ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xrop3_77_1_1>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  movzbl %sil,%edx
  mov    %edx,%esi
  shl    $0x8,%esi
  or     %edx,%esi
  or     %eax,%esi
  xor    $0xff,%al
  or     %esi,%eax
  not    %eax
  movzbl %sil,%esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_77_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk2 = S ^ T;
  stk3 = D ^ S;
  stk2 = stk2 | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: What is the c source code of the assembly code below:

```asm
<xrop3_77_1_1>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%edx
  mov    %edi,%eax
  mov    %edx,%esi
  shl    $0x8,%eax
  shl    $0x8,%esi
  or     %edi,%eax
  or     %edx,%esi
  or     %eax,%esi
  xor    $0xff,%al
  or     %esi,%eax
  movzbl %sil,%esi
  not    %eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_77_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk2 = S ^ T;
  stk3 = D ^ S;
  stk2 = stk2 | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xrop3_77_1_1>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%edx
  mov    %edi,%eax
  mov    %edx,%esi
  shl    $0x8,%eax
  shl    $0x8,%esi
  or     %edi,%eax
  or     %edx,%esi
  or     %eax,%esi
  xor    $0xff,%al
  or     %esi,%eax
  movzbl %sil,%esi
  not    %eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_77_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk2 = S ^ T;
  stk3 = D ^ S;
  stk2 = stk2 | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<anacond>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x248218,-0x8(%rbp)
  je     L82
  cmpq   $0x248218,-0x8(%rbp)
  ja     L69
  cmpq   $0x248210,-0x8(%rbp)
  je     L39
  cmpq   $0x248210,-0x8(%rbp)
  ja     L69
  cmpq   $0x1,-0x8(%rbp)
  je     L42
  cmpq   $0x248200,-0x8(%rbp)
  je     L86
  jmp    L69
L42:
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L39:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L82:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L86:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L69:
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L64:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D45
type_guessed: string
name: read_data
arguments: data_tag: D15
type_guessed: string
name: read_data
arguments: data_tag: D27
type_guessed: string
name: read_data
arguments: data_tag: D38
type_guessed: string
name: read_data
arguments: data_tag: D31
type_guessed: string

tool: D45: SS$_NORMAL


tool: D15: STR$_INVDELIM


tool: D27: STR$_NOELEM


tool: D38: STR$_TRU


tool: D31: Unknown condition code

assistant: ```c
void anacond(unsigned long condcode) {
  switch (condcode) {
  case 1:
    printf("SS$_NORMAL\n");
    break;
  case 2392592:
    printf("STR$_INVDELIM\n");
    break;
  case 2392600:
    printf("STR$_NOELEM\n");
    break;
  case 2392576:
    printf("STR$_TRU\n");
    break;
  default:
    printf("Unknown condition code");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<anacond>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x248210,%rdi
  je     L16
  ja     L42
  cmp    $0x1,%rdi
  je     L76
  cmp    $0x248200,%rdi
  jne    L70
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L67
L42:
  cmp    $0x248218,%rdi
  jne    L70
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L67
L76:
  lea    D22(%rip),%rdi
  call   <printf@plt>
L67:
  add    $0x8,%rsp
  ret
L16:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L67
L70:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L67
```

tool_calls: name: disassemble_data
arguments: label: D28
type_infered: string
name: disassemble_data
arguments: label: D31
type_infered: string
name: disassemble_data
arguments: label: D22
type_infered: string
name: disassemble_data
arguments: label: D0
type_infered: string
name: disassemble_data
arguments: label: D36
type_infered: string

tool: D28: STR$_TRU


tool: D31: STR$_NOELEM


tool: D22: SS$_NORMAL


tool: D0: STR$_INVDELIM


tool: D36: Unknown condition code

assistant: ```c
void anacond(unsigned long condcode) {
  switch (condcode) {
  case 1:
    printf("SS$_NORMAL\n");
    break;
  case 2392592:
    printf("STR$_INVDELIM\n");
    break;
  case 2392600:
    printf("STR$_NOELEM\n");
    break;
  case 2392576:
    printf("STR$_TRU\n");
    break;
  default:
    printf("Unknown condition code");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<anacond>:
  endbr64
  cmp    $0x248210,%rdi
  je     L12
  ja     L13
  cmp    $0x1,%rdi
  je     L31
  cmp    $0x248200,%rdi
  jne    L17
  lea    D27(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  cmp    $0x248218,%rdi
  jne    L17
  lea    D17(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L12:
  lea    D44(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L17:
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L31:
  lea    D30(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D27
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D44
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D30
datatype: string

tool: D27: STR$_TRU


tool: D17: STR$_NOELEM


tool: D44: STR$_INVDELIM


tool: D2: Unknown condition code

tool: D30: SS$_NORMAL


assistant: ```c
void anacond(unsigned long condcode) {
  switch (condcode) {
  case 1:
    printf("SS$_NORMAL\n");
    break;
  case 2392592:
    printf("STR$_INVDELIM\n");
    break;
  case 2392600:
    printf("STR$_NOELEM\n");
    break;
  case 2392576:
    printf("STR$_TRU\n");
    break;
  default:
    printf("Unknown condition code");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<anacond>:
  endbr64
  cmp    $0x248210,%rdi
  je     L32
  ja     L24
  cmp    $0x1,%rdi
  je     L10
  cmp    $0x248200,%rdi
  jne    L1
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L24:
  cmp    $0x248218,%rdi
  jne    L1
  lea    D20(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L32:
  lea    D25(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L1:
  lea    D32(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L10:
  lea    D47(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string
name: disassemble_data
arguments: data_tag: D20
datatype: string
name: disassemble_data
arguments: data_tag: D25
datatype: string
name: disassemble_data
arguments: data_tag: D32
datatype: string
name: disassemble_data
arguments: data_tag: D47
datatype: string

tool: D7: STR$_TRU


tool: D20: STR$_NOELEM


tool: D25: STR$_INVDELIM


tool: D32: Unknown condition code

tool: D47: SS$_NORMAL


assistant: ```c
void anacond(unsigned long condcode) {
  switch (condcode) {
  case 1:
    printf("SS$_NORMAL\n");
    break;
  case 2392592:
    printf("STR$_INVDELIM\n");
    break;
  case 2392600:
    printf("STR$_NOELEM\n");
    break;
  case 2392576:
    printf("STR$_TRU\n");
    break;
  default:
    printf("Unknown condition code");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<i2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%ebx
  mov    $0x0,%r12d
  cmpl   $0x63,-0x1c(%rbp)
  jbe    L8
  mov    %ebx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  shr    $0x5,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    %ebx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  shr    $0x5,%eax
  imul   $0x64,%eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,%ebx
  add    $0x1,%r12d
L8:
  cmpl   $0x9,-0x1c(%rbp)
  jbe    L17
  mov    %ebx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    %ebx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ebx
  mov    %ebx,%edx
  mov    %edx,%ebx
  add    $0x1,%r12d
L17:
  mov    %ebx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  lea    0x1(%r12),%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned int i2a(char *dest, unsigned int x) {
  register unsigned int tmp = x;
  register unsigned int len = 0;
  if (x >= 100) {
    *dest++ = tmp / 100 + '0';
    tmp = tmp % 100;
    ++len;
  }
  if (x >= 10) {
    *dest++ = tmp / 10 + '0';
    tmp = tmp % 10;
    ++len;
  }
  *dest++ = tmp + '0';
  return len + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i2a>:
  endbr64
  mov    %esi,%edx
  cmp    $0x63,%esi
  jbe    L0
  lea    0x1(%rdi),%rsi
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  lea    0x30(%rax),%ecx
  mov    %cl,(%rdi)
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  mov    $0x1,%eax
L10:
  lea    0x1(%rsi),%rdi
  mov    %edx,%ecx
  mov    $0xcccccccd,%r8d
  imul   %r8,%rcx
  shr    $0x23,%rcx
  lea    0x30(%rcx),%r8d
  mov    %r8b,(%rsi)
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x1,%eax
L25:
  add    $0x30,%edx
  mov    %dl,(%rdi)
  add    $0x1,%eax
  ret
L0:
  cmp    $0x9,%esi
  ja     L32
  mov    $0x0,%eax
  jmp    L25
L32:
  mov    %rdi,%rsi
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
unsigned int i2a(char *dest, unsigned int x) {
  register unsigned int tmp = x;
  register unsigned int len = 0;
  if (x >= 100) {
    *dest++ = tmp / 100 + '0';
    tmp = tmp % 100;
    ++len;
  }
  if (x >= 10) {
    *dest++ = tmp / 10 + '0';
    tmp = tmp % 10;
    ++len;
  }
  *dest++ = tmp + '0';
  return len + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<i2a>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%eax
  cmp    $0x63,%esi
  jbe    L16
  mov    %eax,%edx
  lea    0x1(%rdi),%rsi
  mov    $0x3,%r8d
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x25,%rdx
  lea    0x30(%rdx),%edi
  imul   $0x64,%edx,%edx
  mov    %dil,(%rcx)
  sub    %edx,%eax
L19:
  mov    %eax,%edx
  mov    $0xcccccccd,%edi
  lea    0x1(%rsi),%rcx
  imul   %rdi,%rdx
  shr    $0x23,%rdx
  lea    0x30(%rdx),%edi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %dil,(%rsi)
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,(%rcx)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L16:
  cmp    $0x9,%esi
  ja     L8
  add    $0x30,%eax
  mov    $0x1,%r8d
  mov    %al,(%rcx)
  mov    %r8d,%eax
  ret
L8:
  mov    %rdi,%rsi
  mov    $0x2,%r8d
  jmp    L19
```

assistant: ```c
unsigned int i2a(char *dest, unsigned int x) {
  register unsigned int tmp = x;
  register unsigned int len = 0;
  if (x >= 100) {
    *dest++ = tmp / 100 + '0';
    tmp = tmp % 100;
    ++len;
  }
  if (x >= 10) {
    *dest++ = tmp / 10 + '0';
    tmp = tmp % 10;
    ++len;
  }
  *dest++ = tmp + '0';
  return len + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<i2a>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%eax
  cmp    $0x63,%esi
  jbe    L25
  mov    %eax,%edx
  lea    0x1(%rdi),%rsi
  mov    $0x3,%r8d
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x25,%rdx
  lea    0x30(%rdx),%edi
  imul   $0x64,%edx,%edx
  mov    %dil,(%rcx)
  sub    %edx,%eax
L21:
  mov    %eax,%edx
  mov    $0xcccccccd,%edi
  lea    0x1(%rsi),%rcx
  imul   %rdi,%rdx
  shr    $0x23,%rdx
  lea    0x30(%rdx),%edi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %dil,(%rsi)
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,(%rcx)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L25:
  cmp    $0x9,%esi
  ja     L18
  add    $0x30,%eax
  mov    $0x1,%r8d
  mov    %al,(%rcx)
  mov    %r8d,%eax
  ret
L18:
  mov    %rdi,%rsi
  mov    $0x2,%r8d
  jmp    L21
```

assistant: ```c
unsigned int i2a(char *dest, unsigned int x) {
  register unsigned int tmp = x;
  register unsigned int len = 0;
  if (x >= 100) {
    *dest++ = tmp / 100 + '0';
    tmp = tmp % 100;
    ++len;
  }
  if (x >= 10) {
    *dest++ = tmp / 10 + '0';
    tmp = tmp % 10;
    ++len;
  }
  *dest++ = tmp + '0';
  return len + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<to_base_10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movq   $0x1,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L13
L12:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <value_of@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  imul   -0x10(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L13:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x18(%rbp)
  jl     L12
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long int to_base_10(char *number, int base) {
  unsigned long int accumulator = 1, result = 0;
  int i, c;
  for (i = 0; i < strlen(number); i++) {
    c = value_of(number[i]);
    result += (c * accumulator);
    accumulator *= base;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<to_base_10>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  mov    $0x1,%ebp
  movslq %esi,%r14
  jmp    L13
L4:
  movsbl (%r12,%rbx,1),%edi
  call   <value_of@plt>
  cltq
  imul   %rbp,%rax
  add    %rax,%r13
  imul   %r14,%rbp
  add    $0x1,%rbx
L13:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L4
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long int to_base_10(char *number, int base) {
  unsigned long int accumulator = 1, result = 0;
  int i, c;
  for (i = 0; i < strlen(number); i++) {
    c = value_of(number[i]);
    result += (c * accumulator);
    accumulator *= base;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<to_base_10>:
  endbr64
  push   %r14
  movslq %esi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L7
  xchg   %ax,%ax
L8:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <value_of@plt>
  cltq
  imul   %rbp,%rax
  imul   %r14,%rbp
  add    %rax,%r13
L7:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L8
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long int to_base_10(char *number, int base) {
  unsigned long int accumulator = 1, result = 0;
  int i, c;
  for (i = 0; i < strlen(number); i++) {
    c = value_of(number[i]);
    result += (c * accumulator);
    accumulator *= base;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<to_base_10>:
  endbr64
  push   %r14
  movslq %esi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L5
  xchg   %ax,%ax
L6:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <value_of@plt>
  cltq
  imul   %rbp,%rax
  imul   %r14,%rbp
  add    %rax,%r13
L5:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L6
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long int to_base_10(char *number, int base) {
  unsigned long int accumulator = 1, result = 0;
  int i, c;
  for (i = 0; i < strlen(number); i++) {
    c = value_of(number[i]);
    result += (c * accumulator);
    accumulator *= base;
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<crossvecc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    0x1c(%rsp),%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D62(%rip),%rdi
  call   <puts@plt>
  lea    0x24(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x1c(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd 0x24(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd 0x20(%rsp),%xmm1
  lea    D65(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L10
  mov    $0x0,%ebx
L19:
  mov    0x1c(%rsp),%r12d
  mov    0x20(%rsp),%r13d
  pxor   %xmm0,%xmm0
  cvtss2sd 0x24(%rsp),%xmm0
  mulsd  D54(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <sin@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L19
  movd   %r12d,%xmm1
  movd   %r13d,%xmm3
  mulss  %xmm3,%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rsp)
L10:
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  lea    D61(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D46
datatype: string
name: disassemble_data
arguments: data_label: D3
datatype: string
name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D62
datatype: string
name: disassemble_data
arguments: data_label: D65
datatype: string
name: disassemble_data
arguments: data_label: D54
datatype: byte[8]
name: disassemble_data
arguments: data_label: D61
datatype: string

tool: D46: Enter the absolute value of the first vector: 

tool: D3: %f

tool: D21: Enter the absolute value of the second vector: 

tool: D62: Enter the angle, in degrees, between the two vectors: 

tool: D65: The numbers you have input are %.2f, %.2f, and %.2f. 


tool: {"D54": [0x55,0x09,0x8b,0xd9,0xf4,0xdc,0x91,0x3f]}

tool: D61: The cross product of vector A and vector B is %.2f. 


assistant: ```c
void crossvecc(int MAX) {
  float x, a, newvector, rad, deg;
  printf("Enter the absolute value of the first vector: \n");
  scanf("%f", &x);
  printf("Enter the absolute value of the second vector: \n");
  scanf("%f", &a);
  printf("Enter the angle, in degrees, between the two vectors: \n");
  scanf("%f", &deg);
  printf("The numbers you have input are %.2f, %.2f, and %.2f. \n", x, a, deg);
  for (int i = 0; i < MAX; i++) {
    rad = deg * (3.14 / 180.0);
    newvector = x * a * sin(rad);
  }
  printf("The cross product of vector A and vector B is %.2f. \n", newvector);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crossvecc>:
  endbr64
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D3(%rip),%rdi
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x1c(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  lea    0x20(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D65(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  lea    0x24(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  lea    D9(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd 0x1c(%rsp),%xmm0
  cvtss2sd 0x24(%rsp),%xmm2
  cvtss2sd 0x20(%rsp),%xmm1
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L15
  xor    %ebx,%ebx
  nopl   (%rax)
L22:
  pxor   %xmm0,%xmm0
  movss  0x1c(%rsp),%xmm3
  movss  0x20(%rsp),%xmm4
  add    $0x1,%ebx
  cvtss2sd 0x24(%rsp),%xmm0
  mulsd  D39(%rip),%xmm0
  movss  %xmm3,0x8(%rsp)
  movss  %xmm4,0xc(%rsp)
  cvtsd2ss %xmm0,%xmm0
  call   <sin@plt>
  cmp    %ebx,%ebp
  jne    L22
  movss  0x8(%rsp),%xmm1
  mulss  0xc(%rsp),%xmm1
  mulss  %xmm0,%xmm1
  movd   %xmm1,%ebx
L15:
  movd   %ebx,%xmm5
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D20(%rip),%rdi
  cvtss2sd %xmm5,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
data_type: string
name: disassemble_data
arguments: label: D3
data_type: string
name: disassemble_data
arguments: label: D58
data_type: string
name: disassemble_data
arguments: label: D65
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D39
data_type: byte[8]
name: disassemble_data
arguments: label: D20
data_type: string

tool: D15: %f

tool: D3: Enter the absolute value of the first vector: 

tool: D58: Enter the absolute value of the second vector: 

tool: D65: Enter the angle, in degrees, between the two vectors: 

tool: D9: The numbers you have input are %.2f, %.2f, and %.2f. 


tool: {"D39": [0x55,0x09,0x8b,0xd9,0xf4,0xdc,0x91,0x3f]}

tool: D20: The cross product of vector A and vector B is %.2f. 


assistant: ```c
void crossvecc(int MAX) {
  float x, a, newvector, rad, deg;
  printf("Enter the absolute value of the first vector: \n");
  scanf("%f", &x);
  printf("Enter the absolute value of the second vector: \n");
  scanf("%f", &a);
  printf("Enter the angle, in degrees, between the two vectors: \n");
  scanf("%f", &deg);
  printf("The numbers you have input are %.2f, %.2f, and %.2f. \n", x, a, deg);
  for (int i = 0; i < MAX; i++) {
    rad = deg * (3.14 / 180.0);
    newvector = x * a * sin(rad);
  }
  printf("The cross product of vector A and vector B is %.2f. \n", newvector);
}
```