ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fastBounceInOut>:
  endbr64
  movss  D6(%rip),%xmm6
  movaps %xmm0,%xmm5
  movaps %xmm1,%xmm0
  mov    %edi,%esi
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm6,%xmm1
  comiss %xmm5,%xmm6
  movaps %xmm5,%xmm4
  addss  %xmm5,%xmm4
  ja     L9
  subss  D19(%rip),%xmm4
  addss  %xmm1,%xmm0
  cvttss2si %xmm4,%edi
  jmp    1060 <fastBounceOut@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  cvttss2si %xmm4,%edi
  jmp    1070 <fastBounceIn@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: f32
name: unpack_data
arguments: data_tag: D19
type: byte[4]

tool: D6: 0.5

tool: {"D19": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float fastBounceInOut(float fraction, float start, float delta, int bounces, float growth, float damping) {
  if (fraction < 0.5)
    return fastBounceIn(2 * fraction, start, delta / 2, bounces, growth, damping);
  return fastBounceOut(2 * fraction - 1, start + delta / 2, delta / 2, bounces, growth, damping);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fastBounceInOut>:
  endbr64
  movss  D11(%rip),%xmm6
  movaps %xmm0,%xmm5
  movaps %xmm1,%xmm0
  mov    %edi,%esi
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm6,%xmm1
  comiss %xmm5,%xmm6
  movaps %xmm5,%xmm4
  addss  %xmm5,%xmm4
  ja     L6
  subss  D2(%rip),%xmm4
  addss  %xmm1,%xmm0
  cvttss2si %xmm4,%edi
  jmp    1060 <fastBounceOut@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  cvttss2si %xmm4,%edi
  jmp    1070 <fastBounceIn@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
datatype: f32
name: parse_data
arguments: data_tag: D2
datatype: byte[4]

tool: D11: 0.5

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float fastBounceInOut(float fraction, float start, float delta, int bounces, float growth, float damping) {
  if (fraction < 0.5)
    return fastBounceIn(2 * fraction, start, delta / 2, bounces, growth, damping);
  return fastBounceOut(2 * fraction - 1, start + delta / 2, delta / 2, bounces, growth, damping);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__wrap_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mxCalloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mexMakeMemoryPersistent@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *__wrap_calloc(size_t n, size_t bytes) {
  void *ptr;
  ptr = (void *)mxCalloc(n, bytes);
  if (ptr != 0)
    mexMakeMemoryPersistent(ptr);
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__wrap_calloc>:
  endbr64
  push   %rbx
  call   <mxCalloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L3
L17:
  mov    %rbx,%rax
  pop    %rbx
  ret
L3:
  mov    %rax,%rdi
  call   <mexMakeMemoryPersistent@plt>
  jmp    L17
```

assistant: ```c
void *__wrap_calloc(size_t n, size_t bytes) {
  void *ptr;
  ptr = (void *)mxCalloc(n, bytes);
  if (ptr != 0)
    mexMakeMemoryPersistent(ptr);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__wrap_calloc>:
  endbr64
  push   %r12
  call   <mxCalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L5
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    %rax,%rdi
  call   <mexMakeMemoryPersistent@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *__wrap_calloc(size_t n, size_t bytes) {
  void *ptr;
  ptr = (void *)mxCalloc(n, bytes);
  if (ptr != 0)
    mexMakeMemoryPersistent(ptr);
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__wrap_calloc>:
  endbr64
  push   %r12
  call   <mxCalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L4
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    %rax,%rdi
  call   <mexMakeMemoryPersistent@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *__wrap_calloc(size_t n, size_t bytes) {
  void *ptr;
  ptr = (void *)mxCalloc(n, bytes);
  if (ptr != 0)
    mexMakeMemoryPersistent(ptr);
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<_sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _sprintf(char *buffer, const char *fmt, ...) {
  va_list args;
  int i;
  va_start(args, fmt);
  i = _vsprintf(buffer, fmt, args);
  va_end(args);
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_sprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <_vsprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _sprintf(char *buffer, const char *fmt, ...) {
  va_list args;
  int i;
  va_start(args, fmt);
  i = _vsprintf(buffer, fmt, args);
  va_end(args);
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _sprintf(char *buffer, const char *fmt, ...) {
  va_list args;
  int i;
  va_start(args, fmt);
  i = _vsprintf(buffer, fmt, args);
  va_end(args);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _sprintf(char *buffer, const char *fmt, ...) {
  va_list args;
  int i;
  va_start(args, fmt);
  i = _vsprintf(buffer, fmt, args);
  va_end(args);
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fn3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L15
L19:
  mov    -0x44(%rbp),%eax
  lea    0x8(%rax),%ecx
  mov    -0x44(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%edx
  movslq %ecx,%rax
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x44(%rbp),%eax
  lea    0x8(%rax),%edx
  mov    -0x44(%rbp),%eax
  lea    0x8(%rax),%ecx
  movslq %edx,%rax
  movzbl -0x30(%rbp,%rax,1),%edx
  movslq %ecx,%rax
  mov    %dl,-0x40(%rbp,%rax,1)
  addl   $0x1,-0x44(%rbp)
L15:
  cmpl   $0xf,-0x44(%rbp)
  jle    L19
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void fn3(void) {
  unsigned char a[16], b[16], c[16];
  int i;
  bar(b);
  for (i = 0; i < (int)(sizeof(a) / sizeof(a[0])); i++) {
    c[i + 8] = b[i];
    a[i + 8] = b[i + 8];
  }
  bar(a);
  bar(c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn3>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  call   <bar@plt>
  mov    $0x8,%eax
  lea    0x8(%rsp),%rcx
L7:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,0x20(%rsp,%rax,1)
  movzbl 0x10(%rsp,%rax,1),%edx
  mov    %dl,(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x18,%rax
  jne    L7
  mov    %rsp,%rdi
  call   <bar@plt>
  lea    0x20(%rsp),%rdi
  call   <bar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x48,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fn3(void) {
  unsigned char a[16], b[16], c[16];
  int i;
  bar(b);
  for (i = 0; i < (int)(sizeof(a) / sizeof(a[0])); i++) {
    c[i + 8] = b[i];
    a[i + 8] = b[i + 8];
  }
  bar(a);
  bar(c);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fn3>:
  endbr64
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0x20(%rsp),%rbp
  call   <bar@plt>
  movdqa 0x10(%rsp),%xmm0
  movdqu 0x18(%rsp),%xmm1
  mov    %rsp,%rdi
  movups %xmm0,0x28(%rsp)
  movups %xmm1,0x8(%rsp)
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x40,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fn3(void) {
  unsigned char a[16], b[16], c[16];
  int i;
  bar(b);
  for (i = 0; i < (int)(sizeof(a) / sizeof(a[0])); i++) {
    c[i + 8] = b[i];
    a[i + 8] = b[i + 8];
  }
  bar(a);
  bar(c);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fn3>:
  endbr64
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0x20(%rsp),%rbp
  call   <bar@plt>
  movdqa 0x10(%rsp),%xmm0
  movdqu 0x18(%rsp),%xmm1
  mov    %rsp,%rdi
  movups %xmm0,0x28(%rsp)
  movups %xmm1,0x8(%rsp)
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x40,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fn3(void) {
  unsigned char a[16], b[16], c[16];
  int i;
  bar(b);
  for (i = 0; i < (int)(sizeof(a) / sizeof(a[0])); i++) {
    c[i + 8] = b[i];
    a[i + 8] = b[i + 8];
  }
  bar(a);
  bar(c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<makefilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movb   $0x2f,-0x19(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L13
  movb   $0x0,-0x19(%rbp)
  jmp    L7
L13:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L7
  subq   $0x1,-0x18(%rbp)
L7:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpb   $0x0,-0x19(%rbp)
  setne  %al
  movzbl %al,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x30(%rbp)
  ja     L14
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L66
L14:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L33
  mov    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  add    %rax,-0x10(%rbp)
L33:
  cmpb   $0x0,-0x19(%rbp)
  je     L62
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2f,(%rax)
L62:
  mov    -0x8(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
L66:
  leave
  ret
```

assistant: ```c
int makefilename(char *path, size_t max, const char *dir, const char *file) {
  size_t dlen;
  size_t flen;
  char *p;
  char sep;
  sep = '/';
  dlen = strlen(dir);
  if (dlen == 0)
    sep = '\0';
  else if (dir[dlen - 1] == '/')
    dlen--;
  flen = strlen(file);
  if (dlen + (sep == '\0' ? 0 : 1) + flen >= max) {
    errno = E2BIG;
    return (-1);
  }
  p = path;
  if (dlen > 0) {
    memcpy(p, dir, dlen);
    p += dlen;
  }
  if (sep != '\0')
    *p++ = '/';
  memcpy(p, file, flen);
  p += flen;
  *p++ = '\0';
  return (p - path);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<makefilename>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L13
  mov    %rax,%rbx
  lea    -0x1(%rax),%rax
  mov    %rax,0x8(%rsp)
  cmpb   $0x2f,-0x1(%r13,%rbx,1)
  je     L11
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  lea    0x1(%rbx,%rax,1),%rax
  cmp    %rax,%r14
  jbe    L99
L72:
  mov    (%rsp),%rbx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  add    %rbp,%rax
L46:
  lea    0x1(%rax),%rbx
  movb   $0x2f,(%rax)
L94:
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    (%rbx,%r15,1),%rax
  movb   $0x0,(%rax)
  add    $0x1,%rax
  sub    %ebp,%eax
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  add    %rbx,%rax
  cmp    %r14,%rax
  jae    L99
  cmpq   $0x0,0x8(%rsp)
  jne    L28
  mov    %rbp,%rax
  jmp    L46
L99:
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L2
L28:
  mov    0x8(%rsp),%rax
  mov    %rax,(%rsp)
  jmp    L72
L13:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  cmp    %rax,%r14
  jbe    L99
  mov    %rbp,%rbx
  jmp    L94
```

assistant: ```c
int makefilename(char *path, size_t max, const char *dir, const char *file) {
  size_t dlen;
  size_t flen;
  char *p;
  char sep;
  sep = '/';
  dlen = strlen(dir);
  if (dlen == 0)
    sep = '\0';
  else if (dir[dlen - 1] == '/')
    dlen--;
  flen = strlen(file);
  if (dlen + (sep == '\0' ? 0 : 1) + flen >= max) {
    errno = E2BIG;
    return (-1);
  }
  p = path;
  if (dlen > 0) {
    memcpy(p, dir, dlen);
    p += dlen;
  }
  if (sep != '\0')
    *p++ = '/';
  memcpy(p, file, flen);
  p += flen;
  *p++ = '\0';
  return (p - path);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<makefilename>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%r14
  test   %rbx,%rbx
  je     L88
  cmpb   $0x2f,-0x1(%r15,%rbx,1)
  lea    -0x1(%rbx),%rax
  je     L8
  lea    0x1(%rbx,%r14,1),%rax
  cmp    %rax,%r13
  jbe    L66
L64:
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%rbx,1),%rax
L45:
  movb   $0x2f,(%rax)
  lea    0x1(%rax),%rbx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L88:
  cmp    %rax,%r13
  jbe    L66
  mov    %rbp,%rbx
L26:
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    (%rbx,%r14,1),%rax
  movb   $0x0,(%rax)
  add    $0x1,%rax
  sub    %ebp,%eax
L56:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    %r14,%rbx
  cmp    %r13,%rbx
  jae    L66
  test   %rax,%rax
  jne    L59
  mov    %rbp,%rax
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L66:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L56
L59:
  mov    %rax,%rbx
  jmp    L64
```

assistant: ```c
int makefilename(char *path, size_t max, const char *dir, const char *file) {
  size_t dlen;
  size_t flen;
  char *p;
  char sep;
  sep = '/';
  dlen = strlen(dir);
  if (dlen == 0)
    sep = '\0';
  else if (dir[dlen - 1] == '/')
    dlen--;
  flen = strlen(file);
  if (dlen + (sep == '\0' ? 0 : 1) + flen >= max) {
    errno = E2BIG;
    return (-1);
  }
  p = path;
  if (dlen > 0) {
    memcpy(p, dir, dlen);
    p += dlen;
  }
  if (sep != '\0')
    *p++ = '/';
  memcpy(p, file, flen);
  p += flen;
  *p++ = '\0';
  return (p - path);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<makefilename>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%r14
  test   %rbx,%rbx
  je     L82
  cmpb   $0x2f,-0x1(%r15,%rbx,1)
  lea    -0x1(%rbx),%rax
  je     L1
  lea    0x1(%rbx,%r14,1),%rax
  cmp    %rax,%r13
  jbe    L75
L17:
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%rbx,1),%rax
L21:
  movb   $0x2f,(%rax)
  lea    0x1(%rax),%rbx
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L82:
  cmp    %rax,%r13
  jbe    L75
  mov    %rbp,%rbx
L65:
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    (%rbx,%r14,1),%rax
  movb   $0x0,(%rax)
  add    $0x1,%rax
  sub    %ebp,%eax
L63:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    %r14,%rbx
  cmp    %r13,%rbx
  jae    L75
  test   %rax,%rax
  jne    L3
  mov    %rbp,%rax
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L75:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L63
L3:
  mov    %rax,%rbx
  jmp    L17
```

assistant: ```c
int makefilename(char *path, size_t max, const char *dir, const char *file) {
  size_t dlen;
  size_t flen;
  char *p;
  char sep;
  sep = '/';
  dlen = strlen(dir);
  if (dlen == 0)
    sep = '\0';
  else if (dir[dlen - 1] == '/')
    dlen--;
  flen = strlen(file);
  if (dlen + (sep == '\0' ? 0 : 1) + flen >= max) {
    errno = E2BIG;
    return (-1);
  }
  p = path;
  if (dlen > 0) {
    memcpy(p, dir, dlen);
    p += dlen;
  }
  if (sep != '\0')
    *p++ = '/';
  memcpy(p, file, flen);
  p += flen;
  *p++ = '\0';
  return (p - path);
}
```
user: What is the c source code of the assembly code below?

```asm
<PHC_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L33:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  push   $0x20
  push   $0xa
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <test_output@plt>
  add    $0x10,%rsp
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    $0xff,%eax
  jle    L33
  movl   $0x0,-0x10(%rbp)
  jmp    L36
L26:
  lea    -0x10(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  push   $0x20
  push   $0xa
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <test_output@plt>
  add    $0x10,%rsp
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L36:
  mov    -0x10(%rbp),%eax
  cmp    $0xff,%eax
  jle    L26
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void PHC_test() {
  int i;
  uint8_t j = 0;
  for (i = 0; i < 256; i++)
    test_output((uint8_t *)&i, 1, &j, 1, NULL, 0, 10, 32);
  for (i = 0; i < 256; i++)
    test_output(&j, 1, (uint8_t *)&i, 1, NULL, 0, 10, 32);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PHC_test>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  lea    0x4(%rsp),%rbx
L24:
  mov    %rsp,%rdi
  push   $0x20
  push   $0xa
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  call   <test_output@plt>
  mov    0x10(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x10(%rsp)
  add    $0x10,%rsp
  cmp    $0xff,%eax
  jle    L24
  movl   $0x0,(%rsp)
  mov    %rsp,%rbx
L17:
  lea    0x4(%rsp),%rdi
  push   $0x20
  push   $0xa
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  call   <test_output@plt>
  mov    0x10(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x10(%rsp)
  add    $0x10,%rsp
  cmp    $0xff,%eax
  jle    L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void PHC_test() {
  int i;
  uint8_t j = 0;
  for (i = 0; i < 256; i++)
    test_output((uint8_t *)&i, 1, &j, 1, NULL, 0, 10, 32);
  for (i = 0; i < 256; i++)
    test_output(&j, 1, (uint8_t *)&i, 1, NULL, 0, 10, 32);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PHC_test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  mov    %rsp,%rbx
  movl   $0x0,(%rsp)
  nopl   0x0(%rax)
L27:
  push   $0x20
  mov    $0x1,%esi
  mov    %rbx,%rdi
  xor    %r9d,%r9d
  push   $0xa
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  mov    %rbp,%rdx
  call   <test_output@plt>
  mov    0x10(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x10(%rsp)
  pop    %rsi
  pop    %rdi
  cmp    $0xff,%eax
  jle    L27
  movl   $0x0,(%rsp)
  nopw   0x0(%rax,%rax,1)
L23:
  push   $0x20
  mov    $0x1,%ecx
  mov    %rbx,%rdx
  xor    %r9d,%r9d
  push   $0xa
  xor    %r8d,%r8d
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <test_output@plt>
  mov    0x10(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x10(%rsp)
  pop    %rdx
  pop    %rcx
  cmp    $0xff,%eax
  jle    L23
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void PHC_test() {
  int i;
  uint8_t j = 0;
  for (i = 0; i < 256; i++)
    test_output((uint8_t *)&i, 1, &j, 1, NULL, 0, 10, 32);
  for (i = 0; i < 256; i++)
    test_output(&j, 1, (uint8_t *)&i, 1, NULL, 0, 10, 32);
}
```