ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rmkdir>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  lea    D0(%rip),%rdx
  mov    %esi,%r12d
  push   %rbp
  mov    $0x104,%esi
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rsp,%rax,1)
  jne    L37
  movb   $0x0,-0x1(%rsp,%rax,1)
L37:
  movzbl 0x1(%rsp),%eax
  test   %al,%al
  je     L2
  lea    0x1(%rsp),%rbx
  nopl   0x0(%rax)
L6:
  cmp    $0x2f,%al
  jne    L21
  cmpb   $0x3a,-0x1(%rbx)
  je     L21
  mov    %r12d,%esi
  mov    %rbp,%rdi
  movb   $0x0,(%rbx)
  call   <mkdir@plt>
  movb   $0x2f,(%rbx)
L21:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L6
L2:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: %s

assistant: ```c
int rmkdir(const char *path, int mode) {
  char tmp[260];
  char *p = NULL;
  size_t len;
  snprintf(tmp, sizeof(tmp), "%s", path);
  len = strlen(tmp);
  if (len >= sizeof(tmp)) {
    return -1;
  }
  if (tmp[len - 1] == '/') {
    tmp[len - 1] = 0;
  }
  for (p = tmp + 1; *p; p++) {
    if (*p != '/')
      continue;
    if (*(p - 1) == ':')
      continue;
    *p = 0;
    mkdir(tmp, mode);
    *p = '/';
  }
  mkdir(tmp, mode);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x73,-0x30(%rbp)
  movb   $0x77,-0x27(%rbp)
  movb   $0x6b,-0x1e(%rbp)
  movb   $0x69,-0x2f(%rbp)
  movb   $0x79,-0x26(%rbp)
  movb   $0x72,-0x1d(%rbp)
  movb   $0x6e,-0x2e(%rbp)
  movb   $0x63,-0x25(%rbp)
  movb   $0x6a,-0x1c(%rbp)
  movb   $0x68,-0x2d(%rbp)
  movb   $0x20,-0x24(%rbp)
  movb   $0x75,-0x1b(%rbp)
  movb   $0x6d,-0x2c(%rbp)
  movb   $0x62,-0x23(%rbp)
  movb   $0x64,-0x1a(%rbp)
  movb   $0x74,-0x2b(%rbp)
  movb   $0x71,-0x22(%rbp)
  movb   $0x67,-0x19(%rbp)
  movb   $0x70,-0x2a(%rbp)
  movb   $0x78,-0x21(%rbp)
  movb   $0x6f,-0x18(%rbp)
  movb   $0x61,-0x29(%rbp)
  movb   $0x65,-0x20(%rbp)
  movb   $0x66,-0x17(%rbp)
  movb   $0x6c,-0x28(%rbp)
  movb   $0x76,-0x1f(%rbp)
  movb   $0x7a,-0x16(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L29
L22:
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L29:
  mov    -0x34(%rbp),%eax
  test   %eax,%eax
  jns    L22
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D21
data_type: string
name: disassemble_data
arguments: label: D22
data_type: string

tool: D21: %i

tool: D22: 


assistant: ```c
int main() {
  char klucz[27];
  int n;
  klucz[0] = 's';
  klucz[9] = 'w';
  klucz[18] = 'k';
  klucz[1] = 'i';
  klucz[10] = 'y';
  klucz[19] = 'r';
  klucz[2] = 'n';
  klucz[11] = 'c';
  klucz[20] = 'j';
  klucz[3] = 'h';
  klucz[12] = ' ';
  klucz[21] = 'u';
  klucz[4] = 'm';
  klucz[13] = 'b';
  klucz[22] = 'd';
  klucz[5] = 't';
  klucz[14] = 'q';
  klucz[23] = 'g';
  klucz[6] = 'p';
  klucz[15] = 'x';
  klucz[24] = 'o';
  klucz[7] = 'a';
  klucz[16] = 'e';
  klucz[25] = 'f';
  klucz[8] = 'l';
  klucz[17] = 'v';
  klucz[26] = 'z';
  scanf("%i", &n);
  while (n >= 0) {
    scanf("%i", &n);
    printf("%c", klucz[n]);
  }
  printf("\n\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movb   $0x73,0x10(%rsp)
  movb   $0x77,0x19(%rsp)
  movb   $0x6b,0x22(%rsp)
  movb   $0x69,0x11(%rsp)
  movb   $0x79,0x1a(%rsp)
  movb   $0x72,0x23(%rsp)
  movb   $0x6e,0x12(%rsp)
  movb   $0x63,0x1b(%rsp)
  movb   $0x6a,0x24(%rsp)
  movb   $0x68,0x13(%rsp)
  movb   $0x20,0x1c(%rsp)
  movb   $0x75,0x25(%rsp)
  movb   $0x6d,0x14(%rsp)
  movb   $0x62,0x1d(%rsp)
  movb   $0x64,0x26(%rsp)
  movb   $0x74,0x15(%rsp)
  movb   $0x71,0x1e(%rsp)
  movb   $0x67,0x27(%rsp)
  movb   $0x70,0x16(%rsp)
  movb   $0x78,0x1f(%rsp)
  movb   $0x6f,0x28(%rsp)
  movb   $0x61,0x17(%rsp)
  movb   $0x65,0x20(%rsp)
  movb   $0x66,0x29(%rsp)
  movb   $0x6c,0x18(%rsp)
  movb   $0x76,0x21(%rsp)
  movb   $0x7a,0x2a(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  js     L29
  lea    D29(%rip),%rbx
L2:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  movsbl 0x10(%rsp,%rax,1),%edi
  call   <putchar@plt>
  cmpl   $0x0,0xc(%rsp)
  jns    L2
L29:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D29
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string

tool: D29: %i

tool: D10: 


assistant: ```c
int main() {
  char klucz[27];
  int n;
  klucz[0] = 's';
  klucz[9] = 'w';
  klucz[18] = 'k';
  klucz[1] = 'i';
  klucz[10] = 'y';
  klucz[19] = 'r';
  klucz[2] = 'n';
  klucz[11] = 'c';
  klucz[20] = 'j';
  klucz[3] = 'h';
  klucz[12] = ' ';
  klucz[21] = 'u';
  klucz[4] = 'm';
  klucz[13] = 'b';
  klucz[22] = 'd';
  klucz[5] = 't';
  klucz[14] = 'q';
  klucz[23] = 'g';
  klucz[6] = 'p';
  klucz[15] = 'x';
  klucz[24] = 'o';
  klucz[7] = 'a';
  klucz[16] = 'e';
  klucz[25] = 'f';
  klucz[8] = 'l';
  klucz[17] = 'v';
  klucz[26] = 'z';
  scanf("%i", &n);
  while (n >= 0) {
    scanf("%i", &n);
    printf("%c", klucz[n]);
  }
  printf("\n\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x666f,%edx
  push   %rbx
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x6170746d686e6973,%rax
  lea    0xc(%rsp),%rbp
  mov    %dx,0x28(%rsp)
  mov    %rbp,%rsi
  movb   $0x7a,0x2a(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x787162206379776c,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6764756a726b7665,%rax
  mov    %rax,0x20(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  js     L20
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  movsbl 0x10(%rsp,%rax,1),%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L15
L20:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string
name: disassemble_data
arguments: label: D1
data_type: string

tool: D6: %i

tool: D1: 


assistant: ```c
int main() {
  char klucz[27];
  int n;
  klucz[0] = 's';
  klucz[9] = 'w';
  klucz[18] = 'k';
  klucz[1] = 'i';
  klucz[10] = 'y';
  klucz[19] = 'r';
  klucz[2] = 'n';
  klucz[11] = 'c';
  klucz[20] = 'j';
  klucz[3] = 'h';
  klucz[12] = ' ';
  klucz[21] = 'u';
  klucz[4] = 'm';
  klucz[13] = 'b';
  klucz[22] = 'd';
  klucz[5] = 't';
  klucz[14] = 'q';
  klucz[23] = 'g';
  klucz[6] = 'p';
  klucz[15] = 'x';
  klucz[24] = 'o';
  klucz[7] = 'a';
  klucz[16] = 'e';
  klucz[25] = 'f';
  klucz[8] = 'l';
  klucz[17] = 'v';
  klucz[26] = 'z';
  scanf("%i", &n);
  while (n >= 0) {
    scanf("%i", &n);
    printf("%c", klucz[n]);
  }
  printf("\n\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x666f,%edx
  push   %rbx
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x48,%rsp
  movdqa D37(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    D14(%rip),%rax
  mov    %dx,0x28(%rsp)
  mov    %rbp,%rsi
  movb   $0x7a,0x2a(%rsp)
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  js     L20
  nopl   0x0(%rax)
L29:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  movsbl 0x10(%rsp,%rax,1),%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L29
L20:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type: string
name: extract_symbolic_data
arguments: label: D37
type: byte[16]
name: extract_symbolic_data
arguments: label: D14
type: byte[8]
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D20: %i

tool: {"D37": [0x73,0x69,0x6e,0x68,0x6d,0x74,0x70,0x61,0x6c,0x77,0x79,0x63,0x20,0x62,0x71,0x78]}

tool: {"D14": [0x65,0x76,0x6b,0x72,0x6a,0x75,0x64,0x67]}

tool: D9: 


assistant: ```c
int main() {
  char klucz[27];
  int n;
  klucz[0] = 's';
  klucz[9] = 'w';
  klucz[18] = 'k';
  klucz[1] = 'i';
  klucz[10] = 'y';
  klucz[19] = 'r';
  klucz[2] = 'n';
  klucz[11] = 'c';
  klucz[20] = 'j';
  klucz[3] = 'h';
  klucz[12] = ' ';
  klucz[21] = 'u';
  klucz[4] = 'm';
  klucz[13] = 'b';
  klucz[22] = 'd';
  klucz[5] = 't';
  klucz[14] = 'q';
  klucz[23] = 'g';
  klucz[6] = 'p';
  klucz[15] = 'x';
  klucz[24] = 'o';
  klucz[7] = 'a';
  klucz[16] = 'e';
  klucz[25] = 'f';
  klucz[8] = 'l';
  klucz[17] = 'v';
  klucz[26] = 'z';
  scanf("%i", &n);
  while (n >= 0) {
    scanf("%i", &n);
    printf("%c", klucz[n]);
  }
  printf("\n\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x30(%rbp)
  movl   $0x14,-0x2c(%rbp)
  movl   $0x1e,-0x28(%rbp)
  movl   $0x28,-0x24(%rbp)
  movl   $0x32,-0x20(%rbp)
  movl   $0x3c,-0x1c(%rbp)
  movl   $0x46,-0x18(%rbp)
  movl   $0x7,-0x34(%rbp)
  mov    -0x34(%rbp),%ecx
  lea    -0x30(%rbp),%rax
  mov    $0x7,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <findkmax@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: 
 <<<<>>>>>>Kth max is [%u]

assistant: ```c
int main() {
  int arr[] = {10, 20, 30, 40, 50, 60, 70};
  int len = sizeof(arr) / sizeof(arr[0]);
  printf("\n <<<<>>>>>>Kth max is [%u]", findkmax(arr, len, 7));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xa,(%rsp)
  movl   $0x14,0x4(%rsp)
  movl   $0x1e,0x8(%rsp)
  movl   $0x28,0xc(%rsp)
  movl   $0x32,0x10(%rsp)
  movl   $0x3c,0x14(%rsp)
  movl   $0x46,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0x7,%edx
  mov    $0x7,%esi
  call   <findkmax@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: 
 <<<<>>>>>>Kth max is [%u]

assistant: ```c
int main() {
  int arr[] = {10, 20, 30, 40, 50, 60, 70};
  int len = sizeof(arr) / sizeof(arr[0]);
  printf("\n <<<<>>>>>>Kth max is [%u]", findkmax(arr, len, 7));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x7,%esi
  mov    $0x7,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x140000000a,%rax
  mov    %rsp,%rdi
  movl   $0x46,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x280000001e,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x3c00000032,%rax
  mov    %rax,0x10(%rsp)
  call   <findkmax@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string

tool: D6: 
 <<<<>>>>>>Kth max is [%u]

assistant: ```c
int main() {
  int arr[] = {10, 20, 30, 40, 50, 60, 70};
  int len = sizeof(arr) / sizeof(arr[0]);
  printf("\n <<<<>>>>>>Kth max is [%u]", findkmax(arr, len, 7));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x7,%esi
  mov    $0x7,%edx
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rdi
  movl   $0x46,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <findkmax@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type_infered: byte[16]
name: extract_symbolic_data
arguments: tag: D0
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D27
type_infered: string

tool: {"D26": [0x0a,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x28,0x00,0x00,0x00]}

tool: {"D0": [0x32,0x00,0x00,0x00,0x3c,0x00,0x00,0x00]}

tool: D27: 
 <<<<>>>>>>Kth max is [%u]

assistant: ```c
int main() {
  int arr[] = {10, 20, 30, 40, 50, 60, 70};
  int len = sizeof(arr) / sizeof(arr[0]);
  printf("\n <<<<>>>>>>Kth max is [%u]", findkmax(arr, len, 7));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<allNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L21
L0:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printerror@plt>
L21:
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L25
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: input contains invalid characters

assistant: ```c
void allNum(char *str) {
  int i = 0;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] < '0' || str[i] > '9') {
      printerror("input contains invalid characters");
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<allNum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D6(%rip),%r12
  jmp    L5
L6:
  add    $0x1,%rbx
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L25
  movzbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L6
  mov    %r12,%rdi
  call   <printerror@plt>
  jmp    L6
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: string

tool: D6: input contains invalid characters

assistant: ```c
void allNum(char *str) {
  int i = 0;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] < '0' || str[i] > '9') {
      printerror("input contains invalid characters");
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<allNum>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L36:
  add    $0x1,%rbx
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L2
  movzbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L36
  mov    %r12,%rdi
  call   <printerror@plt>
  jmp    L36
  cs nopw 0x0(%rax,%rax,1)
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: input contains invalid characters

assistant: ```c
void allNum(char *str) {
  int i = 0;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] < '0' || str[i] > '9') {
      printerror("input contains invalid characters");
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<allNum>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L32:
  add    $0x1,%rbx
L21:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L19
  movzbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L32
  mov    %r12,%rdi
  call   <printerror@plt>
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: input contains invalid characters

assistant: ```c
void allNum(char *str) {
  int i = 0;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] < '0' || str[i] > '9') {
      printerror("input contains invalid characters");
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<int_pr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %esi,-0x34(%rbp)
  mov    %edx,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L6
L3:
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x38(%rbp),%xmm2
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  movapd %xmm0,%xmm1
  mov    %ecx,%esi
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <pr@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L6:
  mov    -0x1c(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L3
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x38(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double int_pr(double *pars, double d_max, int n_c, int nslice) {
  double sum = 0.0;
  double r;
  double value;
  int i;
  for (i = 0; i < nslice; i++) {
    r = d_max / (1.0 * nslice) * i;
    value = pr(pars, d_max, n_c, r);
    sum += value;
  }
  return sum / (1.0 * nslice) * d_max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_pr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%r14
  mov    %edx,%ebp
  test   %edx,%edx
  jle    L3
  mov    %rdi,%r12
  mov    %esi,%r13d
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movq   %r14,%xmm4
  divsd  %xmm0,%xmm4
  movsd  %xmm4,0x8(%rsp)
  mov    $0x0,%ebx
  pxor   %xmm6,%xmm6
  movsd  %xmm6,(%rsp)
L19:
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  mulsd  0x8(%rsp),%xmm1
  mov    %r13d,%esi
  movq   %r14,%xmm0
  mov    %r12,%rdi
  call   <pr@plt>
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L19
L23:
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %r14,%xmm5
  mulsd  %xmm5,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
  jmp    L23
```

assistant: ```c
double int_pr(double *pars, double d_max, int n_c, int nslice) {
  double sum = 0.0;
  double r;
  double value;
  int i;
  for (i = 0; i < nslice; i++) {
    r = d_max / (1.0 * nslice) * i;
    value = pr(pars, d_max, n_c, r);
    sum += value;
  }
  return sum / (1.0 * nslice) * d_max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_pr>:
  endbr64
  pxor   %xmm5,%xmm5
  push   %r13
  movapd %xmm0,%xmm3
  push   %r12
  cvtsi2sd %edx,%xmm5
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm5,0x18(%rsp)
  test   %edx,%edx
  jle    L11
  movapd %xmm0,%xmm6
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  divsd  %xmm5,%xmm6
  xor    %ebx,%ebx
  pxor   %xmm2,%xmm2
  movsd  %xmm6,0x10(%rsp)
L9:
  pxor   %xmm1,%xmm1
  movapd %xmm3,%xmm0
  mov    %r13d,%esi
  mov    %r12,%rdi
  cvtsi2sd %ebx,%xmm1
  mulsd  0x10(%rsp),%xmm1
  movsd  %xmm3,(%rsp)
  add    $0x1,%ebx
  movsd  %xmm2,0x8(%rsp)
  call   <pr@plt>
  movsd  0x8(%rsp),%xmm2
  cmp    %ebx,%ebp
  movsd  (%rsp),%xmm3
  addsd  %xmm0,%xmm2
  jne    L9
L12:
  divsd  0x18(%rsp),%xmm2
  mulsd  %xmm3,%xmm2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  movapd %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  pxor   %xmm2,%xmm2
  jmp    L12
```

assistant: ```c
double int_pr(double *pars, double d_max, int n_c, int nslice) {
  double sum = 0.0;
  double r;
  double value;
  int i;
  for (i = 0; i < nslice; i++) {
    r = d_max / (1.0 * nslice) * i;
    value = pr(pars, d_max, n_c, r);
    sum += value;
  }
  return sum / (1.0 * nslice) * d_max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_pr>:
  endbr64
  pxor   %xmm5,%xmm5
  push   %r13
  movapd %xmm0,%xmm3
  push   %r12
  cvtsi2sd %edx,%xmm5
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm5,0x18(%rsp)
  test   %edx,%edx
  jle    L28
  movapd %xmm0,%xmm6
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  divsd  %xmm5,%xmm6
  xor    %ebx,%ebx
  pxor   %xmm2,%xmm2
  movsd  %xmm6,0x10(%rsp)
L5:
  pxor   %xmm1,%xmm1
  movapd %xmm3,%xmm0
  mov    %r13d,%esi
  mov    %r12,%rdi
  cvtsi2sd %ebx,%xmm1
  mulsd  0x10(%rsp),%xmm1
  movsd  %xmm3,(%rsp)
  add    $0x1,%ebx
  movsd  %xmm2,0x8(%rsp)
  call   <pr@plt>
  movsd  0x8(%rsp),%xmm2
  cmp    %ebx,%ebp
  movsd  (%rsp),%xmm3
  addsd  %xmm0,%xmm2
  jne    L5
L11:
  divsd  0x18(%rsp),%xmm2
  mulsd  %xmm3,%xmm2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  movapd %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  pxor   %xmm2,%xmm2
  jmp    L11
```

assistant: ```c
double int_pr(double *pars, double d_max, int n_c, int nslice) {
  double sum = 0.0;
  double r;
  double value;
  int i;
  for (i = 0; i < nslice; i++) {
    r = d_max / (1.0 * nslice) * i;
    value = pr(pars, d_max, n_c, r);
    sum += value;
  }
  return sum / (1.0 * nslice) * d_max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<IRobotStartCleaning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <iRobot_Start@plt>
  mov    $0x3e8,%edi
  call   <DelayTime@plt>
  mov    $0x0,%eax
  call   <iRobot_SafeMode@plt>
  mov    $0x3e8,%edi
  call   <DelayTime@plt>
  mov    $0x0,%eax
  call   <iRobot_DefaultClean@plt>
  mov    $0x3e8,%edi
  call   <DelayTime@plt>
  mov    $0x0,%eax
  call   <iRobot_Stop@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void IRobotStartCleaning() {
  iRobot_Start();
  DelayTime(1000);
  iRobot_SafeMode();
  DelayTime(1000);
  iRobot_DefaultClean();
  DelayTime(1000);
  iRobot_Stop();
}
```