ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  movslq %eax,%rdx
  imul   $0x14f8b589,%rdx,%rdx
  sar    $0x2d,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x186a0,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  mov    $0x3,%ebx
  lea    D0(%rip),%rbp
  jmp    L40
L47:
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  je     L34
L40:
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L47
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L47
L34:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: FAILED: File descriptor %d is open


assistant: ```c
main(int argc, char **argv) {
  int i;
  struct stat buf;
  usleep(time(NULL) % 100000);
  for (i = 3; i < 256; i++) {
    if (fstat(i, &buf))
      continue;
    printf("FAILED: File descriptor %d is open\n", i);
  }
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <time@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x14f8b589,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2d,%rdx
  sub    %ecx,%edx
  imul   $0x186a0,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L23
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L23:
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L1
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: FAILED: File descriptor %d is open


assistant: ```c
main(int argc, char **argv) {
  int i;
  struct stat buf;
  usleep(time(NULL) % 100000);
  for (i = 3; i < 256; i++) {
    if (fstat(i, &buf))
      continue;
    printf("FAILED: File descriptor %d is open\n", i);
  }
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <time@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x14f8b589,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2d,%rdx
  sub    %ecx,%edx
  imul   $0x186a0,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L1
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L1:
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L9
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: FAILED: File descriptor %d is open


assistant: ```c
main(int argc, char **argv) {
  int i;
  struct stat buf;
  usleep(time(NULL) % 100000);
  for (i = 3; i < 256; i++) {
    if (fstat(i, &buf))
      continue;
    printf("FAILED: File descriptor %d is open\n", i);
  }
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  js     L102
  mov    $0x0,%r14d
  lea    0x10(%rsp),%rbp
  lea    D27(%rip),%r13
  lea    D14(%rip),%r15
  jmp    L27
L132:
  sub    $0x71,%ecx
  cmp    $0x9,%cl
  ja     L96
  movzbl %cl,%ecx
  movslq 0x0(%r13,%rcx,4),%rax
  add    %r13,%rax
  notrack jmp *%rax
L165:
  add    $0x1,%r12d
L96:
  add    $0x1,%rbx
L200:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L190
  movzbl (%rbx,%rbp,1),%ecx
  cmp    $0x61,%cl
  je     L165
  cmp    $0x64,%cl
  je     L165
  cmp    $0x7a,%cl
  jg     L96
  cmp    $0x70,%cl
  jg     L132
  cmp    $0x20,%cl
  je     L165
  sub    $0x62,%ecx
  cmp    $0xe,%cl
  ja     L96
  mov    $0x1,%eax
  shl    %cl,%rax
  test   $0x2492,%eax
  jne    L169
  test   $0x1249,%eax
  jne    L29
  test   $0x4920,%eax
  jne    L165
  jmp    L96
L29:
  add    $0x2,%r12d
  jmp    L96
L169:
  add    $0x3,%r12d
  jmp    L96
  add    $0x4,%r12d
  jmp    L96
L190:
  test   %r14d,%r14d
  jne    L186
L16:
  add    $0x1,%r14d
  cmp    %r14d,0xc(%rsp)
  jl     L102
L27:
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L200
L186:
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L16
L102:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string

tool: D1: %d

tool: D14: Case #%d: %d


assistant: ```c
int main() {
  char str[102];
  int t, i, j, count;
  scanf("%d", &t);
  for (i = 0; i <= t; i++) {
    gets(str);
    j = 0;
    count = 0;
    while (j < strlen(str)) {
      if (str[j] == 'a' || str[j] == 'd' || str[j] == 'g' || str[j] == 'j' || str[j] == 'm' || str[j] == 'p' || str[j] == 't' || str[j] == 'w' || str[j] == ' ')
        count++;
      else if (str[j] == 'b' || str[j] == 'e' || str[j] == 'h' || str[j] == 'k' || str[j] == 'n' || str[j] == 'q' || str[j] == 'u' || str[j] == 'x')
        count += 2;
      else if (str[j] == 'c' || str[j] == 'f' || str[j] == 'i' || str[j] == 'l' || str[j] == 'o' || str[j] == 'r' || str[j] == 'v' || str[j] == 'y')
        count += 3;
      else if (str[j] == 's' || str[j] == 'z')
        count += 4;
      j++;
    }
    if (i != 0)
      printf("Case #%d: %d\n", i, count);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D2(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  js     L128
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r15
  lea    D15(%rip),%rbx
  mov    $0x1,%r13d
  cs nopw 0x0(%rax,%rax,1)
L102:
  mov    %r15,%rdi
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  call   <gets@plt>
  jmp    L100
L143:
  cmp    $0x7a,%cl
  jg     L5
  cmp    $0x70,%cl
  jg     L145
  cmp    $0x20,%cl
  je     L92
  sub    $0x62,%ecx
  cmp    $0xe,%cl
  ja     L5
  mov    %r13,%rax
  shl    %cl,%rax
  test   $0x2492,%eax
  jne    L18
  test   $0x1249,%eax
  je     L86
L3:
  add    $0x2,%r12d
  nop
L5:
  add    $0x1,%r14
L100:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jle    L196
  movzbl (%r15,%r14,1),%ecx
  cmp    $0x61,%cl
  je     L92
  cmp    $0x64,%cl
  jne    L143
L92:
  add    $0x1,%r12d
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L145:
  sub    $0x72,%ecx
  cmp    $0x8,%cl
  ja     L3
  movzbl %cl,%ecx
  movslq (%rbx,%rcx,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L18:
  add    $0x3,%r12d
  jmp    L5
  xchg   %ax,%ax
  add    $0x4,%r12d
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L86:
  test   $0x4920,%eax
  je     L5
  add    $0x1,%r12d
  jmp    L5
  nopl   (%rax)
L196:
  test   %ebp,%ebp
  jne    L7
L77:
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jge    L102
L128:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L111
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L7:
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L77
L111:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D2: %d

tool: D4: Case #%d: %d


assistant: ```c
int main() {
  char str[102];
  int t, i, j, count;
  scanf("%d", &t);
  for (i = 0; i <= t; i++) {
    gets(str);
    j = 0;
    count = 0;
    while (j < strlen(str)) {
      if (str[j] == 'a' || str[j] == 'd' || str[j] == 'g' || str[j] == 'j' || str[j] == 'm' || str[j] == 'p' || str[j] == 't' || str[j] == 'w' || str[j] == ' ')
        count++;
      else if (str[j] == 'b' || str[j] == 'e' || str[j] == 'h' || str[j] == 'k' || str[j] == 'n' || str[j] == 'q' || str[j] == 'u' || str[j] == 'x')
        count += 2;
      else if (str[j] == 'c' || str[j] == 'f' || str[j] == 'i' || str[j] == 'l' || str[j] == 'o' || str[j] == 'r' || str[j] == 'v' || str[j] == 'y')
        count += 3;
      else if (str[j] == 's' || str[j] == 'z')
        count += 4;
      j++;
    }
    if (i != 0)
      printf("Case #%d: %d\n", i, count);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  js     L2
  xor    %r13d,%r13d
  lea    0x10(%rsp),%r15
  mov    $0x1,%ebp
  lea    D4(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L194:
  mov    %r15,%rdi
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  call   <gets@plt>
  jmp    L117
L99:
  cmp    $0x7a,%cl
  jg     L180
  cmp    $0x70,%cl
  jg     L143
  cmp    $0x20,%cl
  je     L23
  sub    $0x62,%ecx
  cmp    $0xe,%cl
  ja     L180
  mov    %rbp,%rax
  shl    %cl,%rax
  test   $0x2492,%eax
  jne    L154
  test   $0x1249,%eax
  je     L213
L90:
  add    $0x2,%r12d
  nop
L180:
  add    $0x1,%r14
L117:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jle    L0
  movzbl (%r15,%r14,1),%ecx
  cmp    $0x61,%cl
  je     L23
  cmp    $0x64,%cl
  jne    L99
L23:
  add    $0x1,%r12d
  jmp    L180
  cs nopw 0x0(%rax,%rax,1)
L143:
  sub    $0x72,%ecx
  cmp    $0x8,%cl
  ja     L90
  movzbl %cl,%ecx
  movslq (%rbx,%rcx,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L154:
  add    $0x3,%r12d
  jmp    L180
  xchg   %ax,%ax
  add    $0x4,%r12d
  jmp    L180
  cs nopw 0x0(%rax,%rax,1)
L213:
  test   $0x4920,%eax
  je     L180
  add    $0x1,%r12d
  jmp    L180
  nopl   (%rax)
L0:
  test   %r13d,%r13d
  jne    L30
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L2
  mov    $0x1,%r13d
  jmp    L194
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %r13d,%esi
  mov    %r12d,%edx
  lea    D19(%rip),%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    0xc(%rsp),%r13d
  jle    L194
L2:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L216
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L216:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D9: %d

tool: D19: Case #%d: %d


assistant: ```c
int main() {
  char str[102];
  int t, i, j, count;
  scanf("%d", &t);
  for (i = 0; i <= t; i++) {
    gets(str);
    j = 0;
    count = 0;
    while (j < strlen(str)) {
      if (str[j] == 'a' || str[j] == 'd' || str[j] == 'g' || str[j] == 'j' || str[j] == 'm' || str[j] == 'p' || str[j] == 't' || str[j] == 'w' || str[j] == ' ')
        count++;
      else if (str[j] == 'b' || str[j] == 'e' || str[j] == 'h' || str[j] == 'k' || str[j] == 'n' || str[j] == 'q' || str[j] == 'u' || str[j] == 'x')
        count += 2;
      else if (str[j] == 'c' || str[j] == 'f' || str[j] == 'i' || str[j] == 'l' || str[j] == 'o' || str[j] == 'r' || str[j] == 'v' || str[j] == 'y')
        count += 3;
      else if (str[j] == 's' || str[j] == 'z')
        count += 4;
      j++;
    }
    if (i != 0)
      printf("Case #%d: %d\n", i, count);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rndstr_ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  lea    0x21(%rax),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L10:
  movzwl -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L4
  movzwl -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rndstr_ascii(unsigned short len) {
  char *ret = malloc(len);
  for (int i = 0; i < len; ++i)
    ret[i] = (rand() % (126 - 33 + 1) + 33);
  ret[len] = '\0';
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rndstr_ascii>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  movzwl %di,%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L2
  mov    %rax,%rbx
  movzwl %r12w,%ebp
  add    %rax,%rbp
L15:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%edx
  sub    %edx,%eax
  add    $0x21,%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L15
L2:
  movzwl %r12w,%r12d
  movb   $0x0,0x0(%r13,%r12,1)
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *rndstr_ascii(unsigned short len) {
  char *ret = malloc(len);
  for (int i = 0; i < len; ++i)
    ret[i] = (rand() % (126 - 33 + 1) + 33);
  ret[len] = '\0';
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rndstr_ascii>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  movzwl %di,%ebx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  je     L4
  movzwl %bp,%ebp
  mov    %rax,%r13
  lea    (%rax,%rbp,1),%rbx
  nopl   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  add    $0x1,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%edx
  sub    %edx,%eax
  add    $0x21,%eax
  mov    %al,-0x1(%r13)
  cmp    %rbx,%r13
  jne    L29
L1:
  movb   $0x0,(%r12,%rbp,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  movzwl %bp,%ebp
  jmp    L1
```

assistant: ```c
char *rndstr_ascii(unsigned short len) {
  char *ret = malloc(len);
  for (int i = 0; i < len; ++i)
    ret[i] = (rand() % (126 - 33 + 1) + 33);
  ret[len] = '\0';
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rndstr_ascii>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  movzwl %di,%ebx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  je     L9
  movzwl %bp,%ebp
  mov    %rax,%r13
  lea    (%rax,%rbp,1),%rbx
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  add    $0x1,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%edx
  sub    %edx,%eax
  add    $0x21,%eax
  mov    %al,-0x1(%r13)
  cmp    %rbx,%r13
  jne    L14
L20:
  movb   $0x0,(%r12,%rbp,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  movzwl %bp,%ebp
  jmp    L20
```

assistant: ```c
char *rndstr_ascii(unsigned short len) {
  char *ret = malloc(len);
  for (int i = 0; i < len; ++i)
    ret[i] = (rand() % (126 - 33 + 1) + 33);
  ret[len] = '\0';
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strleng>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L3:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strleng(const char *str) {
  int i = 0;
  while (*(str + i))
    i++;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strleng>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L22
  mov    $0x1,%eax
L3:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L3
L14:
  mov    %edx,%eax
  ret
L22:
  mov    $0x0,%edx
  jmp    L14
```

assistant: ```c
int strleng(const char *str) {
  int i = 0;
  while (*(str + i))
    i++;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strleng>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  mov    $0x1,%eax
  xchg   %ax,%ax
L10:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L10
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strleng(const char *str) {
  int i = 0;
  while (*(str + i))
    i++;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strleng>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  mov    $0x1,%eax
  xchg   %ax,%ax
L6:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strleng(const char *str) {
  int i = 0;
  while (*(str + i))
    i++;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_putstr_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L13:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_putstr_fd(char const *s, int fd) {
  int i;
  i = 0;
  while (s[i])
    write(fd, &s[i++], 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_putstr_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  cmpb   $0x0,(%rdi)
  je     L8
L13:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L13
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ft_putstr_fd(char const *s, int fd) {
  int i;
  i = 0;
  while (s[i])
    write(fd, &s[i++], 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putstr_fd>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rsi
  mov    $0x1,%edx
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <write@plt>
  cmpb   $0x0,(%rbx)
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void ft_putstr_fd(char const *s, int fd) {
  int i;
  i = 0;
  while (s[i])
    write(fd, &s[i++], 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_putstr_fd>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    %rbx,%rsi
  mov    $0x1,%edx
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <write@plt>
  cmpb   $0x0,(%rbx)
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void ft_putstr_fd(char const *s, int fd) {
  int i;
  i = 0;
  while (s[i])
    write(fd, &s[i++], 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<glob_errfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %rax,%rsi
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: %d %s: %s


assistant: ```c
int glob_errfunc(const char *epath, int errno) {
  printf("%d %s: %s\n", errno, strerror(errno), epath);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glob_errfunc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <strerror@plt>
  mov    %rax,%rdx
  mov    %rbp,%rcx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D7: %d %s: %s


assistant: ```c
int glob_errfunc(const char *epath, int errno) {
  printf("%d %s: %s\n", errno, strerror(errno), epath);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<glob_errfunc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <strerror@plt>
  mov    %r12,%rcx
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d %s: %s


assistant: ```c
int glob_errfunc(const char *epath, int errno) {
  printf("%d %s: %s\n", errno, strerror(errno), epath);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<glob_errfunc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <strerror@plt>
  mov    %r12,%rcx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: %d %s: %s


assistant: ```c
int glob_errfunc(const char *epath, int errno) {
  printf("%d %s: %s\n", errno, strerror(errno), epath);
  return 0;
}
```