ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<store_cv_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <store32@plt>
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x10,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store32@plt>
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x20,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store32@plt>
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x30,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store32@plt>
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x40,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store32@plt>
  mov    -0x10(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x50,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store32@plt>
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x60,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store32@plt>
  mov    -0x10(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x70,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store32@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void store_cv_words(uint8_t bytes_out[32], uint32_t cv_words[8]) {
  store32(&bytes_out[0 * 4], cv_words[0]);
  store32(&bytes_out[1 * 4], cv_words[1]);
  store32(&bytes_out[2 * 4], cv_words[2]);
  store32(&bytes_out[3 * 4], cv_words[3]);
  store32(&bytes_out[4 * 4], cv_words[4]);
  store32(&bytes_out[5 * 4], cv_words[5]);
  store32(&bytes_out[6 * 4], cv_words[6]);
  store32(&bytes_out[7 * 4], cv_words[7]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store_cv_words>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rsi),%esi
  call   <store32@plt>
  mov    0x4(%rbp),%esi
  lea    0x10(%rbx),%rdi
  call   <store32@plt>
  mov    0x8(%rbp),%esi
  lea    0x20(%rbx),%rdi
  call   <store32@plt>
  mov    0xc(%rbp),%esi
  lea    0x30(%rbx),%rdi
  call   <store32@plt>
  mov    0x10(%rbp),%esi
  lea    0x40(%rbx),%rdi
  call   <store32@plt>
  mov    0x14(%rbp),%esi
  lea    0x50(%rbx),%rdi
  call   <store32@plt>
  mov    0x18(%rbp),%esi
  lea    0x60(%rbx),%rdi
  call   <store32@plt>
  mov    0x1c(%rbp),%esi
  lea    0x70(%rbx),%rdi
  call   <store32@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) void store_cv_words(uint8_t bytes_out[32], uint32_t cv_words[8]) {
  store32(&bytes_out[0 * 4], cv_words[0]);
  store32(&bytes_out[1 * 4], cv_words[1]);
  store32(&bytes_out[2 * 4], cv_words[2]);
  store32(&bytes_out[3 * 4], cv_words[3]);
  store32(&bytes_out[4 * 4], cv_words[4]);
  store32(&bytes_out[5 * 4], cv_words[5]);
  store32(&bytes_out[6 * 4], cv_words[6]);
  store32(&bytes_out[7 * 4], cv_words[7]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<store_cv_words>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%esi
  call   <store32@plt>
  mov    0x4(%rbp),%esi
  lea    0x10(%rbx),%rdi
  call   <store32@plt>
  mov    0x8(%rbp),%esi
  lea    0x20(%rbx),%rdi
  call   <store32@plt>
  mov    0xc(%rbp),%esi
  lea    0x30(%rbx),%rdi
  call   <store32@plt>
  mov    0x10(%rbp),%esi
  lea    0x40(%rbx),%rdi
  call   <store32@plt>
  mov    0x14(%rbp),%esi
  lea    0x50(%rbx),%rdi
  call   <store32@plt>
  mov    0x18(%rbp),%esi
  lea    0x60(%rbx),%rdi
  call   <store32@plt>
  mov    0x1c(%rbp),%esi
  add    $0x8,%rsp
  lea    0x70(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <store32@plt>
```

assistant: ```c
__attribute__((always_)) void store_cv_words(uint8_t bytes_out[32], uint32_t cv_words[8]) {
  store32(&bytes_out[0 * 4], cv_words[0]);
  store32(&bytes_out[1 * 4], cv_words[1]);
  store32(&bytes_out[2 * 4], cv_words[2]);
  store32(&bytes_out[3 * 4], cv_words[3]);
  store32(&bytes_out[4 * 4], cv_words[4]);
  store32(&bytes_out[5 * 4], cv_words[5]);
  store32(&bytes_out[6 * 4], cv_words[6]);
  store32(&bytes_out[7 * 4], cv_words[7]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<store_cv_words>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%esi
  call   <store32@plt>
  mov    0x4(%rbp),%esi
  lea    0x10(%rbx),%rdi
  call   <store32@plt>
  mov    0x8(%rbp),%esi
  lea    0x20(%rbx),%rdi
  call   <store32@plt>
  mov    0xc(%rbp),%esi
  lea    0x30(%rbx),%rdi
  call   <store32@plt>
  mov    0x10(%rbp),%esi
  lea    0x40(%rbx),%rdi
  call   <store32@plt>
  mov    0x14(%rbp),%esi
  lea    0x50(%rbx),%rdi
  call   <store32@plt>
  mov    0x18(%rbp),%esi
  lea    0x60(%rbx),%rdi
  call   <store32@plt>
  mov    0x1c(%rbp),%esi
  add    $0x8,%rsp
  lea    0x70(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <store32@plt>
```

assistant: ```c
__attribute__((always_)) void store_cv_words(uint8_t bytes_out[32], uint32_t cv_words[8]) {
  store32(&bytes_out[0 * 4], cv_words[0]);
  store32(&bytes_out[1 * 4], cv_words[1]);
  store32(&bytes_out[2 * 4], cv_words[2]);
  store32(&bytes_out[3 * 4], cv_words[3]);
  store32(&bytes_out[4 * 4], cv_words[4]);
  store32(&bytes_out[5 * 4], cv_words[5]);
  store32(&bytes_out[6 * 4], cv_words[6]);
  store32(&bytes_out[7 * 4], cv_words[7]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rcx
  mov    %rax,%rsi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D16
type: string
name: retrieve_data
arguments: tag: D42
type: string
name: retrieve_data
arguments: tag: D65
type: string
name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D62
type: string

tool: D16: clear

tool: D42: 
 
 	 Enter value for variables b: 

tool: D65: %ld

tool: D29: 
 
 	 Enter value for variables d: 

tool: D62: 
 
 	 %ld * %ld = %ld

assistant: ```c
int main() {
  long int b, d, f;
  system("clear");
  printf("\n \n \t Enter value for variables b: ");
  scanf("%ld", &b);
  system("clear");
  printf("\n \n \t Enter value for variables d: ");
  scanf("%ld", &d);
  system("clear");
  f = b * d;
  printf("\n \n \t %ld * %ld = %ld", b, d, f);
  getchar();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <system@plt>
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D44(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rdx
  mov    %rsi,%rcx
  imul   %rdx,%rcx
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string
name: retrieve_data
arguments: tag: D12
data_type: string
name: retrieve_data
arguments: tag: D44
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D7
data_type: string

tool: D0: clear

tool: D12: 
 
 	 Enter value for variables b: 

tool: D44: %ld

tool: D1: 
 
 	 Enter value for variables d: 

tool: D7: 
 
 	 %ld * %ld = %ld

assistant: ```c
int main() {
  long int b, d, f;
  system("clear");
  printf("\n \n \t Enter value for variables b: ");
  scanf("%ld", &b);
  system("clear");
  printf("\n \n \t Enter value for variables d: ");
  scanf("%ld", &d);
  system("clear");
  f = b * d;
  printf("\n \n \t %ld * %ld = %ld", b, d, f);
  getchar();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D41(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <system@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  mov    0x10(%rsp),%rdx
  lea    D33(%rip),%rdi
  mov    %rsi,%rcx
  imul   %rdx,%rcx
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D41
type: string
name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D23
type: string
name: retrieve_data
arguments: tag: D33
type: string

tool: D41: %ld

tool: D11: clear

tool: D29: 
 
 	 Enter value for variables b: 

tool: D23: 
 
 	 Enter value for variables d: 

tool: D33: 
 
 	 %ld * %ld = %ld

assistant: ```c
int main() {
  long int b, d, f;
  system("clear");
  printf("\n \n \t Enter value for variables b: ");
  scanf("%ld", &b);
  system("clear");
  printf("\n \n \t Enter value for variables d: ");
  scanf("%ld", &d);
  system("clear");
  f = b * d;
  printf("\n \n \t %ld * %ld = %ld", b, d, f);
  getchar();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    D28(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <system@plt>
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  mov    0x10(%rsp),%rdx
  lea    D27(%rip),%rdi
  mov    %rsi,%rcx
  imul   %rdx,%rcx
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string
name: unpack_data
arguments: data_label: D28
datatype: string
name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D10
datatype: string
name: unpack_data
arguments: data_label: D27
datatype: string

tool: D3: %ld

tool: D28: clear

tool: D8: 
 
 	 Enter value for variables b: 

tool: D10: 
 
 	 Enter value for variables d: 

tool: D27: 
 
 	 %ld * %ld = %ld

assistant: ```c
int main() {
  long int b, d, f;
  system("clear");
  printf("\n \n \t Enter value for variables b: ");
  scanf("%ld", &b);
  system("clear");
  printf("\n \n \t Enter value for variables d: ");
  scanf("%ld", &d);
  system("clear");
  f = b * d;
  printf("\n \n \t %ld * %ld = %ld", b, d, f);
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x14(%rbp)
  jg     L14
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L25
L14:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x10(%rbp),%rdx
  lea    D29(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D29(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <uniquePaths@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
data_type: string
name: retrieve_data
arguments: tag: D29
data_type: string
name: retrieve_data
arguments: tag: D7
data_type: string

tool: D12: Must provide two integers.

tool: D29: %u

tool: D7: %llu


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    puts("Must provide two integers.");
    return 1;
  }
  unsigned int m, n;
  sscanf(argv[1], "%u", &m);
  sscanf(argv[2], "%u", &n);
  printf("%llu\n", uniquePaths(m, n));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jle    L14
  mov    %rsi,%rbx
  mov    %rsp,%rdx
  mov    0x8(%rsi),%rdi
  lea    D3(%rip),%rbp
  mov    %rbp,%rsi
  call   <sscanf@plt>
  lea    0x4(%rsp),%rdx
  mov    0x10(%rbx),%rdi
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <uniquePaths@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L20:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L20
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D29
type_infered: string
name: retrieve_data
arguments: data_label: D17
type_infered: string

tool: D3: %u

tool: D29: %llu


tool: D17: Must provide two integers.

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    puts("Must provide two integers.");
    return 1;
  }
  unsigned int m, n;
  sscanf(argv[1], "%u", &m);
  sscanf(argv[2], "%u", &n);
  printf("%llu\n", uniquePaths(m, n));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jle    L19
  mov    0x8(%rsi),%rdi
  lea    D18(%rip),%rbp
  mov    %rsi,%rbx
  mov    %rsp,%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x10(%rbx),%rdi
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <uniquePaths@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L15
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string

tool: D18: %u

tool: D2: %llu


tool: D7: Must provide two integers.

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    puts("Must provide two integers.");
    return 1;
  }
  unsigned int m, n;
  sscanf(argv[1], "%u", &m);
  sscanf(argv[2], "%u", &n);
  printf("%llu\n", uniquePaths(m, n));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jle    L17
  mov    0x8(%rsi),%rdi
  lea    D12(%rip),%rbp
  mov    %rsi,%rbx
  mov    %rsp,%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x10(%rbx),%rdi
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <uniquePaths@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D20
type_guessed: string

tool: D12: %u

tool: D9: %llu


tool: D20: Must provide two integers.

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    puts("Must provide two integers.");
    return 1;
  }
  unsigned int m, n;
  sscanf(argv[1], "%u", &m);
  sscanf(argv[2], "%u", &n);
  printf("%llu\n", uniquePaths(m, n));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<genBitCount_unsigned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L11:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x0,-0x14(%rbp)
  jne    L11
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int genBitCount_unsigned(unsigned v) {
  unsigned c;
  for (c = 0; v; c++)
    v &= v - 1;
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<genBitCount_unsigned>:
  endbr64
  test   %edi,%edi
  je     L17
  mov    $0x0,%edx
L2:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edx
  and    %eax,%edi
  jne    L2
L20:
  mov    %edx,%eax
  ret
L17:
  mov    %edi,%edx
  jmp    L20
```

assistant: ```c
int genBitCount_unsigned(unsigned v) {
  unsigned c;
  for (c = 0; v; c++)
    v &= v - 1;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<genBitCount_unsigned>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L6
  nopw   0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rdi),%edx
  add    $0x1,%eax
  and    %edx,%edi
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
int genBitCount_unsigned(unsigned v) {
  unsigned c;
  for (c = 0; v; c++)
    v &= v - 1;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<genBitCount_unsigned>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L19
  nopw   0x0(%rax,%rax,1)
L11:
  lea    -0x1(%rdi),%edx
  add    $0x1,%eax
  and    %edx,%edi
  jne    L11
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
int genBitCount_unsigned(unsigned v) {
  unsigned c;
  for (c = 0; v; c++)
    v &= v - 1;
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wp_hash_table_find_closest_shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L5:
  sarl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int wp_hash_table_find_closest_shift(int n) {
  int i;
  for (i = 0; n; i++) {
    n >>= 1;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wp_hash_table_find_closest_shift>:
  endbr64
  test   %edi,%edi
  je     L1
  mov    $0x0,%eax
L0:
  add    $0x1,%eax
  sar    %edi
  jne    L0
  ret
L1:
  mov    %edi,%eax
  ret
```

assistant: ```c
int wp_hash_table_find_closest_shift(int n) {
  int i;
  for (i = 0; n; i++) {
    n >>= 1;
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wp_hash_table_find_closest_shift>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L19
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x1,%eax
  sar    %edi
  jne    L10
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
int wp_hash_table_find_closest_shift(int n) {
  int i;
  for (i = 0; n; i++) {
    n >>= 1;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wp_hash_table_find_closest_shift>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L6
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%eax
  sar    %edi
  jne    L2
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
int wp_hash_table_find_closest_shift(int n) {
  int i;
  for (i = 0; n; i++) {
    n >>= 1;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vsyslog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_info(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: Translate the below assembly code into C programming language:

```asm
<log_info>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void log_info(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log_info>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_info(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(LOG_INFO, format, ap);
  va_end(ap);
}
```