ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncat>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  xor    %edi,%edi
  movslq %eax,%rbx
  add    %r14,%rbx
  add    %rbx,%r13
  cmp    %r13,%rbx
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  je     L66
  jmp    L89
  nop
L25:
  lea    0x1(%rbx),%r12
  xor    %edi,%edi
  cmp    %r12,%r13
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  jne    L99
  movzbl 0x1(%rbp),%eax
  xor    %edi,%edi
  mov    %al,0x1(%rbx)
  test   %al,%al
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  jne    L99
  lea    0x2(%rbx),%r12
  xor    %edi,%edi
  cmp    %r12,%r13
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  jne    L99
  movzbl 0x2(%rbp),%eax
  xor    %edi,%edi
  mov    %al,0x2(%rbx)
  test   %al,%al
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  jne    L99
  lea    0x3(%rbx),%r12
  xor    %edi,%edi
  cmp    %r12,%r13
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  jne    L99
  movzbl 0x3(%rbp),%eax
  xor    %edi,%edi
  mov    %al,0x3(%rbx)
  test   %al,%al
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  jne    L99
  add    $0x4,%rbx
  xor    %edi,%edi
  cmp    %rbx,%r13
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  jne    L45
  add    $0x4,%rbp
L66:
  movzbl 0x0(%rbp),%eax
  xor    %edi,%edi
  mov    %al,(%rbx)
  test   %al,%al
  sete   %dil
  call   <__unlikely@plt>
  test   %rax,%rax
  je     L25
L45:
  mov    %rbx,%r12
L99:
  movb   $0x0,(%r12)
L89:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strncat(char *s, const char *t, size_t n) {
  char *dest = s;
  register char *max;
  s += strlen(s);
  if (__unlikely((max = s + n) == s))
    goto fini;
  for (;;) {
    if (__unlikely(!(*s = *t)))
      break;
    if (__unlikely(++s == max))
      break;
    ++t;
    if (__unlikely(!(*s = *t)))
      break;
    if (__unlikely(++s == max))
      break;
    ++t;
    if (__unlikely(!(*s = *t)))
      break;
    if (__unlikely(++s == max))
      break;
    ++t;
    if (__unlikely(!(*s = *t)))
      break;
    if (__unlikely(++s == max))
      break;
    ++t;
  }
  *s = 0;
fini:
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ServerWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x20(%rbp)
  mov    %ax,-0x18(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L35
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L8
L35:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jg     L13
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
L13:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L8
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string
name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D11
data_type: string

tool: D5: ServerWrite err!arg null

tool: D6: ServerWrite err!len:%d


tool: D11: not all data write back to client!wlen:%d len:%d 


assistant: ```c
void ServerWrite(int fd, short ev, void *arg) {
  if (!arg) {
    printf("ServerWrite err!arg null\n");
    return;
  }
  int len = strlen(arg);
  if (len <= 0) {
    printf("ServerWrite err!len:%d\n", len);
    return;
  }
  int wlen = write(fd, arg, len);
  if (wlen < len) {
    printf("not all data write back to client!wlen:%d len:%d \n", wlen, len);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ServerWrite>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L10
  mov    %edi,%r12d
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L22
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    %eax,%ebp
  jg     L18
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  jmp    L23
L22:
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L18:
  mov    %ebp,%edx
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string
name: disassemble_data
arguments: data_tag: D0
data_type: string

tool: D28: ServerWrite err!arg null

tool: D4: ServerWrite err!len:%d


tool: D0: not all data write back to client!wlen:%d len:%d 


assistant: ```c
void ServerWrite(int fd, short ev, void *arg) {
  if (!arg) {
    printf("ServerWrite err!arg null\n");
    return;
  }
  int len = strlen(arg);
  if (len <= 0) {
    printf("ServerWrite err!len:%d\n", len);
    return;
  }
  int wlen = write(fd, arg, len);
  if (wlen < len) {
    printf("not all data write back to client!wlen:%d len:%d \n", wlen, len);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ServerWrite>:
  endbr64
  test   %rdx,%rdx
  je     L18
  push   %r13
  mov    %edi,%r13d
  mov    %rdx,%rdi
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L7
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %eax,%r12d
  jg     L9
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  pop    %r13
  jmp    10b0 <printf@plt>
  nopl   (%rax)
L9:
  pop    %rbp
  mov    %r12d,%edx
  mov    %eax,%esi
  pop    %r12
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  pop    %r13
  jmp    10b0 <printf@plt>
L18:
  lea    D24(%rip),%rdi
  jmp    1080 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D23
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: string
name: retrieve_data
arguments: data_label: D24
type_guessed: string

tool: D23: ServerWrite err!len:%d


tool: D0: not all data write back to client!wlen:%d len:%d 


tool: D24: ServerWrite err!arg null

assistant: ```c
void ServerWrite(int fd, short ev, void *arg) {
  if (!arg) {
    printf("ServerWrite err!arg null\n");
    return;
  }
  int len = strlen(arg);
  if (len <= 0) {
    printf("ServerWrite err!len:%d\n", len);
    return;
  }
  int wlen = write(fd, arg, len);
  if (wlen < len) {
    printf("not all data write back to client!wlen:%d len:%d \n", wlen, len);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ServerWrite>:
  endbr64
  test   %rdx,%rdx
  je     L7
  push   %r13
  mov    %edi,%r13d
  mov    %rdx,%rdi
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L6
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %eax,%r12d
  jg     L19
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  pop    %r13
  jmp    10b0 <printf@plt>
  nopl   (%rax)
L19:
  pop    %rbp
  mov    %r12d,%edx
  mov    %eax,%esi
  pop    %r12
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  pop    %r13
  jmp    10b0 <printf@plt>
L7:
  lea    D20(%rip),%rdi
  jmp    1080 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D23
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D20
datatype: string

tool: D23: ServerWrite err!len:%d


tool: D19: not all data write back to client!wlen:%d len:%d 


tool: D20: ServerWrite err!arg null

assistant: ```c
void ServerWrite(int fd, short ev, void *arg) {
  if (!arg) {
    printf("ServerWrite err!arg null\n");
    return;
  }
  int len = strlen(arg);
  if (len <= 0) {
    printf("ServerWrite err!len:%d\n", len);
    return;
  }
  int wlen = write(fd, arg, len);
  if (wlen < len) {
    printf("not all data write back to client!wlen:%d len:%d \n", wlen, len);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L42
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L6
L42:
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L20
L6:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L49
L10:
  subl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L49:
  cmpl   $0x1,-0xc(%rbp)
  jne    L10
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D48
type_guessed: string
name: parse_data
arguments: label: D51
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string
name: parse_data
arguments: label: D57
type_guessed: string
name: parse_data
arguments: label: D9
type_guessed: string

tool: D48: 


tool: D51: Enter a positive decimal number: 

tool: D1: %d

tool: D57: Result: 1


tool: D9: Result: %d



assistant: ```c
void factorial(void) {
  int count = 0, fact = 0;
  printf("\n\n");
  printf("Enter a positive decimal number: ");
  scanf("%d", &fact);
  printf("\n\n");
  if ((fact == 0) || (fact == 1)) {
    printf("Result: 1\n\n");
  } else {
    count = fact;
    while (count != 1) {
      count--;
      fact = fact * count;
    }
    printf("Result: %d\n\n", fact);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<factorial>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%esi
  cmp    $0x1,%eax
  jbe    L33
L19:
  sub    $0x1,%eax
  imul   %eax,%esi
  cmp    $0x1,%eax
  jne    L19
  mov    %esi,0x4(%rsp)
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  ret
L33:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D30
type_infered: string
name: retrieve_data
arguments: tag: D21
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: string

tool: D16: 


tool: D30: Enter a positive decimal number: 

tool: D21: %d

tool: D17: Result: %d



tool: D27: Result: 1


assistant: ```c
void factorial(void) {
  int count = 0, fact = 0;
  printf("\n\n");
  printf("Enter a positive decimal number: ");
  scanf("%d", &fact);
  printf("\n\n");
  if ((fact == 0) || (fact == 1)) {
    printf("Result: 1\n\n");
  } else {
    count = fact;
    while (count != 1) {
      count--;
      fact = fact * count;
    }
    printf("Result: %d\n\n", fact);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<factorial>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%esi
  cmp    $0x1,%eax
  jbe    L32
  nopw   0x0(%rax,%rax,1)
L20:
  sub    $0x1,%eax
  imul   %eax,%esi
  cmp    $0x1,%eax
  jne    L20
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  call   <printf@plt>
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string
name: extract_symbolic_data
arguments: label: D35
data_type: string
name: extract_symbolic_data
arguments: label: D40
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string

tool: D26: 


tool: D2: Enter a positive decimal number: 

tool: D35: %d

tool: D40: Result: %d



tool: D15: Result: 1


assistant: ```c
void factorial(void) {
  int count = 0, fact = 0;
  printf("\n\n");
  printf("Enter a positive decimal number: ");
  scanf("%d", &fact);
  printf("\n\n");
  if ((fact == 0) || (fact == 1)) {
    printf("Result: 1\n\n");
  } else {
    count = fact;
    while (count != 1) {
      count--;
      fact = fact * count;
    }
    printf("Result: %d\n\n", fact);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<validate_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L14
  mov    $0xffffffff,%eax
  jmp    L83
L14:
  movq   $0x0,-0x20(%rbp)
  jmp    L152
L26:
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L30
  addl   $0x1,-0x24(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jle    L7
  mov    $0xffffffff,%eax
  jmp    L83
L30:
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L140
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L98
L140:
  mov    $0xffffffff,%eax
  jmp    L83
L98:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %edx,-0x14(%rbp,%rax,4)
L7:
  addq   $0x1,-0x20(%rbp)
L152:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x20(%rbp)
  jb     L26
  cmpl   $0x2,-0x24(%rbp)
  je     L63
  mov    $0xffffffff,%eax
  jmp    L83
L63:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jle    L94
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jle    L94
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jg     L20
L94:
  mov    $0xffffffff,%eax
  jmp    L83
L20:
  mov    $0x0,%eax
L83:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L110
  call   <__stack_chk_fail@plt>
L110:
  leave
  ret
```

assistant: ```c
int validate_version(const char *version) {
  int nof_dots = 0;
  int nof_digits[3] = {0};
  size_t i;
  if (version == NULL) {
    return -1;
  }
  for (i = 0; i < strlen(version); i++) {
    if (version[i] == '.') {
      nof_dots++;
      if (nof_dots > 2) {
        return -1;
      }
    } else if (version[i] < '0' || version[i] > '9') {
      return -1;
    } else {
      nof_digits[nof_dots]++;
    }
  }
  if (nof_dots != 2) {
    return -1;
  }
  if (nof_digits[0] < 1 || nof_digits[1] < 1 || nof_digits[2] < 1) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<validate_version>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  test   %rdi,%rdi
  je     L59
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L82
L55:
  add    $0x1,%r12d
  cmp    $0x2,%r12d
  jle    L29
  mov    $0xffffffff,%eax
  jmp    L86
L32:
  movslq %r12d,%rax
  addl   $0x1,0xc(%rsp,%rax,4)
L29:
  add    $0x1,%rbx
L82:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jbe    L3
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  je     L55
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L32
  mov    $0xffffffff,%eax
  jmp    L86
L3:
  cmp    $0x2,%r12d
  jne    L106
  cmpl   $0x0,0xc(%rsp)
  jle    L119
  cmpl   $0x0,0x10(%rsp)
  jle    L107
  cmpl   $0x0,0x14(%rsp)
  setle  %al
  movzbl %al,%eax
  neg    %eax
L86:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L136
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  mov    $0xffffffff,%eax
  jmp    L86
L106:
  mov    $0xffffffff,%eax
  jmp    L86
L119:
  mov    $0xffffffff,%eax
  jmp    L86
L107:
  mov    $0xffffffff,%eax
  jmp    L86
L136:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int validate_version(const char *version) {
  int nof_dots = 0;
  int nof_digits[3] = {0};
  size_t i;
  if (version == NULL) {
    return -1;
  }
  for (i = 0; i < strlen(version); i++) {
    if (version[i] == '.') {
      nof_dots++;
      if (nof_dots > 2) {
        return -1;
      }
    } else if (version[i] < '0' || version[i] > '9') {
      return -1;
    } else {
      nof_digits[nof_dots]++;
    }
  }
  if (nof_dots != 2) {
    return -1;
  }
  if (nof_digits[0] < 1 || nof_digits[1] < 1 || nof_digits[2] < 1) {
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<validate_version>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  test   %rdi,%rdi
  je     L37
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L67
  nopl   0x0(%rax)
L30:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L37
  movslq %r12d,%rax
  addl   $0x1,0xc(%rsp,%rax,4)
L11:
  add    $0x1,%rbx
L67:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jbe    L115
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  jne    L30
  add    $0x1,%r12d
  cmp    $0x2,%r12d
  jle    L11
L37:
  mov    $0xffffffff,%eax
L80:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L101
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L115:
  cmp    $0x2,%r12d
  jne    L37
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L37
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  jle    L37
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L37
  xor    %eax,%eax
  jmp    L80
L101:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int validate_version(const char *version) {
  int nof_dots = 0;
  int nof_digits[3] = {0};
  size_t i;
  if (version == NULL) {
    return -1;
  }
  for (i = 0; i < strlen(version); i++) {
    if (version[i] == '.') {
      nof_dots++;
      if (nof_dots > 2) {
        return -1;
      }
    } else if (version[i] < '0' || version[i] > '9') {
      return -1;
    } else {
      nof_digits[nof_dots]++;
    }
  }
  if (nof_dots != 2) {
    return -1;
  }
  if (nof_digits[0] < 1 || nof_digits[1] < 1 || nof_digits[2] < 1) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<validate_version>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  test   %rdi,%rdi
  je     L98
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L103
  nopl   0x0(%rax)
L71:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L98
  movslq %r12d,%rax
  addl   $0x1,0xc(%rsp,%rax,4)
L73:
  add    $0x1,%rbx
L103:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jbe    L46
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  jne    L71
  add    $0x1,%r12d
  cmp    $0x2,%r12d
  jle    L73
L98:
  mov    $0xffffffff,%eax
L51:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L46:
  cmp    $0x2,%r12d
  jne    L98
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L98
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  jle    L98
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L98
  xor    %eax,%eax
  jmp    L51
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int validate_version(const char *version) {
  int nof_dots = 0;
  int nof_digits[3] = {0};
  size_t i;
  if (version == NULL) {
    return -1;
  }
  for (i = 0; i < strlen(version); i++) {
    if (version[i] == '.') {
      nof_dots++;
      if (nof_dots > 2) {
        return -1;
      }
    } else if (version[i] < '0' || version[i] > '9') {
      return -1;
    } else {
      nof_digits[nof_dots]++;
    }
  }
  if (nof_dots != 2) {
    return -1;
  }
  if (nof_digits[0] < 1 || nof_digits[1] < 1 || nof_digits[2] < 1) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<child>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *child(void *arg) {
  sleep(1);
  return arg;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<child>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *child(void *arg) {
  sleep(1);
  return arg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<child>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *child(void *arg) {
  sleep(1);
  return arg;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<child>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *child(void *arg) {
  sleep(1);
  return arg;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<asalbul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L4
L35:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L5
  mov    $0x0,%eax
  jmp    L2
L5:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L35
  mov    $0x1,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int asalbul(int *psayi) {
  int i;
  for (i = 2; i < *psayi; i++) {
    if ((*psayi % i) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<asalbul>:
  endbr64
  mov    (%rdi),%esi
  cmp    $0x2,%esi
  jle    L14
  test   $0x1,%sil
  je     L5
  mov    $0x2,%ecx
L38:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  je     L21
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L38
L45:
  ret
L21:
  mov    $0x1,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  jmp    L45
```

assistant: ```c
int asalbul(int *psayi) {
  int i;
  for (i = 2; i < *psayi; i++) {
    if ((*psayi % i) == 0) {
      return 0;
    }
  }
  return 1;
}
```