ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L3
L49:
  movsbl -0x15(%rbp),%eax
  sub    $0x41,%eax
  cmp    $0x34,%eax
  ja     L61
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D5(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  addl   $0x1,-0x14(%rbp)
  jmp    L3
  addl   $0x1,-0x10(%rbp)
  jmp    L3
  addl   $0x1,-0xc(%rbp)
  jmp    L3
  addl   $0x1,-0x8(%rbp)
  jmp    L3
  addl   $0x1,-0x4(%rbp)
  jmp    L3
L61:
  nop
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x15(%rbp)
  cmpb   $0x23,-0x15(%rbp)
  jne    L49
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%esi
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D42
data_type: string
name: unpack_data
arguments: data_tag: D49
data_type: string
name: unpack_data
arguments: data_tag: D22
data_type: string

tool: D13: Enter a statement(# at end):

tool: D42: number of vowels:

tool: D49:    A   E   I   O   U

tool: D22:                  %4d%4d%4d%4d%4d


assistant: ```c
int main(void) {
  char ch;
  int a_c, e_c, i_c, o_c, u_c;
  a_c = e_c = i_c = o_c = u_c = 0;
  printf("Enter a statement(# at end):\n");
  while ((ch = getchar()) != '#') {
    switch (ch) {
    case 'a':
    case 'A':
      a_c++;
      break;
    case 'e':
    case 'E':
      e_c++;
      break;
    case 'i':
    case 'I':
      i_c++;
      break;
    case 'o':
    case 'O':
      o_c++;
      break;
    case 'u':
    case 'U':
      u_c++;
      break;
    default:
      break;
    }
  }
  printf("number of vowels:");
  printf("   A   E   I   O   U\n");
  printf("                 %4d%4d%4d%4d%4d\n", a_c, e_c, i_c, o_c, u_c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D41(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    D5(%rip),%rbx
  jmp    L7
  add    $0x1,%ebp
L7:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L12
  sub    $0x41,%eax
  cmp    $0x34,%al
  ja     L7
  movzbl %al,%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  add    $0x1,%r12d
  jmp    L7
  add    $0x1,%r13d
  jmp    L7
  add    $0x1,%r14d
  jmp    L7
  add    $0x1,%r15d
  jmp    L7
L12:
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D41
datatype: string
name: extract_symbolic_data
arguments: label: D42
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string
name: extract_symbolic_data
arguments: label: D22
datatype: string

tool: D41: Enter a statement(# at end):

tool: D42: number of vowels:

tool: D3:    A   E   I   O   U

tool: D22:                  %4d%4d%4d%4d%4d


assistant: ```c
int main(void) {
  char ch;
  int a_c, e_c, i_c, o_c, u_c;
  a_c = e_c = i_c = o_c = u_c = 0;
  printf("Enter a statement(# at end):\n");
  while ((ch = getchar()) != '#') {
    switch (ch) {
    case 'a':
    case 'A':
      a_c++;
      break;
    case 'e':
    case 'E':
      e_c++;
      break;
    case 'i':
    case 'I':
      i_c++;
      break;
    case 'o':
    case 'O':
      o_c++;
      break;
    case 'u':
    case 'U':
      u_c++;
      break;
    default:
      break;
    }
  }
  printf("number of vowels:");
  printf("   A   E   I   O   U\n");
  printf("                 %4d%4d%4d%4d%4d\n", a_c, e_c, i_c, o_c, u_c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D1(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D49(%rip),%rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L41:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L49
L50:
  sub    $0x41,%eax
  cmp    $0x34,%al
  ja     L41
  movzbl %al,%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <getchar@plt>
  cmp    $0x23,%al
  jne    L50
L49:
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
  add    $0x1,%r14d
  jmp    L41
  nopl   0x0(%rax)
  add    $0x1,%r13d
  jmp    L41
  nopl   0x0(%rax)
  add    $0x1,%r12d
  jmp    L41
  nopl   0x0(%rax)
  add    $0x1,%ebp
  jmp    L41
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string
name: disassemble_data
arguments: data_label: D40
data_type: string
name: disassemble_data
arguments: data_label: D22
data_type: string

tool: D1: Enter a statement(# at end):

tool: D15: number of vowels:

tool: D40:    A   E   I   O   U

tool: D22:                  %4d%4d%4d%4d%4d


assistant: ```c
int main(void) {
  char ch;
  int a_c, e_c, i_c, o_c, u_c;
  a_c = e_c = i_c = o_c = u_c = 0;
  printf("Enter a statement(# at end):\n");
  while ((ch = getchar()) != '#') {
    switch (ch) {
    case 'a':
    case 'A':
      a_c++;
      break;
    case 'e':
    case 'E':
      e_c++;
      break;
    case 'i':
    case 'I':
      i_c++;
      break;
    case 'o':
    case 'O':
      o_c++;
      break;
    case 'u':
    case 'U':
      u_c++;
      break;
    default:
      break;
    }
  }
  printf("number of vowels:");
  printf("   A   E   I   O   U\n");
  printf("                 %4d%4d%4d%4d%4d\n", a_c, e_c, i_c, o_c, u_c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  lea    D40(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D17(%rip),%rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L11
L47:
  sub    $0x41,%eax
  cmp    $0x34,%al
  ja     L45
  movzbl %al,%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <getchar@plt>
  cmp    $0x23,%al
  jne    L47
L11:
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
  add    $0x1,%r14d
  jmp    L45
  nopl   0x0(%rax)
  add    $0x1,%r13d
  jmp    L45
  nopl   0x0(%rax)
  add    $0x1,%r12d
  jmp    L45
  nopl   0x0(%rax)
  add    $0x1,%ebp
  jmp    L45
```

tool_calls: name: retrieve_data
arguments: tag: D40
data_type: string
name: retrieve_data
arguments: tag: D35
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string

tool: D40: Enter a statement(# at end):

tool: D35: number of vowels:

tool: D14:    A   E   I   O   U

tool: D19:                  %4d%4d%4d%4d%4d


assistant: ```c
int main(void) {
  char ch;
  int a_c, e_c, i_c, o_c, u_c;
  a_c = e_c = i_c = o_c = u_c = 0;
  printf("Enter a statement(# at end):\n");
  while ((ch = getchar()) != '#') {
    switch (ch) {
    case 'a':
    case 'A':
      a_c++;
      break;
    case 'e':
    case 'E':
      e_c++;
      break;
    case 'i':
    case 'I':
      i_c++;
      break;
    case 'o':
    case 'O':
      o_c++;
      break;
    case 'u':
    case 'U':
      u_c++;
      break;
    default:
      break;
    }
  }
  printf("number of vowels:");
  printf("   A   E   I   O   U\n");
  printf("                 %4d%4d%4d%4d%4d\n", a_c, e_c, i_c, o_c, u_c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lintyp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  je     L51
  cmpl   $0x6,-0x4(%rbp)
  jg     L86
  cmpl   $0x1,-0x4(%rbp)
  jg     L27
  cmpl   $0x0,-0x4(%rbp)
  jns    L43
  jmp    L86
L27:
  mov    -0x4(%rbp),%eax
  sub    $0x2,%eax
  cmp    $0x1,%eax
  ja     L86
  jmp    L92
L43:
  mov    $0x0,%eax
  jmp    L84
L92:
  mov    $0x1,%eax
  jmp    L84
L51:
  mov    $0x2,%eax
  jmp    L84
L86:
  mov    $0x3,%eax
L84:
  pop    %rbp
  ret
```

assistant: ```c
lintyp(t) {
  switch (t) {
  case 0:
  case 1:
    return (0);
  case 2:
  case 3:
    return (1);
  case 6:
    return (2);
  default:
    return (3);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<lintyp>:
  endbr64
  cmp    $0x3,%edi
  jg     L11
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jg     L16
  cmp    $0x2,%edi
  sbb    %eax,%eax
  not    %eax
  and    $0x3,%eax
  ret
L11:
  cmp    $0x6,%edi
  setne  %al
  movzbl %al,%eax
  add    $0x2,%eax
L16:
  ret
```

assistant: ```c
lintyp(t) {
  switch (t) {
  case 0:
  case 1:
    return (0);
  case 2:
  case 3:
    return (1);
  case 6:
    return (2);
  default:
    return (3);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lintyp>:
  endbr64
  mov    $0x3,%eax
  cmp    $0x6,%edi
  ja     L0
  mov    %edi,%edi
  lea    D6(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: 

assistant: ```c
lintyp(t) {
  switch (t) {
  case 0:
  case 1:
    return (0);
  case 2:
  case 3:
    return (1);
  case 6:
    return (2);
  default:
    return (3);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lintyp>:
  endbr64
  mov    $0x3,%eax
  cmp    $0x6,%edi
  ja     L8
  mov    %edi,%edi
  lea    D6(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L8:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: 

assistant: ```c
lintyp(t) {
  switch (t) {
  case 0:
  case 1:
    return (0);
  case 2:
  case 3:
    return (1);
  case 6:
    return (2);
  default:
    return (3);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D18
type_infered: string

tool: D7: ls


tool: D18: echo hello


assistant: ```c
int main(int argc, char *argv[]) {
  printf("ls\n");
  printf("echo hello\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D12: ls


tool: D1: echo hello


assistant: ```c
int main(int argc, char *argv[]) {
  printf("ls\n");
  printf("echo hello\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D1: ls


tool: D13: echo hello


assistant: ```c
int main(int argc, char *argv[]) {
  printf("ls\n");
  printf("echo hello\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D0: ls


tool: D5: echo hello


assistant: ```c
int main(int argc, char *argv[]) {
  printf("ls\n");
  printf("echo hello\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L12
L23:
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L23
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type: string
name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D22
type: string

tool: D17: Que numero triangular quieres: 

tool: D12: %i

tool: D22: Numero triangular %i es %i


assistant: ```c
int main(void) {
  int n, numero, numeroTriangular;
  printf("Que numero triangular quieres: ");
  scanf("%i", &numero);
  numeroTriangular = 0;
  for (n = 1; n <= numero; n++) {
    numeroTriangular += n;
  }
  printf("Numero triangular %i es %i\n", numero, numeroTriangular);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L32
  lea    0x1(%rsi),%ecx
  mov    $0x0,%edx
  mov    $0x1,%eax
L36:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%ecx
  jne    L36
L31:
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L32:
  mov    $0x0,%edx
  jmp    L31
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D21
type_guessed: string
name: extract_symbolic_data
arguments: label: D27
type_guessed: string

tool: D29: Que numero triangular quieres: 

tool: D21: %i

tool: D27: Numero triangular %i es %i


assistant: ```c
int main(void) {
  int n, numero, numeroTriangular;
  printf("Que numero triangular quieres: ");
  scanf("%i", &numero);
  numeroTriangular = 0;
  for (n = 1; n <= numero; n++) {
    numeroTriangular += n;
  }
  printf("Numero triangular %i es %i\n", numero, numeroTriangular);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L12
  lea    0x1(%rsi),%ecx
  xor    %edx,%edx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L36:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%ecx
  jne    L36
L21:
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  xor    %edx,%edx
  jmp    L21
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D10
type: string
name: parse_data
arguments: tag: D20
type: string

tool: D2: Que numero triangular quieres: 

tool: D10: %i

tool: D20: Numero triangular %i es %i


assistant: ```c
int main(void) {
  int n, numero, numeroTriangular;
  printf("Que numero triangular quieres: ");
  scanf("%i", &numero);
  numeroTriangular = 0;
  for (n = 1; n <= numero; n++) {
    numeroTriangular += n;
  }
  printf("Numero triangular %i es %i\n", numero, numeroTriangular);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L84
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  jbe    L97
  mov    %esi,%edx
  movdqa D11(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D47(%rip),%xmm3
  shr    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L100:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L100
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  lea    0x1(%rcx),%eax
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%edx
  cmp    %ecx,%esi
  je     L60
L119:
  lea    0x1(%rax),%ecx
  add    %eax,%edx
  cmp    %esi,%ecx
  jg     L60
  add    %ecx,%edx
  lea    0x2(%rax),%ecx
  cmp    %ecx,%esi
  jl     L60
  add    %ecx,%edx
  lea    0x3(%rax),%ecx
  cmp    %ecx,%esi
  jl     L60
  add    %ecx,%edx
  lea    0x4(%rax),%ecx
  cmp    %ecx,%esi
  jl     L60
  add    %ecx,%edx
  lea    0x5(%rax),%ecx
  cmp    %ecx,%esi
  jl     L60
  add    %ecx,%edx
  lea    0x6(%rax),%ecx
  cmp    %ecx,%esi
  jl     L60
  add    %ecx,%edx
  lea    0x7(%rax),%ecx
  cmp    %ecx,%esi
  jl     L60
  add    %ecx,%edx
  lea    0x8(%rax),%ecx
  cmp    %ecx,%esi
  jl     L60
  add    $0x9,%eax
  add    %ecx,%edx
  cmp    %eax,%esi
  jl     L60
  add    %eax,%edx
L60:
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L84:
  xor    %edx,%edx
  jmp    L60
L97:
  xor    %edx,%edx
  mov    $0x1,%eax
  jmp    L119
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D23
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D11
type_guessed: byte[16]
name: parse_data
arguments: tag: D47
type_guessed: byte[16]
name: parse_data
arguments: tag: D28
type_guessed: string

tool: D23: Que numero triangular quieres: 

tool: D8: %i

tool: {"D11": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D47": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D28: Numero triangular %i es %i


assistant: ```c
int main(void) {
  int n, numero, numeroTriangular;
  printf("Que numero triangular quieres: ");
  scanf("%i", &numero);
  numeroTriangular = 0;
  for (n = 1; n <= numero; n++) {
    numeroTriangular += n;
  }
  printf("Numero triangular %i es %i\n", numero, numeroTriangular);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_parse_ulong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x0,%eax
  jmp    L21
L2:
  mov    -0x18(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L56
  mov    -0x18(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L48
L56:
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L21
L48:
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string

tool: D13: (nil)

tool: D11: (null)

assistant: ```c
bool check_parse_ulong(const char *number, unsigned long *result) {
  char *endptr;
  if (strlen(number) == 0)
    return false;
  if (strcmp(number, "(nil)") == 0 || strcmp(number, "(null)") == 0) {
    *result = 0;
    return true;
  }
  *result = strtoul(number, &endptr, 0);
  return *endptr == '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_parse_ulong>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L8
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D12(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
L52:
  movq   $0x0,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L1
L29:
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L52
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <strtoul@plt>
  mov    %rax,0x0(%rbp)
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  sete   %al
  movzbl %al,%eax
  jmp    L1
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D12: (nil)

tool: D8: (null)

assistant: ```c
bool check_parse_ulong(const char *number, unsigned long *result) {
  char *endptr;
  if (strlen(number) == 0)
    return false;
  if (strcmp(number, "(nil)") == 0 || strcmp(number, "(null)") == 0) {
    *result = 0;
    return true;
  }
  *result = strtoul(number, &endptr, 0);
  return *endptr == '\0';
}
```