ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<spi_n>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x1,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %ecx,(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %esi,0x14(%rsp)
  movl   $0xf4240,0x4(%rsp)
  movq   $0x8,0x8(%rsp)
  call   <SPI_IOC_MESSAGE@plt>
  mov    %r12d,%edi
  mov    %rsp,%rdx
  xor    %r12d,%r12d
  mov    %eax,%esi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L2
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D4(%rip),%rdi
  mov    %eax,%r12d
  call   <perror@plt>
  jmp    L0
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: SPI transfer error

assistant: ```c
int spi_n(int fd, uint8_t *tx, uint8_t *rx, int len) {
  int ret;
  struct spi_ioc_transfer tr = {
      .tx_buf = (__u32)tx,
      .rx_buf = (__u32)rx,
      .len = len,
      .delay_usecs = 0,
      .speed_hz = 1000000,
      .bits_per_word = 8,
  };
  if ((ret = ioctl(fd, SPI_IOC_MESSAGE(1), &tr)) < 0) {
    perror("SPI transfer error");
    return ret;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ChecksumNmeaLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  cmp    $0x24,%al
  je     L50
  mov    $0x0,%eax
  jmp    L94
L50:
  movl   $0x0,-0x24(%rbp)
  jmp    L82
L4:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0x24(%rbp)
L82:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L102
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L4
L102:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L5
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%edx
  mov    -0x24(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L77
  mov    $0x0,%eax
  jmp    L94
L77:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%edx
  mov    -0x24(%rbp),%eax
  and    $0xf,%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L62
  mov    $0x0,%eax
  jmp    L94
L62:
  mov    $0x1,%eax
  jmp    L94
L5:
  mov    $0x0,%eax
L94:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

assistant: ```c
int ChecksumNmeaLine(const char *in) {
  const char hexdigits[] = "0123456789ABCDEF";
  if (*in++ != '$') {
    return 0;
  }
  int val = 0;
  while (*in != '*' && *in != '\r') {
    val ^= *in++;
  }
  if (*in++ == '*') {
    if (*in++ != hexdigits[((val >> 4) & 0xf)]) {
      return 0;
    }
    if (*in++ != hexdigits[(val & 0xf)]) {
      return 0;
    }
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ChecksumNmeaLine>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movb   $0x0,0x10(%rsp)
  mov    $0x0,%esi
  cmpb   $0x24,(%rdi)
  jne    L8
  lea    0x1(%rdi),%rdx
  movzbl 0x1(%rdi),%eax
  cmp    $0x2a,%al
  je     L57
  cmp    $0xd,%al
  je     L57
  mov    $0x0,%ecx
L38:
  add    $0x1,%rdx
  movsbl %al,%eax
  xor    %eax,%ecx
  movzbl (%rdx),%eax
  cmp    $0x2a,%al
  je     L33
  cmp    $0xd,%al
  jne    L38
L33:
  mov    $0x0,%esi
  cmp    $0x2a,%al
  je     L24
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %esi,%eax
  add    $0x28,%rsp
  ret
L57:
  mov    $0x0,%ecx
  jmp    L33
L24:
  mov    %ecx,%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  movzbl (%rsp,%rax,1),%eax
  cmp    %al,0x1(%rdx)
  jne    L8
  and    $0xf,%ecx
  movzbl 0x2(%rdx),%eax
  cmp    %al,(%rsp,%rcx,1)
  sete   %sil
  movzbl %sil,%esi
  jmp    L8
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ChecksumNmeaLine(const char *in) {
  const char hexdigits[] = "0123456789ABCDEF";
  if (*in++ != '$') {
    return 0;
  }
  int val = 0;
  while (*in != '*' && *in != '\r') {
    val ^= *in++;
  }
  if (*in++ == '*') {
    if (*in++ != hexdigits[((val >> 4) & 0xf)]) {
      return 0;
    }
    if (*in++ != hexdigits[(val & 0xf)]) {
      return 0;
    }
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ChecksumNmeaLine>:
  endbr64
  sub    $0x28,%rsp
  movdqa D1(%rip),%xmm0
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0x24,(%rdi)
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  jne    L23
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %ecx,%ecx
  cmp    $0xd,%al
  je     L4
  cmp    $0x2a,%al
  je     L4
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%rdx
  xor    %eax,%ecx
  movsbl (%rdx),%eax
  cmp    $0x2a,%al
  je     L4
  cmp    $0xd,%al
  jne    L42
L4:
  xor    %r8d,%r8d
  cmp    $0x2a,%al
  je     L18
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    %r8d,%eax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ecx,%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  movzbl (%rsp,%rax,1),%eax
  cmp    %al,0x1(%rdx)
  jne    L23
  and    $0xf,%ecx
  xor    %r8d,%r8d
  movzbl 0x2(%rdx),%eax
  cmp    %al,(%rsp,%rcx,1)
  sete   %r8b
  jmp    L23
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: byte[16]

tool: {"D1": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
int ChecksumNmeaLine(const char *in) {
  const char hexdigits[] = "0123456789ABCDEF";
  if (*in++ != '$') {
    return 0;
  }
  int val = 0;
  while (*in != '*' && *in != '\r') {
    val ^= *in++;
  }
  if (*in++ == '*') {
    if (*in++ != hexdigits[((val >> 4) & 0xf)]) {
      return 0;
    }
    if (*in++ != hexdigits[(val & 0xf)]) {
      return 0;
    }
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ChecksumNmeaLine>:
  endbr64
  sub    $0x28,%rsp
  movdqa D1(%rip),%xmm0
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0x24,(%rdi)
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  jne    L50
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %ecx,%ecx
  cmp    $0xd,%al
  je     L75
  cmp    $0x2a,%al
  je     L75
  nopl   0x0(%rax,%rax,1)
L88:
  add    $0x1,%rdx
  xor    %eax,%ecx
  movsbl (%rdx),%eax
  cmp    $0x2a,%al
  je     L75
  cmp    $0xd,%al
  jne    L88
L75:
  xor    %r8d,%r8d
  cmp    $0x2a,%al
  je     L60
L50:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  mov    %r8d,%eax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  mov    %ecx,%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  movzbl (%rsp,%rax,1),%eax
  cmp    %al,0x1(%rdx)
  jne    L50
  and    $0xf,%ecx
  xor    %r8d,%r8d
  movzbl 0x2(%rdx),%eax
  cmp    %al,(%rsp,%rcx,1)
  sete   %r8b
  jmp    L50
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: byte[16]

tool: {"D1": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
int ChecksumNmeaLine(const char *in) {
  const char hexdigits[] = "0123456789ABCDEF";
  if (*in++ != '$') {
    return 0;
  }
  int val = 0;
  while (*in != '*' && *in != '\r') {
    val ^= *in++;
  }
  if (*in++ == '*') {
    if (*in++ != hexdigits[((val >> 4) & 0xf)]) {
      return 0;
    }
    if (*in++ != hexdigits[(val & 0xf)]) {
      return 0;
    }
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<domts_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x20(%rbp)
  jbe    L7
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L12
L7:
  mov    -0x20(%rbp),%rax
L12:
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *domts_strndup(const char *s, size_t len) {
  size_t retlen = ((strlen(s)) < (len) ? (strlen(s)) : (len));
  char *ret = calloc(retlen + 1, 1);
  memcpy(ret, s, retlen);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<domts_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmovbe %rax,%rbx
  lea    0x1(%rbx),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *domts_strndup(const char *s, size_t len) {
  size_t retlen = ((strlen(s)) < (len) ? (strlen(s)) : (len));
  char *ret = calloc(retlen + 1, 1);
  memcpy(ret, s, retlen);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<domts_strndup>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  cmp    %r12,%rax
  cmovbe %rax,%r12
  lea    0x1(%r12),%rdi
  call   <calloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *domts_strndup(const char *s, size_t len) {
  size_t retlen = ((strlen(s)) < (len) ? (strlen(s)) : (len));
  char *ret = calloc(retlen + 1, 1);
  memcpy(ret, s, retlen);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<domts_strndup>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  cmp    %r12,%rax
  cmovbe %rax,%r12
  lea    0x1(%r12),%rdi
  call   <calloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *domts_strndup(const char *s, size_t len) {
  size_t retlen = ((strlen(s)) < (len) ? (strlen(s)) : (len));
  char *ret = calloc(retlen + 1, 1);
  memcpy(ret, s, retlen);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mcfio_infoblockchar_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9d,-0x3c(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x38(%rbp),%rdi
  mov    -0x8(%rbp),%rcx
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <mcfioC_InfoBlockChar@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L2
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void mcfio_infoblockchar_(int *Event, int *blkId, int *key, char *answer, int *lret, int length) {
  char *aString;
  int ll1;
  aString = (char *)malloc(sizeof(char) * (FILENAME_MAX + 1));
  mcfioC_InfoBlockChar(*Event, *blkId, *key, aString, lret);
  ll1 = *lret;
  if (ll1 > length)
    ll1 = length;
  strncpy(answer, aString, ll1);
  free(aString);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mcfio_infoblockchar_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    %rcx,0x8(%rsp)
  mov    %r8,%r12
  mov    %r9d,%ebx
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%r8
  mov    %rax,%rcx
  mov    (%r15),%edx
  mov    (%r14),%esi
  mov    0x0(%r13),%edi
  call   <mcfioC_InfoBlockChar@plt>
  mov    (%r12),%eax
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mcfio_infoblockchar_(int *Event, int *blkId, int *key, char *answer, int *lret, int length) {
  char *aString;
  int ll1;
  aString = (char *)malloc(sizeof(char) * (FILENAME_MAX + 1));
  mcfioC_InfoBlockChar(*Event, *blkId, *key, aString, lret);
  ll1 = *lret;
  if (ll1 > length)
    ll1 = length;
  strncpy(answer, aString, ll1);
  free(aString);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mcfio_infoblockchar_>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x18,%rsp
  mov    D9(%rip),%rax
  mov    %rdx,0x8(%rsp)
  mov    (%rax),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%rdx
  mov    (%r15),%esi
  mov    %r12,%r8
  mov    (%r14),%edi
  mov    %rax,%rcx
  mov    %rax,%rbp
  mov    (%rdx),%edx
  call   <mcfioC_InfoBlockChar@plt>
  mov    (%r12),%eax
  mov    %r13,%rdi
  mov    %rbp,%rsi
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  mov    %eax,%edx
  call   <strncpy@plt>
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free@plt>
```

assistant: ```c
void mcfio_infoblockchar_(int *Event, int *blkId, int *key, char *answer, int *lret, int length) {
  char *aString;
  int ll1;
  aString = (char *)malloc(sizeof(char) * (FILENAME_MAX + 1));
  mcfioC_InfoBlockChar(*Event, *blkId, *key, aString, lret);
  ll1 = *lret;
  if (ll1 > length)
    ll1 = length;
  strncpy(answer, aString, ll1);
  free(aString);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mcfio_infoblockchar_>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x18,%rsp
  mov    D2(%rip),%rax
  mov    %rdx,0x8(%rsp)
  mov    (%rax),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%rdx
  mov    (%r15),%esi
  mov    %r12,%r8
  mov    (%r14),%edi
  mov    %rax,%rcx
  mov    %rax,%rbp
  mov    (%rdx),%edx
  call   <mcfioC_InfoBlockChar@plt>
  mov    (%r12),%eax
  mov    %r13,%rdi
  mov    %rbp,%rsi
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  mov    %eax,%edx
  call   <strncpy@plt>
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free@plt>
```

assistant: ```c
void mcfio_infoblockchar_(int *Event, int *blkId, int *key, char *answer, int *lret, int length) {
  char *aString;
  int ll1;
  aString = (char *)malloc(sizeof(char) * (FILENAME_MAX + 1));
  mcfioC_InfoBlockChar(*Event, *blkId, *key, aString, lret);
  ll1 = *lret;
  if (ll1 > length)
    ll1 = length;
  strncpy(answer, aString, ll1);
  free(aString);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<create_subdir_cleanup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L48
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L48:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L49
L13:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <rmdir@plt>
  mov    -0x20(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L35
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L35:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L21
L49:
  nop
L21:
  leave
  ret
```

assistant: ```c
void create_subdir_cleanup(char *root_dir, char *path) {
  char *root_dir_int, *slash;
  root_dir_int = strdup(root_dir);
  if (root_dir_int[strlen(root_dir_int) - 1] == '/')
    root_dir_int[strlen(root_dir_int) - 1] = '\0';
  if (!strcasecmp(root_dir_int, path))
    return;
  do {
    rmdir(path);
    slash = strrchr(path, '/');
    if (slash)
      *slash = '\0';
  } while (strcasecmp(root_dir_int, path));
  free(root_dir_int);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<create_subdir_cleanup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  je     L6
L19:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L53
  jmp    L50
L6:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L19
L16:
  movb   $0x0,(%rax)
L14:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L68
L53:
  mov    %rbx,%rdi
  call   <rmdir@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L16
  jmp    L14
L68:
  mov    %rbp,%rdi
  call   <free@plt>
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void create_subdir_cleanup(char *root_dir, char *path) {
  char *root_dir_int, *slash;
  root_dir_int = strdup(root_dir);
  if (root_dir_int[strlen(root_dir_int) - 1] == '/')
    root_dir_int[strlen(root_dir_int) - 1] = '\0';
  if (!strcasecmp(root_dir_int, path))
    return;
  do {
    rmdir(path);
    slash = strrchr(path, '/');
    if (slash)
      *slash = '\0';
  } while (strcasecmp(root_dir_int, path));
  free(root_dir_int);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<create_subdir_cleanup>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  je     L49
L34:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L31
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  call   <rmdir@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L21
  movb   $0x0,(%rax)
L21:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10a0 <free@plt>
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L34
```

assistant: ```c
void create_subdir_cleanup(char *root_dir, char *path) {
  char *root_dir_int, *slash;
  root_dir_int = strdup(root_dir);
  if (root_dir_int[strlen(root_dir_int) - 1] == '/')
    root_dir_int[strlen(root_dir_int) - 1] = '\0';
  if (!strcasecmp(root_dir_int, path))
    return;
  do {
    rmdir(path);
    slash = strrchr(path, '/');
    if (slash)
      *slash = '\0';
  } while (strcasecmp(root_dir_int, path));
  free(root_dir_int);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<create_subdir_cleanup>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  je     L23
L40:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L5
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    %rbx,%rdi
  call   <rmdir@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax)
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L41
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10a0 <free@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L40
```

assistant: ```c
void create_subdir_cleanup(char *root_dir, char *path) {
  char *root_dir_int, *slash;
  root_dir_int = strdup(root_dir);
  if (root_dir_int[strlen(root_dir_int) - 1] == '/')
    root_dir_int[strlen(root_dir_int) - 1] = '\0';
  if (!strcasecmp(root_dir_int, path))
    return;
  do {
    rmdir(path);
    slash = strrchr(path, '/');
    if (slash)
      *slash = '\0';
  } while (strcasecmp(root_dir_int, path));
  free(root_dir_int);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<closeSysFiles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void closeSysFiles(int fdStat, int fdMem, int fdLoad, int fdDisk) {
  close(fdStat);
  close(fdMem);
  close(fdLoad);
  close(fdDisk);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<closeSysFiles>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%ebx
  call   <close@plt>
  mov    %r12d,%edi
  call   <close@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    %ebx,%edi
  call   <close@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void closeSysFiles(int fdStat, int fdMem, int fdLoad, int fdDisk) {
  close(fdStat);
  close(fdMem);
  close(fdLoad);
  close(fdDisk);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<closeSysFiles>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  call   <close@plt>
  mov    %r13d,%edi
  call   <close@plt>
  mov    %r12d,%edi
  call   <close@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <close@plt>
```

assistant: ```c
void closeSysFiles(int fdStat, int fdMem, int fdLoad, int fdDisk) {
  close(fdStat);
  close(fdMem);
  close(fdLoad);
  close(fdDisk);
  return;
}
```