ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rand_dir>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <rand_num@plt>
  cmp    $0x2,%eax
  je     L39
  mov    %eax,%edx
  jg     L34
  mov    $0x7b,%eax
  test   %edx,%edx
  je     L47
  cmp    $0x1,%edx
  mov    $0xffffffff,%eax
  mov    $0x7d,%edx
  cmove  %edx,%eax
L47:
  add    $0x8,%rsp
  ret
L34:
  cmp    $0x3,%eax
  mov    $0xffffffff,%eax
  mov    $0x69,%edx
  cmove  %edx,%eax
  jmp    L47
L39:
  mov    $0x21,%eax
  jmp    L47
```

assistant: ```c
int rand_dir() {
  switch (rand_num(4)) {
  case 0:
    return '{';
  case 1:
    return '}';
  case 2:
    return '!';
  case 3:
    return 'i';
  }
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rand_dir>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <rand_num@plt>
  mov    $0xffffffff,%r8d
  cmp    $0x3,%eax
  ja     L2
  mov    %eax,%eax
  lea    D5(%rip),%rdx
  mov    (%rdx,%rax,4),%r8d
L2:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: {

assistant: ```c
int rand_dir() {
  switch (rand_num(4)) {
  case 0:
    return '{';
  case 1:
    return '}';
  case 2:
    return '!';
  case 3:
    return 'i';
  }
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rand_dir>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <rand_num@plt>
  mov    $0xffffffff,%r8d
  cmp    $0x3,%eax
  ja     L2
  mov    %eax,%eax
  lea    D8(%rip),%rdx
  mov    (%rdx,%rax,4),%r8d
L2:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: {

assistant: ```c
int rand_dir() {
  switch (rand_num(4)) {
  case 0:
    return '{';
  case 1:
    return '}';
  case 2:
    return '!';
  case 3:
    return 'i';
  }
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_pyear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <parse@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int get_pyear(long day) {
  int y, m, d;
  parse(day, &y, &m, &d);
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_pyear>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <parse@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_pyear(long day) {
  int y, m, d;
  parse(day, &y, &m, &d);
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_pyear>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <parse@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_pyear(long day) {
  int y, m, d;
  parse(day, &y, &m, &d);
  return y;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_pyear>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <parse@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_pyear(long day) {
  int y, m, d;
  parse(day, &y, &m, &d);
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yahoo_f01_4c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  lea    D7(%rip),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <yahoo_M1ObfuscatedTableCommon@plt>
  leave
  ret
```

assistant: ```c
int yahoo_f01_4c(int Salt, int Parameter) {
  static unsigned char LUT[32] = {
      0x16, 0x02, 0x06, 0x0E, 0x0D, 0x1C, 0x08, 0x0A, 0x0F, 0x13, 0x0B, 0x18, 0x07, 0x04, 0x14, 0x01, 0x1B, 0x05, 0x17, 0x1E, 0x11, 0x1A, 0x10, 0x1F, 0x12, 0x19, 0x1D, 0x03, 0x0C, 0x00, 0x09, 0x15,
  };
  return yahoo_M1ObfuscatedTableCommon(Salt, Parameter, LUT);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yahoo_f01_4c>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdx
  call   <yahoo_M1ObfuscatedTableCommon@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yahoo_f01_4c(int Salt, int Parameter) {
  static unsigned char LUT[32] = {
      0x16, 0x02, 0x06, 0x0E, 0x0D, 0x1C, 0x08, 0x0A, 0x0F, 0x13, 0x0B, 0x18, 0x07, 0x04, 0x14, 0x01, 0x1B, 0x05, 0x17, 0x1E, 0x11, 0x1A, 0x10, 0x1F, 0x12, 0x19, 0x1D, 0x03, 0x0C, 0x00, 0x09, 0x15,
  };
  return yahoo_M1ObfuscatedTableCommon(Salt, Parameter, LUT);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<yahoo_f01_4c>:
  endbr64
  lea    D7(%rip),%rdx
  jmp    1050 <yahoo_M1ObfuscatedTableCommon@plt>
```

assistant: ```c
int yahoo_f01_4c(int Salt, int Parameter) {
  static unsigned char LUT[32] = {
      0x16, 0x02, 0x06, 0x0E, 0x0D, 0x1C, 0x08, 0x0A, 0x0F, 0x13, 0x0B, 0x18, 0x07, 0x04, 0x14, 0x01, 0x1B, 0x05, 0x17, 0x1E, 0x11, 0x1A, 0x10, 0x1F, 0x12, 0x19, 0x1D, 0x03, 0x0C, 0x00, 0x09, 0x15,
  };
  return yahoo_M1ObfuscatedTableCommon(Salt, Parameter, LUT);
}
```
user: What is the c source code of the assembly code below?

```asm
<yahoo_f01_4c>:
  endbr64
  lea    D4(%rip),%rdx
  jmp    1050 <yahoo_M1ObfuscatedTableCommon@plt>
```

assistant: ```c
int yahoo_f01_4c(int Salt, int Parameter) {
  static unsigned char LUT[32] = {
      0x16, 0x02, 0x06, 0x0E, 0x0D, 0x1C, 0x08, 0x0A, 0x0F, 0x13, 0x0B, 0x18, 0x07, 0x04, 0x14, 0x01, 0x1B, 0x05, 0x17, 0x1E, 0x11, 0x1A, 0x10, 0x1F, 0x12, 0x19, 0x1D, 0x03, 0x0C, 0x00, 0x09, 0x15,
  };
  return yahoo_M1ObfuscatedTableCommon(Salt, Parameter, LUT);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x1028(%rbp)
  movl   $0x0,-0x1038(%rbp)
  movl   $0x0,-0x1034(%rbp)
  movq   $0x0,-0x1030(%rbp)
  movq   $0x40000000,-0x1020(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,-0x1018(%rbp)
  movq   $0x0,-0x1010(%rbp)
  movq   $0x0,-0x1008(%rbp)
  lea    -0x1000(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1fe,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x1018(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x1028(%rbp)
  cmpq   $0x0,-0x1028(%rbp)
  jne    L37
  mov    $0x0,%eax
  jmp    L36
L37:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x1038(%rbp)
  jmp    L41
L9:
  mov    -0x1028(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  addq   $0x64,-0x1030(%rbp)
L41:
  mov    -0x1030(%rbp),%rax
  cmp    -0x1020(%rbp),%rax
  jl     L9
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x1034(%rbp)
  mov    -0x1034(%rbp),%eax
  sub    -0x1038(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
datatype: string
name: disassemble_data
arguments: tag: D5
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: string

tool: D11: aaa.txt

tool: D5: a+

tool: D2: >>>>>use %d second


assistant: ```c
int main(void) {
  FILE *fp = NULL;
  time_t prev = 0, cur = 0;
  uint64_t wrtsize = 0, totalsize = 1024 * 1024 * 1024;
  char *fname = "aaa.txt";
  char content[4096] = {0};
  fp = fopen(fname, "a+");
  if (fp == NULL)
    return 0;
  prev = time(NULL);
  while (wrtsize < totalsize) {
    fwrite(content, 1, 4096, fp);
    wrtsize += 100;
  }
  cur = time(NULL);
  printf(">>>>>use %d second\r\n", cur - prev);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x1fe,%ecx
  rep stos %rax,%es:(%rdi)
  lea    D0(%rip),%rsi
  lea    D21(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%r13d
  mov    $0xa3d70b,%ebx
  mov    %rsp,%r12
L4:
  mov    %rbp,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  sub    $0x1,%rbx
  jne    L4
  mov    $0x0,%edi
  call   <time@plt>
  sub    %r13d,%eax
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
L5:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string
name: parse_data
arguments: data_label: D21
data_type: string
name: parse_data
arguments: data_label: D13
data_type: string

tool: D0: a+

tool: D21: aaa.txt

tool: D13: >>>>>use %d second


assistant: ```c
int main(void) {
  FILE *fp = NULL;
  time_t prev = 0, cur = 0;
  uint64_t wrtsize = 0, totalsize = 1024 * 1024 * 1024;
  char *fname = "aaa.txt";
  char content[4096] = {0};
  fp = fopen(fname, "a+");
  if (fp == NULL)
    return 0;
  prev = time(NULL);
  while (wrtsize < totalsize) {
    fwrite(content, 1, 4096, fp);
    wrtsize += 100;
  }
  cur = time(NULL);
  printf(">>>>>use %d second\r\n", cur - prev);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1fe,%ecx
  pxor   %xmm0,%xmm0
  lea    D27(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    D26(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L24
  xor    %edi,%edi
  mov    %rax,%rbp
  mov    $0xa3d70b,%ebx
  mov    %rsp,%r12
  call   <time@plt>
  mov    %eax,%r13d
  nop
L3:
  mov    %rbp,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  sub    $0x1,%rbx
  jne    L3
  xor    %edi,%edi
  call   <time@plt>
  lea    D11(%rip),%rdi
  sub    %r13d,%eax
  mov    %eax,%esi
  call   <printf@plt>
L24:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x1018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D27: a+

tool: D26: aaa.txt

tool: D11: >>>>>use %d second


assistant: ```c
int main(void) {
  FILE *fp = NULL;
  time_t prev = 0, cur = 0;
  uint64_t wrtsize = 0, totalsize = 1024 * 1024 * 1024;
  char *fname = "aaa.txt";
  char content[4096] = {0};
  fp = fopen(fname, "a+");
  if (fp == NULL)
    return 0;
  prev = time(NULL);
  while (wrtsize < totalsize) {
    fwrite(content, 1, 4096, fp);
    wrtsize += 100;
  }
  cur = time(NULL);
  printf(">>>>>use %d second\r\n", cur - prev);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1fe,%ecx
  pxor   %xmm0,%xmm0
  lea    D10(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    D19(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L8
  xor    %edi,%edi
  mov    %rax,%rbp
  mov    $0xa3d70b,%ebx
  mov    %rsp,%r12
  call   <time@plt>
  mov    %eax,%r13d
  nop
L11:
  mov    %rbp,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  sub    $0x1,%rbx
  jne    L11
  xor    %edi,%edi
  call   <time@plt>
  lea    D20(%rip),%rdi
  sub    %r13d,%eax
  mov    %eax,%esi
  call   <printf@plt>
L8:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x1018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D20
datatype: string

tool: D10: a+

tool: D19: aaa.txt

tool: D20: >>>>>use %d second


assistant: ```c
int main(void) {
  FILE *fp = NULL;
  time_t prev = 0, cur = 0;
  uint64_t wrtsize = 0, totalsize = 1024 * 1024 * 1024;
  char *fname = "aaa.txt";
  char content[4096] = {0};
  fp = fopen(fname, "a+");
  if (fp == NULL)
    return 0;
  prev = time(NULL);
  while (wrtsize < totalsize) {
    fwrite(content, 1, 4096, fp);
    wrtsize += 100;
  }
  cur = time(NULL);
  printf(">>>>>use %d second\r\n", cur - prev);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D4(%rip),%rax
  movq   $0x0,(%rax)
  mov    $0xffffffff,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  call   <do_not_optimize_away@plt>
L3:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  void *p;
  errno = 0;
  p = malloc(-1);
  if (errno != 0)
    do_not_optimize_away();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
  movq   $0x0,(%rbx)
  mov    $0xffffffff,%edi
  call   <malloc@plt>
  cmpq   $0x0,(%rbx)
  jne    L3
L5:
  mov    $0x0,%eax
  pop    %rbx
  ret
L3:
  mov    $0x0,%eax
  call   <do_not_optimize_away@plt>
  jmp    L5
```

assistant: ```c
int main() {
  void *p;
  errno = 0;
  p = malloc(-1);
  if (errno != 0)
    do_not_optimize_away();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D3(%rip),%rbx
  mov    $0xffffffff,%edi
  movq   $0x0,(%rbx)
  call   <malloc@plt>
  cmpq   $0x0,(%rbx)
  jne    L19
L0:
  xor    %eax,%eax
  pop    %rbx
  ret
L19:
  xor    %eax,%eax
  call   <do_not_optimize_away@plt>
  jmp    L0
```

assistant: ```c
int main() {
  void *p;
  errno = 0;
  p = malloc(-1);
  if (errno != 0)
    do_not_optimize_away();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
  mov    $0xffffffff,%edi
  movq   $0x0,(%rbx)
  call   <malloc@plt>
  cmpq   $0x0,(%rbx)
  jne    L0
L6:
  xor    %eax,%eax
  pop    %rbx
  ret
L0:
  xor    %eax,%eax
  call   <do_not_optimize_away@plt>
  jmp    L6
```

assistant: ```c
int main() {
  void *p;
  errno = 0;
  p = malloc(-1);
  if (errno != 0)
    do_not_optimize_away();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPrefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L13
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L26
  mov    $0x0,%eax
  jmp    L5
L26:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int isPrefix(const char *s, const char *pref) {
  while (*pref) {
    if (*pref != *s)
      return 0;
    pref++;
    s++;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isPrefix>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L2
  mov    $0x0,%eax
L0:
  cmp    %dl,(%rdi,%rax,1)
  jne    L22
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L0
  mov    $0x1,%eax
  ret
L2:
  mov    $0x1,%eax
  ret
L22:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isPrefix(const char *s, const char *pref) {
  while (*pref) {
    if (*pref != *s)
      return 0;
    pref++;
    s++;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isPrefix>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L22
  xor    %eax,%eax
  jmp    L34
  nop
L39:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L22
L34:
  cmp    %dl,(%rdi,%rax,1)
  je     L39
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L22:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isPrefix(const char *s, const char *pref) {
  while (*pref) {
    if (*pref != *s)
      return 0;
    pref++;
    s++;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPrefix>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L8
  xor    %eax,%eax
  jmp    L30
  nop
L11:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L8
L30:
  cmp    %dl,(%rdi,%rax,1)
  je     L11
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isPrefix(const char *s, const char *pref) {
  while (*pref) {
    if (*pref != *s)
      return 0;
    pref++;
    s++;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uintpow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L7
L19:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x18(%rbp)
L7:
  cmpl   $0x0,-0x18(%rbp)
  jne    L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int uintpow(unsigned int base, unsigned int exp) {
  unsigned int x = 1;
  while (exp) {
    x = x * base;
    exp--;
  }
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uintpow>:
  endbr64
  test   %esi,%esi
  je     L13
  mov    $0x1,%eax
L15:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L15
  ret
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int uintpow(unsigned int base, unsigned int exp) {
  unsigned int x = 1;
  while (exp) {
    x = x * base;
    exp--;
  }
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<uintpow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L17
  nopl   (%rax)
L9:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L9
  ret
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
unsigned int uintpow(unsigned int base, unsigned int exp) {
  unsigned int x = 1;
  while (exp) {
    x = x * base;
    exp--;
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uintpow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L7
  nopl   (%rax)
L8:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L8
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
unsigned int uintpow(unsigned int base, unsigned int exp) {
  unsigned int x = 1;
  while (exp) {
    x = x * base;
    exp--;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L22
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  jmp    L21
L22:
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <show_stat_info@plt>
L21:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
extern void do_stat(char *filename) {
  struct stat stat_buf;
  if ((stat(filename, &stat_buf) == -1)) {
    perror(filename);
    exit(EXIT_FAILURE);
  } else {
    show_stat_info(filename, &stat_buf);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_stat>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L23
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <show_stat_info@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L23:
  mov    %rbx,%rdi
  call   <perror@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L3
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void do_stat(char *filename) {
  struct stat stat_buf;
  if ((stat(filename, &stat_buf) == -1)) {
    perror(filename);
    exit(EXIT_FAILURE);
  } else {
    show_stat_info(filename, &stat_buf);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_stat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L18
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <show_stat_info@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L1
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void do_stat(char *filename) {
  struct stat stat_buf;
  if ((stat(filename, &stat_buf) == -1)) {
    perror(filename);
    exit(EXIT_FAILURE);
  } else {
    show_stat_info(filename, &stat_buf);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_stat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <show_stat_info@plt>
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L11
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void do_stat(char *filename) {
  struct stat stat_buf;
  if ((stat(filename, &stat_buf) == -1)) {
    perror(filename);
    exit(EXIT_FAILURE);
  } else {
    show_stat_info(filename, &stat_buf);
  }
}
```