ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<offset_span>:
  endbr64
  test   %esi,%esi
  je     L13
  lea    -0x1(%rsi),%eax
  xor    %ecx,%ecx
  lea    0x8(%rdi,%rax,8),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L9:
  mov    (%rdi),%rdx
  cmp    %rdx,%rcx
  cmovg  %rdx,%rcx
  cmp    %rdx,%rax
  cmovl  %rdx,%rax
  add    $0x8,%rdi
  cmp    %rdi,%rsi
  jne    L9
  sub    %rcx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
long long offset_span(long long const *offsets, unsigned int const channels) {
  long long min = 0;
  long long max = 0;
  int i;
  for (i = 0; i < channels; i++) {
    if (offsets[i] < min) {
      min = offsets[i];
    }
    if (offsets[i] > max) {
      max = offsets[i];
    }
  }
  return (max - min);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write_response_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <write_to_buf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: HTTP/1.1 404 Not Found
Content-Length:0



assistant: ```c
void write_response_error(struct fd_state *state) {
  const char *msg = "HTTP/1.1 404 Not Found\r\nContent-Length:0\r\n\r\n";
  write_to_buf(state, msg, strlen(msg));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write_response_error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <write_to_buf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: HTTP/1.1 404 Not Found
Content-Length:0



assistant: ```c
void write_response_error(struct fd_state *state) {
  const char *msg = "HTTP/1.1 404 Not Found\r\nContent-Length:0\r\n\r\n";
  write_to_buf(state, msg, strlen(msg));
}
```
user: What is the c source code of the assembly code below?

```asm
<write_response_error>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <write_to_buf@plt>
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string

tool: D2: HTTP/1.1 404 Not Found
Content-Length:0



assistant: ```c
void write_response_error(struct fd_state *state) {
  const char *msg = "HTTP/1.1 404 Not Found\r\nContent-Length:0\r\n\r\n";
  write_to_buf(state, msg, strlen(msg));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<write_response_error>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <write_to_buf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: HTTP/1.1 404 Not Found
Content-Length:0



assistant: ```c
void write_response_error(struct fd_state *state) {
  const char *msg = "HTTP/1.1 404 Not Found\r\nContent-Length:0\r\n\r\n";
  write_to_buf(state, msg, strlen(msg));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tkh_decode_name_into>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <tkh_string_is_ticklish@plt>
  test   %eax,%eax
  jne    L35
  mov    $0xffffffff,%eax
  jmp    L5
L35:
  mov    -0x18(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <strnlen@plt>
  sub    $0xc,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L48
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x9,%rax
  mov    -0x30(%rbp),%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0xa,%rax
  mov    -0x30(%rbp),%rdx
  add    $0x2,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  add    $0x3,%rax
  movb   $0x0,(%rax)
L48:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jbe    L37
  mov    $0xffffffff,%eax
  jmp    L5
L37:
  mov    -0x18(%rbp),%rax
  lea    0xc(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%eax
L5:
  leave
  ret
```

assistant: ```c
int tkh_decode_name_into(const char *s, char *id, int max_length, char *version) {
  if (!tkh_string_is_ticklish(s))
    return -1;
  size_t n = strnlen(s, 64) - 12;
  if (version != NULL) {
    version[0] = s[8];
    version[1] = s[9];
    version[2] = s[10];
    version[3] = 0;
  }
  if (n + 1 > max_length || n < 0)
    return -1;
  memcpy(id, s + 12, n);
  id[n] = 0;
  return n + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tkh_decode_name_into>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %edx,%r15d
  mov    %rcx,%r12
  call   <tkh_string_is_ticklish@plt>
  test   %eax,%eax
  je     L49
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <strnlen@plt>
  lea    -0xc(%rax),%ebp
  movslq %ebp,%r14
  test   %r12,%r12
  je     L35
  movzbl 0x8(%rbx),%eax
  mov    %al,(%r12)
  movzbl 0x9(%rbx),%eax
  mov    %al,0x1(%r12)
  movzbl 0xa(%rbx),%eax
  mov    %al,0x2(%r12)
  movb   $0x0,0x3(%r12)
L35:
  lea    0x1(%r14),%rax
  movslq %r15d,%r15
  cmp    %r15,%rax
  ja     L23
  lea    0xc(%rbx),%rsi
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%r14,1)
  lea    0x1(%rbp),%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  mov    $0xffffffff,%eax
  jmp    L1
L23:
  mov    $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
int tkh_decode_name_into(const char *s, char *id, int max_length, char *version) {
  if (!tkh_string_is_ticklish(s))
    return -1;
  size_t n = strnlen(s, 64) - 12;
  if (version != NULL) {
    version[0] = s[8];
    version[1] = s[9];
    version[2] = s[10];
    version[3] = 0;
  }
  if (n + 1 > max_length || n < 0)
    return -1;
  memcpy(id, s + 12, n);
  id[n] = 0;
  return n + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tkh_decode_name_into>:
  endbr64
  push   %r15
  push   %r14
  movslq %edx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <tkh_string_is_ticklish@plt>
  test   %eax,%eax
  je     L31
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <strnlen@plt>
  lea    -0xc(%rax),%r15d
  mov    %eax,%ebp
  movslq %r15d,%r15
  test   %r12,%r12
  je     L9
  movzbl 0x8(%rbx),%eax
  mov    %al,(%r12)
  movzbl 0x9(%rbx),%eax
  mov    %al,0x1(%r12)
  movzbl 0xa(%rbx),%eax
  movb   $0x0,0x3(%r12)
  mov    %al,0x2(%r12)
L9:
  lea    0x1(%r15),%rax
  cmp    %r14,%rax
  ja     L31
  lea    0xc(%rbx),%rsi
  mov    %r15,%rdx
  mov    %r13,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%r15,1)
  lea    -0xb(%rbp),%eax
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    $0xffffffff,%eax
  jmp    L24
```

assistant: ```c
int tkh_decode_name_into(const char *s, char *id, int max_length, char *version) {
  if (!tkh_string_is_ticklish(s))
    return -1;
  size_t n = strnlen(s, 64) - 12;
  if (version != NULL) {
    version[0] = s[8];
    version[1] = s[9];
    version[2] = s[10];
    version[3] = 0;
  }
  if (n + 1 > max_length || n < 0)
    return -1;
  memcpy(id, s + 12, n);
  id[n] = 0;
  return n + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<tkh_decode_name_into>:
  endbr64
  push   %r15
  push   %r14
  movslq %edx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <tkh_string_is_ticklish@plt>
  test   %eax,%eax
  je     L10
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <strnlen@plt>
  lea    -0xc(%rax),%r15d
  mov    %eax,%ebp
  movslq %r15d,%r15
  test   %r12,%r12
  je     L7
  movzbl 0x8(%rbx),%eax
  mov    %al,(%r12)
  movzbl 0x9(%rbx),%eax
  mov    %al,0x1(%r12)
  movzbl 0xa(%rbx),%eax
  movb   $0x0,0x3(%r12)
  mov    %al,0x2(%r12)
L7:
  lea    0x1(%r15),%rax
  cmp    %r14,%rax
  ja     L10
  lea    0xc(%rbx),%rsi
  mov    %r15,%rdx
  mov    %r13,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%r15,1)
  lea    -0xb(%rbp),%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int tkh_decode_name_into(const char *s, char *id, int max_length, char *version) {
  if (!tkh_string_is_ticklish(s))
    return -1;
  size_t n = strnlen(s, 64) - 12;
  if (version != NULL) {
    version[0] = s[8];
    version[1] = s[9];
    version[2] = s[10];
    version[3] = 0;
  }
  if (n + 1 > max_length || n < 0)
    return -1;
  memcpy(id, s + 12, n);
  id[n] = 0;
  return n + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<up_and_down>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x4(%rbp),%rdx
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cmp    $0x4,%eax
  jg     L3
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <up_and_down>
L3:
  mov    -0x4(%rbp),%eax
  lea    -0x4(%rbp),%rdx
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D29
datatype: string

tool: D18: Level %d: n location %p


tool: D29: %d  

assistant: ```c
void up_and_down(int n) {
  printf("Level %d: n location %p\n", n, &n);
  if (n < 5) {
    up_and_down(n + 1);
  }
  printf("Level %d: n location %p\n", n, &n);
  printf("%d  ", n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<up_and_down>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edi
  cmp    $0x4,%edi
  jle    L12
L5:
  lea    0xc(%rsp),%rdx
  mov    0xc(%rsp),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  ret
L12:
  add    $0x1,%edi
  call   <up_and_down>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string

tool: D1: Level %d: n location %p


tool: D26: %d  

assistant: ```c
void up_and_down(int n) {
  printf("Level %d: n location %p\n", n, &n);
  if (n < 5) {
    up_and_down(n + 1);
  }
  printf("Level %d: n location %p\n", n, &n);
  printf("%d  ", n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<up_and_down>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %eax,%eax
  push   %rbp
  lea    D2(%rip),%rbp
  sub    $0x18,%rsp
  lea    0xc(%rsp),%r12
  mov    %edi,0xc(%rsp)
  mov    %rbp,%rdi
  mov    %r12,%rdx
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  cmp    $0x4,%esi
  jle    L0
L2:
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    0x1(%rsi),%edi
  call   <up_and_down>
  mov    0xc(%rsp),%esi
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D19
type_guessed: string

tool: D2: Level %d: n location %p


tool: D19: %d  

assistant: ```c
void up_and_down(int n) {
  printf("Level %d: n location %p\n", n, &n);
  if (n < 5) {
    up_and_down(n + 1);
  }
  printf("Level %d: n location %p\n", n, &n);
  printf("%d  ", n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<up_and_down>:
  endbr64
  push   %r14
  mov    %edi,%esi
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  push   %rbp
  lea    D22(%rip),%rbp
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%r12
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  cmp    $0x4,%esi
  jle    L29
L27:
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r12,%rdx
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  lea    0x10(%rsp),%r14
  add    $0x1,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r14,%rdx
  mov    %esi,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  cmp    $0x4,%esi
  jle    L6
L7:
  mov    %r14,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    0x14(%rsp),%r13
  add    $0x1,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r13,%rdx
  mov    %esi,0x14(%rsp)
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  cmp    $0x4,%esi
  jle    L60
L56:
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D2(%rip),%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L60:
  lea    0x1(%rsi),%edi
  call   <up_and_down>
  mov    0x14(%rsp),%esi
  jmp    L56
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string
name: read_data
arguments: tag: D22
type_infered: string

tool: D2: %d  

tool: D22: Level %d: n location %p


assistant: ```c
void up_and_down(int n) {
  printf("Level %d: n location %p\n", n, &n);
  if (n < 5) {
    up_and_down(n + 1);
  }
  printf("Level %d: n location %p\n", n, &n);
  printf("%d  ", n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  cmp    $0x4,%eax
  jg     L20
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  js     L20
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  js     L20
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cmp    $0x4,%eax
  jle    L8
L20:
  mov    -0x38(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L34
L8:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  lea    (%rdx,%rax,1),%r8d
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%esi
  movslq %r8d,%rax
  movzbl (%rdi,%rax,1),%edx
  movslq %esi,%rax
  mov    %dl,(%rcx,%rax,1)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cltq
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rcx,%rax,1)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L34:
  pop    %rbp
  ret
```

assistant: ```c
void move(char puzzle[][5], int *spacex, int *spacey, int movex, int movey, char *flag) {
  char temp;
  if (*spacex + movex > 4 || *spacex + movex < 0 || *spacey + movey < 0 || *spacey + movey > 4) {
    *flag = 0;
    return;
  }
  temp = puzzle[*spacex][*spacey];
  puzzle[*spacex][*spacey] = puzzle[*spacex + movex][*spacey + movey];
  puzzle[*spacex + movex][*spacey + movey] = temp;
  *spacex += movex;
  *spacey += movey;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<move>:
  endbr64
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    (%rax),%r10d
  lea    (%r10,%rcx,1),%ecx
  cmp    $0x4,%ecx
  ja     L21
  push   %rbx
  mov    (%rsi),%r11d
  lea    (%r11,%r8,1),%ebx
  cmp    $0x4,%ebx
  jbe    L29
  movb   $0x0,(%r9)
L9:
  pop    %rbx
  ret
L29:
  movslq %r10d,%r10
  lea    (%r10,%r10,4),%r9
  add    %rdi,%r9
  movslq %r11d,%r11
  movzbl (%r9,%r11,1),%r10d
  movslq %ecx,%rcx
  lea    (%rcx,%rcx,4),%rcx
  add    %rdi,%rcx
  movslq %ebx,%rbx
  movzbl (%rcx,%rbx,1),%ecx
  mov    %cl,(%r9,%r11,1)
  mov    %edx,%ecx
  add    (%rax),%ecx
  movslq %ecx,%rcx
  lea    (%rcx,%rcx,4),%rcx
  add    %rcx,%rdi
  mov    %r8d,%ecx
  add    (%rsi),%ecx
  movslq %ecx,%rcx
  mov    %r10b,(%rdi,%rcx,1)
  add    %edx,(%rax)
  add    %r8d,(%rsi)
  jmp    L9
L21:
  movb   $0x0,(%r9)
  ret
```

assistant: ```c
void move(char puzzle[][5], int *spacex, int *spacey, int movex, int movey, char *flag) {
  char temp;
  if (*spacex + movex > 4 || *spacex + movex < 0 || *spacey + movey < 0 || *spacey + movey > 4) {
    *flag = 0;
    return;
  }
  temp = puzzle[*spacex][*spacey];
  puzzle[*spacex][*spacey] = puzzle[*spacex + movex][*spacey + movey];
  puzzle[*spacex + movex][*spacey + movey] = temp;
  *spacex += movex;
  *spacey += movey;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<move>:
  endbr64
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %ecx,%edx
  movslq (%rax),%r10
  add    %r10d,%ecx
  cmp    $0x4,%ecx
  ja     L10
  movslq (%rsi),%r11
  push   %rbx
  lea    (%r11,%r8,1),%ebx
  cmp    $0x4,%ebx
  jbe    L1
  movb   $0x0,(%r9)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %ecx,%rcx
  movslq %ebx,%rbx
  lea    (%r10,%r10,4),%r9
  lea    (%rcx,%rcx,4),%rcx
  add    %rdi,%r9
  add    %rdi,%rcx
  movzbl (%r9,%r11,1),%r10d
  movzbl (%rcx,%rbx,1),%ecx
  mov    %cl,(%r9,%r11,1)
  mov    (%rax),%ecx
  add    %edx,%ecx
  movslq %ecx,%rcx
  lea    (%rcx,%rcx,4),%rcx
  add    %rcx,%rdi
  mov    (%rsi),%ecx
  add    %r8d,%ecx
  movslq %ecx,%rcx
  mov    %r10b,(%rdi,%rcx,1)
  pop    %rbx
  add    %edx,(%rax)
  add    %r8d,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  movb   $0x0,(%r9)
  ret
```

assistant: ```c
void move(char puzzle[][5], int *spacex, int *spacey, int movex, int movey, char *flag) {
  char temp;
  if (*spacex + movex > 4 || *spacex + movex < 0 || *spacey + movey < 0 || *spacey + movey > 4) {
    *flag = 0;
    return;
  }
  temp = puzzle[*spacex][*spacey];
  puzzle[*spacex][*spacey] = puzzle[*spacex + movex][*spacey + movey];
  puzzle[*spacex + movex][*spacey + movey] = temp;
  *spacex += movex;
  *spacey += movey;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<move>:
  endbr64
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %ecx,%edx
  movslq (%rax),%r10
  add    %r10d,%ecx
  cmp    $0x4,%ecx
  ja     L3
  movslq (%rsi),%r11
  push   %rbx
  lea    (%r11,%r8,1),%ebx
  cmp    $0x4,%ebx
  jbe    L1
  movb   $0x0,(%r9)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %ecx,%rcx
  movslq %ebx,%rbx
  lea    (%r10,%r10,4),%r9
  lea    (%rcx,%rcx,4),%rcx
  add    %rdi,%r9
  add    %rdi,%rcx
  movzbl (%r9,%r11,1),%r10d
  movzbl (%rcx,%rbx,1),%ecx
  mov    %cl,(%r9,%r11,1)
  mov    (%rax),%ecx
  add    %edx,%ecx
  movslq %ecx,%rcx
  lea    (%rcx,%rcx,4),%rcx
  add    %rcx,%rdi
  mov    (%rsi),%ecx
  add    %r8d,%ecx
  movslq %ecx,%rcx
  mov    %r10b,(%rdi,%rcx,1)
  pop    %rbx
  add    %edx,(%rax)
  add    %r8d,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  movb   $0x0,(%r9)
  ret
```

assistant: ```c
void move(char puzzle[][5], int *spacex, int *spacey, int movex, int movey, char *flag) {
  char temp;
  if (*spacex + movex > 4 || *spacex + movex < 0 || *spacey + movey < 0 || *spacey + movey > 4) {
    *flag = 0;
    return;
  }
  temp = puzzle[*spacex][*spacey];
  puzzle[*spacex][*spacey] = puzzle[*spacex + movex][*spacey + movey];
  puzzle[*spacex + movex][*spacey + movey] = temp;
  *spacex += movex;
  *spacey += movey;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f7c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    $0x0,%eax
  call   <qux@plt>
  cltq
  mov    %rax,-0x8(%rbp)
L0:
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x18(%rbp),%rax
  jmp    L16
L6:
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x18(%rbp),%rax
L16:
  leave
  ret
```

assistant: ```c
int *f7c(int *x) {
  int *p = 0;
  if (((void *)0) == x)
    p = qux();
  if (((void *)0) != x)
    return x;
  *p = 1;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f7c>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L17
L10:
  mov    %rbx,%rax
  pop    %rbx
  ret
L17:
  mov    $0x0,%eax
  call   <qux@plt>
  cltq
  movl   $0x1,(%rax)
  jmp    L10
```

assistant: ```c
int *f7c(int *x) {
  int *p = 0;
  if (((void *)0) == x)
    p = qux();
  if (((void *)0) != x)
    return x;
  *p = 1;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f7c>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  jne    L0
  xor    %eax,%eax
  call   <qux@plt>
  cltq
  movl   $0x1,(%rax)
L0:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int *f7c(int *x) {
  int *p = 0;
  if (((void *)0) == x)
    p = qux();
  if (((void *)0) != x)
    return x;
  *p = 1;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f7c>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  jne    L5
  xor    %eax,%eax
  call   <qux@plt>
  cltq
  movl   $0x1,(%rax)
L5:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int *f7c(int *x) {
  int *p = 0;
  if (((void *)0) == x)
    p = qux();
  if (((void *)0) != x)
    return x;
  *p = 1;
  return x;
}
```