ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x40,%esi
  call   <bzero@plt>
  lea    D0(%rip),%rbx
  mov    %rbx,%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdi
  call   <MD5_Init@plt>
  lea    0xc(%rsp),%rbp
L17:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <MD5_Update@plt>
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L17
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <MD5_Final@plt>
  mov    %rbx,%rbp
  lea    0x20(%rsp),%r12
  lea    D19(%rip),%r13
L2:
  movzbl (%rbx),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x10(%rsp),%r13
  mov    $0x40,%esi
  mov    %r13,%rdi
  call   <bzero@plt>
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %r13,%rdx
  mov    %rbx,%rdi
  call   <MD5@plt>
  lea    D19(%rip),%rbx
L28:
  movzbl 0x0(%rbp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D38
datatype: string
name: read_data
arguments: label: D19
datatype: string

tool: D0: abcdefghijklmn

tool: D38: info [%s]


tool: D19: %02x

assistant: ```c
int main() {
  const char *info = "abcdefghijklmn";
  unsigned char szmd5[64] = {0};
  bzero(szmd5, sizeof(szmd5));
  printf("info [%s]\n", info);
  MD5_CTX c;
  MD5_Init(&c);
  int i = 0;
  for (i = 0; info[i] != '\0'; i++) {
    MD5_Update(&c, &info[i], 1);
  }
  MD5_Final(szmd5, &c);
  for (i = 0; i < 16; i++) {
    printf("%02x", szmd5[i]);
  }
  printf("\n");
  bzero(szmd5, sizeof(szmd5));
  MD5((const unsigned char *)info, strlen(info), szmd5);
  for (i = 0; i < 16; i++) {
    printf("%02x", szmd5[i]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  mov    $0x40,%esi
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r14,%rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  movaps %xmm0,0x10(%rsp)
  lea    0xc(%rsp),%rbp
  mov    %r13,%rdi
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <bzero@plt>
  mov    %r14,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <MD5_Init@plt>
  nopl   0x0(%rax)
L27:
  mov    %rbx,%rsi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <MD5_Update@plt>
  cmpb   $0x0,(%rbx)
  jne    L27
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %r13,%rbx
  mov    %r13,%rbp
  call   <MD5_Final@plt>
  lea    0x20(%rsp),%r12
  lea    D1(%rip),%r15
  xchg   %ax,%ax
L10:
  movzbl 0x0(%rbp),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x40,%esi
  mov    %r13,%rdi
  call   <bzero@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <MD5@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  movzbl (%rbx),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_guessed: string
name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D17: abcdefghijklmn

tool: D2: info [%s]


tool: D1: %02x

assistant: ```c
int main() {
  const char *info = "abcdefghijklmn";
  unsigned char szmd5[64] = {0};
  bzero(szmd5, sizeof(szmd5));
  printf("info [%s]\n", info);
  MD5_CTX c;
  MD5_Init(&c);
  int i = 0;
  for (i = 0; info[i] != '\0'; i++) {
    MD5_Update(&c, &info[i], 1);
  }
  MD5_Final(szmd5, &c);
  for (i = 0; i < 16; i++) {
    printf("%02x", szmd5[i]);
  }
  printf("\n");
  bzero(szmd5, sizeof(szmd5));
  MD5((const unsigned char *)info, strlen(info), szmd5);
  for (i = 0; i < 16; i++) {
    printf("%02x", szmd5[i]);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  mov    $0x40,%esi
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r14,%rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  movaps %xmm0,0x10(%rsp)
  lea    0xc(%rsp),%rbp
  mov    %r13,%rdi
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <bzero@plt>
  mov    %r14,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <MD5_Init@plt>
  nopl   0x0(%rax)
L39:
  mov    %rbx,%rsi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <MD5_Update@plt>
  cmpb   $0x0,(%rbx)
  jne    L39
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %r13,%rbx
  mov    %r13,%rbp
  call   <MD5_Final@plt>
  lea    0x20(%rsp),%r12
  lea    D13(%rip),%r15
  xchg   %ax,%ax
L3:
  movzbl 0x0(%rbp),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x40,%esi
  mov    %r13,%rdi
  call   <bzero@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <MD5@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rbx),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D29
type_guessed: string
name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string

tool: D29: abcdefghijklmn

tool: D14: info [%s]


tool: D13: %02x

assistant: ```c
int main() {
  const char *info = "abcdefghijklmn";
  unsigned char szmd5[64] = {0};
  bzero(szmd5, sizeof(szmd5));
  printf("info [%s]\n", info);
  MD5_CTX c;
  MD5_Init(&c);
  int i = 0;
  for (i = 0; info[i] != '\0'; i++) {
    MD5_Update(&c, &info[i], 1);
  }
  MD5_Final(szmd5, &c);
  for (i = 0; i < 16; i++) {
    printf("%02x", szmd5[i]);
  }
  printf("\n");
  bzero(szmd5, sizeof(szmd5));
  MD5((const unsigned char *)info, strlen(info), szmd5);
  for (i = 0; i < 16; i++) {
    printf("%02x", szmd5[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jne    L10
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L15
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jg     L94
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L20
L94:
  mov    -0x20(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L15:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jg     L42
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L20
L42:
  mov    -0x1c(%rbp),%eax
  mov    -0x10(%rbp),%edx
  sub    %edx,%eax
  imul   $0x1f4,%eax,%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L10:
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jge    L44
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L20
L44:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D40
type_infered: string
name: read_data
arguments: data_label: D31
type_infered: string
name: read_data
arguments: data_label: D20
type_infered: string

tool: D40: %d %d %d

tool: D31: %d


tool: D20: 10000

assistant: ```c
int main() {
  int d1;
  int m1;
  int y1;
  scanf("%d %d %d", &d1, &m1, &y1);
  int d2;
  int m2;
  int y2;
  scanf("%d %d %d", &d2, &m2, &y2);
  if (y1 == y2) {
    if (m1 == m2) {
      if (d1 <= d2) {
        printf("0");
      } else {
        printf("%d\n", 15 * (d1 - d2));
      }
    } else {
      if (m1 <= m2) {
        printf("0");
      } else {
        printf("%d\n", 500 * (m1 - m2));
      }
    }
  } else {
    if (y1 < y2) {
      printf("0");
    } else {
      printf("10000");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0x14(%rsp),%eax
  cmp    %eax,%edx
  je     L48
  jge    L72
  mov    $0x30,%edi
  call   <putchar@plt>
L92:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L48:
  mov    0x4(%rsp),%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  je     L70
  jg     L37
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L92
L70:
  mov    (%rsp),%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  jg     L47
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L92
L47:
  sub    %eax,%esi
  imul   $0xf,%esi,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L92
L37:
  sub    %eax,%esi
  imul   $0x1f4,%esi,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L92
L72:
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L92
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type: string
name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D25
type: string

tool: D11: %d %d %d

tool: D4: %d


tool: D25: 10000

assistant: ```c
int main() {
  int d1;
  int m1;
  int y1;
  scanf("%d %d %d", &d1, &m1, &y1);
  int d2;
  int m2;
  int y2;
  scanf("%d %d %d", &d2, &m2, &y2);
  if (y1 == y2) {
    if (m1 == m2) {
      if (d1 <= d2) {
        printf("0");
      } else {
        printf("%d\n", 15 * (d1 - d2));
      }
    } else {
      if (m1 <= m2) {
        printf("0");
      } else {
        printf("%d\n", 500 * (m1 - m2));
      }
    }
  } else {
    if (y1 < y2) {
      printf("0");
    } else {
      printf("10000");
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  je     L37
  jge    L24
L70:
  mov    $0x30,%edi
  call   <putchar@plt>
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L24:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L16
L37:
  mov    0x4(%rsp),%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  je     L82
  jle    L70
  sub    %eax,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  imul   $0x1f4,%esi,%esi
  call   <printf@plt>
  jmp    L16
L82:
  mov    (%rsp),%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  jle    L70
  sub    %eax,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  imul   $0xf,%esi,%esi
  call   <printf@plt>
  jmp    L16
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D22
datatype: string

tool: D2: %d %d %d

tool: D14: 10000

tool: D22: %d


assistant: ```c
int main() {
  int d1;
  int m1;
  int y1;
  scanf("%d %d %d", &d1, &m1, &y1);
  int d2;
  int m2;
  int y2;
  scanf("%d %d %d", &d2, &m2, &y2);
  if (y1 == y2) {
    if (m1 == m2) {
      if (d1 <= d2) {
        printf("0");
      } else {
        printf("%d\n", 15 * (d1 - d2));
      }
    } else {
      if (m1 <= m2) {
        printf("0");
      } else {
        printf("%d\n", 500 * (m1 - m2));
      }
    }
  } else {
    if (y1 < y2) {
      printf("0");
    } else {
      printf("10000");
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  je     L58
  jge    L46
L60:
  mov    $0x30,%edi
  call   <putchar@plt>
L68:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L46:
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L68
L58:
  mov    0x4(%rsp),%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  je     L84
  jle    L60
  sub    %eax,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  imul   $0x1f4,%esi,%esi
  call   <printf@plt>
  jmp    L68
L84:
  mov    (%rsp),%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  jle    L60
  sub    %eax,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  imul   $0xf,%esi,%esi
  call   <printf@plt>
  jmp    L68
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D25
type_infered: string
name: disassemble_data
arguments: tag: D12
type_infered: string

tool: D18: %d %d %d

tool: D25: 10000

tool: D12: %d


assistant: ```c
int main() {
  int d1;
  int m1;
  int y1;
  scanf("%d %d %d", &d1, &m1, &y1);
  int d2;
  int m2;
  int y2;
  scanf("%d %d %d", &d2, &m2, &y2);
  if (y1 == y2) {
    if (m1 == m2) {
      if (d1 <= d2) {
        printf("0");
      } else {
        printf("%d\n", 15 * (d1 - d2));
      }
    } else {
      if (m1 <= m2) {
        printf("0");
      } else {
        printf("%d\n", 500 * (m1 - m2));
      }
    }
  } else {
    if (y1 < y2) {
      printf("0");
    } else {
      printf("10000");
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ubicacionUnicaEnCaja>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %ecx,0xc(%rsp)
  lea    -0x3(%rsi),%ecx
  mov    $0x3,%eax
  cmp    $0x2,%ecx
  jbe    L64
  sub    $0x6,%esi
  cmp    $0x3,%esi
  sbb    %eax,%eax
  and    $0x6,%eax
L64:
  lea    -0x3(%rdx),%ecx
  mov    $0x3,%r13d
  cmp    $0x2,%ecx
  jbe    L88
  sub    $0x6,%edx
  cmp    $0x3,%edx
  sbb    %r13d,%r13d
  and    $0x6,%r13d
L88:
  mov    %eax,%r12d
  movslq %eax,%rdx
  lea    (%rdx,%rdx,8),%rdx
  movslq %r13d,%rcx
  add    %rcx,%rdx
  lea    (%r15,%rdx,4),%rbp
  add    $0x3,%eax
  mov    %eax,0x14(%rsp)
  movl   $0x0,0x10(%rsp)
  jmp    L110
L53:
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  je     L52
L68:
  lea    0x0(%r13,%rbx,1),%r14d
  cmpl   $0x0,0x0(%rbp,%rbx,4)
  jne    L53
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r15,%rdi
  call   <candidatoCabeEnFila@plt>
  test   %rax,%rax
  je     L53
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <candidatoCabeEnColumna@plt>
  test   %rax,%rax
  je     L53
  addl   $0x1,0x10(%rsp)
  mov    %r14d,0x1c(%rsp)
  mov    0x8(%rsp),%eax
  mov    %eax,0x18(%rsp)
  jmp    L53
L52:
  add    $0x1,%r12d
  add    $0x24,%rbp
  cmp    0x14(%rsp),%r12d
  je     L60
L110:
  mov    %r12d,0x8(%rsp)
  mov    $0x0,%ebx
  jmp    L68
L60:
  cmpl   $0x1,0x10(%rsp)
  je     L39
  movl   $0x0,0x10(%rsp)
L54:
  mov    0x10(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  movslq 0x18(%rsp),%rax
  lea    (%rax,%rax,8),%rax
  lea    (%r15,%rax,4),%rdx
  movslq 0x1c(%rsp),%rax
  mov    0xc(%rsp),%edi
  mov    %edi,(%rdx,%rax,4)
  jmp    L54
```

assistant: ```c
int ubicacionUnicaEnCaja(int s[9][9], int f, int c, int candidato) {
  int f2, c2;
  int cajas1, cajas2;
  int pu = 0;
  int pf;
  int pc;
  if (f < 3)
    f2 = 0;
  if (f >= 3 && f < 6)
    f2 = 3;
  if (f >= 6 && f < 9)
    f2 = 6;
  if (c < 3)
    c2 = 0;
  if (c >= 3 && c < 6)
    c2 = 3;
  if (c >= 6 && c < 9)
    c2 = 6;
  cajas1 = f2 + 3;
  cajas2 = c2 + 3;
  int i, j;
  for (pu = 0, i = 0; i < 3; i++)
    for (j = 0; j < 3; j++) {
      if (s[f2 + i][c2 + j] == 0 && candidatoCabeEnFila(s, f2 + i, candidato) && candidatoCabeEnColumna(s, c2 + j, candidato)) {
        pu++;
        pf = f2 + i;
        pc = c2 + j;
      }
    }
  if (pu == 1) {
    s[pf][pc] = candidato;
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ubicacionUnicaEnCaja>:
  endbr64
  push   %r15
  lea    -0x3(%rsi),%eax
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %ecx,0xc(%rsp)
  mov    $0x3,%ecx
  cmp    $0x2,%eax
  jbe    L26
  sub    $0x6,%esi
  cmp    $0x3,%esi
  sbb    %ecx,%ecx
  and    $0x6,%ecx
L26:
  lea    -0x3(%rdx),%eax
  mov    $0x3,%r12d
  cmp    $0x2,%eax
  jbe    L86
  sub    $0x6,%edx
  cmp    $0x3,%edx
  sbb    %r12d,%r12d
  and    $0x6,%r12d
L86:
  movslq %ecx,%rax
  movslq %r12d,%rdx
  movl   $0x0,0x10(%rsp)
  mov    %rax,%r14
  lea    (%rax,%rax,8),%rax
  add    %rdx,%rax
  lea    (%r15,%rax,4),%r13
  lea    0x3(%r14),%eax
  mov    %eax,0x14(%rsp)
L22:
  xor    %ebx,%ebx
L93:
  mov    0x0(%r13,%rbx,4),%eax
  lea    (%r12,%rbx,1),%ebp
  test   %eax,%eax
  je     L96
L69:
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L93
  add    $0x1,%r14d
  add    $0x24,%r13
  cmp    0x14(%rsp),%r14d
  jne    L22
  cmpl   $0x1,0x10(%rsp)
  je     L88
  movl   $0x0,0x10(%rsp)
L53:
  mov    0x10(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <candidatoCabeEnFila@plt>
  test   %rax,%rax
  je     L69
  mov    0xc(%rsp),%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <candidatoCabeEnColumna@plt>
  test   %rax,%rax
  je     L69
  addl   $0x1,0x10(%rsp)
  mov    %ebp,0x1c(%rsp)
  mov    %r14d,0x18(%rsp)
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L88:
  movslq 0x18(%rsp),%r14
  mov    0xc(%rsp),%ecx
  lea    (%r14,%r14,8),%rax
  lea    (%r15,%rax,4),%rax
  movslq 0x1c(%rsp),%r15
  mov    %ecx,(%rax,%r15,4)
  jmp    L53
```

assistant: ```c
int ubicacionUnicaEnCaja(int s[9][9], int f, int c, int candidato) {
  int f2, c2;
  int cajas1, cajas2;
  int pu = 0;
  int pf;
  int pc;
  if (f < 3)
    f2 = 0;
  if (f >= 3 && f < 6)
    f2 = 3;
  if (f >= 6 && f < 9)
    f2 = 6;
  if (c < 3)
    c2 = 0;
  if (c >= 3 && c < 6)
    c2 = 3;
  if (c >= 6 && c < 9)
    c2 = 6;
  cajas1 = f2 + 3;
  cajas2 = c2 + 3;
  int i, j;
  for (pu = 0, i = 0; i < 3; i++)
    for (j = 0; j < 3; j++) {
      if (s[f2 + i][c2 + j] == 0 && candidatoCabeEnFila(s, f2 + i, candidato) && candidatoCabeEnColumna(s, c2 + j, candidato)) {
        pu++;
        pf = f2 + i;
        pc = c2 + j;
      }
    }
  if (pu == 1) {
    s[pf][pc] = candidato;
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getHashIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L15:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long getHashIndex(const char *key, int nTableLength) {
  unsigned long nHash = 0;
  while (*key) {
    nHash = (nHash << 5) + nHash + *key++;
  }
  return (nHash % nTableLength);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getHashIndex>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
  mov    $0x0,%eax
L25:
  mov    %rax,%rcx
  shl    $0x5,%rcx
  add    %rcx,%rax
  add    $0x1,%rdi
  movsbq %dl,%rdx
  add    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L25
L22:
  movslq %esi,%rsi
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%rax
  ret
L14:
  mov    $0x0,%eax
  jmp    L22
```

assistant: ```c
unsigned long getHashIndex(const char *key, int nTableLength) {
  unsigned long nHash = 0;
  while (*key) {
    nHash = (nHash << 5) + nHash + *key++;
  }
  return (nHash % nTableLength);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getHashIndex>:
  endbr64
  movsbq (%rdi),%rdx
  movslq %esi,%rsi
  test   %dl,%dl
  je     L15
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  mov    %rax,%rcx
  add    $0x1,%rdi
  shl    $0x5,%rcx
  add    %rcx,%rax
  add    %rdx,%rax
  movsbq (%rdi),%rdx
  test   %dl,%dl
  jne    L10
  xor    %edx,%edx
  div    %rsi
  mov    %rdx,%r8
  mov    %r8,%rax
  ret
  nopl   (%rax)
L15:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long getHashIndex(const char *key, int nTableLength) {
  unsigned long nHash = 0;
  while (*key) {
    nHash = (nHash << 5) + nHash + *key++;
  }
  return (nHash % nTableLength);
}
```