ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<amode_to_string>:
  endbr64
  push   %rbx
  movslq %edi,%rbx
  xor    %edi,%edi
  cmp    $0x3f,%ebx
  setbe  %dil
  call   <assert@plt>
  lea    D5(%rip),%rax
  mov    (%rax,%rbx,8),%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *amode_to_string(int amode) {
  static const char *amode_string[64] = {
      "dn", "dn", "dn", "dn", "dn", "dn", "dn", "dn", "an", "an", "an", "an", "an", "an", "an", "an", "an@", "an@", "an@", "an@", "an@", "an@", "an@", "an@", "an@+", "an@+", "an@+", "an@+", "an@+", "an@+", "an@+", "an@+", "an@-", "an@-", "an@-", "an@-", "an@-", "an@-", "an@-", "an@-", "an@(d16)", "an@(d16)", "an@(d16)", "an@(d16)", "an@(d16)", "an@(d16)", "an@(d16)", "an@(d16)", "[mode 6/an]", "[mode 6/an]", "[mode 6/an]", "[mode 6/an]", "[mode 6/an]", "[mode 6/an]", "[mode 6/an]", "[mode 6/an]", "abs.w", "abs.l", "pc@(d16)", "[amode 7/3]", "#<data>", "[undefined]", "[undefined]", "[undefined]",
  };
  assert(amode >= 0 && amode < 64);
  return amode_string[amode];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *p, *q;
  p = malloc(256);
  q = malloc(256);
  gets(p);
  free(q);
  free(p);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *p, *q;
  p = malloc(256);
  q = malloc(256);
  gets(p);
  free(q);
  free(p);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x100,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <gets@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *p, *q;
  p = malloc(256);
  q = malloc(256);
  gets(p);
  free(q);
  free(p);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x100,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <gets@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *p, *q;
  p = malloc(256);
  q = malloc(256);
  gets(p);
  free(q);
  free(p);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L8
  mov    $0x0,%eax
  jmp    L12
L8:
  mov    -0xc(%rbp),%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string

tool: D8: %d

assistant: ```c
int read_int(void) {
  int x;
  if (scanf("%d", &x) != 1)
    return 0;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  mov    $0x0,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: %d

assistant: ```c
int read_int(void) {
  int x;
  if (scanf("%d", &x) != 1)
    return 0;
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_int>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  mov    $0x0,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int read_int(void) {
  int x;
  if (scanf("%d", &x) != 1)
    return 0;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_int>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  mov    $0x0,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int read_int(void) {
  int x;
  if (scanf("%d", &x) != 1)
    return 0;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rgb_to_pixel8_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <rgb_to_pixel8@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int rgb_to_pixel8_dup(unsigned int r, unsigned int g, unsigned int b) {
  unsigned int col;
  col = rgb_to_pixel8(r, g, b);
  col |= col << 8;
  col |= col << 16;
  return col;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rgb_to_pixel8_dup>:
  endbr64
  sub    $0x8,%rsp
  call   <rgb_to_pixel8@plt>
  mov    %eax,%edx
  shl    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x10,%eax
  or     %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int rgb_to_pixel8_dup(unsigned int r, unsigned int g, unsigned int b) {
  unsigned int col;
  col = rgb_to_pixel8(r, g, b);
  col |= col << 8;
  col |= col << 16;
  return col;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rgb_to_pixel8_dup>:
  endbr64
  sub    $0x8,%rsp
  call   <rgb_to_pixel8@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  shl    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x10,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int rgb_to_pixel8_dup(unsigned int r, unsigned int g, unsigned int b) {
  unsigned int col;
  col = rgb_to_pixel8(r, g, b);
  col |= col << 8;
  col |= col << 16;
  return col;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rgb_to_pixel8_dup>:
  endbr64
  sub    $0x8,%rsp
  call   <rgb_to_pixel8@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  shl    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x10,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int rgb_to_pixel8_dup(unsigned int r, unsigned int g, unsigned int b) {
  unsigned int col;
  col = rgb_to_pixel8(r, g, b);
  col |= col << 8;
  col |= col << 16;
  return col;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<computeArea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %edx,%ecx
  imul   %eax,%ecx
  mov    0x10(%rbp),%eax
  sub    -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    0x18(%rbp),%eax
  sub    -0x38(%rbp),%eax
  imul   %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jge    L23
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L23
  mov    -0x28(%rbp),%eax
  cmp    0x18(%rbp),%eax
  jge    L23
  mov    -0x30(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jg     L1
L23:
  mov    -0x14(%rbp),%eax
  jmp    L12
L1:
  mov    -0x34(%rbp),%edx
  mov    -0x24(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x28(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    0x10(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    0x18(%rbp),%edx
  mov    -0x30(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  imul   %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int computeArea(int a, int b, int c, int d, int e, int f, int g, int h) {
  int size = (c - a) * (d - b) + (g - e) * (h - f);
  if (a >= g || c <= e || b >= h || d <= f)
    return size;
  int leftMax = a > e ? a : e;
  int bottomMax = b > f ? b : f;
  int rightMin = c < g ? c : g;
  int topMin = d < h ? d : h;
  return size - (rightMin - leftMax) * (topMin - bottomMax);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<computeArea>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%r11d
  mov    %esi,%edi
  mov    %edx,%eax
  mov    0x18(%rsp),%esi
  mov    0x20(%rsp),%ebx
  sub    %r11d,%edx
  mov    %ecx,%r10d
  sub    %edi,%r10d
  imul   %r10d,%edx
  mov    %esi,%r10d
  sub    %r8d,%r10d
  mov    %ebx,%ebp
  sub    %r9d,%ebp
  imul   %ebp,%r10d
  add    %r10d,%edx
  cmp    %esi,%r11d
  jge    L0
  cmp    %r8d,%eax
  jle    L0
  cmp    %ebx,%edi
  jge    L0
  cmp    %r9d,%ecx
  jle    L0
  cmp    %esi,%eax
  cmovg  %esi,%eax
  cmp    %r8d,%r11d
  mov    %r8d,%esi
  cmovge %r11d,%esi
  sub    %esi,%eax
  cmp    %ebx,%ecx
  cmovg  %ebx,%ecx
  cmp    %r9d,%edi
  cmovge %edi,%r9d
  sub    %r9d,%ecx
  imul   %ecx,%eax
  sub    %eax,%edx
L0:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int computeArea(int a, int b, int c, int d, int e, int f, int g, int h) {
  int size = (c - a) * (d - b) + (g - e) * (h - f);
  if (a >= g || c <= e || b >= h || d <= f)
    return size;
  int leftMax = a > e ? a : e;
  int bottomMax = b > f ? b : f;
  int rightMin = c < g ? c : g;
  int topMin = d < h ? d : h;
  return size - (rightMin - leftMax) * (topMin - bottomMax);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<computeArea>:
  endbr64
  mov    %edx,%eax
  mov    %ecx,%edx
  push   %rbp
  mov    %edi,%r11d
  mov    %eax,%r10d
  push   %rbx
  mov    0x18(%rsp),%ecx
  sub    %edi,%r10d
  mov    0x20(%rsp),%ebx
  mov    %edx,%edi
  sub    %esi,%edi
  imul   %edi,%r10d
  mov    %ebx,%ebp
  mov    %ecx,%edi
  sub    %r8d,%edi
  sub    %r9d,%ebp
  imul   %ebp,%edi
  add    %edi,%r10d
  cmp    %ecx,%r11d
  jge    L7
  cmp    %r8d,%eax
  jle    L7
  cmp    %ebx,%esi
  jge    L7
  cmp    %r9d,%edx
  jle    L7
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  cmp    %r8d,%r11d
  mov    %r8d,%ecx
  cmovge %r11d,%ecx
  sub    %ecx,%eax
  cmp    %ebx,%edx
  cmovg  %ebx,%edx
  cmp    %r9d,%esi
  cmovge %esi,%r9d
  sub    %r9d,%edx
  imul   %edx,%eax
  sub    %eax,%r10d
L7:
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int computeArea(int a, int b, int c, int d, int e, int f, int g, int h) {
  int size = (c - a) * (d - b) + (g - e) * (h - f);
  if (a >= g || c <= e || b >= h || d <= f)
    return size;
  int leftMax = a > e ? a : e;
  int bottomMax = b > f ? b : f;
  int rightMin = c < g ? c : g;
  int topMin = d < h ? d : h;
  return size - (rightMin - leftMax) * (topMin - bottomMax);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<computeArea>:
  endbr64
  mov    %edx,%eax
  mov    %ecx,%edx
  push   %rbp
  mov    %edi,%r11d
  mov    %eax,%r10d
  push   %rbx
  mov    0x18(%rsp),%ecx
  sub    %edi,%r10d
  mov    0x20(%rsp),%ebx
  mov    %edx,%edi
  sub    %esi,%edi
  imul   %edi,%r10d
  mov    %ebx,%ebp
  mov    %ecx,%edi
  sub    %r8d,%edi
  sub    %r9d,%ebp
  imul   %ebp,%edi
  add    %edi,%r10d
  cmp    %ecx,%r11d
  jge    L21
  cmp    %r8d,%eax
  jle    L21
  cmp    %ebx,%esi
  jge    L21
  cmp    %r9d,%edx
  jle    L21
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  cmp    %r8d,%r11d
  mov    %r8d,%ecx
  cmovge %r11d,%ecx
  sub    %ecx,%eax
  cmp    %ebx,%edx
  cmovg  %ebx,%edx
  cmp    %r9d,%esi
  cmovge %esi,%r9d
  sub    %r9d,%edx
  imul   %edx,%eax
  sub    %eax,%r10d
L21:
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int computeArea(int a, int b, int c, int d, int e, int f, int g, int h) {
  int size = (c - a) * (d - b) + (g - e) * (h - f);
  if (a >= g || c <= e || b >= h || d <= f)
    return size;
  int leftMax = a > e ? a : e;
  int bottomMax = b > f ? b : f;
  int rightMin = c < g ? c : g;
  int topMin = d < h ? d : h;
  return size - (rightMin - leftMax) * (topMin - bottomMax);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sprintf(char *s, const char *format, ...) {
  int ret;
  va_list ap;
  va_start(ap, format);
  ret = vsprintf(s, format, ap);
  va_end(ap);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sprintf(char *s, const char *format, ...) {
  int ret;
  va_list ap;
  va_start(ap, format);
  ret = vsprintf(s, format, ap);
  va_end(ap);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sprintf(char *s, const char *format, ...) {
  int ret;
  va_list ap;
  va_start(ap, format);
  ret = vsprintf(s, format, ap);
  va_end(ap);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sprintf(char *s, const char *format, ...) {
  int ret;
  va_list ap;
  va_start(ap, format);
  ret = vsprintf(s, format, ap);
  va_end(ap);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<image_crop_rgb24>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,0xc(%rsp)
  mov    %rdx,%r13
  mov    %ecx,%r14d
  mov    %r9d,0x4(%rsp)
  mov    0x50(%rsp),%r12d
  mov    %r8d,0x8(%rsp)
  mov    %r8d,%eax
  imul   %ecx,%eax
  lea    (%rax,%rax,2),%r15d
  movslq %r15d,%r15
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r15,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L73
  mov    %r12d,%ecx
  mov    %r12d,%edi
  imul   %ebx,%edi
  add    0x4(%rsp),%edi
  add    %eax,%r12d
  mov    $0x0,%r8d
  mov    0xc(%rsp),%r15d
  jmp    L70
L59:
  add    $0x1,%edx
  add    $0x3,%eax
  add    $0x3,%esi
  cmp    %r11d,%eax
  je     L88
L98:
  cmp    %edx,%ebx
  jle    L59
  test   %edx,%edx
  js     L59
  movslq %esi,%r9
  movslq %eax,%r10
  movzbl 0x0(%r13,%r10,1),%r10d
  mov    %r10b,0x0(%rbp,%r9,1)
  lea    0x1(%rsi),%r9d
  movslq %r9d,%r9
  lea    0x1(%rax),%r10d
  movslq %r10d,%r10
  movzbl 0x0(%r13,%r10,1),%r10d
  mov    %r10b,0x0(%rbp,%r9,1)
  lea    0x2(%rsi),%r9d
  movslq %r9d,%r9
  lea    0x2(%rax),%r10d
  movslq %r10d,%r10
  movzbl 0x0(%r13,%r10,1),%r10d
  mov    %r10b,0x0(%rbp,%r9,1)
  jmp    L59
L88:
  add    $0x1,%ecx
  add    %r14d,%r8d
  add    %ebx,%edi
  cmp    %r12d,%ecx
  je     L73
L70:
  test   %ecx,%ecx
  js     L88
  cmp    %ecx,%r15d
  jle    L88
  test   %r14d,%r14d
  jle    L88
  lea    (%rdi,%rdi,2),%eax
  lea    (%r8,%r8,2),%esi
  lea    (%r14,%rdi,1),%edx
  lea    (%rdx,%rdx,2),%r11d
  mov    0x4(%rsp),%edx
  jmp    L98
L73:
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char *image_crop_rgb24(signed int xres, signed int yres, unsigned char *img, signed int szx, signed int szy, signed int sx, signed int sy) {
  unsigned char *cropped;
  signed int x;
  signed int y;
  void *return_value_malloc$1;
  return_value_malloc$1 = malloc((unsigned long int)(szx * szy * 3) * 1ul);
  cropped = (unsigned char *)return_value_malloc$1;
  memset((void *)cropped, 0, (unsigned long int)(szx * szy * 3) * 1ul);
  y = 0;
  while (!(y >= szy)) {
    signed int oaddr = ((y + sy) * xres + sx) * 3;
    if (y + sy >= 0) {
      if (!(y + sy >= yres)) {
        x = 0;
        while (!(x >= szx)) {
          if (x + sx >= 0) {
            if (!(x + sx >= xres)) {
              signed int addr = (szx * y + x) * 3;
              cropped[(signed long int)addr] = img[(signed long int)(oaddr + x * 3)];
              cropped[(signed long int)(addr + 1)] = img[(signed long int)(oaddr + x * 3 + 1)];
              cropped[(signed long int)(addr + 2)] = img[(signed long int)(oaddr + x * 3 + 2)];
            }
          }
          x = x + 1;
        }
      }
    }
    y = y + 1;
  }
  return cropped;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<image_crop_rgb24>:
  endbr64
  mov    %ecx,%eax
  push   %r15
  mov    %r9d,%r15d
  imul   %r8d,%eax
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  push   %rbx
  mov    %edi,%ebx
  lea    (%rax,%rax,2),%edi
  movslq %edi,%rdi
  sub    $0x18,%rsp
  mov    %r9d,0xc(%rsp)
  call   <calloc@plt>
  mov    %rax,%r10
  test   %r14d,%r14d
  jle    L69
  mov    0x50(%rsp),%edx
  xor    %r9d,%r9d
  mov    %edx,%edi
  lea    (%r14,%rdx,1),%r8d
  imul   %ebx,%edi
  add    %r15d,%edi
  jmp    L71
  xchg   %ax,%ax
L92:
  add    $0x1,%edx
  add    %r13d,%r9d
  add    %ebx,%edi
  cmp    %r8d,%edx
  je     L69
L71:
  test   %edx,%edx
  js     L92
  cmp    %edx,%ebp
  jle    L92
  test   %r13d,%r13d
  jle    L92
  lea    0x0(%r13,%rdi,1),%ecx
  lea    (%rdi,%rdi,2),%eax
  lea    (%rcx,%rcx,2),%r15d
  mov    0xc(%rsp),%ecx
  lea    (%r9,%r9,2),%esi
  nopw   0x0(%rax,%rax,1)
L20:
  test   %ecx,%ecx
  js     L97
  cmp    %ecx,%ebx
  jle    L97
  movslq %eax,%r14
  movslq %esi,%r11
  movzbl (%r12,%r14,1),%r14d
  mov    %r14b,(%r10,%r11,1)
  lea    0x1(%rax),%r14d
  lea    0x1(%rsi),%r11d
  movslq %r14d,%r14
  movslq %r11d,%r11
  movzbl (%r12,%r14,1),%r14d
  mov    %r14b,(%r10,%r11,1)
  lea    0x2(%rax),%r14d
  lea    0x2(%rsi),%r11d
  movslq %r14d,%r14
  movslq %r11d,%r11
  movzbl (%r12,%r14,1),%r14d
  mov    %r14b,(%r10,%r11,1)
L97:
  add    $0x3,%eax
  add    $0x1,%ecx
  add    $0x3,%esi
  cmp    %r15d,%eax
  jne    L20
  add    $0x1,%edx
  add    %r13d,%r9d
  add    %ebx,%edi
  cmp    %r8d,%edx
  jne    L71
L69:
  add    $0x18,%rsp
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char *image_crop_rgb24(signed int xres, signed int yres, unsigned char *img, signed int szx, signed int szy, signed int sx, signed int sy) {
  unsigned char *cropped;
  signed int x;
  signed int y;
  void *return_value_malloc$1;
  return_value_malloc$1 = malloc((unsigned long int)(szx * szy * 3) * 1ul);
  cropped = (unsigned char *)return_value_malloc$1;
  memset((void *)cropped, 0, (unsigned long int)(szx * szy * 3) * 1ul);
  y = 0;
  while (!(y >= szy)) {
    signed int oaddr = ((y + sy) * xres + sx) * 3;
    if (y + sy >= 0) {
      if (!(y + sy >= yres)) {
        x = 0;
        while (!(x >= szx)) {
          if (x + sx >= 0) {
            if (!(x + sx >= xres)) {
              signed int addr = (szx * y + x) * 3;
              cropped[(signed long int)addr] = img[(signed long int)(oaddr + x * 3)];
              cropped[(signed long int)(addr + 1)] = img[(signed long int)(oaddr + x * 3 + 1)];
              cropped[(signed long int)(addr + 2)] = img[(signed long int)(oaddr + x * 3 + 2)];
            }
          }
          x = x + 1;
        }
      }
    }
    y = y + 1;
  }
  return cropped;
}
```