ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x1(%rax,%rax,2),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L145
L10:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L10
L145:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L73
L147:
  movzbl (%rbx),%eax
  mov    %rsp,%r8
  mov    %rsp,%rdx
  test   %al,%al
  je     L56
  movabs $0xffffb7de00000000,%rdi
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L81:
  cmp    $0x2e,%al
  jbe    L44
  test   %al,%al
  js     L123
L62:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  xchg   %ax,%ax
L9:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L56
L17:
  add    $0x1,%rbx
  cmp    $0x20,%al
  jne    L81
  movzbl (%rbx),%eax
  movb   $0x2b,(%rdx)
  add    $0x1,%rdx
  test   %al,%al
  jne    L17
L56:
  movb   $0x0,(%rdx)
  mov    %r8,%rdi
  call   <strdup@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L118
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopl   (%rax)
L44:
  bt     %rax,%rdi
  jb     L62
  movb   $0x25,(%rdx)
  mov    %eax,%ecx
  shr    $0x4,%cl
L143:
  add    $0x30,%ecx
L27:
  and    $0xf,%eax
  mov    %cl,0x1(%rdx)
  lea    0x30(%rax),%esi
  cmp    $0x9,%al
  lea    0x57(%rax),%ecx
  mov    %esi,%eax
  cmova  %ecx,%eax
  add    $0x3,%rdx
  mov    %al,-0x1(%rdx)
  jmp    L9
  nopl   (%rax)
L123:
  mov    %eax,%ecx
  movb   $0x25,(%rdx)
  shr    $0x4,%cl
  cmp    $0x9f,%al
  jbe    L143
  add    $0x57,%ecx
  jmp    L27
  nopl   0x0(%rax)
L73:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L147
L118:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *escape(const char *str) {
  char *esc_str;
  char esc_tmp[strlen(str) * 3 + 1];
  char *q;
  const unsigned char *p;
  p = (unsigned char *)str;
  q = esc_tmp;
  while (*p) {
    if (*p == ' ') {
      *q++ = '+';
      p++;
    } else if ((*p != '.') && (*p > ' ') && (*p != '+') && (*p != '%') && (*p < 128)) {
      *q++ = *p++;
    } else {
      *q++ = '%';
      *q++ = ((((*p >> 4) & 0x0f) < 10) ? ('0' + ((*p >> 4) & 0x0f)) : ('a' + ((*p >> 4) & 0x0f) - 10));
      *q++ = (((*p & 0x0f) < 10) ? ('0' + (*p & 0x0f)) : ('a' + (*p & 0x0f) - 10));
      p++;
    }
  }
  *q = 0;
  esc_str = strdup(esc_tmp);
  return esc_str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x1(%rax,%rax,2),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L112
L73:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L73
L112:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L60
L74:
  movzbl (%rbx),%eax
  mov    %rsp,%r8
  mov    %rsp,%rdx
  test   %al,%al
  je     L138
  movabs $0xffffb7de00000000,%rdi
  jmp    L122
  cs nopw 0x0(%rax,%rax,1)
L102:
  cmp    $0x2e,%al
  jbe    L25
  test   %al,%al
  js     L116
L66:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  xchg   %ax,%ax
L39:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L138
L122:
  add    $0x1,%rbx
  cmp    $0x20,%al
  jne    L102
  movzbl (%rbx),%eax
  movb   $0x2b,(%rdx)
  add    $0x1,%rdx
  test   %al,%al
  jne    L122
L138:
  movb   $0x0,(%rdx)
  mov    %r8,%rdi
  call   <strdup@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L98
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopl   (%rax)
L25:
  bt     %rax,%rdi
  jb     L66
  movb   $0x25,(%rdx)
  mov    %eax,%ecx
  shr    $0x4,%cl
L90:
  add    $0x30,%ecx
L131:
  and    $0xf,%eax
  mov    %cl,0x1(%rdx)
  lea    0x30(%rax),%esi
  cmp    $0x9,%al
  lea    0x57(%rax),%ecx
  mov    %esi,%eax
  cmova  %ecx,%eax
  add    $0x3,%rdx
  mov    %al,-0x1(%rdx)
  jmp    L39
  nopl   (%rax)
L116:
  mov    %eax,%ecx
  movb   $0x25,(%rdx)
  shr    $0x4,%cl
  cmp    $0x9f,%al
  jbe    L90
  add    $0x57,%ecx
  jmp    L131
  nopl   0x0(%rax)
L60:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L74
L98:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *escape(const char *str) {
  char *esc_str;
  char esc_tmp[strlen(str) * 3 + 1];
  char *q;
  const unsigned char *p;
  p = (unsigned char *)str;
  q = esc_tmp;
  while (*p) {
    if (*p == ' ') {
      *q++ = '+';
      p++;
    } else if ((*p != '.') && (*p > ' ') && (*p != '+') && (*p != '%') && (*p < 128)) {
      *q++ = *p++;
    } else {
      *q++ = '%';
      *q++ = ((((*p >> 4) & 0x0f) < 10) ? ('0' + ((*p >> 4) & 0x0f)) : ('a' + ((*p >> 4) & 0x0f) - 10));
      *q++ = (((*p & 0x0f) < 10) ? ('0' + (*p & 0x0f)) : ('a' + (*p & 0x0f) - 10));
      p++;
    }
  }
  *q = 0;
  esc_str = strdup(esc_tmp);
  return esc_str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<else_ifs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void else_ifs(int i) {
  if (i == 1) {
  } else if (i == 2) {
  } else if (i == 3) {
  } else if (i == 4) {
  } else if (i == 5) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<else_ifs>:
  endbr64
  ret
```

assistant: ```c
void else_ifs(int i) {
  if (i == 1) {
  } else if (i == 2) {
  } else if (i == 3) {
  } else if (i == 4) {
  } else if (i == 5) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<else_ifs>:
  endbr64
  ret
```

assistant: ```c
void else_ifs(int i) {
  if (i == 1) {
  } else if (i == 2) {
  } else if (i == 3) {
  } else if (i == 4) {
  } else if (i == 5) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<else_ifs>:
  endbr64
  ret
```

assistant: ```c
void else_ifs(int i) {
  if (i == 1) {
  } else if (i == 2) {
  } else if (i == 3) {
  } else if (i == 4) {
  } else if (i == 5) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  movl   $0x5,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  lea    -0x1(%rax),%edi
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x34(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x34(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <foo@plt>
  mov    $0x2,%edi
  call   <g@plt>
  mov    %eax,%r13d
  mov    $0x0,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,%r12d
  mov    $0x0,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <f@plt>
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  mov    $0x4,%edi
  call   <g@plt>
  lea    -0x7(%rax),%r14d
  mov    $0x3,%edi
  call   <g@plt>
  mov    %eax,%r13d
  mov    $0x0,%edi
  call   <g@plt>
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <g@plt>
  add    %eax,%ebx
  mov    $0x2,%edi
  call   <g@plt>
  lea    (%rbx,%rax,1),%r12d
  mov    $0x2,%edi
  call   <g@plt>
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <g@plt>
  add    %eax,%ebx
  mov    $0x2,%edi
  call   <g@plt>
  mov    %eax,%r15d
  mov    $0x0,%edi
  call   <g@plt>
  add    %r15d,%eax
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int x;
  foo(0, 1, 2, 3, 4);
  x = 5;
  foo(x + 0, x + 1, x + 2, x + x - 2, x * 2 - 1);
  foo(0, f(0), f(f(0)), f(f(f(0))), g(2));
  foo(g(2) + g(0), g(2) + g(1), g(0) + g(1) + g(2), g(3), g(4) - 7);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  mov    $0x9,%r8d
  mov    $0x8,%ecx
  mov    $0x7,%edx
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <foo@plt>
  mov    $0x2,%edi
  call   <g@plt>
  mov    %eax,%r12d
  mov    $0x0,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,%ebp
  mov    $0x0,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <f@plt>
  mov    %eax,%esi
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x0,%edi
  call   <foo@plt>
  mov    $0x4,%edi
  call   <g@plt>
  mov    %eax,%r14d
  mov    $0x3,%edi
  call   <g@plt>
  mov    %eax,%r13d
  mov    $0x0,%edi
  call   <g@plt>
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <g@plt>
  add    %eax,%ebx
  mov    $0x2,%edi
  call   <g@plt>
  add    %eax,%ebx
  mov    $0x2,%edi
  call   <g@plt>
  mov    %eax,%r12d
  mov    $0x1,%edi
  call   <g@plt>
  add    %eax,%r12d
  mov    $0x2,%edi
  call   <g@plt>
  mov    %eax,%ebp
  mov    $0x0,%edi
  call   <g@plt>
  lea    0x0(%rbp,%rax,1),%edi
  lea    -0x7(%r14),%r8d
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  call   <foo@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(void) {
  int x;
  foo(0, 1, 2, 3, 4);
  x = 5;
  foo(x + 0, x + 1, x + 2, x + x - 2, x * 2 - 1);
  foo(0, f(0), f(f(0)), f(f(f(0))), g(2));
  foo(g(2) + g(0), g(2) + g(1), g(0) + g(1) + g(2), g(3), g(4) - 7);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  xor    %edi,%edi
  push   %r13
  mov    $0x2,%edx
  mov    $0x1,%esi
  push   %r12
  push   %rbp
  push   %rbx
  call   <foo@plt>
  mov    $0x9,%r8d
  mov    $0x8,%ecx
  mov    $0x7,%edx
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <foo@plt>
  mov    $0x2,%edi
  call   <g@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  xor    %edi,%edi
  mov    %eax,%r13d
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <f@plt>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %eax,%esi
  xor    %edi,%edi
  call   <foo@plt>
  mov    $0x4,%edi
  call   <g@plt>
  mov    $0x3,%edi
  mov    %eax,%r14d
  call   <g@plt>
  xor    %edi,%edi
  mov    %eax,%r13d
  call   <g@plt>
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <g@plt>
  mov    $0x2,%edi
  add    %eax,%ebx
  call   <g@plt>
  mov    $0x2,%edi
  lea    (%rbx,%rax,1),%r12d
  call   <g@plt>
  mov    $0x1,%edi
  mov    %eax,%ebp
  call   <g@plt>
  mov    $0x2,%edi
  add    %eax,%ebp
  call   <g@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <g@plt>
  lea    -0x7(%r14),%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  lea    (%rbx,%rax,1),%edi
  mov    %ebp,%esi
  call   <foo@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(void) {
  int x;
  foo(0, 1, 2, 3, 4);
  x = 5;
  foo(x + 0, x + 1, x + 2, x + x - 2, x * 2 - 1);
  foo(0, f(0), f(f(0)), f(f(f(0))), g(2));
  foo(g(2) + g(0), g(2) + g(1), g(0) + g(1) + g(2), g(3), g(4) - 7);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  xor    %edi,%edi
  push   %r13
  mov    $0x2,%edx
  mov    $0x1,%esi
  push   %r12
  push   %rbp
  push   %rbx
  call   <foo@plt>
  mov    $0x9,%r8d
  mov    $0x8,%ecx
  mov    $0x7,%edx
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <foo@plt>
  mov    $0x2,%edi
  call   <g@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  xor    %edi,%edi
  mov    %eax,%r13d
  call   <f@plt>
  mov    %eax,%edi
  call   <f@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <f@plt>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %eax,%esi
  xor    %edi,%edi
  call   <foo@plt>
  mov    $0x4,%edi
  call   <g@plt>
  mov    $0x3,%edi
  mov    %eax,%r14d
  call   <g@plt>
  xor    %edi,%edi
  mov    %eax,%r13d
  call   <g@plt>
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <g@plt>
  mov    $0x2,%edi
  add    %eax,%ebx
  call   <g@plt>
  mov    $0x2,%edi
  lea    (%rbx,%rax,1),%r12d
  call   <g@plt>
  mov    $0x1,%edi
  mov    %eax,%ebp
  call   <g@plt>
  mov    $0x2,%edi
  add    %eax,%ebp
  call   <g@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <g@plt>
  lea    -0x7(%r14),%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  lea    (%rbx,%rax,1),%edi
  mov    %ebp,%esi
  call   <foo@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(void) {
  int x;
  foo(0, 1, 2, 3, 4);
  x = 5;
  foo(x + 0, x + 1, x + 2, x + x - 2, x * 2 - 1);
  foo(0, f(0), f(f(0)), f(f(f(0))), g(2));
  foo(g(2) + g(0), g(2) + g(1), g(0) + g(1) + g(2), g(3), g(4) - 7);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_pmu_active_default>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xc24a,%edx
  mov    $0x18,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xcab0,%edx
  mov    $0x16,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0x1090,%edx
  mov    $0x1a,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_pmu_active_default(void) {
  mbus_remote_register_write(0x8, 0x18, ((3 << 14) | (0 << 13) | (1 << 9) | (2 << 5) | (10)));
  delay(200);
  mbus_remote_register_write(0x8, 0x16, ((0 << 19) | (0 << 18) | (0 << 17) | (3 << 14) | (0 << 13) | (5 << 9) | (5 << 5) | (16)));
  delay(200);
  delay(200);
  mbus_remote_register_write(0x8, 0x1A, ((0 << 13) | (8 << 9) | (4 << 5) | (16)));
  delay(200);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_pmu_active_default>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc24a,%edx
  mov    $0x18,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xcab0,%edx
  mov    $0x16,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0x1090,%edx
  mov    $0x1a,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void set_pmu_active_default(void) {
  mbus_remote_register_write(0x8, 0x18, ((3 << 14) | (0 << 13) | (1 << 9) | (2 << 5) | (10)));
  delay(200);
  mbus_remote_register_write(0x8, 0x16, ((0 << 19) | (0 << 18) | (0 << 17) | (3 << 14) | (0 << 13) | (5 << 9) | (5 << 5) | (16)));
  delay(200);
  delay(200);
  mbus_remote_register_write(0x8, 0x1A, ((0 << 13) | (8 << 9) | (4 << 5) | (16)));
  delay(200);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_pmu_active_default>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc24a,%edx
  mov    $0x18,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xcab0,%edx
  mov    $0x16,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0x8,%edi
  mov    $0x1090,%edx
  mov    $0x1a,%esi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  add    $0x8,%rsp
  jmp    1070 <delay@plt>
```

assistant: ```c
void set_pmu_active_default(void) {
  mbus_remote_register_write(0x8, 0x18, ((3 << 14) | (0 << 13) | (1 << 9) | (2 << 5) | (10)));
  delay(200);
  mbus_remote_register_write(0x8, 0x16, ((0 << 19) | (0 << 18) | (0 << 17) | (3 << 14) | (0 << 13) | (5 << 9) | (5 << 5) | (16)));
  delay(200);
  delay(200);
  mbus_remote_register_write(0x8, 0x1A, ((0 << 13) | (8 << 9) | (4 << 5) | (16)));
  delay(200);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_pmu_active_default>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc24a,%edx
  mov    $0x18,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xcab0,%edx
  mov    $0x16,%esi
  mov    $0x8,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    $0x8,%edi
  mov    $0x1090,%edx
  mov    $0x1a,%esi
  call   <mbus_remote_register_write@plt>
  mov    $0xc8,%edi
  add    $0x8,%rsp
  jmp    1070 <delay@plt>
```

assistant: ```c
void set_pmu_active_default(void) {
  mbus_remote_register_write(0x8, 0x18, ((3 << 14) | (0 << 13) | (1 << 9) | (2 << 5) | (10)));
  delay(200);
  mbus_remote_register_write(0x8, 0x16, ((0 << 19) | (0 << 18) | (0 << 17) | (3 << 14) | (0 << 13) | (5 << 9) | (5 << 5) | (16)));
  delay(200);
  delay(200);
  mbus_remote_register_write(0x8, 0x1A, ((0 << 13) | (8 << 9) | (4 << 5) | (16)));
  delay(200);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <bl_itostr_test@plt>
  test   %rax,%rax
  je     L5
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: 
[SUITE ERR ] %d suite(s)


assistant: ```c
int main(void) {
  int failed = 0;
  if (bl_itostr_test() != 0) {
    ++failed;
  }
  printf("\n[SUITE ERR ] %d suite(s)\n", failed);
  return failed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <bl_itostr_test@plt>
  test   %rax,%rax
  setne  %bl
  movzbl %bl,%ebx
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string

tool: D4: 
[SUITE ERR ] %d suite(s)


assistant: ```c
int main(void) {
  int failed = 0;
  if (bl_itostr_test() != 0) {
    ++failed;
  }
  printf("\n[SUITE ERR ] %d suite(s)\n", failed);
  return failed;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <bl_itostr_test@plt>
  lea    D8(%rip),%rdi
  test   %rax,%rax
  setne  %r12b
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: 
[SUITE ERR ] %d suite(s)


assistant: ```c
int main(void) {
  int failed = 0;
  if (bl_itostr_test() != 0) {
    ++failed;
  }
  printf("\n[SUITE ERR ] %d suite(s)\n", failed);
  return failed;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <bl_itostr_test@plt>
  lea    D5(%rip),%rdi
  test   %rax,%rax
  setne  %r12b
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: 
[SUITE ERR ] %d suite(s)


assistant: ```c
int main(void) {
  int failed = 0;
  if (bl_itostr_test() != 0) {
    ++failed;
  }
  printf("\n[SUITE ERR ] %d suite(s)\n", failed);
  return failed;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<primitives_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D68
data_type: string
name: retrieve_data
arguments: tag: D59
data_type: string
name: retrieve_data
arguments: tag: D60
data_type: string
name: retrieve_data
arguments: tag: D67
data_type: string
name: retrieve_data
arguments: tag: D42
data_type: string
name: retrieve_data
arguments: tag: D51
data_type: string
name: retrieve_data
arguments: tag: D48
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D87
data_type: string
name: retrieve_data
arguments: tag: D63
data_type: string

tool: D68: PRIMITIVES SIZE 

tool: D59: type	size


tool: D60: ------------

tool: D67: char	%d


tool: D42: int	%d


tool: D51: short	%d


tool: D48: long	%d


tool: D18: float	%d


tool: D87: double	%d


tool: D63: ------------


assistant: ```c
void primitives_size() {
  printf("PRIMITIVES SIZE \n");
  printf("type	size\n", sizeof(char));
  printf("------------\n");
  printf("char	%d\n", sizeof(char));
  printf("int	%d\n", sizeof(int));
  printf("short	%d\n", sizeof(short));
  printf("long	%d\n", sizeof(long));
  printf("float	%d\n", sizeof(float));
  printf("double	%d\n", sizeof(double));
  printf("------------\n\n");
}
```