ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  sub    $0x17447d68,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L41
  mov    %rsp,%rdx
  mov    $0x0,%eax
L55:
  mov    (%rsp),%rsi
  cmp    %rax,%rsi
  jbe    L39
  mov    %esi,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %rsi,%r9
  ror    %cl,%r9
  mov    %r9,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rsi,%rcx
  mov    %rcx,(%rsp)
L50:
  mov    (%rsp),%rsi
  cmp    %rax,%rsi
  je     L5
  mov    %esi,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rsi
  mov    %rsi,(%rdx)
L57:
  add    $0x1,%rax
  add    $0x8,%rdx
  cmp    %rdi,%rax
  jne    L55
L41:
  mov    (%rsp),%rax
  rol    $0x5,%rax
  mov    %rax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  ret
L39:
  movzwl 0x2(%rdx),%ecx
  movzwl (%rdx),%esi
  mov    %si,0x2(%rdx)
  movzwl 0x4(%rdx),%esi
  mov    %si,(%rdx)
  mov    %cx,0x4(%rdx)
  jmp    L50
L5:
  mov    %rax,%rcx
  shr    $0x3,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %rax,%rsi
  rol    %cl,%rsi
  mov    %rsi,(%rsp)
  jmp    L57
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
      } else {
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      }
      if (state[0UL] == local1) {
        state[0UL] = (state[0UL] << (((state[0UL] >> 3UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 3UL) & 15UL) | 1UL)));
      } else {
        state[local1] = (state[0UL] << ((state[local1] & 15UL) | 1UL)) | (state[0UL] >> (64 - ((state[local1] & 15UL) | 1UL)));
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 5UL) | (state[0UL] >> 59UL);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  sub    $0x17447d68,%rax
  test   %rdi,%rdi
  je     L39
  xor    %edx,%edx
L10:
  cmp    %rdx,%rax
  jbe    L16
  mov    %eax,%ecx
  mov    %rax,%r8
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%r8
  mov    %r8,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
L16:
  cmp    %rdx,%rax
  je     L6
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rax
L36:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L10
L39:
  rol    $0x5,%rax
  mov    %rax,(%rsi)
  ret
  nopl   0x0(%rax)
L6:
  mov    %rax,%rcx
  shr    $0x3,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rax
  jmp    L36
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
      } else {
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      }
      if (state[0UL] == local1) {
        state[0UL] = (state[0UL] << (((state[0UL] >> 3UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 3UL) & 15UL) | 1UL)));
      } else {
        state[local1] = (state[0UL] << ((state[local1] & 15UL) | 1UL)) | (state[0UL] >> (64 - ((state[local1] & 15UL) | 1UL)));
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 5UL) | (state[0UL] >> 59UL);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  sub    $0x17447d68,%rax
  test   %rdi,%rdi
  je     L88
  test   %rax,%rax
  jne    L131
  cmp    $0x1,%rdi
  je     L88
L81:
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rax
L77:
  cmp    $0x2,%rdi
  jbe    L88
  mov    $0x2,%edx
L39:
  cmp    %rax,%rdx
  jae    L146
  mov    %eax,%ecx
  mov    %rax,%r8
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%r8
  mov    %r8,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
L146:
  cmp    %rax,%rdx
  je     L54
  mov    %eax,%ecx
  add    $0x1,%rdx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rax
  cmp    %rdi,%rdx
  jne    L39
L88:
  rol    $0x5,%rax
  mov    %rax,(%rsi)
  ret
  nop
L131:
  mov    %eax,%ecx
  mov    %rax,%rdx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%rdx
  shl    $0x4,%rdx
  and    $0x3f0,%edx
  or     %rax,%rdx
  mov    %rdx,%rax
  rol    %cl,%rax
  cmp    $0x1,%rdi
  je     L88
  cmp    $0x1,%rax
  jbe    L92
  mov    %eax,%ecx
  mov    %rax,%rdx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%rdx
  shl    $0x4,%rdx
  and    $0x3f0,%edx
  or     %rdx,%rax
  jmp    L81
  nopl   (%rax)
L92:
  jne    L97
  mov    $0x2,%eax
  jmp    L77
  nopl   0x0(%rax)
L54:
  mov    %rdx,%rcx
  mov    %rdx,%rax
  add    $0x1,%rdx
  shr    $0x3,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rax
  cmp    %rdi,%rdx
  jne    L39
  jmp    L88
L97:
  xor    %eax,%eax
  jmp    L81
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
      } else {
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      }
      if (state[0UL] == local1) {
        state[0UL] = (state[0UL] << (((state[0UL] >> 3UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 3UL) & 15UL) | 1UL)));
      } else {
        state[local1] = (state[0UL] << ((state[local1] & 15UL) | 1UL)) | (state[0UL] >> (64 - ((state[local1] & 15UL) | 1UL)));
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 5UL) | (state[0UL] >> 59UL);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__sysconf@plt>
  mov    %rax,-0x28(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <__times@plt>
  mov    D28(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jg     L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    D28(%rip),%rax
  mov    (%rax),%rax
  cqto
  idivq  -0x28(%rbp)
  imul   %rcx,%rax
  jmp    L16
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    D28(%rip),%rax
  mov    (%rax),%rsi
  mov    -0x28(%rbp),%rax
  cqto
  idiv   %rsi
  mov    %rax,%rsi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
clock_t clock(void) {
  struct tms buf;
  long clk_tck = __sysconf(_SC_CLK_TCK);
  __times(&buf);
  return (clk_tck <= CLOCKS_PER_SEC) ? ((unsigned long)buf.tms_utime + buf.tms_stime) * (CLOCKS_PER_SEC / clk_tck) : ((unsigned long)buf.tms_utime + buf.tms_stime) / (clk_tck / CLOCKS_PER_SEC);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clock>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <__sysconf@plt>
  mov    %rax,%rbx
  mov    %rsp,%rdi
  call   <__times@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%rsi
  cmp    %rbx,%rsi
  jl     L24
  mov    (%rsp),%rax
  add    0x8(%rsp),%rax
  mov    %rax,%rcx
  mov    %rsi,%rax
  cqto
  idiv   %rbx
  imul   %rcx,%rax
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x20,%rsp
  pop    %rbx
  ret
L24:
  mov    (%rsp),%rax
  add    0x8(%rsp),%rax
  mov    %rax,%rcx
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  mov    %rax,%rbx
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rbx
  jmp    L9
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
clock_t clock(void) {
  struct tms buf;
  long clk_tck = __sysconf(_SC_CLK_TCK);
  __times(&buf);
  return (clk_tck <= CLOCKS_PER_SEC) ? ((unsigned long)buf.tms_utime + buf.tms_stime) * (CLOCKS_PER_SEC / clk_tck) : ((unsigned long)buf.tms_utime + buf.tms_stime) / (clk_tck / CLOCKS_PER_SEC);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clock>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <__sysconf@plt>
  mov    %rsp,%rdi
  mov    %rax,%rbx
  call   <__times@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%rsi
  mov    (%rsp),%rax
  add    0x8(%rsp),%rax
  mov    %rax,%rcx
  cmp    %rbx,%rsi
  jl     L21
  mov    %rsi,%rax
  cqto
  idiv   %rbx
  imul   %rcx,%rax
L18:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L21:
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  xor    %edx,%edx
  mov    %rax,%rbx
  mov    %rcx,%rax
  div    %rbx
  jmp    L18
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
clock_t clock(void) {
  struct tms buf;
  long clk_tck = __sysconf(_SC_CLK_TCK);
  __times(&buf);
  return (clk_tck <= CLOCKS_PER_SEC) ? ((unsigned long)buf.tms_utime + buf.tms_stime) * (CLOCKS_PER_SEC / clk_tck) : ((unsigned long)buf.tms_utime + buf.tms_stime) / (clk_tck / CLOCKS_PER_SEC);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clock>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <__sysconf@plt>
  mov    %rsp,%rdi
  mov    %rax,%rbx
  call   <__times@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%rsi
  mov    (%rsp),%rax
  add    0x8(%rsp),%rax
  mov    %rax,%rcx
  cmp    %rbx,%rsi
  jl     L26
  mov    %rsi,%rax
  cqto
  idiv   %rbx
  imul   %rcx,%rax
L0:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L26:
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  xor    %edx,%edx
  mov    %rax,%rbx
  mov    %rcx,%rax
  div    %rbx
  jmp    L0
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
clock_t clock(void) {
  struct tms buf;
  long clk_tck = __sysconf(_SC_CLK_TCK);
  __times(&buf);
  return (clk_tck <= CLOCKS_PER_SEC) ? ((unsigned long)buf.tms_utime + buf.tms_stime) * (CLOCKS_PER_SEC / clk_tck) : ((unsigned long)buf.tms_utime + buf.tms_stime) / (clk_tck / CLOCKS_PER_SEC);
}
```
user: What is the c source code of the assembly code below?

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L27
  jmp    L54
L19:
  addq   $0x1,-0x18(%rbp)
L54:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L8:
  subl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L8
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L27:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strip(char *src) {
  if (src != NULL) {
    while (*src == ' ') {
      src++;
    }
    int end = strlen(src) - 1;
    while (src[end] == ' ' || src[end] == '\n') {
      end--;
    }
    src[end + 1] = '\0';
  }
  return src;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strip>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L14
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x20,(%rdi)
  jne    L68
L50:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L50
L68:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%edx
  cmp    $0x20,%dl
  je     L55
  cmp    $0xa,%dl
  jne    L22
L55:
  sub    $0x2,%eax
  cltq
L6:
  movzbl (%rbx,%rax,1),%edx
  mov    %rax,%rcx
  sub    $0x1,%rax
  cmp    $0x20,%dl
  je     L6
  cmp    $0xa,%dl
  je     L6
L22:
  movb   $0x0,0x1(%rbx,%rcx,1)
  mov    %rbx,%rax
  pop    %rbx
  ret
L14:
  ret
```

assistant: ```c
char *strip(char *src) {
  if (src != NULL) {
    while (*src == ' ') {
      src++;
    }
    int end = strlen(src) - 1;
    while (src[end] == ' ' || src[end] == '\n') {
      end--;
    }
    src[end + 1] = '\0';
  }
  return src;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strip>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbx
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbx
  jne    L29
  nopw   0x0(%rax,%rax,1)
L56:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L56
L29:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%edx
  cmp    $0x20,%dl
  je     L38
  cmp    $0xa,%dl
  jne    L8
L38:
  sub    $0x2,%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L34:
  movzbl (%rbx,%rax,1),%edx
  mov    %rax,%rcx
  sub    $0x1,%rax
  cmp    $0x20,%dl
  je     L34
  cmp    $0xa,%dl
  je     L34
L8:
  mov    %rbx,%rax
  movb   $0x0,0x1(%rbx,%rcx,1)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strip(char *src) {
  if (src != NULL) {
    while (*src == ' ') {
      src++;
    }
    int end = strlen(src) - 1;
    while (src[end] == ' ' || src[end] == '\n') {
      end--;
    }
    src[end + 1] = '\0';
  }
  return src;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strip>:
  endbr64
  test   %rdi,%rdi
  je     L50
  push   %rbx
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbx
  jne    L4
  nopw   0x0(%rax,%rax,1)
L62:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L62
L4:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%edx
  cmp    $0x20,%dl
  je     L64
  cmp    $0xa,%dl
  jne    L7
L64:
  sub    $0x2,%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L32:
  movzbl (%rbx,%rax,1),%edx
  mov    %rax,%rcx
  sub    $0x1,%rax
  cmp    $0x20,%dl
  je     L32
  cmp    $0xa,%dl
  je     L32
L7:
  mov    %rbx,%rax
  movb   $0x0,0x1(%rbx,%rcx,1)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strip(char *src) {
  if (src != NULL) {
    while (*src == ' ') {
      src++;
    }
    int end = strlen(src) - 1;
    while (src[end] == ' ' || src[end] == '\n') {
      end--;
    }
    src[end + 1] = '\0';
  }
  return src;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EPIIntErrorClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x400d0000,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmpq   $0xf,-0x10(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x8(%rbp),%rax
  add    $0x21c,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void EPIIntErrorClear(unsigned long ulBase, unsigned long ulErrFlags) {
  DEBUG_ASSERT(ulBase == 0x400D0000);
  DEBUG_ASSERT(ulErrFlags < 16);
  (*((volatile unsigned long *)(ulBase + 0x0000021C))) = ulErrFlags;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EPIIntErrorClear>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmp    $0x400d0000,%rdi
  sete   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  cmp    $0xf,%rbp
  setbe  %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,0x21c(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIIntErrorClear(unsigned long ulBase, unsigned long ulErrFlags) {
  DEBUG_ASSERT(ulBase == 0x400D0000);
  DEBUG_ASSERT(ulErrFlags < 16);
  (*((volatile unsigned long *)(ulBase + 0x0000021C))) = ulErrFlags;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<EPIIntErrorClear>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400d0000,%rbx
  sete   %dil
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    $0xf,%rbp
  setbe  %dil
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,0x21c(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIIntErrorClear(unsigned long ulBase, unsigned long ulErrFlags) {
  DEBUG_ASSERT(ulBase == 0x400D0000);
  DEBUG_ASSERT(ulErrFlags < 16);
  (*((volatile unsigned long *)(ulBase + 0x0000021C))) = ulErrFlags;
}
```
user: Translate the below assembly code into C programming language:

```asm
<EPIIntErrorClear>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400d0000,%rbx
  sete   %dil
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    $0xf,%rbp
  setbe  %dil
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,0x21c(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIIntErrorClear(unsigned long ulBase, unsigned long ulErrFlags) {
  DEBUG_ASSERT(ulBase == 0x400D0000);
  DEBUG_ASSERT(ulErrFlags < 16);
  (*((volatile unsigned long *)(ulBase + 0x0000021C))) = ulErrFlags;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L75:
  cmp    %rdx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L75
L18:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L43
  orq    $0x0,-0x8(%rsp,%rax,1)
L43:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L42
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,8),%r15
L64:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D23(%rip),%xmm0
  subsd  D19(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L64
L42:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L6
  mov    $0x0,%ebx
L12:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <stdlib_strided_dnanmeanpw@plt>
  ucomisd %xmm0,%xmm0
  jp     L76
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L12
L6:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L77:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L76:
  lea    D11(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L77
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D23
type: f64
name: unpack_data
arguments: data_label: D19
type: f64
name: unpack_data
arguments: data_label: D11
type: string

tool: D23: 20000

tool: D19: 10000

tool: D11: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanmeanpw(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```