ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<format_synerr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %rdi,-0x818(%rbp)
  mov    %rsi,-0x820(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x820(%rbp),%rdx
  mov    -0x818(%rbp),%rcx
  lea    -0x810(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <synerr@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void format_synerr(const char msg[], char arg[]) {
  char errmsg[2048];
  (void)sprintf(errmsg, msg, arg);
  synerr(errmsg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<format_synerr>:
  endbr64
  push   %rbx
  sub    $0x810,%rsp
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <synerr@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x810,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void format_synerr(const char msg[], char arg[]) {
  char errmsg[2048];
  (void)sprintf(errmsg, msg, arg);
  synerr(errmsg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<format_synerr>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <synerr@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x810,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void format_synerr(const char msg[], char arg[]) {
  char errmsg[2048];
  (void)sprintf(errmsg, msg, arg);
  synerr(errmsg);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<format_synerr>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <synerr@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x810,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void format_synerr(const char msg[], char arg[]) {
  char errmsg[2048];
  (void)sprintf(errmsg, msg, arg);
  synerr(errmsg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <datetime_stamp_now@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: timstamp (ms) for now is: %.3f ms


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("timstamp (ms) for now is: %.3f ms\n", datetime_stamp_now());
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <datetime_stamp_now@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: timstamp (ms) for now is: %.3f ms


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("timstamp (ms) for now is: %.3f ms\n", datetime_stamp_now());
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <datetime_stamp_now@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: timstamp (ms) for now is: %.3f ms


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("timstamp (ms) for now is: %.3f ms\n", datetime_stamp_now());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <datetime_stamp_now@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: timstamp (ms) for now is: %.3f ms


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("timstamp (ms) for now is: %.3f ms\n", datetime_stamp_now());
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<thread_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <make_blocks@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *thread_func(void *x_void_ptr) {
  make_blocks();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<thread_func>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <make_blocks@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_func(void *x_void_ptr) {
  make_blocks();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<thread_func>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <make_blocks@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_func(void *x_void_ptr) {
  make_blocks();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<thread_func>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <make_blocks@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_func(void *x_void_ptr) {
  make_blocks();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0xffffffff,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0xfffffff8,-0x24(%rbp)
  movl   $0x10,-0x20(%rbp)
  movl   $0xfffffff0,-0x1c(%rbp)
  movl   $0x64,-0x18(%rbp)
  movl   $0xffffff9c,-0x14(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L10
L45:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <sign_direct@plt>
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L10:
  cmpl   $0x7,-0x34(%rbp)
  jle    L45
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L42
L59:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <sign_bitwise@plt>
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L42:
  cmpl   $0x7,-0x34(%rbp)
  jle    L59
  movl   $0x1,-0x34(%rbp)
  jmp    L24
L4:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <opposite_sign_numbers@plt>
  mov    %eax,%ecx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L24:
  cmpl   $0x7,-0x34(%rbp)
  jle    L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string

tool: D4: direct:  sign of %d: %d


tool: D17: bitwise: sign of %d: %d


tool: D23: do %d and %d have opposite signs?: %d


assistant: ```c
int main() {
  int nums[8] = {1, -1, 8, -8, 16, -16, 100, -100};
  int i;
  for (i = 0; i < 8; i++) {
    printf("direct:  sign of %d: %d\n", nums[i], sign_direct(nums[i]));
  }
  printf("\n");
  for (i = 0; i < 8; i++) {
    printf("bitwise: sign of %d: %d\n", nums[i], sign_bitwise(nums[i]));
  }
  for (i = 1; i < 8; i++) {
    printf("do %d and %d have opposite signs?: %d\n", nums[0], nums[i], opposite_sign_numbers(nums[0], nums[i]));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0xfffffff8,0xc(%rsp)
  movl   $0x10,0x10(%rsp)
  movl   $0xfffffff0,0x14(%rsp)
  movl   $0x64,0x18(%rsp)
  movl   $0xffffff9c,0x1c(%rsp)
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  mov    %rbx,%rbp
  lea    D24(%rip),%r14
L10:
  mov    0x0(%rbp),%r13d
  mov    %r13d,%edi
  call   <sign_direct@plt>
  mov    %eax,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D5(%rip),%r13
L19:
  mov    (%rbx),%ebp
  mov    %ebp,%edi
  call   <sign_bitwise@plt>
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L19
  lea    0x4(%rsp),%rbx
  lea    D8(%rip),%r13
L24:
  mov    (%rbx),%ebp
  mov    %ebp,%esi
  mov    $0x1,%edi
  call   <opposite_sign_numbers@plt>
  mov    %eax,%ecx
  mov    %ebp,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L24
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D24
type: string
name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D8
type: string

tool: D24: direct:  sign of %d: %d


tool: D5: bitwise: sign of %d: %d


tool: D8: do %d and %d have opposite signs?: %d


assistant: ```c
int main() {
  int nums[8] = {1, -1, 8, -8, 16, -16, 100, -100};
  int i;
  for (i = 0; i < 8; i++) {
    printf("direct:  sign of %d: %d\n", nums[i], sign_direct(nums[i]));
  }
  printf("\n");
  for (i = 0; i < 8; i++) {
    printf("bitwise: sign of %d: %d\n", nums[i], sign_bitwise(nums[i]));
  }
  for (i = 1; i < 8; i++) {
    printf("do %d and %d have opposite signs?: %d\n", nums[0], nums[i], opposite_sign_numbers(nums[0], nums[i]));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x20(%rsp),%rbp
  movabs $0xfffffff800000008,%rax
  mov    %rax,0x8(%rsp)
  mov    %rbx,%r12
  movabs $0xfffffff000000010,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xffffff9c00000064,%rax
  movl   $0xffffffff,0x4(%rsp)
  mov    %rax,0x18(%rsp)
  jmp    L53
  nopl   0x0(%rax)
L5:
  mov    (%r12),%r14d
  add    $0x4,%r12
L53:
  mov    %r14d,%edi
  call   <sign_direct@plt>
  mov    %r14d,%esi
  mov    %r13,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L5
  mov    $0xa,%edi
  mov    $0x1,%r12d
  lea    D23(%rip),%r13
  call   <putchar@plt>
  jmp    L31
  nopl   (%rax)
L50:
  mov    (%rbx),%r12d
  add    $0x4,%rbx
L31:
  mov    %r12d,%edi
  call   <sign_bitwise@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L50
  lea    0x8(%rsp),%rbx
  mov    $0xffffffff,%r12d
  lea    D1(%rip),%r13
  jmp    L27
  nop
L57:
  mov    (%rbx),%r12d
  add    $0x4,%rbx
L27:
  mov    %r12d,%esi
  mov    $0x1,%edi
  call   <opposite_sign_numbers@plt>
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L57
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string
name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D7: direct:  sign of %d: %d


tool: D23: bitwise: sign of %d: %d


tool: D1: do %d and %d have opposite signs?: %d


assistant: ```c
int main() {
  int nums[8] = {1, -1, 8, -8, 16, -16, 100, -100};
  int i;
  for (i = 0; i < 8; i++) {
    printf("direct:  sign of %d: %d\n", nums[i], sign_direct(nums[i]));
  }
  printf("\n");
  for (i = 0; i < 8; i++) {
    printf("bitwise: sign of %d: %d\n", nums[i], sign_bitwise(nums[i]));
  }
  for (i = 1; i < 8; i++) {
    printf("do %d and %d have opposite signs?: %d\n", nums[0], nums[i], opposite_sign_numbers(nums[0], nums[i]));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D38(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D13(%rip),%xmm0
  mov    %rbx,%rbp
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L30:
  mov    0x0(%rbp),%r14d
  add    $0x4,%rbp
  mov    %r14d,%edi
  call   <sign_direct@plt>
  mov    %r14d,%esi
  mov    %r13,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L30
  mov    $0xa,%edi
  lea    D45(%rip),%r13
  call   <putchar@plt>
  nopl   (%rax)
L26:
  mov    (%rbx),%ebp
  add    $0x4,%rbx
  mov    %ebp,%edi
  call   <sign_bitwise@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L26
  lea    0x4(%rsp),%rbx
  lea    D10(%rip),%rbp
  nopl   0x0(%rax)
L25:
  mov    (%rbx),%r13d
  mov    $0x1,%edi
  add    $0x4,%rbx
  mov    %r13d,%esi
  call   <opposite_sign_numbers@plt>
  mov    %r13d,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L25
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D38
type_guessed: byte[16]
name: retrieve_data
arguments: label: D13
type_guessed: byte[16]
name: retrieve_data
arguments: label: D45
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string

tool: D15: direct:  sign of %d: %d


tool: {"D38": [0x01,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0x08,0x00,0x00,0x00,0xf8,0xff,0xff,0xff]}

tool: {"D13": [0x10,0x00,0x00,0x00,0xf0,0xff,0xff,0xff,0x64,0x00,0x00,0x00,0x9c,0xff,0xff,0xff]}

tool: D45: bitwise: sign of %d: %d


tool: D10: do %d and %d have opposite signs?: %d


assistant: ```c
int main() {
  int nums[8] = {1, -1, 8, -8, 16, -16, 100, -100};
  int i;
  for (i = 0; i < 8; i++) {
    printf("direct:  sign of %d: %d\n", nums[i], sign_direct(nums[i]));
  }
  printf("\n");
  for (i = 0; i < 8; i++) {
    printf("bitwise: sign of %d: %d\n", nums[i], sign_bitwise(nums[i]));
  }
  for (i = 1; i < 8; i++) {
    printf("do %d and %d have opposite signs?: %d\n", nums[0], nums[i], opposite_sign_numbers(nums[0], nums[i]));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compressColid>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    (%rdi),%eax
  mov    %eax,(%rdx)
  cmp    $0x1,%rsi
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    -0x1(%r13),%r9
  cmp    $0x1,%r9
  jbe    L10
  lea    0x4(%rbp),%rax
  lea    -0x4(%rbp,%r13,4),%r8
  mov    $0x0,%esi
  mov    $0x0,%edx
  jmp    L119
L117:
  add    $0x1,%esi
  jmp    L118
L5:
  add    $0x1,%rdx
  add    $0x1,%esi
  mov    %esi,(%rbx,%rdx,4)
L38:
  add    $0x1,%rdx
  mov    (%rdi),%ecx
  mov    %ecx,(%rbx,%rdx,4)
  mov    $0x0,%esi
L118:
  add    $0x4,%rax
  cmp    %rax,%r8
  je     L14
L119:
  mov    %rax,%rdi
  mov    -0x4(%rax),%ecx
  add    $0x1,%ecx
  cmp    %ecx,(%rax)
  je     L117
  test   %esi,%esi
  jne    L5
  orl    $0x80000000,(%rbx,%rdx,4)
  jmp    L38
L14:
  shl    $0x2,%r9
  lea    0x0(%rbp,%r9,1),%rcx
  mov    -0x4(%rbp,%r9,1),%eax
  add    $0x1,%eax
  cmp    %eax,(%rcx)
  je     L61
  test   %esi,%esi
  je     L77
  add    $0x1,%rdx
  add    $0x1,%esi
  mov    %esi,(%rbx,%rdx,4)
  jmp    L111
L61:
  add    $0x1,%rdx
  add    $0x2,%esi
  mov    %esi,(%rbx,%rdx,4)
  jmp    L71
L10:
  lea    0x4(%rbp),%rcx
  mov    0x0(%rbp),%eax
  add    $0x1,%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  cmp    %eax,0x4(%rbp)
  je     L61
L77:
  orl    $0x80000000,(%rbx,%rdx,4)
L111:
  add    $0x1,%rdx
  mov    (%rcx),%eax
  or     $0x80000000,%eax
  mov    %eax,(%rbx,%rdx,4)
L71:
  add    $0x1,%rdx
  mov    %rdx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void compressColid(const uint32_t *cols_reord, const uint64_t nnz, uint32_t *colid, uint64_t *here) {
  uint64_t xhere = 0;
  uint64_t j = 0;
  colid[xhere] = cols_reord[j++];
  uint32_t cons = 0;
  assert(nnz > 1);
  for (; j < nnz - 1; ++j) {
    if (cols_reord[j] == cols_reord[j - 1] + 1) {
      ++cons;
    } else {
      if (cons == 0) {
        colid[xhere] |= (1U << 31);
      } else {
        colid[++xhere] = cons + 1;
      }
      cons = 0;
      colid[++xhere] = cols_reord[j];
    }
  }
  if (cols_reord[j] != cols_reord[j - 1] + 1) {
    if (cons == 0) {
      colid[xhere] |= (1U << 31);
    } else {
      colid[++xhere] = cons + 1;
    }
    colid[++xhere] = cols_reord[j] | (1U << 31);
  } else {
    colid[++xhere] = cons + 2;
  }
  ++xhere;
  *here = xhere;
}
```
user: What is the c source code of the assembly code below?

```asm
<compressColid>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%eax
  xor    %edi,%edi
  cmp    $0x1,%rsi
  seta   %dil
  mov    %eax,(%rdx)
  call   <assert@plt>
  lea    -0x1(%r12),%r8
  cmp    $0x1,%r8
  jbe    L106
  lea    0x4(%rbp),%rax
  lea    -0x4(%rbp,%r12,4),%rdi
  xor    %esi,%esi
  xor    %ecx,%ecx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L96:
  test   %esi,%esi
  jne    L104
  orl    $0x80000000,(%rbx,%rcx,4)
L79:
  mov    (%rax),%edx
  add    $0x1,%rcx
  add    $0x4,%rax
  xor    %esi,%esi
  mov    %edx,(%rbx,%rcx,4)
  cmp    %rax,%rdi
  je     L63
L14:
  mov    -0x4(%rax),%edx
  add    $0x1,%edx
  cmp    %edx,(%rax)
  jne    L96
  add    $0x4,%rax
  add    $0x1,%esi
  cmp    %rax,%rdi
  jne    L14
L63:
  shl    $0x2,%r8
  lea    0x1(%rcx),%r10
  lea    0x2(%rcx),%r9
  mov    -0x4(%rbp,%r8,1),%eax
  lea    0x0(%rbp,%r8,1),%rdi
  lea    0x0(,%r10,4),%rdx
  add    $0x1,%eax
  cmp    %eax,(%rdi)
  je     L76
  lea    -0x4(%rbx,%rdx,1),%rax
  test   %esi,%esi
  je     L95
  add    $0x1,%esi
  add    $0x4,%rdx
  lea    0x3(%rcx),%r9
  mov    %esi,(%rbx,%r10,4)
L93:
  mov    (%rdi),%eax
  or     $0x80000000,%eax
  mov    %eax,(%rbx,%rdx,1)
  mov    %r9,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L104:
  add    $0x1,%rcx
  add    $0x1,%esi
  mov    %esi,(%rbx,%rcx,4)
  jmp    L79
  nop
L106:
  mov    0x0(%rbp),%eax
  lea    0x4(%rbp),%rdi
  add    $0x1,%eax
  cmp    %eax,0x4(%rbp)
  je     L20
  mov    %rbx,%rax
  mov    $0x2,%r9d
  mov    $0x4,%edx
L95:
  orl    $0x80000000,(%rax)
  jmp    L93
  nopl   (%rax)
L76:
  add    $0x2,%esi
L50:
  mov    %esi,(%rbx,%rdx,1)
  mov    %r9,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  mov    $0x2,%r9d
  mov    $0x2,%esi
  mov    $0x4,%edx
  jmp    L50
```

assistant: ```c
void compressColid(const uint32_t *cols_reord, const uint64_t nnz, uint32_t *colid, uint64_t *here) {
  uint64_t xhere = 0;
  uint64_t j = 0;
  colid[xhere] = cols_reord[j++];
  uint32_t cons = 0;
  assert(nnz > 1);
  for (; j < nnz - 1; ++j) {
    if (cols_reord[j] == cols_reord[j - 1] + 1) {
      ++cons;
    } else {
      if (cons == 0) {
        colid[xhere] |= (1U << 31);
      } else {
        colid[++xhere] = cons + 1;
      }
      cons = 0;
      colid[++xhere] = cols_reord[j];
    }
  }
  if (cols_reord[j] != cols_reord[j - 1] + 1) {
    if (cons == 0) {
      colid[xhere] |= (1U << 31);
    } else {
      colid[++xhere] = cons + 1;
    }
    colid[++xhere] = cols_reord[j] | (1U << 31);
  } else {
    colid[++xhere] = cons + 2;
  }
  ++xhere;
  *here = xhere;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compressColid>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%eax
  xor    %edi,%edi
  cmp    $0x1,%rsi
  seta   %dil
  mov    %eax,(%rdx)
  call   <assert@plt>
  lea    -0x1(%r12),%r8
  cmp    $0x1,%r8
  jbe    L86
  lea    0x4(%rbp),%rax
  lea    -0x4(%rbp,%r12,4),%rdi
  xor    %esi,%esi
  xor    %ecx,%ecx
  jmp    L89
  nopl   0x0(%rax,%rax,1)
L88:
  test   %esi,%esi
  jne    L58
  orl    $0x80000000,(%rbx,%rcx,4)
L96:
  mov    (%rax),%edx
  add    $0x1,%rcx
  add    $0x4,%rax
  xor    %esi,%esi
  mov    %edx,(%rbx,%rcx,4)
  cmp    %rax,%rdi
  je     L45
L89:
  mov    -0x4(%rax),%edx
  add    $0x1,%edx
  cmp    %edx,(%rax)
  jne    L88
  add    $0x4,%rax
  add    $0x1,%esi
  cmp    %rax,%rdi
  jne    L89
L45:
  shl    $0x2,%r8
  lea    0x1(%rcx),%r10
  lea    0x2(%rcx),%r9
  mov    -0x4(%rbp,%r8,1),%eax
  lea    0x0(%rbp,%r8,1),%rdi
  lea    0x0(,%r10,4),%rdx
  add    $0x1,%eax
  cmp    %eax,(%rdi)
  je     L97
  lea    -0x4(%rbx,%rdx,1),%rax
  test   %esi,%esi
  je     L17
  add    $0x1,%esi
  add    $0x4,%rdx
  lea    0x3(%rcx),%r9
  mov    %esi,(%rbx,%r10,4)
L48:
  mov    (%rdi),%eax
  or     $0x80000000,%eax
  mov    %eax,(%rbx,%rdx,1)
  mov    %r9,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L58:
  add    $0x1,%rcx
  add    $0x1,%esi
  mov    %esi,(%rbx,%rcx,4)
  jmp    L96
  nop
L86:
  mov    0x0(%rbp),%eax
  lea    0x4(%rbp),%rdi
  add    $0x1,%eax
  cmp    %eax,0x4(%rbp)
  je     L47
  mov    %rbx,%rax
  mov    $0x2,%r9d
  mov    $0x4,%edx
L17:
  orl    $0x80000000,(%rax)
  jmp    L48
  nopl   (%rax)
L97:
  add    $0x2,%esi
L118:
  mov    %esi,(%rbx,%rdx,1)
  mov    %r9,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  mov    $0x2,%r9d
  mov    $0x2,%esi
  mov    $0x4,%edx
  jmp    L118
```

assistant: ```c
void compressColid(const uint32_t *cols_reord, const uint64_t nnz, uint32_t *colid, uint64_t *here) {
  uint64_t xhere = 0;
  uint64_t j = 0;
  colid[xhere] = cols_reord[j++];
  uint32_t cons = 0;
  assert(nnz > 1);
  for (; j < nnz - 1; ++j) {
    if (cols_reord[j] == cols_reord[j - 1] + 1) {
      ++cons;
    } else {
      if (cons == 0) {
        colid[xhere] |= (1U << 31);
      } else {
        colid[++xhere] = cons + 1;
      }
      cons = 0;
      colid[++xhere] = cols_reord[j];
    }
  }
  if (cols_reord[j] != cols_reord[j - 1] + 1) {
    if (cons == 0) {
      colid[xhere] |= (1U << 31);
    } else {
      colid[++xhere] = cons + 1;
    }
    colid[++xhere] = cols_reord[j] | (1U << 31);
  } else {
    colid[++xhere] = cons + 2;
  }
  ++xhere;
  *here = xhere;
}
```