ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: date

assistant: ```c
int main() {
  system("date");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: date

assistant: ```c
int main() {
  system("date");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PrintDribble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <PutcDribbleBuffer@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <EnvDeactivateRouter@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EnvPrintRouter@plt>
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <EnvActivateRouter@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: dribble

assistant: ```c
int PrintDribble(void *theEnv, const char *logicalName, const char *str) {
  int i;
  for (i = 0; str[i] != '\0'; i++) {
    PutcDribbleBuffer(theEnv, str[i]);
  }
  EnvDeactivateRouter(theEnv, "dribble");
  EnvPrintRouter(theEnv, logicalName, str);
  EnvActivateRouter(theEnv, "dribble");
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PrintDribble>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  movzbl (%rdx),%esi
  test   %sil,%sil
  je     L15
  lea    0x1(%rdx),%rbx
L8:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <PutcDribbleBuffer@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L8
L15:
  lea    D1(%rip),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <EnvDeactivateRouter@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <EnvPrintRouter@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <EnvActivateRouter@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: dribble

assistant: ```c
int PrintDribble(void *theEnv, const char *logicalName, const char *str) {
  int i;
  for (i = 0; str[i] != '\0'; i++) {
    PutcDribbleBuffer(theEnv, str[i]);
  }
  EnvDeactivateRouter(theEnv, "dribble");
  EnvPrintRouter(theEnv, logicalName, str);
  EnvActivateRouter(theEnv, "dribble");
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PrintDribble>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdx),%esi
  test   %sil,%sil
  je     L2
  lea    0x1(%rdx),%rbx
  nopl   0x0(%rax)
L18:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <PutcDribbleBuffer@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L18
L2:
  lea    D7(%rip),%r14
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <EnvDeactivateRouter@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <EnvPrintRouter@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <EnvActivateRouter@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: dribble

assistant: ```c
int PrintDribble(void *theEnv, const char *logicalName, const char *str) {
  int i;
  for (i = 0; str[i] != '\0'; i++) {
    PutcDribbleBuffer(theEnv, str[i]);
  }
  EnvDeactivateRouter(theEnv, "dribble");
  EnvPrintRouter(theEnv, logicalName, str);
  EnvActivateRouter(theEnv, "dribble");
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PrintDribble>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdx),%esi
  test   %sil,%sil
  je     L7
  lea    0x1(%rdx),%rbx
  nopl   0x0(%rax)
L13:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <PutcDribbleBuffer@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L13
L7:
  lea    D8(%rip),%r14
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <EnvDeactivateRouter@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <EnvPrintRouter@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <EnvActivateRouter@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: dribble

assistant: ```c
int PrintDribble(void *theEnv, const char *logicalName, const char *str) {
  int i;
  for (i = 0; str[i] != '\0'; i++) {
    PutcDribbleBuffer(theEnv, str[i]);
  }
  EnvDeactivateRouter(theEnv, "dribble");
  EnvPrintRouter(theEnv, logicalName, str);
  EnvActivateRouter(theEnv, "dribble");
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_builtin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L27
  mov    $0x1,%eax
  jmp    L31
L27:
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L15
  mov    $0x1,%eax
  jmp    L31
L15:
  mov    $0x0,%eax
L31:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
data_type: string
name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D16: cd

tool: D6: myuid

assistant: ```c
int is_builtin(char *cmd) {
  if (strcmp(cmd, "cd") == 0) {
    return 1;
  } else if (strcmp(cmd, "myuid") == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_builtin>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L4
L3:
  pop    %rbx
  ret
L4:
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L3
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D6: cd

tool: D7: myuid

assistant: ```c
int is_builtin(char *cmd) {
  if (strcmp(cmd, "cd") == 0) {
    return 1;
  } else if (strcmp(cmd, "myuid") == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_builtin>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L0
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  lea    D19(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string

tool: D9: cd

tool: D19: myuid

assistant: ```c
int is_builtin(char *cmd) {
  if (strcmp(cmd, "cd") == 0) {
    return 1;
  } else if (strcmp(cmd, "myuid") == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_builtin>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L5
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  lea    D19(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string

tool: D5: cd

tool: D19: myuid

assistant: ```c
int is_builtin(char *cmd) {
  if (strcmp(cmd, "cd") == 0) {
    return 1;
  } else if (strcmp(cmd, "myuid") == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ignore_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <index@plt>
  test   %rax,%rax
  je     L7
  mov    $0x1,%eax
  jmp    L24
L7:
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x0,%eax
L24:
  leave
  ret
```

assistant: ```c
int ignore_line(FILE *fp, char *buf, int bufsiz) {
  do {
    if (index(buf, '\n'))
      return 1;
  } while (fgets(buf, bufsiz, fp) != NULL);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ignore_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
L25:
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <index@plt>
  test   %rax,%rax
  jne    L12
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L25
  jmp    L27
L12:
  mov    $0x1,%eax
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ignore_line(FILE *fp, char *buf, int bufsiz) {
  do {
    if (index(buf, '\n'))
      return 1;
  } while (fgets(buf, bufsiz, fp) != NULL);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ignore_line>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L4
L19:
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <index@plt>
  test   %rax,%rax
  je     L0
  mov    $0x1,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ignore_line(FILE *fp, char *buf, int bufsiz) {
  do {
    if (index(buf, '\n'))
      return 1;
  } while (fgets(buf, bufsiz, fp) != NULL);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ignore_line>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L4
L16:
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <index@plt>
  test   %rax,%rax
  je     L6
  mov    $0x1,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ignore_line(FILE *fp, char *buf, int bufsiz) {
  do {
    if (index(buf, '\n'))
      return 1;
  } while (fgets(buf, bufsiz, fp) != NULL);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<blend_image_inplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  jmp    L42
L1:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  and    $0xff,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x10(%rbp),%eax
  lea    0xff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x10(%rbp),%eax
  lea    0xff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x10(%rbp),%eax
  lea    0xff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0xff,-0x28(%rbp)
  jle    L27
  movl   $0xff,-0x28(%rbp)
L27:
  cmpl   $0xff,-0x24(%rbp)
  jle    L44
  movl   $0xff,-0x24(%rbp)
L44:
  cmpl   $0xff,-0x20(%rbp)
  jle    L8
  movl   $0xff,-0x20(%rbp)
L8:
  mov    -0x24(%rbp),%eax
  shl    $0x8,%eax
  or     -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x40(%rbp)
  addq   $0x4,-0x38(%rbp)
  subl   $0x1,-0x44(%rbp)
L42:
  cmpl   $0x0,-0x44(%rbp)
  jne    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void blend_image_inplace(uint32_t *background, uint32_t *foreground, int count) {
  uint32_t Rf, Gf, Bf, Af;
  uint32_t Rb, Gb, Bb;
  uint32_t R, G, B;
  while (count) {
    Rf = (*foreground) & 0xff;
    Gf = ((*foreground) >> 8) & 0xff;
    Bf = ((*foreground) >> 16) & 0xff;
    Af = ((*foreground) >> 24) & 0xff;
    Rb = (*background) & 0xff;
    Gb = ((*background) >> 8) & 0xff;
    Bb = ((*background) >> 16) & 0xff;
    R = (Rf * Af) / 256 + Rb;
    G = (Gf * Af) / 256 + Gb;
    B = (Bf * Af) / 256 + Bb;
    if (R > 255)
      R = 255;
    if (G > 255)
      G = 255;
    if (B > 255)
      B = 255;
    (*background) = R | (G << 8) | (B << 16);
    foreground += 1;
    background += 1;
    count -= 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<blend_image_inplace>:
  endbr64
  test   %edx,%edx
  je     L17
  push   %rbp
  push   %rbx
  mov    %edx,%r8d
  mov    $0x0,%ecx
L5:
  mov    (%rsi,%rcx,4),%eax
  mov    %eax,%r9d
  shr    $0x18,%r9d
  mov    (%rdi,%rcx,4),%ebx
  movzbl %ah,%edx
  imul   %r9d,%edx
  sar    $0x8,%edx
  movzbl %bh,%ebp
  add    %ebp,%edx
  mov    $0xff,%r10d
  cmp    %r10d,%edx
  cmovg  %r10d,%edx
  shl    $0x8,%edx
  mov    %edx,%r10d
  mov    %eax,%edx
  sar    $0x10,%edx
  movzbl %dl,%edx
  imul   %r9d,%edx
  sar    $0x8,%edx
  mov    %ebx,%r11d
  sar    $0x10,%r11d
  movzbl %r11b,%r11d
  add    %r11d,%edx
  mov    $0xff,%r11d
  cmp    %r11d,%edx
  cmovg  %r11d,%edx
  shl    $0x10,%edx
  or     %r10d,%edx
  movzbl %al,%eax
  imul   %r9d,%eax
  sar    $0x8,%eax
  movzbl %bl,%ebx
  add    %ebx,%eax
  mov    $0xff,%r9d
  cmp    %r9d,%eax
  cmovg  %r9d,%eax
  or     %eax,%edx
  mov    %edx,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L5
  pop    %rbx
  pop    %rbp
  ret
L17:
  ret
```

assistant: ```c
void blend_image_inplace(uint32_t *background, uint32_t *foreground, int count) {
  uint32_t Rf, Gf, Bf, Af;
  uint32_t Rb, Gb, Bb;
  uint32_t R, G, B;
  while (count) {
    Rf = (*foreground) & 0xff;
    Gf = ((*foreground) >> 8) & 0xff;
    Bf = ((*foreground) >> 16) & 0xff;
    Af = ((*foreground) >> 24) & 0xff;
    Rb = (*background) & 0xff;
    Gb = ((*background) >> 8) & 0xff;
    Bb = ((*background) >> 16) & 0xff;
    R = (Rf * Af) / 256 + Rb;
    G = (Gf * Af) / 256 + Gb;
    B = (Bf * Af) / 256 + Bb;
    if (R > 255)
      R = 255;
    if (G > 255)
      G = 255;
    if (B > 255)
      B = 255;
    (*background) = R | (G << 8) | (B << 16);
    foreground += 1;
    background += 1;
    count -= 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<blend_image_inplace>:
  endbr64
  test   %edx,%edx
  je     L11
  push   %rbp
  mov    %edx,%r8d
  xor    %ecx,%ecx
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rsi,%rcx,4),%eax
  mov    (%rdi,%rcx,4),%ebx
  mov    $0xff,%r10d
  mov    %eax,%r9d
  movzbl %ah,%edx
  movzbl %bh,%ebp
  mov    %ebx,%r11d
  shr    $0x18,%r9d
  movzbl %bl,%ebx
  imul   %r9d,%edx
  sar    $0x8,%edx
  add    %ebp,%edx
  cmp    %r10d,%edx
  cmovg  %r10d,%edx
  sar    $0x10,%r11d
  movzbl %r11b,%r11d
  shl    $0x8,%edx
  mov    %edx,%r10d
  mov    %eax,%edx
  movzbl %al,%eax
  sar    $0x10,%edx
  movzbl %dl,%edx
  imul   %r9d,%edx
  sar    $0x8,%edx
  add    %r11d,%edx
  mov    $0xff,%r11d
  cmp    %r11d,%edx
  cmovg  %r11d,%edx
  imul   %r9d,%eax
  mov    $0xff,%r9d
  shl    $0x10,%edx
  sar    $0x8,%eax
  or     %r10d,%edx
  add    %ebx,%eax
  cmp    %r9d,%eax
  cmovg  %r9d,%eax
  or     %eax,%edx
  mov    %edx,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%r8
  jne    L17
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
void blend_image_inplace(uint32_t *background, uint32_t *foreground, int count) {
  uint32_t Rf, Gf, Bf, Af;
  uint32_t Rb, Gb, Bb;
  uint32_t R, G, B;
  while (count) {
    Rf = (*foreground) & 0xff;
    Gf = ((*foreground) >> 8) & 0xff;
    Bf = ((*foreground) >> 16) & 0xff;
    Af = ((*foreground) >> 24) & 0xff;
    Rb = (*background) & 0xff;
    Gb = ((*background) >> 8) & 0xff;
    Bb = ((*background) >> 16) & 0xff;
    R = (Rf * Af) / 256 + Rb;
    G = (Gf * Af) / 256 + Gb;
    B = (Bf * Af) / 256 + Bb;
    if (R > 255)
      R = 255;
    if (G > 255)
      G = 255;
    if (B > 255)
      B = 255;
    (*background) = R | (G << 8) | (B << 16);
    foreground += 1;
    background += 1;
    count -= 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wcsspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L23
L18:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L74
L56:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L16
  addq   $0x4,-0x10(%rbp)
L74:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L56
  jmp    L34
L16:
  nop
L34:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L21
  mov    -0x8(%rbp),%rax
  jmp    L14
L21:
  addq   $0x1,-0x8(%rbp)
  addq   $0x4,-0x18(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L18
  mov    -0x8(%rbp),%rax
L14:
  pop    %rbp
  ret
```

assistant: ```c
size_t wcsspn(const wchar_t *wcs, const wchar_t *accept) {
  const wchar_t *p;
  const wchar_t *a;
  size_t count = 0;
  for (p = wcs; *p != L'\0'; ++p) {
    for (a = accept; *a != L'\0'; ++a)
      if (*p == *a)
        break;
    if (*a == L'\0')
      return count;
    else
      ++count;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wcsspn>:
  endbr64
  mov    (%rdi),%ecx
  test   %ecx,%ecx
  je     L19
  mov    (%rsi),%r9d
  test   %r9d,%r9d
  sete   %r10b
  mov    $0x0,%r8d
  jmp    L10
L65:
  mov    %r9d,%edx
L20:
  test   %edx,%edx
  je     L31
  add    $0x1,%r8
  mov    (%rdi,%r8,4),%ecx
  test   %ecx,%ecx
  je     L31
L10:
  cmp    %ecx,%r9d
  je     L65
  test   %r10b,%r10b
  jne    L65
  mov    %rsi,%rax
L81:
  add    $0x4,%rax
  mov    (%rax),%edx
  cmp    %ecx,%edx
  je     L20
  test   %edx,%edx
  jne    L81
  jmp    L20
L19:
  mov    $0x0,%r8d
L31:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t wcsspn(const wchar_t *wcs, const wchar_t *accept) {
  const wchar_t *p;
  const wchar_t *a;
  size_t count = 0;
  for (p = wcs; *p != L'\0'; ++p) {
    for (a = accept; *a != L'\0'; ++a)
      if (*p == *a)
        break;
    if (*a == L'\0')
      return count;
    else
      ++count;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wcsspn>:
  endbr64
  mov    (%rdi),%ecx
  xor    %r8d,%r8d
  test   %ecx,%ecx
  je     L12
  mov    (%rsi),%r9d
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L58:
  test   %r9d,%r9d
  je     L12
  mov    %rsi,%rdx
  mov    %r9d,%eax
  jmp    L39
  nopl   (%rax)
L2:
  mov    0x4(%rdx),%eax
  add    $0x4,%rdx
  test   %eax,%eax
  je     L12
L39:
  cmp    %ecx,%eax
  jne    L2
  add    $0x1,%r8
  mov    (%rdi,%r8,4),%ecx
  test   %ecx,%ecx
  jne    L58
L12:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t wcsspn(const wchar_t *wcs, const wchar_t *accept) {
  const wchar_t *p;
  const wchar_t *a;
  size_t count = 0;
  for (p = wcs; *p != L'\0'; ++p) {
    for (a = accept; *a != L'\0'; ++a)
      if (*p == *a)
        break;
    if (*a == L'\0')
      return count;
    else
      ++count;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wcsspn>:
  endbr64
  mov    (%rdi),%ecx
  xor    %r8d,%r8d
  test   %ecx,%ecx
  je     L18
  mov    (%rsi),%r9d
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L43:
  test   %r9d,%r9d
  je     L18
  mov    %rsi,%rdx
  mov    %r9d,%eax
  jmp    L41
  nopl   (%rax)
L8:
  mov    0x4(%rdx),%eax
  add    $0x4,%rdx
  test   %eax,%eax
  je     L18
L41:
  cmp    %ecx,%eax
  jne    L8
  add    $0x1,%r8
  mov    (%rdi,%r8,4),%ecx
  test   %ecx,%ecx
  jne    L43
L18:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t wcsspn(const wchar_t *wcs, const wchar_t *accept) {
  const wchar_t *p;
  const wchar_t *a;
  size_t count = 0;
  for (p = wcs; *p != L'\0'; ++p) {
    for (a = accept; *a != L'\0'; ++a)
      if (*p == *a)
        break;
    if (*a == L'\0')
      return count;
    else
      ++count;
  }
  return count;
}
```