ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printProgramIdentification>:
  endbr64
  sub    $0x8,%rsp
  lea    D83(%rip),%r8
  xor    %eax,%eax
  lea    D54(%rip),%rcx
  lea    D68(%rip),%rdx
  lea    D63(%rip),%rsi
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdx
  lea    D98(%rip),%rsi
  xor    %eax,%eax
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdx
  lea    D103(%rip),%rsi
  xor    %eax,%eax
  lea    D92(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <printFeatureList@plt>
```

tool_calls: name: unpack_data
arguments: tag: D83
datatype: string
name: unpack_data
arguments: tag: D54
datatype: string
name: unpack_data
arguments: tag: D68
datatype: string
name: unpack_data
arguments: tag: D63
datatype: string
name: unpack_data
arguments: tag: D66
datatype: string
name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D98
datatype: string
name: unpack_data
arguments: tag: D61
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string
name: unpack_data
arguments: tag: D103
datatype: string
name: unpack_data
arguments: tag: D92
datatype: string

tool: D83: Darren Hiebert

tool: D54: Copyright (C) 1996-2009

tool: D68: Development

tool: D63: Universal Ctags

tool: D66: %s %s, %s %s


tool: D28: 02:34:12

tool: D98: Mar 17 2022

tool: D61:   Compiled: %s, %s


tool: D13: https://github.com/universal-ctags/ctags

tool: D103: dhiebert@users.sourceforge.net

tool: D92:   Addresses: <%s>, %s


assistant: ```c
void printProgramIdentification(void) {
  printf("%s %s, %s %s\n", "Universal Ctags", "Development", "Copyright (C) 1996-2009", "Darren Hiebert");
  printf("  Compiled: %s, %s\n", "Mar 17 2022", "02:34:12");
  printf("  Addresses: <%s>, %s\n", "dhiebert@users.sourceforge.net", "https://github.com/universal-ctags/ctags");
  printFeatureList();
}
```
user: Translate the below assembly code into C programming language:

```asm
<printProgramIdentification>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%r8
  xor    %eax,%eax
  lea    D46(%rip),%rcx
  lea    D7(%rip),%rdx
  lea    D1(%rip),%rsi
  lea    D74(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdx
  lea    D2(%rip),%rsi
  xor    %eax,%eax
  lea    D108(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdx
  lea    D23(%rip),%rsi
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <printFeatureList@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
datatype: string
name: retrieve_data
arguments: label: D46
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D74
datatype: string
name: retrieve_data
arguments: label: D38
datatype: string
name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D108
datatype: string
name: retrieve_data
arguments: label: D52
datatype: string
name: retrieve_data
arguments: label: D23
datatype: string
name: retrieve_data
arguments: label: D12
datatype: string

tool: D18: Darren Hiebert

tool: D46: Copyright (C) 1996-2009

tool: D7: Development

tool: D1: Universal Ctags

tool: D74: %s %s, %s %s


tool: D38: 02:34:12

tool: D2: Mar 17 2022

tool: D108:   Compiled: %s, %s


tool: D52: https://github.com/universal-ctags/ctags

tool: D23: dhiebert@users.sourceforge.net

tool: D12:   Addresses: <%s>, %s


assistant: ```c
void printProgramIdentification(void) {
  printf("%s %s, %s %s\n", "Universal Ctags", "Development", "Copyright (C) 1996-2009", "Darren Hiebert");
  printf("  Compiled: %s, %s\n", "Mar 17 2022", "02:34:12");
  printf("  Addresses: <%s>, %s\n", "dhiebert@users.sourceforge.net", "https://github.com/universal-ctags/ctags");
  printFeatureList();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x64,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: You are %i miles away.


assistant: ```c
int main() {
  int distance = 100;
  printf("You are %i miles away.\n", distance);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: string

tool: D6: You are %i miles away.


assistant: ```c
int main() {
  int distance = 100;
  printf("You are %i miles away.\n", distance);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: You are %i miles away.


assistant: ```c
int main() {
  int distance = 100;
  printf("You are %i miles away.\n", distance);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: You are %i miles away.


assistant: ```c
int main() {
  int distance = 100;
  printf("You are %i miles away.\n", distance);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<madd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void madd(double *A, double *B, double *C, int rows, int cols) {
  int N, i;
  N = rows * cols;
#pragma omp parallel for
  for (i = 0; i < N; ++i) {
    C[i] = A[i] + B[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<madd>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  jle    L3
  mov    %ecx,%ecx
  mov    $0x0,%eax
L16:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L16
L3:
  ret
```

assistant: ```c
void madd(double *A, double *B, double *C, int rows, int cols) {
  int N, i;
  N = rows * cols;
#pragma omp parallel for
  for (i = 0; i < N; ++i) {
    C[i] = A[i] + B[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<madd>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  jle    L0
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L16
L0:
  ret
```

assistant: ```c
void madd(double *A, double *B, double *C, int rows, int cols) {
  int N, i;
  N = rows * cols;
#pragma omp parallel for
  for (i = 0; i < N; ++i) {
    C[i] = A[i] + B[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<madd>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  jle    L14
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdx
  lea    0x8(%rdi),%rax
  setne  %r8b
  cmp    %rax,%rdx
  setne  %al
  test   %al,%r8b
  je     L39
  lea    -0x1(%rcx),%eax
  cmp    $0x1,%eax
  jbe    L39
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    %r8d
  shl    $0x4,%r8
  xchg   %ax,%ax
L54:
  movupd (%rdi,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L54
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L14
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  ret
  nopl   (%rax)
L39:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L19
L14:
  ret
```

assistant: ```c
void madd(double *A, double *B, double *C, int rows, int cols) {
  int N, i;
  N = rows * cols;
#pragma omp parallel for
  for (i = 0; i < N; ++i) {
    C[i] = A[i] + B[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FatorialR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L25
  mov    $0x0,%eax
  jmp    L24
L25:
  cmpl   $0x0,-0x4(%rbp)
  je     L36
  cmpl   $0x1,-0x4(%rbp)
  jne    L35
L36:
  mov    $0x1,%eax
  jmp    L24
L35:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <FatorialRec@plt>
  imul   -0x4(%rbp),%eax
L24:
  leave
  ret
```

assistant: ```c
int FatorialR(int n) {
  if (n < 0)
    return 0;
  else if (n == 0 || n == 1)
    return 1;
  else
    return n * FatorialRec(n - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<FatorialR>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L16
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x1,%edi
  ja     L20
L23:
  pop    %rbx
  ret
L20:
  lea    -0x1(%rdi),%edi
  call   <FatorialRec@plt>
  imul   %ebx,%eax
  jmp    L23
L16:
  ret
```

assistant: ```c
int FatorialR(int n) {
  if (n < 0)
    return 0;
  else if (n == 0 || n == 1)
    return 1;
  else
    return n * FatorialRec(n - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FatorialR>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L16
  push   %rbx
  mov    $0x1,%eax
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L3
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  lea    -0x1(%rdi),%edi
  call   <FatorialRec@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L16:
  ret
```

assistant: ```c
int FatorialR(int n) {
  if (n < 0)
    return 0;
  else if (n == 0 || n == 1)
    return 1;
  else
    return n * FatorialRec(n - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FatorialR>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L4
  push   %rbx
  mov    $0x1,%eax
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L18
  pop    %rbx
  ret
  nopl   0x0(%rax)
L18:
  lea    -0x1(%rdi),%edi
  call   <FatorialRec@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
int FatorialR(int n) {
  if (n < 0)
    return 0;
  else if (n == 0 || n == 1)
    return 1;
  else
    return n * FatorialRec(n - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <_event@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x0,%eax
  jmp    L12
L10:
  mov    $0x2,%eax
L12:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return (_event(argv[0]) == 0) ? 0 : 2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <_event@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return (_event(argv[0]) == 0) ? 0 : 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <_event@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return (_event(argv[0]) == 0) ? 0 : 2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <_event@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return (_event(argv[0]) == 0) ? 0 : 2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  cwtl
  mov    -0xc(%rbp),%edx
  sar    $0x10,%edx
  imul   %edx,%eax
  add    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  mov    $0xa,%eax
  jmp    L10
L12:
  mov    -0x4(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  a += (short)b * (c >> 16);
  if (!a)
    return 10;
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  mov    %edx,%eax
  sar    $0x10,%eax
  movswl %si,%esi
  imul   %esi,%eax
  add    %edi,%eax
  mov    $0xa,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  a += (short)b * (c >> 16);
  if (!a)
    return 10;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    %edx,%eax
  movswl %si,%esi
  mov    $0xa,%edx
  sar    $0x10,%eax
  imul   %esi,%eax
  add    %edi,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  a += (short)b * (c >> 16);
  if (!a)
    return 10;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  mov    %edx,%eax
  movswl %si,%esi
  mov    $0xa,%edx
  sar    $0x10,%eax
  imul   %esi,%eax
  add    %edi,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  a += (short)b * (c >> 16);
  if (!a)
    return 10;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mstrlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    $0x0,%eax
  jmp    L5
L29:
  movq   $0x1,-0x8(%rbp)
  jmp    L24
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  addq   $0x1,-0x8(%rbp)
L28:
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    -0x8(%rbp),%rax
L5:
  pop    %rbp
  ret
```

assistant: ```c
size_t mstrlen(const char *s) {
  size_t size;
  if (!*s)
    return 0;
  for (size = 1; *s || *(s + 1); s++)
    if (!*s)
      size++;
  return size;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mstrlen>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  je     L11
  mov    $0x1,%eax
  jmp    L39
L10:
  add    $0x1,%rax
L1:
  add    $0x1,%rdi
L39:
  cmpb   $0x0,(%rdi)
  jne    L1
  cmpb   $0x0,0x1(%rdi)
  jne    L10
L11:
  ret
```

assistant: ```c
size_t mstrlen(const char *s) {
  size_t size;
  if (!*s)
    return 0;
  for (size = 1; *s || *(s + 1); s++)
    if (!*s)
      size++;
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mstrlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L42
  mov    $0x1,%eax
L12:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L12
  cmpb   $0x0,0x1(%rdi)
  je     L42
L46:
  add    $0x1,%rdi
  add    $0x1,%rax
  cmpb   $0x0,(%rdi)
  jne    L12
  cmpb   $0x0,0x1(%rdi)
  jne    L46
L42:
  ret
```

assistant: ```c
size_t mstrlen(const char *s) {
  size_t size;
  if (!*s)
    return 0;
  for (size = 1; *s || *(s + 1); s++)
    if (!*s)
      size++;
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mstrlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L40
  mov    $0x1,%eax
L15:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L15
  cmpb   $0x0,0x1(%rdi)
  je     L40
L0:
  add    $0x1,%rdi
  add    $0x1,%rax
  cmpb   $0x0,(%rdi)
  jne    L15
  cmpb   $0x0,0x1(%rdi)
  jne    L0
L40:
  ret
```

assistant: ```c
size_t mstrlen(const char *s) {
  size_t size;
  if (!*s)
    return 0;
  for (size = 1; *s || *(s + 1); s++)
    if (!*s)
      size++;
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unsigned_high_prod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signed_high_prod@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  add    %ecx,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned unsigned_high_prod(unsigned x, unsigned y) {
  int x_highest_bit = (x & INT_MIN) == INT_MIN;
  int y_highest_bit = (y & INT_MIN) == INT_MIN;
  int result = signed_high_prod(x, y) + x * y_highest_bit + y * x_highest_bit;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unsigned_high_prod>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  and    %edi,%edx
  cmp    %eax,%edx
  sete   %bl
  mov    %eax,%edx
  and    %esi,%edx
  cmp    %eax,%edx
  sete   %bpl
  call   <signed_high_prod@plt>
  mov    %eax,%edx
  movzbl %bl,%ebx
  imul   %r13d,%ebx
  movzbl %bpl,%ebp
  imul   %r12d,%ebp
  lea    (%rbx,%rbp,1),%eax
  add    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned unsigned_high_prod(unsigned x, unsigned y) {
  int x_highest_bit = (x & INT_MIN) == INT_MIN;
  int y_highest_bit = (y & INT_MIN) == INT_MIN;
  int result = signed_high_prod(x, y) + x * y_highest_bit + y * x_highest_bit;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unsigned_high_prod>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  and    %edi,%edx
  cmp    %eax,%edx
  mov    %eax,%edx
  sete   %bl
  and    %esi,%edx
  cmp    %eax,%edx
  movzbl %bl,%ebx
  sete   %bpl
  imul   %r13d,%ebx
  call   <signed_high_prod@plt>
  movzbl %bpl,%ebp
  add    $0x8,%rsp
  imul   %r12d,%ebp
  mov    %eax,%r8d
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  add    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned unsigned_high_prod(unsigned x, unsigned y) {
  int x_highest_bit = (x & INT_MIN) == INT_MIN;
  int y_highest_bit = (y & INT_MIN) == INT_MIN;
  int result = signed_high_prod(x, y) + x * y_highest_bit + y * x_highest_bit;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unsigned_high_prod>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  and    %edi,%edx
  cmp    %eax,%edx
  mov    %eax,%edx
  sete   %bl
  and    %esi,%edx
  cmp    %eax,%edx
  movzbl %bl,%ebx
  sete   %bpl
  imul   %r13d,%ebx
  call   <signed_high_prod@plt>
  movzbl %bpl,%ebp
  add    $0x8,%rsp
  imul   %r12d,%ebp
  mov    %eax,%r8d
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  add    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned unsigned_high_prod(unsigned x, unsigned y) {
  int x_highest_bit = (x & INT_MIN) == INT_MIN;
  int y_highest_bit = (y & INT_MIN) == INT_MIN;
  int result = signed_high_prod(x, y) + x * y_highest_bit + y * x_highest_bit;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LIBRARY_toolconn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <LibraryHeader@plt>
  mov    $0x0,%eax
  call   <DATA_toolconn@plt>
  mov    $0x0,%eax
  call   <STARTUP_toolconn@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string

tool: D14: Sat Feb  1 10:41:08 2014 

tool: D10: toolconn

assistant: ```c
LIBRARY_toolconn() {
  LibraryHeader("toolconn", "Sat Feb  1 10:41:08 2014 ");
  DATA_toolconn();
  STARTUP_toolconn();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LIBRARY_toolconn>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <LibraryHeader@plt>
  mov    $0x0,%eax
  call   <DATA_toolconn@plt>
  mov    $0x0,%eax
  call   <STARTUP_toolconn@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string

tool: D18: Sat Feb  1 10:41:08 2014 

tool: D4: toolconn

assistant: ```c
LIBRARY_toolconn() {
  LibraryHeader("toolconn", "Sat Feb  1 10:41:08 2014 ");
  DATA_toolconn();
  STARTUP_toolconn();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<LIBRARY_toolconn>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <LibraryHeader@plt>
  xor    %eax,%eax
  call   <DATA_toolconn@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <STARTUP_toolconn@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type: string
name: read_data
arguments: tag: D8
type: string

tool: D16: Sat Feb  1 10:41:08 2014 

tool: D8: toolconn

assistant: ```c
LIBRARY_toolconn() {
  LibraryHeader("toolconn", "Sat Feb  1 10:41:08 2014 ");
  DATA_toolconn();
  STARTUP_toolconn();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LIBRARY_toolconn>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <LibraryHeader@plt>
  xor    %eax,%eax
  call   <DATA_toolconn@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <STARTUP_toolconn@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string
name: read_data
arguments: data_tag: D8
data_type: string

tool: D4: Sat Feb  1 10:41:08 2014 

tool: D8: toolconn

assistant: ```c
LIBRARY_toolconn() {
  LibraryHeader("toolconn", "Sat Feb  1 10:41:08 2014 ");
  DATA_toolconn();
  STARTUP_toolconn();
}
```