ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<checkCommand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L27
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  lea    D28(%rip),%r15
  lea    D1(%rip),%r14
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L66:
  mov    0x0(%rbp,%r13,8),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
L15:
  mov    0x0(%rbp,%r13,8),%rdi
  lea    D8(%rip),%rsi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  add    $0x1,%r13
  mov    0x0(%rbp,%r13,8),%rdi
  test   %rdi,%rdi
  je     L28
L23:
  mov    %r15,%rsi
  mov    %r13d,%r12d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L66
  mov    0x8(%rsp),%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  add    $0x1,%ebx
  call   <runIn@plt>
  jmp    L66
  nopl   (%rax)
L34:
  mov    0x8(%rsp),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  add    $0x1,%ebx
  call   <runOut@plt>
  jmp    L15
  nopl   (%rax)
L28:
  test   %ebx,%ebx
  je     L27
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <runCommand@plt>
```

tool_calls: name: parse_data
arguments: data_label: D28
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string

tool: D28: <

tool: D1: >

tool: D8: |

assistant: ```c
void checkCommand(char *command, char **args) {
  int i = 0;
  int check = 0;
  while (args[i] != NULL) {
    if (strcmp(args[i], "<") == 0) {
      check++;
      runIn(command, args, i);
    }
    if (strcmp(args[i], ">") == 0) {
      check++;
      runOut(command, args, i);
    }
    if (strcmp(args[i], "|") == 0) {
      check++;
    }
    i++;
  }
  if (check == 0) {
    runCommand(command, args);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checkCommand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L15
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  lea    D5(%rip),%r15
  lea    D12(%rip),%r14
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L11:
  mov    0x0(%rbp,%r13,8),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L69
L14:
  mov    0x0(%rbp,%r13,8),%rdi
  lea    D17(%rip),%rsi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  add    $0x1,%r13
  mov    0x0(%rbp,%r13,8),%rdi
  test   %rdi,%rdi
  je     L67
L78:
  mov    %r15,%rsi
  mov    %r13d,%r12d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L11
  mov    0x8(%rsp),%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  add    $0x1,%ebx
  call   <runIn@plt>
  jmp    L11
  nopl   (%rax)
L69:
  mov    0x8(%rsp),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  add    $0x1,%ebx
  call   <runOut@plt>
  jmp    L14
  nopl   (%rax)
L67:
  test   %ebx,%ebx
  je     L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <runCommand@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string
name: read_data
arguments: tag: D17
type_guessed: string

tool: D5: <

tool: D12: >

tool: D17: |

assistant: ```c
void checkCommand(char *command, char **args) {
  int i = 0;
  int check = 0;
  while (args[i] != NULL) {
    if (strcmp(args[i], "<") == 0) {
      check++;
      runIn(command, args, i);
    }
    if (strcmp(args[i], ">") == 0) {
      check++;
      runOut(command, args, i);
    }
    if (strcmp(args[i], "|") == 0) {
      check++;
    }
    i++;
  }
  if (check == 0) {
    runCommand(command, args);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<process_message_channel_data_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int process_message_channel_data_response(struct stream *s) {
  {
    if (10 < 5) {
      g_write("xrdp-chansrv [%10.10u]: ", g_time3());
      g_writeln("process_message_channel_data_response:");
    }
  };
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<process_message_channel_data_response>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int process_message_channel_data_response(struct stream *s) {
  {
    if (10 < 5) {
      g_write("xrdp-chansrv [%10.10u]: ", g_time3());
      g_writeln("process_message_channel_data_response:");
    }
  };
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<process_message_channel_data_response>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int process_message_channel_data_response(struct stream *s) {
  {
    if (10 < 5) {
      g_write("xrdp-chansrv [%10.10u]: ", g_time3());
      g_writeln("process_message_channel_data_response:");
    }
  };
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<process_message_channel_data_response>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int process_message_channel_data_response(struct stream *s) {
  {
    if (10 < 5) {
      g_write("xrdp-chansrv [%10.10u]: ", g_time3());
      g_writeln("process_message_channel_data_response:");
    }
  };
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movl   $0x1,-0x60(%rbp)
  movl   $0x2,-0x5c(%rbp)
  movl   $0x3,-0x58(%rbp)
  movl   $0x3,-0x68(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x3,-0x64(%rbp)
  mov    -0x64(%rbp),%esi
  lea    -0x30(%rbp),%rcx
  mov    -0x68(%rbp),%edx
  lea    -0x60(%rbp),%rax
  mov    %esi,%r9d
  mov    $0x3,%r8d
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <merge@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L4
L9:
  mov    -0x6c(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x6c(%rbp)
L4:
  mov    -0x68(%rbp),%edx
  mov    -0x64(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x6c(%rbp)
  jl     L9
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: %d


assistant: ```c
int main() {
  int nums1[10] = {1, 2, 3, 0, 0, 0}, m = 3;
  int nums2[10] = {2, 5, 6}, n = 3;
  merge(nums1, 6, m, nums2, 3, n);
  for (int i = 0; i < m + n; i++) {
    printf("%d\n", nums1[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movl   $0x2,0x30(%rsp)
  movl   $0x5,0x34(%rsp)
  movl   $0x6,0x38(%rsp)
  lea    0x30(%rsp),%rcx
  mov    %rsp,%rbx
  mov    $0x3,%r9d
  mov    $0x3,%r8d
  mov    $0x3,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <merge@plt>
  lea    0x18(%rsp),%r12
  lea    D8(%rip),%rbp
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D8: %d


assistant: ```c
int main() {
  int nums1[10] = {1, 2, 3, 0, 0, 0}, m = 3;
  int nums2[10] = {2, 5, 6}, n = 3;
  merge(nums1, 6, m, nums2, 3, n);
  for (int i = 0; i < m + n; i++) {
    printf("%d\n", nums1[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x3,%edx
  mov    $0x6,%esi
  push   %rbp
  mov    $0x3,%r9d
  mov    $0x3,%r8d
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%rcx
  movups %xmm0,0x8(%rsp)
  mov    %rbx,%rdi
  movups %xmm0,0x38(%rsp)
  lea    0x18(%rsp),%r12
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x2,0x30(%rsp)
  movl   $0x5,0x34(%rsp)
  movl   $0x6,0x38(%rsp)
  movups %xmm0,0x18(%rsp)
  movups %xmm0,0x48(%rsp)
  call   <merge@plt>
  nopl   (%rax)
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: %d


assistant: ```c
int main() {
  int nums1[10] = {1, 2, 3, 0, 0, 0}, m = 3;
  int nums2[10] = {2, 5, 6}, n = 3;
  merge(nums1, 6, m, nums2, 3, n);
  for (int i = 0; i < m + n; i++) {
    printf("%d\n", nums1[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x3,%edx
  mov    $0x6,%esi
  push   %rbp
  mov    $0x3,%r9d
  mov    $0x3,%r8d
  lea    D24(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%rcx
  movups %xmm0,0x8(%rsp)
  mov    D29(%rip),%rax
  mov    %rbx,%rdi
  movups %xmm0,0x38(%rsp)
  lea    0x18(%rsp),%r12
  movl   $0x3,0x8(%rsp)
  mov    %rax,(%rsp)
  mov    D11(%rip),%rax
  movl   $0x6,0x38(%rsp)
  mov    %rax,0x30(%rsp)
  movups %xmm0,0x18(%rsp)
  movups %xmm0,0x48(%rsp)
  call   <merge@plt>
  nopl   (%rax)
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
type_guessed: string
name: retrieve_data
arguments: tag: D29
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D11
type_guessed: byte[8]

tool: D24: %d


tool: {"D29": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D11": [0x02,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int nums1[10] = {1, 2, 3, 0, 0, 0}, m = 3;
  int nums2[10] = {2, 5, 6}, n = 3;
  merge(nums1, 6, m, nums2, 3, n);
  for (int i = 0; i < m + n; i++) {
    printf("%d\n", nums1[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0xdead,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void crash() {
  int *die_sweetie_die = NULL;
  *die_sweetie_die = 0xdead;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<crash>:
  endbr64
  movl   $0xdead,0x0
  ret
```

assistant: ```c
void crash() {
  int *die_sweetie_die = NULL;
  *die_sweetie_die = 0xdead;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<crash>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void crash() {
  int *die_sweetie_die = NULL;
  *die_sweetie_die = 0xdead;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crash>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void crash() {
  int *die_sweetie_die = NULL;
  *die_sweetie_die = 0xdead;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcdSetContrast>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0x81,%edi
  call   <WriteSpiCommand@plt>
  movzbl -0x4(%rbp),%eax
  add    $0x20,%eax
  mov    %eax,%edi
  call   <WriteSpiData@plt>
  mov    $0x3,%edi
  call   <WriteSpiData@plt>
  nop
  leave
  ret
```

assistant: ```c
void lcdSetContrast(unsigned char contrast) {
  WriteSpiCommand(0x81);
  WriteSpiData(32 + contrast);
  WriteSpiData(3);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lcdSetContrast>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x81,%edi
  call   <WriteSpiCommand@plt>
  movzbl %bl,%edi
  add    $0x20,%edi
  call   <WriteSpiData@plt>
  mov    $0x3,%edi
  call   <WriteSpiData@plt>
  pop    %rbx
  ret
```

assistant: ```c
void lcdSetContrast(unsigned char contrast) {
  WriteSpiCommand(0x81);
  WriteSpiData(32 + contrast);
  WriteSpiData(3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lcdSetContrast>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x81,%edi
  call   <WriteSpiCommand@plt>
  movzbl %bl,%edi
  add    $0x20,%edi
  call   <WriteSpiData@plt>
  mov    $0x3,%edi
  pop    %rbx
  jmp    1070 <WriteSpiData@plt>
```

assistant: ```c
void lcdSetContrast(unsigned char contrast) {
  WriteSpiCommand(0x81);
  WriteSpiData(32 + contrast);
  WriteSpiData(3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lcdSetContrast>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x81,%edi
  call   <WriteSpiCommand@plt>
  movzbl %bl,%edi
  add    $0x20,%edi
  call   <WriteSpiData@plt>
  mov    $0x3,%edi
  pop    %rbx
  jmp    1070 <WriteSpiData@plt>
```

assistant: ```c
void lcdSetContrast(unsigned char contrast) {
  WriteSpiCommand(0x81);
  WriteSpiData(32 + contrast);
  WriteSpiData(3);
}
```
user: What is the c source code of the assembly code below?

```asm
<idiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L8
  negl   -0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0x0,-0x18(%rbp)
  jns    L23
  negl   -0x18(%rbp)
  xorl   $0x1,-0x8(%rbp)
L23:
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <udiv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L18
  negl   -0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
signed int idiv(signed int num, signed int den) {
  signed int minus = 0;
  signed int v;
  if (num < 0) {
    num = -num;
    minus = 1;
  }
  if (den < 0) {
    den = -den;
    minus ^= 1;
  }
  v = udiv(num, den, 0);
  if (minus)
    v = -v;
  return v;
}
```
user: Translate the below assembly code into C programming language:

```asm
<idiv>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L53
  test   %esi,%esi
  js     L31
  mov    $0x0,%edx
  call   <udiv@plt>
  jmp    L43
L53:
  neg    %edi
  test   %esi,%esi
  js     L59
  mov    $0x0,%edx
  call   <udiv@plt>
L3:
  neg    %eax
L43:
  add    $0x8,%rsp
  ret
L31:
  neg    %esi
  mov    $0x0,%edx
  call   <udiv@plt>
  jmp    L3
L59:
  neg    %esi
  mov    $0x0,%edx
  call   <udiv@plt>
  jmp    L43
```

assistant: ```c
signed int idiv(signed int num, signed int den) {
  signed int minus = 0;
  signed int v;
  if (num < 0) {
    num = -num;
    minus = 1;
  }
  if (den < 0) {
    den = -den;
    minus ^= 1;
  }
  v = udiv(num, den, 0);
  if (minus)
    v = -v;
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<idiv>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L3
  test   %esi,%esi
  js     L8
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <udiv@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  neg    %esi
L27:
  xor    %edx,%edx
  call   <udiv@plt>
  add    $0x8,%rsp
  neg    %eax
  ret
L3:
  neg    %edi
  test   %esi,%esi
  jns    L27
  neg    %esi
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <udiv@plt>
```

assistant: ```c
signed int idiv(signed int num, signed int den) {
  signed int minus = 0;
  signed int v;
  if (num < 0) {
    num = -num;
    minus = 1;
  }
  if (den < 0) {
    den = -den;
    minus ^= 1;
  }
  v = udiv(num, den, 0);
  if (minus)
    v = -v;
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<idiv>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L3
  test   %esi,%esi
  js     L21
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <udiv@plt>
  nopl   0x0(%rax,%rax,1)
L21:
  neg    %esi
L1:
  xor    %edx,%edx
  call   <udiv@plt>
  add    $0x8,%rsp
  neg    %eax
  ret
L3:
  neg    %edi
  test   %esi,%esi
  jns    L1
  neg    %esi
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <udiv@plt>
```

assistant: ```c
signed int idiv(signed int num, signed int den) {
  signed int minus = 0;
  signed int v;
  if (num < 0) {
    num = -num;
    minus = 1;
  }
  if (den < 0) {
    den = -den;
    minus ^= 1;
  }
  v = udiv(num, den, 0);
  if (minus)
    v = -v;
  return v;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fconcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  jmp    L9
L21:
  subl   $0x1,-0x1c(%rbp)
L9:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L23
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L21
L23:
  mov    -0x1c(%rbp),%eax
  lea    0x2(%rax),%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *fconcat(const char *p1, const char *p2) {
  int len;
  char *new;
  len = strlen(p1);
  while (len > 0 && p1[len - 1] == '/')
    --len;
  new = malloc(len + 2 + strlen(p2));
  memcpy(new, p1, len);
  new[len++] = '/';
  strcpy(new + len, p2);
  return new;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fconcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L29
  cltq
  lea    -0x1(%r13,%rax,1),%rax
L8:
  cmpb   $0x2f,(%rax)
  jne    L29
  sub    $0x1,%rax
  sub    $0x1,%ebx
  jne    L8
L29:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rax
  movb   $0x2f,(%r12,%rax,1)
  lea    0x1(%rbx),%edi
  movslq %edi,%rdi
  add    %r12,%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *fconcat(const char *p1, const char *p2) {
  int len;
  char *new;
  len = strlen(p1);
  while (len > 0 && p1[len - 1] == '/')
    --len;
  new = malloc(len + 2 + strlen(p2));
  memcpy(new, p1, len);
  new[len++] = '/';
  strcpy(new + len, p2);
  return new;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fconcat>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%r14d
  mov    %rbx,%r12
  movslq %r14d,%r14
  test   %ebx,%ebx
  jg     L45
  jmp    L18
L38:
  mov    %rbx,%rax
  lea    -0x1(%rbx),%r12d
  sub    $0x1,%rax
  je     L13
  mov    %rax,%rbx
L45:
  cmpb   $0x2f,-0x1(%rbp,%rbx,1)
  mov    %ebx,%r12d
  je     L38
  lea    0x1(%rbx),%r14d
  movslq %r14d,%r14
L18:
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x2f,0x0(%r13,%rbx,1)
  lea    0x0(%r13,%r14,1),%rdi
  mov    %r15,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L13:
  mov    %rbx,%r14
  movslq %r12d,%rbx
  jmp    L18
```

assistant: ```c
char *fconcat(const char *p1, const char *p2) {
  int len;
  char *new;
  len = strlen(p1);
  while (len > 0 && p1[len - 1] == '/')
    --len;
  new = malloc(len + 2 + strlen(p2));
  memcpy(new, p1, len);
  new[len++] = '/';
  strcpy(new + len, p2);
  return new;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fconcat>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%r14d
  mov    %rbx,%r12
  movslq %r14d,%r14
  test   %ebx,%ebx
  jg     L9
  jmp    L26
L49:
  mov    %rbx,%rax
  lea    -0x1(%rbx),%r12d
  sub    $0x1,%rax
  je     L15
  mov    %rax,%rbx
L9:
  cmpb   $0x2f,-0x1(%rbp,%rbx,1)
  mov    %ebx,%r12d
  je     L49
  lea    0x1(%rbx),%r14d
  movslq %r14d,%r14
L26:
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x2f,0x0(%r13,%rbx,1)
  lea    0x0(%r13,%r14,1),%rdi
  mov    %r15,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L15:
  mov    %rbx,%r14
  movslq %r12d,%rbx
  jmp    L26
```

assistant: ```c
char *fconcat(const char *p1, const char *p2) {
  int len;
  char *new;
  len = strlen(p1);
  while (len > 0 && p1[len - 1] == '/')
    --len;
  new = malloc(len + 2 + strlen(p2));
  memcpy(new, p1, len);
  new[len++] = '/';
  strcpy(new + len, p2);
  return new;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setbuf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L3:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <putc@plt>
  movl   $0x5f5e100,-0x4(%rbp)
  nop
L24:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L24
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void print(const char *str) {
  int i;
  setbuf(stdout, NULL);
  for (i = 0; i < strlen(str); i++) {
    putc(str[i], stdout);
    int delay = 100000000;
    while (delay--)
      ;
  }
}
```