ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<counter>:
  endbr64
  mov    %esi,%eax
  lea    -0x3(%rdi),%edx
  cmp    $0x3,%edx
  ja     L5
  add    $0x1,%eax
  ret
L5:
  cmp    $0xa,%edi
  sete   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int counter(int val, int count) {
  if ((val > 2) && (val < 7)) {
    count++;
  } else if (val == 10) {
    count--;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<counter>:
  endbr64
  lea    -0x3(%rdi),%edx
  mov    %esi,%eax
  cmp    $0x3,%edx
  ja     L0
  add    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %edx,%edx
  cmp    $0xa,%edi
  sete   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int counter(int val, int count) {
  if ((val > 2) && (val < 7)) {
    count++;
  } else if (val == 10) {
    count--;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<counter>:
  endbr64
  lea    -0x3(%rdi),%edx
  mov    %esi,%eax
  cmp    $0x3,%edx
  ja     L1
  add    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %edx,%edx
  cmp    $0xa,%edi
  sete   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int counter(int val, int count) {
  if ((val > 2) && (val < 7)) {
    count++;
  } else if (val == 10) {
    count--;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L3
L28:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  xor    %rax,-0x10(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L28
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
data_type: string
name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string

tool: D20: %d

tool: D13: %lld

tool: D11: %lld


assistant: ```c
int main() {
  int n;
  long long int pi, ans = 0;
  scanf("%d", &n);
  while (n--) {
    scanf("%lld", &pi);
    ans ^= pi;
  }
  printf("%lld\n", ans);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L32
  mov    $0x0,%ebx
  lea    D17(%rip),%rbp
L15:
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  xor    0x10(%rsp),%rbx
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L15
L10:
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  mov    $0x0,%ebx
  jmp    L10
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D2
type: string

tool: D24: %d

tool: D17: %lld

tool: D2: %lld


assistant: ```c
int main() {
  int n;
  long long int pi, ans = 0;
  scanf("%d", &n);
  while (n--) {
    scanf("%lld", &pi);
    ans ^= pi;
  }
  printf("%lld\n", ans);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L14
  lea    0x10(%rsp),%r12
  lea    D0(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  xor    0x10(%rsp),%rbp
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L1
L14:
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D18
type_guessed: string

tool: D23: %d

tool: D0: %lld

tool: D18: %lld


assistant: ```c
int main() {
  int n;
  long long int pi, ans = 0;
  scanf("%d", &n);
  while (n--) {
    scanf("%lld", &pi);
    ans ^= pi;
  }
  printf("%lld\n", ans);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L5
  lea    0x10(%rsp),%r12
  lea    D21(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  xor    0x10(%rsp),%rbp
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L18
L5:
  mov    %rbp,%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D21
data_type: string
name: parse_data
arguments: tag: D22
data_type: string

tool: D9: %d

tool: D21: %lld

tool: D22: %lld


assistant: ```c
int main() {
  int n;
  long long int pi, ans = 0;
  scanf("%d", &n);
  while (n--) {
    scanf("%lld", &pi);
    ans ^= pi;
  }
  printf("%lld\n", ans);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<SortIntegerArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x1,-0x2c(%rbp)
  jle    L36
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <GetBlock@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <GetBlock@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L49:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L49
  movl   $0x0,-0x1c(%rbp)
  jmp    L41
L5:
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L41:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <SortIntegerArray>
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <SortIntegerArray>
  mov    -0x14(%rbp),%edi
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Merge@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <FreeBlock@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <FreeBlock@plt>
L36:
  nop
  leave
  ret
```

assistant: ```c
void SortIntegerArray(int array[], int n) {
  int i, n1, n2;
  int *arr1, *arr2;
  if (n > 1) {
    n1 = n / 2;
    n2 = n - n1;
    arr1 = ((int *)GetBlock((n1) * sizeof(int)));
    arr2 = ((int *)GetBlock((n2) * sizeof(int)));
    for (i = 0; i < n1; i++)
      arr1[i] = array[i];
    for (i = 0; i < n2; i++)
      arr2[i] = array[n1 + i];
    SortIntegerArray(arr1, n1);
    SortIntegerArray(arr2, n2);
    Merge(array, arr1, n1, arr2, n2);
    FreeBlock(arr1);
    FreeBlock(arr2);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SortIntegerArray>:
  endbr64
  cmp    $0x1,%esi
  jg     L13
  ret
L13:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %esi,%r13d
  shr    $0x1f,%r13d
  add    %esi,%r13d
  sar    %r13d
  sub    %r13d,%ebx
  movslq %r13d,%rbp
  shl    $0x2,%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <GetBlock@plt>
  movslq %eax,%r14
  movslq %ebx,%rdi
  shl    $0x2,%rdi
  mov    $0x0,%eax
  call   <GetBlock@plt>
  movslq %eax,%r15
  mov    %r13d,%edx
  lea    (%r14,%rdx,4),%rdi
  mov    %r14,%rdx
  mov    %r12,%rsi
  sub    %r14,%rsi
L9:
  mov    (%rsi,%rdx,1),%ecx
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L9
  test   %ebx,%ebx
  jle    L32
  cltq
  mov    %ebx,%edx
  lea    (%rax,%rdx,4),%rcx
  sub    %rax,%rbp
  add    %r12,%rbp
L22:
  mov    0x0(%rbp,%rax,1),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L22
L32:
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <SortIntegerArray>
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <SortIntegerArray>
  mov    %ebx,%r8d
  mov    %r15,%rcx
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <Merge@plt>
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <FreeBlock@plt>
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <FreeBlock@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void SortIntegerArray(int array[], int n) {
  int i, n1, n2;
  int *arr1, *arr2;
  if (n > 1) {
    n1 = n / 2;
    n2 = n - n1;
    arr1 = ((int *)GetBlock((n1) * sizeof(int)));
    arr2 = ((int *)GetBlock((n2) * sizeof(int)));
    for (i = 0; i < n1; i++)
      arr1[i] = array[i];
    for (i = 0; i < n2; i++)
      arr2[i] = array[n1 + i];
    SortIntegerArray(arr1, n1);
    SortIntegerArray(arr2, n2);
    Merge(array, arr1, n1, arr2, n2);
    FreeBlock(arr1);
    FreeBlock(arr2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SortIntegerArray>:
  endbr64
  cmp    $0x1,%esi
  jg     L6
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %esi,%r14d
  push   %r13
  sar    %r14d
  push   %r12
  movslq %r14d,%r15
  push   %rbp
  shl    $0x2,%r15
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %r15,%rdi
  sub    %r14d,%ebx
  sub    $0x8,%rsp
  call   <GetBlock@plt>
  movslq %ebx,%rdi
  movslq %eax,%r12
  shl    $0x2,%rdi
  xor    %eax,%eax
  call   <GetBlock@plt>
  mov    %rbp,%rcx
  movslq %eax,%r13
  mov    %r14d,%eax
  sub    %r12,%rcx
  lea    (%r12,%rax,4),%rsi
  mov    %r12,%rax
  nopl   0x0(%rax)
L16:
  mov    (%rcx,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L16
  test   %ebx,%ebx
  jle    L39
  mov    %ebx,%edx
  sub    %r13,%r15
  mov    %r13,%rax
  lea    0x0(%r13,%rdx,4),%rsi
  lea    0x0(%rbp,%r15,1),%rcx
  nopl   (%rax)
L29:
  mov    (%rcx,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L29
L39:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <SortIntegerArray>
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <SortIntegerArray>
  mov    %ebx,%r8d
  mov    %r13,%rcx
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <Merge@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <FreeBlock@plt>
  add    $0x8,%rsp
  mov    %r13,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <FreeBlock@plt>
```

assistant: ```c
void SortIntegerArray(int array[], int n) {
  int i, n1, n2;
  int *arr1, *arr2;
  if (n > 1) {
    n1 = n / 2;
    n2 = n - n1;
    arr1 = ((int *)GetBlock((n1) * sizeof(int)));
    arr2 = ((int *)GetBlock((n2) * sizeof(int)));
    for (i = 0; i < n1; i++)
      arr1[i] = array[i];
    for (i = 0; i < n2; i++)
      arr2[i] = array[n1 + i];
    SortIntegerArray(arr1, n1);
    SortIntegerArray(arr2, n2);
    Merge(array, arr1, n1, arr2, n2);
    FreeBlock(arr1);
    FreeBlock(arr2);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  jmp    L12
L20:
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  lea    D14(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L12:
  cmpl   $0xa,-0x14(%rbp)
  jle    L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D0
type_guessed: string

tool: D14: %03d.jpg

tool: D0: %s


assistant: ```c
int main(void) {
  char buffer[8];
  for (int i = 1; i <= 10; i++) {
    sprintf(buffer, "%03d.jpg", i);
    printf("%s\n", buffer);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
  mov    %rsp,%rbp
  lea    D9(%rip),%r13
  lea    D12(%rip),%r12
L15:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L15
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string

tool: D9: %03d.jpg

tool: D12: %s


assistant: ```c
int main(void) {
  char buffer[8];
  for (int i = 1; i <= 10; i++) {
    sprintf(buffer, "%03d.jpg", i);
    printf("%s\n", buffer);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L8:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D15
type: string

tool: D13: %03d.jpg

tool: D15: %s


assistant: ```c
int main(void) {
  char buffer[8];
  for (int i = 1; i <= 10; i++) {
    sprintf(buffer, "%03d.jpg", i);
    printf("%s\n", buffer);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L10:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: D1: %03d.jpg

tool: D14: %s


assistant: ```c
int main(void) {
  char buffer[8];
  for (int i = 1; i <= 10; i++) {
    sprintf(buffer, "%03d.jpg", i);
    printf("%s\n", buffer);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: %i 

assistant: ```c
void printArray(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%i ", a[i]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D5(%rip),%rbp
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: %i 

assistant: ```c
void printArray(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%i ", a[i]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: %i 

assistant: ```c
void printArray(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%i ", a[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D2: %i 

assistant: ```c
void printArray(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%i ", a[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<issquare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L38
  mov    $0x1,%eax
  jmp    L1
L38:
  movl   $0x1,-0x4(%rbp)
  jmp    L33
L10:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jae    L16
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L10
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  setne  %al
  movzbl %al,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int issquare(unsigned n) {
  unsigned i;
  if (n == 1)
    return 1;
  for (i = 1; i < n && n != i * i; ++i)
    ;
  return i != n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<issquare>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L16
  jbe    L26
L36:
  add    $0x1,%eax
  cmp    %eax,%edi
  je     L32
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jne    L36
  jmp    L40
L26:
  mov    $0x1,%eax
  jmp    L40
L32:
  mov    %edi,%eax
L40:
  cmp    %eax,%edi
  setne  %al
  movzbl %al,%eax
L16:
  ret
```

assistant: ```c
int issquare(unsigned n) {
  unsigned i;
  if (n == 1)
    return 1;
  for (i = 1; i < n && n != i * i; ++i)
    ;
  return i != n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<issquare>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L46
  ja     L1
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  je     L35
L1:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L40
L35:
  cmp    %eax,%edi
  setne  %al
  movzbl %al,%eax
L46:
  ret
L25:
  mov    $0x1,%eax
  jmp    L35
```

assistant: ```c
int issquare(unsigned n) {
  unsigned i;
  if (n == 1)
    return 1;
  for (i = 1; i < n && n != i * i; ++i)
    ;
  return i != n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<issquare>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L37
  ja     L3
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  je     L53
L3:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L4
L53:
  cmp    %eax,%edi
  setne  %al
  movzbl %al,%eax
L37:
  ret
L29:
  mov    $0x1,%eax
  jmp    L53
```

assistant: ```c
int issquare(unsigned n) {
  unsigned i;
  if (n == 1)
    return 1;
  for (i = 1; i < n && n != i * i; ++i)
    ;
  return i != n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<av_clip_int8_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0xffffff80,%eax
  mov    $0x0,%al
  test   %eax,%eax
  je     L9
  mov    -0x4(%rbp),%eax
  sar    $0x1f,%eax
  xor    $0x7f,%eax
  jmp    L17
L9:
  mov    -0x4(%rbp),%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int8_t av_clip_int8_c(int a) {
  if ((a + 0x80U) & ~0xFF)
    return (a >> 31) ^ 0x7F;
  else
    return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<av_clip_int8_c>:
  endbr64
  mov    %edi,%eax
  lea    0x80(%rdi),%ecx
  cltd
  xor    $0x7f,%edx
  test   $0xffffff00,%ecx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int8_t av_clip_int8_c(int a) {
  if ((a + 0x80U) & ~0xFF)
    return (a >> 31) ^ 0x7F;
  else
    return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<av_clip_int8_c>:
  endbr64
  mov    %edi,%eax
  lea    0x80(%rdi),%ecx
  cltd
  xor    $0x7f,%edx
  and    $0xffffff00,%ecx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int8_t av_clip_int8_c(int a) {
  if ((a + 0x80U) & ~0xFF)
    return (a >> 31) ^ 0x7F;
  else
    return a;
}
```