ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<gpio_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <__no_gpio_code_for_this_architecture__@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int gpio_get(int gpio) {
  __no_gpio_code_for_this_architecture__();
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gpio_get>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__no_gpio_code_for_this_architecture__@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gpio_get(int gpio) {
  __no_gpio_code_for_this_architecture__();
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<gpio_get>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__no_gpio_code_for_this_architecture__@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gpio_get(int gpio) {
  __no_gpio_code_for_this_architecture__();
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gpio_get>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__no_gpio_code_for_this_architecture__@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gpio_get(int gpio) {
  __no_gpio_code_for_this_architecture__();
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L9:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L9
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t shuffle(uint64_t in, const uint8_t *shuffle, int shuffle_len) {
  int i;
  uint64_t res = 0;
  for (i = 0; i < shuffle_len; i++)
    res += res + ((in >> *shuffle++) & 1);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<shuffle>:
  endbr64
  test   %edx,%edx
  jle    L24
  mov    %edx,%edx
  lea    (%rsi,%rdx,4),%r8
  mov    $0x0,%edx
L25:
  add    $0x4,%rsi
  mov    -0x4(%rsi),%ecx
  mov    %edi,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  lea    (%rax,%rdx,2),%edx
  cmp    %r8,%rsi
  jne    L25
L2:
  mov    %edx,%eax
  ret
L24:
  mov    $0x0,%edx
  jmp    L2
```

assistant: ```c
uint64_t shuffle(uint64_t in, const uint8_t *shuffle, int shuffle_len) {
  int i;
  uint64_t res = 0;
  for (i = 0; i < shuffle_len; i++)
    res += res + ((in >> *shuffle++) & 1);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shuffle>:
  endbr64
  test   %edx,%edx
  jle    L1
  movslq %edx,%rdx
  xor    %r8d,%r8d
  lea    (%rsi,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rsi),%ecx
  mov    %edi,%eax
  add    $0x4,%rsi
  sar    %cl,%eax
  and    $0x1,%eax
  lea    (%rax,%r8,2),%r8d
  cmp    %rsi,%rdx
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t shuffle(uint64_t in, const uint8_t *shuffle, int shuffle_len) {
  int i;
  uint64_t res = 0;
  for (i = 0; i < shuffle_len; i++)
    res += res + ((in >> *shuffle++) & 1);
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shuffle>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  xor    %r8d,%r8d
  lea    (%rsi,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rsi),%ecx
  mov    %edi,%eax
  add    $0x4,%rsi
  sar    %cl,%eax
  and    $0x1,%eax
  lea    (%rax,%r8,2),%r8d
  cmp    %rsi,%rdx
  jne    L14
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t shuffle(uint64_t in, const uint8_t *shuffle, int shuffle_len) {
  int i;
  uint64_t res = 0;
  for (i = 0; i < shuffle_len; i++)
    res += res + ((in >> *shuffle++) & 1);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_one_mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  jne    L52
  mov    -0x2c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L50
L52:
  cmpl   $0x1,-0x30(%rbp)
  jne    L45
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L50
L45:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L48
L39:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
L48:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jg     L39
  cmpl   $0x0,-0x18(%rbp)
  je     L50
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L50:
  nop
  leave
  ret
```

assistant: ```c
void _one_mult(unsigned char *num, int size, int digit, unsigned char *result) {
  int carry, value;
  unsigned char *nptr, *rptr;
  if (digit == 0)
    memset(result, 0, size);
  else {
    if (digit == 1)
      memcpy(result, num, size);
    else {
      nptr = (unsigned char *)(num + size - 1);
      rptr = (unsigned char *)(result + size - 1);
      carry = 0;
      while (size-- > 0) {
        value = *nptr-- * digit + carry;
        *rptr-- = value % 10;
        carry = value / 10;
      }
      if (carry != 0)
        *rptr = carry;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_one_mult>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L43
  mov    %edx,%r8d
  cmp    $0x1,%edx
  je     L28
  movslq %esi,%rax
  sub    $0x1,%rax
  lea    (%rdi,%rax,1),%r9
  lea    (%rcx,%rax,1),%rdi
  lea    -0x1(%rsi),%r10d
  test   %esi,%esi
  jle    L45
  lea    -0x1(%rsi),%esi
  not    %rsi
  mov    $0x0,%ecx
  mov    $0x0,%eax
L24:
  movzbl (%r9,%rcx,1),%edx
  imul   %r8d,%edx
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%eax
  lea    (%rax,%rax,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%edx
  mov    %dl,(%rdi,%rcx,1)
  sub    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L24
  mov    %r10d,%r10d
  not    %r10
  add    %r10,%rdi
  test   %eax,%eax
  je     L45
  mov    %al,(%rdi)
  jmp    L45
L43:
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
L45:
  add    $0x8,%rsp
  ret
L28:
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  jmp    L45
```

assistant: ```c
void _one_mult(unsigned char *num, int size, int digit, unsigned char *result) {
  int carry, value;
  unsigned char *nptr, *rptr;
  if (digit == 0)
    memset(result, 0, size);
  else {
    if (digit == 1)
      memcpy(result, num, size);
    else {
      nptr = (unsigned char *)(num + size - 1);
      rptr = (unsigned char *)(result + size - 1);
      carry = 0;
      while (size-- > 0) {
        value = *nptr-- * digit + carry;
        *rptr-- = value % 10;
        carry = value / 10;
      }
      if (carry != 0)
        *rptr = carry;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_one_mult>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%r8d
  mov    %rcx,%rdi
  test   %edx,%edx
  je     L47
  cmp    $0x1,%edx
  je     L33
  movslq %esi,%rax
  sub    $0x1,%rax
  add    %rax,%r9
  add    %rax,%rdi
  test   %esi,%esi
  jle    L28
  lea    -0x1(%rsi),%r10d
  xor    %ecx,%ecx
  xor    %eax,%eax
  not    %r10
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl (%r9,%rcx,1),%edx
  imul   %r8d,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  mov    %dl,(%rdi,%rcx,1)
  sub    $0x1,%rcx
  cmp    %rcx,%r10
  jne    L17
  add    %r10,%rdi
  test   %eax,%eax
  je     L28
  mov    %al,(%rdi)
L28:
  ret
  nopl   (%rax)
L47:
  mov    %esi,%edx
  xor    %esi,%esi
  jmp    1060 <memset@plt>
  nopl   0x0(%rax)
L33:
  mov    %esi,%edx
  mov    %r9,%rsi
  jmp    1070 <memcpy@plt>
```

assistant: ```c
void _one_mult(unsigned char *num, int size, int digit, unsigned char *result) {
  int carry, value;
  unsigned char *nptr, *rptr;
  if (digit == 0)
    memset(result, 0, size);
  else {
    if (digit == 1)
      memcpy(result, num, size);
    else {
      nptr = (unsigned char *)(num + size - 1);
      rptr = (unsigned char *)(result + size - 1);
      carry = 0;
      while (size-- > 0) {
        value = *nptr-- * digit + carry;
        *rptr-- = value % 10;
        carry = value / 10;
      }
      if (carry != 0)
        *rptr = carry;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_one_mult>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%r8d
  mov    %rcx,%rdi
  test   %edx,%edx
  je     L2
  cmp    $0x1,%edx
  je     L15
  movslq %esi,%rax
  sub    $0x1,%rax
  add    %rax,%r9
  add    %rax,%rdi
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%r10d
  xor    %ecx,%ecx
  xor    %eax,%eax
  not    %r10
  nopw   0x0(%rax,%rax,1)
L31:
  movzbl (%r9,%rcx,1),%edx
  imul   %r8d,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  mov    %dl,(%rdi,%rcx,1)
  sub    $0x1,%rcx
  cmp    %rcx,%r10
  jne    L31
  add    %r10,%rdi
  test   %eax,%eax
  je     L5
  mov    %al,(%rdi)
L5:
  ret
  nopl   (%rax)
L2:
  mov    %esi,%edx
  xor    %esi,%esi
  jmp    1060 <memset@plt>
  nopl   0x0(%rax)
L15:
  mov    %esi,%edx
  mov    %r9,%rsi
  jmp    1070 <memcpy@plt>
```

assistant: ```c
void _one_mult(unsigned char *num, int size, int digit, unsigned char *result) {
  int carry, value;
  unsigned char *nptr, *rptr;
  if (digit == 0)
    memset(result, 0, size);
  else {
    if (digit == 1)
      memcpy(result, num, size);
    else {
      nptr = (unsigned char *)(num + size - 1);
      rptr = (unsigned char *)(result + size - 1);
      carry = 0;
      while (size-- > 0) {
        value = *nptr-- * digit + carry;
        *rptr-- = value % 10;
        carry = value / 10;
      }
      if (carry != 0)
        *rptr = carry;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gcc_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xfffffffe,-0x8(%rbp)
  jne    L15
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L15:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L16
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L18
L16:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L18:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string
name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D29: %d


tool: D17: #<void>

tool: D4: #<procedure>

assistant: ```c
void gcc_print(int value, int type) {
  if (type == -2) {
    printf("%d\n", value);
  } else if (type == -1) {
    printf("#<void>\n");
  } else {
    printf("#<procedure>\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<gcc_print>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xfffffffe,%esi
  je     L33
  cmp    $0xffffffff,%esi
  je     L21
  lea    D21(%rip),%rdi
  call   <puts@plt>
L1:
  add    $0x8,%rsp
  ret
L33:
  mov    %edi,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
L21:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: tag: D21
type_guessed: string
name: parse_data
arguments: tag: D18
type_guessed: string
name: parse_data
arguments: tag: D29
type_guessed: string

tool: D21: #<procedure>

tool: D18: %d


tool: D29: #<void>

assistant: ```c
void gcc_print(int value, int type) {
  if (type == -2) {
    printf("%d\n", value);
  } else if (type == -1) {
    printf("#<void>\n");
  } else {
    printf("#<procedure>\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gcc_print>:
  endbr64
  cmp    $0xfffffffe,%esi
  je     L14
  cmp    $0xffffffff,%esi
  je     L11
  lea    D28(%rip),%rdi
  jmp    1060 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L11:
  lea    D7(%rip),%rdi
  jmp    1060 <puts@plt>
  nopl   0x0(%rax)
L14:
  mov    %edi,%esi
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D28
type: string
name: unpack_data
arguments: data_label: D7
type: string
name: unpack_data
arguments: data_label: D0
type: string

tool: D28: #<procedure>

tool: D7: #<void>

tool: D0: %d


assistant: ```c
void gcc_print(int value, int type) {
  if (type == -2) {
    printf("%d\n", value);
  } else if (type == -1) {
    printf("#<void>\n");
  } else {
    printf("#<procedure>\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<gcc_print>:
  endbr64
  cmp    $0xfffffffe,%esi
  je     L15
  cmp    $0xffffffff,%esi
  je     L12
  lea    D23(%rip),%rdi
  jmp    1060 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  lea    D1(%rip),%rdi
  jmp    1060 <puts@plt>
  nopl   0x0(%rax)
L15:
  mov    %edi,%esi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D20
type_guessed: string

tool: D23: #<procedure>

tool: D1: #<void>

tool: D20: %d


assistant: ```c
void gcc_print(int value, int type) {
  if (type == -2) {
    printf("%d\n", value);
  } else if (type == -1) {
    printf("#<void>\n");
  } else {
    printf("#<procedure>\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L16
L10:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L16:
  cmpl   $0x0,-0x10(%rbp)
  jne    L10
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D4
type: string

tool: D25: Enter a fraction (x/y): 

tool: D23: %d/%d

tool: D4: In lowest terms: %d/%d


assistant: ```c
int main(void) {
  int num, den, r;
  int m = 0;
  int n = 0;
  printf("Enter a fraction (x/y): ");
  scanf("%d/%d", &num, &den);
  m = den;
  n = num;
  while (n != 0) {
    r = m % n;
    m = n;
    n = r;
  }
  num /= m;
  den /= m;
  printf("In lowest terms: %d/%d\n", num, den);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  mov    (%rsp),%esi
  test   %esi,%esi
  je     L33
  mov    %esi,%ecx
  mov    %r8d,%eax
L0:
  mov    %ecx,%edi
  cltd
  idiv   %ecx
  mov    %edx,%ecx
  mov    %edi,%eax
  test   %edx,%edx
  jne    L0
L36:
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %eax,%esi
  mov    %eax,(%rsp)
  mov    %r8d,%eax
  cltd
  idiv   %edi
  mov    %eax,0x4(%rsp)
  mov    %eax,%edx
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L33:
  mov    %r8d,%edi
  jmp    L36
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
data_type: string
name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D23
data_type: string

tool: D16: Enter a fraction (x/y): 

tool: D8: %d/%d

tool: D23: In lowest terms: %d/%d


assistant: ```c
int main(void) {
  int num, den, r;
  int m = 0;
  int n = 0;
  printf("Enter a fraction (x/y): ");
  scanf("%d/%d", &num, &den);
  m = den;
  n = num;
  while (n != 0) {
    r = m % n;
    m = n;
    n = r;
  }
  num /= m;
  den /= m;
  printf("In lowest terms: %d/%d\n", num, den);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  test   %esi,%esi
  je     L4
  mov    %esi,%edx
  mov    %edi,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L13
L30:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,(%rsp)
  mov    %eax,%esi
  mov    %edi,%eax
  lea    D2(%rip),%rdi
  cltd
  idiv   %ecx
  mov    %eax,0x4(%rsp)
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  mov    %edi,%ecx
  jmp    L30
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D29
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D29: Enter a fraction (x/y): 

tool: D19: %d/%d

tool: D2: In lowest terms: %d/%d


assistant: ```c
int main(void) {
  int num, den, r;
  int m = 0;
  int n = 0;
  printf("Enter a fraction (x/y): ");
  scanf("%d/%d", &num, &den);
  m = den;
  n = num;
  while (n != 0) {
    r = m % n;
    m = n;
    n = r;
  }
  num /= m;
  den /= m;
  printf("In lowest terms: %d/%d\n", num, den);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  test   %esi,%esi
  je     L30
  mov    %esi,%edx
  mov    %edi,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L17
L14:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,(%rsp)
  mov    %eax,%esi
  mov    %edi,%eax
  lea    D23(%rip),%rdi
  cltd
  idiv   %ecx
  mov    %eax,0x4(%rsp)
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L30:
  mov    %edi,%ecx
  jmp    L14
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D24
datatype: string
name: parse_data
arguments: label: D23
datatype: string

tool: D10: Enter a fraction (x/y): 

tool: D24: %d/%d

tool: D23: In lowest terms: %d/%d


assistant: ```c
int main(void) {
  int num, den, r;
  int m = 0;
  int n = 0;
  printf("Enter a fraction (x/y): ");
  scanf("%d/%d", &num, &den);
  m = den;
  n = num;
  while (n != 0) {
    r = m % n;
    m = n;
    n = r;
  }
  num /= m;
  den /= m;
  printf("In lowest terms: %d/%d\n", num, den);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %ecx,-0x58(%rbp)
  mov    %r8d,-0x5c(%rbp)
  mov    %r9,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  mov    %rax,-0x30(%rbp)
  mov    -0x58(%rbp),%eax
  cltq
  mov    %rax,-0x28(%rbp)
  mov    -0x5c(%rbp),%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <_mmap@plt>
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
__ptr_t mmap(__ptr_t addr, size_t len, int prot, int flags, int fd, off_t off) {
  unsigned long buffer[6];
  buffer[0] = (unsigned long)addr;
  buffer[1] = (unsigned long)len;
  buffer[2] = (unsigned long)prot;
  buffer[3] = (unsigned long)flags;
  buffer[4] = (unsigned long)fd;
  buffer[5] = (unsigned long)off;
  return (__ptr_t)_mmap(buffer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mmap>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  movslq %edx,%rdx
  mov    %rdx,0x10(%rsp)
  movslq %ecx,%rcx
  mov    %rcx,0x18(%rsp)
  movslq %r8d,%r8
  mov    %r8,0x20(%rsp)
  mov    %r9,0x28(%rsp)
  mov    %rsp,%rdi
  call   <_mmap@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  cltq
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__ptr_t mmap(__ptr_t addr, size_t len, int prot, int flags, int fd, off_t off) {
  unsigned long buffer[6];
  buffer[0] = (unsigned long)addr;
  buffer[1] = (unsigned long)len;
  buffer[2] = (unsigned long)prot;
  buffer[3] = (unsigned long)flags;
  buffer[4] = (unsigned long)fd;
  buffer[5] = (unsigned long)off;
  return (__ptr_t)_mmap(buffer);
}
```