ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gui_keyboard_default_bind>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <gui_keyboard_get_internal_code@plt>
  test   %rax,%rax
  je     L33
  xor    %edi,%edi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <gui_keyboard_search@plt>
  test   %rax,%rax
  je     L5
L29:
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L33:
  xor    %edi,%edi
  mov    %r12,%rsi
  call   <gui_keyboard_search@plt>
  test   %rax,%rax
  je     L9
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  pop    %rbp
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %edi,%edi
  pop    %r12
  pop    %r13
  jmp    10a0 <gui_keyboard_new@plt>
L5:
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <gui_keyboard_new@plt>
  jmp    L29
```

assistant: ```c
void gui_keyboard_default_bind(const char *key, const char *command) {
  struct t_gui_key *ptr_key;
  char *internal_code;
  internal_code = gui_keyboard_get_internal_code(key);
  ptr_key = gui_keyboard_search(NULL, (internal_code) ? internal_code : key);
  if (!ptr_key) {
    gui_keyboard_new(NULL, key, command);
  }
  if (internal_code)
    free(internal_code);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gui_keyboard_default_bind>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <gui_keyboard_get_internal_code@plt>
  test   %rax,%rax
  je     L18
  xor    %edi,%edi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <gui_keyboard_search@plt>
  test   %rax,%rax
  je     L5
L34:
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %edi,%edi
  mov    %r12,%rsi
  call   <gui_keyboard_search@plt>
  test   %rax,%rax
  je     L4
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  pop    %rbp
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %edi,%edi
  pop    %r12
  pop    %r13
  jmp    10a0 <gui_keyboard_new@plt>
L5:
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <gui_keyboard_new@plt>
  jmp    L34
```

assistant: ```c
void gui_keyboard_default_bind(const char *key, const char *command) {
  struct t_gui_key *ptr_key;
  char *internal_code;
  internal_code = gui_keyboard_get_internal_code(key);
  ptr_key = gui_keyboard_search(NULL, (internal_code) ? internal_code : key);
  if (!ptr_key) {
    gui_keyboard_new(NULL, key, command);
  }
  if (internal_code)
    free(internal_code);
}
```
user: Translate the below assembly code into C programming language:

```asm
<recurse_mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dirname@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L11
  mov    -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <recurse_mkdir>
  mov    %eax,-0x1c(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x0,-0x1c(%rbp)
  jns    L35
  mov    -0x1c(%rbp),%eax
  jmp    L23
L35:
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int recurse_mkdir(char *path, int mode) {
  int ret = 0;
  char *cpy = strdup(path);
  char *parent = dirname(cpy);
  struct stat st;
  if (stat(parent, &st) < 0)
    ret = recurse_mkdir(parent, mode);
  free(cpy);
  if (ret < 0)
    return ret;
  return mkdir(path, mode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<recurse_mkdir>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <dirname@plt>
  mov    %rax,%r12
  lea    0x4(%rsp),%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  js     L33
  mov    %rbx,%rdi
  call   <free@plt>
L0:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  mov    %eax,%r12d
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <recurse_mkdir>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <free@plt>
  test   %r12d,%r12d
  js     L29
  jmp    L0
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recurse_mkdir(char *path, int mode) {
  int ret = 0;
  char *cpy = strdup(path);
  char *parent = dirname(cpy);
  struct stat st;
  if (stat(parent, &st) < 0)
    ret = recurse_mkdir(parent, mode);
  free(cpy);
  if (ret < 0)
    return ret;
  return mkdir(path, mode);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<recurse_mkdir>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <dirname@plt>
  lea    0x4(%rsp),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <stat@plt>
  test   %rax,%rax
  js     L31
  mov    %rbp,%rdi
  call   <free@plt>
L25:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <mkdir@plt>
  mov    %eax,%r13d
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L31:
  mov    %r13,%rdi
  mov    %r14d,%esi
  call   <recurse_mkdir>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <free@plt>
  test   %r13d,%r13d
  js     L11
  jmp    L25
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recurse_mkdir(char *path, int mode) {
  int ret = 0;
  char *cpy = strdup(path);
  char *parent = dirname(cpy);
  struct stat st;
  if (stat(parent, &st) < 0)
    ret = recurse_mkdir(parent, mode);
  free(cpy);
  if (ret < 0)
    return ret;
  return mkdir(path, mode);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recurse_mkdir>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <dirname@plt>
  mov    %rsp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <stat@plt>
  test   %rax,%rax
  js     L11
  mov    %rbp,%rdi
  call   <free@plt>
L2:
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <mkdir@plt>
  mov    %eax,%r14d
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %r15,%rdi
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <dirname@plt>
  lea    0x4(%rsp),%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <stat@plt>
  test   %rax,%rax
  js     L42
  mov    %rbx,%rdi
  call   <free@plt>
L21:
  mov    %r15,%rdi
  mov    %r13d,%esi
  call   <mkdir@plt>
  mov    %rbp,%rdi
  mov    %eax,%r14d
  call   <free@plt>
  test   %r14d,%r14d
  js     L0
  jmp    L2
L42:
  mov    %r14,%rdi
  mov    %r13d,%esi
  call   <recurse_mkdir>
  mov    %rbx,%rdi
  mov    %eax,%r14d
  call   <free@plt>
  test   %r14d,%r14d
  jns    L21
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L0
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recurse_mkdir(char *path, int mode) {
  int ret = 0;
  char *cpy = strdup(path);
  char *parent = dirname(cpy);
  struct stat st;
  if (stat(parent, &st) < 0)
    ret = recurse_mkdir(parent, mode);
  free(cpy);
  if (ret < 0)
    return ret;
  return mkdir(path, mode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reassociate_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <freopen@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <child_log@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: Child: Could not reassociate file to %s


assistant: ```c
void reassociate_file(const char *path, const char *mode, FILE *file) {
  if (freopen(path, mode, file) == NULL) {
    child_log("Child: Could not reassociate file to %s\n", path);
    exit(-1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reassociate_file>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <freopen@plt>
  test   %rax,%rax
  je     L10
L17:
  pop    %rbx
  ret
L10:
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <child_log@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: Child: Could not reassociate file to %s


assistant: ```c
void reassociate_file(const char *path, const char *mode, FILE *file) {
  if (freopen(path, mode, file) == NULL) {
    child_log("Child: Could not reassociate file to %s\n", path);
    exit(-1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<reassociate_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <freopen@plt>
  test   %rax,%rax
  je     L0
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <child_log@plt>
  mov    $0xffffffff,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: Child: Could not reassociate file to %s


assistant: ```c
void reassociate_file(const char *path, const char *mode, FILE *file) {
  if (freopen(path, mode, file) == NULL) {
    child_log("Child: Could not reassociate file to %s\n", path);
    exit(-1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reassociate_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <freopen@plt>
  test   %rax,%rax
  je     L8
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <child_log@plt>
  mov    $0xffffffff,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: Child: Could not reassociate file to %s


assistant: ```c
void reassociate_file(const char *path, const char *mode, FILE *file) {
  if (freopen(path, mode, file) == NULL) {
    child_log("Child: Could not reassociate file to %s\n", path);
    exit(-1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x10,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <create_array@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quicksort@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main() {
  int *arr = NULL, size = 16;
  create_array(&arr, size);
  print_array(arr, size);
  quicksort(arr, 0, size - 1);
  print_array(arr, size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rdi
  mov    $0x10,%esi
  call   <create_array@plt>
  mov    $0x10,%esi
  mov    (%rsp),%rdi
  call   <print_array@plt>
  mov    $0xf,%edx
  mov    $0x0,%esi
  mov    (%rsp),%rdi
  call   <quicksort@plt>
  mov    $0x10,%esi
  mov    (%rsp),%rdi
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *arr = NULL, size = 16;
  create_array(&arr, size);
  print_array(arr, size);
  quicksort(arr, 0, size - 1);
  print_array(arr, size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x10,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <create_array@plt>
  mov    (%rsp),%rdi
  mov    $0x10,%esi
  call   <print_array@plt>
  mov    (%rsp),%rdi
  xor    %esi,%esi
  mov    $0xf,%edx
  call   <quicksort@plt>
  mov    (%rsp),%rdi
  mov    $0x10,%esi
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *arr = NULL, size = 16;
  create_array(&arr, size);
  print_array(arr, size);
  quicksort(arr, 0, size - 1);
  print_array(arr, size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x10,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <create_array@plt>
  mov    (%rsp),%rdi
  mov    $0x10,%esi
  call   <print_array@plt>
  mov    (%rsp),%rdi
  xor    %esi,%esi
  mov    $0xf,%edx
  call   <quicksort@plt>
  mov    (%rsp),%rdi
  mov    $0x10,%esi
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *arr = NULL, size = 16;
  create_array(&arr, size);
  print_array(arr, size);
  quicksort(arr, 0, size - 1);
  print_array(arr, size);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lfopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int lfopen(const char *device, int flags) {
  int fd = open(device, flags);
  return fd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lfopen>:
  endbr64
  sub    $0x8,%rsp
  call   <open@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int lfopen(const char *device, int flags) {
  int fd = open(device, flags);
  return fd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lfopen>:
  endbr64
  jmp    1050 <open@plt>
```

assistant: ```c
int lfopen(const char *device, int flags) {
  int fd = open(device, flags);
  return fd;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lfopen>:
  endbr64
  jmp    1050 <open@plt>
```

assistant: ```c
int lfopen(const char *device, int flags) {
  int fd = open(device, flags);
  return fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtokens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L3
  mov    -0x8(%rbp),%rax
  movb   $0x22,(%rax)
L3:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strtokens(char **str) {
  char *s;
  s = *str;
  while (*s) {
    if (*s == '\'')
      *s = '"';
    *s++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strtokens>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L27
L1:
  ret
L38:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L1
L27:
  cmp    $0x27,%dl
  jne    L38
  movb   $0x22,(%rax)
  jmp    L38
```

assistant: ```c
void strtokens(char **str) {
  char *s;
  s = *str;
  while (*s) {
    if (*s == '\'')
      *s = '"';
    *s++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtokens>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L28
  xchg   %ax,%ax
L26:
  cmp    $0x27,%dl
  jne    L8
  movb   $0x22,(%rax)
L8:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L26
L28:
  ret
```

assistant: ```c
void strtokens(char **str) {
  char *s;
  s = *str;
  while (*s) {
    if (*s == '\'')
      *s = '"';
    *s++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtokens>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L7
  xchg   %ax,%ax
L2:
  cmp    $0x27,%dl
  je     L16
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L2
L7:
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  movb   $0x22,(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L2
  ret
```

assistant: ```c
void strtokens(char **str) {
  char *s;
  s = *str;
  while (*s) {
    if (*s == '\'')
      *s = '"';
    *s++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readferetraster>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  lea    D50(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D46(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fopen_with_error@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  lea    D39(%rip),%rax
  mov    %rax,%rdx
  lea    D47(%rip),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <syserr@plt>
L5:
  mov    -0x10(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  test   %eax,%eax
  jne    L29
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <syserr@plt>
L29:
  mov    $0x0,%eax
  call   <isMachineLittleEndian@plt>
  test   %rax,%rax
  je     L28
  mov    -0x2c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <byteswap_4@plt>
L28:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D50
data_type: string
name: read_data
arguments: data_tag: D46
data_type: string
name: read_data
arguments: data_tag: D39
data_type: string
name: read_data
arguments: data_tag: D47
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string

tool: D50: readferetraster

tool: D46: rb

tool: 

tool: D47: malloc of data failed

tool: D4: fread

assistant: ```c
float *readferetraster(const char *fn, int numpix) {
  const char *routine = "readferetraster";
  FILE *fp;
  float *data;
  fp = (FILE *)fopen_with_error(fn, "rb", routine);
  data = (float *)malloc(sizeof(float) * numpix);
  if (!data) {
    syserr("readferetraster", "malloc of data failed", "");
  }
  if (!fread(data, sizeof(float), numpix, fp))
    syserr(routine, fn, "fread");
  if (isMachineLittleEndian())
    byteswap_4(data, numpix);
  fclose(fp);
  return data;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readferetraster>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  lea    D22(%rip),%rdx
  lea    D13(%rip),%rsi
  call   <fopen_with_error@plt>
  mov    %rax,%r12
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
L20:
  mov    %r12,%rcx
  mov    %ebp,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %eax,%eax
  je     L34
L38:
  mov    $0x0,%eax
  call   <isMachineLittleEndian@plt>
  test   %rax,%rax
  jne    L52
L15:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  lea    D47(%rip),%rdx
  lea    D29(%rip),%rsi
  lea    D22(%rip),%rdi
  call   <syserr@plt>
  jmp    L20
L34:
  lea    D33(%rip),%rdx
  mov    %r13,%rsi
  lea    D22(%rip),%rdi
  call   <syserr@plt>
  jmp    L38
L52:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <byteswap_4@plt>
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D47
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D33
type_infered: string

tool: D22: readferetraster

tool: D13: rb

tool: 

tool: D29: malloc of data failed

tool: D33: fread

assistant: ```c
float *readferetraster(const char *fn, int numpix) {
  const char *routine = "readferetraster";
  FILE *fp;
  float *data;
  fp = (FILE *)fopen_with_error(fn, "rb", routine);
  data = (float *)malloc(sizeof(float) * numpix);
  if (!data) {
    syserr("readferetraster", "malloc of data failed", "");
  }
  if (!fread(data, sizeof(float), numpix, fp))
    syserr(routine, fn, "fread");
  if (isMachineLittleEndian())
    byteswap_4(data, numpix);
  fclose(fp);
  return data;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readferetraster>:
  endbr64
  push   %r15
  lea    D17(%rip),%r15
  push   %r14
  mov    %r15,%rdx
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  lea    D49(%rip),%rsi
  call   <fopen_with_error@plt>
  lea    0x0(,%rbp,4),%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L10:
  mov    %r13,%rcx
  mov    %ebp,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  test   %eax,%eax
  je     L57
L51:
  xor    %eax,%eax
  call   <isMachineLittleEndian@plt>
  test   %rax,%rax
  jne    L19
L9:
  mov    %r13,%rdi
  call   <fclose@plt>
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  lea    D26(%rip),%rdx
  lea    D37(%rip),%rsi
  mov    %r15,%rdi
  call   <syserr@plt>
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <byteswap_4@plt>
  jmp    L9
  nopl   0x0(%rax)
L57:
  lea    D8(%rip),%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <syserr@plt>
  jmp    L51
```

tool_calls: name: disassemble_data
arguments: tag: D17
data_type: string
name: disassemble_data
arguments: tag: D49
data_type: string
name: disassemble_data
arguments: tag: D26
data_type: string
name: disassemble_data
arguments: tag: D37
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string

tool: D17: readferetraster

tool: D49: rb

tool: 

tool: D37: malloc of data failed

tool: D8: fread

assistant: ```c
float *readferetraster(const char *fn, int numpix) {
  const char *routine = "readferetraster";
  FILE *fp;
  float *data;
  fp = (FILE *)fopen_with_error(fn, "rb", routine);
  data = (float *)malloc(sizeof(float) * numpix);
  if (!data) {
    syserr("readferetraster", "malloc of data failed", "");
  }
  if (!fread(data, sizeof(float), numpix, fp))
    syserr(routine, fn, "fread");
  if (isMachineLittleEndian())
    byteswap_4(data, numpix);
  fclose(fp);
  return data;
}
```