ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<casadi_decompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,(%rax)
  mov    0x10(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L21
L0:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L37
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  jmp    L38
L37:
  mov    $0x0,%edx
L38:
  mov    0x10(%rbp),%rax
  mov    %rdx,(%rax)
L21:
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: 

assistant: ```c
void casadi_decompress(const int *sp, int *nrow, int *ncol, int *nnz, int *numel, const int **colind, const int **row) {
  if (sp == 0) {
    static const int scalar_colind[2] = {0, 1};
    *ncol = *nrow = 1;
    *nnz = *numel = 1;
    *colind = scalar_colind;
    *row = 0;
  } else {
    *nrow = *sp++;
    *ncol = *sp++;
    *colind = sp;
    *nnz = sp[*ncol];
    *numel = *nrow * *ncol;
    *row = *nnz == *numel ? 0 : sp + *ncol + 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<casadi_decompress>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L25
  mov    (%rdi),%edi
  mov    %edi,(%rsi)
  lea    0x8(%rax),%rdi
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    %rdi,(%r9)
  movslq (%rdx),%rax
  mov    (%rdi,%rax,4),%eax
  mov    %eax,(%rcx)
  mov    (%rsi),%esi
  imul   (%rdx),%esi
  mov    %esi,(%r8)
  mov    $0x0,%eax
  cmp    (%rcx),%esi
  je     L9
  movslq (%rdx),%rax
  lea    0x4(%rdi,%rax,4),%rax
L9:
  mov    0x8(%rsp),%rdx
  mov    %rax,(%rdx)
  ret
L25:
  movl   $0x1,(%rsi)
  movl   $0x1,(%rdx)
  movl   $0x1,(%r8)
  movl   $0x1,(%rcx)
  lea    D0(%rip),%rcx
  mov    %rcx,(%r9)
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: 

assistant: ```c
void casadi_decompress(const int *sp, int *nrow, int *ncol, int *nnz, int *numel, const int **colind, const int **row) {
  if (sp == 0) {
    static const int scalar_colind[2] = {0, 1};
    *ncol = *nrow = 1;
    *nnz = *numel = 1;
    *colind = scalar_colind;
    *row = 0;
  } else {
    *nrow = *sp++;
    *ncol = *sp++;
    *colind = sp;
    *nnz = sp[*ncol];
    *numel = *nrow * *ncol;
    *row = *nnz == *numel ? 0 : sp + *ncol + 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<casadi_decompress>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L12
  mov    (%rdi),%edi
  mov    %edi,(%rsi)
  lea    0x8(%rax),%rdi
  movslq 0x4(%rax),%rax
  mov    %eax,(%rdx)
  mov    (%rdi,%rax,4),%eax
  mov    %rdi,(%r9)
  mov    %eax,(%rcx)
  mov    (%rsi),%esi
  xor    %eax,%eax
  imul   (%rdx),%esi
  mov    %esi,(%r8)
  cmp    (%rcx),%esi
  je     L1
  movslq (%rdx),%rax
  lea    0x4(%rdi,%rax,4),%rax
L1:
  mov    0x8(%rsp),%rdx
  mov    %rax,(%rdx)
  ret
  nopl   0x0(%rax)
L12:
  movl   $0x1,(%rsi)
  movl   $0x1,(%rdx)
  mov    0x8(%rsp),%rdx
  movl   $0x1,(%r8)
  movl   $0x1,(%rcx)
  lea    D2(%rip),%rcx
  mov    %rcx,(%r9)
  mov    %rax,(%rdx)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: 

assistant: ```c
void casadi_decompress(const int *sp, int *nrow, int *ncol, int *nnz, int *numel, const int **colind, const int **row) {
  if (sp == 0) {
    static const int scalar_colind[2] = {0, 1};
    *ncol = *nrow = 1;
    *nnz = *numel = 1;
    *colind = scalar_colind;
    *row = 0;
  } else {
    *nrow = *sp++;
    *ncol = *sp++;
    *colind = sp;
    *nnz = sp[*ncol];
    *numel = *nrow * *ncol;
    *row = *nnz == *numel ? 0 : sp + *ncol + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<casadi_decompress>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L16
  mov    (%rdi),%edi
  mov    %edi,(%rsi)
  lea    0x8(%rax),%rdi
  movslq 0x4(%rax),%rax
  mov    %eax,(%rdx)
  mov    (%rdi,%rax,4),%eax
  mov    %rdi,(%r9)
  mov    %eax,(%rcx)
  mov    (%rsi),%esi
  xor    %eax,%eax
  imul   (%rdx),%esi
  mov    %esi,(%r8)
  cmp    (%rcx),%esi
  je     L12
  movslq (%rdx),%rax
  lea    0x4(%rdi,%rax,4),%rax
L12:
  mov    0x8(%rsp),%rdx
  mov    %rax,(%rdx)
  ret
  nopl   0x0(%rax)
L16:
  movl   $0x1,(%rsi)
  movl   $0x1,(%rdx)
  mov    0x8(%rsp),%rdx
  movl   $0x1,(%r8)
  movl   $0x1,(%rcx)
  lea    D9(%rip),%rcx
  mov    %rcx,(%r9)
  mov    %rax,(%rdx)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string

tool: 

assistant: ```c
void casadi_decompress(const int *sp, int *nrow, int *ncol, int *nnz, int *numel, const int **colind, const int **row) {
  if (sp == 0) {
    static const int scalar_colind[2] = {0, 1};
    *ncol = *nrow = 1;
    *nnz = *numel = 1;
    *colind = scalar_colind;
    *row = 0;
  } else {
    *nrow = *sp++;
    *ncol = *sp++;
    *colind = sp;
    *nnz = sp[*ncol];
    *numel = *nrow * *ncol;
    *row = *nnz == *numel ? 0 : sp + *ncol + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hbCreateDecodeTables>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  mov    0x28(%rsp),%r12d
  cmp    %r9d,%r8d
  jg     L7
  mov    %rdx,%rbp
  lea    0x1(%r9),%r13d
  mov    %r8d,%ecx
  mov    $0x0,%edi
  mov    %r12d,%r10d
  jmp    L126
L44:
  add    $0x1,%rax
  cmp    %r10,%rax
  je     L96
L166:
  movzbl (%rsi,%rax,1),%edx
  cmp    %ecx,%edx
  jne    L44
  movslq %edi,%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
  add    $0x1,%edi
  jmp    L44
L96:
  add    $0x1,%ecx
  cmp    %r13d,%ecx
  je     L7
L126:
  mov    $0x0,%eax
  test   %r12d,%r12d
  jg     L166
  jmp    L96
L7:
  mov    %rbx,%rax
  lea    0x5c(%rbx),%rdx
L107:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L107
  test   %r12d,%r12d
  jle    L131
  mov    %rsi,%rax
  lea    -0x1(%r12),%ecx
  lea    0x1(%rsi,%rcx,1),%rsi
L154:
  movzbl (%rax),%ecx
  addl   $0x1,0x4(%rbx,%rcx,4)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L154
L131:
  lea    0x4(%rbx),%rax
L84:
  mov    -0x4(%rax),%ecx
  add    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L84
  mov    %r11,%rax
  lea    0x5c(%r11),%rdx
L92:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L92
  cmp    %r9d,%r8d
  jg     L75
  movslq %r8d,%rdx
  mov    $0x0,%eax
L114:
  add    0x4(%rbx,%rdx,4),%eax
  sub    (%rbx,%rdx,4),%eax
  lea    -0x1(%rax),%ecx
  mov    %ecx,(%r11,%rdx,4)
  add    %eax,%eax
  add    $0x1,%rdx
  cmp    %edx,%r9d
  jge    L114
L75:
  lea    0x1(%r8),%eax
  cmp    %eax,%r9d
  jl     L118
  cltq
L60:
  mov    -0x4(%r11,%rax,4),%edx
  lea    0x2(%rdx,%rdx,1),%edx
  sub    (%rbx,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r9d
  jge    L60
L118:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void hbCreateDecodeTables(int *limit, int *base, int *perm, unsigned char *length, int minLen, int maxLen, int alphaSize) {
  int pp, i, j, vec;
  pp = 0;
  for (i = minLen; i <= maxLen; i++)
    for (j = 0; j < alphaSize; j++)
      if (length[j] == i) {
        perm[pp] = j;
        pp++;
      };
  for (i = 0; i < 23; i++)
    base[i] = 0;
  for (i = 0; i < alphaSize; i++)
    base[length[i] + 1]++;
  for (i = 1; i < 23; i++)
    base[i] += base[i - 1];
  for (i = 0; i < 23; i++)
    limit[i] = 0;
  vec = 0;
  for (i = minLen; i <= maxLen; i++) {
    vec += (base[i + 1] - base[i]);
    limit[i] = vec - 1;
    vec <<= 1;
  }
  for (i = minLen + 1; i <= maxLen; i++)
    base[i] = ((limit[i - 1] + 1) << 1) - base[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hbCreateDecodeTables>:
  endbr64
  push   %r13
  mov    %rsi,%r11
  mov    %rdi,%r10
  mov    %rcx,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  mov    0x28(%rsp),%ebp
  cmp    %r9d,%r8d
  jg     L34
  mov    %r8d,%ecx
  mov    %rdx,%r12
  lea    0x1(%r9),%r13d
  xor    %edi,%edi
  movslq %ebp,%r8
  xchg   %ax,%ax
L45:
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L91
  cs nopw 0x0(%rax,%rax,1)
L97:
  movzbl (%rsi,%rax,1),%edx
  cmp    %ecx,%edx
  jne    L17
  movslq %edi,%rdx
  add    $0x1,%edi
  mov    %eax,(%r12,%rdx,4)
L17:
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L97
L91:
  add    $0x1,%ecx
  cmp    %r13d,%ecx
  jne    L45
L34:
  lea    0x8(%r11),%rdi
  mov    %r11,%rcx
  xor    %eax,%eax
  movq   $0x0,(%r11)
  and    $0xfffffffffffffff8,%rdi
  movq   $0x0,0x54(%r11)
  sub    %rdi,%rcx
  add    $0x5c,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  test   %ebp,%ebp
  jle    L58
  lea    -0x1(%rbp),%eax
  lea    0x1(%rsi,%rax,1),%rdx
  nopw   0x0(%rax,%rax,1)
L54:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  addl   $0x1,0x4(%r11,%rax,4)
  cmp    %rsi,%rdx
  jne    L54
L58:
  lea    0x4(%r11),%rax
  lea    0x5c(%r11),%rcx
  nopw   0x0(%rax,%rax,1)
L72:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L72
  lea    0x8(%r10),%rdi
  mov    %r10,%rcx
  xor    %eax,%eax
  movq   $0x0,(%r10)
  and    $0xfffffffffffffff8,%rdi
  movq   $0x0,0x54(%r10)
  sub    %rdi,%rcx
  add    $0x5c,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  cmp    %r9d,%ebx
  jg     L81
  movslq %ebx,%rdx
  xchg   %ax,%ax
L102:
  add    0x4(%r11,%rdx,4),%eax
  sub    (%r11,%rdx,4),%eax
  lea    -0x1(%rax),%ecx
  add    %eax,%eax
  mov    %ecx,(%r10,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%r9d
  jge    L102
L81:
  lea    0x1(%rbx),%eax
  cmp    %eax,%r9d
  jl     L9
  cltq
  nopl   (%rax)
L36:
  mov    -0x4(%r10,%rax,4),%edx
  lea    0x2(%rdx,%rdx,1),%edx
  sub    (%r11,%rax,4),%edx
  mov    %edx,(%r11,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r9d
  jge    L36
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void hbCreateDecodeTables(int *limit, int *base, int *perm, unsigned char *length, int minLen, int maxLen, int alphaSize) {
  int pp, i, j, vec;
  pp = 0;
  for (i = minLen; i <= maxLen; i++)
    for (j = 0; j < alphaSize; j++)
      if (length[j] == i) {
        perm[pp] = j;
        pp++;
      };
  for (i = 0; i < 23; i++)
    base[i] = 0;
  for (i = 0; i < alphaSize; i++)
    base[length[i] + 1]++;
  for (i = 1; i < 23; i++)
    base[i] += base[i - 1];
  for (i = 0; i < 23; i++)
    limit[i] = 0;
  vec = 0;
  for (i = minLen; i <= maxLen; i++) {
    vec += (base[i + 1] - base[i]);
    limit[i] = vec - 1;
    vec <<= 1;
  }
  for (i = minLen + 1; i <= maxLen; i++)
    base[i] = ((limit[i - 1] + 1) << 1) - base[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <sub@plt>
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int a;
  a = atoi(argv[1]);
  return sub(argc, a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <sub@plt>
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int a;
  a = atoi(argv[1]);
  return sub(argc, a);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <sub@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int a;
  a = atoi(argv[1]);
  return sub(argc, a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <sub@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int a;
  a = atoi(argv[1]);
  return sub(argc, a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recursive_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L45
  mov    D5(%rip),%rax
  jmp    L7
L45:
  cmpl   $0x0,-0xc(%rbp)
  jle    L41
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <recursive_power>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movq   %xmm1,%rax
  jmp    L7
L41:
  cmpl   $0x0,-0xc(%rbp)
  jns    L23
  mov    -0xc(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  movsd  D5(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <recursive_power>
  movq   %xmm0,%rax
  jmp    L7
L23:
  mov    D5(%rip),%rax
L7:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: f64

tool: D5: 1

assistant: ```c
double recursive_power(double b, int n) {
  if (n == 0)
    return 1.0;
  if (n > 0)
    return (b * recursive_power(b, n - 1));
  if (n < 0)
    return (recursive_power(1 / b, -1 * n));
  return 1.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recursive_power>:
  endbr64
  test   %edi,%edi
  je     L10
  push   %rbx
  movq   %xmm0,%rbx
  jg     L4
  neg    %edi
  movsd  D16(%rip),%xmm0
  movq   %rbx,%xmm2
  divsd  %xmm2,%xmm0
  call   <recursive_power>
  jmp    L27
L4:
  sub    $0x1,%edi
  call   <recursive_power>
  movq   %rbx,%xmm1
  mulsd  %xmm1,%xmm0
L27:
  pop    %rbx
  ret
L10:
  movsd  D16(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
datatype: f64

tool: D16: 1

assistant: ```c
double recursive_power(double b, int n) {
  if (n == 0)
    return 1.0;
  if (n > 0)
    return (b * recursive_power(b, n - 1));
  if (n < 0)
    return (recursive_power(1 / b, -1 * n));
  return 1.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<recursive_power>:
  endbr64
  test   %edi,%edi
  je     L33
  movapd %xmm0,%xmm1
  jg     L11
  movsd  D15(%rip),%xmm0
  neg    %edi
  divsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
L11:
  cmp    $0x1,%edi
  je     L14
  cmp    $0x2,%edi
  je     L53
  cmp    $0x3,%edi
  je     L8
  sub    $0x18,%rsp
  movapd %xmm1,%xmm0
  sub    $0x4,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <recursive_power>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  ret
L33:
  movsd  D15(%rip),%xmm0
  ret
L14:
  movapd %xmm1,%xmm0
  ret
L8:
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
L17:
  mulsd  %xmm1,%xmm0
  ret
L53:
  movapd %xmm1,%xmm0
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type: f64

tool: D15: 1

assistant: ```c
double recursive_power(double b, int n) {
  if (n == 0)
    return 1.0;
  if (n > 0)
    return (b * recursive_power(b, n - 1));
  if (n < 0)
    return (recursive_power(1 / b, -1 * n));
  return 1.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recursive_power>:
  endbr64
  test   %edi,%edi
  je     L4
  movapd %xmm0,%xmm1
  jg     L51
  movsd  D4(%rip),%xmm0
  neg    %edi
  divsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
L51:
  cmp    $0x1,%edi
  je     L5
  cmp    $0x2,%edi
  je     L49
  cmp    $0x3,%edi
  je     L25
  sub    $0x18,%rsp
  movapd %xmm1,%xmm0
  sub    $0x4,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <recursive_power>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  ret
L4:
  movsd  D4(%rip),%xmm0
  ret
L5:
  movapd %xmm1,%xmm0
  ret
L25:
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
L35:
  mulsd  %xmm1,%xmm0
  ret
L49:
  movapd %xmm1,%xmm0
  jmp    L35
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: f64

tool: D4: 1

assistant: ```c
double recursive_power(double b, int n) {
  if (n == 0)
    return 1.0;
  if (n > 0)
    return (b * recursive_power(b, n - 1));
  if (n < 0)
    return (recursive_power(1 / b, -1 * n));
  return 1.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rcx
  mov    %rsi,%rax
  nop
L0:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L0
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *copy(from, to)
register char *from, *to;
{
  while (*to++ = *from++)
    ;
  return to - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy>:
  endbr64
L7:
  add    $0x1,%rdi
  mov    %rsi,%rdx
  add    $0x1,%rsi
  movzbl -0x1(%rdi),%eax
  mov    %al,-0x1(%rsi)
  test   %al,%al
  jne    L7
  mov    %rdx,%rax
  ret
```

assistant: ```c
char *copy(from, to)
register char *from, *to;
{
  while (*to++ = *from++)
    ;
  return to - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<copy>:
  endbr64
  nopl   0x0(%rax)
L9:
  movzbl (%rdi),%eax
  mov    %rsi,%r8
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %al,-0x1(%rsi)
  test   %al,%al
  jne    L9
  mov    %r8,%rax
  ret
```

assistant: ```c
char *copy(from, to)
register char *from, *to;
{
  while (*to++ = *from++)
    ;
  return to - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copy>:
  endbr64
  nopl   0x0(%rax)
L4:
  movzbl (%rdi),%eax
  mov    %rsi,%r8
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %al,-0x1(%rsi)
  test   %al,%al
  jne    L4
  mov    %r8,%rax
  ret
```

assistant: ```c
char *copy(from, to)
register char *from, *to;
{
  while (*to++ = *from++)
    ;
  return to - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_complex_numbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L28
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L81
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  je     L28
L81:
  movsd  -0x10(%rbp),%xmm0
  movq   D39(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L36
L28:
  movsd  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L83
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L107
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  je     L83
L107:
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L36
L83:
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L143
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L143
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jp     L212
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  je     L143
L212:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L36
L143:
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L196
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L196
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jp     L196
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jne    L196
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L36
L196:
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L152
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  je     L36
L152:
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jp     L36
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  je     L34
  jmp    L36
L34:
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L36
L36:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D39
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D49
type_guessed: string
name: disassemble_data
arguments: tag: D48
type_guessed: string
name: disassemble_data
arguments: tag: D27
type_guessed: string
name: disassemble_data
arguments: tag: D25
type_guessed: string

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D49:  %f - %f i 

tool: D48:  %f + %f i 

tool: D27:  %f i 

tool: D25:  %f 

assistant: ```c
void print_complex_numbers(double real, double image) {
  if (image < 0 && real != 0) {
    printf(" %f - %f i ", real, (-1) * image);
  } else if (image > 0 && real != 0) {
    printf(" %f + %f i ", real, image);
  } else if (real == 0 && image != 0) {
    printf(" %f i ", image);
  } else if (real == 0 && image == 0) {
    printf("0");
  } else if (real != 0 && image == 0) {
    printf(" %f ", real);
  }
}
```