string
name: parse_data
arguments: tag: D36
type_infered: byte[4]
name: parse_data
arguments: tag: D38
type_infered: byte[4]
name: parse_data
arguments: tag: D3
type_infered: string

tool: D29: Enter Interval [a,b]: 

tool: D25: %f %f

tool: D24: Enter no of subinterals:

tool: D41: %d

tool: {"D36": [0x00,0x00,0x80,0x40]}

tool: {"D38": [0x00,0x00,0x40,0x40]}

tool: D3: Resul: %f

assistant: ```c
int main() {
  float a, b, h, x, sum;
  int n, i;
  printf("Enter Interval [a,b]: ");
  scanf("%f %f", &a, &b);
  printf("Enter no of subinterals:");
  scanf("%d", &n);
  h = (b - a) / n;
  for (i = 0; i <= n; i++) {
    x = a + i * h;
    if (i != 0 && i != n) {
      if (i % 2 == 0)
        sum += 2 * f(x);
      else
        sum += 4 * f(x);
    } else
      sum += f(x);
  }
  sum = sum * h / 3;
  printf("Resul: %f", sum);
  return 0;
}
```