ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <copyptrs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  copyptrs(0, 0, 0, 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <copyptrs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  copyptrs(0, 0, 0, 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L60
  mov    $0x1,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L60:
  movl   $0x0,-0x1c(%rbp)
  jmp    L5
L9:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp),%edx
  mov    %edx,-0x10(%rbp,%rax,4)
  addl   $0x1,-0x1c(%rbp)
L5:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L9
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x5733c707,%eax
  jne    L16
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L16:
  movl   $0x0,-0x18(%rbp)
  jmp    L37
L36:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0xc(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L37:
  cmpl   $0x0,-0x18(%rbp)
  jle    L36
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D19: Call this program with %i arguments


tool: D4: You win!

tool: D18: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1463011079U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L36
L25:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <RandomFunc@plt>
  cmpl   $0x5733c707,0x4(%rsp)
  je     L46
L45:
  mov    0x4(%rsp),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  mov    $0x1,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L25
L46:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L45
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D6
type_infered: string

tool: D13: %u


tool: D15: Call this program with %i arguments


tool: D6: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1463011079U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L16
  lea    D9(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L16:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x5733c707,%esi
  je     L17
L7:
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L7
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D27
type: string
name: retrieve_data
arguments: label: D21
type: string

tool: D9: Call this program with %i arguments


tool: D27: %u


tool: D21: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1463011079U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L6
  lea    D29(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L6:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x5733c707,%esi
  je     L31
L4:
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L31:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L4
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D29
type_guessed: string
name: read_data
arguments: tag: D21
type_guessed: string
name: read_data
arguments: tag: D9
type_guessed: string

tool: D29: Call this program with %i arguments


tool: D21: %u


tool: D9: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1463011079U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cginocache_msie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D0: Cache-Control: private


tool: D13: Pragma: private


assistant: ```c
void cginocache_msie() {
  printf("Cache-Control: private\n");
  printf("Pragma: private\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cginocache_msie>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D11
type: string

tool: D1: Cache-Control: private


tool: D11: Pragma: private


assistant: ```c
void cginocache_msie() {
  printf("Cache-Control: private\n");
  printf("Pragma: private\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<cginocache_msie>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D15
data_type: string

tool: D9: Cache-Control: private


tool: D15: Pragma: private


assistant: ```c
void cginocache_msie() {
  printf("Cache-Control: private\n");
  printf("Pragma: private\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cginocache_msie>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D17
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D17: Cache-Control: private


tool: D5: Pragma: private


assistant: ```c
void cginocache_msie() {
  printf("Cache-Control: private\n");
  printf("Pragma: private\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fnv_64a_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L14:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x24(%rbp),%eax
  shl    $0x4,%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  shl    $0x5,%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  shl    $0x7,%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  shl    $0x8,%eax
  lea    (%rdx,%rax,1),%esi
  mov    $0x28,%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  add    %esi,%eax
  add    %eax,-0x24(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L14
  mov    -0x24(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t fnv_64a_buf(void *buf, size_t len, uint64_t hval) {
  unsigned char *bp = (unsigned char *)buf;
  unsigned char *be = bp + len;
  while (bp < be) {
    hval ^= (uint64_t)*bp++;
    hval += (hval << 1) + (hval << 4) + (hval << 5) + (hval << 7) + (hval << 8) + (hval << 40);
  }
  return hval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fnv_64a_buf>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%eax
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L6
L9:
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  xor    %edx,%eax
  lea    (%rax,%rax,8),%edi
  mov    %eax,%edx
  shl    $0x5,%edx
  lea    (%rdx,%rdi,2),%edx
  mov    %eax,%edi
  shl    $0x7,%edi
  add    %edi,%edx
  mov    %eax,%edi
  shl    $0x8,%edi
  add    %edi,%edx
  add    %edx,%eax
  cmp    %rcx,%rsi
  jne    L9
L6:
  ret
```

assistant: ```c
uint64_t fnv_64a_buf(void *buf, size_t len, uint64_t hval) {
  unsigned char *bp = (unsigned char *)buf;
  unsigned char *be = bp + len;
  while (bp < be) {
    hval ^= (uint64_t)*bp++;
    hval += (hval << 1) + (hval << 4) + (hval << 5) + (hval << 7) + (hval << 8) + (hval << 40);
  }
  return hval;
}
```
user: What is the c source code of the assembly code below?

```asm
<fnv_64a_buf>:
  endbr64
  add    %rdi,%rsi
  mov    %rdi,%rcx
  mov    %edx,%eax
  cmp    %rsi,%rdi
  jae    L10
  nopl   0x0(%rax)
L3:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  xor    %edx,%eax
  mov    %eax,%edx
  lea    (%rax,%rax,8),%edi
  shl    $0x5,%edx
  lea    (%rdx,%rdi,2),%edx
  mov    %eax,%edi
  shl    $0x7,%edi
  add    %edi,%edx
  mov    %eax,%edi
  shl    $0x8,%edi
  add    %edi,%edx
  add    %edx,%eax
  cmp    %rcx,%rsi
  jne    L3
L10:
  ret
```

assistant: ```c
uint64_t fnv_64a_buf(void *buf, size_t len, uint64_t hval) {
  unsigned char *bp = (unsigned char *)buf;
  unsigned char *be = bp + len;
  while (bp < be) {
    hval ^= (uint64_t)*bp++;
    hval += (hval << 1) + (hval << 4) + (hval << 5) + (hval << 7) + (hval << 8) + (hval << 40);
  }
  return hval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fnv_64a_buf>:
  endbr64
  add    %rdi,%rsi
  mov    %rdi,%rcx
  mov    %edx,%eax
  cmp    %rsi,%rdi
  jae    L8
  nopl   0x0(%rax)
L6:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  xor    %edx,%eax
  mov    %eax,%edx
  lea    (%rax,%rax,8),%edi
  shl    $0x5,%edx
  lea    (%rdx,%rdi,2),%edx
  mov    %eax,%edi
  shl    $0x7,%edi
  add    %edi,%edx
  mov    %eax,%edi
  shl    $0x8,%edi
  add    %edi,%edx
  add    %edx,%eax
  cmp    %rcx,%rsi
  jne    L6
L8:
  ret
```

assistant: ```c
uint64_t fnv_64a_buf(void *buf, size_t len, uint64_t hval) {
  unsigned char *bp = (unsigned char *)buf;
  unsigned char *be = bp + len;
  while (bp < be) {
    hval ^= (uint64_t)*bp++;
    hval += (hval << 1) + (hval << 4) + (hval << 5) + (hval << 7) + (hval << 8) + (hval << 40);
  }
  return hval;
}
```
user: What is the c source code of the assembly code below:

```asm
<cor2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L14
L39:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L20
L5:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  cmp    %eax,-0x24(%rbp)
  jle    L20
  addl   $0x1,-0x1c(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L5
L14:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jg     L39
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int cor2(int r, double *x, double *y, int n) {
  int result = 0;
  int i, j;
  double dx, dy;
  i = n;
  while (i-- > 0) {
    j = i;
    while (j-- > 0) {
      dx = (x[i] - x[j]);
      dy = (y[i] - y[j]);
      if (r > sqrt(dx * dx + dy * dy)) {
        result++;
      }
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<cor2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x8(%rsp)
  lea    -0x1(%rcx),%eax
  mov    %eax,0xc(%rsp)
  test   %ecx,%ecx
  jle    L36
  cltq
  lea    (%rsi,%rax,8),%r13
  lea    -0x8(%rdx,%rax,8),%r14
  mov    $0x0,%r12d
  jmp    L43
L18:
  lea    -0x8(%r13),%rbx
  lea    -0x10(%r13),%r15
  mov    0xc(%rsp),%eax
  shl    $0x3,%rax
  sub    %rax,%r15
  mov    %r14,%rbp
L20:
  movsd  0x0(%r13),%xmm0
  subsd  (%rbx),%xmm0
  movsd  0x8(%r14),%xmm1
  subsd  0x0(%rbp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  call   <sqrt@plt>
  cmp    0x8(%rsp),%eax
  setl   %al
  movzbl %al,%eax
  add    %eax,%r12d
  sub    $0x8,%rbx
  sub    $0x8,%rbp
  cmp    %r15,%rbx
  jne    L20
  sub    $0x8,%r13
  sub    $0x8,%r14
L43:
  subl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0xffffffff,%eax
  jne    L18
L10:
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    $0x0,%r12d
  jmp    L10
```

assistant: ```c
int cor2(int r, double *x, double *y, int n) {
  int result = 0;
  int i, j;
  double dx, dy;
  i = n;
  while (i-- > 0) {
    j = i;
    while (j-- > 0) {
      dx = (x[i] - x[j]);
      dy = (y[i] - y[j]);
      if (r > sqrt(dx * dx + dy * dy)) {
        result++;
      }
    }
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cor2>:
  endbr64
  push   %r15
  lea    -0x1(%rcx),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,(%rsp)
  mov    %eax,0x4(%rsp)
  test   %ecx,%ecx
  jle    L45
  cltq
  subl   $0x1,0x4(%rsp)
  xor    %r12d,%r12d
  lea    (%rsi,%rax,8),%r13
  lea    -0x8(%rdx,%rax,8),%r14
  mov    0x4(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L42
L35:
  mov    0x4(%rsp),%eax
  lea    -0x8(%r13),%r15
  lea    -0x10(%r13),%rbx
  mov    %r14,%rbp
  mov    %r15,0x8(%rsp)
  shl    $0x3,%rax
  sub    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L32:
  movsd  0x0(%r13),%xmm0
  movsd  0x8(%r14),%xmm1
  subsd  (%r15),%xmm0
  subsd  0x0(%rbp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  call   <sqrt@plt>
  cmp    (%rsp),%eax
  setl   %al
  sub    $0x8,%r15
  sub    $0x8,%rbp
  movzbl %al,%eax
  add    %eax,%r12d
  cmp    %rbx,%r15
  jne    L32
  subl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  sub    $0x8,%r14
  mov    0x8(%rsp),%r13
  cmp    $0xffffffff,%eax
  jne    L35
L42:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  xor    %r12d,%r12d
  jmp    L42
```

assistant: ```c
int cor2(int r, double *x, double *y, int n) {
  int result = 0;
  int i, j;
  double dx, dy;
  i = n;
  while (i-- > 0) {
    j = i;
    while (j-- > 0) {
      dx = (x[i] - x[j]);
      dy = (y[i] - y[j]);
      if (r > sqrt(dx * dx + dy * dy)) {
        result++;
      }
    }
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cor2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %ecx,%ecx
  jle    L40
  lea    -0x2(%rcx),%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%ecx
  jle    L40
  mov    %edi,%r13d
  mov    %rsi,%r15
  mov    %rdx,%r14
  movslq %eax,%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L46:
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L32:
  movsd  0x8(%r15,%rbp,8),%xmm0
  movsd  0x8(%r14,%rbp,8),%xmm1
  subsd  (%r15,%rbx,8),%xmm0
  subsd  (%r14,%rbx,8),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  call   <sqrt@plt>
  cmp    %r13d,%eax
  setl   %al
  sub    $0x1,%rbx
  movzbl %al,%eax
  add    %eax,%r12d
  lea    0x1(%rbx),%eax
  test   %eax,%eax
  jg     L32
  subl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  sub    $0x1,%rbp
  cmp    $0xffffffff,%eax
  jne    L46
L15:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  xor    %r12d,%r12d
  jmp    L15
```

assistant: ```c
int cor2(int r, double *x, double *y, int n) {
  int result = 0;
  int i, j;
  double dx, dy;
  i = n;
  while (i-- > 0) {
    j = i;
    while (j-- > 0) {
      dx = (x[i] - x[j]);
      dy = (y[i] - y[j]);
      if (r > sqrt(dx * dx + dy * dy)) {
        result++;
      }
    }
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L34
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jge    L72
  mov    $0xffffffff,%eax
  jmp    L11
L72:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jle    L34
  mov    $0x1,%eax
  jmp    L11
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L44
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L44:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    $0xffffffff,%eax
  jmp    L11
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  mov    $0x1,%eax
  jmp    L11
L29:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    char c1 = *s1++;
    char c2 = *s2++;
    if (c1 < c2)
      return -1;
    else if (c1 > c2)
      return 1;
  }
  if (*s2)
    return -1;
  else if (*s1)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
L22:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L60
  add    $0x1,%rdi
  add    $0x1,%rsi
  cmp    %dl,%al
  jl     L31
  jle    L22
  mov    $0x1,%edx
  jmp    L32
L16:
  movzbl (%rsi),%eax
  mov    $0xffffffff,%edx
  test   %al,%al
  jne    L32
L60:
  test   %al,%al
  setne  %dl
  movzbl %dl,%edx
L32:
  mov    %edx,%eax
  ret
L31:
  mov    $0xffffffff,%edx
  jmp    L32
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    char c1 = *s1++;
    char c2 = *s2++;
    if (c1 < c2)
      return -1;
    else if (c1 > c2)
      return 1;
  }
  if (*s2)
    return -1;
  else if (*s1)
    return 1;
  else
    return 0;
}
```