ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kstrcmp>:
  endbr64
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L53
  jmp    L39
  nopl   (%rax)
L11:
  test   %dl,%dl
  je     L39
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  cmp    %dl,%cl
  jne    L39
L53:
  test   %cl,%cl
  jne    L11
  xor    %eax,%eax
  test   %dl,%dl
  jne    L39
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  cmp    %dl,%cl
  setge  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int kstrcmp(char *str1, char *str2) {
  while ((*str1 == *str2) && *str1 && *str2) {
    str1++;
    str2++;
  }
  if (*str1 == *str2)
    return 0;
  if (*str1 < *str2)
    return -1;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <t1@plt>
  mov    $0x0,%eax
  call   <t2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  t1();
  t2();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <t1@plt>
  mov    $0x0,%eax
  call   <t2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  t1();
  t2();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <t1@plt>
  xor    %eax,%eax
  call   <t2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  t1();
  t2();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <t1@plt>
  xor    %eax,%eax
  call   <t2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  t1();
  t2();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Readline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x1,-0x20(%rbp)
  jmp    L4
L29:
  lea    -0x21(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x1,-0x10(%rbp)
  jne    L90
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x21(%rbp),%edx
  mov    %dl,(%rax)
  movzbl -0x21(%rbp),%eax
  cmp    $0xa,%al
  jne    L3
  jmp    L48
L90:
  cmpq   $0x0,-0x10(%rbp)
  jne    L113
  cmpq   $0x1,-0x20(%rbp)
  jne    L102
  mov    $0x0,%eax
  jmp    L33
L113:
  mov    D0(%rip),%rax
  mov    (%rax),%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L19
  mov    $0xffffffffffffffff,%rax
  jmp    L33
L19:
  nop
L3:
  addq   $0x1,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jb     L29
  jmp    L48
L102:
  nop
L48:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

assistant: ```c
ssize_t Readline(int sockd, void *vptr, size_t maxlen) {
  ssize_t n, rc;
  char c, *buffer;
  buffer = vptr;
  for (n = 1; n < maxlen; n++) {
    if ((rc = recv(sockd, &c, 1, 0)) == 1) {
      *buffer++ = c;
      if (c == '\n')
        break;
    } else if (rc == 0) {
      if (n == 1)
        return 0;
      else
        break;
    } else {
      if (errno == EINTR)
        continue;
      return -1;
    }
  }
  *buffer = 0;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Readline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rdx
  jbe    L69
  mov    %edi,%r13d
  mov    %rdx,%r12
  mov    $0x1,%ebx
  lea    0x7(%rsp),%r14
  jmp    L81
L85:
  lea    0x1(%rbp),%rdx
  movzbl 0x7(%rsp),%eax
  mov    %al,0x0(%rbp)
  cmp    $0xa,%al
  je     L53
  mov    %rdx,%rbp
L6:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L30
L81:
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  cmp    $0x1,%rax
  je     L85
  test   %rax,%rax
  je     L87
  mov    D1(%rip),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L6
  mov    $0xffffffffffffffff,%rbx
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L87:
  cmp    $0x1,%rbx
  jne    L99
  mov    %rax,%rbx
  jmp    L54
L30:
  mov    %r12,%rbx
L99:
  movb   $0x0,0x0(%rbp)
  jmp    L54
L69:
  mov    $0x1,%ebx
  jmp    L99
L53:
  mov    %rdx,%rbp
  jmp    L99
L90:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t Readline(int sockd, void *vptr, size_t maxlen) {
  ssize_t n, rc;
  char c, *buffer;
  buffer = vptr;
  for (n = 1; n < maxlen; n++) {
    if ((rc = recv(sockd, &c, 1, 0)) == 1) {
      *buffer++ = c;
      if (c == '\n')
        break;
    } else if (rc == 0) {
      if (n == 1)
        return 0;
      else
        break;
    } else {
      if (errno == EINTR)
        continue;
      return -1;
    }
  }
  *buffer = 0;
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Readline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rdx
  jbe    L46
  mov    %edi,%r13d
  mov    %rdx,%rbp
  mov    $0x1,%r12d
  lea    0x7(%rsp),%r14
L68:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  cmp    $0x1,%rax
  je     L31
  test   %rax,%rax
  je     L43
  mov    D14(%rip),%rax
  mov    D15(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L109
  mov    $0xffffffffffffffff,%r12
L106:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  movzbl 0x7(%rsp),%eax
  lea    0x1(%rbx),%rdx
  mov    %al,(%rbx)
  mov    %rdx,%rbx
  cmp    $0xa,%al
  je     L70
L109:
  add    $0x1,%r12
  cmp    %r12,%rbp
  jne    L68
L70:
  movb   $0x0,(%rbx)
  jmp    L106
L43:
  cmp    $0x1,%r12
  jne    L70
  xor    %r12d,%r12d
  jmp    L106
  nopl   0x0(%rax,%rax,1)
L46:
  mov    $0x1,%r12d
  jmp    L70
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t Readline(int sockd, void *vptr, size_t maxlen) {
  ssize_t n, rc;
  char c, *buffer;
  buffer = vptr;
  for (n = 1; n < maxlen; n++) {
    if ((rc = recv(sockd, &c, 1, 0)) == 1) {
      *buffer++ = c;
      if (c == '\n')
        break;
    } else if (rc == 0) {
      if (n == 1)
        return 0;
      else
        break;
    } else {
      if (errno == EINTR)
        continue;
      return -1;
    }
  }
  *buffer = 0;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Readline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rdx
  jbe    L105
  mov    %edi,%r13d
  mov    %rdx,%rbp
  mov    $0x1,%r12d
  lea    0x7(%rsp),%r14
L40:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  cmp    $0x1,%rax
  je     L101
  test   %rax,%rax
  je     L97
  mov    D4(%rip),%rax
  mov    D0(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L8
  mov    $0xffffffffffffffff,%r12
L60:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L101:
  movzbl 0x7(%rsp),%eax
  lea    0x1(%rbx),%rdx
  mov    %al,(%rbx)
  mov    %rdx,%rbx
  cmp    $0xa,%al
  je     L109
L8:
  add    $0x1,%r12
  cmp    %r12,%rbp
  jne    L40
L109:
  movb   $0x0,(%rbx)
  jmp    L60
L97:
  cmp    $0x1,%r12
  jne    L109
  xor    %r12d,%r12d
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L105:
  mov    $0x1,%r12d
  jmp    L109
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t Readline(int sockd, void *vptr, size_t maxlen) {
  ssize_t n, rc;
  char c, *buffer;
  buffer = vptr;
  for (n = 1; n < maxlen; n++) {
    if ((rc = recv(sockd, &c, 1, 0)) == 1) {
      *buffer++ = c;
      if (c == '\n')
        break;
    } else if (rc == 0) {
      if (n == 1)
        return 0;
      else
        break;
    } else {
      if (errno == EINTR)
        continue;
      return -1;
    }
  }
  *buffer = 0;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x211c(%rbp)
  jmp    L15
L79:
  cmpl   $0x60,-0x211c(%rbp)
  jbe    L103
  cmpl   $0x7a,-0x211c(%rbp)
  ja     L103
  mov    -0x211c(%rbp),%eax
  mov    $0x7a,%ecx
  mov    $0x61,%edx
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <interval_add@plt>
  mov    -0x211c(%rbp),%edx
  mov    %al,-0x2110(%rbp,%rdx,1)
  jmp    L25
L103:
  cmpl   $0x40,-0x211c(%rbp)
  jbe    L115
  cmpl   $0x5a,-0x211c(%rbp)
  ja     L115
  mov    -0x211c(%rbp),%eax
  mov    $0x5a,%ecx
  mov    $0x41,%edx
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <interval_add@plt>
  mov    -0x211c(%rbp),%edx
  mov    %al,-0x2110(%rbp,%rdx,1)
  jmp    L25
L115:
  mov    -0x211c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x211c(%rbp),%eax
  mov    %dl,-0x2110(%rbp,%rax,1)
L25:
  addl   $0x1,-0x211c(%rbp)
L15:
  cmpl   $0xff,-0x211c(%rbp)
  jbe    L79
  jmp    L20
L96:
  lea    -0x2010(%rbp),%rax
  mov    %rax,-0x2118(%rbp)
  jmp    L71
L37:
  mov    -0x2118(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  movzbl -0x2110(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addq   $0x1,-0x2118(%rbp)
L71:
  mov    -0x2118(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
L20:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  lea    -0x2010(%rbp),%rax
  mov    $0x2000,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L96
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
int main() {
  char signal_table[256];
  for (unsigned i = 0; i < 256; i++) {
    if (i >= 'a' && i <= 'z')
      signal_table[i] = interval_add(i, 3, 'a', 'z');
    else if (i >= 'A' && i <= 'Z')
      signal_table[i] = interval_add(i, 3, 'A', 'Z');
    else
      signal_table[i] = (char)i;
  }
  char buffer[8192];
  while (fgets(buffer, 8192, stdin) != NULL) {
    for (char *p = buffer; *p != 0; p++)
      putchar(signal_table[*p]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2108(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebp
  mov    $0x0,%ebx
L54:
  mov    %ebx,%edi
  lea    -0x62(%rbp),%eax
  cmp    $0x19,%eax
  jbe    L57
  lea    -0x42(%rbp),%eax
  cmp    $0x19,%eax
  jbe    L9
  mov    %bl,(%rsp,%rbx,1)
  cmp    $0xff,%ebp
  ja     L17
L2:
  add    $0x1,%rbx
  add    $0x1,%ebp
  jmp    L54
L57:
  mov    $0x7a,%ecx
  mov    $0x61,%edx
  mov    $0x3,%esi
  call   <interval_add@plt>
L111:
  mov    %al,(%rsp,%rbx,1)
  jmp    L2
L9:
  mov    $0x5a,%ecx
  mov    $0x41,%edx
  mov    $0x3,%esi
  call   <interval_add@plt>
  jmp    L111
L17:
  mov    D3(%rip),%rbp
  jmp    L88
L3:
  movsbq %al,%rax
  movsbl (%rsp,%rax,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L3
L88:
  lea    0x100(%rsp),%rdi
  mov    0x0(%rbp),%edx
  mov    $0x2000,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L80
  movzbl 0x100(%rsp),%eax
  lea    0x100(%rsp),%rbx
  test   %al,%al
  jne    L3
  jmp    L88
L80:
  mov    0x2108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x2118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char signal_table[256];
  for (unsigned i = 0; i < 256; i++) {
    if (i >= 'a' && i <= 'z')
      signal_table[i] = interval_add(i, 3, 'a', 'z');
    else if (i >= 'A' && i <= 'Z')
      signal_table[i] = interval_add(i, 3, 'A', 'Z');
    else
      signal_table[i] = (char)i;
  }
  char buffer[8192];
  while (fgets(buffer, 8192, stdin) != NULL) {
    for (char *p = buffer; *p != 0; p++)
      putchar(signal_table[*p]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x110,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x2108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L11
  nopl   0x0(%rax)
L63:
  add    $0x1,%rbp
  mov    %ebx,%edi
L11:
  lea    -0x61(%rdi),%eax
  lea    0x1(%rdi),%ebx
  cmp    $0x19,%eax
  jbe    L44
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L96
  lea    -0x1(%rbx),%eax
  mov    %al,0x0(%rbp)
  cmp    $0x100,%ebx
  jne    L63
  mov    D7(%rip),%r12
  lea    0x100(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    (%r12),%edx
  mov    $0x2000,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L99
  movsbq 0x100(%rsp),%rax
  mov    %rbp,%rbx
  test   %al,%al
  je     L5
  cs nopw 0x0(%rax,%rax,1)
L23:
  movsbl (%rsp,%rax,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movsbq (%rbx),%rax
  test   %al,%al
  jne    L23
  jmp    L5
L99:
  mov    0x2108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x2110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    $0x7a,%ecx
  mov    $0x61,%edx
  mov    $0x3,%esi
  call   <interval_add@plt>
  mov    %al,0x0(%rbp)
  jmp    L63
L46:
  call   <__stack_chk_fail@plt>
L96:
  mov    $0x5a,%ecx
  mov    $0x41,%edx
  mov    $0x3,%esi
  call   <interval_add@plt>
  mov    %al,0x0(%rbp)
  jmp    L63
```

assistant: ```c
int main() {
  char signal_table[256];
  for (unsigned i = 0; i < 256; i++) {
    if (i >= 'a' && i <= 'z')
      signal_table[i] = interval_add(i, 3, 'a', 'z');
    else if (i >= 'A' && i <= 'Z')
      signal_table[i] = interval_add(i, 3, 'A', 'Z');
    else
      signal_table[i] = (char)i;
  }
  char buffer[8192];
  while (fgets(buffer, 8192, stdin) != NULL) {
    for (char *p = buffer; *p != 0; p++)
      putchar(signal_table[*p]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x110,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x2108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L20
  nopl   0x0(%rax)
L27:
  add    $0x1,%rbp
  mov    %ebx,%edi
L20:
  lea    -0x61(%rdi),%eax
  lea    0x1(%rdi),%ebx
  cmp    $0x19,%eax
  jbe    L66
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L104
  lea    -0x1(%rbx),%eax
  mov    %al,0x0(%rbp)
  cmp    $0x100,%ebx
  jne    L27
  mov    D8(%rip),%r12
  lea    0x100(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L103:
  mov    (%r12),%edx
  mov    $0x2000,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L1
  movsbq 0x100(%rsp),%rax
  mov    %rbp,%rbx
  test   %al,%al
  je     L103
  cs nopw 0x0(%rax,%rax,1)
L81:
  movsbl (%rsp,%rax,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movsbq (%rbx),%rax
  test   %al,%al
  jne    L81
  jmp    L103
L1:
  mov    0x2108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L107
  add    $0x2110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  mov    $0x7a,%ecx
  mov    $0x61,%edx
  mov    $0x3,%esi
  call   <interval_add@plt>
  mov    %al,0x0(%rbp)
  jmp    L27
L107:
  call   <__stack_chk_fail@plt>
L104:
  mov    $0x5a,%ecx
  mov    $0x41,%edx
  mov    $0x3,%esi
  call   <interval_add@plt>
  mov    %al,0x0(%rbp)
  jmp    L27
```

assistant: ```c
int main() {
  char signal_table[256];
  for (unsigned i = 0; i < 256; i++) {
    if (i >= 'a' && i <= 'z')
      signal_table[i] = interval_add(i, 3, 'a', 'z');
    else if (i >= 'A' && i <= 'Z')
      signal_table[i] = interval_add(i, 3, 'A', 'Z');
    else
      signal_table[i] = (char)i;
  }
  char buffer[8192];
  while (fgets(buffer, 8192, stdin) != NULL) {
    for (char *p = buffer; *p != 0; p++)
      putchar(signal_table[*p]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<miller>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  cmpq   $0x1,-0x38(%rbp)
  jg     L132
  mov    $0x0,%eax
  jmp    L1
L132:
  cmpq   $0x2,-0x38(%rbp)
  je     L93
  mov    -0x38(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L93
  mov    $0x0,%eax
  jmp    L1
L93:
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  jmp    L78
L147:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x28(%rbp)
L78:
  mov    -0x28(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L147
  movq   $0x0,-0x20(%rbp)
  jmp    L124
L110:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x38(%rbp),%rdx
  lea    -0x1(%rdx),%rcx
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mod@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L92
L48:
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mul@plt>
  mov    %rax,-0x10(%rbp)
  shlq   -0x18(%rbp)
L92:
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x18(%rbp)
  je     L121
  cmpq   $0x1,-0x10(%rbp)
  je     L121
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jne    L48
L121:
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  je     L9
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L9
  mov    $0x0,%eax
  jmp    L1
L9:
  addq   $0x1,-0x20(%rbp)
L124:
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jl     L110
  mov    $0x1,%eax
L1:
  leave
  ret
```

assistant: ```c
int miller(long long p, long long it) {
  if (p < 2)
    return 0;
  if (p != 2 && p % 2 == 0)
    return 0;
  long long s, i, a, tt, md;
  s = p - 1;
  while (s % 2 == 0)
    s /= 2;
  for (i = 0; i < it; i++) {
    a = rand() % (p - 1) + 1;
    tt = s;
    md = mod(a, tt, p);
    while (tt != p - 1 && md != 1 && md != p - 1) {
      md = mul(md, md, p);
      tt *= 2;
    }
    if (md != p - 1 && tt % 2 == 0)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<miller>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%rdi
  jle    L150
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  cmp    $0x2,%rdi
  je     L47
  test   $0x1,%dil
  je     L141
  lea    -0x1(%rdi),%rbp
  je     L94
  mov    %rbp,%r13
L185:
  mov    %r13,%rax
  shr    $0x3f,%rax
  add    %r13,%rax
  sar    %rax
  mov    %rax,%r13
  test   $0x1,%al
  je     L185
L93:
  test   %r15,%r15
  jle    L180
  mov    $0x0,%r14d
  jmp    L65
L47:
  mov    $0x1,%ebp
  mov    $0x1,%r13d
  jmp    L93
L94:
  mov    %rbp,%r13
  jmp    L93
L176:
  mov    %r13,%rbx
L74:
  cmp    %rdi,%rbp
  je     L95
  test   $0x1,%bl
  je     L44
L95:
  add    $0x1,%r14
  cmp    %r14,%r15
  je     L163
L65:
  mov    $0x0,%eax
  call   <rand@plt>
  cqto
  idiv   %rbp
  lea    0x1(%rdx),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <mod@plt>
  mov    %rax,%rdi
  cmp    $0x1,%rax
  setne  %dl
  cmp    %rax,%rbp
  setne  %al
  test   %al,%dl
  je     L176
  cmp    %r13,%rbp
  je     L176
  mov    %r13,%rbx
L104:
  mov    %r12,%rdx
  mov    %rdi,%rsi
  call   <mul@plt>
  mov    %rax,%rdi
  add    %rbx,%rbx
  cmp    $0x1,%rax
  setne  %dl
  cmp    %rax,%rbp
  setne  %al
  test   %al,%dl
  je     L74
  cmp    %rbx,%rbp
  jne    L104
  jmp    L74
L163:
  mov    $0x1,%eax
L141:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L180:
  mov    $0x1,%eax
  jmp    L141
L44:
  mov    $0x0,%eax
  jmp    L141
L150:
  ret
```

assistant: ```c
int miller(long long p, long long it) {
  if (p < 2)
    return 0;
  if (p != 2 && p % 2 == 0)
    return 0;
  long long s, i, a, tt, md;
  s = p - 1;
  while (s % 2 == 0)
    s /= 2;
  for (i = 0; i < it; i++) {
    a = rand() % (p - 1) + 1;
    tt = s;
    md = mod(a, tt, p);
    while (tt != p - 1 && md != 1 && md != p - 1) {
      md = mul(md, md, p);
      tt *= 2;
    }
    if (md != p - 1 && tt % 2 == 0)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<miller>:
  endbr64
  cmp    $0x1,%rdi
  jle    L21
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cmp    $0x2,%rdi
  je     L163
  test   $0x1,%dil
  je     L159
  lea    -0x1(%rdi),%rbx
  je     L163
  mov    %rbx,%r12
  nopl   0x0(%rax,%rax,1)
L113:
  sar    %r12
  test   $0x1,%r12b
  je     L113
L70:
  xor    %r13d,%r13d
  test   %r14,%r14
  jle    L75
  nopl   0x0(%rax)
L168:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rsi
  cqto
  idiv   %rbx
  lea    0x1(%rdx),%rdi
  mov    %rbp,%rdx
  call   <mod@plt>
  mov    %rax,%rdi
  cmp    %rbx,%r12
  je     L36
  cmp    $0x1,%rax
  je     L36
  cmp    %rbx,%rax
  je     L66
  mov    %r12,%r15
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L173:
  cmp    $0x1,%rax
  je     L115
  cmp    %rbx,%rax
  je     L66
L7:
  mov    %rdi,%rsi
  mov    %rbp,%rdx
  add    %r15,%r15
  call   <mul@plt>
  mov    %rax,%rdi
  cmp    %rbx,%r15
  jne    L173
L115:
  cmp    %rbx,%rdi
  je     L66
  and    $0x1,%r15d
  je     L159
L66:
  add    $0x1,%r13
  cmp    %r13,%r14
  jne    L168
L75:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L159:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    %r12,%r15
  jmp    L115
L163:
  mov    %rbx,%r12
  jmp    L70
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int miller(long long p, long long it) {
  if (p < 2)
    return 0;
  if (p != 2 && p % 2 == 0)
    return 0;
  long long s, i, a, tt, md;
  s = p - 1;
  while (s % 2 == 0)
    s /= 2;
  for (i = 0; i < it; i++) {
    a = rand() % (p - 1) + 1;
    tt = s;
    md = mod(a, tt, p);
    while (tt != p - 1 && md != 1 && md != p - 1) {
      md = mul(md, md, p);
      tt *= 2;
    }
    if (md != p - 1 && tt % 2 == 0)
      return 0;
  }
  return 1;
}
```