ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<findCircleNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L8
L24:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L23
  addl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <selectSameGroup@plt>
L23:
  addl   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L24
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int findCircleNum(int **M, int MRowSize, int MColSize) {
  int n = MRowSize;
  int nGroup = 0;
  int i;
  int *inGroup = (int *)calloc(n, sizeof(int));
  for (i = 0; i < n; i++) {
    if (inGroup[i] == 0) {
      nGroup++;
      inGroup[i] = 1;
      selectSameGroup(M, inGroup, n, i);
    }
  }
  return nGroup;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findCircleNum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r12d
  mov    $0x4,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  test   %r12d,%r12d
  jle    L10
  mov    %rax,%r14
  mov    %rax,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  jmp    L31
L49:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,%r12d
  je     L15
L31:
  cmpl   $0x0,0x0(%rbp)
  jne    L49
  add    $0x1,%r13d
  movl   $0x1,0x0(%rbp)
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <selectSameGroup@plt>
  jmp    L49
L10:
  mov    $0x0,%r13d
L15:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int findCircleNum(int **M, int MRowSize, int MColSize) {
  int n = MRowSize;
  int nGroup = 0;
  int i;
  int *inGroup = (int *)calloc(n, sizeof(int));
  for (i = 0; i < n; i++) {
    if (inGroup[i] == 0) {
      nGroup++;
      inGroup[i] = 1;
      selectSameGroup(M, inGroup, n, i);
    }
  }
  return nGroup;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<findCircleNum>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    $0x4,%esi
  push   %rbp
  mov    %r12d,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %r12d,%r12d
  jle    L20
  mov    %rax,%r15
  mov    %rax,%rbp
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,%r12d
  je     L38
L40:
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jne    L26
  movl   $0x1,0x0(%rbp)
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x1,%r13d
  add    $0x4,%rbp
  call   <selectSameGroup@plt>
  cmp    %ebx,%r12d
  jne    L40
L38:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L20:
  xor    %r13d,%r13d
  jmp    L38
```

assistant: ```c
int findCircleNum(int **M, int MRowSize, int MColSize) {
  int n = MRowSize;
  int nGroup = 0;
  int i;
  int *inGroup = (int *)calloc(n, sizeof(int));
  for (i = 0; i < n; i++) {
    if (inGroup[i] == 0) {
      nGroup++;
      inGroup[i] = 1;
      selectSameGroup(M, inGroup, n, i);
    }
  }
  return nGroup;
}
```
user: What is the c source code of the assembly code below:

```asm
<findCircleNum>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    $0x4,%esi
  push   %rbp
  mov    %r12d,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %r12d,%r12d
  jle    L25
  mov    %rax,%r15
  mov    %rax,%rbp
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,%r12d
  je     L57
L7:
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jne    L17
  movl   $0x1,0x0(%rbp)
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x1,%r13d
  add    $0x4,%rbp
  call   <selectSameGroup@plt>
  cmp    %ebx,%r12d
  jne    L7
L57:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L25:
  xor    %r13d,%r13d
  jmp    L57
```

assistant: ```c
int findCircleNum(int **M, int MRowSize, int MColSize) {
  int n = MRowSize;
  int nGroup = 0;
  int i;
  int *inGroup = (int *)calloc(n, sizeof(int));
  for (i = 0; i < n; i++) {
    if (inGroup[i] == 0) {
      nGroup++;
      inGroup[i] = 1;
      selectSameGroup(M, inGroup, n, i);
    }
  }
  return nGroup;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L26
L23:
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L25
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L25:
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L3
  subl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x0,-0xc(%rbp)
  jg     L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(int *arr, int n) {
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++)
      if (arr[j] > arr[j + 1]) {
        int temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  lea    0x4(%rdi),%r9
  test   %r8d,%r8d
  jg     L54
  ret
L60:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L5
L31:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L60
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L60
L5:
  sub    $0x1,%r8d
  je     L25
L54:
  test   %r8d,%r8d
  jle    L5
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L31
L25:
  ret
```

assistant: ```c
void sort(int *arr, int n) {
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++)
      if (arr[j] > arr[j + 1]) {
        int temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L19
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rdi,%rax,4),%ecx
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %edx,%ecx
  jle    L31
  mov    %ecx,0x4(%rdi,%rax,4)
  mov    %edx,(%rdi,%rax,4)
L31:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L13
  sub    $0x1,%esi
  jne    L10
L19:
  ret
```

assistant: ```c
void sort(int *arr, int n) {
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++)
      if (arr[j] > arr[j + 1]) {
        int temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sort>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L16
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L28:
  movq   (%rdi,%rdx,4),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L37
  movq   %xmm1,(%rdi,%rdx,4)
L37:
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L28
  sub    $0x1,%esi
  jne    L31
L16:
  ret
```

assistant: ```c
void sort(int *arr, int n) {
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++)
      if (arr[j] > arr[j + 1]) {
        int temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L6
L39:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0x989680,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L25
L36:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L25:
  cmpl   $0x2,-0x14(%rbp)
  jle    L36
  addl   $0x1,-0x18(%rbp)
L6:
  cmpl   $0x6,-0x18(%rbp)
  jle    L39
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string

tool: D16: ddot

tool: D24: # c::%s:len=%d


tool: D14: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ddot", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D7(%rip),%r15
  jmp    L10
L34:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L14
L10:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0x989680,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L16:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L16
  jmp    L34
L14:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D24
type_infered: string
name: disassemble_data
arguments: label: D22
type_infered: string

tool: D7: ddot

tool: D24: # c::%s:len=%d


tool: D22: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ddot", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D4(%rip),%r15
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L9:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L4:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L4
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L9
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D29
type: string
name: extract_symbolic_data
arguments: label: D13
type: string

tool: D4: ddot

tool: D29: # c::%s:len=%d


tool: D13: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ddot", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D6(%rip),%r15
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L17:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L18:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L18
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L17
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D28
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string

tool: D6: ddot

tool: D28: # c::%s:len=%d


tool: D14: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ddot", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below:

```asm
<sqlite3IsNaN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  setp   %al
  mov    $0x1,%edx
  ucomisd -0x18(%rbp),%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sqlite3IsNaN(double x) {
  volatile double y = x;
  return x != y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sqlite3IsNaN>:
  endbr64
  movsd  %xmm0,-0x8(%rsp)
  movsd  -0x8(%rsp),%xmm1
  ucomisd %xmm0,%xmm1
  setp   %al
  movzbl %al,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int sqlite3IsNaN(double x) {
  volatile double y = x;
  return x != y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sqlite3IsNaN>:
  endbr64
  movsd  %xmm0,-0x8(%rsp)
  movsd  -0x8(%rsp),%xmm1
  xor    %eax,%eax
  mov    $0x1,%edx
  ucomisd %xmm0,%xmm1
  setp   %al
  cmovne %edx,%eax
  ret
```

assistant: ```c
int sqlite3IsNaN(double x) {
  volatile double y = x;
  return x != y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqlite3IsNaN>:
  endbr64
  movsd  %xmm0,-0x8(%rsp)
  movsd  -0x8(%rsp),%xmm1
  xor    %eax,%eax
  mov    $0x1,%edx
  ucomisd %xmm0,%xmm1
  setp   %al
  cmovne %edx,%eax
  ret
```

assistant: ```c
int sqlite3IsNaN(double x) {
  volatile double y = x;
  return x != y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<romfs_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  sarl   $0x2,-0x1c(%rbp)
  jmp    L12
L8:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  add    %eax,-0x10(%rbp)
  subl   $0x1,-0x1c(%rbp)
L12:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L8
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int romfs_checksum(void *data, int size) {
  int32_t sum, word, *ptr;
  sum = 0;
  ptr = data;
  size >>= 2;
  while (size > 0) {
    word = *ptr++;
    sum += ntohl(word);
    size--;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<romfs_checksum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sar    $0x2,%esi
  test   %esi,%esi
  jle    L20
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%r12
  mov    $0x0,%ebp
L3:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%edi
  call   <ntohl@plt>
  add    %eax,%ebp
  cmp    %r12,%rbx
  jne    L3
L10:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    $0x0,%ebp
  jmp    L10
```

assistant: ```c
int romfs_checksum(void *data, int size) {
  int32_t sum, word, *ptr;
  sum = 0;
  ptr = data;
  size >>= 2;
  while (size > 0) {
    word = *ptr++;
    sum += ntohl(word);
    size--;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<romfs_checksum>:
  endbr64
  sar    $0x2,%esi
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  movslq %esi,%rsi
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    (%rdi,%rsi,4),%rbp
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <ntohl@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L0
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int romfs_checksum(void *data, int size) {
  int32_t sum, word, *ptr;
  sum = 0;
  ptr = data;
  size >>= 2;
  while (size > 0) {
    word = *ptr++;
    sum += ntohl(word);
    size--;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<romfs_checksum>:
  endbr64
  sar    $0x2,%esi
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  movslq %esi,%rsi
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    (%rdi,%rsi,4),%rbp
  nopl   0x0(%rax)
L2:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <ntohl@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L2
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int romfs_checksum(void *data, int size) {
  int32_t sum, word, *ptr;
  sum = 0;
  ptr = data;
  size >>= 2;
  while (size > 0) {
    word = *ptr++;
    sum += ntohl(word);
    size--;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<INThandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: Interupted!


assistant: ```c
void INThandler(int sig) {
  printf("Interupted!\n");
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<INThandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: Interupted!


assistant: ```c
void INThandler(int sig) {
  printf("Interupted!\n");
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<INThandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D3: Interupted!


assistant: ```c
void INThandler(int sig) {
  printf("Interupted!\n");
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<INThandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D8: Interupted!


assistant: ```c
void INThandler(int sig) {
  printf("Interupted!\n");
  exit(1);
}
```