ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xcalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %rbp,%rdx
  lea    D7(%rip),%rsi
  mov    $0x65,%edi
  call   <err@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: label: D7
type: string

tool: D7: Calloc call failed - attempted %zu bytes

assistant: ```c
void *xcalloc(const int num, const size_t size) {
  void *tmp = calloc(num, size);
  if (tmp == NULL) {
    err(101, "Calloc call failed - attempted %zu bytes", size);
  }
  return tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xcalloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r13,%rdx
  lea    D2(%rip),%rsi
  mov    $0x65,%edi
  call   <err@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string

tool: D2: Calloc call failed - attempted %zu bytes

assistant: ```c
void *xcalloc(const int num, const size_t size) {
  void *tmp = calloc(num, size);
  if (tmp == NULL) {
    err(101, "Calloc call failed - attempted %zu bytes", size);
  }
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xcalloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r13,%rdx
  lea    D3(%rip),%rsi
  mov    $0x65,%edi
  call   <err@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: Calloc call failed - attempted %zu bytes

assistant: ```c
void *xcalloc(const int num, const size_t size) {
  void *tmp = calloc(num, size);
  if (tmp == NULL) {
    err(101, "Calloc call failed - attempted %zu bytes", size);
  }
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_longest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x5,-0x14(%rbp)
L43:
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x30(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %rdx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%ecx
  mov    %rdi,%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memmem@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L58
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  cmpl   $0x84,-0x14(%rbp)
  ja     L34
  jmp    L43
L58:
  nop
  jmp    L45
L34:
  nop
L45:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  ja     L17
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L46
L17:
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
L46:
  leave
  ret
```

assistant: ```c
unsigned find_longest(unsigned char *data, unsigned len, unsigned start, unsigned *ofs) {
  unsigned l;
  unsigned char *p, *p1;
  p = data;
  l = 5;
  for (;;) {
    p1 = memmem(p, data + start + l - 1 - p, data + start, l);
    if (!p1)
      break;
    p = p1;
    l++;
    if (l > 127 + 5)
      break;
  }
  l--;
  if (l < 5) {
    *ofs = 0;
    return 0;
  }
  *ofs = p - data;
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_longest>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rcx,%r15
  mov    %edx,%r13d
  lea    0x4(%rdi,%r13,1),%r12
  mov    %rdi,%rbp
  mov    $0x5,%ebx
  add    %rdi,%r13
L49:
  mov    %r12,%rsi
  sub    %rbp,%rsi
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <memmem@plt>
  mov    %rbp,%rdx
  movslq %eax,%rbp
  test   %eax,%eax
  je     L4
  add    $0x1,%ebx
  add    $0x1,%r12
  cmp    $0x85,%ebx
  jne    L49
  mov    %rbp,%rdx
  mov    $0x84,%eax
  jmp    L46
L4:
  lea    -0x1(%rbx),%eax
  cmp    $0x4,%eax
  jbe    L19
L46:
  sub    %r14d,%edx
L43:
  mov    %edx,(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    $0x0,%edx
  mov    $0x0,%eax
  jmp    L43
```

assistant: ```c
unsigned find_longest(unsigned char *data, unsigned len, unsigned start, unsigned *ofs) {
  unsigned l;
  unsigned char *p, *p1;
  p = data;
  l = 5;
  for (;;) {
    p1 = memmem(p, data + start + l - 1 - p, data + start, l);
    if (!p1)
      break;
    p = p1;
    l++;
    if (l > 127 + 5)
      break;
  }
  l--;
  if (l < 5) {
    *ofs = 0;
    return 0;
  }
  *ofs = p - data;
  return l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_longest>:
  endbr64
  push   %r15
  mov    %edx,%edx
  push   %r14
  lea    0x4(%rdi,%rdx,1),%r15
  mov    $0x5,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    (%rdi,%rdx,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L57
  xchg   %ax,%ax
L7:
  add    $0x1,%r14d
  add    $0x1,%r15
  cmp    $0x85,%r14d
  je     L8
L57:
  mov    %r15,%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    %r14d,%ecx
  sub    %rbx,%rsi
  xor    %eax,%eax
  call   <memmem@plt>
  mov    %rbx,%rdx
  movslq %eax,%rbx
  test   %eax,%eax
  jne    L7
  lea    -0x1(%r14),%eax
  cmp    $0x5,%r14d
  je     L29
L30:
  sub    %r12d,%edx
L55:
  mov    %edx,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L55
L8:
  mov    %rbx,%rdx
  mov    $0x84,%eax
  jmp    L30
```

assistant: ```c
unsigned find_longest(unsigned char *data, unsigned len, unsigned start, unsigned *ofs) {
  unsigned l;
  unsigned char *p, *p1;
  p = data;
  l = 5;
  for (;;) {
    p1 = memmem(p, data + start + l - 1 - p, data + start, l);
    if (!p1)
      break;
    p = p1;
    l++;
    if (l > 127 + 5)
      break;
  }
  l--;
  if (l < 5) {
    *ofs = 0;
    return 0;
  }
  *ofs = p - data;
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<find_longest>:
  endbr64
  push   %r15
  mov    %edx,%edx
  push   %r14
  lea    0x4(%rdi,%rdx,1),%r15
  mov    $0x5,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    (%rdi,%rdx,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L36
  xchg   %ax,%ax
L35:
  add    $0x1,%r14d
  add    $0x1,%r15
  cmp    $0x85,%r14d
  je     L52
L36:
  mov    %r15,%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    %r14d,%ecx
  sub    %rbx,%rsi
  xor    %eax,%eax
  call   <memmem@plt>
  mov    %rbx,%rdx
  movslq %eax,%rbx
  test   %eax,%eax
  jne    L35
  lea    -0x1(%r14),%eax
  cmp    $0x5,%r14d
  je     L10
L8:
  sub    %r12d,%edx
L24:
  mov    %edx,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L10:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L24
L52:
  mov    %rbx,%rdx
  mov    $0x84,%eax
  jmp    L8
```

assistant: ```c
unsigned find_longest(unsigned char *data, unsigned len, unsigned start, unsigned *ofs) {
  unsigned l;
  unsigned char *p, *p1;
  p = data;
  l = 5;
  for (;;) {
    p1 = memmem(p, data + start + l - 1 - p, data + start, l);
    if (!p1)
      break;
    p = p1;
    l++;
    if (l > 127 + 5)
      break;
  }
  l--;
  if (l < 5) {
    *ofs = 0;
    return 0;
  }
  *ofs = p - data;
  return l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L24
L75:
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L24:
  cmpl   $0x9,-0x34(%rbp)
  jle    L75
  jmp    L18
L64:
  mov    -0x38(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x38(%rbp)
L18:
  mov    -0x38(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jg     L64
  movl   $0x0,-0x34(%rbp)
  jmp    L12
L79:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  jle    L71
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L71:
  addl   $0x1,-0x34(%rbp)
L12:
  cmpl   $0x9,-0x34(%rbp)
  jle    L79
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D4
type: string

tool: D16: %d

tool: D4: %d %d


assistant: ```c
int main() {
  int a[10], i, n;
  scanf("%d", &n);
  for (i = 0; i < 10; i++) {
    a[i] = 0;
  }
  while (n % 10 > 0) {
    i = n % 10;
    a[i]++;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (a[i] > 0)
      printf("%d %d\n", i, a[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rax
  lea    0x38(%rsp),%rdx
L31:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L31
  mov    0xc(%rsp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  test   %eax,%eax
  jle    L57
L47:
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  test   %eax,%eax
  jg     L47
  mov    %edx,0xc(%rsp)
L57:
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
  jmp    L79
L63:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  je     L11
L79:
  mov    %ebx,%esi
  mov    0x10(%rsp,%rbx,4),%edx
  test   %edx,%edx
  jle    L63
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L63
L11:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string

tool: D16: %d

tool: D3: %d %d


assistant: ```c
int main() {
  int a[10], i, n;
  scanf("%d", &n);
  for (i = 0; i < 10; i++) {
    a[i] = 0;
  }
  while (n % 10 > 0) {
    i = n % 10;
    a[i]++;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (a[i] > 0)
      printf("%d %d\n", i, a[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rdx
  pxor   %xmm0,%xmm0
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  imul   $0x66666667,%rdx,%rax
  mov    %edx,%esi
  movaps %xmm0,0x20(%rsp)
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  test   %eax,%eax
  jle    L30
  mov    %rdx,%rcx
  nopl   0x0(%rax,%rax,1)
L25:
  imul   $0x66666667,%rdx,%rdx
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  mov    %edx,%ecx
  sub    %eax,%ecx
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x66666667,%rdx,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  mov    %ecx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  test   %eax,%eax
  jg     L25
  mov    %ecx,0xc(%rsp)
L30:
  xor    %ebx,%ebx
  lea    0x10(%rsp),%rbp
  lea    D19(%rip),%r12
  nop
L18:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  test   %edx,%edx
  jle    L3
  mov    %r12,%rdi
  call   <printf@plt>
L3:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L18
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D19
type_guessed: string

tool: D4: %d

tool: D19: %d %d


assistant: ```c
int main() {
  int a[10], i, n;
  scanf("%d", &n);
  for (i = 0; i < 10; i++) {
    a[i] = 0;
  }
  while (n % 10 > 0) {
    i = n % 10;
    a[i]++;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (a[i] > 0)
      printf("%d %d\n", i, a[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D94(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rdx
  pxor   %xmm0,%xmm0
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  imul   $0x66666667,%rdx,%rax
  mov    %edx,%esi
  movaps %xmm0,0x20(%rsp)
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  test   %eax,%eax
  jle    L58
  mov    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L91:
  imul   $0x66666667,%rdx,%rdx
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  mov    %edx,%ecx
  sub    %eax,%ecx
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x66666667,%rdx,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  mov    %ecx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  test   %eax,%eax
  jg     L91
  mov    %ecx,0xc(%rsp)
L58:
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  jle    L30
  xor    %esi,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L30:
  mov    0x14(%rsp),%edx
  test   %edx,%edx
  jle    L11
  mov    $0x1,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L11:
  mov    0x18(%rsp),%edx
  test   %edx,%edx
  jle    L24
  mov    $0x2,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L24:
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  jle    L28
  mov    $0x3,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L28:
  mov    0x20(%rsp),%edx
  test   %edx,%edx
  jle    L66
  mov    $0x4,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L66:
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  jle    L97
  mov    $0x5,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L97:
  mov    0x28(%rsp),%edx
  test   %edx,%edx
  jle    L41
  mov    $0x6,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L41:
  mov    0x2c(%rsp),%edx
  test   %edx,%edx
  jle    L21
  mov    $0x7,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x30(%rsp),%edx
  test   %edx,%edx
  jle    L10
  mov    $0x8,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L10:
  mov    0x34(%rsp),%edx
  test   %edx,%edx
  jle    L73
  mov    $0x9,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
L73:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D94
type: string
name: read_data
arguments: data_label: D100
type: string

tool: D94: %d

tool: D100: %d %d


assistant: ```c
int main() {
  int a[10], i, n;
  scanf("%d", &n);
  for (i = 0; i < 10; i++) {
    a[i] = 0;
  }
  while (n % 10 > 0) {
    i = n % 10;
    a[i]++;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (a[i] > 0)
      printf("%d %d\n", i, a[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f_int4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void f_int4(int f) {
  void f4a(void) { return; }
  void f4b() { return; }
  void f4c(int f) { return; }
  void f4d(f) int f;
  { return; }
  void f4e(const char *f, ...) { return; }
  auto f4f(void) { return 0; }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f_int4>:
  endbr64
  ret
```

assistant: ```c
void f_int4(int f) {
  void f4a(void) { return; }
  void f4b() { return; }
  void f4c(int f) { return; }
  void f4d(f) int f;
  { return; }
  void f4e(const char *f, ...) { return; }
  auto f4f(void) { return 0; }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f_int4>:
  endbr64
  ret
```

assistant: ```c
void f_int4(int f) {
  void f4a(void) { return; }
  void f4b() { return; }
  void f4c(int f) { return; }
  void f4d(f) int f;
  { return; }
  void f4e(const char *f, ...) { return; }
  auto f4f(void) { return 0; }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f_int4>:
  endbr64
  ret
```

assistant: ```c
void f_int4(int f) {
  void f4a(void) { return; }
  void f4b() { return; }
  void f4c(int f) { return; }
  void f4d(f) int f;
  { return; }
  void f4e(const char *f, ...) { return; }
  auto f4f(void) { return 0; }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <vmsg@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string

tool: D2: fatal: 

assistant: ```c
void die(int ev, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vmsg("fatal: ", NULL, fmt, ap);
  va_end(ap);
  exit(ev);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<die>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  lea    D1(%rip),%rdi
  call   <vmsg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: fatal: 

assistant: ```c
void die(int ev, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vmsg("fatal: ", NULL, fmt, ap);
  va_end(ap);
  exit(ev);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<die>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  call   <vmsg@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string

tool: D4: fatal: 

assistant: ```c
void die(int ev, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vmsg("fatal: ", NULL, fmt, ap);
  va_end(ap);
  exit(ev);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<die>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  call   <vmsg@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: fatal: 

assistant: ```c
void die(int ev, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vmsg("fatal: ", NULL, fmt, ap);
  va_end(ap);
  exit(ev);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <yyparse@plt>
  mov    $0x0,%eax
  call   <generate@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  yyparse();
  generate();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <yyparse@plt>
  mov    $0x0,%eax
  call   <generate@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  yyparse();
  generate();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <yyparse@plt>
  xor    %eax,%eax
  call   <generate@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  yyparse();
  generate();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <yyparse@plt>
  xor    %eax,%eax
  call   <generate@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  yyparse();
  generate();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L25
  mov    $0xffffffff,%eax
  jmp    L1
L13:
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x4(%rbp),%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int _strlen(char *str) {
  int i = 0;
  if (str == 0)
    return -1;
  while (str[i] != '\0')
    i++;
  return i;
}
```