ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FormatDuration>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  cmp    $0xe0f,%rdi
  jle    L49
  cmp    $0x1517f,%rdi
  jle    L8
  cmp    $0x1e1337f,%rdi
  jg     L55
  movabs $0x1845c8a0ce512957,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0xd,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rsi
  sub    %rax,%rsi
  imul   $0x15180,%rsi,%rax
  sub    %rax,%rcx
  movabs $0x48d159e26af37c05,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0xa,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rcx
  sub    %rax,%rcx
  mov    %rsi,%rdx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L2
L49:
  movabs $0x8888888888888889,%rdx
  mov    %rdi,%rax
  imul   %rdx
  add    %rdi,%rdx
  sar    $0x5,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  lea    D36(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
L8:
  movabs $0x48d159e26af37c05,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0xa,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rsi
  sub    %rax,%rsi
  imul   $0xe10,%rsi,%rax
  sub    %rax,%rcx
  movabs $0x8888888888888889,%rdx
  mov    %rcx,%rax
  imul   %rdx
  add    %rcx,%rdx
  sar    $0x5,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rcx
  sub    %rax,%rcx
  mov    %rsi,%rdx
  lea    D30(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L2
L55:
  movabs $0x883148f5cb1270b9,%rdx
  mov    %rdi,%rax
  imul   %rdx
  lea    (%rdx,%rdi,1),%rsi
  sar    $0x18,%rsi
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rsi
  imul   $0x1e13380,%rsi,%rax
  sub    %rax,%rcx
  movabs $0x1845c8a0ce512957,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0xd,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string
name: extract_symbolic_data
arguments: data_tag: D36
type: string
name: extract_symbolic_data
arguments: data_tag: D30
type: string
name: extract_symbolic_data
arguments: data_tag: D18
type: string

tool: D6: %dd%dh

tool: D36: %dm

tool: D30: %dh%dm

tool: D18: %dy%dd

assistant: ```c
const char *FormatDuration(long seconds, char *buf) {
  if (seconds < (60 * 60)) {
    sprintf(buf, "%dm", seconds / 60);
  } else if (seconds < (24 * 60 * 60)) {
    sprintf(buf, "%dh%dm", seconds / (60 * 60), (seconds % (60 * 60)) / 60);
  } else if (seconds < (365 * 24 * 60 * 60)) {
    sprintf(buf, "%dd%dh", seconds / (24 * 60 * 60), (seconds % (24 * 60 * 60)) / (60 * 60));
  } else {
    sprintf(buf, "%dy%dd", seconds / (365 * 24 * 60 * 60), (seconds % (365 * 24 * 60 * 60)) / (24 * 60 * 60));
  }
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FormatDuration>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  mov    %rsi,%r12
  cmp    $0xe0f,%rdi
  jle    L26
  cmp    $0x1517f,%rdi
  jle    L25
  cmp    $0x1e1337f,%rdi
  jg     L16
  mov    %rdi,%rax
  lea    D11(%rip),%rsi
  movabs $0x1845c8a0ce512957,%rdx
  imul   %rdx
  mov    %rdi,%rax
  mov    %r12,%rdi
  sar    $0x3f,%rax
  sar    $0xd,%rdx
  sub    %rax,%rdx
  imul   $0x15180,%rdx,%rax
  mov    %rdx,%r8
  movabs $0x91a2b3c4d5e6f81,%rdx
  sub    %rax,%rcx
  shr    $0x4,%rcx
  mov    %rcx,%rax
  mul    %rdx
  xor    %eax,%eax
  mov    %rdx,%rcx
  mov    %r8,%rdx
  shr    $0x3,%rcx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L25:
  mov    %rdi,%rax
  lea    D19(%rip),%rsi
  movabs $0x48d159e26af37c05,%rdx
  imul   %rdx
  mov    %rdi,%rax
  mov    %r12,%rdi
  sar    $0x3f,%rax
  sar    $0xa,%rdx
  sub    %rax,%rdx
  imul   $0xe10,%rdx,%rax
  mov    %rdx,%r8
  movabs $0x8888888888888889,%rdx
  sub    %rax,%rcx
  mov    %rcx,%rax
  mul    %rdx
  xor    %eax,%eax
  mov    %rdx,%rcx
  mov    %r8,%rdx
  shr    $0x5,%rcx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  mov    %rdi,%rax
  sar    $0x3f,%rcx
  movabs $0x8888888888888889,%rdx
  lea    D33(%rip),%rsi
  imul   %rdx
  xor    %eax,%eax
  add    %rdi,%rdx
  mov    %r12,%rdi
  sar    $0x5,%rdx
  sub    %rcx,%rdx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L16:
  mov    %rdi,%rax
  lea    D20(%rip),%rsi
  movabs $0x883148f5cb1270b9,%rdx
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  lea    (%rdx,%rdi,1),%r8
  mov    %r12,%rdi
  movabs $0xc22e450672894ab7,%rdx
  sar    $0x18,%r8
  sub    %rax,%r8
  imul   $0x1e13380,%r8,%rax
  sub    %rax,%rcx
  mov    %rcx,%rax
  mul    %rdx
  xor    %eax,%eax
  shr    $0x10,%rdx
  mov    %rdx,%rcx
  mov    %r8,%rdx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D19
type: string
name: retrieve_data
arguments: label: D33
type: string
name: retrieve_data
arguments: label: D20
type: string

tool: D11: %dd%dh

tool: D19: %dh%dm

tool: D33: %dm

tool: D20: %dy%dd

assistant: ```c
const char *FormatDuration(long seconds, char *buf) {
  if (seconds < (60 * 60)) {
    sprintf(buf, "%dm", seconds / 60);
  } else if (seconds < (24 * 60 * 60)) {
    sprintf(buf, "%dh%dm", seconds / (60 * 60), (seconds % (60 * 60)) / 60);
  } else if (seconds < (365 * 24 * 60 * 60)) {
    sprintf(buf, "%dd%dh", seconds / (24 * 60 * 60), (seconds % (24 * 60 * 60)) / (60 * 60));
  } else {
    sprintf(buf, "%dy%dd", seconds / (365 * 24 * 60 * 60), (seconds % (365 * 24 * 60 * 60)) / (24 * 60 * 60));
  }
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<FormatDuration>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  mov    %rsi,%r12
  cmp    $0xe0f,%rdi
  jle    L14
  cmp    $0x1517f,%rdi
  jle    L24
  cmp    $0x1e1337f,%rdi
  jg     L17
  mov    %rdi,%rax
  lea    D34(%rip),%rsi
  movabs $0x1845c8a0ce512957,%rdx
  imul   %rdx
  mov    %rdi,%rax
  mov    %r12,%rdi
  sar    $0x3f,%rax
  sar    $0xd,%rdx
  sub    %rax,%rdx
  imul   $0x15180,%rdx,%rax
  mov    %rdx,%r8
  movabs $0x91a2b3c4d5e6f81,%rdx
  sub    %rax,%rcx
  shr    $0x4,%rcx
  mov    %rcx,%rax
  mul    %rdx
  xor    %eax,%eax
  mov    %rdx,%rcx
  mov    %r8,%rdx
  shr    $0x3,%rcx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L24:
  mov    %rdi,%rax
  lea    D30(%rip),%rsi
  movabs $0x48d159e26af37c05,%rdx
  imul   %rdx
  mov    %rdi,%rax
  mov    %r12,%rdi
  sar    $0x3f,%rax
  sar    $0xa,%rdx
  sub    %rax,%rdx
  imul   $0xe10,%rdx,%rax
  mov    %rdx,%r8
  movabs $0x8888888888888889,%rdx
  sub    %rax,%rcx
  mov    %rcx,%rax
  mul    %rdx
  xor    %eax,%eax
  mov    %rdx,%rcx
  mov    %r8,%rdx
  shr    $0x5,%rcx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  mov    %rdi,%rax
  sar    $0x3f,%rcx
  movabs $0x8888888888888889,%rdx
  lea    D4(%rip),%rsi
  imul   %rdx
  xor    %eax,%eax
  add    %rdi,%rdx
  mov    %r12,%rdi
  sar    $0x5,%rdx
  sub    %rcx,%rdx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L17:
  mov    %rdi,%rax
  lea    D33(%rip),%rsi
  movabs $0x883148f5cb1270b9,%rdx
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  lea    (%rdx,%rdi,1),%r8
  mov    %r12,%rdi
  movabs $0xc22e450672894ab7,%rdx
  sar    $0x18,%r8
  sub    %rax,%r8
  imul   $0x1e13380,%r8,%rax
  sub    %rax,%rcx
  mov    %rcx,%rax
  mul    %rdx
  xor    %eax,%eax
  shr    $0x10,%rdx
  mov    %rdx,%rcx
  mov    %r8,%rdx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D34
type_guessed: string
name: unpack_data
arguments: data_label: D30
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D33
type_guessed: string

tool: D34: %dd%dh

tool: D30: %dh%dm

tool: D4: %dm

tool: D33: %dy%dd

assistant: ```c
const char *FormatDuration(long seconds, char *buf) {
  if (seconds < (60 * 60)) {
    sprintf(buf, "%dm", seconds / 60);
  } else if (seconds < (24 * 60 * 60)) {
    sprintf(buf, "%dh%dm", seconds / (60 * 60), (seconds % (60 * 60)) / 60);
  } else if (seconds < (365 * 24 * 60 * 60)) {
    sprintf(buf, "%dd%dh", seconds / (24 * 60 * 60), (seconds % (24 * 60 * 60)) / (60 * 60));
  } else {
    sprintf(buf, "%dy%dd", seconds / (365 * 24 * 60 * 60), (seconds % (365 * 24 * 60 * 60)) / (24 * 60 * 60));
  }
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EVP_PKEY_new_mac_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <EVP_PKEY_CTX_new_id@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L55
  mov    $0x0,%eax
  jmp    L40
L55:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_keygen_init@plt>
  test   %rax,%rax
  jle    L35
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rdi
  mov    -0x28(%rbp),%esi
  mov    -0x10(%rbp),%rax
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <EVP_PKEY_CTX_ctrl@plt>
  test   %rax,%rax
  jle    L42
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <EVP_PKEY_keygen@plt>
  test   %rax,%rax
  jmp    L12
L35:
  nop
  jmp    L12
L42:
  nop
L12:
  cmpq   $0x0,-0x10(%rbp)
  je     L5
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_CTX_free@plt>
L5:
  mov    -0x18(%rbp),%rax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
EVP_PKEY *EVP_PKEY_new_mac_key(int type, ENGINE *e, const unsigned char *key, int keylen) {
  EVP_PKEY_CTX *mac_ctx = NULL;
  EVP_PKEY *mac_key = NULL;
  mac_ctx = EVP_PKEY_CTX_new_id(type, e);
  if (!mac_ctx)
    return NULL;
  if (EVP_PKEY_keygen_init(mac_ctx) <= 0)
    goto merr;
  if (EVP_PKEY_CTX_ctrl(mac_ctx, -1, EVP_PKEY_OP_KEYGEN, EVP_PKEY_CTRL_SET_MAC_KEY, keylen, (void *)key) <= 0)
    goto merr;
  if (EVP_PKEY_keygen(mac_ctx, &mac_key) <= 0)
    goto merr;
merr:
  if (mac_ctx)
    EVP_PKEY_CTX_free(mac_ctx);
  return mac_key;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<EVP_PKEY_new_mac_key>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <EVP_PKEY_CTX_new_id@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %rax,%rdi
  call   <EVP_PKEY_keygen_init@plt>
  test   %rax,%rax
  jle    L29
  mov    %rbp,%r9
  mov    %r12d,%r8d
  mov    D6(%rip),%rax
  mov    (%rax),%ecx
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <EVP_PKEY_CTX_ctrl@plt>
  test   %rax,%rax
  jle    L29
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <EVP_PKEY_keygen@plt>
L29:
  mov    %rbx,%rdi
  call   <EVP_PKEY_CTX_free@plt>
  mov    (%rsp),%rbx
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
EVP_PKEY *EVP_PKEY_new_mac_key(int type, ENGINE *e, const unsigned char *key, int keylen) {
  EVP_PKEY_CTX *mac_ctx = NULL;
  EVP_PKEY *mac_key = NULL;
  mac_ctx = EVP_PKEY_CTX_new_id(type, e);
  if (!mac_ctx)
    return NULL;
  if (EVP_PKEY_keygen_init(mac_ctx) <= 0)
    goto merr;
  if (EVP_PKEY_CTX_ctrl(mac_ctx, -1, EVP_PKEY_OP_KEYGEN, EVP_PKEY_CTRL_SET_MAC_KEY, keylen, (void *)key) <= 0)
    goto merr;
  if (EVP_PKEY_keygen(mac_ctx, &mac_key) <= 0)
    goto merr;
merr:
  if (mac_ctx)
    EVP_PKEY_CTX_free(mac_ctx);
  return mac_key;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EVP_PKEY_new_mac_key>:
  endbr64
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <EVP_PKEY_CTX_new_id@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
  mov    %rax,%rdi
  call   <EVP_PKEY_keygen_init@plt>
  test   %rax,%rax
  jle    L3
  mov    D10(%rip),%rax
  mov    %rbx,%r9
  mov    %ebp,%r8d
  mov    %r12,%rdi
  mov    $0xffffffff,%esi
  mov    (%rax),%ecx
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  call   <EVP_PKEY_CTX_ctrl@plt>
  test   %rax,%rax
  jle    L3
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <EVP_PKEY_keygen@plt>
L3:
  mov    %r12,%rdi
  call   <EVP_PKEY_CTX_free@plt>
  mov    (%rsp),%r12
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
EVP_PKEY *EVP_PKEY_new_mac_key(int type, ENGINE *e, const unsigned char *key, int keylen) {
  EVP_PKEY_CTX *mac_ctx = NULL;
  EVP_PKEY *mac_key = NULL;
  mac_ctx = EVP_PKEY_CTX_new_id(type, e);
  if (!mac_ctx)
    return NULL;
  if (EVP_PKEY_keygen_init(mac_ctx) <= 0)
    goto merr;
  if (EVP_PKEY_CTX_ctrl(mac_ctx, -1, EVP_PKEY_OP_KEYGEN, EVP_PKEY_CTRL_SET_MAC_KEY, keylen, (void *)key) <= 0)
    goto merr;
  if (EVP_PKEY_keygen(mac_ctx, &mac_key) <= 0)
    goto merr;
merr:
  if (mac_ctx)
    EVP_PKEY_CTX_free(mac_ctx);
  return mac_key;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EVP_PKEY_new_mac_key>:
  endbr64
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <EVP_PKEY_CTX_new_id@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  call   <EVP_PKEY_keygen_init@plt>
  test   %rax,%rax
  jle    L16
  mov    D15(%rip),%rax
  mov    %rbx,%r9
  mov    %ebp,%r8d
  mov    %r12,%rdi
  mov    $0xffffffff,%esi
  mov    (%rax),%ecx
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  call   <EVP_PKEY_CTX_ctrl@plt>
  test   %rax,%rax
  jle    L16
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <EVP_PKEY_keygen@plt>
L16:
  mov    %r12,%rdi
  call   <EVP_PKEY_CTX_free@plt>
  mov    (%rsp),%r12
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
EVP_PKEY *EVP_PKEY_new_mac_key(int type, ENGINE *e, const unsigned char *key, int keylen) {
  EVP_PKEY_CTX *mac_ctx = NULL;
  EVP_PKEY *mac_key = NULL;
  mac_ctx = EVP_PKEY_CTX_new_id(type, e);
  if (!mac_ctx)
    return NULL;
  if (EVP_PKEY_keygen_init(mac_ctx) <= 0)
    goto merr;
  if (EVP_PKEY_CTX_ctrl(mac_ctx, -1, EVP_PKEY_OP_KEYGEN, EVP_PKEY_CTRL_SET_MAC_KEY, keylen, (void *)key) <= 0)
    goto merr;
  if (EVP_PKEY_keygen(mac_ctx, &mac_key) <= 0)
    goto merr;
merr:
  if (mac_ctx)
    EVP_PKEY_CTX_free(mac_ctx);
  return mac_key;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<HariMain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L3:
  jmp    L3
```

assistant: ```c
void HariMain(void) {
finish:
  goto finish;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HariMain>:
  endbr64
L4:
  jmp    L4
```

assistant: ```c
void HariMain(void) {
finish:
  goto finish;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HariMain>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
void HariMain(void) {
finish:
  goto finish;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<HariMain>:
  endbr64
  nopl   0x0(%rax)
L2:
  jmp    L2
```

assistant: ```c
void HariMain(void) {
finish:
  goto finish;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_str_isalpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L68
L59:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jle    L35
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L13
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jle    L35
L13:
  mov    $0x0,%eax
  jmp    L49
L35:
  addl   $0x1,-0x4(%rbp)
L68:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  mov    $0x1,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int my_str_isalpha(char *str) {
  int i;
  for (i = 0; str[i]; i++) {
    if ((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z'))
      ;
    else
      return (0);
  }
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_str_isalpha>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  add    $0x1,%rdi
L20:
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L13
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L20
  mov    $0x1,%eax
  ret
L12:
  mov    $0x1,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int my_str_isalpha(char *str) {
  int i;
  for (i = 0; str[i]; i++) {
    if ((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z'))
      ;
    else
      return (0);
  }
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<my_str_isalpha>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  add    $0x1,%rdi
  jmp    L4
  nopl   0x0(%rax)
L3:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L1
L4:
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  jbe    L3
  xor    %eax,%eax
  ret
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int my_str_isalpha(char *str) {
  int i;
  for (i = 0; str[i]; i++) {
    if ((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z'))
      ;
    else
      return (0);
  }
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_str_isalpha>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L32
  add    $0x1,%rdi
  jmp    L15
  nopl   0x0(%rax)
L38:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L32
L15:
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  jbe    L38
  xor    %eax,%eax
  ret
L32:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int my_str_isalpha(char *str) {
  int i;
  for (i = 0; str[i]; i++) {
    if ((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z'))
      ;
    else
      return (0);
  }
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<comp128>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x298,%rsp
  mov    %rdi,%r14
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x288(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rdi
  mov    $0x10,%edx
  call   <memcpy@plt>
  mov    $0x7,%r13d
  mov    %rsp,%rbx
L36:
  mov    $0x10,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <_comp128_compression@plt>
  lea    0x80(%rsp),%r15
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <_comp128_bitsfrombytes@plt>
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <_comp128_permutation@plt>
  sub    $0x1,%r13d
  jne    L36
  mov    %rsp,%rbx
  mov    $0x10,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <_comp128_compression@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rcx
  mov    $0x0,%esi
L15:
  mov    %esi,%edi
  sar    %edi
  movslq %edi,%rdi
  mov    (%rcx),%eax
  shl    $0x4,%eax
  or     0x4(%rcx),%eax
  mov    %eax,(%r12,%rdi,4)
  add    $0x2,%esi
  add    $0x8,%rcx
  cmp    $0x8,%esi
  jne    L15
  mov    $0x0,%ecx
L34:
  mov    %ecx,%esi
  sar    %esi
  movslq %esi,%rsi
  mov    0x48(%rdx),%eax
  shl    $0x6,%eax
  mov    0x4c(%rdx),%ebx
  lea    0x0(,%rbx,4),%edi
  or     %edi,%eax
  mov    0x50(%rdx),%edi
  sar    $0x2,%edi
  or     %edi,%eax
  mov    %eax,0x0(%rbp,%rsi,4)
  add    $0x2,%ecx
  add    $0x8,%rdx
  cmp    $0xc,%ecx
  jne    L34
  mov    0x78(%rsp),%eax
  shl    $0x6,%eax
  mov    0x7c(%rsp),%ecx
  lea    0x0(,%rcx,4),%edx
  or     %edx,%eax
  mov    %eax,0x18(%rbp)
  movl   $0x0,0x1c(%rbp)
  mov    0x288(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x298,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void comp128(uint8_t *ki, uint8_t *rand, uint8_t *sres, uint8_t *kc) {
  int i;
  uint8_t x[32], bits[128];
  memcpy(&x[16], rand, 16);
  for (i = 0; i < 7; i++) {
    memcpy(x, ki, 16);
    _comp128_compression(x);
    _comp128_bitsfrombytes(x, bits);
    _comp128_permutation(x, bits);
  }
  memcpy(x, ki, 16);
  _comp128_compression(x);
  for (i = 0; i < 8; i += 2)
    sres[i >> 1] = x[i] << 4 | x[i + 1];
  for (i = 0; i < 12; i += 2)
    kc[i >> 1] = (x[i + 18] << 6) | (x[i + 19] << 2) | (x[i + 20] >> 2);
  kc[6] = (x[30] << 6) | (x[31] << 2);
  kc[7] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<comp128>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    $0x7,%r13d
  push   %r12
  mov    %rdx,%r12
  mov    $0x10,%edx
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x298,%rsp
  lea    0x40(%rsp),%rdi
  mov    %rsp,%rbx
  lea    0x80(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x288(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  nopl   0x0(%rax)
L38:
  mov    $0x10,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <_comp128_compression@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <_comp128_bitsfrombytes@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <_comp128_permutation@plt>
  sub    $0x1,%r13d
  jne    L38
  mov    $0x10,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <_comp128_compression@plt>
  mov    %rbx,%rcx
  xor    %edx,%edx
L9:
  mov    (%rcx),%eax
  mov    %edx,%esi
  add    $0x2,%edx
  add    $0x8,%rcx
  sar    %esi
  movslq %esi,%rsi
  shl    $0x4,%eax
  or     -0x4(%rcx),%eax
  mov    %eax,(%r12,%rsi,4)
  cmp    $0x8,%edx
  jne    L9
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    0x48(%rbx),%eax
  mov    0x4c(%rbx),%edi
  mov    %edx,%ecx
  add    $0x2,%edx
  sar    %ecx
  add    $0x8,%rbx
  lea    0x0(,%rdi,4),%esi
  shl    $0x6,%eax
  movslq %ecx,%rcx
  or     %esi,%eax
  mov    0x48(%rbx),%esi
  sar    $0x2,%esi
  or     %esi,%eax
  mov    %eax,0x0(%rbp,%rcx,4)
  cmp    $0xc,%edx
  jne    L10
  mov    0x78(%rsp),%eax
  mov    0x7c(%rsp),%edx
  movl   $0x0,0x1c(%rbp)
  shl    $0x6,%eax
  shl    $0x2,%edx
  or     %edx,%eax
  mov    %eax,0x18(%rbp)
  mov    0x288(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x298,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void comp128(uint8_t *ki, uint8_t *rand, uint8_t *sres, uint8_t *kc) {
  int i;
  uint8_t x[32], bits[128];
  memcpy(&x[16], rand, 16);
  for (i = 0; i < 7; i++) {
    memcpy(x, ki, 16);
    _comp128_compression(x);
    _comp128_bitsfrombytes(x, bits);
    _comp128_permutation(x, bits);
  }
  memcpy(x, ki, 16);
  _comp128_compression(x);
  for (i = 0; i < 8; i += 2)
    sres[i >> 1] = x[i] << 4 | x[i + 1];
  for (i = 0; i < 12; i += 2)
    kc[i >> 1] = (x[i + 18] << 6) | (x[i + 19] << 2) | (x[i + 20] >> 2);
  kc[6] = (x[30] << 6) | (x[31] << 2);
  kc[7] = 0;
}
```