ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0xf,-0x10(%rbp)
  movl   $0x9,-0x14(%rbp)
  jmp    L0
L46:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0xb(%rbp)
  movb   $0x0,-0xa(%rbp)
  addl   $0xa,-0x10(%rbp)
  mov    -0x10(%rbp),%esi
  lea    -0xb(%rbp),%rax
  mov    $0xf,%ecx
  mov    $0x2c,%edx
  mov    %rax,%rdi
  call   <RIT128x96x4StringDraw@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <delay@plt>
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jns    L46
  movl   $0xf,-0x10(%rbp)
  movb   $0x20,-0xb(%rbp)
  movb   $0x0,-0xa(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L32
L38:
  addl   $0xa,-0x10(%rbp)
  mov    -0x10(%rbp),%esi
  lea    -0xb(%rbp),%rax
  mov    $0xf,%ecx
  mov    $0x2c,%edx
  mov    %rax,%rdi
  call   <RIT128x96x4StringDraw@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <delay@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  cmp    $0x9,%eax
  jle    L38
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void display(unsigned long *delayTime, char *startChar) {
  volatile int i = 0;
  int k = 15;
  char myData[3];
  for (i = 9; i >= 0; i--) {
    myData[0] = i + *startChar;
    myData[1] = '\0';
    k = k + 10;
    RIT128x96x4StringDraw(myData, k, 44, 15);
    delay(*delayTime);
  }
  k = 15;
  myData[0] = ' ';
  myData[1] = '\0';
  for (i = 0; i < 10; i++) {
    k = k + 10;
    RIT128x96x4StringDraw(myData, k, 44, 15);
    delay(*delayTime);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<display>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x9,(%rsp)
  mov    (%rsp),%eax
  test   %eax,%eax
  js     L3
  mov    %rsi,%r12
  mov    $0xf,%ebx
  lea    0x5(%rsp),%r13
L40:
  mov    (%rsp),%eax
  add    (%r12),%al
  mov    %al,0x5(%rsp)
  movb   $0x0,0x6(%rsp)
  add    $0xa,%ebx
  mov    $0xf,%ecx
  mov    $0x2c,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <RIT128x96x4StringDraw@plt>
  mov    0x0(%rbp),%rdi
  call   <delay@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  mov    (%rsp),%eax
  test   %eax,%eax
  jns    L40
L3:
  movb   $0x20,0x5(%rsp)
  movb   $0x0,0x6(%rsp)
  movl   $0x0,(%rsp)
  mov    (%rsp),%eax
  cmp    $0x9,%eax
  jg     L8
  mov    $0xf,%ebx
  lea    0x5(%rsp),%r12
L19:
  add    $0xa,%ebx
  mov    $0xf,%ecx
  mov    $0x2c,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <RIT128x96x4StringDraw@plt>
  mov    0x0(%rbp),%rdi
  call   <delay@plt>
  mov    (%rsp),%eax
  add    $0x1,%eax
  mov    %eax,(%rsp)
  mov    (%rsp),%eax
  cmp    $0x9,%eax
  jle    L19
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void display(unsigned long *delayTime, char *startChar) {
  volatile int i = 0;
  int k = 15;
  char myData[3];
  for (i = 9; i >= 0; i--) {
    myData[0] = i + *startChar;
    myData[1] = '\0';
    k = k + 10;
    RIT128x96x4StringDraw(myData, k, 44, 15);
    delay(*delayTime);
  }
  k = 15;
  myData[0] = ' ';
  myData[1] = '\0';
  for (i = 0; i < 10; i++) {
    k = k + 10;
    RIT128x96x4StringDraw(myData, k, 44, 15);
    delay(*delayTime);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x9,(%rsp)
  mov    (%rsp),%eax
  test   %eax,%eax
  js     L38
  mov    %rsi,%r12
  mov    $0xf,%r13d
  lea    0x5(%rsp),%rbp
  nopl   0x0(%rax)
L20:
  add    $0xa,%r13d
  mov    (%rsp),%eax
  mov    $0xf,%ecx
  add    (%r12),%al
  mov    $0x2c,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %al,0x5(%rsp)
  movb   $0x0,0x6(%rsp)
  call   <RIT128x96x4StringDraw@plt>
  mov    (%rbx),%rdi
  call   <delay@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  mov    (%rsp),%eax
  test   %eax,%eax
  jns    L20
L38:
  mov    $0x20,%eax
  movl   $0x0,(%rsp)
  mov    %ax,0x5(%rsp)
  mov    (%rsp),%eax
  cmp    $0x9,%eax
  jg     L4
  mov    $0xf,%r12d
  lea    0x5(%rsp),%rbp
  nopl   (%rax)
L22:
  add    $0xa,%r12d
  mov    $0xf,%ecx
  mov    $0x2c,%edx
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <RIT128x96x4StringDraw@plt>
  mov    (%rbx),%rdi
  call   <delay@plt>
  mov    (%rsp),%eax
  add    $0x1,%eax
  mov    %eax,(%rsp)
  mov    (%rsp),%eax
  cmp    $0x9,%eax
  jle    L22
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void display(unsigned long *delayTime, char *startChar) {
  volatile int i = 0;
  int k = 15;
  char myData[3];
  for (i = 9; i >= 0; i--) {
    myData[0] = i + *startChar;
    myData[1] = '\0';
    k = k + 10;
    RIT128x96x4StringDraw(myData, k, 44, 15);
    delay(*delayTime);
  }
  k = 15;
  myData[0] = ' ';
  myData[1] = '\0';
  for (i = 0; i < 10; i++) {
    k = k + 10;
    RIT128x96x4StringDraw(myData, k, 44, 15);
    delay(*delayTime);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<display>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x9,(%rsp)
  mov    (%rsp),%eax
  test   %eax,%eax
  js     L42
  mov    %rsi,%r12
  mov    $0xf,%r13d
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax)
L45:
  add    $0xa,%r13d
  mov    (%rsp),%eax
  mov    $0xf,%ecx
  add    (%r12),%al
  mov    $0x2c,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %al,0x4(%rsp)
  movb   $0x0,0x5(%rsp)
  call   <RIT128x96x4StringDraw@plt>
  mov    (%rbx),%rdi
  call   <delay@plt>
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  mov    (%rsp),%eax
  test   %eax,%eax
  jns    L45
L42:
  mov    $0x20,%eax
  movl   $0x0,(%rsp)
  mov    %ax,0x4(%rsp)
  mov    (%rsp),%eax
  cmp    $0x9,%eax
  jg     L2
  mov    $0xf,%r12d
  lea    0x4(%rsp),%rbp
  nopl   (%rax)
L5:
  add    $0xa,%r12d
  mov    $0xf,%ecx
  mov    $0x2c,%edx
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <RIT128x96x4StringDraw@plt>
  mov    (%rbx),%rdi
  call   <delay@plt>
  mov    (%rsp),%eax
  add    $0x1,%eax
  mov    %eax,(%rsp)
  mov    (%rsp),%eax
  cmp    $0x9,%eax
  jle    L5
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void display(unsigned long *delayTime, char *startChar) {
  volatile int i = 0;
  int k = 15;
  char myData[3];
  for (i = 9; i >= 0; i--) {
    myData[0] = i + *startChar;
    myData[1] = '\0';
    k = k + 10;
    RIT128x96x4StringDraw(myData, k, 44, 15);
    delay(*delayTime);
  }
  k = 15;
  myData[0] = ' ';
  myData[1] = '\0';
  for (i = 0; i < 10; i++) {
    k = k + 10;
    RIT128x96x4StringDraw(myData, k, 44, 15);
    delay(*delayTime);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_if_char_in_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L21
  mov    $0x1,%eax
  jmp    L27
L21:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L30
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int check_if_char_in_string(char search_string[], char target_char, int search_string_length) {
  int i;
  for (i = 0; i < search_string_length; i++) {
    if (search_string[i] == target_char) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_if_char_in_string>:
  endbr64
  test   %edx,%edx
  jle    L18
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L7:
  cmp    %sil,(%rax)
  je     L14
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L7
  mov    $0x0,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_if_char_in_string(char search_string[], char target_char, int search_string_length) {
  int i;
  for (i = 0; i < search_string_length; i++) {
    if (search_string[i] == target_char) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_if_char_in_string>:
  endbr64
  test   %edx,%edx
  jle    L7
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L7
L34:
  cmp    %sil,(%rdi)
  jne    L18
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_if_char_in_string(char search_string[], char target_char, int search_string_length) {
  int i;
  for (i = 0; i < search_string_length; i++) {
    if (search_string[i] == target_char) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_if_char_in_string>:
  endbr64
  test   %edx,%edx
  jle    L39
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L39
L3:
  cmp    %sil,(%rdi)
  jne    L27
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_if_char_in_string(char search_string[], char target_char, int search_string_length) {
  int i;
  for (i = 0; i < search_string_length; i++) {
    if (search_string[i] == target_char) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pkey_dh_ctrl_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L22
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <EVP_PKEY_CTX_set_dh_paramgen_prime_len@plt>
  jmp    L15
L22:
  mov    -0x20(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L26
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <EVP_PKEY_CTX_set_dh_paramgen_generator@plt>
  jmp    L15
L26:
  mov    $0xfffffffe,%eax
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string

tool: D18: dh_paramgen_prime_len

tool: D1: dh_paramgen_generator

assistant: ```c
int pkey_dh_ctrl_str(EVP_PKEY_CTX *ctx, const char *type, const char *value) {
  if (!strcmp(type, "dh_paramgen_prime_len")) {
    int len;
    len = atoi(value);
    return EVP_PKEY_CTX_set_dh_paramgen_prime_len(ctx, len);
  }
  if (!strcmp(type, "dh_paramgen_generator")) {
    int len;
    len = atoi(value);
    return EVP_PKEY_CTX_set_dh_paramgen_generator(ctx, len);
  }
  return -2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pkey_dh_ctrl_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L13
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L6
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <EVP_PKEY_CTX_set_dh_paramgen_generator@plt>
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <EVP_PKEY_CTX_set_dh_paramgen_prime_len@plt>
  jmp    L17
L6:
  mov    $0xfffffffe,%eax
  jmp    L17
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D18
datatype: string

tool: D0: dh_paramgen_prime_len

tool: D18: dh_paramgen_generator

assistant: ```c
int pkey_dh_ctrl_str(EVP_PKEY_CTX *ctx, const char *type, const char *value) {
  if (!strcmp(type, "dh_paramgen_prime_len")) {
    int len;
    len = atoi(value);
    return EVP_PKEY_CTX_set_dh_paramgen_prime_len(ctx, len);
  }
  if (!strcmp(type, "dh_paramgen_generator")) {
    int len;
    len = atoi(value);
    return EVP_PKEY_CTX_set_dh_paramgen_generator(ctx, len);
  }
  return -2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pkey_dh_ctrl_str>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L4
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L7
  mov    %r13,%rdi
  call   <atoi@plt>
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  mov    %eax,%esi
  pop    %r13
  jmp    10a0 <EVP_PKEY_CTX_set_dh_paramgen_generator@plt>
  nop
L4:
  mov    %r13,%rdi
  call   <atoi@plt>
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  mov    %eax,%esi
  pop    %r13
  jmp    1080 <EVP_PKEY_CTX_set_dh_paramgen_prime_len@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  pop    %rbp
  mov    $0xfffffffe,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D18: dh_paramgen_prime_len

tool: D4: dh_paramgen_generator

assistant: ```c
int pkey_dh_ctrl_str(EVP_PKEY_CTX *ctx, const char *type, const char *value) {
  if (!strcmp(type, "dh_paramgen_prime_len")) {
    int len;
    len = atoi(value);
    return EVP_PKEY_CTX_set_dh_paramgen_prime_len(ctx, len);
  }
  if (!strcmp(type, "dh_paramgen_generator")) {
    int len;
    len = atoi(value);
    return EVP_PKEY_CTX_set_dh_paramgen_generator(ctx, len);
  }
  return -2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pkey_dh_ctrl_str>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L14
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L8
  mov    %r13,%rdi
  call   <atoi@plt>
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  mov    %eax,%esi
  pop    %r13
  jmp    10a0 <EVP_PKEY_CTX_set_dh_paramgen_generator@plt>
  nop
L14:
  mov    %r13,%rdi
  call   <atoi@plt>
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  mov    %eax,%esi
  pop    %r13
  jmp    1080 <EVP_PKEY_CTX_set_dh_paramgen_prime_len@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  pop    %rbp
  mov    $0xfffffffe,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D16: dh_paramgen_prime_len

tool: D7: dh_paramgen_generator

assistant: ```c
int pkey_dh_ctrl_str(EVP_PKEY_CTX *ctx, const char *type, const char *value) {
  if (!strcmp(type, "dh_paramgen_prime_len")) {
    int len;
    len = atoi(value);
    return EVP_PKEY_CTX_set_dh_paramgen_prime_len(ctx, len);
  }
  if (!strcmp(type, "dh_paramgen_generator")) {
    int len;
    len = atoi(value);
    return EVP_PKEY_CTX_set_dh_paramgen_generator(ctx, len);
  }
  return -2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x696c6f696c655a,%rax
  mov    $0x0,%edx
  mov    %rax,-0xf0(%rbp)
  mov    %rdx,-0xe8(%rbp)
  movl   $0x0,-0xe0(%rbp)
  movq   $0x6163754c,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movl   $0x0,-0xc0(%rbp)
  movabs $0x36333935303031,%rax
  mov    $0x0,%edx
  mov    %rax,-0xb0(%rbp)
  mov    %rdx,-0xa8(%rbp)
  movl   $0x0,-0xa0(%rbp)
  movabs $0x2b2b4320432043,%rax
  mov    $0x0,%edx
  mov    %rax,-0x90(%rbp)
  mov    %rdx,-0x88(%rbp)
  movl   $0x0,-0x80(%rbp)
  movabs $0x6948207265707573,%rax
  mov    $0x6867,%edx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movl   $0x0,-0x60(%rbp)
  movq   $0x35,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movl   $0x0,-0x40(%rbp)
  movabs $0x20676e6964757473,%rax
  mov    $0x64726168,%edx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movw   $0x0,-0x14(%rbp)
  lea    -0x70(%rbp),%r8
  lea    -0x90(%rbp),%rdi
  lea    -0xb0(%rbp),%rcx
  lea    -0xd0(%rbp),%rdx
  lea    -0xf0(%rbp),%rax
  lea    -0x30(%rbp),%rsi
  push   %rsi
  lea    -0x50(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: Student:

Last name:				 %s
First name:				 %s
Student number:				 %s
Programming experience:			 %s
Motivation to learn C:			 %s
Grade I aim at:				 %s
My plan to achieve that grade:		 %s


assistant: ```c
int main(void) {
  char lastName[20] = "Zelioli";
  char firstName[20] = "Luca";
  char studentNumber[20] = "1005936";
  char programmingExp[20] = "C C C++";
  char motivationToLearn[20] = "super High";
  char grade[20] = "5";
  char myPlane[30] = "studing hard";
  printf("Student:\n\nLast name:\t\t\t\t %s\nFirst name:\t\t\t\t %s\nStudent number:\t\t\t\t %s\nProgramming experience:\t\t\t %s\nMotivation to learn C:\t\t\t %s\nGrade I aim at:\t\t\t\t %s\nMy plan to achieve that grade:\t\t %s\n", lastName, firstName, studentNumber, programmingExp, motivationToLearn, grade, myPlane);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  movabs $0x696c6f696c655a,%rax
  mov    $0x0,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  movq   $0x6163754c,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  movabs $0x36333935303031,%rax
  mov    $0x0,%edx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movl   $0x0,0x50(%rsp)
  movabs $0x2b2b4320432043,%rax
  mov    $0x0,%edx
  mov    %rax,0x60(%rsp)
  mov    %rdx,0x68(%rsp)
  movl   $0x0,0x70(%rsp)
  movabs $0x6948207265707573,%rax
  mov    $0x6867,%edx
  mov    %rax,0x80(%rsp)
  mov    %rdx,0x88(%rsp)
  movl   $0x0,0x90(%rsp)
  movq   $0x35,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movl   $0x0,0xb0(%rsp)
  movabs $0x20676e6964757473,%rax
  mov    $0x64726168,%edx
  mov    %rax,0xc0(%rsp)
  mov    %rdx,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movl   $0x0,0xd8(%rsp)
  movw   $0x0,0xdc(%rsp)
  lea    0x40(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0xc0(%rsp),%rax
  push   %rax
  lea    0xa8(%rsp),%rax
  push   %rax
  lea    0x90(%rsp),%r9
  lea    0x70(%rsp),%r8
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0xf8,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: Student:

Last name:				 %s
First name:				 %s
Student number:				 %s
Programming experience:			 %s
Motivation to learn C:			 %s
Grade I aim at:				 %s
My plan to achieve that grade:		 %s


assistant: ```c
int main(void) {
  char lastName[20] = "Zelioli";
  char firstName[20] = "Luca";
  char studentNumber[20] = "1005936";
  char programmingExp[20] = "C C C++";
  char motivationToLearn[20] = "super High";
  char grade[20] = "5";
  char myPlane[30] = "studing hard";
  printf("Student:\n\nLast name:\t\t\t\t %s\nFirst name:\t\t\t\t %s\nStudent number:\t\t\t\t %s\nProgramming experience:\t\t\t %s\nMotivation to learn C:\t\t\t %s\nGrade I aim at:\t\t\t\t %s\nMy plan to achieve that grade:\t\t %s\n", lastName, firstName, studentNumber, programmingExp, motivationToLearn, grade, myPlane);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0xf8,%rsp
  xor    %edx,%edx
  movdqa D10(%rip),%xmm0
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  movabs $0x696c6f696c655a,%rax
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  lea    0x40(%rsp),%rcx
  movaps %xmm0,0x80(%rsp)
  mov    %rsp,%rsi
  movdqa D17(%rip),%xmm0
  mov    %rdx,0x48(%rsp)
  xor    %edx,%edx
  mov    %rdx,0x68(%rsp)
  lea    0x20(%rsp),%rdx
  movl   $0x0,0x10(%rsp)
  movq   $0x6163754c,0x20(%rsp)
  mov    %rax,(%rsp)
  movabs $0x36333935303031,%rax
  mov    %rax,0x40(%rsp)
  movabs $0x2b2b4320432043,%rax
  mov    %rax,0x60(%rsp)
  xor    %eax,%eax
  mov    %ax,0xdc(%rsp)
  lea    0xc0(%rsp),%rax
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x50(%rsp)
  movl   $0x0,0x70(%rsp)
  movl   $0x0,0x90(%rsp)
  movq   $0x35,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movl   $0x0,0xb0(%rsp)
  movq   $0x0,0xd0(%rsp)
  movl   $0x0,0xd8(%rsp)
  movaps %xmm0,0xc0(%rsp)
  push   %rax
  lea    0xa8(%rsp),%rax
  push   %rax
  lea    0x90(%rsp),%r9
  lea    0x70(%rsp),%r8
  call   <printf@plt>
  pop    %rdx
  pop    %rcx
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0xf8,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: byte[16]
name: retrieve_data
arguments: data_tag: D6
type: string
name: retrieve_data
arguments: data_tag: D17
type: byte[16]

tool: {"D10": [0x73,0x75,0x70,0x65,0x72,0x20,0x48,0x69,0x67,0x68,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D6: Student:

Last name:				 %s
First name:				 %s
Student number:				 %s
Programming experience:			 %s
Motivation to learn C:			 %s
Grade I aim at:				 %s
My plan to achieve that grade:		 %s


tool: {"D17": [0x73,0x74,0x75,0x64,0x69,0x6e,0x67,0x20,0x68,0x61,0x72,0x64,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  char lastName[20] = "Zelioli";
  char firstName[20] = "Luca";
  char studentNumber[20] = "1005936";
  char programmingExp[20] = "C C C++";
  char motivationToLearn[20] = "super High";
  char grade[20] = "5";
  char myPlane[30] = "studing hard";
  printf("Student:\n\nLast name:\t\t\t\t %s\nFirst name:\t\t\t\t %s\nStudent number:\t\t\t\t %s\nProgramming experience:\t\t\t %s\nMotivation to learn C:\t\t\t %s\nGrade I aim at:\t\t\t\t %s\nMy plan to achieve that grade:\t\t %s\n", lastName, firstName, studentNumber, programmingExp, motivationToLearn, grade, myPlane);
  return 0;
}
```