ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<count>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L7
  mov    %edi,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  lea    0x4(%rsp),%r13
  lea    D14(%rip),%r12
  lea    D15(%rip),%r15
  jmp    L13
L27:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L36
L13:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L36
  mov    0x4(%rsp),%edi
  call   <is_sqr@plt>
  cmp    $0x1,%eax
  jne    L27
  mov    0x4(%rsp),%esi
  mov    %r15,%rdi
  call   <printf@plt>
  add    $0x1,%r14d
  jmp    L27
L7:
  mov    $0x0,%r14d
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    %r14d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
type_guessed: string
name: parse_data
arguments: tag: D15
type_guessed: string

tool: D14: %i

tool: D15: %i


assistant: ```c
int count(int n) {
  int count = 0;
  int number;
  for (int i = 0; i < n; i++) {
    if (scanf("%i", &number) == 1) {
      if (is_sqr(number) == 1) {
        printf("%i\n", number);
        count++;
      }
    } else {
      break;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<count>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L15
  mov    %edi,%ebp
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r13
  xor    %r14d,%r14d
  lea    D9(%rip),%r12
  lea    D13(%rip),%r15
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L14:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L40
L49:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L40
  mov    0x4(%rsp),%edi
  call   <is_sqr@plt>
  cmp    $0x1,%eax
  jne    L14
  mov    0x4(%rsp),%esi
  mov    %r15,%rdi
  add    $0x1,%ebx
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L49
  nopl   0x0(%rax)
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  xor    %r14d,%r14d
  jmp    L40
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string
name: extract_symbolic_data
arguments: label: D13
type: string

tool: D9: %i

tool: D13: %i


assistant: ```c
int count(int n) {
  int count = 0;
  int number;
  for (int i = 0; i < n; i++) {
    if (scanf("%i", &number) == 1) {
      if (is_sqr(number) == 1) {
        printf("%i\n", number);
        count++;
      }
    } else {
      break;
    }
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<count>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L8
  mov    %edi,%ebp
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r13
  xor    %r14d,%r14d
  lea    D7(%rip),%r12
  lea    D13(%rip),%r15
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L47:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L46
L33:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L46
  mov    0x4(%rsp),%edi
  call   <is_sqr@plt>
  cmp    $0x1,%eax
  jne    L47
  mov    0x4(%rsp),%esi
  mov    %r15,%rdi
  add    $0x1,%ebx
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L33
  nopl   0x0(%rax)
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  xor    %r14d,%r14d
  jmp    L46
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string

tool: D7: %i

tool: D13: %i


assistant: ```c
int count(int n) {
  int count = 0;
  int number;
  for (int i = 0; i < n; i++) {
    if (scanf("%i", &number) == 1) {
      if (is_sqr(number) == 1) {
        printf("%i\n", number);
        count++;
      }
    } else {
      break;
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RmatTmatMult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L37:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm2
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L38:
  cmpl   $0x2,-0x8(%rbp)
  jle    L21
  addl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x2,-0x4(%rbp)
  jle    L37
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void RmatTmatMult(float *NT, float (*R)[3l], float *T) {
  signed int i;
  signed int j = 0;
  while (j < 3) {
    NT[(signed long int)j] = (float)0.000000;
    i = 0;
    while (i < 3) {
      NT[(signed long int)j] = NT[(signed long int)j] + R[(signed long int)j][(signed long int)i] * T[(signed long int)i];
      i = i + 1;
    }
    j = j + 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RmatTmatMult>:
  endbr64
  mov    %rsi,%r8
  add    $0x24,%rsi
  jmp    L17
L38:
  add    $0x4,%rdi
  add    $0xc,%r8
  cmp    %rsi,%r8
  je     L28
L17:
  mov    %rdi,%rcx
  movl   $0x0,(%rdi)
  mov    %r8,%r9
  mov    $0x0,%eax
L8:
  movss  (%r9,%rax,1),%xmm0
  mulss  (%rdx,%rax,1),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L8
  jmp    L38
L28:
  ret
```

assistant: ```c
void RmatTmatMult(float *NT, float (*R)[3l], float *T) {
  signed int i;
  signed int j = 0;
  while (j < 3) {
    NT[(signed long int)j] = (float)0.000000;
    i = 0;
    while (i < 3) {
      NT[(signed long int)j] = NT[(signed long int)j] + R[(signed long int)j][(signed long int)i] * T[(signed long int)i];
      i = i + 1;
    }
    j = j + 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RmatTmatMult>:
  endbr64
  lea    0x24(%rsi),%rcx
L7:
  movl   $0x0,(%rdi)
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
L8:
  movss  (%rsi,%rax,1),%xmm0
  mulss  (%rdx,%rax,1),%xmm0
  add    $0x4,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  cmp    $0xc,%rax
  jne    L8
  add    $0xc,%rsi
  add    $0x4,%rdi
  cmp    %rcx,%rsi
  jne    L7
  ret
```

assistant: ```c
void RmatTmatMult(float *NT, float (*R)[3l], float *T) {
  signed int i;
  signed int j = 0;
  while (j < 3) {
    NT[(signed long int)j] = (float)0.000000;
    i = 0;
    while (i < 3) {
      NT[(signed long int)j] = NT[(signed long int)j] + R[(signed long int)j][(signed long int)i] * T[(signed long int)i];
      i = i + 1;
    }
    j = j + 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RmatTmatMult>:
  endbr64
  movl   $0x0,(%rdi)
  movss  (%rsi),%xmm1
  pxor   %xmm2,%xmm2
  mulss  (%rdx),%xmm1
  addss  %xmm2,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rsi),%xmm0
  mulss  0x4(%rdx),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  0x8(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  movl   $0x0,0x4(%rdi)
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0xc(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm2,%xmm1
  movss  %xmm1,0x4(%rdi)
  movss  0x10(%rsi),%xmm0
  mulss  0x4(%rdx),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x14(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  movl   $0x0,0x8(%rdi)
  addss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  movss  0x18(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  addss  %xmm2,%xmm1
  movss  %xmm1,0x8(%rdi)
  movss  0x1c(%rsi),%xmm0
  mulss  0x4(%rdx),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0x20(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rdi)
  ret
```

assistant: ```c
void RmatTmatMult(float *NT, float (*R)[3l], float *T) {
  signed int i;
  signed int j = 0;
  while (j < 3) {
    NT[(signed long int)j] = (float)0.000000;
    i = 0;
    while (i < 3) {
      NT[(signed long int)j] = NT[(signed long int)j] + R[(signed long int)j][(signed long int)i] * T[(signed long int)i];
      i = i + 1;
    }
    j = j + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strdupMemBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <allocMemBlock@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdupMemBlock(struct dumbtts_conf *conf, char *str) {
  char *dst = allocMemBlock(conf, strlen(str) + 1, 0);
  if (dst)
    strcpy(dst, str);
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strdupMemBlock>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <allocMemBlock@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strdupMemBlock(struct dumbtts_conf *conf, char *str) {
  char *dst = allocMemBlock(conf, strlen(str) + 1, 0);
  if (dst)
    strcpy(dst, str);
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strdupMemBlock>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  xor    %edx,%edx
  lea    0x1(%rax),%rsi
  call   <allocMemBlock@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdupMemBlock(struct dumbtts_conf *conf, char *str) {
  char *dst = allocMemBlock(conf, strlen(str) + 1, 0);
  if (dst)
    strcpy(dst, str);
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdupMemBlock>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  xor    %edx,%edx
  lea    0x1(%rax),%rsi
  call   <allocMemBlock@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdupMemBlock(struct dumbtts_conf *conf, char *str) {
  char *dst = allocMemBlock(conf, strlen(str) + 1, 0);
  if (dst)
    strcpy(dst, str);
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x38,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  cltq
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x30,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    $0x28,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x10,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    $0x20,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x18,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sar    $0x18,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x20,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sar    $0x10,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x28,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x30,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x38,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void write_uint64(void *dst, uint64_t data) {
  uint8_t *p = (uint8_t *)dst;
  p[0] = (uint8_t)((data >> 56) & 0xff);
  p[1] = (uint8_t)((data >> 48) & 0xff);
  p[2] = (uint8_t)((data >> 40) & 0xff);
  p[3] = (uint8_t)((data >> 32) & 0xff);
  p[4] = (uint8_t)((data >> 24) & 0xff);
  p[5] = (uint8_t)((data >> 16) & 0xff);
  p[6] = (uint8_t)((data >> 8) & 0xff);
  p[7] = (uint8_t)(data & 0xff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_uint64>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%eax
  mov    $0x38,%ecx
  sar    %cl,%esi
  movzbl %sil,%ecx
  mov    %rcx,(%rdi)
  mov    %eax,%edi
  mov    $0x30,%ecx
  sar    %cl,%edi
  movzbl %dil,%ecx
  mov    %rcx,0x8(%rdx)
  mov    %eax,%esi
  mov    $0x28,%ecx
  sar    %cl,%esi
  movzbl %sil,%ecx
  mov    %rcx,0x10(%rdx)
  mov    %eax,%edi
  mov    $0x20,%ecx
  sar    %cl,%edi
  movzbl %dil,%ecx
  mov    %rcx,0x18(%rdx)
  mov    %eax,%ecx
  shr    $0x18,%ecx
  movslq %ecx,%rcx
  mov    %rcx,0x20(%rdx)
  mov    %eax,%ecx
  sar    $0x10,%ecx
  movzbl %cl,%ecx
  mov    %rcx,0x28(%rdx)
  movzbl %ah,%ecx
  movslq %ecx,%rcx
  mov    %rcx,0x30(%rdx)
  movzbl %al,%eax
  mov    %rax,0x38(%rdx)
  ret
```

assistant: ```c
void write_uint64(void *dst, uint64_t data) {
  uint8_t *p = (uint8_t *)dst;
  p[0] = (uint8_t)((data >> 56) & 0xff);
  p[1] = (uint8_t)((data >> 48) & 0xff);
  p[2] = (uint8_t)((data >> 40) & 0xff);
  p[3] = (uint8_t)((data >> 32) & 0xff);
  p[4] = (uint8_t)((data >> 24) & 0xff);
  p[5] = (uint8_t)((data >> 16) & 0xff);
  p[6] = (uint8_t)((data >> 8) & 0xff);
  p[7] = (uint8_t)(data & 0xff);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write_uint64>:
  endbr64
  mov    $0x38,%ecx
  mov    %esi,%eax
  mov    %rdi,%rdx
  sar    %cl,%esi
  movzbl %sil,%ecx
  mov    %eax,%esi
  mov    %rcx,(%rdi)
  mov    %eax,%edi
  mov    $0x30,%ecx
  sar    %cl,%edi
  movzbl %dil,%ecx
  mov    %eax,%edi
  mov    %rcx,0x8(%rdx)
  mov    $0x28,%ecx
  sar    %cl,%esi
  movzbl %sil,%ecx
  mov    %rcx,0x10(%rdx)
  mov    $0x20,%ecx
  sar    %cl,%edi
  movzbl %dil,%ecx
  mov    %rcx,0x18(%rdx)
  mov    %eax,%ecx
  shr    $0x18,%ecx
  mov    %ecx,%esi
  mov    %eax,%ecx
  sar    $0x10,%ecx
  mov    %rsi,0x20(%rdx)
  movzbl %cl,%ecx
  mov    %rcx,0x28(%rdx)
  movzbl %ah,%ecx
  movzbl %al,%eax
  movslq %ecx,%rcx
  mov    %rax,0x38(%rdx)
  mov    %rcx,0x30(%rdx)
  ret
```

assistant: ```c
void write_uint64(void *dst, uint64_t data) {
  uint8_t *p = (uint8_t *)dst;
  p[0] = (uint8_t)((data >> 56) & 0xff);
  p[1] = (uint8_t)((data >> 48) & 0xff);
  p[2] = (uint8_t)((data >> 40) & 0xff);
  p[3] = (uint8_t)((data >> 32) & 0xff);
  p[4] = (uint8_t)((data >> 24) & 0xff);
  p[5] = (uint8_t)((data >> 16) & 0xff);
  p[6] = (uint8_t)((data >> 8) & 0xff);
  p[7] = (uint8_t)(data & 0xff);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write_uint64>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x38,%ecx
  mov    %esi,%edi
  mov    %esi,%eax
  sar    %cl,%edi
  mov    $0x30,%ecx
  sar    %cl,%esi
  movd   %edi,%xmm0
  mov    $0x28,%ecx
  mov    %eax,%edi
  sar    %cl,%edi
  movd   %esi,%xmm7
  mov    $0x20,%ecx
  mov    %eax,%esi
  sar    %cl,%esi
  movd   %edi,%xmm1
  punpckldq %xmm7,%xmm0
  mov    %eax,%ecx
  movd   %esi,%xmm3
  shr    $0x18,%ecx
  punpckldq %xmm3,%xmm1
  punpcklqdq %xmm1,%xmm0
  pand   D2(%rip),%xmm0
  pxor   %xmm1,%xmm1
  pcmpgtd %xmm0,%xmm1
  movdqa %xmm0,%xmm2
  punpckhdq %xmm1,%xmm0
  punpckldq %xmm1,%xmm2
  movups %xmm0,0x10(%rdx)
  movd   %ecx,%xmm0
  mov    %eax,%ecx
  sar    $0x10,%ecx
  movups %xmm2,(%rdx)
  movzbl %cl,%ecx
  movq   %rcx,%xmm5
  movzbl %ah,%ecx
  movzbl %al,%eax
  punpcklqdq %xmm5,%xmm0
  movslq %ecx,%rdi
  movq   %rax,%xmm6
  movups %xmm0,0x20(%rdx)
  movq   %rdi,%xmm0
  punpcklqdq %xmm6,%xmm0
  movups %xmm0,0x30(%rdx)
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: byte[16]

tool: {"D2": [0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00]}

assistant: ```c
void write_uint64(void *dst, uint64_t data) {
  uint8_t *p = (uint8_t *)dst;
  p[0] = (uint8_t)((data >> 56) & 0xff);
  p[1] = (uint8_t)((data >> 48) & 0xff);
  p[2] = (uint8_t)((data >> 40) & 0xff);
  p[3] = (uint8_t)((data >> 32) & 0xff);
  p[4] = (uint8_t)((data >> 24) & 0xff);
  p[5] = (uint8_t)((data >> 16) & 0xff);
  p[6] = (uint8_t)((data >> 8) & 0xff);
  p[7] = (uint8_t)(data & 0xff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<char2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x78,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void char2() {
  int ch;
  ch = L'x';
}
```
user: What is the c source code of the assembly code below:

```asm
<char2>:
  endbr64
  ret
```

assistant: ```c
void char2() {
  int ch;
  ch = L'x';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<char2>:
  endbr64
  ret
```

assistant: ```c
void char2() {
  int ch;
  ch = L'x';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <adainit@plt>
  mov    $0x0,%eax
  call   <greetings@plt>
  mov    %eax,-0xc(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L2
  mov    $0x0,%eax
  call   <standard_scaler@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L18
L2:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L7
  mov    $0x0,%eax
  call   <dobldobl_scaler@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L18
L7:
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jne    L18
  mov    $0x0,%eax
  call   <quaddobl_scaler@plt>
  mov    %eax,-0xc(%rbp)
L18:
  mov    $0x0,%eax
  call   <adafinal@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D42
type_guessed: string
name: parse_data
arguments: data_tag: D40
type_guessed: string
name: parse_data
arguments: data_tag: D28
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D50
type_guessed: string

tool: D42: 
MENU for the precision of the scalers :


tool: D40:   0. use standard double precision arithmetic; or


tool: D28:   1. use double double precision arithmetic; or


tool: D25:   2. use quad double precision arithmetic.


tool: D15: Type 1, 2, or 3 to make your choice : 

tool: D50: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int fail, choice;
  adainit();
  fail = greetings();
  printf("\nMENU for the precision of the scalers :\n");
  printf("  0. use standard double precision arithmetic; or\n");
  printf("  1. use double double precision arithmetic; or\n");
  printf("  2. use quad double precision arithmetic.\n");
  printf("Type 1, 2, or 3 to make your choice : ");
  scanf("%d", &choice);
  if (choice == 0)
    fail = standard_scaler();
  else if (choice == 1)
    fail = dobldobl_scaler();
  else if (choice == 2)
    fail = quaddobl_scaler();
  adafinal();
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <adainit@plt>
  mov    $0x0,%eax
  call   <greetings@plt>
  mov    %eax,%ebx
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D59(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L9
  cmp    $0x1,%eax
  je     L11
  cmp    $0x2,%eax
  je     L49
L40:
  mov    $0x0,%eax
  call   <adafinal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <standard_scaler@plt>
  mov    %eax,%ebx
  jmp    L40
L11:
  mov    $0x0,%eax
  call   <dobldobl_scaler@plt>
  mov    %eax,%ebx
  jmp    L40
L49:
  mov    $0x0,%eax
  call   <quaddobl_scaler@plt>
  mov    %eax,%ebx
  jmp    L40
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
datatype: string
name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string
name: retrieve_data
arguments: data_label: D59
datatype: string

tool: D16: 
MENU for the precision of the scalers :


tool: D1:   0. use standard double precision arithmetic; or


tool: D2:   1. use double double precision arithmetic; or


tool: D21:   2. use quad double precision arithmetic.


tool: D18: Type 1, 2, or 3 to make your choice : 

tool: D59: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int fail, choice;
  adainit();
  fail = greetings();
  printf("\nMENU for the precision of the scalers :\n");
  printf("  0. use standard double precision arithmetic; or\n");
  printf("  1. use double double precision arithmetic; or\n");
  printf("  2. use quad double precision arithmetic.\n");
  printf("Type 1, 2, or 3 to make your choice : ");
  scanf("%d", &choice);
  if (choice == 0)
    fail = standard_scaler();
  else if (choice == 1)
    fail = dobldobl_scaler();
  else if (choice == 2)
    fail = quaddobl_scaler();
  adafinal();
  return fail;
}
```