ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prefix_update>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    $0x0,%eax
  call   <error_message@plt>
  mov    %eax,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <sprintf@plt>
  mov    $0xfffffff4,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: Prefix configuration on BSD systems not implemented yet.

assistant: ```c
int prefix_update(const char *ifname, int ifindex, const char *prefixPlain, int prefixLength, unsigned long prefered, unsigned long valid) {
  sprintf(error_message(), "Prefix configuration on BSD systems not implemented yet.");
  return -12;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<prefix_update>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <error_message@plt>
  mov    %eax,%edi
  lea    D6(%rip),%rsi
  call   <sprintf@plt>
  mov    $0xfffffff4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: Prefix configuration on BSD systems not implemented yet.

assistant: ```c
int prefix_update(const char *ifname, int ifindex, const char *prefixPlain, int prefixLength, unsigned long prefered, unsigned long valid) {
  sprintf(error_message(), "Prefix configuration on BSD systems not implemented yet.");
  return -12;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prefix_update>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <error_message@plt>
  lea    D4(%rip),%rsi
  mov    %eax,%edi
  call   <sprintf@plt>
  mov    $0xfffffff4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: Prefix configuration on BSD systems not implemented yet.

assistant: ```c
int prefix_update(const char *ifname, int ifindex, const char *prefixPlain, int prefixLength, unsigned long prefered, unsigned long valid) {
  sprintf(error_message(), "Prefix configuration on BSD systems not implemented yet.");
  return -12;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prefix_update>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <error_message@plt>
  lea    D8(%rip),%rsi
  mov    %eax,%edi
  call   <sprintf@plt>
  mov    $0xfffffff4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: Prefix configuration on BSD systems not implemented yet.

assistant: ```c
int prefix_update(const char *ifname, int ifindex, const char *prefixPlain, int prefixLength, unsigned long prefered, unsigned long valid) {
  sprintf(error_message(), "Prefix configuration on BSD systems not implemented yet.");
  return -12;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_divsint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L0
  cmpl   $0x0,-0x8(%rbp)
  jns    L55
  mov    -0x8(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_divuint@plt>
  jmp    L34
L55:
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  neg    %edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <_divuint@plt>
  neg    %eax
  jmp    L34
L0:
  cmpl   $0x0,-0x8(%rbp)
  jns    L33
  mov    -0x8(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_divuint@plt>
  neg    %eax
  jmp    L34
L33:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_divuint@plt>
L34:
  leave
  ret
```

assistant: ```c
int _divsint(int a, int b) {
  if (a < 0) {
    if (b < 0)
      return _divuint((unsigned int)-a, (unsigned int)-b);
    else
      return -_divuint((unsigned int)-a, (unsigned int)b);
  } else {
    if (b < 0)
      return -_divuint((unsigned int)a, (unsigned int)-b);
    else
      return _divuint((unsigned int)a, (unsigned int)b);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_divsint>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L17
  test   %esi,%esi
  js     L34
  call   <_divuint@plt>
L31:
  add    $0x8,%rsp
  ret
L17:
  test   %esi,%esi
  js     L35
  neg    %edi
  call   <_divuint@plt>
  neg    %eax
  jmp    L31
L35:
  neg    %esi
  neg    %edi
  call   <_divuint@plt>
  jmp    L31
L34:
  neg    %esi
  call   <_divuint@plt>
  neg    %eax
  jmp    L31
```

assistant: ```c
int _divsint(int a, int b) {
  if (a < 0) {
    if (b < 0)
      return _divuint((unsigned int)-a, (unsigned int)-b);
    else
      return -_divuint((unsigned int)-a, (unsigned int)b);
  } else {
    if (b < 0)
      return -_divuint((unsigned int)a, (unsigned int)-b);
    else
      return _divuint((unsigned int)a, (unsigned int)b);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_divsint>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L6
  test   %esi,%esi
  js     L29
  add    $0x8,%rsp
  jmp    1050 <_divuint@plt>
  nopl   0x0(%rax)
L29:
  neg    %esi
L4:
  call   <_divuint@plt>
  add    $0x8,%rsp
  neg    %eax
  ret
  xchg   %ax,%ax
L6:
  neg    %edi
  test   %esi,%esi
  jns    L4
  neg    %esi
  add    $0x8,%rsp
  jmp    1050 <_divuint@plt>
```

assistant: ```c
int _divsint(int a, int b) {
  if (a < 0) {
    if (b < 0)
      return _divuint((unsigned int)-a, (unsigned int)-b);
    else
      return -_divuint((unsigned int)-a, (unsigned int)b);
  } else {
    if (b < 0)
      return -_divuint((unsigned int)a, (unsigned int)-b);
    else
      return _divuint((unsigned int)a, (unsigned int)b);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_divsint>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L0
  test   %esi,%esi
  js     L19
  add    $0x8,%rsp
  jmp    1050 <_divuint@plt>
  nopl   0x0(%rax)
L19:
  neg    %esi
L7:
  call   <_divuint@plt>
  add    $0x8,%rsp
  neg    %eax
  ret
  xchg   %ax,%ax
L0:
  neg    %edi
  test   %esi,%esi
  jns    L7
  neg    %esi
  add    $0x8,%rsp
  jmp    1050 <_divuint@plt>
```

assistant: ```c
int _divsint(int a, int b) {
  if (a < 0) {
    if (b < 0)
      return _divuint((unsigned int)-a, (unsigned int)-b);
    else
      return -_divuint((unsigned int)-a, (unsigned int)b);
  } else {
    if (b < 0)
      return -_divuint((unsigned int)a, (unsigned int)-b);
    else
      return _divuint((unsigned int)a, (unsigned int)b);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pwmss_eqep_clk_disable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jbe    L19
  mov    $0xffffffff,%eax
  jmp    L24
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_pwmss_eqep_clk_status_get@plt>
  test   %rax,%rax
  jne    L34
  mov    $0x1,%eax
  jmp    L24
L34:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_pwmss_eqep_clk_disable@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <_pwmss_eqep_clk_status_set@plt>
  mov    $0x0,%eax
L24:
  leave
  ret
```

assistant: ```c
int pwmss_eqep_clk_disable(unsigned int device_id) {
  if (device_id > 2) {
    return -1;
  }
  if (_pwmss_eqep_clk_status_get(device_id) == 0) {
    return 1;
  }
  _pwmss_eqep_clk_disable(device_id);
  _pwmss_eqep_clk_status_set(device_id, 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pwmss_eqep_clk_disable>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    $0x2,%edi
  jbe    L6
  ret
L6:
  push   %rbx
  mov    %edi,%ebx
  call   <_pwmss_eqep_clk_status_get@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L10
L27:
  pop    %rbx
  ret
L10:
  mov    %ebx,%edi
  call   <_pwmss_eqep_clk_disable@plt>
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <_pwmss_eqep_clk_status_set@plt>
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
int pwmss_eqep_clk_disable(unsigned int device_id) {
  if (device_id > 2) {
    return -1;
  }
  if (_pwmss_eqep_clk_status_get(device_id) == 0) {
    return 1;
  }
  _pwmss_eqep_clk_disable(device_id);
  _pwmss_eqep_clk_status_set(device_id, 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pwmss_eqep_clk_disable>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    $0x2,%edi
  jbe    L7
  ret
  nop
L7:
  push   %rbp
  mov    %edi,%ebp
  call   <_pwmss_eqep_clk_status_get@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L10
  mov    %ebp,%edi
  call   <_pwmss_eqep_clk_disable@plt>
  xor    %esi,%esi
  mov    %ebp,%edi
  call   <_pwmss_eqep_clk_status_set@plt>
  xor    %eax,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int pwmss_eqep_clk_disable(unsigned int device_id) {
  if (device_id > 2) {
    return -1;
  }
  if (_pwmss_eqep_clk_status_get(device_id) == 0) {
    return 1;
  }
  _pwmss_eqep_clk_disable(device_id);
  _pwmss_eqep_clk_status_set(device_id, 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pwmss_eqep_clk_disable>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    $0x2,%edi
  jbe    L14
  ret
  nop
L14:
  push   %rbp
  mov    %edi,%ebp
  call   <_pwmss_eqep_clk_status_get@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L11
  mov    %ebp,%edi
  call   <_pwmss_eqep_clk_disable@plt>
  xor    %esi,%esi
  mov    %ebp,%edi
  call   <_pwmss_eqep_clk_status_set@plt>
  xor    %eax,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int pwmss_eqep_clk_disable(unsigned int device_id) {
  if (device_id > 2) {
    return -1;
  }
  if (_pwmss_eqep_clk_status_get(device_id) == 0) {
    return 1;
  }
  _pwmss_eqep_clk_disable(device_id);
  _pwmss_eqep_clk_status_set(device_id, 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x2d,%eax
  je     L123
  cmp    $0x2d,%eax
  jg     L103
  cmp    $0x2b,%eax
  je     L53
  cmp    $0x2b,%eax
  jg     L103
  cmp    $0x9,%eax
  je     L44
  cmp    $0x20,%eax
  jne    L103
  jmp    L44
L123:
  addl   $0x1,-0x4(%rbp)
L53:
  addq   $0x1,-0x18(%rbp)
  jmp    L103
L44:
  nop
  addq   $0x1,-0x18(%rbp)
  jmp    L0
L103:
  nop
  jmp    L38
L73:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L34
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L73
L34:
  cmpl   $0x0,-0x4(%rbp)
  je     L54
  mov    -0x8(%rbp),%eax
  neg    %eax
  jmp    L83
L54:
  mov    -0x8(%rbp),%eax
L83:
  pop    %rbp
  ret
```

assistant: ```c
int atoi(char *p) {
  int n, f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9')
    n = n * 10 + *p++ - '0';
  return (f ? -n : n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<atoi>:
  endbr64
L39:
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L97
  jg     L1
  cmp    $0x9,%al
  je     L102
  cmp    $0x20,%al
  jne    L40
L102:
  add    $0x1,%rdi
  jmp    L39
L40:
  mov    $0x0,%esi
  jmp    L53
L1:
  mov    $0x1,%esi
  cmp    $0x2d,%al
  jne    L20
L54:
  add    $0x1,%rdi
L53:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  mov    $0x0,%edx
  cmp    $0x9,%cl
  ja     L108
L25:
  add    $0x1,%rdi
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L25
L108:
  mov    %edx,%eax
  neg    %eax
  test   %esi,%esi
  cmovne %eax,%edx
  mov    %edx,%eax
  ret
L20:
  mov    $0x0,%esi
  jmp    L53
L97:
  mov    $0x0,%esi
  jmp    L54
```

assistant: ```c
int atoi(char *p) {
  int n, f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9')
    n = n * 10 + *p++ - '0';
  return (f ? -n : n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L93
L62:
  jg     L73
  cmp    $0x9,%al
  je     L98
  cmp    $0x20,%al
  jne    L18
L98:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x2b,%al
  jne    L62
L93:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L55:
  lea    -0x30(%rax),%edx
  xor    %esi,%esi
  cmp    $0x9,%dl
  ja     L18
L50:
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L31:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%edx
  movsbl (%rdi),%eax
  lea    -0x30(%rdx),%r8d
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L31
  mov    $0x30,%eax
  sub    %edx,%eax
  test   %esi,%esi
  cmovne %eax,%r8d
L45:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  cmp    $0x2d,%al
  jne    L55
  movsbl 0x1(%rdi),%eax
  mov    $0x1,%esi
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L50
L18:
  xor    %r8d,%r8d
  jmp    L45
```

assistant: ```c
int atoi(char *p) {
  int n, f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9')
    n = n * 10 + *p++ - '0';
  return (f ? -n : n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L94
L93:
  jg     L18
  cmp    $0x9,%al
  je     L89
  cmp    $0x20,%al
  jne    L1
L89:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x2b,%al
  jne    L93
L94:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L56:
  lea    -0x30(%rax),%edx
  xor    %esi,%esi
  cmp    $0x9,%dl
  ja     L1
L67:
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L21:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%edx
  movsbl (%rdi),%eax
  lea    -0x30(%rdx),%r8d
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L21
  mov    $0x30,%eax
  sub    %edx,%eax
  test   %esi,%esi
  cmovne %eax,%r8d
L26:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  cmp    $0x2d,%al
  jne    L56
  movsbl 0x1(%rdi),%eax
  mov    $0x1,%esi
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L67
L1:
  xor    %r8d,%r8d
  jmp    L26
```

assistant: ```c
int atoi(char *p) {
  int n, f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9')
    n = n * 10 + *p++ - '0';
  return (f ? -n : n);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L11
L12:
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x2,-0x4(%rbp)
  jle    L12
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string

tool: D7: This is a new line from checkout 2

tool: D12: This is a new line from checkout 1

assistant: ```c
int main() {
  int studCount = 0;
  printf("This is a new line from checkout 2");
  for (studCount; studCount < 3; studCount++) {
  }
  printf("This is a new line from checkout 1");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D14: This is a new line from checkout 2

tool: D0: This is a new line from checkout 1

assistant: ```c
int main() {
  int studCount = 0;
  printf("This is a new line from checkout 2");
  for (studCount; studCount < 3; studCount++) {
  }
  printf("This is a new line from checkout 1");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string
name: read_data
arguments: label: D11
type: string

tool: D0: This is a new line from checkout 2

tool: D11: This is a new line from checkout 1

assistant: ```c
int main() {
  int studCount = 0;
  printf("This is a new line from checkout 2");
  for (studCount; studCount < 3; studCount++) {
  }
  printf("This is a new line from checkout 1");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string

tool: D2: This is a new line from checkout 2

tool: D19: This is a new line from checkout 1

assistant: ```c
int main() {
  int studCount = 0;
  printf("This is a new line from checkout 2");
  for (studCount; studCount < 3; studCount++) {
  }
  printf("This is a new line from checkout 1");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L51
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L30
L46:
  subl   $0x1,-0x8(%rbp)
L106:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L17
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L46
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L9
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L9
L58:
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L91
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L58
L91:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L30
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L30:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L106
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  jmp    L40
L51:
  nop
L40:
  leave
  ret
```

assistant: ```c
void quick_sort(int *arr, int s, int e) {
  if (s >= e)
    return;
  int l = s, r = e;
  int base = arr[l];
  while (l < r) {
    while (l < r && arr[r] >= base)
      r--;
    if (l < r)
      arr[l++] = arr[r];
    while (l < r && arr[l] <= base)
      l++;
    if (l < r)
      arr[r--] = arr[l];
  }
  arr[l] = base;
  quick_sort(arr, s, l - 1);
  quick_sort(arr, l + 1, e);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jge    L63
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r11d
  mov    %edx,%r12d
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r8d
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rdx
  lea    -0x1(%r12),%ecx
  mov    %r12d,%esi
  mov    %r11d,%ebx
  jmp    L83
L82:
  mov    %esi,%r10d
  cmp    %esi,%ebx
  jge    L70
  lea    0x1(%rbx),%eax
  movslq %ebx,%rbx
  mov    %edi,0x0(%rbp,%rbx,4)
  cmp    %esi,%eax
  jge    L58
  cltq
L86:
  mov    %eax,%ebx
  cmp    %r8d,0x0(%rbp,%rax,4)
  jg     L41
  lea    0x1(%rax),%ebx
  add    $0x1,%rax
  cmp    %eax,%r10d
  jg     L86
L70:
  movslq %ebx,%rax
  mov    %r8d,0x0(%rbp,%rax,4)
  lea    -0x1(%rbx),%edx
  mov    %r11d,%esi
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quick_sort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  cmp    %r10d,%eax
  jge    L70
  cltq
  mov    0x0(%rbp,%rax,4),%eax
  mov    %eax,(%r9)
  cmp    %ebx,%ecx
  jle    L70
L35:
  sub    $0x4,%rdx
  sub    $0x1,%ecx
  sub    $0x1,%esi
L83:
  mov    %rdx,%r9
  mov    (%rdx),%edi
  cmp    %r8d,%edi
  jl     L82
  cmp    %ebx,%ecx
  jg     L35
  jmp    L70
L58:
  mov    %eax,%ebx
  jmp    L70
L63:
  ret
```

assistant: ```c
void quick_sort(int *arr, int s, int e) {
  if (s >= e)
    return;
  int l = s, r = e;
  int base = arr[l];
  while (l < r) {
    while (l < r && arr[r] >= base)
      r--;
    if (l < r)
      arr[l++] = arr[r];
    while (l < r && arr[l] <= base)
      l++;
    if (l < r)
      arr[r--] = arr[l];
  }
  arr[l] = base;
  quick_sort(arr, s, l - 1);
  quick_sort(arr, l + 1, e);
}
```
user: Translate the below assembly code into C programming language:

```asm
<quick_sort>:
  endbr64
  cmp    %esi,%edx
  jle    L75
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L21:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,4),%edi
  cs nopw 0x0(%rax,%rax,1)
L46:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L84:
  mov    (%rcx),%eax
  cmp    %edi,%eax
  jl     L90
  sub    $0x1,%edx
  sub    $0x4,%rcx
  cmp    %r8d,%edx
  jg     L84
L44:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L16:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %edi,0x0(%rbp,%rax,4)
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L90:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,4),%rsi
  cmp    %edx,%r8d
  jge    L44
  mov    %eax,(%rsi)
  cmp    %edx,%ebx
  jge    L16
  movslq %ebx,%rax
  jmp    L60
  nopl   0x0(%rax)
L53:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L16
L60:
  mov    0x0(%rbp,%rax,4),%esi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %edi,%esi
  jle    L53
  sub    $0x1,%edx
  mov    %esi,(%rcx)
  cmp    %eax,%edx
  jg     L46
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L75:
  ret
```

assistant: ```c
void quick_sort(int *arr, int s, int e) {
  if (s >= e)
    return;
  int l = s, r = e;
  int base = arr[l];
  while (l < r) {
    while (l < r && arr[r] >= base)
      r--;
    if (l < r)
      arr[l++] = arr[r];
    while (l < r && arr[l] <= base)
      l++;
    if (l < r)
      arr[r--] = arr[l];
  }
  arr[l] = base;
  quick_sort(arr, s, l - 1);
  quick_sort(arr, l + 1, e);
}
```