ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    $0xffffffffffffffff,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jle    L42
L12:
  mov    0x8(%rbp),%rdi
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %r12,%rdx
  lea    D32(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  je     L58
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  lea    0x4(%rsp),%r14
  lea    D30(%rip),%r13
  xchg   %ax,%ax
L49:
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  add    %rax,%r12
  cmp    %ebx,(%rsp)
  ja     L49
  jmp    L12
L58:
  xor    %r12d,%r12d
  jmp    L12
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D32
type: string
name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D30
type: string

tool: D3: w

tool: D32: %lld


tool: D5: %u

tool: D30: %i

assistant: ```c
int main(int argc, char **argv) {
  long long sum = -1;
  if (2 >= argc) {
    unsigned n;
    scanf("%u", &n);
    sum = 0;
    int current = 0;
    for (unsigned i = 0; i < n; ++i) {
      scanf("%i", &current);
      sum += current;
    }
  }
  FILE *out = fopen(argv[1], "w");
  fprintf(out, "%lld\n", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<submatch>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  add    $0x1,%rdi
  mov    $0x1,%r8d
L293:
  lea    -0x1(%rdi),%rbp
  lea    0x1(%rsi),%rbx
  movzbl (%rsi),%eax
  cmp    $0x2a,%al
  je     L282
  jbe    L251
  cmp    $0x3f,%al
  je     L80
  cmp    $0x5b,%al
  jne    L161
  movzbl 0x1(%rsi),%edx
  cmp    $0x5e,%dl
  sete   %al
  cmp    $0x21,%dl
  sete   %cl
  or     %ecx,%eax
  movzbl %al,%r9d
  test   %al,%al
  je     L144
  lea    0x2(%rsi),%rbx
  lea    0x3(%rsi),%rcx
  movzbl 0x2(%rsi),%edx
  cmp    $0x5d,%dl
  jne    L300
  mov    %rcx,%rbx
  jmp    L70
L251:
  test   %al,%al
  je     L162
  cmp    $0x24,%al
  jne    L161
  cmpb   $0x0,0x0(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L18
L282:
  mov    $0x1,%eax
  cmpb   $0x0,0x1(%rsi)
  je     L18
  cmpb   $0x0,0x0(%rbp)
  je     L168
L256:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match@plt>
  test   %eax,%eax
  jne    L33
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L256
  jmp    L18
L80:
  cmpb   $0x0,-0x1(%rdi)
  je     L77
L70:
  add    $0x1,%rdi
  mov    %rbx,%rsi
  jmp    L293
L161:
  cmp    -0x1(%rdi),%al
  je     L70
  mov    $0x0,%eax
  jmp    L18
L23:
  mov    %rbx,%rax
  cmp    %dl,-0x1(%rdi)
  cmove  %r8d,%ecx
L244:
  lea    0x1(%rax),%rbx
  movzbl (%rax),%edx
  cmp    $0x5d,%dl
  je     L266
L137:
  cmpb   $0x2d,0x1(%rax)
  jne    L23
  movzbl -0x1(%rdi),%esi
  cmp    %dl,%sil
  jb     L56
  cmp    0x2(%rax),%sil
  cmovbe %r8d,%ecx
L56:
  add    $0x3,%rax
  jmp    L244
L266:
  cmp    %r9d,%ecx
  jne    L70
  mov    $0x0,%eax
  jmp    L18
L162:
  mov    $0x1,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L168:
  mov    $0x0,%eax
  jmp    L18
L33:
  mov    $0x1,%eax
  jmp    L18
L77:
  mov    $0x0,%eax
  jmp    L18
L144:
  lea    0x2(%rsi),%rcx
  cmp    $0x5d,%dl
  je     L64
L300:
  mov    %rbx,%rax
  mov    %rcx,%rbx
  mov    $0x0,%ecx
  jmp    L137
L64:
  mov    $0x0,%eax
  jmp    L18
```

assistant: ```c
int submatch(unsigned char *name, unsigned char *pat) {
  int ok, negate_range;
  for (;;) {
    switch (*pat++) {
    case '*':
      if (!*pat)
        return (1);
      for (; *name; ++name)
        if (match(name, pat))
          return (1);
      return (0);
    case '?':
      if (!*name++)
        return (0);
      break;
    case '$':
      return (!*name);
    case 0:
      return (1);
    default:
      if (*name++ != pat[-1])
        return (0);
      break;
    case '[':
      ok = 0;
      negate_range = (*pat == '^' || *pat == '!');
      if (negate_range)
        ++pat;
      while (*pat++ != ']')
        if (*pat == '-') {
          if (pat[-1] <= *name && *name <= pat[1])
            ok = 1;
          pat += 2;
        } else if (pat[-1] == *name)
          ok = 1;
      if (ok == negate_range)
        return (0);
      ++name;
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<submatch>:
  endbr64
  push   %rbp
  add    $0x1,%rdi
  mov    $0x1,%r8d
  push   %rbx
  lea    -0x1(%rdi),%rbp
  lea    0x1(%rsi),%rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  cmp    $0x2a,%al
  je     L6
L187:
  ja     L161
  test   %al,%al
  je     L33
  cmp    $0x24,%al
  jne    L136
  xor    %eax,%eax
  cmpb   $0x0,0x0(%rbp)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L161:
  cmp    $0x3f,%al
  je     L159
  cmp    $0x5b,%al
  jne    L136
  movzbl 0x1(%rsi),%edx
  cmp    $0x5e,%dl
  sete   %al
  cmp    $0x21,%dl
  sete   %cl
  or     %ecx,%eax
  movzbl %al,%r9d
  test   %al,%al
  jne    L211
  lea    0x2(%rsi),%rcx
  cmp    $0x5d,%dl
  je     L239
L84:
  mov    %rbx,%rax
  movzbl -0x1(%rdi),%esi
  mov    %rcx,%rbx
  xor    %ecx,%ecx
  jmp    L235
  nopl   (%rax)
L227:
  mov    %rbx,%rax
  cmp    %dl,%sil
  movzbl (%rax),%edx
  cmove  %r8d,%ecx
  lea    0x1(%rax),%rbx
  cmp    $0x5d,%dl
  je     L201
L235:
  cmpb   $0x2d,0x1(%rax)
  jne    L227
  cmp    %dl,%sil
  jb     L99
  cmp    0x2(%rax),%sil
  cmovbe %r8d,%ecx
L99:
  movzbl 0x3(%rax),%edx
  add    $0x3,%rax
  lea    0x1(%rax),%rbx
  cmp    $0x5d,%dl
  jne    L235
L201:
  cmp    %r9d,%ecx
  jne    L56
L239:
  xor    %eax,%eax
L110:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L136:
  cmp    -0x1(%rdi),%al
  jne    L239
L56:
  mov    %rbx,%rsi
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  lea    -0x1(%rdi),%rbp
  lea    0x1(%rsi),%rbx
  cmp    $0x2a,%al
  jne    L187
L6:
  cmpb   $0x0,0x1(%rsi)
  jne    L24
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L53:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match@plt>
  test   %eax,%eax
  jne    L33
  add    $0x1,%rbp
L24:
  cmpb   $0x0,0x0(%rbp)
  jne    L53
  xor    %eax,%eax
  jmp    L110
  nopl   (%rax)
L159:
  cmpb   $0x0,-0x1(%rdi)
  jne    L56
  xor    %eax,%eax
  jmp    L110
  nopw   0x0(%rax,%rax,1)
L211:
  movzbl 0x2(%rsi),%edx
  lea    0x2(%rsi),%rbx
  lea    0x3(%rsi),%rcx
  cmp    $0x5d,%dl
  jne    L84
  mov    %rcx,%rbx
  jmp    L56
```

assistant: ```c
int submatch(unsigned char *name, unsigned char *pat) {
  int ok, negate_range;
  for (;;) {
    switch (*pat++) {
    case '*':
      if (!*pat)
        return (1);
      for (; *name; ++name)
        if (match(name, pat))
          return (1);
      return (0);
    case '?':
      if (!*name++)
        return (0);
      break;
    case '$':
      return (!*name);
    case 0:
      return (1);
    default:
      if (*name++ != pat[-1])
        return (0);
      break;
    case '[':
      ok = 0;
      negate_range = (*pat == '^' || *pat == '!');
      if (negate_range)
        ++pat;
      while (*pat++ != ']')
        if (*pat == '-') {
          if (pat[-1] <= *name && *name <= pat[1])
            ok = 1;
          pat += 2;
        } else if (pat[-1] == *name)
          ok = 1;
      if (ok == negate_range)
        return (0);
      ++name;
      break;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<submatch>:
  endbr64
  push   %rbp
  add    $0x1,%rdi
  mov    $0x1,%r8d
  push   %rbx
  lea    -0x1(%rdi),%rbp
  lea    0x1(%rsi),%rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  cmp    $0x2a,%al
  je     L153
L37:
  ja     L97
  test   %al,%al
  je     L49
  cmp    $0x24,%al
  jne    L132
  xor    %eax,%eax
  cmpb   $0x0,0x0(%rbp)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L97:
  cmp    $0x3f,%al
  je     L21
  cmp    $0x5b,%al
  jne    L132
  movzbl 0x1(%rsi),%edx
  cmp    $0x5e,%dl
  sete   %al
  cmp    $0x21,%dl
  sete   %cl
  or     %ecx,%eax
  movzbl %al,%r9d
  test   %al,%al
  jne    L54
  lea    0x2(%rsi),%rcx
  cmp    $0x5d,%dl
  je     L75
L50:
  mov    %rbx,%rax
  movzbl -0x1(%rdi),%esi
  mov    %rcx,%rbx
  xor    %ecx,%ecx
  jmp    L129
  nopl   (%rax)
L53:
  mov    %rbx,%rax
  cmp    %sil,%dl
  movzbl (%rax),%edx
  cmove  %r8d,%ecx
  lea    0x1(%rax),%rbx
  cmp    $0x5d,%dl
  je     L173
L129:
  cmpb   $0x2d,0x1(%rax)
  jne    L53
  cmp    %sil,%dl
  ja     L19
  cmp    %sil,0x2(%rax)
  cmovae %r8d,%ecx
L19:
  movzbl 0x3(%rax),%edx
  add    $0x3,%rax
  lea    0x1(%rax),%rbx
  cmp    $0x5d,%dl
  jne    L129
L173:
  cmp    %r9d,%ecx
  jne    L213
L75:
  xor    %eax,%eax
L176:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L49:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L132:
  cmp    -0x1(%rdi),%al
  jne    L75
L213:
  mov    %rbx,%rsi
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  lea    -0x1(%rdi),%rbp
  lea    0x1(%rsi),%rbx
  cmp    $0x2a,%al
  jne    L37
L153:
  cmpb   $0x0,0x1(%rsi)
  jne    L65
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match@plt>
  test   %eax,%eax
  jne    L49
  add    $0x1,%rbp
L65:
  cmpb   $0x0,0x0(%rbp)
  jne    L58
  xor    %eax,%eax
  jmp    L176
  nopl   (%rax)
L21:
  cmpb   $0x0,-0x1(%rdi)
  jne    L213
  xor    %eax,%eax
  jmp    L176
  nopw   0x0(%rax,%rax,1)
L54:
  movzbl 0x2(%rsi),%edx
  lea    0x2(%rsi),%rbx
  lea    0x3(%rsi),%rcx
  cmp    $0x5d,%dl
  jne    L50
  mov    %rcx,%rbx
  jmp    L213
```

assistant: ```c
int submatch(unsigned char *name, unsigned char *pat) {
  int ok, negate_range;
  for (;;) {
    switch (*pat++) {
    case '*':
      if (!*pat)
        return (1);
      for (; *name; ++name)
        if (match(name, pat))
          return (1);
      return (0);
    case '?':
      if (!*name++)
        return (0);
      break;
    case '$':
      return (!*name);
    case 0:
      return (1);
    default:
      if (*name++ != pat[-1])
        return (0);
      break;
    case '[':
      ok = 0;
      negate_range = (*pat == '^' || *pat == '!');
      if (negate_range)
        ++pat;
      while (*pat++ != ']')
        if (*pat == '-') {
          if (pat[-1] <= *name && *name <= pat[1])
            ok = 1;
          pat += 2;
        } else if (pat[-1] == *name)
          ok = 1;
      if (ok == negate_range)
        return (0);
      ++name;
      break;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Q_strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L36
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <Q_tolower@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <Q_tolower@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L18
  mov    $0xffffffff,%eax
  jmp    L17
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L36
  mov    $0x1,%eax
  jmp    L17
L36:
  cmpl   $0x0,-0x8(%rbp)
  jne    L28
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
int Q_strcasecmp(const char *s1, const char *s2) {
  int c1, c2;
  do {
    c1 = *s1++;
    c2 = *s2++;
    if (c1 != c2) {
      c1 = Q_tolower(c1);
      c2 = Q_tolower(c2);
      if (c1 < c2)
        return -1;
      if (c1 > c2)
        return 1;
    }
  } while (c1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Q_strcasecmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  jmp    L0
L48:
  test   %ebx,%ebx
  je     L66
L0:
  add    $0x1,%r12
  movsbl -0x1(%r12),%edi
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%ebx
  cmp    %ebx,%edi
  je     L48
  call   <Q_tolower@plt>
  mov    %eax,%r13d
  mov    %ebx,%edi
  call   <Q_tolower@plt>
  cmp    %eax,%r13d
  jl     L38
  jg     L40
  mov    %r13d,%ebx
  jmp    L48
L38:
  mov    $0xffffffff,%ebx
L66:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  mov    $0x1,%ebx
  jmp    L66
```

assistant: ```c
int Q_strcasecmp(const char *s1, const char *s2) {
  int c1, c2;
  do {
    c1 = *s1++;
    c2 = *s2++;
    if (c1 != c2) {
      c1 = Q_tolower(c1);
      c2 = Q_tolower(c2);
      if (c1 < c2)
        return -1;
      if (c1 > c2)
        return 1;
    }
  } while (c1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Q_strcasecmp>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  movsbl (%r12),%edi
  movsbl (%rbx),%ebp
  add    $0x1,%r12
  add    $0x1,%rbx
  cmp    %ebp,%edi
  je     L28
  call   <Q_tolower@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <Q_tolower@plt>
  cmp    %eax,%r13d
  jl     L25
  jg     L12
  mov    %r13d,%ebp
L28:
  test   %ebp,%ebp
  jne    L17
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  add    $0x8,%rsp
  mov    $0xffffffff,%ebp
  pop    %rbx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x8,%rsp
  mov    $0x1,%ebp
  pop    %rbx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int Q_strcasecmp(const char *s1, const char *s2) {
  int c1, c2;
  do {
    c1 = *s1++;
    c2 = *s2++;
    if (c1 != c2) {
      c1 = Q_tolower(c1);
      c2 = Q_tolower(c2);
      if (c1 < c2)
        return -1;
      if (c1 > c2)
        return 1;
    }
  } while (c1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Q_strcasecmp>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L18:
  movsbl (%r12),%edi
  movsbl (%rbx),%ebp
  add    $0x1,%r12
  add    $0x1,%rbx
  cmp    %ebp,%edi
  je     L9
  call   <Q_tolower@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <Q_tolower@plt>
  cmp    %eax,%r13d
  jl     L26
  jg     L19
  mov    %r13d,%ebp
L9:
  test   %ebp,%ebp
  jne    L18
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  mov    $0xffffffff,%ebp
  pop    %rbx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  mov    $0x1,%ebp
  pop    %rbx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int Q_strcasecmp(const char *s1, const char *s2) {
  int c1, c2;
  do {
    c1 = *s1++;
    c2 = *s2++;
    if (c1 != c2) {
      c1 = Q_tolower(c1);
      c2 = Q_tolower(c2);
      if (c1 < c2)
        return -1;
      if (c1 > c2)
        return 1;
    }
  } while (c1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<filesize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L10
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L10:
  mov    -0x10(%rbp),%rax
  mov    %eax,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int filesize(char *filename) {
  int size;
  struct stat fileinfo;
  if (stat(filename, &fileinfo) != 0)
    size = (int)0;
  else
    size = (int)fileinfo.st_size;
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<filesize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filesize(char *filename) {
  int size;
  struct stat fileinfo;
  if (stat(filename, &fileinfo) != 0)
    size = (int)0;
  else
    size = (int)fileinfo.st_size;
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<filesize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filesize(char *filename) {
  int size;
  struct stat fileinfo;
  if (stat(filename, &fileinfo) != 0)
    size = (int)0;
  else
    size = (int)fileinfo.st_size;
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<filesize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filesize(char *filename) {
  int size;
  struct stat fileinfo;
  if (stat(filename, &fileinfo) != 0)
    size = (int)0;
  else
    size = (int)fileinfo.st_size;
  return size;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <middle@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <middle@plt>
  lea    -0x10(%rbp),%rax
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <middle@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0xe,%esi
  mov    %rax,%rdi
  call   <push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <push@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printList@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <middle@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D7: 
Given linked list 


assistant: ```c
int main(void) {
  struct LinkedListNode *head = NULL;
  middle(head);
  push(&head, 4);
  middle(head);
  push(&head, 11);
  middle(head);
  push(&head, 7);
  push(&head, 8);
  push(&head, 5);
  push(&head, 14);
  push(&head, 3);
  push(&head, 2);
  push(&head, 1);
  printf("\nGiven linked list \n");
  printList(head);
  middle(head);
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%edi
  call   <middle@plt>
  mov    %rsp,%rbx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    (%rsp),%rdi
  call   <middle@plt>
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    (%rsp),%rdi
  call   <middle@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    $0xe,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <printList@plt>
  mov    (%rsp),%rdi
  call   <middle@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string

tool: D6: 
Given linked list 


assistant: ```c
int main(void) {
  struct LinkedListNode *head = NULL;
  middle(head);
  push(&head, 4);
  middle(head);
  push(&head, 11);
  middle(head);
  push(&head, 7);
  push(&head, 8);
  push(&head, 5);
  push(&head, 14);
  push(&head, 3);
  push(&head, 2);
  push(&head, 1);
  printf("\nGiven linked list \n");
  printList(head);
  middle(head);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  call   <middle@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    (%rsp),%rdi
  call   <middle@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    (%rsp),%rdi
  call   <middle@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    $0xe,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <printList@plt>
  mov    (%rsp),%rdi
  call   <middle@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D0: 
Given linked list 


assistant: ```c
int main(void) {
  struct LinkedListNode *head = NULL;
  middle(head);
  push(&head, 4);
  middle(head);
  push(&head, 11);
  middle(head);
  push(&head, 7);
  push(&head, 8);
  push(&head, 5);
  push(&head, 14);
  push(&head, 3);
  push(&head, 2);
  push(&head, 1);
  printf("\nGiven linked list \n");
  printList(head);
  middle(head);
  return (0);
}
```