ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<findDuplicate>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    %rdi,%r10
  lea    -0x1(%rsi),%r9d
  shr    $0x2,%eax
  push   %rbp
  mov    %esi,%edi
  mov    %r9d,%ebp
  sub    $0x1,%eax
  push   %rbx
  mov    %esi,%ebx
  mov    $0x1,%r8d
  shl    $0x4,%rax
  and    $0xfffffffc,%ebx
  pxor   %xmm3,%xmm3
  lea    0x10(%r10,%rax,1),%rcx
L57:
  movd   %r8d,%xmm7
  pshufd $0x0,%xmm7,%xmm5
  cmp    %r9d,%r8d
  jge    L33
  nopw   0x0(%rax,%rax,1)
L131:
  lea    (%r8,%r9,1),%edx
  sar    %edx
  test   %edi,%edi
  jle    L46
  cmp    $0x2,%ebp
  jbe    L108
  movd   %edx,%xmm7
  mov    %r10,%rax
  pxor   %xmm2,%xmm2
  pshufd $0x0,%xmm7,%xmm4
  nopw   0x0(%rax,%rax,1)
L67:
  movdqu (%rax),%xmm0
  movdqu (%rax),%xmm6
  movdqa %xmm5,%xmm1
  add    $0x10,%rax
  pcmpgtd %xmm4,%xmm0
  pcmpgtd %xmm6,%xmm1
  pcmpeqd %xmm3,%xmm0
  pcmpeqd %xmm3,%xmm1
  pand   %xmm1,%xmm0
  psubd  %xmm0,%xmm2
  cmp    %rax,%rcx
  jne    L67
  movdqa %xmm2,%xmm0
  mov    %ebx,%esi
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movd   %xmm2,%eax
  cmp    %ebx,%edi
  je     L64
L55:
  movslq %esi,%r11
  lea    0x0(,%r11,4),%r12
  mov    (%r10,%r11,4),%r11d
  cmp    %edx,%r11d
  jg     L71
  cmp    %r8d,%r11d
  setge  %r11b
  cmp    $0x1,%r11b
  sbb    $0xffffffff,%eax
L71:
  lea    0x1(%rsi),%r11d
  cmp    %edi,%r11d
  jge    L64
  mov    0x4(%r10,%r12,1),%r11d
  cmp    %r11d,%r8d
  jg     L2
  cmp    %r11d,%edx
  setge  %r11b
  cmp    $0x1,%r11b
  sbb    $0xffffffff,%eax
L2:
  add    $0x2,%esi
  cmp    %esi,%edi
  jle    L64
  mov    0x8(%r10,%r12,1),%esi
  cmp    %esi,%edx
  jl     L64
  cmp    %esi,%r8d
  setle  %sil
  cmp    $0x1,%sil
  sbb    $0xffffffff,%eax
L64:
  mov    %edx,%esi
  sub    %r8d,%esi
  add    $0x1,%esi
  cmp    %eax,%esi
  jge    L41
L30:
  mov    %edx,%r9d
  cmp    %r9d,%r8d
  jl     L131
L33:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %edx,%esi
  xor    %eax,%eax
  sub    %r8d,%esi
  add    $0x1,%esi
  cmp    %eax,%esi
  jl     L30
L41:
  lea    0x1(%rdx),%r8d
  jmp    L57
L108:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L55
```

assistant: ```c
int findDuplicate(int *nums, int size) {
  int l = 1, h = size - 1;
  while (l < h) {
    int m = (l + h) / 2;
    int count = 0;
    for (int i = 0; i < size; i++)
      if (nums[i] >= l && nums[i] <= m)
        count++;
    if (count <= m - l + 1)
      l = m + 1;
    else
      h = m;
  }
  return l;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: Oh no, a bug!


assistant: ```c
int main(int argc, char **argv) {
  int *foo = NULL;
  printf("Oh no, a bug!\n");
  return *foo;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: Oh no, a bug!


assistant: ```c
int main(int argc, char **argv) {
  int *foo = NULL;
  printf("Oh no, a bug!\n");
  return *foo;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x0,%eax
  ud2
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: Oh no, a bug!


assistant: ```c
int main(int argc, char **argv) {
  int *foo = NULL;
  printf("Oh no, a bug!\n");
  return *foo;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x0,%eax
  ud2
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: Oh no, a bug!


assistant: ```c
int main(int argc, char **argv) {
  int *foo = NULL;
  printf("Oh no, a bug!\n");
  return *foo;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <randomize@plt>
  mov    $0xa,%edi
  call   <random@plt>
  mov    %eax,-0x30(%rbp)
  movl   $0x1,-0x38(%rbp)
  jmp    L42
L21:
  mov    $0xa,%edi
  call   <random@plt>
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x30(%rbp,%rdx,4)
  movl   $0x0,-0x34(%rbp)
  jmp    L66
L11:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L86
  subl   $0x1,-0x38(%rbp)
  jmp    L80
L86:
  addl   $0x1,-0x34(%rbp)
L66:
  mov    -0x34(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L11
L80:
  addl   $0x1,-0x38(%rbp)
L42:
  cmpl   $0x9,-0x38(%rbp)
  jle    L21
  movl   $0x0,-0x38(%rbp)
  jmp    L43
L29:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L43:
  cmpl   $0x9,-0x38(%rbp)
  jle    L29
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string

tool: D7: %3d

assistant: ```c
void main() {
  int n, a[10], i, j;
  randomize();
  a[0] = random(10);
  for (i = 1; i < 10; i++) {
    a[i] = random(10);
    for (j = 0; j < i; j++)
      if (a[i] == a[j]) {
        i--;
        break;
      }
  }
  for (i = 0; i < 10; i++)
    printf("%3d", a[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <randomize@plt>
  mov    $0xa,%edi
  call   <random@plt>
  mov    %eax,(%rsp)
  mov    $0x1,%ebx
  lea    0x4(%rsp),%rbp
  jmp    L37
L19:
  sub    $0x1,%ebx
L30:
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jg     L45
L37:
  mov    $0xa,%edi
  call   <random@plt>
  movslq %ebx,%rdx
  mov    %eax,(%rsp,%rdx,4)
  test   %ebx,%ebx
  jle    L30
  mov    %rsp,%rdx
  lea    -0x1(%rbx),%ecx
  lea    0x0(%rbp,%rcx,4),%rcx
L67:
  cmp    (%rdx),%eax
  je     L19
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L67
  jmp    L30
L45:
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  lea    D5(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L14
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D5: %3d

assistant: ```c
void main() {
  int n, a[10], i, j;
  randomize();
  a[0] = random(10);
  for (i = 1; i < 10; i++) {
    a[i] = random(10);
    for (j = 0; j < i; j++)
      if (a[i] == a[j]) {
        i--;
        break;
      }
  }
  for (i = 0; i < 10; i++)
    printf("%3d", a[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <randomize@plt>
  mov    $0xa,%edi
  call   <random@plt>
  mov    %eax,%r12d
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0xa,%edi
  mov    %r13,%rbx
  call   <random@plt>
  movslq %ebp,%rdx
  mov    %r12d,%ecx
  mov    %eax,(%rsp,%rdx,4)
  lea    -0x1(%rbp),%edx
  lea    0x0(%r13,%rdx,4),%rsi
  mov    %r13,%rdx
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rdx),%ecx
  add    $0x4,%rdx
L21:
  cmp    %ecx,%eax
  je     L50
  cmp    %rsi,%rdx
  jne    L5
  add    $0x1,%ebp
L50:
  cmp    $0xa,%ebp
  jne    L26
  mov    %rsp,%rbp
  lea    D4(%rip),%r13
  add    $0x28,%rbp
  jmp    L40
  nop
L68:
  mov    (%rbx),%r12d
  add    $0x4,%rbx
L40:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L68
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: %3d

assistant: ```c
void main() {
  int n, a[10], i, j;
  randomize();
  a[0] = random(10);
  for (i = 1; i < 10; i++) {
    a[i] = random(10);
    for (j = 0; j < i; j++)
      if (a[i] == a[j]) {
        i--;
        break;
      }
  }
  for (i = 0; i < 10; i++)
    printf("%3d", a[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <randomize@plt>
  mov    $0xa,%edi
  call   <random@plt>
  mov    %eax,(%rsp)
  mov    %eax,%ebp
  nopl   (%rax)
L68:
  mov    $0xa,%edi
  call   <random@plt>
  movslq %ebx,%rdx
  mov    %eax,(%rsp,%rdx,4)
  cmp    %eax,%ebp
  je     L133
  cmp    $0x1,%ebx
  je     L135
  cmp    0x4(%rsp),%eax
  je     L133
  cmp    $0x2,%ebx
  je     L135
  cmp    0x8(%rsp),%eax
  je     L133
  cmp    $0x3,%ebx
  je     L135
  cmp    0xc(%rsp),%eax
  je     L133
  cmp    $0x4,%ebx
  je     L135
  cmp    0x10(%rsp),%eax
  je     L133
  cmp    $0x5,%ebx
  je     L135
  cmp    0x14(%rsp),%eax
  je     L133
  cmp    $0x6,%ebx
  je     L135
  cmp    0x18(%rsp),%eax
  je     L133
  cmp    $0x7,%ebx
  je     L135
  cmp    0x1c(%rsp),%eax
  je     L133
  cmp    $0x8,%ebx
  je     L135
  cmp    0x20(%rsp),%eax
  je     L133
  cmp    $0x9,%ebx
  je     L135
  cmp    0x24(%rsp),%eax
  je     L133
L135:
  add    $0x1,%ebx
L133:
  cmp    $0xa,%ebx
  jne    L68
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  lea    D4(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L85:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L85
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L203
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L203:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %3d

assistant: ```c
void main() {
  int n, a[10], i, j;
  randomize();
  a[0] = random(10);
  for (i = 1; i < 10; i++) {
    a[i] = random(10);
    for (j = 0; j < i; j++)
      if (a[i] == a[j]) {
        i--;
        break;
      }
  }
  for (i = 0; i < 10; i++)
    printf("%3d", a[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<STC31xx_SaveBackupSocToRam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <STC3115_UpdateRamCRC@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <STC3115_WriteDataToRam@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int STC31xx_SaveBackupSocToRam(unsigned char *p_RamData) {
  int status;
  STC3115_UpdateRamCRC();
  status = STC3115_WriteDataToRam(p_RamData);
  return status;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<STC31xx_SaveBackupSocToRam>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <STC3115_UpdateRamCRC@plt>
  mov    %rbx,%rdi
  call   <STC3115_WriteDataToRam@plt>
  pop    %rbx
  ret
```

assistant: ```c
int STC31xx_SaveBackupSocToRam(unsigned char *p_RamData) {
  int status;
  STC3115_UpdateRamCRC();
  status = STC3115_WriteDataToRam(p_RamData);
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<STC31xx_SaveBackupSocToRam>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <STC3115_UpdateRamCRC@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <STC3115_WriteDataToRam@plt>
```

assistant: ```c
int STC31xx_SaveBackupSocToRam(unsigned char *p_RamData) {
  int status;
  STC3115_UpdateRamCRC();
  status = STC3115_WriteDataToRam(p_RamData);
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<STC31xx_SaveBackupSocToRam>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <STC3115_UpdateRamCRC@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <STC3115_WriteDataToRam@plt>
```

assistant: ```c
int STC31xx_SaveBackupSocToRam(unsigned char *p_RamData) {
  int status;
  STC3115_UpdateRamCRC();
  status = STC3115_WriteDataToRam(p_RamData);
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<elev_get_floor_sensor_signal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x204,%edi
  call   <io_read_bit@plt>
  test   %rax,%rax
  je     L30
  mov    $0x0,%eax
  jmp    L73
L30:
  mov    $0x205,%edi
  call   <io_read_bit@plt>
  test   %rax,%rax
  je     L61
  mov    $0x1,%eax
  jmp    L73
L61:
  mov    $0x206,%edi
  call   <io_read_bit@plt>
  test   %rax,%rax
  je     L53
  mov    $0x2,%eax
  jmp    L73
L53:
  mov    $0x207,%edi
  call   <io_read_bit@plt>
  test   %rax,%rax
  je     L27
  mov    $0x3,%eax
  jmp    L73
L27:
  mov    $0xffffffff,%eax
L73:
  pop    %rbp
  ret
```

assistant: ```c
int elev_get_floor_sensor_signal(void) {
  if (io_read_bit((0x200 + 4)))
    return 0;
  else if (io_read_bit((0x200 + 5)))
    return 1;
  else if (io_read_bit((0x200 + 6)))
    return 2;
  else if (io_read_bit((0x200 + 7)))
    return 3;
  else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<elev_get_floor_sensor_signal>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x204,%edi
  call   <io_read_bit@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L3
L2:
  add    $0x8,%rsp
  ret
L3:
  mov    $0x205,%edi
  call   <io_read_bit@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L2
  mov    $0x206,%edi
  call   <io_read_bit@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  jne    L2
  mov    $0x207,%edi
  call   <io_read_bit@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  or     $0x3,%eax
  jmp    L2
```

assistant: ```c
int elev_get_floor_sensor_signal(void) {
  if (io_read_bit((0x200 + 4)))
    return 0;
  else if (io_read_bit((0x200 + 5)))
    return 1;
  else if (io_read_bit((0x200 + 6)))
    return 2;
  else if (io_read_bit((0x200 + 7)))
    return 3;
  else
    return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<elev_get_floor_sensor_signal>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x204,%edi
  call   <io_read_bit@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L22
L27:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L22:
  mov    $0x205,%edi
  call   <io_read_bit@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L27
  mov    $0x206,%edi
  call   <io_read_bit@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  jne    L27
  mov    $0x207,%edi
  call   <io_read_bit@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  or     $0x3,%eax
  ret
```

assistant: ```c
int elev_get_floor_sensor_signal(void) {
  if (io_read_bit((0x200 + 4)))
    return 0;
  else if (io_read_bit((0x200 + 5)))
    return 1;
  else if (io_read_bit((0x200 + 6)))
    return 2;
  else if (io_read_bit((0x200 + 7)))
    return 3;
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<elev_get_floor_sensor_signal>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x204,%edi
  call   <io_read_bit@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L0
L14:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x205,%edi
  call   <io_read_bit@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L14
  mov    $0x206,%edi
  call   <io_read_bit@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  jne    L14
  mov    $0x207,%edi
  call   <io_read_bit@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  or     $0x3,%eax
  ret
```

assistant: ```c
int elev_get_floor_sensor_signal(void) {
  if (io_read_bit((0x200 + 4)))
    return 0;
  else if (io_read_bit((0x200 + 5)))
    return 1;
  else if (io_read_bit((0x200 + 6)))
    return 2;
  else if (io_read_bit((0x200 + 7)))
    return 3;
  else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_proxy_cmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rcx
  lea    D8(%rip),%rax
  mov    %rax,%rdx
  mov    $0x49,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_my_log@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L35
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L35:
  movl   $0x0,-0x8(%rbp)
  jmp    L49
L42:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L46
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L42
  jmp    L12
L46:
  nop
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L21
  lea    D15(%rip),%rax
  mov    %rax,%rdx
  mov    $0x5d,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_my_log@plt>
  mov    -0x18(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L2
L21:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L2:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D15
type_infered: string

tool: D8: do_proxy_cmd: %s


tool: D21: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/zhongliangkang/twemproxy41/refs/heads/master/transfer/transfer.c

tool: D15: ERROR: too much data recved.

assistant: ```c
int do_proxy_cmd(int sock, char *cmd, char *buf, int buflen) {
  int n;
  int n_recved;
  do {
    _my_log("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/zhongliangkang/twemproxy41/refs/heads/master/transfer/transfer.c", 73, "do_proxy_cmd: %s\n", cmd);
  } while (0);
  n = send(sock, cmd, strlen(cmd), 0);
  if (n < 0) {
  } else if (n == (int)strlen(cmd)) {
  } else {
  }
  n_recved = 0;
  while (n_recved < buflen) {
    n = recv(sock, buf + n_recved, buflen, 0);
    if (n <= 0) {
      break;
    }
    n_recved += n;
  }
  if (n_recved >= buflen) {
    do {
      _my_log("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/zhongliangkang/twemproxy41/refs/heads/master/transfer/transfer.c", 93, "ERROR: too much data recved.");
    } while (0);
    buf[buflen - 1] = '\0';
  } else {
    buf[n_recved] = '\0';
  }
  return n_recved;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_proxy_cmd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %rsi,%rbx
  mov    %rdx,%r14
  mov    %ecx,%r12d
  mov    %rsi,%rcx
  lea    D34(%rip),%rdx
  mov    $0x49,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <_my_log@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <send@plt>
  test   %r12d,%r12d
  jle    L56
  mov    $0x0,%ebx
L4:
  movslq %ebx,%rbp
  add    %r14,%rbp
  mov    $0x0,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  test   %eax,%eax
  jle    L44
  add    %eax,%ebx
  cmp    %ebx,%r12d
  jg     L4
L21:
  lea    D33(%rip),%rdx
  mov    $0x5d,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <_my_log@plt>
  movslq %r12d,%r12
  movb   $0x0,-0x1(%r14,%r12,1)
  jmp    L41
L44:
  cmp    %ebx,%r12d
  jle    L21
  movb   $0x0,0x0(%rbp)
L41:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  mov    $0x0,%ebx
  jmp    L21
```

tool_calls: name: parse_data
arguments: data_label: D34
type_infered: string
name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D33
type_infered: string

tool: D34: do_proxy_cmd: %s


tool: D15: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/zhongliangkang/twemproxy41/refs/heads/master/transfer/transfer.c

tool: D33: ERROR: too much data recved.

assistant: ```c
int do_proxy_cmd(int sock, char *cmd, char *buf, int buflen) {
  int n;
  int n_recved;
  do {
    _my_log("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/zhongliangkang/twemproxy41/refs/heads/master/transfer/transfer.c", 73, "do_proxy_cmd: %s\n", cmd);
  } while (0);
  n = send(sock, cmd, strlen(cmd), 0);
  if (n < 0) {
  } else if (n == (int)strlen(cmd)) {
  } else {
  }
  n_recved = 0;
  while (n_recved < buflen) {
    n = recv(sock, buf + n_recved, buflen, 0);
    if (n <= 0) {
      break;
    }
    n_recved += n;
  }
  if (n_recved >= buflen) {
    do {
      _my_log("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/zhongliangkang/twemproxy41/refs/heads/master/transfer/transfer.c", 93, "ERROR: too much data recved.");
    } while (0);
    buf[buflen - 1] = '\0';
  } else {
    buf[n_recved] = '\0';
  }
  return n_recved;
}
```