ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  lea    -0x44(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x3a(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L8
L30:
  mov    -0x4c(%rbp),%eax
  cltq
  movzbl -0x44(%rbp,%rax,1),%edx
  mov    -0x4c(%rbp),%eax
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x4c(%rbp)
L8:
  mov    -0x4c(%rbp),%eax
  cltq
  movzbl -0x44(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L30
  jmp    L23
L21:
  mov    -0x48(%rbp),%eax
  cltq
  movzbl -0x3a(%rbp,%rax,1),%edx
  mov    -0x4c(%rbp),%eax
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x4c(%rbp)
  addl   $0x1,-0x48(%rbp)
L23:
  mov    -0x48(%rbp),%eax
  cltq
  movzbl -0x3a(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L21
  mov    -0x4c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
void main() {
  char str1[10], str2[10], str3[30];
  int i = 0, j = 0;
  gets(str1);
  gets(str2);
  while (str1[i] != '\0') {
    str3[i] = str1[i];
    i++;
  }
  while (str2[j] != '\0') {
    str3[i] = str2[j];
    i++;
    j++;
  }
  str3[i + 1] = '\0';
  puts(str3);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <gets@plt>
  lea    0x16(%rsp),%rdi
  call   <gets@plt>
  movzbl 0xc(%rsp),%edx
  test   %dl,%dl
  je     L39
  mov    $0x1,%eax
  lea    0x1f(%rsp),%rdi
  lea    0xb(%rsp),%rsi
L54:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L54
L51:
  movzbl 0x16(%rsp),%edx
  test   %dl,%dl
  je     L24
  lea    0x1(%rcx),%eax
  cltq
  lea    0x1f(%rsp),%rdi
  lea    0x16(%rsp),%rsi
  movslq %ecx,%rcx
  sub    %rcx,%rsi
L29:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L29
L24:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  movb   $0x0,0x20(%rsp,%rcx,1)
  lea    0x20(%rsp),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x58,%rsp
  ret
L39:
  mov    $0x0,%ecx
  jmp    L51
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char str1[10], str2[10], str3[30];
  int i = 0, j = 0;
  gets(str1);
  gets(str2);
  while (str1[i] != '\0') {
    str3[i] = str1[i];
    i++;
  }
  while (str2[j] != '\0') {
    str3[i] = str2[j];
    i++;
    j++;
  }
  str3[i + 1] = '\0';
  puts(str3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  lea    0x16(%rsp),%rbx
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  movzbl 0xc(%rsp),%edx
  test   %dl,%dl
  je     L0
  mov    $0x1,%eax
  lea    0x1f(%rsp),%rsi
  lea    0xb(%rsp),%rdi
  nopl   0x0(%rax)
L24:
  mov    %dl,(%rsi,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L24
L6:
  movzbl 0x16(%rsp),%edx
  test   %dl,%dl
  je     L11
  lea    0x1(%rcx),%eax
  sub    %rcx,%rbx
  lea    0x1f(%rsp),%rsi
  cltq
  mov    %rbx,%rdi
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %dl,(%rsi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L4
L11:
  add    $0x1,%ecx
  lea    0x20(%rsp),%rdi
  movslq %ecx,%rcx
  movb   $0x0,0x20(%rsp,%rcx,1)
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x50,%rsp
  pop    %rbx
  ret
L0:
  xor    %ecx,%ecx
  jmp    L6
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char str1[10], str2[10], str3[30];
  int i = 0, j = 0;
  gets(str1);
  gets(str2);
  while (str1[i] != '\0') {
    str3[i] = str1[i];
    i++;
  }
  while (str2[j] != '\0') {
    str3[i] = str2[j];
    i++;
    j++;
  }
  str3[i + 1] = '\0';
  puts(str3);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <gets@plt>
  lea    0x16(%rsp),%rdi
  call   <gets@plt>
  movzbl 0xc(%rsp),%eax
  test   %al,%al
  je     L96
  mov    %al,0x20(%rsp)
  movzbl 0xd(%rsp),%eax
  test   %al,%al
  je     L64
  mov    %al,0x21(%rsp)
  movzbl 0xe(%rsp),%eax
  test   %al,%al
  je     L287
  mov    %al,0x22(%rsp)
  movzbl 0xf(%rsp),%eax
  test   %al,%al
  je     L72
  mov    %al,0x23(%rsp)
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L23
  mov    %al,0x24(%rsp)
  movzbl 0x11(%rsp),%eax
  test   %al,%al
  je     L254
  mov    %al,0x25(%rsp)
  movzbl 0x12(%rsp),%eax
  test   %al,%al
  je     L103
  mov    %al,0x26(%rsp)
  movzbl 0x13(%rsp),%eax
  test   %al,%al
  je     L249
  mov    %al,0x27(%rsp)
  movzbl 0x14(%rsp),%eax
  test   %al,%al
  je     L154
  mov    %al,0x28(%rsp)
  mov    $0x9,%edx
L273:
  movzbl 0x16(%rsp),%eax
  test   %al,%al
  je     L61
  movslq %edx,%rcx
  mov    %al,0x20(%rsp,%rcx,1)
  movzbl 0x17(%rsp),%ecx
  lea    0x1(%rdx),%eax
  test   %cl,%cl
  je     L195
  cltq
  mov    %cl,0x20(%rsp,%rax,1)
  movzbl 0x18(%rsp),%ecx
  lea    0x2(%rdx),%eax
  test   %cl,%cl
  je     L195
  cltq
  mov    %cl,0x20(%rsp,%rax,1)
  movzbl 0x19(%rsp),%ecx
  lea    0x3(%rdx),%eax
  test   %cl,%cl
  je     L195
  cltq
  mov    %cl,0x20(%rsp,%rax,1)
  movzbl 0x1a(%rsp),%ecx
  lea    0x4(%rdx),%eax
  test   %cl,%cl
  je     L195
  cltq
  mov    %cl,0x20(%rsp,%rax,1)
  movzbl 0x1b(%rsp),%ecx
  lea    0x5(%rdx),%eax
  test   %cl,%cl
  je     L195
  cltq
  mov    %cl,0x20(%rsp,%rax,1)
  movzbl 0x1c(%rsp),%ecx
  lea    0x6(%rdx),%eax
  test   %cl,%cl
  je     L195
  cltq
  mov    %cl,0x20(%rsp,%rax,1)
  movzbl 0x1d(%rsp),%ecx
  lea    0x7(%rdx),%eax
  test   %cl,%cl
  je     L195
  cltq
  mov    %cl,0x20(%rsp,%rax,1)
  movzbl 0x1e(%rsp),%ecx
  lea    0x8(%rdx),%eax
  test   %cl,%cl
  je     L195
  cltq
  mov    %cl,0x20(%rsp,%rax,1)
  lea    0x9(%rdx),%eax
L195:
  add    $0x1,%eax
  lea    0x20(%rsp),%rdi
  cltq
  movb   $0x0,0x20(%rsp,%rax,1)
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x58,%rsp
  ret
L254:
  mov    $0x5,%edx
  jmp    L273
L61:
  mov    %edx,%eax
  jmp    L195
L96:
  xor    %edx,%edx
  jmp    L273
L64:
  mov    $0x1,%edx
  jmp    L273
L287:
  mov    $0x2,%edx
  jmp    L273
L72:
  mov    $0x3,%edx
  jmp    L273
L23:
  mov    $0x4,%edx
  jmp    L273
L103:
  mov    $0x6,%edx
  jmp    L273
L249:
  mov    $0x7,%edx
  jmp    L273
L154:
  mov    $0x8,%edx
  jmp    L273
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char str1[10], str2[10], str3[30];
  int i = 0, j = 0;
  gets(str1);
  gets(str2);
  while (str1[i] != '\0') {
    str3[i] = str1[i];
    i++;
  }
  while (str2[j] != '\0') {
    str3[i] = str2[j];
    i++;
    j++;
  }
  str3[i + 1] = '\0';
  puts(str3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_siglist@plt>
  mov    $0x0,%eax
  call   <test_psig@plt>
  mov    $0x0,%eax
  call   <test_strsig@plt>
  mov    $0x0,%eax
  call   <test_conv@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_siglist();
  test_psig();
  test_strsig();
  test_conv();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_siglist@plt>
  mov    $0x0,%eax
  call   <test_psig@plt>
  mov    $0x0,%eax
  call   <test_strsig@plt>
  mov    $0x0,%eax
  call   <test_conv@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_siglist();
  test_psig();
  test_strsig();
  test_conv();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_siglist@plt>
  xor    %eax,%eax
  call   <test_psig@plt>
  xor    %eax,%eax
  call   <test_strsig@plt>
  xor    %eax,%eax
  call   <test_conv@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_siglist();
  test_psig();
  test_strsig();
  test_conv();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_siglist@plt>
  xor    %eax,%eax
  call   <test_psig@plt>
  xor    %eax,%eax
  call   <test_strsig@plt>
  xor    %eax,%eax
  call   <test_conv@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_siglist();
  test_psig();
  test_strsig();
  test_conv();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<bswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  or     -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t bswap(uint32_t x) {
  const uint32_t b0 = x & 0xff;
  const uint32_t b1 = (x >> 8) & 0xff;
  const uint32_t b2 = (x >> 16) & 0xff;
  const uint32_t b3 = (x >> 24) & 0xff;
  return (b0 << 24) | (b1 << 16) | (b2 << 8) | b3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bswap>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%eax
  and    $0xff0000,%eax
  mov    %edi,%edx
  shr    $0x18,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shl    $0x18,%edx
  or     %edx,%eax
  shr    $0x8,%edi
  and    $0xff00,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
uint32_t bswap(uint32_t x) {
  const uint32_t b0 = x & 0xff;
  const uint32_t b1 = (x >> 8) & 0xff;
  const uint32_t b2 = (x >> 16) & 0xff;
  const uint32_t b3 = (x >> 24) & 0xff;
  return (b0 << 24) | (b1 << 16) | (b2 << 8) | b3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bswap>:
  endbr64
  mov    %edi,%eax
  bswap  %eax
  ret
```

assistant: ```c
uint32_t bswap(uint32_t x) {
  const uint32_t b0 = x & 0xff;
  const uint32_t b1 = (x >> 8) & 0xff;
  const uint32_t b2 = (x >> 16) & 0xff;
  const uint32_t b3 = (x >> 24) & 0xff;
  return (b0 << 24) | (b1 << 16) | (b2 << 8) | b3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bswap>:
  endbr64
  mov    %edi,%eax
  bswap  %eax
  ret
```

assistant: ```c
uint32_t bswap(uint32_t x) {
  const uint32_t b0 = x & 0xff;
  const uint32_t b1 = (x >> 8) & 0xff;
  const uint32_t b2 = (x >> 16) & 0xff;
  const uint32_t b3 = (x >> 24) & 0xff;
  return (b0 << 24) | (b1 << 16) | (b2 << 8) | b3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putsxy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L1:
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <putxy@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void putsxy(char *text, int x, int y) {
  int i;
  for (i = 0; i < strlen(text); i++) {
    putxy(text[i], x + i, y);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putsxy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    $0x0,%ebx
  jmp    L10
L15:
  lea    0x0(%r13,%rbx,1),%esi
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %r12d,%edx
  call   <putxy@plt>
  add    $0x1,%rbx
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void putsxy(char *text, int x, int y) {
  int i;
  for (i = 0; i < strlen(text); i++) {
    putxy(text[i], x + i, y);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<putsxy>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%r13,%rbx,1),%esi
  mov    %r12d,%edx
  add    $0x1,%rbx
  call   <putxy@plt>
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void putsxy(char *text, int x, int y) {
  int i;
  for (i = 0; i < strlen(text); i++) {
    putxy(text[i], x + i, y);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<putsxy>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L14:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%r13,%rbx,1),%esi
  mov    %r12d,%edx
  add    $0x1,%rbx
  call   <putxy@plt>
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void putsxy(char *text, int x, int y) {
  int i;
  for (i = 0; i < strlen(text); i++) {
    putxy(text[i], x + i, y);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<orc_smatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9d,%eax
  mov    %ax,-0x5c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L1
L4:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L26
L23:
  mov    -0x18(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x24(%rbp)
  movzwl -0x24(%rbp),%eax
  or     -0x5c(%rbp),%ax
  mov    %ax,-0x22(%rbp)
  mov    -0x18(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzwl -0x22(%rbp),%eax
  mov    %ax,(%rdx)
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jle    L23
  addq   $0x1,-0x20(%rbp)
L1:
  mov    -0x20(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jle    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void orc_smatrix(short **m1, long nrl, long nrh, long ncl, long nch, short c, short **m2) {
  long i, j;
  short x, y, *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = x | c;
      Yi[j] = y;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<orc_smatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x20(%rsp),%r12
  cmp    %rdx,%rsi
  jg     L34
  mov    %rdi,%rbx
  mov    %rsi,%r10
  mov    %rcx,%r11
  lea    0x1(%rdx),%rbp
  lea    0x1(%r8),%rdi
L21:
  mov    (%rbx,%r10,8),%rcx
  mov    (%r12,%r10,8),%rsi
  cmp    %r8,%r11
  jg     L15
  mov    %r11,%rax
L23:
  mov    %r9d,%edx
  or     (%rcx,%rax,2),%dx
  mov    %dx,(%rsi,%rax,2)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L23
L15:
  add    $0x1,%r10
  cmp    %rbp,%r10
  jne    L21
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void orc_smatrix(short **m1, long nrl, long nrh, long ncl, long nch, short c, short **m2) {
  long i, j;
  short x, y, *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = x | c;
      Yi[j] = y;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<orc_smatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x20(%rsp),%r12
  cmp    %rdx,%rsi
  jg     L29
  mov    %rdi,%rbx
  mov    %rsi,%r10
  lea    0x1(%rdx),%rbp
  mov    %rcx,%r11
  lea    0x1(%r8),%rdi
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%rbx,%r10,8),%rcx
  mov    (%r12,%r10,8),%rsi
  cmp    %r8,%r11
  jg     L13
  mov    %r11,%rax
  nopl   0x0(%rax,%rax,1)
L0:
  movzwl (%rcx,%rax,2),%edx
  or     %r9d,%edx
  mov    %dx,(%rsi,%rax,2)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L0
L13:
  add    $0x1,%r10
  cmp    %rbp,%r10
  jne    L26
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void orc_smatrix(short **m1, long nrl, long nrh, long ncl, long nch, short c, short **m2) {
  long i, j;
  short x, y, *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = x | c;
      Yi[j] = y;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<orc_smatrix>:
  endbr64
  cmp    %rdx,%rsi
  jg     L82
  push   %r15
  mov    %rcx,%r11
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %r8,%rcx
  jg     L113
  lea    0x1(%rdx),%rax
  lea    (%rcx,%rcx,1),%r12
  sub    %rcx,%r8
  mov    %rdi,%rbx
  mov    %rax,-0x30(%rsp)
  movd   %r9d,%xmm1
  mov    %rsi,%rdi
  lea    0x1(%r13),%rbp
  lea    0x2(%r12),%rax
  punpcklwd %xmm1,%xmm1
  mov    %rax,-0x38(%rsp)
  lea    0x1(%r8),%rax
  pshufd $0x0,%xmm1,%xmm1
  mov    %rax,%r10
  mov    %rax,-0x28(%rsp)
  and    $0xfffffffffffffff8,%rax
  mov    %rax,%r14
  lea    (%rcx,%rax,1),%rax
  shr    $0x3,%r10
  mov    %rax,-0x20(%rsp)
  mov    %r8,%rax
  shl    $0x4,%r10
  sub    %r14,%rax
  mov    %rax,-0x18(%rsp)
  add    $0x1,%rax
  mov    %rax,-0x10(%rsp)
L10:
  mov    0x38(%rsp),%rax
  mov    (%rbx,%rdi,8),%rdx
  mov    (%rax,%rdi,8),%rcx
  mov    -0x38(%rsp),%rax
  lea    (%rcx,%r12,1),%rsi
  lea    (%rdx,%rax,1),%r15
  mov    %rsi,%rax
  sub    %r15,%rax
  cmp    $0xc,%rax
  jbe    L103
  cmp    $0x2,%r8
  jbe    L103
  cmp    $0x6,%r8
  jbe    L153
  lea    (%rdx,%r12,1),%r15
  xor    %eax,%eax
  nopl   0x0(%rax)
L86:
  movdqu (%r15,%rax,1),%xmm0
  por    %xmm1,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %r10,%rax
  jne    L86
  cmp    %r14,-0x28(%rsp)
  je     L118
  cmpq   $0x2,-0x18(%rsp)
  mov    -0x10(%rsp),%r15
  jbe    L29
  mov    -0x20(%rsp),%rax
  mov    %r14,%rsi
L119:
  add    %r11,%rsi
  movd   %r9d,%xmm3
  movq   (%rdx,%rsi,2),%xmm0
  pshuflw $0x0,%xmm3,%xmm2
  por    %xmm2,%xmm0
  movq   %xmm0,(%rcx,%rsi,2)
  mov    %r15,%rsi
  and    $0xfffffffffffffffc,%rsi
  add    %rsi,%rax
  cmp    %rsi,%r15
  je     L118
L112:
  movzwl (%rdx,%rax,2),%r15d
  lea    (%rax,%rax,1),%rsi
  or     %r9d,%r15d
  mov    %r15w,(%rcx,%rax,2)
  lea    0x1(%rax),%r15
  cmp    %r15,%r13
  jl     L118
  movzwl 0x2(%rdx,%rsi,1),%r15d
  add    $0x2,%rax
  or     %r9d,%r15d
  mov    %r15w,0x2(%rcx,%rsi,1)
  cmp    %rax,%r13
  jl     L118
  movzwl 0x4(%rdx,%rsi,1),%eax
  or     %r9d,%eax
  mov    %ax,0x4(%rcx,%rsi,1)
L118:
  add    $0x1,%rdi
  cmp    -0x30(%rsp),%rdi
  jne    L10
L113:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L103:
  mov    %r11,%rax
  nopl   0x0(%rax,%rax,1)
L38:
  movzwl (%rdx,%rax,2),%esi
  or     %r9d,%esi
  mov    %si,(%rcx,%rax,2)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L38
  jmp    L118
L153:
  mov    -0x28(%rsp),%r15
  mov    %r11,%rax
  xor    %esi,%esi
  jmp    L119
L29:
  mov    -0x20(%rsp),%rax
  jmp    L112
L82:
  ret
```

assistant: ```c
void orc_smatrix(short **m1, long nrl, long nrh, long ncl, long nch, short c, short **m2) {
  long i, j;
  short x, y, *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = x | c;
      Yi[j] = y;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<blah3_fcn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x67,%edi
  call   *%rax
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    $0x68,%edi
  call   *%rax
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    $0x69,%edi
  call   *%rax
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    $0x6a,%edi
  call   *%rax
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int blah3_fcn(int (*(*fcn_ptrs)[4])(int)) {
  (*fcn_ptrs)[0]('g');
  (*fcn_ptrs)[1]('h');
  (*fcn_ptrs)[2]('i');
  (*fcn_ptrs)[3]('j');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<blah3_fcn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x67,%edi
  call   *(%rbx)
  mov    $0x68,%edi
  call   *0x8(%rbx)
  mov    $0x69,%edi
  call   *0x10(%rbx)
  mov    $0x6a,%edi
  call   *0x18(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int blah3_fcn(int (*(*fcn_ptrs)[4])(int)) {
  (*fcn_ptrs)[0]('g');
  (*fcn_ptrs)[1]('h');
  (*fcn_ptrs)[2]('i');
  (*fcn_ptrs)[3]('j');
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<blah3_fcn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x67,%edi
  call   *(%rbx)
  mov    $0x68,%edi
  call   *0x8(%rbx)
  mov    $0x69,%edi
  call   *0x10(%rbx)
  mov    $0x6a,%edi
  call   *0x18(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int blah3_fcn(int (*(*fcn_ptrs)[4])(int)) {
  (*fcn_ptrs)[0]('g');
  (*fcn_ptrs)[1]('h');
  (*fcn_ptrs)[2]('i');
  (*fcn_ptrs)[3]('j');
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<blah3_fcn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x67,%edi
  call   *(%rbx)
  mov    $0x68,%edi
  call   *0x8(%rbx)
  mov    $0x69,%edi
  call   *0x10(%rbx)
  mov    $0x6a,%edi
  call   *0x18(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int blah3_fcn(int (*(*fcn_ptrs)[4])(int)) {
  (*fcn_ptrs)[0]('g');
  (*fcn_ptrs)[1]('h');
  (*fcn_ptrs)[2]('i');
  (*fcn_ptrs)[3]('j');
  return 0;
}
```