ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  mov    $0xd,%esi
  mov    $0x7df,%edi
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %rsp,%r12
  call   <day_of_year@plt>
  lea    D49(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    $0x7df,%edi
  call   <day_of_year@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    $0x172,%esi
  mov    $0x7df,%edi
  call   <month_day@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    $0x7bd,%edi
  call   <day_of_year@plt>
  lea    D54(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1f,%edx
  mov    $0xc,%esi
  mov    $0x7df,%edi
  call   <day_of_year@plt>
  lea    D46(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    $0x5a,%esi
  mov    %r13,%rcx
  mov    $0x7df,%edi
  call   <month_day@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D49
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string
name: unpack_data
arguments: data_label: D45
type_guessed: string
name: unpack_data
arguments: data_label: D54
type_guessed: string
name: unpack_data
arguments: data_label: D46
type_guessed: string
name: unpack_data
arguments: data_label: D44
type_guessed: string

tool: D49: 13th month exists? %d


tool: D12: 32nd day exists? %d


tool: D45: 370th yearday exists? day = %d, month = %d


tool: D54: 1st day of 1st month exists? %d


tool: D46: 31st of 12th month exists? %d


tool: D44: 90th day of year exists? day = %d, month = %d


assistant: ```c
int main() {
  int month, day, yearday, ret;
  ret = day_of_year(2015, 13, 1);
  printf("13th month exists? %d\n", ret);
  ret = day_of_year(2015, 1, 32);
  printf("32nd day exists? %d\n", ret);
  month_day(2015, 370, &month, &day);
  printf("370th yearday exists? day = %d, month = %d\n", day, month);
  ret = day_of_year(1981, 1, 1);
  printf("1st day of 1st month exists? %d\n", ret);
  ret = day_of_year(2015, 12, 31);
  printf("31st of 12th month exists? %d\n", ret);
  month_day(2015, 90, &month, &day);
  printf("90th day of year exists? day = %d, month = %d\n", day, month);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  mov    $0xd,%esi
  mov    $0x7df,%edi
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %rsp,%r12
  call   <day_of_year@plt>
  lea    D53(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    $0x7df,%edi
  call   <day_of_year@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    $0x172,%esi
  mov    $0x7df,%edi
  call   <month_day@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    $0x7bd,%edi
  call   <day_of_year@plt>
  lea    D38(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1f,%edx
  mov    $0xc,%esi
  mov    $0x7df,%edi
  call   <day_of_year@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    $0x5a,%esi
  mov    %r13,%rcx
  mov    $0x7df,%edi
  call   <month_day@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D53
type: string
name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D38
type: string
name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D57
type: string

tool: D53: 13th month exists? %d


tool: D7: 32nd day exists? %d


tool: D13: 370th yearday exists? day = %d, month = %d


tool: D38: 1st day of 1st month exists? %d


tool: D27: 31st of 12th month exists? %d


tool: D57: 90th day of year exists? day = %d, month = %d


assistant: ```c
int main() {
  int month, day, yearday, ret;
  ret = day_of_year(2015, 13, 1);
  printf("13th month exists? %d\n", ret);
  ret = day_of_year(2015, 1, 32);
  printf("32nd day exists? %d\n", ret);
  month_day(2015, 370, &month, &day);
  printf("370th yearday exists? day = %d, month = %d\n", day, month);
  ret = day_of_year(1981, 1, 1);
  printf("1st day of 1st month exists? %d\n", ret);
  ret = day_of_year(2015, 12, 31);
  printf("31st of 12th month exists? %d\n", ret);
  month_day(2015, 90, &month, &day);
  printf("90th day of year exists? day = %d, month = %d\n", day, month);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x17b699e4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x17b699e4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x17b699e4,%esi
  mov    %rax,%rdi
  call   <randomize@plt>
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x26f5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <transpose@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L77
L64:
  movl   $0x0,-0x1c(%rbp)
  jmp    L45
L1:
  mov    -0x20(%rbp),%eax
  imul   $0x26f5,%eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  imul   $0x26f5,%eax,%ecx
  mov    -0x20(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x1c(%rbp)
L45:
  cmpl   $0x26f4,-0x1c(%rbp)
  jle    L1
  addl   $0x1,-0x20(%rbp)
L77:
  cmpl   $0x26f4,-0x20(%rbp)
  jle    L64
  mov    -0x10(%rbp),%rax
  mov    $0x17b699e4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x26f5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <effective_transpose@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L43
L49:
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L72:
  mov    -0x18(%rbp),%eax
  imul   $0x26f5,%eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  imul   $0x26f5,%eax,%ecx
  mov    -0x18(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x14(%rbp)
L2:
  cmpl   $0x26f4,-0x14(%rbp)
  jle    L72
  addl   $0x1,-0x18(%rbp)
L43:
  cmpl   $0x26f4,-0x18(%rbp)
  jle    L49
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void test(void) {
  int *d = (int *)malloc((sizeof(int) * 9973 * 9973));
  int *s = (int *)malloc((sizeof(int) * 9973 * 9973));
  randomize((void *)s, (sizeof(int) * 9973 * 9973));
  transpose(d, s, 9973);
  for (int i = 0; i < 9973; i++)
    for (int j = 0; j < 9973; j++)
      assert(s[i * 9973 + j] == d[j * 9973 + i]);
  memset(d, 0, (sizeof(int) * 9973 * 9973));
  effective_transpose(d, s, 9973);
  for (int i = 0; i < 9973; i++)
    for (int j = 0; j < 9973; j++)
      assert(s[i * 9973 + j] == d[j * 9973 + i]);
  free((void *)d);
  free((void *)s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    $0x17b699e4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,0x10(%rsp)
  mov    $0x17b699e4,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %rax,0x18(%rsp)
  mov    $0x17b699e4,%esi
  mov    %rax,%rdi
  call   <randomize@plt>
  mov    $0x26f5,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <transpose@plt>
  mov    %r15,0x8(%rsp)
  lea    0x17b699e4(%rbx),%r12
  mov    %r12,%r13
  mov    $0x0,%r14d
L30:
  lea    -0x17b699e4(%r13),%rbx
  mov    %r15,%rbp
L10:
  mov    (%rbx),%eax
  cmp    %eax,0x0(%rbp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbp
  add    $0x9bd4,%rbx
  cmp    %r13,%rbx
  jne    L10
  add    $0x1,%r14d
  add    $0x9bd4,%r15
  add    $0x4,%r13
  cmp    $0x26f5,%r14d
  jne    L30
  mov    $0x17b699e4,%edx
  mov    $0x0,%esi
  mov    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x26f5,%edx
  mov    0x18(%rsp),%rsi
  mov    %rbx,%rdi
  call   <effective_transpose@plt>
  mov    $0x0,%r13d
L38:
  lea    -0x17b699e4(%r12),%rbx
  mov    0x8(%rsp),%rbp
L22:
  mov    (%rbx),%eax
  cmp    %eax,0x0(%rbp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbp
  add    $0x9bd4,%rbx
  cmp    %r12,%rbx
  jne    L22
  add    $0x1,%r13d
  addq   $0x9bd4,0x8(%rsp)
  add    $0x4,%r12
  cmp    $0x26f5,%r13d
  jne    L38
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void test(void) {
  int *d = (int *)malloc((sizeof(int) * 9973 * 9973));
  int *s = (int *)malloc((sizeof(int) * 9973 * 9973));
  randomize((void *)s, (sizeof(int) * 9973 * 9973));
  transpose(d, s, 9973);
  for (int i = 0; i < 9973; i++)
    for (int j = 0; j < 9973; j++)
      assert(s[i * 9973 + j] == d[j * 9973 + i]);
  memset(d, 0, (sizeof(int) * 9973 * 9973));
  effective_transpose(d, s, 9973);
  for (int i = 0; i < 9973; i++)
    for (int j = 0; j < 9973; j++)
      assert(s[i * 9973 + j] == d[j * 9973 + i]);
  free((void *)d);
  free((void *)s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %r15
  mov    $0x17b699e4,%edi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <malloc@plt>
  mov    $0x17b699e4,%edi
  mov    %rax,%rbx
  mov    %rax,0x10(%rsp)
  call   <malloc@plt>
  mov    $0x17b699e4,%esi
  mov    %rax,%r14
  mov    %rax,%rdi
  mov    %rax,0x18(%rsp)
  call   <randomize@plt>
  mov    %rbx,%rdi
  mov    $0x26f5,%edx
  mov    %r14,%rsi
  call   <transpose@plt>
  mov    %r14,0x8(%rsp)
  add    $0x17b699e4,%rbx
  mov    %rbx,%rbp
L5:
  lea    -0x17b699e4(%rbp),%r12
  mov    %r14,%r15
  nop
L4:
  mov    (%r12),%eax
  xor    %edi,%edi
  cmp    %eax,(%r15)
  sete   %dil
  add    $0x9bd4,%r12
  add    $0x4,%r15
  call   <assert@plt>
  cmp    %r12,%rbp
  jne    L4
  add    $0x1,%r13d
  add    $0x9bd4,%r14
  add    $0x4,%rbp
  cmp    $0x26f5,%r13d
  jne    L5
  mov    0x10(%rsp),%r15
  mov    $0x17b699e4,%edx
  xor    %esi,%esi
  xor    %r13d,%r13d
  mov    %r15,%rdi
  call   <memset@plt>
  mov    0x18(%rsp),%rsi
  mov    $0x26f5,%edx
  mov    %r15,%rdi
  call   <effective_transpose@plt>
L9:
  mov    0x8(%rsp),%r14
  lea    -0x17b699e4(%rbx),%rbp
  nop
L31:
  mov    0x0(%rbp),%eax
  xor    %edi,%edi
  cmp    %eax,(%r14)
  sete   %dil
  add    $0x9bd4,%rbp
  add    $0x4,%r14
  call   <assert@plt>
  cmp    %rbp,%rbx
  jne    L31
  add    $0x1,%r13d
  add    $0x4,%rbx
  addq   $0x9bd4,0x8(%rsp)
  cmp    $0x26f5,%r13d
  jne    L9
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rdi
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <free@plt>
```

assistant: ```c
void test(void) {
  int *d = (int *)malloc((sizeof(int) * 9973 * 9973));
  int *s = (int *)malloc((sizeof(int) * 9973 * 9973));
  randomize((void *)s, (sizeof(int) * 9973 * 9973));
  transpose(d, s, 9973);
  for (int i = 0; i < 9973; i++)
    for (int j = 0; j < 9973; j++)
      assert(s[i * 9973 + j] == d[j * 9973 + i]);
  memset(d, 0, (sizeof(int) * 9973 * 9973));
  effective_transpose(d, s, 9973);
  for (int i = 0; i < 9973; i++)
    for (int j = 0; j < 9973; j++)
      assert(s[i * 9973 + j] == d[j * 9973 + i]);
  free((void *)d);
  free((void *)s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %r15
  mov    $0x17b699e4,%edi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <malloc@plt>
  mov    $0x17b699e4,%edi
  mov    %rax,%rbx
  mov    %rax,0x10(%rsp)
  call   <malloc@plt>
  mov    $0x17b699e4,%esi
  mov    %rax,%r14
  mov    %rax,%rdi
  mov    %rax,0x18(%rsp)
  call   <randomize@plt>
  mov    %rbx,%rdi
  mov    $0x26f5,%edx
  mov    %r14,%rsi
  call   <transpose@plt>
  mov    %r14,0x8(%rsp)
  add    $0x17b699e4,%rbx
  mov    %rbx,%rbp
L30:
  lea    -0x17b699e4(%rbp),%r12
  mov    %r14,%r15
  nop
L19:
  mov    (%r12),%eax
  xor    %edi,%edi
  cmp    %eax,(%r15)
  sete   %dil
  add    $0x9bd4,%r12
  add    $0x4,%r15
  call   <assert@plt>
  cmp    %r12,%rbp
  jne    L19
  add    $0x1,%r13d
  add    $0x9bd4,%r14
  add    $0x4,%rbp
  cmp    $0x26f5,%r13d
  jne    L30
  mov    0x10(%rsp),%r15
  mov    $0x17b699e4,%edx
  xor    %esi,%esi
  xor    %r13d,%r13d
  mov    %r15,%rdi
  call   <memset@plt>
  mov    0x18(%rsp),%rsi
  mov    $0x26f5,%edx
  mov    %r15,%rdi
  call   <effective_transpose@plt>
L7:
  mov    0x8(%rsp),%r14
  lea    -0x17b699e4(%rbx),%rbp
  nop
L0:
  mov    0x0(%rbp),%eax
  xor    %edi,%edi
  cmp    %eax,(%r14)
  sete   %dil
  add    $0x9bd4,%rbp
  add    $0x4,%r14
  call   <assert@plt>
  cmp    %rbp,%rbx
  jne    L0
  add    $0x1,%r13d
  add    $0x4,%rbx
  addq   $0x9bd4,0x8(%rsp)
  cmp    $0x26f5,%r13d
  jne    L7
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rdi
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <free@plt>
```

assistant: ```c
void test(void) {
  int *d = (int *)malloc((sizeof(int) * 9973 * 9973));
  int *s = (int *)malloc((sizeof(int) * 9973 * 9973));
  randomize((void *)s, (sizeof(int) * 9973 * 9973));
  transpose(d, s, 9973);
  for (int i = 0; i < 9973; i++)
    for (int j = 0; j < 9973; j++)
      assert(s[i * 9973 + j] == d[j * 9973 + i]);
  memset(d, 0, (sizeof(int) * 9973 * 9973));
  effective_transpose(d, s, 9973);
  for (int i = 0; i < 9973; i++)
    for (int j = 0; j < 9973; j++)
      assert(s[i * 9973 + j] == d[j * 9973 + i]);
  free((void *)d);
  free((void *)s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<leftTrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L18:
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <xStrDup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L6:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *leftTrim(char *str) {
  char *t;
  int i = 0;
  while (isspace(str[i]))
    i++;
  t = xStrDup(&str[i]);
  strcpy(str, t);
  if (t) {
    free(t);
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<leftTrim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdi,%rbx
L18:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L18
  mov    %rbp,%rdi
  call   <xStrDup@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %rbx,%rbx
  je     L6
  mov    %rbx,%rdi
  call   <free@plt>
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *leftTrim(char *str) {
  char *t;
  int i = 0;
  while (isspace(str[i]))
    i++;
  t = xStrDup(&str[i]);
  strcpy(str, t);
  if (t) {
    free(t);
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<leftTrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L8:
  movsbl (%rbx),%edi
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbp,%rdi
  call   <xStrDup@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <strcpy@plt>
  test   %rbp,%rbp
  je     L1
  mov    %rbp,%rdi
  call   <free@plt>
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *leftTrim(char *str) {
  char *t;
  int i = 0;
  while (isspace(str[i]))
    i++;
  t = xStrDup(&str[i]);
  strcpy(str, t);
  if (t) {
    free(t);
  }
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<leftTrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  movsbl (%rbx),%edi
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  mov    %rbp,%rdi
  call   <xStrDup@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <strcpy@plt>
  test   %rbp,%rbp
  je     L16
  mov    %rbp,%rdi
  call   <free@plt>
L16:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *leftTrim(char *str) {
  char *t;
  int i = 0;
  while (isspace(str[i]))
    i++;
  t = xStrDup(&str[i]);
  strcpy(str, t);
  if (t) {
    free(t);
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <times@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <times@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main() {
  struct tms tms;
  times(&tms);
  times((struct tms *)-1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <times@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <times@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct tms tms;
  times(&tms);
  times((struct tms *)-1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <times@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <times@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct tms tms;
  times(&tms);
  times((struct tms *)-1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <times@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <times@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct tms tms;
  times(&tms);
  times((struct tms *)-1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoaBuffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L16
  mov    -0x40(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  movb   $0x2d,(%rax)
  negl   -0x34(%rbp)
  jmp    L16
L7:
  mov    -0x34(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %dl,-0x25(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  movzbl -0x25(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
L16:
  cmpl   $0x0,-0x34(%rbp)
  jne    L7
  cmpl   $0x0,-0x24(%rbp)
  jne    L44
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  movb   $0x30,-0x20(%rbp,%rax,1)
  jmp    L44
L34:
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x40(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x40(%rbp)
L44:
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L34
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

assistant: ```c
char *itoaBuffer(int value, char *buf) {
  char num[20];
  int pos;
  pos = 0;
  if (value < 0) {
    *buf++ = '-';
    value = -value;
  }
  while (value != 0) {
    char c = value % 10;
    value = value / 10;
    num[pos++] = c + '0';
  }
  if (pos == 0)
    num[pos++] = '0';
  while (--pos >= 0) {
    *buf = num[pos];
    buf++;
  }
  *buf = 0;
  return buf;
}
```