ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_int2str>:
  endbr64
  push   %rbx
  mov    %rsi,%r8
  test   %rdi,%rdi
  jne    L4
  lea    0x1(%rsi),%rbx
  movb   $0x30,(%rsi)
  movb   $0x0,0x1(%rsi)
L14:
  mov    %rbx,%rax
  pop    %rbx
  ret
L4:
  mov    %rdi,%rcx
  neg    %rcx
  cmovs  %rdi,%rcx
  mov    %rsi,%rbx
  movabs $0x6666666666666667,%r9
L19:
  mov    %rbx,%r10
  add    $0x1,%rbx
  mov    %rcx,%rax
  imul   %r9
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  mov    %rcx,%rax
  sub    %rsi,%rax
  add    $0x30,%eax
  mov    %al,-0x1(%rbx)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  cmp    $0x9,%rax
  jg     L19
  test   %rdi,%rdi
  js     L44
L38:
  movb   $0x0,(%rbx)
  mov    %rbx,%rsi
  mov    %r8,%rdi
  call   <reverse_string@plt>
  jmp    L14
L44:
  movb   $0x2d,(%rbx)
  lea    0x2(%r10),%rbx
  jmp    L38
```

assistant: ```c
char *_int2str(long val, char *out) {
  char *p = out;
  if (val == 0) {
    *p++ = '0';
    *p = 0;
  } else {
    int neg = val < 0;
    if (neg)
      val = -val;
    while (val > 0) {
      *p++ = (val % 10) + '0';
      val /= 10;
    }
    if (neg)
      *p++ = '-';
    *p = 0;
    reverse_string(out, p);
  }
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_int2str>:
  endbr64
  push   %r12
  mov    %rsi,%r8
  test   %rdi,%rdi
  jne    L1
  lea    0x1(%rsi),%r12
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  mov    %r12,%rax
  pop    %r12
  ret
L1:
  mov    %rdi,%rcx
  mov    %rsi,%r12
  movabs $0xcccccccccccccccd,%rsi
  neg    %rcx
  cmovs  %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %rcx,%rax
  mov    %r12,%r9
  add    $0x1,%r12
  mul    %rsi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r12)
  mov    %rdx,%rcx
  test   %rdx,%rdx
  jne    L30
  test   %rdi,%rdi
  js     L16
  movb   $0x0,(%r12)
  mov    %r12,%rsi
  mov    %r8,%rdi
  call   <reverse_string@plt>
L2:
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  movb   $0x2d,(%r12)
  lea    0x2(%r9),%r12
  mov    %r8,%rdi
  mov    %r12,%rsi
  movb   $0x0,(%r12)
  call   <reverse_string@plt>
  jmp    L2
```

assistant: ```c
char *_int2str(long val, char *out) {
  char *p = out;
  if (val == 0) {
    *p++ = '0';
    *p = 0;
  } else {
    int neg = val < 0;
    if (neg)
      val = -val;
    while (val > 0) {
      *p++ = (val % 10) + '0';
      val /= 10;
    }
    if (neg)
      *p++ = '-';
    *p = 0;
    reverse_string(out, p);
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_int2str>:
  endbr64
  push   %r12
  mov    %rsi,%r8
  test   %rdi,%rdi
  jne    L0
  lea    0x1(%rsi),%r12
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  mov    %r12,%rax
  pop    %r12
  ret
L0:
  mov    %rdi,%rcx
  mov    %rsi,%r12
  movabs $0xcccccccccccccccd,%rsi
  neg    %rcx
  cmovs  %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %rcx,%rax
  mov    %r12,%r9
  add    $0x1,%r12
  mul    %rsi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r12)
  mov    %rdx,%rcx
  test   %rdx,%rdx
  jne    L34
  test   %rdi,%rdi
  js     L26
  movb   $0x0,(%r12)
  mov    %r12,%rsi
  mov    %r8,%rdi
  call   <reverse_string@plt>
L14:
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  movb   $0x2d,(%r12)
  lea    0x2(%r9),%r12
  mov    %r8,%rdi
  mov    %r12,%rsi
  movb   $0x0,(%r12)
  call   <reverse_string@plt>
  jmp    L14
```

assistant: ```c
char *_int2str(long val, char *out) {
  char *p = out;
  if (val == 0) {
    *p++ = '0';
    *p = 0;
  } else {
    int neg = val < 0;
    if (neg)
      val = -val;
    while (val > 0) {
      *p++ = (val % 10) + '0';
      val /= 10;
    }
    if (neg)
      *p++ = '-';
    *p = 0;
    reverse_string(out, p);
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<eslib_string_to_s64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  mov    D98(%rip),%rax
  movq   $0x0,(%rax)
  cmpl   $0xa,-0x34(%rbp)
  je     L137
  mov    D12(%rip),%rax
  mov    (%rax),%rdx
  mov    D98(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L54
L137:
  cmpb   $0x2f,-0x15(%rbp)
  jle    L15
  cmpb   $0x39,-0x15(%rbp)
  jle    L61
L15:
  cmpb   $0x2d,-0x15(%rbp)
  je     L61
  cmpb   $0x2b,-0x15(%rbp)
  je     L61
  mov    D43(%rip),%rax
  mov    (%rax),%rdx
  mov    D98(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L54
L61:
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  je     L60
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
  mov    D98(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L103
L60:
  mov    D98(%rip),%rax
  mov    (%rax),%rdx
  mov    D93(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L18
  mov    D114(%rip),%rax
  mov    (%rax),%rdx
  mov    D98(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L139
L18:
  mov    D43(%rip),%rax
  mov    (%rax),%rdx
  mov    D98(%rip),%rax
  mov    %rdx,(%rax)
L139:
  mov    $0xffffffff,%eax
  jmp    L54
L103:
  mov    -0x30(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L54:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int eslib_string_to_s64(char *str, int64_t *out, int base) {
  int64_t ret;
  char *err = NULL;
  char c = str[0];
  errno = 0;
  if (base != 10) {
    errno = EINVAL;
    return -1;
  }
  if ((c < '0' || c > '9') && c != '-' && c != '+') {
    errno = EIO;
    return -1;
  }
  ret = strtoll(str, &err, 10);
  if (err == NULL || *err || errno) {
    if (errno == ERANGE)
      errno = EOVERFLOW;
    else
      errno = EIO;
    return -1;
  }
  *out = ret;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<eslib_string_to_s64>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movzbl (%rdi),%eax
  mov    D97(%rip),%rcx
  movq   $0x0,(%rcx)
  cmp    $0xa,%edx
  jne    L103
  mov    %rsi,%rbx
  lea    -0x2b(%rax),%edx
  test   $0xfd,%dl
  je     L6
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L63
L6:
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtoll@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  je     L109
  cmpb   $0x0,(%rdx)
  jne    L109
  mov    D97(%rip),%rdx
  cmpq   $0x0,(%rdx)
  jne    L109
  mov    %eax,(%rbx)
  mov    $0x0,%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  ret
L103:
  mov    D60(%rip),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    $0xffffffff,%eax
  jmp    L29
L63:
  mov    D82(%rip),%rax
  mov    (%rax),%rdx
  mov    D97(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L29
L109:
  mov    D97(%rip),%rdx
  mov    D105(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L44
  mov    D82(%rip),%rax
  mov    (%rax),%rdx
  mov    D97(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L29
L44:
  mov    D46(%rip),%rax
  mov    (%rax),%rdx
  mov    D97(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L29
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eslib_string_to_s64(char *str, int64_t *out, int base) {
  int64_t ret;
  char *err = NULL;
  char c = str[0];
  errno = 0;
  if (base != 10) {
    errno = EINVAL;
    return -1;
  }
  if ((c < '0' || c > '9') && c != '-' && c != '+') {
    errno = EIO;
    return -1;
  }
  ret = strtoll(str, &err, 10);
  if (err == NULL || *err || errno) {
    if (errno == ERANGE)
      errno = EOVERFLOW;
    else
      errno = EIO;
    return -1;
  }
  *out = ret;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eslib_string_to_s64>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D32(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  movq   $0x0,(%rsp)
  movq   $0x0,(%rbx)
  cmp    $0xa,%edx
  jne    L81
  lea    -0x2b(%rax),%edx
  mov    %rsi,%rbp
  and    $0xfd,%edx
  je     L48
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L101
L48:
  mov    $0xa,%edx
  mov    %rsp,%rsi
  call   <strtoll@plt>
  mov    (%rsp),%rdx
  mov    (%rbx),%rcx
  test   %rdx,%rdx
  je     L3
  cmpb   $0x0,(%rdx)
  jne    L3
  test   %rcx,%rcx
  jne    L3
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L67
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L101:
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L31
  nopl   0x0(%rax)
L3:
  mov    D25(%rip),%rax
  cmp    (%rax),%rcx
  jne    L101
  mov    D45(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L81:
  mov    D48(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L31
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eslib_string_to_s64(char *str, int64_t *out, int base) {
  int64_t ret;
  char *err = NULL;
  char c = str[0];
  errno = 0;
  if (base != 10) {
    errno = EINVAL;
    return -1;
  }
  if ((c < '0' || c > '9') && c != '-' && c != '+') {
    errno = EIO;
    return -1;
  }
  ret = strtoll(str, &err, 10);
  if (err == NULL || *err || errno) {
    if (errno == ERANGE)
      errno = EOVERFLOW;
    else
      errno = EIO;
    return -1;
  }
  *out = ret;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<eslib_string_to_s64>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D29(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  movq   $0x0,(%rsp)
  movq   $0x0,(%rbx)
  cmp    $0xa,%edx
  jne    L41
  lea    -0x2b(%rax),%edx
  mov    %rsi,%rbp
  and    $0xfd,%edx
  je     L1
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L92
L1:
  mov    $0xa,%edx
  mov    %rsp,%rsi
  call   <strtoll@plt>
  mov    (%rsp),%rdx
  mov    (%rbx),%rcx
  test   %rdx,%rdx
  je     L96
  cmpb   $0x0,(%rdx)
  jne    L96
  test   %rcx,%rcx
  jne    L96
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L105
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L92:
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L29
  nopl   0x0(%rax)
L96:
  mov    D47(%rip),%rax
  cmp    (%rax),%rcx
  jne    L92
  mov    D23(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L41:
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L29
L105:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eslib_string_to_s64(char *str, int64_t *out, int base) {
  int64_t ret;
  char *err = NULL;
  char c = str[0];
  errno = 0;
  if (base != 10) {
    errno = EINVAL;
    return -1;
  }
  if ((c < '0' || c > '9') && c != '-' && c != '+') {
    errno = EIO;
    return -1;
  }
  ret = strtoll(str, &err, 10);
  if (err == NULL || *err || errno) {
    if (errno == ERANGE)
      errno = EOVERFLOW;
    else
      errno = EIO;
    return -1;
  }
  *out = ret;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<BitStream_writeNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L14
L39:
  mov    -0x34(%rbp),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L0
  mov    -0x8(%rbp),%rax
  movb   $0x1,(%rax)
  jmp    L33
L0:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L33:
  addq   $0x1,-0x8(%rbp)
  shrl   -0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L39
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BitStream_writeNum(unsigned char *dest, size_t bits, unsigned int num) {
  unsigned int mask;
  size_t i;
  unsigned char *p;
  p = dest;
  mask = 1 << (bits - 1);
  for (i = 0; i < bits; i++) {
    if (num & mask) {
      *p = 1;
    } else {
      *p = 0;
    }
    p++;
    mask = mask >> 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<BitStream_writeNum>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %rsi,%rsi
  je     L17
  add    %rdi,%rsi
L6:
  test   %eax,%edx
  setne  (%rdi)
  add    $0x1,%rdi
  shr    %eax
  cmp    %rdi,%rsi
  jne    L6
L17:
  ret
```

assistant: ```c
void BitStream_writeNum(unsigned char *dest, size_t bits, unsigned int num) {
  unsigned int mask;
  size_t i;
  unsigned char *p;
  p = dest;
  mask = 1 << (bits - 1);
  for (i = 0; i < bits; i++) {
    if (num & mask) {
      *p = 1;
    } else {
      *p = 0;
    }
    p++;
    mask = mask >> 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<BitStream_writeNum>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %rsi,%rsi
  je     L15
  add    %rdi,%rsi
  cs nopw 0x0(%rax,%rax,1)
L17:
  test   %eax,%edx
  setne  (%rdi)
  add    $0x1,%rdi
  shr    %eax
  cmp    %rsi,%rdi
  jne    L17
L15:
  ret
```

assistant: ```c
void BitStream_writeNum(unsigned char *dest, size_t bits, unsigned int num) {
  unsigned int mask;
  size_t i;
  unsigned char *p;
  p = dest;
  mask = 1 << (bits - 1);
  for (i = 0; i < bits; i++) {
    if (num & mask) {
      *p = 1;
    } else {
      *p = 0;
    }
    p++;
    mask = mask >> 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BitStream_writeNum>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %rsi,%rsi
  je     L2
  add    %rdi,%rsi
  cs nopw 0x0(%rax,%rax,1)
L10:
  test   %eax,%edx
  setne  (%rdi)
  add    $0x1,%rdi
  shr    %eax
  cmp    %rsi,%rdi
  jne    L10
L2:
  ret
```

assistant: ```c
void BitStream_writeNum(unsigned char *dest, size_t bits, unsigned int num) {
  unsigned int mask;
  size_t i;
  unsigned char *p;
  p = dest;
  mask = 1 << (bits - 1);
  for (i = 0; i < bits; i++) {
    if (num & mask) {
      *p = 1;
    } else {
      *p = 0;
    }
    p++;
    mask = mask >> 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmpstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L57
L34:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L12
  mov    $0x1,%eax
  jmp    L51
L12:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L57:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
L26:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  mov    $0x0,%eax
  jmp    L51
L47:
  mov    $0x1,%eax
L51:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long cmpstr(unsigned char *str1, unsigned char *str2) {
  unsigned char *tmpstr1;
  unsigned char *tmpstr2;
  tmpstr1 = str1;
  tmpstr2 = str2;
  while ((*tmpstr1 != 0) && (*tmpstr2 != 0)) {
    if ((*tmpstr1) != (*tmpstr2))
      return 1;
    tmpstr1++;
    tmpstr2++;
  }
  if ((*tmpstr1 == 0) && (*tmpstr2 == 0)) {
    return 0;
  } else {
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmpstr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
L27:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L29
  cmp    %al,%dl
  jne    L36
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L27
L19:
  cmpb   $0x0,(%rsi)
  setne  %al
  movzbl %al,%eax
  ret
L36:
  mov    $0x1,%eax
  ret
L29:
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
unsigned long cmpstr(unsigned char *str1, unsigned char *str2) {
  unsigned char *tmpstr1;
  unsigned char *tmpstr2;
  tmpstr1 = str1;
  tmpstr2 = str2;
  while ((*tmpstr1 != 0) && (*tmpstr2 != 0)) {
    if ((*tmpstr1) != (*tmpstr2))
      return 1;
    tmpstr1++;
    tmpstr2++;
  }
  if ((*tmpstr1 == 0) && (*tmpstr2 == 0)) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmpstr>:
  endbr64
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L33:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L15
  cmp    %al,%dl
  jne    L15
  add    $0x1,%rdi
  add    $0x1,%rsi
L25:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L33
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  setne  %al
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long cmpstr(unsigned char *str1, unsigned char *str2) {
  unsigned char *tmpstr1;
  unsigned char *tmpstr2;
  tmpstr1 = str1;
  tmpstr2 = str2;
  while ((*tmpstr1 != 0) && (*tmpstr2 != 0)) {
    if ((*tmpstr1) != (*tmpstr2))
      return 1;
    tmpstr1++;
    tmpstr2++;
  }
  if ((*tmpstr1 == 0) && (*tmpstr2 == 0)) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmpstr>:
  endbr64
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L9:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L28
  cmp    %al,%dl
  jne    L28
  add    $0x1,%rdi
  add    $0x1,%rsi
L14:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L9
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  setne  %al
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long cmpstr(unsigned char *str1, unsigned char *str2) {
  unsigned char *tmpstr1;
  unsigned char *tmpstr2;
  tmpstr1 = str1;
  tmpstr2 = str2;
  while ((*tmpstr1 != 0) && (*tmpstr2 != 0)) {
    if ((*tmpstr1) != (*tmpstr2))
      return 1;
    tmpstr1++;
    tmpstr2++;
  }
  if ((*tmpstr1 == 0) && (*tmpstr2 == 0)) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(unsigned *a, unsigned *b) {
  unsigned tmp = *a;
  *a = *b;
  *b = tmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(unsigned *a, unsigned *b) {
  unsigned tmp = *a;
  *a = *b;
  *b = tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(unsigned *a, unsigned *b) {
  unsigned tmp = *a;
  *a = *b;
  *b = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(unsigned *a, unsigned *b) {
  unsigned tmp = *a;
  *a = *b;
  *b = tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L15
  jmp    L26
L42:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L26
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L26:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L42
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L27
L15:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L27:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D38
data_type: string

tool: D4: %d

tool: D38: Ne e vnesen broj.

assistant: ```c
int main() {
  int n, max;
  if (scanf("%d", &max)) {
    while (scanf("%d", &n)) {
      if (max < n) {
        max = n;
      }
    }
    printf("%d", max);
  } else {
    printf("Ne e vnesen broj.");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  lea    D0(%rip),%rbx
  test   %rax,%rax
  je     L52
L32:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L18
  mov    (%rsp),%eax
  cmp    %eax,0x4(%rsp)
  jge    L32
  mov    %eax,0x4(%rsp)
  jmp    L32
L18:
  mov    0x4(%rsp),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L52:
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D1
data_type: string

tool: D0: %d

tool: D1: Ne e vnesen broj.

assistant: ```c
int main() {
  int n, max;
  if (scanf("%d", &max)) {
    while (scanf("%d", &n)) {
      if (max < n) {
        max = n;
      }
    }
    printf("%d", max);
  } else {
    printf("Ne e vnesen broj.");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rbx
  call   <scanf@plt>
  test   %rax,%rax
  jne    L39
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L51:
  mov    (%rsp),%eax
  cmp    %eax,0x4(%rsp)
  jl     L14
L39:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L51
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L57:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    %eax,0x4(%rsp)
  jmp    L39
L11:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L57
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_infered: string
name: unpack_data
arguments: data_tag: D19
type_infered: string

tool: D17: %d

tool: D19: Ne e vnesen broj.

assistant: ```c
int main() {
  int n, max;
  if (scanf("%d", &max)) {
    while (scanf("%d", &n)) {
      if (max < n) {
        max = n;
      }
    }
    printf("%d", max);
  } else {
    printf("Ne e vnesen broj.");
  }
  return 0;
}
```