ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_input_to>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  lea    0x8(%rsp),%r9
  lea    0x4(%rsp),%r8
  call   <get_span@plt>
  mov    %r12d,%edi
  call   <get_depth@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %ebp,%eax
  jb     L105
  test   %ebp,%ebp
  jne    L87
L79:
  mov    %ebx,%eax
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L91
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L105:
  mov    0x8(%rsp),%edx
  mov    %ebx,%eax
  test   %edx,%edx
  jne    L15
  mov    (%rsp),%esi
  mov    %ebx,%edx
  mov    0x4(%rsp),%ecx
  sub    %esi,%edx
  mov    %edx,%edi
  or     $0x1,%edi
  cmp    %ecx,%edi
  jae    L15
  test   $0x1,%dl
  jne    L40
  shr    %edx
  lea    (%rdx,%rsi,1),%eax
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L87:
  lea    0xc(%rsp),%rcx
  lea    -0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12d,%edi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <get_span@plt>
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  jne    L79
  mov    (%rsp),%ecx
  mov    0xc(%rsp),%edx
  cmp    %edx,%ecx
  je     L6
  mov    %ebx,%eax
  sub    %edx,%eax
  or     $0x1,%eax
  cmp    0x10(%rsp),%eax
  jae    L79
  sub    %ecx,%ebx
  lea    0x1(%rdx,%rbx,2),%eax
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L40:
  shr    %ecx
  sub    $0x1,%edx
  add    %esi,%ecx
  shr    %edx
  lea    (%rcx,%rdx,1),%eax
  jmp    L15
  nopl   0x0(%rax)
L6:
  sub    %ecx,%ebx
  lea    (%rcx,%rbx,2),%eax
  jmp    L15
L91:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned get_input_to(unsigned inputs, unsigned x, unsigned y) {
  unsigned start, len, is_pipeline;
  get_span(inputs, x, y, &start, &len, &is_pipeline);
  if (x <= get_depth(inputs) / 2) {
    unsigned prev_start, prev_len, prev_was_pipeline;
    if (x == 0) {
      prev_start = 0;
      prev_len = inputs;
      prev_was_pipeline = 1;
    } else {
      get_span(inputs, x - 1, y, &prev_start, &prev_len, &prev_was_pipeline);
    }
    if (prev_was_pipeline) {
      return y;
    } else if (start == prev_start) {
      return prev_start + (y - start) * 2;
    } else {
      if ((y - prev_start) / 2 * 2 + 1 >= prev_len)
        return y;
      return prev_start + (y - start) * 2 + 1;
    }
  } else {
    if (is_pipeline) {
      return y;
    } else if ((y - start) / 2 * 2 + 1 >= len) {
      return y;
    } else if ((y - start) % 2 == 0) {
      return start + (y - start) / 2;
    } else {
      return start + len / 2 + (y - start - 1) / 2;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L1
L3:
  mov    -0x8(%rbp),%eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <palinbase@plt>
  test   %rax,%rax
  je     L27
  mov    -0x8(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <palinbase@plt>
  test   %rax,%rax
  je     L27
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
L27:
  addl   $0x2,-0x8(%rbp)
L1:
  cmpl   $0xf423f,-0x8(%rbp)
  jle    L3
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  int n, s = 0;
  for (n = 1; n < 1000000; n += 2)
    if (palinbase(n, 10) && palinbase(n, 2))
      s += n;
  printf("%d\n", s);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  mov    $0x1,%ebx
  jmp    L2
L33:
  add    $0x2,%ebx
  cmp    $0xf4241,%ebx
  je     L26
L2:
  mov    $0xa,%esi
  mov    %ebx,%edi
  call   <palinbase@plt>
  test   %rax,%rax
  je     L33
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <palinbase@plt>
  mov    %rax,%rdx
  lea    0x0(%rbp,%rbx,1),%eax
  test   %rdx,%rdx
  cmovne %eax,%ebp
  jmp    L33
L26:
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int main(int argc, char **argv) {
  int n, s = 0;
  for (n = 1; n < 1000000; n += 2)
    if (palinbase(n, 10) && palinbase(n, 2))
      s += n;
  printf("%d\n", s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x2,%ebx
  cmp    $0xf4241,%ebx
  je     L1
L4:
  mov    $0xa,%esi
  mov    %ebx,%edi
  call   <palinbase@plt>
  test   %rax,%rax
  je     L34
  mov    %ebx,%edi
  mov    $0x2,%esi
  call   <palinbase@plt>
  mov    %rax,%r8
  lea    0x0(%rbp,%rbx,1),%eax
  test   %r8,%r8
  cmovne %eax,%ebp
  add    $0x2,%ebx
  cmp    $0xf4241,%ebx
  jne    L4
L1:
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
int main(int argc, char **argv) {
  int n, s = 0;
  for (n = 1; n < 1000000; n += 2)
    if (palinbase(n, 10) && palinbase(n, 2))
      s += n;
  printf("%d\n", s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x2,%ebx
  cmp    $0xf4241,%ebx
  je     L30
L8:
  mov    $0xa,%esi
  mov    %ebx,%edi
  call   <palinbase@plt>
  test   %rax,%rax
  je     L31
  mov    %ebx,%edi
  mov    $0x2,%esi
  call   <palinbase@plt>
  mov    %rax,%r8
  lea    0x0(%rbp,%rbx,1),%eax
  test   %r8,%r8
  cmovne %eax,%ebp
  add    $0x2,%ebx
  cmp    $0xf4241,%ebx
  jne    L8
L30:
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string

tool: D7: %d


assistant: ```c
int main(int argc, char **argv) {
  int n, s = 0;
  for (n = 1; n < 1000000; n += 2)
    if (palinbase(n, 10) && palinbase(n, 2))
      s += n;
  printf("%d\n", s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PrintArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L6:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: %d


assistant: ```c
int PrintArray(int *arr, int length) {
  for (int i = 0; i < length; printf("%d\n", arr[i++]))
    ;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PrintArray>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D5(%rip),%rbp
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0x0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D5: %d


assistant: ```c
int PrintArray(int *arr, int length) {
  for (int i = 0; i < length; printf("%d\n", arr[i++]))
    ;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PrintArray>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
int PrintArray(int *arr, int length) {
  for (int i = 0; i < length; printf("%d\n", arr[i++]))
    ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PrintArray>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D9
type: string

tool: D9: %d


assistant: ```c
int PrintArray(int *arr, int length) {
  for (int i = 0; i < length; printf("%d\n", arr[i++]))
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<strhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L16:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strhash(char *x) {
  int h = 0;
  while (*x)
    h = h * 13 + *(x++);
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strhash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L9
  mov    $0x0,%eax
L6:
  lea    (%rax,%rax,2),%ecx
  lea    (%rax,%rcx,4),%eax
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L6
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strhash(char *x) {
  int h = 0;
  while (*x)
    h = h * 13 + *(x++);
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strhash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L5
  nopl   (%rax)
L12:
  lea    (%rax,%rax,2),%ecx
  add    $0x1,%rdi
  lea    (%rax,%rcx,4),%eax
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L12
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
int strhash(char *x) {
  int h = 0;
  while (*x)
    h = h * 13 + *(x++);
  return h;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strhash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L0
  nopl   (%rax)
L3:
  lea    (%rax,%rax,2),%ecx
  add    $0x1,%rdi
  lea    (%rax,%rcx,4),%eax
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  ret
  nopl   0x0(%rax)
L0:
  ret
```

assistant: ```c
int strhash(char *x) {
  int h = 0;
  while (*x)
    h = h * 13 + *(x++);
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_fast_math>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  stmxcsr -0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  orl    $0x8040,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  ldmxcsr -0x14(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((constructor)) set_fast_math(void) {
  unsigned int mxcsr = __builtin_ia32_stmxcsr();
  mxcsr |= (1 << 6) | (1 << 15);
  __builtin_ia32_ldmxcsr(mxcsr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_fast_math>:
  endbr64
  stmxcsr -0x4(%rsp)
  orl    $0x8040,-0x4(%rsp)
  ldmxcsr -0x4(%rsp)
  ret
```

assistant: ```c
void __attribute__((constructor)) set_fast_math(void) {
  unsigned int mxcsr = __builtin_ia32_stmxcsr();
  mxcsr |= (1 << 6) | (1 << 15);
  __builtin_ia32_ldmxcsr(mxcsr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_fast_math>:
  endbr64
  stmxcsr -0x4(%rsp)
  orl    $0x8040,-0x4(%rsp)
  ldmxcsr -0x4(%rsp)
  ret
```

assistant: ```c
void __attribute__((constructor)) set_fast_math(void) {
  unsigned int mxcsr = __builtin_ia32_stmxcsr();
  mxcsr |= (1 << 6) | (1 << 15);
  __builtin_ia32_ldmxcsr(mxcsr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_matrix_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: %f 

assistant: ```c
void print_matrix_row(double *row, int num_cols) {
  for (int j = 0; j < num_cols; j++) {
    printf("%f ", row[j]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_matrix_row>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D2(%rip),%rbp
L6:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: %f 

assistant: ```c
void print_matrix_row(double *row, int num_cols) {
  for (int j = 0; j < num_cols; j++) {
    printf("%f ", row[j]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_matrix_row>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L2:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D8: %f 

assistant: ```c
void print_matrix_row(double *row, int num_cols) {
  for (int j = 0; j < num_cols; j++) {
    printf("%f ", row[j]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_matrix_row>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L8:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0: %f 

assistant: ```c
void print_matrix_row(double *row, int num_cols) {
  for (int j = 0; j < num_cols; j++) {
    printf("%f ", row[j]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pq_upheap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L7
L33:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L7:
  cmpl   $0x0,-0xc(%rbp)
  jg     L33
  jmp    L35
L1:
  nop
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pq_upheap(int at, int *items) {
  int item = items[at];
  int cur = at;
  while (cur > 0) {
    int next = cur / 2;
    if (items[next] >= item) {
      break;
    }
    items[cur] = items[next];
    cur = next;
  }
  items[cur] = item;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pq_upheap>:
  endbr64
  movslq %edi,%rax
  mov    (%rsi,%rax,4),%r8d
  test   %edi,%edi
  jle    L17
L7:
  mov    %edi,%edx
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  mov    %eax,%edi
  cltq
  mov    (%rsi,%rax,4),%eax
  cmp    %r8d,%eax
  jge    L16
  movslq %edx,%rcx
  mov    %eax,(%rsi,%rcx,4)
  cmp    $0x1,%edx
  jg     L7
  mov    %edi,%edx
L16:
  movslq %edx,%rdx
  mov    %r8d,(%rsi,%rdx,4)
  ret
L17:
  mov    %edi,%edx
  jmp    L16
```

assistant: ```c
void pq_upheap(int at, int *items) {
  int item = items[at];
  int cur = at;
  while (cur > 0) {
    int next = cur / 2;
    if (items[next] >= item) {
      break;
    }
    items[cur] = items[next];
    cur = next;
  }
  items[cur] = item;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pq_upheap>:
  endbr64
  movslq %edi,%rax
  lea    (%rsi,%rax,4),%rax
  mov    (%rax),%r8d
  test   %edi,%edi
  jg     L37
  jmp    L27
  nopl   0x0(%rax)
L22:
  mov    %edx,(%rax)
  test   %edi,%edi
  je     L30
L37:
  movslq %edi,%rax
  sar    %edi
  movslq %edi,%rdx
  lea    (%rsi,%rax,4),%rax
  lea    (%rsi,%rdx,4),%rcx
  mov    (%rcx),%edx
  cmp    %r8d,%edx
  jl     L22
L27:
  mov    %r8d,(%rax)
  ret
  nopl   0x0(%rax)
L30:
  mov    %rcx,%rax
  mov    %r8d,(%rax)
  ret
```

assistant: ```c
void pq_upheap(int at, int *items) {
  int item = items[at];
  int cur = at;
  while (cur > 0) {
    int next = cur / 2;
    if (items[next] >= item) {
      break;
    }
    items[cur] = items[next];
    cur = next;
  }
  items[cur] = item;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pq_upheap>:
  endbr64
  movslq %edi,%rax
  lea    (%rsi,%rax,4),%rax
  mov    (%rax),%r8d
  test   %edi,%edi
  jg     L28
  jmp    L19
  nopl   0x0(%rax)
L20:
  mov    %edx,(%rax)
  test   %edi,%edi
  je     L29
L28:
  movslq %edi,%rax
  sar    %edi
  movslq %edi,%rdx
  lea    (%rsi,%rax,4),%rax
  lea    (%rsi,%rdx,4),%rcx
  mov    (%rcx),%edx
  cmp    %r8d,%edx
  jl     L20
L19:
  mov    %r8d,(%rax)
  ret
  nopl   0x0(%rax)
L29:
  mov    %rcx,%rax
  mov    %r8d,(%rax)
  ret
```

assistant: ```c
void pq_upheap(int at, int *items) {
  int item = items[at];
  int cur = at;
  while (cur > 0) {
    int next = cur / 2;
    if (items[next] >= item) {
      break;
    }
    items[cur] = items[next];
    cur = next;
  }
  items[cur] = item;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<M35_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string

tool: D19: M35_f(const char *s) is not yet implemented!


tool: D1: %s


assistant: ```c
int M35_f(char *s) {
  debug("M35_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<M35_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string
name: unpack_data
arguments: data_label: D14
data_type: string

tool: D3: M35_f(const char *s) is not yet implemented!


tool: D14: %s


assistant: ```c
int M35_f(char *s) {
  debug("M35_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<M35_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D18(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string

tool: D18: M35_f(const char *s) is not yet implemented!


tool: D3: %s


assistant: ```c
int M35_f(char *s) {
  debug("M35_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<M35_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D14(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type: string
name: retrieve_data
arguments: data_tag: D3
type: string

tool: D14: M35_f(const char *s) is not yet implemented!


tool: D3: %s


assistant: ```c
int M35_f(char *s) {
  debug("M35_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<safe_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L5
  mov    -0x28(%rbp),%rax
  jmp    L13
L5:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L13:
  leave
  ret
```

assistant: ```c
ssize_t safe_read(int desc, void *ptr, size_t len) {
  ssize_t n_chars;
  if (len <= 0)
    return len;
  n_chars = read(desc, ptr, len);
  return n_chars;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<safe_read>:
  endbr64
  mov    %rdx,%rax
  test   %rdx,%rdx
  jne    L7
  ret
L7:
  sub    $0x8,%rsp
  call   <read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
ssize_t safe_read(int desc, void *ptr, size_t len) {
  ssize_t n_chars;
  if (len <= 0)
    return len;
  n_chars = read(desc, ptr, len);
  return n_chars;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<safe_read>:
  endbr64
  test   %rdx,%rdx
  jne    L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  jmp    1050 <read@plt>
```

assistant: ```c
ssize_t safe_read(int desc, void *ptr, size_t len) {
  ssize_t n_chars;
  if (len <= 0)
    return len;
  n_chars = read(desc, ptr, len);
  return n_chars;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<safe_read>:
  endbr64
  test   %rdx,%rdx
  jne    L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  jmp    1050 <read@plt>
```

assistant: ```c
ssize_t safe_read(int desc, void *ptr, size_t len) {
  ssize_t n_chars;
  if (len <= 0)
    return len;
  n_chars = read(desc, ptr, len);
  return n_chars;
}
```