ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_putextra>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  cmpb   $0x0,-0x14(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L40
L38:
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <ft_preformat@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L9
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L9
  mov    $0x1,%ecx
  jmp    L7
L9:
  mov    $0x0,%ecx
L7:
  mov    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_postformat2@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L40:
  leave
  ret
```

assistant: ```c
int ft_putextra(char c, int fl[8]) {
  int ret;
  if (c == '\0')
    return (0);
  ret = 0;
  ret += ft_preformat(fl, 1);
  ret += ft_putchar(c);
  ret += ft_postformat2(fl, 1 - (fl[5] && !fl[2]));
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_putextra>:
  endbr64
  mov    $0x0,%eax
  test   %dil,%dil
  jne    L10
  ret
L10:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <ft_preformat@plt>
  mov    %rax,%rbp
  movsbl %bl,%edi
  call   <ft_putchar@plt>
  add    %eax,%ebp
  mov    0x14(%r12),%eax
  test   %eax,%eax
  je     L18
  cmpl   $0x0,0x8(%r12)
  sete   %al
  movzbl %al,%eax
L18:
  mov    $0x1,%esi
  sub    %eax,%esi
  mov    %r12,%rdi
  call   <ft_postformat2@plt>
  add    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ft_putextra(char c, int fl[8]) {
  int ret;
  if (c == '\0')
    return (0);
  ret = 0;
  ret += ft_preformat(fl, 1);
  ret += ft_putchar(c);
  ret += ft_postformat2(fl, 1 - (fl[5] && !fl[2]));
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putextra>:
  endbr64
  test   %dil,%dil
  jne    L13
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L13:
  push   %r12
  mov    %rsi,%r12
  mov    $0x1,%esi
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %r12,%rdi
  call   <ft_preformat@plt>
  movsbl %bl,%edi
  mov    %rax,%rbp
  call   <ft_putchar@plt>
  mov    0x14(%r12),%edx
  mov    $0x1,%esi
  add    %eax,%ebp
  test   %edx,%edx
  je     L12
  mov    0x8(%r12),%eax
  xor    %esi,%esi
  test   %eax,%eax
  setne  %sil
L12:
  mov    %r12,%rdi
  call   <ft_postformat2@plt>
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ft_putextra(char c, int fl[8]) {
  int ret;
  if (c == '\0')
    return (0);
  ret = 0;
  ret += ft_preformat(fl, 1);
  ret += ft_putchar(c);
  ret += ft_postformat2(fl, 1 - (fl[5] && !fl[2]));
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_putextra>:
  endbr64
  test   %dil,%dil
  jne    L18
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L18:
  push   %r12
  mov    %rsi,%r12
  mov    $0x1,%esi
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %r12,%rdi
  call   <ft_preformat@plt>
  movsbl %bl,%edi
  mov    %rax,%rbp
  call   <ft_putchar@plt>
  mov    0x14(%r12),%edx
  mov    $0x1,%esi
  add    %eax,%ebp
  test   %edx,%edx
  je     L17
  mov    0x8(%r12),%eax
  xor    %esi,%esi
  test   %eax,%eax
  setne  %sil
L17:
  mov    %r12,%rdi
  call   <ft_postformat2@plt>
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ft_putextra(char c, int fl[8]) {
  int ret;
  if (c == '\0')
    return (0);
  ret = 0;
  ret += ft_preformat(fl, 1);
  ret += ft_putchar(c);
  ret += ft_postformat2(fl, 1 - (fl[5] && !fl[2]));
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<procfs_enum_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1000,-0x14(%rbp)
  mov    $0x4000,%edi
  call   <zalloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L55
  mov    $0xffffffff,%eax
  jmp    L21
L55:
  lea    -0x14(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <procfs_walk@plt>
  test   %rax,%rax
  je     L56
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  je     L18
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L18:
  mov    $0xffffffff,%eax
  jmp    L21
L56:
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

assistant: ```c
int procfs_enum_id(char *path, int **id_arr, int *nids) {
  int *ids, num = 4096;
  if ((ids = zalloc(4096 * sizeof(int))) == NULL) {
    return (-1);
  }
  if (procfs_walk(path, &ids, &num) != 0) {
    if (ids != NULL) {
      free(ids);
    }
    return (-1);
  }
  *id_arr = ids;
  *nids = num;
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<procfs_enum_id>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1000,0xc(%rsp)
  mov    $0x4000,%edi
  call   <zalloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L18
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <procfs_walk@plt>
  test   %rax,%rax
  jne    L11
  mov    0x10(%rsp),%rax
  mov    %rax,(%r12)
  mov    0xc(%rsp),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
L34:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    0x10(%rsp),%rdi
  mov    $0xffffffff,%eax
  test   %rdi,%rdi
  je     L34
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L34
L18:
  mov    $0xffffffff,%eax
  jmp    L34
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int procfs_enum_id(char *path, int **id_arr, int *nids) {
  int *ids, num = 4096;
  if ((ids = zalloc(4096 * sizeof(int))) == NULL) {
    return (-1);
  }
  if (procfs_walk(path, &ids, &num) != 0) {
    if (ids != NULL) {
      free(ids);
    }
    return (-1);
  }
  *id_arr = ids;
  *nids = num;
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<procfs_enum_id>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4000,%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1000,0xc(%rsp)
  call   <zalloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L28
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <procfs_walk@plt>
  test   %rax,%rax
  jne    L46
  mov    0x10(%rsp),%rax
  mov    %rax,(%r12)
  mov    0xc(%rsp),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
L20:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    0x10(%rsp),%rdi
  test   %rdi,%rdi
  je     L28
  call   <free@plt>
L28:
  mov    $0xffffffff,%eax
  jmp    L20
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int procfs_enum_id(char *path, int **id_arr, int *nids) {
  int *ids, num = 4096;
  if ((ids = zalloc(4096 * sizeof(int))) == NULL) {
    return (-1);
  }
  if (procfs_walk(path, &ids, &num) != 0) {
    if (ids != NULL) {
      free(ids);
    }
    return (-1);
  }
  *id_arr = ids;
  *nids = num;
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<procfs_enum_id>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4000,%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1000,0xc(%rsp)
  call   <zalloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L42
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <procfs_walk@plt>
  test   %rax,%rax
  jne    L46
  mov    0x10(%rsp),%rax
  mov    %rax,(%r12)
  mov    0xc(%rsp),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
L25:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    0x10(%rsp),%rdi
  test   %rdi,%rdi
  je     L42
  call   <free@plt>
L42:
  mov    $0xffffffff,%eax
  jmp    L25
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int procfs_enum_id(char *path, int **id_arr, int *nids) {
  int *ids, num = 4096;
  if ((ids = zalloc(4096 * sizeof(int))) == NULL) {
    return (-1);
  }
  if (procfs_walk(path, &ids, &num) != 0) {
    if (ids != NULL) {
      free(ids);
    }
    return (-1);
  }
  *id_arr = ids;
  *nids = num;
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,-0x14(%rbp)
  movl   $0x3e8,-0x18(%rbp)
  jmp    L13
L22:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <first_two@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <last_two@plt>
  lea    (%rbx,%rax,1),%rdx
  mov    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <divisible@plt>
  test   %rax,%rax
  je     L18
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L18:
  addl   $0x1,-0x18(%rbp)
L13:
  cmpl   $0x270f,-0x18(%rbp)
  jle    L22
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string
name: read_data
arguments: label: D5
type_guessed: string

tool: D2: %d


tool: D5: Total: %d


assistant: ```c
int main() {
  int i;
  int count = 0;
  for (i = 1000; i <= 9999; ++i) {
    if (divisible(i, first_two(i) + last_two(i))) {
      printf("%d\n", i);
      ++count;
    }
  }
  printf("Total: %d\n", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  mov    $0x3e8,%ebx
  lea    D0(%rip),%r13
  jmp    L9
L31:
  add    $0x1,%ebx
  cmp    $0x2710,%ebx
  je     L6
L9:
  mov    %ebx,%edi
  call   <first_two@plt>
  mov    %rax,%rbp
  mov    %ebx,%edi
  call   <last_two@plt>
  lea    0x0(%rbp,%rax,1),%rsi
  mov    %ebx,%edi
  call   <divisible@plt>
  test   %rax,%rax
  je     L31
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  jmp    L31
L6:
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D0: %d


tool: D9: Total: %d


assistant: ```c
int main() {
  int i;
  int count = 0;
  for (i = 1000; i <= 9999; ++i) {
    if (divisible(i, first_two(i) + last_two(i))) {
      printf("%d\n", i);
      ++count;
    }
  }
  printf("Total: %d\n", count);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x8,%rsp
  jmp    L22
  nop
L32:
  add    $0x1,%ebx
  cmp    $0x2710,%ebx
  je     L26
L22:
  mov    %ebx,%edi
  call   <first_two@plt>
  mov    %ebx,%edi
  mov    %rax,%rbp
  call   <last_two@plt>
  mov    %ebx,%edi
  lea    0x0(%rbp,%rax,1),%rsi
  call   <divisible@plt>
  test   %rax,%rax
  je     L32
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    $0x2710,%ebx
  jne    L22
L26:
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D6: %d


tool: D1: Total: %d


assistant: ```c
int main() {
  int i;
  int count = 0;
  for (i = 1000; i <= 9999; ++i) {
    if (divisible(i, first_two(i) + last_two(i))) {
      printf("%d\n", i);
      ++count;
    }
  }
  printf("Total: %d\n", count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x8,%rsp
  jmp    L5
  nop
L14:
  add    $0x1,%ebx
  cmp    $0x2710,%ebx
  je     L16
L5:
  mov    %ebx,%edi
  call   <first_two@plt>
  mov    %ebx,%edi
  mov    %rax,%rbp
  call   <last_two@plt>
  mov    %ebx,%edi
  lea    0x0(%rbp,%rax,1),%rsi
  call   <divisible@plt>
  test   %rax,%rax
  je     L14
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    $0x2710,%ebx
  jne    L5
L16:
  mov    %r12d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type: string
name: unpack_data
arguments: tag: D5
type: string

tool: D6: %d


tool: D5: Total: %d


assistant: ```c
int main() {
  int i;
  int count = 0;
  for (i = 1000; i <= 9999; ++i) {
    if (divisible(i, first_two(i) + last_two(i))) {
      printf("%d\n", i);
      ++count;
    }
  }
  printf("Total: %d\n", count);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GPIOGatingRatioConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x130,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x130,%edx
  mov    %edx,%edx
  and    $0xfffffff9,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0x130,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  and    $0x6,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  add    $0x130,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  or     %esi,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void GPIOGatingRatioConfigure(unsigned int baseAdd, unsigned int configFlag) {
  (*((volatile unsigned int *)(baseAdd + (0x130)))) &= ~((0x00000006u));
  (*((volatile unsigned int *)(baseAdd + (0x130)))) |= (configFlag & (0x00000006u));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GPIOGatingRatioConfigure>:
  endbr64
  mov    0x130(%edi),%eax
  and    $0xfffffff9,%eax
  mov    %eax,0x130(%edi)
  mov    0x130(%edi),%eax
  and    $0x6,%esi
  or     %eax,%esi
  mov    %esi,0x130(%edi)
  ret
```

assistant: ```c
void GPIOGatingRatioConfigure(unsigned int baseAdd, unsigned int configFlag) {
  (*((volatile unsigned int *)(baseAdd + (0x130)))) &= ~((0x00000006u));
  (*((volatile unsigned int *)(baseAdd + (0x130)))) |= (configFlag & (0x00000006u));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GPIOGatingRatioConfigure>:
  endbr64
  mov    0x130(%edi),%eax
  and    $0x6,%esi
  and    $0xfffffff9,%eax
  mov    %eax,0x130(%edi)
  mov    0x130(%edi),%eax
  or     %eax,%esi
  mov    %esi,0x130(%edi)
  ret
```

assistant: ```c
void GPIOGatingRatioConfigure(unsigned int baseAdd, unsigned int configFlag) {
  (*((volatile unsigned int *)(baseAdd + (0x130)))) &= ~((0x00000006u));
  (*((volatile unsigned int *)(baseAdd + (0x130)))) |= (configFlag & (0x00000006u));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GPIOGatingRatioConfigure>:
  endbr64
  mov    0x130(%edi),%eax
  and    $0x6,%esi
  and    $0xfffffff9,%eax
  mov    %eax,0x130(%edi)
  mov    0x130(%edi),%eax
  or     %eax,%esi
  mov    %esi,0x130(%edi)
  ret
```

assistant: ```c
void GPIOGatingRatioConfigure(unsigned int baseAdd, unsigned int configFlag) {
  (*((volatile unsigned int *)(baseAdd + (0x130)))) &= ~((0x00000006u));
  (*((volatile unsigned int *)(baseAdd + (0x130)))) |= (configFlag & (0x00000006u));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nexttoken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
L2:
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *nexttoken(const char *q, int sep) {
  if (q)
    q = strchr(q, sep);
  if (q)
    q++;
  return q;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nexttoken>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <strchr@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rax
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
const char *nexttoken(const char *q, int sep) {
  if (q)
    q = strchr(q, sep);
  if (q)
    q++;
  return q;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nexttoken>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <strchr@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rax
  add    $0x8,%rsp
  ret
  nop
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *nexttoken(const char *q, int sep) {
  if (q)
    q = strchr(q, sep);
  if (q)
    q++;
  return q;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nexttoken>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <strchr@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rax
  add    $0x8,%rsp
  ret
  nop
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *nexttoken(const char *q, int sep) {
  if (q)
    q = strchr(q, sep);
  if (q)
    q++;
  return q;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_one_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  jne    L52
  mov    -0x34(%rbp),%eax
  jmp    L34
L52:
  cmpq   $0x0,-0x28(%rbp)
  jne    L28
  mov    -0x38(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  sub    -0x38(%rbp),%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  jmp    L34
L28:
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x30(%rbp)
  mov    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%eax
  cltd
  shr    $0x13,%edx
  add    %edx,%eax
  and    $0x1fff,%eax
  sub    %edx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  js     L33
  addq   $0x1000,-0x10(%rbp)
  jmp    L19
L33:
  subq   $0x1000,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  lea    0x1fff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0xd,%rax
  mov    %eax,%ecx
  mov    -0x38(%rbp),%eax
  lea    0x1fff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xd,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  imul   %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
L34:
  leave
  ret
```

assistant: ```c
uint32_t get_one_value(int16_t *dist_table, size_t dist_size, uint32_t mu, uint32_t sigma) {
  long x;
  long t;
  int32_t rnd;
  if (sigma == 0)
    return mu;
  if (dist_table == NULL) {
    return (rnd % (2 * sigma)) - sigma + mu;
  }
  rnd = random();
  t = dist_table[rnd % dist_size];
  x = t * (sigma % 8192);
  if (x >= 0)
    x += 8192 / 2;
  else
    x -= 8192 / 2;
  return x / 8192 + (sigma / 8192) * t + mu;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_one_value>:
  endbr64
  mov    %edx,%eax
  test   %ecx,%ecx
  je     L15
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %ecx,%ebp
  sub    %ecx,%eax
  test   %rdi,%rdi
  je     L11
  mov    $0x0,%eax
  call   <random@plt>
  cltq
  mov    $0x0,%edx
  div    %r13
  mov    (%r12,%rdx,8),%rsi
  mov    %ebp,%edx
  sar    $0x1f,%edx
  shr    $0x13,%edx
  lea    0x0(%rbp,%rdx,1),%eax
  and    $0x1fff,%eax
  sub    %edx,%eax
  cltq
  imul   %rsi,%rax
  lea    0x1000(%rax),%rdx
  lea    -0x1000(%rax),%rcx
  test   %rax,%rax
  cmovns %rdx,%rcx
  lea    0x1fff(%rbp),%eax
  test   %ebp,%ebp
  cmovns %ebp,%eax
  sar    $0xd,%eax
  imul   %esi,%eax
  add    %ebx,%eax
  lea    0x1fff(%rcx),%rdx
  test   %rcx,%rcx
  cmovns %rcx,%rdx
  sar    $0xd,%rdx
  add    %edx,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  ret
```

assistant: ```c
uint32_t get_one_value(int16_t *dist_table, size_t dist_size, uint32_t mu, uint32_t sigma) {
  long x;
  long t;
  int32_t rnd;
  if (sigma == 0)
    return mu;
  if (dist_table == NULL) {
    return (rnd % (2 * sigma)) - sigma + mu;
  }
  rnd = random();
  t = dist_table[rnd % dist_size];
  x = t * (sigma % 8192);
  if (x >= 0)
    x += 8192 / 2;
  else
    x -= 8192 / 2;
  return x / 8192 + (sigma / 8192) * t + mu;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_one_value>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  je     L1
  mov    %rdi,%rbp
  mov    %ecx,%ebx
  test   %rdi,%rdi
  je     L11
  xor    %eax,%eax
  mov    %rsi,%r13
  call   <random@plt>
  xor    %edx,%edx
  cltq
  div    %r13
  mov    0x0(%rbp,%rdx,8),%rcx
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x13,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0x1fff,%eax
  sub    %edx,%eax
  cltq
  imul   %rcx,%rax
  test   %rax,%rax
  lea    0x1000(%rax),%rsi
  lea    -0x1000(%rax),%rdx
  cmovns %rsi,%rdx
  lea    0x1fff(%rbx),%eax
  test   %ebx,%ebx
  cmovns %ebx,%eax
  sar    $0xd,%eax
  imul   %ecx,%eax
  add    %r12d,%eax
  test   %rdx,%rdx
  lea    0x1fff(%rdx),%r12
  cmovns %rdx,%r12
  sar    $0xd,%r12
  add    %eax,%r12d
L1:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L11:
  add    $0x8,%rsp
  sub    %ecx,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t get_one_value(int16_t *dist_table, size_t dist_size, uint32_t mu, uint32_t sigma) {
  long x;
  long t;
  int32_t rnd;
  if (sigma == 0)
    return mu;
  if (dist_table == NULL) {
    return (rnd % (2 * sigma)) - sigma + mu;
  }
  rnd = random();
  t = dist_table[rnd % dist_size];
  x = t * (sigma % 8192);
  if (x >= 0)
    x += 8192 / 2;
  else
    x -= 8192 / 2;
  return x / 8192 + (sigma / 8192) * t + mu;
}
```