ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %edx,%edi
  test   %edx,%edx
  jle    L88
  movslq %edx,%rax
  lea    -0x1(%rdx),%r9d
  shl    $0x2,%rax
  lea    (%rsi,%rax,1),%rdx
  lea    (%r8,%rax,1),%rsi
  cmp    %r8,%rdx
  setbe  %dl
  cmp    %rsi,%rcx
  setae  %sil
  or     %sil,%dl
  je     L29
  cmp    $0x2,%r9d
  jbe    L29
  mov    %edi,%r10d
  lea    -0x10(%r8,%rax,1),%rsi
  mov    %rcx,%rdx
  shr    $0x2,%r10d
  lea    -0x10(%rsi),%rax
  lea    -0x1(%r10),%r11d
  mov    %rax,%r10
  shl    $0x4,%r11
  sub    %r11,%r10
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L32:
  sub    $0x10,%rax
L25:
  movdqu (%rsi),%xmm0
  add    $0x10,%rdx
  mov    %rax,%rsi
  pshufd $0x1b,%xmm0,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %r10,%rax
  jne    L32
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dil
  je     L88
  mov    %r9d,%edx
  mov    %eax,%esi
  sub    %eax,%edx
  lea    0x0(,%rsi,4),%r10
  movslq %edx,%rdx
  mov    (%r8,%rdx,4),%edx
  mov    %edx,(%rcx,%rsi,4)
  lea    0x1(%rax),%esi
  cmp    %esi,%edi
  jle    L88
  mov    %r9d,%edx
  add    $0x2,%eax
  sub    %esi,%edx
  movslq %edx,%rdx
  mov    (%r8,%rdx,4),%edx
  mov    %edx,0x4(%rcx,%r10,1)
  cmp    %eax,%edi
  jle    L88
  sub    %eax,%r9d
  movslq %r9d,%r9
  mov    (%r8,%r9,4),%eax
  mov    %eax,0x8(%rcx,%r10,1)
  ret
L29:
  lea    -0x4(%r8,%rax,1),%rdx
  lea    0x4(%rcx,%r9,4),%rsi
  mov    %rcx,%rax
  nopl   (%rax)
L43:
  mov    (%rdx),%ecx
  add    $0x4,%rax
  sub    $0x4,%rdx
  mov    %ecx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L43
L88:
  ret
```

assistant: ```c
void reverse(const int x[], int y[], int n) {
  int i;
  for (i = 0; i < n; i++)
    y[i] = x[(n - 1) - i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x3,%esi
  mov    $0x9,%edi
  call   <W@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string

tool: D9: %d


assistant: ```c
int main(int argc, char *argv[]) {
  init();
  printf("%d\n", W(9, 3));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x3,%esi
  mov    $0x9,%edi
  call   <W@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main(int argc, char *argv[]) {
  init();
  printf("%d\n", W(9, 3));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  mov    $0x3,%esi
  mov    $0x9,%edi
  call   <W@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %d


assistant: ```c
int main(int argc, char *argv[]) {
  init();
  printf("%d\n", W(9, 3));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  mov    $0x3,%esi
  mov    $0x9,%edi
  call   <W@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int main(int argc, char *argv[]) {
  init();
  printf("%d\n", W(9, 3));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nulls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movl   $0x40,-0x4(%rbp)
  jmp    L1
L18:
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  je     L9
  mov    $0x0,%eax
  jmp    L26
L9:
  subl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x0,-0x4(%rbp)
  jg     L18
  mov    $0x1,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int nulls(char *buffer, int bufsize) {
  int i;
  char c = buffer[bufsize - 1];
  for (i = 16 * 4; i > 0; i--)
    if (buffer[bufsize - i] != c)
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nulls>:
  endbr64
  movslq %esi,%rsi
  movzbl -0x1(%rdi,%rsi,1),%edx
  lea    -0x40(%rdi,%rsi,1),%rax
  add    %rsi,%rdi
L0:
  cmp    %dl,(%rax)
  jne    L4
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L0
  mov    $0x1,%eax
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int nulls(char *buffer, int bufsize) {
  int i;
  char c = buffer[bufsize - 1];
  for (i = 16 * 4; i > 0; i--)
    if (buffer[bufsize - i] != c)
      return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nulls>:
  endbr64
  movslq %esi,%rsi
  movzbl -0x1(%rdi,%rsi,1),%edx
  lea    -0x40(%rdi,%rsi,1),%rax
  add    %rsi,%rdi
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L21:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L11
L0:
  cmp    %dl,(%rax)
  je     L21
  xor    %eax,%eax
  ret
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int nulls(char *buffer, int bufsize) {
  int i;
  char c = buffer[bufsize - 1];
  for (i = 16 * 4; i > 0; i--)
    if (buffer[bufsize - i] != c)
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nulls>:
  endbr64
  movslq %esi,%rsi
  movzbl -0x1(%rdi,%rsi,1),%edx
  lea    -0x40(%rdi,%rsi,1),%rax
  add    %rsi,%rdi
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L14
L1:
  cmp    %dl,(%rax)
  je     L0
  xor    %eax,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int nulls(char *buffer, int bufsize) {
  int i;
  char c = buffer[bufsize - 1];
  for (i = 16 * 4; i > 0; i--)
    if (buffer[bufsize - i] != c)
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L3:
  mov    $0x61a80,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  addq   $0x4,-0x8(%rbp)
  jmp    L3
```

assistant: ```c
int main() {
  while (1) {
    int *i = (int *)malloc(sizeof(int) * 100000);
    i++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L4:
  mov    $0x61a80,%edi
  call   <malloc@plt>
  jmp    L4
```

assistant: ```c
int main() {
  while (1) {
    int *i = (int *)malloc(sizeof(int) * 100000);
    i++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x61a80,%edi
  call   <malloc@plt>
  jmp    L3
```

assistant: ```c
int main() {
  while (1) {
    int *i = (int *)malloc(sizeof(int) * 100000);
    i++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x61a80,%edi
  call   <malloc@plt>
  jmp    L2
```

assistant: ```c
int main() {
  while (1) {
    int *i = (int *)malloc(sizeof(int) * 100000);
    i++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x40(%rbp)
  movl   $0x1e,-0x3c(%rbp)
  movl   $0x3c,-0x38(%rbp)
  movl   $0x64,-0x34(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0x50,-0x20(%rbp)
  movl   $0x28,-0x1c(%rbp)
  movl   $0x37,-0x18(%rbp)
  movl   $0x16,-0x14(%rbp)
  movl   $0x63,-0x10(%rbp)
  movl   $0xd,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <mergeSort@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L27
L10:
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4c(%rbp)
L27:
  mov    -0x4c(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L10
  movl   $0x7,-0x44(%rbp)
  mov    -0x48(%rbp),%eax
  sub    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D24
datatype: string

tool: D1: Sorted Array

tool: D25: %d 

tool: D24: 
 The element with rank %d is %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {10, 30, 60, 100, 1, 2, 7, 9, 80, 40, 55, 22, 99};
  int size = sizeof(a) / sizeof(a[0]);
  mergeSort(a, 0, size - 1);
  printf("Sorted Array\n");
  for (int i = 0; i < size; i++)
    printf("%d ", a[i]);
  int r = 7;
  printf("\n The element with rank %d is %d", r, a[size - r]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0xa,(%rsp)
  movl   $0x1e,0x4(%rsp)
  movl   $0x3c,0x8(%rsp)
  movl   $0x64,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x9,0x1c(%rsp)
  movl   $0x50,0x20(%rsp)
  movl   $0x28,0x24(%rsp)
  movl   $0x37,0x28(%rsp)
  movl   $0x16,0x2c(%rsp)
  movl   $0x63,0x30(%rsp)
  mov    %rsp,%rbx
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <mergeSort@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    0x34(%rsp),%r12
  lea    D14(%rip),%rbp
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L10
  mov    0x18(%rsp),%edx
  mov    $0x7,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
type_infered: string
name: retrieve_data
arguments: tag: D14
type_infered: string
name: retrieve_data
arguments: tag: D26
type_infered: string

tool: D20: Sorted Array

tool: D14: %d 

tool: D26: 
 The element with rank %d is %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {10, 30, 60, 100, 1, 2, 7, 9, 80, 40, 55, 22, 99};
  int size = sizeof(a) / sizeof(a[0]);
  mergeSort(a, 0, size - 1);
  printf("Sorted Array\n");
  for (int i = 0; i < size; i++)
    printf("%d ", a[i]);
  int r = 7;
  printf("\n The element with rank %d is %d", r, a[size - r]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xc,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x1e0000000a,%rax
  mov    %rsp,%rbx
  movl   $0x63,0x30(%rsp)
  lea    0x34(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x640000003c,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x900000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2800000050,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x1600000037,%rax
  mov    %rax,0x28(%rsp)
  call   <mergeSort@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    0x18(%rsp),%edx
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  mov    $0x7,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D25
type: string
name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D14
type: string

tool: D25: %d 

tool: D27: Sorted Array

tool: D14: 
 The element with rank %d is %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {10, 30, 60, 100, 1, 2, 7, 9, 80, 40, 55, 22, 99};
  int size = sizeof(a) / sizeof(a[0]);
  mergeSort(a, 0, size - 1);
  printf("Sorted Array\n");
  for (int i = 0; i < size; i++)
    printf("%d ", a[i]);
  int r = 7;
  printf("\n The element with rank %d is %d", r, a[size - r]);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xc,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D34(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movl   $0x63,0x30(%rsp)
  lea    0x34(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D58(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D4(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <mergeSort@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L0
  mov    0x18(%rsp),%edx
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  mov    $0x7,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D34
type_infered: byte[16]
name: read_data
arguments: label: D58
type_infered: byte[16]
name: read_data
arguments: label: D4
type_infered: byte[16]
name: read_data
arguments: label: D23
type_infered: string
name: read_data
arguments: label: D19
type_infered: string

tool: D17: %d 

tool: {"D34": [0x0a,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x3c,0x00,0x00,0x00,0x64,0x00,0x00,0x00]}

tool: {"D58": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D4": [0x50,0x00,0x00,0x00,0x28,0x00,0x00,0x00,0x37,0x00,0x00,0x00,0x16,0x00,0x00,0x00]}

tool: D23: Sorted Array

tool: D19: 
 The element with rank %d is %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {10, 30, 60, 100, 1, 2, 7, 9, 80, 40, 55, 22, 99};
  int size = sizeof(a) / sizeof(a[0]);
  mergeSort(a, 0, size - 1);
  printf("Sorted Array\n");
  for (int i = 0; i < size; i++)
    printf("%d ", a[i]);
  int r = 7;
  printf("\n The element with rank %d is %d", r, a[size - r]);
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<UnixIsFolder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %ax,-0xe(%rbp)
  cmpw   $0xffff,-0xe(%rbp)
  jne    L0
  movzwl -0xe(%rbp),%eax
  jmp    L33
L0:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  cmp    $0x1,%eax
  je     L43
  mov    $0x1,%eax
  jmp    L33
L43:
  mov    $0x0,%eax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
short UnixIsFolder(char *path) {
  struct stat filestat;
  short err;
  err = stat(path, &filestat);
  if (err == -1)
    return err;
  if (S_ISREG(filestat.st_mode) != 1)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<UnixIsFolder>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffff,%ax
  je     L10
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short UnixIsFolder(char *path) {
  struct stat filestat;
  short err;
  err = stat(path, &filestat);
  if (err == -1)
    return err;
  if (S_ISREG(filestat.st_mode) != 1)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<UnixIsFolder>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffff,%ax
  je     L3
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short UnixIsFolder(char *path) {
  struct stat filestat;
  short err;
  err = stat(path, &filestat);
  if (err == -1)
    return err;
  if (S_ISREG(filestat.st_mode) != 1)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<UnixIsFolder>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffff,%ax
  je     L7
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short UnixIsFolder(char *path) {
  struct stat filestat;
  short err;
  err = stat(path, &filestat);
  if (err == -1)
    return err;
  if (S_ISREG(filestat.st_mode) != 1)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<detectCapitalUse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L50:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L16
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  jmp    L38
L16:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L69
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L69
  cmpl   $0x0,-0x10(%rbp)
  jne    L102
  movl   $0x1,-0xc(%rbp)
  jmp    L124
L102:
  cmpl   $0x1,-0x10(%rbp)
  jne    L159
  cmpl   $0x0,-0xc(%rbp)
  je     L152
  movl   $0x1,-0x8(%rbp)
  jmp    L124
L152:
  mov    $0x0,%eax
  jmp    L24
L159:
  cmpl   $0x0,-0x8(%rbp)
  jne    L124
  mov    $0x0,%eax
  jmp    L24
L69:
  cmpl   $0x0,-0x8(%rbp)
  je     L54
  mov    $0x0,%eax
  jmp    L24
L124:
  nop
L54:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L50
  mov    $0x1,%eax
L24:
  leave
  ret
```

assistant: ```c
int detectCapitalUse(char *word) {
  int length = strlen(word);
  int c = 0;
  int i = 0;
  int f = 0, a = 0;
  while (c < length) {
    if (word[c] == ' ') {
      f = a = 0;
      i = 0;
      c++;
      continue;
    }
    if (word[c] >= 'A' && word[c] <= 'Z') {
      if (i == 0) {
        f = 1;
      } else if (i == 1) {
        if (f)
          a = 1;
        else
          return 0;
      } else {
        if (!a) {
          return 0;
        }
      }
    } else {
      if (a) {
        return 0;
      }
    }
    c++;
    i++;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<detectCapitalUse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L144
  mov    %rbx,%rdi
  mov    $0x1,%ecx
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  mov    $0x0,%esi
  mov    $0x1,%r11d
  mov    $0x0,%r10d
  jmp    L10
L41:
  mov    %ecx,%edx
  mov    %r10d,%r8d
  mov    %r10d,%r9d
  mov    $0x0,%esi
  jmp    L19
L70:
  test   %r9d,%r9d
  je     L50
  mov    %r9d,%r8d
  jmp    L114
L50:
  mov    %r9d,%r8d
  jmp    L49
L139:
  test   %r8d,%r8d
  jne    L133
L114:
  mov    %ecx,%edx
  add    $0x1,%esi
L19:
  add    $0x1,%rdi
  add    $0x1,%ecx
  cmp    %eax,%edx
  jge    L101
L10:
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L41
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L139
  test   %esi,%esi
  je     L146
  cmp    $0x1,%esi
  je     L70
  test   %r8d,%r8d
  jne    L114
  jmp    L49
L146:
  mov    %r11d,%r9d
  jmp    L114
L101:
  mov    $0x1,%r8d
L49:
  mov    %r8d,%eax
  pop    %rbx
  ret
L144:
  mov    $0x1,%r8d
  jmp    L49
L133:
  mov    $0x0,%r8d
  jmp    L49
```

assistant: ```c
int detectCapitalUse(char *word) {
  int length = strlen(word);
  int c = 0;
  int i = 0;
  int f = 0, a = 0;
  while (c < length) {
    if (word[c] == ' ') {
      f = a = 0;
      i = 0;
      c++;
      continue;
    }
    if (word[c] >= 'A' && word[c] <= 'Z') {
      if (i == 0) {
        f = 1;
      } else if (i == 1) {
        if (f)
          a = 1;
        else
          return 0;
      } else {
        if (!a) {
          return 0;
        }
      }
    } else {
      if (a) {
        return 0;
      }
    }
    c++;
    i++;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<detectCapitalUse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L62
  mov    %rbx,%rdi
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  xor    %esi,%esi
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L112:
  test   %esi,%esi
  je     L85
  cmp    $0x1,%esi
  je     L71
  test   %r8d,%r8d
  je     L97
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %ecx,%edx
  add    $0x1,%esi
  add    $0x1,%rdi
  add    $0x1,%ecx
  cmp    %edx,%eax
  jle    L62
L58:
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L54
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L112
  test   %r8d,%r8d
  je     L19
L20:
  xor    %r8d,%r8d
L97:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L54:
  mov    %ecx,%edx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  xor    %esi,%esi
  add    $0x1,%rdi
  add    $0x1,%ecx
  cmp    %edx,%eax
  jg     L58
L62:
  mov    $0x1,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
L85:
  mov    $0x1,%r9d
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L71:
  test   %r9d,%r9d
  je     L20
  mov    %r9d,%r8d
  jmp    L19
```

assistant: ```c
int detectCapitalUse(char *word) {
  int length = strlen(word);
  int c = 0;
  int i = 0;
  int f = 0, a = 0;
  while (c < length) {
    if (word[c] == ' ') {
      f = a = 0;
      i = 0;
      c++;
      continue;
    }
    if (word[c] >= 'A' && word[c] <= 'Z') {
      if (i == 0) {
        f = 1;
      } else if (i == 1) {
        if (f)
          a = 1;
        else
          return 0;
      } else {
        if (!a) {
          return 0;
        }
      }
    } else {
      if (a) {
        return 0;
      }
    }
    c++;
    i++;
  }
  return 1;
}
```