ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <test_shellcode@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_shellcode(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x3,%edi
  call   <sysfs1@plt>
  mov    %eax,-0x74(%rbp)
  cmpl   $0xffffffff,-0x74(%rbp)
  jne    L22
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L22:
  movl   $0x0,-0x78(%rbp)
  jmp    L12
L2:
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <sysfs@plt>
  test   %rax,%rax
  je     L35
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L35:
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x78(%rbp)
L12:
  mov    -0x78(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string
name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D27
type: string

tool: D7: sysfs(3)

tool: D28: sysfs(2)

tool: D27: %2d: %s


assistant: ```c
main() {
  int i, tot;
  char buf[100];
  tot = sysfs1(3);
  if (tot == -1) {
    perror("sysfs(3)");
    exit(1);
  }
  for (i = 0; i < tot; i++) {
    if (sysfs(2, i, buf)) {
      perror("sysfs(2)");
      exit(1);
    }
    printf("%2d: %s\n", i, buf);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x3,%edi
  call   <sysfs1@plt>
  cmp    $0xffffffff,%eax
  je     L42
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L31
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  lea    D9(%rip),%r14
  lea    D24(%rip),%r13
  jmp    L68
L42:
  lea    D13(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L31:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L31
L68:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <sysfs@plt>
  test   %rax,%rax
  je     L44
  mov    %r14,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L44
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string
name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D13
type: string

tool: D9: sysfs(2)

tool: D24: %2d: %s


tool: D13: sysfs(3)

assistant: ```c
main() {
  int i, tot;
  char buf[100];
  tot = sysfs1(3);
  if (tot == -1) {
    perror("sysfs(3)");
    exit(1);
  }
  for (i = 0; i < tot; i++) {
    if (sysfs(2, i, buf)) {
      perror("sysfs(2)");
      exit(1);
    }
    printf("%2d: %s\n", i, buf);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x3,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <sysfs1@plt>
  cmp    $0xffffffff,%eax
  je     L29
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L68
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  lea    D29(%rip),%r13
  lea    D5(%rip),%r14
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdx
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r12d
  je     L68
L55:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <sysfs@plt>
  test   %rax,%rax
  je     L1
  mov    %r14,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
L29:
  lea    D12(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nopl   0x0(%rax,%rax,1)
L68:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
type: string
name: read_data
arguments: data_tag: D5
type: string
name: read_data
arguments: data_tag: D12
type: string

tool: D29: %2d: %s


tool: D5: sysfs(2)

tool: D12: sysfs(3)

assistant: ```c
main() {
  int i, tot;
  char buf[100];
  tot = sysfs1(3);
  if (tot == -1) {
    perror("sysfs(3)");
    exit(1);
  }
  for (i = 0; i < tot; i++) {
    if (sysfs(2, i, buf)) {
      perror("sysfs(2)");
      exit(1);
    }
    printf("%2d: %s\n", i, buf);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x3,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <sysfs1@plt>
  cmp    $0xffffffff,%eax
  je     L12
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L18
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  lea    D11(%rip),%r13
  lea    D14(%rip),%r14
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %ebx,%esi
  mov    %rbp,%rdx
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r12d
  je     L18
L4:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <sysfs@plt>
  test   %rax,%rax
  je     L22
  mov    %r14,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L22
L12:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D11: %2d: %s


tool: D14: sysfs(2)

tool: D2: sysfs(3)

assistant: ```c
main() {
  int i, tot;
  char buf[100];
  tot = sysfs1(3);
  if (tot == -1) {
    perror("sysfs(3)");
    exit(1);
  }
  for (i = 0; i < tot; i++) {
    if (sysfs(2, i, buf)) {
      perror("sysfs(2)");
      exit(1);
    }
    printf("%2d: %s\n", i, buf);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x14(%rbp)
  jne    L11
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L15
L11:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D23
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string

tool: D23: Ingrese el primer numero: 

tool: D13: Ingrese el segundo numero: 

tool: D11: %f

assistant: ```c
float get_num(int a) {
  if (a == 1)
    printf("Ingrese el primer numero: ");
  else
    printf("Ingrese el segundo numero: ");
  float f;
  scanf("%f", &f);
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_num>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L14
  lea    D2(%rip),%rdi
  call   <printf@plt>
L25:
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L14:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D11
type: string

tool: D2: Ingrese el segundo numero: 

tool: D20: %f

tool: D11: Ingrese el primer numero: 

assistant: ```c
float get_num(int a) {
  if (a == 1)
    printf("Ingrese el primer numero: ");
  else
    printf("Ingrese el segundo numero: ");
  float f;
  scanf("%f", &f);
  return f;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_num>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L7
  lea    D9(%rip),%rdi
  call   <printf@plt>
L26:
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L7:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D17
datatype: string

tool: D9: Ingrese el segundo numero: 

tool: D8: %f

tool: D17: Ingrese el primer numero: 

assistant: ```c
float get_num(int a) {
  if (a == 1)
    printf("Ingrese el primer numero: ");
  else
    printf("Ingrese el segundo numero: ");
  float f;
  scanf("%f", &f);
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_num>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L17
  lea    D22(%rip),%rdi
  call   <printf@plt>
L0:
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L17:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D22: Ingrese el segundo numero: 

tool: D19: %f

tool: D7: Ingrese el primer numero: 

assistant: ```c
float get_num(int a) {
  if (a == 1)
    printf("Ingrese el primer numero: ");
  else
    printf("Ingrese el segundo numero: ");
  float f;
  scanf("%f", &f);
  return f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func11>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func11() {
#pragma critTer : 42 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 43 :../../ test / resources / functionNumber.c:
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func11>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func11() {
#pragma critTer : 42 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 43 :../../ test / resources / functionNumber.c:
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func11>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func11() {
#pragma critTer : 42 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 43 :../../ test / resources / functionNumber.c:
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func11>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func11() {
#pragma critTer : 42 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 43 :../../ test / resources / functionNumber.c:
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <connect_to_irc@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <main_loop@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <disconnect@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main(void) {
  int socket;
  struct sockaddr_in socket_conf;
  connect_to_irc(&socket, &socket_conf);
  main_loop(socket);
  disconnect(socket);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <connect_to_irc@plt>
  mov    (%rsp),%edi
  call   <main_loop@plt>
  mov    (%rsp),%edi
  call   <disconnect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int socket;
  struct sockaddr_in socket_conf;
  connect_to_irc(&socket, &socket_conf);
  main_loop(socket);
  disconnect(socket);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <connect_to_irc@plt>
  mov    (%rsp),%edi
  call   <main_loop@plt>
  mov    (%rsp),%edi
  call   <disconnect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int socket;
  struct sockaddr_in socket_conf;
  connect_to_irc(&socket, &socket_conf);
  main_loop(socket);
  disconnect(socket);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <connect_to_irc@plt>
  mov    (%rsp),%edi
  call   <main_loop@plt>
  mov    (%rsp),%edi
  call   <disconnect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int socket;
  struct sockaddr_in socket_conf;
  connect_to_irc(&socket, &socket_conf);
  main_loop(socket);
  disconnect(socket);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<heapify_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L9:
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <heapify_node@plt>
  subl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapify_array(int last) {
  int i;
  for (i = (last - 1) / 2; i >= 0; i--) {
    heapify_node(i, last);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<heapify_array>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  lea    -0x1(%rdi),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  test   %edi,%edi
  js     L4
L5:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <heapify_node@plt>
  sub    $0x1,%ebx
  jns    L5
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapify_array(int last) {
  int i;
  for (i = (last - 1) / 2; i >= 0; i--) {
    heapify_node(i, last);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<heapify_array>:
  endbr64
  lea    -0x1(%rdi),%eax
  push   %rbp
  push   %rbx
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sub    $0x8,%rsp
  sar    %ebx
  test   %edi,%edi
  js     L2
  mov    %edi,%ebp
  nopl   0x0(%rax)
L3:
  mov    %ebx,%edi
  mov    %ebp,%esi
  call   <heapify_node@plt>
  sub    $0x1,%ebx
  jae    L3
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapify_array(int last) {
  int i;
  for (i = (last - 1) / 2; i >= 0; i--) {
    heapify_node(i, last);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heapify_array>:
  endbr64
  lea    -0x1(%rdi),%eax
  push   %rbp
  push   %rbx
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sub    $0x8,%rsp
  sar    %ebx
  test   %edi,%edi
  js     L1
  mov    %edi,%ebp
  nopl   0x0(%rax)
L3:
  mov    %ebx,%edi
  mov    %ebp,%esi
  call   <heapify_node@plt>
  sub    $0x1,%ebx
  jae    L3
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapify_array(int last) {
  int i;
  for (i = (last - 1) / 2; i >= 0; i--) {
    heapify_node(i, last);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L33
L19:
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x3c(%rbp)
L33:
  mov    -0x3c(%rbp),%eax
  test   %eax,%eax
  jne    L19
  movl   $0x0,-0x38(%rbp)
  jmp    L28
L12:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L26
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L26:
  addl   $0x1,-0x38(%rbp)
L28:
  cmpl   $0x9,-0x38(%rbp)
  jle    L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string

tool: D16: %d

tool: D11: %d - %d


assistant: ```c
int main() {
  int number[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int i, n, k;
  scanf("%d", &n);
  while (n != 0) {
    k = n % 10;
    number[k] = number[k] + 1;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (number[i] != 0) {
      printf("%d - %d\n", i, number[i]);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  je     L68
L38:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %esi,%edx
  test   %esi,%esi
  jne    L38
  movl   $0x0,0xc(%rsp)
L68:
  mov    $0x0,%ebx
  lea    D15(%rip),%rbp
  jmp    L64
L8:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  je     L51
L64:
  mov    %ebx,%esi
  mov    0x10(%rsp,%rbx,4),%edx
  test   %edx,%edx
  je     L8
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L8
L51:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D15
type_infered: string

tool: D11: %d

tool: D15: %d - %d


assistant: ```c
int main() {
  int number[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int i, n, k;
  scanf("%d", &n);
  while (n != 0) {
    k = n % 10;
    number[k] = number[k] + 1;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (number[i] != 0) {
      printf("%d - %d\n", i, number[i]);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D4(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  je     L35
  nopl   0x0(%rax)
L33:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  test   %ecx,%ecx
  jne    L33
  movl   $0x0,0xc(%rsp)
L35:
  xor    %ebx,%ebx
  lea    0x10(%rsp),%rbp
  lea    D11(%rip),%r12
  jmp    L64
  nopl   (%rax)
L63:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  je     L1
L64:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  test   %edx,%edx
  je     L63
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L64
L1:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D11
type: string

tool: D4: %d

tool: D11: %d - %d


assistant: ```c
int main() {
  int number[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int i, n, k;
  scanf("%d", &n);
  while (n != 0) {
    k = n % 10;
    number[k] = number[k] + 1;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (number[i] != 0) {
      printf("%d - %d\n", i, number[i]);
    }
  }
  return 0;
}
```