ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L13
  mov    0x8(%rbx),%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <Print_FileTypeAndPermissions@plt>
  mov    (%rsp),%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <Print_UserAndGroup@plt>
  mov    %rbp,%rdi
  call   <Print_AccessModifyChangeTime@plt>
  xor    %eax,%eax
L15:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    0x8(%rbx),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L15
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D27
type: string

tool: D15: Name of file: 5s


tool: D0: 	Device: %d


tool: D5: 	i_number; %d


tool: D19: 	Links: %d


tool: D27: 	File size: %d


assistant: ```c
int main(int argc, char *argv[]) {
  struct stat stbuf;
  if (stat(argv[1], &stbuf) == -1) {
    perror(argv[1]);
    return 1;
  }
  printf("Name of file: 5s\n", argv[1]);
  printf("\tDevice: %d\n", (int)stbuf.st_dev);
  printf("\ti_number; %d\n", (int)stbuf.st_ino);
  Print_FileTypeAndPermissions(&stbuf);
  printf("\tLinks: %d\n", stbuf.st_nlink);
  printf("\tFile size: %d\n", (int)stbuf.st_size);
  Print_UserAndGroup(&stbuf);
  Print_AccessModifyChangeTime(&stbuf);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<contrivedLeak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x210(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: %s

assistant: ```c
void contrivedLeak() {
  char buf[512];
  scanf("%s", buf);
  printf(buf);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<contrivedLeak>:
  endbr64
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x210,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: %s

assistant: ```c
void contrivedLeak() {
  char buf[512];
  scanf("%s", buf);
  printf(buf);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<contrivedLeak>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x210,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: %s

assistant: ```c
void contrivedLeak() {
  char buf[512];
  scanf("%s", buf);
  printf(buf);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<contrivedLeak>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x210,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: %s

assistant: ```c
void contrivedLeak() {
  char buf[512];
  scanf("%s", buf);
  printf(buf);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<keccak_squeezeblocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  jmp    L7
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <KeccakF1600_StatePermute@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L32
L25:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rcx
  shl    $0x5,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store64@plt>
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x2c(%rbp),%eax
  sar    $0x3,%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jb     L25
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L7:
  cmpq   $0x0,-0x20(%rbp)
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void keccak_squeezeblocks(uint8_t *h, size_t nblocks, uint64_t *s, uint32_t r) {
  while (nblocks > 0) {
    KeccakF1600_StatePermute(s);
    for (size_t i = 0; i < (r >> 3); i++) {
      store64(h + 8 * i, s[i]);
    }
    h += r;
    nblocks--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<keccak_squeezeblocks>:
  endbr64
  test   %rsi,%rsi
  je     L35
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %ecx,%r13d
  sar    $0x3,%r13d
  movslq %r13d,%r13
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%rax
  mov    %rax,0x8(%rsp)
L15:
  mov    %r12,%rdi
  call   <KeccakF1600_StatePermute@plt>
  test   %r13,%r13
  je     L38
  mov    %r15,%rbp
  mov    $0x0,%ebx
L19:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  call   <store64@plt>
  add    $0x1,%rbx
  add    $0x20,%rbp
  cmp    %r13,%rbx
  jne    L19
L38:
  add    0x8(%rsp),%r15
  sub    $0x1,%r14
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  ret
```

assistant: ```c
void keccak_squeezeblocks(uint8_t *h, size_t nblocks, uint64_t *s, uint32_t r) {
  while (nblocks > 0) {
    KeccakF1600_StatePermute(s);
    for (size_t i = 0; i < (r >> 3); i++) {
      store64(h + 8 * i, s[i]);
    }
    h += r;
    nblocks--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<keccak_squeezeblocks>:
  endbr64
  test   %rsi,%rsi
  je     L5
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  movslq %ecx,%rcx
  push   %rbp
  lea    0x0(,%rcx,4),%rax
  sar    $0x3,%r12d
  mov    %rdx,%rbp
  push   %rbx
  movslq %r12d,%r12
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  xchg   %ax,%ax
L9:
  mov    %rbp,%rdi
  call   <KeccakF1600_StatePermute@plt>
  test   %r12,%r12
  je     L39
  mov    %r14,%r15
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L33:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r15,%rdi
  add    $0x1,%rbx
  add    $0x20,%r15
  call   <store64@plt>
  cmp    %r12,%rbx
  jne    L33
L39:
  add    0x8(%rsp),%r14
  sub    $0x1,%r13
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  ret
```

assistant: ```c
void keccak_squeezeblocks(uint8_t *h, size_t nblocks, uint64_t *s, uint32_t r) {
  while (nblocks > 0) {
    KeccakF1600_StatePermute(s);
    for (size_t i = 0; i < (r >> 3); i++) {
      store64(h + 8 * i, s[i]);
    }
    h += r;
    nblocks--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<keccak_squeezeblocks>:
  endbr64
  test   %rsi,%rsi
  je     L8
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  movslq %ecx,%rcx
  push   %rbp
  lea    0x0(,%rcx,4),%rax
  sar    $0x3,%r12d
  mov    %rdx,%rbp
  push   %rbx
  movslq %r12d,%r12
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  xchg   %ax,%ax
L25:
  mov    %rbp,%rdi
  call   <KeccakF1600_StatePermute@plt>
  test   %r12,%r12
  je     L30
  mov    %r14,%r15
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L32:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r15,%rdi
  add    $0x1,%rbx
  add    $0x20,%r15
  call   <store64@plt>
  cmp    %r12,%rbx
  jne    L32
L30:
  add    0x8(%rsp),%r14
  sub    $0x1,%r13
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  ret
```

assistant: ```c
void keccak_squeezeblocks(uint8_t *h, size_t nblocks, uint64_t *s, uint32_t r) {
  while (nblocks > 0) {
    KeccakF1600_StatePermute(s);
    for (size_t i = 0; i < (r >> 3); i++) {
      store64(h + 8 * i, s[i]);
    }
    h += r;
    nblocks--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heap_adjust>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L51:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L55
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L55
  addl   $0x1,-0x8(%rbp)
L55:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L40
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L51
  jmp    L19
L40:
  nop
L19:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void heap_adjust(int *a, int low, int high) {
  int r = a[low];
  for (int i = 2 * low + 1; i <= high; i = 2 * i + 1) {
    if (i < high && a[i] < a[i + 1])
      ++i;
    if (r >= a[i])
      break;
    a[low] = a[i];
    low = i;
  }
  a[low] = r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<heap_adjust>:
  endbr64
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r9d
  lea    0x1(%rsi,%rsi,1),%eax
  cmp    %edx,%eax
  jle    L5
  jmp    L22
L12:
  movslq %ecx,%rax
  mov    (%rdi,%rax,4),%eax
  cmp    %r9d,%eax
  jle    L22
  movslq %esi,%rsi
  mov    %eax,(%rdi,%rsi,4)
  lea    0x1(%rcx,%rcx,1),%eax
  cmp    %eax,%edx
  jl     L9
  mov    %ecx,%esi
L5:
  mov    %eax,%ecx
  cmp    %eax,%edx
  jle    L12
  movslq %eax,%r8
  mov    0x4(%rdi,%r8,4),%r10d
  cmp    %r10d,(%rdi,%r8,4)
  jge    L12
  lea    0x1(%rax),%ecx
  jmp    L12
L9:
  mov    %ecx,%esi
L22:
  movslq %esi,%rsi
  mov    %r9d,(%rdi,%rsi,4)
  ret
```

assistant: ```c
void heap_adjust(int *a, int low, int high) {
  int r = a[low];
  for (int i = 2 * low + 1; i <= high; i = 2 * i + 1) {
    if (i < high && a[i] < a[i + 1])
      ++i;
    if (r >= a[i])
      break;
    a[low] = a[i];
    low = i;
  }
  a[low] = r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heap_adjust>:
  endbr64
  movslq %esi,%r10
  lea    0x1(%rsi,%rsi,1),%esi
  mov    %rdi,%r8
  lea    (%rdi,%r10,4),%rax
  mov    (%rax),%r11d
  cmp    %edx,%esi
  jle    L1
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L55:
  lea    0x1(%rcx,%rcx,1),%esi
  mov    %edi,(%rax)
  cmp    %esi,%edx
  jl     L41
  movslq %ecx,%r10
L1:
  movslq %esi,%rax
  mov    %esi,%ecx
  shl    $0x2,%rax
  lea    (%r8,%rax,1),%r9
  mov    (%r9),%edi
  cmp    %esi,%edx
  jle    L25
  lea    0x4(%r8,%rax,1),%rax
  mov    (%rax),%esi
  cmp    %edi,%esi
  jle    L25
  add    $0x1,%ecx
  mov    %esi,%edi
  mov    %rax,%r9
L25:
  lea    (%r8,%r10,4),%rax
  cmp    %edi,%r11d
  jl     L55
L50:
  mov    %r11d,(%rax)
  ret
  nopl   0x0(%rax)
L41:
  mov    %r9,%rax
  mov    %r11d,(%rax)
  ret
```

assistant: ```c
void heap_adjust(int *a, int low, int high) {
  int r = a[low];
  for (int i = 2 * low + 1; i <= high; i = 2 * i + 1) {
    if (i < high && a[i] < a[i + 1])
      ++i;
    if (r >= a[i])
      break;
    a[low] = a[i];
    low = i;
  }
  a[low] = r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heap_adjust>:
  endbr64
  movslq %esi,%r10
  lea    0x1(%rsi,%rsi,1),%esi
  mov    %rdi,%r8
  lea    (%rdi,%r10,4),%rax
  mov    (%rax),%r11d
  cmp    %edx,%esi
  jle    L30
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L21:
  lea    0x1(%rcx,%rcx,1),%esi
  mov    %edi,(%rax)
  cmp    %esi,%edx
  jl     L9
  movslq %ecx,%r10
L30:
  movslq %esi,%rax
  mov    %esi,%ecx
  shl    $0x2,%rax
  lea    (%r8,%rax,1),%r9
  mov    (%r9),%edi
  cmp    %esi,%edx
  jle    L32
  lea    0x4(%r8,%rax,1),%rax
  mov    (%rax),%esi
  cmp    %edi,%esi
  jle    L32
  add    $0x1,%ecx
  mov    %esi,%edi
  mov    %rax,%r9
L32:
  lea    (%r8,%r10,4),%rax
  cmp    %edi,%r11d
  jl     L21
L0:
  mov    %r11d,(%rax)
  ret
  nopl   0x0(%rax)
L9:
  mov    %r9,%rax
  mov    %r11d,(%rax)
  ret
```

assistant: ```c
void heap_adjust(int *a, int low, int high) {
  int r = a[low];
  for (int i = 2 * low + 1; i <= high; i = 2 * i + 1) {
    if (i < high && a[i] < a[i + 1])
      ++i;
    if (r >= a[i])
      break;
    a[low] = a[i];
    low = i;
  }
  a[low] = r;
}
```
user: What is the c source code of the assembly code below?

```asm
<two_side_distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0xe6,-0xc(%rbp)
  movl   $0x1b8,-0x8(%rbp)
  movl   $0x1c2,-0x4(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L76
  cmpl   $0x0,-0x20(%rbp)
  jne    L76
  cmpl   $0x0,-0x14(%rbp)
  jne    L95
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <match@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  jmp    L5
L95:
  cmpl   $0x0,-0x18(%rbp)
  jne    L22
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <match@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  jmp    L5
L22:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <match@plt>
  jmp    L5
L76:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L9
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <match@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  jmp    L5
L9:
  cmpl   $0x0,-0x20(%rbp)
  jne    L65
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  mov    $0x0,%eax
  call   <match@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  jmp    L5
L65:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  add    %ecx,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <match@plt>
  mov    -0x8(%rbp),%edx
  add    %edx,%eax
L5:
  leave
  ret
```

assistant: ```c
int two_side_distance(x1, y1, x2, y2)
int x1, y1, x2, y2;
{
  int penalty21 = 230;
  int penalty22 = 440;
  int penalty01 = 450;
  if (x2 == 0 && y2 == 0)
    if (x1 == 0)
      return (match(x1, y1) + penalty01);
    else if (y1 == 0)
      return (match(x1, y1) + penalty01);
    else
      return (match(x1, y1));
  else if (x2 == 0)
    return (match(x1, y1 + y2) + penalty21);
  else if (y2 == 0)
    return (match(x1 + x2, y1) + penalty21);
  else
    return (match(x1 + x2, y1 + y2) + penalty22);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<two_side_distance>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%eax
  or     %ecx,%eax
  jne    L73
  test   %edi,%edi
  je     L16
  test   %esi,%esi
  jne    L35
  mov    $0x0,%eax
  call   <match@plt>
  add    $0x1c2,%eax
L41:
  add    $0x8,%rsp
  ret
L16:
  mov    $0x0,%eax
  call   <match@plt>
  add    $0x1c2,%eax
  jmp    L41
L35:
  mov    $0x0,%eax
  call   <match@plt>
  jmp    L41
L73:
  test   %edx,%edx
  je     L14
  test   %ecx,%ecx
  jne    L50
  add    %edx,%edi
  mov    $0x0,%eax
  call   <match@plt>
  add    $0xe6,%eax
  jmp    L41
L14:
  add    %ecx,%esi
  mov    $0x0,%eax
  call   <match@plt>
  add    $0xe6,%eax
  jmp    L41
L50:
  add    %ecx,%esi
  add    %edx,%edi
  mov    $0x0,%eax
  call   <match@plt>
  add    $0x1b8,%eax
  jmp    L41
```

assistant: ```c
int two_side_distance(x1, y1, x2, y2)
int x1, y1, x2, y2;
{
  int penalty21 = 230;
  int penalty22 = 440;
  int penalty01 = 450;
  if (x2 == 0 && y2 == 0)
    if (x1 == 0)
      return (match(x1, y1) + penalty01);
    else if (y1 == 0)
      return (match(x1, y1) + penalty01);
    else
      return (match(x1, y1));
  else if (x2 == 0)
    return (match(x1, y1 + y2) + penalty21);
  else if (y2 == 0)
    return (match(x1 + x2, y1) + penalty21);
  else
    return (match(x1 + x2, y1 + y2) + penalty22);
}
```
user: What is the c source code of the assembly code below?

```asm
<two_side_distance>:
  endbr64
  mov    %edx,%eax
  sub    $0x8,%rsp
  or     %ecx,%eax
  jne    L30
  xor    %eax,%eax
  test   %edi,%edi
  je     L19
  test   %esi,%esi
  jne    L10
L19:
  call   <match@plt>
  add    $0x8,%rsp
  add    $0x1c2,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  test   %edx,%edx
  je     L11
  add    %edx,%edi
  test   %ecx,%ecx
  jne    L44
  xor    %eax,%eax
  call   <match@plt>
  add    $0x8,%rsp
  add    $0xe6,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsp
  jmp    1050 <match@plt>
  nopl   0x0(%rax)
L44:
  add    %ecx,%esi
  xor    %eax,%eax
  call   <match@plt>
  add    $0x8,%rsp
  add    $0x1b8,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  add    %ecx,%esi
  xor    %eax,%eax
  call   <match@plt>
  add    $0x8,%rsp
  add    $0xe6,%eax
  ret
```

assistant: ```c
int two_side_distance(x1, y1, x2, y2)
int x1, y1, x2, y2;
{
  int penalty21 = 230;
  int penalty22 = 440;
  int penalty01 = 450;
  if (x2 == 0 && y2 == 0)
    if (x1 == 0)
      return (match(x1, y1) + penalty01);
    else if (y1 == 0)
      return (match(x1, y1) + penalty01);
    else
      return (match(x1, y1));
  else if (x2 == 0)
    return (match(x1, y1 + y2) + penalty21);
  else if (y2 == 0)
    return (match(x1 + x2, y1) + penalty21);
  else
    return (match(x1 + x2, y1 + y2) + penalty22);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<two_side_distance>:
  endbr64
  mov    %edx,%eax
  sub    $0x8,%rsp
  or     %ecx,%eax
  jne    L47
  xor    %eax,%eax
  test   %edi,%edi
  je     L23
  test   %esi,%esi
  jne    L45
L23:
  call   <match@plt>
  add    $0x8,%rsp
  add    $0x1c2,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  test   %edx,%edx
  je     L48
  add    %edx,%edi
  test   %ecx,%ecx
  jne    L20
  xor    %eax,%eax
  call   <match@plt>
  add    $0x8,%rsp
  add    $0xe6,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x8,%rsp
  jmp    1050 <match@plt>
  nopl   0x0(%rax)
L20:
  add    %ecx,%esi
  xor    %eax,%eax
  call   <match@plt>
  add    $0x8,%rsp
  add    $0x1b8,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  add    %ecx,%esi
  xor    %eax,%eax
  call   <match@plt>
  add    $0x8,%rsp
  add    $0xe6,%eax
  ret
```

assistant: ```c
int two_side_distance(x1, y1, x2, y2)
int x1, y1, x2, y2;
{
  int penalty21 = 230;
  int penalty22 = 440;
  int penalty01 = 450;
  if (x2 == 0 && y2 == 0)
    if (x1 == 0)
      return (match(x1, y1) + penalty01);
    else if (y1 == 0)
      return (match(x1, y1) + penalty01);
    else
      return (match(x1, y1));
  else if (x2 == 0)
    return (match(x1, y1 + y2) + penalty21);
  else if (y2 == 0)
    return (match(x1 + x2, y1) + penalty21);
  else
    return (match(x1 + x2, y1 + y2) + penalty22);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string
name: extract_symbolic_data
arguments: label: D58
type: string
name: extract_symbolic_data
arguments: label: D26
type: string
name: extract_symbolic_data
arguments: label: D51
type: string
name: extract_symbolic_data
arguments: label: D39
type: string

tool: D6: Enter dividend: 

tool: D58: %d

tool: D26: Enter divisor: 

tool: D51: Quotient = %d


tool: D39: Remainder = %d

assistant: ```c
int main() {
  int dividend, divisor, quotient, remainder;
  printf("Enter dividend: ");
  scanf("%d", &dividend);
  printf("Enter divisor: ");
  scanf("%d", &divisor);
  quotient = dividend / divisor;
  remainder = dividend % divisor;
  printf("Quotient = %d\n", quotient);
  printf("Remainder = %d", remainder);
  return 0;
}
```