ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<fig05_13>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D37(%rip),%r12
  mov    $0xcccccccd,%ebp
  lea    D21(%rip),%r13
L30:
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  je     L11
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  imul   %rbp,%rax
  shr    $0x22,%rax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  jne    L30
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L30
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D39
type: string
name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D37
type: string
name: unpack_data
arguments: data_tag: D21
type: string

tool: D39: Enter seed: 

tool: D1: %u

tool: D37: %10d

tool: 

assistant: ```c
void fig05_13() {
  unsigned int i;
  unsigned int seed;
  printf("%s", "Enter seed: \n");
  scanf("%u", &seed);
  srand(seed);
  for (i = 1; i <= 10; ++i) {
    printf("%10d", 1 + (rand() % 6));
    if (i % 5 == 0) {
      puts("");
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fig05_13>:
  endbr64
  push   %r12
  lea    D34(%rip),%rdi
  mov    $0x1,%r12d
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  lea    D25(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbx,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    $0x1,%r12d
  cmp    $0xb,%r12d
  je     L34
L28:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbx,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%r12d,%eax
  cmp    $0x33333333,%eax
  ja     L22
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <puts@plt>
  cmp    $0xb,%r12d
  jne    L28
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D34
type: string
name: disassemble_data
arguments: data_label: D21
type: string
name: disassemble_data
arguments: data_label: D25
type: string
name: disassemble_data
arguments: data_label: D33
type: string

tool: D34: Enter seed: 

tool: 

tool: D25: %10d

tool: D33: %u

assistant: ```c
void fig05_13() {
  unsigned int i;
  unsigned int seed;
  printf("%s", "Enter seed: \n");
  scanf("%u", &seed);
  srand(seed);
  for (i = 1; i <= 10; ++i) {
    printf("%10d", 1 + (rand() % 6));
    if (i % 5 == 0) {
      puts("");
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fig05_13>:
  endbr64
  push   %r12
  lea    D13(%rip),%rdi
  mov    $0x2,%r12d
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbx,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbx,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%r12d,%eax
  cmp    $0x33333333,%eax
  ja     L22
  mov    %rbp,%rdi
  call   <puts@plt>
L22:
  add    $0x1,%r12d
  cmp    $0xb,%r12d
  jne    L2
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D19
type_guessed: string
name: retrieve_data
arguments: data_tag: D21
type_guessed: string

tool: D13: Enter seed: 

tool: 

tool: D19: %10d

tool: D21: %u

assistant: ```c
void fig05_13() {
  unsigned int i;
  unsigned int seed;
  printf("%s", "Enter seed: \n");
  scanf("%u", &seed);
  srand(seed);
  for (i = 1; i <= 10; ++i) {
    printf("%10d", 1 + (rand() % 6));
    if (i % 5 == 0) {
      puts("");
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ands_si_test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x99999999,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L6
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  jmp    L5
L6:
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int ands_si_test2(int a, int b, int c) {
  int d = a & 0x99999999;
  if (d <= 0)
    return a + c;
  else
    return b + d + c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ands_si_test2>:
  endbr64
  mov    %edi,%ecx
  and    $0x99999999,%ecx
  add    %edx,%edi
  lea    (%rcx,%rsi,1),%eax
  add    %edx,%eax
  test   %ecx,%ecx
  cmovle %edi,%eax
  ret
```

assistant: ```c
int ands_si_test2(int a, int b, int c) {
  int d = a & 0x99999999;
  if (d <= 0)
    return a + c;
  else
    return b + d + c;
}
```
user: What is the c source code of the assembly code below?

```asm
<ands_si_test2>:
  endbr64
  mov    %edi,%ecx
  add    %edx,%edi
  and    $0x99999999,%ecx
  lea    (%rcx,%rsi,1),%eax
  add    %edx,%eax
  test   %ecx,%ecx
  cmovle %edi,%eax
  ret
```

assistant: ```c
int ands_si_test2(int a, int b, int c) {
  int d = a & 0x99999999;
  if (d <= 0)
    return a + c;
  else
    return b + d + c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ands_si_test2>:
  endbr64
  mov    %edi,%ecx
  add    %edx,%edi
  and    $0x99999999,%ecx
  lea    (%rcx,%rsi,1),%eax
  add    %edx,%eax
  test   %ecx,%ecx
  cmovle %edi,%eax
  ret
```

assistant: ```c
int ands_si_test2(int a, int b, int c) {
  int d = a & 0x99999999;
  if (d <= 0)
    return a + c;
  else
    return b + d + c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x38(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,%rdx
  lea    D33(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movw   $0x0,-0x4a(%rbp)
  jmp    L22
L1:
  movswq -0x4a(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movswq -0x4a(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  movswl -0x4a(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzwl -0x4a(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4a(%rbp)
L22:
  cmpw   $0x3,-0x4a(%rbp)
  jle    L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D34
type_guessed: string
name: extract_symbolic_data
arguments: label: D33
type_guessed: string
name: extract_symbolic_data
arguments: label: D13
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D34: double

tool: D33: short

tool: D13: %23s %15s


tool: D19: pointers + %d: %10p %10p


assistant: ```c
int main(void) {
  short dates[4];
  short *pti;
  short index;
  double bills[4];
  double *ptf;
  pti = dates;
  ptf = bills;
  printf("%23s %15s\n", "short", "double");
  for (index = 0; index < 4; index++)
    printf("pointers + %d: %10p %10p\n", index, pti + index, ptf + index);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdx
  lea    D32(%rip),%rsi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D33(%rip),%r12
L4:
  lea    0x10(%rsp,%rbx,8),%rcx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  add    $0x2,%rbp
  cmp    $0x4,%rbx
  jne    L4
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D34
type_guessed: string
name: read_data
arguments: data_label: D32
type_guessed: string
name: read_data
arguments: data_label: D38
type_guessed: string
name: read_data
arguments: data_label: D33
type_guessed: string

tool: D34: double

tool: D32: short

tool: D38: %23s %15s


tool: D33: pointers + %d: %10p %10p


assistant: ```c
int main(void) {
  short dates[4];
  short *pti;
  short index;
  double bills[4];
  double *ptf;
  pti = dates;
  ptf = bills;
  printf("%23s %15s\n", "short", "double");
  for (index = 0; index < 4; index++)
    printf("pointers + %d: %10p %10p\n", index, pti + index, ptf + index);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D31(%rip),%rdx
  lea    D23(%rip),%rsi
  push   %r12
  lea    D24(%rip),%rdi
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r13
  call   <printf@plt>
L14:
  lea    0x0(%r13,%rbx,8),%rcx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  add    $0x2,%rbp
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L14
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D31
type: string
name: disassemble_data
arguments: tag: D23
type: string
name: disassemble_data
arguments: tag: D24
type: string
name: disassemble_data
arguments: tag: D3
type: string

tool: D31: double

tool: D23: short

tool: D24: %23s %15s


tool: D3: pointers + %d: %10p %10p


assistant: ```c
int main(void) {
  short dates[4];
  short *pti;
  short index;
  double bills[4];
  double *ptf;
  pti = dates;
  ptf = bills;
  printf("%23s %15s\n", "short", "double");
  for (index = 0; index < 4; index++)
    printf("pointers + %d: %10p %10p\n", index, pti + index, ptf + index);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%rdx
  lea    D6(%rip),%rsi
  push   %r12
  lea    D10(%rip),%rdi
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r13
  call   <printf@plt>
L6:
  lea    0x0(%r13,%rbx,8),%rcx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  add    $0x2,%rbp
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L6
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string

tool: D12: double

tool: D6: short

tool: D10: %23s %15s


tool: D7: pointers + %d: %10p %10p


assistant: ```c
int main(void) {
  short dates[4];
  short *pti;
  short index;
  double bills[4];
  double *ptf;
  pti = dates;
  ptf = bills;
  printf("%23s %15s\n", "short", "double");
  for (index = 0; index < 4; index++)
    printf("pointers + %d: %10p %10p\n", index, pti + index, ptf + index);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fgammaf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x8(%rbp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x4(%rbp),%xmm2
  movsd  D5(%rip),%xmm0
  addsd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  jbe    L11
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <fgamma_sf@plt>
  jmp    L10
L11:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <fgamma_steedf@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: f64

tool: D5: 0.5

assistant: ```c
float fgammaf(int m, float x) {
  if (x < (m + 0.5))
    return fgamma_sf(m, x);
  else
    return fgamma_steedf(m, x);
}
```
user: What is the c source code of the assembly code below:

```asm
<fgammaf>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  addsd  D9(%rip),%xmm1
  comisd %xmm2,%xmm1
  jbe    L5
  call   <fgamma_sf@plt>
L14:
  add    $0x8,%rsp
  ret
L5:
  call   <fgamma_steedf@plt>
  jmp    L14
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: f64

tool: D9: 0.5

assistant: ```c
float fgammaf(int m, float x) {
  if (x < (m + 0.5))
    return fgamma_sf(m, x);
  else
    return fgamma_steedf(m, x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fgammaf>:
  endbr64
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm1
  addsd  D0(%rip),%xmm1
  cvtss2sd %xmm0,%xmm2
  comisd %xmm2,%xmm1
  jbe    L0
  jmp    1060 <fgamma_sf@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  jmp    1070 <fgamma_steedf@plt>
```

tool_calls: name: parse_data
arguments: label: D0
data_type: f64

tool: D0: 0.5

assistant: ```c
float fgammaf(int m, float x) {
  if (x < (m + 0.5))
    return fgamma_sf(m, x);
  else
    return fgamma_steedf(m, x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fgammaf>:
  endbr64
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm1
  addsd  D6(%rip),%xmm1
  cvtss2sd %xmm0,%xmm2
  comisd %xmm2,%xmm1
  jbe    L5
  jmp    1060 <fgamma_sf@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  jmp    1070 <fgamma_steedf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: f64

tool: D6: 0.5

assistant: ```c
float fgammaf(int m, float x) {
  if (x < (m + 0.5))
    return fgamma_sf(m, x);
  else
    return fgamma_steedf(m, x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gui_nick_hash_djb2_64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L14
L8:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x2,%eax
  lea    (%rdx,%rax,1),%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <utf8_char_int@plt>
  lea    (%rbx,%rax,1),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <utf8_next_char@plt>
  mov    %rax,-0x18(%rbp)
L14:
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L5:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void gui_nick_hash_djb2_64(const char *nickname, uint64_t *color_64) {
  while (nickname && nickname[0]) {
    *color_64 ^= (*color_64 << 5) + (*color_64 >> 2) + utf8_char_int(nickname);
    nickname = utf8_next_char(nickname);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<gui_nick_hash_djb2_64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %rdi,%rdi
  je     L7
L5:
  cmpb   $0x0,(%rbx)
  je     L7
  mov    (%r12),%eax
  mov    %eax,%ebp
  shl    $0x5,%ebp
  sar    $0x2,%eax
  add    %eax,%ebp
  mov    %rbx,%rdi
  call   <utf8_char_int@plt>
  add    %eax,%ebp
  xor    %ebp,(%r12)
  mov    %rbx,%rdi
  call   <utf8_next_char@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L5
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void gui_nick_hash_djb2_64(const char *nickname, uint64_t *color_64) {
  while (nickname && nickname[0]) {
    *color_64 ^= (*color_64 << 5) + (*color_64 >> 2) + utf8_char_int(nickname);
    nickname = utf8_next_char(nickname);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gui_nick_hash_djb2_64>:
  endbr64
  test   %rdi,%rdi
  je     L27
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L26
  nopl   (%rax)
L37:
  mov    (%r12),%eax
  mov    %rbp,%rdi
  mov    %eax,%ebx
  sar    $0x2,%eax
  shl    $0x5,%ebx
  add    %eax,%ebx
  call   <utf8_char_int@plt>
  mov    %rbp,%rdi
  add    %eax,%ebx
  xor    %ebx,(%r12)
  call   <utf8_next_char@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L13
L26:
  cmpb   $0x0,0x0(%rbp)
  jne    L37
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  ret
```

assistant: ```c
void gui_nick_hash_djb2_64(const char *nickname, uint64_t *color_64) {
  while (nickname && nickname[0]) {
    *color_64 ^= (*color_64 << 5) + (*color_64 >> 2) + utf8_char_int(nickname);
    nickname = utf8_next_char(nickname);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gui_nick_hash_djb2_64>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L20
  nopl   (%rax)
L31:
  mov    (%r12),%eax
  mov    %rbp,%rdi
  mov    %eax,%ebx
  sar    $0x2,%eax
  shl    $0x5,%ebx
  add    %eax,%ebx
  call   <utf8_char_int@plt>
  mov    %rbp,%rdi
  add    %eax,%ebx
  xor    %ebx,(%r12)
  call   <utf8_next_char@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
L20:
  cmpb   $0x0,0x0(%rbp)
  jne    L31
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  ret
```

assistant: ```c
void gui_nick_hash_djb2_64(const char *nickname, uint64_t *color_64) {
  while (nickname && nickname[0]) {
    *color_64 ^= (*color_64 << 5) + (*color_64 >> 2) + utf8_char_int(nickname);
    nickname = utf8_next_char(nickname);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_ws@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <noctrl@plt>
  subl   $0x2,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jg     L7
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L7:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  je     L4
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *copy_string(char *y, char *x, int len) {
  x = skip_ws(x);
  noctrl(x);
  len -= 2;
  if (strlen(x) >= len)
    x[len] = 0;
  if (y != x)
    strcpy(y, x);
  return (y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %edx,%ebx
  call   <skip_ws@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <noctrl@plt>
  sub    $0x2,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L1
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
L1:
  cmp    %r12,%rbp
  je     L18
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L18:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_string(char *y, char *x, int len) {
  x = skip_ws(x);
  noctrl(x);
  len -= 2;
  if (strlen(x) >= len)
    x[len] = 0;
  if (y != x)
    strcpy(y, x);
  return (y);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x2,%ebx
  call   <skip_ws@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <noctrl@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L4
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
L4:
  cmp    %r12,%rbp
  je     L14
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_string(char *y, char *x, int len) {
  x = skip_ws(x);
  noctrl(x);
  len -= 2;
  if (strlen(x) >= len)
    x[len] = 0;
  if (y != x)
    strcpy(y, x);
  return (y);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x2,%ebx
  call   <skip_ws@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <noctrl@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L11
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
L11:
  cmp    %r12,%rbp
  je     L12
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L12:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_string(char *y, char *x, int len) {
  x = skip_ws(x);
  noctrl(x);
  len -= 2;
  if (strlen(x) >= len)
    x[len] = 0;
  if (y != x)
    strcpy(y, x);
  return (y);
}
```