ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sys_isabsolutepath>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x2f,%dl
  sete   %al
  cmp    $0x7e,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int sys_isabsolutepath(const char *dir) {
  if (dir[0] == '/' || dir[0] == '~') {
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sys_isabsolutepath>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x2f,%dl
  sete   %al
  cmp    $0x7e,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int sys_isabsolutepath(const char *dir) {
  if (dir[0] == '/' || dir[0] == '~') {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sys_isabsolutepath>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x2f,%dl
  sete   %al
  cmp    $0x7e,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int sys_isabsolutepath(const char *dir) {
  if (dir[0] == '/' || dir[0] == '~') {
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<floatToStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%rax
  movd   %edx,%xmm0
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %f

assistant: ```c
void floatToStr(float x, char y[]) {
  sprintf(y, "%f", x);
  y[strlen(y)] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<floatToStr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: %f

assistant: ```c
void floatToStr(float x, char y[]) {
  sprintf(y, "%f", x);
  y[strlen(y)] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floatToStr>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rsi
  mov    %rdi,%rbx
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D9: %f

assistant: ```c
void floatToStr(float x, char y[]) {
  sprintf(y, "%f", x);
  y[strlen(y)] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<floatToStr>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rsi
  mov    %rdi,%rbx
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: %f

assistant: ```c
void floatToStr(float x, char y[]) {
  sprintf(y, "%f", x);
  y[strlen(y)] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Number_of_Legal_Moves>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L73:
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L18:
  movl   $0x1,-0x4(%rbp)
  jmp    L57
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  movsbl -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <sameSide@plt>
  test   %rax,%rax
  je     L46
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %rax,%rdx
  shl    $0x5,%rdx
  add    %rdx,%rax
  add    %rsi,%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    $0x4c,%al
  jne    L46
  addl   $0x1,-0x10(%rbp)
L46:
  addl   $0x1,-0x4(%rbp)
L57:
  cmpl   $0x20,-0x4(%rbp)
  jle    L20
  addl   $0x1,-0x8(%rbp)
L21:
  cmpl   $0x7,-0x8(%rbp)
  jle    L18
  addl   $0x1,-0xc(%rbp)
L17:
  cmpl   $0x7,-0xc(%rbp)
  jle    L73
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Number_of_Legal_Moves(char grid[8][8][33], char pieceTranslator[33], char king) {
  int total = 0, x, y, z;
  for (x = 0; x < 8; ++x)
    for (y = 0; y < 8; ++y)
      for (z = 1; z < 33; ++z)
        if ((sameSide(king, pieceTranslator[z])) && (grid[x][y][z] == 'L'))
          ++total;
  return total;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Number_of_Legal_Moves>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rax
  mov    %rsi,%r12
  mov    %rdi,%r15
  add    $0x840,%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r13d
  movsbl %dl,%ebp
  jmp    L10
L33:
  add    $0x1,%rbx
  cmp    $0x21,%rbx
  je     L3
L16:
  movsbl (%r12,%rbx,1),%esi
  mov    %ebp,%edi
  call   <sameSide@plt>
  test   %rax,%rax
  je     L33
  cmpb   $0x4c,(%r14,%rbx,1)
  sete   %al
  movzbl %al,%eax
  add    %eax,%r13d
  jmp    L33
L3:
  add    $0x21,%r14
  lea    0x108(%r15),%rax
  cmp    %rax,%r14
  je     L27
L58:
  mov    $0x1,%ebx
  jmp    L16
L27:
  cmp    %rax,0x8(%rsp)
  je     L60
  mov    %rax,%r15
L10:
  mov    %r15,%r14
  jmp    L58
L60:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int Number_of_Legal_Moves(char grid[8][8][33], char pieceTranslator[33], char king) {
  int total = 0, x, y, z;
  for (x = 0; x < 8; ++x)
    for (y = 0; y < 8; ++y)
      for (z = 1; z < 33; ++z)
        if ((sameSide(king, pieceTranslator[z])) && (grid[x][y][z] == 'L'))
          ++total;
  return total;
}
```
user: What is the c source code of the assembly code below:

```asm
<Number_of_Legal_Moves>:
  endbr64
  push   %r15
  lea    0x840(%rdi),%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movsbl %dl,%ebx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
L19:
  lea    0x108(%r13),%r14
  nopl   0x0(%rax)
L0:
  mov    $0x1,%r15d
  xchg   %ax,%ax
L17:
  movsbl 0x0(%rbp,%r15,1),%esi
  mov    %ebx,%edi
  call   <sameSide@plt>
  test   %rax,%rax
  je     L37
  xor    %eax,%eax
  cmpb   $0x4c,0x0(%r13,%r15,1)
  sete   %al
  add    %eax,%r12d
L37:
  add    $0x1,%r15
  cmp    $0x21,%r15
  jne    L17
  add    $0x21,%r13
  cmp    %r14,%r13
  jne    L0
  cmp    %r13,0x8(%rsp)
  jne    L19
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int Number_of_Legal_Moves(char grid[8][8][33], char pieceTranslator[33], char king) {
  int total = 0, x, y, z;
  for (x = 0; x < 8; ++x)
    for (y = 0; y < 8; ++y)
      for (z = 1; z < 33; ++z)
        if ((sameSide(king, pieceTranslator[z])) && (grid[x][y][z] == 'L'))
          ++total;
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Number_of_Legal_Moves>:
  endbr64
  push   %r15
  lea    0x840(%rdi),%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movsbl %dl,%ebx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
L7:
  lea    0x108(%r13),%r14
  nopl   0x0(%rax)
L6:
  mov    $0x1,%r15d
  xchg   %ax,%ax
L38:
  movsbl 0x0(%rbp,%r15,1),%esi
  mov    %ebx,%edi
  call   <sameSide@plt>
  test   %rax,%rax
  je     L17
  xor    %eax,%eax
  cmpb   $0x4c,0x0(%r13,%r15,1)
  sete   %al
  add    %eax,%r12d
L17:
  add    $0x1,%r15
  cmp    $0x21,%r15
  jne    L38
  add    $0x21,%r13
  cmp    %r14,%r13
  jne    L6
  cmp    %r13,0x8(%rsp)
  jne    L7
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int Number_of_Legal_Moves(char grid[8][8][33], char pieceTranslator[33], char king) {
  int total = 0, x, y, z;
  for (x = 0; x < 8; ++x)
    for (y = 0; y < 8; ++y)
      for (z = 1; z < 33; ++z)
        if ((sameSide(king, pieceTranslator[z])) && (grid[x][y][z] == 'L'))
          ++total;
  return total;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ceph_have_crc32c_intel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <do_cpuid@plt>
  mov    -0x10(%rbp),%eax
  and    $0x100000,%eax
  test   %eax,%eax
  je     L16
  mov    $0x1,%eax
  jmp    L29
L16:
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int ceph_have_crc32c_intel(void) {
  unsigned int eax = 1, ebx, ecx, edx;
  do_cpuid(&eax, &ebx, &ecx, &edx);
  if ((ecx & (1 << 20)) != 0)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ceph_have_crc32c_intel>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <do_cpuid@plt>
  mov    0x10(%rsp),%eax
  shr    $0x14,%eax
  and    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ceph_have_crc32c_intel(void) {
  unsigned int eax = 1, ebx, ecx, edx;
  do_cpuid(&eax, &ebx, &ecx, &edx);
  if ((ecx & (1 << 20)) != 0)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ceph_have_crc32c_intel>:
  endbr64
  sub    $0x28,%rsp
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movl   $0x1,0x8(%rsp)
  call   <do_cpuid@plt>
  mov    0x10(%rsp),%eax
  shr    $0x14,%eax
  and    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ceph_have_crc32c_intel(void) {
  unsigned int eax = 1, ebx, ecx, edx;
  do_cpuid(&eax, &ebx, &ecx, &edx);
  if ((ecx & (1 << 20)) != 0)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ceph_have_crc32c_intel>:
  endbr64
  sub    $0x28,%rsp
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movl   $0x1,0x8(%rsp)
  call   <do_cpuid@plt>
  mov    0x10(%rsp),%eax
  shr    $0x14,%eax
  and    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ceph_have_crc32c_intel(void) {
  unsigned int eax = 1, ebx, ecx, edx;
  do_cpuid(&eax, &ebx, &ecx, &edx);
  if ((ecx & (1 << 20)) != 0)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  cmpb   $0x40,-0x14(%rbp)
  jle    L9
  movsbl -0x14(%rbp),%eax
  and    $0xdf,%eax
  sub    $0x37,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L9:
  movsbl -0x14(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
L12:
  shll   $0x4,-0x4(%rbp)
  cmpb   $0x40,-0x18(%rbp)
  jle    L19
  movsbl -0x18(%rbp),%eax
  and    $0xdf,%eax
  sub    $0x37,%eax
  or     %eax,-0x4(%rbp)
  jmp    L21
L19:
  movsbl -0x18(%rbp),%eax
  sub    $0x30,%eax
  or     %eax,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char hex2int(char b1, char b2) {
  int digit;
  if (b1 >= 'A') {
    digit = (b1 & 0xDF) - 'A' + 10;
  } else {
    digit = (b1 - '0');
  }
  digit <<= 4;
  if (b2 >= 'A') {
    digit |= (b2 & 0xDF) - 'A' + 10;
  } else {
    digit |= (b2 - '0');
  }
  return digit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2int>:
  endbr64
  cmp    $0x40,%dil
  jle    L6
  and    $0xdf,%edi
  lea    -0x37(%rdi),%eax
L20:
  shl    $0x4,%eax
  cmp    $0x40,%sil
  jle    L27
  and    $0xdf,%esi
  sub    $0x37,%esi
  or     %esi,%eax
  ret
L6:
  movsbl %dil,%eax
  sub    $0x30,%eax
  jmp    L20
L27:
  movsbl %sil,%esi
  sub    $0x30,%esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned char hex2int(char b1, char b2) {
  int digit;
  if (b1 >= 'A') {
    digit = (b1 & 0xDF) - 'A' + 10;
  } else {
    digit = (b1 - '0');
  }
  digit <<= 4;
  if (b2 >= 'A') {
    digit |= (b2 & 0xDF) - 'A' + 10;
  } else {
    digit |= (b2 - '0');
  }
  return digit;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hex2int>:
  endbr64
  mov    %edi,%edx
  movsbl %dil,%eax
  and    $0xdf,%edx
  sub    $0x30,%eax
  sub    $0x37,%edx
  cmp    $0x41,%dil
  cmovge %edx,%eax
  movsbl %sil,%edx
  shl    $0x4,%eax
  cmp    $0x40,%sil
  jle    L8
  and    $0xdf,%edx
  sub    $0x37,%edx
  or     %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  sub    $0x30,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char hex2int(char b1, char b2) {
  int digit;
  if (b1 >= 'A') {
    digit = (b1 & 0xDF) - 'A' + 10;
  } else {
    digit = (b1 - '0');
  }
  digit <<= 4;
  if (b2 >= 'A') {
    digit |= (b2 & 0xDF) - 'A' + 10;
  } else {
    digit |= (b2 - '0');
  }
  return digit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2int>:
  endbr64
  mov    %edi,%edx
  movsbl %dil,%eax
  and    $0xdf,%edx
  sub    $0x30,%eax
  sub    $0x37,%edx
  cmp    $0x41,%dil
  cmovge %edx,%eax
  movsbl %sil,%edx
  shl    $0x4,%eax
  cmp    $0x40,%sil
  jle    L6
  and    $0xdf,%edx
  sub    $0x37,%edx
  or     %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  sub    $0x30,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char hex2int(char b1, char b2) {
  int digit;
  if (b1 >= 'A') {
    digit = (b1 & 0xDF) - 'A' + 10;
  } else {
    digit = (b1 - '0');
  }
  digit <<= 4;
  if (b2 >= 'A') {
    digit |= (b2 & 0xDF) - 'A' + 10;
  } else {
    digit |= (b2 - '0');
  }
  return digit;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_108_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_108_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & T;
  stk1 = S ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_108_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%esi
  xor    %edi,%esi
  mov    %esi,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_108_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & T;
  stk1 = S ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xrop3_108_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  xor    %edi,%esi
  mov    %esi,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_108_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & T;
  stk1 = S ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_108_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  xor    %edi,%esi
  mov    %esi,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_108_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & T;
  stk1 = S ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<err_sys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%ecx
  mov    -0xc8(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <err_doit@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void err_sys(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_doit(1, LOG_ERR, fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<err_sys>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    $0x1,%edi
  call   <err_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void err_sys(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_doit(1, LOG_ERR, fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<err_sys>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x1,%edi
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <err_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void err_sys(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_doit(1, LOG_ERR, fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<err_sys>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x1,%edi
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <err_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void err_sys(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_doit(1, LOG_ERR, fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<StringCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void StringCopy(char *destination, char *source, int length) {
  int i = 0;
  while (i < length) {
    destination[i] = source[i];
    i++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<StringCopy>:
  endbr64
  test   %edx,%edx
  jle    L9
  mov    %edx,%edx
  mov    $0x0,%eax
L0:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
L9:
  ret
```

assistant: ```c
void StringCopy(char *destination, char *source, int length) {
  int i = 0;
  while (i < length) {
    destination[i] = source[i];
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<StringCopy>:
  endbr64
  test   %edx,%edx
  jle    L16
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L2:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L2
L16:
  ret
```

assistant: ```c
void StringCopy(char *destination, char *source, int length) {
  int i = 0;
  while (i < length) {
    destination[i] = source[i];
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<StringCopy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L91
  lea    0x1(%rsi),%r9
  mov    %edx,%r8d
  lea    -0x1(%rdx),%eax
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L106
  cmp    $0x6,%eax
  jbe    L106
  cmp    $0xe,%eax
  jbe    L107
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L5:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L5
  mov    %edx,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L91
  mov    %edx,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L129
L116:
  mov    (%rsi,%rdi,1),%r9
  mov    %r9,(%rcx,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%r8d
  je     L91
L129:
  movslq %eax,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L91
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jle    L91
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jle    L91
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jle    L91
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jle    L91
  movslq %edi,%rdi
  add    $0x6,%eax
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L91
  cltq
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  ret
  nopw   0x0(%rax,%rax,1)
L106:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L13:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L13
L91:
  ret
L107:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L116
```

assistant: ```c
void StringCopy(char *destination, char *source, int length) {
  int i = 0;
  while (i < length) {
    destination[i] = source[i];
    i++;
  }
}
```