ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rawBlock>:
  endbr64
  push   %r15
  lea    D0(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  lea    0x10(%rbx),%rbp
  sub    $0x18,%rsp
  call   <checkBatch@plt>
  lea    0x1010(%rbx),%rax
  mov    %rbp,(%rsp)
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L0:
  mov    %ebp,%esi
  mov    %r15,%rdi
  sub    (%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rbx
  mov    %rbx,%r13
  xchg   %ax,%ax
L19:
  movzbl 0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L19
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L9
  nopl   0x0(%rax)
L17:
  mov    $0x2e,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  je     L61
L9:
  movzbl (%rbx),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%al
  ja     L17
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%edi
  call   <checkBatch@plt>
  test   %rax,%rax
  jne    L64
  add    $0x10,%rbp
  cmp    0x8(%rsp),%rbp
  jne    L0
L64:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D16
type_guessed: string

tool: D0: %04X   

tool: D15:    

tool: D16: %02X 

assistant: ```c
void rawBlock(unsigned char *p) {
  int i, j;
  unsigned char c;
  checkBatch(0);
  for (i = 0; i < 4096 / 16; i++) {
    printf("%04X   ", i * 16);
    for (j = 0; j < 16; j++) {
      c = p[i * 16 + j];
      printf("%02X ", c);
    }
    printf("   ");
    for (j = 0; j < 16; j++) {
      c = p[i * 16 + j];
      if (c < 0x20 || c >= 0x7F) {
        printf(".");
      } else {
        printf("%c", c);
      }
    }
    printf("\n");
    if (checkBatch(1))
      return;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L4
  mov    $0x1,%eax
  jmp    L11
L4:
  mov    $0x0,%eax
  call   <loop@plt>
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv __attribute__((unused))) {
  if (argc > 1)
    return 1;
  loop();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L2
  ret
L2:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <loop@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv __attribute__((unused))) {
  if (argc > 1)
    return 1;
  loop();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  mov    $0x1,%eax
  ret
L7:
  push   %rax
  xor    %eax,%eax
  call   <loop@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

assistant: ```c
int main(int argc, char **argv __attribute__((unused))) {
  if (argc > 1)
    return 1;
  loop();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L8
  mov    $0x1,%eax
  ret
L8:
  push   %rax
  xor    %eax,%eax
  call   <loop@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

assistant: ```c
int main(int argc, char **argv __attribute__((unused))) {
  if (argc > 1)
    return 1;
  loop();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x2,-0x4(%rbp)
L2:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: *

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 2;
  do {
    printf("*");
    x--;
  } while ((!x) == 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: D4: *

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 2;
  do {
    printf("*");
    x--;
  } while ((!x) == 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: *

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 2;
  do {
    printf("*");
    x--;
  } while ((!x) == 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: *

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 2;
  do {
    printf("*");
    x--;
  } while ((!x) == 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<multiply384>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L27
L4:
  movl   $0x0,-0x3c(%rbp)
  jmp    L29
L25:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L29:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L25
  addl   $0x1,-0x40(%rbp)
L27:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L4
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply384(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multiply384>:
  endbr64
  test   %edi,%edi
  jle    L15
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L27:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L4:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L4
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L27
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  ret
```

assistant: ```c
void multiply384(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply384>:
  endbr64
  test   %edi,%edi
  jle    L21
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L20
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L29
  pop    %rbx
  ret
L21:
  ret
```

assistant: ```c
void multiply384(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<multiply384>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L55
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L19:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L43
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L43
  nopl   0x0(%rax)
L9:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L9
  cmp    -0x24(%rsp),%r11d
  je     L77
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L77
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L77
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L77:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L19
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L43:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L94:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L94
  mov    -0x18(%rsp),%r8
  jmp    L77
```

assistant: ```c
void multiply384(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<qsort_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  jmp    L21
L14:
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edi
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x24(%rbp),%eax
  mov    -0x4(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    -0x28(%rbp),%edx
  sub    %ecx,%edx
  cmp    %edx,%eax
  jge    L36
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <qsort_arr>
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  jmp    L21
L36:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <qsort_arr>
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x28(%rbp)
L21:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jg     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void qsort_arr(char *a[], char *b[], int left, int right) {
  while (right > left) {
    int p = left + (right - left) / 2;
    p = partition(a, b, left, right, p);
    if ((p - 1) - left < right - (p + 1)) {
      qsort_arr(a, b, left, p - 1);
      left = p + 1;
    } else {
      qsort_arr(a, b, p + 1, right);
      right = p - 1;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qsort_arr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %ecx,%ebp
  cmp    %ecx,%edx
  jl     L19
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %ebp,%ecx
  mov    %r15d,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <qsort_arr>
  mov    %r14d,%ebp
L35:
  cmp    %ebp,%ebx
  jge    L32
L19:
  mov    %ebp,%eax
  sub    %ebx,%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  add    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <partition@plt>
  lea    -0x1(%rax),%r14d
  lea    0x1(%rax),%r15d
  mov    %r14d,%edx
  sub    %ebx,%edx
  mov    %ebp,%eax
  sub    %r15d,%eax
  cmp    %eax,%edx
  jge    L4
  mov    %r14d,%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <qsort_arr>
  mov    %r15d,%ebx
  jmp    L35
```

assistant: ```c
void qsort_arr(char *a[], char *b[], int left, int right) {
  while (right > left) {
    int p = left + (right - left) / 2;
    p = partition(a, b, left, right, p);
    if ((p - 1) - left < right - (p + 1)) {
      qsort_arr(a, b, left, p - 1);
      left = p + 1;
    } else {
      qsort_arr(a, b, p + 1, right);
      right = p - 1;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<qsort_arr>:
  endbr64
  cmp    %ecx,%edx
  jge    L39
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
L26:
  mov    %r14d,%r8d
  mov    %r13d,%edx
  mov    %r14d,%ecx
  mov    %rbx,%rsi
  sub    %r13d,%r8d
  mov    %rbp,%rdi
  sar    %r8d
  add    %r13d,%r8d
  call   <partition@plt>
  lea    -0x1(%rax),%r15d
  lea    0x1(%rax),%r12d
  mov    %r14d,%eax
  mov    %r15d,%edx
  sub    %r12d,%eax
  sub    %r13d,%edx
  cmp    %eax,%edx
  jge    L21
  mov    %r13d,%edx
  mov    %r15d,%ecx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <qsort_arr>
  mov    %r12d,%r13d
L10:
  cmp    %r14d,%r13d
  jl     L26
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r14d,%ecx
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <qsort_arr>
  mov    %r15d,%r14d
  jmp    L10
  xchg   %ax,%ax
L39:
  ret
```

assistant: ```c
void qsort_arr(char *a[], char *b[], int left, int right) {
  while (right > left) {
    int p = left + (right - left) / 2;
    p = partition(a, b, left, right, p);
    if ((p - 1) - left < right - (p + 1)) {
      qsort_arr(a, b, left, p - 1);
      left = p + 1;
    } else {
      qsort_arr(a, b, p + 1, right);
      right = p - 1;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L88
L56:
  cmpl   $0x0,-0x10(%rbp)
  je     L35
  mov    -0x24(%rbp),%eax
  jmp    L61
L35:
  mov    -0x1c(%rbp),%eax
L61:
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L27
  mov    -0x24(%rbp),%eax
  jmp    L46
L27:
  mov    -0x18(%rbp),%eax
L46:
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x18(%rbp),%edx
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  add    %eax,-0x20(%rbp)
  addl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L88:
  mov    -0x24(%rbp),%eax
  test   %eax,%eax
  jne    L56
  cmpl   $0x0,-0x20(%rbp)
  je     L17
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  divss  %xmm1,%xmm0
  jmp    L42
L17:
  pxor   %xmm0,%xmm0
L42:
  movss  %xmm0,-0xc(%rbp)
  mov    -0xc(%rbp),%esi
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  movd   %esi,%xmm0
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string
name: read_data
arguments: data_tag: D19
type: string
name: read_data
arguments: data_tag: D31
type: string

tool: D0: Digite uma sequencia de numeros: 

tool: D19: %d

tool: D31: 
 Maior: %d
 Menor: %d
 Soma: %d
 Media: %.2f

assistant: ```c
main() {
  int soma = 0, maior = 0, menor = 0, numero, count = 0;
  float media = 0;
  int flag = 1;
  puts("Digite uma sequencia de numeros: ");
  scanf("%d", &numero);
  while (numero != 0) {
    maior = flag ? numero : maior;
    menor = flag ? numero : menor;
    maior = numero > maior ? numero : maior;
    menor = numero < menor ? numero : menor;
    soma += numero;
    count++;
    flag = 0;
    scanf("%d", &numero);
  }
  media = soma == 0 ? 0 : (float)soma / count;
  printf("\n Maior: %d\n Menor: %d\n Soma: %d\n Media: %.2f", maior, menor, soma, media);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L33
  mov    $0x1,%edx
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  lea    D9(%rip),%r14
L22:
  test   %edx,%edx
  cmovne %eax,%ebx
  cmovne %eax,%ebp
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  cmp    %eax,%ebp
  cmovg  %eax,%ebp
  add    %eax,%r12d
  add    $0x1,%r13d
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    $0x0,%edx
  test   %eax,%eax
  jne    L22
  pxor   %xmm0,%xmm0
  test   %r12d,%r12d
  je     L10
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r13d,%xmm1
  divss  %xmm1,%xmm0
L10:
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  mov    %eax,%ebp
  mov    %eax,%ebx
  mov    %eax,%r12d
  pxor   %xmm0,%xmm0
  jmp    L10
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D31
type: string
name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D29
type: string

tool: D31: Digite uma sequencia de numeros: 

tool: D9: %d

tool: D29: 
 Maior: %d
 Menor: %d
 Soma: %d
 Media: %.2f

assistant: ```c
main() {
  int soma = 0, maior = 0, menor = 0, numero, count = 0;
  float media = 0;
  int flag = 1;
  puts("Digite uma sequencia de numeros: ");
  scanf("%d", &numero);
  while (numero != 0) {
    maior = flag ? numero : maior;
    menor = flag ? numero : menor;
    maior = numero > maior ? numero : maior;
    menor = numero < menor ? numero : menor;
    soma += numero;
    count++;
    flag = 0;
    scanf("%d", &numero);
  }
  media = soma == 0 ? 0 : (float)soma / count;
  printf("\n Maior: %d\n Menor: %d\n Soma: %d\n Media: %.2f", maior, menor, soma, media);
}
```