ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_overlay_mount>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D15(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L21
  mov    %rax,%r13
  lea    D3(%rip),%r12
L46:
  mov    %r13,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L41
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L46
  jmp    L29
L41:
  mov    $0xffffffff,%ebx
L29:
  mov    %r13,%rdi
  call   <fclose@plt>
L13:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  mov    $0xffffffff,%ebx
  jmp    L13
```

tool_calls: name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D6
datatype: string

tool: D15: r

tool: D6: /proc/mounts

assistant: ```c
int find_overlay_mount(char *overlay) {
  FILE *fp = fopen("/proc/mounts", "r");
  static char line[256];
  int ret = -1;
  if (!fp)
    return ret;
  while (ret && fgets(line, sizeof(line), fp))
    if (!strncmp(line, overlay, strlen(overlay)))
      ret = 0;
  fclose(fp);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_overlay_mount>:
  endbr64
  push   %r13
  lea    D28(%rip),%rsi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D21(%rip),%rdi
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%r13
  lea    D11(%rip),%rbp
  jmp    L11
  nopl   (%rax)
L31:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L18
L11:
  mov    %r13,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L31
  mov    $0xffffffff,%r12d
L18:
  mov    %r13,%rdi
  call   <fclose@plt>
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0xffffffff,%r12d
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type: string
name: extract_symbolic_data
arguments: label: D21
type: string

tool: D28: r

tool: D21: /proc/mounts

assistant: ```c
int find_overlay_mount(char *overlay) {
  FILE *fp = fopen("/proc/mounts", "r");
  static char line[256];
  int ret = -1;
  if (!fp)
    return ret;
  while (ret && fgets(line, sizeof(line), fp))
    if (!strncmp(line, overlay, strlen(overlay)))
      ret = 0;
  fclose(fp);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find_overlay_mount>:
  endbr64
  push   %r13
  lea    D29(%rip),%rsi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rdi
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%r13
  lea    D9(%rip),%rbp
  jmp    L38
  nopl   (%rax)
L2:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L34
L38:
  mov    %r13,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L2
  mov    $0xffffffff,%r12d
L34:
  mov    %r13,%rdi
  call   <fclose@plt>
L39:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0xffffffff,%r12d
  jmp    L39
```

tool_calls: name: disassemble_data
arguments: label: D29
type_infered: string
name: disassemble_data
arguments: label: D2
type_infered: string

tool: D29: r

tool: D2: /proc/mounts

assistant: ```c
int find_overlay_mount(char *overlay) {
  FILE *fp = fopen("/proc/mounts", "r");
  static char line[256];
  int ret = -1;
  if (!fp)
    return ret;
  while (ret && fgets(line, sizeof(line), fp))
    if (!strncmp(line, overlay, strlen(overlay)))
      ret = 0;
  fclose(fp);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <print_combination_2@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D0: 


assistant: ```c
int main(void) {
  print_combination_2();
  printf("\n");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <print_combination_2@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: string

tool: D6: 


assistant: ```c
int main(void) {
  print_combination_2();
  printf("\n");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_combination_2@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: 


assistant: ```c
int main(void) {
  print_combination_2();
  printf("\n");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_combination_2@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: 


assistant: ```c
int main(void) {
  print_combination_2();
  printf("\n");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xfffffffe,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D54
type: string
name: parse_data
arguments: tag: D50
type: string
name: parse_data
arguments: tag: D70
type: string
name: parse_data
arguments: tag: D53
type: string
name: parse_data
arguments: tag: D6
type: string

tool: D54: i = %d


tool: D50: j = %d


tool: D70: k = %d


tool: D53: 
i = %d


tool: D6: 
j = %d


assistant: ```c
void main() {
  int i, j, k;
  i = 2 / (-2);
  j = 2 % (-2);
  k = 2 % (-3);
  printf("i = %d\n", i);
  printf("j = %d\n", j);
  printf("k = %d\n", k);
  i = (-2) / 2;
  j = (-2) % 2;
  k = -2 % 3;
  printf("\ni = %d\n", i);
  printf("j = %d\n", j);
  printf("k = %d\n", k);
  j = 1, 2;
  k = 2 != 3;
  printf("\nj = %d\n", j);
  printf("k = %d\n", k);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D37(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xfffffffe,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D48
type_guessed: string

tool: D38: i = %d


tool: D1: j = %d


tool: D37: k = %d


tool: D13: 
i = %d


tool: D48: 
j = %d


assistant: ```c
void main() {
  int i, j, k;
  i = 2 / (-2);
  j = 2 % (-2);
  k = 2 % (-3);
  printf("i = %d\n", i);
  printf("j = %d\n", j);
  printf("k = %d\n", k);
  i = (-2) / 2;
  j = (-2) % 2;
  k = -2 % 3;
  printf("\ni = %d\n", i);
  printf("j = %d\n", j);
  printf("k = %d\n", k);
  j = 1, 2;
  k = 2 != 3;
  printf("\nj = %d\n", j);
  printf("k = %d\n", k);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffffff,%esi
  lea    D13(%rip),%r12
  lea    D36(%rip),%rdi
  push   %rbp
  lea    D43(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    $0xffffffff,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xfffffffe,%esi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D36
data_type: string
name: disassemble_data
arguments: tag: D43
data_type: string
name: disassemble_data
arguments: tag: D15
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string

tool: D13: j = %d


tool: D36: i = %d


tool: D43: k = %d


tool: D15: 
i = %d


tool: D17: 
j = %d


assistant: ```c
void main() {
  int i, j, k;
  i = 2 / (-2);
  j = 2 % (-2);
  k = 2 % (-3);
  printf("i = %d\n", i);
  printf("j = %d\n", j);
  printf("k = %d\n", k);
  i = (-2) / 2;
  j = (-2) % 2;
  k = -2 % 3;
  printf("\ni = %d\n", i);
  printf("j = %d\n", j);
  printf("k = %d\n", k);
  j = 1, 2;
  k = 2 != 3;
  printf("\nj = %d\n", j);
  printf("k = %d\n", k);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffffff,%esi
  lea    D19(%rip),%r12
  lea    D17(%rip),%rdi
  push   %rbp
  lea    D39(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    $0xffffffff,%esi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xfffffffe,%esi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string
name: retrieve_data
arguments: data_tag: D39
datatype: string
name: retrieve_data
arguments: data_tag: D45
datatype: string
name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D19: j = %d


tool: D17: i = %d


tool: D39: k = %d


tool: D45: 
i = %d


tool: D7: 
j = %d


assistant: ```c
void main() {
  int i, j, k;
  i = 2 / (-2);
  j = 2 % (-2);
  k = 2 % (-3);
  printf("i = %d\n", i);
  printf("j = %d\n", j);
  printf("k = %d\n", k);
  i = (-2) / 2;
  j = (-2) % 2;
  k = -2 % 3;
  printf("\ni = %d\n", i);
  printf("j = %d\n", j);
  printf("k = %d\n", k);
  j = 1, 2;
  k = 2 != 3;
  printf("\nj = %d\n", j);
  printf("k = %d\n", k);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
f1() {
  typedef struct A A;
  struct A {
    int j;
  };
  {
    struct A {
      int i;
    };
    A a = {.j = 2};
    typedef struct A A;
    A b = {.i = 3};
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<f1>:
  endbr64
  ret
```

assistant: ```c
f1() {
  typedef struct A A;
  struct A {
    int j;
  };
  {
    struct A {
      int i;
    };
    A a = {.j = 2};
    typedef struct A A;
    A b = {.i = 3};
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f1>:
  endbr64
  ret
```

assistant: ```c
f1() {
  typedef struct A A;
  struct A {
    int j;
  };
  {
    struct A {
      int i;
    };
    A a = {.j = 2};
    typedef struct A A;
    A b = {.i = 3};
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f1>:
  endbr64
  ret
```

assistant: ```c
f1() {
  typedef struct A A;
  struct A {
    int j;
  };
  {
    struct A {
      int i;
    };
    A a = {.j = 2};
    typedef struct A A;
    A b = {.i = 3};
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<next_pow_two>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L7
L9:
  shll   -0x4(%rbp)
L7:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L9
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int next_pow_two(int x) {
  int power = 2;
  while (x >>= 1)
    power <<= 1;
  return power;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<next_pow_two>:
  endbr64
  sar    %edi
  je     L11
  mov    $0x2,%eax
L0:
  add    %eax,%eax
  sar    %edi
  jne    L0
  ret
L11:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int next_pow_two(int x) {
  int power = 2;
  while (x >>= 1)
    power <<= 1;
  return power;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<next_pow_two>:
  endbr64
  sar    %edi
  mov    $0x2,%eax
  je     L4
  nopl   (%rax)
L10:
  add    %eax,%eax
  sar    %edi
  jne    L10
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
int next_pow_two(int x) {
  int power = 2;
  while (x >>= 1)
    power <<= 1;
  return power;
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_pow_two>:
  endbr64
  sar    %edi
  mov    $0x2,%eax
  je     L14
  nopl   (%rax)
L16:
  add    %eax,%eax
  sar    %edi
  jne    L16
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
int next_pow_two(int x) {
  int power = 2;
  while (x >>= 1)
    power <<= 1;
  return power;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L10:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L10
  subl   $0x1,-0x8(%rbp)
L30:
  cmpl   $0x0,-0x8(%rbp)
  jg     L11
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c;
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  c = 0;
  while (x > 0) {
    y = 0;
    while (y < x) {
      y = y + 1;
      c = c + 1;
    }
    x = x - 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jg     L36
L42:
  mov    $0x0,%eax
  pop    %rbx
  ret
L38:
  add    $0x1,%eax
  cmp    %ebx,%eax
  jne    L38
L21:
  sub    $0x1,%ebx
  je     L42
L36:
  mov    $0x0,%eax
  test   %ebx,%ebx
  jg     L38
  jmp    L21
```

assistant: ```c
int main() {
  int c;
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  c = 0;
  while (x > 0) {
    y = 0;
    while (y < x) {
      y = y + 1;
      c = c + 1;
    }
    x = x - 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c;
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  c = 0;
  while (x > 0) {
    y = 0;
    while (y < x) {
      y = y + 1;
      c = c + 1;
    }
    x = x - 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movabs $0xffffffff00000000,%r11
  lea    (%rsp,%r11,1),%r11
L13:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L13
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void f() {
  int x0[1073741824];
  int x1[1073741824 + 1];
  int x2[(unsigned)1073741824];
  int x3[(unsigned)1073741824 + 1];
  int x4[1073741824 - 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f() {
  int x0[1073741824];
  int x1[1073741824 + 1];
  int x2[(unsigned)1073741824];
  int x3[(unsigned)1073741824 + 1];
  int x4[1073741824 - 1];
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f() {
  int x0[1073741824];
  int x1[1073741824 + 1];
  int x2[(unsigned)1073741824];
  int x3[(unsigned)1073741824 + 1];
  int x4[1073741824 - 1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f() {
  int x0[1073741824];
  int x1[1073741824 + 1];
  int x2[(unsigned)1073741824];
  int x3[(unsigned)1073741824 + 1];
  int x4[1073741824 - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reaver>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %rdx,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rsi
  mov    -0x120(%rbp),%rcx
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rsi,%r8
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D9: xterm 2> /dev/null -T Reaver -e "reaver -i %s -b %s -c %s -S -L -vv ; read" &

assistant: ```c
void reaver(char *inmon, char *bssid, char *can) {
  char cmd[256];
  sprintf(cmd, "xterm 2> /dev/null -T Reaver -e \"reaver -i %s -b %s -c %s -S -L -vv ; read\" &", inmon, bssid, can);
  system(cmd);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reaver>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %rsi,%rcx
  mov    %rdx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rdx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x110,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: xterm 2> /dev/null -T Reaver -e "reaver -i %s -b %s -c %s -S -L -vv ; read" &

assistant: ```c
void reaver(char *inmon, char *bssid, char *can) {
  char cmd[256];
  sprintf(cmd, "xterm 2> /dev/null -T Reaver -e \"reaver -i %s -b %s -c %s -S -L -vv ; read\" &", inmon, bssid, can);
  system(cmd);
}
```
user: What is the c source code of the assembly code below?

```asm
<reaver>:
  endbr64
  push   %rbp
  mov    %rsi,%rcx
  mov    %rdx,%r8
  lea    D7(%rip),%rsi
  mov    %rdi,%rdx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x110,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D7: xterm 2> /dev/null -T Reaver -e "reaver -i %s -b %s -c %s -S -L -vv ; read" &

assistant: ```c
void reaver(char *inmon, char *bssid, char *can) {
  char cmd[256];
  sprintf(cmd, "xterm 2> /dev/null -T Reaver -e \"reaver -i %s -b %s -c %s -S -L -vv ; read\" &", inmon, bssid, can);
  system(cmd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reaver>:
  endbr64
  push   %rbp
  mov    %rsi,%rcx
  mov    %rdx,%r8
  lea    D2(%rip),%rsi
  mov    %rdi,%rdx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x110,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: xterm 2> /dev/null -T Reaver -e "reaver -i %s -b %s -c %s -S -L -vv ; read" &

assistant: ```c
void reaver(char *inmon, char *bssid, char *can) {
  char cmd[256];
  sprintf(cmd, "xterm 2> /dev/null -T Reaver -e \"reaver -i %s -b %s -c %s -S -L -vv ; read\" &", inmon, bssid, can);
  system(cmd);
}
```