user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D99(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D91
datatype: string
name: disassemble_data
arguments: data_tag: D76
datatype: string
name: disassemble_data
arguments: data_tag: D24
datatype: string
name: disassemble_data
arguments: data_tag: D55
datatype: string
name: disassemble_data
arguments: data_tag: D40
datatype: string
name: disassemble_data
arguments: data_tag: D99
datatype: string
name: disassemble_data
arguments: data_tag: D62
datatype: string
name: disassemble_data
arguments: data_tag: D63
datatype: string
name: disassemble_data
arguments: data_tag: D53
datatype: string

tool: D91: Enter the value of a: 

tool: D76: %d

tool: D24: Enter the value of b: 

tool: D55: The result of a+=b operator is %d . 


tool: D40: The result of a-=b operator is %d . 


tool: D99: The result of a*=b operator is %d 


tool: D62: The result of a/=b operator is %d 


tool: D63: The result of a%=b operator is %d 


tool: D53: The result of a=b operator is %d 


assistant: ```c
int main() {
  int a, b;
  printf("Enter the value of a: ");
  scanf("%d", &a);
  printf("Enter the value of b: ");
  scanf("%d", &b);
  a += b;
  printf("The result of a+=b operator is %d . \n", a);
  a -= b;
  printf("The result of a-=b operator is %d . \n", a);
  a *= b;
  printf("The result of a*=b operator is %d \n", a);
  a /= b;
  printf("The result of a/=b operator is %d \n", a);
  a %= b;
  printf("The result of a%=b operator is %d \n", a);
  a = b;
  printf("The result of a=b operator is %d \n", a);
  return 0;
}
```