ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<read_sudoku>:
  endbr64
  push   %r13
  movabs $0x3ff440000000000,%r13
  push   %r12
  lea    0x51(%rsi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L70:
  cmp    %rbx,%r12
  je     L41
L26:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    D6(%rip),%rdx
  cmp    %al,(%rdx)
  je     L41
  cmp    $0x39,%al
  jg     L71
  cmp    $0x29,%al
  jle    L70
  bt     %rax,%r13
  jae    L70
L3:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L26
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L71:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  cmp    $0x58,%dl
  jne    L70
  jmp    L3
```

assistant: ```c
void read_sudoku(FILE *in, char *read_input) {
  char ch;
  int n = 0;
  while (n < 81 && (ch = fgetc(in)) != EOF) {
    if ((ch >= '0' && ch <= '9') || ch == '*' || ch == '.' || ch == 'x' || ch == 'X') {
      read_input[n++] = ch;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_sudoku>:
  endbr64
  push   %r14
  lea    0x51(%rsi),%r14
  push   %r13
  movabs $0x3ff440000000000,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    %r14,%rbx
  je     L70
  nopl   (%rax)
L20:
  mov    D0(%rip),%rbp
L58:
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    %al,0x0(%rbp)
  je     L70
  cmp    $0x39,%al
  jg     L73
  cmp    $0x29,%al
  jle    L58
  bt     %rax,%r13
  jae    L58
L16:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L20
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L73:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  cmp    $0x58,%dl
  jne    L58
  jmp    L16
```

assistant: ```c
void read_sudoku(FILE *in, char *read_input) {
  char ch;
  int n = 0;
  while (n < 81 && (ch = fgetc(in)) != EOF) {
    if ((ch >= '0' && ch <= '9') || ch == '*' || ch == '.' || ch == 'x' || ch == 'X') {
      read_input[n++] = ch;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s20_quarterround>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ebx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    $0x7,%esi
  mov    %eax,%edi
  call   <rotl@plt>
  xor    %eax,%ebx
  mov    %ebx,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ebx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    $0x9,%esi
  mov    %eax,%edi
  call   <rotl@plt>
  xor    %eax,%ebx
  mov    %ebx,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%ebx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    $0xd,%esi
  mov    %eax,%edi
  call   <rotl@plt>
  xor    %eax,%ebx
  mov    %ebx,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%ebx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    $0x12,%esi
  mov    %eax,%edi
  call   <rotl@plt>
  mov    %ebx,%edx
  xor    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void s20_quarterround(uint32_t *y0, uint32_t *y1, uint32_t *y2, uint32_t *y3) {
  *y1 = *y1 ^ rotl(*y0 + *y3, 7);
  *y2 = *y2 ^ rotl(*y1 + *y0, 9);
  *y3 = *y3 ^ rotl(*y2 + *y1, 13);
  *y0 = *y0 ^ rotl(*y3 + *y2, 18);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<s20_quarterround>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    (%rsi),%ebp
  mov    (%rcx),%edi
  add    (%rbx),%edi
  mov    $0x7,%esi
  call   <rotl@plt>
  mov    %ebp,%edi
  xor    %eax,%edi
  mov    %edi,(%r14)
  mov    (%r12),%ebp
  add    (%rbx),%edi
  mov    $0x9,%esi
  call   <rotl@plt>
  mov    %ebp,%edi
  xor    %eax,%edi
  mov    %edi,(%r12)
  mov    0x0(%r13),%ebp
  add    (%r14),%edi
  mov    $0xd,%esi
  call   <rotl@plt>
  mov    %ebp,%edi
  xor    %eax,%edi
  mov    %edi,0x0(%r13)
  mov    (%rbx),%ebp
  add    (%r12),%edi
  mov    $0x12,%esi
  call   <rotl@plt>
  xor    %eax,%ebp
  mov    %ebp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void s20_quarterround(uint32_t *y0, uint32_t *y1, uint32_t *y2, uint32_t *y3) {
  *y1 = *y1 ^ rotl(*y0 + *y3, 7);
  *y2 = *y2 ^ rotl(*y1 + *y0, 9);
  *y3 = *y3 ^ rotl(*y2 + *y1, 13);
  *y0 = *y0 ^ rotl(*y3 + *y2, 18);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s20_quarterround>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rsi),%ebp
  mov    $0x7,%esi
  mov    (%rcx),%edi
  add    (%rbx),%edi
  call   <rotl@plt>
  mov    %ebp,%edi
  mov    $0x9,%esi
  xor    %eax,%edi
  mov    %edi,(%r14)
  mov    (%r12),%ebp
  add    (%rbx),%edi
  call   <rotl@plt>
  mov    %ebp,%edi
  mov    $0xd,%esi
  xor    %eax,%edi
  mov    %edi,(%r12)
  mov    0x0(%r13),%ebp
  add    (%r14),%edi
  call   <rotl@plt>
  mov    %ebp,%edi
  mov    $0x12,%esi
  xor    %eax,%edi
  mov    %edi,0x0(%r13)
  mov    (%rbx),%ebp
  add    (%r12),%edi
  call   <rotl@plt>
  xor    %eax,%ebp
  mov    %ebp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void s20_quarterround(uint32_t *y0, uint32_t *y1, uint32_t *y2, uint32_t *y3) {
  *y1 = *y1 ^ rotl(*y0 + *y3, 7);
  *y2 = *y2 ^ rotl(*y1 + *y0, 9);
  *y3 = *y3 ^ rotl(*y2 + *y1, 13);
  *y0 = *y0 ^ rotl(*y3 + *y2, 18);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<s20_quarterround>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rsi),%ebp
  mov    $0x7,%esi
  mov    (%rcx),%edi
  add    (%rbx),%edi
  call   <rotl@plt>
  mov    %ebp,%edi
  mov    $0x9,%esi
  xor    %eax,%edi
  mov    %edi,(%r14)
  mov    (%r12),%ebp
  add    (%rbx),%edi
  call   <rotl@plt>
  mov    %ebp,%edi
  mov    $0xd,%esi
  xor    %eax,%edi
  mov    %edi,(%r12)
  mov    0x0(%r13),%ebp
  add    (%r14),%edi
  call   <rotl@plt>
  mov    %ebp,%edi
  mov    $0x12,%esi
  xor    %eax,%edi
  mov    %edi,0x0(%r13)
  mov    (%rbx),%ebp
  add    (%r12),%edi
  call   <rotl@plt>
  xor    %eax,%ebp
  mov    %ebp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void s20_quarterround(uint32_t *y0, uint32_t *y1, uint32_t *y2, uint32_t *y3) {
  *y1 = *y1 ^ rotl(*y0 + *y3, 7);
  *y2 = *y2 ^ rotl(*y1 + *y0, 9);
  *y3 = *y3 ^ rotl(*y2 + *y1, 13);
  *y0 = *y0 ^ rotl(*y3 + *y2, 18);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(const int argc, const char *const *argv) {
  (void)argc;
  (void)argv;
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(const int argc, const char *const *argv) {
  (void)argc;
  (void)argv;
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(const int argc, const char *const *argv) {
  (void)argc;
  (void)argv;
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(const int argc, const char *const *argv) {
  (void)argc;
  (void)argv;
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<initialisiere_int_array_zufaellig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L5:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <liefere_ganze_zufallszahl@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L5
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void initialisiere_int_array_zufaellig(int array[], int laenge, int min, int max) {
  for (int i = 0; i < laenge; i++)
    array[i] = liefere_ganze_zufallszahl(min, max);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<initialisiere_int_array_zufaellig>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r13
L1:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <liefere_ganze_zufallszahl@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  ret
```

assistant: ```c
void initialisiere_int_array_zufaellig(int array[], int laenge, int min, int max) {
  for (int i = 0; i < laenge; i++)
    array[i] = liefere_ganze_zufallszahl(min, max);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<initialisiere_int_array_zufaellig>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r13
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%esi
  mov    %ebp,%edi
  add    $0x4,%rbx
  call   <liefere_ganze_zufallszahl@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
void initialisiere_int_array_zufaellig(int array[], int laenge, int min, int max) {
  for (int i = 0; i < laenge; i++)
    array[i] = liefere_ganze_zufallszahl(min, max);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initialisiere_int_array_zufaellig>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r13
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r12d,%esi
  mov    %ebp,%edi
  add    $0x4,%rbx
  call   <liefere_ganze_zufallszahl@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void initialisiere_int_array_zufaellig(int array[], int laenge, int min, int max) {
  for (int i = 0; i < laenge; i++)
    array[i] = liefere_ganze_zufallszahl(min, max);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pathncat2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pathncat@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pathncat@plt>
  leave
  ret
```

assistant: ```c
char *pathncat2(char *path0, const char *path1, const char *path2, size_t size) {
  pathncat(path0, path1, size);
  return pathncat(path0, path2, size);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pathncat2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %rcx,%rdx
  call   <pathncat@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <pathncat@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pathncat2(char *path0, const char *path1, const char *path2, size_t size) {
  pathncat(path0, path1, size);
  return pathncat(path0, path2, size);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pathncat2>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    %rcx,%rdx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <pathncat@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <pathncat@plt>
```

assistant: ```c
char *pathncat2(char *path0, const char *path1, const char *path2, size_t size) {
  pathncat(path0, path1, size);
  return pathncat(path0, path2, size);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pathncat2>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    %rcx,%rdx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <pathncat@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <pathncat@plt>
```

assistant: ```c
char *pathncat2(char *path0, const char *path1, const char *path2, size_t size) {
  pathncat(path0, path1, size);
  return pathncat(path0, path2, size);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_getc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L19:
  mov    $0x20215054,%edi
  call   <GET32@plt>
  and    $0x1,%eax
  test   %eax,%eax
  jne    L6
  jmp    L19
L6:
  nop
  mov    $0x20215040,%edi
  call   <GET32@plt>
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int uart_getc(void) {
  while (1) {
    if (GET32(0x20215054) & 0x01) {
      break;
    }
  }
  return (GET32(0x20215040) & 0xFF);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uart_getc>:
  endbr64
  sub    $0x8,%rsp
L5:
  mov    $0x20215054,%edi
  call   <GET32@plt>
  test   $0x1,%al
  je     L5
  mov    $0x20215040,%edi
  call   <GET32@plt>
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int uart_getc(void) {
  while (1) {
    if (GET32(0x20215054) & 0x01) {
      break;
    }
  }
  return (GET32(0x20215040) & 0xFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_getc>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x20215054,%edi
  call   <GET32@plt>
  test   $0x1,%al
  je     L1
  mov    $0x20215040,%edi
  call   <GET32@plt>
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
unsigned int uart_getc(void) {
  while (1) {
    if (GET32(0x20215054) & 0x01) {
      break;
    }
  }
  return (GET32(0x20215040) & 0xFF);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uart_getc>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x20215054,%edi
  call   <GET32@plt>
  test   $0x1,%al
  je     L6
  mov    $0x20215040,%edi
  call   <GET32@plt>
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
unsigned int uart_getc(void) {
  while (1) {
    if (GET32(0x20215054) & 0x01) {
      break;
    }
  }
  return (GET32(0x20215040) & 0xFF);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fsfr_filter_xattr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L9
  mov    -0x30(%rbp),%rax
  jmp    L23
L9:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  jmp    L62
L17:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L3
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L2
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L2:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rax,-0x18(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rax,-0x10(%rbp)
L62:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L17
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L38
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L38:
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
data_type: string

tool: D13: user.fsfr.

assistant: ```c
ssize_t fsfr_filter_xattr(char *list, size_t size) {
  if (list == NULL)
    return size;
  char *write_p;
  char *read_p;
  char *end;
  read_p = write_p = list;
  end = list + size;
  int prefix_len = strlen("user.fsfr.");
  while (read_p < end) {
    int len = strlen(read_p);
    if (strncmp(read_p, "user.fsfr.", prefix_len)) {
      if (read_p != write_p) {
        memcpy(write_p, read_p, len);
        write_p[len] = (char)0;
      }
      write_p += len + 1;
    }
    read_p += len + 1;
  }
  if (write_p < end)
    memset(write_p, 0, end - write_p);
  return write_p - list;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fsfr_filter_xattr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rax
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L1
  lea    (%rdi,%rsi,1),%r13
  lea    D1(%rip),%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  cmp    %r13,%rbx
  jae    L96
  mov    %rbx,%rbp
  mov    %rbx,%r12
  lea    D1(%rip),%r15
  jmp    L10
L14:
  movslq %ebx,%rax
  lea    0x1(%r12,%rax,1),%r12
L82:
  movslq %ebx,%rbx
  lea    0x1(%rbp,%rbx,1),%rbp
  cmp    %rbp,%r13
  jbe    L12
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L82
  cmp    %rbp,%r12
  je     L14
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
  jmp    L14
L12:
  cmp    %r13,%r12
  jb     L36
L88:
  mov    %r12,%rax
  sub    0x8(%rsp),%rax
L1:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    %r13d,%edx
  sub    %r12d,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  jmp    L88
L96:
  mov    0x8(%rsp),%r12
  jmp    L88
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: user.fsfr.

assistant: ```c
ssize_t fsfr_filter_xattr(char *list, size_t size) {
  if (list == NULL)
    return size;
  char *write_p;
  char *read_p;
  char *end;
  read_p = write_p = list;
  end = list + size;
  int prefix_len = strlen("user.fsfr.");
  while (read_p < end) {
    int len = strlen(read_p);
    if (strncmp(read_p, "user.fsfr.", prefix_len)) {
      if (read_p != write_p) {
        memcpy(write_p, read_p, len);
        write_p[len] = (char)0;
      }
      write_p += len + 1;
    }
    read_p += len + 1;
  }
  if (write_p < end)
    memset(write_p, 0, end - write_p);
  return write_p - list;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fsfr_filter_xattr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  je     L62
  lea    D8(%rip),%r15
  lea    (%rdi,%rsi,1),%r12
  mov    %rbx,%rbp
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  cmp    %r12,%rbx
  jb     L61
  jmp    L71
  nopl   0x0(%rax)
L36:
  lea    0x1(%rcx),%rax
  add    %rax,%rbx
  cmp    %rbx,%r12
  jbe    L28
L61:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    %eax,%r14d
  call   <strncmp@plt>
  movslq %r14d,%rcx
  test   %rax,%rax
  je     L36
  cmp    %rbp,%rbx
  je     L14
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %rcx,(%rsp)
  call   <memcpy@plt>
  mov    (%rsp),%rcx
  movb   $0x0,0x0(%rbp,%rcx,1)
L14:
  lea    0x1(%rcx),%rax
  add    %rax,%rbx
  add    %rax,%rbp
  cmp    %rbx,%r12
  ja     L61
L28:
  mov    %rbp,%r13
  sub    0x8(%rsp),%r13
  cmp    %r12,%rbp
  jb     L74
L62:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    %ebp,%edx
  call   <memset@plt>
  jmp    L62
  nopl   0x0(%rax)
L71:
  xor    %r13d,%r13d
  jmp    L62
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: user.fsfr.

assistant: ```c
ssize_t fsfr_filter_xattr(char *list, size_t size) {
  if (list == NULL)
    return size;
  char *write_p;
  char *read_p;
  char *end;
  read_p = write_p = list;
  end = list + size;
  int prefix_len = strlen("user.fsfr.");
  while (read_p < end) {
    int len = strlen(read_p);
    if (strncmp(read_p, "user.fsfr.", prefix_len)) {
      if (read_p != write_p) {
        memcpy(write_p, read_p, len);
        write_p[len] = (char)0;
      }
      write_p += len + 1;
    }
    read_p += len + 1;
  }
  if (write_p < end)
    memset(write_p, 0, end - write_p);
  return write_p - list;
}
```