ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  cmp    $0xffff0066,%eax
  jne    L1
L3:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L1:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L3
```

assistant: ```c
int main(void) {
  if ((unsigned char)-1 != 0xff || sizeof(short) != 2 || sizeof(int) != 4)
    exit(0);
  if (foo() != (int)0xffff0066)
    abort();
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  cmp    $0xffff0066,%eax
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  if ((unsigned char)-1 != 0xff || sizeof(short) != 2 || sizeof(int) != 4)
    exit(0);
  if (foo() != (int)0xffff0066)
    abort();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  cmp    $0xffff0066,%eax
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  if ((unsigned char)-1 != 0xff || sizeof(short) != 2 || sizeof(int) != 4)
    exit(0);
  if (foo() != (int)0xffff0066)
    abort();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SetStackString1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L5
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L18
L5:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L18:
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x18(%rbp)
L28:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void SetStackString1(char **ppchStack, int inStackNo, char *pchValue) {
  char *pchStack = ppchStack[inStackNo];
  if (pchValue != NULL) {
    int inLength = strlen(pchValue);
    ppchStack[inStackNo] = malloc(inLength + 1);
    strcpy(ppchStack[inStackNo], pchValue);
  } else {
    ppchStack[inStackNo] = NULL;
  }
  if (pchStack != NULL) {
    free(pchStack);
    pchStack = NULL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SetStackString1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rbp
  mov    0x0(%rbp),%r12
  test   %rdx,%rdx
  je     L0
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  mov    %rbx,%rsi
  call   <strcpy@plt>
L3:
  test   %r12,%r12
  je     L21
  mov    %r12,%rdi
  call   <free@plt>
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  movq   $0x0,0x0(%rbp)
  jmp    L3
```

assistant: ```c
void SetStackString1(char **ppchStack, int inStackNo, char *pchValue) {
  char *pchStack = ppchStack[inStackNo];
  if (pchValue != NULL) {
    int inLength = strlen(pchValue);
    ppchStack[inStackNo] = malloc(inLength + 1);
    strcpy(ppchStack[inStackNo], pchValue);
  } else {
    ppchStack[inStackNo] = NULL;
  }
  if (pchStack != NULL) {
    free(pchStack);
    pchStack = NULL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SetStackString1>:
  endbr64
  movslq %esi,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%rdi,%rsi,8),%rbx
  mov    (%rbx),%r12
  test   %rdx,%rdx
  je     L1
  mov    %rdx,%rdi
  mov    %rdx,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strcpy@plt>
  test   %r12,%r12
  je     L19
L3:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
  nopl   0x0(%rax)
L1:
  movq   $0x0,(%rbx)
  test   %r12,%r12
  jne    L3
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void SetStackString1(char **ppchStack, int inStackNo, char *pchValue) {
  char *pchStack = ppchStack[inStackNo];
  if (pchValue != NULL) {
    int inLength = strlen(pchValue);
    ppchStack[inStackNo] = malloc(inLength + 1);
    strcpy(ppchStack[inStackNo], pchValue);
  } else {
    ppchStack[inStackNo] = NULL;
  }
  if (pchStack != NULL) {
    free(pchStack);
    pchStack = NULL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<SetStackString1>:
  endbr64
  movslq %esi,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%rdi,%rsi,8),%rbx
  mov    (%rbx),%r12
  test   %rdx,%rdx
  je     L5
  mov    %rdx,%rdi
  mov    %rdx,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strcpy@plt>
  test   %r12,%r12
  je     L28
L22:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
  nopl   0x0(%rax)
L5:
  movq   $0x0,(%rbx)
  test   %r12,%r12
  jne    L22
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void SetStackString1(char **ppchStack, int inStackNo, char *pchValue) {
  char *pchStack = ppchStack[inStackNo];
  if (pchValue != NULL) {
    int inLength = strlen(pchValue);
    ppchStack[inStackNo] = malloc(inLength + 1);
    strcpy(ppchStack[inStackNo], pchValue);
  } else {
    ppchStack[inStackNo] = NULL;
  }
  if (pchStack != NULL) {
    free(pchStack);
    pchStack = NULL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rBve99009253050923_br_find_bin_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <rBve99009253050923_br_find_prefix@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L34
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L25
L12:
  mov    $0x0,%eax
  jmp    L25
L34:
  mov    -0x10(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rBve99009253050923_br_build_path@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: bin

assistant: ```c
char *rBve99009253050923_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = rBve99009253050923_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_bin_dir != (const char *)((char *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((char *)0);
  }
  dir = rBve99009253050923_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rBve99009253050923_br_find_bin_dir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <rBve99009253050923_br_find_prefix@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%rbx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <rBve99009253050923_br_build_path@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <free@plt>
L11:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    %rbp,%r12
  test   %rbp,%rbp
  je     L11
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: bin

assistant: ```c
char *rBve99009253050923_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = rBve99009253050923_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_bin_dir != (const char *)((char *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((char *)0);
  }
  dir = rBve99009253050923_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rBve99009253050923_br_find_bin_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <rBve99009253050923_br_find_prefix@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rbp
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <rBve99009253050923_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  test   %r12,%r12
  je     L0
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L0:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: bin

assistant: ```c
char *rBve99009253050923_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = rBve99009253050923_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_bin_dir != (const char *)((char *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((char *)0);
  }
  dir = rBve99009253050923_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rBve99009253050923_br_find_bin_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <rBve99009253050923_br_find_prefix@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbp
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <rBve99009253050923_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  test   %r12,%r12
  je     L2
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string

tool: D7: bin

assistant: ```c
char *rBve99009253050923_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = rBve99009253050923_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_bin_dir != (const char *)((char *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((char *)0);
  }
  dir = rBve99009253050923_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L11:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L22:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L11
L9:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t n) {
  const char *s = src;
  char *d = dest;
  while (*s != '\0' && n-- > 0)
    *(d++) = *(s++);
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L5
  test   %rdx,%rdx
  je     L5
  mov    $0x0,%ecx
L30:
  mov    %r8b,(%rax,%rcx,1)
  movzbl 0x1(%rsi,%rcx,1),%r8d
  test   %r8b,%r8b
  je     L5
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L30
L5:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t n) {
  const char *s = src;
  char *d = dest;
  while (*s != '\0' && n-- > 0)
    *(d++) = *(s++);
  return dest;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncpy>:
  endbr64
  movzbl (%rsi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L42
  test   %rdx,%rdx
  je     L42
  xor    %ecx,%ecx
  jmp    L35
  nopl   0x0(%rax)
L11:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L42
L35:
  mov    %r8b,(%rax,%rcx,1)
  movzbl 0x1(%rsi,%rcx,1),%r8d
  test   %r8b,%r8b
  jne    L11
L42:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t n) {
  const char *s = src;
  char *d = dest;
  while (*s != '\0' && n-- > 0)
    *(d++) = *(s++);
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strncpy>:
  endbr64
  movzbl (%rsi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L30
  test   %rdx,%rdx
  je     L30
  xor    %ecx,%ecx
  jmp    L21
  nopl   0x0(%rax)
L23:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L30
L21:
  mov    %r8b,(%rax,%rcx,1)
  movzbl 0x1(%rsi,%rcx,1),%r8d
  test   %r8b,%r8b
  jne    L23
L30:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t n) {
  const char *s = src;
  char *d = dest;
  while (*s != '\0' && n-- > 0)
    *(d++) = *(s++);
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L30
L7:
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L25:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0xa,-0xd(%rbp)
  jne    L7
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L25
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D20
datatype: string
name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D25
datatype: string

tool: D20:  is not an integer.
Please enter an  

tool: D21: integer value, such as 25, -178, or 3; 

tool: D25: %d

assistant: ```c
int get_int(void) {
  int input;
  char ch;
  while (scanf("%d", &input) != 1) {
    while ((ch = getchar()) != '\n') {
      putchar(ch);
    }
    printf(" is not an integer.\nPlease enter an  ");
    printf("integer value, such as 25, -178, or 3; ");
  }
  return input;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    D17(%rip),%rbx
  lea    D18(%rip),%r13
  lea    D11(%rip),%r12
  jmp    L35
L16:
  movsbl %al,%edi
  call   <putchar@plt>
L5:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L16
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
L35:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L5
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
data_type: string
name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D11
data_type: string

tool: D17: %d

tool: D18:  is not an integer.
Please enter an  

tool: D11: integer value, such as 25, -178, or 3; 

assistant: ```c
int get_int(void) {
  int input;
  char ch;
  while (scanf("%d", &input) != 1) {
    while ((ch = getchar()) != '\n') {
      putchar(ch);
    }
    printf(" is not an integer.\nPlease enter an  ");
    printf("integer value, such as 25, -178, or 3; ");
  }
  return input;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_int>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D27(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L33
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L40:
  movsbl %al,%edi
  call   <putchar@plt>
L33:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L40
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L33
L42:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string
name: disassemble_data
arguments: data_tag: D27
type_guessed: string

tool: D10:  is not an integer.
Please enter an  

tool: D16: integer value, such as 25, -178, or 3; 

tool: D27: %d

assistant: ```c
int get_int(void) {
  int input;
  char ch;
  while (scanf("%d", &input) != 1) {
    while ((ch = getchar()) != '\n') {
      putchar(ch);
    }
    printf(" is not an integer.\nPlease enter an  ");
    printf("integer value, such as 25, -178, or 3; ");
  }
  return input;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_int>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  lea    D29(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L8
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L39:
  movsbl %al,%edi
  call   <putchar@plt>
L8:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L39
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L8
L40:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D0:  is not an integer.
Please enter an  

tool: D29: integer value, such as 25, -178, or 3; 

tool: D6: %d

assistant: ```c
int get_int(void) {
  int input;
  char ch;
  while (scanf("%d", &input) != 1) {
    while ((ch = getchar()) != '\n') {
      putchar(ch);
    }
    printf(" is not an integer.\nPlease enter an  ");
    printf("integer value, such as 25, -178, or 3; ");
  }
  return input;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_exename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <readlink@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L17
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L19
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L19:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: /proc/self/exe

assistant: ```c
char *get_exename(char *exename, int size) {
  int res;
  if ((res = readlink("/proc/self/exe", exename, size - 1)) == -1)
    exename[0] = '\0';
  else
    exename[res] = '\0';
  return (exename);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_exename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  je     L8
  cltq
  movb   $0x0,(%rbx,%rax,1)
L11:
  mov    %rbx,%rax
  pop    %rbx
  ret
L8:
  movb   $0x0,(%rbx)
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: /proc/self/exe

assistant: ```c
char *get_exename(char *exename, int size) {
  int res;
  if ((res = readlink("/proc/self/exe", exename, size - 1)) == -1)
    exename[0] = '\0';
  else
    exename[res] = '\0';
  return (exename);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_exename>:
  endbr64
  push   %r12
  lea    -0x1(%rsi),%edx
  mov    %rdi,%r12
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  je     L3
  cltq
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L3:
  mov    %r12,%rax
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string

tool: D7: /proc/self/exe

assistant: ```c
char *get_exename(char *exename, int size) {
  int res;
  if ((res = readlink("/proc/self/exe", exename, size - 1)) == -1)
    exename[0] = '\0';
  else
    exename[res] = '\0';
  return (exename);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_exename>:
  endbr64
  push   %r12
  lea    -0x1(%rsi),%edx
  mov    %rdi,%r12
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  je     L8
  cltq
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L8:
  mov    %r12,%rax
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: /proc/self/exe

assistant: ```c
char *get_exename(char *exename, int size) {
  int res;
  if ((res = readlink("/proc/self/exe", exename, size - 1)) == -1)
    exename[0] = '\0';
  else
    exename[res] = '\0';
  return (exename);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<clstore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  movabs $0xffffffff7ffffffc,%rax
  and    -0x8(%rbp),%rax
  mov    $0x80000000,%edx
  or     %rdx,%rax
  mov    $0xcf8,%esi
  mov    %rax,%rdi
  call   <outl@plt>
  mov    -0x8(%rbp),%rax
  and    $0x3,%eax
  add    $0xcfc,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <outl@plt>
  nop
  leave
  ret
```

assistant: ```c
void clstore(long cfgadr, long value) {
  outl((cfgadr | 0x80000000) & ~3, 0xcf8);
  outl(value, (0xcfc + (cfgadr & 3)));
}
```