user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x2a,%ecx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  nopl   0x0(%rax,%rax,1)
L26:
  lea    -0x2a(%rcx),%eax
  mov    %rsi,%rdx
  xchg   %ax,%ax
L44:
  mov    %eax,(%rdx)
  add    $0x6,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L44
  lea    0x2a(%rax),%ecx
  add    $0x1c,%rsi
  cmp    $0x126,%eax
  jne    L26
  lea    D10(%rip),%rdi
  lea    0xc4(%r13),%r12
  mov    %r13,%r15
  call   <puts@plt>
  lea    D30(%rip),%rbp
  lea    D47(%rip),%r14
  nop
L3:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%r15,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L11
  mov    %r14,%rdi
  add    $0x1c,%r15
  call   <puts@plt>
  cmp    %r12,%r15
  jne    L3
  lea    D48(%rip),%rdi
  add    $0xe0,%r13
  call   <puts@plt>
  nopl   0x0(%rax)
L10:
  lea    -0xc4(%r12),%rbx
L35:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1c,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L35
  mov    %r14,%rdi
  add    $0x4,%r12
  call   <puts@plt>
  cmp    %r13,%r12
  jne    L10
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D30
datatype: string
name: extract_symbolic_data
arguments: tag: D47
datatype: string
name: extract_symbolic_data
arguments: tag: D48
datatype: string
name: extract_symbolic_data
arguments: tag: D52
datatype: string
name: extract_symbolic_data
arguments: tag: D20
datatype: string

tool: D10: 
Esta es la matriz original[f][c]:  



tool: D30: %d	

tool: D47: 



tool: D48: 
Esta es la matriz transpuesta: 



tool: D52: 


tool: D20: 
Esta es la Suma de la matriz transpuesta: 



assistant: ```c
int main(void) {
  int matriz[7][7], f, c, tras = 0, temp = 0;
  for (f = 0; f < 7; f++) {
    for (c = 0; c < 7; c++) {
      matriz[f][c] = tras;
      tras = tras + 6;
    }
  }
  printf("\nEsta es la matriz original[f][c]:  \n\n\n");
  for (f = 0; f < 7; f++) {
    for (c = 0; c < 7; c++) {
      printf("%d\t", matriz[f][c]);
    }
    printf("\n\n\n");
  }
  printf("\nEsta es la matriz transpuesta: \n\n\n");
  for (f = 0; f < 7; f++) {
    for (c = 0; c < 7; c++) {
      printf("%d\t", matriz[c][f]);
    }
    printf("\n\n\n");
  }
  for (f = 1; f <= 6; f++) {
    for (c = 1; c <= 6; c++) {
      if ((f == 1 || f == 5) && (c == 1 || c == 5)) {
        temp = temp + matriz[c][f];
        if ((f == 2 || f == 3 || f == 4) && (c == 2 || c == 3 || c == 4)) {
          temp = temp + matriz[c][f];
          matriz[c][f] = 0;
          if ((f == 1 || f == 5) && (c == 2 || c == 3 || c == 4)) {
            temp = temp + matriz[c][f];
            if ((f == 2 || f == 3 || f == 4) && (c == 1 || c == 5)) {
              temp = temp + matriz[c][f];
            }
          }
        }
      }
    }
  }
  printf("\n\n");
  printf("\nEsta es la Suma de la matriz transpuesta: \n\n\n");
  return 0;
}
```