ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cJSON_Version>:
  endbr64
  push   %r12
  mov    $0x3,%r8d
  mov    $0x7,%ecx
  lea    D15(%rip),%r12
  mov    %r12,%rdi
  mov    $0x1,%edx
  lea    D0(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 7, 3);
  return version;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tinf_zlib_uncompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x16(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x15(%rbp)
  movzbl -0x16(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x15(%rbp),%eax
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0xffffffff84210843,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x4,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x5,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L53
  mov    $0xfffffffd,%eax
  jmp    L34
L53:
  movzbl -0x16(%rbp),%eax
  and    $0xf,%eax
  cmp    $0x8,%eax
  je     L82
  mov    $0xfffffffd,%eax
  jmp    L34
L82:
  movzbl -0x16(%rbp),%eax
  shr    $0x4,%al
  cmp    $0x7,%al
  jbe    L3
  mov    $0xfffffffd,%eax
  jmp    L34
L3:
  movzbl -0x15(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L36
  mov    $0xfffffffd,%eax
  jmp    L34
L36:
  mov    -0x3c(%rbp),%eax
  lea    -0x6(%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tinf_uncompress@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L75
  mov    $0xfffffffd,%eax
  jmp    L34
L75:
  mov    $0x0,%eax
L34:
  leave
  ret
```

assistant: ```c
int tinf_zlib_uncompress(void *dest, unsigned int *destLen, const void *source, unsigned int sourceLen) {
  unsigned char *src = (unsigned char *)source;
  unsigned char *dst = (unsigned char *)dest;
  int res;
  unsigned char cmf, flg;
  cmf = src[0];
  flg = src[1];
  if (((cmf << 8) + flg) % 31)
    return (-3);
  if ((cmf & 0x0f) != 8)
    return (-3);
  if ((cmf >> 4) > 7)
    return (-3);
  if (flg & 0x20)
    return (-3);
  res = tinf_uncompress(dst, destLen, src + 2, sourceLen - 6);
  if (res != 0)
    return (-3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tinf_zlib_uncompress>:
  endbr64
  mov    %rsi,%r8
  movzbl (%rdx),%r10d
  movzbl 0x1(%rdx),%r11d
  movzbl %r10b,%esi
  shl    $0x8,%esi
  movzbl %r11b,%eax
  add    %eax,%esi
  movslq %esi,%rax
  imul   $0xffffffff84210843,%rax,%rax
  shr    $0x20,%rax
  add    %esi,%eax
  sar    $0x4,%eax
  mov    %eax,%r9d
  shl    $0x5,%r9d
  sub    %eax,%r9d
  cmp    %r9d,%esi
  jne    L34
  mov    %r10d,%eax
  and    $0xf,%eax
  cmp    $0x8,%al
  jne    L44
  test   %r10b,%r10b
  js     L47
  test   $0x20,%r11b
  jne    L29
  sub    $0x8,%rsp
  sub    $0x6,%ecx
  add    $0x2,%rdx
  mov    %r8,%rsi
  call   <tinf_uncompress@plt>
  test   %eax,%eax
  jne    L21
L3:
  add    $0x8,%rsp
  ret
L21:
  mov    $0xfffffffd,%eax
  jmp    L3
L34:
  mov    $0xfffffffd,%eax
  ret
L44:
  mov    $0xfffffffd,%eax
  ret
L47:
  mov    $0xfffffffd,%eax
  ret
L29:
  mov    $0xfffffffd,%eax
  ret
```

assistant: ```c
int tinf_zlib_uncompress(void *dest, unsigned int *destLen, const void *source, unsigned int sourceLen) {
  unsigned char *src = (unsigned char *)source;
  unsigned char *dst = (unsigned char *)dest;
  int res;
  unsigned char cmf, flg;
  cmf = src[0];
  flg = src[1];
  if (((cmf << 8) + flg) % 31)
    return (-3);
  if ((cmf & 0x0f) != 8)
    return (-3);
  if ((cmf >> 4) > 7)
    return (-3);
  if (flg & 0x20)
    return (-3);
  res = tinf_uncompress(dst, destLen, src + 2, sourceLen - 6);
  if (res != 0)
    return (-3);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tinf_zlib_uncompress>:
  endbr64
  movzbl (%rdx),%eax
  movzbl 0x1(%rdx),%r10d
  mov    %rsi,%r8
  mov    %eax,%esi
  shl    $0x8,%eax
  add    %r10d,%eax
  imul   $0xbdef7bdf,%eax,%eax
  cmp    $0x8421084,%eax
  ja     L28
  mov    %esi,%eax
  and    $0xf,%eax
  cmp    $0x8,%al
  jne    L28
  test   %sil,%sil
  js     L28
  mov    %r10d,%r9d
  and    $0x20,%r9d
  jne    L28
  sub    $0x8,%rsp
  sub    $0x6,%ecx
  add    $0x2,%rdx
  mov    %r8,%rsi
  call   <tinf_uncompress@plt>
  test   %eax,%eax
  jne    L22
L5:
  add    $0x8,%rsp
  ret
L22:
  mov    $0xfffffffd,%eax
  jmp    L5
  xchg   %ax,%ax
L28:
  mov    $0xfffffffd,%eax
  ret
```

assistant: ```c
int tinf_zlib_uncompress(void *dest, unsigned int *destLen, const void *source, unsigned int sourceLen) {
  unsigned char *src = (unsigned char *)source;
  unsigned char *dst = (unsigned char *)dest;
  int res;
  unsigned char cmf, flg;
  cmf = src[0];
  flg = src[1];
  if (((cmf << 8) + flg) % 31)
    return (-3);
  if ((cmf & 0x0f) != 8)
    return (-3);
  if ((cmf >> 4) > 7)
    return (-3);
  if (flg & 0x20)
    return (-3);
  res = tinf_uncompress(dst, destLen, src + 2, sourceLen - 6);
  if (res != 0)
    return (-3);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tinf_zlib_uncompress>:
  endbr64
  movzbl (%rdx),%eax
  movzbl 0x1(%rdx),%r10d
  mov    %rsi,%r8
  mov    %eax,%esi
  shl    $0x8,%eax
  add    %r10d,%eax
  imul   $0xbdef7bdf,%eax,%eax
  cmp    $0x8421084,%eax
  ja     L6
  mov    %esi,%eax
  and    $0xf,%eax
  cmp    $0x8,%al
  jne    L6
  test   %sil,%sil
  js     L6
  mov    %r10d,%r9d
  and    $0x20,%r9d
  jne    L6
  sub    $0x8,%rsp
  sub    $0x6,%ecx
  add    $0x2,%rdx
  mov    %r8,%rsi
  call   <tinf_uncompress@plt>
  test   %eax,%eax
  jne    L15
L18:
  add    $0x8,%rsp
  ret
L15:
  mov    $0xfffffffd,%eax
  jmp    L18
  xchg   %ax,%ax
L6:
  mov    $0xfffffffd,%eax
  ret
```

assistant: ```c
int tinf_zlib_uncompress(void *dest, unsigned int *destLen, const void *source, unsigned int sourceLen) {
  unsigned char *src = (unsigned char *)source;
  unsigned char *dst = (unsigned char *)dest;
  int res;
  unsigned char cmf, flg;
  cmf = src[0];
  flg = src[1];
  if (((cmf << 8) + flg) % 31)
    return (-3);
  if ((cmf & 0x0f) != 8)
    return (-3);
  if ((cmf >> 4) > 7)
    return (-3);
  if (flg & 0x20)
    return (-3);
  res = tinf_uncompress(dst, destLen, src + 2, sourceLen - 6);
  if (res != 0)
    return (-3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_ol_logger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4e0,%rsp
  mov    %rdi,-0x4d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x4d8(%rbp),%rdx
  mov    -0x4c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x4c4(%rbp),%edx
  mov    -0x4d8(%rbp),%rcx
  lea    -0x4c0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0x4c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x4c0(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_logger@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
void _ol_logger(const char *fmt, ...) {
  char buff[1024];
  va_list args;
  va_start(args, fmt);
  vsprintf(buff, fmt, args);
  va_end(args);
  ol_logger(buff);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_ol_logger>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rdi
  call   <ol_logger@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _ol_logger(const char *fmt, ...) {
  char buff[1024];
  va_list args;
  va_start(args, fmt);
  vsprintf(buff, fmt, args);
  va_end(args);
  ol_logger(buff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ol_logger>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rdi
  call   <ol_logger@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _ol_logger(const char *fmt, ...) {
  char buff[1024];
  va_list args;
  va_start(args, fmt);
  vsprintf(buff, fmt, args);
  va_end(args);
  ol_logger(buff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ol_logger>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rdi
  call   <ol_logger@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _ol_logger(const char *fmt, ...) {
  char buff[1024];
  va_list args;
  va_start(args, fmt);
  vsprintf(buff, fmt, args);
  va_end(args);
  ol_logger(buff);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x8(%rbp)
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f() {
  int x;
  x = 1;
  {
    int p;
    p = 10;
    x = p + x;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  mov    $0xb,%eax
  ret
```

assistant: ```c
int f() {
  int x;
  x = 1;
  {
    int p;
    p = 10;
    x = p + x;
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  mov    $0xb,%eax
  ret
```

assistant: ```c
int f() {
  int x;
  x = 1;
  {
    int p;
    p = 10;
    x = p + x;
  }
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f>:
  endbr64
  mov    $0xb,%eax
  ret
```

assistant: ```c
int f() {
  int x;
  x = 1;
  {
    int p;
    p = 10;
    x = p + x;
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<semP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  mov    $0x1b6,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <semget@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jns    L28
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <semInit@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  je     L34
L28:
  movq   $0x0,-0x10(%rbp)
  movl   $0xffffffff,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <semop@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L6
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
L34:
  nop
L6:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: P-operation did not succeed %d


assistant: ```c
void semP(int key) {
  int semId = semget(key, 1, 0666);
  if (semId < 0) {
    semId = semInit(1, key);
    if (!semId)
      return;
  }
  struct sembuf operations[1];
  operations[0].sem_num = 0;
  operations[0].sem_op = -1;
  operations[0].sem_flg = 0;
  int retval = semop(semId, operations, 1);
  if (retval == 0) {
    ;
  } else {
    printf("P-operation did not succeed %d\n", key);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<semP>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1b6,%edx
  mov    $0x1,%esi
  call   <semget@plt>
  test   %eax,%eax
  js     L8
L46:
  movq   $0x0,0x10(%rsp)
  movl   $0xffffffff,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <semop@plt>
  test   %eax,%eax
  jne    L10
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  mov    %ebx,%esi
  mov    $0x1,%edi
  call   <semInit@plt>
  test   %eax,%eax
  jne    L46
  jmp    L17
L10:
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: P-operation did not succeed %d


assistant: ```c
void semP(int key) {
  int semId = semget(key, 1, 0666);
  if (semId < 0) {
    semId = semInit(1, key);
    if (!semId)
      return;
  }
  struct sembuf operations[1];
  operations[0].sem_num = 0;
  operations[0].sem_op = -1;
  operations[0].sem_flg = 0;
  int retval = semop(semId, operations, 1);
  if (retval == 0) {
    ;
  } else {
    printf("P-operation did not succeed %d\n", key);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<semP>:
  endbr64
  push   %rbp
  mov    $0x1b6,%edx
  mov    $0x1,%esi
  mov    %edi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <semget@plt>
  mov    %eax,%edi
  test   %eax,%eax
  js     L36
L8:
  mov    %rsp,%rsi
  mov    $0x1,%edx
  movq   $0x0,0x10(%rsp)
  movl   $0xffffffff,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <semop@plt>
  test   %eax,%eax
  jne    L7
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x20,%rsp
  pop    %rbp
  ret
L36:
  mov    $0x1,%edi
  mov    %ebp,%esi
  call   <semInit@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L8
  jmp    L0
  nopl   0x0(%rax)
L7:
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: D8: P-operation did not succeed %d


assistant: ```c
void semP(int key) {
  int semId = semget(key, 1, 0666);
  if (semId < 0) {
    semId = semInit(1, key);
    if (!semId)
      return;
  }
  struct sembuf operations[1];
  operations[0].sem_num = 0;
  operations[0].sem_op = -1;
  operations[0].sem_flg = 0;
  int retval = semop(semId, operations, 1);
  if (retval == 0) {
    ;
  } else {
    printf("P-operation did not succeed %d\n", key);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<semP>:
  endbr64
  push   %rbp
  mov    $0x1b6,%edx
  mov    $0x1,%esi
  mov    %edi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <semget@plt>
  mov    %eax,%edi
  test   %eax,%eax
  js     L10
L14:
  pxor   %xmm0,%xmm0
  mov    %rsp,%rsi
  mov    $0x1,%edx
  movl   $0xffffffff,(%rsp)
  movups %xmm0,0x8(%rsp)
  call   <semop@plt>
  test   %eax,%eax
  jne    L5
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%edi
  mov    %ebp,%esi
  call   <semInit@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L14
  jmp    L32
  nopl   0x0(%rax)
L5:
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: P-operation did not succeed %d


assistant: ```c
void semP(int key) {
  int semId = semget(key, 1, 0666);
  if (semId < 0) {
    semId = semInit(1, key);
    if (!semId)
      return;
  }
  struct sembuf operations[1];
  operations[0].sem_num = 0;
  operations[0].sem_op = -1;
  operations[0].sem_flg = 0;
  int retval = semop(semId, operations, 1);
  if (retval == 0) {
    ;
  } else {
    printf("P-operation did not succeed %d\n", key);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L3
L6:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
char *strdup(const char *str) {
  size_t length = strlen(str);
  char *result = malloc(length + 1);
  if (!result)
    return NULL;
  memcpy(result, str, length + 1);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L2:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *str) {
  size_t length = strlen(str);
  char *result = malloc(length + 1);
  if (!result)
    return NULL;
  memcpy(result, str, length + 1);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L7:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strdup(const char *str) {
  size_t length = strlen(str);
  char *result = malloc(length + 1);
  if (!result)
    return NULL;
  memcpy(result, str, length + 1);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L8:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strdup(const char *str) {
  size_t length = strlen(str);
  char *result = malloc(length + 1);
  if (!result)
    return NULL;
  memcpy(result, str, length + 1);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L49
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L26
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L49
L26:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L49:
  subq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L31
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jle    L2
L31:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L3
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  subq   $0x1,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ltrim(char *c, char *b, int d) {
  char *a, *x;
  a = c;
  for (x = b - 1; x >= c && b - x <= d; x--)
    if (!isspace(x[0]) && (x == c || isspace(x[-1])))
      a = x;
  if (a > c && !isspace(a[-1]))
    a--;
  return (a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ltrim>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  lea    -0x1(%rsi),%rbx
  cmp    %rbx,%rdi
  ja     L30
  mov    %rsi,%r12
  movslq %edx,%rbp
  test   %rbp,%rbp
  jle    L9
  lea    -0x1(%rdi),%r15
  mov    %rdi,%r14
  jmp    L33
L16:
  mov    %rbx,%r14
L19:
  sub    $0x1,%rbx
  cmp    %r15,%rbx
  je     L82
  mov    %r12,%rax
  sub    %rbx,%rax
  cmp    %rbp,%rax
  jg     L82
L33:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  cmp    %rbx,%r13
  je     L16
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  cmovne %rbx,%r14
  jmp    L19
L82:
  cmp    %r13,%r14
  ja     L61
L88:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  movsbl -0x1(%r14),%edi
  call   <isspace@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%r14
  jmp    L88
L30:
  mov    %rdi,%r14
  jmp    L88
L9:
  mov    %rdi,%r14
  jmp    L88
```

assistant: ```c
char *ltrim(char *c, char *b, int d) {
  char *a, *x;
  a = c;
  for (x = b - 1; x >= c && b - x <= d; x--)
    if (!isspace(x[0]) && (x == c || isspace(x[-1])))
      a = x;
  if (a > c && !isspace(a[-1]))
    a--;
  return (a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ltrim>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%rbx
  sub    $0x8,%rsp
  cmp    %rbx,%rdi
  ja     L64
  movslq %edx,%rbp
  test   %rbp,%rbp
  jle    L64
  mov    %rsi,%r13
  lea    -0x1(%rdi),%r15
  mov    %rdi,%r14
  jmp    L91
  nopw   0x0(%rax,%rax,1)
L47:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  cmovne %rbx,%r14
L84:
  sub    $0x1,%rbx
  cmp    %r15,%rbx
  je     L17
L95:
  mov    %r13,%rax
  sub    %rbx,%rax
  cmp    %rbp,%rax
  jg     L17
L91:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L84
  cmp    %rbx,%r12
  jne    L47
  sub    $0x1,%rbx
  mov    %r12,%r14
  cmp    %r15,%rbx
  jne    L95
  nopw   0x0(%rax,%rax,1)
L17:
  cmp    %r12,%r14
  jbe    L15
  movsbl -0x1(%r14),%edi
  call   <isspace@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%r14
L15:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L64:
  mov    %r12,%r14
  jmp    L15
```

assistant: ```c
char *ltrim(char *c, char *b, int d) {
  char *a, *x;
  a = c;
  for (x = b - 1; x >= c && b - x <= d; x--)
    if (!isspace(x[0]) && (x == c || isspace(x[-1])))
      a = x;
  if (a > c && !isspace(a[-1]))
    a--;
  return (a);
}
```