ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<contains_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L15
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  jne    L2
  mov    $0x1,%eax
  jmp    L19
L15:
  mov    $0x0,%eax
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int contains_char(char *str, char search) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == search)
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<contains_char>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  je     L15
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int contains_char(char *str, char search) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == search)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<contains_char>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  je     L13
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int contains_char(char *str, char search) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == search)
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmd_watch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L35:
  cmp    %rdx,%rsp
  je     L9
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L9:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L58
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L58:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L56
L34:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x30(%rbp),%rcx
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x34(%rbp),%ecx
  movslq %ecx,%rcx
  mov    %eax,(%rdx,%rcx,4)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x30(%rbp),%rax
  cmp    %rax,%rdx
  jne    L2
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
L2:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <errx@plt>
L55:
  addl   $0x1,-0x34(%rbp)
L56:
  mov    -0x34(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L34
  mov    -0x20(%rbp),%rdx
  mov    -0x44(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <watchoids@plt>
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: 4-digit hex number expected, got %s

assistant: ```c
int cmd_watch(int argc, char **argv) {
  int i;
  int oids[argc];
  char *end;
  for (i = 0; i < argc; i++) {
    oids[i] = strtol(argv[i], &end, 16);
    if (end != argv[i] + 4 || *end)
      errx(5, "4-digit hex number expected, got %s", argv[i]);
  }
  return watchoids(argc, oids);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmd_watch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L26:
  cmp    %rdx,%rsp
  je     L81
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L26
L81:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L73
  orq    $0x0,-0x8(%rsp,%rax,1)
L73:
  mov    %rsp,%r12
  mov    %r12,-0x48(%rbp)
  test   %r15d,%r15d
  jle    L4
  mov    %rsi,%rbx
  lea    -0x1(%r15),%eax
  lea    0x8(%rsi,%rax,8),%r13
  lea    D8(%rip),%r14
  jmp    L22
L57:
  mov    %r14,%rsi
  mov    $0x5,%edi
  call   <errx@plt>
L54:
  add    $0x8,%rbx
  add    $0x4,%r12
  cmp    %r13,%rbx
  je     L4
L22:
  lea    -0x40(%rbp),%rsi
  mov    $0x10,%edx
  mov    (%rbx),%rdi
  call   <strtol@plt>
  mov    %eax,(%r12)
  mov    (%rbx),%rdx
  mov    -0x40(%rbp),%rax
  lea    0x4(%rdx),%rcx
  cmp    %rcx,%rax
  jne    L57
  cmpb   $0x0,(%rax)
  je     L54
  jmp    L57
L4:
  mov    -0x48(%rbp),%rsi
  mov    %r15d,%edi
  call   <watchoids@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D8: 4-digit hex number expected, got %s

assistant: ```c
int cmd_watch(int argc, char **argv) {
  int i;
  int oids[argc];
  char *end;
  for (i = 0; i < argc; i++) {
    oids[i] = strtol(argv[i], &end, 16);
    if (end != argv[i] + 4 || *end)
      errx(5, "4-digit hex number expected, got %s", argv[i]);
  }
  return watchoids(argc, oids);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmd_watch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L89
L41:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L41
L89:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L79
L83:
  mov    -0x44(%rbp),%eax
  mov    %rsp,%rbx
  mov    %rbx,-0x50(%rbp)
  test   %eax,%eax
  jle    L5
  sub    $0x1,%eax
  mov    %rsi,%r15
  lea    -0x40(%rbp),%r12
  lea    0x8(%rsi,%rax,8),%r13
  lea    D7(%rip),%r14
  jmp    L105
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r14,%rsi
  mov    $0x5,%edi
  add    $0x8,%r15
  add    $0x4,%rbx
  call   <errx@plt>
  cmp    %r13,%r15
  je     L5
L105:
  mov    (%r15),%rdi
  mov    $0x10,%edx
  mov    %r12,%rsi
  call   <strtol@plt>
  mov    (%r15),%rdx
  mov    %eax,(%rbx)
  mov    -0x40(%rbp),%rax
  lea    0x4(%rdx),%rsi
  cmp    %rsi,%rax
  jne    L25
  cmpb   $0x0,(%rax)
  jne    L25
  add    $0x8,%r15
  add    $0x4,%rbx
  cmp    %r13,%r15
  jne    L105
L5:
  mov    -0x50(%rbp),%rsi
  mov    -0x44(%rbp),%edi
  call   <watchoids@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L79:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L83
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: 4-digit hex number expected, got %s

assistant: ```c
int cmd_watch(int argc, char **argv) {
  int i;
  int oids[argc];
  char *end;
  for (i = 0; i < argc; i++) {
    oids[i] = strtol(argv[i], &end, 16);
    if (end != argv[i] + 4 || *end)
      errx(5, "4-digit hex number expected, got %s", argv[i]);
  }
  return watchoids(argc, oids);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmd_watch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L27
L97:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L97
L27:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L109
L2:
  mov    -0x44(%rbp),%eax
  mov    %rsp,%rbx
  mov    %rbx,-0x50(%rbp)
  test   %eax,%eax
  jle    L68
  sub    $0x1,%eax
  mov    %rsi,%r15
  lea    -0x40(%rbp),%r12
  lea    0x8(%rsi,%rax,8),%r13
  lea    D7(%rip),%r14
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %r14,%rsi
  mov    $0x5,%edi
  add    $0x8,%r15
  add    $0x4,%rbx
  call   <errx@plt>
  cmp    %r13,%r15
  je     L68
L84:
  mov    (%r15),%rdi
  mov    $0x10,%edx
  mov    %r12,%rsi
  call   <strtol@plt>
  mov    (%r15),%rdx
  mov    %eax,(%rbx)
  mov    -0x40(%rbp),%rax
  lea    0x4(%rdx),%rsi
  cmp    %rsi,%rax
  jne    L58
  cmpb   $0x0,(%rax)
  jne    L58
  add    $0x8,%r15
  add    $0x4,%rbx
  cmp    %r13,%r15
  jne    L84
L68:
  mov    -0x50(%rbp),%rsi
  mov    -0x44(%rbp),%edi
  call   <watchoids@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L109:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L2
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: D7: 4-digit hex number expected, got %s

assistant: ```c
int cmd_watch(int argc, char **argv) {
  int i;
  int oids[argc];
  char *end;
  for (i = 0; i < argc; i++) {
    oids[i] = strtol(argv[i], &end, 16);
    if (end != argv[i] + 4 || *end)
      errx(5, "4-digit hex number expected, got %s", argv[i]);
  }
  return watchoids(argc, oids);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<open_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
datatype: string

tool: D6: Error - can'jjt open or create file: %s


assistant: ```c
FILE *open_file(const char *filename, const char *mode) {
  FILE *fp;
  fp = fopen(filename, mode);
  if (fp == NULL) {
    printf("Error - can'jjt open or create file: %s\n", filename);
    exit(1);
  }
  return fp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<open_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6: Error - can'jjt open or create file: %s


assistant: ```c
FILE *open_file(const char *filename, const char *mode) {
  FILE *fp;
  fp = fopen(filename, mode);
  if (fp == NULL) {
    printf("Error - can'jjt open or create file: %s\n", filename);
    exit(1);
  }
  return fp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<open_file>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: Error - can'jjt open or create file: %s


assistant: ```c
FILE *open_file(const char *filename, const char *mode) {
  FILE *fp;
  fp = fopen(filename, mode);
  if (fp == NULL) {
    printf("Error - can'jjt open or create file: %s\n", filename);
    exit(1);
  }
  return fp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<open_file>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: Error - can'jjt open or create file: %s


assistant: ```c
FILE *open_file(const char *filename, const char *mode) {
  FILE *fp;
  fp = fopen(filename, mode);
  if (fp == NULL) {
    printf("Error - can'jjt open or create file: %s\n", filename);
    exit(1);
  }
  return fp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcpy_new(const char *s) {
  size_t n = 1 + strlen(s);
  char *p = malloc(n * sizeof(char));
  strncpy(p, s, n);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy_new>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcpy_new(const char *s) {
  size_t n = 1 + strlen(s);
  char *p = malloc(n * sizeof(char));
  strncpy(p, s, n);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strcpy_new>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strcpy_new(const char *s) {
  size_t n = 1 + strlen(s);
  char *p = malloc(n * sizeof(char));
  strncpy(p, s, n);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy_new>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strcpy_new(const char *s) {
  size_t n = 1 + strlen(s);
  char *p = malloc(n * sizeof(char));
  strncpy(p, s, n);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x206f6c706d656a65,%rax
  movabs $0x662f657469727766,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x64616572,-0x10(%rbp)
  movb   $0x0,-0xc(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x48(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  jne    L25
  mov    $0xffffffff,%eax
  jmp    L9
L25:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    -0x48(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    -0x48(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fread@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
datatype: string
name: extract_symbolic_data
arguments: data_label: D23
datatype: string
name: extract_symbolic_data
arguments: data_label: D24
datatype: string

tool: D21: w+

tool: D23: datos.dat

tool: D24: %s


assistant: ```c
int main() {
  FILE *fp;
  char c[] = "ejemplo fwrite/fread";
  char buffer[20];
  fp = fopen("datos.dat", "w+");
  if (fp == NULL)
    return -1;
  fwrite(c, strlen(c) + 1, 1, fp);
  rewind(fp);
  fread(buffer, strlen(c) + 1, 1, fp);
  printf("%s\n", buffer);
  fclose(fp);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x206f6c706d656a65,%rax
  movabs $0x662f657469727766,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movl   $0x64616572,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  lea    D1(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rbx
  lea    0x20(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <rewind@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    %rsp,%rbp
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <fread@plt>
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L6:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L6
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D16
type_guessed: string
name: read_data
arguments: data_tag: D27
type_guessed: string

tool: D1: w+

tool: D16: datos.dat

tool: D27: %s


assistant: ```c
int main() {
  FILE *fp;
  char c[] = "ejemplo fwrite/fread";
  char buffer[20];
  fp = fopen("datos.dat", "w+");
  if (fp == NULL)
    return -1;
  fwrite(c, strlen(c) + 1, 1, fp);
  rewind(fp);
  fread(buffer, strlen(c) + 1, 1, fp);
  printf("%s\n", buffer);
  fclose(fp);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rsi
  lea    D17(%rip),%rdi
  push   %rbp
  sub    $0x48,%rsp
  movdqa D2(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x64616572,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L12
  lea    0x20(%rsp),%r12
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    %r12,%rdi
  lea    0x1(%rax),%rsi
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    %r12,%rdi
  mov    %rsp,%r12
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    %r12,%rdi
  lea    0x1(%rax),%rsi
  call   <fread@plt>
  mov    %r12,%rsi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L16:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
L12:
  or     $0xffffffff,%eax
  jmp    L16
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
data_type: string
name: read_data
arguments: label: D17
data_type: string
name: read_data
arguments: label: D2
data_type: byte[16]
name: read_data
arguments: label: D32
data_type: string

tool: D5: w+

tool: D17: datos.dat

tool: {"D2": [0x65,0x6a,0x65,0x6d,0x70,0x6c,0x6f,0x20,0x66,0x77,0x72,0x69,0x74,0x65,0x2f,0x66]}

tool: D32: %s


assistant: ```c
int main() {
  FILE *fp;
  char c[] = "ejemplo fwrite/fread";
  char buffer[20];
  fp = fopen("datos.dat", "w+");
  if (fp == NULL)
    return -1;
  fwrite(c, strlen(c) + 1, 1, fp);
  rewind(fp);
  fread(buffer, strlen(c) + 1, 1, fp);
  printf("%s\n", buffer);
  fclose(fp);
  return 0;
}
```