ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<dsprstx>:
  endbr64
  push   %r14
  lea    0x2(%r8),%rax
  mov    %r8,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cmp    %rax,0x8(%rsi)
  je     L89
  lea    D5(%rip),%rdi
  call   <nrerror@plt>
L89:
  test   %r14,%r14
  je     L9
  lea    0x8(%r12),%rax
  lea    0x10(%rbx),%rdx
  cmp    %rdx,%rax
  lea    0x10(%rbp),%rcx
  setne  %dl
  cmp    %rcx,%rax
  setne  %al
  test   %al,%dl
  je     L104
  lea    -0x1(%r14),%rax
  cmp    $0x1,%rax
  jbe    L104
  mov    %r14,%rdx
  mov    $0x8,%eax
  shr    %rdx
  shl    $0x4,%rdx
  add    $0x8,%rdx
  nopl   0x0(%rax)
L37:
  movupd (%rbx,%rax,1),%xmm0
  movupd 0x0(%rbp,%rax,1),%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L37
  mov    %r14,%rax
  or     $0x1,%rax
  test   $0x1,%r14b
  je     L60
  movsd  (%rbx,%rax,8),%xmm0
  mulsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%r12,%rax,8)
L60:
  lea    0x8(%rbx),%rcx
  lea    0x8(%r13),%rdi
  lea    (%rcx,%r14,8),%r8
  nopw   0x0(%rax,%rax,1)
L71:
  mov    0x8(%rdi),%rbx
  mov    (%rdi),%rax
  lea    -0x1(%rbx),%rsi
  cmp    %rsi,%rax
  ja     L12
L41:
  mov    0x0(%r13,%rax,8),%rdx
  movsd  0x0(%rbp,%rax,8),%xmm0
  add    $0x1,%rax
  mulsd  (%rcx),%xmm0
  lea    (%r12,%rdx,8),%rdx
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rsi,%rax
  jbe    L41
L12:
  add    $0x8,%rcx
  add    $0x8,%rdi
  cmp    %r8,%rcx
  jne    L71
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L104:
  mov    $0x1,%eax
  nop
L82:
  movsd  (%rbx,%rax,8),%xmm0
  mulsd  0x0(%rbp,%rax,8),%xmm0
  mov    %rax,%rdx
  movsd  %xmm0,(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%r14
  jne    L82
  jmp    L60
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: mismatched vector and matrix in dsprstx

assistant: ```c
void dsprstx(double sa[], unsigned long ija[], double x[], double b[], unsigned long n) {
  void nrerror(char error_text[]);
  unsigned long i, j, k;
  if (ija[1] != n + 2)
    nrerror("mismatched vector and matrix in dsprstx");
  for (i = 1; i <= n; i++)
    b[i] = sa[i] * x[i];
  for (i = 1; i <= n; i++) {
    for (k = ija[i]; k <= ija[i + 1] - 1; k++) {
      j = ija[k];
      b[j] += sa[k] * x[i];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<instruction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D35
datatype: string
name: unpack_data
arguments: data_tag: D52
datatype: string
name: unpack_data
arguments: data_tag: D43
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D35: +-------------------------------+


tool: D52: |     Remote Shell - Client     |


tool: D43: |   Type "exit" to terminate    |


tool: D27: +-------------------------------+



tool: D4: Wait ...


assistant: ```c
void instruction() {
  printf("+-------------------------------+\n");
  printf("|     Remote Shell - Client     |\n");
  printf("+-------------------------------+\n");
  printf("|   Type \"exit\" to terminate    |\n");
  printf("+-------------------------------+\n\n");
  printf("Wait ...\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<instruction>:
  endbr64
  push   %rbx
  lea    D44(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D44
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D36
type_guessed: string
name: retrieve_data
arguments: data_tag: D18
type_guessed: string

tool: D44: +-------------------------------+


tool: D4: |     Remote Shell - Client     |


tool: D9: |   Type "exit" to terminate    |


tool: D36: +-------------------------------+



tool: D18: Wait ...


assistant: ```c
void instruction() {
  printf("+-------------------------------+\n");
  printf("|     Remote Shell - Client     |\n");
  printf("+-------------------------------+\n");
  printf("|   Type \"exit\" to terminate    |\n");
  printf("+-------------------------------+\n\n");
  printf("Wait ...\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<instruction>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D41
type_guessed: string
name: retrieve_data
arguments: data_tag: D35
type_guessed: string
name: retrieve_data
arguments: data_tag: D20
type_guessed: string
name: retrieve_data
arguments: data_tag: D43
type_guessed: string

tool: D14: +-------------------------------+


tool: D41: |     Remote Shell - Client     |


tool: D35: |   Type "exit" to terminate    |


tool: D20: +-------------------------------+



tool: D43: Wait ...


assistant: ```c
void instruction() {
  printf("+-------------------------------+\n");
  printf("|     Remote Shell - Client     |\n");
  printf("+-------------------------------+\n");
  printf("|   Type \"exit\" to terminate    |\n");
  printf("+-------------------------------+\n\n");
  printf("Wait ...\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<instruction>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: string
name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D35
type_infered: string

tool: D3: +-------------------------------+


tool: D28: |     Remote Shell - Client     |


tool: D48: |   Type "exit" to terminate    |


tool: D7: +-------------------------------+



tool: D35: Wait ...


assistant: ```c
void instruction() {
  printf("+-------------------------------+\n");
  printf("|     Remote Shell - Client     |\n");
  printf("+-------------------------------+\n");
  printf("|   Type \"exit\" to terminate    |\n");
  printf("+-------------------------------+\n\n");
  printf("Wait ...\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L29
L25:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L15
L16:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L15:
  cmpl   $0x0,-0x8(%rbp)
  jle    L19
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L16
L19:
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertionSort(int *a, int n) {
  int i, j, tmp;
  j = 0;
  for (i = 1; i < n; i++) {
    j = i;
    while (j > 0 && a[j - 1] > a[j]) {
      tmp = a[j];
      a[j] = a[j - 1];
      a[j - 1] = tmp;
      j--;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<insertionSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L10
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  jmp    L37
L52:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  je     L10
L37:
  test   %r8d,%r8d
  jle    L52
  mov    %r9,%rax
L58:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L52
  mov    %ecx,(%rax)
  mov    %edx,-0x4(%rax)
  sub    $0x4,%rax
  cmp    %rdi,%rax
  jne    L58
  jmp    L52
L10:
  ret
```

assistant: ```c
void insertionSort(int *a, int n) {
  int i, j, tmp;
  j = 0;
  for (i = 1; i < n; i++) {
    j = i;
    while (j > 0 && a[j - 1] > a[j]) {
      tmp = a[j];
      a[j] = a[j - 1];
      a[j - 1] = tmp;
      j--;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertionSort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L14
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L10:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L17
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  mov    %edx,(%rax)
  cmp    %rdi,%rax
  jne    L10
L17:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  jne    L38
  ret
L14:
  ret
```

assistant: ```c
void insertionSort(int *a, int n) {
  int i, j, tmp;
  j = 0;
  for (i = 1; i < n; i++) {
    j = i;
    while (j > 0 && a[j - 1] > a[j]) {
      tmp = a[j];
      a[j] = a[j - 1];
      a[j - 1] = tmp;
      j--;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insertionSort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L32
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %r9,%rdx
  nopl   0x0(%rax,%rax,1)
L9:
  movq   -0x4(%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L28
  movq   %xmm1,-0x4(%rdx)
  sub    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L9
L28:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  jne    L17
  ret
L32:
  ret
```

assistant: ```c
void insertionSort(int *a, int n) {
  int i, j, tmp;
  j = 0;
  for (i = 1; i < n; i++) {
    j = i;
    while (j > 0 && a[j - 1] > a[j]) {
      tmp = a[j];
      a[j] = a[j - 1];
      a[j - 1] = tmp;
      j--;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mmdb_strnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L32
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L9
  jmp    L17
L27:
  nop
L17:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t mmdb_strnlen(const char *s, size_t maxlen) {
  size_t len;
  for (len = 0; len < maxlen; len++, s++) {
    if (!*s)
      break;
  }
  return (len);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mmdb_strnlen>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L0
  mov    $0x0,%edx
L24:
  cmpb   $0x0,(%rdi,%rdx,1)
  je     L18
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L24
  ret
L18:
  mov    %rdx,%rax
L0:
  ret
```

assistant: ```c
size_t mmdb_strnlen(const char *s, size_t maxlen) {
  size_t len;
  for (len = 0; len < maxlen; len++, s++) {
    if (!*s)
      break;
  }
  return (len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mmdb_strnlen>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L5
  xor    %edx,%edx
  jmp    L38
L28:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L18
L38:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L28
  mov    %rdx,%rax
L5:
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
size_t mmdb_strnlen(const char *s, size_t maxlen) {
  size_t len;
  for (len = 0; len < maxlen; len++, s++) {
    if (!*s)
      break;
  }
  return (len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mmdb_strnlen>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L29
  xor    %edx,%edx
  jmp    L6
L16:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L25
L6:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L16
  mov    %rdx,%rax
L29:
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  ret
```

assistant: ```c
size_t mmdb_strnlen(const char *s, size_t maxlen) {
  size_t len;
  for (len = 0; len < maxlen; len++, s++) {
    if (!*s)
      break;
  }
  return (len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cocktail_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
L6:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L50:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L11
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  movl   $0x1,-0xc(%rbp)
L11:
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L50
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L54
L49:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L21
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  movl   $0x1,-0xc(%rbp)
L21:
  subl   $0x1,-0x4(%rbp)
L54:
  cmpl   $0x0,-0x4(%rbp)
  jg     L49
  cmpl   $0x0,-0xc(%rbp)
  jne    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void cocktail_sort(int a[], int n) {
  int swapped = 0;
  do {
    swapped = 0;
    for (int i = 0; i < n; ++i) {
      if (a[i] > a[i + 1]) {
        swap(&a[i], &a[i + 1]);
        swapped = 1;
      }
    }
    for (int i = n - 1; i > 0; --i) {
      if (a[i - 1] > a[i]) {
        swap(&a[i], &a[i - 1]);
        swapped = 1;
      }
    }
  } while (swapped);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cocktail_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r14d
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  mov    $0x1,%r13d
  jmp    L105
L94:
  cmp    %rbx,%r12
  je     L44
L27:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  mov    0x4(%rdi),%ecx
  cmp    %ecx,(%rdi)
  jle    L94
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    %r13d,%eax
  jmp    L94
L44:
  lea    -0x1(%r14),%ebp
  test   %ebp,%ebp
  jle    L87
  movslq %ebp,%rdx
  lea    (%r15,%rdx,4),%rbx
  jmp    L110
L67:
  sub    $0x1,%ebp
  sub    $0x4,%rbx
  test   %ebp,%ebp
  jle    L87
L110:
  lea    -0x4(%rbx),%rsi
  mov    (%rbx),%edx
  cmp    %edx,-0x4(%rbx)
  jle    L67
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    %r13d,%eax
  jmp    L67
L87:
  test   %eax,%eax
  je     L59
L105:
  test   %r14d,%r14d
  jle    L59
  mov    %r15,%rbx
  mov    $0x0,%eax
  jmp    L27
L59:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void cocktail_sort(int a[], int n) {
  int swapped = 0;
  do {
    swapped = 0;
    for (int i = 0; i < n; ++i) {
      if (a[i] > a[i + 1]) {
        swap(&a[i], &a[i + 1]);
        swapped = 1;
      }
    }
    for (int i = n - 1; i > 0; --i) {
      if (a[i - 1] > a[i]) {
        swap(&a[i], &a[i - 1]);
        swapped = 1;
      }
    }
  } while (swapped);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cocktail_sort>:
  endbr64
  lea    -0x1(%rsi),%edx
  push   %r15
  mov    %rdx,%rax
  push   %r14
  mov    %rdi,%r14
  cltq
  push   %r13
  mov    %esi,%r13d
  push   %r12
  lea    (%rdi,%rax,4),%r15
  movslq %esi,%rax
  lea    0x4(%rdi,%rdx,4),%r12
  push   %rbp
  lea    -0x8(%rdi,%rax,4),%rbp
  lea    -0x2(%rsi),%eax
  push   %rbx
  shl    $0x2,%rax
  sub    %rax,%rbp
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L33:
  test   %r13d,%r13d
  jle    L102
  mov    %r14,%rbx
  xor    %eax,%eax
  jmp    L32
  nopl   0x0(%rax)
L1:
  cmp    %rbx,%r12
  je     L108
L32:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  mov    0x4(%rdi),%ecx
  cmp    %ecx,(%rdi)
  jle    L1
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    $0x1,%eax
  cmp    %rbx,%r12
  jne    L32
L108:
  cmp    $0x1,%r13d
  je     L71
  mov    %r15,%rbx
  jmp    L30
L35:
  cmp    %rbx,%rbp
  je     L71
L30:
  mov    %rbx,%rdi
  sub    $0x4,%rbx
  mov    (%rdi),%edx
  cmp    %edx,-0x4(%rdi)
  jle    L35
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    $0x1,%eax
  cmp    %rbx,%rbp
  jne    L30
L71:
  test   %eax,%eax
  jne    L33
L102:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void cocktail_sort(int a[], int n) {
  int swapped = 0;
  do {
    swapped = 0;
    for (int i = 0; i < n; ++i) {
      if (a[i] > a[i + 1]) {
        swap(&a[i], &a[i + 1]);
        swapped = 1;
      }
    }
    for (int i = n - 1; i > 0; --i) {
      if (a[i - 1] > a[i]) {
        swap(&a[i], &a[i - 1]);
        swapped = 1;
      }
    }
  } while (swapped);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cocktail_sort>:
  endbr64
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  mov    %rax,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    0x4(%rdi,%rax,4),%rbp
  cltq
  push   %rbx
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rsi
  lea    -0x4(%rdi,%rax,1),%rbx
  lea    -0x2(%r12),%eax
  sub    $0x18,%rsp
  shl    $0x2,%rax
  mov    %rsi,0x8(%rsp)
  sub    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L66:
  test   %r12d,%r12d
  jle    L28
  mov    %r13,%r15
  xor    %eax,%eax
  jmp    L11
  nopl   0x0(%rax)
L78:
  cmp    %r15,%rbp
  je     L29
L11:
  mov    %r15,%rdi
  add    $0x4,%r15
  mov    0x4(%rdi),%edx
  cmp    %edx,(%rdi)
  jle    L78
  mov    %r15,%rsi
  call   <swap@plt>
  mov    $0x1,%eax
  cmp    %r15,%rbp
  jne    L11
L29:
  test   %r14d,%r14d
  jle    L68
  mov    0x8(%rsp),%r15
  jmp    L73
  nopl   0x0(%rax)
L74:
  cmp    %r15,%rbx
  je     L68
L73:
  mov    %r15,%rdi
  sub    $0x4,%r15
  mov    (%rdi),%ecx
  cmp    %ecx,-0x4(%rdi)
  jle    L74
  mov    %r15,%rsi
  call   <swap@plt>
  mov    $0x1,%eax
  cmp    %r15,%rbx
  jne    L73
L68:
  test   %eax,%eax
  jne    L66
L28:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void cocktail_sort(int a[], int n) {
  int swapped = 0;
  do {
    swapped = 0;
    for (int i = 0; i < n; ++i) {
      if (a[i] > a[i + 1]) {
        swap(&a[i], &a[i + 1]);
        swapped = 1;
      }
    }
    for (int i = n - 1; i > 0; --i) {
      if (a[i - 1] > a[i]) {
        swap(&a[i], &a[i - 1]);
        swapped = 1;
      }
    }
  } while (swapped);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hh_extensions_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x153b10,-0x50(%rbp)
  movl   $0x713b0,-0x4c(%rbp)
  movl   $0x30870,-0x48(%rbp)
  movl   $0x153b1,-0x44(%rbp)
  movl   $0x8490,-0x40(%rbp)
  movl   $0x35d0,-0x3c(%rbp)
  movl   $0x11f0,-0x38(%rbp)
  movl   $0x7b0,-0x34(%rbp)
  movl   $0x35d,-0x30(%rbp)
  movl   $0x150,-0x2c(%rbp)
  movl   $0x70,-0x28(%rbp)
  movl   $0x30,-0x24(%rbp)
  movl   $0x15,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x60(%rbp)
  jmp    L62
L75:
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,-0x5c(%rbp)
  mov    -0x5c(%rbp),%eax
  mov    %eax,-0x68(%rbp)
  jmp    L25
L48:
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x68(%rbp),%eax
  mov    %eax,-0x64(%rbp)
  jmp    L55
L6:
  mov    -0x64(%rbp),%eax
  sub    -0x5c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x78(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x5c(%rbp),%eax
  sub    %eax,-0x64(%rbp)
L55:
  mov    -0x64(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L63
  mov    -0x64(%rbp),%eax
  sub    -0x5c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x58(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jg     L6
L63:
  mov    -0x64(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x68(%rbp)
L25:
  mov    -0x7c(%rbp),%eax
  cmp    -0x68(%rbp),%eax
  jg     L48
  addl   $0x1,-0x60(%rbp)
L62:
  cmpl   $0xf,-0x60(%rbp)
  jle    L75
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

assistant: ```c
void hh_extensions_sort(char **array, int N) {
  int i, j, k, h;
  char *v;
  int incs[16] = {1391376, 463792, 198768, 86961, 33936, 13776, 4592, 1968, 861, 336, 112, 48, 21, 7, 3, 1};
  for (k = 0; k < 16; k++) {
    for (h = incs[k], i = h; i <= N - 1; i++) {
      v = array[i];
      j = i;
      while (j >= h && strcmp(array[j - h], v) > 0) {
        array[j] = array[j - h];
        j -= h;
      }
      array[j] = v;
    }
  }
}
```