ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<page45>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D71(%rip),%rdi
  call   <printf@plt>
  lea    D77(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D56
type_infered: string
name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D66
type_infered: string
name: read_data
arguments: data_tag: D71
type_infered: string
name: read_data
arguments: data_tag: D77
type_infered: string
name: read_data
arguments: data_tag: D53
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string

tool: D13: "Hrank Hrank," snorts the alarm in your living quarters.  Something is up.


tool: D56: You look at the monitor above the bathroom mirror and see the message you have


tool: D24: been waiting for all these years.  "ATTENTION TROUBLESHOOTER, YOU ARE BEING


tool: D18: ACTIVATED. PLEASE REPORT IMMEDIATELY TO MISSION ASSIGNMENT ROOM A17/GAMMA/LB22.


tool: D66: THANK YOU. THE COMPUTER IS YOUR FRIEND."  When you arrive at mission


tool: D71: assignment room A17-gamma/LB22 you are given your previous clone's


tool: D77: remaining possessions and notebook.  You puzzle through your predecessor's


tool: D53: cryptic notes, managing to decipher enough to lead you to the tube station and


tool: D5: the tube car to GDH7-beta.


assistant: ```c
page45() {
  printf("\"Hrank Hrank,\" snorts the alarm in your living quarters.  Something is up.\n");
  printf("You look at the monitor above the bathroom mirror and see the message you have\n");
  printf("been waiting for all these years.  \"ATTENTION TROUBLESHOOTER, YOU ARE BEING\n");
  printf("ACTIVATED. PLEASE REPORT IMMEDIATELY TO MISSION ASSIGNMENT ROOM A17/GAMMA/LB22.\n");
  printf("THANK YOU. THE COMPUTER IS YOUR FRIEND.\"  When you arrive at mission\n");
  printf("assignment room A17-gamma/LB22 you are given your previous clone\'s\n");
  printf("remaining possessions and notebook.  You puzzle through your predecessor\'s\n");
  printf("cryptic notes, managing to decipher enough to lead you to the tube station and\n");
  printf("the tube car to GDH7-beta.\n");
  return 10;
}
```
user: Translate the below assembly code into C programming language:

```asm
<page45>:
  endbr64
  sub    $0x8,%rsp
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D78(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D37
type_guessed: string
name: extract_symbolic_data
arguments: label: D21
type_guessed: string
name: extract_symbolic_data
arguments: label: D66
type_guessed: string
name: extract_symbolic_data
arguments: label: D17
type_guessed: string
name: extract_symbolic_data
arguments: label: D45
type_guessed: string
name: extract_symbolic_data
arguments: label: D34
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D78
type_guessed: string
name: extract_symbolic_data
arguments: label: D47
type_guessed: string

tool: D37: "Hrank Hrank," snorts the alarm in your living quarters.  Something is up.


tool: D21: You look at the monitor above the bathroom mirror and see the message you have


tool: D66: been waiting for all these years.  "ATTENTION TROUBLESHOOTER, YOU ARE BEING


tool: D17: ACTIVATED. PLEASE REPORT IMMEDIATELY TO MISSION ASSIGNMENT ROOM A17/GAMMA/LB22.


tool: D45: THANK YOU. THE COMPUTER IS YOUR FRIEND."  When you arrive at mission


tool: D34: assignment room A17-gamma/LB22 you are given your previous clone's


tool: D23: remaining possessions and notebook.  You puzzle through your predecessor's


tool: D78: cryptic notes, managing to decipher enough to lead you to the tube station and


tool: D47: the tube car to GDH7-beta.


assistant: ```c
page45() {
  printf("\"Hrank Hrank,\" snorts the alarm in your living quarters.  Something is up.\n");
  printf("You look at the monitor above the bathroom mirror and see the message you have\n");
  printf("been waiting for all these years.  \"ATTENTION TROUBLESHOOTER, YOU ARE BEING\n");
  printf("ACTIVATED. PLEASE REPORT IMMEDIATELY TO MISSION ASSIGNMENT ROOM A17/GAMMA/LB22.\n");
  printf("THANK YOU. THE COMPUTER IS YOUR FRIEND.\"  When you arrive at mission\n");
  printf("assignment room A17-gamma/LB22 you are given your previous clone\'s\n");
  printf("remaining possessions and notebook.  You puzzle through your predecessor\'s\n");
  printf("cryptic notes, managing to decipher enough to lead you to the tube station and\n");
  printf("the tube car to GDH7-beta.\n");
  return 10;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pdecode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L52
L62:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L34
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  test   %rax,%rax
  je     L34
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  test   %rax,%rax
  je     L34
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  addq   $0x2,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L57
L34:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L57:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L52:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D7: %2x

assistant: ```c
char *pdecode(char *str) {
  char *s;
  int slen = strlen(str);
  char *result = malloc((slen + 1) * sizeof(char));
  char *r = result;
  for (s = str; *s != '\0'; s++, r++) {
    if (*s == '%' && s + 1 != '\0' && s + 2 != '\0') {
      int c;
      sscanf(s + 1, "%2x", &c);
      s += 2;
      *r = (char)c;
    } else
      *r = *s;
  }
  *r = '\0';
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pdecode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  movzbl (%rbx),%eax
  test   %al,%al
  je     L53
  mov    %r13,%rbp
  lea    D0(%rip),%r14
  jmp    L58
L20:
  mov    %al,0x0(%rbp)
  mov    %rbx,%r12
L42:
  lea    0x1(%r12),%rbx
  add    $0x1,%rbp
  movzbl 0x1(%r12),%eax
  test   %al,%al
  je     L23
L58:
  cmp    $0x25,%al
  jne    L20
  lea    0x2(%rbx),%r12
  lea    0x4(%rsp),%rdx
  lea    0x1(%rbx),%rdi
  mov    %r14,%rsi
  mov    $0x0,%eax
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  mov    %al,0x0(%rbp)
  jmp    L42
L53:
  mov    %r13,%rbp
L23:
  movb   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %r13,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: %2x

assistant: ```c
char *pdecode(char *str) {
  char *s;
  int slen = strlen(str);
  char *result = malloc((slen + 1) * sizeof(char));
  char *r = result;
  for (s = str; *s != '\0'; s++, r++) {
    if (*s == '%' && s + 1 != '\0' && s + 2 != '\0') {
      int c;
      sscanf(s + 1, "%2x", &c);
      s += 2;
      *r = (char)c;
    } else
      *r = *s;
  }
  *r = '\0';
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<pdecode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  movzbl 0x0(%rbp),%edx
  mov    %rax,%r13
  mov    %rax,%rbx
  test   %dl,%dl
  je     L52
  lea    D5(%rip),%r14
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %dl,(%rbx)
  mov    %rbp,%r12
L25:
  movzbl 0x1(%r12),%edx
  lea    0x1(%r12),%rbp
  add    $0x1,%rbx
  test   %dl,%dl
  je     L52
L28:
  cmp    $0x25,%dl
  jne    L49
  lea    0x4(%rsp),%rdx
  lea    0x1(%rbp),%rdi
  mov    %r14,%rsi
  xor    %eax,%eax
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x2(%rbp),%r12
  mov    %al,(%rbx)
  jmp    L25
  nopl   0x0(%rax)
L52:
  movb   $0x0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: %2x

assistant: ```c
char *pdecode(char *str) {
  char *s;
  int slen = strlen(str);
  char *result = malloc((slen + 1) * sizeof(char));
  char *r = result;
  for (s = str; *s != '\0'; s++, r++) {
    if (*s == '%' && s + 1 != '\0' && s + 2 != '\0') {
      int c;
      sscanf(s + 1, "%2x", &c);
      s += 2;
      *r = (char)c;
    } else
      *r = *s;
  }
  *r = '\0';
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pdecode>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %dl,%dl
  je     L35
  lea    D6(%rip),%r13
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %dl,0x0(%rbp)
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rcx
  add    $0x1,%rbp
  test   %dl,%dl
  je     L35
L56:
  mov    %rcx,%rbx
L59:
  cmp    $0x25,%dl
  jne    L0
  lea    0x4(%rsp),%rdx
  lea    0x1(%rbx),%rdi
  mov    %r13,%rsi
  xor    %eax,%eax
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  movzbl 0x3(%rbx),%edx
  lea    0x3(%rbx),%rcx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  test   %dl,%dl
  jne    L56
  nopl   (%rax)
L35:
  movb   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string

tool: D6: %2x

assistant: ```c
char *pdecode(char *str) {
  char *s;
  int slen = strlen(str);
  char *result = malloc((slen + 1) * sizeof(char));
  char *r = result;
  for (s = str; *s != '\0'; s++, r++) {
    if (*s == '%' && s + 1 != '\0' && s + 2 != '\0') {
      int c;
      sscanf(s + 1, "%2x", &c);
      s += 2;
      *r = (char)c;
    } else
      *r = *s;
  }
  *r = '\0';
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BSP_Microphone_Init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <adcinit@plt>
  mov    $0x400fe608,%eax
  mov    (%rax),%eax
  mov    $0x400fe608,%edx
  or     $0x10,%eax
  mov    %eax,(%rdx)
  nop
L8:
  mov    $0x400fea08,%eax
  mov    (%rax),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L8
  mov    $0x40024528,%eax
  mov    (%rax),%eax
  mov    $0x40024528,%edx
  or     $0x20,%eax
  mov    %eax,(%rdx)
  mov    $0x40024400,%eax
  mov    (%rax),%eax
  mov    $0x40024400,%edx
  and    $0xffffffdf,%eax
  mov    %eax,(%rdx)
  mov    $0x40024420,%eax
  mov    (%rax),%eax
  mov    $0x40024420,%edx
  or     $0x20,%eax
  mov    %eax,(%rdx)
  mov    $0x4002451c,%eax
  mov    (%rax),%eax
  mov    $0x4002451c,%edx
  and    $0xffffffdf,%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  call   <adcinit@plt>
  mov    $0x40038000,%eax
  mov    (%rax),%eax
  mov    $0x40038000,%edx
  and    $0xfffffff7,%eax
  mov    %eax,(%rdx)
  mov    $0x40038014,%eax
  mov    (%rax),%eax
  mov    $0x40038014,%edx
  and    $0xf,%ah
  mov    %eax,(%rdx)
  mov    $0x400380a0,%eax
  movl   $0x8,(%rax)
  mov    $0x400380a4,%eax
  movl   $0x6,(%rax)
  mov    $0x40038008,%eax
  mov    (%rax),%eax
  mov    $0x40038008,%edx
  and    $0xfffffff7,%eax
  mov    %eax,(%rdx)
  mov    $0x40038000,%eax
  mov    (%rax),%eax
  mov    $0x40038000,%edx
  or     $0x8,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BSP_Microphone_Init(void) {
  adcinit();
  (*((volatile uint32_t *)0x400FE608)) |= 0x00000010;
  while (((*((volatile uint32_t *)0x400FEA08)) & 0x10) == 0) {
  };
  (*((volatile uint32_t *)0x40024528)) |= 0x20;
  (*((volatile uint32_t *)0x40024400)) &= ~0x20;
  (*((volatile uint32_t *)0x40024420)) |= 0x20;
  (*((volatile uint32_t *)0x4002451C)) &= ~0x20;
  adcinit();
  (*((volatile uint32_t *)0x40038000)) &= ~0x0008;
  (*((volatile uint32_t *)0x40038014)) &= ~0xF000;
  (*((volatile uint32_t *)0x400380A0)) = 0x0008;
  (*((volatile uint32_t *)0x400380A4)) = 0x0006;
  (*((volatile uint32_t *)0x40038008)) &= ~0x0008;
  (*((volatile uint32_t *)0x40038000)) |= 0x0008;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BSP_Microphone_Init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <adcinit@plt>
  mov    0x400fe608,%eax
  or     $0x10,%eax
  mov    %eax,0x400fe608
L9:
  mov    0x400fea08,%eax
  test   $0x10,%al
  je     L9
  mov    0x40024528,%eax
  or     $0x20,%eax
  mov    %eax,0x40024528
  mov    0x40024400,%eax
  and    $0xffffffdf,%eax
  mov    %eax,0x40024400
  mov    0x40024420,%eax
  or     $0x20,%eax
  mov    %eax,0x40024420
  mov    0x4002451c,%eax
  and    $0xffffffdf,%eax
  mov    %eax,0x4002451c
  mov    $0x0,%eax
  call   <adcinit@plt>
  mov    0x40038000,%eax
  and    $0xfffffff7,%eax
  mov    %eax,0x40038000
  mov    0x40038014,%eax
  and    $0xf,%ah
  mov    %eax,0x40038014
  movl   $0x8,0x400380a0
  movl   $0x6,0x400380a4
  mov    0x40038008,%eax
  and    $0xfffffff7,%eax
  mov    %eax,0x40038008
  mov    0x40038000,%eax
  or     $0x8,%eax
  mov    %eax,0x40038000
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BSP_Microphone_Init(void) {
  adcinit();
  (*((volatile uint32_t *)0x400FE608)) |= 0x00000010;
  while (((*((volatile uint32_t *)0x400FEA08)) & 0x10) == 0) {
  };
  (*((volatile uint32_t *)0x40024528)) |= 0x20;
  (*((volatile uint32_t *)0x40024400)) &= ~0x20;
  (*((volatile uint32_t *)0x40024420)) |= 0x20;
  (*((volatile uint32_t *)0x4002451C)) &= ~0x20;
  adcinit();
  (*((volatile uint32_t *)0x40038000)) &= ~0x0008;
  (*((volatile uint32_t *)0x40038014)) &= ~0xF000;
  (*((volatile uint32_t *)0x400380A0)) = 0x0008;
  (*((volatile uint32_t *)0x400380A4)) = 0x0006;
  (*((volatile uint32_t *)0x40038008)) &= ~0x0008;
  (*((volatile uint32_t *)0x40038000)) |= 0x0008;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BSP_Microphone_Init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <adcinit@plt>
  mov    0x400fe608,%eax
  or     $0x10,%eax
  mov    %eax,0x400fe608
L5:
  mov    0x400fea08,%eax
  test   $0x10,%al
  je     L5
  mov    0x40024528,%eax
  or     $0x20,%eax
  mov    %eax,0x40024528
  mov    0x40024400,%eax
  and    $0xffffffdf,%eax
  mov    %eax,0x40024400
  mov    0x40024420,%eax
  or     $0x20,%eax
  mov    %eax,0x40024420
  mov    0x4002451c,%eax
  and    $0xffffffdf,%eax
  mov    %eax,0x4002451c
  xor    %eax,%eax
  call   <adcinit@plt>
  mov    0x40038000,%eax
  and    $0xfffffff7,%eax
  mov    %eax,0x40038000
  mov    0x40038014,%eax
  and    $0xf,%ah
  mov    %eax,0x40038014
  movl   $0x8,0x400380a0
  movl   $0x6,0x400380a4
  mov    0x40038008,%eax
  and    $0xfffffff7,%eax
  mov    %eax,0x40038008
  mov    0x40038000,%eax
  or     $0x8,%eax
  mov    %eax,0x40038000
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BSP_Microphone_Init(void) {
  adcinit();
  (*((volatile uint32_t *)0x400FE608)) |= 0x00000010;
  while (((*((volatile uint32_t *)0x400FEA08)) & 0x10) == 0) {
  };
  (*((volatile uint32_t *)0x40024528)) |= 0x20;
  (*((volatile uint32_t *)0x40024400)) &= ~0x20;
  (*((volatile uint32_t *)0x40024420)) |= 0x20;
  (*((volatile uint32_t *)0x4002451C)) &= ~0x20;
  adcinit();
  (*((volatile uint32_t *)0x40038000)) &= ~0x0008;
  (*((volatile uint32_t *)0x40038014)) &= ~0xF000;
  (*((volatile uint32_t *)0x400380A0)) = 0x0008;
  (*((volatile uint32_t *)0x400380A4)) = 0x0006;
  (*((volatile uint32_t *)0x40038008)) &= ~0x0008;
  (*((volatile uint32_t *)0x40038000)) |= 0x0008;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BSP_Microphone_Init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <adcinit@plt>
  mov    0x400fe608,%eax
  or     $0x10,%eax
  mov    %eax,0x400fe608
L6:
  mov    0x400fea08,%eax
  test   $0x10,%al
  je     L6
  mov    0x40024528,%eax
  or     $0x20,%eax
  mov    %eax,0x40024528
  mov    0x40024400,%eax
  and    $0xffffffdf,%eax
  mov    %eax,0x40024400
  mov    0x40024420,%eax
  or     $0x20,%eax
  mov    %eax,0x40024420
  mov    0x4002451c,%eax
  and    $0xffffffdf,%eax
  mov    %eax,0x4002451c
  xor    %eax,%eax
  call   <adcinit@plt>
  mov    0x40038000,%eax
  and    $0xfffffff7,%eax
  mov    %eax,0x40038000
  mov    0x40038014,%eax
  and    $0xf,%ah
  mov    %eax,0x40038014
  movl   $0x8,0x400380a0
  movl   $0x6,0x400380a4
  mov    0x40038008,%eax
  and    $0xfffffff7,%eax
  mov    %eax,0x40038008
  mov    0x40038000,%eax
  or     $0x8,%eax
  mov    %eax,0x40038000
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BSP_Microphone_Init(void) {
  adcinit();
  (*((volatile uint32_t *)0x400FE608)) |= 0x00000010;
  while (((*((volatile uint32_t *)0x400FEA08)) & 0x10) == 0) {
  };
  (*((volatile uint32_t *)0x40024528)) |= 0x20;
  (*((volatile uint32_t *)0x40024400)) &= ~0x20;
  (*((volatile uint32_t *)0x40024420)) |= 0x20;
  (*((volatile uint32_t *)0x4002451C)) &= ~0x20;
  adcinit();
  (*((volatile uint32_t *)0x40038000)) &= ~0x0008;
  (*((volatile uint32_t *)0x40038014)) &= ~0xF000;
  (*((volatile uint32_t *)0x400380A0)) = 0x0008;
  (*((volatile uint32_t *)0x400380A4)) = 0x0006;
  (*((volatile uint32_t *)0x40038008)) &= ~0x0008;
  (*((volatile uint32_t *)0x40038000)) |= 0x0008;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  js     L24
  mov    -0x10(%rbp),%eax
  cmp    $0x64,%eax
  jle    L11
L24:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L113
L11:
  mov    -0x10(%rbp),%eax
  cmp    $0x5a,%eax
  jle    L118
  movl   $0xa,-0xc(%rbp)
  jmp    L96
L118:
  mov    -0x10(%rbp),%eax
  cmp    $0x50,%eax
  jle    L18
  movl   $0x9,-0xc(%rbp)
  jmp    L96
L18:
  mov    -0x10(%rbp),%eax
  cmp    $0x46,%eax
  jle    L32
  movl   $0x8,-0xc(%rbp)
  jmp    L96
L32:
  mov    -0x10(%rbp),%eax
  cmp    $0x3c,%eax
  jle    L5
  movl   $0x7,-0xc(%rbp)
  jmp    L96
L5:
  mov    -0x10(%rbp),%eax
  cmp    $0x32,%eax
  jle    L17
  movl   $0x6,-0xc(%rbp)
  jmp    L96
L17:
  movl   $0x5,-0xc(%rbp)
L96:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L113:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
type: string
name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D29
type: string

tool: D14: Enter points: 

tool: D12: %d

tool: D22: Invalid value for points!

tool: D29: Grade %d


assistant: ```c
int main() {
  int points, grade = 0;
  printf("Enter points: \n");
  scanf("%d", &points);
  if (points < 0 || points > 100)
    printf("Invalid value for points!\n");
  else {
    if (points > 90)
      grade = 10;
    else if (points > 80)
      grade = 9;
    else if (points > 70)
      grade = 8;
    else if (points > 60)
      grade = 7;
    else if (points > 50)
      grade = 6;
    else
      grade = 5;
    printf("Grade %d\n", grade);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  ja     L25
  mov    $0xa,%esi
  cmp    $0x5a,%eax
  jg     L57
  mov    $0x9,%esi
  cmp    $0x50,%eax
  jg     L57
  mov    $0x8,%esi
  cmp    $0x46,%eax
  jg     L57
  mov    $0x7,%esi
  cmp    $0x3c,%eax
  jg     L57
  cmp    $0x32,%eax
  setg   %sil
  movzbl %sil,%esi
  add    $0x5,%esi
L57:
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L52:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L25:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L52
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string
name: disassemble_data
arguments: data_tag: D11
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: string
name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D9: Enter points: 

tool: D11: %d

tool: D1: Grade %d


tool: D2: Invalid value for points!

assistant: ```c
int main() {
  int points, grade = 0;
  printf("Enter points: \n");
  scanf("%d", &points);
  if (points < 0 || points > 100)
    printf("Invalid value for points!\n");
  else {
    if (points > 90)
      grade = 10;
    else if (points > 80)
      grade = 9;
    else if (points > 70)
      grade = 8;
    else if (points > 60)
      grade = 7;
    else if (points > 50)
      grade = 6;
    else
      grade = 5;
    printf("Grade %d\n", grade);
  }
  return 0;
}
```