ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<if_square_is_magic>:
  endbr64
  test   %edi,%edi
  jle    L89
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  movslq %edi,%r12
  mov    %rsi,%r11
  lea    0x4(%rsi),%r13
  lea    -0x1(%rdi),%eax
  lea    0x0(%r13,%rax,4),%rcx
  mov    %rsi,%rax
  mov    $0x0,%r10d
L23:
  add    (%rax),%r10d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L23
  lea    0x0(,%r12,4),%r8
  mov    $0x1,%r9d
  mov    $0x0,%edi
  mov    %ebx,%r14d
  neg    %r14
  shl    $0x2,%r14
  mov    $0x0,%esi
L31:
  lea    (%r14,%rcx,1),%rax
  mov    %esi,%edx
L27:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L27
  cmp    %r10d,%edx
  cmovne %esi,%r9d
  lea    0x1(%rdi),%eax
  add    %r8,%rcx
  cmp    %eax,%ebx
  je     L16
  mov    %eax,%edi
  jmp    L31
L16:
  mov    %edi,%eax
  lea    0x0(%r13,%rax,4),%r15
  mov    %rbp,%r13
  mov    $0x0,%r14d
L105:
  mov    %r13,%rdx
  mov    %r14d,%ecx
  mov    $0x0,%eax
L45:
  add    (%rdx),%ecx
  mov    %eax,%esi
  add    $0x1,%eax
  add    %r8,%rdx
  cmp    %esi,%edi
  jne    L45
  cmp    %r10d,%ecx
  cmovne %r14d,%r9d
  add    $0x4,%r13
  cmp    %r15,%r13
  jne    L105
  add    $0x4,%r8
  mov    $0x0,%edx
  mov    $0x0,%eax
L76:
  add    (%r11),%edx
  mov    %eax,%ecx
  add    $0x1,%eax
  add    %r8,%r11
  cmp    %ecx,%edi
  jne    L76
  cmp    %r10d,%edx
  je     L33
  mov    $0x0,%r9d
L5:
  lea    -0x4(,%r12,4),%rsi
  movslq %edi,%rdi
  lea    0x0(%rbp,%rdi,4),%rdx
  mov    $0x0,%ecx
  mov    $0x0,%eax
L83:
  add    (%rdx),%ecx
  add    $0x1,%eax
  add    %rsi,%rdx
  cmp    %eax,%ebx
  jg     L83
  cmp    %ecx,%r10d
  mov    $0x0,%eax
  cmovne %eax,%r9d
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L89:
  mov    $0x0,%r10d
  mov    $0x1,%r9d
  mov    $0x0,%ecx
  cmp    %ecx,%r10d
  mov    $0x0,%eax
  cmovne %eax,%r9d
  mov    %r9d,%eax
  ret
L33:
  lea    -0x1(%rbx),%edi
  jmp    L5
```

assistant: ```c
int if_square_is_magic(int size, int square[size][size]) {
  int row, column, magic = 1, i;
  int sum = 0;
  int new_sum = 0;
  for (column = 0; column < size; column++) {
    sum = sum + square[0][column];
  }
  for (row = 0; row < size; row++) {
    for (column = 0; column < size; column++) {
      new_sum = new_sum + square[row][column];
    }
    if (!(new_sum == sum)) {
      magic = 0;
    }
    new_sum = 0;
  }
  new_sum = 0;
  for (column = 0; column < size; column++) {
    for (row = 0; row < size; row++) {
      new_sum = new_sum + square[row][column];
    }
    if (!(new_sum == sum)) {
      magic = 0;
    }
    new_sum = 0;
  }
  new_sum = 0;
  for (i = 0; i < size; i++) {
    new_sum = new_sum + square[i][i];
  }
  if (!(new_sum == sum)) {
    magic = 0;
  }
  new_sum = 0;
  row = 0;
  column = size - 1;
  for (i = 0; i < size; i++) {
    new_sum = new_sum + square[row][column];
    row++;
    column--;
  }
  if (!(new_sum == sum)) {
    magic = 0;
  }
  return magic;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x5,%esi
  mov    $0x0,%edi
  call   <nondet@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L0
  movl   $0x1,-0x8(%rbp)
  jmp    L17
L0:
  movl   $0xffffffff,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i = nondet(0, 5);
  int j = 0;
  if (i > 1) {
    j = 1;
  } else {
    j = -1;
  }
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  mov    $0x0,%edi
  call   <nondet@plt>
  cmp    $0x1,%eax
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i = nondet(0, 5);
  int j = 0;
  if (i > 1) {
    j = 1;
  } else {
    j = -1;
  }
  return j;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  mov    $0x5,%esi
  call   <nondet@plt>
  cmp    $0x1,%eax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int main() {
  int i = nondet(0, 5);
  int j = 0;
  if (i > 1) {
    j = 1;
  } else {
    j = -1;
  }
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  mov    $0x5,%esi
  call   <nondet@plt>
  cmp    $0x1,%eax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int main() {
  int i = nondet(0, 5);
  int j = 0;
  if (i > 1) {
    j = 1;
  } else {
    j = -1;
  }
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<about>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  lea    0x7(%rax),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  sar    $0x3,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int about(int value) {
  value += random() % (value / 8);
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<about>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <random@plt>
  lea    0x7(%rbx),%ecx
  test   %ebx,%ebx
  cmovns %ebx,%ecx
  sar    $0x3,%ecx
  cltd
  idiv   %ecx
  lea    (%rbx,%rdx,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
int about(int value) {
  value += random() % (value / 8);
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<about>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <random@plt>
  test   %ebx,%ebx
  lea    0x7(%rbx),%ecx
  cmovns %ebx,%ecx
  cltd
  sar    $0x3,%ecx
  idiv   %ecx
  lea    (%rbx,%rdx,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
int about(int value) {
  value += random() % (value / 8);
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<about>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <random@plt>
  test   %ebx,%ebx
  lea    0x7(%rbx),%ecx
  cmovns %ebx,%ecx
  cltd
  sar    $0x3,%ecx
  idiv   %ecx
  lea    (%rbx,%rdx,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
int about(int value) {
  value += random() % (value / 8);
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strdfcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L48
L5:
  addq   $0x1,-0x18(%rbp)
L48:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  jmp    L91
L14:
  addq   $0x1,-0x20(%rbp)
L91:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L37
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L37
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x2(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x1(%rbp)
  addq   $0x1,-0x20(%rbp)
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jne    L119
  cmpb   $0x0,-0x2(%rbp)
  jne    L119
  mov    $0x0,%eax
  jmp    L1
L119:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L48
  movsbl -0x2(%rbp),%eax
  movsbl -0x1(%rbp),%edx
  sub    %edx,%eax
L1:
  leave
  ret
```

assistant: ```c
int strdfcmp(char *s1, char *s2) {
  char a, b;
  do {
    while (!isalnum(*s1) && *s1 != ' ' && *s1 != '\0')
      s1++;
    while (!isalnum(*s2) && *s2 != ' ' && *s2 != '\0')
      s2++;
    a = tolower(*s1);
    s1++;
    b = tolower(*s2);
    s2++;
    if (a == b && a == '\0')
      return 0;
  } while (a == b);
  return a - b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strdfcmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  jmp    L40
L42:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L99
  testb  $0xdf,(%rbx)
  je     L99
  add    $0x1,%rbx
  jmp    L42
L99:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%r12d
  add    $0x1,%rbp
  movsbl (%rbx),%edi
  call   <tolower@plt>
  add    $0x1,%rbx
  cmp    %al,%r12b
  jne    L7
  test   %r12b,%r12b
  je     L38
L7:
  cmp    %al,%r12b
  jne    L87
L40:
  movsbl 0x0(%rbp),%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L42
  testb  $0xdf,0x0(%rbp)
  je     L42
  add    $0x1,%rbp
  jmp    L40
L87:
  movsbl %r12b,%r12d
  movsbl %al,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  jmp    L36
L38:
  mov    $0x0,%eax
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strdfcmp(char *s1, char *s2) {
  char a, b;
  do {
    while (!isalnum(*s1) && *s1 != ' ' && *s1 != '\0')
      s1++;
    while (!isalnum(*s2) && *s2 != ' ' && *s2 != '\0')
      s2++;
    a = tolower(*s1);
    s1++;
    b = tolower(*s2);
    s2++;
    if (a == b && a == '\0')
      return 0;
  } while (a == b);
  return a - b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strdfcmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L67:
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%r12
  add    $0x1,%rbp
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L61
  testb  $0xdf,-0x1(%rbp)
  jne    L67
  nopw   0x0(%rax,%rax,1)
L61:
  movsbl (%rbx),%edi
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L24
  testb  $0xdf,-0x1(%rbx)
  jne    L61
L24:
  movsbl (%r12),%edi
  call   <tolower@plt>
  movsbl 0x0(%r13),%edi
  movsbl %al,%r12d
  call   <tolower@plt>
  cmp    %al,%r12b
  jne    L35
  test   %r12b,%r12b
  je     L41
  cmp    %al,%r12b
  je     L67
L35:
  add    $0x8,%rsp
  movsbl %al,%edx
  mov    %r12d,%eax
  pop    %rbx
  sub    %edx,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strdfcmp(char *s1, char *s2) {
  char a, b;
  do {
    while (!isalnum(*s1) && *s1 != ' ' && *s1 != '\0')
      s1++;
    while (!isalnum(*s2) && *s2 != ' ' && *s2 != '\0')
      s2++;
    a = tolower(*s1);
    s1++;
    b = tolower(*s2);
    s2++;
    if (a == b && a == '\0')
      return 0;
  } while (a == b);
  return a - b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strdfcmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%r12
  add    $0x1,%rbp
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L33
  testb  $0xdf,-0x1(%rbp)
  jne    L8
  nopw   0x0(%rax,%rax,1)
L33:
  movsbl (%rbx),%edi
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L24
  testb  $0xdf,-0x1(%rbx)
  jne    L33
L24:
  movsbl (%r12),%edi
  call   <tolower@plt>
  movsbl 0x0(%r13),%edi
  movsbl %al,%r12d
  call   <tolower@plt>
  cmp    %al,%r12b
  jne    L13
  test   %r12b,%r12b
  je     L58
  cmp    %al,%r12b
  je     L8
L13:
  add    $0x8,%rsp
  movsbl %al,%edx
  mov    %r12d,%eax
  pop    %rbx
  sub    %edx,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strdfcmp(char *s1, char *s2) {
  char a, b;
  do {
    while (!isalnum(*s1) && *s1 != ' ' && *s1 != '\0')
      s1++;
    while (!isalnum(*s2) && *s2 != ' ' && *s2 != '\0')
      s2++;
    a = tolower(*s1);
    s1++;
    b = tolower(*s2);
    s2++;
    if (a == b && a == '\0')
      return 0;
  } while (a == b);
  return a - b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L33
  mov    $0x1,%eax
  jmp    L40
L33:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L25
  mov    $0xffffffff,%eax
  jmp    L40
L25:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L21
  mov    $0x0,%eax
  jmp    L40
L21:
  mov    $0x0,%eax
L40:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: [====local is %d and out is %d====]


assistant: ```c
int cmp(void *local, void *out) {
  int *a = (int *)local;
  int *b = (int *)out;
  printf("[====local is %d and out is %d====]\n", *a, *b);
  if (*a > *b)
    return 1;
  if (*a < *b)
    return -1;
  if (*a == *b)
    return 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    (%rsi),%edx
  mov    (%rdi),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x0(%rbp),%ecx
  mov    (%rbx),%edx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  jg     L5
  setl   %al
  movzbl %al,%eax
  neg    %eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: [====local is %d and out is %d====]


assistant: ```c
int cmp(void *local, void *out) {
  int *a = (int *)local;
  int *b = (int *)out;
  printf("[====local is %d and out is %d====]\n", *a, *b);
  if (*a > *b)
    return 1;
  if (*a < *b)
    return -1;
  if (*a == *b)
    return 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%edx
  mov    (%rdi),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%ecx
  mov    $0x1,%eax
  cmp    %ecx,0x0(%rbp)
  jg     L3
  setl   %al
  movzbl %al,%eax
  neg    %eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: [====local is %d and out is %d====]


assistant: ```c
int cmp(void *local, void *out) {
  int *a = (int *)local;
  int *b = (int *)out;
  printf("[====local is %d and out is %d====]\n", *a, *b);
  if (*a > *b)
    return 1;
  if (*a < *b)
    return -1;
  if (*a == *b)
    return 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%edx
  mov    (%rdi),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%ecx
  mov    $0x1,%eax
  cmp    %ecx,0x0(%rbp)
  jg     L9
  setl   %al
  movzbl %al,%eax
  neg    %eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: [====local is %d and out is %d====]


assistant: ```c
int cmp(void *local, void *out) {
  int *a = (int *)local;
  int *b = (int *)out;
  printf("[====local is %d and out is %d====]\n", *a, *b);
  if (*a > *b)
    return 1;
  if (*a < *b)
    return -1;
  if (*a == *b)
    return 0;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L9
  mov    $0x0,%eax
  jmp    L23
L9:
  mov    -0xc(%rbp),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  and    %edx,%eax
  test   %eax,%eax
  jne    L3
  mov    $0x1,%eax
  jmp    L23
L3:
  mov    $0x0,%eax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int isfile(char *name) {
  struct stat stat_buff;
  if (stat(name, &stat_buff) != 0)
    return 0;
  if ((stat_buff.st_mode & (unsigned)S_IFDIR) == 0)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isfile>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L2
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  test   %eax,0x4(%rsp)
  sete   %al
  movzbl %al,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isfile(char *name) {
  struct stat stat_buff;
  if (stat(name, &stat_buff) != 0)
    return 0;
  if ((stat_buff.st_mode & (unsigned)S_IFDIR) == 0)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isfile>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L13
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  test   %eax,0x4(%rsp)
  sete   %al
  movzbl %al,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isfile(char *name) {
  struct stat stat_buff;
  if (stat(name, &stat_buff) != 0)
    return 0;
  if ((stat_buff.st_mode & (unsigned)S_IFDIR) == 0)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isfile>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L8
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  test   %eax,0x4(%rsp)
  sete   %al
  movzbl %al,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isfile(char *name) {
  struct stat stat_buff;
  if (stat(name, &stat_buff) != 0)
    return 0;
  if ((stat_buff.st_mode & (unsigned)S_IFDIR) == 0)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    $0x0,%eax
  sub    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  movswl -0x14(%rbp),%edx
  mov    $0x0,%eax
  sub    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movswl -0x14(%rbp),%eax
  mov    -0x18(%rbp),%esi
  mov    %eax,%edi
  call   <bar@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int foo(short a, unsigned int b, char *unused_str) {
  int c = bar(a, b, -2 * a, -2 * b);
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  movswl %di,%edi
  mov    %esi,%ecx
  neg    %ecx
  add    %ecx,%ecx
  mov    %edi,%edx
  neg    %edx
  add    %edx,%edx
  call   <bar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int foo(short a, unsigned int b, char *unused_str) {
  int c = bar(a, b, -2 * a, -2 * b);
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  movswl %di,%edi
  mov    %esi,%ecx
  mov    %edi,%edx
  neg    %ecx
  neg    %edx
  add    %ecx,%ecx
  add    %edx,%edx
  jmp    1050 <bar@plt>
```

assistant: ```c
int foo(short a, unsigned int b, char *unused_str) {
  int c = bar(a, b, -2 * a, -2 * b);
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  movswl %di,%edi
  mov    %esi,%ecx
  mov    %edi,%edx
  neg    %ecx
  neg    %edx
  add    %ecx,%ecx
  add    %edx,%edx
  jmp    1050 <bar@plt>
```

assistant: ```c
int foo(short a, unsigned int b, char *unused_str) {
  int c = bar(a, b, -2 * a, -2 * b);
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<failed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x1028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x1010(%rbp)
  movq   $0x0,-0x1008(%rbp)
  lea    -0x1000(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1fe,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x1028(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rcx
  lea    D19(%rip),%rdx
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %eax,-0x1014(%rbp)
  cmpl   $0xfff,-0x1014(%rbp)
  jg     L34
  cmpl   $0xffffffff,-0x1014(%rbp)
  jne    L32
L34:
  mov    $0x0,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <write_log@plt>
  mov    $0xffffffff,%eax
  jmp    L4
L32:
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rdi
  call   <_response@plt>
  mov    $0x0,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D10
type: string

tool: D19: 500 '%s' command is not supported.


tool: D10: Too long command got.

assistant: ```c
int failed(const char *s) {
  char msg500[4096] = {0};
  int m_len;
  if ((m_len = snprintf(msg500, 4096, "500 \'%s\' command is not supported.\r\n", s)) >= 4096 || m_len == -1) {
    write_log("Too long command got.", 0);
    return -1;
  }
  _response(msg500);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<failed>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x1fe,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdi
  mov    %rdx,%rcx
  lea    D17(%rip),%rdx
  mov    $0x1000,%esi
  call   <snprintf@plt>
  cmp    $0xffffffff,%eax
  je     L12
  cmp    $0xfff,%eax
  jg     L12
  mov    %rsp,%rdi
  call   <_response@plt>
  mov    $0x0,%eax
L35:
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x1018,%rsp
  ret
L12:
  mov    $0x0,%esi
  lea    D6(%rip),%rdi
  call   <write_log@plt>
  mov    $0xffffffff,%eax
  jmp    L35
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: string
name: unpack_data
arguments: tag: D6
type_infered: string

tool: D17: 500 '%s' command is not supported.


tool: D6: Too long command got.

assistant: ```c
int failed(const char *s) {
  char msg500[4096] = {0};
  int m_len;
  if ((m_len = snprintf(msg500, 4096, "500 \'%s\' command is not supported.\r\n", s)) >= 4096 || m_len == -1) {
    write_log("Too long command got.", 0);
    return -1;
  }
  _response(msg500);
  return 0;
}
```