ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L29
  mov    $0x1,%eax
  jmp    L11
L29:
  cmpl   $0x1,-0x2c(%rbp)
  jne    L2
  mov    $0x1,%eax
  jmp    L11
L2:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   *%rdx
  mov    %eax,%ebx
  mov    -0x2c(%rbp),%eax
  lea    -0x2(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   *%rdx
  add    %ebx,%eax
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(void *p, int i) {
  int (*foo)(void *, int) = (int (*)(void *, int))p;
  if (i == 0)
    return 1;
  if (i == 1)
    return 1;
  return foo(foo, i - 1) + foo(foo, i - 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fib>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%esi
  jbe    L9
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    -0x1(%rsi),%esi
  call   *%rdi
  mov    %eax,%r12d
  lea    -0x2(%rbx),%esi
  mov    %rbp,%rdi
  call   *%rbp
  add    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  ret
```

assistant: ```c
int fib(void *p, int i) {
  int (*foo)(void *, int) = (int (*)(void *, int))p;
  if (i == 0)
    return 1;
  if (i == 1)
    return 1;
  return foo(foo, i - 1) + foo(foo, i - 2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fib>:
  endbr64
  cmp    $0x1,%esi
  jbe    L7
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    -0x1(%rsi),%esi
  call   *%rdi
  lea    -0x2(%rbx),%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   *%rbp
  pop    %rbx
  pop    %rbp
  add    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fib(void *p, int i) {
  int (*foo)(void *, int) = (int (*)(void *, int))p;
  if (i == 0)
    return 1;
  if (i == 1)
    return 1;
  return foo(foo, i - 1) + foo(foo, i - 2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fib>:
  endbr64
  cmp    $0x1,%esi
  jbe    L4
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    -0x1(%rsi),%esi
  call   *%rdi
  lea    -0x2(%rbx),%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   *%rbp
  pop    %rbx
  pop    %rbp
  add    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fib(void *p, int i) {
  int (*foo)(void *, int) = (int (*)(void *, int))p;
  if (i == 0)
    return 1;
  if (i == 1)
    return 1;
  return foo(foo, i - 1) + foo(foo, i - 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_get_nodes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x98(%rbp)
  mov    -0x98(%rbp),%rax
  mov    %eax,%edx
  lea    -0x90(%rbp),%rax
  lea    D0(%rip),%r8
  mov    %edx,%ecx
  lea    D10(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <_xmit@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D10
type: string

tool: D0: CMD=GETNODES ARG=0:ALL

tool: D10: TS=%u AUTH=root DT=%s

assistant: ```c
void _get_nodes(void) {
  time_t now = time(NULL);
  char out_msg[128];
  snprintf(out_msg, sizeof(out_msg), "TS=%u AUTH=root DT=%s", (uint32_t)now, "CMD=GETNODES ARG=0:ALL");
  _xmit(out_msg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_get_nodes>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rsp,%rbx
  lea    D13(%rip),%r8
  mov    %eax,%ecx
  lea    D8(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <_xmit@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x90,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D13
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string

tool: D13: CMD=GETNODES ARG=0:ALL

tool: D8: TS=%u AUTH=root DT=%s

assistant: ```c
void _get_nodes(void) {
  time_t now = time(NULL);
  char out_msg[128];
  snprintf(out_msg, sizeof(out_msg), "TS=%u AUTH=root DT=%s", (uint32_t)now, "CMD=GETNODES ARG=0:ALL");
  _xmit(out_msg);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_get_nodes>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %rbp,%rdi
  mov    $0x80,%esi
  lea    D15(%rip),%r8
  mov    %eax,%ecx
  lea    D5(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x90,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D15: CMD=GETNODES ARG=0:ALL

tool: D5: TS=%u AUTH=root DT=%s

assistant: ```c
void _get_nodes(void) {
  time_t now = time(NULL);
  char out_msg[128];
  snprintf(out_msg, sizeof(out_msg), "TS=%u AUTH=root DT=%s", (uint32_t)now, "CMD=GETNODES ARG=0:ALL");
  _xmit(out_msg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_get_nodes>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %rbp,%rdi
  mov    $0x80,%esi
  lea    D0(%rip),%r8
  mov    %eax,%ecx
  lea    D11(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x90,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D11
data_type: string

tool: D0: CMD=GETNODES ARG=0:ALL

tool: D11: TS=%u AUTH=root DT=%s

assistant: ```c
void _get_nodes(void) {
  time_t now = time(NULL);
  char out_msg[128];
  snprintf(out_msg, sizeof(out_msg), "TS=%u AUTH=root DT=%s", (uint32_t)now, "CMD=GETNODES ARG=0:ALL");
  _xmit(out_msg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movabs $0x20686f59686f42,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
L5:
  mov    $0xd,%edi
  call   <putchar@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L15
L12:
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jle    L44
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L34
L44:
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  sub    -0x14(%rbp),%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L34:
  addl   $0x1,-0x1c(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    $0x1f4,%edi
  call   <sleep@plt>
  cmpl   $0x0,-0x18(%rbp)
  jle    L40
  subl   $0x1,-0x18(%rbp)
  jmp    L5
L40:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L5
```

assistant: ```c
int main(void) {
  int i;
  int cnt = 0;
  char name[] = "BohYoh ";
  int name_len = strlen(name);
  while (1) {
    putchar('\r');
    for (i = 0; i < name_len; i++) {
      if (cnt + i < name_len)
        putchar(name[cnt + i]);
      else
        putchar(name[cnt + i - name_len]);
    }
    fflush(stdout);
    sleep(500);
    if (cnt > 0)
      cnt--;
    else
      cnt = name_len - 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x20686f59686f42,%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x0,%r14d
  mov    %rsp,%r15
  jmp    L31
L26:
  movslq %ebx,%rax
  movsbl (%rsp,%rax,1),%edi
  call   <putchar@plt>
L52:
  add    $0x1,%rbp
  add    $0x1,%ebx
  cmp    %r13d,%ebx
  je     L48
L35:
  lea    (%rbx,%r12,1),%eax
  cmp    %eax,%r12d
  jle    L26
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
  jmp    L52
L48:
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    $0x1f4,%edi
  call   <sleep@plt>
  lea    -0x1(%r14),%eax
  lea    -0x1(%r12),%edx
  test   %r14d,%r14d
  cmovle %edx,%eax
  mov    %eax,%r14d
L31:
  mov    $0xd,%edi
  call   <putchar@plt>
  test   %r12d,%r12d
  jle    L48
  movslq %r14d,%rbp
  add    %r15,%rbp
  mov    %r14d,%r13d
  mov    %r14d,%ebx
  sub    %r12d,%ebx
  jmp    L35
```

assistant: ```c
int main(void) {
  int i;
  int cnt = 0;
  char name[] = "BohYoh ";
  int name_len = strlen(name);
  while (1) {
    putchar('\r');
    for (i = 0; i < name_len; i++) {
      if (cnt + i < name_len)
        putchar(name[cnt + i]);
      else
        putchar(name[cnt + i - name_len]);
    }
    fflush(stdout);
    sleep(500);
    if (cnt > 0)
      cnt--;
    else
      cnt = name_len - 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x20686f59686f42,%rax
  lea    0x10(%rsp),%r15
  mov    %r15,%rdi
  mov    %rax,0x10(%rsp)
  call   <strlen@plt>
  mov    D4(%rip),%r14
  mov    %eax,%ebp
  lea    -0x1(%rax),%eax
  mov    %eax,0xc(%rsp)
  nop
L18:
  mov    $0xd,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L15
  movslq %r12d,%rdx
  mov    %r12d,%ebx
  lea    (%r15,%rdx,1),%r13
  sub    %ebp,%ebx
  jmp    L9
  nopl   0x0(%rax)
L40:
  movsbl 0x0(%r13),%edi
  add    $0x1,%ebx
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    %r12d,%ebx
  je     L15
L9:
  lea    (%rbx,%rbp,1),%eax
  cmp    %eax,%ebp
  jg     L40
  movslq %ebx,%rax
  add    $0x1,%ebx
  add    $0x1,%r13
  movsbl 0x10(%rsp,%rax,1),%edi
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L9
L15:
  mov    (%r14),%edi
  call   <fflush@plt>
  mov    $0x1f4,%edi
  call   <sleep@plt>
  lea    -0x1(%r12),%eax
  test   %r12d,%r12d
  cmovle 0xc(%rsp),%eax
  mov    %eax,%r12d
  jmp    L18
```

assistant: ```c
int main(void) {
  int i;
  int cnt = 0;
  char name[] = "BohYoh ";
  int name_len = strlen(name);
  while (1) {
    putchar('\r');
    for (i = 0; i < name_len; i++) {
      if (cnt + i < name_len)
        putchar(name[cnt + i]);
      else
        putchar(name[cnt + i - name_len]);
    }
    fflush(stdout);
    sleep(500);
    if (cnt > 0)
      cnt--;
    else
      cnt = name_len - 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x20686f59686f42,%rax
  lea    0x10(%rsp),%r15
  mov    %r15,%rdi
  mov    %rax,0x10(%rsp)
  call   <strlen@plt>
  mov    D2(%rip),%r14
  mov    %eax,%ebp
  lea    -0x1(%rax),%eax
  mov    %eax,0xc(%rsp)
  nop
L57:
  mov    $0xd,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L41
  movslq %r12d,%rdx
  mov    %r12d,%ebx
  lea    (%r15,%rdx,1),%r13
  sub    %ebp,%ebx
  jmp    L14
  nopl   0x0(%rax)
L7:
  movsbl 0x0(%r13),%edi
  add    $0x1,%ebx
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    %r12d,%ebx
  je     L41
L14:
  lea    (%rbx,%rbp,1),%eax
  cmp    %eax,%ebp
  jg     L7
  movslq %ebx,%rax
  add    $0x1,%ebx
  add    $0x1,%r13
  movsbl 0x10(%rsp,%rax,1),%edi
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L14
L41:
  mov    (%r14),%edi
  call   <fflush@plt>
  mov    $0x1f4,%edi
  call   <sleep@plt>
  lea    -0x1(%r12),%eax
  test   %r12d,%r12d
  cmovle 0xc(%rsp),%eax
  mov    %eax,%r12d
  jmp    L57
```

assistant: ```c
int main(void) {
  int i;
  int cnt = 0;
  char name[] = "BohYoh ";
  int name_len = strlen(name);
  while (1) {
    putchar('\r');
    for (i = 0; i < name_len; i++) {
      if (cnt + i < name_len)
        putchar(name[cnt + i]);
      else
        putchar(name[cnt + i - name_len]);
    }
    fflush(stdout);
    sleep(500);
    if (cnt > 0)
      cnt--;
    else
      cnt = name_len - 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<FriendlyTimestring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x44(%rbp)
  jne    L28
  mov    $0x0,%edi
  call   <time@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L18
L28:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x44(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L18:
  movsd  -0x20(%rbp),%xmm0
  movsd  D40(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D28(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x28(%rbp),%r9
  lea    -0x30(%rbp),%r10
  lea    -0x34(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  lea    -0x3c(%rbp),%rsi
  lea    -0x40(%rbp),%rdi
  mov    -0x18(%rbp),%rax
  lea    D49(%rip),%r8
  push   %r8
  lea    -0x2c(%rbp),%r8
  push   %r8
  mov    %r10,%r8
  movq   %rax,%xmm0
  call   <InvJulianDay@plt>
  add    $0x10,%rsp
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edi
  call   <GetMonthName@plt>
  mov    %rax,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  cvttsd2si %xmm0,%r8d
  mov    -0x30(%rbp),%edi
  mov    -0x34(%rbp),%esi
  mov    -0x40(%rbp),%ecx
  mov    -0x38(%rbp),%r9d
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%r10d
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  push   %r8
  push   %rdi
  push   %rsi
  push   %rcx
  mov    %r10d,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D26(%rip),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x20,%rsp
  lea    D49(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D40
type_infered: f64
name: parse_data
arguments: data_label: D28
type_infered: f64
name: parse_data
arguments: data_label: D26
type_infered: string

tool: D40: 86400

tool: D28: 2440587.5

tool: D26: %c%c%c %02d %04d %02d:%02d:%02d

assistant: ```c
char *FriendlyTimestring(int t) {
  static char output[256];
  time_t timenow;
  if (!t)
    timenow = time(NULL);
  else
    timenow = (time_t)t;
  const double JD = timenow / 86400.0 + 2440587.5;
  int year, month, day, hour, min, status;
  double sec;
  InvJulianDay(JD, &year, &month, &day, &hour, &min, &sec, &status, output);
  char *mn = GetMonthName(month);
  sprintf(output, "%c%c%c %02d %04d %02d:%02d:%02d", mn[0], mn[1], mn[2], day, year, hour, min, (int)sec);
  return output;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FriendlyTimestring>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L19
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
L18:
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  divsd  D22(%rip),%xmm0
  addsd  D19(%rip),%xmm0
  lea    D15(%rip),%rbx
  push   %rbx
  lea    0x24(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <InvJulianDay@plt>
  mov    0x1c(%rsp),%edi
  call   <GetMonthName@plt>
  movsbl 0x2(%rax),%r8d
  movsbl 0x1(%rax),%ecx
  movsbl (%rax),%edx
  cvttsd2si 0x30(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x34(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x40(%rsp),%r9d
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x30,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %rbx,%rax
  add    $0x30,%rsp
  pop    %rbx
  ret
L19:
  mov    $0x0,%edi
  call   <time@plt>
  jmp    L18
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D22
type: f64
name: unpack_data
arguments: data_label: D19
type: f64
name: unpack_data
arguments: data_label: D9
type: string

tool: D22: 86400

tool: D19: 2440587.5

tool: D9: %c%c%c %02d %04d %02d:%02d:%02d

assistant: ```c
char *FriendlyTimestring(int t) {
  static char output[256];
  time_t timenow;
  if (!t)
    timenow = time(NULL);
  else
    timenow = (time_t)t;
  const double JD = timenow / 86400.0 + 2440587.5;
  int year, month, day, hour, min, status;
  double sec;
  InvJulianDay(JD, &year, &month, &day, &hour, &min, &sec, &status, output);
  char *mn = GetMonthName(month);
  sprintf(output, "%c%c%c %02d %04d %02d:%02d:%02d", mn[0], mn[1], mn[2], day, year, hour, min, (int)sec);
  return output;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<FriendlyTimestring>:
  endbr64
  push   %r12
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L22
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
L16:
  lea    D15(%rip),%r12
  lea    0x14(%rsp),%rcx
  divsd  D30(%rip),%xmm0
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  push   %r12
  addsd  D5(%rip),%xmm0
  lea    0x24(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <InvJulianDay@plt>
  mov    0x1c(%rsp),%edi
  call   <GetMonthName@plt>
  lea    D35(%rip),%rsi
  mov    %r12,%rdi
  movsbl 0x2(%rax),%r8d
  movsbl 0x1(%rax),%ecx
  movsbl (%rax),%edx
  cvttsd2si 0x30(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x34(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x40(%rsp),%r9d
  call   <sprintf@plt>
  add    $0x30,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L22:
  xor    %edi,%edi
  call   <time@plt>
  jmp    L16
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D5
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D35
type_guessed: string

tool: D30: 86400

tool: D5: 2440587.5

tool: D35: %c%c%c %02d %04d %02d:%02d:%02d

assistant: ```c
char *FriendlyTimestring(int t) {
  static char output[256];
  time_t timenow;
  if (!t)
    timenow = time(NULL);
  else
    timenow = (time_t)t;
  const double JD = timenow / 86400.0 + 2440587.5;
  int year, month, day, hour, min, status;
  double sec;
  InvJulianDay(JD, &year, &month, &day, &hour, &min, &sec, &status, output);
  char *mn = GetMonthName(month);
  sprintf(output, "%c%c%c %02d %04d %02d:%02d:%02d", mn[0], mn[1], mn[2], day, year, hour, min, (int)sec);
  return output;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<FriendlyTimestring>:
  endbr64
  push   %r12
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L6
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
L19:
  lea    D13(%rip),%r12
  lea    0x14(%rsp),%rcx
  divsd  D9(%rip),%xmm0
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  push   %r12
  addsd  D27(%rip),%xmm0
  lea    0x24(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <InvJulianDay@plt>
  mov    0x1c(%rsp),%edi
  call   <GetMonthName@plt>
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  movsbl 0x2(%rax),%r8d
  movsbl 0x1(%rax),%ecx
  movsbl (%rax),%edx
  cvttsd2si 0x30(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x34(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x40(%rsp),%r9d
  call   <sprintf@plt>
  add    $0x30,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  xor    %edi,%edi
  call   <time@plt>
  jmp    L19
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: f64
name: read_data
arguments: tag: D27
type_guessed: f64
name: read_data
arguments: tag: D8
type_guessed: string

tool: D9: 86400

tool: D27: 2440587.5

tool: D8: %c%c%c %02d %04d %02d:%02d:%02d

assistant: ```c
char *FriendlyTimestring(int t) {
  static char output[256];
  time_t timenow;
  if (!t)
    timenow = time(NULL);
  else
    timenow = (time_t)t;
  const double JD = timenow / 86400.0 + 2440587.5;
  int year, month, day, hour, min, status;
  double sec;
  InvJulianDay(JD, &year, &month, &day, &hour, &min, &sec, &status, output);
  char *mn = GetMonthName(month);
  sprintf(output, "%c%c%c %02d %04d %02d:%02d:%02d", mn[0], mn[1], mn[2], day, year, hour, min, (int)sec);
  return output;
}
```
user: What is the c source code of the assembly code below?

```asm
<divide_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cli
  mov    $0x0,%esi
  mov    $0xc,%edi
  mov    $0x0,%eax
  call   <SetTextColor@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <kprintf@plt>
L7:
  cli
  hlt
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: 
ERROR: Divide by zero.


assistant: ```c
void divide_error() {
  __asm__ __volatile__("cli");
  SetTextColor(0x04 | 0x08, 0x00);
  kprintf("\nERROR: Divide by zero.\n");
  do {
    __asm__ __volatile__("cli  \n\t"
                         "hlt");
  } while (1 == 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<divide_error>:
  endbr64
  sub    $0x8,%rsp
  cli
  mov    $0x0,%esi
  mov    $0xc,%edi
  mov    $0x0,%eax
  call   <SetTextColor@plt>
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <kprintf@plt>
L5:
  cli
  hlt
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 
ERROR: Divide by zero.


assistant: ```c
void divide_error() {
  __asm__ __volatile__("cli");
  SetTextColor(0x04 | 0x08, 0x00);
  kprintf("\nERROR: Divide by zero.\n");
  do {
    __asm__ __volatile__("cli  \n\t"
                         "hlt");
  } while (1 == 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<divide_error>:
  endbr64
  sub    $0x8,%rsp
  cli
  mov    $0xc,%edi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <SetTextColor@plt>
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <kprintf@plt>
  nopl   (%rax)
L7:
  cli
  hlt
  jmp    L7
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string

tool: D8: 
ERROR: Divide by zero.


assistant: ```c
void divide_error() {
  __asm__ __volatile__("cli");
  SetTextColor(0x04 | 0x08, 0x00);
  kprintf("\nERROR: Divide by zero.\n");
  do {
    __asm__ __volatile__("cli  \n\t"
                         "hlt");
  } while (1 == 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<divide_error>:
  endbr64
  sub    $0x8,%rsp
  cli
  mov    $0xc,%edi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <SetTextColor@plt>
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <kprintf@plt>
  nopl   (%rax)
L0:
  cli
  hlt
  jmp    L0
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8: 
ERROR: Divide by zero.


assistant: ```c
void divide_error() {
  __asm__ __volatile__("cli");
  SetTextColor(0x04 | 0x08, 0x00);
  kprintf("\nERROR: Divide by zero.\n");
  do {
    __asm__ __volatile__("cli  \n\t"
                         "hlt");
  } while (1 == 1);
}
```