ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L33
  mov    0x8(%rsi),%rsi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  lea    D8(%rip),%r13
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L30:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jg     L30
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  lea    D30(%rip),%rdi
  call   <puts@plt>
  sub    $0x1,%ebp
  jne    L13
  mov    (%r12),%rdx
  xor    %esi,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
```

tool_calls: name: parse_data
arguments: tag: D35
type_infered: string
name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D30
type_infered: string

tool: D35: Hello %s!


tool: D8: argv[%d] = %s


tool: D30: Hello!

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc > 1) {
    printf("Hello %s!\n", argv[1]);
  } else {
    printf("Hello!\n");
  }
  for (int i = 0; i < argc; i++) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L32
  mov    0x8(%rsi),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  lea    D29(%rip),%r13
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jg     L19
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  sub    $0x1,%ebp
  jne    L18
  mov    (%r12),%rdx
  xor    %esi,%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
datatype: string
name: extract_symbolic_data
arguments: data_label: D29
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D19: Hello %s!


tool: D29: argv[%d] = %s


tool: D1: Hello!

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc > 1) {
    printf("Hello %s!\n", argv[1]);
  } else {
    printf("Hello!\n");
  }
  for (int i = 0; i < argc; i++) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <get_third_smallest_number@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: %i


assistant: ```c
int main(int argc, char const *argv[]) {
  printf("%i\n", get_third_smallest_number());
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_third_smallest_number@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: %i


assistant: ```c
int main(int argc, char const *argv[]) {
  printf("%i\n", get_third_smallest_number());
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_third_smallest_number@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: %i


assistant: ```c
int main(int argc, char const *argv[]) {
  printf("%i\n", get_third_smallest_number());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_third_smallest_number@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: %i


assistant: ```c
int main(int argc, char const *argv[]) {
  printf("%i\n", get_third_smallest_number());
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Draw_HV_Line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L5
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L47
L5:
  movl   $0x3,-0x4(%rbp)
L47:
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  mov    -0x24(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L28
L22:
  mov    0x10(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    0x10(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    0x10(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L28:
  mov    -0x2c(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  jae    L22
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Draw_HV_Line(unsigned char *Frame, unsigned int Width, int Xmin, int Ymin, int Xmax, int Ymax, int Color) {
  int Index, Step = 0;
  if (Xmin == Xmax)
    Step = 3 * Width;
  else if (Ymax == Ymax)
    Step = 3;
  else
    fprintf(stderr, "HV lines must be either horizontal or vertical\n");
  if (Step != 0)
    for (Index = (Ymin * Width + Xmin) * 3; Index <= (Ymax * Width + Xmax) * 3; Index += Step) {
      Frame[Index] = (unsigned char)(Color >> 16) & 255;
      Frame[Index + 1] = (unsigned char)(Color >> 8) & 255;
      Frame[Index + 2] = (unsigned char)Color & 255;
    }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Draw_HV_Line>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edx,%eax
  mov    0x18(%rsp),%ebx
  mov    $0x3,%edx
  cmp    %r8d,%eax
  je     L42
L31:
  imul   %esi,%ecx
  add    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  imul   %esi,%r9d
  lea    (%r9,%r8,1),%ecx
  lea    (%rcx,%rcx,2),%esi
  cmp    %esi,%eax
  ja     L7
  mov    %ebx,%ecx
  sar    $0x10,%ecx
  movzbl %bh,%ebp
  movslq %edx,%rdx
  cltq
L15:
  mov    %cl,(%rdi,%rax,1)
  mov    %bpl,0x1(%rdi,%rax,1)
  mov    %bl,0x2(%rdi,%rax,1)
  add    %rdx,%rax
  cmp    %eax,%esi
  jae    L15
L7:
  pop    %rbx
  pop    %rbp
  ret
L42:
  lea    (%rsi,%rsi,2),%r10d
  mov    %r10d,%edx
  test   %r10d,%r10d
  je     L7
  jmp    L31
```

assistant: ```c
void Draw_HV_Line(unsigned char *Frame, unsigned int Width, int Xmin, int Ymin, int Xmax, int Ymax, int Color) {
  int Index, Step = 0;
  if (Xmin == Xmax)
    Step = 3 * Width;
  else if (Ymax == Ymax)
    Step = 3;
  else
    fprintf(stderr, "HV lines must be either horizontal or vertical\n");
  if (Step != 0)
    for (Index = (Ymin * Width + Xmin) * 3; Index <= (Ymax * Width + Xmax) * 3; Index += Step) {
      Frame[Index] = (unsigned char)(Color >> 16) & 255;
      Frame[Index + 1] = (unsigned char)(Color >> 8) & 255;
      Frame[Index + 2] = (unsigned char)Color & 255;
    }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Draw_HV_Line>:
  endbr64
  mov    %edx,%eax
  mov    %esi,%r10d
  mov    0x8(%rsp),%edx
  mov    $0x3,%esi
  cmp    %r8d,%eax
  je     L13
L3:
  imul   %r10d,%ecx
  imul   %r10d,%r9d
  add    %ecx,%eax
  lea    (%r9,%r8,1),%ecx
  lea    (%rax,%rax,2),%eax
  lea    (%rcx,%rcx,2),%r9d
  cmp    %r9d,%eax
  ja     L32
  movzbl %dh,%ecx
  mov    %edx,%r8d
  cltq
  mov    %ecx,%r10d
  sar    $0x10,%r8d
  movslq %esi,%rcx
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r8b,(%rdi,%rax,1)
  mov    %r10b,0x1(%rdi,%rax,1)
  mov    %dl,0x2(%rdi,%rax,1)
  add    %rcx,%rax
  cmp    %eax,%r9d
  jae    L25
L32:
  ret
  xchg   %ax,%ax
L13:
  lea    (%r10,%r10,2),%esi
  test   %esi,%esi
  jne    L3
  ret
```

assistant: ```c
void Draw_HV_Line(unsigned char *Frame, unsigned int Width, int Xmin, int Ymin, int Xmax, int Ymax, int Color) {
  int Index, Step = 0;
  if (Xmin == Xmax)
    Step = 3 * Width;
  else if (Ymax == Ymax)
    Step = 3;
  else
    fprintf(stderr, "HV lines must be either horizontal or vertical\n");
  if (Step != 0)
    for (Index = (Ymin * Width + Xmin) * 3; Index <= (Ymax * Width + Xmax) * 3; Index += Step) {
      Frame[Index] = (unsigned char)(Color >> 16) & 255;
      Frame[Index + 1] = (unsigned char)(Color >> 8) & 255;
      Frame[Index + 2] = (unsigned char)Color & 255;
    }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Draw_HV_Line>:
  endbr64
  mov    %edx,%eax
  mov    %esi,%r10d
  mov    0x8(%rsp),%edx
  mov    $0x3,%esi
  cmp    %r8d,%eax
  je     L19
L35:
  imul   %r10d,%ecx
  imul   %r10d,%r9d
  add    %ecx,%eax
  lea    (%r9,%r8,1),%ecx
  lea    (%rax,%rax,2),%eax
  lea    (%rcx,%rcx,2),%r9d
  cmp    %r9d,%eax
  ja     L1
  movzbl %dh,%ecx
  mov    %edx,%r8d
  cltq
  mov    %ecx,%r10d
  sar    $0x10,%r8d
  movslq %esi,%rcx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r8b,(%rdi,%rax,1)
  mov    %r10b,0x1(%rdi,%rax,1)
  mov    %dl,0x2(%rdi,%rax,1)
  add    %rcx,%rax
  cmp    %eax,%r9d
  jae    L18
L1:
  ret
  xchg   %ax,%ax
L19:
  lea    (%r10,%r10,2),%esi
  test   %esi,%esi
  jne    L35
  ret
```

assistant: ```c
void Draw_HV_Line(unsigned char *Frame, unsigned int Width, int Xmin, int Ymin, int Xmax, int Ymax, int Color) {
  int Index, Step = 0;
  if (Xmin == Xmax)
    Step = 3 * Width;
  else if (Ymax == Ymax)
    Step = 3;
  else
    fprintf(stderr, "HV lines must be either horizontal or vertical\n");
  if (Step != 0)
    for (Index = (Ymin * Width + Xmin) * 3; Index <= (Ymax * Width + Xmax) * 3; Index += Step) {
      Frame[Index] = (unsigned char)(Color >> 16) & 255;
      Frame[Index + 1] = (unsigned char)(Color >> 8) & 255;
      Frame[Index + 2] = (unsigned char)Color & 255;
    }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<good_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xf,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,%r12
  mov    -0x18(%rbp),%rcx
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xf,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,%rbx
  imul   $0x1f31d,%rbx,%rax
  mov    %rcx,%rbx
  sub    %rax,%rbx
  imul   $0x41a7,%rbx,%rdx
  imul   $0xfffffffffffff4ec,%r12,%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jg     L2
  addq   $0x7fffffff,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
long good_rand(long x) {
  register long hi, lo;
  hi = x / 127773;
  lo = x % 127773;
  x = 16807 * lo - 2836 * hi;
  if (x <= 0)
    x += 0x7fffffff;
  return (x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<good_rand>:
  endbr64
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0xf,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x1f31d,%rdx,%rax
  sub    %rax,%rdi
  imul   $0x41a7,%rdi,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  ret
```

assistant: ```c
long good_rand(long x) {
  register long hi, lo;
  hi = x / 127773;
  lo = x % 127773;
  x = 16807 * lo - 2836 * hi;
  if (x <= 0)
    x += 0x7fffffff;
  return (x);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<good_rand>:
  endbr64
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0xf,%rdx
  sub    %rax,%rdx
  imul   $0x1f31d,%rdx,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  sub    %rax,%rdi
  imul   $0x41a7,%rdi,%rax
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  ret
```

assistant: ```c
long good_rand(long x) {
  register long hi, lo;
  hi = x / 127773;
  lo = x % 127773;
  x = 16807 * lo - 2836 * hi;
  if (x <= 0)
    x += 0x7fffffff;
  return (x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<good_rand>:
  endbr64
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0xf,%rdx
  sub    %rax,%rdx
  imul   $0x1f31d,%rdx,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  sub    %rax,%rdi
  imul   $0x41a7,%rdi,%rax
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  ret
```

assistant: ```c
long good_rand(long x) {
  register long hi, lo;
  hi = x / 127773;
  lo = x % 127773;
  x = 16807 * lo - 2836 * hi;
  if (x <= 0)
    x += 0x7fffffff;
  return (x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  unsigned int **b;
  int **c;
  c = b;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  unsigned int **b;
  int **c;
  c = b;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  unsigned int **b;
  int **c;
  c = b;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  unsigned int **b;
  int **c;
  c = b;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<emit_fsubd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <assem_debug@plt>
  mov    -0xc(%rbp),%eax
  shl    $0xc,%eax
  and    $0x7000,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  and    $0x70000,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  and    $0x7,%eax
  or     %edx,%eax
  or     $0xee300b40,%eax
  mov    %eax,%edi
  call   <output_w32@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: fsubd d%d,d%d,d%d


assistant: ```c
void emit_fsubd(int s1, int s2, int d) {
  assem_debug("fsubd d%d,d%d,d%d\n", d, s1, s2);
  output_w32(0xee300b40 | ((d & 7) << 12) | ((s1 & 7) << 16) | (s2 & 7));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_fsubd>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    %esi,%ecx
  mov    %edi,%edx
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  call   <assem_debug@plt>
  shl    $0xc,%ebx
  mov    %ebx,%edi
  and    $0x7000,%edi
  and    $0x7,%r12d
  or     %r12d,%edi
  shl    $0x10,%ebp
  and    $0x70000,%ebp
  or     %ebp,%edi
  or     $0xee300b40,%edi
  call   <output_w32@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: fsubd d%d,d%d,d%d


assistant: ```c
void emit_fsubd(int s1, int s2, int d) {
  assem_debug("fsubd d%d,d%d,d%d\n", d, s1, s2);
  output_w32(0xee300b40 | ((d & 7) << 12) | ((s1 & 7) << 16) | (s2 & 7));
}
```
user: What is the c source code of the assembly code below?

```asm
<emit_fsubd>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  and    $0x7,%r12d
  push   %rbx
  mov    %edx,%ebx
  mov    %edi,%edx
  lea    D1(%rip),%rdi
  mov    %ebx,%esi
  shl    $0xc,%ebx
  shl    $0x10,%ebp
  call   <assem_debug@plt>
  mov    %ebx,%edi
  and    $0x70000,%ebp
  pop    %rbx
  and    $0x7000,%edi
  or     %r12d,%edi
  or     %ebp,%edi
  pop    %rbp
  pop    %r12
  or     $0xee300b40,%edi
  jmp    1070 <output_w32@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: fsubd d%d,d%d,d%d


assistant: ```c
void emit_fsubd(int s1, int s2, int d) {
  assem_debug("fsubd d%d,d%d,d%d\n", d, s1, s2);
  output_w32(0xee300b40 | ((d & 7) << 12) | ((s1 & 7) << 16) | (s2 & 7));
}
```
user: What is the c source code of the assembly code below:

```asm
<emit_fsubd>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  and    $0x7,%r12d
  push   %rbx
  mov    %edx,%ebx
  mov    %edi,%edx
  lea    D5(%rip),%rdi
  mov    %ebx,%esi
  shl    $0xc,%ebx
  shl    $0x10,%ebp
  call   <assem_debug@plt>
  mov    %ebx,%edi
  and    $0x70000,%ebp
  pop    %rbx
  and    $0x7000,%edi
  or     %r12d,%edi
  or     %ebp,%edi
  pop    %rbp
  pop    %r12
  or     $0xee300b40,%edi
  jmp    1070 <output_w32@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D5: fsubd d%d,d%d,d%d


assistant: ```c
void emit_fsubd(int s1, int s2, int d) {
  assem_debug("fsubd d%d,d%d,d%d\n", d, s1, s2);
  output_w32(0xee300b40 | ((d & 7) << 12) | ((s1 & 7) << 16) | (s2 & 7));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    $0x0,%eax
  call   <print_prgname@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(const char *str, ...) {
  va_list args;
  va_start(args, str);
  print_prgname();
  vfprintf(stderr, str, args);
  fputc('\n', stderr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<error>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    $0x0,%eax
  call   <print_prgname@plt>
  mov    D8(%rip),%rbp
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    0x0(%rbp),%edi
  call   <vfprintf@plt>
  mov    0x0(%rbp),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(const char *str, ...) {
  va_list args;
  va_start(args, str);
  print_prgname();
  vfprintf(stderr, str, args);
  fputc('\n', stderr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  xor    %eax,%eax
  call   <print_prgname@plt>
  mov    D7(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(const char *str, ...) {
  va_list args;
  va_start(args, str);
  print_prgname();
  vfprintf(stderr, str, args);
  fputc('\n', stderr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  xor    %eax,%eax
  call   <print_prgname@plt>
  mov    D4(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(const char *str, ...) {
  va_list args;
  va_start(args, str);
  print_prgname();
  vfprintf(stderr, str, args);
  fputc('\n', stderr);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  movb   $0x62,-0x14(%rbp)
  movsbl -0x14(%rbp),%edx
  movsbl -0x1(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bar@plt>
  movzbl -0x1(%rbp),%eax
  mov    %al,-0x14(%rbp)
  cmpb   $0x0,-0x14(%rbp)
  jne    L0
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L0:
  movsbl -0x1(%rbp),%edx
  movsbl -0x14(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int foo(char b) {
  char a;
  a = b;
  b = 'b';
  bar(a, b);
  b = a;
  if (b == 0)
    a++;
  return a + b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movsbl %dil,%ebp
  mov    $0x62,%esi
  mov    %ebp,%edi
  call   <bar@plt>
  test   %bl,%bl
  mov    $0x1,%eax
  cmovne %ebx,%eax
  movsbl %al,%eax
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int foo(char b) {
  char a;
  a = b;
  b = 'b';
  bar(a, b);
  b = a;
  if (b == 0)
    a++;
  return a + b;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    $0x62,%esi
  mov    %edi,%ebp
  push   %rbx
  movsbl %dil,%ebx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <bar@plt>
  test   %bpl,%bpl
  mov    $0x1,%eax
  cmovne %ebx,%eax
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int foo(char b) {
  char a;
  a = b;
  b = 'b';
  bar(a, b);
  b = a;
  if (b == 0)
    a++;
  return a + b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    $0x62,%esi
  mov    %edi,%ebp
  push   %rbx
  movsbl %dil,%ebx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <bar@plt>
  test   %bpl,%bpl
  mov    $0x1,%eax
  cmovne %ebx,%eax
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int foo(char b) {
  char a;
  a = b;
  b = 'b';
  bar(a, b);
  b = a;
  if (b == 0)
    a++;
  return a + b;
}
```