ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L12
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    D26(%rip),%r12
  lea    D25(%rip),%r13
  jmp    L8
  nop
L56:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L23
L8:
  mov    (%rbx),%rdi
  call   <find_pname@plt>
  mov    (%rbx),%rsi
  mov    %eax,%edx
  cmp    $0xffffffff,%eax
  jne    L56
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L8
L23:
  xor    %eax,%eax
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    (%rsi),%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L44
```

tool_calls: name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D9
type: string

tool: D26: %s: %d


tool: D25: %s: not found


tool: D9: usage: %s pname1 pname2 ...


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("usage: %s pname1 pname2 ...\n", argv[0]);
    return 1;
  }
  int i;
  for (i = 1; i < argc; ++i) {
    pid_t pid = find_pname(argv[i]);
    if (pid == -1) {
      printf("%s: not found\n", argv[i]);
    } else {
      printf("%s: %d\n", argv[i], pid);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L54
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    D0(%rip),%r12
  lea    D4(%rip),%r13
  jmp    L22
  nop
L25:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L2
L22:
  mov    (%rbx),%rdi
  call   <find_pname@plt>
  mov    (%rbx),%rsi
  mov    %eax,%edx
  cmp    $0xffffffff,%eax
  jne    L25
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L22
L2:
  xor    %eax,%eax
L59:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  mov    (%rsi),%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L59
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D27
type_guessed: string

tool: D0: %s: %d


tool: D4: %s: not found


tool: D27: usage: %s pname1 pname2 ...


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("usage: %s pname1 pname2 ...\n", argv[0]);
    return 1;
  }
  int i;
  for (i = 1; i < argc; ++i) {
    pid_t pid = find_pname(argv[i]);
    if (pid == -1) {
      printf("%s: not found\n", argv[i]);
    } else {
      printf("%s: %d\n", argv[i], pid);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<list_passwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L15:
  mov    $0x0,%eax
  call   <getpwent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <prt_passwd@plt>
  jmp    L15
L8:
  nop
  mov    $0x0,%eax
  call   <endpwent@plt>
  nop
  leave
  ret
```

assistant: ```c
void list_passwd() {
  struct passwd *pw;
  while (1) {
    pw = getpwent();
    if (pw == NULL)
      break;
    prt_passwd(pw);
  }
  endpwent();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<list_passwd>:
  endbr64
  sub    $0x8,%rsp
  jmp    L19
L12:
  mov    %rax,%rdi
  call   <prt_passwd@plt>
L19:
  mov    $0x0,%eax
  call   <getpwent@plt>
  test   %rax,%rax
  jne    L12
  mov    $0x0,%eax
  call   <endpwent@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void list_passwd() {
  struct passwd *pw;
  while (1) {
    pw = getpwent();
    if (pw == NULL)
      break;
    prt_passwd(pw);
  }
  endpwent();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<list_passwd>:
  endbr64
  sub    $0x8,%rsp
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rax,%rdi
  call   <prt_passwd@plt>
L13:
  xor    %eax,%eax
  call   <getpwent@plt>
  test   %rax,%rax
  jne    L10
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <endpwent@plt>
```

assistant: ```c
void list_passwd() {
  struct passwd *pw;
  while (1) {
    pw = getpwent();
    if (pw == NULL)
      break;
    prt_passwd(pw);
  }
  endpwent();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<list_passwd>:
  endbr64
  sub    $0x8,%rsp
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rax,%rdi
  call   <prt_passwd@plt>
L8:
  xor    %eax,%eax
  call   <getpwent@plt>
  test   %rax,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <endpwent@plt>
```

assistant: ```c
void list_passwd() {
  struct passwd *pw;
  while (1) {
    pw = getpwent();
    if (pw == NULL)
      break;
    prt_passwd(pw);
  }
  endpwent();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<are_4at_in_one_plane>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  movsd  %xmm0,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x70(%rbp)
  jmp    L15
L48:
  movl   $0x0,-0x6c(%rbp)
  mov    -0x6c(%rbp),%eax
  mov    %eax,-0x74(%rbp)
  jmp    L35
L75:
  mov    -0x74(%rbp),%eax
  cmp    -0x70(%rbp),%eax
  je     L70
  lea    -0x50(%rbp),%rcx
  mov    -0x6c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x70(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  shl    $0x3,%rax
  mov    %rax,%rcx
  mov    -0x88(%rbp),%rax
  add    %rax,%rcx
  mov    -0x74(%rbp),%eax
  movslq %eax,%rsi
  mov    %rsi,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x3,%rax
  mov    %rax,%rsi
  mov    -0x88(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <diff3@plt>
  addl   $0x1,-0x6c(%rbp)
L70:
  addl   $0x1,-0x74(%rbp)
L35:
  cmpl   $0x3,-0x74(%rbp)
  jle    L75
  lea    -0x68(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <triple_prod_and_min_abs_sine@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x58(%rbp)
  cmpl   $0x0,-0x70(%rbp)
  je     L58
  movsd  -0x68(%rbp),%xmm1
  movsd  -0x60(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L2
L58:
  movsd  -0x68(%rbp),%xmm0
  movsd  %xmm0,-0x60(%rbp)
L2:
  addl   $0x1,-0x70(%rbp)
L15:
  cmpl   $0x3,-0x70(%rbp)
  jle    L48
  movsd  -0x90(%rbp),%xmm0
  comisd -0x60(%rbp),%xmm0
  setae  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int are_4at_in_one_plane(double at_coord[][3], double min_sine) {
  double actual_min_sine, min_actual_min_sine;
  double coord[3][3], prod;
  int i, k, j;
  for (k = 0; k < 4; k++) {
    for (i = j = 0; i < 4; i++) {
      if (i != k) {
        diff3(at_coord[i], at_coord[k], coord[j]);
        j++;
      }
    }
    prod = triple_prod_and_min_abs_sine(coord, &actual_min_sine);
    if (!k || actual_min_sine < min_actual_min_sine) {
      min_actual_min_sine = actual_min_sine;
    }
  }
  return min_actual_min_sine <= min_sine;
}
```
user: Translate the below assembly code into C programming language:

```asm
<are_4at_in_one_plane>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,0x10(%rsp)
  movsd  %xmm0,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  lea    0x30(%rsp),%r14
  jmp    L45
L27:
  add    $0x1,%ebx
  add    $0x18,%rbp
  cmp    $0x4,%ebx
  je     L34
L81:
  cmp    %r12d,%ebx
  je     L27
  movslq %r13d,%rax
  lea    (%rax,%rax,2),%rax
  lea    (%r14,%rax,8),%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <diff3@plt>
  add    $0x1,%r13d
  jmp    L27
L34:
  lea    0x28(%rsp),%rsi
  mov    %r14,%rdi
  call   <triple_prod_and_min_abs_sine@plt>
  cmpl   $0x0,0x4(%rsp)
  je     L78
  movsd  0x8(%rsp),%xmm2
  comisd 0x28(%rsp),%xmm2
  jbe    L75
L78:
  movsd  0x28(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
L75:
  add    $0x1,%r12
  cmp    $0x4,%r12
  je     L55
L45:
  mov    0x10(%rsp),%rcx
  mov    %rcx,%rbp
  lea    (%r12,%r12,2),%rax
  lea    (%rcx,%rax,8),%r15
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  mov    %r12d,0x4(%rsp)
  jmp    L81
L55:
  movsd  0x18(%rsp),%xmm3
  comisd 0x8(%rsp),%xmm3
  setae  %al
  movzbl %al,%eax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L51
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int are_4at_in_one_plane(double at_coord[][3], double min_sine) {
  double actual_min_sine, min_actual_min_sine;
  double coord[3][3], prod;
  int i, k, j;
  for (k = 0; k < 4; k++) {
    for (i = j = 0; i < 4; i++) {
      if (i != k) {
        diff3(at_coord[i], at_coord[k], coord[j]);
        j++;
      }
    }
    prod = triple_prod_and_min_abs_sine(coord, &actual_min_sine);
    if (!k || actual_min_sine < min_actual_min_sine) {
      min_actual_min_sine = actual_min_sine;
    }
  }
  return min_actual_min_sine <= min_sine;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<are_4at_in_one_plane>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,0x18(%rsp)
  lea    0x40(%rsp),%rbp
  movsd  %xmm0,0x28(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x38(%rsp),%rax
  mov    %rax,0x20(%rsp)
L22:
  mov    0x18(%rsp),%rcx
  mov    %r14d,0xc(%rsp)
  lea    (%r14,%r14,2),%rax
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  mov    %rcx,%r15
  lea    (%rcx,%rax,8),%r12
L27:
  cmp    %ebx,%r14d
  je     L30
  movslq %r13d,%rax
  mov    %r12,%rsi
  mov    %r15,%rdi
  add    $0x1,%r13d
  lea    (%rax,%rax,2),%rax
  lea    0x0(%rbp,%rax,8),%rdx
  call   <diff3@plt>
L30:
  add    $0x1,%ebx
  add    $0x18,%r15
  cmp    $0x4,%ebx
  jne    L27
  mov    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <triple_prod_and_min_abs_sine@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L25
  movsd  0x10(%rsp),%xmm2
  comisd 0x38(%rsp),%xmm2
  jbe    L39
L25:
  movsd  0x38(%rsp),%xmm1
  movsd  %xmm1,0x10(%rsp)
L39:
  add    $0x1,%r14
  cmp    $0x4,%r14
  jne    L22
  xor    %eax,%eax
  movsd  0x28(%rsp),%xmm3
  comisd 0x10(%rsp),%xmm3
  setae  %al
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int are_4at_in_one_plane(double at_coord[][3], double min_sine) {
  double actual_min_sine, min_actual_min_sine;
  double coord[3][3], prod;
  int i, k, j;
  for (k = 0; k < 4; k++) {
    for (i = j = 0; i < 4; i++) {
      if (i != k) {
        diff3(at_coord[i], at_coord[k], coord[j]);
        j++;
      }
    }
    prod = triple_prod_and_min_abs_sine(coord, &actual_min_sine);
    if (!k || actual_min_sine < min_actual_min_sine) {
      min_actual_min_sine = actual_min_sine;
    }
  }
  return min_actual_min_sine <= min_sine;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<are_4at_in_one_plane>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,0x18(%rsp)
  lea    0x40(%rsp),%rbp
  movsd  %xmm0,0x28(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x38(%rsp),%rax
  mov    %rax,0x20(%rsp)
L74:
  mov    0x18(%rsp),%rcx
  mov    %r14d,0xc(%rsp)
  lea    (%r14,%r14,2),%rax
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  mov    %rcx,%r15
  lea    (%rcx,%rax,8),%r12
L19:
  cmp    %ebx,%r14d
  je     L69
  movslq %r13d,%rax
  mov    %r15,%rdi
  mov    %r12,%rsi
  add    $0x1,%ebx
  lea    (%rax,%rax,2),%rax
  add    $0x1,%r13d
  add    $0x18,%r15
  lea    0x0(%rbp,%rax,8),%rdx
  call   <diff3@plt>
  cmp    $0x4,%ebx
  jne    L19
L29:
  mov    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <triple_prod_and_min_abs_sine@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L5
  movsd  0x10(%rsp),%xmm2
  comisd 0x38(%rsp),%xmm2
  jbe    L4
L5:
  movsd  0x38(%rsp),%xmm1
  movsd  %xmm1,0x10(%rsp)
L4:
  add    $0x1,%r14
  cmp    $0x4,%r14
  jne    L74
  xor    %eax,%eax
  movsd  0x28(%rsp),%xmm3
  comisd 0x10(%rsp),%xmm3
  setae  %al
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L73
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  add    $0x1,%ebx
  add    $0x18,%r15
  cmp    $0x4,%ebx
  jne    L19
  jmp    L29
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int are_4at_in_one_plane(double at_coord[][3], double min_sine) {
  double actual_min_sine, min_actual_min_sine;
  double coord[3][3], prod;
  int i, k, j;
  for (k = 0; k < 4; k++) {
    for (i = j = 0; i < 4; i++) {
      if (i != k) {
        diff3(at_coord[i], at_coord[k], coord[j]);
        j++;
      }
    }
    prod = triple_prod_and_min_abs_sine(coord, &actual_min_sine);
    if (!k || actual_min_sine < min_actual_min_sine) {
      min_actual_min_sine = actual_min_sine;
    }
  }
  return min_actual_min_sine <= min_sine;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L8
L41:
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L30:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L19
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L19:
  addq   $0x4,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L30
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  neg    %rax
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L41
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int i, j, temp;
  for (i = 1; i < n; i++) {
    for (j = 0; j < n - i; j++) {
      if (*number > *(number + 1)) {
        temp = *number;
        *number = *(number + 1);
        *(number + 1) = temp;
      }
      number++;
    }
    number -= n - i;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L50
  movslq %esi,%rax
  neg    %rax
  lea    0x4(,%rax,4),%r8
  sub    $0x2,%esi
  jmp    L21
L49:
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  je     L38
L10:
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  cmp    %edx,%eax
  jle    L49
  mov    %edx,(%rdi)
  mov    %eax,0x4(%rdi)
  jmp    L49
L38:
  lea    (%rcx,%r8,1),%rdi
  add    $0x4,%r8
  sub    $0x1,%esi
  cmp    $0xffffffff,%esi
  je     L50
L21:
  lea    0x1(%rsi),%eax
  mov    %esi,%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  test   %eax,%eax
  jg     L10
  mov    %rdi,%rcx
  jmp    L38
L50:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int i, j, temp;
  for (i = 1; i < n; i++) {
    for (j = 0; j < n - i; j++) {
      if (*number > *(number + 1)) {
        temp = *number;
        *number = *(number + 1);
        *(number + 1) = temp;
      }
      number++;
    }
    number -= n - i;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L2
  lea    -0x2(%rsi),%r8d
  movslq %esi,%rsi
  neg    %rsi
  lea    0x4(,%rsi,4),%rsi
  nopl   0x0(%rax,%rax,1)
L16:
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  cmp    %edx,%eax
  jle    L33
  mov    %edx,(%rdi)
  mov    %eax,0x4(%rdi)
L33:
  add    $0x4,%rdi
  cmp    %rdi,%rcx
  jne    L5
  sub    $0x1,%r8d
  add    %rsi,%rdi
  add    $0x4,%rsi
  cmp    $0xffffffff,%r8d
  jne    L16
L2:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int i, j, temp;
  for (i = 1; i < n; i++) {
    for (j = 0; j < n - i; j++) {
      if (*number > *(number + 1)) {
        temp = *number;
        *number = *(number + 1);
        *(number + 1) = temp;
      }
      number++;
    }
    number -= n - i;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L27
  lea    -0x2(%rsi),%r8d
  movslq %esi,%rsi
  neg    %rsi
  lea    0x4(,%rsi,4),%rsi
  nopl   0x0(%rax,%rax,1)
L29:
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L28:
  movq   (%rdi),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%edx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%edx
  jle    L9
  movq   %xmm1,(%rdi)
L9:
  add    $0x4,%rdi
  cmp    %rdi,%rcx
  jne    L28
  sub    $0x1,%r8d
  add    %rsi,%rdi
  add    $0x4,%rsi
  cmp    $0xffffffff,%r8d
  jne    L29
L27:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int i, j, temp;
  for (i = 1; i < n; i++) {
    for (j = 0; j < n - i; j++) {
      if (*number > *(number + 1)) {
        temp = *number;
        *number = *(number + 1);
        *(number + 1) = temp;
      }
      number++;
    }
    number -= n - i;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D121(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x9,%eax
  ja     L7
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D72(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D72(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D120(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D121
data_type: string
name: read_data
arguments: data_tag: D52
data_type: string
name: read_data
arguments: data_tag: D36
data_type: string
name: read_data
arguments: data_tag: D120
data_type: string
name: read_data
arguments: data_tag: D91
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D62
data_type: string
name: read_data
arguments: data_tag: D68
data_type: string
name: read_data
arguments: data_tag: D51
data_type: string
name: read_data
arguments: data_tag: D79
data_type: string
name: read_data
arguments: data_tag: D22
data_type: string

tool: D121: %d

tool: D52: 
zero

tool: D36: 
one

tool: D120: 
two

tool: D91: 
three

tool: D11: 
four

tool: D62: 
five

tool: D68: 
six

tool: D51: 
seven

tool: D79: 
eight

tool: D22: 
nine

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  switch (n) {
  case 0:
    printf("\nzero");
    break;
  case 1:
    printf("\none");
    break;
  case 2:
    printf("\ntwo");
    break;
  case 3:
    printf("\nthree");
    break;
  case 4:
    printf("\nfour");
    break;
  case 5:
    printf("\nfive");
    break;
  case 6:
    printf("\nsix");
    break;
  case 7:
    printf("\nseven");
    break;
  case 8:
    printf("\neight");
    break;
  case 9:
    printf("\nnine");
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L90
  mov    0x4(%rsp),%eax
  lea    D117(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D54(%rip),%rdi
  call   <printf@plt>
L90:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D118(%rip),%rdi
  call   <printf@plt>
  jmp    L90
  lea    D102(%rip),%rdi
  call   <printf@plt>
  jmp    L90
  lea    D52(%rip),%rdi
  call   <printf@plt>
  jmp    L90
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L90
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L90
  lea    D72(%rip),%rdi
  call   <printf@plt>
  jmp    L90
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L90
  lea    D98(%rip),%rdi
  call   <printf@plt>
  jmp    L90
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L90
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D54
datatype: string
name: retrieve_data
arguments: data_tag: D118
datatype: string
name: retrieve_data
arguments: data_tag: D102
datatype: string
name: retrieve_data
arguments: data_tag: D52
datatype: string
name: retrieve_data
arguments: data_tag: D34
datatype: string
name: retrieve_data
arguments: data_tag: D15
datatype: string
name: retrieve_data
arguments: data_tag: D72
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D98
datatype: string
name: retrieve_data
arguments: data_tag: D51
datatype: string

tool: D12: %d

tool: D54: 
zero

tool: D118: 
one

tool: D102: 
two

tool: D52: 
three

tool: D34: 
four

tool: D15: 
five

tool: D72: 
six

tool: D5: 
seven

tool: D98: 
eight

tool: D51: 
nine

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  switch (n) {
  case 0:
    printf("\nzero");
    break;
  case 1:
    printf("\none");
    break;
  case 2:
    printf("\ntwo");
    break;
  case 3:
    printf("\nthree");
    break;
  case 4:
    printf("\nfour");
    break;
  case 5:
    printf("\nfive");
    break;
  case 6:
    printf("\nsix");
    break;
  case 7:
    printf("\nseven");
    break;
  case 8:
    printf("\neight");
    break;
  case 9:
    printf("\nnine");
    break;
  }
}
```