ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_netmask_prefix_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L12
  mov    %edi,%ebx
  xor    %r12d,%r12d
  lea    D9(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%eax
  mov    %rbp,%rdi
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r12d
  shr    %ebx
  mov    %ebx,%esi
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L10
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: mask = 0x%x


assistant: ```c
int get_netmask_prefix_len(unsigned int mask) {
  int prefix = 0, max_loop = sizeof(mask) * 8 + 1;
  while (mask) {
    if (mask & 1)
      prefix++;
    mask >>= 1;
    printf("mask = 0x%x\n", mask);
  }
  return prefix;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_netmask_prefix_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L6
  mov    %edi,%ebx
  xor    %r12d,%r12d
  lea    D2(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%eax
  mov    %rbp,%rdi
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r12d
  shr    %ebx
  mov    %ebx,%esi
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L2
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D2: mask = 0x%x


assistant: ```c
int get_netmask_prefix_len(unsigned int mask) {
  int prefix = 0, max_loop = sizeof(mask) * 8 + 1;
  while (mask) {
    if (mask & 1)
      prefix++;
    mask >>= 1;
    printf("mask = 0x%x\n", mask);
  }
  return prefix;
}
```
user: What is the c source code of the assembly code below?

```asm
<standard_diagonal_homotopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa5,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int standard_diagonal_homotopy(int a, int b) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(165, &a, &b, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<standard_diagonal_homotopy>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0xa5,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int standard_diagonal_homotopy(int a, int b) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(165, &a, &b, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<standard_diagonal_homotopy>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0xa5,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int standard_diagonal_homotopy(int a, int b) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(165, &a, &b, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<standard_diagonal_homotopy>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0xa5,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int standard_diagonal_homotopy(int a, int b) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(165, &a, &b, c);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prefixParser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %rdx,-0x448(%rbp)
  mov    %rcx,-0x450(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x448(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x424(%rbp)
  mov    -0x438(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  add    $0x1,%rax
  mov    -0x440(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x418(%rbp)
  jmp    L19
L2:
  mov    -0x440(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x418(%rbp)
L19:
  cmpq   $0x0,-0x418(%rbp)
  je     L22
  mov    -0x424(%rbp),%edx
  mov    -0x448(%rbp),%rcx
  mov    -0x418(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L2
L22:
  cmpq   $0x0,-0x418(%rbp)
  jne    L16
  mov    -0x438(%rbp),%rdx
  mov    -0x450(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  mov    -0x424(%rbp),%edx
  mov    -0x418(%rbp),%rcx
  lea    -0x420(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <StrUtil_copyString@plt>
  mov    %rax,-0x420(%rbp)
  mov    -0x420(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: Error parsing ID in %s from string %s


assistant: ```c
char *prefixParser(char *header, char *delim, char *prefix, char *routine) {
  char *token;
  char workStr[1024];
  char *retToken;
  int len = strlen(prefix);
  strcpy(workStr, header);
  token = strtok(workStr + 1, delim);
  while (token && strncmp(token, prefix, len)) {
    token = strtok(NULL, delim);
  }
  if (token == NULL) {
    printf("Error parsing ID in %s from string %s\n", routine, header);
  }
  retToken = StrUtil_copyString(&retToken, token, len);
  return retToken;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prefixParser>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x10(%rsp),%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  lea    0x11(%rsp),%rdi
  mov    %r13,%rsi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L13
L28:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L1
  mov    %r13,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L28
L13:
  mov    %r14,%rdx
  mov    %r15,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L34
L1:
  test   %rbx,%rbx
  je     L13
L34:
  lea    0x8(%rsp),%rdi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <StrUtil_copyString@plt>
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: Error parsing ID in %s from string %s


assistant: ```c
char *prefixParser(char *header, char *delim, char *prefix, char *routine) {
  char *token;
  char workStr[1024];
  char *retToken;
  int len = strlen(prefix);
  strcpy(workStr, header);
  token = strtok(workStr + 1, delim);
  while (token && strncmp(token, prefix, len)) {
    token = strtok(NULL, delim);
  }
  if (token == NULL) {
    printf("Error parsing ID in %s from string %s\n", routine, header);
  }
  retToken = StrUtil_copyString(&retToken, token, len);
  return retToken;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prefixParser>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x10(%rsp),%rdi
  mov    %r14,%rsi
  mov    %eax,%r12d
  call   <strcpy@plt>
  lea    0x11(%rsp),%rdi
  mov    %r13,%rsi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L48
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L51
L48:
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L52
L35:
  mov    %r12d,%edx
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <StrUtil_copyString@plt>
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r14,%rdx
  mov    %r15,%rsi
  lea    D1(%rip),%rdi
  xor    %ebp,%ebp
  call   <printf@plt>
  jmp    L35
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: Error parsing ID in %s from string %s


assistant: ```c
char *prefixParser(char *header, char *delim, char *prefix, char *routine) {
  char *token;
  char workStr[1024];
  char *retToken;
  int len = strlen(prefix);
  strcpy(workStr, header);
  token = strtok(workStr + 1, delim);
  while (token && strncmp(token, prefix, len)) {
    token = strtok(NULL, delim);
  }
  if (token == NULL) {
    printf("Error parsing ID in %s from string %s\n", routine, header);
  }
  retToken = StrUtil_copyString(&retToken, token, len);
  return retToken;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prefixParser>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x10(%rsp),%rdi
  mov    %r14,%rsi
  mov    %eax,%r12d
  call   <strcpy@plt>
  lea    0x11(%rsp),%rdi
  mov    %r13,%rsi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L16
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L2
L16:
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L32
L47:
  mov    %r12d,%edx
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <StrUtil_copyString@plt>
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r14,%rdx
  mov    %r15,%rsi
  lea    D4(%rip),%rdi
  xor    %ebp,%ebp
  call   <printf@plt>
  jmp    L47
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: Error parsing ID in %s from string %s


assistant: ```c
char *prefixParser(char *header, char *delim, char *prefix, char *routine) {
  char *token;
  char workStr[1024];
  char *retToken;
  int len = strlen(prefix);
  strcpy(workStr, header);
  token = strtok(workStr + 1, delim);
  while (token && strncmp(token, prefix, len)) {
    token = strtok(NULL, delim);
  }
  if (token == NULL) {
    printf("Error parsing ID in %s from string %s\n", routine, header);
  }
  retToken = StrUtil_copyString(&retToken, token, len);
  return retToken;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getcoms>:
  endbr64
  test   %r8d,%r8d
  jle    L28
  push   %rbx
  mov    %rdi,%r9
  mov    %rdx,%r11
  mov    %ecx,%r10d
  mov    %rsi,%rdi
  lea    -0x1(%r8),%eax
  lea    (%rax,%rax,2),%rax
  lea    0x18(%rsi,%rax,8),%rbx
  lea    -0x1(%rcx),%eax
  lea    0x8(%rdx,%rax,8),%rcx
  mov    $0x0,%esi
  jmp    L2
L53:
  movslq %esi,%rax
  lea    (%r9,%rax,8),%rax
  mov    %r11,%rdx
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm4
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm2
L3:
  movsd  (%rdx),%xmm0
  movapd %xmm0,%xmm5
  mulsd  (%rax),%xmm5
  addsd  %xmm5,%xmm2
  movapd %xmm0,%xmm5
  mulsd  0x8(%rax),%xmm5
  addsd  %xmm5,%xmm3
  movapd %xmm0,%xmm5
  mulsd  0x10(%rax),%xmm5
  addsd  %xmm5,%xmm4
  addsd  %xmm0,%xmm1
  add    $0x8,%rdx
  add    $0x18,%rax
  cmp    %rcx,%rdx
  jne    L3
L51:
  divsd  %xmm1,%xmm2
  movsd  %xmm2,(%rdi)
  divsd  %xmm1,%xmm3
  movsd  %xmm3,0x8(%rdi)
  divsd  %xmm1,%xmm4
  movsd  %xmm4,0x10(%rdi)
  add    $0x18,%rdi
  add    %r8d,%esi
  cmp    %rbx,%rdi
  je     L23
L2:
  test   %r10d,%r10d
  jg     L53
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm4
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm2
  jmp    L51
L23:
  pop    %rbx
  ret
L28:
  ret
```

assistant: ```c
void getcoms(double *pos, double *coms, double *masslist, int beads, int mols) {
  int i, j;
  double x, y, z, X, Y, Z, M;
  for (i = 0; i < mols; i++) {
    X = 0;
    Y = 0;
    Z = 0;
    M = 0;
    for (j = 0; j < beads; j++) {
      x = masslist[j] * pos[mols * i + 3 * j];
      y = masslist[j] * pos[mols * i + 3 * j + 1];
      z = masslist[j] * pos[mols * i + 3 * j + 2];
      X += x;
      Y += y;
      Z += z;
      M += masslist[j];
    }
    X /= M;
    Y /= M;
    Z /= M;
    coms[3 * i] = X;
    coms[3 * i + 1] = Y;
    coms[3 * i + 2] = Z;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getcoms>:
  endbr64
  test   %r8d,%r8d
  jle    L29
  lea    -0x1(%r8),%eax
  push   %rbx
  mov    %rdi,%r9
  mov    %ecx,%ebx
  lea    (%rax,%rax,2),%rax
  mov    %rdx,%r11
  pxor   %xmm6,%xmm6
  xor    %edi,%edi
  lea    0x18(%rsi,%rax,8),%r10
  lea    -0x1(%rcx),%eax
  lea    0x8(%rdx,%rax,8),%rcx
  nopl   0x0(%rax)
L2:
  test   %ebx,%ebx
  jle    L25
  movslq %edi,%rax
  movapd %xmm6,%xmm4
  movapd %xmm6,%xmm3
  mov    %r11,%rdx
  lea    (%r9,%rax,8),%rax
  movapd %xmm6,%xmm2
  movapd %xmm6,%xmm1
  nopw   0x0(%rax,%rax,1)
L4:
  movsd  (%rdx),%xmm0
  movsd  (%rax),%xmm5
  add    $0x8,%rdx
  add    $0x18,%rax
  mulsd  %xmm0,%xmm5
  addsd  %xmm0,%xmm4
  addsd  %xmm5,%xmm1
  movsd  -0x10(%rax),%xmm5
  mulsd  %xmm0,%xmm5
  addsd  %xmm5,%xmm2
  movsd  -0x8(%rax),%xmm5
  mulsd  %xmm0,%xmm5
  addsd  %xmm5,%xmm3
  cmp    %rdx,%rcx
  jne    L4
L42:
  divsd  %xmm4,%xmm1
  add    $0x18,%rsi
  add    %r8d,%edi
  divsd  %xmm4,%xmm2
  movsd  %xmm1,-0x18(%rsi)
  divsd  %xmm4,%xmm3
  movsd  %xmm2,-0x10(%rsi)
  movsd  %xmm3,-0x8(%rsi)
  cmp    %rsi,%r10
  jne    L2
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  movapd %xmm6,%xmm4
  movapd %xmm6,%xmm3
  movapd %xmm6,%xmm2
  movapd %xmm6,%xmm1
  jmp    L42
L29:
  ret
```

assistant: ```c
void getcoms(double *pos, double *coms, double *masslist, int beads, int mols) {
  int i, j;
  double x, y, z, X, Y, Z, M;
  for (i = 0; i < mols; i++) {
    X = 0;
    Y = 0;
    Z = 0;
    M = 0;
    for (j = 0; j < beads; j++) {
      x = masslist[j] * pos[mols * i + 3 * j];
      y = masslist[j] * pos[mols * i + 3 * j + 1];
      z = masslist[j] * pos[mols * i + 3 * j + 2];
      X += x;
      Y += y;
      Z += z;
      M += masslist[j];
    }
    X /= M;
    Y /= M;
    Z /= M;
    coms[3 * i] = X;
    coms[3 * i + 1] = Y;
    coms[3 * i + 2] = Z;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getcoms>:
  endbr64
  test   %r8d,%r8d
  jle    L35
  lea    -0x1(%r8),%eax
  push   %rbp
  mov    %ecx,%r11d
  mov    %rdx,%r9
  lea    (%rax,%rax,2),%rax
  push   %rbx
  mov    %ecx,%ebx
  pxor   %xmm7,%xmm7
  lea    0x18(%rsi,%rax,8),%rbp
  mov    %ecx,%eax
  and    $0xfffffffe,%ebx
  xor    %ecx,%ecx
  shr    %eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%rdx,%rax,1),%r10
  nopl   (%rax)
L61:
  pxor   %xmm5,%xmm5
  movapd %xmm7,%xmm8
  movapd %xmm7,%xmm4
  test   %r11d,%r11d
  jle    L7
  cmp    $0x1,%r11d
  je     L20
  movslq %ecx,%rax
  pxor   %xmm5,%xmm5
  movapd %xmm7,%xmm8
  mov    %r9,%rdx
  lea    (%rdi,%rax,8),%rax
  movapd %xmm7,%xmm4
  nopw   0x0(%rax,%rax,1)
L8:
  movupd (%rax),%xmm6
  movupd (%rdx),%xmm1
  add    $0x10,%rdx
  add    $0x30,%rax
  movupd -0x20(%rax),%xmm0
  movapd %xmm6,%xmm2
  movhps -0x18(%rax),%xmm2
  movapd %xmm6,%xmm3
  shufpd $0x1,%xmm6,%xmm3
  movhpd -0x10(%rax),%xmm3
  unpcklpd %xmm6,%xmm0
  movhps -0x8(%rax),%xmm0
  mulpd  %xmm1,%xmm2
  mulpd  %xmm1,%xmm3
  mulpd  %xmm1,%xmm0
  movapd %xmm2,%xmm6
  unpcklpd %xmm3,%xmm6
  unpckhpd %xmm3,%xmm2
  addpd  %xmm6,%xmm5
  addpd  %xmm2,%xmm5
  movapd %xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  addsd  %xmm4,%xmm2
  movapd %xmm0,%xmm4
  movapd %xmm1,%xmm0
  addsd  %xmm8,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm2,%xmm4
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm8
  cmp    %r10,%rdx
  jne    L8
  mov    %ebx,%eax
  cmp    %r11d,%ebx
  je     L7
L48:
  movslq %eax,%rdx
  lea    (%rax,%rax,2),%eax
  movsd  (%r9,%rdx,8),%xmm0
  add    %ecx,%eax
  cltq
  movupd (%rdi,%rax,8),%xmm3
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm8
  unpcklpd %xmm1,%xmm1
  mulpd  %xmm3,%xmm1
  addpd  %xmm1,%xmm5
  movsd  0x10(%rdi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm4
L7:
  movapd %xmm8,%xmm0
  add    $0x18,%rsi
  add    %r8d,%ecx
  divsd  %xmm8,%xmm4
  unpcklpd %xmm0,%xmm0
  divpd  %xmm0,%xmm5
  movsd  %xmm4,-0x8(%rsi)
  movups %xmm5,-0x18(%rsi)
  cmp    %rbp,%rsi
  jne    L61
  pop    %rbx
  pop    %rbp
  ret
L20:
  pxor   %xmm5,%xmm5
  movapd %xmm7,%xmm8
  movapd %xmm7,%xmm4
  xor    %eax,%eax
  jmp    L48
L35:
  ret
```

assistant: ```c
void getcoms(double *pos, double *coms, double *masslist, int beads, int mols) {
  int i, j;
  double x, y, z, X, Y, Z, M;
  for (i = 0; i < mols; i++) {
    X = 0;
    Y = 0;
    Z = 0;
    M = 0;
    for (j = 0; j < beads; j++) {
      x = masslist[j] * pos[mols * i + 3 * j];
      y = masslist[j] * pos[mols * i + 3 * j + 1];
      z = masslist[j] * pos[mols * i + 3 * j + 2];
      X += x;
      Y += y;
      Z += z;
      M += masslist[j];
    }
    X /= M;
    Y /= M;
    Z /= M;
    coms[3 * i] = X;
    coms[3 * i + 1] = Y;
    coms[3 * i + 2] = Z;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tangent_y>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movsd  %xmm3,-0x50(%rbp)
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  movsd  -0x50(%rbp),%xmm2
  movsd  -0x48(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <normal@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  lea    -0x20(%rbp),%rcx
  movsd  -0x50(%rbp),%xmm2
  movsd  -0x48(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rdi
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <binlensd1@plt>
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm2
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x58(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm2
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x60(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void tangent_y(double x1, double x2, double d, double m1, double *ty1, double *ty2) {
  double n1, n2;
  double y11, y12, y22;
  normal(x1, x2, d, m1, &n1, &n2);
  binlensd1(x1, x2, d, m1, &y11, &y12, &y22);
  *ty1 = n1 * y12 - n2 * y11;
  *ty2 = n1 * y22 - n2 * y12;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tangent_y>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  movq   %xmm2,%r12
  movq   %xmm3,%r14
  mov    %rdi,%r15
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  call   <normal@plt>
  lea    0x20(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movq   %r14,%xmm3
  movq   %r12,%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <binlensd1@plt>
  movsd  (%rsp),%xmm0
  movsd  0x18(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm3,%xmm4
  mulsd  0x10(%rsp),%xmm4
  subsd  %xmm4,%xmm2
  movsd  %xmm2,(%r15)
  mulsd  0x20(%rsp),%xmm0
  mulsd  %xmm3,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%r13)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tangent_y(double x1, double x2, double d, double m1, double *ty1, double *ty2) {
  double n1, n2;
  double y11, y12, y22;
  normal(x1, x2, d, m1, &n1, &n2);
  binlensd1(x1, x2, d, m1, &y11, &y12, &y22);
  *ty1 = n1 * y12 - n2 * y11;
  *ty2 = n1 * y22 - n2 * y12;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tangent_y>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <normal@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  lea    0x40(%rsp),%rdx
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  lea    0x38(%rsp),%rsi
  lea    0x30(%rsp),%rdi
  call   <binlensd1@plt>
  movsd  0x20(%rsp),%xmm0
  movsd  0x38(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm4
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  0x40(%rsp),%xmm0
  mulsd  %xmm3,%xmm1
  subsd  %xmm4,%xmm2
  subsd  %xmm1,%xmm0
  movsd  %xmm2,0x0(%rbp)
  movsd  %xmm0,(%rbx)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tangent_y(double x1, double x2, double d, double m1, double *ty1, double *ty2) {
  double n1, n2;
  double y11, y12, y22;
  normal(x1, x2, d, m1, &n1, &n2);
  binlensd1(x1, x2, d, m1, &y11, &y12, &y22);
  *ty1 = n1 * y12 - n2 * y11;
  *ty2 = n1 * y22 - n2 * y12;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tangent_y>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <normal@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  lea    0x40(%rsp),%rdx
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  lea    0x38(%rsp),%rsi
  lea    0x30(%rsp),%rdi
  call   <binlensd1@plt>
  movsd  0x20(%rsp),%xmm0
  movsd  0x38(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm4
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  0x40(%rsp),%xmm0
  mulsd  %xmm3,%xmm1
  subsd  %xmm4,%xmm2
  subsd  %xmm1,%xmm0
  movsd  %xmm2,0x0(%rbp)
  movsd  %xmm0,(%rbx)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tangent_y(double x1, double x2, double d, double m1, double *ty1, double *ty2) {
  double n1, n2;
  double y11, y12, y22;
  normal(x1, x2, d, m1, &n1, &n2);
  binlensd1(x1, x2, d, m1, &y11, &y12, &y22);
  *ty1 = n1 * y12 - n2 * y11;
  *ty2 = n1 * y22 - n2 * y12;
}
```