ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<tmpnam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  movzbl D21(%rip),%eax
  add    $0x1,%eax
  mov    %al,D14(%rip)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D14(%rip),%rax
  jmp    L10
L7:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
char *tmpnam(char *s) {
  static char buf[] = "ZZZZZZZA.$$$";
  buf[7]++;
  if (s == ((void *)0)) {
    return (buf);
  }
  strcpy(s, buf);
  return (s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tmpnam>:
  endbr64
  addb   $0x1,D9(%rip)
  lea    D10(%rip),%rax
  test   %rdi,%rdi
  je     L1
  push   %rbx
  mov    %rax,%rsi
  call   <strcpy@plt>
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
char *tmpnam(char *s) {
  static char buf[] = "ZZZZZZZA.$$$";
  buf[7]++;
  if (s == ((void *)0)) {
    return (buf);
  }
  strcpy(s, buf);
  return (s);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tmpnam>:
  endbr64
  addb   $0x1,D4(%rip)
  lea    D0(%rip),%rax
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  mov    %rax,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
char *tmpnam(char *s) {
  static char buf[] = "ZZZZZZZA.$$$";
  buf[7]++;
  if (s == ((void *)0)) {
    return (buf);
  }
  strcpy(s, buf);
  return (s);
}
```
user: What is the c source code of the assembly code below?

```asm
<tmpnam>:
  endbr64
  addb   $0x1,D6(%rip)
  lea    D14(%rip),%rax
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  mov    %rax,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
char *tmpnam(char *s) {
  static char buf[] = "ZZZZZZZA.$$$";
  buf[7]++;
  if (s == ((void *)0)) {
    return (buf);
  }
  strcpy(s, buf);
  return (s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ASTIL_ParseInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L33
L53:
  cmpl   $0x9,-0x8(%rbp)
  jle    L8
  mov    $0xffffffff,%eax
  jmp    L12
L8:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L29
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L53
L29:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L27
  mov    $0xffffffff,%eax
  jmp    L12
L27:
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int ASTIL_ParseInt(const char *s, int *pos) {
  int result = 0;
  int i = *pos;
  while (s[i] >= '0' && s[i] <= '9') {
    if (result >= 10)
      return -1;
    result = 10 * result + s[i++] - '0';
  }
  if (i == *pos)
    return -1;
  *pos = i;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ASTIL_ParseInt>:
  endbr64
  mov    (%rsi),%r10d
  movslq %r10d,%rax
  movzbl (%rdi,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L31
  lea    0x1(%r10),%ecx
  movslq %ecx,%rcx
  mov    $0x0,%edx
L37:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  movzbl (%rdi,%rcx,1),%eax
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  ja     L32
  add    $0x1,%rcx
  cmp    $0x9,%edx
  jle    L37
  mov    $0xffffffff,%edx
  jmp    L7
L32:
  cmp    %ecx,%r10d
  je     L19
  mov    %ecx,(%rsi)
L7:
  mov    %edx,%eax
  ret
L31:
  mov    $0xffffffff,%edx
  jmp    L7
L19:
  mov    $0xffffffff,%edx
  jmp    L7
```

assistant: ```c
int ASTIL_ParseInt(const char *s, int *pos) {
  int result = 0;
  int i = *pos;
  while (s[i] >= '0' && s[i] <= '9') {
    if (result >= 10)
      return -1;
    result = 10 * result + s[i++] - '0';
  }
  if (i == *pos)
    return -1;
  *pos = i;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ASTIL_ParseInt>:
  endbr64
  movslq (%rsi),%rax
  mov    %rax,%r10
  movsbl (%rdi,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L37
  lea    0x1(%r10),%edx
  xor    %r8d,%r8d
  movslq %edx,%rdx
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rdx
  cmp    $0x9,%r8d
  jg     L37
L21:
  lea    (%r8,%r8,4),%ecx
  lea    -0x30(%rax,%rcx,2),%r8d
  movsbl (%rdi,%rdx,1),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L39
  cmp    %edx,%r10d
  je     L37
  mov    %edx,(%rsi)
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ASTIL_ParseInt(const char *s, int *pos) {
  int result = 0;
  int i = *pos;
  while (s[i] >= '0' && s[i] <= '9') {
    if (result >= 10)
      return -1;
    result = 10 * result + s[i++] - '0';
  }
  if (i == *pos)
    return -1;
  *pos = i;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ASTIL_ParseInt>:
  endbr64
  movslq (%rsi),%rax
  mov    %rax,%r10
  movsbl (%rdi,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L12
  lea    0x1(%r10),%edx
  xor    %r8d,%r8d
  movslq %edx,%rdx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rdx
  cmp    $0x9,%r8d
  jg     L12
L13:
  lea    (%r8,%r8,4),%ecx
  lea    -0x30(%rax,%rcx,2),%r8d
  movsbl (%rdi,%rdx,1),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L5
  cmp    %edx,%r10d
  je     L12
  mov    %edx,(%rsi)
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ASTIL_ParseInt(const char *s, int *pos) {
  int result = 0;
  int i = *pos;
  while (s[i] >= '0' && s[i] <= '9') {
    if (result >= 10)
      return -1;
    result = 10 * result + s[i++] - '0';
  }
  if (i == *pos)
    return -1;
  *pos = i;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D59
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D51
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D54
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string

tool: D59: == program menu ==


tool: D51: Item 1: Control LED


tool: D54: Item 2: Read button state


tool: D1: Item c: Enter a custom command


tool: D20: Item e: Exit


tool: D17: Selection:


assistant: ```c
void print_menu() {
  printf("== program menu ==\n");
  printf("Item 1: Control LED\n");
  printf("Item 2: Read button state\n");
  printf("Item c: Enter a custom command\n");
  printf("Item e: Exit\n");
  printf("Selection:\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string
name: disassemble_data
arguments: label: D15
type_guessed: string
name: disassemble_data
arguments: label: D46
type_guessed: string
name: disassemble_data
arguments: label: D33
type_guessed: string
name: disassemble_data
arguments: label: D37
type_guessed: string
name: disassemble_data
arguments: label: D16
type_guessed: string

tool: D3: == program menu ==


tool: D15: Item 1: Control LED


tool: D46: Item 2: Read button state


tool: D33: Item c: Enter a custom command


tool: D37: Item e: Exit


tool: D16: Selection:


assistant: ```c
void print_menu() {
  printf("== program menu ==\n");
  printf("Item 1: Control LED\n");
  printf("Item 2: Read button state\n");
  printf("Item c: Enter a custom command\n");
  printf("Item e: Exit\n");
  printf("Selection:\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D53
data_type: string
name: retrieve_data
arguments: label: D30
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D24
data_type: string
name: retrieve_data
arguments: label: D44
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string

tool: D53: == program menu ==


tool: D30: Item 1: Control LED


tool: D15: Item 2: Read button state


tool: D24: Item c: Enter a custom command


tool: D44: Item e: Exit


tool: D4: Selection:


assistant: ```c
void print_menu() {
  printf("== program menu ==\n");
  printf("Item 1: Control LED\n");
  printf("Item 2: Read button state\n");
  printf("Item c: Enter a custom command\n");
  printf("Item e: Exit\n");
  printf("Selection:\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D54
type_guessed: string
name: retrieve_data
arguments: data_label: D34
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D53
type_guessed: string
name: retrieve_data
arguments: data_label: D44
type_guessed: string
name: retrieve_data
arguments: data_label: D41
type_guessed: string

tool: D54: == program menu ==


tool: D34: Item 1: Control LED


tool: D12: Item 2: Read button state


tool: D53: Item c: Enter a custom command


tool: D44: Item e: Exit


tool: D41: Selection:


assistant: ```c
void print_menu() {
  printf("== program menu ==\n");
  printf("Item 1: Control LED\n");
  printf("Item 2: Read button state\n");
  printf("Item c: Enter a custom command\n");
  printf("Item e: Exit\n");
  printf("Selection:\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<malloc_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *malloc_zero(int n) {
  int *a = malloc(n * sizeof(int));
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<malloc_zero>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x2,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *malloc_zero(int n) {
  int *a = malloc(n * sizeof(int));
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<malloc_zero>:
  endbr64
  shl    $0x2,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
int *malloc_zero(int n) {
  int *a = malloc(n * sizeof(int));
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_zero>:
  endbr64
  shl    $0x2,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
int *malloc_zero(int n) {
  int *a = malloc(n * sizeof(int));
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findterm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  call   <strlen@plt>
  mov    %eax,%edx
  lea    D39(%rip),%rax
  test   %edx,%edx
  je     L66
  movb   $0x0,D38(%rip)
  mov    %r15,%r13
  lea    D38(%rip),%r14
L44:
  mov    $0x24,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L84
  cmpb   $0x7b,0x1(%rax)
  jne    L84
  lea    0x2(%rax),%rdi
  call   <findRbrace@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L84
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %ebx,%edx
  sub    %r13d,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strncat@plt>
  movslq %ebp,%rbp
  add    %rbx,%rbp
  sub    %r13,%rbp
  movb   $0x0,(%r14,%rbp,1)
  mov    %r12,%r13
  sub    %rbx,%r13
  lea    0x2(%r13),%edi
  call   <__builtin_alloca@plt>
  mov    %rax,%rbp
  lea    0x1(%r13),%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%rbp,%r13,1)
  mov    %rbp,%rdi
  call   <subterm@plt>
  mov    %rax,%rbp
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    $0x3e7,%ebx
  jg     L73
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  lea    0x1(%r12),%r13
  jmp    L44
L84:
  lea    D38(%rip),%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    %r15,%rax
  cmp    $0x3e7,%ebx
  jle    L12
L66:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    %r13,%rsi
  lea    D38(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  jmp    L66
L73:
  mov    %r15,%rax
  jmp    L66
```

tool_calls: name: unpack_data
arguments: data_label: D39
data_type: string

tool: 

assistant: ```c
char *findterm(char *s) {
  char *p, *q, *r, *r2, *ss = s;
  static char ans[1000];
  int nans;
  if (!strlen(s))
    return "";
  ans[0] = '\0';
  while (1) {
    p = strchr(s, '$');
    if (!p || p[1] != '{')
      break;
    q = findRbrace(p + 2);
    if (!q)
      break;
    nans = strlen(ans);
    strncat(ans, s, p - s);
    ans[nans + p - s] = '\0';
    r = (char *)__builtin_alloca((q - p + 2));
    strncpy(r, p, q - p + 1);
    r[q - p + 1] = '\0';
    r2 = subterm(r);
    if (strlen(ans) + strlen(r2) < 1000)
      strcat(ans, r2);
    else
      return ss;
    s = q + 1;
  }
  if (strlen(ans) + strlen(s) < 1000)
    strcat(ans, s);
  else
    return ss;
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findterm>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r8d
  lea    D14(%rip),%rax
  test   %r8d,%r8d
  je     L18
  movb   $0x0,D23(%rip)
  mov    %r15,%r13
  lea    D23(%rip),%r14
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L10:
  cmpb   $0x7b,0x1(%rax)
  jne    L39
  lea    0x2(%rax),%rdi
  call   <findRbrace@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L39
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  movslq %eax,%rbx
  sub    %r13d,%edx
  call   <strncat@plt>
  add    %rbp,%rbx
  sub    %r13,%rbx
  movb   $0x0,(%r14,%rbx,1)
  mov    %r12,%rbx
  sub    %rbp,%rbx
  lea    0x2(%rbx),%edi
  call   <__builtin_alloca@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%r13,%rbx,1)
  mov    %r13,%rdi
  call   <subterm@plt>
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    $0x3e7,%ebx
  jg     L34
  mov    %rbp,%rsi
  mov    %r14,%rdi
  lea    0x1(%r12),%r13
  call   <strcat@plt>
L33:
  mov    $0x24,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L10
L39:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    $0x3e7,%ebx
  jle    L32
L34:
  mov    %r15,%rax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  lea    D23(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
data_type: string

tool: 

assistant: ```c
char *findterm(char *s) {
  char *p, *q, *r, *r2, *ss = s;
  static char ans[1000];
  int nans;
  if (!strlen(s))
    return "";
  ans[0] = '\0';
  while (1) {
    p = strchr(s, '$');
    if (!p || p[1] != '{')
      break;
    q = findRbrace(p + 2);
    if (!q)
      break;
    nans = strlen(ans);
    strncat(ans, s, p - s);
    ans[nans + p - s] = '\0';
    r = (char *)__builtin_alloca((q - p + 2));
    strncpy(r, p, q - p + 1);
    r[q - p + 1] = '\0';
    r2 = subterm(r);
    if (strlen(ans) + strlen(r2) < 1000)
      strcat(ans, r2);
    else
      return ss;
    s = q + 1;
  }
  if (strlen(ans) + strlen(s) < 1000)
    strcat(ans, s);
  else
    return ss;
  return ans;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findterm>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r8d
  lea    D4(%rip),%rax
  test   %r8d,%r8d
  je     L20
  movb   $0x0,D21(%rip)
  mov    %r15,%r13
  lea    D21(%rip),%r14
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L0:
  cmpb   $0x7b,0x1(%rax)
  jne    L30
  lea    0x2(%rax),%rdi
  call   <findRbrace@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L30
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  movslq %eax,%rbx
  sub    %r13d,%edx
  call   <strncat@plt>
  add    %rbp,%rbx
  sub    %r13,%rbx
  movb   $0x0,(%r14,%rbx,1)
  mov    %r12,%rbx
  sub    %rbp,%rbx
  lea    0x2(%rbx),%edi
  call   <__builtin_alloca@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%r13,%rbx,1)
  mov    %r13,%rdi
  call   <subterm@plt>
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    $0x3e7,%ebx
  jg     L68
  mov    %rbp,%rsi
  mov    %r14,%rdi
  lea    0x1(%r12),%r13
  call   <strcat@plt>
L10:
  mov    $0x24,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L0
L30:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    $0x3e7,%ebx
  jle    L35
L68:
  mov    %r15,%rax
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  lea    D21(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: 

assistant: ```c
char *findterm(char *s) {
  char *p, *q, *r, *r2, *ss = s;
  static char ans[1000];
  int nans;
  if (!strlen(s))
    return "";
  ans[0] = '\0';
  while (1) {
    p = strchr(s, '$');
    if (!p || p[1] != '{')
      break;
    q = findRbrace(p + 2);
    if (!q)
      break;
    nans = strlen(ans);
    strncat(ans, s, p - s);
    ans[nans + p - s] = '\0';
    r = (char *)__builtin_alloca((q - p + 2));
    strncpy(r, p, q - p + 1);
    r[q - p + 1] = '\0';
    r2 = subterm(r);
    if (strlen(ans) + strlen(r2) < 1000)
      strcat(ans, r2);
    else
      return ss;
    s = q + 1;
  }
  if (strlen(ans) + strlen(s) < 1000)
    strcat(ans, s);
  else
    return ss;
  return ans;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<regCaseEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L36
  mov    $0x0,%eax
  jmp    L57
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L48:
  mov    $0x1,%eax
  jmp    L57
L8:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L5
L57:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int regCaseEqual(char *s1, char *s2) {
  while (1) {
    if (toupper(*s1) != toupper(*s2))
      return 0;
    if (*s1 == '\0' || *s2 == '\0')
      return 1;
    s1++;
    s2++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<regCaseEqual>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  jmp    L52
L46:
  add    $0x1,%rbx
  add    $0x1,%rbp
L52:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %rax,%r12
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  cmp    %rax,%r12
  jne    L44
  cmpb   $0x0,(%rbx)
  je     L21
  cmpb   $0x0,0x0(%rbp)
  jne    L46
  mov    $0x1,%eax
  jmp    L42
L44:
  mov    $0x0,%eax
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    $0x1,%eax
  jmp    L42
```

assistant: ```c
int regCaseEqual(char *s1, char *s2) {
  while (1) {
    if (toupper(*s1) != toupper(*s2))
      return 0;
    if (*s1 == '\0' || *s2 == '\0')
      return 1;
    s1++;
    s2++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<regCaseEqual>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L31
L36:
  cmpb   $0x0,(%rbx)
  je     L28
  cmpb   $0x0,0x0(%rbp)
  je     L28
  add    $0x1,%rbx
  add    $0x1,%rbp
L31:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  call   <toupper@plt>
  cmp    %rax,%r12
  je     L36
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int regCaseEqual(char *s1, char *s2) {
  while (1) {
    if (toupper(*s1) != toupper(*s2))
      return 0;
    if (*s1 == '\0' || *s2 == '\0')
      return 1;
    s1++;
    s2++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<regCaseEqual>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L39
L16:
  cmpb   $0x0,(%rbx)
  je     L35
  cmpb   $0x0,0x0(%rbp)
  je     L35
  add    $0x1,%rbx
  add    $0x1,%rbp
L39:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  call   <toupper@plt>
  cmp    %rax,%r12
  je     L16
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int regCaseEqual(char *s1, char *s2) {
  while (1) {
    if (toupper(*s1) != toupper(*s2))
      return 0;
    if (*s1 == '\0' || *s2 == '\0')
      return 1;
    s1++;
    s2++;
  }
}
```