user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x40(%rbp)
  jle    L216
  movl   $0x0,-0x44(%rbp)
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  lea    D27(%rip),%r15
  jmp    L227
L235:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L178
  orq    $0x0,-0x8(%rsp,%rdx,1)
L178:
  mov    %rsp,%rbx
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,-0x58(%rbp)
  movl   $0x0,(%rax)
  mov    -0x3c(%rbp),%r8d
  test   %r8d,%r8d
  jle    L35
  lea    0x4(%rax),%r12
  mov    $0x1,%r14d
  mov    $0x0,%r13d
L67:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  mov    (%r12),%eax
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  add    $0x1,%r14d
  mov    -0x3c(%rbp),%r8d
  add    $0x4,%r12
  cmp    %r14d,%r8d
  jge    L67
L31:
  test   %r8d,%r8d
  js     L66
  mov    %rbx,%rax
  mov    %r8d,%edx
  lea    0x8(%rbx,%rdx,8),%rdx
L8:
  movl   $0x0,(%rax)
  movl   $0x0,0x4(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L8
L66:
  lea    -0x2(%r8),%eax
  mov    -0x58(%rbp),%rdi
  lea    0x8(%rdi,%rax,4),%r11
  mov    $0x2,%r12d
  jmp    L25
L35:
  mov    $0x0,%r13d
  jmp    L31
L219:
  mov    0xc(%r9),%r10d
  mov    0x14(%r9),%r14d
  cmp    %r14d,%eax
  cmovl  %r14d,%eax
  cmp    %eax,%r10d
  jg     L14
L222:
  add    $0x8,%rdx
  cmp    %r11,%rcx
  je     L17
L68:
  mov    %rdx,%r9
  mov    (%rcx),%eax
  sub    (%rdx),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  add    $0x4,%rcx
  mov    (%rcx),%eax
  sub    %esi,%eax
  cmp    %eax,0x14(%rdx)
  jge    L219
  cmp    %eax,0xc(%rdx)
  jg     L219
  mov    %eax,0x14(%rdx)
  jmp    L222
L14:
  mov    %r10d,0x14(%r9)
  jmp    L222
L93:
  test   %r8d,%r8d
  js     L204
L17:
  mov    $0x0,%eax
L42:
  mov    0x4(%rbx,%rax,8),%edx
  mov    %edx,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L42
L204:
  sub    $0x1,%r12d
  je     L175
L25:
  lea    0x1(%r13),%esi
  cmp    $0x1,%r8d
  jle    L93
  lea    0x4(%rdi),%rcx
  mov    %rbx,%rdx
  jmp    L68
L175:
  movslq %r8d,%r8
  mov    0x4(%rbx,%r8,8),%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    -0x50(%rbp),%rsp
  addl   $0x1,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x40(%rbp)
  jle    L216
L227:
  mov    %rsp,-0x50(%rbp)
  mov    -0x60(%rbp),%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edi
  movslq %edi,%rax
  lea    0xf(,%rax,8),%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L60:
  cmp    %rdx,%rsp
  je     L235
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L60
L216:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L166
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L166:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D27
type: string
name: read_data
arguments: data_tag: D28
type: string

tool: D27: %d

tool: D28: %d


assistant: ```c
int main() {
  int T, t;
  scanf("%d", &T);
  for (t = 0; t < T; t++) {
    int *stock, max = 0, min, n, k = 2, i, j, x;
    scanf("%d", &n);
    int maxprofit[n + 1][2];
    stock = (int *)malloc(sizeof(int) * (n + 1));
    stock[0] = 0;
    for (i = 1; i < n + 1; i++) {
      scanf("%d", &stock[i]);
      if (stock[i] > max)
        max = stock[i];
    }
    for (i = 0; i < n + 1; i++) {
      maxprofit[i][0] = 0;
      maxprofit[i][1] = 0;
    }
    for (i = 1; i < k + 1; i++) {
      min = max + 1;
      for (j = 2; j < n + 1; j++) {
        if ((stock[j - 1] - maxprofit[j - 2][0]) < min)
          min = stock[j - 1] - maxprofit[j - 2][0];
        x = stock[j] - min;
        if ((x > maxprofit[j][1]) && (x >= maxprofit[j - 1][1]))
          maxprofit[j][1] = x;
        if ((maxprofit[j - 1][1] > maxprofit[j][1]) && (maxprofit[j - 1][1] > x))
          maxprofit[j][1] = maxprofit[j - 1][1];
      }
      for (j = 0; j < n + 1; j++)
        maxprofit[j][0] = maxprofit[j][1];
    }
    printf("%d\n", maxprofit[n][1]);
  }
  return 0;
}
```