ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Util_normalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <Util_in_range@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  subsd  -0x30(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void Util_normalize(double *set, const int n, const double upper, const double min, const double max) {
  int i;
  for (i = 0; i < n; i++) {
    assert(Util_in_range(min, max, set[i]));
    set[i] = upper * ((set[i] - min) / (max - min));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Util_normalize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  test   %esi,%esi
  jle    L15
  movq   %xmm2,%rbp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
L5:
  movsd  (%rbx),%xmm2
  movq   %rbp,%xmm1
  movsd  (%rsp),%xmm0
  call   <Util_in_range@plt>
  mov    %eax,%edi
  call   <assert@plt>
  movsd  (%rbx),%xmm0
  movsd  (%rsp),%xmm3
  subsd  %xmm3,%xmm0
  movq   %rbp,%xmm1
  subsd  %xmm3,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L5
L15:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Util_normalize(double *set, const int n, const double upper, const double min, const double max) {
  int i;
  for (i = 0; i < n; i++) {
    assert(Util_in_range(min, max, set[i]));
    set[i] = upper * ((set[i] - min) / (max - min));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Util_normalize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  test   %esi,%esi
  jle    L12
  movapd %xmm1,%xmm3
  movapd %xmm2,%xmm6
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  subsd  %xmm3,%xmm6
  movapd %xmm2,%xmm1
  lea    0x8(%rdi,%rax,8),%rbp
  movsd  %xmm6,0x18(%rsp)
  nopl   (%rax)
L15:
  movsd  (%rbx),%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  movsd  %xmm3,(%rsp)
  call   <Util_in_range@plt>
  mov    %eax,%edi
  call   <assert@plt>
  movsd  -0x8(%rbx),%xmm0
  movsd  (%rsp),%xmm3
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm3,%xmm0
  divsd  0x18(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L15
L12:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Util_normalize(double *set, const int n, const double upper, const double min, const double max) {
  int i;
  for (i = 0; i < n; i++) {
    assert(Util_in_range(min, max, set[i]));
    set[i] = upper * ((set[i] - min) / (max - min));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Util_normalize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  test   %esi,%esi
  jle    L9
  movapd %xmm1,%xmm3
  movapd %xmm2,%xmm6
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  subsd  %xmm3,%xmm6
  movapd %xmm2,%xmm1
  lea    0x8(%rdi,%rax,8),%rbp
  movsd  %xmm6,0x18(%rsp)
  nopl   (%rax)
L11:
  movsd  (%rbx),%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  movsd  %xmm3,(%rsp)
  call   <Util_in_range@plt>
  mov    %eax,%edi
  call   <assert@plt>
  movsd  -0x8(%rbx),%xmm0
  movsd  (%rsp),%xmm3
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm3,%xmm0
  divsd  0x18(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L11
L9:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Util_normalize(double *set, const int n, const double upper, const double min, const double max) {
  int i;
  for (i = 0; i < n; i++) {
    assert(Util_in_range(min, max, set[i]));
    set[i] = upper * ((set[i] - min) / (max - min));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<timer_tvafter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rcx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  lea    (%rcx,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x3e8,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  add    %ecx,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L15
L2:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    -0xf4240(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xf4240,%eax
  jg     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void timer_tvafter(struct timeval *tv, int msec) {
  tv->tv_sec += msec / 1000;
  tv->tv_usec += msec % 1000;
  while (tv->tv_usec > ((1) * 1000 * 1000)) {
    tv->tv_usec -= ((1) * 1000 * 1000);
    tv->tv_sec++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<timer_tvafter>:
  endbr64
  mov    %rdi,%rcx
  movslq %esi,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  movslq %edx,%rax
  add    0x8(%rdi),%rax
  mov    %rax,0x8(%rdi)
  imul   $0x3e8,%edx,%edx
  sub    %edx,%esi
  add    (%rdi),%esi
  mov    %esi,(%rdi)
  cmp    $0xf4240,%esi
  jle    L16
  add    $0x1,%rax
L4:
  sub    $0xf4240,%esi
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    $0xf4240,%esi
  jg     L4
  mov    %esi,(%rcx)
  mov    %rdx,0x8(%rcx)
L16:
  ret
```

assistant: ```c
void timer_tvafter(struct timeval *tv, int msec) {
  tv->tv_sec += msec / 1000;
  tv->tv_usec += msec % 1000;
  while (tv->tv_usec > ((1) * 1000 * 1000)) {
    tv->tv_usec -= ((1) * 1000 * 1000);
    tv->tv_sec++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timer_tvafter>:
  endbr64
  movslq %esi,%rdx
  mov    %esi,%eax
  mov    %rdi,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x26,%rdx
  sub    %eax,%edx
  movslq %edx,%rax
  imul   $0x3e8,%edx,%edx
  add    0x8(%rdi),%rax
  mov    %rax,0x8(%rdi)
  sub    %edx,%esi
  add    (%rdi),%esi
  mov    %esi,(%rdi)
  cmp    $0xf4240,%esi
  jle    L1
  add    $0x1,%rax
  nop
L4:
  sub    $0xf4240,%esi
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    $0xf4240,%esi
  jg     L4
  mov    %esi,(%rcx)
  mov    %rdx,0x8(%rcx)
L1:
  ret
```

assistant: ```c
void timer_tvafter(struct timeval *tv, int msec) {
  tv->tv_sec += msec / 1000;
  tv->tv_usec += msec % 1000;
  while (tv->tv_usec > ((1) * 1000 * 1000)) {
    tv->tv_usec -= ((1) * 1000 * 1000);
    tv->tv_sec++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timer_tvafter>:
  endbr64
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rdi,%rcx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  movslq %eax,%r8
  imul   $0x3e8,%eax,%eax
  add    0x8(%rdi),%r8
  mov    %r8,0x8(%rdi)
  sub    %eax,%esi
  add    (%rdi),%esi
  mov    %esi,(%rdi)
  cmp    $0xf4240,%esi
  jle    L29
  lea    -0xf4241(%rsi),%edi
  mov    %rdi,%rax
  imul   $0x431bde83,%rdi,%rdi
  shr    $0x32,%rdi
  add    $0x1,%edi
  cmp    $0x5b8d7f,%eax
  jbe    L75
  lea    0x1(%r8),%rax
  movd   %esi,%xmm4
  movq   %r8,%xmm3
  mov    %edi,%edx
  movq   %rax,%xmm5
  pshufd $0x0,%xmm4,%xmm2
  shr    $0x2,%edx
  xor    %eax,%eax
  punpcklqdq %xmm5,%xmm3
  paddd  D19(%rip),%xmm2
  movdqa D31(%rip),%xmm7
  movdqa D42(%rip),%xmm6
  movdqa D28(%rip),%xmm5
  movdqa D39(%rip),%xmm4
  nopl   0x0(%rax,%rax,1)
L51:
  movdqa %xmm3,%xmm1
  movdqa %xmm2,%xmm0
  paddq  %xmm7,%xmm3
  add    $0x1,%eax
  paddd  %xmm6,%xmm2
  paddd  %xmm5,%xmm0
  paddq  %xmm4,%xmm1
  cmp    %edx,%eax
  jne    L51
  mov    %edi,%r9d
  movhlps %xmm1,%xmm6
  pshufd $0xff,%xmm0,%xmm0
  and    $0xfffffffc,%r9d
  movq   %xmm6,%rdx
  movd   %xmm0,%eax
  imul   $0xfff0bdc0,%r9d,%r10d
  add    %r10d,%esi
  mov    %r9d,%r10d
  add    %r10,%r8
  cmp    %r9d,%edi
  je     L43
L75:
  lea    -0xf4240(%rsi),%eax
  lea    0x1(%r8),%rdx
  cmp    $0xf4240,%eax
  jle    L43
  lea    -0x1e8480(%rsi),%eax
  lea    0x2(%r8),%rdx
  cmp    $0xf4240,%eax
  jle    L43
  lea    -0x2dc6c0(%rsi),%eax
  lea    0x3(%r8),%rdx
  cmp    $0xf4240,%eax
  jle    L43
  lea    -0x3d0900(%rsi),%eax
  lea    0x4(%r8),%rdx
  cmp    $0xf4240,%eax
  jle    L43
  lea    -0x4c4b40(%rsi),%eax
  lea    0x5(%r8),%rdx
  cmp    $0xf4240,%eax
  jle    L43
  lea    -0x5b8d80(%rsi),%eax
  lea    0x6(%r8),%rdx
L43:
  mov    %eax,(%rcx)
  mov    %rdx,0x8(%rcx)
L29:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
datatype: byte[16]
name: parse_data
arguments: data_label: D31
datatype: byte[16]
name: parse_data
arguments: data_label: D42
datatype: byte[16]
name: parse_data
arguments: data_label: D28
datatype: byte[16]
name: parse_data
arguments: data_label: D39
datatype: byte[16]

tool: {"D19": [0x00,0x00,0x00,0x00,0xc0,0xbd,0xf0,0xff,0x80,0x7b,0xe1,0xff,0x40,0x39,0xd2,0xff]}

tool: {"D31": [0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D42": [0x00,0xf7,0xc2,0xff,0x00,0xf7,0xc2,0xff,0x00,0xf7,0xc2,0xff,0x00,0xf7,0xc2,0xff]}

tool: {"D28": [0xc0,0xbd,0xf0,0xff,0xc0,0xbd,0xf0,0xff,0xc0,0xbd,0xf0,0xff,0xc0,0xbd,0xf0,0xff]}

tool: {"D39": [0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void timer_tvafter(struct timeval *tv, int msec) {
  tv->tv_sec += msec / 1000;
  tv->tv_usec += msec % 1000;
  while (tv->tv_usec > ((1) * 1000 * 1000)) {
    tv->tv_usec -= ((1) * 1000 * 1000);
    tv->tv_sec++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vga_set_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x3ce,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x3cf,%esi
  mov    %eax,%edi
  call   <outb@plt>
  nop
  leave
  ret
```

assistant: ```c
void vga_set_reset(int mask) {
  outb(0x00, 0x3ce);
  outb(mask, 0x3cf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vga_set_reset>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3ce,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x3cf,%esi
  mov    %ebx,%edi
  call   <outb@plt>
  pop    %rbx
  ret
```

assistant: ```c
void vga_set_reset(int mask) {
  outb(0x00, 0x3ce);
  outb(mask, 0x3cf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vga_set_reset>:
  endbr64
  push   %rbp
  mov    $0x3ce,%esi
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <outb@plt>
  mov    %ebp,%edi
  mov    $0x3cf,%esi
  pop    %rbp
  jmp    1050 <outb@plt>
```

assistant: ```c
void vga_set_reset(int mask) {
  outb(0x00, 0x3ce);
  outb(mask, 0x3cf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vga_set_reset>:
  endbr64
  push   %rbp
  mov    $0x3ce,%esi
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <outb@plt>
  mov    %ebp,%edi
  mov    $0x3cf,%esi
  pop    %rbp
  jmp    1050 <outb@plt>
```

assistant: ```c
void vga_set_reset(int mask) {
  outb(0x00, 0x3ce);
  outb(mask, 0x3cf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_even>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L10
  mov    $0x1,%eax
  jmp    L13
L10:
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
bool is_even(int number) {
  int remainder = number % 2;
  if (remainder == 0) {
    return true;
  }
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_even>:
  endbr64
  mov    %edi,%eax
  xor    $0x1,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool is_even(int number) {
  int remainder = number % 2;
  if (remainder == 0) {
    return true;
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_even>:
  endbr64
  mov    %edi,%eax
  not    %eax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool is_even(int number) {
  int remainder = number % 2;
  if (remainder == 0) {
    return true;
  }
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_even>:
  endbr64
  mov    %edi,%eax
  not    %eax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool is_even(int number) {
  int remainder = number % 2;
  if (remainder == 0) {
    return true;
  }
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<size_of_2d_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L15:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L15
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int size_of_2d_array(char **array) {
  int result;
  result = 0;
  while (array[result])
    result++;
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<size_of_2d_array>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L21
  mov    $0x1,%eax
L6:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L6
L20:
  mov    %edx,%eax
  ret
L21:
  mov    $0x0,%edx
  jmp    L20
```

assistant: ```c
int size_of_2d_array(char **array) {
  int result;
  result = 0;
  while (array[result])
    result++;
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<size_of_2d_array>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L14
  mov    $0x1,%eax
  nop
L12:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int size_of_2d_array(char **array) {
  int result;
  result = 0;
  while (array[result])
    result++;
  return (result);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<size_of_2d_array>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L14
  mov    $0x1,%eax
  nop
L6:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L6
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int size_of_2d_array(char **array) {
  int result;
  result = 0;
  while (array[result])
    result++;
  return (result);
}
```
user: What is the c source code of the assembly code below:

```asm
<findMedianSortedArrays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L18
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  sar    %eax
  lea    0x1(%rax),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getkth@plt>
  movq   %xmm0,%rax
  jmp    L6
L18:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getkth@plt>
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  sar    %eax
  lea    0x1(%rax),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getkth@plt>
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D8(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
L6:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: f64

tool: D8: 2

assistant: ```c
double findMedianSortedArrays(int *a, int n, int *b, int m) {
  if ((n + m) & 0x1) {
    return getkth(a, n, b, m, ((n + m) >> 1) + 1);
  }
  int left = getkth(a, n, b, m, (n + m) >> 1);
  int right = getkth(a, n, b, m, ((n + m) >> 1) + 1);
  return (left + right) / 2.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<findMedianSortedArrays>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %rdx,%r14
  mov    %ecx,%ebp
  lea    (%rsi,%rcx,1),%r8d
  test   $0x1,%r8b
  jne    L1
  sar    %r8d
  mov    %r8d,%r12d
  call   <getkth@plt>
  movsd  %xmm0,0x8(%rsp)
  lea    0x1(%r12),%r8d
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <getkth@plt>
  cvttsd2si 0x8(%rsp),%eax
  cvttsd2si %xmm0,%edx
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D7(%rip),%xmm0
L17:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  sar    %r8d
  add    $0x1,%r8d
  call   <getkth@plt>
  jmp    L17
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *a, int n, int *b, int m) {
  if ((n + m) & 0x1) {
    return getkth(a, n, b, m, ((n + m) >> 1) + 1);
  }
  int left = getkth(a, n, b, m, (n + m) >> 1);
  int right = getkth(a, n, b, m, ((n + m) >> 1) + 1);
  return (left + right) / 2.0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<findMedianSortedArrays>:
  endbr64
  push   %r14
  lea    (%rsi,%rcx,1),%eax
  mov    %rdx,%r14
  push   %r13
  mov    %eax,%r8d
  mov    %rdi,%r13
  push   %r12
  sar    %r8d
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0x1(%r8),%ebx
  sub    $0x10,%rsp
  test   $0x1,%al
  jne    L0
  call   <getkth@plt>
  mov    %r14,%rdx
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%esi
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <getkth@plt>
  movsd  0x8(%rsp),%xmm1
  cvttsd2si %xmm0,%edx
  pxor   %xmm0,%xmm0
  cvttsd2si %xmm1,%eax
  add    %edx,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D6(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x10,%rsp
  mov    %ebx,%r8d
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <getkth@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *a, int n, int *b, int m) {
  if ((n + m) & 0x1) {
    return getkth(a, n, b, m, ((n + m) >> 1) + 1);
  }
  int left = getkth(a, n, b, m, (n + m) >> 1);
  int right = getkth(a, n, b, m, ((n + m) >> 1) + 1);
  return (left + right) / 2.0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findMedianSortedArrays>:
  endbr64
  push   %r14
  lea    (%rsi,%rcx,1),%eax
  mov    %rdx,%r14
  push   %r13
  mov    %eax,%r8d
  mov    %rdi,%r13
  push   %r12
  sar    %r8d
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0x1(%r8),%ebx
  sub    $0x10,%rsp
  test   $0x1,%al
  jne    L9
  call   <getkth@plt>
  mov    %r14,%rdx
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%esi
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <getkth@plt>
  movsd  0x8(%rsp),%xmm1
  cvttsd2si %xmm0,%edx
  pxor   %xmm0,%xmm0
  cvttsd2si %xmm1,%eax
  add    %edx,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D9(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x10,%rsp
  mov    %ebx,%r8d
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <getkth@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *a, int n, int *b, int m) {
  if ((n + m) & 0x1) {
    return getkth(a, n, b, m, ((n + m) >> 1) + 1);
  }
  int left = getkth(a, n, b, m, (n + m) >> 1);
  int right = getkth(a, n, b, m, ((n + m) >> 1) + 1);
  return (left + right) / 2.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x48(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x4c(%rbp),%rcx
  lea    -0x50(%rbp),%rdx
  lea    -0x54(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x4c(%rbp),%eax
  sub    $0x76c,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x50(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0xffffffff,-0x24(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %eax,-0x44(%rbp)
  cmpl   $0xffffffff,-0x44(%rbp)
  jne    L27
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L29
L27:
  mov    -0x44(%rbp),%edx
  mov    -0x48(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rcx
  movabs $0x883148f5cb1270b9,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x18,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,-0x40(%rbp)
  mov    -0x40(%rbp),%eax
  add    $0xa,%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string
name: disassemble_data
arguments: label: D6
data_type: string

tool: D14: Enter birth year in format (day.month.year): 

tool: D0: %d.%d.%d

tool: D15: Error getting time.

tool: D6: Now: %d
After 10 years: %d

assistant: ```c
int main() {
  int day, month, year;
  struct tm time_struct;
  time_t time1, time2;
  time1 = time(NULL);
  printf("Enter birth year in format (day.month.year): ");
  scanf("%d.%d.%d", &day, &month, &year);
  time_struct.tm_year = year - 1900;
  time_struct.tm_mon = month - 1;
  time_struct.tm_mday = day;
  time_struct.tm_sec = 0;
  time_struct.tm_min = 0;
  time_struct.tm_hour = 0;
  time_struct.tm_isdst = -1;
  time2 = mktime(&time_struct);
  if (time2 == -1) {
    printf("Error getting time.\n");
    return -1;
  }
  long long diff_sec = difftime(time1, time2);
  int currentYear = diff_sec / 31536000;
  int afterTenYears = currentYear + 10;
  printf("Now: %d\nAfter 10 years: %d", currentYear, afterTenYears);
  return 0;
}
```