ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_op>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpb   $0x2b,-0x1c(%rbp)
  jne    L83
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L83:
  cmpb   $0x2d,-0x1c(%rbp)
  jne    L0
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L0:
  cmpb   $0x2a,-0x1c(%rbp)
  jne    L26
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L26:
  cmpb   $0x2f,-0x1c(%rbp)
  jne    L69
  cmpl   $0x0,-0x18(%rbp)
  je     L69
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  jmp    L19
L69:
  cmpb   $0x25,-0x1c(%rbp)
  jne    L19
  cmpl   $0x0,-0x18(%rbp)
  je     L19
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int do_op(int a, int b, char op) {
  int result;
  result = 0;
  if (op == '+')
    result = (a + b);
  else if (op == '-')
    result = (a - b);
  else if (op == '*')
    result = (a * b);
  else if (op == '/' && b != 0)
    result = (a / b);
  else if (op == '%' && b != 0)
    result = (a % b);
  return (result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_op>:
  endbr64
  cmp    $0x2b,%dl
  je     L14
  cmp    $0x2d,%dl
  je     L32
  cmp    $0x2a,%dl
  je     L99
  test   %esi,%esi
  setne  %cl
  cmp    $0x2f,%dl
  jne    L8
  test   %cl,%cl
  je     L8
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%edi
  jmp    L18
L14:
  add    %esi,%edi
L18:
  mov    %edi,%eax
  ret
L32:
  sub    %esi,%edi
  jmp    L18
L99:
  imul   %esi,%edi
  jmp    L18
L8:
  cmp    $0x25,%dl
  jne    L20
  test   %cl,%cl
  je     L20
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%edi
  jmp    L18
L20:
  mov    $0x0,%edi
  jmp    L18
```

assistant: ```c
int do_op(int a, int b, char op) {
  int result;
  result = 0;
  if (op == '+')
    result = (a + b);
  else if (op == '-')
    result = (a - b);
  else if (op == '*')
    result = (a * b);
  else if (op == '/' && b != 0)
    result = (a / b);
  else if (op == '%' && b != 0)
    result = (a % b);
  return (result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<do_op>:
  endbr64
  lea    (%rsi,%rdi,1),%r8d
  cmp    $0x2b,%dl
  je     L45
  cmp    $0x2d,%dl
  je     L28
  cmp    $0x2a,%dl
  je     L48
  test   %esi,%esi
  setne  %cl
  cmp    $0x2f,%dl
  jne    L76
  test   %cl,%cl
  je     L76
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%r8d
L45:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L28:
  sub    %esi,%edi
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L76:
  cmp    $0x25,%dl
  jne    L13
  test   %cl,%cl
  je     L13
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%r8d
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L48:
  imul   %edi,%esi
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  jmp    L45
```

assistant: ```c
int do_op(int a, int b, char op) {
  int result;
  result = 0;
  if (op == '+')
    result = (a + b);
  else if (op == '-')
    result = (a - b);
  else if (op == '*')
    result = (a * b);
  else if (op == '/' && b != 0)
    result = (a / b);
  else if (op == '%' && b != 0)
    result = (a % b);
  return (result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_op>:
  endbr64
  lea    (%rsi,%rdi,1),%r8d
  cmp    $0x2b,%dl
  je     L25
  cmp    $0x2d,%dl
  je     L42
  cmp    $0x2a,%dl
  je     L61
  test   %esi,%esi
  setne  %cl
  cmp    $0x2f,%dl
  jne    L59
  test   %cl,%cl
  je     L59
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%r8d
L25:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L42:
  sub    %esi,%edi
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L59:
  cmp    $0x25,%dl
  jne    L49
  test   %cl,%cl
  je     L49
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%r8d
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L61:
  imul   %edi,%esi
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  xor    %r8d,%r8d
  jmp    L25
```

assistant: ```c
int do_op(int a, int b, char op) {
  int result;
  result = 0;
  if (op == '+')
    result = (a + b);
  else if (op == '-')
    result = (a - b);
  else if (op == '*')
    result = (a * b);
  else if (op == '/' && b != 0)
    result = (a / b);
  else if (op == '%' && b != 0)
    result = (a % b);
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xf,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L12:
  subl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L12
L8:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L8
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  unsigned i = 15, j = 0;
  do {
    i--;
    j++;
  } while (i > 0);
  do
    i++;
  while (i < j);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  unsigned i = 15, j = 0;
  do {
    i--;
    j++;
  } while (i > 0);
  do
    i++;
  while (i < j);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  unsigned i = 15, j = 0;
  do {
    i--;
    j++;
  } while (i > 0);
  do
    i++;
  while (i < j);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  unsigned i = 15, j = 0;
  do {
    i--;
    j++;
  } while (i > 0);
  do
    i++;
  while (i < j);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jne    L33
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <convert_hundreds@plt>
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <convert_tens@plt>
  movzbl -0xb(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <convert_units@plt>
  jmp    L38
L33:
  cmpl   $0x2,-0x14(%rbp)
  jne    L58
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <convert_tens@plt>
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <convert_units@plt>
  jmp    L38
L58:
  cmpl   $0x1,-0x14(%rbp)
  jne    L38
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <convert_units@plt>
L38:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: 


assistant: ```c
int main() {
  char x[5];
  int lnth;
  lnth = strlen(gets(x));
  if (lnth == 3) {
    convert_hundreds(x[0]);
    convert_tens(x[1]);
    convert_units(x[2]);
  } else if (lnth == 2) {
    convert_tens(x[0]);
    convert_units(x[1]);
  } else if (lnth == 1) {
    convert_units(x[0]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rdi
  call   <gets@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  cmp    $0x3,%eax
  je     L9
  cmp    $0x2,%eax
  je     L28
  cmp    $0x1,%eax
  je     L0
L3:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  movsbl 0x3(%rsp),%edi
  call   <convert_hundreds@plt>
  movsbl 0x4(%rsp),%edi
  call   <convert_tens@plt>
  movsbl 0x5(%rsp),%edi
  call   <convert_units@plt>
  jmp    L3
L28:
  movsbl 0x3(%rsp),%edi
  call   <convert_tens@plt>
  movsbl 0x4(%rsp),%edi
  call   <convert_units@plt>
  jmp    L3
L0:
  movsbl 0x3(%rsp),%edi
  call   <convert_units@plt>
  jmp    L3
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: 


assistant: ```c
int main() {
  char x[5];
  int lnth;
  lnth = strlen(gets(x));
  if (lnth == 3) {
    convert_hundreds(x[0]);
    convert_tens(x[1]);
    convert_units(x[2]);
  } else if (lnth == 2) {
    convert_tens(x[0]);
    convert_units(x[1]);
  } else if (lnth == 1) {
    convert_units(x[0]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rdi
  call   <gets@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  cmp    $0x3,%eax
  je     L20
  cmp    $0x2,%eax
  je     L24
  sub    $0x1,%eax
  je     L35
L13:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L20:
  movsbl 0x3(%rsp),%edi
  call   <convert_hundreds@plt>
  movsbl 0x4(%rsp),%edi
  call   <convert_tens@plt>
  movsbl 0x5(%rsp),%edi
  call   <convert_units@plt>
  jmp    L13
L24:
  movsbl 0x3(%rsp),%edi
  call   <convert_tens@plt>
  movsbl 0x4(%rsp),%edi
  call   <convert_units@plt>
  jmp    L13
L35:
  movsbl 0x3(%rsp),%edi
  call   <convert_units@plt>
  jmp    L13
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: 


assistant: ```c
int main() {
  char x[5];
  int lnth;
  lnth = strlen(gets(x));
  if (lnth == 3) {
    convert_hundreds(x[0]);
    convert_tens(x[1]);
    convert_units(x[2]);
  } else if (lnth == 2) {
    convert_tens(x[0]);
    convert_units(x[1]);
  } else if (lnth == 1) {
    convert_units(x[0]);
  }
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rdi
  call   <gets@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  cmp    $0x3,%eax
  je     L19
  cmp    $0x2,%eax
  je     L11
  sub    $0x1,%eax
  je     L22
L65:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  movsbl 0x3(%rsp),%edi
  call   <convert_hundreds@plt>
  movsbl 0x4(%rsp),%edi
  call   <convert_tens@plt>
  movsbl 0x5(%rsp),%edi
  call   <convert_units@plt>
  jmp    L65
L11:
  movsbl 0x3(%rsp),%edi
  call   <convert_tens@plt>
  movsbl 0x4(%rsp),%edi
  call   <convert_units@plt>
  jmp    L65
L22:
  movsbl 0x3(%rsp),%edi
  call   <convert_units@plt>
  jmp    L65
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: 


assistant: ```c
int main() {
  char x[5];
  int lnth;
  lnth = strlen(gets(x));
  if (lnth == 3) {
    convert_hundreds(x[0]);
    convert_tens(x[1]);
    convert_units(x[2]);
  } else if (lnth == 2) {
    convert_tens(x[0]);
    convert_units(x[1]);
  } else if (lnth == 1) {
    convert_units(x[0]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<add_signed_long_parse_katcl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <before_add_parse_katcl@plt>
  test   %rax,%rax
  jns    L40
  mov    $0xffffffff,%eax
  jmp    L61
L40:
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <request_space_parse_katcl@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    $0xffffffff,%eax
  jmp    L61
L19:
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  lea    D8(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L28
  cmpl   $0x1f,-0xc(%rbp)
  jle    L31
L28:
  mov    $0xffffffff,%eax
  jmp    L61
L31:
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <after_add_parse_katcl@plt>
L61:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: %ld

assistant: ```c
int add_signed_long_parse_katcl(struct katcl_parse *p, int flags, unsigned long v) {
  int result;
  char *ptr;
  if (before_add_parse_katcl(p, flags) < 0) {
    return -1;
  }
  ptr = request_space_parse_katcl(p, 32);
  if (ptr == NULL) {
    return -1;
  }
  result = snprintf(ptr, 32, "%ld", v);
  if ((result <= 0) || (result >= 32)) {
    return -1;
  }
  return after_add_parse_katcl(p, result, 0, flags);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<add_signed_long_parse_katcl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r12
  call   <before_add_parse_katcl@plt>
  test   %rax,%rax
  js     L23
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <request_space_parse_katcl@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L58
  mov    %r12,%rcx
  lea    D8(%rip),%rdx
  mov    $0x20,%esi
  call   <snprintf@plt>
  mov    %eax,%esi
  lea    -0x1(%rax),%eax
  cmp    $0x1e,%eax
  ja     L38
  mov    %ebp,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <after_add_parse_katcl@plt>
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L28
L58:
  mov    $0xffffffff,%eax
  jmp    L28
L38:
  mov    $0xffffffff,%eax
  jmp    L28
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: %ld

assistant: ```c
int add_signed_long_parse_katcl(struct katcl_parse *p, int flags, unsigned long v) {
  int result;
  char *ptr;
  if (before_add_parse_katcl(p, flags) < 0) {
    return -1;
  }
  ptr = request_space_parse_katcl(p, 32);
  if (ptr == NULL) {
    return -1;
  }
  result = snprintf(ptr, 32, "%ld", v);
  if ((result <= 0) || (result >= 32)) {
    return -1;
  }
  return after_add_parse_katcl(p, result, 0, flags);
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_signed_long_parse_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <before_add_parse_katcl@plt>
  test   %rax,%rax
  js     L12
  mov    %rbp,%rdi
  mov    $0x20,%esi
  call   <request_space_parse_katcl@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L12
  mov    $0x20,%esi
  mov    %r13,%rcx
  lea    D6(%rip),%rdx
  call   <snprintf@plt>
  mov    %eax,%esi
  lea    -0x1(%rax),%eax
  cmp    $0x1e,%eax
  ja     L12
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <after_add_parse_katcl@plt>
  nopl   0x0(%rax)
L12:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: %ld

assistant: ```c
int add_signed_long_parse_katcl(struct katcl_parse *p, int flags, unsigned long v) {
  int result;
  char *ptr;
  if (before_add_parse_katcl(p, flags) < 0) {
    return -1;
  }
  ptr = request_space_parse_katcl(p, 32);
  if (ptr == NULL) {
    return -1;
  }
  result = snprintf(ptr, 32, "%ld", v);
  if ((result <= 0) || (result >= 32)) {
    return -1;
  }
  return after_add_parse_katcl(p, result, 0, flags);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<add_signed_long_parse_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <before_add_parse_katcl@plt>
  test   %rax,%rax
  js     L21
  mov    %rbp,%rdi
  mov    $0x20,%esi
  call   <request_space_parse_katcl@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L21
  mov    $0x20,%esi
  mov    %r13,%rcx
  lea    D0(%rip),%rdx
  call   <snprintf@plt>
  mov    %eax,%esi
  lea    -0x1(%rax),%eax
  cmp    $0x1e,%eax
  ja     L21
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <after_add_parse_katcl@plt>
  nopl   0x0(%rax)
L21:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D0: %ld

assistant: ```c
int add_signed_long_parse_katcl(struct katcl_parse *p, int flags, unsigned long v) {
  int result;
  char *ptr;
  if (before_add_parse_katcl(p, flags) < 0) {
    return -1;
  }
  ptr = request_space_parse_katcl(p, 32);
  if (ptr == NULL) {
    return -1;
  }
  result = snprintf(ptr, 32, "%ld", v);
  if ((result <= 0) || (result >= 32)) {
    return -1;
  }
  return after_add_parse_katcl(p, result, 0, flags);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x58(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  lea    -0x58(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D18(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D34(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D26
type_infered: byte[8]
name: read_data
arguments: tag: D18
type_infered: f64
name: read_data
arguments: tag: D34
type_infered: f64

tool: {"D26": [0xee,0x0c,0x09,0x8f,0x54,0xed,0xea,0x3f]}

tool: D18: 8.8

tool: D34: 2.6

assistant: ```c
void fn(int *p) {
  int **a[] = {&p, (void *)0, &p};
  double d[] = {sin(1.0), 8.8, sin(1.0), 2.6};
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fn>:
  endbr64
  ret
```

assistant: ```c
void fn(int *p) {
  int **a[] = {&p, (void *)0, &p};
  double d[] = {sin(1.0), 8.8, sin(1.0), 2.6};
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fn>:
  endbr64
  ret
```

assistant: ```c
void fn(int *p) {
  int **a[] = {&p, (void *)0, &p};
  double d[] = {sin(1.0), 8.8, sin(1.0), 2.6};
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn>:
  endbr64
  ret
```

assistant: ```c
void fn(int *p) {
  int **a[] = {&p, (void *)0, &p};
  double d[] = {sin(1.0), 8.8, sin(1.0), 2.6};
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
L77:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  je     L84
  jmp    L74
L100:
  mov    -0x38(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L101
  mov    -0x3c(%rbp),%eax
  cltq
  movl   $0x1,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x38(%rbp)
L74:
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  jg     L100
  jmp    L81
L101:
  nop
L81:
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  jle    L1
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L90
L1:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L90:
  movl   $0x0,-0x40(%rbp)
  jmp    L86
L92:
  mov    -0x40(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x40(%rbp)
L86:
  cmpl   $0x9,-0x40(%rbp)
  jle    L92
  jmp    L77
L84:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D37
type: string
name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D25
type: string
name: disassemble_data
arguments: data_label: D12
type: string

tool: D37: enter a number:


tool: D11: %ld

tool: D25: repeated digit


tool: D12: no repeated digit


assistant: ```c
int main(void) {
  bool digit_repeated[10] = {false};
  int digit;
  long n;
  while (1) {
    printf("enter a number:\n");
    scanf("%ld", &n);
    if (n != 0) {
      while (n > 0) {
        digit = n % 10;
        if (digit_repeated[digit]) {
          break;
        }
        digit_repeated[digit] = true;
        n = n / 10;
      }
      if (n > 0) {
        printf("repeated digit\n");
      } else {
        printf("no repeated digit\n");
      }
      for (int i = 0; i < 10; i++) {
        digit_repeated[i] = false;
      }
    } else {
      break;
    }
  }
  return 0;
}
```