ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<qt_internal_get_env_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  cmp    $0x59,%eax
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <check_info@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <qt_internal_envstr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char __attribute__((visibility("hidden"))) * qt_internal_get_env_str(const char *envariable, const char *dflt) {
  assert(strlen(envariable) < 90);
  check_info();
  return qt_internal_envstr(envariable, dflt);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<qt_internal_get_env_str>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    $0x59,%eax
  setle  %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <check_info@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <qt_internal_envstr@plt>
```

assistant: ```c
const char __attribute__((visibility("hidden"))) * qt_internal_get_env_str(const char *envariable, const char *dflt) {
  assert(strlen(envariable) < 90);
  check_info();
  return qt_internal_envstr(envariable, dflt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qt_internal_get_env_str>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    $0x59,%eax
  setle  %dil
  call   <assert@plt>
  xor    %eax,%eax
  call   <check_info@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <qt_internal_envstr@plt>
```

assistant: ```c
const char __attribute__((visibility("hidden"))) * qt_internal_get_env_str(const char *envariable, const char *dflt) {
  assert(strlen(envariable) < 90);
  check_info();
  return qt_internal_envstr(envariable, dflt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vect_norm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double vect_norm(double *a, int n) {
  int i;
  double norm = 0.0;
  for (i = 0; i < n; i++) {
    norm += a[i] * a[i];
  }
  norm = sqrt(norm);
  return norm;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vect_norm>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L26:
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L26
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L14
L30:
  sqrtsd %xmm0,%xmm0
  ret
L8:
  pxor   %xmm0,%xmm0
  jmp    L30
L14:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double vect_norm(double *a, int n) {
  int i;
  double norm = 0.0;
  for (i = 0; i < n; i++) {
    norm += a[i] * a[i];
  }
  norm = sqrt(norm);
  return norm;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vect_norm>:
  endbr64
  test   %esi,%esi
  jle    L28
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%rax,8),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L1:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L1
  ucomisd %xmm0,%xmm2
  ja     L20
  sqrtsd %xmm0,%xmm0
  ret
L28:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L20:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double vect_norm(double *a, int n) {
  int i;
  double norm = 0.0;
  for (i = 0; i < n; i++) {
    norm += a[i] * a[i];
  }
  norm = sqrt(norm);
  return norm;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vect_norm>:
  endbr64
  test   %esi,%esi
  jle    L47
  cmp    $0x1,%esi
  je     L51
  mov    %esi,%edx
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  shr    %edx
  movapd %xmm3,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L54:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L54
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L9
L13:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L9:
  ucomisd %xmm0,%xmm3
  ja     L40
  sqrtsd %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L47:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L51:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L13
L40:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double vect_norm(double *a, int n) {
  int i;
  double norm = 0.0;
  for (i = 0; i < n; i++) {
    norm += a[i] * a[i];
  }
  norm = sqrt(norm);
  return norm;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rcx
  mov    %rbx,%rax
  lea    0x16(%rsp),%rdx
  cmp    $0xa,%ecx
  jne    L8
L10:
  subb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
  movsbl 0xd(%rsp),%edx
  movsbl 0xc(%rsp),%eax
  lea    (%rax,%rdx,2),%eax
  movsbl 0xe(%rsp),%edx
  lea    (%rax,%rdx,4),%edx
  movsbl 0xf(%rsp),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rdx,2),%edx
  movsbl 0x10(%rsp),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  movsbl 0x11(%rsp),%edx
  lea    (%rdx,%rdx,8),%edx
  add    %edx,%eax
  movsbl 0x12(%rsp),%edx
  lea    (%rax,%rdx,8),%eax
  sub    %edx,%eax
  movsbl 0x13(%rsp),%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%eax
  movsbl 0x14(%rsp),%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rax,%rdx,2),%edx
  movslq %edx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0xa,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  movsbl 0x15(%rsp),%edx
  cmp    %eax,%edx
  je     L54
  mov    $0x30,%edi
  call   <putchar@plt>
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L40
L54:
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L40
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: %s

assistant: ```c
int main() {
  char egn[12];
  int l, egn_control, months, i;
  scanf("%s", egn);
  l = strlen(egn);
  if (l != 10) {
    printf("0");
    return 0;
  }
  for (i = 0; i < l; i++) {
    egn[i] = (egn[i] - 48);
  }
  months = (egn[2]) * 10 + (egn[3]);
  if (months < 1 && months > 12) {
    printf("0");
    return 0;
  }
  if (months < 1 + 20 && months > 12 + 20) {
    printf("0");
    return 0;
  }
  if (months < 1 + 40 && months > 12 + 40) {
    printf("0");
    return 0;
  }
  egn_control = (egn[0] * 2) + (egn[1] * 4) + (egn[2] * 8) + (egn[3] * 5) + (egn[4] * 10) + (egn[5] * 9) + (egn[6] * 7) + (egn[7] * 3) + (egn[8] * 6);
  egn_control = egn_control % 11;
  if (egn_control == 10) {
    egn_control = 0;
  }
  if (egn[9] != egn_control) {
    printf("0");
  } else {
    printf("1");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x16(%rsp),%rdx
  mov    %rax,%r8
  mov    %rbx,%rax
  cmp    $0xa,%r8
  jne    L42
  nopw   0x0(%rax,%rax,1)
L32:
  subb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L32
  movsbl 0xd(%rsp),%edx
  movsbl 0xc(%rsp),%eax
  lea    (%rax,%rdx,2),%eax
  movsbl 0xe(%rsp),%edx
  lea    (%rax,%rdx,4),%edx
  movsbl 0xf(%rsp),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rdx,2),%edx
  movsbl 0x10(%rsp),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  movsbl 0x11(%rsp),%edx
  lea    (%rdx,%rdx,8),%edx
  add    %edx,%eax
  movsbl 0x12(%rsp),%edx
  lea    (%rax,%rdx,8),%eax
  sub    %edx,%eax
  movsbl 0x13(%rsp),%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%eax
  movsbl 0x14(%rsp),%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rax,%rdx,2),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  cmp    $0xa,%eax
  cmove  %edx,%eax
  movsbl 0x15(%rsp),%edx
  cmp    %eax,%edx
  je     L11
L42:
  mov    $0x30,%edi
  call   <putchar@plt>
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L31
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: %s

assistant: ```c
int main() {
  char egn[12];
  int l, egn_control, months, i;
  scanf("%s", egn);
  l = strlen(egn);
  if (l != 10) {
    printf("0");
    return 0;
  }
  for (i = 0; i < l; i++) {
    egn[i] = (egn[i] - 48);
  }
  months = (egn[2]) * 10 + (egn[3]);
  if (months < 1 && months > 12) {
    printf("0");
    return 0;
  }
  if (months < 1 + 20 && months > 12 + 20) {
    printf("0");
    return 0;
  }
  if (months < 1 + 40 && months > 12 + 40) {
    printf("0");
    return 0;
  }
  egn_control = (egn[0] * 2) + (egn[1] * 4) + (egn[2] * 8) + (egn[3] * 5) + (egn[4] * 10) + (egn[5] * 9) + (egn[6] * 7) + (egn[7] * 3) + (egn[8] * 6);
  egn_control = egn_control % 11;
  if (egn_control == 10) {
    egn_control = 0;
  }
  if (egn[9] != egn_control) {
    printf("0");
  } else {
    printf("1");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<inet6_opt_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%ecx
  jle    L163
  mov    %esi,%r10d
  mov    %edx,%esi
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  cmp    $0xff,%r8d
  ja     L100
  lea    -0x4(%r9),%eax
  test   $0xfffffffb,%eax
  je     L142
  lea    -0x1(%r9),%eax
  cmp    $0x1,%eax
  ja     L55
L142:
  cmp    %r9d,%ebp
  jl     L87
  lea    0x2(%rsi,%rbp,1),%r13d
  mov    %r13d,%eax
  cltd
  idiv   %r9d
  sub    %edx,%r9d
  test   %edx,%edx
  mov    %edx,%ebx
  cmovne %r9d,%ebx
  add    %ebx,%r13d
  test   %r10d,%r10d
  je     L116
  cmp    %r10d,%r13d
  jg     L66
L116:
  test   %rdi,%rdi
  je     L138
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  cmp    $0x1,%ebx
  je     L96
  test   %ebx,%ebx
  jg     L150
L24:
  mov    %r12d,(%rax)
  mov    %ebp,0x4(%rax)
  add    $0x8,%rax
  mov    0x30(%rsp),%rdx
  mov    %rax,(%rdx)
L138:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L96:
  mov    D17(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  jmp    L24
L150:
  mov    D15(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    0x8(%rax),%r14
  lea    -0x2(%rbx),%edx
  mov    %edx,0x4(%rax)
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  movslq %ebx,%rbx
  lea    -0x8(%r14,%rbx,4),%rax
  jmp    L24
L163:
  mov    $0xffffffff,%r13d
  jmp    L138
L100:
  mov    $0xffffffff,%r13d
  jmp    L138
L55:
  mov    $0xffffffff,%r13d
  jmp    L138
L87:
  mov    $0xffffffff,%r13d
  jmp    L138
L66:
  mov    $0xffffffff,%r13d
  jmp    L138
```

assistant: ```c
int inet6_opt_append(void *extbuf, socklen_t extlen, int offset, u_int8_t type, socklen_t len, u_int8_t align, void **databufp) {
  int currentlen = offset, padlen = 0;
  if (type < 2)
    return (-1);
  if (len < 0 || len > 255)
    return (-1);
  if (align != 1 && align != 2 && align != 4 && align != 8)
    return (-1);
  if (align > len)
    return (-1);
  currentlen += 2 + len;
  if (currentlen % align)
    padlen = align - (currentlen % align);
  currentlen += padlen;
  if (extlen && currentlen > extlen)
    return (-1);
  if (extbuf) {
    u_int8_t *optp = (u_int8_t *)extbuf + offset;
    if (padlen == 1) {
      *optp = IP6OPT_PAD1;
      optp++;
    } else if (padlen > 0) {
      *optp++ = IP6OPT_PADN;
      *optp++ = padlen - 2;
      memset(optp, 0, padlen - 2);
      optp += (padlen - 2);
    }
    *optp++ = type;
    *optp++ = len;
    *databufp = optp;
  }
  return (currentlen);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inet6_opt_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%ecx
  jle    L110
  mov    %r8d,%ebx
  cmp    $0xff,%r8d
  ja     L110
  lea    -0x4(%r9),%eax
  mov    %esi,%r10d
  mov    %ecx,%r12d
  movslq %edx,%rsi
  and    $0xfffffffb,%eax
  je     L32
  lea    -0x1(%r9),%eax
  cmp    $0x1,%eax
  ja     L110
L32:
  cmp    %r9d,%ebx
  jl     L110
  lea    0x2(%rsi,%rbx,1),%r13d
  mov    %r13d,%eax
  cltd
  idiv   %r9d
  movslq %edx,%rbp
  test   %ebp,%ebp
  je     L123
  sub    %ebp,%r9d
  movslq %r9d,%rbp
  add    %ebp,%r13d
L123:
  test   %r10d,%r10d
  je     L108
  cmp    %r13d,%r10d
  jl     L110
L108:
  test   %rdi,%rdi
  je     L101
  lea    (%rdi,%rsi,4),%rax
  cmp    $0x1,%ebp
  je     L52
  test   %ebp,%ebp
  jle    L57
  mov    D14(%rip),%rdx
  lea    0x8(%rax),%r14
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    -0x2(%rbp),%edx
  mov    %edx,0x4(%rax)
  call   <memset@plt>
  lea    -0x8(%r14,%rbp,4),%rax
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L52:
  mov    D9(%rip),%rdx
  add    $0x4,%rax
  mov    (%rdx),%edx
  mov    %edx,-0x4(%rax)
L57:
  mov    0x30(%rsp),%rdx
  mov    %r12d,(%rax)
  add    $0x8,%rax
  mov    %ebx,-0x4(%rax)
  mov    %rax,(%rdx)
L101:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L110:
  mov    $0xffffffff,%r13d
  jmp    L101
```

assistant: ```c
int inet6_opt_append(void *extbuf, socklen_t extlen, int offset, u_int8_t type, socklen_t len, u_int8_t align, void **databufp) {
  int currentlen = offset, padlen = 0;
  if (type < 2)
    return (-1);
  if (len < 0 || len > 255)
    return (-1);
  if (align != 1 && align != 2 && align != 4 && align != 8)
    return (-1);
  if (align > len)
    return (-1);
  currentlen += 2 + len;
  if (currentlen % align)
    padlen = align - (currentlen % align);
  currentlen += padlen;
  if (extlen && currentlen > extlen)
    return (-1);
  if (extbuf) {
    u_int8_t *optp = (u_int8_t *)extbuf + offset;
    if (padlen == 1) {
      *optp = IP6OPT_PAD1;
      optp++;
    } else if (padlen > 0) {
      *optp++ = IP6OPT_PADN;
      *optp++ = padlen - 2;
      memset(optp, 0, padlen - 2);
      optp += (padlen - 2);
    }
    *optp++ = type;
    *optp++ = len;
    *databufp = optp;
  }
  return (currentlen);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inet6_opt_append>:
  endbr64
  push   %r12
  movd   %ecx,%xmm0
  movd   %r8d,%xmm2
  push   %rbp
  punpckldq %xmm2,%xmm0
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x1,%ecx
  jle    L12
  cmp    $0xff,%r8d
  ja     L12
  lea    -0x4(%r9),%eax
  mov    %esi,%r10d
  movslq %edx,%rsi
  and    $0xfffffffb,%eax
  je     L13
  lea    -0x1(%r9),%eax
  cmp    $0x1,%eax
  ja     L12
L13:
  cmp    %r9d,%r8d
  jl     L12
  lea    0x2(%rsi,%r8,1),%r12d
  mov    %r12d,%eax
  cltd
  idiv   %r9d
  movslq %edx,%rbx
  test   %ebx,%ebx
  je     L79
  sub    %ebx,%r9d
  movslq %r9d,%rbx
  add    %ebx,%r12d
L79:
  test   %r10d,%r10d
  je     L46
  cmp    %r12d,%r10d
  jl     L12
L46:
  test   %rdi,%rdi
  je     L51
  lea    (%rdi,%rsi,4),%rax
  cmp    $0x1,%ebx
  je     L38
  test   %ebx,%ebx
  jle    L98
  mov    D0(%rip),%rcx
  lea    -0x2(%rbx),%edx
  lea    0x8(%rax),%rbp
  xor    %esi,%esi
  movd   %edx,%xmm3
  mov    %rbp,%rdi
  movq   %xmm0,0x8(%rsp)
  movd   (%rcx),%xmm1
  punpckldq %xmm3,%xmm1
  movq   %xmm1,(%rax)
  call   <memset@plt>
  movq   0x8(%rsp),%xmm0
  lea    -0x8(%rbp,%rbx,4),%rax
  jmp    L98
  nopl   0x0(%rax,%rax,1)
L38:
  mov    D18(%rip),%rdx
  add    $0x4,%rax
  mov    (%rdx),%edx
  mov    %edx,-0x4(%rax)
L98:
  mov    0x30(%rsp),%rdx
  movq   %xmm0,(%rax)
  add    $0x8,%rax
  mov    %rax,(%rdx)
L51:
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  mov    $0xffffffff,%r12d
  jmp    L51
```

assistant: ```c
int inet6_opt_append(void *extbuf, socklen_t extlen, int offset, u_int8_t type, socklen_t len, u_int8_t align, void **databufp) {
  int currentlen = offset, padlen = 0;
  if (type < 2)
    return (-1);
  if (len < 0 || len > 255)
    return (-1);
  if (align != 1 && align != 2 && align != 4 && align != 8)
    return (-1);
  if (align > len)
    return (-1);
  currentlen += 2 + len;
  if (currentlen % align)
    padlen = align - (currentlen % align);
  currentlen += padlen;
  if (extlen && currentlen > extlen)
    return (-1);
  if (extbuf) {
    u_int8_t *optp = (u_int8_t *)extbuf + offset;
    if (padlen == 1) {
      *optp = IP6OPT_PAD1;
      optp++;
    } else if (padlen > 0) {
      *optp++ = IP6OPT_PADN;
      *optp++ = padlen - 2;
      memset(optp, 0, padlen - 2);
      optp += (padlen - 2);
    }
    *optp++ = type;
    *optp++ = len;
    *databufp = optp;
  }
  return (currentlen);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L44:
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x3e7,%eax
  jg     L20
  mov    -0x18(%rbp),%eax
  cmp    $0x2,%eax
  jle    L20
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L20:
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L18:
  cmpl   $0x0,-0x10(%rbp)
  jne    L44
  movl   $0x2,-0x14(%rbp)
  jmp    L28
L45:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L12
  movl   $0x0,-0xc(%rbp)
L12:
  addl   $0x1,-0x14(%rbp)
L28:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L45
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x0,-0xc(%rbp)
  jne    L68
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L76
L68:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L76:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
data_type: string
name: extract_symbolic_data
arguments: label: D53
data_type: string
name: extract_symbolic_data
arguments: label: D49
data_type: string
name: extract_symbolic_data
arguments: label: D30
data_type: string
name: extract_symbolic_data
arguments: label: D19
data_type: string
name: extract_symbolic_data
arguments: label: D41
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D33: Input: 

tool: D53: Enter a number between 2 and 1000: 

tool: D49: %d

tool: D30: That's not a number between 2 and 1000, try again. 


tool: D19: Output: 

tool: D41: The number you have entered, %d, IS NOT prime. 



tool: D3: The number you have entered, %d, IS prime. 



assistant: ```c
int main() {
  int num, i = 0, test = 1, prime = 1;
  printf("Input: \n");
  do {
    printf("Enter a number between 2 and 1000: ");
    scanf("%d", &num);
    if (num < 1000 && num > 2)
      test = 0;
    else
      printf("That's not a number between 2 and 1000, try again. \n\n");
  } while (test);
  for (i = 2; i < num; i++) {
    if (num % i == 0)
      prime = 0;
  }
  printf("Output: \n");
  if (prime == 0)
    printf("The number you have entered, %d, IS NOT prime. \n\n", num);
  else
    printf("The number you have entered, %d, IS prime. \n\n", num);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D21(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D42(%rip),%rbx
  lea    D51(%rip),%r13
  jmp    L31
L58:
  mov    %r13,%rdi
  call   <puts@plt>
L31:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  lea    -0x3(%rcx),%eax
  cmp    $0x3e4,%eax
  ja     L58
  mov    $0x1,%ebx
  mov    $0x2,%esi
L16:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  cmove  %edx,%ebx
  add    $0x1,%esi
  cmp    %esi,%ecx
  jg     L16
  lea    D52(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jne    L54
  mov    0x4(%rsp),%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  mov    0x4(%rsp),%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L44
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D33
datatype: string
name: disassemble_data
arguments: data_tag: D21
datatype: string
name: disassemble_data
arguments: data_tag: D42
datatype: string
name: disassemble_data
arguments: data_tag: D51
datatype: string
name: disassemble_data
arguments: data_tag: D52
datatype: string
name: disassemble_data
arguments: data_tag: D10
datatype: string
name: disassemble_data
arguments: data_tag: D53
datatype: string

tool: D33: Input: 

tool: D21: Enter a number between 2 and 1000: 

tool: D42: %d

tool: D51: That's not a number between 2 and 1000, try again. 


tool: D52: Output: 

tool: D10: The number you have entered, %d, IS NOT prime. 



tool: D53: The number you have entered, %d, IS prime. 



assistant: ```c
int main() {
  int num, i = 0, test = 1, prime = 1;
  printf("Input: \n");
  do {
    printf("Enter a number between 2 and 1000: ");
    scanf("%d", &num);
    if (num < 1000 && num > 2)
      test = 0;
    else
      printf("That's not a number between 2 and 1000, try again. \n\n");
  } while (test);
  for (i = 2; i < num; i++) {
    if (num % i == 0)
      prime = 0;
  }
  printf("Output: \n");
  if (prime == 0)
    printf("The number you have entered, %d, IS NOT prime. \n\n", num);
  else
    printf("The number you have entered, %d, IS prime. \n\n", num);
  return 0;
}
```