ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L91
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L70:
  movslq %ebx,%rbp
  lea    0x10(%rsp,%rbp,4),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp,%rbp,4),%eax
  and    $0x1,%eax
  add    %eax,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L70
L91:
  mov    0xc(%rsp),%ecx
  cmp    $0x1,%ecx
  jle    L31
  mov    $0x0,%ebx
  lea    D16(%rip),%rbp
  jmp    L81
L83:
  mov    0xc(%rsp),%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  mov    %edx,%eax
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jle    L50
L81:
  mov    %ecx,%eax
  sub    %ebx,%eax
  cmp    %ebx,%eax
  je     L83
  sub    $0x1,%ecx
  sub    %ebx,%ecx
  movslq %ecx,%rcx
  mov    0x10(%rsp,%rbx,4),%esi
  sub    0x10(%rsp,%rcx,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L83
L31:
  mov    $0x2,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
L50:
  test   $0x1,%cl
  jne    L63
L17:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  mov    $0x0,%eax
  add    $0xfc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L63:
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string

tool: D4: %d

tool: D16: %d


assistant: ```c
int main() {
  int n, ar[1000];
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &ar[i]);
    if (ar[i] % 2 == 0) {
      i--;
    }
  }
  for (int i = 0; i < n / 2; i++) {
    if (i != n - i) {
      printf("%d\n", ar[i] - ar[(n - 1) - i]);
    }
  }
  if (n % 2 != 0) {
    printf("%d\n", ar[n / 2]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L80
  xor    %ebp,%ebp
  lea    0x10(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L60:
  movslq %ebp,%r13
  mov    %r12,%rdi
  lea    (%rbx,%r13,4),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp,%r13,4),%eax
  mov    0xc(%rsp),%edx
  and    $0x1,%eax
  mov    %edx,%ecx
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebp
  cmp    %ebp,%edx
  jg     L60
  cmp    $0x1,%edx
  jle    L80
  xor    %r12d,%r12d
  lea    D1(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %edx,%eax
  sub    %r12d,%eax
  cmp    %r12d,%eax
  je     L55
  sub    $0x1,%edx
  mov    (%rbx,%r12,4),%esi
  mov    %rbp,%rdi
  sub    %r12d,%edx
  movslq %edx,%rdx
  sub    0x10(%rsp,%rdx,4),%esi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
L55:
  mov    %edx,%eax
  add    $0x1,%r12
  mov    %edx,%ecx
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jg     L43
L41:
  and    $0x1,%ecx
  jne    L3
L22:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0xfc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  cltq
  lea    D1(%rip),%rdi
  mov    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  jmp    L22
L80:
  mov    %ecx,%eax
  mov    $0x2,%esi
  cltd
  idiv   %esi
  jmp    L41
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D16: %d

tool: D1: %d


assistant: ```c
int main() {
  int n, ar[1000];
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &ar[i]);
    if (ar[i] % 2 == 0) {
      i--;
    }
  }
  for (int i = 0; i < n / 2; i++) {
    if (i != n - i) {
      printf("%d\n", ar[i] - ar[(n - 1) - i]);
    }
  }
  if (n % 2 != 0) {
    printf("%d\n", ar[n / 2]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L84
  xor    %ebp,%ebp
  lea    0x10(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L2:
  movslq %ebp,%r13
  mov    %r12,%rdi
  lea    (%rbx,%r13,4),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp,%r13,4),%eax
  mov    0xc(%rsp),%ecx
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebp
  cmp    %ebp,%ecx
  jg     L2
  cmp    $0x1,%ecx
  jle    L84
  xor    %r12d,%r12d
  lea    D3(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ecx,%eax
  sub    %r12d,%eax
  cmp    %r12d,%eax
  je     L27
  sub    $0x1,%ecx
  mov    (%rbx,%r12,4),%esi
  mov    %rbp,%rdi
  sub    %r12d,%ecx
  movslq %ecx,%rcx
  sub    0x10(%rsp,%rcx,4),%esi
  call   <printf@plt>
  mov    0xc(%rsp),%ecx
L27:
  mov    %ecx,%eax
  add    $0x1,%r12
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jg     L12
L9:
  and    $0x1,%ecx
  jne    L6
L10:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0xfc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  cltq
  lea    D3(%rip),%rdi
  mov    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  jmp    L10
L84:
  mov    %ecx,%eax
  mov    $0x2,%esi
  cltd
  idiv   %esi
  jmp    L9
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D11: %d

tool: D3: %d


assistant: ```c
int main() {
  int n, ar[1000];
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &ar[i]);
    if (ar[i] % 2 == 0) {
      i--;
    }
  }
  for (int i = 0; i < n / 2; i++) {
    if (i != n - i) {
      printf("%d\n", ar[i] - ar[(n - 1) - i]);
    }
  }
  if (n % 2 != 0) {
    printf("%d\n", ar[n / 2]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D79(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jle    L80
  cmp    0x14(%rsp),%esi
  jg     L209
L32:
  mov    0x14(%rsp),%edx
  cmp    %esi,%edx
  jle    L197
  cmp    %eax,%edx
  jl     L167
L197:
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  jle    L63
  cmp    0x10(%rsp),%esi
  jg     L176
L203:
  mov    0x10(%rsp),%edx
  cmp    %esi,%edx
  jle    L63
  cmp    %eax,%edx
  jl     L193
L63:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L209:
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jg     L32
  jmp    L80
L167:
  mov    %edx,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L80:
  mov    0x10(%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  jle    L197
  cmp    0x14(%rsp),%esi
  jg     L154
L10:
  mov    0x14(%rsp),%edx
  cmp    %esi,%edx
  jle    L197
  cmp    %eax,%edx
  jge    L197
  mov    %edx,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L197
L154:
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  jg     L10
  jmp    L197
L176:
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  jg     L203
  jmp    L63
L193:
  mov    %edx,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L63
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D79
type: string
name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D9
type: string

tool: D79: Please enter 3 numbers separated by spaces > 

tool: D7: %d%d%d

tool: D9: %d is the median


assistant: ```c
int main() {
  int a, b, c;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if ((a > b) && (b > c))
    printf("%d is the median\n", b);
  if ((a > b) && (a > c)) {
    if (c > b) {
      printf("%d is the median\n", c);
    }
  }
  if ((b > a) && (a > c))
    printf("%d is the median\n", a);
  if ((b > a) && (b > c)) {
    if (c > a) {
      printf("%d is the median\n", c);
    }
  }
  if ((c > a) && (a > b))
    printf("%d is the median\n", a);
  if ((c > a) && (c > b)) {
    if (b > a) {
      printf("%d is the median\n", b);
    }
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D73(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D52(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r9d
  cmp    %r9d,%esi
  jle    L131
  cmp    0x14(%rsp),%r9d
  jg     L141
L133:
  mov    0x14(%rsp),%r8d
  cmp    %esi,%r8d
  jge    L5
  cmp    %r9d,%r8d
  jg     L109
L5:
  cmp    %esi,%r8d
  jle    L150
  cmp    0x10(%rsp),%esi
  jg     L196
L92:
  mov    0x10(%rsp),%r9d
  cmp    %r8d,%r9d
  jge    L150
  cmp    %esi,%r9d
  jg     L178
L150:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L109:
  mov    %r8d,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r9d
L131:
  mov    0x14(%rsp),%r8d
  cmp    %esi,%r9d
  jle    L5
  cmp    %r8d,%esi
  jg     L175
L74:
  cmp    %r9d,%r8d
  jge    L5
  cmp    %esi,%r8d
  jle    L5
  mov    %r8d,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    0x14(%rsp),%r8d
  jmp    L5
L196:
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%r8d
  mov    0xc(%rsp),%esi
  cmp    %esi,%r8d
  jg     L92
  jmp    L150
L175:
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%r9d
  mov    0xc(%rsp),%esi
  mov    0x14(%rsp),%r8d
  cmp    %esi,%r9d
  jg     L74
  jmp    L5
L141:
  mov    %r9d,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r9d
  cmp    %r9d,%esi
  jg     L133
  jmp    L131
L178:
  mov    %r9d,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L150
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D73
datatype: string
name: unpack_data
arguments: label: D52
datatype: string
name: unpack_data
arguments: label: D40
datatype: string

tool: D73: Please enter 3 numbers separated by spaces > 

tool: D52: %d%d%d

tool: D40: %d is the median


assistant: ```c
int main() {
  int a, b, c;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if ((a > b) && (b > c))
    printf("%d is the median\n", b);
  if ((a > b) && (a > c)) {
    if (c > b) {
      printf("%d is the median\n", c);
    }
  }
  if ((b > a) && (a > c))
    printf("%d is the median\n", a);
  if ((b > a) && (b > c)) {
    if (c > a) {
      printf("%d is the median\n", c);
    }
  }
  if ((c > a) && (a > b))
    printf("%d is the median\n", a);
  if ((c > a) && (c > b)) {
    if (b > a) {
      printf("%d is the median\n", b);
    }
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r9d
  cmp    %r9d,%esi
  jle    L65
  cmp    0x14(%rsp),%r9d
  jg     L194
L207:
  mov    0x14(%rsp),%r8d
  cmp    %esi,%r8d
  jge    L146
  cmp    %r9d,%r8d
  jg     L9
L146:
  cmp    %esi,%r8d
  jle    L80
  cmp    0x10(%rsp),%esi
  jg     L193
L39:
  mov    0x10(%rsp),%r9d
  cmp    %r8d,%r9d
  jge    L80
  cmp    %esi,%r9d
  jg     L58
L80:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L191
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  mov    %r8d,%esi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r9d
L65:
  mov    0x14(%rsp),%r8d
  cmp    %esi,%r9d
  jle    L146
  cmp    %r8d,%esi
  jg     L112
L165:
  cmp    %r9d,%r8d
  jge    L146
  cmp    %esi,%r8d
  jle    L146
  mov    %r8d,%esi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    0x14(%rsp),%r8d
  jmp    L146
L193:
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%r8d
  mov    0xc(%rsp),%esi
  cmp    %esi,%r8d
  jg     L39
  jmp    L80
L112:
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%r9d
  mov    0xc(%rsp),%esi
  mov    0x14(%rsp),%r8d
  cmp    %esi,%r9d
  jg     L165
  jmp    L146
L194:
  mov    %r9d,%esi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r9d
  cmp    %r9d,%esi
  jg     L207
  jmp    L65
L58:
  mov    %r9d,%esi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L80
L191:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D31
type_infered: string
name: parse_data
arguments: label: D24
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string

tool: D31: Please enter 3 numbers separated by spaces > 

tool: D24: %d%d%d

tool: D34: %d is the median


assistant: ```c
int main() {
  int a, b, c;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if ((a > b) && (b > c))
    printf("%d is the median\n", b);
  if ((a > b) && (a > c)) {
    if (c > b) {
      printf("%d is the median\n", c);
    }
  }
  if ((b > a) && (a > c))
    printf("%d is the median\n", a);
  if ((b > a) && (b > c)) {
    if (c > a) {
      printf("%d is the median\n", c);
    }
  }
  if ((c > a) && (a > b))
    printf("%d is the median\n", a);
  if ((c > a) && (c > b)) {
    if (b > a) {
      printf("%d is the median\n", b);
    }
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stoken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L74
L41:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L74:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L51
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L41
L51:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L57
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L57
L25:
  addl   $0x1,-0x8(%rbp)
L57:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jae    L98
  mov    -0x8(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L25
  jmp    L98
L15:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L98:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jae    L0
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L15
L0:
  mov    -0x8(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
const char *stoken(char *c, int *p, char *s, const char *sep, const char *ignore) {
  unsigned begin;
  unsigned end;
  begin = *p;
  while (s[*p] && strchr(sep, s[*p]) == 0)
    ++*p;
  end = *p;
  *c = s[*p];
  if (s[*p]) {
    s[*p] = 0;
    ++*p;
  }
  while (begin < end && strchr(ignore, s[begin]) != 0) {
    ++begin;
  }
  while (begin < end && strchr(ignore, s[end - 1]) != 0) {
    --end;
    s[end] = 0;
  }
  return s + begin;
}
```
user: What is the c source code of the assembly code below:

```asm
<stoken>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %r8,%r12
  mov    (%rsi),%ebx
  movslq %ebx,%rax
  movzbl (%rdx,%rax,1),%esi
  test   %sil,%sil
  je     L106
L60:
  movsbl %sil,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L6
  mov    0x0(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,0x0(%rbp)
  cltq
  movzbl 0x0(%r13,%rax,1),%esi
  test   %sil,%sil
  jne    L60
L6:
  mov    0x0(%rbp),%r14d
  movslq %r14d,%rax
  movzbl 0x0(%r13,%rax,1),%eax
  mov    %al,(%r15)
  movslq 0x0(%rbp),%rax
  add    %r13,%rax
  cmpb   $0x0,(%rax)
  je     L109
L116:
  movb   $0x0,(%rax)
  addl   $0x1,0x0(%rbp)
L109:
  mov    %ebx,%ebp
  add    %r13,%rbp
  cmp    %r14d,%ebx
  jae    L96
L16:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L75
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r14d,%ebx
  jb     L16
  jmp    L96
L75:
  cmp    %r14d,%ebx
  jae    L96
  sub    $0x1,%r14d
  mov    %r14d,%eax
  lea    0x0(%r13,%rax,1),%rbp
  lea    -0x1(%r13,%rax,1),%r15
  sub    %ebx,%r14d
  sub    %r14,%r15
L31:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L96
  movb   $0x0,0x0(%rbp)
  sub    $0x1,%rbp
  cmp    %r15,%rbp
  jne    L31
L96:
  mov    %ebx,%ebx
  lea    0x0(%r13,%rbx,1),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L106:
  mov    0x0(%rbp),%r14d
  movslq %r14d,%rax
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdi)
  movslq 0x0(%rbp),%rax
  add    %rdx,%rax
  cmpb   $0x0,(%rax)
  jne    L116
  jmp    L96
```

assistant: ```c
const char *stoken(char *c, int *p, char *s, const char *sep, const char *ignore) {
  unsigned begin;
  unsigned end;
  begin = *p;
  while (s[*p] && strchr(sep, s[*p]) == 0)
    ++*p;
  end = *p;
  *c = s[*p];
  if (s[*p]) {
    s[*p] = 0;
    ++*p;
  }
  while (begin < end && strchr(ignore, s[begin]) != 0) {
    ++begin;
  }
  while (begin < end && strchr(ignore, s[end - 1]) != 0) {
    --end;
    s[end] = 0;
  }
  return s + begin;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stoken>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  movslq (%rsi),%rax
  mov    %rdi,0x8(%rsp)
  movsbl (%rdx,%rax,1),%esi
  mov    %eax,%r12d
  mov    %rax,%rbp
  add    %rdx,%r12
  test   %sil,%sil
  jne    L0
  jmp    L96
  nopl   (%rax)
L112:
  mov    (%r15),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  mov    %eax,(%r15)
  movsbl (%r14,%rdx,1),%esi
  test   %sil,%sil
  je     L158
L0:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L112
  movslq (%r15),%rdx
  movzbl (%r14,%rdx,1),%esi
  mov    %rdx,%rax
L158:
  mov    %eax,%ebx
  mov    0x8(%rsp),%rax
  mov    %sil,(%rax)
  movslq (%r15),%rax
  add    %r14,%rax
  cmpb   $0x0,(%rax)
  jne    L20
L122:
  mov    %r12,%rax
  cmp    %ebx,%ebp
  jb     L79
  jmp    L16
L45:
  add    $0x1,%ebp
  lea    0x1(%r12),%rax
  cmp    %ebx,%ebp
  jae    L145
L79:
  movsbl (%rax),%esi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strchr@plt>
  test   %rax,%rax
  jne    L45
  cmp    %ebx,%ebp
  jae    L16
  lea    -0x1(%rbx),%eax
  mov    %rax,%rbx
  lea    (%r14,%rax,1),%r15
  lea    -0x1(%r14,%rax,1),%rax
  sub    %ebp,%ebx
  sub    %rbx,%rax
  mov    %rax,%rbp
  jmp    L56
L39:
  movb   $0x0,(%r15)
  sub    $0x1,%r15
  cmp    %rbp,%r15
  je     L16
L56:
  movsbl (%r15),%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L39
L16:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L96:
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  movslq (%r15),%rax
  add    %rdx,%rax
  cmpb   $0x0,(%rax)
  je     L16
  mov    %ebp,%ebx
  nopl   (%rax)
L20:
  movb   $0x0,(%rax)
  addl   $0x1,(%r15)
  jmp    L122
  nopl   0x0(%rax)
L145:
  mov    %ebp,%r12d
  add    %r14,%r12
  jmp    L16
```

assistant: ```c
const char *stoken(char *c, int *p, char *s, const char *sep, const char *ignore) {
  unsigned begin;
  unsigned end;
  begin = *p;
  while (s[*p] && strchr(sep, s[*p]) == 0)
    ++*p;
  end = *p;
  *c = s[*p];
  if (s[*p]) {
    s[*p] = 0;
    ++*p;
  }
  while (begin < end && strchr(ignore, s[begin]) != 0) {
    ++begin;
  }
  while (begin < end && strchr(ignore, s[end - 1]) != 0) {
    --end;
    s[end] = 0;
  }
  return s + begin;
}
```