ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L20
  nopl   0x0(%rax)
L22:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L20:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <retab@plt>
  test   %rax,%rax
  jg     L22
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D1: %s

assistant: ```c
int main() {
  char line[1000];
  while (retab(line, 1000) > 0)
    printf("%s", line);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1fca08,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x1fca055,%edi
  call   <sqrt@plt>
  mov    $0x2,%edx
  jmp    L17
L64:
  add    %edx,%ecx
  cmp    $0x1fca055,%ecx
  jg     L85
L77:
  mov    %ecx,%esi
  sar    $0x6,%esi
  movslq %esi,%rsi
  lea    (%rbx,%rsi,4),%rdi
  mov    (%rdi),%esi
  mov    %ecx,%r8d
  and    $0x3f,%r8d
  bt     %ecx,%esi
  jb     L64
  bts    %r8d,%esi
  mov    %esi,(%rdi)
  jmp    L64
L85:
  add    $0x1,%edx
  cmp    %edx,%eax
  jl     L103
  mov    %edx,%ecx
  sar    $0x6,%ecx
  movslq %ecx,%rcx
  mov    (%rbx,%rcx,4),%ecx
  bt     %edx,%ecx
  jb     L85
L103:
  cmp    $0xfe502a,%edx
  jg     L57
L17:
  lea    (%rdx,%rdx,1),%ecx
  cmp    $0x1fca055,%ecx
  jle    L77
  jmp    L85
L57:
  testb  $0x20,0x1fca06(%rbx)
  je     L70
  mov    $0x1fca054,%esi
L123:
  mov    %esi,%eax
  sar    $0x6,%eax
  cltq
  mov    (%rbx,%rax,4),%eax
  bt     %esi,%eax
  jae    L97
  sub    $0x1,%esi
  jne    L123
  jmp    L18
L70:
  mov    $0x1fca055,%esi
L97:
  lea    D9(%rip),%rdi
  call   <printf@plt>
L18:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d


assistant: ```c
int main() {
  int limit = 33333333;
  size_t primes_size = ((limit >> 6) + 1) * sizeof(uint64_t);
  uint64_t *primes = (uint64_t *)malloc(primes_size);
  int64_t p = 2, sqrt_limit = (int64_t)sqrt(limit);
  while (p <= limit >> 1) {
    for (int64_t n = 2 * p; n <= limit; n += p)
      if (!(primes[n >> 6] & 1 << (n & 0x3f)))
        (primes[n >> 6] |= 1 << (n & 0x3f));
    while (++p <= sqrt_limit && (primes[p >> 6] & 1 << (p & 0x3f)))
      ;
  }
  for (int i = limit; i > 0; i--) {
    if (!(primes[i >> 6] & 1 << (i & 0x3f))) {
      printf("%d\n", i);
      return 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1fca08,%edi
  call   <malloc@plt>
  mov    $0x1fca055,%edi
  mov    %rax,%rbx
  call   <sqrt@plt>
  mov    $0x2,%edx
  nopl   0x0(%rax)
L19:
  lea    (%rdx,%rdx,1),%ecx
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %ecx,%esi
  mov    %ecx,%r8d
  sar    $0x6,%esi
  and    $0x3f,%r8d
  movslq %esi,%rsi
  lea    (%rbx,%rsi,4),%rdi
  mov    (%rdi),%esi
  bt     %ecx,%esi
  jb     L17
  bts    %r8d,%esi
  mov    %esi,(%rdi)
L17:
  add    %edx,%ecx
  cmp    $0x1fca055,%ecx
  jle    L30
  add    $0x1,%edx
  cmp    %edx,%eax
  jl     L6
  nopl   0x0(%rax)
L35:
  mov    %edx,%ecx
  sar    $0x6,%ecx
  movslq %ecx,%rcx
  mov    (%rbx,%rcx,4),%ecx
  bt     %edx,%ecx
  jae    L6
  add    $0x1,%edx
  cmp    %edx,%eax
  jge    L35
L6:
  cmp    $0xfe502a,%edx
  jle    L19
  mov    $0x1fca055,%esi
  jmp    L28
  xchg   %ax,%ax
L59:
  sub    $0x1,%esi
  je     L67
L28:
  mov    %esi,%eax
  sar    $0x6,%eax
  cltq
  mov    (%rbx,%rax,4),%eax
  bt     %esi,%eax
  jb     L59
  lea    D2(%rip),%rdi
  call   <printf@plt>
L67:
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main() {
  int limit = 33333333;
  size_t primes_size = ((limit >> 6) + 1) * sizeof(uint64_t);
  uint64_t *primes = (uint64_t *)malloc(primes_size);
  int64_t p = 2, sqrt_limit = (int64_t)sqrt(limit);
  while (p <= limit >> 1) {
    for (int64_t n = 2 * p; n <= limit; n += p)
      if (!(primes[n >> 6] & 1 << (n & 0x3f)))
        (primes[n >> 6] |= 1 << (n & 0x3f));
    while (++p <= sqrt_limit && (primes[p >> 6] & 1 << (p & 0x3f)))
      ;
  }
  for (int i = limit; i > 0; i--) {
    if (!(primes[i >> 6] & 1 << (i & 0x3f))) {
      printf("%d\n", i);
      return 0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1fca08,%edi
  call   <malloc@plt>
  mov    $0x1fca055,%edi
  mov    %rax,%rbx
  call   <sqrt@plt>
  mov    $0x2,%edx
  nopl   0x0(%rax)
L63:
  lea    (%rdx,%rdx,1),%ecx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ecx,%esi
  mov    %ecx,%r8d
  sar    $0x6,%esi
  and    $0x3f,%r8d
  movslq %esi,%rsi
  lea    (%rbx,%rsi,4),%rdi
  mov    (%rdi),%esi
  bt     %ecx,%esi
  jb     L84
  bts    %r8d,%esi
  mov    %esi,(%rdi)
L84:
  add    %edx,%ecx
  cmp    $0x1fca055,%ecx
  jle    L4
  add    $0x1,%edx
  cmp    %edx,%eax
  jl     L73
  nopl   0x0(%rax)
L56:
  mov    %edx,%ecx
  sar    $0x6,%ecx
  movslq %ecx,%rcx
  mov    (%rbx,%rcx,4),%ecx
  bt     %edx,%ecx
  jae    L73
  add    $0x1,%edx
  cmp    %edx,%eax
  jge    L56
L73:
  cmp    $0xfe502a,%edx
  jle    L63
  mov    $0x1fca055,%esi
  jmp    L65
  xchg   %ax,%ax
L21:
  sub    $0x1,%esi
  je     L46
L65:
  mov    %esi,%eax
  sar    $0x6,%eax
  cltq
  mov    (%rbx,%rax,4),%eax
  bt     %esi,%eax
  jb     L21
  lea    D8(%rip),%rdi
  call   <printf@plt>
L46:
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main() {
  int limit = 33333333;
  size_t primes_size = ((limit >> 6) + 1) * sizeof(uint64_t);
  uint64_t *primes = (uint64_t *)malloc(primes_size);
  int64_t p = 2, sqrt_limit = (int64_t)sqrt(limit);
  while (p <= limit >> 1) {
    for (int64_t n = 2 * p; n <= limit; n += p)
      if (!(primes[n >> 6] & 1 << (n & 0x3f)))
        (primes[n >> 6] |= 1 << (n & 0x3f));
    while (++p <= sqrt_limit && (primes[p >> 6] & 1 << (p & 0x3f)))
      ;
  }
  for (int i = limit; i > 0; i--) {
    if (!(primes[i >> 6] & 1 << (i & 0x3f))) {
      printf("%d\n", i);
      return 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L113
L77:
  addq   $0x1,-0x28(%rbp)
L11:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L204
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L204
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L204
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L157
L204:
  addq   $0x1,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L77
L157:
  nop
L213:
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L213
  jmp    L145
L110:
  addq   $0x1,-0x18(%rbp)
L145:
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L43
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L110
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L110
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L110
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L110
L43:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L142
  mov    $0x0,%eax
  jmp    L113
L142:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L196
L78:
  addq   $0x1,-0x28(%rbp)
L196:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L78
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L78
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L78
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L78
  jmp    L203
L152:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L203:
  subq   $0x1,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L152
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L113:
  leave
  ret
```

assistant: ```c
char *ft_strtrim(char const *s) {
  unsigned long ct;
  char *cp;
  char *str;
  ct = 0;
  cp = (char *)s;
  if (s == NULL)
    return (NULL);
  while ((*s == 10 || *s == 9 || *s == 44 || *s == 32) && ++ct)
    s++;
  while (*++s)
    ;
  while (*--s && (*s == 10 || *s == 9 || *s == 44 || *s == 32))
    ct++;
  s = cp;
  ct = ft_strlen(s) - ct;
  if (!(str = (char *)malloc(++ct * sizeof(*str))))
    return (NULL);
  cp = str;
  while ((*s == 10 || *s == 9 || *s == 44 || *s == 32))
    s++;
  while (--ct)
    *str++ = *s++;
  *str = 0x00;
  return (cp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strtrim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L224
  movzbl (%rdi),%ecx
  cmp    $0x2c,%cl
  ja     L241
  movabs $0x100100000600,%rbp
  shr    %cl,%rbp
  and    $0x1,%ebp
  je     L134
  lea    -0x1(%rdi),%rsi
  mov    %rdi,%rax
  mov    $0x1,%ecx
  sub    %rdi,%rcx
  movabs $0x100100000600,%rdi
  jmp    L9
L41:
  bt     %rdx,%rdi
  jae    L206
  cmp    %rsi,%rax
  je     L29
L9:
  lea    (%rax,%rcx,1),%rbp
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x2c,%dl
  jbe    L41
L206:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L206
  movzbl -0x1(%rax),%eax
  movabs $0x100100000600,%rcx
  test   %al,%al
  jne    L87
  jmp    L21
L29:
  mov    %rsi,%rax
  mov    $0x0,%ebp
  jmp    L206
L241:
  mov    %rdi,%rax
  mov    $0x0,%ebp
  jmp    L206
L134:
  mov    %rdi,%rax
  jmp    L206
L200:
  add    $0x1,%rbp
  sub    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L21
L87:
  cmp    $0x2c,%al
  ja     L21
  bt     %rax,%rcx
  jb     L200
L21:
  mov    %rbx,%rdi
  call   <ft_strlen@plt>
  lea    0x1(%rax),%r12
  sub    %rbp,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L220
  movzbl (%rbx),%edx
  cmp    $0x2c,%dl
  ja     L207
  movabs $0x100100000600,%rcx
  bt     %rdx,%rcx
  jb     L7
  jmp    L207
L27:
  bt     %rdx,%rcx
  jae    L207
L7:
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  cmp    $0x2c,%dl
  jbe    L27
L207:
  mov    %r12,%r9
  sub    $0x1,%r9
  je     L189
  lea    -0x1(%rax,%r12,1),%rdi
  mov    %rax,%rdx
  sub    %rax,%rbx
L228:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  movzbl -0x1(%rdx,%rbx,1),%esi
  mov    %sil,(%rcx)
  cmp    %rdi,%rdx
  jne    L228
  add    %r9,%rax
L189:
  movb   $0x0,(%rax)
L184:
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L224:
  mov    %rdi,%r8
  jmp    L184
L220:
  mov    $0x0,%r8d
  jmp    L184
```

assistant: ```c
char *ft_strtrim(char const *s) {
  unsigned long ct;
  char *cp;
  char *str;
  ct = 0;
  cp = (char *)s;
  if (s == NULL)
    return (NULL);
  while ((*s == 10 || *s == 9 || *s == 44 || *s == 32) && ++ct)
    s++;
  while (*++s)
    ;
  while (*--s && (*s == 10 || *s == 9 || *s == 44 || *s == 32))
    ct++;
  s = cp;
  ct = ft_strlen(s) - ct;
  if (!(str = (char *)malloc(++ct * sizeof(*str))))
    return (NULL);
  cp = str;
  while ((*s == 10 || *s == 9 || *s == 44 || *s == 32))
    s++;
  while (--ct)
    *str++ = *s++;
  *str = 0x00;
  return (cp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strtrim>:
  endbr64
  test   %rdi,%rdi
  je     L117
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  mov    %rdi,%rbx
  cmp    $0x2c,%al
  ja     L141
  movabs $0xffffeffefffff9ff,%rdi
  bt     %rax,%rdi
  jb     L141
  mov    $0x1,%ecx
  lea    -0x1(%rbx),%rsi
  mov    %rbx,%rax
  sub    %rbx,%rcx
  nopw   0x0(%rax,%rax,1)
L13:
  lea    (%rax,%rcx,1),%rbp
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x2c,%dl
  ja     L171
  bt     %rdx,%rdi
  jb     L171
  cmp    %rax,%rsi
  jne    L13
L114:
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L171:
  mov    %rax,%rdx
  lea    0x1(%rax),%rax
  cmpb   $0x0,0x1(%rdx)
  jne    L171
  movabs $0x100100000600,%rcx
  movzbl -0x1(%rax),%eax
  test   %al,%al
  je     L88
  nop
L159:
  cmp    $0x2c,%al
  ja     L88
  bt     %rax,%rcx
  jb     L147
L88:
  mov    %rbx,%rdi
  call   <ft_strlen@plt>
  lea    0x1(%rax),%r12
  sub    %rbp,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L174
  movzbl (%rbx),%edx
  cmp    $0x2c,%dl
  ja     L121
  movabs $0xffffeffefffff9ff,%rcx
  nopl   0x0(%rax,%rax,1)
L19:
  bt     %rdx,%rcx
  jb     L121
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    $0x2c,%dl
  jbe    L19
L121:
  mov    %r12,%r9
  sub    $0x1,%r9
  je     L115
  lea    -0x1(%rax,%r12,1),%rdi
  mov    %rax,%rdx
  sub    %rax,%rbx
  nop
L167:
  mov    %rdx,%rcx
  movzbl (%rdx,%rbx,1),%esi
  add    $0x1,%rdx
  mov    %sil,(%rcx)
  cmp    %rdi,%rdx
  jne    L167
  add    %r9,%rax
L115:
  movb   $0x0,(%rax)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L141:
  mov    %rbx,%rax
  jmp    L114
L147:
  movzbl -0x1(%rdx),%eax
  sub    $0x1,%rdx
  add    $0x1,%rbp
  test   %al,%al
  jne    L159
  jmp    L88
L174:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
L117:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strtrim(char const *s) {
  unsigned long ct;
  char *cp;
  char *str;
  ct = 0;
  cp = (char *)s;
  if (s == NULL)
    return (NULL);
  while ((*s == 10 || *s == 9 || *s == 44 || *s == 32) && ++ct)
    s++;
  while (*++s)
    ;
  while (*--s && (*s == 10 || *s == 9 || *s == 44 || *s == 32))
    ct++;
  s = cp;
  ct = ft_strlen(s) - ct;
  if (!(str = (char *)malloc(++ct * sizeof(*str))))
    return (NULL);
  cp = str;
  while ((*s == 10 || *s == 9 || *s == 44 || *s == 32))
    s++;
  while (--ct)
    *str++ = *s++;
  *str = 0x00;
  return (cp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L32
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L15
  mov    -0x8(%rbp),%rax
  jmp    L22
L15:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    $0x0,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0') {
    if (*s == c)
      return (char *)s;
    s++;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L18
L1:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L26
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L1
  mov    $0x0,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
L26:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0') {
    if (*s == c)
      return (char *)s;
    s++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strchr>:
  endbr64
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L29:
  cmp    %esi,%edx
  je     L1
  add    $0x1,%rdi
L7:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L29
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0') {
    if (*s == c)
      return (char *)s;
    s++;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strchr>:
  endbr64
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L12:
  cmp    %esi,%edx
  je     L6
  add    $0x1,%rdi
L11:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L12
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0') {
    if (*s == c)
      return (char *)s;
    s++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<goo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *goo() {
  static int xyz;
  return &xyz;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<goo>:
  endbr64
  lea    D4(%rip),%rax
  ret
```

assistant: ```c
int *goo() {
  static int xyz;
  return &xyz;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<goo>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

assistant: ```c
int *goo() {
  static int xyz;
  return &xyz;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<goo>:
  endbr64
  lea    D4(%rip),%rax
  ret
```

assistant: ```c
int *goo() {
  static int xyz;
  return &xyz;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_lockname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D5(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  cmp    $0xff,%eax
  jle    L8
  mov    $0xffffffff,%eax
  jmp    L25
L8:
  mov    $0x0,%eax
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: /var/lock/LCK..%s

assistant: ```c
int get_lockname(char *dev, char *buf) {
  char *tmp = strrchr(dev, '/');
  if (tmp)
    dev = tmp + 1;
  if (snprintf(buf, 256, "/var/lock/LCK..%s", dev) >= 256)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_lockname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    %rbx,%rcx
  lea    D2(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cmp    $0xff,%eax
  setg   %al
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: /var/lock/LCK..%s

assistant: ```c
int get_lockname(char *dev, char *buf) {
  char *tmp = strrchr(dev, '/');
  if (tmp)
    dev = tmp + 1;
  if (snprintf(buf, 256, "/var/lock/LCK..%s", dev) >= 256)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_lockname>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2f,%esi
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    %rbp,%rdi
  mov    $0x100,%esi
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  lea    D8(%rip),%rdx
  mov    %r12,%rcx
  call   <snprintf@plt>
  cmp    $0xff,%eax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: /var/lock/LCK..%s

assistant: ```c
int get_lockname(char *dev, char *buf) {
  char *tmp = strrchr(dev, '/');
  if (tmp)
    dev = tmp + 1;
  if (snprintf(buf, 256, "/var/lock/LCK..%s", dev) >= 256)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_lockname>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2f,%esi
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    %rbp,%rdi
  mov    $0x100,%esi
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  lea    D8(%rip),%rdx
  mov    %r12,%rcx
  call   <snprintf@plt>
  cmp    $0xff,%eax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: /var/lock/LCK..%s

assistant: ```c
int get_lockname(char *dev, char *buf) {
  char *tmp = strrchr(dev, '/');
  if (tmp)
    dev = tmp + 1;
  if (snprintf(buf, 256, "/var/lock/LCK..%s", dev) >= 256)
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: catdoc - exctract text from MS-Word files and catenate it to stdout
Copyright (c) by Victor B. Wagner, 1996
Usage catdoc [-ast] files ...
	-a - converts non-standard printable chars into readable form (default)
	-t - converts them into TeX control sequences
	-s - exits with code 1 if MSWordDoc signature not found before
		first printable paragraph

All options affects only files, specified AFTER them


assistant: ```c
void help(void) {
  printf("catdoc - exctract text from MS-Word files and catenate it to stdout\n"
         "Copyright (c) by Victor B. Wagner, 1996\n"
         "Usage catdoc [-ast] files ...\n"
         "\t-a - converts non-standard printable chars into readable form (default)\n"
         "\t-t - converts them into TeX control sequences\n"
         "\t-s - exits with code 1 if MSWordDoc signature not found before\n"
         "\t\tfirst printable paragraph\n\n"
         "All options affects only files, specified AFTER them\n");
  exit(2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: catdoc - exctract text from MS-Word files and catenate it to stdout
Copyright (c) by Victor B. Wagner, 1996
Usage catdoc [-ast] files ...
	-a - converts non-standard printable chars into readable form (default)
	-t - converts them into TeX control sequences
	-s - exits with code 1 if MSWordDoc signature not found before
		first printable paragraph

All options affects only files, specified AFTER them


assistant: ```c
void help(void) {
  printf("catdoc - exctract text from MS-Word files and catenate it to stdout\n"
         "Copyright (c) by Victor B. Wagner, 1996\n"
         "Usage catdoc [-ast] files ...\n"
         "\t-a - converts non-standard printable chars into readable form (default)\n"
         "\t-t - converts them into TeX control sequences\n"
         "\t-s - exits with code 1 if MSWordDoc signature not found before\n"
         "\t\tfirst printable paragraph\n\n"
         "All options affects only files, specified AFTER them\n");
  exit(2);
}
```