ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D67(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x21,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  cmp    $0x4,%eax
  ja     L43
  lea    D14(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D53(%rip),%rdi
  call   <printf@plt>
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D67
data_type: string
name: disassemble_data
arguments: tag: D39
data_type: string
name: disassemble_data
arguments: tag: D53
data_type: string
name: disassemble_data
arguments: tag: D25
data_type: string
name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string

tool: D67:  Think of your question and enter your favorite number?

tool: D39: %d

tool: D53: definitely not


tool: D25: ask again


tool: D11: outcome unclear


tool: D6: absolutely certain


tool: D16: the answer is no


assistant: ```c
int main() {
  int magic = 0;
  int choise;
  int favNum;
  int numChoise;
  printf(" Think of your question and enter your favorite number?");
  scanf("%d", &favNum);
  srand(time(NULL));
  choise = rand() % 5;
  switch (choise) {
  case 0:
    printf("outcome unclear\n");
    break;
  case 1:
    printf("absolutely certain\n");
    break;
  case 2:
    printf("the answer is no\n");
    break;
  case 3:
    printf("ask again\n");
    break;
  case 4:
    printf("definitely not\n");
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D59(%rip),%rdi
  call   <scanf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x21,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  cmp    $0x4,%eax
  ja     L56
  lea    D5(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D62(%rip),%rdi
  call   <printf@plt>
L56:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D78(%rip),%rdi
  call   <printf@plt>
  jmp    L56
  lea    D79(%rip),%rdi
  call   <printf@plt>
  jmp    L56
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L56
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L56
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D59
type: string
name: parse_data
arguments: tag: D62
type: string
name: parse_data
arguments: tag: D78
type: string
name: parse_data
arguments: tag: D79
type: string
name: parse_data
arguments: tag: D41
type: string
name: parse_data
arguments: tag: D18
type: string

tool: D16:  Think of your question and enter your favorite number?

tool: D59: %d

tool: D62: definitely not


tool: D78: ask again


tool: D79: outcome unclear


tool: D41: absolutely certain


tool: D18: the answer is no


assistant: ```c
int main() {
  int magic = 0;
  int choise;
  int favNum;
  int numChoise;
  printf(" Think of your question and enter your favorite number?");
  scanf("%d", &favNum);
  srand(time(NULL));
  choise = rand() % 5;
  switch (choise) {
  case 0:
    printf("outcome unclear\n");
    break;
  case 1:
    printf("absolutely certain\n");
    break;
  case 2:
    printf("the answer is no\n");
    break;
  case 3:
    printf("ask again\n");
    break;
  case 4:
    printf("definitely not\n");
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L51:
  cmpl   $0x0,-0x14(%rbp)
  jle    L47
  subl   $0x1,-0x14(%rbp)
  jmp    L34
L47:
  cmpl   $0x0,-0x18(%rbp)
  jle    L34
  subl   $0x1,-0x18(%rbp)
L34:
  addl   $0x1,-0x4(%rbp)
L36:
  cmpl   $0x0,-0x14(%rbp)
  jg     L51
  cmpl   $0x0,-0x18(%rbp)
  jg     L51
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  int c = 0;
  while ((x > 0) || (y > 0)) {
    if (x > 0) {
      x = x - 1;
    } else {
      if (y > 0) {
        y = y - 1;
      } else {
      }
    }
    c = c + 1;
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_fun>:
  endbr64
  test   %edi,%edi
  jg     L17
  test   %esi,%esi
  jle    L39
L17:
  mov    $0x0,%eax
L69:
  test   %edi,%edi
  jle    L22
  sub    $0x1,%edi
L29:
  add    $0x1,%eax
  test   %edi,%edi
  jg     L69
  test   %esi,%esi
  jg     L69
  ret
L22:
  test   %esi,%esi
  jle    L65
  sub    $0x1,%esi
  jmp    L29
L39:
  mov    $0x0,%eax
  ret
L65:
  add    $0x1,%eax
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  int c = 0;
  while ((x > 0) || (y > 0)) {
    if (x > 0) {
      x = x - 1;
    } else {
      if (y > 0) {
        y = y - 1;
      } else {
      }
    }
    c = c + 1;
  }
  return c;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_fun>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jg     L55
  test   %edi,%edi
  jg     L55
  ret
  nop
L8:
  test   %esi,%esi
  jle    L58
L55:
  test   %edi,%edi
  jg     L41
  test   %esi,%esi
  jle    L46
  sub    $0x1,%esi
L37:
  add    $0x1,%eax
  test   %edi,%edi
  jle    L8
L41:
  sub    $0x1,%edi
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L46:
  add    $0x1,%eax
  ret
L58:
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  int c = 0;
  while ((x > 0) || (y > 0)) {
    if (x > 0) {
      x = x - 1;
    } else {
      if (y > 0) {
        y = y - 1;
      } else {
      }
    }
    c = c + 1;
  }
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_fun>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jg     L86
  test   %edi,%edi
  jle    L44
  xchg   %ax,%ax
L86:
  test   %edi,%edi
  jg     L73
  test   %esi,%esi
  jle    L61
  sub    $0x1,%esi
  add    $0x1,%eax
  test   %esi,%esi
  jg     L22
  jmp    L5
  nopl   0x0(%rax)
L58:
  sub    $0x1,%esi
  add    $0x1,%eax
  test   %esi,%esi
  jle    L15
L22:
  test   %esi,%esi
  jne    L58
L61:
  add    $0x1,%eax
L5:
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  sub    $0x1,%edi
  add    $0x1,%eax
  test   %esi,%esi
  jg     L86
  test   %edi,%edi
  jg     L73
  ret
  nop
L44:
  ret
L15:
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  int c = 0;
  while ((x > 0) || (y > 0)) {
    if (x > 0) {
      x = x - 1;
    } else {
      if (y > 0) {
        y = y - 1;
      } else {
      }
    }
    c = c + 1;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<uninitvar_wcstol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstol@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstoll@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstoul@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstoull@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_wcstol(void) {
  const wchar_t *s;
  wchar_t **endp;
  int base;
  (void)wcstol(s, endp, base);
  (void)wcstoll(s, endp, base);
  (void)wcstoul(s, endp, base);
  (void)wcstoull(s, endp, base);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uninitvar_wcstol>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r12d
  mov    %r12d,%edx
  mov    $0x0,%ebp
  mov    %rbp,%rsi
  mov    $0x0,%ebx
  mov    %rbx,%rdi
  call   <wcstol@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <wcstoll@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <wcstoul@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <wcstoull@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void uninitvar_wcstol(void) {
  const wchar_t *s;
  wchar_t **endp;
  int base;
  (void)wcstol(s, endp, base);
  (void)wcstoll(s, endp, base);
  (void)wcstoul(s, endp, base);
  (void)wcstoull(s, endp, base);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uninitvar_wcstol>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  mov    %r13d,%edx
  push   %rbp
  xor    %ebp,%ebp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wcstol@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wcstoll@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wcstoul@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <wcstoull@plt>
```

assistant: ```c
void uninitvar_wcstol(void) {
  const wchar_t *s;
  wchar_t **endp;
  int base;
  (void)wcstol(s, endp, base);
  (void)wcstoll(s, endp, base);
  (void)wcstoul(s, endp, base);
  (void)wcstoull(s, endp, base);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uninitvar_wcstol>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  mov    %r13d,%edx
  push   %rbp
  xor    %ebp,%ebp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wcstol@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wcstoll@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wcstoul@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <wcstoull@plt>
```

assistant: ```c
void uninitvar_wcstol(void) {
  const wchar_t *s;
  wchar_t **endp;
  int base;
  (void)wcstol(s, endp, base);
  (void)wcstoll(s, endp, base);
  (void)wcstoul(s, endp, base);
  (void)wcstoull(s, endp, base);
}
```
user: What is the c source code of the assembly code below:

```asm
<mergeSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L87:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L87
  sub    $0xaa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L62
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%r12d
  shr    $0x1f,%r12d
  add    %esi,%r12d
  sar    %r12d
  movslq %r12d,%rax
  shl    $0x2,%rax
  lea    0x10(%rsp),%r15
  mov    %rax,0x8(%rsp)
  lea    (%r15,%rax,1),%r13
  mov    %esi,%r14d
  sub    %r12d,%r14d
  lea    0x0(,%r12,4),%edx
  mov    %rdi,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  lea    0x0(,%r14,4),%edx
  mov    0x8(%rsp),%rax
  lea    (%rbx,%rax,1),%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <mergeSort>
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mergeSort>
  mov    $0x1,%eax
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L13
L90:
  add    $0x1,%edx
  mov    %eax,%esi
  mov    %edi,(%rbx)
  jmp    L49
L107:
  mov    %eax,%esi
  movslq %ecx,%rdi
  mov    0x10(%rsp,%rdi,4),%edi
  mov    %edi,(%rbx)
  lea    0x1(%rcx),%ecx
  jmp    L49
L64:
  mov    %eax,%esi
  movslq %edx,%rdi
  mov    0x0(%r13,%rdi,4),%edi
  mov    %edi,(%rbx)
  lea    0x1(%rdx),%edx
L49:
  add    $0x1,%eax
  add    $0x4,%rbx
  cmp    %esi,%ebp
  jle    L62
L13:
  cmp    %ecx,%r12d
  jle    L64
  cmp    %edx,%r14d
  jle    L107
  movslq %ecx,%rsi
  mov    0x10(%rsp,%rsi,4),%r8d
  movslq %edx,%rsi
  mov    0x0(%r13,%rsi,4),%edi
  cmp    %edi,%r8d
  jge    L90
  add    $0x1,%ecx
  mov    %eax,%esi
  mov    %r8d,(%rbx)
  jmp    L49
L62:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x61aa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mergeSort(int arr[], int n) {
  int tmp[100000];
  int *firstHalf = tmp;
  int *secondHalf = tmp + n / 2;
  int firstHalfSize = n / 2;
  int secondHalfSize = (n - n / 2);
  int i, p, q;
  if (n < 2)
    return;
  memcpy(firstHalf, arr, n / 2 * sizeof(int));
  memcpy(secondHalf, arr + n / 2, (n - n / 2) * sizeof(int));
  mergeSort(firstHalf, n / 2);
  mergeSort(secondHalf, n - n / 2);
  i = 0;
  p = 0;
  q = 0;
  while (i < n) {
    if (p < firstHalfSize) {
      if (q < secondHalfSize) {
        if (firstHalf[p] < secondHalf[q]) {
          arr[i++] = firstHalf[p++];
        } else {
          arr[i++] = secondHalf[q++];
        }
      } else {
        arr[i++] = firstHalf[p++];
      }
    } else {
      arr[i++] = secondHalf[q++];
    }
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<mergeSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L84:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L84
  sub    $0xaa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L51
  mov    %esi,%ebp
  lea    0x10(%rsp),%r8
  mov    %esi,%r14d
  mov    %rdi,%rbx
  sar    %ebp
  mov    %esi,%r12d
  mov    %rdi,%rsi
  mov    %r8,%rdi
  movslq %ebp,%r15
  sub    %ebp,%r14d
  mov    %r8,0x8(%rsp)
  lea    0x0(,%rbp,4),%edx
  shl    $0x2,%r15
  lea    (%r8,%r15,1),%r13
  call   <memcpy@plt>
  lea    0x0(,%r14,4),%edx
  lea    (%rbx,%r15,1),%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  mov    %ebp,%esi
  call   <mergeSort>
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mergeSort>
  lea    -0x1(%r12),%edx
  mov    %rbx,%rax
  xor    %esi,%esi
  lea    0x4(%rbx,%rdx,4),%rdi
  xor    %edx,%edx
  jmp    L99
  nop
L85:
  movslq %esi,%rcx
  mov    0x10(%rsp,%rcx,4),%ecx
  cmp    %edx,%r14d
  jle    L91
  movslq %edx,%r8
  mov    0x0(%r13,%r8,4),%r8d
  cmp    %ecx,%r8d
  jg     L91
  add    $0x1,%edx
  mov    %r8d,%ecx
L40:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L51
L99:
  cmp    %esi,%ebp
  jg     L85
  movslq %edx,%rcx
  add    $0x4,%rax
  add    $0x1,%edx
  mov    0x0(%r13,%rcx,4),%ecx
  mov    %ecx,-0x4(%rax)
  cmp    %rdi,%rax
  jne    L99
L51:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x61aa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L91:
  add    $0x1,%esi
  jmp    L40
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mergeSort(int arr[], int n) {
  int tmp[100000];
  int *firstHalf = tmp;
  int *secondHalf = tmp + n / 2;
  int firstHalfSize = n / 2;
  int secondHalfSize = (n - n / 2);
  int i, p, q;
  if (n < 2)
    return;
  memcpy(firstHalf, arr, n / 2 * sizeof(int));
  memcpy(secondHalf, arr + n / 2, (n - n / 2) * sizeof(int));
  mergeSort(firstHalf, n / 2);
  mergeSort(secondHalf, n - n / 2);
  i = 0;
  p = 0;
  q = 0;
  while (i < n) {
    if (p < firstHalfSize) {
      if (q < secondHalfSize) {
        if (firstHalf[p] < secondHalf[q]) {
          arr[i++] = firstHalf[p++];
        } else {
          arr[i++] = secondHalf[q++];
        }
      } else {
        arr[i++] = firstHalf[p++];
      }
    } else {
      arr[i++] = secondHalf[q++];
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mergeSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L2:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L2
  sub    $0xaa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L17
  mov    %esi,%r12d
  lea    0x10(%rsp),%r8
  mov    %esi,%r14d
  mov    %esi,%ebp
  sar    %r12d
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  mov    %r8,%rdi
  movslq %r12d,%r15
  sub    %r12d,%r14d
  mov    %r8,0x8(%rsp)
  lea    0x0(,%r12,4),%edx
  shl    $0x2,%r15
  lea    (%r8,%r15,1),%r13
  call   <memcpy@plt>
  lea    0x0(,%r14,4),%edx
  lea    (%rbx,%r15,1),%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12d,%esi
  call   <mergeSort>
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mergeSort>
  mov    $0x1,%eax
  xor    %ecx,%ecx
  lea    -0x1(%rbp),%edi
  mov    %ebp,%r8d
  xor    %edx,%edx
  mov    %eax,%esi
  cmp    %ecx,%r12d
  jle    L81
  nopl   (%rax)
L82:
  movslq %ecx,%rsi
  mov    0x10(%rsp,%rsi,4),%esi
  cmp    %edx,%r14d
  jle    L12
  movslq %edx,%r9
  mov    0x0(%r13,%r9,4),%r9d
  cmp    %esi,%r9d
  jg     L12
  add    $0x1,%edx
  mov    %r9d,%esi
L43:
  mov    %esi,-0x4(%rbx,%rax,4)
  cmp    %rax,%r8
  je     L17
  add    $0x1,%rax
  mov    %eax,%esi
  cmp    %ecx,%r12d
  jg     L82
L81:
  lea    0x1(%rdx),%ecx
  movslq %edx,%rdx
  mov    0x0(%r13,%rdx,4),%edx
  mov    %edx,-0x4(%rbx,%rax,4)
  cmp    %rax,%r8
  je     L17
  cltq
  movslq %ecx,%rcx
  lea    (%rbx,%rax,4),%r8
  mov    %edi,%eax
  sub    %esi,%eax
  cmp    %esi,%ebp
  lea    0x0(%r13,%rcx,4),%rsi
  mov    %r8,%rdi
  lea    0x4(,%rax,4),%rdx
  mov    $0x4,%eax
  cmovle %rax,%rdx
  call   <memcpy@plt>
L17:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x61aa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L12:
  add    $0x1,%ecx
  jmp    L43
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mergeSort(int arr[], int n) {
  int tmp[100000];
  int *firstHalf = tmp;
  int *secondHalf = tmp + n / 2;
  int firstHalfSize = n / 2;
  int secondHalfSize = (n - n / 2);
  int i, p, q;
  if (n < 2)
    return;
  memcpy(firstHalf, arr, n / 2 * sizeof(int));
  memcpy(secondHalf, arr + n / 2, (n - n / 2) * sizeof(int));
  mergeSort(firstHalf, n / 2);
  mergeSort(secondHalf, n - n / 2);
  i = 0;
  p = 0;
  q = 0;
  while (i < n) {
    if (p < firstHalfSize) {
      if (q < secondHalfSize) {
        if (firstHalf[p] < secondHalf[q]) {
          arr[i++] = firstHalf[p++];
        } else {
          arr[i++] = secondHalf[q++];
        }
      } else {
        arr[i++] = firstHalf[p++];
      }
    } else {
      arr[i++] = secondHalf[q++];
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copy4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy4(unsigned char *out, unsigned x) {
  out[0] = (unsigned char)(x & 0xFF);
  out[1] = (unsigned char)((x >> 8) & 0xFF);
  out[2] = (unsigned char)((x >> 16) & 0xFF);
  out[3] = (unsigned char)((x >> 24) & 0xFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy4>:
  endbr64
  mov    %esi,%eax
  mov    %sil,(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdi)
  mov    %esi,%edx
  shr    $0x10,%edx
  mov    %dl,0x2(%rdi)
  shr    $0x18,%eax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void copy4(unsigned char *out, unsigned x) {
  out[0] = (unsigned char)(x & 0xFF);
  out[1] = (unsigned char)((x >> 8) & 0xFF);
  out[2] = (unsigned char)((x >> 16) & 0xFF);
  out[3] = (unsigned char)((x >> 24) & 0xFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy4>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void copy4(unsigned char *out, unsigned x) {
  out[0] = (unsigned char)(x & 0xFF);
  out[1] = (unsigned char)((x >> 8) & 0xFF);
  out[2] = (unsigned char)((x >> 16) & 0xFF);
  out[3] = (unsigned char)((x >> 24) & 0xFF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copy4>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void copy4(unsigned char *out, unsigned x) {
  out[0] = (unsigned char)(x & 0xFF);
  out[1] = (unsigned char)((x >> 8) & 0xFF);
  out[2] = (unsigned char)((x >> 16) & 0xFF);
  out[3] = (unsigned char)((x >> 24) & 0xFF);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<MemManage_Handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L6:
  jmp    L6
```

assistant: ```c
void MemManage_Handler() {
  for (;;)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<MemManage_Handler>:
  endbr64
L2:
  jmp    L2
```

assistant: ```c
void MemManage_Handler() {
  for (;;)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<MemManage_Handler>:
  endbr64
  nopl   0x0(%rax)
L2:
  jmp    L2
```

assistant: ```c
void MemManage_Handler() {
  for (;;)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<MemManage_Handler>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
void MemManage_Handler() {
  for (;;)
    ;
}
```