user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x124000(%rsp),%r11
L125:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L125
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x124f98(%rbp)
  movl   $0x0,-0x124fb0(%rbp)
  mov    -0x124fb0(%rbp),%eax
  mov    %eax,-0x124fac(%rbp)
  mov    -0x124fac(%rbp),%eax
  mov    %eax,-0x124fa8(%rbp)
  mov    $0x0,%eax
  call   <fastRead@plt>
  mov    %eax,-0x124fc0(%rbp)
  jmp    L185
L154:
  movq   $0x0,-0x124f98(%rbp)
  mov    $0x0,%eax
  call   <fastRead@plt>
  mov    %eax,-0x124fa4(%rbp)
  mov    $0x0,%eax
  call   <fastRead@plt>
  mov    %eax,-0x124fa0(%rbp)
  mov    $0x0,%eax
  call   <fastRead@plt>
  mov    %eax,-0x124f9c(%rbp)
  movl   $0x0,-0x124fbc(%rbp)
  jmp    L10
L184:
  mov    $0x0,%eax
  call   <fastRead@plt>
  mov    -0x124fbc(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x124f90(%rbp,%rdx,4)
  addl   $0x1,-0x124fbc(%rbp)
L10:
  mov    -0x124fbc(%rbp),%eax
  cmp    -0x124fa4(%rbp),%eax
  jl     L184
  movl   $0x0,-0x124fbc(%rbp)
  jmp    L132
L170:
  mov    $0x0,%eax
  call   <fastRead@plt>
  mov    -0x124fbc(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0xc3510(%rbp,%rdx,4)
  addl   $0x1,-0x124fbc(%rbp)
L132:
  mov    -0x124fbc(%rbp),%eax
  cmp    -0x124fa0(%rbp),%eax
  jl     L170
  movl   $0x0,-0x124fbc(%rbp)
  jmp    L167
L61:
  mov    $0x0,%eax
  call   <fastRead@plt>
  mov    -0x124fbc(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x61a90(%rbp,%rdx,4)
  addl   $0x1,-0x124fbc(%rbp)
L167:
  mov    -0x124fbc(%rbp),%eax
  cmp    -0x124f9c(%rbp),%eax
  jl     L61
  movl   $0x0,-0x124fbc(%rbp)
  jmp    L3
L93:
  movl   $0x0,-0x124fb8(%rbp)
  jmp    L63
L104:
  movl   $0x0,-0x124fb4(%rbp)
  jmp    L20
L28:
  mov    -0x124fbc(%rbp),%eax
  cltq
  mov    -0x124f90(%rbp,%rax,4),%edx
  mov    -0x124fb8(%rbp),%eax
  cltq
  mov    -0xc3510(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jg     L101
  mov    -0x124fb8(%rbp),%eax
  cltq
  mov    -0xc3510(%rbp,%rax,4),%edx
  mov    -0x124fb4(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jl     L101
  mov    -0x124fbc(%rbp),%eax
  cltq
  mov    -0x124f90(%rbp,%rax,4),%edx
  mov    -0x124fb8(%rbp),%eax
  cltq
  mov    -0xc3510(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x124fb8(%rbp),%eax
  cltq
  mov    -0xc3510(%rbp,%rax,4),%ecx
  mov    -0x124fb4(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  add    %ecx,%eax
  imul   %edx,%eax
  cltq
  add    %rax,-0x124f98(%rbp)
L101:
  addl   $0x1,-0x124fb4(%rbp)
L20:
  mov    -0x124fb4(%rbp),%eax
  cmp    -0x124f9c(%rbp),%eax
  jl     L28
  addl   $0x1,-0x124fb8(%rbp)
L63:
  mov    -0x124fb8(%rbp),%eax
  cmp    -0x124fa0(%rbp),%eax
  jl     L104
  addl   $0x1,-0x124fbc(%rbp)
L3:
  mov    -0x124fbc(%rbp),%eax
  cmp    -0x124fa4(%rbp),%eax
  jl     L93
  cmpq   $0x0,-0x124f98(%rbp)
  jns    L173
  negq   -0x124f98(%rbp)
L173:
  mov    -0x124f98(%rbp),%rcx
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L185:
  mov    -0x124fc0(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x124fc0(%rbp)
  test   %eax,%eax
  jg     L154
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: %lld


assistant: ```c
int main() {
  int T, p, q, r, max, i, j, k, l, o;
  long long sum;
  max = l = o = sum = 0;
  int a[100000];
  int b[100000];
  int c[100000];
  int d[100000];
  T = fastRead();
  while (T-- > 0) {
    sum = 0;
    p = fastRead();
    q = fastRead();
    r = fastRead();
    for (i = 0; i < p; i++)
      a[i] = fastRead();
    for (i = 0; i < q; i++) {
      b[i] = fastRead();
    }
    for (i = 0; i < r; i++) {
      c[i] = fastRead();
    }
    for (i = 0; i < p; i++) {
      for (j = 0; j < q; j++) {
        for (k = 0; k < r; k++) {
          if (a[i] <= b[j] && b[j] >= c[k]) {
            sum += (a[i] + b[j]) * (b[j] + c[k]);
          }
        }
      }
    }
    if (sum < 0)
      sum = -sum;
    printf("%lld\n", sum % (1000000007));
  }
  return 0;
}
```