ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<marshal_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%r8
  lea    D5(%rip),%rdx
  call   <marshal_string@plt>
  mov    %rax,%rbx
  mov    %r13,%r9
  mov    %r12,%r8
  mov    $0x10,%ecx
  mov    %rbp,%rdx
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <marshal_unsigned@plt>
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: 0x

assistant: ```c
int marshal_hex(char *buffer, size_t len, size_t hex_val, char **nbuffer, size_t *nlen) {
  int ret_val = 0;
  char *my_buffer;
  size_t my_len;
  ret_val += marshal_string(buffer, len, "0x", &my_buffer, &my_len);
  ret_val += marshal_unsigned(my_buffer, my_len, hex_val, 16, nbuffer, nlen);
  return ret_val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<marshal_hex>:
  endbr64
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdx,%r12
  lea    D6(%rip),%rdx
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%r8
  call   <marshal_string@plt>
  mov    0x10(%rsp),%rsi
  mov    %r13,%r9
  mov    %rbp,%r8
  mov    0x8(%rsp),%rdi
  mov    $0x10,%ecx
  mov    %r12,%rdx
  mov    %rax,%rbx
  call   <marshal_unsigned@plt>
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: 0x

assistant: ```c
int marshal_hex(char *buffer, size_t len, size_t hex_val, char **nbuffer, size_t *nlen) {
  int ret_val = 0;
  char *my_buffer;
  size_t my_len;
  ret_val += marshal_string(buffer, len, "0x", &my_buffer, &my_len);
  ret_val += marshal_unsigned(my_buffer, my_len, hex_val, 16, nbuffer, nlen);
  return ret_val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<marshal_hex>:
  endbr64
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdx,%r12
  lea    D9(%rip),%rdx
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%r8
  call   <marshal_string@plt>
  mov    0x10(%rsp),%rsi
  mov    %r13,%r9
  mov    %rbp,%r8
  mov    0x8(%rsp),%rdi
  mov    $0x10,%ecx
  mov    %r12,%rdx
  mov    %rax,%rbx
  call   <marshal_unsigned@plt>
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: 0x

assistant: ```c
int marshal_hex(char *buffer, size_t len, size_t hex_val, char **nbuffer, size_t *nlen) {
  int ret_val = 0;
  char *my_buffer;
  size_t my_len;
  ret_val += marshal_string(buffer, len, "0x", &my_buffer, &my_len);
  ret_val += marshal_unsigned(my_buffer, my_len, hex_val, 16, nbuffer, nlen);
  return ret_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <platform_led_setup@plt>
  mov    $0x3d0900,%edi
  call   <platform_systick_setup@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setup() {
  platform_led_setup();
  platform_systick_setup(4000000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <platform_led_setup@plt>
  mov    $0x3d0900,%edi
  call   <platform_systick_setup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void setup() {
  platform_led_setup();
  platform_systick_setup(4000000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <platform_led_setup@plt>
  mov    $0x3d0900,%edi
  add    $0x8,%rsp
  jmp    1070 <platform_systick_setup@plt>
```

assistant: ```c
void setup() {
  platform_led_setup();
  platform_systick_setup(4000000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<setup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <platform_led_setup@plt>
  mov    $0x3d0900,%edi
  add    $0x8,%rsp
  jmp    1070 <platform_systick_setup@plt>
```

assistant: ```c
void setup() {
  platform_led_setup();
  platform_systick_setup(4000000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_lock@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void bar(void) {
  pthread_mutex_t mx = PTHREAD_MUTEX_INITIALIZER;
  pthread_mutex_lock(&mx);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bar>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <pthread_mutex_lock@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar(void) {
  pthread_mutex_t mx = PTHREAD_MUTEX_INITIALIZER;
  pthread_mutex_lock(&mx);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rdi
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  call   <pthread_mutex_lock@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar(void) {
  pthread_mutex_t mx = PTHREAD_MUTEX_INITIALIZER;
  pthread_mutex_lock(&mx);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D1(%rip),%rax
  lea    0x4(%rsp),%rdi
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  call   <pthread_mutex_lock@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar(void) {
  pthread_mutex_t mx = PTHREAD_MUTEX_INITIALIZER;
  pthread_mutex_lock(&mx);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x5,-0x14(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L8
L18:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D8(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L8:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L18
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D8
type_infered: byte[8]

tool: D1: %d

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
int main() {
  int n, i, j, k, c;
  scanf("%d", &n);
  k = 5;
  for (i = 1; i <= n; i++) {
    j = floor(k / (double)2);
    c += j;
    k = 3 * j;
  }
  printf("%d", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L26
  mov    $0x5,%eax
  mov    $0x1,%ebx
L20:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D16(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  add    %eax,%ebp
  lea    (%rax,%rax,2),%eax
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L20
L26:
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D16
type: byte[8]

tool: D24: %d

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  int n, i, j, k, c;
  scanf("%d", &n);
  k = 5;
  for (i = 1; i <= n; i++) {
    j = floor(k / (double)2);
    c += j;
    k = 3 * j;
  }
  printf("%d", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L2
  mov    $0x5,%eax
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L16:
  pxor   %xmm0,%xmm0
  add    $0x1,%ebx
  cvtsi2sd %eax,%xmm0
  mulsd  D9(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  add    %eax,%ebp
  lea    (%rax,%rax,2),%eax
  cmp    %ebx,0x4(%rsp)
  jge    L16
L2:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: byte[8]

tool: D17: %d

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  int n, i, j, k, c;
  scanf("%d", &n);
  k = 5;
  for (i = 1; i <= n; i++) {
    j = floor(k / (double)2);
    c += j;
    k = 3 * j;
  }
  printf("%d", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L25
  mov    $0x5,%eax
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L23:
  pxor   %xmm0,%xmm0
  add    $0x1,%ebx
  cvtsi2sd %eax,%xmm0
  mulsd  D14(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  add    %eax,%ebp
  lea    (%rax,%rax,2),%eax
  cmp    %ebx,0x4(%rsp)
  jge    L23
L25:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: byte[8]

tool: D18: %d

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  int n, i, j, k, c;
  scanf("%d", &n);
  k = 5;
  for (i = 1; i <= n; i++) {
    j = floor(k / (double)2);
    c += j;
    k = 3 * j;
  }
  printf("%d", c);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<muld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D33(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L142
  movsd  D58(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  jae    L20
L142:
  movsd  -0x20(%rbp),%xmm0
  movsd  D33(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L81
  movsd  D58(%rip),%xmm0
  comisd -0x20(%rbp),%xmm0
  jae    L20
L81:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L168
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L168
  movsd  -0x18(%rbp),%xmm0
  movq   D47(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movq   D47(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  divsd  -0x20(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L20
L168:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L117
  movsd  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L117
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L20
L117:
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L136
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L136
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x18(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L20
L136:
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L48
  movsd  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L48
  movsd  -0x30(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L48
L20:
  mov    $0x1,%eax
  jmp    L188
L48:
  mov    $0x0,%eax
L188:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L150
  cmpl   $0x0,-0x34(%rbp)
  je     L150
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <warning@plt>
  movl   $0x1,-0x4(%rbp)
L150:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D33
type_infered: byte[8]
name: retrieve_data
arguments: tag: D58
type_infered: byte[8]
name: retrieve_data
arguments: tag: D47
type_infered: byte[8]
name: retrieve_data
arguments: tag: D26
type_infered: string

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D26: overflow in constant expression


assistant: ```c
int muld(double x, double y, double min, double max, int needconst) {
  int cond = x >= -1 && x <= 1 || y >= -1 && y <= 1 || x < 0 && y < 0 && -x <= max / -y || x < 0 && y > 0 && x >= min / y || x > 0 && y < 0 && y >= min / x || x > 0 && y > 0 && x <= max / y;
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<muld>:
  endbr64
  movsd  D8(%rip),%xmm4
  comisd %xmm4,%xmm0
  jb     L41
  movsd  D44(%rip),%xmm5
  mov    $0x1,%eax
  comisd %xmm0,%xmm5
  jae    L111
L41:
  comisd %xmm4,%xmm1
  jb     L8
  movsd  D44(%rip),%xmm4
  mov    $0x1,%eax
  comisd %xmm1,%xmm4
  jae    L111
L8:
  pxor   %xmm4,%xmm4
  comisd %xmm0,%xmm4
  ja     L15
L125:
  comisd %xmm4,%xmm0
  jbe    L135
  comisd %xmm1,%xmm4
  ja     L25
L18:
  comisd %xmm4,%xmm1
  jbe    L135
  divsd  %xmm1,%xmm3
  mov    $0x1,%eax
  comisd %xmm0,%xmm3
  jae    L111
  nopl   (%rax)
L135:
  test   %edi,%edi
  je     L143
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <warning@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L15:
  comisd %xmm1,%xmm4
  ja     L28
L130:
  comisd %xmm4,%xmm1
  jbe    L125
  movapd %xmm2,%xmm5
  mov    $0x1,%eax
  divsd  %xmm1,%xmm5
  comisd %xmm5,%xmm0
  jb     L125
L111:
  ret
L25:
  divsd  %xmm0,%xmm2
  mov    $0x1,%eax
  comisd %xmm2,%xmm1
  jb     L18
  ret
L28:
  movq   D41(%rip),%xmm5
  movapd %xmm0,%xmm6
  mov    $0x1,%eax
  xorpd  %xmm5,%xmm6
  xorpd  %xmm3,%xmm5
  divsd  %xmm1,%xmm5
  comisd %xmm6,%xmm5
  jb     L130
  ret
  nopl   0x0(%rax)
L143:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: byte[8]
name: retrieve_data
arguments: data_tag: D44
type: byte[8]
name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D41
type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D15: overflow in constant expression


tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int muld(double x, double y, double min, double max, int needconst) {
  int cond = x >= -1 && x <= 1 || y >= -1 && y <= 1 || x < 0 && y < 0 && -x <= max / -y || x < 0 && y > 0 && x >= min / y || x > 0 && y < 0 && y >= min / x || x > 0 && y > 0 && x <= max / y;
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<muld>:
  endbr64
  movsd  D47(%rip),%xmm4
  comisd %xmm4,%xmm0
  jb     L93
  movsd  D32(%rip),%xmm5
  mov    $0x1,%eax
  comisd %xmm0,%xmm5
  jae    L62
L93:
  comisd %xmm4,%xmm1
  jb     L10
  movsd  D32(%rip),%xmm4
  mov    $0x1,%eax
  comisd %xmm1,%xmm4
  jae    L62
L10:
  pxor   %xmm4,%xmm4
  comisd %xmm0,%xmm4
  ja     L2
L61:
  comisd %xmm4,%xmm0
  jbe    L59
  comisd %xmm1,%xmm4
  ja     L9
L118:
  comisd %xmm4,%xmm1
  jbe    L59
  divsd  %xmm1,%xmm3
  mov    $0x1,%eax
  comisd %xmm0,%xmm3
  jae    L62
  nopl   (%rax)
L59:
  test   %edi,%edi
  je     L91
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <warning@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L2:
  comisd %xmm1,%xmm4
  ja     L63
L67:
  comisd %xmm4,%xmm1
  jbe    L61
  movapd %xmm2,%xmm5
  mov    $0x1,%eax
  divsd  %xmm1,%xmm5
  comisd %xmm5,%xmm0
  jb     L61
L62:
  ret
L9:
  divsd  %xmm0,%xmm2
  mov    $0x1,%eax
  comisd %xmm2,%xmm1
  jb     L118
  ret
L63:
  movq   D28(%rip),%xmm5
  movapd %xmm0,%xmm6
  mov    $0x1,%eax
  xorpd  %xmm5,%xmm6
  xorpd  %xmm3,%xmm5
  divsd  %xmm1,%xmm5
  comisd %xmm6,%xmm5
  jb     L67
  ret
  nopl   0x0(%rax)
L91:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D47
datatype: byte[8]
name: retrieve_data
arguments: tag: D32
datatype: byte[8]
name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D28
datatype: byte[8]

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D16: overflow in constant expression


tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int muld(double x, double y, double min, double max, int needconst) {
  int cond = x >= -1 && x <= 1 || y >= -1 && y <= 1 || x < 0 && y < 0 && -x <= max / -y || x < 0 && y > 0 && x >= min / y || x > 0 && y < 0 && y >= min / x || x > 0 && y > 0 && x <= max / y;
  if (!cond && needconst) {
    warning("overflow in constant expression\n");
    cond = 1;
  }
  return cond;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Double_QR_Iteration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%r9
  lea    -0x18(%rbp),%r8
  mov    -0x48(%rbp),%rcx
  mov    -0x38(%rbp),%edx
  mov    -0x3c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  mov    0x10(%rbp),%edi
  push   %rdi
  mov    %rax,%rdi
  call   <Product_and_Sum_of_Shifts@plt>
  add    $0x10,%rsp
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rdi
  mov    -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%esi
  mov    -0x28(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <Two_Consecutive_Small_Subdiagonal@plt>
  mov    %eax,-0x1c(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rdi
  mov    -0x3c(%rbp),%r9d
  mov    -0x30(%rbp),%r8
  mov    -0x1c(%rbp),%ecx
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%esi
  mov    -0x28(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <Double_QR_Step@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void Double_QR_Iteration(double *H, double *S, int min_row, int max_row, int n, double *shift, int iteration) {
  int k;
  double trace, det;
  Product_and_Sum_of_Shifts(H, n, max_row, shift, &trace, &det, iteration);
  k = Two_Consecutive_Small_Subdiagonal(H, min_row, max_row, n, trace, det);
  Double_QR_Step(H, min_row, max_row, k, trace, det, S, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Double_QR_Iteration>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %ecx,%ebp
  mov    %r8d,%r12d
  mov    %r9,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  mov    0x58(%rsp),%eax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  mov    %ebp,%edx
  mov    %r12d,%esi
  call   <Product_and_Sum_of_Shifts@plt>
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <Two_Consecutive_Small_Subdiagonal@plt>
  mov    %eax,%ecx
  mov    %r12d,%r9d
  mov    %r14,%r8
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <Double_QR_Step@plt>
  add    $0x10,%rsp
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Double_QR_Iteration(double *H, double *S, int min_row, int max_row, int n, double *shift, int iteration) {
  int k;
  double trace, det;
  Product_and_Sum_of_Shifts(H, n, max_row, shift, &trace, &det, iteration);
  k = Two_Consecutive_Small_Subdiagonal(H, min_row, max_row, n, trace, det);
  Double_QR_Step(H, min_row, max_row, k, trace, det, S, n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Double_QR_Iteration>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  mov    %r9,%rcx
  push   %rbp
  mov    %r12d,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  mov    %ebx,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  mov    0x58(%rsp),%eax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <Product_and_Sum_of_Shifts@plt>
  movsd  0x20(%rsp),%xmm1
  mov    %ebx,%ecx
  mov    %r12d,%edx
  movsd  0x18(%rsp),%xmm0
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <Two_Consecutive_Small_Subdiagonal@plt>
  mov    %r12d,%edx
  mov    %ebx,%r9d
  mov    %r14,%r8
  movsd  0x20(%rsp),%xmm1
  mov    %eax,%ecx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  movsd  0x18(%rsp),%xmm0
  call   <Double_QR_Step@plt>
  pop    %rax
  pop    %rdx
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Double_QR_Iteration(double *H, double *S, int min_row, int max_row, int n, double *shift, int iteration) {
  int k;
  double trace, det;
  Product_and_Sum_of_Shifts(H, n, max_row, shift, &trace, &det, iteration);
  k = Two_Consecutive_Small_Subdiagonal(H, min_row, max_row, n, trace, det);
  Double_QR_Step(H, min_row, max_row, k, trace, det, S, n);
}
```