ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D50(%rip),%rax
  mov    %rax,(%rsp)
  mov    D30(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D65(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D18(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D27(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D45(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    %rsp,%rdi
  mov    $0x6,%esi
  call   <median@plt>
  mov    %eax,%esi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D50
type: f64
name: retrieve_data
arguments: data_tag: D30
type: f64
name: retrieve_data
arguments: data_tag: D65
type: f64
name: retrieve_data
arguments: data_tag: D18
type: f64
name: retrieve_data
arguments: data_tag: D27
type: f64
name: retrieve_data
arguments: data_tag: D45
type: f64
name: retrieve_data
arguments: data_tag: D40
type: string

tool: D50: 12.2

tool: D30: 10

tool: D65: 13.4

tool: D18: 14.5

tool: D27: 56.2

tool: D45: 23.3

tool: D40: Median is %lf.


assistant: ```c
int main(int argc, const char *argv[]) {
  double array[] = {12.2, 10.0, 13.4, 14.5, 56.2, 23.3};
  int nArray = sizeof(array) / sizeof(array[0]);
  printf("Median is %lf.\n", median(array, nArray));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x6,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D47(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  mov    D27(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D52(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D2(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D32(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D33(%rip),%rax
  mov    %rax,0x28(%rsp)
  call   <median@plt>
  lea    D62(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D47
type: f64
name: unpack_data
arguments: data_tag: D27
type: f64
name: unpack_data
arguments: data_tag: D52
type: f64
name: unpack_data
arguments: data_tag: D2
type: f64
name: unpack_data
arguments: data_tag: D32
type: f64
name: unpack_data
arguments: data_tag: D33
type: f64
name: unpack_data
arguments: data_tag: D62
type: string

tool: D47: 12.2

tool: D27: 10

tool: D52: 13.4

tool: D2: 14.5

tool: D32: 56.2

tool: D33: 23.3

tool: D62: Median is %lf.


assistant: ```c
int main(int argc, const char *argv[]) {
  double array[] = {12.2, 10.0, 13.4, 14.5, 56.2, 23.3};
  int nArray = sizeof(array) / sizeof(array[0]);
  printf("Median is %lf.\n", median(array, nArray));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  movapd D20(%rip),%xmm0
  mov    $0x6,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movapd D12(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movapd D1(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <median@plt>
  lea    D33(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D20
datatype: f64[2]
name: disassemble_data
arguments: data_label: D12
datatype: f64[2]
name: disassemble_data
arguments: data_label: D1
datatype: f64[2]
name: disassemble_data
arguments: data_label: D33
datatype: string

tool: {"D20": [12.2,10.0]}

tool: {"D12": [13.4,14.5]}

tool: {"D1": [56.2,23.3]}

tool: D33: Median is %lf.


assistant: ```c
int main(int argc, const char *argv[]) {
  double array[] = {12.2, 10.0, 13.4, 14.5, 56.2, 23.3};
  int nArray = sizeof(array) / sizeof(array[0]);
  printf("Median is %lf.\n", median(array, nArray));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<vp8_sad16x16x8_c>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %ecx,%r14d
  mov    %r8,%rbp
  mov    D3(%rip),%r15
  mov    (%r15),%r8d
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0x0(%rbp)
  lea    0x1(%rbx),%rdx
  mov    (%r15),%r8d
  mov    %r14d,%ecx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0x2(%rbp)
  lea    0x2(%rbx),%rdx
  mov    (%r15),%r8d
  mov    %r14d,%ecx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0x4(%rbp)
  lea    0x3(%rbx),%rdx
  mov    (%r15),%r8d
  mov    %r14d,%ecx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0x6(%rbp)
  lea    0x4(%rbx),%rdx
  mov    (%r15),%r8d
  mov    %r14d,%ecx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0x8(%rbp)
  lea    0x5(%rbx),%rdx
  mov    (%r15),%r8d
  mov    %r14d,%ecx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0xa(%rbp)
  lea    0x6(%rbx),%rdx
  mov    (%r15),%r8d
  mov    %r14d,%ecx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0xc(%rbp)
  lea    0x7(%rbx),%rdx
  mov    (%r15),%r8d
  mov    %r14d,%ecx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0xe(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void vp8_sad16x16x8_c(const unsigned char *src_ptr, int src_stride, const unsigned char *ref_ptr, int ref_stride, unsigned short *sad_array) {
  sad_array[0] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 0, ref_stride, UINT_MAX);
  sad_array[1] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 1, ref_stride, UINT_MAX);
  sad_array[2] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 2, ref_stride, UINT_MAX);
  sad_array[3] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 3, ref_stride, UINT_MAX);
  sad_array[4] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 4, ref_stride, UINT_MAX);
  sad_array[5] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 5, ref_stride, UINT_MAX);
  sad_array[6] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 6, ref_stride, UINT_MAX);
  sad_array[7] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 7, ref_stride, UINT_MAX);
}
```
user: What is the c source code of the assembly code below?

```asm
<vp8_sad16x16x8_c>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%r14
  mov    (%r14),%r8d
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x1(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x0(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x2(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x2(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x3(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x4(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x4(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x6(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x5(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x8(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x6(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0xa(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x7(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0xc(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0xe(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void vp8_sad16x16x8_c(const unsigned char *src_ptr, int src_stride, const unsigned char *ref_ptr, int ref_stride, unsigned short *sad_array) {
  sad_array[0] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 0, ref_stride, UINT_MAX);
  sad_array[1] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 1, ref_stride, UINT_MAX);
  sad_array[2] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 2, ref_stride, UINT_MAX);
  sad_array[3] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 3, ref_stride, UINT_MAX);
  sad_array[4] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 4, ref_stride, UINT_MAX);
  sad_array[5] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 5, ref_stride, UINT_MAX);
  sad_array[6] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 6, ref_stride, UINT_MAX);
  sad_array[7] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 7, ref_stride, UINT_MAX);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vp8_sad16x16x8_c>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%r14
  mov    (%r14),%r8d
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x1(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x0(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x2(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x2(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x3(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x4(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x4(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x6(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x5(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0x8(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x6(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0xa(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    (%r14),%r8d
  lea    0x7(%rbx),%rdx
  mov    %r15d,%ecx
  mov    %ax,0xc(%r13)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vp8_sad16x16_c@plt>
  mov    %ax,0xe(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void vp8_sad16x16x8_c(const unsigned char *src_ptr, int src_stride, const unsigned char *ref_ptr, int ref_stride, unsigned short *sad_array) {
  sad_array[0] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 0, ref_stride, UINT_MAX);
  sad_array[1] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 1, ref_stride, UINT_MAX);
  sad_array[2] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 2, ref_stride, UINT_MAX);
  sad_array[3] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 3, ref_stride, UINT_MAX);
  sad_array[4] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 4, ref_stride, UINT_MAX);
  sad_array[5] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 5, ref_stride, UINT_MAX);
  sad_array[6] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 6, ref_stride, UINT_MAX);
  sad_array[7] = (unsigned short)vp8_sad16x16_c(src_ptr, src_stride, ref_ptr + 7, ref_stride, UINT_MAX);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f57206f6c6c6548,%rax
  mov    %rax,-0x15(%rbp)
  movl   $0xa646c72,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L20
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x1c(%rbp)
L20:
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9: %s

assistant: ```c
int main(int argc, char const *argv[]) {
  char string[] = "Hello World\n";
  int i;
  printf("%s", string);
  for (i = 0; string[i] != '\0'; ++i) {
    printf("%c", string[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6f57206f6c6c6548,%rax
  mov    %rax,0xb(%rsp)
  movl   $0xa646c72,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0xb(%rsp),%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl 0xb(%rsp),%edi
  test   %dil,%dil
  je     L23
  lea    0xc(%rsp),%rbx
L29:
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L29
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4: %s

assistant: ```c
int main(int argc, char const *argv[]) {
  char string[] = "Hello World\n";
  int i;
  printf("%s", string);
  for (i = 0; string[i] != '\0'; ++i) {
    printf("%c", string[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6f57206f6c6c6548,%rax
  lea    0xb(%rsp),%rsi
  movl   $0xa646c72,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0xb(%rsp),%edi
  test   %dil,%dil
  je     L1
  lea    0xc(%rsp),%rbx
  nopl   (%rax)
L2:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L2
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: %s

assistant: ```c
int main(int argc, char const *argv[]) {
  char string[] = "Hello World\n";
  int i;
  printf("%s", string);
  for (i = 0; string[i] != '\0'; ++i) {
    printf("%c", string[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6f57206f6c6c6548,%rax
  lea    0xb(%rsp),%rsi
  movl   $0xa646c72,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0xb(%rsp),%edi
  test   %dil,%dil
  je     L16
  lea    0xc(%rsp),%rbx
  nopl   (%rax)
L13:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L13
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: %s

assistant: ```c
int main(int argc, char const *argv[]) {
  char string[] = "Hello World\n";
  int i;
  printf("%s", string);
  for (i = 0; string[i] != '\0'; ++i) {
    printf("%c", string[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<configureMultiProtocolRtlsPatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x210003d4,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x48,%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x144,%rax
  movl   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x68,%rax
  movl   $0x3,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x130,%rax
  movl   $0x4,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xf8,%rax
  movl   $0x5,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x100,%rax
  movl   $0x6,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x16c,%rax
  movl   $0x7,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x13c,%rax
  movl   $0x8,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2a0,%rax
  movl   $0x9,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void configureMultiProtocolRtlsPatch(void) {
  uint8_t *pPatchTab = (uint8_t *)(0x21000000 + 0x03D4);
  pPatchTab[1] = 0;
  pPatchTab[18] = 1;
  pPatchTab[81] = 2;
  pPatchTab[26] = 3;
  pPatchTab[76] = 4;
  pPatchTab[62] = 5;
  pPatchTab[64] = 6;
  pPatchTab[91] = 7;
  pPatchTab[79] = 8;
  pPatchTab[168] = 9;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<configureMultiProtocolRtlsPatch>:
  endbr64
  movl   $0x0,0x210003d8
  movl   $0x1,0x2100041c
  movl   $0x2,0x21000518
  movl   $0x3,0x2100043c
  movl   $0x4,0x21000504
  movl   $0x5,0x210004cc
  movl   $0x6,0x210004d4
  movl   $0x7,0x21000540
  movl   $0x8,0x21000510
  movl   $0x9,0x21000674
  ret
```

assistant: ```c
void configureMultiProtocolRtlsPatch(void) {
  uint8_t *pPatchTab = (uint8_t *)(0x21000000 + 0x03D4);
  pPatchTab[1] = 0;
  pPatchTab[18] = 1;
  pPatchTab[81] = 2;
  pPatchTab[26] = 3;
  pPatchTab[76] = 4;
  pPatchTab[62] = 5;
  pPatchTab[64] = 6;
  pPatchTab[91] = 7;
  pPatchTab[79] = 8;
  pPatchTab[168] = 9;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<configureMultiProtocolRtlsPatch>:
  endbr64
  movl   $0x0,0x210003d8
  movl   $0x1,0x2100041c
  movl   $0x2,0x21000518
  movl   $0x3,0x2100043c
  movl   $0x4,0x21000504
  movl   $0x5,0x210004cc
  movl   $0x6,0x210004d4
  movl   $0x7,0x21000540
  movl   $0x8,0x21000510
  movl   $0x9,0x21000674
  ret
```

assistant: ```c
void configureMultiProtocolRtlsPatch(void) {
  uint8_t *pPatchTab = (uint8_t *)(0x21000000 + 0x03D4);
  pPatchTab[1] = 0;
  pPatchTab[18] = 1;
  pPatchTab[81] = 2;
  pPatchTab[26] = 3;
  pPatchTab[76] = 4;
  pPatchTab[62] = 5;
  pPatchTab[64] = 6;
  pPatchTab[91] = 7;
  pPatchTab[79] = 8;
  pPatchTab[168] = 9;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<configureMultiProtocolRtlsPatch>:
  endbr64
  movl   $0x0,0x210003d8
  movl   $0x1,0x2100041c
  movl   $0x2,0x21000518
  movl   $0x3,0x2100043c
  movl   $0x4,0x21000504
  movl   $0x5,0x210004cc
  movl   $0x6,0x210004d4
  movl   $0x7,0x21000540
  movl   $0x8,0x21000510
  movl   $0x9,0x21000674
  ret
```

assistant: ```c
void configureMultiProtocolRtlsPatch(void) {
  uint8_t *pPatchTab = (uint8_t *)(0x21000000 + 0x03D4);
  pPatchTab[1] = 0;
  pPatchTab[18] = 1;
  pPatchTab[81] = 2;
  pPatchTab[26] = 3;
  pPatchTab[76] = 4;
  pPatchTab[62] = 5;
  pPatchTab[64] = 6;
  pPatchTab[91] = 7;
  pPatchTab[79] = 8;
  pPatchTab[168] = 9;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cvector_normalize_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cvector_norm_l@plt>
  fstpt  -0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L2:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,-0x40(%rbp)
  fldl   -0x40(%rbp)
  fldt   -0x10(%rbp)
  fdivrp %st,%st(1)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  fstpl  -0x40(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void cvector_normalize_l(double *vdest, const double *vorg, int n) {
  long double norm_l = cvector_norm_l(vorg, n);
  for (int i = 0; i < n; i++) {
    vdest[i] = vorg[i] / norm_l;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvector_normalize_l>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %edx,%esi
  mov    %rbp,%rdi
  call   <cvector_norm_l@plt>
  test   %ebx,%ebx
  jle    L9
  mov    %ebx,%edx
  mov    $0x0,%eax
L8:
  fld    %st(0)
  fdivrl 0x0(%rbp,%rax,8)
  fstpl  (%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
  fstp   %st(0)
  jmp    L29
L9:
  fstp   %st(0)
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void cvector_normalize_l(double *vdest, const double *vorg, int n) {
  long double norm_l = cvector_norm_l(vorg, n);
  for (int i = 0; i < n; i++) {
    vdest[i] = vorg[i] / norm_l;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cvector_normalize_l>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %edx,%esi
  push   %rbx
  mov    %rbp,%rdi
  mov    %edx,%ebx
  call   <cvector_norm_l@plt>
  test   %ebx,%ebx
  jle    L27
  movslq %ebx,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L18:
  fld    %st(0)
  fdivrl 0x0(%rbp,%rax,8)
  fstpl  (%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L18
  fstp   %st(0)
  jmp    L5
  nop
L27:
  fstp   %st(0)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void cvector_normalize_l(double *vdest, const double *vorg, int n) {
  long double norm_l = cvector_norm_l(vorg, n);
  for (int i = 0; i < n; i++) {
    vdest[i] = vorg[i] / norm_l;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cvector_normalize_l>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %edx,%esi
  push   %rbx
  mov    %rbp,%rdi
  mov    %edx,%ebx
  call   <cvector_norm_l@plt>
  test   %ebx,%ebx
  jle    L1
  movslq %ebx,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L4:
  fld    %st(0)
  fdivrl 0x0(%rbp,%rax,8)
  fstpl  (%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
  fstp   %st(0)
  jmp    L2
  nop
L1:
  fstp   %st(0)
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void cvector_normalize_l(double *vdest, const double *vorg, int n) {
  long double norm_l = cvector_norm_l(vorg, n);
  for (int i = 0; i < n; i++) {
    vdest[i] = vorg[i] / norm_l;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<to_next_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  jmp    L0
L1:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%rax
L0:
  leave
  ret
```

assistant: ```c
size_t to_next_line(char *b, size_t l) {
  char *p = memchr(b, '\n', l);
  if (!p) {
    return l + 1;
  }
  return p - b + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<to_next_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  mov    $0xa,%esi
  call   <memchr@plt>
  add    $0x1,%rbx
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    $0x1,%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t to_next_line(char *b, size_t l) {
  char *p = memchr(b, '\n', l);
  if (!p) {
    return l + 1;
  }
  return p - b + 1;
}
```