ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<itob>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%r10d
  mov    %edx,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x4e4d4c4b4a494847,%rax
  movabs $0x565554535251504f,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movl   $0x5a595857,0x20(%rsp)
  movb   $0x0,0x24(%rsp)
  lea    -0x2(%rdi),%eax
  cmp    $0x22,%eax
  ja     L35
  mov    %rsi,%r9
  mov    %r10d,%edx
  neg    %edx
  cmovs  %r10d,%edx
  mov    $0x0,%ecx
L31:
  mov    %ecx,%r8d
  add    $0x1,%ecx
  mov    %edx,%eax
  cltd
  idiv   %edi
  movslq %edx,%rdx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,(%rsi)
  mov    %eax,%edx
  add    $0x1,%rsi
  test   %eax,%eax
  jg     L31
  test   %r10d,%r10d
  js     L36
L43:
  movslq %ecx,%rcx
  movb   $0x0,(%r9,%rcx,1)
  mov    %r9,%rdi
  call   <reverse@plt>
L35:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x38,%rsp
  ret
L36:
  movslq %ecx,%rcx
  movb   $0x2d,(%r9,%rcx,1)
  lea    0x2(%r8),%ecx
  jmp    L43
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itob(int n, char s[], int b) {
  const char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int i, sign;
  if (b < 2 || b > 36) {
    return;
  }
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  do {
    s[i++] = digits[n % b];
  } while ((n /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<itob>:
  endbr64
  sub    $0x38,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    -0x2(%rdx),%eax
  movl   $0x5a595857,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D4(%rip),%xmm0
  movb   $0x0,0x24(%rsp)
  movaps %xmm0,0x10(%rsp)
  cmp    $0x22,%eax
  ja     L5
  mov    %edi,%r10d
  mov    %rsi,%r9
  mov    %edx,%edi
  mov    %r10d,%eax
  neg    %eax
  cmovs  %r10d,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L45:
  cltd
  mov    %ecx,%r8d
  add    $0x1,%rsi
  idiv   %edi
  add    $0x1,%ecx
  movslq %edx,%rdx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %eax,%eax
  jne    L45
  test   %r10d,%r10d
  js     L33
L14:
  movslq %ecx,%rcx
  movb   $0x0,(%r9,%rcx,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %r9,%rdi
  add    $0x38,%rsp
  jmp    1060 <reverse@plt>
  nopl   0x0(%rax)
L33:
  movslq %ecx,%rcx
  movb   $0x2d,(%r9,%rcx,1)
  lea    0x2(%r8),%ecx
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: byte[16]
name: unpack_data
arguments: data_tag: D4
datatype: byte[16]

tool: {"D9": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: {"D4": [0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50,0x51,0x52,0x53,0x54,0x55,0x56]}

assistant: ```c
void itob(int n, char s[], int b) {
  const char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int i, sign;
  if (b < 2 || b > 36) {
    return;
  }
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  do {
    s[i++] = digits[n % b];
  } while ((n /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<itob>:
  endbr64
  sub    $0x38,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    -0x2(%rdx),%eax
  movl   $0x5a595857,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D9(%rip),%xmm0
  movb   $0x0,0x24(%rsp)
  movaps %xmm0,0x10(%rsp)
  cmp    $0x22,%eax
  ja     L50
  mov    %edi,%r10d
  mov    %rsi,%r9
  mov    %edx,%edi
  mov    %r10d,%eax
  neg    %eax
  cmovs  %r10d,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L28:
  cltd
  mov    %ecx,%r8d
  add    $0x1,%rsi
  idiv   %edi
  add    $0x1,%ecx
  movslq %edx,%rdx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %eax,%eax
  jne    L28
  test   %r10d,%r10d
  js     L23
L33:
  movslq %ecx,%rcx
  movb   $0x0,(%r9,%rcx,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %r9,%rdi
  add    $0x38,%rsp
  jmp    1060 <reverse@plt>
  nopl   0x0(%rax)
L23:
  movslq %ecx,%rcx
  movb   $0x2d,(%r9,%rcx,1)
  lea    0x2(%r8),%ecx
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D9
type_infered: byte[16]

tool: {"D19": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: {"D9": [0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50,0x51,0x52,0x53,0x54,0x55,0x56]}

assistant: ```c
void itob(int n, char s[], int b) {
  const char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int i, sign;
  if (b < 2 || b > 36) {
    return;
  }
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  do {
    s[i++] = digits[n % b];
  } while ((n /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tcp_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    $0x2,%rax
  jle    L74
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L74
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    $0x3,%rax
  je     L11
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L74
L11:
  mov    $0x1,%eax
  jmp    L70
L74:
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L48
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L48:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L32
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L77
L32:
  mov    $0x0,%eax
  jmp    L70
L77:
  mov    $0x1,%eax
L70:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: tcp

assistant: ```c
int tcp_match(char const *s, char const *e) {
  char const *col;
  if (e - s >= 3 && !strncasecmp(s, "tcp", 3) && (e - s == 3 || s[3] == ':'))
    return true;
  if ((col = memchr(s, ':', e - s)) == NULL)
    col = e;
  if (memchr(s, '.', col - s) == NULL || memchr(s, '/', col - s) != NULL)
    return false;
  return true;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tcp_match>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rbx
  sub    %rdi,%rbx
  cmp    $0x2,%rbx
  jle    L49
  mov    $0x3,%edx
  lea    D8(%rip),%rsi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L49
  mov    $0x1,%eax
  cmp    $0x3,%rbx
  je     L34
  cmpb   $0x3a,0x3(%rbp)
  je     L34
L49:
  mov    %ebx,%edx
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  cmove  %r12,%rax
  mov    %eax,%ebx
  sub    %ebp,%ebx
  mov    %ebx,%edx
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L34
  mov    %ebx,%edx
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: tcp

assistant: ```c
int tcp_match(char const *s, char const *e) {
  char const *col;
  if (e - s >= 3 && !strncasecmp(s, "tcp", 3) && (e - s == 3 || s[3] == ':'))
    return true;
  if ((col = memchr(s, ':', e - s)) == NULL)
    col = e;
  if (memchr(s, '.', col - s) == NULL || memchr(s, '/', col - s) != NULL)
    return false;
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tcp_match>:
  endbr64
  push   %r12
  sub    %rdi,%rsi
  push   %rbp
  mov    %rsi,%r12
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmp    $0x2,%rsi
  jle    L47
  mov    $0x3,%edx
  lea    D1(%rip),%rsi
  call   <strncasecmp@plt>
  test   %eax,%eax
  je     L20
L47:
  mov    %r12d,%edx
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  cmovne %edx,%r12d
  mov    %r12d,%edx
  call   <memchr@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L39
  mov    %r12d,%edx
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L39:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%eax
  cmp    $0x3,%r12
  je     L39
  cmpb   $0x3a,0x3(%rbp)
  jne    L47
  jmp    L39
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: tcp

assistant: ```c
int tcp_match(char const *s, char const *e) {
  char const *col;
  if (e - s >= 3 && !strncasecmp(s, "tcp", 3) && (e - s == 3 || s[3] == ':'))
    return true;
  if ((col = memchr(s, ':', e - s)) == NULL)
    col = e;
  if (memchr(s, '.', col - s) == NULL || memchr(s, '/', col - s) != NULL)
    return false;
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tcp_match>:
  endbr64
  push   %r12
  sub    %rdi,%rsi
  push   %rbp
  mov    %rsi,%r12
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmp    $0x2,%rsi
  jle    L34
  mov    $0x3,%edx
  lea    D6(%rip),%rsi
  call   <strncasecmp@plt>
  test   %eax,%eax
  je     L41
L34:
  mov    %r12d,%edx
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  cmovne %edx,%r12d
  mov    %r12d,%edx
  call   <memchr@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L28
  mov    %r12d,%edx
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L28:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    $0x1,%eax
  cmp    $0x3,%r12
  je     L28
  cmpb   $0x3a,0x3(%rbp)
  jne    L34
  jmp    L28
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: tcp

assistant: ```c
int tcp_match(char const *s, char const *e) {
  char const *col;
  if (e - s >= 3 && !strncasecmp(s, "tcp", 3) && (e - s == 3 || s[3] == ':'))
    return true;
  if ((col = memchr(s, ':', e - s)) == NULL)
    col = e;
  if (memchr(s, '.', col - s) == NULL || memchr(s, '/', col - s) != NULL)
    return false;
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Cmd_Exec_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L8
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  jmp    L18
L8:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%edx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <FS_LoadFile@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L32
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  jmp    L18
L32:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  mov    -0x1c(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <Z_Malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <Cbuf_InsertText@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <Z_Free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <FS_FreeFile@plt>
L18:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string
name: read_data
arguments: tag: D12
type_infered: string

tool: D5: exec <filename> : execute a script file


tool: D16: couldn't exec %s


tool: D12: execing %s


assistant: ```c
void Cmd_Exec_f(void) {
  char *f, *f2;
  int len;
  if (Cmd_Argc() != 2) {
    Com_Printf("exec <filename> : execute a script file\n");
    return;
  }
  len = FS_LoadFile(Cmd_Argv(1), (void **)&f);
  if (!f) {
    Com_Printf("couldn't exec %s\n", Cmd_Argv(1));
    return;
  }
  Com_Printf("execing %s\n", Cmd_Argv(1));
  f2 = Z_Malloc(len + 2);
  memcpy(f2, f, len);
  f2[len] = '\n';
  f2[len + 1] = '\0';
  Cbuf_InsertText(f2);
  Z_Free(f2);
  FS_FreeFile(f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Cmd_Exec_f>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L21
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%edi
  mov    %rsp,%rsi
  call   <FS_LoadFile@plt>
  mov    %eax,%ebx
  cmpq   $0x0,(%rsp)
  je     L26
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  lea    0x2(%rbx),%edi
  call   <Z_Malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    (%rsp),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0xa,0x0(%rbp,%rbx,1)
  movb   $0x0,0x1(%rbp,%rbx,1)
  mov    %rbp,%rdi
  call   <Cbuf_InsertText@plt>
  mov    %rbp,%rdi
  call   <Z_Free@plt>
  mov    (%rsp),%rdi
  call   <FS_FreeFile@plt>
  jmp    L4
L26:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  jmp    L4
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string
name: extract_symbolic_data
arguments: tag: D25
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string

tool: D2: exec <filename> : execute a script file


tool: D25: execing %s


tool: D27: couldn't exec %s


assistant: ```c
void Cmd_Exec_f(void) {
  char *f, *f2;
  int len;
  if (Cmd_Argc() != 2) {
    Com_Printf("exec <filename> : execute a script file\n");
    return;
  }
  len = FS_LoadFile(Cmd_Argv(1), (void **)&f);
  if (!f) {
    Com_Printf("couldn't exec %s\n", Cmd_Argv(1));
    return;
  }
  Com_Printf("execing %s\n", Cmd_Argv(1));
  f2 = Z_Malloc(len + 2);
  memcpy(f2, f, len);
  f2[len] = '\n';
  f2[len + 1] = '\0';
  Cbuf_InsertText(f2);
  Z_Free(f2);
  FS_FreeFile(f);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cmd_Exec_f>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L27
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1150 <Com_Printf@plt>
  nopl   0x0(%rax)
L27:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %rsp,%rsi
  mov    %eax,%edi
  call   <FS_LoadFile@plt>
  cmpq   $0x0,(%rsp)
  mov    $0x1,%edi
  movslq %eax,%rbx
  je     L20
  call   <Cmd_Argv@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <Com_Printf@plt>
  lea    0x2(%rbx),%edi
  call   <Z_Malloc@plt>
  mov    (%rsp),%rsi
  mov    %ebx,%edx
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0xa,0x0(%rbp,%rbx,1)
  mov    %rbp,%rdi
  movb   $0x0,0x1(%rbp,%rbx,1)
  call   <Cbuf_InsertText@plt>
  mov    %rbp,%rdi
  call   <Z_Free@plt>
  mov    (%rsp),%rdi
  call   <FS_FreeFile@plt>
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  call   <Cmd_Argv@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <Com_Printf@plt>
  jmp    L40
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string
name: unpack_data
arguments: data_tag: D24
data_type: string

tool: D29: exec <filename> : execute a script file


tool: D2: execing %s


tool: D24: couldn't exec %s


assistant: ```c
void Cmd_Exec_f(void) {
  char *f, *f2;
  int len;
  if (Cmd_Argc() != 2) {
    Com_Printf("exec <filename> : execute a script file\n");
    return;
  }
  len = FS_LoadFile(Cmd_Argv(1), (void **)&f);
  if (!f) {
    Com_Printf("couldn't exec %s\n", Cmd_Argv(1));
    return;
  }
  Com_Printf("execing %s\n", Cmd_Argv(1));
  f2 = Z_Malloc(len + 2);
  memcpy(f2, f, len);
  f2[len] = '\n';
  f2[len + 1] = '\0';
  Cbuf_InsertText(f2);
  Z_Free(f2);
  FS_FreeFile(f);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Cmd_Exec_f>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L47
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1150 <Com_Printf@plt>
  nopl   0x0(%rax)
L47:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %rsp,%rsi
  mov    %eax,%edi
  call   <FS_LoadFile@plt>
  cmpq   $0x0,(%rsp)
  mov    $0x1,%edi
  movslq %eax,%rbx
  je     L2
  call   <Cmd_Argv@plt>
  lea    D25(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <Com_Printf@plt>
  lea    0x2(%rbx),%edi
  call   <Z_Malloc@plt>
  mov    (%rsp),%rsi
  mov    %ebx,%edx
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0xa,0x0(%rbp,%rbx,1)
  mov    %rbp,%rdi
  movb   $0x0,0x1(%rbp,%rbx,1)
  call   <Cbuf_InsertText@plt>
  mov    %rbp,%rdi
  call   <Z_Free@plt>
  mov    (%rsp),%rdi
  call   <FS_FreeFile@plt>
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  call   <Cmd_Argv@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <Com_Printf@plt>
  jmp    L40
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D25
data_type: string
name: extract_symbolic_data
arguments: tag: D29
data_type: string

tool: D13: exec <filename> : execute a script file


tool: D25: execing %s


tool: D29: couldn't exec %s


assistant: ```c
void Cmd_Exec_f(void) {
  char *f, *f2;
  int len;
  if (Cmd_Argc() != 2) {
    Com_Printf("exec <filename> : execute a script file\n");
    return;
  }
  len = FS_LoadFile(Cmd_Argv(1), (void **)&f);
  if (!f) {
    Com_Printf("couldn't exec %s\n", Cmd_Argv(1));
    return;
  }
  Com_Printf("execing %s\n", Cmd_Argv(1));
  f2 = Z_Malloc(len + 2);
  memcpy(f2, f, len);
  f2[len] = '\n';
  f2[len + 1] = '\0';
  Cbuf_InsertText(f2);
  Z_Free(f2);
  FS_FreeFile(f);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<opt_numint_fdiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <opt_numint_sgn@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <opt_numint_sgn@plt>
  imul   %ebx,%eax
  test   %eax,%eax
  jns    L26
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  je     L26
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  sub    $0x1,%rax
  jmp    L12
L26:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long long int opt_numint_fdiv(long long int num, long long int den) {
  if ((opt_numint_sgn(num) * opt_numint_sgn(den) < 0) && (num % den)) {
    return num / den - 1;
  } else {
    return num / den;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<opt_numint_fdiv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <opt_numint_sgn@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <opt_numint_sgn@plt>
  imul   %eax,%r12d
  test   %r12d,%r12d
  jns    L6
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  test   %rdx,%rdx
  je     L6
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  sub    $0x1,%rax
  jmp    L14
L6:
  mov    %rbx,%rax
  cqto
  idiv   %rbp
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long int opt_numint_fdiv(long long int num, long long int den) {
  if ((opt_numint_sgn(num) * opt_numint_sgn(den) < 0) && (num % den)) {
    return num / den - 1;
  } else {
    return num / den;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<opt_numint_fdiv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <opt_numint_sgn@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <opt_numint_sgn@plt>
  imul   %eax,%ebp
  test   %ebp,%ebp
  jns    L15
  mov    %r12,%rax
  cqto
  idiv   %rbx
  sub    $0x1,%rax
  test   %rdx,%rdx
  jne    L14
L15:
  mov    %r12,%rax
  cqto
  idiv   %rbx
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long int opt_numint_fdiv(long long int num, long long int den) {
  if ((opt_numint_sgn(num) * opt_numint_sgn(den) < 0) && (num % den)) {
    return num / den - 1;
  } else {
    return num / den;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<opt_numint_fdiv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <opt_numint_sgn@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <opt_numint_sgn@plt>
  imul   %eax,%ebp
  test   %ebp,%ebp
  jns    L18
  mov    %r12,%rax
  cqto
  idiv   %rbx
  sub    $0x1,%rax
  test   %rdx,%rdx
  jne    L2
L18:
  mov    %r12,%rax
  cqto
  idiv   %rbx
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long int opt_numint_fdiv(long long int num, long long int den) {
  if ((opt_numint_sgn(num) * opt_numint_sgn(den) < 0) && (num % den)) {
    return num / den - 1;
  } else {
    return num / den;
  }
}
```