ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L56
  mov    $0x0,%eax
  call   <show_presentation@plt>
  mov    $0x0,%eax
  jmp    L50
L56:
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L25
  mov    $0x0,%eax
  call   <show_presentation@plt>
  mov    $0x0,%eax
  jmp    L50
L25:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <run_command@plt>
L50:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: --help

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    show_presentation();
    return 0;
  }
  int i;
  for (i = 1; i < argc; i++) {
    if (!strcmp("--help", argv[i])) {
      show_presentation();
      return 0;
    }
  }
  return run_command(argc, argv);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L42
  mov    %edi,%r14d
  mov    %rsi,%r15
  lea    0x8(%rsi),%rbp
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r13
  lea    D7(%rip),%r12
L14:
  mov    0x0(%rbp),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L45
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L14
  mov    %r15,%rsi
  mov    %r14d,%edi
  call   <run_command@plt>
  mov    %eax,%ebx
L5:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  mov    $0x0,%eax
  call   <show_presentation@plt>
  mov    $0x0,%ebx
  jmp    L5
L45:
  mov    $0x0,%eax
  call   <show_presentation@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: --help

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    show_presentation();
    return 0;
  }
  int i;
  for (i = 1; i < argc; i++) {
    if (!strcmp("--help", argv[i])) {
      show_presentation();
      return 0;
    }
  }
  return run_command(argc, argv);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L0
  lea    -0x2(%rdi),%eax
  mov    %edi,%r13d
  lea    0x8(%rsi),%rbx
  mov    %rsi,%r14
  lea    0x10(%rsi,%rax,8),%r12
  lea    D0(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L0
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  mov    %r14,%rsi
  pop    %rbp
  mov    %r13d,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <run_command@plt>
L0:
  xor    %eax,%eax
  call   <show_presentation@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: --help

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    show_presentation();
    return 0;
  }
  int i;
  for (i = 1; i < argc; i++) {
    if (!strcmp("--help", argv[i])) {
      show_presentation();
      return 0;
    }
  }
  return run_command(argc, argv);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L17
  lea    -0x2(%rdi),%eax
  mov    %edi,%r13d
  lea    0x8(%rsi),%rbx
  mov    %rsi,%r14
  lea    0x10(%rsi,%rax,8),%r12
  lea    D7(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L17
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L26
  pop    %rbx
  mov    %r14,%rsi
  pop    %rbp
  mov    %r13d,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <run_command@plt>
L17:
  xor    %eax,%eax
  call   <show_presentation@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string

tool: D7: --help

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    show_presentation();
    return 0;
  }
  int i;
  for (i = 1; i < argc; i++) {
    if (!strcmp("--help", argv[i])) {
      show_presentation();
      return 0;
    }
  }
  return run_command(argc, argv);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SzFreeTemp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void SzFreeTemp(void *p, void *address) {
  p = p;
  free(address);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SzFreeTemp>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void SzFreeTemp(void *p, void *address) {
  p = p;
  free(address);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SzFreeTemp>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <free@plt>
```

assistant: ```c
void SzFreeTemp(void *p, void *address) {
  p = p;
  free(address);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SzFreeTemp>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <free@plt>
```

assistant: ```c
void SzFreeTemp(void *p, void *address) {
  p = p;
  free(address);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<handle_winch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%eax
  call   <clear@plt>
  mov    $0x0,%eax
  call   <init_clr@plt>
  nop
  leave
  ret
```

assistant: ```c
void handle_winch(int sig) {
  endwin();
  refresh();
  clear();
  init_clr();
}
```
user: Translate the below assembly code into C programming language:

```asm
<handle_winch>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%eax
  call   <clear@plt>
  mov    $0x0,%eax
  call   <init_clr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void handle_winch(int sig) {
  endwin();
  refresh();
  clear();
  init_clr();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<handle_winch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %eax,%eax
  call   <clear@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <init_clr@plt>
```

assistant: ```c
void handle_winch(int sig) {
  endwin();
  refresh();
  clear();
  init_clr();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<handle_winch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %eax,%eax
  call   <clear@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <init_clr@plt>
```

assistant: ```c
void handle_winch(int sig) {
  endwin();
  refresh();
  clear();
  init_clr();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<string_hash_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L3:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L3
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long string_hash_func(const char *str, size_t len) {
  unsigned long hash = 0;
  for (size_t i = 0; i != len; ++i)
    hash = hash * 31 + str[i];
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_hash_func>:
  endbr64
  test   %rsi,%rsi
  je     L3
  mov    %rdi,%rdx
  add    %rsi,%rdi
  mov    $0x0,%eax
L6:
  mov    %rax,%rcx
  shl    $0x5,%rcx
  sub    %rax,%rcx
  movsbq (%rdx),%rax
  add    %rcx,%rax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L6
  ret
L3:
  mov    %rsi,%rax
  ret
```

assistant: ```c
unsigned long string_hash_func(const char *str, size_t len) {
  unsigned long hash = 0;
  for (size_t i = 0; i != len; ++i)
    hash = hash * 31 + str[i];
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<string_hash_func>:
  endbr64
  test   %rsi,%rsi
  je     L16
  add    %rdi,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L6:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  sub    %rax,%rdx
  movsbq -0x1(%rdi),%rax
  add    %rdx,%rax
  cmp    %rsi,%rdi
  jne    L6
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long string_hash_func(const char *str, size_t len) {
  unsigned long hash = 0;
  for (size_t i = 0; i != len; ++i)
    hash = hash * 31 + str[i];
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_hash_func>:
  endbr64
  test   %rsi,%rsi
  je     L14
  add    %rdi,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L1:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  sub    %rax,%rdx
  movsbq -0x1(%rdi),%rax
  add    %rdx,%rax
  cmp    %rdi,%rsi
  jne    L1
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long string_hash_func(const char *str, size_t len) {
  unsigned long hash = 0;
  for (size_t i = 0; i != len; ++i)
    hash = hash * 31 + str[i];
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encodeutf8>:
  endbr64
  cmp    $0x7fffffff,%rdi
  ja     L62
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  cmp    $0x7f,%rdi
  jbe    L110
  cmp    $0x7ff,%rdi
  jbe    L36
  cmp    $0xffff,%rdi
  jbe    L35
  cmp    $0x1fffff,%rdi
  jbe    L49
  cmp    $0x3ffffff,%rdi
  seta   %r12b
  movzbl %r12b,%r12d
  add    $0x4,%r12d
L6:
  mov    $0x1,%edi
  call   <assert@plt>
  movslq %r12d,%r12
  shl    $0x4,%r12
  lea    D8(%rip),%rax
  mov    (%rax,%r12,1),%eax
  movslq %eax,%rcx
  cmp    %r13,%rcx
  ja     L116
  cmp    $0x1,%eax
  je     L100
  lea    -0x1(%rax),%edx
  test   %edx,%edx
  jle    L125
  movslq %edx,%rdx
  add    %rbp,%rdx
  lea    -0x2(%rbp,%rcx,1),%rdi
  lea    -0x2(%rax),%ecx
  sub    %rcx,%rdi
L38:
  mov    %ebx,%esi
  and    $0x3f,%esi
  or     $0xffffff80,%esi
  mov    %sil,(%rdx)
  shr    $0x6,%rbx
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L38
L125:
  mov    $0xff,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  not    %edx
  or     %ebx,%edx
  mov    %dl,0x0(%rbp)
L122:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L110:
  mov    $0x0,%r12d
  jmp    L6
L36:
  mov    $0x1,%r12d
  jmp    L6
L35:
  mov    $0x2,%r12d
  jmp    L6
L49:
  mov    $0x3,%r12d
  jmp    L6
L100:
  mov    %bl,0x0(%rbp)
  jmp    L122
L62:
  mov    $0xffffffff,%eax
  ret
L116:
  mov    $0xffffffff,%eax
  jmp    L122
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: 

assistant: ```c
int encodeutf8(unsigned long u, unsigned char *buf, size_t maxbytes) {
  static const struct {
    int nbytes;
    unsigned long max;
  } tab[] = {
      {1, 0x0000007F}, {2, 0x000007FF}, {3, 0x0000FFFF}, {4, 0x001FFFFF}, {5, 0x03FFFFFF}, {6, 0x7FFFFFFF},
  };
  static const int ntab = sizeof(tab) / sizeof(tab[0]);
  int i, j;
  if (u > tab[ntab - 1].max)
    return -1;
  for (i = 0; i < ntab; ++i) {
    if (u <= tab[i].max)
      break;
  }
  assert(i < ntab);
  if (tab[i].nbytes > maxbytes)
    return -1;
  if (tab[i].nbytes == 1) {
    buf[0] = u;
  } else {
    for (j = tab[i].nbytes - 1; j > 0; --j) {
      buf[j] = 0x80 | (u & 0x3f);
      u >>= 6;
    }
    unsigned char mask = ~(0xFF >> tab[i].nbytes);
    buf[0] = mask | u;
  }
  return tab[i].nbytes;
}
```
user: What is the c source code of the assembly code below:

```asm
<encodeutf8>:
  endbr64
  cmp    $0x7fffffff,%rdi
  ja     L8
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x7f,%rdi
  jbe    L42
  cmp    $0x7ff,%rdi
  jbe    L6
  cmp    $0xffff,%rdi
  jbe    L23
  cmp    $0x1fffff,%rdi
  jbe    L94
  xor    %ebp,%ebp
  cmp    $0x3ffffff,%rdi
  seta   %bpl
  add    $0x4,%ebp
L30:
  mov    $0x1,%edi
  movslq %ebp,%rbp
  call   <assert@plt>
  shl    $0x4,%rbp
  lea    D1(%rip),%rax
  movslq (%rax,%rbp,1),%rcx
  mov    %rcx,%rax
  cmp    %r13,%rcx
  ja     L119
  cmp    $0x1,%ecx
  je     L97
  lea    -0x1(%rcx),%edx
  test   %edx,%edx
  jle    L29
  lea    -0x2(%r12,%rcx,1),%rdi
  movslq %edx,%rdx
  lea    -0x2(%rcx),%ecx
  add    %r12,%rdx
  sub    %rcx,%rdi
  nopw   0x0(%rax,%rax,1)
L100:
  mov    %ebx,%esi
  sub    $0x1,%rdx
  shr    $0x6,%rbx
  and    $0x3f,%esi
  or     $0xffffff80,%esi
  mov    %sil,0x1(%rdx)
  cmp    %rdx,%rdi
  jne    L100
L29:
  mov    $0xff,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  not    %edx
  or     %ebx,%edx
  mov    %dl,(%r12)
L108:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L97:
  mov    %bl,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  xor    %ebp,%ebp
  jmp    L30
L6:
  mov    $0x1,%ebp
  jmp    L30
L23:
  mov    $0x2,%ebp
  jmp    L30
L94:
  mov    $0x3,%ebp
  jmp    L30
L119:
  mov    $0xffffffff,%eax
  jmp    L108
L8:
  or     $0xffffffff,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: 

assistant: ```c
int encodeutf8(unsigned long u, unsigned char *buf, size_t maxbytes) {
  static const struct {
    int nbytes;
    unsigned long max;
  } tab[] = {
      {1, 0x0000007F}, {2, 0x000007FF}, {3, 0x0000FFFF}, {4, 0x001FFFFF}, {5, 0x03FFFFFF}, {6, 0x7FFFFFFF},
  };
  static const int ntab = sizeof(tab) / sizeof(tab[0]);
  int i, j;
  if (u > tab[ntab - 1].max)
    return -1;
  for (i = 0; i < ntab; ++i) {
    if (u <= tab[i].max)
      break;
  }
  assert(i < ntab);
  if (tab[i].nbytes > maxbytes)
    return -1;
  if (tab[i].nbytes == 1) {
    buf[0] = u;
  } else {
    for (j = tab[i].nbytes - 1; j > 0; --j) {
      buf[j] = 0x80 | (u & 0x3f);
      u >>= 6;
    }
    unsigned char mask = ~(0xFF >> tab[i].nbytes);
    buf[0] = mask | u;
  }
  return tab[i].nbytes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<encodeutf8>:
  endbr64
  cmp    $0x7fffffff,%rdi
  ja     L97
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x7f,%rdi
  jbe    L134
  cmp    $0x7ff,%rdi
  jbe    L18
  cmp    $0xffff,%rdi
  jbe    L96
  cmp    $0x1fffff,%rdi
  jbe    L119
  xor    %ebp,%ebp
  cmp    $0x3ffffff,%rdi
  seta   %bpl
  add    $0x4,%ebp
L65:
  mov    $0x1,%edi
  movslq %ebp,%rbp
  call   <assert@plt>
  shl    $0x4,%rbp
  lea    D3(%rip),%rax
  movslq (%rax,%rbp,1),%rcx
  mov    %rcx,%rax
  cmp    %r13,%rcx
  ja     L14
  cmp    $0x1,%ecx
  je     L88
  lea    -0x1(%rcx),%edx
  test   %edx,%edx
  jle    L21
  lea    -0x2(%r12,%rcx,1),%rdi
  movslq %edx,%rdx
  lea    -0x2(%rcx),%ecx
  add    %r12,%rdx
  sub    %rcx,%rdi
  nopw   0x0(%rax,%rax,1)
L76:
  mov    %ebx,%esi
  sub    $0x1,%rdx
  shr    $0x6,%rbx
  and    $0x3f,%esi
  or     $0xffffff80,%esi
  mov    %sil,0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L76
L21:
  mov    $0xff,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  not    %edx
  or     %ebx,%edx
  mov    %dl,(%r12)
L139:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L88:
  mov    %bl,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L134:
  xor    %ebp,%ebp
  jmp    L65
L18:
  mov    $0x1,%ebp
  jmp    L65
L96:
  mov    $0x2,%ebp
  jmp    L65
L119:
  mov    $0x3,%ebp
  jmp    L65
L14:
  mov    $0xffffffff,%eax
  jmp    L139
L97:
  or     $0xffffffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: 

assistant: ```c
int encodeutf8(unsigned long u, unsigned char *buf, size_t maxbytes) {
  static const struct {
    int nbytes;
    unsigned long max;
  } tab[] = {
      {1, 0x0000007F}, {2, 0x000007FF}, {3, 0x0000FFFF}, {4, 0x001FFFFF}, {5, 0x03FFFFFF}, {6, 0x7FFFFFFF},
  };
  static const int ntab = sizeof(tab) / sizeof(tab[0]);
  int i, j;
  if (u > tab[ntab - 1].max)
    return -1;
  for (i = 0; i < ntab; ++i) {
    if (u <= tab[i].max)
      break;
  }
  assert(i < ntab);
  if (tab[i].nbytes > maxbytes)
    return -1;
  if (tab[i].nbytes == 1) {
    buf[0] = u;
  } else {
    for (j = tab[i].nbytes - 1; j > 0; --j) {
      buf[j] = 0x80 | (u & 0x3f);
      u >>= 6;
    }
    unsigned char mask = ~(0xFF >> tab[i].nbytes);
    buf[0] = mask | u;
  }
  return tab[i].nbytes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cpuM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  imul   -0x24(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cpuM(int *hM, int width, int height, int length) {
  int M = 0;
  for (int i = 0; i < width * height * length; i++)
    M += hM[i];
  return M;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cpuM>:
  endbr64
  imul   %edx,%esi
  imul   %ecx,%esi
  test   %esi,%esi
  jle    L11
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L1:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L1
L19:
  mov    %edx,%eax
  ret
L11:
  mov    $0x0,%edx
  jmp    L19
```

assistant: ```c
int cpuM(int *hM, int width, int height, int length) {
  int M = 0;
  for (int i = 0; i < width * height * length; i++)
    M += hM[i];
  return M;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cpuM>:
  endbr64
  imul   %edx,%esi
  imul   %ecx,%esi
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L15:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L15
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cpuM(int *hM, int width, int height, int length) {
  int M = 0;
  for (int i = 0; i < width * height * length; i++)
    M += hM[i];
  return M;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cpuM>:
  endbr64
  imul   %edx,%esi
  imul   %ecx,%esi
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L3
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  cs nopw 0x0(%rax,%rax,1)
L68:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rdx,%rax
  jne    L68
  movdqa %xmm0,%xmm1
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L16
L15:
  movslq %edx,%rcx
  lea    0x0(,%rcx,4),%r8
  add    (%rdi,%rcx,4),%eax
  lea    0x1(%rdx),%ecx
  cmp    %esi,%ecx
  jge    L65
  add    $0x2,%edx
  add    0x4(%rdi,%r8,1),%eax
  cmp    %edx,%esi
  jle    L65
  add    0x8(%rdi,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
L65:
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
L3:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
int cpuM(int *hM, int width, int height, int length) {
  int M = 0;
  for (int i = 0; i < width * height * length; i++)
    M += hM[i];
  return M;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L9
L21:
  addq   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L21
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L31:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  subq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim(char *string) {
  char *end;
  while (isspace(*string))
    string++;
  end = string + strlen(string) - 1;
  while (isspace(*end)) {
    *end = 0;
    end--;
  }
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  jmp    L2
L8:
  add    $0x1,%rbp
L2:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  jmp    L29
L32:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L29:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *trim(char *string) {
  char *end;
  while (isspace(*string))
    string++;
  end = string + strlen(string) - 1;
  while (isspace(*end)) {
    *end = 0;
    end--;
  }
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  jmp    L2
L38:
  add    $0x1,%r12
L2:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L38
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L31
  nopl   0x0(%rax)
L27:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L31:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *string) {
  char *end;
  while (isspace(*string))
    string++;
  end = string + strlen(string) - 1;
  while (isspace(*end)) {
    *end = 0;
    end--;
  }
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  jmp    L9
L31:
  add    $0x1,%r12
L9:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L35
  nopl   0x0(%rax)
L20:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L35:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L20
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *string) {
  char *end;
  while (isspace(*string))
    string++;
  end = string + strlen(string) - 1;
  while (isspace(*end)) {
    *end = 0;
    end--;
  }
  return string;
}
```