ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rbp
  jmp    L18
L31:
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L18:
  mov    %rsp,%rdi
  mov    $0x2710,%esi
  call   <my_getline@plt>
  test   %eax,%eax
  jle    L1
  sub    $0x1,%eax
  movslq %eax,%rdx
  cmpb   $0xa,(%rsp,%rdx,1)
  jne    L31
  movb   $0x0,(%rsp,%rdx,1)
  jmp    L31
L1:
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x2728,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: %s


assistant: ```c
int main() {
  int len;
  char line[10000];
  while ((len = my_getline(line, 10000)) > 0) {
    if (line[len - 1] == '\n')
      line[len - 1] = '\0';
    reverse(line);
    printf("%s\n", line);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  lea    D8(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L4
  nopl   0x0(%rax)
L27:
  sub    $0x1,%eax
  cltq
  cmpb   $0xa,(%rsp,%rax,1)
  jne    L6
  movb   $0x0,(%rsp,%rax,1)
L6:
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L4:
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <my_getline@plt>
  test   %eax,%eax
  jg     L27
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x2728,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: %s


assistant: ```c
int main() {
  int len;
  char line[10000];
  while ((len = my_getline(line, 10000)) > 0) {
    if (line[len - 1] == '\n')
      line[len - 1] = '\0';
    reverse(line);
    printf("%s\n", line);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  lea    D2(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L15
  nopl   0x0(%rax)
L23:
  sub    $0x1,%eax
  cltq
  cmpb   $0xa,(%rsp,%rax,1)
  jne    L34
  movb   $0x0,(%rsp,%rax,1)
L34:
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L15:
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <my_getline@plt>
  test   %eax,%eax
  jg     L23
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x2728,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: %s


assistant: ```c
int main() {
  int len;
  char line[10000];
  while ((len = my_getline(line, 10000)) > 0) {
    if (line[len - 1] == '\n')
      line[len - 1] = '\0';
    reverse(line);
    printf("%s\n", line);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_key_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x20(%rbp)
  movw   $0x3d,-0xa(%rbp)
  lea    -0x28(%rbp),%rdx
  lea    -0xa(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtok_r@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int get_key_value(char *str, char **key, char **value) {
  char *lstr = strdup(str);
  const char s[2] = "=";
  char *lkey;
  char *lvalue;
  lkey = strtok_r(lstr, s, &lvalue);
  *key = (char *)malloc(strlen(lkey) + 1);
  *value = (char *)malloc(strlen(lvalue) + 1);
  strcpy(*key, lkey);
  strcpy(*value, lvalue);
  free(lstr);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_key_value>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,%rbx
  movw   $0x3d,0x16(%rsp)
  lea    0x8(%rsp),%rdx
  lea    0x16(%rsp),%rsi
  mov    %rax,%rdi
  call   <strtok_r@plt>
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    0x8(%rsp),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %r13,%rsi
  mov    (%r12),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rsi
  mov    0x0(%rbp),%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_key_value(char *str, char **key, char **value) {
  char *lstr = strdup(str);
  const char s[2] = "=";
  char *lkey;
  char *lvalue;
  lkey = strtok_r(lstr, s, &lvalue);
  *key = (char *)malloc(strlen(lkey) + 1);
  *value = (char *)malloc(strlen(lvalue) + 1);
  strcpy(*key, lkey);
  strcpy(*value, lvalue);
  free(lstr);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_key_value>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    $0x3d,%edx
  lea    0x16(%rsp),%rsi
  mov    %dx,0x16(%rsp)
  mov    %rax,%rdi
  lea    0x8(%rsp),%rdx
  mov    %rax,%rbp
  call   <strtok_r@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,(%r12)
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,(%rbx)
  mov    (%r12),%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  mov    0x8(%rsp),%rsi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_key_value(char *str, char **key, char **value) {
  char *lstr = strdup(str);
  const char s[2] = "=";
  char *lkey;
  char *lvalue;
  lkey = strtok_r(lstr, s, &lvalue);
  *key = (char *)malloc(strlen(lkey) + 1);
  *value = (char *)malloc(strlen(lvalue) + 1);
  strcpy(*key, lkey);
  strcpy(*value, lvalue);
  free(lstr);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_key_value>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    $0x3d,%edx
  lea    0x16(%rsp),%rsi
  mov    %dx,0x16(%rsp)
  mov    %rax,%rdi
  lea    0x8(%rsp),%rdx
  mov    %rax,%rbp
  call   <strtok_r@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,(%r12)
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,(%rbx)
  mov    (%r12),%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  mov    0x8(%rsp),%rsi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_key_value(char *str, char **key, char **value) {
  char *lstr = strdup(str);
  const char s[2] = "=";
  char *lkey;
  char *lvalue;
  lkey = strtok_r(lstr, s, &lvalue);
  *key = (char *)malloc(strlen(lkey) + 1);
  *value = (char *)malloc(strlen(lvalue) + 1);
  strcpy(*key, lkey);
  strcpy(*value, lvalue);
  free(lstr);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x18(%rbp)
  movl   $0xc,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <list_add_int@plt>
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <list_add_int@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <list_exists_int@plt>
  test   %rax,%rax
  je     L18
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L18:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L24:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <list_free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string
name: parse_data
arguments: tag: D6
type: string

tool: D1: Found


tool: D6: Not Found


assistant: ```c
int main() {
  struct list_int *list_int_pt;
  int i = 4;
  int j = 12;
  list_add_int(&list_int_pt, i);
  list_add_int(&list_int_pt, j);
  if (list_exists_int(list_int_pt, j)) {
    printf("Found\n");
  } else {
    printf("Not Found\n");
  }
  list_free(&list_int_pt);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <list_add_int@plt>
  mov    $0xc,%esi
  mov    %rbx,%rdi
  call   <list_add_int@plt>
  mov    $0xc,%esi
  mov    (%rsp),%rdi
  call   <list_exists_int@plt>
  test   %rax,%rax
  je     L23
  lea    D6(%rip),%rdi
  call   <printf@plt>
L14:
  mov    %rsp,%rdi
  call   <list_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L23:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D9
type: string

tool: D6: Found


tool: D9: Not Found


assistant: ```c
int main() {
  struct list_int *list_int_pt;
  int i = 4;
  int j = 12;
  list_add_int(&list_int_pt, i);
  list_add_int(&list_int_pt, j);
  if (list_exists_int(list_int_pt, j)) {
    printf("Found\n");
  } else {
    printf("Not Found\n");
  }
  list_free(&list_int_pt);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <list_add_int@plt>
  mov    $0xc,%esi
  mov    %rbp,%rdi
  call   <list_add_int@plt>
  mov    (%rsp),%rdi
  mov    $0xc,%esi
  call   <list_exists_int@plt>
  test   %rax,%rax
  je     L2
  lea    D19(%rip),%rdi
  call   <printf@plt>
L6:
  mov    %rbp,%rdi
  call   <list_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D14
type: string

tool: D19: Found


tool: D14: Not Found


assistant: ```c
int main() {
  struct list_int *list_int_pt;
  int i = 4;
  int j = 12;
  list_add_int(&list_int_pt, i);
  list_add_int(&list_int_pt, j);
  if (list_exists_int(list_int_pt, j)) {
    printf("Found\n");
  } else {
    printf("Not Found\n");
  }
  list_free(&list_int_pt);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <list_add_int@plt>
  mov    $0xc,%esi
  mov    %rbp,%rdi
  call   <list_add_int@plt>
  mov    (%rsp),%rdi
  mov    $0xc,%esi
  call   <list_exists_int@plt>
  test   %rax,%rax
  je     L24
  lea    D10(%rip),%rdi
  call   <printf@plt>
L26:
  mov    %rbp,%rdi
  call   <list_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L24:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D17
type_infered: string

tool: D10: Found


tool: D17: Not Found


assistant: ```c
int main() {
  struct list_int *list_int_pt;
  int i = 4;
  int j = 12;
  list_add_int(&list_int_pt, i);
  list_add_int(&list_int_pt, j);
  if (list_exists_int(list_int_pt, j)) {
    printf("Found\n");
  } else {
    printf("Not Found\n");
  }
  list_free(&list_int_pt);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort_of_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movsd  D5(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L14
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sort_of_random>
  jmp    L2
L14:
  nop
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

assistant: ```c
void sort_of_random(int *r) {
  *r = (int)(rand() / (rand() * .25));
  if (*r == 0) {
    sort_of_random(r);
  } else {
    return;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_of_random>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <rand@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movapd %xmm0,%xmm1
  mulsd  D9(%rip),%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,0x0(%rbp)
  test   %eax,%eax
  je     L11
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rbp,%rdi
  call   <sort_of_random>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

assistant: ```c
void sort_of_random(int *r) {
  *r = (int)(rand() / (rand() * .25));
  if (*r == 0) {
    sort_of_random(r);
  } else {
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort_of_random>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  call   <rand@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <rand@plt>
  mulsd  D8(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  mov    %eax,(%rbx)
  test   %eax,%eax
  je     L2
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

assistant: ```c
void sort_of_random(int *r) {
  *r = (int)(rand() / (rand() * .25));
  if (*r == 0) {
    sort_of_random(r);
  } else {
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sort_of_random>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  call   <rand@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <rand@plt>
  mulsd  D8(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  mov    %eax,(%rbx)
  test   %eax,%eax
  je     L4
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

assistant: ```c
void sort_of_random(int *r) {
  *r = (int)(rand() / (rand() * .25));
  if (*r == 0) {
    sort_of_random(r);
  } else {
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parseRankChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  sub    $0x31,%eax
  cmp    $0x7,%eax
  ja     L27
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D4(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L89
  mov    $0x1,%eax
  jmp    L89
  mov    $0x2,%eax
  jmp    L89
  mov    $0x3,%eax
  jmp    L89
  mov    $0x4,%eax
  jmp    L89
  mov    $0x5,%eax
  jmp    L89
  mov    $0x6,%eax
  jmp    L89
  mov    $0x7,%eax
  jmp    L89
L27:
  mov    $0x8,%eax
L89:
  leave
  ret
```

assistant: ```c
int parseRankChar(const char c) {
  switch (tolower(c)) {
  case '1':
    return 0;
  case '2':
    return 1;
  case '3':
    return 2;
  case '4':
    return 3;
  case '5':
    return 4;
  case '6':
    return 5;
  case '7':
    return 6;
  case '8':
    return 7;
  default:
    return 8;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parseRankChar>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <tolower@plt>
  sub    $0x31,%eax
  cmp    $0x7,%eax
  ja     L50
  mov    %eax,%eax
  lea    D4(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
L61:
  add    $0x8,%rsp
  ret
  mov    $0x2,%eax
  jmp    L61
  mov    $0x3,%eax
  jmp    L61
  mov    $0x4,%eax
  jmp    L61
  mov    $0x5,%eax
  jmp    L61
  mov    $0x6,%eax
  jmp    L61
  mov    $0x7,%eax
  jmp    L61
L50:
  mov    $0x8,%eax
  jmp    L61
  mov    $0x0,%eax
  jmp    L61
```

assistant: ```c
int parseRankChar(const char c) {
  switch (tolower(c)) {
  case '1':
    return 0;
  case '2':
    return 1;
  case '3':
    return 2;
  case '4':
    return 3;
  case '5':
    return 4;
  case '6':
    return 5;
  case '7':
    return 6;
  case '8':
    return 7;
  default:
    return 8;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parseRankChar>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    $0x8,%edx
  sub    $0x31,%eax
  cmp    %edx,%eax
  cmova  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int parseRankChar(const char c) {
  switch (tolower(c)) {
  case '1':
    return 0;
  case '2':
    return 1;
  case '3':
    return 2;
  case '4':
    return 3;
  case '5':
    return 4;
  case '6':
    return 5;
  case '7':
    return 6;
  case '8':
    return 7;
  default:
    return 8;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<parseRankChar>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    $0x8,%edx
  sub    $0x31,%eax
  cmp    %edx,%eax
  cmova  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int parseRankChar(const char c) {
  switch (tolower(c)) {
  case '1':
    return 0;
  case '2':
    return 1;
  case '3':
    return 2;
  case '4':
    return 3;
  case '5':
    return 4;
  case '6':
    return 5;
  case '7':
    return 6;
  case '8':
    return 7;
  default:
    return 8;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L13
L47:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L13:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L47
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L44:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L44
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type: string
name: extract_symbolic_data
arguments: data_tag: D29
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D17: Enter size

tool: D29: %d

tool: D8: Average: %f


assistant: ```c
int main() {
  int size = 0;
  printf("Enter size\n");
  scanf("%d", &size);
  int *array = (int *)malloc(sizeof(int) * size);
  for (int i = 0; i < size; ++i)
    scanf("%d", (array + i));
  int sum = 0;
  for (int i = 0; i < size; ++i) {
    sum += *(array + i);
  }
  printf("Average: %f\n", (double)sum / (double)size);
  free(array);
  return 0;
}
```