ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<testOptionalClosureBrV>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L9
  movsbl %sil,%edi
  jmp    *%rax
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void testOptionalClosureBrV(void (*closure)(char), char a1) {
  if (closure) {
    (*closure)(a1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<testOptionalClosureBrV>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L8
  movsbl %sil,%edi
  jmp    *%rax
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void testOptionalClosureBrV(void (*closure)(char), char a1) {
  if (closure) {
    (*closure)(a1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<matmatkij>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %r8d,-0x58(%rbp)
  mov    -0x54(%rbp),%edx
  movslq %edx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x38(%rbp)
  movslq %edx,%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    -0x54(%rbp),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x54(%rbp),%eax
  movslq %eax,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %eax,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L58
L24:
  movl   $0x0,-0x44(%rbp)
  jmp    L36
L35:
  movl   $0x0,-0x40(%rbp)
  jmp    L56
L47:
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm1
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x68(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x70(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm0
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x70(%rbp),%rsi
  add    %rsi,%rdi
  addss  %xmm1,%xmm0
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  movss  %xmm0,(%rdi,%rsi,4)
  addl   $0x1,-0x40(%rbp)
L56:
  mov    -0x40(%rbp),%esi
  cmp    -0x58(%rbp),%esi
  jl     L47
  addl   $0x1,-0x44(%rbp)
L36:
  mov    -0x44(%rbp),%esi
  cmp    -0x58(%rbp),%esi
  jl     L35
  addl   $0x1,-0x3c(%rbp)
L58:
  mov    -0x3c(%rbp),%esi
  cmp    -0x58(%rbp),%esi
  jl     L24
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void matmatkij(int LD, float A[][LD], float B[][LD], float C[][LD], int N) {
  int i = 0, j = 0, k = 0;
  for (k = 0; k < N; k++)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        C[i][j] += A[i][k] * B[k][j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matmatkij>:
  endbr64
  test   %r8d,%r8d
  jle    L27
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8d,%r11d
  movslq %edi,%rdi
  lea    0x0(,%rdi,4),%r10
  mov    %rsi,%rbx
  lea    -0x1(%r8),%edx
  lea    0x4(%rsi,%rdx,4),%r13
  mov    %r8d,%edi
L9:
  mov    %rbp,%rsi
  mov    %r12,%r9
  mov    %rbx,%rcx
  mov    $0x0,%r8d
L25:
  mov    %r9,%rdx
  mov    $0x0,%eax
L8:
  movss  (%rcx),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L8
  add    $0x1,%r8d
  add    %r10,%rcx
  add    %r10,%r9
  cmp    %r8d,%r11d
  jne    L25
  add    %r10,%rbp
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  ret
```

assistant: ```c
void matmatkij(int LD, float A[][LD], float B[][LD], float C[][LD], int N) {
  int i = 0, j = 0, k = 0;
  for (k = 0; k < N; k++)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        C[i][j] += A[i][k] * B[k][j];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<matmatkij>:
  endbr64
  test   %r8d,%r8d
  jle    L26
  mov    %rsi,%r11
  movslq %edi,%rdi
  lea    -0x1(%r8),%eax
  push   %rbp
  lea    0x0(,%rdi,4),%r9
  push   %rbx
  mov    %rdx,%rsi
  mov    %rcx,%rbx
  mov    %r8d,%r10d
  lea    0x4(%r11,%rax,4),%rbp
  mov    %r8d,%edi
  xchg   %ax,%ax
L23:
  mov    %rbx,%rdx
  mov    %r11,%rcx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L22:
  movss  (%rcx),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L22
  add    $0x1,%r8d
  add    %r9,%rcx
  add    %r9,%rdx
  cmp    %r8d,%r10d
  jne    L32
  add    $0x4,%r11
  add    %r9,%rsi
  cmp    %r11,%rbp
  jne    L23
  pop    %rbx
  pop    %rbp
  ret
L26:
  ret
```

assistant: ```c
void matmatkij(int LD, float A[][LD], float B[][LD], float C[][LD], int N) {
  int i = 0, j = 0, k = 0;
  for (k = 0; k < N; k++)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        C[i][j] += A[i][k] * B[k][j];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L19:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <inw@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    %dx,(%rax)
L9:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void insw(unsigned long port, void *dst, unsigned long count) {
  unsigned short *p = dst;
  while (count--)
    *p++ = inw(port);
}
```
user: Translate the below assembly code into C programming language:

```asm
<insw>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%rbp
  test   %rdx,%rdx
  je     L7
L9:
  mov    %r12,%rdi
  call   <inw@plt>
  add    $0x2,%rbx
  mov    %ax,-0x2(%rbx)
  sub    $0x1,%rbp
  cmp    $0xffffffffffffffff,%rbp
  jne    L9
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insw(unsigned long port, void *dst, unsigned long count) {
  unsigned short *p = dst;
  while (count--)
    *p++ = inw(port);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insw>:
  endbr64
  test   %rdx,%rdx
  je     L2
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    -0x1(%rdx),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <inw@plt>
  mov    %ax,-0x2(%rbx)
  sub    $0x1,%rbp
  jae    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void insw(unsigned long port, void *dst, unsigned long count) {
  unsigned short *p = dst;
  while (count--)
    *p++ = inw(port);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<insw>:
  endbr64
  test   %rdx,%rdx
  je     L14
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    -0x1(%rdx),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <inw@plt>
  mov    %ax,-0x2(%rbx)
  sub    $0x1,%rbp
  jae    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void insw(unsigned long port, void *dst, unsigned long count) {
  unsigned short *p = dst;
  while (count--)
    *p++ = inw(port);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ip_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <inet_ntoa@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
char *ip_to_string(unsigned long ip) {
  struct sockaddr_in client;
  memset(&client, 0, sizeof(struct sockaddr_in));
  client.sin_addr.s_addr = ip;
  return inet_ntoa(client.sin_addr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ip_to_string>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbx,(%rsp)
  mov    %rbx,%rdi
  call   <inet_ntoa@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ip_to_string(unsigned long ip) {
  struct sockaddr_in client;
  memset(&client, 0, sizeof(struct sockaddr_in));
  client.sin_addr.s_addr = ip;
  return inet_ntoa(client.sin_addr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ip_to_string>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rdi,%rbp
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  mov    %rbp,(%rsp)
  call   <inet_ntoa@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ip_to_string(unsigned long ip) {
  struct sockaddr_in client;
  memset(&client, 0, sizeof(struct sockaddr_in));
  client.sin_addr.s_addr = ip;
  return inet_ntoa(client.sin_addr);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ip_to_string>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rdi,%rbp
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  mov    %rbp,(%rsp)
  call   <inet_ntoa@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ip_to_string(unsigned long ip) {
  struct sockaddr_in client;
  memset(&client, 0, sizeof(struct sockaddr_in));
  client.sin_addr.s_addr = ip;
  return inet_ntoa(client.sin_addr);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L11
L6:
  cmpl   $0x8,-0x4(%rbp)
  jne    L64
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L11
L64:
  cmpl   $0x9,-0x4(%rbp)
  jne    L74
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L11
L74:
  cmpl   $0x5c,-0x4(%rbp)
  jne    L14
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L11
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L6
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\b') {
      putchar('\\');
      putchar('b');
    } else if (c == '\t') {
      putchar('\\');
      putchar('t');
    } else if (c == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(c);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L75
L69:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L75
L45:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L75
L26:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
L75:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L39
  cmp    $0x8,%eax
  je     L69
  cmp    $0x9,%eax
  je     L45
  cmp    $0x5c,%eax
  je     L26
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L75
L39:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\b') {
      putchar('\\');
      putchar('b');
    } else if (c == '\t') {
      putchar('\\');
      putchar('t');
    } else if (c == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(c);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D0(%rip),%rbx
  nopl   0x0(%rax)
L72:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L50
L16:
  cmp    $0x8,%eax
  je     L19
  cmp    $0x9,%eax
  je     L2
  cmp    $0x5c,%eax
  je     L43
  mov    %eax,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L16
L50:
  xor    %eax,%eax
  pop    %rbx
  ret
L43:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L72
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L72
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L72
```

assistant: ```c
main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\b') {
      putchar('\\');
      putchar('b');
    } else if (c == '\t') {
      putchar('\\');
      putchar('t');
    } else if (c == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(c);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L8
L77:
  cmp    $0x8,%eax
  je     L66
  cmp    $0x9,%eax
  je     L11
  cmp    $0x5c,%eax
  je     L60
  mov    %eax,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L77
L8:
  xor    %eax,%eax
  pop    %rbx
  ret
L60:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L66:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L1
```

assistant: ```c
main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\b') {
      putchar('\\');
      putchar('b');
    } else if (c == '\t') {
      putchar('\\');
      putchar('t');
    } else if (c == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(c);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<play>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
L41:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L46
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  jmp    L7
L46:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L9
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L41
L9:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L41
L7:
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D1
type: string
name: extract_symbolic_data
arguments: data_tag: D38
type: string
name: extract_symbolic_data
arguments: data_tag: D41
type: string
name: extract_symbolic_data
arguments: data_tag: D12
type: string

tool: D0: Enter guess: 

tool: D1: %d

tool: D38: You won in %d guesses!



tool: D41: Too low; try again.

tool: D12: Too high; try again.

assistant: ```c
int play(const int secret_number) {
  int guess, num_guesses = 0;
  while (1) {
    printf("Enter guess: ");
    scanf("%d", &guess);
    ++num_guesses;
    if (guess == secret_number) {
      printf("You won in %d guesses!\n\n", num_guesses);
      break;
    } else if (guess < secret_number)
      printf("Too low; try again.\n");
    else
      printf("Too high; try again.\n");
  }
  return num_guesses;
}
```
user: What is the c source code of the assembly code below?

```asm
<play>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D36(%rip),%r13
  lea    D37(%rip),%r12
  lea    D30(%rip),%r15
  lea    D10(%rip),%r14
  jmp    L42
L28:
  mov    %ebx,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  mov    %r15,%rdi
  call   <puts@plt>
L42:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  je     L28
  jge    L33
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L42
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D36
data_type: string
name: unpack_data
arguments: label: D37
data_type: string
name: unpack_data
arguments: label: D30
data_type: string
name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D23
data_type: string

tool: D36: Enter guess: 

tool: D37: %d

tool: D30: Too high; try again.

tool: D10: Too low; try again.

tool: D23: You won in %d guesses!



assistant: ```c
int play(const int secret_number) {
  int guess, num_guesses = 0;
  while (1) {
    printf("Enter guess: ");
    scanf("%d", &guess);
    ++num_guesses;
    if (guess == secret_number) {
      printf("You won in %d guesses!\n\n", num_guesses);
      break;
    } else if (guess < secret_number)
      printf("Too low; try again.\n");
    else
      printf("Too high; try again.\n");
  }
  return num_guesses;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<play>:
  endbr64
  push   %r15
  lea    D34(%rip),%r15
  push   %r14
  lea    D23(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D44(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L21:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  je     L40
  jge    L25
  lea    D49(%rip),%rdi
  call   <puts@plt>
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L40:
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D34
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: string
name: parse_data
arguments: data_tag: D44
type_infered: string
name: parse_data
arguments: data_tag: D49
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string

tool: D34: Too high; try again.

tool: D23: Enter guess: 

tool: D44: %d

tool: D49: Too low; try again.

tool: D26: You won in %d guesses!



assistant: ```c
int play(const int secret_number) {
  int guess, num_guesses = 0;
  while (1) {
    printf("Enter guess: ");
    scanf("%d", &guess);
    ++num_guesses;
    if (guess == secret_number) {
      printf("You won in %d guesses!\n\n", num_guesses);
      break;
    } else if (guess < secret_number)
      printf("Too low; try again.\n");
    else
      printf("Too high; try again.\n");
  }
  return num_guesses;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<play>:
  endbr64
  push   %r15
  lea    D33(%rip),%r15
  push   %r14
  lea    D48(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L41:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  je     L27
  jge    L49
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D33
datatype: string
name: parse_data
arguments: data_tag: D48
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string
name: parse_data
arguments: data_tag: D37
datatype: string

tool: D33: Too high; try again.

tool: D48: Enter guess: 

tool: D2: %d

tool: D15: Too low; try again.

tool: D37: You won in %d guesses!



assistant: ```c
int play(const int secret_number) {
  int guess, num_guesses = 0;
  while (1) {
    printf("Enter guess: ");
    scanf("%d", &guess);
    ++num_guesses;
    if (guess == secret_number) {
      printf("You won in %d guesses!\n\n", num_guesses);
      break;
    } else if (guess < secret_number)
      printf("Too low; try again.\n");
    else
      printf("Too high; try again.\n");
  }
  return num_guesses;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hd44780DisplayMode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x2,%eax
  or     $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  or     %edx,%eax
  or     -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <hd44780WriteByte@plt>
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <hd44780WriteByte@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int8_t hd44780DisplayMode(struct mcp23017 *mcp23017, struct hd44780 *hd44780, bool display, bool cursor, bool blink) {
  hd44780WriteByte(mcp23017, hd44780, 0x08 | (display * 0x04) | (cursor * 0x02) | (blink * 0x01), 0);
  hd44780WriteByte(mcp23017, hd44780, 0x01, 0);
  return 0;
}
```