ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<egetch>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getch0@plt>
  mov    %eax,%ebx
  lea    -0x3(%rax),%eax
  cmp    $0x1,%eax
  jbe    L103
  cmp    $0xffffffff,%ebx
  je     L103
  mov    %ebx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%eax
  jne    L101
L103:
  mov    $0x0,%eax
  call   <quit@plt>
L101:
  cmp    $0x1b,%ebx
  je     L29
L74:
  mov    %ebx,%eax
  pop    %rbx
  ret
L29:
  mov    $0x0,%eax
  call   <getch0@plt>
  mov    $0x0,%eax
  call   <getch0@plt>
  cmp    $0x41,%eax
  je     L75
  cmp    $0x42,%eax
  je     L51
  cmp    $0x43,%eax
  je     L82
  cmp    $0x44,%eax
  mov    $0x0,%ebx
  mov    $0x104,%eax
  cmove  %eax,%ebx
  jmp    L74
L75:
  mov    $0x101,%ebx
  jmp    L74
L51:
  mov    $0x102,%ebx
  jmp    L74
L82:
  mov    $0x103,%ebx
  jmp    L74
```

assistant: ```c
int egetch() {
  int c, d, e;
  c = getch0();
  if (c == 3 || c == 4 || c == -1 || c == 'q' || c == 'Q')
    quit();
  if (c != 27)
    return c;
  d = getch0();
  e = getch0();
  if (e == 'A')
    return 257;
  if (e == 'B')
    return 258;
  if (e == 'C')
    return 259;
  if (e == 'D')
    return 260;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<egetch>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getch0@plt>
  mov    %eax,%r12d
  sub    $0x3,%eax
  cmp    $0x1,%eax
  jbe    L98
  cmp    $0xffffffff,%r12d
  je     L98
  mov    %r12d,%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%eax
  je     L98
  cmp    $0x1b,%r12d
  je     L105
L49:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L98:
  xor    %eax,%eax
  call   <quit@plt>
  cmp    $0x1b,%r12d
  jne    L49
L105:
  xor    %eax,%eax
  call   <getch0@plt>
  xor    %eax,%eax
  call   <getch0@plt>
  cmp    $0x41,%eax
  je     L15
  cmp    $0x42,%eax
  je     L4
  cmp    $0x43,%eax
  je     L88
  xor    %r12d,%r12d
  cmp    $0x44,%eax
  mov    $0x104,%eax
  cmove  %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0x101,%r12d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x102,%r12d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L88:
  mov    $0x103,%r12d
  jmp    L49
```

assistant: ```c
int egetch() {
  int c, d, e;
  c = getch0();
  if (c == 3 || c == 4 || c == -1 || c == 'q' || c == 'Q')
    quit();
  if (c != 27)
    return c;
  d = getch0();
  e = getch0();
  if (e == 'A')
    return 257;
  if (e == 'B')
    return 258;
  if (e == 'C')
    return 259;
  if (e == 'D')
    return 260;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<egetch>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getch0@plt>
  mov    %eax,%r12d
  sub    $0x3,%eax
  cmp    $0x1,%eax
  jbe    L22
  cmp    $0xffffffff,%r12d
  je     L22
  mov    %r12d,%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%eax
  je     L22
  cmp    $0x1b,%r12d
  je     L104
L54:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L22:
  xor    %eax,%eax
  call   <quit@plt>
  cmp    $0x1b,%r12d
  jne    L54
L104:
  xor    %eax,%eax
  call   <getch0@plt>
  xor    %eax,%eax
  call   <getch0@plt>
  cmp    $0x41,%eax
  je     L9
  cmp    $0x42,%eax
  je     L106
  cmp    $0x43,%eax
  je     L93
  xor    %r12d,%r12d
  cmp    $0x44,%eax
  mov    $0x104,%eax
  cmove  %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x101,%r12d
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L106:
  mov    $0x102,%r12d
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L93:
  mov    $0x103,%r12d
  jmp    L54
```

assistant: ```c
int egetch() {
  int c, d, e;
  c = getch0();
  if (c == 3 || c == 4 || c == -1 || c == 'q' || c == 'Q')
    quit();
  if (c != 27)
    return c;
  d = getch0();
  e = getch0();
  if (e == 'A')
    return 257;
  if (e == 'B')
    return 258;
  if (e == 'C')
    return 259;
  if (e == 'D')
    return 260;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__utoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %edx,-0x84(%rbp)
  mov    %rcx,-0x90(%rbp)
  mov    %r8d,-0x88(%rbp)
  mov    %r9d,-0x94(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rax
  add    $0x41,%rax
  mov    %rax,-0x60(%rbp)
  movl   $0x0,-0x64(%rbp)
  cmpq   $0x0,-0x90(%rbp)
  jne    L16
  mov    -0x90(%rbp),%rax
  jmp    L28
L16:
  mov    -0x60(%rbp),%rax
  movb   $0x0,(%rax)
L23:
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x84(%rbp),%eax
  movslq %eax,%rdi
  mov    -0x78(%rbp),%rax
  mov    $0x0,%edx
  div    %rdi
  mov    %rax,-0x78(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x84(%rbp),%eax
  cltq
  mov    %eax,%esi
  mov    -0x78(%rbp),%rax
  mov    %eax,%edx
  mov    %esi,%eax
  imul   %edx,%eax
  mov    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %al,-0x65(%rbp)
  cmpb   $0x9,-0x65(%rbp)
  jg     L44
  movzbl -0x65(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  jmp    L38
L44:
  mov    0x10(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x65(%rbp),%eax
  add    %edx,%eax
  sub    $0xa,%eax
  mov    %eax,%edx
L38:
  subq   $0x1,-0x60(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x64(%rbp)
  cmpq   $0x0,-0x78(%rbp)
  jne    L23
  jmp    L32
L27:
  subq   $0x1,-0x60(%rbp)
  mov    -0x94(%rbp),%eax
  mov    %eax,%edx
  mov    -0x60(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x64(%rbp)
L32:
  mov    -0x64(%rbp),%eax
  cmp    -0x88(%rbp),%eax
  jl     L27
  movl   $0x0,-0x64(%rbp)
  jmp    L47
L40:
  mov    -0x60(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x60(%rbp)
  mov    -0x80(%rbp),%rdx
  mov    (%rdx),%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subq   $0x1,-0x90(%rbp)
  addl   $0x1,-0x64(%rbp)
  mov    -0x80(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x80(%rbp),%rax
  mov    %rdx,(%rax)
L47:
  mov    -0x60(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L105
  cmpq   $0x0,-0x90(%rbp)
  jne    L40
L105:
  mov    -0x64(%rbp),%eax
  cltq
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
size_t __utoa(unsigned long i, char **dest, int base, size_t size, int pad, int fill, int upper) {
  char temp[65];
  char *str = &temp[sizeof(temp)];
  int s = 0;
  if (size < 1)
    return size;
  *str = '\0';
  do {
    unsigned long m = i;
    i /= base;
    char c = m - base * i;
    *--str = c < 10 ? c + '0' : c + upper - 10;
    s++;
  } while (i);
  while (s < pad) {
    *--str = fill;
    s++;
  }
  s = 0;
  while (*str && (size != 0)) {
    **dest = *str++;
    size--, s++;
    (*dest)++;
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__utoa>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rcx,%rax
  test   %rcx,%rcx
  je     L2
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rcx,%r12
  movb   $0x0,0x41(%rsp)
  mov    $0x0,%ebp
  lea    0x41(%rsp),%rdi
  movslq %edx,%rsi
  movzbl 0x80(%rsp),%eax
  lea    -0xa(%rax),%r13d
L23:
  mov    %r10,%rbx
  mov    %r10,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,%r10
  imul   %esi,%eax
  mov    %ebx,%edx
  sub    %eax,%edx
  lea    0x30(%rdx),%ecx
  lea    0x0(%r13,%rdx,1),%eax
  cmp    $0x9,%dl
  cmovle %ecx,%eax
  sub    $0x1,%rdi
  mov    %al,(%rdi)
  add    $0x1,%ebp
  cmp    %rbx,%rsi
  jbe    L23
  cmp    %r8d,%ebp
  jge    L25
  mov    %ebp,%ecx
  mov    %r8d,%eax
  sub    %ebp,%eax
  lea    -0x1(%rax),%edx
  not    %rdx
  add    %rdi,%rdx
  mov    %rdi,%rax
L16:
  sub    $0x1,%rax
  mov    %r9b,(%rax)
  cmp    %rdx,%rax
  jne    L16
  sub    %ecx,%r8d
  lea    -0x1(%r8),%eax
  not    %rax
  add    %rax,%rdi
L25:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L63
  mov    %rdi,%rdx
  mov    $0x0,%eax
L14:
  add    $0x1,%rdx
  mov    (%r11),%rsi
  mov    %cl,(%rsi)
  add    $0x1,%eax
  addq   $0x1,(%r11)
  movzbl (%rdx),%ecx
  mov    %r12,%rsi
  sub    %rdx,%rsi
  add    %rdi,%rsi
  je     L6
  test   %cl,%cl
  jne    L14
L6:
  cltq
L2:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L63:
  mov    $0x0,%eax
  jmp    L6
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t __utoa(unsigned long i, char **dest, int base, size_t size, int pad, int fill, int upper) {
  char temp[65];
  char *str = &temp[sizeof(temp)];
  int s = 0;
  if (size < 1)
    return size;
  *str = '\0';
  do {
    unsigned long m = i;
    i /= base;
    char c = m - base * i;
    *--str = c < 10 ? c + '0' : c + upper - 10;
    s++;
  } while (i);
  while (s < pad) {
    *--str = fill;
    s++;
  }
  s = 0;
  while (*str && (size != 0)) {
    **dest = *str++;
    size--, s++;
    (*dest)++;
  }
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__utoa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rcx,%rcx
  je     L48
  movb   $0x0,0x41(%rsp)
  movslq %edx,%r10
  mov    %rsi,%rbp
  mov    %rcx,%r12
  movzbl 0x80(%rsp),%eax
  mov    %r10d,%r14d
  xor    %esi,%esi
  lea    0x41(%rsp),%rcx
  lea    -0xa(%rax),%r13d
  nopl   (%rax)
L23:
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %rdi,%r11
  div    %r10
  mov    %r11d,%edx
  mov    %rax,%rdi
  mov    %r14d,%eax
  imul   %edi,%eax
  sub    %eax,%edx
  cmp    $0x9,%dl
  lea    0x30(%rdx),%eax
  lea    0x0(%r13,%rdx,1),%ebx
  cmovle %eax,%ebx
  sub    $0x1,%rcx
  add    $0x1,%esi
  mov    %bl,(%rcx)
  cmp    %r10,%r11
  jae    L23
  cmp    %r8d,%esi
  jge    L68
  sub    %esi,%r8d
  movsbl %r9b,%esi
  mov    %r9d,%ebx
  lea    -0x1(%r8),%edx
  mov    %rdx,%rax
  add    $0x1,%rdx
  not    %rax
  add    %rax,%rcx
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    %rax,%rcx
L68:
  test   %bl,%bl
  je     L58
  mov    0x0(%rbp),%rdx
  mov    %rcx,%rsi
  xor    %eax,%eax
  jmp    L78
  nop
L44:
  test   %bl,%bl
  je     L54
L78:
  mov    %bl,(%rdx)
  add    $0x1,%rsi
  mov    0x0(%rbp),%rbx
  mov    %r12,%rdi
  sub    %rsi,%rdi
  add    $0x1,%eax
  lea    0x1(%rbx),%rdx
  add    %rcx,%rdi
  movzbl (%rsi),%ebx
  mov    %rdx,0x0(%rbp)
  jne    L44
L54:
  cltq
L48:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L58:
  xor    %eax,%eax
  jmp    L48
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t __utoa(unsigned long i, char **dest, int base, size_t size, int pad, int fill, int upper) {
  char temp[65];
  char *str = &temp[sizeof(temp)];
  int s = 0;
  if (size < 1)
    return size;
  *str = '\0';
  do {
    unsigned long m = i;
    i /= base;
    char c = m - base * i;
    *--str = c < 10 ? c + '0' : c + upper - 10;
    s++;
  } while (i);
  while (s < pad) {
    *--str = fill;
    s++;
  }
  s = 0;
  while (*str && (size != 0)) {
    **dest = *str++;
    size--, s++;
    (*dest)++;
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__utoa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rcx,%rcx
  je     L90
  mov    %rcx,%r12
  movslq %edx,%rcx
  mov    %rsi,%rbp
  movb   $0x0,0x41(%rsp)
  movzbl 0x80(%rsp),%eax
  mov    %ecx,%r13d
  xor    %esi,%esi
  lea    0x41(%rsp),%r10
  lea    -0xa(%rax),%r14d
  jmp    L67
  nop
L88:
  add    $0x30,%ebx
  sub    $0x1,%r10
  add    $0x1,%esi
  mov    %bl,(%r10)
  cmp    %rcx,%rdi
  jb     L15
L102:
  mov    %r11,%rdi
L67:
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %edi,%ebx
  div    %rcx
  mov    %rax,%r11
  mov    %r13d,%eax
  imul   %r11d,%eax
  sub    %eax,%ebx
  cmp    $0x9,%bl
  jle    L88
  add    %r14d,%ebx
  sub    $0x1,%r10
  add    $0x1,%esi
  mov    %bl,(%r10)
  cmp    %rcx,%rdi
  jae    L102
L15:
  cmp    %r8d,%esi
  jge    L69
  sub    %esi,%r8d
  movsbl %r9b,%esi
  mov    %r9d,%ebx
  lea    -0x1(%r8),%edx
  mov    %rdx,%rax
  add    $0x1,%rdx
  not    %rax
  add    %rax,%r10
  mov    %r10,%rdi
  call   <memset@plt>
  mov    %rax,%r10
L69:
  test   %bl,%bl
  je     L48
  mov    0x0(%rbp),%rdx
  mov    %r10,%rcx
  xor    %eax,%eax
  jmp    L13
  nopl   0x0(%rax)
L85:
  test   %bl,%bl
  je     L78
L13:
  mov    %bl,(%rdx)
  add    $0x1,%rcx
  mov    0x0(%rbp),%rdi
  mov    %r12,%rsi
  sub    %rcx,%rsi
  add    $0x1,%eax
  movzbl (%rcx),%ebx
  lea    0x1(%rdi),%rdx
  add    %r10,%rsi
  mov    %rdx,0x0(%rbp)
  jne    L85
L78:
  cltq
L90:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L80
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  xor    %eax,%eax
  jmp    L90
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t __utoa(unsigned long i, char **dest, int base, size_t size, int pad, int fill, int upper) {
  char temp[65];
  char *str = &temp[sizeof(temp)];
  int s = 0;
  if (size < 1)
    return size;
  *str = '\0';
  do {
    unsigned long m = i;
    i /= base;
    char c = m - base * i;
    *--str = c < 10 ? c + '0' : c + upper - 10;
    s++;
  } while (i);
  while (s < pad) {
    *--str = fill;
    s++;
  }
  s = 0;
  while (*str && (size != 0)) {
    **dest = *str++;
    size--, s++;
    (*dest)++;
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  movl   $0xa,-0x4(%rbp)
  movl   $0x14,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add(int num1, int num2) {
  num1 = 10;
  num2 = 20;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<add>:
  endbr64
  ret
```

assistant: ```c
void add(int num1, int num2) {
  num1 = 10;
  num2 = 20;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add>:
  endbr64
  ret
```

assistant: ```c
void add(int num1, int num2) {
  num1 = 10;
  num2 = 20;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<add>:
  endbr64
  ret
```

assistant: ```c
void add(int num1, int num2) {
  num1 = 10;
  num2 = 20;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L2:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x1,-0x4(%rbp)
  ja     L2
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int factorial(unsigned int number) {
  unsigned int factorial = 1;
  for (unsigned int i = number; i > 1; i--) {
    factorial *= i;
  }
  return factorial;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<factorial>:
  endbr64
  cmp    $0x1,%edi
  jbe    L4
  mov    $0x1,%eax
L0:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L0
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int factorial(unsigned int number) {
  unsigned int factorial = 1;
  for (unsigned int i = number; i > 1; i--) {
    factorial *= i;
  }
  return factorial;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L18
  xchg   %ax,%ax
L7:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L7
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
unsigned int factorial(unsigned int number) {
  unsigned int factorial = 1;
  for (unsigned int i = number; i > 1; i--) {
    factorial *= i;
  }
  return factorial;
}
```
user: What is the c source code of the assembly code below?

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L15
  xchg   %ax,%ax
L14:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L14
  ret
  nopl   0x0(%rax)
L15:
  ret
```

assistant: ```c
unsigned int factorial(unsigned int number) {
  unsigned int factorial = 1;
  for (unsigned int i = number; i > 1; i--) {
    factorial *= i;
  }
  return factorial;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uintToStr>:
  endbr64
  mov    %rdi,%r8
  lea    -0x2(%rdx),%eax
  cmp    $0xe,%eax
  ja     L5
  sub    $0x8,%rsp
  mov    %edx,%edi
  mov    $0x1,%ecx
  lea    D0(%rip),%r10
  mov    $0x0,%r9d
  test   %esi,%esi
  je     L4
L22:
  mov    %ecx,%r9d
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %edi
  movslq %edx,%rdx
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%r8,%rcx,1)
  mov    %esi,%edx
  mov    %eax,%esi
  add    $0x1,%rcx
  cmp    %edx,%edi
  jbe    L22
L4:
  movslq %r9d,%rax
  movb   $0x0,(%r8,%rax,1)
  mov    %r9d,%esi
  mov    %r8,%rdi
  call   <reverseStr@plt>
  add    $0x8,%rsp
  ret
L5:
  movb   $0x30,(%rdi)
  movb   $0x0,0x1(%rdi)
  mov    %rdi,%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: 0123456789ABCDEF

assistant: ```c
char *uintToStr(char *str, unsigned int value, int base) {
  static char *chars = "0123456789ABCDEF";
  if (base < 2 || base > 16) {
    str[0] = '0';
    str[1] = '\0';
    return str;
  } else {
    int pos = 0;
    while (value != 0) {
      int curr = value % base;
      str[pos++] = chars[curr];
      value /= base;
    }
    str[pos] = '\0';
    return reverseStr(str, pos);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uintToStr>:
  endbr64
  lea    -0x2(%rdx),%eax
  mov    %rdi,%r8
  mov    %edx,%edi
  cmp    $0xe,%eax
  ja     L12
  mov    $0x1,%ecx
  lea    D3(%rip),%r10
  mov    %r8,%rax
  xor    %r9d,%r9d
  test   %esi,%esi
  je     L14
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %esi,%eax
  xor    %edx,%edx
  mov    %ecx,%r9d
  div    %edi
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%r8,%rcx,1)
  mov    %esi,%edx
  add    $0x1,%rcx
  mov    %eax,%esi
  cmp    %edx,%edi
  jbe    L22
  movslq %r9d,%rax
  add    %r8,%rax
L14:
  movb   $0x0,(%rax)
  mov    %r9d,%esi
  mov    %r8,%rdi
  jmp    1050 <reverseStr@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  mov    $0x30,%eax
  mov    %ax,(%r8)
  mov    %r8,%rax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: 0123456789ABCDEF

assistant: ```c
char *uintToStr(char *str, unsigned int value, int base) {
  static char *chars = "0123456789ABCDEF";
  if (base < 2 || base > 16) {
    str[0] = '0';
    str[1] = '\0';
    return str;
  } else {
    int pos = 0;
    while (value != 0) {
      int curr = value % base;
      str[pos++] = chars[curr];
      value /= base;
    }
    str[pos] = '\0';
    return reverseStr(str, pos);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uintToStr>:
  endbr64
  lea    -0x2(%rdx),%eax
  mov    %rdi,%r8
  mov    %edx,%edi
  cmp    $0xe,%eax
  ja     L21
  mov    $0x1,%ecx
  lea    D3(%rip),%r10
  mov    %r8,%rax
  xor    %r9d,%r9d
  test   %esi,%esi
  je     L0
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %esi,%eax
  xor    %edx,%edx
  mov    %ecx,%r9d
  div    %edi
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%r8,%rcx,1)
  mov    %esi,%edx
  add    $0x1,%rcx
  mov    %eax,%esi
  cmp    %edx,%edi
  jbe    L10
  movslq %r9d,%rax
  add    %r8,%rax
L0:
  movb   $0x0,(%rax)
  mov    %r9d,%esi
  mov    %r8,%rdi
  jmp    1050 <reverseStr@plt>
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0x30,%eax
  mov    %ax,(%r8)
  mov    %r8,%rax
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: 0123456789ABCDEF

assistant: ```c
char *uintToStr(char *str, unsigned int value, int base) {
  static char *chars = "0123456789ABCDEF";
  if (base < 2 || base > 16) {
    str[0] = '0';
    str[1] = '\0';
    return str;
  } else {
    int pos = 0;
    while (value != 0) {
      int curr = value % base;
      str[pos++] = chars[curr];
      value /= base;
    }
    str[pos] = '\0';
    return reverseStr(str, pos);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decomposicao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void decomposicao(double x, long *part_int, double *part_frac) {
  *part_int = (long)x;
  *part_frac = x - *part_int;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decomposicao>:
  endbr64
  cvttsd2si %xmm0,%rax
  mov    %rax,(%rdi)
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void decomposicao(double x, long *part_int, double *part_frac) {
  *part_int = (long)x;
  *part_frac = x - *part_int;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decomposicao>:
  endbr64
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    %rax,(%rdi)
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void decomposicao(double x, long *part_int, double *part_frac) {
  *part_int = (long)x;
  *part_frac = x - *part_int;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<decomposicao>:
  endbr64
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    %rax,(%rdi)
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void decomposicao(double x, long *part_int, double *part_frac) {
  *part_int = (long)x;
  *part_frac = x - *part_int;
}
```