ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_num_and_caps_lights>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    %edi,%eax
  mov    %rsp,%rbp
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    %ecx,%ecx
  and    $0x2,%edi
  and    $0xd,%ecx
  add    $0x20,%ecx
  cmp    $0x1,%edi
  mov    %rbp,%rdi
  sbb    %edx,%edx
  and    $0xd,%edx
  add    $0x20,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: xset %cled 2 %cled 1

assistant: ```c
void set_num_and_caps_lights(int lights) {
  char command[32];
  sprintf(command, "xset %cled 2 %cled 1", (lights & 2) ? ' ' : '-', (lights & 1) ? ' ' : '-');
  system(command);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CreatePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L46
  addq   $0x2,-0x428(%rbp)
L46:
  mov    -0x428(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x418(%rbp)
  jmp    L47
L45:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x419(%rbp)
  cmpb   $0x2f,-0x419(%rbp)
  je     L53
  cmpb   $0x5c,-0x419(%rbp)
  jne    L55
L53:
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  mov    %eax,%edx
  mov    -0x428(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  movb   $0x0,-0x410(%rbp,%rax,1)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <Q_mkdir@plt>
L55:
  addq   $0x1,-0x418(%rbp)
L47:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmpb   $0x3a,0x1(%rdi)
  je     L43
L5:
  lea    0x1(%rbp),%rbx
  movzbl 0x1(%rbp),%eax
  test   %al,%al
  je     L4
  mov    %rsp,%r13
  jmp    L7
L43:
  add    $0x2,%rbp
  jmp    L5
L9:
  mov    %rbx,%r12
  sub    %rbp,%r12
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rsp,%r12,1)
  mov    %r13,%rdi
  call   <Q_mkdir@plt>
L88:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L4
L7:
  cmp    $0x2f,%al
  je     L9
  cmp    $0x5c,%al
  jne    L88
  jmp    L9
L4:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L81:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl 0x1(%rdi),%eax
  cmp    $0x3a,%al
  jne    L17
  movzbl 0x3(%rdi),%eax
  add    $0x2,%rbp
L17:
  lea    0x1(%rbp),%rbx
  mov    %rsp,%r13
  test   %al,%al
  jne    L44
  jmp    L67
  nopl   0x0(%rax)
L26:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L67
L44:
  cmp    $0x2f,%al
  je     L60
  cmp    $0x5c,%al
  jne    L26
L60:
  mov    %rbx,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    %rbp,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%r12,1)
  call   <Q_mkdir@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L44
L67:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl 0x1(%rdi),%eax
  cmp    $0x3a,%al
  jne    L14
  movzbl 0x3(%rdi),%eax
  add    $0x2,%rbp
L14:
  lea    0x1(%rbp),%rbx
  mov    %rsp,%r13
  test   %al,%al
  je     L54
  nopw   0x0(%rax,%rax,1)
L57:
  cmp    $0x2f,%al
  je     L36
  cmp    $0x5c,%al
  je     L36
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L57
L54:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L36:
  mov    %rbx,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    %rbp,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%r12,1)
  call   <Q_mkdir@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L57
  jmp    L54
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  D30(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D30(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L15:
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L15
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  je     L35
  jmp    L15
L35:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D43
type_guessed: string
name: disassemble_data
arguments: label: D40
type_guessed: string
name: disassemble_data
arguments: label: D30
type_guessed: f64
name: disassemble_data
arguments: label: D7
type_guessed: f64
name: disassemble_data
arguments: label: D37
type_guessed: string

tool: D43: input n:

tool: D40: %lf

tool: D30: 1

tool: D7: 2

tool: D37: output sqrt(n)=%lf


assistant: ```c
int main() {
  double n;
  printf("input n:");
  scanf("%lf", &n);
  double last_num = 1;
  double new_num = 1;
  do {
    last_num = new_num;
    new_num = (last_num + n / last_num) / 2.0;
  } while (last_num != new_num);
  printf("output sqrt(n)=%lf\n", new_num);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm4
  movsd  D13(%rip),%xmm0
  movsd  D2(%rip),%xmm3
L22:
  movapd %xmm4,%xmm1
  divsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  ucomisd %xmm0,%xmm2
  jp     L22
  jne    L22
  lea    D29(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D36
type: string
name: unpack_data
arguments: data_tag: D13
type: f64
name: unpack_data
arguments: data_tag: D2
type: byte[8]
name: unpack_data
arguments: data_tag: D29
type: string

tool: D22: input n:

tool: D36: %lf

tool: D13: 1

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D29: output sqrt(n)=%lf


assistant: ```c
int main() {
  double n;
  printf("input n:");
  scanf("%lf", &n);
  double last_num = 1;
  double new_num = 1;
  do {
    last_num = new_num;
    new_num = (last_num + n / last_num) / 2.0;
  } while (last_num != new_num);
  printf("output sqrt(n)=%lf\n", new_num);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D41(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm4
  movsd  D7(%rip),%xmm0
  movsd  D38(%rip),%xmm3
  nopl   0x0(%rax,%rax,1)
L20:
  movapd %xmm4,%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  ucomisd %xmm0,%xmm2
  jp     L20
  jne    L20
  lea    D27(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D41
datatype: string
name: disassemble_data
arguments: label: D34
datatype: string
name: disassemble_data
arguments: label: D7
datatype: f64
name: disassemble_data
arguments: label: D38
datatype: byte[8]
name: disassemble_data
arguments: label: D27
datatype: string

tool: D41: input n:

tool: D34: %lf

tool: D7: 1

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D27: output sqrt(n)=%lf


assistant: ```c
int main() {
  double n;
  printf("input n:");
  scanf("%lf", &n);
  double last_num = 1;
  double new_num = 1;
  do {
    last_num = new_num;
    new_num = (last_num + n / last_num) / 2.0;
  } while (last_num != new_num);
  printf("output sqrt(n)=%lf\n", new_num);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D49(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm4
  movsd  D45(%rip),%xmm0
  movsd  D40(%rip),%xmm3
  nopl   0x0(%rax,%rax,1)
L26:
  movapd %xmm4,%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  ucomisd %xmm0,%xmm2
  jp     L26
  jne    L26
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D49
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string
name: extract_symbolic_data
arguments: data_tag: D45
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D40
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D20
data_type: string

tool: D49: input n:

tool: D13: %lf

tool: D45: 1

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D20: output sqrt(n)=%lf


assistant: ```c
int main() {
  double n;
  printf("input n:");
  scanf("%lf", &n);
  double last_num = 1;
  double new_num = 1;
  do {
    last_num = new_num;
    new_num = (last_num + n / last_num) / 2.0;
  } while (last_num != new_num);
  printf("output sqrt(n)=%lf\n", new_num);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fitfun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L8:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  D0(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  D13(%rip),%xmm1
  movapd %xmm0,%xmm4
  subsd  %xmm1,%xmm4
  movq   %xmm4,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  addsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L8
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: f64
name: disassemble_data
arguments: tag: D13
type_guessed: f64

tool: D0: 100

tool: D13: 1

assistant: ```c
double fitfun(double *x, int N, void *output, int *info) {
  double f;
  int i;
  f = 0.0;
  for (i = 0; i < N - 1; i++)
    f = f + 100.0 * pow((x[i + 1] - x[i] * x[i]), 2) + pow((x[i] - 1.0), 2);
  return f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fitfun>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%esi
  jle    L16
  mov    %rdi,%rbx
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L10:
  movsd  (%rbx),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  0x8(%rbx),%xmm1
  subsd  %xmm0,%xmm1
  mov    $0x2,%edi
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mulsd  D19(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rbx),%xmm0
  subsd  D17(%rip),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  movapd %xmm0,%xmm3
  addsd  0x8(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L10
L27:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  pxor   %xmm6,%xmm6
  movsd  %xmm6,0x8(%rsp)
  jmp    L27
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_infered: f64
name: disassemble_data
arguments: tag: D17
type_infered: f64

tool: D19: 100

tool: D17: 1

assistant: ```c
double fitfun(double *x, int N, void *output, int *info) {
  double f;
  int i;
  f = 0.0;
  for (i = 0; i < N - 1; i++)
    f = f + 100.0 * pow((x[i + 1] - x[i] * x[i]), 2) + pow((x[i] - 1.0), 2);
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fitfun>:
  endbr64
  cmp    $0x1,%esi
  jle    L1
  push   %rbp
  lea    -0x2(%rsi),%eax
  pxor   %xmm1,%xmm1
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  movsd  (%rbx),%xmm0
  movsd  0x8(%rbx),%xmm2
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x2,%edi
  mulsd  D10(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  -0x8(%rbx),%xmm0
  subsd  D19(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L7
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D10
type: f64
name: read_data
arguments: label: D19
type: f64

tool: D10: 100

tool: D19: 1

assistant: ```c
double fitfun(double *x, int N, void *output, int *info) {
  double f;
  int i;
  f = 0.0;
  for (i = 0; i < N - 1; i++)
    f = f + 100.0 * pow((x[i + 1] - x[i] * x[i]), 2) + pow((x[i] - 1.0), 2);
  return f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fitfun>:
  endbr64
  cmp    $0x1,%esi
  jle    L12
  push   %rbp
  lea    -0x2(%rsi),%eax
  pxor   %xmm1,%xmm1
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  (%rbx),%xmm0
  movsd  0x8(%rbx),%xmm2
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x2,%edi
  mulsd  D5(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  -0x8(%rbx),%xmm0
  subsd  D7(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L11
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: f64
name: extract_symbolic_data
arguments: label: D7
datatype: f64

tool: D5: 100

tool: D7: 1

assistant: ```c
double fitfun(double *x, int N, void *output, int *info) {
  double f;
  int i;
  f = 0.0;
  for (i = 0; i < N - 1; i++)
    f = f + 100.0 * pow((x[i + 1] - x[i] * x[i]), 2) + pow((x[i] - 1.0), 2);
  return f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0xc(%rbp),%rdx
  lea    -0x11(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  movzbl -0x11(%rbp),%eax
  movsbl %al,%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <func@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5: %c%d%d

assistant: ```c
int main(void) {
  char ch;
  int row, col;
  scanf("%c%d%d", &ch, &col, &row);
  func(ch, col, row);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0xf(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%edi
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  call   <func@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: %c%d%d

assistant: ```c
int main(void) {
  char ch;
  int row, col;
  scanf("%c%d%d", &ch, &col, &row);
  func(ch, col, row);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  call   <scanf@plt>
  movsbl 0xf(%rsp),%edi
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  call   <func@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: %c%d%d

assistant: ```c
int main(void) {
  char ch;
  int row, col;
  scanf("%c%d%d", &ch, &col, &row);
  func(ch, col, row);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  call   <scanf@plt>
  movsbl 0xf(%rsp),%edi
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  call   <func@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: %c%d%d

assistant: ```c
int main(void) {
  char ch;
  int row, col;
  scanf("%c%d%d", &ch, &col, &row);
  func(ch, col, row);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gf8mul_01110101>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm5
  pxor   %xmm7,%xmm1
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm4
  pxor   %xmm6,%xmm3
  pxor   %xmm7,%xmm6
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm3
  pxor   %xmm5,%xmm2
  pxor   %xmm6,%xmm5
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm2
  pxor   %xmm4,%xmm1
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm4
  pxor   %xmm3,%xmm1
  pxor   %xmm3,%xmm0
  pxor   %xmm4,%xmm3
  pxor   %xmm2,%xmm7
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm2,%xmm3
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm6
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm3
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm5
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm2
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gf8mul_01110101(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm5\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm4\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm3\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm2\n"
                       "\tpxor    %xmm4, %xmm1\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm4\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm3, %xmm0\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm2, %xmm7\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm2, %xmm3\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm6\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm5\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm2\n");
}
```