ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <open@plt>
  lea    D7(%rip),%rdi
  call   <open@plt>
  lea    D4(%rip),%rdi
  call   <open@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string
name: parse_data
arguments: tag: D4
type_guessed: string

tool: D17: /root/abc

tool: D7: /media/xyz

tool: D4: /mnt/abc

assistant: ```c
int main() {
  open("/root/abc");
  open("/media/xyz");
  open("/mnt/abc");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encodeTimeout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jle    L19
  mov    -0x18(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L33
L6:
  sarl   -0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  mov    $0x0,%al
  test   %eax,%eax
  jne    L6
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movzbl %al,%eax
  or     %rdx,%rax
  jmp    L22
L19:
  mov    $0x0,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
uint16_t encodeTimeout(uint16_t timeout_mclks) {
  uint32_t ls_byte = 0;
  uint16_t ms_byte = 0;
  if (timeout_mclks > 0) {
    ls_byte = timeout_mclks - 1;
    while ((ls_byte & 0xFFFFFF00) > 0) {
      ls_byte >>= 1;
      ms_byte++;
    }
    return (ms_byte << 8) | (ls_byte & 0xFF);
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<encodeTimeout>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  jle    L20
  sub    $0x1,%edi
  mov    %edi,%edx
  test   $0xffffff00,%edi
  je     L39
L36:
  sar    %edx
  add    $0x1,%rax
  test   $0xffffff00,%edx
  jne    L36
L8:
  shl    $0x8,%rax
  movzbl %dl,%edx
  or     %rdx,%rax
L20:
  ret
L39:
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
uint16_t encodeTimeout(uint16_t timeout_mclks) {
  uint32_t ls_byte = 0;
  uint16_t ms_byte = 0;
  if (timeout_mclks > 0) {
    ls_byte = timeout_mclks - 1;
    while ((ls_byte & 0xFFFFFF00) > 0) {
      ls_byte >>= 1;
      ms_byte++;
    }
    return (ms_byte << 8) | (ls_byte & 0xFF);
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<encodeTimeout>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  jle    L18
  lea    -0x1(%rdi),%eax
  xor    %edx,%edx
  test   $0xffffff00,%eax
  je     L3
  nopw   0x0(%rax,%rax,1)
L19:
  sar    %eax
  add    $0x1,%rdx
  test   $0xffffff00,%eax
  jne    L19
  shl    $0x8,%rdx
L3:
  cltq
  or     %rdx,%rax
L18:
  ret
```

assistant: ```c
uint16_t encodeTimeout(uint16_t timeout_mclks) {
  uint32_t ls_byte = 0;
  uint16_t ms_byte = 0;
  if (timeout_mclks > 0) {
    ls_byte = timeout_mclks - 1;
    while ((ls_byte & 0xFFFFFF00) > 0) {
      ls_byte >>= 1;
      ms_byte++;
    }
    return (ms_byte << 8) | (ls_byte & 0xFF);
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encodeTimeout>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  jle    L11
  lea    -0x1(%rdi),%eax
  xor    %edx,%edx
  test   $0xffffff00,%eax
  je     L29
  nopw   0x0(%rax,%rax,1)
L10:
  sar    %eax
  add    $0x1,%rdx
  test   $0xffffff00,%eax
  jne    L10
  shl    $0x8,%rdx
L29:
  cltq
  or     %rdx,%rax
L11:
  ret
```

assistant: ```c
uint16_t encodeTimeout(uint16_t timeout_mclks) {
  uint32_t ls_byte = 0;
  uint16_t ms_byte = 0;
  if (timeout_mclks > 0) {
    ls_byte = timeout_mclks - 1;
    while ((ls_byte & 0xFFFFFF00) > 0) {
      ls_byte >>= 1;
      ms_byte++;
    }
    return (ms_byte << 8) | (ls_byte & 0xFF);
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pm_writelittleshort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %ax,-0xc(%rbp)
  movswl -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  movzwl -0xc(%rbp),%eax
  shr    $0x8,%ax
  cwtl
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int pm_writelittleshort(FILE *const ofP, short const s) {
  putc((s >> 0) & 0xff, ofP);
  putc((s >> 8) & 0xff, ofP);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pm_writelittleshort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movzbl %sil,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int pm_writelittleshort(FILE *const ofP, short const s) {
  putc((s >> 0) & 0xff, ofP);
  putc((s >> 8) & 0xff, ofP);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<pm_writelittleshort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int pm_writelittleshort(FILE *const ofP, short const s) {
  putc((s >> 0) & 0xff, ofP);
  putc((s >> 8) & 0xff, ofP);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pm_writelittleshort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int pm_writelittleshort(FILE *const ofP, short const s) {
  putc((s >> 0) & 0xff, ofP);
  putc((s >> 8) & 0xff, ofP);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nmea_calc_crc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int nmea_calc_crc(const char *buff, int buff_sz) {
  int chsum = 0, it;
  for (it = 0; it < buff_sz; ++it)
    chsum ^= (int)buff[it];
  return chsum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nmea_calc_crc>:
  endbr64
  test   %esi,%esi
  jle    L23
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    $0x0,%edx
L4:
  movsbl (%rax),%ecx
  xor    %ecx,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L4
L15:
  mov    %edx,%eax
  ret
L23:
  mov    $0x0,%edx
  jmp    L15
```

assistant: ```c
int nmea_calc_crc(const char *buff, int buff_sz) {
  int chsum = 0, it;
  for (it = 0; it < buff_sz; ++it)
    chsum ^= (int)buff[it];
  return chsum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nmea_calc_crc>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %edx,%eax
  cmp    %rcx,%rdi
  jne    L10
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int nmea_calc_crc(const char *buff, int buff_sz) {
  int chsum = 0, it;
  for (it = 0; it < buff_sz; ++it)
    chsum ^= (int)buff[it];
  return chsum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D20(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movsd  D54(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm3,%xmm3
  cvtsd2ss %xmm0,%xmm3
  movd   %xmm3,%eax
  movd   %eax,%xmm0
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D20
datatype: f64
name: parse_data
arguments: tag: D54
datatype: f64
name: parse_data
arguments: tag: D7
datatype: f64
name: parse_data
arguments: tag: D14
datatype: string

tool: D9: %f

tool: D20: 3.5

tool: D54: 7.5

tool: D7: 11

tool: D14: MEDIA = %.5f


assistant: ```c
int main() {
  float a, b;
  scanf("%f", &a);
  scanf("%f", &b);
  printf("MEDIA = %.5f\n", (a * 3.5 + b * 7.5) / 11.0);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D37(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd (%rsp),%xmm0
  mulsd  D22(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x4(%rsp),%xmm1
  mulsd  D43(%rip),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D10(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D22
type_infered: f64
name: read_data
arguments: data_label: D43
type_infered: f64
name: read_data
arguments: data_label: D10
type_infered: f64
name: read_data
arguments: data_label: D33
type_infered: string

tool: D37: %f

tool: D22: 3.5

tool: D43: 7.5

tool: D10: 11

tool: D33: MEDIA = %.5f


assistant: ```c
int main() {
  float a, b;
  scanf("%f", &a);
  scanf("%f", &b);
  printf("MEDIA = %.5f\n", (a * 3.5 + b * 7.5) / 11.0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D29(%rip),%rdi
  cvtss2sd (%rsp),%xmm0
  cvtss2sd 0x4(%rsp),%xmm1
  mulsd  D48(%rip),%xmm0
  mulsd  D28(%rip),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D16(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D48
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: f64

tool: D13: %f

tool: D29: MEDIA = %.5f


tool: D48: 3.5

tool: D28: 7.5

tool: D16: 11

assistant: ```c
int main() {
  float a, b;
  scanf("%f", &a);
  scanf("%f", &b);
  printf("MEDIA = %.5f\n", (a * 3.5 + b * 7.5) / 11.0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D41(%rip),%rdi
  cvtss2sd (%rsp),%xmm0
  cvtss2sd 0x4(%rsp),%xmm1
  mulsd  D10(%rip),%xmm0
  mulsd  D29(%rip),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D7(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D20
type: string
name: parse_data
arguments: tag: D41
type: string
name: parse_data
arguments: tag: D10
type: f64
name: parse_data
arguments: tag: D29
type: f64
name: parse_data
arguments: tag: D7
type: f64

tool: D20: %f

tool: D41: MEDIA = %.5f


tool: D10: 3.5

tool: D29: 7.5

tool: D7: 11

assistant: ```c
int main() {
  float a, b;
  scanf("%f", &a);
  scanf("%f", &b);
  printf("MEDIA = %.5f\n", (a * 3.5 + b * 7.5) / 11.0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x21,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int i = 33;
  foo(i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x21,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i = 33;
  foo(i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x21,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i = 33;
  foo(i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x21,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i = 33;
  foo(i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isProbablyFE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %rdi,-0x1b8(%rbp)
  mov    %esi,-0x1bc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x20,-0x1a0(%rbp)
  movl   $0xd0,-0x198(%rbp)
  movl   $0xc6,-0x194(%rbp)
  movl   $0xc5,-0x190(%rbp)
  movl   $0x20,-0x13c(%rbp)
  movl   $0xc3,-0x138(%rbp)
  movl   $0xf8,-0x134(%rbp)
  movl   $0xa5,-0x130(%rbp)
  movl   $0x82,-0x12c(%rbp)
  movl   $0xd0,-0xd8(%rbp)
  movl   $0xfb,-0xd4(%rbp)
  movl   $0x20,-0xd0(%rbp)
  movl   $0x73,-0xcc(%rbp)
  movl   $0xfe,-0xc8(%rbp)
  movl   $0x20,-0x74(%rbp)
  movl   $0xf0,-0x6c(%rbp)
  movl   $0x84,-0x68(%rbp)
  movl   $0xd6,-0x64(%rbp)
  movl   $0x0,-0x1a4(%rbp)
  jmp    L42
L39:
  lea    -0x1a0(%rbp),%rcx
  mov    -0x1a4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x1bc(%rbp),%esi
  mov    -0x1b8(%rbp),%rax
  mov    $0x1,%r8d
  mov    $0x5,%ecx
  mov    %rax,%rdi
  call   <searchForBytes@plt>
  test   %rax,%rax
  je     L18
  mov    $0x1,%eax
  jmp    L9
L18:
  addl   $0x1,-0x1a4(%rbp)
L42:
  cmpl   $0x3,-0x1a4(%rbp)
  jle    L39
  mov    $0x0,%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int isProbablyFE(const uint8_t *image, uint32_t size) {
  uint8_t signature[4][5] = {{0x20, 0x00, 0xD0, 0xC6, 0xC5}, {0x20, 0xC3, 0xF8, 0xA5, 0x82}, {0xD0, 0xFB, 0x20, 0x73, 0xFE}, {0x20, 0x00, 0xF0, 0x84, 0xD6}};
  uint32_t i;
  for (i = 0; i < 4; ++i)
    if (searchForBytes(image, size, signature[i], 5, 1))
      return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isProbablyFE>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x20,(%rsp)
  movl   $0xd0,0x8(%rsp)
  movl   $0xc6,0xc(%rsp)
  movl   $0xc5,0x10(%rsp)
  movl   $0x20,0x64(%rsp)
  movl   $0xc3,0x68(%rsp)
  movl   $0xf8,0x6c(%rsp)
  movl   $0xa5,0x70(%rsp)
  movl   $0x82,0x74(%rsp)
  movl   $0xd0,0xc8(%rsp)
  movl   $0xfb,0xcc(%rsp)
  movl   $0x20,0xd0(%rsp)
  movl   $0x73,0xd4(%rsp)
  movl   $0xfe,0xd8(%rsp)
  movl   $0x20,0x12c(%rsp)
  movl   $0xf0,0x134(%rsp)
  movl   $0x84,0x138(%rsp)
  movl   $0xd6,0x13c(%rsp)
  mov    %rsp,%rbx
  lea    0x190(%rsp),%r13
L23:
  mov    $0x1,%r8d
  mov    $0x5,%ecx
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <searchForBytes@plt>
  test   %rax,%rax
  jne    L38
  add    $0x64,%rbx
  cmp    %r13,%rbx
  jne    L23
L10:
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    $0x1,%eax
  jmp    L10
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isProbablyFE(const uint8_t *image, uint32_t size) {
  uint8_t signature[4][5] = {{0x20, 0x00, 0xD0, 0xC6, 0xC5}, {0x20, 0xC3, 0xF8, 0xA5, 0x82}, {0xD0, 0xFB, 0x20, 0x73, 0xFE}, {0x20, 0x00, 0xF0, 0x84, 0xD6}};
  uint32_t i;
  for (i = 0; i < 4; ++i)
    if (searchForBytes(image, size, signature[i], 5, 1))
      return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isProbablyFE>:
  endbr64
  push   %r13
  mov    $0x32,%ecx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rbx
  lea    0x190(%rsp),%r13
  rep stos %rax,%es:(%rdi)
  movl   $0x20,(%rsp)
  movabs $0xc6000000d0,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xf8000000c3,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x82000000a5,%rax
  mov    %rax,0x70(%rsp)
  movabs $0xfb000000d0,%rax
  mov    %rax,0xc8(%rsp)
  movabs $0x7300000020,%rax
  mov    %rax,0xd0(%rsp)
  movabs $0xd600000084,%rax
  movl   $0xc5,0x10(%rsp)
  movl   $0x20,0x64(%rsp)
  movl   $0xfe,0xd8(%rsp)
  movl   $0x20,0x12c(%rsp)
  movl   $0xf0,0x134(%rsp)
  mov    %rax,0x138(%rsp)
L30:
  mov    $0x1,%r8d
  mov    $0x5,%ecx
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <searchForBytes@plt>
  test   %rax,%rax
  jne    L33
  add    $0x64,%rbx
  cmp    %r13,%rbx
  jne    L30
L34:
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  mov    $0x1,%eax
  jmp    L34
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isProbablyFE(const uint8_t *image, uint32_t size) {
  uint8_t signature[4][5] = {{0x20, 0x00, 0xD0, 0xC6, 0xC5}, {0x20, 0xC3, 0xF8, 0xA5, 0x82}, {0xD0, 0xFB, 0x20, 0x73, 0xFE}, {0x20, 0x00, 0xF0, 0x84, 0xD6}};
  uint32_t i;
  for (i = 0; i < 4; ++i)
    if (searchForBytes(image, size, signature[i], 5, 1))
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isProbablyFE>:
  endbr64
  push   %r13
  mov    $0x32,%ecx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x1a8,%rsp
  movdqa D27(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rbx
  lea    0x190(%rsp),%r13
  rep stos %rax,%es:(%rdi)
  mov    D21(%rip),%rax
  movups %xmm0,0x64(%rsp)
  movdqa D13(%rip),%xmm0
  movl   $0x20,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    D11(%rip),%rax
  movl   $0xc5,0x10(%rsp)
  movl   $0x82,0x74(%rsp)
  movl   $0xfe,0xd8(%rsp)
  movl   $0x20,0x12c(%rsp)
  mov    %rax,0x134(%rsp)
  movl   $0xd6,0x13c(%rsp)
  movups %xmm0,0xc8(%rsp)
L38:
  mov    $0x1,%r8d
  mov    $0x5,%ecx
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <searchForBytes@plt>
  test   %rax,%rax
  jne    L17
  add    $0x64,%rbx
  cmp    %rbx,%r13
  jne    L38
L7:
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    $0x1,%eax
  jmp    L7
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D27
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D21
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D13
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D11
type_guessed: byte[8]

tool: {"D27": [0x20,0x00,0x00,0x00,0xc3,0x00,0x00,0x00,0xf8,0x00,0x00,0x00,0xa5,0x00,0x00,0x00]}

tool: {"D21": [0xd0,0x00,0x00,0x00,0xc6,0x00,0x00,0x00]}

tool: {"D13": [0xd0,0x00,0x00,0x00,0xfb,0x00,0x00,0x00,0x20,0x00,0x00,0x00,0x73,0x00,0x00,0x00]}

tool: {"D11": [0xf0,0x00,0x00,0x00,0x84,0x00,0x00,0x00]}

assistant: ```c
int isProbablyFE(const uint8_t *image, uint32_t size) {
  uint8_t signature[4][5] = {{0x20, 0x00, 0xD0, 0xC6, 0xC5}, {0x20, 0xC3, 0xF8, 0xA5, 0x82}, {0xD0, 0xFB, 0x20, 0x73, 0xFE}, {0x20, 0x00, 0xF0, 0x84, 0xD6}};
  uint32_t i;
  for (i = 0; i < 4; ++i)
    if (searchForBytes(image, size, signature[i], 5, 1))
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nist_rbg_get_entropy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L75:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <padlock_xstore_rng@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jg     L3
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L10
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x24(%rbp),%eax
  jmp    L18
L3:
  mov    -0x40(%rbp),%eax
  sub    -0x24(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L85
  mov    -0x40(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L85
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x24(%rbp),%eax
  jmp    L18
L85:
  mov    -0x20(%rbp),%edx
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  add    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L75
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x24(%rbp),%eax
  jmp    L18
L10:
  nop
  jmp    L75
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

assistant: ```c
int nist_rbg_get_entropy(void *entropy, int min_length, int buffer_length) {
  int count = 0, rv, len;
  int buffer[2];
  char *p = (char *)entropy;
  for (;;) {
    rv = padlock_xstore_rng(buffer);
    len = rv & 0x0f;
    if (len < 1) {
      if (count >= min_length) {
        memset((buffer), 0, (sizeof(buffer)));
        return count;
      }
      continue;
    }
    if (len > buffer_length - count) {
      len = buffer_length - count;
      if (!len) {
        memset((buffer), 0, (sizeof(buffer)));
        return count;
      }
    }
    memcpy(p, buffer, len);
    p += len;
    count += len;
    if (count >= buffer_length) {
      memset((buffer), 0, (sizeof(buffer)));
      return count;
    }
  }
}
```