ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rbx
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <strcopy@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D12: my name is patri

tool: D13: my name is conor

tool: D0: %s

assistant: ```c
int main() {
  char *str1 = "my name is conor";
  char *str2 = "my name is patri";
  strcopy(str1, str2);
  printf("%s", str2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  lea    D1(%rip),%rdi
  mov    %rbp,%rsi
  call   <strcopy@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string
name: unpack_data
arguments: tag: D14
datatype: string

tool: D18: my name is patri

tool: D1: my name is conor

tool: D14: %s

assistant: ```c
int main() {
  char *str1 = "my name is conor";
  char *str2 = "my name is patri";
  strcopy(str1, str2);
  printf("%s", str2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rbp
  lea    D23(%rip),%rdi
  mov    %rbp,%rsi
  call   <strcopy@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: string
name: parse_data
arguments: data_tag: D10
type_infered: string

tool: D27: my name is patri

tool: D23: my name is conor

tool: D10: %s

assistant: ```c
int main() {
  char *str1 = "my name is conor";
  char *str2 = "my name is patri";
  strcopy(str1, str2);
  printf("%s", str2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x5,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int *p = malloc(sizeof(int));
  *p = 5;
  free(p);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movl   $0x5,(%rax)
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *p = malloc(sizeof(int));
  *p = 5;
  free(p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x5,(%rax)
  mov    %rax,%rdi
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *p = malloc(sizeof(int));
  *p = 5;
  free(p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x5,(%rax)
  mov    %rax,%rdi
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *p = malloc(sizeof(int));
  *p = 5;
  free(p);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<out_u16be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  jmp    L2
L15:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  add    $0x8000,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L2:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L15
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *out_u16be(int *src, unsigned char *dst, unsigned n, unsigned shift) {
  while (n--) {
    int val = (*src++ >> shift) + 0x8000;
    *dst++ = (val >> 8) & 0xFF;
    *dst++ = val & 0xFF;
  }
  return dst;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<out_u16be>:
  endbr64
  mov    %rdi,%r9
  lea    -0x1(%rdx),%r8d
  test   %edx,%edx
  je     L6
  mov    %r8d,%r8d
  lea    0x1(%r8),%r10
  mov    $0x0,%edi
L3:
  mov    (%r9,%rdi,4),%edx
  sar    %cl,%edx
  add    $0x8000,%edx
  movzbl %dh,%eax
  mov    %al,(%rsi,%rdi,2)
  mov    %dl,0x1(%rsi,%rdi,2)
  mov    %rdi,%rax
  add    $0x1,%rdi
  cmp    %r8,%rax
  jne    L3
  lea    (%rsi,%r10,2),%rax
  ret
L6:
  mov    %rsi,%rax
  ret
```

assistant: ```c
unsigned char *out_u16be(int *src, unsigned char *dst, unsigned n, unsigned shift) {
  while (n--) {
    int val = (*src++ >> shift) + 0x8000;
    *dst++ = (val >> 8) & 0xFF;
    *dst++ = val & 0xFF;
  }
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<out_u16be>:
  endbr64
  test   %edx,%edx
  je     L9
  push   %rbx
  mov    %edx,%eax
  xor    %r8d,%r8d
  xchg   %ax,%ax
L11:
  mov    (%rdi,%r8,4),%edx
  sar    %cl,%edx
  add    $0x8000,%edx
  movzbl %dh,%ebx
  mov    %dl,0x1(%rsi,%r8,2)
  mov    %bl,(%rsi,%r8,2)
  add    $0x1,%r8
  cmp    %rax,%r8
  jne    L11
  lea    (%rsi,%r8,2),%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rsi,%rax
  ret
```

assistant: ```c
unsigned char *out_u16be(int *src, unsigned char *dst, unsigned n, unsigned shift) {
  while (n--) {
    int val = (*src++ >> shift) + 0x8000;
    *dst++ = (val >> 8) & 0xFF;
    *dst++ = val & 0xFF;
  }
  return dst;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putnbrlong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L47
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  movabs $0x8000000000000000,%rax
  cmp    %rax,-0x8(%rbp)
  jne    L20
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
  jmp    L31
L20:
  negq   -0x8(%rbp)
L47:
  cmpq   $0x9,-0x8(%rbp)
  jg     L42
  mov    -0x8(%rbp),%rax
  add    $0x30,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  jmp    L31
L42:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdi
  call   <ft_putnbrlong>
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,%rdi
  call   <ft_putnbrlong>
L31:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: 9223372036854775808

assistant: ```c
void ft_putnbrlong(long long int nb) {
  if (nb < 0) {
    ft_putchar('-');
    if (nb == (-9223372036854775807 - 1)) {
      ft_putstr("9223372036854775808");
      return;
    }
    nb = -nb;
  }
  if (nb < 10)
    ft_putchar(48 + nb);
  else {
    ft_putnbrlong(nb / 10);
    ft_putnbrlong(nb % 10);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_putnbrlong>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  js     L5
L12:
  cmp    $0x9,%rbx
  jg     L45
  lea    0x30(%rbx),%edi
  call   <ft_putchar@plt>
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  movabs $0x8000000000000000,%rax
  cmp    %rax,%rbx
  je     L53
  neg    %rbx
  jmp    L12
L53:
  lea    D1(%rip),%rdi
  call   <ft_putstr@plt>
  jmp    L24
L45:
  movabs $0x6666666666666667,%rdx
  mov    %rbx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <ft_putnbrlong>
  lea    0x0(%rbp,%rbp,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  mov    %rbx,%rdi
  call   <ft_putnbrlong>
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: 9223372036854775808

assistant: ```c
void ft_putnbrlong(long long int nb) {
  if (nb < 0) {
    ft_putchar('-');
    if (nb == (-9223372036854775807 - 1)) {
      ft_putstr("9223372036854775808");
      return;
    }
    nb = -nb;
  }
  if (nb < 10)
    ft_putchar(48 + nb);
  else {
    ft_putnbrlong(nb / 10);
    ft_putnbrlong(nb % 10);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_putnbrlong>:
  endbr64
  push   %r13
  movabs $0xcccccccccccccccd,%r13
  push   %r12
  movabs $0x8000000000000000,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rbx,%rbx
  js     L17
L10:
  cmp    $0x9,%rbx
  jle    L23
L18:
  mov    %rbx,%rax
  mul    %r13
  shr    $0x3,%rdx
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <ft_putnbrlong>
  lea    0x0(%rbp,%rbp,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  test   %rbx,%rbx
  jns    L10
L17:
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  cmp    %r12,%rbx
  je     L29
  neg    %rbx
  cmp    $0x9,%rbx
  jg     L18
L23:
  add    $0x8,%rsp
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <ft_putchar@plt>
  nop
L29:
  add    $0x8,%rsp
  lea    D3(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <ft_putstr@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: 9223372036854775808

assistant: ```c
void ft_putnbrlong(long long int nb) {
  if (nb < 0) {
    ft_putchar('-');
    if (nb == (-9223372036854775807 - 1)) {
      ft_putstr("9223372036854775808");
      return;
    }
    nb = -nb;
  }
  if (nb < 10)
    ft_putchar(48 + nb);
  else {
    ft_putnbrlong(nb / 10);
    ft_putnbrlong(nb % 10);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string
name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D26
type: string
name: parse_data
arguments: data_tag: D17
type: string

tool: D4: before_text_with_more_than_one_charactersgeeksforgeeks

tool: D5: 
abcd

tool: D26: si

tool: D17: %d

assistant: ```c
int main() {
  char str[20];
  printf("before_text_with_more_than_one_characters\rgeeksforgeeks");
  printf("\nabcd");
  printf("\bsi");
  printf("%d", (13 & 1));
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D26
type_infered: string
name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D25
type_infered: string
name: read_data
arguments: tag: D18
type_infered: string

tool: D26: before_text_with_more_than_one_charactersgeeksforgeeks

tool: D1: 
abcd

tool: D25: si

tool: D18: %d

assistant: ```c
int main() {
  char str[20];
  printf("before_text_with_more_than_one_characters\rgeeksforgeeks");
  printf("\nabcd");
  printf("\bsi");
  printf("%d", (13 & 1));
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
type_guessed: string
name: extract_symbolic_data
arguments: tag: D30
type_guessed: string
name: extract_symbolic_data
arguments: tag: D31
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string

tool: D20: before_text_with_more_than_one_charactersgeeksforgeeks

tool: D30: 
abcd

tool: D31: si

tool: D13: %d

assistant: ```c
int main() {
  char str[20];
  printf("before_text_with_more_than_one_characters\rgeeksforgeeks");
  printf("\nabcd");
  printf("\bsi");
  printf("%d", (13 & 1));
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type: string
name: unpack_data
arguments: label: D21
type: string
name: unpack_data
arguments: label: D26
type: string
name: unpack_data
arguments: label: D39
type: string

tool: D5: before_text_with_more_than_one_charactersgeeksforgeeks

tool: D21: 
abcd

tool: D26: si

tool: D39: %d

assistant: ```c
int main() {
  char str[20];
  printf("before_text_with_more_than_one_characters\rgeeksforgeeks");
  printf("\nabcd");
  printf("\bsi");
  printf("%d", (13 & 1));
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ipc_read_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x14(%rbp)
  jns    L32
  mov    $0x0,%eax
  jmp    L1
L32:
  lea    -0x9(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L41
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L1
L41:
  movzbl -0x9(%rbp),%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6: read

assistant: ```c
char ipc_read_one(int fd) {
  char resp;
  if (fd < 0)
    return 0;
  if (read(fd, &resp, 1) != 1) {
    perror("read");
    return 0;
  }
  return resp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipc_read_one>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L22
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  mov    %eax,%edx
  movzbl 0x7(%rsp),%eax
  cmp    $0x1,%edx
  jne    L20
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L20:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L22
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: read

assistant: ```c
char ipc_read_one(int fd) {
  char resp;
  if (fd < 0)
    return 0;
  if (read(fd, &resp, 1) != 1) {
    perror("read");
    return 0;
  }
  return resp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ipc_read_one>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L5
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  mov    %eax,%r8d
  movzbl 0x7(%rsp),%eax
  cmp    $0x1,%r8d
  jne    L25
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L25:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  jmp    L5
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D4: read

assistant: ```c
char ipc_read_one(int fd) {
  char resp;
  if (fd < 0)
    return 0;
  if (read(fd, &resp, 1) != 1) {
    perror("read");
    return 0;
  }
  return resp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ipc_read_one>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L29
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  mov    %eax,%r8d
  movzbl 0x7(%rsp),%eax
  cmp    $0x1,%r8d
  jne    L26
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L26:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  jmp    L29
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: read

assistant: ```c
char ipc_read_one(int fd) {
  char resp;
  if (fd < 0)
    return 0;
  if (read(fd, &resp, 1) != 1) {
    perror("read");
    return 0;
  }
  return resp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_right_side_result>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <modular_power@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x20(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_right_side_result(int a, int b, int module, int x) {
  int result = 0;
  result += modular_power(x, 3, module);
  result += (a * x);
  result += b;
  result = result % module;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_right_side_result>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%ebx
  mov    $0x3,%esi
  mov    %ecx,%edi
  call   <modular_power@plt>
  imul   %r13d,%ebx
  add    %eax,%ebx
  lea    (%rbx,%r12,1),%eax
  cltd
  idiv   %ebp
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_right_side_result(int a, int b, int module, int x) {
  int result = 0;
  result += modular_power(x, 3, module);
  result += (a * x);
  result += b;
  result = result % module;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_right_side_result>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %ecx,%edi
  push   %r12
  mov    %esi,%r12d
  mov    $0x3,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ecx,%ebx
  imul   %r13d,%ebx
  sub    $0x8,%rsp
  call   <modular_power@plt>
  add    $0x8,%rsp
  add    %eax,%ebx
  lea    (%rbx,%r12,1),%eax
  pop    %rbx
  cltd
  idiv   %ebp
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    %edx,%eax
  ret
```

assistant: ```c
int get_right_side_result(int a, int b, int module, int x) {
  int result = 0;
  result += modular_power(x, 3, module);
  result += (a * x);
  result += b;
  result = result % module;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_right_side_result>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %ecx,%edi
  push   %r12
  mov    %esi,%r12d
  mov    $0x3,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ecx,%ebx
  imul   %r13d,%ebx
  sub    $0x8,%rsp
  call   <modular_power@plt>
  add    $0x8,%rsp
  add    %eax,%ebx
  lea    (%rbx,%r12,1),%eax
  pop    %rbx
  cltd
  idiv   %ebp
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    %edx,%eax
  ret
```

assistant: ```c
int get_right_side_result(int a, int b, int module, int x) {
  int result = 0;
  result += modular_power(x, 3, module);
  result += (a * x);
  result += b;
  result = result % module;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D6: input a and b

tool: D3: %d%d

tool: D2: a+b=%d


assistant: ```c
void main() {
  int a, b;
  printf("input a and b\n");
  scanf("%d%d", &a, &b);
  printf("a+b=%d\n", a + b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  add    (%rsp),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D11
data_type: string
name: disassemble_data
arguments: data_label: D13
data_type: string

tool: D23: input a and b

tool: D11: %d%d

tool: D13: a+b=%d


assistant: ```c
void main() {
  int a, b;
  printf("input a and b\n");
  scanf("%d%d", &a, &b);
  printf("a+b=%d\n", a + b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string

tool: D1: input a and b

tool: D4: %d%d

tool: D22: a+b=%d


assistant: ```c
void main() {
  int a, b;
  printf("input a and b\n");
  scanf("%d%d", &a, &b);
  printf("a+b=%d\n", a + b);
  return 0;
}
```