ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<red_counter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D2(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D18(%rip)
  mov    D18(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int red_counter() {
  static int counter = 10;
  counter = counter + 1;
  return counter;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<red_counter>:
  endbr64
  mov    D8(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D0(%rip)
  ret
```

assistant: ```c
int red_counter() {
  static int counter = 10;
  counter = counter + 1;
  return counter;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<red_counter>:
  endbr64
  mov    D5(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D18(%rip)
  ret
```

assistant: ```c
int red_counter() {
  static int counter = 10;
  counter = counter + 1;
  return counter;
}
```
user: Translate the below assembly code into C programming language:

```asm
<red_counter>:
  endbr64
  mov    D17(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D16(%rip)
  ret
```

assistant: ```c
int red_counter() {
  static int counter = 10;
  counter = counter + 1;
  return counter;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<math_atan2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <atan2@plt>
  movsd  D19(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D11(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <lua_pushnumber@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
data_type: f64
name: parse_data
arguments: data_label: D11
data_type: f64

tool: D19: 180

tool: D11: 3.141592653589793

assistant: ```c
void math_atan2(void) {
  double d1 = luaL_check_number(1);
  double d2 = luaL_check_number(2);
  lua_pushnumber(((atan2(d1, d2)) * 180.0 / 3.14159265358979323846));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<math_atan2>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <luaL_check_number@plt>
  mov    %eax,%ebx
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  call   <atan2@plt>
  mulsd  D12(%rip),%xmm0
  divsd  D5(%rip),%xmm0
  mov    $0x1,%eax
  call   <lua_pushnumber@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type: f64
name: retrieve_data
arguments: tag: D5
type: f64

tool: D12: 180

tool: D5: 3.141592653589793

assistant: ```c
void math_atan2(void) {
  double d1 = luaL_check_number(1);
  double d2 = luaL_check_number(2);
  lua_pushnumber(((atan2(d1, d2)) * 180.0 / 3.14159265358979323846));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<math_atan2>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <luaL_check_number@plt>
  mov    $0x2,%edi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm0
  cvtsi2sd %eax,%xmm1
  call   <atan2@plt>
  mov    $0x1,%eax
  pop    %rbx
  mulsd  D8(%rip),%xmm0
  divsd  D13(%rip),%xmm0
  jmp    1080 <lua_pushnumber@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: f64
name: read_data
arguments: data_tag: D13
datatype: f64

tool: D8: 180

tool: D13: 3.141592653589793

assistant: ```c
void math_atan2(void) {
  double d1 = luaL_check_number(1);
  double d2 = luaL_check_number(2);
  lua_pushnumber(((atan2(d1, d2)) * 180.0 / 3.14159265358979323846));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<math_atan2>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <luaL_check_number@plt>
  mov    $0x2,%edi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm0
  cvtsi2sd %eax,%xmm1
  call   <atan2@plt>
  mov    $0x1,%eax
  pop    %rbx
  mulsd  D0(%rip),%xmm0
  divsd  D9(%rip),%xmm0
  jmp    1080 <lua_pushnumber@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: f64
name: disassemble_data
arguments: tag: D9
type: f64

tool: D0: 180

tool: D9: 3.141592653589793

assistant: ```c
void math_atan2(void) {
  double d1 = luaL_check_number(1);
  double d2 = luaL_check_number(2);
  lua_pushnumber(((atan2(d1, d2)) * 180.0 / 3.14159265358979323846));
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <argument_delim_split@plt>
  test   %rax,%rax
  jns    L12
  mov    $0x0,%eax
  jmp    L26
L12:
  mov    -0x10(%rbp),%rax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
char **get_command(const char *cCommand) {
  char **command = NULL;
  if (argument_delim_split(cCommand, &command) < 0)
    return NULL;
  return command;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_command>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  call   <argument_delim_split@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovns (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **get_command(const char *cCommand) {
  char **command = NULL;
  if (argument_delim_split(cCommand, &command) < 0)
    return NULL;
  return command;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_command>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <argument_delim_split@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovns (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **get_command(const char *cCommand) {
  char **command = NULL;
  if (argument_delim_split(cCommand, &command) < 0)
    return NULL;
  return command;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_command>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <argument_delim_split@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovns (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **get_command(const char *cCommand) {
  char **command = NULL;
  if (argument_delim_split(cCommand, &command) < 0)
    return NULL;
  return command;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<path_016_expected_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  cmpl   $0x1,-0x4(%rbp)
  je     L34
  jmp    L28
L13:
  cmpl   $0x0,-0x4(%rbp)
  jmp    L28
L34:
  cmpl   $0xa,-0x4(%rbp)
  nop
L28:
  pop    %rbp
  ret
```

assistant: ```c
void path_016_expected_8(int a, int b) {
  switch (a) {
  case 0:
    if (a > 0) {
      return;
    }
    break;
  case 1:
    if (a > 10) {
      return;
    }
    break;
  default:
    break;
  }
  if (b) {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<path_016_expected_8>:
  endbr64
  ret
```

assistant: ```c
void path_016_expected_8(int a, int b) {
  switch (a) {
  case 0:
    if (a > 0) {
      return;
    }
    break;
  case 1:
    if (a > 10) {
      return;
    }
    break;
  default:
    break;
  }
  if (b) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<path_016_expected_8>:
  endbr64
  ret
```

assistant: ```c
void path_016_expected_8(int a, int b) {
  switch (a) {
  case 0:
    if (a > 0) {
      return;
    }
    break;
  case 1:
    if (a > 10) {
      return;
    }
    break;
  default:
    break;
  }
  if (b) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<path_016_expected_8>:
  endbr64
  ret
```

assistant: ```c
void path_016_expected_8(int a, int b) {
  switch (a) {
  case 0:
    if (a > 0) {
      return;
    }
    break;
  case 1:
    if (a > 10) {
      return;
    }
    break;
  default:
    break;
  }
  if (b) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getBeginTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,-0x8(%rbp)
  nop
L2:
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L2
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
clock_t getBeginTime() {
  clock_t beginTime;
  clock_t lastTime = clock();
  while ((beginTime = clock()) == lastTime)
    ;
  return beginTime;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getBeginTime>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,%ebx
L5:
  mov    $0x0,%eax
  call   <clock@plt>
  cmp    %eax,%ebx
  je     L5
  pop    %rbx
  ret
```

assistant: ```c
clock_t getBeginTime() {
  clock_t beginTime;
  clock_t lastTime = clock();
  while ((beginTime = clock()) == lastTime)
    ;
  return beginTime;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getBeginTime>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <clock@plt>
  mov    %eax,%ebx
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  call   <clock@plt>
  cmp    %eax,%ebx
  je     L6
  pop    %rbx
  ret
```

assistant: ```c
clock_t getBeginTime() {
  clock_t beginTime;
  clock_t lastTime = clock();
  while ((beginTime = clock()) == lastTime)
    ;
  return beginTime;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getBeginTime>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <clock@plt>
  mov    %eax,%ebx
  xchg   %ax,%ax
L8:
  xor    %eax,%eax
  call   <clock@plt>
  cmp    %eax,%ebx
  je     L8
  pop    %rbx
  ret
```

assistant: ```c
clock_t getBeginTime() {
  clock_t beginTime;
  clock_t lastTime = clock();
  while ((beginTime = clock()) == lastTime)
    ;
  return beginTime;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getfname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rax,%rbx
  jmp    L10
L21:
  add    $0x1,%rax
L10:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L21
  cmp    %rbx,%rax
  jne    L65
  mov    $0x0,%eax
  jmp    L29
L39:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  jne    L9
  add    $0x1,%rax
  jmp    L29
L9:
  sub    $0x1,%rax
L65:
  cmp    %rbx,%rax
  jne    L39
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *getfname(p)
register char *p;
{
  register char *s;
  s = p;
  while (*p != '\0')
    p++;
  if (p == s)
    return (0);
  for (; p != s; p--)
    if (*p == '/') {
      p++;
      break;
    }
  return (p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getfname>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L29
  mov    %rdi,%rax
L14:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L14
  cmp    %rax,%rdi
  je     L39
L32:
  cmpb   $0x2f,(%rax)
  je     L31
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jne    L32
  ret
L31:
  add    $0x1,%rax
  ret
L29:
  mov    $0x0,%eax
  ret
L39:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *getfname(p)
register char *p;
{
  register char *s;
  s = p;
  while (*p != '\0')
    p++;
  if (p == s)
    return (0);
  for (; p != s; p--)
    if (*p == '/') {
      p++;
      break;
    }
  return (p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getfname>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L40
  mov    %rdi,%rax
  nopl   0x0(%rax)
L14:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L14
  cmp    %rax,%rdi
  jne    L5
  jmp    L40
L29:
  cmpb   $0x2f,(%rax)
  je     L37
L5:
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jne    L29
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %rdx,%rax
  ret
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *getfname(p)
register char *p;
{
  register char *s;
  s = p;
  while (*p != '\0')
    p++;
  if (p == s)
    return (0);
  for (; p != s; p--)
    if (*p == '/') {
      p++;
      break;
    }
  return (p);
}
```
user: What is the c source code of the assembly code below?

```asm
<getfname>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  mov    %rdi,%rax
  nopl   0x0(%rax)
L34:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L34
  cmp    %rax,%rdi
  je     L11
  xchg   %ax,%ax
L5:
  cmpb   $0x2f,(%rax)
  je     L22
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jne    L5
  ret
  nop
L22:
  add    $0x1,%rax
  ret
  nopl   (%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *getfname(p)
register char *p;
{
  register char *s;
  s = p;
  while (*p != '\0')
    p++;
  if (p == s)
    return (0);
  for (; p != s; p--)
    if (*p == '/') {
      p++;
      break;
    }
  return (p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<loglikelihood>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  not    %rax
  shr    $0x3f,%rax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  movsd  D0(%rip),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L2
L7:
  pxor   %xmm0,%xmm0
  jmp    L14
L2:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x18(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  lea    -0x1(%rax),%ebx
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  cltq
  imul   -0x18(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L14:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x00]}

assistant: ```c
double loglikelihood(long edge_count, double edgelen_sum) {
  assert(edge_count >= 0);
  if (edge_count == 0 || edgelen_sum < ((double)2.22507385850720138309023271733240406e-308L))
    return 0;
  return edge_count * (log(edge_count) - 1 - log(edgelen_sum));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<loglikelihood>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movq   %xmm0,%rbp
  not    %rdi
  shr    $0x3f,%rdi
  call   <assert@plt>
  pxor   %xmm0,%xmm0
  test   %rbx,%rbx
  je     L24
  pxor   %xmm0,%xmm0
  movsd  D0(%rip),%xmm1
  movq   %rbp,%xmm2
  comisd %xmm2,%xmm1
  jbe    L11
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  call   <log@plt>
  mov    %eax,%r12d
  movq   %rbp,%xmm0
  call   <log@plt>
  sub    $0x1,%r12d
  sub    %eax,%r12d
  movslq %r12d,%r12
  imul   %rbx,%r12
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12,%xmm0
  jmp    L24
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x00]}

assistant: ```c
double loglikelihood(long edge_count, double edgelen_sum) {
  assert(edge_count >= 0);
  if (edge_count == 0 || edgelen_sum < ((double)2.22507385850720138309023271733240406e-308L))
    return 0;
  return edge_count * (log(edge_count) - 1 - log(edgelen_sum));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<loglikelihood>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  not    %rdi
  shr    $0x3f,%rdi
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  pxor   %xmm0,%xmm0
  test   %rbx,%rbx
  je     L10
  movsd  D6(%rip),%xmm1
  comisd 0x8(%rsp),%xmm1
  jbe    L15
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L15:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  call   <log@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ebp
  call   <log@plt>
  sub    $0x1,%ebp
  add    $0x18,%rsp
  pxor   %xmm0,%xmm0
  sub    %eax,%ebp
  movslq %ebp,%rbp
  imul   %rbx,%rbp
  pop    %rbx
  cvtsi2sd %rbp,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x00]}

assistant: ```c
double loglikelihood(long edge_count, double edgelen_sum) {
  assert(edge_count >= 0);
  if (edge_count == 0 || edgelen_sum < ((double)2.22507385850720138309023271733240406e-308L))
    return 0;
  return edge_count * (log(edge_count) - 1 - log(edgelen_sum));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<loglikelihood>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  not    %rdi
  shr    $0x3f,%rdi
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  pxor   %xmm0,%xmm0
  test   %rbx,%rbx
  je     L16
  movsd  D7(%rip),%xmm1
  comisd 0x8(%rsp),%xmm1
  jbe    L6
L16:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L6:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  call   <log@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ebp
  call   <log@plt>
  sub    $0x1,%ebp
  add    $0x18,%rsp
  pxor   %xmm0,%xmm0
  sub    %eax,%ebp
  movslq %ebp,%rbp
  imul   %rbx,%rbp
  pop    %rbx
  cvtsi2sd %rbp,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D7
data_type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x00]}

assistant: ```c
double loglikelihood(long edge_count, double edgelen_sum) {
  assert(edge_count >= 0);
  if (edge_count == 0 || edgelen_sum < ((double)2.22507385850720138309023271733240406e-308L))
    return 0;
  return edge_count * (log(edge_count) - 1 - log(edgelen_sum));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) void func1(int x) {
  x++;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func1>:
  endbr64
  ret
```

assistant: ```c
__attribute__((always_)) void func1(int x) {
  x++;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func1>:
  endbr64
  ret
```

assistant: ```c
__attribute__((always_)) void func1(int x) {
  x++;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func1>:
  endbr64
  ret
```

assistant: ```c
__attribute__((always_)) void func1(int x) {
  x++;
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<id2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  lea    D39(%rip),%rax
  jmp    L2
L13:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D33(%rip),%rax
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string

tool: D39: x

tool: D21: %d

assistant: ```c
char *id2str(int i) {
  static char buff[5];
  if (i < 0)
    return ("x");
  else {
    sprintf(buff, "%d", i);
    return buff;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<id2str>:
  endbr64
  lea    D14(%rip),%rax
  test   %edi,%edi
  jns    L0
  ret
L0:
  push   %rbx
  mov    %edi,%edx
  lea    D18(%rip),%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string

tool: D14: x

tool: D18: %d

assistant: ```c
char *id2str(int i) {
  static char buff[5];
  if (i < 0)
    return ("x");
  else {
    sprintf(buff, "%d", i);
    return buff;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<id2str>:
  endbr64
  test   %edi,%edi
  jns    L1
  lea    D18(%rip),%rax
  ret
L1:
  push   %rbx
  lea    D7(%rip),%rbx
  mov    %edi,%edx
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D16
datatype: string

tool: D18: x

tool: D16: %d

assistant: ```c
char *id2str(int i) {
  static char buff[5];
  if (i < 0)
    return ("x");
  else {
    sprintf(buff, "%d", i);
    return buff;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<id2str>:
  endbr64
  test   %edi,%edi
  jns    L4
  lea    D7(%rip),%rax
  ret
L4:
  push   %rbx
  lea    D24(%rip),%rbx
  mov    %edi,%edx
  lea    D20(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D20
data_type: string

tool: D7: x

tool: D20: %d

assistant: ```c
char *id2str(int i) {
  static char buff[5];
  if (i < 0)
    return ("x");
  else {
    sprintf(buff, "%d", i);
    return buff;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<clear_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void clear_memory(int array[1024]) {
  int elem = 0;
  for (; elem < 1024; ++elem) {
    array[elem] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clear_memory>:
  endbr64
  lea    0x1000(%rdi),%rax
L0:
  movl   $0x0,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L0
  ret
```

assistant: ```c
void clear_memory(int array[1024]) {
  int elem = 0;
  for (; elem < 1024; ++elem) {
    array[elem] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clear_memory>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  lea    0x8(%rdi),%rdi
  movq   $0x0,0xff0(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rax
  lea    0x1000(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  ret
```

assistant: ```c
void clear_memory(int array[1024]) {
  int elem = 0;
  for (; elem < 1024; ++elem) {
    array[elem] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clear_memory>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  lea    0x8(%rdi),%rdi
  movq   $0x0,0xff0(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rax
  lea    0x1000(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  ret
```

assistant: ```c
void clear_memory(int array[1024]) {
  int elem = 0;
  for (; elem < 1024; ++elem) {
    array[elem] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ex_inquire_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x10(%rbp),%rdi
  lea    -0x1c(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <ex_inquire@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L8
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int ex_inquire_int(int exoid, int req_info) {
  char *cdummy = 0;
  float fdummy = 0;
  int ret_val = 0;
  int error = ex_inquire(exoid, req_info, &ret_val, &fdummy, cdummy);
  if (error < 0)
    ret_val = error;
  return ret_val;
}
```