ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<index_solution_diff>:
  endbr64
  push   %r12
  test   %edx,%edx
  jle    L0
  lea    -0x1(%rdx),%r10d
  mov    %edx,%r9d
  xor    %eax,%eax
  xor    %r12d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    (%rsi,%rax,8),%r11
  cmp    %r11,(%rdi,%rax,8)
  je     L16
  movslq %r12d,%r8
  add    $0x1,%r12d
  mov    %eax,(%rcx,%r8,4)
L16:
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L15
  cmp    %edx,%r12d
  jge    L8
  mov    %r10d,%eax
  xor    %esi,%esi
  sub    %r12d,%eax
  lea    0x4(,%rax,4),%rdx
  movslq %r12d,%rax
  lea    (%rcx,%rax,4),%rdi
  call   <memset@plt>
L8:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L0:
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int index_solution_diff(int8_t *solution_A, int8_t *solution_B, int nbits, int *index) {
  int i, ndiff = 0;
  for (i = 0; i < nbits; i++) {
    if (solution_A[i] != solution_B[i]) {
      index[ndiff++] = i;
    }
  }
  for (i = ndiff; i < nbits; i++) {
    index[i] = 0;
  }
  return ndiff;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<index_solution_diff>:
  endbr64
  push   %r12
  test   %edx,%edx
  jle    L29
  lea    -0x1(%rdx),%r10d
  mov    %edx,%r9d
  xor    %eax,%eax
  xor    %r12d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    (%rsi,%rax,8),%r11
  cmp    %r11,(%rdi,%rax,8)
  je     L16
  movslq %r12d,%r8
  add    $0x1,%r12d
  mov    %eax,(%rcx,%r8,4)
L16:
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L15
  cmp    %edx,%r12d
  jge    L12
  mov    %r10d,%eax
  xor    %esi,%esi
  sub    %r12d,%eax
  lea    0x4(,%rax,4),%rdx
  movslq %r12d,%rax
  lea    (%rcx,%rax,4),%rdi
  call   <memset@plt>
L12:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L29:
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int index_solution_diff(int8_t *solution_A, int8_t *solution_B, int nbits, int *index) {
  int i, ndiff = 0;
  for (i = 0; i < nbits; i++) {
    if (solution_A[i] != solution_B[i]) {
      index[ndiff++] = i;
    }
  }
  for (i = ndiff; i < nbits; i++) {
    index[i] = 0;
  }
  return ndiff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<spr_compile>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    $0x3b,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L145
  mov    %rsp,%rdx
L20:
  movb   $0x0,(%rax)
  cmp    %rdx,%rax
  je     L94
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L20
L145:
  cmpb   $0x20,(%rsp)
  je     L193
  mov    %rsp,%rax
L44:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  jne    L44
L18:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L18
  mov    $0x0,%ecx
  cmp    $0x44,%dl
  jne    L89
  cmpb   $0x42,0x1(%rax)
  jne    L89
  lea    0x2(%rax),%rbx
  mov    $0x0,%r14d
  jmp    L178
L166:
  add    $0x1,%rbx
  jmp    L178
L86:
  movslq %r14d,%r15
  add    %rbp,%r15
  lea    0x1(%rbx),%rdi
  call   <hex2i@plt>
  mov    %al,(%r15)
  jmp    L199
L4:
  add    $0x1,%r14d
  test   %r13,%r13
  je     L34
  lea    0x1(%r13),%rbx
L178:
  cmpb   $0x20,(%rbx)
  je     L166
  mov    $0x2c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L147
  movb   $0x0,(%rax)
L147:
  cmpb   $0x23,(%rbx)
  je     L86
  movslq %r14d,%r15
  add    %rbp,%r15
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %al,(%r15)
L199:
  test   %r12d,%r12d
  je     L4
  movslq %r14d,%rax
  notb   0x0(%rbp,%rax,1)
  jmp    L4
L94:
  mov    $0x0,%ecx
L89:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L133
  mov    %ecx,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  mov    $0x1,%ecx
  jmp    L89
L193:
  mov    %rsp,%rax
  jmp    L18
L133:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int spr_compile(char *_s, int f, char *code) {
  char *poo, *po;
  char s[100];
  int codelen = 0;
  strcpy(s, _s);
  po = strchr(s, ';');
  if (po != NULL) {
    while (1) {
      *po = 0;
      if (po == s)
        return 0;
      po--;
      if (*po != ' ')
        break;
    }
  }
  po = s;
  while (*po != ' ')
    po++;
  while (*po == ' ')
    po++;
  if (*po != 'D')
    return 0;
  po++;
  if (*po != 'B')
    return 0;
  po++;
  while (1) {
    while (*po == ' ')
      po++;
    poo = strchr(po, ',');
    if (poo != NULL)
      *poo = 0;
    if (*po == '#')
      code[codelen] = hex2i(po + 1);
    else
      code[codelen] = atoi(po);
    if (f)
      code[codelen] = ~code[codelen];
    codelen++;
    if (poo == NULL)
      break;
    poo++;
    po = poo;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spr_compile>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    $0x3b,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L128
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L70:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  jne    L16
L128:
  movb   $0x0,(%rax)
  cmp    %rbx,%rax
  jne    L70
L101:
  xor    %eax,%eax
L120:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L125
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  cmpb   $0x20,(%rsp)
  mov    %rbx,%rax
  je     L17
  nopl   0x0(%rax)
L173:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  jne    L173
  nopl   0x0(%rax)
L17:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L17
  cmp    $0x44,%dl
  jne    L101
  cmpb   $0x42,0x1(%rax)
  jne    L101
  lea    0x2(%rax),%rbp
  xor    %r14d,%r14d
  nop
L52:
  cmpb   $0x20,0x0(%rbp)
  je     L110
L126:
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L61
  movb   $0x0,(%rax)
L61:
  movslq %r14d,%rbx
  add    %r13,%rbx
  cmpb   $0x23,0x0(%rbp)
  je     L144
  mov    %rbp,%rdi
  call   <atoi@plt>
L14:
  mov    %eax,%edx
  test   %r12d,%r12d
  not    %edx
  cmovne %edx,%eax
  add    $0x1,%r14d
  mov    %al,(%rbx)
  test   %r15,%r15
  je     L138
  cmpb   $0x20,0x1(%r15)
  lea    0x1(%r15),%rbp
  jne    L126
L110:
  add    $0x1,%rbp
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L144:
  lea    0x1(%rbp),%rdi
  call   <hex2i@plt>
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L138:
  mov    $0x1,%eax
  jmp    L120
L125:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int spr_compile(char *_s, int f, char *code) {
  char *poo, *po;
  char s[100];
  int codelen = 0;
  strcpy(s, _s);
  po = strchr(s, ';');
  if (po != NULL) {
    while (1) {
      *po = 0;
      if (po == s)
        return 0;
      po--;
      if (*po != ' ')
        break;
    }
  }
  po = s;
  while (*po != ' ')
    po++;
  while (*po == ' ')
    po++;
  if (*po != 'D')
    return 0;
  po++;
  if (*po != 'B')
    return 0;
  po++;
  while (1) {
    while (*po == ' ')
      po++;
    poo = strchr(po, ',');
    if (poo != NULL)
      *poo = 0;
    if (*po == '#')
      code[codelen] = hex2i(po + 1);
    else
      code[codelen] = atoi(po);
    if (f)
      code[codelen] = ~code[codelen];
    codelen++;
    if (poo == NULL)
      break;
    poo++;
    po = poo;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  jne    L13
L68:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    %rdi,%r13
  movslq %esi,%r14
  lea    0x0(,%rsi,4),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movl   $0x0,(%r12)
  movl   $0x0,-0x4(%rax,%r14,4)
  cmp    $0x2,%ebx
  jle    L40
  lea    -0x3(%rbx),%eax
  lea    0x4(%r12,%rax,4),%rdi
  mov    %r12,%rax
  mov    %r13,%rsi
  sub    %r12,%rsi
L54:
  mov    (%rax),%edx
  mov    (%rsi,%rax,1),%ecx
  add    $0x4,%rax
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,(%rax)
  cmp    %rdi,%rax
  jne    L54
L40:
  lea    -0x2(%rbx),%eax
  test   %eax,%eax
  jle    L53
  lea    -0x1(%rbx),%edi
  movslq %edi,%rdi
  shl    $0x2,%rdi
  lea    (%rdi,%rbp,1),%rdx
  sub    $0x4,%rdi
  lea    -0x3(%rbx),%eax
  shl    $0x2,%rax
  sub    %rax,%rdi
  add    %rbp,%rdi
  mov    $0x0,%ebx
  sub    %rbp,%r13
  lea    -0x4(%r12),%r8
  sub    %rbp,%r8
L48:
  mov    (%rdx),%eax
  mov    0x0(%r13,%rdx,1),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  mov    %eax,-0x4(%rdx)
  mov    (%r8,%rdx,1),%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    -0x4(%r13,%rdx,1),%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  add    %ebx,%ecx
  cmp    %eax,%esi
  cmovl  %ecx,%ebx
  sub    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L48
L35:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L68
L53:
  mov    $0x0,%ebx
  jmp    L35
```

assistant: ```c
int trap(int *height, int heightSize) {
  int *l_hi, *r_hi, i, m, w = 0;
  if (!heightSize)
    return 0;
  l_hi = (int *)malloc(heightSize * sizeof(int));
  r_hi = (int *)malloc(heightSize * sizeof(int));
  l_hi[0] = 0;
  r_hi[heightSize - 1] = 0;
  for (i = 1; i < heightSize - 1; ++i)
    l_hi[i] = (height[i - 1] > l_hi[i - 1] ? height[i - 1] : l_hi[i - 1]);
  for (i = heightSize - 2; i > 0; --i) {
    r_hi[i] = (height[i + 1] > r_hi[i + 1] ? height[i + 1] : r_hi[i + 1]);
    m = (l_hi[i] < r_hi[i] ? l_hi[i] : r_hi[i]);
    if (height[i] < m)
      w += m - height[i];
  }
  free(l_hi);
  free(r_hi);
  return w;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trap>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jne    L51
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  lea    0x0(,%rsi,4),%ebp
  mov    %rdi,%rbx
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  movl   $0x0,0x0(%r13)
  mov    %rax,%rbp
  movslq %r12d,%rax
  movl   $0x0,-0x4(%rbp,%rax,4)
  cmp    $0x2,%r12d
  jle    L21
  lea    -0x3(%r12),%eax
  mov    %rbx,%rsi
  lea    0x4(%r13,%rax,4),%rdi
  sub    %r13,%rsi
  mov    %r13,%rax
  nopw   0x0(%rax,%rax,1)
L23:
  mov    (%rax),%edx
  mov    (%rsi,%rax,1),%ecx
  add    $0x4,%rax
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,(%rax)
  cmp    %rdi,%rax
  jne    L23
L21:
  lea    -0x2(%r12),%eax
  test   %eax,%eax
  jle    L54
  lea    -0x1(%r12),%r8d
  lea    -0x3(%r12),%eax
  sub    %rbp,%rbx
  xor    %r12d,%r12d
  movslq %r8d,%r8
  shl    $0x2,%rax
  lea    -0x4(%r13),%r9
  mov    %rbx,%rsi
  shl    $0x2,%r8
  sub    %rbp,%r9
  lea    0x0(%rbp,%r8,1),%rdx
  sub    $0x4,%r8
  sub    %rax,%r8
  add    %rbp,%r8
  xchg   %ax,%ax
L42:
  mov    (%rsi,%rdx,1),%edi
  mov    (%rdx),%eax
  mov    %rdx,%rcx
  sub    $0x4,%rdx
  cmp    %edi,%eax
  cmovl  %edi,%eax
  mov    %eax,(%rdx)
  mov    (%r9,%rcx,1),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  mov    -0x4(%rsi,%rcx,1),%edi
  mov    %eax,%ecx
  sub    %edi,%ecx
  add    %r12d,%ecx
  cmp    %eax,%edi
  cmovl  %ecx,%r12d
  cmp    %r8,%rdx
  jne    L42
L7:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  xor    %r12d,%r12d
  jmp    L7
```

assistant: ```c
int trap(int *height, int heightSize) {
  int *l_hi, *r_hi, i, m, w = 0;
  if (!heightSize)
    return 0;
  l_hi = (int *)malloc(heightSize * sizeof(int));
  r_hi = (int *)malloc(heightSize * sizeof(int));
  l_hi[0] = 0;
  r_hi[heightSize - 1] = 0;
  for (i = 1; i < heightSize - 1; ++i)
    l_hi[i] = (height[i - 1] > l_hi[i - 1] ? height[i - 1] : l_hi[i - 1]);
  for (i = heightSize - 2; i > 0; --i) {
    r_hi[i] = (height[i + 1] > r_hi[i + 1] ? height[i + 1] : r_hi[i + 1]);
    m = (l_hi[i] < r_hi[i] ? l_hi[i] : r_hi[i]);
    if (height[i] < m)
      w += m - height[i];
  }
  free(l_hi);
  free(r_hi);
  return w;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trap>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jne    L46
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  lea    0x0(,%rsi,4),%r13d
  mov    %rdi,%rbx
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  movslq %r12d,%r8
  movl   $0x0,0x0(%rbp)
  shl    $0x2,%r8
  mov    %rax,%r13
  movl   $0x0,-0x4(%rax,%r8,1)
  cmp    $0x2,%r12d
  jle    L7
  lea    -0x3(%r12),%edx
  mov    %rbx,%rsi
  lea    0x4(%rbp),%rax
  mov    %rdx,%r9
  lea    0x8(%rbp,%rdx,4),%rdi
  sub    %rbp,%rsi
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    -0x4(%rsi,%rax,1),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rdi,%rax
  jne    L4
  cmp    $0x2,%r12d
  jle    L7
  shl    $0x2,%r9
  mov    -0x4(%r13,%r8,1),%edx
  mov    %r13,%r10
  xor    %r12d,%r12d
  lea    -0x8(%rbx,%r8,1),%rax
  lea    -0xc(%rbx,%r8,1),%r8
  sub    %rbx,%r10
  sub    %r9,%r8
  mov    %rbp,%r9
  sub    %rbx,%r9
  nopl   0x0(%rax,%rax,1)
L11:
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,(%r10,%rax,1)
  mov    (%r9,%rax,1),%ecx
  mov    (%rax),%edi
  cmp    %ecx,%edx
  cmovle %edx,%ecx
  mov    %ecx,%esi
  sub    %edi,%esi
  add    %r12d,%esi
  cmp    %ecx,%edi
  cmovl  %esi,%r12d
  sub    $0x4,%rax
  cmp    %r8,%rax
  jne    L11
L35:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %r12d,%r12d
  jmp    L35
```

assistant: ```c
int trap(int *height, int heightSize) {
  int *l_hi, *r_hi, i, m, w = 0;
  if (!heightSize)
    return 0;
  l_hi = (int *)malloc(heightSize * sizeof(int));
  r_hi = (int *)malloc(heightSize * sizeof(int));
  l_hi[0] = 0;
  r_hi[heightSize - 1] = 0;
  for (i = 1; i < heightSize - 1; ++i)
    l_hi[i] = (height[i - 1] > l_hi[i - 1] ? height[i - 1] : l_hi[i - 1]);
  for (i = heightSize - 2; i > 0; --i) {
    r_hi[i] = (height[i + 1] > r_hi[i + 1] ? height[i + 1] : r_hi[i + 1]);
    m = (l_hi[i] < r_hi[i] ? l_hi[i] : r_hi[i]);
    if (height[i] < m)
      w += m - height[i];
  }
  free(l_hi);
  free(r_hi);
  return w;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x9999,%edi
  call   <bufferedInputStream@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferedReadInt@plt>
  mov    %eax,-0x1c(%rbp)
  fildl  -0x1c(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  jmp    L11
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferedReadLongDouble@plt>
  fstpt  -0x10(%rbp)
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
L11:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D5: %d


tool: D1: %.6LF


assistant: ```c
int main() {
  struct BufferedInputStream *bis = bufferedInputStream(786432ull / 20);
  int n;
  long double d;
  n = bufferedReadInt(bis);
  printf("%d\n", n);
  while (n--) {
    d = bufferedReadLongDouble(bis);
    printf("%.6LF\n", d);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    $0x9999,%edi
  call   <bufferedInputStream@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <bufferedReadInt@plt>
  mov    %eax,%ebx
  mov    %eax,0xc(%rsp)
  fildl  0xc(%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  test   %ebx,%ebx
  je     L5
  lea    D18(%rip),%r12
L14:
  mov    %rbp,%rdi
  call   <bufferedReadLongDouble@plt>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  sub    $0x1,%ebx
  jne    L14
L5:
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string

tool: D5: %d


tool: D18: %.6LF


assistant: ```c
int main() {
  struct BufferedInputStream *bis = bufferedInputStream(786432ull / 20);
  int n;
  long double d;
  n = bufferedReadInt(bis);
  printf("%d\n", n);
  while (n--) {
    d = bufferedReadLongDouble(bis);
    printf("%.6LF\n", d);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9999,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <bufferedInputStream@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <bufferedReadInt@plt>
  sub    $0x10,%rsp
  lea    D6(%rip),%rdi
  mov    %eax,0x1c(%rsp)
  fildl  0x1c(%rsp)
  mov    %eax,%ebx
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rcx
  pop    %rsi
  test   %ebx,%ebx
  je     L16
  lea    D4(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rdi
  call   <bufferedReadLongDouble@plt>
  sub    $0x10,%rsp
  mov    %r12,%rdi
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  sub    $0x1,%ebx
  jne    L11
L16:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string

tool: D6: %d


tool: D4: %.6LF


assistant: ```c
int main() {
  struct BufferedInputStream *bis = bufferedInputStream(786432ull / 20);
  int n;
  long double d;
  n = bufferedReadInt(bis);
  printf("%d\n", n);
  while (n--) {
    d = bufferedReadLongDouble(bis);
    printf("%.6LF\n", d);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9999,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <bufferedInputStream@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <bufferedReadInt@plt>
  sub    $0x10,%rsp
  lea    D11(%rip),%rdi
  mov    %eax,0x1c(%rsp)
  fildl  0x1c(%rsp)
  mov    %eax,%ebx
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rcx
  pop    %rsi
  test   %ebx,%ebx
  je     L3
  lea    D17(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <bufferedReadLongDouble@plt>
  sub    $0x10,%rsp
  mov    %r12,%rdi
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  sub    $0x1,%ebx
  jne    L2
L3:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string

tool: D11: %d


tool: D17: %.6LF


assistant: ```c
int main() {
  struct BufferedInputStream *bis = bufferedInputStream(786432ull / 20);
  int n;
  long double d;
  n = bufferedReadInt(bis);
  printf("%d\n", n);
  while (n--) {
    d = bufferedReadLongDouble(bis);
    printf("%.6LF\n", d);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<insertion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L22
L9:
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L23:
  cmpl   $0x0,-0xc(%rbp)
  js     L49
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jg     L12
L49:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L22:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void insertion(void **ar, int (*cmp)(const void *, const void *), int low, int high) {
  int loc;
  for (loc = low + 1; loc <= high; loc++) {
    int i = loc - 1;
    void *value = ar[loc];
    while (i >= 0 && cmp(ar[i], value) > 0) {
      ar[i + 1] = ar[i];
      i--;
    }
    ar[i + 1] = value;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertion>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %ecx,0xc(%rsp)
  lea    0x1(%rdx),%r15d
  cmp    %ecx,%r15d
  jg     L35
  mov    %rsi,%r13
  mov    %edx,%r14d
  movslq %r15d,%r15
  jmp    L4
L46:
  movslq %ebp,%rbp
  mov    (%rsp),%rax
  mov    %r12,0x8(%rax,%rbp,8)
  add    $0x1,%r15
  add    $0x1,%r14d
  cmp    %r15d,0xc(%rsp)
  jl     L35
L4:
  mov    %r14d,%ebp
  mov    (%rsp),%rdx
  mov    (%rdx,%r15,8),%r12
  test   %r14d,%r14d
  js     L46
  movslq %r14d,%rax
  lea    (%rdx,%rax,8),%rbx
L31:
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   *%r13
  test   %eax,%eax
  jle    L46
  mov    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  sub    $0x1,%ebp
  sub    $0x8,%rbx
  cmp    $0xffffffff,%ebp
  jne    L31
  jmp    L46
L35:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void insertion(void **ar, int (*cmp)(const void *, const void *), int low, int high) {
  int loc;
  for (loc = low + 1; loc <= high; loc++) {
    int i = loc - 1;
    void *value = ar[loc];
    while (i >= 0 && cmp(ar[i], value) > 0) {
      ar[i + 1] = ar[i];
      i--;
    }
    ar[i + 1] = value;
  }
}
```