ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<func3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  sub    %rsp,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    (%rbx,%r12,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D34
type_guessed: string
name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D25
type_guessed: string

tool: D34: In func3

tool: D4: func3 rbp %p


tool: D11: func3 rsp %p


tool: D25: func3 stack frame size = 0x%x


assistant: ```c
int func3(int x, int y) {
  register char *const basepointer __asm("rbp");
  register char *const stackpointer __asm("rsp");
  printf("In func3\n");
  printf("func3 rbp %p\n", basepointer);
  printf("func3 rsp %p\n", stackpointer);
  printf("func3 stack frame size = 0x%x\n", basepointer - stackpointer);
  return x + y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func3>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  sub    %rsp,%rsi
  call   <printf@plt>
  lea    (%rbx,%r12,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D6
type: string
name: retrieve_data
arguments: label: D25
type: string
name: retrieve_data
arguments: label: D21
type: string

tool: D29: In func3

tool: D6: func3 rbp %p


tool: D25: func3 rsp %p


tool: D21: func3 stack frame size = 0x%x


assistant: ```c
int func3(int x, int y) {
  register char *const basepointer __asm("rbp");
  register char *const stackpointer __asm("rsp");
  printf("In func3\n");
  printf("func3 rbp %p\n", basepointer);
  printf("func3 rsp %p\n", stackpointer);
  printf("func3 stack frame size = 0x%x\n", basepointer - stackpointer);
  return x + y;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<func3>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  sub    %rsp,%rsi
  call   <printf@plt>
  lea    (%rbx,%r12,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D28
type_guessed: string
name: retrieve_data
arguments: data_tag: D29
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string

tool: D14: In func3

tool: D28: func3 rbp %p


tool: D29: func3 rsp %p


tool: D13: func3 stack frame size = 0x%x


assistant: ```c
int func3(int x, int y) {
  register char *const basepointer __asm("rbp");
  register char *const stackpointer __asm("rsp");
  printf("In func3\n");
  printf("func3 rbp %p\n", basepointer);
  printf("func3 rsp %p\n", stackpointer);
  printf("func3 stack frame size = 0x%x\n", basepointer - stackpointer);
  return x + y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<freeSortedPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <secFree@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <secFree@plt>
  nop
  leave
  ret
```

assistant: ```c
void freeSortedPath(char **cpp_path, int i_num_folders) {
  for (int i_current_folder = 0; i_current_folder < i_num_folders; i_current_folder++)
    secFree(&(cpp_path[i_current_folder]));
  secFree(cpp_path);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<freeSortedPath>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L14
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L0:
  mov    %rbx,%rdi
  call   <secFree@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L0
L14:
  mov    %r12,%rdi
  call   <secFree@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void freeSortedPath(char **cpp_path, int i_num_folders) {
  for (int i_current_folder = 0; i_current_folder < i_num_folders; i_current_folder++)
    secFree(&(cpp_path[i_current_folder]));
  secFree(cpp_path);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<freeSortedPath>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdi
  add    $0x8,%rbx
  call   <secFree@plt>
  cmp    %rbp,%rbx
  jne    L2
L5:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <secFree@plt>
```

assistant: ```c
void freeSortedPath(char **cpp_path, int i_num_folders) {
  for (int i_current_folder = 0; i_current_folder < i_num_folders; i_current_folder++)
    secFree(&(cpp_path[i_current_folder]));
  secFree(cpp_path);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<freeSortedPath>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  add    $0x8,%rbx
  call   <secFree@plt>
  cmp    %rbp,%rbx
  jne    L0
L9:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <secFree@plt>
```

assistant: ```c
void freeSortedPath(char **cpp_path, int i_num_folders) {
  for (int i_current_folder = 0; i_current_folder < i_num_folders; i_current_folder++)
    secFree(&(cpp_path[i_current_folder]));
  secFree(cpp_path);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_indexof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L28
  mov    -0x4(%rbp),%eax
  jmp    L25
L28:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    $0xffffffff,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int ft_indexof(char *str, char c) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] == c)
      return (i);
    ++i;
  }
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_indexof>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
  mov    $0x0,%eax
L13:
  mov    %eax,%ecx
  cmp    %dl,%sil
  je     L31
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L13
  mov    $0xffffffff,%ecx
L31:
  mov    %ecx,%eax
  ret
L14:
  mov    $0xffffffff,%ecx
  jmp    L31
```

assistant: ```c
int ft_indexof(char *str, char c) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] == c)
      return (i);
    ++i;
  }
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_indexof>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L0
  xor    %eax,%eax
  jmp    L29
  nop
L21:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L0
L29:
  mov    %eax,%r8d
  cmp    %dl,%sil
  jne    L21
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_indexof(char *str, char c) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] == c)
      return (i);
    ++i;
  }
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_indexof>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L38
  xor    %eax,%eax
  jmp    L30
  nop
L17:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L38
L30:
  mov    %eax,%r8d
  cmp    %dl,%sil
  jne    L17
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_indexof(char *str, char c) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] == c)
      return (i);
    ++i;
  }
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  movl   $0x1,-0x38(%rbp)
  jmp    L4
L7:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L4:
  mov    -0x38(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L7
  lea    D26(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D59(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L48
L29:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L48:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D54
type: string
name: retrieve_data
arguments: tag: D26
type: string
name: retrieve_data
arguments: tag: D59
type: string
name: retrieve_data
arguments: tag: D30
type: string
name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D38
type: string

tool: D54: arg %d: %s


tool: D26: California

tool: D59: Oregon

tool: D30: Washington

tool: D6: Texas

tool: D38: stat %d: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  };
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("stat %d: %s\n", i, states[i]);
  };
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L15
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x1,%ebx
  lea    D56(%rip),%r13
L26:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L26
L15:
  lea    D10(%rip),%rax
  mov    %rax,(%rsp)
  lea    D29(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D46(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D43(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
L2:
  mov    (%rsp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L2
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D56
type_infered: string
name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string
name: unpack_data
arguments: label: D46
type_infered: string
name: unpack_data
arguments: label: D43
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string

tool: D56: arg %d: %s


tool: D10: California

tool: D29: Oregon

tool: D46: Washington

tool: D43: Texas

tool: D4: stat %d: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  };
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("stat %d: %s\n", i, states[i]);
  };
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L18
  mov    %rsi,%rbp
  movslq %edi,%r13
  mov    $0x1,%ebx
  lea    D27(%rip),%r12
  nopl   (%rax)
L28:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L28
L18:
  lea    D25(%rip),%rax
  xor    %ebx,%ebx
  lea    D22(%rip),%rdx
  mov    %rax,0x8(%rsp)
  lea    D16(%rip),%rax
  lea    D1(%rip),%rbp
  mov    %rax,0x10(%rsp)
  lea    D33(%rip),%rax
  mov    %rax,0x18(%rsp)
L37:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L44
  mov    (%rsp,%rbx,8),%rdx
  jmp    L37
  xchg   %ax,%ax
L44:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D27
type: string
name: unpack_data
arguments: label: D25
type: string
name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D16
type: string
name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D33
type: string

tool: D27: arg %d: %s


tool: D25: Oregon

tool: D22: California

tool: D16: Washington

tool: D1: stat %d: %s


tool: D33: Texas

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  };
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("stat %d: %s\n", i, states[i]);
  };
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L4
  mov    %rsi,%r12
  movslq %edi,%rbp
  mov    $0x1,%ebx
  lea    D14(%rip),%r13
  nopl   (%rax)
L29:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L29
L4:
  lea    D59(%rip),%rax
  lea    D47(%rip),%rcx
  xor    %ebx,%ebx
  mov    %rsp,%r12
  movq   %rcx,%xmm0
  movq   %rax,%xmm1
  lea    D52(%rip),%rcx
  punpcklqdq %xmm1,%xmm0
  lea    D0(%rip),%rax
  lea    D39(%rip),%rbp
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm2
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L21:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L21
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D59
type: string
name: extract_symbolic_data
arguments: data_label: D47
type: string
name: extract_symbolic_data
arguments: data_label: D52
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D39
type: string

tool: D14: arg %d: %s


tool: D59: Oregon

tool: D47: California

tool: D52: Washington

tool: D0: Texas

tool: D39: stat %d: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  };
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("stat %d: %s\n", i, states[i]);
  };
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<handleErrors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void handleErrors() {
  ERR_print_errors_fp(stderr);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<handleErrors>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void handleErrors() {
  ERR_print_errors_fp(stderr);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<handleErrors>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <exit@plt>
```

assistant: ```c
void handleErrors() {
  ERR_print_errors_fp(stderr);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<handleErrors>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <exit@plt>
```

assistant: ```c
void handleErrors() {
  ERR_print_errors_fp(stderr);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute_mantissa_size_final>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  sar    %eax
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int compute_mantissa_size_final(int mant_cnt[5]) {
  int bits = (mant_cnt[1] / 3) * 5;
  bits += ((mant_cnt[2] / 3) + (mant_cnt[4] >> 1)) * 7;
  bits += mant_cnt[3] * 3;
  return bits;
}
```
user: What is the c source code of the assembly code below?

```asm
<compute_mantissa_size_final>:
  endbr64
  mov    0x4(%rdi),%ecx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    0x8(%rdi),%ecx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    0x10(%rdi),%ecx
  sar    %ecx
  add    %ecx,%eax
  lea    (%rsi,%rax,8),%ecx
  sub    %eax,%ecx
  mov    0xc(%rdi),%eax
  lea    (%rax,%rax,2),%eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int compute_mantissa_size_final(int mant_cnt[5]) {
  int bits = (mant_cnt[1] / 3) * 5;
  bits += ((mant_cnt[2] / 3) + (mant_cnt[4] >> 1)) * 7;
  bits += mant_cnt[3] * 3;
  return bits;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compute_mantissa_size_final>:
  endbr64
  movslq 0x4(%rdi),%rax
  mov    %rax,%rcx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  movslq 0x8(%rdi),%rax
  mov    %rax,%rcx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  mov    0x10(%rdi),%ecx
  sar    %ecx
  add    %ecx,%eax
  lea    (%rsi,%rax,8),%ecx
  sub    %eax,%ecx
  mov    0xc(%rdi),%eax
  lea    (%rax,%rax,2),%eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int compute_mantissa_size_final(int mant_cnt[5]) {
  int bits = (mant_cnt[1] / 3) * 5;
  bits += ((mant_cnt[2] / 3) + (mant_cnt[4] >> 1)) * 7;
  bits += mant_cnt[3] * 3;
  return bits;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compute_mantissa_size_final>:
  endbr64
  movslq 0x4(%rdi),%rax
  mov    %rax,%rcx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  movslq 0x8(%rdi),%rax
  mov    %rax,%rcx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  mov    0x10(%rdi),%ecx
  sar    %ecx
  add    %ecx,%eax
  lea    (%rsi,%rax,8),%ecx
  sub    %eax,%ecx
  mov    0xc(%rdi),%eax
  lea    (%rax,%rax,2),%eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int compute_mantissa_size_final(int mant_cnt[5]) {
  int bits = (mant_cnt[1] / 3) * 5;
  bits += ((mant_cnt[2] / 3) + (mant_cnt[4] >> 1)) * 7;
  bits += mant_cnt[3] * 3;
  return bits;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_absent_codes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%edi
  call   <expect_absent@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x1,%edi
  call   <expect_absent@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x32,%edi
  call   <expect_absent@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x63,%edi
  call   <expect_absent@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x258,%edi
  call   <expect_absent@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x259,%edi
  call   <expect_absent@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x384,%edi
  call   <expect_absent@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x2710,%edi
  call   <expect_absent@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int test_absent_codes(void) {
  int errcount = 0;
  errcount += expect_absent(0);
  errcount += expect_absent(1);
  errcount += expect_absent(50);
  errcount += expect_absent(99);
  errcount += expect_absent(600);
  errcount += expect_absent(601);
  errcount += expect_absent(900);
  errcount += expect_absent(10000);
  return errcount;
}
```