user: Translate the below assembly code into C programming language:

```asm
<process>:
  endbr64
  push   %r13
  mov    %edi,%r8d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1d8,%rsp
  movzbl (%rsi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  test   %dl,%dl
  je     L174
  add    $0x1,%rsi
  xor    %ecx,%ecx
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L183:
  cmp    $0xa,%dl
  je     L27
  cmp    $0xd,%dl
  je     L27
  lea    0x1(%rcx),%r9d
  mov    %eax,%edi
L109:
  cltq
  shl    $0x6,%rax
  add    $0x1d0,%rax
  add    %rsp,%rax
  mov    %dl,-0x1d0(%rcx,%rax,1)
  cmp    $0x7,%edi
  je     L148
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  test   %dl,%dl
  je     L54
  movslq %r9d,%rcx
  mov    %edi,%eax
L22:
  cmp    $0x20,%dl
  jne    L183
  lea    0x1(%rax),%edi
  xor    %edx,%edx
  xor    %r9d,%r9d
  jmp    L109
L174:
  movb   $0x0,(%rsp)
L148:
  mov    %r8d,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L125:
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x1d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  movslq %edi,%rdx
  movslq %r9d,%r9
  lea    0x1(%rdi),%eax
  shl    $0x6,%rdx
  lea    0x1d0(%rdx),%rbx
  lea    (%rsp,%rbx,1),%rdx
  movb   $0x0,-0x1d0(%r9,%rdx,1)
L40:
  cmp    $0x6,%eax
  jle    L148
  xor    %r10d,%r10d
  mov    %rsp,%rbp
  lea    0x1(%rsp),%r13
  mov    $0x40,%r11d
L185:
  lea    0x1(%r10),%r12d
  mov    %rbp,%rbx
  lea    0x0(%r13,%r10,1),%rdi
  mov    %rbp,%r8
  xor    %esi,%esi
  mov    $0x1,%r9d
L81:
  mov    %r11,%rcx
  add    $0x1,%r9
  sub    %rsi,%rcx
  nopl   0x0(%rax)
L113:
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L172:
  lea    (%rax,%rsi,1),%rdx
  movzbl (%rdx,%rcx,1),%edx
  cmp    %dl,(%rax)
  jne    L111
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L172
  add    $0x1,%r10
  cmp    $0x3f,%r10
  jne    L185
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L125
  nopw   0x0(%rax,%rax,1)
L111:
  add    $0x40,%rcx
  cmp    $0x1c0,%rcx
  jne    L113
  add    $0x40,%r8
  sub    $0x40,%rsi
  add    $0x40,%rdi
  cmp    $0x7,%r9
  jne    L81
  mov    %r12d,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  add    $0x1c0,%rbp
  call   <printf@plt>
  lea    D2(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x40,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L35
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L125
L27:
  movslq %eax,%rdx
  add    $0x1,%eax
  shl    $0x6,%rdx
  lea    0x1d0(%rdx),%rbx
  lea    (%rsp,%rbx,1),%rdx
  movb   $0x0,-0x1d0(%rcx,%rdx,1)
  jmp    L40
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type: string
name: read_data
arguments: data_label: D20
type: string
name: read_data
arguments: data_label: D18
type: string
name: read_data
arguments: data_label: D2
type: string

tool: D5: There aren't 7 days in line %d


tool: D20: Failed to find uniqueness within the bounds.

tool: D18: %2d 

tool: D2:  %s

assistant: ```c
void process(int lineNum, char buffer[]) {
  char days[7][64];
  int i = 0, d = 0, j = 0;
  while (buffer[i] != 0) {
    if (buffer[i] == ' ') {
      days[d][j] = '\0';
      ++d;
      j = 0;
    } else if (buffer[i] == '\n' || buffer[i] == '\r') {
      days[d][j] = '\0';
      ++d;
      break;
    } else {
      days[d][j] = buffer[i];
      ++j;
    }
    if (d >= 7) {
      printf("There aren't 7 days in line %d\n", lineNum);
      return;
    }
    ++i;
  }
  if (buffer[i] == '\0') {
    days[d][j] = '\0';
    ++d;
  }
  if (d < 7) {
    printf("There aren't 7 days in line %d\n", lineNum);
    return;
  } else {
    int len = 0;
    for (len = 1; len < 64; ++len) {
      int d1;
      for (d1 = 0; d1 < 7; ++d1) {
        int d2;
        for (d2 = d1 + 1; d2 < 7; ++d2) {
          int unique = 0;
          for (i = 0; i < len; ++i) {
            if (days[d1][i] != days[d2][i]) {
              unique = 1;
              break;
            }
          }
          if (!unique) {
            goto next_length;
          }
        }
      }
      printf("%2d ", len);
      for (i = 0; i < 7; ++i) {
        printf(" %s", days[i]);
      }
      printf("\n");
      return;
    next_length : {}
    }
  }
  printf("Failed to find uniqueness within the bounds.");
}
```