ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L29
  nopl   0x0(%rax)
L13:
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
L29:
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <getline2@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jne    L13
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: len = %d, line = %s


assistant: ```c
int main(void) {
  int len;
  char buffer[128];
  while (1) {
    len = getline2(buffer, 128);
    if (len == 0)
      break;
    printf("len = %d, line = %s\n", len, buffer);
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L12
  nopl   0x0(%rax)
L0:
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
L12:
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <getline2@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jne    L0
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: len = %d, line = %s


assistant: ```c
int main(void) {
  int len;
  char buffer[128];
  while (1) {
    len = getline2(buffer, 128);
    if (len == 0)
      break;
    printf("len = %d, line = %s\n", len, buffer);
  };
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L9
L23:
  movl   $0x2,-0xc(%rbp)
  jmp    L42
L73:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L16
  addl   $0x1,-0xc(%rbp)
L42:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L73
  jmp    L38
L16:
  nop
L38:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L68
  cmpl   $0x1,-0x10(%rbp)
  je     L68
  cmpl   $0x0,-0x10(%rbp)
  je     L68
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L68:
  subl   $0x1,-0x10(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L23
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string

tool: D1: %d%d

tool: D3: =====

tool: D0: %d


assistant: ```c
int main() {
  int m, n, i, j, k;
  scanf("%d%d", &m, &n);
  printf("=====\n");
  for (i = n; i >= m; i--) {
    for (j = 2; j < i; j++)
      if (i % j == 0)
        break;
    if (j >= i && i != 1 && i != 0)
      printf("%d\n", i);
  }
  printf("=====\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%ebx
  lea    D31(%rip),%rbp
  cmp    (%rsp),%ebx
  jge    L45
L36:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L77:
  mov    $0x2,%ecx
  jmp    L51
L2:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L82:
  sub    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L36
L45:
  cmp    $0x2,%ebx
  jle    L77
  test   $0x1,%bl
  je     L82
  mov    $0x2,%ecx
L73:
  add    $0x1,%ecx
  cmp    %ebx,%ecx
  je     L2
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L73
L51:
  cmp    %ecx,%ebx
  jg     L82
  cmp    $0x1,%ebx
  jbe    L82
  jmp    L2
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D30
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string
name: parse_data
arguments: data_label: D31
type_guessed: string

tool: D30: %d%d

tool: D2: =====

tool: D31: %d


assistant: ```c
int main() {
  int m, n, i, j, k;
  scanf("%d%d", &m, &n);
  printf("=====\n");
  for (i = n; i >= m; i--) {
    for (j = 2; j < i; j++)
      if (i % j == 0)
        break;
    if (j >= i && i != 1 && i != 0)
      printf("%d\n", i);
  }
  printf("=====\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  lea    D22(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%r12d
  cmp    (%rsp),%r12d
  jl     L60
  nopl   0x0(%rax)
L108:
  cmp    $0x2,%r12d
  jle    L53
  test   $0x1,%r12b
  je     L66
  mov    $0x2,%ecx
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L10
L45:
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jne    L9
L10:
  cmp    %r12d,%ecx
  jl     L66
  cmp    $0x1,%r12d
  ja     L41
L66:
  sub    $0x1,%r12d
  cmp    %r12d,(%rsp)
  jle    L108
L60:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L66
L53:
  mov    $0x2,%ecx
  jmp    L10
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D27
type_infered: string
name: extract_symbolic_data
arguments: data_label: D22
type_infered: string

tool: D2: %d%d

tool: D27: =====

tool: D22: %d


assistant: ```c
int main() {
  int m, n, i, j, k;
  scanf("%d%d", &m, &n);
  printf("=====\n");
  for (i = n; i >= m; i--) {
    for (j = 2; j < i; j++)
      if (i % j == 0)
        break;
    if (j >= i && i != 1 && i != 0)
      printf("%d\n", i);
  }
  printf("=====\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%r12d
  mov    (%rsp),%esi
  cmp    %esi,%r12d
  jl     L53
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    $0x2,%r12d
  jle    L87
  test   $0x1,%r12b
  je     L91
  mov    $0x2,%ecx
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L109:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L81
L88:
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jne    L109
L81:
  cmp    %r12d,%ecx
  jl     L91
  cmp    $0x1,%r12d
  ja     L16
L91:
  sub    $0x1,%r12d
  cmp    %esi,%r12d
  jge    L8
L53:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  jmp    L91
L87:
  mov    $0x2,%ecx
  jmp    L81
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D28
data_type: string
name: unpack_data
arguments: label: D9
data_type: string
name: unpack_data
arguments: label: D19
data_type: string

tool: D28: %d%d

tool: D9: =====

tool: D19: %d


assistant: ```c
int main() {
  int m, n, i, j, k;
  scanf("%d%d", &m, &n);
  printf("=====\n");
  for (i = n; i >= m; i--) {
    for (j = 2; j < i; j++)
      if (i % j == 0)
        break;
    if (j >= i && i != 1 && i != 0)
      printf("%d\n", i);
  }
  printf("=====\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <close_all@plt>
  mov    $0x0,%edi
  call   <sys_env_destroy@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void exit(void) {
  close_all();
  sys_env_destroy(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<exit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <close_all@plt>
  mov    $0x0,%edi
  call   <sys_env_destroy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void exit(void) {
  close_all();
  sys_env_destroy(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <close_all@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <sys_env_destroy@plt>
```

assistant: ```c
void exit(void) {
  close_all();
  sys_env_destroy(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <close_all@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <sys_env_destroy@plt>
```

assistant: ```c
void exit(void) {
  close_all();
  sys_env_destroy(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copyout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int copyout(const void *kaddr, void *uaddr, size_t len) {
  memcpy(uaddr, kaddr, len);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copyout>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rax,%rsi
  call   <memcpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copyout(const void *kaddr, void *uaddr, size_t len) {
  memcpy(uaddr, kaddr, len);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copyout>:
  endbr64
  mov    %rdi,%r8
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %r8,%rsi
  call   <memcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copyout(const void *kaddr, void *uaddr, size_t len) {
  memcpy(uaddr, kaddr, len);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copyout>:
  endbr64
  mov    %rdi,%r8
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %r8,%rsi
  call   <memcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copyout(const void *kaddr, void *uaddr, size_t len) {
  memcpy(uaddr, kaddr, len);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<factor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  addl   $0x1,-0xc(%rbp)
  cmpb   $0x20,-0xd(%rbp)
  je     L31
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <lexer@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L13
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <term@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L58
L13:
  cmpl   $0x9,-0x4(%rbp)
  jne    L50
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <term@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L58
L50:
  cmpl   $0x7,-0x4(%rbp)
  jne    L66
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <term@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L58
L66:
  mov    $0x0,%eax
  jmp    L48
L58:
  mov    -0x8(%rbp),%eax
L48:
  leave
  ret
```

assistant: ```c
int factor(char string[], int count) {
  int ctr = 0;
  char letter;
  int token = 0;
  int checked = 0;
  do {
    letter = string[ctr];
    ctr++;
  } while (letter == ' ');
  token = lexer(letter);
  if (token == 1)
    checked = term(string, ctr, 1);
  else if (token == 9)
    checked = term(string, ctr, 2);
  else if (token == 7)
    checked = term(string, ctr, 3);
  else
    return 0;
  return checked;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<factor>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x1,%eax
L56:
  movzbl -0x1(%rbx,%rax,1),%edi
  mov    %eax,%ebp
  add    $0x1,%rax
  cmp    $0x20,%dil
  je     L56
  movsbl %dil,%edi
  call   <lexer@plt>
  cmp    $0x1,%eax
  je     L37
  cmp    $0x9,%eax
  je     L66
  mov    $0x0,%edx
  cmp    $0x7,%eax
  je     L9
L22:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <term@plt>
  mov    %eax,%edx
  jmp    L22
L66:
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <term@plt>
  mov    %eax,%edx
  jmp    L22
L9:
  mov    $0x3,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <term@plt>
  mov    %eax,%edx
  jmp    L22
```

assistant: ```c
int factor(char string[], int count) {
  int ctr = 0;
  char letter;
  int token = 0;
  int checked = 0;
  do {
    letter = string[ctr];
    ctr++;
  } while (letter == ' ');
  token = lexer(letter);
  if (token == 1)
    checked = term(string, ctr, 1);
  else if (token == 9)
    checked = term(string, ctr, 2);
  else if (token == 7)
    checked = term(string, ctr, 3);
  else
    return 0;
  return checked;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<factor>:
  endbr64
  push   %r12
  mov    $0x1,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L28:
  movsbl -0x1(%rbp,%rax,1),%edi
  mov    %eax,%r12d
  add    $0x1,%rax
  cmp    $0x20,%dil
  je     L28
  call   <lexer@plt>
  mov    $0x1,%edx
  cmp    $0x1,%eax
  je     L34
  mov    $0x2,%edx
  cmp    $0x9,%eax
  je     L34
  cmp    $0x7,%eax
  je     L13
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0x3,%edx
L34:
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <term@plt>
```

assistant: ```c
int factor(char string[], int count) {
  int ctr = 0;
  char letter;
  int token = 0;
  int checked = 0;
  do {
    letter = string[ctr];
    ctr++;
  } while (letter == ' ');
  token = lexer(letter);
  if (token == 1)
    checked = term(string, ctr, 1);
  else if (token == 9)
    checked = term(string, ctr, 2);
  else if (token == 7)
    checked = term(string, ctr, 3);
  else
    return 0;
  return checked;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factor>:
  endbr64
  push   %r12
  mov    $0x1,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L10:
  movsbl -0x1(%rbp,%rax,1),%edi
  mov    %eax,%r12d
  add    $0x1,%rax
  cmp    $0x20,%dil
  je     L10
  call   <lexer@plt>
  mov    $0x1,%edx
  cmp    $0x1,%eax
  je     L19
  mov    $0x2,%edx
  cmp    $0x9,%eax
  je     L19
  cmp    $0x7,%eax
  je     L22
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    $0x3,%edx
L19:
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <term@plt>
```

assistant: ```c
int factor(char string[], int count) {
  int ctr = 0;
  char letter;
  int token = 0;
  int checked = 0;
  do {
    letter = string[ctr];
    ctr++;
  } while (letter == ' ');
  token = lexer(letter);
  if (token == 1)
    checked = term(string, ctr, 1);
  else if (token == 9)
    checked = term(string, ctr, 2);
  else if (token == 7)
    checked = term(string, ctr, 3);
  else
    return 0;
  return checked;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<input_get_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <input_get_argument@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    -0x28(%rbp),%rdx
  movq   %rax,%xmm0
  mov    %rdx,%rdi
  call   <input_append_input_arguments_with_double@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  jmp    L15
L18:
  mov    -0x30(%rbp),%rax
L15:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double input_get_double(int argc, char **argv, const char *argument, double _default) {
  char *value = input_get_argument(argc, argv, argument);
  if (value) {
    input_append_input_arguments_with_double(argument, atof(value));
    return atof(value);
  }
  return _default;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<input_get_double>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  movq   %xmm0,%rbx
  call   <input_get_argument@plt>
  test   %rax,%rax
  jne    L6
L7:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <atof@plt>
  mov    %r12,%rdi
  call   <input_append_input_arguments_with_double@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  movq   %xmm0,%rbx
  jmp    L7
```

assistant: ```c
double input_get_double(int argc, char **argv, const char *argument, double _default) {
  char *value = input_get_argument(argc, argv, argument);
  if (value) {
    input_append_input_arguments_with_double(argument, atof(value));
    return atof(value);
  }
  return _default;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<input_get_double>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <input_get_argument@plt>
  movsd  0x8(%rsp),%xmm0
  test   %rax,%rax
  jne    L9
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <atof@plt>
  mov    %r12,%rdi
  call   <input_append_input_arguments_with_double@plt>
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <atof@plt>
```

assistant: ```c
double input_get_double(int argc, char **argv, const char *argument, double _default) {
  char *value = input_get_argument(argc, argv, argument);
  if (value) {
    input_append_input_arguments_with_double(argument, atof(value));
    return atof(value);
  }
  return _default;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<input_get_double>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <input_get_argument@plt>
  movsd  0x8(%rsp),%xmm0
  test   %rax,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <atof@plt>
  mov    %r12,%rdi
  call   <input_append_input_arguments_with_double@plt>
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <atof@plt>
```

assistant: ```c
double input_get_double(int argc, char **argv, const char *argument, double _default) {
  char *value = input_get_argument(argc, argv, argument);
  if (value) {
    input_append_input_arguments_with_double(argument, atof(value));
    return atof(value);
  }
  return _default;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L22
L15:
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L22:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L15
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D28
type_guessed: string
name: read_data
arguments: data_tag: D15
type_guessed: string
name: read_data
arguments: data_tag: D29
type_guessed: string

tool: D28: Enter n = 

tool: D15: %d

tool: D29: %d


assistant: ```c
int main() {
  int n, i = 0, s = 0;
  printf("Enter n = ");
  scanf("%d", &n);
  while (i <= n) {
    s = s + i;
    i++;
  }
  printf("%d\n", s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  js     L25
  add    $0x1,%edx
  mov    $0x0,%esi
  mov    $0x0,%eax
L18:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L18
L36:
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L25:
  mov    $0x0,%esi
  jmp    L36
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D13
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string

tool: D26: Enter n = 

tool: D13: %d

tool: D16: %d


assistant: ```c
int main() {
  int n, i = 0, s = 0;
  printf("Enter n = ");
  scanf("%d", &n);
  while (i <= n) {
    s = s + i;
    i++;
  }
  printf("%d\n", s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  js     L37
  add    $0x1,%edx
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L30:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L30
L6:
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L37:
  xor    %esi,%esi
  jmp    L6
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
data_type: string
name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D23
data_type: string

tool: D29: Enter n = 

tool: D22: %d

tool: D23: %d


assistant: ```c
int main() {
  int n, i = 0, s = 0;
  printf("Enter n = ");
  scanf("%d", &n);
  while (i <= n) {
    s = s + i;
    i++;
  }
  printf("%d\n", s);
  return 0;
}
```