ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sigint_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <cleanup@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void sigint_handler(int sig) {
  (void)sig;
  cleanup();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sigint_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cleanup@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sigint_handler(int sig) {
  (void)sig;
  cleanup();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sigint_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cleanup@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void sigint_handler(int sig) {
  (void)sig;
  cleanup();
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sigint_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cleanup@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void sigint_handler(int sig) {
  (void)sig;
  cleanup();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delete_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x1c(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L4
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *delete_str(char *string, int start, int num_chars) {
  int far_str;
  for (far_str = start + num_chars; far_str <= strlen(string); far_str++, start++)
    string[start] = string[far_str];
  return string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<delete_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  add    %edx,%esi
  movslq %esi,%rbx
  movslq %edx,%r12
  jmp    L4
L6:
  movzbl 0x0(%rbp,%rbx,1),%edx
  mov    %rbp,%rax
  sub    %r12,%rax
  mov    %dl,(%rax,%rbx,1)
  add    $0x1,%rbx
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L6
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *delete_str(char *string, int start, int num_chars) {
  int far_str;
  for (far_str = start + num_chars; far_str <= strlen(string); far_str++, start++)
    string[start] = string[far_str];
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<delete_str>:
  endbr64
  add    %edx,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  movslq %esi,%rbx
  jmp    L14
  nopl   (%rax)
L13:
  movzbl (%r12,%rbx,1),%edx
  mov    %r12,%rax
  sub    %rbp,%rax
  mov    %dl,(%rax,%rbx,1)
  add    $0x1,%rbx
L14:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L13
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *delete_str(char *string, int start, int num_chars) {
  int far_str;
  for (far_str = start + num_chars; far_str <= strlen(string); far_str++, start++)
    string[start] = string[far_str];
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delete_str>:
  endbr64
  add    %edx,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  movslq %esi,%rbx
  jmp    L1
  nopl   (%rax)
L11:
  movzbl (%r12,%rbx,1),%edx
  mov    %r12,%rax
  sub    %rbp,%rax
  mov    %dl,(%rax,%rbx,1)
  add    $0x1,%rbx
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L11
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *delete_str(char *string, int start, int num_chars) {
  int far_str;
  for (far_str = start + num_chars; far_str <= strlen(string); far_str++, start++)
    string[start] = string[far_str];
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L39
  mov    $0x1,%eax
  jmp    L5
L39:
  mov    $0xffffffff,%eax
L5:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L43
  negl   -0x14(%rbp)
L43:
  movl   $0x0,-0x8(%rbp)
  jmp    L48
L27:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L48:
  cmpl   $0x0,-0x14(%rbp)
  jg     L27
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int reverse(int x) {
  int t = x > 0 ? 1 : -1;
  if (x < 0)
    x = -x;
  int r = 0;
  while (x > 0) {
    if (r * 10 / 10 != r)
      return 0;
    r *= 10;
    r += x % 10;
    x /= 10;
  }
  return r * t;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reverse>:
  endbr64
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  mov    $0x1,%r8d
  test   %edi,%edi
  jle    L47
L4:
  mov    $0x0,%eax
L2:
  lea    (%rax,%rax,4),%edi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  mov    %ecx,%esi
  sub    %eax,%esi
  lea    (%rsi,%rdi,2),%eax
  mov    %ecx,%esi
  mov    %edx,%ecx
  cmp    $0x9,%esi
  jg     L2
L45:
  imul   %r8d,%eax
  ret
L47:
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  test   %ecx,%ecx
  jle    L9
  mov    $0xffffffff,%r8d
  jmp    L4
L9:
  mov    $0xffffffff,%r8d
  mov    $0x0,%eax
  jmp    L45
```

assistant: ```c
int reverse(int x) {
  int t = x > 0 ? 1 : -1;
  if (x < 0)
    x = -x;
  int r = 0;
  while (x > 0) {
    if (r * 10 / 10 != r)
      return 0;
    r *= 10;
    r += x % 10;
    x /= 10;
  }
  return r * t;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%r8d
  neg    %ecx
  cmovs  %edi,%ecx
  test   %edi,%edi
  jle    L2
L9:
  xor    %eax,%eax
  mov    $0xcccccccd,%edi
  nopl   0x0(%rax)
L0:
  mov    %ecx,%edx
  lea    (%rax,%rax,4),%esi
  imul   %rdi,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  lea    (%rcx,%rsi,2),%eax
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L0
  imul   %r8d,%eax
L19:
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x0,%eax
  je     L19
  mov    $0xffffffff,%r8d
  jmp    L9
```

assistant: ```c
int reverse(int x) {
  int t = x > 0 ? 1 : -1;
  if (x < 0)
    x = -x;
  int r = 0;
  while (x > 0) {
    if (r * 10 / 10 != r)
      return 0;
    r *= 10;
    r += x % 10;
    x /= 10;
  }
  return r * t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%r8d
  neg    %ecx
  cmovs  %edi,%ecx
  test   %edi,%edi
  jle    L18
L0:
  xor    %eax,%eax
  mov    $0xcccccccd,%edi
  nopl   0x0(%rax)
L23:
  mov    %ecx,%edx
  lea    (%rax,%rax,4),%esi
  imul   %rdi,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  lea    (%rcx,%rsi,2),%eax
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L23
  imul   %r8d,%eax
L30:
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0x0,%eax
  je     L30
  mov    $0xffffffff,%r8d
  jmp    L0
```

assistant: ```c
int reverse(int x) {
  int t = x > 0 ? 1 : -1;
  if (x < 0)
    x = -x;
  int r = 0;
  while (x > 0) {
    if (r * 10 / 10 != r)
      return 0;
    r *= 10;
    r += x % 10;
    x /= 10;
  }
  return r * t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<whosthere>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: Quem eh?


assistant: ```c
int whosthere() {
  printf("Quem eh?\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<whosthere>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: Quem eh?


assistant: ```c
int whosthere() {
  printf("Quem eh?\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<whosthere>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: Quem eh?


assistant: ```c
int whosthere() {
  printf("Quem eh?\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<whosthere>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: Quem eh?


assistant: ```c
int whosthere() {
  printf("Quem eh?\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rocket_equation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  D4(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x1c(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm4
  divss  -0x18(%rbp),%xmm4
  movd   %xmm4,%eax
  movd   %eax,%xmm0
  call   <log@plt>
  mulss  -0x20(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: f32

tool: D4: 9.81

assistant: ```c
float rocket_equation(float total_mass, float dry_mass, float sp_impulse) {
  float delta_v;
  float g = 9.81;
  delta_v = sp_impulse * g * log(total_mass / dry_mass);
  return delta_v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rocket_equation>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm2,0xc(%rsp)
  divss  %xmm1,%xmm0
  call   <log@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  mulss  D4(%rip),%xmm0
  mulss  %xmm1,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: f32

tool: D4: 9.81

assistant: ```c
float rocket_equation(float total_mass, float dry_mass, float sp_impulse) {
  float delta_v;
  float g = 9.81;
  delta_v = sp_impulse * g * log(total_mass / dry_mass);
  return delta_v;
}
```
user: What is the c source code of the assembly code below:

```asm
<rocket_equation>:
  endbr64
  divss  %xmm1,%xmm0
  sub    $0x18,%rsp
  movss  %xmm2,0xc(%rsp)
  call   <log@plt>
  movss  0xc(%rsp),%xmm2
  mulss  D7(%rip),%xmm2
  add    $0x18,%rsp
  mulss  %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: f32

tool: D7: 9.81

assistant: ```c
float rocket_equation(float total_mass, float dry_mass, float sp_impulse) {
  float delta_v;
  float g = 9.81;
  delta_v = sp_impulse * g * log(total_mass / dry_mass);
  return delta_v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rocket_equation>:
  endbr64
  divss  %xmm1,%xmm0
  sub    $0x18,%rsp
  movss  %xmm2,0xc(%rsp)
  call   <log@plt>
  movss  0xc(%rsp),%xmm2
  mulss  D0(%rip),%xmm2
  add    $0x18,%rsp
  mulss  %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: f32

tool: D0: 9.81

assistant: ```c
float rocket_equation(float total_mass, float dry_mass, float sp_impulse) {
  float delta_v;
  float g = 9.81;
  delta_v = sp_impulse * g * log(total_mass / dry_mass);
  return delta_v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_2D_array_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L36:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L36
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L11
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D12
type: string

tool: D2: %s:


tool: D12: %.1f 

assistant: ```c
void print_2D_array_float(char *label, float **array, int rows, int cols) {
  int i, j;
  printf("%s:\n", label);
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      printf("%.1f ", array[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_2D_array_float>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %ecx,%r14d
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L47
  mov    %r12,%rbp
  lea    -0x1(%rbx),%eax
  lea    0x8(%r12,%rax,8),%r15
  lea    -0x1(%r14),%eax
  lea    0x4(,%rax,4),%r13
  lea    D6(%rip),%r12
  jmp    L57
L5:
  mov    0x0(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax,%rbx,1),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L5
L58:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L47
L57:
  mov    $0x0,%ebx
  test   %r14d,%r14d
  jg     L5
  jmp    L58
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string
name: read_data
arguments: data_label: D6
type_infered: string

tool: D9: %s:


tool: D6: %.1f 

assistant: ```c
void print_2D_array_float(char *label, float **array, int rows, int cols) {
  int i, j;
  printf("%s:\n", label);
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      printf("%.1f ", array[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_2D_array_float>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rsi,%r15
  mov    %rdi,%rsi
  push   %r14
  lea    D18(%rip),%rdi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L29
  lea    -0x1(%rbx),%eax
  lea    D12(%rip),%rbp
  lea    0x8(%r15,%rax,8),%r14
  lea    -0x1(%r13),%eax
  lea    0x4(,%rax,4),%r12
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L8
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%r15),%rax
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  cvtss2sd (%rax,%rbx,1),%xmm0
  mov    $0x1,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L7
L8:
  mov    $0xa,%edi
  add    $0x8,%r15
  call   <putchar@plt>
  cmp    %r14,%r15
  jne    L12
L29:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string

tool: D18: %s:


tool: D12: %.1f 

assistant: ```c
void print_2D_array_float(char *label, float **array, int rows, int cols) {
  int i, j;
  printf("%s:\n", label);
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      printf("%.1f ", array[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_2D_array_float>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rsi,%r15
  mov    %rdi,%rsi
  push   %r14
  lea    D12(%rip),%rdi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L5
  lea    -0x1(%rbx),%eax
  lea    D1(%rip),%rbp
  lea    0x8(%r15,%rax,8),%r14
  lea    -0x1(%r13),%eax
  lea    0x4(,%rax,4),%r12
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L31
  nopw   0x0(%rax,%rax,1)
L28:
  mov    (%r15),%rax
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  cvtss2sd (%rax,%rbx,1),%xmm0
  mov    $0x1,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L28
L31:
  mov    $0xa,%edi
  add    $0x8,%r15
  call   <putchar@plt>
  cmp    %r14,%r15
  jne    L26
L5:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D1
data_type: string

tool: D12: %s:


tool: D1: %.1f 

assistant: ```c
void print_2D_array_float(char *label, float **array, int rows, int cols) {
  int i, j;
  printf("%s:\n", label);
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      printf("%.1f ", array[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_trim_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L63
  cmpq   $0x0,-0x20(%rbp)
  je     L63
  cmpq   $0x0,-0x28(%rbp)
  jne    L36
L63:
  mov    $0xffffffff,%eax
  jmp    L12
L36:
  nop
L14:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  jmp    L51
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L64
L51:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L27
  jmp    L83
L64:
  nop
L83:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int string_trim_right(const char *src, char *dst, char *module) {
  const char *temp = src;
  char c;
  if (!src || !dst || !module) {
    return -1;
  }
  while (*(++temp) != '\0')
    ;
  while ((--temp) != src) {
    c = *temp;
    if (strchr(module, c) == NULL) {
      break;
    }
  }
  strncpy(dst, src, temp - src + 1);
  dst[temp - src + 1] = '\0';
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_trim_right>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L56
  mov    %rdi,%rbp
  mov    %rsi,%r13
  test   %rdi,%rdi
  je     L56
  mov    %rdi,%rax
L4:
  mov    %rax,%rbx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L4
L57:
  mov    %rbx,%r14
  cmp    %rbp,%rbx
  je     L25
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  sub    $0x1,%rbx
  test   %rax,%rax
  jne    L57
L25:
  sub    %rbp,%r14
  lea    0x1(%r14),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%r13,%r14,1)
  mov    $0x0,%eax
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  mov    $0xffffffff,%eax
  jmp    L36
```

assistant: ```c
int string_trim_right(const char *src, char *dst, char *module) {
  const char *temp = src;
  char c;
  if (!src || !dst || !module) {
    return -1;
  }
  while (*(++temp) != '\0')
    ;
  while ((--temp) != src) {
    c = *temp;
    if (strchr(module, c) == NULL) {
      break;
    }
  }
  strncpy(dst, src, temp - src + 1);
  dst[temp - src + 1] = '\0';
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_trim_right>:
  endbr64
  test   %rsi,%rsi
  push   %r14
  sete   %al
  test   %rdx,%rdx
  push   %r13
  push   %r12
  mov    %rdx,%r12
  sete   %dl
  or     %dl,%al
  push   %rbp
  push   %rbx
  jne    L55
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L55
  mov    %rsi,%r13
  mov    %rdi,%rax
  nopl   (%rax)
L54:
  mov    %rax,%rbx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L54
  mov    %rbx,%r14
  cmp    %rbx,%rbp
  je     L56
  nopl   0x0(%rax)
L45:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  sub    $0x1,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L56
  mov    %rbx,%r14
  cmp    %rbx,%rbp
  jne    L45
L56:
  sub    %rbp,%r14
  mov    %rbp,%rsi
  mov    %r13,%rdi
  lea    0x1(%r14),%edx
  call   <strncpy@plt>
  movb   $0x0,0x1(%r13,%r14,1)
  xor    %eax,%eax
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L55:
  mov    $0xffffffff,%eax
  jmp    L51
```

assistant: ```c
int string_trim_right(const char *src, char *dst, char *module) {
  const char *temp = src;
  char c;
  if (!src || !dst || !module) {
    return -1;
  }
  while (*(++temp) != '\0')
    ;
  while ((--temp) != src) {
    c = *temp;
    if (strchr(module, c) == NULL) {
      break;
    }
  }
  strncpy(dst, src, temp - src + 1);
  dst[temp - src + 1] = '\0';
  return 0;
}
```