ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x40,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memclr@plt>
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L7
  lea    0x1(%rbp),%rsi
  mov    $0x1,%edi
  xchg   %ax,%ax
L44:
  movsbq %cl,%rax
  mov    %edi,%edx
  and    $0xf,%ecx
  add    $0x1,%rsi
  shl    %cl,%edx
  movzbl -0x1(%rsi),%ecx
  shr    $0x4,%rax
  or     %edx,(%rsp,%rax,4)
  test   %cl,%cl
  jne    L44
L7:
  movzbl (%rbx),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L8
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L46:
  add    $0x1,%r8
  movzbl (%rbx,%r8,1),%eax
  test   %al,%al
  je     L55
L8:
  movsbq %al,%rdx
  and    $0xf,%eax
  shr    $0x4,%rdx
  mov    (%rsp,%rdx,4),%edx
  not    %edx
  bt     %eax,%edx
  jae    L46
L55:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x58,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t strspn(const char *s, const char *accept) {
  uint16_t mask[16];
  size_t i;
  memclr(mask, sizeof(uint16_t) * 16);
  for (i = 0; accept[i]; i++) {
    mask[(size_t)accept[i] >> 4] |= (1 << ((size_t)accept[i] & 0xF));
  }
  for (i = 0; s[i]; i++) {
    if (~mask[(size_t)s[i] >> 4] & (1 << ((size_t)s[i] & 0xF))) {
      break;
    }
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_find_not_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L78
L44:
  cmpq   $0x0,-0x20(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L78
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_len@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L59
L32:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L36
  mov    -0x10(%rbp),%rax
  jmp    L78
L36:
  addq   $0x1,-0x10(%rbp)
L59:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L32
  mov    $0x0,%eax
L78:
  leave
  ret
```

assistant: ```c
char *str_find_not_char(char *haystack, char *needles) {
  char *str = NULL;
  size_t len_haystack;
  if (haystack == NULL)
    return (NULL);
  if (needles == NULL)
    return (NULL);
  len_haystack = str_len(haystack);
  for (str = haystack; str < haystack + len_haystack; str++) {
    if (strchr(needles, *str) == NULL)
      return (str);
  }
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_find_not_char>:
  endbr64
  test   %rsi,%rsi
  je     L62
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L3
  call   <str_len@plt>
  lea    (%rbx,%rax,1),%r12
  cmp    %r12,%rbx
  jae    L40
L19:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L34
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L19
  mov    $0x0,%eax
  jmp    L45
L3:
  mov    $0x0,%eax
  jmp    L45
L40:
  mov    $0x0,%eax
  jmp    L45
L34:
  mov    %rbx,%rax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L62:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *str_find_not_char(char *haystack, char *needles) {
  char *str = NULL;
  size_t len_haystack;
  if (haystack == NULL)
    return (NULL);
  if (needles == NULL)
    return (NULL);
  len_haystack = str_len(haystack);
  for (str = haystack; str < haystack + len_haystack; str++) {
    if (strchr(needles, *str) == NULL)
      return (str);
  }
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_find_not_char>:
  endbr64
  test   %rsi,%rsi
  je     L16
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L2
  mov    %rsi,%rbp
  call   <str_len@plt>
  lea    (%rbx,%rax,1),%r12
  cmp    %r12,%rbx
  jb     L48
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L2
L48:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L13
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *str_find_not_char(char *haystack, char *needles) {
  char *str = NULL;
  size_t len_haystack;
  if (haystack == NULL)
    return (NULL);
  if (needles == NULL)
    return (NULL);
  len_haystack = str_len(haystack);
  for (str = haystack; str < haystack + len_haystack; str++) {
    if (strchr(needles, *str) == NULL)
      return (str);
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_find_not_char>:
  endbr64
  test   %rsi,%rsi
  je     L35
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L40
  mov    %rsi,%rbp
  call   <str_len@plt>
  lea    (%rbx,%rax,1),%r12
  cmp    %r12,%rbx
  jb     L59
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L40
L59:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L45
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L40:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *str_find_not_char(char *haystack, char *needles) {
  char *str = NULL;
  size_t len_haystack;
  if (haystack == NULL)
    return (NULL);
  if (needles == NULL)
    return (NULL);
  len_haystack = str_len(haystack);
  for (str = haystack; str < haystack + len_haystack; str++) {
    if (strchr(needles, *str) == NULL)
      return (str);
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0xd,%edx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x20,%ecx
  mov    $0xa,%edx
  mov    $0x3,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <conv@plt>
  mov    $0x3,%edx
  mov    %eax,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x1,%edx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string

tool: D17: FATAL ERROR: 

tool: D11: 


assistant: ```c
fatal(n) {
  write(1, "FATAL ERROR: ", 13);
  write(1, conv(n, 3, 10, ' '), 3);
  write(1, "\n", 1);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fatal>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xd,%edx
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x20,%ecx
  mov    $0xa,%edx
  mov    $0x3,%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <conv@plt>
  mov    %eax,%esi
  mov    $0x3,%edx
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x1,%edx
  lea    D12(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D12
data_type: string

tool: D1: FATAL ERROR: 

tool: D12: 


assistant: ```c
fatal(n) {
  write(1, "FATAL ERROR: ", 13);
  write(1, conv(n, 3, 10, ' '), 3);
  write(1, "\n", 1);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fatal>:
  endbr64
  push   %rbp
  mov    $0xd,%edx
  mov    %edi,%ebp
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <write@plt>
  mov    $0x20,%ecx
  mov    %ebp,%edi
  xor    %eax,%eax
  mov    $0xa,%edx
  mov    $0x3,%esi
  call   <conv@plt>
  mov    $0x3,%edx
  mov    $0x1,%edi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <write@plt>
  mov    $0x1,%edi
  mov    $0x1,%edx
  xor    %eax,%eax
  lea    D19(%rip),%rsi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D19
datatype: string

tool: D0: FATAL ERROR: 

tool: D19: 


assistant: ```c
fatal(n) {
  write(1, "FATAL ERROR: ", 13);
  write(1, conv(n, 3, 10, ' '), 3);
  write(1, "\n", 1);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fatal>:
  endbr64
  push   %rbp
  mov    $0xd,%edx
  mov    %edi,%ebp
  lea    D19(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <write@plt>
  mov    $0x20,%ecx
  mov    %ebp,%edi
  xor    %eax,%eax
  mov    $0xa,%edx
  mov    $0x3,%esi
  call   <conv@plt>
  mov    $0x3,%edx
  mov    $0x1,%edi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <write@plt>
  mov    $0x1,%edi
  mov    $0x1,%edx
  xor    %eax,%eax
  lea    D15(%rip),%rsi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D15
type_infered: string

tool: D19: FATAL ERROR: 

tool: D15: 


assistant: ```c
fatal(n) {
  write(1, "FATAL ERROR: ", 13);
  write(1, conv(n, 3, 10, ' '), 3);
  write(1, "\n", 1);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sshbuf_get_stringb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sshbuf_peek_string_direct@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L41
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sshbuf_get_u32@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L41
  mov    -0x18(%rbp),%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sshbuf_reserve@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L41
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sshbuf_get@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L27
L41:
  mov    -0x14(%rbp),%eax
  jmp    L45
L27:
  mov    $0x0,%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int sshbuf_get_stringb(struct sshbuf *buf, struct sshbuf *v) {
  u_int32_t len;
  u_char *p;
  int r;
  if ((r = sshbuf_peek_string_direct(buf, NULL, NULL)) != 0 || (r = sshbuf_get_u32(buf, &len)) != 0 || (r = sshbuf_reserve(v, len, &p)) != 0 || (r = sshbuf_get(buf, p, len)) != 0)
    return r;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sshbuf_get_stringb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <sshbuf_peek_string_direct@plt>
  test   %eax,%eax
  je     L29
L0:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <sshbuf_get_u32@plt>
  test   %eax,%eax
  jne    L0
  lea    0x10(%rsp),%rdx
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <sshbuf_reserve@plt>
  test   %eax,%eax
  jne    L0
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <sshbuf_get@plt>
  jmp    L0
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sshbuf_get_stringb(struct sshbuf *buf, struct sshbuf *v) {
  u_int32_t len;
  u_char *p;
  int r;
  if ((r = sshbuf_peek_string_direct(buf, NULL, NULL)) != 0 || (r = sshbuf_get_u32(buf, &len)) != 0 || (r = sshbuf_reserve(v, len, &p)) != 0 || (r = sshbuf_get(buf, p, len)) != 0)
    return r;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sshbuf_get_stringb>:
  endbr64
  push   %r12
  xor    %edx,%edx
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <sshbuf_peek_string_direct@plt>
  test   %eax,%eax
  je     L8
L23:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <sshbuf_get_u32@plt>
  test   %eax,%eax
  jne    L23
  mov    0xc(%rsp),%esi
  lea    0x10(%rsp),%rdx
  mov    %r12,%rdi
  call   <sshbuf_reserve@plt>
  test   %eax,%eax
  jne    L23
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <sshbuf_get@plt>
  jmp    L23
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sshbuf_get_stringb(struct sshbuf *buf, struct sshbuf *v) {
  u_int32_t len;
  u_char *p;
  int r;
  if ((r = sshbuf_peek_string_direct(buf, NULL, NULL)) != 0 || (r = sshbuf_get_u32(buf, &len)) != 0 || (r = sshbuf_reserve(v, len, &p)) != 0 || (r = sshbuf_get(buf, p, len)) != 0)
    return r;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sshbuf_get_stringb>:
  endbr64
  push   %r12
  xor    %edx,%edx
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <sshbuf_peek_string_direct@plt>
  test   %eax,%eax
  je     L25
L42:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <sshbuf_get_u32@plt>
  test   %eax,%eax
  jne    L42
  mov    0xc(%rsp),%esi
  lea    0x10(%rsp),%rdx
  mov    %r12,%rdi
  call   <sshbuf_reserve@plt>
  test   %eax,%eax
  jne    L42
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <sshbuf_get@plt>
  jmp    L42
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sshbuf_get_stringb(struct sshbuf *buf, struct sshbuf *v) {
  u_int32_t len;
  u_char *p;
  int r;
  if ((r = sshbuf_peek_string_direct(buf, NULL, NULL)) != 0 || (r = sshbuf_get_u32(buf, &len)) != 0 || (r = sshbuf_reserve(v, len, &p)) != 0 || (r = sshbuf_get(buf, p, len)) != 0)
    return r;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7,-0x30(%rbp)
  movl   $0x8,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x4,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  lea    -0x60(%rbp),%rax
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <quick_sort@plt>
  movl   $0x0,-0x64(%rbp)
  jmp    L22
L11:
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x64(%rbp)
L22:
  cmpl   $0x9,-0x64(%rbp)
  jle    L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D0: %d

assistant: ```c
int main() {
  int x[10];
  memcpy(x, (int[]){7, 8, 6, 5, 3, 4, 2, 1, 9, 0}, sizeof x);
  quick_sort(x, 0, 9);
  for (int i = 0; i < 10; i++)
    printf("%d", x[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x7,(%rsp)
  movl   $0x8,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  mov    %rsp,%rbx
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <quick_sort@plt>
  lea    0x28(%rsp),%r12
  lea    D9(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: %d

assistant: ```c
int main() {
  int x[10];
  memcpy(x, (int[]){7, 8, 6, 5, 3, 4, 2, 1, 9, 0}, sizeof x);
  quick_sort(x, 0, 9);
  for (int i = 0; i < 10; i++)
    printf("%d", x[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x800000007,%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  movq   $0x9,0x20(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x500000006,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <quick_sort@plt>
  xchg   %ax,%ax
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  int x[10];
  memcpy(x, (int[]){7, 8, 6, 5, 3, 4, 2, 1, 9, 0}, sizeof x);
  quick_sort(x, 0, 9);
  for (int i = 0; i < 10; i++)
    printf("%d", x[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D32(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D31(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D28(%rip),%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D5(%rip),%xmm0
  mov    %rbx,%rdi
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <quick_sort@plt>
  nopl   0x0(%rax)
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L1
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D32
type: string
name: retrieve_data
arguments: label: D31
type: byte[16]
name: retrieve_data
arguments: label: D28
type: byte[8]
name: retrieve_data
arguments: label: D5
type: byte[16]

tool: D32: %d

tool: {"D31": [0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D28": [0x09,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D5": [0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int x[10];
  memcpy(x, (int[]){7, 8, 6, 5, 3, 4, 2, 1, 9, 0}, sizeof x);
  quick_sort(x, 0, 9);
  for (int i = 0; i < 10; i++)
    printf("%d", x[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<step_regress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L33
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  sub    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L11:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L11
  subl   $0x1,-0xc(%rbp)
L33:
  cmpl   $0x1,-0xc(%rbp)
  jle    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void step_regress(r_bar, theta_bar, beta, ivars) float *r_bar, *theta_bar, *beta;
int ivars;
{
  int i, k, next_r;
  for (i = ivars; i <= 1; i--) {
    beta[i] = theta_bar[i];
    next_r = (i - 1) * (2 * ivars - i) / 2 + 1;
    for (k = i + 1; k <= ivars; k++) {
      beta[i] = beta[i] - r_bar[next_r] * beta[k];
      next_r++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<step_regress>:
  endbr64
  cmp    $0x1,%ecx
  jg     L17
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rdx,%rdi
  mov    %ecx,%esi
  movslq %ecx,%r9
  lea    (%rdx,%r9,4),%r10
  lea    0x1(%rcx),%ebp
  neg    %r9
  shl    $0x2,%r9
  mov    %ecx,%r8d
  lea    -0x1(%rcx,%rcx,1),%r12d
L5:
  mov    %r9,%rax
  neg    %rax
  movss  (%rbx,%rax,1),%xmm0
  mov    %r10,%rdx
  movss  %xmm0,(%r10)
  sub    $0x1,%r8d
  mov    %r12d,%ecx
  sub    %r8d,%ecx
  imul   %r8d,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%ecx
  cmp    %ebp,%esi
  jl     L20
  movslq %ebp,%rax
  movslq %ecx,%rcx
  lea    (%r9,%rcx,4),%rcx
  add    %r11,%rcx
L33:
  movss  (%rcx,%rax,4),%xmm1
  mulss  (%rdi,%rax,4),%xmm1
  movss  (%rdx),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L33
L20:
  sub    $0x4,%r10
  sub    $0x1,%ebp
  add    $0x4,%r9
  cmp    $0x1,%r8d
  jle    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  ret
```

assistant: ```c
void step_regress(r_bar, theta_bar, beta, ivars) float *r_bar, *theta_bar, *beta;
int ivars;
{
  int i, k, next_r;
  for (i = ivars; i <= 1; i--) {
    beta[i] = theta_bar[i];
    next_r = (i - 1) * (2 * ivars - i) / 2 + 1;
    for (k = i + 1; k <= ivars; k++) {
      beta[i] = beta[i] - r_bar[next_r] * beta[k];
      next_r++;
    }
  }
}
```