ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<pr_error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pr_error(const char *msg) {
  perror(msg);
  abort();
}
```
user: What is the c source code of the assembly code below:

```asm
<pr_error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

assistant: ```c
void pr_error(const char *msg) {
  perror(msg);
  abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pr_error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

assistant: ```c
void pr_error(const char *msg) {
  perror(msg);
  abort();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<convolve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x30(%rbp)
  mov    %esi,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movw   $0x0,-0x8(%rbp)
  jmp    L8
L57:
  movzwl -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  movzwl -0x8(%rbp),%eax
  movzwl -0x20(%rbp),%edx
  sub    $0x1,%edx
  cmp    %edx,%eax
  jl     L26
  movzwl -0x8(%rbp),%eax
  sub    -0x20(%rbp),%ax
  add    $0x1,%eax
  jmp    L11
L26:
  mov    $0x0,%eax
L11:
  mov    %ax,-0x4(%rbp)
  movzwl -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  movzwl -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x4(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  jmp    L46
L16:
  movzwl -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  movzwl -0x6(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  movzwl -0x8(%rbp),%eax
  movzwl -0x6(%rbp),%esi
  sub    %esi,%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  movzwl -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rsi
  mov    -0x30(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  movzwl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x6(%rbp)
L46:
  movzwl -0x6(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  jbe    L16
  movzwl -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x8(%rbp)
L8:
  movzwl -0x8(%rbp),%eax
  movzwl -0x1c(%rbp),%ecx
  movzwl -0x20(%rbp),%edx
  add    %ecx,%edx
  sub    $0x1,%edx
  cmp    %edx,%eax
  jl     L57
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void convolve(uint32_t Signal[], unsigned short SignalLen, uint32_t Kernel[], unsigned short KernelLen, uint32_t Result[]) {
  uint16_t n;
  for (n = 0; n < SignalLen + KernelLen - 1; n++) {
    unsigned short kmin, kmax, k;
    Result[n] = 0;
    kmin = (n >= KernelLen - 1) ? n - (KernelLen - 1) : 0;
    kmax = (n < SignalLen - 1) ? n : SignalLen - 1;
    for (k = kmin; k <= kmax; k++) {
      Result[n] += Signal[k] * Kernel[n - k];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<convolve>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movzwl %si,%ebx
  movzwl %cx,%ebp
  lea    -0x1(%rbx,%rbp,1),%r13d
  test   %r13d,%r13d
  jle    L60
  mov    %rdi,%r9
  mov    %rdx,%r10
  mov    %r8,%r12
  mov    $0x1,%r8d
  sub    %ecx,%r8d
  mov    $0x0,%r11d
  mov    $0x0,%esi
  sub    $0x1,%ebp
  sub    $0x1,%ebx
  jmp    L44
L2:
  cmp    %esi,%ebx
  mov    %esi,%eax
  cmovle %ebx,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
L49:
  movzwl %ax,%r14d
  mov    %esi,%edx
  sub    %r14d,%edx
  movslq %edx,%rdx
  movzwl %ax,%r14d
  mov    (%r10,%rdx,4),%edx
  imul   (%r9,%r14,4),%edx
  add    %edx,(%rcx)
  add    $0x1,%eax
  cmp    %di,%ax
  jbe    L49
L25:
  add    $0x1,%r11d
  movzwl %r11w,%esi
  add    $0x1,%r8d
  cmp    %r13d,%esi
  jge    L60
L44:
  movzwl %r11w,%eax
  lea    (%r12,%rax,4),%rcx
  movl   $0x0,(%rcx)
  cmp    %esi,%ebp
  jg     L2
  cmp    %esi,%ebx
  mov    %esi,%eax
  cmovle %ebx,%eax
  mov    %eax,%edi
  cmp    %r8w,%ax
  jb     L25
  mov    %r8d,%eax
  jmp    L49
L60:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void convolve(uint32_t Signal[], unsigned short SignalLen, uint32_t Kernel[], unsigned short KernelLen, uint32_t Result[]) {
  uint16_t n;
  for (n = 0; n < SignalLen + KernelLen - 1; n++) {
    unsigned short kmin, kmax, k;
    Result[n] = 0;
    kmin = (n >= KernelLen - 1) ? n - (KernelLen - 1) : 0;
    kmax = (n < SignalLen - 1) ? n : SignalLen - 1;
    for (k = kmin; k <= kmax; k++) {
      Result[n] += Signal[k] * Kernel[n - k];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<convolve>:
  endbr64
  push   %r15
  movzwl %si,%eax
  push   %r14
  push   %r13
  push   %r12
  movzwl %cx,%r12d
  lea    -0x1(%rax,%r12,1),%r14d
  push   %rbp
  push   %rbx
  test   %r14d,%r14d
  jle    L12
  mov    $0x1,%ebx
  mov    %r8,%r13
  mov    %rdi,%r10
  mov    %rdx,%r11
  sub    $0x1,%r12d
  sub    %ecx,%ebx
  xor    %r8d,%r8d
  xor    %esi,%esi
  lea    -0x1(%rax),%ebp
  nop
L11:
  cmp    %esi,%ebp
  mov    %esi,%edx
  movzwl %r8w,%eax
  cmovle %ebp,%edx
  lea    0x0(%r13,%rax,4),%rdi
  movl   $0x0,(%rdi)
  mov    %edx,%r9d
  cmp    %r12d,%esi
  jl     L7
  mov    %ebx,%eax
  cmp    %dx,%bx
  ja     L6
L37:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L14:
  movzwl %ax,%r15d
  mov    %esi,%edx
  sub    %r15d,%edx
  movzwl %ax,%r15d
  add    $0x1,%eax
  movslq %edx,%rdx
  mov    (%r11,%rdx,4),%edx
  imul   (%r10,%r15,4),%edx
  add    %edx,%ecx
  mov    %ecx,(%rdi)
  cmp    %r9w,%ax
  jbe    L14
L6:
  add    $0x1,%r8d
  add    $0x1,%ebx
  movzwl %r8w,%esi
  cmp    %r14d,%esi
  jl     L11
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  jmp    L37
```

assistant: ```c
void convolve(uint32_t Signal[], unsigned short SignalLen, uint32_t Kernel[], unsigned short KernelLen, uint32_t Result[]) {
  uint16_t n;
  for (n = 0; n < SignalLen + KernelLen - 1; n++) {
    unsigned short kmin, kmax, k;
    Result[n] = 0;
    kmin = (n >= KernelLen - 1) ? n - (KernelLen - 1) : 0;
    kmax = (n < SignalLen - 1) ? n : SignalLen - 1;
    for (k = kmin; k <= kmax; k++) {
      Result[n] += Signal[k] * Kernel[n - k];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<convolve>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  movzwl %cx,%r12d
  push   %rbp
  movzwl %si,%ebp
  lea    -0x1(%rbp,%r12,1),%r14d
  push   %rbx
  test   %r14d,%r14d
  jle    L23
  mov    $0x1,%ebx
  mov    %r8,%r13
  mov    %rdi,%r10
  mov    %rdx,%r11
  sub    $0x1,%r12d
  sub    $0x1,%ebp
  sub    %ecx,%ebx
  xor    %r8d,%r8d
  xor    %esi,%esi
  nop
L33:
  cmp    %ebp,%esi
  mov    %ebp,%edx
  movzwl %r8w,%eax
  cmovle %esi,%edx
  lea    0x0(%r13,%rax,4),%rdi
  movl   $0x0,(%rdi)
  mov    %edx,%r9d
  cmp    %r12d,%esi
  jl     L25
  mov    %ebx,%eax
  cmp    %dx,%bx
  ja     L36
L1:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L39:
  movzwl %ax,%r15d
  mov    %esi,%edx
  sub    %r15d,%edx
  movzwl %ax,%r15d
  add    $0x1,%eax
  movslq %edx,%rdx
  mov    (%r11,%rdx,4),%edx
  imul   (%r10,%r15,4),%edx
  add    %edx,%ecx
  mov    %ecx,(%rdi)
  cmp    %r9w,%ax
  jbe    L39
L36:
  add    $0x1,%r8d
  add    $0x1,%ebx
  movzwl %r8w,%esi
  cmp    %r14d,%esi
  jl     L33
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
void convolve(uint32_t Signal[], unsigned short SignalLen, uint32_t Kernel[], unsigned short KernelLen, uint32_t Result[]) {
  uint16_t n;
  for (n = 0; n < SignalLen + KernelLen - 1; n++) {
    unsigned short kmin, kmax, k;
    Result[n] = 0;
    kmin = (n >= KernelLen - 1) ? n - (KernelLen - 1) : 0;
    kmax = (n < SignalLen - 1) ? n : SignalLen - 1;
    for (k = kmin; k <= kmax; k++) {
      Result[n] += Signal[k] * Kernel[n - k];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calculateSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L12
  mov    D11(%rip),%rax
  jmp    L3
L12:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    D11(%rip),%rax
  add    %rdx,%rax
  mov    %rax,D20(%rip)
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <calculateSum>
L3:
  leave
  ret
```

assistant: ```c
long calculateSum(int a[], int n) {
  static long sum = 0;
  if (n == 0)
    return sum;
  sum = sum + a[n - 1];
  return calculateSum(a, --n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calculateSum>:
  endbr64
  test   %esi,%esi
  jne    L1
  mov    D8(%rip),%rax
  ret
L1:
  sub    $0x8,%rsp
  movslq %esi,%rax
  movslq -0x4(%rdi,%rax,4),%rax
  add    %rax,D18(%rip)
  sub    $0x1,%esi
  call   <calculateSum>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long calculateSum(int a[], int n) {
  static long sum = 0;
  if (n == 0)
    return sum;
  sum = sum + a[n - 1];
  return calculateSum(a, --n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculateSum>:
  endbr64
  mov    D13(%rip),%r8
  movslq %esi,%rax
  test   %esi,%esi
  je     L7
  nopw   0x0(%rax,%rax,1)
L5:
  movslq -0x4(%rdi,%rax,4),%rdx
  sub    $0x1,%rax
  add    %rdx,%r8
  test   %eax,%eax
  jne    L5
  mov    %r8,D18(%rip)
L7:
  mov    %r8,%rax
  ret
```

assistant: ```c
long calculateSum(int a[], int n) {
  static long sum = 0;
  if (n == 0)
    return sum;
  sum = sum + a[n - 1];
  return calculateSum(a, --n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<calculateSum>:
  endbr64
  mov    D12(%rip),%r9
  mov    %rdi,%r8
  mov    %esi,%edx
  test   %esi,%esi
  je     L31
  lea    -0x1(%rsi),%eax
  mov    %esi,%r10d
  cmp    $0x2,%eax
  jbe    L15
  movslq %esi,%rax
  shr    $0x2,%esi
  pxor   %xmm1,%xmm1
  pxor   %xmm4,%xmm4
  lea    -0x10(%rdi,%rax,4),%rcx
  lea    -0x1(%rsi),%edi
  lea    -0x10(%rcx),%rax
  shl    $0x4,%rdi
  mov    %rax,%rsi
  sub    %rdi,%rsi
  jmp    L60
  nopl   (%rax)
L68:
  sub    $0x10,%rax
L60:
  movdqu (%rcx),%xmm0
  movdqa %xmm4,%xmm2
  mov    %rax,%rcx
  pshufd $0x1b,%xmm0,%xmm0
  pcmpgtd %xmm0,%xmm2
  movdqa %xmm0,%xmm3
  punpckldq %xmm2,%xmm3
  punpckhdq %xmm2,%xmm0
  paddq  %xmm3,%xmm1
  paddq  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L68
  movdqa %xmm1,%xmm0
  psrldq $0x8,%xmm0
  paddq  %xmm0,%xmm1
  movq   %xmm1,%rax
  add    %rax,%r9
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  sub    %eax,%edx
  cmp    %eax,%r10d
  je     L20
  lea    -0x1(%rdx),%eax
L15:
  movslq %edx,%rcx
  movslq -0x4(%r8,%rcx,4),%rcx
  add    %rcx,%r9
  test   %eax,%eax
  je     L20
  cltq
  movslq -0x4(%r8,%rax,4),%rax
  add    %rax,%r9
  sub    $0x2,%edx
  je     L20
  movslq %edx,%rdx
  movslq -0x4(%r8,%rdx,4),%rax
  add    %rax,%r9
L20:
  mov    %r9,D9(%rip)
L31:
  mov    %r9,%rax
  ret
```

assistant: ```c
long calculateSum(int a[], int n) {
  static long sum = 0;
  if (n == 0)
    return sum;
  sum = sum + a[n - 1];
  return calculateSum(a, --n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__UQASX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x10,%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <__IUSAT@plt>
  and    $0xffff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x10,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <__IUSAT@plt>
  and    $0xffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  or     -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __UQASX(uint32_t x, uint32_t y) {
  int32_t r, s;
  r = __IUSAT((((x << 16) >> 16) - ((y) >> 16)), 16) & 0x0000FFFF;
  s = __IUSAT((((x) >> 16) + ((y << 16) >> 16)), 16) & 0x0000FFFF;
  return ((s << 16) | (r));
}
```
user: Translate the below assembly code into C programming language:

```asm
<__UQASX>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebx
  movswl %di,%edi
  mov    %esi,%eax
  sar    $0x10,%eax
  sub    %eax,%edi
  mov    $0x10,%esi
  call   <__IUSAT@plt>
  mov    %eax,%ebp
  movswl %bx,%edi
  sar    $0x10,%r12d
  add    %r12d,%edi
  mov    $0x10,%esi
  call   <__IUSAT@plt>
  movzwl %bp,%ebp
  shl    $0x10,%eax
  or     %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __UQASX(uint32_t x, uint32_t y) {
  int32_t r, s;
  r = __IUSAT((((x << 16) >> 16) - ((y) >> 16)), 16) & 0x0000FFFF;
  s = __IUSAT((((x) >> 16) + ((y << 16) >> 16)), 16) & 0x0000FFFF;
  return ((s << 16) | (r));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__UQASX>:
  endbr64
  push   %r12
  mov    %esi,%eax
  mov    %edi,%r12d
  movswl %di,%edi
  push   %rbp
  sar    $0x10,%eax
  sar    $0x10,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    %eax,%edi
  mov    $0x10,%esi
  movswl %bx,%ebx
  call   <__IUSAT@plt>
  lea    (%rbx,%r12,1),%edi
  mov    $0x10,%esi
  mov    %eax,%ebp
  call   <__IUSAT@plt>
  movzwl %bp,%ebp
  pop    %rbx
  shl    $0x10,%eax
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __UQASX(uint32_t x, uint32_t y) {
  int32_t r, s;
  r = __IUSAT((((x << 16) >> 16) - ((y) >> 16)), 16) & 0x0000FFFF;
  s = __IUSAT((((x) >> 16) + ((y << 16) >> 16)), 16) & 0x0000FFFF;
  return ((s << 16) | (r));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__UQASX>:
  endbr64
  push   %r12
  mov    %esi,%eax
  mov    %edi,%r12d
  movswl %di,%edi
  push   %rbp
  sar    $0x10,%eax
  sar    $0x10,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    %eax,%edi
  mov    $0x10,%esi
  movswl %bx,%ebx
  call   <__IUSAT@plt>
  lea    (%rbx,%r12,1),%edi
  mov    $0x10,%esi
  mov    %eax,%ebp
  call   <__IUSAT@plt>
  movzwl %bp,%ebp
  pop    %rbx
  shl    $0x10,%eax
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __UQASX(uint32_t x, uint32_t y) {
  int32_t r, s;
  r = __IUSAT((((x << 16) >> 16) - ((y) >> 16)), 16) & 0x0000FFFF;
  s = __IUSAT((((x) >> 16) + ((y << 16) >> 16)), 16) & 0x0000FFFF;
  return ((s << 16) | (r));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<areTreesEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <qsTreeCompare@plt>
  test   %rax,%rax
  je     L19
  mov    $0x0,%eax
  jmp    L25
L19:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    $0x1,%eax
L25:
  leave
  ret
```

assistant: ```c
int areTreesEqual(struct QSTree **arr, int tree_count) {
  int i;
  for (i = 1; i < tree_count; ++i) {
    if (qsTreeCompare(arr[i], arr[0]) != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<areTreesEqual>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    0x8(%rdi),%rbx
  lea    -0x2(%rsi),%eax
  lea    0x10(%rdi,%rax,8),%r12
L32:
  mov    0x0(%rbp),%rsi
  mov    (%rbx),%rdi
  call   <qsTreeCompare@plt>
  test   %rax,%rax
  jne    L25
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L32
  mov    $0x1,%eax
  jmp    L1
L15:
  mov    $0x1,%eax
  ret
L25:
  mov    $0x0,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int areTreesEqual(struct QSTree **arr, int tree_count) {
  int i;
  for (i = 1; i < tree_count; ++i) {
    if (qsTreeCompare(arr[i], arr[0]) != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<areTreesEqual>:
  endbr64
  cmp    $0x1,%esi
  jle    L5
  lea    -0x2(%rsi),%eax
  push   %r12
  lea    0x10(%rdi,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x8(%rdi),%rbx
  jmp    L3
  xchg   %ax,%ax
L38:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L9
L3:
  mov    0x0(%rbp),%rsi
  mov    (%rbx),%rdi
  call   <qsTreeCompare@plt>
  test   %rax,%rax
  je     L38
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int areTreesEqual(struct QSTree **arr, int tree_count) {
  int i;
  for (i = 1; i < tree_count; ++i) {
    if (qsTreeCompare(arr[i], arr[0]) != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<areTreesEqual>:
  endbr64
  cmp    $0x1,%esi
  jle    L14
  lea    -0x2(%rsi),%eax
  push   %r12
  lea    0x10(%rdi,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x8(%rdi),%rbx
  jmp    L17
  xchg   %ax,%ax
L24:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L32
L17:
  mov    0x0(%rbp),%rsi
  mov    (%rbx),%rdi
  call   <qsTreeCompare@plt>
  test   %rax,%rax
  je     L24
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int areTreesEqual(struct QSTree **arr, int tree_count) {
  int i;
  for (i = 1; i < tree_count; ++i) {
    if (qsTreeCompare(arr[i], arr[0]) != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str_replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L23
  cmpq   $0x0,-0x30(%rbp)
  je     L23
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
L23:
  mov    $0xffffffff,%eax
  jmp    L61
L38:
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L20
L64:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x1c(%rbp),%edx
  add    %edx,%eax
  cmp    %eax,-0x34(%rbp)
  jle    L56
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x1c(%rbp),%edx
  add    %edx,%eax
  cmp    %eax,-0x34(%rbp)
  jle    L2
  mov    -0x1c(%rbp),%edx
  mov    -0x48(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L20:
  mov    -0x40(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L64
  jmp    L40
L56:
  nop
  jmp    L40
L2:
  nop
L40:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L101
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
L101:
  mov    $0x0,%eax
L61:
  leave
  ret
```

assistant: ```c
int str_replace(char *dest, const char *src, int dest_size, const char *search, const char *replace) {
  char *pdest, *psrc, *p;
  int len;
  if (!dest || !src || !*src) {
    return -1;
  }
  memset(dest, 0, dest_size);
  pdest = dest;
  psrc = (char *)src;
  while ((p = strstr(psrc, search)) != NULL) {
    len = p - psrc;
    if ((strlen(dest) + len) >= dest_size) {
      break;
    }
    strncpy(pdest, psrc, len);
    pdest += len;
    len = strlen(replace);
    if ((strlen(dest) + len) >= dest_size) {
      break;
    }
    strncpy(pdest, replace, len);
    pdest += len;
    psrc = p + strlen(search);
  }
  if (strlen(psrc) > 0) {
    len = dest_size - strlen(dest) - 1;
    strncpy(pdest, psrc, len);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %r8,0x10(%rsp)
  test   %rdi,%rdi
  je     L24
  mov    %rdi,%r14
  mov    %rsi,%rbx
  mov    %edx,%r15d
  test   %rsi,%rsi
  je     L24
  cmpb   $0x0,(%rsi)
  je     L26
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %r14,%r13
L69:
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L105
  mov    %r12,%rbp
  sub    %rbx,%rbp
  mov    %ebp,0x1c(%rsp)
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %ebp,%eax
  cmp    %r15d,%eax
  jge    L105
  mov    0x1c(%rsp),%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movslq %ebp,%rbp
  add    %rbp,%r13
  mov    0x10(%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %ebp,%eax
  cmp    %r15d,%eax
  jge    L105
  mov    %ebp,%edx
  mov    0x10(%rsp),%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movslq %ebp,%rbp
  add    %rbp,%r13
  mov    0x8(%rsp),%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %r12,%rbx
  jmp    L69
L105:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jg     L58
L83:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  mov    %r14,%rdi
  call   <strlen@plt>
  sub    %eax,%r15d
  lea    -0x1(%r15),%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  mov    $0x0,%eax
  jmp    L83
L24:
  mov    $0xffffffff,%eax
  jmp    L83
L26:
  mov    $0xffffffff,%eax
  jmp    L83
```

assistant: ```c
int str_replace(char *dest, const char *src, int dest_size, const char *search, const char *replace) {
  char *pdest, *psrc, *p;
  int len;
  if (!dest || !src || !*src) {
    return -1;
  }
  memset(dest, 0, dest_size);
  pdest = dest;
  psrc = (char *)src;
  while ((p = strstr(psrc, search)) != NULL) {
    len = p - psrc;
    if ((strlen(dest) + len) >= dest_size) {
      break;
    }
    strncpy(pdest, psrc, len);
    pdest += len;
    len = strlen(replace);
    if ((strlen(dest) + len) >= dest_size) {
      break;
    }
    strncpy(pdest, replace, len);
    pdest += len;
    psrc = p + strlen(search);
  }
  if (strlen(psrc) > 0) {
    len = dest_size - strlen(dest) - 1;
    strncpy(pdest, psrc, len);
  }
  return 0;
}
```