ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<R_unif_index>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movapd %xmm0,%xmm2
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  jae    L7
  movapd %xmm2,%xmm0
  call   <log2@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,%ebx
L25:
  mov    %ebx,%edi
  call   <rbits@plt>
  comisd 0x8(%rsp),%xmm0
  jae    L25
L1:
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  pxor   %xmm0,%xmm0
  jmp    L1
```

assistant: ```c
double R_unif_index(double dn) {
  if (dn <= 0)
    return 0.0;
  int bits = (int)ceil(log2(dn));
  double dv;
  do {
    dv = rbits(bits);
  } while (dn <= dv);
  return dv;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<R_unif_index>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm2
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  jae    L11
  movapd %xmm2,%xmm0
  call   <log2@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,%ebx
  nop
L1:
  mov    %ebx,%edi
  call   <rbits@plt>
  comisd 0x8(%rsp),%xmm0
  jae    L1
L11:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double R_unif_index(double dn) {
  if (dn <= 0)
    return 0.0;
  int bits = (int)ceil(log2(dn));
  double dv;
  do {
    dv = rbits(bits);
  } while (dn <= dv);
  return dv;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<R_unif_index>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm2
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  jae    L5
  movapd %xmm2,%xmm0
  call   <log2@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,%ebx
  nop
L4:
  mov    %ebx,%edi
  call   <rbits@plt>
  comisd 0x8(%rsp),%xmm0
  jae    L4
L5:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double R_unif_index(double dn) {
  if (dn <= 0)
    return 0.0;
  int bits = (int)ceil(log2(dn));
  double dv;
  do {
    dv = rbits(bits);
  } while (dn <= dv);
  return dv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_palindrome1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L29:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L21
  mov    $0x0,%eax
  jmp    L37
L21:
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L29
  mov    $0x1,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int is_palindrome1(const char phrase[], int length) {
  int i, j;
  for (i = 0, j = length - 1; i < j; i++, j--) {
    if (phrase[i] != phrase[j]) {
      return 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_palindrome1>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L20
  movslq %esi,%rsi
  mov    $0x0,%eax
L0:
  movzbl (%rdi,%rsi,1),%edx
  cmp    %dl,(%rdi,%rax,1)
  jne    L8
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L0
  mov    $0x1,%eax
  ret
L20:
  mov    $0x1,%eax
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_palindrome1(const char phrase[], int length) {
  int i, j;
  for (i = 0, j = length - 1; i < j; i++, j--) {
    if (phrase[i] != phrase[j]) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_palindrome1>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L39
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jge    L39
L37:
  movzbl (%rdi,%rsi,1),%edx
  cmp    %dl,(%rdi,%rax,1)
  je     L30
  xor    %eax,%eax
  ret
L39:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_palindrome1(const char phrase[], int length) {
  int i, j;
  for (i = 0, j = length - 1; i < j; i++, j--) {
    if (phrase[i] != phrase[j]) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_palindrome1>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L23
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jge    L23
L5:
  movzbl (%rdi,%rsi,1),%edx
  cmp    %dl,(%rdi,%rax,1)
  je     L3
  xor    %eax,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_palindrome1(const char phrase[], int length) {
  int i, j;
  for (i = 0, j = length - 1; i < j; i++, j--) {
    if (phrase[i] != phrase[j]) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<replace_dot_by_N>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L0
L28:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L18
  addq   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x4e,(%rax)
L18:
  addq   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long replace_dot_by_N(char *seq) {
  long n = 0;
  long replaced = 0;
  while (seq[n] != '\0') {
    if (seq[n] == '.') {
      ++replaced;
      seq[n] = 'N';
    }
    ++n;
  }
  return replaced;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<replace_dot_by_N>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  mov    $0x0,%edx
  jmp    L29
L37:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
L29:
  cmp    $0x2e,%al
  jne    L37
  add    $0x1,%rdx
  movb   $0x4e,(%rdi)
  jmp    L37
L17:
  mov    $0x0,%edx
L28:
  mov    %rdx,%rax
  ret
```

assistant: ```c
long replace_dot_by_N(char *seq) {
  long n = 0;
  long replaced = 0;
  while (seq[n] != '\0') {
    if (seq[n] == '.') {
      ++replaced;
      seq[n] = 'N';
    }
    ++n;
  }
  return replaced;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<replace_dot_by_N>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L4
  xchg   %ax,%ax
L14:
  cmp    $0x2e,%al
  jne    L0
  movb   $0x4e,(%rdi)
  add    $0x1,%r8
L0:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L14
L4:
  mov    %r8,%rax
  ret
```

assistant: ```c
long replace_dot_by_N(char *seq) {
  long n = 0;
  long replaced = 0;
  while (seq[n] != '\0') {
    if (seq[n] == '.') {
      ++replaced;
      seq[n] = 'N';
    }
    ++n;
  }
  return replaced;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<replace_dot_by_N>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L38
  xchg   %ax,%ax
L33:
  cmp    $0x2e,%al
  je     L17
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L33
L38:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L17:
  movb   $0x4e,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  add    $0x1,%r8
  test   %al,%al
  jne    L33
  mov    %r8,%rax
  ret
```

assistant: ```c
long replace_dot_by_N(char *seq) {
  long n = 0;
  long replaced = 0;
  while (seq[n] != '\0') {
    if (seq[n] == '.') {
      ++replaced;
      seq[n] = 'N';
    }
    ++n;
  }
  return replaced;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tokpos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L27:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  jne    L36
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L20
L36:
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
L20:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int tokpos(char *str, int len, char tok) {
  int i;
  int pos = -1;
  for (i = 0; i < len; i++) {
    if (str[i] == tok) {
      pos = i;
      break;
    }
  }
  return pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tokpos>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    %esi,%esi
  mov    $0x0,%eax
L20:
  mov    %eax,%ecx
  cmp    %dl,(%rdi,%rax,1)
  je     L35
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L20
  mov    $0xffffffff,%ecx
L35:
  mov    %ecx,%eax
  ret
L16:
  mov    $0xffffffff,%ecx
  jmp    L35
```

assistant: ```c
int tokpos(char *str, int len, char tok) {
  int i;
  int pos = -1;
  for (i = 0; i < len; i++) {
    if (str[i] == tok) {
      pos = i;
      break;
    }
  }
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tokpos>:
  endbr64
  test   %esi,%esi
  jle    L12
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L0
  nop
L19:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L12
L0:
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  jne    L19
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L12:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int tokpos(char *str, int len, char tok) {
  int i;
  int pos = -1;
  for (i = 0; i < len; i++) {
    if (str[i] == tok) {
      pos = i;
      break;
    }
  }
  return pos;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tokpos>:
  endbr64
  test   %esi,%esi
  jle    L28
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L3
  nop
L1:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L28
L3:
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  jne    L1
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L28:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int tokpos(char *str, int len, char tok) {
  int i;
  int pos = -1;
  for (i = 0; i < len; i++) {
    if (str[i] == tok) {
      pos = i;
      break;
    }
  }
  return pos;
}
```
user: What is the c source code of the assembly code below:

```asm
<login>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x20(%rbp)
  mov    D37(%rip),%rax
  mov    (%rax),%ecx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x24(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <htons@plt>
  mov    %eax,-0x10(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <inet_pton@plt>
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int login(char *ip, char *port) {
  int fd_socket;
  long port_number = strtol(port, NULL, 0);
  struct sockaddr_in servaddr;
  fd_socket = socket(AF_INET, SOCK_STREAM, 0);
  memset(&servaddr, 0, sizeof(servaddr));
  servaddr.sin_family = AF_INET;
  servaddr.sin_port = htons(port_number);
  inet_pton(AF_INET, ip, &(servaddr.sin_addr));
  connect(fd_socket, (struct sockaddr *)&servaddr, sizeof(servaddr));
  return fd_socket;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<login>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%r14
  mov    D17(%rip),%r12
  mov    $0x0,%edx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  mov    (%r12),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  lea    0xc(%rsp),%rbp
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%r12),%eax
  mov    %eax,0x14(%rsp)
  mov    %r14,%rdi
  call   <htons@plt>
  mov    %eax,0x10(%rsp)
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    (%r12),%edi
  call   <inet_pton@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <connect@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int login(char *ip, char *port) {
  int fd_socket;
  long port_number = strtol(port, NULL, 0);
  struct sockaddr_in servaddr;
  fd_socket = socket(AF_INET, SOCK_STREAM, 0);
  memset(&servaddr, 0, sizeof(servaddr));
  servaddr.sin_family = AF_INET;
  servaddr.sin_port = htons(port_number);
  inet_pton(AF_INET, ip, &(servaddr.sin_addr));
  connect(fd_socket, (struct sockaddr *)&servaddr, sizeof(servaddr));
  return fd_socket;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<login>:
  endbr64
  push   %r14
  xor    %edx,%edx
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  xor    %esi,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <strtol@plt>
  mov    D2(%rip),%rbx
  xor    %edx,%edx
  mov    %rax,%r14
  mov    D0(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %r14,%rdi
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    (%rbx),%edi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %eax,0x10(%rsp)
  call   <inet_pton@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int login(char *ip, char *port) {
  int fd_socket;
  long port_number = strtol(port, NULL, 0);
  struct sockaddr_in servaddr;
  fd_socket = socket(AF_INET, SOCK_STREAM, 0);
  memset(&servaddr, 0, sizeof(servaddr));
  servaddr.sin_family = AF_INET;
  servaddr.sin_port = htons(port_number);
  inet_pton(AF_INET, ip, &(servaddr.sin_addr));
  connect(fd_socket, (struct sockaddr *)&servaddr, sizeof(servaddr));
  return fd_socket;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<login>:
  endbr64
  push   %r14
  xor    %edx,%edx
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  xor    %esi,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <strtol@plt>
  mov    D8(%rip),%rbx
  xor    %edx,%edx
  mov    %rax,%r14
  mov    D12(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %r14,%rdi
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    (%rbx),%edi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %eax,0x10(%rsp)
  call   <inet_pton@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int login(char *ip, char *port) {
  int fd_socket;
  long port_number = strtol(port, NULL, 0);
  struct sockaddr_in servaddr;
  fd_socket = socket(AF_INET, SOCK_STREAM, 0);
  memset(&servaddr, 0, sizeof(servaddr));
  servaddr.sin_family = AF_INET;
  servaddr.sin_port = htons(port_number);
  inet_pton(AF_INET, ip, &(servaddr.sin_addr));
  connect(fd_socket, (struct sockaddr *)&servaddr, sizeof(servaddr));
  return fd_socket;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<slab_deinit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <slab_deinit_ctable@plt>
  mov    $0x0,%eax
  call   <slab_deinit_stable@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void slab_deinit(void) {
  slab_deinit_ctable();
  slab_deinit_stable();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<slab_deinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <slab_deinit_ctable@plt>
  mov    $0x0,%eax
  call   <slab_deinit_stable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void slab_deinit(void) {
  slab_deinit_ctable();
  slab_deinit_stable();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<slab_deinit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <slab_deinit_ctable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <slab_deinit_stable@plt>
```

assistant: ```c
void slab_deinit(void) {
  slab_deinit_ctable();
  slab_deinit_stable();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<slab_deinit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <slab_deinit_ctable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <slab_deinit_stable@plt>
```

assistant: ```c
void slab_deinit(void) {
  slab_deinit_ctable();
  slab_deinit_stable();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vp8cx_vertical_band_4_5_scale_c>:
  endbr64
  test   %edx,%edx
  je     L18
  push   %r14
  push   %rbx
  mov    %rdi,%rax
  lea    (%rsi,%rsi,1),%ecx
  mov    %ecx,%r9d
  lea    (%rcx,%rsi,1),%r8d
  lea    0x0(,%rsi,4),%r11d
  lea    (%r11,%rsi,1),%r14d
  mov    %r11d,%r11d
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%r10
  mov    %esi,%edi
L11:
  movzbl (%rax,%rdi,1),%esi
  movzbl (%rax),%edx
  imul   $0x33,%edx,%edx
  imul   $0xcd,%esi,%ecx
  lea    0x80(%rdx,%rcx,1),%edx
  movzbl %dh,%ecx
  mov    %cl,(%rax,%rdi,1)
  movzbl (%rax,%r9,1),%ecx
  imul   $0x9a,%ecx,%ecx
  movzbl (%rax,%r8,1),%edx
  imul   $0x66,%esi,%esi
  lea    0x80(%rcx,%rsi,1),%esi
  mov    %esi,%ebx
  movzbl %bh,%ebx
  mov    %bl,(%rax,%r9,1)
  imul   $0x66,%edx,%esi
  lea    0x80(%rcx,%rsi,1),%ecx
  movzbl %ch,%ebx
  mov    %bl,(%rax,%r8,1)
  movzbl (%rax,%r14,1),%ecx
  imul   $0x33,%ecx,%ecx
  imul   $0xcd,%edx,%edx
  lea    0x80(%rcx,%rdx,1),%edx
  movzbl %dh,%ebx
  mov    %bl,(%rax,%r11,1)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L11
  pop    %rbx
  pop    %r14
  ret
L18:
  ret
```

assistant: ```c
void vp8cx_vertical_band_4_5_scale_c(unsigned char *dest, unsigned int dest_pitch, unsigned int dest_width) {
  unsigned int i;
  unsigned int a, b, c, d;
  unsigned char *des = dest;
  for (i = 0; i < dest_width; i++) {
    a = des[0];
    b = des[dest_pitch];
    des[dest_pitch] = (unsigned char)((a * 51 + 205 * b + 128) >> 8);
    c = des[dest_pitch * 2] * 154;
    d = des[dest_pitch * 3];
    des[dest_pitch * 2] = (unsigned char)((b * 102 + c + 128) >> 8);
    des[dest_pitch * 3] = (unsigned char)((c + 102 * d + 128) >> 8);
    a = des[dest_pitch * 5];
    des[dest_pitch * 4] = (unsigned char)((d * 205 + 51 * a + 128) >> 8);
    des++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vp8cx_vertical_band_4_5_scale_c>:
  endbr64
  test   %edx,%edx
  je     L19
  push   %r14
  mov    %rdi,%rax
  lea    (%rsi,%rsi,1),%r9d
  mov    %edx,%edx
  push   %rbx
  lea    0x0(,%rsi,4),%r11d
  lea    (%r9,%rsi,1),%r8d
  mov    %esi,%edi
  lea    (%r11,%rsi,1),%r14d
  lea    (%rax,%rdx,1),%r10
  xchg   %ax,%ax
L12:
  movzbl (%rax,%rdi,1),%esi
  movzbl (%rax),%edx
  add    $0x1,%rax
  imul   $0xcd,%esi,%ecx
  imul   $0x33,%edx,%edx
  imul   $0x66,%esi,%esi
  lea    0x80(%rdx,%rcx,1),%edx
  mov    %dh,-0x1(%rax,%rdi,1)
  movzbl -0x1(%rax,%r9,1),%ecx
  movzbl -0x1(%rax,%r8,1),%edx
  imul   $0x9a,%ecx,%ecx
  lea    0x80(%rcx,%rsi,1),%esi
  mov    %esi,%ebx
  imul   $0x66,%edx,%esi
  movzbl %bh,%ebx
  imul   $0xcd,%edx,%edx
  mov    %bl,-0x1(%rax,%r9,1)
  lea    0x80(%rcx,%rsi,1),%ecx
  movzbl %ch,%ebx
  mov    %bl,-0x1(%rax,%r8,1)
  movzbl -0x1(%rax,%r14,1),%ecx
  imul   $0x33,%ecx,%ecx
  lea    0x80(%rcx,%rdx,1),%edx
  movzbl %dh,%ebx
  mov    %bl,-0x1(%rax,%r11,1)
  cmp    %r10,%rax
  jne    L12
  pop    %rbx
  pop    %r14
  ret
  xchg   %ax,%ax
L19:
  ret
```

assistant: ```c
void vp8cx_vertical_band_4_5_scale_c(unsigned char *dest, unsigned int dest_pitch, unsigned int dest_width) {
  unsigned int i;
  unsigned int a, b, c, d;
  unsigned char *des = dest;
  for (i = 0; i < dest_width; i++) {
    a = des[0];
    b = des[dest_pitch];
    des[dest_pitch] = (unsigned char)((a * 51 + 205 * b + 128) >> 8);
    c = des[dest_pitch * 2] * 154;
    d = des[dest_pitch * 3];
    des[dest_pitch * 2] = (unsigned char)((b * 102 + c + 128) >> 8);
    des[dest_pitch * 3] = (unsigned char)((c + 102 * d + 128) >> 8);
    a = des[dest_pitch * 5];
    des[dest_pitch * 4] = (unsigned char)((d * 205 + 51 * a + 128) >> 8);
    des++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vp8cx_vertical_band_4_5_scale_c>:
  endbr64
  test   %edx,%edx
  je     L19
  push   %r14
  mov    %rdi,%rax
  lea    (%rsi,%rsi,1),%r9d
  mov    %edx,%edx
  push   %rbx
  lea    0x0(,%rsi,4),%r11d
  lea    (%r9,%rsi,1),%r8d
  mov    %esi,%edi
  lea    (%r11,%rsi,1),%r14d
  lea    (%rax,%rdx,1),%r10
  xchg   %ax,%ax
L12:
  movzbl (%rax,%rdi,1),%esi
  movzbl (%rax),%edx
  add    $0x1,%rax
  imul   $0xcd,%esi,%ecx
  imul   $0x33,%edx,%edx
  imul   $0x66,%esi,%esi
  lea    0x80(%rdx,%rcx,1),%edx
  mov    %dh,-0x1(%rax,%rdi,1)
  movzbl -0x1(%rax,%r9,1),%ecx
  movzbl -0x1(%rax,%r8,1),%edx
  imul   $0x9a,%ecx,%ecx
  lea    0x80(%rcx,%rsi,1),%esi
  mov    %esi,%ebx
  imul   $0x66,%edx,%esi
  movzbl %bh,%ebx
  imul   $0xcd,%edx,%edx
  mov    %bl,-0x1(%rax,%r9,1)
  lea    0x80(%rcx,%rsi,1),%ecx
  movzbl %ch,%ebx
  mov    %bl,-0x1(%rax,%r8,1)
  movzbl -0x1(%rax,%r14,1),%ecx
  imul   $0x33,%ecx,%ecx
  lea    0x80(%rcx,%rdx,1),%edx
  movzbl %dh,%ebx
  mov    %bl,-0x1(%rax,%r11,1)
  cmp    %r10,%rax
  jne    L12
  pop    %rbx
  pop    %r14
  ret
  xchg   %ax,%ax
L19:
  ret
```

assistant: ```c
void vp8cx_vertical_band_4_5_scale_c(unsigned char *dest, unsigned int dest_pitch, unsigned int dest_width) {
  unsigned int i;
  unsigned int a, b, c, d;
  unsigned char *des = dest;
  for (i = 0; i < dest_width; i++) {
    a = des[0];
    b = des[dest_pitch];
    des[dest_pitch] = (unsigned char)((a * 51 + 205 * b + 128) >> 8);
    c = des[dest_pitch * 2] * 154;
    d = des[dest_pitch * 3];
    des[dest_pitch * 2] = (unsigned char)((b * 102 + c + 128) >> 8);
    des[dest_pitch * 3] = (unsigned char)((c + 102 * d + 128) >> 8);
    a = des[dest_pitch * 5];
    des[dest_pitch * 4] = (unsigned char)((d * 205 + 51 * a + 128) >> 8);
    des++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<se_8_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x80,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L8
  mov    -0x8(%rbp),%eax
  sub    $0x100,%eax
  mov    %eax,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int se_8_32(int reg) {
  int value = (0x000000ff & reg);
  int mask = 0x00000080;
  if (mask & reg) {
    value += 0xffffff00;
  }
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<se_8_32>:
  endbr64
  movzbl %dil,%eax
  sub    $0x100,%eax
  movzbl %dil,%edx
  test   $0x80,%dil
  cmove  %edx,%eax
  ret
```

assistant: ```c
int se_8_32(int reg) {
  int value = (0x000000ff & reg);
  int mask = 0x00000080;
  if (mask & reg) {
    value += 0xffffff00;
  }
  return value;
}
```