ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <ReadInt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fibonacci@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D9: 
fibonacci(%i): %lu


assistant: ```c
int main(int argc, char const *argv[]) {
  int inp = ReadInt();
  printf("\nfibonacci(%i): %lu\n", inp, fibonacci(inp));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <ReadInt@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <fibonacci@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D1: 
fibonacci(%i): %lu


assistant: ```c
int main(int argc, char const *argv[]) {
  int inp = ReadInt();
  printf("\nfibonacci(%i): %lu\n", inp, fibonacci(inp));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <ReadInt@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <fibonacci@plt>
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: 
fibonacci(%i): %lu


assistant: ```c
int main(int argc, char const *argv[]) {
  int inp = ReadInt();
  printf("\nfibonacci(%i): %lu\n", inp, fibonacci(inp));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <ReadInt@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <fibonacci@plt>
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: 
fibonacci(%i): %lu


assistant: ```c
int main(int argc, char const *argv[]) {
  int inp = ReadInt();
  printf("\nfibonacci(%i): %lu\n", inp, fibonacci(inp));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L1:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  mov    %eax,%edx
  sub    %esi,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x63,-0x4(%rbp)
  jle    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: %u 

assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int i;
  for (i = 0; i < 100; i++) {
    printf("%u ", rand() % 6);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x64,%ebx
  lea    D1(%rip),%rbp
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %u 

assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int i;
  for (i = 0; i < 100; i++) {
    printf("%u ", rand() % 6);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: %u 

assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int i;
  for (i = 0; i < 100; i++) {
    printf("%u ", rand() % 6);
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: %u 

assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int i;
  for (i = 0; i < 100; i++) {
    printf("%u ", rand() % 6);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<login>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  jns    L10
  mov    $0xffffffff,%eax
  jmp    L11
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
  mov    $0x0,%eax
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string

tool: D8: %s %s


assistant: ```c
int login(char *user, char *passwd, FILE *conn) {
  if (fprintf(conn, "%s %s\n", user, passwd) < 0) {
    return -1;
  }
  fflush(conn);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<login>:
  endbr64
  push   %rbx
  mov    %rsi,%rcx
  mov    %rdx,%rbx
  mov    %rdi,%rdx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  js     L16
  mov    %rbx,%rdi
  call   <fflush@plt>
  mov    $0x0,%eax
L4:
  pop    %rbx
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: %s %s


assistant: ```c
int login(char *user, char *passwd, FILE *conn) {
  if (fprintf(conn, "%s %s\n", user, passwd) < 0) {
    return -1;
  }
  fflush(conn);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<login>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  js     L5
  mov    %rbp,%rdi
  call   <fflush@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L5:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: %s %s


assistant: ```c
int login(char *user, char *passwd, FILE *conn) {
  if (fprintf(conn, "%s %s\n", user, passwd) < 0) {
    return -1;
  }
  fflush(conn);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<login>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  js     L3
  mov    %rbp,%rdi
  call   <fflush@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L3:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %s %s


assistant: ```c
int login(char *user, char *passwd, FILE *conn) {
  if (fprintf(conn, "%s %s\n", user, passwd) < 0) {
    return -1;
  }
  fflush(conn);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0x450,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x9438(%rbp)
  movl   $0x0,-0x9448(%rbp)
  lea    -0x9420(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    $0x32,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  movl   $0x4,-0x9430(%rbp)
  movl   $0x4,-0x942c(%rbp)
  movl   $0x4,-0x9428(%rbp)
  movl   $0x4,-0x9424(%rbp)
  movl   $0x0,-0x9444(%rbp)
  jmp    L58
L85:
  lea    -0x9420(%rbp),%rcx
  mov    -0x9444(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rcx
  lea    -0x9290(%rbp),%rax
  mov    $0xfa,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <get_all_words@plt>
  mov    %eax,-0x9434(%rbp)
  mov    -0x9434(%rbp),%ecx
  lea    -0x9290(%rbp),%rax
  mov    $0x96,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <print_string_array@plt>
  mov    -0x9444(%rbp),%eax
  cltq
  mov    -0x9430(%rbp,%rax,4),%eax
  cmp    %eax,-0x9434(%rbp)
  je     L92
  movl   $0xffffffff,-0x9448(%rbp)
L92:
  movl   $0x0,-0x9440(%rbp)
  jmp    L6
L76:
  movl   $0x0,-0x943c(%rbp)
  jmp    L1
L71:
  addl   $0x1,-0x943c(%rbp)
L1:
  mov    -0x943c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x9440(%rbp),%eax
  cltq
  imul   $0x96,%rax,%rax
  add    %rbp,%rax
  add    %rdx,%rax
  sub    $0x9290,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  cmpl   $0x0,-0x943c(%rbp)
  jg     L93
  mov    -0x943c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x9440(%rbp),%eax
  cltq
  imul   $0x96,%rax,%rax
  add    %rbp,%rax
  add    %rdx,%rax
  sub    $0x9290,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L93
  movl   $0xffffffff,-0x9448(%rbp)
L93:
  addl   $0x1,-0x9440(%rbp)
L6:
  mov    -0x9440(%rbp),%eax
  cmp    -0x9434(%rbp),%eax
  jl     L76
  addl   $0x1,-0x9444(%rbp)
L58:
  mov    -0x9444(%rbp),%eax
  cmp    -0x9438(%rbp),%eax
  jl     L85
  mov    -0x9448(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type: string

tool: D4:     Hello    world    good     !

assistant: ```c
int main() {
  int num = 4;
  int ret = 0;
  char source[4][100] = {"    Hello    world    good     !", "lol i good * # Hello world     p ", "  Hel, wr k   lk    ", "create_print_function printDouble \"%lf\" double"};
  int wc[4] = {4, 4, 4, 4};
  for (int k = 0; k < num; ++k) {
    char buff[250][150];
    int count = get_all_words(source[k], buff, 250);
    print_string_array(buff, count, 150);
    if (count != wc[k]) {
      ret = -1;
    }
    for (int i = 0; i < count; ++i) {
      int j;
      for (j = 0; buff[i][j] != '\0'; ++j)
        ;
      if (j < 1)
        if (buff[i][j] == ' ')
          ret = -1;
    }
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L97:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L97
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9428(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    D9(%rip),%rsi
  mov    $0x32,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  movl   $0x4,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %rsp,%rbp
  lea    0x1a0(%rsp),%r14
  mov    $0x0,%r12d
  mov    %r14,%r13
  jmp    L47
L28:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L28
L8:
  add    $0x96,%rdx
  cmp    %rcx,%rdx
  je     L57
L5:
  mov    %rdx,%rax
  cmpb   $0x0,-0x1(%rdx)
  jne    L28
  jmp    L8
L57:
  add    $0x64,%rbx
  add    $0x4,%rbp
  cmp    %r14,%rbx
  je     L31
L47:
  mov    $0xfa,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <get_all_words@plt>
  mov    %eax,%r15d
  mov    $0x96,%edx
  mov    %eax,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <print_string_array@plt>
  cmp    %r15d,0x0(%rbp)
  mov    $0xffffffff,%eax
  cmovne %eax,%r12d
  test   %r15d,%r15d
  jle    L57
  lea    0x1a1(%rsp),%rdx
  lea    -0x1(%r15),%eax
  imul   $0x96,%rax,%rax
  lea    0x237(%rsp,%rax,1),%rcx
  jmp    L5
L31:
  mov    0x9428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    %r12d,%eax
  add    $0x9438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9:     Hello    world    good     !

assistant: ```c
int main() {
  int num = 4;
  int ret = 0;
  char source[4][100] = {"    Hello    world    good     !", "lol i good * # Hello world     p ", "  Hel, wr k   lk    ", "create_print_function printDouble \"%lf\" double"};
  int wc[4] = {4, 4, 4, 4};
  for (int k = 0; k < num; ++k) {
    char buff[250][150];
    int count = get_all_words(source[k], buff, 250);
    print_string_array(buff, count, 150);
    if (count != wc[k]) {
      ret = -1;
    }
    for (int i = 0; i < count; ++i) {
      int j;
      for (j = 0; buff[i][j] != '\0'; ++j)
        ;
      if (j < 1)
        if (buff[i][j] == ' ')
          ret = -1;
    }
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x438,%rsp
  lea    D4(%rip),%rsi
  mov    $0x32,%ecx
  xor    %r15d,%r15d
  mov    $0xffffffff,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x9428(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0x10(%rsp),%rbp
  mov    %rsp,%r13
  rep movsq %ds:(%rsi),%es:(%rdi)
  lea    0x1a0(%rsp),%r12
  movabs $0x400000004,%rax
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
L10:
  mov    %rbp,%rdi
  mov    $0xfa,%edx
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <get_all_words@plt>
  mov    $0x96,%edx
  mov    %r12,%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <print_string_array@plt>
  cmp    %ebx,0x0(%r13)
  cmovne %r14d,%r15d
  add    $0x64,%rbp
  add    $0x4,%r13
  cmp    %r12,%rbp
  jne    L10
  mov    0x9428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x9438,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4:     Hello    world    good     !

assistant: ```c
int main() {
  int num = 4;
  int ret = 0;
  char source[4][100] = {"    Hello    world    good     !", "lol i good * # Hello world     p ", "  Hel, wr k   lk    ", "create_print_function printDouble \"%lf\" double"};
  int wc[4] = {4, 4, 4, 4};
  for (int k = 0; k < num; ++k) {
    char buff[250][150];
    int count = get_all_words(source[k], buff, 250);
    print_string_array(buff, count, 150);
    if (count != wc[k]) {
      ret = -1;
    }
    for (int i = 0; i < count; ++i) {
      int j;
      for (j = 0; buff[i][j] != '\0'; ++j)
        ;
      if (j < 1)
        if (buff[i][j] == ' ')
          ret = -1;
    }
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L8:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L8
  sub    $0x438,%rsp
  lea    D16(%rip),%rsi
  mov    $0x32,%ecx
  xor    %r15d,%r15d
  movdqa D4(%rip),%xmm0
  mov    $0xffffffff,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x9428(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  lea    0x10(%rsp),%rbp
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    %rsp,%r13
  lea    0x1a0(%rsp),%r12
L17:
  mov    %rbp,%rdi
  mov    $0xfa,%edx
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <get_all_words@plt>
  mov    $0x96,%edx
  mov    %r12,%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <print_string_array@plt>
  cmp    %ebx,0x0(%r13)
  cmovne %r14d,%r15d
  add    $0x64,%rbp
  add    $0x4,%r13
  cmp    %r12,%rbp
  jne    L17
  mov    0x9428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x9438,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type_infered: string
name: read_data
arguments: tag: D4
type_infered: byte[16]

tool: D16:     Hello    world    good     !

tool: {"D4": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int num = 4;
  int ret = 0;
  char source[4][100] = {"    Hello    world    good     !", "lol i good * # Hello world     p ", "  Hel, wr k   lk    ", "create_print_function printDouble \"%lf\" double"};
  int wc[4] = {4, 4, 4, 4};
  for (int k = 0; k < num; ++k) {
    char buff[250][150];
    int count = get_all_words(source[k], buff, 250);
    print_string_array(buff, count, 150);
    if (count != wc[k]) {
      ret = -1;
    }
    for (int i = 0; i < count; ++i) {
      int j;
      for (j = 0; buff[i][j] != '\0'; ++j)
        ;
      if (j < 1)
        if (buff[i][j] == ' ')
          ret = -1;
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cbm_parallel_burst_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <cbmarch_parallel_burst_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void cbm_parallel_burst_write(int HandleDevice, __u_char Value) {
  ;
  cbmarch_parallel_burst_write(HandleDevice, Value);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cbm_parallel_burst_write>:
  endbr64
  sub    $0x8,%rsp
  call   <cbmarch_parallel_burst_write@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cbm_parallel_burst_write(int HandleDevice, __u_char Value) {
  ;
  cbmarch_parallel_burst_write(HandleDevice, Value);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cbm_parallel_burst_write>:
  endbr64
  jmp    1050 <cbmarch_parallel_burst_write@plt>
```

assistant: ```c
void cbm_parallel_burst_write(int HandleDevice, __u_char Value) {
  ;
  cbmarch_parallel_burst_write(HandleDevice, Value);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cbm_parallel_burst_write>:
  endbr64
  jmp    1050 <cbmarch_parallel_burst_write@plt>
```

assistant: ```c
void cbm_parallel_burst_write(int HandleDevice, __u_char Value) {
  ;
  cbmarch_parallel_burst_write(HandleDevice, Value);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x6,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: TWO * THREE = SIX:
	%d * %d = %d


assistant: ```c
main(void) {
  printf("TWO"
         " * "
         "THREE"
         " = "
         "SIX"
         ":\n\t%d * %d = %d\n",
         2, 3, 2 * 3);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: TWO * THREE = SIX:
	%d * %d = %d


assistant: ```c
main(void) {
  printf("TWO"
         " * "
         "THREE"
         " = "
         "SIX"
         ":\n\t%d * %d = %d\n",
         2, 3, 2 * 3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: TWO * THREE = SIX:
	%d * %d = %d


assistant: ```c
main(void) {
  printf("TWO"
         " * "
         "THREE"
         " = "
         "SIX"
         ":\n\t%d * %d = %d\n",
         2, 3, 2 * 3);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D0: TWO * THREE = SIX:
	%d * %d = %d


assistant: ```c
main(void) {
  printf("TWO"
         " * "
         "THREE"
         " = "
         "SIX"
         ":\n\t%d * %d = %d\n",
         2, 3, 2 * 3);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__aeabi_idiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L1:
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int __aeabi_idiv(int num, int denom) {
  int q = 0;
  while (num >= denom) {
    num -= denom;
    q++;
  }
  return q;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__aeabi_idiv>:
  endbr64
  cmp    %esi,%edi
  jl     L7
  mov    $0x0,%eax
L18:
  sub    %esi,%edi
  add    $0x1,%eax
  cmp    %edi,%esi
  jle    L18
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int __aeabi_idiv(int num, int denom) {
  int q = 0;
  while (num >= denom) {
    num -= denom;
    q++;
  }
  return q;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__aeabi_idiv>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  jl     L13
  nopw   0x0(%rax,%rax,1)
L1:
  sub    %esi,%edi
  add    $0x1,%eax
  cmp    %edi,%esi
  jle    L1
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
int __aeabi_idiv(int num, int denom) {
  int q = 0;
  while (num >= denom) {
    num -= denom;
    q++;
  }
  return q;
}
```