ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<change_check_pull>:
  endbr64
  lea    0x51(%rsi),%rcx
  lea    0x32a(%rsi),%r9
  xor    %r10d,%r10d
  nopw   0x0(%rax,%rax,1)
L247:
  lea    -0x51(%rcx),%rax
  mov    %rdi,%rdx
  jmp    L180
  nopl   0x0(%rax)
L167:
  add    $0x9,%rax
  add    $0x1,%rdx
  cmp    %rax,%rcx
  je     L105
L180:
  cmpb   $0x20,(%rdx)
  jne    L167
  movzbl (%rax),%r8d
  movzbl 0x1(%rax),%esi
  cmp    $0x20,%r8b
  je     L29
  cmp    $0x20,%sil
  jne    L167
  mov    %r8d,%esi
L63:
  cmpb   $0x20,0x2(%rax)
  jne    L167
  cmpb   $0x20,0x3(%rax)
  jne    L167
  cmpb   $0x20,0x4(%rax)
  je     L161
  add    $0x9,%rax
  add    $0x1,%rdx
  cmp    %rax,%rcx
  jne    L180
L105:
  add    $0x51,%rcx
  add    $0x9,%rdi
  cmp    %r9,%rcx
  jne    L247
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax)
L29:
  cmp    $0x20,%sil
  jne    L63
  movzbl 0x2(%rax),%esi
  movzbl 0x3(%rax),%r8d
  cmp    $0x20,%sil
  je     L96
  cmp    $0x20,%r8b
  jne    L167
  cmpb   $0x20,0x4(%rax)
  jne    L167
L161:
  cmpb   $0x20,0x5(%rax)
  jne    L167
  nopw   0x0(%rax,%rax,1)
L316:
  cmpb   $0x20,0x6(%rax)
  jne    L167
  cmpb   $0x20,0x7(%rax)
  jne    L167
L116:
  cmpb   $0x20,0x8(%rax)
  jne    L167
L41:
  mov    %sil,(%rdx)
  mov    $0x1,%r10d
  jmp    L167
L96:
  movzbl 0x4(%rax),%esi
  cmp    $0x20,%r8b
  je     L146
  cmp    $0x20,%sil
  jne    L167
  cmpb   $0x20,0x5(%rax)
  jne    L167
  cmpb   $0x20,0x6(%rax)
  jne    L167
  nopl   0x0(%rax)
L381:
  cmpb   $0x20,0x7(%rax)
  jne    L167
  cmpb   $0x20,0x8(%rax)
  jne    L167
  mov    %r8d,%esi
  jmp    L41
L146:
  movzbl 0x5(%rax),%r8d
  cmp    $0x20,%sil
  je     L36
  cmp    $0x20,%r8b
  jne    L167
  jmp    L316
L36:
  movzbl 0x6(%rax),%esi
  cmp    $0x20,%r8b
  je     L358
  cmp    $0x20,%sil
  jne    L167
  jmp    L381
L358:
  cmp    $0x20,%sil
  je     L144
  cmpb   $0x20,0x7(%rax)
  jne    L167
  cmpb   $0x20,0x8(%rax)
  jne    L167
  mov    %sil,(%rdx)
  mov    $0x1,%r10d
  jmp    L167
L144:
  movzbl 0x7(%rax),%esi
  cmp    $0x20,%sil
  jne    L116
  movzbl 0x8(%rax),%esi
  cmp    $0x20,%sil
  jne    L41
  jmp    L167
```

assistant: ```c
bool change_check_pull(char pattern[9][9], char possibilities[9][9][9]) {
  bool change = false;
  for (int x = 0; x < 9; x++) {
    for (int y = 0; y < 9; y++) {
      if (pattern[x][y] == ' ') {
        bool numberbool = false;
        char numberchar = ' ';
        for (int z = 0; z < 9; z++) {
          if (possibilities[x][y][z] != ' ') {
            if (!numberbool) {
              numberbool = true;
              numberchar = possibilities[x][y][z];
            } else {
              numberbool = false;
              break;
            }
          }
        }
        if (numberbool) {
          pattern[x][y] = numberchar;
          change = true;
        }
      }
    }
  }
  return change;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_mx_log_level>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <mx_log_level_get@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <mx_log_level_set@plt>
  cmp    %eax,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <mx_log_level_get@plt>
  cmp    %eax,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <test_mx_log_shortname@plt>
  cmpl   $0x0,-0x14(%rbp)
  setg   %dl
  movzbl %dl,%ecx
  mov    -0x14(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <test_mx_log@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int test_mx_log_level(int level) {
  int x;
  int curr;
  curr = mx_log_level_get();
  assert(mx_log_level_set(level) == curr);
  assert(mx_log_level_get() == level);
  assert(test_mx_log_shortname() == level + (level > 0));
  assert((x = test_mx_log()) == level);
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_mx_log_level>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <mx_log_level_get@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <mx_log_level_set@plt>
  cmp    %ebp,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <mx_log_level_get@plt>
  cmp    %ebx,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <test_mx_log_shortname@plt>
  mov    %eax,%edx
  test   %ebx,%ebx
  setg   %al
  movzbl %al,%eax
  add    %ebx,%eax
  cmp    %edx,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <test_mx_log@plt>
  mov    %eax,%ebp
  cmp    %eax,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int test_mx_log_level(int level) {
  int x;
  int curr;
  curr = mx_log_level_get();
  assert(mx_log_level_set(level) == curr);
  assert(mx_log_level_get() == level);
  assert(test_mx_log_shortname() == level + (level > 0));
  assert((x = test_mx_log()) == level);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_mx_log_level>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <mx_log_level_get@plt>
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <mx_log_level_set@plt>
  xor    %edi,%edi
  cmp    %r12d,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <mx_log_level_get@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <test_mx_log_shortname@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %ebx,%ebx
  setg   %al
  xor    %edi,%edi
  add    %ebx,%eax
  cmp    %r8d,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <test_mx_log@plt>
  xor    %edi,%edi
  cmp    %eax,%ebx
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int test_mx_log_level(int level) {
  int x;
  int curr;
  curr = mx_log_level_get();
  assert(mx_log_level_set(level) == curr);
  assert(mx_log_level_get() == level);
  assert(test_mx_log_shortname() == level + (level > 0));
  assert((x = test_mx_log()) == level);
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sum@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0xa,-0x4(%rbp)
  jle    L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string

tool: D6: n=%d wa=%d


assistant: ```c
main() {
  int n = 1;
  while (n <= 10) {
    printf("n=%d wa=%d\n", n, sum(n));
    n++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D7(%rip),%rbp
L2:
  mov    %ebx,%edi
  call   <sum@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: n=%d wa=%d


assistant: ```c
main() {
  int n = 1;
  while (n <= 10) {
    printf("n=%d wa=%d\n", n, sum(n));
    n++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  call   <sum@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: n=%d wa=%d


assistant: ```c
main() {
  int n = 1;
  while (n <= 10) {
    printf("n=%d wa=%d\n", n, sum(n));
    n++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  call   <sum@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: n=%d wa=%d


assistant: ```c
main() {
  int n = 1;
  while (n <= 10) {
    printf("n=%d wa=%d\n", n, sum(n));
    n++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bgra8888_to_abgr8888_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0x2,%eax
  add    $0x3,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L45
  cmpl   $0x0,-0x1c(%rbp)
  jle    L45
  cmpl   $0x0,-0x20(%rbp)
  jle    L45
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L45
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bgra8888_to_abgr8888@plt>
  test   %rax,%rax
  je     L45
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
L45:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *bgra8888_to_abgr8888_buffer(const void *psrc, int w, int h) {
  int size = h * (((w * 4) + 3) & ~3);
  void *pdst = NULL;
  if (psrc && w > 0 && h > 0) {
    pdst = malloc(size);
    if (pdst) {
      if (bgra8888_to_abgr8888(psrc, w, h, pdst)) {
        free(pdst);
        pdst = NULL;
      }
    }
  }
  return pdst;
}
```
user: What is the c source code of the assembly code below?

```asm
<bgra8888_to_abgr8888_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  test   %rdi,%rdi
  setne  %dl
  test   %ebx,%ebx
  setg   %al
  test   %al,%dl
  je     L40
  mov    %rdi,%r12
  mov    %esi,%ebp
  test   %esi,%esi
  jle    L40
  lea    0x0(,%rsi,4),%edi
  imul   %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L36
  mov    %rax,%rcx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <bgra8888_to_abgr8888@plt>
  test   %rax,%rax
  je     L36
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%r13d
  jmp    L36
L40:
  mov    $0x0,%r13d
L36:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *bgra8888_to_abgr8888_buffer(const void *psrc, int w, int h) {
  int size = h * (((w * 4) + 3) & ~3);
  void *pdst = NULL;
  if (psrc && w > 0 && h > 0) {
    pdst = malloc(size);
    if (pdst) {
      if (bgra8888_to_abgr8888(psrc, w, h, pdst)) {
        free(pdst);
        pdst = NULL;
      }
    }
  }
  return pdst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bgra8888_to_abgr8888_buffer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dl
  test   %r12d,%r12d
  setg   %al
  test   %al,%dl
  je     L17
  mov    %esi,%ebp
  test   %esi,%esi
  jle    L17
  mov    %rdi,%r13
  lea    0x0(,%rsi,4),%edi
  imul   %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L17
  mov    %rax,%rcx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <bgra8888_to_abgr8888@plt>
  test   %rax,%rax
  je     L39
  mov    %r14,%rdi
  call   <free@plt>
L17:
  xor    %r14d,%r14d
L39:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *bgra8888_to_abgr8888_buffer(const void *psrc, int w, int h) {
  int size = h * (((w * 4) + 3) & ~3);
  void *pdst = NULL;
  if (psrc && w > 0 && h > 0) {
    pdst = malloc(size);
    if (pdst) {
      if (bgra8888_to_abgr8888(psrc, w, h, pdst)) {
        free(pdst);
        pdst = NULL;
      }
    }
  }
  return pdst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bgra8888_to_abgr8888_buffer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dl
  test   %r12d,%r12d
  setg   %al
  test   %al,%dl
  je     L18
  mov    %esi,%ebp
  test   %esi,%esi
  jle    L18
  mov    %rdi,%r13
  lea    0x0(,%rsi,4),%edi
  imul   %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L18
  mov    %rax,%rcx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <bgra8888_to_abgr8888@plt>
  test   %rax,%rax
  je     L19
  mov    %r14,%rdi
  call   <free@plt>
L18:
  xor    %r14d,%r14d
L19:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *bgra8888_to_abgr8888_buffer(const void *psrc, int w, int h) {
  int size = h * (((w * 4) + 3) & ~3);
  void *pdst = NULL;
  if (psrc && w > 0 && h > 0) {
    pdst = malloc(size);
    if (pdst) {
      if (bgra8888_to_abgr8888(psrc, w, h, pdst)) {
        free(pdst);
        pdst = NULL;
      }
    }
  }
  return pdst;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitfn_swap32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  bswap  %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t bitfn_swap32(uint32_t a) {
  asm("bswap %0" : "=r"(a) : "0"(a));
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bitfn_swap32>:
  endbr64
  mov    %rdi,%rax
  bswap  %rax
  ret
```

assistant: ```c
uint32_t bitfn_swap32(uint32_t a) {
  asm("bswap %0" : "=r"(a) : "0"(a));
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitfn_swap32>:
  endbr64
  mov    %rdi,%rax
  bswap  %rax
  ret
```

assistant: ```c
uint32_t bitfn_swap32(uint32_t a) {
  asm("bswap %0" : "=r"(a) : "0"(a));
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitfn_swap32>:
  endbr64
  mov    %rdi,%rax
  bswap  %rax
  ret
```

assistant: ```c
uint32_t bitfn_swap32(uint32_t a) {
  asm("bswap %0" : "=r"(a) : "0"(a));
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getCurrentTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
long getCurrentTime() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getCurrentTime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  cltq
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long getCurrentTime() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getCurrentTime>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  cltq
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long getCurrentTime() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getCurrentTime>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  cltq
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long getCurrentTime() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nsleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x44b82fa1,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1c,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x44b82fa1,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1c,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x3b9aca00,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  cmpl   $0x0,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void nsleep(int64_t wait_ns) {
  struct timespec tp;
  int rc;
  tp.tv_sec = wait_ns / 1000000000;
  tp.tv_nsec = wait_ns % 1000000000;
  nanosleep(&tp, NULL);
  assert(rc == 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nsleep>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x44b82fa1,%rax,%rax
  sar    $0x3c,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3b9aca00,%eax,%eax
  sub    %eax,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nsleep(int64_t wait_ns) {
  struct timespec tp;
  int rc;
  tp.tv_sec = wait_ns / 1000000000;
  tp.tv_nsec = wait_ns % 1000000000;
  nanosleep(&tp, NULL);
  assert(rc == 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nsleep>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  imul   $0x44b82fa1,%rax,%rax
  sar    $0x3c,%rax
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3b9aca00,%eax,%eax
  sub    %eax,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  call   <nanosleep@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nsleep(int64_t wait_ns) {
  struct timespec tp;
  int rc;
  tp.tv_sec = wait_ns / 1000000000;
  tp.tv_nsec = wait_ns % 1000000000;
  nanosleep(&tp, NULL);
  assert(rc == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nsleep>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  imul   $0x44b82fa1,%rax,%rax
  sar    $0x3c,%rax
  sub    %edx,%eax
  imul   $0x3b9aca00,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%edi
  movd   %edi,%xmm1
  mov    %rsp,%rdi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  call   <nanosleep@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nsleep(int64_t wait_ns) {
  struct timespec tp;
  int rc;
  tp.tv_sec = wait_ns / 1000000000;
  tp.tv_nsec = wait_ns % 1000000000;
  nanosleep(&tp, NULL);
  assert(rc == 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ensure_buffer@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void write_buffer(struct matlab_buffer *buffer, void *data, size_t size) {
  void *target = ensure_buffer(buffer, size);
  memcpy(target, data, size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_buffer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  call   <ensure_buffer@plt>
  mov    %rax,%rdi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_buffer(struct matlab_buffer *buffer, void *data, size_t size) {
  void *target = ensure_buffer(buffer, size);
  memcpy(target, data, size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_buffer>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  call   <ensure_buffer@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void write_buffer(struct matlab_buffer *buffer, void *data, size_t size) {
  void *target = ensure_buffer(buffer, size);
  memcpy(target, data, size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_buffer>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  call   <ensure_buffer@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void write_buffer(struct matlab_buffer *buffer, void *data, size_t size) {
  void *target = ensure_buffer(buffer, size);
  memcpy(target, data, size);
}
```