ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<print_system_status>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  lea    D32(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebp,%edi
  call   <WIFEXITED@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L7
  call   <WEXITSTATUS@plt>
  add    $0x8,%rsp
  lea    D42(%rip),%rdi
  mov    %eax,%esi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    10a0 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  call   <WIFSIGNALED@plt>
  test   %rax,%rax
  jne    L14
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %ebp,%edi
  lea    D9(%rip),%r12
  call   <WCOREDUMP@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  lea    D44(%rip),%rax
  cmove  %rax,%r12
  call   <WTERMSIG@plt>
  add    $0x8,%rsp
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  mov    %r12,%rdx
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    10a0 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D32
type: string
name: parse_data
arguments: label: D42
type: string
name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D44
type: string
name: parse_data
arguments: label: D12
type: string

tool: D32: status = %d


tool: D42: normal termination,exit status = %d


tool: D9: core file generated

tool: 

tool: D12: abnormal termination,signal number =%d%s


assistant: ```c
void print_system_status(int status) {
  printf("status = %d\n", status);
  if (WIFEXITED(status)) {
    printf("normal termination,exit status = %d\n", WEXITSTATUS(status));
  } else if (WIFSIGNALED(status)) {
    printf("abnormal termination,signal number =%d%s\n", WTERMSIG(status), WCOREDUMP(status) ? "core file generated" : "");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<log_pid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  jmp    L5
L1:
  nop
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D6: w

tool: D8: %d


assistant: ```c
void log_pid(const char *pidfile) {
  FILE *f;
  pid_t pid;
  pid = getpid();
  if ((f = fopen(pidfile, "w")) == NULL)
    return;
  fprintf(f, "%d\n", pid);
  fclose(f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log_pid>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ebp
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rbx
  mov    %ebp,%edx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string

tool: D15: w

tool: D13: %d


assistant: ```c
void log_pid(const char *pidfile) {
  FILE *f;
  pid_t pid;
  pid = getpid();
  if ((f = fopen(pidfile, "w")) == NULL)
    return;
  fprintf(f, "%d\n", pid);
  fclose(f);
}
```
user: Translate the below assembly code into C programming language:

```asm
<log_pid>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getpid@plt>
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fopen@plt>
  test   %rax,%rax
  je     L0
  mov    %r12d,%edx
  mov    %rax,%rdi
  lea    D14(%rip),%rsi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <fclose@plt>
L0:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string
name: extract_symbolic_data
arguments: tag: D14
type: string

tool: D9: w

tool: D14: %d


assistant: ```c
void log_pid(const char *pidfile) {
  FILE *f;
  pid_t pid;
  pid = getpid();
  if ((f = fopen(pidfile, "w")) == NULL)
    return;
  fprintf(f, "%d\n", pid);
  fclose(f);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_pid>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getpid@plt>
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fopen@plt>
  test   %rax,%rax
  je     L3
  mov    %r12d,%edx
  mov    %rax,%rdi
  lea    D5(%rip),%rsi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <fclose@plt>
L3:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D5
type_guessed: string

tool: D17: w

tool: D5: %d


assistant: ```c
void log_pid(const char *pidfile) {
  FILE *f;
  pid_t pid;
  pid = getpid();
  if ((f = fopen(pidfile, "w")) == NULL)
    return;
  fprintf(f, "%d\n", pid);
  fclose(f);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<concat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <intlen@plt>
  mov    %eax,%edi
  call   <pow10_g@plt>
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
uint32_t concat(uint32_t a, uint32_t b) {
  a *= pow10_g(intlen(b));
  return a + b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <intlen@plt>
  mov    %eax,%edi
  call   <pow10_g@plt>
  imul   %rbp,%rax
  add    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t concat(uint32_t a, uint32_t b) {
  a *= pow10_g(intlen(b));
  return a + b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <intlen@plt>
  mov    %eax,%edi
  call   <pow10_g@plt>
  add    $0x8,%rsp
  imul   %rbp,%rax
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t concat(uint32_t a, uint32_t b) {
  a *= pow10_g(intlen(b));
  return a + b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<concat>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <intlen@plt>
  mov    %eax,%edi
  call   <pow10_g@plt>
  add    $0x8,%rsp
  imul   %rbp,%rax
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t concat(uint32_t a, uint32_t b) {
  a *= pow10_g(intlen(b));
  return a + b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dump_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x5b,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L5
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D18
type_guessed: string
name: read_data
arguments: label: D4
type_guessed: string

tool: D18: %ld 

tool: D4: ]

assistant: ```c
void dump_array(long *p, size_t n) {
  printf("[");
  for (int i = 0; i < n; ++i)
    printf("%ld ", p[i]);
  printf("\b]\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_array>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x5b,%edi
  call   <putchar@plt>
  test   %rbp,%rbp
  je     L8
  mov    $0x0,%ebx
  lea    D4(%rip),%r13
L3:
  mov    (%r12,%rbx,8),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L3
L8:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D2
type: string

tool: D4: %ld 

tool: D2: ]

assistant: ```c
void dump_array(long *p, size_t n) {
  printf("[");
  for (int i = 0; i < n; ++i)
    printf("%ld ", p[i]);
  printf("\b]\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dump_array>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x5b,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %rbp,%rbp
  je     L12
  xor    %ebx,%ebx
  lea    D19(%rip),%r13
  nopl   0x0(%rax)
L10:
  mov    (%r12,%rbx,8),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L10
L12:
  add    $0x8,%rsp
  lea    D17(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <puts@plt>
```

tool_calls: name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D17
datatype: string

tool: D19: %ld 

tool: D17: ]

assistant: ```c
void dump_array(long *p, size_t n) {
  printf("[");
  for (int i = 0; i < n; ++i)
    printf("%ld ", p[i]);
  printf("\b]\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_array>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x5b,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %rbp,%rbp
  je     L10
  xor    %ebx,%ebx
  lea    D15(%rip),%r13
  nopl   0x0(%rax)
L14:
  mov    (%r12,%rbx,8),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L14
L10:
  add    $0x8,%rsp
  lea    D13(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type: string
name: parse_data
arguments: tag: D13
type: string

tool: D15: %ld 

tool: D13: ]

assistant: ```c
void dump_array(long *p, size_t n) {
  printf("[");
  for (int i = 0; i < n; ++i)
    printf("%ld ", p[i]);
  printf("\b]\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbp
  mov    $0x0,%r13d
  lea    D11(%rip),%r12
L41:
  lea    -0x10(%rbp),%rbx
L22:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L22
  add    $0x4,%r13
  add    $0x10,%rbp
  cmp    $0xc,%r13
  jne    L41
  lea    0x40(%rsp),%rbp
  mov    $0x0,%r13d
  lea    D11(%rip),%r12
L35:
  lea    -0x10(%rbp),%rbx
L71:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <flushall@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L71
  add    $0x4,%r13
  add    $0x10,%rbp
  cmp    $0xc,%r13
  jne    L35
  mov    $0x10,%ecx
  lea    0x30(%rsp),%rsi
L60:
  lea    -0x10(%rcx),%rax
L36:
  mov    (%rsp,%rax,1),%edx
  imul   (%rax,%rsi,1),%edx
  mov    %edx,0x60(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L36
  add    $0x10,%rcx
  cmp    $0x40,%rcx
  jne    L60
  lea    0x70(%rsp),%rbp
  lea    0xa0(%rsp),%r13
  lea    D3(%rip),%r12
L6:
  lea    -0x10(%rbp),%rbx
L25:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L25
  add    $0x10,%rbp
  cmp    %r13,%rbp
  jne    L6
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D0: Please enter 24 values into the following array


tool: D11: %d

tool: D3: %d, 

assistant: ```c
main() {
  int matrix1[3][4];
  int matrix2[3][4];
  int matrix3[3][4];
  int i;
  int j;
  printf("Please enter 24 values into the following array\n\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrix1[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrix2[i][j]);
      flushall();
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      matrix3[i][j] = (matrix1[i][j] * matrix2[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      printf("%d, ", matrix3[i][j]);
    }
  }
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D27(%rip),%rdi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
L45:
  lea    -0x10(%r12),%rbx
L36:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L36
  add    $0x4,%r13
  lea    0x10(%rbx),%r12
  cmp    $0xc,%r13
  jne    L45
  lea    0x40(%rsp),%r12
  xor    %r13d,%r13d
L15:
  lea    -0x10(%r12),%rbx
L61:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  xor    %eax,%eax
  call   <flushall@plt>
  cmp    %r12,%rbx
  jne    L61
  add    $0x4,%r13
  lea    0x10(%rbx),%r12
  cmp    $0xc,%r13
  jne    L15
  mov    $0x10,%ecx
  lea    0x60(%rsp),%r8
  mov    %rsp,%rdi
  lea    0x30(%rsp),%rsi
L47:
  lea    -0x10(%rcx),%rax
L51:
  mov    (%rdi,%rax,1),%edx
  imul   (%rsi,%rax,1),%edx
  mov    %edx,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L51
  lea    0x10(%rax),%rcx
  cmp    $0x30,%rax
  jne    L47
  lea    0x70(%rsp),%rbp
  lea    0xa0(%rsp),%r13
  lea    D26(%rip),%r12
L13:
  lea    -0x10(%rbp),%rbx
L40:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L40
  lea    0x10(%rbx),%rbp
  cmp    %r13,%rbp
  jne    L13
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D27
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string

tool: D27: Please enter 24 values into the following array


tool: D8: %d

tool: D26: %d, 

assistant: ```c
main() {
  int matrix1[3][4];
  int matrix2[3][4];
  int matrix3[3][4];
  int i;
  int j;
  printf("Please enter 24 values into the following array\n\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrix1[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrix2[i][j]);
      flushall();
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      matrix3[i][j] = (matrix1[i][j] * matrix2[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      printf("%d, ", matrix3[i][j]);
    }
  }
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%rdi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
L38:
  lea    -0x10(%r12),%rbx
L33:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L33
  add    $0x4,%r13
  lea    0x10(%rbx),%r12
  cmp    $0xc,%r13
  jne    L38
  lea    0x40(%rsp),%r12
  xor    %r13d,%r13d
L62:
  lea    -0x10(%r12),%rbx
L15:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  xor    %eax,%eax
  call   <flushall@plt>
  cmp    %rbx,%r12
  jne    L15
  add    $0x4,%r13
  add    $0x10,%r12
  cmp    $0xc,%r13
  jne    L62
  movdqa (%rsp),%xmm1
  movdqa 0x30(%rsp),%xmm2
  lea    0x70(%rsp),%rbp
  lea    0xa0(%rsp),%r13
  movdqa (%rsp),%xmm0
  pmuludq 0x30(%rsp),%xmm0
  pshufd $0x8,%xmm0,%xmm0
  lea    D0(%rip),%r12
  psrlq  $0x20,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm2,%xmm1
  movdqa 0x10(%rsp),%xmm2
  psrlq  $0x20,%xmm2
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  movdqa 0x40(%rsp),%xmm1
  movaps %xmm0,0x60(%rsp)
  movdqa 0x40(%rsp),%xmm0
  pmuludq 0x10(%rsp),%xmm0
  pshufd $0x8,%xmm0,%xmm0
  psrlq  $0x20,%xmm1
  pmuludq %xmm2,%xmm1
  movdqa 0x20(%rsp),%xmm2
  psrlq  $0x20,%xmm2
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  movdqa 0x50(%rsp),%xmm1
  movaps %xmm0,0x70(%rsp)
  movdqa 0x50(%rsp),%xmm0
  pmuludq 0x20(%rsp),%xmm0
  pshufd $0x8,%xmm0,%xmm0
  psrlq  $0x20,%xmm1
  pmuludq %xmm2,%xmm1
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  movaps %xmm0,0x80(%rsp)
L47:
  lea    -0x10(%rbp),%rbx
L45:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L45
  lea    0x10(%rbx),%rbp
  cmp    %rbp,%r13
  jne    L47
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D0
datatype: string

tool: D11: Please enter 24 values into the following array


tool: D10: %d

tool: D0: %d, 

assistant: ```c
main() {
  int matrix1[3][4];
  int matrix2[3][4];
  int matrix3[3][4];
  int i;
  int j;
  printf("Please enter 24 values into the following array\n\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrix1[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrix2[i][j]);
      flushall();
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      matrix3[i][j] = (matrix1[i][j] * matrix2[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      printf("%d, ", matrix3[i][j]);
    }
  }
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<inputYOrN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L1
  lea    D12(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L1:
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  nop
L11:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <inputYesOrNo@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D12: Do you want to login(Y) or exit(N)?

tool: D2: Enter 'Y' to continue (Y/N):

assistant: ```c
int inputYOrN(int template) {
  char *customMessage;
  switch (template) {
  case 1:
    customMessage = "Do you want to login(Y) or exit(N)?";
    break;
  default:
    customMessage = "Enter 'Y' to continue (Y/N):";
    break;
  }
  return inputYesOrNo(customMessage);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<inputYOrN>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  lea    D7(%rip),%rdi
  lea    D9(%rip),%rax
  cmovne %rax,%rdi
  call   <inputYesOrNo@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string

tool: D7: Do you want to login(Y) or exit(N)?

tool: D9: Enter 'Y' to continue (Y/N):

assistant: ```c
int inputYOrN(int template) {
  char *customMessage;
  switch (template) {
  case 1:
    customMessage = "Do you want to login(Y) or exit(N)?";
    break;
  default:
    customMessage = "Enter 'Y' to continue (Y/N):";
    break;
  }
  return inputYesOrNo(customMessage);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inputYOrN>:
  endbr64
  cmp    $0x1,%edi
  lea    D15(%rip),%rax
  lea    D1(%rip),%rdi
  cmovne %rax,%rdi
  jmp    1050 <inputYesOrNo@plt>
```

tool_calls: name: read_data
arguments: label: D15
data_type: string
name: read_data
arguments: label: D1
data_type: string

tool: D15: Enter 'Y' to continue (Y/N):

tool: D1: Do you want to login(Y) or exit(N)?

assistant: ```c
int inputYOrN(int template) {
  char *customMessage;
  switch (template) {
  case 1:
    customMessage = "Do you want to login(Y) or exit(N)?";
    break;
  default:
    customMessage = "Enter 'Y' to continue (Y/N):";
    break;
  }
  return inputYesOrNo(customMessage);
}
```
user: What is the c source code of the assembly code below:

```asm
<inputYOrN>:
  endbr64
  cmp    $0x1,%edi
  lea    D2(%rip),%rax
  lea    D16(%rip),%rdi
  cmovne %rax,%rdi
  jmp    1050 <inputYesOrNo@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string

tool: D2: Enter 'Y' to continue (Y/N):

tool: D16: Do you want to login(Y) or exit(N)?

assistant: ```c
int inputYOrN(int template) {
  char *customMessage;
  switch (template) {
  case 1:
    customMessage = "Do you want to login(Y) or exit(N)?";
    break;
  default:
    customMessage = "Enter 'Y' to continue (Y/N):";
    break;
  }
  return inputYesOrNo(customMessage);
}
```