ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<split_vars>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%r11
  mov    %rdx,%r8
  mov    $0x0,%eax
  cmpb   $0x23,(%rdi)
  je     L31
  push   %rbp
  push   %rbx
  jmp    L170
L31:
  movb   $0x0,(%rsi)
  movb   $0x0,(%rdx)
  mov    $0x1,%eax
  ret
L63:
  add    $0x1,%rax
  cmp    $0xff,%rax
  je     L92
L170:
  mov    %eax,%esi
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x20,%dl
  je     L63
  cmp    $0x9,%dl
  je     L63
  cmp    $0xfe,%eax
  jg     L15
  mov    %eax,%ebp
  mov    $0xff,%ebx
  sub    %eax,%ebx
  mov    $0x0,%eax
  movslq %esi,%rsi
  lea    (%rcx,%rsi,1),%rdi
L163:
  mov    %eax,%r10d
  mov    %eax,%r9d
  lea    0x0(%rbp,%rax,1),%edx
  movzbl (%rdi,%rax,1),%esi
  test   $0xdf,%sil
  je     L95
  cmp    $0xa,%sil
  je     L95
  mov    %sil,(%r11,%rax,1)
  lea    0x1(%r10),%r9d
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L163
L108:
  movslq %r9d,%rax
  movb   $0x0,(%r11,%rax,1)
L139:
  mov    $0x0,%esi
  jmp    L9
L95:
  movslq %r9d,%rax
  movb   $0x0,(%r11,%rax,1)
  cmp    $0xfe,%edx
  jg     L139
  movslq %edx,%rax
  jmp    L199
L151:
  add    $0x1,%rax
  cmp    $0xfe,%eax
  jg     L139
L199:
  mov    %eax,%esi
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x20,%dl
  je     L151
  cmp    $0x9,%dl
  je     L151
  cmp    $0xfe,%eax
  jg     L201
  mov    $0xff,%r10d
  sub    %eax,%r10d
  mov    $0x0,%eax
  movslq %esi,%rsi
  add    %rsi,%rcx
L69:
  mov    %eax,%edi
  mov    %eax,%esi
  movzbl (%rcx,%rax,1),%edx
  test   $0xdf,%dl
  je     L9
  cmp    $0xa,%dl
  je     L9
  mov    %dl,(%r8,%rax,1)
  lea    0x1(%rdi),%esi
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L69
L9:
  movslq %esi,%rax
  movb   $0x0,(%r8,%rax,1)
  test   %r9d,%r9d
  setne  %al
  test   %esi,%esi
  setne  %dl
  and    %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
L201:
  mov    $0x0,%esi
  jmp    L9
L92:
  mov    $0x0,%r9d
  jmp    L108
L15:
  mov    $0x0,%r9d
  jmp    L108
```

assistant: ```c
int split_vars(char line[256], char var_str[256], char val_str[256]) {
  int iln = 0;
  int ivar = 0;
  int ival = 0;
  if (*line == '#') {
    *var_str = '\0';
    *val_str = '\0';
    return 1;
  }
  for (; iln < 255 && (line[iln] == ' ' || line[iln] == '\t'); iln++)
    ;
  for (; iln < 255 && line[iln] != ' ' && line[iln] != '\0' && line[iln] != '\n'; iln++, ivar++)
    var_str[ivar] = line[iln];
  var_str[ivar] = '\0';
  for (; iln < 255 && (line[iln] == ' ' || line[iln] == '\t'); iln++)
    ;
  for (; iln < 255 && line[iln] != ' ' && line[iln] != '\0' && line[iln] != '\n'; iln++, ival++)
    val_str[ival] = line[iln];
  val_str[ival] = '\0';
  if (ivar != 0 && ival != 0)
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<split_vars>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdx,%r10
  mov    %rdi,%rcx
  xor    %edx,%edx
  cmp    $0x23,%al
  jne    L71
  jmp    L123
  nopl   0x0(%rax,%rax,1)
L185:
  add    $0x1,%rdx
  cmp    $0xff,%rdx
  je     L113
  movzbl (%rcx,%rdx,1),%eax
L71:
  cmp    $0x20,%al
  je     L185
  cmp    $0x9,%al
  je     L185
  mov    $0xff,%r11d
  movslq %edx,%rdi
  mov    %rsi,%r9
  xor    %r8d,%r8d
  sub    %edx,%r11d
  jmp    L142
  nopl   0x0(%rax)
L118:
  cmp    $0xa,%al
  je     L52
  add    $0x1,%r8d
  mov    %al,(%r9)
  add    $0x1,%rdi
  add    $0x1,%r9
  cmp    %r11d,%r8d
  je     L149
  movzbl (%rcx,%rdi,1),%eax
L142:
  movslq %edi,%rdx
  test   $0xdf,%al
  jne    L118
L52:
  test   %r8d,%r8d
  movb   $0x0,(%r9)
  setne  %r9b
  cmp    $0xff,%edx
  jne    L153
  jmp    L176
  nopw   0x0(%rax,%rax,1)
L64:
  add    $0x1,%rdx
  cmp    $0xff,%edx
  je     L176
L153:
  movzbl (%rcx,%rdx,1),%eax
  mov    %edx,%esi
  cmp    $0x20,%al
  je     L64
  cmp    $0x9,%al
  je     L64
  cmp    $0xff,%edx
  je     L176
  movslq %esi,%rdi
  mov    %r10,%rdx
  lea    0x1(%rcx,%rdi,1),%rcx
  mov    $0xfe,%edi
  sub    %esi,%edi
  xor    %esi,%esi
  add    %r10,%rdi
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L67:
  cmp    $0xa,%al
  je     L72
  mov    %al,(%rdx)
  add    $0x1,%esi
  cmp    %rdx,%rdi
  je     L122
  movzbl (%rcx),%eax
  add    $0x1,%rdx
  add    $0x1,%rcx
L10:
  test   $0xdf,%al
  jne    L67
L72:
  test   %esi,%esi
  mov    %rdx,%r10
  setne  %al
  movb   $0x0,(%r10)
  and    %r9d,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
L149:
  movslq %r8d,%r8
  add    %r8,%rsi
L113:
  movb   $0x0,(%rsi)
L176:
  movb   $0x0,(%r10)
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L123:
  movb   $0x0,(%rsi)
  mov    $0x1,%eax
  movb   $0x0,(%r10)
  ret
  nopl   (%rax)
L122:
  movslq %esi,%rsi
  xor    %eax,%eax
  add    %rsi,%r10
  test   %r8d,%r8d
  movb   $0x0,(%r10)
  sete   %al
  ret
```

assistant: ```c
int split_vars(char line[256], char var_str[256], char val_str[256]) {
  int iln = 0;
  int ivar = 0;
  int ival = 0;
  if (*line == '#') {
    *var_str = '\0';
    *val_str = '\0';
    return 1;
  }
  for (; iln < 255 && (line[iln] == ' ' || line[iln] == '\t'); iln++)
    ;
  for (; iln < 255 && line[iln] != ' ' && line[iln] != '\0' && line[iln] != '\n'; iln++, ivar++)
    var_str[ivar] = line[iln];
  var_str[ivar] = '\0';
  for (; iln < 255 && (line[iln] == ' ' || line[iln] == '\t'); iln++)
    ;
  for (; iln < 255 && line[iln] != ' ' && line[iln] != '\0' && line[iln] != '\n'; iln++, ival++)
    val_str[ival] = line[iln];
  val_str[ival] = '\0';
  if (ivar != 0 && ival != 0)
    return 0;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<split_vars>:
  endbr64
  mov    %rdx,%r9
  movzbl (%rdi),%edx
  mov    %rsi,%r11
  mov    %rdi,%rcx
  xor    %eax,%eax
  cmp    $0x23,%dl
  jne    L101
  jmp    L150
  nopl   0x0(%rax)
L52:
  add    $0x1,%rax
  cmp    $0xff,%rax
  je     L2
  movzbl (%rcx,%rax,1),%edx
L101:
  cmp    $0x20,%dl
  je     L52
  cmp    $0x9,%dl
  je     L52
  mov    $0xff,%r10d
  movslq %eax,%rdx
  mov    %r11,%r8
  xor    %edi,%edi
  sub    %eax,%r10d
  jmp    L8
  nopl   0x0(%rax)
L117:
  cmp    $0xa,%sil
  je     L112
  add    $0x1,%edi
  mov    %sil,(%r8)
  add    $0x1,%rdx
  add    $0x1,%r8
  cmp    %r10d,%edi
  je     L68
L8:
  movzbl (%rcx,%rdx,1),%esi
  movslq %edx,%rax
  test   $0xdf,%sil
  jne    L117
L112:
  test   %edi,%edi
  movb   $0x0,(%r8)
  setne  %r8b
  cmp    $0xff,%eax
  jne    L103
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x1,%rax
  cmp    $0xff,%eax
  je     L26
L103:
  movzbl (%rcx,%rax,1),%edx
  movslq %eax,%rsi
  cmp    $0x20,%dl
  je     L38
  cmp    $0x9,%dl
  je     L38
  cmp    $0xff,%esi
  je     L26
  mov    $0xfe,%r10d
  push   %rbx
  xor    %eax,%eax
  add    %rsi,%rcx
  sub    %esi,%r10d
  jmp    L28
  nopl   (%rax)
L145:
  cmp    $0xa,%dl
  je     L17
  mov    %dl,(%r9,%rax,1)
  add    $0x1,%esi
  lea    0x1(%rax),%rdx
  cmp    %rax,%r10
  je     L23
  mov    %rdx,%rax
L28:
  movzbl (%rcx,%rax,1),%edx
  mov    %eax,%esi
  mov    %eax,%ebx
  lea    (%r9,%rax,1),%r11
  test   $0xdf,%dl
  jne    L145
L17:
  test   %ebx,%ebx
  mov    %r11,%r9
  setne  %al
  movb   $0x0,(%r9)
  pop    %rbx
  and    %r8d,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
L68:
  movslq %edi,%rdi
  add    %rdi,%r11
L2:
  movb   $0x0,(%r11)
L26:
  movb   $0x0,(%r9)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L150:
  movb   $0x0,(%rsi)
  mov    $0x1,%eax
  movb   $0x0,(%r9)
  ret
  nopl   (%rax)
L23:
  movslq %esi,%rsi
  xor    %eax,%eax
  add    %rsi,%r9
  test   %edi,%edi
  movb   $0x0,(%r9)
  sete   %al
  pop    %rbx
  ret
```

assistant: ```c
int split_vars(char line[256], char var_str[256], char val_str[256]) {
  int iln = 0;
  int ivar = 0;
  int ival = 0;
  if (*line == '#') {
    *var_str = '\0';
    *val_str = '\0';
    return 1;
  }
  for (; iln < 255 && (line[iln] == ' ' || line[iln] == '\t'); iln++)
    ;
  for (; iln < 255 && line[iln] != ' ' && line[iln] != '\0' && line[iln] != '\n'; iln++, ivar++)
    var_str[ivar] = line[iln];
  var_str[ivar] = '\0';
  for (; iln < 255 && (line[iln] == ' ' || line[iln] == '\t'); iln++)
    ;
  for (; iln < 255 && line[iln] != ' ' && line[iln] != '\0' && line[iln] != '\n'; iln++, ival++)
    val_str[ival] = line[iln];
  val_str[ival] = '\0';
  if (ivar != 0 && ival != 0)
    return 0;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L65
L72:
  addq   $0x1,-0x8(%rbp)
L65:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L72
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L169
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L169
L1:
  addq   $0x1,-0x8(%rbp)
  movl   $0x10,-0x1c(%rbp)
  jmp    L169
L40:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x2f,-0xd(%rbp)
  jle    L142
  cmpb   $0x39,-0xd(%rbp)
  jg     L142
  movzbl -0xd(%rbp),%eax
  sub    $0x30,%eax
  mov    %al,-0xd(%rbp)
  jmp    L62
L142:
  andb   $0xdf,-0xd(%rbp)
  cmpb   $0x40,-0xd(%rbp)
  jle    L63
  cmpb   $0x46,-0xd(%rbp)
  jg     L63
  movzbl -0xd(%rbp),%eax
  sub    $0x37,%eax
  mov    %al,-0xd(%rbp)
  jmp    L62
L63:
  subq   $0x1,-0x8(%rbp)
  jmp    L96
L62:
  movsbl -0xd(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jg     L86
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L96
L86:
  mov    -0xc(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  movsbl -0xd(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L169:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
L96:
  jmp    L32
L135:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L135
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: Syntax error: %s


assistant: ```c
int get_val(const char **pp, int base) {
  int val = 0;
  const char *p = *pp;
  while (*p == ' ')
    p++;
  if (*p == '0') {
    p++;
    if ((*p == 'x') || (*p == 'X')) {
      p++;
      base = 16;
    }
  }
  while (*p) {
    char c = *p++;
    if ((c >= '0') && (c <= '9')) {
      c -= '0';
    } else {
      c &= ~('a' - 'A');
      if ((c >= 'A') && (c <= 'F'))
        c -= ('A' - 10);
      else {
        p--;
        break;
      }
    }
    if (c >= base) {
      printf("Syntax error: %s\n", p - 1);
      val = -1;
      break;
    }
    val = (val * base) + c;
  }
  while (*p == ' ')
    p++;
  *pp = p;
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_val>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%edi
  mov    0x0(%rbp),%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L0
L36:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L36
L0:
  cmp    $0x30,%al
  je     L84
L15:
  movzbl (%rbx),%ecx
  mov    $0x0,%eax
  test   %cl,%cl
  jne    L44
L59:
  mov    %rbx,%rsi
  jmp    L140
L84:
  movzbl 0x1(%rbx),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  je     L81
  add    $0x1,%rbx
  jmp    L15
L81:
  add    $0x2,%rbx
  mov    $0x10,%edi
  jmp    L15
L52:
  movsbl %dl,%edx
  cmp    %edi,%edx
  jge    L41
  imul   %edi,%eax
  add    %edx,%eax
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L59
L44:
  mov    %rbx,%rsi
  add    $0x1,%rbx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  jbe    L52
  and    $0xffffffdf,%ecx
  lea    -0x41(%rcx),%edx
  cmp    $0x5,%dl
  ja     L113
  lea    -0x37(%rcx),%edx
  jmp    L52
L41:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0xffffffff,%eax
L113:
  cmpb   $0x20,(%rsi)
  jne    L140
L131:
  add    $0x1,%rsi
  cmpb   $0x20,(%rsi)
  je     L131
L140:
  mov    %rsi,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: Syntax error: %s


assistant: ```c
int get_val(const char **pp, int base) {
  int val = 0;
  const char *p = *pp;
  while (*p == ' ')
    p++;
  if (*p == '0') {
    p++;
    if ((*p == 'x') || (*p == 'X')) {
      p++;
      base = 16;
    }
  }
  while (*p) {
    char c = *p++;
    if ((c >= '0') && (c <= '9')) {
      c -= '0';
    } else {
      c &= ~('a' - 'A');
      if ((c >= 'A') && (c <= 'F'))
        c -= ('A' - 10);
      else {
        p--;
        break;
      }
    }
    if (c >= base) {
      printf("Syntax error: %s\n", p - 1);
      val = -1;
      break;
    }
    val = (val * base) + c;
  }
  while (*p == ' ')
    p++;
  *pp = p;
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_val>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  sub    $0x8,%rsp
  mov    0x0(%rbp),%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L36
  nopw   0x0(%rax,%rax,1)
L64:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L64
L36:
  cmp    $0x30,%al
  je     L45
  movzbl (%rbx),%ecx
L68:
  xor    %eax,%eax
  test   %cl,%cl
  jne    L2
  jmp    L88
  xchg   %ax,%ax
L67:
  imul   %edi,%eax
  movzbl (%rbx),%ecx
  add    %edx,%eax
  test   %cl,%cl
  je     L88
L2:
  lea    -0x30(%rcx),%edx
  mov    %rbx,%rsi
  add    $0x1,%rbx
  cmp    $0x9,%dl
  jbe    L106
  and    $0xffffffdf,%ecx
  lea    -0x41(%rcx),%edx
  cmp    $0x5,%dl
  ja     L117
  lea    -0x37(%rcx),%edx
L106:
  movsbl %dl,%edx
  cmp    %edi,%edx
  jl     L67
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0xffffffff,%eax
L117:
  cmpb   $0x20,(%rsi)
  jne    L41
  nopl   (%rax)
L128:
  add    $0x1,%rsi
  cmpb   $0x20,(%rsi)
  je     L128
L41:
  mov    %rsi,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L45:
  movzbl 0x1(%rbx),%ecx
  mov    %ecx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L12
  movzbl 0x2(%rbx),%ecx
  mov    $0x10,%edi
  add    $0x2,%rbx
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rbx
  jmp    L68
  nopl   0x0(%rax)
L88:
  mov    %rbx,%rsi
  mov    %rsi,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: Syntax error: %s


assistant: ```c
int get_val(const char **pp, int base) {
  int val = 0;
  const char *p = *pp;
  while (*p == ' ')
    p++;
  if (*p == '0') {
    p++;
    if ((*p == 'x') || (*p == 'X')) {
      p++;
      base = 16;
    }
  }
  while (*p) {
    char c = *p++;
    if ((c >= '0') && (c <= '9')) {
      c -= '0';
    } else {
      c &= ~('a' - 'A');
      if ((c >= 'A') && (c <= 'F'))
        c -= ('A' - 10);
      else {
        p--;
        break;
      }
    }
    if (c >= base) {
      printf("Syntax error: %s\n", p - 1);
      val = -1;
      break;
    }
    val = (val * base) + c;
  }
  while (*p == ' ')
    p++;
  *pp = p;
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_val>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rbx
  movzbl (%rbx),%ecx
  cmp    $0x20,%cl
  jne    L98
  cs nopw 0x0(%rax,%rax,1)
L20:
  movzbl 0x1(%rbx),%ecx
  add    $0x1,%rbx
  cmp    $0x20,%cl
  je     L20
L98:
  cmp    $0x30,%cl
  je     L125
L82:
  xor    %eax,%eax
  test   %cl,%cl
  jne    L14
  jmp    L103
  nopl   0x0(%rax)
L36:
  imul   %esi,%eax
  movzbl (%rbx),%ecx
  add    %edx,%eax
  test   %cl,%cl
  je     L103
L14:
  lea    -0x30(%rcx),%edx
  mov    %rbx,%rbp
  add    $0x1,%rbx
  cmp    $0x9,%dl
  jbe    L80
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  lea    -0x41(%rdx),%edi
  cmp    $0x5,%dil
  ja     L104
  sub    $0x37,%edx
L80:
  movsbl %dl,%edx
  cmp    %esi,%edx
  jl     L36
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  movzbl 0x1(%rbp),%ecx
  mov    $0xffffffff,%eax
  mov    %rbx,%rbp
L104:
  cmp    $0x20,%cl
  jne    L39
  nop
L110:
  add    $0x1,%rbp
  cmpb   $0x20,0x0(%rbp)
  je     L110
L39:
  mov    %rbp,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L125:
  movzbl 0x1(%rbx),%ecx
  mov    %ecx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L132
  movzbl 0x2(%rbx),%ecx
  mov    $0x10,%esi
  add    $0x2,%rbx
  jmp    L82
  nopw   0x0(%rax,%rax,1)
L132:
  add    $0x1,%rbx
  jmp    L82
  nopl   0x0(%rax)
L103:
  mov    %rbx,%rbp
  pop    %rbx
  mov    %rbp,(%r12)
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: Syntax error: %s


assistant: ```c
int get_val(const char **pp, int base) {
  int val = 0;
  const char *p = *pp;
  while (*p == ' ')
    p++;
  if (*p == '0') {
    p++;
    if ((*p == 'x') || (*p == 'X')) {
      p++;
      base = 16;
    }
  }
  while (*p) {
    char c = *p++;
    if ((c >= '0') && (c <= '9')) {
      c -= '0';
    } else {
      c &= ~('a' - 'A');
      if ((c >= 'A') && (c <= 'F'))
        c -= ('A' - 10);
      else {
        p--;
        break;
      }
    }
    if (c >= base) {
      printf("Syntax error: %s\n", p - 1);
      val = -1;
      break;
    }
    val = (val * base) + c;
  }
  while (*p == ' ')
    p++;
  *pp = p;
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x64,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <SquareOfSums@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <SumOfSquares@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: %d

assistant: ```c
int main() {
  const unsigned int RANGE = 100;
  unsigned int difference = 0;
  difference = SquareOfSums(RANGE) - SumOfSquares(RANGE);
  printf("%d", difference);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x64,%edi
  call   <SquareOfSums@plt>
  mov    %eax,%ebx
  mov    $0x64,%edi
  call   <SumOfSquares@plt>
  sub    %eax,%ebx
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: string

tool: D8: %d

assistant: ```c
int main() {
  const unsigned int RANGE = 100;
  unsigned int difference = 0;
  difference = SquareOfSums(RANGE) - SumOfSquares(RANGE);
  printf("%d", difference);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x64,%edi
  call   <SquareOfSums@plt>
  mov    $0x64,%edi
  mov    %eax,%ebx
  call   <SumOfSquares@plt>
  lea    D7(%rip),%rdi
  sub    %eax,%ebx
  mov    %ebx,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string

tool: D7: %d

assistant: ```c
int main() {
  const unsigned int RANGE = 100;
  unsigned int difference = 0;
  difference = SquareOfSums(RANGE) - SumOfSquares(RANGE);
  printf("%d", difference);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x64,%edi
  call   <SquareOfSums@plt>
  mov    $0x64,%edi
  mov    %eax,%ebx
  call   <SumOfSquares@plt>
  lea    D1(%rip),%rdi
  sub    %eax,%ebx
  mov    %ebx,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: %d

assistant: ```c
int main() {
  const unsigned int RANGE = 100;
  unsigned int difference = 0;
  difference = SquareOfSums(RANGE) - SumOfSquares(RANGE);
  printf("%d", difference);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Operand_mr2_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xfffffffc,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_mr2_encode(unsigned int *valp) {
  int error;
  error = (*valp & ~0x3) != 0;
  return error;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Operand_mr2_encode>:
  endbr64
  testl  $0xfffffffc,(%rdi)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int Operand_mr2_encode(unsigned int *valp) {
  int error;
  error = (*valp & ~0x3) != 0;
  return error;
}
```
user: What is the c source code of the assembly code below:

```asm
<Operand_mr2_encode>:
  endbr64
  xor    %eax,%eax
  testl  $0xfffffffc,(%rdi)
  setne  %al
  ret
```

assistant: ```c
int Operand_mr2_encode(unsigned int *valp) {
  int error;
  error = (*valp & ~0x3) != 0;
  return error;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Operand_mr2_encode>:
  endbr64
  xor    %eax,%eax
  testl  $0xfffffffc,(%rdi)
  setne  %al
  ret
```

assistant: ```c
int Operand_mr2_encode(unsigned int *valp) {
  int error;
  error = (*valp & ~0x3) != 0;
  return error;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_config_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L27
L21:
  addq   $0x7,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L6
L75:
  addq   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L80
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L75
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L75
L80:
  mov    -0x10(%rbp),%rax
  sub    $0x7,%rax
  mov    $0x7,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L71
  mov    -0x10(%rbp),%rax
  sub    $0x7,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L71:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L25
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <use_config@plt>
L25:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L27:
  mov    -0x18(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L21
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string

tool: D7: _MODULE

tool: D18: CONFIG_

assistant: ```c
void parse_config_file(const char *p) {
  const char *q, *r;
  while ((p = strstr(p, "CONFIG_"))) {
    p += 7;
    q = p;
    while (*q && (isalnum(*q) || *q == '_'))
      q++;
    if (memcmp(q - 7, "_MODULE", 7) == 0)
      r = q - 7;
    else
      r = q;
    if (r > p)
      use_config(p, r - p);
    p = q;
  }
}
```