ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
L7:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L23
L12:
  cmp    $0x20,%edi
  je     L5
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L12
L23:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  call   <putchar@plt>
  nopl   (%rax)
L53:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x20,%eax
  je     L53
  cmp    %eax,(%rbx)
  je     L23
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L7
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      putchar(c);
      while ((c = getchar()) == ' ') {
      }
      if (c == EOF)
        return 0;
      putchar(c);
    } else {
      putchar(c);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D5(%rip),%rbx
L44:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L28
L0:
  cmp    $0x20,%edi
  je     L20
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L0
L28:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L20:
  call   <putchar@plt>
  nopl   (%rax)
L38:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x20,%eax
  je     L38
  cmp    %eax,(%rbx)
  je     L28
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L44
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      putchar(c);
      while ((c = getchar()) == ' ') {
      }
      if (c == EOF)
        return 0;
      putchar(c);
    } else {
      putchar(c);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_l2assoc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0xf,-0x18(%rbp)
  ja     L24
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  lea    D27(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D27(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
  movq   $0x2,-0x8(%rbp)
  jmp    L36
  movq   $0x4,-0x8(%rbp)
  jmp    L36
  movq   $0x8,-0x8(%rbp)
  jmp    L36
  movq   $0x10,-0x8(%rbp)
  jmp    L36
  movq   $0x20,-0x8(%rbp)
  jmp    L36
  movq   $0x30,-0x8(%rbp)
  jmp    L36
  movq   $0x40,-0x8(%rbp)
  jmp    L36
  movq   $0x60,-0x8(%rbp)
  jmp    L36
  movq   $0x80,-0x8(%rbp)
  jmp    L36
L24:
  nop
L36:
  cmpq   $0x0,-0x8(%rbp)
  je     L109
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L109:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D50
data_type: string
name: parse_data
arguments: label: D32
data_type: string
name: parse_data
arguments: label: D31
data_type: string
name: parse_data
arguments: label: D55
data_type: string

tool: D50: Disabled. 

tool: D32: Direct mapped. 

tool: D31: Fully associative. 

tool: D55: %lu-way associative. 

assistant: ```c
void do_l2assoc(unsigned long assoc) {
  unsigned long a;
  a = 0;
  switch (assoc) {
  case 0x0:
    printf("Disabled. ");
    break;
  case 0x1:
    printf("Direct mapped. ");
    break;
  case 0xf:
    printf("Fully associative. ");
    break;
  case 0x2:
    a = 2;
    break;
  case 0x4:
    a = 4;
    break;
  case 0x6:
    a = 8;
    break;
  case 0x8:
    a = 16;
    break;
  case 0xa:
    a = 32;
    break;
  case 0xb:
    a = 48;
    break;
  case 0xc:
    a = 64;
    break;
  case 0xd:
    a = 96;
    break;
  case 0xe:
    a = 128;
    break;
  default:
    break;
  }
  if (a)
    printf("%lu-way associative. ", a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_l2assoc>:
  endbr64
  cmp    $0xf,%rdi
  ja     L22
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x80,%esi
  jmp    L14
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L73
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L73
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L73
  mov    $0x60,%esi
L14:
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L73:
  add    $0x8,%rsp
  ret
  mov    $0x40,%esi
  jmp    L14
  mov    $0x30,%esi
  jmp    L14
  mov    $0x20,%esi
  jmp    L14
  mov    $0x10,%esi
  jmp    L14
  mov    $0x8,%esi
  jmp    L14
L22:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D41
type_guessed: string
name: parse_data
arguments: data_label: D44
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string

tool: D41: Disabled. 

tool: D44: Direct mapped. 

tool: D12: Fully associative. 

tool: D16: %lu-way associative. 

assistant: ```c
void do_l2assoc(unsigned long assoc) {
  unsigned long a;
  a = 0;
  switch (assoc) {
  case 0x0:
    printf("Disabled. ");
    break;
  case 0x1:
    printf("Direct mapped. ");
    break;
  case 0xf:
    printf("Fully associative. ");
    break;
  case 0x2:
    a = 2;
    break;
  case 0x4:
    a = 4;
    break;
  case 0x6:
    a = 8;
    break;
  case 0x8:
    a = 16;
    break;
  case 0xa:
    a = 32;
    break;
  case 0xb:
    a = 48;
    break;
  case 0xc:
    a = 64;
    break;
  case 0xd:
    a = 96;
    break;
  case 0xe:
    a = 128;
    break;
  default:
    break;
  }
  if (a)
    printf("%lu-way associative. ", a);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_l2assoc>:
  endbr64
  mov    %rdi,%rsi
  cmp    $0xf,%rdi
  ja     L37
  lea    D39(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xchg   %ax,%ax
  mov    $0x8,%esi
L11:
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L37:
  ret
  nopl   0x0(%rax)
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
  mov    $0x10,%esi
  jmp    L11
  nopw   0x0(%rax,%rax,1)
  mov    $0x20,%esi
  jmp    L11
  nopw   0x0(%rax,%rax,1)
  mov    $0x30,%esi
  jmp    L11
  nopw   0x0(%rax,%rax,1)
  mov    $0x40,%esi
  jmp    L11
  nopw   0x0(%rax,%rax,1)
  mov    $0x60,%esi
  jmp    L11
  nopw   0x0(%rax,%rax,1)
  mov    $0x80,%esi
  jmp    L11
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D26
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D18: %lu-way associative. 

tool: D26: Disabled. 

tool: D14: Direct mapped. 

tool: D6: Fully associative. 

assistant: ```c
void do_l2assoc(unsigned long assoc) {
  unsigned long a;
  a = 0;
  switch (assoc) {
  case 0x0:
    printf("Disabled. ");
    break;
  case 0x1:
    printf("Direct mapped. ");
    break;
  case 0xf:
    printf("Fully associative. ");
    break;
  case 0x2:
    a = 2;
    break;
  case 0x4:
    a = 4;
    break;
  case 0x6:
    a = 8;
    break;
  case 0x8:
    a = 16;
    break;
  case 0xa:
    a = 32;
    break;
  case 0xb:
    a = 48;
    break;
  case 0xc:
    a = 64;
    break;
  case 0xd:
    a = 96;
    break;
  case 0xe:
    a = 128;
    break;
  default:
    break;
  }
  if (a)
    printf("%lu-way associative. ", a);
}
```
user: What is the c source code of the assembly code below?

```asm
<do_l2assoc>:
  endbr64
  mov    %rdi,%rsi
  cmp    $0xf,%rdi
  ja     L25
  lea    D6(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xchg   %ax,%ax
  mov    $0x8,%esi
L37:
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L25:
  ret
  nopl   0x0(%rax)
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
  mov    $0x10,%esi
  jmp    L37
  nopw   0x0(%rax,%rax,1)
  mov    $0x20,%esi
  jmp    L37
  nopw   0x0(%rax,%rax,1)
  mov    $0x30,%esi
  jmp    L37
  nopw   0x0(%rax,%rax,1)
  mov    $0x40,%esi
  jmp    L37
  nopw   0x0(%rax,%rax,1)
  mov    $0x60,%esi
  jmp    L37
  nopw   0x0(%rax,%rax,1)
  mov    $0x80,%esi
  jmp    L37
```

tool_calls: name: retrieve_data
arguments: label: D37
data_type: string
name: retrieve_data
arguments: label: D30
data_type: string
name: retrieve_data
arguments: label: D29
data_type: string
name: retrieve_data
arguments: label: D36
data_type: string

tool: D37: %lu-way associative. 

tool: D30: Disabled. 

tool: D29: Direct mapped. 

tool: D36: Fully associative. 

assistant: ```c
void do_l2assoc(unsigned long assoc) {
  unsigned long a;
  a = 0;
  switch (assoc) {
  case 0x0:
    printf("Disabled. ");
    break;
  case 0x1:
    printf("Direct mapped. ");
    break;
  case 0xf:
    printf("Fully associative. ");
    break;
  case 0x2:
    a = 2;
    break;
  case 0x4:
    a = 4;
    break;
  case 0x6:
    a = 8;
    break;
  case 0x8:
    a = 16;
    break;
  case 0xa:
    a = 32;
    break;
  case 0xb:
    a = 48;
    break;
  case 0xc:
    a = 64;
    break;
  case 0xd:
    a = 96;
    break;
  case 0xe:
    a = 128;
    break;
  default:
    break;
  }
  if (a)
    printf("%lu-way associative. ", a);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <__REGISTER_RTX_ENTRY__@plt>
  mov    $0x0,%eax
  call   <__RTX_ENTRY__@plt>
L6:
  jmp    L6
```

assistant: ```c
int main(void) {
  __REGISTER_RTX_ENTRY__();
  __RTX_ENTRY__();
  while (1) {
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__REGISTER_RTX_ENTRY__@plt>
  mov    $0x0,%eax
  call   <__RTX_ENTRY__@plt>
L8:
  jmp    L8
```

assistant: ```c
int main(void) {
  __REGISTER_RTX_ENTRY__();
  __RTX_ENTRY__();
  while (1) {
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__REGISTER_RTX_ENTRY__@plt>
  xor    %eax,%eax
  call   <__RTX_ENTRY__@plt>
L0:
  jmp    L0
```

assistant: ```c
int main(void) {
  __REGISTER_RTX_ENTRY__();
  __RTX_ENTRY__();
  while (1) {
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__REGISTER_RTX_ENTRY__@plt>
  xor    %eax,%eax
  call   <__RTX_ENTRY__@plt>
L8:
  jmp    L8
```

assistant: ```c
int main(void) {
  __REGISTER_RTX_ENTRY__();
  __RTX_ENTRY__();
  while (1) {
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bcholu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  movl   $0x20,-0x20(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %eax,%edx
  mov    -0x3c(%rbp),%eax
  cltq
  imul   %edx,%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  cltq
  imul   %edx,%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rdi
  mov    -0x8(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x3c(%rbp),%esi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <rbcholu@plt>
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L39
L1:
  mov    -0x28(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L26
L27:
  mov    -0x14(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x24(%rbp)
L26:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L27
  addl   $0x1,-0x28(%rbp)
L39:
  mov    -0x28(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int bcholu(double *A, int N) {
  int stride, i, j, t, b, sc;
  double *UB, *UT;
  b = (int)32;
  UT = (double *)malloc(sizeof(double) * N * N);
  UB = (double *)malloc(sizeof(double) * b * b);
  stride = N;
  sc = rbcholu(A, N, stride, UB, UT);
  for (i = 0; i < N; ++i) {
    t = i * N;
    for (j = 0; j < i; ++j) {
      A[t + j] = 0.;
    }
  }
  free(UB);
  free(UT);
  return sc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bcholu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebx
  movslq %esi,%r15
  mov    %esi,%edi
  imul   %esi,%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x2000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbp,%r8
  mov    %rax,%rcx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <rbcholu@plt>
  mov    %eax,%r13d
  test   %ebx,%ebx
  jle    L39
  lea    0x0(,%r15,8),%rdi
  lea    (%r14,%rdi,1),%rsi
  lea    0x8(%rdi),%r8
  lea    0x8(%r14,%rdi,1),%rdx
  mov    $0x0,%ecx
  jmp    L10
L42:
  test   %ecx,%ecx
  jle    L47
  mov    %rsi,%rax
L7:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L7
L47:
  add    %rdi,%rsi
  add    %r8,%rdx
L10:
  add    $0x1,%ecx
  cmp    %ecx,%ebx
  jne    L42
L39:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int bcholu(double *A, int N) {
  int stride, i, j, t, b, sc;
  double *UB, *UT;
  b = (int)32;
  UT = (double *)malloc(sizeof(double) * N * N);
  UB = (double *)malloc(sizeof(double) * b * b);
  stride = N;
  sc = rbcholu(A, N, stride, UB, UT);
  for (i = 0; i < N; ++i) {
    t = i * N;
    for (j = 0; j < i; ++j) {
      A[t + j] = 0.;
    }
  }
  free(UB);
  free(UT);
  return sc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bcholu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,%edi
  imul   %r12d,%edi
  sub    $0x18,%rsp
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    $0x2000,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %r13,%r8
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %rax,%rcx
  mov    %rbx,%rdi
  mov    %rax,%r14
  call   <rbcholu@plt>
  mov    %eax,0xc(%rsp)
  test   %r12d,%r12d
  jle    L20
  mov    %r12,%rbp
  shl    $0x3,%r12
  mov    $0x8,%r15d
  lea    (%rbx,%r12,1),%rcx
  xor    %ebx,%ebx
  jmp    L4
  nopl   0x0(%rax)
L0:
  mov    %r15,%rdx
  mov    %rcx,%rdi
  xor    %esi,%esi
  add    $0x8,%r15
  call   <memset@plt>
  mov    %rax,%rcx
  add    %r12,%rcx
L4:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L0
L20:
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int bcholu(double *A, int N) {
  int stride, i, j, t, b, sc;
  double *UB, *UT;
  b = (int)32;
  UT = (double *)malloc(sizeof(double) * N * N);
  UB = (double *)malloc(sizeof(double) * b * b);
  stride = N;
  sc = rbcholu(A, N, stride, UB, UT);
  for (i = 0; i < N; ++i) {
    t = i * N;
    for (j = 0; j < i; ++j) {
      A[t + j] = 0.;
    }
  }
  free(UB);
  free(UT);
  return sc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bcholu>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  mov    %ebp,%edi
  push   %rbx
  imul   %ebp,%edi
  sub    $0x18,%rsp
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    $0x2000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%r8
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %rax,%rcx
  mov    %r15,%rdi
  mov    %rax,%r13
  call   <rbcholu@plt>
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%ebp
  jle    L0
  mov    %rbp,%rbx
  shl    $0x3,%rbp
  mov    $0x8,%r14d
  lea    (%r15,%rbp,1),%rcx
  mov    $0x1,%r15d
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r14,%rdx
  mov    %rcx,%rdi
  xor    %esi,%esi
  add    $0x1,%r15d
  call   <memset@plt>
  add    $0x8,%r14
  mov    %rax,%rcx
  add    %rbp,%rcx
  cmp    %r15d,%ebx
  jne    L7
L0:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int bcholu(double *A, int N) {
  int stride, i, j, t, b, sc;
  double *UB, *UT;
  b = (int)32;
  UT = (double *)malloc(sizeof(double) * N * N);
  UB = (double *)malloc(sizeof(double) * b * b);
  stride = N;
  sc = rbcholu(A, N, stride, UB, UT);
  for (i = 0; i < N; ++i) {
    t = i * N;
    for (j = 0; j < i; ++j) {
      A[t + j] = 0.;
    }
  }
  free(UB);
  free(UT);
  return sc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<v4l2_ioctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <x_ioctl@plt>
  leave
  ret
```

assistant: ```c
int v4l2_ioctl(int fd, int id, void *param) {
  init();
  return x_ioctl(fd, id, param);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<v4l2_ioctl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    $0x0,%eax
  call   <init@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <x_ioctl@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int v4l2_ioctl(int fd, int id, void *param) {
  init();
  return x_ioctl(fd, id, param);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<v4l2_ioctl>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <init@plt>
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <x_ioctl@plt>
```

assistant: ```c
int v4l2_ioctl(int fd, int id, void *param) {
  init();
  return x_ioctl(fd, id, param);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<v4l2_ioctl>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <init@plt>
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <x_ioctl@plt>
```

assistant: ```c
int v4l2_ioctl(int fd, int id, void *param) {
  init();
  return x_ioctl(fd, id, param);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<exValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L3
  mov    $0xffffffff,%eax
  jmp    L34
L3:
  movl   $0x1,-0x24(%rbp)
  jmp    L28
L39:
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x34(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x24(%rbp)
L28:
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L39
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L39
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
L34:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
type_infered: f64

tool: D27: 1

assistant: ```c
exValue(int x) {
  int termino;
  double factorial = 1, potencia = 1;
  double e = 1.0, eAnt = 0.0;
  if (x < 0) {
    return -1;
  }
  for (termino = 1; (e != eAnt); termino++) {
    eAnt = e;
    factorial *= termino;
    potencia *= x;
    e += (potencia / factorial);
  }
  return e;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exValue>:
  endbr64
  test   %edi,%edi
  js     L7
  movsd  D3(%rip),%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  mov    $0x1,%eax
  pxor   %xmm5,%xmm5
  cvtsi2sd %edi,%xmm5
L10:
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  mulsd  %xmm3,%xmm1
  mulsd  %xmm5,%xmm2
  movapd %xmm0,%xmm3
  movapd %xmm2,%xmm4
  divsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm0
  add    $0x1,%eax
  ucomisd %xmm3,%xmm0
  jp     L10
  jne    L10
  cvttsd2si %xmm0,%eax
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: f64

tool: D3: 1

assistant: ```c
exValue(int x) {
  int termino;
  double factorial = 1, potencia = 1;
  double e = 1.0, eAnt = 0.0;
  if (x < 0) {
    return -1;
  }
  for (termino = 1; (e != eAnt); termino++) {
    eAnt = e;
    factorial *= termino;
    potencia *= x;
    e += (potencia / factorial);
  }
  return e;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<exValue>:
  endbr64
  test   %edi,%edi
  js     L16
  pxor   %xmm5,%xmm5
  movsd  D8(%rip),%xmm0
  mov    $0x1,%eax
  cvtsi2sd %edi,%xmm5
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  nopl   (%rax)
L6:
  mulsd  %xmm5,%xmm2
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  add    $0x1,%eax
  mulsd  %xmm3,%xmm1
  movapd %xmm2,%xmm4
  movapd %xmm0,%xmm3
  divsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm0
  ucomisd %xmm3,%xmm0
  jp     L6
  jne    L6
  cvttsd2si %xmm0,%eax
  ret
L16:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: f64

tool: D8: 1

assistant: ```c
exValue(int x) {
  int termino;
  double factorial = 1, potencia = 1;
  double e = 1.0, eAnt = 0.0;
  if (x < 0) {
    return -1;
  }
  for (termino = 1; (e != eAnt); termino++) {
    eAnt = e;
    factorial *= termino;
    potencia *= x;
    e += (potencia / factorial);
  }
  return e;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exValue>:
  endbr64
  test   %edi,%edi
  js     L3
  pxor   %xmm5,%xmm5
  movsd  D8(%rip),%xmm0
  mov    $0x1,%eax
  cvtsi2sd %edi,%xmm5
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  nopl   (%rax)
L8:
  mulsd  %xmm5,%xmm2
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  add    $0x1,%eax
  mulsd  %xmm3,%xmm1
  movapd %xmm2,%xmm4
  movapd %xmm0,%xmm3
  divsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm0
  ucomisd %xmm3,%xmm0
  jp     L8
  jne    L8
  cvttsd2si %xmm0,%eax
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: f64

tool: D8: 1

assistant: ```c
exValue(int x) {
  int termino;
  double factorial = 1, potencia = 1;
  double e = 1.0, eAnt = 0.0;
  if (x < 0) {
    return -1;
  }
  for (termino = 1; (e != eAnt); termino++) {
    eAnt = e;
    factorial *= termino;
    potencia *= x;
    e += (potencia / factorial);
  }
  return e;
}
```