ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<M26_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D19(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string

tool: D19: M26_f(const char *s) is not yet implemented!


tool: D18: %s


assistant: ```c
int M26_f(char *s) {
  debug("M26_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<M26_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string
name: unpack_data
arguments: data_label: D2
data_type: string

tool: D3: M26_f(const char *s) is not yet implemented!


tool: D2: %s


assistant: ```c
int M26_f(char *s) {
  debug("M26_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lookfor_notzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  jmp    L34
L49:
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  movsd  (%rcx,%rdx,8),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L44
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  je     L9
L44:
  mov    -0x24(%rbp),%eax
  jmp    L2
L9:
  addl   $0x1,-0x24(%rbp)
L34:
  mov    -0x24(%rbp),%edx
  cmp    -0x14(%rbp),%edx
  jl     L49
  mov    $0xffffffff,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int lookfor_notzero(int imax, int jmax, double matrix[imax][jmax], int i, int j) {
  for (; i < imax; ++i) {
    if (matrix[i][j] != 0)
      return i;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lookfor_notzero>:
  endbr64
  mov    %ecx,%eax
  movslq %esi,%r9
  cmp    %ecx,%edi
  jle    L13
  lea    0x0(,%r9,8),%rcx
  movslq %eax,%rsi
  imul   %r9,%rsi
  movslq %r8d,%r8
  add    %r8,%rsi
  lea    (%rdx,%rsi,8),%rdx
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm1
L18:
  ucomisd (%rdx),%xmm0
  jp     L1
  ucomisd (%rdx),%xmm1
  jne    L1
  add    $0x1,%eax
  add    %rcx,%rdx
  cmp    %eax,%edi
  jne    L18
  mov    $0xffffffff,%eax
  ret
L13:
  mov    $0xffffffff,%eax
L1:
  ret
```

assistant: ```c
int lookfor_notzero(int imax, int jmax, double matrix[imax][jmax], int i, int j) {
  for (; i < imax; ++i) {
    if (matrix[i][j] != 0)
      return i;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lookfor_notzero>:
  endbr64
  mov    %ecx,%eax
  movslq %esi,%r9
  cmp    %ecx,%edi
  jle    L21
  movslq %eax,%rsi
  movslq %r8d,%r8
  lea    0x0(,%r9,8),%rcx
  imul   %r9,%rsi
  pxor   %xmm0,%xmm0
  add    %r8,%rsi
  lea    (%rdx,%rsi,8),%rdx
  jmp    L13
  nopl   0x0(%rax)
L20:
  add    $0x1,%eax
  add    %rcx,%rdx
  cmp    %eax,%edi
  je     L21
L13:
  ucomisd (%rdx),%xmm0
  jp     L41
  je     L20
L41:
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lookfor_notzero(int imax, int jmax, double matrix[imax][jmax], int i, int j) {
  for (; i < imax; ++i) {
    if (matrix[i][j] != 0)
      return i;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lookfor_notzero>:
  endbr64
  mov    %ecx,%eax
  movslq %esi,%r9
  cmp    %ecx,%edi
  jle    L43
  movslq %eax,%rsi
  movslq %r8d,%r8
  lea    0x0(,%r9,8),%rcx
  imul   %r9,%rsi
  pxor   %xmm0,%xmm0
  add    %r8,%rsi
  lea    (%rdx,%rsi,8),%rdx
  jmp    L44
  nopl   0x0(%rax)
L23:
  add    $0x1,%eax
  add    %rcx,%rdx
  cmp    %eax,%edi
  je     L43
L44:
  ucomisd (%rdx),%xmm0
  jp     L4
  je     L23
L4:
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lookfor_notzero(int imax, int jmax, double matrix[imax][jmax], int i, int j) {
  for (; i < imax; ++i) {
    if (matrix[i][j] != 0)
      return i;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L83
  movss  0xc(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L16
  comiss %xmm0,%xmm1
  ja     L49
L16:
  movss  0x10(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jb     L121
  comiss %xmm0,%xmm2
  ja     L25
L121:
  movss  0x14(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L31
  comiss %xmm0,%xmm1
  ja     L37
L31:
  comiss %xmm0,%xmm2
  jbe    L43
  lea    D82(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L83:
  lea    D86(%rip),%rdi
  call   <printf@plt>
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L49:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L25:
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L37:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D55
data_type: string
name: disassemble_data
arguments: data_tag: D50
data_type: string
name: disassemble_data
arguments: data_tag: D48
data_type: string
name: disassemble_data
arguments: data_tag: D82
data_type: string
name: disassemble_data
arguments: data_tag: D86
data_type: string
name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D44
data_type: string
name: disassemble_data
arguments: data_tag: D22
data_type: string

tool: D16: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D55: %f%f%f%f

tool: D50: Thank you. Now enter student score (percent) >

tool: D48: %f

tool: D82: Studnet has failed the course


tool: D86: Student has an A grade


tool: D20: Student has an B grade


tool: D44: Studnet has an C grade


tool: D22: Student has an D grade


assistant: ```c
int main() {
  float grade, per1, per2, per3, per4;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &per1, &per2, &per3, &per4);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &grade);
  if (grade >= per1) {
    printf("Student has an A grade\n");
  } else if (grade >= per2 && grade < per1) {
    printf("Student has an B grade\n");
  } else if (grade >= per3 && grade < per2) {
    printf("Studnet has an C grade\n");
  } else if (grade >= per4 && grade < per3) {
    printf("Student has an D grade\n");
  } else if (grade < per4) {
    printf("Studnet has failed the course\n");
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  lea    D81(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D57(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L121
  movss  0xc(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L43
  comiss %xmm0,%xmm1
  ja     L112
L43:
  movss  0x10(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L1
L56:
  movss  0x14(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L133
  comiss %xmm0,%xmm1
  ja     L2
L133:
  comiss %xmm0,%xmm2
  ja     L44
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  comiss %xmm0,%xmm2
  jbe    L56
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L121:
  lea    D88(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L112:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L2:
  lea    D87(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L44:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D25
type_infered: string
name: retrieve_data
arguments: data_tag: D81
type_infered: string
name: retrieve_data
arguments: data_tag: D57
type_infered: string
name: retrieve_data
arguments: data_tag: D44
type_infered: string
name: retrieve_data
arguments: data_tag: D88
type_infered: string
name: retrieve_data
arguments: data_tag: D34
type_infered: string
name: retrieve_data
arguments: data_tag: D87
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string

tool: D12: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D25: %f%f%f%f

tool: D81: Thank you. Now enter student score (percent) >

tool: D57: %f

tool: D44: Studnet has an C grade


tool: D88: Student has an A grade


tool: D34: Student has an B grade


tool: D87: Student has an D grade


tool: D29: Studnet has failed the course


assistant: ```c
int main() {
  float grade, per1, per2, per3, per4;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &per1, &per2, &per3, &per4);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &grade);
  if (grade >= per1) {
    printf("Student has an A grade\n");
  } else if (grade >= per2 && grade < per1) {
    printf("Student has an B grade\n");
  } else if (grade >= per3 && grade < per2) {
    printf("Studnet has an C grade\n");
  } else if (grade >= per4 && grade < per3) {
    printf("Student has an D grade\n");
  } else if (grade < per4) {
    printf("Studnet has failed the course\n");
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  lea    D60(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L8
  movss  0xc(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L51
  comiss %xmm0,%xmm1
  ja     L88
L51:
  movss  0x10(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L24
L86:
  movss  0x14(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L99
  comiss %xmm0,%xmm1
  ja     L128
L99:
  comiss %xmm0,%xmm2
  ja     L117
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L24:
  comiss %xmm0,%xmm2
  jbe    L86
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L8:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L88:
  lea    D66(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L128:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L117:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D56
type: string
name: read_data
arguments: data_tag: D60
type: string
name: read_data
arguments: data_tag: D21
type: string
name: read_data
arguments: data_tag: D29
type: string
name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D66
type: string
name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D53
type: string

tool: D30: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D56: %f%f%f%f

tool: D60: Thank you. Now enter student score (percent) >

tool: D21: %f

tool: D29: Studnet has an C grade


tool: D11: Student has an A grade


tool: D66: Student has an B grade


tool: D34: Student has an D grade


tool: D53: Studnet has failed the course


assistant: ```c
int main() {
  float grade, per1, per2, per3, per4;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &per1, &per2, &per3, &per4);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &grade);
  if (grade >= per1) {
    printf("Student has an A grade\n");
  } else if (grade >= per2 && grade < per1) {
    printf("Student has an B grade\n");
  } else if (grade >= per3 && grade < per2) {
    printf("Studnet has an C grade\n");
  } else if (grade >= per4 && grade < per3) {
    printf("Student has an D grade\n");
  } else if (grade < per4) {
    printf("Studnet has failed the course\n");
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<HandleKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xff1b,-0x4(%rbp)
  jne    L0
  mov    $0x0,%edi
  call   <exit@plt>
L0:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: Key: %d -> %d


assistant: ```c
void HandleKey(int keycode, int bDown) {
  if (keycode == 65307)
    exit(0);
  printf("Key: %d -> %d\n", keycode, bDown);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<HandleKey>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0xff1b,%edi
  je     L19
L0:
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: Key: %d -> %d


assistant: ```c
void HandleKey(int keycode, int bDown) {
  if (keycode == 65307)
    exit(0);
  printf("Key: %d -> %d\n", keycode, bDown);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HandleKey>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %edi,%ebp
  sub    $0x10,%rsp
  cmp    $0xff1b,%edi
  je     L12
L13:
  add    $0x10,%rsp
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %edi,%edi
  mov    %esi,0xc(%rsp)
  call   <exit@plt>
  mov    0xc(%rsp),%edx
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string

tool: D5: Key: %d -> %d


assistant: ```c
void HandleKey(int keycode, int bDown) {
  if (keycode == 65307)
    exit(0);
  printf("Key: %d -> %d\n", keycode, bDown);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<HandleKey>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %edi,%ebp
  sub    $0x10,%rsp
  cmp    $0xff1b,%edi
  je     L9
L5:
  add    $0x10,%rsp
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %edi,%edi
  mov    %esi,0xc(%rsp)
  call   <exit@plt>
  mov    0xc(%rsp),%edx
  jmp    L5
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: Key: %d -> %d


assistant: ```c
void HandleKey(int keycode, int bDown) {
  if (keycode == 65307)
    exit(0);
  printf("Key: %d -> %d\n", keycode, bDown);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  shl    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  shl    $0x10,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  shl    $0x18,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int getle(FILE *f) {
  unsigned int res;
  res = fgetc(f);
  res |= fgetc(f) << 8;
  res |= fgetc(f) << 16;
  res |= fgetc(f) << 24;
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getle>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <fgetc@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <fgetc@plt>
  shl    $0x8,%ebx
  shl    $0x10,%eax
  or     %eax,%ebx
  or     %r12d,%ebx
  mov    %rbp,%rdi
  call   <fgetc@plt>
  shl    $0x18,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int getle(FILE *f) {
  unsigned int res;
  res = fgetc(f);
  res |= fgetc(f) << 8;
  res |= fgetc(f) << 16;
  res |= fgetc(f) << 24;
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getle>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <fgetc@plt>
  shl    $0x8,%ebx
  mov    %rbp,%rdi
  shl    $0x10,%eax
  or     %eax,%ebx
  call   <fgetc@plt>
  or     %r12d,%ebx
  shl    $0x18,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int getle(FILE *f) {
  unsigned int res;
  res = fgetc(f);
  res |= fgetc(f) << 8;
  res |= fgetc(f) << 16;
  res |= fgetc(f) << 24;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getle>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <fgetc@plt>
  shl    $0x8,%ebx
  mov    %rbp,%rdi
  shl    $0x10,%eax
  or     %eax,%ebx
  call   <fgetc@plt>
  or     %r12d,%ebx
  shl    $0x18,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int getle(FILE *f) {
  unsigned int res;
  res = fgetc(f);
  res |= fgetc(f) << 8;
  res |= fgetc(f) << 16;
  res |= fgetc(f) << 24;
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wv_ugstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L5
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <wv_ugch@plt>
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void wv_ugstr(s) char *s;
{
  while (*s != '\0')
    wv_ugch(*s++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wv_ugstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L6
L5:
  add    $0x1,%rbx
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <wv_ugch@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
L6:
  pop    %rbx
  ret
```

assistant: ```c
void wv_ugstr(s) char *s;
{
  while (*s != '\0')
    wv_ugch(*s++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wv_ugstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
L2:
  add    $0x1,%rbx
  xor    %eax,%eax
  call   <wv_ugch@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L2
L10:
  pop    %rbx
  ret
```

assistant: ```c
void wv_ugstr(s) char *s;
{
  while (*s != '\0')
    wv_ugch(*s++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wv_ugstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L11
L12:
  add    $0x1,%rbx
  xor    %eax,%eax
  call   <wv_ugch@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L12
L11:
  pop    %rbx
  ret
```

assistant: ```c
void wv_ugstr(s) char *s;
{
  while (*s != '\0')
    wv_ugch(*s++);
}
```
user: What is the c source code of the assembly code below:

```asm
<quest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L29
  movzbl -0x70(%rbp),%eax
  cmp    $0x79,%al
  jne    L35
  mov    $0x1,%eax
  jmp    L42
L35:
  mov    $0x2,%eax
  jmp    L42
L29:
  mov    $0x3,%eax
L42:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
quest() {
  char *s;
  char answer[100];
  s = answer;
  if (gets(s) != NULL) {
    if (answer[0] == 'y')
      return (1);
    else
      return (2);
  }
  return (3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quest>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L20
  cmpb   $0x79,(%rsp)
  setne  %al
  movzbl %al,%eax
  add    $0x1,%eax
L25:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x78,%rsp
  ret
L20:
  mov    $0x3,%eax
  jmp    L25
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
quest() {
  char *s;
  char answer[100];
  s = answer;
  if (gets(s) != NULL) {
    if (answer[0] == 'y')
      return (1);
    else
      return (2);
  }
  return (3);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<quest>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L3
  xor    %eax,%eax
  cmpb   $0x79,(%rsp)
  setne  %al
  add    $0x1,%eax
L21:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x78,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    $0x3,%eax
  jmp    L21
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
quest() {
  char *s;
  char answer[100];
  s = answer;
  if (gets(s) != NULL) {
    if (answer[0] == 'y')
      return (1);
    else
      return (2);
  }
  return (3);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quest>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L7
  xor    %eax,%eax
  cmpb   $0x79,(%rsp)
  setne  %al
  add    $0x1,%eax
L19:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x78,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    $0x3,%eax
  jmp    L19
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
quest() {
  char *s;
  char answer[100];
  s = answer;
  if (gets(s) != NULL) {
    if (answer[0] == 'y')
      return (1);
    else
      return (2);
  }
  return (3);
}
```