ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dns_format>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  lea    D5(%rip),%rsi
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strcat@plt>
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L43:
  add    $0x1,%rbx
L50:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  cmp    %ebx,%eax
  jle    L46
  cmpb   $0x2e,0x0(%rbp,%rbx,1)
  jne    L43
  mov    %ebx,%eax
  lea    0x1(%r13),%rsi
  sub    %r12d,%eax
  mov    %al,0x0(%r13)
  cmp    %edx,%r12d
  jge    L48
  movslq %r12d,%rax
  sub    %rax,%r13
  nopl   0x0(%rax)
L15:
  movzbl 0x0(%rbp,%rax,1),%ecx
  mov    %cl,0x1(%r13,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L15
  mov    %ebx,%eax
  sub    %r12d,%eax
  sub    $0x1,%eax
  lea    0x1(%rsi,%rax,1),%r13
L24:
  lea    0x1(%rdx),%r12d
  jmp    L43
  nopl   (%rax)
L46:
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  mov    %r12d,%edx
  mov    %rsi,%r13
  jmp    L24
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: .

assistant: ```c
void dns_format(unsigned char *dns, unsigned char *host) {
  int lock = 0, i;
  strcat((char *)host, ".");
  for (i = 0; i < strlen((char *)host); i++) {
    if (host[i] == '.') {
      *dns++ = i - lock;
      for (; lock < i; lock++) {
        *dns++ = host[lock];
      }
      lock++;
    }
  }
  *dns++ = 0x00;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sys$flush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0xb,%rax
  int    $0x82
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sys$flush(struct _fab *fab, void *err, void *suc) {
  return ({
    unsigned long resultvar;
    register long int _a3 asm("rdx") = (long)(suc);
    register long int _a2 asm("rsi") = (long)(err);
    register long int _a1 asm("rdi") = (long)(fab);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x82\n\t"
                 : "=a"(resultvar)
                 : "i"(11), "r"(_a1), "r"(_a2), "r"(_a3)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sys$flush>:
  endbr64
  mov    $0xb,%rax
  int    $0x82
  ret
```

assistant: ```c
int sys$flush(struct _fab *fab, void *err, void *suc) {
  return ({
    unsigned long resultvar;
    register long int _a3 asm("rdx") = (long)(suc);
    register long int _a2 asm("rsi") = (long)(err);
    register long int _a1 asm("rdi") = (long)(fab);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x82\n\t"
                 : "=a"(resultvar)
                 : "i"(11), "r"(_a1), "r"(_a2), "r"(_a3)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sys$flush>:
  endbr64
  mov    $0xb,%rax
  int    $0x82
  ret
```

assistant: ```c
int sys$flush(struct _fab *fab, void *err, void *suc) {
  return ({
    unsigned long resultvar;
    register long int _a3 asm("rdx") = (long)(suc);
    register long int _a2 asm("rsi") = (long)(err);
    register long int _a1 asm("rdi") = (long)(fab);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x82\n\t"
                 : "=a"(resultvar)
                 : "i"(11), "r"(_a1), "r"(_a2), "r"(_a3)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  je     L45
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L31
L45:
  mov    $0xffffffff,%eax
  jmp    L35
L31:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L58
  mov    -0x10(%rbp),%edx
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L58
  mov    $0x0,%eax
  jmp    L35
L58:
  mov    $0xffffffff,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
int is_directory(const char *dirname) {
  struct stat buf;
  int n;
  if (!dirname || !strlen(dirname)) {
    return -1;
  }
  n = stat(dirname, &buf);
  return (n == 0 && (buf.st_mode & S_IFDIR) != 0) ? 0 : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_directory>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L59
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L49
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L58
  mov    D9(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L62
  add    $0x10,%rsp
  pop    %rbx
  ret
L59:
  mov    $0xffffffff,%eax
  jmp    L29
L49:
  mov    $0xffffffff,%eax
  jmp    L29
L58:
  mov    $0xffffffff,%eax
  jmp    L29
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *dirname) {
  struct stat buf;
  int n;
  if (!dirname || !strlen(dirname)) {
    return -1;
  }
  n = stat(dirname, &buf);
  return (n == 0 && (buf.st_mode & S_IFDIR) != 0) ? 0 : -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_directory>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L13
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  je     L13
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L13
  mov    D3(%rip),%rcx
  mov    0x4(%rsp),%edx
  and    (%rcx),%edx
  je     L13
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L53
  add    $0x10,%rsp
  pop    %rbp
  ret
L13:
  mov    $0xffffffff,%eax
  jmp    L41
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *dirname) {
  struct stat buf;
  int n;
  if (!dirname || !strlen(dirname)) {
    return -1;
  }
  n = stat(dirname, &buf);
  return (n == 0 && (buf.st_mode & S_IFDIR) != 0) ? 0 : -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_directory>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L49
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  je     L49
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L49
  mov    D1(%rip),%rcx
  mov    0x4(%rsp),%edx
  and    (%rcx),%edx
  je     L49
L52:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x10,%rsp
  pop    %rbp
  ret
L49:
  mov    $0xffffffff,%eax
  jmp    L52
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *dirname) {
  struct stat buf;
  int n;
  if (!dirname || !strlen(dirname)) {
    return -1;
  }
  n = stat(dirname, &buf);
  return (n == 0 && (buf.st_mode & S_IFDIR) != 0) ? 0 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hex2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L2
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L6
L2:
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
L6:
  leave
  ret
```

assistant: ```c
unsigned hex2int(char c) {
  c = toupper(c);
  return isdigit(c) ? c - '0' : c - 'A' + 10;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hex2int>:
  endbr64
  push   %rbx
  movsbl %dil,%edi
  call   <toupper@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  mov    %rax,%rdx
  lea    -0x30(%rbx),%eax
  sub    $0x37,%ebx
  test   %rdx,%rdx
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned hex2int(char c) {
  c = toupper(c);
  return isdigit(c) ? c - '0' : c - 'A' + 10;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hex2int>:
  endbr64
  push   %rbx
  movsbl %dil,%edi
  call   <toupper@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  mov    %rax,%r8
  lea    -0x30(%rbx),%eax
  sub    $0x37,%ebx
  test   %r8,%r8
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned hex2int(char c) {
  c = toupper(c);
  return isdigit(c) ? c - '0' : c - 'A' + 10;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hex2int>:
  endbr64
  push   %rbx
  movsbl %dil,%edi
  call   <toupper@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  mov    %rax,%r8
  lea    -0x30(%rbx),%eax
  sub    $0x37,%ebx
  test   %r8,%r8
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned hex2int(char c) {
  c = toupper(c);
  return isdigit(c) ? c - '0' : c - 'A' + 10;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<before_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L12:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L12
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L26
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L26:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *before_tag(theword)
char *theword;
{
  int count = 0;
  while (theword[count] != '\0' && theword[count] != '/')
    count++;
  if (theword[count] == '/')
    theword[count] = '\0';
  return (theword);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<before_tag>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L20
  cmp    $0x2f,%cl
  je     L20
  lea    0x1(%rdi),%rdx
L7:
  mov    %rdx,%rsi
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  je     L4
  cmp    $0x2f,%cl
  jne    L7
L4:
  cmp    $0x2f,%cl
  je     L42
L12:
  ret
L20:
  mov    %rax,%rsi
  jmp    L4
L42:
  movb   $0x0,(%rsi)
  jmp    L12
```

assistant: ```c
char *before_tag(theword)
char *theword;
{
  int count = 0;
  while (theword[count] != '\0' && theword[count] != '/')
    count++;
  if (theword[count] == '/')
    theword[count] = '\0';
  return (theword);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<before_tag>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L31
  cmp    $0x2f,%cl
  je     L31
  lea    0x1(%rdi),%rdx
  nopw   0x0(%rax,%rax,1)
L36:
  movzbl (%rdx),%ecx
  mov    %rdx,%rsi
  add    $0x1,%rdx
  test   %cl,%cl
  je     L49
  cmp    $0x2f,%cl
  jne    L36
L19:
  movb   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %rax,%rsi
  nopl   0x0(%rax,%rax,1)
L49:
  cmp    $0x2f,%cl
  je     L19
  ret
```

assistant: ```c
char *before_tag(theword)
char *theword;
{
  int count = 0;
  while (theword[count] != '\0' && theword[count] != '/')
    count++;
  if (theword[count] == '/')
    theword[count] = '\0';
  return (theword);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<before_tag>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L32
  cmp    $0x2f,%cl
  je     L32
  lea    0x1(%rdi),%rdx
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl (%rdx),%ecx
  mov    %rdx,%rsi
  add    $0x1,%rdx
  test   %cl,%cl
  je     L22
  cmp    $0x2f,%cl
  jne    L2
L13:
  movb   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %rax,%rsi
  nopl   0x0(%rax,%rax,1)
L22:
  cmp    $0x2f,%cl
  je     L13
  ret
```

assistant: ```c
char *before_tag(theword)
char *theword;
{
  int count = 0;
  while (theword[count] != '\0' && theword[count] != '/')
    count++;
  if (theword[count] == '/')
    theword[count] = '\0';
  return (theword);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<whatever>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <arrayPromotion@plt>
  mov    D9(%rip),%rax
  mov    %rax,%rdi
  call   <functionPromotion@plt>
  nop
  leave
  ret
```

assistant: ```c
int whatever(int argc, char *argv[]) {
  arrayPromotion(argv);
  functionPromotion(arrayPromotion);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<whatever>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <arrayPromotion@plt>
  mov    D7(%rip),%rdi
  call   <functionPromotion@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int whatever(int argc, char *argv[]) {
  arrayPromotion(argv);
  functionPromotion(arrayPromotion);
}
```
user: What is the c source code of the assembly code below:

```asm
<whatever>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <arrayPromotion@plt>
  mov    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <functionPromotion@plt>
```

assistant: ```c
int whatever(int argc, char *argv[]) {
  arrayPromotion(argv);
  functionPromotion(arrayPromotion);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<whatever>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <arrayPromotion@plt>
  mov    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <functionPromotion@plt>
```

assistant: ```c
int whatever(int argc, char *argv[]) {
  arrayPromotion(argv);
  functionPromotion(arrayPromotion);
}
```
user: What is the c source code of the assembly code below?

```asm
<back_mm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <back@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <linear_distance_mm@plt>
  nop
  leave
  ret
```

assistant: ```c
void back_mm(unsigned int DistanceInMM) {
  back();
  linear_distance_mm(DistanceInMM);
}
```
user: Translate the below assembly code into C programming language:

```asm
<back_mm>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <back@plt>
  mov    %ebx,%edi
  call   <linear_distance_mm@plt>
  pop    %rbx
  ret
```

assistant: ```c
void back_mm(unsigned int DistanceInMM) {
  back();
  linear_distance_mm(DistanceInMM);
}
```
user: Translate the below assembly code into C programming language:

```asm
<back_mm>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <back@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <linear_distance_mm@plt>
```

assistant: ```c
void back_mm(unsigned int DistanceInMM) {
  back();
  linear_distance_mm(DistanceInMM);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<back_mm>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <back@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <linear_distance_mm@plt>
```

assistant: ```c
void back_mm(unsigned int DistanceInMM) {
  back();
  linear_distance_mm(DistanceInMM);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L8
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L8:
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L4
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_substring(char *full_string, char *cutoff) {
  char *sub_copy, *dummy1 = full_string, *dummy2;
  sub_copy = (char *)malloc((int)(cutoff - full_string + 1) * sizeof(char));
  dummy2 = sub_copy;
  while (dummy1 < cutoff + 1) {
    *dummy2 = *dummy1;
    dummy1++;
    dummy2++;
  }
  *(sub_copy + (int)(cutoff - full_string)) = '\0';
  return sub_copy;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_substring>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rsi,%rbp
  sub    %rdi,%rbp
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  lea    0x1(%r12),%rdx
  cmp    %rdx,%rbx
  jae    L16
  lea    0x1(%rbp,%rax,1),%rdi
  mov    %rax,%rdx
  sub    %rax,%rbx
  mov    %rbx,%rsi
L2:
  movzbl (%rdx,%rsi,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L2
L16:
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_substring(char *full_string, char *cutoff) {
  char *sub_copy, *dummy1 = full_string, *dummy2;
  sub_copy = (char *)malloc((int)(cutoff - full_string + 1) * sizeof(char));
  dummy2 = sub_copy;
  while (dummy1 < cutoff + 1) {
    *dummy2 = *dummy1;
    dummy1++;
    dummy2++;
  }
  *(sub_copy + (int)(cutoff - full_string)) = '\0';
  return sub_copy;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_substring>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    %rdi,%r12
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%r12),%edi
  mov    %rsi,%rbx
  call   <malloc@plt>
  lea    0x1(%rbx),%rcx
  cmp    %rcx,%rbp
  jae    L6
  sub    %rbp,%rcx
  mov    %rbp,%rdi
  mov    %rax,%rdx
  add    %rax,%rcx
  sub    %rax,%rdi
  cs nopw 0x0(%rax,%rax,1)
L9:
  movzbl (%rdx,%rdi,1),%esi
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L9
L6:
  movslq %r12d,%r12
  movb   $0x0,(%rax,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_substring(char *full_string, char *cutoff) {
  char *sub_copy, *dummy1 = full_string, *dummy2;
  sub_copy = (char *)malloc((int)(cutoff - full_string + 1) * sizeof(char));
  dummy2 = sub_copy;
  while (dummy1 < cutoff + 1) {
    *dummy2 = *dummy1;
    dummy1++;
    dummy2++;
  }
  *(sub_copy + (int)(cutoff - full_string)) = '\0';
  return sub_copy;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_substring>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    %rdi,%r12
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%r12),%edi
  mov    %rsi,%rbx
  call   <malloc@plt>
  lea    0x1(%rbx),%rdx
  mov    %rax,%r8
  cmp    %rdx,%rbp
  jae    L89
  lea    0x1(%rbp),%rcx
  sub    %rcx,%rax
  cmp    $0xe,%rax
  jbe    L60
  cmp    $0x6,%r12
  jbe    L60
  lea    0x1(%r12),%rsi
  cmp    $0xe,%r12
  jbe    L154
  mov    %rsi,%rcx
  mov    %rbp,%rdi
  mov    %r8,%rax
  and    $0xfffffffffffffff0,%rcx
  sub    %r8,%rdi
  add    %r8,%rcx
  nopl   0x0(%rax,%rax,1)
L145:
  movdqu (%rax,%rdi,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rcx
  jne    L145
  mov    %rsi,%rdi
  and    $0xfffffffffffffff0,%rdi
  lea    0x0(%rbp,%rdi,1),%rax
  lea    (%r8,%rdi,1),%rcx
  cmp    %rdi,%rsi
  je     L89
  mov    %r12,%r9
  sub    %rdi,%r9
  lea    0x1(%r9),%rsi
  cmp    $0x6,%r9
  jbe    L112
L42:
  mov    0x0(%rbp,%rdi,1),%r9
  mov    %r9,(%r8,%rdi,1)
  mov    %rsi,%rdi
  and    $0xfffffffffffffff8,%rdi
  add    %rdi,%rax
  add    %rdi,%rcx
  cmp    %rdi,%rsi
  je     L89
L112:
  movzbl (%rax),%esi
  mov    %sil,(%rcx)
  lea    0x1(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L89
  movzbl 0x1(%rax),%esi
  mov    %sil,0x1(%rcx)
  lea    0x2(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L89
  movzbl 0x2(%rax),%esi
  mov    %sil,0x2(%rcx)
  lea    0x3(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L89
  movzbl 0x3(%rax),%esi
  mov    %sil,0x3(%rcx)
  lea    0x4(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L89
  movzbl 0x4(%rax),%esi
  mov    %sil,0x4(%rcx)
  lea    0x5(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L89
  movzbl 0x5(%rax),%esi
  mov    %sil,0x5(%rcx)
  lea    0x6(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L89
  movzbl 0x6(%rax),%eax
  mov    %al,0x6(%rcx)
L89:
  movslq %r12d,%r12
  mov    %r8,%rax
  movb   $0x0,(%r8,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L60:
  sub    %rbp,%rdx
  mov    %r8,%rax
  sub    %r8,%rbp
  add    %r8,%rdx
  nopl   0x0(%rax)
L52:
  movzbl (%rax,%rbp,1),%ecx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    %rdx,%rax
  jne    L52
  movslq %r12d,%r12
  mov    %r8,%rax
  movb   $0x0,(%r8,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L154:
  mov    %r8,%rcx
  mov    %rbp,%rax
  xor    %edi,%edi
  jmp    L42
```

assistant: ```c
char *get_substring(char *full_string, char *cutoff) {
  char *sub_copy, *dummy1 = full_string, *dummy2;
  sub_copy = (char *)malloc((int)(cutoff - full_string + 1) * sizeof(char));
  dummy2 = sub_copy;
  while (dummy1 < cutoff + 1) {
    *dummy2 = *dummy1;
    dummy1++;
    dummy2++;
  }
  *(sub_copy + (int)(cutoff - full_string)) = '\0';
  return sub_copy;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x32,-0x9(%rbp)
L7:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  lea    -0x9(%rbp),%rcx
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  jmp    L7
```

assistant: ```c
int main(void) {
  char chr = '2';
  while (1)
    write(STDOUT_FILENO, &chr, 1);
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x32,0x7(%rsp)
  lea    0x7(%rsp),%rbx
L5:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  jmp    L5
```

assistant: ```c
int main(void) {
  char chr = '2';
  while (1)
    write(STDOUT_FILENO, &chr, 1);
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D7(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x32,0x7(%rsp)
  lea    0x7(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%edi
  mov    $0x1,%edx
  mov    %rbp,%rsi
  call   <write@plt>
  jmp    L1
```

assistant: ```c
int main(void) {
  char chr = '2';
  while (1)
    write(STDOUT_FILENO, &chr, 1);
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D0(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x32,0x7(%rsp)
  lea    0x7(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%edi
  mov    $0x1,%edx
  mov    %rbp,%rsi
  call   <write@plt>
  jmp    L8
```

assistant: ```c
int main(void) {
  char chr = '2';
  while (1)
    write(STDOUT_FILENO, &chr, 1);
  return EXIT_SUCCESS;
}
```