user: 这段汇编代码用C语言表示是什么样的?

```asm
<wrap>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbp
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %rcx,0x28(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(,%rsi,8),%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  lea    -0x8(%rbx),%r13
  mov    %r13,0x20(%rsp)
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rbp,%rbp
  jle    L0
  lea    0x0(,%rbp,4),%r12
  mov    %rax,%rbx
  lea    0x0(%r13,%rax,1),%rbp
L36:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L36
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  js     L51
L109:
  movslq 0x14(%rsp),%rax
  lea    0x0(,%rax,4),%r13
  lea    0x1(%rax),%r12
  jmp    L16
L0:
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  jns    L109
L259:
  cmpq   $0x0,0x8(%rsp)
  js     L152
L51:
  mov    $0x0,%ebx
  mov    0x18(%rsp),%rbp
  mov    0x8(%rsp),%r12
L129:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  movl   $0xffffffff,(%rax)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jge    L129
L152:
  mov    0x18(%rsp),%rax
  mov    (%rax),%rax
  movl   $0x0,(%rax)
  mov    0x8(%rsp),%r12
  mov    %r12d,%edi
  cmp    $0x1,%r12d
  jle    L2
  mov    $0x0,%ebp
  lea    0x34(%rsp),%rbx
  mov    %ebp,(%rsp)
  mov    0x10(%rsp),%ebp
  mov    0x28(%rsp),%r13
  jmp    L134
L79:
  mov    (%r14,%rbx,1),%rax
  movl   $0xffffffff,(%rax,%r13,1)
L23:
  sub    $0x4,%r13
  sub    $0x1,%r12
  subl   $0x1,0x14(%rsp)
  js     L259
L16:
  cmpl   $0x0,0x14(%rsp)
  js     L23
  lea    0x0(%r13,%r13,1),%rbx
  lea    -0x1(%r12),%rax
  mov    0x14(%rsp),%edx
  sub    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,(%rsp)
  mov    $0x0,%ebp
  jmp    L224
L85:
  mov    (%r14,%rbx,1),%rax
  movl   $0x0,(%rax,%r13,1)
L52:
  lea    -0x8(%rbx),%rax
  cmp    %rbx,(%rsp)
  je     L23
  mov    %rax,%rbx
L224:
  mov    (%r15,%rbx,1),%rdi
  call   <strlen@plt>
  add    %ebp,%eax
  lea    0x1(%rax),%ebp
  cmp    0x10(%rsp),%eax
  jg     L79
  cmp    %r12,0x8(%rsp)
  je     L85
  mov    (%r14,%rbx,1),%rdx
  mov    %eax,(%rdx,%r13,1)
  jmp    L52
L88:
  sub    $0x8,%rsp
  push   %r14
  mov    0x28(%rsp),%r9
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    $0x0,%eax
  call   <f@plt>
  mov    %eax,0x10(%rsp)
  add    $0x10,%rsp
L104:
  mov    0x34(%rsp),%eax
  lea    -0x1(%rax),%edi
  movslq %edi,%rax
  movb   $0x1,0x0(%r13,%rax,1)
  cmp    $0x1,%edi
  jle    L194
L134:
  movslq %edi,%rax
  cmp    %r12,%rax
  je     L88
  sub    $0x8,%rsp
  push   %r14
  mov    0x28(%rsp),%r9
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    $0x0,%eax
  call   <f@plt>
  add    $0x10,%rsp
  jmp    L104
L194:
  mov    (%rsp),%ebp
L69:
  cmpq   $0x0,0x8(%rsp)
  jle    L170
  mov    %r14,%rbx
  mov    0x20(%rsp),%r12
  add    %r14,%r12
L106:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbx,%r12
  jne    L106
  mov    %r14,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  mov    0x18(%rsp),%r12
  mov    0x8(%rsp),%r13
L75:
  mov    (%r12,%rbx,8),%rdi
  call   <free@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jge    L75
L193:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    %ebp,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  mov    $0x0,%ebp
  jmp    L69
L170:
  mov    %r14,%rdi
  call   <free@plt>
  cmpq   $0x0,0x8(%rsp)
  jne    L193
  mov    0x18(%rsp),%rax
  mov    (%rax),%rdi
  call   <free@plt>
  jmp    L193
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wrap(char **words, long words_no, int w, char *allages) {
  int i, j, wij, x, k, cmin, temp_min_i, min;
  int cost = 0, min_i;
  int **costs = malloc((words_no + 1) * sizeof(int *));
  int **line_costs = malloc(words_no * sizeof(int *));
  for (i = 0; i < words_no; i++)
    line_costs[i] = malloc(words_no * sizeof(int));
  for (i = words_no - 1; i >= 0; i--) {
    wij = 0;
    for (j = i; j >= 0; j--) {
      wij = wij + strlen(words[j]) + 1;
      if (wij - 1 > w) {
        line_costs[j][i] = -1;
        break;
      } else if (i + 1 == words_no)
        line_costs[j][i] = 0;
      else
        line_costs[j][i] = wij - 1;
    }
  }
  for (i = 0; i < words_no + 1; i++) {
    costs[i] = malloc(2 * sizeof(int));
    costs[i][0] = -1;
  }
  costs[0][0] = 0;
  i = words_no;
  while (i > 1) {
    if (i == words_no)
      cost = f(i, words, words_no, w, &min_i, costs, line_costs);
    else {
      f(i, words, words_no, w, &min_i, costs, line_costs);
    }
    i = min_i - 1;
    allages[i] = 1;
  }
  for (i = 0; i < words_no; i++)
    free(line_costs[i]);
  free(line_costs);
  for (i = 0; i <= words_no; i++)
    free(costs[i]);
  free(costs);
  return cost;
}
```