ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L28
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r12
  lea    D23(%rip),%rbp
  lea    D0(%rip),%r14
  lea    D2(%rip),%r13
  jmp    L74
L49:
  mov    %rdx,%rax
L85:
  cmp    %rax,%rcx
  je     L20
  lea    (%rsi,%rax,1),%rdx
  mov    %rax,%rsi
  cmp    %rcx,%rdx
  jle    L49
L3:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L12
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    %r13,%rdi
  call   <printf@plt>
L12:
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  jle    L28
L74:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rcx
  test   %rcx,%rcx
  jle    L3
  mov    $0x1,%eax
  mov    $0x1,%esi
  jmp    L85
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D23
type_infered: string
name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D2
type_infered: string

tool: D23: %ld

tool: D0: IsNotFibo


tool: D2: IsFibo


assistant: ```c
int main() {
  long t, n, a = 0, b = 1, c, j;
  bool isFibo = false;
  scanf("%ld", &t);
  for (j = 0; j < t; j++) {
    scanf("%ld", &n);
    a = 0;
    b = 1;
    c = a + b;
    isFibo = false;
    while (c <= n) {
      if (c == n) {
        isFibo = true;
        break;
      } else {
        a = b;
        b = c;
        c = a + b;
      }
    }
    if (isFibo) {
      printf("IsFibo\n");
    } else {
      printf("IsNotFibo\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L36
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  lea    D10(%rip),%r14
  lea    D9(%rip),%r13
  nopl   0x0(%rax)
L23:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rcx
  test   %rcx,%rcx
  jle    L69
  mov    $0x1,%eax
  mov    $0x1,%esi
  jmp    L55
  nopl   0x0(%rax)
L37:
  lea    (%rsi,%rax,1),%rdx
  mov    %rax,%rsi
  cmp    %rcx,%rdx
  jg     L69
  mov    %rdx,%rax
L55:
  cmp    %rax,%rcx
  jne    L37
  mov    %r13,%rdi
  call   <printf@plt>
L25:
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  jg     L23
L36:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L25
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type: string
name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D28: %ld

tool: D10: IsNotFibo


tool: D9: IsFibo


assistant: ```c
int main() {
  long t, n, a = 0, b = 1, c, j;
  bool isFibo = false;
  scanf("%ld", &t);
  for (j = 0; j < t; j++) {
    scanf("%ld", &n);
    a = 0;
    b = 1;
    c = a + b;
    isFibo = false;
    while (c <= n) {
      if (c == n) {
        isFibo = true;
        break;
      } else {
        a = b;
        b = c;
        c = a + b;
      }
    }
    if (isFibo) {
      printf("IsFibo\n");
    } else {
      printf("IsNotFibo\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L49
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  lea    D7(%rip),%r14
  lea    D1(%rip),%r13
  nopl   0x0(%rax)
L52:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rcx
  test   %rcx,%rcx
  jle    L7
  mov    $0x1,%eax
  mov    $0x1,%esi
  jmp    L5
  nopl   0x0(%rax)
L27:
  lea    (%rsi,%rax,1),%rdx
  mov    %rax,%rsi
  cmp    %rcx,%rdx
  jg     L7
  mov    %rdx,%rax
L5:
  cmp    %rax,%rcx
  jne    L27
  mov    %r13,%rdi
  call   <printf@plt>
L24:
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  jg     L52
L49:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L24
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D22: %ld

tool: D7: IsNotFibo


tool: D1: IsFibo


assistant: ```c
int main() {
  long t, n, a = 0, b = 1, c, j;
  bool isFibo = false;
  scanf("%ld", &t);
  for (j = 0; j < t; j++) {
    scanf("%ld", &n);
    a = 0;
    b = 1;
    c = a + b;
    isFibo = false;
    while (c <= n) {
      if (c == n) {
        isFibo = true;
        break;
      } else {
        a = b;
        b = c;
        c = a + b;
      }
    }
    if (isFibo) {
      printf("IsFibo\n");
    } else {
      printf("IsNotFibo\n");
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_xmlGetNumTags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L67
L3:
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L49
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  je     L79
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L67
L79:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  je     L66
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L67
L66:
  addl   $0x1,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L67:
  cmpq   $0x0,-0x10(%rbp)
  jne    L3
  jmp    L11
L49:
  nop
L11:
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _xmlGetNumTags(const char *xmlString, const char *tagName) {
  int numTags;
  const char *src;
  char *strTag;
  int tagLen;
  tagLen = strlen(tagName);
  numTags = 0;
  src = xmlString;
  while (src) {
    strTag = strstr(src, tagName);
    if (strTag == NULL)
      break;
    if (strTag[-1] != '<') {
      src = strTag + 1;
      continue;
    }
    if (strTag[tagLen] != '>') {
      src = strTag + tagLen + 1;
      continue;
    }
    numTags++;
    src = strTag + tagLen + 1;
  }
  return numTags;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_xmlGetNumTags>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %rbx,%rbx
  je     L38
  mov    $0x0,%r13d
  movslq %eax,%r12
  lea    0x1(%r12),%r14
L18:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L43
  lea    0x1(%rax),%rbx
  cmpb   $0x3c,-0x1(%rax)
  jne    L18
  lea    (%rax,%r14,1),%rbx
  cmpb   $0x3e,(%rax,%r12,1)
  jne    L18
  add    $0x1,%r13d
  lea    (%rax,%r14,1),%rbx
  jmp    L18
L38:
  mov    $0x0,%r13d
L43:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _xmlGetNumTags(const char *xmlString, const char *tagName) {
  int numTags;
  const char *src;
  char *strTag;
  int tagLen;
  tagLen = strlen(tagName);
  numTags = 0;
  src = xmlString;
  while (src) {
    strTag = strstr(src, tagName);
    if (strTag == NULL)
      break;
    if (strTag[-1] != '<') {
      src = strTag + 1;
      continue;
    }
    if (strTag[tagLen] != '>') {
      src = strTag + tagLen + 1;
      continue;
    }
    numTags++;
    src = strTag + tagLen + 1;
  }
  return numTags;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_xmlGetNumTags>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %r14,%r14
  je     L35
  movslq %eax,%rbp
  lea    0x1(%rbp),%r13
  nopl   0x0(%rax)
L15:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L35
L27:
  cmpb   $0x3c,-0x1(%rax)
  lea    0x1(%rax),%r14
  jne    L15
  cmpb   $0x3e,(%rax,%rbp,1)
  lea    (%rax,%r13,1),%r14
  mov    %rbx,%rsi
  sete   %al
  mov    %r14,%rdi
  movzbl %al,%eax
  add    %eax,%r12d
  call   <strstr@plt>
  test   %rax,%rax
  jne    L27
L35:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _xmlGetNumTags(const char *xmlString, const char *tagName) {
  int numTags;
  const char *src;
  char *strTag;
  int tagLen;
  tagLen = strlen(tagName);
  numTags = 0;
  src = xmlString;
  while (src) {
    strTag = strstr(src, tagName);
    if (strTag == NULL)
      break;
    if (strTag[-1] != '<') {
      src = strTag + 1;
      continue;
    }
    if (strTag[tagLen] != '>') {
      src = strTag + tagLen + 1;
      continue;
    }
    numTags++;
    src = strTag + tagLen + 1;
  }
  return numTags;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_xmlGetNumTags>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %r14,%r14
  je     L29
  movslq %eax,%rbp
  lea    0x1(%rbp),%r13
  nopl   0x0(%rax)
L10:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L29
L8:
  cmpb   $0x3c,-0x1(%rax)
  lea    0x1(%rax),%r14
  jne    L10
  cmpb   $0x3e,(%rax,%rbp,1)
  lea    (%rax,%r13,1),%r14
  mov    %rbx,%rsi
  sete   %al
  mov    %r14,%rdi
  movzbl %al,%eax
  add    %eax,%r12d
  call   <strstr@plt>
  test   %rax,%rax
  jne    L8
L29:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _xmlGetNumTags(const char *xmlString, const char *tagName) {
  int numTags;
  const char *src;
  char *strTag;
  int tagLen;
  tagLen = strlen(tagName);
  numTags = 0;
  src = xmlString;
  while (src) {
    strTag = strstr(src, tagName);
    if (strTag == NULL)
      break;
    if (strTag[-1] != '<') {
      src = strTag + 1;
      continue;
    }
    if (strTag[tagLen] != '>') {
      src = strTag + tagLen + 1;
      continue;
    }
    numTags++;
    src = strTag + tagLen + 1;
  }
  return numTags;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gauss_2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  %xmm3,-0x20(%rbp)
  movss  %xmm4,-0x24(%rbp)
  movss  %xmm5,-0x28(%rbp)
  movss  -0x24(%rbp),%xmm0
  subss  -0x14(%rbp),%xmm0
  divss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x28(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  divss  -0x20(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x8(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x4(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  movss  D1(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  D12(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <exp@plt>
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D12
type_guessed: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x80]}

tool: {"D12": [0x00,0x00,0x00,0x40]}

assistant: ```c
float gauss_2d(float mx, float my, float sx, float sy, float x, float y) {
  float const dx = (x - mx) / sx;
  float const dy = (y - my) / sy;
  return exp(-(dx * dx + dy * dy) / 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gauss_2d>:
  endbr64
  sub    $0x8,%rsp
  subss  %xmm0,%xmm4
  divss  %xmm2,%xmm4
  subss  %xmm1,%xmm5
  divss  %xmm3,%xmm5
  mulss  %xmm4,%xmm4
  mulss  %xmm5,%xmm5
  addss  %xmm5,%xmm4
  xorps  D4(%rip),%xmm4
  mulss  D0(%rip),%xmm4
  movaps %xmm4,%xmm0
  call   <exp@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: byte[16]
name: disassemble_data
arguments: data_tag: D0
datatype: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D0": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float gauss_2d(float mx, float my, float sx, float sy, float x, float y) {
  float const dx = (x - mx) / sx;
  float const dy = (y - my) / sy;
  return exp(-(dx * dx + dy * dy) / 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gauss_2d>:
  endbr64
  subss  %xmm0,%xmm4
  subss  %xmm1,%xmm5
  movss  D12(%rip),%xmm0
  divss  %xmm2,%xmm4
  divss  %xmm3,%xmm5
  mulss  %xmm4,%xmm4
  mulss  %xmm5,%xmm5
  addss  %xmm5,%xmm4
  xorps  D14(%rip),%xmm4
  mulss  %xmm4,%xmm0
  jmp    1050 <exp@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type: byte[4]
name: read_data
arguments: tag: D14
type: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x3f]}

tool: {"D14": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float gauss_2d(float mx, float my, float sx, float sy, float x, float y) {
  float const dx = (x - mx) / sx;
  float const dy = (y - my) / sy;
  return exp(-(dx * dx + dy * dy) / 2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gauss_2d>:
  endbr64
  subss  %xmm0,%xmm4
  subss  %xmm1,%xmm5
  movss  D14(%rip),%xmm0
  divss  %xmm2,%xmm4
  divss  %xmm3,%xmm5
  mulss  %xmm4,%xmm4
  mulss  %xmm5,%xmm5
  addss  %xmm5,%xmm4
  xorps  D17(%rip),%xmm4
  mulss  %xmm4,%xmm0
  jmp    1050 <exp@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
data_type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D17
data_type: byte[16]

tool: {"D14": [0x00,0x00,0x00,0x3f]}

tool: {"D17": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float gauss_2d(float mx, float my, float sx, float sy, float x, float y) {
  float const dx = (x - mx) / sx;
  float const dy = (y - my) / sy;
  return exp(-(dx * dx + dy * dy) / 2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<support>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L26:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L14
  addl   $0x1,-0x4(%rbp)
L14:
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int support(int *v, int length) {
  int i;
  int count = 0;
  for (i = 0; i < length; i++)
    if (v[i])
      count++;
  return (count);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<support>:
  endbr64
  test   %esi,%esi
  jle    L27
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L19:
  cmpl   $0x1,(%rax)
  sbb    $0xffffffff,%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L19
L24:
  mov    %edx,%eax
  ret
L27:
  mov    $0x0,%edx
  jmp    L24
```

assistant: ```c
int support(int *v, int length) {
  int i;
  int count = 0;
  for (i = 0; i < length; i++)
    if (v[i])
      count++;
  return (count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<support>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  cmpl   $0x1,(%rdi)
  sbb    $0xffffffff,%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L7
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int support(int *v, int length) {
  int i;
  int count = 0;
  for (i = 0; i < length; i++)
    if (v[i])
      count++;
  return (count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<support>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L33
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L30
  mov    %esi,%ecx
  pxor   %xmm1,%xmm1
  mov    %rdi,%rax
  shr    $0x2,%ecx
  movdqa %xmm1,%xmm2
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L39:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pcmpeqd %xmm2,%xmm0
  pcmpeqd %xmm2,%xmm0
  psubd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L39
  movdqa %xmm1,%xmm0
  mov    %esi,%ecx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%ecx
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x3,%sil
  je     L5
L35:
  movslq %ecx,%rdi
  cmpl   $0x1,(%rdx,%rdi,4)
  lea    0x0(,%rdi,4),%r8
  lea    0x1(%rcx),%edi
  sbb    $0xffffffff,%eax
  cmp    %esi,%edi
  jge    L57
  cmpl   $0x1,0x4(%rdx,%r8,1)
  sbb    $0xffffffff,%eax
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jle    L57
  cmpl   $0x1,0x8(%rdx,%r8,1)
  sbb    $0xffffffff,%eax
  ret
  nopl   (%rax)
L33:
  xor    %eax,%eax
L57:
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
L30:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L35
```

assistant: ```c
int support(int *v, int length) {
  int i;
  int count = 0;
  for (i = 0; i < length; i++)
    if (v[i])
      count++;
  return (count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mono16_buf_to_mono8_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L13:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x8(%rbp)
  addq   $0x4,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mono16_buf_to_mono8_buf(u_int16_t *mono16_buf, u_int8_t *mono8_buf, int len) {
  int i;
  u_int16_t *mono16_ptr;
  u_int8_t *mono8_ptr;
  mono16_ptr = mono16_buf;
  mono8_ptr = mono8_buf;
  for (i = 0; i < len; i++) {
    *mono8_ptr = (*mono16_ptr) >> 4;
    mono8_ptr++;
    mono16_ptr++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mono16_buf_to_mono8_buf>:
  endbr64
  test   %edx,%edx
  jle    L11
  mov    %edx,%edx
  mov    $0x0,%eax
L19:
  mov    (%rdi,%rax,4),%ecx
  sar    $0x4,%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
L11:
  ret
```

assistant: ```c
void mono16_buf_to_mono8_buf(u_int16_t *mono16_buf, u_int8_t *mono8_buf, int len) {
  int i;
  u_int16_t *mono16_ptr;
  u_int8_t *mono8_ptr;
  mono16_ptr = mono16_buf;
  mono8_ptr = mono8_buf;
  for (i = 0; i < len; i++) {
    *mono8_ptr = (*mono16_ptr) >> 4;
    mono8_ptr++;
    mono16_ptr++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mono16_buf_to_mono8_buf>:
  endbr64
  test   %edx,%edx
  jle    L8
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L3:
  mov    (%rdi,%rax,4),%ecx
  sar    $0x4,%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L8:
  ret
```

assistant: ```c
void mono16_buf_to_mono8_buf(u_int16_t *mono16_buf, u_int8_t *mono8_buf, int len) {
  int i;
  u_int16_t *mono16_ptr;
  u_int8_t *mono8_ptr;
  mono16_ptr = mono16_buf;
  mono8_ptr = mono8_buf;
  for (i = 0; i < len; i++) {
    *mono8_ptr = (*mono16_ptr) >> 4;
    mono8_ptr++;
    mono16_ptr++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mono16_buf_to_mono8_buf>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  test   %edx,%edx
  jle    L43
  lea    0x4(%rcx),%rsi
  mov    %rdi,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L20
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L20
  mov    %edx,%esi
  xor    %eax,%eax
  shr    $0x2,%esi
  shl    $0x4,%rsi
  nopl   (%rax)
L39:
  movdqu (%rcx,%rax,1),%xmm0
  psrad  $0x4,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L39
  mov    %edx,%esi
  and    $0xfffffffc,%esi
  mov    %esi,%eax
  shl    $0x2,%rax
  add    %rax,%rcx
  add    %rdi,%rax
  cmp    %esi,%edx
  je     L43
  mov    (%rcx),%edi
  sar    $0x4,%edi
  mov    %edi,(%rax)
  lea    0x1(%rsi),%edi
  cmp    %edi,%edx
  jle    L43
  mov    0x4(%rcx),%edi
  add    $0x2,%esi
  sar    $0x4,%edi
  mov    %edi,0x4(%rax)
  cmp    %esi,%edx
  jle    L43
  mov    0x8(%rcx),%edx
  sar    $0x4,%edx
  mov    %edx,0x8(%rax)
  ret
  nopl   0x0(%rax)
L20:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L26:
  mov    (%rcx,%rax,4),%esi
  sar    $0x4,%esi
  mov    %esi,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L26
L43:
  ret
```

assistant: ```c
void mono16_buf_to_mono8_buf(u_int16_t *mono16_buf, u_int8_t *mono8_buf, int len) {
  int i;
  u_int16_t *mono16_ptr;
  u_int8_t *mono8_ptr;
  mono16_ptr = mono16_buf;
  mono8_ptr = mono8_buf;
  for (i = 0; i < len; i++) {
    *mono8_ptr = (*mono16_ptr) >> 4;
    mono8_ptr++;
    mono16_ptr++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D40
type: string
name: unpack_data
arguments: tag: D60
type: string
name: unpack_data
arguments: tag: D33
type: string
name: unpack_data
arguments: tag: D6
type: string
name: unpack_data
arguments: tag: D25
type: string
name: unpack_data
arguments: tag: D14
type: string

tool: D9: Super bookshelf manager v4.2


tool: D40: 1. Add book


tool: D60: 2. Print book


tool: D33: 3. Delete book


tool: D6: 4. Edit book


tool: D25: 5. Exit


tool: D14: > 

assistant: ```c
void print_menu(void) {
  printf("Super bookshelf manager v4.2\n");
  printf("1. Add book\n");
  printf("2. Print book\n");
  printf("3. Delete book\n");
  printf("4. Edit book\n");
  printf("5. Exit\n");
  printf("> ");
}
```