ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<timeval_sub>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%rdi
  mov    (%rdx),%r8
  mov    0x8(%rdx),%r10
  mov    (%rdi),%rcx
  mov    %rdx,%rsi
  cmp    %r8,%rcx
  jge    L10
  mov    %r8,%rdx
  sub    %rcx,%rdx
  movabs $0x431bde82d7b634db,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x12,%rdx
  add    $0x1,%edx
  imul   $0xf4240,%edx,%eax
  movslq %edx,%rdx
  add    %rdx,%r10
  mov    %r10,0x8(%rsi)
  cltq
  sub    %rax,%r8
  mov    %r8,(%rsi)
  mov    (%rdi),%rcx
L10:
  sub    %r8,%rcx
  cmp    $0xf4240,%rcx
  jle    L0
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rcx
  imul   %rdx
  sar    $0x12,%rdx
  sub    %rcx,%rdx
  imul   $0xf4240,%edx,%eax
  movslq %edx,%rdx
  sub    %rdx,%r10
  mov    %r10,0x8(%rsi)
  cltq
  add    %r8,%rax
  mov    %rax,(%rsi)
  mov    (%rdi),%rcx
  sub    %rax,%rcx
L0:
  mov    0x8(%rdi),%rax
  movq   %rcx,%xmm0
  sub    %r10,%rax
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%r9)
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int timeval_sub(struct timeval *result, struct timeval *x, struct timeval *y) {
  if (x->tv_usec < y->tv_usec) {
    int nsec = (y->tv_usec - x->tv_usec) / 1000000 + 1;
    y->tv_usec -= 1000000 * nsec;
    y->tv_sec += nsec;
  }
  if (x->tv_usec - y->tv_usec > 1000000) {
    int nsec = (x->tv_usec - y->tv_usec) / 1000000;
    y->tv_usec += 1000000 * nsec;
    y->tv_sec -= nsec;
  }
  result->tv_sec = x->tv_sec - y->tv_sec;
  result->tv_usec = x->tv_usec - y->tv_usec;
  return x->tv_sec < y->tv_sec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itohex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L23
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x30,(%rax)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L75
L23:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L8:
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,-0x8(%rbp)
L14:
  cmpl   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0xc(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rax,-0x20(%rbp)
  jmp    L79
L93:
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jle    L49
  cmpl   $0x0,-0x18(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  lea    0x37(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L16
L1:
  mov    -0x4(%rbp),%eax
  lea    0x57(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L16
L49:
  mov    -0x4(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L16:
  mov    -0x14(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,-0x14(%rbp)
L79:
  cmpl   $0x0,-0x14(%rbp)
  jne    L93
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
L75:
  pop    %rbp
  ret
```

assistant: ```c
void itohex(unsigned int value, char *str, int uppercase) {
  int length;
  unsigned int tmp;
  int digit;
  if (value == 0) {
    *(str++) = '0';
    *str = '\0';
    return;
  }
  tmp = value;
  length = 0;
  while (tmp > 0) {
    length++;
    tmp /= 0x10;
  }
  str += length - 1;
  while (value > 0) {
    digit = (value % 0x10);
    if (digit >= 10)
      if (uppercase)
        *(str--) = (digit - 10) + 'A';
      else
        *(str--) = (digit - 10) + 'a';
    else
      *(str--) = digit + '0';
    value /= 0x10;
  }
  str += length + 1;
  *(str) = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itohex>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  mov    $0x0,%edi
  test   %ecx,%ecx
  je     L23
L13:
  add    $0x1,%edi
  mov    %eax,%r8d
  shr    $0x4,%eax
  cmp    $0xf,%r8d
  ja     L13
  movslq %edi,%rdi
  lea    -0x2(%rsi,%rdi,1),%rsi
  jmp    L43
L23:
  movb   $0x30,(%rsi)
  movb   $0x0,0x1(%rsi)
  ret
L56:
  mov    %rsi,%r8
  add    $0x57,%eax
  jmp    L32
L19:
  mov    %rsi,%r8
  add    $0x30,%eax
L32:
  mov    %al,0x1(%rsi)
  mov    %ecx,%eax
  shr    $0x4,%eax
  sub    $0x1,%rsi
  cmp    $0xf,%ecx
  jbe    L27
  mov    %eax,%ecx
L43:
  mov    %ecx,%eax
  and    $0xf,%eax
  cmp    $0x9,%eax
  jle    L19
  test   %edx,%edx
  je     L56
  mov    %rsi,%r8
  add    $0x37,%eax
  jmp    L32
L27:
  movb   $0x0,0x1(%r8,%rdi,1)
  ret
```

assistant: ```c
void itohex(unsigned int value, char *str, int uppercase) {
  int length;
  unsigned int tmp;
  int digit;
  if (value == 0) {
    *(str++) = '0';
    *str = '\0';
    return;
  }
  tmp = value;
  length = 0;
  while (tmp > 0) {
    length++;
    tmp /= 0x10;
  }
  str += length - 1;
  while (value > 0) {
    digit = (value % 0x10);
    if (digit >= 10)
      if (uppercase)
        *(str--) = (digit - 10) + 'A';
      else
        *(str--) = (digit - 10) + 'a';
    else
      *(str--) = digit + '0';
    value /= 0x10;
  }
  str += length + 1;
  *(str) = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<itohex>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  xor    %edi,%edi
  test   %ecx,%ecx
  je     L20
  xchg   %ax,%ax
L17:
  add    $0x1,%edi
  shr    $0x4,%eax
  jne    L17
  movslq %edi,%r8
  lea    -0x1(%rsi,%r8,1),%rsi
L15:
  mov    %ecx,%eax
  mov    %rsi,%r9
  sub    $0x1,%rsi
  and    $0xf,%eax
  lea    0x30(%rax),%edi
  cmp    $0x9,%eax
  jle    L24
  lea    0x37(%rax),%edi
  add    $0x57,%eax
  test   %edx,%edx
  cmove  %eax,%edi
L24:
  shr    $0x4,%ecx
  mov    %dil,0x1(%rsi)
  jne    L15
  movb   $0x0,(%r9,%r8,1)
  ret
  xchg   %ax,%ax
L20:
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void itohex(unsigned int value, char *str, int uppercase) {
  int length;
  unsigned int tmp;
  int digit;
  if (value == 0) {
    *(str++) = '0';
    *str = '\0';
    return;
  }
  tmp = value;
  length = 0;
  while (tmp > 0) {
    length++;
    tmp /= 0x10;
  }
  str += length - 1;
  while (value > 0) {
    digit = (value % 0x10);
    if (digit >= 10)
      if (uppercase)
        *(str--) = (digit - 10) + 'A';
      else
        *(str--) = (digit - 10) + 'a';
    else
      *(str--) = digit + '0';
    value /= 0x10;
  }
  str += length + 1;
  *(str) = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itohex>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  xor    %edi,%edi
  test   %eax,%eax
  je     L61
  nopw   0x0(%rax,%rax,1)
L84:
  add    $0x1,%edi
  shr    $0x4,%ecx
  jne    L84
  movslq %edi,%rdi
  lea    -0x1(%rsi,%rdi,1),%rcx
  test   %edx,%edx
  jne    L91
  nopl   0x0(%rax)
L17:
  mov    %eax,%edx
  sub    $0x1,%rcx
  and    $0xf,%edx
  cmp    $0x9,%edx
  jle    L5
  add    $0x57,%edx
  shr    $0x4,%eax
  mov    %dl,0x1(%rcx)
  jne    L17
L32:
  movb   $0x0,0x1(%rcx,%rdi,1)
  ret
  nop
L0:
  add    $0x30,%edx
  shr    $0x4,%eax
  mov    %dl,0x1(%rcx)
  je     L32
L91:
  mov    %eax,%edx
  sub    $0x1,%rcx
  and    $0xf,%edx
  cmp    $0x9,%edx
  jle    L0
  add    $0x37,%edx
  shr    $0x4,%eax
  mov    %dl,0x1(%rcx)
  jne    L91
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L5:
  add    $0x30,%edx
  shr    $0x4,%eax
  mov    %dl,0x1(%rcx)
  jne    L17
  movb   $0x0,0x1(%rcx,%rdi,1)
  ret
  nopl   0x0(%rax)
L61:
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void itohex(unsigned int value, char *str, int uppercase) {
  int length;
  unsigned int tmp;
  int digit;
  if (value == 0) {
    *(str++) = '0';
    *str = '\0';
    return;
  }
  tmp = value;
  length = 0;
  while (tmp > 0) {
    length++;
    tmp /= 0x10;
  }
  str += length - 1;
  while (value > 0) {
    digit = (value % 0x10);
    if (digit >= 10)
      if (uppercase)
        *(str--) = (digit - 10) + 'A';
      else
        *(str--) = (digit - 10) + 'a';
    else
      *(str--) = digit + '0';
    value /= 0x10;
  }
  str += length + 1;
  *(str) = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<softboundmpx_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L1
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_copy_metadata@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) void *softboundmpx_realloc(void *ptr, size_t size) {
  void *ret_ptr = realloc(ptr, size);
  __softboundmpx_store_return_metadata(ret_ptr, (char *)(ret_ptr) + size);
  if (ret_ptr != ptr) {
    __softboundmpx_copy_metadata(ret_ptr, ptr, size);
  }
  return ret_ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<softboundmpx_realloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <realloc@plt>
  mov    %rax,%rbx
  lea    (%rax,%r12,1),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  cmp    %rbx,%rbp
  je     L1
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__softboundmpx_copy_metadata@plt>
L1:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) void *softboundmpx_realloc(void *ptr, size_t size) {
  void *ret_ptr = realloc(ptr, size);
  __softboundmpx_store_return_metadata(ret_ptr, (char *)(ret_ptr) + size);
  if (ret_ptr != ptr) {
    __softboundmpx_copy_metadata(ret_ptr, ptr, size);
  }
  return ret_ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<softboundmpx_realloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <realloc@plt>
  mov    %rax,%r12
  lea    (%rax,%r13,1),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  cmp    %r12,%rbp
  je     L7
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <__softboundmpx_copy_metadata@plt>
L7:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) void *softboundmpx_realloc(void *ptr, size_t size) {
  void *ret_ptr = realloc(ptr, size);
  __softboundmpx_store_return_metadata(ret_ptr, (char *)(ret_ptr) + size);
  if (ret_ptr != ptr) {
    __softboundmpx_copy_metadata(ret_ptr, ptr, size);
  }
  return ret_ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<softboundmpx_realloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <realloc@plt>
  mov    %rax,%r12
  lea    (%rax,%r13,1),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  cmp    %r12,%rbp
  je     L2
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <__softboundmpx_copy_metadata@plt>
L2:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) void *softboundmpx_realloc(void *ptr, size_t size) {
  void *ret_ptr = realloc(ptr, size);
  __softboundmpx_store_return_metadata(ret_ptr, (char *)(ret_ptr) + size);
  if (ret_ptr != ptr) {
    __softboundmpx_copy_metadata(ret_ptr, ptr, size);
  }
  return ret_ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thr_fn1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <pthread_exit@plt>
  mov    $0x2,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D1: This is 1 thread


assistant: ```c
void *thr_fn1(void *arg) {
  sleep(2);
  printf("This is 1 thread\n");
  pthread_exit((void *)2);
  return ((void *)2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thr_fn1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <pthread_exit@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: This is 1 thread


assistant: ```c
void *thr_fn1(void *arg) {
  sleep(2);
  printf("This is 1 thread\n");
  pthread_exit((void *)2);
  return ((void *)2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<thr_fn1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <pthread_exit@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: string

tool: D3: This is 1 thread


assistant: ```c
void *thr_fn1(void *arg) {
  sleep(2);
  printf("This is 1 thread\n");
  pthread_exit((void *)2);
  return ((void *)2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<thr_fn1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <pthread_exit@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string

tool: D4: This is 1 thread


assistant: ```c
void *thr_fn1(void *arg) {
  sleep(2);
  printf("This is 1 thread\n");
  pthread_exit((void *)2);
  return ((void *)2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L22
  cmpb   $0x39,-0x4(%rbp)
  jg     L22
  mov    $0x1,%eax
  jmp    L11
L22:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int is_digit(char c) {
  if (c >= '0' && c <= '9')
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_digit>:
  endbr64
  sub    $0x30,%edi
  cmp    $0x9,%dil
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_digit(char c) {
  if (c >= '0' && c <= '9')
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_digit>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_digit(char c) {
  if (c >= '0' && c <= '9')
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_digit>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_digit(char c) {
  if (c >= '0' && c <= '9')
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x30,-0xc(%rbp)
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rsi,%xmm0
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <minprintf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: f64
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D16: 1.03

tool: D19: %d,%f,%x,%c,%e,%g


assistant: ```c
int main() {
  int i = 48;
  double d = 1.03;
  minprintf("%d,%f,%x,%c,%e,%g\n", i, d, i, i, d, d);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D12(%rip),%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  mov    $0x30,%ecx
  mov    $0x30,%edx
  mov    $0x30,%esi
  lea    D0(%rip),%rdi
  call   <minprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D12: 1.03

tool: D0: %d,%f,%x,%c,%e,%g


assistant: ```c
int main() {
  int i = 48;
  double d = 1.03;
  minprintf("%d,%f,%x,%c,%e,%g\n", i, d, i, i, d, d);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x30,%ecx
  mov    $0x30,%edx
  movsd  D18(%rip),%xmm0
  mov    $0x30,%esi
  lea    D7(%rip),%rdi
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  call   <minprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
data_type: f64
name: unpack_data
arguments: data_label: D7
data_type: string

tool: D18: 1.03

tool: D7: %d,%f,%x,%c,%e,%g


assistant: ```c
int main() {
  int i = 48;
  double d = 1.03;
  minprintf("%d,%f,%x,%c,%e,%g\n", i, d, i, i, d, d);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x30,%ecx
  mov    $0x30,%edx
  movsd  D4(%rip),%xmm0
  mov    $0x30,%esi
  lea    D16(%rip),%rdi
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  call   <minprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
datatype: f64
name: parse_data
arguments: label: D16
datatype: string

tool: D4: 1.03

tool: D16: %d,%f,%x,%c,%e,%g


assistant: ```c
int main() {
  int i = 48;
  double d = 1.03;
  minprintf("%d,%f,%x,%c,%e,%g\n", i, d, i, i, d, d);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fpoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x1,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fileno@plt>
  mov    %eax,-0x30(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x34(%rbp),%rdx
  mov    -0x30(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x20(%rbp),%rdx
  lea    -0x34(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int fpoll(void *h) {
  FILE *f = (FILE *)h;
  fd_set x;
  struct timeval timeout;
  timeout.tv_sec = 1;
  timeout.tv_usec = 0;
  int fd = fileno(f);
  FD_ZERO(&x);
  FD_SET(fd, &x);
  int r = select(fd + 1, &x, 0, 0, &timeout);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fpoll>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <fileno@plt>
  mov    %eax,%ebx
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  lea    0x1(%rbx),%edi
  lea    0x10(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fpoll(void *h) {
  FILE *f = (FILE *)h;
  fd_set x;
  struct timeval timeout;
  timeout.tv_sec = 1;
  timeout.tv_usec = 0;
  int fd = fileno(f);
  FD_ZERO(&x);
  FD_SET(fd, &x);
  int r = select(fd + 1, &x, 0, 0, &timeout);
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fpoll>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  movl   $0x1,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <fileno@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbx),%edi
  lea    0x10(%rsp),%r8
  mov    %rbp,%rsi
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fpoll(void *h) {
  FILE *f = (FILE *)h;
  fd_set x;
  struct timeval timeout;
  timeout.tv_sec = 1;
  timeout.tv_usec = 0;
  int fd = fileno(f);
  FD_ZERO(&x);
  FD_SET(fd, &x);
  int r = select(fd + 1, &x, 0, 0, &timeout);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fpoll>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  movl   $0x1,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <fileno@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbx),%edi
  lea    0x10(%rsp),%r8
  mov    %rbp,%rsi
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fpoll(void *h) {
  FILE *f = (FILE *)h;
  fd_set x;
  struct timeval timeout;
  timeout.tv_sec = 1;
  timeout.tv_usec = 0;
  int fd = fileno(f);
  FD_ZERO(&x);
  FD_SET(fd, &x);
  int r = select(fd + 1, &x, 0, 0, &timeout);
  return r;
}
```