ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PowerMod>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L23
  push   %r14
  push   %r13
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  cmp    $0x1,%esi
  je     L27
  mov    %esi,%edx
  mov    $0x1,%eax
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,%r13d
  je     L6
  cmp    $0x1,%edx
  je     L117
  test   %esi,%esi
  lea    0x3(%rsi),%edx
  mov    $0x1,%eax
  cmovns %esi,%edx
  sar    $0x2,%edx
  mov    %edx,%r14d
  je     L85
  cmp    $0x1,%edx
  je     L13
  test   %ebx,%ebx
  lea    0x7(%rsi),%esi
  mov    %ebp,%edx
  mov    %edi,0xc(%rsp)
  cmovns %ebx,%esi
  sar    $0x3,%esi
  call   <PowerMod>
  xor    %edx,%edx
  mov    0xc(%rsp),%edi
  imul   %eax,%eax
  div    %ebp
  and    $0x1,%r14d
  mov    %edx,%eax
  jne    L43
L32:
  imul   %edx,%eax
L85:
  xor    %edx,%edx
  div    %ebp
  and    $0x1,%r13d
  mov    %edx,%eax
  je     L36
  imul   %edi,%eax
  xor    %edx,%edx
  div    %ebp
  mov    %edx,%eax
L36:
  imul   %edx,%eax
L6:
  xor    %edx,%edx
  div    %ebp
  and    $0x1,%ebx
  mov    %edx,%r8d
  je     L18
  mov    %edi,%eax
  add    $0x18,%rsp
  imul   %edx,%eax
  xor    %edx,%edx
  pop    %rbx
  div    %ebp
  pop    %rbp
  pop    %r13
  pop    %r14
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L27:
  mov    %edi,%eax
  cltd
  idiv   %ebp
  mov    %edx,%r8d
L18:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L117:
  mov    %edi,%eax
  cltd
  idiv   %ebp
  mov    %edx,%eax
  imul   %edx,%eax
  jmp    L6
  nopl   0x0(%rax)
L43:
  imul   %edi,%eax
  xor    %edx,%edx
  div    %ebp
  mov    %edx,%eax
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %edi,%eax
  cltd
  idiv   %ebp
  mov    %edx,%eax
  imul   %edx,%eax
  jmp    L85
```

assistant: ```c
unsigned int PowerMod(int a, int num, int mod) {
  unsigned int temp;
  if (num == 0)
    return 1;
  if (num == 1)
    return a % mod;
  temp = PowerMod(a, num / 2, mod);
  temp = temp * temp % mod;
  if (!(num & 1))
    return temp;
  else
    return a * temp % mod;
}
```
user: What is the c source code of the assembly code below?

```asm
<PowerMod>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L31
  push   %r14
  push   %r13
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  cmp    $0x1,%esi
  je     L80
  mov    %esi,%edx
  mov    $0x1,%eax
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,%r13d
  je     L47
  cmp    $0x1,%edx
  je     L27
  test   %esi,%esi
  lea    0x3(%rsi),%edx
  mov    $0x1,%eax
  cmovns %esi,%edx
  sar    $0x2,%edx
  mov    %edx,%r14d
  je     L13
  cmp    $0x1,%edx
  je     L87
  test   %ebx,%ebx
  lea    0x7(%rsi),%esi
  mov    %ebp,%edx
  mov    %edi,0xc(%rsp)
  cmovns %ebx,%esi
  sar    $0x3,%esi
  call   <PowerMod>
  xor    %edx,%edx
  mov    0xc(%rsp),%edi
  imul   %eax,%eax
  div    %ebp
  and    $0x1,%r14d
  mov    %edx,%eax
  jne    L59
L35:
  imul   %edx,%eax
L13:
  xor    %edx,%edx
  div    %ebp
  and    $0x1,%r13d
  mov    %edx,%eax
  je     L43
  imul   %edi,%eax
  xor    %edx,%edx
  div    %ebp
  mov    %edx,%eax
L43:
  imul   %edx,%eax
L47:
  xor    %edx,%edx
  div    %ebp
  and    $0x1,%ebx
  mov    %edx,%r8d
  je     L53
  mov    %edi,%eax
  add    $0x18,%rsp
  imul   %edx,%eax
  xor    %edx,%edx
  pop    %rbx
  div    %ebp
  pop    %rbp
  pop    %r13
  pop    %r14
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L80:
  mov    %edi,%eax
  cltd
  idiv   %ebp
  mov    %edx,%r8d
L53:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L27:
  mov    %edi,%eax
  cltd
  idiv   %ebp
  mov    %edx,%eax
  imul   %edx,%eax
  jmp    L47
  nopl   0x0(%rax)
L59:
  imul   %edi,%eax
  xor    %edx,%edx
  div    %ebp
  mov    %edx,%eax
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L87:
  mov    %edi,%eax
  cltd
  idiv   %ebp
  mov    %edx,%eax
  imul   %edx,%eax
  jmp    L13
```

assistant: ```c
unsigned int PowerMod(int a, int num, int mod) {
  unsigned int temp;
  if (num == 0)
    return 1;
  if (num == 1)
    return a % mod;
  temp = PowerMod(a, num / 2, mod);
  temp = temp * temp % mod;
  if (!(num & 1))
    return temp;
  else
    return a * temp % mod;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_timegm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x1,%edx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <setenv@plt>
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <setenv@plt>
  jmp    L17
L18:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <unsetenv@plt>
L17:
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D5
type_infered: string

tool: D7: TZ

tool: 

assistant: ```c
time_t my_timegm(struct tm *tm) {
  time_t ret;
  char *tz;
  tz = getenv("TZ");
  setenv("TZ", "", 1);
  tzset();
  ret = mktime(tm);
  if (tz)
    setenv("TZ", tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_timegm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D3(%rip),%r12
  mov    %r12,%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  mov    $0x1,%edx
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <setenv@plt>
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    %rbp,%rdi
  call   <mktime@plt>
  mov    %eax,%ebp
  test   %rbx,%rbx
  je     L12
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <setenv@plt>
L11:
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  lea    D3(%rip),%rdi
  call   <unsetenv@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D3: TZ

tool: 

assistant: ```c
time_t my_timegm(struct tm *tm) {
  time_t ret;
  char *tz;
  tz = getenv("TZ");
  setenv("TZ", "", 1);
  tzset();
  ret = mktime(tm);
  if (tz)
    setenv("TZ", tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_timegm>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  call   <getenv@plt>
  mov    $0x1,%edx
  lea    D8(%rip),%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12,%rdi
  call   <mktime@plt>
  mov    %eax,%r12d
  test   %rbp,%rbp
  je     L5
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x1,%edx
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %r13,%rdi
  call   <unsetenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D8
data_type: string

tool: D1: TZ

tool: 

assistant: ```c
time_t my_timegm(struct tm *tm) {
  time_t ret;
  char *tz;
  tz = getenv("TZ");
  setenv("TZ", "", 1);
  tzset();
  ret = mktime(tm);
  if (tz)
    setenv("TZ", tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_timegm>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  call   <getenv@plt>
  mov    $0x1,%edx
  lea    D5(%rip),%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12,%rdi
  call   <mktime@plt>
  mov    %eax,%r12d
  test   %rbp,%rbp
  je     L3
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x1,%edx
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdi
  call   <unsetenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string
name: parse_data
arguments: tag: D5
type: string

tool: D3: TZ

tool: 

assistant: ```c
time_t my_timegm(struct tm *tm) {
  time_t ret;
  char *tz;
  tz = getenv("TZ");
  setenv("TZ", "", 1);
  tzset();
  ret = mktime(tm);
  if (tz)
    setenv("TZ", tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<digital_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L8:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L13:
  cmpl   $0x0,-0x14(%rbp)
  jne    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t digital_sum(uint64_t i) {
  uint64_t digital_sum = 0;
  for (; i; i /= 10) {
    digital_sum += i % 10;
  }
  return digital_sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<digital_sum>:
  endbr64
  test   %edi,%edi
  je     L28
  mov    $0x0,%ecx
L23:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%ecx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L23
L8:
  mov    %ecx,%eax
  ret
L28:
  mov    %edi,%ecx
  jmp    L8
```

assistant: ```c
uint64_t digital_sum(uint64_t i) {
  uint64_t digital_sum = 0;
  for (; i; i /= 10) {
    digital_sum += i % 10;
  }
  return digital_sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<digital_sum>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L0
  nopl   0x0(%rax,%rax,1)
L19:
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L19
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t digital_sum(uint64_t i) {
  uint64_t digital_sum = 0;
  for (; i; i /= 10) {
    digital_sum += i % 10;
  }
  return digital_sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<digital_sum>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L4
  nopl   0x0(%rax,%rax,1)
L10:
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L10
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t digital_sum(uint64_t i) {
  uint64_t digital_sum = 0;
  for (; i; i /= 10) {
    digital_sum += i % 10;
  }
  return digital_sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vector_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L22:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L39
  mov    $0xffffffff,%eax
  jmp    L4
L39:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  mov    -0x4(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int vector_sum(int *result, int size) {
  int i, sum;
  sum = 0;
  for (i = 0; i < size; i++) {
    if (result[i] < 0) {
      return -1;
    }
    sum += result[i];
  }
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<vector_sum>:
  endbr64
  test   %esi,%esi
  jle    L43
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rsi
  mov    $0x0,%ecx
L42:
  mov    (%rax),%edx
  test   %edx,%edx
  js     L44
  add    %edx,%ecx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L42
  jmp    L21
L43:
  mov    $0x0,%ecx
  jmp    L21
L44:
  mov    $0xffffffff,%ecx
L21:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int vector_sum(int *result, int size) {
  int i, sum;
  sum = 0;
  for (i = 0; i < size; i++) {
    if (result[i] < 0) {
      return -1;
    }
    sum += result[i];
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector_sum>:
  endbr64
  test   %esi,%esi
  jle    L45
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rdx
  jmp    L40
  nopl   (%rax)
L33:
  add    $0x4,%rdi
  add    %eax,%r8d
  cmp    %rdx,%rdi
  je     L29
L40:
  mov    (%rdi),%eax
  test   %eax,%eax
  jns    L33
  mov    $0xffffffff,%r8d
L29:
  mov    %r8d,%eax
  ret
L45:
  xor    %r8d,%r8d
  jmp    L29
```

assistant: ```c
int vector_sum(int *result, int size) {
  int i, sum;
  sum = 0;
  for (i = 0; i < size; i++) {
    if (result[i] < 0) {
      return -1;
    }
    sum += result[i];
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vector_sum>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rdx
  jmp    L0
  nopl   (%rax)
L31:
  add    $0x4,%rdi
  add    %eax,%r8d
  cmp    %rdx,%rdi
  je     L22
L0:
  mov    (%rdi),%eax
  test   %eax,%eax
  jns    L31
  mov    $0xffffffff,%r8d
L22:
  mov    %r8d,%eax
  ret
L6:
  xor    %r8d,%r8d
  jmp    L22
```

assistant: ```c
int vector_sum(int *result, int size) {
  int i, sum;
  sum = 0;
  for (i = 0; i < size; i++) {
    if (result[i] < 0) {
      return -1;
    }
    sum += result[i];
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L10:
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <paths@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x14,-0x8(%rbp)
  jle    L10
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: %dx%d: %llu


assistant: ```c
int main() {
  for (int i = 0; i < 21; i++) {
    uint64_t count = paths(0, 0, i, i);
    printf("%dx%d: %llu\n", i, i, count);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D6(%rip),%rbp
L2:
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <paths@plt>
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x15,%ebx
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: %dx%d: %llu


assistant: ```c
int main() {
  for (int i = 0; i < 21; i++) {
    uint64_t count = paths(0, 0, i, i);
    printf("%dx%d: %llu\n", i, i, count);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%ecx
  mov    %ebx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <paths@plt>
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x15,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: %dx%d: %llu


assistant: ```c
int main() {
  for (int i = 0; i < 21; i++) {
    uint64_t count = paths(0, 0, i, i);
    printf("%dx%d: %llu\n", i, i, count);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%ecx
  mov    %ebx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <paths@plt>
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x15,%ebx
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string

tool: D2: %dx%d: %llu


assistant: ```c
int main() {
  for (int i = 0; i < 21; i++) {
    uint64_t count = paths(0, 0, i, i);
    printf("%dx%d: %llu\n", i, i, count);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fgets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jg     L40
  mov    $0x0,%eax
  jmp    L26
L40:
  movl   $0x0,-0xc(%rbp)
  jmp    L49
L63:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L26
L30:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0xa,-0xc(%rbp)
  je     L14
L49:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L63
  jmp    L41
L14:
  nop
L41:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L26:
  leave
  ret
```

assistant: ```c
char *fgets(char *str, int num, FILE *stream) {
  char *buf = str;
  if (num <= 1) {
    return NULL;
  }
  int ch = '\0';
  while (--num > 0) {
    ch = fgetc(stream);
    if (ch == EOF) {
      return NULL;
    }
    *str++ = ch;
    if (ch == '\n') {
      break;
    }
  }
  *str = '\0';
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<fgets>:
  endbr64
  cmp    $0x1,%esi
  jle    L48
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rdx,%rbp
  lea    -0x1(%rsi),%r12d
  add    %rdi,%r12
  mov    %rdi,%rbx
L54:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L33
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%eax
  je     L22
  cmp    %rbx,%r12
  jne    L54
L6:
  movb   $0x0,(%r12)
  mov    %r13,%rax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    %rbx,%r12
  jmp    L6
L48:
  mov    $0x0,%eax
  ret
L33:
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
char *fgets(char *str, int num, FILE *stream) {
  char *buf = str;
  if (num <= 1) {
    return NULL;
  }
  int ch = '\0';
  while (--num > 0) {
    ch = fgetc(stream);
    if (ch == EOF) {
      return NULL;
    }
    *str++ = ch;
    if (ch == '\n') {
      break;
    }
  }
  *str = '\0';
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fgets>:
  endbr64
  cmp    $0x1,%esi
  jle    L8
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    D8(%rip),%r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  add    %rdi,%rbp
  mov    %rdx,%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r12)
  je     L19
  add    $0x1,%r14
  mov    %al,-0x1(%r14)
  cmp    $0xa,%eax
  je     L6
  cmp    %r14,%rbp
  jne    L0
L6:
  movb   $0x0,(%r14)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *fgets(char *str, int num, FILE *stream) {
  char *buf = str;
  if (num <= 1) {
    return NULL;
  }
  int ch = '\0';
  while (--num > 0) {
    ch = fgetc(stream);
    if (ch == EOF) {
      return NULL;
    }
    *str++ = ch;
    if (ch == '\n') {
      break;
    }
  }
  *str = '\0';
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fgets>:
  endbr64
  cmp    $0x1,%esi
  jle    L6
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    D5(%rip),%r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  add    %rdi,%rbp
  mov    %rdx,%rbx
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r12)
  je     L25
  add    $0x1,%r14
  mov    %al,-0x1(%r14)
  cmp    $0xa,%eax
  je     L16
  cmp    %r14,%rbp
  jne    L36
L16:
  movb   $0x0,(%r14)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *fgets(char *str, int num, FILE *stream) {
  char *buf = str;
  if (num <= 1) {
    return NULL;
  }
  int ch = '\0';
  while (--num > 0) {
    ch = fgetc(stream);
    if (ch == EOF) {
      return NULL;
    }
    *str++ = ch;
    if (ch == '\n') {
      break;
    }
  }
  *str = '\0';
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<udpnumlisten>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  lea    -0xc(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sockaddrnumfill@plt>
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int udpnumlisten(int sock, uint32_t ip, uint16_t port) {
  struct sockaddr_in sa;
  sockaddrnumfill(&sa, ip, port);
  return bind(sock, (struct sockaddr *)&sa, sizeof(struct sockaddr_in));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<udpnumlisten>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sockaddrnumfill@plt>
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udpnumlisten(int sock, uint32_t ip, uint16_t port) {
  struct sockaddr_in sa;
  sockaddrnumfill(&sa, ip, port);
  return bind(sock, (struct sockaddr *)&sa, sizeof(struct sockaddr_in));
}
```