ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_check_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L17:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  cmpl   $0x2,-0x4(%rbp)
  jg     L23
  mov    $0x0,%eax
  jmp    L32
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x73,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L22
L5:
  mov    $0x0,%eax
  jmp    L32
L22:
  mov    $0x1,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
int ft_check_type(char *name) {
  int i;
  i = 0;
  while (name[i])
    i++;
  if (i <= 2)
    return (0);
  if (name[i - 1] != 's' || name[i - 2] != '.')
    return (0);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_check_type>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L32
  mov    $0x1,%eax
L16:
  mov    %eax,%ecx
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L16
  mov    $0x0,%eax
  cmp    $0x2,%ecx
  jle    L22
  cmpb   $0x73,-0x1(%rdi,%rdx,1)
  jne    L22
  cmpb   $0x2e,-0x2(%rdi,%rdx,1)
  sete   %al
  movzbl %al,%eax
  ret
L32:
  mov    $0x0,%eax
L22:
  ret
```

assistant: ```c
int ft_check_type(char *name) {
  int i;
  i = 0;
  while (name[i])
    i++;
  if (i <= 2)
    return (0);
  if (name[i - 1] != 's' || name[i - 2] != '.')
    return (0);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_check_type>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L39
  mov    $0x1,%eax
  xchg   %ax,%ax
L18:
  mov    %eax,%ecx
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L18
  xor    %eax,%eax
  cmp    $0x2,%ecx
  jle    L21
  cmpb   $0x73,-0x1(%rdi,%rdx,1)
  je     L27
L21:
  ret
  nop
L27:
  xor    %eax,%eax
  cmpb   $0x2e,-0x2(%rdi,%rdx,1)
  sete   %al
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_check_type(char *name) {
  int i;
  i = 0;
  while (name[i])
    i++;
  if (i <= 2)
    return (0);
  if (name[i - 1] != 's' || name[i - 2] != '.')
    return (0);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_check_type>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L22
  mov    $0x1,%eax
  xchg   %ax,%ax
L12:
  mov    %eax,%ecx
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L12
  xor    %eax,%eax
  cmp    $0x2,%ecx
  jle    L5
  cmpb   $0x73,-0x1(%rdi,%rdx,1)
  je     L2
L5:
  ret
  nop
L2:
  xor    %eax,%eax
  cmpb   $0x2e,-0x2(%rdi,%rdx,1)
  sete   %al
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_check_type(char *name) {
  int i;
  i = 0;
  while (name[i])
    i++;
  if (i <= 2)
    return (0);
  if (name[i - 1] != 's' || name[i - 2] != '.')
    return (0);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int x;
  x = 2;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int x;
  x = 2;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int x;
  x = 2;
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int x;
  x = 2;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<string_array_append>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L38
L31:
  addq   $0x8,-0x20(%rbp)
L38:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L31
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  add    $0x9,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xxrealloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x38(%rbp),%rax
  add    $0x8,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L33
L34:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x8,-0x20(%rbp)
L33:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L34
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memmove@plt>
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **string_array_append(char **oarray, char *str) {
  char **narray, **tmp;
  for (tmp = oarray; *tmp; tmp++)
    ;
  tmp++;
  size_t olength = *((size_t *)tmp);
  size_t nlength = olength + strlen(str) + 1 + sizeof(char *);
  narray = xxrealloc(oarray, nlength);
  ptrdiff_t offset = ((void *)narray) - ((void *)oarray) + sizeof(char *);
  for (tmp = narray; *tmp; tmp++)
    *tmp = ((void *)*tmp) + offset;
  *tmp = (char *)(((void *)narray) + olength + sizeof(char *));
  strcpy(*tmp, str);
  tmp++;
  memmove(((void *)tmp) + sizeof(char *), tmp, olength - (((void *)tmp) - ((void *)narray)));
  *tmp = NULL;
  tmp++;
  *((size_t *)tmp) = nlength;
  return narray;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_array_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  cmpq   $0x0,(%rdi)
  je     L36
  mov    %rdi,%rax
L44:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L44
L8:
  mov    0x8(%rax),%r12
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x9(%r12,%rax,1),%r14
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <xxrealloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdx
  sub    %rbx,%rdx
  add    $0x8,%edx
  mov    (%rax),%rax
  test   %rax,%rax
  je     L9
  mov    %rbp,%rbx
  movslq %edx,%rdx
L13:
  add    %rdx,%rax
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L13
L24:
  lea    0x8(%rbp,%r12,1),%rdi
  mov    %rdi,(%rbx)
  mov    %r13,%rsi
  call   <strcpy@plt>
  lea    0x8(%rbx),%rsi
  mov    %rsi,%rax
  sub    %rbp,%rax
  mov    %r12,%rdx
  sub    %rax,%rdx
  lea    0x10(%rbx),%rdi
  call   <memmove@plt>
  movq   $0x0,0x8(%rbx)
  mov    %r14,0x10(%rbx)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  mov    %rdi,%rax
  jmp    L8
L9:
  mov    %rbp,%rbx
  jmp    L24
```

assistant: ```c
char **string_array_append(char **oarray, char *str) {
  char **narray, **tmp;
  for (tmp = oarray; *tmp; tmp++)
    ;
  tmp++;
  size_t olength = *((size_t *)tmp);
  size_t nlength = olength + strlen(str) + 1 + sizeof(char *);
  narray = xxrealloc(oarray, nlength);
  ptrdiff_t offset = ((void *)narray) - ((void *)oarray) + sizeof(char *);
  for (tmp = narray; *tmp; tmp++)
    *tmp = ((void *)*tmp) + offset;
  *tmp = (char *)(((void *)narray) + olength + sizeof(char *));
  strcpy(*tmp, str);
  tmp++;
  memmove(((void *)tmp) + sizeof(char *), tmp, olength - (((void *)tmp) - ((void *)narray)));
  *tmp = NULL;
  tmp++;
  *((size_t *)tmp) = nlength;
  return narray;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<string_array_append>:
  endbr64
  push   %r14
  mov    %rdi,%rax
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L15
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L49
L15:
  mov    0x8(%rax),%rbp
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  lea    0x9(%rbp,%rax,1),%r12
  mov    %r12,%rsi
  call   <xxrealloc@plt>
  mov    %rax,%rdx
  mov    %rax,%r13
  mov    (%rax),%rax
  sub    %rbx,%rdx
  add    $0x8,%edx
  test   %rax,%rax
  je     L25
  movslq %edx,%rdx
  mov    %r13,%rbx
L46:
  add    %rdx,%rax
  add    $0x8,%rbx
  mov    %rax,-0x8(%rbx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L46
L40:
  lea    0x8(%r13,%rbp,1),%rdi
  mov    %r14,%rsi
  mov    %rdi,(%rbx)
  call   <strcpy@plt>
  lea    0x8(%rbx),%rsi
  mov    %rbp,%rdx
  lea    0x10(%rbx),%rdi
  mov    %rsi,%rax
  sub    %r13,%rax
  sub    %rax,%rdx
  call   <memmove@plt>
  movq   $0x0,0x8(%rbx)
  mov    %r13,%rax
  mov    %r12,0x10(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L25:
  mov    %r13,%rbx
  jmp    L40
```

assistant: ```c
char **string_array_append(char **oarray, char *str) {
  char **narray, **tmp;
  for (tmp = oarray; *tmp; tmp++)
    ;
  tmp++;
  size_t olength = *((size_t *)tmp);
  size_t nlength = olength + strlen(str) + 1 + sizeof(char *);
  narray = xxrealloc(oarray, nlength);
  ptrdiff_t offset = ((void *)narray) - ((void *)oarray) + sizeof(char *);
  for (tmp = narray; *tmp; tmp++)
    *tmp = ((void *)*tmp) + offset;
  *tmp = (char *)(((void *)narray) + olength + sizeof(char *));
  strcpy(*tmp, str);
  tmp++;
  memmove(((void *)tmp) + sizeof(char *), tmp, olength - (((void *)tmp) - ((void *)narray)));
  *tmp = NULL;
  tmp++;
  *((size_t *)tmp) = nlength;
  return narray;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<string_array_append>:
  endbr64
  push   %r14
  mov    %rdi,%rax
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L7
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L41
L7:
  mov    0x8(%rax),%rbp
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  lea    0x9(%rbp,%rax,1),%r12
  mov    %r12,%rsi
  call   <xxrealloc@plt>
  mov    %rax,%rdx
  mov    %rax,%r13
  mov    (%rax),%rax
  sub    %rbx,%rdx
  add    $0x8,%edx
  test   %rax,%rax
  je     L8
  movslq %edx,%rdx
  mov    %r13,%rbx
L29:
  add    %rdx,%rax
  add    $0x8,%rbx
  mov    %rax,-0x8(%rbx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L29
L47:
  lea    0x8(%r13,%rbp,1),%rdi
  mov    %r14,%rsi
  mov    %rdi,(%rbx)
  call   <strcpy@plt>
  lea    0x8(%rbx),%rsi
  mov    %rbp,%rdx
  lea    0x10(%rbx),%rdi
  mov    %rsi,%rax
  sub    %r13,%rax
  sub    %rax,%rdx
  call   <memmove@plt>
  movq   $0x0,0x8(%rbx)
  mov    %r13,%rax
  mov    %r12,0x10(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  mov    %r13,%rbx
  jmp    L47
```

assistant: ```c
char **string_array_append(char **oarray, char *str) {
  char **narray, **tmp;
  for (tmp = oarray; *tmp; tmp++)
    ;
  tmp++;
  size_t olength = *((size_t *)tmp);
  size_t nlength = olength + strlen(str) + 1 + sizeof(char *);
  narray = xxrealloc(oarray, nlength);
  ptrdiff_t offset = ((void *)narray) - ((void *)oarray) + sizeof(char *);
  for (tmp = narray; *tmp; tmp++)
    *tmp = ((void *)*tmp) + offset;
  *tmp = (char *)(((void *)narray) + olength + sizeof(char *));
  strcpy(*tmp, str);
  tmp++;
  memmove(((void *)tmp) + sizeof(char *), tmp, olength - (((void *)tmp) - ((void *)narray)));
  *tmp = NULL;
  tmp++;
  *((size_t *)tmp) = nlength;
  return narray;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<exm_file_size_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L26
  mov    $0x0,%eax
  jmp    L6
L26:
  mov    -0x10(%rbp),%rax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
unsigned long long exm_file_size_get(const char *filename) {
  struct stat buf;
  if (stat(filename, &buf) != 0)
    return 0;
  return buf.st_size;
}
```
user: What is the c source code of the assembly code below:

```asm
<exm_file_size_get>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long exm_file_size_get(const char *filename) {
  struct stat buf;
  if (stat(filename, &buf) != 0)
    return 0;
  return buf.st_size;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<exm_file_size_get>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long exm_file_size_get(const char *filename) {
  struct stat buf;
  if (stat(filename, &buf) != 0)
    return 0;
  return buf.st_size;
}
```
user: What is the c source code of the assembly code below?

```asm
<exm_file_size_get>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long exm_file_size_get(const char *filename) {
  struct stat buf;
  if (stat(filename, &buf) != 0)
    return 0;
  return buf.st_size;
}
```
user: What is the c source code of the assembly code below:

```asm
<b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: %d


assistant: ```c
void b() {
  int x = 1;
  printf("%d\n", (x + 1));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<b>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: %d


assistant: ```c
void b() {
  int x = 1;
  printf("%d\n", (x + 1));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<b>:
  endbr64
  mov    $0x2,%esi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: %d


assistant: ```c
void b() {
  int x = 1;
  printf("%d\n", (x + 1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<b>:
  endbr64
  mov    $0x2,%esi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: %d


assistant: ```c
void b() {
  int x = 1;
  printf("%d\n", (x + 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cosTheta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jp     L8
  pxor   %xmm0,%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jne    L8
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  D19(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L29
L8:
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  D19(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D19(%rip),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x20(%rbp),%xmm2
  movsd  -0x20(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  D19(%rip),%xmm0
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L29:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
data_type: f64

tool: D19: 1

assistant: ```c
double cosTheta(double xi, double g) {
  double ans;
  if (g == 0.0) {
    ans = 2 * xi - 1;
  } else {
    double temp = (1.0 - g * g) / (1.0 - g + 2.0 * g * xi);
    ans = 1.0 / (2.0 * g) * (1.0 + g * g - temp * temp);
  }
  return (ans);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cosTheta>:
  endbr64
  ucomisd D3(%rip),%xmm1
  jp     L17
  jne    L17
  addsd  %xmm0,%xmm0
  subsd  D1(%rip),%xmm0
  ret
L17:
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm1,%xmm6
  addsd  %xmm1,%xmm6
  movsd  D1(%rip),%xmm3
  movapd %xmm3,%xmm4
  subsd  %xmm2,%xmm4
  movapd %xmm3,%xmm5
  subsd  %xmm1,%xmm5
  mulsd  %xmm6,%xmm0
  addsd  %xmm5,%xmm0
  divsd  %xmm0,%xmm4
  movapd %xmm4,%xmm1
  addsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  mulsd  %xmm4,%xmm1
  subsd  %xmm1,%xmm0
  divsd  %xmm6,%xmm3
  mulsd  %xmm3,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: f64
name: parse_data
arguments: data_tag: D1
type_infered: f64

tool: D3: 0

tool: D1: 1

assistant: ```c
double cosTheta(double xi, double g) {
  double ans;
  if (g == 0.0) {
    ans = 2 * xi - 1;
  } else {
    double temp = (1.0 - g * g) / (1.0 - g + 2.0 * g * xi);
    ans = 1.0 / (2.0 * g) * (1.0 + g * g - temp * temp);
  }
  return (ans);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cosTheta>:
  endbr64
  ucomisd D16(%rip),%xmm1
  jp     L15
  jne    L15
  addsd  %xmm0,%xmm0
  subsd  D25(%rip),%xmm0
  ret
  nopl   (%rax)
L15:
  movapd %xmm1,%xmm6
  movsd  D25(%rip),%xmm3
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm6
  mulsd  %xmm1,%xmm2
  movapd %xmm3,%xmm5
  movapd %xmm3,%xmm4
  subsd  %xmm1,%xmm5
  mulsd  %xmm6,%xmm0
  subsd  %xmm2,%xmm4
  addsd  %xmm3,%xmm2
  divsd  %xmm6,%xmm3
  addsd  %xmm5,%xmm0
  divsd  %xmm0,%xmm4
  movapd %xmm2,%xmm0
  movapd %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
data_type: f64
name: unpack_data
arguments: tag: D25
data_type: f64

tool: D16: 0

tool: D25: 1

assistant: ```c
double cosTheta(double xi, double g) {
  double ans;
  if (g == 0.0) {
    ans = 2 * xi - 1;
  } else {
    double temp = (1.0 - g * g) / (1.0 - g + 2.0 * g * xi);
    ans = 1.0 / (2.0 * g) * (1.0 + g * g - temp * temp);
  }
  return (ans);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cosTheta>:
  endbr64
  ucomisd D9(%rip),%xmm1
  jp     L18
  jne    L18
  addsd  %xmm0,%xmm0
  subsd  D16(%rip),%xmm0
  ret
  nopl   (%rax)
L18:
  movapd %xmm1,%xmm6
  movsd  D16(%rip),%xmm3
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm6
  mulsd  %xmm1,%xmm2
  movapd %xmm3,%xmm5
  movapd %xmm3,%xmm4
  subsd  %xmm1,%xmm5
  mulsd  %xmm6,%xmm0
  subsd  %xmm2,%xmm4
  addsd  %xmm3,%xmm2
  divsd  %xmm6,%xmm3
  addsd  %xmm5,%xmm0
  divsd  %xmm0,%xmm4
  movapd %xmm2,%xmm0
  movapd %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: f64
name: extract_symbolic_data
arguments: label: D16
type: f64

tool: D9: 0

tool: D16: 1

assistant: ```c
double cosTheta(double xi, double g) {
  double ans;
  if (g == 0.0) {
    ans = 2 * xi - 1;
  } else {
    double temp = (1.0 - g * g) / (1.0 - g + 2.0 * g * xi);
    ans = 1.0 / (2.0 * g) * (1.0 + g * g - temp * temp);
  }
  return (ans);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<maxXor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  cmpl   $0x3e8,-0x18(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L42
L24:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L38
L4:
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L37
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L37:
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L4
  addl   $0x1,-0x14(%rbp)
L42:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L24
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int maxXor(int l, int r) {
  assert(1 <= l);
  assert(l <= r);
  assert(r <= pow(10, 3));
  int max = 0;
  int inner_r;
  int xor ;
  for (l; l <= r; l++) {
    for (inner_r = l; inner_r <= r; inner_r++) {
      xor = l ^ inner_r;
      if (xor > max) {
        max = xor;
      }
    }
  }
  return max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maxXor>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  test   %edi,%edi
  setg   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    %ebp,%ebx
  setle  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    $0x3e8,%ebp
  setle  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    %ebp,%ebx
  jg     L11
  lea    0x1(%rbp),%esi
  mov    $0x0,%edx
  jmp    L2
L44:
  mov    %ebx,%ecx
  xor    %eax,%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L44
L8:
  add    $0x1,%ebx
  cmp    %esi,%ebx
  je     L15
L2:
  mov    %ebx,%eax
  cmp    %ebx,%ebp
  jge    L44
  jmp    L8
L11:
  mov    $0x0,%edx
L15:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int maxXor(int l, int r) {
  assert(1 <= l);
  assert(l <= r);
  assert(r <= pow(10, 3));
  int max = 0;
  int inner_r;
  int xor ;
  for (l; l <= r; l++) {
    for (inner_r = l; inner_r <= r; inner_r++) {
      xor = l ^ inner_r;
      if (xor > max) {
        max = xor;
      }
    }
  }
  return max;
}
```