ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<glmComputeTriangleTangentsf>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  mov    %rcx,%rdx
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %r15,%rsi
  push   %rbx
  sub    $0x48,%rsp
  mov    %r8,0x8(%rsp)
  lea    0x18(%rsp),%rdi
  mov    0x80(%rsp),%r14
  mov    0x88(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <glmMakeVector3f@plt>
  mov    0x8(%rsp),%rdx
  lea    0x28(%rsp),%rdi
  mov    %r15,%rsi
  call   <glmMakeVector3f@plt>
  movss  0x4(%r13),%xmm2
  mov    %r12,%rdi
  movss  0x4(%rbx),%xmm0
  movss  0x4(%r14),%xmm1
  movq   0x18(%rsp),%xmm3
  subss  %xmm2,%xmm0
  movq   0x28(%rsp),%xmm4
  subss  %xmm2,%xmm1
  movaps %xmm0,%xmm2
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm3,%xmm2
  movaps %xmm1,%xmm3
  mulss  0x20(%rsp),%xmm0
  shufps $0xe0,%xmm3,%xmm3
  mulss  0x30(%rsp),%xmm1
  mulps  %xmm4,%xmm3
  subss  %xmm1,%xmm0
  subps  %xmm3,%xmm2
  movss  %xmm0,0x8(%r12)
  movlps %xmm2,(%r12)
  call   <glmNormalizeVector3f@plt>
  movss  0x0(%r13),%xmm2
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  movss  (%r14),%xmm1
  movq   0x18(%rsp),%xmm3
  subss  %xmm2,%xmm0
  movq   0x28(%rsp),%xmm4
  subss  %xmm2,%xmm1
  movaps %xmm0,%xmm2
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm3,%xmm2
  movaps %xmm1,%xmm3
  mulss  0x20(%rsp),%xmm0
  shufps $0xe0,%xmm3,%xmm3
  mulss  0x30(%rsp),%xmm1
  mulps  %xmm4,%xmm3
  subss  %xmm1,%xmm0
  subps  %xmm3,%xmm2
  movss  %xmm0,0x8(%rbp)
  movlps %xmm2,0x0(%rbp)
  call   <glmNormalizeVector3f@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void glmComputeTriangleTangentsf(float sTangent[3], float tTangent[3], const float c1[3], const float c2[3], const float c3[3], const float t1[2], const float t2[2], const float t3[2]) {
  float side1[3], side2[3];
  float deltaT1, deltaT2, deltaS1, deltaS2;
  glmMakeVector3f(side1, c1, c2);
  glmMakeVector3f(side2, c1, c3);
  deltaT1 = t2[1] - t1[1];
  deltaT2 = t3[1] - t1[1];
  sTangent[0] = deltaT2 * side1[0] - deltaT1 * side2[0];
  sTangent[1] = deltaT2 * side1[1] - deltaT1 * side2[1];
  sTangent[2] = deltaT2 * side1[2] - deltaT1 * side2[2];
  glmNormalizeVector3f(sTangent);
  deltaS1 = t2[0] - t1[0];
  deltaS2 = t3[0] - t1[0];
  tTangent[0] = deltaS2 * side1[0] - deltaS1 * side2[0];
  tTangent[1] = deltaS2 * side1[1] - deltaS1 * side2[1];
  tTangent[2] = deltaS2 * side1[2] - deltaS1 * side2[2];
  glmNormalizeVector3f(tTangent);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<CrossProduct_SOA_pure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CrossProduct_SOA_pure(double *cx, double *cy, double *cz, double *ax, double *ay, double *az, double *bx, double *by, double *bz) {
  *cx = (*ay) * (*bz) - (*az) * (*by);
  *cy = (*az) * (*bx) - (*ax) * (*bz);
  *cz = (*ax) * (*by) - (*ay) * (*bx);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CrossProduct_SOA_pure>:
  endbr64
  mov    %rcx,%rax
  mov    0x8(%rsp),%rcx
  mov    0x10(%rsp),%r10
  mov    0x18(%rsp),%r11
  movsd  (%r8),%xmm0
  mulsd  (%r11),%xmm0
  movsd  (%r9),%xmm1
  mulsd  (%r10),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  (%r9),%xmm0
  mulsd  (%rcx),%xmm0
  movsd  (%rax),%xmm1
  mulsd  (%r11),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  movsd  (%rax),%xmm0
  mulsd  (%r10),%xmm0
  movsd  (%r8),%xmm1
  mulsd  (%rcx),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  ret
```

assistant: ```c
void CrossProduct_SOA_pure(double *cx, double *cy, double *cz, double *ax, double *ay, double *az, double *bx, double *by, double *bz) {
  *cx = (*ay) * (*bz) - (*az) * (*by);
  *cy = (*az) * (*bx) - (*ax) * (*bz);
  *cz = (*ax) * (*by) - (*ay) * (*bx);
}
```
user: What is the c source code of the assembly code below?

```asm
<CrossProduct_SOA_pure>:
  endbr64
  mov    0x10(%rsp),%r10
  mov    0x18(%rsp),%r11
  mov    %rcx,%rax
  movsd  (%r8),%xmm0
  movsd  (%r9),%xmm1
  mulsd  (%r11),%xmm0
  mov    0x8(%rsp),%rcx
  mulsd  (%r10),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  (%r9),%xmm0
  movsd  (%rax),%xmm1
  mulsd  (%rcx),%xmm0
  mulsd  (%r11),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  movsd  (%rax),%xmm0
  movsd  (%r8),%xmm1
  mulsd  (%r10),%xmm0
  mulsd  (%rcx),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  ret
```

assistant: ```c
void CrossProduct_SOA_pure(double *cx, double *cy, double *cz, double *ax, double *ay, double *az, double *bx, double *by, double *bz) {
  *cx = (*ay) * (*bz) - (*az) * (*by);
  *cy = (*az) * (*bx) - (*ax) * (*bz);
  *cz = (*ax) * (*by) - (*ay) * (*bx);
}
```
user: What is the c source code of the assembly code below:

```asm
<CrossProduct_SOA_pure>:
  endbr64
  mov    0x10(%rsp),%r10
  mov    0x18(%rsp),%r11
  mov    %rcx,%rax
  movsd  (%r8),%xmm0
  movsd  (%r9),%xmm1
  mulsd  (%r11),%xmm0
  mov    0x8(%rsp),%rcx
  mulsd  (%r10),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  (%r9),%xmm0
  movsd  (%rax),%xmm1
  mulsd  (%rcx),%xmm0
  mulsd  (%r11),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  movsd  (%rax),%xmm0
  movsd  (%r8),%xmm1
  mulsd  (%r10),%xmm0
  mulsd  (%rcx),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  ret
```

assistant: ```c
void CrossProduct_SOA_pure(double *cx, double *cy, double *cz, double *ax, double *ay, double *az, double *bx, double *by, double *bz) {
  *cx = (*ay) * (*bz) - (*az) * (*by);
  *cy = (*az) * (*bx) - (*ax) * (*bz);
  *cz = (*ax) * (*by) - (*ay) * (*bx);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <test_strings@plt>
  mov    $0x0,%eax
  call   <test_integers@plt>
  movl   $0xa,-0x4(%rbp)
  jmp    L11
L0:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <test_integers_multi@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x63,-0x4(%rbp)
  jle    L0
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  test_strings();
  test_integers();
  for (i = 10; i < 100; ++i)
    test_integers_multi(i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <test_strings@plt>
  mov    $0x0,%eax
  call   <test_integers@plt>
  mov    $0xa,%ebx
L0:
  mov    %ebx,%edi
  call   <test_integers_multi@plt>
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L0
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  test_strings();
  test_integers();
  for (i = 10; i < 100; ++i)
    test_integers_multi(i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0xa,%ebx
  call   <test_strings@plt>
  xor    %eax,%eax
  call   <test_integers@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <test_integers_multi@plt>
  cmp    $0x64,%ebx
  jne    L6
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  test_strings();
  test_integers();
  for (i = 10; i < 100; ++i)
    test_integers_multi(i);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0xa,%ebx
  call   <test_strings@plt>
  xor    %eax,%eax
  call   <test_integers@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <test_integers_multi@plt>
  cmp    $0x64,%ebx
  jne    L4
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  test_strings();
  test_integers();
  for (i = 10; i < 100; ++i)
    test_integers_multi(i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unique_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x3(%rdi),%rdi
  call   <strlen@plt>
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rdi
  call   <opendir@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x50(%rbp)
  movb   $0x5f,-0x1(%r12,%rax,1)
  movb   $0x0,0x1(%r12,%rax,1)
  movss  D13(%rip),%xmm2
  movss  %xmm2,-0x44(%rbp)
  mov    $0x1,%r14d
  mov    $0x1,%r13d
  jmp    L15
L14:
  mov    $0x0,%edi
  call   <closedir@plt>
L5:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    %r12,%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L22:
  mov    %rbx,%rdi
  call   <closedir@plt>
L11:
  add    $0x1,%r13d
  pxor   %xmm0,%xmm0
  cvtsi2ss %r13d,%xmm0
  movss  -0x44(%rbp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L69
  je     L56
L69:
  lea    0x1(%r14),%r15d
  mov    %r15d,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    %r13d,%edx
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movslq %r14d,%rax
  movb   $0x0,(%rbx,%rax,1)
  mov    -0x50(%rbp),%rax
  lea    (%r12,%rax,1),%rdi
  mov    %r15d,%edx
  mov    %rbx,%rsi
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L15:
  test   %rbx,%rbx
  jne    L22
  jmp    L11
L56:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rax),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  add    $0x1,%r14d
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movss  %xmm0,-0x44(%rbp)
  jmp    L69
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
datatype: f32
name: parse_data
arguments: tag: D1
datatype: string

tool: D13: 10

tool: D1: %d

assistant: ```c
char *unique_dir(const char *name) {
  char *new_name = malloc(strlen(name + 3));
  strncpy(new_name, name, strlen(name));
  new_name[strlen(name)] = '\0';
  DIR *d;
  if (!(d = opendir(new_name))) {
    closedir(d);
    return new_name;
  }
  int count = 1;
  int place = 1;
  float res = 10;
  int pos = strlen(name) + 1;
  new_name[pos - 1] = '_';
  new_name[pos + 1] = '\0';
  do {
    if (d)
      closedir(d);
    if (++count == res) {
      new_name = realloc(new_name, strlen(new_name) + 2);
      new_name[strlen(new_name)] = '\0';
      res = pow(10, ++place);
    }
    char *num = alloca(place + 1);
    sprintf(num, "%d", count);
    num[place] = '\0';
    strncpy(new_name + pos, num, place + 1);
  } while (d = opendir(new_name));
  return new_name;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<determine_token_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  cmp    $0x60,%eax
  je     L119
  cmp    $0x60,%eax
  jg     L67
  cmp    $0x3d,%eax
  je     L81
  cmp    $0x3d,%eax
  jg     L67
  cmp    $0x2d,%eax
  je     L81
  cmp    $0x2d,%eax
  jg     L67
  cmp    $0x23,%eax
  je     L31
  cmp    $0x2a,%eax
  je     L109
  jmp    L67
L31:
  lea    D12(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L67
L81:
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L67
L109:
  lea    D19(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L67
L119:
  lea    D11(%rip),%rax
  mov    %rax,-0x8(%rbp)
  nop
L67:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string

tool: D12: heading

tool: D2: blank_line

tool: D19: star

tool: D11: tilde

assistant: ```c
char *determine_token_type(char sample) {
  char *type;
  switch (sample) {
  case '#':
    type = "heading";
    break;
  case '-':
  case '=':
    type = "blank_line";
    break;
  case '*':
    type = "star";
    break;
  case '`':
    type = "tilde";
    break;
  }
  return type;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<determine_token_type>:
  endbr64
  lea    D40(%rip),%rax
  cmp    $0x2d,%dil
  je     L22
  jg     L23
  lea    D1(%rip),%rax
  cmp    $0x23,%dil
  je     L22
  cmp    $0x2a,%dil
  lea    D34(%rip),%rdx
  cmove  %rdx,%rax
  ret
L23:
  lea    D40(%rip),%rax
  cmp    $0x3d,%dil
  je     L22
  cmp    $0x60,%dil
  lea    D27(%rip),%rdx
  cmove  %rdx,%rax
L22:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D40
type: string
name: retrieve_data
arguments: data_tag: D1
type: string
name: retrieve_data
arguments: data_tag: D34
type: string
name: retrieve_data
arguments: data_tag: D27
type: string

tool: D40: blank_line

tool: D1: heading

tool: D34: star

tool: D27: tilde

assistant: ```c
char *determine_token_type(char sample) {
  char *type;
  switch (sample) {
  case '#':
    type = "heading";
    break;
  case '-':
  case '=':
    type = "blank_line";
    break;
  case '*':
    type = "star";
    break;
  case '`':
    type = "tilde";
    break;
  }
  return type;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<determine_token_type>:
  endbr64
  lea    D4(%rip),%rax
  cmp    $0x2d,%dil
  je     L2
  jg     L10
  lea    D0(%rip),%rax
  cmp    $0x23,%dil
  je     L2
  cmp    $0x2a,%dil
  lea    D27(%rip),%rdx
  cmove  %rdx,%rax
  ret
L10:
  cmp    $0x3d,%dil
  je     L2
  cmp    $0x60,%dil
  lea    D23(%rip),%rdx
  cmove  %rdx,%rax
L2:
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string
name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D23
datatype: string

tool: D4: blank_line

tool: D0: heading

tool: D27: star

tool: D23: tilde

assistant: ```c
char *determine_token_type(char sample) {
  char *type;
  switch (sample) {
  case '#':
    type = "heading";
    break;
  case '-':
  case '=':
    type = "blank_line";
    break;
  case '*':
    type = "star";
    break;
  case '`':
    type = "tilde";
    break;
  }
  return type;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<determine_token_type>:
  endbr64
  lea    D13(%rip),%rax
  cmp    $0x2d,%dil
  je     L11
  jg     L8
  lea    D16(%rip),%rax
  cmp    $0x23,%dil
  je     L11
  cmp    $0x2a,%dil
  lea    D2(%rip),%rdx
  cmove  %rdx,%rax
  ret
L8:
  cmp    $0x3d,%dil
  je     L11
  cmp    $0x60,%dil
  lea    D27(%rip),%rdx
  cmove  %rdx,%rax
L11:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string
name: extract_symbolic_data
arguments: data_label: D27
type: string

tool: D13: blank_line

tool: D16: heading

tool: D2: star

tool: D27: tilde

assistant: ```c
char *determine_token_type(char sample) {
  char *type;
  switch (sample) {
  case '#':
    type = "heading";
    break;
  case '-':
  case '=':
    type = "blank_line";
    break;
  case '*':
    type = "star";
    break;
  case '`':
    type = "tilde";
    break;
  }
  return type;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Operand_bt4_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_bt4_decode(unsigned int *valp) {
  *valp = *valp << 2;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Operand_bt4_decode>:
  endbr64
  shll   $0x2,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Operand_bt4_decode(unsigned int *valp) {
  *valp = *valp << 2;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Operand_bt4_decode>:
  endbr64
  shll   $0x2,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_bt4_decode(unsigned int *valp) {
  *valp = *valp << 2;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Operand_bt4_decode>:
  endbr64
  shll   $0x2,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_bt4_decode(unsigned int *valp) {
  *valp = *valp << 2;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fn1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void __attribute__((no, noclone)) fn1(void) {
  volatile int a[5];
  asm("" : : "r"(&a) : "memory");
  a[2] = a[5];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn1>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    0x14(%rsp),%eax
  mov    %eax,0x8(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no, noclone)) fn1(void) {
  volatile int a[5];
  asm("" : : "r"(&a) : "memory");
  a[2] = a[5];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn1>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    %rsp,%rax
  mov    0x14(%rsp),%eax
  mov    %eax,0x8(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no, noclone)) fn1(void) {
  volatile int a[5];
  asm("" : : "r"(&a) : "memory");
  a[2] = a[5];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn1>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    %rsp,%rax
  mov    0x14(%rsp),%eax
  mov    %eax,0x8(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no, noclone)) fn1(void) {
  volatile int a[5];
  asm("" : : "r"(&a) : "memory");
  a[2] = a[5];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<waitstartkey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L6:
  mov    $0x0,%eax
  call   <readjoy@plt>
  cmp    $0x10,%eax
  jne    L6
  nop
L12:
  mov    $0x0,%eax
  call   <readjoy@plt>
  cmp    $0x10,%eax
  je     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void waitstartkey() {
  for (; readjoy() != 0x10;)
    ;
  for (; readjoy() == 0x10;)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<waitstartkey>:
  endbr64
  sub    $0x8,%rsp
L11:
  mov    $0x0,%eax
  call   <readjoy@plt>
  cmp    $0x10,%eax
  jne    L11
L17:
  mov    $0x0,%eax
  call   <readjoy@plt>
  cmp    $0x10,%eax
  je     L17
  add    $0x8,%rsp
  ret
```

assistant: ```c
void waitstartkey() {
  for (; readjoy() != 0x10;)
    ;
  for (; readjoy() == 0x10;)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<waitstartkey>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <readjoy@plt>
  cmp    $0x10,%eax
  jne    L10
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <readjoy@plt>
  cmp    $0x10,%eax
  je     L1
  add    $0x8,%rsp
  ret
```

assistant: ```c
void waitstartkey() {
  for (; readjoy() != 0x10;)
    ;
  for (; readjoy() == 0x10;)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<waitstartkey>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <readjoy@plt>
  cmp    $0x10,%eax
  jne    L17
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  call   <readjoy@plt>
  cmp    $0x10,%eax
  je     L18
  add    $0x8,%rsp
  ret
```

assistant: ```c
void waitstartkey() {
  for (; readjoy() != 0x10;)
    ;
  for (; readjoy() == 0x10;)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RPYToRot>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movq   %xmm1,%rbp
  movq   %xmm2,%r14
  mov    %rdi,%rbx
  lea    0x28(%rsp),%r12
  lea    0x20(%rsp),%r13
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sincos@plt>
  movsd  0x20(%rsp),%xmm6
  movsd  %xmm6,0x10(%rsp)
  movsd  0x28(%rsp),%xmm5
  movsd  %xmm5,0x18(%rsp)
  mov    %r13,%rsi
  mov    %r12,%rdi
  movq   %rbp,%xmm0
  call   <sincos@plt>
  movsd  0x20(%rsp),%xmm7
  movsd  %xmm7,0x8(%rsp)
  mov    0x28(%rsp),%rbp
  mov    %r13,%rsi
  mov    %r12,%rdi
  movq   %r14,%xmm0
  call   <sincos@plt>
  movsd  0x20(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm7
  movapd %xmm7,%xmm2
  mulsd  %xmm1,%xmm2
  movsd  %xmm2,(%rbx)
  movq   %rbp,%xmm2
  mulsd  %xmm1,%xmm2
  movsd  0x18(%rsp),%xmm5
  movapd %xmm5,%xmm3
  mulsd  %xmm2,%xmm3
  movsd  0x10(%rsp),%xmm6
  movapd %xmm6,%xmm4
  mulsd  %xmm0,%xmm4
  subsd  %xmm4,%xmm3
  movsd  %xmm3,0x8(%rbx)
  mulsd  %xmm6,%xmm2
  movapd %xmm5,%xmm3
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
  movsd  %xmm2,0x10(%rbx)
  movapd %xmm7,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,0x18(%rbx)
  movq   %rbp,%xmm4
  mulsd  %xmm4,%xmm0
  movapd %xmm5,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm6,%xmm3
  mulsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm2
  movsd  %xmm2,0x20(%rbx)
  mulsd  %xmm6,%xmm0
  mulsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rbx)
  movq   %rbp,%xmm0
  xorpd  D8(%rip),%xmm0
  movsd  %xmm0,0x30(%rbx)
  mulsd  %xmm7,%xmm5
  movsd  %xmm5,0x38(%rbx)
  movapd %xmm7,%xmm0
  mulsd  %xmm6,%xmm0
  movsd  %xmm0,0x40(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void RPYToRot(double roll, double pitch, double yaw, double R[3][3]) {
  double alpha = yaw;
  double beta = pitch;
  double gamma = roll;
  R[0][0] = cos(alpha) * cos(beta);
  R[0][1] = cos(alpha) * sin(beta) * sin(gamma) - sin(alpha) * cos(gamma);
  R[0][2] = cos(alpha) * sin(beta) * cos(gamma) + sin(alpha) * sin(gamma);
  R[1][0] = sin(alpha) * cos(beta);
  R[1][1] = sin(alpha) * sin(beta) * sin(gamma) + cos(alpha) * cos(gamma);
  R[1][2] = sin(alpha) * sin(beta) * cos(gamma) - cos(alpha) * sin(gamma);
  R[2][0] = -sin(beta);
  R[2][1] = cos(beta) * sin(gamma);
  R[2][2] = cos(beta) * cos(gamma);
  return;
}
```