ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<lwt_show_queue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L7
  cmpl   $0x2,-0x4(%rbp)
  jmp    L5
L7:
  nop
L5:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lwt_show_queue(int q) {
  switch (q) {
  case 1:
    ((void)0);
    break;
  case 2:
    ((void)0);
    break;
  case 3:
    ((void)0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lwt_show_queue>:
  endbr64
  ret
```

assistant: ```c
void lwt_show_queue(int q) {
  switch (q) {
  case 1:
    ((void)0);
    break;
  case 2:
    ((void)0);
    break;
  case 3:
    ((void)0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lwt_show_queue>:
  endbr64
  ret
```

assistant: ```c
void lwt_show_queue(int q) {
  switch (q) {
  case 1:
    ((void)0);
    break;
  case 2:
    ((void)0);
    break;
  case 3:
    ((void)0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lwt_show_queue>:
  endbr64
  ret
```

assistant: ```c
void lwt_show_queue(int q) {
  switch (q) {
  case 1:
    ((void)0);
    break;
  case 2:
    ((void)0);
    break;
  case 3:
    ((void)0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L92:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x15(%rbp)
  cmpb   $0x64,-0x15(%rbp)
  je     L118
  cmpb   $0x68,-0x15(%rbp)
  jne    L92
L118:
  cmpb   $0x64,-0x15(%rbp)
  jne    L32
L1:
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  js     L1
  mov    -0x14(%rbp),%eax
  cmp    $0xff,%eax
  jg     L1
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  js     L1
  mov    -0x10(%rbp),%eax
  cmp    $0xff,%eax
  jg     L1
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L1
  mov    -0xc(%rbp),%eax
  cmp    $0xff,%eax
  jg     L1
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L101
L32:
  cmpb   $0x68,-0x15(%rbp)
  jne    L64
  mov    $0x0,%eax
  call   <conv_h_to_d@plt>
  mov    $0x0,%eax
  jmp    L101
L64:
  mov    $0x0,%eax
L101:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string
name: read_data
arguments: label: D7
type_infered: string

tool: D9: %d, %d, %d

tool: D7: #%x%x%x


assistant: ```c
int main() {
  int r;
  int g;
  int b;
  char a;
  do {
    a = getchar();
  } while (a != 'd' && a != 'h');
  if (a == 'd') {
    do {
      scanf("%d, %d, %d", &r, &g, &b);
    } while (r < 0 || r > 255 || g < 0 || g > 255 || b < 0 || b > 255);
    printf("#%x%x%x\n", r, g, b);
    return 0;
  }
  if (a == 'h') {
    conv_h_to_d();
    return 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    -0x64(%rax),%edx
  test   $0xfb,%dl
  jne    L9
  cmp    $0x64,%al
  je     L40
  cmp    $0x68,%al
  je     L13
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L40:
  lea    D15(%rip),%rbx
L49:
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    $0xff,%esi
  ja     L49
  mov    0x10(%rsp),%edx
  cmp    $0xff,%edx
  ja     L49
  mov    0x14(%rsp),%ecx
  cmp    $0xff,%ecx
  ja     L49
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L13:
  mov    $0x0,%eax
  call   <conv_h_to_d@plt>
  jmp    L4
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D11
type_infered: string

tool: D15: %d, %d, %d

tool: D11: #%x%x%x


assistant: ```c
int main() {
  int r;
  int g;
  int b;
  char a;
  do {
    a = getchar();
  } while (a != 'd' && a != 'h');
  if (a == 'd') {
    do {
      scanf("%d, %d, %d", &r, &g, &b);
    } while (r < 0 || r > 255 || g < 0 || g > 255 || b < 0 || b > 255);
    printf("#%x%x%x\n", r, g, b);
    return 0;
  }
  if (a == 'h') {
    conv_h_to_d();
    return 0;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xchg   %ax,%ax
L5:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    -0x64(%rax),%edx
  and    $0xfb,%edx
  jne    L5
  cmp    $0x64,%al
  jne    L25
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  lea    D13(%rip),%rbx
  nopl   0x0(%rax)
L41:
  mov    %rbp,%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    $0xff,%esi
  ja     L41
  mov    0x10(%rsp),%edx
  cmp    $0xff,%edx
  ja     L41
  mov    0x14(%rsp),%ecx
  cmp    $0xff,%ecx
  ja     L41
  lea    D16(%rip),%rdi
  call   <printf@plt>
L52:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  xor    %eax,%eax
  call   <conv_h_to_d@plt>
  jmp    L52
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D13: %d, %d, %d

tool: D16: #%x%x%x


assistant: ```c
int main() {
  int r;
  int g;
  int b;
  char a;
  do {
    a = getchar();
  } while (a != 'd' && a != 'h');
  if (a == 'd') {
    do {
      scanf("%d, %d, %d", &r, &g, &b);
    } while (r < 0 || r > 255 || g < 0 || g > 255 || b < 0 || b > 255);
    printf("#%x%x%x\n", r, g, b);
    return 0;
  }
  if (a == 'h') {
    conv_h_to_d();
    return 0;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xchg   %ax,%ax
L15:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    -0x64(%rax),%edx
  and    $0xfb,%edx
  jne    L15
  cmp    $0x64,%al
  jne    L48
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  lea    D4(%rip),%rbx
  nopl   0x0(%rax)
L65:
  mov    %rbp,%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    $0xff,%esi
  ja     L65
  mov    0x10(%rsp),%edx
  cmp    $0xff,%edx
  ja     L65
  mov    0x14(%rsp),%ecx
  cmp    $0xff,%ecx
  ja     L65
  lea    D5(%rip),%rdi
  call   <printf@plt>
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  xor    %eax,%eax
  call   <conv_h_to_d@plt>
  jmp    L38
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string
name: read_data
arguments: tag: D5
data_type: string

tool: D4: %d, %d, %d

tool: D5: #%x%x%x


assistant: ```c
int main() {
  int r;
  int g;
  int b;
  char a;
  do {
    a = getchar();
  } while (a != 'd' && a != 'h');
  if (a == 'd') {
    do {
      scanf("%d, %d, %d", &r, &g, &b);
    } while (r < 0 || r > 255 || g < 0 || g > 255 || b < 0 || b > 255);
    printf("#%x%x%x\n", r, g, b);
    return 0;
  }
  if (a == 'h') {
    conv_h_to_d();
    return 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__test_and_change_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x3f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x3f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x6,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  xor    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int __test_and_change_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % ((int)sizeof(unsigned long) * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / ((int)sizeof(unsigned long) * 8));
  unsigned long old = *p;
  *p = old ^ mask;
  return (old & mask) != 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__test_and_change_bit>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%edx
  shl    %cl,%rdx
  lea    0x3f(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x6,%eax
  cltq
  lea    (%rsi,%rax,8),%rcx
  mov    (%rcx),%rax
  mov    %rdx,%rsi
  xor    %rax,%rsi
  mov    %rsi,(%rcx)
  test   %rax,%rdx
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int __test_and_change_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % ((int)sizeof(unsigned long) * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / ((int)sizeof(unsigned long) * 8));
  unsigned long old = *p;
  *p = old ^ mask;
  return (old & mask) != 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__test_and_change_bit>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%edx
  lea    0x3f(%rdi),%eax
  shl    %cl,%rdx
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x6,%eax
  cltq
  lea    (%rsi,%rax,8),%rcx
  mov    %rdx,%rsi
  mov    (%rcx),%rax
  xor    %rax,%rsi
  test   %rax,%rdx
  setne  %al
  mov    %rsi,(%rcx)
  movzbl %al,%eax
  ret
```

assistant: ```c
int __test_and_change_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % ((int)sizeof(unsigned long) * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / ((int)sizeof(unsigned long) * 8));
  unsigned long old = *p;
  *p = old ^ mask;
  return (old & mask) != 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__test_and_change_bit>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%edx
  lea    0x3f(%rdi),%eax
  shl    %cl,%rdx
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x6,%eax
  cltq
  lea    (%rsi,%rax,8),%rcx
  mov    %rdx,%rsi
  mov    (%rcx),%rax
  xor    %rax,%rsi
  test   %rax,%rdx
  setne  %al
  mov    %rsi,(%rcx)
  movzbl %al,%eax
  ret
```

assistant: ```c
int __test_and_change_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % ((int)sizeof(unsigned long) * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / ((int)sizeof(unsigned long) * 8));
  unsigned long old = *p;
  *p = old ^ mask;
  return (old & mask) != 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ap_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x14(%rbp),%eax
  mov    %al,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xa(%rbp),%rax
  mov    %rax,%rdi
  call   <ap_str@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void ap_char(char c) {
  char buf[2];
  buf[0] = c;
  buf[1] = '\0';
  ap_str(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ap_char>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%rdi
  call   <ap_str@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ap_char(char c) {
  char buf[2];
  buf[0] = c;
  buf[1] = '\0';
  ap_str(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ap_char>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x6(%rsp)
  lea    0x6(%rsp),%rdi
  movb   $0x0,0x7(%rsp)
  call   <ap_str@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ap_char(char c) {
  char buf[2];
  buf[0] = c;
  buf[1] = '\0';
  ap_str(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ap_char>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x6(%rsp)
  lea    0x6(%rsp),%rdi
  movb   $0x0,0x7(%rsp)
  call   <ap_str@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ap_char(char c) {
  char buf[2];
  buf[0] = c;
  buf[1] = '\0';
  ap_str(buf);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L10:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  sub    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void substring(char *src, int stripFromBewb, int stripFromAss, char *dest) {
  for (int destIndex = 0; stripFromBewb <= (strlen(src) - 1 - stripFromAss); stripFromBewb++, destIndex++)
    dest[destIndex] = src[stripFromBewb];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<substring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%r12d
  movslq %esi,%rsi
  mov    %rsi,%rbx
  sub    %rsi,%rcx
  mov    %rcx,%r13
  jmp    L14
L18:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  sub    %r12d,%eax
  cmp    %ebx,%eax
  jge    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void substring(char *src, int stripFromBewb, int stripFromAss, char *dest) {
  for (int destIndex = 0; stripFromBewb <= (strlen(src) - 1 - stripFromAss); stripFromBewb++, destIndex++)
    dest[destIndex] = src[stripFromBewb];
}
```
user: What is the c source code of the assembly code below:

```asm
<substring>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    %rbx,%rcx
  mov    %rcx,%r12
  sub    $0x8,%rsp
  jmp    L12
  xchg   %ax,%ax
L4:
  movzbl 0x0(%r13,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L12:
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jge    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void substring(char *src, int stripFromBewb, int stripFromAss, char *dest) {
  for (int destIndex = 0; stripFromBewb <= (strlen(src) - 1 - stripFromAss); stripFromBewb++, destIndex++)
    dest[destIndex] = src[stripFromBewb];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<substring>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    %rbx,%rcx
  mov    %rcx,%r12
  sub    $0x8,%rsp
  jmp    L18
  xchg   %ax,%ax
L5:
  movzbl 0x0(%r13,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L18:
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jge    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void substring(char *src, int stripFromBewb, int stripFromAss, char *dest) {
  for (int destIndex = 0; stripFromBewb <= (strlen(src) - 1 - stripFromAss); stripFromBewb++, destIndex++)
    dest[destIndex] = src[stripFromBewb];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int Free(void *devPtr) {
  free(devPtr);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Free>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Free(void *devPtr) {
  free(devPtr);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Free>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Free(void *devPtr) {
  free(devPtr);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Free>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Free(void *devPtr) {
  free(devPtr);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<connect_retry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L37:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
  jmp    L29
L8:
  cmpl   $0x40,-0x4(%rbp)
  jg     L44
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
L44:
  shll   -0x4(%rbp)
L6:
  cmpl   $0x80,-0x4(%rbp)
  jle    L37
  mov    $0xffffffff,%eax
L29:
  leave
  ret
```

assistant: ```c
int connect_retry(int sockfd, const struct sockaddr *addr, socklen_t alen) {
  int nsec;
  for (nsec = 1; nsec <= 128; nsec <<= 1) {
    if (connect(sockfd, addr, alen) == 0) {
      return (0);
    }
    if (nsec <= 128 / 2) {
      sleep(nsec);
    }
  }
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<connect_retry>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x1,%ebx
  jmp    L18
L54:
  add    %ebx,%ebx
  cmp    $0x80,%ebx
  jg     L23
L18:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <connect@plt>
  test   %rax,%rax
  je     L13
  cmp    $0x40,%ebx
  jg     L54
  mov    %ebx,%edi
  call   <sleep@plt>
  jmp    L54
L23:
  mov    $0xffffffff,%eax
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    $0x0,%eax
  jmp    L35
```

assistant: ```c
int connect_retry(int sockfd, const struct sockaddr *addr, socklen_t alen) {
  int nsec;
  for (nsec = 1; nsec <= 128; nsec <<= 1) {
    if (connect(sockfd, addr, alen) == 0) {
      return (0);
    }
    if (nsec <= 128 / 2) {
      sleep(nsec);
    }
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<connect_retry>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <connect@plt>
  test   %rax,%rax
  je     L39
  lea    0x0(%rbp,%rbp,1),%ebx
  cmp    $0x40,%ebp
  jle    L0
  cmp    $0x80,%ebx
  jg     L28
  mov    %ebx,%ebp
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L28:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L0:
  mov    %ebp,%edi
  mov    %ebx,%ebp
  call   <sleep@plt>
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L39:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int connect_retry(int sockfd, const struct sockaddr *addr, socklen_t alen) {
  int nsec;
  for (nsec = 1; nsec <= 128; nsec <<= 1) {
    if (connect(sockfd, addr, alen) == 0) {
      return (0);
    }
    if (nsec <= 128 / 2) {
      sleep(nsec);
    }
  }
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<connect_retry>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <connect@plt>
  test   %rax,%rax
  je     L28
  lea    0x0(%rbp,%rbp,1),%ebx
  cmp    $0x40,%ebp
  jle    L8
  cmp    $0x80,%ebx
  jg     L25
  mov    %ebx,%ebp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L25:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L8:
  mov    %ebp,%edi
  mov    %ebx,%ebp
  call   <sleep@plt>
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L28:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int connect_retry(int sockfd, const struct sockaddr *addr, socklen_t alen) {
  int nsec;
  for (nsec = 1; nsec <= 128; nsec <<= 1) {
    if (connect(sockfd, addr, alen) == 0) {
      return (0);
    }
    if (nsec <= 128 / 2) {
      sleep(nsec);
    }
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movl   $0x4,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L5:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L5
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0xc(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string
name: disassemble_data
arguments: label: D1
type: string

tool: D7: %f

tool: D1: %f


assistant: ```c
int main(void) {
  float input;
  float sum = 0;
  int qttNums = 4;
  for (int i = 0; i < qttNums; i++) {
    scanf("%f", &input);
    sum += input;
  }
  printf("%f\n", (sum / qttNums));
  return 0;
}
```