ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<HSIround>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  comisd D0(%rip),%xmm0
  jbe    L14
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L12
L14:
  mov    -0x4(%rbp),%eax
L12:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: f64

tool: D0: 0.5

assistant: ```c
int HSIround(double d) {
  int n = (int)d;
  return (d - (double)n) > 0.5 ? (int)(n + 1) : (int)n;
}
```
user: What is the c source code of the assembly code below:

```asm
<HSIround>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D5(%rip),%xmm0
  seta   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type: f64

tool: D5: 0.5

assistant: ```c
int HSIround(double d) {
  int n = (int)d;
  return (d - (double)n) > 0.5 ? (int)(n + 1) : (int)n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HSIround>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  xor    %edx,%edx
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D7(%rip),%xmm0
  seta   %dl
  add    %edx,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: f64

tool: D7: 0.5

assistant: ```c
int HSIround(double d) {
  int n = (int)d;
  return (d - (double)n) > 0.5 ? (int)(n + 1) : (int)n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<HSIround>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  xor    %edx,%edx
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D1(%rip),%xmm0
  seta   %dl
  add    %edx,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: f64

tool: D1: 0.5

assistant: ```c
int HSIround(double d) {
  int n = (int)d;
  return (d - (double)n) > 0.5 ? (int)(n + 1) : (int)n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<elim_par>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  ja     L55
  mov    $0x0,%eax
  jmp    L57
L55:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  jne    L49
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  je     L45
L49:
  mov    $0x0,%eax
  jmp    L57
L45:
  mov    -0xc(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  mov    $0x0,%edi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L57
L21:
  mov    -0xc(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L57:
  leave
  ret
```

assistant: ```c
unsigned char *elim_par(const unsigned char *par_str) {
  unsigned char *ret;
  unsigned int par_len = strlen((const char *)par_str);
  if (par_len < 2)
    return NULL;
  if (par_str[0] != '(' || par_str[par_len - 1] != ')')
    return NULL;
  ret = (unsigned char *)calloc(par_len, sizeof(char));
  if (!(ret)) {
    perror(NULL);
    return NULL;
  };
  strncpy(ret, par_str + 1, par_len - 2);
  ret[par_len - 2] = '\0';
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<elim_par>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  cmp    $0x1,%eax
  jbe    L53
  mov    %eax,%ebx
  mov    $0x0,%r12d
  cmpb   $0x28,0x0(%rbp)
  jne    L44
  lea    -0x1(%rax),%eax
  cmpb   $0x29,0x0(%rbp,%rax,1)
  jne    L44
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  sub    $0x2,%ebx
  lea    0x1(%rbp),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %ebx,%ebx
  movb   $0x0,(%r12,%rbx,1)
L44:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0x0,%edi
  call   <perror@plt>
  jmp    L44
L53:
  mov    $0x0,%r12d
  jmp    L44
```

assistant: ```c
unsigned char *elim_par(const unsigned char *par_str) {
  unsigned char *ret;
  unsigned int par_len = strlen((const char *)par_str);
  if (par_len < 2)
    return NULL;
  if (par_str[0] != '(' || par_str[par_len - 1] != ')')
    return NULL;
  ret = (unsigned char *)calloc(par_len, sizeof(char));
  if (!(ret)) {
    perror(NULL);
    return NULL;
  };
  strncpy(ret, par_str + 1, par_len - 2);
  ret[par_len - 2] = '\0';
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<elim_par>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jbe    L40
  cmpb   $0x28,0x0(%rbp)
  jne    L40
  mov    %eax,%ebx
  lea    -0x1(%rax),%eax
  cmpb   $0x29,0x0(%rbp,%rax,1)
  jne    L40
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  sub    $0x2,%ebx
  lea    0x1(%rbp),%rsi
  mov    %rax,%rdi
  mov    %ebx,%edx
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L40:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  xor    %edi,%edi
  call   <perror@plt>
  jmp    L40
```

assistant: ```c
unsigned char *elim_par(const unsigned char *par_str) {
  unsigned char *ret;
  unsigned int par_len = strlen((const char *)par_str);
  if (par_len < 2)
    return NULL;
  if (par_str[0] != '(' || par_str[par_len - 1] != ')')
    return NULL;
  ret = (unsigned char *)calloc(par_len, sizeof(char));
  if (!(ret)) {
    perror(NULL);
    return NULL;
  };
  strncpy(ret, par_str + 1, par_len - 2);
  ret[par_len - 2] = '\0';
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<elim_par>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jbe    L14
  cmpb   $0x28,0x0(%rbp)
  jne    L14
  mov    %eax,%ebx
  lea    -0x1(%rax),%eax
  cmpb   $0x29,0x0(%rbp,%rax,1)
  jne    L14
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L40
  sub    $0x2,%ebx
  lea    0x1(%rbp),%rsi
  mov    %rax,%rdi
  mov    %ebx,%edx
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L40:
  xor    %edi,%edi
  call   <perror@plt>
  jmp    L14
```

assistant: ```c
unsigned char *elim_par(const unsigned char *par_str) {
  unsigned char *ret;
  unsigned int par_len = strlen((const char *)par_str);
  if (par_len < 2)
    return NULL;
  if (par_str[0] != '(' || par_str[par_len - 1] != ')')
    return NULL;
  ret = (unsigned char *)calloc(par_len, sizeof(char));
  if (!(ret)) {
    perror(NULL);
    return NULL;
  };
  strncpy(ret, par_str + 1, par_len - 2);
  ret[par_len - 2] = '\0';
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<create_rp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L6
L4:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <rand_normal_r@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L6:
  mov    -0x2c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L4
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void create_rp(double *X, int M, int Mp) {
  int j;
  for (j = 0; j < M * Mp; j++)
    X[j] = rand_normal_r();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<create_rp>:
  endbr64
  imul   %edx,%esi
  test   %esi,%esi
  jle    L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L10:
  mov    $0x0,%eax
  call   <rand_normal_r@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
void create_rp(double *X, int M, int Mp) {
  int j;
  for (j = 0; j < M * Mp; j++)
    X[j] = rand_normal_r();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<create_rp>:
  endbr64
  imul   %edx,%esi
  test   %esi,%esi
  jle    L14
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <rand_normal_r@plt>
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
void create_rp(double *X, int M, int Mp) {
  int j;
  for (j = 0; j < M * Mp; j++)
    X[j] = rand_normal_r();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_rp>:
  endbr64
  imul   %edx,%esi
  test   %esi,%esi
  jle    L14
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <rand_normal_r@plt>
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
void create_rp(double *X, int M, int Mp) {
  int j;
  for (j = 0; j < M * Mp; j++)
    X[j] = rand_normal_r();
}
```
user: Translate the below assembly code into C programming language:

```asm
<dieWithMessage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: %s


assistant: ```c
void dieWithMessage(char *msg) {
  printf("%s\n", msg);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dieWithMessage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string

tool: D8: %s


assistant: ```c
void dieWithMessage(char *msg) {
  printf("%s\n", msg);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dieWithMessage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D0: %s


assistant: ```c
void dieWithMessage(char *msg) {
  printf("%s\n", msg);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dieWithMessage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: %s


assistant: ```c
void dieWithMessage(char *msg) {
  printf("%s\n", msg);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readArgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L11
L6:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x3a,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <readField@plt>
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L13
  cmpl   $0x0,-0xc(%rbp)
  jg     L6
L13:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int readArgs(int sd, char *argv[], size_t n) {
  size_t i = 0;
  int ret = 1;
  while (i < n && ret > 0) {
    ret = readField(sd, &argv[i], ':');
    i++;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readArgs>:
  endbr64
  test   %rdx,%rdx
  je     L26
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rdx,%r12
  mov    %rsi,%rbx
  mov    $0x0,%r13d
L15:
  mov    $0x3a,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <readField@plt>
  add    $0x1,%r13
  add    $0x8,%rbx
  cmp    %r13,%r12
  jbe    L22
  test   %eax,%eax
  jg     L15
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int readArgs(int sd, char *argv[], size_t n) {
  size_t i = 0;
  int ret = 1;
  while (i < n && ret > 0) {
    ret = readField(sd, &argv[i], ':');
    i++;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readArgs>:
  endbr64
  test   %rdx,%rdx
  je     L3
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L15:
  mov    %rbx,%rsi
  mov    $0x3a,%edx
  mov    %ebp,%edi
  add    $0x1,%r13
  call   <readField@plt>
  add    $0x8,%rbx
  cmp    %r13,%r12
  jbe    L7
  test   %eax,%eax
  jg     L15
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int readArgs(int sd, char *argv[], size_t n) {
  size_t i = 0;
  int ret = 1;
  while (i < n && ret > 0) {
    ret = readField(sd, &argv[i], ':');
    i++;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readArgs>:
  endbr64
  test   %rdx,%rdx
  je     L4
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L19:
  mov    %rbx,%rsi
  mov    $0x3a,%edx
  mov    %ebp,%edi
  add    $0x1,%r13
  call   <readField@plt>
  add    $0x8,%rbx
  cmp    %r13,%r12
  jbe    L12
  test   %eax,%eax
  jg     L19
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int readArgs(int sd, char *argv[], size_t n) {
  size_t i = 0;
  int ret = 1;
  while (i < n && ret > 0) {
    ret = readField(sd, &argv[i], ':');
    i++;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: %s%s

assistant: ```c
char *ext(char *path, char *extension) {
  char *file = basename(path);
  char *temp = malloc((strlen(file) + strlen(extension) + 1) * sizeof(char));
  sprintf(temp, "%s%s", file, extension);
  return (temp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ext>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  call   <basename@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rcx
  mov    %rbp,%rdx
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: %s%s

assistant: ```c
char *ext(char *path, char *extension) {
  char *file = basename(path);
  char *temp = malloc((strlen(file) + strlen(extension) + 1) * sizeof(char));
  sprintf(temp, "%s%s", file, extension);
  return (temp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ext>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  call   <basename@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  lea    D4(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D4: %s%s

assistant: ```c
char *ext(char *path, char *extension) {
  char *file = basename(path);
  char *temp = malloc((strlen(file) + strlen(extension) + 1) * sizeof(char));
  sprintf(temp, "%s%s", file, extension);
  return (temp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ext>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  call   <basename@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  lea    D6(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: %s%s

assistant: ```c
char *ext(char *path, char *extension) {
  char *file = basename(path);
  char *temp = malloc((strlen(file) + strlen(extension) + 1) * sizeof(char));
  sprintf(temp, "%s%s", file, extension);
  return (temp);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xfffffffd,-0x20(%rbp)
  movl   $0x4,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x5a,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <twoSum@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int nums[] = {-3, 4, 3, 90};
  twoSum(nums, 4, 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xfffffffd,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x5a,0xc(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%edx
  mov    $0x4,%esi
  call   <twoSum@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int nums[] = {-3, 4, 3, 90};
  twoSum(nums, 4, 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4fffffffd,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x5a00000003,%rax
  mov    %rax,0x8(%rsp)
  call   <twoSum@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int nums[] = {-3, 4, 3, 90};
  twoSum(nums, 4, 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D7(%rip),%xmm0
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <twoSum@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type: byte[16]

tool: {"D7": [0xfd,0xff,0xff,0xff,0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x5a,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char const *argv[]) {
  int nums[] = {-3, 4, 3, 90};
  twoSum(nums, 4, 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x5,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L25
L11:
  lea    -0x20(%rbp),%rcx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x44(%rbp),%edx
  mov    -0x44(%rbp),%eax
  mov    $0xc,%r8d
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L25:
  cmpl   $0x1,-0x44(%rbp)
  jle    L11
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D43
type_infered: string
name: retrieve_data
arguments: data_label: D60
type_infered: string
name: retrieve_data
arguments: data_label: D4
type_infered: string
name: retrieve_data
arguments: data_label: D36
type_infered: string

tool: D43: %d


tool: D60: %p


tool: D4: &matrix[%d]: %p sizeof(matrix[%d]): %d


tool: D36: -----------------

assistant: ```c
int main() {
  int vector[5];
  printf("%d\n", sizeof(vector) / sizeof(int));
  printf("%p\n", vector);
  printf("%p\n", &vector[0]);
  int matrix[2][3];
  for (int i = 0; i < 2; i++) {
    printf("&matrix[%d]: %p sizeof(matrix[%d]): %d\n", i, &matrix[i], i, sizeof(matrix[i]));
  }
  printf("-----------------\n");
  printf("%d\n", sizeof(char));
  printf("%d\n", sizeof('a'));
  return 0;
}
```