ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<open_fifo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <path@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1b6,%esi
  mov    %rax,%rdi
  call   <mkfifo@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <check@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <check@plt>
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string
name: read_data
arguments: label: D14
type_infered: string

tool: D8: mkfifo

tool: D14: open

assistant: ```c
int open_fifo(char *base, int oflag) {
  char *filename = path(base);
  check("mkfifo", mkfifo(filename, 0666));
  return check("open", open(filename, oflag));
}
```
user: What is the c source code of the assembly code below?

```asm
<open_fifo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  call   <path@plt>
  mov    %rax,%rbx
  mov    $0x1b6,%esi
  mov    %rax,%rdi
  call   <mkfifo@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <check@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <open@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <check@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string
name: read_data
arguments: tag: D5
data_type: string

tool: D2: mkfifo

tool: D5: open

assistant: ```c
int open_fifo(char *base, int oflag) {
  char *filename = path(base);
  check("mkfifo", mkfifo(filename, 0666));
  return check("open", open(filename, oflag));
}
```
user: What is the c source code of the assembly code below:

```asm
<open_fifo>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <path@plt>
  mov    $0x1b6,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <mkfifo@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <check@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <open@plt>
  add    $0x8,%rsp
  lea    D4(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    10b0 <check@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string

tool: D7: mkfifo

tool: D4: open

assistant: ```c
int open_fifo(char *base, int oflag) {
  char *filename = path(base);
  check("mkfifo", mkfifo(filename, 0666));
  return check("open", open(filename, oflag));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<open_fifo>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <path@plt>
  mov    $0x1b6,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <mkfifo@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <check@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <open@plt>
  add    $0x8,%rsp
  lea    D1(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    10b0 <check@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D3: mkfifo

tool: D1: open

assistant: ```c
int open_fifo(char *base, int oflag) {
  char *filename = path(base);
  check("mkfifo", mkfifo(filename, 0666));
  return check("open", open(filename, oflag));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Q_strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Q_strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  jmp    L25
L35:
  subq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L25
  mov    -0x18(%rbp),%rax
  jmp    L7
L25:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L35
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
char *Q_strrchr(const char *s, char c) {
  int len = Q_strlen(s);
  s += len;
  while (len--) {
    if (*--s == c)
      return (char *)s;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Q_strrchr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <Q_strlen@plt>
  mov    %eax,%edx
  cltq
  add    %rbx,%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  sub    %rcx,%rdx
L17:
  cmp    %rdx,%rax
  je     L20
  sub    $0x1,%rax
  cmp    %bpl,(%rax)
  jne    L17
  jmp    L5
L20:
  mov    $0x0,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *Q_strrchr(const char *s, char c) {
  int len = Q_strlen(s);
  s += len;
  while (len--) {
    if (*--s == c)
      return (char *)s;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Q_strrchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <Q_strlen@plt>
  mov    %eax,%edx
  cltq
  add    %rbx,%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  sub    %rcx,%rdx
  jmp    L13
  nopl   (%rax)
L26:
  sub    $0x1,%rax
  cmp    %bpl,(%rax)
  je     L25
L13:
  cmp    %rdx,%rax
  jne    L26
  xor    %eax,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *Q_strrchr(const char *s, char c) {
  int len = Q_strlen(s);
  s += len;
  while (len--) {
    if (*--s == c)
      return (char *)s;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Q_strrchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <Q_strlen@plt>
  mov    %eax,%edx
  cltq
  add    %rbx,%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  sub    %rcx,%rdx
  jmp    L4
  nopl   (%rax)
L27:
  sub    $0x1,%rax
  cmp    %bpl,(%rax)
  je     L11
L4:
  cmp    %rdx,%rax
  jne    L27
  xor    %eax,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *Q_strrchr(const char *s, char c) {
  int len = Q_strlen(s);
  s += len;
  while (len--) {
    if (*--s == c)
      return (char *)s;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<aes_sub_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L26
L27:
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L35:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_aes_sub_bytes@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,(%rbx,%rdx,1)
  addl   $0x1,-0x14(%rbp)
L5:
  cmpl   $0x3,-0x14(%rbp)
  jle    L35
  addl   $0x1,-0x18(%rbp)
L26:
  cmpl   $0x3,-0x18(%rbp)
  jle    L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int aes_sub_bytes(const int box[][16], char state[][4]) {
  int i;
  int j;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      state[i][j] = _aes_sub_bytes(box, state[i][j]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aes_sub_bytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  lea    0x4(%rsi),%rbp
  lea    0x14(%rsi),%r13
L18:
  lea    -0x4(%rbp),%rbx
L9:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <_aes_sub_bytes@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L18
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int aes_sub_bytes(const int box[][16], char state[][4]) {
  int i;
  int j;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      state[i][j] = _aes_sub_bytes(box, state[i][j]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aes_sub_bytes>:
  endbr64
  push   %r13
  lea    0x14(%rsi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x4(%rsi),%rbp
  push   %rbx
  sub    $0x8,%rsp
L2:
  lea    -0x4(%rbp),%rbx
L8:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <_aes_sub_bytes@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L8
  lea    0x4(%rbx),%rbp
  cmp    %r13,%rbp
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int aes_sub_bytes(const int box[][16], char state[][4]) {
  int i;
  int j;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      state[i][j] = _aes_sub_bytes(box, state[i][j]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<aes_sub_bytes>:
  endbr64
  push   %r13
  lea    0x14(%rsi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x4(%rsi),%rbp
  push   %rbx
  sub    $0x8,%rsp
L15:
  lea    -0x4(%rbp),%rbx
L7:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <_aes_sub_bytes@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L7
  lea    0x4(%rbx),%rbp
  cmp    %r13,%rbp
  jne    L15
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int aes_sub_bytes(const int box[][16], char state[][4]) {
  int i;
  int j;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      state[i][j] = _aes_sub_bytes(box, state[i][j]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<manual_dcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void manual_dcopy(const int n, const double *x, double *y) {
  for (int i = 0; i < n; ++i) {
    y[i] = x[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<manual_dcopy>:
  endbr64
  test   %edi,%edi
  jle    L8
  mov    %edi,%edi
  mov    $0x0,%eax
L2:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L2
L8:
  ret
```

assistant: ```c
void manual_dcopy(const int n, const double *x, double *y) {
  for (int i = 0; i < n; ++i) {
    y[i] = x[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<manual_dcopy>:
  endbr64
  test   %edi,%edi
  jle    L13
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L3:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L3
L13:
  ret
```

assistant: ```c
void manual_dcopy(const int n, const double *x, double *y) {
  for (int i = 0; i < n; ++i) {
    y[i] = x[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<manual_dcopy>:
  endbr64
  test   %edi,%edi
  jle    L38
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L19
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdx
  je     L19
  mov    %edi,%ecx
  xor    %eax,%eax
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L44:
  movupd (%rsi,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L44
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L38
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  ret
  nop
L19:
  mov    %edi,%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L45:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L45
L38:
  ret
```

assistant: ```c
void manual_dcopy(const int n, const double *x, double *y) {
  for (int i = 0; i < n; ++i) {
    y[i] = x[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inttest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  movabs $0x100000002,%rax
  cmp    %rax,-0x8(%rbp)
  je     L54
  mov    $0x0,%eax
  jmp    L24
L54:
  movabs $0x300000004,%rax
  cmp    %rax,-0x10(%rbp)
  je     L18
  mov    $0x0,%eax
  jmp    L24
L18:
  movabs $0x500000006,%rax
  cmp    %rax,-0x18(%rbp)
  je     L88
  mov    $0x0,%eax
  jmp    L24
L88:
  movabs $0x700000008,%rax
  cmp    %rax,-0x20(%rbp)
  je     L61
  mov    $0x0,%eax
  jmp    L24
L61:
  movabs $0x90000000a,%rax
  cmp    %rax,-0x28(%rbp)
  je     L78
  mov    $0x0,%eax
  jmp    L24
L78:
  mov    $0x1,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
bool inttest(long long p1, long long p2, long long p3, long long p4, long long p5) {
  if (p1 != 0x100000002)
    return false;
  if (p2 != 0x300000004)
    return false;
  if (p3 != 0x500000006)
    return false;
  if (p4 != 0x700000008)
    return false;
  if (p5 != 0x90000000A)
    return false;
  return true;
}
```
user: What is the c source code of the assembly code below?

```asm
<inttest>:
  endbr64
  mov    %rdx,%r9
  movabs $0x700000008,%rax
  cmp    %rax,%rcx
  setne  %al
  movabs $0x90000000a,%rdx
  cmp    %rdx,%r8
  setne  %dl
  or     %edx,%eax
  movabs $0x500000006,%rdx
  cmp    %rdx,%r9
  setne  %dl
  or     %edx,%eax
  movabs $0x300000004,%rdx
  cmp    %rdx,%rsi
  setne  %dl
  or     %edx,%eax
  movabs $0x100000002,%rdx
  cmp    %rdx,%rdi
  setne  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
bool inttest(long long p1, long long p2, long long p3, long long p4, long long p5) {
  if (p1 != 0x100000002)
    return false;
  if (p2 != 0x300000004)
    return false;
  if (p3 != 0x500000006)
    return false;
  if (p4 != 0x700000008)
    return false;
  if (p5 != 0x90000000A)
    return false;
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inttest>:
  endbr64
  movabs $0x700000008,%rax
  mov    %rdx,%r9
  movabs $0x90000000a,%rdx
  cmp    %rax,%rcx
  setne  %al
  cmp    %rdx,%r8
  setne  %dl
  or     %edx,%eax
  movabs $0x500000006,%rdx
  cmp    %rdx,%r9
  setne  %dl
  or     %edx,%eax
  movabs $0x300000004,%rdx
  cmp    %rdx,%rsi
  setne  %dl
  or     %edx,%eax
  movabs $0x100000002,%rdx
  cmp    %rdx,%rdi
  setne  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
bool inttest(long long p1, long long p2, long long p3, long long p4, long long p5) {
  if (p1 != 0x100000002)
    return false;
  if (p2 != 0x300000004)
    return false;
  if (p3 != 0x500000006)
    return false;
  if (p4 != 0x700000008)
    return false;
  if (p5 != 0x90000000A)
    return false;
  return true;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inttest>:
  endbr64
  movabs $0x700000008,%rax
  mov    %rdx,%r9
  movabs $0x90000000a,%rdx
  cmp    %rax,%rcx
  setne  %al
  cmp    %rdx,%r8
  setne  %dl
  or     %edx,%eax
  movabs $0x500000006,%rdx
  cmp    %rdx,%r9
  setne  %dl
  or     %edx,%eax
  movabs $0x300000004,%rdx
  cmp    %rdx,%rsi
  setne  %dl
  or     %edx,%eax
  movabs $0x100000002,%rdx
  cmp    %rdx,%rdi
  setne  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
bool inttest(long long p1, long long p2, long long p3, long long p4, long long p5) {
  if (p1 != 0x100000002)
    return false;
  if (p2 != 0x300000004)
    return false;
  if (p3 != 0x500000006)
    return false;
  if (p4 != 0x700000008)
    return false;
  if (p5 != 0x90000000A)
    return false;
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<my_strupcase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L29
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L29
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L29:
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_strupcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] >= 'A' && str[i] <= 'Z')
      str[i] = str[i] + 32;
    i++;
  }
  return (str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strupcase>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L41
  mov    %rdi,%rcx
  jmp    L36
L7:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L41
L36:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L7
  add    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L7
L41:
  ret
```

assistant: ```c
char *my_strupcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] >= 'A' && str[i] <= 'Z')
      str[i] = str[i] + 32;
    i++;
  }
  return (str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strupcase>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L10
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L28:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L12
  add    $0x20,%edx
  mov    %dl,(%rcx)
L12:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L28
L10:
  ret
```

assistant: ```c
char *my_strupcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] >= 'A' && str[i] <= 'Z')
      str[i] = str[i] + 32;
    i++;
  }
  return (str);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_strupcase>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L9
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L36:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L8
  add    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L36
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L36
L9:
  ret
```

assistant: ```c
char *my_strupcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] >= 'A' && str[i] <= 'Z')
      str[i] = str[i] + 32;
    i++;
  }
  return (str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fetrans_deschook_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sfree@plt>
  nop
L9:
  nop
  leave
  ret
```

assistant: ```c
void fetrans_deschook_free(void *hook) {
  if (hook) {
    sfree(hook);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fetrans_deschook_free>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <sfree@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
void fetrans_deschook_free(void *hook) {
  if (hook) {
    sfree(hook);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fetrans_deschook_free>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <sfree@plt>
  xchg   %ax,%ax
L0:
  ret
```

assistant: ```c
void fetrans_deschook_free(void *hook) {
  if (hook) {
    sfree(hook);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fetrans_deschook_free>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <sfree@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void fetrans_deschook_free(void *hook) {
  if (hook) {
    sfree(hook);
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    $0x0,%edi
  call   <set_warn_handler@plt>
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <die_v@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *p, ...) {
  set_warn_handler(((void *)0));
  do {
    va_list args;
    va_start(args, p);
    die_v(p, args);
    va_end(args);
  } while (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <set_warn_handler@plt>
  mov    %rbx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <die_v@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void die(const char *p, ...) {
  set_warn_handler(((void *)0));
  do {
    va_list args;
    va_start(args, p);
    die_v(p, args);
    va_end(args);
  } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <set_warn_handler@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <die_v@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *p, ...) {
  set_warn_handler(((void *)0));
  do {
    va_list args;
    va_start(args, p);
    die_v(p, args);
    va_end(args);
  } while (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <set_warn_handler@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <die_v@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *p, ...) {
  set_warn_handler(((void *)0));
  do {
    va_list args;
    va_start(args, p);
    die_v(p, args);
    va_end(args);
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glRasterPos2f@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glutBitmapCharacter@plt>
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void output(int x, int y, char *string) {
  int len, i;
  glRasterPos2f(x, y);
  len = (int)strlen(string);
  for (i = 0; i < len; i++) {
    glutBitmapCharacter(GLUT_BITMAP_HELVETICA_18, string[i]);
  }
}
```