ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<resparse>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L26:
  add    %rbx,%r15
  cmp    %r8,%r12
  jne    L27
  cmp    (%rsp),%r15
  jae    L27
L45:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <readfd@plt>
  xor    %edx,%edx
  mov    %rax,%rbx
  div    %rbp
  mov    %rbx,%r8
  sub    %rdx,%r8
  je     L26
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %r14d,%edi
  mov    %r8,0x8(%rsp)
  call   <punch_hole@plt>
  mov    0x8(%rsp),%r8
  test   %eax,%eax
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
bool resparse(int fd, off_t flen, size_t blksz, char *buf, size_t bufsz) {
  bool ret = false;
  off_t len, span = 0, offt = 0, rlen = 0;
  do {
    rlen = readfd(fd, buf, bufsz);
    if (rlen < 0)
      goto fail;
    len = rlen % blksz;
    rlen -= len;
    if (rlen > 0 && !punch_hole(fd, offt, blksz, buf, rlen))
      goto fail;
    offt += rlen + len;
  } while (rlen == bufsz && offt < flen);
  ret = true;
fail:
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L6
L8:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int _system(const char *command) {
  if (!command)
    return 0;
  errno = ENOSYS;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_system>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  jne    L17
L19:
  ret
L17:
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int _system(const char *command) {
  if (!command)
    return 0;
  errno = ENOSYS;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_system>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L5
  ret
  nopl   0x0(%rax)
L5:
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _system(const char *command) {
  if (!command)
    return 0;
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_system>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L0
  ret
  nopl   0x0(%rax)
L0:
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _system(const char *command) {
  if (!command)
    return 0;
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<assemble_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shr    $0x12,%eax
  add    %eax,%eax
  and    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  shr    $0x12,%eax
  and    $0x1,%eax
  or     %edx,%eax
  shl    $0xe,%eax
  movzwl %ax,%edx
  mov    -0x18(%rbp),%eax
  shr    $0x12,%eax
  shl    $0xd,%eax
  and    $0x2000,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%eax
  shr    $0x13,%eax
  or     %ecx,%eax
  and    $0x3fff,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x10,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <sign_extend@plt>
  cltq
  leave
  ret
```

assistant: ```c
unsigned long assemble_16(x, y)
unsigned int x, y;
{
  unsigned int temp;
  if ((0)) {
    temp = ((((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 1) | ((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) ^ ((x) >> (31 - (0)) & ((1 << ((0) - (0) + 1)) - 1))) & (~((-1) << 1)))) & (~((-1) << 2))) << 14) | (((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) ^ ((x) >> (31 - (1)) & ((1 << ((1) - (1) + 1)) - 1))) & (~((-1) << 1))) << 13) | (((y) >> (31 - (12)) & ((1 << ((12) - (0) + 1)) - 1)) & (~((-1) << 13)))) & (~((-1) << 14))));
  } else {
    temp = ((((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 1) | (((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1)))) & (~((-1) << 2))) << 14) | ((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 13) | (((y) >> (31 - (12)) & ((1 << ((12) - (0) + 1)) - 1)) & (~((-1) << 13)))) & (~((-1) << 14))));
  }
  return sign_extend(temp, 16);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<assemble_16>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  shr    $0x12,%eax
  lea    (%rax,%rax,1),%edi
  and    $0x2,%edi
  mov    %eax,%edx
  and    $0x1,%edx
  or     %edx,%edi
  shl    $0xe,%edi
  shl    $0xd,%eax
  and    $0x2000,%eax
  shr    $0x13,%esi
  or     %esi,%eax
  or     %eax,%edi
  mov    $0x10,%esi
  mov    $0x0,%eax
  call   <sign_extend@plt>
  cltq
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long assemble_16(x, y)
unsigned int x, y;
{
  unsigned int temp;
  if ((0)) {
    temp = ((((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 1) | ((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) ^ ((x) >> (31 - (0)) & ((1 << ((0) - (0) + 1)) - 1))) & (~((-1) << 1)))) & (~((-1) << 2))) << 14) | (((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) ^ ((x) >> (31 - (1)) & ((1 << ((1) - (1) + 1)) - 1))) & (~((-1) << 1))) << 13) | (((y) >> (31 - (12)) & ((1 << ((12) - (0) + 1)) - 1)) & (~((-1) << 13)))) & (~((-1) << 14))));
  } else {
    temp = ((((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 1) | (((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1)))) & (~((-1) << 2))) << 14) | ((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 13) | (((y) >> (31 - (12)) & ((1 << ((12) - (0) + 1)) - 1)) & (~((-1) << 13)))) & (~((-1) << 14))));
  }
  return sign_extend(temp, 16);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<assemble_16>:
  endbr64
  mov    %esi,%eax
  shr    $0x13,%esi
  sub    $0x8,%rsp
  shr    $0x12,%eax
  lea    (%rax,%rax,1),%edi
  mov    %eax,%edx
  shl    $0xd,%eax
  and    $0x1,%edx
  and    $0x2,%edi
  and    $0x2000,%eax
  or     %edx,%edi
  or     %esi,%eax
  mov    $0x10,%esi
  shl    $0xe,%edi
  or     %eax,%edi
  xor    %eax,%eax
  call   <sign_extend@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
unsigned long assemble_16(x, y)
unsigned int x, y;
{
  unsigned int temp;
  if ((0)) {
    temp = ((((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 1) | ((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) ^ ((x) >> (31 - (0)) & ((1 << ((0) - (0) + 1)) - 1))) & (~((-1) << 1)))) & (~((-1) << 2))) << 14) | (((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) ^ ((x) >> (31 - (1)) & ((1 << ((1) - (1) + 1)) - 1))) & (~((-1) << 1))) << 13) | (((y) >> (31 - (12)) & ((1 << ((12) - (0) + 1)) - 1)) & (~((-1) << 13)))) & (~((-1) << 14))));
  } else {
    temp = ((((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 1) | (((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1)))) & (~((-1) << 2))) << 14) | ((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 13) | (((y) >> (31 - (12)) & ((1 << ((12) - (0) + 1)) - 1)) & (~((-1) << 13)))) & (~((-1) << 14))));
  }
  return sign_extend(temp, 16);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<assemble_16>:
  endbr64
  mov    %esi,%eax
  shr    $0x13,%esi
  sub    $0x8,%rsp
  shr    $0x12,%eax
  lea    (%rax,%rax,1),%edi
  mov    %eax,%edx
  shl    $0xd,%eax
  and    $0x1,%edx
  and    $0x2,%edi
  and    $0x2000,%eax
  or     %edx,%edi
  or     %esi,%eax
  mov    $0x10,%esi
  shl    $0xe,%edi
  or     %eax,%edi
  xor    %eax,%eax
  call   <sign_extend@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
unsigned long assemble_16(x, y)
unsigned int x, y;
{
  unsigned int temp;
  if ((0)) {
    temp = ((((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 1) | ((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) ^ ((x) >> (31 - (0)) & ((1 << ((0) - (0) + 1)) - 1))) & (~((-1) << 1)))) & (~((-1) << 2))) << 14) | (((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) ^ ((x) >> (31 - (1)) & ((1 << ((1) - (1) + 1)) - 1))) & (~((-1) << 1))) << 13) | (((y) >> (31 - (12)) & ((1 << ((12) - (0) + 1)) - 1)) & (~((-1) << 13)))) & (~((-1) << 14))));
  } else {
    temp = ((((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 1) | (((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1)))) & (~((-1) << 2))) << 14) | ((((((y) >> (31 - (13)) & ((1 << ((13) - (13) + 1)) - 1)) & (~((-1) << 1))) << 13) | (((y) >> (31 - (12)) & ((1 << ((12) - (0) + 1)) - 1)) & (~((-1) << 13)))) & (~((-1) << 14))));
  }
  return sign_extend(temp, 16);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_shift>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    %r12,%rbx
  mov    %r13,%rbp
  lea    0x800(%r12),%r14
L14:
  mov    $0x0,%eax
  call   <randf@plt>
  movss  %xmm0,(%rbx)
  movl   $0x0,0x0(%rbp)
  movl   $0x0,0x800(%rbx)
  movl   $0x0,0x800(%rbp)
  add    $0x4,%rbx
  add    $0x4,%rbp
  cmp    %r14,%rbx
  jne    L14
  mov    $0x200,%esi
  sub    0xc(%rsp),%esi
  lea    0x800(%r15),%r9
  mov    %r15,%rdx
  mov    (%rsp),%rax
  mov    %rax,%r8
  sub    %r15,%r8
  lea    0x800(%rax),%rdi
  sub    %r15,%rdi
L9:
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  shr    $0x17,%ecx
  lea    (%rsi,%rcx,1),%eax
  and    $0x1ff,%eax
  sub    %ecx,%eax
  cltq
  movss  (%r12,%rax,4),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x0(%r13,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rdx,1)
  movl   $0x0,0x800(%rdx)
  movl   $0x0,(%rdi,%rdx,1)
  add    $0x1,%esi
  add    $0x4,%rdx
  cmp    %r9,%rdx
  jne    L9
  mov    $0x400,%r8d
  mov    (%rsp),%rcx
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <calculate_shift@plt>
  mov    0xc(%rsp),%edi
  cmp    %edi,%eax
  jne    L3
L0:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  mov    %eax,%edx
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: ERROR: Expected shift %i, but got %i


assistant: ```c
void test_shift(int shift) {
  int i, n = 512;
  float *re = (float *)malloc(sizeof(*re) * n * 2);
  float *im = (float *)malloc(sizeof(*im) * n * 2);
  float *re_shifted = (float *)malloc(sizeof(*re) * n * 2);
  float *im_shifted = (float *)malloc(sizeof(*im) * n * 2);
  for (i = 0; i < n; i++) {
    re[i] = randf();
    im[i] = 0.0f;
    re[i + n] = 0.0f;
    im[i + n] = 0.0f;
  }
  for (i = 0; i < n; i++) {
    int j = (i - shift + n) % n;
    re_shifted[i] = re[j];
    im_shifted[i] = im[j];
    re_shifted[i + n] = 0.0f;
    im_shifted[i + n] = 0.0f;
  }
  int calculated_shift = calculate_shift(re, im, re_shifted, im_shifted, n * 2);
  if (shift != calculated_shift) {
    printf("ERROR: Expected shift %i, but got %i\n", shift, calculated_shift);
    exit(-1);
  }
  free(re);
  free(im);
  free(re_shifted);
  free(im_shifted);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_shift>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %r15,%r13
  lea    0x800(%r15),%rbx
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rbp,%r14
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  add    $0x4,%r13
  add    $0x4,%r14
  call   <randf@plt>
  movss  %xmm0,-0x4(%r13)
  movl   $0x0,-0x4(%r14)
  movl   $0x0,0x7fc(%r13)
  movl   $0x0,0x7fc(%r14)
  cmp    %rbx,%r13
  jne    L1
  mov    (%rsp),%rax
  mov    $0x200,%esi
  mov    %r12,%rdx
  sub    0xc(%rsp),%esi
  lea    0x800(%r12),%r9
  lea    0x800(%rax),%rdi
  sub    %r12,%rax
  mov    %rax,%r8
  sub    %r12,%rdi
L22:
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  shr    $0x17,%ecx
  lea    (%rsi,%rcx,1),%eax
  add    $0x1,%esi
  and    $0x1ff,%eax
  sub    %ecx,%eax
  cltq
  movss  (%r15,%rax,4),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x0(%rbp,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rdx,1)
  movl   $0x0,0x800(%rdx)
  movl   $0x0,(%rdi,%rdx,1)
  add    $0x4,%rdx
  cmp    %r9,%rdx
  jne    L22
  mov    (%rsp),%rcx
  mov    %r12,%rdx
  mov    $0x400,%r8d
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <calculate_shift@plt>
  mov    %eax,%edx
  mov    0xc(%rsp),%eax
  cmp    %eax,%edx
  je     L23
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L23:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    (%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: ERROR: Expected shift %i, but got %i


assistant: ```c
void test_shift(int shift) {
  int i, n = 512;
  float *re = (float *)malloc(sizeof(*re) * n * 2);
  float *im = (float *)malloc(sizeof(*im) * n * 2);
  float *re_shifted = (float *)malloc(sizeof(*re) * n * 2);
  float *im_shifted = (float *)malloc(sizeof(*im) * n * 2);
  for (i = 0; i < n; i++) {
    re[i] = randf();
    im[i] = 0.0f;
    re[i + n] = 0.0f;
    im[i + n] = 0.0f;
  }
  for (i = 0; i < n; i++) {
    int j = (i - shift + n) % n;
    re_shifted[i] = re[j];
    im_shifted[i] = im[j];
    re_shifted[i + n] = 0.0f;
    im_shifted[i + n] = 0.0f;
  }
  int calculated_shift = calculate_shift(re, im, re_shifted, im_shifted, n * 2);
  if (shift != calculated_shift) {
    printf("ERROR: Expected shift %i, but got %i\n", shift, calculated_shift);
    exit(-1);
  }
  free(re);
  free(im);
  free(re_shifted);
  free(im_shifted);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_shift>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %r15,%r13
  lea    0x800(%r15),%rbx
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rbp,%r14
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  add    $0x4,%r13
  add    $0x4,%r14
  call   <randf@plt>
  movss  %xmm0,-0x4(%r13)
  movl   $0x0,-0x4(%r14)
  movl   $0x0,0x7fc(%r13)
  movl   $0x0,0x7fc(%r14)
  cmp    %r13,%rbx
  jne    L20
  mov    (%rsp),%rax
  mov    $0x200,%esi
  mov    %r12,%rdx
  sub    0xc(%rsp),%esi
  lea    0x800(%r12),%r9
  lea    0x800(%rax),%rdi
  sub    %r12,%rax
  mov    %rax,%r8
  sub    %r12,%rdi
L22:
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  shr    $0x17,%ecx
  lea    (%rsi,%rcx,1),%eax
  add    $0x1,%esi
  and    $0x1ff,%eax
  sub    %ecx,%eax
  cltq
  movss  (%r15,%rax,4),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x0(%rbp,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rdx,1)
  movl   $0x0,0x800(%rdx)
  movl   $0x0,(%rdi,%rdx,1)
  add    $0x4,%rdx
  cmp    %rdx,%r9
  jne    L22
  mov    (%rsp),%rcx
  mov    %r12,%rdx
  mov    $0x400,%r8d
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <calculate_shift@plt>
  mov    %eax,%edx
  mov    0xc(%rsp),%eax
  cmp    %eax,%edx
  je     L15
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L15:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    (%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2: ERROR: Expected shift %i, but got %i


assistant: ```c
void test_shift(int shift) {
  int i, n = 512;
  float *re = (float *)malloc(sizeof(*re) * n * 2);
  float *im = (float *)malloc(sizeof(*im) * n * 2);
  float *re_shifted = (float *)malloc(sizeof(*re) * n * 2);
  float *im_shifted = (float *)malloc(sizeof(*im) * n * 2);
  for (i = 0; i < n; i++) {
    re[i] = randf();
    im[i] = 0.0f;
    re[i + n] = 0.0f;
    im[i + n] = 0.0f;
  }
  for (i = 0; i < n; i++) {
    int j = (i - shift + n) % n;
    re_shifted[i] = re[j];
    im_shifted[i] = im[j];
    re_shifted[i + n] = 0.0f;
    im_shifted[i + n] = 0.0f;
  }
  int calculated_shift = calculate_shift(re, im, re_shifted, im_shifted, n * 2);
  if (shift != calculated_shift) {
    printf("ERROR: Expected shift %i, but got %i\n", shift, calculated_shift);
    exit(-1);
  }
  free(re);
  free(im);
  free(re_shifted);
  free(im_shifted);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ifx_dsl_dfe_setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <dsl_powerup@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L20:
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x270f,-0x4(%rbp)
  jle    L20
  mov    $0x0,%edi
  call   <wait_ppe_sync_state@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L15:
  addl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x270f,-0x4(%rbp)
  jle    L15
  mov    $0x1,%edi
  call   <wait_ppe_sync_state@plt>
  nop
  leave
  ret
```

assistant: ```c
void ifx_dsl_dfe_setup(void) {
  int i = 0;
  dsl_powerup();
  for (i = 0; i < 10000; i++)
    ;
  wait_ppe_sync_state(0);
  for (i = 0; i < 10000; i++)
    ;
  wait_ppe_sync_state(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ifx_dsl_dfe_setup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dsl_powerup@plt>
  mov    $0x2710,%eax
L2:
  sub    $0x1,%eax
  jne    L2
  mov    $0x0,%edi
  call   <wait_ppe_sync_state@plt>
  mov    $0x2710,%eax
L10:
  sub    $0x1,%eax
  jne    L10
  mov    $0x1,%edi
  call   <wait_ppe_sync_state@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ifx_dsl_dfe_setup(void) {
  int i = 0;
  dsl_powerup();
  for (i = 0; i < 10000; i++)
    ;
  wait_ppe_sync_state(0);
  for (i = 0; i < 10000; i++)
    ;
  wait_ppe_sync_state(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ifx_dsl_dfe_setup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dsl_powerup@plt>
  xor    %edi,%edi
  call   <wait_ppe_sync_state@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <wait_ppe_sync_state@plt>
```

assistant: ```c
void ifx_dsl_dfe_setup(void) {
  int i = 0;
  dsl_powerup();
  for (i = 0; i < 10000; i++)
    ;
  wait_ppe_sync_state(0);
  for (i = 0; i < 10000; i++)
    ;
  wait_ppe_sync_state(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ifx_dsl_dfe_setup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dsl_powerup@plt>
  xor    %edi,%edi
  call   <wait_ppe_sync_state@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <wait_ppe_sync_state@plt>
```

assistant: ```c
void ifx_dsl_dfe_setup(void) {
  int i = 0;
  dsl_powerup();
  for (i = 0; i < 10000; i++)
    ;
  wait_ppe_sync_state(0);
  for (i = 0; i < 10000; i++)
    ;
  wait_ppe_sync_state(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printSN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <printS@plt>
  mov    $0x0,%eax
  call   <lf@plt>
  nop
  leave
  ret
```

assistant: ```c
void printSN(const char *s, char *t) {
  printS(s, t);
  lf();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printSN>:
  endbr64
  sub    $0x8,%rsp
  call   <printS@plt>
  mov    $0x0,%eax
  call   <lf@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void printSN(const char *s, char *t) {
  printS(s, t);
  lf();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printSN>:
  endbr64
  sub    $0x8,%rsp
  call   <printS@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <lf@plt>
```

assistant: ```c
void printSN(const char *s, char *t) {
  printS(s, t);
  lf();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printSN>:
  endbr64
  sub    $0x8,%rsp
  call   <printS@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <lf@plt>
```

assistant: ```c
void printSN(const char *s, char *t) {
  printS(s, t);
  lf();
}
```