user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x4c(%rbp),%rdx
  lea    -0x50(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D31(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  lea    -0x44(%rbp),%rdx
  lea    -0x48(%rbp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    -0x3c(%rbp),%rdx
  lea    -0x40(%rbp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x40(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L97
L200:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L200
L97:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L74
L123:
  mov    %rsp,%r14
  test   %ecx,%ecx
  jle    L146
  mov    %r14,%r12
  xor    %ebx,%ebx
  lea    D25(%rip),%r15
L104:
  mov    %r12,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    %ebx,-0x40(%rbp)
  jg     L104
L146:
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L73
L61:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L61
L73:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L86
L98:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L29
  mov    %rbx,%r13
  xor    %r12d,%r12d
  lea    D25(%rip),%r15
  nop
L175:
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <scanf@plt>
  mov    -0x3c(%rbp),%edx
  add    $0x4,%r13
  cmp    %r12d,%edx
  jg     L175
  mov    -0x40(%rbp),%edi
  test   %edi,%edi
  jle    L178
L108:
  mov    -0x48(%rbp),%r9d
  mov    -0x50(%rbp),%r8d
  xor    %eax,%eax
  xor    %esi,%esi
  mov    -0x4c(%rbp),%r10d
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%r14,%rax,4),%ecx
  add    %r9d,%ecx
  cmp    %r8d,%ecx
  jl     L183
  cmp    %r10d,%ecx
  setle  %cl
  movzbl %cl,%ecx
  add    %ecx,%esi
L183:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L9
L32:
  test   %edx,%edx
  jle    L116
  sub    $0x1,%edx
  mov    -0x44(%rbp),%r9d
  mov    -0x50(%rbp),%edi
  mov    %rbx,%rax
  mov    -0x4c(%rbp),%r10d
  lea    0x4(%rbx,%rdx,4),%rcx
  xor    %r8d,%r8d
L211:
  mov    (%rax),%edx
  add    %r9d,%edx
  cmp    %edi,%edx
  jl     L149
  cmp    %r10d,%edx
  setle  %dl
  movzbl %dl,%edx
  add    %edx,%r8d
L149:
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L211
L38:
  mov    %r8d,%edx
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L194
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L86:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L98
L74:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L123
L29:
  mov    -0x40(%rbp),%edi
  xor    %esi,%esi
  xor    %r8d,%r8d
  test   %edi,%edi
  jg     L108
  jmp    L38
L178:
  xor    %esi,%esi
  jmp    L32
L116:
  xor    %r8d,%r8d
  jmp    L38
L194:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D25
data_type: string
name: unpack_data
arguments: tag: D30
data_type: string

tool: D31: %d %d

tool: D25: %d

tool: D30: %d
%d

assistant: ```c
int main() {
  int s;
  int t;
  scanf("%d %d", &s, &t);
  int a;
  int b;
  scanf("%d %d", &a, &b);
  int m;
  int n;
  scanf("%d %d", &m, &n);
  int apple[m];
  for (int apple_i = 0; apple_i < m; apple_i++) {
    scanf("%d", &apple[apple_i]);
  }
  int orange[n];
  for (int orange_i = 0; orange_i < n; orange_i++) {
    scanf("%d", &orange[orange_i]);
  }
  int numOfApples = 0;
  int numOfOranges = 0;
  for (int i = 0; i < m; i++) {
    if ((a + apple[i]) >= s && (a + apple[i]) <= t) {
      numOfApples++;
    }
  }
  for (int i = 0; i < n; i++) {
    if ((b + orange[i]) >= s && (b + orange[i]) <= t) {
      numOfOranges++;
    }
  }
  printf("%d\n%d", numOfApples, numOfOranges);
  return 0;
}
```