ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x64(%rsp),%rbx
  call   <time@plt>
  mov    %rbp,%r12
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,0x60(%r12)
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L3
  mov    %rbp,%rdi
  call   <printarray@plt>
  mov    %rbp,%rdi
  mov    $0x19,%esi
  call   <mergesort_itr@plt>
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rdi
  call   <printarray@plt>
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[(2)][(25)];
  int i;
  srand(time(NULL));
  for (i = 0; i < (25); ++i) {
    array[(0)][i] = array[(1)][i] = rand() % 100;
  }
  printarray(array[(0)]);
  i = mergesort_itr(array, (25));
  return printarray(array[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_order>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L6
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L6
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <hexprint@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <hexprint@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L6:
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string
name: disassemble_data
arguments: tag: D14
data_type: string
name: disassemble_data
arguments: tag: D24
data_type: string

tool: D4: first:

tool: D14: second:

tool: D24: FAIL: keys not ordered

assistant: ```c
int check_order(const char *key, void *value, void *arg) {
  char **prev = arg;
  if (*prev && strcmp(*prev, key) >= 0) {
    hexprint("first:", *prev);
    hexprint("second:", key);
    die("FAIL: keys not ordered");
  }
  *prev = value;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_order>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    (%rdx),%rdi
  test   %rdi,%rdi
  je     L18
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L24
L18:
  mov    %rbp,(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    (%rbx),%rsi
  lea    D2(%rip),%rdi
  call   <hexprint@plt>
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  call   <hexprint@plt>
  lea    D1(%rip),%rdi
  call   <die@plt>
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D2: first:

tool: D0: second:

tool: D1: FAIL: keys not ordered

assistant: ```c
int check_order(const char *key, void *value, void *arg) {
  char **prev = arg;
  if (*prev && strcmp(*prev, key) >= 0) {
    hexprint("first:", *prev);
    hexprint("second:", key);
    die("FAIL: keys not ordered");
  }
  *prev = value;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_order>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    (%rdx),%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L6
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L17
L6:
  mov    %rbp,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    (%rbx),%rsi
  lea    D11(%rip),%rdi
  call   <hexprint@plt>
  mov    %r12,%rsi
  lea    D3(%rip),%rdi
  call   <hexprint@plt>
  lea    D26(%rip),%rdi
  call   <die@plt>
  mov    %rbp,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D11
data_type: string
name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D26
data_type: string

tool: D11: first:

tool: D3: second:

tool: D26: FAIL: keys not ordered

assistant: ```c
int check_order(const char *key, void *value, void *arg) {
  char **prev = arg;
  if (*prev && strcmp(*prev, key) >= 0) {
    hexprint("first:", *prev);
    hexprint("second:", key);
    die("FAIL: keys not ordered");
  }
  *prev = value;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_order>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    (%rdx),%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L2
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L11
L2:
  mov    %rbp,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    (%rbx),%rsi
  lea    D18(%rip),%rdi
  call   <hexprint@plt>
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  call   <hexprint@plt>
  lea    D26(%rip),%rdi
  call   <die@plt>
  mov    %rbp,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D12
datatype: string
name: extract_symbolic_data
arguments: label: D26
datatype: string

tool: D18: first:

tool: D12: second:

tool: D26: FAIL: keys not ordered

assistant: ```c
int check_order(const char *key, void *value, void *arg) {
  char **prev = arg;
  if (*prev && strcmp(*prev, key) >= 0) {
    hexprint("first:", *prev);
    hexprint("second:", key);
    die("FAIL: keys not ordered");
  }
  *prev = value;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swapone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int swapone(int *A, int left, int right) {
  int tmp;
  tmp = A[left];
  A[left] = A[right];
  A[right] = tmp;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swapone>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int swapone(int *A, int left, int right) {
  int tmp;
  tmp = A[left];
  A[left] = A[right];
  A[right] = tmp;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swapone>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rax),%edx
  mov    (%rcx),%esi
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int swapone(int *A, int left, int right) {
  int tmp;
  tmp = A[left];
  A[left] = A[right];
  A[right] = tmp;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swapone>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rax),%edx
  mov    (%rcx),%esi
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int swapone(int *A, int left, int right) {
  int tmp;
  tmp = A[left];
  A[left] = A[right];
  A[right] = tmp;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xrop3_228_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_228_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T ^ S;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_228_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%esi
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  xor    %edi,%edx
  movzbl %dl,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_228_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T ^ S;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_228_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  mov    %esi,%edx
  shl    $0x8,%edi
  shl    $0x8,%edx
  or     %eax,%edi
  or     %esi,%edx
  xor    %edi,%edx
  movzbl %dl,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_228_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T ^ S;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_228_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  mov    %esi,%edx
  shl    $0x8,%edi
  shl    $0x8,%edx
  or     %eax,%edi
  or     %esi,%edx
  xor    %edi,%edx
  movzbl %dl,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_228_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T ^ S;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<allocArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x2,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <halloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L18:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: size = %d, init = %d, descriptor = 0x%x


assistant: ```c
int *allocArray(int size, int init, int descriptor) {
  int i;
  int *a = (int *)halloc((2 + size) * sizeof(int));
  printf("size = %d, init = %d, descriptor = 0x%x\n", size, init, descriptor);
  a[0] = descriptor;
  a[1] = size;
  for (i = 0; i < size; i++)
    a[i + 2] = init;
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<allocArray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r13d
  lea    0x8(,%rdi,4),%edi
  call   <halloc@plt>
  mov    %rax,%r12
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r13d,(%r12)
  mov    %ebp,0x4(%r12)
  test   %ebp,%ebp
  jle    L8
  lea    0x8(%r12),%rax
  lea    -0x1(%rbp),%edx
  lea    0xc(%r12,%rdx,4),%rdx
L17:
  mov    %ebx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L17
L8:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: size = %d, init = %d, descriptor = 0x%x


assistant: ```c
int *allocArray(int size, int init, int descriptor) {
  int i;
  int *a = (int *)halloc((2 + size) * sizeof(int));
  printf("size = %d, init = %d, descriptor = 0x%x\n", size, init, descriptor);
  a[0] = descriptor;
  a[1] = size;
  for (i = 0; i < size; i++)
    a[i + 2] = init;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<allocArray>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    0x8(,%rdi,4),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <halloc@plt>
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %rax,%r12
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r13d,(%r12)
  mov    %ebp,0x4(%r12)
  test   %ebp,%ebp
  jle    L11
  lea    -0x1(%rbp),%edx
  lea    0x8(%r12),%rax
  lea    0xc(%r12,%rdx,4),%rdx
  nopl   0x0(%rax)
L1:
  mov    %ebx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L1
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: size = %d, init = %d, descriptor = 0x%x


assistant: ```c
int *allocArray(int size, int init, int descriptor) {
  int i;
  int *a = (int *)halloc((2 + size) * sizeof(int));
  printf("size = %d, init = %d, descriptor = 0x%x\n", size, init, descriptor);
  a[0] = descriptor;
  a[1] = size;
  for (i = 0; i < size; i++)
    a[i + 2] = init;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<allocArray>:
  endbr64
  push   %r13
  movd   %edi,%xmm1
  movd   %edx,%xmm0
  mov    %edx,%r13d
  push   %r12
  punpckldq %xmm1,%xmm0
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x8(,%rdi,4),%edi
  sub    $0x18,%rsp
  movq   %xmm0,0x8(%rsp)
  call   <halloc@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  mov    %rax,%r12
  call   <printf@plt>
  movq   0x8(%rsp),%xmm0
  movq   %xmm0,(%r12)
  test   %ebx,%ebx
  jle    L20
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L26
  mov    %ebx,%edx
  movd   %ebp,%xmm2
  lea    0x8(%r12),%rax
  shr    $0x2,%edx
  pshufd $0x0,%xmm2,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x18(%r12,%rdx,1),%rdx
L10:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L10
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L20
L53:
  lea    0x2(%rax),%ecx
  add    $0x1,%eax
  movslq %ecx,%rdx
  mov    %ebp,(%r12,%rdx,4)
  lea    0x0(,%rdx,4),%rsi
  cmp    %eax,%ebx
  jle    L20
  mov    %ebp,0x4(%r12,%rsi,1)
  cmp    %ecx,%ebx
  jle    L20
  mov    %ebp,0x8(%r12,%rsi,1)
L20:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  xor    %eax,%eax
  jmp    L53
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string

tool: D3: size = %d, init = %d, descriptor = 0x%x


assistant: ```c
int *allocArray(int size, int init, int descriptor) {
  int i;
  int *a = (int *)halloc((2 + size) * sizeof(int));
  printf("size = %d, init = %d, descriptor = 0x%x\n", size, init, descriptor);
  a[0] = descriptor;
  a[1] = size;
  for (i = 0; i < size; i++)
    a[i + 2] = init;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<validation>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0xa,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  mov    %rdi,%rdx
  lea    0xa(%rdi),%rcx
L58:
  movzbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L22
  add    $0x1,%rdx
  cmp    %rdx,%rcx
  jne    L58
  movzbl 0x4(%rdi),%edx
  cmp    $0x3,%dl
  je     L12
  mov    $0x0,%eax
  cmp    $0x33,%dl
  jg     L156
  jmp    L19
L12:
  mov    $0x0,%eax
  cmpb   $0x31,0x5(%rdi)
  jg     L156
L19:
  movzbl 0x2(%rdi),%edx
  mov    $0x0,%eax
  cmp    $0x35,%dl
  jg     L156
  ja     L99
  movabs $0x2a000000000000,%rax
  bt     %rdx,%rax
  jae    L46
  mov    $0x0,%eax
  cmpb   $0x32,0x3(%rdi)
  jg     L156
  mov    $0x0,%edx
  mov    $0x0,%ecx
L136:
  mov    %rsp,%rsi
L90:
  movsbl (%rdi,%rdx,1),%eax
  sub    $0x30,%eax
  mov    %eax,0x30(%rsp,%rdx,4)
  imul   (%rsi,%rdx,4),%eax
  add    %eax,%ecx
  add    $0x1,%rdx
  cmp    $0xa,%rdx
  jne    L90
  movslq %ecx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    $0x9,%eax
  jg     L108
  cmp    %eax,0x54(%rsp)
  sete   %al
  movzbl %al,%eax
  jmp    L156
L99:
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L136
L46:
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L136
L108:
  cmpl   $0x0,0x54(%rsp)
  sete   %al
  movzbl %al,%eax
  jmp    L156
L22:
  mov    $0x0,%eax
L156:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x78,%rsp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int validation(char *EGN) {
  int counter = 0, cont = 0, chisla[12];
  int weights[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (counter = 0; counter < 10; counter++) {
    if (EGN[counter] < '0' || EGN[counter] > '9') {
      return 0;
    }
  }
  if (EGN[4] == 3 && EGN[5] > '1') {
    return 0;
  }
  if (EGN[4] > '3' || counter == 0 || EGN[2] >= '6') {
    return 0;
  }
  if (EGN[2] == '1' || EGN[2] == '3' || EGN[2] == '5')
    if (EGN[3] > '2') {
      return 0;
    }
  counter = 0;
  while (counter < 10) {
    chisla[counter] = EGN[counter] - 48;
    if (counter < 10) {
      cont = cont + (weights[counter] * chisla[counter]);
    }
    counter++;
  }
  cont = cont % 11;
  if (cont < 10)
    if (chisla[9] != cont) {
      return 0;
    }
  if (cont == 10)
    if (chisla[9] != 0) {
      return 0;
    }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<validation>:
  endbr64
  sub    $0x78,%rsp
  mov    %rdi,%rcx
  lea    0xa(%rdi),%rsi
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x800000004,%rax
  mov    %rax,0x4(%rsp)
  movabs $0xa00000005,%rax
  mov    %rax,0xc(%rsp)
  movabs $0x700000009,%rax
  mov    %rax,0x14(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x1c(%rsp)
  nopl   0x0(%rax)
L35:
  movzbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L60
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L35
  movzbl 0x4(%rcx),%edx
  xor    %eax,%eax
  cmp    $0x3,%dl
  je     L15
  cmp    $0x33,%dl
  jg     L106
L90:
  movzbl 0x2(%rcx),%edx
  xor    %eax,%eax
  cmp    $0x35,%dl
  jg     L106
  ja     L125
  movabs $0x2a000000000000,%rsi
  bt     %rdx,%rsi
  jae    L125
  cmpb   $0x32,0x3(%rcx)
  jg     L106
L125:
  xor    %edx,%edx
  mov    $0x2,%edi
  lea    0x30(%rsp),%r8
  xor    %esi,%esi
  jmp    L111
  nopw   0x0(%rax,%rax,1)
L122:
  mov    (%rsp,%rdx,4),%edi
L111:
  movsbl (%rcx,%rdx,1),%eax
  sub    $0x30,%eax
  mov    %eax,(%r8,%rdx,4)
  imul   %edi,%eax
  add    $0x1,%rdx
  add    %eax,%esi
  cmp    $0xa,%rdx
  jne    L122
  movslq %esi,%rax
  mov    %esi,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %esi,%eax
  sub    %edx,%eax
  mov    0x54(%rsp),%edx
  cmp    $0xa,%eax
  je     L31
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  nopl   (%rax)
L106:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L105
  add    $0x78,%rsp
  ret
  nopl   (%rax)
L15:
  cmpb   $0x31,0x5(%rcx)
  jle    L90
  jmp    L106
  nopl   0x0(%rax)
L60:
  xor    %eax,%eax
  jmp    L106
L31:
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
  jmp    L106
L105:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int validation(char *EGN) {
  int counter = 0, cont = 0, chisla[12];
  int weights[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (counter = 0; counter < 10; counter++) {
    if (EGN[counter] < '0' || EGN[counter] > '9') {
      return 0;
    }
  }
  if (EGN[4] == 3 && EGN[5] > '1') {
    return 0;
  }
  if (EGN[4] > '3' || counter == 0 || EGN[2] >= '6') {
    return 0;
  }
  if (EGN[2] == '1' || EGN[2] == '3' || EGN[2] == '5')
    if (EGN[3] > '2') {
      return 0;
    }
  counter = 0;
  while (counter < 10) {
    chisla[counter] = EGN[counter] - 48;
    if (counter < 10) {
      cont = cont + (weights[counter] * chisla[counter]);
    }
    counter++;
  }
  cont = cont % 11;
  if (cont < 10)
    if (chisla[9] != cont) {
      return 0;
    }
  if (cont == 10)
    if (chisla[9] != 0) {
      return 0;
    }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mkdtemp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <anvil_syslog@plt>
L7:
  jmp    L7
```

tool_calls: name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D19
datatype: string

tool: D18: mkdtemp

tool: D19: %s unimplemented


assistant: ```c
char *mkdtemp(char *template) {
  anvil_syslog(0, "%s unimplemented\n", __FUNCTION__);
  while (1)
    ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mkdtemp>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdx
  lea    D11(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <anvil_syslog@plt>
L3:
  jmp    L3
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D3: mkdtemp

tool: D11: %s unimplemented


assistant: ```c
char *mkdtemp(char *template) {
  anvil_syslog(0, "%s unimplemented\n", __FUNCTION__);
  while (1)
    ;
  return 0;
}
```