user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_response_type>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,%r14d
  mov    %rdx,0x8(%rsp)
  lea    -0x7(%rsi),%r15d
  test   %r15d,%r15d
  jle    L183
  mov    %rdi,%rbp
  mov    %r15d,%r12d
  mov    $0x0,%ebx
  lea    D19(%rip),%r13
L9:
  mov    $0x7,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L210
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L9
  jmp    L136
L210:
  lea    0x7(%rbx),%r12d
L136:
  mov    $0xffffffff,%eax
  cmp    %r15d,%r12d
  je     L64
  movslq %r12d,%r12
  mov    $0x0,%eax
  mov    (%rsp),%rbp
  cmpb   $0x6c,0x0(%rbp,%r12,1)
  jne    L64
  mov    0x8(%rsp),%rax
  movl   $0x0,(%rax)
  lea    -0x10(%r14),%r15d
  test   %r15d,%r15d
  jle    L104
  mov    %r15d,%ebx
  mov    $0x0,%r12d
  lea    D25(%rip),%r13
L78:
  mov    $0x10,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L87
  add    $0x1,%r12d
  add    $0x1,%rbp
  cmp    %ebx,%r12d
  jne    L78
  jmp    L96
L183:
  mov    $0x0,%r12d
  jmp    L136
L87:
  lea    0x10(%r12),%ebx
L96:
  cmp    %r15d,%ebx
  je     L142
L134:
  movslq %ebx,%rbx
  add    (%rsp),%rbx
  mov    $0x0,%r12d
L32:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L177
  lea    (%r12,%r12,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%r12d
  add    $0x1,%rbx
  jmp    L32
L177:
  lea    -0x4(%r14),%r15d
  test   %r15d,%r15d
  jle    L161
  mov    (%rsp),%rbx
  mov    %r15d,%r14d
  mov    $0x0,%ebp
  lea    D8(%rip),%r13
L144:
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L17
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %r14d,%ebp
  jne    L144
  jmp    L189
L17:
  lea    0x4(%rbp),%r14d
L189:
  cmp    %r15d,%r14d
  je     L142
  add    %r12d,%r14d
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
L142:
  mov    0x8(%rsp),%rax
  cmpl   $0x1,(%rax)
  sbb    %eax,%eax
  or     $0x1,%eax
L64:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L161:
  mov    $0x0,%r14d
  jmp    L189
L104:
  mov    $0x0,%ebx
  jne    L134
  mov    $0xffffffff,%eax
  jmp    L64
```

tool_calls: name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D19: 5:peers

tool: D25: Content-Length: 

tool: D8: 



assistant: ```c
int get_response_type(char *buffer, int len, int *total_length) {
  int i, content_length = 0;
  for (i = 0; i < len - 7; i++) {
    if (memcmp(&buffer[i], "5:peers", 7) == 0) {
      i = i + 7;
      break;
    }
  }
  if (i == len - 7)
    return -1;
  if (buffer[i] != 'l')
    return 0;
  *total_length = 0;
  for (i = 0; i < len - 16; i++) {
    if (memcmp(&buffer[i], "Content-Length: ", 16) == 0) {
      i = i + 16;
      break;
    }
  }
  if (i != len - 16) {
    while (isdigit(buffer[i])) {
      content_length = content_length * 10 + (buffer[i] - '0');
      i++;
    }
    for (i = 0; i < len - 4; i++) {
      if (memcmp(&buffer[i], "\r\n\r\n", 4) == 0) {
        i = i + 4;
        break;
      }
    }
    if (i != len - 4)
      *total_length = content_length + i;
  }
  if (*total_length == 0)
    return -1;
  else
    return 1;
}
```