ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_data_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %rdi,0x20(%rsp)
  mov    %esi,0x18(%rsp)
  mov    %edx,%ebp
  mov    %rcx,0x28(%rsp)
  lea    0x14(%rdx,%rdx,4),%eax
  mov    %eax,0x1c(%rsp)
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rbx,%rdi
  call   <fopen_read@plt>
  mov    %rax,%r15
  mov    $0x0,%eax
  mov    $0x0,%r14d
  lea    D5(%rip),%r12
  mov    %r15,0x10(%rsp)
  mov    %eax,%r15d
  jmp    L17
L54:
  mov    $0x0,%esi
L36:
  add    $0x1,%r14d
  mov    %rdi,%r9
  mov    %ebp,%r8d
  mov    %r14d,%ecx
  mov    %esi,%edx
  mov    0x10(%rsp),%rsi
  mov    0x20(%rsp),%rdi
  call   <test_column@plt>
  add    %ebp,%r15d
L17:
  mov    0x10(%rsp),%rdx
  mov    0x1c(%rsp),%esi
  mov    0x8(%rsp),%rdi
  call   <fgets@plt>
  cmp    0x18(%rsp),%r14d
  jge    L67
  test   %rax,%rax
  je     L67
  mov    %r12,%rsi
  mov    0x8(%rsp),%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L54
  test   %ebp,%ebp
  jle    L54
  movslq %r15d,%rax
  mov    0x28(%rsp),%rcx
  lea    (%rcx,%rax,4),%r13
  mov    $0x1,%ebx
L62:
  call   <atof@plt>
  mov    %eax,-0x4(%r13,%rbx,4)
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  test   %rax,%rax
  setne  %dl
  cmp    %ebx,%ebp
  setg   %al
  add    $0x1,%rbx
  test   %al,%dl
  jne    L62
  jmp    L36
L67:
  mov    0x10(%rsp),%r15
  mov    0x18(%rsp),%ecx
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    0x20(%rsp),%rdi
  call   <test_line@plt>
  mov    %r15,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5:  	


assistant: ```c
void read_data_int(char *file_data, int N, int M, int *dat) {
  FILE *m_File = NULL;
  int i = 0;
  int j = 0;
  int max_char_per_line = 5 * M + 20;
  char *szbuff;
  char *token;
  szbuff = (char *)malloc(max_char_per_line * sizeof(char));
  m_File = fopen_read(file_data);
  i = 0;
  while (fgets(szbuff, max_char_per_line, m_File) && (i < N)) {
    j = 0;
    token = strtok(szbuff, " \t\n");
    while (token && j < M) {
      dat[i * M + j] = (int)atof(token);
      token = strtok(NULL, " \t\n");
      j++;
    }
    i++;
    test_column(file_data, m_File, j, i, M, token);
  }
  test_line(file_data, m_File, i, N);
  fclose(m_File);
  free(szbuff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_data_int>:
  endbr64
  push   %r15
  lea    0x14(%rdx,%rdx,4),%eax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %eax,%edi
  mov    %esi,0x18(%rsp)
  mov    %rcx,0x28(%rsp)
  mov    %eax,0x1c(%rsp)
  call   <malloc@plt>
  mov    %r14,%rdi
  mov    %rax,0x8(%rsp)
  call   <fopen_read@plt>
  movl   $0x0,0x14(%rsp)
  mov    %rax,%r14
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    0x1c(%rsp),%esi
  mov    0x8(%rsp),%rdi
  mov    %r14,%rdx
  call   <fgets@plt>
  cmp    0x18(%rsp),%r13d
  jge    L62
  test   %rax,%rax
  je     L62
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %ebx,%ebx
  jle    L2
  test   %rax,%rax
  je     L2
  movslq 0x14(%rsp),%rax
  mov    0x28(%rsp),%rcx
  mov    $0x1,%r15d
  lea    (%rcx,%rax,4),%r12
  nopw   0x0(%rax,%rax,1)
L3:
  call   <atof@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  mov    %eax,-0x4(%r12,%r15,4)
  call   <strtok@plt>
  mov    %r15d,%r10d
  test   %rax,%rax
  mov    %rax,%rdi
  setne  %dl
  cmp    %r15d,%ebx
  setg   %al
  add    $0x1,%r15
  test   %al,%dl
  jne    L3
L53:
  mov    %rdi,%r9
  add    $0x1,%r13d
  mov    0x20(%rsp),%rdi
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r10d,%edx
  mov    %r14,%rsi
  call   <test_column@plt>
  add    %ebx,0x14(%rsp)
  jmp    L44
  nopl   0x0(%rax)
L62:
  mov    0x18(%rsp),%ecx
  mov    0x20(%rsp),%rdi
  mov    %r13d,%edx
  mov    %r14,%rsi
  call   <test_line@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rdi
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10d0 <free@plt>
  nopl   0x0(%rax)
L2:
  xor    %r10d,%r10d
  jmp    L53
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1:  	


assistant: ```c
void read_data_int(char *file_data, int N, int M, int *dat) {
  FILE *m_File = NULL;
  int i = 0;
  int j = 0;
  int max_char_per_line = 5 * M + 20;
  char *szbuff;
  char *token;
  szbuff = (char *)malloc(max_char_per_line * sizeof(char));
  m_File = fopen_read(file_data);
  i = 0;
  while (fgets(szbuff, max_char_per_line, m_File) && (i < N)) {
    j = 0;
    token = strtok(szbuff, " \t\n");
    while (token && j < M) {
      dat[i * M + j] = (int)atof(token);
      token = strtok(NULL, " \t\n");
      j++;
    }
    i++;
    test_column(file_data, m_File, j, i, M, token);
  }
  test_line(file_data, m_File, i, N);
  fclose(m_File);
  free(szbuff);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_data_int>:
  endbr64
  push   %r15
  lea    0x14(%rdx,%rdx,4),%eax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %eax,%edi
  mov    %esi,0x18(%rsp)
  mov    %rcx,0x28(%rsp)
  mov    %eax,0x1c(%rsp)
  call   <malloc@plt>
  mov    %r14,%rdi
  mov    %rax,0x8(%rsp)
  call   <fopen_read@plt>
  movl   $0x0,0x14(%rsp)
  mov    %rax,%r14
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    0x1c(%rsp),%esi
  mov    0x8(%rsp),%rdi
  mov    %r14,%rdx
  call   <fgets@plt>
  cmp    0x18(%rsp),%r13d
  jge    L20
  test   %rax,%rax
  je     L20
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %ebx,%ebx
  jle    L49
  test   %rax,%rax
  je     L49
  movslq 0x14(%rsp),%rax
  mov    0x28(%rsp),%rcx
  mov    $0x1,%r15d
  lea    (%rcx,%rax,4),%r12
  nopw   0x0(%rax,%rax,1)
L42:
  call   <atof@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  mov    %eax,-0x4(%r12,%r15,4)
  call   <strtok@plt>
  mov    %r15d,%r10d
  test   %rax,%rax
  mov    %rax,%rdi
  setne  %dl
  cmp    %r15d,%ebx
  setg   %al
  add    $0x1,%r15
  test   %al,%dl
  jne    L42
L7:
  mov    %rdi,%r9
  add    $0x1,%r13d
  mov    0x20(%rsp),%rdi
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r10d,%edx
  mov    %r14,%rsi
  call   <test_column@plt>
  add    %ebx,0x14(%rsp)
  jmp    L32
  nopl   0x0(%rax)
L20:
  mov    0x18(%rsp),%ecx
  mov    0x20(%rsp),%rdi
  mov    %r13d,%edx
  mov    %r14,%rsi
  call   <test_line@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rdi
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10d0 <free@plt>
  nopl   0x0(%rax)
L49:
  xor    %r10d,%r10d
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8:  	


assistant: ```c
void read_data_int(char *file_data, int N, int M, int *dat) {
  FILE *m_File = NULL;
  int i = 0;
  int j = 0;
  int max_char_per_line = 5 * M + 20;
  char *szbuff;
  char *token;
  szbuff = (char *)malloc(max_char_per_line * sizeof(char));
  m_File = fopen_read(file_data);
  i = 0;
  while (fgets(szbuff, max_char_per_line, m_File) && (i < N)) {
    j = 0;
    token = strtok(szbuff, " \t\n");
    while (token && j < M) {
      dat[i * M + j] = (int)atof(token);
      token = strtok(NULL, " \t\n");
      j++;
    }
    i++;
    test_column(file_data, m_File, j, i, M, token);
  }
  test_line(file_data, m_File, i, N);
  fclose(m_File);
  free(szbuff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x10,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D8: 
%d

assistant: ```c
main() {
  int i = 0x10;
  printf("\n%d", i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: string

tool: D7: 
%d

assistant: ```c
main() {
  int i = 0x10;
  printf("\n%d", i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: 
%d

assistant: ```c
main() {
  int i = 0x10;
  printf("\n%d", i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: 
%d

assistant: ```c
main() {
  int i = 0x10;
  printf("\n%d", i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lua_dofile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <lua_openfile@plt>
  test   %rax,%rax
  je     L36
  mov    $0x1,%eax
  jmp    L11
L36:
  mov    $0x0,%eax
  call   <lua_parse@plt>
  test   %rax,%rax
  je     L25
  mov    $0x0,%eax
  call   <lua_closefile@plt>
  mov    $0x1,%eax
  jmp    L11
L25:
  mov    $0x0,%eax
  call   <lua_closefile@plt>
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int lua_dofile(char *filename) {
  if (lua_openfile(filename))
    return 1;
  if (lua_parse()) {
    lua_closefile();
    return 1;
  }
  lua_closefile();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lua_dofile>:
  endbr64
  sub    $0x8,%rsp
  call   <lua_openfile@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L36
L31:
  add    $0x8,%rsp
  ret
L36:
  mov    $0x0,%eax
  call   <lua_parse@plt>
  test   %rax,%rax
  jne    L29
  mov    $0x0,%eax
  call   <lua_closefile@plt>
  mov    $0x0,%eax
  jmp    L31
L29:
  mov    $0x0,%eax
  call   <lua_closefile@plt>
  mov    $0x1,%eax
  jmp    L31
```

assistant: ```c
int lua_dofile(char *filename) {
  if (lua_openfile(filename))
    return 1;
  if (lua_parse()) {
    lua_closefile();
    return 1;
  }
  lua_closefile();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lua_dofile>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  call   <lua_openfile@plt>
  test   %rax,%rax
  je     L13
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  call   <lua_parse@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  jne    L15
  call   <lua_closefile@plt>
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L15:
  call   <lua_closefile@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int lua_dofile(char *filename) {
  if (lua_openfile(filename))
    return 1;
  if (lua_parse()) {
    lua_closefile();
    return 1;
  }
  lua_closefile();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lua_dofile>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  call   <lua_openfile@plt>
  test   %rax,%rax
  je     L7
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  call   <lua_parse@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  jne    L0
  call   <lua_closefile@plt>
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L0:
  call   <lua_closefile@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int lua_dofile(char *filename) {
  if (lua_openfile(filename))
    return 1;
  if (lua_parse()) {
    lua_closefile();
    return 1;
  }
  lua_closefile();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  lea    0x5f158c66(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 2699719578U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x5e7b97ab,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 2699719578U;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x5e7b97ab,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 2699719578U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x5e7b97ab,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 2699719578U;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printTri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string

tool: D11: *


tool: D22: **


tool: D2: ***


assistant: ```c
void printTri() {
  printf("*\n");
  printf("**\n");
  printf("***\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printTri>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D23
type_guessed: string
name: read_data
arguments: data_tag: D10
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string

tool: D23: *


tool: D10: **


tool: D11: ***


assistant: ```c
void printTri() {
  printf("*\n");
  printf("**\n");
  printf("***\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printTri>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string
name: unpack_data
arguments: data_tag: D22
data_type: string
name: unpack_data
arguments: data_tag: D25
data_type: string

tool: D0: *


tool: D22: **


tool: D25: ***


assistant: ```c
void printTri() {
  printf("*\n");
  printf("**\n");
  printf("***\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printTri>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
data_type: string
name: retrieve_data
arguments: data_label: D19
data_type: string
name: retrieve_data
arguments: data_label: D29
data_type: string

tool: D16: *


tool: D19: **


tool: D29: ***


assistant: ```c
void printTri() {
  printf("*\n");
  printf("**\n");
  printf("***\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x4,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D7: Value of integer pointed by p: %d


tool: D6: Next value of integer pointed by p: %d


assistant: ```c
int main() {
  int *p;
  int a = 3;
  p = &a;
  printf("Value of integer pointed by p: %d\n", *p);
  p++;
  printf("Next value of integer pointed by p: %d\n", *p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  mov    0x10(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D1
type: string

tool: D11: Value of integer pointed by p: %d


tool: D1: Next value of integer pointed by p: %d


assistant: ```c
int main() {
  int *p;
  int a = 3;
  p = &a;
  printf("Value of integer pointed by p: %d\n", *p);
  p++;
  printf("Next value of integer pointed by p: %d\n", *p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D1(%rip),%rdi
  movl   $0x0,0xc(%rsp)
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D10: Value of integer pointed by p: %d


tool: D1: Next value of integer pointed by p: %d


assistant: ```c
int main() {
  int *p;
  int a = 3;
  p = &a;
  printf("Value of integer pointed by p: %d\n", *p);
  p++;
  printf("Next value of integer pointed by p: %d\n", *p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D12(%rip),%rdi
  movl   $0x0,0xc(%rsp)
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D12
type: string

tool: D3: Value of integer pointed by p: %d


tool: D12: Next value of integer pointed by p: %d


assistant: ```c
int main() {
  int *p;
  int a = 3;
  p = &a;
  printf("Value of integer pointed by p: %d\n", *p);
  p++;
  printf("Next value of integer pointed by p: %d\n", *p);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<writeFPRData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L2
  mov    -0x18(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L3
L2:
  mov    -0x18(%rbp),%rax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
L3:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D23
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D10: w

tool: D23: a

tool: D6: %lld,


assistant: ```c
void writeFPRData(const char *fname, long long fpstatus, int wr_flag) {
  FILE *fp;
  if (wr_flag)
    fp = fopen(fname, "w");
  else
    fp = fopen(fname, "a");
  fprintf(fp, "%lld,\n", fpstatus);
  fclose(fp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<writeFPRData>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %edx,%edx
  je     L14
  lea    D22(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
L10:
  mov    %rbp,%rdx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string
name: disassemble_data
arguments: tag: D10
data_type: string

tool: D22: w

tool: D8: %lld,


tool: D10: a

assistant: ```c
void writeFPRData(const char *fname, long long fpstatus, int wr_flag) {
  FILE *fp;
  if (wr_flag)
    fp = fopen(fname, "w");
  else
    fp = fopen(fname, "a");
  fprintf(fp, "%lld,\n", fpstatus);
  fclose(fp);
}
```
user: What is the c source code of the assembly code below:

```asm
<writeFPRData>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L0
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
L15:
  mov    %rbp,%rdi
  mov    %r12,%rdx
  lea    D20(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string
name: unpack_data
arguments: tag: D20
type: string
name: unpack_data
arguments: tag: D1
type: string

tool: D5: w

tool: D20: %lld,


tool: D1: a

assistant: ```c
void writeFPRData(const char *fname, long long fpstatus, int wr_flag) {
  FILE *fp;
  if (wr_flag)
    fp = fopen(fname, "w");
  else
    fp = fopen(fname, "a");
  fprintf(fp, "%lld,\n", fpstatus);
  fclose(fp);
}
```