ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%eax
  mov    $0x17,%esi
  jmp    L7
  nopl   0x0(%rax)
L13:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  je     L37
L7:
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  jbe    L13
  imul   $0xaaaaaaab,%eax,%ecx
  lea    (%rsi,%rax,1),%edx
  cmp    $0x55555556,%ecx
  cmovb  %edx,%esi
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  jne    L7
L37:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D3: %d


assistant: ```c
int main() {
  int sum = 23;
  int n = 10;
  int n_max = 1000;
  while (n < n_max) {
    if (n % 5 == 0)
      sum += n;
    else if (n % 3 == 0)
      sum += n;
    n++;
  }
  printf("%d\n", sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<try_setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  movb   $0x0,-0x11(%rbp)
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: ip link set %s up

assistant: ```c
int try_setup(const char *iface) {
  char buffer[256];
  snprintf(buffer, sizeof(buffer), "ip link set %s up", iface);
  buffer[sizeof(buffer) - 1] = '\0';
  return system(buffer);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<try_setup>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D9(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  movb   $0x0,0xff(%rsp)
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x110,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: ip link set %s up

assistant: ```c
int try_setup(const char *iface) {
  char buffer[256];
  snprintf(buffer, sizeof(buffer), "ip link set %s up", iface);
  buffer[sizeof(buffer) - 1] = '\0';
  return system(buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<try_setup>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  lea    D7(%rip),%rdx
  mov    $0x100,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  movb   $0x0,0xff(%rsp)
  call   <system@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x110,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: ip link set %s up

assistant: ```c
int try_setup(const char *iface) {
  char buffer[256];
  snprintf(buffer, sizeof(buffer), "ip link set %s up", iface);
  buffer[sizeof(buffer) - 1] = '\0';
  return system(buffer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<try_setup>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  lea    D3(%rip),%rdx
  mov    $0x100,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  movb   $0x0,0xff(%rsp)
  call   <system@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x110,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: ip link set %s up

assistant: ```c
int try_setup(const char *iface) {
  char buffer[256];
  snprintf(buffer, sizeof(buffer), "ip link set %s up", iface);
  buffer[sizeof(buffer) - 1] = '\0';
  return system(buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L22
L6:
  mov    -0x28(%rbp),%eax
  cltq
  movzbl -0x1c(%rbp,%rax,1),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
  subl   $0x1,-0x28(%rbp)
  addl   $0x1,-0x24(%rbp)
L22:
  cmpl   $0x0,-0x28(%rbp)
  jns    L6
  mov    -0x24(%rbp),%eax
  cltq
  movb   $0x0,-0x12(%rbp,%rax,1)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D14
type_guessed: string

tool: D0: %s

tool: D14: %s


assistant: ```c
int main() {
  char s[10], r[10];
  int n, i, d;
  scanf("%s", &s);
  n = strlen(s);
  for (i = n - 1, d = 0; i >= 0; i--, d++)
    r[d] = s[i];
  r[d] = '\0';
  printf("%s\n", r);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L25
  movslq %eax,%rdx
  lea    0x4(%rsp,%rdx,1),%rcx
  lea    0xe(%rsp),%rdx
  lea    -0x1(%rax),%esi
  lea    0xf(%rsp,%rsi,1),%rdi
L0:
  movzbl -0x1(%rcx),%esi
  mov    %sil,(%rdx)
  sub    $0x1,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L0
L20:
  cltq
  movb   $0x0,0xe(%rsp,%rax,1)
  lea    0xe(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L25:
  mov    $0x0,%eax
  jmp    L20
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D18
datatype: string

tool: D1: %s

tool: D18: %s


assistant: ```c
int main() {
  char s[10], r[10];
  int n, i, d;
  scanf("%s", &s);
  n = strlen(s);
  for (i = n - 1, d = 0; i >= 0; i--, d++)
    r[d] = s[i];
  r[d] = '\0';
  printf("%s\n", r);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L3
  movslq %eax,%rdi
  lea    0xe(%rsp),%r8
  sub    $0x1,%eax
  lea    (%rbx,%rdi,1),%rcx
  mov    %r8,%rdx
  lea    0xf(%rsp,%rax,1),%rsi
L0:
  movzbl -0x1(%rcx),%eax
  add    $0x1,%rdx
  sub    $0x1,%rcx
  mov    %al,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L0
L13:
  movb   $0x0,0xe(%rsp,%rdi,1)
  mov    %r8,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  xor    %edi,%edi
  lea    0xe(%rsp),%r8
  jmp    L13
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D9: %s

tool: D5: %s


assistant: ```c
int main() {
  char s[10], r[10];
  int n, i, d;
  scanf("%s", &s);
  n = strlen(s);
  for (i = n - 1, d = 0; i >= 0; i--, d++)
    r[d] = s[i];
  r[d] = '\0';
  printf("%s\n", r);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L10
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0xe(%rsp)
  lea    -0x2(%rax),%edx
  cmp    $0x1,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0xf(%rsp)
  lea    -0x3(%rax),%edx
  cmp    $0x2,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0x10(%rsp)
  lea    -0x4(%rax),%edx
  cmp    $0x3,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0x11(%rsp)
  lea    -0x5(%rax),%edx
  cmp    $0x4,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0x12(%rsp)
  lea    -0x6(%rax),%edx
  cmp    $0x5,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0x13(%rsp)
  lea    -0x7(%rax),%edx
  cmp    $0x6,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0x14(%rsp)
  lea    -0x8(%rax),%edx
  cmp    $0x7,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0x15(%rsp)
  lea    -0x9(%rax),%edx
  cmp    $0x8,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0x16(%rsp)
  lea    -0xa(%rax),%edx
  cmp    $0x9,%eax
  je     L52
  movslq %edx,%rdx
  movzbl 0x4(%rsp,%rdx,1),%edx
  mov    %dl,0x17(%rsp)
L52:
  cltq
  lea    0xe(%rsp),%rsi
  lea    D0(%rip),%rdi
  movb   $0x0,0xe(%rsp,%rax,1)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L10:
  xor    %eax,%eax
  jmp    L52
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D13: %s

tool: D0: %s


assistant: ```c
int main() {
  char s[10], r[10];
  int n, i, d;
  scanf("%s", &s);
  n = strlen(s);
  for (i = n - 1, d = 0; i >= 0; i--, d++)
    r[d] = s[i];
  r[d] = '\0';
  printf("%s\n", r);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L10:
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <getpass@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L10
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D22(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypt@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D47
datatype: string
name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D46
datatype: string
name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D49
datatype: string

tool: D47: Give me a password: 

tool: D16: r

tool: D46: /dev/random

tool: D22: $2b$%llu

tool: D49: 
%s


assistant: ```c
int main(void) {
  char *pass;
  do {
    pass = getpass("Give me a password: ");
  } while (pass == NULL);
  unsigned long long seed;
  FILE *f;
  f = fopen("/dev/random", "r");
  fread(&seed, sizeof(seed), 1, f);
  fclose(f);
  char *sseed = malloc(1024 * sizeof(char));
  sprintf(sseed, "$2b$%llu", seed);
  char *enc = crypt(pass, sseed);
  printf("\n%s\n", enc);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rbp
L8:
  mov    %rbp,%rdi
  call   <getpass@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  lea    D18(%rip),%rsi
  lea    D7(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rsp,%rdi
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  call   <fread@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    (%rsp),%rdx
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <crypt@plt>
  mov    %rax,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D29
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D11: Give me a password: 

tool: D18: r

tool: D7: /dev/random

tool: D29: $2b$%llu

tool: D5: 
%s


assistant: ```c
int main(void) {
  char *pass;
  do {
    pass = getpass("Give me a password: ");
  } while (pass == NULL);
  unsigned long long seed;
  FILE *f;
  f = fopen("/dev/random", "r");
  fread(&seed, sizeof(seed), 1, f);
  fclose(f);
  char *sseed = malloc(1024 * sizeof(char));
  sprintf(sseed, "$2b$%llu", seed);
  char *enc = crypt(pass, sseed);
  printf("\n%s\n", enc);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D30(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbx,%rdi
  call   <getpass@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L18
  lea    D48(%rip),%rsi
  lea    D21(%rip),%rdi
  call   <fopen@plt>
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rsp,%rdi
  mov    %rax,%rcx
  mov    %rax,%r12
  call   <fread@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    (%rsp),%rdx
  lea    D12(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crypt@plt>
  lea    D11(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D30
datatype: string
name: parse_data
arguments: tag: D48
datatype: string
name: parse_data
arguments: tag: D21
datatype: string
name: parse_data
arguments: tag: D12
datatype: string
name: parse_data
arguments: tag: D11
datatype: string

tool: D30: Give me a password: 

tool: D48: r

tool: D21: /dev/random

tool: D12: $2b$%llu

tool: D11: 
%s


assistant: ```c
int main(void) {
  char *pass;
  do {
    pass = getpass("Give me a password: ");
  } while (pass == NULL);
  unsigned long long seed;
  FILE *f;
  f = fopen("/dev/random", "r");
  fread(&seed, sizeof(seed), 1, f);
  fclose(f);
  char *sseed = malloc(1024 * sizeof(char));
  sprintf(sseed, "$2b$%llu", seed);
  char *enc = crypt(pass, sseed);
  printf("\n%s\n", enc);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  call   <getpass@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L3
  lea    D10(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <fopen@plt>
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rsp,%rdi
  mov    %rax,%rcx
  mov    %rax,%r12
  call   <fread@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    (%rsp),%rdx
  lea    D37(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crypt@plt>
  lea    D39(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D37
type_infered: string
name: parse_data
arguments: data_label: D39
type_infered: string

tool: D1: Give me a password: 

tool: D10: r

tool: D6: /dev/random

tool: D37: $2b$%llu

tool: D39: 
%s


assistant: ```c
int main(void) {
  char *pass;
  do {
    pass = getpass("Give me a password: ");
  } while (pass == NULL);
  unsigned long long seed;
  FILE *f;
  f = fopen("/dev/random", "r");
  fread(&seed, sizeof(seed), 1, f);
  fclose(f);
  char *sseed = malloc(1024 * sizeof(char));
  sprintf(sseed, "$2b$%llu", seed);
  char *enc = crypt(pass, sseed);
  printf("\n%s\n", enc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L65
L12:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L67
L64:
  addq   $0x1,-0x8(%rbp)
L67:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L64
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L45
  mov    -0x18(%rbp),%rax
  jmp    L62
L45:
  addq   $0x1,-0x18(%rbp)
L65:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L12
  mov    $0x0,%eax
L62:
  pop    %rbp
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  int c;
  const char *p;
  for (; c = *s1; ++s1) {
    for (p = s2; *p && *p != c; ++p)
      ;
    if (*p == c)
      return s1;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L79
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  setne  %r9b
  jmp    L67
L90:
  mov    %r8d,%edx
L75:
  cmp    %cl,%dl
  je     L48
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L77
L67:
  cmp    %cl,%r8b
  je     L90
  mov    %rsi,%rax
  test   %r9b,%r9b
  je     L90
L66:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %cl,%dl
  je     L75
  test   %dl,%dl
  jne    L66
  jmp    L75
L79:
  mov    $0x0,%edi
  jmp    L48
L77:
  mov    $0x0,%edi
L48:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  int c;
  const char *p;
  for (; c = *s1; ++s1) {
    for (p = s2; *p && *p != c; ++p)
      ;
    if (*p == c)
      return s1;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%r8
  test   %cl,%cl
  je     L31
  movzbl (%rsi),%edi
  nopl   0x0(%rax)
L12:
  mov    %rsi,%rdx
  mov    %edi,%eax
  test   %dil,%dil
  jne    L22
  jmp    L20
  nopl   0x0(%rax)
L13:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L20
L22:
  cmp    %cl,%al
  jne    L13
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L20:
  movzbl 0x1(%r8),%ecx
  add    $0x1,%r8
  test   %cl,%cl
  jne    L12
L31:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  int c;
  const char *p;
  for (; c = *s1; ++s1) {
    for (p = s2; *p && *p != c; ++p)
      ;
    if (*p == c)
      return s1;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%r8
  test   %cl,%cl
  je     L28
  movzbl (%rsi),%edi
  nopl   0x0(%rax)
L50:
  mov    %rsi,%rdx
  mov    %edi,%eax
  test   %dil,%dil
  jne    L23
  jmp    L16
  nopl   0x0(%rax)
L51:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L16
L23:
  cmp    %cl,%al
  jne    L51
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L16:
  movzbl 0x1(%r8),%ecx
  add    $0x1,%r8
  test   %cl,%cl
  jne    L50
L28:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  int c;
  const char *p;
  for (; c = *s1; ++s1) {
    for (p = s2; *p && *p != c; ++p)
      ;
    if (*p == c)
      return s1;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L20:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L20
L27:
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t skip_spaces(const char *str, const char **end) {
  const char *cur = str;
  size_t len = 0;
  while (*cur && isspace(*cur)) {
    cur++;
    len++;
  }
  *end = cur;
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_spaces>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  movzbl (%rdi),%edi
  mov    $0x0,%ebp
  test   %dil,%dil
  je     L22
L12:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L22
  add    $0x1,%rbx
  add    $0x1,%rbp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L12
L22:
  mov    %rbx,(%r12)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t skip_spaces(const char *str, const char **end) {
  const char *cur = str;
  size_t len = 0;
  while (*cur && isspace(*cur)) {
    cur++;
    len++;
  }
  *end = cur;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_spaces>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L8
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%r12
  test   %dil,%dil
  je     L15
L8:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
L15:
  mov    %rbx,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t skip_spaces(const char *str, const char **end) {
  const char *cur = str;
  size_t len = 0;
  while (*cur && isspace(*cur)) {
    cur++;
    len++;
  }
  *end = cur;
  return len;
}
```