user: Demonstrate the C code that generates the assembly output below:

```asm
<my_split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x828,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1818(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r13
  test   %rsi,%rsi
  je     L56
  mov    %rsi,%rdi
  mov    %rsi,%r14
  call   <strlen@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %eax,%r15d
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
  movslq %r15d,%rax
  mov    $0x1,%r12d
  lea    0x810(%rsp),%r15
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rax
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L68:
  mov    %rbx,%rbp
  mov    %r13,%rsi
  mov    %r15,%rdi
  sub    %r13,%rbp
  mov    %ebp,%edx
  movslq %ebp,%rbp
  call   <memcpy@plt>
  mov    %r15,%rdi
  movb   $0x0,0x810(%rsp,%rbp,1)
  movslq %r12d,%rbp
  call   <strdup@plt>
  mov    (%rsp),%rcx
  mov    %r14,%rsi
  mov    %rax,-0x8(%rcx,%r12,8)
  mov    0x8(%rsp),%rax
  add    $0x1,%r12
  lea    (%rbx,%rax,1),%r13
  mov    %r13,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L68
  lea    0x1(%rbp),%ebx
  lea    0x10(,%rbp,8),%r14d
  movslq %ebx,%rbx
  shl    $0x3,%rbx
L4:
  mov    %r13,%rdi
  xor    %esi,%esi
  call   <strchr@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  sub    %r13,%rax
  mov    %eax,%edx
  mov    %rax,%r12
  call   <memcpy@plt>
  movslq %r12d,%r12
  mov    %r15,%rdi
  movb   $0x0,0x810(%rsp,%r12,1)
  call   <strdup@plt>
  mov    %r14d,%edi
  mov    %rax,0x10(%rsp,%rbp,8)
  call   <malloc@plt>
  mov    (%rsp),%r13
  mov    %rax,%r12
  lea    0x8(%rax,%rbp,8),%rax
  mov    %r12,%rdx
  sub    %r12,%r13
  nopl   0x0(%rax)
L25:
  mov    0x0(%r13,%rdx,1),%rcx
  add    $0x8,%rdx
  mov    %rcx,-0x8(%rdx)
  cmp    %rdx,%rax
  jne    L25
  movq   $0x0,(%r12,%rbx,1)
L10:
  mov    0x1818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x1828,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strdup@plt>
  movq   $0x0,0x8(%r12)
  mov    %rax,(%r12)
  jmp    L10
  nopl   0x0(%rax)
L27:
  lea    0x10(%rsp),%rax
  mov    $0x8,%ebx
  mov    $0x10,%r14d
  xor    %ebp,%ebp
  mov    %rax,(%rsp)
  lea    0x810(%rsp),%r15
  jmp    L4
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **my_split(char *str, char *spl) {
  char **ret, *buffer[256], buf[4096];
  int i;
  if (!spl) {
    ret = (char **)malloc(2 * sizeof(char *));
    ret[0] = (char *)strdup(str);
    ret[1] = NULL;
    return (ret);
  }
  int count = 0;
  char *fptr = str;
  const int spl_len = strlen(spl);
  char *sptr = strstr(fptr, spl);
  while (sptr) {
    i = sptr - fptr;
    memcpy(buf, fptr, i);
    buf[i] = '\0';
    buffer[count++] = (char *)strdup(buf);
    fptr = sptr + spl_len;
    sptr = strstr(fptr, spl);
  }
  sptr = strchr(fptr, '\0');
  i = sptr - fptr;
  memcpy(buf, fptr, i);
  buf[i] = '\0';
  buffer[count++] = (char *)strdup(buf);
  ret = (char **)malloc((count + 1) * sizeof(char *));
  for (i = 0; i < count; i++) {
    ret[i] = buffer[i];
  }
  ret[count] = NULL;
  return (ret);
}
```