ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aes_block_decrypt>:
  endbr64
  push   %r15
  mov    %ecx,%r8d
  mov    %rdx,%r9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r13
  mov    %rbx,%rcx
L1:
  xor    %eax,%eax
L59:
  movzbl (%rdi,%rax,4),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L59
  add    $0x1,%esi
  add    $0x1,%rdi
  add    $0x4,%rcx
  cmp    $0x4,%esi
  jne    L1
  mov    %r8d,%r12d
  lea    0x10(%rsp),%r15
  mov    %r8d,%esi
  mov    %r9,%rdi
  sar    $0x2,%r12d
  mov    %r15,%rdx
  call   <compute_key_schedule@plt>
  add    $0x6,%r12d
  mov    %rbx,%rdi
  lea    0x0(,%r12,4),%r14d
  movslq %r14d,%r14
  shl    $0x2,%r14
  lea    (%r15,%r14,1),%rsi
  lea    -0x10(%r15,%r14,1),%r14
  call   <add_round_key@plt>
  jmp    L56
  nop
L15:
  mov    %rbx,%rdi
  sub    $0x1,%r12d
  call   <inversion_mix_columns@plt>
L56:
  test   %r12d,%r12d
  jle    L44
  mov    %rbx,%rdi
  call   <inversion_shift_rows@plt>
  mov    %rbx,%rdi
  call   <inversion_subsitution_bytes@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  sub    $0x10,%r14
  call   <add_round_key@plt>
  cmp    $0x1,%r12d
  jne    L15
L44:
  mov    %rbp,%rcx
  xor    %esi,%esi
L5:
  xor    %eax,%eax
L43:
  movzbl 0x0(%r13,%rax,1),%edx
  mov    %dl,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L43
  add    $0x1,%esi
  add    $0x4,%r13
  add    $0x1,%rcx
  cmp    $0x4,%esi
  jne    L5
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_block_decrypt(const unsigned char *input_block, unsigned char *output_block, const unsigned char *key, int key_size) {
  int i;
  int j;
  int ronde;
  int number;
  unsigned char state[4][4];
  unsigned char w[60][4];
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      state[i][j] = input_block[i + (j * 4)];
    }
  }
  number = (key_size >> 2) + 6;
  compute_key_schedule(key, key_size, w);
  add_round_key(state, &w[number * 4]);
  for (ronde = number; ronde > 0; ronde--) {
    inversion_shift_rows(state);
    inversion_subsitution_bytes(state);
    add_round_key(state, &w[(ronde - 1) * 4]);
    if (ronde > 1) {
      inversion_mix_columns(state);
    }
  }
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      output_block[i + (4 * j)] = state[i][j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L3:
  mov    $0x0,%eax
  call   <processMessageQueue@plt>
  jmp    L3
```

assistant: ```c
int main() {
  while (1) {
    processMessageQueue();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L8:
  mov    $0x0,%eax
  call   <processMessageQueue@plt>
  jmp    L8
```

assistant: ```c
int main() {
  while (1) {
    processMessageQueue();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <processMessageQueue@plt>
  jmp    L5
```

assistant: ```c
int main() {
  while (1) {
    processMessageQueue();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <processMessageQueue@plt>
  jmp    L9
```

assistant: ```c
int main() {
  while (1) {
    processMessageQueue();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <inet_aton@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string

tool: D11: 1.2.3.4

tool: D19: addr.s_addr = 0x%08x


assistant: ```c
int main(void) {
  struct in_addr addr;
  inet_aton("1.2.3.4", &addr);
  printf("addr.s_addr = 0x%08x\n", addr.s_addr);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <inet_aton@plt>
  mov    0x4(%rsp),%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type: string
name: read_data
arguments: data_label: D13
type: string

tool: D2: 1.2.3.4

tool: D13: addr.s_addr = 0x%08x


assistant: ```c
int main(void) {
  struct in_addr addr;
  inet_aton("1.2.3.4", &addr);
  printf("addr.s_addr = 0x%08x\n", addr.s_addr);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <inet_aton@plt>
  mov    0x4(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D2
type: string

tool: D12: 1.2.3.4

tool: D2: addr.s_addr = 0x%08x


assistant: ```c
int main(void) {
  struct in_addr addr;
  inet_aton("1.2.3.4", &addr);
  printf("addr.s_addr = 0x%08x\n", addr.s_addr);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <inet_aton@plt>
  mov    0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D13
type: string
name: retrieve_data
arguments: label: D7
type: string

tool: D13: 1.2.3.4

tool: D7: addr.s_addr = 0x%08x


assistant: ```c
int main(void) {
  struct in_addr addr;
  inet_aton("1.2.3.4", &addr);
  printf("addr.s_addr = 0x%08x\n", addr.s_addr);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L40
L3:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L40:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L3
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,-0x14(%rbp)
  cmpl   $0x6,-0x14(%rbp)
  jg     L35
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L35:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D25
data_type: string

tool: D6: %d

tool: D27: light

tool: D25: heavy

assistant: ```c
int main() {
  int a, sum = 0, i, n;
  scanf("%d", &a);
  for (i = 0; a != 0; i++) {
    n = a % 10;
    sum += n;
    a /= 10;
  }
  sum /= i;
  if (sum < 7) {
    printf("light");
  } else {
    printf("heavy");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  je     L22
  mov    $0x0,%edi
  mov    $0x0,%eax
L23:
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    %ecx,%eax
  mov    %edx,%ecx
  add    $0x1,%edi
  test   %edx,%edx
  jne    L23
  movl   $0x0,0x4(%rsp)
L45:
  cltd
  idiv   %edi
  cmp    $0x6,%eax
  jg     L24
  lea    D11(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L22:
  mov    %ecx,%edi
  mov    %ecx,%eax
  jmp    L45
L24:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string

tool: D9: %d

tool: D11: light

tool: D4: heavy

assistant: ```c
int main() {
  int a, sum = 0, i, n;
  scanf("%d", &a);
  for (i = 0; a != 0; i++) {
    n = a % 10;
    sum += n;
    a /= 10;
  }
  sum /= i;
  if (sum < 7) {
    printf("light");
  } else {
    printf("heavy");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  je     10a0 <main.cold>
  xor    %edi,%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L11:
  movslq %ecx,%rdx
  mov    %ecx,%esi
  add    $0x1,%edi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    %ecx,%eax
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L11
  cltd
  movl   $0x0,0x4(%rsp)
  idiv   %edi
  cmp    $0x6,%eax
  jle    L20
  lea    D16(%rip),%rdi
  call   <printf@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L20:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
datatype: string
name: extract_symbolic_data
arguments: data_label: D16
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: string

tool: D22: %d

tool: D16: heavy

tool: D26: light

assistant: ```c
int main() {
  int a, sum = 0, i, n;
  scanf("%d", &a);
  for (i = 0; a != 0; i++) {
    n = a % 10;
    sum += n;
    a /= 10;
  }
  sum /= i;
  if (sum < 7) {
    printf("light");
  } else {
    printf("heavy");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  je     10a0 <main.cold>
  xor    %edi,%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L35:
  movslq %ecx,%rdx
  mov    %ecx,%esi
  add    $0x1,%edi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    %ecx,%eax
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L35
  cltd
  movl   $0x0,0x4(%rsp)
  idiv   %edi
  cmp    $0x6,%eax
  jle    L1
  lea    D7(%rip),%rdi
  call   <printf@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D18: %d

tool: D7: heavy

tool: D4: light

assistant: ```c
int main() {
  int a, sum = 0, i, n;
  scanf("%d", &a);
  for (i = 0; a != 0; i++) {
    n = a % 10;
    sum += n;
    a /= 10;
  }
  sum /= i;
  if (sum < 7) {
    printf("light");
  } else {
    printf("heavy");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_psdmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_psdmatrix(double **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<free_psdmatrix>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void free_psdmatrix(double **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_psdmatrix>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_psdmatrix(double **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<free_psdmatrix>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_psdmatrix(double **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x4,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x73,%al
  jne    L41
  mov    -0x34(%rbp),%eax
  sub    $0x3,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x73,%al
  jne    L41
  mov    -0x34(%rbp),%eax
  sub    $0x2,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x65,%al
  jne    L41
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x73,%al
  jne    L41
  mov    -0x34(%rbp),%eax
  sub    $0x2,%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  jmp    L74
L41:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x73,%al
  jne    L50
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  jmp    L74
L50:
  mov    -0x34(%rbp),%eax
  sub    $0x2,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x65,%al
  jne    L74
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x64,%al
  jne    L74
  mov    -0x34(%rbp),%eax
  sub    $0x2,%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
L74:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D29
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string
name: parse_data
arguments: tag: D39
type_guessed: string
name: parse_data
arguments: tag: D16
type_guessed: string

tool: D29: 
Enter a word to stem: 

tool: D7: %s

tool: D39: Initial word: %s


tool: D16: Stemmed word: %s



assistant: ```c
int main() {
  char word[30];
  int len;
  printf("\nEnter a word to stem: ");
  scanf("%s", word);
  printf("Initial word: %s\n", word);
  len = strlen(word);
  if (word[len - 4] == 's' && word[len - 3] == 's' && word[len - 2] == 'e' && word[len - 1] == 's') {
    word[len - 2] = '\0';
  } else if (word[len - 1] == 's') {
    word[len - 1] = '\0';
  } else if (word[len - 2] == 'e' && word[len - 1] == 'd') {
    word[len - 2] = '\0';
  }
  printf("Stemmed word: %s\n\n", word);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x4(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x73,(%rsp,%rdx,1)
  je     L55
L14:
  lea    -0x1(%rax),%edx
  movslq %edx,%rcx
  movzbl (%rsp,%rcx,1),%ecx
  cmp    $0x73,%cl
  je     L16
L25:
  sub    $0x2,%eax
  movslq %eax,%rdx
  cmpb   $0x65,(%rsp,%rdx,1)
  jne    L80
  cmp    $0x64,%cl
  jne    L80
  movb   $0x0,(%rsp,%rdx,1)
  jmp    L80
L55:
  lea    -0x3(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x73,(%rsp,%rdx,1)
  jne    L14
  lea    -0x2(%rax),%edx
  movslq %edx,%rcx
  cmpb   $0x65,(%rsp,%rcx,1)
  je     L106
  lea    -0x1(%rax),%edx
  movslq %edx,%rax
  cmpb   $0x73,(%rsp,%rax,1)
  jne    L80
L16:
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
L80:
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L106:
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  movzbl (%rsp,%rcx,1),%ecx
  cmp    $0x73,%cl
  jne    L25
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  jmp    L80
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string
name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D35
data_type: string
name: read_data
arguments: tag: D0
data_type: string

tool: D4: 
Enter a word to stem: 

tool: D7: %s

tool: D35: Initial word: %s


tool: D0: Stemmed word: %s



assistant: ```c
int main() {
  char word[30];
  int len;
  printf("\nEnter a word to stem: ");
  scanf("%s", word);
  printf("Initial word: %s\n", word);
  len = strlen(word);
  if (word[len - 4] == 's' && word[len - 3] == 's' && word[len - 2] == 'e' && word[len - 1] == 's') {
    word[len - 2] = '\0';
  } else if (word[len - 1] == 's') {
    word[len - 1] = '\0';
  } else if (word[len - 2] == 'e' && word[len - 1] == 'd') {
    word[len - 2] = '\0';
  }
  printf("Stemmed word: %s\n\n", word);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x4(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x73,(%rsp,%rdx,1)
  je     L47
L21:
  lea    -0x1(%rax),%edx
  sub    $0x2,%eax
  movslq %edx,%rdx
  movzbl (%rsp,%rdx,1),%ecx
  cmp    $0x73,%cl
  je     L105
L50:
  cltq
  cmpb   $0x65,(%rsp,%rax,1)
  jne    L76
  cmp    $0x64,%cl
  je     L8
L76:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L47:
  lea    -0x3(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x73,(%rsp,%rdx,1)
  jne    L21
  lea    -0x1(%rax),%edx
  sub    $0x2,%eax
  movslq %eax,%rsi
  movslq %edx,%rdx
  cmpb   $0x65,(%rsp,%rsi,1)
  movzbl (%rsp,%rdx,1),%ecx
  je     L101
  cmp    $0x73,%cl
  jne    L76
L105:
  movb   $0x0,(%rsp,%rdx,1)
  jmp    L76
L8:
  movb   $0x0,(%rsp,%rax,1)
  jmp    L76
L101:
  cmp    $0x73,%cl
  jne    L50
  movb   $0x0,(%rsp,%rsi,1)
  jmp    L76
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D25
datatype: string
name: retrieve_data
arguments: tag: D35
datatype: string
name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D31
datatype: string

tool: D25: 
Enter a word to stem: 

tool: D35: %s

tool: D10: Initial word: %s


tool: D31: Stemmed word: %s



assistant: ```c
int main() {
  char word[30];
  int len;
  printf("\nEnter a word to stem: ");
  scanf("%s", word);
  printf("Initial word: %s\n", word);
  len = strlen(word);
  if (word[len - 4] == 's' && word[len - 3] == 's' && word[len - 2] == 'e' && word[len - 1] == 's') {
    word[len - 2] = '\0';
  } else if (word[len - 1] == 's') {
    word[len - 1] = '\0';
  } else if (word[len - 2] == 'e' && word[len - 1] == 'd') {
    word[len - 2] = '\0';
  }
  printf("Stemmed word: %s\n\n", word);
  return 0;
}
```