ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x14,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x14,-0x10(%rbp)
  jmp    L44
L3:
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L9
L5:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L43
  movl   $0x0,-0x8(%rbp)
  nop
L43:
  addl   $0x1,-0xc(%rbp)
L9:
  cmpl   $0x14,-0xc(%rbp)
  jle    L5
  addl   $0x14,-0x10(%rbp)
L44:
  cmpl   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x10(%rbp),%eax
  sub    $0x14,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 20;
  int n;
  int div;
  int test = 0;
  for (n = 20; !test; n += 20) {
    test = 1;
    for (div = 2; div <= 20; div++) {
      if ((n % div) != 0) {
        test = 0;
        continue;
      }
    }
  }
  printf("%d\n", n - 20);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  mov    $0x0,%r8d
L9:
  mov    $0x1,%edi
  mov    $0x2,%ecx
L11:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmovne %r8d,%edi
  add    $0x1,%ecx
  cmp    $0x15,%ecx
  jne    L11
  lea    0x14(%rsi),%eax
  test   %edi,%edi
  jne    L10
  mov    %eax,%esi
  jmp    L9
L10:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 20;
  int n;
  int div;
  int test = 0;
  for (n = 20; !test; n += 20) {
    test = 1;
    for (div = 2; div <= 20; div++) {
      if ((n % div) != 0) {
        test = 0;
        continue;
      }
    }
  }
  printf("%d\n", n - 20);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  xor    %r8d,%r8d
L26:
  mov    $0x1,%edi
  mov    $0x2,%ecx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmovne %r8d,%edi
  add    $0x1,%ecx
  cmp    $0x15,%ecx
  jne    L4
  lea    0x14(%rsi),%eax
  test   %edi,%edi
  jne    L27
  mov    %eax,%esi
  jmp    L26
L27:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type: string

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 20;
  int n;
  int div;
  int test = 0;
  for (n = 20; !test; n += 20) {
    test = 1;
    for (div = 2; div <= 20; div++) {
      if ((n % div) != 0) {
        test = 0;
        continue;
      }
    }
  }
  printf("%d\n", n - 20);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  xor    %r8d,%r8d
L19:
  mov    $0x1,%edi
  mov    $0x2,%ecx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmovne %r8d,%edi
  add    $0x1,%ecx
  cmp    $0x15,%ecx
  jne    L3
  lea    0x14(%rsi),%eax
  test   %edi,%edi
  jne    L0
  mov    %eax,%esi
  jmp    L19
L0:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 20;
  int n;
  int div;
  int test = 0;
  for (n = 20; !test; n += 20) {
    test = 1;
    for (div = 2; div <= 20; div++) {
      if ((n % div) != 0) {
        test = 0;
        continue;
      }
    }
  }
  printf("%d\n", n - 20);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xaa,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <rightrot@plt>
  mov    %eax,-0x4(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <dec2bin@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <dec2bin@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <dec2bin@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D21
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string

tool: D6: x   = 

tool: D21: n   = 

tool: D28: result   = 

assistant: ```c
int main(void) {
  unsigned x = 170;
  int n = 3;
  int result = rightrot(x, n);
  printf("x   = ");
  dec2bin(x);
  printf("n   = ");
  dec2bin(n);
  printf("result   = ");
  dec2bin(result);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3,%esi
  mov    $0xaa,%edi
  call   <rightrot@plt>
  mov    %eax,%ebx
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0xaa,%edi
  call   <dec2bin@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <dec2bin@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <dec2bin@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D10
type_guessed: string

tool: D14: x   = 

tool: D29: n   = 

tool: D10: result   = 

assistant: ```c
int main(void) {
  unsigned x = 170;
  int n = 3;
  int result = rightrot(x, n);
  printf("x   = ");
  dec2bin(x);
  printf("n   = ");
  dec2bin(n);
  printf("result   = ");
  dec2bin(result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%esi
  mov    $0xaa,%edi
  call   <rightrot@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%ebp
  call   <printf@plt>
  mov    $0xaa,%edi
  call   <dec2bin@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <dec2bin@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <dec2bin@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string

tool: D27: x   = 

tool: D8: n   = 

tool: D0: result   = 

assistant: ```c
int main(void) {
  unsigned x = 170;
  int n = 3;
  int result = rightrot(x, n);
  printf("x   = ");
  dec2bin(x);
  printf("n   = ");
  dec2bin(n);
  printf("result   = ");
  dec2bin(result);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%esi
  mov    $0xaa,%edi
  call   <rightrot@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%ebp
  call   <printf@plt>
  mov    $0xaa,%edi
  call   <dec2bin@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <dec2bin@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <dec2bin@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string

tool: D24: x   = 

tool: D10: n   = 

tool: D13: result   = 

assistant: ```c
int main(void) {
  unsigned x = 170;
  int n = 3;
  int result = rightrot(x, n);
  printf("x   = ");
  dec2bin(x);
  printf("n   = ");
  dec2bin(n);
  printf("result   = ");
  dec2bin(result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L6:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  and    $0x3ff,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L6
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int unsigned hash(const char *s) {
  int unsigned h = 0;
  for (int i = 0; i < strlen(s); i++) {
    h = (h * 3 + s[i]) % 1024;
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L7
L8:
  lea    (%rbx,%rbx,2),%ebx
  movsbl (%r12,%rbp,1),%eax
  add    %eax,%ebx
  and    $0x3ff,%ebx
  add    $0x1,%rbp
L7:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L8
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int unsigned hash(const char *s) {
  int unsigned h = 0;
  for (int i = 0; i < strlen(s); i++) {
    h = (h * 3 + s[i]) % 1024;
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L3:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    (%r12,%r12,2),%r12d
  add    $0x1,%rbx
  add    %eax,%r12d
  and    $0x3ff,%r12d
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L3
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int unsigned hash(const char *s) {
  int unsigned h = 0;
  for (int i = 0; i < strlen(s); i++) {
    h = (h * 3 + s[i]) % 1024;
  }
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    (%r12,%r12,2),%r12d
  add    $0x1,%rbx
  add    %eax,%r12d
  and    $0x3ff,%r12d
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L6
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int unsigned hash(const char *s) {
  int unsigned h = 0;
  for (int i = 0; i < strlen(s); i++) {
    h = (h * 3 + s[i]) % 1024;
  }
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<free_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L27
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L27:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L15:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int free_matrix(char **m, int rows) {
  int r = 0;
  if (m) {
    for (r = 0; r < rows; r++) {
      if (m[r])
        free(m[r]);
    }
    free(m);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<free_matrix>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L9
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
  jmp    L53
L14:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L9
L53:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L14
  call   <free@plt>
  jmp    L14
L9:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int free_matrix(char **m, int rows) {
  int r = 0;
  if (m) {
    for (r = 0; r < rows; r++) {
      if (m[r])
        free(m[r]);
    }
    free(m);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_matrix>:
  endbr64
  test   %rdi,%rdi
  je     L35
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L22
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nop
L28:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L18
  call   <free@plt>
L18:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L28
L22:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int free_matrix(char **m, int rows) {
  int r = 0;
  if (m) {
    for (r = 0; r < rows; r++) {
      if (m[r])
        free(m[r]);
    }
    free(m);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<free_matrix>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L29
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nop
L36:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L15
  call   <free@plt>
L15:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L36
L29:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int free_matrix(char **m, int rows) {
  int r = 0;
  if (m) {
    for (r = 0; r < rows; r++) {
      if (m[r])
        free(m[r]);
    }
    free(m);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tolower_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L10
L11:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x18(%rbp)
  jb     L11
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void tolower_string(char *str) {
  for (size_t i = 0; i < strlen(str); i++)
    str[i] = tolower(str[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tolower_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L8
L10:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void tolower_string(char *str) {
  for (size_t i = 0; i < strlen(str); i++)
    str[i] = tolower(str[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<tolower_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L17
  nopl   0x0(%rax)
L11:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void tolower_string(char *str) {
  for (size_t i = 0; i < strlen(str); i++)
    str[i] = tolower(str[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tolower_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax)
L5:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void tolower_string(char *str) {
  for (size_t i = 0; i < strlen(str); i++)
    str[i] = tolower(str[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<IF_execCS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getString@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IF_execFct@plt>
  test   %eax,%eax
  jne    L15
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x15,%edi
  call   <messErr@plt>
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L11:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string

tool: D0: %s - 

assistant: ```c
void IF_execCS(void) {
  char *f;
  f = getString();
  if (f != NULL) {
    if (!IF_execFct(f)) {
      printf("%s - ", f);
      messErr(21);
    }
    free((void *)f);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IF_execCS>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getString@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <IF_execFct@plt>
  test   %eax,%eax
  je     L14
L4:
  mov    %rbx,%rdi
  call   <free@plt>
L27:
  pop    %rbx
  ret
L14:
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x15,%edi
  call   <messErr@plt>
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: %s - 

assistant: ```c
void IF_execCS(void) {
  char *f;
  f = getString();
  if (f != NULL) {
    if (!IF_execFct(f)) {
      printf("%s - ", f);
      messErr(21);
    }
    free((void *)f);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<IF_execCS>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <getString@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <IF_execFct@plt>
  test   %eax,%eax
  je     L6
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10a0 <free@plt>
  nopl   0x0(%rax)
L18:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x15,%edi
  call   <messErr@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10a0 <free@plt>
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: D4: %s - 

assistant: ```c
void IF_execCS(void) {
  char *f;
  f = getString();
  if (f != NULL) {
    if (!IF_execFct(f)) {
      printf("%s - ", f);
      messErr(21);
    }
    free((void *)f);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<IF_execCS>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <getString@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <IF_execFct@plt>
  test   %eax,%eax
  je     L11
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10a0 <free@plt>
  nopl   0x0(%rax)
L8:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x15,%edi
  call   <messErr@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10a0 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: %s - 

assistant: ```c
void IF_execCS(void) {
  char *f;
  f = getString();
  if (f != NULL) {
    if (!IF_execFct(f)) {
      printf("%s - ", f);
      messErr(21);
    }
    free((void *)f);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<libjte_add_exclude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <jte_add_exclude@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int libjte_add_exclude(struct libjte_env *o, char *pattern) {
  int ret;
  ret = jte_add_exclude(o, pattern);
  return !ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<libjte_add_exclude>:
  endbr64
  sub    $0x8,%rsp
  call   <jte_add_exclude@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int libjte_add_exclude(struct libjte_env *o, char *pattern) {
  int ret;
  ret = jte_add_exclude(o, pattern);
  return !ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<libjte_add_exclude>:
  endbr64
  sub    $0x8,%rsp
  call   <jte_add_exclude@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int libjte_add_exclude(struct libjte_env *o, char *pattern) {
  int ret;
  ret = jte_add_exclude(o, pattern);
  return !ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<libjte_add_exclude>:
  endbr64
  sub    $0x8,%rsp
  call   <jte_add_exclude@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int libjte_add_exclude(struct libjte_env *o, char *pattern) {
  int ret;
  ret = jte_add_exclude(o, pattern);
  return !ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BeaufordGetKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L3
L21:
  cmpb   $0x40,-0xd(%rbp)
  jle    L12
  cmpb   $0x5a,-0xd(%rbp)
  jle    L40
L12:
  cmpb   $0x60,-0xd(%rbp)
  jle    L3
  cmpb   $0x7a,-0xd(%rbp)
  jg     L3
L40:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  je     L74
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0xa,-0xd(%rbp)
  jne    L21
  jmp    L9
L74:
  nop
L9:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *BeaufordGetKey(int *keysize, int maxKeySize) {
  char *key = malloc(maxKeySize * sizeof(char));
  char ch;
  int position = -1;
  while ((ch = getchar()) != '\n') {
    if ((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch <= 'z')) {
      position++;
      key[position] = ch;
      if (position == maxKeySize - 1)
        break;
    }
  }
  *keysize = position + 1;
  return (key);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<BeaufordGetKey>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%r14
  mov    $0xffffffff,%ebp
  sub    $0x1,%ebx
L25:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L0
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L25
  add    $0x1,%ebp
  mov    %al,(%r14)
  add    $0x1,%r14
  cmp    %ebp,%ebx
  jne    L25
L0:
  add    $0x1,%ebp
  mov    %ebp,0x0(%r13)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *BeaufordGetKey(int *keysize, int maxKeySize) {
  char *key = malloc(maxKeySize * sizeof(char));
  char ch;
  int position = -1;
  while ((ch = getchar()) != '\n') {
    if ((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch <= 'z')) {
      position++;
      key[position] = ch;
      if (position == maxKeySize - 1)
        break;
    }
  }
  *keysize = position + 1;
  return (key);
}
```