ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<samplet>:
  endbr64
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  jae    L34
  mulsd  %xmm0,%xmm1
  test   %esi,%esi
  je     L8
  mov    %esi,%edx
  xor    %eax,%eax
  jmp    L59
  nopl   0x0(%rax)
L49:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L8
L59:
  pxor   %xmm0,%xmm0
  mov    %eax,%r8d
  cvtss2sd (%rdi,%rax,4),%xmm0
  subsd  %xmm0,%xmm1
  comisd %xmm1,%xmm2
  jbe    L49
L19:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %esi,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,%r8d
  cmp    %eax,%esi
  ja     L19
L8:
  lea    -0x1(%rsi),%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned samplet(float *fact, double facttot, unsigned dim, double U) {
  unsigned k;
  if (facttot <= 0) {
    k = U * dim;
  } else {
    facttot *= U;
    for (k = 0; k < dim; k++) {
      facttot -= fact[k];
      if (facttot < 0)
        break;
    }
  }
  if (k >= dim)
    k = dim - 1;
  return k;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<replace_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %ecx,-0x24(%rbp)
  mov    %esi,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L1:
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  mov    -0x18(%rbp),%rax
  movzbl -0x20(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L14
L20:
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  jmp    L8
L14:
  nop
L8:
  leave
  ret
```

assistant: ```c
void replace_char(char *string, char from, char to, int maxlen) {
  char *lastchar = string + maxlen;
  while (string) {
    string = strchr(string, from);
    if (string) {
      *string = to;
      if (string >= lastchar)
        return;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<replace_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,1),%rbp
  test   %rdi,%rdi
  je     L10
  mov    %edx,%r12d
  movsbl %sil,%ebx
L28:
  mov    %ebx,%esi
  call   <strchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L10
  mov    %r12b,(%rax)
  cmp    %rax,%rbp
  ja     L28
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void replace_char(char *string, char from, char to, int maxlen) {
  char *lastchar = string + maxlen;
  while (string) {
    string = strchr(string, from);
    if (string) {
      *string = to;
      if (string >= lastchar)
        return;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<replace_char>:
  endbr64
  movslq %ecx,%rcx
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    (%rdi,%rcx,1),%rbp
  push   %rbx
  movsbl %sil,%ebx
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %r12b,(%rax)
  cmp    %rax,%rbp
  jbe    L37
L33:
  test   %rdi,%rdi
  je     L37
  mov    %ebx,%esi
  call   <strchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L11
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void replace_char(char *string, char from, char to, int maxlen) {
  char *lastchar = string + maxlen;
  while (string) {
    string = strchr(string, from);
    if (string) {
      *string = to;
      if (string >= lastchar)
        return;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<replace_char>:
  endbr64
  movslq %ecx,%rcx
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    (%rdi,%rcx,1),%rbp
  push   %rbx
  movsbl %sil,%ebx
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r12b,(%rax)
  cmp    %rax,%rbp
  jbe    L8
L3:
  test   %rdi,%rdi
  je     L8
  mov    %ebx,%esi
  call   <strchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L33
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void replace_char(char *string, char from, char to, int maxlen) {
  char *lastchar = string + maxlen;
  while (string) {
    string = strchr(string, from);
    if (string) {
      *string = to;
      if (string >= lastchar)
        return;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yxisChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <inch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L2
  mov    $0x1,%eax
  jmp    L1
L2:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int yxisChar(const int y, const int x, const int c) {
  int cmp;
  move(y, x);
  cmp = inch();
  if (cmp == c) {
    return 1;
  } else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<yxisChar>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <move@plt>
  mov    $0x0,%eax
  call   <inch@plt>
  cmp    %ebx,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int yxisChar(const int y, const int x, const int c) {
  int cmp;
  move(y, x);
  cmp = inch();
  if (cmp == c) {
    return 1;
  } else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yxisChar>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <move@plt>
  xor    %eax,%eax
  call   <inch@plt>
  cmp    %ebx,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int yxisChar(const int y, const int x, const int c) {
  int cmp;
  move(y, x);
  cmp = inch();
  if (cmp == c) {
    return 1;
  } else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yxisChar>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <move@plt>
  xor    %eax,%eax
  call   <inch@plt>
  cmp    %ebx,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int yxisChar(const int y, const int x, const int c) {
  int cmp;
  move(y, x);
  cmp = inch();
  if (cmp == c) {
    return 1;
  } else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L10
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L12
L10:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *dst, int c, size_t n) {
  if (n) {
    char *d = dst;
    do {
      *d++ = c;
    } while (--n);
  }
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L13
  add    %rdi,%rdx
  mov    %rdi,%rcx
L6:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L6
L13:
  ret
```

assistant: ```c
void *memset(void *dst, int c, size_t n) {
  if (n) {
    char *d = dst;
    do {
      *d++ = c;
    } while (--n);
  }
  return dst;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L0
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dst, int c, size_t n) {
  if (n) {
    char *d = dst;
    do {
      *d++ = c;
    } while (--n);
  }
  return dst;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L8
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dst, int c, size_t n) {
  if (n) {
    char *d = dst;
    do {
      *d++ = c;
    } while (--n);
  }
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string
name: unpack_data
arguments: data_label: D63
datatype: string
name: unpack_data
arguments: data_label: D43
datatype: string
name: unpack_data
arguments: data_label: D75
datatype: string
name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D45
datatype: string
name: unpack_data
arguments: data_label: D64
datatype: string

tool: D3: what is the first int?

tool: D63:  %d

tool: D43: what is the second int?

tool: D75: the sum is %d


tool: D8: the different is %d


tool: D45: the product is %d


tool: D64: the qoutient is %d


assistant: ```c
int main() {
  int int1;
  int int2;
  int int_sum;
  int int_product;
  int int_different;
  int int_qoutient;
  printf("what is the first int?\n");
  scanf(" %d", &int1);
  printf("what is the second int?\n");
  scanf(" %d", &int2);
  int_sum = (int1 + int2);
  printf("the sum is %d\n", int_sum);
  int_different = (int1 - int2);
  printf("the different is %d\n", int_different);
  int_product = (int1 * int2);
  printf("the product is %d\n", int_product);
  int_qoutient = (int1 / int2);
  printf("the qoutient is %d\n", int_qoutient);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D64(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  add    (%rsp),%esi
  lea    D51(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  sub    0x4(%rsp),%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  imul   0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D64
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D39
datatype: string
name: extract_symbolic_data
arguments: label: D51
datatype: string
name: extract_symbolic_data
arguments: label: D37
datatype: string
name: extract_symbolic_data
arguments: label: D7
datatype: string
name: extract_symbolic_data
arguments: label: D49
datatype: string

tool: D64: what is the first int?

tool: D11:  %d

tool: D39: what is the second int?

tool: D51: the sum is %d


tool: D37: the different is %d


tool: D7: the product is %d


tool: D49: the qoutient is %d


assistant: ```c
int main() {
  int int1;
  int int2;
  int int_sum;
  int int_product;
  int int_different;
  int int_qoutient;
  printf("what is the first int?\n");
  scanf(" %d", &int1);
  printf("what is the second int?\n");
  scanf(" %d", &int2);
  int_sum = (int1 + int2);
  printf("the sum is %d\n", int_sum);
  int_different = (int1 - int2);
  printf("the different is %d\n", int_different);
  int_product = (int1 * int2);
  printf("the product is %d\n", int_product);
  int_qoutient = (int1 / int2);
  printf("the qoutient is %d\n", int_qoutient);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D68(%rip),%rdi
  lea    D59(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  add    (%rsp),%esi
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  sub    0x4(%rsp),%esi
  call   <printf@plt>
  mov    (%rsp),%esi
  imul   0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    D46(%rip),%rdi
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D68
datatype: string
name: retrieve_data
arguments: data_label: D59
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string
name: retrieve_data
arguments: data_label: D34
datatype: string
name: retrieve_data
arguments: data_label: D55
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D46
datatype: string

tool: D68: what is the first int?

tool: D59:  %d

tool: D18: what is the second int?

tool: D34: the sum is %d


tool: D55: the different is %d


tool: D26: the product is %d


tool: D46: the qoutient is %d


assistant: ```c
int main() {
  int int1;
  int int2;
  int int_sum;
  int int_product;
  int int_different;
  int int_qoutient;
  printf("what is the first int?\n");
  scanf(" %d", &int1);
  printf("what is the second int?\n");
  scanf(" %d", &int2);
  int_sum = (int1 + int2);
  printf("the sum is %d\n", int_sum);
  int_different = (int1 - int2);
  printf("the different is %d\n", int_different);
  int_product = (int1 * int2);
  printf("the product is %d\n", int_product);
  int_qoutient = (int1 / int2);
  printf("the qoutient is %d\n", int_qoutient);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  lea    D67(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  add    (%rsp),%esi
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  sub    0x4(%rsp),%esi
  call   <printf@plt>
  mov    (%rsp),%esi
  imul   0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    D41(%rip),%rdi
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D67
type_guessed: string
name: read_data
arguments: data_label: D31
type_guessed: string
name: read_data
arguments: data_label: D39
type_guessed: string
name: read_data
arguments: data_label: D55
type_guessed: string
name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D41
type_guessed: string

tool: D14: what is the first int?

tool: D67:  %d

tool: D31: what is the second int?

tool: D39: the sum is %d


tool: D55: the different is %d


tool: D27: the product is %d


tool: D41: the qoutient is %d


assistant: ```c
int main() {
  int int1;
  int int2;
  int int_sum;
  int int_product;
  int int_different;
  int int_qoutient;
  printf("what is the first int?\n");
  scanf(" %d", &int1);
  printf("what is the second int?\n");
  scanf(" %d", &int2);
  int_sum = (int1 + int2);
  printf("the sum is %d\n", int_sum);
  int_different = (int1 - int2);
  printf("the different is %d\n", int_different);
  int_product = (int1 * int2);
  printf("the product is %d\n", int_product);
  int_qoutient = (int1 / int2);
  printf("the qoutient is %d\n", int_qoutient);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex_to_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2f,-0x4(%rbp)
  jle    L15
  cmpl   $0x39,-0x4(%rbp)
  jg     L15
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L7
L15:
  cmpl   $0x60,-0x4(%rbp)
  jle    L50
  cmpl   $0x66,-0x4(%rbp)
  jg     L50
  mov    -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L7
L50:
  mov    $0xffffffff,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int hex_to_num(int ch) {
  if ('0' <= ch && ch <= '9')
    return ch - '0';
  if ('a' <= ch && ch <= 'f')
    return ch - 'a' + 10;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hex_to_num>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L3
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%eax
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L3:
  ret
```

assistant: ```c
int hex_to_num(int ch) {
  if ('0' <= ch && ch <= '9')
    return ch - '0';
  if ('a' <= ch && ch <= 'f')
    return ch - 'a' + 10;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hex_to_num>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L5
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%eax
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L5:
  ret
```

assistant: ```c
int hex_to_num(int ch) {
  if ('0' <= ch && ch <= '9')
    return ch - '0';
  if ('a' <= ch && ch <= 'f')
    return ch - 'a' + 10;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<hex_to_num>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L8
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%eax
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L8:
  ret
```

assistant: ```c
int hex_to_num(int ch) {
  if ('0' <= ch && ch <= '9')
    return ch - '0';
  if ('a' <= ch && ch <= 'f')
    return ch - 'a' + 10;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hypotenuse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  ja     L14
  pxor   %xmm0,%xmm0
  comisd -0x30(%rbp),%xmm0
  jbe    L16
L14:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L16:
  mov    -0x28(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: Legs cannot be negative.


assistant: ```c
double hypotenuse(double side0, double side1) {
  double retVal;
  if ((side0 < 0) || (side1 < 0))
    die("Legs cannot be negative.\n");
  retVal = sqrt(pow(side0, 2) + pow(side1, 2));
  return retVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hypotenuse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  pxor   %xmm0,%xmm0
  movq   %rbx,%xmm2
  comisd %xmm2,%xmm0
  ja     L18
  comisd %xmm1,%xmm0
  jbe    L19
L18:
  lea    D3(%rip),%rdi
  call   <die@plt>
L19:
  mov    $0x2,%edi
  movq   %rbx,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  mov    $0x2,%edi
  movq   %rbp,%xmm0
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: Legs cannot be negative.


assistant: ```c
double hypotenuse(double side0, double side1) {
  double retVal;
  if ((side0 < 0) || (side1 < 0))
    die("Legs cannot be negative.\n");
  retVal = sqrt(pow(side0, 2) + pow(side1, 2));
  return retVal;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hypotenuse>:
  endbr64
  push   %rbx
  pxor   %xmm2,%xmm2
  sub    $0x10,%rsp
  comisd %xmm0,%xmm2
  ja     L7
  comisd %xmm1,%xmm2
  ja     L7
L27:
  mov    $0x2,%edi
  movsd  %xmm1,(%rsp)
  call   <pow@plt>
  movsd  (%rsp),%xmm1
  mov    $0x2,%edi
  mov    %rax,%rbx
  movapd %xmm1,%xmm0
  call   <pow@plt>
  add    $0x10,%rsp
  lea    (%rbx,%rax,1),%rdi
  pop    %rbx
  jmp    1070 <sqrt@plt>
  nopl   0x0(%rax)
L7:
  lea    D7(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <die@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  jmp    L27
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: Legs cannot be negative.


assistant: ```c
double hypotenuse(double side0, double side1) {
  double retVal;
  if ((side0 < 0) || (side1 < 0))
    die("Legs cannot be negative.\n");
  retVal = sqrt(pow(side0, 2) + pow(side1, 2));
  return retVal;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hypotenuse>:
  endbr64
  push   %rbx
  pxor   %xmm2,%xmm2
  sub    $0x10,%rsp
  comisd %xmm0,%xmm2
  ja     L14
  comisd %xmm1,%xmm2
  ja     L14
L10:
  mov    $0x2,%edi
  movsd  %xmm1,(%rsp)
  call   <pow@plt>
  movsd  (%rsp),%xmm1
  mov    $0x2,%edi
  mov    %rax,%rbx
  movapd %xmm1,%xmm0
  call   <pow@plt>
  add    $0x10,%rsp
  lea    (%rbx,%rax,1),%rdi
  pop    %rbx
  jmp    1070 <sqrt@plt>
  nopl   0x0(%rax)
L14:
  lea    D2(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <die@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: Legs cannot be negative.


assistant: ```c
double hypotenuse(double side0, double side1) {
  double retVal;
  if ((side0 < 0) || (side1 < 0))
    die("Legs cannot be negative.\n");
  retVal = sqrt(pow(side0, 2) + pow(side1, 2));
  return retVal;
}
```