user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    0x3a0(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D9(%rip),%r12
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x330(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,(%rsp)
  lea    -0x1(%rax),%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%esi
  cmp    %esi,%ebp
  mov    %esi,%edx
  cmovge %ebp,%edx
  lea    0x2(%rdx,%rdx,1),%ebx
  mov    %ebx,0x4(%rsp)
  lea    0x10(%rsp),%rbx
  lea    0x330(%rsp),%rcx
  mov    %rbx,%rdx
L83:
  movl   $0x0,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L83
  test   %esi,%esi
  js     L100
  mov    0x4(%rsp),%r11d
  mov    %r11d,%edi
  movslq %r11d,%rdx
  lea    0x10(%rsp,%rdx,4),%r13
  movslq %eax,%rdx
  lea    0x32f(%rsp,%rdx,1),%r12
  sub    %eax,%edi
  mov    $0x0,%r14d
  lea    0x3a0(%rsp),%r10
  mov    %rbx,0x8(%rsp)
  mov    %edi,%ebx
L43:
  sub    $0x1,%r11d
  test   %ebp,%ebp
  js     L13
  movsbl (%r12),%r9d
  sub    $0x30,%r9d
  movslq %ebp,%r8
  mov    %r13,%rdi
  mov    %r14d,%eax
L110:
  mov    -0x4(%rdi),%edx
  movsbl (%r8,%r10,1),%ecx
  sub    $0x30,%ecx
  imul   %r9d,%ecx
  add    %eax,%ecx
  movslq %edx,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %edx,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%r15d
  sar    $0x1f,%r15d
  sub    %r15d,%eax
  lea    (%rax,%rax,4),%r15d
  add    %r15d,%r15d
  sub    %r15d,%ecx
  add    %ecx,%edx
  movslq %edx,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %edx,%r15d
  sar    $0x1f,%r15d
  sub    %r15d,%ecx
  lea    (%rsi,%rcx,1),%esi
  add    %esi,-0x8(%rdi)
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rdi)
  sub    $0x1,%r8
  sub    $0x4,%rdi
  test   %r8d,%r8d
  jns    L110
  mov    (%rsp),%ecx
L97:
  mov    %r11d,%edx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %eax,0x10(%rsp,%rdx,4)
  sub    $0x4,%r13
  sub    $0x1,%r12
  cmp    %ebx,%r11d
  jne    L43
  mov    0x8(%rsp),%rbx
L100:
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L12
  lea    -0x1(%rax),%eax
  lea    0x4(%rbx,%rax,4),%rbp
  mov    $0x0,%eax
  lea    D42(%rip),%r12
  jmp    L64
L13:
  mov    %r14d,%ecx
  mov    %r14d,%eax
  jmp    L97
L84:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L88:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L12
L64:
  mov    (%rbx),%esi
  test   %eax,%eax
  jne    L51
  test   %esi,%esi
  jne    L84
L51:
  cmp    $0x1,%eax
  jne    L88
  jmp    L84
L12:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L122
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L122:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D44
data_type: string
name: read_data
arguments: data_tag: D9
data_type: string
name: read_data
arguments: data_tag: D34
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string
name: read_data
arguments: data_tag: D42
data_type: string

tool: D44: 
Enter the first number

tool: D9: %s

tool: D34: 
Enter the second number

tool: D4: 
The product is : 

tool: D42: %d

assistant: ```c
void main() {
  int c[200], car, i, j, k, l, r, s, a, flag = 0;
  char n[100], m[100];
  printf("\nEnter the first number");
  scanf("%s", m);
  printf("\nEnter the second number");
  scanf("%s", n);
  k = strlen(m) - 1;
  l = strlen(n) - 1;
  r = 2 * (((k) > (l)) ? (k) : (l)) + 2;
  for (i = 0; i < 200; i++)
    c[i] = 0;
  s = r;
  for (j = l; j >= 0; j--) {
    s--;
    a = 0;
    car = 0;
    for (i = k; i >= 0; i--) {
      c[s - a - 1] += (c[s - a] / 10);
      c[s - a] %= 10;
      c[s - a] += (((int)(m[i] - '0') * (int)(n[j] - '0') + car) % 10);
      car = ((int)(m[i] - '0') * (int)(n[j] - '0') + car) / 10;
      c[s - a - 1] += (c[s - a] / 10);
      c[s - a] %= 10;
      a++;
    }
    c[s - a] += car;
  }
  printf("\nThe product is : ");
  for (i = 0; i < r; i++) {
    if (c[i] != 0 && flag == 0)
      flag = 1;
    if (flag == 1)
      printf("%d", c[i]);
  }
}
```