ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  if (a) {
    b = 0;
    c = 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <be_nice_to_people@plt>
  cmpl   $0x1,-0x4(%rbp)
  jle    L8
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <vuln@plt>
L8:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  be_nice_to_people();
  if (argc > 1)
    vuln(argv[1]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <be_nice_to_people@plt>
  cmp    $0x1,%ebx
  jg     L4
L19:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    0x8(%rbp),%rdi
  call   <vuln@plt>
  jmp    L19
```

assistant: ```c
int main(int argc, char **argv) {
  be_nice_to_people();
  if (argc > 1)
    vuln(argv[1]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <be_nice_to_people@plt>
  cmp    $0x1,%ebx
  jle    L2
  mov    0x8(%rbp),%rdi
  call   <vuln@plt>
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  be_nice_to_people();
  if (argc > 1)
    vuln(argv[1]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <be_nice_to_people@plt>
  cmp    $0x1,%ebx
  jle    L7
  mov    0x8(%rbp),%rdi
  call   <vuln@plt>
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  be_nice_to_people();
  if (argc > 1)
    vuln(argv[1]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gen_42>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <handle_42@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_42() {
  handle_42(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gen_42>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <handle_42@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_42() {
  handle_42(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gen_42>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_42@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_42() {
  handle_42(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_42>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_42@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_42() {
  handle_42(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_int_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jns    L10
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0xa,-0x4(%rbp)
  jle    L6
  jmp    L3
L10:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
L3:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_int_array(int *array, int value, int index) {
  int i;
  if (index < 0) {
    for (i = 0; i < 11; i++)
      array[i] = value;
  } else
    array[index] = value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_int_array>:
  endbr64
  test   %edx,%edx
  js     L7
  movslq %edx,%rdx
  mov    %esi,(%rdi,%rdx,4)
  ret
L7:
  mov    %rdi,%rax
  add    $0x2c,%rdi
L5:
  mov    %esi,(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L5
  ret
```

assistant: ```c
void set_int_array(int *array, int value, int index) {
  int i;
  if (index < 0) {
    for (i = 0; i < 11; i++)
      array[i] = value;
  } else
    array[index] = value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_int_array>:
  endbr64
  test   %edx,%edx
  js     L7
  movslq %edx,%rdx
  mov    %esi,(%rdi,%rdx,4)
  ret
  nop
L7:
  lea    0x2c(%rdi),%rax
  nopl   0x0(%rax)
L13:
  mov    %esi,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L13
  ret
```

assistant: ```c
void set_int_array(int *array, int value, int index) {
  int i;
  if (index < 0) {
    for (i = 0; i < 11; i++)
      array[i] = value;
  } else
    array[index] = value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_int_array>:
  endbr64
  movd   %esi,%xmm0
  test   %edx,%edx
  js     L3
  movslq %edx,%rdx
  mov    %esi,(%rdi,%rdx,4)
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  pshufd $0x0,%xmm0,%xmm1
  mov    %esi,0x28(%rdi)
  movups %xmm1,(%rdi)
  movups %xmm1,0x10(%rdi)
  pshufd $0xe0,%xmm0,%xmm1
  movq   %xmm1,0x20(%rdi)
  ret
```

assistant: ```c
void set_int_array(int *array, int value, int index) {
  int i;
  if (index < 0) {
    for (i = 0; i < 11; i++)
      array[i] = value;
  } else
    array[index] = value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<inet_netof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L36
  mov    D36(%rip),%rax
  mov    (%rax),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D58(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  jmp    L22
L36:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L2
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  jmp    L22
L2:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
L22:
  leave
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  u_int32_t i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return (((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT);
  else if (IN_CLASSB(i))
    return (((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT);
  else
    return (((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L36
  mov    D59(%rip),%rax
  and    (%rax),%ebx
  mov    %ebx,%eax
  mov    D41(%rip),%rdx
  mov    (%rdx),%ecx
  sar    %cl,%eax
L0:
  pop    %rbx
  ret
L36:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L24
  mov    D31(%rip),%rax
  and    (%rax),%ebx
  mov    D53(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  sar    %cl,%eax
  jmp    L0
L24:
  mov    D5(%rip),%rax
  and    (%rax),%ebx
  mov    D58(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  sar    %cl,%eax
  jmp    L0
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  u_int32_t i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return (((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT);
  else if (IN_CLASSB(i))
    return (((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT);
  else
    return (((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L3
  mov    D25(%rip),%rax
  mov    D45(%rip),%rdx
  and    (%rax),%ebx
  mov    (%rdx),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
L3:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L8
  mov    D13(%rip),%rax
  and    (%rax),%ebx
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
  nopl   0x0(%rax)
L8:
  mov    D14(%rip),%rax
  and    (%rax),%ebx
  mov    D18(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  u_int32_t i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return (((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT);
  else if (IN_CLASSB(i))
    return (((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT);
  else
    return (((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L7
  mov    D35(%rip),%rax
  mov    D28(%rip),%rdx
  and    (%rax),%ebx
  mov    (%rdx),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
L7:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L16
  mov    D3(%rip),%rax
  and    (%rax),%ebx
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
  nopl   0x0(%rax)
L16:
  mov    D1(%rip),%rax
  and    (%rax),%ebx
  mov    D47(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  u_int32_t i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return (((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT);
  else if (IN_CLASSB(i))
    return (((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT);
  else
    return (((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bitwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %edx,%edi
  mov    %ecx,%edx
  mov    %esi,%ecx
  shr    $0x5,%ecx
  mov    %ecx,%ecx
  shl    $0x2,%rcx
  add    %rcx,%rax
  and    $0x1f,%esi
  cmp    $0x20,%edi
  jne    L52
  mov    (%rax),%edi
  mov    (%rax),%r8d
  mov    $0x1,%r9d
  mov    %esi,%ecx
  shl    %cl,%r9d
  mov    %r9d,%ecx
  sub    $0x1,%ecx
  and    %ecx,%r8d
  mov    %edx,%r10d
  mov    %esi,%ecx
  shl    %cl,%r10d
  mov    %r10d,%ecx
  or     %r8d,%ecx
  or     %edi,%ecx
  mov    %ecx,(%rax)
  test   %esi,%esi
  je     L26
  add    $0x4,%rax
  mov    (%rax),%edi
  mov    $0x1,%r8d
  mov    %esi,%ecx
  shl    %cl,%r8d
  mov    %r8d,%ecx
  neg    %ecx
  and    %ecx,%edi
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shr    %cl,%edx
  or     %edi,%edx
  mov    %edx,(%rax)
  jmp    L32
L52:
  lea    (%rsi,%rdi,1),%ecx
  cmp    $0x20,%ecx
  ja     L57
  mov    (%rax),%r8d
  mov    $0x1,%r9d
  mov    %edi,%ecx
  shl    %cl,%r9d
  mov    %r9d,%ecx
  lea    -0x1(%rcx),%edi
  mov    %esi,%ecx
  shl    %cl,%edi
  mov    %edi,%ecx
  not    %ecx
  mov    %r8d,%edi
  and    %ecx,%edi
  mov    %esi,%ecx
  shl    %cl,%edx
  or     %edi,%edx
  mov    %edx,(%rax)
  jmp    L32
L57:
  mov    (%rax),%r8d
  mov    $0x1,%r9d
  mov    %esi,%ecx
  shl    %cl,%r9d
  mov    %r9d,%ecx
  sub    $0x1,%ecx
  and    %ecx,%r8d
  mov    %edx,%r11d
  mov    %esi,%ecx
  shl    %cl,%r11d
  mov    %r11d,%ecx
  or     %r8d,%ecx
  mov    %ecx,(%rax)
  add    $0x4,%rax
  lea    (%rsi,%rdi,1),%ecx
  lea    -0x20(%rcx),%edi
  mov    (%rax),%r8d
  mov    $0x1,%r9d
  mov    %edi,%ecx
  shl    %cl,%r9d
  mov    %r9d,%ecx
  neg    %ecx
  mov    %r8d,%edi
  and    %ecx,%edi
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shr    %cl,%edx
  or     %edi,%edx
  mov    %edx,(%rax)
  jmp    L32
L26:
  nop
L32:
  pop    %rbp
  ret
```

assistant: ```c
void bitwrite(register unsigned int *e, register unsigned int p, register unsigned int len, register unsigned int s) {
  e += p / 32;
  p %= 32;
  if (len == 32) {
    *e |= (*e & ((1 << p) - 1)) | (s << p);
    if (!p)
      return;
    e++;
    *e = (*e & ~((1 << p) - 1)) | (s >> (32 - p));
  } else {
    if (p + len <= 32) {
      *e = (*e & ~(((1 << len) - 1) << p)) | (s << p);
      return;
    }
    *e = (*e & ((1 << p) - 1)) | (s << p);
    e++;
    len -= 32 - p;
    *e = (*e & ~((1 << len) - 1)) | (s >> (32 - p));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitwrite>:
  endbr64
  mov    %ecx,%eax
  mov    %esi,%ecx
  shr    $0x5,%ecx
  mov    %ecx,%ecx
  lea    (%rdi,%rcx,4),%rdi
  and    $0x1f,%esi
  cmp    $0x20,%edx
  je     L0
  lea    (%rsi,%rdx,1),%r9d
  cmp    $0x20,%r9d
  jbe    L17
  mov    $0x1,%edx
  mov    %edx,%r8d
  mov    %esi,%ecx
  shl    %cl,%r8d
  sub    $0x1,%r8d
  and    (%rdi),%r8d
  mov    %eax,%r10d
  shl    %cl,%r10d
  or     %r10d,%r8d
  mov    %r8d,(%rdi)
  lea    -0x20(%r9),%ecx
  shl    %cl,%edx
  neg    %edx
  and    0x4(%rdi),%edx
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shr    %cl,%eax
  or     %eax,%edx
  mov    %edx,0x4(%rdi)
L21:
  ret
L0:
  mov    $0x1,%edx
  mov    %esi,%ecx
  shl    %cl,%edx
  mov    %eax,%r11d
  shl    %cl,%r11d
  or     %r11d,(%rdi)
  test   %esi,%esi
  je     L21
  neg    %edx
  and    0x4(%rdi),%edx
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shr    %cl,%eax
  or     %eax,%edx
  mov    %edx,0x4(%rdi)
  ret
L17:
  mov    $0x1,%r8d
  mov    %edx,%ecx
  shl    %cl,%r8d
  lea    -0x1(%r8),%edx
  mov    %esi,%ecx
  shl    %cl,%edx
  not    %edx
  and    (%rdi),%edx
  shl    %cl,%eax
  or     %eax,%edx
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void bitwrite(register unsigned int *e, register unsigned int p, register unsigned int len, register unsigned int s) {
  e += p / 32;
  p %= 32;
  if (len == 32) {
    *e |= (*e & ((1 << p) - 1)) | (s << p);
    if (!p)
      return;
    e++;
    *e = (*e & ~((1 << p) - 1)) | (s >> (32 - p));
  } else {
    if (p + len <= 32) {
      *e = (*e & ~(((1 << len) - 1) << p)) | (s << p);
      return;
    }
    *e = (*e & ((1 << p) - 1)) | (s << p);
    e++;
    len -= 32 - p;
    *e = (*e & ~((1 << len) - 1)) | (s >> (32 - p));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitwrite>:
  endbr64
  mov    %ecx,%eax
  mov    %esi,%ecx
  mov    %esi,%r8d
  shr    $0x5,%ecx
  mov    %eax,%r9d
  and    $0x1f,%r8d
  lea    (%rdi,%rcx,4),%rdi
  mov    %esi,%ecx
  mov    (%rdi),%r10d
  shl    %cl,%r9d
  cmp    $0x20,%edx
  je     L29
  lea    (%r8,%rdx,1),%r11d
  cmp    $0x20,%r11d
  jbe    L22
  mov    $0x1,%edx
  mov    %r8d,%ecx
  mov    %edx,%esi
  shl    %cl,%esi
  lea    -0x20(%r11),%ecx
  shl    %cl,%edx
  mov    $0x20,%ecx
  sub    $0x1,%esi
  sub    %r8d,%ecx
  and    %r10d,%esi
  neg    %edx
  and    0x4(%rdi),%edx
  shr    %cl,%eax
  or     %r9d,%esi
  or     %eax,%edx
  mov    %esi,(%rdi)
  mov    %edx,0x4(%rdi)
L26:
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %edx,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %r8d,%ecx
  sub    $0x1,%eax
  shl    %cl,%eax
  not    %eax
  and    %r10d,%eax
  or     %r9d,%eax
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L29:
  mov    $0x1,%esi
  mov    %r8d,%ecx
  or     %r9d,%r10d
  mov    %r10d,(%rdi)
  shl    %cl,%esi
  test   %r8d,%r8d
  je     L26
  sub    %r8d,%edx
  neg    %esi
  and    0x4(%rdi),%esi
  mov    %edx,%ecx
  shr    %cl,%eax
  or     %eax,%esi
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void bitwrite(register unsigned int *e, register unsigned int p, register unsigned int len, register unsigned int s) {
  e += p / 32;
  p %= 32;
  if (len == 32) {
    *e |= (*e & ((1 << p) - 1)) | (s << p);
    if (!p)
      return;
    e++;
    *e = (*e & ~((1 << p) - 1)) | (s >> (32 - p));
  } else {
    if (p + len <= 32) {
      *e = (*e & ~(((1 << len) - 1) << p)) | (s << p);
      return;
    }
    *e = (*e & ((1 << p) - 1)) | (s << p);
    e++;
    len -= 32 - p;
    *e = (*e & ~((1 << len) - 1)) | (s >> (32 - p));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitwrite>:
  endbr64
  mov    %ecx,%eax
  mov    %esi,%ecx
  mov    %esi,%r8d
  shr    $0x5,%ecx
  mov    %eax,%r9d
  and    $0x1f,%r8d
  lea    (%rdi,%rcx,4),%rdi
  mov    %esi,%ecx
  mov    (%rdi),%r10d
  shl    %cl,%r9d
  cmp    $0x20,%edx
  je     L18
  lea    (%r8,%rdx,1),%r11d
  cmp    $0x20,%r11d
  jbe    L0
  mov    $0x1,%edx
  mov    %r8d,%ecx
  mov    %edx,%esi
  shl    %cl,%esi
  lea    -0x20(%r11),%ecx
  shl    %cl,%edx
  mov    $0x20,%ecx
  sub    $0x1,%esi
  sub    %r8d,%ecx
  and    %r10d,%esi
  neg    %edx
  and    0x4(%rdi),%edx
  shr    %cl,%eax
  or     %r9d,%esi
  or     %eax,%edx
  mov    %esi,(%rdi)
  mov    %edx,0x4(%rdi)
L7:
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %edx,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %r8d,%ecx
  sub    $0x1,%eax
  shl    %cl,%eax
  not    %eax
  and    %r10d,%eax
  or     %r9d,%eax
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x1,%esi
  mov    %r8d,%ecx
  or     %r9d,%r10d
  mov    %r10d,(%rdi)
  shl    %cl,%esi
  test   %r8d,%r8d
  je     L7
  sub    %r8d,%edx
  neg    %esi
  and    0x4(%rdi),%esi
  mov    %edx,%ecx
  shr    %cl,%eax
  or     %eax,%esi
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void bitwrite(register unsigned int *e, register unsigned int p, register unsigned int len, register unsigned int s) {
  e += p / 32;
  p %= 32;
  if (len == 32) {
    *e |= (*e & ((1 << p) - 1)) | (s << p);
    if (!p)
      return;
    e++;
    *e = (*e & ~((1 << p) - 1)) | (s >> (32 - p));
  } else {
    if (p + len <= 32) {
      *e = (*e & ~(((1 << len) - 1) << p)) | (s << p);
      return;
    }
    *e = (*e & ((1 << p) - 1)) | (s << p);
    e++;
    len -= 32 - p;
    *e = (*e & ~((1 << len) - 1)) | (s >> (32 - p));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<BLNK_QuickHashName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L8:
  mov    -0x10(%rbp),%eax
  imul   $0xfb,%eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x10(%rbp),%eax
  imul   $0xfb,%eax,%eax
  sar    $0x8,%eax
  and    $0xfff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int BLNK_QuickHashName(char *name) {
  char *s;
  int i, hi;
  i = 0;
  s = name;
  while (*s)
    i = i * 251 + (*s++);
  hi = ((i * 251) >> 8) & 0xFFF;
  return (hi);
}
```
user: Translate the below assembly code into C programming language:

```asm
<BLNK_QuickHashName>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
  mov    $0x0,%edx
L15:
  imul   $0xfb,%edx,%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L15
L10:
  imul   $0xfb,%edx,%eax
  sar    $0x8,%eax
  and    $0xfff,%eax
  ret
L28:
  mov    $0x0,%edx
  jmp    L10
```

assistant: ```c
int BLNK_QuickHashName(char *name) {
  char *s;
  int i, hi;
  i = 0;
  s = name;
  while (*s)
    i = i * 251 + (*s++);
  hi = ((i * 251) >> 8) & 0xFFF;
  return (hi);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<BLNK_QuickHashName>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L2
  xor    %edx,%edx
  nopl   (%rax)
L14:
  imul   $0xfb,%edx,%edx
  add    $0x1,%rdi
  add    %eax,%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L14
  imul   $0xfb,%edx,%eax
  sar    $0x8,%eax
  and    $0xfff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int BLNK_QuickHashName(char *name) {
  char *s;
  int i, hi;
  i = 0;
  s = name;
  while (*s)
    i = i * 251 + (*s++);
  hi = ((i * 251) >> 8) & 0xFFF;
  return (hi);
}
```
user: What is the c source code of the assembly code below?

```asm
<BLNK_QuickHashName>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L3
  xor    %edx,%edx
  nopl   (%rax)
L14:
  imul   $0xfb,%edx,%edx
  add    $0x1,%rdi
  add    %eax,%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L14
  imul   $0xfb,%edx,%eax
  sar    $0x8,%eax
  and    $0xfff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int BLNK_QuickHashName(char *name) {
  char *s;
  int i, hi;
  i = 0;
  s = name;
  while (*s)
    i = i * 251 + (*s++);
  hi = ((i * 251) >> 8) & 0xFFF;
  return (hi);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <readline@plt>
  test   %rax,%rax
  je     L3
  mov    $0xffffffff,%eax
  jmp    L19
L3:
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
L19:
  leave
  ret
```

assistant: ```c
int readnum(char *buf, size_t buf_size) {
  if (readline(buf, buf_size))
    return -1;
  return strtol(&buf[0], NULL, 10);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readnum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <readline@plt>
  test   %rax,%rax
  jne    L8
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strtol@plt>
L3:
  pop    %rbx
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int readnum(char *buf, size_t buf_size) {
  if (readline(buf, buf_size))
    return -1;
  return strtol(&buf[0], NULL, 10);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readnum>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <readline@plt>
  test   %rax,%rax
  jne    L9
  mov    %rbp,%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  pop    %rbp
  jmp    1070 <strtol@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int readnum(char *buf, size_t buf_size) {
  if (readline(buf, buf_size))
    return -1;
  return strtol(&buf[0], NULL, 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readnum>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <readline@plt>
  test   %rax,%rax
  jne    L0
  mov    %rbp,%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  pop    %rbp
  jmp    1070 <strtol@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int readnum(char *buf, size_t buf_size) {
  if (readline(buf, buf_size))
    return -1;
  return strtol(&buf[0], NULL, 10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inotifytools_get_max_queued_events>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <read_num_from_file@plt>
  test   %eax,%eax
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L18
L8:
  mov    -0xc(%rbp),%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: /proc/sys/fs/inotify/max_queued_watches

assistant: ```c
int inotifytools_get_max_queued_events() {
  int ret;
  if (!read_num_from_file("/proc/sys/fs/inotify/"
                          "max_queued_watches",
                          &ret))
    return -1;
  return ret;
}
```