ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<aligned_malloc>:
  endbr64
  test   %rdi,%rdi
  je     L8
  lea    -0x1(%rsi),%rax
  test   %rsi,%rax
  jne    L36
  push   %rbx
  mov    $0x8,%eax
  cmp    %rax,%rsi
  cmovae %rsi,%rax
  mov    %rax,%rbx
  mov    $0xfffffffffffffff6,%rdx
  sub    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdi,%rdx
  jb     L35
  lea    0x7(%rbx,%rdi,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L30
  lea    0x7(%rbx,%rax,1),%rax
  neg    %rbx
  and    %rbx,%rax
  mov    %rax,%rcx
  sub    %rdx,%rcx
  mov    %rcx,-0x8(%rax)
L35:
  pop    %rbx
  ret
L8:
  mov    $0x0,%eax
  ret
L36:
  mov    $0x0,%eax
  ret
L30:
  mov    $0x0,%eax
  jmp    L35
```

assistant: ```c
void *aligned_malloc(size_t bytes, size_t alignment) {
  size_t real_alignment;
  size_t real_size;
  size_t alignment_mask;
  size_t adj_size;
  unsigned long p;
  unsigned long ret_p;
  size_t sizet;
  if (bytes == 0)
    return NULL;
  if (alignment & (alignment - 1))
    return NULL;
  sizet = sizeof(size_t);
  real_alignment = alignment < sizet ? sizet : alignment;
  alignment_mask = ~(real_alignment - 1);
  if (bytes > (size_t)-1 - sizet - real_alignment - 1)
    return NULL;
  real_size = bytes + real_alignment - 1 + sizet;
  if ((p = (unsigned long)malloc(real_size)) == 0)
    return NULL;
  ret_p = (p + sizet + real_alignment - 1) & alignment_mask;
  adj_size = ret_p - p;
  ((size_t *)ret_p)[-1] = adj_size;
  return (void *)ret_p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aligned_malloc>:
  endbr64
  test   %rdi,%rdi
  je     L20
  lea    -0x1(%rsi),%rax
  test   %rsi,%rax
  jne    L20
  mov    $0x8,%eax
  push   %rbx
  cmp    %rax,%rsi
  cmovae %rsi,%rax
  mov    %rax,%rbx
  mov    $0xfffffffffffffff6,%rax
  sub    %rbx,%rax
  cmp    %rdi,%rax
  jb     L4
  lea    0x7(%rbx,%rdi,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L4
  lea    0x7(%rax,%rbx,1),%rax
  neg    %rbx
  and    %rbx,%rax
  mov    %rax,%rcx
  sub    %rdx,%rcx
  mov    %rcx,-0x8(%rax)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *aligned_malloc(size_t bytes, size_t alignment) {
  size_t real_alignment;
  size_t real_size;
  size_t alignment_mask;
  size_t adj_size;
  unsigned long p;
  unsigned long ret_p;
  size_t sizet;
  if (bytes == 0)
    return NULL;
  if (alignment & (alignment - 1))
    return NULL;
  sizet = sizeof(size_t);
  real_alignment = alignment < sizet ? sizet : alignment;
  alignment_mask = ~(real_alignment - 1);
  if (bytes > (size_t)-1 - sizet - real_alignment - 1)
    return NULL;
  real_size = bytes + real_alignment - 1 + sizet;
  if ((p = (unsigned long)malloc(real_size)) == 0)
    return NULL;
  ret_p = (p + sizet + real_alignment - 1) & alignment_mask;
  adj_size = ret_p - p;
  ((size_t *)ret_p)[-1] = adj_size;
  return (void *)ret_p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aligned_malloc>:
  endbr64
  test   %rdi,%rdi
  je     L18
  lea    -0x1(%rsi),%rax
  test   %rsi,%rax
  jne    L18
  mov    $0x8,%eax
  push   %rbx
  cmp    %rax,%rsi
  cmovae %rsi,%rax
  mov    %rax,%rbx
  mov    $0xfffffffffffffff6,%rax
  sub    %rbx,%rax
  cmp    %rdi,%rax
  jb     L19
  lea    0x7(%rbx,%rdi,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L19
  lea    0x7(%rax,%rbx,1),%rax
  neg    %rbx
  and    %rbx,%rax
  mov    %rax,%rcx
  sub    %rdx,%rcx
  mov    %rcx,-0x8(%rax)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *aligned_malloc(size_t bytes, size_t alignment) {
  size_t real_alignment;
  size_t real_size;
  size_t alignment_mask;
  size_t adj_size;
  unsigned long p;
  unsigned long ret_p;
  size_t sizet;
  if (bytes == 0)
    return NULL;
  if (alignment & (alignment - 1))
    return NULL;
  sizet = sizeof(size_t);
  real_alignment = alignment < sizet ? sizet : alignment;
  alignment_mask = ~(real_alignment - 1);
  if (bytes > (size_t)-1 - sizet - real_alignment - 1)
    return NULL;
  real_size = bytes + real_alignment - 1 + sizet;
  if ((p = (unsigned long)malloc(real_size)) == 0)
    return NULL;
  ret_p = (p + sizet + real_alignment - 1) & alignment_mask;
  adj_size = ret_p - p;
  ((size_t *)ret_p)[-1] = adj_size;
  return (void *)ret_p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ActualFileRename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rename@plt>
  nop
  leave
  ret
```

assistant: ```c
void ActualFileRename(const char *origname, const char *newname) {
  rename(origname, newname);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ActualFileRename>:
  endbr64
  sub    $0x8,%rsp
  call   <rename@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ActualFileRename(const char *origname, const char *newname) {
  rename(origname, newname);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ActualFileRename>:
  endbr64
  jmp    1050 <rename@plt>
```

assistant: ```c
void ActualFileRename(const char *origname, const char *newname) {
  rename(origname, newname);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ActualFileRename>:
  endbr64
  jmp    1050 <rename@plt>
```

assistant: ```c
void ActualFileRename(const char *origname, const char *newname) {
  rename(origname, newname);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L4:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L78
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L78
  cmpl   $0x2b,-0xc(%rbp)
  je     L78
  cmpl   $0x2d,-0xc(%rbp)
  je     L78
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  mov    $0x0,%eax
  jmp    L23
L78:
  cmpl   $0x2d,-0xc(%rbp)
  jne    L79
  mov    $0xffffffff,%eax
  jmp    L51
L79:
  mov    $0x1,%eax
L51:
  mov    %eax,-0x8(%rbp)
  cmpl   $0x2b,-0xc(%rbp)
  je     L133
  cmpl   $0x2d,-0xc(%rbp)
  jne    L87
L133:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L106
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  mov    $0x0,%eax
  jmp    L23
L106:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L87:
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L98
L7:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sub    $0x30,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0xc(%rbp)
L98:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L7
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L21
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L21:
  mov    -0xc(%rbp),%eax
L23:
  leave
  ret
```

assistant: ```c
int get_int(int *i) {
  int current_char;
  int sign;
  while (isspace(current_char = getch())) {
  }
  if (!isdigit(current_char) && current_char != EOF && current_char != '+' && current_char != '-') {
    ungetch(current_char);
    return 0;
  }
  sign = (current_char == '-' ? -1 : 1);
  if (current_char == '+' || current_char == '-') {
    int tmp = current_char;
    if (!isdigit(current_char = getch())) {
      ungetch(tmp);
      ungetch(current_char);
      return 0;
    }
    ungetch(current_char);
  }
  for (*i = 0; isdigit(current_char); current_char = getch()) {
    *i = *i * 10 + (current_char - '0');
  }
  *i *= sign;
  if (current_char != EOF) {
    ungetch(current_char);
  }
  return current_char;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L102:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L102
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L91
  mov    D7(%rip),%rax
  cmp    %ebx,(%rax)
  je     L91
  lea    -0x2b(%rbx),%eax
  test   $0xfffffffd,%eax
  jne    L95
L91:
  cmp    $0x2d,%ebx
  je     L62
  lea    -0x2b(%rbx),%eax
  test   $0xfffffffd,%eax
  je     L27
  mov    $0x1,%r12d
L40:
  movl   $0x0,0x0(%rbp)
  jmp    L86
L95:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x0,%ebx
  jmp    L31
L27:
  mov    $0x1,%r12d
  jmp    L67
L62:
  mov    $0xffffffff,%r12d
L67:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r13d
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L85
  mov    %r13d,%edi
  call   <ungetch@plt>
  mov    %r13d,%ebx
  jmp    L40
L85:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    %r13d,%edi
  call   <ungetch@plt>
  mov    $0x0,%ebx
  jmp    L31
L147:
  mov    0x0(%rbp),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rbx,%rax,2),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
L86:
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L147
  imul   0x0(%rbp),%r12d
  mov    %r12d,0x0(%rbp)
  mov    D7(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L1
L31:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %ebx,%edi
  call   <ungetch@plt>
  jmp    L31
```

assistant: ```c
int get_int(int *i) {
  int current_char;
  int sign;
  while (isspace(current_char = getch())) {
  }
  if (!isdigit(current_char) && current_char != EOF && current_char != '+' && current_char != '-') {
    ungetch(current_char);
    return 0;
  }
  sign = (current_char == '-' ? -1 : 1);
  if (current_char == '+' || current_char == '-') {
    int tmp = current_char;
    if (!isdigit(current_char = getch())) {
      ungetch(tmp);
      ungetch(current_char);
      return 0;
    }
    ungetch(current_char);
  }
  for (*i = 0; isdigit(current_char); current_char = getch()) {
    *i = *i * 10 + (current_char - '0');
  }
  *i *= sign;
  if (current_char != EOF) {
    ungetch(current_char);
  }
  return current_char;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L62:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L62
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L12
  mov    D16(%rip),%rax
  cmp    %r12d,(%rax)
  je     L12
  lea    -0x2b(%r12),%eax
  and    $0xfffffffd,%eax
  jne    L5
L12:
  cmp    $0x2d,%r12d
  je     L46
  mov    $0x1,%ebp
  cmp    $0x2b,%r12d
  je     L108
L7:
  movl   $0x0,(%rbx)
  jmp    L45
  xchg   %ax,%ax
L111:
  mov    (%rbx),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%r12,%rax,2),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
L45:
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L111
  imul   (%rbx),%ebp
  mov    D16(%rip),%rax
  mov    %ebp,(%rbx)
  cmp    %r12d,(%rax)
  jne    L95
L21:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L95:
  mov    %r12d,%edi
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L46:
  mov    $0xffffffff,%ebp
L108:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r13d
  call   <isdigit@plt>
  test   %rax,%rax
  je     L42
  mov    %r13d,%edi
  mov    %r13d,%r12d
  call   <ungetch@plt>
  jmp    L7
L5:
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <ungetch@plt>
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <ungetch@plt>
  mov    %r13d,%edi
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_int(int *i) {
  int current_char;
  int sign;
  while (isspace(current_char = getch())) {
  }
  if (!isdigit(current_char) && current_char != EOF && current_char != '+' && current_char != '-') {
    ungetch(current_char);
    return 0;
  }
  sign = (current_char == '-' ? -1 : 1);
  if (current_char == '+' || current_char == '-') {
    int tmp = current_char;
    if (!isdigit(current_char = getch())) {
      ungetch(tmp);
      ungetch(current_char);
      return 0;
    }
    ungetch(current_char);
  }
  for (*i = 0; isdigit(current_char); current_char = getch()) {
    *i = *i * 10 + (current_char - '0');
  }
  *i *= sign;
  if (current_char != EOF) {
    ungetch(current_char);
  }
  return current_char;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L64:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L64
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L20
  mov    D1(%rip),%rax
  cmp    %r12d,(%rax)
  je     L20
  lea    -0x2b(%r12),%eax
  and    $0xfffffffd,%eax
  jne    L81
L20:
  cmp    $0x2d,%r12d
  je     L50
  mov    $0x1,%ebp
  cmp    $0x2b,%r12d
  je     L22
L93:
  movl   $0x0,(%rbx)
  jmp    L113
  xchg   %ax,%ax
L78:
  mov    (%rbx),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%r12,%rax,2),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
L113:
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L78
  imul   (%rbx),%ebp
  mov    D1(%rip),%rax
  mov    %ebp,(%rbx)
  cmp    %r12d,(%rax)
  jne    L13
L86:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r12d,%edi
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L50:
  mov    $0xffffffff,%ebp
L22:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r13d
  call   <isdigit@plt>
  test   %rax,%rax
  je     L71
  mov    %r13d,%edi
  mov    %r13d,%r12d
  call   <ungetch@plt>
  jmp    L93
L81:
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <ungetch@plt>
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L71:
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <ungetch@plt>
  mov    %r13d,%edi
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_int(int *i) {
  int current_char;
  int sign;
  while (isspace(current_char = getch())) {
  }
  if (!isdigit(current_char) && current_char != EOF && current_char != '+' && current_char != '-') {
    ungetch(current_char);
    return 0;
  }
  sign = (current_char == '-' ? -1 : 1);
  if (current_char == '+' || current_char == '-') {
    int tmp = current_char;
    if (!isdigit(current_char = getch())) {
      ungetch(tmp);
      ungetch(current_char);
      return 0;
    }
    ungetch(current_char);
  }
  for (*i = 0; isdigit(current_char); current_char = getch()) {
    *i = *i * 10 + (current_char - '0');
  }
  *i *= sign;
  if (current_char != EOF) {
    ungetch(current_char);
  }
  return current_char;
}
```
user: What is the c source code of the assembly code below?

```asm
<pclosep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L6
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void pclosep(FILE **f) {
  if (*f)
    pclose(*f);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pclosep>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <pclose@plt>
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
void pclosep(FILE **f) {
  if (*f)
    pclose(*f);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pclosep>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  jmp    1050 <pclose@plt>
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void pclosep(FILE **f) {
  if (*f)
    pclose(*f);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pclosep>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  jmp    1050 <pclose@plt>
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void pclosep(FILE **f) {
  if (*f)
    pclose(*f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    0x10(%rbp),%rax
  mov    %rax,-0x14(%rbp)
  mov    0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0xc(%rbp),%eax
  and    $0x7f,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
unsigned int foo(long double x) {
  struct {
    char a[8];
    unsigned int b : 7;
  } c;
  __builtin_memcpy(&c, &x, sizeof(c));
  return c.b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  mov    0x10(%rsp),%eax
  and    $0x7f,%eax
  ret
```

assistant: ```c
unsigned int foo(long double x) {
  struct {
    char a[8];
    unsigned int b : 7;
  } c;
  __builtin_memcpy(&c, &x, sizeof(c));
  return c.b;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  mov    0x10(%rsp),%eax
  and    $0x7f,%eax
  ret
```

assistant: ```c
unsigned int foo(long double x) {
  struct {
    char a[8];
    unsigned int b : 7;
  } c;
  __builtin_memcpy(&c, &x, sizeof(c));
  return c.b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  mov    0x10(%rsp),%eax
  and    $0x7f,%eax
  ret
```

assistant: ```c
unsigned int foo(long double x) {
  struct {
    char a[8];
    unsigned int b : 7;
  } c;
  __builtin_memcpy(&c, &x, sizeof(c));
  return c.b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cdio_get_devices_nrg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cdio_add_device_list@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <cdio_add_device_list@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: image.nrg

assistant: ```c
char **cdio_get_devices_nrg(void) {
  char **drives = ((void *)0);
  unsigned int num_files = 0;
  cdio_add_device_list(&drives, "image.nrg", &num_files);
  cdio_add_device_list(&drives, ((void *)0), &num_files);
  return drives;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cdio_get_devices_nrg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%rbx
  mov    %rbp,%rdx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <cdio_add_device_list@plt>
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <cdio_add_device_list@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: image.nrg

assistant: ```c
char **cdio_get_devices_nrg(void) {
  char **drives = ((void *)0);
  unsigned int num_files = 0;
  cdio_add_device_list(&drives, "image.nrg", &num_files);
  cdio_add_device_list(&drives, ((void *)0), &num_files);
  return drives;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cdio_get_devices_nrg>:
  endbr64
  push   %r12
  lea    D3(%rip),%rsi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rbp
  movq   $0x0,0x10(%rsp)
  mov    %r12,%rdx
  mov    %rbp,%rdi
  movl   $0x0,0xc(%rsp)
  call   <cdio_add_device_list@plt>
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <cdio_add_device_list@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: image.nrg

assistant: ```c
char **cdio_get_devices_nrg(void) {
  char **drives = ((void *)0);
  unsigned int num_files = 0;
  cdio_add_device_list(&drives, "image.nrg", &num_files);
  cdio_add_device_list(&drives, ((void *)0), &num_files);
  return drives;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cdio_get_devices_nrg>:
  endbr64
  push   %r12
  lea    D5(%rip),%rsi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rbp
  movq   $0x0,0x10(%rsp)
  mov    %r12,%rdx
  mov    %rbp,%rdi
  movl   $0x0,0xc(%rsp)
  call   <cdio_add_device_list@plt>
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <cdio_add_device_list@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: image.nrg

assistant: ```c
char **cdio_get_devices_nrg(void) {
  char **drives = ((void *)0);
  unsigned int num_files = 0;
  cdio_add_device_list(&drives, "image.nrg", &num_files);
  cdio_add_device_list(&drives, ((void *)0), &num_files);
  return drives;
}
```
user: What is the c source code of the assembly code below?

```asm
<grid_err_strerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9523dfd,-0x4(%rbp)
  je     L7
  cmpl   $0x9523dfe,-0x4(%rbp)
  je     L18
  jmp    L46
L7:
  lea    D7(%rip),%rax
  jmp    L16
L18:
  lea    D1(%rip),%rax
  jmp    L16
L46:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D7: Nanomsg library was terminated

tool: D1: Operation cannot be performed in this state

assistant: ```c
const char *grid_err_strerror(int errnum) {
  switch (errnum) {
  case (156384712 + 53):
    return "Nanomsg library was terminated";
  case (156384712 + 54):
    return "Operation cannot be performed in this state";
  default:
    return strerror(errnum);
  }
}
```