ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<uint_dec>:
  endbr64
  mov    %rsi,%r8
  lea    D3(%rip),%r11
  mov    $0xcccccccd,%r10d
  nopl   0x0(%rax)
L4:
  mov    %edi,%edi
  mov    %r8,%rax
  add    $0x1,%r8
  mov    %rdi,%rdx
  imul   %r10,%rdi
  mov    %edx,%r9d
  shr    $0x23,%rdi
  lea    (%rdi,%rdi,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%r9d
  movzbl (%r11,%r9,1),%ecx
  mov    %cl,-0x1(%r8)
  cmp    $0x9,%edx
  ja     L4
  cmp    %rsi,%rax
  ja     L19
  jmp    L7
  nopl   0x0(%rax)
L35:
  movzbl (%rax),%ecx
L19:
  movzbl (%rsi),%edx
  sub    $0x1,%rax
  add    $0x1,%rsi
  mov    %dl,0x1(%rax)
  mov    %cl,-0x1(%rsi)
  cmp    %rsi,%rax
  ja     L35
L7:
  mov    %r8,%rax
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string

tool: D3: 0123456789

assistant: ```c
char *uint_dec(unsigned int x, char *buf) {
  char *ptr = buf, *ptr1 = buf, *ptr_end, tmp_char;
  int x_tmp;
  do {
    x_tmp = x;
    x /= 10;
    *ptr++ = "0123456789"[x_tmp - x * 10];
  } while (x);
  ptr_end = ptr--;
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return ptr_end;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uint_dec>:
  endbr64
  mov    %rsi,%r8
  lea    D3(%rip),%r11
  mov    $0xcccccccd,%r10d
  nopl   0x0(%rax)
L21:
  mov    %edi,%edi
  mov    %r8,%rax
  add    $0x1,%r8
  mov    %rdi,%rdx
  imul   %r10,%rdi
  mov    %edx,%r9d
  shr    $0x23,%rdi
  lea    (%rdi,%rdi,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%r9d
  movzbl (%r11,%r9,1),%ecx
  mov    %cl,-0x1(%r8)
  cmp    $0x9,%edx
  ja     L21
  cmp    %rsi,%rax
  jbe    L9
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%rax),%edx
  movzbl (%rsi),%ecx
  sub    $0x1,%rax
  add    $0x1,%rsi
  mov    %cl,0x1(%rax)
  mov    %dl,-0x1(%rsi)
  cmp    %rsi,%rax
  ja     L15
L9:
  mov    %r8,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: 0123456789

assistant: ```c
char *uint_dec(unsigned int x, char *buf) {
  char *ptr = buf, *ptr1 = buf, *ptr_end, tmp_char;
  int x_tmp;
  do {
    x_tmp = x;
    x /= 10;
    *ptr++ = "0123456789"[x_tmp - x * 10];
  } while (x);
  ptr_end = ptr--;
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return ptr_end;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L12
  mov    $0x1,%eax
  jmp    L11
L12:
  mov    $0x0,%eax
L11:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: PATH

assistant: ```c
int check_path(char path[100]) {
  if (strstr(path, "PATH") != NULL)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_path>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: PATH

assistant: ```c
int check_path(char path[100]) {
  if (strstr(path, "PATH") != NULL)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_path>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string

tool: D9: PATH

assistant: ```c
int check_path(char path[100]) {
  if (strstr(path, "PATH") != NULL)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_path>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: PATH

assistant: ```c
int check_path(char path[100]) {
  if (strstr(path, "PATH") != NULL)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<jrand_>:
  endbr64
  imul   $0xab,(%rsi),%r8d
  movslq %r8d,%rax
  imul   $0x4548a88b,%rax,%rax
  sar    $0x2d,%rax
  mov    %r8d,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  imul   $0x763d,%eax,%eax
  sub    %eax,%r8d
  mov    %r8d,(%rsi)
  imul   $0xac,(%rdx),%r8d
  movslq %r8d,%rax
  imul   $0x45326b65,%rax,%rax
  sar    $0x2d,%rax
  mov    %r8d,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  imul   $0x7663,%eax,%eax
  sub    %eax,%r8d
  mov    %r8d,(%rdx)
  imul   $0xaa,(%rcx),%r8d
  movslq %r8d,%rax
  imul   $0xffffffff8a522519,%rax,%rax
  shr    $0x20,%rax
  add    %r8d,%eax
  sar    $0xe,%eax
  mov    %r8d,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  imul   $0x7673,%eax,%r9d
  mov    %r8d,%eax
  sub    %r9d,%eax
  mov    %eax,(%rcx)
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rsi),%xmm0
  divsd  D8(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rdx),%xmm1
  divsd  D37(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  D5(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rdi),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D10(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: f64
name: retrieve_data
arguments: tag: D37
type: f64
name: retrieve_data
arguments: tag: D5
type: f64
name: retrieve_data
arguments: tag: D10
type: f64

tool: D8: 30269

tool: D37: 30307

tool: D5: 30323

tool: D10: 1

assistant: ```c
int jrand_(int *n, int *ix, int *iy, int *iz) {
  int ret_val;
  static double u, x;
  *ix = *ix * 171 % 30269;
  *iy = *iy * 172 % 30307;
  *iz = *iz * 170 % 30323;
  x = (double)(*ix) / 30269. + (double)(*iy) / 30307. + (double)(*iz) / 30323.;
  u = x - (int)x;
  ret_val = (int)((double)(*n) * u + 1.);
  return ret_val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<jrand_>:
  endbr64
  imul   $0xab,(%rsi),%r8d
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movslq %r8d,%rax
  mov    %r8d,%r9d
  imul   $0x4548a88b,%rax,%rax
  sar    $0x1f,%r9d
  sar    $0x2d,%rax
  sub    %r9d,%eax
  imul   $0x763d,%eax,%eax
  sub    %eax,%r8d
  mov    %r8d,(%rsi)
  imul   $0xac,(%rdx),%r8d
  movslq %r8d,%rax
  mov    %r8d,%r9d
  imul   $0x45326b65,%rax,%rax
  sar    $0x1f,%r9d
  sar    $0x2d,%rax
  sub    %r9d,%eax
  imul   $0x7663,%eax,%eax
  sub    %eax,%r8d
  mov    %r8d,(%rdx)
  imul   $0xaa,(%rcx),%r8d
  movslq %r8d,%rax
  mov    %r8d,%r9d
  imul   $0xffffffff8a522519,%rax,%rax
  sar    $0x1f,%r9d
  shr    $0x20,%rax
  add    %r8d,%eax
  sar    $0xe,%eax
  sub    %r9d,%eax
  imul   $0x7673,%eax,%r9d
  mov    %r8d,%eax
  sub    %r9d,%eax
  mov    %eax,(%rcx)
  cvtsi2sdl (%rsi),%xmm0
  divsd  D5(%rip),%xmm0
  cvtsi2sdl (%rdx),%xmm1
  divsd  D3(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  D1(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%eax
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rdi),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D37(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: f64
name: retrieve_data
arguments: label: D3
data_type: f64
name: retrieve_data
arguments: label: D1
data_type: f64
name: retrieve_data
arguments: label: D37
data_type: f64

tool: D5: 30269

tool: D3: 30307

tool: D1: 30323

tool: D37: 1

assistant: ```c
int jrand_(int *n, int *ix, int *iy, int *iz) {
  int ret_val;
  static double u, x;
  *ix = *ix * 171 % 30269;
  *iy = *iy * 172 % 30307;
  *iz = *iz * 170 % 30323;
  x = (double)(*ix) / 30269. + (double)(*iy) / 30307. + (double)(*iz) / 30323.;
  u = x - (int)x;
  ret_val = (int)((double)(*n) * u + 1.);
  return ret_val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jrand_>:
  endbr64
  imul   $0xab,(%rsi),%r8d
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movslq %r8d,%rax
  mov    %r8d,%r9d
  imul   $0x4548a88b,%rax,%rax
  sar    $0x1f,%r9d
  sar    $0x2d,%rax
  sub    %r9d,%eax
  imul   $0x763d,%eax,%eax
  sub    %eax,%r8d
  mov    %r8d,(%rsi)
  imul   $0xac,(%rdx),%r8d
  movslq %r8d,%rax
  mov    %r8d,%r9d
  imul   $0x45326b65,%rax,%rax
  sar    $0x1f,%r9d
  sar    $0x2d,%rax
  sub    %r9d,%eax
  imul   $0x7663,%eax,%eax
  sub    %eax,%r8d
  mov    %r8d,(%rdx)
  imul   $0xaa,(%rcx),%r8d
  movslq %r8d,%rax
  mov    %r8d,%r9d
  imul   $0xffffffff8a522519,%rax,%rax
  sar    $0x1f,%r9d
  shr    $0x20,%rax
  add    %r8d,%eax
  sar    $0xe,%eax
  sub    %r9d,%eax
  imul   $0x7673,%eax,%r9d
  mov    %r8d,%eax
  sub    %r9d,%eax
  mov    %eax,(%rcx)
  cvtsi2sdl (%rsi),%xmm0
  divsd  D28(%rip),%xmm0
  cvtsi2sdl (%rdx),%xmm1
  divsd  D31(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  D16(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%eax
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rdi),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D19(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D31
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D16
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D19
type_infered: f64

tool: D28: 30269

tool: D31: 30307

tool: D16: 30323

tool: D19: 1

assistant: ```c
int jrand_(int *n, int *ix, int *iy, int *iz) {
  int ret_val;
  static double u, x;
  *ix = *ix * 171 % 30269;
  *iy = *iy * 172 % 30307;
  *iz = *iz * 170 % 30323;
  x = (double)(*ix) / 30269. + (double)(*iy) / 30307. + (double)(*iz) / 30323.;
  u = x - (int)x;
  ret_val = (int)((double)(*n) * u + 1.);
  return ret_val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readFromStdin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
L17:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fgetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L8
  cmpl   $0xa,-0xc(%rbp)
  je     L14
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
  jmp    L17
L8:
  nop
  jmp    L38
L14:
  nop
L38:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *readFromStdin(int size) {
  char *str = malloc(size);
  int ch;
  int i = 0;
  while (1) {
    ch = fgetc(stdin);
    if (ch == EOF)
      break;
    if (ch == '\n')
      break;
    str[i] = ch;
    i++;
  }
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readFromStdin>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rbx
  mov    D6(%rip),%rbp
L11:
  mov    0x0(%rbp),%edi
  call   <fgetc@plt>
  mov    D10(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L27
  cmp    $0xa,%eax
  je     L27
  mov    %al,(%rbx)
  add    $0x1,%rbx
  jmp    L11
L27:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *readFromStdin(int size) {
  char *str = malloc(size);
  int ch;
  int i = 0;
  while (1) {
    ch = fgetc(stdin);
    if (ch == EOF)
      break;
    if (ch == '\n')
      break;
    str[i] = ch;
    i++;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readFromStdin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    D12(%rip),%r12
  mov    D5(%rip),%rbp
  mov    %rax,%r13
  mov    %rax,%rbx
  jmp    L28
  nopl   0x0(%rax)
L2:
  cmp    $0xa,%eax
  je     L7
  mov    %al,(%rbx)
  add    $0x1,%rbx
L28:
  mov    (%r12),%edi
  call   <fgetc@plt>
  cmp    %eax,0x0(%rbp)
  jne    L2
L7:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *readFromStdin(int size) {
  char *str = malloc(size);
  int ch;
  int i = 0;
  while (1) {
    ch = fgetc(stdin);
    if (ch == EOF)
      break;
    if (ch == '\n')
      break;
    str[i] = ch;
    i++;
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readFromStdin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    D13(%rip),%r12
  mov    D3(%rip),%rbp
  mov    %rax,%r13
  mov    %rax,%rbx
  jmp    L7
  nopl   0x0(%rax)
L26:
  cmp    $0xa,%eax
  je     L24
  mov    %al,(%rbx)
  add    $0x1,%rbx
L7:
  mov    (%r12),%edi
  call   <fgetc@plt>
  cmp    %eax,0x0(%rbp)
  jne    L26
L24:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *readFromStdin(int size) {
  char *str = malloc(size);
  int ch;
  int i = 0;
  while (1) {
    ch = fgetc(stdin);
    if (ch == EOF)
      break;
    if (ch == '\n')
      break;
    str[i] = ch;
    i++;
  }
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fix_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%edx
  lea    -0x12(%rbp),%rax
  movd   %edx,%xmm0
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  movss  -0x18(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D11: %8.4e

tool: D3: %e

assistant: ```c
float fix_float(float number) {
  float result;
  char ascii[10];
  sprintf(ascii, "%8.4e", number);
  sscanf(ascii, "%e", &result);
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fix_float>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    0x8(%rsp),%rdx
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  movss  0x8(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D15
datatype: string

tool: D18: %8.4e

tool: D15: %e

assistant: ```c
float fix_float(float number) {
  float result;
  char ascii[10];
  sprintf(ascii, "%8.4e", number);
  sscanf(ascii, "%e", &result);
  return (result);
}
```
user: What is the c source code of the assembly code below:

```asm
<fix_float>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x8(%rsp),%rdx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  movss  0x8(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D9
type_guessed: string

tool: D6: %8.4e

tool: D9: %e

assistant: ```c
float fix_float(float number) {
  float result;
  char ascii[10];
  sprintf(ascii, "%8.4e", number);
  sscanf(ascii, "%e", &result);
  return (result);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fix_float>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x8(%rsp),%rdx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  movss  0x8(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D19
type_infered: string
name: unpack_data
arguments: tag: D0
type_infered: string

tool: D19: %8.4e

tool: D0: %e

assistant: ```c
float fix_float(float number) {
  float result;
  char ascii[10];
  sprintf(ascii, "%8.4e", number);
  sscanf(ascii, "%e", &result);
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pruefe_siegesbedingung>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x8(%rbp)
  cltq
  mov    %rax,%r10
  mov    $0x0,%r11d
  movb   $0x0,-0x9(%rbp)
  mov    -0x28(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <pruefe_siegesbedingung_horizontal@plt>
  test   %eax,%eax
  setne  %al
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  xor    $0x1,%eax
  test   %al,%al
  je     L9
  mov    -0x28(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <pruefe_siegesbedingung_vertikal@plt>
  test   %eax,%eax
  setne  %al
  mov    %al,-0x9(%rbp)
L9:
  movzbl -0x9(%rbp),%eax
  xor    $0x1,%eax
  test   %al,%al
  je     L2
  mov    -0x28(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <pruefe_siegesbedingung_diagonal@plt>
  test   %eax,%eax
  setne  %al
  mov    %al,-0x9(%rbp)
L2:
  movzbl -0x9(%rbp),%eax
  leave
  ret
```

assistant: ```c
_Bool pruefe_siegesbedingung(int zeilen, int spalten, int spielfeld[zeilen][spalten], int laenge_linie, int spielstein) {
  _Bool gewonnen = 0;
  gewonnen = pruefe_siegesbedingung_horizontal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  if (gewonnen == 0)
    gewonnen = pruefe_siegesbedingung_vertikal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  if (gewonnen == 0)
    gewonnen = pruefe_siegesbedingung_diagonal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  return gewonnen;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pruefe_siegesbedingung>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  mov    $0x0,%eax
  call   <pruefe_siegesbedingung_horizontal@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L29
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <pruefe_siegesbedingung_vertikal@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L3
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <pruefe_siegesbedingung_diagonal@plt>
  test   %eax,%eax
  setne  %al
  jmp    L3
```

assistant: ```c
_Bool pruefe_siegesbedingung(int zeilen, int spalten, int spielfeld[zeilen][spalten], int laenge_linie, int spielstein) {
  _Bool gewonnen = 0;
  gewonnen = pruefe_siegesbedingung_horizontal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  if (gewonnen == 0)
    gewonnen = pruefe_siegesbedingung_vertikal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  if (gewonnen == 0)
    gewonnen = pruefe_siegesbedingung_diagonal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  return gewonnen;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pruefe_siegesbedingung>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8d,%ebx
  call   <pruefe_siegesbedingung_horizontal@plt>
  test   %eax,%eax
  je     L12
L5:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <pruefe_siegesbedingung_vertikal@plt>
  test   %eax,%eax
  jne    L5
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <pruefe_siegesbedingung_diagonal@plt>
  pop    %rbx
  pop    %rbp
  test   %eax,%eax
  pop    %r12
  pop    %r13
  setne  %al
  pop    %r14
  ret
```

assistant: ```c
_Bool pruefe_siegesbedingung(int zeilen, int spalten, int spielfeld[zeilen][spalten], int laenge_linie, int spielstein) {
  _Bool gewonnen = 0;
  gewonnen = pruefe_siegesbedingung_horizontal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  if (gewonnen == 0)
    gewonnen = pruefe_siegesbedingung_vertikal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  if (gewonnen == 0)
    gewonnen = pruefe_siegesbedingung_diagonal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  return gewonnen;
}
```
user: What is the c source code of the assembly code below?

```asm
<pruefe_siegesbedingung>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8d,%ebx
  call   <pruefe_siegesbedingung_horizontal@plt>
  test   %eax,%eax
  je     L11
L4:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <pruefe_siegesbedingung_vertikal@plt>
  test   %eax,%eax
  jne    L4
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <pruefe_siegesbedingung_diagonal@plt>
  pop    %rbx
  pop    %rbp
  test   %eax,%eax
  pop    %r12
  pop    %r13
  setne  %al
  pop    %r14
  ret
```

assistant: ```c
_Bool pruefe_siegesbedingung(int zeilen, int spalten, int spielfeld[zeilen][spalten], int laenge_linie, int spielstein) {
  _Bool gewonnen = 0;
  gewonnen = pruefe_siegesbedingung_horizontal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  if (gewonnen == 0)
    gewonnen = pruefe_siegesbedingung_vertikal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  if (gewonnen == 0)
    gewonnen = pruefe_siegesbedingung_diagonal(zeilen, spalten, spielfeld, laenge_linie, spielstein);
  return gewonnen;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SumArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int SumArray(int Array[], int Num) {
  int i, Result = 0;
  for (i = 0; i < Num; ++i)
    Result += Array[i];
  return Result;
}
```