ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L10
  mov    D58(%rip),%ebx
  mov    %ebx,0xc(%rsp)
  lea    0x14(%rsp),%r12
  lea    D0(%rip),%rbp
L37:
  movss  0xc(%rsp),%xmm1
  addss  0x14(%rsp),%xmm1
  movss  %xmm1,0xc(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movd   %ebx,%xmm2
  addss  D10(%rip),%xmm2
  movd   %xmm2,%ebx
  test   %eax,%eax
  jne    L37
L18:
  movss  0xc(%rsp),%xmm0
  movd   %ebx,%xmm3
  divss  %xmm3,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D41(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    D58(%rip),%ebx
  mov    %ebx,0xc(%rsp)
  jmp    L18
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D55
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D58
datatype: f32
name: parse_data
arguments: data_tag: D10
datatype: byte[4]
name: parse_data
arguments: data_tag: D41
datatype: string

tool: D55: Rentrez vos nombres :

tool: D0: %f

tool: D58: 0

tool: {"D10": [0x00,0x00,0x80,0x3f]}

tool: D41: La moyenne est de %f


assistant: ```c
int main(int argc, char *argv[], char *env[]) {
  float M = 0, x, i = 0;
  printf("Rentrez vos nombres :\n");
  int continuer = scanf("%f", &x);
  while (continuer) {
    M += x;
    continuer = scanf("%f", &x);
    i++;
  }
  printf("La moyenne est de %f\n", (M / i));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbx
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  test   %eax,%eax
  je     L9
  nopl   0x0(%rax,%rax,1)
L1:
  addss  0x14(%rsp),%xmm0
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  test   %eax,%eax
  addss  D26(%rip),%xmm1
  jne    L1
L9:
  divss  %xmm1,%xmm0
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string
name: parse_data
arguments: data_label: D26
type_guessed: byte[4]
name: parse_data
arguments: data_label: D36
type_guessed: string

tool: D25: Rentrez vos nombres :

tool: D2: %f

tool: {"D26": [0x00,0x00,0x80,0x3f]}

tool: D36: La moyenne est de %f


assistant: ```c
int main(int argc, char *argv[], char *env[]) {
  float M = 0, x, i = 0;
  printf("Rentrez vos nombres :\n");
  int continuer = scanf("%f", &x);
  while (continuer) {
    M += x;
    continuer = scanf("%f", &x);
    i++;
  }
  printf("La moyenne est de %f\n", (M / i));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbx
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  test   %eax,%eax
  je     L19
  nopl   0x0(%rax,%rax,1)
L8:
  addss  0x14(%rsp),%xmm0
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  test   %eax,%eax
  addss  D32(%rip),%xmm1
  jne    L8
L19:
  divss  %xmm1,%xmm0
  lea    D38(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D32
data_type: byte[4]
name: retrieve_data
arguments: label: D38
data_type: string

tool: D14: Rentrez vos nombres :

tool: D7: %f

tool: {"D32": [0x00,0x00,0x80,0x3f]}

tool: D38: La moyenne est de %f


assistant: ```c
int main(int argc, char *argv[], char *env[]) {
  float M = 0, x, i = 0;
  printf("Rentrez vos nombres :\n");
  int continuer = scanf("%f", &x);
  while (continuer) {
    M += x;
    continuer = scanf("%f", &x);
    i++;
  }
  printf("La moyenne est de %f\n", (M / i));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D41
data_type: string
name: read_data
arguments: label: D9
data_type: string
name: read_data
arguments: label: D20
data_type: string
name: read_data
arguments: label: D25
data_type: string
name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D45
data_type: string
name: read_data
arguments: label: D81
data_type: string
name: read_data
arguments: label: D72
data_type: string
name: read_data
arguments: label: D26
data_type: string

tool: D41: Usage: %s [-h] [-b <script.au> [<arguments>]] [{-t|-o} <nmrfile> [<access>]]


tool: D9: Options:

tool: D20:   -h: help. Print this message.

tool: D25:   -b: background mode. Process the scriptfile <script.au> as a batch job.

tool: D14:       Everything that follows this command goes as arguments to <script.au>.

tool: D45:           Example: %s -b prepa_bruker.au -i data/1/ -o noesy.p


tool: D81:   <nmrfile>: load this file on opening program.

tool: D72:       Access directions may follow the file name.

tool: D26:           Example: %s noesy.p 2


assistant: ```c
void print_usage(int argc, char *argv[]) {
  printf("\n");
  printf("Usage: %s [-h] [-b <script.au> [<arguments>]] [{-t|-o} <nmrfile> [<access>]]\n", argv[0]);
  printf("\n");
  printf("Options:\n");
  printf("  -h: help. Print this message.\n");
  printf("  -b: background mode. Process the scriptfile <script.au> as a batch job.\n");
  printf("      Everything that follows this command goes as arguments to <script.au>.\n");
  printf("          Example: %s -b prepa_bruker.au -i data/1/ -o noesy.p\n", argv[0]);
  printf("  <nmrfile>: load this file on opening program.\n");
  printf("      Access directions may follow the file name.\n");
  printf("          Example: %s noesy.p 2\n", argv[0]);
  printf("\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_usage>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%rbx),%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D44(%rip),%rdi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D85(%rip),%rdi
  call   <puts@plt>
  lea    D60(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  lea    D65(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D82(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D44
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D85
type_infered: string
name: parse_data
arguments: tag: D60
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: string
name: parse_data
arguments: tag: D63
type_infered: string
name: parse_data
arguments: tag: D65
type_infered: string
name: parse_data
arguments: tag: D82
type_infered: string

tool: D25: Usage: %s [-h] [-b <script.au> [<arguments>]] [{-t|-o} <nmrfile> [<access>]]


tool: D44: Options:

tool: D5:   -h: help. Print this message.

tool: D85:   -b: background mode. Process the scriptfile <script.au> as a batch job.

tool: D60:       Everything that follows this command goes as arguments to <script.au>.

tool: D29:           Example: %s -b prepa_bruker.au -i data/1/ -o noesy.p


tool: D63:   <nmrfile>: load this file on opening program.

tool: D65:       Access directions may follow the file name.

tool: D82:           Example: %s noesy.p 2


assistant: ```c
void print_usage(int argc, char *argv[]) {
  printf("\n");
  printf("Usage: %s [-h] [-b <script.au> [<arguments>]] [{-t|-o} <nmrfile> [<access>]]\n", argv[0]);
  printf("\n");
  printf("Options:\n");
  printf("  -h: help. Print this message.\n");
  printf("  -b: background mode. Process the scriptfile <script.au> as a batch job.\n");
  printf("      Everything that follows this command goes as arguments to <script.au>.\n");
  printf("          Example: %s -b prepa_bruker.au -i data/1/ -o noesy.p\n", argv[0]);
  printf("  <nmrfile>: load this file on opening program.\n");
  printf("      Access directions may follow the file name.\n");
  printf("          Example: %s noesy.p 2\n", argv[0]);
  printf("\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_usage>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  mov    %rsi,%rbx
  call   <putchar@plt>
  mov    (%rbx),%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D53(%rip),%rdi
  call   <puts@plt>
  lea    D74(%rip),%rdi
  call   <puts@plt>
  lea    D57(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D87(%rip),%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D81(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %edi,%edi
  pop    %rbx
  jmp    10b0 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D39
datatype: string
name: disassemble_data
arguments: data_tag: D53
datatype: string
name: disassemble_data
arguments: data_tag: D74
datatype: string
name: disassemble_data
arguments: data_tag: D57
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D25
datatype: string
name: disassemble_data
arguments: data_tag: D87
datatype: string
name: disassemble_data
arguments: data_tag: D28
datatype: string
name: disassemble_data
arguments: data_tag: D81
datatype: string

tool: D39: Usage: %s [-h] [-b <script.au> [<arguments>]] [{-t|-o} <nmrfile> [<access>]]


tool: D53: Options:

tool: D74:   -h: help. Print this message.

tool: D57:   -b: background mode. Process the scriptfile <script.au> as a batch job.

tool: D26:       Everything that follows this command goes as arguments to <script.au>.

tool: D25:           Example: %s -b prepa_bruker.au -i data/1/ -o noesy.p


tool: D87:   <nmrfile>: load this file on opening program.

tool: D28:       Access directions may follow the file name.

tool: D81:           Example: %s noesy.p 2


assistant: ```c
void print_usage(int argc, char *argv[]) {
  printf("\n");
  printf("Usage: %s [-h] [-b <script.au> [<arguments>]] [{-t|-o} <nmrfile> [<access>]]\n", argv[0]);
  printf("\n");
  printf("Options:\n");
  printf("  -h: help. Print this message.\n");
  printf("  -b: background mode. Process the scriptfile <script.au> as a batch job.\n");
  printf("      Everything that follows this command goes as arguments to <script.au>.\n");
  printf("          Example: %s -b prepa_bruker.au -i data/1/ -o noesy.p\n", argv[0]);
  printf("  <nmrfile>: load this file on opening program.\n");
  printf("      Access directions may follow the file name.\n");
  printf("          Example: %s noesy.p 2\n", argv[0]);
  printf("\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  mov    %rsi,%rbx
  call   <putchar@plt>
  mov    (%rbx),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D74(%rip),%rdi
  call   <puts@plt>
  lea    D43(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    D83(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D82(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %edi,%edi
  pop    %rbx
  jmp    10b0 <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D74
datatype: string
name: unpack_data
arguments: label: D43
datatype: string
name: unpack_data
arguments: label: D34
datatype: string
name: unpack_data
arguments: label: D83
datatype: string
name: unpack_data
arguments: label: D42
datatype: string
name: unpack_data
arguments: label: D40
datatype: string
name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D82
datatype: string

tool: D1: Usage: %s [-h] [-b <script.au> [<arguments>]] [{-t|-o} <nmrfile> [<access>]]


tool: D74: Options:

tool: D43:   -h: help. Print this message.

tool: D34:   -b: background mode. Process the scriptfile <script.au> as a batch job.

tool: D83:       Everything that follows this command goes as arguments to <script.au>.

tool: D42:           Example: %s -b prepa_bruker.au -i data/1/ -o noesy.p


tool: D40:   <nmrfile>: load this file on opening program.

tool: D19:       Access directions may follow the file name.

tool: D82:           Example: %s noesy.p 2


assistant: ```c
void print_usage(int argc, char *argv[]) {
  printf("\n");
  printf("Usage: %s [-h] [-b <script.au> [<arguments>]] [{-t|-o} <nmrfile> [<access>]]\n", argv[0]);
  printf("\n");
  printf("Options:\n");
  printf("  -h: help. Print this message.\n");
  printf("  -b: background mode. Process the scriptfile <script.au> as a batch job.\n");
  printf("      Everything that follows this command goes as arguments to <script.au>.\n");
  printf("          Example: %s -b prepa_bruker.au -i data/1/ -o noesy.p\n", argv[0]);
  printf("  <nmrfile>: load this file on opening program.\n");
  printf("      Access directions may follow the file name.\n");
  printf("          Example: %s noesy.p 2\n", argv[0]);
  printf("\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<contains1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,%eax
  mov    %al,-0x10(%rbp)
  jmp    L10
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x10(%rbp)
  je     L10
  mov    $0x1,%eax
  jmp    L24
L10:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L3
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
size_t contains1(char *block, int res, char nullbyte) {
  while (res--) {
    if (block[res] != nullbyte)
      return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<contains1>:
  endbr64
  movslq %esi,%rcx
  lea    -0x1(%rdi,%rcx,1),%rax
  mov    %rax,%rcx
  mov    %esi,%esi
  sub    %rsi,%rcx
L18:
  cmp    %rcx,%rax
  je     L5
  sub    $0x1,%rax
  cmp    %dl,0x1(%rax)
  je     L18
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t contains1(char *block, int res, char nullbyte) {
  while (res--) {
    if (block[res] != nullbyte)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<contains1>:
  endbr64
  movslq %esi,%rcx
  mov    %esi,%esi
  lea    -0x1(%rdi,%rcx,1),%rax
  mov    %rax,%rcx
  sub    %rsi,%rcx
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L10:
  sub    $0x1,%rax
  cmp    %dl,0x1(%rax)
  jne    L7
L12:
  cmp    %rcx,%rax
  jne    L10
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t contains1(char *block, int res, char nullbyte) {
  while (res--) {
    if (block[res] != nullbyte)
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<contains1>:
  endbr64
  movslq %esi,%rcx
  mov    %esi,%esi
  lea    -0x1(%rdi,%rcx,1),%rax
  mov    %rax,%rcx
  sub    %rsi,%rcx
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L0:
  sub    $0x1,%rax
  cmp    %dl,0x1(%rax)
  jne    L3
L25:
  cmp    %rcx,%rax
  jne    L0
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t contains1(char *block, int res, char nullbyte) {
  while (res--) {
    if (block[res] != nullbyte)
      return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x36b,-0x4(%rbp)
  jne    L6
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L6:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: aaaa

assistant: ```c
int main(int argc) {
  if (argc == 875)
    puts("aaaa");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  cmp    $0x36b,%edi
  je     L3
  mov    $0x0,%eax
  ret
L3:
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: aaaa

assistant: ```c
int main(int argc) {
  if (argc == 875)
    puts("aaaa");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  cmp    $0x36b,%edi
  je     L6
  xor    %eax,%eax
  ret
L6:
  push   %rax
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: aaaa

assistant: ```c
int main(int argc) {
  if (argc == 875)
    puts("aaaa");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  cmp    $0x36b,%edi
  je     L0
  xor    %eax,%eax
  ret
L0:
  push   %rax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: aaaa

assistant: ```c
int main(int argc) {
  if (argc == 875)
    puts("aaaa");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<volconvert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  sarl   $0xe,-0x4(%rbp)
  andl   $0x3,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L90
  cmpl   $0x3,-0x4(%rbp)
  jg     L96
  cmpl   $0x2,-0x4(%rbp)
  je     L104
  cmpl   $0x2,-0x4(%rbp)
  jg     L96
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  cmpl   $0x1,-0x4(%rbp)
  je     L51
  jmp    L96
L7:
  mov    $0x0,%eax
  jmp    L17
L51:
  mov    $0x1,%eax
  jmp    L17
L104:
  mov    $0x4,%eax
  jmp    L17
L90:
  mov    $0x5,%eax
  jmp    L17
L96:
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int volconvert(int level) {
  level >>= 14;
  level &= 3;
  switch (level) {
  case 0:
    return 0;
  case 1:
    return 1;
  case 2:
    return 4;
  case 3:
    return 5;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<volconvert>:
  endbr64
  sar    $0xe,%edi
  and    $0x3,%edi
  mov    $0x4,%eax
  cmp    $0x2,%edi
  je     L7
  mov    $0x5,%eax
  cmp    $0x3,%edi
  je     L7
  cmp    $0x1,%edi
  sete   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int volconvert(int level) {
  level >>= 14;
  level &= 3;
  switch (level) {
  case 0:
    return 0;
  case 1:
    return 1;
  case 2:
    return 4;
  case 3:
    return 5;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<volconvert>:
  endbr64
  sar    $0xe,%edi
  xor    %eax,%eax
  and    $0x3,%edi
  sub    $0x1,%edi
  cmp    $0x2,%edi
  ja     L0
  lea    D7(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: 

assistant: ```c
int volconvert(int level) {
  level >>= 14;
  level &= 3;
  switch (level) {
  case 0:
    return 0;
  case 1:
    return 1;
  case 2:
    return 4;
  case 3:
    return 5;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<volconvert>:
  endbr64
  sar    $0xe,%edi
  xor    %eax,%eax
  and    $0x3,%edi
  sub    $0x1,%edi
  cmp    $0x2,%edi
  ja     L4
  lea    D9(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L4:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string

tool: D9: 

assistant: ```c
int volconvert(int level) {
  level >>= 14;
  level &= 3;
  switch (level) {
  case 0:
    return 0;
  case 1:
    return 1;
  case 2:
    return 4;
  case 3:
    return 5;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mod_inv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jne    L31
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  jmp    L66
L3:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L31:
  cmpl   $0x1,-0x24(%rbp)
  jle    L55
  cmpl   $0x0,-0x28(%rbp)
  jne    L3
L55:
  cmpl   $0x1,-0x24(%rbp)
  jle    L15
  cmpl   $0x0,-0x28(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L66
L15:
  cmpl   $0x0,-0x10(%rbp)
  jns    L50
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
L50:
  mov    -0x10(%rbp),%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int mod_inv(int a, int b) {
  int b0 = b, t, q;
  int x0 = 0, x1 = 1;
  if (a == 1)
    return b + 1;
  while (a > 1 && b != 0) {
    q = a / b;
    t = b, b = a % b, a = t;
    t = x0, x0 = x1 - q * x0, x1 = t;
  }
  if (a > 1 && b == 0)
    return 0;
  if (x1 < 0)
    x1 += b0;
  return x1;
}
```