ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x100000,%ebp
  cmp    $0x1,%edi
  jle    L9
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %rax,%rbp
L9:
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0xa,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    $0x6,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x8,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    $0xa,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    $0x9,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x4,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    $0x8,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x6,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x6,%edx
  mov    $0x9,%esi
  call   <EvaluateRS@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  size_t block_size = 1 << 20;
  if (argc > 1) {
    block_size = (size_t)atol(argv[1]);
  }
  EvaluateRS(block_size, 10, 4);
  EvaluateRS(block_size, 6, 3);
  EvaluateRS(block_size, 8, 4);
  EvaluateRS(block_size, 10, 5);
  EvaluateRS(block_size, 9, 3);
  EvaluateRS(block_size, 4, 2);
  EvaluateRS(block_size, 8, 3);
  EvaluateRS(block_size, 6, 4);
  EvaluateRS(block_size, 9, 6);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x100000,%ebp
  cmp    $0x1,%edi
  jle    L6
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %rax,%rbp
L6:
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0xa,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    $0x6,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x8,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    $0xa,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    $0x9,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x4,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    $0x8,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x6,%esi
  call   <EvaluateRS@plt>
  mov    %rbp,%rdi
  mov    $0x6,%edx
  mov    $0x9,%esi
  call   <EvaluateRS@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  size_t block_size = 1 << 20;
  if (argc > 1) {
    block_size = (size_t)atol(argv[1]);
  }
  EvaluateRS(block_size, 10, 4);
  EvaluateRS(block_size, 6, 3);
  EvaluateRS(block_size, 8, 4);
  EvaluateRS(block_size, 10, 5);
  EvaluateRS(block_size, 9, 3);
  EvaluateRS(block_size, 4, 2);
  EvaluateRS(block_size, 8, 3);
  EvaluateRS(block_size, 6, 4);
  EvaluateRS(block_size, 9, 6);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x14,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L5:
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movsd  %xmm2,-0x18(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <calc_factorial@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D3(%rip),%xmm0
  divsd  %xmm1,%xmm0
  addsd  -0x18(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L5
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: f64
name: disassemble_data
arguments: label: D11
type_infered: string

tool: D3: 1

tool: D11: Eular constant is equal to:%f


assistant: ```c
int main(void) {
  int terms = 20;
  float eular = 0;
  int counter = 0;
  for (counter = 0; counter < terms; counter++) {
    eular = eular + 1. / calc_factorial(counter);
  }
  printf("Eular constant is equal to:%f\n", eular);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    $0x0,%ebx
  pxor   %xmm3,%xmm3
  movss  %xmm3,0xc(%rsp)
L5:
  mov    %ebx,%edi
  call   <calc_factorial@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D16(%rip),%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsd2ss %xmm0,%xmm2
  movss  %xmm2,0xc(%rsp)
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L5
  movaps %xmm2,%xmm0
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type_infered: f64
name: read_data
arguments: data_label: D11
type_infered: string

tool: D16: 1

tool: D11: Eular constant is equal to:%f


assistant: ```c
int main(void) {
  int terms = 20;
  float eular = 0;
  int counter = 0;
  for (counter = 0; counter < terms; counter++) {
    eular = eular + 1. / calc_factorial(counter);
  }
  printf("Eular constant is equal to:%f\n", eular);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  pxor   %xmm0,%xmm0
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  nop
L4:
  mov    %ebx,%edi
  movss  %xmm0,0xc(%rsp)
  add    $0x1,%ebx
  call   <calc_factorial@plt>
  pxor   %xmm2,%xmm2
  movsd  D6(%rip),%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2sd %eax,%xmm2
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cmp    $0x14,%ebx
  jne    L4
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D6
datatype: f64
name: read_data
arguments: tag: D2
datatype: string

tool: D6: 1

tool: D2: Eular constant is equal to:%f


assistant: ```c
int main(void) {
  int terms = 20;
  float eular = 0;
  int counter = 0;
  for (counter = 0; counter < terms; counter++) {
    eular = eular + 1. / calc_factorial(counter);
  }
  printf("Eular constant is equal to:%f\n", eular);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  pxor   %xmm0,%xmm0
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  nop
L4:
  mov    %ebx,%edi
  movss  %xmm0,0xc(%rsp)
  add    $0x1,%ebx
  call   <calc_factorial@plt>
  pxor   %xmm2,%xmm2
  movsd  D7(%rip),%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2sd %eax,%xmm2
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cmp    $0x14,%ebx
  jne    L4
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: f64
name: retrieve_data
arguments: label: D16
data_type: string

tool: D7: 1

tool: D16: Eular constant is equal to:%f


assistant: ```c
int main(void) {
  int terms = 20;
  float eular = 0;
  int counter = 0;
  for (counter = 0; counter < terms; counter++) {
    eular = eular + 1. / calc_factorial(counter);
  }
  printf("Eular constant is equal to:%f\n", eular);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_cmdstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D35(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strmi@plt>
  test   %rax,%rax
  je     L15
  mov    $0x1,%eax
  jmp    L36
L15:
  mov    -0x10(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strmi@plt>
  test   %rax,%rax
  je     L20
  mov    $0x1,%eax
  jmp    L36
L20:
  mov    -0x10(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strmi@plt>
  test   %rax,%rax
  je     L17
  mov    $0x1,%eax
  jmp    L36
L17:
  mov    -0x4(%rbp),%eax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <syntax_err@plt>
  mov    $0x0,%eax
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D35
datatype: string
name: read_data
arguments: data_tag: D31
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D23
datatype: string

tool: D35: set

tool: D31: add

tool: D1: die

tool: D23: Invalid command

assistant: ```c
int check_cmdstr(int line, char *cmd) {
  if (strmi(cmd, "set"))
    return 1;
  if (strmi(cmd, "add"))
    return 1;
  if (strmi(cmd, "die"))
    return 1;
  syntax_err(line, "Invalid command");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_cmdstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  lea    D38(%rip),%rsi
  mov    %rbx,%rdi
  call   <strmi@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L17
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  call   <strmi@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L32
  lea    D29(%rip),%rsi
  mov    %rbx,%rdi
  call   <strmi@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L32
  lea    D18(%rip),%rsi
  mov    %ebp,%edi
  call   <syntax_err@plt>
  mov    $0x0,%eax
  jmp    L32
```

tool_calls: name: unpack_data
arguments: data_tag: D38
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string
name: unpack_data
arguments: data_tag: D29
datatype: string
name: unpack_data
arguments: data_tag: D18
datatype: string

tool: D38: set

tool: D28: add

tool: D29: die

tool: D18: Invalid command

assistant: ```c
int check_cmdstr(int line, char *cmd) {
  if (strmi(cmd, "set"))
    return 1;
  if (strmi(cmd, "add"))
    return 1;
  if (strmi(cmd, "die"))
    return 1;
  syntax_err(line, "Invalid command");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_cmdstr>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  lea    D33(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strmi@plt>
  test   %rax,%rax
  je     L27
L8:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strmi@plt>
  test   %rax,%rax
  jne    L8
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  call   <strmi@plt>
  test   %rax,%rax
  jne    L8
  mov    %r12d,%edi
  lea    D3(%rip),%rsi
  call   <syntax_err@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D33
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string

tool: D33: set

tool: D7: add

tool: D28: die

tool: D3: Invalid command

assistant: ```c
int check_cmdstr(int line, char *cmd) {
  if (strmi(cmd, "set"))
    return 1;
  if (strmi(cmd, "add"))
    return 1;
  if (strmi(cmd, "die"))
    return 1;
  syntax_err(line, "Invalid command");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_cmdstr>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strmi@plt>
  test   %rax,%rax
  je     L25
L8:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strmi@plt>
  test   %rax,%rax
  jne    L8
  lea    D35(%rip),%rsi
  mov    %rbp,%rdi
  call   <strmi@plt>
  test   %rax,%rax
  jne    L8
  mov    %r12d,%edi
  lea    D5(%rip),%rsi
  call   <syntax_err@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D35
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D17: set

tool: D14: add

tool: D35: die

tool: D5: Invalid command

assistant: ```c
int check_cmdstr(int line, char *cmd) {
  if (strmi(cmd, "set"))
    return 1;
  if (strmi(cmd, "add"))
    return 1;
  if (strmi(cmd, "die"))
    return 1;
  syntax_err(line, "Invalid command");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,-0x18(%rbp)
  movq   $0xffffffffffffffff,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D9
data_type: string
name: disassemble_data
arguments: tag: D36
data_type: string
name: disassemble_data
arguments: tag: D4
data_type: string

tool: D7: %p


tool: D9: %Lx

tool: D36: 123456789

tool: D4: val = %Lx


assistant: ```c
int main(void) {
  unsigned long long val = -1;
  void *ptr = (void *)-1;
  printf("%p\n", ptr);
  sscanf("123456789", "%Lx", &val);
  printf("val = %Lx\n", val);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  mov    $0xffffffffffffffff,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdx
  lea    D39(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <sscanf@plt>
  mov    (%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D39
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D2: %p


tool: D39: %Lx

tool: D8: 123456789

tool: D4: val = %Lx


assistant: ```c
int main(void) {
  unsigned long long val = -1;
  void *ptr = (void *)-1;
  printf("%p\n", ptr);
  sscanf("123456789", "%Lx", &val);
  printf("val = %Lx\n", val);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xffffffffffffffff,%rsi
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  call   <printf@plt>
  lea    D18(%rip),%rsi
  lea    D13(%rip),%rdi
  mov    %rsp,%rdx
  call   <sscanf@plt>
  mov    (%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D24
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D13
data_type: string
name: disassemble_data
arguments: label: D27
data_type: string

tool: D24: %p


tool: D18: %Lx

tool: D13: 123456789

tool: D27: val = %Lx


assistant: ```c
int main(void) {
  unsigned long long val = -1;
  void *ptr = (void *)-1;
  printf("%p\n", ptr);
  sscanf("123456789", "%Lx", &val);
  printf("val = %Lx\n", val);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xffffffffffffffff,%rsi
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  call   <printf@plt>
  lea    D17(%rip),%rsi
  lea    D22(%rip),%rdi
  mov    %rsp,%rdx
  call   <sscanf@plt>
  mov    (%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D27
datatype: string
name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D4
datatype: string

tool: D27: %p


tool: D17: %Lx

tool: D22: 123456789

tool: D4: val = %Lx


assistant: ```c
int main(void) {
  unsigned long long val = -1;
  void *ptr = (void *)-1;
  printf("%p\n", ptr);
  sscanf("123456789", "%Lx", &val);
  printf("val = %Lx\n", val);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <binary@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D1: Allocatin Error.


tool: D6: Binary Numbers:


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  int *vet;
  n = atoi(argv[1]);
  vet = (int *)malloc(n * sizeof(int));
  if (vet == NULL) {
    printf("Allocatin Error.\n");
    exit(1);
  }
  printf("Binary Numbers:\n");
  binary(vet, n, 0);
  free(vet);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
L1:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <binary@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string
name: retrieve_data
arguments: data_label: D9
type: string

tool: D0: Binary Numbers:


tool: D9: Allocatin Error.


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  int *vet;
  n = atoi(argv[1]);
  vet = (int *)malloc(n * sizeof(int));
  if (vet == NULL) {
    printf("Allocatin Error.\n");
    exit(1);
  }
  printf("Binary Numbers:\n");
  binary(vet, n, 0);
  free(vet);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    0x0(,%rax,4),%edi
  mov    %eax,%r12d
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L2
L4:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <binary@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D0: Binary Numbers:


tool: D19: Allocatin Error.


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  int *vet;
  n = atoi(argv[1]);
  vet = (int *)malloc(n * sizeof(int));
  if (vet == NULL) {
    printf("Allocatin Error.\n");
    exit(1);
  }
  printf("Binary Numbers:\n");
  binary(vet, n, 0);
  free(vet);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    0x0(,%rax,4),%edi
  mov    %eax,%r12d
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L10
L17:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <binary@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L10:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D11: Binary Numbers:


tool: D1: Allocatin Error.


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  int *vet;
  n = atoi(argv[1]);
  vet = (int *)malloc(n * sizeof(int));
  if (vet == NULL) {
    printf("Allocatin Error.\n");
    exit(1);
  }
  printf("Binary Numbers:\n");
  binary(vet, n, 0);
  free(vet);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lngpio_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%ecx
  lea    D2(%rip),%rdx
  mov    $0x1e,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x30(%rbp),%rax
  lea    D24(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x3c(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D21(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x3c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string
name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D21
type: string

tool: D2: /sys/class/gpio/gpio%d/value

tool: D24: rw

tool: D21: %d

assistant: ```c
int lngpio_read(int pin) {
  char path[30];
  FILE *f;
  int result;
  snprintf(path, 30, "/sys/class/gpio/gpio%d/value", pin);
  f = fopen(path, "rw");
  fscanf(f, "%d", &result);
  fclose(f);
  return result;
}
```