ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_is_empty>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L18
  add    $0x1,%rbx
  cmpb   $0x20,-0x1(%rbp,%rbx,1)
  je     L13
  mov    $0x0,%eax
  jmp    L29
L18:
  mov    $0x1,%eax
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool string_is_empty(char *str) {
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] != ' ')
      return false;
  }
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_is_empty>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L9
  nopl   0x0(%rax)
L5:
  add    $0x1,%rbx
  cmpb   $0x20,-0x1(%rbp,%rbx,1)
  jne    L29
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L5
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool string_is_empty(char *str) {
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] != ' ')
      return false;
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<string_is_empty>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L12
  nopl   0x0(%rax)
L14:
  add    $0x1,%rbx
  cmpb   $0x20,-0x1(%rbp,%rbx,1)
  jne    L7
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L14
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool string_is_empty(char *str) {
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] != ' ')
      return false;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  sub    %edx,%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x30(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L49
L19:
  movl   $0x0,-0x1c(%rbp)
  jmp    L3
L6:
  mov    -0x1c(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0xffffff,%eax
  cmp    %eax,-0x34(%rbp)
  je     L28
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%esi
  mov    -0x20(%rbp),%eax
  and    $0x7,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    %esi,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L28:
  addl   $0x1,-0x1c(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L6
  addl   $0x1,-0x20(%rbp)
L49:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *create_mask(unsigned char *data, int width, int height, unsigned int mask_color) {
  unsigned int *pixels = (unsigned int *)data;
  int id;
  int i, j;
  unsigned char *mask;
  int scanline = width + (8 - width % 8) % 8;
  mask = calloc((scanline * height) / 8, 1);
  for (i = 0; i < width; i++) {
    for (j = 0; j < height; j++) {
      id = (i + j * scanline) / 8;
      if ((pixels[i + j * width] & 0xffffff) != mask_color) {
        mask[id] |= 1 << (i % 8);
      }
    }
  }
  return mask;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_mask>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    (%rsi,%rax,1),%edx
  and    $0x7,%edx
  sub    %edx,%eax
  lea    0x8(%rax),%eax
  cltd
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ebp
  and    $0x7,%ebp
  sub    %edx,%ebp
  add    %esi,%ebp
  mov    %ebp,%eax
  imul   %ebx,%eax
  lea    0x7(%rax),%edi
  test   %eax,%eax
  cmovns %eax,%edi
  sar    $0x3,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  test   %r13d,%r13d
  jle    L19
  mov    %r14,%r10
  movslq %r13d,%r8
  shl    $0x2,%r8
  mov    $0x0,%r9d
  mov    $0x1,%r11d
  jmp    L8
L20:
  lea    0x7(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x3,%eax
  cltq
  or     %r14b,(%rdi,%rax,1)
L12:
  add    $0x1,%ecx
  add    %r8,%rsi
  add    %ebp,%edx
  cmp    %ecx,%ebx
  je     L29
L79:
  mov    (%rsi),%eax
  and    $0xffffff,%eax
  cmp    %r12d,%eax
  jne    L20
  jmp    L12
L29:
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %r9d,%r13d
  je     L19
L8:
  test   %ebx,%ebx
  jle    L29
  mov    %r9d,%ecx
  and    $0x7,%ecx
  mov    %r11d,%r14d
  shl    %cl,%r14d
  mov    %r9d,%edx
  mov    %r10,%rsi
  mov    $0x0,%ecx
  jmp    L79
L19:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char *create_mask(unsigned char *data, int width, int height, unsigned int mask_color) {
  unsigned int *pixels = (unsigned int *)data;
  int id;
  int i, j;
  unsigned char *mask;
  int scanline = width + (8 - width % 8) % 8;
  mask = calloc((scanline * height) / 8, 1);
  for (i = 0; i < width; i++) {
    for (j = 0; j < height; j++) {
      id = (i + j * scanline) / 8;
      if ((pixels[i + j * width] & 0xffffff) != mask_color) {
        mask[id] |= 1 << (i % 8);
      }
    }
  }
  return mask;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<create_mask>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  neg    %ebp
  push   %rbx
  mov    %edx,%ebx
  and    $0x7,%ebp
  add    %esi,%ebp
  mov    $0x1,%esi
  mov    %ebp,%eax
  imul   %edx,%eax
  test   %eax,%eax
  lea    0x7(%rax),%edi
  cmovns %eax,%edi
  sar    $0x3,%edi
  call   <calloc@plt>
  mov    %rax,%r8
  test   %r13d,%r13d
  jle    L8
  movslq %r13d,%rdi
  mov    %r14,%r10
  xor    %r9d,%r9d
  mov    $0x1,%r11d
  shl    $0x2,%rdi
  nopl   (%rax)
L26:
  test   %ebx,%ebx
  jle    L43
  mov    %r9d,%ecx
  mov    %r11d,%r14d
  mov    %r9d,%edx
  mov    %r10,%rsi
  and    $0x7,%ecx
  shl    %cl,%r14d
  xor    %ecx,%ecx
L20:
  mov    (%rsi),%eax
  and    $0xffffff,%eax
  cmp    %r12d,%eax
  je     L24
  test   %edx,%edx
  lea    0x7(%rdx),%eax
  cmovns %edx,%eax
  sar    $0x3,%eax
  cltq
  or     %r14b,(%r8,%rax,1)
L24:
  add    $0x1,%ecx
  add    %rdi,%rsi
  add    %ebp,%edx
  cmp    %ecx,%ebx
  jne    L20
L43:
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %r9d,%r13d
  jne    L26
L8:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char *create_mask(unsigned char *data, int width, int height, unsigned int mask_color) {
  unsigned int *pixels = (unsigned int *)data;
  int id;
  int i, j;
  unsigned char *mask;
  int scanline = width + (8 - width % 8) % 8;
  mask = calloc((scanline * height) / 8, 1);
  for (i = 0; i < width; i++) {
    for (j = 0; j < height; j++) {
      id = (i + j * scanline) / 8;
      if ((pixels[i + j * width] & 0xffffff) != mask_color) {
        mask[id] |= 1 << (i % 8);
      }
    }
  }
  return mask;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<create_mask>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  neg    %ebx
  and    $0x7,%ebx
  add    %esi,%ebx
  mov    $0x1,%esi
  mov    %ebx,%eax
  imul   %edx,%eax
  test   %eax,%eax
  lea    0x7(%rax),%edi
  cmovns %eax,%edi
  sar    $0x3,%edi
  call   <calloc@plt>
  mov    %rax,%r8
  test   %r13d,%r13d
  jle    L49
  test   %ebp,%ebp
  jle    L49
  movslq %r13d,%rdi
  mov    %r14,%r10
  xor    %r9d,%r9d
  mov    $0x1,%r11d
  shl    $0x2,%rdi
  nopl   0x0(%rax)
L21:
  mov    %r9d,%ecx
  mov    %r11d,%r14d
  mov    %r9d,%edx
  mov    %r10,%rsi
  and    $0x7,%ecx
  shl    %cl,%r14d
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L27:
  mov    (%rsi),%eax
  and    $0xffffff,%eax
  cmp    %r12d,%eax
  je     L35
  test   %edx,%edx
  lea    0x7(%rdx),%eax
  cmovns %edx,%eax
  sar    $0x3,%eax
  cltq
  or     %r14b,(%r8,%rax,1)
L35:
  add    $0x1,%ecx
  add    %rdi,%rsi
  add    %ebx,%edx
  cmp    %ecx,%ebp
  jne    L27
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %r9d,%r13d
  jne    L21
L49:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char *create_mask(unsigned char *data, int width, int height, unsigned int mask_color) {
  unsigned int *pixels = (unsigned int *)data;
  int id;
  int i, j;
  unsigned char *mask;
  int scanline = width + (8 - width % 8) % 8;
  mask = calloc((scanline * height) / 8, 1);
  for (i = 0; i < width; i++) {
    for (j = 0; j < height; j++) {
      id = (i + j * scanline) / 8;
      if ((pixels[i + j * width] & 0xffffff) != mask_color) {
        mask[id] |= 1 << (i % 8);
      }
    }
  }
  return mask;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<block_sigterm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void block_sigterm(sigset_t *oldset) {
  sigset_t sigset;
  sigemptyset(&sigset);
  sigaddset(&sigset, SIGTERM);
  sigprocmask(SIG_BLOCK, &sigset, oldset);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<block_sigterm>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <sigemptyset@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void block_sigterm(sigset_t *oldset) {
  sigset_t sigset;
  sigemptyset(&sigset);
  sigaddset(&sigset, SIGTERM);
  sigprocmask(SIG_BLOCK, &sigset, oldset);
}
```
user: What is the c source code of the assembly code below:

```asm
<block_sigterm>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    D14(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D4(%rip),%rax
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void block_sigterm(sigset_t *oldset) {
  sigset_t sigset;
  sigemptyset(&sigset);
  sigaddset(&sigset, SIGTERM);
  sigprocmask(SIG_BLOCK, &sigset, oldset);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<block_sigterm>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    D3(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D19(%rip),%rax
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void block_sigterm(sigset_t *oldset) {
  sigset_t sigset;
  sigemptyset(&sigset);
  sigaddset(&sigset, SIGTERM);
  sigprocmask(SIG_BLOCK, &sigset, oldset);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<s_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *s_malloc(size_t len) {
  void *ptr = malloc(len);
  assert(ptr);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<s_malloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *s_malloc(size_t len) {
  void *ptr = malloc(len);
  assert(ptr);
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *s_malloc(size_t len) {
  void *ptr = malloc(len);
  assert(ptr);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *s_malloc(size_t len) {
  void *ptr = malloc(len);
  assert(ptr);
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<OPENSSL_strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L22
L11:
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x18(%rbp)
L22:
  cmpq   $0x0,-0x28(%rbp)
  je     L0
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
L0:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <OPENSSL_strlcpy@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
size_t OPENSSL_strlcat(char *dst, const char *src, size_t size) {
  size_t l = 0;
  for (; size > 0 && *dst; size--, dst++)
    l++;
  return l + OPENSSL_strlcpy(dst, src, size);
}
```
user: What is the c source code of the assembly code below:

```asm
<OPENSSL_strlcat>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L8
L25:
  mov    %rbx,%rdx
  sub    %rax,%rdx
  cmpb   $0x0,(%rdi)
  je     L12
  add    $0x1,%rax
  add    $0x1,%rdi
  cmp    %rax,%rbx
  jne    L25
  mov    $0x0,%edx
  jmp    L8
L12:
  mov    %rax,%rbx
L8:
  call   <OPENSSL_strlcpy@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t OPENSSL_strlcat(char *dst, const char *src, size_t size) {
  size_t l = 0;
  for (; size > 0 && *dst; size--, dst++)
    l++;
  return l + OPENSSL_strlcpy(dst, src, size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<OPENSSL_strlcat>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jne    L35
  jmp    L33
  nopl   0x0(%rax)
L3:
  add    $0x1,%rax
  add    $0x1,%rdi
  cmp    %rax,%rbx
  je     L33
L35:
  mov    %rbx,%rdx
  sub    %rax,%rdx
  cmpb   $0x0,(%rdi)
  jne    L3
  mov    %rax,%rbx
  call   <OPENSSL_strlcpy@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L33:
  xor    %edx,%edx
  call   <OPENSSL_strlcpy@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t OPENSSL_strlcat(char *dst, const char *src, size_t size) {
  size_t l = 0;
  for (; size > 0 && *dst; size--, dst++)
    l++;
  return l + OPENSSL_strlcpy(dst, src, size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<OPENSSL_strlcat>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jne    L14
  jmp    L6
  nopl   0x0(%rax)
L3:
  add    $0x1,%rax
  add    $0x1,%rdi
  cmp    %rax,%rbx
  je     L6
L14:
  mov    %rbx,%rdx
  sub    %rax,%rdx
  cmpb   $0x0,(%rdi)
  jne    L3
  mov    %rax,%rbx
  call   <OPENSSL_strlcpy@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L6:
  xor    %edx,%edx
  call   <OPENSSL_strlcpy@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t OPENSSL_strlcat(char *dst, const char *src, size_t size) {
  size_t l = 0;
  for (; size > 0 && *dst; size--, dst++)
    l++;
  return l + OPENSSL_strlcpy(dst, src, size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<trap_eflags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <_sys_printf@plt>
L3:
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: trap


assistant: ```c
void trap_eflags() {
  _sys_printf("trap\n");
  for (;;) {
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trap_eflags>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <_sys_printf@plt>
L2:
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: trap


assistant: ```c
void trap_eflags() {
  _sys_printf("trap\n");
  for (;;) {
  };
}
```
user: What is the c source code of the assembly code below?

```asm
<trap_eflags>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <_sys_printf@plt>
L1:
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: trap


assistant: ```c
void trap_eflags() {
  _sys_printf("trap\n");
  for (;;) {
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trap_eflags>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <_sys_printf@plt>
L2:
  jmp    L2
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: trap


assistant: ```c
void trap_eflags() {
  _sys_printf("trap\n");
  for (;;) {
  };
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcstoimax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L125
L14:
  addq   $0x1,-0x18(%rbp)
L125:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswspace@plt>
  test   %rax,%rax
  jne    L14
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L100
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L112
L100:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L112
  addq   $0x1,-0x18(%rbp)
L112:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstoumax@plt>
  mov    %eax,-0x4(%rbp)
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L93
  cmpl   $0x0,-0x8(%rbp)
  je     L10
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    D53(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L47
L10:
  mov    D59(%rip),%rax
  mov    (%rax),%edx
  mov    D50(%rip),%rax
  mov    %edx,(%rax)
L47:
  cmpl   $0x0,-0x8(%rbp)
  je     L78
  mov    D53(%rip),%rax
  mov    (%rax),%eax
  jmp    L16
L78:
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  jmp    L16
L93:
  cmpl   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  neg    %eax
  jmp    L16
L15:
  mov    -0x4(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
intmax_t wcstoimax(const wchar_t *s, wchar_t **p, int base) {
  int sign = 0;
  uintmax_t x;
  for (; iswspace(*s); s++)
    ;
  if (*s == '-')
    sign = *s++;
  else if (*s == '+')
    s++;
  x = wcstoumax(s, p, base);
  if (x > INTMAX_MAX) {
    if (!sign || -x != INTMAX_MIN)
      errno = ERANGE;
    return sign ? INTMAX_MIN : INTMAX_MAX;
  }
  return sign ? -x : x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wcstoimax>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  jmp    L48
L16:
  add    $0x1,%rbx
L48:
  movsbl (%rbx),%edi
  call   <iswspace@plt>
  test   %rax,%rax
  jne    L16
  movzbl (%rbx),%eax
  cmp    $0x2d,%al
  je     L76
  cmp    $0x2b,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <wcstoumax@plt>
  mov    D49(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jg     L10
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L76:
  lea    0x1(%rbx),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <wcstoumax@plt>
  mov    D49(%rip),%rdx
  cmp    (%rdx),%eax
  jg     L11
  neg    %eax
  jmp    L59
L11:
  mov    D57(%rip),%rdx
  add    (%rdx),%eax
  je     L21
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D32(%rip),%rax
  mov    %edx,(%rax)
L21:
  mov    D57(%rip),%rax
  mov    (%rax),%eax
  jmp    L59
L10:
  mov    D11(%rip),%rax
  mov    (%rax),%ecx
  mov    D32(%rip),%rax
  mov    %ecx,(%rax)
  mov    %edx,%eax
  jmp    L59
```

assistant: ```c
intmax_t wcstoimax(const wchar_t *s, wchar_t **p, int base) {
  int sign = 0;
  uintmax_t x;
  for (; iswspace(*s); s++)
    ;
  if (*s == '-')
    sign = *s++;
  else if (*s == '+')
    s++;
  x = wcstoumax(s, p, base);
  if (x > INTMAX_MAX) {
    if (!sign || -x != INTMAX_MIN)
      errno = ERANGE;
    return sign ? INTMAX_MIN : INTMAX_MAX;
  }
  return sign ? -x : x;
}
```