ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<hm_pool_strlendup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  lea    0x1(%rdx),%rsi
  call   <hm_pool_malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *hm_pool_strlendup(struct hm_pool *po, const char *str, size_t len) {
  char *ret = (char *)hm_pool_malloc(po, len + 1);
  memcpy(ret, str, len);
  ret[len] = '\0';
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hm_pool_strlendup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  lea    0x1(%rdx),%rsi
  push   %rbx
  mov    %rdx,%rbx
  call   <hm_pool_malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *hm_pool_strlendup(struct hm_pool *po, const char *str, size_t len) {
  char *ret = (char *)hm_pool_malloc(po, len + 1);
  memcpy(ret, str, len);
  ret[len] = '\0';
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hm_pool_strlendup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  lea    0x1(%rdx),%rsi
  push   %rbx
  mov    %rdx,%rbx
  call   <hm_pool_malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *hm_pool_strlendup(struct hm_pool *po, const char *str, size_t len) {
  char *ret = (char *)hm_pool_malloc(po, len + 1);
  memcpy(ret, str, len);
  ret[len] = '\0';
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_to_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x14,-0x20(%rbp)
  jbe    L109
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  jmp    L36
L109:
  movl   $0x0,-0x8(%rbp)
  jmp    L105
L95:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L10
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L20
L10:
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  jmp    L36
L20:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L53
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L79
L53:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L5
L79:
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  jmp    L36
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L105:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L95
  mov    -0x8(%rbp),%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
uint64_t str_to_uint64(char *str, size_t n, int *err) {
  uint64_t value;
  if (n > 20) {
    *err = 1;
    return 0;
  }
  for (value = 0; n--; str++) {
    uint64_t check;
    if (*str < '0' || *str > '9') {
      *err = 1;
      return 0;
    }
    check = value * 10 + (*str - '0');
    if ((value && check <= value) || check > UINT64_MAX) {
      *err = 1;
      return 0;
    }
    value = check;
  }
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_to_uint64>:
  endbr64
  cmp    $0x14,%rsi
  ja     L34
  test   %rsi,%rsi
  je     L54
  mov    D0(%rip),%rax
  mov    (%rax),%r9d
  add    %rdi,%rsi
  mov    $0x0,%ecx
  jmp    L72
L54:
  mov    $0x0,%eax
  ret
L34:
  movl   $0x1,(%rdx)
  mov    $0x0,%eax
  ret
L44:
  movl   $0x1,(%rdx)
  mov    $0x0,%eax
  ret
L68:
  cmp    %eax,%r9d
  jl     L59
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  je     L69
  mov    %eax,%ecx
L72:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  ja     L44
  lea    (%rcx,%rcx,4),%r8d
  movsbl %al,%eax
  lea    -0x30(%rax,%r8,2),%eax
  test   %ecx,%ecx
  je     L68
  cmp    %ecx,%eax
  jg     L68
L59:
  movl   $0x1,(%rdx)
  mov    $0x0,%eax
  ret
L69:
  ret
```

assistant: ```c
uint64_t str_to_uint64(char *str, size_t n, int *err) {
  uint64_t value;
  if (n > 20) {
    *err = 1;
    return 0;
  }
  for (value = 0; n--; str++) {
    uint64_t check;
    if (*str < '0' || *str > '9') {
      *err = 1;
      return 0;
    }
    check = value * 10 + (*str - '0');
    if ((value && check <= value) || check > UINT64_MAX) {
      *err = 1;
      return 0;
    }
    value = check;
  }
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_to_uint64>:
  endbr64
  cmp    $0x14,%rsi
  ja     L77
  test   %rsi,%rsi
  je     L46
  mov    D9(%rip),%rax
  add    %rdi,%rsi
  xor    %ecx,%ecx
  mov    (%rax),%r9d
  jmp    L1
L30:
  lea    (%rcx,%rcx,4),%r8d
  movsbl %al,%eax
  lea    (%rax,%r8,2),%eax
  test   %ecx,%ecx
  je     L31
  cmp    %ecx,%eax
  jle    L77
L31:
  cmp    %eax,%r9d
  jl     L77
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  je     L63
  mov    %eax,%ecx
L1:
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L30
L77:
  movl   $0x1,(%rdx)
L46:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L63:
  ret
```

assistant: ```c
uint64_t str_to_uint64(char *str, size_t n, int *err) {
  uint64_t value;
  if (n > 20) {
    *err = 1;
    return 0;
  }
  for (value = 0; n--; str++) {
    uint64_t check;
    if (*str < '0' || *str > '9') {
      *err = 1;
      return 0;
    }
    check = value * 10 + (*str - '0');
    if ((value && check <= value) || check > UINT64_MAX) {
      *err = 1;
      return 0;
    }
    value = check;
  }
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_to_uint64>:
  endbr64
  cmp    $0x14,%rsi
  ja     L43
  test   %rsi,%rsi
  je     L4
  mov    D3(%rip),%rax
  add    %rdi,%rsi
  xor    %ecx,%ecx
  mov    (%rax),%r9d
  jmp    L60
L78:
  lea    (%rcx,%rcx,4),%r8d
  movsbl %al,%eax
  lea    (%rax,%r8,2),%eax
  test   %ecx,%ecx
  je     L48
  cmp    %ecx,%eax
  jle    L43
L48:
  cmp    %eax,%r9d
  jl     L43
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L1
  mov    %eax,%ecx
L60:
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L78
L43:
  movl   $0x1,(%rdx)
L4:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
uint64_t str_to_uint64(char *str, size_t n, int *err) {
  uint64_t value;
  if (n > 20) {
    *err = 1;
    return 0;
  }
  for (value = 0; n--; str++) {
    uint64_t check;
    if (*str < '0' || *str > '9') {
      *err = 1;
      return 0;
    }
    check = value * 10 + (*str - '0');
    if ((value && check <= value) || check > UINT64_MAX) {
      *err = 1;
      return 0;
    }
    value = check;
  }
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x100(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x118(%rbp)
  movq   $0x0,-0x108(%rbp)
  lea    -0x100(%rbp),%rax
  mov    $0x1e,%esi
  mov    %rax,%rdi
  call   <backtrace@plt>
  mov    %rax,-0x110(%rbp)
  mov    -0x110(%rbp),%rdx
  lea    -0x100(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <backtrace_symbols@plt>
  mov    %rax,-0x108(%rbp)
  cmpq   $0x0,-0x108(%rbp)
  je     L0
  movq   $0x0,-0x118(%rbp)
  jmp    L20
L3:
  mov    -0x118(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x108(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x118(%rbp)
L20:
  mov    -0x118(%rbp),%rax
  cmp    -0x110(%rbp),%rax
  jb     L3
  mov    -0x108(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L21
L0:
  nop
L21:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: %s


assistant: ```c
void dump(int signo) {
  void *buffer[30] = {0};
  size_t size = 0;
  size_t i = 0;
  char **strings = NULL;
  size = backtrace(buffer, 30);
  strings = backtrace_symbols(buffer, size);
  if (strings == NULL) {
    return;
  }
  for (i = 0; i < size; i++) {
    printf("%s\n", strings[i]);
  }
  free(strings);
}
```
user: What is the c source code of the assembly code below:

```asm
<dump>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1e,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbx
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <backtrace@plt>
  mov    %rax,%r12
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <backtrace_symbols@plt>
  test   %rax,%rax
  je     L29
  mov    %rax,%rbp
  test   %r12,%r12
  je     L5
  mov    $0x0,%ebx
  lea    D8(%rip),%r13
L36:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L36
L5:
  mov    %rbp,%rdi
  call   <free@plt>
L29:
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x108,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: %s


assistant: ```c
void dump(int signo) {
  void *buffer[30] = {0};
  size_t size = 0;
  size_t i = 0;
  char **strings = NULL;
  size = backtrace(buffer, 30);
  strings = backtrace_symbols(buffer, size);
  if (strings == NULL) {
    return;
  }
  for (i = 0; i < size; i++) {
    printf("%s\n", strings[i]);
  }
  free(strings);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dump>:
  endbr64
  push   %r13
  mov    $0x1e,%ecx
  mov    $0x1e,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <backtrace@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <backtrace_symbols@plt>
  test   %rax,%rax
  je     L37
  mov    %rax,%rbp
  test   %r12,%r12
  je     L4
  xor    %ebx,%ebx
  lea    D7(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L36:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L36
L4:
  mov    %rbp,%rdi
  call   <free@plt>
L37:
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x108,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %s


assistant: ```c
void dump(int signo) {
  void *buffer[30] = {0};
  size_t size = 0;
  size_t i = 0;
  char **strings = NULL;
  size = backtrace(buffer, 30);
  strings = backtrace_symbols(buffer, size);
  if (strings == NULL) {
    return;
  }
  for (i = 0; i < size; i++) {
    printf("%s\n", strings[i]);
  }
  free(strings);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dump>:
  endbr64
  push   %r13
  mov    $0x1e,%ecx
  mov    $0x1e,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <backtrace@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <backtrace_symbols@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%rbp
  test   %r12,%r12
  je     L3
  xor    %ebx,%ebx
  lea    D5(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L15
L3:
  mov    %rbp,%rdi
  call   <free@plt>
L22:
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x108,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: %s


assistant: ```c
void dump(int signo) {
  void *buffer[30] = {0};
  size_t size = 0;
  size_t i = 0;
  char **strings = NULL;
  size = backtrace(buffer, 30);
  strings = backtrace_symbols(buffer, size);
  if (strings == NULL) {
    return;
  }
  for (i = 0; i < size; i++) {
    printf("%s\n", strings[i]);
  }
  free(strings);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_taskloop_normal@plt>
  test   %rax,%rax
  jne    L17
  mov    $0x0,%eax
  call   <test_taskloop_simd_normal@plt>
  test   %rax,%rax
  je     L19
L17:
  movl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int err = 0;
#pragma omp parallel reduction(| : err)
#pragma omp single
  {
    if (test_taskloop_normal() || test_taskloop_simd_normal())
      err = 1;
  }
  if (err)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_taskloop_normal@plt>
  test   %rax,%rax
  jne    L7
  call   <test_taskloop_simd_normal@plt>
  test   %rax,%rax
  je     L4
L7:
  mov    $0x0,%eax
  call   <abort@plt>
L4:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int err = 0;
#pragma omp parallel reduction(| : err)
#pragma omp single
  {
    if (test_taskloop_normal() || test_taskloop_simd_normal())
      err = 1;
  }
  if (err)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_taskloop_normal@plt>
  test   %rax,%rax
  jne    L7
  xor    %eax,%eax
  call   <test_taskloop_simd_normal@plt>
  test   %rax,%rax
  je     L19
L7:
  xor    %eax,%eax
  call   <abort@plt>
L19:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int err = 0;
#pragma omp parallel reduction(| : err)
#pragma omp single
  {
    if (test_taskloop_normal() || test_taskloop_simd_normal())
      err = 1;
  }
  if (err)
    abort();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_taskloop_normal@plt>
  test   %rax,%rax
  jne    L18
  xor    %eax,%eax
  call   <test_taskloop_simd_normal@plt>
  test   %rax,%rax
  je     L1
L18:
  xor    %eax,%eax
  call   <abort@plt>
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int err = 0;
#pragma omp parallel reduction(| : err)
#pragma omp single
  {
    if (test_taskloop_normal() || test_taskloop_simd_normal())
      err = 1;
  }
  if (err)
    abort();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f72702073696854,%rax
  movabs $0x207369206d617267,%rdx
  mov    %rax,-0x90(%rbp)
  mov    %rdx,-0x88(%rbp)
  movl   $0x6e697270,-0x80(%rbp)
  movw   $0x74,-0x7c(%rbp)
  lea    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <myAcronmy@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: D2: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  char dst[100];
  char src[] = "This program is print";
  myAcronmy(dst, src);
  printf("%s\n", dst);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movabs $0x6f72702073696854,%rax
  movabs $0x207369206d617267,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x6e697270,0x10(%rsp)
  movw   $0x74,0x14(%rsp)
  mov    %rsp,%rsi
  lea    0x20(%rsp),%rbx
  mov    %rbx,%rdi
  call   <myAcronmy@plt>
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  char dst[100];
  char src[] = "This program is print";
  myAcronmy(dst, src);
  printf("%s\n", dst);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x90,%rsp
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    $0x74,%eax
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  movl   $0x6e697270,0x10(%rsp)
  mov    %ax,0x14(%rsp)
  movaps %xmm0,(%rsp)
  call   <myAcronmy@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
type: byte[16]
name: parse_data
arguments: tag: D16
type: string

tool: {"D13": [0x54,0x68,0x69,0x73,0x20,0x70,0x72,0x6f,0x67,0x72,0x61,0x6d,0x20,0x69,0x73,0x20]}

tool: D16: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  char dst[100];
  char src[] = "This program is print";
  myAcronmy(dst, src);
  printf("%s\n", dst);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x90,%rsp
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    $0x74,%eax
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  movl   $0x6e697270,0x10(%rsp)
  mov    %ax,0x14(%rsp)
  movaps %xmm0,(%rsp)
  call   <myAcronmy@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type: byte[16]
name: disassemble_data
arguments: data_tag: D6
type: string

tool: {"D18": [0x54,0x68,0x69,0x73,0x20,0x70,0x72,0x6f,0x67,0x72,0x61,0x6d,0x20,0x69,0x73,0x20]}

tool: D6: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  char dst[100];
  char src[] = "This program is print";
  myAcronmy(dst, src);
  printf("%s\n", dst);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6968666564636261,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x6a,-0xa(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  lea    -0x12(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <right_shift_str@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D8
data_type: string

tool: D2: please input the number to right shift the str."abcdefhij"


tool: D8: %d

assistant: ```c
int main() {
  char str[10] = "abcdefhij";
  int shift_digit = 0;
  printf("please input the number to right shift the str.\"abcdefhij\"\n");
  scanf("%d", &shift_digit);
  right_shift_str(str, shift_digit);
  puts(str);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6968666564636261,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x6a,0x16(%rsp)
  movl   $0x0,0x8(%rsp)
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  lea    0xe(%rsp),%rbx
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  call   <right_shift_str@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D6: please input the number to right shift the str."abcdefhij"


tool: D9: %d

assistant: ```c
int main() {
  char str[10] = "abcdefhij";
  int shift_digit = 0;
  printf("please input the number to right shift the str.\"abcdefhij\"\n");
  scanf("%d", &shift_digit);
  right_shift_str(str, shift_digit);
  puts(str);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6968666564636261,%rax
  movl   $0x0,0x8(%rsp)
  lea    0xe(%rsp),%rbp
  mov    %rax,0xe(%rsp)
  mov    $0x6a,%eax
  mov    %ax,0x16(%rsp)
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <right_shift_str@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D10
type: string

tool: D0: please input the number to right shift the str."abcdefhij"


tool: D10: %d

assistant: ```c
int main() {
  char str[10] = "abcdefhij";
  int shift_digit = 0;
  printf("please input the number to right shift the str.\"abcdefhij\"\n");
  scanf("%d", &shift_digit);
  right_shift_str(str, shift_digit);
  puts(str);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6968666564636261,%rax
  movl   $0x0,0x8(%rsp)
  lea    0xe(%rsp),%rbp
  mov    %rax,0xe(%rsp)
  mov    $0x6a,%eax
  mov    %ax,0x16(%rsp)
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <right_shift_str@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type_guessed: string
name: retrieve_data
arguments: label: D4
type_guessed: string

tool: D18: please input the number to right shift the str."abcdefhij"


tool: D4: %d

assistant: ```c
int main() {
  char str[10] = "abcdefhij";
  int shift_digit = 0;
  printf("please input the number to right shift the str.\"abcdefhij\"\n");
  scanf("%d", &shift_digit);
  right_shift_str(str, shift_digit);
  puts(str);
  return 0;
}
```