ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<bftmap_example>:
  endbr64
  push   %r15
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <bftmap_create@plt>
  mov    %rax,%r13
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    $0x64,%edi
  mov    %eax,%r15d
  call   <malloc@plt>
  mov    %ebp,%ecx
  mov    $0x64,%esi
  add    $0x1,%ebp
  mov    %rax,%r12
  lea    D6(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %r12,%rcx
  mov    %r15d,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <bftmap_put@plt>
  cmp    $0x3e8,%ebp
  jne    L46
  mov    %r13,%rdi
  call   <bftree_count@plt>
  xor    %edi,%edi
  cmp    $0x3e8,%eax
  sete   %dil
  xor    %ebp,%ebp
  call   <assert@plt>
  mov    %r13,%rdi
  call   <bftree_get_iterator@plt>
  mov    %rax,%r12
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%ebp
L10:
  mov    %r12,%rdi
  call   <bftree_next@plt>
  test   %rax,%rax
  jne    L17
  mov    %r12,%rdi
  call   <bftree_free_iterator@plt>
  xor    %edi,%edi
  cmp    $0x3e8,%ebp
  sete   %dil
  xor    %ebp,%ebp
  call   <assert@plt>
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  add    $0x1,%ebp
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    %eax,%edx
  call   <bftmap_del@plt>
  cmp    $0x2710,%ebp
  jne    L56
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L4:
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  add    $0x1,%ebp
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    %eax,%edx
  call   <bftmap_get@plt>
  cmp    $0x3e8,%ebp
  jne    L4
  mov    %r13,%rdi
  call   <bftmap_free@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D17: key%d

tool: D6: val%d

assistant: ```c
void bftmap_example() {
  struct bftree *tree;
  int i, len;
  char buf[100];
  char *val;
  struct bftree_iterator *iter;
  int count;
  tree = bftmap_create();
  for (i = 0; i < 1000; i++) {
    len = snprintf(buf, 100, "key%d", i);
    val = malloc(100);
    snprintf(val, 100, "val%d", i);
    bftmap_put(tree, buf, len, val);
  }
  assert(bftree_count(tree) == 1000);
  count = 0;
  iter = bftree_get_iterator(tree);
  while (bftree_next(iter) != NULL)
    count++;
  bftree_free_iterator(iter);
  assert(count == 1000);
  for (i = 0; i < 10000; i++) {
    len = snprintf(buf, 100, "key%d", i);
    bftmap_del(tree, buf, len);
  }
  for (i = 0; i < 1000; i++) {
    len = snprintf(buf, 100, "key%d", i);
    bftmap_get(tree, buf, len);
  }
  bftmap_free(tree);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <read_length@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L18
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L18
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L9
L18:
  mov    $0xffffffff,%eax
  jmp    L30
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
L30:
  leave
  ret
```

assistant: ```c
int read_string(int file, char *s, int s_size) {
  int len;
  len = read_length(file);
  if (len < 0 || len > s_size - 1 || read(file, s, len) < len)
    return -1;
  s[len] = 0;
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%r13d
  call   <read_length@plt>
  test   %eax,%eax
  js     L44
  mov    %eax,%ebx
  cmp    %r13d,%eax
  jge    L44
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    %ebx,%eax
  jl     L16
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
L19:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  mov    $0xffffffff,%ebx
  jmp    L19
L16:
  mov    $0xffffffff,%ebx
  jmp    L19
```

assistant: ```c
int read_string(int file, char *s, int s_size) {
  int len;
  len = read_length(file);
  if (len < 0 || len > s_size - 1 || read(file, s, len) < len)
    return -1;
  s[len] = 0;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_string>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <read_length@plt>
  test   %eax,%eax
  js     L18
  mov    %eax,%r12d
  cmp    %r13d,%eax
  jge    L18
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    %r12d,%eax
  jl     L18
  movslq %r12d,%rax
  movb   $0x0,(%rbx,%rax,1)
L24:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  mov    $0xffffffff,%r12d
  jmp    L24
```

assistant: ```c
int read_string(int file, char *s, int s_size) {
  int len;
  len = read_length(file);
  if (len < 0 || len > s_size - 1 || read(file, s, len) < len)
    return -1;
  s[len] = 0;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_string>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <read_length@plt>
  test   %eax,%eax
  js     L24
  mov    %eax,%r12d
  cmp    %r13d,%eax
  jge    L24
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    %r12d,%eax
  jl     L24
  movslq %r12d,%rax
  movb   $0x0,(%rbx,%rax,1)
L1:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L24:
  mov    $0xffffffff,%r12d
  jmp    L1
```

assistant: ```c
int read_string(int file, char *s, int s_size) {
  int len;
  len = read_length(file);
  if (len < 0 || len > s_size - 1 || read(file, s, len) < len)
    return -1;
  s[len] = 0;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_dirname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L17:
  subq   $0x1,-0x8(%rbp)
L11:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L29
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L17
L29:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L27
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strndup@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L27:
  nop
  leave
  ret
```

assistant: ```c
void get_dirname(char **dirname, const char *path) {
  const char *s;
  *dirname = NULL;
  s = path + strlen(path);
  while (path < s && *s != '/') {
    s--;
  }
  if (path < s) {
    *dirname = strndup(path, (size_t)(s - path));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_dirname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movq   $0x0,(%rdi)
  mov    %rsi,%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  add    %rbx,%rsi
  cmp    %rsi,%rbx
  jae    L7
L17:
  cmpb   $0x2f,(%rsi)
  je     L11
  sub    $0x1,%rsi
  cmp    %rsi,%rbx
  jne    L17
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  cmp    %rsi,%rbx
  jae    L7
  sub    %rbx,%rsi
  mov    %rbx,%rdi
  call   <strndup@plt>
  mov    %rax,0x0(%rbp)
  jmp    L7
```

assistant: ```c
void get_dirname(char **dirname, const char *path) {
  const char *s;
  *dirname = NULL;
  s = path + strlen(path);
  while (path < s && *s != '/') {
    s--;
  }
  if (path < s) {
    *dirname = strndup(path, (size_t)(s - path));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<get_dirname>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movq   $0x0,(%rdi)
  mov    %rsi,%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  add    %rbp,%rsi
  cmp    %rsi,%rbp
  jb     L23
  jmp    L31
  nopl   0x0(%rax)
L46:
  sub    $0x1,%rsi
  cmp    %rsi,%rbp
  je     L31
L23:
  cmpb   $0x2f,(%rsi)
  jne    L46
  cmp    %rsi,%rbp
  jae    L31
  sub    %rbp,%rsi
  mov    %rbp,%rdi
  call   <strndup@plt>
  mov    %rax,(%rbx)
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void get_dirname(char **dirname, const char *path) {
  const char *s;
  *dirname = NULL;
  s = path + strlen(path);
  while (path < s && *s != '/') {
    s--;
  }
  if (path < s) {
    *dirname = strndup(path, (size_t)(s - path));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_dirname>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movq   $0x0,(%rdi)
  mov    %rsi,%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  add    %rbp,%rsi
  cmp    %rsi,%rbp
  jb     L41
  jmp    L2
  nopl   0x0(%rax)
L6:
  sub    $0x1,%rsi
  cmp    %rsi,%rbp
  je     L2
L41:
  cmpb   $0x2f,(%rsi)
  jne    L6
  cmp    %rsi,%rbp
  jae    L2
  sub    %rbp,%rsi
  mov    %rbp,%rdi
  call   <strndup@plt>
  mov    %rax,(%rbx)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void get_dirname(char **dirname, const char *path) {
  const char *s;
  *dirname = NULL;
  s = path + strlen(path);
  while (path < s && *s != '/') {
    s--;
  }
  if (path < s) {
    *dirname = strndup(path, (size_t)(s - path));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wcsutil_intEq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L45
  mov    $0x1,%eax
  jmp    L0
L45:
  cmpl   $0x0,-0x14(%rbp)
  jns    L126
  mov    $0x0,%eax
  jmp    L0
L126:
  cmpq   $0x0,-0x20(%rbp)
  jne    L92
  cmpq   $0x0,-0x28(%rbp)
  jne    L92
  mov    $0x1,%eax
  jmp    L0
L92:
  cmpq   $0x0,-0x20(%rbp)
  je     L94
  cmpq   $0x0,-0x28(%rbp)
  jne    L27
L94:
  mov    $0x0,%eax
  jmp    L0
L27:
  movl   $0x0,-0x4(%rbp)
  jmp    L78
L99:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L132
  mov    $0x0,%eax
  jmp    L0
L132:
  addl   $0x1,-0x4(%rbp)
  addq   $0x4,-0x20(%rbp)
  addq   $0x4,-0x28(%rbp)
L78:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L99
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int wcsutil_intEq(int nelem, const int *arr1, const int *arr2) {
  int i;
  if (nelem == 0)
    return 1;
  if (nelem < 0)
    return 0;
  if (arr1 == 0x0 && arr2 == 0x0)
    return 1;
  if (arr1 == 0x0 || arr2 == 0x0)
    return 0;
  for (i = 0; i < nelem; i++, arr1++, arr2++) {
    if (*arr1 != *arr2)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcsutil_intEq>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L36
  mov    $0x0,%eax
  js     L36
  mov    $0x1,%eax
  mov    %rsi,%rcx
  or     %rdx,%rcx
  je     L36
  test   %rsi,%rsi
  je     L8
  test   %rdx,%rdx
  je     L8
  mov    %edi,%edi
  mov    $0x0,%eax
L54:
  mov    (%rdx,%rax,4),%ecx
  cmp    %ecx,(%rsi,%rax,4)
  jne    L16
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L54
  mov    $0x1,%eax
  ret
L8:
  mov    $0x0,%eax
  ret
L16:
  mov    $0x0,%eax
L36:
  ret
```

assistant: ```c
int wcsutil_intEq(int nelem, const int *arr1, const int *arr2) {
  int i;
  if (nelem == 0)
    return 1;
  if (nelem < 0)
    return 0;
  if (arr1 == 0x0 && arr2 == 0x0)
    return 1;
  if (arr1 == 0x0 || arr2 == 0x0)
    return 0;
  for (i = 0; i < nelem; i++, arr1++, arr2++) {
    if (*arr1 != *arr2)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcsutil_intEq>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L64
  mov    $0x0,%eax
  js     L64
  mov    %rsi,%rcx
  mov    $0x1,%eax
  or     %rdx,%rcx
  je     L64
  test   %rsi,%rsi
  je     L22
  test   %rdx,%rdx
  je     L22
  movslq %edi,%rdi
  xor    %eax,%eax
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L62:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L66
L24:
  mov    (%rdx,%rax,4),%ecx
  cmp    %ecx,(%rsi,%rax,4)
  je     L62
L22:
  xor    %eax,%eax
L64:
  ret
  nopl   0x0(%rax)
L66:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wcsutil_intEq(int nelem, const int *arr1, const int *arr2) {
  int i;
  if (nelem == 0)
    return 1;
  if (nelem < 0)
    return 0;
  if (arr1 == 0x0 && arr2 == 0x0)
    return 1;
  if (arr1 == 0x0 || arr2 == 0x0)
    return 0;
  for (i = 0; i < nelem; i++, arr1++, arr2++) {
    if (*arr1 != *arr2)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wcsutil_intEq>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L74
  mov    $0x0,%eax
  js     L74
  mov    %rsi,%rcx
  mov    $0x1,%eax
  or     %rdx,%rcx
  je     L74
  test   %rsi,%rsi
  je     L33
  test   %rdx,%rdx
  je     L33
  movslq %edi,%rdi
  xor    %eax,%eax
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L45
L34:
  mov    (%rdx,%rax,4),%ecx
  cmp    %ecx,(%rsi,%rax,4)
  je     L8
L33:
  xor    %eax,%eax
L74:
  ret
  nopl   0x0(%rax)
L45:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wcsutil_intEq(int nelem, const int *arr1, const int *arr2) {
  int i;
  if (nelem == 0)
    return 1;
  if (nelem < 0)
    return 0;
  if (arr1 == 0x0 && arr2 == 0x0)
    return 1;
  if (arr1 == 0x0 || arr2 == 0x0)
    return 0;
  for (i = 0; i < nelem; i++, arr1++, arr2++) {
    if (*arr1 != *arr2)
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MyFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1c8,%esi
  mov    $0x7b,%edi
  call   <AddNum@plt>
  mov    %eax,-0x4(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void MyFunc() {
  int c;
  c = AddNum(123, 456);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MyFunc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1c8,%esi
  mov    $0x7b,%edi
  call   <AddNum@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MyFunc() {
  int c;
  c = AddNum(123, 456);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MyFunc>:
  endbr64
  mov    $0x1c8,%esi
  mov    $0x7b,%edi
  jmp    1050 <AddNum@plt>
```

assistant: ```c
void MyFunc() {
  int c;
  c = AddNum(123, 456);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MyFunc>:
  endbr64
  mov    $0x1c8,%esi
  mov    $0x7b,%edi
  jmp    1050 <AddNum@plt>
```

assistant: ```c
void MyFunc() {
  int c;
  c = AddNum(123, 456);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LedsP__Leds__led0On>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <LedsP__Led0__clr@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LedsP__Leds__led0On(void) {
  LedsP__Led0__clr();
  ;
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<LedsP__Leds__led0On>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <LedsP__Led0__clr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void LedsP__Leds__led0On(void) {
  LedsP__Led0__clr();
  ;
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LedsP__Leds__led0On>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <LedsP__Led0__clr@plt>
```

assistant: ```c
void LedsP__Leds__led0On(void) {
  LedsP__Led0__clr();
  ;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<LedsP__Leds__led0On>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <LedsP__Led0__clr@plt>
```

assistant: ```c
void LedsP__Leds__led0On(void) {
  LedsP__Led0__clr();
  ;
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %edx,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x7c(%rbp),%ecx
  mov    -0x80(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jg     L14
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L6
L14:
  mov    -0x7c(%rbp),%edx
  mov    -0x80(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
L6:
  mov    -0x78(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
char *delete (char *source, int index, int n) {
  char rest_str[100];
  if (strlen(source) <= index + n) {
    source[index] = '\0';
  } else {
    strcpy(rest_str, &source[index + n]);
    strcpy(&source[index], rest_str);
  }
  return (source);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<delete>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    (%rbx,%rbp,1),%edx
  cmp    %edx,%eax
  jg     L13
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
L23:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %r12,%rax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  movslq %edx,%rdx
  lea    (%r12,%rdx,1),%rsi
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  movslq %ebx,%rdi
  add    %r12,%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  jmp    L23
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *delete (char *source, int index, int n) {
  char rest_str[100];
  if (strlen(source) <= index + n) {
    source[index] = '\0';
  } else {
    strcpy(rest_str, &source[index + n]);
    strcpy(&source[index], rest_str);
  }
  return (source);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<delete>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    (%rbx,%rbp,1),%edx
  lea    (%r12,%rbx,1),%rbp
  cmp    %edx,%eax
  jg     L24
  movb   $0x0,0x0(%rbp)
L0:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x78,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  movslq %edx,%rdx
  mov    %rsp,%r13
  lea    (%r12,%rdx,1),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L0
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *delete (char *source, int index, int n) {
  char rest_str[100];
  if (strlen(source) <= index + n) {
    source[index] = '\0';
  } else {
    strcpy(rest_str, &source[index + n]);
    strcpy(&source[index], rest_str);
  }
  return (source);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<delete>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    (%rbx,%rbp,1),%edx
  lea    (%r12,%rbx,1),%rbp
  cmp    %edx,%eax
  jg     L5
  movb   $0x0,0x0(%rbp)
L14:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x78,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  movslq %edx,%rdx
  mov    %rsp,%r13
  lea    (%r12,%rdx,1),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L14
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *delete (char *source, int index, int n) {
  char rest_str[100];
  if (strlen(source) <= index + n) {
    source[index] = '\0';
  } else {
    strcpy(rest_str, &source[index + n]);
    strcpy(&source[index], rest_str);
  }
  return (source);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string
name: retrieve_data
arguments: tag: D44
type_guessed: string
name: retrieve_data
arguments: tag: D80
type_guessed: string
name: retrieve_data
arguments: tag: D85
type_guessed: string
name: retrieve_data
arguments: tag: D46
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D60
type_guessed: string
name: retrieve_data
arguments: tag: D49
type_guessed: string
name: retrieve_data
arguments: tag: D32
type_guessed: string
name: retrieve_data
arguments: tag: D94
type_guessed: string

tool: D6: xcp - by Q++ Studio 2013-11-1


tool: D44: description:cp with progress


tool: D80: synopsis: xcp [OPTIONS] src1 [src2 ... srcn] dest



tool: D85: [OPTIONS]


tool: D46: -r:recusive copy sub directories.


tool: D13: -f:force overwrite without prompt.


tool: D60: -q:quiet no warning/error message.


tool: D49: -d:demo,do not copy,output message only.


tool: D32: -v:verbos output.


tool: D94: -h:show usage message.


assistant: ```c
void usage() {
  printf("xcp - by Q++ Studio 2013-11-1\n");
  printf("description:cp with progress\n");
  printf("synopsis: xcp [OPTIONS] src1 [src2 ... srcn] dest\n\n");
  printf("[OPTIONS]\n");
  printf("-r:recusive copy sub directories.\n");
  printf("-f:force overwrite without prompt.\n");
  printf("-q:quiet no warning/error message.\n");
  printf("-d:demo,do not copy,output message only.\n");
  printf("-v:verbos output.\n");
  printf("-h:show usage message.\n");
}
```