ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<yydestruct>:
  endbr64
  ret
```

assistant: ```c
void yydestruct(const char *yymsg, int yytype, int *yyvaluep) {
  ((void)(yyvaluep));
  if (!yymsg)
    yymsg = "Deleting";
  ;

#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wuninitialized"

#pragma GCC diagnostic ignored "-Wmaybe-uninitialized"

  ((void)(yytype));

#pragma GCC diagnostic pop
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<yydestruct>:
  endbr64
  ret
```

assistant: ```c
void yydestruct(const char *yymsg, int yytype, int *yyvaluep) {
  ((void)(yyvaluep));
  if (!yymsg)
    yymsg = "Deleting";
  ;

#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wuninitialized"

#pragma GCC diagnostic ignored "-Wmaybe-uninitialized"

  ((void)(yytype));

#pragma GCC diagnostic pop
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L1
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L1:
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(int *arr, int lhs, int rhs) {
  if (lhs < rhs) {
    int mid;
    mid = partition(arr, lhs, rhs);
    quick_sort(arr, lhs, mid - 1);
    quick_sort(arr, mid + 1, rhs);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L1
  ret
L1:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quick_sort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quick_sort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quick_sort(int *arr, int lhs, int rhs) {
  if (lhs < rhs) {
    int mid;
    mid = partition(arr, lhs, rhs);
    quick_sort(arr, lhs, mid - 1);
    quick_sort(arr, mid + 1, rhs);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strncpyy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L17:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strncpyy(char *s, char *t, int n) {
  for (int i = 0; i < n; i++) {
    *s++ = *t++;
  }
  *s = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strncpyy>:
  endbr64
  test   %edx,%edx
  jle    L14
  mov    %edx,%edx
  mov    $0x0,%eax
L17:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
  add    %rdx,%rdi
L14:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void strncpyy(char *s, char *t, int n) {
  for (int i = 0; i < n; i++) {
    *s++ = *t++;
  }
  *s = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncpyy>:
  endbr64
  test   %edx,%edx
  jle    L13
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L9:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
  add    %rax,%rdi
L13:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void strncpyy(char *s, char *t, int n) {
  for (int i = 0; i < n; i++) {
    *s++ = *t++;
  }
  *s = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncpyy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L75
  lea    0x1(%rsi),%r8
  lea    -0x1(%rdx),%eax
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L139
  cmp    $0x6,%eax
  jbe    L139
  cmp    $0xe,%eax
  jbe    L137
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
L44:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L44
  mov    %edx,%eax
  mov    %edx,%edi
  and    $0xfffffff0,%eax
  mov    %eax,%r8d
  lea    (%rcx,%r8,1),%r10
  lea    (%rsi,%r8,1),%r11
  cmp    %eax,%edx
  je     L34
  mov    %edx,%r9d
  sub    %eax,%r9d
  lea    -0x1(%r9),%edi
  cmp    $0x6,%edi
  jbe    L104
L14:
  mov    (%rsi,%r8,1),%rsi
  mov    %rsi,(%rcx,%r8,1)
  mov    %r9d,%esi
  and    $0xfffffff8,%esi
  mov    %esi,%edi
  add    %esi,%eax
  add    %rdi,%r10
  add    %rdi,%r11
  mov    %edx,%edi
  cmp    %esi,%r9d
  je     L34
L104:
  movzbl (%r11),%esi
  mov    %edx,%edi
  mov    %sil,(%r10)
  lea    0x1(%rax),%esi
  cmp    %esi,%edx
  jle    L34
  movzbl 0x1(%r11),%esi
  mov    %sil,0x1(%r10)
  lea    0x2(%rax),%esi
  cmp    %esi,%edx
  jle    L34
  movzbl 0x2(%r11),%esi
  mov    %sil,0x2(%r10)
  lea    0x3(%rax),%esi
  cmp    %esi,%edx
  jle    L34
  movzbl 0x3(%r11),%esi
  mov    %sil,0x3(%r10)
  lea    0x4(%rax),%esi
  cmp    %esi,%edx
  jle    L34
  movzbl 0x4(%r11),%esi
  mov    %sil,0x4(%r10)
  lea    0x5(%rax),%esi
  cmp    %esi,%edx
  jle    L34
  movzbl 0x5(%r11),%esi
  add    $0x6,%eax
  mov    %sil,0x5(%r10)
  cmp    %eax,%edx
  jle    L34
  movzbl 0x6(%r11),%eax
  mov    %al,0x6(%r10)
L34:
  add    %rdi,%rcx
L75:
  movb   $0x0,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L139:
  mov    %edx,%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L130:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L130
  jmp    L34
L137:
  mov    %edx,%r9d
  mov    %rsi,%r11
  mov    %rcx,%r10
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L14
```

assistant: ```c
void strncpyy(char *s, char *t, int n) {
  for (int i = 0; i < n; i++) {
    *s++ = *t++;
  }
  *s = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtok_csv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L0
  cmpq   $0x0,-0x28(%rbp)
  jne    L91
L0:
  mov    $0x0,%eax
  jmp    L87
L91:
  cmpq   $0x0,-0x18(%rbp)
  jne    L24
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L60
  mov    $0x0,%eax
  jmp    L87
L24:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L60:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L77
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  jmp    L87
L77:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L62
L49:
  addq   $0x1,-0x10(%rbp)
L62:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L107
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L49
L107:
  mov    -0x10(%rbp),%rax
L87:
  leave
  ret
```

assistant: ```c
char *strtok_csv(char *string, const char *separators, char **savedptr) {
  char *p, *s;
  int i;
  if (separators == NULL || savedptr == NULL) {
    return NULL;
  }
  if (string == NULL) {
    p = *savedptr;
    if (p == NULL) {
      return NULL;
    }
  } else {
    p = string;
  }
  s = strstr(p, separators);
  if (s == NULL) {
    *savedptr = NULL;
    return p;
  }
  *s = 0;
  *savedptr = s + 1;
  while (isspace(*p) && p < s) {
    ++p;
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtok_csv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L9
  mov    %rdi,%rbx
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L9
  test   %rdi,%rdi
  je     L3
L61:
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L23
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rax
  mov    %rax,(%r12)
L60:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  cmp    %rbp,%rbx
  jae    L95
  test   %rax,%rax
  je     L95
  add    $0x1,%rbx
  jmp    L60
L3:
  mov    (%rdx),%rbx
  test   %rbx,%rbx
  jne    L61
  jmp    L95
L23:
  movq   $0x0,(%r12)
  jmp    L95
L9:
  mov    $0x0,%ebx
L95:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok_csv(char *string, const char *separators, char **savedptr) {
  char *p, *s;
  int i;
  if (separators == NULL || savedptr == NULL) {
    return NULL;
  }
  if (string == NULL) {
    p = *savedptr;
    if (p == NULL) {
      return NULL;
    }
  } else {
    p = string;
  }
  s = strstr(p, separators);
  if (s == NULL) {
    *savedptr = NULL;
    return p;
  }
  *s = 0;
  *savedptr = s + 1;
  while (isspace(*p) && p < s) {
    ++p;
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtok_csv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L11
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L11
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L52
L50:
  mov    %r12,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L73
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rax
  mov    %rax,0x0(%rbp)
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L47:
  test   %rax,%rax
  je     L72
  add    $0x1,%r12
L36:
  movsbl (%r12),%edi
  call   <isspace@plt>
  cmp    %rbx,%r12
  jb     L47
L72:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L52:
  mov    (%rdx),%r12
  test   %r12,%r12
  jne    L50
L11:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  movq   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok_csv(char *string, const char *separators, char **savedptr) {
  char *p, *s;
  int i;
  if (separators == NULL || savedptr == NULL) {
    return NULL;
  }
  if (string == NULL) {
    p = *savedptr;
    if (p == NULL) {
      return NULL;
    }
  } else {
    p = string;
  }
  s = strstr(p, separators);
  if (s == NULL) {
    *savedptr = NULL;
    return p;
  }
  *s = 0;
  *savedptr = s + 1;
  while (isspace(*p) && p < s) {
    ++p;
  }
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtok_csv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L73
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L73
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L48
L1:
  mov    %r12,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L64
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rax
  mov    %rax,0x0(%rbp)
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L9:
  test   %rax,%rax
  je     L41
  add    $0x1,%r12
L58:
  movsbl (%r12),%edi
  call   <isspace@plt>
  cmp    %rbx,%r12
  jb     L9
L41:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  mov    (%rdx),%r12
  test   %r12,%r12
  jne    L1
L73:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  movq   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok_csv(char *string, const char *separators, char **savedptr) {
  char *p, *s;
  int i;
  if (separators == NULL || savedptr == NULL) {
    return NULL;
  }
  if (string == NULL) {
    p = *savedptr;
    if (p == NULL) {
      return NULL;
    }
  } else {
    p = string;
  }
  s = strstr(p, separators);
  if (s == NULL) {
    *savedptr = NULL;
    return p;
  }
  *s = 0;
  *savedptr = s + 1;
  while (isspace(*p) && p < s) {
    ++p;
  }
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<n_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L2
L16:
  mov    $0x20,%edi
  call   <putchar@plt>
  subl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x4(%rbp)
  jne    L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void n_spaces(n) int n;
{
  while (!(n == 0)) {
    putchar(' ');
    n--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<n_spaces>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  je     L17
L0:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L0
L17:
  pop    %rbx
  ret
```

assistant: ```c
void n_spaces(n) int n;
{
  while (!(n == 0)) {
    putchar(' ');
    n--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<n_spaces>:
  endbr64
  test   %edi,%edi
  je     L18
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L10
  pop    %rbx
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
void n_spaces(n) int n;
{
  while (!(n == 0)) {
    putchar(' ');
    n--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<n_spaces>:
  endbr64
  test   %edi,%edi
  je     L17
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L5
  pop    %rbx
  ret
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
void n_spaces(n) int n;
{
  while (!(n == 0)) {
    putchar(' ');
    n--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_progs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <add_prog@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void add_progs(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++)
    add_prog(argv[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_progs>:
  endbr64
  cmp    $0x1,%edi
  jle    L9
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L12:
  mov    (%rbx),%rdi
  call   <add_prog@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  ret
```

assistant: ```c
void add_progs(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++)
    add_prog(argv[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<add_progs>:
  endbr64
  cmp    $0x1,%edi
  jle    L4
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <add_prog@plt>
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void add_progs(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++)
    add_prog(argv[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<add_progs>:
  endbr64
  cmp    $0x1,%edi
  jle    L6
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <add_prog@plt>
  cmp    %rbp,%rbx
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void add_progs(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++)
    add_prog(argv[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    0x18(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    0x20(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x50(%rbp),%r9
  mov    -0x58(%rbp),%r8
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  lea    -0x10(%rbp),%rdi
  push   %rdi
  push   -0x18(%rbp)
  mov    %rax,%rdi
  call   <deoxys_aead_encrypt@plt>
  add    $0x10,%rsp
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  size_t outlen = 0;
  deoxys_aead_encrypt(ad, adlen, m, mlen, k, npub, c, &outlen);
  *clen = outlen;
  (void)nsec;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %r8,%rdi
  mov    %r9,%rsi
  mov    %fs:0x28,%r8
  mov    %r8,0x8(%rsp)
  xor    %r8d,%r8d
  movq   $0x0,(%rsp)
  mov    %rsp,%r8
  push   %r8
  push   %rax
  mov    0x38(%rsp),%r9
  mov    0x40(%rsp),%r8
  call   <deoxys_aead_encrypt@plt>
  mov    0x10(%rsp),%rax
  mov    %rax,(%rbx)
  add    $0x10,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  size_t outlen = 0;
  deoxys_aead_encrypt(ad, adlen, m, mlen, k, npub, c, &outlen);
  *clen = outlen;
  (void)nsec;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%rbx
  mov    %r8,%rdi
  mov    %r9,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  movq   $0x0,(%rsp)
  push   %rax
  push   %r10
  mov    0x38(%rsp),%r9
  mov    0x40(%rsp),%r8
  call   <deoxys_aead_encrypt@plt>
  mov    0x10(%rsp),%rax
  mov    %rax,(%rbx)
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  size_t outlen = 0;
  deoxys_aead_encrypt(ad, adlen, m, mlen, k, npub, c, &outlen);
  *clen = outlen;
  (void)nsec;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%rbx
  mov    %r8,%rdi
  mov    %r9,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  movq   $0x0,(%rsp)
  push   %rax
  push   %r10
  mov    0x38(%rsp),%r9
  mov    0x40(%rsp),%r8
  call   <deoxys_aead_encrypt@plt>
  mov    0x10(%rsp),%rax
  mov    %rax,(%rbx)
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  size_t outlen = 0;
  deoxys_aead_encrypt(ad, adlen, m, mlen, k, npub, c, &outlen);
  *clen = outlen;
  (void)nsec;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L0
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L28
L0:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L28:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D37
type_guessed: string
name: retrieve_data
arguments: data_tag: D29
type_guessed: string
name: retrieve_data
arguments: data_tag: D32
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string

tool: D37: Enter a number: 

tool: D29: %i

tool: D32: %i is prime.

tool: D10: %i is not prime.

assistant: ```c
int main() {
  int a;
  printf("Enter a number: ");
  scanf("%i", &a);
  if (isPrime(a))
    printf("%i is prime.", a);
  else
    printf("%i is not prime.", a);
  getch();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L1
  mov    0x4(%rsp),%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  mov    0x4(%rsp),%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D7
datatype: string
name: extract_symbolic_data
arguments: label: D34
datatype: string
name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D11: Enter a number: 

tool: D7: %i

tool: D34: %i is prime.

tool: D0: %i is not prime.

assistant: ```c
int main() {
  int a;
  printf("Enter a number: ");
  scanf("%i", &a);
  if (isPrime(a))
    printf("%i is prime.", a);
  else
    printf("%i is not prime.", a);
  getch();
  return 0;
}
```