ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gate_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__wasi_proc_exit@plt>
```

assistant: ```c
__attribute__((noreturn)) void gate_exit(int status) {
  __attribute__((noreturn)) void __wasi_proc_exit(uint32_t);
  __wasi_proc_exit(status);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gate_exit>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__wasi_proc_exit@plt>
```

assistant: ```c
__attribute__((noreturn)) void gate_exit(int status) {
  __attribute__((noreturn)) void __wasi_proc_exit(uint32_t);
  __wasi_proc_exit(status);
}
```
user: What is the c source code of the assembly code below:

```asm
<gate_exit>:
  endbr64
  push   %rax
  pop    %rax
  xor    %eax,%eax
  sub    $0x8,%rsp
  call   <__wasi_proc_exit@plt>
```

assistant: ```c
__attribute__((noreturn)) void gate_exit(int status) {
  __attribute__((noreturn)) void __wasi_proc_exit(uint32_t);
  __wasi_proc_exit(status);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gate_exit>:
  endbr64
  push   %rax
  pop    %rax
  xor    %eax,%eax
  sub    $0x8,%rsp
  call   <__wasi_proc_exit@plt>
```

assistant: ```c
__attribute__((noreturn)) void gate_exit(int status) {
  __attribute__((noreturn)) void __wasi_proc_exit(uint32_t);
  __wasi_proc_exit(status);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  long maplength;
  int type;
  {
    const long nibbles = 8;
    char buf1[nibbles + 1];
    char buf2[nibbles + 1];
    char buf3[nibbles + 1];
    buf1[nibbles] = '\0';
    buf2[nibbles] = '\0';
    buf3[nibbles] = '\0';
    ((nibbles) <= 16 ? (({
      void *__s = (buf1);
      union {
        unsigned int __ui;
        unsigned short int __usi;
        unsigned char __uc;
      } *__u = __s;
      unsigned char __c = (unsigned char)('0');
      switch ((unsigned int)(nibbles)) {
      case 16:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 12:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 0:
        break;
      }
      __s;
    }))
                     : 0);
    ((nibbles) <= 16 ? (({
      void *__s = (buf2);
      union {
        unsigned int __ui;
        unsigned short int __usi;
        unsigned char __uc;
      } *__u = __s;
      unsigned char __c = (unsigned char)('0');
      switch ((unsigned int)(nibbles)) {
      case 16:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 12:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 8:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 4:
        __u->__ui = __c * 0x01010101;
      case 0:
        break;
      }
      __s;
    }))
                     : 0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  long maplength;
  int type;
  {
    const long nibbles = 8;
    char buf1[nibbles + 1];
    char buf2[nibbles + 1];
    char buf3[nibbles + 1];
    buf1[nibbles] = '\0';
    buf2[nibbles] = '\0';
    buf3[nibbles] = '\0';
    ((nibbles) <= 16 ? (({
      void *__s = (buf1);
      union {
        unsigned int __ui;
        unsigned short int __usi;
        unsigned char __uc;
      } *__u = __s;
      unsigned char __c = (unsigned char)('0');
      switch ((unsigned int)(nibbles)) {
      case 16:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 12:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 0:
        break;
      }
      __s;
    }))
                     : 0);
    ((nibbles) <= 16 ? (({
      void *__s = (buf2);
      union {
        unsigned int __ui;
        unsigned short int __usi;
        unsigned char __uc;
      } *__u = __s;
      unsigned char __c = (unsigned char)('0');
      switch ((unsigned int)(nibbles)) {
      case 16:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 12:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 8:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 4:
        __u->__ui = __c * 0x01010101;
      case 0:
        break;
      }
      __s;
    }))
                     : 0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  long maplength;
  int type;
  {
    const long nibbles = 8;
    char buf1[nibbles + 1];
    char buf2[nibbles + 1];
    char buf3[nibbles + 1];
    buf1[nibbles] = '\0';
    buf2[nibbles] = '\0';
    buf3[nibbles] = '\0';
    ((nibbles) <= 16 ? (({
      void *__s = (buf1);
      union {
        unsigned int __ui;
        unsigned short int __usi;
        unsigned char __uc;
      } *__u = __s;
      unsigned char __c = (unsigned char)('0');
      switch ((unsigned int)(nibbles)) {
      case 16:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 12:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 0:
        break;
      }
      __s;
    }))
                     : 0);
    ((nibbles) <= 16 ? (({
      void *__s = (buf2);
      union {
        unsigned int __ui;
        unsigned short int __usi;
        unsigned char __uc;
      } *__u = __s;
      unsigned char __c = (unsigned char)('0');
      switch ((unsigned int)(nibbles)) {
      case 16:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 12:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 8:
        __u->__ui = __c * 0x01010101;
        __u = __extension__((void *)__u + 4);
      case 4:
        __u->__ui = __c * 0x01010101;
      case 0:
        break;
      }
      __s;
    }))
                     : 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x21c(%rbp)
  movl   $0x0,-0x218(%rbp)
  movl   $0x0,-0x214(%rbp)
  jmp    L85
L53:
  mov    -0x21c(%rbp),%eax
  mov    %eax,-0x218(%rbp)
  jmp    L29
L24:
  mov    -0x218(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x228(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L119
  addl   $0x1,-0x218(%rbp)
L29:
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x218(%rbp)
  jl     L24
  jmp    L129
L119:
  nop
L129:
  mov    -0x21c(%rbp),%eax
  mov    %eax,-0x220(%rbp)
  jmp    L115
L2:
  mov    -0x220(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x228(%rbp),%rax
  add    %rax,%rdx
  mov    -0x220(%rbp),%eax
  sub    -0x21c(%rbp),%eax
  movzbl (%rdx),%edx
  cltq
  mov    %dl,-0x210(%rbp,%rax,1)
  addl   $0x1,-0x220(%rbp)
L115:
  mov    -0x220(%rbp),%eax
  cmp    -0x218(%rbp),%eax
  jle    L2
  mov    -0x220(%rbp),%eax
  sub    -0x21c(%rbp),%eax
  cltq
  movb   $0x0,-0x210(%rbp,%rax,1)
  mov    -0x214(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x214(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x230(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  mov    -0x218(%rbp),%eax
  mov    %eax,-0x21c(%rbp)
  jmp    L89
L109:
  mov    -0x21c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x228(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L93
  jmp    L85
L93:
  addl   $0x1,-0x21c(%rbp)
L89:
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x21c(%rbp)
  jl     L109
L85:
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x21c(%rbp)
  jl     L53
  mov    -0x214(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L107
  call   <__stack_chk_fail@plt>
L107:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int getArray(char *string, double *array) {
  int i;
  int start, end, index;
  char tmp[500];
  start = 0;
  end = 0;
  index = 0;
  while (start <= (int)strlen(string) - 1) {
    for (end = start; end < (int)strlen(string); end++)
      if (string[end] == ' ')
        break;
    for (i = start; i <= end; i++)
      tmp[i - start] = string[i];
    tmp[i - start] = 0;
    array[index++] = atof(tmp);
    for (start = end; start < (int)strlen(string); start++)
      if (string[start] != ' ')
        break;
  }
  return (index);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getArray>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    %rsp,%r13
  jmp    L83
L48:
  mov    %rsi,%rax
  mov    %r13,%rcx
  sub    %rsi,%rcx
  cmp    %r15d,%ebp
  jg     L3
L102:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%r15d
  jge    L102
  lea    0x1(%r15),%eax
L49:
  sub    %ebp,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    %r13,%rdi
  call   <atof@plt>
  movsd  %xmm0,(%r14,%r12,8)
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %r15d,%rdx
L37:
  mov    %edx,%ebp
  cmp    %edx,%eax
  jle    L42
  add    $0x1,%rdx
  cmpb   $0x20,-0x1(%rbx,%rdx,1)
  je     L37
L42:
  add    $0x1,%r12
L83:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  cmp    %ebp,%eax
  jle    L94
  movslq %ebp,%rsi
  lea    (%rbx,%rsi,1),%rax
  mov    %ebp,%r15d
L54:
  cmpb   $0x20,(%rax)
  je     L48
  add    $0x1,%r15d
  add    $0x1,%rax
  cmp    %r15d,%edx
  jne    L54
  jmp    L48
L3:
  mov    %ebp,%eax
  jmp    L49
L94:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    %r12d,%eax
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getArray(char *string, double *array) {
  int i;
  int start, end, index;
  char tmp[500];
  start = 0;
  end = 0;
  index = 0;
  while (start <= (int)strlen(string) - 1) {
    for (end = start; end < (int)strlen(string); end++)
      if (string[end] == ' ')
        break;
    for (i = start; i <= end; i++)
      tmp[i - start] = string[i];
    tmp[i - start] = 0;
    array[index++] = atof(tmp);
    for (start = end; start < (int)strlen(string); start++)
      if (string[start] != ' ')
        break;
  }
  return (index);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getArray>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <strlen@plt>
  mov    %eax,%edx
  cmp    %r14d,%eax
  jle    L50
  cs nopw 0x0(%rax,%rax,1)
L9:
  movslq %r14d,%rsi
  mov    %r14d,%ebx
  add    %r15,%rsi
  mov    %rsi,%rax
  nopl   0x0(%rax)
L59:
  cmpb   $0x20,(%rax)
  je     L20
  add    $0x1,%ebx
  add    $0x1,%rax
  cmp    %ebx,%edx
  jne    L59
L20:
  mov    %ebx,%edx
  mov    %r12,%rdi
  sub    %r14d,%edx
  add    $0x1,%rdx
  call   <memcpy@plt>
  lea    0x1(%rbx),%eax
  mov    %r12,%rdi
  sub    %r14d,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  call   <atof@plt>
  mov    %r15,%rdi
  movsd  %xmm0,0x0(%r13,%rbp,8)
  call   <strlen@plt>
  movslq %ebx,%rdx
  mov    %eax,%ecx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L47:
  add    $0x1,%rdx
  cmpb   $0x20,-0x1(%r15,%rdx,1)
  jne    L56
L19:
  mov    %edx,%r14d
  cmp    %edx,%ecx
  jg     L47
L56:
  add    $0x1,%rbp
  mov    %eax,%edx
  cmp    %r14d,%eax
  jg     L9
L50:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x208,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getArray(char *string, double *array) {
  int i;
  int start, end, index;
  char tmp[500];
  start = 0;
  end = 0;
  index = 0;
  while (start <= (int)strlen(string) - 1) {
    for (end = start; end < (int)strlen(string); end++)
      if (string[end] == ' ')
        break;
    for (i = start; i <= end; i++)
      tmp[i - start] = string[i];
    tmp[i - start] = 0;
    array[index++] = atof(tmp);
    for (start = end; start < (int)strlen(string); start++)
      if (string[start] != ' ')
        break;
  }
  return (index);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getArray>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jle    L80
  mov    %eax,%ecx
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L56:
  movslq %r15d,%rsi
  mov    %r15d,%ebx
  add    %r13,%rsi
  mov    %rsi,%rax
  nopl   0x0(%rax)
L49:
  cmpb   $0x20,(%rax)
  je     L34
  add    $0x1,%ebx
  add    $0x1,%rax
  cmp    %ebx,%ecx
  jg     L49
  xor    %eax,%eax
  cmp    %r15d,%ebx
  jl     L78
L34:
  mov    %ebx,%edx
  mov    %r12,%rdi
  sub    %r15d,%edx
  add    $0x1,%rdx
  call   <memcpy@plt>
  lea    0x1(%rbx),%eax
  sub    %r15d,%eax
L78:
  cltq
  mov    %r12,%rdi
  lea    0x1(%rbp),%r14d
  movb   $0x0,0x10(%rsp,%rax,1)
  call   <atof@plt>
  mov    0x8(%rsp),%rax
  mov    %r13,%rdi
  movsd  %xmm0,(%rax,%rbp,8)
  call   <strlen@plt>
  movslq %ebx,%rdx
  mov    %eax,%ecx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x1,%rdx
  cmpb   $0x20,-0x1(%r13,%rdx,1)
  jne    L68
L30:
  mov    %edx,%r15d
  cmp    %edx,%ecx
  jg     L36
L68:
  add    $0x1,%rbp
  cmp    %r15d,%eax
  jg     L56
L7:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x218,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L80:
  xor    %r14d,%r14d
  jmp    L7
L83:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getArray(char *string, double *array) {
  int i;
  int start, end, index;
  char tmp[500];
  start = 0;
  end = 0;
  index = 0;
  while (start <= (int)strlen(string) - 1) {
    for (end = start; end < (int)strlen(string); end++)
      if (string[end] == ' ')
        break;
    for (i = start; i <= end; i++)
      tmp[i - start] = string[i];
    tmp[i - start] = 0;
    array[index++] = atof(tmp);
    for (start = end; start < (int)strlen(string); start++)
      if (string[start] != ' ')
        break;
  }
  return (index);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x330(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <backtrace@plt>
  mov    %eax,-0x33c(%rbp)
  mov    -0x33c(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x33c(%rbp),%edx
  lea    -0x330(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <backtrace_symbols@plt>
  mov    %rax,-0x338(%rbp)
  cmpq   $0x0,-0x338(%rbp)
  jne    L22
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L22:
  movl   $0x0,-0x340(%rbp)
  jmp    L5
L25:
  mov    -0x340(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x338(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x340(%rbp)
L5:
  mov    -0x340(%rbp),%eax
  cmp    -0x33c(%rbp),%eax
  jl     L25
  mov    -0x338(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L6:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type_guessed: string
name: disassemble_data
arguments: data_label: D17
type_guessed: string

tool: D13: backtrace() returned : %d 


tool: D17: backtrace_symbols returned NULL

assistant: ```c
void func3() {
  int i, num_of_addrs;
  void *buff[(100)];
  char **symbol_str;
  num_of_addrs = backtrace(buff, (100));
  printf("backtrace() returned : %d \n", num_of_addrs);
  symbol_str = backtrace_symbols(buff, num_of_addrs);
  if (symbol_str == NULL) {
    printf("backtrace_symbols returned NULL");
    return;
  }
  for (i = 0; i < num_of_addrs; i++)
    printf("%s\n", symbol_str[i]);
  free(symbol_str);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<func3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <backtrace@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <backtrace_symbols@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L22
  mov    %rax,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%rbp
L3:
  mov    (%rbx),%rdi
  call   <puts@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L3
L22:
  mov    %r12,%rdi
  call   <free@plt>
L12:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x330,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D17: backtrace() returned : %d 


tool: D6: backtrace_symbols returned NULL

assistant: ```c
void func3() {
  int i, num_of_addrs;
  void *buff[(100)];
  char **symbol_str;
  num_of_addrs = backtrace(buff, (100));
  printf("backtrace() returned : %d \n", num_of_addrs);
  symbol_str = backtrace_symbols(buff, num_of_addrs);
  if (symbol_str == NULL) {
    printf("backtrace_symbols returned NULL");
    return;
  }
  for (i = 0; i < num_of_addrs; i++)
    printf("%s\n", symbol_str[i]);
  free(symbol_str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func3>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <backtrace@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <backtrace_symbols@plt>
  test   %rax,%rax
  je     L25
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L32
  mov    %rax,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%rbp
  nopl   (%rax)
L17:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L17
L32:
  mov    %r12,%rdi
  call   <free@plt>
L10:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x330,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L10
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D4
datatype: string

tool: D1: backtrace() returned : %d 


tool: D4: backtrace_symbols returned NULL

assistant: ```c
void func3() {
  int i, num_of_addrs;
  void *buff[(100)];
  char **symbol_str;
  num_of_addrs = backtrace(buff, (100));
  printf("backtrace() returned : %d \n", num_of_addrs);
  symbol_str = backtrace_symbols(buff, num_of_addrs);
  if (symbol_str == NULL) {
    printf("backtrace_symbols returned NULL");
    return;
  }
  for (i = 0; i < num_of_addrs; i++)
    printf("%s\n", symbol_str[i]);
  free(symbol_str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func3>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <backtrace@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <backtrace_symbols@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L7
  mov    %rax,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%rbp
  nopl   (%rax)
L34:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L34
L7:
  mov    %r12,%rdi
  call   <free@plt>
L23:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x330,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type_guessed: string
name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D16: backtrace() returned : %d 


tool: D6: backtrace_symbols returned NULL

assistant: ```c
void func3() {
  int i, num_of_addrs;
  void *buff[(100)];
  char **symbol_str;
  num_of_addrs = backtrace(buff, (100));
  printf("backtrace() returned : %d \n", num_of_addrs);
  symbol_str = backtrace_symbols(buff, num_of_addrs);
  if (symbol_str == NULL) {
    printf("backtrace_symbols returned NULL");
    return;
  }
  for (i = 0; i < num_of_addrs; i++)
    printf("%s\n", symbol_str[i]);
  free(symbol_str);
}
```