ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<gameStart>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L9:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <gameInit@plt>
  mov    %rbx,%rdi
  call   <gameIn@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <gameIn2int@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <gameIn2count@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <judgeGame@plt>
  jmp    L9
```

assistant: ```c
void gameStart(char *inChar, int *toInt, int *count) {
  while (1) {
    gameInit(inChar, toInt, count);
    gameIn(inChar);
    gameIn2int(inChar, toInt);
    gameIn2count(inChar, count);
    judgeGame(inChar, toInt, count);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x8,-0x8(%rbp)
  movl   $0x9,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int x = 8, y = 9;
  assert(x == y);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int x = 8, y = 9;
  assert(x == y);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int x = 8, y = 9;
  assert(x == y);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int x = 8, y = 9;
  assert(x == y);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L14
  nop
L15:
  mov    $0xe000c014,%eax
  mov    (%rax),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L15
  mov    $0xe000c000,%eax
  movl   $0xd,(%rax)
L14:
  nop
L24:
  mov    $0xe000c014,%eax
  mov    (%rax),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L24
  mov    $0xe000c000,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int putchar(int ch) {
  if (ch == '\n') {
    while (!(*(volatile unsigned int *)0xE000C014 & 0x20))
      ;
    *(volatile unsigned int *)0xE000C000 = '\r';
  }
  while (!(*(volatile unsigned int *)0xE000C014 & 0x20))
    ;
  *(volatile unsigned int *)0xE000C000 = ch;
  return ch;
}
```
user: Translate the below assembly code into C programming language:

```asm
<putchar>:
  endbr64
  mov    %edi,%eax
  cmp    $0xa,%edi
  je     L35
L11:
  mov    $0xe000c014,%ecx
L23:
  mov    (%rcx),%edx
  test   $0x20,%dl
  je     L23
  movabs %eax,0xe000c000
  ret
L35:
  mov    $0xe000c014,%ecx
L31:
  mov    (%rcx),%edx
  test   $0x20,%dl
  je     L31
  mov    $0xe000c000,%esi
  movl   $0xd,(%rsi)
  jmp    L11
```

assistant: ```c
int putchar(int ch) {
  if (ch == '\n') {
    while (!(*(volatile unsigned int *)0xE000C014 & 0x20))
      ;
    *(volatile unsigned int *)0xE000C000 = '\r';
  }
  while (!(*(volatile unsigned int *)0xE000C014 & 0x20))
    ;
  *(volatile unsigned int *)0xE000C000 = ch;
  return ch;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<putchar>:
  endbr64
  mov    %edi,%eax
  cmp    $0xa,%edi
  je     L6
L29:
  mov    $0xe000c014,%ecx
L31:
  mov    (%rcx),%edx
  and    $0x20,%edx
  je     L31
  movabs %eax,0xe000c000
  ret
  nopl   0x0(%rax)
L6:
  mov    $0xe000c014,%ecx
  nopl   (%rax)
L13:
  mov    (%rcx),%edx
  and    $0x20,%edx
  je     L13
  mov    $0xe000c000,%esi
  movl   $0xd,(%rsi)
  jmp    L29
```

assistant: ```c
int putchar(int ch) {
  if (ch == '\n') {
    while (!(*(volatile unsigned int *)0xE000C014 & 0x20))
      ;
    *(volatile unsigned int *)0xE000C000 = '\r';
  }
  while (!(*(volatile unsigned int *)0xE000C014 & 0x20))
    ;
  *(volatile unsigned int *)0xE000C000 = ch;
  return ch;
}
```
user: Translate the below assembly code into C programming language:

```asm
<putchar>:
  endbr64
  mov    %edi,%eax
  cmp    $0xa,%edi
  je     L3
L9:
  mov    $0xe000c014,%ecx
L38:
  mov    (%rcx),%edx
  and    $0x20,%edx
  je     L38
  movabs %eax,0xe000c000
  ret
  nopl   0x0(%rax)
L3:
  mov    $0xe000c014,%ecx
  nopl   (%rax)
L17:
  mov    (%rcx),%edx
  and    $0x20,%edx
  je     L17
  mov    $0xe000c000,%esi
  movl   $0xd,(%rsi)
  jmp    L9
```

assistant: ```c
int putchar(int ch) {
  if (ch == '\n') {
    while (!(*(volatile unsigned int *)0xE000C014 & 0x20))
      ;
    *(volatile unsigned int *)0xE000C000 = '\r';
  }
  while (!(*(volatile unsigned int *)0xE000C014 & 0x20))
    ;
  *(volatile unsigned int *)0xE000C000 = ch;
  return ch;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<skip_until_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  mov    %edx,%eax
  mov    %al,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L17
L4:
  movslq %ebx,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x18(%rbp)
  je     L36
  add    $0x1,%ebx
L17:
  cmp    -0x14(%rbp),%ebx
  jl     L4
  jmp    L19
L36:
  nop
L19:
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int skip_until_char(const char *s, int len, char c) {
  register int i;
  for (i = 0; i < len; i++) {
    if (s[i] == c)
      break;
  }
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_until_char>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    $0x0,%eax
L3:
  cmp    %dl,(%rdi)
  je     L26
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%esi
  jne    L3
  mov    %esi,%eax
  ret
L6:
  mov    $0x0,%eax
L26:
  ret
```

assistant: ```c
int skip_until_char(const char *s, int len, char c) {
  register int i;
  for (i = 0; i < len; i++) {
    if (s[i] == c)
      break;
  }
  return (i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_until_char>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jg     L33
  jmp    L27
  nopl   0x0(%rax)
L30:
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%esi
  je     L20
L33:
  cmp    %dl,(%rdi)
  jne    L30
L27:
  ret
L20:
  ret
```

assistant: ```c
int skip_until_char(const char *s, int len, char c) {
  register int i;
  for (i = 0; i < len; i++) {
    if (s[i] == c)
      break;
  }
  return (i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_until_char>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jg     L14
  jmp    L6
  nopl   0x0(%rax)
L24:
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%esi
  je     L15
L14:
  cmp    %dl,(%rdi)
  jne    L24
L6:
  ret
L15:
  ret
```

assistant: ```c
int skip_until_char(const char *s, int len, char c) {
  register int i;
  for (i = 0; i < len; i++) {
    if (s[i] == c)
      break;
  }
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L2
L4:
  addq   $0x1,-0x20(%rbp)
  mov    -0x28(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x28(%rbp)
L2:
  cmpq   $0x0,-0x28(%rbp)
  jne    L4
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L11
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L14
L11:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string

tool: D19: %lld

tool: D25: Given number is automorphic


tool: D16: Given number is not automorphic


assistant: ```c
int main() {
  long long int n, p, count = 0, q;
  unsigned long long int k;
  scanf("%lld", &n);
  p = n;
  while (p) {
    count++;
    p = p / 10;
  }
  q = pow(10, count);
  k = n * n;
  k = k % q;
  if (k == n)
    printf("Given number is automorphic\n");
  else
    printf("Given number is not automorphic\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  test   %rcx,%rcx
  je     L3
  mov    $0x0,%esi
  movabs $0x6666666666666667,%rdi
L54:
  add    $0x1,%rsi
  mov    %rcx,%rax
  imul   %rdi
  sar    $0x2,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  mov    %rdx,%rcx
  jne    L54
L15:
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%rsi
  mov    (%rsp),%rcx
  mov    %rcx,%rax
  imul   %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  cmp    %rdx,%rcx
  je     L10
  lea    D14(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  mov    %rcx,%rsi
  jmp    L15
L10:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string
name: unpack_data
arguments: label: D15
type_infered: string

tool: D10: %lld

tool: D14: Given number is not automorphic


tool: D15: Given number is automorphic


assistant: ```c
int main() {
  long long int n, p, count = 0, q;
  unsigned long long int k;
  scanf("%lld", &n);
  p = n;
  while (p) {
    count++;
    p = p / 10;
  }
  q = pow(10, count);
  k = n * n;
  k = k % q;
  if (k == n)
    printf("Given number is automorphic\n");
  else
    printf("Given number is not automorphic\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  xor    %esi,%esi
  test   %rcx,%rcx
  je     L40
  movabs $0x6666666666666667,%rdi
  nopl   0x0(%rax)
L32:
  mov    %rcx,%rax
  add    $0x1,%rsi
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  jne    L32
L40:
  mov    $0xa,%edi
  call   <pow@plt>
  mov    (%rsp),%rcx
  xor    %edx,%edx
  mov    %rax,%r8
  mov    %rcx,%rax
  imul   %rcx,%rax
  div    %r8
  cmp    %rdx,%rcx
  je     L47
  lea    D27(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L47:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string
name: disassemble_data
arguments: data_tag: D27
type_infered: string
name: disassemble_data
arguments: data_tag: D12
type_infered: string

tool: D6: %lld

tool: D27: Given number is not automorphic


tool: D12: Given number is automorphic


assistant: ```c
int main() {
  long long int n, p, count = 0, q;
  unsigned long long int k;
  scanf("%lld", &n);
  p = n;
  while (p) {
    count++;
    p = p / 10;
  }
  q = pow(10, count);
  k = n * n;
  k = k % q;
  if (k == n)
    printf("Given number is automorphic\n");
  else
    printf("Given number is not automorphic\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  xor    %esi,%esi
  test   %rcx,%rcx
  je     L25
  movabs $0x6666666666666667,%rdi
  nopl   0x0(%rax)
L28:
  mov    %rcx,%rax
  add    $0x1,%rsi
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  jne    L28
L25:
  mov    $0xa,%edi
  call   <pow@plt>
  mov    (%rsp),%rcx
  xor    %edx,%edx
  mov    %rax,%r8
  mov    %rcx,%rax
  imul   %rcx,%rax
  div    %r8
  cmp    %rdx,%rcx
  je     L7
  lea    D16(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D16
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D14: %lld

tool: D16: Given number is not automorphic


tool: D0: Given number is automorphic


assistant: ```c
int main() {
  long long int n, p, count = 0, q;
  unsigned long long int k;
  scanf("%lld", &n);
  p = n;
  while (p) {
    count++;
    p = p / 10;
  }
  q = pow(10, count);
  k = n * n;
  k = k % q;
  if (k == n)
    printf("Given number is automorphic\n");
  else
    printf("Given number is not automorphic\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<space_to_hyphen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D9(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  cmp    $0x20,%al
  jne    L25
  mov    -0x4(%rbp),%eax
  cltq
  lea    D9(%rip),%rdx
  movb   $0x2d,(%rax,%rdx,1)
L25:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D9(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  test   %al,%al
  jne    L24
  lea    D9(%rip),%rax
  leave
  ret
```

assistant: ```c
char *space_to_hyphen(const char *s) {
  static char result[100];
  int i;
  strcpy(result, s);
  for (i = 0; result[i] != '\0'; i++) {
    if (result[i] == ' ') {
      result[i] = '-';
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<space_to_hyphen>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <strcpy@plt>
  movzbl D6(%rip),%edx
  test   %dl,%dl
  je     L26
  lea    D6(%rip),%rax
  jmp    L1
L48:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L26
L1:
  cmp    $0x20,%dl
  jne    L48
  movb   $0x2d,(%rax)
  jmp    L48
L26:
  lea    D6(%rip),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *space_to_hyphen(const char *s) {
  static char result[100];
  int i;
  strcpy(result, s);
  for (i = 0; result[i] != '\0'; i++) {
    if (result[i] == ' ') {
      result[i] = '-';
    }
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<space_to_hyphen>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  movzbl D4(%rip),%edx
  test   %dl,%dl
  je     L21
  mov    %r12,%rax
  cs nopw 0x0(%rax,%rax,1)
L18:
  cmp    $0x20,%dl
  jne    L1
  movb   $0x2d,(%rax)
L1:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L18
L21:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *space_to_hyphen(const char *s) {
  static char result[100];
  int i;
  strcpy(result, s);
  for (i = 0; result[i] != '\0'; i++) {
    if (result[i] == ' ') {
      result[i] = '-';
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<space_to_hyphen>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  movzbl D19(%rip),%edx
  test   %dl,%dl
  je     L37
  mov    %r12,%rax
  cs nopw 0x0(%rax,%rax,1)
L7:
  cmp    $0x20,%dl
  je     L14
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L7
L37:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  movb   $0x2d,(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L7
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *space_to_hyphen(const char *s) {
  static char result[100];
  int i;
  strcpy(result, s);
  for (i = 0; result[i] != '\0'; i++) {
    if (result[i] == ' ') {
      result[i] = '-';
    }
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fbdCRC32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movq   $0xffffffffffffffff,-0x10(%rbp)
  jmp    L1
L34:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L10
L25:
  mov    -0x10(%rbp),%rax
  and    $0x1,%eax
  neg    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  shr    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  and    $0xedb88320,%eax
  xor    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L10:
  cmpl   $0x7,-0x14(%rbp)
  jle    L25
L1:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L34
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long int fbdCRC32(const unsigned char *data, int size) {
  unsigned long int crc = ~0;
  while (size--) {
    crc ^= *data++;
    for (int i = 0; i < 8; i++) {
      unsigned long int t = ~((crc & 1) - 1);
      crc = (crc >> 1) ^ (0xEDB88320 & t);
    }
  }
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fbdCRC32>:
  endbr64
  test   %esi,%esi
  je     L22
  mov    %esi,%esi
  add    %rdi,%rsi
  mov    $0xffffffffffffffff,%rax
  jmp    L39
L41:
  cmp    %rsi,%rdi
  je     L21
L39:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  xor    %rdx,%rax
  mov    $0x8,%edx
L0:
  mov    %rax,%rcx
  shr    %rcx
  and    $0x1,%eax
  neg    %rax
  and    $0xedb88320,%eax
  xor    %rcx,%rax
  sub    $0x1,%edx
  jne    L0
  jmp    L41
L21:
  ret
L22:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
unsigned long int fbdCRC32(const unsigned char *data, int size) {
  unsigned long int crc = ~0;
  while (size--) {
    crc ^= *data++;
    for (int i = 0; i < 8; i++) {
      unsigned long int t = ~((crc & 1) - 1);
      crc = (crc >> 1) ^ (0xEDB88320 & t);
    }
  }
  return crc;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fbdCRC32>:
  endbr64
  test   %esi,%esi
  je     L3
  mov    %esi,%esi
  mov    $0xffffffffffffffff,%rax
  add    %rdi,%rsi
  nopl   0x0(%rax)
L12:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %rdx,%rax
  mov    $0x8,%edx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rax,%rcx
  and    $0x1,%eax
  neg    %rax
  shr    %rcx
  and    $0xedb88320,%eax
  xor    %rcx,%rax
  sub    $0x1,%edx
  jne    L0
  cmp    %rsi,%rdi
  jne    L12
  ret
L3:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
unsigned long int fbdCRC32(const unsigned char *data, int size) {
  unsigned long int crc = ~0;
  while (size--) {
    crc ^= *data++;
    for (int i = 0; i < 8; i++) {
      unsigned long int t = ~((crc & 1) - 1);
      crc = (crc >> 1) ^ (0xEDB88320 & t);
    }
  }
  return crc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fbdCRC32>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  je     L17
  mov    %esi,%esi
  mov    $0xffffffffffffffff,%r8
  add    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  xor    %r8,%rax
  mov    %rax,%rdx
  and    $0x1,%eax
  neg    %rax
  shr    %rdx
  and    $0xedb88320,%eax
  xor    %rax,%rdx
  mov    %rdx,%rax
  and    $0x1,%edx
  neg    %rdx
  shr    %rax
  and    $0xedb88320,%edx
  xor    %rdx,%rax
  mov    %rax,%rdx
  and    $0x1,%eax
  neg    %rax
  shr    %rdx
  and    $0xedb88320,%eax
  xor    %rax,%rdx
  mov    %rdx,%rax
  and    $0x1,%edx
  neg    %rdx
  shr    %rax
  and    $0xedb88320,%edx
  xor    %rdx,%rax
  mov    %rax,%rdx
  and    $0x1,%eax
  neg    %rax
  shr    %rdx
  and    $0xedb88320,%eax
  xor    %rax,%rdx
  mov    %rdx,%rax
  and    $0x1,%edx
  neg    %rdx
  shr    %rax
  and    $0xedb88320,%edx
  xor    %rdx,%rax
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  neg    %rax
  and    $0xedb88320,%eax
  xor    %rax,%rdx
  mov    %rdx,%r8
  and    $0x1,%edx
  neg    %rdx
  shr    %r8
  and    $0xedb88320,%edx
  xor    %rdx,%r8
  cmp    %rsi,%rcx
  jne    L1
  mov    %r8,%rax
  ret
L17:
  mov    $0xffffffffffffffff,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long int fbdCRC32(const unsigned char *data, int size) {
  unsigned long int crc = ~0;
  while (size--) {
    crc ^= *data++;
    for (int i = 0; i < 8; i++) {
      unsigned long int t = ~((crc & 1) - 1);
      crc = (crc >> 1) ^ (0xEDB88320 & t);
    }
  }
  return crc;
}
```