ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<zzzstrlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0x2,%eax
  jmp    L19
L15:
  mov    $0xa,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int zzzstrlen(char *str) {
  if (str[1] == 0)
    return 2;
  else
    return 10;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<zzzstrlen>:
  endbr64
  cmpb   $0x1,0x1(%rdi)
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0xa,%eax
  ret
```

assistant: ```c
int zzzstrlen(char *str) {
  if (str[1] == 0)
    return 2;
  else
    return 10;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zzzstrlen>:
  endbr64
  cmpb   $0x1,0x1(%rdi)
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0xa,%eax
  ret
```

assistant: ```c
int zzzstrlen(char *str) {
  if (str[1] == 0)
    return 2;
  else
    return 10;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zzzstrlen>:
  endbr64
  cmpb   $0x1,0x1(%rdi)
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0xa,%eax
  ret
```

assistant: ```c
int zzzstrlen(char *str) {
  if (str[1] == 0)
    return 2;
  else
    return 10;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GenPrintInstr3Operands>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  cmpl   $0x80,0x10(%rbp)
  jne    L29
  cmpl   $0x0,0x18(%rbp)
  jne    L29
  cmpl   $0x11,-0x4(%rbp)
  je     L44
  cmpl   $0x12,-0x4(%rbp)
  je     L44
L29:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <GenPrintInstr@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <GenPrintOperand@plt>
  mov    $0x0,%eax
  call   <GenPrintOperandSeparator@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <GenPrintOperand@plt>
  mov    $0x0,%eax
  call   <GenPrintOperandSeparator@plt>
  mov    0x18(%rbp),%eax
  mov    %eax,%esi
  mov    0x10(%rbp),%edi
  call   <GenPrintOperand@plt>
  mov    $0x0,%eax
  call   <GenPrintNewLine@plt>
  cmpl   $0x21,-0x4(%rbp)
  je     L5
  cmpl   $0x22,-0x4(%rbp)
  jne    L38
L5:
  mov    $0x0,%eax
  call   <GenNop@plt>
  jmp    L38
L44:
  nop
L38:
  leave
  ret
```

assistant: ```c
void GenPrintInstr3Operands(int instr, int instrval, int operand1, int operand1val, int operand2, int operand2val, int operand3, int operand3val) {
  if (operand3 == 0x80 && operand3val == 0 && (instr == 0x11 || instr == 0x12))
    return;
  GenPrintInstr(instr, instrval);
  GenPrintOperand(operand1, operand1val);
  GenPrintOperandSeparator();
  GenPrintOperand(operand2, operand2val);
  GenPrintOperandSeparator();
  GenPrintOperand(operand3, operand3val);
  GenPrintNewLine();
  if (instr == 0x21 || instr == 0x22)
    GenNop();
}
```
user: Translate the below assembly code into C programming language:

```asm
<GenPrintInstr3Operands>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edx,%r13d
  mov    %ecx,%r14d
  mov    %r8d,%ebp
  mov    %r9d,%r12d
  mov    0x48(%rsp),%r15d
  cmpl   $0x80,0x40(%rsp)
  jne    L45
  test   %r15d,%r15d
  jne    L45
  lea    -0x11(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L28
L45:
  mov    %ebx,%edi
  call   <GenPrintInstr@plt>
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <GenPrintOperand@plt>
  mov    $0x0,%eax
  call   <GenPrintOperandSeparator@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <GenPrintOperand@plt>
  mov    $0x0,%eax
  call   <GenPrintOperandSeparator@plt>
  mov    %r15d,%esi
  mov    0x40(%rsp),%edi
  call   <GenPrintOperand@plt>
  mov    $0x0,%eax
  call   <GenPrintNewLine@plt>
  sub    $0x21,%ebx
  cmp    $0x1,%ebx
  jbe    L22
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    $0x0,%eax
  call   <GenNop@plt>
  jmp    L28
```

assistant: ```c
void GenPrintInstr3Operands(int instr, int instrval, int operand1, int operand1val, int operand2, int operand2val, int operand3, int operand3val) {
  if (operand3 == 0x80 && operand3val == 0 && (instr == 0x11 || instr == 0x12))
    return;
  GenPrintInstr(instr, instrval);
  GenPrintOperand(operand1, operand1val);
  GenPrintOperandSeparator();
  GenPrintOperand(operand2, operand2val);
  GenPrintOperandSeparator();
  GenPrintOperand(operand3, operand3val);
  GenPrintNewLine();
  if (instr == 0x21 || instr == 0x22)
    GenNop();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GenPrintInstr3Operands>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r14d
  mov    0x58(%rsp),%r15d
  cmp    $0x80,%r14d
  jne    L15
  test   %r15d,%r15d
  jne    L15
  lea    -0x11(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L8
L15:
  mov    %ebx,%edi
  mov    %ecx,0xc(%rsp)
  sub    $0x21,%ebx
  call   <GenPrintInstr@plt>
  mov    0xc(%rsp),%esi
  mov    %r13d,%edi
  call   <GenPrintOperand@plt>
  xor    %eax,%eax
  call   <GenPrintOperandSeparator@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <GenPrintOperand@plt>
  xor    %eax,%eax
  call   <GenPrintOperandSeparator@plt>
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <GenPrintOperand@plt>
  xor    %eax,%eax
  call   <GenPrintNewLine@plt>
  cmp    $0x1,%ebx
  jbe    L4
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L4:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <GenNop@plt>
```

assistant: ```c
void GenPrintInstr3Operands(int instr, int instrval, int operand1, int operand1val, int operand2, int operand2val, int operand3, int operand3val) {
  if (operand3 == 0x80 && operand3val == 0 && (instr == 0x11 || instr == 0x12))
    return;
  GenPrintInstr(instr, instrval);
  GenPrintOperand(operand1, operand1val);
  GenPrintOperandSeparator();
  GenPrintOperand(operand2, operand2val);
  GenPrintOperandSeparator();
  GenPrintOperand(operand3, operand3val);
  GenPrintNewLine();
  if (instr == 0x21 || instr == 0x22)
    GenNop();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GenPrintInstr3Operands>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r14d
  mov    0x58(%rsp),%r15d
  cmp    $0x80,%r14d
  jne    L6
  test   %r15d,%r15d
  jne    L6
  lea    -0x11(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L31
L6:
  mov    %ebx,%edi
  mov    %ecx,0xc(%rsp)
  sub    $0x21,%ebx
  call   <GenPrintInstr@plt>
  mov    0xc(%rsp),%esi
  mov    %r13d,%edi
  call   <GenPrintOperand@plt>
  xor    %eax,%eax
  call   <GenPrintOperandSeparator@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <GenPrintOperand@plt>
  xor    %eax,%eax
  call   <GenPrintOperandSeparator@plt>
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <GenPrintOperand@plt>
  xor    %eax,%eax
  call   <GenPrintNewLine@plt>
  cmp    $0x1,%ebx
  jbe    L36
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L36:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <GenNop@plt>
```

assistant: ```c
void GenPrintInstr3Operands(int instr, int instrval, int operand1, int operand1val, int operand2, int operand2val, int operand3, int operand3val) {
  if (operand3 == 0x80 && operand3val == 0 && (instr == 0x11 || instr == 0x12))
    return;
  GenPrintInstr(instr, instrval);
  GenPrintOperand(operand1, operand1val);
  GenPrintOperandSeparator();
  GenPrintOperand(operand2, operand2val);
  GenPrintOperandSeparator();
  GenPrintOperand(operand3, operand3val);
  GenPrintNewLine();
  if (instr == 0x21 || instr == 0x22)
    GenNop();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pdp_invert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
unsigned long pdp_invert(unsigned long l) {
  unsigned short *s = &l;
  return (s[0] << 16) + s[1];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pdp_invert>:
  endbr64
  rol    $0x10,%edi
  movslq %edi,%rax
  ret
```

assistant: ```c
unsigned long pdp_invert(unsigned long l) {
  unsigned short *s = &l;
  return (s[0] << 16) + s[1];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pdp_invert>:
  endbr64
  rol    $0x10,%edi
  movslq %edi,%rax
  ret
```

assistant: ```c
unsigned long pdp_invert(unsigned long l) {
  unsigned short *s = &l;
  return (s[0] << 16) + s[1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<part1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D20(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x14,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L71
L76:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L71:
  cmpl   $0x64,-0x8(%rbp)
  jle    L76
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x64,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L8
L43:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0x13,-0x8(%rbp)
  jg     L43
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x7d0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L18
L36:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x989680,-0x8(%rbp)
  jle    L36
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x989680,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L23
L4:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x7cf,-0x8(%rbp)
  jg     L4
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D20
datatype: byte[4]
name: disassemble_data
arguments: tag: D7
datatype: string
name: disassemble_data
arguments: tag: D5
datatype: string
name: disassemble_data
arguments: tag: D34
datatype: string
name: disassemble_data
arguments: tag: D33
datatype: string

tool: {"D20": [0x00,0x00,0x80,0x3f]}

tool: D7: 
Part 1A --increasing i's-- sum = %e


tool: D5: Part 1A --decreasing i's-- sum = %e


tool: D34: 
Part 1B--increasing i's -- sum = %e


tool: D33: Part 1B -- decreasing i's -- sum = %e


assistant: ```c
void part1() {
  float sum = 0;
  float one = 1.0F;
  int i;
  for (i = 20, sum = 0.0; i <= 100; i++) {
    sum = sum + one / i;
  }
  printf("\nPart 1A --increasing i's-- sum = %e\n", sum);
  for (i = 100, sum = 0.0; i >= 20; i--) {
    sum = sum + one / i;
  }
  printf("Part 1A --decreasing i's-- sum = %e\n", sum);
  for (i = 2000, sum = 0.0; i <= 10000000; i++) {
    sum = sum + one / i;
  }
  printf("\nPart 1B--increasing i's -- sum = %e\n", sum);
  for (i = 10000000, sum = 0.0; i >= 2000; i--) {
    sum = sum + one / i;
  }
  printf("Part 1B -- decreasing i's -- sum = %e\n", sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<part1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%eax
  pxor   %xmm0,%xmm0
  movss  D63(%rip),%xmm3
L11:
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movaps %xmm3,%xmm1
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    $0x65,%eax
  jne    L11
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%eax
  pxor   %xmm0,%xmm0
  movss  D63(%rip),%xmm3
L5:
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movaps %xmm3,%xmm1
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  sub    $0x1,%eax
  cmp    $0x13,%eax
  jne    L5
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x7d0,%eax
  pxor   %xmm0,%xmm0
  movss  D63(%rip),%xmm3
L8:
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movaps %xmm3,%xmm1
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    $0x989681,%eax
  jne    L8
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0x989680,%eax
  pxor   %xmm0,%xmm0
  movss  D63(%rip),%xmm3
L9:
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movaps %xmm3,%xmm1
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  sub    $0x1,%eax
  cmp    $0x7cf,%eax
  jne    L9
  lea    D19(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D63
type_infered: byte[4]
name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D29
type_infered: string
name: disassemble_data
arguments: label: D36
type_infered: string
name: disassemble_data
arguments: label: D19
type_infered: string

tool: {"D63": [0x00,0x00,0x80,0x3f]}

tool: D6: 
Part 1A --increasing i's-- sum = %e


tool: D29: Part 1A --decreasing i's-- sum = %e


tool: D36: 
Part 1B--increasing i's -- sum = %e


tool: D19: Part 1B -- decreasing i's -- sum = %e


assistant: ```c
void part1() {
  float sum = 0;
  float one = 1.0F;
  int i;
  for (i = 20, sum = 0.0; i <= 100; i++) {
    sum = sum + one / i;
  }
  printf("\nPart 1A --increasing i's-- sum = %e\n", sum);
  for (i = 100, sum = 0.0; i >= 20; i--) {
    sum = sum + one / i;
  }
  printf("Part 1A --decreasing i's-- sum = %e\n", sum);
  for (i = 2000, sum = 0.0; i <= 10000000; i++) {
    sum = sum + one / i;
  }
  printf("\nPart 1B--increasing i's -- sum = %e\n", sum);
  for (i = 10000000, sum = 0.0; i >= 2000; i--) {
    sum = sum + one / i;
  }
  printf("Part 1B -- decreasing i's -- sum = %e\n", sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<part1>:
  endbr64
  sub    $0x8,%rsp
  movss  D51(%rip),%xmm1
  mov    $0x14,%eax
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax)
L2:
  pxor   %xmm3,%xmm3
  movaps %xmm1,%xmm2
  cvtsi2ss %eax,%xmm3
  add    $0x1,%eax
  divss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  cmp    $0x65,%eax
  jne    L2
  lea    D79(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%eax
  pxor   %xmm0,%xmm0
  movss  D51(%rip),%xmm1
  nopl   0x0(%rax,%rax,1)
L30:
  pxor   %xmm3,%xmm3
  movaps %xmm1,%xmm2
  cvtsi2ss %eax,%xmm3
  sub    $0x1,%eax
  divss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  cmp    $0x13,%eax
  jne    L30
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x7d0,%eax
  pxor   %xmm0,%xmm0
  movss  D51(%rip),%xmm1
  nopl   0x0(%rax,%rax,1)
L19:
  pxor   %xmm3,%xmm3
  movaps %xmm1,%xmm2
  cvtsi2ss %eax,%xmm3
  add    $0x1,%eax
  divss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  cmp    $0x989681,%eax
  jne    L19
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x989680,%eax
  pxor   %xmm0,%xmm0
  movss  D51(%rip),%xmm1
  nopw   0x0(%rax,%rax,1)
L33:
  pxor   %xmm3,%xmm3
  movaps %xmm1,%xmm2
  cvtsi2ss %eax,%xmm3
  sub    $0x1,%eax
  divss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  cmp    $0x7cf,%eax
  jne    L33
  lea    D43(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D51
data_type: byte[4]
name: retrieve_data
arguments: tag: D79
data_type: string
name: retrieve_data
arguments: tag: D16
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D43
data_type: string

tool: {"D51": [0x00,0x00,0x80,0x3f]}

tool: D79: 
Part 1A --increasing i's-- sum = %e


tool: D16: Part 1A --decreasing i's-- sum = %e


tool: D13: 
Part 1B--increasing i's -- sum = %e


tool: D43: Part 1B -- decreasing i's -- sum = %e


assistant: ```c
void part1() {
  float sum = 0;
  float one = 1.0F;
  int i;
  for (i = 20, sum = 0.0; i <= 100; i++) {
    sum = sum + one / i;
  }
  printf("\nPart 1A --increasing i's-- sum = %e\n", sum);
  for (i = 100, sum = 0.0; i >= 20; i--) {
    sum = sum + one / i;
  }
  printf("Part 1A --decreasing i's-- sum = %e\n", sum);
  for (i = 2000, sum = 0.0; i <= 10000000; i++) {
    sum = sum + one / i;
  }
  printf("\nPart 1B--increasing i's -- sum = %e\n", sum);
  for (i = 10000000, sum = 0.0; i >= 2000; i--) {
    sum = sum + one / i;
  }
  printf("Part 1B -- decreasing i's -- sum = %e\n", sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L4:
  mov    $0x0,%eax
  call   <must_be_true_sample@plt>
  addl   $0x1,-0x8(%rbp)
L6:
  cmpl   $0x3d08ff,-0x8(%rbp)
  jle    L4
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L23:
  mov    $0x0,%eax
  call   <must_be_false_sample@plt>
  addl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x3d08ff,-0x4(%rbp)
  jle    L23
  mov    $0x0,%eax
  call   <issues@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  for (int i = 0; i < 4000000; i++)
    must_be_true_sample();
  for (int i = 0; i < 4000000; i++)
    must_be_false_sample();
  issues();
  return (EXIT_SUCCESS);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3d0900,%ebx
L9:
  mov    $0x0,%eax
  call   <must_be_true_sample@plt>
  sub    $0x1,%ebx
  jne    L9
  mov    $0x3d0900,%ebx
L5:
  mov    $0x0,%eax
  call   <must_be_false_sample@plt>
  sub    $0x1,%ebx
  jne    L5
  mov    $0x0,%eax
  call   <issues@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  for (int i = 0; i < 4000000; i++)
    must_be_true_sample();
  for (int i = 0; i < 4000000; i++)
    must_be_false_sample();
  issues();
  return (EXIT_SUCCESS);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3d0900,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <must_be_true_sample@plt>
  sub    $0x1,%ebx
  jne    L5
  mov    $0x3d0900,%ebx
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  call   <must_be_false_sample@plt>
  sub    $0x1,%ebx
  jne    L2
  xor    %eax,%eax
  call   <issues@plt>
  mov    D6(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  for (int i = 0; i < 4000000; i++)
    must_be_true_sample();
  for (int i = 0; i < 4000000; i++)
    must_be_false_sample();
  issues();
  return (EXIT_SUCCESS);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3d0900,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  call   <must_be_true_sample@plt>
  sub    $0x1,%ebx
  jne    L18
  mov    $0x3d0900,%ebx
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  call   <must_be_false_sample@plt>
  sub    $0x1,%ebx
  jne    L11
  xor    %eax,%eax
  call   <issues@plt>
  mov    D3(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  for (int i = 0; i < 4000000; i++)
    must_be_true_sample();
  for (int i = 0; i < 4000000; i++)
    must_be_false_sample();
  issues();
  return (EXIT_SUCCESS);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L6:
  movl   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L27
L36:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L64
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  jmp    L4
L64:
  cmpl   $0x0,-0x10(%rbp)
  jle    L40
  movl   $0x1,-0x4(%rbp)
  jmp    L61
L29:
  addl   $0x1,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L61
  movl   $0x0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L4
L61:
  mov    -0x10(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L29
  jmp    L39
L40:
  movl   $0x1,-0x8(%rbp)
L39:
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L134
  cmpl   $0x1,-0x8(%rbp)
  je     L36
L134:
  addl   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L4
  cmpl   $0x0,-0x8(%rbp)
  je     L6
L4:
  pop    %rbp
  ret
```

assistant: ```c
int min(int inp[], int n) {
  int i, j, state;
  j = 0;
  state = 0;
  for (i = 0; i <= n && state == 0; ++i) {
    state = 1;
    for (j = i + 1; j <= n && state == 1; ++j) {
      if (inp[0] < inp[j]) {
        state = 0;
        return inp[0];
      } else if (i > 0) {
        int k;
        k = 1;
        while (inp[i - k] > inp[i]) {
          ++k;
          if (inp[i] < inp[j]) {
            state = 0;
            return inp[i];
          }
        }
      } else {
        state = 1;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<min>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    (%rdi),%edx
  mov    $0x1,%eax
L16:
  cmp    (%rdi,%rax,4),%edx
  jl     L15
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L16
L15:
  mov    %edx,%eax
  ret
```

assistant: ```c
int min(int inp[], int n) {
  int i, j, state;
  j = 0;
  state = 0;
  for (i = 0; i <= n && state == 0; ++i) {
    state = 1;
    for (j = i + 1; j <= n && state == 1; ++j) {
      if (inp[0] < inp[j]) {
        state = 0;
        return inp[0];
      } else if (i > 0) {
        int k;
        k = 1;
        while (inp[i - k] > inp[i]) {
          ++k;
          if (inp[i] < inp[j]) {
            state = 0;
            return inp[i];
          }
        }
      } else {
        state = 1;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<min>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    (%rdi),%r8d
  mov    $0x1,%eax
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rax
  cmp    %eax,%esi
  jl     L6
L13:
  cmp    (%rdi,%rax,4),%r8d
  jge    L37
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int min(int inp[], int n) {
  int i, j, state;
  j = 0;
  state = 0;
  for (i = 0; i <= n && state == 0; ++i) {
    state = 1;
    for (j = i + 1; j <= n && state == 1; ++j) {
      if (inp[0] < inp[j]) {
        state = 0;
        return inp[0];
      } else if (i > 0) {
        int k;
        k = 1;
        while (inp[i - k] > inp[i]) {
          ++k;
          if (inp[i] < inp[j]) {
            state = 0;
            return inp[i];
          }
        }
      } else {
        state = 1;
      }
    }
  }
}
```