ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<division>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D17(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    D9(%rip),%rdi
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string
name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string
name: read_data
arguments: data_tag: D9
type_infered: string

tool: D0: 
Please enter first number  : 

tool: D17: %d

tool: D4: Please enter second number : 

tool: D9: 
Division of entered numbers=%d


assistant: ```c
void division() {
  int a, b, d = 0;
  printf("\nPlease enter first number  : ");
  scanf("%d", &a);
  printf("Please enter second number : ");
  scanf("%d", &b);
  d = a / b;
  printf("\nDivision of entered numbers=%d\n", d);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<division>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D36(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    D21(%rip),%rdi
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D36
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D21
datatype: string

tool: D15: 
Please enter first number  : 

tool: D36: %d

tool: D17: Please enter second number : 

tool: D21: 
Division of entered numbers=%d


assistant: ```c
void division() {
  int a, b, d = 0;
  printf("\nPlease enter first number  : ");
  scanf("%d", &a);
  printf("Please enter second number : ");
  scanf("%d", &b);
  d = a / b;
  printf("\nDivision of entered numbers=%d\n", d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hidpp_cpu_to_le_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <hidpp_set_unaligned_le_u16@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
uint16_t hidpp_cpu_to_le_u16(uint16_t data) {
  uint16_t result;
  hidpp_set_unaligned_le_u16((uint8_t *)&result, data);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hidpp_cpu_to_le_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <hidpp_set_unaligned_le_u16@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t hidpp_cpu_to_le_u16(uint16_t data) {
  uint16_t result;
  hidpp_set_unaligned_le_u16((uint8_t *)&result, data);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hidpp_cpu_to_le_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <hidpp_set_unaligned_le_u16@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t hidpp_cpu_to_le_u16(uint16_t data) {
  uint16_t result;
  hidpp_set_unaligned_le_u16((uint8_t *)&result, data);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hidpp_cpu_to_le_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <hidpp_set_unaligned_le_u16@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t hidpp_cpu_to_le_u16(uint16_t data) {
  uint16_t result;
  hidpp_set_unaligned_le_u16((uint8_t *)&result, data);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  call   <do_something@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void bar() {
  int **p;
  if (foo(p))
    do_something();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <foo@plt>
  test   %rax,%rax
  jne    L12
L4:
  add    $0x8,%rsp
  ret
L12:
  mov    $0x0,%eax
  call   <do_something@plt>
  jmp    L4
```

assistant: ```c
void bar() {
  int **p;
  if (foo(p))
    do_something();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <foo@plt>
  test   %rax,%rax
  jne    L5
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <do_something@plt>
```

assistant: ```c
void bar() {
  int **p;
  if (foo(p))
    do_something();
}
```
user: What is the c source code of the assembly code below:

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <foo@plt>
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <do_something@plt>
```

assistant: ```c
void bar() {
  int **p;
  if (foo(p))
    do_something();
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L10
L0:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L0
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a && *b && *a == *b) {
    a++, b++;
  }
  return *a - *b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
L2:
  movzbl (%rsi),%edx
  cmp    %al,%dl
  jne    L9
  test   %dl,%dl
  je     L9
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
L9:
  movsbl %al,%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a && *b && *a == *b) {
    a++, b++;
  }
  return *a - *b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcmp>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L0
  jmp    L35
  nopl   (%rax)
L24:
  test   %dl,%dl
  je     L53
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L7
  mov    %rdx,%rsi
L0:
  movsbl (%rsi),%edx
  cmp    %al,%dl
  je     L24
L53:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L7:
  movsbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L35:
  movsbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L53
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a && *b && *a == *b) {
    a++, b++;
  }
  return *a - *b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcmp>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L54
  jmp    L51
  nopl   (%rax)
L39:
  test   %dl,%dl
  je     L59
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L26
  mov    %rdx,%rsi
L54:
  movsbl (%rsi),%edx
  cmp    %al,%dl
  je     L39
L59:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L26:
  movsbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L51:
  movsbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L59
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a && *b && *a == *b) {
    a++, b++;
  }
  return *a - *b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L0:
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L55:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L12
L27:
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L55
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
char *my_strstr(char *str, char *to_find) {
  int i;
  int j;
  i = 0;
  while (str[i] != '\0') {
    j = 0;
    while (to_find[j] == str[i + j]) {
      if (to_find[j + 1] == '\0') {
        return (str + i);
      }
      j++;
    }
    i++;
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_strstr>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L49
  movzbl (%rsi),%edi
L14:
  mov    $0x1,%edx
  cmp    (%rax),%dil
  jne    L1
L7:
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  je     L33
  add    $0x1,%rdx
  cmp    -0x1(%rax,%rdx,1),%cl
  je     L7
L1:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L14
  mov    $0x0,%eax
L33:
  ret
L49:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *my_strstr(char *str, char *to_find) {
  int i;
  int j;
  i = 0;
  while (str[i] != '\0') {
    j = 0;
    while (to_find[j] == str[i + j]) {
      if (to_find[j + 1] == '\0') {
        return (str + i);
      }
      j++;
    }
    i++;
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strstr>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L25
  movzbl (%rsi),%edi
L58:
  mov    $0x1,%edx
  cmp    %dil,%cl
  je     L23
  jmp    L29
  nopl   (%rax)
L34:
  add    $0x1,%rdx
  cmp    -0x1(%rax,%rdx,1),%cl
  jne    L29
L23:
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L34
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  jne    L58
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *my_strstr(char *str, char *to_find) {
  int i;
  int j;
  i = 0;
  while (str[i] != '\0') {
    j = 0;
    while (to_find[j] == str[i + j]) {
      if (to_find[j + 1] == '\0') {
        return (str + i);
      }
      j++;
    }
    i++;
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_strstr>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L45
  movzbl (%rsi),%edi
L8:
  mov    $0x1,%edx
  cmp    (%rax),%dil
  je     L56
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L32:
  add    $0x1,%rdx
  cmp    -0x1(%rax,%rdx,1),%cl
  jne    L48
L56:
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L32
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L8
L45:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *my_strstr(char *str, char *to_find) {
  int i;
  int j;
  i = 0;
  while (str[i] != '\0') {
    j = 0;
    while (to_find[j] == str[i + j]) {
      if (to_find[j + 1] == '\0') {
        return (str + i);
      }
      j++;
    }
    i++;
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Mat_vect_mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L24:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L5
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Mat_vect_mult(double A[], double x[], double y[], int m, int n) {
  int i, j;
  for (i = 0; i < m; i++) {
    y[i] = 0.0;
    for (j = 0; j < n; j++)
      y[i] += A[i * n + j] * x[j];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Mat_vect_mult>:
  endbr64
  test   %ecx,%ecx
  jle    L3
  push   %rbx
  mov    %rdi,%r11
  mov    %rdx,%r9
  lea    -0x1(%rcx),%eax
  lea    0x8(%rdx,%rax,8),%rbx
  mov    $0x0,%r10d
  mov    %r8d,%edi
L13:
  mov    %r9,%rdx
  movq   $0x0,(%r9)
  test   %r8d,%r8d
  jle    L23
  movslq %r10d,%rax
  lea    (%r11,%rax,8),%rcx
  mov    $0x0,%eax
L36:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L36
L23:
  add    $0x8,%r9
  add    %r8d,%r10d
  cmp    %rbx,%r9
  jne    L13
  pop    %rbx
  ret
L3:
  ret
```

assistant: ```c
void Mat_vect_mult(double A[], double x[], double y[], int m, int n) {
  int i, j;
  for (i = 0; i < m; i++) {
    y[i] = 0.0;
    for (j = 0; j < n; j++)
      y[i] += A[i * n + j] * x[j];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Mat_vect_mult>:
  endbr64
  test   %ecx,%ecx
  jle    L31
  lea    -0x1(%rcx),%eax
  push   %rbx
  mov    %rdi,%r11
  xor    %r10d,%r10d
  lea    0x8(%rdx,%rax,8),%rbx
  pxor   %xmm2,%xmm2
  lea    -0x1(%r8),%r9d
  mov    %rsi,%rdi
  nopw   0x0(%rax,%rax,1)
L8:
  movq   $0x0,(%rdx)
  test   %r8d,%r8d
  jle    L37
  movslq %r10d,%rax
  movapd %xmm2,%xmm1
  lea    (%r11,%rax,8),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L38:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  mov    %rax,%rcx
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %r9,%rcx
  jne    L38
L37:
  add    $0x8,%rdx
  add    %r8d,%r10d
  cmp    %rbx,%rdx
  jne    L8
  pop    %rbx
  ret
L31:
  ret
```

assistant: ```c
void Mat_vect_mult(double A[], double x[], double y[], int m, int n) {
  int i, j;
  for (i = 0; i < m; i++) {
    y[i] = 0.0;
    for (j = 0; j < n; j++)
      y[i] += A[i * n + j] * x[j];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Mat_vect_mult>:
  endbr64
  test   %ecx,%ecx
  jle    L0
  lea    -0x1(%rcx),%eax
  push   %rbx
  mov    %rdi,%r11
  xor    %r10d,%r10d
  lea    0x8(%rdx,%rax,8),%rbx
  pxor   %xmm2,%xmm2
  lea    -0x1(%r8),%r9d
  mov    %rsi,%rdi
  nopw   0x0(%rax,%rax,1)
L31:
  movq   $0x0,(%rdx)
  test   %r8d,%r8d
  jle    L6
  movslq %r10d,%rax
  movapd %xmm2,%xmm1
  lea    (%r11,%rax,8),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L12:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  mov    %rax,%rcx
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %r9,%rcx
  jne    L12
L6:
  add    $0x8,%rdx
  add    %r8d,%r10d
  cmp    %rdx,%rbx
  jne    L31
  pop    %rbx
  ret
L0:
  ret
```

assistant: ```c
void Mat_vect_mult(double A[], double x[], double y[], int m, int n) {
  int i, j;
  for (i = 0; i < m; i++) {
    y[i] = 0.0;
    for (j = 0; j < n; j++)
      y[i] += A[i * n + j] * x[j];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<module_control>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %ecx,%eax
  mov    %esi,%ecx
  mov    %cl,-0xc(%rbp)
  mov    %dl,-0x10(%rbp)
  mov    %al,-0x14(%rbp)
  cmpb   $0x1a,-0x14(%rbp)
  jne    L4
  cmpb   $0x0,-0x10(%rbp)
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  or     -0xc(%rbp),%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L4
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  movzbl -0xc(%rbp),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void module_control(volatile unsigned char *port, unsigned char pin, char state, char permission) {
  if (permission == 0x1A) {
    if (state)
      *port |= pin;
    else
      *port &= ~pin;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<module_control>:
  endbr64
  cmp    $0x1a,%cl
  je     L13
L19:
  ret
L13:
  test   %dl,%dl
  je     L5
  movzbl (%rdi),%eax
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
L5:
  movzbl (%rdi),%eax
  not    %esi
  and    %eax,%esi
  mov    %sil,(%rdi)
  jmp    L19
```

assistant: ```c
void module_control(volatile unsigned char *port, unsigned char pin, char state, char permission) {
  if (permission == 0x1A) {
    if (state)
      *port |= pin;
    else
      *port &= ~pin;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<module_control>:
  endbr64
  cmp    $0x1a,%cl
  je     L19
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl (%rdi),%eax
  test   %dl,%dl
  je     L18
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
  nopl   0x0(%rax)
L18:
  not    %esi
  and    %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void module_control(volatile unsigned char *port, unsigned char pin, char state, char permission) {
  if (permission == 0x1A) {
    if (state)
      *port |= pin;
    else
      *port &= ~pin;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<module_control>:
  endbr64
  cmp    $0x1a,%cl
  je     L12
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl (%rdi),%eax
  test   %dl,%dl
  je     L4
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
  nopl   0x0(%rax)
L4:
  not    %esi
  and    %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void module_control(volatile unsigned char *port, unsigned char pin, char state, char permission) {
  if (permission == 0x1A) {
    if (state)
      *port |= pin;
    else
      *port &= ~pin;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<delete_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x38(%rbp)
  jne    L7
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <cprintf@plt>
  movb   $0xc,-0x17(%rbp)
  lea    -0x17(%rbp),%rax
  mov    %rax,%rdi
  call   <cgets@plt>
  lea    -0x17(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L4
L7:
  mov    -0x38(%rbp),%rdx
  lea    -0x17(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x17(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <remove_app@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jne    L29
  mov    $0xc,%edi
  call   <textattr@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <cprintf@plt>
  mov    $0x7,%edi
  call   <textattr@plt>
  jmp    L42
L29:
  cmpl   $0x1,-0x24(%rbp)
  jne    L50
  mov    $0xc,%edi
  call   <textattr@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <cprintf@plt>
  mov    $0x7,%edi
  call   <textattr@plt>
  jmp    L42
L50:
  mov    $0x3,%edi
  call   <textattr@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <cprintf@plt>
  mov    $0x7,%edi
  call   <textattr@plt>
L42:
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D38
type_guessed: string
name: parse_data
arguments: data_label: D31
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D28
type_guessed: string

tool: D38: 
Enter (existing) file name: 

tool: D31: 
Error: file NOT removed. Data error. STATUS: %d

tool: D13: 
Error: file NOT removed. Failed. STATUS: %d

tool: D28: 
File removed successfully. STATUS: %d

assistant: ```c
int delete_file(char *s) {
  char cfname[15];
  char *fname;
  int status;
  if (s == NULL) {
    cprintf("\n\rEnter (existing) file name: ");
    cfname[0] = 12;
    cgets(cfname);
    fname = cfname + 2;
  } else {
    strcpy(cfname, s);
    fname = cfname;
  }
  status = remove_app(fname, 1);
  if (status == 2) {
    textattr(0x0C);
    cprintf("\n\rError: file NOT removed. Data error. STATUS: %d", status);
    textattr(0x07);
  } else if (status == 1) {
    textattr(0x0C);
    cprintf("\n\rError: file NOT removed. Failed. STATUS: %d", status);
    textattr(0x07);
  } else {
    textattr(0x03);
    cprintf("\n\rFile removed successfully. STATUS: %d", status);
    textattr(0x07);
  }
  return status;
}
```