ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<menuCalcul>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  lea    D99(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    D81(%rip),%rdi
  call   <printf@plt>
  lea    D102(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D89(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
datatype: string
name: read_data
arguments: label: D99
datatype: string
name: read_data
arguments: label: D81
datatype: string
name: read_data
arguments: label: D102
datatype: string
name: read_data
arguments: label: D89
datatype: string
name: read_data
arguments: label: D43
datatype: string
name: read_data
arguments: label: D53
datatype: string
name: read_data
arguments: label: D68
datatype: string
name: read_data
arguments: label: D39
datatype: string
name: read_data
arguments: label: D61
datatype: string
name: read_data
arguments: label: D28
datatype: string

tool: D12: *************************************************

tool: D99: 
*************************************************

tool: D81: 
***************CALCULATEUR D'IMPOT***************

tool: D102: 
******************SUR LE REVENU******************

tool: D89: 
       Mode de calcul ? :                        

tool: D43: 
            1 - Chainage avant ?                 

tool: D53: 
            2 - Chainage arriere ?               

tool: D68: 
            3 - Chainage Av et Ar avec details ? 

tool: D39: 
            0 - Quitter ?                        

tool: D61: 
      Votre choix ? : 

tool: D28: %d

assistant: ```c
int menuCalcul() {
  int choix = 0;
  printf("*************************************************");
  printf("\n***************CALCULATEUR D'IMPOT***************");
  printf("\n******************SUR LE REVENU******************");
  printf("\n*************************************************");
  printf("\n       Mode de calcul ? :                        ");
  printf("\n            1 - Chainage avant ?                 ");
  printf("\n            2 - Chainage arriere ?               ");
  printf("\n            3 - Chainage Av et Ar avec details ? ");
  printf("\n            0 - Quitter ?                        ");
  printf("\n*************************************************");
  printf("\n*************************************************");
  printf("\n      Votre choix ? : ");
  scanf("%d", &choix);
  return choix;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ec_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: in ec_malloc() on memory allocation

assistant: ```c
void *ec_malloc(size_t size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr == NULL)
    fatal("in ec_malloc() on memory allocation");
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ec_malloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L12:
  mov    %rbx,%rax
  pop    %rbx
  ret
L7:
  lea    D3(%rip),%rdi
  call   <fatal@plt>
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: in ec_malloc() on memory allocation

assistant: ```c
void *ec_malloc(size_t size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr == NULL)
    fatal("in ec_malloc() on memory allocation");
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<ec_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
L19:
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  lea    D0(%rip),%rdi
  call   <fatal@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: in ec_malloc() on memory allocation

assistant: ```c
void *ec_malloc(size_t size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr == NULL)
    fatal("in ec_malloc() on memory allocation");
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ec_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L10:
  mov    %r12,%rax
  pop    %r12
  ret
L15:
  lea    D6(%rip),%rdi
  call   <fatal@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: in ec_malloc() on memory allocation

assistant: ```c
void *ec_malloc(size_t size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr == NULL)
    fatal("in ec_malloc() on memory allocation");
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_f() {
  unsigned int local;
  return 2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_f>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int my_f() {
  unsigned int local;
  return 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_f>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int my_f() {
  unsigned int local;
  return 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_argv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_argv(char **argv, int argc) {
  int i;
  for (i = 0; i < argc; ++i) {
    free(argv[i]);
  }
  free(argv);
}
```
user: What is the c source code of the assembly code below:

```asm
<free_argv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L1
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L15:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L15
L1:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free_argv(char **argv, int argc) {
  int i;
  for (i = 0; i < argc; ++i) {
    free(argv[i]);
  }
  free(argv);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<free_argv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L11
L3:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_argv(char **argv, int argc) {
  int i;
  for (i = 0; i < argc; ++i) {
    free(argv[i]);
  }
  free(argv);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<free_argv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L6
L7:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_argv(char **argv, int argc) {
  int i;
  for (i = 0; i < argc; ++i) {
    free(argv[i]);
  }
  free(argv);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_putnwstr_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  jmp    L15
L45:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_wctomb@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L56
  mov    $0xffffffffffffffff,%rax
  jmp    L48
L56:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x30(%rbp)
  jb     L33
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x34(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ft_putwchar_fd@plt>
  jmp    L50
L33:
  mov    -0x18(%rbp),%rax
  jmp    L48
L50:
  addq   $0x4,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
L15:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L45
  mov    -0x18(%rbp),%rax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
size_t ft_putnwstr_fd(wchar_t *wstr, size_t n, int fd) {
  size_t converted_char;
  int current_char;
  char temp[4];
  converted_char = 0;
  while (*wstr) {
    if ((current_char = ft_wctomb(temp, *wstr)) == -1)
      return ((size_t)-1);
    if ((converted_char + current_char) <= n)
      ft_putwchar_fd(*wstr, fd);
    else
      return (converted_char);
    wstr++;
    converted_char += current_char;
  }
  return (converted_char);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_putnwstr_fd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%esi
  test   %esi,%esi
  je     L76
  mov    %rdi,%rbx
  mov    %edx,%r13d
  mov    $0x0,%ebp
  lea    0x4(%rsp),%r14
  jmp    L36
L30:
  mov    %r15,%rbp
L36:
  mov    %r14,%rdi
  call   <ft_wctomb@plt>
  cmp    $0xffffffff,%eax
  je     L27
  cltq
  lea    (%rax,%rbp,1),%r15
  cmp    %r12,%r15
  ja     L7
  mov    %r13d,%esi
  mov    (%rbx),%edi
  call   <ft_putwchar_fd@plt>
  add    $0x4,%rbx
  mov    (%rbx),%esi
  test   %esi,%esi
  jne    L30
  mov    %r15,%rbp
  jmp    L7
L76:
  mov    $0x0,%ebp
  jmp    L7
L27:
  mov    $0xffffffffffffffff,%rbp
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t ft_putnwstr_fd(wchar_t *wstr, size_t n, int fd) {
  size_t converted_char;
  int current_char;
  char temp[4];
  converted_char = 0;
  while (*wstr) {
    if ((current_char = ft_wctomb(temp, *wstr)) == -1)
      return ((size_t)-1);
    if ((converted_char + current_char) <= n)
      ft_putwchar_fd(*wstr, fd);
    else
      return (converted_char);
    wstr++;
    converted_char += current_char;
  }
  return (converted_char);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_putnwstr_fd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L59
  mov    %rdi,%rbp
  mov    %edx,%r13d
  lea    0x4(%rsp),%r14
  xor    %r15d,%r15d
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L3:
  cltq
  lea    (%rax,%r15,1),%rbx
  cmp    %r12,%rbx
  ja     L36
  mov    0x0(%rbp),%edi
  mov    %r13d,%esi
  add    $0x4,%rbp
  mov    %rbx,%r15
  call   <ft_putwchar_fd@plt>
  mov    0x0(%rbp),%esi
  test   %esi,%esi
  je     L36
L30:
  mov    %r14,%rdi
  call   <ft_wctomb@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  mov    $0xffffffffffffffff,%r15
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  xor    %r15d,%r15d
  jmp    L36
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t ft_putnwstr_fd(wchar_t *wstr, size_t n, int fd) {
  size_t converted_char;
  int current_char;
  char temp[4];
  converted_char = 0;
  while (*wstr) {
    if ((current_char = ft_wctomb(temp, *wstr)) == -1)
      return ((size_t)-1);
    if ((converted_char + current_char) <= n)
      ft_putwchar_fd(*wstr, fd);
    else
      return (converted_char);
    wstr++;
    converted_char += current_char;
  }
  return (converted_char);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_putnwstr_fd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L32
  mov    %rdi,%rbp
  mov    %edx,%r13d
  lea    0x4(%rsp),%r14
  xor    %r15d,%r15d
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L42:
  cltq
  lea    (%rax,%r15,1),%rbx
  cmp    %r12,%rbx
  ja     L5
  mov    0x0(%rbp),%edi
  mov    %r13d,%esi
  add    $0x4,%rbp
  mov    %rbx,%r15
  call   <ft_putwchar_fd@plt>
  mov    0x0(%rbp),%esi
  test   %esi,%esi
  je     L5
L3:
  mov    %r14,%rdi
  call   <ft_wctomb@plt>
  cmp    $0xffffffff,%eax
  jne    L42
  mov    $0xffffffffffffffff,%r15
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  xor    %r15d,%r15d
  jmp    L5
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t ft_putnwstr_fd(wchar_t *wstr, size_t n, int fd) {
  size_t converted_char;
  int current_char;
  char temp[4];
  converted_char = 0;
  while (*wstr) {
    if ((current_char = ft_wctomb(temp, *wstr)) == -1)
      return ((size_t)-1);
    if ((converted_char + current_char) <= n)
      ft_putwchar_fd(*wstr, fd);
    else
      return (converted_char);
    wstr++;
    converted_char += current_char;
  }
  return (converted_char);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PresentBuffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movb   $0x0,-0x9(%rbp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <LCDPosition@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L0:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <screenBuffer@plt>
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <LCDWrite@plt>
  addq   $0x1,-0x8(%rbp)
L12:
  cmpq   $0x1f7,-0x8(%rbp)
  jbe    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void PresentBuffer(void) {
  size_t idx = 0;
  unsigned char val = 0;
  LCDPosition(0, 0);
  for (idx = 0; idx < 84 * (48 / 8); ++idx) {
    val = screenBuffer(idx);
    LCDWrite(1, val);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PresentBuffer>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <LCDPosition@plt>
  mov    $0x0,%ebx
L3:
  mov    %rbx,%rdi
  call   <screenBuffer@plt>
  movzbl %al,%esi
  mov    $0x1,%edi
  call   <LCDWrite@plt>
  add    $0x1,%rbx
  cmp    $0x1f8,%rbx
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
void PresentBuffer(void) {
  size_t idx = 0;
  unsigned char val = 0;
  LCDPosition(0, 0);
  for (idx = 0; idx < 84 * (48 / 8); ++idx) {
    val = screenBuffer(idx);
    LCDWrite(1, val);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<PresentBuffer>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  xor    %edi,%edi
  xor    %ebx,%ebx
  call   <LCDPosition@plt>
L6:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <screenBuffer@plt>
  mov    $0x1,%edi
  movzbl %al,%esi
  call   <LCDWrite@plt>
  cmp    $0x1f8,%rbx
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
void PresentBuffer(void) {
  size_t idx = 0;
  unsigned char val = 0;
  LCDPosition(0, 0);
  for (idx = 0; idx < 84 * (48 / 8); ++idx) {
    val = screenBuffer(idx);
    LCDWrite(1, val);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PresentBuffer>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  xor    %edi,%edi
  xor    %ebx,%ebx
  call   <LCDPosition@plt>
L8:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <screenBuffer@plt>
  mov    $0x1,%edi
  movzbl %al,%esi
  call   <LCDWrite@plt>
  cmp    $0x1f8,%rbx
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void PresentBuffer(void) {
  size_t idx = 0;
  unsigned char val = 0;
  LCDPosition(0, 0);
  for (idx = 0; idx < 84 * (48 / 8); ++idx) {
    val = screenBuffer(idx);
    LCDWrite(1, val);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L21
L18:
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x40(%rbp)
L21:
  cmpl   $0x9,-0x40(%rbp)
  jle    L18
  movl   $0x0,-0x40(%rbp)
  jmp    L33
L38:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L35
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
L35:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jge    L25
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x38(%rbp)
L25:
  addl   $0x1,-0x40(%rbp)
L33:
  cmpl   $0x9,-0x40(%rbp)
  jle    L38
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
  movl   $0x0,-0x40(%rbp)
  jmp    L78
L83:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x40(%rbp)
L78:
  cmpl   $0x9,-0x40(%rbp)
  jle    L83
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D2
type: string

tool: D12: %d

tool: D2: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, max = 0, min = 0, tmp, a[10];
  for (i = 0; i < 10; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < 10; i++) {
    if (a[i] > a[max])
      max = i;
    if (a[i] < a[min])
      min = i;
  }
  tmp = a[9];
  a[9] = a[max];
  a[max] = tmp;
  tmp = a[0];
  a[0] = a[min];
  a[min] = tmp;
  for (i = 0; i < 10; i++) {
    printf("%d ", a[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
  lea    D7(%rip),%r13
L16:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L16
  mov    $0x0,%eax
  mov    $0x0,%edx
  mov    $0x0,%ecx
L19:
  mov    (%rsp,%rax,4),%esi
  movslq %ecx,%rdi
  cmp    (%rsp,%rdi,4),%esi
  cmovg  %eax,%ecx
  movslq %edx,%rdi
  cmp    (%rsp,%rdi,4),%esi
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L19
  mov    0x24(%rsp),%eax
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,4),%esi
  mov    %esi,0x24(%rsp)
  mov    %eax,(%rsp,%rcx,4)
  mov    (%rsp),%eax
  movslq %edx,%rdx
  mov    (%rsp,%rdx,4),%ecx
  mov    %ecx,(%rsp)
  mov    %eax,(%rsp,%rdx,4)
  lea    D0(%rip),%rbp
L28:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L28
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D7: %d

tool: D0: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, max = 0, min = 0, tmp, a[10];
  for (i = 0; i < 10; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < 10; i++) {
    if (a[i] > a[max])
      max = i;
    if (a[i] < a[min])
      min = i;
  }
  tmp = a[9];
  a[9] = a[max];
  a[max] = tmp;
  tmp = a[0];
  a[0] = a[min];
  a[min] = tmp;
  for (i = 0; i < 10; i++) {
    printf("%d ", a[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x28(%rsp),%r12
  mov    %r13,%rbx
  mov    %r13,%rbp
  nopl   (%rax)
L20:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L20
  mov    (%rsp),%r8d
  xor    %eax,%eax
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  mov    %r8d,%edx
  mov    %r8d,%edi
  jmp    L2
  nop
L32:
  movslq %ecx,%rdx
  mov    (%rsp,%rdx,4),%edi
  mov    0x0(%r13,%rax,4),%edx
L2:
  movslq %eax,%rsi
  cmp    %edx,%r8d
  jge    L40
  mov    %edx,%r8d
  movslq %eax,%r9
L40:
  cmp    %edx,%edi
  cmovg  %rsi,%rcx
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L32
  mov    0x24(%rsp),%eax
  mov    %r8d,0x24(%rsp)
  lea    D5(%rip),%rbp
  mov    %eax,(%rsp,%r9,4)
  mov    (%rsp),%eax
  mov    (%rsp,%rcx,4),%edx
  mov    %edx,(%rsp)
  mov    %eax,(%rsp,%rcx,4)
  nopl   0x0(%rax)
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D14: %d

tool: D5: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, max = 0, min = 0, tmp, a[10];
  for (i = 0; i < 10; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < 10; i++) {
    if (a[i] > a[max])
      max = i;
    if (a[i] < a[min])
      min = i;
  }
  tmp = a[9];
  a[9] = a[max];
  a[max] = tmp;
  tmp = a[0];
  a[0] = a[min];
  a[min] = tmp;
  for (i = 0; i < 10; i++) {
    printf("%d ", a[i]);
  }
  return 0;
}
```