ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<configureUBLOX>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <sendNMEAMsgAndChecksum@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string

tool: D4: $PUBX,41,1,0001,0001,115200,0*

assistant: ```c
void configureUBLOX(void *port) {
  static const char msg[] = "$PUBX,41,1,0001,0001,115200,0*";
  sendNMEAMsgAndChecksum(port, msg, strlen(msg));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<configureUBLOX>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <sendNMEAMsgAndChecksum@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8: $PUBX,41,1,0001,0001,115200,0*

assistant: ```c
void configureUBLOX(void *port) {
  static const char msg[] = "$PUBX,41,1,0001,0001,115200,0*";
  sendNMEAMsgAndChecksum(port, msg, strlen(msg));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sgn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L13
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L13:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L15
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L15:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: f64
name: disassemble_data
arguments: tag: D16
data_type: f32[2]

tool: D6: 1

tool: {"D16": [0.0,-1.875]}

assistant: ```c
double sgn(x)
double x;
{
  double value = 0.0;
  if (x > 0.0)
    value = 1.0;
  if (x < 0.0)
    value = -1.0;
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sgn>:
  endbr64
  movsd  D11(%rip),%xmm1
  comisd D24(%rip),%xmm0
  jbe    L22
L12:
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  ja     L6
L39:
  movapd %xmm1,%xmm0
  ret
L22:
  pxor   %xmm1,%xmm1
  jmp    L12
L6:
  movsd  D15(%rip),%xmm1
  jmp    L39
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
data_type: f64
name: extract_symbolic_data
arguments: label: D24
data_type: f64[2]
name: extract_symbolic_data
arguments: label: D15
data_type: byte[8]

tool: D11: 1

tool: {"D24": [0.0,1.0]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double sgn(x)
double x;
{
  double value = 0.0;
  if (x > 0.0)
    value = 1.0;
  if (x < 0.0)
    value = -1.0;
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sgn>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D0(%rip),%xmm1
  movapd %xmm2,%xmm3
  comisd %xmm0,%xmm2
  cmpltsd %xmm0,%xmm3
  andpd  %xmm3,%xmm1
  jbe    L2
  movsd  D7(%rip),%xmm1
L2:
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: f64
name: retrieve_data
arguments: tag: D7
type_guessed: f32[2]

tool: D0: 1

tool: {"D7": [0.0,-1.875]}

assistant: ```c
double sgn(x)
double x;
{
  double value = 0.0;
  if (x > 0.0)
    value = 1.0;
  if (x < 0.0)
    value = -1.0;
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sgn>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D11(%rip),%xmm1
  movapd %xmm2,%xmm3
  comisd %xmm0,%xmm2
  cmpltsd %xmm0,%xmm3
  andpd  %xmm3,%xmm1
  jbe    L2
  movsd  D12(%rip),%xmm1
L2:
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type: f64
name: unpack_data
arguments: data_label: D12
type: f32[2]

tool: D11: 1

tool: {"D12": [0.0,-1.875]}

assistant: ```c
double sgn(x)
double x;
{
  double value = 0.0;
  if (x > 0.0)
    value = 1.0;
  if (x < 0.0)
    value = -1.0;
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compareInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L34
  mov    $0x1,%eax
  jmp    L10
L34:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L32
  mov    $0xffffffff,%eax
  jmp    L10
L32:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int compareInt(int *t, int *d) {
  if (*t > *d)
    return 1;
  else if (*t < *d)
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compareInt>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  jg     L3
  setl   %al
  movzbl %al,%eax
  neg    %eax
L3:
  ret
```

assistant: ```c
int compareInt(int *t, int *d) {
  if (*t > *d)
    return 1;
  else if (*t < *d)
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compareInt>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L8
  setl   %al
  movzbl %al,%eax
  neg    %eax
L8:
  ret
```

assistant: ```c
int compareInt(int *t, int *d) {
  if (*t > *d)
    return 1;
  else if (*t < *d)
    return -1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compareInt>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L5
  setl   %al
  movzbl %al,%eax
  neg    %eax
L5:
  ret
```

assistant: ```c
int compareInt(int *t, int *d) {
  if (*t > *d)
    return 1;
  else if (*t < *d)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<__udiv64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <_PROCEDURE_LINKAGE_TABLE_@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __udiv64() {
  _PROCEDURE_LINKAGE_TABLE_();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__udiv64>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <_PROCEDURE_LINKAGE_TABLE_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __udiv64() {
  _PROCEDURE_LINKAGE_TABLE_();
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<__udiv64>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <_PROCEDURE_LINKAGE_TABLE_@plt>
```

assistant: ```c
void __udiv64() {
  _PROCEDURE_LINKAGE_TABLE_();
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__udiv64>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <_PROCEDURE_LINKAGE_TABLE_@plt>
```

assistant: ```c
void __udiv64() {
  _PROCEDURE_LINKAGE_TABLE_();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <prog@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <maxargs@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <interp@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: maxargs(prog()) -> %d


assistant: ```c
int main(void) {
  struct stmt *init_s = prog();
  printf("maxargs(prog()) -> %d\n", maxargs(init_s));
  interp(init_s);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <prog@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <maxargs@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <interp@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: maxargs(prog()) -> %d


assistant: ```c
int main(void) {
  struct stmt *init_s = prog();
  printf("maxargs(prog()) -> %d\n", maxargs(init_s));
  interp(init_s);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <prog@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <maxargs@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <interp@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: maxargs(prog()) -> %d


assistant: ```c
int main(void) {
  struct stmt *init_s = prog();
  printf("maxargs(prog()) -> %d\n", maxargs(init_s));
  interp(init_s);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <prog@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <maxargs@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <interp@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: maxargs(prog()) -> %d


assistant: ```c
int main(void) {
  struct stmt *init_s = prog();
  printf("maxargs(prog()) -> %d\n", maxargs(init_s));
  interp(init_s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<STB_StrNiCmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L83
  cmpq   $0x0,-0x40(%rbp)
  jne    L20
L83:
  mov    $0x1,%eax
  jmp    L34
L20:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L81
L15:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L71
  mov    -0x18(%rbp),%rax
  jmp    L34
L71:
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x2c(%rbp)
L81:
  mov    -0x2c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jge    L47
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
L47:
  mov    $0x0,%eax
L34:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int STB_StrNiCmp(const char *szSrc, const char *szDst, int nCount) {
  char *pcSrc, *pcDst;
  long cTmp;
  int i;
  if (szSrc == (0) || szDst == (0)) {
    (void)(0);
    return 1;
  }
  pcSrc = (char *)szSrc;
  pcDst = (char *)szDst;
  for (i = 0; i < nCount && (*pcSrc != '\0' || *pcDst != '\0'); i++) {
    cTmp = (long)(tolower(*pcSrc) - tolower(*pcDst));
    if (cTmp != 0) {
      return cTmp;
    }
    pcSrc++;
    pcDst++;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<STB_StrNiCmp>:
  endbr64
  test   %rdi,%rdi
  je     L7
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L24
  test   %edx,%edx
  jle    L86
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%r13
  jmp    L42
L30:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  movsbl (%r12),%edi
  call   <tolower@plt>
  sub    %rax,%rbx
  jne    L37
  add    $0x1,%rbp
  add    $0x1,%r12
  cmp    %r13,%rbp
  je     L111
L42:
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L30
  cmpb   $0x0,(%r12)
  jne    L30
  mov    $0x0,%eax
  jmp    L74
L37:
  mov    %ebx,%eax
  jmp    L74
L24:
  mov    $0x1,%eax
L74:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L86:
  mov    $0x0,%eax
  jmp    L74
L111:
  mov    $0x0,%eax
  jmp    L74
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int STB_StrNiCmp(const char *szSrc, const char *szDst, int nCount) {
  char *pcSrc, *pcDst;
  long cTmp;
  int i;
  if (szSrc == (0) || szDst == (0)) {
    (void)(0);
    return 1;
  }
  pcSrc = (char *)szSrc;
  pcDst = (char *)szDst;
  for (i = 0; i < nCount && (*pcSrc != '\0' || *pcDst != '\0'); i++) {
    cTmp = (long)(tolower(*pcSrc) - tolower(*pcDst));
    if (cTmp != 0) {
      return cTmp;
    }
    pcSrc++;
    pcDst++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<STB_StrNiCmp>:
  endbr64
  test   %rdi,%rdi
  je     L20
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L33
  movslq %edx,%r12
  mov    %rdi,%r13
  add    %rdi,%r12
  test   %edx,%edx
  jg     L29
  jmp    L5
  xchg   %ax,%ax
L26:
  add    $0x1,%r13
  add    $0x1,%rbp
  cmp    %r12,%r13
  je     L5
L29:
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  jne    L44
  cmpb   $0x0,0x0(%rbp)
  je     L5
L44:
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%rbx
  call   <tolower@plt>
  sub    %rax,%rbx
  je     L26
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L33:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int STB_StrNiCmp(const char *szSrc, const char *szDst, int nCount) {
  char *pcSrc, *pcDst;
  long cTmp;
  int i;
  if (szSrc == (0) || szDst == (0)) {
    (void)(0);
    return 1;
  }
  pcSrc = (char *)szSrc;
  pcDst = (char *)szDst;
  for (i = 0; i < nCount && (*pcSrc != '\0' || *pcDst != '\0'); i++) {
    cTmp = (long)(tolower(*pcSrc) - tolower(*pcDst));
    if (cTmp != 0) {
      return cTmp;
    }
    pcSrc++;
    pcDst++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<STB_StrNiCmp>:
  endbr64
  test   %rdi,%rdi
  je     L66
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L77
  movslq %edx,%r12
  mov    %rdi,%r13
  add    %rdi,%r12
  test   %edx,%edx
  jg     L32
  jmp    L61
  xchg   %ax,%ax
L31:
  add    $0x1,%r13
  add    $0x1,%rbp
  cmp    %r12,%r13
  je     L61
L32:
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  jne    L72
  cmpb   $0x0,0x0(%rbp)
  je     L61
L72:
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%rbx
  call   <tolower@plt>
  sub    %rax,%rbx
  je     L31
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L77:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int STB_StrNiCmp(const char *szSrc, const char *szDst, int nCount) {
  char *pcSrc, *pcDst;
  long cTmp;
  int i;
  if (szSrc == (0) || szDst == (0)) {
    (void)(0);
    return 1;
  }
  pcSrc = (char *)szSrc;
  pcDst = (char *)szDst;
  for (i = 0; i < nCount && (*pcSrc != '\0' || *pcDst != '\0'); i++) {
    cTmp = (long)(tolower(*pcSrc) - tolower(*pcDst));
    if (cTmp != 0) {
      return cTmp;
    }
    pcSrc++;
    pcDst++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fp_log10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  shr    %eax
  add    $0x2,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jg     L50
  mov    $0xffffffff80000001,%rax
  jmp    L76
L50:
  movq   $0x0,-0x28(%rbp)
  jmp    L41
L77:
  mov    -0x18(%rbp),%rax
  sub    %rax,-0x28(%rbp)
  shlq   -0x38(%rbp)
L41:
  mov    -0x38(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L77
  jmp    L14
L5:
  mov    -0x18(%rbp),%rax
  add    %rax,-0x28(%rbp)
  sarq   -0x38(%rbp)
L14:
  mov    -0x38(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jge    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L34
L75:
  sarq   -0x20(%rbp)
  mov    -0x38(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jl     L34
  sarq   -0x38(%rbp)
  mov    -0x20(%rbp),%rax
  add    %rax,-0x28(%rbp)
L34:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jg     L75
  mov    $0x1c,%eax
  sub    -0x3c(%rbp),%eax
  mov    $0x4d104d4,%edx
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
L76:
  pop    %rbp
  ret
```

assistant: ```c
long fp_log10(long n, unsigned int fracbits) {
  long log2, frac;
  const long fp_one = (1 << fracbits);
  const long fp_two = (2 << fracbits);
  const long tolerance = (1 << ((fracbits / 2) + 2));
  if (n <= 0)
    return -(0x7fffffff);
  log2 = 0;
  while (n < fp_one) {
    log2 -= fp_one;
    n <<= 1;
  }
  while (n >= fp_two) {
    log2 += fp_one;
    n >>= 1;
  }
  frac = fp_one;
  while (frac > tolerance) {
    frac >>= 1;
    n = (long)((((long long)(n)) * ((long long)(n))) >> (fracbits));
    if (n >= fp_two) {
      n >>= 1;
      log2 += frac;
    }
  }
  return (long)((((long long)(log2)) * ((long long)(((80807124L) >> (28 - fracbits))))) >> (fracbits));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fp_log10>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%r8d
  mov    $0x1,%r9d
  mov    %r9d,%esi
  mov    %r8d,%ecx
  shl    %cl,%esi
  movslq %esi,%rsi
  mov    $0x2,%eax
  shl    %cl,%eax
  cltq
  mov    %r8d,%ecx
  shr    %ecx
  add    $0x2,%ecx
  shl    %cl,%r9d
  movslq %r9d,%r9
  test   %rdi,%rdi
  jle    L5
  cmp    %rdi,%rsi
  jle    L99
  mov    $0x0,%edi
L94:
  sub    %rsi,%rdi
  add    %rdx,%rdx
  cmp    %rdx,%rsi
  jg     L94
L26:
  cmp    %rdx,%rax
  jg     L77
L91:
  add    %rsi,%rdi
  sar    %rdx
  cmp    %rdx,%rax
  jle    L91
L77:
  cmp    %r9,%rsi
  jg     L23
L0:
  mov    $0x1c,%ecx
  sub    %r8d,%ecx
  mov    $0x4d104d4,%eax
  sar    %cl,%rax
  imul   %rdi,%rax
  mov    %r8d,%ecx
  sar    %cl,%rax
  ret
L99:
  mov    $0x0,%edi
  jmp    L26
L52:
  cmp    %rsi,%r9
  jge    L0
L23:
  sar    %rsi
  imul   %rdx,%rdx
  mov    %r8d,%ecx
  sar    %cl,%rdx
  cmp    %rdx,%rax
  jg     L52
  sar    %rdx
  add    %rsi,%rdi
  jmp    L52
L5:
  mov    $0xffffffff80000001,%rax
  ret
```

assistant: ```c
long fp_log10(long n, unsigned int fracbits) {
  long log2, frac;
  const long fp_one = (1 << fracbits);
  const long fp_two = (2 << fracbits);
  const long tolerance = (1 << ((fracbits / 2) + 2));
  if (n <= 0)
    return -(0x7fffffff);
  log2 = 0;
  while (n < fp_one) {
    log2 -= fp_one;
    n <<= 1;
  }
  while (n >= fp_two) {
    log2 += fp_one;
    n >>= 1;
  }
  frac = fp_one;
  while (frac > tolerance) {
    frac >>= 1;
    n = (long)((((long long)(n)) * ((long long)(n))) >> (fracbits));
    if (n >= fp_two) {
      n >>= 1;
      log2 += frac;
    }
  }
  return (long)((((long long)(log2)) * ((long long)(((80807124L) >> (28 - fracbits))))) >> (fracbits));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fp_log10>:
  endbr64
  mov    %esi,%r8d
  mov    $0x1,%r9d
  mov    $0x2,%eax
  mov    %rdi,%rdx
  mov    %r8d,%ecx
  mov    %r9d,%esi
  shl    %cl,%esi
  shl    %cl,%eax
  mov    %r8d,%ecx
  shr    %ecx
  movslq %esi,%rsi
  cltq
  add    $0x2,%ecx
  shl    %cl,%r9d
  movslq %r9d,%r9
  test   %rdi,%rdi
  jle    L71
  xor    %edi,%edi
  cmp    %rdx,%rsi
  jle    L49
  xchg   %ax,%ax
L18:
  add    %rdx,%rdx
  sub    %rsi,%rdi
  cmp    %rdx,%rsi
  jg     L18
  cmp    %rdx,%rax
  jg     L26
L64:
  add    %rsi,%rdi
  sar    %rdx
L49:
  cmp    %rdx,%rax
  jle    L64
L26:
  cmp    %r9,%rsi
  jle    L11
L62:
  imul   %rdx,%rdx
  mov    %r8d,%ecx
  sar    %rsi
  sar    %cl,%rdx
  cmp    %rdx,%rax
  jg     L16
  sar    %rdx
  add    %rsi,%rdi
L16:
  cmp    %rsi,%r9
  jl     L62
L11:
  mov    $0x1c,%ecx
  mov    $0x4d104d4,%eax
  sub    %r8d,%ecx
  sar    %cl,%rax
  mov    %r8d,%ecx
  imul   %rdi,%rax
  sar    %cl,%rax
  ret
L71:
  mov    $0xffffffff80000001,%rax
  ret
```

assistant: ```c
long fp_log10(long n, unsigned int fracbits) {
  long log2, frac;
  const long fp_one = (1 << fracbits);
  const long fp_two = (2 << fracbits);
  const long tolerance = (1 << ((fracbits / 2) + 2));
  if (n <= 0)
    return -(0x7fffffff);
  log2 = 0;
  while (n < fp_one) {
    log2 -= fp_one;
    n <<= 1;
  }
  while (n >= fp_two) {
    log2 += fp_one;
    n >>= 1;
  }
  frac = fp_one;
  while (frac > tolerance) {
    frac >>= 1;
    n = (long)((((long long)(n)) * ((long long)(n))) >> (fracbits));
    if (n >= fp_two) {
      n >>= 1;
      log2 += frac;
    }
  }
  return (long)((((long long)(log2)) * ((long long)(((80807124L) >> (28 - fracbits))))) >> (fracbits));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fp_log10>:
  endbr64
  mov    %esi,%r8d
  mov    $0x1,%r9d
  mov    $0x2,%eax
  mov    %rdi,%rdx
  mov    %r8d,%ecx
  mov    %r9d,%esi
  shl    %cl,%esi
  shl    %cl,%eax
  mov    %r8d,%ecx
  shr    %ecx
  movslq %esi,%rsi
  cltq
  add    $0x2,%ecx
  shl    %cl,%r9d
  movslq %r9d,%r9
  test   %rdi,%rdi
  jle    L79
  xor    %edi,%edi
  cmp    %rdx,%rsi
  jle    L70
  xchg   %ax,%ax
L49:
  add    %rdx,%rdx
  sub    %rsi,%rdi
  cmp    %rdx,%rsi
  jg     L49
  cmp    %rdx,%rax
  jg     L20
L9:
  add    %rsi,%rdi
  sar    %rdx
L70:
  cmp    %rdx,%rax
  jle    L9
L20:
  cmp    %r9,%rsi
  jle    L52
L35:
  imul   %rdx,%rdx
  mov    %r8d,%ecx
  sar    %rsi
  sar    %cl,%rdx
  cmp    %rdx,%rax
  jg     L2
  sar    %rdx
  add    %rsi,%rdi
L2:
  cmp    %rsi,%r9
  jl     L35
L52:
  mov    $0x1c,%ecx
  mov    $0x4d104d4,%eax
  sub    %r8d,%ecx
  sar    %cl,%rax
  mov    %r8d,%ecx
  imul   %rdi,%rax
  sar    %cl,%rax
  ret
L79:
  mov    $0xffffffff80000001,%rax
  ret
```

assistant: ```c
long fp_log10(long n, unsigned int fracbits) {
  long log2, frac;
  const long fp_one = (1 << fracbits);
  const long fp_two = (2 << fracbits);
  const long tolerance = (1 << ((fracbits / 2) + 2));
  if (n <= 0)
    return -(0x7fffffff);
  log2 = 0;
  while (n < fp_one) {
    log2 -= fp_one;
    n <<= 1;
  }
  while (n >= fp_two) {
    log2 += fp_one;
    n >>= 1;
  }
  frac = fp_one;
  while (frac > tolerance) {
    frac >>= 1;
    n = (long)((((long long)(n)) * ((long long)(n))) >> (fracbits));
    if (n >= fp_two) {
      n >>= 1;
      log2 += frac;
    }
  }
  return (long)((((long long)(log2)) * ((long long)(((80807124L) >> (28 - fracbits))))) >> (fracbits));
}
```