ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<ximage_convert_rgb555>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L22:
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L33:
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0xb(%rbp),%eax
  shl    $0x7,%eax
  and    $0x7c00,%ax
  mov    %eax,%edx
  movzbl -0xa(%rbp),%eax
  shl    $0x2,%eax
  and    $0x3e0,%ax
  or     %eax,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L33
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ximage_convert_rgb555(const unsigned char *__restrict src, int srcstride, unsigned char *__restrict dst, int dststride, int w, int h) {
  unsigned char r, g, b;
  int x, y;
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++) {
      r = src[4 * x + 0];
      g = src[4 * x + 1];
      b = src[4 * x + 2];
      ((unsigned short *)dst)[x] = ((r & 0xF8) << 7) | ((g & 0xF8) << 2) | (b >> 3);
    }
    src += srcstride;
    dst += dststride;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ximage_convert_rgb555>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%eax
  mov    %rdx,%rsi
  mov    %r8d,%ebx
  mov    %r9d,%ebp
  mov    $0x0,%r11d
  mov    %r8d,%r10d
  movslq %eax,%r9
  movslq %ecx,%r8
  test   %ebp,%ebp
  jg     L1
L45:
  pop    %rbx
  pop    %rbp
  ret
L34:
  movzbl (%rdi,%rdx,4),%eax
  shl    $0x7,%eax
  and    $0x7c00,%ax
  movzbl 0x1(%rdi,%rdx,4),%ecx
  shl    $0x2,%ecx
  and    $0x3e0,%cx
  or     %ecx,%eax
  movzbl 0x2(%rdi,%rdx,4),%ecx
  shr    $0x3,%cl
  movzbl %cl,%ecx
  or     %ecx,%eax
  mov    %ax,(%rsi,%rdx,2)
  add    $0x1,%rdx
  cmp    %rdx,%r10
  jne    L34
L15:
  add    %r9,%rdi
  add    %r8,%rsi
  add    $0x1,%r11d
  cmp    %r11d,%ebp
  je     L45
L1:
  mov    $0x0,%edx
  test   %ebx,%ebx
  jg     L34
  jmp    L15
```

assistant: ```c
void ximage_convert_rgb555(const unsigned char *__restrict src, int srcstride, unsigned char *__restrict dst, int dststride, int w, int h) {
  unsigned char r, g, b;
  int x, y;
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++) {
      r = src[4 * x + 0];
      g = src[4 * x + 1];
      b = src[4 * x + 2];
      ((unsigned short *)dst)[x] = ((r & 0xF8) << 7) | ((g & 0xF8) << 2) | (b >> 3);
    }
    src += srcstride;
    dst += dststride;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ximage_convert_rgb555>:
  endbr64
  test   %r9d,%r9d
  jle    L26
  push   %rbp
  mov    %rdx,%r10
  mov    %r9d,%ebp
  xor    %r11d,%r11d
  push   %rbx
  mov    %r8d,%ebx
  movslq %esi,%r9
  movslq %ecx,%r8
  movslq %ebx,%rsi
L20:
  xor    %edx,%edx
  test   %ebx,%ebx
  jle    L4
  cs nopw 0x0(%rax,%rax,1)
L34:
  movzbl (%rdi,%rdx,4),%eax
  movzbl 0x1(%rdi,%rdx,4),%ecx
  shl    $0x7,%eax
  shl    $0x2,%ecx
  and    $0x3e0,%cx
  and    $0x7c00,%ax
  or     %ecx,%eax
  movzbl 0x2(%rdi,%rdx,4),%ecx
  shr    $0x3,%cl
  movzbl %cl,%ecx
  or     %ecx,%eax
  mov    %ax,(%r10,%rdx,2)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L34
L4:
  add    $0x1,%r11d
  add    %r9,%rdi
  add    %r8,%r10
  cmp    %r11d,%ebp
  jne    L20
  pop    %rbx
  pop    %rbp
  ret
L26:
  ret
```

assistant: ```c
void ximage_convert_rgb555(const unsigned char *__restrict src, int srcstride, unsigned char *__restrict dst, int dststride, int w, int h) {
  unsigned char r, g, b;
  int x, y;
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++) {
      r = src[4 * x + 0];
      g = src[4 * x + 1];
      b = src[4 * x + 2];
      ((unsigned short *)dst)[x] = ((r & 0xF8) << 7) | ((g & 0xF8) << 2) | (b >> 3);
    }
    src += srcstride;
    dst += dststride;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L11:
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x30,%rax
  mov    %rax,%rdi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void print(uint8_t *signal, int offset, int n) {
  for (int i = 0; i < n; i++) {
    putchar('0' + signal[offset + i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print>:
  endbr64
  test   %edx,%edx
  jle    L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rbx
  lea    -0x1(%rdx),%eax
  add    %rsi,%rax
  lea    0x8(%rdi,%rax,8),%rbp
L3:
  mov    (%rbx),%rax
  lea    0x30(%rax),%rdi
  call   <putchar@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
void print(uint8_t *signal, int offset, int n) {
  for (int i = 0; i < n; i++) {
    putchar('0' + signal[offset + i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print>:
  endbr64
  test   %edx,%edx
  jle    L13
  push   %rbp
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  push   %rbx
  add    %rsi,%rax
  lea    (%rdi,%rsi,8),%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  sub    $0x8,%rsp
L4:
  mov    (%rbx),%rax
  add    $0x8,%rbx
  lea    0x30(%rax),%rdi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L13:
  ret
```

assistant: ```c
void print(uint8_t *signal, int offset, int n) {
  for (int i = 0; i < n; i++) {
    putchar('0' + signal[offset + i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print>:
  endbr64
  test   %edx,%edx
  jle    L14
  push   %rbp
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  push   %rbx
  add    %rsi,%rax
  lea    (%rdi,%rsi,8),%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  sub    $0x8,%rsp
L17:
  mov    (%rbx),%rax
  add    $0x8,%rbx
  lea    0x30(%rax),%rdi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
void print(uint8_t *signal, int offset, int n) {
  for (int i = 0; i < n; i++) {
    putchar('0' + signal[offset + i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L69
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L22
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L56
L22:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L56
L69:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L48
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L56
L48:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L56:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D47
type: string
name: parse_data
arguments: tag: D50
type: string
name: parse_data
arguments: tag: D52
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D36
type: string
name: parse_data
arguments: tag: D14
type: string

tool: D47: enter the numbers:

tool: D50: %d%d%d

tool: D52: num1 %d is greater


tool: D11: num3 %d is greater


tool: D36: num2 %d is greater


tool: D14: num3 %d is greater 


assistant: ```c
int main(int argc, char const *argv[]) {
  int num1, num2, num3;
  printf("enter the numbers:\n");
  scanf("%d%d%d", &num1, &num2, &num3);
  if (num1 > num2) {
    if (num1 > num3) {
      printf("num1 %d is greater\n", num1);
    } else {
      printf("num3 %d is greater\n", num3);
    }
  } else {
    if (num2 > num3) {
      printf("num2 %d is greater\n", num2);
    } else {
      printf("num3 %d is greater \n", num3);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jle    L18
  mov    0x14(%rsp),%esi
  cmp    %esi,%eax
  jle    L57
  mov    %eax,%esi
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L30:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L57:
  lea    D52(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L30
L18:
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  jle    L11
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L30
L11:
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L30
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D46
datatype: string
name: extract_symbolic_data
arguments: tag: D20
datatype: string
name: extract_symbolic_data
arguments: tag: D41
datatype: string
name: extract_symbolic_data
arguments: tag: D52
datatype: string
name: extract_symbolic_data
arguments: tag: D53
datatype: string
name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D46: enter the numbers:

tool: D20: %d%d%d

tool: D41: num1 %d is greater


tool: D52: num3 %d is greater


tool: D53: num2 %d is greater


tool: D6: num3 %d is greater 


assistant: ```c
int main(int argc, char const *argv[]) {
  int num1, num2, num3;
  printf("enter the numbers:\n");
  scanf("%d%d%d", &num1, &num2, &num3);
  if (num1 > num2) {
    if (num1 > num3) {
      printf("num1 %d is greater\n", num1);
    } else {
      printf("num3 %d is greater\n", num3);
    }
  } else {
    if (num2 > num3) {
      printf("num2 %d is greater\n", num2);
    } else {
      printf("num3 %d is greater \n", num3);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    0x10(%rsp),%esi
  cmp    %esi,%r8d
  jle    L21
  mov    0x14(%rsp),%esi
  cmp    %esi,%r8d
  jle    L17
  mov    %r8d,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
L21:
  mov    0x14(%rsp),%r8d
  cmp    %r8d,%esi
  jg     L50
  mov    %r8d,%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L50:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
L17:
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D34
type: string
name: unpack_data
arguments: label: D5
type: string
name: unpack_data
arguments: label: D33
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D20
type: string

tool: D10: enter the numbers:

tool: D34: %d%d%d

tool: D5: num1 %d is greater


tool: D33: num3 %d is greater 


tool: D23: num2 %d is greater


tool: D20: num3 %d is greater


assistant: ```c
int main(int argc, char const *argv[]) {
  int num1, num2, num3;
  printf("enter the numbers:\n");
  scanf("%d%d%d", &num1, &num2, &num3);
  if (num1 > num2) {
    if (num1 > num3) {
      printf("num1 %d is greater\n", num1);
    } else {
      printf("num3 %d is greater\n", num3);
    }
  } else {
    if (num2 > num3) {
      printf("num2 %d is greater\n", num2);
    } else {
      printf("num3 %d is greater \n", num3);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D41(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    0x10(%rsp),%esi
  cmp    %esi,%r8d
  jle    L0
  mov    0x14(%rsp),%esi
  cmp    %esi,%r8d
  jle    L29
  mov    %r8d,%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L42
L0:
  mov    0x14(%rsp),%r8d
  cmp    %r8d,%esi
  jg     L11
  mov    %r8d,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L11:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L42
L29:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L42
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D41
type_guessed: string
name: parse_data
arguments: tag: D50
type_guessed: string
name: parse_data
arguments: tag: D30
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string

tool: D41: enter the numbers:

tool: D50: %d%d%d

tool: D30: num1 %d is greater


tool: D1: num3 %d is greater 


tool: D2: num2 %d is greater


tool: D17: num3 %d is greater


assistant: ```c
int main(int argc, char const *argv[]) {
  int num1, num2, num3;
  printf("enter the numbers:\n");
  scanf("%d%d%d", &num1, &num2, &num3);
  if (num1 > num2) {
    if (num1 > num3) {
      printf("num1 %d is greater\n", num1);
    } else {
      printf("num3 %d is greater\n", num3);
    }
  } else {
    if (num2 > num3) {
      printf("num2 %d is greater\n", num2);
    } else {
      printf("num3 %d is greater \n", num3);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <usage@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D5: cmail-admin-permissions

assistant: ```c
int help(int argc, char *argv[], void *__attribute__((unused)) config) {
  usage("cmail-admin-permissions");
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <usage@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: cmail-admin-permissions

assistant: ```c
int help(int argc, char *argv[], void *__attribute__((unused)) config) {
  usage("cmail-admin-permissions");
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <usage@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: cmail-admin-permissions

assistant: ```c
int help(int argc, char *argv[], void *__attribute__((unused)) config) {
  usage("cmail-admin-permissions");
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <usage@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: cmail-admin-permissions

assistant: ```c
int help(int argc, char *argv[], void *__attribute__((unused)) config) {
  usage("cmail-admin-permissions");
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<PWMPulseWidthSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0xffffffc0,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rax),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L6
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1c(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  add    $0x10,%eax
  cltq
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L17
  mov    -0x8(%rbp),%eax
  add    $0x1c,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L14
L17:
  mov    -0x8(%rbp),%eax
  add    $0x18,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L14:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PWMPulseWidthSet(uint32_t ui32Base, uint32_t ui32PWMOut, uint32_t ui32Width) {
  uint32_t ui32GenBase, ui32Reg;
  ;
  ;
  ui32GenBase = ((ui32Base) + ((ui32PWMOut)&0xFFFFFFC0));
  if ((*((volatile uint32_t *)(ui32GenBase + 0x00000000))) & 0x00000002) {
    ui32Width /= 2;
  }
  ui32Reg = (*((volatile uint32_t *)(ui32GenBase + 0x00000010)));
  ;
  ui32Reg = ui32Reg - ui32Width;
  if (((ui32PWMOut)&0x00000001)) {
    (*((volatile uint32_t *)(ui32GenBase + 0x0000001C))) = ui32Reg;
  } else {
    (*((volatile uint32_t *)(ui32GenBase + 0x00000018))) = ui32Reg;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PWMPulseWidthSet>:
  endbr64
  mov    %esi,%eax
  and    $0xffffffc0,%eax
  add    %edi,%eax
  movslq %eax,%rcx
  mov    (%rcx),%ecx
  test   $0x2,%cl
  je     L0
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  sar    %edx
L0:
  lea    0x10(%rax),%ecx
  movslq %ecx,%rcx
  mov    (%rcx),%ecx
  sub    %edx,%ecx
  test   $0x1,%sil
  je     L15
  add    $0x1c,%eax
  cltq
  mov    %ecx,(%rax)
  ret
L15:
  add    $0x18,%eax
  cltq
  mov    %ecx,(%rax)
  ret
```

assistant: ```c
void PWMPulseWidthSet(uint32_t ui32Base, uint32_t ui32PWMOut, uint32_t ui32Width) {
  uint32_t ui32GenBase, ui32Reg;
  ;
  ;
  ui32GenBase = ((ui32Base) + ((ui32PWMOut)&0xFFFFFFC0));
  if ((*((volatile uint32_t *)(ui32GenBase + 0x00000000))) & 0x00000002) {
    ui32Width /= 2;
  }
  ui32Reg = (*((volatile uint32_t *)(ui32GenBase + 0x00000010)));
  ;
  ui32Reg = ui32Reg - ui32Width;
  if (((ui32PWMOut)&0x00000001)) {
    (*((volatile uint32_t *)(ui32GenBase + 0x0000001C))) = ui32Reg;
  } else {
    (*((volatile uint32_t *)(ui32GenBase + 0x00000018))) = ui32Reg;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<PWMPulseWidthSet>:
  endbr64
  mov    %esi,%eax
  and    $0xffffffc0,%eax
  add    %edi,%eax
  movslq %eax,%rcx
  mov    (%rcx),%ecx
  and    $0x2,%ecx
  je     L16
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  sar    %edx
L16:
  lea    0x10(%rax),%ecx
  movslq %ecx,%rcx
  mov    (%rcx),%ecx
  sub    %edx,%ecx
  and    $0x1,%esi
  je     L10
  add    $0x1c,%eax
  cltq
  mov    %ecx,(%rax)
  ret
  nopl   (%rax)
L10:
  add    $0x18,%eax
  cltq
  mov    %ecx,(%rax)
  ret
```

assistant: ```c
void PWMPulseWidthSet(uint32_t ui32Base, uint32_t ui32PWMOut, uint32_t ui32Width) {
  uint32_t ui32GenBase, ui32Reg;
  ;
  ;
  ui32GenBase = ((ui32Base) + ((ui32PWMOut)&0xFFFFFFC0));
  if ((*((volatile uint32_t *)(ui32GenBase + 0x00000000))) & 0x00000002) {
    ui32Width /= 2;
  }
  ui32Reg = (*((volatile uint32_t *)(ui32GenBase + 0x00000010)));
  ;
  ui32Reg = ui32Reg - ui32Width;
  if (((ui32PWMOut)&0x00000001)) {
    (*((volatile uint32_t *)(ui32GenBase + 0x0000001C))) = ui32Reg;
  } else {
    (*((volatile uint32_t *)(ui32GenBase + 0x00000018))) = ui32Reg;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PWMPulseWidthSet>:
  endbr64
  mov    %esi,%eax
  and    $0xffffffc0,%eax
  add    %edi,%eax
  movslq %eax,%rcx
  mov    (%rcx),%ecx
  and    $0x2,%ecx
  je     L14
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  sar    %edx
L14:
  lea    0x10(%rax),%ecx
  movslq %ecx,%rcx
  mov    (%rcx),%ecx
  sub    %edx,%ecx
  and    $0x1,%esi
  je     L15
  add    $0x1c,%eax
  cltq
  mov    %ecx,(%rax)
  ret
  nopl   (%rax)
L15:
  add    $0x18,%eax
  cltq
  mov    %ecx,(%rax)
  ret
```

assistant: ```c
void PWMPulseWidthSet(uint32_t ui32Base, uint32_t ui32PWMOut, uint32_t ui32Width) {
  uint32_t ui32GenBase, ui32Reg;
  ;
  ;
  ui32GenBase = ((ui32Base) + ((ui32PWMOut)&0xFFFFFFC0));
  if ((*((volatile uint32_t *)(ui32GenBase + 0x00000000))) & 0x00000002) {
    ui32Width /= 2;
  }
  ui32Reg = (*((volatile uint32_t *)(ui32GenBase + 0x00000010)));
  ;
  ui32Reg = ui32Reg - ui32Width;
  if (((ui32PWMOut)&0x00000001)) {
    (*((volatile uint32_t *)(ui32GenBase + 0x0000001C))) = ui32Reg;
  } else {
    (*((volatile uint32_t *)(ui32GenBase + 0x00000018))) = ui32Reg;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: romcc 0.80 released 18 November 2015


assistant: ```c
void version(FILE *fp) {
  fprintf(fp, "romcc "
              "0"
              "."
              "80"
              " released "
              "18 November 2015"
              "\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: romcc 0.80 released 18 November 2015


assistant: ```c
void version(FILE *fp) {
  fprintf(fp, "romcc "
              "0"
              "."
              "80"
              " released "
              "18 November 2015"
              "\n");
}
```