ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getProduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0xfffffc18,-0x18(%rbp)
  jmp    L33
L14:
  movl   $0xfffffc18,-0x14(%rbp)
  jmp    L49
L0:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <checkForPrimes@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L46
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L46:
  addl   $0x1,-0x14(%rbp)
L49:
  cmpl   $0x3e7,-0x14(%rbp)
  jle    L0
  addl   $0x1,-0x18(%rbp)
L33:
  cmpl   $0x3e7,-0x18(%rbp)
  jle    L14
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getProduct() {
  int i, j, a, b, numberofPrimes = 0, aux;
  for (i = -1000; i < 1000; i++) {
    for (j = -1000; j < 1000; j++) {
      aux = checkForPrimes(i, j);
      if (aux > numberofPrimes) {
        numberofPrimes = aux;
        a = i;
        b = j;
      }
    }
  }
  return a * b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getProduct>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r12d
  mov    $0xfffffc18,%ebp
  jmp    L34
L22:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L41
L20:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <checkForPrimes@plt>
  cmp    %r12d,%eax
  jle    L22
  mov    %eax,%r12d
  mov    %ebx,%r14d
  mov    %ebp,%r13d
  jmp    L22
L41:
  add    $0x1,%ebp
  cmp    $0x3e8,%ebp
  je     L19
L34:
  mov    $0xfffffc18,%ebx
  jmp    L20
L19:
  mov    %r13d,%eax
  imul   %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getProduct() {
  int i, j, a, b, numberofPrimes = 0, aux;
  for (i = -1000; i < 1000; i++) {
    for (j = -1000; j < 1000; j++) {
      aux = checkForPrimes(i, j);
      if (aux > numberofPrimes) {
        numberofPrimes = aux;
        a = i;
        b = j;
      }
    }
  }
  return a * b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getProduct>:
  endbr64
  push   %r14
  mov    $0xfffffc18,%r14d
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
L16:
  mov    $0xfffffc18,%ebx
  nopl   0x0(%rax)
L20:
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <checkForPrimes@plt>
  cmp    %ebp,%eax
  jle    L12
  mov    %eax,%ebp
  mov    %ebx,%r13d
  mov    %r14d,%r12d
L12:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  jne    L20
  add    $0x1,%r14d
  cmp    $0x3e8,%r14d
  jne    L16
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  imul   %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getProduct() {
  int i, j, a, b, numberofPrimes = 0, aux;
  for (i = -1000; i < 1000; i++) {
    for (j = -1000; j < 1000; j++) {
      aux = checkForPrimes(i, j);
      if (aux > numberofPrimes) {
        numberofPrimes = aux;
        a = i;
        b = j;
      }
    }
  }
  return a * b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getProduct>:
  endbr64
  push   %r14
  mov    $0xfffffc18,%r14d
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
L8:
  mov    $0xfffffc18,%ebx
  nopl   0x0(%rax)
L12:
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <checkForPrimes@plt>
  cmp    %ebp,%eax
  jle    L14
  mov    %eax,%ebp
  mov    %ebx,%r13d
  mov    %r14d,%r12d
L14:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  jne    L12
  add    $0x1,%r14d
  cmp    $0x3e8,%r14d
  jne    L8
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  imul   %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getProduct() {
  int i, j, a, b, numberofPrimes = 0, aux;
  for (i = -1000; i < 1000; i++) {
    for (j = -1000; j < 1000; j++) {
      aux = checkForPrimes(i, j);
      if (aux > numberofPrimes) {
        numberofPrimes = aux;
        a = i;
        b = j;
      }
    }
  }
  return a * b;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rsi
  lea    D34(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r13
  lea    D40(%rip),%rsi
  lea    D48(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r14
  mov    %rsp,%r12
  lea    0x40(%rsp),%rbx
  lea    D20(%rip),%r15
  jmp    L18
L66:
  add    $0x1,%edx
  mov    %dl,(%rax)
L60:
  add    $0x1,%rax
  cmp    %rbx,%rax
  je     L95
L83:
  movzbl (%rax),%edx
  lea    -0x61(%rdx),%ecx
  cmp    $0x18,%cl
  jbe    L66
  cmp    $0x7a,%dl
  jne    L60
  movb   $0x61,(%rax)
  jmp    L60
L95:
  mov    %r14,%rcx
  mov    %ebp,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  cmp    %eax,%ebp
  jne    L58
L18:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L54
  mov    %r13,%rcx
  mov    $0x40,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %eax,%ebp
  mov    %r12,%rax
  jmp    L83
L58:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
L54:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
datatype: string
name: disassemble_data
arguments: data_label: D34
datatype: string
name: disassemble_data
arguments: data_label: D40
datatype: string
name: disassemble_data
arguments: data_label: D48
datatype: string
name: disassemble_data
arguments: data_label: D20
datatype: string

tool: D16: rt

tool: D34: text1.txt

tool: D40: wt

tool: D48: encrypted.txt

tool: D20: Error in write command!


assistant: ```c
int main() {
  int i, n = 1, nr, nw;
  char buf[64];
  FILE *fpR, *fpW;
  fpR = fopen("text1.txt", "rt");
  fpW = fopen("encrypted.txt", "wt");
  while (!feof(fpR)) {
    nr = fread(buf, 1, 64, fpR);
    for (i = 0; i < 64; i++) {
      if (buf[i] >= 'a' && buf[i] <= ('z' - n)) {
        buf[i] += n;
      } else if (buf[i] > ('z' - n) && buf[i] <= 'z') {
        buf[i] += (n - (26));
      }
    }
    nw = fwrite(buf, 1, nr, fpW);
    if (nw != nr) {
      printf("Error in write command!\n");
      getchar();
      exit(1);
    }
  }
  fclose(fpR);
  fclose(fpW);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D29(%rip),%rsi
  lea    D38(%rip),%rdi
  push   %r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%r14
  call   <fopen@plt>
  lea    D37(%rip),%rsi
  lea    D16(%rip),%rdi
  mov    %rax,%rbp
  call   <fopen@plt>
  mov    %rax,%r12
  nopl   (%rax)
L40:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L20
L39:
  mov    %rbp,%rcx
  mov    $0x40,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %eax,%r15d
  mov    %rbx,%rax
  jmp    L70
  nopl   (%rax)
L57:
  add    $0x1,%edx
  mov    %dl,(%rax)
L24:
  add    $0x1,%rax
  cmp    %rax,%r14
  je     L8
L70:
  movzbl (%rax),%edx
  cmp    $0x60,%dl
  jle    L24
  cmp    $0x79,%dl
  jle    L57
  cmp    $0x7a,%dl
  jne    L24
  movb   $0x61,(%rax)
  add    $0x1,%rax
  cmp    %rax,%r14
  jne    L70
  nopl   0x0(%rax)
L8:
  mov    %r12,%rcx
  mov    %r15d,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  cmp    %eax,%r15d
  je     L40
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L39
L20:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D29
type_infered: string
name: disassemble_data
arguments: label: D38
type_infered: string
name: disassemble_data
arguments: label: D25
type_infered: string
name: disassemble_data
arguments: label: D37
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: string

tool: D29: rt

tool: D38: text1.txt

tool: D25: Error in write command!


tool: D37: wt

tool: D16: encrypted.txt

assistant: ```c
int main() {
  int i, n = 1, nr, nw;
  char buf[64];
  FILE *fpR, *fpW;
  fpR = fopen("text1.txt", "rt");
  fpW = fopen("encrypted.txt", "wt");
  while (!feof(fpR)) {
    nr = fread(buf, 1, 64, fpR);
    for (i = 0; i < 64; i++) {
      if (buf[i] >= 'a' && buf[i] <= ('z' - n)) {
        buf[i] += n;
      } else if (buf[i] > ('z' - n) && buf[i] <= 'z') {
        buf[i] += (n - (26));
      }
    }
    nw = fwrite(buf, 1, nr, fpW);
    if (nw != nr) {
      printf("Error in write command!\n");
      getchar();
      exit(1);
    }
  }
  fclose(fpR);
  fclose(fpW);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D19(%rip),%rsi
  lea    D40(%rip),%rdi
  push   %r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%r14
  call   <fopen@plt>
  lea    D34(%rip),%rsi
  lea    D7(%rip),%rdi
  mov    %rax,%rbp
  call   <fopen@plt>
  mov    %rax,%r12
  nopl   (%rax)
L31:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L58
L63:
  mov    %rbp,%rcx
  mov    $0x40,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %eax,%r15d
  mov    %rbx,%rax
  jmp    L52
  nopl   (%rax)
L69:
  add    $0x1,%edx
  mov    %dl,(%rax)
L82:
  add    $0x1,%rax
  cmp    %r14,%rax
  je     L30
L52:
  movzbl (%rax),%edx
  cmp    $0x60,%dl
  jle    L82
  cmp    $0x79,%dl
  jle    L69
  cmp    $0x7a,%dl
  jne    L82
  movb   $0x61,(%rax)
  add    $0x1,%rax
  cmp    %r14,%rax
  jne    L52
  nopl   0x0(%rax)
L30:
  mov    %r12,%rcx
  mov    %r15d,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  cmp    %eax,%r15d
  je     L31
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L63
L58:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type: string
name: read_data
arguments: tag: D40
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D34
type: string
name: read_data
arguments: tag: D7
type: string

tool: D19: rt

tool: D40: text1.txt

tool: D15: Error in write command!


tool: D34: wt

tool: D7: encrypted.txt

assistant: ```c
int main() {
  int i, n = 1, nr, nw;
  char buf[64];
  FILE *fpR, *fpW;
  fpR = fopen("text1.txt", "rt");
  fpW = fopen("encrypted.txt", "wt");
  while (!feof(fpR)) {
    nr = fread(buf, 1, 64, fpR);
    for (i = 0; i < 64; i++) {
      if (buf[i] >= 'a' && buf[i] <= ('z' - n)) {
        buf[i] += n;
      } else if (buf[i] > ('z' - n) && buf[i] <= 'z') {
        buf[i] += (n - (26));
      }
    }
    nw = fwrite(buf, 1, nr, fpW);
    if (nw != nr) {
      printf("Error in write command!\n");
      getchar();
      exit(1);
    }
  }
  fclose(fpR);
  fclose(fpW);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<next_power_of_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2000,-0x8(%rbp)
  jmp    L14
L5:
  shlq   -0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L5
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t next_power_of_2(size_t x) {
  size_t r = 8192;
  while (r < x)
    r <<= 1;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_power_of_2>:
  endbr64
  cmp    $0x2000,%rdi
  jbe    L18
  mov    $0x2000,%eax
L15:
  add    %rax,%rax
  cmp    %rax,%rdi
  ja     L15
  ret
L18:
  mov    $0x2000,%eax
  ret
```

assistant: ```c
size_t next_power_of_2(size_t x) {
  size_t r = 8192;
  while (r < x)
    r <<= 1;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_power_of_2>:
  endbr64
  mov    $0x2000,%eax
  cmp    $0x2000,%rdi
  jbe    L15
  nopw   0x0(%rax,%rax,1)
L13:
  add    %rax,%rax
  cmp    %rax,%rdi
  ja     L13
  ret
  nopl   0x0(%rax)
L15:
  ret
```

assistant: ```c
size_t next_power_of_2(size_t x) {
  size_t r = 8192;
  while (r < x)
    r <<= 1;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<next_power_of_2>:
  endbr64
  mov    $0x2000,%eax
  cmp    $0x2000,%rdi
  jbe    L9
  nopw   0x0(%rax,%rax,1)
L16:
  add    %rax,%rax
  cmp    %rax,%rdi
  ja     L16
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
size_t next_power_of_2(size_t x) {
  size_t r = 8192;
  while (r < x)
    r <<= 1;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fs_load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <load_fs@plt>
  test   %rax,%rax
  jns    L0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <fail@plt>
L0:
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string

tool: D13: fat.part

tool: D4: 'load' failed!


assistant: ```c
void fs_load() {
  if (load_fs("fat.part") < 0)
    fail("'load' failed!\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fs_load>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <load_fs@plt>
  test   %rax,%rax
  js     L7
L11:
  add    $0x8,%rsp
  ret
L7:
  lea    D15(%rip),%rdi
  call   <fail@plt>
  jmp    L11
```

tool_calls: name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string

tool: D12: fat.part

tool: D15: 'load' failed!


assistant: ```c
void fs_load() {
  if (load_fs("fat.part") < 0)
    fail("'load' failed!\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fs_load>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <load_fs@plt>
  test   %rax,%rax
  js     L4
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L4:
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <fail@plt>
```

tool_calls: name: read_data
arguments: label: D15
type_infered: string
name: read_data
arguments: label: D8
type_infered: string

tool: D15: fat.part

tool: D8: 'load' failed!


assistant: ```c
void fs_load() {
  if (load_fs("fat.part") < 0)
    fail("'load' failed!\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fs_load>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <load_fs@plt>
  test   %rax,%rax
  js     L4
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L4:
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D17
type_infered: string

tool: D7: fat.part

tool: D17: 'load' failed!


assistant: ```c
void fs_load() {
  if (load_fs("fat.part") < 0)
    fail("'load' failed!\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<my_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L9:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *my_realloc(char *old, int oldlen, int newlen) {
  char *new = malloc(newlen);
  int i = 0;
  while (i <= oldlen - 1) {
    new[i] = old[i];
    i = i + 1;
  }
  return new;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_realloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L15
  mov    %ebx,%esi
  mov    $0x0,%edx
L17:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L17
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *my_realloc(char *old, int oldlen, int newlen) {
  char *new = malloc(newlen);
  int i = 0;
  while (i <= oldlen - 1) {
    new[i] = old[i];
    i = i + 1;
  }
  return new;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_realloc>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L5
  movslq %ebx,%rsi
  xor    %edx,%edx
  nop
L8:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L8
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *my_realloc(char *old, int oldlen, int newlen) {
  char *new = malloc(newlen);
  int i = 0;
  while (i <= oldlen - 1) {
    new[i] = old[i];
    i = i + 1;
  }
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_realloc>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L131
  lea    0x1(%rbx),%rsi
  mov    %r8,%rdx
  lea    -0x1(%rbp),%eax
  mov    %ebp,%ecx
  sub    %rsi,%rdx
  cmp    $0xe,%rdx
  jbe    L51
  cmp    $0x6,%eax
  jbe    L51
  cmp    $0xe,%eax
  jbe    L98
  mov    %ebp,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
  nopw   0x0(%rax,%rax,1)
L62:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L62
  mov    %ebp,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%ebp
  je     L131
  mov    %ebp,%ecx
  sub    %edx,%ecx
  lea    -0x1(%rcx),%esi
  cmp    $0x6,%esi
  jbe    L100
L1:
  mov    (%rbx,%rdx,1),%rsi
  mov    %rsi,(%r8,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L131
L100:
  movslq %eax,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L131
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%ebp
  jle    L131
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%ebp
  jle    L131
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%ebp
  jle    L131
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%ebp
  jle    L131
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  cmp    %eax,%ebp
  jle    L131
  cltq
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
L131:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L51:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L101:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L101
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L98:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
char *my_realloc(char *old, int oldlen, int newlen) {
  char *new = malloc(newlen);
  int i = 0;
  while (i <= oldlen - 1) {
    new[i] = old[i];
    i = i + 1;
  }
  return new;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  jg     L33
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L38
L33:
  cmpl   $0x7ff,-0x4(%rbp)
  jg     L26
  mov    -0x4(%rbp),%eax
  sar    $0x6,%eax
  or     $0xc0,%al
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  and    $0x3f,%eax
  or     $0x80,%al
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L38
L26:
  mov    -0x4(%rbp),%eax
  sar    $0xc,%eax
  or     $0xe0,%al
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  sar    $0x6,%eax
  and    $0x3f,%eax
  or     $0x80,%al
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  and    $0x3f,%eax
  or     $0x80,%al
  mov    %eax,%edi
  call   <putchar@plt>
L38:
  nop
  leave
  ret
```

assistant: ```c
void print_utf8(int code) {
  if (code <= 0x7f) {
    putchar(code);
  } else if (code <= 0x7ff) {
    putchar(0xc0 | code >> 6);
    putchar(0x80 | (code & 0x3f));
  } else {
    putchar(0xe0 | code >> 12);
    putchar(0x80 | (code >> 6 & 0x3f));
    putchar(0x80 | (code & 0x3f));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_utf8>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x7f,%edi
  jle    L17
  cmp    $0x7ff,%edi
  jg     L38
  sar    $0x6,%edi
  or     $0xc0,%dil
  call   <putchar@plt>
  and    $0x3f,%ebx
  mov    %ebx,%edi
  or     $0x80,%dil
  call   <putchar@plt>
L1:
  pop    %rbx
  ret
L17:
  call   <putchar@plt>
  jmp    L1
L38:
  sar    $0xc,%edi
  or     $0xe0,%dil
  call   <putchar@plt>
  mov    %ebx,%edi
  sar    $0x6,%edi
  and    $0x3f,%edi
  or     $0x80,%dil
  call   <putchar@plt>
  and    $0x3f,%ebx
  mov    %ebx,%edi
  or     $0x80,%dil
  call   <putchar@plt>
  jmp    L1
```

assistant: ```c
void print_utf8(int code) {
  if (code <= 0x7f) {
    putchar(code);
  } else if (code <= 0x7ff) {
    putchar(0xc0 | code >> 6);
    putchar(0x80 | (code & 0x3f));
  } else {
    putchar(0xe0 | code >> 12);
    putchar(0x80 | (code >> 6 & 0x3f));
    putchar(0x80 | (code & 0x3f));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_utf8>:
  endbr64
  cmp    $0x7f,%edi
  jle    L25
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  and    $0x3f,%ebp
  mov    %edi,%ebx
  sar    $0x6,%ebx
  or     $0x80,%bpl
  sub    $0x8,%rsp
  cmp    $0x7ff,%edi
  jle    L26
  sar    $0xc,%edi
  and    $0x3f,%ebx
  or     $0xe0,%dil
  call   <putchar@plt>
  mov    %ebx,%edi
  or     $0x80,%dil
L1:
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
L25:
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax)
L26:
  or     $0xc0,%bl
  mov    %ebx,%edi
  jmp    L1
```

assistant: ```c
void print_utf8(int code) {
  if (code <= 0x7f) {
    putchar(code);
  } else if (code <= 0x7ff) {
    putchar(0xc0 | code >> 6);
    putchar(0x80 | (code & 0x3f));
  } else {
    putchar(0xe0 | code >> 12);
    putchar(0x80 | (code >> 6 & 0x3f));
    putchar(0x80 | (code & 0x3f));
  }
}
```