ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<load_iframe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L1
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L12
L1:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <videoStillPicture@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    -0x38(%rbp),%eax
  mov    %eax,%edi
  call   <videoPlay@plt>
L12:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string
name: disassemble_data
arguments: data_label: D23
type: string
name: disassemble_data
arguments: data_label: D14
type: string

tool: D8: I-frame size: %d


tool: D23: No memory for I-Frame

tool: D14: read: %zd bytes


assistant: ```c
void load_iframe(int filefd, int fd) {
  struct stat st;
  struct video_still_picture sp;
  fstat(filefd, &st);
  sp.iFrame = (char *)malloc(st.st_size);
  sp.size = st.st_size;
  printf("I-frame size: %d\n", sp.size);
  if (!sp.iFrame) {
    printf("No memory for I-Frame\n");
    return;
  }
  printf("read: %zd bytes\n", read(filefd, sp.iFrame, sp.size));
  videoStillPicture(fd, &sp);
  sleep(3);
  videoPlay(fd);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<load_iframe>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <fstat@plt>
  mov    0xc(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  mov    0xc(%rsp),%esi
  mov    %esi,0x18(%rsp)
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  test   %rsi,%rsi
  je     L7
  mov    0x18(%rsp),%edx
  mov    %ebx,%edi
  call   <read@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %ebp,%edi
  call   <videoStillPicture@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %ebp,%edi
  call   <videoPlay@plt>
L25:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L25
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D25
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string

tool: D25: I-frame size: %d


tool: D13: read: %zd bytes


tool: D7: No memory for I-Frame

assistant: ```c
void load_iframe(int filefd, int fd) {
  struct stat st;
  struct video_still_picture sp;
  fstat(filefd, &st);
  sp.iFrame = (char *)malloc(st.st_size);
  sp.size = st.st_size;
  printf("I-frame size: %d\n", sp.size);
  if (!sp.iFrame) {
    printf("No memory for I-Frame\n");
    return;
  }
  printf("read: %zd bytes\n", read(filefd, sp.iFrame, sp.size));
  videoStillPicture(fd, &sp);
  sleep(3);
  videoPlay(fd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<load_iframe>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <fstat@plt>
  mov    0xc(%rsp),%edi
  call   <malloc@plt>
  mov    0xc(%rsp),%esi
  lea    D23(%rip),%rdi
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  mov    %esi,0x18(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  test   %rsi,%rsi
  je     L21
  mov    0x18(%rsp),%edx
  mov    %ebp,%edi
  call   <read@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12d,%edi
  call   <videoStillPicture@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %r12d,%edi
  call   <videoPlay@plt>
L15:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  jmp    L15
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
data_type: string
name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string

tool: D23: I-frame size: %d


tool: D8: read: %zd bytes


tool: D17: No memory for I-Frame

assistant: ```c
void load_iframe(int filefd, int fd) {
  struct stat st;
  struct video_still_picture sp;
  fstat(filefd, &st);
  sp.iFrame = (char *)malloc(st.st_size);
  sp.size = st.st_size;
  printf("I-frame size: %d\n", sp.size);
  if (!sp.iFrame) {
    printf("No memory for I-Frame\n");
    return;
  }
  printf("read: %zd bytes\n", read(filefd, sp.iFrame, sp.size));
  videoStillPicture(fd, &sp);
  sleep(3);
  videoPlay(fd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<load_iframe>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <fstat@plt>
  mov    0xc(%rsp),%edi
  call   <malloc@plt>
  mov    0xc(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  mov    %esi,0x18(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  test   %rsi,%rsi
  je     L14
  mov    0x18(%rsp),%edx
  mov    %ebp,%edi
  call   <read@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12d,%edi
  call   <videoStillPicture@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %r12d,%edi
  call   <videoPlay@plt>
L4:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L4
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string
name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string

tool: D3: I-frame size: %d


tool: D27: read: %zd bytes


tool: D16: No memory for I-Frame

assistant: ```c
void load_iframe(int filefd, int fd) {
  struct stat st;
  struct video_still_picture sp;
  fstat(filefd, &st);
  sp.iFrame = (char *)malloc(st.st_size);
  sp.size = st.st_size;
  printf("I-frame size: %d\n", sp.size);
  if (!sp.iFrame) {
    printf("No memory for I-Frame\n");
    return;
  }
  printf("read: %zd bytes\n", read(filefd, sp.iFrame, sp.size));
  videoStillPicture(fd, &sp);
  sleep(3);
  videoPlay(fd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  notl   -0x14(%rbp)
  jmp    L9
L16:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  xor    %eax,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L12:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L25
  sarl   -0x14(%rbp)
  mov    -0x14(%rbp),%eax
  xor    $0xedb88320,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L22
L25:
  sarl   -0x14(%rbp)
L22:
  addl   $0x1,-0xc(%rbp)
L21:
  cmpl   $0x7,-0xc(%rbp)
  jle    L12
L9:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L16
  mov    -0x14(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t crc32(uint32_t crc, const void *data, int len) {
  uint8_t *tmp = (uint8_t *)data;
  int i;
  crc = ~crc;
  while (len--) {
    crc ^= *tmp++;
    for (i = 0; i < 8; i++)
      if (crc & 1)
        crc >>= 1, crc ^= 0xedb88320;
      else
        crc >>= 1;
  }
  return ~crc;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<crc32>:
  endbr64
  mov    %edi,%eax
  not    %eax
  test   %edx,%edx
  je     L15
  mov    %edx,%edx
  lea    (%rsi,%rdx,4),%r8
  jmp    L1
L16:
  cmp    %r8,%rsi
  je     L15
L1:
  add    $0x4,%rsi
  xor    -0x4(%rsi),%eax
  mov    $0x8,%ecx
L45:
  mov    %eax,%edx
  sar    %edx
  xor    $0xedb88320,%edx
  mov    %eax,%edi
  sar    %edi
  test   $0x1,%al
  mov    %edx,%eax
  cmove  %edi,%eax
  sub    $0x1,%ecx
  jne    L45
  jmp    L16
L15:
  not    %eax
  ret
```

assistant: ```c
uint32_t crc32(uint32_t crc, const void *data, int len) {
  uint8_t *tmp = (uint8_t *)data;
  int i;
  crc = ~crc;
  while (len--) {
    crc ^= *tmp++;
    for (i = 0; i < 8; i++)
      if (crc & 1)
        crc >>= 1, crc ^= 0xedb88320;
      else
        crc >>= 1;
  }
  return ~crc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crc32>:
  endbr64
  mov    %edi,%eax
  not    %eax
  test   %edx,%edx
  je     L20
  mov    %edx,%edx
  lea    (%rsi,%rdx,4),%r8
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x4,%rsi
  mov    $0x8,%edx
  xor    -0x4(%rsi),%eax
  nopl   0x0(%rax)
L19:
  mov    %eax,%edi
  sar    %eax
  mov    %eax,%ecx
  and    $0x1,%edi
  xor    $0xedb88320,%ecx
  test   %edi,%edi
  cmovne %ecx,%eax
  sub    $0x1,%edx
  jne    L19
  cmp    %r8,%rsi
  jne    L6
  not    %eax
  ret
L20:
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t crc32(uint32_t crc, const void *data, int len) {
  uint8_t *tmp = (uint8_t *)data;
  int i;
  crc = ~crc;
  while (len--) {
    crc ^= *tmp++;
    for (i = 0; i < 8; i++)
      if (crc & 1)
        crc >>= 1, crc ^= 0xedb88320;
      else
        crc >>= 1;
  }
  return ~crc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crc32>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rcx
  not    %eax
  test   %edx,%edx
  je     L6
  mov    %edx,%edx
  lea    (%rsi,%rdx,4),%rdi
  nopl   0x0(%rax)
L9:
  xor    (%rcx),%eax
  add    $0x4,%rcx
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%esi
  xor    $0xedb88320,%esi
  test   $0x1,%al
  cmovne %esi,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  xor    $0xedb88320,%esi
  and    $0x1,%edx
  cmovne %esi,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%esi
  xor    $0xedb88320,%esi
  test   $0x1,%al
  cmovne %esi,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  xor    $0xedb88320,%esi
  and    $0x1,%edx
  cmovne %esi,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%esi
  xor    $0xedb88320,%esi
  test   $0x1,%al
  cmovne %esi,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  xor    $0xedb88320,%esi
  and    $0x1,%edx
  cmovne %esi,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%esi
  xor    $0xedb88320,%esi
  test   $0x1,%al
  cmovne %esi,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  xor    $0xedb88320,%esi
  and    $0x1,%edx
  cmovne %esi,%eax
  cmp    %rcx,%rdi
  jne    L9
  not    %eax
  ret
L6:
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t crc32(uint32_t crc, const void *data, int len) {
  uint8_t *tmp = (uint8_t *)data;
  int i;
  crc = ~crc;
  while (len--) {
    crc ^= *tmp++;
    for (i = 0; i < 8; i++)
      if (crc & 1)
        crc >>= 1, crc ^= 0xedb88320;
      else
        crc >>= 1;
  }
  return ~crc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L5
L13:
  mov    $0x2,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int foo(int i, int j) {
  int x = 1;
  int y = i + x;
  int z = y - i;
  if (z == 1)
    return 1;
  return 2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int foo(int i, int j) {
  int x = 1;
  int y = i + x;
  int z = y - i;
  if (z == 1)
    return 1;
  return 2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int foo(int i, int j) {
  int x = 1;
  int y = i + x;
  int z = y - i;
  if (z == 1)
    return 1;
  return 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int foo(int i, int j) {
  int x = 1;
  int y = i + x;
  int z = y - i;
  if (z == 1)
    return 1;
  return 2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pyi_path_homepath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pyi_path_dirname@plt>
  nop
  leave
  ret
```

assistant: ```c
void pyi_path_homepath(char *homepath, const char *thisfile) {
  pyi_path_dirname(homepath, thisfile);
  ;
}
```
user: What is the c source code of the assembly code below?

```asm
<pyi_path_homepath>:
  endbr64
  sub    $0x8,%rsp
  call   <pyi_path_dirname@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pyi_path_homepath(char *homepath, const char *thisfile) {
  pyi_path_dirname(homepath, thisfile);
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pyi_path_homepath>:
  endbr64
  jmp    1050 <pyi_path_dirname@plt>
```

assistant: ```c
void pyi_path_homepath(char *homepath, const char *thisfile) {
  pyi_path_dirname(homepath, thisfile);
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pyi_path_homepath>:
  endbr64
  jmp    1050 <pyi_path_dirname@plt>
```

assistant: ```c
void pyi_path_homepath(char *homepath, const char *thisfile) {
  pyi_path_dirname(homepath, thisfile);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<baf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  shr    $0xf,%ax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl %cl,%eax
  mov    %ax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0xf,-0xc(%rbp)
  jle    L5
  nop
  pop    %rbp
  ret
```

assistant: ```c
int baf(short *x) {
  int i;
  short *xx = __builtin_assume_aligned(x, 8);
  for (i = 0; i < 16; i++)
    xx[i] = xx[i] >= 0 ? 0 : 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<baf>:
  endbr64
  lea    0x20(%rdi),%rax
L5:
  shrw   $0xf,(%rdi)
  add    $0x2,%rdi
  cmp    %rax,%rdi
  jne    L5
  ret
```

assistant: ```c
int baf(short *x) {
  int i;
  short *xx = __builtin_assume_aligned(x, 8);
  for (i = 0; i < 16; i++)
    xx[i] = xx[i] >= 0 ? 0 : 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<baf>:
  endbr64
  lea    0x20(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L3:
  shrw   $0xf,(%rdi)
  add    $0x2,%rdi
  cmp    %rax,%rdi
  jne    L3
  ret
```

assistant: ```c
int baf(short *x) {
  int i;
  short *xx = __builtin_assume_aligned(x, 8);
  for (i = 0; i < 16; i++)
    xx[i] = xx[i] >= 0 ? 0 : 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<baf>:
  endbr64
  movdqu (%rdi),%xmm0
  psrlw  $0xf,%xmm0
  movups %xmm0,(%rdi)
  movdqu 0x10(%rdi),%xmm0
  psrlw  $0xf,%xmm0
  movups %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
int baf(short *x) {
  int i;
  short *xx = __builtin_assume_aligned(x, 8);
  for (i = 0; i < 16; i++)
    xx[i] = xx[i] >= 0 ? 0 : 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fn_cl_48_57_65_70_91_91_97_102>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <next_utf8@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x2f,-0xc(%rbp)
  jbe    L49
  cmpl   $0x39,-0xc(%rbp)
  ja     L49
  mov    -0x10(%rbp),%eax
  jmp    L82
L49:
  cmpl   $0x40,-0xc(%rbp)
  jbe    L44
  cmpl   $0x46,-0xc(%rbp)
  ja     L44
  mov    -0x10(%rbp),%eax
  jmp    L82
L44:
  cmpl   $0x5a,-0xc(%rbp)
  jbe    L107
  cmpl   $0x5b,-0xc(%rbp)
  ja     L107
  mov    -0x10(%rbp),%eax
  jmp    L82
L107:
  cmpl   $0x60,-0xc(%rbp)
  jbe    L39
  cmpl   $0x66,-0xc(%rbp)
  ja     L39
  mov    -0x10(%rbp),%eax
  jmp    L82
L39:
  mov    $0xffffffff,%eax
L82:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
int fn_cl_48_57_65_70_91_91_97_102(const char *text) {
  int pos = 0;
  unsigned int c = next_utf8(text, &pos);
  if (c >= 48 && c <= 57)
    return pos;
  if (c >= 65 && c <= 70)
    return pos;
  if (c >= 91 && c <= 91)
    return pos;
  if (c >= 97 && c <= 102)
    return pos;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn_cl_48_57_65_70_91_91_97_102>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <next_utf8@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L48
  lea    -0x41(%rax),%edx
  cmp    $0x5,%edx
  jbe    L3
  cmp    $0x5b,%eax
  je     L59
  sub    $0x61,%eax
  cmp    $0x6,%eax
  mov    $0xffffffff,%eax
  cmovb  0x4(%rsp),%eax
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L48:
  mov    0x4(%rsp),%eax
  jmp    L41
L3:
  mov    0x4(%rsp),%eax
  jmp    L41
L59:
  mov    0x4(%rsp),%eax
  jmp    L41
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_cl_48_57_65_70_91_91_97_102(const char *text) {
  int pos = 0;
  unsigned int c = next_utf8(text, &pos);
  if (c >= 48 && c <= 57)
    return pos;
  if (c >= 65 && c <= 70)
    return pos;
  if (c >= 91 && c <= 91)
    return pos;
  if (c >= 97 && c <= 102)
    return pos;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fn_cl_48_57_65_70_91_91_97_102>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <next_utf8@plt>
  lea    -0x30(%rax),%ecx
  mov    $0xffffffff,%eax
  cmp    $0x36,%ecx
  ja     L6
  movabs $0xff81f7ffff81fc00,%rdx
  sar    %cl,%rdx
  and    $0x1,%edx
  cmove  0x4(%rsp),%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_cl_48_57_65_70_91_91_97_102(const char *text) {
  int pos = 0;
  unsigned int c = next_utf8(text, &pos);
  if (c >= 48 && c <= 57)
    return pos;
  if (c >= 65 && c <= 70)
    return pos;
  if (c >= 91 && c <= 91)
    return pos;
  if (c >= 97 && c <= 102)
    return pos;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fn_cl_48_57_65_70_91_91_97_102>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <next_utf8@plt>
  lea    -0x30(%rax),%ecx
  mov    $0xffffffff,%eax
  cmp    $0x36,%ecx
  ja     L13
  movabs $0xff81f7ffff81fc00,%rdx
  sar    %cl,%rdx
  and    $0x1,%edx
  cmove  0x4(%rsp),%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_cl_48_57_65_70_91_91_97_102(const char *text) {
  int pos = 0;
  unsigned int c = next_utf8(text, &pos);
  if (c >= 48 && c <= 57)
    return pos;
  if (c >= 65 && c <= 70)
    return pos;
  if (c >= 91 && c <= 91)
    return pos;
  if (c >= 97 && c <= 102)
    return pos;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<showValueU32U16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %ecx,%eax
  mov    %r8d,%edx
  mov    %ax,-0x6c(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strclr@plt>
  mov    -0x60(%rbp),%rdx
  mov    -0x58(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <addValueU32@plt>
  movzwl -0x6c(%rbp),%edx
  mov    -0x68(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <addValueU16@plt>
  movzwl -0x70(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <VDP_drawText@plt>
  movzwl -0x70(%rbp),%eax
  add    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned short showValueU32U16(char *str1, unsigned long value1, char *str2, unsigned short value2, unsigned short pos) {
  char s[64];
  strclr(s);
  addValueU32(s, str1, value1);
  addValueU16(s, str2, value2);
  VDP_drawText(s, 0, pos);
  return pos + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<showValueU32U16>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %rdx,%r13
  mov    %ecx,%ebp
  mov    %r8d,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strclr@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <addValueU32@plt>
  movzwl %bp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <addValueU16@plt>
  movzwl %bx,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <VDP_drawText@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  lea    0x1(%rbx),%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short showValueU32U16(char *str1, unsigned long value1, char *str2, unsigned short value2, unsigned short pos) {
  char s[64];
  strclr(s);
  addValueU32(s, str1, value1);
  addValueU16(s, str2, value2);
  VDP_drawText(s, 0, pos);
  return pos + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<showValueU32U16>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strclr@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <addValueU32@plt>
  movzwl %bp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <addValueU16@plt>
  movzwl %bx,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <VDP_drawText@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x58,%rsp
  lea    0x1(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short showValueU32U16(char *str1, unsigned long value1, char *str2, unsigned short value2, unsigned short pos) {
  char s[64];
  strclr(s);
  addValueU32(s, str1, value1);
  addValueU16(s, str2, value2);
  VDP_drawText(s, 0, pos);
  return pos + 1;
}
```