ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fputc>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <flockfile@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <fputc_unlocked@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <funlockfile@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fputc(int c, FILE *file) {
  flockfile(file);
  int result = fputc_unlocked(c, file);
  funlockfile(file);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SolveScalarError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x3f8(%rbp)
  mov    %rsi,-0x400(%rbp)
  mov    %rdx,-0x408(%rbp)
  movsd  %xmm0,-0x410(%rbp)
  movsd  %xmm1,-0x418(%rbp)
  mov    %ecx,-0x41c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x41c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L16
  lea    D10(%rip),%rax
  jmp    L0
L16:
  lea    D7(%rip),%rax
L0:
  movsd  -0x418(%rbp),%xmm0
  mov    -0x410(%rbp),%rcx
  mov    -0x408(%rbp),%r8
  mov    -0x400(%rbp),%rsi
  mov    -0x3f8(%rbp),%rdx
  lea    -0x3f0(%rbp),%rdi
  movapd %xmm0,%xmm1
  movq   %rcx,%xmm0
  mov    %r8,%r9
  mov    %rsi,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  call   <sprintf@plt>
  mov    -0x41c(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L40
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <DymosimError@plt>
  jmp    L38
L40:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <DymosimMessage@plt>
L38:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D7
type: string
name: unpack_data
arguments: data_label: D21
type: string

tool: D10: Scalar system is always singular, it may be possible to evaluate parameters to avoid this,

tool: D7: Singular inconsistent scalar system

tool: D21: Error: %s for %.400s = (%.200s)/(%.200s) = %g/%g

assistant: ```c
void SolveScalarError(const char *xs, const char *bs, const char *As, double bval_, double Aval_, int alwaysError) {
  char s[1000];
  sprintf(s, "Error: %s for %.400s = (%.200s)/(%.200s) = %g/%g", (alwaysError & 1) ? "Scalar system is always singular, it may be possible to evaluate parameters to avoid this," : "Singular inconsistent scalar system", xs, bs, As, bval_, Aval_);
  if (alwaysError & 2)
    DymosimError(s);
  else
    DymosimMessage(s);
}
```
user: What is the c source code of the assembly code below?

```asm
<SolveScalarError>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %rsi,%r8
  mov    %rdx,%r9
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  test   $0x1,%cl
  lea    D6(%rip),%rax
  lea    D18(%rip),%rdx
  cmovne %rax,%rdx
  mov    %rsp,%rax
  mov    %rdi,%rcx
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  test   $0x2,%bl
  je     L2
  mov    %rsp,%rdi
  call   <DymosimError@plt>
L1:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L2:
  mov    %rsp,%rdi
  call   <DymosimMessage@plt>
  jmp    L1
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string

tool: D6: Scalar system is always singular, it may be possible to evaluate parameters to avoid this,

tool: D18: Singular inconsistent scalar system

tool: D19: Error: %s for %.400s = (%.200s)/(%.200s) = %g/%g

assistant: ```c
void SolveScalarError(const char *xs, const char *bs, const char *As, double bval_, double Aval_, int alwaysError) {
  char s[1000];
  sprintf(s, "Error: %s for %.400s = (%.200s)/(%.200s) = %g/%g", (alwaysError & 1) ? "Scalar system is always singular, it may be possible to evaluate parameters to avoid this," : "Singular inconsistent scalar system", xs, bs, As, bval_, Aval_);
  if (alwaysError & 2)
    DymosimError(s);
  else
    DymosimMessage(s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SolveScalarError>:
  endbr64
  push   %rbp
  mov    %rdx,%r9
  lea    D15(%rip),%rdx
  mov    %rsi,%r8
  push   %rbx
  mov    %ecx,%ebx
  lea    D1(%rip),%rsi
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  and    $0x1,%ecx
  lea    D21(%rip),%rax
  mov    %rsp,%rbp
  cmovne %rax,%rdx
  mov    %rdi,%rcx
  mov    %rbp,%rdi
  call   <sprintf@plt>
  and    $0x2,%ebx
  mov    %rbp,%rdi
  je     L10
  call   <DymosimError@plt>
L8:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  call   <DymosimMessage@plt>
  jmp    L8
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string

tool: D15: Singular inconsistent scalar system

tool: D1: Error: %s for %.400s = (%.200s)/(%.200s) = %g/%g

tool: D21: Scalar system is always singular, it may be possible to evaluate parameters to avoid this,

assistant: ```c
void SolveScalarError(const char *xs, const char *bs, const char *As, double bval_, double Aval_, int alwaysError) {
  char s[1000];
  sprintf(s, "Error: %s for %.400s = (%.200s)/(%.200s) = %g/%g", (alwaysError & 1) ? "Scalar system is always singular, it may be possible to evaluate parameters to avoid this," : "Singular inconsistent scalar system", xs, bs, As, bval_, Aval_);
  if (alwaysError & 2)
    DymosimError(s);
  else
    DymosimMessage(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SolveScalarError>:
  endbr64
  push   %rbp
  mov    %rdx,%r9
  lea    D27(%rip),%rdx
  mov    %rsi,%r8
  push   %rbx
  mov    %ecx,%ebx
  lea    D13(%rip),%rsi
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  and    $0x1,%ecx
  lea    D29(%rip),%rax
  mov    %rsp,%rbp
  cmovne %rax,%rdx
  mov    %rdi,%rcx
  mov    %rbp,%rdi
  call   <sprintf@plt>
  and    $0x2,%ebx
  mov    %rbp,%rdi
  je     L15
  call   <DymosimError@plt>
L16:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L15:
  call   <DymosimMessage@plt>
  jmp    L16
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D29
datatype: string

tool: D27: Singular inconsistent scalar system

tool: D13: Error: %s for %.400s = (%.200s)/(%.200s) = %g/%g

tool: D29: Scalar system is always singular, it may be possible to evaluate parameters to avoid this,

assistant: ```c
void SolveScalarError(const char *xs, const char *bs, const char *As, double bval_, double Aval_, int alwaysError) {
  char s[1000];
  sprintf(s, "Error: %s for %.400s = (%.200s)/(%.200s) = %g/%g", (alwaysError & 1) ? "Scalar system is always singular, it may be possible to evaluate parameters to avoid this," : "Singular inconsistent scalar system", xs, bs, As, bval_, Aval_);
  if (alwaysError & 2)
    DymosimError(s);
  else
    DymosimMessage(s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SubStrings_StripLeadingChars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rax
  mov    %rsi,-0x38(%rbp)
  mov    %rax,-0x18(%rbp)
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L27
L22:
  mov    -0x38(%rbp),%rbx
  jmp    L78
L1:
  movzbl (%rax),%ecx
  movzbl (%rbx),%edx
  cmp    %dl,%cl
  jne    L75
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
  jmp    L46
L75:
  add    $0x1,%rbx
L78:
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L1
L46:
  add    $0x1,%rax
L27:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L22
  cmp    -0x18(%rbp),%rax
  jne    L13
  mov    $0x0,%eax
  jmp    L66
L13:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <SubStrings_Length@plt>
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SubStrings_Copy@plt>
  mov    -0x24(%rbp),%eax
L66:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned SubStrings_StripLeadingChars(register char *Stream, const char *Match) {
  register const char *M;
  char *Orig = Stream, *Worker = Stream;
  unsigned StripCount = 0;
  for (; *Stream; ++Stream) {
    for (M = Match; *M; ++M) {
      if (*Stream == *M) {
        Worker = Stream + 1;
        ++StripCount;
        break;
      }
    }
  }
  if (Stream == Orig)
    return 0;
  SubStrings_Copy(Orig, Worker, SubStrings_Length(Worker) + 1);
  return StripCount;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SubStrings_StripLeadingChars>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L88
  mov    %rdi,%rbp
  movzbl (%rsi),%r8d
  lea    0x1(%rdi),%rdi
  mov    %rbp,%r12
  mov    $0x0,%ebx
  jmp    L63
L6:
  mov    %rdi,%r12
  add    $0x1,%ebx
L55:
  mov    %rdi,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%ecx
  test   %cl,%cl
  je     L73
L63:
  mov    %rsi,%rdx
  mov    %r8d,%eax
  test   %r8b,%r8b
  je     L55
L87:
  cmp    %cl,%al
  je     L6
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L87
  jmp    L55
L73:
  cmp    %rax,%rbp
  je     L22
  mov    %r12,%rdi
  call   <SubStrings_Length@plt>
  lea    0x1(%rax),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SubStrings_Copy@plt>
L34:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L88:
  mov    $0x0,%ebx
  jmp    L34
L22:
  mov    $0x0,%ebx
  jmp    L34
```

assistant: ```c
unsigned SubStrings_StripLeadingChars(register char *Stream, const char *Match) {
  register const char *M;
  char *Orig = Stream, *Worker = Stream;
  unsigned StripCount = 0;
  for (; *Stream; ++Stream) {
    for (M = Match; *M; ++M) {
      if (*Stream == *M) {
        Worker = Stream + 1;
        ++StripCount;
        break;
      }
    }
  }
  if (Stream == Orig)
    return 0;
  SubStrings_Copy(Orig, Worker, SubStrings_Length(Worker) + 1);
  return StripCount;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SubStrings_StripLeadingChars>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L62
  movzbl (%rsi),%r8d
  mov    %rdi,%rbp
  mov    %rdi,%r13
  xor    %r12d,%r12d
  nopl   (%rax)
L9:
  add    $0x1,%rdi
  mov    %rsi,%rdx
  mov    %r8d,%eax
  test   %r8b,%r8b
  jne    L66
  jmp    L42
  nopl   0x0(%rax)
L40:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L42
L66:
  cmp    %al,%cl
  jne    L40
  add    $0x1,%r12d
  mov    %rdi,%r13
L42:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L9
  cmp    %rdi,%rbp
  je     L62
  mov    %r13,%rdi
  call   <SubStrings_Length@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <SubStrings_Copy@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L62:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned SubStrings_StripLeadingChars(register char *Stream, const char *Match) {
  register const char *M;
  char *Orig = Stream, *Worker = Stream;
  unsigned StripCount = 0;
  for (; *Stream; ++Stream) {
    for (M = Match; *M; ++M) {
      if (*Stream == *M) {
        Worker = Stream + 1;
        ++StripCount;
        break;
      }
    }
  }
  if (Stream == Orig)
    return 0;
  SubStrings_Copy(Orig, Worker, SubStrings_Length(Worker) + 1);
  return StripCount;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SubStrings_StripLeadingChars>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L42
  movzbl (%rsi),%r8d
  mov    %rdi,%rbp
  mov    %rdi,%r13
  xor    %r12d,%r12d
  nopl   (%rax)
L32:
  add    $0x1,%rdi
  mov    %rsi,%rdx
  mov    %r8d,%eax
  test   %r8b,%r8b
  jne    L54
  jmp    L65
  nopl   0x0(%rax)
L41:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L65
L54:
  cmp    %al,%cl
  jne    L41
  add    $0x1,%r12d
  mov    %rdi,%r13
L65:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L32
  cmp    %rdi,%rbp
  je     L42
  mov    %r13,%rdi
  call   <SubStrings_Length@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <SubStrings_Copy@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned SubStrings_StripLeadingChars(register char *Stream, const char *Match) {
  register const char *M;
  char *Orig = Stream, *Worker = Stream;
  unsigned StripCount = 0;
  for (; *Stream; ++Stream) {
    for (M = Match; *M; ++M) {
      if (*Stream == *M) {
        Worker = Stream + 1;
        ++StripCount;
        break;
      }
    }
  }
  if (Stream == Orig)
    return 0;
  SubStrings_Copy(Orig, Worker, SubStrings_Length(Worker) + 1);
  return StripCount;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bitcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L28:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L15
  addl   $0x1,-0x4(%rbp)
L15:
  shrl   -0x14(%rbp)
L6:
  cmpl   $0x0,-0x14(%rbp)
  jne    L28
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
bitcount(unsigned x) {
  int b;
  for (b = 0; x != 0; x >>= 1)
    if (x & 01)
      b++;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitcount>:
  endbr64
  test   %edi,%edi
  je     L13
  mov    $0x0,%eax
L1:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  jne    L1
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bitcount(unsigned x) {
  int b;
  for (b = 0; x != 0; x >>= 1)
    if (x & 01)
      b++;
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bitcount>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L16
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  jne    L15
  ret
L16:
  ret
```

assistant: ```c
bitcount(unsigned x) {
  int b;
  for (b = 0; x != 0; x >>= 1)
    if (x & 01)
      b++;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitcount>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L6
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  jne    L0
  ret
L6:
  ret
```

assistant: ```c
bitcount(unsigned x) {
  int b;
  for (b = 0; x != 0; x >>= 1)
    if (x & 01)
      b++;
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<thomas>:
  endbr64
  movsd  (%rcx),%xmm0
  divsd  (%rdx),%xmm0
  movsd  %xmm0,(%rcx)
  movsd  (%rdi),%xmm0
  divsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  cmp    $0x1,%r8d
  jle    L9
  mov    %r8d,%r9d
  mov    $0x1,%eax
  movsd  D1(%rip),%xmm3
L27:
  movsd  -0x8(%rcx,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movsd  (%rdx,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movapd %xmm3,%xmm2
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  movsd  -0x8(%rdi,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movsd  (%rdi,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L27
  sub    $0x2,%r8d
  movslq %r8d,%rax
L8:
  movsd  (%rcx,%rax,8),%xmm1
  mulsd  0x8(%rdi,%rax,8),%xmm1
  movsd  (%rdi,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L8
  ret
L9:
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void thomas(double *x, const double *a, const double *b, double *c, int n) {
  double tmp;
  int i;
  c[0] /= b[0];
  x[0] /= b[0];
  for (i = 1; i < n; ++i) {
    tmp = 1 / (b[i] - c[i - 1] * a[i]);
    c[i] *= tmp;
    x[i] = (x[i] - x[i - 1] * a[i]) * tmp;
  }
  for (i = n - 2; i >= 0; --i) {
    x[i] -= c[i] * x[i + 1];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thomas>:
  endbr64
  movsd  (%rcx),%xmm0
  mov    %rdx,%r9
  divsd  (%rdx),%xmm0
  movsd  %xmm0,(%rcx)
  movsd  (%rdi),%xmm0
  divsd  (%rdx),%xmm0
  lea    -0x2(%r8),%edx
  movsd  %xmm0,(%rdi)
  cmp    $0x1,%r8d
  jle    L15
  movsd  D2(%rip),%xmm3
  movslq %r8d,%r8
  mov    $0x1,%eax
  nopl   (%rax)
L25:
  movsd  -0x8(%rcx,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movapd %xmm3,%xmm2
  movsd  (%r9,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  movsd  -0x8(%rdi,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movsd  (%rdi,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L25
L37:
  movslq %edx,%rax
  nopl   0x0(%rax)
L12:
  movsd  (%rcx,%rax,8),%xmm1
  mulsd  0x8(%rdi,%rax,8),%xmm1
  movsd  (%rdi,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  test   %edx,%edx
  jns    L37
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void thomas(double *x, const double *a, const double *b, double *c, int n) {
  double tmp;
  int i;
  c[0] /= b[0];
  x[0] /= b[0];
  for (i = 1; i < n; ++i) {
    tmp = 1 / (b[i] - c[i - 1] * a[i]);
    c[i] *= tmp;
    x[i] = (x[i] - x[i - 1] * a[i]) * tmp;
  }
  for (i = n - 2; i >= 0; --i) {
    x[i] -= c[i] * x[i + 1];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<thomas>:
  endbr64
  movsd  (%rcx),%xmm0
  mov    %rdx,%r9
  divsd  (%rdx),%xmm0
  movsd  %xmm0,(%rcx)
  movsd  (%rdi),%xmm0
  divsd  (%rdx),%xmm0
  lea    -0x2(%r8),%edx
  movsd  %xmm0,(%rdi)
  cmp    $0x1,%r8d
  jle    L24
  movsd  D8(%rip),%xmm3
  movslq %r8d,%r8
  mov    $0x1,%eax
  nopl   (%rax)
L23:
  movsd  -0x8(%rcx,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movapd %xmm3,%xmm2
  movsd  (%r9,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  movsd  -0x8(%rdi,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movsd  (%rdi,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L23
L29:
  movsd  -0x8(%rdi,%r8,8),%xmm0
  movslq %edx,%rax
  nopl   0x0(%rax,%rax,1)
L18:
  movsd  (%rcx,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  (%rdi,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L18
L41:
  ret
L24:
  test   %edx,%edx
  js     L41
  movslq %r8d,%r8
  jmp    L29
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void thomas(double *x, const double *a, const double *b, double *c, int n) {
  double tmp;
  int i;
  c[0] /= b[0];
  x[0] /= b[0];
  for (i = 1; i < n; ++i) {
    tmp = 1 / (b[i] - c[i - 1] * a[i]);
    c[i] *= tmp;
    x[i] = (x[i] - x[i - 1] * a[i]) * tmp;
  }
  for (i = n - 2; i >= 0; --i) {
    x[i] -= c[i] * x[i + 1];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L29
L41:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L36:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0x0,-0x8(%rbp)
  jle    L7
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L36
L7:
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L41
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_sort(int vetor[], int max) {
  int i, j, aux;
  for (i = 1; i < max; i++) {
    j = i;
    while (j > 0 && vetor[j - 1] > vetor[j]) {
      aux = vetor[j];
      vetor[j] = vetor[j - 1];
      vetor[j - 1] = aux;
      j--;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L17
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  jmp    L61
L37:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  je     L17
L61:
  test   %r8d,%r8d
  jle    L37
  mov    %r9,%rax
L45:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L37
  mov    %ecx,(%rax)
  mov    %edx,-0x4(%rax)
  sub    $0x4,%rax
  cmp    %rdi,%rax
  jne    L45
  jmp    L37
L17:
  ret
```

assistant: ```c
void insertion_sort(int vetor[], int max) {
  int i, j, aux;
  for (i = 1; i < max; i++) {
    j = i;
    while (j > 0 && vetor[j - 1] > vetor[j]) {
      aux = vetor[j];
      vetor[j] = vetor[j - 1];
      vetor[j - 1] = aux;
      j--;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertion_sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L36
  nopl   0x0(%rax,%rax,1)
L35:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L23:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L39
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  mov    %edx,(%rax)
  cmp    %rdi,%rax
  jne    L23
L39:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  jne    L35
  ret
L36:
  ret
```

assistant: ```c
void insertion_sort(int vetor[], int max) {
  int i, j, aux;
  for (i = 1; i < max; i++) {
    j = i;
    while (j > 0 && vetor[j - 1] > vetor[j]) {
      aux = vetor[j];
      vetor[j] = vetor[j - 1];
      vetor[j - 1] = aux;
      j--;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<insertion_sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L23
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r9,%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  movq   -0x4(%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L3
  movq   %xmm1,-0x4(%rdx)
  sub    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L4
L3:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  jne    L29
  ret
L23:
  ret
```

assistant: ```c
void insertion_sort(int vetor[], int max) {
  int i, j, aux;
  for (i = 1; i < max; i++) {
    j = i;
    while (j > 0 && vetor[j - 1] > vetor[j]) {
      aux = vetor[j];
      vetor[j] = vetor[j - 1];
      vetor[j - 1] = aux;
      j--;
    }
  }
}
```