ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<comp_alias>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D3(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strcspn@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L42
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  cmp    %rbx,%rax
  jne    L14
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %r13,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0x2a,%esi
  mov    %rbp,%rdi
  lea    -0x1(%rbp,%rax,1),%rbx
  call   <rindex@plt>
  cmp    %rax,%rbx
  je     L1
  mov    %r12,%rdi
  call   <strlen@plt>
  movzbl (%rbx),%edx
  lea    -0x1(%r12,%rax,1),%rcx
  cmp    $0x2a,%dl
  je     L1
  xor    %eax,%eax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L60:
  sub    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  cmp    $0x2a,%dl
  je     L1
L22:
  cmp    %dl,(%rcx,%rax,1)
  je     L60
L42:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: *

assistant: ```c
int comp_alias(char *alias, char *name) {
  size_t compare_length = 0;
  char *alias_pointer = NULL;
  char *name_pointer = NULL;
  compare_length = strcspn(alias, "*");
  if (strncmp(name, alias, compare_length) == 0) {
    if (compare_length == strlen(alias)) {
      if (strlen(alias) == strlen(name)) {
        return 0;
      }
    } else {
      alias_pointer = alias + strlen(alias) - 1;
      if (rindex(alias, '*') == alias_pointer) {
        return 0;
      } else {
        name_pointer = name + strlen(name) - 1;
        while (*alias_pointer != '*') {
          if (*alias_pointer == *name_pointer) {
            alias_pointer--;
            name_pointer--;
          } else {
            return 1;
          }
        }
        return 0;
      }
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<comp_alias>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strcspn@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L33
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  cmp    %rbx,%rax
  jne    L57
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %r13,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    $0x2a,%esi
  mov    %rbp,%rdi
  lea    -0x1(%rbp,%rax,1),%rbx
  call   <rindex@plt>
  cmp    %rax,%rbx
  je     L22
  mov    %r12,%rdi
  call   <strlen@plt>
  movzbl (%rbx),%edx
  lea    -0x1(%r12,%rax,1),%rcx
  cmp    $0x2a,%dl
  je     L22
  xor    %eax,%eax
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L50:
  sub    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  cmp    $0x2a,%dl
  je     L22
L43:
  cmp    %dl,(%rcx,%rax,1)
  je     L50
L33:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string

tool: D4: *

assistant: ```c
int comp_alias(char *alias, char *name) {
  size_t compare_length = 0;
  char *alias_pointer = NULL;
  char *name_pointer = NULL;
  compare_length = strcspn(alias, "*");
  if (strncmp(name, alias, compare_length) == 0) {
    if (compare_length == strlen(alias)) {
      if (strlen(alias) == strlen(name)) {
        return 0;
      }
    } else {
      alias_pointer = alias + strlen(alias) - 1;
      if (rindex(alias, '*') == alias_pointer) {
        return 0;
      } else {
        name_pointer = name + strlen(name) - 1;
        while (*alias_pointer != '*') {
          if (*alias_pointer == *name_pointer) {
            alias_pointer--;
            name_pointer--;
          } else {
            return 1;
          }
        }
        return 0;
      }
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<btruth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L1:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sar    %eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    -0x20(%rbp),%rcx
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%rcx
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L16:
  cmpl   $0x3,-0xc(%rbp)
  jle    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: D5: %d %d | %d


assistant: ```c
void btruth(const char *name, bool (*f)(bool, bool)) {
  bool a, b;
  int i;
  printf("%s\n", name);
  for (i = 0; i < 4; i++) {
    a = (i >> 0) & 1;
    b = (i >> 1) & 1;
    printf("%d %d | %d\n", a, b, f(a, b));
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<btruth>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r13
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D7(%rip),%r14
L7:
  mov    %ebx,%r12d
  and    $0x1,%r12d
  mov    %ebx,%ebp
  sar    %ebp
  and    $0x1,%ebp
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   *%r13
  mov    %eax,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x4,%ebx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: %d %d | %d


assistant: ```c
void btruth(const char *name, bool (*f)(bool, bool)) {
  bool a, b;
  int i;
  printf("%s\n", name);
  for (i = 0; i < 4; i++) {
    a = (i >> 0) & 1;
    b = (i >> 1) & 1;
    printf("%d %d | %d\n", a, b, f(a, b));
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<btruth>:
  endbr64
  push   %r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
L4:
  mov    %ebx,%ebp
  mov    %ebx,%r14d
  add    $0x1,%ebx
  and    $0x1,%ebp
  sar    %r14d
  mov    %r14d,%esi
  mov    %ebp,%edi
  call   *%r12
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L4
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: %d %d | %d


assistant: ```c
void btruth(const char *name, bool (*f)(bool, bool)) {
  bool a, b;
  int i;
  printf("%s\n", name);
  for (i = 0; i < 4; i++) {
    a = (i >> 0) & 1;
    b = (i >> 1) & 1;
    printf("%d %d | %d\n", a, b, f(a, b));
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<btruth>:
  endbr64
  push   %r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
L7:
  mov    %ebx,%ebp
  mov    %ebx,%r14d
  add    $0x1,%ebx
  and    $0x1,%ebp
  sar    %r14d
  mov    %r14d,%esi
  mov    %ebp,%edi
  call   *%r12
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L7
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: %d %d | %d


assistant: ```c
void btruth(const char *name, bool (*f)(bool, bool)) {
  bool a, b;
  int i;
  printf("%s\n", name);
  for (i = 0; i < 4; i++) {
    a = (i >> 0) & 1;
    b = (i >> 1) & 1;
    printf("%d %d | %d\n", a, b, f(a, b));
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<test25b>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r12
  movsbl 0x2(%rdi),%ecx
  movsbl 0x1(%rdi),%edx
  movsbl (%rdi),%esi
  movsbl 0x2(%r12),%eax
  push   %rax
  movsbl 0x1(%r12),%eax
  push   %rax
  movsbl (%r12),%eax
  push   %rax
  movswl 0x0(%r13),%eax
  push   %rax
  movsbl 0x1(%rbp),%eax
  push   %rax
  movsbl 0x0(%rbp),%eax
  push   %rax
  movsbl 0x5(%rdi),%eax
  push   %rax
  movsbl 0x4(%rdi),%r9d
  movsbl 0x3(%rdi),%r8d
  lea    D10(%rip),%rdi
  call   <printf@plt>
  movb   $0x70,(%rbx)
  movb   $0x71,0x1(%rbx)
  movb   $0x72,0x2(%rbx)
  movb   $0x73,0x3(%rbx)
  movb   $0x74,0x4(%rbx)
  movb   $0x79,0x5(%rbx)
  movb   $0x31,0x0(%rbp)
  movb   $0x34,0x1(%rbp)
  movw   $0x12,0x0(%r13)
  movb   $0x31,(%r12)
  movb   $0x34,0x1(%r12)
  movb   $0x34,0x2(%r12)
  add    $0x38,%rsp
  movsbl 0x2(%rbx),%ecx
  movsbl 0x1(%rbx),%edx
  movsbl (%rbx),%esi
  push   $0x34
  push   $0x34
  push   $0x31
  movswl 0x0(%r13),%eax
  push   %rax
  movsbl 0x1(%rbp),%eax
  push   %rax
  movsbl 0x0(%rbp),%eax
  push   %rax
  movsbl 0x5(%rbx),%eax
  push   %rax
  movsbl 0x4(%rbx),%r9d
  movsbl 0x3(%rbx),%r8d
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string

tool: D10: sub  (test25b) C   input  :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:


tool: D19: sub  (test25b) C   return :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:


assistant: ```c
int test25b(char *c1, char *c2, short *c3, char *c4) {
  int r = 0;
  char *pt;
  printf("sub  (test25b) C   input  :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:\n", c1[0], c1[1], c1[2], c1[3], c1[4], c1[5], c2[0], c2[1], *c3, c4[0], c4[1], c4[2]);
  pt = c1;
  *pt = 'p';
  pt++;
  *pt = 'q';
  pt++;
  *pt = 'r';
  pt++;
  *pt = 's';
  pt++;
  *pt = 't';
  pt++;
  *pt = 'y';
  pt = c2;
  *pt = '1';
  pt++;
  *pt = '4';
  *c3 = 18;
  pt = c4;
  *pt = '1';
  pt++;
  *pt = '4';
  pt++;
  *pt = '4';
  pt = NULL;
  printf("sub  (test25b) C   return :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:\n", c1[0], c1[1], c1[2], c1[3], c1[4], c1[5], c2[0], c2[1], *c3, c4[0], c4[1], c4[2]);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test25b>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsbl 0x2(%r12),%eax
  movsbl 0x2(%rdi),%ecx
  movsbl 0x1(%rdi),%edx
  movsbl (%rdi),%esi
  push   %rax
  movsbl 0x1(%r12),%eax
  push   %rax
  movsbl (%r12),%eax
  push   %rax
  movswl 0x0(%r13),%eax
  push   %rax
  movsbl 0x1(%rbp),%eax
  push   %rax
  movsbl 0x0(%rbp),%eax
  push   %rax
  movsbl 0x5(%rdi),%eax
  push   %rax
  movsbl 0x4(%rdi),%r9d
  movsbl 0x3(%rdi),%r8d
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x7974,%eax
  mov    $0x3431,%edx
  mov    $0x12,%ecx
  mov    $0x3431,%esi
  movl   $0x73727170,(%rbx)
  add    $0x38,%rsp
  lea    D18(%rip),%rdi
  mov    %ax,0x4(%rbx)
  mov    %dx,0x0(%rbp)
  mov    %cx,0x0(%r13)
  mov    %si,(%r12)
  movb   $0x34,0x2(%r12)
  movswl 0x0(%r13),%eax
  movsbl 0x2(%rbx),%ecx
  movsbl 0x1(%rbx),%edx
  push   $0x34
  movsbl (%rbx),%esi
  movsbl 0x4(%rbx),%r9d
  push   $0x34
  push   $0x31
  movsbl 0x3(%rbx),%r8d
  push   %rax
  movsbl 0x1(%rbp),%eax
  push   %rax
  movsbl 0x0(%rbp),%eax
  push   %rax
  movsbl 0x5(%rbx),%eax
  push   %rax
  call   <printf@plt>
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string

tool: D19: sub  (test25b) C   input  :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:


tool: D18: sub  (test25b) C   return :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:


assistant: ```c
int test25b(char *c1, char *c2, short *c3, char *c4) {
  int r = 0;
  char *pt;
  printf("sub  (test25b) C   input  :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:\n", c1[0], c1[1], c1[2], c1[3], c1[4], c1[5], c2[0], c2[1], *c3, c4[0], c4[1], c4[2]);
  pt = c1;
  *pt = 'p';
  pt++;
  *pt = 'q';
  pt++;
  *pt = 'r';
  pt++;
  *pt = 's';
  pt++;
  *pt = 't';
  pt++;
  *pt = 'y';
  pt = c2;
  *pt = '1';
  pt++;
  *pt = '4';
  *c3 = 18;
  pt = c4;
  *pt = '1';
  pt++;
  *pt = '4';
  pt++;
  *pt = '4';
  pt = NULL;
  printf("sub  (test25b) C   return :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:\n", c1[0], c1[1], c1[2], c1[3], c1[4], c1[5], c2[0], c2[1], *c3, c4[0], c4[1], c4[2]);
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test25b>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsbl 0x2(%r12),%eax
  movsbl 0x2(%rdi),%ecx
  movsbl 0x1(%rdi),%edx
  movsbl (%rdi),%esi
  push   %rax
  movsbl 0x1(%r12),%eax
  push   %rax
  movsbl (%r12),%eax
  push   %rax
  movswl 0x0(%r13),%eax
  push   %rax
  movsbl 0x1(%rbp),%eax
  push   %rax
  movsbl 0x0(%rbp),%eax
  push   %rax
  movsbl 0x5(%rdi),%eax
  push   %rax
  movsbl 0x4(%rdi),%r9d
  movsbl 0x3(%rdi),%r8d
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x7974,%eax
  mov    $0x3431,%edx
  mov    $0x12,%ecx
  mov    $0x3431,%esi
  movl   $0x73727170,(%rbx)
  add    $0x38,%rsp
  lea    D4(%rip),%rdi
  mov    %ax,0x4(%rbx)
  mov    %dx,0x0(%rbp)
  mov    %cx,0x0(%r13)
  mov    %si,(%r12)
  movb   $0x34,0x2(%r12)
  movswl 0x0(%r13),%eax
  movsbl 0x2(%rbx),%ecx
  movsbl 0x1(%rbx),%edx
  push   $0x34
  movsbl (%rbx),%esi
  movsbl 0x4(%rbx),%r9d
  push   $0x34
  push   $0x31
  movsbl 0x3(%rbx),%r8d
  push   %rax
  movsbl 0x1(%rbp),%eax
  push   %rax
  movsbl 0x0(%rbp),%eax
  push   %rax
  movsbl 0x5(%rbx),%eax
  push   %rax
  call   <printf@plt>
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D0: sub  (test25b) C   input  :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:


tool: D4: sub  (test25b) C   return :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:


assistant: ```c
int test25b(char *c1, char *c2, short *c3, char *c4) {
  int r = 0;
  char *pt;
  printf("sub  (test25b) C   input  :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:\n", c1[0], c1[1], c1[2], c1[3], c1[4], c1[5], c2[0], c2[1], *c3, c4[0], c4[1], c4[2]);
  pt = c1;
  *pt = 'p';
  pt++;
  *pt = 'q';
  pt++;
  *pt = 'r';
  pt++;
  *pt = 's';
  pt++;
  *pt = 't';
  pt++;
  *pt = 'y';
  pt = c2;
  *pt = '1';
  pt++;
  *pt = '4';
  *c3 = 18;
  pt = c4;
  *pt = '1';
  pt++;
  *pt = '4';
  pt++;
  *pt = '4';
  pt = NULL;
  printf("sub  (test25b) C   return :%c%c%c%c%c%c:%c%c:%02d:%c%c%c:\n", c1[0], c1[1], c1[2], c1[3], c1[4], c1[5], c2[0], c2[1], *c3, c4[0], c4[1], c4[2]);
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x78(%rbp)
  jmp    L32
L15:
  movzbl -0x70(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L32
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <addtree@plt>
  mov    %rax,-0x78(%rbp)
L32:
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <getword@plt>
  mov    D4(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L15
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <treeprint@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
main() {
  struct tnode *root;
  char word[100];
  root = NULL;
  while (getword(word, 100) != EOF)
    if (isalpha(word[0]))
      root = addtree(root, word);
  treeprint(root);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    %rsp,%rbx
L27:
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <getword@plt>
  mov    D0(%rip),%rdx
  cmp    (%rdx),%rax
  je     L31
  movsbl (%rsp),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L27
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <addtree@plt>
  mov    %rax,%rbp
  jmp    L27
L31:
  mov    %rbp,%rdi
  call   <treeprint@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  struct tnode *root;
  char word[100];
  root = NULL;
  while (getword(word, 100) != EOF)
    if (isalpha(word[0]))
      root = addtree(root, word);
  treeprint(root);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    D4(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L40:
  movsbl (%rsp),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L43
L10:
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <getword@plt>
  cmp    0x0(%rbp),%rax
  jne    L40
  mov    %r12,%rdi
  call   <treeprint@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L43:
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <addtree@plt>
  mov    %rax,%r12
  jmp    L10
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  struct tnode *root;
  char word[100];
  root = NULL;
  while (getword(word, 100) != EOF)
    if (isalpha(word[0]))
      root = addtree(root, word);
  treeprint(root);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    D8(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%rsp),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L14
L0:
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <getword@plt>
  cmp    0x0(%rbp),%rax
  jne    L6
  mov    %r12,%rdi
  call   <treeprint@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <addtree@plt>
  mov    %rax,%r12
  jmp    L0
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  struct tnode *root;
  char word[100];
  root = NULL;
  while (getword(word, 100) != EOF)
    if (isalpha(word[0]))
      root = addtree(root, word);
  treeprint(root);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <itoa@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void printi(int i) {
  char temp[10];
  itoa(i, temp, 10);
  puts(temp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printi>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  mov    $0xa,%edx
  mov    %rbx,%rsi
  call   <itoa@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printi(int i) {
  char temp[10];
  itoa(i, temp, 10);
  puts(temp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printi>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printi(int i) {
  char temp[10];
  itoa(i, temp, 10);
  puts(temp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printi>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printi(int i) {
  char temp[10];
  itoa(i, temp, 10);
  puts(temp);
}
```