ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmd2args>:
  endbr64
  test   %esi,%esi
  jle    L44
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L21
  xchg   %ax,%ax
L23:
  mov    %rdi,0x0(%r13,%rax,8)
  lea    0x1(%rax),%r14d
  call   <strlen@plt>
  add    %eax,%ebx
  movslq %r14d,%rax
  cmp    %ebp,%ebx
  jge    L29
L21:
  movslq %ebx,%rdi
  add    %r12,%rdi
  cmpb   $0x0,(%rdi)
  jne    L23
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jl     L21
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmd2args(const char *cmdline, int len, char **argv) {
  int i = 0;
  int argc = 0;
  char *ptr = (char *)cmdline;
  while (i < len) {
    if (ptr[i] == 0) {
      i++;
      continue;
    }
    argv[argc++] = ptr + i;
    i += strlen(ptr + i);
  }
  return argc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmd2args>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L20
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%r13
  xor    %eax,%eax
  xor    %ebx,%ebx
L43:
  movslq %ebx,%rdi
  add    %r12,%rdi
  cmpb   $0x0,(%rdi)
  je     L3
L33:
  mov    %rdi,0x0(%r13,%rax,8)
  lea    0x1(%rax),%r14d
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jle    L7
  movslq %ebx,%rdi
  movslq %r14d,%rax
  add    %r12,%rdi
  cmpb   $0x0,(%rdi)
  jne    L33
L3:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jg     L43
  mov    %eax,%r14d
L7:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L20:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int cmd2args(const char *cmdline, int len, char **argv) {
  int i = 0;
  int argc = 0;
  char *ptr = (char *)cmdline;
  while (i < len) {
    if (ptr[i] == 0) {
      i++;
      continue;
    }
    argv[argc++] = ptr + i;
    i += strlen(ptr + i);
  }
  return argc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x4,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <sysctlbyname@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L3
L0:
  mov    -0x18(%rbp),%eax
  sar    $0x14,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: hw.memsize

assistant: ```c
uint32_t get_memory(void) {
  size_t len;
  uint64_t memory;
  int retcode;
  len = sizeof(memory);
  retcode = sysctlbyname("hw.memsize", &memory, &len, NULL, 0);
  if (retcode == -1) {
    return 0;
  }
  memory >>= 20;
  return (uint32_t)memory;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_memory>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x4,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  lea    D0(%rip),%rdi
  call   <sysctlbyname@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L6
  mov    0xc(%rsp),%eax
  sar    $0x14,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: hw.memsize

assistant: ```c
uint32_t get_memory(void) {
  size_t len;
  uint64_t memory;
  int retcode;
  len = sizeof(memory);
  retcode = sysctlbyname("hw.memsize", &memory, &len, NULL, 0);
  if (retcode == -1) {
    return 0;
  }
  memory >>= 20;
  return (uint32_t)memory;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_memory>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  lea    D9(%rip),%rdi
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  movq   $0x4,0x10(%rsp)
  call   <sysctlbyname@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L8
  mov    0xc(%rsp),%eax
  sar    $0x14,%eax
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D9: hw.memsize

assistant: ```c
uint32_t get_memory(void) {
  size_t len;
  uint64_t memory;
  int retcode;
  len = sizeof(memory);
  retcode = sysctlbyname("hw.memsize", &memory, &len, NULL, 0);
  if (retcode == -1) {
    return 0;
  }
  memory >>= 20;
  return (uint32_t)memory;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_memory>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  lea    D2(%rip),%rdi
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  movq   $0x4,0x10(%rsp)
  call   <sysctlbyname@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L0
  mov    0xc(%rsp),%eax
  sar    $0x14,%eax
L0:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: hw.memsize

assistant: ```c
uint32_t get_memory(void) {
  size_t len;
  uint64_t memory;
  int retcode;
  len = sizeof(memory);
  retcode = sysctlbyname("hw.memsize", &memory, &len, NULL, 0);
  if (retcode == -1) {
    return 0;
  }
  memory >>= 20;
  return (uint32_t)memory;
}
```
user: What is the c source code of the assembly code below?

```asm
<floats_xytcov_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x24,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void floats_xytcov_copy(const float xyta[3], const float Ca[9], float xytr[3], float Cr[9]) {
  memcpy(xytr, xyta, 3 * sizeof(float));
  memcpy(Cr, Ca, 9 * sizeof(float));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<floats_xytcov_copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rbp
  mov    %rdx,%rdi
  mov    %rcx,%rbx
  mov    $0xc,%edx
  mov    %rax,%rsi
  call   <memcpy@plt>
  mov    $0x24,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void floats_xytcov_copy(const float xyta[3], const float Ca[9], float xytr[3], float Cr[9]) {
  memcpy(xytr, xyta, 3 * sizeof(float));
  memcpy(Cr, Ca, 9 * sizeof(float));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<floats_xytcov_copy>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  mov    %rsi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    $0xc,%edx
  mov    %r8,%rsi
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x24,%edx
  pop    %rbp
  pop    %r12
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void floats_xytcov_copy(const float xyta[3], const float Ca[9], float xytr[3], float Cr[9]) {
  memcpy(xytr, xyta, 3 * sizeof(float));
  memcpy(Cr, Ca, 9 * sizeof(float));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<floats_xytcov_copy>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  mov    %rsi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    $0xc,%edx
  mov    %r8,%rsi
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x24,%edx
  pop    %rbp
  pop    %r12
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void floats_xytcov_copy(const float xyta[3], const float Ca[9], float xytr[3], float Cr[9]) {
  memcpy(xytr, xyta, 3 * sizeof(float));
  memcpy(Cr, Ca, 9 * sizeof(float));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getRandomArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: Array filled.


assistant: ```c
void getRandomArray(int *array, int length) {
  for (int i = 0; i < length; i++)
    array[i] = rand() % 100;
  printf("Array filled.\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getRandomArray>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L2
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
L5:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L5
L2:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: Array filled.


assistant: ```c
void getRandomArray(int *array, int length) {
  for (int i = 0; i < length; i++)
    array[i] = rand() % 100;
  printf("Array filled.\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<getRandomArray>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %rbp
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbp
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L10
  add    $0x8,%rsp
  lea    D15(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
  nop
L12:
  lea    D15(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
datatype: string

tool: D15: Array filled.


assistant: ```c
void getRandomArray(int *array, int length) {
  for (int i = 0; i < length; i++)
    array[i] = rand() % 100;
  printf("Array filled.\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getRandomArray>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %rbp
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbp
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L16
  add    $0x8,%rsp
  lea    D3(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
  nop
L1:
  lea    D3(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: Array filled.


assistant: ```c
void getRandomArray(int *array, int length) {
  for (int i = 0; i < length; i++)
    array[i] = rand() % 100;
  printf("Array filled.\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ieee80211_mhz2ieee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9b4,-0x4(%rbp)
  jne    L3
  mov    $0xe,%eax
  jmp    L102
L3:
  cmpl   $0x9b3,-0x4(%rbp)
  jg     L80
  mov    -0x4(%rbp),%eax
  sub    $0x967,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L102
L80:
  cmpl   $0x1387,-0x4(%rbp)
  jg     L128
  cmpl   $0x134c,-0x4(%rbp)
  jle    L69
  cmpl   $0x137d,-0x4(%rbp)
  jg     L69
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  jne    L124
  mov    $0x5,%eax
  jmp    L26
L124:
  mov    $0x0,%eax
L26:
  add    %esi,%eax
  sub    $0xc0f8,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L102
L69:
  cmpl   $0x1324,-0x4(%rbp)
  jle    L50
  mov    -0x4(%rbp),%eax
  sub    $0xfa0,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L102
L50:
  mov    -0x4(%rbp),%eax
  sub    $0x9d0,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0xf,%eax
  jmp    L102
L128:
  mov    -0x4(%rbp),%eax
  sub    $0x1388,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L102:
  pop    %rbp
  ret
```

assistant: ```c
u_int ieee80211_mhz2ieee(u_int16_t freq) {
  if (freq == 2484)
    return 14;
  if (freq < 2484)
    return (freq - 2407) / 5;
  if (freq < 5000) {
    if (((freq) > 4940 && (freq) < 4990)) {
      return ((freq * 10) + (((freq % 5) == 2) ? 5 : 0) - 49400) / 5;
    } else if (freq > 4900) {
      return (freq - 4000) / 5;
    } else {
      return 15 + ((freq - 2512) / 20);
    }
  }
  return (freq - 5000) / 5;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ieee80211_mhz2ieee>:
  endbr64
  cmp    $0x9b4,%edi
  je     L3
  cmp    $0x9b3,%edi
  jle    L9
  cmp    $0x1387,%edi
  jg     L35
  lea    -0x134d(%rdi),%eax
  cmp    $0x30,%eax
  jbe    L19
  cmp    $0x1324,%edi
  jle    L8
  sub    $0xfa0,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  ret
L9:
  sub    $0x967,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  ret
L19:
  lea    (%rdi,%rdi,4),%edx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edi
  cmp    $0x2,%edi
  sete   %al
  movzbl %al,%eax
  lea    (%rax,%rax,4),%eax
  lea    -0xc0f8(%rax,%rdx,2),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  ret
L8:
  sub    $0x9d0,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  add    $0xf,%eax
  ret
L35:
  sub    $0x1388,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  ret
L3:
  mov    $0xe,%eax
  ret
```

assistant: ```c
u_int ieee80211_mhz2ieee(u_int16_t freq) {
  if (freq == 2484)
    return 14;
  if (freq < 2484)
    return (freq - 2407) / 5;
  if (freq < 5000) {
    if (((freq) > 4940 && (freq) < 4990)) {
      return ((freq * 10) + (((freq % 5) == 2) ? 5 : 0) - 49400) / 5;
    } else if (freq > 4900) {
      return (freq - 4000) / 5;
    } else {
      return 15 + ((freq - 2512) / 20);
    }
  }
  return (freq - 5000) / 5;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ieee80211_mhz2ieee>:
  endbr64
  cmp    $0x9b4,%edi
  je     L8
  cmp    $0x9b3,%edi
  jle    L2
  cmp    $0x1387,%edi
  jg     L12
  lea    -0x134d(%rdi),%eax
  cmp    $0x30,%eax
  jbe    L23
  cmp    $0x1324,%edi
  jle    L25
  lea    -0xfa0(%rdi),%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  lea    -0x1388(%rdi),%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x967,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sub    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  movslq %edi,%rax
  mov    %edi,%ecx
  lea    (%rdi,%rdi,4),%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  add    %edx,%edx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edi
  lea    0x5(%rdx),%eax
  cmp    $0x2,%edi
  cmovne %edx,%eax
  mov    $0xcccccccd,%edx
  sub    $0xc0f8,%eax
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xe,%eax
  ret
  xchg   %ax,%ax
L25:
  sub    $0x9d0,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  sub    %edi,%eax
  add    $0xf,%eax
  ret
```

assistant: ```c
u_int ieee80211_mhz2ieee(u_int16_t freq) {
  if (freq == 2484)
    return 14;
  if (freq < 2484)
    return (freq - 2407) / 5;
  if (freq < 5000) {
    if (((freq) > 4940 && (freq) < 4990)) {
      return ((freq * 10) + (((freq % 5) == 2) ? 5 : 0) - 49400) / 5;
    } else if (freq > 4900) {
      return (freq - 4000) / 5;
    } else {
      return 15 + ((freq - 2512) / 20);
    }
  }
  return (freq - 5000) / 5;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ieee80211_mhz2ieee>:
  endbr64
  cmp    $0x9b4,%edi
  je     L13
  cmp    $0x9b3,%edi
  jle    L0
  cmp    $0x1387,%edi
  jg     L15
  lea    -0x134d(%rdi),%eax
  cmp    $0x30,%eax
  jbe    L25
  cmp    $0x1324,%edi
  jle    L35
  lea    -0xfa0(%rdi),%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  lea    -0x1388(%rdi),%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax)
L0:
  sub    $0x967,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sub    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movslq %edi,%rax
  mov    %edi,%ecx
  lea    (%rdi,%rdi,4),%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  add    %edx,%edx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edi
  lea    0x5(%rdx),%eax
  cmp    $0x2,%edi
  cmovne %edx,%eax
  mov    $0xcccccccd,%edx
  sub    $0xc0f8,%eax
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xe,%eax
  ret
  xchg   %ax,%ax
L35:
  sub    $0x9d0,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  sub    %edi,%eax
  add    $0xf,%eax
  ret
```

assistant: ```c
u_int ieee80211_mhz2ieee(u_int16_t freq) {
  if (freq == 2484)
    return 14;
  if (freq < 2484)
    return (freq - 2407) / 5;
  if (freq < 5000) {
    if (((freq) > 4940 && (freq) < 4990)) {
      return ((freq * 10) + (((freq % 5) == 2) ? 5 : 0) - 49400) / 5;
    } else if (freq > 4900) {
      return (freq - 4000) / 5;
    } else {
      return 15 + ((freq - 2512) / 20);
    }
  }
  return (freq - 5000) / 5;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tap_error_errno_at>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %rcx,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rcx
  mov    -0x7c(%rbp),%eax
  mov    $0x64,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <strerror_r@plt>
  mov    %eax,%esi
  mov    -0x7c(%rbp),%edi
  mov    -0x78(%rbp),%rcx
  mov    -0x90(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %esi,%r9d
  mov    %edi,%r8d
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <tap_error@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: %s:%lu: %s failed: %d (%s)

assistant: ```c
void tap_error_errno_at(const char *function, int errnum, const char *filename, unsigned long line) {
  char buf[100];
  tap_error("%s:%lu: %s failed: %d (%s)", filename, line, function, errnum, strerror_r(errnum, buf, sizeof(buf)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tap_error_errno_at>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x64,%edx
  mov    %ebx,%edi
  call   <strerror_r@plt>
  mov    %eax,%r9d
  mov    %ebx,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <tap_error@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: %s:%lu: %s failed: %d (%s)

assistant: ```c
void tap_error_errno_at(const char *function, int errnum, const char *filename, unsigned long line) {
  char buf[100];
  tap_error("%s:%lu: %s failed: %d (%s)", filename, line, function, errnum, strerror_r(errnum, buf, sizeof(buf)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tap_error_errno_at>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x64,%edx
  push   %rbx
  mov    %esi,%ebx
  mov    %ebx,%edi
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strerror_r@plt>
  mov    %ebx,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %eax,%r9d
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <tap_error@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: %s:%lu: %s failed: %d (%s)

assistant: ```c
void tap_error_errno_at(const char *function, int errnum, const char *filename, unsigned long line) {
  char buf[100];
  tap_error("%s:%lu: %s failed: %d (%s)", filename, line, function, errnum, strerror_r(errnum, buf, sizeof(buf)));
}
```