user: 这段汇编代码用C语言表示是什么样的:

```asm
<permuteInv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %esi,-0x78(%rbp)
  mov    %rdx,-0x80(%rbp)
  mov    %rcx,-0x88(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x98(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0xa0(%rbp)
  mov    0x18(%rbp),%rax
  mov    %rax,-0xa8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x6c(%rbp)
  jmp    L51
L69:
  mov    -0x6c(%rbp),%eax
  cltq
  movl   $0x0,-0x60(%rbp,%rax,4)
  addl   $0x1,-0x6c(%rbp)
L51:
  mov    -0x6c(%rbp),%eax
  cmp    -0x78(%rbp),%eax
  jle    L69
  movl   $0x0,-0x64(%rbp)
  movl   $0x0,-0x6c(%rbp)
  jmp    L35
L56:
  mov    -0x64(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x90(%rbp),%rax
  add    %rax,%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0xa0(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x64(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x6c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x1,-0x68(%rbp)
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x64(%rbp)
  mov    -0x5c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x5c(%rbp)
  jmp    L27
L65:
  mov    -0x68(%rbp),%eax
  cltq
  movl   $0x0,-0x60(%rbp,%rax,4)
  mov    -0x68(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x64(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x68(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %ecx,%eax
  mov    %eax,-0x64(%rbp)
  addl   $0x1,-0x68(%rbp)
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x68(%rbp),%eax
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
L27:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x80(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L65
  addl   $0x1,-0x6c(%rbp)
L35:
  mov    -0x74(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x6c(%rbp)
  jl     L56
  mov    -0x74(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x90(%rbp),%rax
  add    %rax,%rdx
  mov    -0x74(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0xa0(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x74(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x74(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void permuteInv(int nPoint, int nFact, int fact[], int remain[], double xRe[], double xIm[], double yRe[], double yIm[]) {
  int i, j, k;
  int count[20];
  for (i = 1; i <= nFact; i++)
    count[i] = 0;
  k = 0;
  for (i = 0; i <= nPoint - 2; i++) {
    yRe[i] = xRe[k];
    yIm[i] = -xIm[k];
    j = 1;
    k = k + remain[j];
    count[1] = count[1] + 1;
    while (count[j] >= fact[j]) {
      count[j] = 0;
      k = k - remain[j - 1] + remain[j + 1];
      j = j + 1;
      count[j] = count[j] + 1;
    }
  }
  yRe[nPoint - 1] = xRe[nPoint - 1];
  yIm[nPoint - 1] = -xIm[nPoint - 1];
}
```