ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sc_check>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  call   <load_4@plt>
  mov    %eax,%r15d
  lea    0x4(%rbx),%rdi
  call   <load_4@plt>
  mov    %eax,%r14d
  lea    0x8(%rbx),%rdi
  call   <load_4@plt>
  mov    %eax,0x4(%rsp)
  lea    0xc(%rbx),%rdi
  call   <load_4@plt>
  mov    %eax,0x8(%rsp)
  lea    0x10(%rbx),%rdi
  call   <load_4@plt>
  mov    %eax,%r13d
  lea    0x14(%rbx),%rdi
  call   <load_4@plt>
  mov    %eax,%r12d
  lea    0x18(%rbx),%rdi
  call   <load_4@plt>
  mov    %eax,%ebp
  lea    0x1c(%rbx),%rdi
  call   <load_4@plt>
  mov    %eax,0xc(%rsp)
  mov    $0x5cf5d3ec,%edi
  sub    %r15d,%edi
  call   <signum@plt>
  mov    %eax,%ebx
  mov    $0x5812631a,%edi
  sub    %r14d,%edi
  call   <signum@plt>
  lea    (%rbx,%rax,2),%ebx
  mov    $0xa2f79cd6,%edi
  sub    0x4(%rsp),%edi
  call   <signum@plt>
  lea    (%rbx,%rax,4),%ebx
  mov    $0x14def9de,%edi
  sub    0x8(%rsp),%edi
  call   <signum@plt>
  lea    (%rbx,%rax,8),%ebx
  mov    %r13d,%edi
  neg    %edi
  call   <signum@plt>
  shl    $0x4,%eax
  add    %eax,%ebx
  mov    %r12d,%edi
  neg    %edi
  call   <signum@plt>
  shl    $0x5,%eax
  add    %eax,%ebx
  mov    %ebp,%edi
  neg    %edi
  call   <signum@plt>
  shl    $0x6,%eax
  add    %eax,%ebx
  mov    $0x10000000,%edi
  sub    0xc(%rsp),%edi
  call   <signum@plt>
  shl    $0x7,%eax
  add    %ebx,%eax
  sar    $0x8,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int sc_check(const unsigned char *s) {
  int64_t s0 = load_4(s);
  int64_t s1 = load_4(s + 4);
  int64_t s2 = load_4(s + 8);
  int64_t s3 = load_4(s + 12);
  int64_t s4 = load_4(s + 16);
  int64_t s5 = load_4(s + 20);
  int64_t s6 = load_4(s + 24);
  int64_t s7 = load_4(s + 28);
  return (signum(1559614444 - s0) + (signum(1477600026 - s1) << 1) + (signum(2734136534 - s2) << 2) + (signum(350157278 - s3) << 3) + (signum(-s4) << 4) + (signum(-s5) << 5) + (signum(-s6) << 6) + (signum(268435456 - s7) << 7)) >> 8;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sc_check>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <load_4@plt>
  lea    0x4(%rbx),%rdi
  mov    %eax,%r13d
  call   <load_4@plt>
  lea    0x8(%rbx),%rdi
  mov    %eax,%r12d
  call   <load_4@plt>
  lea    0xc(%rbx),%rdi
  mov    %eax,%ebp
  call   <load_4@plt>
  lea    0x10(%rbx),%rdi
  mov    %eax,%r15d
  call   <load_4@plt>
  lea    0x14(%rbx),%rdi
  mov    %eax,0x4(%rsp)
  call   <load_4@plt>
  lea    0x18(%rbx),%rdi
  mov    %eax,0x8(%rsp)
  call   <load_4@plt>
  lea    0x1c(%rbx),%rdi
  mov    %eax,0xc(%rsp)
  call   <load_4@plt>
  mov    $0x5cf5d3ec,%edi
  sub    %r13d,%edi
  mov    %eax,%r14d
  call   <signum@plt>
  mov    $0x5812631a,%edi
  sub    %r12d,%edi
  mov    %eax,%ebx
  call   <signum@plt>
  mov    $0xa2f79cd6,%edi
  sub    %ebp,%edi
  lea    (%rbx,%rax,2),%ebx
  call   <signum@plt>
  mov    $0x14def9de,%edi
  sub    %r15d,%edi
  lea    (%rbx,%rax,4),%ebx
  call   <signum@plt>
  mov    0x4(%rsp),%edi
  lea    (%rbx,%rax,8),%ebx
  neg    %edi
  call   <signum@plt>
  mov    0x8(%rsp),%edi
  shl    $0x4,%eax
  neg    %edi
  add    %eax,%ebx
  call   <signum@plt>
  mov    0xc(%rsp),%edi
  shl    $0x5,%eax
  neg    %edi
  add    %eax,%ebx
  call   <signum@plt>
  mov    $0x10000000,%edi
  shl    $0x6,%eax
  sub    %r14d,%edi
  add    %eax,%ebx
  call   <signum@plt>
  shl    $0x7,%eax
  add    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  sar    $0x8,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int sc_check(const unsigned char *s) {
  int64_t s0 = load_4(s);
  int64_t s1 = load_4(s + 4);
  int64_t s2 = load_4(s + 8);
  int64_t s3 = load_4(s + 12);
  int64_t s4 = load_4(s + 16);
  int64_t s5 = load_4(s + 20);
  int64_t s6 = load_4(s + 24);
  int64_t s7 = load_4(s + 28);
  return (signum(1559614444 - s0) + (signum(1477600026 - s1) << 1) + (signum(2734136534 - s2) << 2) + (signum(350157278 - s3) << 3) + (signum(-s4) << 4) + (signum(-s5) << 5) + (signum(-s6) << 6) + (signum(268435456 - s7) << 7)) >> 8;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sc_check>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <load_4@plt>
  lea    0x4(%rbx),%rdi
  mov    %eax,%r13d
  call   <load_4@plt>
  lea    0x8(%rbx),%rdi
  mov    %eax,%r12d
  call   <load_4@plt>
  lea    0xc(%rbx),%rdi
  mov    %eax,%ebp
  call   <load_4@plt>
  lea    0x10(%rbx),%rdi
  mov    %eax,%r15d
  call   <load_4@plt>
  lea    0x14(%rbx),%rdi
  mov    %eax,0x4(%rsp)
  call   <load_4@plt>
  lea    0x18(%rbx),%rdi
  mov    %eax,0x8(%rsp)
  call   <load_4@plt>
  lea    0x1c(%rbx),%rdi
  mov    %eax,0xc(%rsp)
  call   <load_4@plt>
  mov    $0x5cf5d3ec,%edi
  sub    %r13d,%edi
  mov    %eax,%r14d
  call   <signum@plt>
  mov    $0x5812631a,%edi
  sub    %r12d,%edi
  mov    %eax,%ebx
  call   <signum@plt>
  mov    $0xa2f79cd6,%edi
  sub    %ebp,%edi
  lea    (%rbx,%rax,2),%ebx
  call   <signum@plt>
  mov    $0x14def9de,%edi
  sub    %r15d,%edi
  lea    (%rbx,%rax,4),%ebx
  call   <signum@plt>
  mov    0x4(%rsp),%edi
  lea    (%rbx,%rax,8),%ebx
  neg    %edi
  call   <signum@plt>
  mov    0x8(%rsp),%edi
  shl    $0x4,%eax
  neg    %edi
  add    %eax,%ebx
  call   <signum@plt>
  mov    0xc(%rsp),%edi
  shl    $0x5,%eax
  neg    %edi
  add    %eax,%ebx
  call   <signum@plt>
  mov    $0x10000000,%edi
  shl    $0x6,%eax
  sub    %r14d,%edi
  add    %eax,%ebx
  call   <signum@plt>
  shl    $0x7,%eax
  add    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  sar    $0x8,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int sc_check(const unsigned char *s) {
  int64_t s0 = load_4(s);
  int64_t s1 = load_4(s + 4);
  int64_t s2 = load_4(s + 8);
  int64_t s3 = load_4(s + 12);
  int64_t s4 = load_4(s + 16);
  int64_t s5 = load_4(s + 20);
  int64_t s6 = load_4(s + 24);
  int64_t s7 = load_4(s + 28);
  return (signum(1559614444 - s0) + (signum(1477600026 - s1) << 1) + (signum(2734136534 - s2) << 2) + (signum(350157278 - s3) << 3) + (signum(-s4) << 4) + (signum(-s5) << 5) + (signum(-s6) << 6) + (signum(268435456 - s7) << 7)) >> 8;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wl_get_country>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x4,%ecx
  mov    $0x53,%esi
  mov    %rax,%rdi
  call   <wl_ioctl@plt>
  test   %eax,%eax
  jne    L29
  lea    -0xc(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L56
  mov    -0x20(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L41
L56:
  lea    -0xc(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L30
  mov    -0x20(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L41
L30:
  lea    -0xc(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L41:
  mov    $0x0,%eax
  jmp    L49
L29:
  mov    $0xffffffff,%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string
name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D21: IL0

tool: D9: 00

tool: D15: YU

tool: D1: RS

assistant: ```c
int wl_get_country(const char *ifname, char *buf) {
  char ccode[4];
  if (!wl_ioctl(ifname, 83, ccode, 4)) {
    if (!strcmp(ccode, "IL0"))
      sprintf(buf, "00");
    else if (!strcmp(ccode, "YU"))
      sprintf(buf, "RS");
    else
      memcpy(buf, ccode, 2);
    return 0;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wl_get_country>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    $0x4,%ecx
  mov    $0x53,%esi
  call   <wl_ioctl@plt>
  test   %eax,%eax
  jne    L58
  mov    %eax,%ebp
  lea    0x4(%rsp),%rdi
  lea    D4(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L21
  lea    0x4(%rsp),%rdi
  lea    D6(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L12
  lea    D17(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  lea    D34(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  jmp    L4
L12:
  lea    0x4(%rsp),%rsi
  mov    $0x2,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %ebp,%ebx
  jmp    L4
L58:
  mov    $0xffffffff,%ebx
  jmp    L4
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string
name: extract_symbolic_data
arguments: data_tag: D34
type: string

tool: D4: IL0

tool: D6: YU

tool: D17: RS

tool: D34: 00

assistant: ```c
int wl_get_country(const char *ifname, char *buf) {
  char ccode[4];
  if (!wl_ioctl(ifname, 83, ccode, 4)) {
    if (!strcmp(ccode, "IL0"))
      sprintf(buf, "00");
    else if (!strcmp(ccode, "YU"))
      sprintf(buf, "RS");
    else
      memcpy(buf, ccode, 2);
    return 0;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wl_get_country>:
  endbr64
  push   %r13
  mov    $0x4,%ecx
  mov    %rsi,%r13
  mov    $0x53,%esi
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  call   <wl_ioctl@plt>
  test   %eax,%eax
  jne    L15
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L63
  cmpw   $0x5559,0x4(%rsp)
  je     L11
L38:
  mov    $0x2,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %r12d,%r12d
  call   <memcpy@plt>
L75:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L11:
  cmpb   $0x0,0x6(%rsp)
  jne    L38
  lea    D22(%rip),%rsi
  mov    %r13,%rdi
  xor    %r12d,%r12d
  call   <sprintf@plt>
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L63:
  lea    D17(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  jmp    L75
  nopl   0x0(%rax)
L15:
  mov    $0xffffffff,%r12d
  jmp    L75
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D22
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string

tool: D27: IL0

tool: D22: RS

tool: D17: 00

assistant: ```c
int wl_get_country(const char *ifname, char *buf) {
  char ccode[4];
  if (!wl_ioctl(ifname, 83, ccode, 4)) {
    if (!strcmp(ccode, "IL0"))
      sprintf(buf, "00");
    else if (!strcmp(ccode, "YU"))
      sprintf(buf, "RS");
    else
      memcpy(buf, ccode, 2);
    return 0;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wl_get_country>:
  endbr64
  push   %r13
  mov    $0x4,%ecx
  mov    %rsi,%r13
  mov    $0x53,%esi
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  call   <wl_ioctl@plt>
  test   %eax,%eax
  jne    L35
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L55
  cmpw   $0x5559,0x4(%rsp)
  je     L19
L58:
  mov    $0x2,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %r12d,%r12d
  call   <memcpy@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L19:
  cmpb   $0x0,0x6(%rsp)
  jne    L58
  lea    D18(%rip),%rsi
  mov    %r13,%rdi
  xor    %r12d,%r12d
  call   <sprintf@plt>
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L55:
  lea    D28(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  jmp    L12
  nopl   0x0(%rax)
L35:
  mov    $0xffffffff,%r12d
  jmp    L12
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D28
datatype: string

tool: D17: IL0

tool: D18: RS

tool: D28: 00

assistant: ```c
int wl_get_country(const char *ifname, char *buf) {
  char ccode[4];
  if (!wl_ioctl(ifname, 83, ccode, 4)) {
    if (!strcmp(ccode, "IL0"))
      sprintf(buf, "00");
    else if (!strcmp(ccode, "YU"))
      sprintf(buf, "RS");
    else
      memcpy(buf, ccode, 2);
    return 0;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<convert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x28(%rbp)
  je     L155
  cmpl   $0xffffffff,-0x30(%rbp)
  jne    L98
L155:
  mov    $0x1,%eax
  jmp    L26
L98:
  cmpl   $0x0,0x10(%rbp)
  je     L109
  cmpl   $0x0,-0x28(%rbp)
  jne    L109
  cmpl   $0x0,-0x30(%rbp)
  jne    L109
  mov    -0x2c(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpq_cmp@plt>
  test   %rax,%rax
  jle    L109
  mov    $0x1,%eax
  jmp    L26
L109:
  lea    -0x18(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <convertNum@plt>
  mov    -0x40(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <convertNum@plt>
  cmpl   $0x0,0x10(%rbp)
  jne    L127
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L127
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  -0x10(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L5
  ucomisd %xmm1,%xmm0
  jne    L5
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  -0x18(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L5
  ucomisd %xmm1,%xmm0
  je     L127
L5:
  mov    $0x1,%eax
  jmp    L26
L127:
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int convert(mpq_t infq, int isInfinityInf, mpq_t supq, int isInfinitySup, double *inf, double *sup, int strictBoundsCheck) {
  double inf1, sup1;
  if (isInfinityInf == +1 || isInfinitySup == -1)
    return 1;
  if (strictBoundsCheck) {
    if (isInfinityInf == 0 && isInfinitySup == 0 && mpq_cmp(infq, supq) > 0)
      return 1;
  }
  convertNum(infq, isInfinityInf, inf, &inf1);
  convertNum(supq, isInfinitySup, &sup1, sup);
  if (!strictBoundsCheck) {
    if (inf1 >= sup1 && (*inf != sup1 || inf1 != *sup))
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L76
  mov    %edi,%r14d
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %ecx,%ebp
  mov    %r8,%r12
  mov    %r9,%r15
  cmp    $0xffffffff,%ecx
  je     L76
  cmpl   $0x0,0x60(%rsp)
  je     L138
  mov    %esi,%eax
  or     %ecx,%eax
  je     L16
L105:
  lea    0x8(%rsp),%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <convertNum@plt>
  lea    0x10(%rsp),%rdx
  mov    %r15,%rcx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <convertNum@plt>
  mov    $0x0,%eax
  jmp    L70
L16:
  mov    %edx,%esi
  call   <mpq_cmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jle    L105
  jmp    L70
L57:
  ucomisd (%r12),%xmm0
  jp     L62
  jne    L62
  ucomisd (%r15),%xmm1
  setp   %al
  movzbl %al,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
  jmp    L70
L76:
  mov    $0x1,%eax
L70:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L107
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  mov    $0x1,%eax
  jmp    L70
L138:
  lea    0x8(%rsp),%rcx
  mov    %r8,%rdx
  call   <convertNum@plt>
  lea    0x10(%rsp),%rdx
  mov    %r15,%rcx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <convertNum@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  comisd %xmm0,%xmm1
  jae    L57
  mov    0x60(%rsp),%eax
  jmp    L70
L107:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int convert(mpq_t infq, int isInfinityInf, mpq_t supq, int isInfinitySup, double *inf, double *sup, int strictBoundsCheck) {
  double inf1, sup1;
  if (isInfinityInf == +1 || isInfinitySup == -1)
    return 1;
  if (strictBoundsCheck) {
    if (isInfinityInf == 0 && isInfinitySup == 0 && mpq_cmp(infq, supq) > 0)
      return 1;
  }
  convertNum(infq, isInfinityInf, inf, &inf1);
  convertNum(supq, isInfinitySup, &sup1, sup);
  if (!strictBoundsCheck) {
    if (inf1 >= sup1 && (*inf != sup1 || inf1 != *sup))
      return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<convert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L34
  mov    %ecx,%r12d
  cmp    $0xffffffff,%ecx
  je     L34
  mov    0x60(%rsp),%eax
  mov    %esi,%ebp
  mov    %edx,%r15d
  mov    %r8,%r13
  mov    %r9,%r14
  test   %eax,%eax
  je     L112
  mov    %esi,%eax
  or     %ecx,%eax
  je     L110
L7:
  lea    0x18(%rsp),%rcx
  mov    %r13,%rdx
  mov    %ebp,%esi
  call   <convertNum@plt>
  lea    0x20(%rsp),%rdx
  mov    %r14,%rcx
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <convertNum@plt>
L11:
  xor    %eax,%eax
L71:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L115
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L112:
  mov    %r8,%rdx
  lea    0x18(%rsp),%rcx
  call   <convertNum@plt>
  lea    0x20(%rsp),%rdx
  mov    %r14,%rcx
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <convertNum@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm0
  comisd %xmm0,%xmm1
  jb     L11
  ucomisd 0x0(%r13),%xmm0
  jp     L34
  jne    L34
  ucomisd (%r14),%xmm1
  jp     L34
  mov    $0x0,%eax
  je     L71
  nopw   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%eax
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L110:
  mov    %edx,%esi
  mov    %edi,0xc(%rsp)
  call   <mpq_cmp@plt>
  mov    0xc(%rsp),%edi
  test   %rax,%rax
  jle    L7
  jmp    L34
L115:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int convert(mpq_t infq, int isInfinityInf, mpq_t supq, int isInfinitySup, double *inf, double *sup, int strictBoundsCheck) {
  double inf1, sup1;
  if (isInfinityInf == +1 || isInfinitySup == -1)
    return 1;
  if (strictBoundsCheck) {
    if (isInfinityInf == 0 && isInfinitySup == 0 && mpq_cmp(infq, supq) > 0)
      return 1;
  }
  convertNum(infq, isInfinityInf, inf, &inf1);
  convertNum(supq, isInfinitySup, &sup1, sup);
  if (!strictBoundsCheck) {
    if (inf1 >= sup1 && (*inf != sup1 || inf1 != *sup))
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L25
  mov    %ecx,%r12d
  cmp    $0xffffffff,%ecx
  je     L25
  mov    0x60(%rsp),%eax
  mov    %esi,%ebp
  mov    %edx,%r15d
  mov    %r8,%r13
  mov    %r9,%r14
  test   %eax,%eax
  je     L128
  mov    %esi,%eax
  or     %ecx,%eax
  je     L44
L38:
  lea    0x18(%rsp),%rcx
  mov    %r13,%rdx
  mov    %ebp,%esi
  call   <convertNum@plt>
  lea    0x20(%rsp),%rdx
  mov    %r14,%rcx
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <convertNum@plt>
L2:
  xor    %eax,%eax
L60:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L128:
  mov    %r8,%rdx
  lea    0x18(%rsp),%rcx
  call   <convertNum@plt>
  lea    0x20(%rsp),%rdx
  mov    %r14,%rcx
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <convertNum@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm0
  comisd %xmm0,%xmm1
  jb     L2
  ucomisd 0x0(%r13),%xmm0
  jp     L25
  jne    L25
  ucomisd (%r14),%xmm1
  jp     L25
  mov    $0x0,%eax
  je     L60
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x1,%eax
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %edx,%esi
  mov    %edi,0xc(%rsp)
  call   <mpq_cmp@plt>
  mov    0xc(%rsp),%edi
  test   %rax,%rax
  jle    L38
  jmp    L25
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int convert(mpq_t infq, int isInfinityInf, mpq_t supq, int isInfinitySup, double *inf, double *sup, int strictBoundsCheck) {
  double inf1, sup1;
  if (isInfinityInf == +1 || isInfinitySup == -1)
    return 1;
  if (strictBoundsCheck) {
    if (isInfinityInf == 0 && isInfinitySup == 0 && mpq_cmp(infq, supq) > 0)
      return 1;
  }
  convertNum(infq, isInfinityInf, inf, &inf1);
  convertNum(supq, isInfinitySup, &sup1, sup);
  if (!strictBoundsCheck) {
    if (inf1 >= sup1 && (*inf != sup1 || inf1 != *sup))
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<errx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <verrx@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void errx(int exitval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  verrx(exitval, fmt, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below:

```asm
<errx>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <verrx@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void errx(int exitval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  verrx(exitval, fmt, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below:

```asm
<errx>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <verrx@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void errx(int exitval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  verrx(exitval, fmt, ap);
  va_end(ap);
}
```