ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<countingBits1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x55555555,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    %eax
  and    $0x55555555,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf0f0f0f,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xff00ff,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int countingBits1(int value) {
  int tmp = value;
  tmp = (tmp & 0x55555555) + ((tmp >> 1) & 0x55555555);
  tmp = (tmp & 0x33333333) + ((tmp >> 2) & 0x33333333);
  tmp = (tmp & 0x0F0F0F0F) + ((tmp >> 4) & 0x0F0F0F0F);
  tmp = (tmp & 0x00FF00FF) + ((tmp >> 8) & 0x00FF00FF);
  tmp = (tmp & 0x0000FFFF) + ((tmp >> 16) & 0x0000FFFF);
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<countingBits1>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  and    $0x55555555,%edi
  add    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  and    $0xf0f0f0f,%eax
  sar    $0x4,%edx
  and    $0xf0f0f0f,%edx
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xff00ff,%edx
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  add    %eax,%edx
  movzwl %dx,%eax
  shr    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int countingBits1(int value) {
  int tmp = value;
  tmp = (tmp & 0x55555555) + ((tmp >> 1) & 0x55555555);
  tmp = (tmp & 0x33333333) + ((tmp >> 2) & 0x33333333);
  tmp = (tmp & 0x0F0F0F0F) + ((tmp >> 4) & 0x0F0F0F0F);
  tmp = (tmp & 0x00FF00FF) + ((tmp >> 8) & 0x00FF00FF);
  tmp = (tmp & 0x0000FFFF) + ((tmp >> 16) & 0x0000FFFF);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<countingBits1>:
  endbr64
  mov    %edi,%eax
  and    $0x55555555,%edi
  sar    %eax
  and    $0x55555555,%eax
  add    %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%edx
  and    $0xf0f0f0f,%edx
  and    $0xf0f0f0f,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  and    $0xff00ff,%edx
  add    %eax,%edx
  movzwl %dx,%eax
  shr    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int countingBits1(int value) {
  int tmp = value;
  tmp = (tmp & 0x55555555) + ((tmp >> 1) & 0x55555555);
  tmp = (tmp & 0x33333333) + ((tmp >> 2) & 0x33333333);
  tmp = (tmp & 0x0F0F0F0F) + ((tmp >> 4) & 0x0F0F0F0F);
  tmp = (tmp & 0x00FF00FF) + ((tmp >> 8) & 0x00FF00FF);
  tmp = (tmp & 0x0000FFFF) + ((tmp >> 16) & 0x0000FFFF);
  return tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<countingBits1>:
  endbr64
  mov    %edi,%eax
  and    $0x55555555,%edi
  sar    %eax
  and    $0x55555555,%eax
  add    %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%edx
  and    $0xf0f0f0f,%edx
  and    $0xf0f0f0f,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  and    $0xff00ff,%edx
  add    %eax,%edx
  movzwl %dx,%eax
  shr    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int countingBits1(int value) {
  int tmp = value;
  tmp = (tmp & 0x55555555) + ((tmp >> 1) & 0x55555555);
  tmp = (tmp & 0x33333333) + ((tmp >> 2) & 0x33333333);
  tmp = (tmp & 0x0F0F0F0F) + ((tmp >> 4) & 0x0F0F0F0F);
  tmp = (tmp & 0x00FF00FF) + ((tmp >> 8) & 0x00FF00FF);
  tmp = (tmp & 0x0000FFFF) + ((tmp >> 16) & 0x0000FFFF);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<streqci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x60,-0x2(%rbp)
  jle    L32
  cmpb   $0x7a,-0x2(%rbp)
  jg     L32
  movzbl -0x2(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x2(%rbp)
L32:
  cmpb   $0x60,-0x1(%rbp)
  jle    L37
  cmpb   $0x7a,-0x1(%rbp)
  jg     L37
  movzbl -0x1(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x1(%rbp)
L37:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L31
  mov    $0x0,%eax
  jmp    L9
L31:
  cmpb   $0x0,-0x2(%rbp)
  je     L8
  jmp    L4
L8:
  nop
  mov    $0x1,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int streqci(const char *s1, const char *s2) {
  for (;;) {
    char c1 = *s1++;
    char c2 = *s2++;
    if (0x61 <= c1 && c1 <= 0x7A)
      c1 += 0x41 - 0x61;
    if (0x61 <= c2 && c2 <= 0x7A)
      c2 += 0x41 - 0x61;
    if (c1 != c2)
      return 0;
    if (!c1)
      break;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<streqci>:
  endbr64
  mov    $0x0,%ecx
L9:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x61(%rax),%r9d
  lea    -0x20(%rax),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%eax
  lea    -0x61(%rdx),%r9d
  lea    -0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  cmp    %dl,%al
  jne    L1
  add    $0x1,%rcx
  test   %al,%al
  jne    L9
  mov    $0x1,%eax
  ret
L1:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int streqci(const char *s1, const char *s2) {
  for (;;) {
    char c1 = *s1++;
    char c2 = *s2++;
    if (0x61 <= c1 && c1 <= 0x7A)
      c1 += 0x41 - 0x61;
    if (0x61 <= c2 && c2 <= 0x7A)
      c2 += 0x41 - 0x61;
    if (c1 != c2)
      return 0;
    if (!c1)
      break;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<streqci>:
  endbr64
  xor    %ecx,%ecx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rcx
  test   %al,%al
  je     L28
L23:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x61(%rax),%r9d
  lea    -0x20(%rax),%r8d
  cmp    $0x1a,%r9b
  lea    -0x61(%rdx),%r9d
  cmovb  %r8d,%eax
  lea    -0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  cmp    %dl,%al
  je     L11
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int streqci(const char *s1, const char *s2) {
  for (;;) {
    char c1 = *s1++;
    char c2 = *s2++;
    if (0x61 <= c1 && c1 <= 0x7A)
      c1 += 0x41 - 0x61;
    if (0x61 <= c2 && c2 <= 0x7A)
      c2 += 0x41 - 0x61;
    if (c1 != c2)
      return 0;
    if (!c1)
      break;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<streqci>:
  endbr64
  xor    %ecx,%ecx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x1,%rcx
  test   %al,%al
  je     L24
L19:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x61(%rax),%r9d
  lea    -0x20(%rax),%r8d
  cmp    $0x1a,%r9b
  lea    -0x61(%rdx),%r9d
  cmovb  %r8d,%eax
  lea    -0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  cmp    %dl,%al
  je     L21
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int streqci(const char *s1, const char *s2) {
  for (;;) {
    char c1 = *s1++;
    char c2 = *s2++;
    if (0x61 <= c1 && c1 <= 0x7A)
      c1 += 0x41 - 0x61;
    if (0x61 <= c2 && c2 <= 0x7A)
      c2 += 0x41 - 0x61;
    if (c1 != c2)
      return 0;
    if (!c1)
      break;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stbi_write_tga_w>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%esi
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x24(%rbp),%r8d
  mov    -0x20(%rbp),%edi
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  push   %rsi
  push   %rcx
  mov    -0x20(%rbp),%ecx
  push   %rcx
  mov    -0x1c(%rbp),%ecx
  push   %rcx
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x2
  push   $0x0
  push   $0x0
  lea    D9(%rip),%rcx
  push   %rcx
  push   $0x0
  mov    -0x4(%rbp),%ecx
  push   %rcx
  push   -0x30(%rbp)
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <outfile_w@plt>
  sub    $0xffffffffffffff80,%rsp
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: 111 221 2222 11

assistant: ```c
int stbi_write_tga_w(wchar_t const *filename, int x, int y, int comp, const void *data) {
  int has_alpha = !(comp & 1);
  return outfile_w(filename, -1, -1, x, y, comp, data, has_alpha, 0, "111 221 2222 11", 0, 0, 2, 0, 0, 0, 0, 0, x, y, 24 + 8 * has_alpha, 8 * has_alpha);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi_write_tga_w>:
  endbr64
  sub    $0x8,%rsp
  mov    %ecx,%r9d
  test   $0x1,%cl
  sete   %cl
  movzbl %cl,%ecx
  lea    0x0(,%rcx,8),%eax
  push   %rax
  add    $0x18,%eax
  push   %rax
  push   %rdx
  push   %rsi
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x2
  push   $0x0
  push   $0x0
  lea    D3(%rip),%rax
  push   %rax
  push   $0x0
  push   %rcx
  push   %r8
  mov    %edx,%r8d
  mov    %esi,%ecx
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  call   <outfile_w@plt>
  add    $0x88,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: 111 221 2222 11

assistant: ```c
int stbi_write_tga_w(wchar_t const *filename, int x, int y, int comp, const void *data) {
  int has_alpha = !(comp & 1);
  return outfile_w(filename, -1, -1, x, y, comp, data, has_alpha, 0, "111 221 2222 11", 0, 0, 2, 0, 0, 0, 0, 0, x, y, 24 + 8 * has_alpha, 8 * has_alpha);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stbi_write_tga_w>:
  endbr64
  mov    %ecx,%eax
  sub    $0x8,%rsp
  mov    %ecx,%r9d
  mov    %esi,%r10d
  not    %eax
  and    $0x1,%eax
  lea    0x0(,%rax,8),%ecx
  push   %rcx
  add    $0x18,%ecx
  push   %rcx
  mov    %r10d,%ecx
  push   %rdx
  push   %rsi
  lea    D4(%rip),%rsi
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x2
  push   $0x0
  push   $0x0
  push   %rsi
  mov    $0xffffffff,%esi
  push   $0x0
  push   %rax
  push   %r8
  mov    %edx,%r8d
  mov    $0xffffffff,%edx
  call   <outfile_w@plt>
  add    $0x88,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: 111 221 2222 11

assistant: ```c
int stbi_write_tga_w(wchar_t const *filename, int x, int y, int comp, const void *data) {
  int has_alpha = !(comp & 1);
  return outfile_w(filename, -1, -1, x, y, comp, data, has_alpha, 0, "111 221 2222 11", 0, 0, 2, 0, 0, 0, 0, 0, x, y, 24 + 8 * has_alpha, 8 * has_alpha);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi_write_tga_w>:
  endbr64
  mov    %ecx,%eax
  sub    $0x8,%rsp
  mov    %ecx,%r9d
  mov    %esi,%r10d
  not    %eax
  and    $0x1,%eax
  lea    0x0(,%rax,8),%ecx
  push   %rcx
  add    $0x18,%ecx
  push   %rcx
  mov    %r10d,%ecx
  push   %rdx
  push   %rsi
  lea    D2(%rip),%rsi
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x2
  push   $0x0
  push   $0x0
  push   %rsi
  mov    $0xffffffff,%esi
  push   $0x0
  push   %rax
  push   %r8
  mov    %edx,%r8d
  mov    $0xffffffff,%edx
  call   <outfile_w@plt>
  add    $0x88,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: 111 221 2222 11

assistant: ```c
int stbi_write_tga_w(wchar_t const *filename, int x, int y, int comp, const void *data) {
  int has_alpha = !(comp & 1);
  return outfile_w(filename, -1, -1, x, y, comp, data, has_alpha, 0, "111 221 2222 11", 0, 0, 2, 0, 0, 0, 0, 0, x, y, 24 + 8 * has_alpha, 8 * has_alpha);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lz_strincmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L33
L72:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L12
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jge    L11
  mov    $0xffffffff,%eax
  jmp    L34
L11:
  mov    $0x1,%eax
  jmp    L34
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
  mov    $0x0,%eax
  jmp    L34
L60:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  subq   $0x1,-0x28(%rbp)
L33:
  cmpq   $0x0,-0x28(%rbp)
  jne    L72
  mov    $0x0,%eax
L34:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int lz_strincmp(char *src, char *dst, size_t n) {
  for (; n > 0; src++, dst++, --n)
    if (toupper(*src) != toupper(*dst))
      return ((toupper(*(unsigned char *)src) < toupper(*(unsigned char *)dst)) ? -1 : 1);
    else if (*src == '\0')
      return 0;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lz_strincmp>:
  endbr64
  test   %rdx,%rdx
  je     L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  lea    (%rdi,%rdx,1),%r13
L42:
  movzbl (%rbx),%edi
  call   <toupper@plt>
  mov    %rax,%rbp
  movzbl (%r12),%edi
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L13
  cmpb   $0x0,(%rbx)
  je     L34
  add    $0x1,%rbx
  add    $0x1,%r12
  cmp    %rbx,%r13
  jne    L42
  mov    $0x0,%eax
  jmp    L30
L13:
  movzbl (%rbx),%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  movzbl (%r12),%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0x0,%eax
  ret
L34:
  mov    $0x0,%eax
  jmp    L30
```

assistant: ```c
int lz_strincmp(char *src, char *dst, size_t n) {
  for (; n > 0; src++, dst++, --n)
    if (toupper(*src) != toupper(*dst))
      return ((toupper(*(unsigned char *)src) < toupper(*(unsigned char *)dst)) ? -1 : 1);
    else if (*src == '\0')
      return 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lz_strincmp>:
  endbr64
  test   %rdx,%rdx
  je     L32
  push   %r13
  lea    (%rdi,%rdx,1),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L16:
  cmpb   $0x0,(%rbx)
  je     L28
  add    $0x1,%rbx
  add    $0x1,%r12
  cmp    %rbx,%r13
  je     L28
L35:
  movzbl (%rbx),%edi
  call   <toupper@plt>
  movzbl (%r12),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  je     L16
  movzbl (%rbx),%edi
  call   <toupper@plt>
  movzbl (%r12),%edi
  mov    %rax,%rbx
  call   <toupper@plt>
  cmp    %rax,%rbx
  setge  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  lea    -0x1(%rax,%rax,1),%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L28:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
int lz_strincmp(char *src, char *dst, size_t n) {
  for (; n > 0; src++, dst++, --n)
    if (toupper(*src) != toupper(*dst))
      return ((toupper(*(unsigned char *)src) < toupper(*(unsigned char *)dst)) ? -1 : 1);
    else if (*src == '\0')
      return 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lz_strincmp>:
  endbr64
  test   %rdx,%rdx
  je     L42
  push   %r13
  lea    (%rdi,%rdx,1),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L30:
  cmpb   $0x0,(%rbx)
  je     L22
  add    $0x1,%rbx
  add    $0x1,%r12
  cmp    %rbx,%r13
  je     L22
L47:
  movzbl (%rbx),%edi
  call   <toupper@plt>
  movzbl (%r12),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  je     L30
  movzbl (%rbx),%edi
  call   <toupper@plt>
  movzbl (%r12),%edi
  mov    %rax,%rbx
  call   <toupper@plt>
  cmp    %rax,%rbx
  setge  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  lea    -0x1(%rax,%rax,1),%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
int lz_strincmp(char *src, char *dst, size_t n) {
  for (; n > 0; src++, dst++, --n)
    if (toupper(*src) != toupper(*dst))
      return ((toupper(*(unsigned char *)src) < toupper(*(unsigned char *)dst)) ? -1 : 1);
    else if (*src == '\0')
      return 0;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_swaps_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rbx
  mov    -0x40(%rbp),%r12
  cmp    %r12,%rbx
  je     L43
  add    $0x2,%rbx
  addl   $0x1,-0x44(%rbp)
  jmp    L59
L36:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  sub    $0x1,%rbx
  movzbl (%rax),%eax
  mov    %al,(%rbx)
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  sub    $0x1,%rbx
  movzbl (%rax),%eax
  mov    %al,(%rbx)
  add    $0x4,%rbx
L59:
  subl   $0x1,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jne    L36
  jmp    L2
L43:
  mov    -0x38(%rbp),%r13
  addl   $0x1,-0x44(%rbp)
  jmp    L42
L5:
  lea    -0x2c(%rbp),%rax
  lea    0x2(%rax),%rbx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  sub    $0x1,%rbx
  movzbl (%rax),%eax
  mov    %al,(%rbx)
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  sub    $0x1,%rbx
  movzbl (%rax),%eax
  mov    %al,(%rbx)
  mov    %r13,%rax
  lea    0x2(%rax),%r13
  movzwl -0x2c(%rbp),%edx
  mov    %dx,(%rax)
L42:
  subl   $0x1,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jne    L5
L2:
  nop
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  add    $0x38,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void _swaps_buffer(short *s2, short *s1, int n) {
  register char *p, *q;
  short r[2];
  register short *s;
  p = (char *)s2;
  q = (char *)s1;
  if (p != q) {
    p += sizeof(short);
    for (n++; --n; p += 2 * sizeof(short)) {
      *--p = *q++;
      *--p = *q++;
    }
  } else {
    for (s = s2, n++; --n; *s++ = r[0]) {
      p = (char *)&r[1];
      *--p = *q++;
      *--p = *q++;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_swaps_buffer>:
  endbr64
  cmp    %rsi,%rdi
  je     L11
  lea    0x2(%rdi),%rax
  test   %edx,%edx
  je     L6
  lea    -0x1(%rdx),%edx
  lea    0x4(%rdi,%rdx,2),%rcx
L33:
  movzbl (%rsi),%edx
  mov    %dl,-0x1(%rax)
  add    $0x2,%rsi
  movzbl -0x1(%rsi),%edx
  mov    %dl,-0x2(%rax)
  add    $0x2,%rax
  cmp    %rax,%rcx
  jne    L33
  ret
L11:
  test   %edx,%edx
  je     L6
  push   %rbx
  mov    %edx,%edx
  mov    $0x0,%eax
L32:
  movzbl (%rsi,%rax,2),%ebx
  mov    %bl,%ch
  mov    0x1(%rsi,%rax,2),%cl
  mov    %cx,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L32
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
void _swaps_buffer(short *s2, short *s1, int n) {
  register char *p, *q;
  short r[2];
  register short *s;
  p = (char *)s2;
  q = (char *)s1;
  if (p != q) {
    p += sizeof(short);
    for (n++; --n; p += 2 * sizeof(short)) {
      *--p = *q++;
      *--p = *q++;
    }
  } else {
    for (s = s2, n++; --n; *s++ = r[0]) {
      p = (char *)&r[1];
      *--p = *q++;
      *--p = *q++;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_swaps_buffer>:
  endbr64
  cmp    %rsi,%rdi
  je     L26
  lea    0x2(%rdi),%rax
  test   %edx,%edx
  je     L48
  sub    $0x1,%edx
  lea    0x4(%rdi,%rdx,2),%rcx
  nopl   0x0(%rax)
L34:
  movzbl (%rsi),%edx
  add    $0x2,%rsi
  add    $0x2,%rax
  mov    %dl,-0x3(%rax)
  movzbl -0x1(%rsi),%edx
  mov    %dl,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L34
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  test   %edx,%edx
  je     L48
  push   %rbx
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L38:
  mov    (%rsi,%rax,2),%ch
  mov    0x1(%rsi,%rax,2),%cl
  mov    %cx,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L38
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  ret
```

assistant: ```c
void _swaps_buffer(short *s2, short *s1, int n) {
  register char *p, *q;
  short r[2];
  register short *s;
  p = (char *)s2;
  q = (char *)s1;
  if (p != q) {
    p += sizeof(short);
    for (n++; --n; p += 2 * sizeof(short)) {
      *--p = *q++;
      *--p = *q++;
    }
  } else {
    for (s = s2, n++; --n; *s++ = r[0]) {
      p = (char *)&r[1];
      *--p = *q++;
      *--p = *q++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ipow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L16:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L16
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ipow(int m, int n) {
  int ret = 1;
  for (int i = 0; i < n; ++i)
    ret *= m;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ipow>:
  endbr64
  test   %esi,%esi
  jle    L5
  mov    $0x0,%eax
  mov    $0x1,%edx
L26:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L26
L21:
  mov    %edx,%eax
  ret
L5:
  mov    $0x1,%edx
  jmp    L21
```

assistant: ```c
int ipow(int m, int n) {
  int ret = 1;
  for (int i = 0; i < n; ++i)
    ret *= m;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ipow>:
  endbr64
  test   %esi,%esi
  jle    L7
  xor    %eax,%eax
  mov    $0x1,%r8d
L9:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L9
  mov    %r8d,%eax
  ret
  nop
L7:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ipow(int m, int n) {
  int ret = 1;
  for (int i = 0; i < n; ++i)
    ret *= m;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ipow>:
  endbr64
  test   %esi,%esi
  jle    L16
  xor    %eax,%eax
  mov    $0x1,%r8d
L5:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L5
  mov    %r8d,%eax
  ret
  nop
L16:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ipow(int m, int n) {
  int ret = 1;
  for (int i = 0; i < n; ++i)
    ret *= m;
  return ret;
}
```