ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<chapter_2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <quadruplet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <quadruplet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <doublet@plt>
  mov    $0x0,%eax
  call   <triplet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <triplet@plt>
  mov    $0x0,%eax
  call   <triplet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <triplet@plt>
  mov    $0x0,%eax
  call   <doublet@plt>
  mov    $0x0,%eax
  call   <doublet@plt>
  mov    $0x0,%eax
  call   <doublet@plt>
  mov    $0x0,%eax
  call   <doublet@plt>
  mov    $0x0,%eax
  call   <doublet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <quadruplet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <doublet@plt>
  mov    $0x0,%eax
  call   <triplet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  mov    $0x0,%eax
  call   <singlet@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void chapter_2() {
  singlet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  doublet();
  triplet();
  singlet();
  singlet();
  triplet();
  triplet();
  singlet();
  triplet();
  doublet();
  doublet();
  doublet();
  doublet();
  doublet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  doublet();
  triplet();
  singlet();
  singlet();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chapter_2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <quadruplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <quadruplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <quadruplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <singlet@plt>
```

assistant: ```c
void chapter_2() {
  singlet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  doublet();
  triplet();
  singlet();
  singlet();
  triplet();
  triplet();
  singlet();
  triplet();
  doublet();
  doublet();
  doublet();
  doublet();
  doublet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  doublet();
  triplet();
  singlet();
  singlet();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<chapter_2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <quadruplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <quadruplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <quadruplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  call   <doublet@plt>
  xor    %eax,%eax
  call   <triplet@plt>
  xor    %eax,%eax
  call   <singlet@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <singlet@plt>
```

assistant: ```c
void chapter_2() {
  singlet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  doublet();
  triplet();
  singlet();
  singlet();
  triplet();
  triplet();
  singlet();
  triplet();
  doublet();
  doublet();
  doublet();
  doublet();
  doublet();
  singlet();
  quadruplet();
  singlet();
  singlet();
  singlet();
  doublet();
  triplet();
  singlet();
  singlet();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msbbit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L29
  mov    $0x1f,%eax
  jmp    L2
L24:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  and    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sparsebit@plt>
L2:
  leave
  ret
```

assistant: ```c
int msbbit(long i) {
  long i2;
  if (i < 0)
    return (31);
  while ((i2 = (i & (i - 1))))
    i = i2;
  return (sparsebit(i));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<msbbit>:
  endbr64
  test   %rdi,%rdi
  js     L14
  sub    $0x8,%rsp
L1:
  mov    %rdi,%rdx
  lea    -0x1(%rdi),%rax
  and    %rax,%rdi
  jne    L1
  mov    %rdx,%rdi
  call   <sparsebit@plt>
  add    $0x8,%rsp
  ret
L14:
  mov    $0x1f,%eax
  ret
```

assistant: ```c
int msbbit(long i) {
  long i2;
  if (i < 0)
    return (31);
  while ((i2 = (i & (i - 1))))
    i = i2;
  return (sparsebit(i));
}
```
user: Translate the below assembly code into C programming language:

```asm
<msbbit>:
  endbr64
  test   %rdi,%rdi
  js     L8
  nopl   0x0(%rax)
L17:
  lea    -0x1(%rdi),%rax
  mov    %rdi,%r8
  and    %rax,%rdi
  jne    L17
  mov    %r8,%rdi
  jmp    1050 <sparsebit@plt>
  nopl   0x0(%rax)
L8:
  mov    $0x1f,%eax
  ret
```

assistant: ```c
int msbbit(long i) {
  long i2;
  if (i < 0)
    return (31);
  while ((i2 = (i & (i - 1))))
    i = i2;
  return (sparsebit(i));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<msbbit>:
  endbr64
  test   %rdi,%rdi
  js     L2
  nopl   0x0(%rax)
L3:
  lea    -0x1(%rdi),%rax
  mov    %rdi,%r8
  and    %rax,%rdi
  jne    L3
  mov    %r8,%rdi
  jmp    1050 <sparsebit@plt>
  nopl   0x0(%rax)
L2:
  mov    $0x1f,%eax
  ret
```

assistant: ```c
int msbbit(long i) {
  long i2;
  if (i < 0)
    return (31);
  while ((i2 = (i & (i - 1))))
    i = i2;
  return (sparsebit(i));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strUpper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L37
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L33
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L33
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  lea    -0x20(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L37
L33:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strUpper(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0')
    if ((*in >= 'a') && (*in <= 'z'))
      *scan++ = *in++ + 'A' - 'a';
    else
      *scan++ = *in++;
  *scan = '\0';
  return out;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strUpper>:
  endbr64
  mov    %rsi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L41
  add    $0x1,%rdi
  lea    0x1(%rsi),%rcx
  jmp    L16
L35:
  mov    %rdi,%r8
  mov    %rcx,%r9
L2:
  mov    %dl,-0x1(%rcx)
  movzbl (%r8),%edx
  add    $0x1,%rdi
  add    $0x1,%rcx
  test   %dl,%dl
  je     L47
L16:
  lea    -0x61(%rdx),%r8d
  cmp    $0x19,%r8b
  ja     L35
  mov    %rdi,%r8
  mov    %rcx,%r9
  sub    $0x20,%edx
  jmp    L2
L41:
  mov    %rsi,%r9
L47:
  movb   $0x0,(%r9)
  ret
```

assistant: ```c
char *strUpper(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0')
    if ((*in >= 'a') && (*in <= 'z'))
      *scan++ = *in++ + 'A' - 'a';
    else
      *scan++ = *in++;
  *scan = '\0';
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strUpper>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  mov    %rsi,%rcx
  test   %dl,%dl
  je     L3
  nopl   0x0(%rax)
L7:
  lea    -0x61(%rdx),%r9d
  add    $0x1,%rdi
  lea    -0x20(%rdx),%r8d
  add    $0x1,%rcx
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L7
L3:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strUpper(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0')
    if ((*in >= 'a') && (*in <= 'z'))
      *scan++ = *in++ + 'A' - 'a';
    else
      *scan++ = *in++;
  *scan = '\0';
  return out;
}
```
user: What is the c source code of the assembly code below:

```asm
<strUpper>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  mov    %rsi,%rcx
  test   %dl,%dl
  je     L15
  nopl   0x0(%rax)
L10:
  lea    -0x61(%rdx),%r8d
  add    $0x1,%rdi
  add    $0x1,%rcx
  cmp    $0x19,%r8b
  ja     L31
  sub    $0x20,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
L15:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %dl,-0x1(%rcx)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strUpper(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0')
    if ((*in >= 'a') && (*in <= 'z'))
      *scan++ = *in++ + 'A' - 'a';
    else
      *scan++ = *in++;
  *scan = '\0';
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L5:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L27
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L27
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L27
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x7530,-0x4(%rbp)
  jle    L5
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 30000; ++i) {
    if ((i % 2 != 0) && (i % 3 == 0) && (i % 7 == 0)) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D2(%rip),%rbp
  jmp    L26
L28:
  add    $0x1,%ebx
  cmp    $0x7531,%ebx
  je     L33
L26:
  test   $0x1,%bl
  je     L28
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rdx
  shr    $0x20,%rdx
  mov    %ebx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edx
  mov    %ebx,%ecx
  sub    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x2,%eax
  sub    %esi,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  or     %eax,%ecx
  jne    L28
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L28
L33:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 30000; ++i) {
    if ((i % 2 != 0) && (i % 3 == 0) && (i % 7 == 0)) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L20
  nopl   0x0(%rax)
L41:
  add    $0x1,%ebx
  cmp    $0x7531,%ebx
  je     L32
L20:
  test   $0x1,%bl
  je     L41
  mov    %ebx,%edx
  mov    %ebx,%ecx
  mov    %rdx,%rax
  imul   $0x24924925,%rdx,%rdx
  imul   %r12,%rax
  shr    $0x20,%rdx
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%ecx
  mov    %ebx,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  or     %eax,%ecx
  jne    L41
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7531,%ebx
  jne    L20
L32:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 30000; ++i) {
    if ((i % 2 != 0) && (i % 3 == 0) && (i % 7 == 0)) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L40
  nopl   0x0(%rax)
L38:
  add    $0x1,%ebx
  cmp    $0x7531,%ebx
  je     L29
L40:
  test   $0x1,%bl
  je     L38
  mov    %ebx,%edx
  mov    %ebx,%ecx
  mov    %rdx,%rax
  imul   $0x24924925,%rdx,%rdx
  imul   %r12,%rax
  shr    $0x20,%rdx
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%ecx
  mov    %ebx,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  or     %eax,%ecx
  jne    L38
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7531,%ebx
  jne    L40
L29:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: %d


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 30000; ++i) {
    if ((i % 2 != 0) && (i % 3 == 0) && (i % 7 == 0)) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L12:
  mov    -0x8(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <rol@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0xd(%rbp)
  movzbl -0xd(%rbp),%eax
  movzbl -0xd(%rbp),%edx
  add    $0x2,%edx
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  imul   -0xc(%rbp),%eax
  xor    %edx,%eax
  cltq
  xor    %rax,-0x8(%rbp)
  mov    $0xffffffff,%eax
  and    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0xc,%rax
  and    $0xfff000,%eax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x18,%rax
  mov    %rax,%rdx
  movabs $0xff000000000,%rax
  and    %rdx,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int calcHash(char *name) {
  unsigned long hash;
  int i;
  unsigned char c;
  hash = 0;
  i = 0;
  while (*name) {
    hash = rol(hash, 5);
    c = toupper(*name);
    hash ^= (c * (c + 2)) ^ (i * (i + 2));
    hash &= 0xffffffff;
    i++, name++;
  }
  hash = hash * (hash + 2);
  hash ^= (hash & 0xfff) << 12;
  hash ^= (hash & 0xff000) << 24;
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calcHash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L29
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%edi
L21:
  mov    $0x5,%esi
  call   <rol@plt>
  mov    %rax,%r12
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  movzbl %al,%eax
  lea    0x2(%rax),%edi
  imul   %eax,%edi
  lea    0x2(%rbx),%eax
  imul   %ebx,%eax
  xor    %eax,%edi
  xor    %r12d,%edi
  add    $0x1,%rbx
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  jne    L21
L3:
  lea    0x2(%rdi),%rdx
  imul   %rdi,%rdx
  mov    %rdx,%rax
  shl    $0xc,%rax
  and    $0xfff000,%eax
  xor    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    $0x0,%edi
  jmp    L3
```

assistant: ```c
int calcHash(char *name) {
  unsigned long hash;
  int i;
  unsigned char c;
  hash = 0;
  i = 0;
  while (*name) {
    hash = rol(hash, 5);
    c = toupper(*name);
    hash ^= (c * (c + 2)) ^ (i * (i + 2));
    hash &= 0xffffffff;
    i++, name++;
  }
  hash = hash * (hash + 2);
  hash ^= (hash & 0xfff) << 12;
  hash ^= (hash & 0xff000) << 24;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calcHash>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L6
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L12:
  mov    $0x5,%esi
  call   <rol@plt>
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %rax,%r12
  call   <toupper@plt>
  movzbl %al,%eax
  lea    0x2(%rax),%edi
  imul   %eax,%edi
  lea    0x2(%rbx),%eax
  imul   %ebx,%eax
  add    $0x1,%rbx
  xor    %eax,%edi
  xor    %r12d,%edi
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  jne    L12
  lea    0x2(%rdi),%rdx
  pop    %rbx
  pop    %rbp
  imul   %rdi,%rdx
  pop    %r12
  mov    %rdx,%rax
  shl    $0xc,%rax
  and    $0xfff000,%eax
  xor    %edx,%eax
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int calcHash(char *name) {
  unsigned long hash;
  int i;
  unsigned char c;
  hash = 0;
  i = 0;
  while (*name) {
    hash = rol(hash, 5);
    c = toupper(*name);
    hash ^= (c * (c + 2)) ^ (i * (i + 2));
    hash &= 0xffffffff;
    i++, name++;
  }
  hash = hash * (hash + 2);
  hash ^= (hash & 0xfff) << 12;
  hash ^= (hash & 0xff000) << 24;
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcHash>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L7:
  mov    $0x5,%esi
  call   <rol@plt>
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %rax,%r12
  call   <toupper@plt>
  movzbl %al,%eax
  lea    0x2(%rax),%edi
  imul   %eax,%edi
  lea    0x2(%rbx),%eax
  imul   %ebx,%eax
  add    $0x1,%rbx
  xor    %eax,%edi
  xor    %r12d,%edi
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  jne    L7
  lea    0x2(%rdi),%rdx
  pop    %rbx
  pop    %rbp
  imul   %rdi,%rdx
  pop    %r12
  mov    %rdx,%rax
  shl    $0xc,%rax
  and    $0xfff000,%eax
  xor    %edx,%eax
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int calcHash(char *name) {
  unsigned long hash;
  int i;
  unsigned char c;
  hash = 0;
  i = 0;
  while (*name) {
    hash = rol(hash, 5);
    c = toupper(*name);
    hash ^= (c * (c + 2)) ^ (i * (i + 2));
    hash &= 0xffffffff;
    i++, name++;
  }
  hash = hash * (hash + 2);
  hash ^= (hash & 0xfff) << 12;
  hash ^= (hash & 0xff000) << 24;
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<Hash32Len5to12>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x9,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <read32@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <read32@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  shr    %rax
  and    $0x4,%eax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <read32@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mur@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mur@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mur@plt>
  mov    %eax,%edi
  call   <fmix@plt>
  leave
  ret
```

assistant: ```c
uint32_t Hash32Len5to12(const char *s, size_t len) {
  uint32_t a = len, b = len * 5, c = 9, d = b;
  a += read32(s);
  b += read32(s + len - 4);
  c += read32(s + ((len >> 1) & 4));
  return fmix(mur(c, mur(b, mur(a, d))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Hash32Len5to12>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    (%rsi,%rsi,4),%r12d
  call   <read32@plt>
  mov    %rax,%r14
  lea    -0x4(%rbp,%rbx,1),%rdi
  call   <read32@plt>
  mov    %rax,%r13
  mov    %rbx,%rax
  shr    %rax
  and    $0x4,%eax
  lea    0x0(%rbp,%rax,1),%rdi
  call   <read32@plt>
  mov    %rax,%rbp
  lea    (%rbx,%r14,1),%edi
  mov    %r12d,%esi
  call   <mur@plt>
  mov    %eax,%esi
  lea    (%r12,%r13,1),%edi
  call   <mur@plt>
  mov    %eax,%esi
  lea    0x9(%rbp),%edi
  call   <mur@plt>
  mov    %eax,%edi
  call   <fmix@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint32_t Hash32Len5to12(const char *s, size_t len) {
  uint32_t a = len, b = len * 5, c = 9, d = b;
  a += read32(s);
  b += read32(s + len - 4);
  c += read32(s + ((len >> 1) & 4));
  return fmix(mur(c, mur(b, mur(a, d))));
}
```