ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x6f,%edx
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  mov    %dx,0x36(%rsp)
  lea    0x2d(%rsp),%rsi
  lea    0xc(%rsp),%rdx
  lea    0x32(%rsp),%rdi
  movl   $0x6c6c6568,0x32(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x2d(%rsp)
  movb   $0x0,0x31(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <permute@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char const *argv[]) {
  char test[] = "hello";
  int len = 0;
  int used[5];
  char out[5];
  memset(used, 0, sizeof(used));
  memset(out, 0, sizeof(out));
  permute(test, out, &len, used);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x6f,%edx
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  mov    %dx,0x36(%rsp)
  lea    0x2d(%rsp),%rsi
  lea    0xc(%rsp),%rdx
  lea    0x32(%rsp),%rdi
  movl   $0x6c6c6568,0x32(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x2d(%rsp)
  movb   $0x0,0x31(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <permute@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char const *argv[]) {
  char test[] = "hello";
  int len = 0;
  int used[5];
  char out[5];
  memset(used, 0, sizeof(used));
  memset(out, 0, sizeof(out));
  permute(test, out, &len, used);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xdr_rmtcallres>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    D18(%rip),%rax
  mov    %eax,%edx
  lea    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <xdr_reference@plt>
  test   %rax,%rax
  je     L6
  mov    -0x20(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xdr_u_long@plt>
  test   %rax,%rax
  je     L6
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,0x10(%rax)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rcx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   *%rcx
  jmp    L33
L6:
  mov    D17(%rip),%rax
  mov    (%rax),%eax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
bool_t xdr_rmtcallres(XDR *xdrs, struct rmtcallres *crp) {
  caddr_t port_ptr;
  assert(xdrs != NULL);
  assert(crp != NULL);
  port_ptr = (caddr_t)(void *)crp->port_ptr;
  if (xdr_reference(xdrs, &port_ptr, sizeof(u_long), (xdrproc_t)xdr_u_long) && xdr_u_long(xdrs, &crp->resultslen)) {
    crp->port_ptr = (u_long *)(void *)port_ptr;
    return ((*(crp->xdr_results))(xdrs, crp->results_ptr));
  }
  return (FALSE);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xdr_rmtcallres>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x10(%rbx),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rsi
  mov    D15(%rip),%ecx
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <xdr_reference@plt>
  test   %rax,%rax
  jne    L23
L25:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  lea    0x18(%rbx),%rsi
  mov    %rbp,%rdi
  call   <xdr_u_long@plt>
  test   %rax,%rax
  je     L25
  mov    (%rsp),%rax
  mov    %rax,0x10(%rbx)
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   *0x8(%rbx)
  jmp    L29
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_rmtcallres(XDR *xdrs, struct rmtcallres *crp) {
  caddr_t port_ptr;
  assert(xdrs != NULL);
  assert(crp != NULL);
  port_ptr = (caddr_t)(void *)crp->port_ptr;
  if (xdr_reference(xdrs, &port_ptr, sizeof(u_long), (xdrproc_t)xdr_u_long) && xdr_u_long(xdrs, &crp->resultslen)) {
    crp->port_ptr = (u_long *)(void *)port_ptr;
    return ((*(crp->xdr_results))(xdrs, crp->results_ptr));
  }
  return (FALSE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xdr_rmtcallres>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    0x10(%rbx),%rax
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    D0(%rip),%ecx
  mov    $0x4,%edx
  mov    %rax,(%rsp)
  call   <xdr_reference@plt>
  test   %rax,%rax
  jne    L15
L36:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L15:
  lea    0x18(%rbx),%rsi
  mov    %rbp,%rdi
  call   <xdr_u_long@plt>
  test   %rax,%rax
  je     L36
  mov    (%rsp),%rax
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    %rax,0x10(%rbx)
  call   *0x8(%rbx)
  jmp    L21
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_rmtcallres(XDR *xdrs, struct rmtcallres *crp) {
  caddr_t port_ptr;
  assert(xdrs != NULL);
  assert(crp != NULL);
  port_ptr = (caddr_t)(void *)crp->port_ptr;
  if (xdr_reference(xdrs, &port_ptr, sizeof(u_long), (xdrproc_t)xdr_u_long) && xdr_u_long(xdrs, &crp->resultslen)) {
    crp->port_ptr = (u_long *)(void *)port_ptr;
    return ((*(crp->xdr_results))(xdrs, crp->results_ptr));
  }
  return (FALSE);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xdr_rmtcallres>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    0x10(%rbx),%rax
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    D13(%rip),%ecx
  mov    $0x4,%edx
  mov    %rax,(%rsp)
  call   <xdr_reference@plt>
  test   %rax,%rax
  jne    L8
L23:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  lea    0x18(%rbx),%rsi
  mov    %rbp,%rdi
  call   <xdr_u_long@plt>
  test   %rax,%rax
  je     L23
  mov    (%rsp),%rax
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    %rax,0x10(%rbx)
  call   *0x8(%rbx)
  jmp    L9
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_rmtcallres(XDR *xdrs, struct rmtcallres *crp) {
  caddr_t port_ptr;
  assert(xdrs != NULL);
  assert(crp != NULL);
  port_ptr = (caddr_t)(void *)crp->port_ptr;
  if (xdr_reference(xdrs, &port_ptr, sizeof(u_long), (xdrproc_t)xdr_u_long) && xdr_u_long(xdrs, &crp->resultslen)) {
    crp->port_ptr = (u_long *)(void *)port_ptr;
    return ((*(crp->xdr_results))(xdrs, crp->results_ptr));
  }
  return (FALSE);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Idle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glutGet@plt>
  mov    %eax,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glutGet@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L4
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  mov    -0x4(%rbp),%eax
  add    $0x32,%eax
  mov    %eax,-0x8(%rbp)
L4:
  nop
  leave
  ret
```

assistant: ```c
void Idle() {
  int nWaitUntil = glutGet(GLUT_ELAPSED_TIME);
  int nTimer = glutGet(GLUT_ELAPSED_TIME);
  if (nTimer >= nWaitUntil) {
    glutPostRedisplay();
    nWaitUntil = nTimer + (1000 / 20);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Idle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <glutGet@plt>
  mov    %eax,%ebx
  mov    0x0(%rbp),%edi
  call   <glutGet@plt>
  cmp    %eax,%ebx
  jle    L16
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  jmp    L1
```

assistant: ```c
void Idle() {
  int nWaitUntil = glutGet(GLUT_ELAPSED_TIME);
  int nTimer = glutGet(GLUT_ELAPSED_TIME);
  if (nTimer >= nWaitUntil) {
    glutPostRedisplay();
    nWaitUntil = nTimer + (1000 / 20);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Idle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <glutGet@plt>
  mov    0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <glutGet@plt>
  cmp    %eax,%ebx
  jle    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <glutPostRedisplay@plt>
```

assistant: ```c
void Idle() {
  int nWaitUntil = glutGet(GLUT_ELAPSED_TIME);
  int nTimer = glutGet(GLUT_ELAPSED_TIME);
  if (nTimer >= nWaitUntil) {
    glutPostRedisplay();
    nWaitUntil = nTimer + (1000 / 20);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Idle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <glutGet@plt>
  mov    0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <glutGet@plt>
  cmp    %eax,%ebx
  jle    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <glutPostRedisplay@plt>
```

assistant: ```c
void Idle() {
  int nWaitUntil = glutGet(GLUT_ELAPSED_TIME);
  int nTimer = glutGet(GLUT_ELAPSED_TIME);
  if (nTimer >= nWaitUntil) {
    glutPostRedisplay();
    nWaitUntil = nTimer + (1000 / 20);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GPIOPinTypeGPIOInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  movzbl -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <GPIODirModeSet@plt>
  movzbl -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    $0x8,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <GPIOPadConfigSet@plt>
  nop
  leave
  ret
```

assistant: ```c
void GPIOPinTypeGPIOInput(unsigned long ulPort, unsigned char ucPins) {
  ;
  GPIODirModeSet(ulPort, ucPins, 0x00000000);
  GPIOPadConfigSet(ulPort, ucPins, 0x00000001, 0x00000008);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GPIOPinTypeGPIOInput>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl %sil,%ebp
  mov    $0x0,%edx
  mov    %ebp,%esi
  call   <GPIODirModeSet@plt>
  mov    $0x8,%ecx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <GPIOPadConfigSet@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void GPIOPinTypeGPIOInput(unsigned long ulPort, unsigned char ucPins) {
  ;
  GPIODirModeSet(ulPort, ucPins, 0x00000000);
  GPIOPadConfigSet(ulPort, ucPins, 0x00000001, 0x00000008);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GPIOPinTypeGPIOInput>:
  endbr64
  push   %r12
  movzbl %sil,%r12d
  xor    %edx,%edx
  push   %rbp
  mov    %r12d,%esi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <GPIODirModeSet@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    $0x8,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <GPIOPadConfigSet@plt>
```

assistant: ```c
void GPIOPinTypeGPIOInput(unsigned long ulPort, unsigned char ucPins) {
  ;
  GPIODirModeSet(ulPort, ucPins, 0x00000000);
  GPIOPadConfigSet(ulPort, ucPins, 0x00000001, 0x00000008);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GPIOPinTypeGPIOInput>:
  endbr64
  push   %r12
  movzbl %sil,%r12d
  xor    %edx,%edx
  push   %rbp
  mov    %r12d,%esi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <GPIODirModeSet@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    $0x8,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <GPIOPadConfigSet@plt>
```

assistant: ```c
void GPIOPinTypeGPIOInput(unsigned long ulPort, unsigned char ucPins) {
  ;
  GPIODirModeSet(ulPort, ucPins, 0x00000000);
  GPIOPadConfigSet(ulPort, ucPins, 0x00000001, 0x00000008);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_pthread_rwlock_timedrdlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <hybris_set_realrwlock@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pthread_rwlock_timedrdlock@plt>
  leave
  ret
```

assistant: ```c
int my_pthread_rwlock_timedrdlock(pthread_rwlock_t *__rwlock, __const struct timespec *abs_timeout) {
  pthread_rwlock_t *realrwlock = hybris_set_realrwlock(__rwlock);
  return pthread_rwlock_timedrdlock(realrwlock, abs_timeout);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_pthread_rwlock_timedrdlock>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <hybris_set_realrwlock@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <pthread_rwlock_timedrdlock@plt>
  pop    %rbx
  ret
```

assistant: ```c
int my_pthread_rwlock_timedrdlock(pthread_rwlock_t *__rwlock, __const struct timespec *abs_timeout) {
  pthread_rwlock_t *realrwlock = hybris_set_realrwlock(__rwlock);
  return pthread_rwlock_timedrdlock(realrwlock, abs_timeout);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_pthread_rwlock_timedrdlock>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <hybris_set_realrwlock@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <pthread_rwlock_timedrdlock@plt>
```

assistant: ```c
int my_pthread_rwlock_timedrdlock(pthread_rwlock_t *__rwlock, __const struct timespec *abs_timeout) {
  pthread_rwlock_t *realrwlock = hybris_set_realrwlock(__rwlock);
  return pthread_rwlock_timedrdlock(realrwlock, abs_timeout);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_pthread_rwlock_timedrdlock>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <hybris_set_realrwlock@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <pthread_rwlock_timedrdlock@plt>
```

assistant: ```c
int my_pthread_rwlock_timedrdlock(pthread_rwlock_t *__rwlock, __const struct timespec *abs_timeout) {
  pthread_rwlock_t *realrwlock = hybris_set_realrwlock(__rwlock);
  return pthread_rwlock_timedrdlock(realrwlock, abs_timeout);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fz_accelerate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fz_is_big_endian@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fz_accelerate(void) {
  if (sizeof(int) == 4 && sizeof(unsigned int) == 4 && !fz_is_big_endian()) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fz_accelerate>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fz_is_big_endian@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fz_accelerate(void) {
  if (sizeof(int) == 4 && sizeof(unsigned int) == 4 && !fz_is_big_endian()) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fz_accelerate>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <fz_is_big_endian@plt>
```

assistant: ```c
void fz_accelerate(void) {
  if (sizeof(int) == 4 && sizeof(unsigned int) == 4 && !fz_is_big_endian()) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fz_accelerate>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <fz_is_big_endian@plt>
```

assistant: ```c
void fz_accelerate(void) {
  if (sizeof(int) == 4 && sizeof(unsigned int) == 4 && !fz_is_big_endian()) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rsi
  imul   $0x51eb851f,%rsi,%rsi
  sar    $0x25,%rsi
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  mov    %esi,%eax
  sub    %ecx,%eax
  imul   $0x64,%eax,%edi
  mov    %edx,%eax
  sub    %edi,%eax
  movslq %eax,%rbx
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x24,%rbx
  mov    %eax,%r12d
  sar    $0x1f,%r12d
  mov    %ebx,%ebp
  sub    %r12d,%ebp
  imul   $0x32,%ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  sub    %ecx,%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  sub    %r12d,%ebx
  mov    %ebx,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  movslq %ebp,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  mov    %ebx,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %ebp,%esi
  sub    %eax,%esi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type_infered: string
name: parse_data
arguments: label: D46
type_infered: string
name: parse_data
arguments: label: D44
type_infered: string
name: parse_data
arguments: label: D31
type_infered: string
name: parse_data
arguments: label: D41
type_infered: string

tool: D10: %i

tool: D46: NOTAS DE 100 = %i


tool: D44: NOTAS DE 50 = %i


tool: D31: NOTAS DE 10 = %i


tool: D41: NOTAS DE 1 = %i


assistant: ```c
int main() {
  int valorTotal, cem, cinquenta, dez, um;
  scanf("%i", &valorTotal);
  cem = valorTotal / 100;
  int quociente1 = valorTotal % 100;
  cinquenta = quociente1 / 50;
  int quociente2 = quociente1 % 50;
  dez = quociente2 / 10;
  um = quociente2 % 10;
  printf("NOTAS DE 100 = %i\n", cem);
  printf("NOTAS DE 50 = %i\n", cinquenta);
  printf("NOTAS DE 10 = %i\n", dez);
  printf("NOTAS DE 1 = %i\n", um);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D22(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rdx
  imul   $0x51eb851f,%rsi,%rsi
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x25,%rsi
  mov    %esi,%eax
  sub    %ecx,%esi
  sub    %ecx,%eax
  imul   $0x64,%eax,%edi
  mov    %edx,%eax
  sub    %edi,%eax
  lea    D42(%rip),%rdi
  movslq %eax,%rbx
  mov    %eax,%r12d
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x1f,%r12d
  sar    $0x24,%rbx
  mov    %ebx,%ebp
  sub    %r12d,%ebx
  sub    %r12d,%ebp
  imul   $0x32,%ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  call   <printf@plt>
  mov    %ebx,%esi
  movslq %ebp,%rbx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  imul   $0x66666667,%rbx,%rbx
  mov    %ebp,%eax
  lea    D32(%rip),%rdi
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  mov    %ebx,%esi
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%eax
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  add    %eax,%eax
  sub    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D42
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string
name: extract_symbolic_data
arguments: tag: D32
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D22: %i

tool: D42: NOTAS DE 100 = %i


tool: D5: NOTAS DE 50 = %i


tool: D32: NOTAS DE 10 = %i


tool: D12: NOTAS DE 1 = %i


assistant: ```c
int main() {
  int valorTotal, cem, cinquenta, dez, um;
  scanf("%i", &valorTotal);
  cem = valorTotal / 100;
  int quociente1 = valorTotal % 100;
  cinquenta = quociente1 / 50;
  int quociente2 = quociente1 % 50;
  dez = quociente2 / 10;
  um = quociente2 % 10;
  printf("NOTAS DE 100 = %i\n", cem);
  printf("NOTAS DE 50 = %i\n", cinquenta);
  printf("NOTAS DE 10 = %i\n", dez);
  printf("NOTAS DE 1 = %i\n", um);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D40(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rdx
  imul   $0x51eb851f,%rsi,%rsi
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x25,%rsi
  mov    %esi,%eax
  sub    %ecx,%esi
  sub    %ecx,%eax
  imul   $0x64,%eax,%edi
  mov    %edx,%eax
  sub    %edi,%eax
  lea    D2(%rip),%rdi
  movslq %eax,%rbx
  mov    %eax,%r12d
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x1f,%r12d
  sar    $0x24,%rbx
  mov    %ebx,%ebp
  sub    %r12d,%ebx
  sub    %r12d,%ebp
  imul   $0x32,%ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  call   <printf@plt>
  mov    %ebx,%esi
  movslq %ebp,%rbx
  lea    D42(%rip),%rdi
  call   <printf@plt>
  imul   $0x66666667,%rbx,%rbx
  mov    %ebp,%eax
  lea    D48(%rip),%rdi
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  mov    %ebx,%esi
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%eax
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  add    %eax,%eax
  sub    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D40
data_type: string
name: read_data
arguments: tag: D2
data_type: string
name: read_data
arguments: tag: D42
data_type: string
name: read_data
arguments: tag: D48
data_type: string
name: read_data
arguments: tag: D24
data_type: string

tool: D40: %i

tool: D2: NOTAS DE 100 = %i


tool: D42: NOTAS DE 50 = %i


tool: D48: NOTAS DE 10 = %i


tool: D24: NOTAS DE 1 = %i


assistant: ```c
int main() {
  int valorTotal, cem, cinquenta, dez, um;
  scanf("%i", &valorTotal);
  cem = valorTotal / 100;
  int quociente1 = valorTotal % 100;
  cinquenta = quociente1 / 50;
  int quociente2 = quociente1 % 50;
  dez = quociente2 / 10;
  um = quociente2 % 10;
  printf("NOTAS DE 100 = %i\n", cem);
  printf("NOTAS DE 50 = %i\n", cinquenta);
  printf("NOTAS DE 10 = %i\n", dez);
  printf("NOTAS DE 1 = %i\n", um);
  return 0;
}
```