ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<_asn1_check_infinite_end>:
  endbr64
  mov    $0x1,%eax
  test   %rsi,%rsi
  jle    L33
  xor    %eax,%eax
  cmp    $0x1,%rsi
  je     L33
  mov    (%rdi),%rdx
  cmpb   $0x0,(%rdx)
  jne    L33
  cmpb   $0x0,0x1(%rdx)
  je     L35
L33:
  ret
  nopl   (%rax)
L35:
  add    $0x2,%rdx
  mov    $0x1,%eax
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
int _asn1_check_infinite_end(const unsigned char **p, long len) {
  if (len <= 0)
    return (1);
  else if ((len >= 2) && ((*p)[0] == 0) && ((*p)[1] == 0)) {
    (*p) += 2;
    return (1);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Simon_Decrypt_64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  movl   $0x20,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  jmp    L17
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    (%rax,%rax,1),%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  mov    %eax,%edi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %edi,%eax
  and    %eax,%esi
  mov    %esi,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  xor    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x0(,%rax,4),%edi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %edi,%eax
  xor    %esi,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  subq   $0x1,-0x20(%rbp)
L17:
  cmpq   $0x0,-0x20(%rbp)
  jns    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Simon_Decrypt_64(const uint8_t round_limit, const uint8_t *key_schedule, const uint8_t *ciphertext, uint8_t *plaintext) {
  const uint8_t word_size = 32;
  uint32_t *x_word = (uint32_t *)plaintext;
  uint32_t *y_word = ((uint32_t *)plaintext) + 1;
  uint32_t *round_key_ptr = (uint32_t *)key_schedule;
  *x_word = *(uint32_t *)ciphertext;
  *y_word = *(((uint32_t *)ciphertext) + 1);
  for (int8_t i = round_limit - 1; i >= 0; i--) {
    uint32_t temp = ((((*x_word) << 1) | ((*x_word) >> (word_size - 1))) & (((*x_word) << 8) | ((*x_word) >> (word_size - 8)))) ^ *y_word ^ (((*x_word) << 2) | ((*x_word) >> (word_size - 2)));
    *y_word = *x_word;
    *x_word = temp ^ *(round_key_ptr + i);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Simon_Decrypt_64>:
  endbr64
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    (%rdx),%eax
  mov    %eax,(%rcx)
  mov    0x4(%rdx),%eax
  mov    %eax,0x4(%rcx)
  lea    -0x1(%rdi),%esi
  movslq %esi,%rsi
  test   %rsi,%rsi
  js     L8
L9:
  mov    (%r8),%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  or     %ecx,%eax
  mov    %edx,%ecx
  shl    $0x8,%ecx
  mov    %edx,%edi
  sar    $0x18,%edi
  or     %edi,%ecx
  and    %ecx,%eax
  lea    0x0(,%rdx,4),%ecx
  mov    %edx,%edi
  sar    $0x1e,%edi
  or     %edi,%ecx
  xor    0x4(%r8),%ecx
  xor    %ecx,%eax
  mov    %edx,0x4(%r8)
  xor    (%r9,%rsi,4),%eax
  mov    %eax,(%r8)
  sub    $0x1,%rsi
  cmp    $0xffffffffffffffff,%rsi
  jne    L9
L8:
  ret
```

assistant: ```c
void Simon_Decrypt_64(const uint8_t round_limit, const uint8_t *key_schedule, const uint8_t *ciphertext, uint8_t *plaintext) {
  const uint8_t word_size = 32;
  uint32_t *x_word = (uint32_t *)plaintext;
  uint32_t *y_word = ((uint32_t *)plaintext) + 1;
  uint32_t *round_key_ptr = (uint32_t *)key_schedule;
  *x_word = *(uint32_t *)ciphertext;
  *y_word = *(((uint32_t *)ciphertext) + 1);
  for (int8_t i = round_limit - 1; i >= 0; i--) {
    uint32_t temp = ((((*x_word) << 1) | ((*x_word) >> (word_size - 1))) & (((*x_word) << 8) | ((*x_word) >> (word_size - 8)))) ^ *y_word ^ (((*x_word) << 2) | ((*x_word) >> (word_size - 2)));
    *y_word = *x_word;
    *x_word = temp ^ *(round_key_ptr + i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Simon_Decrypt_64>:
  endbr64
  mov    %rcx,%r9
  mov    (%rdx),%ecx
  sub    $0x1,%edi
  mov    %rsi,%r8
  movslq %edi,%rsi
  mov    %ecx,(%r9)
  mov    0x4(%rdx),%r10d
  mov    %r10d,0x4(%r9)
  jns    L29
  jmp    L26
  nopl   0x0(%rax)
L20:
  mov    %eax,%ecx
L29:
  mov    %ecx,%edx
  lea    (%rcx,%rcx,1),%eax
  mov    %ecx,%edi
  mov    %ecx,0x4(%r9)
  sar    $0x1f,%edx
  sar    $0x18,%edi
  or     %edx,%eax
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  mov    %ecx,%edi
  and    %edx,%eax
  sar    $0x1e,%edi
  lea    0x0(,%rcx,4),%edx
  or     %edi,%edx
  xor    (%r8,%rsi,4),%edx
  sub    $0x1,%rsi
  xor    %edx,%eax
  xor    %r10d,%eax
  mov    %ecx,%r10d
  mov    %eax,(%r9)
  cmp    $0xffffffffffffffff,%rsi
  jne    L20
  ret
  xchg   %ax,%ax
L26:
  ret
```

assistant: ```c
void Simon_Decrypt_64(const uint8_t round_limit, const uint8_t *key_schedule, const uint8_t *ciphertext, uint8_t *plaintext) {
  const uint8_t word_size = 32;
  uint32_t *x_word = (uint32_t *)plaintext;
  uint32_t *y_word = ((uint32_t *)plaintext) + 1;
  uint32_t *round_key_ptr = (uint32_t *)key_schedule;
  *x_word = *(uint32_t *)ciphertext;
  *y_word = *(((uint32_t *)ciphertext) + 1);
  for (int8_t i = round_limit - 1; i >= 0; i--) {
    uint32_t temp = ((((*x_word) << 1) | ((*x_word) >> (word_size - 1))) & (((*x_word) << 8) | ((*x_word) >> (word_size - 8)))) ^ *y_word ^ (((*x_word) << 2) | ((*x_word) >> (word_size - 2)));
    *y_word = *x_word;
    *x_word = temp ^ *(round_key_ptr + i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Simon_Decrypt_64>:
  endbr64
  mov    %rcx,%r9
  mov    (%rdx),%ecx
  sub    $0x1,%edi
  mov    %rsi,%r8
  movslq %edi,%rsi
  mov    %ecx,(%r9)
  mov    0x4(%rdx),%r10d
  mov    %r10d,0x4(%r9)
  jns    L13
  jmp    L23
  nopl   0x0(%rax)
L1:
  mov    %eax,%ecx
L13:
  mov    %ecx,%edx
  lea    (%rcx,%rcx,1),%eax
  mov    %ecx,%edi
  mov    %ecx,0x4(%r9)
  sar    $0x1f,%edx
  sar    $0x18,%edi
  or     %edx,%eax
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  mov    %ecx,%edi
  and    %edx,%eax
  sar    $0x1e,%edi
  lea    0x0(,%rcx,4),%edx
  or     %edi,%edx
  xor    (%r8,%rsi,4),%edx
  sub    $0x1,%rsi
  xor    %edx,%eax
  xor    %r10d,%eax
  mov    %ecx,%r10d
  mov    %eax,(%r9)
  cmp    $0xffffffffffffffff,%rsi
  jne    L1
  ret
  xchg   %ax,%ax
L23:
  ret
```

assistant: ```c
void Simon_Decrypt_64(const uint8_t round_limit, const uint8_t *key_schedule, const uint8_t *ciphertext, uint8_t *plaintext) {
  const uint8_t word_size = 32;
  uint32_t *x_word = (uint32_t *)plaintext;
  uint32_t *y_word = ((uint32_t *)plaintext) + 1;
  uint32_t *round_key_ptr = (uint32_t *)key_schedule;
  *x_word = *(uint32_t *)ciphertext;
  *y_word = *(((uint32_t *)ciphertext) + 1);
  for (int8_t i = round_limit - 1; i >= 0; i--) {
    uint32_t temp = ((((*x_word) << 1) | ((*x_word) >> (word_size - 1))) & (((*x_word) << 8) | ((*x_word) >> (word_size - 8)))) ^ *y_word ^ (((*x_word) << 2) | ((*x_word) >> (word_size - 2)));
    *y_word = *x_word;
    *x_word = temp ^ *(round_key_ptr + i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ascii2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x8(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L42
  shlb   -0x9(%rbp)
  cmpl   $0x30,-0x4(%rbp)
  jle    L41
  orb    $0x1,-0x9(%rbp)
L41:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L29
  movzbl -0x9(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  movb   $0x0,-0x9(%rbp)
  jmp    L29
L42:
  nop
  mov    -0x8(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  je     L35
  movzbl -0x9(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  nop
L35:
  nop
  leave
  ret
```

assistant: ```c
void ascii2bin(FILE *input, FILE *output) {
  unsigned char holder = 0;
  int num = 0;
  while (1) {
    int x = fgetc(input);
    if (x == EOF)
      break;
    holder <<= 1;
    if (x >= '1') {
      holder = holder | 0x01;
    }
    num++;
    if (num % 8 == 0) {
      fputc(holder, output);
      holder = 0;
    }
  }
  if (num % 8 != 0)
    fputc(holder, output);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ascii2bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L16:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L23
  add    %ebx,%ebx
  mov    %ebx,%edx
  or     $0x1,%edx
  cmp    $0x30,%eax
  cmovg  %edx,%ebx
  add    $0x1,%ebp
  test   $0x7,%bpl
  jne    L16
  movzbl %bl,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  mov    $0x0,%ebx
  jmp    L16
L23:
  test   $0x7,%bpl
  jne    L41
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  movzbl %bl,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  jmp    L37
```

assistant: ```c
void ascii2bin(FILE *input, FILE *output) {
  unsigned char holder = 0;
  int num = 0;
  while (1) {
    int x = fgetc(input);
    if (x == EOF)
      break;
    holder <<= 1;
    if (x >= '1') {
      holder = holder | 0x01;
    }
    num++;
    if (num % 8 == 0) {
      fputc(holder, output);
      holder = 0;
    }
  }
  if (num % 8 != 0)
    fputc(holder, output);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ascii2bin>:
  endbr64
  push   %r14
  mov    D6(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L37:
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r14)
  je     L35
L38:
  add    %ebx,%ebx
  mov    %ebx,%edx
  or     $0x1,%edx
  cmp    $0x30,%eax
  cmovg  %edx,%ebx
  add    $0x1,%ebp
  test   $0x7,%bpl
  jne    L37
  movzbl %bl,%edi
  mov    %r13,%rsi
  xor    %ebx,%ebx
  call   <fputc@plt>
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r14)
  jne    L38
L35:
  and    $0x7,%ebp
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl %bl,%edi
  mov    %r13,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <fputc@plt>
```

assistant: ```c
void ascii2bin(FILE *input, FILE *output) {
  unsigned char holder = 0;
  int num = 0;
  while (1) {
    int x = fgetc(input);
    if (x == EOF)
      break;
    holder <<= 1;
    if (x >= '1') {
      holder = holder | 0x01;
    }
    num++;
    if (num % 8 == 0) {
      fputc(holder, output);
      holder = 0;
    }
  }
  if (num % 8 != 0)
    fputc(holder, output);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ascii2bin>:
  endbr64
  push   %r14
  mov    D2(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L26:
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r14)
  je     L5
L30:
  add    %ebx,%ebx
  mov    %ebx,%edx
  or     $0x1,%edx
  cmp    $0x30,%eax
  cmovg  %edx,%ebx
  add    $0x1,%ebp
  test   $0x7,%bpl
  jne    L26
  movzbl %bl,%edi
  mov    %r13,%rsi
  xor    %ebx,%ebx
  call   <fputc@plt>
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r14)
  jne    L30
L5:
  and    $0x7,%ebp
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  movzbl %bl,%edi
  mov    %r13,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <fputc@plt>
```

assistant: ```c
void ascii2bin(FILE *input, FILE *output) {
  unsigned char holder = 0;
  int num = 0;
  while (1) {
    int x = fgetc(input);
    if (x == EOF)
      break;
    holder <<= 1;
    if (x >= '1') {
      holder = holder | 0x01;
    }
    num++;
    if (num % 8 == 0) {
      fputc(holder, output);
      holder = 0;
    }
  }
  if (num % 8 != 0)
    fputc(holder, output);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s_memcpy1orgb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x44(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x8,%eax
  sub    -0x44(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  mov    $0x8,%eax
  sub    0x10(%rbp),%eax
  mov    %eax,0x10(%rbp)
  mov    $0x8,%eax
  sub    0x18(%rbp),%eax
  mov    %eax,0x18(%rbp)
  jmp    L2
L1:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L25
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %al,-0x13(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x10,%eax
  mov    %al,-0x12(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x8,%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x13(%rbp),%edx
  mov    -0x44(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    0x20(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%esi
  movzbl -0x12(%rbp),%edx
  mov    0x10(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    0x28(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  movzbl -0x11(%rbp),%edx
  mov    0x18(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    0x30(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L25:
  addq   $0x1,-0x10(%rbp)
  addq   $0x4,-0x8(%rbp)
  addq   $0x1,-0x28(%rbp)
L2:
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  test   %eax,%eax
  jne    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void s_memcpy1orgb(unsigned char *m, int id, void *dest, unsigned int *rgb, int n, int rl, int gl, int bl, int ro, int go, int bo) {
  unsigned char dr;
  unsigned char dg;
  unsigned char db;
  unsigned char *d = (unsigned char *)dest;
  unsigned int *s = (unsigned int *)rgb;
  rl = 8 - rl;
  gl = 8 - gl;
  bl = 8 - bl;
  while (n--) {
    if (*m == id) {
      dr = *s >> 0x18;
      dg = *s >> 0x10;
      db = *s >> 0x08;
      *d = ((dr >> rl) << ro) | ((dg >> gl) << go) | ((db >> bl) << bo);
    }
    d++;
    s++;
    m++;
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<s_memcpy1orgb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    0x48(%rsp),%r12d
  mov    0x50(%rsp),%r13d
  mov    0x58(%rsp),%r14d
  mov    $0x8,%edx
  mov    %edx,%r11d
  sub    %r9d,%r11d
  mov    %edx,%ebp
  sub    0x38(%rsp),%ebp
  sub    0x40(%rsp),%edx
  test   %r8d,%r8d
  je     L8
  mov    %rdi,%rax
  mov    %rcx,%rdi
  mov    %edx,%r9d
  mov    %r8d,%r8d
  add    %rax,%r8
  jmp    L44
L21:
  add    $0x1,%rsi
  add    $0x4,%rdi
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L8
L44:
  movzbl (%rax),%edx
  cmp    %r10d,%edx
  jne    L21
  mov    (%rdi),%ebx
  mov    %ebx,%edx
  shr    $0x10,%edx
  movzbl %dl,%edx
  mov    %ebp,%ecx
  sar    %cl,%edx
  mov    %r13d,%ecx
  shl    %cl,%edx
  movzbl %bh,%ecx
  mov    %ecx,%r15d
  mov    %r9d,%ecx
  sar    %cl,%r15d
  mov    %r14d,%ecx
  shl    %cl,%r15d
  or     %r15d,%edx
  shr    $0x18,%ebx
  mov    %r11d,%ecx
  sar    %cl,%ebx
  mov    %r12d,%ecx
  shl    %cl,%ebx
  or     %ebx,%edx
  mov    %dl,(%rsi)
  jmp    L21
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void s_memcpy1orgb(unsigned char *m, int id, void *dest, unsigned int *rgb, int n, int rl, int gl, int bl, int ro, int go, int bo) {
  unsigned char dr;
  unsigned char dg;
  unsigned char db;
  unsigned char *d = (unsigned char *)dest;
  unsigned int *s = (unsigned int *)rgb;
  rl = 8 - rl;
  gl = 8 - gl;
  bl = 8 - bl;
  while (n--) {
    if (*m == id) {
      dr = *s >> 0x18;
      dg = *s >> 0x10;
      db = *s >> 0x08;
      *d = ((dr >> rl) << ro) | ((dg >> gl) << go) | ((db >> bl) << bo);
    }
    d++;
    s++;
    m++;
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s_memcpy1orgb>:
  endbr64
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    $0x8,%edx
  push   %r15
  mov    %edx,%r11d
  push   %r14
  sub    %r9d,%r11d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    0x48(%rsp),%r12d
  mov    0x50(%rsp),%r13d
  mov    0x58(%rsp),%r14d
  sub    0x38(%rsp),%ebp
  sub    0x40(%rsp),%edx
  test   %r8d,%r8d
  je     L11
  mov    %rdi,%rax
  mov    %r8d,%r8d
  mov    %rcx,%rdi
  mov    %edx,%r9d
  add    %rax,%r8
  nopl   0x0(%rax)
L9:
  movzbl (%rax),%edx
  cmp    %r10d,%edx
  jne    L24
  mov    (%rdi),%ebx
  mov    %ebp,%ecx
  mov    %ebx,%edx
  shr    $0x10,%edx
  movzbl %dl,%edx
  sar    %cl,%edx
  mov    %r13d,%ecx
  shl    %cl,%edx
  movzbl %bh,%ecx
  shr    $0x18,%ebx
  mov    %ecx,%r15d
  mov    %r9d,%ecx
  sar    %cl,%r15d
  mov    %r14d,%ecx
  shl    %cl,%r15d
  mov    %r11d,%ecx
  sar    %cl,%ebx
  mov    %r12d,%ecx
  or     %r15d,%edx
  shl    %cl,%ebx
  or     %ebx,%edx
  mov    %dl,(%rsi)
L24:
  add    $0x1,%rax
  add    $0x1,%rsi
  add    $0x4,%rdi
  cmp    %rax,%r8
  jne    L9
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void s_memcpy1orgb(unsigned char *m, int id, void *dest, unsigned int *rgb, int n, int rl, int gl, int bl, int ro, int go, int bo) {
  unsigned char dr;
  unsigned char dg;
  unsigned char db;
  unsigned char *d = (unsigned char *)dest;
  unsigned int *s = (unsigned int *)rgb;
  rl = 8 - rl;
  gl = 8 - gl;
  bl = 8 - bl;
  while (n--) {
    if (*m == id) {
      dr = *s >> 0x18;
      dg = *s >> 0x10;
      db = *s >> 0x08;
      *d = ((dr >> rl) << ro) | ((dg >> gl) << go) | ((db >> bl) << bo);
    }
    d++;
    s++;
    m++;
  };
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<s_memcpy1orgb>:
  endbr64
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    $0x8,%edx
  push   %r15
  mov    %edx,%r11d
  push   %r14
  sub    %r9d,%r11d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    0x48(%rsp),%r12d
  mov    0x50(%rsp),%r13d
  mov    0x58(%rsp),%r14d
  sub    0x38(%rsp),%ebp
  sub    0x40(%rsp),%edx
  test   %r8d,%r8d
  je     L11
  mov    %rdi,%rax
  mov    %r8d,%r8d
  mov    %rcx,%rdi
  mov    %edx,%r9d
  add    %rax,%r8
  nopl   0x0(%rax)
L17:
  movzbl (%rax),%edx
  cmp    %r10d,%edx
  jne    L28
  mov    (%rdi),%ebx
  mov    %ebp,%ecx
  mov    %ebx,%edx
  shr    $0x10,%edx
  movzbl %dl,%edx
  sar    %cl,%edx
  mov    %r13d,%ecx
  shl    %cl,%edx
  movzbl %bh,%ecx
  shr    $0x18,%ebx
  mov    %ecx,%r15d
  mov    %r9d,%ecx
  sar    %cl,%r15d
  mov    %r14d,%ecx
  shl    %cl,%r15d
  mov    %r11d,%ecx
  sar    %cl,%ebx
  mov    %r12d,%ecx
  or     %r15d,%edx
  shl    %cl,%ebx
  or     %ebx,%edx
  mov    %dl,(%rsi)
L28:
  add    $0x1,%rax
  add    $0x1,%rsi
  add    $0x4,%rdi
  cmp    %r8,%rax
  jne    L17
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void s_memcpy1orgb(unsigned char *m, int id, void *dest, unsigned int *rgb, int n, int rl, int gl, int bl, int ro, int go, int bo) {
  unsigned char dr;
  unsigned char dg;
  unsigned char db;
  unsigned char *d = (unsigned char *)dest;
  unsigned int *s = (unsigned int *)rgb;
  rl = 8 - rl;
  gl = 8 - gl;
  bl = 8 - bl;
  while (n--) {
    if (*m == id) {
      dr = *s >> 0x18;
      dg = *s >> 0x10;
      db = *s >> 0x08;
      *d = ((dr >> rl) << ro) | ((dg >> gl) << go) | ((db >> bl) << bo);
    }
    d++;
    s++;
    m++;
  };
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__int8_t_encoded_array_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t __int8_t_encoded_array_size(const int8_t *p, uint32_t elements) {
  (void)p;
  return (1) * elements;
}
```
user: What is the c source code of the assembly code below?

```asm
<__int8_t_encoded_array_size>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
uint32_t __int8_t_encoded_array_size(const int8_t *p, uint32_t elements) {
  (void)p;
  return (1) * elements;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__int8_t_encoded_array_size>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
uint32_t __int8_t_encoded_array_size(const int8_t *p, uint32_t elements) {
  (void)p;
  return (1) * elements;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__int8_t_encoded_array_size>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
uint32_t __int8_t_encoded_array_size(const int8_t *p, uint32_t elements) {
  (void)p;
  return (1) * elements;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: %02x 

assistant: ```c
void print_raw(int len, char *buf) {
  int i;
  for (i = 0; i < len; i++)
    printf("%02x ", (unsigned char)buf[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_raw>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L9
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x1(%rsi,%rax,1),%r12
  lea    D4(%rip),%rbp
L3:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L3
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %02x 

assistant: ```c
void print_raw(int len, char *buf) {
  int i;
  for (i = 0; i < len; i++)
    printf("%02x ", (unsigned char)buf[i]);
  printf("\n");
}
```