ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<back_solve>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %ecx,%ecx
  je     L23
  mov    %ecx,%edx
  xor    %esi,%esi
  mov    %r8,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L23:
  mov    %r13d,%edx
  sub    $0x1,%ebp
  sub    $0x1,%edx
  js     L108
  mov    %ebp,%eax
  movslq %edx,%rbx
  lea    (%r12,%rax,4),%r13
  jmp    L58
  nop
L115:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  js     L108
L58:
  mov    0x0(%r13),%ecx
  mov    (%r14,%rbx,8),%rax
  mov    %ebx,0x4(%rsp)
  movss  (%rax,%rcx,4),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jle    L115
L108:
  movslq 0x4(%rsp),%rdx
  movsd  D9(%rip),%xmm4
  pxor   %xmm3,%xmm3
  nopl   0x0(%rax,%rax,1)
L51:
  mov    (%r14,%rdx,8),%rsi
  cmp    $0xffffffff,%ebp
  je     L67
  movslq %ebp,%rax
  movaps %xmm3,%xmm1
  nopl   0x0(%rax,%rax,1)
L79:
  cmp    %edx,%eax
  jle    L36
  mov    (%r12,%rax,4),%ecx
  movss  (%r15,%rcx,4),%xmm0
  mulss  (%rsi,%rcx,4),%xmm0
  addss  %xmm0,%xmm1
L36:
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L79
L116:
  mov    (%r12,%rdx,4),%eax
  pxor   %xmm0,%xmm0
  movss  (%rsi,%rax,4),%xmm2
  lea    (%r15,%rax,4),%rax
  cvtss2sd %xmm2,%xmm0
  comisd %xmm4,%xmm0
  jbe    L15
  mov    0x8(%rsp),%rdi
  movss  (%rdi,%rdx,4),%xmm0
  subss  %xmm1,%xmm0
  divss  %xmm2,%xmm0
L33:
  sub    $0x1,%rdx
  movss  %xmm0,(%rax)
  cmp    $0xffffffff,%edx
  jne    L51
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L15:
  movaps %xmm3,%xmm0
  jmp    L33
  nopl   (%rax)
L67:
  movaps %xmm3,%xmm1
  jmp    L116
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: byte[8]

tool: {"D9": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x7a,0x3e]}

assistant: ```c
void back_solve(float **mat, float *rhs, unsigned int rows, unsigned int cols, float *sol, unsigned int *p) {
  int i, j, bottom;
  float sum;
  for (i = 0; i < cols; i++)
    sol[i] = 0.0;
  for (i = rows - 1; i >= 0; i--)
    if (fabs(mat[i][p[cols - 1]]) > 1e-7) {
      bottom = i;
      break;
    }
  for (i = bottom; i >= 0; i--) {
    sum = 0.0;
    for (j = cols - 1; j >= 0; j--)
      if (j > i)
        sum += sol[p[j]] * mat[i][p[j]];
    if (mat[i][p[i]] > 1e-7)
      sol[p[i]] = (rhs[i] - sum) / mat[i][p[i]];
    else
      sol[p[i]] = 0.0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<back_solve>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %ecx,%ecx
  je     L72
  mov    %ecx,%edx
  xor    %esi,%esi
  mov    %r8,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L72:
  mov    %r13d,%edx
  sub    $0x1,%ebp
  sub    $0x1,%edx
  js     L54
  mov    %ebp,%eax
  movslq %edx,%rbx
  lea    (%r12,%rax,4),%r13
  jmp    L2
  nop
L58:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  js     L54
L2:
  mov    0x0(%r13),%ecx
  mov    (%r14,%rbx,8),%rax
  mov    %ebx,0x4(%rsp)
  movss  (%rax,%rcx,4),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jle    L58
L54:
  movslq 0x4(%rsp),%rdx
  movsd  D0(%rip),%xmm3
  pxor   %xmm4,%xmm4
L4:
  mov    (%r14,%rdx,8),%rsi
  cmp    $0xffffffff,%ebp
  je     L70
L8:
  movslq %ebp,%rax
  movaps %xmm4,%xmm1
  cs nopw 0x0(%rax,%rax,1)
L6:
  cmp    %edx,%eax
  jle    L86
  mov    (%r12,%rax,4),%ecx
  movss  (%r15,%rcx,4),%xmm0
  mulss  (%rsi,%rcx,4),%xmm0
  addss  %xmm0,%xmm1
L86:
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L6
L41:
  mov    (%r12,%rdx,4),%eax
  pxor   %xmm0,%xmm0
  movss  (%rsi,%rax,4),%xmm2
  lea    (%r15,%rax,4),%rax
  cvtss2sd %xmm2,%xmm0
  comisd %xmm3,%xmm0
  jbe    L49
  mov    0x8(%rsp),%rdi
  movss  (%rdi,%rdx,4),%xmm0
  sub    $0x1,%rdx
  subss  %xmm1,%xmm0
  divss  %xmm2,%xmm0
  movss  %xmm0,(%rax)
  cmp    $0xffffffff,%edx
  jne    L4
L112:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L49:
  sub    $0x1,%rdx
  movl   $0x0,(%rax)
  cmp    $0xffffffff,%edx
  je     L112
  mov    (%r14,%rdx,8),%rsi
  cmp    $0xffffffff,%ebp
  jne    L8
L70:
  movaps %xmm4,%xmm1
  jmp    L41
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: byte[8]

tool: {"D0": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x7a,0x3e]}

assistant: ```c
void back_solve(float **mat, float *rhs, unsigned int rows, unsigned int cols, float *sol, unsigned int *p) {
  int i, j, bottom;
  float sum;
  for (i = 0; i < cols; i++)
    sol[i] = 0.0;
  for (i = rows - 1; i >= 0; i--)
    if (fabs(mat[i][p[cols - 1]]) > 1e-7) {
      bottom = i;
      break;
    }
  for (i = bottom; i >= 0; i--) {
    sum = 0.0;
    for (j = cols - 1; j >= 0; j--)
      if (j > i)
        sum += sol[p[j]] * mat[i][p[j]];
    if (mat[i][p[i]] > 1e-7)
      sol[p[i]] = (rhs[i] - sum) / mat[i][p[i]];
    else
      sol[p[i]] = 0.0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<hex2mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L6:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <hex@plt>
  shl    $0x4,%eax
  mov    %al,-0x5(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <hex@plt>
  add    %al,-0x5(%rbp)
  movzbl -0x5(%rbp),%edx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  mov    %edx,%esi
  mov    %eax,%edi
  call   <set_char@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void hex2mem(unsigned char *buf, unsigned long mem, int count) {
  int i;
  unsigned char ch;
  for (i = 0; i < count; i++) {
    ch = hex(*buf++) << 4;
    ch = ch + hex(*buf++);
    set_char(mem++, ch);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hex2mem>:
  endbr64
  test   %edx,%edx
  jle    L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    (%rdx,%rsi,1),%r12d
L14:
  movzbl (%rbx),%edi
  call   <hex@plt>
  shl    $0x4,%eax
  mov    %eax,%r13d
  add    $0x2,%rbx
  movzbl -0x1(%rbx),%edi
  call   <hex@plt>
  lea    (%rax,%r13,1),%esi
  movzbl %sil,%esi
  mov    %ebp,%edi
  call   <set_char@plt>
  add    $0x1,%ebp
  cmp    %r12d,%ebp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

assistant: ```c
void hex2mem(unsigned char *buf, unsigned long mem, int count) {
  int i;
  unsigned char ch;
  for (i = 0; i < count; i++) {
    ch = hex(*buf++) << 4;
    ch = ch + hex(*buf++);
    set_char(mem++, ch);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hex2mem>:
  endbr64
  test   %edx,%edx
  jle    L18
  push   %r13
  push   %r12
  lea    (%rdx,%rsi,1),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl (%rbx),%edi
  add    $0x2,%rbx
  call   <hex@plt>
  movzbl -0x1(%rbx),%edi
  shl    $0x4,%eax
  mov    %eax,%r13d
  call   <hex@plt>
  mov    %ebp,%edi
  add    $0x1,%ebp
  lea    (%rax,%r13,1),%esi
  movzbl %sil,%esi
  call   <set_char@plt>
  cmp    %r12d,%ebp
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  ret
```

assistant: ```c
void hex2mem(unsigned char *buf, unsigned long mem, int count) {
  int i;
  unsigned char ch;
  for (i = 0; i < count; i++) {
    ch = hex(*buf++) << 4;
    ch = ch + hex(*buf++);
    set_char(mem++, ch);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hex2mem>:
  endbr64
  test   %edx,%edx
  jle    L12
  push   %r13
  push   %r12
  lea    (%rdx,%rsi,1),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L16:
  movzbl (%rbx),%edi
  add    $0x2,%rbx
  call   <hex@plt>
  movzbl -0x1(%rbx),%edi
  shl    $0x4,%eax
  mov    %eax,%r13d
  call   <hex@plt>
  mov    %ebp,%edi
  add    $0x1,%ebp
  lea    (%rax,%r13,1),%esi
  movzbl %sil,%esi
  call   <set_char@plt>
  cmp    %r12d,%ebp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L12:
  ret
```

assistant: ```c
void hex2mem(unsigned char *buf, unsigned long mem, int count) {
  int i;
  unsigned char ch;
  for (i = 0; i < count; i++) {
    ch = hex(*buf++) << 4;
    ch = ch + hex(*buf++);
    set_char(mem++, ch);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3e8,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L14
L4:
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L39
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L49
L39:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x2c(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
L49:
  addl   $0x1,-0x2c(%rbp)
L14:
  mov    -0x2c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L4
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <array_sum@plt>
  mov    %eax,-0x24(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int size = 1000;
  int multiple[sizeof(size)] = {0};
  int total = 0;
  for (int i = 0; i < size; i++) {
    if ((i % 3 == 0) || (i % 5 == 0))
      multiple[i] = i;
  }
  total = array_sum(multiple);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  jmp    L18
L48:
  mov    %esi,(%rsp,%rax,4)
L26:
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  je     L47
L18:
  mov    %eax,%esi
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  cmp    %eax,%edx
  je     L48
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  cmp    %eax,%edx
  jne    L26
  jmp    L48
L47:
  mov    %rsp,%rdi
  call   <array_sum@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int size = 1000;
  int multiple[sizeof(size)] = {0};
  int total = 0;
  for (int i = 0; i < size; i++) {
    if ((i % 3 == 0) || (i % 5 == 0))
      multiple[i] = i;
  }
  total = array_sum(multiple);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  nopl   0x0(%rax,%rax,1)
L18:
  imul   $0xaaaaaaab,%eax,%edx
  mov    %eax,%ecx
  cmp    $0x55555555,%edx
  jbe    L13
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  ja     L35
L13:
  mov    %ecx,(%rdi,%rax,4)
L35:
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L18
  call   <array_sum@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int size = 1000;
  int multiple[sizeof(size)] = {0};
  int total = 0;
  for (int i = 0; i < size; i++) {
    if ((i % 3 == 0) || (i % 5 == 0))
      multiple[i] = i;
  }
  total = array_sum(multiple);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  nopl   0x0(%rax,%rax,1)
L34:
  imul   $0xaaaaaaab,%eax,%edx
  mov    %eax,%ecx
  cmp    $0x55555555,%edx
  jbe    L24
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  ja     L32
L24:
  mov    %ecx,(%rdi,%rax,4)
L32:
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L34
  call   <array_sum@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int size = 1000;
  int multiple[sizeof(size)] = {0};
  int total = 0;
  for (int i = 0; i < size; i++) {
    if ((i % 3 == 0) || (i % 5 == 0))
      multiple[i] = i;
  }
  total = array_sum(multiple);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x10(%rbp)
  cmpb   $0x74,-0x10(%rbp)
  jne    L19
  mov    -0x8(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  jmp    L0
L19:
  mov    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int map(int i, int j, int ncols, char transpose) {
  if (transpose == 't') {
    return j * ncols + i;
  } else {
    return i * ncols + j;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<map>:
  endbr64
  cmp    $0x74,%cl
  je     L2
  imul   %edx,%edi
  lea    (%rdi,%rsi,1),%eax
  ret
L2:
  imul   %esi,%edx
  lea    (%rdx,%rdi,1),%eax
  ret
```

assistant: ```c
int map(int i, int j, int ncols, char transpose) {
  if (transpose == 't') {
    return j * ncols + i;
  } else {
    return i * ncols + j;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<map>:
  endbr64
  cmp    $0x74,%cl
  je     L9
  imul   %edx,%edi
  lea    (%rdi,%rsi,1),%eax
  ret
L9:
  imul   %esi,%edx
  lea    (%rdx,%rdi,1),%eax
  ret
```

assistant: ```c
int map(int i, int j, int ncols, char transpose) {
  if (transpose == 't') {
    return j * ncols + i;
  } else {
    return i * ncols + j;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<map>:
  endbr64
  cmp    $0x74,%cl
  je     L2
  imul   %edx,%edi
  lea    (%rdi,%rsi,1),%eax
  ret
L2:
  imul   %esi,%edx
  lea    (%rdx,%rdi,1),%eax
  ret
```

assistant: ```c
int map(int i, int j, int ncols, char transpose) {
  if (transpose == 't') {
    return j * ncols + i;
  } else {
    return i * ncols + j;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_alphanum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L20
  mov    $0x0,%eax
  jmp    L12
L20:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <cgc_strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L28
  mov    $0x1,%eax
L12:
  leave
  ret
```

assistant: ```c
int is_alphanum(const char *s) {
  int i;
  for (i = 0; i < cgc_strlen(s) - 1; ++i) {
    if (!isalnum(s[i]))
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_alphanum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L10:
  mov    %rbp,%rdi
  call   <cgc_strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L19
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isalnum@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  jne    L10
  jmp    L23
L19:
  mov    $0x1,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_alphanum(const char *s) {
  int i;
  for (i = 0; i < cgc_strlen(s) - 1; ++i) {
    if (!isalnum(s[i]))
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_alphanum>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax)
L2:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <isalnum@plt>
  test   %eax,%eax
  je     L11
L13:
  mov    %rbp,%rdi
  call   <cgc_strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L2
  mov    $0x1,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_alphanum(const char *s) {
  int i;
  for (i = 0; i < cgc_strlen(s) - 1; ++i) {
    if (!isalnum(s[i]))
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_alphanum>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L7
  nopl   0x0(%rax)
L13:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <isalnum@plt>
  test   %eax,%eax
  je     L28
L7:
  mov    %rbp,%rdi
  call   <cgc_strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L13
  mov    $0x1,%eax
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_alphanum(const char *s) {
  int i;
  for (i = 0; i < cgc_strlen(s) - 1; ++i) {
    if (!isalnum(s[i]))
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<callKernel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x24,%rax
  lea    D21(%rip),%rdx
  mov    $0xea,%esi
  mov    %rax,%rdi
  call   <eipa_malloc@plt>
  mov    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    -0x58(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x50(%rbp),%rax
  lea    D60(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D57(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    D68(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D75(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x40(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <buildString@plt>
  mov    %rax,-0x48(%rbp)
  lea    -0x50(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    $0xfc,%esi
  mov    %rax,%rdi
  call   <eipa_free@plt>
  mov    -0x48(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D21
type_infered: string
name: retrieve_data
arguments: tag: D60
type_infered: string
name: retrieve_data
arguments: tag: D57
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string
name: retrieve_data
arguments: tag: D68
type_infered: string
name: retrieve_data
arguments: tag: D75
type_infered: string
name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D21: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c

tool: D60: <<<blocks,grid>>>(TODO:parameters);

tool: D57: dim3 grid(TODO:set grid dimensions);

tool: D11: dim3 blocks(TODO:set block dimensions);

tool: D68: cudaDeviceSynchronize();

tool: D75: cudaError_t err = cudaGetLastError();

tool: D2: HANDLE_ERROR( err );

assistant: ```c
char *callKernel(char *name) {
  char *aux = eipa_malloc((strlen(name) + strlen("<<<blocks,grid>>>(TODO:parameters);") + 1), 234, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c");
  strcpy(aux, name);
  strcat(aux, "<<<blocks,grid>>>(TODO:parameters);");
  char *string[6] = {"dim3 grid(TODO:set grid dimensions);", "dim3 blocks(TODO:set block dimensions);", aux, "cudaDeviceSynchronize();", "cudaError_t err = cudaGetLastError();", "HANDLE_ERROR( err );"};
  char *result = buildString(string, 6);
  eipa_free((void **)(&(aux)), 252, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c");
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<callKernel>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x24(%rax),%rdi
  lea    D5(%rip),%rbp
  mov    %rbp,%rdx
  mov    $0xea,%esi
  call   <eipa_malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  mov    %rbx,%rsi
  call   <strcpy@plt>
  lea    D0(%rip),%rsi
  mov    0x8(%rsp),%rdi
  call   <strcat@plt>
  lea    D18(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D50(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    0x8(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    D59(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D1(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D44(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x6,%esi
  call   <buildString@plt>
  mov    %rax,%rbx
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  mov    $0xfc,%esi
  call   <eipa_free@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %rbx,%rax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D50
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D59
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D44
type_guessed: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c

tool: D0: <<<blocks,grid>>>(TODO:parameters);

tool: D18: dim3 grid(TODO:set grid dimensions);

tool: D50: dim3 blocks(TODO:set block dimensions);

tool: D59: cudaDeviceSynchronize();

tool: D1: cudaError_t err = cudaGetLastError();

tool: D44: HANDLE_ERROR( err );

assistant: ```c
char *callKernel(char *name) {
  char *aux = eipa_malloc((strlen(name) + strlen("<<<blocks,grid>>>(TODO:parameters);") + 1), 234, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c");
  strcpy(aux, name);
  strcat(aux, "<<<blocks,grid>>>(TODO:parameters);");
  char *string[6] = {"dim3 grid(TODO:set grid dimensions);", "dim3 blocks(TODO:set block dimensions);", aux, "cudaDeviceSynchronize();", "cudaError_t err = cudaGetLastError();", "HANDLE_ERROR( err );"};
  char *result = buildString(string, 6);
  eipa_free((void **)(&(aux)), 252, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c");
  return result;
}
```