ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<cut_selection>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <copy_selection@plt>
  mov    %rbp,%rdi
  call   <erase_selection@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <select_toggle@plt>
```

assistant: ```c
void cut_selection(struct editor *ed) {
  copy_selection(ed);
  erase_selection(ed);
  select_toggle(ed);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cut_selection>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <copy_selection@plt>
  mov    %rbp,%rdi
  call   <erase_selection@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <select_toggle@plt>
```

assistant: ```c
void cut_selection(struct editor *ed) {
  copy_selection(ed);
  erase_selection(ed);
  select_toggle(ed);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_209_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_209_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D ^ T;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What is the c source code of the assembly code below?

```asm
<rop3_209_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  xor    (%rdi),%sil
  or     %eax,%esi
  xor    %edx,%esi
  or     %eax,%esi
  not    %esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_209_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D ^ T;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_209_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  xor    %edx,%esi
  or     %eax,%esi
  xor    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_209_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D ^ T;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rop3_209_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  xor    %edx,%esi
  or     %eax,%esi
  xor    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_209_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D ^ T;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L34:
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L12:
  mov    -0x8(%rbp),%eax
  lea    0x40(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L33:
  mov    $0x6,%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L12
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L20:
  cmpl   $0x5,-0x8(%rbp)
  jle    L34
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6 - i; j++) {
      printf("%c", 'F' - (6 - i) + j + 1);
    }
    printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x6,%ebp
  mov    $0x47,%r12d
L19:
  mov    %r12d,%ebx
  sub    %ebp,%ebx
  test   %ebp,%ebp
  jle    L24
L11:
  mov    %ebx,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    $0x47,%ebx
  jne    L11
L24:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L19
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6 - i; j++) {
      printf("%c", 'F' - (6 - i) + j + 1);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  lea    0x41(%rbp),%ebx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x47,%ebx
  jne    L17
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    $0x6,%ebp
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6 - i; j++) {
      printf("%c", 'F' - (6 - i) + j + 1);
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  lea    0x41(%rbp),%ebx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x47,%ebx
  jne    L0
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    $0x6,%ebp
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6 - i; j++) {
      printf("%c", 'F' - (6 - i) + j + 1);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ijkl2intindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L10
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%esi
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <ijkl2intindex>
  jmp    L3
L10:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L41
  mov    -0x1c(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ijkl2intindex>
  jmp    L3
L41:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L24
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
L3:
  leave
  ret
```

assistant: ```c
int ijkl2intindex(int i, int j, int k, int l) {
  int tmp, ij, kl;
  if (i < j)
    return ijkl2intindex(j, i, k, l);
  if (k < l)
    return ijkl2intindex(i, j, l, k);
  ij = i * (i + 1) / 2 + j;
  kl = k * (k + 1) / 2 + l;
  if (ij < kl) {
    tmp = ij;
    ij = kl;
    kl = tmp;
  }
  return ij * (ij + 1) / 2 + kl;
}
```
user: What is the c source code of the assembly code below:

```asm
<ijkl2intindex>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  mov    %ecx,%esi
  cmp    %eax,%edi
  jl     L15
  cmp    %ecx,%edx
  jl     L10
  lea    0x1(%rdi),%ecx
  imul   %edi,%ecx
  mov    %ecx,%edi
  shr    $0x1f,%edi
  add    %ecx,%edi
  sar    %edi
  add    %eax,%edi
  lea    0x1(%rdx),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  add    %esi,%edx
  cmp    %edx,%edi
  jge    L33
  mov    %edi,%eax
  mov    %edx,%edi
  mov    %eax,%edx
L33:
  lea    0x1(%rdi),%ecx
  imul   %edi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %edx,%eax
L6:
  add    $0x8,%rsp
  ret
L15:
  mov    %edi,%esi
  mov    %eax,%edi
  call   <ijkl2intindex>
  jmp    L6
L10:
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  call   <ijkl2intindex>
  jmp    L6
```

assistant: ```c
int ijkl2intindex(int i, int j, int k, int l) {
  int tmp, ij, kl;
  if (i < j)
    return ijkl2intindex(j, i, k, l);
  if (k < l)
    return ijkl2intindex(i, j, l, k);
  ij = i * (i + 1) / 2 + j;
  kl = k * (k + 1) / 2 + l;
  if (ij < kl) {
    tmp = ij;
    ij = kl;
    kl = tmp;
  }
  return ij * (ij + 1) / 2 + kl;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ijkl2intindex>:
  endbr64
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %edi,%eax
  mov    %esi,%edi
  mov    %eax,%esi
L43:
  cmp    %esi,%edi
  jl     L4
  cmp    %edx,%ecx
  jle    L22
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %eax,%ecx
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L22:
  lea    0x1(%rdi),%eax
  imul   %eax,%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  add    %esi,%eax
  lea    0x1(%rdx),%esi
  imul   %edx,%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jge    L29
  mov    %eax,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
L29:
  lea    0x1(%rax),%ecx
  imul   %eax,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %edx,%eax
  ret
```

assistant: ```c
int ijkl2intindex(int i, int j, int k, int l) {
  int tmp, ij, kl;
  if (i < j)
    return ijkl2intindex(j, i, k, l);
  if (k < l)
    return ijkl2intindex(i, j, l, k);
  ij = i * (i + 1) / 2 + j;
  kl = k * (k + 1) / 2 + l;
  if (ij < kl) {
    tmp = ij;
    ij = kl;
    kl = tmp;
  }
  return ij * (ij + 1) / 2 + kl;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ijkl2intindex>:
  endbr64
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %edi,%eax
  mov    %esi,%edi
  mov    %eax,%esi
L29:
  cmp    %esi,%edi
  jl     L19
  cmp    %edx,%ecx
  jle    L16
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %eax,%ecx
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L16:
  lea    0x1(%rdi),%eax
  imul   %eax,%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  add    %esi,%eax
  lea    0x1(%rdx),%esi
  imul   %edx,%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jge    L41
  mov    %eax,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
L41:
  lea    0x1(%rax),%ecx
  imul   %eax,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %edx,%eax
  ret
```

assistant: ```c
int ijkl2intindex(int i, int j, int k, int l) {
  int tmp, ij, kl;
  if (i < j)
    return ijkl2intindex(j, i, k, l);
  if (k < l)
    return ijkl2intindex(i, j, l, k);
  ij = i * (i + 1) / 2 + j;
  kl = k * (k + 1) / 2 + l;
  if (ij < kl) {
    tmp = ij;
    ij = kl;
    kl = tmp;
  }
  return ij * (ij + 1) / 2 + kl;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L11
L19:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
L11:
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *basename(const char *filename) {
  const char *base;
  const char *x;
  base = filename;
  for (x = filename; *x != 0; ++x) {
    if (*x == '/' || *x == '\\')
      base = x + 1;
  }
  return base;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<basename>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L38
  lea    0x1(%rdi),%rcx
  jmp    L28
L29:
  mov    %rcx,%rax
L14:
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  je     L38
L28:
  cmp    $0x2f,%dl
  je     L29
  cmp    $0x5c,%dl
  jne    L14
  jmp    L29
L38:
  ret
```

assistant: ```c
const char *basename(const char *filename) {
  const char *base;
  const char *x;
  base = filename;
  for (x = filename; *x != 0; ++x) {
    if (*x == '/' || *x == '\\')
      base = x + 1;
  }
  return base;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<basename>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  jne    L51
  jmp    L4
L35:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
L51:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  je     L42
  cmp    $0x5c,%al
  jne    L35
L42:
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  jne    L51
L4:
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *basename(const char *filename) {
  const char *base;
  const char *x;
  base = filename;
  for (x = filename; *x != 0; ++x) {
    if (*x == '/' || *x == '\\')
      base = x + 1;
  }
  return base;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<basename>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  jne    L53
  jmp    L36
L0:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
L53:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  je     L15
  cmp    $0x5c,%al
  jne    L0
L15:
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  jne    L53
L36:
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *basename(const char *filename) {
  const char *base;
  const char *x;
  base = filename;
  for (x = filename; *x != 0; ++x) {
    if (*x == '/' || *x == '\\')
      base = x + 1;
  }
  return base;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xce4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  mov    $0xce4,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fpsimple_log_9j>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,0x18(%rsp)
  mov    %r8d,%r13d
  mov    %r9d,0x1c(%rsp)
  mov    0xa0(%rsp),%r14d
  mov    0xa8(%rsp),%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %esi,%eax
  sub    %r15d,%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    %r12d,%eax
  sub    0x90(%rsp),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    %r14d,%eax
  sub    %r8d,%eax
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  call   <max3@plt>
  mov    %eax,%ebx
  lea    0x0(%rbp,%r15,1),%edx
  mov    %r12d,%esi
  add    0x90(%rsp),%esi
  lea    (%r14,%r13,1),%edi
  call   <min3@plt>
  mov    %eax,0x14(%rsp)
  cmp    %eax,%ebx
  jg     L16
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x20(%rsp)
L6:
  sub    $0x8,%rsp
  push   %rbx
  mov    %r15d,%r9d
  mov    0xa0(%rsp),%r8d
  mov    0x28(%rsp),%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    0x30(%rsp),%rdi
  call   <fpsimple_log_6j@plt>
  lea    0x48(%rsp),%rdi
  mov    %ebx,(%rsp)
  mov    %r12d,%r9d
  mov    %r14d,%r8d
  mov    0x2c(%rsp),%ecx
  mov    %r13d,%edx
  mov    0xa0(%rsp),%esi
  call   <fpsimple_log_6j@plt>
  lea    0x50(%rsp),%rdi
  mov    %ebx,(%rsp)
  mov    %r13d,%r9d
  mov    %ebp,%r8d
  mov    0xa8(%rsp),%ecx
  mov    %r15d,%edx
  mov    %r14d,%esi
  call   <fpsimple_log_6j@plt>
  movsd  0x40(%rsp),%xmm0
  mulsd  0x48(%rsp),%xmm0
  mulsd  0x50(%rsp),%xmm0
  lea    0x1(%rbx),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm1,%xmm0
  mov    %ebx,%edx
  and    $0x1,%edx
  add    %edx,%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x18(%rsp)
  add    $0x2,%ebx
  add    $0x10,%rsp
  cmp    %ebx,0x14(%rsp)
  jge    L6
L13:
  mov    0x28(%rsp),%rax
  movsd  0x8(%rsp),%xmm3
  movsd  %xmm3,(%rax)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
  jmp    L13
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fpsimple_log_9j(double *result, int two_a, int two_b, int two_c, int two_d, int two_e, int two_f, int two_g, int two_h, int two_i) {
  int two_kmin = max3(abs(two_h - two_d), abs(two_b - two_f), abs(two_a - two_i));
  int two_kmax = min3(two_h + two_d, two_b + two_f, two_a + two_i);
  int two_k;
  double sum_prod = 0;
  for (two_k = two_kmin; two_k <= two_kmax; two_k += 2) {
    double f1, f2, f3;
    fpsimple_log_6j(&f1, two_a, two_b, two_c, two_f, two_i, two_k);
    fpsimple_log_6j(&f2, two_f, two_d, two_e, two_h, two_b, two_k);
    fpsimple_log_6j(&f3, two_h, two_i, two_g, two_a, two_d, two_k);
    double factor = f1 * f2 * f3;
    double prod = (two_k + 1) * factor;
    sum_prod += (1 - 2 * ((two_k)&1)) * prod;
  }
  *result = sum_prod;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fpsimple_log_9j>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x68,%rsp
  mov    %rdi,0x38(%rsp)
  mov    0xb8(%rsp),%r15d
  mov    %ecx,0x18(%rsp)
  mov    0xa0(%rsp),%r13d
  mov    %r9d,0x1c(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  mov    %esi,%eax
  sub    %r15d,%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    %ebp,%eax
  sub    %r13d,%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    0xb0(%rsp),%eax
  sub    %r8d,%eax
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  call   <max3@plt>
  mov    0xb0(%rsp),%edi
  lea    (%rbx,%r15,1),%edx
  lea    0x0(%rbp,%r13,1),%esi
  mov    %eax,%r14d
  add    %r12d,%edi
  call   <min3@plt>
  pxor   %xmm1,%xmm1
  mov    %eax,0x14(%rsp)
  cmp    %eax,%r14d
  jg     L16
  lea    0x40(%rsp),%rax
  mov    %rax,0x30(%rsp)
  lea    0x48(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    0x50(%rsp),%rax
  mov    %rax,0x28(%rsp)
  nopl   (%rax)
L10:
  movsd  %xmm1,0x8(%rsp)
  sub    $0x8,%rsp
  mov    %r15d,%r9d
  mov    %r13d,%r8d
  push   %r14
  mov    0x28(%rsp),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    0x40(%rsp),%rdi
  call   <fpsimple_log_6j@plt>
  mov    0x2c(%rsp),%ecx
  mov    %ebp,%r9d
  mov    %r12d,%edx
  mov    0xc0(%rsp),%r8d
  mov    0x30(%rsp),%rdi
  mov    %r13d,%esi
  mov    %r14d,(%rsp)
  call   <fpsimple_log_6j@plt>
  mov    0x38(%rsp),%rdi
  mov    %r15d,%edx
  mov    %r12d,%r9d
  mov    0xb8(%rsp),%ecx
  mov    0xc0(%rsp),%esi
  mov    %ebx,%r8d
  mov    %r14d,(%rsp)
  call   <fpsimple_log_6j@plt>
  movsd  0x50(%rsp),%xmm0
  mulsd  0x58(%rsp),%xmm0
  lea    0x1(%r14),%eax
  mulsd  0x60(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  mov    $0x1,%edx
  movsd  0x18(%rsp),%xmm1
  cvtsi2sd %eax,%xmm2
  mov    %r14d,%eax
  add    $0x2,%r14d
  and    $0x1,%eax
  add    %eax,%eax
  sub    %eax,%edx
  pop    %rax
  mulsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %edx,%xmm2
  pop    %rdx
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %r14d,0x14(%rsp)
  jge    L10
L16:
  mov    0x38(%rsp),%rax
  movsd  %xmm1,(%rax)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fpsimple_log_9j(double *result, int two_a, int two_b, int two_c, int two_d, int two_e, int two_f, int two_g, int two_h, int two_i) {
  int two_kmin = max3(abs(two_h - two_d), abs(two_b - two_f), abs(two_a - two_i));
  int two_kmax = min3(two_h + two_d, two_b + two_f, two_a + two_i);
  int two_k;
  double sum_prod = 0;
  for (two_k = two_kmin; two_k <= two_kmax; two_k += 2) {
    double f1, f2, f3;
    fpsimple_log_6j(&f1, two_a, two_b, two_c, two_f, two_i, two_k);
    fpsimple_log_6j(&f2, two_f, two_d, two_e, two_h, two_b, two_k);
    fpsimple_log_6j(&f3, two_h, two_i, two_g, two_a, two_d, two_k);
    double factor = f1 * f2 * f3;
    double prod = (two_k + 1) * factor;
    sum_prod += (1 - 2 * ((two_k)&1)) * prod;
  }
  *result = sum_prod;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_init_memory_stack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L23:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L23
L21:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L51
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L51:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L32
L46:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x44(%rbp),%eax
  sub    -0x34(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x34(%rbp)
L32:
  mov    -0x34(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L46
  mov    -0x20(%rbp),%rax
  mov    %rsi,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int *get_init_memory_stack(int size) {
  int arr[size];
  int *p = arr;
  for (int i = 0; i < size; i++)
    p[i] = size - i;
  return p;
}
```