ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<nwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L7
L17:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L7:
  cmpl   $0x0,-0x18(%rbp)
  jne    L17
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int nwd(int a, int b) {
  while (b != 0) {
    int temp = a % b;
    a = b;
    b = temp;
  }
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nwd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L16
L18:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L18
L15:
  mov    %ecx,%eax
  ret
L16:
  mov    %edi,%ecx
  jmp    L15
```

assistant: ```c
int nwd(int a, int b) {
  while (b != 0) {
    int temp = a % b;
    a = b;
    b = temp;
  }
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nwd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L14
  nopl   0x0(%rax)
L19:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L19
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nwd(int a, int b) {
  while (b != 0) {
    int temp = a % b;
    a = b;
    b = temp;
  }
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<nwd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L17
  nopl   0x0(%rax)
L18:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L18
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nwd(int a, int b) {
  while (b != 0) {
    int temp = a % b;
    a = b;
    b = temp;
  }
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nChancellors>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    $0x0,%edx
  call   <findnextSlot@plt>
  test   %eax,%eax
  js     L153
  mov    %eax,%ebx
  movslq %r13d,%rax
  lea    -0x4(%r12,%rax,4),%r15
  movl   $0x0,0x8(%rsp)
  lea    -0x1(%r13),%eax
  mov    %eax,0xc(%rsp)
  jmp    L144
L53:
  addl   $0x1,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <getPosition@plt>
  cmp    %r13d,%eax
  jge    L27
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <checkConflict@plt>
  test   %rax,%rax
  jne    L53
  jmp    L27
L23:
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <printBoard@plt>
  jmp    L93
L14:
  cmpl   $0x0,(%r15)
  js     L152
L136:
  cmpl   $0x0,0x0(%rbp)
  jle    L85
  movl   $0x0,0x0(%rbp)
L85:
  lea    -0x1(%rbx),%eax
  sub    $0x2,%ebx
  cmpl   $0x0,-0x4(%r12,%r14,1)
  js     L93
  mov    %eax,%ebx
L93:
  test   %ebx,%ebx
  js     L162
L144:
  movslq %ebx,%r14
  shl    $0x2,%r14
  lea    (%r12,%r14,1),%rbp
  cmpl   $0x0,0x0(%rbp)
  jns    L53
L27:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <getPosition@plt>
  cmp    %r13d,%eax
  jge    L14
  cmpl   $0x0,0x0(%rbp)
  js     L14
  cmp    %ebx,0xc(%rsp)
  jle    L23
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <findnextSlot@plt>
  mov    %eax,%ebx
  jmp    L93
L152:
  cmp    %ebx,0xc(%rsp)
  jne    L136
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <printBoard@plt>
  jmp    L136
L153:
  movl   $0x0,0x8(%rsp)
L162:
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nChancellors(int *board, int n) {
  int solutions = 0;
  int x = findnextSlot(board, n, 0);
  while (x >= 0) {
    if (board[x] >= 0)
      do
        board[x]++;
      while (getPosition(board, x) < n && checkConflict(board, n, x));
    if (getPosition(board, x) < n && board[x] >= 0) {
      if (x < n - 1)
        x = findnextSlot(board, n, x);
      else
        printBoard(board, n, ++solutions);
    } else {
      if (board[n - 1] < 0 && x == n - 1)
        printBoard(board, n, ++solutions);
      if (board[x] > 0)
        board[x] = 0;
      if (board[--x] < 0)
        x--;
    }
  }
  return solutions;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nChancellors>:
  endbr64
  push   %r15
  xor    %edx,%edx
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <findnextSlot@plt>
  test   %eax,%eax
  js     L23
  mov    %eax,%r15d
  movslq %r12d,%rax
  movl   $0x0,0x8(%rsp)
  lea    -0x4(%rbx,%rax,4),%rax
  movslq %r15d,%r14
  mov    %rax,(%rsp)
  lea    -0x1(%r12),%eax
  mov    %eax,0xc(%rsp)
  nopw   0x0(%rax,%rax,1)
L116:
  lea    0x0(,%r14,4),%r13
  lea    (%rbx,%r13,1),%rbp
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jns    L85
L73:
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <getPosition@plt>
  cmp    %r12d,%eax
  jge    L160
L141:
  mov    0x0(%rbp),%edi
  test   %edi,%edi
  js     L160
  cmp    %r15d,0xc(%rsp)
  jle    L121
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <findnextSlot@plt>
  mov    %eax,%r15d
L124:
  test   %r15d,%r15d
  js     L36
L173:
  movslq %r15d,%r14
  jmp    L116
L27:
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <checkConflict@plt>
  test   %rax,%rax
  je     L73
  mov    0x0(%rbp),%eax
L85:
  add    $0x1,%eax
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mov    %eax,0x0(%rbp)
  call   <getPosition@plt>
  cmp    %r12d,%eax
  jl     L27
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <getPosition@plt>
  cmp    %r12d,%eax
  jl     L141
  nopl   0x0(%rax)
L160:
  mov    (%rsp),%rax
  mov    (%rax),%esi
  test   %esi,%esi
  js     L47
L17:
  mov    0x0(%rbp),%ecx
  test   %ecx,%ecx
  jle    L161
  movl   $0x0,0x0(%rbp)
L161:
  mov    -0x4(%rbx,%r13,1),%edx
  lea    -0x1(%r15),%eax
  sub    $0x2,%r15d
  test   %edx,%edx
  js     L124
  mov    %eax,%r15d
  test   %r15d,%r15d
  jns    L173
L36:
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L47:
  cmp    %r15d,0xc(%rsp)
  jne    L17
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printBoard@plt>
  jmp    L17
  nopl   (%rax)
L121:
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printBoard@plt>
  jmp    L116
L23:
  movl   $0x0,0x8(%rsp)
  jmp    L36
```

assistant: ```c
int nChancellors(int *board, int n) {
  int solutions = 0;
  int x = findnextSlot(board, n, 0);
  while (x >= 0) {
    if (board[x] >= 0)
      do
        board[x]++;
      while (getPosition(board, x) < n && checkConflict(board, n, x));
    if (getPosition(board, x) < n && board[x] >= 0) {
      if (x < n - 1)
        x = findnextSlot(board, n, x);
      else
        printBoard(board, n, ++solutions);
    } else {
      if (board[n - 1] < 0 && x == n - 1)
        printBoard(board, n, ++solutions);
      if (board[x] > 0)
        board[x] = 0;
      if (board[--x] < 0)
        x--;
    }
  }
  return solutions;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nChancellors>:
  endbr64
  push   %r15
  xor    %edx,%edx
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <findnextSlot@plt>
  test   %eax,%eax
  js     L105
  mov    %eax,%r15d
  movslq %r12d,%rax
  movl   $0x0,0x8(%rsp)
  lea    -0x4(%rbx,%rax,4),%rax
  movslq %r15d,%r14
  mov    %rax,(%rsp)
  lea    -0x1(%r12),%eax
  mov    %eax,0xc(%rsp)
  nopw   0x0(%rax,%rax,1)
L31:
  lea    0x0(,%r14,4),%r13
  lea    (%rbx,%r13,1),%rbp
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jns    L96
L142:
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <getPosition@plt>
  cmp    %r12d,%eax
  jge    L135
L131:
  mov    0x0(%rbp),%edi
  test   %edi,%edi
  js     L135
  cmp    %r15d,0xc(%rsp)
  jle    L92
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <findnextSlot@plt>
  mov    %eax,%r15d
L11:
  test   %r15d,%r15d
  js     L45
L74:
  movslq %r15d,%r14
  jmp    L31
L7:
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <checkConflict@plt>
  test   %rax,%rax
  je     L142
  mov    0x0(%rbp),%eax
L96:
  add    $0x1,%eax
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mov    %eax,0x0(%rbp)
  call   <getPosition@plt>
  cmp    %r12d,%eax
  jl     L7
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <getPosition@plt>
  cmp    %r12d,%eax
  jl     L131
  nopl   0x0(%rax)
L135:
  mov    (%rsp),%rax
  mov    (%rax),%esi
  test   %esi,%esi
  js     L65
L75:
  mov    0x0(%rbp),%ecx
  test   %ecx,%ecx
  jle    L134
  movl   $0x0,0x0(%rbp)
L134:
  mov    -0x4(%rbx,%r13,1),%edx
  lea    -0x1(%r15),%eax
  sub    $0x2,%r15d
  test   %edx,%edx
  js     L11
  mov    %eax,%r15d
  test   %r15d,%r15d
  jns    L74
L45:
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L65:
  cmp    %r15d,0xc(%rsp)
  jne    L75
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printBoard@plt>
  jmp    L75
  nopl   (%rax)
L92:
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printBoard@plt>
  jmp    L31
L105:
  movl   $0x0,0x8(%rsp)
  jmp    L45
```

assistant: ```c
int nChancellors(int *board, int n) {
  int solutions = 0;
  int x = findnextSlot(board, n, 0);
  while (x >= 0) {
    if (board[x] >= 0)
      do
        board[x]++;
      while (getPosition(board, x) < n && checkConflict(board, n, x));
    if (getPosition(board, x) < n && board[x] >= 0) {
      if (x < n - 1)
        x = findnextSlot(board, n, x);
      else
        printBoard(board, n, ++solutions);
    } else {
      if (board[n - 1] < 0 && x == n - 1)
        printBoard(board, n, ++solutions);
      if (board[x] > 0)
        board[x] = 0;
      if (board[--x] < 0)
        x--;
    }
  }
  return solutions;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
L61:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L32:
  movsbl -0x1(%rbp),%eax
  cmp    $0x5c,%eax
  je     L98
  cmp    $0x5c,%eax
  jg     L53
  cmp    $0x8,%eax
  je     L12
  cmp    $0x9,%eax
  jne    L53
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L12:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L98:
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L53:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  nop
L45:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0xa,-0x1(%rbp)
  jne    L32
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L61
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D32
type_guessed: string
name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D33
type_guessed: string

tool: D19: >>> 

tool: D32: \t

tool: D28: \b

tool: D33: \\

assistant: ```c
int main(int argc, const char **argv) {
  char c;
  while (1) {
    printf(">>> ");
    while ((c = getchar()) != '\n') {
      switch (c) {
      case '\t':
        printf("\\t");
        break;
      case '\b':
        printf("\\b");
        break;
      case '\\':
        printf("\\\\");
        break;
      default:
        putchar(c);
        break;
      }
    }
    putchar('\n');
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D3(%rip),%rbp
  lea    D35(%rip),%r13
  lea    D12(%rip),%r12
  jmp    L0
L25:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L24
L15:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L24
L76:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L24
L85:
  mov    $0xa,%edi
  call   <putchar@plt>
L0:
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D30(%rip),%rbx
L24:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L85
  cmp    $0x9,%al
  je     L25
  cmp    $0x5c,%al
  je     L76
  cmp    $0x8,%al
  je     L15
  movsbl %al,%edi
  call   <putchar@plt>
  jmp    L24
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string
name: unpack_data
arguments: label: D35
type_infered: string
name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: string

tool: D3: >>> 

tool: D35: \t

tool: D12: \\

tool: D30: \b

assistant: ```c
int main(int argc, const char **argv) {
  char c;
  while (1) {
    printf(">>> ");
    while ((c = getchar()) != '\n') {
      switch (c) {
      case '\t':
        printf("\\t");
        break;
      case '\b':
        printf("\\b");
        break;
      case '\\':
        printf("\\\\");
        break;
      default:
        putchar(c);
        break;
      }
    }
    putchar('\n');
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  lea    D36(%rip),%rbp
  push   %rbx
  lea    D35(%rip),%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %rbx,%rdi
  call   <printf@plt>
L47:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L45
L40:
  cmp    $0x9,%al
  je     L21
  cmp    $0x5c,%al
  je     L39
  cmp    $0x8,%al
  je     L42
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L40
  nopw   0x0(%rax,%rax,1)
L45:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L74
  nopl   0x0(%rax)
L42:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L47
```

tool_calls: name: read_data
arguments: label: D12
data_type: string
name: read_data
arguments: label: D26
data_type: string
name: read_data
arguments: label: D36
data_type: string
name: read_data
arguments: label: D35
data_type: string

tool: D12: \t

tool: D26: \b

tool: D36: \\

tool: D35: >>> 

assistant: ```c
int main(int argc, const char **argv) {
  char c;
  while (1) {
    printf(">>> ");
    while ((c = getchar()) != '\n') {
      switch (c) {
      case '\t':
        printf("\\t");
        break;
      case '\b':
        printf("\\b");
        break;
      case '\\':
        printf("\\\\");
        break;
      default:
        putchar(c);
        break;
      }
    }
    putchar('\n');
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D37(%rip),%r13
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  lea    D31(%rip),%rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %rbx,%rdi
  call   <printf@plt>
L23:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L61
L43:
  cmp    $0x9,%al
  je     L76
  cmp    $0x5c,%al
  je     L19
  cmp    $0x8,%al
  je     L58
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L43
  nopw   0x0(%rax,%rax,1)
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L47
  nopl   0x0(%rax)
L58:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L76:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: data_tag: D37
type_infered: string
name: retrieve_data
arguments: data_tag: D34
type_infered: string
name: retrieve_data
arguments: data_tag: D31
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string

tool: D37: \t

tool: D34: \b

tool: D31: \\

tool: D15: >>> 

assistant: ```c
int main(int argc, const char **argv) {
  char c;
  while (1) {
    printf(">>> ");
    while ((c = getchar()) != '\n') {
      switch (c) {
      case '\t':
        printf("\\t");
        break;
      case '\b':
        printf("\\b");
        break;
      case '\\':
        printf("\\\\");
        break;
      default:
        putchar(c);
        break;
      }
    }
    putchar('\n');
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fov>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movss  %xmm0,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D12(%rip),%xmm0
  movss  %xmm0,-0x34(%rbp)
  movss  -0x44(%rbp),%xmm0
  mulss  -0x34(%rbp),%xmm0
  cvttss2si %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    $0x8504f35f,%eax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  movss  -0x44(%rbp),%xmm1
  movss  D19(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x30(%rbp)
  movss  -0x44(%rbp),%xmm0
  movss  %xmm0,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x2c(%rbp)
  lea    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movss  -0x38(%rbp),%xmm1
  movss  -0x38(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  mulss  -0x30(%rbp),%xmm0
  cvttss2si %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  sar    %rax
  mov    %rax,%rdx
  mov    $0x5f3759df,%eax
  sub    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  -0x44(%rbp),%xmm0
  addss  -0x34(%rbp),%xmm0
  cvttss2si %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movss  -0x38(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x30(%rbp),%xmm1
  movss  -0x38(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  -0x34(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x38(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  -0x38(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: byte[4]
name: unpack_data
arguments: label: D19
type_infered: byte[4]

tool: {"D12": [0x00,0x00,0xc0,0x3f]}

tool: {"D19": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float fov(float z) {
  long a, e, f, h;
  float b, c, g;
  const float d = 1.5F;
  e = z * d;
  f = 0x8504f35f - (e << 3);
  b = z * 0.5F;
  c = z;
  g = f << 2;
  a = *(long *)&c;
  f = a;
  a = c * c * b;
  a = 0x5f3759df - (f >> 1);
  c = *(float *)&a;
  h = z + d;
  c = c * (d - (b * c * c));
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fov>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mov    -0x4(%rsp),%rdx
  sar    %rdx
  mov    $0x5f3759df,%eax
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  D8(%rip),%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  movss  D17(%rip),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: byte[4]
name: retrieve_data
arguments: label: D17
type_infered: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x3f]}

tool: {"D17": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float fov(float z) {
  long a, e, f, h;
  float b, c, g;
  const float d = 1.5F;
  e = z * d;
  f = 0x8504f35f - (e << 3);
  b = z * 0.5F;
  c = z;
  g = f << 2;
  a = *(long *)&c;
  f = a;
  a = c * c * b;
  a = 0x5f3759df - (f >> 1);
  c = *(float *)&a;
  h = z + d;
  c = c * (d - (b * c * c));
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fov>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mulss  D19(%rip),%xmm0
  mov    -0x4(%rsp),%rdx
  mov    $0x5f3759df,%eax
  movss  D7(%rip),%xmm1
  sar    %rdx
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D7
datatype: byte[4]

tool: {"D19": [0x00,0x00,0x00,0x3f]}

tool: {"D7": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float fov(float z) {
  long a, e, f, h;
  float b, c, g;
  const float d = 1.5F;
  e = z * d;
  f = 0x8504f35f - (e << 3);
  b = z * 0.5F;
  c = z;
  g = f << 2;
  a = *(long *)&c;
  f = a;
  a = c * c * b;
  a = 0x5f3759df - (f >> 1);
  c = *(float *)&a;
  h = z + d;
  c = c * (d - (b * c * c));
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fov>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mulss  D9(%rip),%xmm0
  mov    -0x4(%rsp),%rdx
  mov    $0x5f3759df,%eax
  movss  D6(%rip),%xmm1
  sar    %rdx
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: byte[4]
name: read_data
arguments: data_label: D6
type_guessed: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x3f]}

tool: {"D6": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float fov(float z) {
  long a, e, f, h;
  float b, c, g;
  const float d = 1.5F;
  e = z * d;
  f = 0x8504f35f - (e << 3);
  b = z * 0.5F;
  c = z;
  g = f << 2;
  a = *(long *)&c;
  f = a;
  a = c * c * b;
  a = 0x5f3759df - (f >> 1);
  c = *(float *)&a;
  h = z + d;
  c = c * (d - (b * c * c));
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L78
  mov    $0xffffffff,%eax
  jmp    L35
L78:
  cmpl   $0x2,-0x4(%rbp)
  je     L32
  cmpl   $0x3,-0x4(%rbp)
  jne    L40
L32:
  mov    $0x1,%eax
  jmp    L35
L40:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L10
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L69
L10:
  mov    $0x0,%eax
  jmp    L35
L69:
  mov    $0x1,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(int in) {
  if (in < 2)
    return -1;
  if (in == 2 || in == 3)
    return 1;
  if (in % 2 == 0 || in % 3 == 0)
    return 0;
  else
    return 1;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_prime>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    $0x1,%edi
  jle    L6
  lea    -0x2(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  jbe    L6
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L6
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  setne  %al
  movzbl %al,%eax
L6:
  ret
```

assistant: ```c
int is_prime(int in) {
  if (in < 2)
    return -1;
  if (in == 2 || in == 3)
    return 1;
  if (in % 2 == 0 || in % 3 == 0)
    return 0;
  else
    return 1;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_prime>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    $0x1,%edi
  jle    L17
  lea    -0x2(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  jbe    L17
  xor    %eax,%eax
  test   $0x1,%dil
  je     L17
  imul   $0xaaaaaaab,%edi,%edi
  xor    %eax,%eax
  add    $0x2aaaaaaa,%edi
  cmp    $0x55555554,%edi
  seta   %al
L17:
  ret
```

assistant: ```c
int is_prime(int in) {
  if (in < 2)
    return -1;
  if (in == 2 || in == 3)
    return 1;
  if (in % 2 == 0 || in % 3 == 0)
    return 0;
  else
    return 1;
  return -1;
}
```