ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tcp_connect>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    D8(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <inet_addr@plt>
  movd   (%rbx),%xmm0
  mov    %ebp,%edi
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0xc(%rsp)
  call   <htons@plt>
  lea    0x8(%rsp),%rsi
  mov    $0xc,%edx
  mov    %r12d,%edi
  mov    %eax,0x8(%rsp)
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L27
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L27:
  mov    $0xffffffff,%r12d
  jmp    L22
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tcp_connect(const char *host, int port) {
  int fd = socket(AF_INET, SOCK_STREAM, 0);
  if (fd == -1) {
    return -1;
  }
  struct sockaddr_in my_addr;
  my_addr.sin_addr.s_addr = inet_addr(host);
  my_addr.sin_family = AF_INET;
  my_addr.sin_port = htons(port);
  if (connect(fd, (struct sockaddr *)&my_addr, sizeof(struct sockaddr_in)) == -1) {
    return -1;
  }
  return fd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L30
L8:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L30:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jle    L8
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L42
L12:
  addl   $0x1,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L42:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L12
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string

tool: D11: %d

tool: D6: %d


assistant: ```c
int main() {
  int x, z, i, cont = 1;
  scanf("%d", &x);
  for (z = x; z <= x;)
    scanf("%d", &z);
  i = x;
  while (x <= z) {
    i++;
    x = x + i;
    cont++;
  }
  printf("%d\n", cont);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  lea    D9(%rip),%rbx
L5:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  cmp    %edx,%ecx
  jle    L5
  mov    %edx,%eax
  mov    $0x1,%esi
L13:
  lea    (%rsi,%rdx,1),%edi
  add    %edi,%eax
  add    $0x1,%esi
  cmp    %eax,%ecx
  jge    L13
  mov    %eax,(%rsp)
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D1
type_infered: string

tool: D9: %d

tool: D1: %d


assistant: ```c
int main() {
  int x, z, i, cont = 1;
  scanf("%d", &x);
  for (z = x; z <= x;)
    scanf("%d", &z);
  i = x;
  while (x <= z) {
    i++;
    x = x + i;
    cont++;
  }
  printf("%d\n", cont);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rbp
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  cmp    %edx,%ecx
  jle    L21
  mov    %edx,%eax
  mov    $0x1,%esi
  nopl   (%rax)
L3:
  lea    (%rdx,%rsi,1),%edi
  add    $0x1,%esi
  add    %edi,%eax
  cmp    %eax,%ecx
  jge    L3
  lea    D3(%rip),%rdi
  mov    %eax,(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
type: string
name: disassemble_data
arguments: label: D3
type: string

tool: D19: %d

tool: D3: %d


assistant: ```c
int main() {
  int x, z, i, cont = 1;
  scanf("%d", &x);
  for (z = x; z <= x;)
    scanf("%d", &z);
  i = x;
  while (x <= z) {
    i++;
    x = x + i;
    cont++;
  }
  printf("%d\n", cont);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rbp
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  cmp    %edx,%ecx
  jle    L3
  mov    %edx,%eax
  mov    $0x1,%esi
  nopl   (%rax)
L29:
  lea    (%rsi,%rdx,1),%edi
  add    $0x1,%esi
  add    %edi,%eax
  cmp    %eax,%ecx
  jge    L29
  lea    D6(%rip),%rdi
  mov    %eax,(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
data_type: string
name: parse_data
arguments: data_label: D6
data_type: string

tool: D19: %d

tool: D6: %d


assistant: ```c
int main() {
  int x, z, i, cont = 1;
  scanf("%d", &x);
  for (z = x; z <= x;)
    scanf("%d", &z);
  i = x;
  while (x <= z) {
    i++;
    x = x + i;
    cont++;
  }
  printf("%d\n", cont);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aes_expandEncKey>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  movzbl 0x1d(%rcx),%esi
  movzbl (%rcx),%eax
  xor    (%rdi),%al
  xor    (%rdx,%rsi,1),%al
  mov    %al,(%rcx)
  movzbl 0x1e(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x1(%rcx)
  movzbl 0x1f(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x2(%rcx)
  movzbl 0x1c(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x3(%rcx)
  movzbl (%rdi),%esi
  mov    %esi,%eax
  shr    $0x7,%al
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rax,8),%eax
  add    %esi,%esi
  xor    %eax,%esi
  mov    %sil,(%rdi)
  lea    0xc(%rcx),%rdi
  mov    %rcx,%rax
L10:
  movzbl (%rax),%esi
  xor    %sil,0x4(%rax)
  movzbl 0x1(%rax),%esi
  xor    %sil,0x5(%rax)
  movzbl 0x2(%rax),%esi
  xor    %sil,0x6(%rax)
  movzbl 0x3(%rax),%esi
  xor    %sil,0x7(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L10
  movzbl 0xc(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x10(%rcx)
  movzbl 0xd(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x11(%rcx)
  movzbl 0xe(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x12(%rcx)
  movzbl 0xf(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x13(%rcx)
  lea    0x10(%rcx),%rax
  add    $0x1c,%rcx
L5:
  movzbl (%rax),%edx
  xor    %dl,0x4(%rax)
  movzbl 0x1(%rax),%edx
  xor    %dl,0x5(%rax)
  movzbl 0x2(%rax),%edx
  xor    %dl,0x6(%rax)
  movzbl 0x3(%rax),%edx
  xor    %dl,0x7(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L5
  ret
```

assistant: ```c
void aes_expandEncKey(unsigned char *k, unsigned char *rc, const unsigned char *sb) {
  register unsigned char i;
  k[0] ^= sb[k[29]] ^ (*rc);
  k[1] ^= sb[k[30]];
  k[2] ^= sb[k[31]];
  k[3] ^= sb[k[28]];
  *rc = (((*rc) << 1) ^ ((((*rc) >> 7) & 1) * 0x1b));
  for (i = 4; i < 16; i += 4) {
    k[i] ^= k[i - 4];
    k[i + 1] ^= k[i - 3];
    k[i + 2] ^= k[i - 2];
    k[i + 3] ^= k[i - 1];
  }
  k[16] ^= sb[k[12]];
  k[17] ^= sb[k[13]];
  k[18] ^= sb[k[14]];
  k[19] ^= sb[k[15]];
  for (i = 20; i < 32; i += 4) {
    k[i] ^= k[i - 4];
    k[i + 1] ^= k[i - 3];
    k[i + 2] ^= k[i - 2];
    k[i + 3] ^= k[i - 1];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aes_expandEncKey>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  movzbl 0x1d(%rcx),%esi
  movzbl (%rcx),%eax
  xor    (%rdi),%al
  xor    (%rdx,%rsi,1),%al
  mov    %al,(%rcx)
  movzbl 0x1e(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x1(%rcx)
  movzbl 0x1f(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x2(%rcx)
  movzbl 0x1c(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x3(%rcx)
  movzbl (%rdi),%esi
  mov    %esi,%eax
  add    %esi,%esi
  shr    $0x7,%al
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rax,8),%eax
  xor    %eax,%esi
  mov    %rcx,%rax
  mov    %sil,(%rdi)
  lea    0xc(%rcx),%rdi
L1:
  movzbl (%rax),%esi
  xor    %sil,0x4(%rax)
  movzbl 0x1(%rax),%esi
  xor    %sil,0x5(%rax)
  movzbl 0x2(%rax),%esi
  xor    %sil,0x6(%rax)
  movzbl 0x3(%rax),%esi
  xor    %sil,0x7(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L1
  movzbl 0xc(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x10(%rcx)
  movzbl 0xd(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x11(%rcx)
  movzbl 0xe(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x12(%rcx)
  movzbl 0xf(%rcx),%eax
  movzbl (%rdx,%rax,1),%eax
  xor    %al,0x13(%rcx)
  lea    0x10(%rcx),%rax
  add    $0x1c,%rcx
L2:
  movzbl (%rax),%edx
  xor    %dl,0x4(%rax)
  movzbl 0x1(%rax),%edx
  xor    %dl,0x5(%rax)
  movzbl 0x2(%rax),%edx
  xor    %dl,0x6(%rax)
  movzbl 0x3(%rax),%edx
  xor    %dl,0x7(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L2
  ret
```

assistant: ```c
void aes_expandEncKey(unsigned char *k, unsigned char *rc, const unsigned char *sb) {
  register unsigned char i;
  k[0] ^= sb[k[29]] ^ (*rc);
  k[1] ^= sb[k[30]];
  k[2] ^= sb[k[31]];
  k[3] ^= sb[k[28]];
  *rc = (((*rc) << 1) ^ ((((*rc) >> 7) & 1) * 0x1b));
  for (i = 4; i < 16; i += 4) {
    k[i] ^= k[i - 4];
    k[i + 1] ^= k[i - 3];
    k[i + 2] ^= k[i - 2];
    k[i + 3] ^= k[i - 1];
  }
  k[16] ^= sb[k[12]];
  k[17] ^= sb[k[13]];
  k[18] ^= sb[k[14]];
  k[19] ^= sb[k[15]];
  for (i = 20; i < 32; i += 4) {
    k[i] ^= k[i - 4];
    k[i + 1] ^= k[i - 3];
    k[i + 2] ^= k[i - 2];
    k[i + 3] ^= k[i - 1];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aes_expandEncKey>:
  endbr64
  mov    %rdi,%rax
  mov    %rdx,%rdi
  movzbl 0x1d(%rax),%ecx
  movzbl (%rax),%edx
  xor    (%rsi),%dl
  xor    (%rdi,%rcx,1),%dl
  mov    %dl,(%rax)
  movzbl 0x1e(%rax),%edx
  movzbl (%rdi,%rdx,1),%edx
  xor    %dl,0x1(%rax)
  movzbl 0x1f(%rax),%edx
  movzbl (%rdi,%rdx,1),%edx
  xor    %dl,0x2(%rax)
  movzbl 0x1c(%rax),%edx
  movzbl (%rdi,%rdx,1),%edx
  xor    %dl,0x3(%rax)
  movzbl (%rsi),%ecx
  mov    %ecx,%edx
  add    %ecx,%ecx
  shr    $0x7,%dl
  lea    (%rdx,%rdx,2),%edx
  lea    (%rdx,%rdx,8),%edx
  xor    %edx,%ecx
  mov    %cl,(%rsi)
  movzbl (%rax),%r8d
  xor    0x4(%rax),%r8b
  movzbl 0x3(%rax),%edx
  movzbl 0x2(%rax),%ecx
  xor    0x7(%rax),%dl
  mov    %r8b,0x4(%rax)
  xor    0x6(%rax),%cl
  xor    0x8(%rax),%r8b
  mov    %dl,0x7(%rax)
  movzbl 0x1(%rax),%esi
  xor    0x5(%rax),%sil
  mov    %cl,0x6(%rax)
  mov    %sil,0x5(%rax)
  mov    %r8b,0x8(%rax)
  xor    0x9(%rax),%sil
  xor    0xa(%rax),%cl
  xor    0xb(%rax),%dl
  mov    %sil,0x9(%rax)
  xor    0xc(%rax),%r8b
  xor    0xd(%rax),%sil
  mov    %cl,0xa(%rax)
  mov    %dl,0xb(%rax)
  xor    0xe(%rax),%cl
  mov    %r8b,0xc(%rax)
  xor    0xf(%rax),%dl
  movzbl %r8b,%r8d
  mov    %sil,0xd(%rax)
  movzbl %sil,%esi
  mov    %cl,0xe(%rax)
  movzbl %cl,%ecx
  mov    %dl,0xf(%rax)
  movzbl (%rdi,%r8,1),%r8d
  movzbl %dl,%edx
  xor    0x10(%rax),%r8b
  mov    %r8b,0x10(%rax)
  movzbl (%rdi,%rsi,1),%esi
  xor    0x11(%rax),%sil
  mov    %sil,0x11(%rax)
  movzbl (%rdi,%rcx,1),%ecx
  xor    0x12(%rax),%cl
  xor    0x15(%rax),%sil
  mov    %cl,0x12(%rax)
  movzbl (%rdi,%rdx,1),%edx
  movzbl 0x14(%rax),%edi
  xor    0x16(%rax),%cl
  mov    %sil,0x15(%rax)
  xor    0x13(%rax),%dl
  mov    %cl,0x16(%rax)
  xor    %r8d,%edi
  mov    %dl,0x13(%rax)
  mov    %dil,0x14(%rax)
  xor    0x17(%rax),%dl
  xor    0x19(%rax),%sil
  xor    0x1a(%rax),%cl
  mov    %dl,0x17(%rax)
  xor    0x18(%rax),%dil
  xor    0x1b(%rax),%dl
  mov    %sil,0x19(%rax)
  xor    %dil,0x1c(%rax)
  mov    %dil,0x18(%rax)
  xor    %sil,0x1d(%rax)
  xor    %cl,0x1e(%rax)
  xor    %dl,0x1f(%rax)
  mov    %cl,0x1a(%rax)
  mov    %dl,0x1b(%rax)
  ret
```

assistant: ```c
void aes_expandEncKey(unsigned char *k, unsigned char *rc, const unsigned char *sb) {
  register unsigned char i;
  k[0] ^= sb[k[29]] ^ (*rc);
  k[1] ^= sb[k[30]];
  k[2] ^= sb[k[31]];
  k[3] ^= sb[k[28]];
  *rc = (((*rc) << 1) ^ ((((*rc) >> 7) & 1) * 0x1b));
  for (i = 4; i < 16; i += 4) {
    k[i] ^= k[i - 4];
    k[i + 1] ^= k[i - 3];
    k[i + 2] ^= k[i - 2];
    k[i + 3] ^= k[i - 1];
  }
  k[16] ^= sb[k[12]];
  k[17] ^= sb[k[13]];
  k[18] ^= sb[k[14]];
  k[19] ^= sb[k[15]];
  for (i = 20; i < 32; i += 4) {
    k[i] ^= k[i - 4];
    k[i + 1] ^= k[i - 3];
    k[i + 2] ^= k[i - 2];
    k[i + 3] ^= k[i - 1];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_v_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L1
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xfffffff7,%eax
  jne    L33
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L0
L33:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L0:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffff9d,%eax
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D24
type: string

tool: D0: v-list dump:

tool: D11:  | 

tool: D24: %d 

assistant: ```c
void dump_v_list(int *sorted_v_list) {
  int i = 0;
  printf("v-list dump:\n");
  while (*(sorted_v_list + i) != -99) {
    if (*(sorted_v_list + i) == -9) {
      printf(" | ");
    } else {
      printf("%d ", *(sorted_v_list + i));
    }
    i++;
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dump_v_list>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%esi
  cmp    $0xffffff9d,%esi
  je     L12
  add    $0x4,%rbx
  lea    D27(%rip),%rbp
  lea    D5(%rip),%r12
  jmp    L14
L30:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L27:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  cmp    $0xffffff9d,%esi
  je     L12
L14:
  cmp    $0xfffffff7,%esi
  je     L30
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L27
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D15
data_type: string
name: read_data
arguments: label: D27
data_type: string
name: read_data
arguments: label: D5
data_type: string

tool: D15: v-list dump:

tool: D27: %d 

tool: D5:  | 

assistant: ```c
void dump_v_list(int *sorted_v_list) {
  int i = 0;
  printf("v-list dump:\n");
  while (*(sorted_v_list + i) != -99) {
    if (*(sorted_v_list + i) == -9) {
      printf(" | ");
    } else {
      printf("%d ", *(sorted_v_list + i));
    }
    i++;
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_v_list>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%esi
  cmp    $0xffffff9d,%esi
  je     L33
  add    $0x4,%rbx
  lea    D16(%rip),%rbp
  lea    D14(%rip),%r12
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  cmp    $0xffffff9d,%esi
  je     L33
L17:
  cmp    $0xfffffff7,%esi
  jne    L25
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  cmp    $0xffffff9d,%esi
  jne    L17
L33:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D14
type: string

tool: D1: v-list dump:

tool: D16: %d 

tool: D14:  | 

assistant: ```c
void dump_v_list(int *sorted_v_list) {
  int i = 0;
  printf("v-list dump:\n");
  while (*(sorted_v_list + i) != -99) {
    if (*(sorted_v_list + i) == -9) {
      printf(" | ");
    } else {
      printf("%d ", *(sorted_v_list + i));
    }
    i++;
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_v_list>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%esi
  cmp    $0xffffff9d,%esi
  je     L20
  add    $0x4,%rbx
  lea    D5(%rip),%rbp
  lea    D29(%rip),%r12
L18:
  cmp    $0xfffffff7,%esi
  je     L38
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  cmp    $0xffffff9d,%esi
  jne    L18
L20:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
  nopl   0x0(%rax)
L38:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  cmp    $0xffffff9d,%esi
  jne    L18
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D29
type: string

tool: D13: v-list dump:

tool: D5: %d 

tool: D29:  | 

assistant: ```c
void dump_v_list(int *sorted_v_list) {
  int i = 0;
  printf("v-list dump:\n");
  while (*(sorted_v_list + i) != -99) {
    if (*(sorted_v_list + i) == -9) {
      printf(" | ");
    } else {
      printf("%d ", *(sorted_v_list + i));
    }
    i++;
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
L47:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  jg     L49
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  jmp    L39
L68:
  mov    -0x38(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L25
  mov    -0x3c(%rbp),%eax
  cltq
  movl   $0x1,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x38(%rbp)
L49:
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  jg     L68
  jmp    L9
L25:
  nop
L9:
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  jle    L54
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L47
L54:
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L47
L39:
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D35
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D26
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D47
type_infered: string

tool: D2: Enter a number: 

tool: D29: %ld

tool: D35: Error: the value of number is invailded.


tool: D26: Repeated digit


tool: D47: No repeated digit


assistant: ```c
int main(void) {
  bool digit_seen[10] = {false};
  int digit;
  long n;
  while (1) {
    printf("Enter a number: ");
    scanf("%ld", &n);
    if (n <= 0) {
      printf("Error: the value of number is invailded.\n");
      break;
    }
    while (n > 0) {
      digit = n % 10;
      if (digit_seen[digit])
        break;
      digit_seen[digit] = true;
      n /= 10;
    }
    if (n > 0)
      printf("Repeated digit\n");
    else
      printf("No repeated digit\n");
  }
  return 0;
}
```