ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__res_dnok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
L44:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L25
  cmpl   $0x20,-0xc(%rbp)
  jle    L7
  cmpl   $0x7e,-0xc(%rbp)
  jle    L44
  mov    $0x0,%eax
  jmp    L46
L7:
  mov    $0x0,%eax
  jmp    L46
L25:
  nop
  mov    $0x1,%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
int __res_dnok(char const *dn) {
  int ch;
  char const *tmp;
  char __cil_tmp4;
  {
    {
      while (1) {
      while_continue:;
        tmp = dn;
        dn = dn + 1;
        __cil_tmp4 = *tmp;
        ch = (int)__cil_tmp4;
        if (ch != 0) {
        } else {
          goto while_break;
        }
        if (ch > 32) {
          if (ch < 127) {
          } else {
            return (0);
          }
        } else {
          return (0);
        }
      }
    while_break:;
    }
    return (1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__res_dnok>:
  endbr64
L16:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L11
  movsbl %al,%eax
  sub    $0x21,%eax
  cmp    $0x5d,%eax
  jbe    L16
  mov    $0x0,%eax
  ret
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int __res_dnok(char const *dn) {
  int ch;
  char const *tmp;
  char __cil_tmp4;
  {
    {
      while (1) {
      while_continue:;
        tmp = dn;
        dn = dn + 1;
        __cil_tmp4 = *tmp;
        ch = (int)__cil_tmp4;
        if (ch != 0) {
        } else {
          goto while_break;
        }
        if (ch > 32) {
          if (ch < 127) {
          } else {
            return (0);
          }
        } else {
          return (0);
        }
      }
    while_break:;
    }
    return (1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__res_dnok>:
  endbr64
  nopl   0x0(%rax)
L10:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L2
  sub    $0x21,%eax
  cmp    $0x5d,%al
  jbe    L10
  xor    %eax,%eax
  ret
  nopl   (%rax)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int __res_dnok(char const *dn) {
  int ch;
  char const *tmp;
  char __cil_tmp4;
  {
    {
      while (1) {
      while_continue:;
        tmp = dn;
        dn = dn + 1;
        __cil_tmp4 = *tmp;
        ch = (int)__cil_tmp4;
        if (ch != 0) {
        } else {
          goto while_break;
        }
        if (ch > 32) {
          if (ch < 127) {
          } else {
            return (0);
          }
        } else {
          return (0);
        }
      }
    while_break:;
    }
    return (1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__res_dnok>:
  endbr64
  nopl   0x0(%rax)
L8:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L6
  sub    $0x21,%eax
  cmp    $0x5d,%al
  jbe    L8
  xor    %eax,%eax
  ret
  nopl   (%rax)
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int __res_dnok(char const *dn) {
  int ch;
  char const *tmp;
  char __cil_tmp4;
  {
    {
      while (1) {
      while_continue:;
        tmp = dn;
        dn = dn + 1;
        __cil_tmp4 = *tmp;
        ch = (int)__cil_tmp4;
        if (ch != 0) {
        } else {
          goto while_break;
        }
        if (ch > 32) {
          if (ch < 127) {
          } else {
            return (0);
          }
        } else {
          return (0);
        }
      }
    while_break:;
    }
    return (1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
data_type: string
name: parse_data
arguments: tag: D12
data_type: string

tool: D14: %d=============================


tool: D12: %d==============================


assistant: ```c
int main(void) {
  int a[5] = {1, 2, 3, 4, 5};
  printf("%d=============================\n", a[4]);
  printf("%d==============================\n", 0 [a]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D18
type: string

tool: D12: %d=============================


tool: D18: %d==============================


assistant: ```c
int main(void) {
  int a[5] = {1, 2, 3, 4, 5};
  printf("%d=============================\n", a[4]);
  printf("%d==============================\n", 0 [a]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string

tool: D18: %d=============================


tool: D6: %d==============================


assistant: ```c
int main(void) {
  int a[5] = {1, 2, 3, 4, 5};
  printf("%d=============================\n", a[4]);
  printf("%d==============================\n", 0 [a]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D1
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D1: %d=============================


tool: D10: %d==============================


assistant: ```c
int main(void) {
  int a[5] = {1, 2, 3, 4, 5};
  printf("%d=============================\n", a[4]);
  printf("%d==============================\n", 0 [a]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%edi
  call   <isatty@plt>
  test   %rax,%rax
  je     L7
  mov    $0x1,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <pprint@plt>
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: exit


assistant: ```c
void get_out(int exitval) {
  if ((isatty(0)))
    pprint("exit\n", 1);
  exit(exitval);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_out>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edi
  call   <isatty@plt>
  test   %rax,%rax
  jne    L2
L19:
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
L2:
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <pprint@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: exit


assistant: ```c
void get_out(int exitval) {
  if ((isatty(0)))
    pprint("exit\n", 1);
  exit(exitval);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_out>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <isatty@plt>
  test   %rax,%rax
  jne    L4
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D1(%rip),%rdi
  mov    $0x1,%esi
  call   <pprint@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string

tool: D1: exit


assistant: ```c
void get_out(int exitval) {
  if ((isatty(0)))
    pprint("exit\n", 1);
  exit(exitval);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_out>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <isatty@plt>
  test   %rax,%rax
  jne    L9
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  lea    D5(%rip),%rdi
  mov    $0x1,%esi
  call   <pprint@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: exit


assistant: ```c
void get_out(int exitval) {
  if ((isatty(0)))
    pprint("exit\n", 1);
  exit(exitval);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nuc_str_to_ids>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L1
  mov    -0x38(%rbp),%rax
  mov    %eax,%edi
  call   <my_malloc@plt>
  mov    %rax,-0x28(%rbp)
L1:
  movq   $0x0,-0x18(%rbp)
  jmp    L7
L3:
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <nuc_char_to_id@plt>
  mov    %al,(%rbx)
  addq   $0x1,-0x18(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jl     L3
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned char *nuc_str_to_ids(unsigned char *buf, const char *str, const long len) {
  long i;
  if (buf == NULL) {
    buf = ((unsigned char *)my_malloc(sizeof(unsigned char) * len));
  }
  for (i = 0; i < len; i++) {
    buf[i] = nuc_char_to_id(str[i]);
  }
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nuc_str_to_ids>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  test   %rdi,%rdi
  je     L15
L38:
  test   %r12,%r12
  jle    L10
  mov    $0x0,%ebx
L25:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <nuc_char_to_id@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L25
L10:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %edx,%edi
  call   <my_malloc@plt>
  mov    %rax,%rbp
  jmp    L38
```

assistant: ```c
unsigned char *nuc_str_to_ids(unsigned char *buf, const char *str, const long len) {
  long i;
  if (buf == NULL) {
    buf = ((unsigned char *)my_malloc(sizeof(unsigned char) * len));
  }
  for (i = 0; i < len; i++) {
    buf[i] = nuc_char_to_id(str[i]);
  }
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nuc_str_to_ids>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L12
L30:
  test   %rbp,%rbp
  jle    L35
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L26:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <nuc_char_to_id@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L26
L35:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L12:
  mov    %edx,%edi
  call   <my_malloc@plt>
  mov    %rax,%r12
  jmp    L30
```

assistant: ```c
unsigned char *nuc_str_to_ids(unsigned char *buf, const char *str, const long len) {
  long i;
  if (buf == NULL) {
    buf = ((unsigned char *)my_malloc(sizeof(unsigned char) * len));
  }
  for (i = 0; i < len; i++) {
    buf[i] = nuc_char_to_id(str[i]);
  }
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nuc_str_to_ids>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L30
L11:
  test   %rbp,%rbp
  jle    L32
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L24:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <nuc_char_to_id@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L24
L32:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L30:
  mov    %edx,%edi
  call   <my_malloc@plt>
  mov    %rax,%r12
  jmp    L11
```

assistant: ```c
unsigned char *nuc_str_to_ids(unsigned char *buf, const char *str, const long len) {
  long i;
  if (buf == NULL) {
    buf = ((unsigned char *)my_malloc(sizeof(unsigned char) * len));
  }
  for (i = 0; i < len; i++) {
    buf[i] = nuc_char_to_id(str[i]);
  }
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L5
L10:
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  lea    -0x30(%rbp),%rax
  add    $0x28,%rax
  cmp    %rax,-0x38(%rbp)
  jb     L10
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: %3d

assistant: ```c
int main() {
  int a[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, *p;
  for (p = a; p < a + 10; printf("%3d", *p++))
    ;
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  mov    %rsp,%rbx
  lea    D1(%rip),%rbp
L9:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x28(%rsp),%rax
  cmp    %rax,%rbx
  jne    L9
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: %3d

assistant: ```c
int main() {
  int a[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, *p;
  for (p = a; p < a + 10; printf("%3d", *p++))
    ;
  getchar();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x20(%rsp)
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%esi
L12:
  add    $0x4,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L11
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: %3d

assistant: ```c
int main() {
  int a[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, *p;
  for (p = a; p < a + 10; printf("%3d", *p++))
    ;
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D38(%rip),%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  movaps %xmm0,(%rsp)
  movdqa D6(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
L18:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L18
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D25
type: string
name: read_data
arguments: label: D8
type: byte[16]
name: read_data
arguments: label: D38
type: byte[8]
name: read_data
arguments: label: D6
type: byte[16]

tool: D25: %3d

tool: {"D8": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D38": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D6": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, *p;
  for (p = a; p < a + 10; printf("%3d", *p++))
    ;
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <compress_file@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  compress_file();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <compress_file@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  compress_file();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <compress_file@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  compress_file();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <compress_file@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  compress_file();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rnd16lfsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L20
  movq   $0x1,-0x18(%rbp)
  jmp    L0
L20:
  mov    -0x18(%rbp),%rax
  shr    $0x2,%rax
  xor    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  shr    $0x3,%rax
  xor    %rax,%rdx
  mov    -0x18(%rbp),%rax
  shr    $0x5,%rax
  xor    %rdx,%rax
  and    $0x1,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  shr    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0xf,%rax
  or     %rdx,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x1,-0x18(%rbp)
  jne    L0
  movq   $0x0,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long int rnd16lfsr(unsigned long long int x) {
  unsigned long long int bit;
  if (x == 0) {
    x = 1;
  } else {
    bit = ((x >> 0) ^ (x >> 2) ^ (x >> 3) ^ (x >> 5)) & 1;
    x = (x >> 1) | (bit << 15);
    if (x == 1)
      x = 0;
  }
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rnd16lfsr>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L4
  mov    %rdi,%rax
  shr    %rax
  mov    %rdi,%rdx
  shr    $0x2,%rdx
  mov    %rdi,%rcx
  shr    $0x3,%rcx
  xor    %rcx,%rdx
  xor    %rdi,%rdx
  shr    $0x5,%rdi
  xor    %rdi,%rdx
  shl    $0xf,%rdx
  movzwl %dx,%edx
  or     %rdx,%rax
  cmp    $0x1,%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
L4:
  ret
```

assistant: ```c
unsigned long long int rnd16lfsr(unsigned long long int x) {
  unsigned long long int bit;
  if (x == 0) {
    x = 1;
  } else {
    bit = ((x >> 0) ^ (x >> 2) ^ (x >> 3) ^ (x >> 5)) & 1;
    x = (x >> 1) | (bit << 15);
    if (x == 1)
      x = 0;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rnd16lfsr>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  mov    %rdi,%rax
  shr    $0x2,%rdx
  shr    $0x3,%rcx
  xor    %rcx,%rdx
  shr    %rax
  xor    %rdi,%rdx
  shr    $0x5,%rdi
  xor    %rdi,%rdx
  shl    $0xf,%rdx
  movzwl %dx,%edx
  or     %rdx,%rax
  xor    %edx,%edx
  cmp    $0x1,%rax
  cmove  %rdx,%rax
L3:
  ret
```

assistant: ```c
unsigned long long int rnd16lfsr(unsigned long long int x) {
  unsigned long long int bit;
  if (x == 0) {
    x = 1;
  } else {
    bit = ((x >> 0) ^ (x >> 2) ^ (x >> 3) ^ (x >> 5)) & 1;
    x = (x >> 1) | (bit << 15);
    if (x == 1)
      x = 0;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rnd16lfsr>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L9
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  mov    %rdi,%rax
  shr    $0x2,%rdx
  shr    $0x3,%rcx
  xor    %rcx,%rdx
  shr    %rax
  xor    %rdi,%rdx
  shr    $0x5,%rdi
  xor    %rdi,%rdx
  shl    $0xf,%rdx
  movzwl %dx,%edx
  or     %rdx,%rax
  xor    %edx,%edx
  cmp    $0x1,%rax
  cmove  %rdx,%rax
L9:
  ret
```

assistant: ```c
unsigned long long int rnd16lfsr(unsigned long long int x) {
  unsigned long long int bit;
  if (x == 0) {
    x = 1;
  } else {
    bit = ((x >> 0) ^ (x >> 2) ^ (x >> 3) ^ (x >> 5)) & 1;
    x = (x >> 1) | (bit << 15);
    if (x == 1)
      x = 0;
  }
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fp_addexp>:
  endbr64
  mov    %edx,%r8d
  lea    0x1(%rsi),%eax
  movslq %esi,%rdx
  mov    %cl,(%rdi,%rdx,1)
  test   %r8d,%r8d
  js     L20
  add    $0x2,%esi
  cltq
  movb   $0x2b,(%rdi,%rax,1)
L11:
  cmp    $0x3e7,%r8d
  jle    L2
  movslq %r8d,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %r8d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  movslq %esi,%rdx
  lea    0x30(%rax),%ecx
  mov    %cl,(%rdi,%rdx,1)
  imul   $0xfffffc18,%eax,%eax
  add    %eax,%r8d
  lea    0x1(%rsi),%esi
L2:
  cmp    $0x63,%r8d
  jle    L27
  movslq %r8d,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %r8d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  movslq %esi,%rdx
  lea    0x30(%rax),%ecx
  mov    %cl,(%rdi,%rdx,1)
  imul   $0xffffff9c,%eax,%eax
  add    %eax,%r8d
  lea    0x1(%rsi),%esi
L27:
  movslq %r8d,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  movslq %esi,%rax
  lea    0x30(%rdx),%ecx
  mov    %cl,(%rdi,%rax,1)
  lea    0x1(%rsi),%ecx
  movslq %ecx,%rcx
  mov    $0xfffffff6,%eax
  imul   %edx,%eax
  lea    0x30(%rax,%r8,1),%eax
  mov    %al,(%rdi,%rcx,1)
  lea    0x2(%rsi),%eax
  ret
L20:
  neg    %r8d
  add    $0x2,%esi
  cltq
  movb   $0x2d,(%rdi,%rax,1)
  jmp    L11
```

assistant: ```c
int fp_addexp(char *buff, int len, int dx, int ch) {
  int dxDiv10;
  buff[len++] = ch;
  if (dx < 0) {
    dx = -dx;
    buff[len++] = '-';
  } else
    buff[len++] = '+';
  if (dx >= 1000) {
    int dxDiv1000 = ((dx) / (1000));
    buff[len++] = '0' + dxDiv1000;
    dx = dx - dxDiv1000 * 1000;
  }
  if (dx >= 100) {
    int dxDiv100 = ((dx) / (100));
    buff[len++] = '0' + dxDiv100;
    dx = dx - dxDiv100 * 100;
  }
  dxDiv10 = ((dx) / 10);
  buff[len++] = '0' + dxDiv10;
  buff[len++] = '0' + dx - dxDiv10 * 10;
  return len;
}
```