ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<send_mouse_Y_event>:
  endbr64
  push   %r12
  mov    $0xc,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  mov    %r12,%rdi
  call   <memset@plt>
  movd   %ebx,%xmm0
  mov    $0xc,%edx
  mov    %ebp,%edi
  mov    D0(%rip),%rax
  mov    %r12,%rsi
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x8(%rsp)
  call   <write@plt>
  test   %rax,%rax
  js     L3
  mov    $0xc,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    D31(%rip),%rax
  mov    D34(%rip),%rdx
  mov    %ebp,%edi
  mov    %r12,%rsi
  mov    (%rax),%eax
  movd   (%rdx),%xmm0
  mov    $0xc,%edx
  movd   %eax,%xmm2
  punpckldq %xmm2,%xmm0
  movq   %xmm0,0xc(%rsp)
  call   <write@plt>
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void send_mouse_Y_event(int uinput_fd, int pixels) {
  struct input_event ev;
  memset(&ev, 0, sizeof(struct input_event));
  ev.type = EV_REL;
  ev.code = REL_Y;
  ev.value = pixels;
  if (write(uinput_fd, &ev, sizeof(struct input_event)) < 0)
    return;
  memset(&ev, 0, sizeof(struct input_event));
  ev.type = EV_SYN;
  ev.code = SYN_REPORT;
  if (write(uinput_fd, &ev, sizeof(struct input_event)) < 0)
    return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L15:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x30(%rbp),%eax
  cmp    $0x30,%al
  je     L10
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <solve@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L15
L10:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D11
type: string

tool: D0: %s

tool: D11: %lld

assistant: ```c
int main() {
  long long int i, j, c, len, temp, t, res;
  long long int num;
  char str[30];
  while (1) {
    scanf("%s", str);
    if (str[0] == '0')
      break;
    else {
      printf("%lld", solve(str, 0, strlen(str) - 1));
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D1(%rip),%rbp
  lea    D4(%rip),%r12
  jmp    L4
L12:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <solve@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpb   $0x30,(%rsp)
  jne    L12
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string

tool: D1: %s

tool: D4: %lld

assistant: ```c
int main() {
  long long int i, j, c, len, temp, t, res;
  long long int num;
  char str[30];
  while (1) {
    scanf("%s", str);
    if (str[0] == '0')
      break;
    else {
      printf("%lld", solve(str, 0, strlen(str) - 1));
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L12
  nop
L20:
  mov    %rbx,%rdi
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  lea    -0x1(%rax),%rdx
  call   <solve@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L12:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpb   $0x30,(%rsp)
  jne    L20
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D11: %lld

tool: D3: %s

assistant: ```c
int main() {
  long long int i, j, c, len, temp, t, res;
  long long int num;
  char str[30];
  while (1) {
    scanf("%s", str);
    if (str[0] == '0')
      break;
    else {
      printf("%lld", solve(str, 0, strlen(str) - 1));
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L28
  nop
L18:
  mov    %rbx,%rdi
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  lea    -0x1(%rax),%rdx
  call   <solve@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L28:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpb   $0x30,(%rsp)
  jne    L18
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string

tool: D6: %lld

tool: D0: %s

assistant: ```c
int main() {
  long long int i, j, c, len, temp, t, res;
  long long int num;
  char str[30];
  while (1) {
    scanf("%s", str);
    if (str[0] == '0')
      break;
    else {
      printf("%lld", solve(str, 0, strlen(str) - 1));
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clear_t10k_comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <clear_compression_mode_pg@plt>
  leave
  ret
```

assistant: ```c
uint8_t clear_t10k_comp(struct list_head *m) {
  ;
  return clear_compression_mode_pg(m);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<clear_t10k_comp>:
  endbr64
  sub    $0x8,%rsp
  call   <clear_compression_mode_pg@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t clear_t10k_comp(struct list_head *m) {
  ;
  return clear_compression_mode_pg(m);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_t10k_comp>:
  endbr64
  jmp    1050 <clear_compression_mode_pg@plt>
```

assistant: ```c
uint8_t clear_t10k_comp(struct list_head *m) {
  ;
  return clear_compression_mode_pg(m);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clear_t10k_comp>:
  endbr64
  jmp    1050 <clear_compression_mode_pg@plt>
```

assistant: ```c
uint8_t clear_t10k_comp(struct list_head *m) {
  ;
  return clear_compression_mode_pg(m);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<warshall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L80:
  movl   $0x0,-0x8(%rbp)
  jmp    L42
L54:
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L72:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L65
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L65
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L65
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x31,(%rax)
L65:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L72
  addl   $0x1,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L54
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L80
  nop
  pop    %rbp
  ret
```

assistant: ```c
void warshall(char **matrix, int dimension) {
  int k, i, j;
  for (k = 0; k < dimension; k++) {
    for (i = 0; i < dimension; i++) {
      for (j = 0; j < dimension; j++) {
        if (matrix[i][j] == '1') {
        } else if (matrix[i][k] == '1' && matrix[k][j] == '1')
          matrix[i][j] = '1';
      }
    }
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<warshall>:
  endbr64
  mov    %rdi,%r9
  test   %esi,%esi
  jle    L99
  mov    %esi,%edi
  lea    -0x1(%rsi),%eax
  lea    0x8(%r9,%rax,8),%r10
  mov    $0x0,%r8d
  jmp    L34
L11:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L18
L85:
  mov    (%rsi),%rdx
  lea    (%rdx,%rax,1),%rcx
  cmpb   $0x31,(%rcx)
  je     L11
  cmpb   $0x31,(%rdx,%r8,1)
  jne    L11
  mov    (%r9,%r8,8),%rdx
  cmpb   $0x31,(%rdx,%rax,1)
  jne    L11
  movb   $0x31,(%rcx)
  jmp    L11
L18:
  add    $0x8,%rsi
  cmp    %r10,%rsi
  je     L93
L29:
  mov    $0x0,%eax
  jmp    L85
L93:
  add    $0x1,%r8
  cmp    %rdi,%r8
  je     L99
L34:
  mov    %r9,%rsi
  jmp    L29
L99:
  ret
```

assistant: ```c
void warshall(char **matrix, int dimension) {
  int k, i, j;
  for (k = 0; k < dimension; k++) {
    for (i = 0; i < dimension; i++) {
      for (j = 0; j < dimension; j++) {
        if (matrix[i][j] == '1') {
        } else if (matrix[i][k] == '1' && matrix[k][j] == '1')
          matrix[i][j] = '1';
      }
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<warshall>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%eax
  test   %esi,%esi
  jle    L73
  sub    $0x1,%eax
  mov    %esi,%edi
  xor    %r8d,%r8d
  lea    0x8(%r9,%rax,8),%r10
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r9,%rsi
  nopl   0x0(%rax,%rax,1)
L78:
  xor    %eax,%eax
  jmp    L23
  nopl   0x0(%rax)
L26:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L86
L23:
  mov    (%rsi),%rdx
  lea    (%rdx,%rax,1),%rcx
  cmpb   $0x31,(%rcx)
  je     L26
  cmpb   $0x31,(%rdx,%r8,1)
  jne    L26
  mov    (%r9,%r8,8),%rdx
  cmpb   $0x31,(%rdx,%rax,1)
  jne    L26
  add    $0x1,%rax
  movb   $0x31,(%rcx)
  cmp    %rdi,%rax
  jne    L23
  nopw   0x0(%rax,%rax,1)
L86:
  add    $0x8,%rsi
  cmp    %r10,%rsi
  jne    L78
  add    $0x1,%r8
  cmp    %rdi,%r8
  jne    L51
L73:
  ret
```

assistant: ```c
void warshall(char **matrix, int dimension) {
  int k, i, j;
  for (k = 0; k < dimension; k++) {
    for (i = 0; i < dimension; i++) {
      for (j = 0; j < dimension; j++) {
        if (matrix[i][j] == '1') {
        } else if (matrix[i][k] == '1' && matrix[k][j] == '1')
          matrix[i][j] = '1';
      }
    }
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<warshall>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%eax
  test   %esi,%esi
  jle    L76
  sub    $0x1,%eax
  mov    %esi,%edi
  xor    %r8d,%r8d
  lea    0x8(%r9,%rax,8),%r10
  nopw   0x0(%rax,%rax,1)
L70:
  mov    %r9,%rsi
  nopl   0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  jmp    L43
  nopl   0x0(%rax)
L79:
  add    $0x1,%rax
  cmp    %rax,%rdi
  je     L7
L43:
  mov    (%rsi),%rdx
  lea    (%rdx,%rax,1),%rcx
  cmpb   $0x31,(%rcx)
  je     L79
  cmpb   $0x31,(%rdx,%r8,1)
  jne    L79
  mov    (%r9,%r8,8),%rdx
  cmpb   $0x31,(%rdx,%rax,1)
  jne    L79
  add    $0x1,%rax
  movb   $0x31,(%rcx)
  cmp    %rax,%rdi
  jne    L43
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsi
  cmp    %rsi,%r10
  jne    L69
  add    $0x1,%r8
  cmp    %r8,%rdi
  jne    L70
L76:
  ret
```

assistant: ```c
void warshall(char **matrix, int dimension) {
  int k, i, j;
  for (k = 0; k < dimension; k++) {
    for (i = 0; i < dimension; i++) {
      for (j = 0; j < dimension; j++) {
        if (matrix[i][j] == '1') {
        } else if (matrix[i][k] == '1' && matrix[k][j] == '1')
          matrix[i][j] = '1';
      }
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ubbf2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D11(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
L42:
  movl   $0x1,-0x48(%rbp)
  mov    -0x60(%rbp),%rax
  movsd  (%rax),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  jmp    L56
L73:
  mov    -0x58(%rbp),%rax
  mov    (%rax),%rax
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <d3@plt>
  movq   %xmm0,%rax
  mov    -0x48(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x30(%rbp,%rdx,8)
  addl   $0x1,-0x48(%rbp)
  movsd  -0x40(%rbp),%xmm0
  addsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x40(%rbp)
L56:
  mov    -0x60(%rbp),%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x38(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  addsd  %xmm1,%xmm0
  comisd -0x40(%rbp),%xmm0
  jae    L73
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x3,%eax
  call   <i_min@plt>
  mov    %eax,-0x44(%rbp)
  cmpl   $0x1,-0x44(%rbp)
  jne    L23
  mov    -0x60(%rbp),%rax
  movsd  (%rax),%xmm0
  subsd  -0x38(%rbp),%xmm0
  mov    -0x60(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L42
L23:
  cmpl   $0x2,-0x44(%rbp)
  je     L74
  cmpl   $0x3,-0x44(%rbp)
  jne    L44
  mov    -0x60(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  -0x38(%rbp),%xmm0
  mov    -0x60(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L42
L74:
  nop
  jmp    L1
L44:
  nop
L1:
  mov    -0x44(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D8
data_type: f64

tool: {"D11": [0x50,0x45,0x52,0x54,0xfb,0x21,0x19,0x40]}

tool: D8: 0.1

assistant: ```c
int ubbf2(a1, a2)
double *a1, *a2;
{
  double s[5], aa2;
  int ic, ik;
  double d3(), Pi2;
  int i_min();
  Pi2 = 3.141592654 * 2.;
l1:
  ik = 1;
  for (aa2 = *a2 - Pi2; aa2 <= *a2 + Pi2 + 0.1; aa2 += Pi2) {
    s[ik] = d3(*a1, aa2);
    ik++;
  }
  ic = i_min(s[1], s[2], s[3]);
  if (ic == 1) {
    *a2 -= Pi2;
    goto l1;
  }
  if (ic == 2) {
    goto l2;
  }
  if (ic == 3) {
    *a2 += Pi2;
    goto l1;
  }
l2:
  return ic;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ubbf2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  jmp    L24
L13:
  movsd  0x0(%rbp),%xmm0
  subsd  D37(%rip),%xmm0
L19:
  movsd  %xmm0,0x0(%rbp)
L24:
  movsd  0x0(%rbp),%xmm0
  movapd %xmm0,%xmm4
  subsd  D37(%rip),%xmm4
  movsd  %xmm4,0x8(%rsp)
  addsd  D37(%rip),%xmm0
  addsd  D46(%rip),%xmm0
  lea    0x10(%rsp),%rbx
  comisd %xmm4,%xmm0
  jb     L69
L57:
  movsd  0x8(%rsp),%xmm1
  movsd  (%r12),%xmm0
  mov    $0x2,%eax
  call   <d3@plt>
  movsd  %xmm0,0x8(%rbx)
  movsd  0x8(%rsp),%xmm3
  addsd  D37(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  add    $0x8,%rbx
  movsd  0x0(%rbp),%xmm0
  addsd  D37(%rip),%xmm0
  addsd  D46(%rip),%xmm0
  comisd %xmm3,%xmm0
  jae    L57
L69:
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  mov    $0x3,%eax
  call   <i_min@plt>
  cmp    $0x1,%eax
  je     L13
  cmp    $0x3,%eax
  jne    L51
  movsd  D37(%rip),%xmm0
  addsd  0x0(%rbp),%xmm0
  jmp    L19
L51:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D46
type_infered: f64

tool: {"D37": [0x50,0x45,0x52,0x54,0xfb,0x21,0x19,0x40]}

tool: D46: 0.1

assistant: ```c
int ubbf2(a1, a2)
double *a1, *a2;
{
  double s[5], aa2;
  int ic, ik;
  double d3(), Pi2;
  int i_min();
  Pi2 = 3.141592654 * 2.;
l1:
  ik = 1;
  for (aa2 = *a2 - Pi2; aa2 <= *a2 + Pi2 + 0.1; aa2 += Pi2) {
    s[ik] = d3(*a1, aa2);
    ik++;
  }
  ic = i_min(s[1], s[2], s[3]);
  if (ic == 1) {
    *a2 -= Pi2;
    goto l1;
  }
  if (ic == 2) {
    goto l2;
  }
  if (ic == 3) {
    *a2 += Pi2;
    goto l1;
  }
l2:
  return ic;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ubbf2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  0x0(%rbp),%xmm0
  lea    0x10(%rsp),%rbx
  movapd %xmm0,%xmm1
  addsd  D4(%rip),%xmm0
  subsd  D4(%rip),%xmm1
  addsd  D76(%rip),%xmm0
  comisd %xmm1,%xmm0
  jb     L49
L37:
  movsd  (%r12),%xmm0
  mov    $0x2,%eax
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <d3@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  D4(%rip),%xmm1
  movsd  %xmm0,(%rbx)
  movsd  D4(%rip),%xmm0
  addsd  0x0(%rbp),%xmm0
  addsd  D76(%rip),%xmm0
  comisd %xmm1,%xmm0
  jae    L37
L49:
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  mov    $0x3,%eax
  movsd  0x18(%rsp),%xmm0
  call   <i_min@plt>
  cmp    $0x1,%eax
  je     L47
  cmp    $0x2,%eax
  je     L60
  cmp    $0x3,%eax
  jne    L60
  movsd  D4(%rip),%xmm0
  addsd  0x0(%rbp),%xmm0
L69:
  movsd  %xmm0,0x0(%rbp)
  jmp    L2
  nopl   (%rax)
L47:
  movsd  0x0(%rbp),%xmm0
  subsd  D4(%rip),%xmm0
  jmp    L69
  nop
L60:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type: byte[8]
name: parse_data
arguments: tag: D76
type: f64

tool: {"D4": [0x50,0x45,0x52,0x54,0xfb,0x21,0x19,0x40]}

tool: D76: 0.1

assistant: ```c
int ubbf2(a1, a2)
double *a1, *a2;
{
  double s[5], aa2;
  int ic, ik;
  double d3(), Pi2;
  int i_min();
  Pi2 = 3.141592654 * 2.;
l1:
  ik = 1;
  for (aa2 = *a2 - Pi2; aa2 <= *a2 + Pi2 + 0.1; aa2 += Pi2) {
    s[ik] = d3(*a1, aa2);
    ik++;
  }
  ic = i_min(s[1], s[2], s[3]);
  if (ic == 1) {
    *a2 -= Pi2;
    goto l1;
  }
  if (ic == 2) {
    goto l2;
  }
  if (ic == 3) {
    *a2 += Pi2;
    goto l1;
  }
l2:
  return ic;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ubbf2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x40,%rsp
  movsd  (%rsi),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L25:
  movapd %xmm0,%xmm1
  addsd  D68(%rip),%xmm0
  lea    0x10(%rsp),%rbx
  subsd  D68(%rip),%xmm1
  addsd  D11(%rip),%xmm0
  comisd %xmm1,%xmm0
  jb     L33
L56:
  movsd  (%r12),%xmm0
  mov    $0x2,%eax
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <d3@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  D68(%rip),%xmm1
  movsd  %xmm0,(%rbx)
  movsd  D68(%rip),%xmm0
  addsd  0x0(%rbp),%xmm0
  addsd  D11(%rip),%xmm0
  comisd %xmm1,%xmm0
  jae    L56
L33:
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  mov    $0x3,%eax
  movsd  0x18(%rsp),%xmm0
  call   <i_min@plt>
  cmp    $0x1,%eax
  je     L20
  cmp    $0x2,%eax
  je     L72
  cmp    $0x3,%eax
  jne    L72
  movsd  D68(%rip),%xmm0
  addsd  0x0(%rbp),%xmm0
L29:
  movsd  %xmm0,0x0(%rbp)
  jmp    L25
L20:
  movsd  0x0(%rbp),%xmm0
  subsd  D68(%rip),%xmm0
  jmp    L29
  nop
L72:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D68
type_guessed: byte[8]
name: unpack_data
arguments: label: D11
type_guessed: f64

tool: {"D68": [0x50,0x45,0x52,0x54,0xfb,0x21,0x19,0x40]}

tool: D11: 0.1

assistant: ```c
int ubbf2(a1, a2)
double *a1, *a2;
{
  double s[5], aa2;
  int ic, ik;
  double d3(), Pi2;
  int i_min();
  Pi2 = 3.141592654 * 2.;
l1:
  ik = 1;
  for (aa2 = *a2 - Pi2; aa2 <= *a2 + Pi2 + 0.1; aa2 += Pi2) {
    s[ik] = d3(*a1, aa2);
    ik++;
  }
  ic = i_min(s[1], s[2], s[3]);
  if (ic == 1) {
    *a2 -= Pi2;
    goto l1;
  }
  if (ic == 2) {
    goto l2;
  }
  if (ic == 3) {
    *a2 += Pi2;
    goto l1;
  }
l2:
  return ic;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x90(%rbp)
  jmp    L38
L165:
  lea    -0x70(%rbp),%rax
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x8c(%rbp)
  movl   $0x0,-0x88(%rbp)
  movl   $0x0,-0x88(%rbp)
  jmp    L23
L113:
  call   <fork@plt>
  mov    %eax,-0x84(%rbp)
  cmpl   $0x0,-0x84(%rbp)
  jne    L19
  movl   $0x1,-0x8c(%rbp)
  jmp    L124
L19:
  cmpl   $0x0,-0x84(%rbp)
  jle    L32
  mov    -0x84(%rbp),%eax
  mov    %eax,%edx
  mov    -0x88(%rbp),%eax
  cltq
  mov    %dl,-0x80(%rbp,%rax,1)
  jmp    L169
L32:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L174
L169:
  addl   $0x1,-0x88(%rbp)
L23:
  cmpl   $0xf,-0x88(%rbp)
  jle    L113
L124:
  cmpl   $0x0,-0x8c(%rbp)
  je     L100
  mov    $0x20,%edi
  call   <call_rec@plt>
  mov    $0x0,%eax
  jmp    L174
L100:
  movl   $0x0,-0x88(%rbp)
  jmp    L30
L127:
  mov    -0x88(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <waitpid@plt>
  addl   $0x1,-0x88(%rbp)
L30:
  cmpl   $0xf,-0x88(%rbp)
  jle    L127
  movl   $0x0,-0x88(%rbp)
  jmp    L163
L43:
  mov    -0x88(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  je     L146
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L174
L146:
  addl   $0x1,-0x88(%rbp)
L163:
  cmpl   $0x63,-0x88(%rbp)
  jle    L43
  addl   $0x1,-0x90(%rbp)
L38:
  cmpl   $0x3f,-0x90(%rbp)
  jle    L165
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L174:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L129
  call   <__stack_chk_fail@plt>
L129:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
type: string
name: disassemble_data
arguments: data_tag: D5
type: string
name: disassemble_data
arguments: data_tag: D19
type: string

tool: D23: FORK FAILED


tool: D5: TEST FAILED!!


tool: D19: Context switch test passed.


assistant: ```c
int main(int argc, char **argv) {
  int x;
  for (x = 0; x < 64; x++) {
    char buff1[100];
    memset(buff1, 0, 100);
    char procs[16];
    int is_child = 0;
    int y = 0;
    for (y = 0; y < 16; y++) {
      int pid = fork();
      if (pid == 0) {
        is_child = 1;
        break;
      } else if (pid > 0) {
        procs[y] = pid;
      } else {
        printf("FORK FAILED\n");
        return -1;
      }
    }
    if (is_child) {
      call_rec(32);
      return 0;
    }
    for (y = 0; y < 16; y++)
      waitpid(procs[y], NULL, 0);
    for (y = 0; y < 100; y++)
      if (buff1[y] != 0) {
        printf("TEST FAILED!!\n");
        return -1;
      }
  }
  printf("Context switch test passed.\n");
  return 0;
}
```