ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<procuraTodos>:
  endbr64
  mov    %rdi,%r9
  test   %esi,%esi
  jle    L20
  mov    %esi,%esi
  mov    $0x0,%eax
  jmp    L14
L33:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L20
L14:
  cmp    %edx,(%r9,%rax,4)
  jne    L33
  mov    (%r8),%edi
  lea    0x1(%rdi),%r10d
  mov    %r10d,(%r8)
  movslq %edi,%rdi
  mov    %eax,(%rcx,%rdi,4)
  jmp    L33
L20:
  cmpl   $0x0,(%r8)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int procuraTodos(int *v, int N, int x, int *posicoes, int *nPosicoes) {
  for (int i = 0; i < N; ++i) {
    if (v[i] == x) {
      posicoes[(*nPosicoes)++] = i;
    }
  }
  return (*nPosicoes) != 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<procuraTodos>:
  endbr64
  movslq %esi,%r9
  xor    %eax,%eax
  test   %esi,%esi
  jle    L9
  nopl   (%rax)
L26:
  cmp    %edx,(%rdi,%rax,4)
  jne    L23
  movslq (%r8),%rsi
  lea    0x1(%rsi),%r10d
  mov    %r10d,(%r8)
  mov    %eax,(%rcx,%rsi,4)
L23:
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L26
L9:
  mov    (%r8),%edx
  xor    %eax,%eax
  test   %edx,%edx
  setne  %al
  ret
```

assistant: ```c
int procuraTodos(int *v, int N, int x, int *posicoes, int *nPosicoes) {
  for (int i = 0; i < N; ++i) {
    if (v[i] == x) {
      posicoes[(*nPosicoes)++] = i;
    }
  }
  return (*nPosicoes) != 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<procuraTodos>:
  endbr64
  movslq %esi,%r9
  xor    %eax,%eax
  test   %esi,%esi
  jle    L10
  nopl   (%rax)
L2:
  cmp    %edx,(%rdi,%rax,4)
  jne    L7
  movslq (%r8),%rsi
  lea    0x1(%rsi),%r10d
  mov    %r10d,(%r8)
  mov    %eax,(%rcx,%rsi,4)
L7:
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L2
L10:
  mov    (%r8),%edx
  xor    %eax,%eax
  test   %edx,%edx
  setne  %al
  ret
```

assistant: ```c
int procuraTodos(int *v, int N, int x, int *posicoes, int *nPosicoes) {
  for (int i = 0; i < N; ++i) {
    if (v[i] == x) {
      posicoes[(*nPosicoes)++] = i;
    }
  }
  return (*nPosicoes) != 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fibo1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L31
  mov    $0x0,%eax
  jmp    L38
L31:
  cmpl   $0x1,-0x14(%rbp)
  jne    L0
  mov    $0x1,%eax
  jmp    L38
L0:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibo2@plt>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibo2@plt>
  add    %ebx,%eax
L38:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibo1(int n) {
  if (n < 1) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return fibo2(n - 1) + fibo2(n - 2);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fibo1>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  jle    L15
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    $0x1,%edi
  jne    L2
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    -0x1(%rdi),%edi
  call   <fibo2@plt>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fibo2@plt>
  add    %ebp,%eax
  jmp    L26
L15:
  ret
```

assistant: ```c
int fibo1(int n) {
  if (n < 1) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return fibo2(n - 1) + fibo2(n - 2);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fibo1>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L9
  push   %rbp
  mov    $0x1,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x1(%rdi),%edi
  call   <fibo2@plt>
  lea    -0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <fibo2@plt>
  add    $0x8,%rsp
  add    %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
int fibo1(int n) {
  if (n < 1) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return fibo2(n - 1) + fibo2(n - 2);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fibo1>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L8
  push   %rbp
  mov    $0x1,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  lea    -0x1(%rdi),%edi
  call   <fibo2@plt>
  lea    -0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <fibo2@plt>
  add    $0x8,%rsp
  add    %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
int fibo1(int n) {
  if (n < 1) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return fibo2(n - 1) + fibo2(n - 2);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  cmpl   $0x2,-0x34(%rbp)
  jg     L10
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L10:
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%rax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fft@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <imprimeVetor@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: ERRO: informe s quantidade de elementos do FFT, a quantidade de threads : <./fft-mpi> <qtdElementos> <qtdProcessos> 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long tamTotalArray, qtdElementos, qtdElementosArray;
  int qtdProcessos;
  float *data;
  if (argc < 3) {
    printf("ERRO: informe s quantidade de elementos do FFT, a quantidade de threads : <./fft-mpi> <qtdElementos> <qtdProcessos> \n");
    return -1;
  }
  qtdElementos = strtoul(argv[1], NULL, 10);
  qtdElementosArray = qtdElementos * 2;
  tamTotalArray = qtdElementosArray + 1;
  qtdProcessos = atoi(argv[2]);
  data = malloc(sizeof(float) * tamTotalArray);
  fft(data, tamTotalArray, qtdProcessos);
  imprimeVetor(data, tamTotalArray);
  free(data);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jle    L16
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  lea    0x1(%rax,%rax,1),%rbp
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <fft@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <imprimeVetor@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: ERRO: informe s quantidade de elementos do FFT, a quantidade de threads : <./fft-mpi> <qtdElementos> <qtdProcessos> 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long tamTotalArray, qtdElementos, qtdElementosArray;
  int qtdProcessos;
  float *data;
  if (argc < 3) {
    printf("ERRO: informe s quantidade de elementos do FFT, a quantidade de threads : <./fft-mpi> <qtdElementos> <qtdProcessos> \n");
    return -1;
  }
  qtdElementos = strtoul(argv[1], NULL, 10);
  qtdElementosArray = qtdElementos * 2;
  tamTotalArray = qtdElementosArray + 1;
  qtdProcessos = atoi(argv[2]);
  data = malloc(sizeof(float) * tamTotalArray);
  fft(data, tamTotalArray, qtdProcessos);
  imprimeVetor(data, tamTotalArray);
  free(data);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  cmp    $0x2,%edi
  jle    L6
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    0x10(%rbp),%rdi
  lea    0x1(%rax,%rax,1),%r12
  call   <atoi@plt>
  lea    0x0(,%r12,4),%edi
  mov    %eax,%r13d
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fft@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <imprimeVetor@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L9:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L9
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: ERRO: informe s quantidade de elementos do FFT, a quantidade de threads : <./fft-mpi> <qtdElementos> <qtdProcessos> 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long tamTotalArray, qtdElementos, qtdElementosArray;
  int qtdProcessos;
  float *data;
  if (argc < 3) {
    printf("ERRO: informe s quantidade de elementos do FFT, a quantidade de threads : <./fft-mpi> <qtdElementos> <qtdProcessos> \n");
    return -1;
  }
  qtdElementos = strtoul(argv[1], NULL, 10);
  qtdElementosArray = qtdElementos * 2;
  tamTotalArray = qtdElementosArray + 1;
  qtdProcessos = atoi(argv[2]);
  data = malloc(sizeof(float) * tamTotalArray);
  fft(data, tamTotalArray, qtdProcessos);
  imprimeVetor(data, tamTotalArray);
  free(data);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  cmp    $0x2,%edi
  jle    L0
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    0x10(%rbp),%rdi
  lea    0x1(%rax,%rax,1),%r12
  call   <atoi@plt>
  lea    0x0(,%r12,4),%edi
  mov    %eax,%r13d
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fft@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <imprimeVetor@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L11:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: ERRO: informe s quantidade de elementos do FFT, a quantidade de threads : <./fft-mpi> <qtdElementos> <qtdProcessos> 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long tamTotalArray, qtdElementos, qtdElementosArray;
  int qtdProcessos;
  float *data;
  if (argc < 3) {
    printf("ERRO: informe s quantidade de elementos do FFT, a quantidade de threads : <./fft-mpi> <qtdElementos> <qtdProcessos> \n");
    return -1;
  }
  qtdElementos = strtoul(argv[1], NULL, 10);
  qtdElementosArray = qtdElementos * 2;
  tamTotalArray = qtdElementosArray + 1;
  qtdProcessos = atoi(argv[2]);
  data = malloc(sizeof(float) * tamTotalArray);
  fft(data, tamTotalArray, qtdProcessos);
  imprimeVetor(data, tamTotalArray);
  free(data);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<store_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %eax,%edi
  call   <asctime@plt>
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1a,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <str_copy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void store_time(char *buf) {
  time_t now = time(0);
  str_copy(buf, asctime(localtime(&now)), 26);
  buf[strlen(buf) - 1] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<store_time>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    %eax,%edi
  call   <asctime@plt>
  mov    %eax,%esi
  mov    $0x1a,%edx
  mov    %rbx,%rdi
  call   <str_copy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void store_time(char *buf) {
  time_t now = time(0);
  str_copy(buf, asctime(localtime(&now)), 26);
  buf[strlen(buf) - 1] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<store_time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    %eax,%edi
  call   <asctime@plt>
  mov    $0x1a,%edx
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <str_copy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void store_time(char *buf) {
  time_t now = time(0);
  str_copy(buf, asctime(localtime(&now)), 26);
  buf[strlen(buf) - 1] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<store_time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    %eax,%edi
  call   <asctime@plt>
  mov    $0x1a,%edx
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <str_copy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void store_time(char *buf) {
  time_t now = time(0);
  str_copy(buf, asctime(localtime(&now)), 26);
  buf[strlen(buf) - 1] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<soustringcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  sub    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L10
  mov    -0x4(%rbp),%eax
  sub    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void soustringcopy(char *source, char *destination, int posdepart, int nbpos) {
  int i;
  for (i = posdepart; i < posdepart + nbpos; i++) {
    destination[i - posdepart] = source[i];
  }
  destination[i - posdepart] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<soustringcopy>:
  endbr64
  add    %edx,%ecx
  cmp    %ecx,%edx
  jge    L8
  movslq %edx,%r8
  mov    %r8,%rax
  mov    %rsi,%r9
  sub    %r8,%r9
L18:
  movzbl (%rdi,%rax,1),%r8d
  mov    %r8b,(%r9,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L18
L22:
  sub    %edx,%ecx
  movslq %ecx,%rcx
  movb   $0x0,(%rsi,%rcx,1)
  ret
L8:
  mov    %edx,%ecx
  jmp    L22
```

assistant: ```c
void soustringcopy(char *source, char *destination, int posdepart, int nbpos) {
  int i;
  for (i = posdepart; i < posdepart + nbpos; i++) {
    destination[i - posdepart] = source[i];
  }
  destination[i - posdepart] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<soustringcopy>:
  endbr64
  lea    (%rdx,%rcx,1),%r8d
  cmp    %r8d,%edx
  jge    L2
  movslq %edx,%rdx
  mov    %rsi,%r9
  sub    %rdx,%r9
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl (%rdi,%rdx,1),%eax
  mov    %al,(%r9,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%r8d
  jg     L19
  movslq %ecx,%rcx
  add    %rcx,%rsi
L2:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void soustringcopy(char *source, char *destination, int posdepart, int nbpos) {
  int i;
  for (i = posdepart; i < posdepart + nbpos; i++) {
    destination[i - posdepart] = source[i];
  }
  destination[i - posdepart] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<soustringcopy>:
  endbr64
  lea    (%rdx,%rcx,1),%r11d
  cmp    %r11d,%edx
  jge    L33
  mov    %rdi,%r9
  mov    %edx,%edi
  mov    %rsi,%r8
  push   %rbx
  movslq %edi,%rax
  mov    %ecx,%ebx
  lea    -0x1(%rcx),%edx
  lea    0x1(%r9,%rax,1),%r10
  sub    %r10,%r8
  cmp    $0xe,%r8
  jbe    L145
  cmp    $0x6,%edx
  jbe    L145
  cmp    $0xe,%edx
  jbe    L9
  mov    %ecx,%r8d
  lea    (%r9,%rax,1),%rdx
  xor    %eax,%eax
  shr    $0x4,%r8d
  shl    $0x4,%r8
  nopw   0x0(%rax,%rax,1)
L53:
  movdqu (%rdx,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L53
  mov    %ecx,%r10d
  and    $0xfffffff0,%r10d
  lea    (%r10,%rdi,1),%r8d
  cmp    %r10d,%ecx
  je     L40
  mov    %ecx,%ebx
  sub    %r10d,%ebx
  lea    -0x1(%rbx),%eax
  cmp    $0x6,%eax
  jbe    L74
L55:
  mov    (%rdx,%r10,1),%rax
  mov    %rax,(%rsi,%r10,1)
  mov    %ebx,%eax
  and    $0xfffffff8,%eax
  add    %eax,%r8d
  cmp    %eax,%ebx
  je     L40
L74:
  movslq %r8d,%rax
  movzbl (%r9,%rax,1),%edx
  mov    %r8d,%eax
  sub    %edi,%eax
  cltq
  mov    %dl,(%rsi,%rax,1)
  lea    0x1(%r8),%eax
  cmp    %eax,%r11d
  jle    L40
  movslq %eax,%rdx
  sub    %edi,%eax
  movzbl (%r9,%rdx,1),%edx
  cltq
  mov    %dl,(%rsi,%rax,1)
  lea    0x2(%r8),%eax
  cmp    %eax,%r11d
  jle    L40
  movslq %eax,%rdx
  sub    %edi,%eax
  movzbl (%r9,%rdx,1),%edx
  cltq
  mov    %dl,(%rsi,%rax,1)
  lea    0x3(%r8),%eax
  cmp    %eax,%r11d
  jle    L40
  movslq %eax,%rdx
  sub    %edi,%eax
  movzbl (%r9,%rdx,1),%edx
  cltq
  mov    %dl,(%rsi,%rax,1)
  lea    0x4(%r8),%eax
  cmp    %eax,%r11d
  jle    L40
  movslq %eax,%rdx
  sub    %edi,%eax
  movzbl (%r9,%rdx,1),%edx
  cltq
  mov    %dl,(%rsi,%rax,1)
  lea    0x5(%r8),%eax
  cmp    %eax,%r11d
  jle    L40
  movslq %eax,%rdx
  sub    %edi,%eax
  add    $0x6,%r8d
  movzbl (%r9,%rdx,1),%edx
  cltq
  mov    %dl,(%rsi,%rax,1)
  cmp    %r8d,%r11d
  jle    L40
  movslq %r8d,%rax
  sub    %edi,%r8d
  movzbl (%r9,%rax,1),%eax
  movslq %r8d,%r8
  mov    %al,(%rsi,%r8,1)
L40:
  movslq %ecx,%rcx
  pop    %rbx
  add    %rcx,%rsi
  movb   $0x0,(%rsi)
  ret
  nop
L145:
  mov    %rsi,%rdi
  sub    %rax,%rdi
  cs nopw 0x0(%rax,%rax,1)
L79:
  movzbl (%r9,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%r11d
  jg     L79
  movslq %ecx,%rcx
  pop    %rbx
  add    %rcx,%rsi
  movb   $0x0,(%rsi)
  ret
  nopl   0x0(%rax)
L33:
  movb   $0x0,(%rsi)
  ret
L9:
  mov    %edi,%r8d
  xor    %r10d,%r10d
  lea    (%r9,%rax,1),%rdx
  jmp    L55
```

assistant: ```c
void soustringcopy(char *source, char *destination, int posdepart, int nbpos) {
  int i;
  for (i = posdepart; i < posdepart + nbpos; i++) {
    destination[i - posdepart] = source[i];
  }
  destination[i - posdepart] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <aloja_espacio_e_incializa_matrices@plt>
  mov    $0x0,%eax
  call   <imprime_matrices@plt>
  mov    $0x0,%eax
  call   <multiplica_matrices@plt>
  mov    $0x0,%eax
  call   <imprime_matriz_resultado@plt>
  mov    $0x0,%eax
  call   <libera_espacio@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  aloja_espacio_e_incializa_matrices();
  imprime_matrices();
  multiplica_matrices();
  imprime_matriz_resultado();
  libera_espacio();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <aloja_espacio_e_incializa_matrices@plt>
  mov    $0x0,%eax
  call   <imprime_matrices@plt>
  mov    $0x0,%eax
  call   <multiplica_matrices@plt>
  mov    $0x0,%eax
  call   <imprime_matriz_resultado@plt>
  mov    $0x0,%eax
  call   <libera_espacio@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  aloja_espacio_e_incializa_matrices();
  imprime_matrices();
  multiplica_matrices();
  imprime_matriz_resultado();
  libera_espacio();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <aloja_espacio_e_incializa_matrices@plt>
  xor    %eax,%eax
  call   <imprime_matrices@plt>
  xor    %eax,%eax
  call   <multiplica_matrices@plt>
  xor    %eax,%eax
  call   <imprime_matriz_resultado@plt>
  xor    %eax,%eax
  call   <libera_espacio@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  aloja_espacio_e_incializa_matrices();
  imprime_matrices();
  multiplica_matrices();
  imprime_matriz_resultado();
  libera_espacio();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <aloja_espacio_e_incializa_matrices@plt>
  xor    %eax,%eax
  call   <imprime_matrices@plt>
  xor    %eax,%eax
  call   <multiplica_matrices@plt>
  xor    %eax,%eax
  call   <imprime_matriz_resultado@plt>
  xor    %eax,%eax
  call   <libera_espacio@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  aloja_espacio_e_incializa_matrices();
  imprime_matrices();
  multiplica_matrices();
  imprime_matriz_resultado();
  libera_espacio();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rdi
  mov    -0x24(%rbp),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movslq %ecx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movslq %ecx,%rax
  lea    (%rax,%rax,1),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  mov    %rsp,%rdx
  sub    %rsi,%rdx
L6:
  cmp    %rdx,%rsp
  je     L3
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L3:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L35
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L35:
  mov    %rsp,%rax
  add    $0x1,%rax
  shr    %rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  movslq %ecx,%rax
  add    %eax,%eax
  mov    %rdi,%rsp
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
f(int x) {
  short buf[x];
  return sizeof buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
f(int x) {
  short buf[x];
  return sizeof buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
f(int x) {
  short buf[x];
  return sizeof buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
f(int x) {
  short buf[x];
  return sizeof buf;
}
```