ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L73:
  cmp    %rdx,%rsp
  je     L30
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L73
L30:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L20
  orq    $0x0,-0x8(%rsp,%rax,1)
L20:
  mov    %rsp,%r13
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  test   %esi,%esi
  jle    L59
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D4(%rip),%r14
L23:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%esi
  add    $0x4,%r12
  cmp    %ebx,%esi
  jg     L23
L59:
  mov    %r13,%rdi
  call   <counting_sort@plt>
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x2c(%rbp)
  jle    L34
  mov    $0x0,%ebx
  lea    D55(%rip),%r12
L2:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,-0x2c(%rbp)
  jg     L2
L34:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D38
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D40
type_guessed: string
name: retrieve_data
arguments: data_label: D48
type_guessed: string
name: retrieve_data
arguments: data_label: D55
type_guessed: string

tool: D38: Enter number of elements in your array: 

tool: D4: %d

tool: D40: Enter your array: 

tool: D48: Sorted Array : 

tool: D55: %d 

assistant: ```c
int main() {
  int n, i;
  printf("Enter number of elements in your array: ");
  scanf("%d", &n);
  int input[n];
  printf("Enter your array: ");
  for (i = 0; i < n; i++)
    scanf("%d", &input[i]);
  counting_sort(input, n);
  printf("Sorted Array : ");
  for (i = 0; i < n; i++)
    printf("%d ", input[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L63
L72:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L72
L63:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L62
L33:
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  test   %esi,%esi
  jle    L50
  mov    %r13,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L88:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  cmp    %ebx,%esi
  jg     L88
L50:
  mov    %r13,%rdi
  call   <counting_sort@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L73
  xor    %ebx,%ebx
  lea    D32(%rip),%r12
  nop
L41:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L41
L73:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L62:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L33
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D46
type: string
name: unpack_data
arguments: data_tag: D14
type: string
name: unpack_data
arguments: data_tag: D32
type: string

tool: D16: Enter number of elements in your array: 

tool: D6: %d

tool: D46: Enter your array: 

tool: D14: Sorted Array : 

tool: D32: %d 

assistant: ```c
int main() {
  int n, i;
  printf("Enter number of elements in your array: ");
  scanf("%d", &n);
  int input[n];
  printf("Enter your array: ");
  for (i = 0; i < n; i++)
    scanf("%d", &input[i]);
  counting_sort(input, n);
  printf("Sorted Array : ");
  for (i = 0; i < n; i++)
    printf("%d ", input[i]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D42(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  lea    D41(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L47
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L21
L47:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L8
L20:
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  test   %esi,%esi
  jle    L11
  mov    %r13,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L78:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  cmp    %ebx,%esi
  jg     L78
L11:
  mov    %r13,%rdi
  call   <counting_sort@plt>
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L84
  xor    %ebx,%ebx
  lea    D35(%rip),%r12
  nop
L79:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L79
L84:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L8:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L20
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D42
type: string
name: retrieve_data
arguments: tag: D41
type: string
name: retrieve_data
arguments: tag: D45
type: string
name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D35
type: string

tool: D42: Enter number of elements in your array: 

tool: D41: %d

tool: D45: Enter your array: 

tool: D20: Sorted Array : 

tool: D35: %d 

assistant: ```c
int main() {
  int n, i;
  printf("Enter number of elements in your array: ");
  scanf("%d", &n);
  int input[n];
  printf("Enter your array: ");
  for (i = 0; i < n; i++)
    scanf("%d", &input[i]);
  counting_sort(input, n);
  printf("Sorted Array : ");
  for (i = 0; i < n; i++)
    printf("%d ", input[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L0:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L10
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L3
L10:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L0
  mov    $0x0,%eax
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: read_n|read

assistant: ```c
int read_n(int fd, char *buf, int n) {
  int readed = 0;
  int ret;
  while (n > readed) {
    ret = read(fd, buf + readed, n - readed);
    if (ret == -1) {
      perror("read_n|read");
      return -1;
    }
    readed += ret;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_n>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L47
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    %edx,%r12d
  mov    $0x0,%ebp
L27:
  mov    %r12d,%edx
  sub    %ebp,%edx
  movslq %ebp,%rsi
  add    %r14,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L36
  add    %eax,%ebp
  cmp    %ebp,%r12d
  jg     L27
  mov    $0x0,%ebx
  jmp    L5
L36:
  lea    D5(%rip),%rdi
  call   <perror@plt>
L5:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  mov    $0x0,%ebx
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D5: read_n|read

assistant: ```c
int read_n(int fd, char *buf, int n) {
  int readed = 0;
  int ret;
  while (n > readed) {
    ret = read(fd, buf + readed, n - readed);
    if (ret == -1) {
      perror("read_n|read");
      return -1;
    }
    readed += ret;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_n>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L31
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    %edx,%ebp
  xor    %ebx,%ebx
  jmp    L37
  nopl   0x0(%rax)
L14:
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jle    L31
L37:
  mov    %ebp,%edx
  movslq %ebx,%rsi
  mov    %r13d,%edi
  sub    %ebx,%edx
  add    %r14,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  jne    L14
  lea    D8(%rip),%rdi
  call   <perror@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D8: read_n|read

assistant: ```c
int read_n(int fd, char *buf, int n) {
  int readed = 0;
  int ret;
  while (n > readed) {
    ret = read(fd, buf + readed, n - readed);
    if (ret == -1) {
      perror("read_n|read");
      return -1;
    }
    readed += ret;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_n>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L39
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    %edx,%ebp
  xor    %ebx,%ebx
  jmp    L27
  nopl   0x0(%rax)
L24:
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jle    L39
L27:
  mov    %ebp,%edx
  movslq %ebx,%rsi
  mov    %r13d,%edi
  sub    %ebx,%edx
  add    %r14,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  jne    L24
  lea    D9(%rip),%rdi
  call   <perror@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: read_n|read

assistant: ```c
int read_n(int fd, char *buf, int n) {
  int readed = 0;
  int ret;
  while (n > readed) {
    ret = read(fd, buf + readed, n - readed);
    if (ret == -1) {
      perror("read_n|read");
      return -1;
    }
    readed += ret;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gmx_rotacf@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_rotacf(argc, argv);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_rotacf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_rotacf(argc, argv);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_rotacf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_rotacf(argc, argv);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_rotacf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_rotacf(argc, argv);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SteamAPI_ISteamApps_GetAppBuildId>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <xlogf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D10
type_infered: string

tool: D5: SteamAPI_ISteamApps_GetAppBuildId

tool: D10: %s(self = %p)


assistant: ```c
int SteamAPI_ISteamApps_GetAppBuildId(void *self) {
  xlogf("%s(self = %p)\n", __func__, self);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SteamAPI_ISteamApps_GetAppBuildId>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D11(%rip),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <xlogf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
datatype: string
name: retrieve_data
arguments: data_tag: D15
datatype: string

tool: D11: SteamAPI_ISteamApps_GetAppBuildId

tool: D15: %s(self = %p)


assistant: ```c
int SteamAPI_ISteamApps_GetAppBuildId(void *self) {
  xlogf("%s(self = %p)\n", __func__, self);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SteamAPI_ISteamApps_GetAppBuildId>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D2(%rip),%rsi
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <xlogf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D7
type: string

tool: D2: SteamAPI_ISteamApps_GetAppBuildId

tool: D7: %s(self = %p)


assistant: ```c
int SteamAPI_ISteamApps_GetAppBuildId(void *self) {
  xlogf("%s(self = %p)\n", __func__, self);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SteamAPI_ISteamApps_GetAppBuildId>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <xlogf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string
name: retrieve_data
arguments: data_label: D17
type: string

tool: D8: SteamAPI_ISteamApps_GetAppBuildId

tool: D17: %s(self = %p)


assistant: ```c
int SteamAPI_ISteamApps_GetAppBuildId(void *self) {
  xlogf("%s(self = %p)\n", __func__, self);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L42:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  jmp    L26
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
L26:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    D23(%rip),%rcx
  mov    %al,(%rdx,%rcx,1)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    -0x4(%rbp),%eax
  cltq
  lea    D23(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D23(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strlower(const char *str) {
  static char strlow[4096];
  int i;
  for (i = 0; str[i] != '\0'; i++)
    strlow[i] = ((str[i]) >= 'A' && (str[i]) <= 'Z' ? (str[i]) + 'a' - 'A' : (str[i]));
  strlow[i] = '\0';
  return strlow;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlower>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
  mov    $0x1,%edx
  lea    D8(%rip),%r8
L4:
  lea    -0x41(%rax),%esi
  lea    0x20(%rax),%ecx
  cmp    $0x1a,%sil
  cmovb  %ecx,%eax
  mov    %al,(%rdx,%r8,1)
  mov    %edx,%ecx
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L4
L16:
  lea    D9(%rip),%rax
  movslq %ecx,%rcx
  movb   $0x0,(%rax,%rcx,1)
  ret
L0:
  mov    $0x0,%ecx
  jmp    L16
```

assistant: ```c
char *strlower(const char *str) {
  static char strlow[4096];
  int i;
  for (i = 0; str[i] != '\0'; i++)
    strlow[i] = ((str[i]) >= 'A' && (str[i]) <= 'Z' ? (str[i]) + 'a' - 'A' : (str[i]));
  strlow[i] = '\0';
  return strlow;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlower>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  mov    $0x1,%edx
  lea    D17(%rip),%r8
  nopw   0x0(%rax,%rax,1)
L5:
  lea    -0x41(%rax),%esi
  lea    0x20(%rax),%ecx
  cmp    $0x1a,%sil
  cmovb  %ecx,%eax
  movslq %edx,%rcx
  mov    %al,(%r8,%rdx,1)
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L5
  lea    D0(%rip),%rax
  movb   $0x0,(%rax,%rcx,1)
  ret
  nopl   (%rax)
L2:
  xor    %ecx,%ecx
  lea    D0(%rip),%rax
  movb   $0x0,(%rax,%rcx,1)
  ret
```

assistant: ```c
char *strlower(const char *str) {
  static char strlow[4096];
  int i;
  for (i = 0; str[i] != '\0'; i++)
    strlow[i] = ((str[i]) >= 'A' && (str[i]) <= 'Z' ? (str[i]) + 'a' - 'A' : (str[i]));
  strlow[i] = '\0';
  return strlow;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlower>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  mov    $0x1,%edx
  lea    D17(%rip),%rsi
  nopw   0x0(%rax,%rax,1)
L4:
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L17
  add    $0x20,%eax
L17:
  mov    %al,(%rsi,%rdx,1)
  movslq %edx,%rcx
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L4
  lea    D26(%rip),%rax
  movb   $0x0,(%rax,%rcx,1)
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %ecx,%ecx
  lea    D26(%rip),%rax
  movb   $0x0,(%rax,%rcx,1)
  ret
```

assistant: ```c
char *strlower(const char *str) {
  static char strlow[4096];
  int i;
  for (i = 0; str[i] != '\0'; i++)
    strlow[i] = ((str[i]) >= 'A' && (str[i]) <= 'Z' ? (str[i]) + 'a' - 'A' : (str[i]));
  strlow[i] = '\0';
  return strlow;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timer_delay_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
L13:
  lea    -0x18(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sigwait@plt>
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L10
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L13
L10:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void timer_delay_ms(uint16_t ms) {
  int signum = 0;
  int retval = 0;
  sigset_t set;
  uint32_t counts = 0;
  sigaddset(&set, SIGALRM);
  do {
    retval = sigwait(&set, &signum);
    counts++;
  } while ((retval != -1) && ((counts) < ((uint32_t)ms * 10)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timer_delay_ms>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  lea    0x4(%rsp),%rdi
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <sigaddset@plt>
  lea    (%rbx,%rbx,4),%ebp
  add    %ebp,%ebp
  mov    $0x0,%ebx
  mov    %rsp,%r12
L12:
  lea    0x4(%rsp),%rdi
  mov    %r12,%rsi
  call   <sigwait@plt>
  add    $0x1,%ebx
  cmp    $0xffffffff,%eax
  je     L28
  cmp    %ebx,%ebp
  jg     L12
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void timer_delay_ms(uint16_t ms) {
  int signum = 0;
  int retval = 0;
  sigset_t set;
  uint32_t counts = 0;
  sigaddset(&set, SIGALRM);
  do {
    retval = sigwait(&set, &signum);
    counts++;
  } while ((retval != -1) && ((counts) < ((uint32_t)ms * 10)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timer_delay_ms>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    (%rbx,%rbx,4),%ebp
  xor    %ebx,%ebx
  add    %ebp,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%r12
  mov    %rsp,%r13
  mov    %r12,%rdi
  movl   $0x0,(%rsp)
  mov    (%rax),%esi
  call   <sigaddset@plt>
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    %ebx,%ebp
  jle    L28
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <sigwait@plt>
  cmp    $0xffffffff,%eax
  jne    L10
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void timer_delay_ms(uint16_t ms) {
  int signum = 0;
  int retval = 0;
  sigset_t set;
  uint32_t counts = 0;
  sigaddset(&set, SIGALRM);
  do {
    retval = sigwait(&set, &signum);
    counts++;
  } while ((retval != -1) && ((counts) < ((uint32_t)ms * 10)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timer_delay_ms>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    (%rbx,%rbx,4),%ebp
  xor    %ebx,%ebx
  add    %ebp,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%r12
  mov    %rsp,%r13
  mov    %r12,%rdi
  movl   $0x0,(%rsp)
  mov    (%rax),%esi
  call   <sigaddset@plt>
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    %ebx,%ebp
  jle    L1
L16:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <sigwait@plt>
  cmp    $0xffffffff,%eax
  jne    L0
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void timer_delay_ms(uint16_t ms) {
  int signum = 0;
  int retval = 0;
  sigset_t set;
  uint32_t counts = 0;
  sigaddset(&set, SIGALRM);
  do {
    retval = sigwait(&set, &signum);
    counts++;
  } while ((retval != -1) && ((counts) < ((uint32_t)ms * 10)));
}
```