user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r15d
  mov    %eax,0x28(%rsp)
  cltq
  mov    %rax,0x40(%rsp)
  lea    0x0(,%r15,8),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,0x8(%rsp)
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,0x38(%rsp)
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %r15d,%r15d
  jle    L41
  mov    %rax,%r14
  lea    0x0(,%r15,4),%ebp
  lea    -0x1(%r15),%eax
  mov    %r13,%rdi
  lea    0x8(%r13,%rax,8),%r13
  mov    %rdi,%rbx
  sub    %rdi,%r12
L6:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%r12,%rbx,1)
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %r14,%rax
  sub    0x8(%rsp),%rax
  mov    %rdx,(%rax,%rbx,1)
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L6
  cmpq   $0x0,0x8(%rsp)
  sete   %al
  cmpq   $0x0,0x38(%rsp)
  sete   %dl
  or     %dl,%al
  jne    L38
  cmpq   $0x0,0x18(%rsp)
  je     L38
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  jmp    L155
L38:
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  cmpl   $0x0,0x28(%rsp)
  jle    L120
L155:
  mov    0x28(%rsp),%edi
  lea    -0x1(%rdi),%eax
  mov    %eax,0x2c(%rsp)
  mov    %eax,%eax
  mov    %rax,0x48(%rsp)
  mov    %edi,%eax
  mov    %rax,0x20(%rsp)
  mov    0x8(%rsp),%rax
  mov    %rax,0x10(%rsp)
  mov    $0x0,%r15d
  mov    0x38(%rsp),%rdi
  sub    %rax,%rdi
  mov    %rdi,0x30(%rsp)
  jmp    L132
L73:
  mov    0x10(%rsp),%rax
  mov    %rax,%r14
  mov    0x30(%rsp),%r13
  add    %rax,%r13
  mov    0x18(%rsp),%r12
  sub    0x8(%rsp),%r12
  add    %rax,%r12
  lea    0x0(,%r15,4),%rbx
  mov    0x2c(%rsp),%eax
  sub    %r15d,%eax
  lea    0x1(%r15,%rax,1),%rbp
  shl    $0x2,%rbp
L93:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    (%r14),%rcx
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,(%rcx,%rbx,1)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    0x0(%r13),%rcx
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,(%rcx,%rbx,1)
  mov    (%r12),%rax
  movl   $0x0,(%rax,%rbx,1)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L93
L14:
  add    $0x1,%r15
  addq   $0x8,0x10(%rsp)
  cmp    0x20(%rsp),%r15
  je     L127
L132:
  cmp    %r15d,0x28(%rsp)
  jg     L73
  jmp    L14
L127:
  mov    0x18(%rsp),%rax
  mov    0x48(%rsp),%rsi
  lea    0x8(%rax,%rsi,8),%r11
  mov    0x20(%rsp),%r10
  shl    $0x2,%r10
  mov    %rax,%rbx
  mov    0x8(%rsp),%rbp
  sub    %rax,%rbp
  mov    0x38(%rsp),%r12
  sub    %rax,%r12
L5:
  mov    %rbx,%r9
  lea    0x0(%rbp,%rbx,1),%r8
  lea    (%r12,%rbx,1),%rdi
  mov    $0x0,%eax
L147:
  mov    %rax,%rcx
  add    (%r9),%rcx
  mov    (%r8),%rdx
  mov    (%rdi),%rsi
  mov    (%rdx,%rax,1),%edx
  imul   (%rsi,%rax,1),%edx
  add    %edx,(%rcx)
  add    $0x4,%rax
  cmp    %rax,%r10
  jne    L147
  add    $0x8,%rbx
  cmp    %rbx,%r11
  jne    L5
L120:
  mov    0x18(%rsp),%rbx
  mov    (%rbx),%rax
  mov    (%rax),%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x40(%rsp),%rdi
  mov    -0x8(%rbx,%rdi,8),%rax
  mov    -0x4(%rax,%rdi,4),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  cmpq   $0x0,0x8(%rsp)
  sete   %al
  cmpq   $0x0,0x38(%rsp)
  sete   %dl
  or     %dl,%al
  jne    L38
  cmpq   $0x0,0x18(%rsp)
  je     L38
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  jmp    L120
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string
name: retrieve_data
arguments: label: D23
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string

tool: D9: 
Error en la reserva de memoria.

tool: D23: Valor (0,0): %d 


tool: D13: Valor (n-1,n-1): %d 


assistant: ```c
int main(int argc, char **argv) {
  int n, i, j, k;
  struct timespec cgt1, cgt2;
  double ncgt;
  n = atoi(argv[1]);
  int **m1, **m2, **m3;
  m1 = (int **)malloc(n * sizeof(int *));
  m2 = (int **)malloc(n * sizeof(int *));
  m3 = (int **)malloc(n * sizeof(int *));
  for (i = 0; i < n; i++) {
    m1[i] = (int *)malloc(n * sizeof(int));
    m2[i] = (int *)malloc(n * sizeof(int));
    m3[i] = (int *)malloc(n * sizeof(int));
  }
  if ((m1 == NULL) || (m2 == NULL) || (m3 == NULL)) {
    printf("\nError en la reserva de memoria.");
    exit(-1);
  }
  srand(time(NULL));
  for (i = 0; i < n; i++) {
    for (j = i; j < n; j++) {
      m1[i][j] = ((rand() % 4) + 1);
      m2[i][j] = ((rand() % 4) + 1);
      m3[i][j] = 0;
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++)
      m3[i][j] += m1[i][j] * m2[i][j];
  }
  printf("Valor (0,0): %d \n", m3[0][0]);
  printf("Valor (n-1,n-1): %d \n", m3[n - 1][n - 1]);
  printf("\n");
}
```