ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D12(%rip),%rdi
  lea    D21(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L49
  mov    %r13,%rbx
  mov    %r13,%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jg     L16
  test   %eax,%eax
  jle    L49
  lea    0x0(%r13,%rax,4),%rax
  xor    %esi,%esi
  nopl   (%rax)
L46:
  add    (%rbx),%esi
  add    $0x4,%rbx
  cmp    %rax,%rbx
  jne    L46
L35:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  xor    %esi,%esi
  jmp    L35
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D26
type: string

tool: D12: 
Enter number of elements : 

tool: D21: %d

tool: D26: 
The sum of elements is : %d


assistant: ```c
int main() {
  int *iPtr, iNum, i, iSum = 0;
  printf("\nEnter number of elements : ");
  scanf("%d", &iNum);
  iPtr = (int *)malloc(iNum * sizeof(int));
  for (i = 0; i < iNum; i++)
    scanf("%d", iPtr + i);
  for (i = 0; i < iNum; i++)
    iSum += *(iPtr + i);
  printf("\nThe sum of elements is : %d\n", iSum);
  free(iPtr);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%rdi
  lea    D9(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L88
  mov    %r13,%r12
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L35
  test   %eax,%eax
  jle    L88
  lea    -0x1(%rax),%edx
  cmp    $0x2,%edx
  jbe    L96
  mov    %eax,%edx
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %r13,%rdx
  xchg   %ax,%ax
L89:
  movdqu (%r12),%xmm2
  add    $0x10,%r12
  paddd  %xmm2,%xmm0
  cmp    %rdx,%r12
  jne    L89
  movdqa %xmm0,%xmm1
  mov    %eax,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  test   $0x3,%al
  je     L109
L81:
  movslq %edx,%rcx
  lea    0x0(,%rcx,4),%rdi
  add    0x0(%r13,%rcx,4),%esi
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%eax
  jle    L109
  add    $0x2,%edx
  add    0x4(%r13,%rdi,1),%esi
  cmp    %edx,%eax
  jle    L109
  add    0x8(%r13,%rdi,1),%esi
L109:
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L88:
  xor    %esi,%esi
  jmp    L109
L96:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L81
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
data_type: string
name: disassemble_data
arguments: data_tag: D9
data_type: string
name: disassemble_data
arguments: data_tag: D22
data_type: string

tool: D10: 
Enter number of elements : 

tool: D9: %d

tool: D22: 
The sum of elements is : %d


assistant: ```c
int main() {
  int *iPtr, iNum, i, iSum = 0;
  printf("\nEnter number of elements : ");
  scanf("%d", &iNum);
  iPtr = (int *)malloc(iNum * sizeof(int));
  for (i = 0; i < iNum; i++)
    scanf("%d", iPtr + i);
  for (i = 0; i < iNum; i++)
    iSum += *(iPtr + i);
  printf("\nThe sum of elements is : %d\n", iSum);
  free(iPtr);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L20
L11:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L28
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L28:
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x20(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L11
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  leave
  ret
```

assistant: ```c
int partition(int *A, int p, int r) {
  int key = A[r];
  int i = p - 1;
  for (int j = p; j <= r - 1; j++) {
    if (A[j] <= key) {
      i++;
      swap(A, i, j);
    }
  }
  swap(A, i + 1, r);
  return i + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<partition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%r14d
  movslq %edx,%rax
  mov    (%rdi,%rax,4),%r13d
  lea    -0x1(%rsi),%r12d
  cmp    %esi,%edx
  jle    L23
  movslq %esi,%rbx
  mov    %edx,%eax
  sub    %esi,%eax
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%r15
  jmp    L17
L44:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L23
L17:
  mov    %ebx,%edx
  cmp    %r13d,0x0(%rbp,%rbx,4)
  jg     L44
  add    $0x1,%r12d
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L44
L23:
  add    $0x1,%r12d
  mov    %r14d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int partition(int *A, int p, int r) {
  int key = A[r];
  int i = p - 1;
  for (int j = p; j <= r - 1; j++) {
    if (A[j] <= key) {
      i++;
      swap(A, i, j);
    }
  }
  swap(A, i + 1, r);
  return i + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<partition>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  push   %r13
  mov    %rax,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi,%rax,4),%r15d
  cmp    %esi,%eax
  jle    L25
  mov    %r13d,%edx
  movslq %esi,%rax
  lea    -0x1(%rsi),%r14d
  sub    %esi,%edx
  lea    0x1(%rax),%rbx
  lea    -0x1(%rdx),%r12d
  add    %rbx,%r12
  jmp    L8
  nopl   0x0(%rax)
L49:
  mov    %rbx,%rax
  cmp    %r12,%rbx
  je     L36
L27:
  add    $0x1,%rbx
L8:
  mov    %eax,%edx
  cmp    %r15d,0x0(%rbp,%rax,4)
  jg     L49
  add    $0x1,%r14d
  mov    %rbp,%rdi
  mov    %r14d,%esi
  call   <swap@plt>
  mov    %rbx,%rax
  cmp    %r12,%rbx
  jne    L27
L36:
  add    $0x1,%r14d
L18:
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    %esi,%r14d
  jmp    L18
```

assistant: ```c
int partition(int *A, int p, int r) {
  int key = A[r];
  int i = p - 1;
  for (int j = p; j <= r - 1; j++) {
    if (A[j] <= key) {
      i++;
      swap(A, i, j);
    }
  }
  swap(A, i + 1, r);
  return i + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<partition>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  push   %r13
  mov    %rax,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi,%rax,4),%r15d
  cmp    %esi,%eax
  jle    L51
  mov    %r13d,%edx
  movslq %esi,%rax
  lea    -0x1(%rsi),%r14d
  sub    %esi,%edx
  lea    0x1(%rax),%rbx
  lea    -0x1(%rdx),%r12d
  add    %rbx,%r12
  jmp    L16
  nopl   0x0(%rax)
L52:
  mov    %rbx,%rax
  cmp    %r12,%rbx
  je     L10
L37:
  add    $0x1,%rbx
L16:
  mov    %eax,%edx
  cmp    %r15d,0x0(%rbp,%rax,4)
  jg     L52
  add    $0x1,%r14d
  mov    %rbp,%rdi
  mov    %r14d,%esi
  call   <swap@plt>
  mov    %rbx,%rax
  cmp    %r12,%rbx
  jne    L37
L10:
  add    $0x1,%r14d
L0:
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  mov    %esi,%r14d
  jmp    L0
```

assistant: ```c
int partition(int *A, int p, int r) {
  int key = A[r];
  int i = p - 1;
  for (int j = p; j <= r - 1; j++) {
    if (A[j] <= key) {
      i++;
      swap(A, i, j);
    }
  }
  swap(A, i + 1, r);
  return i + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  xor    $0x1cdb,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L5
L55:
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  je     L48
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L14
L48:
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%ecx
  movzwl -0xa(%rbp),%edx
  movzwl -0xc(%rbp),%eax
  xor    %ecx,%edx
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
L14:
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L24
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  jmp    L69
L24:
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%edx
  movzwl -0xa(%rbp),%eax
  shr    $0x4,%ax
  movzwl %ax,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %ax,-0xa(%rbp)
L69:
  addw   $0x2,-0xc(%rbp)
L5:
  cmpw   $0x0,-0xc(%rbp)
  je     L55
  movzwl -0xa(%rbp),%eax
  xor    $0xd9bf,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        state[local1] ^= state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] <<= (state[local1] & (unsigned short)7) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ (unsigned short)55743;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  mov    %ecx,%edx
  xor    $0x1cdb,%dx
  mov    %edx,%eax
  cmp    $0x1cdb,%cx
  je     L22
  movsbl %dh,%edx
  mov    %al,%ah
  mov    %dl,%al
  test   %ax,%ax
  je     L22
  mov    %eax,%ecx
  shr    $0x4,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  jmp    L17
L22:
  mov    $0x0,%eax
L17:
  xor    $0xd9bf,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        state[local1] ^= state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] <<= (state[local1] & (unsigned short)7) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ (unsigned short)55743;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  mov    %edx,%eax
  xor    $0x1cdb,%ax
  cmp    $0x1cdb,%dx
  jne    L3
L19:
  mov    $0xffffd9bf,%eax
  mov    %ax,(%rsi)
  ret
  nopl   (%rax)
L3:
  rol    $0x8,%ax
  test   %ax,%ax
  je     L19
  mov    %eax,%ecx
  shr    $0x4,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  xor    $0xd9bf,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        state[local1] ^= state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] <<= (state[local1] & (unsigned short)7) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ (unsigned short)55743;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  mov    $0xffffd9bf,%edx
  mov    %ecx,%eax
  xor    $0x1cdb,%ax
  cmp    $0x1cdb,%cx
  jne    L0
L9:
  mov    %dx,(%rsi)
  ret
  nopl   (%rax)
L0:
  rol    $0x8,%ax
  test   %ax,%ax
  je     L9
  mov    %eax,%ecx
  shr    $0x4,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  xor    $0xd9bf,%ax
  mov    %eax,%edx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        state[local1] ^= state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] <<= (state[local1] & (unsigned short)7) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ (unsigned short)55743;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mpz_add_int64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set_int64@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_add@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  nop
  leave
  ret
```

assistant: ```c
void mpz_add_int64(mpz_t z, int64_t x) {
  mpz_t aux;
  mpz_init(aux);
  mpz_set_int64(aux, x);
  mpz_add(z, z, aux);
  mpz_clear(aux);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mpz_add_int64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_init@plt>
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <mpz_set_int64@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_add@plt>
  mov    %ebx,%edi
  call   <mpz_clear@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mpz_add_int64(mpz_t z, int64_t x) {
  mpz_t aux;
  mpz_init(aux);
  mpz_set_int64(aux, x);
  mpz_add(z, z, aux);
  mpz_clear(aux);
}
```
user: What is the c source code of the assembly code below?

```asm
<mpz_add_int64>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_set_int64@plt>
  mov    %r12d,%edi
  mov    %ebp,%edx
  mov    %r12d,%esi
  call   <mpz_add@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <mpz_clear@plt>
```

assistant: ```c
void mpz_add_int64(mpz_t z, int64_t x) {
  mpz_t aux;
  mpz_init(aux);
  mpz_set_int64(aux, x);
  mpz_add(z, z, aux);
  mpz_clear(aux);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mpz_add_int64>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_set_int64@plt>
  mov    %r12d,%edi
  mov    %ebp,%edx
  mov    %r12d,%esi
  call   <mpz_add@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <mpz_clear@plt>
```

assistant: ```c
void mpz_add_int64(mpz_t z, int64_t x) {
  mpz_t aux;
  mpz_init(aux);
  mpz_set_int64(aux, x);
  mpz_add(z, z, aux);
  mpz_clear(aux);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_up_ids_for_scheduled_decoding>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %rcx,%rbp
  mov    %r8,%r12
  cmpl   $0xffffffff,(%rdx)
  je     L126
  lea    0x4(%rdx),%rax
L140:
  add    $0x4,%rax
  cmpl   $0xffffffff,-0x4(%rax)
  jne    L140
L126:
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <jerasure_erasures_to_erased@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L47
  test   %ebx,%ebx
  jle    L133
  mov    %ebx,%r10d
  mov    %ebx,%esi
  mov    %ebx,%ecx
  mov    $0x0,%edx
  jmp    L87
L63:
  movslq %ecx,%r11
  lea    0x0(,%r11,4),%r8
  lea    0x1(%rcx),%eax
  cltq
  cmpl   $0x0,(%rdi,%r11,4)
  je     L145
L59:
  mov    %eax,%ecx
  lea    0x0(,%rax,4),%r8
  add    $0x1,%rax
  cmpl   $0x0,-0x4(%rdi,%rax,4)
  jne    L59
L145:
  mov    %ecx,0x0(%rbp,%rdx,4)
  mov    %r9d,(%r12,%r8,1)
  add    $0x1,%ecx
  movslq %esi,%rax
  mov    %r9d,0x0(%rbp,%rax,4)
  mov    %esi,(%r12,%rdx,4)
  add    $0x1,%esi
L31:
  add    $0x1,%rdx
  cmp    %rdx,%r10
  je     L136
L87:
  mov    %edx,%r9d
  cmpl   $0x0,(%rdi,%rdx,4)
  jne    L63
  mov    %edx,0x0(%rbp,%rdx,4)
  mov    %edx,(%r12,%rdx,4)
  jmp    L31
L133:
  mov    %ebx,%esi
L136:
  add    %ebx,%r13d
  cmp    %r13d,%ebx
  jge    L153
  movslq %ebx,%rbx
  jmp    L26
L132:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jle    L153
L26:
  cmpl   $0x0,(%rdi,%rbx,4)
  je     L132
  movslq %esi,%rax
  mov    %ebx,0x0(%rbp,%rax,4)
  mov    %esi,(%r12,%rbx,4)
  add    $0x1,%esi
  jmp    L132
L153:
  call   <free@plt>
  mov    $0x0,%eax
L75:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  mov    $0xffffffff,%eax
  jmp    L75
```

assistant: ```c
int set_up_ids_for_scheduled_decoding(int k, int m, int *erasures, int *row_ids, int *ind_to_row) {
  int ddf, cdf;
  int *erased;
  int i, j, x;
  ddf = 0;
  cdf = 0;
  for (i = 0; erasures[i] != -1; i++) {
    if (erasures[i] < k)
      ddf++;
    else
      cdf++;
  }
  erased = jerasure_erasures_to_erased(k, m, erasures);
  if (erased == NULL)
    return -1;
  j = k;
  x = k;
  for (i = 0; i < k; i++) {
    if (erased[i] == 0) {
      row_ids[i] = i;
      ind_to_row[i] = i;
    } else {
      while (erased[j])
        j++;
      row_ids[i] = j;
      ind_to_row[j] = i;
      j++;
      row_ids[x] = i;
      ind_to_row[i] = x;
      x++;
    }
  }
  for (i = k; i < k + m; i++) {
    if (erased[i]) {
      row_ids[x] = i;
      ind_to_row[i] = x;
      x++;
    }
  }
  free(erased);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_up_ids_for_scheduled_decoding>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <jerasure_erasures_to_erased@plt>
  test   %rax,%rax
  je     L102
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L15
  movslq %r12d,%r10
  mov    %r12d,%esi
  mov    %r12d,%ecx
  xor    %edx,%edx
  jmp    L71
  nopl   0x0(%rax)
L103:
  mov    %edx,(%rbx,%rdx,4)
  mov    %r8d,0x0(%rbp,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r10
  je     L35
L71:
  mov    (%rdi,%rdx,4),%eax
  mov    %edx,%r8d
  test   %eax,%eax
  je     L103
  movslq %ecx,%r11
  lea    0x1(%rcx),%eax
  lea    0x0(,%r11,4),%r9
  mov    (%rdi,%r11,4),%r11d
  cltq
  test   %r11d,%r11d
  je     L119
  nopl   0x0(%rax)
L38:
  mov    %eax,%ecx
  lea    0x0(,%rax,4),%r9
  add    $0x1,%rax
  mov    -0x4(%rdi,%rax,4),%r11d
  test   %r11d,%r11d
  jne    L38
L119:
  movslq %esi,%rax
  mov    %ecx,(%rbx,%rdx,4)
  add    $0x1,%ecx
  mov    %r8d,0x0(%rbp,%r9,1)
  mov    %r8d,(%rbx,%rax,4)
  mov    %esi,%r8d
  add    $0x1,%esi
  mov    %r8d,0x0(%rbp,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r10
  jne    L71
L35:
  add    %r12d,%r13d
  movslq %r12d,%rax
  cmp    %r13d,%r12d
  jge    L92
  nopl   0x0(%rax)
L93:
  mov    (%rdi,%rax,4),%edx
  test   %edx,%edx
  je     L55
  movslq %esi,%rdx
  mov    %eax,(%rbx,%rdx,4)
  mov    %esi,0x0(%rbp,%rax,4)
  add    $0x1,%esi
L55:
  add    $0x1,%rax
  cmp    %eax,%r13d
  jg     L93
L92:
  call   <free@plt>
  xor    %eax,%eax
L106:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %r12d,%esi
  jmp    L35
L102:
  mov    $0xffffffff,%eax
  jmp    L106
```

assistant: ```c
int set_up_ids_for_scheduled_decoding(int k, int m, int *erasures, int *row_ids, int *ind_to_row) {
  int ddf, cdf;
  int *erased;
  int i, j, x;
  ddf = 0;
  cdf = 0;
  for (i = 0; erasures[i] != -1; i++) {
    if (erasures[i] < k)
      ddf++;
    else
      cdf++;
  }
  erased = jerasure_erasures_to_erased(k, m, erasures);
  if (erased == NULL)
    return -1;
  j = k;
  x = k;
  for (i = 0; i < k; i++) {
    if (erased[i] == 0) {
      row_ids[i] = i;
      ind_to_row[i] = i;
    } else {
      while (erased[j])
        j++;
      row_ids[i] = j;
      ind_to_row[j] = i;
      j++;
      row_ids[x] = i;
      ind_to_row[i] = x;
      x++;
    }
  }
  for (i = k; i < k + m; i++) {
    if (erased[i]) {
      row_ids[x] = i;
      ind_to_row[i] = x;
      x++;
    }
  }
  free(erased);
  return 0;
}
```