user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x0,%ecx
  mov    $0x4ee728,%edx
L18:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L18
  mov    %ecx,%edx
  mov    $0x4ee728,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x6,%esi
  mov    $0x0,%ecx
  mov    $0x63427,%edx
L41:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L41
  mov    %ecx,%edx
  mov    $0x63427,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x6,%esi
  mov    $0x0,%ecx
  mov    $0x5a06e,%edx
L45:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L45
  mov    %ecx,%edx
  mov    $0x5a06e,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x7,%esi
  mov    $0x0,%ecx
  mov    $0x2427e6,%edx
L23:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L23
  mov    %ecx,%edx
  mov    $0x2427e6,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x7,%esi
  mov    $0x0,%ecx
  mov    $0x21507d,%edx
L27:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L27
  mov    %ecx,%edx
  mov    $0x21507d,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D36
type_infered: string

tool: D36: %d-%d


assistant: ```c
int main() {
  int num = 5170984, n = num;
  int rev = 0, revnum = 0;
  while (num != 0) {
    rev = num % 10;
    revnum = revnum * 10 + rev;
    num /= 10;
  }
  printf("%d-%d\n", n, revnum);
  printf("\n");
  n = num = 406567;
  rev = 0, revnum = 0;
  while (num != 0) {
    rev = num % 10;
    revnum = revnum * 10 + rev;
    num /= 10;
  }
  printf("%d-%d\n", n, revnum);
  printf("\n");
  n = num = 368750;
  rev = 0, revnum = 0;
  while (num != 0) {
    rev = num % 10;
    revnum = revnum * 10 + rev;
    num /= 10;
  }
  printf("%d-%d\n", n, revnum);
  printf("\n");
  n = num = 2369510;
  rev = 0, revnum = 0;
  while (num != 0) {
    rev = num % 10;
    revnum = revnum * 10 + rev;
    num /= 10;
  }
  printf("%d-%d\n", n, revnum);
  printf("\n");
  n = num = 2183293;
  rev = 0, revnum = 0;
  while (num != 0) {
    rev = num % 10;
    revnum = revnum * 10 + rev;
    num /= 10;
  }
  printf("%d-%d\n", n, revnum);
  return 0;
}
```