user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  lea    D36(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0x8(%rsp)
  lea    0xc(%rsp),%r12
  movabs $0x53202e412064655a,%rax
  mov    %rax,0xc(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  movl   $0x776168,0x14(%rsp)
  call   <printf@plt>
  mov    $0x14,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D70(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xa,%esi
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D84(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  lea    D71(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D36
type_infered: string
name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D70
type_infered: string
name: parse_data
arguments: data_tag: D32
type_infered: string
name: parse_data
arguments: data_tag: D37
type_infered: string
name: parse_data
arguments: data_tag: D84
type_infered: string
name: parse_data
arguments: data_tag: D45
type_infered: string
name: parse_data
arguments: data_tag: D54
type_infered: string
name: parse_data
arguments: data_tag: D71
type_infered: string
name: parse_data
arguments: data_tag: D49
type_infered: string
name: parse_data
arguments: data_tag: D29
type_infered: string

tool: D36: The size of an int is %ld


tool: D13: The size of areas (int[]): %ld


tool: D70: The number of ints in areas: %ld


tool: D32: The first area is %d, the 2nd is %d.


tool: D37: The size of char: %ld


tool: D84: The size of name (char[]): %ld


tool: D45: The number of chars in name: %ld


tool: D54: The size of full_name (char[]): %ld


tool: D71: The number of chars in full_name is %ld


tool: D49: name = "%s" and full_name = "%s"


tool: D29: name = %s, full name is %s


assistant: ```c
int main(int argc, char *argv[]) {
  int areas[] = {10, 12, 13, 14, 20};
  char name[] = "Zed";
  char full_name[] = {'Z', 'e', 'd', ' ', 'A', '.', ' ', 'S', 'h', 'a', 'w', '\0'};
  printf("The size of an int is %ld\n", sizeof(int));
  printf("The size of areas (int[]): %ld\n", sizeof(areas));
  printf("The number of ints in areas: %ld\n", sizeof(areas) / sizeof(int));
  printf("The first area is %d, the 2nd is %d.\n", areas[0], areas[1]);
  printf("The size of char: %ld\n", sizeof(char));
  printf("The size of name (char[]): %ld\n", sizeof(name));
  printf("The number of chars in name: %ld\n", sizeof(name) / sizeof(char));
  printf("The size of full_name (char[]): %ld\n", sizeof(full_name));
  printf("The number of chars in full_name is %ld\n", sizeof(full_name) / sizeof(char));
  printf("name = \"%s\" and full_name = \"%s\"\n", name, full_name);
  printf("name = %s, full name is %s\n", name, full_name);
  return 0;
}
```