ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <print_emerg@plt>
L3:
  jmp    L3
```

assistant: ```c
void die(const char *str) {
  print_emerg(str);
  do {
    asm(" ");
  } while (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <print_emerg@plt>
L2:
  jmp    L2
```

assistant: ```c
void die(const char *str) {
  print_emerg(str);
  do {
    asm(" ");
  } while (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_emerg@plt>
  nop
L8:
  jmp    L8
```

assistant: ```c
void die(const char *str) {
  print_emerg(str);
  do {
    asm(" ");
  } while (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_emerg@plt>
  nop
L3:
  jmp    L3
```

assistant: ```c
void die(const char *str) {
  print_emerg(str);
  do {
    asm(" ");
  } while (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nullPointer_epoll_ctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <epoll_ctl@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <epoll_ctl@plt>
  leave
  ret
```

assistant: ```c
int nullPointer_epoll_ctl(int epfd, int op, int fd, struct epoll_event *event) {
  (void)epoll_ctl(epfd, op, fd, event);
  return epoll_ctl(epfd, EPOLL_CTL_DEL, fd, NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nullPointer_epoll_ctl>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edx,%ebp
  call   <epoll_ctl@plt>
  mov    $0x0,%ecx
  mov    %ebp,%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <epoll_ctl@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int nullPointer_epoll_ctl(int epfd, int op, int fd, struct epoll_event *event) {
  (void)epoll_ctl(epfd, op, fd, event);
  return epoll_ctl(epfd, EPOLL_CTL_DEL, fd, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nullPointer_epoll_ctl>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <epoll_ctl@plt>
  mov    D6(%rip),%rax
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    %r12d,%edx
  mov    (%rax),%esi
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1050 <epoll_ctl@plt>
```

assistant: ```c
int nullPointer_epoll_ctl(int epfd, int op, int fd, struct epoll_event *event) {
  (void)epoll_ctl(epfd, op, fd, event);
  return epoll_ctl(epfd, EPOLL_CTL_DEL, fd, NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nullPointer_epoll_ctl>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <epoll_ctl@plt>
  mov    D0(%rip),%rax
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    %r12d,%edx
  mov    (%rax),%esi
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1050 <epoll_ctl@plt>
```

assistant: ```c
int nullPointer_epoll_ctl(int epfd, int op, int fd, struct epoll_event *event) {
  (void)epoll_ctl(epfd, op, fd, event);
  return epoll_ctl(epfd, EPOLL_CTL_DEL, fd, NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x8(%rbp)
  mov    D15(%rip),%edx
  mov    $0x0,%eax
  sub    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    D11(%rip),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7fffffff,-0x4(%rbp)
  je     L3
  call   <abort@plt>
L3:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int a = -1;
  static int b = -2147483647 - 1;
  static int c = 0;
  int t = a - (b + c * -2);
  if (t != 2147483647)
    __builtin_abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = -1;
  static int b = -2147483647 - 1;
  static int c = 0;
  int t = a - (b + c * -2);
  if (t != 2147483647)
    __builtin_abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = -1;
  static int b = -2147483647 - 1;
  static int c = 0;
  int t = a - (b + c * -2);
  if (t != 2147483647)
    __builtin_abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = -1;
  static int b = -2147483647 - 1;
  static int c = 0;
  int t = a - (b + c * -2);
  if (t != 2147483647)
    __builtin_abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fz_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x20(%rbp),%r13
  mov    -0x28(%rbp),%r12
  mov    -0x2c(%rbp),%ebx
  test   %ebx,%ebx
  je     L19
  sub    $0x1,%ebx
  test   %ebx,%ebx
  je     L19
L40:
  mov    %r12,%rdx
  lea    0x1(%rdx),%r12
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L5
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jne    L40
  jmp    L19
L5:
  nop
L19:
  test   %ebx,%ebx
  jne    L37
  cmpl   $0x0,-0x2c(%rbp)
  je     L25
  movb   $0x0,0x0(%r13)
L25:
  nop
L71:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
L37:
  mov    %r12,%rax
  sub    -0x28(%rbp),%rax
  sub    $0x1,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int fz_strlcpy(char *dst, const char *src, int siz) {
  register char *d = dst;
  register const char *s = src;
  register int n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fz_strlcpy>:
  endbr64
  test   %edx,%edx
  je     L18
  sub    $0x1,%edx
  je     L84
  mov    %rsi,%rax
L24:
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdi)
  test   %cl,%cl
  je     L78
  sub    $0x1,%edx
  jne    L24
  jmp    L27
L18:
  mov    %rsi,%rax
L20:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L20
L55:
  sub    %rsi,%rax
  sub    $0x1,%eax
  ret
L84:
  mov    %rsi,%rax
L27:
  movb   $0x0,(%rdi)
  jmp    L20
L78:
  test   %edx,%edx
  jne    L55
  jmp    L27
```

assistant: ```c
int fz_strlcpy(char *dst, const char *src, int siz) {
  register char *d = dst;
  register const char *s = src;
  register int n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fz_strlcpy>:
  endbr64
  test   %edx,%edx
  je     L66
  cmp    $0x1,%edx
  je     L41
  lea    -0x1(%rdx),%ecx
  mov    %rsi,%rax
  add    %rdi,%rcx
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L14:
  cmp    %rcx,%rdi
  je     L57
L34:
  movzbl (%rax),%edx
  add    $0x1,%rax
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  jne    L14
  sub    %rsi,%rax
  sub    $0x1,%eax
  ret
  xchg   %ax,%ax
L66:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L23
  sub    %rsi,%rax
  sub    $0x1,%eax
  ret
  nopl   0x0(%rax)
L41:
  mov    %rsi,%rax
L57:
  movb   $0x0,(%rdi)
  jmp    L23
```

assistant: ```c
int fz_strlcpy(char *dst, const char *src, int siz) {
  register char *d = dst;
  register const char *s = src;
  register int n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fz_strlcpy>:
  endbr64
  test   %edx,%edx
  je     L24
  cmp    $0x1,%edx
  je     L65
  lea    -0x1(%rdx),%ecx
  mov    %rsi,%rax
  add    %rdi,%rcx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L69:
  cmp    %rcx,%rdi
  je     L20
L13:
  movzbl (%rax),%edx
  add    $0x1,%rax
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  jne    L69
  sub    %rsi,%rax
  sub    $0x1,%eax
  ret
  xchg   %ax,%ax
L24:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L19
  sub    %rsi,%rax
  sub    $0x1,%eax
  ret
  nopl   0x0(%rax)
L65:
  mov    %rsi,%rax
L20:
  movb   $0x0,(%rdi)
  jmp    L19
```

assistant: ```c
int fz_strlcpy(char *dst, const char *src, int siz) {
  register char *d = dst;
  register const char *s = src;
  register int n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<extract_receive_buffer_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x2(%rbp),%eax
  or     %edx,%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl -0x2(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0x30(%rbp),%rax
  movzbl 0x2(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x30(%rbp),%rax
  movzbl 0x3(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int extract_receive_buffer_header(unsigned short *length, unsigned char *serial_number, unsigned char *packet_type, unsigned char *buffer) {
  unsigned short data;
  data = buffer[0] << 0;
  data |= buffer[1] << 8;
  *length = data;
  *serial_number = buffer[2];
  *packet_type = buffer[3];
  return (*length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<extract_receive_buffer_header>:
  endbr64
  mov    %rsi,%r8
  mov    %rdx,%rsi
  movzbl 0x1(%rcx),%edx
  shl    $0x8,%edx
  movzbl (%rcx),%eax
  or     %edx,%eax
  mov    %ax,(%rdi)
  movzbl 0x2(%rcx),%eax
  mov    %al,(%r8)
  movzbl 0x3(%rcx),%eax
  mov    %al,(%rsi)
  movzwl (%rdi),%eax
  ret
```

assistant: ```c
int extract_receive_buffer_header(unsigned short *length, unsigned char *serial_number, unsigned char *packet_type, unsigned char *buffer) {
  unsigned short data;
  data = buffer[0] << 0;
  data |= buffer[1] << 8;
  *length = data;
  *serial_number = buffer[2];
  *packet_type = buffer[3];
  return (*length);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<extract_receive_buffer_header>:
  endbr64
  movzwl (%rcx),%eax
  mov    %ax,(%rdi)
  movzbl 0x2(%rcx),%eax
  mov    %al,(%rsi)
  movzbl 0x3(%rcx),%eax
  mov    %al,(%rdx)
  movzwl (%rdi),%eax
  ret
```

assistant: ```c
int extract_receive_buffer_header(unsigned short *length, unsigned char *serial_number, unsigned char *packet_type, unsigned char *buffer) {
  unsigned short data;
  data = buffer[0] << 0;
  data |= buffer[1] << 8;
  *length = data;
  *serial_number = buffer[2];
  *packet_type = buffer[3];
  return (*length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<extract_receive_buffer_header>:
  endbr64
  movzwl (%rcx),%eax
  mov    %ax,(%rdi)
  movzbl 0x2(%rcx),%eax
  mov    %al,(%rsi)
  movzbl 0x3(%rcx),%eax
  mov    %al,(%rdx)
  movzwl (%rdi),%eax
  ret
```

assistant: ```c
int extract_receive_buffer_header(unsigned short *length, unsigned char *serial_number, unsigned char *packet_type, unsigned char *buffer) {
  unsigned short data;
  data = buffer[0] << 0;
  data |= buffer[1] << 8;
  *length = data;
  *serial_number = buffer[2];
  *packet_type = buffer[3];
  return (*length);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L38
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jge    L48
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
L48:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
L38:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jge    L60
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
L60:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D22
type_guessed: string
name: disassemble_data
arguments: data_label: D59
type_guessed: string

tool: D11: input three integers:

tool: D22: %d,%d,%d

tool: D59: max=%d


assistant: ```c
int main() {
  int a, b, c;
  printf("input three integers:");
  scanf("%d,%d,%d", &a, &b, &c);
  if (a < b)
    if (b < c)
      printf("max=%d\n", c);
    else
      printf("max=%d\n", b);
  else if (a < c)
    printf("max=%d\n", c);
  else
    printf("max=%d\n", a);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  jge    L9
  mov    0x14(%rsp),%esi
  cmp    %esi,%eax
  jge    L14
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L14:
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L9:
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  jge    L49
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L49:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D38
type: string
name: unpack_data
arguments: data_tag: D43
type: string
name: unpack_data
arguments: data_tag: D5
type: string

tool: D38: input three integers:

tool: D43: %d,%d,%d

tool: D5: max=%d


assistant: ```c
int main() {
  int a, b, c;
  printf("input three integers:");
  scanf("%d,%d,%d", &a, &b, &c);
  if (a < b)
    if (b < c)
      printf("max=%d\n", c);
    else
      printf("max=%d\n", b);
  else if (a < c)
    printf("max=%d\n", c);
  else
    printf("max=%d\n", a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r8d
  cmp    %r8d,%esi
  jge    L26
  mov    0x14(%rsp),%esi
  cmp    %esi,%r8d
  jl     L44
L15:
  mov    %r8d,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L26:
  mov    0x14(%rsp),%r8d
  cmp    %r8d,%esi
  jl     L15
L44:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string
name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D6
type: string

tool: D7: input three integers:

tool: D29: %d,%d,%d

tool: D6: max=%d


assistant: ```c
int main() {
  int a, b, c;
  printf("input three integers:");
  scanf("%d,%d,%d", &a, &b, &c);
  if (a < b)
    if (b < c)
      printf("max=%d\n", c);
    else
      printf("max=%d\n", b);
  else if (a < c)
    printf("max=%d\n", c);
  else
    printf("max=%d\n", a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D20(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r8d
  cmp    %r8d,%esi
  jge    L31
  mov    0x14(%rsp),%esi
  cmp    %esi,%r8d
  jl     L34
L5:
  mov    %r8d,%esi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L31:
  mov    0x14(%rsp),%r8d
  cmp    %r8d,%esi
  jl     L5
L34:
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L11
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D20
data_type: string
name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D37
data_type: string

tool: D20: input three integers:

tool: D6: %d,%d,%d

tool: D37: max=%d


assistant: ```c
int main() {
  int a, b, c;
  printf("input three integers:");
  scanf("%d,%d,%d", &a, &b, &c);
  if (a < b)
    if (b < c)
      printf("max=%d\n", c);
    else
      printf("max=%d\n", b);
  else if (a < c)
    printf("max=%d\n", c);
  else
    printf("max=%d\n", a);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<leftmostNotR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x52,%al
  je     L5
  mov    -0x4(%rbp),%eax
  jmp    L36
L5:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L32
  mov    $0xffffffff,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int leftmostNotR(char *array, int n) {
  for (int i = 0; i < n; i++) {
    if (array[i] != 'R') {
      return i;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<leftmostNotR>:
  endbr64
  test   %esi,%esi
  jle    L28
  mov    %esi,%esi
  mov    $0x0,%eax
L18:
  mov    %eax,%edx
  cmpb   $0x52,(%rdi,%rax,1)
  jne    L32
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L18
  mov    $0xffffffff,%edx
L32:
  mov    %edx,%eax
  ret
L28:
  mov    $0xffffffff,%edx
  jmp    L32
```

assistant: ```c
int leftmostNotR(char *array, int n) {
  for (int i = 0; i < n; i++) {
    if (array[i] != 'R') {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<leftmostNotR>:
  endbr64
  test   %esi,%esi
  jle    L7
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L26
  nop
L30:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L7
L26:
  cmpb   $0x52,(%rdi,%rax,1)
  mov    %eax,%r8d
  je     L30
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int leftmostNotR(char *array, int n) {
  for (int i = 0; i < n; i++) {
    if (array[i] != 'R') {
      return i;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<leftmostNotR>:
  endbr64
  test   %esi,%esi
  jle    L31
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L18
  nop
L39:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L31
L18:
  cmpb   $0x52,(%rdi,%rax,1)
  mov    %eax,%r8d
  je     L39
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int leftmostNotR(char *array, int n) {
  for (int i = 0; i < n; i++) {
    if (array[i] != 'R') {
      return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<glmMultVectorByMatrix32d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x38,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void glmMultVectorByMatrix32d(double result[2], const double v[2], const double m[9]) {
  result[0] = m[0] * v[0] + m[3] * v[1] + m[6];
  result[1] = m[1] * v[0] + m[4] * v[1] + m[7];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glmMultVectorByMatrix32d>:
  endbr64
  movsd  (%rdx),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x18(%rdx),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x30(%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rdx),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x20(%rdx),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x38(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void glmMultVectorByMatrix32d(double result[2], const double v[2], const double m[9]) {
  result[0] = m[0] * v[0] + m[3] * v[1] + m[6];
  result[1] = m[1] * v[0] + m[4] * v[1] + m[7];
}
```
user: Translate the below assembly code into C programming language:

```asm
<glmMultVectorByMatrix32d>:
  endbr64
  movsd  (%rdx),%xmm0
  movsd  0x18(%rdx),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x30(%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rdx),%xmm0
  movsd  0x20(%rdx),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x38(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void glmMultVectorByMatrix32d(double result[2], const double v[2], const double m[9]) {
  result[0] = m[0] * v[0] + m[3] * v[1] + m[6];
  result[1] = m[1] * v[0] + m[4] * v[1] + m[7];
}
```