ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<init_cong_ctrl>:
  endbr64
  movw   $0x1,0x10(%rdi)
  movw   $0x1,0xe(%rdi)
  movw   $0x1,0xc(%rdi)
  movw   $0x1,0xa(%rdi)
  movw   $0x1,0x8(%rdi)
  movw   $0x1,0x6(%rdi)
  movw   $0x1,0x4(%rdi)
  movw   $0x1,0x2(%rdi)
  movw   $0x1,(%rdi)
  movw   $0x2,0x12(%rdi)
  movw   $0x3,0x14(%rdi)
  movw   $0x4,0x16(%rdi)
  movw   $0x5,0x18(%rdi)
  movw   $0x6,0x1a(%rdi)
  movw   $0x7,0x1c(%rdi)
  movw   $0x8,0x1e(%rdi)
  movw   $0x9,0x20(%rdi)
  movw   $0xa,0x22(%rdi)
  movw   $0xe,0x24(%rdi)
  movw   $0x11,0x26(%rdi)
  movw   $0x15,0x28(%rdi)
  movw   $0x19,0x2a(%rdi)
  movw   $0x1e,0x2c(%rdi)
  movw   $0x23,0x2e(%rdi)
  movw   $0x2d,0x30(%rdi)
  movw   $0x3c,0x32(%rdi)
  movw   $0x50,0x34(%rdi)
  movw   $0x64,0x36(%rdi)
  movw   $0xc8,0x38(%rdi)
  movw   $0x12c,0x3a(%rdi)
  movw   $0x190,0x3c(%rdi)
  movw   $0x1f4,0x3e(%rdi)
  movw   $0x0,0x10(%rsi)
  movw   $0x0,0xe(%rsi)
  movw   $0x0,0xc(%rsi)
  movw   $0x0,0xa(%rsi)
  movw   $0x0,0x8(%rsi)
  movw   $0x0,0x6(%rsi)
  movw   $0x0,0x4(%rsi)
  movw   $0x0,0x2(%rsi)
  movw   $0x0,(%rsi)
  movw   $0x1,0x14(%rsi)
  movw   $0x1,0x12(%rsi)
  movw   $0x2,0x18(%rsi)
  movw   $0x2,0x16(%rsi)
  movw   $0x3,0x20(%rsi)
  movw   $0x3,0x1e(%rsi)
  movw   $0x3,0x1c(%rsi)
  movw   $0x3,0x1a(%rsi)
  movw   $0x4,0x2a(%rsi)
  movw   $0x4,0x28(%rsi)
  movw   $0x4,0x26(%rsi)
  movw   $0x4,0x24(%rsi)
  movw   $0x4,0x22(%rsi)
  movw   $0x5,0x36(%rsi)
  movw   $0x5,0x34(%rsi)
  movw   $0x5,0x32(%rsi)
  movw   $0x5,0x30(%rsi)
  movw   $0x5,0x2e(%rsi)
  movw   $0x5,0x2c(%rsi)
  movw   $0x6,0x3a(%rsi)
  movw   $0x6,0x38(%rsi)
  movw   $0x7,0x3e(%rsi)
  movw   $0x7,0x3c(%rsi)
  ret
```

assistant: ```c
void init_cong_ctrl(unsigned short *a, unsigned short *b) {
  a[0] = a[1] = a[2] = a[3] = a[4] = a[5] = a[6] = a[7] = a[8] = 1;
  a[9] = 2;
  a[10] = 3;
  a[11] = 4;
  a[12] = 5;
  a[13] = 6;
  a[14] = 7;
  a[15] = 8;
  a[16] = 9;
  a[17] = 10;
  a[18] = 14;
  a[19] = 17;
  a[20] = 21;
  a[21] = 25;
  a[22] = 30;
  a[23] = 35;
  a[24] = 45;
  a[25] = 60;
  a[26] = 80;
  a[27] = 100;
  a[28] = 200;
  a[29] = 300;
  a[30] = 400;
  a[31] = 500;
  b[0] = b[1] = b[2] = b[3] = b[4] = b[5] = b[6] = b[7] = b[8] = 0;
  b[9] = b[10] = 1;
  b[11] = b[12] = 2;
  b[13] = b[14] = b[15] = b[16] = 3;
  b[17] = b[18] = b[19] = b[20] = b[21] = 4;
  b[22] = b[23] = b[24] = b[25] = b[26] = b[27] = 5;
  b[28] = b[29] = 6;
  b[30] = b[31] = 7;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_cong_ctrl>:
  endbr64
  movabs $0x1000100010001,%rax
  mov    %rax,(%rdi)
  mov    %rax,0x8(%rdi)
  movabs $0x4000300020001,%rax
  mov    %rax,0x10(%rdi)
  movabs $0x8000700060005,%rax
  mov    %rax,0x18(%rdi)
  movabs $0x11000e000a0009,%rax
  mov    %rax,0x20(%rdi)
  movabs $0x23001e00190015,%rax
  mov    %rax,0x28(%rdi)
  movabs $0x640050003c002d,%rax
  mov    %rax,0x30(%rdi)
  movabs $0x1f40190012c00c8,%rax
  mov    %rax,0x38(%rdi)
  movabs $0x2000100010000,%rax
  mov    %rax,0x10(%rsi)
  movabs $0x3000300030002,%rax
  mov    %rax,0x18(%rsi)
  movabs $0x4000400040003,%rax
  mov    %rax,0x20(%rsi)
  movabs $0x5000500040004,%rax
  mov    %rax,0x28(%rsi)
  add    $0x10001,%rax
  mov    %rax,0x30(%rsi)
  movabs $0x7000700060006,%rax
  movq   $0x0,(%rsi)
  movq   $0x0,0x8(%rsi)
  mov    %rax,0x38(%rsi)
  ret
```

assistant: ```c
void init_cong_ctrl(unsigned short *a, unsigned short *b) {
  a[0] = a[1] = a[2] = a[3] = a[4] = a[5] = a[6] = a[7] = a[8] = 1;
  a[9] = 2;
  a[10] = 3;
  a[11] = 4;
  a[12] = 5;
  a[13] = 6;
  a[14] = 7;
  a[15] = 8;
  a[16] = 9;
  a[17] = 10;
  a[18] = 14;
  a[19] = 17;
  a[20] = 21;
  a[21] = 25;
  a[22] = 30;
  a[23] = 35;
  a[24] = 45;
  a[25] = 60;
  a[26] = 80;
  a[27] = 100;
  a[28] = 200;
  a[29] = 300;
  a[30] = 400;
  a[31] = 500;
  b[0] = b[1] = b[2] = b[3] = b[4] = b[5] = b[6] = b[7] = b[8] = 0;
  b[9] = b[10] = 1;
  b[11] = b[12] = 2;
  b[13] = b[14] = b[15] = b[16] = 3;
  b[17] = b[18] = b[19] = b[20] = b[21] = 4;
  b[22] = b[23] = b[24] = b[25] = b[26] = b[27] = 5;
  b[28] = b[29] = 6;
  b[30] = b[31] = 7;
}
```
user: What is the c source code of the assembly code below:

```asm
<init_cong_ctrl>:
  endbr64
  movdqa D60(%rip),%xmm0
  movups %xmm0,(%rdi)
  movdqa D63(%rip),%xmm0
  movups %xmm0,0x10(%rdi)
  movdqa D16(%rip),%xmm0
  movups %xmm0,0x20(%rdi)
  movdqa D62(%rip),%xmm0
  movups %xmm0,0x30(%rdi)
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rsi)
  movdqa D49(%rip),%xmm0
  movups %xmm0,0x10(%rsi)
  movdqa D52(%rip),%xmm0
  movups %xmm0,0x20(%rsi)
  movdqa D25(%rip),%xmm0
  movups %xmm0,0x30(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D60
type: byte[16]
name: retrieve_data
arguments: tag: D63
type: byte[16]
name: retrieve_data
arguments: tag: D16
type: byte[16]
name: retrieve_data
arguments: tag: D62
type: byte[16]
name: retrieve_data
arguments: tag: D49
type: byte[16]
name: retrieve_data
arguments: tag: D52
type: byte[16]
name: retrieve_data
arguments: tag: D25
type: byte[16]

tool: {"D60": [0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00]}

tool: {"D63": [0x01,0x00,0x02,0x00,0x03,0x00,0x04,0x00,0x05,0x00,0x06,0x00,0x07,0x00,0x08,0x00]}

tool: {"D16": [0x09,0x00,0x0a,0x00,0x0e,0x00,0x11,0x00,0x15,0x00,0x19,0x00,0x1e,0x00,0x23,0x00]}

tool: {"D62": [0x2d,0x00,0x3c,0x00,0x50,0x00,0x64,0x00,0xc8,0x00,0x2c,0x01,0x90,0x01,0xf4,0x01]}

tool: {"D49": [0x00,0x00,0x01,0x00,0x01,0x00,0x02,0x00,0x02,0x00,0x03,0x00,0x03,0x00,0x03,0x00]}

tool: {"D52": [0x03,0x00,0x04,0x00,0x04,0x00,0x04,0x00,0x04,0x00,0x04,0x00,0x05,0x00,0x05,0x00]}

tool: {"D25": [0x05,0x00,0x05,0x00,0x05,0x00,0x05,0x00,0x06,0x00,0x06,0x00,0x07,0x00,0x07,0x00]}

assistant: ```c
void init_cong_ctrl(unsigned short *a, unsigned short *b) {
  a[0] = a[1] = a[2] = a[3] = a[4] = a[5] = a[6] = a[7] = a[8] = 1;
  a[9] = 2;
  a[10] = 3;
  a[11] = 4;
  a[12] = 5;
  a[13] = 6;
  a[14] = 7;
  a[15] = 8;
  a[16] = 9;
  a[17] = 10;
  a[18] = 14;
  a[19] = 17;
  a[20] = 21;
  a[21] = 25;
  a[22] = 30;
  a[23] = 35;
  a[24] = 45;
  a[25] = 60;
  a[26] = 80;
  a[27] = 100;
  a[28] = 200;
  a[29] = 300;
  a[30] = 400;
  a[31] = 500;
  b[0] = b[1] = b[2] = b[3] = b[4] = b[5] = b[6] = b[7] = b[8] = 0;
  b[9] = b[10] = 1;
  b[11] = b[12] = 2;
  b[13] = b[14] = b[15] = b[16] = 3;
  b[17] = b[18] = b[19] = b[20] = b[21] = 4;
  b[22] = b[23] = b[24] = b[25] = b[26] = b[27] = 5;
  b[28] = b[29] = 6;
  b[30] = b[31] = 7;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_190_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_190_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T ^ S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rop3_190_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  xor    %esi,%edx
  or     (%rdi),%dl
  mov    %eax,%ecx
  not    %ecx
  and    %ecx,%edx
  and    (%rdi),%al
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_190_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T ^ S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rop3_190_1_1>:
  endbr64
  mov    %edx,%eax
  xor    %esi,%edx
  or     (%rdi),%dl
  or     %esi,%eax
  mov    %eax,%ecx
  and    (%rdi),%al
  not    %ecx
  and    %ecx,%edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_190_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T ^ S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_190_1_1>:
  endbr64
  mov    %edx,%eax
  xor    %esi,%edx
  or     (%rdi),%dl
  or     %esi,%eax
  mov    %eax,%ecx
  and    (%rdi),%al
  not    %ecx
  and    %ecx,%edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_190_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T ^ S;
  stk1 = *D | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: What is the c source code of the assembly code below?

```asm
<vowel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x61,-0x18(%rbp)
  je     L5
  cmpq   $0x41,-0x18(%rbp)
  je     L5
  cmpq   $0x65,-0x18(%rbp)
  je     L5
  cmpq   $0x45,-0x18(%rbp)
  je     L5
  cmpq   $0x69,-0x18(%rbp)
  je     L5
  cmpq   $0x49,-0x18(%rbp)
  je     L5
  cmpq   $0x6f,-0x18(%rbp)
  je     L5
  cmpq   $0x4f,-0x18(%rbp)
  je     L5
  cmpq   $0x75,-0x18(%rbp)
  je     L5
  cmpq   $0x55,-0x18(%rbp)
  jne    L53
L5:
  addl   $0x1,-0x4(%rbp)
L53:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int vowel(char a[]) {
  int count = 0;
  if (a == 'a' || a == 'A' || a == 'e' || a == 'E' || a == 'i' || a == 'I' || a == 'o' || a == 'O' || a == 'u' || a == 'U') {
    count++;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vowel>:
  endbr64
  cmp    $0x61,%rdi
  je     L27
  cmp    $0x41,%rdi
  je     L27
  cmp    $0x65,%rdi
  je     L68
  cmp    $0x45,%rdi
  je     L68
  cmp    $0x69,%rdi
  je     L47
  cmp    $0x49,%rdi
  je     L47
  cmp    $0x6f,%rdi
  je     L20
  cmp    $0x4f,%rdi
  je     L20
  cmp    $0x75,%rdi
  sete   %al
  cmp    $0x55,%rdi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
L27:
  mov    $0x1,%eax
  ret
L68:
  mov    $0x1,%eax
  ret
L47:
  mov    $0x1,%eax
  ret
L20:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int vowel(char a[]) {
  int count = 0;
  if (a == 'a' || a == 'A' || a == 'e' || a == 'E' || a == 'i' || a == 'I' || a == 'o' || a == 'O' || a == 'u' || a == 'U') {
    count++;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vowel>:
  endbr64
  cmp    $0x61,%rdi
  je     L32
  cmp    $0x41,%rdi
  je     L32
  cmp    $0x65,%rdi
  je     L32
  cmp    $0x45,%rdi
  je     L32
  cmp    $0x69,%rdi
  je     L32
  cmp    $0x49,%rdi
  je     L32
  cmp    $0x6f,%rdi
  je     L32
  cmp    $0x4f,%rdi
  je     L32
  cmp    $0x75,%rdi
  sete   %al
  cmp    $0x55,%rdi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int vowel(char a[]) {
  int count = 0;
  if (a == 'a' || a == 'A' || a == 'e' || a == 'E' || a == 'i' || a == 'I' || a == 'o' || a == 'O' || a == 'u' || a == 'U') {
    count++;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vowel>:
  endbr64
  cmp    $0x61,%rdi
  je     L48
  cmp    $0x41,%rdi
  je     L48
  cmp    $0x65,%rdi
  je     L48
  cmp    $0x45,%rdi
  je     L48
  cmp    $0x69,%rdi
  je     L48
  cmp    $0x49,%rdi
  je     L48
  cmp    $0x6f,%rdi
  je     L48
  cmp    $0x4f,%rdi
  je     L48
  cmp    $0x75,%rdi
  sete   %al
  cmp    $0x55,%rdi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int vowel(char a[]) {
  int count = 0;
  if (a == 'a' || a == 'A' || a == 'e' || a == 'E' || a == 'i' || a == 'I' || a == 'o' || a == 'O' || a == 'u' || a == 'U') {
    count++;
  }
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<intrinit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <cli@plt>
  mov    $0x0,%edi
  call   <enable_irq@plt>
  mov    $0x1,%edi
  call   <enable_irq@plt>
  mov    $0x0,%eax
  call   <timerinit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void intrinit(void) {
  cli();
  enable_irq(0);
  enable_irq(1);
  timerinit();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<intrinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cli@plt>
  mov    $0x0,%edi
  call   <enable_irq@plt>
  mov    $0x1,%edi
  call   <enable_irq@plt>
  mov    $0x0,%eax
  call   <timerinit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void intrinit(void) {
  cli();
  enable_irq(0);
  enable_irq(1);
  timerinit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intrinit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cli@plt>
  xor    %edi,%edi
  call   <enable_irq@plt>
  mov    $0x1,%edi
  call   <enable_irq@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <timerinit@plt>
```

assistant: ```c
void intrinit(void) {
  cli();
  enable_irq(0);
  enable_irq(1);
  timerinit();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intrinit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cli@plt>
  xor    %edi,%edi
  call   <enable_irq@plt>
  mov    $0x1,%edi
  call   <enable_irq@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <timerinit@plt>
```

assistant: ```c
void intrinit(void) {
  cli();
  enable_irq(0);
  enable_irq(1);
  timerinit();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<adaptivereleasecurve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  addsd  -0x38(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double adaptivereleasecurve(double x, double a, double b, double c, double d) {
  double x2 = x * x;
  return a * x2 * x + b * x2 + c * x + d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<adaptivereleasecurve>:
  endbr64
  movapd %xmm0,%xmm5
  mulsd  %xmm0,%xmm5
  mulsd  %xmm5,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm5
  addsd  %xmm5,%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double adaptivereleasecurve(double x, double a, double b, double c, double d) {
  double x2 = x * x;
  return a * x2 * x + b * x2 + c * x + d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adaptivereleasecurve>:
  endbr64
  movapd %xmm0,%xmm5
  mulsd  %xmm0,%xmm5
  mulsd  %xmm5,%xmm1
  mulsd  %xmm2,%xmm5
  mulsd  %xmm0,%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm5,%xmm1
  addsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double adaptivereleasecurve(double x, double a, double b, double c, double d) {
  double x2 = x * x;
  return a * x2 * x + b * x2 + c * x + d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<adaptivereleasecurve>:
  endbr64
  movapd %xmm0,%xmm5
  mulsd  %xmm0,%xmm5
  mulsd  %xmm5,%xmm1
  mulsd  %xmm2,%xmm5
  mulsd  %xmm0,%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm5,%xmm1
  addsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double adaptivereleasecurve(double x, double a, double b, double c, double d) {
  double x2 = x * x;
  return a * x2 * x + b * x2 + c * x + d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<genCSName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movl   $0x1,-0x8(%rbp)
  jmp    L31
L8:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L46
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L46:
  cmpb   $0x5f,-0xd(%rbp)
  jne    L43
  movl   $0x1,-0xc(%rbp)
  jmp    L20
L43:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
L20:
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L8
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void genCSName(char *out, const char *name) {
  bool upperCaseNext = false;
  int len = (int)strlen(name);
  *out++ = (char)toupper(name[0]);
  for (int i = 1; i < len; ++i) {
    char c = name[i];
    if (upperCaseNext) {
      *out++ = (char)toupper(c);
      upperCaseNext = false;
    } else {
      if (c == '_')
        upperCaseNext = true;
      else
        *out++ = c;
    }
  }
  *out = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<genCSName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  movsbl (%r12),%edi
  call   <toupper@plt>
  lea    0x1(%rbx),%rbp
  mov    %al,(%rbx)
  cmp    $0x1,%r13d
  jle    L36
  lea    0x1(%r12),%rbx
  lea    -0x2(%r13),%eax
  lea    0x2(%r12,%rax,1),%r12
  mov    $0x0,%eax
  mov    $0x1,%r13d
  jmp    L28
L5:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  mov    $0x0,%eax
L37:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L36
L28:
  movzbl (%rbx),%edi
  test   %eax,%eax
  jne    L5
  cmp    $0x5f,%dil
  je     L41
  mov    %dil,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L37
L41:
  mov    %r13d,%eax
  jmp    L37
L36:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void genCSName(char *out, const char *name) {
  bool upperCaseNext = false;
  int len = (int)strlen(name);
  *out++ = (char)toupper(name[0]);
  for (int i = 1; i < len; ++i) {
    char c = name[i];
    if (upperCaseNext) {
      *out++ = (char)toupper(c);
      upperCaseNext = false;
    } else {
      if (c == '_')
        upperCaseNext = true;
      else
        *out++ = c;
    }
  }
  *out = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<genCSName>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  lea    0x1(%rbx),%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  movsbl (%r12),%edi
  mov    %rax,%r13
  call   <toupper@plt>
  mov    %al,(%rbx)
  cmp    $0x1,%r13d
  jle    L49
  lea    -0x2(%r13),%eax
  lea    0x1(%r12),%rbx
  lea    0x2(%r12,%rax,1),%r12
  xor    %eax,%eax
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L53:
  cmp    $0x5f,%dil
  je     L4
  mov    %dil,0x0(%rbp)
  add    $0x1,%rbp
L50:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L49
L58:
  movsbl (%rbx),%edi
  test   %eax,%eax
  je     L53
  call   <toupper@plt>
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  xor    %eax,%eax
  cmp    %r12,%rbx
  jne    L58
L49:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1,%eax
  jmp    L50
```

assistant: ```c
void genCSName(char *out, const char *name) {
  bool upperCaseNext = false;
  int len = (int)strlen(name);
  *out++ = (char)toupper(name[0]);
  for (int i = 1; i < len; ++i) {
    char c = name[i];
    if (upperCaseNext) {
      *out++ = (char)toupper(c);
      upperCaseNext = false;
    } else {
      if (c == '_')
        upperCaseNext = true;
      else
        *out++ = c;
    }
  }
  *out = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<genCSName>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  lea    0x1(%rbx),%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  movsbl (%r12),%edi
  mov    %rax,%r13
  call   <toupper@plt>
  mov    %al,(%rbx)
  cmp    $0x1,%r13d
  jle    L21
  lea    -0x2(%r13),%eax
  lea    0x1(%r12),%rbx
  lea    0x2(%r12,%rax,1),%r12
  xor    %eax,%eax
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L30:
  cmp    $0x5f,%dil
  je     L37
  mov    %dil,0x0(%rbp)
  add    $0x1,%rbp
L40:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L21
L36:
  movsbl (%rbx),%edi
  test   %eax,%eax
  je     L30
  call   <toupper@plt>
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  xor    %eax,%eax
  cmp    %r12,%rbx
  jne    L36
L21:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L37:
  mov    $0x1,%eax
  jmp    L40
```

assistant: ```c
void genCSName(char *out, const char *name) {
  bool upperCaseNext = false;
  int len = (int)strlen(name);
  *out++ = (char)toupper(name[0]);
  for (int i = 1; i < len; ++i) {
    char c = name[i];
    if (upperCaseNext) {
      *out++ = (char)toupper(c);
      upperCaseNext = false;
    } else {
      if (c == '_')
        upperCaseNext = true;
      else
        *out++ = c;
    }
  }
  *out = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitreverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  or     %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L1:
  shll   -0xc(%rbp)
  sarl   -0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  or     %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jb     L1
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitreverse(int input, int N) {
  unsigned int n = 0, i, bit;
  bit = input & 1;
  n |= bit;
  for (i = 0; i < N - 1; i++) {
    n <<= 1;
    input >>= 1;
    bit = input & 1;
    n |= bit;
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitreverse>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    $0x1,%esi
  je     L3
  sub    $0x1,%esi
  mov    $0x0,%edx
L2:
  add    %eax,%eax
  sar    %edi
  mov    %edi,%ecx
  and    $0x1,%ecx
  or     %ecx,%eax
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L2
L3:
  ret
```

assistant: ```c
int bitreverse(int input, int N) {
  unsigned int n = 0, i, bit;
  bit = input & 1;
  n |= bit;
  for (i = 0; i < N - 1; i++) {
    n <<= 1;
    input >>= 1;
    bit = input & 1;
    n |= bit;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitreverse>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    $0x1,%esi
  je     L14
  sub    $0x1,%esi
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L11:
  sar    %edi
  add    %eax,%eax
  add    $0x1,%edx
  mov    %edi,%ecx
  and    $0x1,%ecx
  or     %ecx,%eax
  cmp    %esi,%edx
  jne    L11
L14:
  ret
```

assistant: ```c
int bitreverse(int input, int N) {
  unsigned int n = 0, i, bit;
  bit = input & 1;
  n |= bit;
  for (i = 0; i < N - 1; i++) {
    n <<= 1;
    input >>= 1;
    bit = input & 1;
    n |= bit;
  }
  return n;
}
```