ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <validate@plt>
  test   %rax,%rax
  je     L64
  xor    %eax,%eax
  call   <init_solution@plt>
  lea    0x8(%rbx),%rdx
  mov    %rax,%rbp
  lea    0x48(%rax),%rdi
  nopl   (%rax)
L18:
  mov    (%rdx),%rsi
  mov    (%rax),%rcx
  add    $0x8,%rax
  add    $0x8,%rdx
  movzbl (%rsi),%esi
  mov    %sil,(%rcx)
  mov    -0x8(%rdx),%rsi
  mov    -0x8(%rax),%rcx
  movzbl 0x1(%rsi),%esi
  mov    %sil,0x1(%rcx)
  mov    -0x8(%rdx),%rsi
  mov    -0x8(%rax),%rcx
  movzbl 0x2(%rsi),%esi
  mov    %sil,0x2(%rcx)
  mov    -0x8(%rdx),%rsi
  mov    -0x8(%rax),%rcx
  movzbl 0x3(%rsi),%esi
  mov    %sil,0x3(%rcx)
  mov    -0x8(%rdx),%rsi
  mov    -0x8(%rax),%rcx
  movzbl 0x4(%rsi),%esi
  mov    %sil,0x4(%rcx)
  mov    -0x8(%rdx),%rsi
  mov    -0x8(%rax),%rcx
  movzbl 0x5(%rsi),%esi
  mov    %sil,0x5(%rcx)
  mov    -0x8(%rdx),%rsi
  mov    -0x8(%rax),%rcx
  movzbl 0x6(%rsi),%esi
  mov    %sil,0x6(%rcx)
  mov    -0x8(%rdx),%rsi
  mov    -0x8(%rax),%rcx
  movzbl 0x7(%rsi),%esi
  mov    %sil,0x7(%rcx)
  mov    -0x8(%rax),%rcx
  mov    -0x8(%rdx),%rsi
  movzbl 0x8(%rsi),%esi
  mov    %sil,0x8(%rcx)
  cmp    %rax,%rdi
  jne    L18
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x30,%ecx
  mov    %rbp,%rdi
  call   <solve@plt>
  cmpq   $0x0,0x0(%rbp)
  lea    D26(%rip),%r13
  lea    D12(%rip),%r12
  je     L26
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x0(%rbp),%rsi
  mov    $0x1,%ebx
  cmpb   $0x0,(%rsi)
  je     L61
  xchg   %ax,%ax
L23:
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    %r12,%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    0x0(%rbp),%rsi
  add    %rbx,%rsi
  add    $0x1,%rbx
  cmpb   $0x0,(%rsi)
  jne    L23
L61:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  add    $0x8,%rbp
  call   <write@plt>
  cmpq   $0x0,0x0(%rbp)
  jne    L7
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  mov    $0x6,%edx
  lea    D29(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L26
```

tool_calls: name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D29
data_type: string

tool: D26: 


tool: D12:  

tool: D29: Error


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int j;
  char **solution;
  ;
  if (validate(argc, argv, 0, 0)) {
    solution = init_solution();
    i = -1;
    while (++i < 9) {
      j = -1;
      while (++j < 9)
        solution[i][j] = argv[i + 1][j];
    }
    solve(solution, 0, 0, '0');
    i = -1;
    while (solution[++i]) {
      j = -1;
      while (solution[i][++j]) {
        write(1, &solution[i][j], 1);
        write(1, " ", 1);
      };
      write(1, "\n", 1);
    }
  } else
    write(1, "Error\n", 6);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: Sum = %d

assistant: ```c
void Sum(int a, int b) {
  int sum = a + b;
  printf("Sum = %d", sum);
}
```
user: What is the c source code of the assembly code below:

```asm
<Sum>:
  endbr64
  sub    $0x8,%rsp
  add    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: Sum = %d

assistant: ```c
void Sum(int a, int b) {
  int sum = a + b;
  printf("Sum = %d", sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Sum>:
  endbr64
  add    %edi,%esi
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: Sum = %d

assistant: ```c
void Sum(int a, int b) {
  int sum = a + b;
  printf("Sum = %d", sum);
}
```
user: What is the c source code of the assembly code below?

```asm
<Sum>:
  endbr64
  add    %edi,%esi
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: Sum = %d

assistant: ```c
void Sum(int a, int b) {
  int sum = a + b;
  printf("Sum = %d", sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x2,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
int d(int e) {
  struct {
    int f;
  } g = {1};
  int h;
  g = (typeof(g)){2};
}
```
user: What is the c source code of the assembly code below?

```asm
<d>:
  endbr64
  ret
```

assistant: ```c
int d(int e) {
  struct {
    int f;
  } g = {1};
  int h;
  g = (typeof(g)){2};
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d>:
  endbr64
  ret
```

assistant: ```c
int d(int e) {
  struct {
    int f;
  } g = {1};
  int h;
  g = (typeof(g)){2};
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<d>:
  endbr64
  ret
```

assistant: ```c
int d(int e) {
  struct {
    int f;
  } g = {1};
  int h;
  g = (typeof(g)){2};
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_kt_backslash_escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  test   %eax,%eax
  je     L129
  test   %eax,%eax
  js     L99
  cmp    $0x76,%eax
  jg     L99
  cmp    $0x30,%eax
  jl     L99
  sub    $0x30,%eax
  cmp    $0x46,%eax
  ja     L99
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x18(%rbp),%rax
  lea    -0x18(%rbp),%rcx
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %al,-0x1(%rbp)
  jmp    L132
  movb   $0x7,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L132
  movb   $0x8,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L132
  movb   $0x1b,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L132
  movb   $0xc,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L132
  movb   $0xa,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L132
  movb   $0xd,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L132
  movb   $0x9,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L132
  movb   $0xb,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L132
L129:
  movb   $0x5c,-0x1(%rbp)
  jmp    L132
L99:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  nop
L132:
  cmpq   $0x0,-0x20(%rbp)
  je     L4
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
L4:
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char _kt_backslash_escape(const char *string, const char **endp) {
  char c;
  switch (*string) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
    c = strtol(string, (char **)&string, 8);
    break;
  case 'a':
    c = '\a';
    string++;
    break;
  case 'b':
    c = '\b';
    string++;
    break;
  case 'e':
  case 'E':
    c = '\033';
    string++;
    break;
  case 'f':
    c = '\f';
    string++;
    break;
  case 'n':
    c = '\n';
    string++;
    break;
  case 'r':
    c = '\r';
    string++;
    break;
  case 't':
    c = '\t';
    string++;
    break;
  case 'v':
    c = '\v';
    string++;
    break;
  case '\0':
    c = '\\';
    break;
  default:
    c = *string++;
    break;
  };
  if (endp)
    *endp = string;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_kt_backslash_escape>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L90
  mov    %rdi,%rcx
  lea    -0x30(%rax),%edx
  cmp    $0x46,%dl
  ja     L126
  ja     L126
  movzbl %dl,%eax
  lea    D3(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    0x8(%rsp),%rsi
  mov    $0x8,%edx
  call   <strtol@plt>
L37:
  test   %rbx,%rbx
  je     L98
  mov    0x8(%rsp),%rdx
  mov    %rdx,(%rbx)
L98:
  add    $0x10,%rsp
  pop    %rbx
  ret
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  mov    $0x7,%eax
  jmp    L37
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  mov    $0x8,%eax
  jmp    L37
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  mov    $0x1b,%eax
  jmp    L37
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  mov    $0xc,%eax
  jmp    L37
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  mov    $0xa,%eax
  jmp    L37
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  mov    $0xd,%eax
  jmp    L37
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  mov    $0x9,%eax
  jmp    L37
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  mov    $0xb,%eax
  jmp    L37
L126:
  lea    0x1(%rcx),%rax
  mov    %rax,0x8(%rsp)
  movzbl (%rcx),%eax
  jmp    L37
L90:
  mov    $0x5c,%eax
  jmp    L37
```

assistant: ```c
char _kt_backslash_escape(const char *string, const char **endp) {
  char c;
  switch (*string) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
    c = strtol(string, (char **)&string, 8);
    break;
  case 'a':
    c = '\a';
    string++;
    break;
  case 'b':
    c = '\b';
    string++;
    break;
  case 'e':
  case 'E':
    c = '\033';
    string++;
    break;
  case 'f':
    c = '\f';
    string++;
    break;
  case 'n':
    c = '\n';
    string++;
    break;
  case 'r':
    c = '\r';
    string++;
    break;
  case 't':
    c = '\t';
    string++;
    break;
  case 'v':
    c = '\v';
    string++;
    break;
  case '\0':
    c = '\\';
    break;
  default:
    c = *string++;
    break;
  };
  if (endp)
    *endp = string;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_kt_backslash_escape>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  movzbl (%rdi),%eax
  mov    %rdi,0x8(%rsp)
  test   %al,%al
  je     L124
  sub    $0x30,%eax
  mov    %rdi,%r8
  cmp    $0x46,%al
  ja     L55
  lea    D1(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L55:
  lea    0x1(%r8),%rax
  mov    %rax,0x8(%rsp)
  movzbl (%r8),%eax
  nopl   (%rax)
L59:
  test   %rbx,%rbx
  je     L28
  mov    0x8(%rsp),%rdx
  mov    %rdx,(%rbx)
L28:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
  lea    0x8(%rsp),%rsi
  mov    $0x8,%edx
  call   <strtol@plt>
  jmp    L59
  nopl   0x0(%rax)
  add    $0x1,%r8
  mov    $0x1b,%eax
  mov    %r8,0x8(%rsp)
  jmp    L59
  add    $0x1,%r8
  mov    $0xc,%eax
  mov    %r8,0x8(%rsp)
  jmp    L59
  add    $0x1,%r8
  mov    $0x8,%eax
  mov    %r8,0x8(%rsp)
  jmp    L59
  add    $0x1,%r8
  mov    $0xb,%eax
  mov    %r8,0x8(%rsp)
  jmp    L59
  add    $0x1,%r8
  mov    $0xa,%eax
  mov    %r8,0x8(%rsp)
  jmp    L59
  add    $0x1,%r8
  mov    $0xd,%eax
  mov    %r8,0x8(%rsp)
  jmp    L59
  nopl   0x0(%rax,%rax,1)
  add    $0x1,%r8
  mov    $0x9,%eax
  mov    %r8,0x8(%rsp)
  jmp    L59
  nopl   0x0(%rax,%rax,1)
  add    $0x1,%r8
  mov    $0x7,%eax
  mov    %r8,0x8(%rsp)
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L124:
  mov    $0x5c,%eax
  jmp    L59
```

assistant: ```c
char _kt_backslash_escape(const char *string, const char **endp) {
  char c;
  switch (*string) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
    c = strtol(string, (char **)&string, 8);
    break;
  case 'a':
    c = '\a';
    string++;
    break;
  case 'b':
    c = '\b';
    string++;
    break;
  case 'e':
  case 'E':
    c = '\033';
    string++;
    break;
  case 'f':
    c = '\f';
    string++;
    break;
  case 'n':
    c = '\n';
    string++;
    break;
  case 'r':
    c = '\r';
    string++;
    break;
  case 't':
    c = '\t';
    string++;
    break;
  case 'v':
    c = '\v';
    string++;
    break;
  case '\0':
    c = '\\';
    break;
  default:
    c = *string++;
    break;
  };
  if (endp)
    *endp = string;
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_kt_backslash_escape>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  movzbl (%rdi),%eax
  mov    %rdi,0x8(%rsp)
  test   %al,%al
  je     L9
  sub    $0x30,%eax
  mov    %rdi,%r8
  cmp    $0x46,%al
  ja     L56
  lea    D9(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L56:
  lea    0x1(%r8),%rax
  mov    %rax,0x8(%rsp)
  movzbl (%r8),%eax
  nopl   (%rax)
L53:
  test   %rbx,%rbx
  je     L74
  mov    0x8(%rsp),%rdx
  mov    %rdx,(%rbx)
L74:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
  lea    0x8(%rsp),%rsi
  mov    $0x8,%edx
  call   <strtol@plt>
  jmp    L53
  nopl   0x0(%rax)
  add    $0x1,%r8
  mov    $0x1b,%eax
  mov    %r8,0x8(%rsp)
  jmp    L53
  add    $0x1,%r8
  mov    $0xc,%eax
  mov    %r8,0x8(%rsp)
  jmp    L53
  add    $0x1,%r8
  mov    $0x8,%eax
  mov    %r8,0x8(%rsp)
  jmp    L53
  add    $0x1,%r8
  mov    $0xb,%eax
  mov    %r8,0x8(%rsp)
  jmp    L53
  add    $0x1,%r8
  mov    $0xa,%eax
  mov    %r8,0x8(%rsp)
  jmp    L53
  add    $0x1,%r8
  mov    $0xd,%eax
  mov    %r8,0x8(%rsp)
  jmp    L53
  nopl   0x0(%rax,%rax,1)
  add    $0x1,%r8
  mov    $0x9,%eax
  mov    %r8,0x8(%rsp)
  jmp    L53
  nopl   0x0(%rax,%rax,1)
  add    $0x1,%r8
  mov    $0x7,%eax
  mov    %r8,0x8(%rsp)
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x5c,%eax
  jmp    L53
```

assistant: ```c
char _kt_backslash_escape(const char *string, const char **endp) {
  char c;
  switch (*string) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
    c = strtol(string, (char **)&string, 8);
    break;
  case 'a':
    c = '\a';
    string++;
    break;
  case 'b':
    c = '\b';
    string++;
    break;
  case 'e':
  case 'E':
    c = '\033';
    string++;
    break;
  case 'f':
    c = '\f';
    string++;
    break;
  case 'n':
    c = '\n';
    string++;
    break;
  case 'r':
    c = '\r';
    string++;
    break;
  case 't':
    c = '\t';
    string++;
    break;
  case 'v':
    c = '\v';
    string++;
    break;
  case '\0':
    c = '\\';
    break;
  default:
    c = *string++;
    break;
  };
  if (endp)
    *endp = string;
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x24(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x14(%rbp)
  movss  -0x18(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  addss  -0x10(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string

tool: D16: %f %f

tool: D10: %.4f


assistant: ```c
int main(void) {
  float x1, y1, x2, y2, potencia1, potencia2, total;
  scanf("%f %f", &x1, &y1);
  scanf("%f %f", &x2, &y2);
  potencia1 = (x1 - x2);
  potencia1 = pow(potencia1, 2);
  potencia2 = (y2 - y1);
  potencia2 = pow(potencia2, 2);
  total = sqrt(potencia1 + potencia2);
  printf("%.4f\n", total);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x24(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x18(%rsp),%xmm0
  subss  0x20(%rsp),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  movss  %xmm0,0xc(%rsp)
  movss  0x24(%rsp),%xmm0
  subss  0x1c(%rsp),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  addss  0xc(%rsp),%xmm0
  call   <sqrt@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string
name: retrieve_data
arguments: data_tag: D11
type: string

tool: D7: %f %f

tool: D11: %.4f


assistant: ```c
int main(void) {
  float x1, y1, x2, y2, potencia1, potencia2, total;
  scanf("%f %f", &x1, &y1);
  scanf("%f %f", &x2, &y2);
  potencia1 = (x1 - x2);
  potencia1 = pow(potencia1, 2);
  potencia2 = (y2 - y1);
  potencia2 = pow(potencia2, 2);
  total = sqrt(potencia1 + potencia2);
  printf("%.4f\n", total);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  lea    0x24(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x18(%rsp),%xmm0
  mov    $0x2,%edi
  subss  0x20(%rsp),%xmm0
  call   <pow@plt>
  mov    $0x2,%edi
  movss  %xmm0,0xc(%rsp)
  movss  0x24(%rsp),%xmm0
  subss  0x1c(%rsp),%xmm0
  call   <pow@plt>
  addss  0xc(%rsp),%xmm0
  call   <sqrt@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string

tool: D5: %f %f

tool: D7: %.4f


assistant: ```c
int main(void) {
  float x1, y1, x2, y2, potencia1, potencia2, total;
  scanf("%f %f", &x1, &y1);
  scanf("%f %f", &x2, &y2);
  potencia1 = (x1 - x2);
  potencia1 = pow(potencia1, 2);
  potencia2 = (y2 - y1);
  potencia2 = pow(potencia2, 2);
  total = sqrt(potencia1 + potencia2);
  printf("%.4f\n", total);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  lea    0x24(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x18(%rsp),%xmm0
  mov    $0x2,%edi
  subss  0x20(%rsp),%xmm0
  call   <pow@plt>
  mov    $0x2,%edi
  movss  %xmm0,0xc(%rsp)
  movss  0x24(%rsp),%xmm0
  subss  0x1c(%rsp),%xmm0
  call   <pow@plt>
  addss  0xc(%rsp),%xmm0
  call   <sqrt@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: D8: %f %f

tool: D3: %.4f


assistant: ```c
int main(void) {
  float x1, y1, x2, y2, potencia1, potencia2, total;
  scanf("%f %f", &x1, &y1);
  scanf("%f %f", &x2, &y2);
  potencia1 = (x1 - x2);
  potencia1 = pow(potencia1, 2);
  potencia2 = (y2 - y1);
  potencia2 = pow(potencia2, 2);
  total = sqrt(potencia1 + potencia2);
  printf("%.4f\n", total);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Heap_HeapSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  sar    %rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L10
L23:
  subq   $0x1,-0x18(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Heap_Sift@plt>
L10:
  cmpq   $0x0,-0x18(%rbp)
  jg     L23
  jmp    L27
L4:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  subq   $0x1,-0x10(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Heap_Sift@plt>
L27:
  cmpq   $0x0,-0x10(%rbp)
  jg     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void Heap_HeapSort(long long n, long long *a, long long a__len) {
  long long l, r, x;
  l = ((long long)(n) >> (1));
  r = n - 1;
  while (l > 0) {
    l -= 1;
    Heap_Sift(l, r, (void *)a, a__len);
  }
  while (r > 0) {
    x = a[0];
    a[0] = a[r];
    a[r] = x;
    r -= 1;
    Heap_Sift(l, r, (void *)a, a__len);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Heap_HeapSort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rdi,%r12
  sar    %r12
  lea    -0x1(%rdi),%rbx
  test   %r12,%r12
  jle    L6
L0:
  sub    $0x1,%r12
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <Heap_Sift@plt>
  test   %r12,%r12
  jne    L0
L6:
  test   %rbx,%rbx
  jle    L22
L3:
  mov    0x0(%rbp),%rax
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %rdx,0x0(%rbp)
  mov    %rax,0x0(%rbp,%rbx,8)
  sub    $0x1,%rbx
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <Heap_Sift@plt>
  test   %rbx,%rbx
  jne    L3
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void Heap_HeapSort(long long n, long long *a, long long a__len) {
  long long l, r, x;
  l = ((long long)(n) >> (1));
  r = n - 1;
  while (l > 0) {
    l -= 1;
    Heap_Sift(l, r, (void *)a, a__len);
  }
  while (r > 0) {
    x = a[0];
    a[0] = a[r];
    a[r] = x;
    r -= 1;
    Heap_Sift(l, r, (void *)a, a__len);
  }
}
```