ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D20(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  lea    0x14(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  xor    %esi,%esi
  movss  0xc(%rsp),%xmm0
  test   %edx,%edx
  jle    L36
  mov    $0xcccccccd,%r8d
  nopl   (%rax)
L48:
  mov    %edx,%eax
  mov    %edx,%edi
  pxor   %xmm1,%xmm1
  add    $0x1,%esi
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  mov    %edx,%ecx
  mov    %eax,%edx
  cvtsi2ss %edi,%xmm1
  addss  %xmm1,%xmm0
  cmp    $0x9,%ecx
  jg     L48
  mov    %eax,0x14(%rsp)
L36:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  movss  D9(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L11
  lea    D2(%rip),%rdi
  call   <printf@plt>
L30:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L11:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D20
datatype: string
name: retrieve_data
arguments: label: D9
datatype: byte[4]
name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D27
datatype: string

tool: D20: %d

tool: {"D9": [0x00,0x00,0xe0,0x40]}

tool: D2: light


tool: D27: heavy


assistant: ```c
int main() {
  int n, i;
  float sm;
  scanf("%d", &n);
  for (i = 0; n > 0; i++) {
    sm = sm + n % 10;
    n = n / 10;
  }
  sm = sm / i;
  if (sm < 7)
    printf("light\n");
  else
    printf("heavy\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rotateMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  cmpl   $0x0,-0x1c(%rbp)
  jle    L18
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L59:
  movl   $0x0,-0x8(%rbp)
  jmp    L58
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L58:
  mov    -0x1c(%rbp),%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L15
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  sar    %eax
  cmp    %eax,-0xc(%rbp)
  jl     L59
  jmp    L22
L18:
  nop
L22:
  pop    %rbp
  ret
```

assistant: ```c
void rotateMat(int **xs, int size) {
  if (!xs || size <= 0)
    return;
  for (int i = 0; i < size >> 1; i++) {
    for (int j = 0; j < size >> 1; j++) {
      int tmp = xs[i][j];
      xs[i][j] = xs[size - j - 1][i];
      xs[size - j - 1][i] = xs[size - i - 1][size - j - 1];
      xs[size - i - 1][size - j - 1] = xs[j][size - i - 1];
      xs[j][size - i - 1] = tmp;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rotateMat>:
  endbr64
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rcx
  test   %esi,%esi
  jle    L0
  mov    %esi,%eax
  sar    %eax
  test   %eax,%eax
  jle    L0
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%ebp
  mov    %esi,%r13d
  sub    %eax,%r13d
  movslq %esi,%rsi
  lea    -0x4(,%rsi,4),%r12
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rbx
  mov    $0x0,%edi
L23:
  movslq %ebp,%rax
  lea    -0x8(%rcx,%rax,8),%r9
  lea    -0x4(,%rax,4),%r8
  mov    %r12,%rdx
  mov    $0x0,%eax
L1:
  mov    %rax,%rsi
  add    (%r11),%rsi
  mov    (%rsi),%r10d
  mov    (%rcx,%rdx,2),%r14
  mov    (%r14,%rdi,1),%r14d
  mov    %r14d,(%rsi)
  mov    (%r9),%rsi
  mov    (%rsi,%rdx,1),%r14d
  mov    (%rcx,%rdx,2),%rsi
  mov    %r14d,(%rsi,%rdi,1)
  mov    (%rcx,%rax,2),%rsi
  mov    (%rsi,%r8,1),%r14d
  mov    (%r9),%rsi
  mov    %r14d,(%rsi,%rdx,1)
  mov    (%rcx,%rax,2),%rsi
  mov    %r10d,(%rsi,%r8,1)
  add    $0x4,%rax
  sub    $0x4,%rdx
  cmp    %rbx,%rax
  jne    L1
  add    $0x8,%r11
  add    $0x4,%rdi
  sub    $0x1,%ebp
  cmp    %r13d,%ebp
  jne    L23
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  ret
```

assistant: ```c
void rotateMat(int **xs, int size) {
  if (!xs || size <= 0)
    return;
  for (int i = 0; i < size >> 1; i++) {
    for (int j = 0; j < size >> 1; j++) {
      int tmp = xs[i][j];
      xs[i][j] = xs[size - j - 1][i];
      xs[size - j - 1][i] = xs[size - i - 1][size - j - 1];
      xs[size - i - 1][size - j - 1] = xs[j][size - i - 1];
      xs[j][size - i - 1] = tmp;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<rotateMat>:
  endbr64
  test   %rdi,%rdi
  je     L25
  test   %esi,%esi
  jle    L25
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sar    %ebp
  push   %rbx
  je     L15
  movslq %esi,%rsi
  movslq %ebp,%rbp
  mov    %rdi,%rbx
  xor    %r10d,%r10d
  lea    0x0(,%rsi,4),%r12
  lea    0x0(,%rbp,4),%r14
  lea    -0x4(%r12),%r11
  lea    (%rdi,%rsi,8),%r13
  nopl   0x0(%rax)
L21:
  mov    (%rbx,%r11,2),%rdx
  mov    (%rbx,%r10,2),%rdi
  mov    %r13,%rcx
  xor    %eax,%eax
  add    %r12,%rdx
L30:
  mov    -0x8(%rcx),%rsi
  mov    (%rdi,%rax,4),%r8d
  sub    $0x8,%rcx
  sub    $0x4,%rdx
  add    %r10,%rsi
  mov    (%rsi),%r9d
  mov    %r9d,(%rdi,%rax,4)
  mov    (%rdx),%r9d
  mov    %r9d,(%rsi)
  mov    (%rbx,%rax,8),%rsi
  add    $0x1,%rax
  add    %r11,%rsi
  mov    (%rsi),%r9d
  mov    %r9d,(%rdx)
  mov    %r8d,(%rsi)
  cmp    %rax,%rbp
  jne    L30
  add    $0x4,%r10
  sub    $0x4,%r11
  cmp    %r10,%r14
  jne    L21
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  ret
```

assistant: ```c
void rotateMat(int **xs, int size) {
  if (!xs || size <= 0)
    return;
  for (int i = 0; i < size >> 1; i++) {
    for (int j = 0; j < size >> 1; j++) {
      int tmp = xs[i][j];
      xs[i][j] = xs[size - j - 1][i];
      xs[size - j - 1][i] = xs[size - i - 1][size - j - 1];
      xs[size - i - 1][size - j - 1] = xs[j][size - i - 1];
      xs[j][size - i - 1] = tmp;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rotateMat>:
  endbr64
  test   %rdi,%rdi
  je     L48
  test   %esi,%esi
  jle    L48
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sar    %ebp
  push   %rbx
  je     L41
  movslq %esi,%rsi
  movslq %ebp,%rbp
  mov    %rdi,%rbx
  xor    %r10d,%r10d
  lea    0x0(,%rsi,4),%r12
  lea    0x0(,%rbp,4),%r14
  lea    -0x4(%r12),%r11
  lea    (%rdi,%rsi,8),%r13
  nopl   0x0(%rax)
L12:
  mov    (%rbx,%r11,2),%rdx
  mov    (%rbx,%r10,2),%rdi
  mov    %r13,%rcx
  xor    %eax,%eax
  add    %r12,%rdx
L44:
  mov    -0x8(%rcx),%rsi
  mov    (%rdi,%rax,4),%r8d
  sub    $0x8,%rcx
  sub    $0x4,%rdx
  add    %r10,%rsi
  mov    (%rsi),%r9d
  mov    %r9d,(%rdi,%rax,4)
  mov    (%rdx),%r9d
  mov    %r9d,(%rsi)
  mov    (%rbx,%rax,8),%rsi
  add    $0x1,%rax
  add    %r11,%rsi
  mov    (%rsi),%r9d
  mov    %r9d,(%rdx)
  mov    %r8d,(%rsi)
  cmp    %rax,%rbp
  jne    L44
  add    $0x4,%r10
  sub    $0x4,%r11
  cmp    %r10,%r14
  jne    L12
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  ret
```

assistant: ```c
void rotateMat(int **xs, int size) {
  if (!xs || size <= 0)
    return;
  for (int i = 0; i < size >> 1; i++) {
    for (int j = 0; j < size >> 1; j++) {
      int tmp = xs[i][j];
      xs[i][j] = xs[size - j - 1][i];
      xs[size - j - 1][i] = xs[size - i - 1][size - j - 1];
      xs[size - i - 1][size - j - 1] = xs[j][size - i - 1];
      xs[j][size - i - 1] = tmp;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  cmpl   $0x0,-0xc(%rbp)
  je     L20
  jmp    L43
L49:
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0xf,-0x4(%rbp)
  jne    L45
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L25
L45:
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L43:
  cmpl   $0x1d,-0x8(%rbp)
  jle    L49
L20:
  cmpl   $0x7b,-0x8(%rbp)
  jne    L55
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L57
L55:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L25:
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L57:
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D68
type: string
name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D60
type: string
name: disassemble_data
arguments: label: D19
type: string
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D57
type: string
name: disassemble_data
arguments: label: D33
type: string

tool: D68: 1


tool: D14: 2


tool: D60: 3


tool: D19: 4


tool: D23: 5


tool: D57: end


tool: D33: finish


assistant: ```c
int main() {
  int i, j, k;
  if (k) {
    while (i < 30) {
      printf("1\n");
      if (j == 15) {
        printf("2\n");
        goto end;
      }
      printf("3\n");
    }
  }
  if (i == 123) {
    printf("4\n");
    goto finish;
  } else {
    printf("5\n");
  }
end:
  printf("end\n");
finish:
  printf("finish\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string

tool: D11: 5


tool: D6: end


tool: D19: finish


assistant: ```c
int main() {
  int i, j, k;
  if (k) {
    while (i < 30) {
      printf("1\n");
      if (j == 15) {
        printf("2\n");
        goto end;
      }
      printf("3\n");
    }
  }
  if (i == 123) {
    printf("4\n");
    goto finish;
  } else {
    printf("5\n");
  }
end:
  printf("end\n");
finish:
  printf("finish\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type: string
name: unpack_data
arguments: data_label: D26
type: string
name: unpack_data
arguments: data_label: D0
type: string

tool: D11: 5


tool: D26: end


tool: D0: finish


assistant: ```c
int main() {
  int i, j, k;
  if (k) {
    while (i < 30) {
      printf("1\n");
      if (j == 15) {
        printf("2\n");
        goto end;
      }
      printf("3\n");
    }
  }
  if (i == 123) {
    printf("4\n");
    goto finish;
  } else {
    printf("5\n");
  }
end:
  printf("end\n");
finish:
  printf("finish\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
datatype: string
name: unpack_data
arguments: data_label: D27
datatype: string
name: unpack_data
arguments: data_label: D15
datatype: string

tool: D10: 5


tool: D27: end


tool: D15: finish


assistant: ```c
int main() {
  int i, j, k;
  if (k) {
    while (i < 30) {
      printf("1\n");
      if (j == 15) {
        printf("2\n");
        goto end;
      }
      printf("3\n");
    }
  }
  if (i == 123) {
    printf("4\n");
    goto finish;
  } else {
    printf("5\n");
  }
end:
  printf("end\n");
finish:
  printf("finish\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <np_werror@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int err(char *msg, int no) {
  np_werror(msg, no);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  call   <np_werror@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int err(char *msg, int no) {
  np_werror(msg, no);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  call   <np_werror@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int err(char *msg, int no) {
  np_werror(msg, no);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  call   <np_werror@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int err(char *msg, int no) {
  np_werror(msg, no);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_peg_path_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L13
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L13
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strbuf_addstr@plt>
L13:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strbuf_addstr@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D5: ./

assistant: ```c
void get_peg_path_buf(struct strbuf *bf, const char *path) {
  if (path[0] != '.' && path[1] != '/') {
    strbuf_addstr(bf, "./");
  }
  strbuf_addstr(bf, path);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_peg_path_buf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  cmpb   $0x2e,(%rsi)
  je     L17
  cmpb   $0x2f,0x1(%rsi)
  jne    L20
L17:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strbuf_addstr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  lea    D9(%rip),%rsi
  call   <strbuf_addstr@plt>
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: ./

assistant: ```c
void get_peg_path_buf(struct strbuf *bf, const char *path) {
  if (path[0] != '.' && path[1] != '/') {
    strbuf_addstr(bf, "./");
  }
  strbuf_addstr(bf, path);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_peg_path_buf>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  cmpb   $0x2e,(%rsi)
  je     L5
  cmpb   $0x2f,0x1(%rsi)
  jne    L19
L5:
  add    $0x10,%rsp
  mov    %rbp,%rsi
  pop    %rbp
  jmp    1050 <strbuf_addstr@plt>
  nopl   0x0(%rax)
L19:
  lea    D5(%rip),%rsi
  mov    %rdi,0x8(%rsp)
  call   <strbuf_addstr@plt>
  mov    0x8(%rsp),%rdi
  add    $0x10,%rsp
  mov    %rbp,%rsi
  pop    %rbp
  jmp    1050 <strbuf_addstr@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: ./

assistant: ```c
void get_peg_path_buf(struct strbuf *bf, const char *path) {
  if (path[0] != '.' && path[1] != '/') {
    strbuf_addstr(bf, "./");
  }
  strbuf_addstr(bf, path);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_peg_path_buf>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  cmpb   $0x2e,(%rsi)
  je     L19
  cmpb   $0x2f,0x1(%rsi)
  jne    L14
L19:
  add    $0x10,%rsp
  mov    %rbp,%rsi
  pop    %rbp
  jmp    1050 <strbuf_addstr@plt>
  nopl   0x0(%rax)
L14:
  lea    D3(%rip),%rsi
  mov    %rdi,0x8(%rsp)
  call   <strbuf_addstr@plt>
  mov    0x8(%rsp),%rdi
  add    $0x10,%rsp
  mov    %rbp,%rsi
  pop    %rbp
  jmp    1050 <strbuf_addstr@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: ./

assistant: ```c
void get_peg_path_buf(struct strbuf *bf, const char *path) {
  if (path[0] != '.' && path[1] != '/') {
    strbuf_addstr(bf, "./");
  }
  strbuf_addstr(bf, path);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x61,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  putchar('a');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x61,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  putchar('a');
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x61,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  putchar('a');
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x61,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  putchar('a');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__moddi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L32
  movl   $0x1,-0x8(%rbp)
  negl   -0x14(%rbp)
L32:
  cmpl   $0x0,-0x18(%rbp)
  jns    L42
  movl   $0x1,-0x4(%rbp)
  negl   -0x18(%rbp)
L42:
  cmpl   $0x0,-0x18(%rbp)
  jne    L21
  mov    $0xffffffff,%eax
  jmp    L69
L47:
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
L21:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L47
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L24
  mov    -0x14(%rbp),%eax
  neg    %eax
  jmp    L69
L24:
  mov    -0x14(%rbp),%eax
L69:
  pop    %rbp
  ret
```

assistant: ```c
int64_t __moddi3(int64_t a, int64_t b) {
  int sign1 = 0, sign2 = 0;
  if (a < 0) {
    sign1 = 1;
    a = -a;
  }
  if (b < 0) {
    sign2 = 1;
    b = -b;
  }
  if (b == 0)
    return (int64_t)-1;
  while (a > b)
    a = a - b;
  return (sign1 ^ sign2) ? -a : a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__moddi3>:
  endbr64
  mov    $0x0,%edx
  test   %edi,%edi
  js     L64
L25:
  test   %esi,%esi
  js     L29
  je     L60
  mov    $0x0,%ecx
L59:
  cmp    %esi,%edi
  jle    L36
L38:
  sub    %esi,%edi
  cmp    %esi,%edi
  jg     L38
L36:
  mov    %edi,%eax
  neg    %eax
  cmp    %ecx,%edx
  cmove  %edi,%eax
  ret
L64:
  neg    %edi
  mov    $0x1,%edx
  jmp    L25
L29:
  neg    %esi
  mov    $0x1,%ecx
  jmp    L59
L60:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int64_t __moddi3(int64_t a, int64_t b) {
  int sign1 = 0, sign2 = 0;
  if (a < 0) {
    sign1 = 1;
    a = -a;
  }
  if (b < 0) {
    sign2 = 1;
    b = -b;
  }
  if (b == 0)
    return (int64_t)-1;
  while (a > b)
    a = a - b;
  return (sign1 ^ sign2) ? -a : a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__moddi3>:
  endbr64
  xor    %edx,%edx
  test   %edi,%edi
  jns    L27
  neg    %edi
  mov    $0x1,%edx
L27:
  test   %esi,%esi
  js     L33
  je     L59
  xor    %ecx,%ecx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L12:
  sub    %esi,%edi
L23:
  cmp    %esi,%edi
  jg     L12
  mov    %edi,%eax
  neg    %eax
  cmp    %ecx,%edx
  cmove  %edi,%eax
  ret
L33:
  neg    %esi
  mov    $0x1,%ecx
  jmp    L23
L59:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int64_t __moddi3(int64_t a, int64_t b) {
  int sign1 = 0, sign2 = 0;
  if (a < 0) {
    sign1 = 1;
    a = -a;
  }
  if (b < 0) {
    sign2 = 1;
    b = -b;
  }
  if (b == 0)
    return (int64_t)-1;
  while (a > b)
    a = a - b;
  return (sign1 ^ sign2) ? -a : a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__moddi3>:
  endbr64
  xor    %edx,%edx
  test   %edi,%edi
  jns    L17
  neg    %edi
  mov    $0x1,%edx
L17:
  test   %esi,%esi
  js     L24
  je     L29
  xor    %ecx,%ecx
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L45:
  sub    %esi,%edi
L11:
  cmp    %esi,%edi
  jg     L45
  mov    %edi,%eax
  neg    %eax
  cmp    %ecx,%edx
  cmove  %edi,%eax
  ret
L24:
  neg    %esi
  mov    $0x1,%ecx
  jmp    L11
L29:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int64_t __moddi3(int64_t a, int64_t b) {
  int sign1 = 0, sign2 = 0;
  if (a < 0) {
    sign1 = 1;
    a = -a;
  }
  if (b < 0) {
    sign2 = 1;
    b = -b;
  }
  if (b == 0)
    return (int64_t)-1;
  while (a > b)
    a = a - b;
  return (sign1 ^ sign2) ? -a : a;
}
```