ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<_mutex_release>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  movzwl %ax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x2,%eax
  movzbl %al,%eax
  or     %edx,%eax
  or     $0x13010000,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _mutex_release(unsigned int tid, unsigned int mid) {
  unsigned int cmd;
  unsigned int sta;
  cmd = (((0x13000000)) | ((1 & ((1 << 3) - 1)) << (8 + (6 + 2))) | ((tid & ((1 << 8) - 1)) << (6 + 2)) | ((mid & ((1 << 6) - 1)) << 2));
  sta = (*(volatile unsigned int *)(cmd));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_mutex_release>:
  endbr64
  shl    $0x8,%edi
  movzwl %di,%edi
  shl    $0x2,%esi
  movzbl %sil,%esi
  or     %esi,%edi
  or     $0x13010000,%edi
  mov    (%edi),%eax
  ret
```

assistant: ```c
void _mutex_release(unsigned int tid, unsigned int mid) {
  unsigned int cmd;
  unsigned int sta;
  cmd = (((0x13000000)) | ((1 & ((1 << 3) - 1)) << (8 + (6 + 2))) | ((tid & ((1 << 8) - 1)) << (6 + 2)) | ((mid & ((1 << 6) - 1)) << 2));
  sta = (*(volatile unsigned int *)(cmd));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_mutex_release>:
  endbr64
  shl    $0x8,%edi
  shl    $0x2,%esi
  movzwl %di,%edi
  movzbl %sil,%esi
  or     %esi,%edi
  or     $0x13010000,%edi
  mov    (%edi),%eax
  ret
```

assistant: ```c
void _mutex_release(unsigned int tid, unsigned int mid) {
  unsigned int cmd;
  unsigned int sta;
  cmd = (((0x13000000)) | ((1 & ((1 << 3) - 1)) << (8 + (6 + 2))) | ((tid & ((1 << 8) - 1)) << (6 + 2)) | ((mid & ((1 << 6) - 1)) << 2));
  sta = (*(volatile unsigned int *)(cmd));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_mutex_release>:
  endbr64
  shl    $0x8,%edi
  shl    $0x2,%esi
  movzwl %di,%edi
  movzbl %sil,%esi
  or     %esi,%edi
  or     $0x13010000,%edi
  mov    (%edi),%eax
  ret
```

assistant: ```c
void _mutex_release(unsigned int tid, unsigned int mid) {
  unsigned int cmd;
  unsigned int sta;
  cmd = (((0x13000000)) | ((1 & ((1 << 3) - 1)) << (8 + (6 + 2))) | ((tid & ((1 << 8) - 1)) << (6 + 2)) | ((mid & ((1 << 6) - 1)) << 2));
  sta = (*(volatile unsigned int *)(cmd));
}
```
user: What is the c source code of the assembly code below:

```asm
<array_to_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L33:
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L5
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L33
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
data_type: string
name: retrieve_data
arguments: data_tag: D16
data_type: string

tool: D17: Array to array

tool: D16: 	%d

assistant: ```c
void array_to_array(int b[][2], int m, int n) {
  int i, j;
  printf("Array to array\n");
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("\t%d", b[i][j]);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<array_to_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%r14d
  lea    D18(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L55
  lea    -0x1(%r14),%r13d
  lea    0x4(%r12,%r13,4),%rbp
  lea    -0x1(%rbx),%eax
  lea    0x0(%r13,%rax,2),%rax
  lea    0xc(%r12,%rax,4),%r15
  not    %r13
  shl    $0x2,%r13
  lea    D13(%rip),%r12
  jmp    L58
L26:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L26
L51:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L55
L58:
  lea    0x0(%r13,%rbp,1),%rbx
  test   %r14d,%r14d
  jg     L26
  jmp    L51
L55:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string

tool: D18: Array to array

tool: D13: 	%d

assistant: ```c
void array_to_array(int b[][2], int m, int n) {
  int i, j;
  printf("Array to array\n");
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("\t%d", b[i][j]);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<array_to_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    D1(%rip),%rdi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L3
  lea    -0x1(%r13),%edx
  lea    -0x1(%rbx),%ecx
  mov    $0xfffffffffffffffc,%r14
  lea    0x0(,%rdx,4),%rax
  lea    (%rdx,%rcx,2),%rdx
  lea    0x4(%r12,%rax,1),%rbp
  lea    0xc(%r12,%rdx,4),%r15
  sub    %rax,%r14
  lea    D14(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L15:
  lea    (%r14,%rbp,1),%rbx
  test   %r13d,%r13d
  jle    L22
L39:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L39
L22:
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %r15,%rbp
  jne    L15
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string
name: disassemble_data
arguments: tag: D14
type: string

tool: D1: Array to array

tool: D14: 	%d

assistant: ```c
void array_to_array(int b[][2], int m, int n) {
  int i, j;
  printf("Array to array\n");
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("\t%d", b[i][j]);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<array_to_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  lea    D10(%rip),%rdi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L61
  lea    -0x1(%r12),%eax
  lea    0xc(%r13),%rbx
  lea    0x14(%r13,%rax,8),%r13
  lea    -0x4(%rbp),%eax
  lea    0x4(,%rax,4),%rax
  lea    D5(%rip),%r12
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L60:
  test   %ebp,%ebp
  jle    L14
  mov    -0xc(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  je     L14
  mov    -0x8(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x2,%ebp
  je     L14
  mov    -0x4(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebp
  je     L14
  mov    0x8(%rsp),%rax
  mov    %rbx,%r14
  lea    (%rax,%rbx,1),%r15
L9:
  mov    (%r14),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %r15,%r14
  jne    L9
  nopl   0x0(%rax)
L14:
  mov    $0xa,%edi
  add    $0x8,%rbx
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L60
L61:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string

tool: D10: Array to array

tool: D5: 	%d

assistant: ```c
void array_to_array(int b[][2], int m, int n) {
  int i, j;
  printf("Array to array\n");
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("\t%d", b[i][j]);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x47464544434241,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x47444342,-0x16(%rbp)
  movw   $0x4b,-0x12(%rbp)
  lea    -0x16(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x6,%ecx
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <lengthLongestCommonSubstring@plt>
  mov    %eax,%ecx
  lea    -0x16(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0: Length of LCS between "%s" and "%s" = %d.


assistant: ```c
int main() {
  char str1[] = "ABCDEFG";
  char str2[] = "BCDGK";
  printf("Length of LCS between \"%s\" and \"%s\" = %d.\n", str1, str2, lengthLongestCommonSubstring(str1, 7, str2, 6));
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x47464544434241,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x47444342,0xa(%rsp)
  movw   $0x4b,0xe(%rsp)
  lea    0xa(%rsp),%rbp
  lea    0x10(%rsp),%rbx
  mov    $0x6,%ecx
  mov    %rbp,%rdx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <lengthLongestCommonSubstring@plt>
  mov    %eax,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: Length of LCS between "%s" and "%s" = %d.


assistant: ```c
int main() {
  char str1[] = "ABCDEFG";
  char str2[] = "BCDGK";
  printf("Length of LCS between \"%s\" and \"%s\" = %d.\n", str1, str2, lengthLongestCommonSubstring(str1, 7, str2, 6));
  getchar();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x6,%ecx
  mov    $0x7,%esi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x47464544434241,%rax
  lea    0xa(%rsp),%r12
  lea    0x10(%rsp),%rbp
  movl   $0x47444342,0xa(%rsp)
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  mov    $0x4b,%eax
  mov    %ax,0xe(%rsp)
  call   <lengthLongestCommonSubstring@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: Length of LCS between "%s" and "%s" = %d.


assistant: ```c
int main() {
  char str1[] = "ABCDEFG";
  char str2[] = "BCDGK";
  printf("Length of LCS between \"%s\" and \"%s\" = %d.\n", str1, str2, lengthLongestCommonSubstring(str1, 7, str2, 6));
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x6,%ecx
  mov    $0x7,%esi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x47464544434241,%rax
  lea    0xa(%rsp),%r12
  lea    0x10(%rsp),%rbp
  movl   $0x47444342,0xa(%rsp)
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  mov    $0x4b,%eax
  mov    %ax,0xe(%rsp)
  call   <lengthLongestCommonSubstring@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Length of LCS between "%s" and "%s" = %d.


assistant: ```c
int main() {
  char str1[] = "ABCDEFG";
  char str2[] = "BCDGK";
  printf("Length of LCS between \"%s\" and \"%s\" = %d.\n", str1, str2, lengthLongestCommonSubstring(str1, 7, str2, 6));
  getchar();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x2d0,-0x1c(%rbp)
  je     L4
  mov    -0x1c(%rbp),%eax
  sub    $0x2d0,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L8
  movl   $0x0,-0xc(%rbp)
  jmp    L92
L61:
  movl   $0x59f,-0x8(%rbp)
  jmp    L39
L55:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x8(%rbp)
L39:
  cmpl   $0x0,-0x8(%rbp)
  jg     L55
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L92:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L61
  jmp    L72
L8:
  negl   -0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L90
L69:
  movl   $0x1,-0x8(%rbp)
  jmp    L100
L29:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L100:
  cmpl   $0x59f,-0x8(%rbp)
  jle    L29
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L90:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L69
  jmp    L72
L4:
  nop
L72:
  pop    %rbp
  ret
```

assistant: ```c
void shift(double *rpots_daily, const int hroz) {
  int i;
  int y;
  int row;
  if (720 == hroz) {
    return;
  }
  row = hroz - 720;
  if (row > 0) {
    for (i = 0; i < row; i++) {
      for (y = 1440 - 1; y > 0; y--) {
        rpots_daily[y] = rpots_daily[y - 1];
      }
      rpots_daily[y] = 0;
    }
  } else {
    row *= -1;
    for (i = 0; i < row; i++) {
      for (y = 1; y < 1440; y++) {
        rpots_daily[y - 1] = rpots_daily[y];
      }
      rpots_daily[y - 1] = 0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift>:
  endbr64
  cmp    $0x2d0,%esi
  je     L54
  jle    L59
  sub    $0x2d0,%esi
  mov    $0x0,%ecx
L28:
  lea    0x2cf0(%rdi),%rax
L66:
  mov    %rax,%rdx
  movsd  (%rax),%xmm0
  movsd  %xmm0,0x8(%rax)
  sub    $0x8,%rax
  cmp    %rdx,%rdi
  jne    L66
  movq   $0x0,(%rdi)
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L28
L54:
  ret
L59:
  mov    $0x2d0,%r8d
  sub    %esi,%r8d
  mov    $0x0,%ecx
  lea    0x2cf8(%rdi),%rdx
  test   %r8d,%r8d
  jle    L2
L58:
  mov    %rdi,%rax
L60:
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L60
  movq   $0x0,0x2cf8(%rdi)
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L58
  jmp    L54
L2:
  ret
```

assistant: ```c
void shift(double *rpots_daily, const int hroz) {
  int i;
  int y;
  int row;
  if (720 == hroz) {
    return;
  }
  row = hroz - 720;
  if (row > 0) {
    for (i = 0; i < row; i++) {
      for (y = 1440 - 1; y > 0; y--) {
        rpots_daily[y] = rpots_daily[y - 1];
      }
      rpots_daily[y] = 0;
    }
  } else {
    row *= -1;
    for (i = 0; i < row; i++) {
      for (y = 1; y < 1440; y++) {
        rpots_daily[y - 1] = rpots_daily[y];
      }
      rpots_daily[y - 1] = 0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shift>:
  endbr64
  cmp    $0x2d0,%esi
  je     L34
  push   %r13
  lea    -0x2d0(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %r13d,%r13d
  jle    L27
  xor    %ebp,%ebp
  lea    0x8(%rdi),%r12
L36:
  mov    $0x2cf8,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <memmove@plt>
  movq   $0x0,(%rbx)
  cmp    %ebp,%r13d
  jne    L36
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    $0x2d0,%r13d
  sub    %esi,%r13d
  test   %r13d,%r13d
  jle    L31
  xor    %ebp,%ebp
  lea    0x8(%rdi),%r12
L29:
  mov    $0x2cf8,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x1,%ebp
  call   <memmove@plt>
  movq   $0x0,0x2cf8(%rbx)
  cmp    %ebp,%r13d
  jne    L29
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  ret
```

assistant: ```c
void shift(double *rpots_daily, const int hroz) {
  int i;
  int y;
  int row;
  if (720 == hroz) {
    return;
  }
  row = hroz - 720;
  if (row > 0) {
    for (i = 0; i < row; i++) {
      for (y = 1440 - 1; y > 0; y--) {
        rpots_daily[y] = rpots_daily[y - 1];
      }
      rpots_daily[y] = 0;
    }
  } else {
    row *= -1;
    for (i = 0; i < row; i++) {
      for (y = 1; y < 1440; y++) {
        rpots_daily[y - 1] = rpots_daily[y];
      }
      rpots_daily[y - 1] = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shift>:
  endbr64
  cmp    $0x2d0,%esi
  je     L9
  push   %r13
  lea    -0x2d0(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %r13d,%r13d
  jle    L34
  xor    %ebp,%ebp
  lea    0x8(%rdi),%r12
L37:
  mov    $0x2cf8,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <memmove@plt>
  movq   $0x0,(%rbx)
  cmp    %ebp,%r13d
  jne    L37
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    $0x2d0,%r13d
  sub    %esi,%r13d
  test   %r13d,%r13d
  jle    L31
  xor    %ebp,%ebp
  lea    0x8(%rdi),%r12
L43:
  mov    $0x2cf8,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x1,%ebp
  call   <memmove@plt>
  movq   $0x0,0x2cf8(%rbx)
  cmp    %ebp,%r13d
  jne    L43
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

assistant: ```c
void shift(double *rpots_daily, const int hroz) {
  int i;
  int y;
  int row;
  if (720 == hroz) {
    return;
  }
  row = hroz - 720;
  if (row > 0) {
    for (i = 0; i < row; i++) {
      for (y = 1440 - 1; y > 0; y--) {
        rpots_daily[y] = rpots_daily[y - 1];
      }
      rpots_daily[y] = 0;
    }
  } else {
    row *= -1;
    for (i = 0; i < row; i++) {
      for (y = 1; y < 1440; y++) {
        rpots_daily[y - 1] = rpots_daily[y];
      }
      rpots_daily[y - 1] = 0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<swapbytes>:
  endbr64
  mov    %rdi,%rax
  test   $0x4,%sil
  jne    L14
  test   $0x2,%sil
  jne    L42
  test   $0x1,%sil
  jne    L67
  test   $0x8,%sil
  je     L40
  test   %edx,%edx
  je     L67
  mov    %edx,%edx
  lea    (%rdi,%rdx,8),%rsi
L20:
  movzbl 0x7(%rax),%edx
  movzbl (%rax),%ecx
  mov    %cl,0x7(%rax)
  mov    %dl,(%rax)
  movzbl 0x6(%rax),%edx
  movzbl 0x1(%rax),%ecx
  mov    %cl,0x6(%rax)
  mov    %dl,0x1(%rax)
  movzbl 0x5(%rax),%edx
  movzbl 0x2(%rax),%ecx
  mov    %cl,0x5(%rax)
  mov    %dl,0x2(%rax)
  movzbl 0x4(%rax),%edx
  movzbl 0x3(%rax),%ecx
  mov    %cl,0x4(%rax)
  mov    %dl,0x3(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L20
  ret
L14:
  test   %edx,%edx
  je     L67
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rsi
L54:
  movzbl 0x3(%rax),%edx
  movzbl (%rax),%ecx
  mov    %cl,0x3(%rax)
  mov    %dl,(%rax)
  movzbl 0x2(%rax),%edx
  movzbl 0x1(%rax),%ecx
  mov    %cl,0x2(%rax)
  mov    %dl,0x1(%rax)
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L54
  ret
L42:
  test   %edx,%edx
  je     L67
  mov    %edx,%edx
  lea    (%rdi,%rdx,2),%rsi
L66:
  movzbl 0x1(%rax),%edx
  movzbl (%rax),%ecx
  mov    %cl,0x1(%rax)
  mov    %dl,(%rax)
  add    $0x2,%rax
  cmp    %rax,%rsi
  jne    L66
  ret
L40:
  sub    $0x8,%rsp
  lea    D2(%rip),%rdx
  lea    D6(%rip),%rsi
  mov    $0xffffffff,%edi
  call   <error@plt>
  add    $0x8,%rsp
  ret
L67:
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D2: swapbytes()

tool: D6: *Internal Error*: Unknown size in 

assistant: ```c
void swapbytes(void *ptr, int nb, int n) {
  char *cp, c;
  int j;
  cp = (char *)ptr;
  if (nb & 4) {
    for (j = n; j--; cp += 4) {
      c = cp[3];
      cp[3] = cp[0];
      cp[0] = c;
      c = cp[2];
      cp[2] = cp[1];
      cp[1] = c;
    }
    return;
  }
  if (nb & 2) {
    for (j = n; j--; cp += 2) {
      c = cp[1];
      cp[1] = cp[0];
      cp[0] = c;
    }
    return;
  }
  if (nb & 1)
    return;
  if (nb & 8) {
    for (j = n; j--; cp += 8) {
      c = cp[7];
      cp[7] = cp[0];
      cp[0] = c;
      c = cp[6];
      cp[6] = cp[1];
      cp[1] = c;
      c = cp[5];
      cp[5] = cp[2];
      cp[2] = c;
      c = cp[4];
      cp[4] = cp[3];
      cp[3] = c;
    }
    return;
  }
  error(-1, "*Internal Error*: Unknown size in ", "swapbytes()");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<swapbytes>:
  endbr64
  mov    %rdi,%rax
  test   $0x4,%sil
  jne    L60
  test   $0x2,%sil
  jne    L67
  test   $0x1,%sil
  jne    L64
  and    $0x8,%esi
  je     L4
  test   %edx,%edx
  je     L64
  mov    %edx,%edx
  lea    (%rdi,%rdx,8),%rsi
  nopl   0x0(%rax,%rax,1)
L39:
  movzbl 0x7(%rax),%edx
  movzbl (%rax),%ecx
  add    $0x8,%rax
  mov    %cl,-0x1(%rax)
  movzbl -0x7(%rax),%ecx
  mov    %dl,-0x8(%rax)
  movzbl -0x2(%rax),%edx
  mov    %cl,-0x2(%rax)
  movzbl -0x6(%rax),%ecx
  mov    %dl,-0x7(%rax)
  movzbl -0x3(%rax),%edx
  mov    %cl,-0x3(%rax)
  movzbl -0x5(%rax),%ecx
  mov    %dl,-0x6(%rax)
  movzbl -0x4(%rax),%edx
  mov    %cl,-0x4(%rax)
  mov    %dl,-0x5(%rax)
  cmp    %rsi,%rax
  jne    L39
  ret
  nopl   0x0(%rax)
L67:
  test   %edx,%edx
  je     L64
  mov    %edx,%edx
  lea    (%rdi,%rdx,2),%rsi
  nopw   0x0(%rax,%rax,1)
L23:
  movzbl 0x1(%rax),%edx
  movzbl (%rax),%ecx
  add    $0x2,%rax
  mov    %cl,-0x1(%rax)
  mov    %dl,-0x2(%rax)
  cmp    %rsi,%rax
  jne    L23
  ret
  nop
L64:
  ret
  nopl   0x0(%rax)
L60:
  mov    %edx,%ecx
  lea    (%rdi,%rcx,4),%rsi
  test   %edx,%edx
  je     L64
  nopw   0x0(%rax,%rax,1)
L10:
  movzbl 0x3(%rax),%edx
  movzbl (%rax),%ecx
  add    $0x4,%rax
  mov    %cl,-0x1(%rax)
  movzbl -0x3(%rax),%ecx
  mov    %dl,-0x4(%rax)
  movzbl -0x2(%rax),%edx
  mov    %cl,-0x2(%rax)
  mov    %dl,-0x3(%rax)
  cmp    %rax,%rsi
  jne    L10
  ret
  nopl   (%rax)
L4:
  lea    D7(%rip),%rdx
  lea    D12(%rip),%rsi
  mov    $0xffffffff,%edi
  jmp    1050 <error@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string

tool: D7: swapbytes()

tool: D12: *Internal Error*: Unknown size in 

assistant: ```c
void swapbytes(void *ptr, int nb, int n) {
  char *cp, c;
  int j;
  cp = (char *)ptr;
  if (nb & 4) {
    for (j = n; j--; cp += 4) {
      c = cp[3];
      cp[3] = cp[0];
      cp[0] = c;
      c = cp[2];
      cp[2] = cp[1];
      cp[1] = c;
    }
    return;
  }
  if (nb & 2) {
    for (j = n; j--; cp += 2) {
      c = cp[1];
      cp[1] = cp[0];
      cp[0] = c;
    }
    return;
  }
  if (nb & 1)
    return;
  if (nb & 8) {
    for (j = n; j--; cp += 8) {
      c = cp[7];
      cp[7] = cp[0];
      cp[0] = c;
      c = cp[6];
      cp[6] = cp[1];
      cp[1] = c;
      c = cp[5];
      cp[5] = cp[2];
      cp[2] = c;
      c = cp[4];
      cp[4] = cp[3];
      cp[3] = c;
    }
    return;
  }
  error(-1, "*Internal Error*: Unknown size in ", "swapbytes()");
  return;
}
```