ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<range_constraint>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %ecx,%ecx
  jle    L17
  mov    %rsi,%r11
  mov    %edx,%r10d
  lea    0x8(%rdi),%r9
  lea    -0x1(%rcx),%eax
  lea    0x10(%rdi,%rax,8),%rbp
  lea    -0x1(%r8),%eax
  mov    $0x0,%ebx
  lea    0x8(,%rax,4),%r12
  jmp    L45
L88:
  cmp    $0xfa0a1f00,%r10d
  setg   %al
  movzbl %al,%eax
  add    %eax,%ebx
  jmp    L31
L17:
  mov    $0x0,%ebx
L59:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  add    $0x1,%ebx
  movslq %ebx,%rax
  lea    (%r11,%rax,8),%rdi
  mov    $0x4,%eax
  mov    $0x1,%edx
L49:
  mov    (%r9),%rcx
  mov    (%rcx,%rax,1),%esi
  mov    (%rdi),%rcx
  mov    %esi,(%rcx,%rax,1)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%r8d
  jge    L49
L31:
  add    $0x8,%r9
  cmp    %rbp,%r9
  je     L59
L45:
  test   %r8d,%r8d
  jle    L88
  mov    (%r9),%rdi
  lea    0x4(%rdi),%rdx
  add    %r12,%rdi
  mov    $0x5f5e100,%esi
  mov    $0x0,%ecx
L44:
  mov    (%rdx),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L44
  sub    %esi,%ecx
  cmp    %r10d,%ecx
  jge    L31
  jmp    L24
```

assistant: ```c
int range_constraint(int **m_old, int **m_new, int range_threshold, int n_entries, int n_motifs) {
  int i, j;
  int running_n = 0;
  int max;
  int min;
  int range;
  for (i = 1; i <= n_entries; i++) {
    max = 0;
    min = 100000000;
    for (j = 1; j <= n_motifs; j++) {
      if (m_old[i][j] < min)
        min = m_old[i][j];
      if (m_old[i][j] > max)
        max = m_old[i][j];
    }
    range = max - min;
    if (range < range_threshold) {
      running_n++;
      for (j = 1; j <= n_motifs; j++)
        m_new[running_n][j] = m_old[i][j];
    }
  }
  return running_n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<range_constraint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %ecx,%ecx
  jle    L56
  lea    -0x1(%r8),%r10d
  lea    -0x1(%rcx),%eax
  mov    %rsi,%rbx
  mov    %edx,%r11d
  lea    0x8(,%r10,4),%r13
  lea    0x8(%rdi),%r9
  xor    %r12d,%r12d
  add    $0x2,%r10
  lea    0x10(%rdi,%rax,8),%rbp
  nopl   0x0(%rax)
L37:
  test   %r8d,%r8d
  jle    L60
  mov    (%r9),%rdi
  mov    $0x5f5e100,%esi
  xor    %ecx,%ecx
  lea    0x4(%rdi),%rdx
  lea    (%rdi,%r13,1),%r14
  nopl   0x0(%rax,%rax,1)
L32:
  mov    (%rdx),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  add    $0x4,%rdx
  cmp    %r14,%rdx
  jne    L32
  sub    %esi,%ecx
  cmp    %r11d,%ecx
  jl     L55
L38:
  add    $0x8,%r9
  cmp    %rbp,%r9
  jne    L37
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L55:
  add    $0x1,%r12d
  movslq %r12d,%rax
  mov    (%rbx,%rax,8),%rcx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r10
  jne    L26
  jmp    L38
  nopl   0x0(%rax)
L60:
  xor    %eax,%eax
  cmp    $0xfa0a1f00,%r11d
  setg   %al
  add    %eax,%r12d
  jmp    L38
L56:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int range_constraint(int **m_old, int **m_new, int range_threshold, int n_entries, int n_motifs) {
  int i, j;
  int running_n = 0;
  int max;
  int min;
  int range;
  for (i = 1; i <= n_entries; i++) {
    max = 0;
    min = 100000000;
    for (j = 1; j <= n_motifs; j++) {
      if (m_old[i][j] < min)
        min = m_old[i][j];
      if (m_old[i][j] > max)
        max = m_old[i][j];
    }
    range = max - min;
    if (range < range_threshold) {
      running_n++;
      for (j = 1; j <= n_motifs; j++)
        m_new[running_n][j] = m_old[i][j];
    }
  }
  return running_n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<crypt_des_ecb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%rdi
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <str_to_key@plt>
  mov    $0x0,%eax
  mov    $0x7,%edi
L68:
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  lea    (%rcx,%rax,1),%esi
  and    $0x7,%esi
  sub    %ecx,%esi
  mov    %edi,%ecx
  sub    %esi,%ecx
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%esi
  sar    %cl,%esi
  and    $0x1,%esi
  mov    %sil,0x50(%rsp,%rax,1)
  movzbl 0x8(%rsp,%rdx,1),%edx
  sar    %cl,%edx
  and    $0x1,%edx
  mov    %dl,0x90(%rsp,%rax,1)
  movb   $0x0,0x10(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L68
  lea    0x90(%rsp),%rdx
  lea    0x50(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %r12d,%ecx
  call   <dohash@plt>
  mov    %rbx,%rax
  lea    0x8(%rbx),%rdx
L8:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
  mov    $0x0,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x7,%r9d
  mov    $0x1,%r8d
  jmp    L65
L54:
  add    $0x1,%rax
  cmp    $0x40,%rax
  je     L44
L65:
  cmpb   $0x0,(%rax,%rdi,1)
  je     L54
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x3,%edx
  movslq %edx,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  lea    (%rcx,%rax,1),%esi
  and    $0x7,%esi
  sub    %ecx,%esi
  mov    %r9d,%ecx
  sub    %esi,%ecx
  mov    %r8d,%esi
  shl    %cl,%esi
  or     %sil,(%rbx,%rdx,1)
  jmp    L54
L44:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void crypt_des_ecb(unsigned char *out, const unsigned char *in, const unsigned char *key, unsigned forw) {
  int i;
  unsigned char outb[64];
  unsigned char inb[64];
  unsigned char keyb[64];
  unsigned char key2[8];
  str_to_key(key, key2);
  for (i = 0; i < 64; i++) {
    inb[i] = (unsigned char)((in[i / 8] & (1 << (7 - (i % 8)))) ? 1 : 0);
    keyb[i] = (unsigned char)((key2[i / 8] & (1 << (7 - (i % 8)))) ? 1 : 0);
    outb[i] = 0;
  }
  dohash(outb, inb, keyb, forw);
  for (i = 0; i < 8; i++) {
    out[i] = 0;
  }
  for (i = 0; i < 64; i++) {
    if (outb[i])
      out[i / 8] |= (1 << (7 - (i % 8)));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crypt_des_ecb>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <str_to_key@plt>
  xor    %eax,%eax
  lea    0x50(%rsp),%rsi
  lea    0x90(%rsp),%r8
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %eax,%edi
  mov    %eax,%ecx
  sar    $0x3,%edi
  not    %ecx
  movslq %edi,%rdi
  and    $0x7,%ecx
  movzbl 0x0(%rbp,%rdi,1),%edx
  sar    %cl,%edx
  and    $0x1,%edx
  mov    %dl,(%rsi,%rax,1)
  movzbl 0x8(%rsp,%rdi,1),%edx
  sar    %cl,%edx
  and    $0x1,%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L11
  lea    0x10(%rsp),%rbp
  pxor   %xmm0,%xmm0
  mov    %r12d,%ecx
  mov    %r8,%rdx
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <dohash@plt>
  movq   $0x0,(%rbx)
  xor    %eax,%eax
  mov    $0x1,%esi
  nopl   (%rax)
L15:
  cmpb   $0x0,0x0(%rbp,%rax,1)
  je     L10
  mov    %eax,%edx
  mov    %eax,%ecx
  mov    %esi,%edi
  sar    $0x3,%edx
  not    %ecx
  movslq %edx,%rdx
  and    $0x7,%ecx
  shl    %cl,%edi
  or     %dil,(%rbx,%rdx,1)
L10:
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L15
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void crypt_des_ecb(unsigned char *out, const unsigned char *in, const unsigned char *key, unsigned forw) {
  int i;
  unsigned char outb[64];
  unsigned char inb[64];
  unsigned char keyb[64];
  unsigned char key2[8];
  str_to_key(key, key2);
  for (i = 0; i < 64; i++) {
    inb[i] = (unsigned char)((in[i / 8] & (1 << (7 - (i % 8)))) ? 1 : 0);
    keyb[i] = (unsigned char)((key2[i / 8] & (1 << (7 - (i % 8)))) ? 1 : 0);
    outb[i] = 0;
  }
  dohash(outb, inb, keyb, forw);
  for (i = 0; i < 8; i++) {
    out[i] = 0;
  }
  for (i = 0; i < 64; i++) {
    if (outb[i])
      out[i / 8] |= (1 << (7 - (i % 8)));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<crypt_des_ecb>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <str_to_key@plt>
  xor    %eax,%eax
  lea    0x50(%rsp),%rsi
  nop
L39:
  mov    %eax,%edx
  mov    %eax,%ecx
  sar    $0x3,%edx
  not    %ecx
  movslq %edx,%rdx
  and    $0x7,%ecx
  movzbl 0x0(%rbp,%rdx,1),%edx
  sar    %cl,%edx
  and    $0x1,%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L39
  xor    %eax,%eax
  lea    0x90(%rsp),%r8
L38:
  mov    %eax,%edx
  mov    %eax,%ecx
  sar    $0x3,%edx
  not    %ecx
  movslq %edx,%rdx
  and    $0x7,%ecx
  movzbl 0x8(%rsp,%rdx,1),%edx
  sar    %cl,%edx
  and    $0x1,%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L38
  lea    0x10(%rsp),%rbp
  pxor   %xmm0,%xmm0
  mov    %r12d,%ecx
  mov    %r8,%rdx
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <dohash@plt>
  movq   $0x0,(%rbx)
  xor    %eax,%eax
  mov    $0x1,%esi
L1:
  cmpb   $0x0,0x0(%rbp,%rax,1)
  je     L30
  mov    %eax,%edx
  mov    %eax,%ecx
  mov    %esi,%edi
  sar    $0x3,%edx
  not    %ecx
  movslq %edx,%rdx
  and    $0x7,%ecx
  shl    %cl,%edi
  or     %dil,(%rbx,%rdx,1)
L30:
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L1
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void crypt_des_ecb(unsigned char *out, const unsigned char *in, const unsigned char *key, unsigned forw) {
  int i;
  unsigned char outb[64];
  unsigned char inb[64];
  unsigned char keyb[64];
  unsigned char key2[8];
  str_to_key(key, key2);
  for (i = 0; i < 64; i++) {
    inb[i] = (unsigned char)((in[i / 8] & (1 << (7 - (i % 8)))) ? 1 : 0);
    keyb[i] = (unsigned char)((key2[i / 8] & (1 << (7 - (i % 8)))) ? 1 : 0);
    outb[i] = 0;
  }
  dohash(outb, inb, keyb, forw);
  for (i = 0; i < 8; i++) {
    out[i] = 0;
  }
  for (i = 0; i < 64; i++) {
    if (outb[i])
      out[i / 8] |= (1 << (7 - (i % 8)));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FlashReset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xd0006c,%esi
  mov    $0xc000,%edi
  call   <RamWrite32A@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xd000,%edi
  call   <RamRead32A@plt>
  mov    -0x10(%rbp),%rax
  and    $0xffffffffffffffef,%rax
  mov    %rax,%rsi
  mov    $0xd000,%edi
  call   <RamWrite32A@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void FlashReset(void) {
  unsigned long UlReadVal;
  RamWrite32A(0xC000, 0xD0006C);
  RamRead32A(0xD000, &UlReadVal);
  RamWrite32A(0xD000, (UlReadVal & (~0x00000010)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<FlashReset>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0xd0006c,%esi
  mov    $0xc000,%edi
  call   <RamWrite32A@plt>
  mov    %rsp,%rsi
  mov    $0xd000,%edi
  call   <RamRead32A@plt>
  mov    (%rsp),%rsi
  and    $0xffffffffffffffef,%rsi
  mov    $0xd000,%edi
  call   <RamWrite32A@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void FlashReset(void) {
  unsigned long UlReadVal;
  RamWrite32A(0xC000, 0xD0006C);
  RamRead32A(0xD000, &UlReadVal);
  RamWrite32A(0xD000, (UlReadVal & (~0x00000010)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FlashReset>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xd0006c,%esi
  mov    $0xc000,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <RamWrite32A@plt>
  mov    %rsp,%rsi
  mov    $0xd000,%edi
  call   <RamRead32A@plt>
  mov    (%rsp),%rsi
  mov    $0xd000,%edi
  and    $0xffffffffffffffef,%rsi
  call   <RamWrite32A@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void FlashReset(void) {
  unsigned long UlReadVal;
  RamWrite32A(0xC000, 0xD0006C);
  RamRead32A(0xD000, &UlReadVal);
  RamWrite32A(0xD000, (UlReadVal & (~0x00000010)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FlashReset>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xd0006c,%esi
  mov    $0xc000,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <RamWrite32A@plt>
  mov    %rsp,%rsi
  mov    $0xd000,%edi
  call   <RamRead32A@plt>
  mov    (%rsp),%rsi
  mov    $0xd000,%edi
  and    $0xffffffffffffffef,%rsi
  call   <RamWrite32A@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void FlashReset(void) {
  unsigned long UlReadVal;
  RamWrite32A(0xC000, 0xD0006C);
  RamRead32A(0xD000, &UlReadVal);
  RamWrite32A(0xD000, (UlReadVal & (~0x00000010)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Free2DArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void Free2DArray(void **array, unsigned int nrow) {
  int row;
  for (row = 0; row < nrow; row++) {
    free(array[row]);
  }
  free(array);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Free2DArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  je     L1
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L6:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L6
L1:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Free2DArray(void **array, unsigned int nrow) {
  int row;
  for (row = 0; row < nrow; row++) {
    free(array[row]);
  }
  free(array);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Free2DArray>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L13
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L19
L13:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void Free2DArray(void **array, unsigned int nrow) {
  int row;
  for (row = 0; row < nrow; row++) {
    free(array[row]);
  }
  free(array);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Free2DArray>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L6
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L16
L6:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void Free2DArray(void **array, unsigned int nrow) {
  int row;
  for (row = 0; row < nrow; row++) {
    free(array[row]);
  }
  free(array);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D65
type: string
name: retrieve_data
arguments: label: D67
type: string
name: retrieve_data
arguments: label: D28
type: string
name: retrieve_data
arguments: label: D50
type: string
name: retrieve_data
arguments: label: D54
type: string

tool: D4: Hello

tool: D65: enter first number: 

tool: D67: %d

tool: D28: enter second number: 

tool: D50: Sum is : %d

tool: D54: Product is : %d

assistant: ```c
void main() {
  int a, b;
  printf("Hello");
  printf("enter first number: ");
  scanf("%d", &a);
  printf("enter second number: ");
  scanf("%d", &b);
  printf("Sum is : %d", a + b);
  printf("Product is : %d", a * b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D22(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  add    (%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  imul   0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D39
data_type: string
name: read_data
arguments: label: D13
data_type: string
name: read_data
arguments: label: D22
data_type: string
name: read_data
arguments: label: D7
data_type: string
name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D27
data_type: string

tool: D39: Hello

tool: D13: enter first number: 

tool: D22: %d

tool: D7: enter second number: 

tool: D19: Sum is : %d

tool: D27: Product is : %d

assistant: ```c
void main() {
  int a, b;
  printf("Hello");
  printf("enter first number: ");
  scanf("%d", &a);
  printf("enter second number: ");
  scanf("%d", &b);
  printf("Sum is : %d", a + b);
  printf("Product is : %d", a * b);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  lea    D42(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  add    (%rsp),%esi
  call   <printf@plt>
  mov    (%rsp),%esi
  xor    %eax,%eax
  imul   0x4(%rsp),%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D23
type_infered: string
name: parse_data
arguments: data_tag: D42
type_infered: string
name: parse_data
arguments: data_tag: D12
type_infered: string
name: parse_data
arguments: data_tag: D29
type_infered: string
name: parse_data
arguments: data_tag: D55
type_infered: string
name: parse_data
arguments: data_tag: D31
type_infered: string

tool: D23: Hello

tool: D42: %d

tool: D12: enter first number: 

tool: D29: enter second number: 

tool: D55: Sum is : %d

tool: D31: Product is : %d

assistant: ```c
void main() {
  int a, b;
  printf("Hello");
  printf("enter first number: ");
  scanf("%d", &a);
  printf("enter second number: ");
  scanf("%d", &b);
  printf("Sum is : %d", a + b);
  printf("Product is : %d", a * b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D55(%rip),%rdi
  lea    D51(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  add    (%rsp),%esi
  call   <printf@plt>
  mov    (%rsp),%esi
  xor    %eax,%eax
  imul   0x4(%rsp),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D55
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D51
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D36
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D42
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D55: Hello

tool: D51: %d

tool: D15: enter first number: 

tool: D36: enter second number: 

tool: D42: Sum is : %d

tool: D6: Product is : %d

assistant: ```c
void main() {
  int a, b;
  printf("Hello");
  printf("enter first number: ");
  scanf("%d", &a);
  printf("enter second number: ");
  scanf("%d", &b);
  printf("Sum is : %d", a + b);
  printf("Product is : %d", a * b);
}
```