ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<init_nand>:
  endbr64
  movl   $0x0,0x7e00f120
  mov    0x70200000,%eax
  and    $0xbc7f888f,%eax
  or     $0x1000310,%eax
  mov    %eax,0x70200000
  mov    0x70200004,%eax
  and    $0xfffcff08,%eax
  or     $0xf7,%al
  mov    %eax,0x70200004
  xor    %eax,%eax
  jmp    1050 <nand_reset@plt>
```

assistant: ```c
void init_nand(void) {
  (*(volatile unsigned int *)(0x7E00F120)) = 0;
  (*(volatile unsigned int *)(0x70200000)) = ((*(volatile unsigned int *)(0x70200000)) & 0xBC7F888F) | 0x01000310;
  (*(volatile unsigned int *)(0x70200004)) = ((*(volatile unsigned int *)(0x70200004)) & 0xFFFCFF08) | 0xF7;
  nand_reset();
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_nand>:
  endbr64
  movl   $0x0,0x7e00f120
  mov    0x70200000,%eax
  and    $0xbc7f888f,%eax
  or     $0x1000310,%eax
  mov    %eax,0x70200000
  mov    0x70200004,%eax
  and    $0xfffcff08,%eax
  or     $0xf7,%al
  mov    %eax,0x70200004
  xor    %eax,%eax
  jmp    1050 <nand_reset@plt>
```

assistant: ```c
void init_nand(void) {
  (*(volatile unsigned int *)(0x7E00F120)) = 0;
  (*(volatile unsigned int *)(0x70200000)) = ((*(volatile unsigned int *)(0x70200000)) & 0xBC7F888F) | 0x01000310;
  (*(volatile unsigned int *)(0x70200004)) = ((*(volatile unsigned int *)(0x70200004)) & 0xFFFCFF08) | 0xF7;
  nand_reset();
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crc32_le2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L41
L52:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %eax,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L58:
  mov    -0x14(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L55
  mov    $0xedb88320,%eax
  jmp    L14
L55:
  mov    $0x0,%eax
L14:
  xor    %edx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L42:
  cmpl   $0x7,-0x4(%rbp)
  jle    L58
L41:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L52
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t crc32_le2(uint32_t crc, unsigned char const *p, size_t len) {
  int i;
  while (len--) {
    crc ^= *p++;
    for (i = 0; i < 8; i++)
      crc = (crc >> 1) ^ ((crc & 1) ? 0xedb88320 : 0);
  }
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crc32_le2>:
  endbr64
  mov    %edi,%eax
  test   %rdx,%rdx
  je     L20
  lea    (%rsi,%rdx,1),%rdi
  jmp    L16
L1:
  cmp    %rsi,%rdi
  je     L20
L16:
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%edx
  xor    %edx,%eax
  mov    $0x8,%edx
L37:
  mov    %eax,%ecx
  sar    %ecx
  and    $0x1,%eax
  neg    %eax
  and    $0xedb88320,%eax
  xor    %ecx,%eax
  sub    $0x1,%edx
  jne    L37
  jmp    L1
L20:
  ret
```

assistant: ```c
uint32_t crc32_le2(uint32_t crc, unsigned char const *p, size_t len) {
  int i;
  while (len--) {
    crc ^= *p++;
    for (i = 0; i < 8; i++)
      crc = (crc >> 1) ^ ((crc & 1) ? 0xedb88320 : 0);
  }
  return crc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crc32_le2>:
  endbr64
  mov    %edi,%eax
  test   %rdx,%rdx
  je     L4
  lea    (%rsi,%rdx,1),%r8
  nop
L21:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  xor    %edx,%eax
  mov    $0x8,%edx
  xchg   %ax,%ax
L13:
  mov    %eax,%ecx
  sar    %ecx
  mov    %ecx,%edi
  xor    $0xedb88320,%edi
  test   $0x1,%al
  mov    %ecx,%eax
  cmovne %edi,%eax
  sub    $0x1,%edx
  jne    L13
  cmp    %rsi,%r8
  jne    L21
L4:
  ret
```

assistant: ```c
uint32_t crc32_le2(uint32_t crc, unsigned char const *p, size_t len) {
  int i;
  while (len--) {
    crc ^= *p++;
    for (i = 0; i < 8; i++)
      crc = (crc >> 1) ^ ((crc & 1) ? 0xedb88320 : 0);
  }
  return crc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc32_le2>:
  endbr64
  mov    %edi,%r8d
  mov    %rsi,%rcx
  test   %rdx,%rdx
  je     L16
  lea    (%rsi,%rdx,1),%rdi
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  xor    %r8d,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  xor    $0xedb88320,%esi
  and    $0x1,%edx
  cmovne %esi,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%esi
  xor    $0xedb88320,%esi
  test   $0x1,%al
  cmovne %esi,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  xor    $0xedb88320,%esi
  and    $0x1,%edx
  cmovne %esi,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%esi
  xor    $0xedb88320,%esi
  test   $0x1,%al
  cmovne %esi,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  xor    $0xedb88320,%esi
  and    $0x1,%edx
  cmovne %esi,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%esi
  xor    $0xedb88320,%esi
  test   $0x1,%al
  cmovne %esi,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  xor    $0xedb88320,%esi
  and    $0x1,%edx
  cmovne %esi,%eax
  mov    %eax,%r8d
  sar    %r8d
  mov    %r8d,%edx
  xor    $0xedb88320,%edx
  test   $0x1,%al
  cmovne %edx,%r8d
  cmp    %rcx,%rdi
  jne    L7
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t crc32_le2(uint32_t crc, unsigned char const *p, size_t len) {
  int i;
  while (len--) {
    crc ^= *p++;
    for (i = 0; i < 8; i++)
      crc = (crc >> 1) ^ ((crc & 1) ? 0xedb88320 : 0);
  }
  return crc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getcode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L0
  movl   $0xffffffff,-0xc(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getcode(char *reply) {
  int code = 0;
  char *charcode = (char *)malloc(3);
  bzero(charcode, 3);
  charcode = strncpy(charcode, reply, 3);
  if ((code = atoi(charcode)) == 0)
    code = -1;
  free(charcode);
  return code;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getcode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    $0x3,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L9
L12:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    $0xffffffff,%ebx
  jmp    L12
```

assistant: ```c
int getcode(char *reply) {
  int code = 0;
  char *charcode = (char *)malloc(3);
  bzero(charcode, 3);
  charcode = strncpy(charcode, reply, 3);
  if ((code = atoi(charcode)) == 0)
    code = -1;
  free(charcode);
  return code;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getcode>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x3,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x3,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    %r12,%rsi
  call   <strncpy@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <atoi@plt>
  test   %eax,%eax
  je     L1
  mov    %eax,%r12d
L17:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L1:
  mov    $0xffffffff,%r12d
  jmp    L17
```

assistant: ```c
int getcode(char *reply) {
  int code = 0;
  char *charcode = (char *)malloc(3);
  bzero(charcode, 3);
  charcode = strncpy(charcode, reply, 3);
  if ((code = atoi(charcode)) == 0)
    code = -1;
  free(charcode);
  return code;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getcode>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x3,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x3,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    %r12,%rsi
  call   <strncpy@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <atoi@plt>
  test   %eax,%eax
  je     L5
  mov    %eax,%r12d
L16:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L5:
  mov    $0xffffffff,%r12d
  jmp    L16
```

assistant: ```c
int getcode(char *reply) {
  int code = 0;
  char *charcode = (char *)malloc(3);
  bzero(charcode, 3);
  charcode = strncpy(charcode, reply, 3);
  if ((code = atoi(charcode)) == 0)
    code = -1;
  free(charcode);
  return code;
}
```
user: What is the c source code of the assembly code below?

```asm
<sha1_process_part2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    (%rdi),%r14d
  mov    0x4(%rdi),%r13d
  mov    0x8(%rdi),%r10d
  mov    %r10d,-0xc(%rsp)
  mov    0xc(%rdi),%r8d
  mov    %r8d,-0x8(%rsp)
  mov    0x10(%rdi),%eax
  mov    %eax,-0x4(%rsp)
  mov    %r13d,%esi
  mov    %r14d,%edi
  mov    $0x0,%ecx
  mov    $0x0,%r11d
  mov    $0x0,%r9d
  mov    $0x5a827999,%ebp
  jmp    L84
L35:
  lea    -0x14(%rcx),%r15d
  cmp    $0x13,%r15d
  jbe    L79
  lea    -0x28(%rcx),%r15d
  cmp    $0x13,%r15d
  jbe    L41
  sub    $0x3c,%edx
  cmp    $0x13,%edx
  jbe    L25
L96:
  mov    %edi,%edx
  shl    $0x5,%edx
  mov    %edi,%r15d
  sar    $0x1b,%r15d
  or     %r15d,%edx
  add    %r9d,%edx
  add    %eax,%edx
  add    %r11d,%edx
  add    (%rbx,%rcx,4),%edx
  mov    %esi,%eax
  shl    $0x1e,%eax
  sar    $0x2,%esi
  or     %esi,%eax
  mov    %eax,%r15d
  add    $0x1,%rcx
  mov    %edi,%esi
  mov    %r8d,%eax
  cmp    $0x50,%rcx
  je     L48
  mov    %r10d,%r8d
  mov    %r15d,%r10d
  mov    %edx,%edi
L84:
  mov    %ecx,%edx
  cmp    $0x13,%ecx
  ja     L35
  mov    %r10d,%r9d
  xor    %r8d,%r9d
  and    %esi,%r9d
  xor    %r8d,%r9d
  mov    %ebp,%r11d
  jmp    L96
L79:
  mov    %esi,%r9d
  xor    %r10d,%r9d
  xor    %r8d,%r9d
  mov    $0x6ed9eba1,%r11d
  jmp    L96
L41:
  mov    %r10d,%r9d
  or     %r8d,%r9d
  and    %esi,%r9d
  mov    %r10d,%edx
  and    %r8d,%edx
  or     %edx,%r9d
  mov    $0x8f1bbcdc,%r11d
  jmp    L96
L25:
  mov    %esi,%r9d
  xor    %r10d,%r9d
  xor    %r8d,%r9d
  mov    $0xca62c1d6,%r11d
  jmp    L96
L48:
  add    %edx,%r14d
  mov    %r14d,(%r12)
  add    %edi,%r13d
  mov    %r13d,0x4(%r12)
  mov    -0xc(%rsp),%eax
  add    %r15d,%eax
  mov    %eax,0x8(%r12)
  mov    -0x8(%rsp),%eax
  add    %r10d,%eax
  mov    %eax,0xc(%r12)
  mov    -0x4(%rsp),%eax
  add    %r8d,%eax
  mov    %eax,0x10(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sha1_process_part2(uint32_t abcde[5], uint32_t *w) {
  uint32_t i;
  uint32_t a = abcde[0];
  uint32_t b = abcde[1];
  uint32_t c = abcde[2];
  uint32_t d = abcde[3];
  uint32_t e = abcde[4];
  uint32_t f = 0;
  uint32_t k = 0;
  for (i = 0; i <= 79; i++) {
    if (i >= 0 && i <= 19) {
      f = (b & c) | ((~b) & d);
      k = 0x5A827999;
    } else if (i >= 20 && i <= 39) {
      f = b ^ c ^ d;
      k = 0x6ED9EBA1;
    } else if (i >= 40 && i <= 59) {
      f = (b & c) | (b & d) | (c & d);
      k = 0x8F1BBCDC;
    } else if (i >= 60 && i <= 79) {
      f = b ^ c ^ d;
      k = 0xCA62C1D6;
    }
    uint32_t temp = (((a) << (5)) | ((a) >> (32 - (5)))) + f + e + k + w[i];
    e = d;
    d = c;
    c = (((b) << (30)) | ((b) >> (32 - (30))));
    b = a;
    a = temp;
  }
  abcde[0] += a;
  abcde[1] += b;
  abcde[2] += c;
  abcde[3] += d;
  abcde[4] += e;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sha1_process_part2>:
  endbr64
  push   %r15
  xor    %ecx,%ecx
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%r15d
  mov    0x4(%rdi),%r14d
  mov    0x8(%rdi),%r13d
  mov    0xc(%rdi),%r9d
  mov    0x10(%rdi),%eax
  mov    %r15d,%r8d
  mov    %r13d,%r10d
  mov    %r14d,%esi
  mov    %r9d,-0x8(%rsp)
  mov    %eax,-0x4(%rsp)
  jmp    L17
  nopl   0x0(%rax)
L75:
  lea    -0x14(%rcx),%edx
  cmp    $0x13,%edx
  jbe    L56
  lea    -0x28(%rcx),%edx
  cmp    $0x13,%edx
  jbe    L2
  mov    %esi,%r11d
  mov    $0xca62c1d6,%edi
  xor    %r10d,%r11d
  xor    %r9d,%r11d
L25:
  mov    %r8d,%edx
  mov    %r8d,%ebx
  shl    $0x5,%edx
  sar    $0x1b,%ebx
  or     %ebx,%edx
  add    %r11d,%edx
  add    %eax,%edx
  mov    %esi,%eax
  sar    $0x2,%esi
  shl    $0x1e,%eax
  add    %edi,%edx
  add    0x0(%rbp,%rcx,4),%edx
  add    $0x1,%rcx
  or     %esi,%eax
  mov    %r8d,%esi
  mov    %eax,%edi
  mov    %r9d,%eax
  cmp    $0x50,%rcx
  je     L40
  mov    %r10d,%r9d
  mov    %edx,%r8d
  mov    %edi,%r10d
L17:
  cmp    $0x13,%rcx
  ja     L75
  mov    %r10d,%r11d
  mov    $0x5a827999,%edi
  xor    %r9d,%r11d
  and    %esi,%r11d
  xor    %r9d,%r11d
  jmp    L25
  nopl   (%rax)
L40:
  mov    -0x8(%rsp),%eax
  add    %edx,%r15d
  add    %r8d,%r14d
  add    %edi,%r13d
  mov    %r15d,(%r12)
  add    %r10d,%eax
  mov    %r14d,0x4(%r12)
  mov    %eax,0xc(%r12)
  mov    -0x4(%rsp),%eax
  mov    %r13d,0x8(%r12)
  pop    %rbx
  add    %r9d,%eax
  pop    %rbp
  mov    %eax,0x10(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  mov    %esi,%r11d
  mov    $0x6ed9eba1,%edi
  xor    %r10d,%r11d
  xor    %r9d,%r11d
  jmp    L25
L2:
  mov    %r10d,%r11d
  mov    %r10d,%edx
  mov    $0x8f1bbcdc,%edi
  or     %r9d,%r11d
  and    %r9d,%edx
  and    %esi,%r11d
  or     %edx,%r11d
  jmp    L25
```

assistant: ```c
void sha1_process_part2(uint32_t abcde[5], uint32_t *w) {
  uint32_t i;
  uint32_t a = abcde[0];
  uint32_t b = abcde[1];
  uint32_t c = abcde[2];
  uint32_t d = abcde[3];
  uint32_t e = abcde[4];
  uint32_t f = 0;
  uint32_t k = 0;
  for (i = 0; i <= 79; i++) {
    if (i >= 0 && i <= 19) {
      f = (b & c) | ((~b) & d);
      k = 0x5A827999;
    } else if (i >= 20 && i <= 39) {
      f = b ^ c ^ d;
      k = 0x6ED9EBA1;
    } else if (i >= 40 && i <= 59) {
      f = (b & c) | (b & d) | (c & d);
      k = 0x8F1BBCDC;
    } else if (i >= 60 && i <= 79) {
      f = b ^ c ^ d;
      k = 0xCA62C1D6;
    }
    uint32_t temp = (((a) << (5)) | ((a) >> (32 - (5)))) + f + e + k + w[i];
    e = d;
    d = c;
    c = (((b) << (30)) | ((b) >> (32 - (30))));
    b = a;
    a = temp;
  }
  abcde[0] += a;
  abcde[1] += b;
  abcde[2] += c;
  abcde[3] += d;
  abcde[4] += e;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sha1_process_part2>:
  endbr64
  mov    %rdi,%r10
  push   %r13
  xor    %edx,%edx
  push   %r12
  mov    0x10(%r10),%r11d
  push   %rbp
  push   %rbx
  movdqu (%rdi),%xmm1
  mov    %rsi,%rbx
  mov    %r11d,%ebp
  mov    0xc(%rdi),%r8d
  mov    0x8(%rdi),%r9d
  mov    0x4(%rdi),%ecx
  movd   %xmm1,%edi
  jmp    L41
  xchg   %ax,%ax
L74:
  lea    -0x14(%rdx),%eax
  cmp    $0x13,%eax
  jbe    L56
  lea    -0x28(%rdx),%eax
  mov    %r8d,%esi
  cmp    $0x13,%eax
  jbe    L67
  xor    %r9d,%esi
  mov    $0xca62c1d6,%r12d
  xor    %ecx,%esi
L57:
  mov    %edi,%eax
  mov    %edi,%r13d
  sar    $0x1b,%eax
  shl    $0x5,%r13d
  or     %r13d,%eax
  add    %esi,%eax
  mov    %ecx,%esi
  sar    $0x2,%ecx
  add    %ebp,%eax
  shl    $0x1e,%esi
  mov    %r8d,%ebp
  add    %r12d,%eax
  add    (%rbx,%rdx,4),%eax
  add    $0x1,%rdx
  or     %ecx,%esi
  mov    %edi,%ecx
  cmp    $0x50,%rdx
  je     L27
  mov    %r9d,%r8d
  mov    %eax,%edi
  mov    %esi,%r9d
L41:
  cmp    $0x13,%rdx
  ja     L74
  mov    %r8d,%esi
  mov    $0x5a827999,%r12d
  xor    %r9d,%esi
  and    %ecx,%esi
  xor    %r8d,%esi
  jmp    L57
  nopl   0x0(%rax)
L27:
  movd   %esi,%xmm2
  movd   %r9d,%xmm3
  movd   %eax,%xmm0
  add    %r8d,%r11d
  movd   %edi,%xmm4
  punpckldq %xmm3,%xmm2
  pop    %rbx
  mov    %r11d,0x10(%r10)
  punpckldq %xmm4,%xmm0
  pop    %rbp
  pop    %r12
  punpcklqdq %xmm2,%xmm0
  pop    %r13
  paddd  %xmm1,%xmm0
  movups %xmm0,(%r10)
  ret
L56:
  mov    %r8d,%esi
  mov    $0x6ed9eba1,%r12d
  xor    %r9d,%esi
  xor    %ecx,%esi
  jmp    L57
L67:
  or     %r9d,%esi
  mov    %r8d,%eax
  mov    $0x8f1bbcdc,%r12d
  and    %ecx,%esi
  and    %r9d,%eax
  or     %eax,%esi
  jmp    L57
```

assistant: ```c
void sha1_process_part2(uint32_t abcde[5], uint32_t *w) {
  uint32_t i;
  uint32_t a = abcde[0];
  uint32_t b = abcde[1];
  uint32_t c = abcde[2];
  uint32_t d = abcde[3];
  uint32_t e = abcde[4];
  uint32_t f = 0;
  uint32_t k = 0;
  for (i = 0; i <= 79; i++) {
    if (i >= 0 && i <= 19) {
      f = (b & c) | ((~b) & d);
      k = 0x5A827999;
    } else if (i >= 20 && i <= 39) {
      f = b ^ c ^ d;
      k = 0x6ED9EBA1;
    } else if (i >= 40 && i <= 59) {
      f = (b & c) | (b & d) | (c & d);
      k = 0x8F1BBCDC;
    } else if (i >= 60 && i <= 79) {
      f = b ^ c ^ d;
      k = 0xCA62C1D6;
    }
    uint32_t temp = (((a) << (5)) | ((a) >> (32 - (5)))) + f + e + k + w[i];
    e = d;
    d = c;
    c = (((b) << (30)) | ((b) >> (32 - (30))));
    b = a;
    a = temp;
  }
  abcde[0] += a;
  abcde[1] += b;
  abcde[2] += c;
  abcde[3] += d;
  abcde[4] += e;
}
```
user: What is the c source code of the assembly code below?

```asm
<polacz2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L10:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  nop
L0:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void polacz2(char *s, char *d) {
  while (*++d != '\0')
    ;
  while (*d++ = *s++)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<polacz2>:
  endbr64
L18:
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  jne    L18
  mov    $0x0,%eax
L16:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L16
  ret
```

assistant: ```c
void polacz2(char *s, char *d) {
  while (*++d != '\0')
    ;
  while (*d++ = *s++)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<polacz2>:
  endbr64
  nopl   0x0(%rax)
L6:
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  jne    L6
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L9
  ret
```

assistant: ```c
void polacz2(char *s, char *d) {
  while (*++d != '\0')
    ;
  while (*d++ = *s++)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<polacz2>:
  endbr64
  nopl   0x0(%rax)
L8:
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  jne    L8
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L12
  ret
```

assistant: ```c
void polacz2(char *s, char *d) {
  while (*++d != '\0')
    ;
  while (*d++ = *s++)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bi_mod1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L4
L11:
  mov    -0x8(%rbp),%rax
  shl    $0x20,%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x28(%rbp)
  mov    %rdx,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L4:
  cmpl   $0x0,-0xc(%rbp)
  jns    L11
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long bi_mod1(int a_len, unsigned long *a_data, unsigned long b_d) {
  unsigned long long num;
  int i;
  num = 0;
  for (i = a_len - 1; i >= 0; i--) {
    num = (num << 32) + a_data[i];
    num = num % b_d;
  }
  return (unsigned long)num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bi_mod1>:
  endbr64
  mov    %rdx,%rcx
  sub    $0x1,%edi
  js     L9
  movslq %edi,%rdi
  mov    $0x0,%edx
L18:
  mov    %rdx,%rax
  shl    $0x20,%rax
  add    (%rsi,%rdi,8),%rax
  mov    $0x0,%edx
  div    %rcx
  sub    $0x1,%rdi
  test   %edi,%edi
  jns    L18
L16:
  mov    %rdx,%rax
  ret
L9:
  mov    $0x0,%edx
  jmp    L16
```

assistant: ```c
unsigned long bi_mod1(int a_len, unsigned long *a_data, unsigned long b_d) {
  unsigned long long num;
  int i;
  num = 0;
  for (i = a_len - 1; i >= 0; i--) {
    num = (num << 32) + a_data[i];
    num = num % b_d;
  }
  return (unsigned long)num;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bi_mod1>:
  endbr64
  mov    %rdx,%rcx
  sub    $0x1,%edi
  js     L4
  movslq %edi,%rdi
  xor    %edx,%edx
  nopl   0x0(%rax)
L6:
  mov    %rdx,%rax
  xor    %edx,%edx
  shl    $0x20,%rax
  add    (%rsi,%rdi,8),%rax
  sub    $0x1,%rdi
  div    %rcx
  test   %edi,%edi
  jns    L6
  mov    %rdx,%rax
  ret
  nopl   0x0(%rax)
L4:
  xor    %edx,%edx
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned long bi_mod1(int a_len, unsigned long *a_data, unsigned long b_d) {
  unsigned long long num;
  int i;
  num = 0;
  for (i = a_len - 1; i >= 0; i--) {
    num = (num << 32) + a_data[i];
    num = num % b_d;
  }
  return (unsigned long)num;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bi_mod1>:
  endbr64
  mov    %rdx,%rcx
  sub    $0x1,%edi
  js     L15
  movslq %edi,%rdi
  xor    %edx,%edx
  nopl   0x0(%rax)
L10:
  mov    %rdx,%rax
  xor    %edx,%edx
  shl    $0x20,%rax
  add    (%rsi,%rdi,8),%rax
  sub    $0x1,%rdi
  div    %rcx
  test   %edi,%edi
  jns    L10
  mov    %rdx,%rax
  ret
  nopl   0x0(%rax)
L15:
  xor    %edx,%edx
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned long bi_mod1(int a_len, unsigned long *a_data, unsigned long b_d) {
  unsigned long long num;
  int i;
  num = 0;
  for (i = a_len - 1; i >= 0; i--) {
    num = (num << 32) + a_data[i];
    num = num % b_d;
  }
  return (unsigned long)num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<q_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L20
L19:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L21
  mov    -0x8(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,-0x8(%rbp)
L21:
  mov    -0x10(%rbp),%rax
  imul   %rax,%rax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,-0x10(%rbp)
  sarq   -0x20(%rbp)
L20:
  cmpq   $0x0,-0x20(%rbp)
  jne    L19
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long q_pow(long long a, long long b, long long c) {
  long long A = a;
  long long ret = 1;
  while (b) {
    if (b % 2 != 0) {
      ret *= A;
      ret %= c;
    }
    A = A * A % c;
    b >>= 1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<q_pow>:
  endbr64
  mov    %rdx,%rcx
  test   %rsi,%rsi
  je     L5
  mov    $0x1,%r8d
  jmp    L30
L49:
  imul   %rdi,%rdi
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rdi
  sar    %rsi
  je     L24
L30:
  test   $0x1,%sil
  je     L49
  mov    %r8,%rax
  imul   %rdi,%rax
  cqto
  idiv   %rcx
  mov    %rdx,%r8
  jmp    L49
L5:
  mov    $0x1,%r8d
L24:
  mov    %r8,%rax
  ret
```

assistant: ```c
long long q_pow(long long a, long long b, long long c) {
  long long A = a;
  long long ret = 1;
  while (b) {
    if (b % 2 != 0) {
      ret *= A;
      ret %= c;
    }
    A = A * A % c;
    b >>= 1;
  }
  return ret;
}
```