ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<crear_bitmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L49
  mov    $0x0,%eax
  jmp    L74
L49:
  movq   $0x0,-0x20(%rbp)
  jmp    L18
L50:
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L33
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <binarise@plt>
  mov    %rax,-0x30(%rbp)
  jmp    L45
L33:
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <binarise@plt>
  mov    %rax,-0x30(%rbp)
L45:
  movq   $0x0,-0x28(%rbp)
  jmp    L13
L55:
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pot@plt>
  mov    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pot@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%edx
  div    %rbx
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pot@plt>
  imul   %rbx,%rax
  sub    %rax,-0x30(%rbp)
  addq   $0x1,-0x28(%rbp)
L13:
  cmpq   $0x7,-0x28(%rbp)
  jbe    L55
  addq   $0x1,-0x20(%rbp)
L18:
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L50
  mov    -0x18(%rbp),%rax
L74:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *crear_bitmap(char *bloque, size_t tam) {
  size_t binario, j;
  char *bitmap = calloc(1, tam * 8);
  if (!bitmap)
    return NULL;
  for (size_t i = 0; i < tam; i++) {
    if (bloque[i] < 0)
      binario = binarise(bloque[i] + 256);
    else
      binario = binarise(bloque[i]);
    for (j = 0; j < 8; j++) {
      bitmap[8 * i + j] = binario / pot(10, 7 - j);
      binario = binario - (binario / pot(10, 7 - j)) * pot(10, 7 - j);
    }
  }
  return bitmap;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<crear_bitmap>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x0(,%rsi,8),%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L17
  mov    %rax,%r14
  test   %rbx,%rbx
  je     L17
  mov    %rbp,0x8(%rsp)
  lea    0x0(%rbp,%rbx,1),%rax
  mov    %rax,0x10(%rsp)
  mov    $0x7,%r15d
  jmp    L14
L31:
  movsbl %dil,%edi
  call   <binarise@plt>
  mov    %rax,%rbx
L22:
  mov    $0x0,%ebp
L51:
  mov    %r15d,%r13d
  sub    %ebp,%r13d
  mov    %r13d,%esi
  mov    $0xa,%edi
  call   <pot@plt>
  mov    %rax,%rcx
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %al,(%r14,%rbp,1)
  mov    %r13d,%esi
  mov    $0xa,%edi
  call   <pot@plt>
  mov    %rax,%rcx
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,%r12
  mov    %r13d,%esi
  mov    $0xa,%edi
  call   <pot@plt>
  imul   %rax,%r12
  sub    %r12,%rbx
  add    $0x1,%rbp
  cmp    $0x8,%rbp
  jne    L51
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  add    $0x8,%r14
  cmp    0x10(%rsp),%rax
  je     L17
L14:
  mov    0x8(%rsp),%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  js     L31
  movsbl %dil,%edi
  call   <binarise@plt>
  mov    %rax,%rbx
  jmp    L22
L17:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *crear_bitmap(char *bloque, size_t tam) {
  size_t binario, j;
  char *bitmap = calloc(1, tam * 8);
  if (!bitmap)
    return NULL;
  for (size_t i = 0; i < tam; i++) {
    if (bloque[i] < 0)
      binario = binarise(bloque[i] + 256);
    else
      binario = binarise(bloque[i]);
    for (j = 0; j < 8; j++) {
      bitmap[8 * i + j] = binario / pot(10, 7 - j);
      binario = binario - (binario / pot(10, 7 - j)) * pot(10, 7 - j);
    }
  }
  return bitmap;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crear_bitmap>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  shl    $0x3,%rsi
  push   %r14
  mov    %rdi,%r14
  mov    $0x1,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L25
  test   %r15,%r15
  je     L25
  add    %r14,%r15
  mov    %r14,0x8(%rsp)
  mov    %rax,%r12
  mov    $0x7,%r13d
  mov    %r15,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L4:
  mov    0x8(%rsp),%rax
  xor    %r15d,%r15d
  movsbl (%rax),%edi
  call   <binarise@plt>
  mov    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r13d,%r14d
  mov    $0xa,%edi
  sub    %r15d,%r14d
  mov    %r14d,%esi
  call   <pot@plt>
  xor    %edx,%edx
  mov    %r14d,%esi
  mov    $0xa,%edi
  mov    %rax,%r8
  mov    %rbx,%rax
  div    %r8
  mov    %al,(%r12,%r15,1)
  add    $0x1,%r15
  call   <pot@plt>
  xor    %edx,%edx
  mov    %r14d,%esi
  mov    $0xa,%edi
  mov    %rax,%r8
  mov    %rbx,%rax
  div    %r8
  mov    %rax,%rbp
  call   <pot@plt>
  imul   %rax,%rbp
  sub    %rbp,%rbx
  cmp    $0x8,%r15
  jne    L33
  addq   $0x1,0x8(%rsp)
  add    $0x8,%r12
  mov    0x8(%rsp),%rax
  cmp    0x10(%rsp),%rax
  jne    L4
L25:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *crear_bitmap(char *bloque, size_t tam) {
  size_t binario, j;
  char *bitmap = calloc(1, tam * 8);
  if (!bitmap)
    return NULL;
  for (size_t i = 0; i < tam; i++) {
    if (bloque[i] < 0)
      binario = binarise(bloque[i] + 256);
    else
      binario = binarise(bloque[i]);
    for (j = 0; j < 8; j++) {
      bitmap[8 * i + j] = binario / pot(10, 7 - j);
      binario = binario - (binario / pot(10, 7 - j)) * pot(10, 7 - j);
    }
  }
  return bitmap;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crear_bitmap>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  shl    $0x3,%rsi
  push   %r14
  mov    %rdi,%r14
  mov    $0x1,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L6
  test   %r15,%r15
  je     L6
  add    %r14,%r15
  mov    %r14,0x8(%rsp)
  mov    %rax,%r12
  mov    $0x7,%r13d
  mov    %r15,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L20:
  mov    0x8(%rsp),%rax
  xor    %r15d,%r15d
  movsbl (%rax),%edi
  call   <binarise@plt>
  mov    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %r13d,%r14d
  mov    $0xa,%edi
  sub    %r15d,%r14d
  mov    %r14d,%esi
  call   <pot@plt>
  xor    %edx,%edx
  mov    %r14d,%esi
  mov    $0xa,%edi
  mov    %rax,%r8
  mov    %rbx,%rax
  div    %r8
  mov    %al,(%r12,%r15,1)
  add    $0x1,%r15
  call   <pot@plt>
  xor    %edx,%edx
  mov    %r14d,%esi
  mov    $0xa,%edi
  mov    %rax,%r8
  mov    %rbx,%rax
  div    %r8
  mov    %rax,%rbp
  call   <pot@plt>
  imul   %rax,%rbp
  sub    %rbp,%rbx
  cmp    $0x8,%r15
  jne    L12
  addq   $0x1,0x8(%rsp)
  add    $0x8,%r12
  mov    0x8(%rsp),%rax
  cmp    %rax,0x10(%rsp)
  jne    L20
L6:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *crear_bitmap(char *bloque, size_t tam) {
  size_t binario, j;
  char *bitmap = calloc(1, tam * 8);
  if (!bitmap)
    return NULL;
  for (size_t i = 0; i < tam; i++) {
    if (bloque[i] < 0)
      binario = binarise(bloque[i] + 256);
    else
      binario = binarise(bloque[i]);
    for (j = 0; j < 8; j++) {
      bitmap[8 * i + j] = binario / pot(10, 7 - j);
      binario = binario - (binario / pot(10, 7 - j)) * pot(10, 7 - j);
    }
  }
  return bitmap;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  negl   -0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init(int *a1, int *a2, int N) {
  int i, s = -1;
  for (i = 0; i < N; i++) {
    a1[i] = s;
    a2[i] = i;
    s = -s;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<init>:
  endbr64
  test   %edx,%edx
  jle    L18
  mov    %edx,%edx
  mov    $0x0,%eax
  mov    $0xffffffff,%ecx
L17:
  mov    %ecx,(%rdi,%rax,4)
  mov    %eax,(%rsi,%rax,4)
  neg    %ecx
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L18:
  ret
```

assistant: ```c
void init(int *a1, int *a2, int N) {
  int i, s = -1;
  for (i = 0; i < N; i++) {
    a1[i] = s;
    a2[i] = i;
    s = -s;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  xor    %eax,%eax
  mov    $0xffffffff,%ecx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ecx,(%rdi,%rax,4)
  neg    %ecx
  mov    %eax,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L11:
  ret
```

assistant: ```c
void init(int *a1, int *a2, int N) {
  int i, s = -1;
  for (i = 0; i < N; i++) {
    a1[i] = s;
    a2[i] = i;
    s = -s;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init>:
  endbr64
  test   %edx,%edx
  jle    L15
  movslq %edx,%rdx
  xor    %eax,%eax
  mov    $0xffffffff,%ecx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ecx,(%rdi,%rax,4)
  neg    %ecx
  mov    %eax,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
L15:
  ret
```

assistant: ```c
void init(int *a1, int *a2, int N) {
  int i, s = -1;
  for (i = 0; i < N; i++) {
    a1[i] = s;
    a2[i] = i;
    s = -s;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L26
  addq   $0x1,-0x10(%rbp)
  jmp    L10
L6:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
L26:
  mov    -0x8(%rbp),%rcx
  movabs $0x3e88cb3c9484e2b,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    %rdx
  mov    %rdx,%rax
  shl    $0x6,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(const char *str) {
  const char *p = str;
  unsigned long h = *p;
  if (h) {
    for (p += 1; *p != '\0'; p++) {
      h = (h << 5) - h + *p;
    }
  }
  return h % 131;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rcx
  test   %rcx,%rcx
  je     L6
  lea    0x1(%rdi),%rsi
  movzbl 0x1(%rdi),%edx
  test   %dl,%dl
  je     L6
L14:
  mov    %rcx,%rax
  shl    $0x5,%rax
  sub    %rcx,%rax
  movsbq %dl,%rdx
  lea    (%rdx,%rax,1),%rcx
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L14
L6:
  movabs $0x3e88cb3c9484e2b,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    %rdx
  mov    %rdx,%rax
  shl    $0x6,%rax
  add    %rdx,%rax
  lea    (%rdx,%rax,2),%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
unsigned int hash(const char *str) {
  const char *p = str;
  unsigned long h = *p;
  if (h) {
    for (p += 1; *p != '\0'; p++) {
      h = (h << 5) - h + *p;
    }
  }
  return h % 131;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rcx
  xor    %eax,%eax
  test   %rcx,%rcx
  je     L8
  movsbq 0x1(%rdi),%rax
  lea    0x1(%rdi),%rsi
  test   %al,%al
  je     L23
  nopl   0x0(%rax)
L1:
  mov    %rcx,%rdx
  add    $0x1,%rsi
  shl    $0x5,%rdx
  sub    %rcx,%rdx
  lea    (%rax,%rdx,1),%rcx
  movsbq (%rsi),%rax
  test   %al,%al
  jne    L1
L23:
  movabs $0x3e88cb3c9484e2b,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    %rdx
  mov    %rdx,%rax
  shl    $0x6,%rax
  add    %rdx,%rax
  lea    (%rdx,%rax,2),%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
L8:
  ret
```

assistant: ```c
unsigned int hash(const char *str) {
  const char *p = str;
  unsigned long h = *p;
  if (h) {
    for (p += 1; *p != '\0'; p++) {
      h = (h << 5) - h + *p;
    }
  }
  return h % 131;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rcx
  xor    %eax,%eax
  test   %rcx,%rcx
  je     L14
  movsbq 0x1(%rdi),%rax
  lea    0x1(%rdi),%rsi
  test   %al,%al
  je     L20
  nopl   0x0(%rax)
L4:
  mov    %rcx,%rdx
  add    $0x1,%rsi
  shl    $0x5,%rdx
  sub    %rcx,%rdx
  lea    (%rax,%rdx,1),%rcx
  movsbq (%rsi),%rax
  test   %al,%al
  jne    L4
L20:
  movabs $0x3e88cb3c9484e2b,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    %rdx
  mov    %rdx,%rax
  shl    $0x6,%rax
  add    %rdx,%rax
  lea    (%rdx,%rax,2),%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
L14:
  ret
```

assistant: ```c
unsigned int hash(const char *str) {
  const char *p = str;
  unsigned long h = *p;
  if (h) {
    for (p += 1; *p != '\0'; p++) {
      h = (h << 5) - h + *p;
    }
  }
  return h % 131;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ComplexMask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    %r9d,-0x48(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%eax
  mov    %eax,%edi
  call   <_mm_set1_epi8@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_subs_epu8@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_cmpeq_epi8@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x18(%rbp),%r8
  mov    -0x44(%rbp),%edi
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <NeedsFilter@plt>
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_and_si128@plt>
  mov    -0x50(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void ComplexMask(const __m128i *const p1, const __m128i *const p0, const __m128i *const q0, const __m128i *const q1, int thresh, int ithresh, __m128i *const mask) {
  const __m128i it = _mm_set1_epi8(ithresh);
  const __m128i diff = _mm_subs_epu8(*mask, it);
  const __m128i thresh_mask = _mm_cmpeq_epi8(diff, _mm_setzero_si128());
  __m128i filter_mask;
  NeedsFilter(p1, p0, q0, q1, thresh, &filter_mask);
  *mask = _mm_and_si128(thresh_mask, filter_mask);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ComplexMask>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8d,%r13d
  mov    %r9d,%edi
  mov    0x60(%rsp),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <_mm_set1_epi8@plt>
  mov    %eax,%esi
  mov    (%r15),%edi
  call   <_mm_subs_epu8@plt>
  mov    %eax,%r14d
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %eax,%esi
  mov    %r14d,%edi
  call   <_mm_cmpeq_epi8@plt>
  mov    %eax,%r14d
  lea    0x14(%rsp),%r9
  mov    %r13d,%r8d
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <NeedsFilter@plt>
  mov    0x14(%rsp),%esi
  mov    %r14d,%edi
  call   <_mm_and_si128@plt>
  mov    %eax,(%r15)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ComplexMask(const __m128i *const p1, const __m128i *const p0, const __m128i *const q0, const __m128i *const q1, int thresh, int ithresh, __m128i *const mask) {
  const __m128i it = _mm_set1_epi8(ithresh);
  const __m128i diff = _mm_subs_epu8(*mask, it);
  const __m128i thresh_mask = _mm_cmpeq_epi8(diff, _mm_setzero_si128());
  __m128i filter_mask;
  NeedsFilter(p1, p0, q0, q1, thresh, &filter_mask);
  *mask = _mm_and_si128(thresh_mask, filter_mask);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ComplexMask>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r9d,%edi
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8d,0xc(%rsp)
  mov    0x60(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <_mm_set1_epi8@plt>
  mov    (%rbx),%edi
  mov    %eax,%esi
  call   <_mm_subs_epu8@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <_mm_setzero_si128@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <_mm_cmpeq_epi8@plt>
  mov    0xc(%rsp),%r8d
  mov    %r15,%rcx
  mov    %r14,%rdx
  lea    0x14(%rsp),%r9
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <NeedsFilter@plt>
  mov    0x14(%rsp),%esi
  mov    %ebp,%edi
  call   <_mm_and_si128@plt>
  mov    %eax,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ComplexMask(const __m128i *const p1, const __m128i *const p0, const __m128i *const q0, const __m128i *const q1, int thresh, int ithresh, __m128i *const mask) {
  const __m128i it = _mm_set1_epi8(ithresh);
  const __m128i diff = _mm_subs_epu8(*mask, it);
  const __m128i thresh_mask = _mm_cmpeq_epi8(diff, _mm_setzero_si128());
  __m128i filter_mask;
  NeedsFilter(p1, p0, q0, q1, thresh, &filter_mask);
  *mask = _mm_and_si128(thresh_mask, filter_mask);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ComplexMask>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r9d,%edi
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8d,0xc(%rsp)
  mov    0x60(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <_mm_set1_epi8@plt>
  mov    (%rbx),%edi
  mov    %eax,%esi
  call   <_mm_subs_epu8@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <_mm_setzero_si128@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <_mm_cmpeq_epi8@plt>
  mov    0xc(%rsp),%r8d
  mov    %r15,%rcx
  mov    %r14,%rdx
  lea    0x14(%rsp),%r9
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <NeedsFilter@plt>
  mov    0x14(%rsp),%esi
  mov    %ebp,%edi
  call   <_mm_and_si128@plt>
  mov    %eax,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ComplexMask(const __m128i *const p1, const __m128i *const p0, const __m128i *const q0, const __m128i *const q1, int thresh, int ithresh, __m128i *const mask) {
  const __m128i it = _mm_set1_epi8(ithresh);
  const __m128i diff = _mm_subs_epu8(*mask, it);
  const __m128i thresh_mask = _mm_cmpeq_epi8(diff, _mm_setzero_si128());
  __m128i filter_mask;
  NeedsFilter(p1, p0, q0, q1, thresh, &filter_mask);
  *mask = _mm_and_si128(thresh_mask, filter_mask);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<one_step_heun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  movapd %xmm0,%xmm1
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <set_wieners@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0x3c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rdi
  movq   %rax,%xmm0
  call   <my_rhs@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L9
L34:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L34
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rsi
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x3c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rdi
  movq   %rax,%xmm0
  call   <my_rhs@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L30
L1:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L1
  mov    -0x48(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void one_step_heun(double *y, double dt, double *yval[2], int neq, double *tim) {
  int i;
  double t = *tim, t1;
  set_wieners(dt, y, *tim);
  my_rhs(t, y, yval[0], neq);
  for (i = 0; i < neq; i++)
    yval[0][i] = dt * yval[0][i] + y[i];
  t1 = t + dt;
  my_rhs(t1, yval[0], yval[1], neq);
  for (i = 0; i < neq; i++)
    y[i] = .5 * (y[i] + yval[0][i] + dt * yval[1][i]);
  *tim = t1;
}
```