ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<purchased_toys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quicksort@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L20:
  cmpl   $0x0,-0x18(%rbp)
  jle    L0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    %eax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L20
L0:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int purchased_toys(int num_items, int *toys, int money) {
  int i, purchased = 0;
  quicksort(toys, 0, num_items - 1);
  for (i = 0; i < num_items; i++) {
    if (money > 0 && toys[i] < money) {
      money -= toys[i];
      purchased++;
    } else
      break;
  }
  return purchased;
}
```
user: What is the c source code of the assembly code below?

```asm
<purchased_toys>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %edx,%ebp
  lea    -0x1(%rdi),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <quicksort@plt>
  test   %ebp,%ebp
  jle    L12
  test   %r12d,%r12d
  jle    L12
  mov    %rbx,%rsi
  mov    $0x0,%eax
L19:
  mov    (%rsi),%edx
  cmp    %ebp,%edx
  jge    L10
  sub    %edx,%ebp
  add    $0x1,%eax
  add    $0x4,%rsi
  cmp    %eax,%r12d
  jg     L19
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
int purchased_toys(int num_items, int *toys, int money) {
  int i, purchased = 0;
  quicksort(toys, 0, num_items - 1);
  for (i = 0; i < num_items; i++) {
    if (money > 0 && toys[i] < money) {
      money -= toys[i];
      purchased++;
    } else
      break;
  }
  return purchased;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<purchased_toys>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  lea    -0x1(%rdi),%edx
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <quicksort@plt>
  test   %ebp,%ebp
  jle    L22
  test   %r12d,%r12d
  jle    L22
  mov    %rbx,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rsi),%edx
  cmp    %ebp,%edx
  jge    L10
  add    $0x1,%eax
  sub    %edx,%ebp
  add    $0x4,%rsi
  cmp    %eax,%r12d
  jg     L5
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  xor    %eax,%eax
  jmp    L10
```

assistant: ```c
int purchased_toys(int num_items, int *toys, int money) {
  int i, purchased = 0;
  quicksort(toys, 0, num_items - 1);
  for (i = 0; i < num_items; i++) {
    if (money > 0 && toys[i] < money) {
      money -= toys[i];
      purchased++;
    } else
      break;
  }
  return purchased;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<purchased_toys>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  lea    -0x1(%rdi),%edx
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <quicksort@plt>
  test   %ebp,%ebp
  jle    L32
  test   %r12d,%r12d
  jle    L32
  mov    %rbx,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L16:
  mov    (%rsi),%edx
  cmp    %ebp,%edx
  jge    L29
  add    $0x1,%eax
  sub    %edx,%ebp
  add    $0x4,%rsi
  cmp    %eax,%r12d
  jg     L16
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  xor    %eax,%eax
  jmp    L29
```

assistant: ```c
int purchased_toys(int num_items, int *toys, int money) {
  int i, purchased = 0;
  quicksort(toys, 0, num_items - 1);
  for (i = 0; i < num_items; i++) {
    if (money > 0 && toys[i] < money) {
      money -= toys[i];
      purchased++;
    } else
      break;
  }
  return purchased;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L48
L24:
  movl   $0x0,-0x10(%rbp)
  jmp    L4
L35:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rcx,%rdx,4),%ecx
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    -0x38(%rbp),%rdx
  add    %rsi,%rdx
  mov    (%rdx),%edx
  imul   %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x40(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  cmp    %edx,-0xc(%rbp)
  je     L34
  movl   $0x0,-0xc(%rbp)
L34:
  addl   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%edx
  cmp    -0x28(%rbp),%edx
  jl     L35
  addl   $0x1,-0x14(%rbp)
L48:
  mov    -0x14(%rbp),%edx
  cmp    -0x24(%rbp),%edx
  jl     L24
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_function(int n, int m, int a[][m], int x[n], int b[m]) {
  int i, j, resultado = 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      resultado = a[i][j] * x[i];
      if (resultado != b[j]) {
        resultado = 0;
      }
    }
  }
  return resultado;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_function>:
  endbr64
  test   %edi,%edi
  jle    L31
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  movslq %esi,%rbp
  shl    $0x2,%rbp
  mov    %rcx,%r11
  lea    -0x1(%rdi),%eax
  lea    0x4(%rcx,%rax,4),%r12
  mov    $0x1,%ecx
  mov    %esi,%r10d
  mov    $0x0,%r9d
  jmp    L47
L17:
  mov    %rdx,%rdi
  mov    (%r11),%esi
  mov    $0x0,%eax
L43:
  mov    %esi,%ecx
  imul   (%rdi,%rax,4),%ecx
  cmp    %ecx,(%r8,%rax,4)
  cmovne %r9d,%ecx
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L43
L46:
  add    %rbp,%rdx
  add    $0x4,%r11
  cmp    %r12,%r11
  je     L20
L47:
  test   %ebx,%ebx
  jg     L17
  jmp    L46
L31:
  mov    $0x1,%ecx
  mov    %ecx,%eax
  ret
L20:
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int test_function(int n, int m, int a[][m], int x[n], int b[m]) {
  int i, j, resultado = 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      resultado = a[i][j] * x[i];
      if (resultado != b[j]) {
        resultado = 0;
      }
    }
  }
  return resultado;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_function>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jle    L26
  movslq %esi,%rdi
  sub    $0x1,%eax
  push   %rbx
  mov    $0x1,%r9d
  mov    %rdi,%r10
  lea    0x0(,%rdi,4),%rbx
  lea    0x4(%rcx,%rax,4),%r11
  nopw   0x0(%rax,%rax,1)
L4:
  test   %r10d,%r10d
  jle    L27
  mov    (%rcx),%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L23:
  mov    (%rdx,%rax,4),%r9d
  imul   %esi,%r9d
  cmp    %r9d,(%r8,%rax,4)
  je     L0
  xor    %r9d,%r9d
L0:
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L23
L27:
  add    $0x4,%rcx
  add    %rbx,%rdx
  cmp    %r11,%rcx
  jne    L4
  mov    %r9d,%eax
  pop    %rbx
  ret
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test_function(int n, int m, int a[][m], int x[n], int b[m]) {
  int i, j, resultado = 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      resultado = a[i][j] * x[i];
      if (resultado != b[j]) {
        resultado = 0;
      }
    }
  }
  return resultado;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_function>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jle    L98
  push   %r15
  sub    $0x1,%eax
  push   %r14
  lea    0x4(%rcx,%rax,4),%r14
  push   %r13
  movslq %esi,%r13
  mov    %rcx,%rsi
  mov    %r13,%rdi
  push   %r12
  shl    $0x2,%r13
  mov    %edi,%eax
  push   %rbp
  mov    %edi,%r12d
  lea    -0x1(%rdi),%r15d
  shr    $0x2,%eax
  push   %rbx
  and    $0xfffffffc,%r12d
  lea    -0x1(%rax),%ecx
  mov    $0x1,%eax
  add    $0x1,%rcx
  shl    $0x4,%rcx
  nopl   (%rax)
L105:
  test   %edi,%edi
  jle    L18
  mov    (%rsi),%r10d
  cmp    $0x2,%r15d
  jbe    L13
  movd   %r10d,%xmm4
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm2
  movdqa %xmm2,%xmm3
  psrlq  $0x20,%xmm3
  nopw   0x0(%rax,%rax,1)
L15:
  movdqu (%rdx,%rax,1),%xmm0
  movdqu (%rdx,%rax,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%r8,%rax,1),%xmm0
  add    $0x10,%rax
  pcmpeqd %xmm1,%xmm0
  pand   %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L15
  pshufd $0xff,%xmm0,%xmm0
  mov    %r12d,%r9d
  movd   %xmm0,%eax
  cmp    %r12d,%edi
  je     L18
L61:
  movslq %r9d,%rbp
  lea    0x0(,%rbp,4),%r11
  lea    (%rdx,%r11,1),%rbx
  mov    (%rbx),%eax
  imul   %r10d,%eax
  cmp    (%r8,%rbp,4),%eax
  mov    $0x0,%ebp
  cmovne %ebp,%eax
  lea    0x1(%r9),%ebp
  cmp    %edi,%ebp
  jge    L18
  mov    0x4(%rbx),%eax
  imul   %r10d,%eax
  cmp    %eax,0x4(%r8,%r11,1)
  je     L103
  xor    %eax,%eax
L103:
  add    $0x2,%r9d
  cmp    %r9d,%edi
  jle    L18
  mov    0x8(%rbx),%eax
  imul   %r10d,%eax
  cmp    0x8(%r8,%r11,1),%eax
  je     L18
  xor    %eax,%eax
L18:
  add    $0x4,%rsi
  add    %r13,%rdx
  cmp    %r14,%rsi
  jne    L105
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  xor    %r9d,%r9d
  jmp    L61
L98:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test_function(int n, int m, int a[][m], int x[n], int b[m]) {
  int i, j, resultado = 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      resultado = a[i][j] * x[i];
      if (resultado != b[j]) {
        resultado = 0;
      }
    }
  }
  return resultado;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strrev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L8
L7:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L7
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strrev(char *str) {
  size_t start = 0;
  size_t end = strlen(str) - 1;
  char swap;
  while (start < end) {
    swap = str[start];
    str[start] = str[end];
    str[end] = swap;
    start++;
    end--;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strrev>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  test   %rax,%rax
  je     L19
  mov    $0x0,%edx
L16:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %rax,%rdx
  jb     L16
L19:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *strrev(char *str) {
  size_t start = 0;
  size_t end = strlen(str) - 1;
  char swap;
  while (start < end) {
    swap = str[start];
    str[start] = str[end];
    str[end] = swap;
    start++;
    end--;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrev>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  test   %rax,%rax
  je     L15
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl (%r12,%rdx,1),%ecx
  movzbl (%r12,%rax,1),%esi
  mov    %sil,(%r12,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%r12,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rdx
  jb     L9
L15:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strrev(char *str) {
  size_t start = 0;
  size_t end = strlen(str) - 1;
  char swap;
  while (start < end) {
    swap = str[start];
    str[start] = str[end];
    str[end] = swap;
    start++;
    end--;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strrev>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  test   %rax,%rax
  je     L15
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl (%r12,%rdx,1),%ecx
  movzbl (%r12,%rax,1),%esi
  mov    %sil,(%r12,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%r12,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rdx
  jb     L16
L15:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strrev(char *str) {
  size_t start = 0;
  size_t end = strlen(str) - 1;
  char swap;
  while (start < end) {
    swap = str[start];
    str[start] = str[end];
    str[end] = swap;
    start++;
    end--;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_integer_to_float@plt>
  mov    $0x0,%eax
  call   <test_float_to_integer@plt>
  mov    $0x0,%eax
  call   <test_longlong_integer_to_float@plt>
  mov    $0x0,%eax
  call   <test_float_to_longlong_integer@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  test_integer_to_float();
  test_float_to_integer();
  test_longlong_integer_to_float();
  test_float_to_longlong_integer();
  _exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_integer_to_float@plt>
  mov    $0x0,%eax
  call   <test_float_to_integer@plt>
  mov    $0x0,%eax
  call   <test_longlong_integer_to_float@plt>
  mov    $0x0,%eax
  call   <test_float_to_longlong_integer@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  test_integer_to_float();
  test_float_to_integer();
  test_longlong_integer_to_float();
  test_float_to_longlong_integer();
  _exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_integer_to_float@plt>
  xor    %eax,%eax
  call   <test_float_to_integer@plt>
  xor    %eax,%eax
  call   <test_longlong_integer_to_float@plt>
  xor    %eax,%eax
  call   <test_float_to_longlong_integer@plt>
  xor    %edi,%edi
  call   <_exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  test_integer_to_float();
  test_float_to_integer();
  test_longlong_integer_to_float();
  test_float_to_longlong_integer();
  _exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_integer_to_float@plt>
  xor    %eax,%eax
  call   <test_float_to_integer@plt>
  xor    %eax,%eax
  call   <test_longlong_integer_to_float@plt>
  xor    %eax,%eax
  call   <test_float_to_longlong_integer@plt>
  xor    %edi,%edi
  call   <_exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  test_integer_to_float();
  test_float_to_integer();
  test_longlong_integer_to_float();
  test_float_to_longlong_integer();
  _exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_desktop_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <count_desktops@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L4
L40:
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
L4:
  cmpq   $0x0,-0x28(%rbp)
  je     L3
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4d,%al
  je     L40
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x6d,%al
  je     L40
L3:
  movl   $0x0,-0x30(%rbp)
  jmp    L29
L57:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    -0x30(%rbp),%edx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x30(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addl   $0x1,-0x30(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
L29:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L57
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D22
type: string

tool: D22: :

assistant: ```c
char **get_desktop_info(const char *bspwm_output) {
  unsigned int num_of_desktops = count_desktops(bspwm_output);
  char **desktop_info = malloc(sizeof(char *) * num_of_desktops);
  char *tmp = malloc(strlen(bspwm_output));
  strcpy(tmp, bspwm_output + 1);
  char *pch = strtok(tmp, ":");
  for (; pch != NULL && (pch[0] == 'M' || pch[0] == 'm'); pch = strtok(NULL, ":"))
    ;
  for (unsigned int i = 0; i < num_of_desktops; ++i, pch = strtok(NULL, ":")) {
    desktop_info[i] = malloc(strlen(pch) + 1);
    strcpy(desktop_info[i], pch);
  }
  free(tmp);
  return desktop_info;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_desktop_info>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <count_desktops@plt>
  mov    %eax,%r12d
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  lea    0x1(%rbx),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D6(%rip),%rsi
  mov    %r14,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  lea    D6(%rip),%rbp
  test   %rax,%rax
  je     L3
L31:
  movzbl (%rbx),%eax
  and    $0xffffffdf,%eax
  cmp    $0x4d,%al
  jne    L3
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L31
L3:
  test   %r12d,%r12d
  je     L24
  mov    %r15,%rbp
  lea    -0x1(%r12),%eax
  lea    0x8(%r15,%rax,8),%r13
  lea    D6(%rip),%r12
L35:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  mov    %rbx,%rsi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L35
L24:
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: :

assistant: ```c
char **get_desktop_info(const char *bspwm_output) {
  unsigned int num_of_desktops = count_desktops(bspwm_output);
  char **desktop_info = malloc(sizeof(char *) * num_of_desktops);
  char *tmp = malloc(strlen(bspwm_output));
  strcpy(tmp, bspwm_output + 1);
  char *pch = strtok(tmp, ":");
  for (; pch != NULL && (pch[0] == 'M' || pch[0] == 'm'); pch = strtok(NULL, ":"))
    ;
  for (unsigned int i = 0; i < num_of_desktops; ++i, pch = strtok(NULL, ":")) {
    desktop_info[i] = malloc(strlen(pch) + 1);
    strcpy(desktop_info[i], pch);
  }
  free(tmp);
  return desktop_info;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_desktop_info>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <count_desktops@plt>
  lea    0x0(,%rax,8),%edi
  mov    %eax,%r13d
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  lea    0x1(%rbx),%rsi
  lea    D9(%rip),%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L52
  jmp    L4
  nopl   0x0(%rax)
L68:
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
L52:
  movzbl 0x0(%rbp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x4d,%al
  je     L68
L10:
  test   %r13d,%r13d
  je     L2
  lea    -0x1(%r13),%eax
  mov    %r14,%r15
  lea    0x8(%r14,%rax,8),%r13
  xchg   %ax,%ax
L43:
  mov    %rbp,%rdi
  add    $0x8,%r15
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,-0x8(%r15)
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  cmp    %r15,%r13
  jne    L43
L2:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L4:
  xor    %ebp,%ebp
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: :

assistant: ```c
char **get_desktop_info(const char *bspwm_output) {
  unsigned int num_of_desktops = count_desktops(bspwm_output);
  char **desktop_info = malloc(sizeof(char *) * num_of_desktops);
  char *tmp = malloc(strlen(bspwm_output));
  strcpy(tmp, bspwm_output + 1);
  char *pch = strtok(tmp, ":");
  for (; pch != NULL && (pch[0] == 'M' || pch[0] == 'm'); pch = strtok(NULL, ":"))
    ;
  for (unsigned int i = 0; i < num_of_desktops; ++i, pch = strtok(NULL, ":")) {
    desktop_info[i] = malloc(strlen(pch) + 1);
    strcpy(desktop_info[i], pch);
  }
  free(tmp);
  return desktop_info;
}
```