ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xff,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bitcount@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type_infered: string
name: parse_data
arguments: label: D2
type_infered: string

tool: D15: 0x%x


tool: D2: %d


assistant: ```c
main() {
  int x = 0xff;
  printf("0x%x\n", x);
  printf("%d\n", bitcount(x));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0xff,%edi
  call   <bitcount@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
datatype: string
name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D12: 0x%x


tool: D4: %d


assistant: ```c
main() {
  int x = 0xff;
  printf("0x%x\n", x);
  printf("%d\n", bitcount(x));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xff,%edi
  call   <bitcount@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string

tool: D1: 0x%x


tool: D8: %d


assistant: ```c
main() {
  int x = 0xff;
  printf("0x%x\n", x);
  printf("%d\n", bitcount(x));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xff,%edi
  call   <bitcount@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: string

tool: D2: 0x%x


tool: D18: %d


assistant: ```c
main() {
  int x = 0xff;
  printf("0x%x\n", x);
  printf("%d\n", bitcount(x));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__xcalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <mhandle_out_of_memory@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *__xcalloc(size_t nmemb, size_t size, char *at) {
  void *ptr;
  ptr = calloc(nmemb, size);
  if (!ptr)
    mhandle_out_of_memory(at);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__xcalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L19
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    %rbp,%rdi
  call   <mhandle_out_of_memory@plt>
  jmp    L8
```

assistant: ```c
void *__xcalloc(size_t nmemb, size_t size, char *at) {
  void *ptr;
  ptr = calloc(nmemb, size);
  if (!ptr)
    mhandle_out_of_memory(at);
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__xcalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    %rbp,%rdi
  call   <mhandle_out_of_memory@plt>
  jmp    L4
```

assistant: ```c
void *__xcalloc(size_t nmemb, size_t size, char *at) {
  void *ptr;
  ptr = calloc(nmemb, size);
  if (!ptr)
    mhandle_out_of_memory(at);
  return ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<__xcalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    %rbp,%rdi
  call   <mhandle_out_of_memory@plt>
  jmp    L16
```

assistant: ```c
void *__xcalloc(size_t nmemb, size_t size, char *at) {
  void *ptr;
  ptr = calloc(nmemb, size);
  if (!ptr)
    mhandle_out_of_memory(at);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L13
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L2
L13:
  mov    -0x418(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D6: Error.


tool: D5: %s


assistant: ```c
int main(void) {
  char buf[1024];
  char *cwd = getcwd(buf, sizeof(buf));
  if (cwd == NULL) {
    perror("Error.\n");
    exit(-1);
  } else {
    printf("%s\n", cwd);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x400,%esi
  call   <getcwd@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x418,%rsp
  ret
L10:
  lea    D10(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L7
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string
name: parse_data
arguments: label: D10
data_type: string

tool: D6: %s


tool: D10: Error.


assistant: ```c
int main(void) {
  char buf[1024];
  char *cwd = getcwd(buf, sizeof(buf));
  if (cwd == NULL) {
    perror("Error.\n");
    exit(-1);
  } else {
    printf("%s\n", cwd);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x418,%rsp
  mov    $0x400,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getcwd@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L28:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x418,%rsp
  ret
L7:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L28
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D9: %s


tool: D4: Error.


assistant: ```c
int main(void) {
  char buf[1024];
  char *cwd = getcwd(buf, sizeof(buf));
  if (cwd == NULL) {
    perror("Error.\n");
    exit(-1);
  } else {
    printf("%s\n", cwd);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x418,%rsp
  mov    $0x400,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getcwd@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
L3:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x418,%rsp
  ret
L11:
  lea    D18(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L3
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D18
type_infered: string

tool: D19: %s


tool: D18: Error.


assistant: ```c
int main(void) {
  char buf[1024];
  char *cwd = getcwd(buf, sizeof(buf));
  if (cwd == NULL) {
    perror("Error.\n");
    exit(-1);
  } else {
    printf("%s\n", cwd);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L17:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  addl   $0x1,-0x8(%rbp)
  cmpl   $0xa,-0x8(%rbp)
  jle    L17
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D10
data_type: string
name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D38
data_type: string
name: disassemble_data
arguments: tag: D30
data_type: string

tool: D10: Table of Triangular Numbers


tool: D2:  n  Sum from 1 to n

tool: D38: --- ---------------

tool: D30: %3i %15i


assistant: ```c
int main(void) {
  int n, triangularNumber;
  printf("Table of Triangular Numbers\n\n");
  printf(" n  Sum from 1 to n\n");
  printf("--- ---------------\n");
  triangularNumber = 0;
  n = 0;
  while (++n <= 10) {
    triangularNumber += n;
    printf("%3i %15i\n", n, triangularNumber);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  mov    $0x0,%ebp
  lea    D35(%rip),%r12
L3:
  add    %ebx,%ebp
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L3
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D30
data_type: string
name: read_data
arguments: tag: D39
data_type: string
name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D35
data_type: string

tool: D30: Table of Triangular Numbers


tool: D39:  n  Sum from 1 to n

tool: D8: --- ---------------

tool: D35: %3i %15i


assistant: ```c
int main(void) {
  int n, triangularNumber;
  printf("Table of Triangular Numbers\n\n");
  printf(" n  Sum from 1 to n\n");
  printf("--- ---------------\n");
  triangularNumber = 0;
  n = 0;
  while (++n <= 10) {
    triangularNumber += n;
    printf("%3i %15i\n", n, triangularNumber);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  lea    D25(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  call   <puts@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  add    %ebx,%ebp
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %ebp,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D25
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D31
type_guessed: string

tool: D0: Table of Triangular Numbers


tool: D25: %3i %15i


tool: D12:  n  Sum from 1 to n

tool: D31: --- ---------------

assistant: ```c
int main(void) {
  int n, triangularNumber;
  printf("Table of Triangular Numbers\n\n");
  printf(" n  Sum from 1 to n\n");
  printf("--- ---------------\n");
  triangularNumber = 0;
  n = 0;
  while (++n <= 10) {
    triangularNumber += n;
    printf("%3i %15i\n", n, triangularNumber);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  lea    D2(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  call   <puts@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  add    %ebx,%ebp
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %ebp,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L2
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string
name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D33
type_guessed: string
name: parse_data
arguments: label: D24
type_guessed: string

tool: D8: Table of Triangular Numbers


tool: D2: %3i %15i


tool: D33:  n  Sum from 1 to n

tool: D24: --- ---------------

assistant: ```c
int main(void) {
  int n, triangularNumber;
  printf("Table of Triangular Numbers\n\n");
  printf(" n  Sum from 1 to n\n");
  printf("--- ---------------\n");
  triangularNumber = 0;
  n = 0;
  while (++n <= 10) {
    triangularNumber += n;
    printf("%3i %15i\n", n, triangularNumber);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <tq2440_lcd_init@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L39:
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L27:
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    $0xff,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tq2440_lcd_set_color@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0xef,-0x4(%rbp)
  jle    L27
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0xef,-0x8(%rbp)
  jle    L39
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  tq2440_lcd_init();
  for (int i = 0; i < 240; ++i) {
    for (int j = 0; j < 240; ++j) {
      tq2440_lcd_set_color(i, j, 255);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tq2440_lcd_init@plt>
  mov    $0x0,%ebp
L5:
  mov    $0x0,%ebx
L18:
  mov    $0xff,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <tq2440_lcd_set_color@plt>
  add    $0x1,%ebx
  cmp    $0xf0,%ebx
  jne    L18
  add    $0x1,%ebp
  cmp    $0xf0,%ebp
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  tq2440_lcd_init();
  for (int i = 0; i < 240; ++i) {
    for (int j = 0; j < 240; ++j) {
      tq2440_lcd_set_color(i, j, 255);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <tq2440_lcd_init@plt>
L19:
  xor    %ebx,%ebx
  nopl   (%rax)
L2:
  mov    %ebx,%esi
  mov    $0xff,%edx
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <tq2440_lcd_set_color@plt>
  cmp    $0xf0,%ebx
  jne    L2
  add    $0x1,%ebp
  cmp    $0xf0,%ebp
  jne    L19
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  tq2440_lcd_init();
  for (int i = 0; i < 240; ++i) {
    for (int j = 0; j < 240; ++j) {
      tq2440_lcd_set_color(i, j, 255);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <tq2440_lcd_init@plt>
L16:
  xor    %ebx,%ebx
  nopl   (%rax)
L7:
  mov    %ebx,%esi
  mov    $0xff,%edx
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <tq2440_lcd_set_color@plt>
  cmp    $0xf0,%ebx
  jne    L7
  add    $0x1,%ebp
  cmp    $0xf0,%ebp
  jne    L16
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  tq2440_lcd_init();
  for (int i = 0; i < 240; ++i) {
    for (int j = 0; j < 240; ++j) {
      tq2440_lcd_set_color(i, j, 255);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L21
L7:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L50
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L54
  mov    -0x8(%rbp),%rax
  jmp    L31
L54:
  addq   $0x1,-0x10(%rbp)
L50:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x8(%rbp),%rax
L31:
  pop    %rbp
  ret
```

assistant: ```c
size_t strcspn(const char *s, const char *reject) {
  const char *p;
  const char *r;
  size_t count = 0;
  for (p = s; *p != '\0'; ++p) {
    for (r = reject; *r != '\0'; ++r) {
      if (*p == *r)
        return count;
    }
    ++count;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcspn>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L30
  movzbl (%rsi),%r9d
  mov    $0x0,%r8d
L45:
  mov    %rsi,%rdx
  mov    %r9d,%eax
  test   %r9b,%r9b
  je     L34
L38:
  cmp    %cl,%al
  je     L12
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L38
L34:
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L45
  jmp    L12
L30:
  mov    $0x0,%r8d
L12:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t strcspn(const char *s, const char *reject) {
  const char *p;
  const char *r;
  size_t count = 0;
  for (p = s; *p != '\0'; ++p) {
    for (r = reject; *r != '\0'; ++r) {
      if (*p == *r)
        return count;
    }
    ++count;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcspn>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L7
  movzbl (%rsi),%r9d
  xor    %r8d,%r8d
L61:
  mov    %rsi,%rdx
  mov    %r9d,%eax
  test   %r9b,%r9b
  jne    L72
  jmp    L62
  nop
L8:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L62
L72:
  cmp    %cl,%al
  jne    L8
L63:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L62:
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L61
  jmp    L63
L7:
  xor    %r8d,%r8d
  jmp    L63
```

assistant: ```c
size_t strcspn(const char *s, const char *reject) {
  const char *p;
  const char *r;
  size_t count = 0;
  for (p = s; *p != '\0'; ++p) {
    for (r = reject; *r != '\0'; ++r) {
      if (*p == *r)
        return count;
    }
    ++count;
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcspn>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L51
  movzbl (%rsi),%r9d
  xor    %r8d,%r8d
L21:
  mov    %rsi,%rdx
  mov    %r9d,%eax
  test   %r9b,%r9b
  jne    L26
  jmp    L1
  nop
L5:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L1
L26:
  cmp    %cl,%al
  jne    L5
L45:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L1:
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L21
  jmp    L45
L51:
  xor    %r8d,%r8d
  jmp    L45
```

assistant: ```c
size_t strcspn(const char *s, const char *reject) {
  const char *p;
  const char *r;
  size_t count = 0;
  for (p = s; *p != '\0'; ++p) {
    for (r = reject; *r != '\0'; ++r) {
      if (*p == *r)
        return count;
    }
    ++count;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %edi,-0xfc4(%rbp)
  mov    %rsi,-0xfd0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xfb0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1f4,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0xfbc(%rbp)
  jmp    L18
L66:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfbc(%rbp)
L18:
  cmpl   $0x3e7,-0xfbc(%rbp)
  jle    L66
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xfb8(%rbp)
  jmp    L50
L46:
  mov    -0xfb8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xfb8(%rbp)
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L50:
  cmpl   $0x3e7,-0xfb8(%rbp)
  jle    L46
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xfb0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xfb4(%rbp)
  jmp    L62
L67:
  mov    -0xfb4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xfb4(%rbp)
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L62:
  cmpl   $0x3e7,-0xfb4(%rbp)
  jle    L67
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D38
datatype: string
name: extract_symbolic_data
arguments: label: D41
datatype: string
name: extract_symbolic_data
arguments: label: D54
datatype: string
name: extract_symbolic_data
arguments: label: D48
datatype: string

tool: D38: Original array: 
[

tool: D41: %d, 

tool: D54: ]

tool: D48: 
Sorted array: 
[

assistant: ```c
int main(int argc, char *argv[]) {
  int a[1000] = {0};
  srand(time(0));
  for (int i = 0; i < 1000; a[i] = rand() % 1000, i++) {
  }
  printf("Original array: \n[");
  for (int i = 0; i < 1000; printf("%d, ", a[i++])) {
  }
  printf("\b\b]\n");
  merge_sort(a, 1000);
  printf("\nSorted array: \n[");
  for (int i = 0; i < 1000; printf("%d, ", a[i++])) {
  }
  printf("\b\b]\n");
  return 0;
}
```