ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  lea    D56(%rip),%rsi
  lea    D54(%rip),%rdi
  call   <congratulatesStudent@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    $0x2,%edx
  lea    D57(%rip),%rsi
  lea    D89(%rip),%rdi
  call   <congratulatesStudent@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    $0x5,%edx
  lea    D9(%rip),%rsi
  lea    D52(%rip),%rdi
  call   <congratulatesStudent@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    $0x5,%edx
  lea    D62(%rip),%rsi
  lea    D36(%rip),%rdi
  call   <congratulatesStudent@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D56
type: string
name: retrieve_data
arguments: label: D54
type: string
name: retrieve_data
arguments: label: D57
type: string
name: retrieve_data
arguments: label: D89
type: string
name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D52
type: string
name: retrieve_data
arguments: label: D62
type: string
name: retrieve_data
arguments: label: D36
type: string
name: retrieve_data
arguments: label: D51
type: string

tool: D56: Cocoa

tool: D54: Kate

tool: D57: Objective-C

tool: D89: Bo

tool: D9: Python

tool: D52: Mike

tool: D62: iOS

tool: D36: Liz

tool: D51: "It doesn't happen all at once," said the Skin Horse.


assistant: ```c
int main(int argc, const char *argv[]) {
  congratulatesStudent("Kate", "Cocoa", 5);
  sleep(2);
  congratulatesStudent("Bo", "Objective-C", 2);
  sleep(2);
  congratulatesStudent("Mike", "Python", 5);
  sleep(2);
  congratulatesStudent("Liz", "iOS", 5);
  printf("\"It doesn't happen all at once,\" said the Skin Horse.\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    -0x38(%rbp),%rbx
  mov    -0x40(%rbp),%r13
  mov    -0x44(%rbp),%r12d
  jmp    L1
L56:
  add    $0x1,%rbx
L1:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L22
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  test   %eax,%eax
  jne    L56
L22:
  mov    %rbx,%rax
  sub    -0x38(%rbp),%rax
  mov    %eax,-0x24(%rbp)
  mov    -0x44(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%r12d
  test   %r12d,%r12d
  jne    L23
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    -0x24(%rbp),%edx
  add    %edx,%eax
  jmp    L41
L55:
  cmp    $0x1,%r12d
  je     L13
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl 0x0(%r13),%edx
  mov    %dl,(%rax)
  sub    $0x1,%r12d
L13:
  add    $0x1,%r13
L23:
  movzbl 0x0(%r13),%eax
  test   %al,%al
  jne    L55
  movb   $0x0,(%rbx)
  mov    %r13,%rax
  sub    -0x40(%rbp),%rax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
L41:
  add    $0x38,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int strlcat(char *dst, const char *src, int siz) {
  register char *d = dst;
  register const char *s = src;
  register int n = siz;
  int dlen;
  while (*d != '\0' && n-- != 0)
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return dlen + strlen(s);
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return dlen + (s - src);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlcat>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%rdi
  cmpb   $0x0,(%r8)
  je     L60
  test   %edx,%edx
  je     L31
  mov    %edx,%eax
  add    %r8,%rax
  mov    %r8,%rcx
L25:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L95
  cmp    %rax,%rcx
  jne    L25
  mov    %rax,%rcx
L95:
  mov    %rcx,%rsi
  sub    %r8,%rsi
  mov    %esi,%ebx
  sub    %esi,%edx
  je     L48
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  jne    L13
L1:
  movb   $0x0,(%rcx)
  sub    %rdi,%rax
  add    %esi,%eax
L103:
  pop    %rbx
  ret
L60:
  mov    %r8,%rcx
  jmp    L95
L31:
  mov    %edx,%ebx
L48:
  call   <strlen@plt>
  add    %ebx,%eax
  jmp    L103
L93:
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  je     L1
L13:
  cmp    $0x1,%edx
  je     L93
  mov    %r8b,(%rcx)
  sub    $0x1,%edx
  lea    0x1(%rcx),%rcx
  jmp    L93
```

assistant: ```c
int strlcat(char *dst, const char *src, int siz) {
  register char *d = dst;
  register const char *s = src;
  register int n = siz;
  int dlen;
  while (*d != '\0' && n-- != 0)
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return dlen + strlen(s);
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return dlen + (s - src);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlcat>:
  endbr64
  mov    %rdi,%r8
  push   %rbx
  mov    %rsi,%rdi
  cmpb   $0x0,(%r8)
  je     L46
  test   %edx,%edx
  je     L45
  mov    %edx,%eax
  mov    %r8,%rcx
  add    %r8,%rax
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L12:
  cmp    %rax,%rcx
  je     L70
L50:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L12
L70:
  mov    %rcx,%rsi
  sub    %r8,%rsi
  mov    %esi,%ebx
  sub    %esi,%edx
L121:
  test   %edx,%edx
  je     L89
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  jne    L119
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L68:
  mov    %r8b,(%rcx)
  sub    $0x1,%edx
  mov    %rax,%r8
  add    $0x1,%rcx
L90:
  lea    0x1(%r8),%rax
  movzbl 0x1(%r8),%r8d
  test   %r8b,%r8b
  je     L19
L119:
  cmp    $0x1,%edx
  jne    L68
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%r8
  jne    L90
  mov    %r8d,%eax
  sub    %edi,%eax
L32:
  movb   $0x0,(%rcx)
  add    %esi,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L19:
  sub    %edi,%eax
  jmp    L32
L45:
  xor    %ebx,%ebx
L89:
  call   <strlen@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
L64:
  xor    %eax,%eax
  jmp    L32
L46:
  mov    %r8,%rcx
  xor    %ebx,%ebx
  xor    %esi,%esi
  jmp    L121
```

assistant: ```c
int strlcat(char *dst, const char *src, int siz) {
  register char *d = dst;
  register const char *s = src;
  register int n = siz;
  int dlen;
  while (*d != '\0' && n-- != 0)
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return dlen + strlen(s);
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return dlen + (s - src);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlcat>:
  endbr64
  mov    %rdi,%r8
  push   %rbx
  mov    %rsi,%rdi
  cmpb   $0x0,(%r8)
  je     L118
  test   %edx,%edx
  je     L86
  mov    %edx,%eax
  mov    %r8,%rcx
  add    %r8,%rax
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    %rax,%rcx
  je     L138
L84:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L1
L138:
  mov    %rcx,%rsi
  sub    %r8,%rsi
  mov    %esi,%ebx
  sub    %esi,%edx
L133:
  test   %edx,%edx
  je     L37
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  jne    L92
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %r8b,(%rcx)
  sub    $0x1,%edx
  mov    %rax,%r8
  add    $0x1,%rcx
L67:
  lea    0x1(%r8),%rax
  movzbl 0x1(%r8),%r8d
  test   %r8b,%r8b
  je     L27
L92:
  cmp    $0x1,%edx
  jne    L35
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%r8
  jne    L67
  mov    %r8d,%eax
  sub    %edi,%eax
L90:
  movb   $0x0,(%rcx)
  add    %esi,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L27:
  sub    %edi,%eax
  jmp    L90
L86:
  xor    %ebx,%ebx
L37:
  call   <strlen@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
L96:
  xor    %eax,%eax
  jmp    L90
L118:
  mov    %r8,%rcx
  xor    %ebx,%ebx
  xor    %esi,%esi
  jmp    L133
```

assistant: ```c
int strlcat(char *dst, const char *src, int siz) {
  register char *d = dst;
  register const char *s = src;
  register int n = siz;
  int dlen;
  while (*d != '\0' && n-- != 0)
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return dlen + strlen(s);
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return dlen + (s - src);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: i_array: %p; *ip = %d

assistant: ```c
main() {
  int i_array[10];
  char c_array[10];
  int *ip;
  ip = i_array;
  printf("i_array: %p; *ip = %d", i_array, *ip);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    (%rsp),%edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: i_array: %p; *ip = %d

assistant: ```c
main() {
  int i_array[10];
  char c_array[10];
  int *ip;
  ip = i_array;
  printf("i_array: %p; *ip = %d", i_array, *ip);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%edx
  mov    %rsp,%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: i_array: %p; *ip = %d

assistant: ```c
main() {
  int i_array[10];
  char c_array[10];
  int *ip;
  ip = i_array;
  printf("i_array: %p; *ip = %d", i_array, *ip);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%edx
  mov    %rsp,%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: i_array: %p; *ip = %d

assistant: ```c
main() {
  int i_array[10];
  char c_array[10];
  int *ip;
  ip = i_array;
  printf("i_array: %p; *ip = %d", i_array, *ip);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<valid_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D29(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L4
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L35
L4:
  mov    $0x0,%eax
  jmp    L43
L35:
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jg     L33
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jl     L33
  mov    $0x1,%eax
  jmp    L43
L33:
  mov    $0x0,%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
int valid_int(long long int check) {
  if ((check == LONG_MIN) || (check == LONG_MAX))
    return 0;
  else if ((check <= INT_MAX) && (check >= INT_MIN))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<valid_int>:
  endbr64
  mov    $0x0,%eax
  mov    D35(%rip),%rdx
  cmp    %rdi,(%rdx)
  je     L4
  mov    D5(%rip),%rdx
  cmp    %rdi,(%rdx)
  je     L4
  mov    D32(%rip),%rdx
  cmp    %rdi,(%rdx)
  jl     L4
  mov    D2(%rip),%rax
  cmp    %rdi,(%rax)
  setle  %al
  movzbl %al,%eax
L4:
  ret
```

assistant: ```c
int valid_int(long long int check) {
  if ((check == LONG_MIN) || (check == LONG_MAX))
    return 0;
  else if ((check <= INT_MAX) && (check >= INT_MIN))
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<valid_int>:
  endbr64
  mov    D15(%rip),%rdx
  xor    %eax,%eax
  cmp    %rdi,(%rdx)
  je     L15
  mov    D21(%rip),%rdx
  cmp    %rdi,(%rdx)
  je     L15
  mov    D35(%rip),%rdx
  cmp    %rdi,(%rdx)
  jl     L15
  mov    D39(%rip),%rax
  cmp    %rdi,(%rax)
  setle  %al
  movzbl %al,%eax
L15:
  ret
```

assistant: ```c
int valid_int(long long int check) {
  if ((check == LONG_MIN) || (check == LONG_MAX))
    return 0;
  else if ((check <= INT_MAX) && (check >= INT_MIN))
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<valid_int>:
  endbr64
  mov    D6(%rip),%rdx
  xor    %eax,%eax
  cmp    %rdi,(%rdx)
  je     L26
  mov    D38(%rip),%rdx
  cmp    %rdi,(%rdx)
  je     L26
  mov    D15(%rip),%rdx
  cmp    %rdi,(%rdx)
  jl     L26
  mov    D30(%rip),%rax
  cmp    %rdi,(%rax)
  setle  %al
  movzbl %al,%eax
L26:
  ret
```

assistant: ```c
int valid_int(long long int check) {
  if ((check == LONG_MIN) || (check == LONG_MAX))
    return 0;
  else if ((check <= INT_MAX) && (check >= INT_MIN))
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x44(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L91
L67:
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x48(%rbp)
L91:
  cmpl   $0x4,-0x48(%rbp)
  jle    L67
  movl   $0x0,-0x48(%rbp)
  jmp    L72
L71:
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x48(%rbp)
L72:
  cmpl   $0x4,-0x48(%rbp)
  jle    L71
  movl   $0x0,-0x48(%rbp)
  jmp    L78
L24:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L69
  movl   $0x0,-0x44(%rbp)
  jmp    L63
L69:
  nop
  addl   $0x1,-0x48(%rbp)
L78:
  cmpl   $0x4,-0x48(%rbp)
  jle    L24
L63:
  cmpl   $0x0,-0x44(%rbp)
  je     L45
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L100
L45:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L100:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
type: string
name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D32
type: string

tool: D26: %d

tool: D18: Y


tool: D32: N


assistant: ```c
int main(void) {
  int macho[5], femea[5], i, encaixa = 1;
  for (i = 0; i < 5; i++) {
    scanf("%d", macho + i);
  }
  for (i = 0; i < 5; i++) {
    scanf("%d", femea + i);
  }
  for (i = 0; i < 5; i++) {
    if (macho[i] ^ femea[i])
      continue;
    else {
      encaixa = 0;
      break;
    }
  }
  if (encaixa) {
    printf("Y\n");
  } else {
    printf("N\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  lea    D21(%rip),%rbp
L36:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L36
  lea    0x20(%rsp),%rbx
  lea    0x34(%rsp),%r12
  lea    D21(%rip),%rbp
L55:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L55
  mov    $0x0,%eax
  lea    0x20(%rsp),%rdx
L29:
  mov    (%rdx,%rax,1),%ecx
  cmp    %ecx,(%rsp,%rax,1)
  jne    L58
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L58:
  add    $0x4,%rax
  cmp    $0x14,%rax
  jne    L29
  lea    D33(%rip),%rdi
  call   <printf@plt>
L44:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type_guessed: string
name: retrieve_data
arguments: data_tag: D22
type_guessed: string
name: retrieve_data
arguments: data_tag: D33
type_guessed: string

tool: D21: %d

tool: D22: N


tool: D33: Y


assistant: ```c
int main(void) {
  int macho[5], femea[5], i, encaixa = 1;
  for (i = 0; i < 5; i++) {
    scanf("%d", macho + i);
  }
  for (i = 0; i < 5; i++) {
    scanf("%d", femea + i);
  }
  for (i = 0; i < 5; i++) {
    if (macho[i] ^ femea[i])
      continue;
    else {
      encaixa = 0;
      break;
    }
  }
  if (encaixa) {
    printf("Y\n");
  } else {
    printf("N\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x14(%rsp),%r12
  mov    %r13,%rbx
L30:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L30
  lea    0x20(%rsp),%r14
  lea    0x34(%rsp),%r12
  mov    %r14,%rbx
L28:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L28
  xor    %eax,%eax
L9:
  mov    (%r14,%rax,1),%edx
  cmp    %edx,0x0(%r13,%rax,1)
  jne    L55
  lea    D5(%rip),%rdi
  call   <printf@plt>
L27:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L55:
  add    $0x4,%rax
  cmp    $0x14,%rax
  jne    L9
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: string
name: parse_data
arguments: tag: D5
data_type: string
name: parse_data
arguments: tag: D29
data_type: string

tool: D10: %d

tool: D5: N


tool: D29: Y


assistant: ```c
int main(void) {
  int macho[5], femea[5], i, encaixa = 1;
  for (i = 0; i < 5; i++) {
    scanf("%d", macho + i);
  }
  for (i = 0; i < 5; i++) {
    scanf("%d", femea + i);
  }
  for (i = 0; i < 5; i++) {
    if (macho[i] ^ femea[i])
      continue;
    else {
      encaixa = 0;
      break;
    }
  }
  if (encaixa) {
    printf("Y\n");
  } else {
    printf("N\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
L47:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L47
  lea    0x20(%rsp),%rbx
  lea    0x34(%rsp),%r12
L16:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L16
  mov    (%rsp),%eax
  cmp    %eax,0x20(%rsp)
  jne    L49
L17:
  lea    D12(%rip),%rdi
  call   <printf@plt>
L77:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  mov    0x4(%rsp),%eax
  cmp    %eax,0x24(%rsp)
  je     L17
  mov    0x28(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  je     L17
  mov    0x2c(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  je     L17
  mov    0x30(%rsp),%eax
  cmp    %eax,0x10(%rsp)
  je     L17
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L77
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type: string
name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D24
type: string

tool: D10: %d

tool: D12: N


tool: D24: Y


assistant: ```c
int main(void) {
  int macho[5], femea[5], i, encaixa = 1;
  for (i = 0; i < 5; i++) {
    scanf("%d", macho + i);
  }
  for (i = 0; i < 5; i++) {
    scanf("%d", femea + i);
  }
  for (i = 0; i < 5; i++) {
    if (macho[i] ^ femea[i])
      continue;
    else {
      encaixa = 0;
      break;
    }
  }
  if (encaixa) {
    printf("Y\n");
  } else {
    printf("N\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_word_wrapped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x4c,-0x14(%rbp)
  movl   $0xffffffff,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L133
L4:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x20,%edi
  call   <putc@plt>
  addl   $0x1,-0x30(%rbp)
L133:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L101
L84:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L26
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L47
  cmpl   $0x0,-0x20(%rbp)
  jns    L71
L47:
  movl   $0x0,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L68
L109:
  addl   $0x1,-0x20(%rbp)
  addq   $0x1,-0x8(%rbp)
L68:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L109
L53:
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  jle    L71
  jmp    L13
L26:
  nop
L13:
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <putc@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L35
L83:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x20,%edi
  call   <putc@plt>
  addl   $0x1,-0x18(%rbp)
L35:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L83
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  jmp    L33
L71:
  mov    D27(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <putc@plt>
L33:
  addq   $0x1,-0x10(%rbp)
L101:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L84
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_word_wrapped(const char *s, int indent, int start) {
  const int width = 76;
  const char *c, *t;
  int next_space = -1;
  int last_line = indent;
  while (start < indent) {
    putc(' ', stderr);
    start++;
  }
  for (c = s; *c != 0; c++) {
    if (*c == '\n')
      goto new_line;
    if (*c == ' ' || next_space < 0) {
      next_space = 0;
      for (t = c + 1; *t != 0 && *t != ' '; t++)
        next_space++;
      if (((int)(c - s) + start + next_space) > (last_line - indent + width)) {
        int i;
      new_line:
        last_line = (int)(c - s) + start;
        putc('\n', stderr);
        for (i = 0; i < indent; i++)
          putc(' ', stderr);
        start = indent;
        continue;
      }
    }
    putc(*c, stderr);
  }
}
```