ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_md5_salt_para>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    $0x10,%eax
  jle    L15
L6:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rdx
  lea    D17(%rip),%r12
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D22: Invalid Salt, please use up to 16 random alphanumeric characters


tool: D8: $1$%s$

assistant: ```c
char *make_md5_salt_para(char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    sprintf(salt, "$1$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<make_md5_salt_para>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    $0x10,%eax
  jle    L10
L3:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rdx
  lea    D5(%rip),%r12
  lea    D22(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D22
type: string

tool: D16: Invalid Salt, please use up to 16 random alphanumeric characters


tool: D22: $1$%s$

assistant: ```c
char *make_md5_salt_para(char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    sprintf(salt, "$1$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L9
L0:
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %rax,-0x10(%rbp)
L9:
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x10(%rbp),%xmm0
  mov    D11(%rip),%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x8(%rbp),%xmm1
  mov    D11(%rip),%rax
  movsd  (%rax),%xmm3
  movapd %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void delay(double dly) {
  clock_t ticks1, ticks2;
  ticks1 = clock();
  ticks2 = ticks1;
  while (((double)ticks2 / CLOCKS_PER_SEC - (double)ticks1 / CLOCKS_PER_SEC) < dly)
    ticks2 = clock();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<delay>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <clock@plt>
  pxor   %xmm4,%xmm4
  cvtsi2sd %rax,%xmm4
  movq   %xmm4,%r14
  mov    D7(%rip),%rax
  movapd %xmm4,%xmm0
  divsd  (%rax),%xmm0
  subsd  %xmm0,%xmm0
  movq   %rbx,%xmm5
  comisd %xmm0,%xmm5
  jbe    L11
L5:
  mov    $0x0,%eax
  call   <clock@plt>
  mov    D7(%rip),%rdx
  movsd  (%rdx),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  %xmm1,%xmm0
  movq   %r14,%xmm2
  divsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  movq   %rbx,%xmm3
  comisd %xmm0,%xmm3
  ja     L5
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
void delay(double dly) {
  clock_t ticks1, ticks2;
  ticks1 = clock();
  ticks2 = ticks1;
  while (((double)ticks2 / CLOCKS_PER_SEC - (double)ticks1 / CLOCKS_PER_SEC) < dly)
    ticks2 = clock();
}
```
user: Translate the below assembly code into C programming language:

```asm
<delay>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  movq   %xmm0,%r14
  push   %rbx
  call   <clock@plt>
  pxor   %xmm4,%xmm4
  movq   %r14,%xmm5
  mov    D1(%rip),%rbx
  cvtsi2sd %rax,%xmm4
  movapd %xmm4,%xmm0
  divsd  (%rbx),%xmm0
  subsd  %xmm0,%xmm0
  comisd %xmm0,%xmm5
  jbe    L11
  movq   %xmm4,%r15
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  call   <clock@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rbx),%xmm1
  movq   %r15,%xmm2
  cvtsi2sd %rax,%xmm0
  movq   %r14,%xmm3
  divsd  %xmm1,%xmm2
  divsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  comisd %xmm0,%xmm3
  ja     L5
L11:
  pop    %rbx
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void delay(double dly) {
  clock_t ticks1, ticks2;
  ticks1 = clock();
  ticks2 = ticks1;
  while (((double)ticks2 / CLOCKS_PER_SEC - (double)ticks1 / CLOCKS_PER_SEC) < dly)
    ticks2 = clock();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delay>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  movq   %xmm0,%r14
  push   %rbx
  call   <clock@plt>
  pxor   %xmm4,%xmm4
  movq   %r14,%xmm5
  mov    D3(%rip),%rbx
  cvtsi2sd %rax,%xmm4
  movapd %xmm4,%xmm0
  divsd  (%rbx),%xmm0
  subsd  %xmm0,%xmm0
  comisd %xmm0,%xmm5
  jbe    L11
  movq   %xmm4,%r15
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  call   <clock@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rbx),%xmm1
  movq   %r15,%xmm2
  cvtsi2sd %rax,%xmm0
  movq   %r14,%xmm3
  divsd  %xmm1,%xmm2
  divsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  comisd %xmm0,%xmm3
  ja     L10
L11:
  pop    %rbx
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void delay(double dly) {
  clock_t ticks1, ticks2;
  ticks1 = clock();
  ticks2 = ticks1;
  while (((double)ticks2 / CLOCKS_PER_SEC - (double)ticks1 / CLOCKS_PER_SEC) < dly)
    ticks2 = clock();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x34333231,-0xe(%rbp)
  movw   $0x35,-0xa(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xe(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ho_memset@plt>
  mov    $0x5,%edx
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <write@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: ::

assistant: ```c
int main() {
  char buf[] = "12345";
  printf("%s\n", buf);
  write(1, ho_memset(buf, 0, 5), 5);
  printf("::\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x34333231,0x2(%rsp)
  movw   $0x35,0x6(%rsp)
  lea    0x2(%rsp),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <ho_memset@plt>
  mov    %eax,%esi
  mov    $0x5,%edx
  mov    $0x1,%edi
  call   <write@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D2: ::

assistant: ```c
int main() {
  char buf[] = "12345";
  printf("%s\n", buf);
  write(1, ho_memset(buf, 0, 5), 5);
  printf("::\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  mov    $0x35,%eax
  movl   $0x34333231,0x2(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x6(%rsp)
  call   <puts@plt>
  xor    %esi,%esi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <ho_memset@plt>
  mov    $0x1,%edi
  mov    $0x5,%edx
  mov    %eax,%esi
  call   <write@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: ::

assistant: ```c
int main() {
  char buf[] = "12345";
  printf("%s\n", buf);
  write(1, ho_memset(buf, 0, 5), 5);
  printf("::\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  mov    $0x35,%eax
  movl   $0x34333231,0x2(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x6(%rsp)
  call   <puts@plt>
  xor    %esi,%esi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <ho_memset@plt>
  mov    $0x1,%edi
  mov    $0x5,%edx
  mov    %eax,%esi
  call   <write@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: ::

assistant: ```c
int main() {
  char buf[] = "12345";
  printf("%s\n", buf);
  write(1, ho_memset(buf, 0, 5), 5);
  printf("::\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sumofdigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  jg     L36
  mov    -0x14(%rbp),%eax
  jmp    L40
L9:
  cmpl   $0x0,-0x14(%rbp)
  jne    L37
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
L37:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L36:
  cmpl   $0x0,-0x14(%rbp)
  jg     L9
  cmpl   $0x9,-0x4(%rbp)
  jg     L9
  mov    -0x4(%rbp),%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int sumofdigits(int n) {
  int sum = 0;
  if (n < 10) {
    return n;
  }
  while (n > 0 || sum > 9) {
    if (n == 0) {
      n = sum;
      sum = 0;
    }
    sum += n % 10;
    n = n / 10;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sumofdigits>:
  endbr64
  mov    %edi,%edx
  cmp    $0x9,%edi
  jle    L15
  mov    $0x0,%edx
  jmp    L40
L12:
  mov    %eax,%edi
  test   %eax,%eax
  jne    L40
  mov    %edx,%edi
  mov    %eax,%edx
L40:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edi,%esi
  sub    %ecx,%esi
  add    %esi,%edx
  cmp    $0x9,%edi
  jg     L12
  cmp    $0x9,%edx
  jg     L12
L15:
  mov    %edx,%eax
  ret
```

assistant: ```c
int sumofdigits(int n) {
  int sum = 0;
  if (n < 10) {
    return n;
  }
  while (n > 0 || sum > 9) {
    if (n == 0) {
      n = sum;
      sum = 0;
    }
    sum += n % 10;
    n = n / 10;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sumofdigits>:
  endbr64
  mov    %edi,%r8d
  cmp    $0x9,%edi
  jg     L44
  jmp    L35
  xchg   %ax,%ax
L27:
  mov    %eax,%edi
  test   %eax,%eax
  jne    L24
  mov    %r8d,%edi
L44:
  xor    %r8d,%r8d
L24:
  movslq %edi,%rax
  mov    %edi,%edx
  mov    %edi,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  add    %ecx,%r8d
  cmp    $0x9,%edi
  jg     L27
  cmp    $0x9,%r8d
  jg     L27
L35:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sumofdigits(int n) {
  int sum = 0;
  if (n < 10) {
    return n;
  }
  while (n > 0 || sum > 9) {
    if (n == 0) {
      n = sum;
      sum = 0;
    }
    sum += n % 10;
    n = n / 10;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sumofdigits>:
  endbr64
  mov    %edi,%eax
  cmp    $0x9,%edi
  jle    L64
  xor    %edx,%edx
L62:
  test   %edi,%edi
  je     L58
L39:
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %edi,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%esi
  add    %esi,%edx
  cmp    $0x9,%edx
  jg     L47
  cmp    $0x9,%edi
  jle    L15
L47:
  mov    %eax,%edi
  test   %edi,%edi
  jne    L39
L58:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %eax,%edi
  mov    %edx,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  cmp    $0x9,%edx
  jle    L64
  mov    %eax,%edx
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L64:
  ret
  nopl   0x0(%rax)
L15:
  mov    %edx,%eax
  ret
```

assistant: ```c
int sumofdigits(int n) {
  int sum = 0;
  if (n < 10) {
    return n;
  }
  while (n > 0 || sum > 9) {
    if (n == 0) {
      n = sum;
      sum = 0;
    }
    sum += n % 10;
    n = n / 10;
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aes_write_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0xc,%edi
  call   <nvmem_write@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
signed long aes_write_key(unsigned char *key) {
  signed long returnValue;
  returnValue = nvmem_write((12), 16, 0, key);
  return returnValue;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aes_write_key>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0xc,%edi
  call   <nvmem_write@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed long aes_write_key(unsigned char *key) {
  signed long returnValue;
  returnValue = nvmem_write((12), 16, 0, key);
  return returnValue;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<aes_write_key>:
  endbr64
  mov    %rdi,%rcx
  xor    %edx,%edx
  mov    $0x10,%esi
  mov    $0xc,%edi
  jmp    1050 <nvmem_write@plt>
```

assistant: ```c
signed long aes_write_key(unsigned char *key) {
  signed long returnValue;
  returnValue = nvmem_write((12), 16, 0, key);
  return returnValue;
}
```
user: Translate the below assembly code into C programming language:

```asm
<aes_write_key>:
  endbr64
  mov    %rdi,%rcx
  xor    %edx,%edx
  mov    $0x10,%esi
  mov    $0xc,%edi
  jmp    1050 <nvmem_write@plt>
```

assistant: ```c
signed long aes_write_key(unsigned char *key) {
  signed long returnValue;
  returnValue = nvmem_write((12), 16, 0, key);
  return returnValue;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pre_process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L43:
  cmpl   $0x0,-0xc(%rbp)
  jne    L21
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L38
L21:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L35
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  jmp    L38
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L38:
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L43
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *pre_process(int *a, int n) {
  int *f = (int *)malloc(n * sizeof(int));
  int i;
  for (i = 0; i < n; i++) {
    if (i == 0)
      f[i] = a[i];
    else if (f[i - 1] >= 0)
      f[i] = f[i - 1] + a[i];
    else
      f[i] = a[i];
  }
  return f;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pre_process>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L33
  mov    %rax,%rcx
  mov    %ebp,%esi
  mov    $0x0,%edx
  jmp    L60
L49:
  mov    (%rbx),%edi
  mov    %edi,(%rax)
L36:
  add    $0x1,%rdx
  add    $0x4,%rcx
  cmp    %rsi,%rdx
  je     L33
L60:
  test   %edx,%edx
  je     L49
  mov    -0x4(%rcx),%edi
  test   %edi,%edi
  js     L34
  add    (%rbx,%rdx,4),%edi
  mov    %edi,(%rcx)
  jmp    L36
L34:
  mov    (%rbx,%rdx,4),%edi
  mov    %edi,(%rcx)
  jmp    L36
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *pre_process(int *a, int n) {
  int *f = (int *)malloc(n * sizeof(int));
  int i;
  for (i = 0; i < n; i++) {
    if (i == 0)
      f[i] = a[i];
    else if (f[i - 1] >= 0)
      f[i] = f[i - 1] + a[i];
    else
      f[i] = a[i];
  }
  return f;
}
```
user: What is the c source code of the assembly code below:

```asm
<pre_process>:
  endbr64
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L19
  mov    %rax,%rcx
  xor    %edx,%edx
  jmp    L39
  nopl   (%rax)
L44:
  mov    (%rbx,%rdx,4),%edi
  mov    -0x4(%rcx),%r8d
  test   %r8d,%r8d
  lea    (%r8,%rdi,1),%esi
  cmovs  %edi,%esi
  add    $0x1,%rdx
  add    $0x4,%rcx
  mov    %esi,-0x4(%rcx)
  cmp    %rbp,%rdx
  je     L19
L39:
  test   %rdx,%rdx
  jne    L44
  mov    (%rbx),%esi
  add    $0x1,%rdx
  add    $0x4,%rcx
  mov    %esi,(%rax)
  cmp    %rbp,%rdx
  jne    L39
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *pre_process(int *a, int n) {
  int *f = (int *)malloc(n * sizeof(int));
  int i;
  for (i = 0; i < n; i++) {
    if (i == 0)
      f[i] = a[i];
    else if (f[i - 1] >= 0)
      f[i] = f[i - 1] + a[i];
    else
      f[i] = a[i];
  }
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pre_process>:
  endbr64
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L47
  mov    %rax,%rcx
  xor    %edx,%edx
  jmp    L24
  nopl   (%rax)
L5:
  mov    (%rbx,%rdx,4),%edi
  mov    -0x4(%rcx),%r8d
  test   %r8d,%r8d
  lea    (%r8,%rdi,1),%esi
  cmovs  %edi,%esi
  add    $0x1,%rdx
  add    $0x4,%rcx
  mov    %esi,-0x4(%rcx)
  cmp    %rbp,%rdx
  je     L47
L24:
  test   %rdx,%rdx
  jne    L5
  mov    (%rbx),%esi
  add    $0x1,%rdx
  add    $0x4,%rcx
  mov    %esi,(%rax)
  cmp    %rbp,%rdx
  jne    L24
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *pre_process(int *a, int n) {
  int *f = (int *)malloc(n * sizeof(int));
  int i;
  for (i = 0; i < n; i++) {
    if (i == 0)
      f[i] = a[i];
    else if (f[i - 1] >= 0)
      f[i] = f[i - 1] + a[i];
    else
      f[i] = a[i];
  }
  return f;
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: list_version -s filename


assistant: ```c
void usage() {
  printf("list_version -s filename\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: list_version -s filename


assistant: ```c
void usage() {
  printf("list_version -s filename\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: list_version -s filename


assistant: ```c
void usage() {
  printf("list_version -s filename\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: list_version -s filename


assistant: ```c
void usage() {
  printf("list_version -s filename\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<config_change_save_layout_on_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  call   <config_change_save_config_layout_on_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void config_change_save_layout_on_exit(const void *pointer, void *data, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)option;
  config_change_save_config_layout_on_exit();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<config_change_save_layout_on_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <config_change_save_config_layout_on_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void config_change_save_layout_on_exit(const void *pointer, void *data, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)option;
  config_change_save_config_layout_on_exit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<config_change_save_layout_on_exit>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <config_change_save_config_layout_on_exit@plt>
```

assistant: ```c
void config_change_save_layout_on_exit(const void *pointer, void *data, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)option;
  config_change_save_config_layout_on_exit();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<config_change_save_layout_on_exit>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <config_change_save_config_layout_on_exit@plt>
```

assistant: ```c
void config_change_save_layout_on_exit(const void *pointer, void *data, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)option;
  config_change_save_config_layout_on_exit();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<close_pipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int close_pipe(FILE *fp) {
  fclose(fp);
  int status;
  wait(&status);
  return status;
}
```