ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x136ff696,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x10,%eax
  test   %rax,%rax
  je     L52
  mov    -0x10(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L1
  mov    -0x10(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L24
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L60
L24:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L60
L1:
  mov    -0x10(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L40
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L60
L40:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L60
L52:
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0x10(%rbp),%rdx
  add    $0x4,%rdx
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
  lea    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  lea    -0x10(%rbp),%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
L60:
  mov    -0x10(%rbp),%rax
  lea    -0x52654fc3(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else if ((state[0UL] >> 2UL) & 1UL) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      copy11 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy11;
    }
    output[0UL] = (state[0UL] - 306719454UL) - 1075651813UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  test   $0x10,%al
  je     L1
  lea    (%rax,%rax,1),%rdx
L18:
  sub    $0x52654fc3,%rdx
  mov    %rdx,(%rcx)
  ret
L1:
  mov    %rax,%rsi
  shr    $0x10,%rsi
  movzwl %si,%esi
  shl    $0x20,%rsi
  movabs $0xffff0000ffffffff,%rdx
  and    %rax,%rdx
  or     %rsi,%rdx
  mov    %rax,%rsi
  shr    $0x20,%rsi
  mov    %si,%dx
  movzwl %ax,%eax
  shl    $0x10,%rax
  movabs $0xffffffff0000ffff,%rsi
  and    %rsi,%rdx
  or     %rax,%rdx
  jmp    L18
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else if ((state[0UL] >> 2UL) & 1UL) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      copy11 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy11;
    }
    output[0UL] = (state[0UL] - 306719454UL) - 1075651813UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  mov    %rax,%rdx
  test   $0x10,%al
  je     L4
  add    %rax,%rax
  sub    $0x52654fc3,%rax
  mov    %rax,(%rsi)
  ret
  nopl   0x0(%rax)
L4:
  mov    %rax,%rcx
  mov    %eax,%eax
  shr    $0x20,%rcx
  shl    $0x10,%rax
  mov    %cx,%dx
  movabs $0xffff00000000ffff,%rcx
  and    %rcx,%rdx
  or     %rdx,%rax
  sub    $0x52654fc3,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else if ((state[0UL] >> 2UL) & 1UL) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      copy11 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy11;
    }
    output[0UL] = (state[0UL] - 306719454UL) - 1075651813UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rsi,%rcx
  add    $0x136ff696,%rdx
  test   $0x10,%dl
  je     L3
  lea    (%rdx,%rdx,1),%rax
  sub    $0x52654fc3,%rax
  mov    %rax,(%rcx)
  ret
  nopl   0x0(%rax)
L3:
  movabs $0xffff0000ffffffff,%rax
  mov    %rdx,%rsi
  shr    $0x10,%rsi
  and    %rdx,%rax
  movzwl %si,%esi
  shl    $0x20,%rsi
  or     %rsi,%rax
  mov    %rdx,%rsi
  shl    $0x10,%edx
  shr    $0x20,%rsi
  movzwl %si,%esi
  or     %esi,%edx
  movabs $0xffffffff00000000,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
  sub    $0x52654fc3,%rax
  mov    %rax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else if ((state[0UL] >> 2UL) & 1UL) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      copy11 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy11;
    }
    output[0UL] = (state[0UL] - 306719454UL) - 1075651813UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void f(char *src) {
  char dst[2];
  strcpy(dst, src);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f(char *src) {
  char dst[2];
  strcpy(dst, src);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f(char *src) {
  char dst[2];
  strcpy(dst, src);
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f(char *src) {
  char dst[2];
  strcpy(dst, src);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L27
L14:
  cmpl   $0x1,-0x1c(%rbp)
  jne    L16
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L27
L16:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lcp>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lcp>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L54
  cmpl   $0x0,-0x4(%rbp)
  jne    L70
L54:
  mov    $0x0,%eax
  jmp    L27
L70:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L103
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L103:
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L94:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L51
  mov    -0x8(%rbp),%eax
  jmp    L27
L51:
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L94
L27:
  leave
  ret
```

assistant: ```c
int lcp(char *strs[], int n) {
  if (n == 0)
    return 0;
  if (n == 1)
    return strlen(strs[0]);
  int left = lcp(strs, n / 2);
  int right = lcp(strs + n / 2, n - n / 2);
  if (!left || !right)
    return 0;
  if (left > right)
    left = right;
  for (int i = 0; i < left; ++i) {
    if (strs[0][i] != strs[n / 2][i])
      return i;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lcp>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L28
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  cmp    $0x1,%esi
  je     L76
  mov    %esi,%r14d
  shr    $0x1f,%r14d
  add    %esi,%r14d
  sar    %r14d
  mov    %r14d,%esi
  call   <lcp>
  mov    %eax,%ebp
  movslq %r14d,%rax
  lea    (%r12,%rax,8),%r13
  mov    %ebx,%esi
  sub    %r14d,%esi
  mov    %r13,%rdi
  call   <lcp>
  test   %ebp,%ebp
  je     L27
  test   %eax,%eax
  je     L27
  cmp    %eax,%ebp
  cmovle %ebp,%eax
  test   %eax,%eax
  jle    L41
  mov    (%r12),%rdi
  mov    0x0(%r13),%rsi
  mov    %eax,%ecx
  mov    $0x0,%edx
L85:
  mov    %edx,%eax
  movzbl (%rsi,%rdx,1),%ebx
  cmp    %bl,(%rdi,%rdx,1)
  jne    L41
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L85
  jmp    L41
L76:
  mov    (%rdi),%rdi
  call   <strlen@plt>
  jmp    L41
L27:
  mov    $0x0,%eax
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  ret
```

assistant: ```c
int lcp(char *strs[], int n) {
  if (n == 0)
    return 0;
  if (n == 1)
    return strlen(strs[0]);
  int left = lcp(strs, n / 2);
  int right = lcp(strs + n / 2, n - n / 2);
  if (!left || !right)
    return 0;
  if (left > right)
    left = right;
  for (int i = 0; i < left; ++i) {
    if (strs[0][i] != strs[n / 2][i])
      return i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcp>:
  endbr64
  test   %esi,%esi
  je     L5
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x1,%esi
  je     L13
  mov    %esi,%r13d
  shr    $0x1f,%r13d
  add    %esi,%r13d
  sar    %r13d
  mov    %r13d,%esi
  sub    %r13d,%ebx
  call   <lcp>
  mov    %ebx,%esi
  mov    %eax,%ebp
  movslq %r13d,%rax
  lea    (%r12,%rax,8),%r14
  mov    %r14,%rdi
  call   <lcp>
  test   %ebp,%ebp
  je     L1
  test   %eax,%eax
  je     L1
  cmp    %eax,%ebp
  cmovle %ebp,%eax
  movslq %eax,%rdx
  test   %edx,%edx
  jle    L10
  mov    (%r12),%rsi
  mov    (%r14),%rcx
  xor    %eax,%eax
  jmp    L67
  nopl   0x0(%rax)
L42:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L10
L67:
  movzbl (%rcx,%rax,1),%edi
  mov    %eax,%r8d
  cmp    %dil,(%rsi,%rax,1)
  je     L42
L10:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rdi),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <strlen@plt>
```

assistant: ```c
int lcp(char *strs[], int n) {
  if (n == 0)
    return 0;
  if (n == 1)
    return strlen(strs[0]);
  int left = lcp(strs, n / 2);
  int right = lcp(strs + n / 2, n - n / 2);
  if (!left || !right)
    return 0;
  if (left > right)
    left = right;
  for (int i = 0; i < left; ++i) {
    if (strs[0][i] != strs[n / 2][i])
      return i;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lcp>:
  endbr64
  test   %esi,%esi
  je     L7
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x1,%esi
  je     L25
  mov    %esi,%r13d
  shr    $0x1f,%r13d
  add    %esi,%r13d
  sar    %r13d
  mov    %r13d,%esi
  sub    %r13d,%ebx
  call   <lcp>
  mov    %ebx,%esi
  mov    %eax,%ebp
  movslq %r13d,%rax
  lea    (%r12,%rax,8),%r14
  mov    %r14,%rdi
  call   <lcp>
  test   %ebp,%ebp
  je     L70
  test   %eax,%eax
  je     L70
  cmp    %eax,%ebp
  cmovle %ebp,%eax
  movslq %eax,%rdx
  test   %edx,%edx
  jle    L5
  mov    (%r12),%rsi
  mov    (%r14),%rcx
  xor    %eax,%eax
  jmp    L27
  nopl   0x0(%rax)
L37:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L5
L27:
  movzbl (%rcx,%rax,1),%edi
  mov    %eax,%r8d
  cmp    %dil,(%rsi,%rax,1)
  je     L37
L5:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L70:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    (%rdi),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <strlen@plt>
```

assistant: ```c
int lcp(char *strs[], int n) {
  if (n == 0)
    return 0;
  if (n == 1)
    return strlen(strs[0]);
  int left = lcp(strs, n / 2);
  int right = lcp(strs + n / 2, n - n / 2);
  if (!left || !right)
    return 0;
  if (left > right)
    left = right;
  for (int i = 0; i < left; ++i) {
    if (strs[0][i] != strs[n / 2][i])
      return i;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mDelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L32
L17:
  movq   $0x0,-0x8(%rbp)
  jmp    L34
L16:
  addq   $0x1,-0x8(%rbp)
L34:
  cmpq   $0x2edf,-0x8(%rbp)
  jle    L16
  subq   $0x1,-0x18(%rbp)
L32:
  cmpq   $0x0,-0x18(%rbp)
  jg     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mDelay(uint32_t i) {
  uint32_t j = 0;
  for (; i > 0; i--) {
    for (j = 0; j < 12000; j++)
      ;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mDelay>:
  endbr64
  mov    %rdi,%rdx
  test   %rdi,%rdi
  jle    L4
L2:
  mov    $0x2ee0,%eax
L8:
  sub    $0x1,%rax
  jne    L8
  sub    $0x1,%rdx
  jne    L2
  ret
L4:
  ret
```

assistant: ```c
void mDelay(uint32_t i) {
  uint32_t j = 0;
  for (; i > 0; i--) {
    for (j = 0; j < 12000; j++)
      ;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mDelay>:
  endbr64
  ret
```

assistant: ```c
void mDelay(uint32_t i) {
  uint32_t j = 0;
  for (; i > 0; i--) {
    for (j = 0; j < 12000; j++)
      ;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<mDelay>:
  endbr64
  ret
```

assistant: ```c
void mDelay(uint32_t i) {
  uint32_t j = 0;
  for (; i > 0; i--) {
    for (j = 0; j < 12000; j++)
      ;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fig07_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <getSize@plt>
  mov    %eax,%edx
  mov    $0x50,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: The number of bytes in the array is %u.
The number of bytes returned by getSize is %u.


assistant: ```c
void fig07_16() {
  float array[20];
  printf("The number of bytes in the array is %u."
         "\nThe number of bytes returned by getSize is %u.\n",
         sizeof(array), getSize(array));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fig07_16>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getSize@plt>
  mov    %eax,%edx
  mov    $0x50,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x68,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: The number of bytes in the array is %u.
The number of bytes returned by getSize is %u.


assistant: ```c
void fig07_16() {
  float array[20];
  printf("The number of bytes in the array is %u."
         "\nThe number of bytes returned by getSize is %u.\n",
         sizeof(array), getSize(array));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fig07_16>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getSize@plt>
  mov    $0x50,%esi
  lea    D2(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x68,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: The number of bytes in the array is %u.
The number of bytes returned by getSize is %u.


assistant: ```c
void fig07_16() {
  float array[20];
  printf("The number of bytes in the array is %u."
         "\nThe number of bytes returned by getSize is %u.\n",
         sizeof(array), getSize(array));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fig07_16>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getSize@plt>
  mov    $0x50,%esi
  lea    D3(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x68,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: The number of bytes in the array is %u.
The number of bytes returned by getSize is %u.


assistant: ```c
void fig07_16() {
  float array[20];
  printf("The number of bytes in the array is %u."
         "\nThe number of bytes returned by getSize is %u.\n",
         sizeof(array), getSize(array));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<millis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%rax
  imul   $0x3e8,%rax,%rsi
  mov    -0x18(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  add    %rsi,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
long millis(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec) * 1000L + (tv.tv_usec) / 1000L;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<millis>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%rsi
  mov    0x8(%rsp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0x7,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long millis(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec) * 1000L + (tv.tv_usec) / 1000L;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<millis>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   $0x3e8,(%rsp),%rsi
  mov    %rcx,%rax
  sar    $0x3f,%rcx
  imul   %rdx
  sar    $0x7,%rdx
  sub    %rcx,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long millis(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec) * 1000L + (tv.tv_usec) / 1000L;
}
```
user: Translate the below assembly code into C programming language:

```asm
<millis>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   $0x3e8,(%rsp),%rsi
  mov    %rcx,%rax
  sar    $0x3f,%rcx
  imul   %rdx
  sar    $0x7,%rdx
  sub    %rcx,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long millis(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec) * 1000L + (tv.tv_usec) / 1000L;
}
```