ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fprop_compute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rdx)
  mov    %rdx,(%rsp)
  mov    %r8d,0xc(%rsp)
  test   %r8d,%r8d
  jle    L18
  mov    %rcx,%r15
  lea    -0x1(%r8),%eax
  lea    0x8(%rdx),%r12
  mov    %rsi,%r13
  add    $0x4,%r15
  lea    0x8(%rsi,%rax,8),%rbp
  xchg   %ax,%ax
L38:
  mov    (%r15),%eax
  xor    %r14d,%r14d
  mov    $0x1,%ebx
  test   %eax,%eax
  jle    L28
  nop
L3:
  mov    0x0(%r13),%rax
  movslq -0x4(%r15),%rcx
  mov    (%rax,%r14,8),%rdx
  movss  (%rdx,%rcx,4),%xmm0
  test   %ecx,%ecx
  jle    L43
  mov    -0x8(%r12),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L54:
  movss  (%rsi,%rax,4),%xmm1
  mulss  (%rdx,%rax,4),%xmm1
  add    $0x1,%rax
  addss  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L54
L43:
  xorps  D0(%rip),%xmm0
  call   <expf@plt>
  pxor   %xmm0,%xmm0
  mov    (%r12),%rsi
  lea    0x1(%rax),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%rsi,%r14,4)
  add    $0x1,%r14
  cmp    %r14d,(%r15)
  jg     L3
L28:
  add    $0x8,%r13
  add    $0x4,%r15
  add    $0x8,%r12
  cmp    %r13,%rbp
  jne    L38
L18:
  movslq 0xc(%rsp),%r12
  mov    (%rsp),%rax
  mov    (%rax,%r12,8),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: byte[16]

tool: {"D0": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float *fprop_compute(float *vector, float ***weights, float **res, int *layers, int layers_count) {
  res[0] = vector;
  int l, n, w;
  for (l = 0; l < layers_count; l++) {
#pragma omp parallel for private(n, w)
    for (n = 0; n < layers[l + 1]; n++) {
      float sum = 0;
      sum = weights[l][n][layers[l]];
      for (w = 0; w < layers[l]; w++) {
        sum += res[l][w] * weights[l][n][w];
      }
      res[l + 1][n] = 1 / (1 + expf(-sum));
    }
  }
  return res[layers_count];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fprop_compute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rdx)
  mov    %rdx,(%rsp)
  mov    %r8d,0xc(%rsp)
  test   %r8d,%r8d
  jle    L4
  mov    %r8d,%eax
  mov    %rcx,%r15
  mov    %rdx,%r13
  mov    %rsi,%r12
  sub    $0x1,%eax
  add    $0x4,%r15
  mov    $0x1,%ebx
  lea    0x8(%rdx,%rax,8),%rbp
  nopl   0x0(%rax)
L78:
  mov    (%r15),%eax
  xor    %r14d,%r14d
  test   %eax,%eax
  jle    L29
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    (%r12),%rax
  mov    (%rax,%r14,8),%rdi
  movslq -0x4(%r15),%rax
  movss  (%rdi,%rax,4),%xmm0
  mov    %rax,%r8
  test   %eax,%eax
  jle    L77
  lea    -0x1(%rax),%eax
  mov    0x0(%r13),%r9
  cmp    $0x2,%eax
  jbe    L38
  mov    %r8d,%edx
  xor    %eax,%eax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  nopl   0x0(%rax,%rax,1)
L100:
  movups (%rdi,%rax,1),%xmm1
  movups (%r9,%rax,1),%xmm3
  add    $0x10,%rax
  mulps  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm0,%xmm2
  movaps %xmm1,%xmm0
  unpckhps %xmm1,%xmm0
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L100
  mov    %r8d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r8b
  je     L77
L42:
  movslq %eax,%r10
  movss  (%r9,%r10,4),%xmm1
  mulss  (%rdi,%r10,4),%xmm1
  lea    0x0(,%r10,4),%rdx
  lea    0x1(%rax),%r10d
  addss  %xmm1,%xmm0
  cmp    %r10d,%r8d
  jle    L77
  movss  0x4(%rdi,%rdx,1),%xmm1
  mulss  0x4(%r9,%rdx,1),%xmm1
  add    $0x2,%eax
  addss  %xmm1,%xmm0
  cmp    %eax,%r8d
  jle    L77
  movss  0x8(%rdi,%rdx,1),%xmm1
  mulss  0x8(%r9,%rdx,1),%xmm1
  addss  %xmm1,%xmm0
L77:
  xorps  D2(%rip),%xmm0
  call   <expf@plt>
  pxor   %xmm0,%xmm0
  mov    0x8(%r13),%r8
  lea    0x1(%rax),%edi
  mov    %ebx,%eax
  cltd
  idiv   %edi
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%r8,%r14,4)
  add    $0x1,%r14
  cmp    %r14d,(%r15)
  jg     L54
L29:
  add    $0x8,%r13
  add    $0x8,%r12
  add    $0x4,%r15
  cmp    %rbp,%r13
  jne    L78
L4:
  movslq 0xc(%rsp),%r12
  mov    (%rsp),%rax
  mov    (%rax,%r12,8),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  xor    %eax,%eax
  jmp    L42
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float *fprop_compute(float *vector, float ***weights, float **res, int *layers, int layers_count) {
  res[0] = vector;
  int l, n, w;
  for (l = 0; l < layers_count; l++) {
#pragma omp parallel for private(n, w)
    for (n = 0; n < layers[l + 1]; n++) {
      float sum = 0;
      sum = weights[l][n][layers[l]];
      for (w = 0; w < layers[l]; w++) {
        sum += res[l][w] * weights[l][n][w];
      }
      res[l + 1][n] = 1 / (1 + expf(-sum));
    }
  }
  return res[layers_count];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L19
  mov    -0x4(%rbp),%eax
  or     $0x20,%eax
  jmp    L12
L19:
  mov    -0x4(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int tolower(int c) {
  if (isupper(c)) {
    return (c | (0x20));
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tolower>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isupper@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  or     $0x20,%eax
  test   %rdx,%rdx
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int tolower(int c) {
  if (isupper(c)) {
    return (c | (0x20));
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tolower>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <isupper@plt>
  mov    %rax,%r8
  mov    %r12d,%eax
  or     $0x20,%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int tolower(int c) {
  if (isupper(c)) {
    return (c | (0x20));
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tolower>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <isupper@plt>
  mov    %rax,%r8
  mov    %r12d,%eax
  or     $0x20,%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int tolower(int c) {
  if (isupper(c)) {
    return (c | (0x20));
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<islegal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1f,-0x4(%rbp)
  jle    L54
  cmpl   $0x7e,-0x4(%rbp)
  jg     L54
  mov    $0x1,%eax
  jmp    L95
L54:
  cmpl   $0x20,-0x4(%rbp)
  jne    L61
  mov    $0x1,%eax
  jmp    L95
L61:
  cmpl   $0x9,-0x4(%rbp)
  jne    L10
  mov    $0x1,%eax
  jmp    L95
L10:
  cmpl   $0xa,-0x4(%rbp)
  jne    L93
  mov    $0x1,%eax
  jmp    L95
L93:
  cmpl   $0x4,-0x4(%rbp)
  jne    L71
  mov    $0x1,%eax
  jmp    L95
L71:
  mov    $0x0,%eax
L95:
  pop    %rbp
  ret
```

assistant: ```c
int islegal(int c) {
  if (c >= ' ') {
    if (c <= '~') {
      return (1);
    }
  }
  if (c == ' ')
    return (1);
  if (c == '\t')
    return (1);
  if (c == '\n')
    return (1);
  if (c == 4)
    return (1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<islegal>:
  endbr64
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%eax
  jbe    L4
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  setbe  %al
  cmp    $0x4,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int islegal(int c) {
  if (c >= ' ') {
    if (c <= '~') {
      return (1);
    }
  }
  if (c == ' ')
    return (1);
  if (c == '\t')
    return (1);
  if (c == '\n')
    return (1);
  if (c == 4)
    return (1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<islegal>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1f,%edi
  jle    L37
  cmp    $0x7e,%edi
  jle    L8
L19:
  cmp    $0xa,%edi
  sete   %al
  cmp    $0x4,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L24:
  ret
  nopl   (%rax)
L37:
  cmp    $0x9,%edi
  jne    L19
  jmp    L24
  nop
L8:
  ret
```

assistant: ```c
int islegal(int c) {
  if (c >= ' ') {
    if (c <= '~') {
      return (1);
    }
  }
  if (c == ' ')
    return (1);
  if (c == '\t')
    return (1);
  if (c == '\n')
    return (1);
  if (c == 4)
    return (1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<islegal>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1f,%edi
  jle    L31
  cmp    $0x7e,%edi
  jle    L36
L17:
  cmp    $0xa,%edi
  sete   %al
  cmp    $0x4,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L4:
  ret
  nopl   (%rax)
L31:
  cmp    $0x9,%edi
  jne    L17
  jmp    L4
  nop
L36:
  ret
```

assistant: ```c
int islegal(int c) {
  if (c >= ' ') {
    if (c <= '~') {
      return (1);
    }
  }
  if (c == ' ')
    return (1);
  if (c == '\t')
    return (1);
  if (c == '\n')
    return (1);
  if (c == 4)
    return (1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unaddr_test4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: testing access after free


assistant: ```c
int unaddr_test4(int *val_p) {
  int x = 1;
  printf("testing access after free\n");
  return (*val_p & x) ? 1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unaddr_test4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  and    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string

tool: D6: testing access after free


assistant: ```c
int unaddr_test4(int *val_p) {
  int x = 1;
  printf("testing access after free\n");
  return (*val_p & x) ? 1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unaddr_test4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  pop    %rbx
  and    $0x1,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: testing access after free


assistant: ```c
int unaddr_test4(int *val_p) {
  int x = 1;
  printf("testing access after free\n");
  return (*val_p & x) ? 1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unaddr_test4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  pop    %rbx
  and    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: testing access after free


assistant: ```c
int unaddr_test4(int *val_p) {
  int x = 1;
  printf("testing access after free\n");
  return (*val_p & x) ? 1 : 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<funcHashExpressions_DEFAULT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1505,-0x8(%rbp)
  jmp    L19
L16:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rcx,%rax
  add    %rax,-0x8(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long funcHashExpressions_DEFAULT(unsigned char *key) {
  unsigned long hashval = 5381;
  while (*key) {
    hashval += (hashval << 5) + (*key++);
  }
  return hashval;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<funcHashExpressions_DEFAULT>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  mov    $0x1505,%ecx
L12:
  add    $0x1,%rdi
  mov    %rcx,%rdx
  shl    $0x5,%rdx
  movzbl %al,%eax
  add    %rdx,%rax
  add    %rax,%rcx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L12
L20:
  mov    %rcx,%rax
  ret
L24:
  mov    $0x1505,%ecx
  jmp    L20
```

assistant: ```c
unsigned long funcHashExpressions_DEFAULT(unsigned char *key) {
  unsigned long hashval = 5381;
  while (*key) {
    hashval += (hashval << 5) + (*key++);
  }
  return hashval;
}
```
user: What is the c source code of the assembly code below?

```asm
<funcHashExpressions_DEFAULT>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x1505,%r8d
  test   %al,%al
  je     L8
  nopl   0x0(%rax)
L14:
  mov    %r8,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  add    %rax,%r8
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L14
L8:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long funcHashExpressions_DEFAULT(unsigned char *key) {
  unsigned long hashval = 5381;
  while (*key) {
    hashval += (hashval << 5) + (*key++);
  }
  return hashval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<funcHashExpressions_DEFAULT>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x1505,%r8d
  test   %al,%al
  je     L8
  nopl   0x0(%rax)
L0:
  mov    %r8,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  add    %rax,%r8
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L0
L8:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long funcHashExpressions_DEFAULT(unsigned char *key) {
  unsigned long hashval = 5381;
  while (*key) {
    hashval += (hashval << 5) + (*key++);
  }
  return hashval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Pthread_cond_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pthread_cond_wait@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <Sys_failure@plt>
L8:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: pthread_cond_wait

assistant: ```c
void Pthread_cond_wait(pthread_cond_t *cond, pthread_mutex_t *mutex) {
  int retval;
  assert(cond != NULL);
  assert(mutex != NULL);
  retval = pthread_cond_wait(cond, mutex);
  if (retval != 0)
    Sys_failure("pthread_cond_wait");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Pthread_cond_wait>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <pthread_cond_wait@plt>
  test   %eax,%eax
  jne    L6
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  lea    D9(%rip),%rdi
  call   <Sys_failure@plt>
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D9: pthread_cond_wait

assistant: ```c
void Pthread_cond_wait(pthread_cond_t *cond, pthread_mutex_t *mutex) {
  int retval;
  assert(cond != NULL);
  assert(mutex != NULL);
  retval = pthread_cond_wait(cond, mutex);
  if (retval != 0)
    Sys_failure("pthread_cond_wait");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Pthread_cond_wait>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pthread_cond_wait@plt>
  test   %eax,%eax
  jne    L7
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <Sys_failure@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0: pthread_cond_wait

assistant: ```c
void Pthread_cond_wait(pthread_cond_t *cond, pthread_mutex_t *mutex) {
  int retval;
  assert(cond != NULL);
  assert(mutex != NULL);
  retval = pthread_cond_wait(cond, mutex);
  if (retval != 0)
    Sys_failure("pthread_cond_wait");
}
```
user: Translate the below assembly code into C programming language:

```asm
<Pthread_cond_wait>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pthread_cond_wait@plt>
  test   %eax,%eax
  jne    L8
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <Sys_failure@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: pthread_cond_wait

assistant: ```c
void Pthread_cond_wait(pthread_cond_t *cond, pthread_mutex_t *mutex) {
  int retval;
  assert(cond != NULL);
  assert(mutex != NULL);
  retval = pthread_cond_wait(cond, mutex);
  if (retval != 0)
    Sys_failure("pthread_cond_wait");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<s_cat2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <alloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <dealloc@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <dealloc@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *s_cat2(char *a, char *b) {
  char *ret = (char *)alloc(strlen(a) + strlen(b) + 1);
  strcpy(ret, a);
  strcat(ret, b);
  dealloc(a);
  dealloc(b);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<s_cat2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <alloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <dealloc@plt>
  mov    %rbp,%rdi
  call   <dealloc@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *s_cat2(char *a, char *b) {
  char *ret = (char *)alloc(strlen(a) + strlen(b) + 1);
  strcpy(ret, a);
  strcat(ret, b);
  dealloc(a);
  dealloc(b);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s_cat2>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rdi
  call   <alloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r13,%rdi
  call   <dealloc@plt>
  mov    %rbp,%rdi
  call   <dealloc@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *s_cat2(char *a, char *b) {
  char *ret = (char *)alloc(strlen(a) + strlen(b) + 1);
  strcpy(ret, a);
  strcat(ret, b);
  dealloc(a);
  dealloc(b);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<s_cat2>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rdi
  call   <alloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r13,%rdi
  call   <dealloc@plt>
  mov    %rbp,%rdi
  call   <dealloc@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *s_cat2(char *a, char *b) {
  char *ret = (char *)alloc(strlen(a) + strlen(b) + 1);
  strcpy(ret, a);
  strcat(ret, b);
  dealloc(a);
  dealloc(b);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inputGraph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L3:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  movl   $0x1,(%rdx,%rax,4)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  movl   $0x1,(%rdx,%rax,4)
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L3
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D48
data_type: string
name: retrieve_data
arguments: data_label: D58
data_type: string
name: retrieve_data
arguments: data_label: D49
data_type: string
name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D66
data_type: string
name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D48: 
	Inputting Edges: 

tool: D58: 	How many edges do you wish to add? ans = 

tool: D49: %d

tool: D25: 	%d.
	Node 1: 

tool: D66: 	Node 2: 

tool: D3: 	Edge (%d,%d) added.



assistant: ```c
void inputGraph(int g[5][5]) {
  printf("\n\tInputting Edges: \n");
  printf("\tHow many edges do you wish to add? ans = ");
  int numberOfEdges = 0;
  scanf("%d", &numberOfEdges);
  int i;
  int a, b;
  for (i = 0; i < numberOfEdges; i++) {
    printf("\t%d.\n\tNode 1: ", i);
    scanf("%d", &a);
    printf("\tNode 2: ");
    scanf("%d", &b);
    g[a][b] = 1;
    g[b][a] = 1;
    printf("\tEdge (%d,%d) added.\n\n", a, b);
  }
}
```