ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lfds700_misc_prng_internal_hash_murmurhash3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    (%rbx),%rax
  mov    %rax,%rdx
  shr    $0x21,%rdx
  xor    %rax,%rdx
  movabs $0xff51afd7ed558ccd,%rax
  imul   %rax,%rdx
  mov    %rdx,%rax
  shr    $0x21,%rax
  xor    %rdx,%rax
  movabs $0xc4ceb9fe1a85ec53,%rdx
  imul   %rdx,%rax
  mov    %rax,%rdx
  shr    $0x21,%rdx
  xor    %rdx,%rax
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void lfds700_misc_prng_internal_hash_murmurhash3(int long long unsigned *murmurhash3_state) {
  assert(murmurhash3_state != ((void *)0));
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  *murmurhash3_state *= 0xff51afd7ed558ccdULL;
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  *murmurhash3_state *= 0xc4ceb9fe1a85ec53ULL;
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lfds700_misc_prng_internal_hash_murmurhash3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    (%rbx),%rax
  mov    %rax,%rdx
  shr    $0x21,%rdx
  xor    %rax,%rdx
  movabs $0xff51afd7ed558ccd,%rax
  imul   %rax,%rdx
  mov    %rdx,%rax
  shr    $0x21,%rax
  xor    %rdx,%rax
  movabs $0xc4ceb9fe1a85ec53,%rdx
  imul   %rdx,%rax
  mov    %rax,%rdx
  shr    $0x21,%rdx
  xor    %rdx,%rax
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void lfds700_misc_prng_internal_hash_murmurhash3(int long long unsigned *murmurhash3_state) {
  assert(murmurhash3_state != ((void *)0));
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  *murmurhash3_state *= 0xff51afd7ed558ccdULL;
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  *murmurhash3_state *= 0xc4ceb9fe1a85ec53ULL;
  *murmurhash3_state ^= *murmurhash3_state >> 33;
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<load_srec>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %rdi,%rdx
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0xc8,%esi
  call   <fgets@plt>
  lea    0x10(%rsp),%r15
  lea    0x14(%rsp),%r14
  jmp    L49
L10:
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jle    L3
  lea    0x18(%rsp),%rbp
  mov    0x8(%rsp),%rax
  lea    -0x8000(%rax,%r12,1),%r12
  lea    -0x4(%rbx),%eax
  lea    0xa(%r15,%rax,2),%r13
L16:
  movsbl 0x0(%rbp),%edi
  call   <hex_to_int@plt>
  mov    %eax,%ebx
  movsbl 0x1(%rbp),%edi
  call   <hex_to_int@plt>
  shl    $0x4,%ebx
  add    %eax,%ebx
  mov    %bl,(%r12)
  add    $0x2,%rbp
  add    $0x1,%r12
  cmp    %r13,%rbp
  jne    L16
L3:
  mov    $0x2,%edx
  mov    %r15,%rsi
  lea    D18(%rip),%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L29
  mov    (%rsp),%rbx
  mov    %rbx,%rdx
  mov    $0xc8,%esi
  mov    %r15,%rdi
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L29
L49:
  movsbl 0x12(%rsp),%edi
  call   <hex_to_int@plt>
  mov    %eax,%ebx
  movsbl 0x13(%rsp),%edi
  call   <hex_to_int@plt>
  shl    $0x4,%ebx
  add    %eax,%ebx
  mov    %r15,%rbp
  mov    $0x0,%r12d
L18:
  shl    $0x4,%r12
  movsbl 0x4(%rbp),%edi
  call   <hex_to_int@plt>
  cltq
  add    %rax,%r12
  add    $0x1,%rbp
  cmp    %r14,%rbp
  jne    L18
  jmp    L10
L29:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x1,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string

tool: D5: %04x


tool: D18: S9

assistant: ```c
int load_srec(FILE *in, char *buffer) {
  char buf[200];
  int num_bytes, i, p, done = 0;
  long start_addr;
  char value;
  fgets(buf, 200, in);
  while (!done) {
    num_bytes = (16 * hex_to_int(buf[2]) + hex_to_int(buf[3])) - 3;
    start_addr = 0;
    for (p = 4, i = 0; i < 4; i++)
      start_addr = (start_addr << 4) + hex_to_int(buf[p++]);
    printf("%04x\n", start_addr);
    for (i = 0; i < num_bytes; i++) {
      value = 16 * hex_to_int(buf[p]) + hex_to_int(buf[p + 1]);
      p += 2;
      buffer[start_addr + i - 0x8000] = value;
    }
    if (!strncmp("S9", buf, 2)) {
      break;
    }
    fgets(buf, 200, in);
    if (feof(in))
      done = 1;
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<load_srec>:
  endbr64
  push   %r15
  mov    %rdi,%rdx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %rdi,(%rsp)
  lea    0x10(%rsp),%r12
  lea    0x14(%rsp),%rbp
  mov    %rsi,0x8(%rsp)
  mov    %r12,%rdi
  mov    $0xc8,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  call   <fgets@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  movsbl 0x12(%rsp),%edi
  mov    %r12,%r14
  xor    %ebx,%ebx
  call   <hex_to_int@plt>
  movsbl 0x13(%rsp),%edi
  mov    %eax,%r15d
  call   <hex_to_int@plt>
  shl    $0x4,%r15d
  add    %eax,%r15d
L9:
  movsbl 0x4(%r14),%edi
  shl    $0x4,%rbx
  add    $0x1,%r14
  call   <hex_to_int@plt>
  cltq
  add    %rax,%rbx
  cmp    %rbp,%r14
  jne    L9
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  cmp    $0x3,%r15d
  jle    L24
  mov    0x8(%rsp),%rax
  lea    0x18(%rsp),%r13
  lea    -0x8000(%rax,%rbx,1),%r14
  lea    -0x4(%r15),%eax
  lea    0xa(%r12,%rax,2),%r15
  nop
L32:
  movsbl 0x0(%r13),%edi
  add    $0x2,%r13
  add    $0x1,%r14
  call   <hex_to_int@plt>
  movsbl -0x1(%r13),%edi
  mov    %eax,%ebx
  call   <hex_to_int@plt>
  shl    $0x4,%ebx
  add    %eax,%ebx
  mov    %bl,-0x1(%r14)
  cmp    %r15,%r13
  jne    L32
L24:
  mov    $0x2,%edx
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L1
  mov    (%rsp),%rbx
  mov    %r12,%rdi
  mov    $0xc8,%esi
  mov    %rbx,%rdx
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L18
L1:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0xe8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D12
data_type: string

tool: D7: %04x


tool: D12: S9

assistant: ```c
int load_srec(FILE *in, char *buffer) {
  char buf[200];
  int num_bytes, i, p, done = 0;
  long start_addr;
  char value;
  fgets(buf, 200, in);
  while (!done) {
    num_bytes = (16 * hex_to_int(buf[2]) + hex_to_int(buf[3])) - 3;
    start_addr = 0;
    for (p = 4, i = 0; i < 4; i++)
      start_addr = (start_addr << 4) + hex_to_int(buf[p++]);
    printf("%04x\n", start_addr);
    for (i = 0; i < num_bytes; i++) {
      value = 16 * hex_to_int(buf[p]) + hex_to_int(buf[p + 1]);
      p += 2;
      buffer[start_addr + i - 0x8000] = value;
    }
    if (!strncmp("S9", buf, 2)) {
      break;
    }
    fgets(buf, 200, in);
    if (feof(in))
      done = 1;
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<load_srec>:
  endbr64
  push   %r15
  mov    %rdi,%rdx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %rdi,(%rsp)
  lea    0x10(%rsp),%r12
  lea    0x14(%rsp),%rbp
  mov    %rsi,0x8(%rsp)
  mov    %r12,%rdi
  mov    $0xc8,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  call   <fgets@plt>
  nopl   0x0(%rax,%rax,1)
L59:
  movsbl 0x12(%rsp),%edi
  mov    %r12,%r14
  xor    %ebx,%ebx
  call   <hex_to_int@plt>
  movsbl 0x13(%rsp),%edi
  mov    %eax,%r15d
  call   <hex_to_int@plt>
  shl    $0x4,%r15d
  add    %eax,%r15d
L11:
  movsbl 0x4(%r14),%edi
  shl    $0x4,%rbx
  add    $0x1,%r14
  call   <hex_to_int@plt>
  cltq
  add    %rax,%rbx
  cmp    %rbp,%r14
  jne    L11
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  cmp    $0x3,%r15d
  jle    L43
  mov    0x8(%rsp),%rax
  lea    0x18(%rsp),%r13
  lea    -0x8000(%rax,%rbx,1),%r14
  lea    -0x4(%r15),%eax
  lea    0xa(%r12,%rax,2),%r15
  nop
L21:
  movsbl 0x0(%r13),%edi
  add    $0x2,%r13
  add    $0x1,%r14
  call   <hex_to_int@plt>
  movsbl -0x1(%r13),%edi
  mov    %eax,%ebx
  call   <hex_to_int@plt>
  shl    $0x4,%ebx
  add    %eax,%ebx
  mov    %bl,-0x1(%r14)
  cmp    %r13,%r15
  jne    L21
L43:
  mov    $0x2,%edx
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L33
  mov    (%rsp),%rbx
  mov    %r12,%rdi
  mov    $0xc8,%esi
  mov    %rbx,%rdx
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L59
L33:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0xe8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D9
type: string

tool: D13: %04x


tool: D9: S9

assistant: ```c
int load_srec(FILE *in, char *buffer) {
  char buf[200];
  int num_bytes, i, p, done = 0;
  long start_addr;
  char value;
  fgets(buf, 200, in);
  while (!done) {
    num_bytes = (16 * hex_to_int(buf[2]) + hex_to_int(buf[3])) - 3;
    start_addr = 0;
    for (p = 4, i = 0; i < 4; i++)
      start_addr = (start_addr << 4) + hex_to_int(buf[p++]);
    printf("%04x\n", start_addr);
    for (i = 0; i < num_bytes; i++) {
      value = 16 * hex_to_int(buf[p]) + hex_to_int(buf[p + 1]);
      p += 2;
      buffer[start_addr + i - 0x8000] = value;
    }
    if (!strncmp("S9", buf, 2)) {
      break;
    }
    fgets(buf, 200, in);
    if (feof(in))
      done = 1;
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<realizar_jugada>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  lea    0x0(,%rdx,8),%ecx
  mov    -0x18(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <convertir_peones_reinas@plt>
  nop
  leave
  ret
```

assistant: ```c
void realizar_jugada(char *ptablero, int fi, int ci, int ff, int cf) {
  ptablero[ff * 8 + cf] = ptablero[fi * 8 + ci];
  ptablero[fi * 8 + ci] = ' ';
  convertir_peones_reinas(ptablero);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<realizar_jugada>:
  endbr64
  sub    $0x8,%rsp
  lea    (%rdx,%rsi,8),%eax
  cltq
  add    %rdi,%rax
  movzbl (%rax),%esi
  lea    (%r8,%rcx,8),%edx
  movslq %edx,%rdx
  mov    %sil,(%rdi,%rdx,1)
  movb   $0x20,(%rax)
  call   <convertir_peones_reinas@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void realizar_jugada(char *ptablero, int fi, int ci, int ff, int cf) {
  ptablero[ff * 8 + cf] = ptablero[fi * 8 + ci];
  ptablero[fi * 8 + ci] = ' ';
  convertir_peones_reinas(ptablero);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<realizar_jugada>:
  endbr64
  lea    (%rdx,%rsi,8),%eax
  lea    (%r8,%rcx,8),%edx
  cltq
  movslq %edx,%rdx
  add    %rdi,%rax
  movzbl (%rax),%esi
  mov    %sil,(%rdi,%rdx,1)
  movb   $0x20,(%rax)
  jmp    1050 <convertir_peones_reinas@plt>
```

assistant: ```c
void realizar_jugada(char *ptablero, int fi, int ci, int ff, int cf) {
  ptablero[ff * 8 + cf] = ptablero[fi * 8 + ci];
  ptablero[fi * 8 + ci] = ' ';
  convertir_peones_reinas(ptablero);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<realizar_jugada>:
  endbr64
  lea    (%rdx,%rsi,8),%eax
  lea    (%r8,%rcx,8),%edx
  cltq
  movslq %edx,%rdx
  add    %rdi,%rax
  movzbl (%rax),%esi
  mov    %sil,(%rdi,%rdx,1)
  movb   $0x20,(%rax)
  jmp    1050 <convertir_peones_reinas@plt>
```

assistant: ```c
void realizar_jugada(char *ptablero, int fi, int ci, int ff, int cf) {
  ptablero[ff * 8 + cf] = ptablero[fi * 8 + ci];
  ptablero[fi * 8 + ci] = ' ';
  convertir_peones_reinas(ptablero);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D10
datatype: string

tool: D17: Usage: cps_test <num_files> <file 1> <file 2> .... <file n>


tool: D10: 	<file> is swap replay dump file from sr_collect


assistant: ```c
void usage(void) {
  printf("Usage: cps_test <num_files> <file 1> <file 2> .... <file n>\n");
  printf("\t<file> is swap replay dump file from sr_collect\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D5: Usage: cps_test <num_files> <file 1> <file 2> .... <file n>


tool: D7: 	<file> is swap replay dump file from sr_collect


assistant: ```c
void usage(void) {
  printf("Usage: cps_test <num_files> <file 1> <file 2> .... <file n>\n");
  printf("\t<file> is swap replay dump file from sr_collect\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D10
type_guessed: string

tool: D1: Usage: cps_test <num_files> <file 1> <file 2> .... <file n>


tool: D10: 	<file> is swap replay dump file from sr_collect


assistant: ```c
void usage(void) {
  printf("Usage: cps_test <num_files> <file 1> <file 2> .... <file n>\n");
  printf("\t<file> is swap replay dump file from sr_collect\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D10
type_infered: string
name: read_data
arguments: tag: D0
type_infered: string

tool: D10: Usage: cps_test <num_files> <file 1> <file 2> .... <file n>


tool: D0: 	<file> is swap replay dump file from sr_collect


assistant: ```c
void usage(void) {
  printf("Usage: cps_test <num_files> <file 1> <file 2> .... <file n>\n");
  printf("\t<file> is swap replay dump file from sr_collect\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Action>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D24(%rip),%rax
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <LrsSend@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdx
  lea    D44(%rip),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <LrsReceive@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D41
type: string
name: extract_symbolic_data
arguments: data_tag: D44
type: string

tool: D24: 0

tool: D0: buf0

tool: D41: socket0

tool: D44: buf1

assistant: ```c
Action() {
  LrsSend("socket0", "buf0", "0");
  LrsReceive("socket0", "buf1", "0");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Action>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdx
  lea    D13(%rip),%rsi
  lea    D34(%rip),%rbx
  mov    %rbx,%rdi
  call   <LrsSend@plt>
  mov    %rbp,%rdx
  lea    D39(%rip),%rsi
  mov    %rbx,%rdi
  call   <LrsReceive@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D39
type_guessed: string

tool: D15: 0

tool: D13: buf0

tool: D34: socket0

tool: D39: buf1

assistant: ```c
Action() {
  LrsSend("socket0", "buf0", "0");
  LrsReceive("socket0", "buf1", "0");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Action>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  lea    D7(%rip),%rsi
  push   %rbp
  lea    D25(%rip),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <LrsSend@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D23(%rip),%rsi
  call   <LrsReceive@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string
name: read_data
arguments: label: D7
data_type: string
name: read_data
arguments: label: D25
data_type: string
name: read_data
arguments: label: D23
data_type: string

tool: D8: 0

tool: D7: buf0

tool: D25: socket0

tool: D23: buf1

assistant: ```c
Action() {
  LrsSend("socket0", "buf0", "0");
  LrsReceive("socket0", "buf1", "0");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Action>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  lea    D38(%rip),%rsi
  push   %rbp
  lea    D13(%rip),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <LrsSend@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D17(%rip),%rsi
  call   <LrsReceive@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string
name: retrieve_data
arguments: data_label: D38
type_guessed: string
name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string

tool: D2: 0

tool: D38: buf0

tool: D13: socket0

tool: D17: buf1

assistant: ```c
Action() {
  LrsSend("socket0", "buf0", "0");
  LrsReceive("socket0", "buf1", "0");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mm_madd_add_epi8_sse2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_madd_epi16@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_madd_epi16@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_add_epi32@plt>
  leave
  ret
```

assistant: ```c
__m128i mm_madd_add_epi8_sse2(const __m128i *const src_1, const __m128i *const src_2, const __m128i *const ker_1, const __m128i *const ker_2) {
  const __m128i src_1_half = _mm_unpacklo_epi8(*src_1, _mm_setzero_si128());
  const __m128i src_2_half = _mm_unpacklo_epi8(*src_2, _mm_setzero_si128());
  const __m128i madd_1 = _mm_madd_epi16(src_1_half, *ker_1);
  const __m128i madd_2 = _mm_madd_epi16(src_2_half, *ker_2);
  return _mm_add_epi32(madd_1, madd_2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mm_madd_add_epi8_sse2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %eax,%esi
  mov    (%rbx),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %eax,%esi
  mov    0x0(%rbp),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,%ebp
  mov    0x0(%r13),%esi
  mov    %ebx,%edi
  call   <_mm_madd_epi16@plt>
  mov    %eax,%ebx
  mov    (%r12),%esi
  mov    %ebp,%edi
  call   <_mm_madd_epi16@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <_mm_add_epi32@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__m128i mm_madd_add_epi8_sse2(const __m128i *const src_1, const __m128i *const src_2, const __m128i *const ker_1, const __m128i *const ker_2) {
  const __m128i src_1_half = _mm_unpacklo_epi8(*src_1, _mm_setzero_si128());
  const __m128i src_2_half = _mm_unpacklo_epi8(*src_2, _mm_setzero_si128());
  const __m128i madd_1 = _mm_madd_epi16(src_1_half, *ker_1);
  const __m128i madd_2 = _mm_madd_epi16(src_2_half, *ker_2);
  return _mm_add_epi32(madd_1, madd_2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mm_madd_add_epi8_sse2>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <_mm_setzero_si128@plt>
  mov    0x0(%rbp),%edi
  mov    %eax,%esi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <_mm_setzero_si128@plt>
  mov    (%r12),%edi
  mov    %eax,%esi
  call   <_mm_unpacklo_epi8@plt>
  mov    0x0(%r13),%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <_mm_madd_epi16@plt>
  mov    (%rbx),%esi
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <_mm_madd_epi16@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  mov    %eax,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <_mm_add_epi32@plt>
```

assistant: ```c
__m128i mm_madd_add_epi8_sse2(const __m128i *const src_1, const __m128i *const src_2, const __m128i *const ker_1, const __m128i *const ker_2) {
  const __m128i src_1_half = _mm_unpacklo_epi8(*src_1, _mm_setzero_si128());
  const __m128i src_2_half = _mm_unpacklo_epi8(*src_2, _mm_setzero_si128());
  const __m128i madd_1 = _mm_madd_epi16(src_1_half, *ker_1);
  const __m128i madd_2 = _mm_madd_epi16(src_2_half, *ker_2);
  return _mm_add_epi32(madd_1, madd_2);
}
```