user: 下面的汇编指令对应的C源代码是什么：

```asm
<atou1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    $0x8,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,%r9
  mov    %ebx,%eax
  imul   %ebx,%eax
  cltq
  lea    -0x8(%r12,%rax,8),%r11
  mov    %ebp,%r10d
  sub    %ebx,%r10d
  lea    -0x1(%rbx),%r12d
  jne    L10
  mov    D7(%rip),%rax
  mov    %rax,(%r11)
  movslq %ebx,%rax
  shl    $0x3,%rax
  sub    %rax,%r11
  lea    -0x8(%r11),%r11
  lea    -0x2(%rbx),%r12d
  mov    $0x1,%r10d
L10:
  test   %r12d,%r12d
  js     L46
  movslq %ebx,%rsi
  shl    $0x3,%rsi
  mov    $0xfffffffffffffff8,%rax
  sub    %rsi,%rax
  mov    %rax,0x8(%rsp)
  add    $0x1,%r12d
  lea    -0x1(%r10),%r13d
  lea    0x8(%r11),%r14
  pxor   %xmm6,%xmm6
  lea    -0x1(%rbx),%r15d
  movapd %xmm6,%xmm10
  movq   D9(%rip),%xmm4
  movsd  D7(%rip),%xmm9
  movapd %xmm4,%xmm8
  movapd %xmm6,%xmm5
  movapd %xmm9,%xmm7
  jmp    L155
L199:
  lea    (%r11,%rsi,1),%rcx
  test   %r10d,%r10d
  jle    L116
  mov    %r9,%rax
  mov    %r13d,%edx
  lea    0x8(%r9,%rdx,8),%r8
  mov    %r9,%rdx
  mov    %rcx,%rdi
L12:
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rdx)
  add    %rsi,%rdi
  add    $0x8,%rdx
  cmp    %r8,%rdx
  jne    L12
  movsd  (%r11),%xmm3
  movapd %xmm9,%xmm0
  subsd  %xmm3,%xmm0
  movsd  %xmm0,(%r11)
  movapd %xmm3,%xmm1
  xorpd  %xmm8,%xmm1
L111:
  movapd %xmm1,%xmm0
  mulsd  (%rax),%xmm0
  movsd  %xmm0,(%rcx)
  add    %rsi,%rcx
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L111
L47:
  mov    %r14,%r8
  cmp    %r12d,%ebx
  jle    L96
  mov    %r15d,%eax
  sub    %r12d,%eax
  lea    0x10(%r11,%rax,8),%rbp
  mov    %r13d,%eax
  lea    0x8(%r9,%rax,8),%rdi
  jmp    L183
L82:
  movapd %xmm1,%xmm2
  mulsd  (%rdx),%xmm2
  movsd  (%rax),%xmm0
  subsd  %xmm2,%xmm0
  movsd  %xmm0,(%rax)
  add    %rsi,%rax
  add    $0x8,%rdx
  cmp    %rdx,%rdi
  jne    L82
L163:
  add    $0x8,%r8
  xorpd  %xmm4,%xmm1
  movsd  %xmm1,-0x8(%r8)
  cmp    %r8,%rbp
  je     L96
L183:
  lea    (%r8,%rsi,1),%rax
  test   %r10d,%r10d
  jle    L170
  mov    %r9,%rdx
  mov    %rax,%rcx
  pxor   %xmm1,%xmm1
L126:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  addsd  %xmm0,%xmm1
  add    %rsi,%rcx
  add    $0x8,%rdx
  cmp    %rdx,%rdi
  jne    L126
  mulsd  %xmm3,%xmm1
  mov    %r9,%rdx
  jmp    L82
L96:
  add    $0x1,%r10d
  mov    0x8(%rsp),%rax
  add    %rax,%r11
  add    $0x1,%r13d
  add    %rax,%r14
  sub    $0x1,%r12d
  je     L46
L155:
  movsd  (%r11),%xmm3
  ucomisd %xmm6,%xmm3
  jp     L199
  ucomisd %xmm5,%xmm3
  jne    L199
  movsd  %xmm7,(%r11)
  lea    (%r11,%rsi,1),%rdx
  mov    %r14,%rax
  test   %r10d,%r10d
  jle    L96
  mov    %r13d,%ecx
  lea    0x10(%r11,%rcx,8),%rcx
L57:
  add    $0x8,%rax
  movq   $0x0,-0x8(%rax)
  movq   $0x0,(%rdx)
  add    %rsi,%rdx
  cmp    %rcx,%rax
  jne    L57
  jmp    L96
L46:
  mov    %r9,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L170:
  movapd %xmm3,%xmm1
  mulsd  %xmm10,%xmm1
  jmp    L163
L116:
  movsd  D7(%rip),%xmm0
  subsd  %xmm3,%xmm0
  movsd  %xmm0,(%r11)
  jmp    L47
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D9
data_type: f32[2]

tool: D7: 1

tool: {"D9": [0.0,-0.0]}

assistant: ```c
void atou1(double *a, int m, int n) {
  double *p0, *p, *q, *w;
  int i, j, k, mm;
  double s, h;
  w = (double *)calloc(m, sizeof(double));
  p0 = a + n * n - 1;
  i = n - 1;
  mm = m - n;
  if (mm == 0) {
    *p0 = 1.;
    p0 -= n + 1;
    --i;
    ++mm;
  }
  for (; i >= 0; --i, ++mm, p0 -= n + 1) {
    if (*p0 != 0.) {
      for (j = 0, p = p0 + n; j < mm; p += n)
        w[j++] = *p;
      h = *p0;
      *p0 = 1. - h;
      for (j = 0, p = p0 + n; j < mm; p += n)
        *p = -h * w[j++];
      for (k = i + 1, q = p0 + 1; k < n; ++k) {
        for (j = 0, p = q + n, s = 0.; j < mm; p += n)
          s += w[j++] * *p;
        s *= h;
        for (j = 0, p = q + n; j < mm; p += n)
          *p -= s * w[j++];
        *q++ = -s;
      }
    } else {
      *p0 = 1.;
      for (j = 0, p = p0 + n, q = p0 + 1; j < mm; ++j, p += n)
        *p = *q++ = 0.;
    }
  }
  free(w);
}
```