ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<prewarp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    D9(%rip),%rax
  movss  %xmm1,0xc(%rsp)
  mulss  (%rax),%xmm0
  divss  %xmm1,%xmm0
  call   <tan@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rbx),%xmm2
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  movss  0x4(%rbx),%xmm1
  cvtsd2ss %xmm0,%xmm0
  divss  %xmm0,%xmm1
  mulss  %xmm0,%xmm0
  divss  %xmm0,%xmm2
  unpcklps %xmm2,%xmm1
  movlps %xmm1,0x4(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void prewarp(float *a, float fc, float fs) {
  float wp;
  wp = 2.0 * fs * tan(M_PI * fc / fs);
  a[2] = a[2] / (wp * wp);
  a[1] = a[1] / wp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sdtools_logN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <sdtools_isinepsilon@plt>
  test   %rax,%rax
  jne    L47
  movsd  D72(%rip),%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L31
  movsd  D72(%rip),%xmm0
  comisd -0x30(%rbp),%xmm0
  jbe    L31
L47:
  pxor   %xmm0,%xmm0
  jmp    L30
L31:
  jmp    L116
L35:
  movsd  -0x10(%rbp),%xmm0
  movsd  D72(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
L116:
  movsd  D72(%rip),%xmm0
  comisd -0x28(%rbp),%xmm0
  ja     L35
  jmp    L100
L38:
  movsd  -0x10(%rbp),%xmm1
  movsd  D72(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  divsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
L100:
  movsd  -0x28(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jae    L38
  movsd  D35(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  jmp    L110
L37:
  movsd  -0x28(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jb     L57
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  divsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
L57:
  movsd  -0x8(%rbp),%xmm1
  movsd  D35(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  addl   $0x1,-0x14(%rbp)
L110:
  cmpl   $0xfe,-0x14(%rbp)
  jg     L63
  movsd  -0x8(%rbp),%xmm0
  comisd D62(%rip),%xmm0
  ja     L37
L63:
  movsd  -0x10(%rbp),%xmm0
L30:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D72
datatype: f64
name: retrieve_data
arguments: data_tag: D35
datatype: f64
name: retrieve_data
arguments: data_tag: D62
datatype: f64

tool: D72: 1

tool: D35: 0.5

tool: D62: 1e-12

assistant: ```c
double sdtools_logN(double x, double base) {
  double result = 0.0;
  double term;
  int n = 0;
  if (sdtools_isinepsilon(x) || (x < 1.0 && base < 1.0))
    return 0.0;
  while (x < 1.0) {
    result -= 1.0;
    x *= base;
  }
  while (x >= base) {
    result += 1.0;
    x /= base;
  }
  term = 0.5;
  x *= x;
  while (n < 255 && term > 0.000000000001) {
    if (x >= base) {
      result += term;
      x = x / base;
    }
    term *= 0.5;
    x *= x;
    n++;
  }
  return (result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sdtools_logN>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <sdtools_isinepsilon@plt>
  pxor   %xmm2,%xmm2
  test   %rax,%rax
  jne    L114
  movsd  D8(%rip),%xmm0
  movsd  0x8(%rsp),%xmm3
  comisd %xmm3,%xmm0
  ja     L52
  pxor   %xmm2,%xmm2
  jbe    L108
L115:
  movsd  D8(%rip),%xmm0
L0:
  subsd  %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm6
  mulsd  (%rsp),%xmm6
  movsd  %xmm6,0x8(%rsp)
  comisd %xmm6,%xmm0
  ja     L0
L108:
  movsd  D8(%rip),%xmm0
  movsd  0x8(%rsp),%xmm3
  comisd (%rsp),%xmm3
  jb     L54
L76:
  addsd  %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm7
  movsd  (%rsp),%xmm4
  divsd  %xmm4,%xmm7
  movsd  %xmm7,0x8(%rsp)
  comisd %xmm4,%xmm7
  jae    L76
L54:
  movsd  0x8(%rsp),%xmm0
  mulsd  %xmm0,%xmm0
  mov    $0xff,%eax
  movsd  D46(%rip),%xmm1
  movapd %xmm1,%xmm3
  movsd  D7(%rip),%xmm4
  jmp    L8
L52:
  movsd  D8(%rip),%xmm0
  pxor   %xmm2,%xmm2
  comisd (%rsp),%xmm0
  ja     L114
  pxor   %xmm2,%xmm2
  jmp    L115
L107:
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm0
  sub    $0x1,%eax
  je     L114
  comisd %xmm4,%xmm1
  jbe    L114
L8:
  movsd  (%rsp),%xmm5
  comisd %xmm5,%xmm0
  jb     L107
  addsd  %xmm1,%xmm2
  divsd  %xmm5,%xmm0
  jmp    L107
L114:
  movapd %xmm2,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: f64
name: unpack_data
arguments: label: D46
type_guessed: f64
name: unpack_data
arguments: label: D7
type_guessed: f64

tool: D8: 1

tool: D46: 0.5

tool: D7: 1e-12

assistant: ```c
double sdtools_logN(double x, double base) {
  double result = 0.0;
  double term;
  int n = 0;
  if (sdtools_isinepsilon(x) || (x < 1.0 && base < 1.0))
    return 0.0;
  while (x < 1.0) {
    result -= 1.0;
    x *= base;
  }
  while (x >= base) {
    result += 1.0;
    x /= base;
  }
  term = 0.5;
  x *= x;
  while (n < 255 && term > 0.000000000001) {
    if (x >= base) {
      result += term;
      x = x / base;
    }
    term *= 0.5;
    x *= x;
    n++;
  }
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sdtools_logN>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <sdtools_isinepsilon@plt>
  pxor   %xmm3,%xmm3
  test   %rax,%rax
  jne    L71
  movsd  (%rsp),%xmm0
  movsd  D0(%rip),%xmm2
  pxor   %xmm3,%xmm3
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm2
  jbe    L76
  comisd %xmm1,%xmm2
  ja     L71
  nopl   0x0(%rax,%rax,1)
L92:
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm3
  comisd %xmm0,%xmm2
  jbe    L76
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm3
  comisd %xmm0,%xmm2
  ja     L92
  jmp    L76
  xchg   %ax,%ax
L46:
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm3
L76:
  comisd %xmm1,%xmm0
  jae    L46
  mulsd  %xmm0,%xmm0
  movsd  D14(%rip),%xmm4
  mov    $0xff,%eax
  movsd  D7(%rip),%xmm5
  movapd %xmm4,%xmm2
  nopl   0x0(%rax,%rax,1)
L28:
  comisd %xmm1,%xmm0
  jb     L12
  addsd  %xmm2,%xmm3
  divsd  %xmm1,%xmm0
L12:
  mulsd  %xmm4,%xmm2
  mulsd  %xmm0,%xmm0
  sub    $0x1,%eax
  je     L71
  comisd %xmm5,%xmm2
  ja     L28
L71:
  movapd %xmm3,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: f64
name: retrieve_data
arguments: data_label: D14
data_type: f64
name: retrieve_data
arguments: data_label: D7
data_type: f64

tool: D0: 1

tool: D14: 0.5

tool: D7: 1e-12

assistant: ```c
double sdtools_logN(double x, double base) {
  double result = 0.0;
  double term;
  int n = 0;
  if (sdtools_isinepsilon(x) || (x < 1.0 && base < 1.0))
    return 0.0;
  while (x < 1.0) {
    result -= 1.0;
    x *= base;
  }
  while (x >= base) {
    result += 1.0;
    x /= base;
  }
  term = 0.5;
  x *= x;
  while (n < 255 && term > 0.000000000001) {
    if (x >= base) {
      result += term;
      x = x / base;
    }
    term *= 0.5;
    x *= x;
    n++;
  }
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sdtools_logN>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <sdtools_isinepsilon@plt>
  pxor   %xmm3,%xmm3
  test   %rax,%rax
  jne    L14
  movsd  (%rsp),%xmm0
  movsd  D4(%rip),%xmm2
  pxor   %xmm3,%xmm3
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm2
  jbe    L89
  comisd %xmm1,%xmm2
  ja     L14
  nopl   0x0(%rax,%rax,1)
L8:
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm3
  comisd %xmm0,%xmm2
  jbe    L89
  mulsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm3
  comisd %xmm0,%xmm2
  ja     L8
  jmp    L89
  xchg   %ax,%ax
L78:
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm3
L89:
  comisd %xmm1,%xmm0
  jae    L78
  mulsd  %xmm0,%xmm0
  movsd  D1(%rip),%xmm4
  mov    $0xff,%eax
  movsd  D16(%rip),%xmm5
  movapd %xmm4,%xmm2
  nopl   0x0(%rax,%rax,1)
L42:
  comisd %xmm1,%xmm0
  jb     L62
  addsd  %xmm2,%xmm3
  divsd  %xmm1,%xmm0
L62:
  mulsd  %xmm4,%xmm2
  mulsd  %xmm0,%xmm0
  sub    $0x1,%eax
  je     L14
  comisd %xmm5,%xmm2
  ja     L42
L14:
  movapd %xmm3,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: f64
name: retrieve_data
arguments: label: D1
data_type: f64
name: retrieve_data
arguments: label: D16
data_type: f64

tool: D4: 1

tool: D1: 0.5

tool: D16: 1e-12

assistant: ```c
double sdtools_logN(double x, double base) {
  double result = 0.0;
  double term;
  int n = 0;
  if (sdtools_isinepsilon(x) || (x < 1.0 && base < 1.0))
    return 0.0;
  while (x < 1.0) {
    result -= 1.0;
    x *= base;
  }
  while (x >= base) {
    result += 1.0;
    x /= base;
  }
  term = 0.5;
  x *= x;
  while (n < 255 && term > 0.000000000001) {
    if (x >= base) {
      result += term;
      x = x / base;
    }
    term *= 0.5;
    x *= x;
    n++;
  }
  return (result);
}
```
user: What is the c source code of the assembly code below?

```asm
<string__NativeString___91d_93d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x2(%rbp),%eax
  mov    %al,-0x1(%rbp)
  nop
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char string__NativeString___91d_93d(char *self, long p0) {
  char var;
  char var1;
  var1 = self[p0];
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string__NativeString___91d_93d>:
  endbr64
  movzbl (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
char string__NativeString___91d_93d(char *self, long p0) {
  char var;
  char var1;
  var1 = self[p0];
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string__NativeString___91d_93d>:
  endbr64
  movzbl (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
char string__NativeString___91d_93d(char *self, long p0) {
  char var;
  char var1;
  var1 = self[p0];
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string__NativeString___91d_93d>:
  endbr64
  movzbl (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
char string__NativeString___91d_93d(char *self, long p0) {
  char var;
  char var1;
  var1 = self[p0];
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<NearestPowerOfTwo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L14
L7:
  shll   -0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int NearestPowerOfTwo(int val) {
  int answer;
  for (answer = 1; answer < val; answer <<= 1)
    ;
  return answer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<NearestPowerOfTwo>:
  endbr64
  cmp    $0x1,%edi
  jle    L9
  mov    $0x1,%eax
L16:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L16
  ret
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int NearestPowerOfTwo(int val) {
  int answer;
  for (answer = 1; answer < val; answer <<= 1)
    ;
  return answer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<NearestPowerOfTwo>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L10
  xchg   %ax,%ax
L17:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L17
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
int NearestPowerOfTwo(int val) {
  int answer;
  for (answer = 1; answer < val; answer <<= 1)
    ;
  return answer;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<NearestPowerOfTwo>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L10
  xchg   %ax,%ax
L9:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L9
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
int NearestPowerOfTwo(int val) {
  int answer;
  for (answer = 1; answer < val; answer <<= 1)
    ;
  return answer;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverseinplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L5
L17:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  sub    $0x1,%edx
  sub    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x1c(%rbp)
  jl     L17
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **reverseinplace(char **str, int i) {
  int sz;
  char *c;
  c = *str;
  sz = strlen(c);
  for (i = 0; i < sz / 2; ++i) {
    c[sz] = c[i];
    c[i] = c[sz - 1 - i];
    c[sz - 1 - i] = c[sz];
  }
  c[sz] = 0;
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverseinplace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L6
  movslq %eax,%rsi
  lea    -0x1(%rbx,%rsi,1),%rcx
  mov    $0x0,%edx
  add    %rbx,%rsi
L4:
  movzbl (%rbx,%rdx,1),%edi
  mov    %dil,(%rsi)
  movzbl (%rcx),%edi
  mov    %dil,(%rbx,%rdx,1)
  movzbl (%rsi),%edi
  mov    %dil,(%rcx)
  add    $0x1,%rdx
  sub    $0x1,%rcx
  cmp    %edx,%r8d
  jg     L4
L6:
  cltq
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char **reverseinplace(char **str, int i) {
  int sz;
  char *c;
  c = *str;
  sz = strlen(c);
  for (i = 0; i < sz / 2; ++i) {
    c[sz] = c[i];
    c[i] = c[sz - 1 - i];
    c[sz - 1 - i] = c[sz];
  }
  c[sz] = 0;
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverseinplace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L18
  movslq %eax,%rcx
  sub    $0x1,%eax
  xor    %edx,%edx
  cltq
  add    %rbx,%rcx
  add    %rbx,%rax
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl (%rbx,%rdx,1),%esi
  sub    $0x1,%rax
  mov    %sil,(%rcx)
  movzbl 0x1(%rax),%esi
  mov    %sil,(%rbx,%rdx,1)
  movzbl (%rcx),%esi
  add    $0x1,%rdx
  mov    %sil,0x1(%rax)
  cmp    %edx,%edi
  jg     L5
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L18:
  cltq
  lea    (%rbx,%rax,1),%rcx
  mov    %r12,%rax
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char **reverseinplace(char **str, int i) {
  int sz;
  char *c;
  c = *str;
  sz = strlen(c);
  for (i = 0; i < sz / 2; ++i) {
    c[sz] = c[i];
    c[i] = c[sz - 1 - i];
    c[sz - 1 - i] = c[sz];
  }
  c[sz] = 0;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverseinplace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L13
  movslq %eax,%rcx
  sub    $0x1,%eax
  xor    %edx,%edx
  cltq
  add    %rbx,%rcx
  add    %rbx,%rax
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl (%rbx,%rdx,1),%esi
  sub    $0x1,%rax
  mov    %sil,(%rcx)
  movzbl 0x1(%rax),%esi
  mov    %sil,(%rbx,%rdx,1)
  movzbl (%rcx),%esi
  add    $0x1,%rdx
  mov    %sil,0x1(%rax)
  cmp    %edx,%edi
  jg     L5
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L13:
  cltq
  lea    (%rbx,%rax,1),%rcx
  mov    %r12,%rax
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char **reverseinplace(char **str, int i) {
  int sz;
  char *c;
  c = *str;
  sz = strlen(c);
  for (i = 0; i < sz / 2; ++i) {
    c[sz] = c[i];
    c[i] = c[sz - 1 - i];
    c[sz - 1 - i] = c[sz];
  }
  c[sz] = 0;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get_dec@plt>
  jmp    L19
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_space@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get_hex@plt>
L19:
  leave
  ret
```

assistant: ```c
long get_num(const char **s) {
  if ((**s) != '$')
    return get_dec(s);
  (*s)++;
  skip_space(s);
  return get_hex(s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_num>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  cmpb   $0x24,(%rax)
  je     L11
  call   <get_dec@plt>
L12:
  pop    %rbx
  ret
L11:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  call   <skip_space@plt>
  mov    %rbx,%rdi
  call   <get_hex@plt>
  jmp    L12
```

assistant: ```c
long get_num(const char **s) {
  if ((**s) != '$')
    return get_dec(s);
  (*s)++;
  skip_space(s);
  return get_hex(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_num>:
  endbr64
  push   %rbp
  mov    (%rdi),%rax
  mov    %rdi,%rbp
  cmpb   $0x24,(%rax)
  je     L8
  pop    %rbp
  jmp    1070 <get_dec@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  call   <skip_space@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <get_hex@plt>
```

assistant: ```c
long get_num(const char **s) {
  if ((**s) != '$')
    return get_dec(s);
  (*s)++;
  skip_space(s);
  return get_hex(s);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_num>:
  endbr64
  push   %rbp
  mov    (%rdi),%rax
  mov    %rdi,%rbp
  cmpb   $0x24,(%rax)
  je     L8
  pop    %rbp
  jmp    1070 <get_dec@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  call   <skip_space@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <get_hex@plt>
```

assistant: ```c
long get_num(const char **s) {
  if ((**s) != '$')
    return get_dec(s);
  (*s)++;
  skip_space(s);
  return get_hex(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  sub    %eax,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L47:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L40
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L40
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L41
L40:
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L47
  mov    $0x0,%eax
L41:
  leave
  ret
```

assistant: ```c
char *find_str(const char *haystack, int hsize, const char *needle) {
  int i = 0;
  int nsize = strlen(needle);
  hsize -= nsize - 1;
  for (i = 0; i < hsize; i++) {
    if (haystack[i] == needle[0] && strncmp(haystack + i, needle, nsize) == 0) {
      return (char *)(haystack + i);
    }
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    -0x1(%rax),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  test   %eax,%eax
  jle    L59
  mov    %r12,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%r13
  jmp    L30
L66:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L13
L30:
  mov    %rbx,%r12
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%rbx)
  jne    L66
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L66
  jmp    L14
L13:
  mov    $0x0,%r12d
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  mov    $0x0,%r12d
  jmp    L14
```

assistant: ```c
char *find_str(const char *haystack, int hsize, const char *needle) {
  int i = 0;
  int nsize = strlen(needle);
  hsize -= nsize - 1;
  for (i = 0; i < hsize; i++) {
    if (haystack[i] == needle[0] && strncmp(haystack + i, needle, nsize) == 0) {
      return (char *)(haystack + i);
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  mov    %eax,%r14d
  mov    %r12d,%eax
  sub    %edx,%eax
  test   %eax,%eax
  jle    L11
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r13
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L11
L2:
  movzbl 0x0(%rbp),%eax
  mov    %rbx,%r12
  cmp    %al,(%rbx)
  jne    L15
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L15
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *find_str(const char *haystack, int hsize, const char *needle) {
  int i = 0;
  int nsize = strlen(needle);
  hsize -= nsize - 1;
  for (i = 0; i < hsize; i++) {
    if (haystack[i] == needle[0] && strncmp(haystack + i, needle, nsize) == 0) {
      return (char *)(haystack + i);
    }
  }
  return NULL;
}
```