ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmd_source>:
  endbr64
  cmp    $0x1,%edi
  jle    L8
  mov    0x8(%rsi),%rdi
  jmp    1050 <rc_sourcefile@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cmd_source(int argc, char **argv) {
  if (argc < 2)
    return -1;
  return rc_sourcefile(argv[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<addArrayToArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L11
L13:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: Array must be initialized

assistant: ```c
int **addArrayToArray(int **array, int *toAdd, int oldcount) {
  if (array == NULL) {
    printf("Array must be initialized");
    exit(1);
  } else
    array = realloc(array, sizeof(int *) * (oldcount + 1));
  array[oldcount] = toAdd;
  return array;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addArrayToArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  test   %rdi,%rdi
  je     L15
  lea    0x8(,%rdx,8),%esi
  call   <realloc@plt>
L19:
  movslq %ebp,%rbp
  mov    %r12,(%rax,%rbp,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %rbx,%rax
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: Array must be initialized

assistant: ```c
int **addArrayToArray(int **array, int *toAdd, int oldcount) {
  if (array == NULL) {
    printf("Array must be initialized");
    exit(1);
  } else
    array = realloc(array, sizeof(int *) * (oldcount + 1));
  array[oldcount] = toAdd;
  return array;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<addArrayToArray>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L7
  lea    0x8(,%rbx,8),%esi
  call   <realloc@plt>
  mov    %rbp,(%rax,%rbx,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  mov    %rbp,(%rax,%rbx,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: Array must be initialized

assistant: ```c
int **addArrayToArray(int **array, int *toAdd, int oldcount) {
  if (array == NULL) {
    printf("Array must be initialized");
    exit(1);
  } else
    array = realloc(array, sizeof(int *) * (oldcount + 1));
  array[oldcount] = toAdd;
  return array;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<addArrayToArray>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L4
  lea    0x8(,%rbx,8),%esi
  call   <realloc@plt>
  mov    %rbp,(%rax,%rbx,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  mov    %rbp,(%rax,%rbx,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: Array must be initialized

assistant: ```c
int **addArrayToArray(int **array, int *toAdd, int oldcount) {
  if (array == NULL) {
    printf("Array must be initialized");
    exit(1);
  } else
    array = realloc(array, sizeof(int *) * (oldcount + 1));
  array[oldcount] = toAdd;
  return array;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fs_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L13
  mov    -0x38(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L13:
  lea    D3(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <shell_out@plt>
  mov    %eax,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <cl_must_pass_@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string
name: parse_data
arguments: data_tag: D17
datatype: string
name: parse_data
arguments: data_tag: D13
datatype: string

tool: D3: /bin/cp

tool: D17: -R

tool: D13: Failed to copy test fixtures to sandbox

assistant: ```c
void fs_copy(const char *_source, const char *dest) {
  char *argv[5];
  char *source;
  size_t source_len;
  source = strdup(_source);
  source_len = strlen(source);
  if (source[source_len - 1] == '/')
    source[source_len - 1] = 0;
  argv[0] = "/bin/cp";
  argv[1] = "-R";
  argv[2] = source;
  argv[3] = (char *)dest;
  argv[4] = NULL;
  cl_must_pass_(shell_out(argv), "Failed to copy test fixtures to sandbox");
  free(source);
}
```
user: What is the c source code of the assembly code below?

```asm
<fs_copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  je     L21
L22:
  lea    D14(%rip),%rax
  mov    %rax,(%rsp)
  lea    D0(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    %rbx,0x10(%rsp)
  mov    %rbp,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  mov    %rsp,%rdi
  call   <shell_out@plt>
  mov    %eax,%edi
  lea    D23(%rip),%rsi
  call   <cl_must_pass_@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  movb   $0x0,(%rax)
  jmp    L22
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string

tool: D14: /bin/cp

tool: D0: -R

tool: D23: Failed to copy test fixtures to sandbox

assistant: ```c
void fs_copy(const char *_source, const char *dest) {
  char *argv[5];
  char *source;
  size_t source_len;
  source = strdup(_source);
  source_len = strlen(source);
  if (source[source_len - 1] == '/')
    source[source_len - 1] = 0;
  argv[0] = "/bin/cp";
  argv[1] = "-R";
  argv[2] = source;
  argv[3] = (char *)dest;
  argv[4] = NULL;
  cl_must_pass_(shell_out(argv), "Failed to copy test fixtures to sandbox");
  free(source);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fs_copy>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    -0x1(%rbp,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  jne    L11
  movb   $0x0,(%rax)
L11:
  lea    D15(%rip),%rax
  mov    %rsp,%rdi
  mov    %rbp,0x10(%rsp)
  mov    %rax,(%rsp)
  lea    D19(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    %rbx,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  call   <shell_out@plt>
  lea    D22(%rip),%rsi
  mov    %eax,%edi
  call   <cl_must_pass_@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D15
datatype: string
name: read_data
arguments: tag: D19
datatype: string
name: read_data
arguments: tag: D22
datatype: string

tool: D15: /bin/cp

tool: D19: -R

tool: D22: Failed to copy test fixtures to sandbox

assistant: ```c
void fs_copy(const char *_source, const char *dest) {
  char *argv[5];
  char *source;
  size_t source_len;
  source = strdup(_source);
  source_len = strlen(source);
  if (source[source_len - 1] == '/')
    source[source_len - 1] = 0;
  argv[0] = "/bin/cp";
  argv[1] = "-R";
  argv[2] = source;
  argv[3] = (char *)dest;
  argv[4] = NULL;
  cl_must_pass_(shell_out(argv), "Failed to copy test fixtures to sandbox");
  free(source);
}
```
user: What is the c source code of the assembly code below:

```asm
<fs_copy>:
  endbr64
  push   %rbp
  sub    $0x40,%rsp
  mov    %rsi,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  movq   %rax,%xmm1
  mov    %rax,%rdi
  mov    %rax,%rbp
  movhps (%rsp),%xmm1
  movaps %xmm1,(%rsp)
  call   <strlen@plt>
  movdqa (%rsp),%xmm1
  lea    -0x1(%rbp,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  jne    L10
  movb   $0x0,(%rax)
L10:
  lea    D8(%rip),%rdx
  lea    0x10(%rsp),%rdi
  movaps %xmm1,0x20(%rsp)
  lea    D1(%rip),%rax
  movq   %rdx,%xmm0
  movq   $0x0,0x30(%rsp)
  movq   %rax,%xmm2
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <shell_out@plt>
  lea    D15(%rip),%rsi
  mov    %eax,%edi
  call   <cl_must_pass_@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string
name: read_data
arguments: data_tag: D1
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string

tool: D8: /bin/cp

tool: D1: -R

tool: D15: Failed to copy test fixtures to sandbox

assistant: ```c
void fs_copy(const char *_source, const char *dest) {
  char *argv[5];
  char *source;
  size_t source_len;
  source = strdup(_source);
  source_len = strlen(source);
  if (source[source_len - 1] == '/')
    source[source_len - 1] = 0;
  argv[0] = "/bin/cp";
  argv[1] = "-R";
  argv[2] = source;
  argv[3] = (char *)dest;
  argv[4] = NULL;
  cl_must_pass_(shell_out(argv), "Failed to copy test fixtures to sandbox");
  free(source);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L7
L2:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L7:
  cmpl   $0x0,-0x18(%rbp)
  jne    L2
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a, b, x, y, t, gcd, lcm;
  a = x;
  b = y << 2;
  while (b != 0) {
    t = b;
    b = a / b;
    a = t;
  }
  gcd = a;
  lcm = (x * y) / gcd;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, x, y, t, gcd, lcm;
  a = x;
  b = y << 2;
  while (b != 0) {
    t = b;
    b = a / b;
    a = t;
  }
  gcd = a;
  lcm = (x * y) / gcd;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, x, y, t, gcd, lcm;
  a = x;
  b = y << 2;
  while (b != 0) {
    t = b;
    b = a / b;
    a = t;
  }
  gcd = a;
  lcm = (x * y) / gcd;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, x, y, t, gcd, lcm;
  a = x;
  b = y << 2;
  while (b != 0) {
    t = b;
    b = a / b;
    a = t;
  }
  gcd = a;
  lcm = (x * y) / gcd;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L21
L11:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  movzbl -0x12(%rbp),%eax
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  jne    L12
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x12(%rbp),%eax
  shl    $0x6,%eax
  and    $0xffffffc0,%eax
  mov    %eax,%edx
  movzbl -0x11(%rbp),%eax
  and    $0x3f,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L33
L12:
  movzbl -0x12(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L33:
  addq   $0x1,-0x10(%rbp)
L21:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *utf8_decode(const char *src) {
  char *ret = calloc(1, strlen(src) + 1);
  char *aux = ret;
  while (*src) {
    unsigned char lead = *src++;
    if ((lead & 0xe0) == 0xc0) {
      unsigned char ch2 = *src++;
      *aux = ((lead & 0x1f) << 6) | (ch2 & 0x3f);
    } else {
      *aux = lead;
    }
    aux++;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utf8_decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L17
  mov    %rax,%rcx
  jmp    L41
L45:
  movzbl 0x1(%rbx),%esi
  and    $0x3f,%esi
  shl    $0x6,%edx
  or     %esi,%edx
  lea    0x2(%rbx),%rbx
L18:
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L17
L41:
  mov    %edx,%esi
  and    $0xffffffe0,%esi
  cmp    $0xc0,%sil
  je     L45
  add    $0x1,%rbx
  jmp    L18
L17:
  pop    %rbx
  ret
```

assistant: ```c
char *utf8_decode(const char *src) {
  char *ret = calloc(1, strlen(src) + 1);
  char *aux = ret;
  while (*src) {
    unsigned char lead = *src++;
    if ((lead & 0xe0) == 0xc0) {
      unsigned char ch2 = *src++;
      *aux = ((lead & 0x1f) << 6) | (ch2 & 0x3f);
    } else {
      *aux = lead;
    }
    aux++;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<utf8_decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%rsi
  call   <calloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L31
  mov    %rax,%rcx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x1,%rbx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L31
L27:
  mov    %edx,%esi
  and    $0xffffffe0,%esi
  cmp    $0xc0,%sil
  jne    L38
  movzbl 0x1(%rbx),%esi
  shl    $0x6,%edx
  add    $0x2,%rbx
  add    $0x1,%rcx
  and    $0x3f,%esi
  or     %esi,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L27
L31:
  pop    %rbx
  ret
```

assistant: ```c
char *utf8_decode(const char *src) {
  char *ret = calloc(1, strlen(src) + 1);
  char *aux = ret;
  while (*src) {
    unsigned char lead = *src++;
    if ((lead & 0xe0) == 0xc0) {
      unsigned char ch2 = *src++;
      *aux = ((lead & 0x1f) << 6) | (ch2 & 0x3f);
    } else {
      *aux = lead;
    }
    aux++;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<utf8_decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%rsi
  call   <calloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L22
  mov    %rax,%rcx
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %dl,(%rcx)
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rsi
  add    $0x1,%rcx
  test   %dl,%dl
  je     L22
L27:
  mov    %rsi,%rbx
L11:
  mov    %edx,%esi
  and    $0xffffffe0,%esi
  cmp    $0xc0,%sil
  jne    L20
  movzbl 0x1(%rbx),%edi
  shl    $0x6,%edx
  lea    0x2(%rbx),%rsi
  add    $0x1,%rcx
  and    $0x3f,%edi
  or     %edi,%edx
  mov    %dl,-0x1(%rcx)
  movzbl 0x2(%rbx),%edx
  test   %dl,%dl
  jne    L27
L22:
  pop    %rbx
  ret
```

assistant: ```c
char *utf8_decode(const char *src) {
  char *ret = calloc(1, strlen(src) + 1);
  char *aux = ret;
  while (*src) {
    unsigned char lead = *src++;
    if ((lead & 0xe0) == 0xc0) {
      unsigned char ch2 = *src++;
      *aux = ((lead & 0x1f) << 6) | (ch2 & 0x3f);
    } else {
      *aux = lead;
    }
    aux++;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<doit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  call   <baz@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void doit() {
  foo();
  bar();
  baz();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<doit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  call   <baz@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void doit() {
  foo();
  bar();
  baz();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<doit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <baz@plt>
```

assistant: ```c
void doit() {
  foo();
  bar();
  baz();
}
```
user: What is the c source code of the assembly code below:

```asm
<doit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <baz@plt>
```

assistant: ```c
void doit() {
  foo();
  bar();
  baz();
}
```
user: What is the c source code of the assembly code below?

```asm
<fill_testfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xe,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L26
  movl   $0x1,-0xc(%rbp)
L26:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  shl    $0xa,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L33:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x41,(%rax)
  addl   $0x1,-0x10(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  shl    $0xa,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L33
  movl   $0x0,-0x10(%rbp)
  jmp    L30
L45:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  shl    $0xa,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  test   %rax,%rax
  jns    L3
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L59
L3:
  addl   $0x1,-0x10(%rbp)
L30:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L45
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
L59:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string

tool: D7: write

assistant: ```c
int fill_testfile(int testfile_descriptor, int testfile_size) {
  char *zero;
  int i;
  int parts;
  parts = (testfile_size / 51200);
  if (parts < 1)
    parts = 1;
  zero = (char *)calloc((testfile_size / parts) * 1024, sizeof(char));
  for (i = 0; i < (testfile_size / parts) * 1024; i++)
    zero[i] = 'A';
  for (i = 0; i < parts; i++) {
    if (write(testfile_descriptor, (char *)zero, ((testfile_size / parts) * 1024) * sizeof(char)) < 0) {
      perror("write");
      free(zero);
      return -1;
    }
  }
  free(zero);
  return testfile_descriptor;
}
```
user: What is the c source code of the assembly code below:

```asm
<fill_testfile>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  cmp    $0xc7ff,%esi
  jle    L41
  movslq %esi,%r14
  imul   $0x51eb851f,%r14,%r14
  sar    $0x2e,%r14
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%r14d
  mov    %esi,%eax
  cltd
  idiv   %r14d
  shl    $0xa,%eax
  mov    %eax,%ebx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,%r12
L1:
  mov    $0x0,%edx
L14:
  movb   $0x41,(%r12,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L14
L64:
  mov    $0x0,%ebp
L42:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  test   %rax,%rax
  js     L19
  add    $0x1,%ebp
  cmp    %r14d,%ebp
  jl     L42
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13d,%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L16
L41:
  shl    $0xa,%esi
  mov    %esi,%ebx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    $0x1,%r14d
  test   %ebx,%ebx
  jg     L1
  jmp    L64
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: write

assistant: ```c
int fill_testfile(int testfile_descriptor, int testfile_size) {
  char *zero;
  int i;
  int parts;
  parts = (testfile_size / 51200);
  if (parts < 1)
    parts = 1;
  zero = (char *)calloc((testfile_size / parts) * 1024, sizeof(char));
  for (i = 0; i < (testfile_size / parts) * 1024; i++)
    zero[i] = 'A';
  for (i = 0; i < parts; i++) {
    if (write(testfile_descriptor, (char *)zero, ((testfile_size / parts) * 1024) * sizeof(char)) < 0) {
      perror("write");
      free(zero);
      return -1;
    }
  }
  free(zero);
  return testfile_descriptor;
}
```