ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  jne    L30
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L30:
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <child@plt>
  jmp    L32
L39:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <parent@plt>
L32:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: pipe

assistant: ```c
int main(int argc, char **argv) {
  int fds[2];
  if (pipe(fds) == -1) {
    perror("pipe");
    exit(1);
  }
  if (fork() == 0) {
    child(fds[0]);
  } else {
    parent(fds[1]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  je     L45
L2:
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L11
  mov    (%rsp),%edi
  call   <child@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L45:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
L11:
  mov    0x4(%rsp),%edi
  call   <parent@plt>
  jmp    L26
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: pipe

assistant: ```c
int main(int argc, char **argv) {
  int fds[2];
  if (pipe(fds) == -1) {
    perror("pipe");
    exit(1);
  }
  if (fork() == 0) {
    child(fds[0]);
  } else {
    parent(fds[1]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  je     L41
L28:
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L13
  mov    (%rsp),%edi
  call   <child@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L13:
  mov    0x4(%rsp),%edi
  call   <parent@plt>
  jmp    L17
L41:
  lea    D8(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L28
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: pipe

assistant: ```c
int main(int argc, char **argv) {
  int fds[2];
  if (pipe(fds) == -1) {
    perror("pipe");
    exit(1);
  }
  if (fork() == 0) {
    child(fds[0]);
  } else {
    parent(fds[1]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  je     L20
L45:
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L37
  mov    (%rsp),%edi
  call   <child@plt>
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L37:
  mov    0x4(%rsp),%edi
  call   <parent@plt>
  jmp    L38
L20:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L45
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string

tool: D7: pipe

assistant: ```c
int main(int argc, char **argv) {
  int fds[2];
  if (pipe(fds) == -1) {
    perror("pipe");
    exit(1);
  }
  if (fork() == 0) {
    child(fds[0]);
  } else {
    parent(fds[1]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<edflib_remove_padding_trailing_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L3
L82:
  movl   $0x0,-0x4(%rbp)
L68:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
  jmp    L3
L75:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  jmp    L68
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L82
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L26
L39:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L53
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x0,-0x4(%rbp)
  jg     L39
  jmp    L70
L53:
  nop
L70:
  nop
  leave
  ret
```

assistant: ```c
void edflib_remove_padding_trailing_spaces(char *str) {
  int i;
  while (str[0] == ' ') {
    for (i = 0;; i++) {
      if (str[i] == 0)
        break;
      str[i] = str[i + 1];
    }
  }
  for (i = strlen(str); i > 0; i--) {
    if (str[i - 1] == ' ')
      str[i - 1] = 0;
    else
      break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<edflib_remove_padding_trailing_spaces>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rcx
  mov    $0x0,%edx
  mov    $0x0,%eax
  mov    $0x0,%esi
  cmpb   $0x20,(%rdi)
  je     L21
L53:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  jle    L62
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x2(%rbx,%rax,1),%rax
  lea    -0x1(%rcx),%ecx
  sub    %rcx,%rax
L36:
  cmpb   $0x20,(%rdx)
  jne    L62
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L36
L62:
  pop    %rbx
  ret
L43:
  mov    %rbx,%rcx
  mov    $0x0,%edx
  mov    %rsi,%rax
L21:
  movzbl 0x1(%rbx,%rax,1),%eax
  mov    %al,(%rcx)
  add    $0x1,%edx
  movslq %edx,%rax
  lea    (%rbx,%rax,1),%rcx
  cmpb   $0x0,(%rcx)
  jne    L21
  cmpb   $0x20,(%rbx)
  je     L43
  jmp    L53
```

assistant: ```c
void edflib_remove_padding_trailing_spaces(char *str) {
  int i;
  while (str[0] == ' ') {
    for (i = 0;; i++) {
      if (str[i] == 0)
        break;
      str[i] = str[i + 1];
    }
  }
  for (i = strlen(str); i > 0; i--) {
    if (str[i - 1] == ' ')
      str[i - 1] = 0;
    else
      break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<edflib_remove_padding_trailing_spaces>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  xor    %eax,%eax
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbx
  mov    %rdi,%rcx
  jne    L56
  nopl   0x0(%rax)
L26:
  movzbl 0x1(%rbx,%rax,1),%eax
  add    $0x1,%edx
  mov    %al,(%rcx)
  movslq %edx,%rax
  lea    (%rbx,%rax,1),%rcx
  cmpb   $0x0,(%rcx)
  jne    L26
  cmpb   $0x20,(%rbx)
  jne    L56
  mov    %rbx,%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L26
  nopl   0x0(%rax)
L56:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  jle    L8
  cltq
  sub    $0x1,%ecx
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x2(%rbx,%rax,1),%rax
  sub    %rcx,%rax
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L46:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  je     L8
L78:
  cmpb   $0x20,(%rdx)
  je     L46
L8:
  pop    %rbx
  ret
```

assistant: ```c
void edflib_remove_padding_trailing_spaces(char *str) {
  int i;
  while (str[0] == ' ') {
    for (i = 0;; i++) {
      if (str[i] == 0)
        break;
      str[i] = str[i + 1];
    }
  }
  for (i = strlen(str); i > 0; i--) {
    if (str[i - 1] == ' ')
      str[i - 1] = 0;
    else
      break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<edflib_remove_padding_trailing_spaces>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  xor    %eax,%eax
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbx
  mov    %rdi,%rcx
  jne    L25
  nopl   0x0(%rax)
L35:
  movzbl 0x1(%rbx,%rax,1),%eax
  add    $0x1,%edx
  mov    %al,(%rcx)
  movslq %edx,%rax
  lea    (%rbx,%rax,1),%rcx
  cmpb   $0x0,(%rcx)
  jne    L35
  cmpb   $0x20,(%rbx)
  jne    L25
  mov    %rbx,%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L35
  nopl   0x0(%rax)
L25:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  jle    L7
  cltq
  sub    $0x1,%ecx
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x2(%rbx,%rax,1),%rax
  sub    %rcx,%rax
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L59:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  je     L7
L78:
  cmpb   $0x20,(%rdx)
  je     L59
L7:
  pop    %rbx
  ret
```

assistant: ```c
void edflib_remove_padding_trailing_spaces(char *str) {
  int i;
  while (str[0] == ' ') {
    for (i = 0;; i++) {
      if (str[i] == 0)
        break;
      str[i] = str[i + 1];
    }
  }
  for (i = strlen(str); i > 0; i--) {
    if (str[i - 1] == ' ')
      str[i - 1] = 0;
    else
      break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rbx
  mov    -0x30(%rbp),%r12
  cmpq   $0x0,-0x38(%rbp)
  je     L47
  jmp    L27
L0:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L27
  mov    -0x14(%rbp),%eax
  jmp    L10
L27:
  mov    -0x38(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  test   %rax,%rax
  jne    L0
L47:
  mov    $0x0,%eax
L10:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  register unsigned const char *p1 = s1, *p2 = s2;
  int d;
  if (n)
    while (n-- > 0) {
      d = *p1++ - *p2++;
      if (d != 0)
        return d;
    }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcmp>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L7
  mov    $0x0,%ecx
L1:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  jne    L7
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L1
L7:
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  register unsigned const char *p1 = s1, *p2 = s2;
  int d;
  if (n)
    while (n-- > 0) {
      d = *p1++ - *p2++;
      if (d != 0)
        return d;
    }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L4
  xor    %ecx,%ecx
  nopl   (%rax)
L18:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  jne    L4
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L18
L4:
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  register unsigned const char *p1 = s1, *p2 = s2;
  int d;
  if (n)
    while (n-- > 0) {
      d = *p1++ - *p2++;
      if (d != 0)
        return d;
    }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memcmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L4
  xor    %ecx,%ecx
  nopl   (%rax)
L22:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  jne    L4
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L22
L4:
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  register unsigned const char *p1 = s1, *p2 = s2;
  int d;
  if (n)
    while (n-- > 0) {
      d = *p1++ - *p2++;
      if (d != 0)
        return d;
    }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0xc(%rbp)
  movl   $0x7,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: %i

assistant: ```c
int main() {
  int myNumber = 5;
  int mySecondNumber = 7;
  int myThirdNumber = myNumber + mySecondNumber;
  printf("%i", myThirdNumber);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: %i

assistant: ```c
int main() {
  int myNumber = 5;
  int mySecondNumber = 7;
  int myThirdNumber = myNumber + mySecondNumber;
  printf("%i", myThirdNumber);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: %i

assistant: ```c
int main() {
  int myNumber = 5;
  int mySecondNumber = 7;
  int myThirdNumber = myNumber + mySecondNumber;
  printf("%i", myThirdNumber);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D4: %i

assistant: ```c
int main() {
  int myNumber = 5;
  int mySecondNumber = 7;
  int myThirdNumber = myNumber + mySecondNumber;
  printf("%i", myThirdNumber);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L16
L1:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jg     L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type_guessed: string
name: read_data
arguments: data_tag: D17
type_guessed: string

tool: D14: %d

tool: D17: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int t;
  scanf("%d", &t);
  int n;
  for (; t > 0; t--) {
    scanf("%d", &n);
    printf("%d\n", n * (n - 1) / 2);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L1
  lea    0x4(%rsp),%r12
  lea    D27(%rip),%rbp
  lea    D25(%rip),%rbx
L5:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  lea    -0x1(%rdx),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jg     L5
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D25
datatype: string

tool: D27: %d

tool: D25: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int t;
  scanf("%d", &t);
  int n;
  for (; t > 0; t--) {
    scanf("%d", &n);
    printf("%d\n", n * (n - 1) / 2);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L29
  lea    0x4(%rsp),%r12
  lea    D18(%rip),%rbp
  nopl   0x0(%rax)
L14:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    %rbp,%rdi
  lea    -0x1(%rdx),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  call   <printf@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jg     L14
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D1: %d

tool: D18: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int t;
  scanf("%d", &t);
  int n;
  for (; t > 0; t--) {
    scanf("%d", &n);
    printf("%d\n", n * (n - 1) / 2);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L15
  lea    0x4(%rsp),%r12
  lea    D19(%rip),%rbp
  nopl   0x0(%rax)
L18:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    %rbp,%rdi
  lea    -0x1(%rdx),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  call   <printf@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jg     L18
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D19
datatype: string

tool: D1: %d

tool: D19: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int t;
  scanf("%d", &t);
  int n;
  for (; t > 0; t--) {
    scanf("%d", &n);
    printf("%d\n", n * (n - 1) / 2);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jtag_instruction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x80030003,(%rax)
  mov    -0xc(%rbp),%eax
  or     $0x40090000,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  movl   $0x80010001,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void jtag_instruction(volatile uint32_t *host, uint32_t inst) {
  host[0] = 0x80000000 | (3 << 16) | 0x03;
  host[0] = 0x40000000 | (9 << 16) | inst;
  host[0] = 0x80000000 | (1 << 16) | 0x01;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jtag_instruction>:
  endbr64
  movl   $0x80030003,(%rdi)
  or     $0x40090000,%esi
  mov    %esi,(%rdi)
  movl   $0x80010001,(%rdi)
  ret
```

assistant: ```c
void jtag_instruction(volatile uint32_t *host, uint32_t inst) {
  host[0] = 0x80000000 | (3 << 16) | 0x03;
  host[0] = 0x40000000 | (9 << 16) | inst;
  host[0] = 0x80000000 | (1 << 16) | 0x01;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jtag_instruction>:
  endbr64
  or     $0x40090000,%esi
  movl   $0x80030003,(%rdi)
  mov    %esi,(%rdi)
  movl   $0x80010001,(%rdi)
  ret
```

assistant: ```c
void jtag_instruction(volatile uint32_t *host, uint32_t inst) {
  host[0] = 0x80000000 | (3 << 16) | 0x03;
  host[0] = 0x40000000 | (9 << 16) | inst;
  host[0] = 0x80000000 | (1 << 16) | 0x01;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<allocateArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L6
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
L6:
  nop
  leave
  ret
```

assistant: ```c
void allocateArray(int **array, int size, int value) {
  *array = (int *)malloc(size * sizeof(int));
  if (*array != NULL) {
    for (int i = 0; i < size; i++) {
      *(*array + i) = value;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<allocateArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L21
  test   %ebx,%ebx
  jle    L21
  mov    %ebx,%ecx
  shl    $0x2,%rcx
  mov    $0x0,%eax
L16:
  mov    0x0(%rbp),%rdx
  mov    %r12d,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L16
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void allocateArray(int **array, int size, int value) {
  *array = (int *)malloc(size * sizeof(int));
  if (*array != NULL) {
    for (int i = 0; i < size; i++) {
      *(*array + i) = value;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<allocateArray>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0x0(,%rbp,4),%edi
  mov    %edx,%ebx
  call   <malloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L26
  test   %ebp,%ebp
  jle    L26
  lea    (%rax,%rbp,4),%rdx
  nopl   0x0(%rax)
L27:
  mov    %ebx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L27
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void allocateArray(int **array, int size, int value) {
  *array = (int *)malloc(size * sizeof(int));
  if (*array != NULL) {
    for (int i = 0; i < size; i++) {
      *(*array + i) = value;
    }
  }
}
```