ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_ckpt_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x60,-0x74(%rbp)
  mov    -0x74(%rbp),%esi
  mov    -0x88(%rbp),%rax
  lea    D4(%rip),%r8
  mov    $0x2,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <print_decode_line@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L12
L18:
  mov    -0x78(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D42(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x78(%rbp),%eax
  add    $0x1,%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x74(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  lea    -0x70(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x2,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <print_decode_line@plt>
  addl   $0x1,-0x78(%rbp)
L12:
  cmpl   $0x4,-0x78(%rbp)
  jle    L18
  mov    -0x74(%rbp),%eax
  lea    0x18(%rax),%esi
  mov    -0x88(%rbp),%rax
  lea    D15(%rip),%r8
  mov    $0x0,%ecx
  mov    $0x8,%edx
  mov    %rax,%rdi
  call   <print_decode_line@plt>
  mov    -0x74(%rbp),%eax
  lea    0x20(%rax),%esi
  mov    -0x88(%rbp),%rax
  lea    D32(%rip),%r8
  mov    $0x2,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <print_decode_line@plt>
  mov    -0x74(%rbp),%eax
  lea    0x24(%rax),%esi
  mov    -0x88(%rbp),%rax
  lea    D35(%rip),%r8
  mov    $0x2,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <print_decode_line@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string
name: disassemble_data
arguments: label: D42
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string
name: disassemble_data
arguments: label: D32
datatype: string
name: disassemble_data
arguments: label: D35
datatype: string

tool: D4: nBackfill

tool: D42: aReadMark[%d]

tool: D15: aLock

tool: D32: nBackfillAttempted

tool: D35: notUsed0

assistant: ```c
void print_ckpt_info(unsigned char *aData) {
  const int i = 96;
  int j;
  print_decode_line(aData, 0 + i, 4, 2, "nBackfill");
  for (j = 0; j < 5; j++) {
    char zLabel[100];
    sprintf(zLabel, "aReadMark[%d]", j);
    print_decode_line(aData, 4 * j + 4 + i, 4, 2, zLabel);
  }
  print_decode_line(aData, 24 + i, 8, 0, "aLock");
  print_decode_line(aData, 32 + i, 4, 2, "nBackfillAttempted");
  print_decode_line(aData, 36 + i, 4, 2, "notUsed0");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_ckpt_info>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%r8
  mov    $0x2,%ecx
  mov    $0x4,%edx
  mov    $0x60,%esi
  call   <print_decode_line@plt>
  mov    $0x0,%ebx
  lea    D41(%rip),%r13
L19:
  mov    %rsp,%rbp
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x64(,%rbx,4),%esi
  mov    %rbp,%r8
  mov    $0x2,%ecx
  mov    $0x4,%edx
  mov    %r12,%rdi
  call   <print_decode_line@plt>
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L19
  lea    D7(%rip),%r8
  mov    $0x0,%ecx
  mov    $0x8,%edx
  mov    $0x78,%esi
  mov    %r12,%rdi
  call   <print_decode_line@plt>
  lea    D44(%rip),%r8
  mov    $0x2,%ecx
  mov    $0x4,%edx
  mov    $0x80,%esi
  mov    %r12,%rdi
  call   <print_decode_line@plt>
  lea    D9(%rip),%r8
  mov    $0x2,%ecx
  mov    $0x4,%edx
  mov    $0x84,%esi
  mov    %r12,%rdi
  call   <print_decode_line@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D41
type_infered: string
name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D44
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D2: nBackfill

tool: D41: aReadMark[%d]

tool: D7: aLock

tool: D44: nBackfillAttempted

tool: D9: notUsed0

assistant: ```c
void print_ckpt_info(unsigned char *aData) {
  const int i = 96;
  int j;
  print_decode_line(aData, 0 + i, 4, 2, "nBackfill");
  for (j = 0; j < 5; j++) {
    char zLabel[100];
    sprintf(zLabel, "aReadMark[%d]", j);
    print_decode_line(aData, 4 * j + 4 + i, 4, 2, zLabel);
  }
  print_decode_line(aData, 24 + i, 8, 0, "aLock");
  print_decode_line(aData, 32 + i, 4, 2, "nBackfillAttempted");
  print_decode_line(aData, 36 + i, 4, 2, "notUsed0");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_ckpt_info>:
  endbr64
  push   %r13
  mov    $0x2,%ecx
  mov    $0x4,%edx
  lea    D14(%rip),%r8
  push   %r12
  mov    $0x60,%esi
  lea    D47(%rip),%r13
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <print_decode_line@plt>
L10:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%r8
  mov    $0x2,%ecx
  mov    %rbp,%rdi
  lea    0x64(,%rbx,4),%esi
  mov    $0x4,%edx
  add    $0x1,%ebx
  call   <print_decode_line@plt>
  cmp    $0x5,%ebx
  jne    L10
  xor    %ecx,%ecx
  mov    $0x8,%edx
  mov    $0x78,%esi
  mov    %rbp,%rdi
  lea    D11(%rip),%r8
  call   <print_decode_line@plt>
  lea    D27(%rip),%r8
  mov    $0x2,%ecx
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x80,%esi
  call   <print_decode_line@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x78,%rsp
  mov    %rbp,%rdi
  mov    $0x2,%ecx
  mov    $0x4,%edx
  pop    %rbx
  lea    D45(%rip),%r8
  pop    %rbp
  mov    $0x84,%esi
  pop    %r12
  pop    %r13
  jmp    1080 <print_decode_line@plt>
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
type_guessed: string
name: parse_data
arguments: tag: D47
type_guessed: string
name: parse_data
arguments: tag: D11
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: string
name: parse_data
arguments: tag: D45
type_guessed: string

tool: D14: nBackfill

tool: D47: aReadMark[%d]

tool: D11: aLock

tool: D27: nBackfillAttempted

tool: D45: notUsed0

assistant: ```c
void print_ckpt_info(unsigned char *aData) {
  const int i = 96;
  int j;
  print_decode_line(aData, 0 + i, 4, 2, "nBackfill");
  for (j = 0; j < 5; j++) {
    char zLabel[100];
    sprintf(zLabel, "aReadMark[%d]", j);
    print_decode_line(aData, 4 * j + 4 + i, 4, 2, zLabel);
  }
  print_decode_line(aData, 24 + i, 8, 0, "aLock");
  print_decode_line(aData, 32 + i, 4, 2, "nBackfillAttempted");
  print_decode_line(aData, 36 + i, 4, 2, "notUsed0");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_ckpt_info>:
  endbr64
  push   %r13
  mov    $0x2,%ecx
  mov    $0x4,%edx
  lea    D14(%rip),%r8
  push   %r12
  mov    $0x60,%esi
  lea    D9(%rip),%r13
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <print_decode_line@plt>
L14:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%r8
  mov    $0x2,%ecx
  mov    %rbp,%rdi
  lea    0x64(,%rbx,4),%esi
  mov    $0x4,%edx
  add    $0x1,%ebx
  call   <print_decode_line@plt>
  cmp    $0x5,%ebx
  jne    L14
  xor    %ecx,%ecx
  mov    $0x8,%edx
  mov    $0x78,%esi
  mov    %rbp,%rdi
  lea    D44(%rip),%r8
  call   <print_decode_line@plt>
  lea    D20(%rip),%r8
  mov    $0x2,%ecx
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x80,%esi
  call   <print_decode_line@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x78,%rsp
  mov    %rbp,%rdi
  mov    $0x2,%ecx
  mov    $0x4,%edx
  pop    %rbx
  lea    D41(%rip),%r8
  pop    %rbp
  mov    $0x84,%esi
  pop    %r12
  pop    %r13
  jmp    1080 <print_decode_line@plt>
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
datatype: string
name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D44
datatype: string
name: parse_data
arguments: tag: D20
datatype: string
name: parse_data
arguments: tag: D41
datatype: string

tool: D14: nBackfill

tool: D9: aReadMark[%d]

tool: D44: aLock

tool: D20: nBackfillAttempted

tool: D41: notUsed0

assistant: ```c
void print_ckpt_info(unsigned char *aData) {
  const int i = 96;
  int j;
  print_decode_line(aData, 0 + i, 4, 2, "nBackfill");
  for (j = 0; j < 5; j++) {
    char zLabel[100];
    sprintf(zLabel, "aReadMark[%d]", j);
    print_decode_line(aData, 4 * j + 4 + i, 4, 2, zLabel);
  }
  print_decode_line(aData, 24 + i, 8, 0, "aLock");
  print_decode_line(aData, 32 + i, 4, 2, "nBackfillAttempted");
  print_decode_line(aData, 36 + i, 4, 2, "notUsed0");
}
```
user: What is the c source code of the assembly code below?

```asm
<radius_effective>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  movsd  %xmm1,-0x18(%rbp)
  movsd  %xmm2,-0x20(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L13
  movsd  -0x10(%rbp),%xmm0
  jmp    L15
L13:
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  addsd  -0x10(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
L15:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double radius_effective(int mode, double radius_lg, double radius_sm, double penetration) {
  switch (mode) {
  default:
  case 1:
    return radius_lg;
  case 2:
    return radius_lg + 2.0 * radius_sm - penetration;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<radius_effective>:
  endbr64
  cmp    $0x2,%edi
  je     L12
L13:
  ret
L12:
  addsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  jmp    L13
```

assistant: ```c
double radius_effective(int mode, double radius_lg, double radius_sm, double penetration) {
  switch (mode) {
  default:
  case 1:
    return radius_lg;
  case 2:
    return radius_lg + 2.0 * radius_sm - penetration;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<radius_effective>:
  endbr64
  cmp    $0x2,%edi
  je     L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  addsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  ret
```

assistant: ```c
double radius_effective(int mode, double radius_lg, double radius_sm, double penetration) {
  switch (mode) {
  default:
  case 1:
    return radius_lg;
  case 2:
    return radius_lg + 2.0 * radius_sm - penetration;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<radius_effective>:
  endbr64
  cmp    $0x2,%edi
  je     L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  addsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  ret
```

assistant: ```c
double radius_effective(int mode, double radius_lg, double radius_sm, double penetration) {
  switch (mode) {
  default:
  case 1:
    return radius_lg;
  case 2:
    return radius_lg + 2.0 * radius_sm - penetration;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L22
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <scan_file@plt>
  test   %rax,%rax
  js     L5
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  jmp    L33
L5:
  nop
L33:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    if (scan_file(argv[i]) < 0)
      break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L20
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L12:
  mov    (%rbx),%rdi
  call   <scan_file@plt>
  test   %rax,%rax
  js     L21
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L12
L21:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    if (scan_file(argv[i]) < 0)
      break;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L26
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  jmp    L34
  nopl   (%rax)
L10:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L22
L34:
  mov    (%rbx),%rdi
  call   <scan_file@plt>
  test   %rax,%rax
  jns    L10
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    if (scan_file(argv[i]) < 0)
      break;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L34
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  jmp    L6
  nopl   (%rax)
L8:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L4
L6:
  mov    (%rbx),%rdi
  call   <scan_file@plt>
  test   %rax,%rax
  jns    L8
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    if (scan_file(argv[i]) < 0)
      break;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L26
L1:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x20(%rbp)
  subq   $0x1,-0x30(%rbp)
L26:
  cmpq   $0x1,-0x20(%rbp)
  jbe    L24
  cmpq   $0x0,-0x30(%rbp)
  je     L24
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
L24:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t strlncpy(char *dst, size_t size, const char *src, size_t len) {
  size_t n = 0;
  assert(size > 0);
  while (size > 1 && len > 0 && *src) {
    *dst++ = *src++;
    n++;
    size--;
    len--;
  }
  *dst = '\0';
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlncpy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r12
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x1,%rbp
  jbe    L21
  mov    $0x0,%eax
  test   %r12,%r12
  je     L21
L29:
  movzbl 0x0(%r13,%rax,1),%edx
  test   %dl,%dl
  je     L44
  add    $0x1,%rbx
  mov    %dl,-0x1(%rbx)
  add    $0x1,%rax
  mov    %rbp,%rdx
  sub    %rax,%rdx
  cmp    $0x1,%rdx
  jbe    L44
  cmp    %rax,%r12
  jne    L29
L44:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  mov    $0x0,%eax
  jmp    L44
```

assistant: ```c
size_t strlncpy(char *dst, size_t size, const char *src, size_t len) {
  size_t n = 0;
  assert(size > 0);
  while (size > 1 && len > 0 && *src) {
    *dst++ = *src++;
    n++;
    size--;
    len--;
  }
  *dst = '\0';
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlncpy>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  cmp    $0x1,%rbp
  jbe    L35
  xor    %eax,%eax
  test   %r12,%r12
  jne    L31
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L46:
  add    $0x1,%rax
  mov    %dil,(%rbx)
  mov    %rbp,%rdi
  add    $0x1,%rbx
  sub    %rax,%rdi
  cmp    $0x1,%rdi
  jbe    L68
  cmp    %rax,%r12
  je     L68
L31:
  movzbl 0x0(%r13,%rax,1),%edi
  test   %dil,%dil
  jne    L46
L68:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  xor    %eax,%eax
  jmp    L68
```

assistant: ```c
size_t strlncpy(char *dst, size_t size, const char *src, size_t len) {
  size_t n = 0;
  assert(size > 0);
  while (size > 1 && len > 0 && *src) {
    *dst++ = *src++;
    n++;
    size--;
    len--;
  }
  *dst = '\0';
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlncpy>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  cmp    $0x1,%rbp
  jbe    L32
  xor    %eax,%eax
  test   %r12,%r12
  jne    L54
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  mov    %dil,(%rbx)
  mov    %rbp,%rdi
  add    $0x1,%rbx
  sub    %rax,%rdi
  cmp    $0x1,%rdi
  jbe    L68
  cmp    %rax,%r12
  je     L68
L54:
  movzbl 0x0(%r13,%rax,1),%edi
  test   %dil,%dil
  jne    L8
L68:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  xor    %eax,%eax
  jmp    L68
```

assistant: ```c
size_t strlncpy(char *dst, size_t size, const char *src, size_t len) {
  size_t n = 0;
  assert(size > 0);
  while (size > 1 && len > 0 && *src) {
    *dst++ = *src++;
    n++;
    size--;
    len--;
  }
  *dst = '\0';
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<StateCache_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ParsedPMinisock_cache_destroy@plt>
  mov    $0x0,%eax
  call   <Continuation_cache_destroy@plt>
  mov    $0x0,%eax
  call   <NonceKey_cache_destroy@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void StateCache_destroy(void) {
  ParsedPMinisock_cache_destroy();
  Continuation_cache_destroy();
  NonceKey_cache_destroy();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<StateCache_destroy>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ParsedPMinisock_cache_destroy@plt>
  mov    $0x0,%eax
  call   <Continuation_cache_destroy@plt>
  mov    $0x0,%eax
  call   <NonceKey_cache_destroy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void StateCache_destroy(void) {
  ParsedPMinisock_cache_destroy();
  Continuation_cache_destroy();
  NonceKey_cache_destroy();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<StateCache_destroy>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ParsedPMinisock_cache_destroy@plt>
  xor    %eax,%eax
  call   <Continuation_cache_destroy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <NonceKey_cache_destroy@plt>
```

assistant: ```c
void StateCache_destroy(void) {
  ParsedPMinisock_cache_destroy();
  Continuation_cache_destroy();
  NonceKey_cache_destroy();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<StateCache_destroy>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ParsedPMinisock_cache_destroy@plt>
  xor    %eax,%eax
  call   <Continuation_cache_destroy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <NonceKey_cache_destroy@plt>
```

assistant: ```c
void StateCache_destroy(void) {
  ParsedPMinisock_cache_destroy();
  Continuation_cache_destroy();
  NonceKey_cache_destroy();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_file@plt>
  mov    $0x0,%eax
  call   <test_bom@plt>
  mov    $0x0,%eax
  call   <test_no_newline@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_file();
  test_bom();
  test_no_newline();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_file@plt>
  mov    $0x0,%eax
  call   <test_bom@plt>
  mov    $0x0,%eax
  call   <test_no_newline@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_file();
  test_bom();
  test_no_newline();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_file@plt>
  xor    %eax,%eax
  call   <test_bom@plt>
  xor    %eax,%eax
  call   <test_no_newline@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_file();
  test_bom();
  test_no_newline();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_file@plt>
  xor    %eax,%eax
  call   <test_bom@plt>
  xor    %eax,%eax
  call   <test_no_newline@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_file();
  test_bom();
  test_no_newline();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0xffffffff,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  lea    -0x24(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <insertion_sort@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <insertion_sort@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L2
L35:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,-0x28(%rbp)
  jle    L6
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0xffffffff,-0x30(%rbp)
L6:
  addl   $0x1,-0x2c(%rbp)
L2:
  cmpl   $0x4,-0x2c(%rbp)
  jle    L35
  mov    -0x30(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: us2 error: index %d, val %d > index %d, val %d


assistant: ```c
int main(int argc, char **argv) {
  int failed = 0;
  int us1[1] = {-1};
  int us2[5] = {4, 3, 2, 1, 2};
  insertion_sort(us1, 0, 0);
  insertion_sort(us2, 0, 5);
  int prev = us2[0];
  for (int i = 0; i < 5; i++) {
    if (us2[i] < prev) {
      printf("us2 error: index %d, val %d > index %d, val %d\n", i, us2[i], i - 1, prev);
      failed = -1;
    }
  }
  return failed;
}
```