ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  lea    0x20(%rsp),%rbp
  mov    0x8(%rsp),%ecx
  mov    0xc(%rsp),%r8d
  lea    D48(%rip),%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x10(%rsp),%rdi
  mov    %eax,%r12d
  call   <pipe@plt>
  lea    0x18(%rsp),%rdi
  call   <pipe@plt>
  call   <fork@plt>
  test   %eax,%eax
  je     L41
  js     L47
L10:
  mov    0x14(%rsp),%edi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <write@plt>
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    0x1c(%rsp),%edi
  call   <close@plt>
  mov    0x18(%rsp),%edi
  mov    %rbp,%rsi
  mov    $0x400,%edx
  call   <read@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  cltq
  movb   $0x0,0x20(%rsp,%rax,1)
  call   <printf@plt>
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x438,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    0x10(%rsp),%edi
  xor    %esi,%esi
  call   <dup2@plt>
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    0x1c(%rsp),%edi
  mov    $0x1,%esi
  call   <dup2@plt>
  mov    0x18(%rsp),%edi
  call   <close@plt>
  mov    0x1c(%rsp),%edi
  call   <close@plt>
  lea    D30(%rip),%rdi
  xor    %ecx,%ecx
  lea    D14(%rip),%rdx
  mov    %rdi,%rsi
  call   <execlp@plt>
  lea    D24(%rip),%rdi
  call   <die@plt>
  jmp    L10
L47:
  lea    D17(%rip),%rdi
  call   <die@plt>
  jmp    L10
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string
name: parse_data
arguments: data_label: D48
type_guessed: string
name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D30
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D24
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: string

tool: D5: %d%d

tool: D48: %d + %d


tool: D9: %s

tool: D30: /usr/bin/bc

tool: D14: --quiet

tool: D24: execlp failed

tool: D17: fork failed

assistant: ```c
int main(void) {
  int a, b, blen, pid;
  char buf[1024];
  int fd1[2], fd2[2];
  scanf("%d%d", &a, &b);
  snprintf(buf, sizeof(buf), "%d + %d\n", a, b);
  blen = strlen(buf);
  if (pipe(fd1) < 0) {
  }
  if (pipe(fd2) < 0) {
  }
  if (!(pid = fork())) {
    dup2(fd1[0], 0);
    close(fd1[0]);
    close(fd1[1]);
    dup2(fd2[1], 1);
    close(fd2[0]);
    close(fd2[1]);
    execlp("/usr/bin/bc", "/usr/bin/bc", "--quiet", NULL);
    die("execlp failed");
  } else if (pid < 0) {
    die("fork failed");
  }
  write(fd1[1], buf, blen);
  close(fd1[0]);
  close(fd1[1]);
  close(fd2[1]);
  blen = read(fd2[0], buf, sizeof(buf));
  buf[blen] = 0;
  printf("%s", buf);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hashup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  imul   $0x446f8657,%rax,%rax
  shr    $0x20,%rax
  mov    %rax,%rcx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hashup(char *s) {
  unsigned int hashval;
  hashval = 0;
  while (*s != '\0') {
    hashval = *s + 31 * hashval;
    s++;
  }
  return (hashval % 101);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hashup>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  mov    $0x0,%ecx
L8:
  mov    %ecx,%edx
  shl    $0x5,%edx
  sub    %ecx,%edx
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%ecx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L8
L25:
  mov    %ecx,%edx
  imul   $0x446f8657,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
L10:
  mov    $0x0,%ecx
  jmp    L25
```

assistant: ```c
unsigned int hashup(char *s) {
  unsigned int hashval;
  hashval = 0;
  while (*s != '\0') {
    hashval = *s + 31 * hashval;
    s++;
  }
  return (hashval % 101);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hashup>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L0
  xor    %ecx,%ecx
  nopl   (%rax)
L15:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L15
  mov    %ecx,%edx
  mov    %ecx,%eax
  imul   $0x446f8657,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
  nopl   (%rax)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hashup(char *s) {
  unsigned int hashval;
  hashval = 0;
  while (*s != '\0') {
    hashval = *s + 31 * hashval;
    s++;
  }
  return (hashval % 101);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hashup>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L11
  xor    %ecx,%ecx
  nopl   (%rax)
L4:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L4
  mov    %ecx,%edx
  mov    %ecx,%eax
  imul   $0x446f8657,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
  nopl   (%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hashup(char *s) {
  unsigned int hashval;
  hashval = 0;
  while (*s != '\0') {
    hashval = *s + 31 * hashval;
    s++;
  }
  return (hashval % 101);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<subtracao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void subtracao(void *num1, void *num2) {
  int *pnum1 = (int *)num1;
  int *pnum2 = (int *)num2;
  *pnum2 = *pnum1 - *pnum2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<subtracao>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void subtracao(void *num1, void *num2) {
  int *pnum1 = (int *)num1;
  int *pnum2 = (int *)num2;
  *pnum2 = *pnum1 - *pnum2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subtracao>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void subtracao(void *num1, void *num2) {
  int *pnum1 = (int *)num1;
  int *pnum2 = (int *)num2;
  *pnum2 = *pnum1 - *pnum2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<subtracao>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void subtracao(void *num1, void *num2) {
  int *pnum1 = (int *)num1;
  int *pnum2 = (int *)num2;
  *pnum2 = *pnum1 - *pnum2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serializer_write_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x3(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void serializer_write_int(char *dest, int *pointer, int value) {
  dest[(*pointer)] = ((value >> 0) & 0xFF);
  dest[(*pointer) + 1] = ((value >> 8) & 0xFF);
  dest[(*pointer) + 2] = ((value >> 16) & 0xFF);
  dest[(*pointer) + 3] = ((value >> 24) & 0xFF);
  (*pointer) += 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<serializer_write_int>:
  endbr64
  movslq (%rsi),%rax
  mov    %dl,(%rdi,%rax,1)
  movslq (%rsi),%rax
  movzbl %dh,%ecx
  mov    %cl,0x1(%rdi,%rax,1)
  movslq (%rsi),%rax
  mov    %edx,%ecx
  sar    $0x10,%ecx
  mov    %cl,0x2(%rdi,%rax,1)
  movslq (%rsi),%rax
  shr    $0x18,%edx
  mov    %dl,0x3(%rdi,%rax,1)
  addl   $0x4,(%rsi)
  ret
```

assistant: ```c
void serializer_write_int(char *dest, int *pointer, int value) {
  dest[(*pointer)] = ((value >> 0) & 0xFF);
  dest[(*pointer) + 1] = ((value >> 8) & 0xFF);
  dest[(*pointer) + 2] = ((value >> 16) & 0xFF);
  dest[(*pointer) + 3] = ((value >> 24) & 0xFF);
  (*pointer) += 4;
}
```
user: What is the c source code of the assembly code below?

```asm
<serializer_write_int>:
  endbr64
  movslq (%rsi),%rax
  mov    %edx,%ecx
  sar    $0x10,%ecx
  mov    %dl,(%rdi,%rax,1)
  movslq (%rsi),%rax
  mov    %dh,0x1(%rdi,%rax,1)
  movslq (%rsi),%rax
  shr    $0x18,%edx
  mov    %cl,0x2(%rdi,%rax,1)
  movslq (%rsi),%rax
  mov    %dl,0x3(%rdi,%rax,1)
  addl   $0x4,(%rsi)
  ret
```

assistant: ```c
void serializer_write_int(char *dest, int *pointer, int value) {
  dest[(*pointer)] = ((value >> 0) & 0xFF);
  dest[(*pointer) + 1] = ((value >> 8) & 0xFF);
  dest[(*pointer) + 2] = ((value >> 16) & 0xFF);
  dest[(*pointer) + 3] = ((value >> 24) & 0xFF);
  (*pointer) += 4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<serializer_write_int>:
  endbr64
  movslq (%rsi),%rax
  mov    %edx,%ecx
  sar    $0x10,%ecx
  mov    %dl,(%rdi,%rax,1)
  movslq (%rsi),%rax
  mov    %dh,0x1(%rdi,%rax,1)
  movslq (%rsi),%rax
  shr    $0x18,%edx
  mov    %cl,0x2(%rdi,%rax,1)
  movslq (%rsi),%rax
  mov    %dl,0x3(%rdi,%rax,1)
  addl   $0x4,(%rsi)
  ret
```

assistant: ```c
void serializer_write_int(char *dest, int *pointer, int value) {
  dest[(*pointer)] = ((value >> 0) & 0xFF);
  dest[(*pointer) + 1] = ((value >> 8) & 0xFF);
  dest[(*pointer) + 2] = ((value >> 16) & 0xFF);
  dest[(*pointer) + 3] = ((value >> 24) & 0xFF);
  (*pointer) += 4;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scan1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L55
  nop
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  jmp    L14
L11:
  nop
  mov    -0x18(%rbp),%rax
  jmp    L30
L55:
  nop
  addq   $0x1,-0x18(%rbp)
  mov    $0x0,%eax
  jmp    L30
L13:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
L14:
  movsbl -0x1(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L11
  jmp    L13
L30:
  pop    %rbp
  ret
```

assistant: ```c
char *scan1(char *p) {
  char *q;
  {
    char yych;
  yy8:
    if ((p - p) < 2)
      ;
    yych = *p;
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy10;
    default:
      goto yy12;
    }
  yy10:
    ++p;
    yych = *p;
    goto yy15;
  yy11 : { return p; }
  yy12:
    ++p;
    { return ((char *)0); }
  yy14:
    ++p;
    if (p <= p)
      ;
    yych = *p;
  yy15:
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy14;
    default:
      goto yy11;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<scan1>:
  endbr64
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  mov    $0x0,%edx
  cmp    $0x9,%eax
  ja     L23
  lea    0x1(%rdi),%rdx
  movsbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L23
L29:
  add    $0x1,%rdx
  movsbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L29
L23:
  mov    %rdx,%rax
  ret
```

assistant: ```c
char *scan1(char *p) {
  char *q;
  {
    char yych;
  yy8:
    if ((p - p) < 2)
      ;
    yych = *p;
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy10;
    default:
      goto yy12;
    }
  yy10:
    ++p;
    yych = *p;
    goto yy15;
  yy11 : { return p; }
  yy12:
    ++p;
    { return ((char *)0); }
  yy14:
    ++p;
    if (p <= p)
      ;
    yych = *p;
  yy15:
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy14;
    default:
      goto yy11;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scan1>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L4
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L4
  nopw   0x0(%rax,%rax,1)
L22:
  movsbl 0x1(%r8),%eax
  add    $0x1,%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L22
L4:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *scan1(char *p) {
  char *q;
  {
    char yych;
  yy8:
    if ((p - p) < 2)
      ;
    yych = *p;
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy10;
    default:
      goto yy12;
    }
  yy10:
    ++p;
    yych = *p;
    goto yy15;
  yy11 : { return p; }
  yy12:
    ++p;
    { return ((char *)0); }
  yy14:
    ++p;
    if (p <= p)
      ;
    yych = *p;
  yy15:
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy14;
    default:
      goto yy11;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scan1>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L26
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L26
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl 0x1(%r8),%eax
  add    $0x1,%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L18
L26:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *scan1(char *p) {
  char *q;
  {
    char yych;
  yy8:
    if ((p - p) < 2)
      ;
    yych = *p;
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy10;
    default:
      goto yy12;
    }
  yy10:
    ++p;
    yych = *p;
    goto yy15;
  yy11 : { return p; }
  yy12:
    ++p;
    { return ((char *)0); }
  yy14:
    ++p;
    if (p <= p)
      ;
    yych = *p;
  yy15:
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy14;
    default:
      goto yy11;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pst_fwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L0
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L19
L0:
  movq   $0x0,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t pst_fwrite(const void *ptr, size_t size, size_t nmemb, FILE *stream) {
  size_t r;
  {};
  if (ptr != NULL)
    r = fwrite(ptr, size, nmemb, stream);
  else {
    r = 0;
    {};
  }
  {};
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pst_fwrite>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <fwrite@plt>
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
size_t pst_fwrite(const void *ptr, size_t size, size_t nmemb, FILE *stream) {
  size_t r;
  {};
  if (ptr != NULL)
    r = fwrite(ptr, size, nmemb, stream);
  else {
    r = 0;
    {};
  }
  {};
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pst_fwrite>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <fwrite@plt>
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t pst_fwrite(const void *ptr, size_t size, size_t nmemb, FILE *stream) {
  size_t r;
  {};
  if (ptr != NULL)
    r = fwrite(ptr, size, nmemb, stream);
  else {
    r = 0;
    {};
  }
  {};
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pst_fwrite>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <fwrite@plt>
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t pst_fwrite(const void *ptr, size_t size, size_t nmemb, FILE *stream) {
  size_t r;
  {};
  if (ptr != NULL)
    r = fwrite(ptr, size, nmemb, stream);
  else {
    r = 0;
    {};
  }
  {};
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<optimain_two>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hexa_line_two@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void optimain_two(int n) {
  hexa_line_two(n);
  ft_putchar('\n');
}
```
user: What is the c source code of the assembly code below:

```asm
<optimain_two>:
  endbr64
  sub    $0x8,%rsp
  call   <hexa_line_two@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void optimain_two(int n) {
  hexa_line_two(n);
  ft_putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<optimain_two>:
  endbr64
  sub    $0x8,%rsp
  call   <hexa_line_two@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1060 <ft_putchar@plt>
```

assistant: ```c
void optimain_two(int n) {
  hexa_line_two(n);
  ft_putchar('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<optimain_two>:
  endbr64
  sub    $0x8,%rsp
  call   <hexa_line_two@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1060 <ft_putchar@plt>
```

assistant: ```c
void optimain_two(int n) {
  hexa_line_two(n);
  ft_putchar('\n');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isatty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int isatty(int fd) {
  int retval;
  struct termios t;
  retval = 1;
  return (retval);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isatty>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isatty(int fd) {
  int retval;
  struct termios t;
  retval = 1;
  return (retval);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isatty>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isatty(int fd) {
  int retval;
  struct termios t;
  retval = 1;
  return (retval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isatty>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isatty(int fd) {
  int retval;
  struct termios t;
  retval = 1;
  return (retval);
}
```
user: Translate the below assembly code into C programming language:

```asm
<merge>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    %edx,0xc(%rsp)
  mov    %edx,%r15d
  sub    %esi,%r15d
  lea    0x1(%r15),%r13d
  sub    %edx,%ecx
  mov    %ecx,%ebp
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %r13d,%r13d
  jle    L156
  mov    %r15d,%eax
  lea    0x4(,%rax,4),%rdi
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%rsi
  mov    $0x0,%eax
L19:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%r12,%rax,1)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L19
L156:
  test   %ebp,%ebp
  jle    L108
  lea    0x1(%rbp),%edi
  movslq 0xc(%rsp),%rax
  lea    (%r14,%rax,4),%rsi
  mov    $0x1,%eax
L115:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,-0x4(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L115
  test   %r13d,%r13d
  jle    L111
  lea    0x1(%rbx),%edi
  movslq %ebx,%rbx
  lea    (%r14,%rbx,4),%rsi
  mov    $0x0,%eax
  mov    $0x0,%edx
  jmp    L56
L99:
  add    $0x1,%eax
  mov    %edi,%ebx
  mov    %r8d,(%rsi)
L75:
  add    $0x1,%edi
  add    $0x4,%rsi
  cmp    %r13d,%edx
  jge    L101
  cmp    %ebp,%eax
  jge    L101
L56:
  movslq %edx,%r8
  mov    (%r12,%r8,4),%r9d
  movslq %eax,%r8
  mov    (%rcx,%r8,4),%r8d
  cmp    %r8d,%r9d
  jg     L99
  add    $0x1,%edx
  mov    %edi,%ebx
  mov    %r9d,(%rsi)
  jmp    L75
L101:
  cmp    %r13d,%edx
  jge    L163
L11:
  mov    %edx,%r10d
  mov    %r15d,%r9d
  sub    %edx,%r9d
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%r8
  movslq %ebx,%rdx
  lea    (%r14,%rdx,4),%rdi
  mov    $0x0,%edx
L62:
  mov    (%r8,%rdx,4),%esi
  mov    %esi,(%rdi,%rdx,4)
  mov    %rdx,%rsi
  add    $0x1,%rdx
  cmp    %r9,%rsi
  jne    L62
  lea    0x1(%r15,%rbx,1),%ebx
  sub    %r10d,%ebx
L163:
  cmp    %ebp,%eax
  jge    L59
  cltq
  movslq %ebx,%rbx
  sub    %rax,%rbx
  lea    (%r14,%rbx,4),%rsi
L100:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L100
L59:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L111:
  mov    $0x0,%eax
  jmp    L163
L108:
  mov    $0x0,%eax
  mov    $0x0,%edx
  test   %r13d,%r13d
  jg     L11
  jmp    L59
```

assistant: ```c
void merge(int *a, int p, int q, int r) {
  int n1 = q - p + 1;
  int n2 = r - q;
  int *left = malloc(n1 * sizeof(int));
  int *right = malloc(n2 * sizeof(int));
  int i, j, k;
  for (i = 0; i < n1; i++)
    left[i] = a[p + i];
  for (j = 0; j < n2; j++)
    right[j] = a[q + j + 1];
  i = j = 0;
  k = p;
  while (i < n1 & j < n2) {
    if (left[i] <= right[j]) {
      a[k++] = left[i++];
    } else {
      a[k++] = right[j++];
    }
  }
  while (i < n1) {
    a[k++] = left[i++];
  }
  while (j < n2) {
    a[k++] = right[j++];
  }
}
```