ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<uint64Pack>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  push   %rbx
  mov    (%rcx),%rax
  mov    %rbp,%rdi
  mov    %rcx,%rbx
  lea    0x4(%rax),%rdx
  call   <size_buffer@plt>
  mov    (%r12),%eax
  mov    (%rbx),%rdx
  mov    $0x38,%ecx
  sar    %cl,%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%r12),%eax
  mov    $0x30,%ecx
  mov    (%rbx),%rdx
  sar    %cl,%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%r12),%eax
  mov    $0x28,%ecx
  mov    (%rbx),%rdx
  sar    %cl,%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%r12),%eax
  mov    $0x20,%ecx
  mov    (%rbx),%rdx
  sar    %cl,%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%rbx),%rdx
  mov    (%r12),%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  shr    $0x18,%eax
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%rbx),%rdx
  mov    (%r12),%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  sar    $0x10,%eax
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%r12),%ecx
  mov    0x0(%rbp),%rdx
  mov    (%rbx),%rax
  lea    0x1(%rax),%rsi
  mov    %rsi,(%rbx)
  mov    %ch,(%rdx,%rax,1)
  mov    (%rbx),%rax
  mov    (%r12),%ecx
  mov    0x0(%rbp),%rdx
  lea    0x1(%rax),%rsi
  mov    %rsi,(%rbx)
  mov    %cl,(%rdx,%rax,1)
  mov    $0x4,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t uint64Pack(const uint64_t *data, char **buffer, size_t *size, size_t *pos) {
  size_buffer(buffer, size, *pos + sizeof(uint64_t));
  (*buffer)[(*pos)++] = (*data >> 56) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 48) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 40) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 32) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 24) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 16) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 8) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 0) & 0xFF;
  return sizeof(uint64_t);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uint64Pack>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  push   %rbx
  mov    (%rcx),%rax
  mov    %rbp,%rdi
  mov    %rcx,%rbx
  lea    0x4(%rax),%rdx
  call   <size_buffer@plt>
  mov    (%r12),%eax
  mov    (%rbx),%rdx
  mov    $0x38,%ecx
  sar    %cl,%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%r12),%eax
  mov    $0x30,%ecx
  mov    (%rbx),%rdx
  sar    %cl,%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%r12),%eax
  mov    $0x28,%ecx
  mov    (%rbx),%rdx
  sar    %cl,%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%r12),%eax
  mov    $0x20,%ecx
  mov    (%rbx),%rdx
  sar    %cl,%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%rbx),%rdx
  mov    (%r12),%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  shr    $0x18,%eax
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%rbx),%rdx
  mov    (%r12),%eax
  mov    0x0(%rbp),%rcx
  lea    0x1(%rdx),%rsi
  sar    $0x10,%eax
  mov    %rsi,(%rbx)
  mov    %al,(%rcx,%rdx,1)
  mov    (%r12),%ecx
  mov    0x0(%rbp),%rdx
  mov    (%rbx),%rax
  lea    0x1(%rax),%rsi
  mov    %rsi,(%rbx)
  mov    %ch,(%rdx,%rax,1)
  mov    (%rbx),%rax
  mov    (%r12),%ecx
  mov    0x0(%rbp),%rdx
  lea    0x1(%rax),%rsi
  mov    %rsi,(%rbx)
  mov    %cl,(%rdx,%rax,1)
  mov    $0x4,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t uint64Pack(const uint64_t *data, char **buffer, size_t *size, size_t *pos) {
  size_buffer(buffer, size, *pos + sizeof(uint64_t));
  (*buffer)[(*pos)++] = (*data >> 56) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 48) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 40) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 32) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 24) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 16) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 8) & 0xFF;
  (*buffer)[(*pos)++] = (*data >> 0) & 0xFF;
  return sizeof(uint64_t);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_expr_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    $0x0,%ebx
  jmp    L4
L19:
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L4:
  cmp    $0x8002,%ebx
  jle    L19
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void init_expr_hash(struct expr_list **list) {
  register int i = 0;
  while (i < 32771)
    list[i++] = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_expr_hash>:
  endbr64
  lea    0x40018(%rdi),%rax
L2:
  movq   $0x0,(%rdi)
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L2
  ret
```

assistant: ```c
void init_expr_hash(struct expr_list **list) {
  register int i = 0;
  while (i < 32771)
    list[i++] = NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init_expr_hash>:
  endbr64
  mov    $0x40018,%edx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void init_expr_hash(struct expr_list **list) {
  register int i = 0;
  while (i < 32771)
    list[i++] = NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_expr_hash>:
  endbr64
  mov    $0x40018,%edx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void init_expr_hash(struct expr_list **list) {
  register int i = 0;
  while (i < 32771)
    list[i++] = NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L113
L40:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L21
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L113:
  cmpl   $0x5,-0x14(%rbp)
  jle    L40
  jmp    L53
L21:
  nop
L53:
  cmpl   $0x1,-0x14(%rbp)
  jne    L63
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L63:
  cmpl   $0x2,-0x14(%rbp)
  jne    L19
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L19:
  cmpl   $0x3,-0x14(%rbp)
  jne    L120
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L120:
  cmpl   $0x4,-0x14(%rbp)
  jne    L136
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L136:
  cmpl   $0x5,-0x14(%rbp)
  jne    L24
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L24:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L90
  call   <__stack_chk_fail@plt>
L90:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D69
type_infered: string
name: extract_symbolic_data
arguments: tag: D31
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D62
type_infered: string
name: extract_symbolic_data
arguments: tag: D26
type_infered: string
name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D69: Enter the number

tool: D31: %d

tool: D7: The numbr is in Ten's

tool: D62: The numbr is in Hundred's

tool: D26: The number is in Thousand's

tool: D1: The number is in Ten thousand's

tool: D9: The numbr is in lakh's 

assistant: ```c
int main() {
  int n, i, a, b;
  printf("Enter the number");
  scanf("%d", &n);
  for (i = 1; i <= 5; i++) {
    a = n % 10;
    b = n / 10;
    if (a == 0) {
      break;
    }
    n = b;
  }
  if (i == 1) {
    printf("The numbr is in Ten's");
  } else if (i == 2) {
    printf("The numbr is in Hundred's");
  } else if (i == 3) {
    printf("The number is in Thousand's");
  } else if (i == 4) {
    printf("The number is in Ten thousand's");
  } else if (i == 5) {
    printf("The numbr is in lakh's ");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    $0x1,%r9d
L67:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edi
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %edx,%esi
  mov    %edi,%edx
  je     L38
  add    $0x1,%ecx
  mov    %r9d,%r8d
  cmp    $0x6,%ecx
  jne    L67
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L38:
  test   %r8b,%r8b
  je     L22
  mov    %esi,0x4(%rsp)
L22:
  cmp    $0x5,%ecx
  ja     L26
  mov    %ecx,%ecx
  lea    D10(%rip),%rdx
  movslq (%rdx,%rcx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D79(%rip),%rdi
  call   <printf@plt>
  jmp    L26
  lea    D63(%rip),%rdi
  call   <printf@plt>
  jmp    L26
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L26
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L26
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D32
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string
name: parse_data
arguments: data_tag: D79
type_guessed: string
name: parse_data
arguments: data_tag: D63
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D12
type_guessed: string
name: parse_data
arguments: data_tag: D62
type_guessed: string

tool: D32: Enter the number

tool: D21: %d

tool: D79: The numbr is in Ten's

tool: D63: The numbr is in Hundred's

tool: D4: The number is in Thousand's

tool: D12: The number is in Ten thousand's

tool: D62: The numbr is in lakh's 

assistant: ```c
int main() {
  int n, i, a, b;
  printf("Enter the number");
  scanf("%d", &n);
  for (i = 1; i <= 5; i++) {
    a = n % 10;
    b = n / 10;
    if (a == 0) {
      break;
    }
    n = b;
  }
  if (i == 1) {
    printf("The numbr is in Ten's");
  } else if (i == 2) {
    printf("The numbr is in Hundred's");
  } else if (i == 3) {
    printf("The number is in Thousand's");
  } else if (i == 4) {
    printf("The number is in Ten thousand's");
  } else if (i == 5) {
    printf("The numbr is in lakh's ");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D55(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %r8d,%r8d
  mov    $0x1,%edi
L11:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  mov    %edx,%esi
  mov    %ecx,%edx
  je     L38
  add    $0x1,%edi
  mov    $0x1,%r8d
  cmp    $0x6,%edi
  jne    L11
L122:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L38:
  test   %r8b,%r8b
  je     L113
  mov    %esi,0x4(%rsp)
L113:
  cmp    $0x1,%edi
  jne    L28
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L122
L28:
  cmp    $0x2,%edi
  je     L86
  cmp    $0x3,%edi
  je     L59
  cmp    $0x4,%edi
  jne    L97
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L122
L59:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L122
L86:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L122
L97:
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L122
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D55
datatype: string
name: retrieve_data
arguments: data_label: D29
datatype: string
name: retrieve_data
arguments: data_label: D53
datatype: string
name: retrieve_data
arguments: data_label: D62
datatype: string
name: retrieve_data
arguments: data_label: D22
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string
name: retrieve_data
arguments: data_label: D46
datatype: string

tool: D55: Enter the number

tool: D29: %d

tool: D53: The numbr is in Ten's

tool: D62: The number is in Ten thousand's

tool: D22: The number is in Thousand's

tool: D15: The numbr is in Hundred's

tool: D46: The numbr is in lakh's 

assistant: ```c
int main() {
  int n, i, a, b;
  printf("Enter the number");
  scanf("%d", &n);
  for (i = 1; i <= 5; i++) {
    a = n % 10;
    b = n / 10;
    if (a == 0) {
      break;
    }
    n = b;
  }
  if (i == 1) {
    printf("The numbr is in Ten's");
  } else if (i == 2) {
    printf("The numbr is in Hundred's");
  } else if (i == 3) {
    printf("The number is in Thousand's");
  } else if (i == 4) {
    printf("The number is in Ten thousand's");
  } else if (i == 5) {
    printf("The numbr is in lakh's ");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D54(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rcx
  imul   $0x66666667,%rax,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  cmp    %edx,%ecx
  je     L49
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  cmp    %ecx,%eax
  je     L51
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  cmp    %ecx,%edx
  je     L62
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  cmp    %ecx,%eax
  je     L42
  imul   $0xcccccccd,%edx,%eax
  add    $0x19999998,%eax
  ror    %eax
  cmp    $0x19999998,%eax
  jbe    L8
L75:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L49:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L75
L51:
  lea    D28(%rip),%rdi
  mov    %eax,0x4(%rsp)
  call   <printf@plt>
  jmp    L75
L62:
  lea    D41(%rip),%rdi
  mov    %edx,0x4(%rsp)
  call   <printf@plt>
  jmp    L75
L8:
  lea    D52(%rip),%rdi
  mov    %edx,0x4(%rsp)
  call   <printf@plt>
  jmp    L75
L69:
  call   <__stack_chk_fail@plt>
L42:
  lea    D36(%rip),%rdi
  mov    %eax,0x4(%rsp)
  call   <printf@plt>
  jmp    L75
```

tool_calls: name: extract_symbolic_data
arguments: label: D54
type_infered: string
name: extract_symbolic_data
arguments: label: D16
type_infered: string
name: extract_symbolic_data
arguments: label: D32
type_infered: string
name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D41
type_infered: string
name: extract_symbolic_data
arguments: label: D52
type_infered: string
name: extract_symbolic_data
arguments: label: D36
type_infered: string

tool: D54: Enter the number

tool: D16: %d

tool: D32: The numbr is in Ten's

tool: D28: The numbr is in Hundred's

tool: D41: The number is in Thousand's

tool: D52: The numbr is in lakh's 

tool: D36: The number is in Ten thousand's

assistant: ```c
int main() {
  int n, i, a, b;
  printf("Enter the number");
  scanf("%d", &n);
  for (i = 1; i <= 5; i++) {
    a = n % 10;
    b = n / 10;
    if (a == 0) {
      break;
    }
    n = b;
  }
  if (i == 1) {
    printf("The numbr is in Ten's");
  } else if (i == 2) {
    printf("The numbr is in Hundred's");
  } else if (i == 3) {
    printf("The number is in Thousand's");
  } else if (i == 4) {
    printf("The number is in Ten thousand's");
  } else if (i == 5) {
    printf("The numbr is in lakh's ");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<err_quit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%ecx
  mov    -0xc8(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <err_doit@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void err_quit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_doit(0, LOG_ERR, fmt, ap);
  va_end(ap);
  exit(EXIT_FAILURE);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<err_quit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <err_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void err_quit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_doit(0, LOG_ERR, fmt, ap);
  va_end(ap);
  exit(EXIT_FAILURE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<err_quit>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D17(%rip),%rax
  mov    %ebp,%ecx
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    (%rax),%esi
  call   <err_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void err_quit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_doit(0, LOG_ERR, fmt, ap);
  va_end(ap);
  exit(EXIT_FAILURE);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<err_quit>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %ebp,%ecx
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    (%rax),%esi
  call   <err_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void err_quit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_doit(0, LOG_ERR, fmt, ap);
  va_end(ap);
  exit(EXIT_FAILURE);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<full>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L3:
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L13:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0x1,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void full(int size, int table[5][5]) {
  int temp_w, temp_h;
  for (temp_w = 0; temp_w < size; temp_w++) {
    for (temp_h = 0; temp_h < size; temp_h++) {
      table[temp_w][temp_h] = 1;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<full>:
  endbr64
  test   %edi,%edi
  jle    L21
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rdx
  lea    (%rax,%rax,2),%rax
  lea    0x18(%rsi,%rax,8),%rsi
  mov    %edi,%edi
  neg    %rdi
  lea    0x0(,%rdi,4),%rcx
  jmp    L28
L30:
  add    $0x14,%rdx
  cmp    %rsi,%rdx
  je     L21
L28:
  lea    (%rcx,%rdx,1),%rax
L37:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L37
  jmp    L30
L21:
  ret
```

assistant: ```c
void full(int size, int table[5][5]) {
  int temp_w, temp_h;
  for (temp_w = 0; temp_w < size; temp_w++) {
    for (temp_h = 0; temp_h < size; temp_h++) {
      table[temp_w][temp_h] = 1;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<full>:
  endbr64
  test   %edi,%edi
  jle    L17
  lea    -0x1(%rdi),%eax
  mov    $0xfffffffffffffffc,%rcx
  lea    0x0(,%rax,4),%rdi
  lea    (%rax,%rax,2),%rax
  lea    0x4(%rsi,%rdi,1),%rdx
  sub    %rdi,%rcx
  lea    0x18(%rsi,%rax,8),%rsi
  nopl   0x0(%rax,%rax,1)
L14:
  lea    (%rcx,%rdx,1),%rax
  nopl   0x0(%rax)
L22:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L22
  add    $0x14,%rdx
  cmp    %rsi,%rdx
  jne    L14
L17:
  ret
```

assistant: ```c
void full(int size, int table[5][5]) {
  int temp_w, temp_h;
  for (temp_w = 0; temp_w < size; temp_w++) {
    for (temp_h = 0; temp_h < size; temp_h++) {
      table[temp_w][temp_h] = 1;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<full>:
  endbr64
  test   %edi,%edi
  jle    L34
  lea    -0x1(%rdi),%eax
  lea    (%rax,%rax,4),%rax
  lea    0x14(%rsi,%rax,4),%rdx
  nopl   0x0(%rax)
L7:
  movl   $0x1,(%rsi)
  cmp    $0x1,%edi
  je     L64
  movl   $0x1,0x4(%rsi)
  cmp    $0x2,%edi
  je     L64
  movl   $0x1,0x8(%rsi)
  cmp    $0x3,%edi
  je     L64
  movl   $0x1,0xc(%rsi)
  cmp    $0x4,%edi
  je     L64
  movl   $0x1,0x10(%rsi)
  cmp    $0x5,%edi
  je     L64
  movl   $0x1,0x14(%rsi)
  mov    $0x6,%eax
  cmp    $0x6,%edi
  je     L64
L36:
  movl   $0x1,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L36
  nopl   0x0(%rax,%rax,1)
L64:
  add    $0x14,%rsi
  cmp    %rdx,%rsi
  jne    L7
L34:
  ret
```

assistant: ```c
void full(int size, int table[5][5]) {
  int temp_w, temp_h;
  for (temp_w = 0; temp_w < size; temp_w++) {
    for (temp_h = 0; temp_h < size; temp_h++) {
      table[temp_w][temp_h] = 1;
    }
  }
}
```