user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  imul   %eax,%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x4(%rsp),%eax
  imul   %eax,%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ebp
  lea    D21(%rip),%r14
  cmpl   $0x0,0x4(%rsp)
  jg     L105
L30:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L196
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L220:
  imul   %ebp,%eax
  add    %ebx,%eax
  cltq
  lea    (%r12,%rax,4),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L220
L3:
  add    $0x1,%ebp
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jle    L156
L105:
  mov    0x4(%rsp),%eax
  mov    $0x0,%ebx
  test   %eax,%eax
  jg     L220
  jmp    L3
L156:
  test   %eax,%eax
  jle    L30
  mov    $0x0,%ebp
  lea    D21(%rip),%r14
  jmp    L67
L155:
  imul   %ebp,%eax
  add    %ebx,%eax
  cltq
  lea    0x0(%r13,%rax,4),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L155
L96:
  add    $0x1,%ebp
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jle    L136
L67:
  mov    0x4(%rsp),%eax
  mov    $0x0,%ebx
  test   %eax,%eax
  jg     L155
  jmp    L96
L136:
  test   %eax,%eax
  jle    L30
  mov    $0x0,%r14d
  lea    D25(%rip),%r15
  jmp    L2
L75:
  mov    0x4(%rsp),%ebx
  add    $0x1,%rbp
  cmp    %ebp,%ebx
  jle    L41
L141:
  test   %ebx,%ebx
  jle    L218
  mov    %ebx,%edx
  imul   %r14d,%edx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rax
  movslq %ebx,%rdi
  shl    $0x2,%rdi
  lea    0x0(%r13,%rbp,4),%rcx
  lea    -0x1(%rbx),%esi
  add    %rsi,%rdx
  lea    0x4(%r12,%rdx,4),%r8
  mov    $0x0,%esi
L167:
  mov    (%rax),%edx
  imul   (%rcx),%edx
  add    %edx,%esi
  add    $0x4,%rax
  add    %rdi,%rcx
  cmp    %rax,%r8
  jne    L167
L90:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L75
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L75
L218:
  mov    $0x0,%esi
  mov    $0x0,%ebx
  jmp    L90
L41:
  add    $0x1,%r14d
  cmp    %r14d,0x4(%rsp)
  jle    L30
L2:
  mov    0x4(%rsp),%ebx
  mov    $0x0,%ebp
  test   %ebx,%ebx
  jg     L141
  jmp    L41
L196:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
datatype: string
name: disassemble_data
arguments: data_tag: D21
datatype: string
name: disassemble_data
arguments: data_tag: D25
datatype: string

tool: D11: %i


tool: D21: %i

tool: D25: %i 

assistant: ```c
int main(int argc, char **argv) {
  int size = 0;
  int i, j, k;
  scanf("%i\n", &size);
  int *matice1 = (int *)malloc(size * size * sizeof(int));
  int *matice2 = (int *)malloc(size * size * sizeof(int));
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      scanf("%i", &matice1[i * size + j]);
    }
  }
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      scanf("%i", &matice2[i * size + j]);
    }
  }
  int sum = 0;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      for (k = 0; k < size; k++) {
        sum += matice1[i * size + k] * matice2[k * size + j];
      }
      printf("%i ", sum);
      sum = 0;
      if (j == k - 1)
        printf("\n");
    }
  }
  free(matice1);
  free(matice2);
  return 0;
}
```