ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0x97000000,%ebx
  sub    $0x8,%rsp
  movq   $0x0,(%rbx)
  call   <Set640x480_60@plt>
  mov    $0x97000014,%eax
  mov    $0x1f1f590,%edx
  movq   $0x1f00000,(%rax)
  movq   $0x1f00000,0x4(%rax)
  movq   $0x1f00000,0x21000000(%rax)
  movq   $0x381,(%rbx)
  movq   $0x6,0x20ffffec(%rax)
  nopl   0x0(%rax,%rax,1)
L14:
  lea    -0xc8(%rdx),%rax
  nop
L49:
  mov    $0xff00ff00,%ecx
  add    $0x4,%rax
  mov    %rcx,-0x4(%rax)
  cmp    %rdx,%rax
  jne    L49
  lea    0x500(%rax),%rdx
  cmp    $0x1f3e490,%rax
  jne    L14
  mov    $0xc8,%ebp
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    $0xc8,%ebx
  nopl   (%rax)
L42:
  mov    %ebx,%edi
  mov    $0xf800f800,%edx
  mov    %ebp,%esi
  add    $0x2,%ebx
  call   <drawPixel@plt>
  cmp    $0x12c,%ebx
  jne    L42
  add    $0x1,%ebp
  cmp    $0x12c,%ebp
  jne    L37
L29:
  jmp    L29
```

assistant: ```c
int main(void) {
  *((volatile unsigned long *)(0x97000000 + 0x000)) = 0;
  Set640x480_60();
  *((volatile unsigned long *)(0x97000000 + 0x014)) = 0x01f00000;
  *((volatile unsigned long *)(0x97000000 + 0x018)) = 0x01f00000;
  *((volatile unsigned long *)(0xB8000000 + 0x014)) = 0x01f00000;
  *((volatile unsigned long *)(0x97000000 + 0x000)) = 0x00000001 | 0x00000180 | 0x00000200;
  *((volatile unsigned long *)(0xB8000000 + 0x000)) = 6;
  int x, y;
  for (y = 100; y < 200; ++y) {
    for (x = 50; x < 100; x++) {
      int addr = (y * 320 + x) * 4;
      *((volatile unsigned long *)(0x01f00000 + addr)) = 0xff00ff00;
    }
  }
  for (y = 200; y < 300; ++y)
    for (x = 200; x < 300; x += 2)
      drawPixel(x, y, 0xf800f800);
  while (1)
    ;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0x97000000,%ebx
  sub    $0x8,%rsp
  movq   $0x0,(%rbx)
  call   <Set640x480_60@plt>
  mov    $0x97000014,%eax
  mov    $0x1f1f590,%edx
  movq   $0x1f00000,(%rax)
  movq   $0x1f00000,0x4(%rax)
  movq   $0x1f00000,0x21000000(%rax)
  movq   $0x381,(%rbx)
  movq   $0x6,0x20ffffec(%rax)
  nopl   0x0(%rax,%rax,1)
L13:
  lea    -0xc8(%rdx),%rax
  nop
L45:
  mov    $0xff00ff00,%ecx
  add    $0x4,%rax
  mov    %rcx,-0x4(%rax)
  cmp    %rax,%rdx
  jne    L45
  add    $0x500,%rdx
  cmp    $0x1f3e990,%rdx
  jne    L13
  mov    $0xc8,%ebp
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0xc8,%ebx
  nopl   (%rax)
L19:
  mov    %ebx,%edi
  mov    $0xf800f800,%edx
  mov    %ebp,%esi
  add    $0x2,%ebx
  call   <drawPixel@plt>
  cmp    $0x12c,%ebx
  jne    L19
  add    $0x1,%ebp
  cmp    $0x12c,%ebp
  jne    L14
L48:
  jmp    L48
```

assistant: ```c
int main(void) {
  *((volatile unsigned long *)(0x97000000 + 0x000)) = 0;
  Set640x480_60();
  *((volatile unsigned long *)(0x97000000 + 0x014)) = 0x01f00000;
  *((volatile unsigned long *)(0x97000000 + 0x018)) = 0x01f00000;
  *((volatile unsigned long *)(0xB8000000 + 0x014)) = 0x01f00000;
  *((volatile unsigned long *)(0x97000000 + 0x000)) = 0x00000001 | 0x00000180 | 0x00000200;
  *((volatile unsigned long *)(0xB8000000 + 0x000)) = 6;
  int x, y;
  for (y = 100; y < 200; ++y) {
    for (x = 50; x < 100; x++) {
      int addr = (y * 320 + x) * 4;
      *((volatile unsigned long *)(0x01f00000 + addr)) = 0xff00ff00;
    }
  }
  for (y = 200; y < 300; ++y)
    for (x = 200; x < 300; x += 2)
      drawPixel(x, y, 0xf800f800);
  while (1)
    ;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FileWritePermissionCheck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  je     L17
  mov    $0x1,%eax
  jmp    L3
L17:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
bool FileWritePermissionCheck(const char *file_name) {
  if (access(file_name, W_OK) != -1) {
    return true;
  } else {
    return false;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<FileWritePermissionCheck>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool FileWritePermissionCheck(const char *file_name) {
  if (access(file_name, W_OK) != -1) {
    return true;
  } else {
    return false;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<FileWritePermissionCheck>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool FileWritePermissionCheck(const char *file_name) {
  if (access(file_name, W_OK) != -1) {
    return true;
  } else {
    return false;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FileWritePermissionCheck>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool FileWritePermissionCheck(const char *file_name) {
  if (access(file_name, W_OK) != -1) {
    return true;
  } else {
    return false;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tar_getsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0xb,-0x8(%rbp)
  jmp    L12
L11:
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
  shll   $0x3,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x8(%rbp)
  jg     L11
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int tar_getsize(const char *in) {
  int size = 0;
  int i;
  int count = 1;
  for (i = 11; i > 0; i--, count *= 8) {
    size += ((in[i - 1] - '0') * count);
  }
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tar_getsize>:
  endbr64
  lea    0xa(%rdi),%rdx
  mov    $0x1,%ecx
  mov    $0x0,%esi
L5:
  movsbl (%rdx),%eax
  sub    $0x30,%eax
  imul   %ecx,%eax
  add    %eax,%esi
  shl    $0x3,%ecx
  mov    %rdx,%rax
  sub    $0x1,%rdx
  cmp    %rdi,%rax
  jne    L5
  mov    %esi,%eax
  ret
```

assistant: ```c
int tar_getsize(const char *in) {
  int size = 0;
  int i;
  int count = 1;
  for (i = 11; i > 0; i--, count *= 8) {
    size += ((in[i - 1] - '0') * count);
  }
  return size;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tar_getsize>:
  endbr64
  lea    0xa(%rdi),%rdx
  mov    $0x1,%ecx
  xor    %r8d,%r8d
L5:
  movsbl (%rdx),%eax
  sub    $0x30,%eax
  imul   %ecx,%eax
  shl    $0x3,%ecx
  add    %eax,%r8d
  mov    %rdx,%rax
  sub    $0x1,%rdx
  cmp    %rax,%rdi
  jne    L5
  mov    %r8d,%eax
  ret
```

assistant: ```c
int tar_getsize(const char *in) {
  int size = 0;
  int i;
  int count = 1;
  for (i = 11; i > 0; i--, count *= 8) {
    size += ((in[i - 1] - '0') * count);
  }
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tar_getsize>:
  endbr64
  movsbl 0x9(%rdi),%ecx
  movsbl 0xa(%rdi),%edx
  movsbl (%rdi),%eax
  lea    -0x1b0(%rdx,%rcx,8),%edx
  movsbl 0x8(%rdi),%ecx
  shl    $0x1e,%eax
  sub    $0x30,%ecx
  shl    $0x6,%ecx
  add    %edx,%ecx
  movsbl 0x7(%rdi),%edx
  sub    $0x30,%edx
  shl    $0x9,%edx
  add    %ecx,%edx
  movsbl 0x6(%rdi),%ecx
  sub    $0x30,%ecx
  shl    $0xc,%ecx
  add    %edx,%ecx
  movsbl 0x5(%rdi),%edx
  sub    $0x30,%edx
  shl    $0xf,%edx
  add    %ecx,%edx
  movsbl 0x4(%rdi),%ecx
  sub    $0x30,%ecx
  shl    $0x12,%ecx
  add    %edx,%ecx
  movsbl 0x3(%rdi),%edx
  sub    $0x30,%edx
  shl    $0x15,%edx
  add    %ecx,%edx
  movsbl 0x2(%rdi),%ecx
  sub    $0x30,%ecx
  shl    $0x18,%ecx
  add    %edx,%ecx
  movsbl 0x1(%rdi),%edx
  sub    $0x30,%edx
  shl    $0x1b,%edx
  add    %ecx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int tar_getsize(const char *in) {
  int size = 0;
  int i;
  int count = 1;
  for (i = 11; i > 0; i--, count *= 8) {
    size += ((in[i - 1] - '0') * count);
  }
  return size;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L29
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L30
L29:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  cmpl   $0x0,-0x4(%rbp)
  je     L38
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L17
L38:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string
name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D12
type_infered: string

tool: D14: x vrai


tool: D2: x faux


tool: D16: y vrai


tool: D12: y faux


assistant: ```c
main() {
  int x = 0;
  int y = -1;
  if (x)
    printf("x vrai\n");
  else
    printf("x faux\n");
  if (y)
    printf("y vrai\n");
  else
    printf("y faux\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string

tool: D9: x faux


tool: D19: y vrai


assistant: ```c
main() {
  int x = 0;
  int y = -1;
  if (x)
    printf("x vrai\n");
  else
    printf("x faux\n");
  if (y)
    printf("y vrai\n");
  else
    printf("y faux\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type: string
name: unpack_data
arguments: data_tag: D2
type: string

tool: D18: x faux


tool: D2: y vrai


assistant: ```c
main() {
  int x = 0;
  int y = -1;
  if (x)
    printf("x vrai\n");
  else
    printf("x faux\n");
  if (y)
    printf("y vrai\n");
  else
    printf("y faux\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D5: x faux


tool: D0: y vrai


assistant: ```c
main() {
  int x = 0;
  int y = -1;
  if (x)
    printf("x vrai\n");
  else
    printf("x faux\n");
  if (y)
    printf("y vrai\n");
  else
    printf("y faux\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  shl    $0x7,%eax
  and    $0xb500,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  shr    $0x3,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
      } else {
        state[local1] >>= ((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] >> (unsigned short)3;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x4,%eax
  and    $0x16a0,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
      } else {
        state[local1] >>= ((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] >> (unsigned short)3;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x4,%eax
  and    $0x16a0,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
      } else {
        state[local1] >>= ((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] >> (unsigned short)3;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x4,%eax
  and    $0x16a0,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
      } else {
        state[local1] >>= ((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] >> (unsigned short)3;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D54(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D38(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  lea    D39(%rip),%rdx
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <cov_log@plt>
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cov_check@plt>
  fldl   -0x28(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: f64
name: retrieve_data
arguments: data_tag: D54
data_type: f64
name: retrieve_data
arguments: data_tag: D38
data_type: f64
name: retrieve_data
arguments: data_tag: D10
data_type: f64
name: retrieve_data
arguments: data_tag: D39
data_type: string
name: retrieve_data
arguments: data_tag: D50
data_type: string

tool: D9: 2.1

tool: D54: 2.2

tool: D38: 2.3

tool: D10: 3

tool: D39: result

tool: D50: %1.15Le


assistant: ```c
int main(int argc, char *argv[]) {
  double a[3] = {2.1, 2.2, 2.3};
  double b = 3;
  double c = a[1] + b;
  cov_log(c, "result", argv[2]);
  cov_check(argv[2], argv[1], argv[3]);
  printf("%1.15Le\n", (long double)c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    0x10(%rsi),%rsi
  lea    D12(%rip),%rdi
  movsd  D16(%rip),%xmm0
  call   <cov_log@plt>
  mov    0x18(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <cov_check@plt>
  fldl   0xe7c(%rip)        # 2010 <_fini+0xe58>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_infered: string
name: extract_symbolic_data
arguments: label: D16
type_infered: byte[8]
name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D12: result

tool: {"D16": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0x14,0x40]}

tool: D6: %1.15Le


assistant: ```c
int main(int argc, char *argv[]) {
  double a[3] = {2.1, 2.2, 2.3};
  double b = 3;
  double c = a[1] + b;
  cov_log(c, "result", argv[2]);
  cov_check(argv[2], argv[1], argv[3]);
  printf("%1.15Le\n", (long double)c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  lea    D18(%rip),%rdi
  sub    $0x10,%rsp
  movsd  D7(%rip),%xmm0
  mov    0x10(%rsi),%rsi
  call   <cov_log@plt>
  mov    0x18(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <cov_check@plt>
  fldl   0xf35(%rip)        # 2010 <_fini+0xe54>
  lea    D4(%rip),%rdi
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  call   <printf@plt>
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D18
data_type: string
name: read_data
arguments: data_label: D7
data_type: byte[8]
name: read_data
arguments: data_label: D4
data_type: string

tool: D18: result

tool: {"D7": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0x14,0x40]}

tool: D4: %1.15Le


assistant: ```c
int main(int argc, char *argv[]) {
  double a[3] = {2.1, 2.2, 2.3};
  double b = 3;
  double c = a[1] + b;
  cov_log(c, "result", argv[2]);
  cov_check(argv[2], argv[1], argv[3]);
  printf("%1.15Le\n", (long double)c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  lea    D25(%rip),%rdi
  sub    $0x10,%rsp
  movsd  D0(%rip),%xmm0
  mov    0x10(%rsi),%rsi
  call   <cov_log@plt>
  mov    0x18(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <cov_check@plt>
  fldl   0xf35(%rip)        # 2010 <_fini+0xe54>
  lea    D2(%rip),%rdi
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  call   <printf@plt>
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: byte[8]
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D25: result

tool: {"D0": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0x14,0x40]}

tool: D2: %1.15Le


assistant: ```c
int main(int argc, char *argv[]) {
  double a[3] = {2.1, 2.2, 2.3};
  double b = 3;
  double c = a[1] + b;
  cov_log(c, "result", argv[2]);
  cov_check(argv[2], argv[1], argv[3]);
  printf("%1.15Le\n", (long double)c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dup_at_least_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
L39:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <dup@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0xffffffff,-0x24(%rbp)
  je     L1
  cmpl   $0x2,-0x1c(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x2,-0x1c(%rbp)
  jle    L28
  mov    $0x0,%eax
  call   <abort@plt>
L28:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  cltq
  mov    -0x24(%rbp),%edx
  mov    %edx,-0x14(%rbp,%rax,4)
  cmpl   $0x2,-0x24(%rbp)
  jle    L39
  subl   $0x1,-0x1c(%rbp)
  jmp    L31
L1:
  nop
L31:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L50
L49:
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <close@plt>
L50:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L49
  mov    D1(%rip),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
int dup_at_least_3(int old) {
  int intermediary[3];
  int i = 0, saved_errno;
  do {
    if (old = dup(old), old == -1)
      goto fail;
    assert(i < 3);
    if (i >= 3)
      abort();
    intermediary[i++] = old;
  } while (old < 3);
  i--;
fail:
  saved_errno = errno;
  while (i--)
    close(intermediary[i]);
  errno = saved_errno;
  return old;
}
```