ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mvnapp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe28,%rsp
  mov    (%rsi),%ebp
  mov    0xe68(%rsp),%rax
  mov    %rdi,0x8(%rsp)
  mov    %r9,0x10(%rsp)
  mov    0xe60(%rsp),%r15
  mov    %rax,0x18(%rsp)
  mov    0xe70(%rsp),%rax
  mov    %rax,0x20(%rsp)
  mov    0xe78(%rsp),%rax
  mov    %rax,0x28(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0xe18(%rsp)
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L21
  mov    %ebp,%ebx
  mov    %rcx,%r13
  mov    %rdx,%rsi
  mov    %r8,%r12
  shl    $0x3,%rbx
  lea    0x58(%rsp),%rdi
  xor    %r14d,%r14d
  mov    %rbx,%rdx
  call   <memcpy@plt>
  mov    %r13,%rsi
  lea    0xf8(%rsp),%rdi
  mov    %rbx,%rdx
  call   <memcpy@plt>
  lea    -0x1(%rbp),%eax
  lea    0x238(%rsp),%rcx
  lea    (%rax,%rax,4),%rax
  shl    $0x5,%rax
  lea    0x2d8(%rsp,%rax,1),%r13
  nopl   0x0(%rax)
L33:
  movslq %r14d,%rax
  mov    %rcx,%rdi
  mov    %rbx,%rdx
  add    %ebp,%r14d
  lea    (%r12,%rax,8),%rsi
  call   <memcpy@plt>
  mov    %rax,%rcx
  add    $0xa0,%rcx
  cmp    %r13,%rcx
  jne    L33
L21:
  mov    0x10(%rsp),%rax
  movsd  (%r15),%xmm0
  lea    0x190(%rsp),%rcx
  lea    0xf0(%rsp),%rdx
  lea    0x50(%rsp),%rsi
  mov    (%rax),%r8d
  mov    0x8(%rsp),%rax
  cmpl   $0x1,(%rax)
  lea    0x3c(%rsp),%rax
  je     L35
  push   %rax
  mov    %ebp,%edi
  lea    0x50(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%r9
  call   <mvn2@plt>
  pop    %rax
  pop    %rdx
L45:
  movsd  0x40(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  mov    0x28(%rsp),%rbx
  movsd  %xmm0,(%rax)
  mov    0x20(%rsp),%rax
  movsd  0x48(%rsp),%xmm0
  movsd  %xmm0,(%rax)
  mov    0x3c(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0xe18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0xe28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  push   %rax
  mov    %ebp,%edi
  lea    0x50(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%r9
  call   <mvn1@plt>
  pop    %rcx
  pop    %rsi
  jmp    L45
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mvnapp(int *type, int *m0, double w0[], double x0[], double corr[], int *nsim, double *eps, double *pr, double *sd, int *ifail) {
  double r[20][20];
  double w[20], x[20];
  double p, perr;
  int i, m, j, k, ierr;
  void mvn1(int, double[], double[], double[][20], int, double, double *, double *, int *);
  void mvn2(int, double[], double[], double[][20], int, double, double *, double *, int *);
  m = *m0;
  for (i = 1; i <= m; i++) {
    w[i] = w0[i - 1];
    x[i] = x0[i - 1];
  }
  for (i = 1, k = 0; i <= m; i++) {
    for (j = 1; j <= m; j++) {
      r[i][j] = corr[k];
      k++;
    }
  }
  if (*type == 1)
    mvn1(m, w, x, r, *nsim, *eps, &p, &perr, &ierr);
  else
    mvn2(m, w, x, r, *nsim, *eps, &p, &perr, &ierr);
  *pr = p;
  *sd = perr;
  *ifail = ierr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mvnapp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe28,%rsp
  mov    (%rsi),%ebp
  mov    0xe68(%rsp),%rax
  mov    %rdi,0x8(%rsp)
  mov    %r9,0x10(%rsp)
  mov    0xe60(%rsp),%r15
  mov    %rax,0x18(%rsp)
  mov    0xe70(%rsp),%rax
  mov    %rax,0x20(%rsp)
  mov    0xe78(%rsp),%rax
  mov    %rax,0x28(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0xe18(%rsp)
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L11
  mov    %ebp,%ebx
  mov    %rcx,%r13
  mov    %rdx,%rsi
  mov    %r8,%r12
  shl    $0x3,%rbx
  lea    0x58(%rsp),%rdi
  xor    %r14d,%r14d
  mov    %rbx,%rdx
  call   <memcpy@plt>
  mov    %r13,%rsi
  lea    0xf8(%rsp),%rdi
  mov    %rbx,%rdx
  call   <memcpy@plt>
  lea    -0x1(%rbp),%eax
  lea    0x238(%rsp),%rcx
  lea    (%rax,%rax,4),%rax
  shl    $0x5,%rax
  lea    0x2d8(%rsp,%rax,1),%r13
  nopl   0x0(%rax)
L29:
  movslq %r14d,%rax
  mov    %rcx,%rdi
  mov    %rbx,%rdx
  add    %ebp,%r14d
  lea    (%r12,%rax,8),%rsi
  call   <memcpy@plt>
  mov    %rax,%rcx
  add    $0xa0,%rcx
  cmp    %r13,%rcx
  jne    L29
L11:
  mov    0x10(%rsp),%rax
  movsd  (%r15),%xmm0
  lea    0x190(%rsp),%rcx
  lea    0xf0(%rsp),%rdx
  lea    0x50(%rsp),%rsi
  mov    (%rax),%r8d
  mov    0x8(%rsp),%rax
  cmpl   $0x1,(%rax)
  lea    0x3c(%rsp),%rax
  je     L38
  push   %rax
  mov    %ebp,%edi
  lea    0x50(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%r9
  call   <mvn2@plt>
  pop    %rax
  pop    %rdx
L48:
  movsd  0x40(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  mov    0x28(%rsp),%rbx
  movsd  %xmm0,(%rax)
  mov    0x20(%rsp),%rax
  movsd  0x48(%rsp),%xmm0
  movsd  %xmm0,(%rax)
  mov    0x3c(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0xe18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0xe28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  push   %rax
  mov    %ebp,%edi
  lea    0x50(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%r9
  call   <mvn1@plt>
  pop    %rcx
  pop    %rsi
  jmp    L48
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mvnapp(int *type, int *m0, double w0[], double x0[], double corr[], int *nsim, double *eps, double *pr, double *sd, int *ifail) {
  double r[20][20];
  double w[20], x[20];
  double p, perr;
  int i, m, j, k, ierr;
  void mvn1(int, double[], double[], double[][20], int, double, double *, double *, int *);
  void mvn2(int, double[], double[], double[][20], int, double, double *, double *, int *);
  m = *m0;
  for (i = 1; i <= m; i++) {
    w[i] = w0[i - 1];
    x[i] = x0[i - 1];
  }
  for (i = 1, k = 0; i <= m; i++) {
    for (j = 1; j <= m; j++) {
      r[i][j] = corr[k];
      k++;
    }
  }
  if (*type == 1)
    mvn1(m, w, x, r, *nsim, *eps, &p, &perr, &ierr);
  else
    mvn2(m, w, x, r, *nsim, *eps, &p, &perr, &ierr);
  *pr = p;
  *sd = perr;
  *ifail = ierr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L19:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L9
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x8,%eax
  add    $0x10,%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  and    $0x40,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %esi,%eax
  sar    %eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  and    $0x4,%eax
  shl    $0x2,%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x20,%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  and    $0x2,%eax
  add    %eax,%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x10,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %edx,(%rax)
L9:
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L19
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *split(int *block, int n) {
  int i;
  for (i = 0; i < 64; i++) {
    if ((i - 1) % n == 0) {
      block[i] = block[i] & 128 + (block[i] & 8) * 8 + (block[i] & 64) / 2 + (block[i] & 4) * 4 + (block[i] & 32) / 4 + (block[i] & 2) * 2 + (block[i] & 16) / 8 + (block[i] & 1);
    }
  }
  return block;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<split>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%edi
  mov    %r9,%rsi
  mov    $0xffffffff,%ecx
  jmp    L36
L39:
  add    $0x1,%ecx
  add    $0x4,%rsi
  cmp    $0x3f,%ecx
  je     L28
L36:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L39
  mov    (%rsi),%eax
  mov    %eax,%r8d
  and    $0x8,%r8d
  mov    %eax,%edx
  and    $0x40,%edx
  sar    %edx
  lea    0x80(%rdx,%r8,8),%edx
  mov    %eax,%r8d
  and    $0x4,%r8d
  lea    (%rdx,%r8,4),%edx
  mov    %eax,%r8d
  and    $0x20,%r8d
  sar    $0x2,%r8d
  add    %r8d,%edx
  mov    %eax,%r8d
  and    $0x2,%r8d
  lea    (%rdx,%r8,2),%edx
  mov    %eax,%r8d
  and    $0x10,%r8d
  sar    $0x3,%r8d
  add    %r8d,%edx
  mov    %eax,%r8d
  and    $0x1,%r8d
  add    %r8d,%edx
  and    %edx,%eax
  mov    %eax,(%rsi)
  jmp    L39
L28:
  mov    %r9,%rax
  ret
```

assistant: ```c
int *split(int *block, int n) {
  int i;
  for (i = 0; i < 64; i++) {
    if ((i - 1) % n == 0) {
      block[i] = block[i] & 128 + (block[i] & 8) * 8 + (block[i] & 64) / 2 + (block[i] & 4) * 4 + (block[i] & 32) / 4 + (block[i] & 2) * 2 + (block[i] & 16) / 8 + (block[i] & 1);
    }
  }
  return block;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<split>:
  endbr64
  mov    %rdi,%r9
  mov    $0xffffffff,%ecx
  mov    %esi,%edi
  mov    %r9,%rsi
  nopl   0x0(%rax)
L13:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L5
  mov    (%rsi),%eax
  mov    %eax,%edx
  mov    %eax,%r8d
  sar    %edx
  and    $0x8,%r8d
  and    $0x20,%edx
  lea    0x80(%rdx,%r8,8),%edx
  mov    %eax,%r8d
  and    $0x4,%r8d
  lea    (%rdx,%r8,4),%edx
  mov    %eax,%r8d
  sar    $0x2,%r8d
  and    $0x8,%r8d
  add    %r8d,%edx
  mov    %eax,%r8d
  and    $0x2,%r8d
  lea    (%rdx,%r8,2),%edx
  mov    %eax,%r8d
  sar    $0x3,%r8d
  and    $0x2,%r8d
  add    %r8d,%edx
  mov    %eax,%r8d
  and    $0x1,%r8d
  add    %r8d,%edx
  and    %edx,%eax
  mov    %eax,(%rsi)
L5:
  add    $0x1,%ecx
  add    $0x4,%rsi
  cmp    $0x3f,%ecx
  jne    L13
  mov    %r9,%rax
  ret
```

assistant: ```c
int *split(int *block, int n) {
  int i;
  for (i = 0; i < 64; i++) {
    if ((i - 1) % n == 0) {
      block[i] = block[i] & 128 + (block[i] & 8) * 8 + (block[i] & 64) / 2 + (block[i] & 4) * 4 + (block[i] & 32) / 4 + (block[i] & 2) * 2 + (block[i] & 16) / 8 + (block[i] & 1);
    }
  }
  return block;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<split>:
  endbr64
  mov    %rdi,%r9
  mov    $0xffffffff,%ecx
  mov    %esi,%edi
  mov    %r9,%rsi
  nopl   0x0(%rax)
L19:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L0
  mov    (%rsi),%eax
  mov    %eax,%edx
  mov    %eax,%r8d
  sar    %edx
  and    $0x8,%r8d
  and    $0x20,%edx
  lea    0x80(%rdx,%r8,8),%edx
  mov    %eax,%r8d
  and    $0x4,%r8d
  lea    (%rdx,%r8,4),%edx
  mov    %eax,%r8d
  sar    $0x2,%r8d
  and    $0x8,%r8d
  add    %r8d,%edx
  mov    %eax,%r8d
  and    $0x2,%r8d
  lea    (%rdx,%r8,2),%edx
  mov    %eax,%r8d
  sar    $0x3,%r8d
  and    $0x2,%r8d
  add    %r8d,%edx
  mov    %eax,%r8d
  and    $0x1,%r8d
  add    %r8d,%edx
  and    %edx,%eax
  mov    %eax,(%rsi)
L0:
  add    $0x1,%ecx
  add    $0x4,%rsi
  cmp    $0x3f,%ecx
  jne    L19
  mov    %r9,%rax
  ret
```

assistant: ```c
int *split(int *block, int n) {
  int i;
  for (i = 0; i < 64; i++) {
    if ((i - 1) % n == 0) {
      block[i] = block[i] & 128 + (block[i] & 8) * 8 + (block[i] & 64) / 2 + (block[i] & 4) * 4 + (block[i] & 32) / 4 + (block[i] & 2) * 2 + (block[i] & 16) / 8 + (block[i] & 1);
    }
  }
  return block;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<writeContent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: w

assistant: ```c
void writeContent(char *sentence, const char *filePath) {
  FILE *output = fopen(filePath, "w");
  fwrite(sentence, sizeof(char), strlen(sentence), output);
  fclose(output);
}
```
user: What is the c source code of the assembly code below?

```asm
<writeContent>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rcx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: w

assistant: ```c
void writeContent(char *sentence, const char *filePath) {
  FILE *output = fopen(filePath, "w");
  fwrite(sentence, sizeof(char), strlen(sentence), output);
  fclose(output);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writeContent>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  lea    D9(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %eax,%edx
  call   <fwrite@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <fclose@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: w

assistant: ```c
void writeContent(char *sentence, const char *filePath) {
  FILE *output = fopen(filePath, "w");
  fwrite(sentence, sizeof(char), strlen(sentence), output);
  fclose(output);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<writeContent>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  lea    D9(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %eax,%edx
  call   <fwrite@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <fclose@plt>
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: w

assistant: ```c
void writeContent(char *sentence, const char *filePath) {
  FILE *output = fopen(filePath, "w");
  fwrite(sentence, sizeof(char), strlen(sentence), output);
  fclose(output);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L14:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L13:
  mov    -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L51
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  jmp    L6
L67:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  jmp    L25
L1:
  addq   $0x1,-0x8(%rbp)
L51:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L67
L25:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
L6:
  leave
  ret
```

assistant: ```c
int get_word(char *word, int max_length) {
  int current_char;
  char *word_ptr = word;
  while (isspace(current_char = getch())) {
  }
  if (current_char != EOF) {
    *word_ptr++ = current_char;
  }
  if (!isalnum(current_char)) {
    *word_ptr = '\0';
    return current_char;
  }
  for (; --max_length > 0; ++word_ptr) {
    if (!isalnum(*word_ptr = getch())) {
      ungetch(*word_ptr);
      break;
    }
  }
  *word_ptr = '\0';
  return word[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_word>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
L19:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %rax,%rbx
  mov    %eax,%r14d
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  mov    %r12,%rbp
  mov    D0(%rip),%rax
  cmp    %ebx,(%rax)
  je     L43
  lea    0x1(%r12),%rbp
  mov    %bl,(%r12)
L43:
  movsbl %bl,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L27
  lea    -0x2(%r13),%eax
  lea    0x1(%rbp,%rax,1),%rbx
  cmp    $0x1,%r13d
  jle    L5
L61:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,0x0(%rbp)
  movsbl %al,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L12
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L61
  jmp    L40
L5:
  mov    %rbp,%rbx
  jmp    L40
L27:
  movb   $0x0,0x0(%rbp)
  jmp    L81
L12:
  movsbl 0x0(%rbp),%edi
  call   <ungetch@plt>
  mov    %rbp,%rbx
L40:
  movb   $0x0,(%rbx)
  movsbl (%r12),%r14d
L81:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_word(char *word, int max_length) {
  int current_char;
  char *word_ptr = word;
  while (isspace(current_char = getch())) {
  }
  if (current_char != EOF) {
    *word_ptr++ = current_char;
  }
  if (!isalnum(current_char)) {
    *word_ptr = '\0';
    return current_char;
  }
  for (; --max_length > 0; ++word_ptr) {
    if (!isalnum(*word_ptr = getch())) {
      ungetch(*word_ptr);
      break;
    }
  }
  *word_ptr = '\0';
  return word[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_word>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L58:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %rax,%rbx
  mov    %eax,%r14d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L58
  mov    D4(%rip),%rax
  mov    %r12,%rbp
  cmp    %ebx,(%rax)
  je     L65
  mov    %bl,(%r12)
  lea    0x1(%r12),%rbp
L65:
  movsbl %bl,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L20
  lea    -0x2(%r13),%eax
  lea    0x1(%rbp,%rax,1),%rbx
  cmp    $0x1,%r13d
  jg     L23
  jmp    L69
  nopl   (%rax)
L4:
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  je     L52
L23:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,0x0(%rbp)
  movsbl %al,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L4
  movsbl 0x0(%rbp),%edi
  call   <ungetch@plt>
L69:
  mov    %rbp,%rbx
L52:
  movb   $0x0,(%rbx)
  movsbl (%r12),%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  movb   $0x0,0x0(%rbp)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_word(char *word, int max_length) {
  int current_char;
  char *word_ptr = word;
  while (isspace(current_char = getch())) {
  }
  if (current_char != EOF) {
    *word_ptr++ = current_char;
  }
  if (!isalnum(current_char)) {
    *word_ptr = '\0';
    return current_char;
  }
  for (; --max_length > 0; ++word_ptr) {
    if (!isalnum(*word_ptr = getch())) {
      ungetch(*word_ptr);
      break;
    }
  }
  *word_ptr = '\0';
  return word[0];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_word>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %rax,%rbx
  mov    %eax,%r14d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
  mov    D7(%rip),%rax
  mov    %r12,%rbp
  cmp    %ebx,(%rax)
  je     L38
  mov    %bl,(%r12)
  lea    0x1(%r12),%rbp
L38:
  movsbl %bl,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L32
  lea    -0x2(%r13),%eax
  lea    0x1(%rbp,%rax,1),%rbx
  cmp    $0x1,%r13d
  jg     L31
  jmp    L42
  nopl   (%rax)
L20:
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  je     L59
L31:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,0x0(%rbp)
  movsbl %al,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L20
  movsbl 0x0(%rbp),%edi
  call   <ungetch@plt>
L42:
  mov    %rbp,%rbx
L59:
  movb   $0x0,(%rbx)
  movsbl (%r12),%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  movb   $0x0,0x0(%rbp)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_word(char *word, int max_length) {
  int current_char;
  char *word_ptr = word;
  while (isspace(current_char = getch())) {
  }
  if (current_char != EOF) {
    *word_ptr++ = current_char;
  }
  if (!isalnum(current_char)) {
    *word_ptr = '\0';
    return current_char;
  }
  for (; --max_length > 0; ++word_ptr) {
    if (!isalnum(*word_ptr = getch())) {
      ungetch(*word_ptr);
      break;
    }
  }
  *word_ptr = '\0';
  return word[0];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<egetch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getch0@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  je     L111
  cmpl   $0x4,-0xc(%rbp)
  je     L111
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L111
  cmpl   $0x71,-0xc(%rbp)
  je     L111
  cmpl   $0x51,-0xc(%rbp)
  jne    L122
L111:
  mov    $0x0,%eax
  call   <quit@plt>
L122:
  cmpl   $0x1b,-0xc(%rbp)
  je     L81
  mov    -0xc(%rbp),%eax
  jmp    L20
L81:
  mov    $0x0,%eax
  call   <getch0@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <getch0@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x41,-0x4(%rbp)
  jne    L41
  mov    $0x101,%eax
  jmp    L20
L41:
  cmpl   $0x42,-0x4(%rbp)
  jne    L102
  mov    $0x102,%eax
  jmp    L20
L102:
  cmpl   $0x43,-0x4(%rbp)
  jne    L29
  mov    $0x103,%eax
  jmp    L20
L29:
  cmpl   $0x44,-0x4(%rbp)
  jne    L64
  mov    $0x104,%eax
  jmp    L20
L64:
  mov    $0x0,%eax
L20:
  leave
  ret
```

assistant: ```c
int egetch() {
  int c, d, e;
  c = getch0();
  if (c == 3 || c == 4 || c == -1 || c == 'q' || c == 'Q')
    quit();
  if (c != 27)
    return c;
  d = getch0();
  e = getch0();
  if (e == 'A')
    return 257;
  if (e == 'B')
    return 258;
  if (e == 'C')
    return 259;
  if (e == 'D')
    return 260;
  return 0;
}
```