ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<strstrnull>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L2
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *strstrnull(const char *s, const char *c) {
  const char *result = strstr(s, c);
  if (!result) {
    result = s + strlen(s);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strstrnull>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L8
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *strstrnull(const char *s, const char *c) {
  const char *result = strstr(s, c);
  if (!result) {
    result = s + strlen(s);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<imprimeTabuleiro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L82
L7:
  movl   $0x0,-0x4(%rbp)
  jmp    L78
L41:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L18
  mov    $0x58,%edi
  call   <putchar@plt>
  jmp    L34
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0xffffffff,%eax
  jne    L98
  mov    $0x4f,%edi
  call   <putchar@plt>
  jmp    L34
L98:
  mov    $0x20,%edi
  call   <putchar@plt>
L34:
  cmpl   $0x0,-0x4(%rbp)
  je     L20
  cmpl   $0x1,-0x4(%rbp)
  jne    L94
L20:
  mov    $0x2502,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L113
L94:
  cmpl   $0x2,-0x4(%rbp)
  jne    L113
  mov    $0xa,%edi
  call   <putchar@plt>
L113:
  addl   $0x1,-0x4(%rbp)
L78:
  cmpl   $0x2,-0x4(%rbp)
  jle    L41
  cmpl   $0x0,-0x8(%rbp)
  je     L26
  cmpl   $0x1,-0x8(%rbp)
  jne    L107
L26:
  mov    $0x2500,%r9d
  mov    $0x253c,%r8d
  mov    $0x2500,%ecx
  mov    $0x253c,%edx
  mov    $0x2500,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L107:
  addl   $0x1,-0x8(%rbp)
L82:
  cmpl   $0x2,-0x8(%rbp)
  jle    L7
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D13
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string

tool: D1: 


tool: D13: %lc

tool: D18: %lc%lc%lc%lc%lc


assistant: ```c
void imprimeTabuleiro(int tab[3][3]) {
  int i, j;
  printf("\n\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (tab[i][j] == 1) {
        printf("X");
      } else if (tab[i][j] == -1) {
        printf("O");
      } else {
        printf(" ");
      }
      if (j == 0 || j == 1) {
        printf("%lc", L'\u2502');
      } else if (j == 2) {
        printf("\n");
      }
    }
    if (i == 0 || i == 1)
      printf("%lc%lc%lc%lc%lc\n", L'\u2500', L'\u253c', L'\u2500', L'\u253c', L'\u2500');
  }
  printf("\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<imprimeTabuleiro>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%r13d
  lea    D7(%rip),%r14
  lea    D25(%rip),%r15
  jmp    L7
L106:
  mov    $0x58,%edi
  call   <putchar@plt>
  jmp    L83
L19:
  mov    $0x4f,%edi
  call   <putchar@plt>
L83:
  mov    %ebx,%eax
  cmp    $0x1,%ebx
  ja     L3
  mov    $0x2502,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L12:
  add    $0x1,%rbx
L101:
  mov    (%r12,%rbx,4),%eax
  cmp    $0x1,%eax
  je     L106
  cmp    $0xffffffff,%eax
  je     L19
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L83
L3:
  cmp    $0x2,%ebx
  je     L96
  add    $0x1,%eax
  cmp    $0x2,%eax
  jle    L12
L2:
  lea    -0x1(%r13),%eax
  cmp    $0x1,%eax
  ja     L22
  mov    $0x2500,%r9d
  mov    $0x253c,%r8d
  mov    $0x2500,%ecx
  mov    $0x253c,%edx
  mov    $0x2500,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L45:
  add    $0x1,%r13d
  add    $0xc,%rbp
L7:
  mov    %rbp,%r12
  mov    $0x0,%ebx
  jmp    L101
L96:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L2
L22:
  cmp    $0x2,%r13d
  jle    L45
  lea    D38(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string

tool: D38: 


tool: D7: %lc

tool: D25: %lc%lc%lc%lc%lc


assistant: ```c
void imprimeTabuleiro(int tab[3][3]) {
  int i, j;
  printf("\n\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (tab[i][j] == 1) {
        printf("X");
      } else if (tab[i][j] == -1) {
        printf("O");
      } else {
        printf(" ");
      }
      if (j == 0 || j == 1) {
        printf("%lc", L'\u2502');
      } else if (j == 2) {
        printf("\n");
      }
    }
    if (i == 0 || i == 1)
      printf("%lc%lc%lc%lc%lc\n", L'\u2500', L'\u253c', L'\u2500', L'\u253c', L'\u2500');
  }
  printf("\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<imprimeTabuleiro>:
  endbr64
  push   %r15
  lea    D17(%rip),%r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r14,%rdi
  push   %rbx
  lea    0x18(%rbp),%r13
  sub    $0x18,%rsp
  call   <puts@plt>
  lea    0x24(%rbp),%rax
  mov    %rax,0x8(%rsp)
L64:
  xor    %ebx,%ebx
  mov    0x0(%rbp,%rbx,4),%eax
  cmp    $0x1,%eax
  je     L35
L72:
  cmp    $0xffffffff,%eax
  je     L18
  mov    $0x20,%edi
  call   <putchar@plt>
L47:
  cmp    $0x2,%rbx
  je     L0
L3:
  mov    $0x2502,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,4),%eax
  cmp    $0x1,%eax
  jne    L72
L35:
  mov    $0x58,%edi
  call   <putchar@plt>
  cmp    $0x2,%rbx
  jne    L3
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r13,%rbp
  je     L43
  mov    $0x2500,%r9d
  mov    $0x2500,%ecx
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0x253c,%r8d
  mov    $0x253c,%edx
  mov    $0x2500,%esi
  add    $0xc,%rbp
  call   <printf@plt>
  cmp    0x8(%rsp),%rbp
  jne    L64
L43:
  add    $0x18,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x4f,%edi
  call   <putchar@plt>
  jmp    L47
```

tool_calls: name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D17: %lc%lc%lc%lc%lc


tool: D1: 


tool: D6: %lc

assistant: ```c
void imprimeTabuleiro(int tab[3][3]) {
  int i, j;
  printf("\n\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (tab[i][j] == 1) {
        printf("X");
      } else if (tab[i][j] == -1) {
        printf("O");
      } else {
        printf(" ");
      }
      if (j == 0 || j == 1) {
        printf("%lc", L'\u2502');
      } else if (j == 2) {
        printf("\n");
      }
    }
    if (i == 0 || i == 1)
      printf("%lc%lc%lc%lc%lc\n", L'\u2500', L'\u253c', L'\u2500', L'\u253c', L'\u2500');
  }
  printf("\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<imprimeTabuleiro>:
  endbr64
  push   %r15
  lea    D8(%rip),%r15
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r14,%rdi
  push   %rbx
  lea    0x18(%rbp),%r13
  sub    $0x18,%rsp
  call   <puts@plt>
  lea    0x24(%rbp),%rax
  mov    %rax,0x8(%rsp)
L33:
  xor    %ebx,%ebx
  mov    0x0(%rbp,%rbx,4),%eax
  cmp    $0x1,%eax
  je     L73
L41:
  cmp    $0xffffffff,%eax
  je     L47
  mov    $0x20,%edi
  call   <putchar@plt>
L16:
  cmp    $0x2,%rbx
  je     L29
L62:
  mov    $0x2502,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,4),%eax
  cmp    $0x1,%eax
  jne    L41
L73:
  mov    $0x58,%edi
  call   <putchar@plt>
  cmp    $0x2,%rbx
  jne    L62
L29:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r13,%rbp
  je     L71
  mov    $0x2500,%r9d
  mov    $0x2500,%ecx
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0x253c,%r8d
  mov    $0x253c,%edx
  mov    $0x2500,%esi
  add    $0xc,%rbp
  call   <printf@plt>
  cmp    0x8(%rsp),%rbp
  jne    L33
L71:
  add    $0x18,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0x4f,%edi
  call   <putchar@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D22
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D8: %lc%lc%lc%lc%lc


tool: D22: 


tool: D9: %lc

assistant: ```c
void imprimeTabuleiro(int tab[3][3]) {
  int i, j;
  printf("\n\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (tab[i][j] == 1) {
        printf("X");
      } else if (tab[i][j] == -1) {
        printf("O");
      } else {
        printf(" ");
      }
      if (j == 0 || j == 1) {
        printf("%lc", L'\u2502');
      } else if (j == 2) {
        printf("\n");
      }
    }
    if (i == 0 || i == 1)
      printf("%lc%lc%lc%lc%lc\n", L'\u2500', L'\u253c', L'\u2500', L'\u253c', L'\u2500');
  }
  printf("\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<left_shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  jmp    L40
L2:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x14(%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L15:
  cmpl   $0x3,-0xc(%rbp)
  jg     L28
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L48
L28:
  cmpl   $0x4,-0xc(%rbp)
  jle    L48
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L48:
  addl   $0x1,-0xc(%rbp)
L20:
  cmpl   $0x8,-0xc(%rbp)
  jle    L15
  mov    -0x18(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x24(%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x1c(%rbp)
L40:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void left_shift(int keyip[], int shifts) {
  int t1, t2, i;
  while (shifts > 0) {
    t1 = keyip[0], t2 = keyip[5];
    for (i = 0; i < 9; i++)
      if (i < 4)
        keyip[i] = keyip[i + 1];
      else if (i > 4)
        keyip[i] = keyip[i + 1];
    keyip[4] = t1, keyip[9] = t2;
    shifts--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<left_shift>:
  endbr64
  test   %esi,%esi
  jg     L69
L21:
  ret
L18:
  mov    0x4(%rdi,%rax,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  jmp    L75
L29:
  cmp    $0x8,%edx
  jg     L74
L75:
  add    $0x1,%rax
  add    $0x1,%edx
L67:
  cmp    $0x3,%eax
  jle    L18
  cmp    $0x4,%eax
  jle    L29
  mov    0x4(%rdi,%rax,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  jmp    L29
L74:
  mov    %r9d,0x10(%rdi)
  mov    %r8d,0x24(%rdi)
  sub    $0x1,%esi
  je     L21
L69:
  mov    (%rdi),%r9d
  mov    0x14(%rdi),%r8d
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L67
```

assistant: ```c
void left_shift(int keyip[], int shifts) {
  int t1, t2, i;
  while (shifts > 0) {
    t1 = keyip[0], t2 = keyip[5];
    for (i = 0; i < 9; i++)
      if (i < 4)
        keyip[i] = keyip[i + 1];
      else if (i > 4)
        keyip[i] = keyip[i + 1];
    keyip[4] = t1, keyip[9] = t2;
    shifts--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<left_shift>:
  endbr64
  test   %esi,%esi
  jle    L34
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rdi),%r8d
  mov    0x14(%rdi),%ecx
  xor    %eax,%eax
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L45:
  cmp    $0x4,%eax
  je     L51
  mov    0x4(%rdi,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  cmp    $0x8,%rax
  je     L13
L51:
  add    $0x1,%rax
L37:
  cmp    $0x3,%rax
  ja     L45
  mov    0x4(%rdi,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  jmp    L51
  nopl   (%rax)
L13:
  mov    %r8d,0x10(%rdi)
  mov    %ecx,0x24(%rdi)
  sub    $0x1,%esi
  jne    L8
  ret
L34:
  ret
```

assistant: ```c
void left_shift(int keyip[], int shifts) {
  int t1, t2, i;
  while (shifts > 0) {
    t1 = keyip[0], t2 = keyip[5];
    for (i = 0; i < 9; i++)
      if (i < 4)
        keyip[i] = keyip[i + 1];
      else if (i > 4)
        keyip[i] = keyip[i + 1];
    keyip[4] = t1, keyip[9] = t2;
    shifts--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<left_shift>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r13
  mov    %rdi,%rax
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%ecx
  mov    0x14(%rdi),%edx
  mov    0x4(%rdi),%r12d
  mov    0x8(%rdi),%ebp
  mov    0xc(%rdi),%ebx
  mov    0x10(%rdi),%r11d
  mov    0x18(%rdi),%r10d
  mov    0x1c(%rdi),%r9d
  mov    0x20(%rdi),%r8d
  mov    0x24(%rdi),%edi
  jmp    L12
  nopl   0x0(%rax)
L8:
  mov    %edx,%r13d
  mov    %r10d,%edx
  mov    %r9d,%r10d
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %r13d,%edi
  mov    %ecx,%r13d
  mov    %r12d,%ecx
  mov    %ebp,%r12d
  mov    %ebx,%ebp
  mov    %r11d,%ebx
  mov    %r13d,%r11d
L12:
  sub    $0x1,%esi
  jne    L8
  mov    %r12d,(%rax)
  mov    %ebp,0x4(%rax)
  mov    %ebx,0x8(%rax)
  mov    %r11d,0xc(%rax)
  mov    %r10d,0x14(%rax)
  mov    %r9d,0x18(%rax)
  mov    %r8d,0x1c(%rax)
  mov    %edi,0x20(%rax)
  mov    %ecx,0x10(%rax)
  mov    %edx,0x24(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  ret
```

assistant: ```c
void left_shift(int keyip[], int shifts) {
  int t1, t2, i;
  while (shifts > 0) {
    t1 = keyip[0], t2 = keyip[5];
    for (i = 0; i < 9; i++)
      if (i < 4)
        keyip[i] = keyip[i + 1];
      else if (i > 4)
        keyip[i] = keyip[i + 1];
    keyip[4] = t1, keyip[9] = t2;
    shifts--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cp_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cp_name(char *s, char *d, int len) {
  int i;
  for (i = 0; i < len; ++i)
    d[i] = s[i];
  d[i] = 0;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cp_name>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L19
  mov    %edx,%r9d
  mov    $0x0,%ecx
L29:
  movzbl (%rdi,%rcx,1),%r8d
  mov    %r8b,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L29
L9:
  movslq %eax,%rdx
  movb   $0x0,(%rsi,%rdx,1)
  ret
L19:
  mov    $0x0,%eax
  jmp    L9
```

assistant: ```c
int cp_name(char *s, char *d, int len) {
  int i;
  for (i = 0; i < len; ++i)
    d[i] = s[i];
  d[i] = 0;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cp_name>:
  endbr64
  test   %edx,%edx
  jle    L13
  movslq %edx,%r9
  xor    %ecx,%ecx
  nopl   (%rax)
L3:
  movzbl (%rdi,%rcx,1),%r8d
  mov    %r8b,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L3
  add    %r9,%rsi
  mov    %edx,%eax
  movb   $0x0,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  movb   $0x0,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int cp_name(char *s, char *d, int len) {
  int i;
  for (i = 0; i < len; ++i)
    d[i] = s[i];
  d[i] = 0;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cp_name>:
  endbr64
  mov    %rsi,%rcx
  mov    %edx,%eax
  test   %edx,%edx
  jle    L68
  lea    0x1(%rdi),%r9
  mov    %edx,%r8d
  lea    -0x1(%rdx),%edx
  sub    %r9,%rsi
  cmp    $0xe,%rsi
  jbe    L144
  cmp    $0x6,%edx
  jbe    L144
  cmp    $0xe,%edx
  jbe    L92
  mov    %eax,%esi
  xor    %edx,%edx
  shr    $0x4,%esi
  shl    $0x4,%rsi
  nopl   (%rax)
L115:
  movdqu (%rdi,%rdx,1),%xmm0
  movups %xmm0,(%rcx,%rdx,1)
  add    $0x10,%rdx
  cmp    %rsi,%rdx
  jne    L115
  mov    %eax,%esi
  and    $0xfffffff0,%esi
  mov    %esi,%edx
  cmp    %esi,%eax
  je     L41
  mov    %eax,%r8d
  sub    %esi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L113
L15:
  mov    (%rdi,%rsi,1),%r9
  mov    %r9,(%rcx,%rsi,1)
  mov    %r8d,%esi
  and    $0xfffffff8,%esi
  add    %esi,%edx
  cmp    %esi,%r8d
  je     L41
L113:
  movslq %edx,%rsi
  movzbl (%rdi,%rsi,1),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  lea    0x1(%rdx),%esi
  cmp    %esi,%eax
  jle    L41
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  lea    0x2(%rdx),%esi
  cmp    %esi,%eax
  jle    L41
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  lea    0x3(%rdx),%esi
  cmp    %esi,%eax
  jle    L41
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  lea    0x4(%rdx),%esi
  cmp    %esi,%eax
  jle    L41
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  lea    0x5(%rdx),%esi
  cmp    %esi,%eax
  jle    L41
  movslq %esi,%rsi
  add    $0x6,%edx
  movzbl (%rdi,%rsi,1),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  cmp    %edx,%eax
  jle    L41
  movslq %edx,%rdx
  movzbl (%rdi,%rdx,1),%esi
  mov    %sil,(%rcx,%rdx,1)
L41:
  movslq %eax,%rdx
  add    %rdx,%rcx
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L144:
  mov    %eax,%r8d
  xor    %edx,%edx
  nopl   (%rax)
L85:
  movzbl (%rdi,%rdx,1),%esi
  mov    %sil,(%rcx,%rdx,1)
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L85
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L68:
  movb   $0x0,(%rcx)
  xor    %eax,%eax
  ret
L92:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L15
```

assistant: ```c
int cp_name(char *s, char *d, int len) {
  int i;
  for (i = 0; i < len; ++i)
    d[i] = s[i];
  d[i] = 0;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L52
L55:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L10
  mov    -0x4(%rbp),%eax
  jmp    L43
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L13
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L52
L13:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L52:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L55
  mov    $0xffffffff,%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
int binary_search(int *a, int n, int key) {
  int start = 0;
  int end = n - 1;
  while (start <= end) {
    int mid = (start + end) / 2;
    if (*(a + mid) == key)
      return mid;
    else if (*(a + mid) > key)
      end = mid - 1;
    else
      start = mid + 1;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binary_search>:
  endbr64
  sub    $0x1,%esi
  js     L63
  mov    $0x0,%r8d
  jmp    L25
L8:
  lea    0x1(%rax),%r8d
L65:
  cmp    %esi,%r8d
  jg     L10
L25:
  lea    (%r8,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %edx,%ecx
  je     L23
  jle    L8
  lea    -0x1(%rax),%esi
  jmp    L65
L10:
  mov    $0xffffffff,%r9d
L23:
  mov    %r9d,%eax
  ret
L63:
  mov    $0xffffffff,%r9d
  jmp    L23
```

assistant: ```c
int binary_search(int *a, int n, int key) {
  int start = 0;
  int end = n - 1;
  while (start <= end) {
    int mid = (start + end) / 2;
    if (*(a + mid) == key)
      return mid;
    else if (*(a + mid) > key)
      end = mid - 1;
    else
      start = mid + 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<binary_search>:
  endbr64
  sub    $0x1,%esi
  js     L34
  xor    %ecx,%ecx
  jmp    L33
  nopl   (%rax)
L18:
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jl     L34
L33:
  lea    (%rsi,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L24
  jg     L18
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jge    L33
L34:
  mov    $0xffffffff,%eax
L24:
  ret
```

assistant: ```c
int binary_search(int *a, int n, int key) {
  int start = 0;
  int end = n - 1;
  while (start <= end) {
    int mid = (start + end) / 2;
    if (*(a + mid) == key)
      return mid;
    else if (*(a + mid) > key)
      end = mid - 1;
    else
      start = mid + 1;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<binary_search>:
  endbr64
  sub    $0x1,%esi
  js     L51
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L34:
  lea    (%rsi,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L16
  jle    L57
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L34
L51:
  mov    $0xffffffff,%eax
L16:
  ret
  nopl   (%rax)
L57:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L34
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int binary_search(int *a, int n, int key) {
  int start = 0;
  int end = n - 1;
  while (start <= end) {
    int mid = (start + end) / 2;
    if (*(a + mid) == key)
      return mid;
    else if (*(a + mid) > key)
      end = mid - 1;
    else
      start = mid + 1;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<WAIT1_Wait10Cycles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void WAIT1_Wait10Cycles(void) {
  asm("nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t");
}
```
user: Translate the below assembly code into C programming language:

```asm
<WAIT1_Wait10Cycles>:
  endbr64
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  nop
  ret
```

assistant: ```c
void WAIT1_Wait10Cycles(void) {
  asm("nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t"
      "nop \n\t");
}
```