ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<transfer_YUV888_to_YUV101010>:
  endbr64
  push   %rbx
  movzbl (%rsi),%eax
  shl    $0x18,%eax
  movzbl 0x1(%rsi),%ecx
  shl    $0xe,%ecx
  or     %ecx,%eax
  movzbl 0x2(%rsi),%ecx
  shl    $0x4,%ecx
  or     %ecx,%eax
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %al,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  movzbl %ah,%ebx
  mov    %bl,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %eax,%esi
  sar    $0x10,%esi
  mov    %sil,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  shr    $0x18,%eax
  mov    %al,(%rcx)
  pop    %rbx
  ret
```

assistant: ```c
void transfer_YUV888_to_YUV101010(unsigned char *(*output), unsigned char *input) {
  uint16_t y_i = ((uint16_t)input[0]) << 8;
  uint16_t u_i = ((uint16_t)input[1]) << 8;
  uint16_t v_i = ((uint16_t)input[2]) << 8;
  {
    uint32_t output_i = ((y_i & 0xffc0) << 16) | ((u_i & 0xffc0) << 6) | ((v_i & 0xffc0) >> 4);
    *(*output)++ = (output_i & 0xff);
    *(*output)++ = (output_i & 0xff00) >> 8;
    *(*output)++ = (output_i & 0xff0000) >> 16;
    *(*output)++ = (output_i & 0xff000000) >> 24;
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<transfer_YUV888_to_YUV101010>:
  endbr64
  push   %rbx
  movzbl (%rsi),%eax
  movzbl 0x1(%rsi),%ecx
  shl    $0x18,%eax
  shl    $0xe,%ecx
  or     %ecx,%eax
  movzbl 0x2(%rsi),%ecx
  shl    $0x4,%ecx
  or     %ecx,%eax
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %al,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %ah,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %eax,%esi
  shr    $0x18,%eax
  sar    $0x10,%esi
  mov    %sil,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %al,(%rcx)
  pop    %rbx
  ret
```

assistant: ```c
void transfer_YUV888_to_YUV101010(unsigned char *(*output), unsigned char *input) {
  uint16_t y_i = ((uint16_t)input[0]) << 8;
  uint16_t u_i = ((uint16_t)input[1]) << 8;
  uint16_t v_i = ((uint16_t)input[2]) << 8;
  {
    uint32_t output_i = ((y_i & 0xffc0) << 16) | ((u_i & 0xffc0) << 6) | ((v_i & 0xffc0) >> 4);
    *(*output)++ = (output_i & 0xff);
    *(*output)++ = (output_i & 0xff00) >> 8;
    *(*output)++ = (output_i & 0xff0000) >> 16;
    *(*output)++ = (output_i & 0xff000000) >> 24;
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<transfer_YUV888_to_YUV101010>:
  endbr64
  push   %rbx
  movzbl (%rsi),%eax
  movzbl 0x1(%rsi),%ecx
  shl    $0x18,%eax
  shl    $0xe,%ecx
  or     %ecx,%eax
  movzbl 0x2(%rsi),%ecx
  shl    $0x4,%ecx
  or     %ecx,%eax
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %al,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %ah,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %eax,%esi
  shr    $0x18,%eax
  sar    $0x10,%esi
  mov    %sil,(%rcx)
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  mov    %al,(%rcx)
  pop    %rbx
  ret
```

assistant: ```c
void transfer_YUV888_to_YUV101010(unsigned char *(*output), unsigned char *input) {
  uint16_t y_i = ((uint16_t)input[0]) << 8;
  uint16_t u_i = ((uint16_t)input[1]) << 8;
  uint16_t v_i = ((uint16_t)input[2]) << 8;
  {
    uint32_t output_i = ((y_i & 0xffc0) << 16) | ((u_i & 0xffc0) << 6) | ((v_i & 0xffc0) >> 4);
    *(*output)++ = (output_i & 0xff);
    *(*output)++ = (output_i & 0xff00) >> 8;
    *(*output)++ = (output_i & 0xff0000) >> 16;
    *(*output)++ = (output_i & 0xff000000) >> 24;
  };
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int g(struct B *b) {
  struct B {
    int i;
  };
  return b->i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int g(struct B *b) {
  struct B {
    int i;
  };
  return b->i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<g>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int g(struct B *b) {
  struct B {
    int i;
  };
  return b->i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<g>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int g(struct B *b) {
  struct B {
    int i;
  };
  return b->i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<node_counter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L6
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L20
L6:
  cmpl   $0x0,-0x14(%rbp)
  jne    L20
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int node_counter(int pulse100ms, int counter_at_last, int *output) {
  int _tmp000;
  if (pulse100ms == 1) {
    _tmp000 = (counter_at_last + 1);
  } else if (pulse100ms == 0) {
    _tmp000 = counter_at_last;
  }
  *output = (_tmp000 % 10);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<node_counter>:
  endbr64
  cmp    $0x1,%edi
  sete   %al
  movzbl %al,%eax
  add    %eax,%esi
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %esi,(%rdx)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int node_counter(int pulse100ms, int counter_at_last, int *output) {
  int _tmp000;
  if (pulse100ms == 1) {
    _tmp000 = (counter_at_last + 1);
  } else if (pulse100ms == 0) {
    _tmp000 = counter_at_last;
  }
  *output = (_tmp000 % 10);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<node_counter>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  sete   %al
  add    %eax,%esi
  movslq %esi,%rax
  mov    %esi,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    $0x1,%eax
  mov    %esi,(%rdx)
  ret
```

assistant: ```c
int node_counter(int pulse100ms, int counter_at_last, int *output) {
  int _tmp000;
  if (pulse100ms == 1) {
    _tmp000 = (counter_at_last + 1);
  } else if (pulse100ms == 0) {
    _tmp000 = counter_at_last;
  }
  *output = (_tmp000 % 10);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<node_counter>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  sete   %al
  add    %eax,%esi
  movslq %esi,%rax
  mov    %esi,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    $0x1,%eax
  mov    %esi,(%rdx)
  ret
```

assistant: ```c
int node_counter(int pulse100ms, int counter_at_last, int *output) {
  int _tmp000;
  if (pulse100ms == 1) {
    _tmp000 = (counter_at_last + 1);
  } else if (pulse100ms == 0) {
    _tmp000 = counter_at_last;
  }
  *output = (_tmp000 % 10);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<yrc_uiRestore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <clrtoeol@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int yrc_uiRestore(void) {
  clrtoeol();
  refresh();
  endwin();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yrc_uiRestore>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clrtoeol@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yrc_uiRestore(void) {
  clrtoeol();
  refresh();
  endwin();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<yrc_uiRestore>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clrtoeol@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yrc_uiRestore(void) {
  clrtoeol();
  refresh();
  endwin();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<yrc_uiRestore>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clrtoeol@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yrc_uiRestore(void) {
  clrtoeol();
  refresh();
  endwin();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<place_robot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <dp@plt>
  cmp    $0x1,%eax
  jne    L13
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <da@plt>
  cmp    $0x1,%eax
  je     L9
L13:
  mov    $0x0,%eax
  jmp    L21
L9:
  mov    $0x1,%eax
L21:
  leave
  ret
```

assistant: ```c
int place_robot(int x, int y, int th, int tu) {
  if (dp(x, y) != 1 || da(th, tu) != 1)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<place_robot>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  mov    %ecx,%ebp
  call   <dp@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  je     L16
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <da@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L9
```

assistant: ```c
int place_robot(int x, int y, int th, int tu) {
  if (dp(x, y) != 1 || da(th, tu) != 1)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<place_robot>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  sub    $0x8,%rsp
  call   <dp@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  je     L8
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <da@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int place_robot(int x, int y, int th, int tu) {
  if (dp(x, y) != 1 || da(th, tu) != 1)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<place_robot>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  sub    $0x8,%rsp
  call   <dp@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  je     L5
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <da@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int place_robot(int x, int y, int th, int tu) {
  if (dp(x, y) != 1 || da(th, tu) != 1)
    return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x9,-0x4(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D7: loop iteration: %d


assistant: ```c
int main(void) {
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("loop iteration: %d\n", i);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D6(%rip),%rbp
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L9
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: loop iteration: %d


assistant: ```c
int main(void) {
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("loop iteration: %d\n", i);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: loop iteration: %d


assistant: ```c
int main(void) {
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("loop iteration: %d\n", i);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: loop iteration: %d


assistant: ```c
int main(void) {
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("loop iteration: %d\n", i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotateX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm5
  movsd  %xmm5,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm6
  movsd  %xmm6,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mulsd  -0x28(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  movq   D6(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm4
  mulsd  -0x20(%rbp),%xmm4
  movsd  %xmm4,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm7
  movsd  %xmm7,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x28(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void rotateX(const double v1[3], const double alpha, double result[3]) {
  result[0] = v1[0];
  result[1] = v1[1] * cos(alpha) + v1[2] * sin(alpha);
  result[2] = -v1[1] * sin(alpha) + v1[2] * cos(alpha);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rotateX>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  (%rbx),%xmm2
  movsd  %xmm2,0x0(%rbp)
  movapd %xmm0,%xmm2
  mulsd  0x8(%rbx),%xmm2
  movapd %xmm1,%xmm3
  mulsd  0x10(%rbx),%xmm3
  addsd  %xmm3,%xmm2
  movsd  %xmm2,0x8(%rbp)
  mulsd  0x8(%rbx),%xmm1
  mulsd  0x10(%rbx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotateX(const double v1[3], const double alpha, double result[3]) {
  result[0] = v1[0];
  result[1] = v1[1] * cos(alpha) + v1[2] * sin(alpha);
  result[2] = -v1[1] * sin(alpha) + v1[2] * cos(alpha);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rotateX>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  (%rbx),%xmm2
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm2,0x0(%rbp)
  movsd  0x8(%rbx),%xmm2
  movsd  0x10(%rbx),%xmm3
  mulsd  %xmm0,%xmm2
  mulsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm2
  movsd  %xmm2,0x8(%rbp)
  mulsd  0x8(%rbx),%xmm1
  mulsd  0x10(%rbx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotateX(const double v1[3], const double alpha, double result[3]) {
  result[0] = v1[0];
  result[1] = v1[1] * cos(alpha) + v1[2] * sin(alpha);
  result[2] = -v1[1] * sin(alpha) + v1[2] * cos(alpha);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotateX>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  (%rbx),%xmm2
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm2,0x0(%rbp)
  movsd  0x8(%rbx),%xmm2
  movsd  0x10(%rbx),%xmm3
  mulsd  %xmm0,%xmm2
  mulsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm2
  movsd  %xmm2,0x8(%rbp)
  mulsd  0x8(%rbx),%xmm1
  mulsd  0x10(%rbx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotateX(const double v1[3], const double alpha, double result[3]) {
  result[0] = v1[0];
  result[1] = v1[1] * cos(alpha) + v1[2] * sin(alpha);
  result[2] = -v1[1] * sin(alpha) + v1[2] * cos(alpha);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lcd_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0x3fffc074,%edx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  mov    $0x3fffc058,%eax
  movq   $0x4,(%rax)
  mov    $0x3fffc058,%eax
  movq   $0x8,(%rax)
  mov    $0x3fffc05c,%eax
  movq   $0x8,(%rax)
  mov    $0x8,%edi
  call   <ms_sleep@plt>
  nop
  leave
  ret
```

assistant: ```c
void lcd_char(char c) {
  (*(volatile unsigned char *)(0x3FFFC000 + 0x74)) = c;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x58)) = 4;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x58)) = 8;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x5C)) = 8;
  ms_sleep(8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lcd_char>:
  endbr64
  sub    $0x8,%rsp
  mov    %dil,0x3fffc074
  movq   $0x4,0x3fffc058
  movq   $0x8,0x3fffc058
  movq   $0x8,0x3fffc05c
  mov    $0x8,%edi
  call   <ms_sleep@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void lcd_char(char c) {
  (*(volatile unsigned char *)(0x3FFFC000 + 0x74)) = c;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x58)) = 4;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x58)) = 8;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x5C)) = 8;
  ms_sleep(8);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lcd_char>:
  endbr64
  mov    %dil,0x3fffc074
  mov    $0x8,%edi
  movq   $0x4,0x3fffc058
  movq   $0x8,0x3fffc058
  movq   $0x8,0x3fffc05c
  jmp    1050 <ms_sleep@plt>
```

assistant: ```c
void lcd_char(char c) {
  (*(volatile unsigned char *)(0x3FFFC000 + 0x74)) = c;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x58)) = 4;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x58)) = 8;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x5C)) = 8;
  ms_sleep(8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcd_char>:
  endbr64
  mov    %dil,0x3fffc074
  mov    $0x8,%edi
  movq   $0x4,0x3fffc058
  movq   $0x8,0x3fffc058
  movq   $0x8,0x3fffc05c
  jmp    1050 <ms_sleep@plt>
```

assistant: ```c
void lcd_char(char c) {
  (*(volatile unsigned char *)(0x3FFFC000 + 0x74)) = c;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x58)) = 4;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x58)) = 8;
  (*(volatile unsigned long *)(0x3FFFC000 + 0x5C)) = 8;
  ms_sleep(8);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_disk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cl,-0x14(%rbp)
  mov    %esi,%ecx
  mov    %cl,-0x18(%rbp)
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x18(%rbp),%eax
  add    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  add    %al,-0x1(%rbp)
  movzbl -0x20(%rbp),%eax
  add    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char read_disk(unsigned char drive_head, unsigned char sector, unsigned char cylinder1, unsigned char cylinder2) {
  unsigned char tmp = drive_head;
  tmp += sector;
  tmp += cylinder1;
  tmp += cylinder2;
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_disk>:
  endbr64
  add    %edx,%ecx
  add    %esi,%ecx
  lea    (%rcx,%rdi,1),%eax
  ret
```

assistant: ```c
unsigned char read_disk(unsigned char drive_head, unsigned char sector, unsigned char cylinder1, unsigned char cylinder2) {
  unsigned char tmp = drive_head;
  tmp += sector;
  tmp += cylinder1;
  tmp += cylinder2;
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_disk>:
  endbr64
  add    %edx,%ecx
  add    %esi,%ecx
  lea    (%rcx,%rdi,1),%eax
  ret
```

assistant: ```c
unsigned char read_disk(unsigned char drive_head, unsigned char sector, unsigned char cylinder1, unsigned char cylinder2) {
  unsigned char tmp = drive_head;
  tmp += sector;
  tmp += cylinder1;
  tmp += cylinder2;
  return tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_disk>:
  endbr64
  add    %edx,%ecx
  add    %esi,%ecx
  lea    (%rcx,%rdi,1),%eax
  ret
```

assistant: ```c
unsigned char read_disk(unsigned char drive_head, unsigned char sector, unsigned char cylinder1, unsigned char cylinder2) {
  unsigned char tmp = drive_head;
  tmp += sector;
  tmp += cylinder1;
  tmp += cylinder2;
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<s2cM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    -0x4(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void s2cM(const uint16_t s, uint8_t *c) {
  memcpy(c, &s, sizeof(uint16_t));
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s2cM>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void s2cM(const uint16_t s, uint8_t *c) {
  memcpy(c, &s, sizeof(uint16_t));
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s2cM>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdi
  lea    0xc(%rsp),%rsi
  call   <memcpy@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void s2cM(const uint16_t s, uint8_t *c) {
  memcpy(c, &s, sizeof(uint16_t));
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s2cM>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdi
  lea    0xc(%rsp),%rsi
  call   <memcpy@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void s2cM(const uint16_t s, uint8_t *c) {
  memcpy(c, &s, sizeof(uint16_t));
  return;
}
```