ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<htonl>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
uint32_t htonl(uint32_t hostint) {
  swap(&hostint);
  return hostint;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L93
L30:
  lea    -0x60(%rbp),%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x6c(%rbp)
L93:
  mov    -0x70(%rbp),%eax
  cmp    %eax,-0x6c(%rbp)
  jl     L30
  movl   $0x1,-0x68(%rbp)
  jmp    L91
L25:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,-0x64(%rbp)
  mov    -0x68(%rbp),%eax
  mov    %eax,-0x6c(%rbp)
  jmp    L32
L39:
  mov    -0x6c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  mov    -0x6c(%rbp),%eax
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
  subl   $0x1,-0x6c(%rbp)
L32:
  cmpl   $0x0,-0x6c(%rbp)
  jle    L40
  mov    -0x6c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  cmp    %eax,-0x64(%rbp)
  jl     L39
L40:
  mov    -0x6c(%rbp),%eax
  cltq
  mov    -0x64(%rbp),%edx
  mov    %edx,-0x60(%rbp,%rax,4)
  addl   $0x1,-0x68(%rbp)
L91:
  mov    -0x70(%rbp),%eax
  cmp    %eax,-0x68(%rbp)
  jl     L25
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L58
L72:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L58:
  mov    -0x70(%rbp),%eax
  cmp    %eax,-0x68(%rbp)
  jl     L72
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
datatype: string

tool: D14: %d

assistant: ```c
int main() {
  int a[20], n, j, i, temp;
  scanf("%d", &n);
  for (j = 0; j < n; j++)
    scanf("%d", &a[j]);
  for (i = 1; i < n; i++) {
    temp = a[i];
    j = i;
    while (j > 0 && temp < a[j - 1]) {
      a[j] = a[j - 1];
      j--;
    }
    a[j] = temp;
  }
  printf("\n");
  for (i = 0; i < n; i++) {
    printf("%d", a[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r10d
  test   %r10d,%r10d
  jle    L13
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D13(%rip),%r12
L35:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%r10d
  add    $0x4,%rbp
  cmp    %ebx,%r10d
  jg     L35
L13:
  cmp    $0x1,%r10d
  jle    L17
  lea    0x14(%rsp),%r9
  mov    $0x1,%r8d
  jmp    L91
L59:
  movslq %esi,%rsi
  mov    %edi,0x10(%rsp,%rsi,4)
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r10d,%r8d
  je     L17
L91:
  mov    (%r9),%edi
  mov    %r9,%rdx
  mov    %r8d,%eax
  mov    %r8d,%esi
  test   %r8d,%r8d
  jle    L59
L12:
  mov    %eax,%esi
  sub    $0x1,%eax
  mov    -0x4(%rdx),%ecx
  cmp    %edi,%ecx
  jle    L59
  mov    %ecx,(%rdx)
  sub    $0x4,%rdx
  test   %eax,%eax
  jne    L12
  mov    %eax,%esi
  jmp    L59
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L73
  mov    $0x0,%ebx
  lea    D13(%rip),%rbp
L64:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L64
L73:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
type: string

tool: D13: %d

assistant: ```c
int main() {
  int a[20], n, j, i, temp;
  scanf("%d", &n);
  for (j = 0; j < n; j++)
    scanf("%d", &a[j]);
  for (i = 1; i < n; i++) {
    temp = a[i];
    j = i;
    while (j > 0 && temp < a[j - 1]) {
      a[j] = a[j - 1];
      j--;
    }
    a[j] = temp;
  }
  printf("\n");
  for (i = 0; i < n; i++) {
    printf("%d", a[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L89
  lea    0x10(%rsp),%r12
  xor    %ebp,%ebp
  nop
L94:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%r10d
  cmp    %ebp,%r10d
  jg     L94
  cmp    $0x1,%r10d
  jle    L89
  lea    0x14(%rsp),%r9
  mov    $0x1,%r8d
  nopl   (%rax)
L42:
  mov    (%r9),%esi
  mov    %r9,%rdx
  mov    %r8d,%eax
  nopl   0x0(%rax)
L65:
  mov    -0x4(%rdx),%ecx
  mov    %eax,%edi
  sub    $0x1,%eax
  cmp    %esi,%ecx
  jle    L6
  mov    %ecx,(%rdx)
  sub    $0x4,%rdx
  test   %eax,%eax
  jne    L65
L73:
  cltq
  add    $0x1,%r8d
  add    $0x4,%r9
  mov    %esi,0x10(%rsp,%rax,4)
  cmp    %r8d,%r10d
  jne    L42
L89:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L31
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L43:
  mov    (%r12,%rbp,4),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jg     L43
L31:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %edi,%eax
  jmp    L73
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: %d

assistant: ```c
int main() {
  int a[20], n, j, i, temp;
  scanf("%d", &n);
  for (j = 0; j < n; j++)
    scanf("%d", &a[j]);
  for (i = 1; i < n; i++) {
    temp = a[i];
    j = i;
    while (j > 0 && temp < a[j - 1]) {
      a[j] = a[j - 1];
      j--;
    }
    a[j] = temp;
  }
  printf("\n");
  for (i = 0; i < n; i++) {
    printf("%d", a[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L34
  lea    0x10(%rsp),%r12
  xor    %ebp,%ebp
  nop
L33:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%r10d
  cmp    %ebp,%r10d
  jg     L33
  cmp    $0x1,%r10d
  jle    L34
  lea    0x14(%rsp),%r9
  mov    $0x1,%r8d
  nopl   (%rax)
L32:
  mov    (%r9),%esi
  mov    %r9,%rdx
  mov    %r8d,%eax
  nopl   0x0(%rax)
L54:
  mov    -0x4(%rdx),%ecx
  mov    %eax,%edi
  sub    $0x1,%eax
  cmp    %esi,%ecx
  jle    L77
  mov    %ecx,(%rdx)
  sub    $0x4,%rdx
  test   %eax,%eax
  jne    L54
L52:
  cltq
  add    $0x1,%r8d
  add    $0x4,%r9
  mov    %esi,0x10(%rsp,%rax,4)
  cmp    %r8d,%r10d
  jne    L32
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L44
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L75:
  mov    (%r12,%rbp,4),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jg     L75
L44:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %edi,%eax
  jmp    L52
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string

tool: D0: %d

assistant: ```c
int main() {
  int a[20], n, j, i, temp;
  scanf("%d", &n);
  for (j = 0; j < n; j++)
    scanf("%d", &a[j]);
  for (i = 1; i < n; i++) {
    temp = a[i];
    j = i;
    while (j > 0 && temp < a[j - 1]) {
      a[j] = a[j - 1];
      j--;
    }
    a[j] = temp;
  }
  printf("\n");
  for (i = 0; i < n; i++) {
    printf("%d", a[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L8
  mov    -0x8(%rbp),%eax
  jmp    L15
L8:
  mov    -0x4(%rbp),%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int min(a, b) {
  if (a > b)
    return b;
  else
    return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(a, b) {
  if (a > b)
    return b;
  else
    return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(a, b) {
  if (a > b)
    return b;
  else
    return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(a, b) {
  if (a > b)
    return b;
  else
    return a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gang>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <gang>
  mov    $0x0,%eax
  call   <worker@plt>
  mov    $0x0,%eax
  call   <vector@plt>
  mov    $0x0,%eax
  call   <seq@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gang(void) {
  gang();
  worker();
  vector();
  seq();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gang>:
  endbr64
  sub    $0x8,%rsp
  call   <gang>
  mov    $0x0,%eax
  call   <worker@plt>
  mov    $0x0,%eax
  call   <vector@plt>
  mov    $0x0,%eax
  call   <seq@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gang(void) {
  gang();
  worker();
  vector();
  seq();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gang>:
  endbr64
  sub    $0x8,%rsp
  call   <gang>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <seq@plt>
```

assistant: ```c
void gang(void) {
  gang();
  worker();
  vector();
  seq();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gang>:
  endbr64
  sub    $0x8,%rsp
  call   <gang>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <worker@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <seq@plt>
```

assistant: ```c
void gang(void) {
  gang();
  worker();
  vector();
  seq();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <function_a@plt>
  mov    $0x0,%eax
  call   <function_b@plt>
  mov    $0x0,%eax
  call   <function_d@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  function_a();
  function_b();
  function_d();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <function_a@plt>
  mov    $0x0,%eax
  call   <function_b@plt>
  mov    $0x0,%eax
  call   <function_d@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  function_a();
  function_b();
  function_d();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <function_a@plt>
  xor    %eax,%eax
  call   <function_b@plt>
  xor    %eax,%eax
  call   <function_d@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  function_a();
  function_b();
  function_d();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <function_a@plt>
  xor    %eax,%eax
  call   <function_b@plt>
  xor    %eax,%eax
  call   <function_d@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  function_a();
  function_b();
  function_d();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x24(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x24(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x20(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm3
  movaps %xmm0,%xmm2
  subss  %xmm3,%xmm2
  movss  -0x20(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm3
  subss  %xmm3,%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movss  -0x1c(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L13
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L25
L13:
  movss  -0x1c(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L58
  ucomiss -0xc(%rbp),%xmm0
  jne    L58
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L25
L58:
  movss  -0x1c(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L25
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L25:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string

tool: D23: %f %f %f %f %f

tool: D9: Point is inside the Circle

tool: D18: Point is on the Circle

tool: D27: Point is outside the Circle

assistant: ```c
int main() {
  float x, y, r, x1, y1, d, e;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  d = (x - x1) * (x - x1) + (y - y1) * (y - y1);
  e = sqrt(d);
  if (e < r) {
    printf("Point is inside the Circle");
  } else if (e == r) {
    printf("Point is on the Circle");
  } else if (e > r) {
    printf("Point is outside the Circle");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  subss  0x10(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  subss  0x14(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L11
  ucomiss %xmm0,%xmm1
  jp     L24
  je     L1
L24:
  comiss %xmm1,%xmm0
  jbe    L19
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L11:
  lea    D1(%rip),%rdi
  call   <printf@plt>
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D20
type: string

tool: D12: %f %f %f %f %f

tool: D19: Point is outside the Circle

tool: D1: Point is inside the Circle

tool: D20: Point is on the Circle

assistant: ```c
int main() {
  float x, y, r, x1, y1, d, e;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  d = (x - x1) * (x - x1) + (y - y1) * (y - y1);
  e = sqrt(d);
  if (e < r) {
    printf("Point is inside the Circle");
  } else if (e == r) {
    printf("Point is on the Circle");
  } else if (e > r) {
    printf("Point is outside the Circle");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D35(%rip),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  subss  0x10(%rsp),%xmm0
  subss  0x14(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L5
  ucomiss %xmm0,%xmm1
  jp     L51
  je     L44
L51:
  comiss %xmm1,%xmm0
  ja     L50
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L44:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L5:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L50:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
type_infered: string
name: retrieve_data
arguments: data_tag: D33
type_infered: string
name: retrieve_data
arguments: data_tag: D37
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D35: %f %f %f %f %f

tool: D33: Point is on the Circle

tool: D37: Point is inside the Circle

tool: D7: Point is outside the Circle

assistant: ```c
int main() {
  float x, y, r, x1, y1, d, e;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  d = (x - x1) * (x - x1) + (y - y1) * (y - y1);
  e = sqrt(d);
  if (e < r) {
    printf("Point is inside the Circle");
  } else if (e == r) {
    printf("Point is on the Circle");
  } else if (e > r) {
    printf("Point is outside the Circle");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D11(%rip),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  subss  0x10(%rsp),%xmm0
  subss  0x14(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L69
  ucomiss %xmm0,%xmm1
  jp     L70
  je     L9
L70:
  comiss %xmm1,%xmm0
  ja     L77
L78:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L78
L69:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L78
L77:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L78
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D35
datatype: string
name: parse_data
arguments: tag: D32
datatype: string
name: parse_data
arguments: tag: D18
datatype: string

tool: D11: %f %f %f %f %f

tool: D35: Point is on the Circle

tool: D32: Point is inside the Circle

tool: D18: Point is outside the Circle

assistant: ```c
int main() {
  float x, y, r, x1, y1, d, e;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  d = (x - x1) * (x - x1) + (y - y1) * (y - y1);
  e = sqrt(d);
  if (e < r) {
    printf("Point is inside the Circle");
  } else if (e == r) {
    printf("Point is on the Circle");
  } else if (e > r) {
    printf("Point is outside the Circle");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_193_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x1c(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x18(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_193_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = ~S;
  stk3 = D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_193_0_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  mov    %edi,%edx
  not    %edx
  movzbl %dl,%edx
  or     %edx,%eax
  xor    %edi,%eax
  not    %eax
  ret
```

assistant: ```c
unsigned xrop3_193_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = ~S;
  stk3 = D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```