ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<xilinxcorelib_a_1203745346_2959432447_p_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x790,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x29e8,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  mov    -0x48(%rbp),%rax
  add    $0x28a8,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void xilinxcorelib_a_1203745346_2959432447_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 1936U);
  t2 = *((char **)t1);
  t1 = (t0 + 10728);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 16U);
  xsi_driver_first_trans_fast_port(t1);
LAB2:
  t7 = (t0 + 10408);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xilinxcorelib_a_1203745346_2959432447_p_3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x790(%rdi),%rsi
  mov    0x2a20(%rdi),%rax
  mov    0x38(%rax),%rdi
  mov    $0x10,%edx
  call   <memcpy@plt>
  lea    0x29e8(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x28a8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_1203745346_2959432447_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 1936U);
  t2 = *((char **)t1);
  t1 = (t0 + 10728);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 16U);
  xsi_driver_first_trans_fast_port(t1);
LAB2:
  t7 = (t0 + 10408);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xilinxcorelib_a_1203745346_2959432447_p_3>:
  endbr64
  push   %rbx
  mov    0x2a20(%rdi),%rax
  mov    %rdi,%rbx
  mov    $0x10,%edx
  mov    0x790(%rdi),%rsi
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  lea    0x29e8(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x28a8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_1203745346_2959432447_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 1936U);
  t2 = *((char **)t1);
  t1 = (t0 + 10728);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 16U);
  xsi_driver_first_trans_fast_port(t1);
LAB2:
  t7 = (t0 + 10408);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xilinxcorelib_a_1203745346_2959432447_p_3>:
  endbr64
  push   %rbx
  mov    0x2a20(%rdi),%rax
  mov    %rdi,%rbx
  mov    $0x10,%edx
  mov    0x790(%rdi),%rsi
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  lea    0x29e8(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x28a8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_1203745346_2959432447_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 1936U);
  t2 = *((char **)t1);
  t1 = (t0 + 10728);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 16U);
  xsi_driver_first_trans_fast_port(t1);
LAB2:
  t7 = (t0 + 10408);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<field_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L23
  cmpq   $0x0,-0x20(%rbp)
  jne    L43
L23:
  mov    $0xffffffff,%eax
  jmp    L15
L47:
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L43:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L47
L0:
  mov    -0x4(%rbp),%eax
L15:
  leave
  ret
```

assistant: ```c
int field_length(const char *s, const char *delimiters) {
  int len = 0;
  if (!s || !delimiters)
    return -1;
  while (*s != '\0' && !strchr(delimiters, *s)) {
    len++;
    s++;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<field_length>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L13
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L13
  movzbl (%rdi),%esi
  mov    $0x0,%ebp
  test   %sil,%sil
  je     L46
L44:
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L46
  add    $0x1,%ebp
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L44
L46:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    $0xffffffff,%ebp
  jmp    L46
```

assistant: ```c
int field_length(const char *s, const char *delimiters) {
  int len = 0;
  if (!s || !delimiters)
    return -1;
  while (*s != '\0' && !strchr(delimiters, *s)) {
    len++;
    s++;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<field_length>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L57
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L57
  movsbl (%rdi),%esi
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  test   %sil,%sil
  jne    L52
  jmp    L13
  nopl   (%rax)
L64:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  add    $0x1,%r12d
  test   %sil,%sil
  je     L13
L52:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L64
L13:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  mov    $0xffffffff,%r12d
  jmp    L13
```

assistant: ```c
int field_length(const char *s, const char *delimiters) {
  int len = 0;
  if (!s || !delimiters)
    return -1;
  while (*s != '\0' && !strchr(delimiters, *s)) {
    len++;
    s++;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<field_length>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L65
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L65
  movsbl (%rdi),%esi
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  test   %sil,%sil
  jne    L19
  jmp    L49
  nopl   (%rax)
L69:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  add    $0x1,%r12d
  test   %sil,%sil
  je     L49
L19:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L69
L49:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L65:
  mov    $0xffffffff,%r12d
  jmp    L49
```

assistant: ```c
int field_length(const char *s, const char *delimiters) {
  int len = 0;
  if (!s || !delimiters)
    return -1;
  while (*s != '\0' && !strchr(delimiters, *s)) {
    len++;
    s++;
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<free_critbit_node>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_critbit_node(void *const ctx, void *const node) {
  assert(ctx == NULL);
  free(node);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<free_critbit_node>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void free_critbit_node(void *const ctx, void *const node) {
  assert(ctx == NULL);
  free(node);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<free_critbit_node>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  mov    %rsi,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void free_critbit_node(void *const ctx, void *const node) {
  assert(ctx == NULL);
  free(node);
}
```
user: What is the c source code of the assembly code below:

```asm
<free_critbit_node>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  mov    %rsi,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void free_critbit_node(void *const ctx, void *const node) {
  assert(ctx == NULL);
  free(node);
}
```
user: Translate the below assembly code into C programming language:

```asm
<token>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%ecx
  cmp    $0x20,%cl
  je     L173
  cmp    $0x9,%cl
  jne    L218
L173:
  add    $0x1,%rax
  movzbl (%rax),%ecx
  cmp    $0x20,%cl
  je     L173
  cmp    $0x9,%cl
  je     L173
L218:
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L66
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1,%edx
  mov    $0x0,%r8d
  lea    D4(%rip),%r9
  mov    $0xd,%ebp
  mov    $0xc,%ebx
  mov    $0x8,%r11d
  mov    $0x9,%r10d
  mov    $0xa,%r12d
  jmp    L190
L6:
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L21
  add    $0x2,%rax
  lea    -0x62(%rcx),%edi
  cmp    $0x12,%dil
  ja     L169
  movzbl %dil,%edi
  movslq (%r9,%rdi,4),%rdi
  add    %r9,%rdi
  notrack jmp *%rdi
  mov    %r12d,%ecx
  jmp    L169
  mov    %r10d,%ecx
L169:
  test   %edx,%edx
  jle    L200
  mov    %cl,(%rsi)
  lea    0x1(%rsi),%rsi
  jmp    L200
  mov    %r11d,%ecx
  jmp    L169
  mov    %ebx,%ecx
  jmp    L169
  mov    %ebp,%ecx
  jmp    L169
L181:
  cmp    $0x20,%cl
  je     L28
  cmp    $0x9,%cl
  je     L28
  cmp    $0x22,%cl
  sete   %r8b
  movzbl %r8b,%r8d
L149:
  add    $0x1,%rax
  test   %edx,%edx
  jle    L200
  mov    %cl,(%rsi)
  lea    0x1(%rsi),%rsi
L200:
  movzbl (%rax),%ecx
  sub    $0x1,%edx
  test   %cl,%cl
  je     L29
L190:
  cmp    $0x7e,%cl
  je     L6
  test   %r8d,%r8d
  je     L181
  cmp    $0x22,%cl
  jne    L149
  jmp    L28
L21:
  add    $0x1,%rax
L28:
  cmpb   $0x1,(%rax)
  sbb    $0xffffffffffffffff,%rax
L29:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
char *token(char *src, char *tok, int size) {
  register int quotef;
  register char c;
  while (*src == ' ' || *src == '\t')
    ++src;
  quotef = 0;
  while (*src) {
    if (*src == '~') {
      ++src;
      if (*src == 0)
        break;
      switch (*src++) {
      case 'r':
        c = 13;
        break;
      case 'n':
        c = 13;
        break;
      case 'l':
        c = 10;
        break;
      case 't':
        c = 9;
        break;
      case 'b':
        c = 8;
        break;
      case 'f':
        c = 12;
        break;
      default:
        c = *(src - 1);
      }
      if (--size > 0) {
        *tok++ = c;
      }
    } else {
      if (quotef) {
        if (*src == '"')
          break;
      } else {
        if (*src == ' ' || *src == '\t')
          break;
      }
      if (*src == '"')
        quotef = 1;
      c = *src++;
      if (--size > 0)
        *tok++ = c;
    }
  }
  if (*src)
    ++src;
  *tok = 0;
  return (src);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<token>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  cmp    $0x9,%cl
  je     L38
  cmp    $0x20,%cl
  jne    L102
  nopl   0x0(%rax)
L38:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  cmp    $0x20,%cl
  je     L38
  cmp    $0x9,%cl
  je     L38
L102:
  test   %cl,%cl
  je     L31
  sub    $0x1,%edx
  xor    %r8d,%r8d
  lea    D0(%rip),%r9
  jmp    L152
  nopl   0x0(%rax)
L81:
  test   %r8d,%r8d
  je     L23
  cmp    $0x22,%cl
  je     L99
L129:
  add    $0x1,%rax
L12:
  test   %edx,%edx
  jle    L11
  mov    %cl,(%rsi)
  add    $0x1,%rsi
L11:
  movzbl (%rax),%ecx
  sub    $0x1,%edx
  test   %cl,%cl
  je     L31
L152:
  cmp    $0x7e,%cl
  jne    L81
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L204
  lea    -0x62(%rcx),%edi
  add    $0x2,%rax
  cmp    $0x12,%dil
  ja     L12
  movzbl %dil,%edi
  movslq (%r9,%rdi,4),%rdi
  add    %r9,%rdi
  notrack jmp *%rdi
  nopw   0x0(%rax,%rax,1)
  mov    $0xd,%ecx
  jmp    L12
  nop
  mov    $0xc,%ecx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
  mov    $0x8,%ecx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
  mov    $0x9,%ecx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L23:
  cmp    $0x20,%cl
  je     L99
  cmp    $0x9,%cl
  je     L99
  xor    %r8d,%r8d
  cmp    $0x22,%cl
  sete   %r8b
  jmp    L129
  nopl   0x0(%rax)
L99:
  movzbl (%rax),%edx
  cmp    $0x1,%dl
  sbb    $0xffffffffffffffff,%rax
L31:
  movb   $0x0,(%rsi)
  ret
  xchg   %ax,%ax
  mov    $0xa,%ecx
  jmp    L12
L204:
  movb   $0x0,(%rsi)
  add    $0x1,%rax
  ret
```

assistant: ```c
char *token(char *src, char *tok, int size) {
  register int quotef;
  register char c;
  while (*src == ' ' || *src == '\t')
    ++src;
  quotef = 0;
  while (*src) {
    if (*src == '~') {
      ++src;
      if (*src == 0)
        break;
      switch (*src++) {
      case 'r':
        c = 13;
        break;
      case 'n':
        c = 13;
        break;
      case 'l':
        c = 10;
        break;
      case 't':
        c = 9;
        break;
      case 'b':
        c = 8;
        break;
      case 'f':
        c = 12;
        break;
      default:
        c = *(src - 1);
      }
      if (--size > 0) {
        *tok++ = c;
      }
    } else {
      if (quotef) {
        if (*src == '"')
          break;
      } else {
        if (*src == ' ' || *src == '\t')
          break;
      }
      if (*src == '"')
        quotef = 1;
      c = *src++;
      if (--size > 0)
        *tok++ = c;
    }
  }
  if (*src)
    ++src;
  *tok = 0;
  return (src);
}
```
user: What is the c source code of the assembly code below:

```asm
<token>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  cmp    $0x9,%cl
  je     L169
  cmp    $0x20,%cl
  jne    L184
  nopl   0x0(%rax)
L169:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  cmp    $0x20,%cl
  je     L169
  cmp    $0x9,%cl
  je     L169
L184:
  test   %cl,%cl
  je     L119
  sub    $0x1,%edx
  xor    %r8d,%r8d
  lea    D4(%rip),%r9
  jmp    L185
  nopl   0x0(%rax)
L48:
  test   %r8d,%r8d
  je     L20
  cmp    $0x22,%cl
  je     L117
L7:
  add    $0x1,%rax
L40:
  test   %edx,%edx
  jle    L199
  mov    %cl,(%rsi)
  add    $0x1,%rsi
L199:
  movzbl (%rax),%ecx
  sub    $0x1,%edx
  test   %cl,%cl
  je     L119
L185:
  cmp    $0x7e,%cl
  jne    L48
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L136
  lea    -0x62(%rcx),%edi
  add    $0x2,%rax
  cmp    $0x12,%dil
  ja     L40
  movzbl %dil,%edi
  movslq (%r9,%rdi,4),%rdi
  add    %r9,%rdi
  notrack jmp *%rdi
  nopw   0x0(%rax,%rax,1)
  mov    $0xd,%ecx
  jmp    L40
  nop
  mov    $0xc,%ecx
  jmp    L40
  nopw   0x0(%rax,%rax,1)
  mov    $0x8,%ecx
  jmp    L40
  nopw   0x0(%rax,%rax,1)
  mov    $0x9,%ecx
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L20:
  cmp    $0x20,%cl
  je     L117
  cmp    $0x9,%cl
  je     L117
  xor    %r8d,%r8d
  cmp    $0x22,%cl
  sete   %r8b
  jmp    L7
  nopl   0x0(%rax)
L117:
  movzbl (%rax),%edx
  cmp    $0x1,%dl
  sbb    $0xffffffffffffffff,%rax
L119:
  movb   $0x0,(%rsi)
  ret
  xchg   %ax,%ax
  mov    $0xa,%ecx
  jmp    L40
L136:
  movb   $0x0,(%rsi)
  add    $0x1,%rax
  ret
```

assistant: ```c
char *token(char *src, char *tok, int size) {
  register int quotef;
  register char c;
  while (*src == ' ' || *src == '\t')
    ++src;
  quotef = 0;
  while (*src) {
    if (*src == '~') {
      ++src;
      if (*src == 0)
        break;
      switch (*src++) {
      case 'r':
        c = 13;
        break;
      case 'n':
        c = 13;
        break;
      case 'l':
        c = 10;
        break;
      case 't':
        c = 9;
        break;
      case 'b':
        c = 8;
        break;
      case 'f':
        c = 12;
        break;
      default:
        c = *(src - 1);
      }
      if (--size > 0) {
        *tok++ = c;
      }
    } else {
      if (quotef) {
        if (*src == '"')
          break;
      } else {
        if (*src == ' ' || *src == '\t')
          break;
      }
      if (*src == '"')
        quotef = 1;
      c = *src++;
      if (--size > 0)
        *tok++ = c;
    }
  }
  if (*src)
    ++src;
  *tok = 0;
  return (src);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<trace_read_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void trace_read_reset(void) {
  static struct task_set *priv_ts;
  priv_ts == NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<trace_read_reset>:
  endbr64
  ret
```

assistant: ```c
void trace_read_reset(void) {
  static struct task_set *priv_ts;
  priv_ts == NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trace_read_reset>:
  endbr64
  ret
```

assistant: ```c
void trace_read_reset(void) {
  static struct task_set *priv_ts;
  priv_ts == NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trace_read_reset>:
  endbr64
  ret
```

assistant: ```c
void trace_read_reset(void) {
  static struct task_set *priv_ts;
  priv_ts == NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x2,%esi
  mov    $0xffffffff,%edi
  call   <int_add@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <int_sub@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <int_mul@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0xfffffffe,%esi
  mov    $0x4,%edi
  call   <int_div@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b, c, d;
  a = int_add(-1, 2);
  b = int_sub(1, 2);
  c = int_mul(3, 4);
  d = int_div(4, -2);
  return (a + b + c + d) ? 0 : 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2,%esi
  mov    $0xffffffff,%edi
  call   <int_add@plt>
  mov    %eax,%ebx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <int_sub@plt>
  mov    %eax,%r12d
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <int_mul@plt>
  mov    %eax,%ebp
  mov    $0xfffffffe,%esi
  mov    $0x4,%edi
  call   <int_div@plt>
  add    %r12d,%ebx
  add    %ebp,%ebx
  add    %eax,%ebx
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b, c, d;
  a = int_add(-1, 2);
  b = int_sub(1, 2);
  c = int_mul(3, 4);
  d = int_div(4, -2);
  return (a + b + c + d) ? 0 : 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  mov    $0xffffffff,%edi
  push   %rbp
  push   %rbx
  call   <int_add@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <int_sub@plt>
  mov    $0x4,%esi
  mov    $0x3,%edi
  mov    %eax,%r12d
  call   <int_mul@plt>
  add    %r12d,%ebx
  mov    $0xfffffffe,%esi
  mov    $0x4,%edi
  mov    %eax,%ebp
  call   <int_div@plt>
  add    %ebp,%ebx
  add    %eax,%ebx
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  movzbl %al,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b, c, d;
  a = int_add(-1, 2);
  b = int_sub(1, 2);
  c = int_mul(3, 4);
  d = int_div(4, -2);
  return (a + b + c + d) ? 0 : 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  mov    $0xffffffff,%edi
  push   %rbp
  push   %rbx
  call   <int_add@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <int_sub@plt>
  mov    $0x4,%esi
  mov    $0x3,%edi
  mov    %eax,%r12d
  call   <int_mul@plt>
  add    %r12d,%ebx
  mov    $0xfffffffe,%esi
  mov    $0x4,%edi
  mov    %eax,%ebp
  call   <int_div@plt>
  add    %ebp,%ebx
  add    %eax,%ebx
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  movzbl %al,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b, c, d;
  a = int_add(-1, 2);
  b = int_sub(1, 2);
  c = int_mul(3, 4);
  d = int_div(4, -2);
  return (a + b + c + d) ? 0 : 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_bigint_mul136>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  jmp    L18
L42:
  lea    -0x70(%rbp),%rax
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <randombytes@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <randombytes@plt>
  lea    -0x50(%rbp),%rdx
  lea    -0x70(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bigint_mul136@plt>
  lea    -0x70(%rbp),%rax
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <bigint_print@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <bigint_print@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <bigint_print@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  addl   $0x1,-0x74(%rbp)
L18:
  cmpl   $0x3b,-0x74(%rbp)
  jle    L42
  movl   $0x0,-0x78(%rbp)
  jmp    L28
L34:
  mov    -0x78(%rbp),%eax
  cltq
  movb   $0xff,-0x50(%rbp,%rax,1)
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x78(%rbp)
L28:
  cmpl   $0x10,-0x78(%rbp)
  jle    L34
  lea    -0x50(%rbp),%rdx
  lea    -0x70(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bigint_mul136@plt>
  lea    -0x70(%rbp),%rax
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <bigint_print@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <bigint_print@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <bigint_print@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D35
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D42
datatype: string

tool: D35: *

tool: D18: -

tool: D42: 


assistant: ```c
void test_bigint_mul136() {
  unsigned char a[17], b[17], r[34];
  int i, n;
  for (n = 0; n < 60; n++) {
    randombytes(a, 17);
    randombytes(b, 17);
    bigint_mul136(r, a, b);
    bigint_print(a, 17);
    print("*");
    bigint_print(b, 17);
    print("-");
    bigint_print(r, 34);
    print("\r\n");
  }
  for (i = 0; i < 17; i++)
    a[i] = b[i] = 255;
  bigint_mul136(r, a, b);
  bigint_print(a, 17);
  print("*");
  bigint_print(b, 17);
  print("-");
  bigint_print(r, 34);
  print("\r\n");
}
```