ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<cas>:
  endbr64
  mov    %esi,%eax
  lock cmpxchg %edx,(%rdi)
  sete   %dl
  movzbl %dl,%eax
  ret
```

assistant: ```c
int cas(volatile int *addr, int expected, int newval) {
  unsigned char result;
  asm volatile("lock; cmpxchg %3, %1\n"
               "sete %b0\n"
               : "=r"(result), "+m"(*addr), "+a"(expected)
               : "r"(newval)
               : "memory", "cc");
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ssim_end4_10b>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L9
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    -0x1(%rdx),%eax
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%r12
  pxor   %xmm2,%xmm2
  movss  %xmm2,0xc(%rsp)
L28:
  mov    0x1c(%rbx),%ecx
  add    0xc(%rbx),%ecx
  add    0xc(%rbp),%ecx
  add    0x1c(%rbp),%ecx
  mov    0x18(%rbx),%edx
  add    0x8(%rbx),%edx
  add    0x8(%rbp),%edx
  add    0x18(%rbp),%edx
  mov    0x14(%rbx),%esi
  add    0x4(%rbx),%esi
  add    0x4(%rbp),%esi
  add    0x14(%rbp),%esi
  mov    0x10(%rbx),%edi
  add    (%rbx),%edi
  add    0x0(%rbp),%edi
  add    0x10(%rbp),%edi
  call   <ssim_end1_10b@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  add    $0x10,%rbx
  add    $0x10,%rbp
  cmp    %r12,%rbx
  jne    L28
L12:
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  pxor   %xmm3,%xmm3
  movss  %xmm3,0xc(%rsp)
  jmp    L12
```

assistant: ```c
float ssim_end4_10b(int sum0[5][4], int sum1[5][4], int width) {
  float ssim = 0.0;
  for (int i = 0; i < width; i++)
    ssim += ssim_end1_10b(sum0[i][0] + sum0[i + 1][0] + sum1[i][0] + sum1[i + 1][0], sum0[i][1] + sum0[i + 1][1] + sum1[i][1] + sum1[i + 1][1], sum0[i][2] + sum0[i + 1][2] + sum1[i][2] + sum1[i + 1][2], sum0[i][3] + sum0[i + 1][3] + sum1[i][3] + sum1[i + 1][3]);
  return ssim;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ssim_end4_10b>:
  endbr64
  test   %edx,%edx
  jle    L11
  push   %r12
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  push   %rbp
  shl    $0x4,%rax
  mov    %rsi,%rbp
  push   %rbx
  lea    0x10(%rdi,%rax,1),%r12
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x1c(%rbx),%ecx
  mov    0x18(%rbx),%edx
  movss  %xmm0,0xc(%rsp)
  add    $0x10,%rbx
  add    -0x4(%rbx),%ecx
  add    -0x8(%rbx),%edx
  add    $0x10,%rbp
  add    -0x4(%rbp),%ecx
  add    -0x8(%rbp),%edx
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  add    -0xc(%rbx),%esi
  add    -0x10(%rbx),%edi
  add    -0xc(%rbp),%esi
  add    -0x10(%rbp),%edi
  add    0xc(%rbp),%ecx
  add    0x8(%rbp),%edx
  add    0x4(%rbp),%esi
  add    0x0(%rbp),%edi
  call   <ssim_end1_10b@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rbx,%r12
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float ssim_end4_10b(int sum0[5][4], int sum1[5][4], int width) {
  float ssim = 0.0;
  for (int i = 0; i < width; i++)
    ssim += ssim_end1_10b(sum0[i][0] + sum0[i + 1][0] + sum1[i][0] + sum1[i + 1][0], sum0[i][1] + sum0[i + 1][1] + sum1[i][1] + sum1[i + 1][1], sum0[i][2] + sum0[i + 1][2] + sum1[i][2] + sum1[i + 1][2], sum0[i][3] + sum0[i + 1][3] + sum1[i][3] + sum1[i + 1][3]);
  return ssim;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ssim_end4_10b>:
  endbr64
  test   %edx,%edx
  jle    L2
  push   %r12
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  push   %rbp
  shl    $0x4,%rax
  mov    %rsi,%rbp
  push   %rbx
  lea    0x10(%rdi,%rax,1),%r12
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x1c(%rbx),%ecx
  mov    0x18(%rbx),%edx
  movss  %xmm0,0xc(%rsp)
  add    $0x10,%rbx
  add    -0x4(%rbx),%ecx
  add    -0x8(%rbx),%edx
  add    $0x10,%rbp
  add    -0x4(%rbp),%ecx
  add    -0x8(%rbp),%edx
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  add    -0xc(%rbx),%esi
  add    -0x10(%rbx),%edi
  add    -0xc(%rbp),%esi
  add    -0x10(%rbp),%edi
  add    0xc(%rbp),%ecx
  add    0x8(%rbp),%edx
  add    0x4(%rbp),%esi
  add    0x0(%rbp),%edi
  call   <ssim_end1_10b@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rbx,%r12
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float ssim_end4_10b(int sum0[5][4], int sum1[5][4], int width) {
  float ssim = 0.0;
  for (int i = 0; i < width; i++)
    ssim += ssim_end1_10b(sum0[i][0] + sum0[i + 1][0] + sum1[i][0] + sum1[i + 1][0], sum0[i][1] + sum0[i + 1][1] + sum1[i][1] + sum1[i + 1][1], sum0[i][2] + sum0[i + 1][2] + sum1[i][2] + sum1[i + 1][2], sum0[i][3] + sum0[i + 1][3] + sum1[i][3] + sum1[i + 1][3]);
  return ssim;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    $0xa,%edx
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D3: hello

assistant: ```c
int main(void) {
  char dst[10];
  strlcpy(dst, "hello", 10);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  mov    $0xa,%edx
  lea    D0(%rip),%rsi
  call   <strlcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: hello

assistant: ```c
int main(void) {
  char dst[10];
  strlcpy(dst, "hello", 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xa,%edx
  lea    D4(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <strlcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: hello

assistant: ```c
int main(void) {
  char dst[10];
  strlcpy(dst, "hello", 10);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xa,%edx
  lea    D2(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <strlcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D2: hello

assistant: ```c
int main(void) {
  char dst[10];
  strlcpy(dst, "hello", 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L25
L4:
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L73:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L17
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x18(%rbp)
  jmp    L78
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L78
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x14(%rbp)
L78:
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L73
  addl   $0x1,-0x10(%rbp)
L25:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L4
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D18
type_guessed: string

tool: D16: %d

tool: D18: %d
%d

assistant: ```c
int main() {
  int up = 0, down = 0, i, j, n, temp;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", &temp);
      if (j > i) {
        up += temp;
      } else if (j < i) {
        down += temp;
      }
    }
  }
  printf("%d\n%d", up, down);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
  mov    $0x0,%r14d
  mov    $0x0,%r12d
  lea    D28(%rip),%r13
  cmpl   $0x0,(%rsp)
  jg     L46
L81:
  mov    %r14d,%edx
  mov    %r12d,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  jle    L86
  add    0x4(%rsp),%r14d
L86:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jle    L37
L71:
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    %ebx,%ebp
  jge    L0
  add    0x4(%rsp),%r12d
  jmp    L86
L37:
  add    $0x1,%ebp
  cmp    %ebp,(%rsp)
  jle    L81
L46:
  mov    $0x0,%ebx
  cmpl   $0x0,(%rsp)
  jg     L71
  jmp    L37
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D28
type: string
name: read_data
arguments: data_label: D27
type: string

tool: D28: %d

tool: D27: %d
%d

assistant: ```c
int main() {
  int up = 0, down = 0, i, j, n, temp;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", &temp);
      if (j > i) {
        up += temp;
      } else if (j < i) {
        down += temp;
      }
    }
  }
  printf("%d\n%d", up, down);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L40
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  lea    0x4(%rsp),%r14
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L44:
  xor    %ebx,%ebx
  jmp    L77
  nopl   0x0(%rax)
L15:
  add    0x4(%rsp),%r12d
L29:
  mov    (%rsp),%eax
  add    $0x1,%ebx
  cmp    %ebx,%eax
  jle    L47
L77:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    %ebp,%ebx
  jg     L15
  jge    L29
  mov    (%rsp),%eax
  add    $0x1,%ebx
  add    0x4(%rsp),%r15d
  cmp    %ebx,%eax
  jg     L77
L47:
  add    $0x1,%ebp
  cmp    %ebp,%eax
  jle    L20
  test   %eax,%eax
  jg     L44
L20:
  mov    %r15d,%edx
  mov    %r12d,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  xor    %r15d,%r15d
  xor    %r12d,%r12d
  jmp    L20
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D9: %d

tool: D2: %d
%d

assistant: ```c
int main() {
  int up = 0, down = 0, i, j, n, temp;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", &temp);
      if (j > i) {
        up += temp;
      } else if (j < i) {
        down += temp;
      }
    }
  }
  printf("%d\n%d", up, down);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L18
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  lea    0x4(%rsp),%r14
  xor    %r12d,%r12d
  xchg   %ax,%ax
L47:
  xor    %ebx,%ebx
  jmp    L57
  nopl   0x0(%rax)
L19:
  add    0x4(%rsp),%r12d
L54:
  mov    (%rsp),%eax
  add    $0x1,%ebx
  cmp    %ebx,%eax
  jle    L77
L57:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    %ebx,%ebp
  jl     L19
  jle    L54
  mov    (%rsp),%eax
  add    $0x1,%ebx
  add    0x4(%rsp),%r15d
  cmp    %ebx,%eax
  jg     L57
L77:
  add    $0x1,%ebp
  cmp    %ebp,%eax
  jg     L47
L18:
  mov    %r15d,%edx
  mov    %r12d,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string
name: disassemble_data
arguments: label: D13
data_type: string

tool: D5: %d

tool: D13: %d
%d

assistant: ```c
int main() {
  int up = 0, down = 0, i, j, n, temp;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", &temp);
      if (j > i) {
        up += temp;
      } else if (j < i) {
        down += temp;
      }
    }
  }
  printf("%d\n%d", up, down);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  cmpl   $0x9,-0x4(%rbp)
  jg     L10
  cmpl   $0xfffffff7,-0x4(%rbp)
  jge    L37
L10:
  mov    $0x0,%eax
  jmp    L13
L32:
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    $0x63,%eax
  jle    L32
  cmpl   $0xa,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  if (!(i < 10 && i > -10))
    return 0;
  while (i * i < 100) {
    i = i + 1;
  }
  assert(i == 10);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
L8:
  add    $0x1,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x63,%edx
  jle    L8
  cmp    $0xa,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  if (!(i < 10 && i > -10))
    return 0;
  while (i * i < 100) {
    i = i + 1;
  }
  assert(i == 10);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x1,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x63,%edx
  jle    L7
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

assistant: ```c
int main() {
  int i;
  if (!(i < 10 && i > -10))
    return 0;
  while (i * i < 100) {
    i = i + 1;
  }
  assert(i == 10);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x63,%edx
  jle    L8
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

assistant: ```c
int main() {
  int i;
  if (!(i < 10 && i > -10))
    return 0;
  while (i * i < 100) {
    i = i + 1;
  }
  assert(i == 10);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D41(%rip),%rax
  mov    %rax,-0x70(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x68(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x60(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x58(%rbp)
  lea    D99(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D63(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D31(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D142(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x70(%rbp),%rax
  mov    $0xc,%ecx
  mov    $0x0,%edx
  lea    D99(%rip),%rsi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D133(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D41
datatype: string
name: unpack_data
arguments: tag: D142
datatype: string
name: unpack_data
arguments: tag: D99
datatype: string
name: unpack_data
arguments: tag: D63
datatype: string
name: unpack_data
arguments: tag: D31
datatype: string
name: unpack_data
arguments: tag: D133
datatype: string

tool: D41: at

tool: 

tool: D99: ball

tool: D63: car

tool: D31: dad

tool: D133: %d


assistant: ```c
main() {
  char *s[] = {"at", "", "", "", "ball", "", "", "car", "", "", "dad", "", ""};
  printf("%d\n", search(s, "ball", 0, 12));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,(%rsp)
  lea    D6(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  lea    D16(%rip),%rsi
  mov    %rsi,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  mov    %rax,0x30(%rsp)
  lea    D3(%rip),%rdx
  mov    %rdx,0x38(%rsp)
  mov    %rax,0x40(%rsp)
  mov    %rax,0x48(%rsp)
  lea    D1(%rip),%rcx
  mov    %rcx,0x50(%rsp)
  mov    %rax,0x58(%rsp)
  mov    %rax,0x60(%rsp)
  mov    %rsp,%rdi
  mov    $0xc,%ecx
  mov    $0x0,%edx
  call   <search@plt>
  mov    %eax,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D22
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string
name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D44
data_type: string

tool: D22: at

tool: 

tool: D16: ball

tool: D3: car

tool: D1: dad

tool: D44: %d


assistant: ```c
main() {
  char *s[] = {"at", "", "", "", "ball", "", "", "car", "", "", "dad", "", ""};
  printf("%d\n", search(s, "ball", 0, 12));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  lea    D46(%rip),%rdx
  lea    D27(%rip),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  lea    D21(%rip),%rax
  lea    D29(%rip),%rsi
  mov    %rdx,0x38(%rsp)
  mov    %rsp,%rdi
  mov    %rcx,0x50(%rsp)
  xor    %edx,%edx
  mov    $0xc,%ecx
  mov    %rsi,0x20(%rsp)
  mov    %rax,(%rsp)
  lea    D1(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rax,0x28(%rsp)
  mov    %rax,0x30(%rsp)
  mov    %rax,0x40(%rsp)
  mov    %rax,0x48(%rsp)
  mov    %rax,0x58(%rsp)
  mov    %rax,0x60(%rsp)
  call   <search@plt>
  lea    D37(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D46
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string
name: unpack_data
arguments: label: D21
type_guessed: string
name: unpack_data
arguments: label: D29
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D37
type_guessed: string

tool: D46: car

tool: D27: dad

tool: D21: at

tool: D29: ball

tool: 

tool: D37: %d


assistant: ```c
main() {
  char *s[] = {"at", "", "", "", "ball", "", "", "car", "", "", "dad", "", ""};
  printf("%d\n", search(s, "ball", 0, 12));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  lea    D5(%rip),%rsi
  xor    %edx,%edx
  mov    $0xc,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  lea    D57(%rip),%rax
  mov    %rsp,%rdi
  movq   %rax,%xmm0
  movq   %rax,%xmm2
  lea    D40(%rip),%rax
  movq   %rax,%xmm1
  lea    D54(%rip),%rax
  punpcklqdq %xmm2,%xmm2
  movq   %xmm0,0x60(%rsp)
  punpcklqdq %xmm0,%xmm1
  movq   %rax,%xmm3
  movaps %xmm2,0x10(%rsp)
  lea    D17(%rip),%rax
  movaps %xmm1,(%rsp)
  movq   %rsi,%xmm1
  punpcklqdq %xmm0,%xmm1
  movaps %xmm2,0x40(%rsp)
  movaps %xmm1,0x20(%rsp)
  movdqa %xmm0,%xmm1
  punpcklqdq %xmm3,%xmm1
  movaps %xmm1,0x30(%rsp)
  movq   %rax,%xmm1
  punpcklqdq %xmm0,%xmm1
  movaps %xmm1,0x50(%rsp)
  call   <search@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D57
type: string
name: parse_data
arguments: label: D40
type: string
name: parse_data
arguments: label: D54
type: string
name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D12
type: string

tool: D5: ball

tool: 

tool: D40: at

tool: D54: car

tool: D17: dad

tool: D12: %d


assistant: ```c
main() {
  char *s[] = {"at", "", "", "", "ball", "", "", "car", "", "", "dad", "", ""};
  printf("%d\n", search(s, "ball", 0, 12));
  return 0;
}
```