ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_cut_end>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jae    L6
  sub    %rbx,%rax
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  mov    %rax,%rsi
  pop    %rbp
  jmp    1070 <strndup@plt>
  nopl   0x0(%rax)
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *string_cut_end(const char *str, const char *end) {
  const size_t end_len = strlen(end);
  const size_t str_len = strlen(str);
  if (end_len >= str_len) {
    return NULL;
  }
  return strndup(str, str_len - end_len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_cut_end>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jae    L1
  sub    %rbx,%rax
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  mov    %rax,%rsi
  pop    %rbp
  jmp    1070 <strndup@plt>
  nopl   0x0(%rax)
L1:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *string_cut_end(const char *str, const char *end) {
  const size_t end_len = strlen(end);
  const size_t str_len = strlen(str);
  if (end_len >= str_len) {
    return NULL;
  }
  return strndup(str, str_len - end_len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<binary_search_rec_helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L55
  mov    $0xffffffff,%eax
  jmp    L37
L55:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L22
  mov    -0x4(%rbp),%eax
  jmp    L37
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L4
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binary_search_rec_helper>
  jmp    L37
L4:
  mov    -0x24(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binary_search_rec_helper>
L37:
  leave
  ret
```

assistant: ```c
int binary_search_rec_helper(int *arr, int low, int high, int value) {
  if (low == high) {
    return -1;
  } else {
    int mid = (low + high) / 2;
    if (value == arr[mid]) {
      return mid;
    } else if (arr[mid] < value) {
      return binary_search_rec_helper(arr, mid + 1, high, value);
    } else {
      return binary_search_rec_helper(arr, low, mid, value);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binary_search_rec_helper>:
  endbr64
  cmp    %edx,%esi
  je     L4
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    %edx,%edi
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %edx,%eax
  movslq %edx,%r9
  mov    (%r8,%r9,4),%r9d
  cmp    %ecx,%r9d
  je     L37
  jge    L39
  lea    0x1(%rdx),%esi
  mov    %edi,%edx
  mov    %r8,%rdi
  call   <binary_search_rec_helper>
L37:
  add    $0x8,%rsp
  ret
L39:
  mov    %r8,%rdi
  call   <binary_search_rec_helper>
  jmp    L37
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int binary_search_rec_helper(int *arr, int low, int high, int value) {
  if (low == high) {
    return -1;
  } else {
    int mid = (low + high) / 2;
    if (value == arr[mid]) {
      return mid;
    } else if (arr[mid] < value) {
      return binary_search_rec_helper(arr, mid + 1, high, value);
    } else {
      return binary_search_rec_helper(arr, low, mid, value);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<binary_search_rec_helper>:
  endbr64
  mov    %rdi,%r8
  jmp    L3
  nopl   0x0(%rax)
L44:
  lea    (%rdx,%rsi,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %ecx,(%r8,%rdi,4)
  je     L46
  jl     L32
  mov    %eax,%edx
L3:
  cmp    %esi,%edx
  jne    L44
  mov    $0xffffffff,%r9d
L46:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  lea    0x1(%rax),%esi
  jmp    L3
```

assistant: ```c
int binary_search_rec_helper(int *arr, int low, int high, int value) {
  if (low == high) {
    return -1;
  } else {
    int mid = (low + high) / 2;
    if (value == arr[mid]) {
      return mid;
    } else if (arr[mid] < value) {
      return binary_search_rec_helper(arr, mid + 1, high, value);
    } else {
      return binary_search_rec_helper(arr, low, mid, value);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<binary_search_rec_helper>:
  endbr64
  mov    %rdi,%r8
  jmp    L41
  nopl   0x0(%rax)
L40:
  lea    (%rdx,%rsi,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %ecx,(%r8,%rdi,4)
  je     L19
  jl     L48
  mov    %eax,%edx
L41:
  cmp    %esi,%edx
  jne    L40
  mov    $0xffffffff,%r9d
L19:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  lea    0x1(%rax),%esi
  jmp    L41
```

assistant: ```c
int binary_search_rec_helper(int *arr, int low, int high, int value) {
  if (low == high) {
    return -1;
  } else {
    int mid = (low + high) / 2;
    if (value == arr[mid]) {
      return mid;
    } else if (arr[mid] < value) {
      return binary_search_rec_helper(arr, mid + 1, high, value);
    } else {
      return binary_search_rec_helper(arr, low, mid, value);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_filesize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L31
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L1
L31:
  mov    $0xffffffff,%eax
  jmp    L22
L1:
  mov    -0x10(%rbp),%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int _filesize(int fd) {
  struct stat buffer;
  int status;
  status = fstat(fd, &buffer);
  if (status || errno) {
    return -1;
  }
  return buffer.st_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_filesize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %eax,%eax
  jne    L0
  mov    D0(%rip),%rax
  cmpq   $0x0,(%rax)
  jne    L49
  mov    0x4(%rsp),%eax
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L44
L49:
  mov    $0xffffffff,%eax
  jmp    L44
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _filesize(int fd) {
  struct stat buffer;
  int status;
  status = fstat(fd, &buffer);
  if (status || errno) {
    return -1;
  }
  return buffer.st_size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_filesize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %eax,%eax
  jne    L30
  mov    D6(%rip),%rax
  cmpq   $0x0,(%rax)
  jne    L30
  mov    0x4(%rsp),%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L30:
  mov    $0xffffffff,%eax
  jmp    L34
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _filesize(int fd) {
  struct stat buffer;
  int status;
  status = fstat(fd, &buffer);
  if (status || errno) {
    return -1;
  }
  return buffer.st_size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_filesize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %eax,%eax
  jne    L23
  mov    D8(%rip),%rax
  cmpq   $0x0,(%rax)
  jne    L23
  mov    0x4(%rsp),%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L23:
  mov    $0xffffffff,%eax
  jmp    L29
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _filesize(int fd) {
  struct stat buffer;
  int status;
  status = fstat(fd, &buffer);
  if (status || errno) {
    return -1;
  }
  return buffer.st_size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findRudolph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %rdi,-0x1b8(%rbp)
  mov    %esi,-0x1bc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movl   $0x0,-0x1a4(%rbp)
  jmp    L10
L26:
  mov    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x1a0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a4(%rbp)
L10:
  mov    -0x1a4(%rbp),%eax
  cmp    -0x1bc(%rbp),%eax
  jl     L26
  movl   $0x0,-0x1a4(%rbp)
  jmp    L32
L31:
  mov    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L28
  mov    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L44
L28:
  addl   $0x1,-0x1a4(%rbp)
L32:
  mov    -0x1a4(%rbp),%eax
  cmp    -0x1bc(%rbp),%eax
  jl     L31
  mov    $0x0,%eax
L44:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int findRudolph(int reindeer[200], int amountOfReindeer) {
  int i, rooms[101] = {0};
  for (i = 0; i < amountOfReindeer; i++) {
    rooms[reindeer[i]]++;
  }
  for (i = 0; i < amountOfReindeer; i++) {
    if (rooms[reindeer[i]] == 1) {
      return reindeer[i];
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<findRudolph>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  test   %esi,%esi
  jle    L33
  mov    %rdx,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdx,%rcx,4),%rsi
  mov    %rdx,%rdi
L17:
  movslq (%rdi),%rdx
  addl   $0x1,(%rsp,%rdx,4)
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L17
L52:
  mov    (%rax),%edx
  movslq %edx,%rcx
  cmpl   $0x1,(%rsp,%rcx,4)
  je     L12
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L52
  mov    $0x0,%edx
L12:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %edx,%eax
  add    $0x1a8,%rsp
  ret
L33:
  mov    $0x0,%edx
  jmp    L12
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findRudolph(int reindeer[200], int amountOfReindeer) {
  int i, rooms[101] = {0};
  for (i = 0; i < amountOfReindeer; i++) {
    rooms[reindeer[i]]++;
  }
  for (i = 0; i < amountOfReindeer; i++) {
    if (rooms[reindeer[i]] == 1) {
      return reindeer[i];
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findRudolph>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %rdi,%rdx
  mov    $0x32,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  test   %esi,%esi
  jle    L66
  lea    -0x1(%rsi),%eax
  mov    %rdx,%rdi
  lea    0x4(%rdx,%rax,4),%rcx
  mov    %rdx,%rax
  nopl   0x0(%rax)
L60:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L60
  movslq (%rdi),%rdx
  cmpl   $0x1,(%rsp,%rdx,4)
  mov    %rdx,%rax
  je     L62
  nopl   0x0(%rax)
L38:
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  je     L66
  movslq (%rdi),%rdx
  cmpl   $0x1,(%rsp,%rdx,4)
  mov    %rdx,%rax
  jne    L38
L62:
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x1a8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  xor    %eax,%eax
  jmp    L62
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findRudolph(int reindeer[200], int amountOfReindeer) {
  int i, rooms[101] = {0};
  for (i = 0; i < amountOfReindeer; i++) {
    rooms[reindeer[i]]++;
  }
  for (i = 0; i < amountOfReindeer; i++) {
    if (rooms[reindeer[i]] == 1) {
      return reindeer[i];
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<findRudolph>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %rdi,%rdx
  mov    $0x32,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  mov    %rdx,%rdi
  lea    0x4(%rdx,%rax,4),%rcx
  mov    %rdx,%rax
  nopl   0x0(%rax)
L1:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L1
  movslq (%rdi),%rdx
  cmpl   $0x1,(%rsp,%rdx,4)
  mov    %rdx,%rax
  je     L30
  nopl   0x0(%rax)
L2:
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  je     L3
  movslq (%rdi),%rdx
  cmpl   $0x1,(%rsp,%rdx,4)
  mov    %rdx,%rax
  jne    L2
L30:
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x1a8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  jmp    L30
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findRudolph(int reindeer[200], int amountOfReindeer) {
  int i, rooms[101] = {0};
  for (i = 0; i < amountOfReindeer; i++) {
    rooms[reindeer[i]]++;
  }
  for (i = 0; i < amountOfReindeer; i++) {
    if (rooms[reindeer[i]] == 1) {
      return reindeer[i];
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dehex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L5
  cmpb   $0x39,-0x4(%rbp)
  jg     L5
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L21
L5:
  cmpb   $0x40,-0x4(%rbp)
  jle    L65
  cmpb   $0x46,-0x4(%rbp)
  jg     L65
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L21
L65:
  cmpb   $0x60,-0x4(%rbp)
  jle    L3
  cmpb   $0x66,-0x4(%rbp)
  jg     L3
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L21
L3:
  mov    $0xffffffff,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int dehex(char c) {
  if (c >= '0' && c <= '9')
    return c - '0' + 0x0;
  if (c >= 'A' && c <= 'F')
    return c - 'A' + 0xA;
  if (c >= 'a' && c <= 'f')
    return c - 'a' + 0xa;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dehex>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L1
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L4
  lea    -0x61(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x57,%eax
  cmp    $0x6,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L1:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L4:
  movsbl %dil,%edi
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
int dehex(char c) {
  if (c >= '0' && c <= '9')
    return c - '0' + 0x0;
  if (c >= 'A' && c <= 'F')
    return c - 'A' + 0xA;
  if (c >= 'a' && c <= 'f')
    return c - 'a' + 0xa;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dehex>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L17
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L9
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl %al,%eax
  ret
```

assistant: ```c
int dehex(char c) {
  if (c >= '0' && c <= '9')
    return c - '0' + 0x0;
  if (c >= 'A' && c <= 'F')
    return c - 'A' + 0xA;
  if (c >= 'a' && c <= 'f')
    return c - 'a' + 0xa;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dehex>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L0
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L13
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  movsbl %al,%eax
  ret
```

assistant: ```c
int dehex(char c) {
  if (c >= '0' && c <= '9')
    return c - '0' + 0x0;
  if (c >= 'A' && c <= 'F')
    return c - 'A' + 0xA;
  if (c >= 'a' && c <= 'f')
    return c - 'a' + 0xa;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xe589eac7,%edi
  call   <largest_prime_factor@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: %ld


assistant: ```c
int main() {
  unsigned long factor;
  factor = largest_prime_factor(600851475143);
  printf("%ld\n", factor);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe589eac7,%edi
  call   <largest_prime_factor@plt>
  mov    %rax,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: %ld


assistant: ```c
int main() {
  unsigned long factor;
  factor = largest_prime_factor(600851475143);
  printf("%ld\n", factor);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe589eac7,%edi
  call   <largest_prime_factor@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D6: %ld


assistant: ```c
int main() {
  unsigned long factor;
  factor = largest_prime_factor(600851475143);
  printf("%ld\n", factor);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe589eac7,%edi
  call   <largest_prime_factor@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %ld


assistant: ```c
int main() {
  unsigned long factor;
  factor = largest_prime_factor(600851475143);
  printf("%ld\n", factor);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__bitmap_xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x3f,%rax
  shr    $0x6,%rax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L15:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __bitmap_xor(unsigned long *dst, const unsigned long *bitmap1, const unsigned long *bitmap2, unsigned int bits) {
  unsigned int k;
  unsigned int nr = (((bits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  for (k = 0; k < nr; k++)
    dst[k] = bitmap1[k] ^ bitmap2[k];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__bitmap_xor>:
  endbr64
  mov    %ecx,%ecx
  add    $0x3f,%rcx
  shr    $0x6,%rcx
  je     L17
  mov    $0x0,%eax
L6:
  mov    (%rsi,%rax,8),%r8
  xor    (%rdx,%rax,8),%r8
  mov    %r8,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L6
L17:
  ret
```

assistant: ```c
void __bitmap_xor(unsigned long *dst, const unsigned long *bitmap1, const unsigned long *bitmap2, unsigned int bits) {
  unsigned int k;
  unsigned int nr = (((bits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  for (k = 0; k < nr; k++)
    dst[k] = bitmap1[k] ^ bitmap2[k];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__bitmap_xor>:
  endbr64
  mov    %ecx,%ecx
  add    $0x3f,%rcx
  shr    $0x6,%rcx
  je     L5
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rsi,%rax,8),%r8
  xor    (%rdx,%rax,8),%r8
  mov    %r8,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L8
L5:
  ret
```

assistant: ```c
void __bitmap_xor(unsigned long *dst, const unsigned long *bitmap1, const unsigned long *bitmap2, unsigned int bits) {
  unsigned int k;
  unsigned int nr = (((bits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  for (k = 0; k < nr; k++)
    dst[k] = bitmap1[k] ^ bitmap2[k];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__bitmap_xor>:
  endbr64
  mov    %rdx,%r8
  mov    %ecx,%edx
  add    $0x3f,%rdx
  shr    $0x6,%rdx
  je     L37
  lea    0x8(%r8),%rax
  cmp    %rax,%rdi
  lea    0x8(%rsi),%rax
  setne  %cl
  cmp    %rax,%rdi
  setne  %al
  test   %al,%cl
  je     L30
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L30
  mov    %rdx,%rcx
  xor    %eax,%eax
  shr    %rcx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L10:
  movdqu (%rsi,%rax,1),%xmm0
  movdqu (%r8,%rax,1),%xmm1
  pxor   %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L10
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0xf8000001,%edx
  je     L37
  mov    (%rsi,%rax,8),%rdx
  xor    (%r8,%rax,8),%rdx
  mov    %rdx,(%rdi,%rax,8)
  ret
  xchg   %ax,%ax
L30:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rsi,%rax,8),%rcx
  xor    (%r8,%rax,8),%rcx
  mov    %rcx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L2
L37:
  ret
```

assistant: ```c
void __bitmap_xor(unsigned long *dst, const unsigned long *bitmap1, const unsigned long *bitmap2, unsigned int bits) {
  unsigned int k;
  unsigned int nr = (((bits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  for (k = 0; k < nr; k++)
    dst[k] = bitmap1[k] ^ bitmap2[k];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<prefetch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void(prefetch)(void const *x) {
  {
    ;
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<prefetch>:
  endbr64
  ret
```

assistant: ```c
void(prefetch)(void const *x) {
  {
    ;
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prefetch>:
  endbr64
  ret
```

assistant: ```c
void(prefetch)(void const *x) {
  {
    ;
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prefetch>:
  endbr64
  ret
```

assistant: ```c
void(prefetch)(void const *x) {
  {
    ;
    return;
  }
}
```