user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D56(%rip),%rax
  mov    %rax,%rsi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L44
  lea    D75(%rip),%rax
  mov    %rax,%rsi
  lea    D104(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L44:
  lea    D75(%rip),%rax
  mov    %rax,%rsi
  lea    D115(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D79(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L40
L25:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    D79(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  addl   $0x1,-0x2c(%rbp)
L40:
  mov    -0x30(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L25
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x30(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArrows@plt>
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <equalizza@plt>
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <equalizza@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <din@plt>
  mov    -0x30(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArrows@plt>
  mov    -0x30(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getCosto@plt>
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x50,-0x2c(%rbp)
  jmp    L55
L12:
  mov    $0x2d,%edi
  call   <putchar@plt>
L55:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jg     L12
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <equalizza@plt>
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <equalizza@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x30(%rbp),%esi
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <comb@plt>
  mov    -0x30(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArrows@plt>
  mov    -0x30(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getCosto@plt>
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D56
data_type: string
name: retrieve_data
arguments: tag: D75
data_type: string
name: retrieve_data
arguments: tag: D104
data_type: string
name: retrieve_data
arguments: tag: D115
data_type: string
name: retrieve_data
arguments: tag: D79
data_type: string
name: retrieve_data
arguments: tag: D51
data_type: string
name: retrieve_data
arguments: tag: D49
data_type: string
name: retrieve_data
arguments: tag: D31
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string

tool: D56: r

tool: D75: frecce2.txt

tool: D104: Errore! Impossibile aprire il file "%s"


tool: D115: Sto usando il file "%s"...


tool: D79: %d

tool: D51: Ho trovato %d frecce...


tool: D49: Metodo programmazione dinamica...

tool: D31: Costo: %d


tool: D9: Metodo calcolo combinatorio...

assistant: ```c
int main() {
  FILE *fp;
  int i, n;
  int *f, *sol, *bestSol;
  if ((fp = fopen("frecce2.txt", "r")) == NULL) {
    printf("Errore! Impossibile aprire il file \"%s\"\n", "frecce2.txt");
    exit(1);
  }
  printf("Sto usando il file \"%s\"...\n", "frecce2.txt");
  fscanf(fp, "%d", &n);
  printf("Ho trovato %d frecce...\n", n);
  f = (int *)malloc(n * sizeof(int));
  sol = (int *)calloc(n, sizeof(int));
  bestSol = (int *)calloc(n, sizeof(int));
  for (i = 0; i < n; i++) {
    fscanf(fp, "%d", &f[i]);
  }
  fclose(fp);
  printArrows(f, n);
  equalizza(sol, 0, n - 1);
  equalizza(bestSol, 0, n - 1);
  puts("Metodo programmazione dinamica...");
  din(f, 0, n - 1, 0, sol, bestSol);
  printArrows(bestSol, n);
  printf("Costo: %d\n", getCosto(f, bestSol, n));
  for (i = 80; i-- > 0; printf("-"))
    ;
  equalizza(sol, 0, n - 1);
  equalizza(bestSol, 0, n - 1);
  puts("Metodo calcolo combinatorio...");
  comb(f, n, 0, sol, bestSol);
  printArrows(bestSol, n);
  printf("Costo: %d\n", getCosto(f, bestSol, n));
  return 0;
}
```