ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_latlong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rsp,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%r15d
  add    $0x1,%r15d
  movslq %r15d,%r15
  lea    0xf(%r15,%r15,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L102
L48:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L48
L102:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L3
L92:
  mov    %rsp,%rbx
  mov    %rsp,%r14
  xor    %r12d,%r12d
L0:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%edi
  movslq %edi,%rdx
  lea    0x0(%r13,%rdx,1),%r8
  cmpb   $0x5f,(%r8)
  je     L45
  lea    -0x1(%r13,%rdx,1),%rdx
  nopl   0x0(%rax)
L114:
  mov    %rdx,%r8
  sub    $0x1,%rdx
  mov    %edi,%eax
  sub    $0x1,%edi
  cmpb   $0x5f,0x1(%rdx)
  jne    L114
L45:
  cltq
  movb   $0x0,(%r8)
  lea    0x0(%r13,%rax,1),%rdx
  movzbl (%rdx),%edi
  test   %dil,%dil
  je     L8
  mov    $0x1,%eax
  xchg   %ax,%ax
L108:
  mov    %dil,-0x1(%r14,%rax,1)
  movslq %eax,%r8
  movb   $0x0,-0x1(%rdx,%rax,1)
  add    $0x1,%rax
  movzbl -0x1(%rdx,%rax,1),%edi
  test   %dil,%dil
  jne    L108
L58:
  movslq %r12d,%rax
  add    %rbx,%r8
  add    %r15,%r14
  imul   %r15,%rax
  movb   $0x0,(%r8,%rax,1)
  cmp    $0x1,%r12d
  jne    L5
  mov    %rbx,%rdi
  call   <atof@plt>
  mov    -0x50(%rbp),%rax
  lea    (%rbx,%r15,1),%rdi
  movss  %xmm0,(%rax)
  call   <atof@plt>
  mov    -0x48(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%r12d
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %r8d,%r8d
  jmp    L58
L3:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L92
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_latlong(char fname[BUFSIZ + 1], float *lat, float *lon) {
  int i, j, delim;
  char latlong[2][BUFSIZ + 1];
  for (i = 0; i < 2; i++) {
    delim = strlen(fname) - 1;
    while (fname[delim] != '_')
      delim--;
    fname[delim] = '\0';
    delim++;
    j = 0;
    while (fname[delim] != '\0') {
      latlong[i][j] = fname[delim];
      fname[delim] = '\0';
      delim++;
      j++;
    }
    latlong[i][j] = '\0';
  }
  *lon = atof(latlong[0]);
  *lat = atof(latlong[1]);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L94
L64:
  addq   $0x1,-0x18(%rbp)
L94:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x8,%al
  jle    L68
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jle    L64
L68:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L64
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L95
  mov    $0xffffffff,%eax
  jmp    L69
L95:
  mov    $0x1,%eax
L69:
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L65
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L41
L65:
  addq   $0x1,-0x18(%rbp)
  jmp    L41
L92:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
L41:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L100
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L92
L100:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  int total;
  int is_neg;
  total = 0;
  while ((*str >= '\t' && *str <= '\r') || *str == ' ')
    str++;
  if ((is_neg = *str == '-' ? -1 : 1) == -1 || *str == '+')
    str++;
  while (*str && ft_isdigit(*str))
    total = (total * 10) + (*str++ - '0');
  return (total * is_neg);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L4
  cmp    $0x20,%dl
  jne    L100
L4:
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L4
  cmp    $0x20,%dl
  je     L4
L100:
  cmp    $0x2d,%dl
  je     L41
  mov    $0x1,%r12d
  cmp    $0x2b,%dl
  jne    L85
  jmp    L2
L41:
  mov    $0xffffffff,%r12d
L2:
  add    $0x1,%rbx
L85:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L83
  mov    $0x0,%ebp
L79:
  movsbl %dil,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  je     L94
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L79
L94:
  mov    %r12d,%eax
  imul   %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L83:
  mov    $0x0,%ebp
  jmp    L94
```

assistant: ```c
int ft_atoi(const char *str) {
  int total;
  int is_neg;
  total = 0;
  while ((*str >= '\t' && *str <= '\r') || *str == ' ')
    str++;
  if ((is_neg = *str == '-' ? -1 : 1) == -1 || *str == '+')
    str++;
  while (*str && ft_isdigit(*str))
    total = (total * 10) + (*str++ - '0');
  return (total * is_neg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%edx
  mov    %rdi,%rbx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  ja     L29
  nopl   (%rax)
L68:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L68
L29:
  cmp    $0x20,%dl
  je     L68
  cmp    $0x2d,%dl
  je     L25
  mov    $0x1,%r12d
  cmp    $0x2b,%dl
  je     L5
L66:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L65
  xor    %ebp,%ebp
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L23:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
  test   %dil,%dil
  je     L47
L57:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L23
L47:
  mov    %r12d,%eax
  imul   %ebp,%eax
L97:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L25:
  mov    $0xffffffff,%r12d
L5:
  add    $0x1,%rbx
  jmp    L66
L65:
  xor    %eax,%eax
  jmp    L97
```

assistant: ```c
int ft_atoi(const char *str) {
  int total;
  int is_neg;
  total = 0;
  while ((*str >= '\t' && *str <= '\r') || *str == ' ')
    str++;
  if ((is_neg = *str == '-' ? -1 : 1) == -1 || *str == '+')
    str++;
  while (*str && ft_isdigit(*str))
    total = (total * 10) + (*str++ - '0');
  return (total * is_neg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  lea    -0x9(%rdi),%eax
  cmp    $0x4,%al
  ja     L10
  nopl   (%rax)
L27:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  lea    -0x9(%rdi),%eax
  cmp    $0x4,%al
  jbe    L27
L10:
  cmp    $0x20,%dil
  je     L27
  cmp    $0x2d,%dil
  je     L90
  mov    $0x1,%r12d
  cmp    $0x2b,%dil
  je     L58
L79:
  test   %dil,%dil
  je     L103
  xor    %ebp,%ebp
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L37:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
  test   %dil,%dil
  je     L66
L28:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L37
L66:
  mov    %r12d,%eax
  imul   %ebp,%eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L90:
  mov    $0xffffffff,%r12d
L58:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  jmp    L79
L103:
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
int ft_atoi(const char *str) {
  int total;
  int is_neg;
  total = 0;
  while ((*str >= '\t' && *str <= '\r') || *str == ' ')
    str++;
  if ((is_neg = *str == '-' ? -1 : 1) == -1 || *str == '+')
    str++;
  while (*str && ft_isdigit(*str))
    total = (total * 10) + (*str++ - '0');
  return (total * is_neg);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<flash_writecommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
  movl   $0xe0000000,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x9,%eax
  or     -0x8(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x18(%rbp),%eax
  add    %eax,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0xcc006814,%eax
  movl   $0xc0,(%rax)
  mov    $0xcc006824,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0xcc006820,%eax
  movl   $0x35,(%rax)
  nop
L7:
  mov    $0xcc006820,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L7
  mov    $0xcc006814,%eax
  movl   $0xc0,(%rax)
  mov    $0xcc006820,%eax
  movl   $0x35,(%rax)
  nop
L15:
  mov    $0xcc006820,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L15
  mov    $0xcc006814,%eax
  movl   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void flash_writecommand(unsigned int flashaddress, unsigned char flashdata) {
  unsigned int datatosend;
  unsigned int flashcommand = 0xE0000000;
  datatosend = flashcommand | (flashaddress << 9) | (flashdata << 1);
  *(volatile unsigned int *)0xCC006814 = 0x000000C0;
  *(volatile unsigned int *)0xCC006824 = datatosend;
  *(volatile unsigned int *)0xCC006820 = 0x35;
  while ((*(volatile unsigned int *)0xCC006820) & 1)
    ;
  *(volatile unsigned int *)0xCC006814 = 0x000000C0;
  *(volatile unsigned int *)0xCC006820 = 0x35;
  while ((*(volatile unsigned int *)0xCC006820) & 1)
    ;
  *(volatile unsigned int *)0xCC006814 = 0x0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flash_writecommand>:
  endbr64
  shl    $0x9,%edi
  movzbl %sil,%esi
  add    %esi,%esi
  or     %esi,%edi
  mov    %edi,%eax
  or     $0xe0000000,%eax
  mov    $0xcc006814,%ecx
  movl   $0xc0,(%rcx)
  movabs %eax,0xcc006824
  mov    $0xcc006820,%eax
  movl   $0x35,(%rax)
  mov    %rax,%rdx
L1:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L1
  mov    $0xcc006814,%eax
  movl   $0xc0,(%rax)
  lea    0xc(%rax),%rax
  movl   $0x35,(%rax)
  mov    %rax,%rdx
L8:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L8
  mov    $0xcc006814,%eax
  movl   $0x0,(%rax)
  ret
```

assistant: ```c
void flash_writecommand(unsigned int flashaddress, unsigned char flashdata) {
  unsigned int datatosend;
  unsigned int flashcommand = 0xE0000000;
  datatosend = flashcommand | (flashaddress << 9) | (flashdata << 1);
  *(volatile unsigned int *)0xCC006814 = 0x000000C0;
  *(volatile unsigned int *)0xCC006824 = datatosend;
  *(volatile unsigned int *)0xCC006820 = 0x35;
  while ((*(volatile unsigned int *)0xCC006820) & 1)
    ;
  *(volatile unsigned int *)0xCC006814 = 0x000000C0;
  *(volatile unsigned int *)0xCC006820 = 0x35;
  while ((*(volatile unsigned int *)0xCC006820) & 1)
    ;
  *(volatile unsigned int *)0xCC006814 = 0x0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<flash_writecommand>:
  endbr64
  movzbl %sil,%esi
  shl    $0x9,%edi
  mov    $0xcc006814,%ecx
  add    %esi,%esi
  movl   $0xc0,(%rcx)
  or     %esi,%edi
  mov    %edi,%eax
  or     $0xe0000000,%eax
  movabs %eax,0xcc006824
  mov    $0xcc006820,%eax
  movl   $0x35,(%rax)
  mov    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L12:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L12
  mov    $0xcc006814,%eax
  movl   $0xc0,(%rax)
  add    $0xc,%rax
  movl   $0x35,(%rax)
  mov    %rax,%rdx
  xchg   %ax,%ax
L15:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L15
  mov    $0xcc006814,%eax
  movl   $0x0,(%rax)
  ret
```

assistant: ```c
void flash_writecommand(unsigned int flashaddress, unsigned char flashdata) {
  unsigned int datatosend;
  unsigned int flashcommand = 0xE0000000;
  datatosend = flashcommand | (flashaddress << 9) | (flashdata << 1);
  *(volatile unsigned int *)0xCC006814 = 0x000000C0;
  *(volatile unsigned int *)0xCC006824 = datatosend;
  *(volatile unsigned int *)0xCC006820 = 0x35;
  while ((*(volatile unsigned int *)0xCC006820) & 1)
    ;
  *(volatile unsigned int *)0xCC006814 = 0x000000C0;
  *(volatile unsigned int *)0xCC006820 = 0x35;
  while ((*(volatile unsigned int *)0xCC006820) & 1)
    ;
  *(volatile unsigned int *)0xCC006814 = 0x0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<flash_writecommand>:
  endbr64
  movzbl %sil,%esi
  shl    $0x9,%edi
  mov    $0xcc006814,%ecx
  add    %esi,%esi
  movl   $0xc0,(%rcx)
  or     %esi,%edi
  mov    %edi,%eax
  or     $0xe0000000,%eax
  movabs %eax,0xcc006824
  mov    $0xcc006820,%eax
  movl   $0x35,(%rax)
  mov    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L14
  mov    $0xcc006814,%eax
  movl   $0xc0,(%rax)
  add    $0xc,%rax
  movl   $0x35,(%rax)
  mov    %rax,%rdx
  xchg   %ax,%ax
L10:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L10
  mov    $0xcc006814,%eax
  movl   $0x0,(%rax)
  ret
```

assistant: ```c
void flash_writecommand(unsigned int flashaddress, unsigned char flashdata) {
  unsigned int datatosend;
  unsigned int flashcommand = 0xE0000000;
  datatosend = flashcommand | (flashaddress << 9) | (flashdata << 1);
  *(volatile unsigned int *)0xCC006814 = 0x000000C0;
  *(volatile unsigned int *)0xCC006824 = datatosend;
  *(volatile unsigned int *)0xCC006820 = 0x35;
  while ((*(volatile unsigned int *)0xCC006820) & 1)
    ;
  *(volatile unsigned int *)0xCC006814 = 0x000000C0;
  *(volatile unsigned int *)0xCC006820 = 0x35;
  while ((*(volatile unsigned int *)0xCC006820) & 1)
    ;
  *(volatile unsigned int *)0xCC006814 = 0x0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MD5_Final>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    0x30(%rsi),%r12
  mov    (%rsi),%rdi
  movb   $0x80,(%r12,%rdi,1)
  add    $0x1,%rdi
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  lea    -0x8(%rdx),%eax
  cltq
  cmp    %rdi,%rax
  jb     L18
L16:
  mov    D1(%rip),%r13
  mov    0x0(%r13),%eax
  lea    -0x8(%rax),%edx
  sub    %edi,%edx
  add    %r12,%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  movslq 0x0(%r13),%rax
  lea    -0x8(%r12,%rax,1),%rax
  mov    0x8(%rbx),%edx
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  mov    %edx,0x4(%rax)
  lea    0x8(%rax),%r12
  movslq 0x0(%r13),%rax
  sub    %rax,%r12
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <md5_block_data_order@plt>
  movq   $0x0,(%rbx)
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  call   <OPENSSL_cleanse@plt>
  mov    0x10(%rbx),%rax
  mov    %eax,0x0(%rbp)
  mov    0x18(%rbx),%rax
  mov    %eax,0x4(%rbp)
  mov    0x20(%rbx),%rax
  mov    %eax,0x8(%rbp)
  mov    0x28(%rbx),%rax
  mov    %eax,0xc(%rbp)
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  sub    %edi,%edx
  add    %r12,%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <md5_block_data_order@plt>
  mov    $0x0,%edi
  jmp    L16
```

assistant: ```c
int MD5_Final(unsigned char *md, MD5_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (MD5_CBLOCK - 8)) {
    memset(p + n, 0, MD5_CBLOCK - n);
    n = 0;
    md5_block_data_order(c, p, 1);
  }
  memset(p + n, 0, MD5_CBLOCK - 8 - n);
  p += MD5_CBLOCK - 8;
  (void)(*((unsigned int *)(p)) = (c->Nl), (p) += 4, c->Nl);
  (void)(*((unsigned int *)(p)) = (c->Nh), (p) += 4, c->Nh);
  p -= MD5_CBLOCK;
  md5_block_data_order(c, p, 1);
  c->num = 0;
  OPENSSL_cleanse(p, MD5_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
  } while (0);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MD5_Final>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x30(%rsi),%rbp
  mov    (%rsi),%rax
  mov    D0(%rip),%r12
  movb   $0x80,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  mov    (%r12),%edx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %eax,%esi
  lea    -0x8(%rdx),%ecx
  movslq %ecx,%rcx
  cmp    %rax,%rcx
  jb     L14
L3:
  sub    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%edx
  call   <memset@plt>
  movslq (%r12),%rax
  mov    0x8(%rbx),%edx
  mov    %rbx,%rdi
  lea    -0x8(%rbp,%rax,1),%rax
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  lea    0x8(%rax),%rbp
  mov    %edx,0x4(%rax)
  movslq (%r12),%rax
  mov    $0x1,%edx
  sub    %rax,%rbp
  mov    %rbp,%rsi
  call   <md5_block_data_order@plt>
  movq   $0x0,(%rbx)
  mov    (%r12),%esi
  mov    %rbp,%rdi
  call   <OPENSSL_cleanse@plt>
  mov    0x10(%rbx),%rax
  mov    %eax,0x0(%r13)
  mov    0x18(%rbx),%rax
  mov    %eax,0x4(%r13)
  mov    0x20(%rbx),%rax
  mov    %eax,0x8(%r13)
  mov    0x28(%rbx),%rax
  mov    %eax,0xc(%r13)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L14:
  sub    %eax,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <md5_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  jmp    L3
```

assistant: ```c
int MD5_Final(unsigned char *md, MD5_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (MD5_CBLOCK - 8)) {
    memset(p + n, 0, MD5_CBLOCK - n);
    n = 0;
    md5_block_data_order(c, p, 1);
  }
  memset(p + n, 0, MD5_CBLOCK - 8 - n);
  p += MD5_CBLOCK - 8;
  (void)(*((unsigned int *)(p)) = (c->Nl), (p) += 4, c->Nl);
  (void)(*((unsigned int *)(p)) = (c->Nh), (p) += 4, c->Nh);
  p -= MD5_CBLOCK;
  md5_block_data_order(c, p, 1);
  c->num = 0;
  OPENSSL_cleanse(p, MD5_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
  } while (0);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MD5_Final>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x30(%rsi),%rbp
  mov    (%rsi),%rax
  mov    D1(%rip),%r12
  movb   $0x80,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  mov    (%r12),%edx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %eax,%esi
  lea    -0x8(%rdx),%ecx
  movslq %ecx,%rcx
  cmp    %rax,%rcx
  jb     L14
L10:
  sub    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%edx
  call   <memset@plt>
  movslq (%r12),%rax
  mov    0x8(%rbx),%edx
  mov    %rbx,%rdi
  lea    -0x8(%rbp,%rax,1),%rax
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  lea    0x8(%rax),%rbp
  mov    %edx,0x4(%rax)
  movslq (%r12),%rax
  mov    $0x1,%edx
  sub    %rax,%rbp
  mov    %rbp,%rsi
  call   <md5_block_data_order@plt>
  movq   $0x0,(%rbx)
  mov    (%r12),%esi
  mov    %rbp,%rdi
  call   <OPENSSL_cleanse@plt>
  movdqu 0x10(%rbx),%xmm0
  movdqu 0x20(%rbx),%xmm1
  mov    $0x1,%eax
  shufps $0x88,%xmm1,%xmm0
  movups %xmm0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  sub    %eax,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <md5_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  jmp    L10
```

assistant: ```c
int MD5_Final(unsigned char *md, MD5_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (MD5_CBLOCK - 8)) {
    memset(p + n, 0, MD5_CBLOCK - n);
    n = 0;
    md5_block_data_order(c, p, 1);
  }
  memset(p + n, 0, MD5_CBLOCK - 8 - n);
  p += MD5_CBLOCK - 8;
  (void)(*((unsigned int *)(p)) = (c->Nl), (p) += 4, c->Nl);
  (void)(*((unsigned int *)(p)) = (c->Nh), (p) += 4, c->Nh);
  p -= MD5_CBLOCK;
  md5_block_data_order(c, p, 1);
  c->num = 0;
  OPENSSL_cleanse(p, MD5_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
  } while (0);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fahr_to_celc@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x14,-0x4(%rbp)
L9:
  cmpl   $0x12c,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %d	%d


assistant: ```c
int main() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr += 20) {
    printf("%d\t%d\n", fahr, fahr_to_celc(fahr));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D2(%rip),%rbp
L4:
  mov    %ebx,%edi
  call   <fahr_to_celc@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  cmp    $0x140,%ebx
  jne    L4
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: %d	%d


assistant: ```c
int main() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr += 20) {
    printf("%d\t%d\n", fahr, fahr_to_celc(fahr));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  call   <fahr_to_celc@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x14,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string

tool: D2: %d	%d


assistant: ```c
int main() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr += 20) {
    printf("%d\t%d\n", fahr, fahr_to_celc(fahr));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  call   <fahr_to_celc@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x14,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: %d	%d


assistant: ```c
int main() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr += 20) {
    printf("%d\t%d\n", fahr, fahr_to_celc(fahr));
  }
  return 0;
}
```