ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<rec_sahaHeI>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm2,0x18(%rsp)
  addsd  D10(%rip),%xmm3
  movapd %xmm1,%xmm4
  mulsd  %xmm3,%xmm4
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  cvttsd2si %xmm4,%edi
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm4
  movapd %xmm4,%xmm1
  mulsd  D2(%rip),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  movsd  D52(%rip),%xmm0
  divsd  %xmm4,%xmm0
  cvttsd2si %xmm0,%edi
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  divsd  0x10(%rsp),%xmm1
  movsd  D64(%rip),%xmm3
  mulsd  %xmm3,%xmm1
  movsd  D10(%rip),%xmm5
  addsd  %xmm1,%xmm5
  movapd %xmm1,%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x18(%rsp),%xmm6
  mulsd  %xmm6,%xmm0
  divsd  %xmm5,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm3,%xmm1
  mulsd  %xmm6,%xmm1
  divsd  %xmm5,%xmm1
  divsd  %xmm5,%xmm1
  addsd  D10(%rip),%xmm1
  cvttsd2si %xmm1,%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  D10(%rip),%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  addsd  D10(%rip),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D10
datatype: f64
name: read_data
arguments: label: D2
datatype: f64
name: read_data
arguments: label: D52
datatype: byte[8]
name: read_data
arguments: label: D64
datatype: f64

tool: D10: 1

tool: D2: 2.414194e+21

tool: {"D52": [0x00,0x00,0x00,0x00,0x34,0x6a,0x11,0xc1]}

tool: D64: 4

assistant: ```c
double rec_sahaHeI(double nH0, double Tr0, double fHe, double z) {
  double Tr, nH, ainv, s, q;
  Tr = Tr0 * (ainv = 1 + z);
  nH = nH0 * ainv * ainv * ainv;
  s = 2.414194e21 * Tr * sqrt(Tr) * exp(-285325. / Tr) / nH * 4.;
  q = 2. * s * fHe / (1. + s) / (1. + sqrt(1. + 4. * s * fHe / (1. + s) / (1. + s)));
  return (1. + q);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rec_sahaHeI>:
  endbr64
  sub    $0x28,%rsp
  addsd  D66(%rip),%xmm3
  movsd  %xmm2,0x18(%rsp)
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm0
  cvttsd2si %xmm1,%edi
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,0x10(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  movsd  D17(%rip),%xmm3
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm3
  movsd  D72(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  cvttsd2si %xmm0,%edi
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  D57(%rip),%xmm4
  movsd  D66(%rip),%xmm3
  movsd  0x18(%rsp),%xmm2
  mulsd  %xmm0,%xmm1
  divsd  0x10(%rsp),%xmm1
  mulsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm1,%xmm3
  addsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  divsd  %xmm3,%xmm0
  divsd  %xmm3,%xmm1
  movsd  %xmm0,0x8(%rsp)
  divsd  %xmm3,%xmm1
  addsd  D66(%rip),%xmm1
  cvttsd2si %xmm1,%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %eax,%xmm1
  addsd  D66(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  D66(%rip),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D66
type_guessed: f64
name: disassemble_data
arguments: tag: D17
type_guessed: f64
name: disassemble_data
arguments: tag: D72
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D57
type_guessed: f64

tool: D66: 1

tool: D17: 2.414194e+21

tool: {"D72": [0x00,0x00,0x00,0x00,0x34,0x6a,0x11,0xc1]}

tool: D57: 4

assistant: ```c
double rec_sahaHeI(double nH0, double Tr0, double fHe, double z) {
  double Tr, nH, ainv, s, q;
  Tr = Tr0 * (ainv = 1 + z);
  nH = nH0 * ainv * ainv * ainv;
  s = 2.414194e21 * Tr * sqrt(Tr) * exp(-285325. / Tr) / nH * 4.;
  q = 2. * s * fHe / (1. + s) / (1. + sqrt(1. + 4. * s * fHe / (1. + s) / (1. + s)));
  return (1. + q);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rec_sahaHeI>:
  endbr64
  sub    $0x28,%rsp
  addsd  D3(%rip),%xmm3
  movsd  %xmm2,0x18(%rsp)
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm0
  cvttsd2si %xmm1,%edi
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,0x10(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  movsd  D7(%rip),%xmm3
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm3
  movsd  D33(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  cvttsd2si %xmm0,%edi
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  D55(%rip),%xmm4
  movsd  D3(%rip),%xmm3
  movsd  0x18(%rsp),%xmm2
  mulsd  %xmm0,%xmm1
  divsd  0x10(%rsp),%xmm1
  mulsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm1,%xmm3
  addsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  divsd  %xmm3,%xmm0
  divsd  %xmm3,%xmm1
  movsd  %xmm0,0x8(%rsp)
  divsd  %xmm3,%xmm1
  addsd  D3(%rip),%xmm1
  cvttsd2si %xmm1,%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %eax,%xmm1
  addsd  D3(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  D3(%rip),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: f64
name: read_data
arguments: data_tag: D7
data_type: f64
name: read_data
arguments: data_tag: D33
data_type: byte[8]
name: read_data
arguments: data_tag: D55
data_type: f64

tool: D3: 1

tool: D7: 2.414194e+21

tool: {"D33": [0x00,0x00,0x00,0x00,0x34,0x6a,0x11,0xc1]}

tool: D55: 4

assistant: ```c
double rec_sahaHeI(double nH0, double Tr0, double fHe, double z) {
  double Tr, nH, ainv, s, q;
  Tr = Tr0 * (ainv = 1 + z);
  nH = nH0 * ainv * ainv * ainv;
  s = 2.414194e21 * Tr * sqrt(Tr) * exp(-285325. / Tr) / nH * 4.;
  q = 2. * s * fHe / (1. + s) / (1. + sqrt(1. + 4. * s * fHe / (1. + s) / (1. + s)));
  return (1. + q);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x1fff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xd,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltd
  shr    $0x13,%edx
  add    %edx,%eax
  and    $0x1fff,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xd,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x8,%edx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: Virtual Address: 0x%x
Page Size: %dKB
Page Number: 0x%x
Offset: 0x%x


assistant: ```c
void getInfo(const char *virtualAddress) {
  int address = (int)strtol(virtualAddress, NULL, 0);
  int pageNumber = address / 8192;
  int offset = address % 8192;
  int virtual = 8192 * pageNumber + offset;
  printf("Virtual Address: 0x%x\nPage Size: %dKB\nPage Number: 0x%x\nOffset: 0x%x\n", virtual, 8192 / 1024, pageNumber, offset);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getInfo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%esi
  cltd
  shr    $0x13,%edx
  lea    (%rdx,%rax,1),%r8d
  and    $0x1fff,%r8d
  lea    0x1fff(%rax),%ecx
  test   %eax,%eax
  cmovns %eax,%ecx
  sar    $0xd,%ecx
  sub    %edx,%r8d
  mov    $0x8,%edx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: Virtual Address: 0x%x
Page Size: %dKB
Page Number: 0x%x
Offset: 0x%x


assistant: ```c
void getInfo(const char *virtualAddress) {
  int address = (int)strtol(virtualAddress, NULL, 0);
  int pageNumber = address / 8192;
  int offset = address % 8192;
  int virtual = 8192 * pageNumber + offset;
  printf("Virtual Address: 0x%x\nPage Size: %dKB\nPage Number: 0x%x\nOffset: 0x%x\n", virtual, 8192 / 1024, pageNumber, offset);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getInfo>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  lea    D5(%rip),%rdi
  cltd
  lea    0x1fff(%rax),%ecx
  mov    %eax,%esi
  shr    $0x13,%edx
  lea    (%rdx,%rax,1),%r8d
  and    $0x1fff,%r8d
  test   %eax,%eax
  cmovns %eax,%ecx
  sub    %edx,%r8d
  add    $0x8,%rsp
  mov    $0x8,%edx
  sar    $0xd,%ecx
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: Virtual Address: 0x%x
Page Size: %dKB
Page Number: 0x%x
Offset: 0x%x


assistant: ```c
void getInfo(const char *virtualAddress) {
  int address = (int)strtol(virtualAddress, NULL, 0);
  int pageNumber = address / 8192;
  int offset = address % 8192;
  int virtual = 8192 * pageNumber + offset;
  printf("Virtual Address: 0x%x\nPage Size: %dKB\nPage Number: 0x%x\nOffset: 0x%x\n", virtual, 8192 / 1024, pageNumber, offset);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getInfo>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  lea    D0(%rip),%rdi
  cltd
  lea    0x1fff(%rax),%ecx
  mov    %eax,%esi
  shr    $0x13,%edx
  lea    (%rdx,%rax,1),%r8d
  and    $0x1fff,%r8d
  test   %eax,%eax
  cmovns %eax,%ecx
  sub    %edx,%r8d
  add    $0x8,%rsp
  mov    $0x8,%edx
  sar    $0xd,%ecx
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: Virtual Address: 0x%x
Page Size: %dKB
Page Number: 0x%x
Offset: 0x%x


assistant: ```c
void getInfo(const char *virtualAddress) {
  int address = (int)strtol(virtualAddress, NULL, 0);
  int pageNumber = address / 8192;
  int offset = address % 8192;
  int virtual = 8192 * pageNumber + offset;
  printf("Virtual Address: 0x%x\nPage Size: %dKB\nPage Number: 0x%x\nOffset: 0x%x\n", virtual, 8192 / 1024, pageNumber, offset);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rrdMHz_Maxilife>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L53
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L53
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L53
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L53
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L53
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L53
  mov    $0x0,%eax
  jmp    L17
L53:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rrdF2@plt>
L17:
  leave
  ret
```

assistant: ```c
const char *rrdMHz_Maxilife(const double values[]) {
  if (!values[0] && !values[1] && !values[2])
    return NULL;
  return rrdF2(values);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rrdMHz_Maxilife>:
  endbr64
  pxor   %xmm0,%xmm0
  ucomisd (%rdi),%xmm0
  jp     L25
  jne    L25
  ucomisd 0x8(%rdi),%xmm0
  jp     L25
  jne    L25
  ucomisd 0x10(%rdi),%xmm0
  jp     L25
  je     L28
L25:
  sub    $0x8,%rsp
  call   <rrdF2@plt>
  add    $0x8,%rsp
  ret
L28:
  mov    $0x0,%eax
  ret
```

assistant: ```c
const char *rrdMHz_Maxilife(const double values[]) {
  if (!values[0] && !values[1] && !values[2])
    return NULL;
  return rrdF2(values);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rrdMHz_Maxilife>:
  endbr64
  pxor   %xmm0,%xmm0
  ucomisd (%rdi),%xmm0
  jp     L21
  jne    L21
  ucomisd 0x8(%rdi),%xmm0
  jp     L21
  jne    L21
  ucomisd 0x10(%rdi),%xmm0
  jp     L21
  je     L55
L21:
  jmp    1050 <rrdF2@plt>
  nopw   0x0(%rax,%rax,1)
L55:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *rrdMHz_Maxilife(const double values[]) {
  if (!values[0] && !values[1] && !values[2])
    return NULL;
  return rrdF2(values);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rrdMHz_Maxilife>:
  endbr64
  pxor   %xmm0,%xmm0
  ucomisd (%rdi),%xmm0
  jp     L45
  jne    L45
  ucomisd 0x8(%rdi),%xmm0
  jp     L45
  jne    L45
  ucomisd 0x10(%rdi),%xmm0
  jp     L45
  je     L3
L45:
  jmp    1050 <rrdF2@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *rrdMHz_Maxilife(const double values[]) {
  if (!values[0] && !values[1] && !values[2])
    return NULL;
  return rrdF2(values);
}
```
user: What is the c source code of the assembly code below?

```asm
<Normalize2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  divss  -0x4(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  divss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void Normalize2D(float v[2]) {
  float len;
  len = (float)sqrt(v[0] * v[0] + v[1] * v[1]);
  v[0] /= len;
  v[1] /= len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Normalize2D>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  movss  (%rbx),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rbx)
  movss  0x4(%rbx),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void Normalize2D(float v[2]) {
  float len;
  len = (float)sqrt(v[0] * v[0] + v[1] * v[1]);
  v[0] /= len;
  v[1] /= len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Normalize2D>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  push   %rbx
  mov    %rdi,%rbx
  mulss  %xmm1,%xmm1
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movss  (%rbx),%xmm0
  cvtsi2ss %rax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rbx)
  movss  0x4(%rbx),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void Normalize2D(float v[2]) {
  float len;
  len = (float)sqrt(v[0] * v[0] + v[1] * v[1]);
  v[0] /= len;
  v[1] /= len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Normalize2D>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  push   %rbx
  mov    %rdi,%rbx
  mulss  %xmm1,%xmm1
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm2,%xmm2
  movss  (%rbx),%xmm0
  movss  0x4(%rbx),%xmm1
  cvtsi2ss %rax,%xmm2
  divss  %xmm2,%xmm0
  divss  %xmm2,%xmm1
  unpcklps %xmm1,%xmm0
  movlps %xmm0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void Normalize2D(float v[2]) {
  float len;
  len = (float)sqrt(v[0] * v[0] + v[1] * v[1]);
  v[0] /= len;
  v[1] /= len;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  je     L79
  cmp    $0x3,%eax
  jg     L26
  cmp    $0x1,%eax
  je     L77
  cmp    $0x2,%eax
  je     L50
  jmp    L26
L77:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L26
L50:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L26
L79:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L26:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D32
datatype: string
name: parse_data
arguments: data_label: D36
datatype: string
name: parse_data
arguments: data_label: D22
datatype: string

tool: D21: %d

tool: D32: ONE


tool: D36: TWO


tool: D22: THREE


assistant: ```c
int main(int argc, const char *argv[]) {
  int num;
  scanf("%d", &num);
  switch (num) {
  case 1:
    printf("ONE\n");
    break;
  case 2:
    printf("TWO\n");
    break;
  case 3:
    printf("THREE\n");
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L25
  cmp    $0x3,%eax
  je     L18
  cmp    $0x1,%eax
  je     L9
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L25:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L18:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D30
datatype: string
name: unpack_data
arguments: data_tag: D35
datatype: string
name: unpack_data
arguments: data_tag: D17
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string

tool: D30: %d

tool: D35: ONE


tool: D17: TWO


tool: D27: THREE


assistant: ```c
int main(int argc, const char *argv[]) {
  int num;
  scanf("%d", &num);
  switch (num) {
  case 1:
    printf("ONE\n");
    break;
  case 2:
    printf("TWO\n");
    break;
  case 3:
    printf("THREE\n");
    break;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L19
  cmp    $0x3,%eax
  je     L63
  cmp    $0x1,%eax
  je     L24
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L24:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L63:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D38
type: string
name: disassemble_data
arguments: tag: D27
type: string

tool: D18: %d

tool: D16: TWO


tool: D38: ONE


tool: D27: THREE


assistant: ```c
int main(int argc, const char *argv[]) {
  int num;
  scanf("%d", &num);
  switch (num) {
  case 1:
    printf("ONE\n");
    break;
  case 2:
    printf("TWO\n");
    break;
  case 3:
    printf("THREE\n");
    break;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L41
  cmp    $0x3,%eax
  je     L14
  cmp    $0x1,%eax
  je     L54
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L41:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L54:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L14:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D38
data_type: string
name: read_data
arguments: tag: D34
data_type: string
name: read_data
arguments: tag: D32
data_type: string
name: read_data
arguments: tag: D19
data_type: string

tool: D38: %d

tool: D34: TWO


tool: D32: ONE


tool: D19: THREE


assistant: ```c
int main(int argc, const char *argv[]) {
  int num;
  scanf("%d", &num);
  switch (num) {
  case 1:
    printf("ONE\n");
    break;
  case 2:
    printf("TWO\n");
    break;
  case 3:
    printf("THREE\n");
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <size_multiply_overflow@plt>
  test   %rax,%rax
  je     L19
  mov    $0x0,%eax
  jmp    L33
L19:
  mov    -0x8(%rbp),%rax
  imul   -0x10(%rbp),%rax
  test   %rax,%rax
  je     L16
  jmp    L31
L16:
  mov    $0x1,%eax
L31:
  mov    %eax,%edi
  call   <malloc@plt>
L33:
  leave
  ret
```

assistant: ```c
__attribute__((__malloc__)) __attribute__((__alloc_size__(1, 2))) void *malloc_multiply(size_t size, size_t need) {
  if (size_multiply_overflow(size, need))
    return NULL;
  return malloc(size * need ?: 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_multiply>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <size_multiply_overflow@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L7
  imul   %rbp,%rbx
  test   %rbx,%rbx
  mov    $0x1,%eax
  cmovne %rbx,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((__malloc__)) __attribute__((__alloc_size__(1, 2))) void *malloc_multiply(size_t size, size_t need) {
  if (size_multiply_overflow(size, need))
    return NULL;
  return malloc(size * need ?: 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<malloc_multiply>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <size_multiply_overflow@plt>
  test   %rax,%rax
  jne    L4
  imul   %rbp,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  cmovne %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <malloc@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((__malloc__)) __attribute__((__alloc_size__(1, 2))) void *malloc_multiply(size_t size, size_t need) {
  if (size_multiply_overflow(size, need))
    return NULL;
  return malloc(size * need ?: 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_multiply>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <size_multiply_overflow@plt>
  test   %rax,%rax
  jne    L4
  imul   %rbp,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  cmovne %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <malloc@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((__malloc__)) __attribute__((__alloc_size__(1, 2))) void *malloc_multiply(size_t size, size_t need) {
  if (size_multiply_overflow(size, need))
    return NULL;
  return malloc(size * need ?: 1);
}
```