ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reads>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x40,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <check_malloc@plt>
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L15
L27:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L11
  shlq   -0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <check_malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x29(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
L15:
  lea    -0x29(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <check@plt>
  cmp    $0x1,%eax
  je     L27
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D8: reads

assistant: ```c
char *reads(int fd) {
  size_t buf_sz = 64;
  char *buf = check_malloc(buf_sz);
  off_t off = 0;
  char next;
  while (check(read(fd, &next, 1), "reads") == 1) {
    if (off >= buf_sz - 1) {
      buf_sz *= 2;
      char *tmp = check_malloc(buf_sz);
      memcpy(tmp, buf, off);
      free(buf);
      buf = tmp;
    }
    buf[off] = next;
    off++;
  }
  buf[off] = 0;
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reads>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x40,%edi
  call   <check_malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  mov    $0x40,%r12d
  lea    D1(%rip),%r14
  jmp    L41
L45:
  movzbl 0x7(%rsp),%eax
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L41:
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%edi
  mov    %r14,%rsi
  call   <check@plt>
  cmp    $0x1,%eax
  jne    L14
  lea    -0x1(%r12),%rax
  cmp    %rbx,%rax
  ja     L45
  add    %r12,%r12
  mov    %r12,%rdi
  call   <check_malloc@plt>
  mov    %rax,%r15
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r15,%rbp
  jmp    L45
L14:
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: reads

assistant: ```c
char *reads(int fd) {
  size_t buf_sz = 64;
  char *buf = check_malloc(buf_sz);
  off_t off = 0;
  char next;
  while (check(read(fd, &next, 1), "reads") == 1) {
    if (off >= buf_sz - 1) {
      buf_sz *= 2;
      char *tmp = check_malloc(buf_sz);
      memcpy(tmp, buf, off);
      free(buf);
      buf = tmp;
    }
    buf[off] = next;
    off++;
  }
  buf[off] = 0;
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reads>:
  endbr64
  push   %r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  mov    $0x40,%edi
  push   %r12
  mov    $0x40,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%r15
  call   <check_malloc@plt>
  mov    %rax,%rbp
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl 0x17(%rsp),%eax
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L46:
  mov    %r15,%rsi
  mov    %r13d,%edi
  mov    $0x1,%edx
  call   <read@plt>
  mov    %r14,%rsi
  mov    %eax,%edi
  call   <check@plt>
  cmp    $0x1,%eax
  jne    L9
  lea    -0x1(%r12),%rax
  cmp    %rbx,%rax
  ja     L1
  add    %r12,%r12
  mov    %r12,%rdi
  call   <check_malloc@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rbp
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L9:
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x28,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: D8: reads

assistant: ```c
char *reads(int fd) {
  size_t buf_sz = 64;
  char *buf = check_malloc(buf_sz);
  off_t off = 0;
  char next;
  while (check(read(fd, &next, 1), "reads") == 1) {
    if (off >= buf_sz - 1) {
      buf_sz *= 2;
      char *tmp = check_malloc(buf_sz);
      memcpy(tmp, buf, off);
      free(buf);
      buf = tmp;
    }
    buf[off] = next;
    off++;
  }
  buf[off] = 0;
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reads>:
  endbr64
  push   %r15
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  mov    $0x40,%edi
  push   %r12
  mov    $0x40,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%r15
  call   <check_malloc@plt>
  mov    %rax,%rbp
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl 0x17(%rsp),%eax
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L16:
  mov    %r15,%rsi
  mov    %r13d,%edi
  mov    $0x1,%edx
  call   <read@plt>
  mov    %r14,%rsi
  mov    %eax,%edi
  call   <check@plt>
  cmp    $0x1,%eax
  jne    L44
  lea    -0x1(%r12),%rax
  cmp    %rbx,%rax
  ja     L9
  add    %r12,%r12
  mov    %r12,%rdi
  call   <check_malloc@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rbp
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L44:
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string

tool: D7: reads

assistant: ```c
char *reads(int fd) {
  size_t buf_sz = 64;
  char *buf = check_malloc(buf_sz);
  off_t off = 0;
  char next;
  while (check(read(fd, &next, 1), "reads") == 1) {
    if (off >= buf_sz - 1) {
      buf_sz *= 2;
      char *tmp = check_malloc(buf_sz);
      memcpy(tmp, buf, off);
      free(buf);
      buf = tmp;
    }
    buf[off] = next;
    off++;
  }
  buf[off] = 0;
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eStrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <eMalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
extern char *eStrdup(const char *str) {
  char *result = (char *)eMalloc((size_t)(strlen(str) + 1) * sizeof(char));
  strcpy(result, str);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eStrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <eMalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
extern char *eStrdup(const char *str) {
  char *result = (char *)eMalloc((size_t)(strlen(str) + 1) * sizeof(char));
  strcpy(result, str);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<eStrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <eMalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
extern char *eStrdup(const char *str) {
  char *result = (char *)eMalloc((size_t)(strlen(str) + 1) * sizeof(char));
  strcpy(result, str);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eStrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <eMalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
extern char *eStrdup(const char *str) {
  char *result = (char *)eMalloc((size_t)(strlen(str) + 1) * sizeof(char));
  strcpy(result, str);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<plus_linear_min2_Good_FP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <plus_linear_min@plt>
  movl   $0x1,-0x30(%rbp,%rax,4)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void plus_linear_min2_Good_FP() {
  int a[10];
  a[plus_linear_min(4)] = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<plus_linear_min2_Good_FP>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <plus_linear_min@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void plus_linear_min2_Good_FP() {
  int a[10];
  a[plus_linear_min(4)] = 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<plus_linear_min2_Good_FP>:
  endbr64
  mov    $0x4,%edi
  jmp    1050 <plus_linear_min@plt>
```

assistant: ```c
void plus_linear_min2_Good_FP() {
  int a[10];
  a[plus_linear_min(4)] = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<plus_linear_min2_Good_FP>:
  endbr64
  mov    $0x4,%edi
  jmp    1050 <plus_linear_min@plt>
```

assistant: ```c
void plus_linear_min2_Good_FP() {
  int a[10];
  a[plus_linear_min(4)] = 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L2
  jmp    L62
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L66
  addl   $0x1,-0xc(%rbp)
  jmp    L62
L66:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rdi
  mov    %rdx,%rcx
  mov    %eax,%edx
  call   <swap@plt>
L62:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L13
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L4
  subl   $0x1,-0xc(%rbp)
  jmp    L34
L4:
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x28(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <sort>
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sort>
L2:
  nop
  leave
  ret
```

assistant: ```c
void sort(int num[], int beg, int end, char arr[][80]) {
  int i = beg + 1, j = end, piv = num[beg];
  if (end > beg) {
    while (i < j) {
      if (num[i] < piv)
        i++;
      else
        swap(num, i, j--, arr);
    }
    if (num[i] > piv)
      i--;
    else
      j++;
    swap(num, beg, i, arr);
    sort(num, beg, i - 1, arr);
    sort(num, j, end, arr);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %edx,%esi
  jge    L38
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %rcx,%r14
  lea    0x1(%rsi),%ebx
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r15d
  cmp    %edx,%ebx
  jge    L35
  mov    %edx,%r12d
  jmp    L14
L76:
  add    $0x1,%ebx
L50:
  cmp    %r12d,%ebx
  jge    L70
L14:
  movslq %ebx,%rax
  cmp    %r15d,0x0(%rbp,%rax,4)
  jl     L76
  lea    -0x1(%r12),%eax
  mov    %eax,0x8(%rsp)
  mov    %r14,%rcx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x8(%rsp),%r12d
  jmp    L50
L35:
  mov    0xc(%rsp),%r12d
L70:
  movslq %ebx,%rax
  cmp    %r15d,0x0(%rbp,%rax,4)
  jle    L60
  sub    $0x1,%ebx
L42:
  mov    %r14,%rcx
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    -0x1(%rbx),%edx
  mov    %r14,%rcx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <sort>
  mov    %r14,%rcx
  mov    0xc(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <sort>
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  add    $0x1,%r12d
  jmp    L42
```

assistant: ```c
void sort(int num[], int beg, int end, char arr[][80]) {
  int i = beg + 1, j = end, piv = num[beg];
  if (end > beg) {
    while (i < j) {
      if (num[i] < piv)
        i++;
      else
        swap(num, i, j--, arr);
    }
    if (num[i] > piv)
      i--;
    else
      j++;
    swap(num, beg, i, arr);
    sort(num, beg, i - 1, arr);
    sort(num, j, end, arr);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  push   %rbx
  lea    0x1(%rax),%ebx
  lea    (%rdi,%rax,4),%rax
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %r12d,%edx
  jle    L33
  mov    0xc(%rsp),%r8d
  mov    (%rax),%r13d
  mov    %rdi,%r15
  mov    %rcx,%rbp
  cmp    %ebx,%r8d
  jg     L8
  jmp    L45
  nopl   0x0(%rax)
L58:
  add    $0x1,%ebx
  lea    0x4(%r15,%rax,1),%r14
  cmp    %ebx,%r8d
  jle    L73
L8:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r15,%rax,1),%r14
  cmp    %r13d,(%r14)
  jl     L58
  lea    -0x1(%r8),%eax
  mov    %r8d,%edx
  mov    %rbp,%rcx
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    %eax,0x8(%rsp)
  call   <swap@plt>
  mov    0x8(%rsp),%r8d
  cmp    %ebx,%r8d
  jg     L8
L73:
  cmp    %r13d,(%r14)
  jg     L65
L50:
  add    $0x1,%r8d
L47:
  mov    %ebx,%edx
  mov    %rbp,%rcx
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    %r8d,0x8(%rsp)
  call   <swap@plt>
  lea    -0x1(%rbx),%edx
  mov    %rbp,%rcx
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <sort>
  movslq 0x8(%rsp),%rax
  mov    %rax,%r8
  lea    0x1(%rax),%ebx
  lea    (%r15,%rax,4),%rax
  cmp    0xc(%rsp),%r8d
  jge    L33
  mov    %r8d,%r12d
  mov    0xc(%rsp),%r8d
  mov    (%rax),%r13d
  cmp    %ebx,%r8d
  jg     L8
L45:
  movslq %ebx,%rax
  mov    0xc(%rsp),%r8d
  lea    (%r15,%rax,4),%r14
  cmp    %r13d,(%r14)
  jle    L50
  nopl   0x0(%rax)
L65:
  sub    $0x1,%ebx
  jmp    L47
  nopl   (%rax)
L33:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sort(int num[], int beg, int end, char arr[][80]) {
  int i = beg + 1, j = end, piv = num[beg];
  if (end > beg) {
    while (i < j) {
      if (num[i] < piv)
        i++;
      else
        swap(num, i, j--, arr);
    }
    if (num[i] > piv)
      i--;
    else
      j++;
    swap(num, beg, i, arr);
    sort(num, beg, i - 1, arr);
    sort(num, j, end, arr);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  mov    %esi,%ecx
  push   %rbp
  movslq %ecx,%rax
  push   %rbx
  lea    (%r15,%rax,4),%rax
  lea    0x1(%rcx),%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  cmp    %ecx,0x8(%rsp)
  jle    L46
L51:
  mov    0x8(%rsp),%r8d
  mov    (%rax),%r14d
  cmp    %ebx,%r8d
  jg     L56
  jmp    L138
  nopl   0x0(%rax,%rax,1)
L87:
  add    $0x1,%ebx
  lea    0x4(%r15,%rax,1),%rbp
  cmp    %r8d,%ebx
  jge    L130
L56:
  movslq %ebx,%r9
L104:
  lea    0x0(,%r9,4),%rax
  lea    (%r15,%rax,1),%rbp
  cmp    %r14d,0x0(%rbp)
  jl     L87
  lea    -0x1(%r8),%r13d
  mov    %r8d,%edx
  mov    %r12,%rcx
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    %r9,(%rsp)
  call   <swap@plt>
  mov    %r13d,%r8d
  cmp    %ebx,%r13d
  jle    L130
  mov    (%rsp),%r9
  jmp    L104
  nopl   0x0(%rax,%rax,1)
L130:
  cmp    %r14d,0x0(%rbp)
  jle    L106
  mov    0xc(%rsp),%r14d
  lea    -0x1(%rbx),%edx
  mov    %r12,%rcx
  mov    %r15,%rdi
  mov    %r8d,(%rsp)
  mov    %r14d,%esi
  call   <swap@plt>
  lea    -0x2(%rbx),%edx
  mov    %r12,%rcx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <sort>
  movslq (%rsp),%rax
  mov    %rax,%r8
  lea    0x1(%rax),%ebx
  lea    (%r15,%rax,4),%rax
  cmp    %r8d,0x8(%rsp)
  jle    L46
L30:
  mov    %r8d,0xc(%rsp)
  mov    0x8(%rsp),%r8d
  mov    (%rax),%r14d
  cmp    %ebx,%r8d
  jg     L56
L138:
  movslq %ebx,%rax
  cmp    (%r15,%rax,4),%r14d
  jge    L106
  mov    0xc(%rsp),%esi
  lea    -0x1(%rbx),%edx
  mov    %r12,%rcx
  mov    %r15,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%ecx
  lea    -0x2(%rbx),%eax
  mov    %eax,0x8(%rsp)
  movslq %ecx,%rax
  lea    0x1(%rcx),%ebx
  lea    (%r15,%rax,4),%rax
  cmp    %ecx,0x8(%rsp)
  jg     L51
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L106:
  mov    0xc(%rsp),%r14d
  mov    %ebx,%edx
  mov    %r12,%rcx
  mov    %r15,%rdi
  lea    0x1(%r8),%ebp
  mov    %r8d,(%rsp)
  mov    %r14d,%esi
  call   <swap@plt>
  lea    -0x1(%rbx),%edx
  mov    %r12,%rcx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <sort>
  mov    (%rsp),%r8d
  movslq %ebp,%rax
  lea    (%r15,%rax,4),%rax
  lea    0x2(%r8),%ebx
  cmp    %ebp,0x8(%rsp)
  jle    L46
  mov    %ebp,%r8d
  jmp    L30
```

assistant: ```c
void sort(int num[], int beg, int end, char arr[][80]) {
  int i = beg + 1, j = end, piv = num[beg];
  if (end > beg) {
    while (i < j) {
      if (num[i] < piv)
        i++;
      else
        swap(num, i, j--, arr);
    }
    if (num[i] > piv)
      i--;
    else
      j++;
    swap(num, beg, i, arr);
    sort(num, beg, i - 1, arr);
    sort(num, j, end, arr);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x74(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L3
L22:
  movl   $0x0,-0x78(%rbp)
  jmp    L46
L49:
  mov    -0x7c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x78(%rbp),%eax
  add    %edx,%eax
  lea    0x1(%rax),%ecx
  mov    -0x78(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    %ecx,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x78(%rbp)
L46:
  cmpl   $0x4,-0x78(%rbp)
  jle    L49
  addl   $0x1,-0x7c(%rbp)
L3:
  cmpl   $0x4,-0x7c(%rbp)
  jle    L22
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <Print@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <TLBR@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <BLTR@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <TLBR@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <BLTR@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

assistant: ```c
void main() {
  int array[5][5], i, j, n = 1;
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      array[i][j] = j + i * 5 + 1;
  Print(array);
  TLBR(array);
  BLTR(array);
  TLBR(array);
  BLTR(array);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x6,%ecx
L22:
  lea    -0x5(%rcx),%eax
  mov    %rsi,%rdx
L18:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L18
  add    $0x14,%rsi
  add    $0x5,%ecx
  cmp    $0x1f,%ecx
  jne    L22
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <Print@plt>
  mov    %rbx,%rdi
  call   <TLBR@plt>
  mov    %rbx,%rdi
  call   <BLTR@plt>
  mov    %rbx,%rdi
  call   <TLBR@plt>
  mov    %rbx,%rdi
  call   <BLTR@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x70,%rsp
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  int array[5][5], i, j, n = 1;
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      array[i][j] = j + i * 5 + 1;
  Print(array);
  TLBR(array);
  BLTR(array);
  TLBR(array);
  BLTR(array);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6,%ecx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
L4:
  lea    -0x5(%rcx),%eax
  mov    %rsi,%rdx
L15:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L15
  add    $0x14,%rsi
  lea    0x5(%rax),%ecx
  cmp    $0x1a,%eax
  jne    L4
  mov    %rbp,%rdi
  call   <Print@plt>
  mov    %rbp,%rdi
  call   <TLBR@plt>
  mov    %rbp,%rdi
  call   <BLTR@plt>
  mov    %rbp,%rdi
  call   <TLBR@plt>
  mov    %rbp,%rdi
  call   <BLTR@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x70,%rsp
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  int array[5][5], i, j, n = 1;
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      array[i][j] = j + i * 5 + 1;
  Print(array);
  TLBR(array);
  BLTR(array);
  TLBR(array);
  BLTR(array);
  return;
}
```