ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x0,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xb(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xb(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
  mov    -0x18(%rbp),%eax
  cmp    $0xc,%eax
  je     L44
  mov    -0x18(%rbp),%eax
  add    $0xc,%eax
  jmp    L49
L44:
  mov    -0x18(%rbp),%eax
L49:
  mov    %eax,-0x18(%rbp)
  lea    -0xb(%rbp),%rax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L15
  mov    -0x18(%rbp),%eax
  cmp    $0xc,%eax
  jne    L15
  movl   $0x0,-0x18(%rbp)
L15:
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D31
datatype: string
name: extract_symbolic_data
arguments: data_tag: D36
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D6: %d:%d:%d %[^
]%*c

tool: D31: PM

tool: D36: AM

tool: D10: %02d:%02d:%02d

assistant: ```c
int main() {
  int hh, mm, ss;
  char tt[3] = "";
  scanf("%d:%d:%d %[^\n]%*c", &hh, &mm, &ss, tt);
  hh = (strcmp(tt, "PM") == 0 && hh != 12) ? hh + 12 : hh;
  if (strcmp(tt, "AM") == 0 && hh == 12)
    hh = 0;
  printf("%02d:%02d:%02d", hh, mm, ss);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movw   $0x0,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0x15(%rsp),%rbx
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbx,%r8
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L54
  mov    0x8(%rsp),%eax
  cmp    $0xc,%eax
  je     L54
  add    $0xc,%eax
  jmp    L30
L54:
  mov    0x8(%rsp),%eax
L30:
  mov    %eax,0x8(%rsp)
  lea    0x15(%rsp),%rdi
  lea    D31(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  cmpl   $0xc,0x8(%rsp)
  je     L42
L25:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L42:
  movl   $0x0,0x8(%rsp)
  jmp    L25
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D21
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D31
type_guessed: string
name: retrieve_data
arguments: tag: D26
type_guessed: string

tool: D21: %d:%d:%d %[^
]%*c

tool: D12: PM

tool: D31: AM

tool: D26: %02d:%02d:%02d

assistant: ```c
int main() {
  int hh, mm, ss;
  char tt[3] = "";
  scanf("%d:%d:%d %[^\n]%*c", &hh, &mm, &ss, tt);
  hh = (strcmp(tt, "PM") == 0 && hh != 12) ? hh + 12 : hh;
  if (strcmp(tt, "AM") == 0 && hh == 12)
    hh = 0;
  printf("%02d:%02d:%02d", hh, mm, ss);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x15(%rsp),%rbp
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%r8
  mov    %ax,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <scanf@plt>
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  mov    0x8(%rsp),%eax
  jne    L30
  cmp    $0xc,%eax
  je     L30
  add    $0xc,%eax
L30:
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,0x8(%rsp)
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  cmpl   $0xc,0x8(%rsp)
  je     L6
L25:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D3(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  movl   $0x0,0x8(%rsp)
  jmp    L25
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D32
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: string

tool: D27: %d:%d:%d %[^
]%*c

tool: D32: PM

tool: D11: AM

tool: D3: %02d:%02d:%02d

assistant: ```c
int main() {
  int hh, mm, ss;
  char tt[3] = "";
  scanf("%d:%d:%d %[^\n]%*c", &hh, &mm, &ss, tt);
  hh = (strcmp(tt, "PM") == 0 && hh != 12) ? hh + 12 : hh;
  if (strcmp(tt, "AM") == 0 && hh == 12)
    hh = 0;
  printf("%02d:%02d:%02d", hh, mm, ss);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x15(%rsp),%rbp
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%r8
  mov    %ax,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <scanf@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  mov    0x8(%rsp),%eax
  jne    L6
  cmp    $0xc,%eax
  je     L6
  add    $0xc,%eax
L6:
  lea    D31(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,0x8(%rsp)
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  cmpl   $0xc,0x8(%rsp)
  je     L54
L25:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D37(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L54:
  movl   $0x0,0x8(%rsp)
  jmp    L25
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
datatype: string
name: extract_symbolic_data
arguments: tag: D26
datatype: string
name: extract_symbolic_data
arguments: tag: D31
datatype: string
name: extract_symbolic_data
arguments: tag: D37
datatype: string

tool: D34: %d:%d:%d %[^
]%*c

tool: D26: PM

tool: D31: AM

tool: D37: %02d:%02d:%02d

assistant: ```c
int main() {
  int hh, mm, ss;
  char tt[3] = "";
  scanf("%d:%d:%d %[^\n]%*c", &hh, &mm, &ss, tt);
  hh = (strcmp(tt, "PM") == 0 && hh != 12) ? hh + 12 : hh;
  if (strcmp(tt, "AM") == 0 && hh == 12)
    hh = 0;
  printf("%02d:%02d:%02d", hh, mm, ss);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_swap16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x2,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_swap16(unsigned int numel, void *data) {
  unsigned int n;
  char *d = (char *)data;
  for (n = 0; n < numel; n++) {
    char t = d[0];
    d[0] = d[1];
    d[1] = t;
    d += 2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_swap16>:
  endbr64
  test   %edi,%edi
  je     L13
  mov    %edi,%edi
  lea    (%rsi,%rdi,2),%rcx
L2:
  movzbl (%rsi),%eax
  movzbl 0x1(%rsi),%edx
  mov    %dl,(%rsi)
  mov    %al,0x1(%rsi)
  add    $0x2,%rsi
  cmp    %rcx,%rsi
  jne    L2
L13:
  ret
```

assistant: ```c
void ft_swap16(unsigned int numel, void *data) {
  unsigned int n;
  char *d = (char *)data;
  for (n = 0; n < numel; n++) {
    char t = d[0];
    d[0] = d[1];
    d[1] = t;
    d += 2;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_swap16>:
  endbr64
  test   %edi,%edi
  je     L8
  mov    %edi,%edi
  lea    (%rsi,%rdi,2),%rcx
  xchg   %ax,%ax
L12:
  movzbl (%rsi),%eax
  movzbl 0x1(%rsi),%edx
  add    $0x2,%rsi
  mov    %dl,-0x2(%rsi)
  mov    %al,-0x1(%rsi)
  cmp    %rcx,%rsi
  jne    L12
L8:
  ret
```

assistant: ```c
void ft_swap16(unsigned int numel, void *data) {
  unsigned int n;
  char *d = (char *)data;
  for (n = 0; n < numel; n++) {
    char t = d[0];
    d[0] = d[1];
    d[1] = t;
    d += 2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_swap16>:
  endbr64
  mov    %rsi,%rdx
  test   %edi,%edi
  je     L79
  lea    -0x1(%rdi),%eax
  cmp    $0xe,%eax
  jbe    L138
  mov    %edi,%ecx
  movdqa D7(%rip),%xmm3
  mov    %rsi,%rax
  shr    $0x4,%ecx
  sub    $0x1,%ecx
  shl    $0x5,%rcx
  lea    0x20(%rsi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L175:
  movdqu (%rax),%xmm1
  movdqu 0x10(%rax),%xmm0
  add    $0x20,%rax
  movdqu -0x10(%rax),%xmm2
  pand   %xmm3,%xmm0
  pand   %xmm3,%xmm1
  packuswb %xmm0,%xmm1
  movdqu -0x20(%rax),%xmm0
  psrlw  $0x8,%xmm2
  psrlw  $0x8,%xmm0
  packuswb %xmm2,%xmm0
  movdqa %xmm0,%xmm2
  punpckhbw %xmm1,%xmm0
  punpcklbw %xmm1,%xmm2
  movups %xmm0,-0x10(%rax)
  movups %xmm2,-0x20(%rax)
  cmp    %rcx,%rax
  jne    L175
  mov    %edi,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%ecx
  lea    (%rdx,%rcx,2),%rdx
  cmp    %eax,%edi
  je     L169
L185:
  lea    0x1(%rax),%ecx
  rolw   $0x8,(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0x2(%rax),%ecx
  rolw   $0x8,0x2(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0x3(%rax),%ecx
  rolw   $0x8,0x4(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0x4(%rax),%ecx
  rolw   $0x8,0x6(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0x5(%rax),%ecx
  rolw   $0x8,0x8(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0x6(%rax),%ecx
  rolw   $0x8,0xa(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0x7(%rax),%ecx
  rolw   $0x8,0xc(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0x8(%rax),%ecx
  rolw   $0x8,0xe(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0x9(%rax),%ecx
  rolw   $0x8,0x10(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0xa(%rax),%ecx
  rolw   $0x8,0x12(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0xb(%rax),%ecx
  rolw   $0x8,0x14(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0xc(%rax),%ecx
  rolw   $0x8,0x16(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  lea    0xd(%rax),%ecx
  rolw   $0x8,0x18(%rdx)
  cmp    %ecx,%edi
  jbe    L79
  add    $0xe,%eax
  rolw   $0x8,0x1a(%rdx)
  cmp    %eax,%edi
  jbe    L79
  rolw   $0x8,0x1c(%rdx)
L79:
  ret
L138:
  xor    %eax,%eax
  jmp    L185
L169:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: byte[16]

tool: {"D7": [0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00]}

assistant: ```c
void ft_swap16(unsigned int numel, void *data) {
  unsigned int n;
  char *d = (char *)data;
  for (n = 0; n < numel; n++) {
    char t = d[0];
    d[0] = d[1];
    d[1] = t;
    d += 2;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<countMinNumFlipByInversion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L39:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L42:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L26
  addl   $0x1,-0xc(%rbp)
L26:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L42
  addl   $0x1,-0x8(%rbp)
L41:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L39
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int countMinNumFlipByInversion(int arr[], int len) {
  int minNumFlip = 0, i, j;
  for (i = 0; i < len - 1; i++)
    for (j = i + 1; j < len; j++)
      if (arr[i] > arr[j])
        minNumFlip++;
  return minNumFlip;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<countMinNumFlipByInversion>:
  endbr64
  cmp    $0x1,%esi
  jle    L64
  lea    -0x2(%rsi),%r9d
  add    $0x2,%r9
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  jmp    L8
L36:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L37
L38:
  cmp    (%rdi,%rax,4),%edx
  jle    L36
  add    $0x1,%ecx
  jmp    L36
L37:
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L34
L8:
  cmp    %r8d,%esi
  jle    L37
  mov    -0x4(%rdi,%r8,4),%edx
  mov    %r8,%rax
  jmp    L38
L64:
  mov    $0x0,%ecx
L34:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int countMinNumFlipByInversion(int arr[], int len) {
  int minNumFlip = 0, i, j;
  for (i = 0; i < len - 1; i++)
    for (j = i + 1; j < len; j++)
      if (arr[i] > arr[j])
        minNumFlip++;
  return minNumFlip;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<countMinNumFlipByInversion>:
  endbr64
  cmp    $0x1,%esi
  jle    L8
  lea    -0x2(%rsi),%r9d
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  add    $0x2,%r9
  nopl   0x0(%rax)
L10:
  cmp    %ecx,%esi
  jle    L32
  mov    -0x4(%rdi,%rcx,4),%edx
  mov    %rcx,%rax
  nopl   0x0(%rax,%rax,1)
L30:
  cmp    (%rdi,%rax,4),%edx
  jle    L40
  add    $0x1,%r8d
L40:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L30
L32:
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L10
  mov    %r8d,%eax
  ret
L8:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int countMinNumFlipByInversion(int arr[], int len) {
  int minNumFlip = 0, i, j;
  for (i = 0; i < len - 1; i++)
    for (j = i + 1; j < len; j++)
      if (arr[i] > arr[j])
        minNumFlip++;
  return minNumFlip;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<countMinNumFlipByInversion>:
  endbr64
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L43
  mov    %rdi,%rbx
  mov    %esi,%r11d
  mov    %ebp,%edi
  xor    %ecx,%ecx
  lea    0x4(%rbx),%rsi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L100:
  add    $0x1,%ecx
  lea    -0x1(%rdi),%r10d
  cmp    %ecx,%r11d
  jle    L70
  lea    -0x1(%rdi),%r10d
  mov    -0x4(%rsi),%r9d
  cmp    $0x2,%r10d
  jbe    L21
  mov    %edi,%eax
  movd   %r9d,%xmm4
  pxor   %xmm0,%xmm0
  shr    $0x2,%eax
  pshufd $0x0,%xmm4,%xmm2
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%rsi,%rax,1),%rdx
  mov    %rsi,%rax
  nopl   0x0(%rax)
L58:
  movdqu (%rax),%xmm3
  movdqa %xmm2,%xmm1
  add    $0x10,%rax
  pcmpgtd %xmm3,%xmm1
  psubd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L58
  movdqa %xmm0,%xmm1
  mov    %edi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %eax,%r8d
  lea    (%rdx,%rcx,1),%eax
  cmp    %edx,%edi
  je     L70
L86:
  movslq %eax,%rdx
  cmp    (%rbx,%rdx,4),%r9d
  lea    0x0(,%rdx,4),%rdi
  setg   %dl
  movzbl %dl,%edx
  add    %edx,%r8d
  lea    0x1(%rax),%edx
  cmp    %r11d,%edx
  jge    L70
  cmp    0x4(%rbx,%rdi,1),%r9d
  jle    L61
  add    $0x1,%r8d
L61:
  add    $0x2,%eax
  cmp    %eax,%r11d
  jle    L70
  cmp    0x8(%rbx,%rdi,1),%r9d
  jle    L70
  add    $0x1,%r8d
L70:
  mov    %r10d,%edi
  add    $0x4,%rsi
  cmp    %ebp,%ecx
  jne    L100
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    %ecx,%eax
  jmp    L86
L43:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int countMinNumFlipByInversion(int arr[], int len) {
  int minNumFlip = 0, i, j;
  for (i = 0; i < len - 1; i++)
    for (j = i + 1; j < len; j++)
      if (arr[i] > arr[j])
        minNumFlip++;
  return minNumFlip;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

assistant: ```c
void print_string(int str_len, FILE *fw, char str[]) {
  int i;
  for (i = 0; i < str_len; ++i)
    fprintf(fw, "%c", str[i]);
  fprintf(fw, "\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  test   %edi,%edi
  jle    L4
  mov    %rdx,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x1(%rdx,%rax,1),%r12
L9:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L9
L4:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void print_string(int str_len, FILE *fw, char str[]) {
  int i;
  for (i = 0; i < str_len; ++i)
    fprintf(fw, "%c", str[i]);
  fprintf(fw, "\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %edi,%edi
  jle    L3
  lea    -0x1(%rdi),%eax
  mov    %rdx,%rbx
  lea    0x1(%rdx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r12,%rbx
  jne    L18
L3:
  pop    %rbx
  mov    %rbp,%rsi
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <fputc@plt>
```

assistant: ```c
void print_string(int str_len, FILE *fw, char str[]) {
  int i;
  for (i = 0; i < str_len; ++i)
    fprintf(fw, "%c", str[i]);
  fprintf(fw, "\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %edi,%edi
  jle    L18
  lea    -0x1(%rdi),%eax
  mov    %rdx,%rbx
  lea    0x1(%rdx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L19:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r12,%rbx
  jne    L19
L18:
  pop    %rbx
  mov    %rbp,%rsi
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <fputc@plt>
```

assistant: ```c
void print_string(int str_len, FILE *fw, char str[]) {
  int i;
  for (i = 0; i < str_len; ++i)
    fprintf(fw, "%c", str[i]);
  fprintf(fw, "\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L62:
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L73
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L20
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jne    L20
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
L20:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L3
L73:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L3:
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x20(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L62
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D16
type: string

tool: D19:  %.2f 

tool: D16: %.2f 

assistant: ```c
void printMatrix(float **T, int m, int n) {
  int i, j;
  for (i = 0; i < m + 1; i++) {
    for (j = 0; j < n + 1; j++) {
      if (T[i][j] >= 0) {
        if (T[i][j] == -0.0)
          T[i][j] = 0;
        printf(" %.2f ", T[i][j]);
      } else
        printf("%.2f ", T[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  js     L3
  mov    %edx,%r12d
  mov    %rdi,%rbp
  mov    $0x0,%r14d
  lea    D15(%rip),%r15
  jmp    L109
L41:
  mov    (%rcx),%rdx
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdx,%rax,1),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L25:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L64
L80:
  mov    %rbp,%rcx
  lea    0x0(,%rbx,4),%rax
  mov    %rax,%rdx
  add    0x0(%rbp),%rdx
  movss  (%rdx),%xmm0
  comiss D28(%rip),%xmm0
  jb     L28
  ucomiss D28(%rip),%xmm0
  jp     L41
  jne    L41
  movl   $0x0,(%rdx)
  jmp    L41
L28:
  cvtss2sd %xmm0,%xmm0
  mov    %r15,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L25
L64:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r14d
  add    $0x8,%rbp
  cmp    %r14d,0xc(%rsp)
  jl     L3
L109:
  mov    $0x0,%ebx
  lea    D20(%rip),%r13
  test   %r12d,%r12d
  jns    L80
  jmp    L64
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D28
type_guessed: f32
name: parse_data
arguments: data_tag: D20
type_guessed: string

tool: D15: %.2f 

tool: D28: 0

tool: D20:  %.2f 

assistant: ```c
void printMatrix(float **T, int m, int n) {
  int i, j;
  for (i = 0; i < m + 1; i++) {
    for (j = 0; j < n + 1; j++) {
      if (T[i][j] >= 0) {
        if (T[i][j] == -0.0)
          T[i][j] = 0;
        printf(" %.2f ", T[i][j]);
      } else
        printf("%.2f ", T[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```