ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  sub    $0x60,%rsp
  movdqa D38(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  movaps %xmm0,0x30(%rsp)
  movdqa D18(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <printf@plt>
  lea    0x30(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0x8,%edx
  mov    $0x2,%edi
  call   <generate_combinations@plt>
  movdqa D20(%rip),%xmm0
  lea    D62(%rip),%rdi
  movaps %xmm0,0x20(%rsp)
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rbp,%rcx
  mov    $0x3,%edi
  call   <generate_combinations@plt>
  movdqa D7(%rip),%xmm0
  lea    D16(%rip),%rdi
  movaps %xmm0,0x20(%rsp)
  call   <printf@plt>
  mov    $0x3,%edx
  mov    %rbp,%rsi
  mov    $0x4,%edi
  call   <iterative_combinations@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D38
datatype: byte[16]
name: parse_data
arguments: label: D18
datatype: byte[16]
name: parse_data
arguments: label: D20
datatype: byte[16]
name: parse_data
arguments: label: D62
datatype: string
name: parse_data
arguments: label: D7
datatype: byte[16]
name: parse_data
arguments: label: D16
datatype: string

tool: D5: generate combination of octal numbers


tool: {"D38": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D18": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D20": [0x41,0x00,0x00,0x00,0x42,0x00,0x00,0x00,0x43,0x00,0x00,0x00,0x44,0x00,0x00,0x00]}

tool: D62: 
generate padlock combinations when it is 4 wheels of A to C


tool: {"D7": [0x51,0x00,0x00,0x00,0x52,0x00,0x00,0x00,0x53,0x00,0x00,0x00,0x54,0x00,0x00,0x00]}

tool: D16: 
generate padlock combinations iteratively


assistant: ```c
int main() {
  int positions = 2;
  int combo[positions];
  int set_size = 8;
  int num_set[set_size];
  int i;
  for (i = 0; i < set_size; i++) {
    num_set[i] = i;
  }
  printf("generate combination of octal numbers\n");
  generate_combinations(positions, combo, set_size, num_set);
  positions = 3;
  set_size = 4;
  int second_combo[positions];
  int letter_set[set_size];
  for (i = 0; i < set_size; i++) {
    letter_set[i] = 'A' + i;
  }
  printf("\ngenerate padlock combinations when it is 4 wheels of A to C\n");
  generate_combinations(positions, second_combo, set_size, letter_set);
  for (i = 0; i < set_size; i++) {
    letter_set[i] = 'Q' + i;
  }
  printf("\ngenerate padlock combinations iteratively\n");
  iterative_combinations(set_size, letter_set, positions);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D13(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <duplica_string@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string

tool: D13: Campos verdes

tool: D18: %s


assistant: ```c
int main(void) {
  char *s_a = "Campos verdes";
  char *s;
  s = malloc(strlen(s_a));
  s = s_a;
  char *s_duplicado;
  s_duplicado = duplica_string(s_a);
  printf("%s\n", s_duplicado);
  free(s_duplicado);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  call   <duplica_string@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string
name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D6: Campos verdes

tool: D9: %s


assistant: ```c
int main(void) {
  char *s_a = "Campos verdes";
  char *s;
  s = malloc(strlen(s_a));
  s = s_a;
  char *s_duplicado;
  s_duplicado = duplica_string(s_a);
  printf("%s\n", s_duplicado);
  free(s_duplicado);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  call   <duplica_string@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D10
datatype: string

tool: D9: Campos verdes

tool: D10: %s


assistant: ```c
int main(void) {
  char *s_a = "Campos verdes";
  char *s;
  s = malloc(strlen(s_a));
  s = s_a;
  char *s_duplicado;
  s_duplicado = duplica_string(s_a);
  printf("%s\n", s_duplicado);
  free(s_duplicado);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  call   <duplica_string@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string
name: disassemble_data
arguments: label: D7
type: string

tool: D4: Campos verdes

tool: D7: %s


assistant: ```c
int main(void) {
  char *s_a = "Campos verdes";
  char *s;
  s = malloc(strlen(s_a));
  s = s_a;
  char *s_duplicado;
  s_duplicado = duplica_string(s_a);
  printf("%s\n", s_duplicado);
  free(s_duplicado);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotate_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x3,%eax
  and    $0x10,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x3,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  or     %edx,%eax
  and    $0xffffffef,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rotate_left(unsigned char *target) {
  int carry_left = 0;
  int carry_right = 0;
  carry_left = (target[0] & 0x80) >> 3;
  target[0] = (target[0] << 1) | ((target[1] & 0x80) >> 7);
  target[1] = (target[1] << 1) | ((target[2] & 0x80) >> 7);
  target[2] = (target[2] << 1) | ((target[3] & 0x80) >> 7);
  carry_right = (target[3] & 0x08) >> 3;
  target[3] = (((target[3] << 1) | ((target[4] & 0x80) >> 7)) & ~0x10) | carry_left;
  target[4] = (target[4] << 1) | ((target[5] & 0x80) >> 7);
  target[5] = (target[5] << 1) | ((target[6] & 0x80) >> 7);
  target[6] = (target[6] << 1) | carry_right;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rotate_left>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%esi
  movzbl 0x1(%rdi),%edx
  mov    %edx,%ecx
  shr    $0x7,%cl
  lea    (%rsi,%rsi,1),%edi
  or     %edi,%ecx
  mov    %cl,(%rax)
  movzbl 0x2(%rax),%ecx
  mov    %ecx,%edi
  shr    $0x7,%dil
  add    %edx,%edx
  or     %edi,%edx
  mov    %dl,0x1(%rax)
  movzbl 0x3(%rax),%edx
  mov    %edx,%edi
  shr    $0x7,%dil
  add    %ecx,%ecx
  or     %edi,%ecx
  mov    %cl,0x2(%rax)
  movzbl %dl,%edx
  movzbl 0x4(%rax),%edi
  lea    (%rdx,%rdx,1),%r8d
  mov    %edi,%ecx
  shr    $0x7,%cl
  or     %r8d,%ecx
  and    $0xffffffef,%ecx
  sar    $0x3,%esi
  and    $0x10,%esi
  or     %esi,%ecx
  mov    %cl,0x3(%rax)
  movzbl 0x5(%rax),%esi
  mov    %esi,%ecx
  shr    $0x7,%cl
  add    %edi,%edi
  or     %ecx,%edi
  mov    %dil,0x4(%rax)
  movzbl 0x6(%rax),%ecx
  mov    %ecx,%edi
  shr    $0x7,%dil
  add    %esi,%esi
  or     %edi,%esi
  mov    %sil,0x5(%rax)
  sar    $0x3,%edx
  and    $0x1,%edx
  add    %ecx,%ecx
  or     %edx,%ecx
  mov    %cl,0x6(%rax)
  ret
```

assistant: ```c
void rotate_left(unsigned char *target) {
  int carry_left = 0;
  int carry_right = 0;
  carry_left = (target[0] & 0x80) >> 3;
  target[0] = (target[0] << 1) | ((target[1] & 0x80) >> 7);
  target[1] = (target[1] << 1) | ((target[2] & 0x80) >> 7);
  target[2] = (target[2] << 1) | ((target[3] & 0x80) >> 7);
  carry_right = (target[3] & 0x08) >> 3;
  target[3] = (((target[3] << 1) | ((target[4] & 0x80) >> 7)) & ~0x10) | carry_left;
  target[4] = (target[4] << 1) | ((target[5] & 0x80) >> 7);
  target[5] = (target[5] << 1) | ((target[6] & 0x80) >> 7);
  target[6] = (target[6] << 1) | carry_right;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotate_left>:
  endbr64
  movzbl 0x1(%rdi),%edx
  movzbl (%rdi),%esi
  mov    %rdi,%rax
  mov    %edx,%ecx
  lea    (%rsi,%rsi,1),%edi
  add    %edx,%edx
  sar    $0x3,%esi
  shr    $0x7,%cl
  and    $0x10,%esi
  or     %edi,%ecx
  mov    %cl,(%rax)
  movzbl 0x2(%rax),%ecx
  mov    %ecx,%edi
  add    %ecx,%ecx
  shr    $0x7,%dil
  or     %edi,%edx
  mov    %dl,0x1(%rax)
  movzbl 0x3(%rax),%edx
  mov    %edx,%edi
  lea    (%rdx,%rdx,1),%r8d
  sar    $0x3,%edx
  shr    $0x7,%dil
  and    $0x1,%edx
  or     %edi,%ecx
  movzbl 0x4(%rax),%edi
  mov    %cl,0x2(%rax)
  mov    %edi,%ecx
  add    %edi,%edi
  shr    $0x7,%cl
  or     %r8d,%ecx
  and    $0xffffffef,%ecx
  or     %esi,%ecx
  movzbl 0x5(%rax),%esi
  mov    %cl,0x3(%rax)
  mov    %esi,%ecx
  add    %esi,%esi
  shr    $0x7,%cl
  or     %ecx,%edi
  movzbl 0x6(%rax),%ecx
  mov    %dil,0x4(%rax)
  mov    %ecx,%edi
  add    %ecx,%ecx
  shr    $0x7,%dil
  or     %edx,%ecx
  or     %edi,%esi
  mov    %cl,0x6(%rax)
  mov    %sil,0x5(%rax)
  ret
```

assistant: ```c
void rotate_left(unsigned char *target) {
  int carry_left = 0;
  int carry_right = 0;
  carry_left = (target[0] & 0x80) >> 3;
  target[0] = (target[0] << 1) | ((target[1] & 0x80) >> 7);
  target[1] = (target[1] << 1) | ((target[2] & 0x80) >> 7);
  target[2] = (target[2] << 1) | ((target[3] & 0x80) >> 7);
  carry_right = (target[3] & 0x08) >> 3;
  target[3] = (((target[3] << 1) | ((target[4] & 0x80) >> 7)) & ~0x10) | carry_left;
  target[4] = (target[4] << 1) | ((target[5] & 0x80) >> 7);
  target[5] = (target[5] << 1) | ((target[6] & 0x80) >> 7);
  target[6] = (target[6] << 1) | carry_right;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotate_left>:
  endbr64
  movzbl 0x1(%rdi),%edx
  movzbl (%rdi),%esi
  mov    %rdi,%rax
  mov    %edx,%ecx
  lea    (%rsi,%rsi,1),%edi
  add    %edx,%edx
  sar    $0x3,%esi
  shr    $0x7,%cl
  and    $0x10,%esi
  or     %edi,%ecx
  mov    %cl,(%rax)
  movzbl 0x2(%rax),%ecx
  mov    %ecx,%edi
  add    %ecx,%ecx
  shr    $0x7,%dil
  or     %edi,%edx
  mov    %dl,0x1(%rax)
  movzbl 0x3(%rax),%edx
  mov    %edx,%edi
  lea    (%rdx,%rdx,1),%r8d
  sar    $0x3,%edx
  shr    $0x7,%dil
  and    $0x1,%edx
  or     %edi,%ecx
  movzbl 0x4(%rax),%edi
  mov    %cl,0x2(%rax)
  mov    %edi,%ecx
  add    %edi,%edi
  shr    $0x7,%cl
  or     %r8d,%ecx
  and    $0xffffffef,%ecx
  or     %esi,%ecx
  movzbl 0x5(%rax),%esi
  mov    %cl,0x3(%rax)
  mov    %esi,%ecx
  add    %esi,%esi
  shr    $0x7,%cl
  or     %ecx,%edi
  movzbl 0x6(%rax),%ecx
  mov    %dil,0x4(%rax)
  mov    %ecx,%edi
  add    %ecx,%ecx
  shr    $0x7,%dil
  or     %edx,%ecx
  or     %edi,%esi
  mov    %cl,0x6(%rax)
  mov    %sil,0x5(%rax)
  ret
```

assistant: ```c
void rotate_left(unsigned char *target) {
  int carry_left = 0;
  int carry_right = 0;
  carry_left = (target[0] & 0x80) >> 3;
  target[0] = (target[0] << 1) | ((target[1] & 0x80) >> 7);
  target[1] = (target[1] << 1) | ((target[2] & 0x80) >> 7);
  target[2] = (target[2] << 1) | ((target[3] & 0x80) >> 7);
  carry_right = (target[3] & 0x08) >> 3;
  target[3] = (((target[3] << 1) | ((target[4] & 0x80) >> 7)) & ~0x10) | carry_left;
  target[4] = (target[4] << 1) | ((target[5] & 0x80) >> 7);
  target[5] = (target[5] << 1) | ((target[6] & 0x80) >> 7);
  target[6] = (target[6] << 1) | carry_right;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L35
  mov    $0x2,%eax
  jmp    L43
L35:
  cmpl   $0x1,-0x14(%rbp)
  jne    L29
  mov    $0x1,%eax
  jmp    L43
L29:
  cmpl   $0x1,-0x14(%rbp)
  jle    L43
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fun>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fun>
  add    %ebx,%eax
  jmp    L43
L43:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fun(int n) {
  if (n == 0) {
    return 2;
  }
  if (n == 1) {
    return 1;
  }
  if (n > 1) {
    return fun(n - 1) + fun(n - 2);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fun>:
  endbr64
  mov    $0x2,%eax
  test   %edi,%edi
  je     L22
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    $0x1,%edi
  je     L30
  jg     L36
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  lea    -0x1(%rdi),%edi
  call   <fun>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fun>
  add    %ebp,%eax
  jmp    L30
L22:
  ret
```

assistant: ```c
int fun(int n) {
  if (n == 0) {
    return 2;
  }
  if (n == 1) {
    return 1;
  }
  if (n > 1) {
    return fun(n - 1) + fun(n - 2);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<GetComment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  movl   $0x400,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L90
  mov    $0x0,%eax
  jmp    L97
L90:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L82
L81:
  mov    -0x28(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x2c(%rbp)
  jg     L83
  shll   -0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L70
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L97
L70:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L83:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,(%rbx)
  cmpl   $0x2,-0x28(%rbp)
  jle    L76
  mov    -0x28(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L76
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L76
  movl   $0x1,-0x24(%rbp)
L76:
  addl   $0x1,-0x28(%rbp)
L82:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L56
  cmpl   $0x0,-0x24(%rbp)
  je     L81
L56:
  mov    -0x28(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
L97:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *GetComment(FILE *input) {
  int alloc_size = 1024;
  int len = 0;
  char *buffer = NULL;
  char *tmp = NULL;
  bool done = false;
  if (!input)
    return NULL;
  buffer = malloc(alloc_size);
  while (!feof(input) && !done) {
    if ((len + 2) >= alloc_size) {
      alloc_size *= 2;
      tmp = realloc(buffer, alloc_size);
      if (!tmp) {
        free(buffer);
        return NULL;
      }
      buffer = tmp;
    }
    buffer[len] = fgetc(input);
    if ((len > 2) && (buffer[len - 1] == '*') && (buffer[len] == '/')) {
      done = true;
    }
    len++;
  }
  buffer[len - 2] = '\0';
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetComment>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  test   %rdi,%rdi
  je     L37
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x400,%r13d
  jmp    L74
L53:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15,%r12
  jmp    L42
L32:
  lea    (%r12,%rbx,1),%r15
  mov    %r14,%rdi
  call   <fgetc@plt>
  mov    %al,(%r15)
  cmp    $0x2,%ebx
  jle    L18
  cmpb   $0x2a,-0x1(%r12,%rbx,1)
  sete   %dl
  cmp    $0x2f,%al
  sete   %bpl
  movzbl %bpl,%ebp
  and    %edx,%ebp
L18:
  add    $0x1,%rbx
L74:
  mov    %r14,%rdi
  call   <feof@plt>
  or     %eax,%ebp
  jne    L51
  lea    0x2(%rbx),%eax
  cmp    %eax,%r13d
  jg     L32
  add    %r13d,%r13d
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L53
  mov    %rax,%r12
  jmp    L32
L51:
  movslq %ebx,%r15
  movb   $0x0,-0x2(%r12,%r15,1)
L42:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  mov    %rdi,%r12
  jmp    L42
```

assistant: ```c
char *GetComment(FILE *input) {
  int alloc_size = 1024;
  int len = 0;
  char *buffer = NULL;
  char *tmp = NULL;
  bool done = false;
  if (!input)
    return NULL;
  buffer = malloc(alloc_size);
  while (!feof(input) && !done) {
    if ((len + 2) >= alloc_size) {
      alloc_size *= 2;
      tmp = realloc(buffer, alloc_size);
      if (!tmp) {
        free(buffer);
        return NULL;
      }
      buffer = tmp;
    }
    buffer[len] = fgetc(input);
    if ((len > 2) && (buffer[len - 1] == '*') && (buffer[len] == '/')) {
      done = true;
    }
    len++;
  }
  buffer[len - 2] = '\0';
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetComment>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L48
  mov    %rdi,%r14
  mov    $0x400,%edi
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  call   <malloc@plt>
  mov    $0x400,%r13d
  mov    %rax,%r12
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L9:
  lea    0x2(%rbx),%eax
  cmp    %eax,%r13d
  jg     L58
  add    %r13d,%r13d
  mov    %r12,%rdi
  mov    %r13d,%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%r12
L58:
  mov    %r14,%rdi
  lea    (%r12,%rbx,1),%r15
  call   <fgetc@plt>
  mov    %al,(%r15)
  cmp    $0x2,%rbx
  jbe    L31
  cmpb   $0x2a,-0x1(%r12,%rbx,1)
  sete   %dl
  xor    %ebp,%ebp
  cmp    $0x2f,%al
  sete   %bpl
  and    %edx,%ebp
L31:
  add    $0x1,%rbx
L56:
  mov    %r14,%rdi
  movslq %ebx,%r15
  call   <feof@plt>
  or     %eax,%ebp
  je     L9
  movb   $0x0,-0x2(%r12,%r15,1)
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L2:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L13
  nopl   (%rax)
L48:
  xor    %r12d,%r12d
  jmp    L13
```

assistant: ```c
char *GetComment(FILE *input) {
  int alloc_size = 1024;
  int len = 0;
  char *buffer = NULL;
  char *tmp = NULL;
  bool done = false;
  if (!input)
    return NULL;
  buffer = malloc(alloc_size);
  while (!feof(input) && !done) {
    if ((len + 2) >= alloc_size) {
      alloc_size *= 2;
      tmp = realloc(buffer, alloc_size);
      if (!tmp) {
        free(buffer);
        return NULL;
      }
      buffer = tmp;
    }
    buffer[len] = fgetc(input);
    if ((len > 2) && (buffer[len - 1] == '*') && (buffer[len] == '/')) {
      done = true;
    }
    len++;
  }
  buffer[len - 2] = '\0';
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetComment>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L63
  mov    %rdi,%r14
  mov    $0x400,%edi
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  call   <malloc@plt>
  mov    $0x400,%r13d
  mov    %rax,%r12
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L0:
  lea    0x2(%rbx),%eax
  cmp    %eax,%r13d
  jg     L24
  add    %r13d,%r13d
  mov    %r12,%rdi
  mov    %r13d,%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L52
  mov    %rax,%r12
L24:
  mov    %r14,%rdi
  lea    (%r12,%rbx,1),%r15
  call   <fgetc@plt>
  mov    %al,(%r15)
  cmp    $0x2,%rbx
  jbe    L65
  cmpb   $0x2a,-0x1(%r12,%rbx,1)
  sete   %dl
  xor    %ebp,%ebp
  cmp    $0x2f,%al
  sete   %bpl
  and    %edx,%ebp
L65:
  add    $0x1,%rbx
L1:
  mov    %r14,%rdi
  movslq %ebx,%r15
  call   <feof@plt>
  or     %eax,%ebp
  je     L0
  movb   $0x0,-0x2(%r12,%r15,1)
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L52:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L13
  nopl   (%rax)
L63:
  xor    %r12d,%r12d
  jmp    L13
```

assistant: ```c
char *GetComment(FILE *input) {
  int alloc_size = 1024;
  int len = 0;
  char *buffer = NULL;
  char *tmp = NULL;
  bool done = false;
  if (!input)
    return NULL;
  buffer = malloc(alloc_size);
  while (!feof(input) && !done) {
    if ((len + 2) >= alloc_size) {
      alloc_size *= 2;
      tmp = realloc(buffer, alloc_size);
      if (!tmp) {
        free(buffer);
        return NULL;
      }
      buffer = tmp;
    }
    buffer[len] = fgetc(input);
    if ((len > 2) && (buffer[len - 1] == '*') && (buffer[len] == '/')) {
      done = true;
    }
    len++;
  }
  buffer[len - 2] = '\0';
  return buffer;
}
```