ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<create_palette>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    %eax,%edx
  shl    $0x14,%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0xf,%rax
  jne    L32
  lea    0x3c(%rdi),%rdx
  mov    $0xf00000,%eax
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %eax,(%rdx)
  add    $0x1000,%eax
  add    $0x4,%rdx
  cmp    $0xf0f000,%eax
  jne    L30
  lea    0x78(%rdi),%rdx
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    %eax,(%rdx)
  sub    $0x100000,%eax
  add    $0x4,%rdx
  cmp    $0xf000,%eax
  jne    L20
  lea    0xb4(%rdi),%rdx
  nopl   0x0(%rax)
L56:
  mov    %eax,(%rdx)
  add    $0x10,%eax
  add    $0x4,%rdx
  cmp    $0xf0f0,%eax
  jne    L56
  lea    0xf0(%rdi),%rdx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %eax,(%rdx)
  sub    $0x1000,%eax
  add    $0x4,%rdx
  cmp    $0xf0,%eax
  jne    L8
  lea    0x12c(%rdi),%rdx
  nopl   0x0(%rax)
L43:
  mov    %eax,(%rdx)
  add    $0x100000,%eax
  add    $0x4,%rdx
  cmp    $0xf000f0,%eax
  jne    L43
  lea    0x168(%rdi),%rdx
  nopl   0x0(%rax)
L67:
  mov    %eax,(%rdx)
  add    $0x1000,%eax
  add    $0x4,%rdx
  cmp    $0xf0f0f0,%eax
  jne    L67
  mov    $0x69,%eax
  ret
```

assistant: ```c
int create_palette(uint32_t palet[]) {
  int i;
  int k = 0;
  int r = 0, g = 0, b = 0;
  for (i = 0; i < 15; i++) {
    palet[k++] = (r << 20) + (g << 12) + (b << 4);
    r++;
  }
  for (i = 0; i < 15; i++) {
    palet[k++] = (r << 20) + (g << 12) + (b << 4);
    g++;
  }
  for (i = 0; i < 15; i++) {
    palet[k++] = (r << 20) + (g << 12) + (b << 4);
    r--;
  }
  for (i = 0; i < 15; i++) {
    palet[k++] = (r << 20) + (g << 12) + (b << 4);
    b++;
  }
  for (i = 0; i < 15; i++) {
    palet[k++] = (r << 20) + (g << 12) + (b << 4);
    g--;
  }
  for (i = 0; i < 15; i++) {
    palet[k++] = (r << 20) + (g << 12) + (b << 4);
    r++;
  }
  for (i = 0; i < 15; i++) {
    palet[k++] = (r << 20) + (g << 12) + (b << 4);
    g++;
  }
  return k;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aeron_number_of_leading_zeroes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x20,%eax
  jmp    L1
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_clz@plt>
L1:
  leave
  ret
```

assistant: ```c
int aeron_number_of_leading_zeroes(int32_t value) {
  if (0 == value) {
    return 32;
  }
  return __builtin_clz(value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aeron_number_of_leading_zeroes>:
  endbr64
  mov    $0x20,%eax
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <__builtin_clz@plt>
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
int aeron_number_of_leading_zeroes(int32_t value) {
  if (0 == value) {
    return 32;
  }
  return __builtin_clz(value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aeron_number_of_leading_zeroes>:
  endbr64
  test   %rdi,%rdi
  je     L8
  jmp    1050 <__builtin_clz@plt>
  xchg   %ax,%ax
L8:
  mov    $0x20,%eax
  ret
```

assistant: ```c
int aeron_number_of_leading_zeroes(int32_t value) {
  if (0 == value) {
    return 32;
  }
  return __builtin_clz(value);
}
```
user: What is the c source code of the assembly code below?

```asm
<aeron_number_of_leading_zeroes>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <__builtin_clz@plt>
  xchg   %ax,%ax
L3:
  mov    $0x20,%eax
  ret
```

assistant: ```c
int aeron_number_of_leading_zeroes(int32_t value) {
  if (0 == value) {
    return 32;
  }
  return __builtin_clz(value);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<AtmegaCounterP__0__Counter__overflow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <CounterToLocalTimeC__1__Counter__overflow@plt>
  mov    $0x0,%eax
  call   <TransformCounterC__0__CounterFrom__overflow@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void AtmegaCounterP__0__Counter__overflow(void) {
  CounterToLocalTimeC__1__Counter__overflow();
  TransformCounterC__0__CounterFrom__overflow();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<AtmegaCounterP__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CounterToLocalTimeC__1__Counter__overflow@plt>
  mov    $0x0,%eax
  call   <TransformCounterC__0__CounterFrom__overflow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void AtmegaCounterP__0__Counter__overflow(void) {
  CounterToLocalTimeC__1__Counter__overflow();
  TransformCounterC__0__CounterFrom__overflow();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<AtmegaCounterP__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CounterToLocalTimeC__1__Counter__overflow@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <TransformCounterC__0__CounterFrom__overflow@plt>
```

assistant: ```c
void AtmegaCounterP__0__Counter__overflow(void) {
  CounterToLocalTimeC__1__Counter__overflow();
  TransformCounterC__0__CounterFrom__overflow();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AtmegaCounterP__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CounterToLocalTimeC__1__Counter__overflow@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <TransformCounterC__0__CounterFrom__overflow@plt>
```

assistant: ```c
void AtmegaCounterP__0__Counter__overflow(void) {
  CounterToLocalTimeC__1__Counter__overflow();
  TransformCounterC__0__CounterFrom__overflow();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memzero32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L0:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  subq   $0x4,-0x20(%rbp)
L9:
  cmpq   $0x3,-0x20(%rbp)
  ja     L0
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memzero32(void *dest, size_t n) {
  uint32_t z32 = 0U;
  do {
    uint32_t *p = (uint32_t *)dest;
    for (; n >= sizeof(uint32_t); n -= sizeof(uint32_t))
      *p++ = z32;
  } while (0);
  return (dest);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memzero32>:
  endbr64
  mov    %rdi,%rax
  cmp    $0x3,%rsi
  jbe    L2
  sub    $0x4,%rsi
  shr    $0x2,%rsi
  lea    0x4(%rdi,%rsi,4),%rcx
  mov    %rdi,%rdx
L4:
  add    $0x4,%rdx
  movl   $0x0,-0x4(%rdx)
  cmp    %rcx,%rdx
  jne    L4
L2:
  ret
```

assistant: ```c
void *memzero32(void *dest, size_t n) {
  uint32_t z32 = 0U;
  do {
    uint32_t *p = (uint32_t *)dest;
    for (; n >= sizeof(uint32_t); n -= sizeof(uint32_t))
      *p++ = z32;
  } while (0);
  return (dest);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memzero32>:
  endbr64
  cmp    $0x3,%rsi
  jbe    L0
  sub    $0x4,%rsi
  sub    $0x8,%rsp
  shr    $0x2,%rsi
  lea    0x4(,%rsi,4),%rdx
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memzero32(void *dest, size_t n) {
  uint32_t z32 = 0U;
  do {
    uint32_t *p = (uint32_t *)dest;
    for (; n >= sizeof(uint32_t); n -= sizeof(uint32_t))
      *p++ = z32;
  } while (0);
  return (dest);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memzero32>:
  endbr64
  cmp    $0x3,%rsi
  jbe    L5
  sub    $0x4,%rsi
  sub    $0x8,%rsp
  shr    $0x2,%rsi
  lea    0x4(,%rsi,4),%rdx
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memzero32(void *dest, size_t n) {
  uint32_t z32 = 0U;
  do {
    uint32_t *p = (uint32_t *)dest;
    for (; n >= sizeof(uint32_t); n -= sizeof(uint32_t))
      *p++ = z32;
  } while (0);
  return (dest);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fun_2D_sin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double fun_2D_sin(double x, double unused_0, double unused_1) {
  unused_0 = unused_0;
  unused_1 = unused_1;
  return sin(x);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fun_2D_sin>:
  endbr64
  sub    $0x8,%rsp
  call   <sin@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double fun_2D_sin(double x, double unused_0, double unused_1) {
  unused_0 = unused_0;
  unused_1 = unused_1;
  return sin(x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fun_2D_sin>:
  endbr64
  jmp    1050 <sin@plt>
```

assistant: ```c
double fun_2D_sin(double x, double unused_0, double unused_1) {
  unused_0 = unused_0;
  unused_1 = unused_1;
  return sin(x);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fun_2D_sin>:
  endbr64
  jmp    1050 <sin@plt>
```

assistant: ```c
double fun_2D_sin(double x, double unused_0, double unused_1) {
  unused_0 = unused_0;
  unused_1 = unused_1;
  return sin(x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x1,%eax
  jmp    L6
L0:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <fact>
  imul   -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
long fact(long n) {
  if (n == 0)
    return 1;
  return n * fact(n - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  jne    L7
  ret
L7:
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rdi),%rdi
  call   <fact>
  imul   %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long fact(long n) {
  if (n == 0)
    return 1;
  return n * fact(n - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L18
  xchg   %ax,%ax
L7:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  jne    L7
L18:
  ret
```

assistant: ```c
long fact(long n) {
  if (n == 0)
    return 1;
  return n * fact(n - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L8
  xchg   %ax,%ax
L12:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  jne    L12
L8:
  ret
```

assistant: ```c
long fact(long n) {
  if (n == 0)
    return 1;
  return n * fact(n - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L21
L31:
  movq   $0x0,-0x10(%rbp)
  jmp    L9
L14:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L14
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L21:
  leave
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *fresh;
  size_t i;
  if (!(fresh = (char *)malloc(sizeof(char) * (len + 1))))
    return (NULL);
  i = 0;
  while (i < len) {
    fresh[i] = s[i + start];
    i++;
  }
  fresh[i] = '\0';
  return (fresh);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_strsub>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%rbp
  lea    0x1(%rdx),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%r8
  test   %rbp,%rbp
  je     L29
  lea    (%rax,%rbp,1),%rdi
  mov    %rax,%rdx
  mov    %r12d,%r12d
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rsi
L17:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L17
L29:
  movb   $0x0,(%rax,%rbp,1)
L13:
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    $0x0,%r8d
  jmp    L13
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *fresh;
  size_t i;
  if (!(fresh = (char *)malloc(sizeof(char) * (len + 1))))
    return (NULL);
  i = 0;
  while (i < len) {
    fresh[i] = s[i + start];
    i++;
  }
  fresh[i] = '\0';
  return (fresh);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strsub>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rdx),%edi
  push   %rbx
  mov    %rdx,%rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L38
  test   %rbx,%rbx
  je     L9
  sub    %rax,%r12
  lea    (%rbx,%rax,1),%rdx
  mov    %rax,%rcx
  lea    0x0(%rbp,%r12,1),%rdi
  nopw   0x0(%rax,%rax,1)
L20:
  movzbl (%rdi,%rcx,1),%esi
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L20
L30:
  movb   $0x0,(%rcx)
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    %rax,%rcx
  jmp    L30
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *fresh;
  size_t i;
  if (!(fresh = (char *)malloc(sizeof(char) * (len + 1))))
    return (NULL);
  i = 0;
  while (i < len) {
    fresh[i] = s[i + start];
    i++;
  }
  fresh[i] = '\0';
  return (fresh);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strsub>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rdx),%edi
  push   %rbx
  mov    %rdx,%rbx
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L114
  test   %rbx,%rbx
  je     L49
  mov    %r12d,%edx
  mov    %r8,%rcx
  lea    -0x1(%rbx),%rax
  lea    0x1(%rbp,%rdx,1),%rsi
  sub    %rsi,%rcx
  cmp    $0xe,%rcx
  jbe    L111
  cmp    $0x6,%rax
  jbe    L111
  cmp    $0xe,%rax
  jbe    L27
  mov    %rbx,%rsi
  mov    %rdx,%rcx
  mov    %r8,%rax
  and    $0xfffffffffffffff0,%rsi
  sub    %r8,%rcx
  add    %r8,%rsi
  add    %rbp,%rcx
  nopl   0x0(%rax)
L101:
  movdqu (%rax,%rcx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L101
  mov    %rbx,%rax
  and    $0xfffffffffffffff0,%rax
  test   $0xf,%bl
  je     L195
  mov    %rbx,%rcx
  sub    %rax,%rcx
  lea    -0x1(%rcx),%rsi
  cmp    $0x6,%rsi
  jbe    L50
L157:
  add    %rbp,%rdx
  mov    (%rdx,%rax,1),%rsi
  mov    %rsi,(%r8,%rax,1)
  mov    %rcx,%rsi
  and    $0xfffffffffffffff8,%rsi
  add    %rsi,%rax
  cmp    %rsi,%rcx
  je     L195
L82:
  movzbl (%rdx,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  lea    0x1(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L195
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x1(%r8,%rax,1)
  lea    0x2(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L195
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x2(%r8,%rax,1)
  lea    0x3(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L195
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x3(%r8,%rax,1)
  lea    0x4(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L195
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x4(%r8,%rax,1)
  lea    0x5(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L195
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x5(%r8,%rax,1)
  lea    0x6(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L195
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,0x6(%r8,%rax,1)
L195:
  add    %r8,%rbx
L123:
  movb   $0x0,(%rbx)
L114:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L111:
  sub    %r8,%rdx
  add    %r8,%rbx
  mov    %r8,%rax
  add    %rbp,%rdx
  nopl   0x0(%rax)
L165:
  movzbl (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    %rbx,%rax
  jne    L165
  jmp    L123
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %rax,%rbx
  jmp    L123
L27:
  mov    %rbx,%rcx
  xor    %eax,%eax
  jmp    L157
L50:
  add    %rbp,%rdx
  jmp    L82
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *fresh;
  size_t i;
  if (!(fresh = (char *)malloc(sizeof(char) * (len + 1))))
    return (NULL);
  i = 0;
  while (i < len) {
    fresh[i] = s[i + start];
    i++;
  }
  fresh[i] = '\0';
  return (fresh);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_column>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x9,-0x4(%rbp)
  jmp    L22
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L22
  mov    $0x1,%eax
  jmp    L28
L22:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L13
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
bool check_column(int sudoku[9][9], int h, int k) {
  int p;
  p = 9;
  while (p--) {
    if (sudoku[p][h] == k)
      return true;
  }
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_column>:
  endbr64
  movslq %esi,%rsi
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%rax
  lea    -0x144(%rdi,%rsi,1),%rcx
L0:
  cmp    %edx,0x120(%rax)
  je     L15
  sub    $0x24,%rax
  cmp    %rcx,%rax
  jne    L0
  mov    $0x0,%eax
  ret
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool check_column(int sudoku[9][9], int h, int k) {
  int p;
  p = 9;
  while (p--) {
    if (sudoku[p][h] == k)
      return true;
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_column>:
  endbr64
  movslq %esi,%rsi
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%rax
  lea    -0x144(%rdi,%rsi,1),%rcx
  nopw   0x0(%rax,%rax,1)
L3:
  cmp    %edx,0x120(%rax)
  je     L12
  sub    $0x24,%rax
  cmp    %rcx,%rax
  jne    L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool check_column(int sudoku[9][9], int h, int k) {
  int p;
  p = 9;
  while (p--) {
    if (sudoku[p][h] == k)
      return true;
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_column>:
  endbr64
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rax
  cmp    0x120(%rdi,%rsi,4),%edx
  je     L66
  cmp    0xfc(%rdi,%rax,1),%edx
  je     L66
  cmp    0xd8(%rdi,%rax,1),%edx
  je     L66
  cmp    0xb4(%rdi,%rax,1),%edx
  je     L66
  cmp    0x90(%rdi,%rax,1),%edx
  je     L66
  cmp    0x6c(%rdi,%rax,1),%edx
  je     L66
  cmp    0x48(%rdi,%rax,1),%edx
  je     L66
  cmp    0x24(%rdi,%rax,1),%edx
  je     L66
  xor    %eax,%eax
  cmp    %edx,(%rdi,%rsi,4)
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool check_column(int sudoku[9][9], int h, int k) {
  int p;
  p = 9;
  while (p--) {
    if (sudoku[p][h] == k)
      return true;
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L13
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L13:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int c;
  while (c != EOF) {
    c = getchar();
    putchar(c);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    D3(%rip),%rax
  cmpl   $0x0,(%rax)
  je     L15
  push   %rbx
L18:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <putchar@plt>
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L18
  pop    %rbx
  ret
L15:
  ret
```

assistant: ```c
void main() {
  int c;
  while (c != EOF) {
    c = getchar();
    putchar(c);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D1(%rip),%rbp
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  je     L15
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <putchar@plt>
  cmp    %ebx,0x0(%rbp)
  jne    L17
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int c;
  while (c != EOF) {
    c = getchar();
    putchar(c);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%rbp
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  je     L16
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <putchar@plt>
  cmp    %ebx,0x0(%rbp)
  jne    L6
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int c;
  while (c != EOF) {
    c = getchar();
    putchar(c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L10:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void printArray(int *arr, int len) {
  do {
    if (0)
      fprintf(stderr, "[%d", arr[0]);
  } while (0);
  for (int i = 1; i < len; i++) {
    do {
      if (0)
        fprintf(stderr, "\t%d", arr[i]);
    } while (0);
  }
  do {
    if (0)
      fprintf(stderr, "]\n");
  } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printArray>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  mov    $0x1,%eax
L6:
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L6
L15:
  ret
```

assistant: ```c
void printArray(int *arr, int len) {
  do {
    if (0)
      fprintf(stderr, "[%d", arr[0]);
  } while (0);
  for (int i = 1; i < len; i++) {
    do {
      if (0)
        fprintf(stderr, "\t%d", arr[i]);
    } while (0);
  }
  do {
    if (0)
      fprintf(stderr, "]\n");
  } while (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<printArray>:
  endbr64
  ret
```

assistant: ```c
void printArray(int *arr, int len) {
  do {
    if (0)
      fprintf(stderr, "[%d", arr[0]);
  } while (0);
  for (int i = 1; i < len; i++) {
    do {
      if (0)
        fprintf(stderr, "\t%d", arr[i]);
    } while (0);
  }
  do {
    if (0)
      fprintf(stderr, "]\n");
  } while (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<printArray>:
  endbr64
  ret
```

assistant: ```c
void printArray(int *arr, int len) {
  do {
    if (0)
      fprintf(stderr, "[%d", arr[0]);
  } while (0);
  for (int i = 1; i < len; i++) {
    do {
      if (0)
        fprintf(stderr, "\t%d", arr[i]);
    } while (0);
  }
  do {
    if (0)
      fprintf(stderr, "]\n");
  } while (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strprefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L31
  mov    $0x0,%eax
  jmp    L23
L31:
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L33
  mov    $0x0,%eax
  jmp    L23
L33:
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L18
  mov    $0x1,%eax
L23:
  leave
  ret
```

assistant: ```c
int strprefix(const char *pre, const char *s) {
  int n = strlen(pre);
  if (strlen(s) < n)
    return 0;
  for (int i = 0; i < n; i++)
    if (pre[i] != s[i])
      return 0;
  return 1;
}
```