ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L4
  negl   -0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _abs(int i) {
  if (i < 0)
    i = i * -1;
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int _abs(int i) {
  if (i < 0)
    i = i * -1;
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int _abs(int i) {
  if (i < 0)
    i = i * -1;
  return (i);
}
```
user: What is the c source code of the assembly code below:

```asm
<_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int _abs(int i) {
  if (i < 0)
    i = i * -1;
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <use_math@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  use_math();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <use_math@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  use_math();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <use_math@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  use_math();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <use_math@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  use_math();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<luaHelper_FreeFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void luaHelper_FreeFunction(void *ptr, int oldsize, void *data) {
  ((void)(data));
  ((void)(oldsize));
  free(ptr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<luaHelper_FreeFunction>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void luaHelper_FreeFunction(void *ptr, int oldsize, void *data) {
  ((void)(data));
  ((void)(oldsize));
  free(ptr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<luaHelper_FreeFunction>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void luaHelper_FreeFunction(void *ptr, int oldsize, void *data) {
  ((void)(data));
  ((void)(oldsize));
  free(ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<luaHelper_FreeFunction>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void luaHelper_FreeFunction(void *ptr, int oldsize, void *data) {
  ((void)(data));
  ((void)(oldsize));
  free(ptr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<query>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x1028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1028(%rbp),%rax
  mov    %rax,%rdi
  call   <getpwnam@plt>
  mov    %rax,-0x1018(%rbp)
  cmpq   $0x0,-0x1018(%rbp)
  je     L7
  mov    -0x1018(%rbp),%rax
  mov    0x20(%rax),%rdi
  mov    -0x1018(%rbp),%rax
  mov    0x18(%rax),%rsi
  mov    -0x1018(%rbp),%rax
  mov    0x10(%rax),%r9
  mov    -0x1018(%rbp),%rax
  mov    0xc(%rax),%r8d
  mov    -0x1018(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    -0x1018(%rbp),%rax
  mov    (%rax),%rdx
  lea    -0x1010(%rbp),%rax
  push   %rdi
  push   %rsi
  lea    D16(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  add    $0x10,%rsp
  jmp    L1
L7:
  mov    -0x1028(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L1:
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string

tool: D16: Username: %s, uid: %d, gid: %d, gecos: %s, dir: %s, shell: %s



tool: D5: %s does not exist on this system, according to getpwnam().



assistant: ```c
void query(char *username) {
  struct passwd *pw;
  char response[4096];
  pw = getpwnam(username);
  if (pw) {
    sprintf(response, "Username: %s, uid: %d, gid: %d, gecos: %s, dir: %s, shell: %s\n\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_gecos, pw->pw_dir, pw->pw_shell);
  } else {
    sprintf(response, "%s does not exist on this system, according to getpwnam().\n\n", username);
  }
  printf(response);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<query>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  call   <getpwnam@plt>
  test   %rax,%rax
  je     L4
  mov    0x10(%rax),%r9
  mov    0xc(%rax),%r8d
  mov    0x8(%rax),%ecx
  mov    %rsp,%rdi
  push   0x20(%rax)
  push   0x18(%rax)
  mov    (%rax),%rdx
  lea    D11(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  add    $0x10,%rsp
L24:
  mov    %rsp,%rdi
  call   <printf@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x1010,%rsp
  pop    %rbx
  ret
L4:
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  lea    D14(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L24
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D11: Username: %s, uid: %d, gid: %d, gecos: %s, dir: %s, shell: %s



tool: D14: %s does not exist on this system, according to getpwnam().



assistant: ```c
void query(char *username) {
  struct passwd *pw;
  char response[4096];
  pw = getpwnam(username);
  if (pw) {
    sprintf(response, "Username: %s, uid: %d, gid: %d, gecos: %s, dir: %s, shell: %s\n\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_gecos, pw->pw_dir, pw->pw_shell);
  } else {
    sprintf(response, "%s does not exist on this system, according to getpwnam().\n\n", username);
  }
  printf(response);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<query>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <getpwnam@plt>
  test   %rax,%rax
  je     L28
  mov    0x10(%rax),%r9
  mov    0x8(%rax),%ecx
  mov    %rsp,%rbp
  lea    D3(%rip),%rsi
  mov    0xc(%rax),%r8d
  push   0x20(%rax)
  mov    %rbp,%rdi
  push   0x18(%rax)
  mov    (%rax),%rdx
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rsp
L0:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x1018,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rsp,%rbp
  mov    %r12,%rdx
  lea    D7(%rip),%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <sprintf@plt>
  jmp    L0
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string
name: disassemble_data
arguments: label: D7
data_type: string

tool: D3: Username: %s, uid: %d, gid: %d, gecos: %s, dir: %s, shell: %s



tool: D7: %s does not exist on this system, according to getpwnam().



assistant: ```c
void query(char *username) {
  struct passwd *pw;
  char response[4096];
  pw = getpwnam(username);
  if (pw) {
    sprintf(response, "Username: %s, uid: %d, gid: %d, gecos: %s, dir: %s, shell: %s\n\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_gecos, pw->pw_dir, pw->pw_shell);
  } else {
    sprintf(response, "%s does not exist on this system, according to getpwnam().\n\n", username);
  }
  printf(response);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<query>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <getpwnam@plt>
  test   %rax,%rax
  je     L20
  mov    0x10(%rax),%r9
  mov    0x8(%rax),%ecx
  mov    %rsp,%rbp
  lea    D15(%rip),%rsi
  mov    0xc(%rax),%r8d
  push   0x20(%rax)
  mov    %rbp,%rdi
  push   0x18(%rax)
  mov    (%rax),%rdx
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rsp
L4:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x1018,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rsp,%rbp
  mov    %r12,%rdx
  lea    D7(%rip),%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <sprintf@plt>
  jmp    L4
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D15
data_type: string
name: read_data
arguments: tag: D7
data_type: string

tool: D15: Username: %s, uid: %d, gid: %d, gecos: %s, dir: %s, shell: %s



tool: D7: %s does not exist on this system, according to getpwnam().



assistant: ```c
void query(char *username) {
  struct passwd *pw;
  char response[4096];
  pw = getpwnam(username);
  if (pw) {
    sprintf(response, "Username: %s, uid: %d, gid: %d, gecos: %s, dir: %s, shell: %s\n\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_gecos, pw->pw_dir, pw->pw_shell);
  } else {
    sprintf(response, "%s does not exist on this system, according to getpwnam().\n\n", username);
  }
  printf(response);
}
```
user: What is the c source code of the assembly code below:

```asm
<rmstodb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L36
  pxor   %xmm0,%xmm0
  jmp    L28
L36:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L11
  pxor   %xmm0,%xmm0
  jmp    L28
L11:
  movsd  -0x8(%rbp),%xmm0
L28:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: byte[8]
name: parse_data
arguments: tag: D2
type_guessed: f64

tool: {"D7": [0x8a,0x4f,0x38,0xed,0x2c,0x5f,0x21,0x40]}

tool: D2: 100

assistant: ```c
double rmstodb(double f) {
  if (f <= 0)
    return (0);
  else {
    double val = 100 + 20. / 2.302585092994 * log(f);
    return (val < 0 ? 0 : val);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rmstodb>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jb     L16
  pxor   %xmm0,%xmm0
  ret
L16:
  sub    $0x8,%rsp
  call   <log@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D10(%rip),%xmm0
  addsd  D3(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L28
L8:
  add    $0x8,%rsp
  ret
L28:
  pxor   %xmm0,%xmm0
  jmp    L8
```

tool_calls: name: read_data
arguments: label: D10
type_infered: byte[8]
name: read_data
arguments: label: D3
type_infered: f64

tool: {"D10": [0x8a,0x4f,0x38,0xed,0x2c,0x5f,0x21,0x40]}

tool: D3: 100

assistant: ```c
double rmstodb(double f) {
  if (f <= 0)
    return (0);
  else {
    double val = 100 + 20. / 2.302585092994 * log(f);
    return (val < 0 ? 0 : val);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rmstodb>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jb     L19
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  sub    $0x8,%rsp
  call   <log@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm0
  mulsd  D0(%rip),%xmm0
  addsd  D1(%rip),%xmm0
  comisd %xmm0,%xmm1
  jbe    L15
  movapd %xmm1,%xmm0
L15:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D1
data_type: f64

tool: {"D0": [0x8a,0x4f,0x38,0xed,0x2c,0x5f,0x21,0x40]}

tool: D1: 100

assistant: ```c
double rmstodb(double f) {
  if (f <= 0)
    return (0);
  else {
    double val = 100 + 20. / 2.302585092994 * log(f);
    return (val < 0 ? 0 : val);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rmstodb>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jb     L11
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  sub    $0x8,%rsp
  call   <log@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm0
  mulsd  D13(%rip),%xmm0
  addsd  D7(%rip),%xmm0
  comisd %xmm0,%xmm1
  jbe    L12
  movapd %xmm1,%xmm0
L12:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D7
data_type: f64

tool: {"D13": [0x8a,0x4f,0x38,0xed,0x2c,0x5f,0x21,0x40]}

tool: D7: 100

assistant: ```c
double rmstodb(double f) {
  if (f <= 0)
    return (0);
  else {
    double val = 100 + 20. / 2.302585092994 * log(f);
    return (val < 0 ? 0 : val);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L67
L32:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L50
  addl   $0x1,-0xc(%rbp)
  nop
L67:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L32
  jmp    L41
L50:
  nop
L41:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L63
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L68
L63:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L68:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D23
type_infered: string
name: read_data
arguments: data_tag: D20
type_infered: string

tool: D17: %d

tool: D23: %d is zhishu

tool: D20: %d isn't zhishu

assistant: ```c
int main() {
  int i, num;
  scanf("%d", &num);
  i = 2;
  while (i < num) {
    if (num % i == 0)
      break;
    else {
      i++;
      continue;
    }
  }
  if (num == i)
    printf("%d is zhishu", num);
  else
    printf("%d isn't zhishu", num);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L14
  mov    $0x2,%ecx
  test   $0x1,%sil
  jne    L16
L34:
  lea    D27(%rip),%rdi
  call   <printf@plt>
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L16:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  je     L71
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L34
  jmp    L16
L14:
  jne    L34
L71:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D4: %d

tool: D27: %d isn't zhishu

tool: D16: %d is zhishu

assistant: ```c
int main() {
  int i, num;
  scanf("%d", &num);
  i = 2;
  while (i < num) {
    if (num % i == 0)
      break;
    else {
      i++;
      continue;
    }
  }
  if (num == i)
    printf("%d is zhishu", num);
  else
    printf("%d isn't zhishu", num);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L73
  mov    $0x2,%ecx
  test   $0x1,%sil
  jne    L29
L27:
  lea    D9(%rip),%rdi
  call   <printf@plt>
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L29:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  je     L57
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L27
  jmp    L29
L73:
  jne    L27
L57:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D24
type_guessed: string
name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D28
type_guessed: string

tool: D24: %d

tool: D9: %d isn't zhishu

tool: D28: %d is zhishu

assistant: ```c
int main() {
  int i, num;
  scanf("%d", &num);
  i = 2;
  while (i < num) {
    if (num % i == 0)
      break;
    else {
      i++;
      continue;
    }
  }
  if (num == i)
    printf("%d is zhishu", num);
  else
    printf("%d isn't zhishu", num);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L67
  mov    $0x2,%ecx
  test   $0x1,%sil
  jne    L26
L24:
  lea    D12(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L26:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  je     L60
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L24
  jmp    L26
L67:
  jne    L24
L60:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string

tool: D10: %d

tool: D12: %d isn't zhishu

tool: D16: %d is zhishu

assistant: ```c
int main() {
  int i, num;
  scanf("%d", &num);
  i = 2;
  while (i < num) {
    if (num % i == 0)
      break;
    else {
      i++;
      continue;
    }
  }
  if (num == i)
    printf("%d is zhishu", num);
  else
    printf("%d isn't zhishu", num);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movsd  D33(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L11
L1:
  movsd  -0x10(%rbp),%xmm1
  movsd  D59(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D27(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  -0x10(%rbp),%xmm1
  movsd  D12(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L11:
  movsd  D54(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  ja     L1
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D52
type_guessed: string
name: retrieve_data
arguments: tag: D33
type_guessed: f64
name: retrieve_data
arguments: tag: D59
type_guessed: f64
name: retrieve_data
arguments: tag: D27
type_guessed: f64
name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: f64
name: retrieve_data
arguments: tag: D54
type_guessed: f64
name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D52: Shoe size (man's) foot length

tool: D33: 3

tool: D59: 0.325

tool: D27: 7.64

tool: D5: %10.1f %15.2f inches


tool: D12: 1

tool: D54: 18.5

tool: D10: If the shoe fits, wear it.

assistant: ```c
int main(void) {
  double shoe, foot;
  printf("Shoe size (man's) foot length\n");
  shoe = 3.0;
  while (shoe < 18.5) {
    foot = 0.325 * shoe + 7.64;
    printf("%10.1f %15.2f inches\n", shoe, foot);
    shoe += 1.0;
  }
  printf("If the shoe fits, wear it.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D56(%rip),%rdi
  call   <puts@plt>
  mov    $0x10,%ebx
  movsd  D26(%rip),%xmm4
  movsd  %xmm4,0x8(%rsp)
  lea    D29(%rip),%rbp
L9:
  movsd  D1(%rip),%xmm1
  movsd  0x8(%rsp),%xmm2
  mulsd  %xmm2,%xmm1
  addsd  D32(%rip),%xmm1
  movapd %xmm2,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  D53(%rip),%xmm3
  addsd  0x8(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L9
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D56
datatype: string
name: extract_symbolic_data
arguments: tag: D26
datatype: f64
name: extract_symbolic_data
arguments: tag: D29
datatype: string
name: extract_symbolic_data
arguments: tag: D1
datatype: f64
name: extract_symbolic_data
arguments: tag: D32
datatype: f64
name: extract_symbolic_data
arguments: tag: D53
datatype: f64
name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D56: Shoe size (man's) foot length

tool: D26: 3

tool: D29: %10.1f %15.2f inches


tool: D1: 0.325

tool: D32: 7.64

tool: D53: 1

tool: D9: If the shoe fits, wear it.

assistant: ```c
int main(void) {
  double shoe, foot;
  printf("Shoe size (man's) foot length\n");
  shoe = 3.0;
  while (shoe < 18.5) {
    foot = 0.325 * shoe + 7.64;
    printf("%10.1f %15.2f inches\n", shoe, foot);
    shoe += 1.0;
  }
  printf("If the shoe fits, wear it.\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D36(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  movsd  D0(%rip),%xmm0
  nopw   0x0(%rax,%rax,1)
L6:
  movsd  D45(%rip),%xmm1
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm1
  addsd  D30(%rip),%xmm1
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  addsd  D23(%rip),%xmm0
  sub    $0x1,%ebx
  jne    L6
  lea    D21(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D36
type: string
name: retrieve_data
arguments: tag: D0
type: f64
name: retrieve_data
arguments: tag: D45
type: f64
name: retrieve_data
arguments: tag: D30
type: f64
name: retrieve_data
arguments: tag: D23
type: f64
name: retrieve_data
arguments: tag: D21
type: string

tool: D15: Shoe size (man's) foot length

tool: D36: %10.1f %15.2f inches


tool: D0: 3

tool: D45: 0.325

tool: D30: 7.64

tool: D23: 1

tool: D21: If the shoe fits, wear it.

assistant: ```c
int main(void) {
  double shoe, foot;
  printf("Shoe size (man's) foot length\n");
  shoe = 3.0;
  while (shoe < 18.5) {
    foot = 0.325 * shoe + 7.64;
    printf("%10.1f %15.2f inches\n", shoe, foot);
    shoe += 1.0;
  }
  printf("If the shoe fits, wear it.\n");
  return 0;
}
```