ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<split_into_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  movsbl %r13b,%r13d
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x238,%rsp
  mov    %rdx,0x10(%rsp)
  lea    0x20(%rsp),%rbx
  mov    %rcx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x228(%rsp)
  xor    %eax,%eax
  call   <STRDUP@plt>
  mov    %rax,(%rsp)
  mov    %rax,%rdi
  nopl   (%rax)
L23:
  mov    %r13d,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x200,%edx
  mov    %rbx,%rsi
  call   <quoted_string_parse@plt>
  movslq %r12d,%r14
  add    $0x1,%r12d
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L23
  lea    0x0(,%r12,8),%edi
  call   <MALLOC@plt>
  mov    (%rsp),%r15
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
  lea    0x8(%rax,%r14,8),%r14
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r13d,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x200,%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  add    $0x8,%rbp
  call   <quoted_string_parse@plt>
  mov    %rbx,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  lea    0x5(%rax),%edi
  call   <MALLOC@plt>
  mov    %rbx,%rsi
  mov    %rax,-0x8(%rbp)
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmp    %r14,%rbp
  jne    L15
  mov    0x18(%rsp),%rax
  mov    0x8(%rsp),%rdx
  mov    %rdx,(%rax)
  mov    0x10(%rsp),%rax
  mov    %r12d,(%rax)
  mov    0x228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    (%rsp),%rdi
  add    $0x238,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <FREE@plt>
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void split_into_array(const char *str_in, char sep, int *nelem, char ***parr) {
  char *str = STRDUP(str_in);
  char *p = str;
  int i, n = 0;
  do {
    char val[512];
    p = quoted_string_parse(p, val, 512, -1, sep);
    ++n;
  } while (p);
  char **arr = MALLOC(sizeof(char *) * n);
  p = str;
  for (i = 0; i < n; ++i) {
    char val[512];
    p = quoted_string_parse(p, val, 512, -1, sep);
    arr[i] = MALLOC(sizeof(char) * (strlen(val) + 5));
    strcpy(arr[i], val);
  }
  *parr = arr;
  *nelem = n;
  FREE(str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<split_into_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  movsbl %r13b,%r13d
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x238,%rsp
  mov    %rdx,0x10(%rsp)
  lea    0x20(%rsp),%rbx
  mov    %rcx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x228(%rsp)
  xor    %eax,%eax
  call   <STRDUP@plt>
  mov    %rax,(%rsp)
  mov    %rax,%rdi
  nopl   (%rax)
L28:
  mov    %r13d,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x200,%edx
  mov    %rbx,%rsi
  call   <quoted_string_parse@plt>
  movslq %r12d,%r14
  add    $0x1,%r12d
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L28
  lea    0x0(,%r12,8),%edi
  call   <MALLOC@plt>
  mov    (%rsp),%r15
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
  lea    0x8(%rax,%r14,8),%r14
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r13d,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x200,%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  add    $0x8,%rbp
  call   <quoted_string_parse@plt>
  mov    %rbx,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  lea    0x5(%rax),%edi
  call   <MALLOC@plt>
  mov    %rbx,%rsi
  mov    %rax,-0x8(%rbp)
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmp    %r14,%rbp
  jne    L27
  mov    0x18(%rsp),%rax
  mov    0x8(%rsp),%rdx
  mov    %rdx,(%rax)
  mov    0x10(%rsp),%rax
  mov    %r12d,(%rax)
  mov    0x228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    (%rsp),%rdi
  add    $0x238,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <FREE@plt>
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void split_into_array(const char *str_in, char sep, int *nelem, char ***parr) {
  char *str = STRDUP(str_in);
  char *p = str;
  int i, n = 0;
  do {
    char val[512];
    p = quoted_string_parse(p, val, 512, -1, sep);
    ++n;
  } while (p);
  char **arr = MALLOC(sizeof(char *) * n);
  p = str;
  for (i = 0; i < n; ++i) {
    char val[512];
    p = quoted_string_parse(p, val, 512, -1, sep);
    arr[i] = MALLOC(sizeof(char) * (strlen(val) + 5));
    strcpy(arr[i], val);
  }
  *parr = arr;
  *nelem = n;
  FREE(str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lpt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0xc(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x1,%ebx
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L0
L18:
  add    %ebx,%ebx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L0:
  cmp    -0xc(%rbp),%ebx
  jl     L18
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int lpt(int n, int *lambda) {
  register int i = 1;
  *lambda = 0;
  while (i < n) {
    i <<= 1;
    ++(*lambda);
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lpt>:
  endbr64
  movl   $0x0,(%rsi)
  cmp    $0x1,%edi
  jle    L16
  mov    $0x1,%edx
  mov    $0x1,%eax
L19:
  add    %eax,%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  cmp    %eax,%edi
  jg     L19
  mov    %ecx,(%rsi)
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int lpt(int n, int *lambda) {
  register int i = 1;
  *lambda = 0;
  while (i < n) {
    i <<= 1;
    ++(*lambda);
  }
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lpt>:
  endbr64
  movl   $0x0,(%rsi)
  cmp    $0x1,%edi
  jle    L14
  mov    $0x1,%edx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L18:
  add    %eax,%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  cmp    %eax,%edi
  jg     L18
  mov    %ecx,(%rsi)
  ret
  xchg   %ax,%ax
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int lpt(int n, int *lambda) {
  register int i = 1;
  *lambda = 0;
  while (i < n) {
    i <<= 1;
    ++(*lambda);
  }
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lpt>:
  endbr64
  movl   $0x0,(%rsi)
  cmp    $0x1,%edi
  jle    L9
  mov    $0x1,%edx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L14:
  add    %eax,%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  cmp    %eax,%edi
  jg     L14
  mov    %ecx,(%rsi)
  ret
  xchg   %ax,%ax
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int lpt(int n, int *lambda) {
  register int i = 1;
  *lambda = 0;
  while (i < n) {
    i <<= 1;
    ++(*lambda);
  }
  return (i);
}
```
user: What is the c source code of the assembly code below:

```asm
<Mstrcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jg     L7
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L7:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
int Mstrcpy(int nargs, int *argsv) {
  if (nargs < 2) {
    eset(21);
    return -1;
  }
  char *a = (char *)argsv[0];
  char *b = (char *)argsv[1];
  int x = (int)strcpy(a, b);
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<Mstrcpy>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L5
  movslq 0x4(%rsi),%rax
  movslq (%rsi),%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
L14:
  add    $0x8,%rsp
  ret
L5:
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int Mstrcpy(int nargs, int *argsv) {
  if (nargs < 2) {
    eset(21);
    return -1;
  }
  char *a = (char *)argsv[0];
  char *b = (char *)argsv[1];
  int x = (int)strcpy(a, b);
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Mstrcpy>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L16
  movslq 0x4(%rsi),%r8
  movslq (%rsi),%rdi
  mov    %r8,%rsi
  call   <strcpy@plt>
L14:
  add    $0x8,%rsp
  ret
L16:
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int Mstrcpy(int nargs, int *argsv) {
  if (nargs < 2) {
    eset(21);
    return -1;
  }
  char *a = (char *)argsv[0];
  char *b = (char *)argsv[1];
  int x = (int)strcpy(a, b);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Mstrcpy>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L14
  movslq 0x4(%rsi),%r8
  movslq (%rsi),%rdi
  mov    %r8,%rsi
  call   <strcpy@plt>
L4:
  add    $0x8,%rsp
  ret
L14:
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  jmp    L4
```

assistant: ```c
int Mstrcpy(int nargs, int *argsv) {
  if (nargs < 2) {
    eset(21);
    return -1;
  }
  char *a = (char *)argsv[0];
  char *b = (char *)argsv[1];
  int x = (int)strcpy(a, b);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  je     L22
  cmpl   $0x2,-0x14(%rbp)
  jne    L19
L22:
  mov    $0x1,%eax
  jmp    L10
L19:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int x) {
  if (x == 1 || x == 2) {
    return 1;
  } else {
    return fib(x - 1) + fib(x - 2);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fib>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  ja     L8
  ret
L8:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edx,%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fib(int x) {
  if (x == 1 || x == 2) {
    return 1;
  } else {
    return fib(x - 1) + fib(x - 2);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mat2_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movss  0x8(%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movss  0xc(%rax),%xmm0
  movss  %xmm0,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mat2_copy(float *dst, float *src) {
  dst[0] = src[0];
  dst[1] = src[1];
  dst[2] = src[2];
  dst[3] = src[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mat2_copy>:
  endbr64
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void mat2_copy(float *dst, float *src) {
  dst[0] = src[0];
  dst[1] = src[1];
  dst[2] = src[2];
  dst[3] = src[3];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mat2_copy>:
  endbr64
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void mat2_copy(float *dst, float *src) {
  dst[0] = src[0];
  dst[1] = src[1];
  dst[2] = src[2];
  dst[3] = src[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mat2_copy>:
  endbr64
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void mat2_copy(float *dst, float *src) {
  dst[0] = src[0];
  dst[1] = src[1];
  dst[2] = src[2];
  dst[3] = src[3];
}
```
user: What is the c source code of the assembly code below:

```asm
<strcmpic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%r12
  mov    -0x30(%rbp),%rbx
  jmp    L45
L78:
  movzbl (%r12),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L33
  movzbl (%r12),%eax
  movsbl %al,%eax
  lea    0x20(%rax),%r13d
  jmp    L8
L33:
  movzbl (%r12),%eax
  movsbl %al,%r13d
L8:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L20
  movzbl (%rbx),%eax
  movsbl %al,%eax
  add    $0x20,%eax
  jmp    L24
L20:
  movzbl (%rbx),%eax
  movsbl %al,%eax
L24:
  cmp    %eax,%r13d
  jne    L72
  add    $0x1,%rbx
  add    $0x1,%r12
L45:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L78
  jmp    L115
L72:
  nop
L115:
  movzbl (%r12),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L36
  movzbl (%r12),%eax
  movsbl %al,%eax
  lea    0x20(%rax),%r12d
  jmp    L74
L36:
  movzbl (%r12),%eax
  movsbl %al,%r12d
L74:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L38
  movzbl (%rbx),%eax
  movsbl %al,%eax
  add    $0x20,%eax
  jmp    L41
L38:
  movzbl (%rbx),%eax
  movsbl %al,%eax
L41:
  mov    %r12d,%edx
  sub    %eax,%edx
  mov    %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int strcmpic(char *s1, char *s2) {
  register char *u = s1;
  register char *p = s2;
  while (*p != '\0') {
    if ((isupper(*u) ? *u - 'A' + 'a' : *u) == (isupper(*p) ? *p - 'A' + 'a' : *p)) {
      p++;
      u++;
    } else {
      break;
    }
  }
  return ((isupper(*u) ? *u - 'A' + 'a' : *u) - (isupper(*p) ? *p - 'A' + 'a' : *p));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcmpic>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  cmpb   $0x0,(%rsi)
  jne    L81
L30:
  movsbl 0x0(%rbp),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L36
  movsbl 0x0(%rbp),%eax
  lea    0x20(%rax),%ebp
L109:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L22
  movsbl (%rbx),%edx
  add    $0x20,%edx
L98:
  mov    %ebp,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L87:
  movsbl 0x0(%rbp),%r12d
  jmp    L59
L21:
  movsbl (%rbx),%eax
L99:
  cmp    %eax,%r12d
  jne    L30
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmpb   $0x0,(%rbx)
  je     L30
L81:
  movsbl 0x0(%rbp),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L87
  movsbl 0x0(%rbp),%r12d
  add    $0x20,%r12d
L59:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L21
  movsbl (%rbx),%eax
  add    $0x20,%eax
  jmp    L99
L36:
  movsbl 0x0(%rbp),%ebp
  jmp    L109
L22:
  movsbl (%rbx),%edx
  jmp    L98
```

assistant: ```c
int strcmpic(char *s1, char *s2) {
  register char *u = s1;
  register char *p = s2;
  while (*p != '\0') {
    if ((isupper(*u) ? *u - 'A' + 'a' : *u) == (isupper(*p) ? *p - 'A' + 'a' : *p)) {
      p++;
      u++;
    } else {
      break;
    }
  }
  return ((isupper(*u) ? *u - 'A' + 'a' : *u) - (isupper(*p) ? *p - 'A' + 'a' : *p));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcmpic>:
  endbr64
  cmpb   $0x0,(%rsi)
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jne    L32
  jmp    L52
  nopl   (%rax)
L76:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmpb   $0x0,(%rbx)
  je     L52
L32:
  movsbl 0x0(%rbp),%edi
  call   <isupper@plt>
  movsbl 0x0(%rbp),%r12d
  test   %rax,%rax
  je     L8
  add    $0x20,%r12d
L8:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  movsbl (%rbx),%eax
  je     L7
  add    $0x20,%eax
L7:
  cmp    %eax,%r12d
  je     L76
L52:
  movsbl 0x0(%rbp),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L22
  movsbl 0x0(%rbp),%eax
  lea    0x20(%rax),%ebp
L66:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  movsbl (%rbx),%edx
  test   %rax,%rax
  je     L77
  add    $0x20,%edx
L77:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  nopl   (%rax)
L22:
  movsbl 0x0(%rbp),%ebp
  jmp    L66
```

assistant: ```c
int strcmpic(char *s1, char *s2) {
  register char *u = s1;
  register char *p = s2;
  while (*p != '\0') {
    if ((isupper(*u) ? *u - 'A' + 'a' : *u) == (isupper(*p) ? *p - 'A' + 'a' : *p)) {
      p++;
      u++;
    } else {
      break;
    }
  }
  return ((isupper(*u) ? *u - 'A' + 'a' : *u) - (isupper(*p) ? *p - 'A' + 'a' : *p));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcmpic>:
  endbr64
  cmpb   $0x0,(%rsi)
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jne    L43
  jmp    L84
  nopl   (%rax)
L50:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmpb   $0x0,(%rbx)
  je     L84
L43:
  movsbl 0x0(%rbp),%edi
  call   <isupper@plt>
  movsbl 0x0(%rbp),%r12d
  test   %rax,%rax
  je     L82
  add    $0x20,%r12d
L82:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  movsbl (%rbx),%eax
  je     L60
  add    $0x20,%eax
L60:
  cmp    %eax,%r12d
  je     L50
L84:
  movsbl 0x0(%rbp),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L23
  movsbl 0x0(%rbp),%eax
  lea    0x20(%rax),%ebp
L83:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  movsbl (%rbx),%edx
  test   %rax,%rax
  je     L1
  add    $0x20,%edx
L1:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  nopl   (%rax)
L23:
  movsbl 0x0(%rbp),%ebp
  jmp    L83
```

assistant: ```c
int strcmpic(char *s1, char *s2) {
  register char *u = s1;
  register char *p = s2;
  while (*p != '\0') {
    if ((isupper(*u) ? *u - 'A' + 'a' : *u) == (isupper(*p) ? *p - 'A' + 'a' : *p)) {
      p++;
      u++;
    } else {
      break;
    }
  }
  return ((isupper(*u) ? *u - 'A' + 'a' : *u) - (isupper(*p) ? *p - 'A' + 'a' : *p));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_errno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int set_errno(int code) {
  errno = code;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_errno>:
  endbr64
  mov    D3(%rip),%rax
  mov    %edi,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int set_errno(int code) {
  errno = code;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<set_errno>:
  endbr64
  mov    D9(%rip),%rax
  mov    %edi,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int set_errno(int code) {
  errno = code;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_errno>:
  endbr64
  mov    D8(%rip),%rax
  mov    %edi,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int set_errno(int code) {
  errno = code;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x91,-0x14(%rbp)
  jg     L48
  cmpl   $0x5c,-0x14(%rbp)
  jge    L40
  cmpl   $0x3a,-0x14(%rbp)
  je     L34
  cmpl   $0x47,-0x14(%rbp)
  je     L34
  jmp    L48
L40:
  mov    -0x14(%rbp),%eax
  sub    $0x5c,%eax
  movabs $0x2e001001901421,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L48
L34:
  movl   $0x1,-0x4(%rbp)
  nop
L48:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_matrix(const int symbology) {
  int result = 0;
  switch (symbology) {
  case 58:
  case 71:
  case 97:
  case 102:
  case 92:
  case 104:
  case 112:
  case 128:
  case 141:
  case 142:
  case 116:
  case 115:
  case 143:
  case 145:
    result = 1;
    break;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_matrix>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x91,%edi
  jg     L15
  cmp    $0x5b,%edi
  jle    L28
  lea    -0x5c(%rdi),%ecx
  movabs $0x2e001001901421,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L28:
  cmp    $0x3a,%edi
  je     L16
  cmp    $0x47,%edi
  sete   %al
  movzbl %al,%eax
  ret
L16:
  mov    $0x1,%eax
L15:
  ret
```

assistant: ```c
int is_matrix(const int symbology) {
  int result = 0;
  switch (symbology) {
  case 58:
  case 71:
  case 97:
  case 102:
  case 92:
  case 104:
  case 112:
  case 128:
  case 141:
  case 142:
  case 116:
  case 115:
  case 143:
  case 145:
    result = 1;
    break;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_matrix>:
  endbr64
  xor    %eax,%eax
  cmp    $0x91,%edi
  jg     L10
  cmp    $0x5b,%edi
  jle    L11
  movabs $0x2e001001901421,%rax
  lea    -0x5c(%rdi),%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
L10:
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  cmp    $0x3a,%edi
  je     L18
  xor    %eax,%eax
  cmp    $0x47,%edi
  sete   %al
  ret
```

assistant: ```c
int is_matrix(const int symbology) {
  int result = 0;
  switch (symbology) {
  case 58:
  case 71:
  case 97:
  case 102:
  case 92:
  case 104:
  case 112:
  case 128:
  case 141:
  case 142:
  case 116:
  case 115:
  case 143:
  case 145:
    result = 1;
    break;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_matrix>:
  endbr64
  xor    %eax,%eax
  cmp    $0x91,%edi
  jg     L24
  cmp    $0x5b,%edi
  jle    L3
  movabs $0x2e001001901421,%rax
  lea    -0x5c(%rdi),%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    $0x1,%eax
L24:
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  cmp    $0x3a,%edi
  je     L21
  xor    %eax,%eax
  cmp    $0x47,%edi
  sete   %al
  ret
```

assistant: ```c
int is_matrix(const int symbology) {
  int result = 0;
  switch (symbology) {
  case 58:
  case 71:
  case 97:
  case 102:
  case 92:
  case 104:
  case 112:
  case 128:
  case 141:
  case 142:
  case 116:
  case 115:
  case 143:
  case 145:
    result = 1;
    break;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<imgFreeAll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <imgFreePixelBuffers@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <imgFreeImage@plt>
  jmp    L12
L18:
  nop
L12:
  leave
  ret
```

assistant: ```c
void imgFreeAll(struct imgImage *img) {
  if (!img)
    return;
  imgFreePixelBuffers(img);
  imgFreeImage(img);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<imgFreeAll>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbx
  mov    %rdi,%rbx
  call   <imgFreePixelBuffers@plt>
  mov    %rbx,%rdi
  call   <imgFreeImage@plt>
  pop    %rbx
  ret
L0:
  ret
```

assistant: ```c
void imgFreeAll(struct imgImage *img) {
  if (!img)
    return;
  imgFreePixelBuffers(img);
  imgFreeImage(img);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<imgFreeAll>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbp
  mov    %rdi,%rbp
  call   <imgFreePixelBuffers@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <imgFreeImage@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void imgFreeAll(struct imgImage *img) {
  if (!img)
    return;
  imgFreePixelBuffers(img);
  imgFreeImage(img);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<imgFreeAll>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  call   <imgFreePixelBuffers@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <imgFreeImage@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void imgFreeAll(struct imgImage *img) {
  if (!img)
    return;
  imgFreePixelBuffers(img);
  imgFreeImage(img);
}
```