user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rgrep_matches>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strleng@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strleng@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <checkSpecial@plt>
  cmp    $0x1388,%rax
  je     L144
  mov    %rbp,%rdi
  call   <checkSpecial@plt>
  movzbl 0x0(%rbp,%rax,1),%eax
  cmp    $0x2e,%al
  je     L161
  cmp    $0x3f,%al
  je     L50
  cmp    $0x2b,%al
  je     L19
L68:
  xor    %eax,%eax
L102:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L144:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <firstOccur@plt>
  movslq %eax,%r13
  test   %ebx,%ebx
  je     L46
  cmp    $0x1388,%r13d
  setne  %al
  cmp    $0x1,%ebx
  je     L22
  jle    L68
  test   %al,%al
  je     L68
  mov    %r12,%rdi
  add    %r13,%r12
  call   <strleng@plt>
  mov    $0x1,%edx
  jmp    L58
  xchg   %ax,%ax
L47:
  movzbl (%r12,%rdx,1),%ecx
  cmp    %cl,0x0(%rbp,%rdx,1)
  jne    L68
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  je     L46
L58:
  cmp    %edx,%eax
  jg     L47
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L19:
  cmp    $0x1,%ebx
  je     L46
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <morePlus@plt>
  test   %eax,%eax
  je     L147
L46:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L50:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <questionMark@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  movzbl %al,%eax
  jmp    L102
  nopl   0x0(%rax,%rax,1)
L161:
  mov    %rbp,%rdi
  call   <sameChar@plt>
  test   %eax,%eax
  je     L132
  xor    %eax,%eax
  cmp    %r13d,%ebx
  sete   %al
  jmp    L102
  nopl   0x0(%rax)
L147:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <patternPlus@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L102
  nopl   0x0(%rax,%rax,1)
L132:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matchPatternDots@plt>
  test   %eax,%eax
  jne    L46
  mov    $0x2b,%esi
  mov    %rbp,%rdi
  call   <firstOccur@plt>
  cmp    $0x1388,%eax
  je     L68
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <afterPlus@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L102
```

assistant: ```c
int rgrep_matches(char *line, char *pattern) {
  int n = strleng(pattern);
  int m = strleng(line);
  if (checkSpecial(pattern) != 5000) {
    switch (pattern[checkSpecial(pattern)]) {
    case '.':
      if (sameChar(pattern)) {
        if (m == n)
          return 1;
        else
          return 0;
      } else if (matchPatternDots(pattern, line)) {
        return 1;
      } else if (firstOccur(pattern, '+') != 5000) {
        if (afterPlus(pattern, line))
          return 1;
      } else
        return 0;
    case '\\':
      return 0;
    case '+':
      if (n == 1)
        return 1;
      if (morePlus(pattern, line))
        return 1;
      if (patternPlus(pattern, line))
        return 1;
      return 0;
    case '?':
      if (questionMark(pattern, line))
        return 1;
      return 0;
    default:
      return 0;
    }
  } else {
    int matches = 0;
    int index = firstOccur(line, pattern[0]);
    if (n == 0) {
      return 1;
    } else if (n == 1) {
      if (index != 5000) {
        return 1;
      }
    } else if (n > 1) {
      if (index != 5000) {
        matches++;
        for (int i = 1, l = strleng(line); i < l; i++) {
          if (pattern[i] == line[index + i]) {
            matches++;
            if (matches == n) {
              return 1;
            }
          } else
            return 0;
        }
      } else
        return 0;
    }
    return 0;
  }
  return 0;
}
```