ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<lusolve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movb   $0x4e,-0x39(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L1:
  cmp    %rdx,%rsp
  je     L30
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L1
L30:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L33
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L33:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%r9
  lea    -0x34(%rbp),%r8
  mov    -0x50(%rbp),%rcx
  lea    -0x2c(%rbp),%rdx
  lea    -0x44(%rbp),%rsi
  lea    -0x39(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x38(%rbp),%rdi
  push   %rdi
  lea    -0x30(%rbp),%rdi
  push   %rdi
  push   -0x58(%rbp)
  mov    %rax,%rdi
  call   <dgetrs_@plt>
  add    $0x20,%rsp
  mov    -0x38(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int lusolve(int N, double *A, double *B) {
  char trans = 'N';
  int info;
  int lda = N;
  int ldb = N;
  int NRHS = 1;
  int ipiv[N];
  dgetrs_(&trans, &N, &NRHS, A, &lda, ipiv, B, &ldb, &info);
  return info;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lusolve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %edi,-0x24(%rbp)
  mov    %rdx,%rcx
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x8(%rbp)
  xor    %edx,%edx
  movb   $0x4e,-0x19(%rbp)
  mov    %edi,-0x14(%rbp)
  mov    %edi,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L35:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L13:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L33
  orq    $0x0,-0x8(%rsp,%rax,1)
L33:
  mov    %rsp,%r9
  lea    -0xc(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  lea    -0x19(%rbp),%rdi
  sub    $0x8,%rsp
  lea    -0x18(%rbp),%r8
  push   %r8
  lea    -0x10(%rbp),%r8
  push   %r8
  push   %rcx
  lea    -0x14(%rbp),%r8
  mov    %rsi,%rcx
  mov    %rax,%rsi
  call   <dgetrs_@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  leave
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lusolve(int N, double *A, double *B) {
  char trans = 'N';
  int info;
  int lda = N;
  int ldb = N;
  int NRHS = 1;
  int ipiv[N];
  dgetrs_(&trans, &N, &NRHS, A, &lda, ipiv, B, &ldb, &info);
  return info;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lusolve>:
  endbr64
  push   %rbp
  movslq %edi,%rax
  mov    %rsi,%r10
  mov    %rdx,%rsi
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x8(%rbp)
  xor    %edx,%edx
  mov    %eax,-0x14(%rbp)
  mov    %eax,-0x10(%rbp)
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  movb   $0x4e,-0x19(%rbp)
  sub    %rax,%rcx
  movl   $0x1,-0xc(%rbp)
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L4
L11:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L11
L4:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L0
L48:
  mov    %rsp,%r9
  lea    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  mov    %r10,%rcx
  push   %rax
  lea    -0x10(%rbp),%rax
  lea    -0x24(%rbp),%r11
  push   %rax
  lea    -0xc(%rbp),%rdx
  lea    -0x19(%rbp),%rdi
  push   %rsi
  lea    -0x14(%rbp),%r8
  mov    %r11,%rsi
  call   <dgetrs_@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  leave
  ret
  nopl   0x0(%rax)
L0:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L48
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lusolve(int N, double *A, double *B) {
  char trans = 'N';
  int info;
  int lda = N;
  int ldb = N;
  int NRHS = 1;
  int ipiv[N];
  dgetrs_(&trans, &N, &NRHS, A, &lda, ipiv, B, &ldb, &info);
  return info;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lusolve>:
  endbr64
  push   %rbp
  movslq %edi,%rax
  mov    %rsi,%r10
  mov    %rdx,%rsi
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x8(%rbp)
  xor    %edx,%edx
  mov    %eax,-0x14(%rbp)
  mov    %eax,-0x10(%rbp)
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  movb   $0x4e,-0x19(%rbp)
  sub    %rax,%rcx
  movl   $0x1,-0xc(%rbp)
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L30
L28:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L28
L30:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L16
L32:
  mov    %rsp,%r9
  lea    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  mov    %r10,%rcx
  push   %rax
  lea    -0x10(%rbp),%rax
  lea    -0x24(%rbp),%r11
  push   %rax
  lea    -0xc(%rbp),%rdx
  lea    -0x19(%rbp),%rdi
  push   %rsi
  lea    -0x14(%rbp),%r8
  mov    %r11,%rsi
  call   <dgetrs_@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  leave
  ret
  nopl   0x0(%rax)
L16:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L32
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lusolve(int N, double *A, double *B) {
  char trans = 'N';
  int info;
  int lda = N;
  int ldb = N;
  int NRHS = 1;
  int ipiv[N];
  dgetrs_(&trans, &N, &NRHS, A, &lda, ipiv, B, &ldb, &info);
  return info;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<real_lswap4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long real_lswap4(long i) {
  char *ii = (char *)&(i);
  char *jj = ii + 3;
  *ii ^= *jj;
  *jj ^= *ii;
  *ii ^= *jj;
  ii++;
  jj--;
  *ii ^= *jj;
  *jj ^= *ii;
  *ii ^= *jj;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<real_lswap4>:
  endbr64
  mov    %rdi,%rax
  mov    %edi,%ecx
  sar    $0x18,%ecx
  movzbl %dil,%edx
  shl    $0x18,%rdx
  movabs $0xffffffff00ffffff,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
  mov    %cl,%al
  mov    %eax,%edx
  shl    $0x8,%edx
  sar    $0x18,%edx
  movzbl %ah,%ecx
  shl    $0x10,%rcx
  and    $0xffffffffff00ffff,%rax
  or     %rcx,%rax
  mov    %dl,%ah
  ret
```

assistant: ```c
long real_lswap4(long i) {
  char *ii = (char *)&(i);
  char *jj = ii + 3;
  *ii ^= *jj;
  *jj ^= *ii;
  *ii ^= *jj;
  ii++;
  jj--;
  *ii ^= *jj;
  *jj ^= *ii;
  *ii ^= *jj;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<real_lswap4>:
  endbr64
  movabs $0xffffffff00ffffff,%rcx
  movzbl %dil,%eax
  mov    %edi,%edx
  shl    $0x18,%rax
  and    %rcx,%rdi
  sar    $0x18,%edx
  or     %rax,%rdi
  mov    %dl,%dil
  mov    %rdi,%rax
  and    $0xffffffffff0000ff,%rdi
  shr    $0x8,%rax
  rol    $0x8,%ax
  movzwl %ax,%eax
  shl    $0x8,%rax
  or     %rdi,%rax
  ret
```

assistant: ```c
long real_lswap4(long i) {
  char *ii = (char *)&(i);
  char *jj = ii + 3;
  *ii ^= *jj;
  *jj ^= *ii;
  *ii ^= *jj;
  ii++;
  jj--;
  *ii ^= *jj;
  *jj ^= *ii;
  *ii ^= *jj;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<real_lswap4>:
  endbr64
  movabs $0xffffffff00000000,%rdx
  mov    %edi,%eax
  bswap  %eax
  and    %rdx,%rdi
  mov    %eax,%eax
  or     %rdi,%rax
  ret
```

assistant: ```c
long real_lswap4(long i) {
  char *ii = (char *)&(i);
  char *jj = ii + 3;
  *ii ^= *jj;
  *jj ^= *ii;
  *ii ^= *jj;
  ii++;
  jj--;
  *ii ^= *jj;
  *jj ^= *ii;
  *ii ^= *jj;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sys_fstat64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printargs@plt>
  leave
  ret
```

assistant: ```c
int sys_fstat64(tcp)
struct tcb *tcp;
{
  return printargs(tcp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sys_fstat64>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <printargs@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sys_fstat64(tcp)
struct tcb *tcp;
{
  return printargs(tcp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sys_fstat64>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <printargs@plt>
```

assistant: ```c
int sys_fstat64(tcp)
struct tcb *tcp;
{
  return printargs(tcp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sys_fstat64>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <printargs@plt>
```

assistant: ```c
int sys_fstat64(tcp)
struct tcb *tcp;
{
  return printargs(tcp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xffffffffffffffe9,-0x10(%rbp)
  addq   $0x17,-0x10(%rbp)
  mov    $0xffffffffffffffe9,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x17,%rax
  mov    %rax,-0x10(%rbp)
  pop    -0x10(%rbp)
  pop    %rax
  mov    %rax,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void bar4() {
  if (sizeof(void *) == sizeof(long long)) {
    long long foo;
    asm volatile("mov%z0 %1, %0" : "=m"(foo) : "er"(-23));
    asm volatile("add%z0 %1, %0" : "+m"(foo) : "er"(23));
    asm volatile("mov%z0 %1, %0" : "=r"(foo) : "er"(-23));
    asm volatile("add%z0 %1, %0" : "+r"(foo) : "er"(23));
    asm volatile("pop%z0 %0" : "=m"(foo));
    asm volatile("pop%z0 %0" : "=r"(foo));
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<bar4>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffe9,(%rsp)
  addq   $0x17,(%rsp)
  mov    $0xffffffffffffffe9,%rax
  add    $0x17,%rax
  pop    (%rsp)
  pop    %rax
  mov    %rax,(%rsp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar4() {
  if (sizeof(void *) == sizeof(long long)) {
    long long foo;
    asm volatile("mov%z0 %1, %0" : "=m"(foo) : "er"(-23));
    asm volatile("add%z0 %1, %0" : "+m"(foo) : "er"(23));
    asm volatile("mov%z0 %1, %0" : "=r"(foo) : "er"(-23));
    asm volatile("add%z0 %1, %0" : "+r"(foo) : "er"(23));
    asm volatile("pop%z0 %0" : "=m"(foo));
    asm volatile("pop%z0 %0" : "=r"(foo));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bar4>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffe9,(%rsp)
  addq   $0x17,(%rsp)
  mov    $0xffffffffffffffe9,%rax
  add    $0x17,%rax
  pop    (%rsp)
  pop    %rax
  mov    %rax,(%rsp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar4() {
  if (sizeof(void *) == sizeof(long long)) {
    long long foo;
    asm volatile("mov%z0 %1, %0" : "=m"(foo) : "er"(-23));
    asm volatile("add%z0 %1, %0" : "+m"(foo) : "er"(23));
    asm volatile("mov%z0 %1, %0" : "=r"(foo) : "er"(-23));
    asm volatile("add%z0 %1, %0" : "+r"(foo) : "er"(23));
    asm volatile("pop%z0 %0" : "=m"(foo));
    asm volatile("pop%z0 %0" : "=r"(foo));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar4>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffe9,(%rsp)
  addq   $0x17,(%rsp)
  mov    $0xffffffffffffffe9,%rax
  add    $0x17,%rax
  pop    (%rsp)
  pop    %rax
  mov    %rax,(%rsp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar4() {
  if (sizeof(void *) == sizeof(long long)) {
    long long foo;
    asm volatile("mov%z0 %1, %0" : "=m"(foo) : "er"(-23));
    asm volatile("add%z0 %1, %0" : "+m"(foo) : "er"(23));
    asm volatile("mov%z0 %1, %0" : "=r"(foo) : "er"(-23));
    asm volatile("add%z0 %1, %0" : "+r"(foo) : "er"(23));
    asm volatile("pop%z0 %0" : "=m"(foo));
    asm volatile("pop%z0 %0" : "=r"(foo));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ic_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L14
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L19
L14:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L22
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L19
L22:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string
name: extract_symbolic_data
arguments: label: D14
data_type: string

tool: D2: ic_strdup: ch was null

tool: D14: ic_strdup: call to calloc failed

assistant: ```c
char *ic_strdup(char *ch) {
  char *buffer = 0;
  size_t len = 0;
  if (!ch) {
    puts("ic_strdup: ch was null");
    return 0;
  }
  len = strlen(ch);
  buffer = calloc(len + 1, sizeof(char));
  if (!buffer) {
    puts("ic_strdup: call to calloc failed");
    return 0;
  }
  strncpy(buffer, ch, len);
  buffer[len] = '\0';
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ic_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L21
  call   <strlen@plt>
  mov    %rax,%r12
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r12,1)
L16:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rbx
  jmp    L16
L6:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D0: ic_strdup: ch was null

tool: D4: ic_strdup: call to calloc failed

assistant: ```c
char *ic_strdup(char *ch) {
  char *buffer = 0;
  size_t len = 0;
  if (!ch) {
    puts("ic_strdup: ch was null");
    return 0;
  }
  len = strlen(ch);
  buffer = calloc(len + 1, sizeof(char));
  if (!buffer) {
    puts("ic_strdup: call to calloc failed");
    return 0;
  }
  strncpy(buffer, ch, len);
  buffer[len] = '\0';
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ic_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L18
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L34:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  lea    D1(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L34
  nopl   0x0(%rax)
L10:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L34
```

tool_calls: name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D7
type: string

tool: D1: ic_strdup: ch was null

tool: D7: ic_strdup: call to calloc failed

assistant: ```c
char *ic_strdup(char *ch) {
  char *buffer = 0;
  size_t len = 0;
  if (!ch) {
    puts("ic_strdup: ch was null");
    return 0;
  }
  len = strlen(ch);
  buffer = calloc(len + 1, sizeof(char));
  if (!buffer) {
    puts("ic_strdup: call to calloc failed");
    return 0;
  }
  strncpy(buffer, ch, len);
  buffer[len] = '\0';
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ic_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L27
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L38
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L32:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  lea    D4(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L32
  nopl   0x0(%rax)
L38:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L32
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string
name: read_data
arguments: tag: D18
type_infered: string

tool: D4: ic_strdup: ch was null

tool: D18: ic_strdup: call to calloc failed

assistant: ```c
char *ic_strdup(char *ch) {
  char *buffer = 0;
  size_t len = 0;
  if (!ch) {
    puts("ic_strdup: ch was null");
    return 0;
  }
  len = strlen(ch);
  buffer = calloc(len + 1, sizeof(char));
  if (!buffer) {
    puts("ic_strdup: call to calloc failed");
    return 0;
  }
  strncpy(buffer, ch, len);
  buffer[len] = '\0';
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fbtext_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L9
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <fbtext_putc@plt>
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void fbtext_puts(char *s) {
  while (*s) {
    fbtext_putc(*s++);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fbtext_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L5:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <fbtext_putc@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
L2:
  pop    %rbx
  ret
```

assistant: ```c
void fbtext_puts(char *s) {
  while (*s) {
    fbtext_putc(*s++);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fbtext_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L19
L0:
  call   <fbtext_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L0
L19:
  pop    %rbx
  ret
```

assistant: ```c
void fbtext_puts(char *s) {
  while (*s) {
    fbtext_putc(*s++);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fbtext_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L18:
  call   <fbtext_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L18
L7:
  pop    %rbx
  ret
```

assistant: ```c
void fbtext_puts(char *s) {
  while (*s) {
    fbtext_putc(*s++);
  }
}
```