ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<hex2str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L31
L2:
  mov    %edx,%r12d
  shr    $0x1f,%r12d
  add    %edx,%r12d
  sar    %r12d
  cmp    $0x1,%edx
  jle    L4
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r15
  lea    D6(%rip),%r14
  nopl   0x0(%rax)
L46:
  mov    %rbp,%rdi
  mov    %r15,%rdx
  mov    %r14,%rsi
  add    $0x2,%rbp
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L46
L4:
  movslq %r12d,%r12
  movb   $0x0,0x0(%r13,%r12,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L31:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L2
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: %02x

assistant: ```c
void hex2str(char *dest, const char *src, int slen) {
  const char *p = src;
  int i;
  unsigned int v;
  if (slen == 0)
    slen = strlen(src);
  slen /= 2;
  for (i = 0; i < slen; i++) {
    sscanf(p, "%02x", &v);
    dest[i] = (char)v;
    p += 2;
  }
  dest[slen] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L1
L48:
  mov    %edx,%r12d
  shr    $0x1f,%r12d
  add    %edx,%r12d
  sar    %r12d
  cmp    $0x1,%edx
  jle    L11
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r15
  lea    D0(%rip),%r14
  nopl   0x0(%rax)
L17:
  mov    %rbp,%rdi
  mov    %r15,%rdx
  mov    %r14,%rsi
  add    $0x2,%rbp
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L17
L11:
  movslq %r12d,%r12
  movb   $0x0,0x0(%r13,%r12,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L48
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: %02x

assistant: ```c
void hex2str(char *dest, const char *src, int slen) {
  const char *p = src;
  int i;
  unsigned int v;
  if (slen == 0)
    slen = strlen(src);
  slen /= 2;
  for (i = 0; i < slen; i++) {
    sscanf(p, "%02x", &v);
    dest[i] = (char)v;
    p += 2;
  }
  dest[slen] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_striter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L31
  cmpq   $0x0,-0x20(%rbp)
  je     L31
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rdi
  call   *%rax
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  jmp    L49
L31:
  nop
L49:
  leave
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  int i;
  if (!s || !f)
    return;
  i = 0;
  while (s[i]) {
    f(&s[i]);
    ++i;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_striter>:
  endbr64
  test   %rdi,%rdi
  je     L30
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L35
  cmpb   $0x0,(%rdi)
  je     L35
L9:
  mov    %rbx,%rdi
  call   *%rbp
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L9
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  int i;
  if (!s || !f)
    return;
  i = 0;
  while (s[i]) {
    f(&s[i]);
    ++i;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_striter>:
  endbr64
  test   %rdi,%rdi
  je     L36
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L22
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L22
  nop
L6:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L6
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L36:
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  int i;
  if (!s || !f)
    return;
  i = 0;
  while (s[i]) {
    f(&s[i]);
    ++i;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_striter>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L27
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L27
  nop
L4:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L4
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L21:
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  int i;
  if (!s || !f)
    return;
  i = 0;
  while (s[i]) {
    f(&s[i]);
    ++i;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <charlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  ja     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverse(char *s) {
  unsigned int len = charlen(s);
  char temp;
  for (int var = 0; var < len / 2; var++) {
    temp = *(s + var);
    *(s + var) = *(s + len - 1 - var);
    *(s + len - 1 - var) = temp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <charlen@plt>
  mov    %eax,%edi
  shr    %edi
  cmp    $0x1,%eax
  jbe    L7
  mov    %eax,%eax
  lea    -0x1(%rbx,%rax,1),%rdx
  mov    $0x0,%eax
L16:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%rdx),%esi
  mov    %sil,(%rbx,%rax,1)
  mov    %cl,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%edi
  ja     L16
L7:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *s) {
  unsigned int len = charlen(s);
  char temp;
  for (int var = 0; var < len / 2; var++) {
    temp = *(s + var);
    *(s + var) = *(s + len - 1 - var);
    *(s + len - 1 - var) = temp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <charlen@plt>
  mov    %eax,%ecx
  shr    %ecx
  je     L3
  mov    %eax,%eax
  mov    %rbx,%rdi
  lea    -0x2(%rbx,%rax,1),%rsi
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x1(%rcx),%eax
  sub    %rax,%rsi
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl (%rdi),%eax
  movzbl (%rdx),%ecx
  sub    $0x1,%rdx
  add    $0x1,%rdi
  mov    %cl,-0x1(%rdi)
  mov    %al,0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L11
L3:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *s) {
  unsigned int len = charlen(s);
  char temp;
  for (int var = 0; var < len / 2; var++) {
    temp = *(s + var);
    *(s + var) = *(s + len - 1 - var);
    *(s + len - 1 - var) = temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <charlen@plt>
  mov    %eax,%ecx
  shr    %ecx
  je     L0
  mov    %eax,%eax
  mov    %rbx,%rdi
  lea    -0x2(%rbx,%rax,1),%rsi
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x1(%rcx),%eax
  sub    %rax,%rsi
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%rdi),%eax
  movzbl (%rdx),%ecx
  sub    $0x1,%rdx
  add    $0x1,%rdi
  mov    %cl,-0x1(%rdi)
  mov    %al,0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L2
L0:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *s) {
  unsigned int len = charlen(s);
  char temp;
  for (int var = 0; var < len / 2; var++) {
    temp = *(s + var);
    *(s + var) = *(s + len - 1 - var);
    *(s + len - 1 - var) = temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((no, noclone)) char *foo(char *p, const char *q) {
  char *e = strchr(p, '\0');
  strcat(p, q);
  return e;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    $0x0,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((no, noclone)) char *foo(char *p, const char *q) {
  char *e = strchr(p, '\0');
  strcat(p, q);
  return e;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strchr@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((no, noclone)) char *foo(char *p, const char *q) {
  char *e = strchr(p, '\0');
  strcat(p, q);
  return e;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strchr@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((no, noclone)) char *foo(char *p, const char *q) {
  char *e = strchr(p, '\0');
  strcat(p, q);
  return e;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverseBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L2:
  shll   -0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  add    %eax,-0x8(%rbp)
  shrl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x8,-0x4(%rbp)
  jbe    L2
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int reverseBits(unsigned int initial) {
  unsigned int reversed = 0, loop;
  for (loop = 0; loop < 9; loop++) {
    reversed <<= 1;
    reversed += (initial & 1);
    initial >>= 1;
  }
  return reversed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reverseBits>:
  endbr64
  mov    $0x9,%eax
  mov    $0x0,%edx
L1:
  mov    %edi,%ecx
  and    $0x1,%ecx
  lea    (%rcx,%rdx,2),%edx
  shr    %edi
  sub    $0x1,%eax
  jne    L1
  mov    %edx,%eax
  ret
```

assistant: ```c
int reverseBits(unsigned int initial) {
  unsigned int reversed = 0, loop;
  for (loop = 0; loop < 9; loop++) {
    reversed <<= 1;
    reversed += (initial & 1);
    initial >>= 1;
  }
  return reversed;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverseBits>:
  endbr64
  mov    $0x9,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  mov    %edi,%edx
  shr    %edi
  and    $0x1,%edx
  lea    (%rdx,%r8,2),%r8d
  sub    $0x1,%eax
  jne    L4
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverseBits(unsigned int initial) {
  unsigned int reversed = 0, loop;
  for (loop = 0; loop < 9; loop++) {
    reversed <<= 1;
    reversed += (initial & 1);
    initial >>= 1;
  }
  return reversed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverseBits>:
  endbr64
  mov    %edi,%edx
  lea    (%rdi,%rdi,1),%ecx
  mov    %edi,%eax
  shr    %edx
  and    $0x2,%ecx
  shr    $0x8,%eax
  and    $0x1,%edx
  and    $0x1,%eax
  or     %ecx,%edx
  mov    %edi,%ecx
  shr    $0x2,%ecx
  and    $0x1,%ecx
  lea    (%rcx,%rdx,2),%ecx
  mov    %edi,%edx
  shr    $0x3,%edx
  and    $0x1,%edx
  lea    (%rdx,%rcx,2),%ecx
  mov    %edi,%edx
  shr    $0x4,%edx
  and    $0x1,%edx
  lea    (%rdx,%rcx,2),%ecx
  mov    %edi,%edx
  shr    $0x5,%edx
  and    $0x1,%edx
  lea    (%rdx,%rcx,2),%ecx
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x1,%edx
  lea    (%rdx,%rcx,2),%ecx
  mov    %edi,%edx
  shr    $0x7,%edx
  and    $0x1,%edx
  lea    (%rdx,%rcx,2),%edx
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
int reverseBits(unsigned int initial) {
  unsigned int reversed = 0, loop;
  for (loop = 0; loop < 9; loop++) {
    reversed <<= 1;
    reversed += (initial & 1);
    initial >>= 1;
  }
  return reversed;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cc_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  D13(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  mov    -0x1c(%rbp),%eax
  test   %rax,%rax
  js     L26
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L33
L26:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L33:
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,-0x8(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  D13(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  mov    -0x1c(%rbp),%eax
  test   %rax,%rax
  js     L35
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L31
L35:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L31:
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  movsd  -0x30(%rbp),%xmm0
  mov    -0x28(%rbp),%rdi
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <cc_init_full@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
datatype: f64

tool: D13: 1.5707963267948966

assistant: ```c
void cc_init(struct cc_context *ctx, const unsigned int px_in_w, const double rd_view_h, const double rd_view_v) {
  unsigned int px_pano_h = (unsigned int)((rd_view_h / 1.57079632679489661923) * (double)px_in_w);
  unsigned int px_pano_v = (unsigned int)((rd_view_v / 1.57079632679489661923) * (double)px_in_w);
  cc_init_full(ctx, px_in_w, rd_view_h, rd_view_v, px_pano_h, px_pano_v);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cc_init>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %rax,%xmm3
  movsd  D8(%rip),%xmm4
  movapd %xmm1,%xmm2
  divsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  cvttsd2si %xmm2,%rcx
  movapd %xmm0,%xmm2
  divsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  cvttsd2si %xmm2,%rdx
  call   <cc_init_full@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: f64

tool: D8: 1.5707963267948966

assistant: ```c
void cc_init(struct cc_context *ctx, const unsigned int px_in_w, const double rd_view_h, const double rd_view_v) {
  unsigned int px_pano_h = (unsigned int)((rd_view_h / 1.57079632679489661923) * (double)px_in_w);
  unsigned int px_pano_v = (unsigned int)((rd_view_v / 1.57079632679489661923) * (double)px_in_w);
  cc_init_full(ctx, px_in_w, rd_view_h, rd_view_v, px_pano_h, px_pano_v);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cc_init>:
  endbr64
  movsd  D8(%rip),%xmm4
  movapd %xmm1,%xmm2
  mov    %esi,%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %rax,%xmm3
  divsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  cvttsd2si %xmm2,%rcx
  movapd %xmm0,%xmm2
  divsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  cvttsd2si %xmm2,%rdx
  jmp    1050 <cc_init_full@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: f64

tool: D8: 1.5707963267948966

assistant: ```c
void cc_init(struct cc_context *ctx, const unsigned int px_in_w, const double rd_view_h, const double rd_view_v) {
  unsigned int px_pano_h = (unsigned int)((rd_view_h / 1.57079632679489661923) * (double)px_in_w);
  unsigned int px_pano_v = (unsigned int)((rd_view_v / 1.57079632679489661923) * (double)px_in_w);
  cc_init_full(ctx, px_in_w, rd_view_h, rd_view_v, px_pano_h, px_pano_v);
}
```
user: What is the c source code of the assembly code below?

```asm
<cc_init>:
  endbr64
  movsd  D2(%rip),%xmm4
  movapd %xmm1,%xmm2
  mov    %esi,%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %rax,%xmm3
  divsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  cvttsd2si %xmm2,%rcx
  movapd %xmm0,%xmm2
  divsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  cvttsd2si %xmm2,%rdx
  jmp    1050 <cc_init_full@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: f64

tool: D2: 1.5707963267948966

assistant: ```c
void cc_init(struct cc_context *ctx, const unsigned int px_in_w, const double rd_view_h, const double rd_view_v) {
  unsigned int px_pano_h = (unsigned int)((rd_view_h / 1.57079632679489661923) * (double)px_in_w);
  unsigned int px_pano_v = (unsigned int)((rd_view_v / 1.57079632679489661923) * (double)px_in_w);
  cc_init_full(ctx, px_in_w, rd_view_h, rd_view_v, px_pano_h, px_pano_v);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<t4_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0xf,-0x4(%rbp)
  jle    L0
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  D1(%rip),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x5,-0x4(%rbp)
L5:
  cmpl   $0xf,-0x4(%rbp)
  jle    L3
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: f32

tool: D1: 1

assistant: ```c
void t4_init(float *t4) {
  int i;
  for (i = 0; i < 16; i++)
    t4[i] = 0.;
  for (i = 0; i < 16; i += 5)
    t4[i] = 1.;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t4_init>:
  endbr64
  mov    %rdi,%rax
  lea    0x40(%rdi),%rdx
L1:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L1
  movss  D1(%rip),%xmm0
  movss  %xmm0,(%rdi)
  movss  %xmm0,0x14(%rdi)
  movss  %xmm0,0x28(%rdi)
  movss  %xmm0,0x3c(%rdi)
  ret
```

tool_calls: name: read_data
arguments: label: D1
type: f32

tool: D1: 1

assistant: ```c
void t4_init(float *t4) {
  int i;
  for (i = 0; i < 16; i++)
    t4[i] = 0.;
  for (i = 0; i < 16; i += 5)
    t4[i] = 1.;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t4_init>:
  endbr64
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  movups %xmm0,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  movss  D7(%rip),%xmm0
  movss  %xmm0,(%rdi)
  movss  %xmm0,0x14(%rdi)
  movss  %xmm0,0x28(%rdi)
  movss  %xmm0,0x3c(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: f32

tool: D7: 1

assistant: ```c
void t4_init(float *t4) {
  int i;
  for (i = 0; i < 16; i++)
    t4[i] = 0.;
  for (i = 0; i < 16; i += 5)
    t4[i] = 1.;
}
```
user: What is the c source code of the assembly code below:

```asm
<t4_init>:
  endbr64
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  movups %xmm0,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  movss  D2(%rip),%xmm0
  movss  %xmm0,(%rdi)
  movss  %xmm0,0x14(%rdi)
  movss  %xmm0,0x28(%rdi)
  movss  %xmm0,0x3c(%rdi)
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type: f32

tool: D2: 1

assistant: ```c
void t4_init(float *t4) {
  int i;
  for (i = 0; i < 16; i++)
    t4[i] = 0.;
  for (i = 0; i < 16; i += 5)
    t4[i] = 1.;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cntrl_c_handler_W>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <cleanupW@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void cntrl_c_handler_W(int signum) {
  cleanupW();
  exit(EXIT_SUCCESS);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cntrl_c_handler_W>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cleanupW@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cntrl_c_handler_W(int signum) {
  cleanupW();
  exit(EXIT_SUCCESS);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cntrl_c_handler_W>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cleanupW@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void cntrl_c_handler_W(int signum) {
  cleanupW();
  exit(EXIT_SUCCESS);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cntrl_c_handler_W>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cleanupW@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void cntrl_c_handler_W(int signum) {
  cleanupW();
  exit(EXIT_SUCCESS);
}
```
user: Translate the below assembly code into C programming language:

```asm
<normalize_encoding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <cli_malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L20
L31:
  lea    D19(%rip),%rax
  cmp    %rax,-0x38(%rbp)
  jne    L0
  lea    D0(%rip),%rax
  mov    %rax,-0x38(%rbp)
L0:
  movq   $0x0,-0x28(%rbp)
  jmp    L5
L38:
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addq   $0x1,-0x28(%rbp)
L5:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x28(%rbp)
  jb     L38
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
data_type: string
name: unpack_data
arguments: data_label: D0
data_type: string

tool: D19: OTHER

tool: D0: ISO-8859-1

assistant: ```c
unsigned char *normalize_encoding(const unsigned char *enc) {
  unsigned char *norm;
  size_t i;
  const size_t len = strlen((const char *)enc);
  norm = cli_malloc(len + 1);
  if (!norm)
    return NULL;
  if (enc == (const unsigned char *)"OTHER")
    enc = (const unsigned char *)"ISO-8859-1";
  for (i = 0; i < strlen((const char *)enc); i++)
    norm[i] = toupper(enc[i]);
  norm[len] = '\0';
  return norm;
}
```