ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<axp_set_warning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int axp_set_warning(int warn1, int warn2) {
  int ret = 0;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<axp_set_warning>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int axp_set_warning(int warn1, int warn2) {
  int ret = 0;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<axp_set_warning>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int axp_set_warning(int warn1, int warn2) {
  int ret = 0;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<axp_set_warning>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int axp_set_warning(int warn1, int warn2) {
  int ret = 0;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<f4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L19:
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((no, noclone)) f4(float *__restrict a, float *__restrict b, float *__restrict c, float *__restrict d, float *__restrict e) {
  for (int i = 0; i < 1024; ++i) {
    a[i] = e[i * 4];
    b[i] = e[i * 4 + 1];
    c[i] = e[i * 4 + 2];
    d[i] = e[i * 4 + 3];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f4>:
  endbr64
  mov    $0x0,%eax
L7:
  movss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  movss  0x4(%r8,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,1)
  movss  0x8(%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,1)
  movss  0xc(%r8,%rax,4),%xmm0
  movss  %xmm0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0x1000,%rax
  jne    L7
  ret
```

assistant: ```c
void __attribute__((no, noclone)) f4(float *__restrict a, float *__restrict b, float *__restrict c, float *__restrict d, float *__restrict e) {
  for (int i = 0; i < 1024; ++i) {
    a[i] = e[i * 4];
    b[i] = e[i * 4 + 1];
    c[i] = e[i * 4 + 2];
    d[i] = e[i * 4 + 3];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f4>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L6:
  movss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  movss  0x4(%r8,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,1)
  movss  0x8(%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,1)
  movss  0xc(%r8,%rax,4),%xmm0
  movss  %xmm0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0x1000,%rax
  jne    L6
  ret
```

assistant: ```c
void __attribute__((no, noclone)) f4(float *__restrict a, float *__restrict b, float *__restrict c, float *__restrict d, float *__restrict e) {
  for (int i = 0; i < 1024; ++i) {
    a[i] = e[i * 4];
    b[i] = e[i * 4 + 1];
    c[i] = e[i * 4 + 2];
    d[i] = e[i * 4 + 3];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f4>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L3:
  movups (%r8,%rax,4),%xmm0
  movups 0x20(%r8,%rax,4),%xmm1
  movups 0x10(%r8,%rax,4),%xmm5
  movups 0x30(%r8,%rax,4),%xmm7
  movaps %xmm0,%xmm2
  movaps %xmm1,%xmm3
  shufps $0x88,%xmm5,%xmm2
  movaps %xmm2,%xmm4
  shufps $0xdd,%xmm5,%xmm0
  shufps $0x88,%xmm7,%xmm3
  shufps $0x88,%xmm3,%xmm4
  movups %xmm4,(%rdi,%rax,1)
  movaps %xmm0,%xmm4
  shufps $0xdd,%xmm7,%xmm1
  shufps $0xdd,%xmm3,%xmm2
  shufps $0x88,%xmm1,%xmm4
  movups %xmm2,(%rdx,%rax,1)
  shufps $0xdd,%xmm1,%xmm0
  movups %xmm4,(%rsi,%rax,1)
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    $0x1000,%rax
  jne    L3
  ret
```

assistant: ```c
void __attribute__((no, noclone)) f4(float *__restrict a, float *__restrict b, float *__restrict c, float *__restrict d, float *__restrict e) {
  for (int i = 0; i < 1024; ++i) {
    a[i] = e[i * 4];
    b[i] = e[i * 4 + 1];
    c[i] = e[i * 4 + 2];
    d[i] = e[i * 4 + 3];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<path_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0xe,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x3e,(%rax)
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L23:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L8
  cmpl   $0x8,-0x14(%rbp)
  jne    L30
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x2e,(%rax)
L30:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L8:
  addl   $0x1,-0x14(%rbp)
L7:
  cmpl   $0xa,-0x14(%rbp)
  jle    L23
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *path_name(const char *dir, const char *name) {
  size_t n = strlen(dir);
  char *ret = malloc(n + 14);
  strcpy(ret, dir);
  ret[n++] = '>';
  int i;
  for (i = 0; i < 11; i++) {
    if (name[i] != ' ') {
      if (i == 8)
        ret[n++] = '.';
      ret[n++] = name[i];
    }
  }
  ret[n] = 0;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<path_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  lea    0xe(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0x1(%r12),%rcx
  movb   $0x3e,(%rbx,%r12,1)
  mov    $0x0,%eax
  jmp    L37
L5:
  mov    %dl,(%rbx,%rcx,1)
  lea    0x1(%rcx),%rcx
L33:
  add    $0x1,%rax
  cmp    $0xb,%rax
  je     L46
L37:
  movzbl 0x0(%rbp,%rax,1),%edx
  cmp    $0x20,%dl
  je     L33
  cmp    $0x8,%eax
  jne    L5
  movb   $0x2e,(%rbx,%rcx,1)
  lea    0x1(%rcx),%rcx
  jmp    L5
L46:
  movb   $0x0,(%rbx,%rcx,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *path_name(const char *dir, const char *name) {
  size_t n = strlen(dir);
  char *ret = malloc(n + 14);
  strcpy(ret, dir);
  ret[n++] = '>';
  int i;
  for (i = 0; i < 11; i++) {
    if (name[i] != ' ') {
      if (i == 8)
        ret[n++] = '.';
      ret[n++] = name[i];
    }
  }
  ret[n] = 0;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<path_name>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0xe(%rax),%rdi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  movb   $0x3e,(%r12,%rbp,1)
  lea    0x1(%rbp),%rcx
  xor    %eax,%eax
  jmp    L29
L17:
  mov    %dl,(%r12,%rcx,1)
  add    $0x1,%rcx
L23:
  add    $0x1,%rax
  cmp    $0xb,%rax
  je     L42
L29:
  movzbl (%rbx,%rax,1),%edx
  cmp    $0x20,%dl
  je     L23
  cmp    $0x8,%rax
  jne    L17
  movb   $0x2e,(%r12,%rcx,1)
  add    $0x1,%rcx
  jmp    L17
  nopl   0x0(%rax)
L42:
  movb   $0x0,(%r12,%rcx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *path_name(const char *dir, const char *name) {
  size_t n = strlen(dir);
  char *ret = malloc(n + 14);
  strcpy(ret, dir);
  ret[n++] = '>';
  int i;
  for (i = 0; i < 11; i++) {
    if (name[i] != ' ') {
      if (i == 8)
        ret[n++] = '.';
      ret[n++] = name[i];
    }
  }
  ret[n] = 0;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<path_name>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0xe(%rax),%rdi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movzbl (%rbx),%edx
  movb   $0x3e,(%r12,%rbp,1)
  lea    0x1(%rbp),%rax
  cmp    $0x20,%dl
  je     L71
  mov    %dl,0x1(%r12,%rbp,1)
  lea    0x2(%rbp),%rax
L71:
  movzbl 0x1(%rbx),%edx
  cmp    $0x20,%dl
  je     L62
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L62:
  movzbl 0x2(%rbx),%edx
  cmp    $0x20,%dl
  je     L47
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L47:
  movzbl 0x3(%rbx),%edx
  cmp    $0x20,%dl
  je     L29
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L29:
  movzbl 0x4(%rbx),%edx
  cmp    $0x20,%dl
  je     L43
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L43:
  movzbl 0x5(%rbx),%edx
  cmp    $0x20,%dl
  je     L83
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L83:
  movzbl 0x6(%rbx),%edx
  cmp    $0x20,%dl
  je     L10
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L10:
  movzbl 0x7(%rbx),%edx
  cmp    $0x20,%dl
  je     L1
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L1:
  movzbl 0x8(%rbx),%edx
  cmp    $0x20,%dl
  je     L102
  lea    0x1(%rax),%rcx
  movb   $0x2e,(%r12,%rax,1)
  add    $0x2,%rax
  mov    %dl,(%r12,%rcx,1)
L102:
  movzbl 0x9(%rbx),%edx
  cmp    $0x20,%dl
  je     L59
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L59:
  movzbl 0xa(%rbx),%edx
  cmp    $0x20,%dl
  je     L14
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
L14:
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *path_name(const char *dir, const char *name) {
  size_t n = strlen(dir);
  char *ret = malloc(n + 14);
  strcpy(ret, dir);
  ret[n++] = '>';
  int i;
  for (i = 0; i < 11; i++) {
    if (name[i] != ' ') {
      if (i == 8)
        ret[n++] = '.';
      ret[n++] = name[i];
    }
  }
  ret[n] = 0;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lash_polarToCartesian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  mov    %esi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <cos@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm2
  mulss  -0x8(%rbp),%xmm2
  movd   %xmm2,%eax
  movd   %eax,%xmm0
  call   <floor@plt>
  mov    -0xc(%rbp),%edx
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm3
  mulss  -0x8(%rbp),%xmm3
  movd   %xmm3,%eax
  movd   %eax,%xmm0
  call   <floor@plt>
  mov    -0x10(%rbp),%edx
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int lash_polarToCartesian(const float radians, const float radius, const int source_x, const int source_y, int *target_x, int *target_y) {
  *target_x = source_x + floor(cos(radians) * radius);
  *target_y = source_y + floor(sin(radians) * radius);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lash_polarToCartesian>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  mov    %edi,%r13d
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %rcx,%rbx
  movss  %xmm0,0xc(%rsp)
  call   <cos@plt>
  mulss  0x8(%rsp),%xmm0
  call   <floor@plt>
  add    %r13d,%eax
  mov    %eax,(%r12)
  movss  0xc(%rsp),%xmm0
  call   <sin@plt>
  mulss  0x8(%rsp),%xmm0
  call   <floor@plt>
  add    %ebp,%eax
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int lash_polarToCartesian(const float radians, const float radius, const int source_x, const int source_y, int *target_x, int *target_y) {
  *target_x = source_x + floor(cos(radians) * radius);
  *target_y = source_y + floor(sin(radians) * radius);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lash_polarToCartesian>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <cos@plt>
  mulss  0x8(%rsp),%xmm0
  call   <floor@plt>
  movss  0xc(%rsp),%xmm2
  add    %r13d,%eax
  mov    %eax,(%r12)
  movaps %xmm2,%xmm0
  call   <sin@plt>
  mulss  0x8(%rsp),%xmm0
  call   <floor@plt>
  add    %ebp,%eax
  mov    %eax,(%rbx)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int lash_polarToCartesian(const float radians, const float radius, const int source_x, const int source_y, int *target_x, int *target_y) {
  *target_x = source_x + floor(cos(radians) * radius);
  *target_y = source_y + floor(sin(radians) * radius);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lash_polarToCartesian>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <cos@plt>
  mulss  0x8(%rsp),%xmm0
  call   <floor@plt>
  movss  0xc(%rsp),%xmm2
  add    %r13d,%eax
  mov    %eax,(%r12)
  movaps %xmm2,%xmm0
  call   <sin@plt>
  mulss  0x8(%rsp),%xmm0
  call   <floor@plt>
  add    %ebp,%eax
  mov    %eax,(%rbx)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int lash_polarToCartesian(const float radians, const float radius, const int source_x, const int source_y, int *target_x, int *target_y) {
  *target_x = source_x + floor(cos(radians) * radius);
  *target_y = source_y + floor(sin(radians) * radius);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<netutils_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <netutils_errfunc@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int netutils_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  int len = netutils_errfunc(fmt, args);
  va_end(args);
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<netutils_error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <netutils_errfunc@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int netutils_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  int len = netutils_errfunc(fmt, args);
  va_end(args);
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<netutils_error>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <netutils_errfunc@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int netutils_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  int len = netutils_errfunc(fmt, args);
  va_end(args);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<netutils_error>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <netutils_errfunc@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int netutils_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  int len = netutils_errfunc(fmt, args);
  va_end(args);
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<putpopbulk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  test   %rax,%rax
  jns    L1
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: write

assistant: ```c
void putpopbulk(int socket, char *data) {
  ssize_t datalen = strlen(data);
  if (write(socket, data, datalen) < 0) {
    perror("write");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putpopbulk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %rax,%rax
  js     L12
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: write

assistant: ```c
void putpopbulk(int socket, char *data) {
  ssize_t datalen = strlen(data);
  if (write(socket, data, datalen) < 0) {
    perror("write");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<putpopbulk>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  test   %rax,%rax
  js     L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  lea    D1(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <perror@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: write

assistant: ```c
void putpopbulk(int socket, char *data) {
  ssize_t datalen = strlen(data);
  if (write(socket, data, datalen) < 0) {
    perror("write");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<putpopbulk>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  test   %rax,%rax
  js     L7
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  lea    D1(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <perror@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D1: write

assistant: ```c
void putpopbulk(int socket, char *data) {
  ssize_t datalen = strlen(data);
  if (write(socket, data, datalen) < 0) {
    perror("write");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L18
L13:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %rax,-0x18(%rbp)
  addq   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(char *a) {
  char *b;
  for (; *a; a++)
    a = b++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L7
L2:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L2
L7:
  ret
```

assistant: ```c
void foo(char *a) {
  char *b;
  for (; *a; a++)
    a = b++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  nopl   0x0(%rax)
L8:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L8
L9:
  ret
```

assistant: ```c
void foo(char *a) {
  char *b;
  for (; *a; a++)
    a = b++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  nopl   0x0(%rax)
L16:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L16
L19:
  ret
```

assistant: ```c
void foo(char *a) {
  char *b;
  for (; *a; a++)
    a = b++;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L5
  movl   $0xfa0,-0x4(%rbp)
  jmp    L18
L5:
  cmpl   $0x2,-0x14(%rbp)
  jne    L6
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L18
L6:
  mov    $0x1,%eax
  jmp    L45
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <startServer@plt>
L45:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int port;
  if (argc < 2)
    port = 4000;
  else if (argc == 2)
    port = atoi(argv[1]);
  else
    return 1;
  return startServer(port);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L16
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jne    L13
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  jmp    L1
L16:
  mov    $0xfa0,%edi
L1:
  call   <startServer@plt>
L13:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int port;
  if (argc < 2)
    port = 4000;
  else if (argc == 2)
    port = atoi(argv[1]);
  else
    return 1;
  return startServer(port);
}
```