user: Translate the below assembly code into C programming language:

```asm
<detcoef2>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %r8,%r14
  push   %r13
  lea    0x0(,%r9,4),%r13d
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13d,%edi
  sub    $0x28,%rsp
  mov    0x60(%rsp),%r11d
  mov    0x68(%rsp),%rax
  mov    %r11d,0x1c(%rsp)
  mov    %rax,0x10(%rsp)
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%rcx
  mov    %r15d,%edi
  mov    %r12,%rdx
  mov    %rax,%r8
  mov    %r14,%rsi
  mov    %rax,%r13
  call   <matrix_locate@plt>
  mov    0x10(%rsp),%rdi
  lea    D7(%rip),%rsi
  call   <strcmp@plt>
  mov    0x1c(%rsp),%r11d
  sub    %r11d,%r15d
  mov    %r15d,%r9d
  test   %rax,%rax
  jne    L32
  movslq %r15d,%rax
  mov    (%r12,%rax,4),%edx
L57:
  lea    0x2(%r9,%r9,1),%eax
  cltq
  mov    (%r14,%rax,4),%r15d
  test   %r15d,%r15d
  jle    L83
  mov    0x4(%r14,%rax,4),%r11d
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  movslq %edx,%r14
  lea    -0x1(%r11),%edi
  nopl   0x0(%rax)
L24:
  test   %r11d,%r11d
  jle    L42
  movslq %r9d,%rax
  lea    (%r14,%rax,1),%rdx
  lea    0x0(%rbp,%rax,8),%rcx
  xor    %eax,%eax
  lea    (%rbx,%rdx,8),%rsi
  nop
L3:
  movsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%rdx
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L3
L42:
  add    $0x1,%r8d
  add    %r11d,%r9d
  cmp    %r15d,%r8d
  jne    L24
L83:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  add    $0x28,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free@plt>
L32:
  mov    0x10(%rsp),%rdi
  lea    D16(%rip),%rsi
  mov    %r15d,0x1c(%rsp)
  call   <strcmp@plt>
  mov    0x1c(%rsp),%r9d
  test   %rax,%rax
  jne    L61
  mov    0x8(%rsp),%rcx
  movslq %r9d,%rax
  mov    (%rcx,%rax,4),%edx
  jmp    L57
L61:
  mov    0x10(%rsp),%rdi
  lea    D24(%rip),%rsi
  mov    %r9d,0x1c(%rsp)
  call   <strcmp@plt>
  xor    %edx,%edx
  mov    0x1c(%rsp),%r9d
  test   %rax,%rax
  jne    L57
  movslq %r9d,%rax
  mov    0x0(%r13,%rax,4),%edx
  jmp    L57
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string
name: unpack_data
arguments: data_label: D24
data_type: string

tool: D7: h

tool: D16: v

tool: D24: d

assistant: ```c
void detcoef2(double *coef, int sigInLength, double *coefOut, int sigOutLength, int *pLen, int stride, int level, char *coefType) {
  int row, col, sta = 0;
  int *pH, *pV, *pD;
  pH = malloc(stride * sizeof(int));
  pV = malloc(stride * sizeof(int));
  pD = malloc(stride * sizeof(int));
  matrix_locate(stride, pLen, pH, pV, pD);
  if (strcmp(coefType, "h") == 0) {
    sta = pH[stride - level];
  } else if (strcmp(coefType, "v") == 0) {
    sta = pV[stride - level];
  } else if (strcmp(coefType, "d") == 0) {
    sta = pD[stride - level];
  }
  for (row = 0; row < pLen[(stride - level + 1) * 2]; row++) {
    for (col = 0; col < pLen[(stride - level + 1) * 2 + 1]; col++)
      coefOut[col + row * (pLen[(stride - level + 1) * 2 + 1])] = coef[sta + col + row * (pLen[(stride - level + 1) * 2 + 1])];
  }
  free(pH);
  free(pV);
  free(pD);
  return;
}
```