ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<gen_salt_alloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  lea    0x1(%rbx),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L31
  test   %ebx,%ebx
  jle    L25
  mov    %rax,%r13
  lea    (%rax,%rbx,1),%rbp
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  add    $0x1,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  lea    0x1(%rax,%rdx,1),%eax
  mov    %al,-0x1(%r13)
  cmp    %r13,%rbp
  jne    L39
  add    %r12,%rbx
L24:
  movb   $0x0,(%rbx)
L31:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %rax,%rbx
  jmp    L24
```

assistant: ```c
char *gen_salt_alloc(int count) {
  char *salt = (char *)malloc(count + 1);
  if (salt) {
    int n;
    for (n = 0; n < count; n++)
      salt[n] = (((int)rand()) % 255) + 1;
    salt[n] = 0;
  }
  return salt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vec_insert_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <vec_expand_@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L14
  mov    -0x4(%rbp),%eax
  jmp    L0
L14:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x30(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    (%rdx),%rcx
  mov    -0x30(%rbp),%edx
  imul   -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    -0x18(%rbp),%rdx
  mov    (%rdx),%rcx
  mov    -0x30(%rbp),%edx
  add    $0x1,%edx
  imul   -0x2c(%rbp),%edx
  movslq %edx,%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memmove@plt>
  mov    $0x0,%eax
L0:
  leave
  ret
```

assistant: ```c
int vec_insert_(char **data, int *length, int *capacity, int memsz, int idx) {
  int err = vec_expand_(data, length, capacity, memsz);
  if (err) {
    return err;
  }
  memmove(*data + (idx + 1) * memsz, *data + idx * memsz, (*length - idx) * memsz);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<vec_insert_>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %ecx,%ebx
  mov    %r8d,%r14d
  call   <vec_expand_@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L6
L9:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    0x0(%r13),%rdi
  mov    %ebx,%eax
  imul   %r14d,%eax
  mov    (%r12),%edx
  sub    %r14d,%edx
  imul   %ebx,%edx
  movslq %eax,%rsi
  add    %rdi,%rsi
  add    %ebx,%eax
  cltq
  add    %rax,%rdi
  call   <memmove@plt>
  jmp    L9
```

assistant: ```c
int vec_insert_(char **data, int *length, int *capacity, int memsz, int idx) {
  int err = vec_expand_(data, length, capacity, memsz);
  if (err) {
    return err;
  }
  memmove(*data + (idx + 1) * memsz, *data + idx * memsz, (*length - idx) * memsz);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec_insert_>:
  endbr64
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  call   <vec_expand_@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L6
  mov    %ebx,%eax
  mov    0x0(%rbp),%edx
  mov    0x0(%r13),%rdi
  imul   %r14d,%eax
  sub    %r14d,%edx
  imul   %ebx,%edx
  movslq %eax,%rsi
  add    %ebx,%eax
  cltq
  add    %rdi,%rsi
  add    %rax,%rdi
  call   <memmove@plt>
L6:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int vec_insert_(char **data, int *length, int *capacity, int memsz, int idx) {
  int err = vec_expand_(data, length, capacity, memsz);
  if (err) {
    return err;
  }
  memmove(*data + (idx + 1) * memsz, *data + idx * memsz, (*length - idx) * memsz);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<vec_insert_>:
  endbr64
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  call   <vec_expand_@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L4
  mov    %ebx,%eax
  mov    0x0(%rbp),%edx
  mov    0x0(%r13),%rdi
  imul   %r14d,%eax
  sub    %r14d,%edx
  imul   %ebx,%edx
  movslq %eax,%rsi
  add    %ebx,%eax
  cltq
  add    %rdi,%rsi
  add    %rax,%rdi
  call   <memmove@plt>
L4:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int vec_insert_(char **data, int *length, int *capacity, int memsz, int idx) {
  int err = vec_expand_(data, length, capacity, memsz);
  if (err) {
    return err;
  }
  memmove(*data + (idx + 1) * memsz, *data + idx * memsz, (*length - idx) * memsz);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<h2o_mem_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <h2o__fatal@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/nkmideb/h2o-server/refs/heads/master/include/h2o/memory.h:310:no memory

assistant: ```c
void *h2o_mem_alloc(size_t sz) {
  void *p = malloc(sz);
  if (p == NULL)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/nkmideb/h2o-server/refs/heads/master/include/h2o/memory.h"
               ":"
               "310"
               ":"
               "no memory");
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<h2o_mem_alloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
L3:
  mov    %rbx,%rax
  pop    %rbx
  ret
L9:
  lea    D6(%rip),%rdi
  call   <h2o__fatal@plt>
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/nkmideb/h2o-server/refs/heads/master/include/h2o/memory.h:310:no memory

assistant: ```c
void *h2o_mem_alloc(size_t sz) {
  void *p = malloc(sz);
  if (p == NULL)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/nkmideb/h2o-server/refs/heads/master/include/h2o/memory.h"
               ":"
               "310"
               ":"
               "no memory");
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<h2o_mem_alloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
L1:
  mov    %r12,%rax
  pop    %r12
  ret
L4:
  lea    D6(%rip),%rdi
  call   <h2o__fatal@plt>
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/nkmideb/h2o-server/refs/heads/master/include/h2o/memory.h:310:no memory

assistant: ```c
void *h2o_mem_alloc(size_t sz) {
  void *p = malloc(sz);
  if (p == NULL)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/nkmideb/h2o-server/refs/heads/master/include/h2o/memory.h"
               ":"
               "310"
               ":"
               "no memory");
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<h2o_mem_alloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L10:
  mov    %r12,%rax
  pop    %r12
  ret
L7:
  lea    D2(%rip),%rdi
  call   <h2o__fatal@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/nkmideb/h2o-server/refs/heads/master/include/h2o/memory.h:310:no memory

assistant: ```c
void *h2o_mem_alloc(size_t sz) {
  void *p = malloc(sz);
  if (p == NULL)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/nkmideb/h2o-server/refs/heads/master/include/h2o/memory.h"
               ":"
               "310"
               ":"
               "no memory");
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<acosl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  fldt   0xed5(%rip)        # 2000 <_fini+0xeac>
  fstpt  -0x10(%rbp)
  fldt   -0x10(%rbp)
  fldt   0xed9(%rip)        # 2010 <_fini+0xebc>
  fdivrp %st,%st(1)
  fstpt  -0x20(%rbp)
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <asinl@plt>
  add    $0x10,%rsp
  fldt   -0x20(%rbp)
  fsubp  %st,%st(1)
  leave
  ret
```

assistant: ```c
long double acosl(long double x) {
  long double pi;
  pi = 3.14159265358979;
  return (pi / 2) - asinl(x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<acosl>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <asinl@plt>
  fsubrl 0xecc(%rip)        # 2000 <_fini+0xec4>
  add    $0x18,%rsp
  ret
```

assistant: ```c
long double acosl(long double x) {
  long double pi;
  pi = 3.14159265358979;
  return (pi / 2) - asinl(x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<acosl>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <asinl@plt>
  fsubrl 0xec5(%rip)        # 2000 <_fini+0xec0>
  add    $0x18,%rsp
  ret
```

assistant: ```c
long double acosl(long double x) {
  long double pi;
  pi = 3.14159265358979;
  return (pi / 2) - asinl(x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<acosl>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <asinl@plt>
  fsubrl 0xec5(%rip)        # 2000 <_fini+0xec0>
  add    $0x18,%rsp
  ret
```

assistant: ```c
long double acosl(long double x) {
  long double pi;
  pi = 3.14159265358979;
  return (pi / 2) - asinl(x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<divisao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L2
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %eax,%edx
  jmp    L1
L2:
  mov    $0x0,%edx
L1:
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void divisao(void *num1, void *num2) {
  int *pnum1 = (int *)num1;
  int *pnum2 = (int *)num2;
  *pnum2 = *pnum2 == 0 ? 0 : *pnum1 / *pnum2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<divisao>:
  endbr64
  mov    (%rsi),%ecx
  test   %ecx,%ecx
  je     L0
  mov    (%rdi),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ecx
L0:
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void divisao(void *num1, void *num2) {
  int *pnum1 = (int *)num1;
  int *pnum2 = (int *)num2;
  *pnum2 = *pnum2 == 0 ? 0 : *pnum1 / *pnum2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<divisao>:
  endbr64
  mov    (%rsi),%ecx
  test   %ecx,%ecx
  je     L8
  mov    (%rdi),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ecx
L8:
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void divisao(void *num1, void *num2) {
  int *pnum1 = (int *)num1;
  int *pnum2 = (int *)num2;
  *pnum2 = *pnum2 == 0 ? 0 : *pnum1 / *pnum2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<divisao>:
  endbr64
  mov    (%rsi),%ecx
  test   %ecx,%ecx
  je     L1
  mov    (%rdi),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ecx
L1:
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void divisao(void *num1, void *num2) {
  int *pnum1 = (int *)num1;
  int *pnum2 = (int *)num2;
  *pnum2 = *pnum2 == 0 ? 0 : *pnum1 / *pnum2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zip_is_intranet2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L104
  mov    $0x0,%eax
  jmp    L128
L104:
  mov    -0x18(%rbp),%rax
  mov    $0x4,%edx
  lea    D28(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L21
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L21
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L34
L21:
  mov    $0x1,%eax
  jmp    L128
L34:
  mov    -0x18(%rbp),%rax
  mov    $0x4,%edx
  lea    D18(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L22
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L22
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xf,-0x4(%rbp)
  jle    L22
  cmpl   $0x1f,-0x4(%rbp)
  jg     L22
  mov    $0x1,%eax
  jmp    L128
L22:
  mov    $0x0,%eax
L128:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D28
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string

tool: D28: 127.

tool: D0: 10.

tool: D4: 192.168.

tool: D18: 172.

assistant: ```c
int zip_is_intranet2(const char *ip) {
  if (!ip) {
    return 0;
  }
  if ((!strncmp(ip, "127.", 4)) || (!strncmp(ip, "10.", 3)) || (!strncmp(ip, "192.168.", 8))) {
    return 1;
  }
  if ((!strncmp(ip, "172.", 4)) && ip[4] && ip[5] && (ip[6] == '.')) {
    int a = (ip[4] - '0') * 10 + (ip[5] - '0');
    if ((a > 15) && (a < 32)) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zip_is_intranet2>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L59
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  lea    D16(%rip),%rsi
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L9
L29:
  pop    %rbx
  ret
L9:
  mov    $0x3,%edx
  lea    D26(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L29
  mov    $0x8,%edx
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L29
  mov    $0x4,%edx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L31
  movzbl 0x4(%rbx),%edx
  test   %dl,%dl
  je     L29
  movzbl 0x5(%rbx),%ecx
  test   %cl,%cl
  je     L29
  cmpb   $0x2e,0x6(%rbx)
  jne    L29
  movsbl %dl,%edx
  lea    -0xf0(%rdx,%rdx,4),%eax
  movsbl %cl,%ecx
  lea    -0x40(%rcx,%rax,2),%eax
  cmp    $0xf,%eax
  setbe  %al
  movzbl %al,%eax
  jmp    L29
L31:
  mov    $0x0,%eax
  jmp    L29
L59:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
data_type: string
name: retrieve_data
arguments: data_tag: D26
data_type: string
name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D16: 127.

tool: D26: 10.

tool: D14: 192.168.

tool: D8: 172.

assistant: ```c
int zip_is_intranet2(const char *ip) {
  if (!ip) {
    return 0;
  }
  if ((!strncmp(ip, "127.", 4)) || (!strncmp(ip, "10.", 3)) || (!strncmp(ip, "192.168.", 8))) {
    return 1;
  }
  if ((!strncmp(ip, "172.", 4)) && ip[4] && ip[5] && (ip[6] == '.')) {
    int a = (ip[4] - '0') * 10 + (ip[5] - '0');
    if ((a > 15) && (a < 32)) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zip_is_intranet2>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %rbx
  mov    $0x4,%edx
  lea    D16(%rip),%rsi
  mov    %rdi,%rbx
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L37
L24:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L37:
  mov    $0x3,%edx
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L24
  mov    $0x8,%edx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L24
  mov    $0x4,%edx
  lea    D34(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L1
  movsbl 0x4(%rbx),%eax
  test   %al,%al
  je     L1
  movsbl 0x5(%rbx),%edx
  test   %dl,%dl
  je     L1
  cmpb   $0x2e,0x6(%rbx)
  jne    L1
  lea    -0xf0(%rax,%rax,4),%eax
  pop    %rbx
  lea    -0x40(%rdx,%rax,2),%eax
  cmp    $0xf,%eax
  setbe  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D16
datatype: string
name: read_data
arguments: tag: D28
datatype: string
name: read_data
arguments: tag: D9
datatype: string
name: read_data
arguments: tag: D34
datatype: string

tool: D16: 127.

tool: D28: 10.

tool: D9: 192.168.

tool: D34: 172.

assistant: ```c
int zip_is_intranet2(const char *ip) {
  if (!ip) {
    return 0;
  }
  if ((!strncmp(ip, "127.", 4)) || (!strncmp(ip, "10.", 3)) || (!strncmp(ip, "192.168.", 8))) {
    return 1;
  }
  if ((!strncmp(ip, "172.", 4)) && ip[4] && ip[5] && (ip[6] == '.')) {
    int a = (ip[4] - '0') * 10 + (ip[5] - '0');
    if ((a > 15) && (a < 32)) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<zip_is_intranet2>:
  endbr64
  test   %rdi,%rdi
  je     L40
  push   %rbx
  mov    $0x4,%edx
  lea    D22(%rip),%rsi
  mov    %rdi,%rbx
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L26
L61:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L26:
  mov    $0x3,%edx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L61
  mov    $0x8,%edx
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L61
  mov    $0x4,%edx
  lea    D33(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L68
  movsbl 0x4(%rbx),%eax
  test   %al,%al
  je     L68
  movsbl 0x5(%rbx),%edx
  test   %dl,%dl
  je     L68
  cmpb   $0x2e,0x6(%rbx)
  jne    L68
  lea    -0xf0(%rax,%rax,4),%eax
  pop    %rbx
  lea    -0x40(%rdx,%rax,2),%eax
  cmp    $0xf,%eax
  setbe  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L68:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D22
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D33
data_type: string

tool: D22: 127.

tool: D4: 10.

tool: D15: 192.168.

tool: D33: 172.

assistant: ```c
int zip_is_intranet2(const char *ip) {
  if (!ip) {
    return 0;
  }
  if ((!strncmp(ip, "127.", 4)) || (!strncmp(ip, "10.", 3)) || (!strncmp(ip, "192.168.", 8))) {
    return 1;
  }
  if ((!strncmp(ip, "172.", 4)) && ip[4] && ip[5] && (ip[6] == '.')) {
    int a = (ip[4] - '0') * 10 + (ip[5] - '0');
    if ((a > 15) && (a < 32)) {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<editDist>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,0x4(%rsp)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    0x4(,%rax,4),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,0x20(%rsp)
  test   %r13d,%r13d
  js     L17
  lea    0x1(%r13),%ecx
  mov    $0x0,%eax
L4:
  mov    0x18(%rsp),%rdx
  mov    %eax,(%rdx,%rax,4)
  mov    0x20(%rsp),%rdx
  mov    %eax,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L4
L17:
  cmpl   $0x0,0x4(%rsp)
  jle    L56
  movl   $0x1,(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L30
L101:
  mov    0x18(%rsp),%rax
  mov    (%rax,%rbx,1),%r15d
  mov    0x20(%rsp),%rdx
  mov    (%rdx,%rbx,1),%esi
  mov    0x4(%rax,%rbx,1),%edi
  call   <min@plt>
  mov    %eax,%edi
  mov    %r15d,%esi
  call   <min@plt>
  add    $0x1,%eax
  mov    0x20(%rsp),%rdx
  mov    %eax,0x4(%rdx,%rbx,1)
L105:
  add    $0x1,%rbp
  add    $0x4,%rbx
  cmp    %ebp,%r13d
  jl     L93
L20:
  movzbl -0x1(%r14,%rbp,1),%eax
  cmp    %al,(%r12)
  jne    L101
  mov    0x18(%rsp),%rax
  mov    (%rax,%rbx,1),%edx
  mov    0x20(%rsp),%rax
  mov    %edx,0x4(%rax,%rbx,1)
  jmp    L105
L93:
  lea    0x18(%rsp),%rdi
  mov    0x8(%rsp),%rsi
  call   <swap@plt>
  addl   $0x1,(%rsp)
  mov    (%rsp),%eax
  add    $0x1,%r12
  cmp    %eax,0x4(%rsp)
  jl     L56
L30:
  mov    0x20(%rsp),%rax
  mov    (%rsp),%ecx
  mov    %ecx,(%rax)
  test   %r13d,%r13d
  jle    L93
  mov    $0x0,%ebx
  mov    $0x1,%ebp
  jmp    L20
L56:
  mov    0x18(%rsp),%rdi
  movslq %r13d,%r13
  mov    (%rdi,%r13,4),%ebx
  call   <free@plt>
  mov    0x20(%rsp),%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %ebx,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int editDist(char *word1, char *word2) {
  int word1_len = strlen(word1);
  int word2_len = strlen(word2);
  int *oldDist = (int *)malloc((word2_len + 1) * sizeof(int));
  int *curDist = (int *)malloc((word2_len + 1) * sizeof(int));
  int i, j, dist;
  for (i = 0; i < word2_len + 1; i++) {
    oldDist[i] = i;
    curDist[i] = i;
  }
  for (i = 1; i < word1_len + 1; i++) {
    curDist[0] = i;
    for (j = 1; j < word2_len + 1; j++) {
      if (word1[i - 1] == word2[j - 1]) {
        curDist[j] = oldDist[j - 1];
      } else {
        curDist[j] = min(min(oldDist[j], curDist[j - 1]), oldDist[j - 1]) + 1;
      }
    }
    swap(&oldDist, &curDist);
  }
  dist = oldDist[word2_len];
  free(oldDist);
  free(curDist);
  return dist;
}
```