user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  jmp    L96
  nopl   0x0(%rax)
L145:
  add    $0x1,%ebp
L96:
  movsbl (%rbx),%edi
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L145
  movzbl 0x0(%r13),%eax
  cmp    $0x2d,%al
  je     L106
  mov    $0x1,%r14d
  cmp    $0x2b,%al
  je     L46
L176:
  movslq %ebp,%r13
  pxor   %xmm6,%xmm6
  add    %r12,%r13
  movsd  %xmm6,0x8(%rsp)
  mov    %r13,%r15
  jmp    L147
  nopw   0x0(%rax,%rax,1)
L188:
  movsbl (%r15),%eax
  movsd  D52(%rip),%xmm0
  pxor   %xmm1,%xmm1
  add    $0x1,%r15
  mulsd  0x8(%rsp),%xmm0
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
L147:
  mov    %ebp,%ebx
  movsbl (%r15),%edi
  sub    %r13d,%ebx
  add    %r15d,%ebx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L188
  xor    %eax,%eax
  cmpb   $0x2e,(%r15)
  sete   %al
  add    %eax,%ebx
  mov    D30(%rip),%rax
  movslq %ebx,%r13
  add    %r12,%r13
  mov    %rax,0x10(%rsp)
  mov    %r13,%r15
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L184:
  movsbl (%r15),%eax
  pxor   %xmm1,%xmm1
  add    $0x1,%r15
  movsd  D52(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  D52(%rip),%xmm2
  mulsd  0x10(%rsp),%xmm2
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
L10:
  mov    %ebx,%ebp
  movsbl (%r15),%edi
  sub    %r13d,%ebp
  add    %r15d,%ebp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L184
  movzbl (%r15),%eax
  mov    D30(%rip),%rsi
  and    $0xffffffdf,%eax
  movq   %rsi,%xmm1
  cmp    $0x45,%al
  jne    L77
  lea    0x1(%rbp),%eax
  cltq
  movzbl (%r12,%rax,1),%edx
  cmp    $0x2d,%dl
  je     L52
  movl   $0x1,0x1c(%rsp)
  cmp    $0x2b,%dl
  je     L121
L187:
  add    %rax,%r12
  xor    %ebx,%ebx
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%r12),%eax
  lea    (%rbx,%rbx,4),%edx
  add    $0x1,%r12
  lea    -0x30(%rax,%rdx,2),%ebx
L73:
  movsbl (%r12),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L6
  test   %ebx,%ebx
  jle    L166
  mov    %ebx,%ecx
  cmp    $0x1,%ebx
  je     L24
  movq   D54(%rip),%xmm0
  mov    %ebx,%edx
  shr    %edx
  nopw   0x0(%rax,%rax,1)
L137:
  movdqa %xmm0,%xmm1
  add    $0x1,%eax
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %edx,%eax
  jne    L137
  movd   %xmm0,%eax
  pshufd $0xe5,%xmm0,%xmm7
  movd   %xmm7,%ebx
  imul   %eax,%ebx
  and    $0x1,%ecx
  je     L71
L24:
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
L71:
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
L77:
  pxor   %xmm0,%xmm0
  cmpl   $0x1,0x1c(%rsp)
  cvtsi2sd %r14d,%xmm0
  mulsd  0x8(%rsp),%xmm0
  je     L90
  mulsd  0x10(%rsp),%xmm1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L106:
  mov    $0xffffffff,%r14d
L46:
  add    $0x1,%ebp
  jmp    L176
  cs nopw 0x0(%rax,%rax,1)
L90:
  mulsd  %xmm1,%xmm0
  divsd  0x10(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L52:
  movl   $0xffffffff,0x1c(%rsp)
L121:
  lea    0x2(%rbp),%eax
  cltq
  jmp    L187
L166:
  mov    D30(%rip),%rax
  movq   %rax,%xmm1
  jmp    L77
```

tool_calls: name: parse_data
arguments: data_tag: D52
data_type: f32[2]
name: parse_data
arguments: data_tag: D30
data_type: f64
name: parse_data
arguments: data_tag: D54
data_type: byte[8]

tool: {"D52": [0.0,2.5625]}

tool: D30: 1

tool: {"D54": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
double atof(char s[]) {
  double val, power;
  int i, sign, exp_sign, exp, exp_val;
  exp_val = 1;
  for (i = 0; isspace(s[i]); i++)
    ;
  sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  for (val = 0.0; isdigit(s[i]); i++)
    val = val * 10 + (s[i] - '0');
  if (s[i] == '.')
    i++;
  for (power = 1.0; isdigit(s[i]); i++) {
    val = val * 10 + (s[i] - '0');
    power *= 10;
  }
  if (s[i] == 'e' || s[i] == 'E') {
    i++;
    exp_sign = (s[i] == '-') ? -1 : 1;
    if (s[i] == '+' || s[i] == '-')
      i++;
    for (exp = 0; isdigit(s[i]); i++)
      exp = exp * 10 + (s[i] - '0');
    while (exp > 0) {
      exp_val *= 10;
      exp--;
    }
  }
  if (exp_sign == 1)
    return ((sign * val * exp_val) / power);
  else
    return ((sign * val) / (exp_val * power));
}
```