ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x27000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x140,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x27134(%rbp)
  movsd  D32(%rip),%xmm0
  movsd  %xmm0,-0x27130(%rbp)
  movsd  D37(%rip),%xmm0
  movsd  %xmm0,-0x27128(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x27120(%rbp)
  jmp    L4
L8:
  addl   $0x1,-0x27134(%rbp)
L4:
  cmpl   $0x4e1f,-0x27134(%rbp)
  jg     L15
  lea    -0x27110(%rbp),%rdx
  mov    -0x27134(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L8
L15:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x27134(%rbp),%xmm1
  movsd  -0x27120(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x27118(%rbp)
  movsd  -0x27128(%rbp),%xmm1
  movsd  -0x27130(%rbp),%xmm0
  mov    -0x27118(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D32
type_guessed: f64
name: disassemble_data
arguments: tag: D37
type_guessed: f32[2]
name: disassemble_data
arguments: tag: D8
type_guessed: string
name: disassemble_data
arguments: tag: D27
type_guessed: string

tool: D32: 100

tool: {"D37": [0.0,-3.390625]}

tool: D8: %lf

tool: D27: med = %.3lf, min = %.3lf, max = %.3lf


assistant: ```c
int main() {
  int n = 0;
  double t[20000], med, min = 100, max = -100, soma = 0;
  ;
  while (n < 20000 && scanf("%lf", &t[n]) > 0) {
    n++;
  }
  med = soma / n;
  printf("med = %.3lf, min = %.3lf, max = %.3lf\n", med, min, max);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x27000(%rsp),%r11
L23:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L23
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x27108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jle    L0
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    $0x4e20,%ebx
  jne    L3
L0:
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  pxor   %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  movsd  D23(%rip),%xmm2
  movsd  D39(%rip),%xmm1
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x27108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x27110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D23
type: f32[2]
name: disassemble_data
arguments: data_label: D39
type: f64
name: disassemble_data
arguments: data_label: D25
type: string

tool: D4: %lf

tool: {"D23": [0.0,-3.390625]}

tool: D39: 100

tool: D25: med = %.3lf, min = %.3lf, max = %.3lf


assistant: ```c
int main() {
  int n = 0;
  double t[20000], med, min = 100, max = -100, soma = 0;
  ;
  while (n < 20000 && scanf("%lf", &t[n]) > 0) {
    n++;
  }
  med = soma / n;
  printf("med = %.3lf, min = %.3lf, max = %.3lf\n", med, min, max);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x27000(%rsp),%r11
L33:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L33
  sub    $0x110,%rsp
  xor    %ebx,%ebx
  lea    D4(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x27108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L32
  nopl   0x0(%rax)
L49:
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    $0x4e20,%ebx
  je     L34
L32:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L49
L34:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  movsd  D1(%rip),%xmm2
  lea    D5(%rip),%rdi
  cvtsi2sd %ebx,%xmm1
  divsd  %xmm1,%xmm0
  movsd  D3(%rip),%xmm1
  call   <printf@plt>
  mov    0x27108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x27110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: f32[2]
name: read_data
arguments: data_label: D5
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: f64

tool: D4: %lf

tool: {"D1": [0.0,-3.390625]}

tool: D5: med = %.3lf, min = %.3lf, max = %.3lf


tool: D3: 100

assistant: ```c
int main() {
  int n = 0;
  double t[20000], med, min = 100, max = -100, soma = 0;
  ;
  while (n < 20000 && scanf("%lf", &t[n]) > 0) {
    n++;
  }
  med = soma / n;
  printf("med = %.3lf, min = %.3lf, max = %.3lf\n", med, min, max);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x27000(%rsp),%r11
L35:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L35
  sub    $0x110,%rsp
  xor    %ebx,%ebx
  lea    D17(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x27108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L10
  nopl   0x0(%rax)
L33:
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    $0x4e20,%ebx
  je     L42
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L33
L42:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  movsd  D2(%rip),%xmm2
  lea    D6(%rip),%rdi
  cvtsi2sd %ebx,%xmm1
  divsd  %xmm1,%xmm0
  movsd  D24(%rip),%xmm1
  call   <printf@plt>
  mov    0x27108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x27110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D2
type: f32[2]
name: retrieve_data
arguments: data_tag: D6
type: string
name: retrieve_data
arguments: data_tag: D24
type: f64

tool: D17: %lf

tool: {"D2": [0.0,-3.390625]}

tool: D6: med = %.3lf, min = %.3lf, max = %.3lf


tool: D24: 100

assistant: ```c
int main() {
  int n = 0;
  double t[20000], med, min = 100, max = -100, soma = 0;
  ;
  while (n < 20000 && scanf("%lf", &t[n]) > 0) {
    n++;
  }
  med = soma / n;
  printf("med = %.3lf, min = %.3lf, max = %.3lf\n", med, min, max);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L17
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L17:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L23
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L23:
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  jne    L43
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jne    L43
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L43:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
type: string
name: parse_data
arguments: tag: D41
type: string
name: parse_data
arguments: tag: D34
type: string
name: parse_data
arguments: tag: D40
type: string
name: parse_data
arguments: tag: D1
type: string

tool: D13: /

tool: D41: stat

tool: D34: /proc/1/root

tool: D40: proc path test success


tool: D1: proc path test failure


assistant: ```c
int main(int argc, char **argv) {
  struct stat root, proc_root;
  if (stat("/", &root) == -1) {
    perror("stat");
    exit(1);
  }
  if (stat("/proc/1/root", &proc_root) == -1) {
    perror("stat");
    exit(1);
  }
  if (root.st_dev == proc_root.st_dev && root.st_ino == proc_root.st_ino) {
    printf("proc path test success\n");
  } else {
    printf("proc path test failure\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D41(%rip),%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L68
L34:
  lea    0x10(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L49
L23:
  mov    0x10(%rsp),%rax
  cmp    %rax,(%rsp)
  jne    L79
  mov    0x18(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  je     L27
L79:
  lea    D16(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L68:
  lea    D23(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L34
L49:
  lea    D23(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L23
L27:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D41
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D23
data_type: string
name: extract_symbolic_data
arguments: data_tag: D53
data_type: string

tool: D41: /

tool: D11: /proc/1/root

tool: D16: proc path test failure


tool: D23: stat

tool: D53: proc path test success


assistant: ```c
int main(int argc, char **argv) {
  struct stat root, proc_root;
  if (stat("/", &root) == -1) {
    perror("stat");
    exit(1);
  }
  if (stat("/proc/1/root", &proc_root) == -1) {
    perror("stat");
    exit(1);
  }
  if (root.st_dev == proc_root.st_dev && root.st_ino == proc_root.st_ino) {
    printf("proc path test success\n");
  } else {
    printf("proc path test failure\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D47(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L39
L23:
  lea    0x10(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L32
L36:
  mov    0x10(%rsp),%rax
  cmp    %rax,(%rsp)
  jne    L75
  mov    0x18(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  je     L44
L75:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L32:
  lea    D52(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L36
L39:
  lea    D52(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L23
L44:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D47
type_guessed: string
name: parse_data
arguments: data_tag: D31
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string
name: parse_data
arguments: data_tag: D52
type_guessed: string
name: parse_data
arguments: data_tag: D53
type_guessed: string

tool: D47: /

tool: D31: /proc/1/root

tool: D8: proc path test failure


tool: D52: stat

tool: D53: proc path test success


assistant: ```c
int main(int argc, char **argv) {
  struct stat root, proc_root;
  if (stat("/", &root) == -1) {
    perror("stat");
    exit(1);
  }
  if (stat("/proc/1/root", &proc_root) == -1) {
    perror("stat");
    exit(1);
  }
  if (root.st_dev == proc_root.st_dev && root.st_ino == proc_root.st_ino) {
    printf("proc path test success\n");
  } else {
    printf("proc path test failure\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D49(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L33
L72:
  lea    0x10(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L41
L21:
  mov    0x10(%rsp),%rax
  cmp    %rax,(%rsp)
  jne    L0
  mov    0x18(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  je     L26
L0:
  lea    D52(%rip),%rdi
  call   <printf@plt>
L59:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L41:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L21
L33:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L72
L26:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D49
type_infered: string
name: retrieve_data
arguments: data_label: D2
type_infered: string
name: retrieve_data
arguments: data_label: D52
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string
name: retrieve_data
arguments: data_label: D39
type_infered: string

tool: D49: /

tool: D2: /proc/1/root

tool: D52: proc path test failure


tool: D6: stat

tool: D39: proc path test success


assistant: ```c
int main(int argc, char **argv) {
  struct stat root, proc_root;
  if (stat("/", &root) == -1) {
    perror("stat");
    exit(1);
  }
  if (stat("/proc/1/root", &proc_root) == -1) {
    perror("stat");
    exit(1);
  }
  if (root.st_dev == proc_root.st_dev && root.st_ino == proc_root.st_ino) {
    printf("proc path test success\n");
  } else {
    printf("proc path test failure\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<random_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <f_getrandom@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L6:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    $0x4f,%ecx
  mov    %ecx,%eax
  mul    %dl
  shr    $0x8,%ax
  shr    $0x3,%al
  mov    $0x1a,%ecx
  imul   %ecx,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x61(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void random_name(char *buf, size_t len) {
  f_getrandom(buf, len, 0);
  for (size_t i = 0; i < len; i++)
    buf[i] = (unsigned char)buf[i] % 26 + 'a';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<random_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%edx
  call   <f_getrandom@plt>
  test   %rbp,%rbp
  je     L9
  mov    %rbx,%rcx
  lea    (%rbx,%rbp,1),%rdi
  mov    $0x4f,%r8d
  mov    $0x1a,%esi
L10:
  movzbl (%rcx),%edx
  mov    %edx,%eax
  mul    %r8b
  shr    $0xb,%ax
  imul   %esi,%eax
  sub    %eax,%edx
  add    $0x61,%edx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L10
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void random_name(char *buf, size_t len) {
  f_getrandom(buf, len, 0);
  for (size_t i = 0; i < len; i++)
    buf[i] = (unsigned char)buf[i] % 26 + 'a';
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<random_name>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <f_getrandom@plt>
  test   %rbp,%rbp
  je     L14
  mov    %rbx,%rdi
  lea    (%rbx,%rbp,1),%rsi
  mov    $0x4f,%r8d
  mov    $0x1a,%ecx
  xchg   %ax,%ax
L19:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    %edx,%eax
  mul    %r8b
  shr    $0xb,%ax
  imul   %ecx,%eax
  sub    %eax,%edx
  add    $0x61,%edx
  mov    %dl,-0x1(%rdi)
  cmp    %rdi,%rsi
  jne    L19
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void random_name(char *buf, size_t len) {
  f_getrandom(buf, len, 0);
  for (size_t i = 0; i < len; i++)
    buf[i] = (unsigned char)buf[i] % 26 + 'a';
}
```
user: What is the c source code of the assembly code below:

```asm
<test_arylen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L8:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_arylen(char *ary[]) {
  int i;
  for (i = 0; ary[i]; i++) {
  };
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_arylen>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L17
  mov    $0x1,%eax
L6:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L6
L4:
  mov    %edx,%eax
  ret
L17:
  mov    $0x0,%edx
  jmp    L4
```

assistant: ```c
int test_arylen(char *ary[]) {
  int i;
  for (i = 0; ary[i]; i++) {
  };
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_arylen>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  nop
L8:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L8
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int test_arylen(char *ary[]) {
  int i;
  for (i = 0; ary[i]; i++) {
  };
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_arylen>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L6
  mov    $0x1,%eax
  nop
L12:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int test_arylen(char *ary[]) {
  int i;
  for (i = 0; ary[i]; i++) {
  };
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_VFAT_volume_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L125
L95:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jg     L57
  mov    $0x1,%eax
  jmp    L157
L57:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3c,%eax
  jg     L15
  cmp    $0x22,%eax
  jge    L153
  jmp    L3
L59:
  sub    $0x3e,%eax
  movabs $0x4000000040000003,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L40
  jmp    L3
L153:
  mov    %eax,%edx
  movabs $0x1400840400000000,%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L40
  jmp    L3
L15:
  cmp    $0x7c,%eax
  jg     L3
  cmp    $0x3e,%eax
  jge    L59
  jmp    L3
L40:
  mov    $0x1,%eax
  jmp    L157
L3:
  addl   $0x1,-0x4(%rbp)
L125:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jae    L44
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L95
L44:
  mov    $0x0,%eax
L157:
  pop    %rbp
  ret
```

assistant: ```c
int check_VFAT_volume_name(const char *name, const unsigned int max_size) {
  unsigned int i;
  for (i = 0; i < max_size && name[i] != '\0'; i++) {
    if (name[i] < 0x20)
      return 1;
    switch (name[i]) {
    case '<':
    case '>':
    case ':':
    case '"':
    case '/':
    case '\\':
    case '|':
    case '?':
    case '*':
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_VFAT_volume_name>:
  endbr64
  test   %esi,%esi
  je     L1
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rdi
  movabs $0x4000000040000003,%rsi
  movabs $0x1400840400000000,%rcx
  jmp    L56
L27:
  cmp    $0x21,%al
  jg     L34
L65:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L76
L56:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L33
  cmp    $0x1f,%al
  jle    L91
  cmp    $0x3c,%al
  jle    L27
  sub    $0x3e,%eax
  cmp    $0x3e,%al
  ja     L65
  bt     %rax,%rsi
  jae    L65
  mov    $0x1,%eax
  ret
L34:
  bt     %rax,%rcx
  jae    L65
  mov    $0x1,%eax
  ret
L33:
  mov    $0x0,%eax
  ret
L1:
  mov    $0x0,%eax
  ret
L91:
  mov    $0x1,%eax
  ret
L76:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int check_VFAT_volume_name(const char *name, const unsigned int max_size) {
  unsigned int i;
  for (i = 0; i < max_size && name[i] != '\0'; i++) {
    if (name[i] < 0x20)
      return 1;
    switch (name[i]) {
    case '<':
    case '>':
    case ':':
    case '"':
    case '/':
    case '\\':
    case '|':
    case '?':
    case '*':
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_VFAT_volume_name>:
  endbr64
  test   %esi,%esi
  je     L7
  movabs $0x4000000040000003,%rcx
  lea    -0x1(%rsi),%eax
  movabs $0x1400840400000000,%rdx
  lea    0x1(%rdi,%rax,1),%rsi
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L49:
  cmp    $0x21,%al
  jg     L61
L16:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L7
  nopl   (%rax)
L22:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  cmp    $0x1f,%al
  jle    L88
  cmp    $0x3c,%al
  jle    L49
  sub    $0x3e,%eax
  cmp    $0x3e,%al
  ja     L16
  bt     %rax,%rcx
  jae    L16
L88:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  bt     %rax,%rdx
  jb     L88
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L22
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_VFAT_volume_name(const char *name, const unsigned int max_size) {
  unsigned int i;
  for (i = 0; i < max_size && name[i] != '\0'; i++) {
    if (name[i] < 0x20)
      return 1;
    switch (name[i]) {
    case '<':
    case '>':
    case ':':
    case '"':
    case '/':
    case '\\':
    case '|':
    case '?':
    case '*':
      return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_VFAT_volume_name>:
  endbr64
  test   %esi,%esi
  je     L5
  movabs $0x4000000040000003,%rcx
  lea    -0x1(%rsi),%eax
  movabs $0x1400840400000000,%rdx
  lea    0x1(%rdi,%rax,1),%rsi
  jmp    L93
  cs nopw 0x0(%rax,%rax,1)
L17:
  cmp    $0x21,%al
  jg     L105
L81:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L5
  nopl   (%rax)
L93:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  cmp    $0x1f,%al
  jle    L91
  cmp    $0x3c,%al
  jle    L17
  sub    $0x3e,%eax
  cmp    $0x3e,%al
  ja     L81
  bt     %rax,%rcx
  jae    L81
L91:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L105:
  bt     %rax,%rdx
  jb     L91
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L93
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_VFAT_volume_name(const char *name, const unsigned int max_size) {
  unsigned int i;
  for (i = 0; i < max_size && name[i] != '\0'; i++) {
    if (name[i] < 0x20)
      return 1;
    switch (name[i]) {
    case '<':
    case '>':
    case ':':
    case '"':
    case '/':
    case '\\':
    case '|':
    case '?':
    case '*':
      return 1;
    }
  }
  return 0;
}
```