ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  movsd  D38(%rip),%xmm2
  movsd  D60(%rip),%xmm1
  movsd  D11(%rip),%xmm0
  lea    0x18(%rsp),%rdx
  lea    0x20(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <JacobiElliptic_complex@plt>
  mov    D38(%rip),%rax
  sub    $0x8,%rsp
  lea    D34(%rip),%rdi
  push   0x38(%rsp)
  movsd  0x38(%rsp),%xmm7
  movq   %rax,%xmm2
  mov    D60(%rip),%rax
  movsd  0x30(%rsp),%xmm6
  movsd  0x28(%rsp),%xmm5
  movq   %rax,%xmm1
  mov    D11(%rip),%rax
  movsd  0x20(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm3
  movq   %rax,%xmm0
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D38
datatype: f64
name: extract_symbolic_data
arguments: label: D60
datatype: f64
name: extract_symbolic_data
arguments: label: D11
datatype: f64
name: extract_symbolic_data
arguments: label: D34
datatype: string

tool: D38: 0.5

tool: D60: 0.4

tool: D11: 0.3

tool: D34: %g	%g	%g	%g	%g	%g	%g	%g	%g


assistant: ```c
int main() {
  double k = 0.5;
  double zr = 0.3;
  double zi = 0.4;
  double cnr, cni, snr, sni, dnr, dni;
  JacobiElliptic_complex(zr, zi, k, &cnr, &cni, &snr, &sni, &dnr, &dni);
  printf("%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\n", zr, zi, k, cnr, cni, snr, sni, dnr, dni);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  movsd  D29(%rip),%xmm2
  movsd  D49(%rip),%xmm1
  movsd  D47(%rip),%xmm0
  lea    0x18(%rsp),%rdx
  lea    0x20(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <JacobiElliptic_complex@plt>
  mov    D29(%rip),%rax
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  push   0x38(%rsp)
  movsd  0x38(%rsp),%xmm7
  movq   %rax,%xmm2
  mov    D49(%rip),%rax
  movsd  0x30(%rsp),%xmm6
  movsd  0x28(%rsp),%xmm5
  movq   %rax,%xmm1
  mov    D47(%rip),%rax
  movsd  0x20(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm3
  movq   %rax,%xmm0
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type_guessed: f64
name: retrieve_data
arguments: data_tag: D49
type_guessed: f64
name: retrieve_data
arguments: data_tag: D47
type_guessed: f64
name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D29: 0.5

tool: D49: 0.4

tool: D47: 0.3

tool: D9: %g	%g	%g	%g	%g	%g	%g	%g	%g


assistant: ```c
int main() {
  double k = 0.5;
  double zr = 0.3;
  double zi = 0.4;
  double cnr, cni, snr, sni, dnr, dni;
  JacobiElliptic_complex(zr, zi, k, &cnr, &cni, &snr, &sni, &dnr, &dni);
  printf("%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\n", zr, zi, k, cnr, cni, snr, sni, dnr, dni);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_inner_vec_ddot>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rax
  mov    %rcx,%r11
  movapd %xmm0,%xmm2
  cmp    $0x3,%r9d
  jle    L24
  movslq %r8d,%rbp
  shl    $0x3,%rbp
  lea    (%r8,%r8,1),%esi
  movslq %esi,%rbx
  shl    $0x3,%rbx
  add    %r8d,%esi
  movslq %esi,%rsi
  shl    $0x3,%rsi
  lea    0x0(,%r8,4),%ecx
  movslq %ecx,%rcx
  shl    $0x3,%rcx
  lea    -0x4(%r9),%r12d
  shr    $0x2,%r12d
  lea    0x1(%r12),%r13d
  mov    %r13d,%r13d
  mov    %r13,%r10
  shl    $0x5,%r10
  add    %rdx,%r10
  mov    %r11,%rdx
  pxor   %xmm0,%xmm0
L35:
  movsd  (%rax),%xmm1
  mulsd  (%rdx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x8(%rax),%xmm0
  mulsd  (%rdx,%rbp,1),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x10(%rax),%xmm1
  mulsd  (%rdx,%rbx,1),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x18(%rax),%xmm0
  mulsd  (%rdx,%rsi,1),%xmm0
  addsd  %xmm1,%xmm0
  add    %rcx,%rdx
  add    $0x20,%rax
  cmp    %r10,%rax
  jne    L35
  imul   %r13,%rcx
  add    %rcx,%r11
  lea    0x4(,%r12,4),%eax
L58:
  cmp    %eax,%r9d
  je     L55
  lea    -0x1(%r9),%edx
  cmp    %eax,%edx
  jle    L8
  movsd  (%r10),%xmm1
  mulsd  (%r11),%xmm1
  addsd  %xmm1,%xmm0
  movslq %r8d,%rdx
  movsd  (%r11,%rdx,8),%xmm1
  mulsd  0x8(%r10),%xmm1
  addsd  %xmm1,%xmm0
  add    %r8d,%r8d
  movslq %r8d,%r8
  lea    (%r11,%r8,8),%r11
  add    $0x10,%r10
  add    $0x2,%eax
L8:
  cmp    %r9d,%eax
  jge    L55
  movsd  (%r10),%xmm1
  mulsd  (%r11),%xmm1
  addsd  %xmm1,%xmm0
L55:
  mulsd  %xmm2,%xmm0
  addsd  (%rdi),%xmm0
  movsd  %xmm0,(%rdi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    %rdx,%r10
  pxor   %xmm0,%xmm0
  mov    $0x0,%eax
  jmp    L58
```

assistant: ```c
void _inner_vec_ddot(double *y0, int incY, const double *a0, const double *x0, int incX, double alpha, int nC) {
  register int i;
  register double ytmp;
  ytmp = 0.0;
  for (i = 0; i < nC - 3; i += 4) {
    ytmp += a0[0] * x0[0];
    ytmp += a0[1] * x0[incX];
    ytmp += a0[2] * x0[2 * incX];
    ytmp += a0[3] * x0[3 * incX];
    x0 += incX << 2;
    a0 += 4;
  }
  if (i == nC)
    goto update;
  if (i < nC - 1) {
    ytmp += a0[0] * x0[0];
    ytmp += a0[1] * x0[incX];
    x0 += incX << 1;
    a0 += 2;
    i += 2;
  }
  if (i < nC) {
    ytmp += a0[0] * x0[0];
    x0 += incX;
    i++;
  }
update:
  y0[0] += ytmp * alpha;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_inner_vec_ddot>:
  endbr64
  push   %r13
  mov    %rdx,%rax
  mov    %rcx,%r10
  movapd %xmm0,%xmm2
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x3,%r9d
  jle    L33
  lea    -0x4(%r9),%esi
  lea    (%r8,%r8,1),%edx
  pxor   %xmm0,%xmm0
  movslq %r8d,%rbx
  shr    $0x2,%esi
  movslq %edx,%r11
  add    %r8d,%edx
  shl    $0x3,%rbx
  lea    0x1(%rsi),%r13d
  lea    0x0(,%r8,4),%ecx
  movslq %edx,%rdx
  shl    $0x3,%r11
  mov    %r13,%rbp
  movslq %ecx,%rcx
  lea    0x0(,%rdx,8),%r12
  mov    %r13,%rsi
  shl    $0x5,%rbp
  shl    $0x3,%rcx
  mov    %r10,%rdx
  add    %rax,%rbp
  nopl   0x0(%rax)
L58:
  movsd  (%rax),%xmm1
  mulsd  (%rdx),%xmm1
  add    $0x20,%rax
  addsd  %xmm0,%xmm1
  movsd  -0x18(%rax),%xmm0
  mulsd  (%rdx,%rbx,1),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x10(%rax),%xmm1
  mulsd  (%rdx,%r11,1),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rax),%xmm0
  mulsd  (%rdx,%r12,1),%xmm0
  add    %rcx,%rdx
  addsd  %xmm1,%xmm0
  cmp    %rbp,%rax
  jne    L58
  imul   %r13,%rcx
  lea    0x0(,%rsi,4),%eax
  add    %rcx,%r10
L15:
  cmp    %eax,%r9d
  je     L0
  lea    -0x1(%r9),%edx
  cmp    %eax,%edx
  jle    L46
  movsd  0x0(%rbp),%xmm1
  mulsd  (%r10),%xmm1
  movslq %r8d,%rdx
  add    %r8d,%r8d
  movslq %r8d,%r8
  add    $0x10,%rbp
  add    $0x2,%eax
  addsd  %xmm1,%xmm0
  movsd  (%r10,%rdx,8),%xmm1
  mulsd  -0x8(%rbp),%xmm1
  lea    (%r10,%r8,8),%r10
  addsd  %xmm1,%xmm0
L46:
  cmp    %r9d,%eax
  jge    L0
  movsd  0x0(%rbp),%xmm1
  mulsd  (%r10),%xmm1
  addsd  %xmm1,%xmm0
L0:
  mulsd  %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  addsd  (%rdi),%xmm0
  pop    %r12
  pop    %r13
  movsd  %xmm0,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %rdx,%rbp
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
void _inner_vec_ddot(double *y0, int incY, const double *a0, const double *x0, int incX, double alpha, int nC) {
  register int i;
  register double ytmp;
  ytmp = 0.0;
  for (i = 0; i < nC - 3; i += 4) {
    ytmp += a0[0] * x0[0];
    ytmp += a0[1] * x0[incX];
    ytmp += a0[2] * x0[2 * incX];
    ytmp += a0[3] * x0[3 * incX];
    x0 += incX << 2;
    a0 += 4;
  }
  if (i == nC)
    goto update;
  if (i < nC - 1) {
    ytmp += a0[0] * x0[0];
    ytmp += a0[1] * x0[incX];
    x0 += incX << 1;
    a0 += 2;
    i += 2;
  }
  if (i < nC) {
    ytmp += a0[0] * x0[0];
    x0 += incX;
    i++;
  }
update:
  y0[0] += ytmp * alpha;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_inner_vec_ddot>:
  endbr64
  push   %r13
  mov    %rdx,%rax
  mov    %rcx,%r10
  movapd %xmm0,%xmm2
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x3,%r9d
  jle    L1
  lea    -0x4(%r9),%esi
  lea    (%r8,%r8,1),%edx
  pxor   %xmm0,%xmm0
  movslq %r8d,%rbx
  shr    $0x2,%esi
  movslq %edx,%r11
  add    %r8d,%edx
  shl    $0x3,%rbx
  lea    0x1(%rsi),%r13d
  lea    0x0(,%r8,4),%ecx
  movslq %edx,%rdx
  shl    $0x3,%r11
  mov    %r13,%rbp
  movslq %ecx,%rcx
  lea    0x0(,%rdx,8),%r12
  mov    %r13,%rsi
  shl    $0x5,%rbp
  shl    $0x3,%rcx
  mov    %r10,%rdx
  add    %rax,%rbp
  nopl   0x0(%rax)
L26:
  movsd  (%rax),%xmm1
  mulsd  (%rdx),%xmm1
  add    $0x20,%rax
  addsd  %xmm0,%xmm1
  movsd  -0x18(%rax),%xmm0
  mulsd  (%rdx,%rbx,1),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x10(%rax),%xmm1
  mulsd  (%rdx,%r11,1),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rax),%xmm0
  mulsd  (%rdx,%r12,1),%xmm0
  add    %rcx,%rdx
  addsd  %xmm1,%xmm0
  cmp    %rbp,%rax
  jne    L26
  imul   %r13,%rcx
  lea    0x0(,%rsi,4),%eax
  add    %rcx,%r10
L50:
  cmp    %eax,%r9d
  je     L56
  lea    -0x1(%r9),%edx
  cmp    %eax,%edx
  jle    L33
  movsd  0x0(%rbp),%xmm1
  mulsd  (%r10),%xmm1
  movslq %r8d,%rdx
  add    %r8d,%r8d
  movslq %r8d,%r8
  add    $0x10,%rbp
  add    $0x2,%eax
  addsd  %xmm1,%xmm0
  movsd  (%r10,%rdx,8),%xmm1
  mulsd  -0x8(%rbp),%xmm1
  lea    (%r10,%r8,8),%r10
  addsd  %xmm1,%xmm0
L33:
  cmp    %r9d,%eax
  jge    L56
  movsd  0x0(%rbp),%xmm1
  mulsd  (%r10),%xmm1
  addsd  %xmm1,%xmm0
L56:
  mulsd  %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  addsd  (%rdi),%xmm0
  pop    %r12
  pop    %r13
  movsd  %xmm0,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rdx,%rbp
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L50
```

assistant: ```c
void _inner_vec_ddot(double *y0, int incY, const double *a0, const double *x0, int incX, double alpha, int nC) {
  register int i;
  register double ytmp;
  ytmp = 0.0;
  for (i = 0; i < nC - 3; i += 4) {
    ytmp += a0[0] * x0[0];
    ytmp += a0[1] * x0[incX];
    ytmp += a0[2] * x0[2 * incX];
    ytmp += a0[3] * x0[3 * incX];
    x0 += incX << 2;
    a0 += 4;
  }
  if (i == nC)
    goto update;
  if (i < nC - 1) {
    ytmp += a0[0] * x0[0];
    ytmp += a0[1] * x0[incX];
    x0 += incX << 1;
    a0 += 2;
    i += 2;
  }
  if (i < nC) {
    ytmp += a0[0] * x0[0];
    x0 += incX;
    i++;
  }
update:
  y0[0] += ytmp * alpha;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<next_generation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  movl   $0x1,-0x8(%rbp)
  jmp    L35
L37:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L57
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  jmp    L47
L57:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
L47:
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L37
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void next_generation(int *current, int *next, int length) {
  next[0] = 0;
  next[length - 1] = 0;
  for (int i = 1; i < length - 1; i++) {
    if (current[i - 1] == current[i + 1]) {
      next[i] = 0;
    } else {
      next[i] = 1;
    }
  }
  for (int i = 0; i < length - 1; i++) {
    current[i] = next[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<next_generation>:
  endbr64
  mov    %rdi,%rcx
  movl   $0x0,(%rsi)
  movslq %edx,%rax
  movl   $0x0,-0x4(%rsi,%rax,4)
  lea    -0x1(%rdx),%r8d
  cmp    $0x1,%r8d
  jle    L3
  lea    -0x3(%rdx),%edi
  add    $0x2,%rdi
  mov    $0x1,%eax
L23:
  mov    0x4(%rcx,%rax,4),%edx
  cmp    %edx,-0x4(%rcx,%rax,4)
  setne  %dl
  movzbl %dl,%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L23
  mov    $0x0,%eax
L38:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L38
  ret
L3:
  je     L24
L44:
  ret
L24:
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  jmp    L44
```

assistant: ```c
void next_generation(int *current, int *next, int length) {
  next[0] = 0;
  next[length - 1] = 0;
  for (int i = 1; i < length - 1; i++) {
    if (current[i - 1] == current[i + 1]) {
      next[i] = 0;
    } else {
      next[i] = 1;
    }
  }
  for (int i = 0; i < length - 1; i++) {
    current[i] = next[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_generation>:
  endbr64
  mov    %rdi,%rcx
  movslq %edx,%rax
  lea    -0x1(%rdx),%edi
  movl   $0x0,(%rsi)
  movl   $0x0,-0x4(%rsi,%rax,4)
  cmp    $0x1,%edi
  jle    L39
  lea    -0x3(%rdx),%r8d
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0x8(%rcx,%rax,4),%edx
  cmp    %edx,(%rcx,%rax,4)
  setne  %dl
  movzbl %dl,%edx
  mov    %edx,0x4(%rsi,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%r8
  jne    L5
  xor    %eax,%eax
  nop
L8:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L8
  ret
  nop
L39:
  je     L3
  ret
L3:
  mov    (%rsi),%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void next_generation(int *current, int *next, int length) {
  next[0] = 0;
  next[length - 1] = 0;
  for (int i = 1; i < length - 1; i++) {
    if (current[i - 1] == current[i + 1]) {
      next[i] = 0;
    } else {
      next[i] = 1;
    }
  }
  for (int i = 0; i < length - 1; i++) {
    current[i] = next[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x50(%rbp)
  jmp    L11
L79:
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L34:
  cmp    %rdx,%rsp
  je     L19
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L34
L19:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L29
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L29:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L76
L45:
  mov    -0x4c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x4c(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  addl   $0x1,-0x4c(%rbp)
L76:
  mov    -0x4c(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  jl     L45
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <bar@plt>
  mov    %rbx,%rsp
  addl   $0x1,-0x50(%rbp)
L11:
  mov    -0x50(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L79
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void foo(int b) {
  for (int i = 1; i < b; ++i) {
    char buffer[i];
    for (int j = 0; j < i; ++j) {
      buffer[j] = j;
    }
    bar(i, buffer);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L70
  mov    %edi,%r14d
  mov    $0x1,%ebx
  mov    $0x10,%r12d
  jmp    L85
L69:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L50
  orq    $0x0,-0x8(%rsp,%rdx,1)
L50:
  mov    %rsp,%rsi
  test   %ebx,%ebx
  jle    L62
  mov    $0x0,%eax
L5:
  mov    %al,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L5
L62:
  call   <bar@plt>
  mov    %r13,%rsp
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L70
L85:
  mov    %ebx,%edi
  mov    %rsp,%r13
  lea    0xf(%rbx),%rax
  mov    $0x0,%edx
  div    %r12
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L79:
  cmp    %rdx,%rsp
  je     L69
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L79
L70:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int b) {
  for (int i = 1; i < b; ++i) {
    char buffer[i];
    for (int j = 0; j < i; ++j) {
      buffer[j] = j;
    }
    bar(i, buffer);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L43
  movslq %edi,%r12
  mov    $0x1,%ebx
  nopl   (%rax)
L37:
  lea    0xf(%rbx),%rax
  mov    %rsp,%rcx
  mov    %ebx,%edi
  mov    %rsp,%r13
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L11
L54:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L54
L11:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L32
  orq    $0x0,-0x8(%rsp,%rdx,1)
L32:
  mov    %rsp,%rsi
  xor    %eax,%eax
  nop
L48:
  mov    %al,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L48
  call   <bar@plt>
  add    $0x1,%rbx
  mov    %r13,%rsp
  cmp    %r12,%rbx
  jne    L37
L43:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int b) {
  for (int i = 1; i < b; ++i) {
    char buffer[i];
    for (int j = 0; j < i; ++j) {
      buffer[j] = j;
    }
    bar(i, buffer);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<free_formats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L16
  jmp    L25
L11:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <LispFree@plt>
L25:
  subl   $0x1,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <LispFree@plt>
L16:
  nop
  leave
  ret
```

assistant: ```c
void free_formats(char **formats, int num_formats) {
  if (num_formats) {
    while (--num_formats >= 0)
      LispFree(formats[num_formats]);
    LispFree(formats);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_formats>:
  endbr64
  test   %esi,%esi
  je     L21
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  sub    $0x1,%esi
  js     L24
  movslq %esi,%rbx
L0:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    $0x0,%eax
  call   <LispFree@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L0
L24:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <LispFree@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  ret
```

assistant: ```c
void free_formats(char **formats, int num_formats) {
  if (num_formats) {
    while (--num_formats >= 0)
      LispFree(formats[num_formats]);
    LispFree(formats);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_formats>:
  endbr64
  test   %esi,%esi
  je     L29
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  sub    $0x1,%esi
  js     L2
  movslq %esi,%rbx
  nopl   0x0(%rax)
L11:
  mov    0x0(%rbp,%rbx,8),%rdi
  xor    %eax,%eax
  sub    $0x1,%rbx
  call   <LispFree@plt>
  test   %ebx,%ebx
  jns    L11
L2:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <LispFree@plt>
  nopl   0x0(%rax)
L29:
  ret
```

assistant: ```c
void free_formats(char **formats, int num_formats) {
  if (num_formats) {
    while (--num_formats >= 0)
      LispFree(formats[num_formats]);
    LispFree(formats);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<free_formats>:
  endbr64
  test   %esi,%esi
  je     L1
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  sub    $0x1,%esi
  js     L17
  movslq %esi,%rbx
  nopl   0x0(%rax)
L12:
  mov    0x0(%rbp,%rbx,8),%rdi
  xor    %eax,%eax
  sub    $0x1,%rbx
  call   <LispFree@plt>
  test   %ebx,%ebx
  jns    L12
L17:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <LispFree@plt>
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void free_formats(char **formats, int num_formats) {
  if (num_formats) {
    while (--num_formats >= 0)
      LispFree(formats[num_formats]);
    LispFree(formats);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glClear@plt>
  mov    $0x0,%eax
  call   <triangle@plt>
  mov    $0x0,%eax
  call   <glFlush@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void display(void) {
  glClear(GL_COLOR_BUFFER_BIT);
  triangle();
  glFlush();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <glClear@plt>
  mov    $0x0,%eax
  call   <triangle@plt>
  mov    $0x0,%eax
  call   <glFlush@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void display(void) {
  glClear(GL_COLOR_BUFFER_BIT);
  triangle();
  glFlush();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <glClear@plt>
  xor    %eax,%eax
  call   <triangle@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <glFlush@plt>
```

assistant: ```c
void display(void) {
  glClear(GL_COLOR_BUFFER_BIT);
  triangle();
  glFlush();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <glClear@plt>
  xor    %eax,%eax
  call   <triangle@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <glFlush@plt>
```

assistant: ```c
void display(void) {
  glClear(GL_COLOR_BUFFER_BIT);
  triangle();
  glFlush();
}
```