ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  je     L3
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L3:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <omp_set_dynamic@plt>
  mov    %r12d,%edi
  call   <omp_set_num_threads@plt>
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <fib@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D38
type_infered: string
name: read_data
arguments: data_label: D29
type_infered: string
name: read_data
arguments: data_label: D27
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string

tool: D38: 		 Very Few Arguments
 

tool: D29: 		 Syntax : exec <Number> <No. of Threads>

tool: D27: 
 Total Threads %d 

tool: D0: 
 Fibnacci Number fib(%d) = %d



assistant: ```c
int main(int argc, char **argv) {
  int number, numThreads;
  if (argc != 3) {
    printf("\t\t Very Few Arguments\n ");
    printf("\t\t Syntax : exec <Number> <No. of Threads>\n");
    exit(-1);
  }
  number = atoi(argv[1]);
  numThreads = atoi(argv[2]);
  omp_set_dynamic(0);
  omp_set_num_threads(numThreads);
#pragma omp parallel shared(number)
  {
#pragma omp single
    {
      printf("\n Total Threads %d ", omp_get_num_threads());
      printf("\n Fibnacci Number fib(%d) = %d\n\n", number, fib(number));
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  je     L5
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L5:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <omp_set_dynamic@plt>
  mov    %r12d,%edi
  call   <omp_set_num_threads@plt>
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <fib@plt>
  mov    %ebp,%esi
  lea    D38(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D24
type: string
name: retrieve_data
arguments: label: D19
type: string
name: retrieve_data
arguments: label: D14
type: string
name: retrieve_data
arguments: label: D38
type: string

tool: D24: 		 Very Few Arguments
 

tool: D19: 		 Syntax : exec <Number> <No. of Threads>

tool: D14: 
 Total Threads %d 

tool: D38: 
 Fibnacci Number fib(%d) = %d



assistant: ```c
int main(int argc, char **argv) {
  int number, numThreads;
  if (argc != 3) {
    printf("\t\t Very Few Arguments\n ");
    printf("\t\t Syntax : exec <Number> <No. of Threads>\n");
    exit(-1);
  }
  number = atoi(argv[1]);
  numThreads = atoi(argv[2]);
  omp_set_dynamic(0);
  omp_set_num_threads(numThreads);
#pragma omp parallel shared(number)
  {
#pragma omp single
    {
      printf("\n Total Threads %d ", omp_get_num_threads());
      printf("\n Fibnacci Number fib(%d) = %d\n\n", number, fib(number));
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ConnexClose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <shutdown@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void ConnexClose(int msgin_sock) {
  shutdown(msgin_sock, 2);
  close(msgin_sock);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ConnexClose>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%esi
  call   <shutdown@plt>
  mov    %ebx,%edi
  call   <close@plt>
  pop    %rbx
  ret
```

assistant: ```c
void ConnexClose(int msgin_sock) {
  shutdown(msgin_sock, 2);
  close(msgin_sock);
}
```
user: What is the c source code of the assembly code below:

```asm
<ConnexClose>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  mov    %edi,%ebp
  call   <shutdown@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <close@plt>
```

assistant: ```c
void ConnexClose(int msgin_sock) {
  shutdown(msgin_sock, 2);
  close(msgin_sock);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ConnexClose>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  mov    %edi,%ebp
  call   <shutdown@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <close@plt>
```

assistant: ```c
void ConnexClose(int msgin_sock) {
  shutdown(msgin_sock, 2);
  close(msgin_sock);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rtc_get_alarm_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0xd0,%edi
  call   <hal_iic_start@plt>
  mov    $0xb,%edi
  call   <hal_iic_write@plt>
  mov    $0xd1,%edi
  call   <hal_iic_rep_start@plt>
  mov    $0x0,%eax
  call   <hal_iic_read_nak@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <hal_iic_stop@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint8_t rtc_get_alarm_state(void) {
  uint8_t ret = 0;
  hal_iic_start(0xd0U + 0x00U);
  hal_iic_write(0x0bU);
  hal_iic_rep_start(0xd0U + 0x01U);
  ret = hal_iic_read_nak();
  hal_iic_stop();
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rtc_get_alarm_state>:
  endbr64
  push   %rbx
  mov    $0xd0,%edi
  call   <hal_iic_start@plt>
  mov    $0xb,%edi
  call   <hal_iic_write@plt>
  mov    $0xd1,%edi
  call   <hal_iic_rep_start@plt>
  mov    $0x0,%eax
  call   <hal_iic_read_nak@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <hal_iic_stop@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint8_t rtc_get_alarm_state(void) {
  uint8_t ret = 0;
  hal_iic_start(0xd0U + 0x00U);
  hal_iic_write(0x0bU);
  hal_iic_rep_start(0xd0U + 0x01U);
  ret = hal_iic_read_nak();
  hal_iic_stop();
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rtc_get_alarm_state>:
  endbr64
  push   %r12
  mov    $0xd0,%edi
  call   <hal_iic_start@plt>
  mov    $0xb,%edi
  call   <hal_iic_write@plt>
  mov    $0xd1,%edi
  call   <hal_iic_rep_start@plt>
  xor    %eax,%eax
  call   <hal_iic_read_nak@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <hal_iic_stop@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
uint8_t rtc_get_alarm_state(void) {
  uint8_t ret = 0;
  hal_iic_start(0xd0U + 0x00U);
  hal_iic_write(0x0bU);
  hal_iic_rep_start(0xd0U + 0x01U);
  ret = hal_iic_read_nak();
  hal_iic_stop();
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtc_get_alarm_state>:
  endbr64
  push   %r12
  mov    $0xd0,%edi
  call   <hal_iic_start@plt>
  mov    $0xb,%edi
  call   <hal_iic_write@plt>
  mov    $0xd1,%edi
  call   <hal_iic_rep_start@plt>
  xor    %eax,%eax
  call   <hal_iic_read_nak@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <hal_iic_stop@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
uint8_t rtc_get_alarm_state(void) {
  uint8_t ret = 0;
  hal_iic_start(0xd0U + 0x00U);
  hal_iic_write(0x0bU);
  hal_iic_rep_start(0xd0U + 0x01U);
  ret = hal_iic_read_nak();
  hal_iic_stop();
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BIO_dgram_non_fatal_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int BIO_dgram_non_fatal_error(int err) {
  switch (err) {
    return (1);
  default:
    break;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BIO_dgram_non_fatal_error>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int BIO_dgram_non_fatal_error(int err) {
  switch (err) {
    return (1);
  default:
    break;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BIO_dgram_non_fatal_error>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int BIO_dgram_non_fatal_error(int err) {
  switch (err) {
    return (1);
  default:
    break;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BIO_dgram_non_fatal_error>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int BIO_dgram_non_fatal_error(int err) {
  switch (err) {
    return (1);
  default:
    break;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L0
  cmpl   $0x2,-0x8(%rbp)
  jne    L0
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L13
L0:
  mov    $0x0,%eax
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: %d %d

assistant: ```c
int check(int zero, int count, int x, int y) {
  if (zero == 1 && count == 2) {
    printf("%d %d", x, y);
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check>:
  endbr64
  cmp    $0x1,%edi
  jne    L4
  mov    %edx,%eax
  cmp    $0x2,%esi
  je     L3
L4:
  mov    $0x0,%eax
  ret
L3:
  sub    $0x8,%rsp
  mov    %ecx,%edx
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d %d

assistant: ```c
int check(int zero, int count, int x, int y) {
  if (zero == 1 && count == 2) {
    printf("%d %d", x, y);
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check>:
  endbr64
  cmp    $0x1,%edi
  jne    L17
  cmp    $0x2,%esi
  je     L0
L17:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L0:
  mov    %edx,%r8d
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  mov    %ecx,%edx
  mov    %r8d,%esi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: %d %d

assistant: ```c
int check(int zero, int count, int x, int y) {
  if (zero == 1 && count == 2) {
    printf("%d %d", x, y);
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check>:
  endbr64
  cmp    $0x1,%edi
  jne    L2
  cmp    $0x2,%esi
  je     L15
L2:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L15:
  mov    %edx,%r8d
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  mov    %ecx,%edx
  mov    %r8d,%esi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: %d %d

assistant: ```c
int check(int zero, int count, int x, int y) {
  if (zero == 1 && count == 2) {
    printf("%d %d", x, y);
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L58
L19:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L23
  nop
  addl   $0x1,-0x4(%rbp)
L58:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  jmp    L49
L23:
  nop
L49:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L7
  mov    $0x1,%eax
  jmp    L0
L7:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i != 0)
      continue;
    else
      break;
  }
  if (num == i)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L46
  mov    $0x2,%ecx
  test   $0x1,%dil
  jne    L30
L39:
  cmp    %ecx,%edi
  sete   %al
  movzbl %al,%eax
  ret
L30:
  mov    $0x2,%ecx
L15:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L51
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L39
  jmp    L15
L51:
  mov    %edi,%ecx
  jmp    L39
L46:
  mov    $0x2,%ecx
  jmp    L39
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i != 0)
      continue;
    else
      break;
  }
  if (num == i)
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L13
  xor    %r8d,%r8d
  test   $0x1,%dil
  jne    L20
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    $0x2,%ecx
L4:
  add    $0x1,%ecx
  mov    %edi,%eax
  cmp    %ecx,%edi
  je     L29
  cltd
  idiv   %ecx
  mov    %edx,%r8d
  test   %edx,%edx
  jne    L4
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L13:
  mov    $0x2,%eax
L29:
  xor    %r8d,%r8d
  cmp    %eax,%edi
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i != 0)
      continue;
    else
      break;
  }
  if (num == i)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L24
  xor    %r8d,%r8d
  test   $0x1,%dil
  jne    L6
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    $0x2,%ecx
L11:
  add    $0x1,%ecx
  mov    %edi,%eax
  cmp    %ecx,%edi
  je     L23
  cltd
  idiv   %ecx
  mov    %edx,%r8d
  test   %edx,%edx
  jne    L11
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L24:
  mov    $0x2,%eax
L23:
  xor    %r8d,%r8d
  cmp    %eax,%edi
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i != 0)
      continue;
    else
      break;
  }
  if (num == i)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uart_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3f9,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3fa,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x83,%edi
  call   <outb@plt>
  mov    $0x3f8,%esi
  mov    $0xc,%edi
  call   <outb@plt>
  mov    $0x3f9,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x3,%edi
  call   <outb@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uart_init(void) {
  outb(0x0, 0x3f8 + 0x01);
  outb(0x01, 0x3f8 + 0x02);
  outb(0x80 | 0x3, 0x3f8 + 0x03);
  outb((115200 / 9600) & 0xFF, 0x3f8 + 0x00);
  outb(((115200 / 9600) >> 8) & 0xFF, 0x3f8 + 0x01);
  outb(0x3, 0x3f8 + 0x03);
}
```
user: What is the c source code of the assembly code below:

```asm
<uart_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3f9,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3fa,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x83,%edi
  call   <outb@plt>
  mov    $0x3f8,%esi
  mov    $0xc,%edi
  call   <outb@plt>
  mov    $0x3f9,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x3,%edi
  call   <outb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uart_init(void) {
  outb(0x0, 0x3f8 + 0x01);
  outb(0x01, 0x3f8 + 0x02);
  outb(0x80 | 0x3, 0x3f8 + 0x03);
  outb((115200 / 9600) & 0xFF, 0x3f8 + 0x00);
  outb(((115200 / 9600) >> 8) & 0xFF, 0x3f8 + 0x01);
  outb(0x3, 0x3f8 + 0x03);
}
```
user: What is the c source code of the assembly code below?

```asm
<uart_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3f9,%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    $0x3fa,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x83,%edi
  call   <outb@plt>
  mov    $0x3f8,%esi
  mov    $0xc,%edi
  call   <outb@plt>
  mov    $0x3f9,%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1050 <outb@plt>
```

assistant: ```c
void uart_init(void) {
  outb(0x0, 0x3f8 + 0x01);
  outb(0x01, 0x3f8 + 0x02);
  outb(0x80 | 0x3, 0x3f8 + 0x03);
  outb((115200 / 9600) & 0xFF, 0x3f8 + 0x00);
  outb(((115200 / 9600) >> 8) & 0xFF, 0x3f8 + 0x01);
  outb(0x3, 0x3f8 + 0x03);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3f9,%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    $0x3fa,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x83,%edi
  call   <outb@plt>
  mov    $0x3f8,%esi
  mov    $0xc,%edi
  call   <outb@plt>
  mov    $0x3f9,%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    $0x3fb,%esi
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1050 <outb@plt>
```

assistant: ```c
void uart_init(void) {
  outb(0x0, 0x3f8 + 0x01);
  outb(0x01, 0x3f8 + 0x02);
  outb(0x80 | 0x3, 0x3f8 + 0x03);
  outb((115200 / 9600) & 0xFF, 0x3f8 + 0x00);
  outb(((115200 / 9600) >> 8) & 0xFF, 0x3f8 + 0x01);
  outb(0x3, 0x3f8 + 0x03);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int32hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x7ed55d16(%rax),%edx
  mov    -0x4(%rbp),%eax
  shl    $0xc,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x13,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  xor    %edx,%eax
  xor    $0xc761c23c,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x165667b1(%rax),%edx
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x2c5d9b94(%rax),%edx
  mov    -0x4(%rbp),%eax
  shl    $0x9,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x28fb93b,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  xor    %edx,%eax
  xor    $0xb55a4f09,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
u_int32_t int32hash(u_int32_t a) {
  a = (a + 0x7ed55d16) + (a << 12);
  a = (a ^ 0xc761c23c) ^ (a >> 19);
  a = (a + 0x165667b1) + (a << 5);
  a = (a + 0xd3a2646c) ^ (a << 9);
  a = (a + 0xfd7046c5) + (a << 3);
  a = (a ^ 0xb55a4f09) ^ (a >> 16);
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int32hash>:
  endbr64
  mov    %edi,%eax
  shl    $0xc,%eax
  lea    0x7ed55d16(%rax,%rdi,1),%edx
  mov    %edx,%eax
  sar    $0x13,%eax
  xor    %edx,%eax
  xor    $0xc761c23c,%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  lea    0x165667b1(%rax,%rdx,1),%edx
  lea    -0x2c5d9b94(%rdx),%eax
  shl    $0x9,%edx
  xor    %edx,%eax
  lea    -0x28fb93b(%rax,%rax,8),%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  xor    $0xb55a4f09,%eax
  ret
```

assistant: ```c
u_int32_t int32hash(u_int32_t a) {
  a = (a + 0x7ed55d16) + (a << 12);
  a = (a ^ 0xc761c23c) ^ (a >> 19);
  a = (a + 0x165667b1) + (a << 5);
  a = (a + 0xd3a2646c) ^ (a << 9);
  a = (a + 0xfd7046c5) + (a << 3);
  a = (a ^ 0xb55a4f09) ^ (a >> 16);
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int32hash>:
  endbr64
  mov    %edi,%eax
  shl    $0xc,%eax
  lea    0x7ed55d16(%rax,%rdi,1),%edx
  mov    %edx,%eax
  sar    $0x13,%eax
  xor    %edx,%eax
  xor    $0xc761c23c,%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  lea    0x165667b1(%rax,%rdx,1),%edx
  lea    -0x2c5d9b94(%rdx),%eax
  shl    $0x9,%edx
  xor    %edx,%eax
  lea    -0x28fb93b(%rax,%rax,8),%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  xor    $0xb55a4f09,%eax
  ret
```

assistant: ```c
u_int32_t int32hash(u_int32_t a) {
  a = (a + 0x7ed55d16) + (a << 12);
  a = (a ^ 0xc761c23c) ^ (a >> 19);
  a = (a + 0x165667b1) + (a << 5);
  a = (a + 0xd3a2646c) ^ (a << 9);
  a = (a + 0xfd7046c5) + (a << 3);
  a = (a ^ 0xb55a4f09) ^ (a >> 16);
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int32hash>:
  endbr64
  mov    %edi,%eax
  shl    $0xc,%eax
  lea    0x7ed55d16(%rax,%rdi,1),%edx
  mov    %edx,%eax
  sar    $0x13,%eax
  xor    %edx,%eax
  xor    $0xc761c23c,%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  lea    0x165667b1(%rax,%rdx,1),%edx
  lea    -0x2c5d9b94(%rdx),%eax
  shl    $0x9,%edx
  xor    %edx,%eax
  lea    -0x28fb93b(%rax,%rax,8),%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  xor    $0xb55a4f09,%eax
  ret
```

assistant: ```c
u_int32_t int32hash(u_int32_t a) {
  a = (a + 0x7ed55d16) + (a << 12);
  a = (a ^ 0xc761c23c) ^ (a >> 19);
  a = (a + 0x165667b1) + (a << 5);
  a = (a + 0xd3a2646c) ^ (a << 9);
  a = (a + 0xfd7046c5) + (a << 3);
  a = (a ^ 0xb55a4f09) ^ (a >> 16);
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lire_reel_binaire_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swap_octets@plt>
  movss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
float lire_reel_binaire_swap(FILE *fichier) {
  float reel, reel2;
  fread(&reel, 4, 1, fichier);
  swap_octets(&reel, &reel2, 4);
  return (reel2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lire_reel_binaire_swap>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rbx,%rdi
  call   <swap_octets@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float lire_reel_binaire_swap(FILE *fichier) {
  float reel, reel2;
  fread(&reel, 4, 1, fichier);
  swap_octets(&reel, &reel2, 4);
  return (reel2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lire_reel_binaire_swap>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fread@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <swap_octets@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float lire_reel_binaire_swap(FILE *fichier) {
  float reel, reel2;
  fread(&reel, 4, 1, fichier);
  swap_octets(&reel, &reel2, 4);
  return (reel2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lire_reel_binaire_swap>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fread@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <swap_octets@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float lire_reel_binaire_swap(FILE *fichier) {
  float reel, reel2;
  fread(&reel, 4, 1, fichier);
  swap_octets(&reel, &reel2, 4);
  return (reel2);
}
```