ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_hor_pred>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jle    L20
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L37:
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L74:
  mov    -0xc(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L74
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L37
  jmp    L52
L20:
  movl   $0x0,-0xc(%rbp)
  jmp    L54
L13:
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L40:
  mov    -0xc(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movl   $0x80,(%rax)
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L40
  addl   $0x1,-0xc(%rbp)
L54:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L13
L52:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_hor_pred(uint8_t *rec, int ypos, int xpos, int stride, int size, uint8_t *pblock) {
  int i, j, val;
  if (xpos > 0) {
    for (i = 0; i < size; i++) {
      val = rec[(ypos + i) * stride + xpos - 1];
      for (j = 0; j < size; j++) {
        pblock[i * size + j] = val;
      }
    }
  } else {
    for (i = 0; i < size; i++) {
      for (j = 0; j < size; j++) {
        pblock[i * size + j] = 128;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_hor_pred>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L11
  test   %r8d,%r8d
  jle    L68
  movslq %ecx,%r11
  shl    $0x2,%r11
  imul   %ecx,%esi
  movslq %esi,%rdx
  cltq
  add    %rdx,%rax
  lea    (%rdi,%rax,4),%rdi
  movslq %r8d,%r10
  shl    $0x2,%r10
  lea    -0x1(%r8),%eax
  lea    0x4(%r9,%rax,4),%rdx
  mov    $0x0,%esi
  mov    %r8d,%r9d
  neg    %r9
  shl    $0x2,%r9
L33:
  mov    -0x4(%rdi),%ecx
  lea    (%r9,%rdx,1),%rax
L45:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L45
  add    $0x1,%esi
  add    %r11,%rdi
  add    %r10,%rdx
  cmp    %esi,%r8d
  jne    L33
  ret
L11:
  test   %r8d,%r8d
  jle    L68
  movslq %r8d,%rdi
  shl    $0x2,%rdi
  lea    -0x1(%r8),%eax
  lea    0x4(%r9,%rax,4),%rdx
  mov    $0x0,%ecx
  mov    %r8d,%esi
  neg    %rsi
  shl    $0x2,%rsi
L36:
  lea    (%rsi,%rdx,1),%rax
L52:
  movl   $0x80,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L52
  add    $0x1,%ecx
  add    %rdi,%rdx
  cmp    %ecx,%r8d
  jne    L36
L68:
  ret
```

assistant: ```c
void get_hor_pred(uint8_t *rec, int ypos, int xpos, int stride, int size, uint8_t *pblock) {
  int i, j, val;
  if (xpos > 0) {
    for (i = 0; i < size; i++) {
      val = rec[(ypos + i) * stride + xpos - 1];
      for (j = 0; j < size; j++) {
        pblock[i * size + j] = val;
      }
    }
  } else {
    for (i = 0; i < size; i++) {
      for (j = 0; j < size; j++) {
        pblock[i * size + j] = 128;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_hor_pred>:
  endbr64
  movslq %edx,%rax
  test   %eax,%eax
  jle    L52
  test   %r8d,%r8d
  jle    L1
  imul   %ecx,%esi
  movslq %ecx,%r11
  movslq %r8d,%r10
  shl    $0x2,%r11
  shl    $0x2,%r10
  movslq %esi,%rdx
  xor    %esi,%esi
  add    %rdx,%rax
  lea    (%rdi,%rax,4),%rdi
  lea    -0x1(%r8),%eax
  shl    $0x2,%rax
  lea    0x4(%r9,%rax,1),%rdx
  mov    $0xfffffffffffffffc,%r9
  sub    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L56:
  mov    -0x4(%rdi),%ecx
  lea    (%r9,%rdx,1),%rax
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L16
  add    $0x1,%esi
  add    %r11,%rdi
  add    %r10,%rdx
  cmp    %esi,%r8d
  jne    L56
  ret
L52:
  test   %r8d,%r8d
  jle    L1
  lea    -0x1(%r8),%eax
  movslq %r8d,%rdi
  mov    $0xfffffffffffffffc,%rsi
  xor    %ecx,%ecx
  shl    $0x2,%rax
  shl    $0x2,%rdi
  lea    0x4(%r9,%rax,1),%rdx
  sub    %rax,%rsi
  nop
L26:
  lea    (%rsi,%rdx,1),%rax
  nopl   0x0(%rax)
L34:
  movl   $0x80,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L34
  add    $0x1,%ecx
  add    %rdi,%rdx
  cmp    %ecx,%r8d
  jne    L26
L1:
  ret
```

assistant: ```c
void get_hor_pred(uint8_t *rec, int ypos, int xpos, int stride, int size, uint8_t *pblock) {
  int i, j, val;
  if (xpos > 0) {
    for (i = 0; i < size; i++) {
      val = rec[(ypos + i) * stride + xpos - 1];
      for (j = 0; j < size; j++) {
        pblock[i * size + j] = val;
      }
    }
  } else {
    for (i = 0; i < size; i++) {
      for (j = 0; j < size; j++) {
        pblock[i * size + j] = 128;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bytes_per_char_for_encoding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L18
  cmpl   $0x2,-0x4(%rbp)
  jne    L24
L18:
  mov    $0x2,%eax
  jmp    L25
L24:
  mov    $0x1,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int bytes_per_char_for_encoding(int encoding) {
  if (encoding == 1 || encoding == 2) {
    return 2;
  } else {
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bytes_per_char_for_encoding>:
  endbr64
  sub    $0x1,%edi
  cmp    $0x2,%edi
  setb   %al
  movzbl %al,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int bytes_per_char_for_encoding(int encoding) {
  if (encoding == 1 || encoding == 2) {
    return 2;
  } else {
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bytes_per_char_for_encoding>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x2,%edi
  setb   %al
  add    $0x1,%eax
  ret
```

assistant: ```c
int bytes_per_char_for_encoding(int encoding) {
  if (encoding == 1 || encoding == 2) {
    return 2;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bytes_per_char_for_encoding>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x2,%edi
  setb   %al
  add    $0x1,%eax
  ret
```

assistant: ```c
int bytes_per_char_for_encoding(int encoding) {
  if (encoding == 1 || encoding == 2) {
    return 2;
  } else {
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_token@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  jmp    L5
L2:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_quoted_string@plt>
L5:
  leave
  ret
```

assistant: ```c
const char *parse_value(const char *value, char **pbuf) {
  const char *ret;
  if ((ret = parse_token(value, pbuf)))
    return ret;
  return parse_quoted_string(value, pbuf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_value>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <parse_token@plt>
  test   %rax,%rax
  je     L15
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <parse_quoted_string@plt>
  jmp    L16
```

assistant: ```c
const char *parse_value(const char *value, char **pbuf) {
  const char *ret;
  if ((ret = parse_token(value, pbuf)))
    return ret;
  return parse_quoted_string(value, pbuf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_value>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <parse_token@plt>
  test   %rax,%rax
  je     L9
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <parse_quoted_string@plt>
```

assistant: ```c
const char *parse_value(const char *value, char **pbuf) {
  const char *ret;
  if ((ret = parse_token(value, pbuf)))
    return ret;
  return parse_quoted_string(value, pbuf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_value>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <parse_token@plt>
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <parse_quoted_string@plt>
```

assistant: ```c
const char *parse_value(const char *value, char **pbuf) {
  const char *ret;
  if ((ret = parse_token(value, pbuf)))
    return ret;
  return parse_quoted_string(value, pbuf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  struct sigaction act;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  struct sigaction act;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct sigaction act;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct sigaction act;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_roots>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <print@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L16:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <print@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L16
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <print@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string

tool: D1: roots: {

tool: D19:  %f

tool: D27:  }


assistant: ```c
void print_roots(unsigned n, double x[]) {
  unsigned i;
  print("roots: {");
  for (i = 0; i < n; ++i)
    print(" %f", x[i]);
  print(" }\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_roots>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  test   %ebp,%ebp
  je     L0
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r12
  lea    D9(%rip),%rbp
L19:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <print@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L19
L0:
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D4
type: string

tool: D1: roots: {

tool: D9:  %f

tool: D4:  }


assistant: ```c
void print_roots(unsigned n, double x[]) {
  unsigned i;
  print("roots: {");
  for (i = 0; i < n; ++i)
    print(" %f", x[i]);
  print(" }\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_roots>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  lea    D18(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <print@plt>
  test   %ebp,%ebp
  je     L12
  lea    -0x1(%rbp),%eax
  lea    D12(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  xchg   %ax,%ax
L6:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <print@plt>
  cmp    %r12,%rbx
  jne    L6
L12:
  pop    %rbx
  lea    D23(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1050 <print@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
datatype: string
name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D23
datatype: string

tool: D18: roots: {

tool: D12:  %f

tool: D23:  }


assistant: ```c
void print_roots(unsigned n, double x[]) {
  unsigned i;
  print("roots: {");
  for (i = 0; i < n; ++i)
    print(" %f", x[i]);
  print(" }\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_roots>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  lea    D29(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <print@plt>
  test   %ebp,%ebp
  je     L6
  lea    -0x1(%rbp),%eax
  lea    D24(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  xchg   %ax,%ax
L19:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <print@plt>
  cmp    %r12,%rbx
  jne    L19
L6:
  pop    %rbx
  lea    D6(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1050 <print@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
type: string
name: read_data
arguments: data_tag: D24
type: string
name: read_data
arguments: data_tag: D6
type: string

tool: D29: roots: {

tool: D24:  %f

tool: D6:  }


assistant: ```c
void print_roots(unsigned n, double x[]) {
  unsigned i;
  print("roots: {");
  for (i = 0; i < n; ++i)
    print(" %f", x[i]);
  print(" }\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_file_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L25
  mov    -0xc(%rbp),%eax
  jmp    L14
L25:
  mov    $0xffffffff,%eax
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
off_t get_file_size(const char *filename) {
  struct stat buffer;
  return (stat(filename, &buffer) == 0 ? buffer.st_size : -1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L7
  mov    0x4(%rsp),%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L27
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
off_t get_file_size(const char *filename) {
  struct stat buffer;
  return (stat(filename, &buffer) == 0 ? buffer.st_size : -1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L13
  mov    0x4(%rsp),%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
L13:
  mov    $0xffffffff,%eax
  jmp    L18
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
off_t get_file_size(const char *filename) {
  struct stat buffer;
  return (stat(filename, &buffer) == 0 ? buffer.st_size : -1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L1
  mov    0x4(%rsp),%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L1:
  mov    $0xffffffff,%eax
  jmp    L18
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
off_t get_file_size(const char *filename) {
  struct stat buffer;
  return (stat(filename, &buffer) == 0 ? buffer.st_size : -1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bug_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <sm@plt>
  mov    $0x51,%esi
  mov    $0x1,%edi
  call   <cup@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <rm@plt>
  mov    $0x5,%esi
  mov    $0xc,%edi
  call   <cup@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <holdit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D15: ?3

tool: D12: Except for this line, the screen should be blank. 

assistant: ```c
bug_c() {
  sm("?3");
  cup(1, 81);
  rm("?3");
  cup(12, 5);
  printf("Except for this line, the screen should be blank. ");
  holdit();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bug_c>:
  endbr64
  push   %rbx
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  call   <sm@plt>
  mov    $0x51,%esi
  mov    $0x1,%edi
  call   <cup@plt>
  mov    %rbx,%rdi
  call   <rm@plt>
  mov    $0x5,%esi
  mov    $0xc,%edi
  call   <cup@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <holdit@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D4
type: string

tool: D18: ?3

tool: D4: Except for this line, the screen should be blank. 

assistant: ```c
bug_c() {
  sm("?3");
  cup(1, 81);
  rm("?3");
  cup(12, 5);
  printf("Except for this line, the screen should be blank. ");
  holdit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bug_c>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <sm@plt>
  mov    $0x51,%esi
  mov    $0x1,%edi
  call   <cup@plt>
  mov    %rbp,%rdi
  call   <rm@plt>
  mov    $0x5,%esi
  mov    $0xc,%edi
  call   <cup@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    10d0 <holdit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D1: ?3

tool: D16: Except for this line, the screen should be blank. 

assistant: ```c
bug_c() {
  sm("?3");
  cup(1, 81);
  rm("?3");
  cup(12, 5);
  printf("Except for this line, the screen should be blank. ");
  holdit();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bug_c>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  call   <sm@plt>
  mov    $0x51,%esi
  mov    $0x1,%edi
  call   <cup@plt>
  mov    %rbp,%rdi
  call   <rm@plt>
  mov    $0x5,%esi
  mov    $0xc,%edi
  call   <cup@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    10d0 <holdit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D12
type_infered: string

tool: D15: ?3

tool: D12: Except for this line, the screen should be blank. 

assistant: ```c
bug_c() {
  sm("?3");
  cup(1, 81);
  rm("?3");
  cup(12, 5);
  printf("Except for this line, the screen should be blank. ");
  holdit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_infered: string

tool: D12: %d

assistant: ```c
int main() {
  int n, c;
  scanf("%d", &n);
  c = is_prime(n);
  printf("%d", c);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: %d

assistant: ```c
int main() {
  int n, c;
  scanf("%d", &n);
  c = is_prime(n);
  printf("%d", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: %d

assistant: ```c
int main() {
  int n, c;
  scanf("%d", &n);
  c = is_prime(n);
  printf("%d", c);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: %d

assistant: ```c
int main() {
  int n, c;
  scanf("%d", &n);
  c = is_prime(n);
  printf("%d", c);
  return 0;
}
```