ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_on_screen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %esi,%ebx
  movq   %xmm1,%r13
  mov    %edx,%r12d
  mov    %rdi,%rsi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%r12d
  je     L12
  lea    D4(%rip),%rdx
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L2:
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  movq   %r13,%xmm1
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D27(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_tag: D33
datatype: string
name: unpack_data
arguments: data_tag: D48
datatype: string
name: unpack_data
arguments: data_tag: D4
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D38
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string

tool: D33: 
	---------------%s----------------



tool: D48: 		NUM_OF_INTERVALS	 TIME_SEC	 gflops 

tool: D4: ---

tool: D7: 		%d			%lf 	%s	

tool: D38: 

	----------------------------------------------

tool: D27: 		%d		%f	 %lf	

assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\tNUM_OF_INTERVALS\t TIME_SEC\t gflops \n");
  if (flag == 1)
    printf("\t\t%d\t\t%f\t %lf\t", size, tsec, gflops);
  else
    printf("\t\t%d\t\t\t%lf \t%s\t", size, tsec, "---");
  printf("\n\n\t----------------------------------------------");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D58(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L2
  lea    D52(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
L18:
  add    $0x18,%rsp
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L2:
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: label: D58
type: string
name: parse_data
arguments: label: D33
type: string
name: parse_data
arguments: label: D52
type: string
name: parse_data
arguments: label: D38
type: string
name: parse_data
arguments: label: D41
type: string
name: parse_data
arguments: label: D2
type: string

tool: D58: 
	---------------%s----------------



tool: D33: 		NUM_OF_INTERVALS	 TIME_SEC	 gflops 

tool: D52: ---

tool: D38: 		%d			%lf 	%s	

tool: D41: 

	----------------------------------------------

tool: D2: 		%d		%f	 %lf	

assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\tNUM_OF_INTERVALS\t TIME_SEC\t gflops \n");
  if (flag == 1)
    printf("\t\t%d\t\t%f\t %lf\t", size, tsec, gflops);
  else
    printf("\t\t%d\t\t\t%lf \t%s\t", size, tsec, "---");
  printf("\n\n\t----------------------------------------------");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D18(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L2
  lea    D48(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
L5:
  add    $0x18,%rsp
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L2:
  mov    %ebp,%esi
  lea    D21(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: label: D18
type: string
name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D48
type: string
name: parse_data
arguments: label: D37
type: string
name: parse_data
arguments: label: D46
type: string
name: parse_data
arguments: label: D21
type: string

tool: D18: 
	---------------%s----------------



tool: D24: 		NUM_OF_INTERVALS	 TIME_SEC	 gflops 

tool: D48: ---

tool: D37: 		%d			%lf 	%s	

tool: D46: 

	----------------------------------------------

tool: D21: 		%d		%f	 %lf	

assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\tNUM_OF_INTERVALS\t TIME_SEC\t gflops \n");
  if (flag == 1)
    printf("\t\t%d\t\t%f\t %lf\t", size, tsec, gflops);
  else
    printf("\t\t%d\t\t\t%lf \t%s\t", size, tsec, "---");
  printf("\n\n\t----------------------------------------------");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bytes_ready>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int bytes_ready(int fd) {
  int n;
  (void)ioctl(fd, FIONREAD, &n);
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bytes_ready>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bytes_ready(int fd) {
  int n;
  (void)ioctl(fd, FIONREAD, &n);
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bytes_ready>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bytes_ready(int fd) {
  int n;
  (void)ioctl(fd, FIONREAD, &n);
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bytes_ready>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bytes_ready(int fd) {
  int n;
  (void)ioctl(fd, FIONREAD, &n);
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread_proc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <abort@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *thread_proc(void *arg) {
  abort();
  return arg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread_proc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <abort@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *thread_proc(void *arg) {
  abort();
  return arg;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<thread_proc>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *thread_proc(void *arg) {
  abort();
  return arg;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<thread_proc>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *thread_proc(void *arg) {
  abort();
  return arg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  lea    D8(%rip),%rdx
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <error@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string

tool: D8: 0.2, Nov 3, 2002

tool: D11: spicctrld %s

assistant: ```c
void version(void) {
  char *versionstr;
  asprintf(&versionstr, "spicctrld %s", "0.2, Nov 3, 2002");
  error(versionstr, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<version>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D11(%rip),%rdx
  lea    D2(%rip),%rsi
  call   <asprintf@plt>
  mov    $0x1,%esi
  mov    (%rsp),%rdi
  call   <error@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D2
data_type: string

tool: D11: 0.2, Nov 3, 2002

tool: D2: spicctrld %s

assistant: ```c
void version(void) {
  char *versionstr;
  asprintf(&versionstr, "spicctrld %s", "0.2, Nov 3, 2002");
  error(versionstr, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<version>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rsi
  lea    D2(%rip),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rdi
  mov    $0x1,%esi
  call   <error@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D13: spicctrld %s

tool: D2: 0.2, Nov 3, 2002

assistant: ```c
void version(void) {
  char *versionstr;
  asprintf(&versionstr, "spicctrld %s", "0.2, Nov 3, 2002");
  error(versionstr, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<version>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rsi
  lea    D10(%rip),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rdi
  mov    $0x1,%esi
  call   <error@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D10
type: string

tool: D13: spicctrld %s

tool: D10: 0.2, Nov 3, 2002

assistant: ```c
void version(void) {
  char *versionstr;
  asprintf(&versionstr, "spicctrld %s", "0.2, Nov 3, 2002");
  error(versionstr, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CSPL_Stats_percentile>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rdi,0x18(%rsp)
  movsd  %xmm0,0x8(%rsp)
  mov    %rsi,%rbx
  mov    $0x8,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  lea    0x1(%rbx),%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  lea    0x8(,%rbx,8),%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <CSPL_Sort_mergesort@plt>
  test   %rbx,%rbx
  jle    L36
  mov    %r13,%r14
  mov    $0x0,%ebp
  mov    %r12,%rax
  sub    %r13,%rax
  mov    %rax,0x10(%rsp)
L39:
  lea    0x0(,%rbp,8),%r15
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <CSPL_Stats_percent_rank@plt>
  movsd  %xmm0,(%r14)
  test   %rbp,%rbp
  jne    L56
  comisd 0x8(%rsp),%xmm0
  jbe    L56
  mov    (%r12,%r15,1),%r15
L101:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  movq   %r15,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  movsd  0x8(%rsp),%xmm4
  ucomisd %xmm4,%xmm0
  jp     L48
  je     L68
L48:
  comisd 0x8(%rsp),%xmm0
  ja     L91
  mov    0x10(%rsp),%rax
  mov    (%rax,%r14,1),%r15
  add    $0x1,%rbp
  add    $0x8,%r14
  cmp    %rbp,%rbx
  jne    L39
  jmp    L101
L68:
  mov    (%r12,%r15,1),%r15
  jmp    L101
L91:
  mov    0x18(%rsp),%rax
  movsd  -0x8(%rax,%r15,1),%xmm2
  movsd  0x8(%rsp),%xmm0
  subsd  -0x8(%r13,%r15,1),%xmm0
  divsd  D12(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rbx,%xmm1
  mulsd  %xmm1,%xmm0
  movsd  (%rax,%r15,1),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  movq   %xmm0,%r15
  jmp    L101
L36:
  mov    D13(%rip),%r15
  jmp    L101
```

tool_calls: name: unpack_data
arguments: tag: D12
type_guessed: f64
name: unpack_data
arguments: tag: D13
type_guessed: byte[8]

tool: D12: 100

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CSPL_Stats_percentile(double *inval, double percentile, long n) {
  long i;
  double *incopy;
  double *rank;
  double answer;
  rank = (double *)calloc(n, sizeof(double));
  {
    incopy = (double *)calloc((n) - (0) + 1, sizeof(double));
    memcpy((incopy), &(inval)[(0)], sizeof(double) * ((n) - (0) + 1));
  };
  CSPL_Sort_mergesort(incopy, n);
  for (i = 0; i < n; i++) {
    rank[i] = CSPL_Stats_percent_rank(i, n);
    if ((rank[i] > percentile) && (0 == i)) {
      answer = incopy[i];
      break;
    }
    if (rank[i] == percentile) {
      answer = incopy[i];
      break;
    } else if (rank[i] > percentile) {
      answer = inval[i - 1] + (n * ((percentile - rank[i - 1]) / 100.)) * (inval[i] - inval[i - 1]);
      break;
    }
    answer = incopy[i];
  }
  free(incopy);
  free(rank);
  return (answer);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CSPL_Stats_percentile>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x8,%esi
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %ebx,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <calloc@plt>
  lea    0x1(%rbx),%edi
  mov    $0x8,%esi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %r15,%rsi
  lea    0x8(,%rbx,8),%edx
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <CSPL_Sort_mergesort@plt>
  test   %rbx,%rbx
  jle    L26
  mov    %r14,%rax
  mov    %rbp,%r12
  xor    %r15d,%r15d
  sub    %rbp,%rax
  mov    %rax,0x10(%rsp)
L65:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  lea    0x0(,%r15,8),%r13
  call   <CSPL_Stats_percent_rank@plt>
  comisd 0x8(%rsp),%xmm0
  movsd  %xmm0,(%r12)
  jbe    L75
  test   %r15,%r15
  jne    L75
L48:
  movsd  (%r14,%r13,1),%xmm0
L58:
  mov    %r14,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  ucomisd 0x8(%rsp),%xmm0
  jp     L90
  je     L48
L90:
  comisd 0x8(%rsp),%xmm0
  ja     L10
  mov    0x10(%rsp),%rax
  add    $0x1,%r15
  movsd  (%rax,%r12,1),%xmm0
  add    $0x8,%r12
  cmp    %r15,%rbx
  jne    L65
  jmp    L58
L26:
  pxor   %xmm0,%xmm0
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L10:
  pxor   %xmm2,%xmm2
  mov    0x18(%rsp),%rax
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rbx,%xmm2
  subsd  -0x8(%rbp,%r13,1),%xmm1
  divsd  D2(%rip),%xmm1
  movsd  -0x8(%rax,%r13,1),%xmm0
  mulsd  %xmm2,%xmm1
  movsd  (%rax,%r13,1),%xmm2
  subsd  %xmm0,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  jmp    L58
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: f64

tool: D2: 100

assistant: ```c
double CSPL_Stats_percentile(double *inval, double percentile, long n) {
  long i;
  double *incopy;
  double *rank;
  double answer;
  rank = (double *)calloc(n, sizeof(double));
  {
    incopy = (double *)calloc((n) - (0) + 1, sizeof(double));
    memcpy((incopy), &(inval)[(0)], sizeof(double) * ((n) - (0) + 1));
  };
  CSPL_Sort_mergesort(incopy, n);
  for (i = 0; i < n; i++) {
    rank[i] = CSPL_Stats_percent_rank(i, n);
    if ((rank[i] > percentile) && (0 == i)) {
      answer = incopy[i];
      break;
    }
    if (rank[i] == percentile) {
      answer = incopy[i];
      break;
    } else if (rank[i] > percentile) {
      answer = inval[i - 1] + (n * ((percentile - rank[i - 1]) / 100.)) * (inval[i] - inval[i - 1]);
      break;
    }
    answer = incopy[i];
  }
  free(incopy);
  free(rank);
  return (answer);
}
```
user: What is the c source code of the assembly code below:

```asm
<CSPL_Stats_percentile>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x8,%esi
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %ebx,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <calloc@plt>
  lea    0x1(%rbx),%edi
  mov    $0x8,%esi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %r15,%rsi
  lea    0x8(,%rbx,8),%edx
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <CSPL_Sort_mergesort@plt>
  test   %rbx,%rbx
  jle    L38
  mov    %r14,%rax
  mov    %rbp,%r12
  xor    %r15d,%r15d
  sub    %rbp,%rax
  mov    %rax,0x10(%rsp)
L28:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  lea    0x0(,%r15,8),%r13
  call   <CSPL_Stats_percent_rank@plt>
  comisd 0x8(%rsp),%xmm0
  movsd  %xmm0,(%r12)
  jbe    L1
  test   %r15,%r15
  jne    L1
L8:
  movsd  (%r14,%r13,1),%xmm0
L77:
  mov    %r14,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  ucomisd 0x8(%rsp),%xmm0
  jp     L96
  je     L8
L96:
  comisd 0x8(%rsp),%xmm0
  ja     L14
  mov    0x10(%rsp),%rax
  add    $0x1,%r15
  movsd  (%rax,%r12,1),%xmm0
  add    $0x8,%r12
  cmp    %r15,%rbx
  jne    L28
  jmp    L77
L38:
  pxor   %xmm0,%xmm0
  jmp    L77
  cs nopw 0x0(%rax,%rax,1)
L14:
  pxor   %xmm2,%xmm2
  mov    0x18(%rsp),%rax
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rbx,%xmm2
  subsd  -0x8(%rbp,%r13,1),%xmm1
  divsd  D0(%rip),%xmm1
  movsd  -0x8(%rax,%r13,1),%xmm0
  mulsd  %xmm2,%xmm1
  movsd  (%rax,%r13,1),%xmm2
  subsd  %xmm0,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  jmp    L77
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: f64

tool: D0: 100

assistant: ```c
double CSPL_Stats_percentile(double *inval, double percentile, long n) {
  long i;
  double *incopy;
  double *rank;
  double answer;
  rank = (double *)calloc(n, sizeof(double));
  {
    incopy = (double *)calloc((n) - (0) + 1, sizeof(double));
    memcpy((incopy), &(inval)[(0)], sizeof(double) * ((n) - (0) + 1));
  };
  CSPL_Sort_mergesort(incopy, n);
  for (i = 0; i < n; i++) {
    rank[i] = CSPL_Stats_percent_rank(i, n);
    if ((rank[i] > percentile) && (0 == i)) {
      answer = incopy[i];
      break;
    }
    if (rank[i] == percentile) {
      answer = incopy[i];
      break;
    } else if (rank[i] > percentile) {
      answer = inval[i - 1] + (n * ((percentile - rank[i - 1]) / 100.)) * (inval[i] - inval[i - 1]);
      break;
    }
    answer = incopy[i];
  }
  free(incopy);
  free(rank);
  return (answer);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ppmM_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <ppmM_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ppmM_strdup(const char *string) {
  char *copy;
  size_t len = strlen(string);
  copy = ppmM_alloc(len + 1);
  strncpy(copy, string, len);
  copy[len] = '\0';
  return copy;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ppmM_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rax),%rdi
  call   <ppmM_alloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ppmM_strdup(const char *string) {
  char *copy;
  size_t len = strlen(string);
  copy = ppmM_alloc(len + 1);
  strncpy(copy, string, len);
  copy[len] = '\0';
  return copy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ppmM_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <ppmM_alloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ppmM_strdup(const char *string) {
  char *copy;
  size_t len = strlen(string);
  copy = ppmM_alloc(len + 1);
  strncpy(copy, string, len);
  copy[len] = '\0';
  return copy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ppmM_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <ppmM_alloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ppmM_strdup(const char *string) {
  char *copy;
  size_t len = strlen(string);
  copy = ppmM_alloc(len + 1);
  strncpy(copy, string, len);
  copy[len] = '\0';
  return copy;
}
```