ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<setMinMax>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <setMax@plt>
  mov    %ebp,%esi
  pop    %rbp
  mov    %eax,%edi
  jmp    1070 <setMin@plt>
```

assistant: ```c
unsigned int setMinMax(unsigned int e, int i, int j) {
  e = setMax(e, i);
  e = setMin(e, j);
  return e;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<equal_ValueOrPossibility_XY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    $0x2,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L57
  movl   $0x1,-0xc(%rbp)
  jmp    L44
L20:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  and    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L44:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L20
  jmp    L23
L57:
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L30:
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  and    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L30
L23:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int equal_ValueOrPossibility_XY(int X, int value, int pos[]) {
  int i, ret = 1, start = 2 - X;
  if (value < 0)
    for (i = 1; i < pos[0]; i++)
      ret &= (pos[start] == pos[start + 2 * i]);
  else
    for (i = 0; i < pos[0]; i++)
      ret &= (value != pos[start + 2 * i]);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<equal_ValueOrPossibility_XY>:
  endbr64
  mov    %rdx,%rcx
  mov    $0x2,%eax
  sub    %edi,%eax
  test   %esi,%esi
  js     L26
  mov    (%rdx),%edi
  mov    $0x1,%edx
  test   %edi,%edi
  jle    L16
  movslq %eax,%rdx
  lea    (%rcx,%rdx,4),%rax
  lea    -0x1(%rdi),%edi
  lea    (%rdx,%rdi,2),%rdx
  lea    0x8(%rcx,%rdx,4),%rdi
  mov    $0x1,%edx
L13:
  cmp    %esi,(%rax)
  setne  %cl
  movzbl %cl,%ecx
  and    %ecx,%edx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L13
L16:
  mov    %edx,%eax
  ret
L26:
  mov    (%rdx),%esi
  cmp    $0x1,%esi
  jle    L28
  movslq %eax,%rdx
  lea    (%rcx,%rdx,4),%rax
  mov    (%rax),%edi
  lea    -0x2(%rsi),%esi
  lea    (%rdx,%rsi,2),%rdx
  lea    0x8(%rcx,%rdx,4),%rsi
  mov    $0x1,%edx
L54:
  cmp    %edi,0x8(%rax)
  sete   %cl
  movzbl %cl,%ecx
  and    %ecx,%edx
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L54
  jmp    L16
L28:
  mov    $0x1,%edx
  jmp    L16
```

assistant: ```c
int equal_ValueOrPossibility_XY(int X, int value, int pos[]) {
  int i, ret = 1, start = 2 - X;
  if (value < 0)
    for (i = 1; i < pos[0]; i++)
      ret &= (pos[start] == pos[start + 2 * i]);
  else
    for (i = 0; i < pos[0]; i++)
      ret &= (value != pos[start + 2 * i]);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<equal_ValueOrPossibility_XY>:
  endbr64
  mov    $0x2,%eax
  mov    %rdx,%rcx
  sub    %edi,%eax
  mov    (%rdx),%edi
  test   %esi,%esi
  js     L10
  test   %edi,%edi
  jle    L27
  movslq %eax,%rdx
  sub    $0x1,%edi
  mov    $0x1,%r8d
  lea    (%rcx,%rdx,4),%rax
  lea    (%rdx,%rdi,2),%rdx
  lea    0x8(%rcx,%rdx,4),%rcx
  nopl   0x0(%rax)
L18:
  xor    %edx,%edx
  cmp    %esi,(%rax)
  setne  %dl
  add    $0x8,%rax
  and    %edx,%r8d
  cmp    %rcx,%rax
  jne    L18
  mov    %r8d,%eax
  ret
  nop
L10:
  cmp    $0x1,%edi
  jle    L27
  movslq %eax,%rdx
  sub    $0x2,%edi
  mov    $0x1,%r8d
  lea    (%rcx,%rdx,4),%rax
  lea    (%rdx,%rdi,2),%rdx
  mov    (%rax),%esi
  lea    0x8(%rcx,%rdx,4),%rcx
L28:
  xor    %edx,%edx
  cmp    %esi,0x8(%rax)
  sete   %dl
  add    $0x8,%rax
  and    %edx,%r8d
  cmp    %rax,%rcx
  jne    L28
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int equal_ValueOrPossibility_XY(int X, int value, int pos[]) {
  int i, ret = 1, start = 2 - X;
  if (value < 0)
    for (i = 1; i < pos[0]; i++)
      ret &= (pos[start] == pos[start + 2 * i]);
  else
    for (i = 0; i < pos[0]; i++)
      ret &= (value != pos[start + 2 * i]);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quatf_from_mat4f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat3f_from_mat4f@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <quatf_from_mat3f@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void quatf_from_mat4f(float quat[4], const float matrix[16]) {
  float tmpMat[9];
  mat3f_from_mat4f(tmpMat, matrix);
  quatf_from_mat3f(quat, tmpMat);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quatf_from_mat4f>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <mat3f_from_mat4f@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <quatf_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void quatf_from_mat4f(float quat[4], const float matrix[16]) {
  float tmpMat[9];
  mat3f_from_mat4f(tmpMat, matrix);
  quatf_from_mat3f(quat, tmpMat);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quatf_from_mat4f>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <mat3f_from_mat4f@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <quatf_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void quatf_from_mat4f(float quat[4], const float matrix[16]) {
  float tmpMat[9];
  mat3f_from_mat4f(tmpMat, matrix);
  quatf_from_mat3f(quat, tmpMat);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quatf_from_mat4f>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <mat3f_from_mat4f@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <quatf_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void quatf_from_mat4f(float quat[4], const float matrix[16]) {
  float tmpMat[9];
  mat3f_from_mat4f(tmpMat, matrix);
  quatf_from_mat3f(quat, tmpMat);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_palindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <len@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L5
L33:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L42
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L5
  mov    $0x0,%eax
  jmp    L14
L42:
  mov    $0x1,%eax
  jmp    L14
L5:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L33
L14:
  leave
  ret
```

assistant: ```c
int is_palindrome(char a[]) {
  int i = 0, b, l, k = 1;
  l = len(a);
  b = l / 2;
  while (i < b) {
    if (a[i] == a[l - k]) {
      i++;
      k++;
      if (i == b) {
        return 0;
      }
    } else
      return 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<is_palindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <len@plt>
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x1(%rsi),%edi
  mov    $0x0,%eax
L40:
  cmp    %eax,%esi
  jle    L2
  movzbl (%rdx),%ecx
  cmp    %cl,(%rbx,%rax,1)
  jne    L43
  lea    0x1(%rax),%rcx
  sub    $0x1,%rdx
  cmp    %rdi,%rax
  je     L29
  mov    %rcx,%rax
  jmp    L40
L43:
  mov    $0x1,%eax
L2:
  pop    %rbx
  ret
L29:
  mov    $0x0,%eax
  jmp    L2
```

assistant: ```c
int is_palindrome(char a[]) {
  int i = 0, b, l, k = 1;
  l = len(a);
  b = l / 2;
  while (i < b) {
    if (a[i] == a[l - k]) {
      i++;
      k++;
      if (i == b) {
        return 0;
      }
    } else
      return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_palindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <len@plt>
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  cltq
  sar    %esi
  lea    -0x1(%rbx,%rax,1),%rdx
  xor    %eax,%eax
  lea    -0x1(%rsi),%edi
  jmp    L31
  nopl   0x0(%rax)
L20:
  movzbl (%rdx),%ecx
  cmp    %cl,(%rbx,%rax,1)
  jne    L29
  lea    0x1(%rax),%rcx
  sub    $0x1,%rdx
  cmp    %rdi,%rax
  je     L7
  mov    %rcx,%rax
L31:
  cmp    %eax,%esi
  jg     L20
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_palindrome(char a[]) {
  int i = 0, b, l, k = 1;
  l = len(a);
  b = l / 2;
  while (i < b) {
    if (a[i] == a[l - k]) {
      i++;
      k++;
      if (i == b) {
        return 0;
      }
    } else
      return 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_palindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <len@plt>
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  cltq
  sar    %esi
  lea    -0x1(%rbx,%rax,1),%rdx
  xor    %eax,%eax
  lea    -0x1(%rsi),%edi
  jmp    L21
  nopl   0x0(%rax)
L29:
  movzbl (%rdx),%ecx
  cmp    %cl,(%rbx,%rax,1)
  jne    L12
  lea    0x1(%rax),%rcx
  sub    $0x1,%rdx
  cmp    %rdi,%rax
  je     L20
  mov    %rcx,%rax
L21:
  cmp    %eax,%esi
  jg     L29
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_palindrome(char a[]) {
  int i = 0, b, l, k = 1;
  l = len(a);
  b = l / 2;
  while (i < b) {
    if (a[i] == a[l - k]) {
      i++;
      k++;
      if (i == b) {
        return 0;
      }
    } else
      return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <countEverything@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D19
data_type: string
name: extract_symbolic_data
arguments: label: D33
data_type: string

tool: D28: ENTER FILE NAME : 

tool: D13: %s

tool: D19: FILE NAME: %s 


tool: D33: r

assistant: ```c
int main(int argc, char **argv) {
  FILE *f;
  char ch;
  char *fileName;
  int character = 0, line = 0, word = 0;
  printf("ENTER FILE NAME : ");
  scanf("%s", fileName);
  printf("FILE NAME: %s \n", fileName);
  f = fopen(fileName, "r");
  countEverything(f);
  fclose(f);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D38(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <countEverything@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
datatype: string
name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string
name: disassemble_data
arguments: data_tag: D38
datatype: string

tool: D28: ENTER FILE NAME : 

tool: D5: %s

tool: D4: FILE NAME: %s 


tool: D38: r

assistant: ```c
int main(int argc, char **argv) {
  FILE *f;
  char ch;
  char *fileName;
  int character = 0, line = 0, word = 0;
  printf("ENTER FILE NAME : ");
  scanf("%s", fileName);
  printf("FILE NAME: %s \n", fileName);
  f = fopen(fileName, "r");
  countEverything(f);
  fclose(f);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D31(%rip),%rdi
  xor    %ebp,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <countEverything@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D37
type_infered: string
name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D26
type_infered: string

tool: D31: ENTER FILE NAME : 

tool: D37: %s

tool: D12: FILE NAME: %s 


tool: D26: r

assistant: ```c
int main(int argc, char **argv) {
  FILE *f;
  char ch;
  char *fileName;
  int character = 0, line = 0, word = 0;
  printf("ENTER FILE NAME : ");
  scanf("%s", fileName);
  printf("FILE NAME: %s \n", fileName);
  f = fopen(fileName, "r");
  countEverything(f);
  fclose(f);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  xor    %ebp,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D36(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <countEverything@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D24
datatype: string
name: retrieve_data
arguments: label: D36
datatype: string

tool: D16: ENTER FILE NAME : 

tool: D28: %s

tool: D24: FILE NAME: %s 


tool: D36: r

assistant: ```c
int main(int argc, char **argv) {
  FILE *f;
  char ch;
  char *fileName;
  int character = 0, line = 0, word = 0;
  printf("ENTER FILE NAME : ");
  scanf("%s", fileName);
  printf("FILE NAME: %s \n", fileName);
  f = fopen(fileName, "r");
  countEverything(f);
  fclose(f);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<substrn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *substrn(const char *key, int from, int len) {
  char *res = malloc((len + 1) * sizeof(char));
  strncpy(res, &key[from], len);
  res[len] = '\0';
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<substrn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  lea    0x1(%rdx),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movslq %r13d,%r13
  lea    (%r12,%r13,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substrn(const char *key, int from, int len) {
  char *res = malloc((len + 1) * sizeof(char));
  strncpy(res, &key[from], len);
  res[len] = '\0';
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<substrn>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x1(%rbx),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substrn(const char *key, int from, int len) {
  char *res = malloc((len + 1) * sizeof(char));
  strncpy(res, &key[from], len);
  res[len] = '\0';
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<VolumeAveragedVOFCoefficientsEvaluate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x20(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x28(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L5
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void VolumeAveragedVOFCoefficientsEvaluate(int nPoints, int nSpace, double eps, double *v, double *phi, double *porosity, double *u, double *m, double *dm, double *f, double *df) {
  int i, I;
  for (i = 0; i < nPoints; i++) {
    m[i] = u[i] * porosity[i];
    dm[i] = porosity[i];
    for (I = 0; I < nSpace; I++) {
      f[i * nSpace + I] = porosity[i] * v[i * nSpace + I] * u[i];
      df[i * nSpace + I] = porosity[i] * v[i * nSpace + I];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<VolumeAveragedVOFCoefficientsEvaluate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r14
  mov    0x40(%rsp),%r15
  mov    0x48(%rsp),%r10
  mov    0x50(%rsp),%r11
  test   %edi,%edi
  jle    L39
  mov    %esi,%r12d
  mov    %rdx,%rcx
  mov    %r9,%rbx
  mov    %edi,%r13d
  mov    $0x0,%ebp
  mov    $0x0,%r9d
  mov    %esi,%eax
  mov    %rax,-0x8(%rsp)
L2:
  mov    %rbx,%rdi
  mov    %r8,%rdx
  movsd  (%rbx),%xmm0
  mulsd  (%r8),%xmm0
  movsd  %xmm0,(%r14,%r9,8)
  movsd  (%r8),%xmm0
  movsd  %xmm0,(%r15,%r9,8)
  test   %r12d,%r12d
  jle    L38
  movslq %ebp,%rsi
  lea    0x0(,%rsi,8),%rax
  add    -0x8(%rsp),%rsi
  shl    $0x3,%rsi
L21:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx,%rax,1),%xmm0
  mulsd  (%rdi),%xmm0
  movsd  %xmm0,(%r10,%rax,1)
  movsd  (%rdx),%xmm0
  mulsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%r11,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L21
L38:
  add    $0x1,%r9
  add    $0x8,%rbx
  add    $0x8,%r8
  add    %r12d,%ebp
  cmp    %r13,%r9
  jne    L2
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void VolumeAveragedVOFCoefficientsEvaluate(int nPoints, int nSpace, double eps, double *v, double *phi, double *porosity, double *u, double *m, double *dm, double *f, double *df) {
  int i, I;
  for (i = 0; i < nPoints; i++) {
    m[i] = u[i] * porosity[i];
    dm[i] = porosity[i];
    for (I = 0; I < nSpace; I++) {
      f[i * nSpace + I] = porosity[i] * v[i * nSpace + I] * u[i];
      df[i * nSpace + I] = porosity[i] * v[i * nSpace + I];
    }
  }
}
```