ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<setattr>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x8,%rsp
L5:
  mov    %rbp,%rdx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <tcsetattr@plt>
  cmp    $0xffffffff,%eax
  jne    L24
  sub    $0x1,%ebx
  je     L24
  mov    D11(%rip),%rdx
  mov    D12(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L5
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int setattr(int fd, int opt, const struct termios *arg) {
  int result, retries = 3;
  while (-1 == (result = tcsetattr(fd, opt, arg)) && retries > 0) {
    retries--;
    if (EINTR == errno)
      continue;
    break;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_36_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  or     -0x10(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_36_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk1 = S ^ T;
  stk2 = D ^ S;
  stk1 = stk1 & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrop3_36_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%ecx
  xor    %esi,%ecx
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  mov    %edi,%edx
  xor    $0xff,%dl
  and    %ecx,%edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_36_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk1 = S ^ T;
  stk2 = D ^ S;
  stk1 = stk1 & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What is the c source code of the assembly code below:

```asm
<xrop3_36_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%ecx
  mov    %edi,%edx
  shl    $0x8,%esi
  xor    $0xff,%dl
  or     %eax,%esi
  mov    %esi,%eax
  xor    %esi,%ecx
  not    %eax
  and    %ecx,%edx
  or     %edi,%eax
  not    %edi
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_36_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk1 = S ^ T;
  stk2 = D ^ S;
  stk1 = stk1 & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string
name: parse_data
arguments: data_tag: D44
type_infered: string
name: parse_data
arguments: data_tag: D56
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D45
type_infered: string

tool: D0: Podaj x1: 

tool: D44: %d

tool: D56: Podaj x2: 

tool: D7: x1 = %d


tool: D45: x2 = %d


assistant: ```c
int main(void) {
  int x1, x2;
  printf("Podaj x1: ");
  scanf("%d", &x1);
  printf("Podaj x2: ");
  scanf("%d", &x2);
  printf("x1 = %d\n", x1);
  printf("x2 = %d\n", x2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D49
datatype: string
name: read_data
arguments: label: D1
datatype: string
name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D42
datatype: string
name: read_data
arguments: label: D19
datatype: string

tool: D49: Podaj x1: 

tool: D1: %d

tool: D8: Podaj x2: 

tool: D42: x1 = %d


tool: D19: x2 = %d


assistant: ```c
int main(void) {
  int x1, x2;
  printf("Podaj x1: ");
  scanf("%d", &x1);
  printf("Podaj x2: ");
  scanf("%d", &x2);
  printf("x1 = %d\n", x1);
  printf("x2 = %d\n", x2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rdi
  lea    D42(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type_infered: string
name: retrieve_data
arguments: data_tag: D42
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D38
type_infered: string
name: retrieve_data
arguments: data_tag: D33
type_infered: string

tool: D22: Podaj x1: 

tool: D42: %d

tool: D7: Podaj x2: 

tool: D38: x1 = %d


tool: D33: x2 = %d


assistant: ```c
int main(void) {
  int x1, x2;
  printf("Podaj x1: ");
  scanf("%d", &x1);
  printf("Podaj x2: ");
  scanf("%d", &x2);
  printf("x1 = %d\n", x1);
  printf("x2 = %d\n", x2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  lea    D15(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D39
datatype: string
name: extract_symbolic_data
arguments: tag: D15
datatype: string
name: extract_symbolic_data
arguments: tag: D25
datatype: string
name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D38
datatype: string

tool: D39: Podaj x1: 

tool: D15: %d

tool: D25: Podaj x2: 

tool: D13: x1 = %d


tool: D38: x2 = %d


assistant: ```c
int main(void) {
  int x1, x2;
  printf("Podaj x1: ");
  scanf("%d", &x1);
  printf("Podaj x2: ");
  scanf("%d", &x2);
  printf("x1 = %d\n", x1);
  printf("x2 = %d\n", x2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bc_str_starts_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L2
  mov    $0x0,%eax
  jmp    L16
L2:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L16:
  leave
  ret
```

assistant: ```c
bool bc_str_starts_with(const char *str, const char *prefix) {
  int str_l = strlen(str);
  int str_lp = strlen(prefix);
  if (str_lp > str_l)
    return false;
  return strncmp(str, prefix, str_lp) == 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bc_str_starts_with>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%r12d
  jge    L19
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L15
```

assistant: ```c
bool bc_str_starts_with(const char *str, const char *prefix) {
  int str_l = strlen(str);
  int str_lp = strlen(prefix);
  if (str_lp > str_l)
    return false;
  return strncmp(str, prefix, str_lp) == 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bc_str_starts_with>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    %edx,%ebx
  jl     L1
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool bc_str_starts_with(const char *str, const char *prefix) {
  int str_l = strlen(str);
  int str_lp = strlen(prefix);
  if (str_lp > str_l)
    return false;
  return strncmp(str, prefix, str_lp) == 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bc_str_starts_with>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    %edx,%ebx
  jl     L3
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool bc_str_starts_with(const char *str, const char *prefix) {
  int str_l = strlen(str);
  int str_lp = strlen(prefix);
  if (str_lp > str_l)
    return false;
  return strncmp(str, prefix, str_lp) == 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%r8
  lea    -0x1c(%rbp),%rdi
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x14(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  add    $0x10,%rsp
  movss  -0x28(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L70
  ucomiss %xmm1,%xmm0
  jne    L70
  movss  -0x18(%rbp),%xmm0
  movss  -0x28(%rbp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L29
  ucomiss %xmm1,%xmm0
  jne    L29
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L29:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L70:
  movss  -0x1c(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  -0x20(%rbp),%xmm1
  movss  -0x28(%rbp),%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  -0x18(%rbp),%xmm1
  movss  -0x28(%rbp),%xmm2
  subss  %xmm2,%xmm1
  mulss  -0x10(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L19
  pxor   %xmm0,%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jne    L19
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L19:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L99
  call   <__stack_chk_fail@plt>
L99:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D35
datatype: string
name: retrieve_data
arguments: tag: D3
datatype: string
name: retrieve_data
arguments: tag: D32
datatype: string

tool: D35: %f%f%f%f%f%f

tool: D3: All the points are on same line.

tool: D32: All the points are not on same line.

assistant: ```c
int main() {
  float x1, y1, x2, y2, x3, y3, slope, v;
  scanf("%f%f%f%f%f%f", &x1, &y1, &x2, &y2, &x3, &y3);
  if (x1 == x2) {
    if (x3 == x1)
      printf("All the points are on same line.");
    else
      printf("All the points are not on same line.");
  } else {
    slope = (y2 - y1) / (x2 - x1);
    v = (y3 - y1) - slope * (x3 - x1);
    if (v == 0)
      printf("All the points are on same line.");
    else
      printf("All the points are not on same line.");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm0
  movss  0x18(%rsp),%xmm1
  add    $0x10,%rsp
  ucomiss %xmm1,%xmm0
  jp     L17
  jne    L17
  ucomiss 0x10(%rsp),%xmm0
  jp     L85
  jne    L85
  lea    D34(%rip),%rdi
  call   <printf@plt>
L55:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L85:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L17:
  movss  0x4(%rsp),%xmm4
  movss  0x14(%rsp),%xmm2
  movaps %xmm2,%xmm3
  subss  %xmm4,%xmm3
  movss  0xc(%rsp),%xmm2
  subss  %xmm4,%xmm2
  subss  %xmm0,%xmm1
  divss  %xmm1,%xmm2
  movss  0x10(%rsp),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm1,%xmm2
  subss  %xmm2,%xmm3
  ucomiss D29(%rip),%xmm3
  jp     L83
  jne    L83
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L83:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D34
type_guessed: string
name: unpack_data
arguments: data_tag: D50
type_guessed: string
name: unpack_data
arguments: data_tag: D29
type_guessed: byte[4]

tool: D0: %f%f%f%f%f%f

tool: D34: All the points are on same line.

tool: D50: All the points are not on same line.

tool: {"D29": [0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  float x1, y1, x2, y2, x3, y3, slope, v;
  scanf("%f%f%f%f%f%f", &x1, &y1, &x2, &y2, &x3, &y3);
  if (x1 == x2) {
    if (x3 == x1)
      printf("All the points are on same line.");
    else
      printf("All the points are not on same line.");
  } else {
    slope = (y2 - y1) / (x2 - x1);
    v = (y3 - y1) - slope * (x3 - x1);
    if (v == 0)
      printf("All the points are on same line.");
    else
      printf("All the points are not on same line.");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  pop    %rax
  pop    %rdx
  ucomiss %xmm2,%xmm1
  jp     L35
  jne    L35
  ucomiss 0x10(%rsp),%xmm1
  jp     L15
L56:
  jne    L15
  lea    D25(%rip),%rdi
  call   <printf@plt>
L65:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L35:
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm4
  subss  %xmm1,%xmm2
  movaps %xmm0,%xmm3
  movss  0xc(%rsp),%xmm0
  subss  %xmm4,%xmm3
  subss  %xmm4,%xmm0
  divss  %xmm2,%xmm0
  movss  0x10(%rsp),%xmm2
  subss  %xmm1,%xmm2
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm3
  ucomiss D18(%rip),%xmm3
  jnp    L56
L15:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L65
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D18
datatype: byte[4]
name: retrieve_data
arguments: label: D22
datatype: string

tool: D3: %f%f%f%f%f%f

tool: D25: All the points are on same line.

tool: {"D18": [0x00,0x00,0x00,0x00]}

tool: D22: All the points are not on same line.

assistant: ```c
int main() {
  float x1, y1, x2, y2, x3, y3, slope, v;
  scanf("%f%f%f%f%f%f", &x1, &y1, &x2, &y2, &x3, &y3);
  if (x1 == x2) {
    if (x3 == x1)
      printf("All the points are on same line.");
    else
      printf("All the points are not on same line.");
  } else {
    slope = (y2 - y1) / (x2 - x1);
    v = (y3 - y1) - slope * (x3 - x1);
    if (v == 0)
      printf("All the points are on same line.");
    else
      printf("All the points are not on same line.");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  pop    %rax
  pop    %rdx
  ucomiss %xmm2,%xmm1
  jp     L33
  jne    L33
  ucomiss 0x10(%rsp),%xmm1
  jp     L69
L39:
  jne    L69
  lea    D26(%rip),%rdi
  call   <printf@plt>
L47:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L33:
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm4
  subss  %xmm1,%xmm2
  movaps %xmm0,%xmm3
  movss  0xc(%rsp),%xmm0
  subss  %xmm4,%xmm3
  subss  %xmm4,%xmm0
  divss  %xmm2,%xmm0
  movss  0x10(%rsp),%xmm2
  subss  %xmm1,%xmm2
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm3
  ucomiss D3(%rip),%xmm3
  jnp    L39
L69:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L47
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D31
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D3
data_type: byte[4]
name: read_data
arguments: tag: D6
data_type: string

tool: D31: %f%f%f%f%f%f

tool: D26: All the points are on same line.

tool: {"D3": [0x00,0x00,0x00,0x00]}

tool: D6: All the points are not on same line.

assistant: ```c
int main() {
  float x1, y1, x2, y2, x3, y3, slope, v;
  scanf("%f%f%f%f%f%f", &x1, &y1, &x2, &y2, &x3, &y3);
  if (x1 == x2) {
    if (x3 == x1)
      printf("All the points are on same line.");
    else
      printf("All the points are not on same line.");
  } else {
    slope = (y2 - y1) / (x2 - x1);
    v = (y3 - y1) - slope * (x3 - x1);
    if (v == 0)
      printf("All the points are on same line.");
    else
      printf("All the points are not on same line.");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fset_config_change_help_color_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  call   <fset_bar_item_update@plt>
  nop
  leave
  ret
```

assistant: ```c
void fset_config_change_help_color_cb(const void *pointer, void *data, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)option;
  fset_bar_item_update();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fset_config_change_help_color_cb>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fset_bar_item_update@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fset_config_change_help_color_cb(const void *pointer, void *data, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)option;
  fset_bar_item_update();
}
```
user: Translate the below assembly code into C programming language:

```asm
<fset_config_change_help_color_cb>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <fset_bar_item_update@plt>
```

assistant: ```c
void fset_config_change_help_color_cb(const void *pointer, void *data, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)option;
  fset_bar_item_update();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fset_config_change_help_color_cb>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <fset_bar_item_update@plt>
```

assistant: ```c
void fset_config_change_help_color_cb(const void *pointer, void *data, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)option;
  fset_bar_item_update();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<w_strcmp0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  cmpq   $0x0,-0x10(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L36
L12:
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0xffffffff,%eax
  jmp    L36
L3:
  cmpq   $0x0,-0x10(%rbp)
  jne    L18
  mov    $0x1,%eax
  jmp    L36
L18:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
L36:
  leave
  ret
```

assistant: ```c
int w_strcmp0(const char *s1, const char *s2) {
  if (s1 == NULL && s2 == NULL) {
    return 0;
  } else if (s1 == NULL) {
    return -1;
  } else if (s2 == NULL) {
    return 1;
  }
  return strcmp(s1, s2);
}
```