ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<move_fsr>:
  endbr64
  mov    %edi,%eax
  and    $0xffc0,%eax
  cmp    $0x40c0,%eax
  je     L5
  ret
L5:
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D7(%rip),%rdi
  call   <gen_move_from_sr@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <add_opcode@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: move

assistant: ```c
void move_fsr(int opcode) {
  if ((opcode & 0xFFC0) != 0x40C0)
    return;
  add_opcode(gen_move_from_sr("move", opcode), opcode);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<move_fsr>:
  endbr64
  mov    %edi,%eax
  and    $0xffc0,%eax
  cmp    $0x40c0,%eax
  je     L0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D4(%rip),%rdi
  call   <gen_move_from_sr@plt>
  mov    %ebp,%esi
  pop    %rbp
  mov    %eax,%edi
  jmp    1070 <add_opcode@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: move

assistant: ```c
void move_fsr(int opcode) {
  if ((opcode & 0xFFC0) != 0x40C0)
    return;
  add_opcode(gen_move_from_sr("move", opcode), opcode);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<move_fsr>:
  endbr64
  mov    %edi,%eax
  and    $0xffc0,%eax
  cmp    $0x40c0,%eax
  je     L2
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D0(%rip),%rdi
  call   <gen_move_from_sr@plt>
  mov    %ebp,%esi
  pop    %rbp
  mov    %eax,%edi
  jmp    1070 <add_opcode@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string

tool: D0: move

assistant: ```c
void move_fsr(int opcode) {
  if ((opcode & 0xFFC0) != 0x40C0)
    return;
  add_opcode(gen_move_from_sr("move", opcode), opcode);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <cbreak@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%eax
  call   <clear@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
L3:
  jmp    L3
```

assistant: ```c
int main() {
  WINDOW *wnd;
  wnd = initscr();
  cbreak();
  noecho();
  clear();
  refresh();
  while (1) {
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <cbreak@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%eax
  call   <clear@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
L6:
  jmp    L6
```

assistant: ```c
int main() {
  WINDOW *wnd;
  wnd = initscr();
  cbreak();
  noecho();
  clear();
  refresh();
  while (1) {
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <cbreak@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %eax,%eax
  call   <clear@plt>
  xor    %eax,%eax
  call   <refresh@plt>
L0:
  jmp    L0
```

assistant: ```c
int main() {
  WINDOW *wnd;
  wnd = initscr();
  cbreak();
  noecho();
  clear();
  refresh();
  while (1) {
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <cbreak@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %eax,%eax
  call   <clear@plt>
  xor    %eax,%eax
  call   <refresh@plt>
L4:
  jmp    L4
```

assistant: ```c
int main() {
  WINDOW *wnd;
  wnd = initscr();
  cbreak();
  noecho();
  clear();
  refresh();
  while (1) {
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %rdi,-0x1a8(%rbp)
  mov    %rsi,-0x1b0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1a8(%rbp),%rdx
  lea    -0x1a0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x1b0(%rbp),%rdx
  lea    -0xd0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x1b0(%rbp),%rdx
  lea    -0x1a0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x1a8(%rbp),%rdx
  lea    -0xd0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x1a0(%rbp),%rdx
  lea    -0xd0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  char x[200];
  char y[200];
  strcpy(x, a);
  strcpy(y, b);
  strcat(x, b);
  strcat(y, a);
  return strcmp(y, x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdi,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  lea    0xd0(%rsp),%r12
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmp(const void *a, const void *b) {
  char x[200];
  char y[200];
  strcpy(x, a);
  strcpy(y, b);
  strcat(x, b);
  strcat(y, a);
  return strcmp(y, x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0xd0(%rsp),%r13
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x1a8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmp(const void *a, const void *b) {
  char x[200];
  char y[200];
  strcpy(x, a);
  strcpy(y, b);
  strcat(x, b);
  strcat(y, a);
  return strcmp(y, x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0xd0(%rsp),%r13
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x1a8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmp(const void *a, const void *b) {
  char x[200];
  char y[200];
  strcpy(x, a);
  strcpy(y, b);
  strcat(x, b);
  strcat(y, a);
  return strcmp(y, x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InsertB20>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  and    $0xf,%edx
  mov    %dl,(%rax)
  sarl   $0x4,-0x4(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  sarl   $0x8,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void InsertB20(int x, unsigned char *buf) {
  buf[2] = x & 0xf;
  x >>= 4;
  buf[1] = x & 0xff;
  x >>= 8;
  buf[0] = x & 0xff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InsertB20>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  mov    %al,0x2(%rsi)
  mov    %edi,%eax
  sar    $0x4,%eax
  mov    %al,0x1(%rsi)
  sar    $0xc,%edi
  mov    %dil,(%rsi)
  ret
```

assistant: ```c
void InsertB20(int x, unsigned char *buf) {
  buf[2] = x & 0xf;
  x >>= 4;
  buf[1] = x & 0xff;
  x >>= 8;
  buf[0] = x & 0xff;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<InsertB20>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  mov    %al,0x2(%rsi)
  mov    %edi,%eax
  sar    $0xc,%edi
  sar    $0x4,%eax
  mov    %dil,(%rsi)
  mov    %al,0x1(%rsi)
  ret
```

assistant: ```c
void InsertB20(int x, unsigned char *buf) {
  buf[2] = x & 0xf;
  x >>= 4;
  buf[1] = x & 0xff;
  x >>= 8;
  buf[0] = x & 0xff;
}
```
user: What is the c source code of the assembly code below:

```asm
<InsertB20>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  mov    %al,0x2(%rsi)
  mov    %edi,%eax
  sar    $0xc,%edi
  sar    $0x4,%eax
  mov    %dil,(%rsi)
  mov    %al,0x1(%rsi)
  ret
```

assistant: ```c
void InsertB20(int x, unsigned char *buf) {
  buf[2] = x & 0xf;
  x >>= 4;
  buf[1] = x & 0xff;
  x >>= 8;
  buf[0] = x & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ice_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L28
  cmpq   $0x0,-0x10(%rbp)
  jne    L9
L28:
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <xa_debug@plt>
  mov    $0x0,%eax
  jmp    L4
L9:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: ERROR: ice_strcmp() called with NULL pointers!

assistant: ```c
int ice_strcmp(const char *s1, const char *s2) {
  if (!s1 || !s2) {
    xa_debug(1, "ERROR: ice_strcmp() called with NULL pointers!");
    return 0;
  }
  return strcmp(s1, s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ice_strcmp>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L12
  test   %rsi,%rsi
  je     L12
  call   <strcmp@plt>
L8:
  add    $0x8,%rsp
  ret
L12:
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <xa_debug@plt>
  mov    $0x0,%eax
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: D4: ERROR: ice_strcmp() called with NULL pointers!

assistant: ```c
int ice_strcmp(const char *s1, const char *s2) {
  if (!s1 || !s2) {
    xa_debug(1, "ERROR: ice_strcmp() called with NULL pointers!");
    return 0;
  }
  return strcmp(s1, s2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ice_strcmp>:
  endbr64
  test   %rdi,%rdi
  je     L15
  test   %rsi,%rsi
  je     L15
  jmp    1070 <strcmp@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  mov    $0x1,%edi
  call   <xa_debug@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D3: ERROR: ice_strcmp() called with NULL pointers!

assistant: ```c
int ice_strcmp(const char *s1, const char *s2) {
  if (!s1 || !s2) {
    xa_debug(1, "ERROR: ice_strcmp() called with NULL pointers!");
    return 0;
  }
  return strcmp(s1, s2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ice_strcmp>:
  endbr64
  test   %rdi,%rdi
  je     L2
  test   %rsi,%rsi
  je     L2
  jmp    1070 <strcmp@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  mov    $0x1,%edi
  call   <xa_debug@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: ERROR: ice_strcmp() called with NULL pointers!

assistant: ```c
int ice_strcmp(const char *s1, const char *s2) {
  if (!s1 || !s2) {
    xa_debug(1, "ERROR: ice_strcmp() called with NULL pointers!");
    return 0;
  }
  return strcmp(s1, s2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4c(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L47
L93:
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L84
L15:
  mov    -0x3c(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x3c(%rbp)
L84:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L15
  movl   $0x0,-0x38(%rbp)
  jmp    L109
L89:
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  jmp    L96
L35:
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%ecx
  movslq %edx,%rax
  mov    %ecx,-0x30(%rbp,%rax,4)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x44(%rbp)
L96:
  cmpl   $0x0,-0x44(%rbp)
  jne    L35
  addl   $0x1,-0x38(%rbp)
L109:
  mov    -0x48(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jle    L89
  movl   $0x0,-0x34(%rbp)
  jmp    L23
L78:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L23:
  cmpl   $0x8,-0x34(%rbp)
  jle    L78
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x40(%rbp)
L47:
  mov    -0x4c(%rbp),%eax
  cmp    %eax,-0x40(%rbp)
  jl     L93
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D32
type_infered: string
name: read_data
arguments: tag: D30
type_infered: string
name: read_data
arguments: tag: D38
type_infered: string

tool: D32: %d

tool: D30: %d 

tool: D38: %d


assistant: ```c
int main() {
  int num, var, temp, digit[10];
  scanf("%d", &num);
  for (int i = 0; i < num; i++) {
    scanf("%d", &var);
    for (int j = 0; j < 10; j++)
      digit[j] = 0;
    for (int j = 0; j <= var; j++) {
      temp = j;
      while (temp) {
        digit[temp % 10]++;
        temp /= 10;
      }
    }
    for (int j = 0; j < 9; j++)
      printf("%d ", digit[j]);
    printf("%d\n", digit[9]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L32
  mov    $0x0,%r13d
  lea    0xc(%rsp),%r15
  lea    D15(%rip),%r14
  lea    D23(%rip),%r12
  jmp    L6
L64:
  mov    %esi,%edx
L71:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%r8d
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L71
L25:
  add    $0x1,%esi
  cmp    %esi,%edi
  je     L80
  test   %esi,%esi
  jne    L64
  jmp    L25
L80:
  lea    0x24(%rbx),%rbp
L1:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L1
  mov    0x34(%rsp),%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  cmp    %r13d,0x8(%rsp)
  jle    L32
L6:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
  lea    0x38(%rsp),%rdx
  mov    %rbx,%rax
L93:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L93
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  js     L80
  add    $0x1,%edi
  mov    $0x0,%esi
  jmp    L25
L32:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D23
type_guessed: string
name: read_data
arguments: data_label: D29
type_guessed: string

tool: D15: %d

tool: D23: %d 

tool: D29: %d


assistant: ```c
int main() {
  int num, var, temp, digit[10];
  scanf("%d", &num);
  for (int i = 0; i < num; i++) {
    scanf("%d", &var);
    for (int j = 0; j < 10; j++)
      digit[j] = 0;
    for (int j = 0; j <= var; j++) {
      temp = j;
      while (temp) {
        digit[temp % 10]++;
        temp /= 10;
      }
    }
    for (int j = 0; j < 9; j++)
      printf("%d ", digit[j]);
    printf("%d\n", digit[9]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L27
  lea    0x1c(%rsp),%rax
  xor    %r13d,%r13d
  lea    0x20(%rsp),%r12
  mov    %rax,0x8(%rsp)
  lea    0x44(%rsp),%rbp
  lea    D9(%rip),%rbx
L12:
  mov    0x8(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edi
  pxor   %xmm0,%xmm0
  movq   $0x0,0x20(%r12)
  movaps %xmm0,(%r12)
  movaps %xmm0,0x10(%r12)
  test   %edi,%edi
  js     L51
  xor    %esi,%esi
  add    $0x1,%edi
  add    $0x1,%esi
  cmp    %esi,%edi
  je     L51
  nopl   0x0(%rax)
L78:
  mov    %esi,%edx
  nopw   0x0(%rax,%rax,1)
L52:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%r8d
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %r8d,%r8d
  mov    %ecx,%edx
  sub    %r8d,%eax
  cltq
  addl   $0x1,0x20(%rsp,%rax,4)
  test   %ecx,%ecx
  jne    L52
  add    $0x1,%esi
  cmp    %esi,%edi
  jne    L78
L51:
  mov    %r12,%r15
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%r15),%esi
  mov    %rbx,%rdi
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L13
  mov    0x44(%rsp),%esi
  lea    D1(%rip),%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    %r13d,0x18(%rsp)
  jg     L12
L27:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D1
datatype: string

tool: D6: %d

tool: D9: %d 

tool: D1: %d


assistant: ```c
int main() {
  int num, var, temp, digit[10];
  scanf("%d", &num);
  for (int i = 0; i < num; i++) {
    scanf("%d", &var);
    for (int j = 0; j < 10; j++)
      digit[j] = 0;
    for (int j = 0; j <= var; j++) {
      temp = j;
      while (temp) {
        digit[temp % 10]++;
        temp /= 10;
      }
    }
    for (int j = 0; j < 9; j++)
      printf("%d ", digit[j]);
    printf("%d\n", digit[9]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D38(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L43
  lea    0x1c(%rsp),%rax
  xor    %r12d,%r12d
  lea    0x44(%rsp),%rbp
  mov    $0xcccccccd,%r15d
  mov    %rax,(%rsp)
  lea    0x20(%rsp),%rax
  lea    D2(%rip),%rbx
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L86:
  mov    (%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%r8d
  pxor   %xmm0,%xmm0
  movq   $0x0,0x40(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  test   %r8d,%r8d
  js     L8
  je     L90
  mov    $0x1,%edi
  nopl   0x0(%rax)
L15:
  mov    %edi,%edx
  nopw   0x0(%rax,%rax,1)
L87:
  mov    %edx,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r9d
  mov    %eax,%esi
  mov    %edx,%eax
  add    %r9d,%r9d
  mov    %esi,%edx
  sub    %r9d,%eax
  cltq
  addl   $0x1,0x20(%rsp,%rax,4)
  test   %esi,%esi
  jne    L87
  lea    0x1(%rdi),%eax
  cmp    %r8d,%edi
  je     L90
  mov    %eax,%edi
  jmp    L15
  nopl   0x0(%rax)
L90:
  mov    0x44(%rsp),%r13d
L48:
  mov    0x8(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L98:
  mov    (%r14),%esi
  mov    %rbx,%rdi
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L98
  mov    %r13d,%esi
  lea    D28(%rip),%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x18(%rsp)
  jg     L86
L43:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  xor    %r13d,%r13d
  jmp    L48
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D38
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string
name: disassemble_data
arguments: tag: D28
type_infered: string

tool: D38: %d

tool: D2: %d 

tool: D28: %d


assistant: ```c
int main() {
  int num, var, temp, digit[10];
  scanf("%d", &num);
  for (int i = 0; i < num; i++) {
    scanf("%d", &var);
    for (int j = 0; j < 10; j++)
      digit[j] = 0;
    for (int j = 0; j <= var; j++) {
      temp = j;
      while (temp) {
        digit[temp % 10]++;
        temp /= 10;
      }
    }
    for (int j = 0; j < 9; j++)
      printf("%d ", digit[j]);
    printf("%d\n", digit[9]);
  }
}
```