ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<compute_all_bingham_dF1_2d>:
  endbr64
  push   %r15
  lea    D32(%rip),%rdi
  movq   %xmm1,%r15
  push   %r14
  movq   %xmm4,%r14
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x38,%rsp
  movsd  %xmm5,0x18(%rsp)
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm3,0x28(%rsp)
  call   <puts@plt>
  movq   %r15,%xmm5
  comisd 0x8(%rsp),%xmm5
  jb     L64
  nopw   0x0(%rax,%rax,1)
L52:
  movsd  0x28(%rsp),%xmm3
  movq   %r14,%xmm5
  comisd %xmm3,%xmm5
  movapd %xmm3,%xmm1
  jb     L32
  nopl   (%rax)
L25:
  comisd 0x8(%rsp),%xmm1
  movsd  %xmm1,0x10(%rsp)
  jae    L51
  pxor   %xmm0,%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm1
  movq   %r14,%xmm2
  addsd  0x18(%rsp),%xmm1
  comisd %xmm1,%xmm2
  jae    L25
L32:
  mov    %rbp,%rdi
  call   <puts@plt>
  movsd  0x8(%rsp),%xmm5
  movq   %r15,%xmm4
  addsd  0x20(%rsp),%xmm5
  comisd %xmm5,%xmm4
  movsd  %xmm5,0x8(%rsp)
  jae    L52
L64:
  add    $0x38,%rsp
  lea    D3(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r14
  pop    %r15
  jmp    1070 <puts@plt>
  nopl   0x0(%rax)
L51:
  movsd  0x8(%rsp),%xmm0
  call   <bingham_dF1_2d@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm1
  movq   %r14,%xmm4
  addsd  0x18(%rsp),%xmm1
  comisd %xmm1,%xmm4
  jae    L25
  jmp    L32
```

tool_calls: name: disassemble_data
arguments: data_tag: D32
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D32: dF1 = [ ...

tool: D14: ; ...

tool: D16: %f 

tool: D3: ];


assistant: ```c
void compute_all_bingham_dF1_2d(double z1_min, double z1_max, double z1_step, double z2_min, double z2_max, double z2_step) {
  double z1, z2;
  printf("dF1 = [ ...\n");
  for (z1 = z1_min; z1 <= z1_max; z1 += z1_step) {
    for (z2 = z2_min; z2 <= z2_max; z2 += z2_step)
      printf("%f ", z1 <= z2 ? bingham_dF1_2d(z1, z2) : 0.0);
    printf("; ...\n");
  }
  printf("];\n\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strdupped_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int strdupped_cmp(const void *a, const void *b) {
  char *c = *(char **)a;
  char *d = *(char **)b;
  return strcmp(c, d);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strdupped_cmp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int strdupped_cmp(const void *a, const void *b) {
  char *c = *(char **)a;
  char *d = *(char **)b;
  return strcmp(c, d);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdupped_cmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int strdupped_cmp(const void *a, const void *b) {
  char *c = *(char **)a;
  char *d = *(char **)b;
  return strcmp(c, d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strdupped_cmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int strdupped_cmp(const void *a, const void *b) {
  char *c = *(char **)a;
  char *d = *(char **)b;
  return strcmp(c, d);
}
```
user: What is the c source code of the assembly code below:

```asm
<initPerm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <mCalloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L16:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *initPerm(int size) {
  int *p;
  int i;
  p = (int *)mCalloc(size, sizeof(int));
  for (i = 0; i < size; i++)
    p[i] = i;
  return (p);
}
```
user: What is the c source code of the assembly code below:

```asm
<initPerm>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%esi
  call   <mCalloc@plt>
  test   %ebx,%ebx
  jle    L12
  mov    %rax,%rcx
  mov    $0x0,%edx
L5:
  mov    %edx,(%rcx)
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%ebx
  jne    L5
L12:
  pop    %rbx
  ret
```

assistant: ```c
int *initPerm(int size) {
  int *p;
  int i;
  p = (int *)mCalloc(size, sizeof(int));
  for (i = 0; i < size; i++)
    p[i] = i;
  return (p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<initPerm>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    %edi,%ebx
  call   <mCalloc@plt>
  test   %ebx,%ebx
  jle    L8
  mov    %rax,%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %edx,(%rcx)
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%ebx
  jne    L7
L8:
  pop    %rbx
  ret
```

assistant: ```c
int *initPerm(int size) {
  int *p;
  int i;
  p = (int *)mCalloc(size, sizeof(int));
  for (i = 0; i < size; i++)
    p[i] = i;
  return (p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initPerm>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    %edi,%ebx
  call   <mCalloc@plt>
  test   %ebx,%ebx
  jle    L62
  lea    -0x1(%rbx),%edx
  cmp    $0x2,%edx
  jbe    L24
  mov    %ebx,%ecx
  movdqa D12(%rip),%xmm0
  movdqa D1(%rip),%xmm2
  mov    %rax,%rdx
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  add    %rax,%rcx
  nopl   0x0(%rax)
L5:
  movdqa %xmm0,%xmm1
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rdx)
  cmp    %rcx,%rdx
  jne    L5
  mov    %ebx,%edx
  and    $0xfffffffc,%edx
  test   $0x3,%bl
  je     L62
L40:
  movslq %edx,%rcx
  mov    %edx,(%rax,%rcx,4)
  lea    0x0(,%rcx,4),%rsi
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%ebx
  jle    L62
  add    $0x2,%edx
  mov    %ecx,0x4(%rax,%rsi,1)
  cmp    %edx,%ebx
  jle    L62
  mov    %edx,0x8(%rax,%rsi,1)
L62:
  pop    %rbx
  ret
L24:
  xor    %edx,%edx
  jmp    L40
```

tool_calls: name: read_data
arguments: label: D12
type_infered: byte[16]
name: read_data
arguments: label: D1
type_infered: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D1": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int *initPerm(int size) {
  int *p;
  int i;
  p = (int *)mCalloc(size, sizeof(int));
  for (i = 0; i < size; i++)
    p[i] = i;
  return (p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scl_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L0:
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L36:
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mulss  -0x24(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L36
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void scl_data(float *data, int nsam, int nrec, float scl, float *datout, int nsamout) {
  int it, ix;
  for (ix = 0; ix < nrec; ix++) {
    for (it = 0; it < nsamout; it++)
      datout[ix * nsamout + it] = scl * data[ix * nsam + it];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scl_data>:
  endbr64
  test   %edx,%edx
  jle    L14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %rcx,%r12
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  mov    $0x0,%edi
  mov    %r8d,%esi
  jmp    L27
L5:
  movslq %r9d,%rax
  lea    (%r11,%rax,4),%rcx
  movslq %r10d,%rax
  lea    (%r12,%rax,4),%rdx
  mov    $0x0,%eax
L38:
  movaps %xmm0,%xmm1
  mulss  (%rcx,%rax,4),%xmm1
  movss  %xmm1,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L38
L21:
  add    $0x1,%edi
  add    %ebx,%r9d
  add    %r8d,%r10d
  cmp    %edi,%ebp
  je     L23
L27:
  test   %r8d,%r8d
  jg     L5
  jmp    L21
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  ret
```

assistant: ```c
void scl_data(float *data, int nsam, int nrec, float scl, float *datout, int nsamout) {
  int it, ix;
  for (ix = 0; ix < nrec; ix++) {
    for (it = 0; it < nsamout; it++)
      datout[ix * nsamout + it] = scl * data[ix * nsam + it];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scl_data>:
  endbr64
  test   %edx,%edx
  jle    L7
  push   %r13
  mov    %r8d,%r13d
  mov    %rdi,%r11
  xor    %r8d,%r8d
  push   %r12
  xor    %r10d,%r10d
  mov    %rcx,%r12
  xor    %r9d,%r9d
  push   %rbp
  lea    -0x1(%r13),%edi
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  nopl   0x0(%rax,%rax,1)
L15:
  test   %r13d,%r13d
  jle    L9
  movslq %r10d,%rax
  lea    (%r11,%rax,4),%rsi
  movslq %r8d,%rax
  lea    (%r12,%rax,4),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L19:
  movss  (%rsi,%rax,4),%xmm1
  mov    %rax,%rdx
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L19
L9:
  add    $0x1,%r9d
  add    %ebx,%r10d
  add    %r13d,%r8d
  cmp    %r9d,%ebp
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  ret
```

assistant: ```c
void scl_data(float *data, int nsam, int nrec, float scl, float *datout, int nsamout) {
  int it, ix;
  for (ix = 0; ix < nrec; ix++) {
    for (it = 0; it < nsamout; it++)
      datout[ix * nsamout + it] = scl * data[ix * nsam + it];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<scl_data>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %eax,-0x34(%rsp)
  mov    %edx,-0x18(%rsp)
  test   %edx,%edx
  jle    L84
  mov    %r8d,%ebx
  test   %r8d,%r8d
  jle    L84
  mov    %rax,-0x30(%rsp)
  shl    $0x2,%rax
  mov    %rdi,%r10
  mov    %rdi,%rdx
  mov    %rax,-0x28(%rsp)
  movslq %r8d,%rax
  movaps %xmm0,%xmm3
  movaps %xmm0,%xmm2
  mov    %rax,-0x20(%rsp)
  lea    -0x1(%r8),%eax
  mov    %rcx,%rsi
  xor    %ebp,%ebp
  mov    %eax,-0x14(%rsp)
  mov    %r8d,%eax
  xor    %r9d,%r9d
  xor    %edi,%edi
  shr    $0x2,%eax
  xor    %r12d,%r12d
  mov    %ebx,%r15d
  shufps $0xe0,%xmm3,%xmm3
  lea    -0x1(%rax),%r11d
  mov    %r8d,%eax
  xor    %r8d,%r8d
  shufps $0x0,%xmm2,%xmm2
  and    $0xfffffffc,%eax
  add    $0x1,%r11
  mov    %eax,-0x10(%rsp)
  mov    %ebx,%eax
  shl    $0x4,%r11
  and    $0x3,%eax
  mov    %eax,-0xc(%rsp)
  nopw   0x0(%rax,%rax,1)
L54:
  lea    (%rsi,%r8,4),%rax
  lea    0x4(%rdx),%r13
  mov    %rax,%rcx
  sub    %r13,%rcx
  cmp    $0x8,%rcx
  jbe    L59
  cmp    $0x1,%ebx
  je     L59
  cmpl   $0x2,-0x14(%rsp)
  jbe    L19
  xor    %ecx,%ecx
  xchg   %ax,%ax
L13:
  movups (%rdx,%rcx,1),%xmm1
  mulps  %xmm2,%xmm1
  movups %xmm1,(%rax,%rcx,1)
  add    $0x10,%rcx
  cmp    %r11,%rcx
  jne    L13
  mov    -0x10(%rsp),%eax
  cmp    %eax,%ebx
  je     L50
  mov    -0xc(%rsp),%ecx
  mov    %ecx,%r13d
  cmp    $0x1,%ecx
  je     L113
  mov    %eax,%ecx
L46:
  lea    0x0(%rbp,%rcx,1),%r14
  add    %r8,%rcx
  movq   (%r10,%r14,4),%xmm1
  mulps  %xmm3,%xmm1
  movlps %xmm1,(%rsi,%rcx,4)
  mov    %r13d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r13d
  je     L50
L113:
  lea    (%r9,%rax,1),%ecx
  add    %edi,%eax
  cltq
  movslq %ecx,%rcx
  movss  (%r10,%rax,4),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rsi,%rcx,4)
L50:
  add    $0x1,%r12d
  add    -0x28(%rsp),%rdx
  add    -0x34(%rsp),%edi
  add    %ebx,%r9d
  add    -0x30(%rsp),%rbp
  add    -0x20(%rsp),%r8
  cmp    %r12d,-0x18(%rsp)
  jne    L54
L84:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L59:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L5:
  movss  (%rdx,%rcx,4),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %r15,%rcx
  jne    L5
  jmp    L50
L19:
  mov    %ebx,%r13d
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L46
```

assistant: ```c
void scl_data(float *data, int nsam, int nrec, float scl, float *datout, int nsamout) {
  int it, ix;
  for (ix = 0; ix < nrec; ix++) {
    for (it = 0; it < nsamout; it++)
      datout[ix * nsamout + it] = scl * data[ix * nsam + it];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <getlogin@plt>
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rdi
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rsi
  mov    -0x8(%rbp),%rax
  mov    0xc(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <getpwnam@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rdi
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rsi
  mov    -0x8(%rbp),%rax
  mov    0xc(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string
name: retrieve_data
arguments: label: D32
type: string
name: retrieve_data
arguments: label: D45
type: string
name: retrieve_data
arguments: label: D23
type: string
name: retrieve_data
arguments: label: D18
type: string

tool: D3: User is %s.


tool: D32: User IDs: uid = %d, gid = %d.


tool: D45: UID passwd entry:
 name = %s, uid = %d, gid = %d, home = %s, shell = %s.


tool: D23: root

tool: D18: root passwd entry:
 name = %s, uid = %d, git = %d, home = %s, shell = %s.


assistant: ```c
int main() {
  uid_t uid;
  gid_t gid;
  struct passwd *pw;
  uid = getuid();
  gid = getgid();
  printf("User is %s.\n", getlogin());
  printf("User IDs: uid = %d, gid = %d.\n", uid, gid);
  pw = getpwuid(uid);
  printf("UID passwd entry:\n name = %s, uid = %d, gid = %d, home = %s, shell = %s.\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_dir, pw->pw_shell);
  pw = getpwnam("root");
  printf("root passwd entry:\n name = %s, uid = %d, git = %d, home = %s, shell = %s.\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_dir, pw->pw_shell);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <getlogin@plt>
  mov    %rax,%rsi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <getpwuid@plt>
  mov    0xc(%rax),%ecx
  mov    0x8(%rax),%edx
  mov    0x18(%rax),%r9
  mov    0x10(%rax),%r8
  mov    (%rax),%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <getpwnam@plt>
  mov    0xc(%rax),%ecx
  mov    0x8(%rax),%edx
  mov    0x18(%rax),%r9
  mov    0x10(%rax),%r8
  mov    (%rax),%rsi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D34
type: string
name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D45
type: string
name: read_data
arguments: tag: D42
type: string
name: read_data
arguments: tag: D47
type: string

tool: D34: User is %s.


tool: D8: User IDs: uid = %d, gid = %d.


tool: D45: UID passwd entry:
 name = %s, uid = %d, gid = %d, home = %s, shell = %s.


tool: D42: root

tool: D47: root passwd entry:
 name = %s, uid = %d, git = %d, home = %s, shell = %s.


assistant: ```c
int main() {
  uid_t uid;
  gid_t gid;
  struct passwd *pw;
  uid = getuid();
  gid = getgid();
  printf("User is %s.\n", getlogin());
  printf("User IDs: uid = %d, gid = %d.\n", uid, gid);
  pw = getpwuid(uid);
  printf("UID passwd entry:\n name = %s, uid = %d, gid = %d, home = %s, shell = %s.\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_dir, pw->pw_shell);
  pw = getpwnam("root");
  printf("root passwd entry:\n name = %s, uid = %d, git = %d, home = %s, shell = %s.\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_dir, pw->pw_shell);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <getuid@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getlogin@plt>
  lea    D11(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <getpwuid@plt>
  lea    D0(%rip),%rdi
  mov    0xc(%rax),%ecx
  mov    0x8(%rax),%edx
  mov    0x18(%rax),%r9
  mov    0x10(%rax),%r8
  mov    (%rax),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <getpwnam@plt>
  lea    D28(%rip),%rdi
  mov    0xc(%rax),%ecx
  mov    0x8(%rax),%edx
  mov    0x18(%rax),%r9
  mov    0x10(%rax),%r8
  mov    (%rax),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_infered: string
name: retrieve_data
arguments: data_label: D48
type_infered: string
name: retrieve_data
arguments: data_label: D0
type_infered: string
name: retrieve_data
arguments: data_label: D39
type_infered: string
name: retrieve_data
arguments: data_label: D28
type_infered: string

tool: D11: User is %s.


tool: D48: User IDs: uid = %d, gid = %d.


tool: D0: UID passwd entry:
 name = %s, uid = %d, gid = %d, home = %s, shell = %s.


tool: D39: root

tool: D28: root passwd entry:
 name = %s, uid = %d, git = %d, home = %s, shell = %s.


assistant: ```c
int main() {
  uid_t uid;
  gid_t gid;
  struct passwd *pw;
  uid = getuid();
  gid = getgid();
  printf("User is %s.\n", getlogin());
  printf("User IDs: uid = %d, gid = %d.\n", uid, gid);
  pw = getpwuid(uid);
  printf("UID passwd entry:\n name = %s, uid = %d, gid = %d, home = %s, shell = %s.\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_dir, pw->pw_shell);
  pw = getpwnam("root");
  printf("root passwd entry:\n name = %s, uid = %d, git = %d, home = %s, shell = %s.\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_dir, pw->pw_shell);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <getuid@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getlogin@plt>
  lea    D38(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <getpwuid@plt>
  lea    D4(%rip),%rdi
  mov    0xc(%rax),%ecx
  mov    0x8(%rax),%edx
  mov    0x18(%rax),%r9
  mov    0x10(%rax),%r8
  mov    (%rax),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <getpwnam@plt>
  lea    D0(%rip),%rdi
  mov    0xc(%rax),%ecx
  mov    0x8(%rax),%edx
  mov    0x18(%rax),%r9
  mov    0x10(%rax),%r8
  mov    (%rax),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D38: User is %s.


tool: D6: User IDs: uid = %d, gid = %d.


tool: D4: UID passwd entry:
 name = %s, uid = %d, gid = %d, home = %s, shell = %s.


tool: D12: root

tool: D0: root passwd entry:
 name = %s, uid = %d, git = %d, home = %s, shell = %s.


assistant: ```c
int main() {
  uid_t uid;
  gid_t gid;
  struct passwd *pw;
  uid = getuid();
  gid = getgid();
  printf("User is %s.\n", getlogin());
  printf("User IDs: uid = %d, gid = %d.\n", uid, gid);
  pw = getpwuid(uid);
  printf("UID passwd entry:\n name = %s, uid = %d, gid = %d, home = %s, shell = %s.\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_dir, pw->pw_shell);
  pw = getpwnam("root");
  printf("root passwd entry:\n name = %s, uid = %d, git = %d, home = %s, shell = %s.\n", pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_dir, pw->pw_shell);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<readline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L26
  mov    $0x0,%eax
  jmp    L2
L13:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  imul   -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L57
L26:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x20(%rbp),%rdx
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L35
  mov    -0x20(%rbp),%rax
  lea    -0x2(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L13
  jmp    L35
L57:
  nop
L35:
  mov    -0x10(%rbp),%rax
L2:
  leave
  ret
```

assistant: ```c
char *readline(FILE *fp, size_t size) {
  char *buff = (char *)malloc(size * sizeof(char));
  size_t times = 1;
  if (fgets(buff, size, fp) == NULL)
    return NULL;
  while ((strlen(buff) == size - 1) && buff[size - 2] != '\n') {
    buff = (char *)realloc(buff, ++times * size * sizeof(char));
    if (fgets(buff + (times - 1) * size - 1, size, fp) == NULL)
      break;
  }
  return buff;
}
```