ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ln_get_mercury_phase>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ln_get_earth_solar_dist@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <ln_get_mercury_solar_dist@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <ln_get_mercury_earth_dist@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm3
  mulsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm0
  subsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  call   <acos@plt>
  add    $0x28,%rsp
  jmp    10b0 <ln_rad_to_deg@plt>
```

assistant: ```c
double ln_get_mercury_phase(double JD) {
  double i, r, delta, R;
  R = ln_get_earth_solar_dist(JD);
  r = ln_get_mercury_solar_dist(JD);
  delta = ln_get_mercury_earth_dist(JD);
  i = (r * r + delta * delta - R * R) / (2 * r * delta);
  i = acos(i);
  return ln_rad_to_deg(i);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ln_get_mercury_phase>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ln_get_earth_solar_dist@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <ln_get_mercury_solar_dist@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <ln_get_mercury_earth_dist@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm3
  mulsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm0
  subsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  call   <acos@plt>
  add    $0x28,%rsp
  jmp    10b0 <ln_rad_to_deg@plt>
```

assistant: ```c
double ln_get_mercury_phase(double JD) {
  double i, r, delta, R;
  R = ln_get_earth_solar_dist(JD);
  r = ln_get_mercury_solar_dist(JD);
  delta = ln_get_mercury_earth_dist(JD);
  i = (r * r + delta * delta - R * R) / (2 * r * delta);
  i = acos(i);
  return ln_rad_to_deg(i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<simple_memmem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rcx,%rcx
  je     L145
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    %rcx,%r13
  cmp    $0x1,%rcx
  jne    L93
  movzbl (%rdx),%esi
  mov    %r14,%rdx
  call   <memchr@plt>
  mov    %rax,%rbp
L145:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L93:
  movzbl (%rdx),%esi
  mov    %r14,%rdx
  call   <memchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L145
  sub    %rbx,%rax
  sub    %rax,%r14
  cmp    %r14,%r13
  ja     L151
  lea    0x1(%r15),%rsi
  lea    0x1(%rbp),%rdi
  lea    (%r15,%r13,1),%rax
  cmp    %rax,%rsi
  je     L41
  mov    $0x1,%eax
  mov    $0x0,%ebx
L165:
  movzbl 0x0(%rbp,%rax,1),%edx
  add    %ebx,%edx
  movzbl (%r15,%rax,1),%ecx
  sub    %ecx,%edx
  mov    %edx,%ebx
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L165
  lea    0x0(%rbp,%r13,1),%r12
  test   %edx,%edx
  je     L77
L23:
  add    %rbp,%r14
  cmp    %r14,%r12
  je     L118
  sub    $0x1,%r13
  jmp    L178
L41:
  mov    %rdi,%r12
L77:
  lea    -0x2(%r13),%rdx
  call   <memcmp@plt>
  test   %rax,%rax
  je     L145
  mov    $0x0,%ebx
  jmp    L23
L35:
  cmp    %r12,%r14
  je     L116
L178:
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%eax
  sub    %eax,%ebx
  add    $0x1,%r12
  movzbl -0x1(%r12),%eax
  add    %eax,%ebx
  jne    L35
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L35
  jmp    L145
L116:
  mov    $0x0,%ebp
  jmp    L145
L151:
  mov    $0x0,%ebp
  jmp    L145
L118:
  mov    $0x0,%ebp
  jmp    L145
```

assistant: ```c
char *simple_memmem(const char *haystack, size_t haystacklen, const char *needle, size_t needlelen) {
  const char *needle_ptr;
  const char *haystack_ptr;
  int sums_diff;
  switch (needlelen) {
  case (0):
    return (char *)haystack;
    break;
  case (1):
    return memchr(haystack, *((unsigned char *)needle), haystacklen);
    break;
  }
  haystack_ptr = memchr(haystack, *((unsigned char *)needle), haystacklen);
  if (!haystack_ptr) {
    return NULL;
  }
  haystacklen -= (haystack_ptr - haystack);
  if (haystacklen < needlelen) {
    return NULL;
  }
  haystack = haystack_ptr;
  sums_diff = 0;
  needle_ptr = needle + 1;
  haystack_ptr++;
  needle += needlelen;
  while (needle_ptr != needle) {
    sums_diff += *((unsigned char *)haystack_ptr++);
    sums_diff -= *((unsigned char *)needle_ptr++);
  }
  needle -= needlelen;
  if (sums_diff == 0 && memcmp(haystack + 1, needle + 1, needlelen - 2) == 0) {
    return (char *)haystack;
  }
  needle_ptr = haystack + haystacklen;
  while (haystack_ptr != needle_ptr) {
    sums_diff -= *((unsigned char *)haystack++);
    sums_diff += *((unsigned char *)haystack_ptr++);
    if (sums_diff == 0 && memcmp(haystack, needle, needlelen - 1) == 0) {
      return (char *)haystack;
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  D0(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
L2:
  movss  -0x8(%rbp),%xmm0
  movaps %xmm0,%xmm2
  addss  %xmm0,%xmm2
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  -0x8(%rbp),%xmm0
  movss  D14(%rip),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x8(%rbp),%xmm0
  subss  -0x4(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jle    L9
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  jmp    L2
L9:
  nop
  movss  -0x8(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: f32
name: disassemble_data
arguments: data_label: D14
type_guessed: byte[4]

tool: D0: 1

tool: {"D14": [0x00,0x00,0x00,0x40]}

assistant: ```c
float sqrt(float a) {
  float x0, x1;
  x0 = 1.0;
  do {
    x1 = a / (2 * x0) + x0 / 2;
    if (fabs(x0 - x1) < 10e-3)
      break;
    x0 = x1;
  } while (1);
  return x0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sqrt>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  movss  D18(%rip),%xmm5
  movss  %xmm5,0x4(%rsp)
L8:
  movss  0x4(%rsp),%xmm3
  movaps %xmm3,%xmm2
  movss  %xmm3,0x8(%rsp)
  movaps %xmm3,%xmm0
  addss  %xmm3,%xmm0
  movss  0xc(%rsp),%xmm1
  divss  %xmm0,%xmm1
  movss  D0(%rip),%xmm0
  mulss  %xmm3,%xmm0
  addss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rsp)
  subss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L8
  movss  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: f32
name: unpack_data
arguments: label: D0
type_guessed: byte[4]

tool: D18: 1

tool: {"D0": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float sqrt(float a) {
  float x0, x1;
  x0 = 1.0;
  do {
    x1 = a / (2 * x0) + x0 / 2;
    if (fabs(x0 - x1) < 10e-3)
      break;
    x0 = x1;
  } while (1);
  return x0;
}
```
user: What is the c source code of the assembly code below?

```asm
<sqrt>:
  endbr64
  push   %rbx
  movd   %xmm0,%ebx
  sub    $0x10,%rsp
  movss  D12(%rip),%xmm2
  nopl   (%rax)
L8:
  movaps %xmm2,%xmm0
  movaps %xmm2,%xmm1
  addss  %xmm2,%xmm0
  movd   %ebx,%xmm2
  movss  %xmm1,0xc(%rsp)
  divss  %xmm0,%xmm2
  movss  D18(%rip),%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm0,%xmm2
  movaps %xmm1,%xmm0
  subss  %xmm2,%xmm0
  movss  %xmm2,0x8(%rsp)
  call   <fabs@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  test   %eax,%eax
  jg     L8
  add    $0x10,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: f32
name: unpack_data
arguments: label: D18
type_infered: byte[4]

tool: D12: 1

tool: {"D18": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float sqrt(float a) {
  float x0, x1;
  x0 = 1.0;
  do {
    x1 = a / (2 * x0) + x0 / 2;
    if (fabs(x0 - x1) < 10e-3)
      break;
    x0 = x1;
  } while (1);
  return x0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sqrt>:
  endbr64
  push   %rbx
  movd   %xmm0,%ebx
  sub    $0x10,%rsp
  movss  D14(%rip),%xmm2
  nopl   (%rax)
L8:
  movaps %xmm2,%xmm0
  movaps %xmm2,%xmm1
  addss  %xmm2,%xmm0
  movd   %ebx,%xmm2
  movss  %xmm1,0xc(%rsp)
  divss  %xmm0,%xmm2
  movss  D6(%rip),%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm0,%xmm2
  movaps %xmm1,%xmm0
  subss  %xmm2,%xmm0
  movss  %xmm2,0x8(%rsp)
  call   <fabs@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  test   %eax,%eax
  jg     L8
  add    $0x10,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type: f32
name: parse_data
arguments: data_label: D6
type: byte[4]

tool: D14: 1

tool: {"D6": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float sqrt(float a) {
  float x0, x1;
  x0 = 1.0;
  do {
    x1 = a / (2 * x0) + x0 / 2;
    if (fabs(x0 - x1) < 10e-3)
      break;
    x0 = x1;
  } while (1);
  return x0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L85
  mov    $0x0,%eax
  jmp    L9
L85:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L21:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L64
L72:
  cmpl   $0x0,-0xc(%rbp)
  je     L53
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L29
L53:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  jmp    L66
L29:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
L66:
  subl   $0x1,-0xc(%rbp)
L64:
  cmpl   $0x0,-0xc(%rbp)
  jns    L72
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L21
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
L9:
  leave
  ret
```

assistant: ```c
int *getRow(int rowIndex, int *returnSize) {
  if (rowIndex < 0) {
    return NULL;
  }
  int *res = (int *)malloc(sizeof(int) * (rowIndex + 1));
  for (int i = 0; i <= rowIndex; i++) {
    for (int j = i; j >= 0; j--) {
      if (j == 0 || j == i) {
        res[j] = 1;
      } else {
        res[j] = res[j - 1] + res[j];
      }
    }
  }
  *returnSize = rowIndex + 1;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getRow>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L8
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    0x1(%rdi),%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    $0x0,%esi
  jmp    L75
L69:
  movl   $0x1,(%rcx)
L66:
  sub    $0x1,%edx
  sub    $0x4,%rcx
  cmp    $0xffffffff,%edx
  je     L70
L30:
  test   %edx,%edx
  je     L69
  cmp    %edx,%esi
  je     L69
  mov    -0x4(%rcx),%edi
  add    %edi,(%rcx)
  jmp    L66
L70:
  add    $0x1,%esi
  add    $0x4,%r8
  cmp    %ebx,%esi
  je     L9
L75:
  mov    %r8,%rcx
  mov    %esi,%edx
  test   %esi,%esi
  jns    L30
  jmp    L70
L9:
  mov    %ebx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  ret
```

assistant: ```c
int *getRow(int rowIndex, int *returnSize) {
  if (rowIndex < 0) {
    return NULL;
  }
  int *res = (int *)malloc(sizeof(int) * (rowIndex + 1));
  for (int i = 0; i <= rowIndex; i++) {
    for (int j = i; j >= 0; j--) {
      if (j == 0 || j == i) {
        res[j] = 1;
      } else {
        res[j] = res[j - 1] + res[j];
      }
    }
  }
  *returnSize = rowIndex + 1;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getRow>:
  endbr64
  test   %edi,%edi
  js     L63
  push   %r12
  lea    0x1(%rdi),%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L60:
  mov    %r9,%rcx
  mov    %edi,%edx
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L19:
  sub    $0x1,%edx
  mov    -0x4(%rcx),%r8d
  add    %r8d,(%rcx)
  sub    $0x4,%rcx
  cmp    $0xffffffff,%edx
  je     L2
L59:
  test   %edx,%edx
  je     L72
  cmp    %edx,%edi
  jne    L19
L72:
  sub    $0x1,%edx
  movl   $0x1,(%rcx)
  sub    $0x4,%rcx
  cmp    $0xffffffff,%edx
  jne    L59
L2:
  lea    0x1(%rdi),%edx
  add    $0x4,%r9
  cmp    %edi,%ebx
  je     L28
  mov    %edx,%edi
  jmp    L60
  nopl   0x0(%rax)
L28:
  mov    %r12d,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L63:
  xor    %eax,%eax
  ret
```

assistant: ```c
int *getRow(int rowIndex, int *returnSize) {
  if (rowIndex < 0) {
    return NULL;
  }
  int *res = (int *)malloc(sizeof(int) * (rowIndex + 1));
  for (int i = 0; i <= rowIndex; i++) {
    for (int j = i; j >= 0; j--) {
      if (j == 0 || j == i) {
        res[j] = 1;
      } else {
        res[j] = res[j - 1] + res[j];
      }
    }
  }
  *returnSize = rowIndex + 1;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getRow>:
  endbr64
  test   %edi,%edi
  js     L27
  push   %r12
  lea    0x1(%rdi),%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L55:
  mov    %r9,%rcx
  mov    %edi,%edx
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x1,%edx
  mov    -0x4(%rcx),%r8d
  add    %r8d,(%rcx)
  sub    $0x4,%rcx
  cmp    $0xffffffff,%edx
  je     L56
L61:
  test   %edx,%edx
  je     L7
  cmp    %edx,%edi
  jne    L5
L7:
  sub    $0x1,%edx
  movl   $0x1,(%rcx)
  sub    $0x4,%rcx
  cmp    $0xffffffff,%edx
  jne    L61
L56:
  lea    0x1(%rdi),%edx
  add    $0x4,%r9
  cmp    %edi,%ebx
  je     L41
  mov    %edx,%edi
  jmp    L55
  nopl   0x0(%rax)
L41:
  mov    %r12d,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int *getRow(int rowIndex, int *returnSize) {
  if (rowIndex < 0) {
    return NULL;
  }
  int *res = (int *)malloc(sizeof(int) * (rowIndex + 1));
  for (int i = 0; i <= rowIndex; i++) {
    for (int j = i; j >= 0; j--) {
      if (j == 0 || j == i) {
        res[j] = 1;
      } else {
        res[j] = res[j - 1] + res[j];
      }
    }
  }
  *returnSize = rowIndex + 1;
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<storeData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L17
L10:
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L10
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D4: STORING %i AT %i POSITION.


assistant: ```c
int storeData(int data, unsigned char *memory, int last) {
  int count, final = last + 4, aux = 0;
  for (count = last; count < final; count++) {
    memory[count] = data >> (8 * aux);
    printf("STORING %i AT %i POSITION.\n", memory[count], count);
    aux++;
  }
  return final;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<storeData>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  lea    0x4(%rdx),%r15d
  movslq %edx,%rbx
  mov    $0x0,%ebp
  lea    D9(%rip),%r14
L7:
  mov    %r13d,%esi
  mov    %ebp,%ecx
  sar    %cl,%esi
  mov    %sil,(%r12,%rbx,1)
  movzbl %sil,%esi
  mov    %ebx,%edx
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  add    $0x8,%ebp
  cmp    $0x20,%ebp
  jne    L7
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D9: STORING %i AT %i POSITION.


assistant: ```c
int storeData(int data, unsigned char *memory, int last) {
  int count, final = last + 4, aux = 0;
  for (count = last; count < final; count++) {
    memory[count] = data >> (8 * aux);
    printf("STORING %i AT %i POSITION.\n", memory[count], count);
    aux++;
  }
  return final;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<storeData>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  lea    0x4(%rdx),%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
L4:
  mov    %r15d,%ecx
  mov    %r12d,%esi
  mov    %ebx,%edx
  mov    %r14,%rdi
  sar    %cl,%esi
  add    $0x8,%r15d
  mov    %sil,0x0(%rbp,%rbx,1)
  movzbl %sil,%esi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x20,%r15d
  jne    L4
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: STORING %i AT %i POSITION.


assistant: ```c
int storeData(int data, unsigned char *memory, int last) {
  int count, final = last + 4, aux = 0;
  for (count = last; count < final; count++) {
    memory[count] = data >> (8 * aux);
    printf("STORING %i AT %i POSITION.\n", memory[count], count);
    aux++;
  }
  return final;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<storeData>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  lea    0x4(%rdx),%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
L7:
  mov    %r15d,%ecx
  mov    %r12d,%esi
  mov    %ebx,%edx
  mov    %r14,%rdi
  sar    %cl,%esi
  add    $0x8,%r15d
  mov    %sil,0x0(%rbp,%rbx,1)
  movzbl %sil,%esi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x20,%r15d
  jne    L7
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: STORING %i AT %i POSITION.


assistant: ```c
int storeData(int data, unsigned char *memory, int last) {
  int count, final = last + 4, aux = 0;
  for (count = last; count < final; count++) {
    memory[count] = data >> (8 * aux);
    printf("STORING %i AT %i POSITION.\n", memory[count], count);
    aux++;
  }
  return final;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getarg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    $0x1,%ebx
  jmp    L74
L88:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rcx
  mov    %r13d,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L86
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movslq %r13d,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,%r12d
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movslq %r13d,%rax
  add    %rdx,%rax
  mov    $0x6b,%esi
  mov    %rax,%rdi
  call   <rindex@plt>
  test   %rax,%rax
  je     L85
  shl    $0xa,%r12d
  jmp    L8
L85:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movslq %r13d,%rax
  add    %rdx,%rax
  mov    $0x6d,%esi
  mov    %rax,%rdi
  call   <rindex@plt>
  test   %rax,%rax
  je     L8
  shl    $0x14,%r12d
L8:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x5,%edx
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L39
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movslq %r13d,%rax
  add    %rdx,%rax
  jmp    L82
L39:
  movslq %r12d,%rax
  jmp    L82
L86:
  add    $0x1,%ebx
L74:
  cmp    -0x2c(%rbp),%ebx
  jl     L88
  mov    $0xffffffffffffffff,%rax
L82:
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: label

assistant: ```c
long getarg(s, ac, av)
char *s;
char **av;
{
  register len, i;
  len = strlen(s);
  for (i = 1; i < ac; ++i)
    if (!strncmp(av[i], s, len)) {
      register bs = atoi(&av[i][len]);
      if (rindex(&av[i][len], 'k'))
        bs *= 1024;
      else if (rindex(&av[i][len], 'm'))
        bs *= (1024 * 1024);
      if (!strncmp(av[i], "label", 5)) {
        return (long)(&av[i][len]);
      }
      return (bs);
    }
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getarg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%r14
  call   <strlen@plt>
  mov    %rax,0x8(%rsp)
  cmp    $0x1,%ebp
  jle    L61
  mov    %eax,%r13d
  lea    0x8(%r14),%rbx
  lea    -0x2(%rbp),%eax
  lea    0x10(%r14,%rax,8),%r15
  movslq %r13d,%r13
L38:
  mov    %rbx,%r14
  mov    (%rbx),%rbp
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L38
  mov    $0xffffffffffffffff,%rax
  jmp    L56
L1:
  movslq 0x8(%rsp),%r13
  lea    0x0(%rbp,%r13,1),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    (%r14),%r12
  add    %r12,%r13
  mov    $0x6b,%esi
  mov    %r13,%rdi
  call   <rindex@plt>
  test   %rax,%rax
  je     L45
  shl    $0xa,%ebx
L20:
  mov    $0x5,%edx
  lea    D0(%rip),%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    %eax,%edx
  movslq %ebx,%rax
  test   %edx,%edx
  cmove  %r13,%rax
L56:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  mov    $0x6d,%esi
  mov    %r13,%rdi
  call   <rindex@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  shl    $0x14,%eax
  test   %rdx,%rdx
  cmovne %eax,%ebx
  jmp    L20
L61:
  mov    $0xffffffffffffffff,%rax
  jmp    L56
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: label

assistant: ```c
long getarg(s, ac, av)
char *s;
char **av;
{
  register len, i;
  len = strlen(s);
  for (i = 1; i < ac; ++i)
    if (!strncmp(av[i], s, len)) {
      register bs = atoi(&av[i][len]);
      if (rindex(&av[i][len], 'k'))
        bs *= 1024;
      else if (rindex(&av[i][len], 'm'))
        bs *= (1024 * 1024);
      if (!strncmp(av[i], "label", 5)) {
        return (long)(&av[i][len]);
      }
      return (bs);
    }
  return (-1);
}
```