ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_strip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L3
  jmp    L50
  nopl   (%rax)
L49:
  movb   $0x0,(%r12,%rbx,1)
  test   %rbx,%rbx
  je     L50
L3:
  sub    $0x1,%rbx
  movzbl (%r12,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L49
  movzbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L35
  nopl   0x0(%rax)
L58:
  add    $0x1,%r12
L50:
  movzbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L58
L35:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *str_strip(char *p) {
  size_t len = strlen(p);
  while (len > 0 && isspace((unsigned char)p[len - 1]))
    p[--len] = '\0';
  while (isspace((unsigned char)*p))
    p++;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<slputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L0:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <write_serial@plt>
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void slputs(char *a) {
  int i = 0;
  while (a[i])
    write_serial(a[i++]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<slputs>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  push   %rbx
  lea    0x1(%rdi),%rbx
L16:
  movsbl %al,%edi
  call   <write_serial@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L16
  pop    %rbx
  ret
L18:
  ret
```

assistant: ```c
void slputs(char *a) {
  int i = 0;
  while (a[i])
    write_serial(a[i++]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<slputs>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  push   %rbx
  lea    0x1(%rdi),%rbx
L0:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <write_serial@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L0
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void slputs(char *a) {
  int i = 0;
  while (a[i])
    write_serial(a[i++]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<slputs>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
  push   %rbx
  lea    0x1(%rdi),%rbx
L19:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <write_serial@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L19
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void slputs(char *a) {
  int i = 0;
  while (a[i])
    write_serial(a[i++]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x5000(%rsp),%r11
L49:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L49
  sub    $0xde0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x5de0(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x5ddc(%rbp)
  jmp    L53
L3:
  addl   $0x1,-0x5ddc(%rbp)
  mov    -0x5ddc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x5dd0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L53:
  mov    -0x5de0(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x5de0(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x5ddc(%rbp)
  jl     L3
  mov    -0x5de0(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x5dd8(%rbp)
  jmp    L63
L78:
  mov    -0x5dd8(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x5dd8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    $0x1,%eax
  mov    %eax,-0x5dd4(%rbp)
  mov    -0x5dd4(%rbp),%eax
  mov    %eax,-0x5ddc(%rbp)
  jmp    L29
L37:
  mov    -0x5ddc(%rbp),%eax
  cltq
  mov    -0x5dd0(%rbp,%rax,4),%ecx
  mov    -0x5ddc(%rbp),%edx
  mov    -0x5dd8(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  cltq
  mov    -0x5dd0(%rbp,%rax,4),%edx
  mov    -0x5ddc(%rbp),%esi
  mov    -0x5dd8(%rbp),%eax
  add    %esi,%eax
  cltq
  mov    -0x5dd0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x5ddc(%rbp),%eax
  cltq
  mov    %edx,-0x5dd0(%rbp,%rax,4)
  addl   $0x1,-0x5ddc(%rbp)
L29:
  mov    -0x5dd4(%rbp),%edx
  mov    -0x5dd8(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x5ddc(%rbp)
  jl     L37
  subl   $0x1,-0x5dd8(%rbp)
L63:
  cmpl   $0x0,-0x5dd8(%rbp)
  jg     L78
  mov    -0x5dcc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string

tool: D15: %d

tool: D21: %d


assistant: ```c
int main() {
  int i, j, row, R, A[6000];
  scanf("%d", &R);
  for (i = 0; i < R * (R + 1) / 2; scanf("%d", A + (++i)))
    ;
  for (row = R - 1; row > 0; row--) {
    j = row * (row - 1) / 2 + 1;
    for (i = j; i < j + row; i++)
      A[i] += (A[i + row] > A[i + row + 1] ? A[i + row] : A[i + row + 1]);
  }
  return printf("%d\n", A[1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L31:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L31
  sub    $0xde0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x5dd8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    0x1(%rsi),%eax
  imul   %esi,%eax
  cmp    $0x1,%eax
  jle    L74
  lea    0x14(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D26(%rip),%r12
L53:
  add    $0x1,%ebx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  add    $0x4,%rbp
  lea    0x1(%rsi),%edx
  imul   %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L53
L74:
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L36
  movslq %esi,%rsi
  lea    0x10(%rsp),%r11
  mov    $0xfffffffe,%r10d
  lea    0x14(%rsp),%r9
L59:
  mov    %r8d,%eax
  sub    $0x1,%r8d
  mov    %r8d,%ecx
  imul   %eax,%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  lea    0x1(%rdx),%edi
  lea    (%rdi,%rax,1),%ecx
  cmp    %ecx,%edi
  jge    L43
  movslq %edx,%rdi
  lea    (%r11,%rdi,4),%rax
  mov    %r10d,%ebx
  sub    %edx,%ebx
  lea    (%rbx,%rcx,1),%edx
  add    %rdi,%rdx
  lea    (%r9,%rdx,4),%rdi
L35:
  mov    0x4(%rax,%rsi,4),%edx
  mov    (%rax,%rsi,4),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    %edx,0x4(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L35
L43:
  sub    $0x1,%rsi
  test   %r8d,%r8d
  jne    L59
L36:
  mov    0x14(%rsp),%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x5dd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L67
  add    $0x5de0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D23
datatype: string

tool: D26: %d

tool: D23: %d


assistant: ```c
int main() {
  int i, j, row, R, A[6000];
  scanf("%d", &R);
  for (i = 0; i < R * (R + 1) / 2; scanf("%d", A + (++i)))
    ;
  for (row = R - 1; row > 0; row--) {
    j = row * (row - 1) / 2 + 1;
    for (i = j; i < j + row; i++)
      A[i] += (A[i + row] > A[i + row + 1] ? A[i + row] : A[i + row + 1]);
  }
  return printf("%d\n", A[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L56:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L56
  sub    $0xde0,%rsp
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x5dd8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rsi
  lea    0x1(%rsi),%eax
  imul   %esi,%eax
  cmp    $0x1,%eax
  jle    L12
  lea    0x14(%rsp),%r12
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  movslq 0xc(%rsp),%rsi
  lea    0x1(%rsi),%edx
  imul   %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %ebp,%eax
  jg     L21
L12:
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L19
  lea    0x10(%rsp),%r11
  mov    $0xfffffffe,%r10d
  lea    0x14(%rsp),%r9
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %r8d,%eax
  sub    $0x1,%r8d
  mov    %r8d,%ecx
  imul   %eax,%ecx
  sar    %ecx
  lea    0x1(%rcx),%edi
  lea    (%rdi,%rax,1),%edx
  cmp    %edx,%edi
  jge    L17
  mov    %r10d,%ebx
  movslq %ecx,%rdi
  sub    %ecx,%ebx
  lea    (%r11,%rdi,4),%rax
  add    %ebx,%edx
  mov    %edx,%edx
  add    %rdi,%rdx
  lea    (%r9,%rdx,4),%rdi
  nopl   0x0(%rax,%rax,1)
L65:
  mov    0x4(%rax,%rsi,4),%edx
  mov    (%rax,%rsi,4),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    %edx,0x4(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L65
L17:
  sub    $0x1,%rsi
  test   %r8d,%r8d
  jne    L40
L19:
  mov    0x14(%rsp),%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x5dd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x5de0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D16
data_type: string

tool: D6: %d

tool: D16: %d


assistant: ```c
int main() {
  int i, j, row, R, A[6000];
  scanf("%d", &R);
  for (i = 0; i < R * (R + 1) / 2; scanf("%d", A + (++i)))
    ;
  for (row = R - 1; row > 0; row--) {
    j = row * (row - 1) / 2 + 1;
    for (i = j; i < j + row; i++)
      A[i] += (A[i + row] > A[i + row + 1] ? A[i + row] : A[i + row + 1]);
  }
  return printf("%d\n", A[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char inb(unsigned short port) {
  unsigned char v;
  asm volatile("inb %1,%0" : "=a"(v) : "dN"(port));
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inb(unsigned short port) {
  unsigned char v;
  asm volatile("inb %1,%0" : "=a"(v) : "dN"(port));
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inb(unsigned short port) {
  unsigned char v;
  asm volatile("inb %1,%0" : "=a"(v) : "dN"(port));
  return v;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inb(unsigned short port) {
  unsigned char v;
  asm volatile("inb %1,%0" : "=a"(v) : "dN"(port));
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L8
  mov    -0x28(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  add    %rax,-0x10(%rbp)
  jmp    L7
L6:
  subq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L7:
  cmpq   $0x0,-0x28(%rbp)
  jne    L6
  jmp    L66
L8:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L66
  jmp    L5
L36:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L5:
  cmpq   $0x0,-0x28(%rbp)
  jne    L36
L66:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memmove(void *d, const void *s, size_t n) {
  char *dst = (char *)d;
  const char *src = (const char *)s;
  if (src < dst) {
    src += n;
    dst += n;
    for (; n; --n)
      *--dst = *--src;
  } else if (dst < src)
    for (; n; --n)
      *dst++ = *src++;
  return d;
}
```
user: What is the c source code of the assembly code below:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jbe    L59
  test   %rdx,%rdx
  je     L42
L50:
  movzbl -0x1(%rsi,%rdx,1),%ecx
  mov    %cl,-0x1(%rax,%rdx,1)
  sub    $0x1,%rdx
  jne    L50
  ret
L59:
  jae    L42
  test   %rdx,%rdx
  je     L42
  mov    $0x0,%ecx
L17:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L17
L42:
  ret
```

assistant: ```c
void *memmove(void *d, const void *s, size_t n) {
  char *dst = (char *)d;
  const char *src = (const char *)s;
  if (src < dst) {
    src += n;
    dst += n;
    for (; n; --n)
      *--dst = *--src;
  } else if (dst < src)
    for (; n; --n)
      *dst++ = *src++;
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jbe    L35
  test   %rdx,%rdx
  je     L34
  nopl   0x0(%rax)
L21:
  movzbl -0x1(%rsi,%rdx,1),%ecx
  mov    %cl,-0x1(%rax,%rdx,1)
  sub    $0x1,%rdx
  jne    L21
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  jb     L46
L34:
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  test   %rdx,%rdx
  je     L34
  xor    %ecx,%ecx
  nop
L15:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L15
  ret
```

assistant: ```c
void *memmove(void *d, const void *s, size_t n) {
  char *dst = (char *)d;
  const char *src = (const char *)s;
  if (src < dst) {
    src += n;
    dst += n;
    for (; n; --n)
      *--dst = *--src;
  } else if (dst < src)
    for (; n; --n)
      *dst++ = *src++;
  return d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %rdx,%rax
  cmp    %rsi,%rdi
  jbe    L44
  test   %rdx,%rdx
  je     L215
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl -0x1(%rcx,%rax,1),%edx
  mov    %dl,-0x1(%r8,%rax,1)
  sub    $0x1,%rax
  jne    L5
L215:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L44:
  jae    L215
  test   %rdx,%rdx
  je     L215
  lea    0x1(%rsi),%rdi
  mov    %r8,%rsi
  lea    -0x1(%rdx),%rdx
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L162
  cmp    $0x6,%rdx
  jbe    L162
  cmp    $0xe,%rdx
  jbe    L105
  mov    %rax,%rsi
  xor    %edx,%edx
  and    $0xfffffffffffffff0,%rsi
  nopl   0x0(%rax)
L73:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rsi
  jne    L73
  mov    %rax,%r9
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%r9
  and    $0xf,%edx
  lea    (%r8,%r9,1),%rsi
  lea    (%rcx,%r9,1),%rdi
  cmp    %r9,%rax
  je     L215
  lea    -0x1(%rdx),%r10
  mov    %rdx,%rax
  cmp    $0x6,%r10
  jbe    L46
L217:
  mov    (%rcx,%r9,1),%rcx
  mov    %rcx,(%r8,%r9,1)
  mov    %rax,%rcx
  and    $0xfffffffffffffff8,%rcx
  sub    %rcx,%rdx
  add    %rcx,%rsi
  add    %rcx,%rdi
  cmp    %rcx,%rax
  je     L215
  lea    -0x1(%rdx),%r10
L46:
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  test   %r10,%r10
  je     L215
  movzbl 0x1(%rdi),%eax
  mov    %al,0x1(%rsi)
  cmp    $0x2,%rdx
  je     L215
  movzbl 0x2(%rdi),%eax
  mov    %al,0x2(%rsi)
  cmp    $0x3,%rdx
  je     L215
  movzbl 0x3(%rdi),%eax
  mov    %al,0x3(%rsi)
  cmp    $0x4,%rdx
  je     L215
  movzbl 0x4(%rdi),%eax
  mov    %al,0x4(%rsi)
  cmp    $0x5,%rdx
  je     L215
  movzbl 0x5(%rdi),%eax
  mov    %al,0x5(%rsi)
  cmp    $0x6,%rdx
  je     L215
  movzbl 0x6(%rdi),%eax
  mov    %al,0x6(%rsi)
  jmp    L215
L162:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L115:
  movzbl (%rcx,%rdx,1),%esi
  mov    %sil,(%r8,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L115
  jmp    L215
L105:
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    %rax,%rdx
  xor    %r9d,%r9d
  jmp    L217
```

assistant: ```c
void *memmove(void *d, const void *s, size_t n) {
  char *dst = (char *)d;
  const char *src = (const char *)s;
  if (src < dst) {
    src += n;
    dst += n;
    for (; n; --n)
      *--dst = *--src;
  } else if (dst < src)
    for (; n; --n)
      *dst++ = *src++;
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<skipline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %edi,-0x3f4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L27
L13:
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  subl   $0x1,-0x3f4(%rbp)
L27:
  cmpl   $0x0,-0x3f4(%rbp)
  jne    L13
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void skipline(int n) {
  char line[1000];
  while (n) {
    fgets(line, 1000, stdin);
    n--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<skipline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L29
  mov    %edi,%ebx
  mov    D7(%rip),%rbp
L10:
  mov    %rsp,%rdi
  mov    0x0(%rbp),%edx
  mov    $0x3e8,%esi
  call   <fgets@plt>
  sub    $0x1,%ebx
  jne    L10
L29:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void skipline(int n) {
  char line[1000];
  while (n) {
    fgets(line, 1000, stdin);
    n--;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<skipline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L15
  mov    D8(%rip),%r12
  mov    %edi,%ebx
  mov    %rsp,%rbp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%r12),%edx
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  sub    $0x1,%ebx
  jne    L19
L15:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x3f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void skipline(int n) {
  char line[1000];
  while (n) {
    fgets(line, 1000, stdin);
    n--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skipline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L22
  mov    D7(%rip),%r12
  mov    %edi,%ebx
  mov    %rsp,%rbp
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%r12),%edx
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  sub    $0x1,%ebx
  jne    L26
L22:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x3f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void skipline(int n) {
  char line[1000];
  while (n) {
    fgets(line, 1000, stdin);
    n--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ADSGetByteB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x0,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOInput@plt>
  movb   $0x0,-0x5(%rbp)
  jmp    L21
L6:
  shll   -0x4(%rbp)
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinRead@plt>
  and    $0x20,%eax
  test   %eax,%eax
  je     L24
  orl    $0x1,-0x4(%rbp)
L24:
  movzbl -0x5(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
L21:
  cmpb   $0x7,-0x5(%rbp)
  jbe    L6
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0x0,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char ADSGetByteB() {
  unsigned char i = 0;
  unsigned int temp = 0;
  GPIOPinTypeGPIOInput(0x40007000, 0x00000020);
  for (i = 0; i < 8; i++) {
    temp = temp << 1;
    GPIOPinWrite(0x40007000, 0x00000010, 0x00);
    GPIOPinWrite(0x40007000, 0x00000010, 0xff);
    if ((GPIOPinRead(0x40007000, 0x00000020) & 0x00000020)) {
      temp |= 0x01;
    }
  }
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000020);
  GPIOPinWrite(0x40007000, 0x00000010, 0x00);
  GPIOPinWrite(0x40007000, 0x00000020, 0x00);
  GPIOPinWrite(0x40007000, 0x00000010, 0xff);
  GPIOPinWrite(0x40007000, 0x00000010, 0x00);
  GPIOPinWrite(0x40007000, 0x00000020, 0xff);
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ADSGetByteB>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOInput@plt>
  mov    $0x8,%ebp
  mov    $0x0,%ebx
L7:
  add    %ebx,%ebx
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinRead@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  or     $0x1,%eax
  test   $0x20,%dl
  cmovne %eax,%ebx
  sub    $0x1,%bpl
  jne    L7
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0x0,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char ADSGetByteB() {
  unsigned char i = 0;
  unsigned int temp = 0;
  GPIOPinTypeGPIOInput(0x40007000, 0x00000020);
  for (i = 0; i < 8; i++) {
    temp = temp << 1;
    GPIOPinWrite(0x40007000, 0x00000010, 0x00);
    GPIOPinWrite(0x40007000, 0x00000010, 0xff);
    if ((GPIOPinRead(0x40007000, 0x00000020) & 0x00000020)) {
      temp |= 0x01;
    }
  }
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000020);
  GPIOPinWrite(0x40007000, 0x00000010, 0x00);
  GPIOPinWrite(0x40007000, 0x00000020, 0x00);
  GPIOPinWrite(0x40007000, 0x00000010, 0xff);
  GPIOPinWrite(0x40007000, 0x00000010, 0x00);
  GPIOPinWrite(0x40007000, 0x00000020, 0xff);
  return temp;
}
```