user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rdx
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    $0x5,%eax
  ja     L1
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D32(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D32(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
  mov    -0x34(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  add    %ebx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
  mov    -0x34(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <pow@plt>
  add    %ebx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L1:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L33:
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D20
type_guessed: string
name: unpack_data
arguments: data_tag: D54
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D78
type_guessed: string
name: unpack_data
arguments: data_tag: D93
type_guessed: string
name: unpack_data
arguments: data_tag: D33
type_guessed: string
name: unpack_data
arguments: data_tag: D89
type_guessed: string
name: unpack_data
arguments: data_tag: D83
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string

tool: D20: Enter two numbers: 

tool: D54: %d %d

tool: D25: 
---------------- MENU -------------- 

tool: D78: 
	 1. Summation 
	 2. Sum of squares 
	 3. Sum of cubes 
	 4. Product 
	 5. Exit 
 Your choice: 

tool: D93: %d

tool: D33: 
The sum is %d

tool: D89: 
The sum of squares is %d

tool: D83: 
The sum of cubes is %d

tool: D30: 
The product is %d

tool: D22: 
Wrong choice

assistant: ```c
int main(void) {
  int a, b, sum, sq_sum, cu_sum, product, choice;
  printf("Enter two numbers: \n");
  scanf("%d %d", &a, &b);
  printf("\n---------------- MENU -------------- ");
  printf("\n\t 1. Summation \n\t 2. Sum of squares \n\t 3. Sum of cubes \n\t 4. Product \n\t 5. Exit \n Your choice: ");
  scanf("%d", &choice);
  switch (choice) {
  case 1:
    sum = a + b;
    printf("\nThe sum is %d", sum);
    break;
  case 2:
    sq_sum = pow(a, 2) + pow(b, 2);
    printf("\nThe sum of squares is %d", sq_sum);
    break;
  case 3:
    cu_sum = pow(a, 3) + pow(b, 3);
    printf("\nThe sum of cubes is %d", cu_sum);
    break;
  case 4:
    product = a * b;
    printf("\nThe product is %d", product);
  case 5:
    exit(0);
  default:
    printf("\nWrong choice");
  }
}
```