ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x11,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movl   $0x1,(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0x1,0x48(%rsp)
  movl   $0x1,0x60(%rsp)
  movl   $0x1,0x78(%rsp)
  movl   $0x1,0xa8(%rsp)
  movl   $0x1,0x8c(%rsp)
  movl   $0x1,0x70(%rsp)
  movl   $0x1,0x54(%rsp)
  movl   $0x1,0x38(%rsp)
  movl   $0x1,0x1c(%rsp)
  mov    $0xffffffffffffffe8,%rdi
  mov    $0x2,%esi
  mov    $0x18,%r10d
  jmp    L3
L1:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0x5,%eax
  je     L11
L74:
  cmp    %eax,%esi
  jl     L1
  lea    (%rdx,%rdi,1),%r8
  mov    0x4(%rdx),%ecx
  add    (%rdx),%ecx
  mov    %ecx,0x4(%r8,%r9,1)
  jmp    L1
L11:
  add    $0x1,%esi
  sub    $0x18,%rdi
  cmp    $0x6,%esi
  je     L31
L3:
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  sub    %rdi,%rdx
  mov    $0x1,%eax
  mov    %r10,%r9
  sub    %rdi,%r9
  jmp    L74
L31:
  lea    0x90(%rbp),%r14
  lea    D7(%rip),%r13
  lea    D10(%rip),%r12
  jmp    L82
L43:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L110:
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  je     L109
L57:
  mov    0x0(%rbp,%rbx,4),%esi
  test   %esi,%esi
  je     L43
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L110
L109:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rbp
  cmp    %rbp,%r14
  je     L105
L82:
  mov    $0x0,%ebx
  jmp    L57
L105:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type: string
name: read_data
arguments: tag: D10
type: string

tool: D7:   

tool: D10: %4d

assistant: ```c
int main() {
  int i = 0, j = 0;
  int arr[6][6] = {0};
  for (i = 0; i < 6; i++) {
    arr[i][j] = 1;
  }
  for (j = i; j > 0; j--) {
    arr[i][j] = 1;
    i--;
  }
  for (i = 2; i < 6; i++) {
    for (j = 1; j < 6 - 1; j++) {
      if (i >= j)
        arr[i][j] = arr[i - 1][j - 1] + arr[i - 1][j];
    }
  }
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6; j++) {
      if (arr[i][j] != 0)
        printf("%4d", arr[i][j]);
      else
        printf("  ");
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x11,%ecx
  mov    $0x2,%esi
  mov    $0x18,%r11d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x1,0x18(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0x1,0x48(%rsp)
  movl   $0x1,0x60(%rsp)
  movl   $0x1,0x78(%rsp)
  movl   $0x1,0x70(%rsp)
  movl   $0x0,(%rdi)
  mov    $0xffffffffffffffe8,%rdi
  movl   $0x1,0x8c(%rsp)
  movl   $0x1,0x54(%rsp)
  movl   $0x1,0x38(%rsp)
  movl   $0x1,0x1c(%rsp)
L73:
  mov    %r14,%rdx
  mov    %r11,%r10
  mov    %r14,%rbp
  mov    $0x1,%eax
  sub    %rdi,%rdx
  sub    %rdi,%r10
L72:
  cmp    %esi,%eax
  jg     L43
  mov    0x4(%rdx),%ecx
  lea    (%rdi,%rdx,1),%r9
  add    (%rdx),%ecx
  mov    %ecx,0x4(%r9,%r10,1)
L43:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0x5,%eax
  jne    L72
  add    $0x1,%esi
  sub    $0x18,%rdi
  cmp    $0x6,%esi
  jne    L73
  add    $0x90,%r14
  mov    $0x1,%esi
  lea    D3(%rip),%r13
  lea    D7(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L84:
  xor    %ebx,%ebx
  jmp    L96
  nopl   0x0(%rax)
L63:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  je     L32
L66:
  mov    0x0(%rbp,%rbx,4),%esi
L96:
  test   %esi,%esi
  jne    L63
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  jne    L66
L32:
  mov    $0xa,%edi
  add    $0x18,%rbp
  call   <putchar@plt>
  cmp    %r14,%rbp
  je     L93
  mov    0x0(%rbp),%esi
  jmp    L84
L93:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D7
type: string

tool: D3:   

tool: D7: %4d

assistant: ```c
int main() {
  int i = 0, j = 0;
  int arr[6][6] = {0};
  for (i = 0; i < 6; i++) {
    arr[i][j] = 1;
  }
  for (j = i; j > 0; j--) {
    arr[i][j] = 1;
    i--;
  }
  for (i = 2; i < 6; i++) {
    for (j = 1; j < 6 - 1; j++) {
      if (i >= j)
        arr[i][j] = arr[i - 1][j - 1] + arr[i - 1][j];
    }
  }
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6; j++) {
      if (arr[i][j] != 0)
        printf("%4d", arr[i][j]);
      else
        printf("  ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x11,%ecx
  push   %r13
  lea    D39(%rip),%r13
  push   %r12
  lea    D69(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  movdqa D56(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rbp
  lea    0x90(%rsp),%r14
  rep stos %rax,%es:(%rdi)
  mov    D27(%rip),%rax
  movups %xmm0,0x48(%rsp)
  movdqa D67(%rip),%xmm0
  movl   $0x1,(%rsp)
  mov    %rax,0x18(%rsp)
  mov    D52(%rip),%rax
  movaps %xmm0,0x60(%rsp)
  movdqa D2(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  mov    D62(%rip),%rax
  movl   $0x1,0x70(%rsp)
  movl   $0x1,0x38(%rsp)
  mov    %rax,0x88(%rsp)
  movups %xmm0,0x78(%rsp)
  nop
L59:
  xor    %ebx,%ebx
  jmp    L46
  nopl   0x0(%rax)
L26:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  je     L20
L46:
  mov    0x0(%rbp,%rbx,4),%esi
  test   %esi,%esi
  jne    L26
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  jne    L46
L20:
  mov    $0xa,%edi
  add    $0x18,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r14
  jne    L59
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D39
type_guessed: string
name: read_data
arguments: label: D69
type_guessed: string
name: read_data
arguments: label: D56
type_guessed: byte[16]
name: read_data
arguments: label: D27
type_guessed: byte[8]
name: read_data
arguments: label: D67
type_guessed: byte[16]
name: read_data
arguments: label: D52
type_guessed: byte[8]
name: read_data
arguments: label: D2
type_guessed: byte[16]
name: read_data
arguments: label: D62
type_guessed: byte[8]

tool: D39:   

tool: D69: %4d

tool: {"D56": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D27": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D67": [0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D52": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D2": [0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D62": [0x05,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int i = 0, j = 0;
  int arr[6][6] = {0};
  for (i = 0; i < 6; i++) {
    arr[i][j] = 1;
  }
  for (j = i; j > 0; j--) {
    arr[i][j] = 1;
    i--;
  }
  for (i = 2; i < 6; i++) {
    for (j = 1; j < 6 - 1; j++) {
      if (i >= j)
        arr[i][j] = arr[i - 1][j - 1] + arr[i - 1][j];
    }
  }
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6; j++) {
      if (arr[i][j] != 0)
        printf("%4d", arr[i][j]);
      else
        printf("  ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,%eax
  mov    %al,-0x5c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x50(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movzbl -0x5c(%rbp),%eax
  mov    %al,-0x1a(%rbp)
  movb   $0x0,-0x19(%rbp)
  jmp    L15
L35:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5c(%rbp)
  jne    L12
  addq   $0x1,-0x50(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x40(%rbp)
L12:
  addq   $0x1,-0x48(%rbp)
L15:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x40(%rbp)
  setb   %al
  movzbl %al,%eax
  cltq
  add    %rax,-0x50(%rbp)
  addq   $0x1,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L31
  movq   $0x0,-0x38(%rbp)
  lea    -0x1a(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x30(%rbp)
  jmp    L53
L37:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %eax,%ecx
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    %ecx,%edi
  call   <trim_blanks@plt>
  mov    %rax,(%rbx)
  lea    -0x1a(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x30(%rbp)
L53:
  cmpq   $0x0,-0x30(%rbp)
  jne    L37
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L31:
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **str_split(char *a_str, const char a_delim) {
  char **result = 0;
  size_t count = 0;
  char *tmp = a_str;
  char *last_comma = 0;
  char delim[2];
  delim[0] = a_delim;
  delim[1] = 0;
  while (*tmp) {
    if (a_delim == *tmp) {
      count++;
      last_comma = tmp;
    }
    tmp++;
  }
  count += last_comma < (a_str + strlen(a_str) - 1);
  count++;
  result = malloc(sizeof(char *) * count);
  if (result) {
    size_t idx = 0;
    char *token = strtok(a_str, delim);
    while (token) {
      *(result + idx++) = trim_blanks(strdup(token));
      token = strtok(0, delim);
    }
    *(result + idx) = 0;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_split>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L93
  mov    %esi,%ecx
  mov    %rdi,%rax
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L29
L78:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L47
L29:
  cmp    %dl,%cl
  jne    L78
  add    $0x1,%rbx
  mov    %rax,%rbp
  jmp    L78
L93:
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L47:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmp    %rax,%rbp
  adc    $0x1,%rbx
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L35
  lea    0x6(%rsp),%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L33
  mov    $0x0,%ebx
  lea    0x6(%rsp),%r12
L32:
  call   <strdup@plt>
  mov    %eax,%edi
  add    $0x1,%rbx
  call   <trim_blanks@plt>
  mov    %rax,-0x8(%rbp,%rbx,8)
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L32
L40:
  movq   $0x0,0x0(%rbp,%rbx,8)
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    $0x0,%ebx
  jmp    L40
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **str_split(char *a_str, const char a_delim) {
  char **result = 0;
  size_t count = 0;
  char *tmp = a_str;
  char *last_comma = 0;
  char delim[2];
  delim[0] = a_delim;
  delim[1] = 0;
  while (*tmp) {
    if (a_delim == *tmp) {
      count++;
      last_comma = tmp;
    }
    tmp++;
  }
  count += last_comma < (a_str + strlen(a_str) - 1);
  count++;
  result = malloc(sizeof(char *) * count);
  if (result) {
    size_t idx = 0;
    char *token = strtok(a_str, delim);
    while (token) {
      *(result + idx++) = trim_blanks(strdup(token));
      token = strtok(0, delim);
    }
    *(result + idx) = 0;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_split>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  test   %dl,%dl
  je     L17
  mov    %esi,%edi
  mov    %rbp,%rax
  xor    %r12d,%r12d
  xor    %ecx,%ecx
  xchg   %ax,%ax
L42:
  cmp    %dl,%dil
  jne    L14
  add    $0x1,%rcx
  mov    %rax,%r12
L14:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L42
  lea    0x1(%rcx),%rbx
L47:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rcx
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%r12
  adc    $0x0,%rcx
  lea    0x0(,%rcx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L34
  lea    0x6(%rsp),%rbx
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L65
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L53:
  call   <strdup@plt>
  add    $0x1,%rbp
  mov    %eax,%edi
  call   <trim_blanks@plt>
  xor    %edi,%edi
  mov    %rbx,%rsi
  mov    %rax,-0x8(%r12,%rbp,8)
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L53
  lea    (%r12,%rbp,8),%rax
L10:
  movq   $0x0,(%rax)
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L65:
  mov    %r12,%rax
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  jmp    L47
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **str_split(char *a_str, const char a_delim) {
  char **result = 0;
  size_t count = 0;
  char *tmp = a_str;
  char *last_comma = 0;
  char delim[2];
  delim[0] = a_delim;
  delim[1] = 0;
  while (*tmp) {
    if (a_delim == *tmp) {
      count++;
      last_comma = tmp;
    }
    tmp++;
  }
  count += last_comma < (a_str + strlen(a_str) - 1);
  count++;
  result = malloc(sizeof(char *) * count);
  if (result) {
    size_t idx = 0;
    char *token = strtok(a_str, delim);
    while (token) {
      *(result + idx++) = trim_blanks(strdup(token));
      token = strtok(0, delim);
    }
    *(result + idx) = 0;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_split>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  test   %dl,%dl
  je     L29
  mov    %esi,%edi
  mov    %rbp,%rax
  xor    %r12d,%r12d
  xor    %ecx,%ecx
  xchg   %ax,%ax
L34:
  cmp    %dil,%dl
  jne    L82
  add    $0x1,%rcx
  mov    %rax,%r12
L82:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L34
  lea    0x1(%rcx),%rbx
L80:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rcx
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%r12
  adc    $0x0,%rcx
  lea    0x0(,%rcx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
  lea    0x6(%rsp),%rbx
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L53
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L73:
  call   <strdup@plt>
  add    $0x1,%rbp
  mov    %eax,%edi
  call   <trim_blanks@plt>
  xor    %edi,%edi
  mov    %rbx,%rsi
  mov    %rax,-0x8(%r12,%rbp,8)
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L73
  lea    (%r12,%rbp,8),%rax
L36:
  movq   $0x0,(%rax)
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  mov    %r12,%rax
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  jmp    L80
L71:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **str_split(char *a_str, const char a_delim) {
  char **result = 0;
  size_t count = 0;
  char *tmp = a_str;
  char *last_comma = 0;
  char delim[2];
  delim[0] = a_delim;
  delim[1] = 0;
  while (*tmp) {
    if (a_delim == *tmp) {
      count++;
      last_comma = tmp;
    }
    tmp++;
  }
  count += last_comma < (a_str + strlen(a_str) - 1);
  count++;
  result = malloc(sizeof(char *) * count);
  if (result) {
    size_t idx = 0;
    char *token = strtok(a_str, delim);
    while (token) {
      *(result + idx++) = trim_blanks(strdup(token));
      token = strtok(0, delim);
    }
    *(result + idx) = 0;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convertpalette>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L19
L16:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x7,%eax
  and    $0x7c00,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  and    $0x3e0,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x3,%eax
  and    $0x1f,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x14(%rbp)
L19:
  cmpl   $0xff,-0x14(%rbp)
  jle    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void convertpalette(char *in, char *out) {
  uint16_t tgtcol;
  int pc;
  uint8_t r, g, b;
  for (pc = 0; pc < 256; pc++) {
    b = in[pc * 3 + 0];
    g = in[pc * 3 + 1];
    r = in[pc * 3 + 2];
    tgtcol = ((b & 0xf8) << 7) | ((g & 0xf8) << 2) | ((r & 0xf8) >> 3);
    out[pc * 2 + 0] = tgtcol & 0xff;
    out[pc * 2 + 1] = tgtcol >> 8;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<convertpalette>:
  endbr64
  mov    %rdi,%rdx
  add    $0x300,%rdi
L2:
  movsbl (%rdx),%eax
  shl    $0x7,%eax
  and    $0x7c00,%eax
  movsbl 0x1(%rdx),%ecx
  shl    $0x2,%ecx
  and    $0x3e0,%ecx
  or     %ecx,%eax
  movsbl 0x2(%rdx),%ecx
  sar    $0x3,%ecx
  and    $0x1f,%ecx
  or     %ecx,%eax
  mov    %al,(%rsi)
  movzbl %ah,%eax
  mov    %al,0x1(%rsi)
  add    $0x3,%rdx
  add    $0x2,%rsi
  cmp    %rdi,%rdx
  jne    L2
  ret
```

assistant: ```c
void convertpalette(char *in, char *out) {
  uint16_t tgtcol;
  int pc;
  uint8_t r, g, b;
  for (pc = 0; pc < 256; pc++) {
    b = in[pc * 3 + 0];
    g = in[pc * 3 + 1];
    r = in[pc * 3 + 2];
    tgtcol = ((b & 0xf8) << 7) | ((g & 0xf8) << 2) | ((r & 0xf8) >> 3);
    out[pc * 2 + 0] = tgtcol & 0xff;
    out[pc * 2 + 1] = tgtcol >> 8;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convertpalette>:
  endbr64
  lea    0x300(%rdi),%rcx
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl (%rdi),%eax
  movsbl 0x1(%rdi),%edx
  add    $0x3,%rdi
  add    $0x2,%rsi
  shl    $0x7,%eax
  shl    $0x2,%edx
  and    $0x3e0,%edx
  and    $0x7c00,%eax
  or     %edx,%eax
  movsbl -0x1(%rdi),%edx
  sar    $0x3,%edx
  and    $0x1f,%edx
  or     %edx,%eax
  mov    %al,-0x2(%rsi)
  mov    %ah,-0x1(%rsi)
  cmp    %rdi,%rcx
  jne    L9
  ret
```

assistant: ```c
void convertpalette(char *in, char *out) {
  uint16_t tgtcol;
  int pc;
  uint8_t r, g, b;
  for (pc = 0; pc < 256; pc++) {
    b = in[pc * 3 + 0];
    g = in[pc * 3 + 1];
    r = in[pc * 3 + 2];
    tgtcol = ((b & 0xf8) << 7) | ((g & 0xf8) << 2) | ((r & 0xf8) >> 3);
    out[pc * 2 + 0] = tgtcol & 0xff;
    out[pc * 2 + 1] = tgtcol >> 8;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<convertpalette>:
  endbr64
  lea    0x300(%rdi),%rcx
  nopl   0x0(%rax,%rax,1)
L5:
  movsbl (%rdi),%eax
  movsbl 0x1(%rdi),%edx
  add    $0x3,%rdi
  add    $0x2,%rsi
  shl    $0x7,%eax
  shl    $0x2,%edx
  and    $0x3e0,%edx
  and    $0x7c00,%eax
  or     %edx,%eax
  movsbl -0x1(%rdi),%edx
  sar    $0x3,%edx
  and    $0x1f,%edx
  or     %edx,%eax
  mov    %al,-0x2(%rsi)
  mov    %ah,-0x1(%rsi)
  cmp    %rdi,%rcx
  jne    L5
  ret
```

assistant: ```c
void convertpalette(char *in, char *out) {
  uint16_t tgtcol;
  int pc;
  uint8_t r, g, b;
  for (pc = 0; pc < 256; pc++) {
    b = in[pc * 3 + 0];
    g = in[pc * 3 + 1];
    r = in[pc * 3 + 2];
    tgtcol = ((b & 0xf8) << 7) | ((g & 0xf8) << 2) | ((r & 0xf8) >> 3);
    out[pc * 2 + 0] = tgtcol & 0xff;
    out[pc * 2 + 1] = tgtcol >> 8;
  }
}
```