ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<upper_aligned>:
  endbr64
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  push   %rbx
  mov    %esi,%ebx
  cvtsi2ss %edi,%xmm0
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  call   <ceil@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int upper_aligned(int number, int align) {
  int partial = (int)ceil(((float)number) / ((float)align));
  return (partial * align);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L78
  jmp    L26
L48:
  subl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss -0x4(%rbp),%xmm0
  jb     L21
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L48
L21:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  jmp    L8
L51:
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  movss  -0x4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jb     L38
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L51
L38:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L10
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
L78:
  nop
  leave
  ret
```

assistant: ```c
void quicksort(float c[], int low, int high) {
  int i = low;
  int j = high;
  float temp = c[i];
  if (low < high) {
    while (i < j) {
      while ((c[j] >= temp) && (i < j)) {
        j--;
      }
      c[i] = c[j];
      while ((c[i] <= temp) && (i < j)) {
        i++;
      }
      c[j] = c[i];
    }
    c[i] = temp;
    quicksort(c, low, i - 1);
    quicksort(c, j + 1, high);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jge    L31
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r8d
  mov    %edx,%r12d
  movslq %esi,%rax
  movss  (%rdi,%rax,4),%xmm1
  mov    %edx,%ebx
  mov    %esi,%edx
  jmp    L82
L42:
  movslq %edx,%rax
  movss  %xmm0,0x0(%rbp,%rax,4)
  cmp    %ebx,%edx
  jge    L97
  comiss %xmm0,%xmm1
  jb     L97
  add    $0x1,%edx
  movslq %edx,%rax
L33:
  mov    %eax,%edx
  movss  0x0(%rbp,%rax,4),%xmm0
  cmp    %eax,%ebx
  setg   %sil
  comiss %xmm0,%xmm1
  setae  %cl
  add    $0x1,%rax
  test   %cl,%sil
  jne    L33
L97:
  movss  %xmm0,(%rdi)
  cmp    %ebx,%edx
  jge    L0
L82:
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  movss  (%rdi),%xmm0
  cmp    %ebx,%edx
  jge    L42
  lea    -0x4(%rbp,%rax,4),%rax
  comiss %xmm1,%xmm0
  jb     L42
L19:
  sub    $0x1,%ebx
  mov    %rax,%rdi
  movss  (%rax),%xmm0
  sub    $0x4,%rax
  cmp    %edx,%ebx
  jle    L42
  comiss %xmm1,%xmm0
  jae    L19
  jmp    L42
L0:
  movslq %edx,%rax
  movss  %xmm1,0x0(%rbp,%rax,4)
  sub    $0x1,%edx
  mov    %r8d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quicksort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  ret
```

assistant: ```c
void quicksort(float c[], int low, int high) {
  int i = low;
  int j = high;
  float temp = c[i];
  if (low < high) {
    while (i < j) {
      while ((c[j] >= temp) && (i < j)) {
        j--;
      }
      c[i] = c[j];
      while ((c[i] <= temp) && (i < j)) {
        i++;
      }
      c[j] = c[i];
    }
    c[i] = temp;
    quicksort(c, low, i - 1);
    quicksort(c, j + 1, high);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quicksort>:
  endbr64
  movslq %esi,%rax
  mov    %rax,%r8
  lea    (%rdi,%rax,4),%rax
  cmp    %edx,%r8d
  jge    L86
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L91:
  movss  (%rax),%xmm1
  mov    %r12d,%ebx
  mov    %r8d,%eax
  nopl   0x0(%rax,%rax,1)
L96:
  movslq %ebx,%rdx
  cmp    %ebx,%eax
  lea    0x0(%rbp,%rdx,4),%rsi
  setl   %cl
  movss  (%rsi),%xmm0
  comiss %xmm1,%xmm0
  jb     L75
  lea    -0x4(%rbp,%rdx,4),%rdx
  jmp    L26
  nopl   (%rax)
L30:
  movss  (%rdx),%xmm0
  sub    $0x1,%ebx
  mov    %rdx,%rsi
  cmp    %eax,%ebx
  setg   %cl
  sub    $0x4,%rdx
  comiss %xmm1,%xmm0
  jb     L75
L26:
  test   %cl,%cl
  jne    L30
L75:
  movslq %eax,%rdx
  shl    $0x2,%rdx
  comiss %xmm0,%xmm1
  lea    0x0(%rbp,%rdx,1),%rdi
  movss  %xmm0,(%rdi)
  jb     L57
  test   %cl,%cl
  je     L57
  lea    0x4(%rbp,%rdx,1),%rdx
  jmp    L119
  nopl   0x0(%rax)
L31:
  cmp    %ebx,%eax
  jge    L57
L119:
  movss  (%rdx),%xmm0
  add    $0x1,%eax
  mov    %rdx,%rdi
  add    $0x4,%rdx
  comiss %xmm0,%xmm1
  jae    L31
L57:
  movss  %xmm0,(%rsi)
  cmp    %ebx,%eax
  jl     L96
  movss  %xmm1,(%rdi)
  lea    -0x1(%rax),%edx
  mov    %r8d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%rbx),%r8d
  movslq %r8d,%rax
  lea    0x0(%rbp,%rax,4),%rax
  cmp    %r12d,%r8d
  jl     L91
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L86:
  ret
```

assistant: ```c
void quicksort(float c[], int low, int high) {
  int i = low;
  int j = high;
  float temp = c[i];
  if (low < high) {
    while (i < j) {
      while ((c[j] >= temp) && (i < j)) {
        j--;
      }
      c[i] = c[j];
      while ((c[i] <= temp) && (i < j)) {
        i++;
      }
      c[j] = c[i];
    }
    c[i] = temp;
    quicksort(c, low, i - 1);
    quicksort(c, j + 1, high);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quicksort>:
  endbr64
  movslq %esi,%rax
  mov    %rax,%r8
  lea    (%rdi,%rax,4),%rax
  cmp    %edx,%r8d
  jge    L53
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L3:
  movss  (%rax),%xmm1
  mov    %r12d,%ebx
  mov    %r8d,%eax
  nopl   0x0(%rax,%rax,1)
L85:
  movslq %ebx,%rdx
  cmp    %ebx,%eax
  lea    0x0(%rbp,%rdx,4),%rsi
  setl   %cl
  movss  (%rsi),%xmm0
  comiss %xmm1,%xmm0
  jb     L62
  lea    -0x4(%rbp,%rdx,4),%rdx
  jmp    L63
  nopl   (%rax)
L17:
  movss  (%rdx),%xmm0
  sub    $0x1,%ebx
  mov    %rdx,%rsi
  cmp    %eax,%ebx
  setg   %cl
  sub    $0x4,%rdx
  comiss %xmm1,%xmm0
  jb     L62
L63:
  test   %cl,%cl
  jne    L17
L62:
  movslq %eax,%rdx
  shl    $0x2,%rdx
  comiss %xmm0,%xmm1
  lea    0x0(%rbp,%rdx,1),%rdi
  movss  %xmm0,(%rdi)
  jb     L66
  test   %cl,%cl
  je     L66
  lea    0x4(%rbp,%rdx,1),%rdx
  jmp    L25
  nopl   0x0(%rax)
L56:
  cmp    %ebx,%eax
  jge    L66
L25:
  movss  (%rdx),%xmm0
  add    $0x1,%eax
  mov    %rdx,%rdi
  add    $0x4,%rdx
  comiss %xmm0,%xmm1
  jae    L56
L66:
  movss  %xmm0,(%rsi)
  cmp    %ebx,%eax
  jl     L85
  movss  %xmm1,(%rdi)
  lea    -0x1(%rax),%edx
  mov    %r8d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%rbx),%r8d
  movslq %r8d,%rax
  lea    0x0(%rbp,%rax,4),%rax
  cmp    %r12d,%r8d
  jl     L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  ret
```

assistant: ```c
void quicksort(float c[], int low, int high) {
  int i = low;
  int j = high;
  float temp = c[i];
  if (low < high) {
    while (i < j) {
      while ((c[j] >= temp) && (i < j)) {
        j--;
      }
      c[i] = c[j];
      while ((c[i] <= temp) && (i < j)) {
        i++;
      }
      c[j] = c[i];
    }
    c[i] = temp;
    quicksort(c, low, i - 1);
    quicksort(c, j + 1, high);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xor128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D115(%rip),%eax
  shl    $0xb,%eax
  mov    %eax,%edx
  mov    D115(%rip),%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    D32(%rip),%eax
  mov    %eax,D119(%rip)
  mov    D119(%rip),%eax
  mov    %eax,D78(%rip)
  mov    D78(%rip),%eax
  mov    %eax,D68(%rip)
  mov    D78(%rip),%eax
  shr    $0x13,%eax
  mov    %eax,%edx
  mov    D78(%rip),%eax
  xor    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  xor    -0x4(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,D68(%rip)
  mov    D68(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int xor128() {
  static unsigned int x = 123456789;
  static unsigned int y = 362436069;
  static unsigned int z = 521288629;
  static unsigned int w = 88675123;
  unsigned int t;
  t = x ^ (x << 11);
  x = y;
  y = z;
  z = w;
  return w = w ^ (w >> 19) ^ (t ^ (t >> 8));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xor128>:
  endbr64
  mov    D66(%rip),%eax
  mov    %eax,%edx
  shl    $0xb,%edx
  xor    %eax,%edx
  mov    D70(%rip),%eax
  mov    %eax,D34(%rip)
  mov    D34(%rip),%eax
  mov    %eax,D42(%rip)
  mov    D42(%rip),%ecx
  mov    %ecx,D69(%rip)
  mov    %ecx,%eax
  shr    $0x13,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  shr    $0x8,%edx
  xor    %edx,%eax
  mov    %eax,D69(%rip)
  ret
```

assistant: ```c
unsigned int xor128() {
  static unsigned int x = 123456789;
  static unsigned int y = 362436069;
  static unsigned int z = 521288629;
  static unsigned int w = 88675123;
  unsigned int t;
  t = x ^ (x << 11);
  x = y;
  y = z;
  z = w;
  return w = w ^ (w >> 19) ^ (t ^ (t >> 8));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xor128>:
  endbr64
  mov    D7(%rip),%eax
  mov    D34(%rip),%ecx
  mov    %eax,%edx
  shl    $0xb,%edx
  xor    %eax,%edx
  mov    D36(%rip),%eax
  mov    %eax,D77(%rip)
  mov    D77(%rip),%eax
  mov    %ecx,D60(%rip)
  mov    %eax,D60(%rip)
  mov    %ecx,%eax
  shr    $0x13,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  shr    $0x8,%edx
  xor    %edx,%eax
  mov    %eax,D60(%rip)
  ret
```

assistant: ```c
unsigned int xor128() {
  static unsigned int x = 123456789;
  static unsigned int y = 362436069;
  static unsigned int z = 521288629;
  static unsigned int w = 88675123;
  unsigned int t;
  t = x ^ (x << 11);
  x = y;
  y = z;
  z = w;
  return w = w ^ (w >> 19) ^ (t ^ (t >> 8));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xor128>:
  endbr64
  mov    D66(%rip),%eax
  mov    D43(%rip),%ecx
  mov    %eax,%edx
  shl    $0xb,%edx
  xor    %eax,%edx
  mov    D59(%rip),%eax
  mov    %eax,D60(%rip)
  mov    D60(%rip),%eax
  mov    %ecx,D68(%rip)
  mov    %eax,D68(%rip)
  mov    %ecx,%eax
  shr    $0x13,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  shr    $0x8,%edx
  xor    %edx,%eax
  mov    %eax,D68(%rip)
  ret
```

assistant: ```c
unsigned int xor128() {
  static unsigned int x = 123456789;
  static unsigned int y = 362436069;
  static unsigned int z = 521288629;
  static unsigned int w = 88675123;
  unsigned int t;
  t = x ^ (x << 11);
  x = y;
  y = z;
  z = w;
  return w = w ^ (w >> 19) ^ (t ^ (t >> 8));
}
```
user: What is the c source code of the assembly code below:

```asm
<BogoSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L4
L12:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <Shuffle@plt>
L4:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <IsSorted@plt>
  test   %eax,%eax
  je     L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void BogoSort(int *data, int count) {
  while (!IsSorted(data, count))
    Shuffle(data, count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BogoSort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  jmp    L9
L15:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Shuffle@plt>
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <IsSorted@plt>
  test   %eax,%eax
  je     L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void BogoSort(int *data, int count) {
  while (!IsSorted(data, count))
    Shuffle(data, count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<BogoSort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Shuffle@plt>
L11:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <IsSorted@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void BogoSort(int *data, int count) {
  while (!IsSorted(data, count))
    Shuffle(data, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<BogoSort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L18
  nopl   0x0(%rax)
L16:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Shuffle@plt>
L18:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <IsSorted@plt>
  test   %eax,%eax
  je     L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void BogoSort(int *data, int count) {
  while (!IsSorted(data, count))
    Shuffle(data, count);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L2
L48:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L21
  mov    $0xffffffff,%eax
  jmp    L39
L21:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jbe    L29
  mov    $0x1,%eax
  jmp    L39
L29:
  addq   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L48
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *p1, const void *p2, size_t size) {
  const unsigned char *s1 = (const unsigned char *)p1;
  const unsigned char *s2 = (const unsigned char *)p2;
  for (size_t i = 0; i < size; i++) {
    if (s1[i] < s2[i])
      return -1;
    else if (s1[i] > s2[i])
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L7
  mov    $0x0,%eax
L10:
  movzbl (%rdi,%rax,1),%r8d
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%r8b
  jb     L37
  ja     L16
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L10
  mov    $0x0,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
L37:
  mov    $0xffffffff,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *p1, const void *p2, size_t size) {
  const unsigned char *s1 = (const unsigned char *)p1;
  const unsigned char *s2 = (const unsigned char *)p2;
  for (size_t i = 0; i < size; i++) {
    if (s1[i] < s2[i])
      return -1;
    else if (s1[i] > s2[i])
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L37
  xor    %eax,%eax
  jmp    L40
  nopl   (%rax)
L48:
  ja     L45
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L37
L40:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jae    L48
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *p1, const void *p2, size_t size) {
  const unsigned char *s1 = (const unsigned char *)p1;
  const unsigned char *s2 = (const unsigned char *)p2;
  for (size_t i = 0; i < size; i++) {
    if (s1[i] < s2[i])
      return -1;
    else if (s1[i] > s2[i])
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L13
  xor    %eax,%eax
  jmp    L38
  nopl   (%rax)
L43:
  ja     L4
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L13
L38:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jae    L43
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *p1, const void *p2, size_t size) {
  const unsigned char *s1 = (const unsigned char *)p1;
  const unsigned char *s2 = (const unsigned char *)p2;
  for (size_t i = 0; i < size; i++) {
    if (s1[i] < s2[i])
      return -1;
    else if (s1[i] > s2[i])
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x2,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L26
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L26:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L1
L16:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jle    L16
  mov    -0x18(%rbp),%rdx
  mov    $0x1,%eax
  sub    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0: allocation failure in dvector()

assistant: ```c
double *dvector(long nl, long nh) {
  double *v;
  long i;
  v = (double *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(double)));
  if (!v)
    nrerror("allocation failure in dvector()");
  for (i = nl; i <= nh; i++)
    v[i] = 0.0;
  return v - nl + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dvector>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L37
L12:
  cmp    %rbx,%r12
  jl     L28
  lea    0x0(%rbp,%rbx,8),%rax
  lea    0x8(%rbp,%r12,8),%rdx
L20:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L20
L28:
  mov    $0x1,%eax
  sub    %rbx,%rax
  lea    0x0(%rbp,%rax,8),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  lea    D1(%rip),%rdi
  call   <nrerror@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string

tool: D1: allocation failure in dvector()

assistant: ```c
double *dvector(long nl, long nh) {
  double *v;
  long i;
  v = (double *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(double)));
  if (!v)
    nrerror("allocation failure in dvector()");
  for (i = nl; i <= nh; i++)
    v[i] = 0.0;
  return v - nl + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dvector>:
  endbr64
  push   %r12
  mov    %rsi,%rax
  push   %rbp
  sub    %rdi,%rax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L13:
  cmp    %rbx,%rbp
  jl     L22
  sub    %rbx,%rbp
  lea    (%r12,%rbx,8),%rdi
  xor    %esi,%esi
  lea    0x8(,%rbp,8),%rdx
  call   <memset@plt>
L22:
  mov    $0x1,%eax
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  lea    (%r12,%rax,8),%rax
  pop    %r12
  ret
  nopl   (%rax)
L17:
  lea    D9(%rip),%rdi
  call   <nrerror@plt>
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: allocation failure in dvector()

assistant: ```c
double *dvector(long nl, long nh) {
  double *v;
  long i;
  v = (double *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(double)));
  if (!v)
    nrerror("allocation failure in dvector()");
  for (i = nl; i <= nh; i++)
    v[i] = 0.0;
  return v - nl + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dvector>:
  endbr64
  push   %r12
  mov    %rsi,%rax
  push   %rbp
  sub    %rdi,%rax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
L2:
  cmp    %rbx,%rbp
  jl     L24
  sub    %rbx,%rbp
  lea    (%r12,%rbx,8),%rdi
  xor    %esi,%esi
  lea    0x8(,%rbp,8),%rdx
  call   <memset@plt>
L24:
  mov    $0x1,%eax
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  lea    (%r12,%rax,8),%rax
  pop    %r12
  ret
  nopl   (%rax)
L5:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: allocation failure in dvector()

assistant: ```c
double *dvector(long nl, long nh) {
  double *v;
  long i;
  v = (double *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(double)));
  if (!v)
    nrerror("allocation failure in dvector()");
  for (i = nl; i <= nh; i++)
    v[i] = 0.0;
  return v - nl + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L49
L29:
  movl   $0x0,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L25
L41:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jg     L41
  cmpl   $0x0,-0x4(%rbp)
  jne    L13
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L29
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d	

assistant: ```c
void primes(int cap) {
  int i, j, composite;
  for (i = 2; i < cap; ++i) {
    composite = 0;
    for (j = 2; j * j < i; ++j) {
      composite += !(i % j);
    }
    if (!composite) {
      printf("%d\t", i);
    }
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<primes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x2,%ebx
  lea    D0(%rip),%r12
  cmp    $0x2,%edi
  jg     L44
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L4
L44:
  mov    $0x0,%esi
  mov    $0x2,%ecx
  cmp    $0x4,%ebx
  jle    L3
L38:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %ebx,%eax
  jl     L38
  test   %esi,%esi
  jne    L19
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: %d	

assistant: ```c
void primes(int cap) {
  int i, j, composite;
  for (i = 2; i < cap; ++i) {
    composite = 0;
    for (j = 2; j * j < i; ++j) {
      composite += !(i % j);
    }
    if (!composite) {
      printf("%d\t", i);
    }
  }
  printf("\n");
}
```