ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L101
L29:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L29
L101:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L77
L111:
  mov    %rsp,%rbx
  test   %eax,%eax
  jle    L94
  pxor   %xmm6,%xmm6
  xor    %r13d,%r13d
  movss  %xmm6,-0x44(%rbp)
  movd   %xmm6,%r15d
  movd   %xmm6,%r14d
  jmp    L66
  nopl   0x0(%rax)
L115:
  movss  D32(%rip),%xmm2
  movd   %r14d,%xmm3
  addss  %xmm3,%xmm2
  movd   %xmm2,%r14d
L39:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  cmp    %r13d,%eax
  jle    L81
L66:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L115
  jne    L0
  movd   %r15d,%xmm7
  mov    -0x3c(%rbp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  movss  D32(%rip),%xmm4
  addss  %xmm7,%xmm4
  movd   %xmm4,%r15d
  cmp    %r13d,%eax
  jg     L66
  nopl   0x0(%rax,%rax,1)
L81:
  pxor   %xmm1,%xmm1
  movd   %r14d,%xmm0
  lea    D25(%rip),%r12
  cvtsi2ss %eax,%xmm1
  mov    %r12,%rdi
  divss  %xmm1,%xmm0
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  -0x44(%rbp),%xmm0
  mov    %r12,%rdi
  cvtsi2ssl -0x3c(%rbp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movd   %r15d,%xmm0
  mov    %r12,%rdi
  cvtsi2ssl -0x3c(%rbp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  movss  D32(%rip),%xmm5
  addss  -0x44(%rbp),%xmm5
  movss  %xmm5,-0x44(%rbp)
  jmp    L39
L77:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L111
L94:
  pxor   %xmm4,%xmm4
  movss  %xmm4,-0x44(%rbp)
  movd   %xmm4,%r15d
  movd   %xmm4,%r14d
  jmp    L81
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D32
type: byte[4]
name: unpack_data
arguments: data_label: D25
type: string

tool: D3: %d

tool: {"D32": [0x00,0x00,0x80,0x3f]}

tool: D25: %f


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  int arr[a];
  float count = 0;
  float cou = 0;
  float num = 0;
  for (int i = 0; i < a; ++i) {
    scanf("%d", &arr[i]);
    if (arr[i] > 0) {
      count = count + 1;
    } else if (arr[i] == 0) {
      cou = cou + 1;
    } else if (arr[i] < 0) {
      num = num + 1;
    }
  }
  printf("%f\n", count / a);
  printf("%f\n", num / a);
  printf("%f\n", cou / a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L104
L59:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L59
L104:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L82
L120:
  mov    %rsp,%rbx
  test   %eax,%eax
  jle    L69
  pxor   %xmm6,%xmm6
  xor    %r13d,%r13d
  movss  %xmm6,-0x44(%rbp)
  movd   %xmm6,%r15d
  movd   %xmm6,%r14d
  jmp    L29
  nopl   0x0(%rax)
L19:
  movss  D0(%rip),%xmm2
  movd   %r14d,%xmm3
  addss  %xmm3,%xmm2
  movd   %xmm2,%r14d
L17:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  cmp    %r13d,%eax
  jle    L10
L29:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L19
  jne    L81
  movd   %r15d,%xmm7
  mov    -0x3c(%rbp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  movss  D0(%rip),%xmm4
  addss  %xmm7,%xmm4
  movd   %xmm4,%r15d
  cmp    %r13d,%eax
  jg     L29
  nopl   0x0(%rax,%rax,1)
L10:
  pxor   %xmm1,%xmm1
  movd   %r14d,%xmm0
  lea    D11(%rip),%r12
  cvtsi2ss %eax,%xmm1
  mov    %r12,%rdi
  divss  %xmm1,%xmm0
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  -0x44(%rbp),%xmm0
  mov    %r12,%rdi
  cvtsi2ssl -0x3c(%rbp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movd   %r15d,%xmm0
  mov    %r12,%rdi
  cvtsi2ssl -0x3c(%rbp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L81:
  movss  D0(%rip),%xmm5
  addss  -0x44(%rbp),%xmm5
  movss  %xmm5,-0x44(%rbp)
  jmp    L17
L82:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L120
L69:
  pxor   %xmm4,%xmm4
  movss  %xmm4,-0x44(%rbp)
  movd   %xmm4,%r15d
  movd   %xmm4,%r14d
  jmp    L10
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D0
type_guessed: byte[4]
name: unpack_data
arguments: data_label: D11
type_guessed: string

tool: D7: %d

tool: {"D0": [0x00,0x00,0x80,0x3f]}

tool: D11: %f


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  int arr[a];
  float count = 0;
  float cou = 0;
  float num = 0;
  for (int i = 0; i < a; ++i) {
    scanf("%d", &arr[i]);
    if (arr[i] > 0) {
      count = count + 1;
    } else if (arr[i] == 0) {
      cou = cou + 1;
    } else if (arr[i] < 0) {
      num = num + 1;
    }
  }
  printf("%f\n", count / a);
  printf("%f\n", num / a);
  printf("%f\n", cou / a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MAIN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x2,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <print@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <print@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: i 

assistant: ```c
int MAIN() {
  int i = 8;
  int *p = &i;
  *p >>= 2;
  print("i ", *p);
  print(i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MAIN>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <print@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: i 

assistant: ```c
int MAIN() {
  int i = 8;
  int *p = &i;
  *p >>= 2;
  print("i ", *p);
  print(i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MAIN>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <print@plt>
  mov    $0x2,%edi
  xor    %eax,%eax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: i 

assistant: ```c
int MAIN() {
  int i = 8;
  int *p = &i;
  *p >>= 2;
  print("i ", *p);
  print(i);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<MAIN>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <print@plt>
  mov    $0x2,%edi
  xor    %eax,%eax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: i 

assistant: ```c
int MAIN() {
  int i = 8;
  int *p = &i;
  *p >>= 2;
  print("i ", *p);
  print(i);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<loop_g_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x1024(%rbp)
  movl   $0x0,-0x1020(%rbp)
  jmp    L37
L45:
  mov    -0x1020(%rbp),%eax
  cltq
  mov    -0x1020(%rbp),%edx
  mov    %edx,-0x1010(%rbp,%rax,4)
  addl   $0x1,-0x1020(%rbp)
L37:
  cmpl   $0x3ff,-0x1020(%rbp)
  jle    L45
  movl   $0x0,-0x1020(%rbp)
  jmp    L75
L61:
  lea    -0x1024(%rbp),%rax
  mov    %rax,-0x1018(%rbp)
  mov    -0x1020(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x1024(%rbp)
  movl   $0x0,-0x101c(%rbp)
  jmp    L17
L32:
  mov    -0x1020(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x101c(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%ecx
  mov    -0x1024(%rbp),%edx
  mov    -0x1020(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%esi
  mov    -0x101c(%rbp),%eax
  add    %esi,%eax
  add    %ecx,%edx
  cltq
  mov    %edx,-0x1010(%rbp,%rax,4)
  addl   $0x1,-0x101c(%rbp)
L17:
  cmpl   $0x1f,-0x101c(%rbp)
  jle    L32
  mov    -0x1018(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1018(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x1020(%rbp)
L75:
  cmpl   $0x1f,-0x1020(%rbp)
  jle    L61
  movl   $0x0,-0x1020(%rbp)
  jmp    L66
L52:
  mov    -0x1020(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%edx
  mov    -0x1020(%rbp),%eax
  lea    0x1f(%rax),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  sar    $0x5,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x1020(%rbp),%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x1020(%rbp)
L66:
  cmpl   $0x3ff,-0x1020(%rbp)
  jle    L52
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L72
  call   <__stack_chk_fail@plt>
L72:
  leave
  ret
```

assistant: ```c
void loop_g_4() {
  int x = 5, i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
#pragma acc loop gang private(x)
    for (i = 0; i < 32; i++) {
      int *p = &x;
      x = i * 2;
#pragma acc loop worker
      for (int j = 0; j < 32; j++)
        arr[i * 32 + j] += x;
      (*p)--;
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + (i / 32) * 2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<loop_g_4>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
L10:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L10
  lea    0x80(%rsp),%rdx
  mov    $0x0,%esi
L30:
  mov    %esi,%ecx
  lea    -0x80(%rdx),%rax
L8:
  add    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L8
  add    $0x2,%esi
  sub    $0xffffffffffffff80,%rdx
  cmp    $0x40,%esi
  jne    L30
  mov    $0x0,%ebx
  mov    %rsp,%rbp
L5:
  lea    0x1f(%rbx),%eax
  test   %ebx,%ebx
  cmovns %ebx,%eax
  sar    $0x5,%eax
  lea    (%rbx,%rax,2),%eax
  cmp    0x0(%rbp,%rbx,4),%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x1,%rbx
  cmp    $0x400,%rbx
  jne    L5
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void loop_g_4() {
  int x = 5, i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
#pragma acc loop gang private(x)
    for (i = 0; i < 32; i++) {
      int *p = &x;
      x = i * 2;
#pragma acc loop worker
      for (int j = 0; j < 32; j++)
        arr[i * 32 + j] += x;
      (*p)--;
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + (i / 32) * 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<loop_g_4>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L42:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L42
  lea    0x80(%rsp),%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L27:
  lea    -0x80(%rcx),%rax
  nopl   0x0(%rax)
L10:
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L10
  add    $0x2,%edx
  lea    0x80(%rax),%rcx
  cmp    $0x40,%edx
  jne    L27
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L33:
  mov    %ebx,%eax
  xor    %edi,%edi
  sar    $0x5,%eax
  lea    (%rbx,%rax,2),%eax
  cmp    0x0(%rbp,%rbx,4),%eax
  sete   %dil
  add    $0x1,%rbx
  call   <assert@plt>
  cmp    $0x400,%rbx
  jne    L33
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void loop_g_4() {
  int x = 5, i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
#pragma acc loop gang private(x)
    for (i = 0; i < 32; i++) {
      int *p = &x;
      x = i * 2;
#pragma acc loop worker
      for (int j = 0; j < 32; j++)
        arr[i * 32 + j] += x;
      (*p)--;
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + (i / 32) * 2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<loop_g_4>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  movdqa D6(%rip),%xmm0
  movdqa D14(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1000(%rsp),%rcx
  mov    %rbp,%rax
  mov    %rbp,%rdx
  nopw   0x0(%rax,%rax,1)
L35:
  movdqa %xmm0,%xmm1
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rdx)
  cmp    %rcx,%rdx
  jne    L35
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L0:
  movdqa (%rax),%xmm1
  movd   %edx,%xmm3
  sub    $0xffffffffffffff80,%rax
  add    $0x2,%edx
  pshufd $0x0,%xmm3,%xmm0
  paddd  %xmm0,%xmm1
  movaps %xmm1,-0x80(%rax)
  movdqa -0x70(%rax),%xmm1
  paddd  %xmm0,%xmm1
  movaps %xmm1,-0x70(%rax)
  movdqa -0x60(%rax),%xmm1
  paddd  %xmm0,%xmm1
  movaps %xmm1,-0x60(%rax)
  movdqa -0x50(%rax),%xmm1
  paddd  %xmm0,%xmm1
  movaps %xmm1,-0x50(%rax)
  movdqa -0x40(%rax),%xmm1
  paddd  %xmm0,%xmm1
  movaps %xmm1,-0x40(%rax)
  movdqa -0x30(%rax),%xmm1
  paddd  %xmm0,%xmm1
  movaps %xmm1,-0x30(%rax)
  movdqa -0x20(%rax),%xmm1
  paddd  %xmm0,%xmm1
  paddd  -0x10(%rax),%xmm0
  movaps %xmm1,-0x20(%rax)
  movaps %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L0
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%eax
  xor    %edi,%edi
  sar    $0x5,%eax
  lea    (%rbx,%rax,2),%eax
  cmp    0x0(%rbp,%rbx,4),%eax
  sete   %dil
  add    $0x1,%rbx
  call   <assert@plt>
  cmp    $0x400,%rbx
  jne    L5
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: byte[16]
name: disassemble_data
arguments: label: D14
type: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D14": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void loop_g_4() {
  int x = 5, i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
#pragma acc loop gang private(x)
    for (i = 0; i < 32; i++) {
      int *p = &x;
      x = i * 2;
#pragma acc loop worker
      for (int j = 0; j < 32; j++)
        arr[i * 32 + j] += x;
      (*p)--;
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + (i / 32) * 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<si470x_mute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <si470x_powerdown@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t si470x_mute() {
  si470x_powerdown();
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<si470x_mute>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <si470x_powerdown@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t si470x_mute() {
  si470x_powerdown();
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<si470x_mute>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <si470x_powerdown@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t si470x_mute() {
  si470x_powerdown();
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<si470x_mute>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <si470x_powerdown@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t si470x_mute() {
  si470x_powerdown();
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<req_swoa_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <build_sw_path@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <req_sw@plt>
  mov    %eax,%edi
  call   <response_char@plt>
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movzbl -0x9(%rbp),%eax
  leave
  ret
```

assistant: ```c
char req_swoa_char(const char *command, const char *hostname, const char *session_id) {
  char *path = build_sw_path(command, session_id, 0);
  char res = response_char(req_sw(hostname, command, path));
  free(path);
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<req_swoa_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    $0x0,%edx
  call   <build_sw_path@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <req_sw@plt>
  mov    %eax,%edi
  call   <response_char@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char req_swoa_char(const char *command, const char *hostname, const char *session_id) {
  char *path = build_sw_path(command, session_id, 0);
  char res = response_char(req_sw(hostname, command, path));
  free(path);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<req_swoa_char>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  xor    %edx,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <build_sw_path@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <req_sw@plt>
  mov    %eax,%edi
  call   <response_char@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char req_swoa_char(const char *command, const char *hostname, const char *session_id) {
  char *path = build_sw_path(command, session_id, 0);
  char res = response_char(req_sw(hostname, command, path));
  free(path);
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<req_swoa_char>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  xor    %edx,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <build_sw_path@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <req_sw@plt>
  mov    %eax,%edi
  call   <response_char@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char req_swoa_char(const char *command, const char *hostname, const char *session_id) {
  char *path = build_sw_path(command, session_id, 0);
  char res = response_char(req_sw(hostname, command, path));
  free(path);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sedb_string_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L28
L78:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x12(%rbp)
  jne    L67
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L67:
  cmpb   $0x0,-0x11(%rbp)
  jne    L9
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L9:
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  je     L7
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L7:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L28:
  cmpl   $0x0,-0x4(%rbp)
  jne    L78
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sedb_string_match(char *indication, char *frame) {
  int i1 = 0;
  int i2 = 0;
  int result = 0;
  char c1, c2;
  int again = 1;
  while (again) {
    c1 = indication[i1];
    c2 = frame[i2];
    if (c1 == '\0') {
      result = 1;
      again = 0;
    } else if (c2 == '\0') {
      result = 0;
      again = 0;
    } else if (c1 != c2) {
      i2 = i2 - i1 + 1;
      i1 = 0;
    } else {
      i1++;
      i2++;
    }
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sedb_string_match>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    $0x0,%edi
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  mov    $0x1,%r13d
  mov    $0x0,%ecx
L23:
  mov    %r13d,%eax
  movslq %r12d,%r11
  movslq %ebp,%rbx
L47:
  mov    %edi,%r10d
L68:
  test   %eax,%eax
  je     L26
  movzbl (%r9,%r11,1),%edx
  test   %dl,%dl
  je     L17
  movzbl (%rsi,%rbx,1),%r8d
  mov    %ecx,%edi
  mov    %ecx,%eax
  test   %r8b,%r8b
  je     L47
  cmp    %r8b,%dl
  je     L30
  sub    %r12d,%ebp
  add    $0x1,%ebp
  mov    $0x0,%r12d
L34:
  mov    %r10d,%edi
  jmp    L23
L30:
  add    $0x1,%r12d
  add    $0x1,%ebp
  jmp    L34
L17:
  mov    %eax,%r10d
  mov    %ecx,%eax
  jmp    L68
L26:
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sedb_string_match(char *indication, char *frame) {
  int i1 = 0;
  int i2 = 0;
  int result = 0;
  char c1, c2;
  int again = 1;
  while (again) {
    c1 = indication[i1];
    c2 = frame[i2];
    if (c1 == '\0') {
      result = 1;
      again = 0;
    } else if (c2 == '\0') {
      result = 0;
      again = 0;
    } else if (c1 != c2) {
      i2 = i2 - i1 + 1;
      i1 = 0;
    } else {
      i1++;
      i2++;
    }
  }
  return result;
}
```