ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  lea    D11(%rip),%r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    D39(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x17(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rbp,%rdi
  lea    0x4(,%rbx,4),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
L2:
  mov    %r15,%rdi
  lea    0x0(,%rbx,4),%r12
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x17(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x53,%al
  je     L25
  lea    0x4(%rbp,%r12,1),%r12
  lea    D43(%rip),%rbx
  nopl   0x0(%rax)
L35:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L35
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D39
type_guessed: string
name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D43
type_guessed: string

tool: D11: Digite um valor para salvar no vetor: 

tool: D3: %d

tool: D39: Deseja cadastrar mais um numero? 

tool: D7:  %c

tool: D43:  (%d) 

assistant: ```c
int main() {
  int *vetor, contador = 0;
  char c;
  vetor = malloc(sizeof(int));
  while (1) {
    printf("Digite um valor para salvar no vetor: ");
    scanf("%d", &vetor[contador]);
    printf("Deseja cadastrar mais um numero? ");
    scanf(" %c", &c);
    contador++;
    if (c != 's' && c != 'S')
      break;
    vetor = realloc(vetor, sizeof(int) * (contador + 1));
  }
  for (int i = 0; i < contador; i++)
    printf(" (%d) ", vetor[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  lea    D22(%rip),%r15
  push   %r14
  lea    D34(%rip),%r14
  push   %r13
  lea    D33(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x17(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rbp,%rdi
  lea    0x4(,%rbx,4),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
L6:
  mov    %r15,%rdi
  lea    0x0(,%rbx,4),%r12
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x17(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x53,%al
  je     L35
  lea    0x4(%rbp,%r12,1),%r12
  lea    D44(%rip),%rbx
  nopl   0x0(%rax)
L2:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
data_type: string
name: extract_symbolic_data
arguments: tag: D34
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string
name: extract_symbolic_data
arguments: tag: D38
data_type: string
name: extract_symbolic_data
arguments: tag: D44
data_type: string

tool: D22: Digite um valor para salvar no vetor: 

tool: D34: %d

tool: D33: Deseja cadastrar mais um numero? 

tool: D38:  %c

tool: D44:  (%d) 

assistant: ```c
int main() {
  int *vetor, contador = 0;
  char c;
  vetor = malloc(sizeof(int));
  while (1) {
    printf("Digite um valor para salvar no vetor: ");
    scanf("%d", &vetor[contador]);
    printf("Deseja cadastrar mais um numero? ");
    scanf(" %c", &c);
    contador++;
    if (c != 's' && c != 'S')
      break;
    vetor = realloc(vetor, sizeof(int) * (contador + 1));
  }
  for (int i = 0; i < contador; i++)
    printf(" (%d) ", vetor[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movb   $0x55,-0x1(%rbp)
  mov    $0x42,%eax
  cmp    $0x84,%eax
  setb   %al
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char out = 0x55;
  __asm__("movl $0x42, %%eax; cmpl $0x84, %%eax; setc %%al" : "=a"(out));
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x42,%eax
  cmp    $0x84,%eax
  setb   %al
  movsbl %al,%eax
  ret
```

assistant: ```c
int main() {
  char out = 0x55;
  __asm__("movl $0x42, %%eax; cmpl $0x84, %%eax; setc %%al" : "=a"(out));
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x42,%eax
  cmp    $0x84,%eax
  setb   %al
  movsbl %al,%eax
  ret
```

assistant: ```c
int main() {
  char out = 0x55;
  __asm__("movl $0x42, %%eax; cmpl $0x84, %%eax; setc %%al" : "=a"(out));
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x42,%eax
  cmp    $0x84,%eax
  setb   %al
  movsbl %al,%eax
  ret
```

assistant: ```c
int main() {
  char out = 0x55;
  __asm__("movl $0x42, %%eax; cmpl $0x84, %%eax; setc %%al" : "=a"(out));
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ack@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  long m = strtol(argv[1], 0, 10);
  long n = strtol(argv[2], 0, 10);
  printf("%d\n", ack(m, n));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%rbp
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <ack@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(int argc, char **argv) {
  long m = strtol(argv[1], 0, 10);
  long n = strtol(argv[2], 0, 10);
  printf("%d\n", ack(m, n));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  xor    %esi,%esi
  call   <strtol@plt>
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rax,%rbp
  call   <strtol@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <ack@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  long m = strtol(argv[1], 0, 10);
  long n = strtol(argv[2], 0, 10);
  printf("%d\n", ack(m, n));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  xor    %esi,%esi
  call   <strtol@plt>
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rax,%rbp
  call   <strtol@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <ack@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d


assistant: ```c
int main(int argc, char **argv) {
  long m = strtol(argv[1], 0, 10);
  long n = strtol(argv[2], 0, 10);
  printf("%d\n", ack(m, n));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  sete   %al
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t isqrt(uint64_t a, bool *isinteger) {
  uint64_t x = sqrt(a);
  *isinteger = x * x == a;
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isqrt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  call   <sqrt@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %ebx,%edx
  sete   %dl
  movzbl %dl,%edx
  mov    %edx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t isqrt(uint64_t a, bool *isinteger) {
  uint64_t x = sqrt(a);
  *isinteger = x * x == a;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isqrt>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <sqrt@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %ebx,%edx
  sete   %dl
  movzbl %dl,%edx
  mov    %edx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t isqrt(uint64_t a, bool *isinteger) {
  uint64_t x = sqrt(a);
  *isinteger = x * x == a;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isqrt>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <sqrt@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %ebx,%edx
  sete   %dl
  movzbl %dl,%edx
  mov    %edx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t isqrt(uint64_t a, bool *isinteger) {
  uint64_t x = sqrt(a);
  *isinteger = x * x == a;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<in_netrange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  xor    -0x8(%rbp),%eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L31
  lea    D21(%rip),%rax
  jmp    L12
L31:
  mov    -0x4(%rbp),%eax
  and    -0xc(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L5
  lea    D9(%rip),%rax
  jmp    L12
L5:
  mov    -0xc(%rbp),%eax
  not    %eax
  or     -0x4(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L42
  lea    D9(%rip),%rax
  jmp    L12
L42:
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D21: Error: the IP address is not in the interface range


tool: D9: Error: the IP address is a network address


assistant: ```c
char *in_netrange(uint32_t ip, uint32_t ifip, uint32_t ifmask) {
  if ((ip & ifmask) != (ifip & ifmask))
    return (char *)"Error: the IP address is not in the interface range\n";
  else if ((ip & ifmask) == ip)
    return (char *)"Error: the IP address is a network address\n";
  else if ((ip | ~ifmask) == ip)
    return (char *)"Error: the IP address is a network address\n";
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<in_netrange>:
  endbr64
  xor    %edi,%esi
  lea    D1(%rip),%rax
  test   %edx,%esi
  jne    L15
  mov    %edi,%ecx
  and    %edx,%ecx
  lea    D2(%rip),%rax
  cmp    %edi,%ecx
  je     L15
  not    %edx
  or     %edi,%edx
  cmp    %edi,%edx
  mov    $0x0,%edx
  cmovne %rdx,%rax
L15:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D1: Error: the IP address is not in the interface range


tool: D2: Error: the IP address is a network address


assistant: ```c
char *in_netrange(uint32_t ip, uint32_t ifip, uint32_t ifmask) {
  if ((ip & ifmask) != (ifip & ifmask))
    return (char *)"Error: the IP address is not in the interface range\n";
  else if ((ip & ifmask) == ip)
    return (char *)"Error: the IP address is a network address\n";
  else if ((ip | ~ifmask) == ip)
    return (char *)"Error: the IP address is a network address\n";
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<in_netrange>:
  endbr64
  xor    %edi,%esi
  lea    D2(%rip),%rax
  test   %edx,%esi
  jne    L6
  mov    %edi,%ecx
  lea    D1(%rip),%rax
  and    %edx,%ecx
  cmp    %edi,%ecx
  je     L6
  not    %edx
  or     %edi,%edx
  cmp    %edi,%edx
  mov    $0x0,%edx
  cmovne %rdx,%rax
L6:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string

tool: D2: Error: the IP address is not in the interface range


tool: D1: Error: the IP address is a network address


assistant: ```c
char *in_netrange(uint32_t ip, uint32_t ifip, uint32_t ifmask) {
  if ((ip & ifmask) != (ifip & ifmask))
    return (char *)"Error: the IP address is not in the interface range\n";
  else if ((ip & ifmask) == ip)
    return (char *)"Error: the IP address is a network address\n";
  else if ((ip | ~ifmask) == ip)
    return (char *)"Error: the IP address is a network address\n";
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<in_netrange>:
  endbr64
  xor    %edi,%esi
  lea    D18(%rip),%rax
  test   %edx,%esi
  jne    L4
  mov    %edi,%ecx
  lea    D3(%rip),%rax
  and    %edx,%ecx
  cmp    %edi,%ecx
  je     L4
  not    %edx
  or     %edi,%edx
  cmp    %edi,%edx
  mov    $0x0,%edx
  cmovne %rdx,%rax
L4:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type: string
name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D18: Error: the IP address is not in the interface range


tool: D3: Error: the IP address is a network address


assistant: ```c
char *in_netrange(uint32_t ip, uint32_t ifip, uint32_t ifmask) {
  if ((ip & ifmask) != (ifip & ifmask))
    return (char *)"Error: the IP address is not in the interface range\n";
  else if ((ip & ifmask) == ip)
    return (char *)"Error: the IP address is a network address\n";
  else if ((ip | ~ifmask) == ip)
    return (char *)"Error: the IP address is a network address\n";
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dedup_cluster>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <duptab_new@plt>
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <duptab_first@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L22
L20:
  mov    -0x24(%rbp),%eax
  cmp    $0x1,%eax
  jle    L57
  movl   $0x0,-0x1c(%rbp)
  jmp    L42
L59:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  lea    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <duptab_add@plt>
  addl   $0x1,-0x1c(%rbp)
L42:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L59
  jmp    L23
L57:
  nop
L23:
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <duptab_next@plt>
  mov    %rax,-0x10(%rbp)
L22:
  cmpq   $0x0,-0x10(%rbp)
  jne    L20
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <duptab_count@plt>
  test   %rax,%rax
  jne    L68
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <duptab_free@plt>
  mov    %rax,-0x18(%rbp)
L68:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

assistant: ```c
struct duptab *dedup_cluster(struct duptab *in) {
  struct duptab *out = duptab_new();
  ino_t *inos;
  int icnt, i;
  struct stat st;
  for (inos = duptab_first(in, &icnt, &st); inos != NULL; inos = duptab_next(in, &icnt, &st)) {
    if (icnt < 2)
      continue;
    for (i = 0; i < icnt; i++) {
      st.st_ino = inos[i];
      duptab_add(out, &st, 0, NULL);
    }
  }
  if (duptab_count(out) == 0)
    out = duptab_free(out);
  return out;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dedup_cluster>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <duptab_new@plt>
  mov    %rax,%r12
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <duptab_first@plt>
  test   %rax,%rax
  je     L26
  mov    %rax,%rbp
  lea    0x4(%rsp),%r14
  jmp    L39
L65:
  mov    %rsp,%rsi
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <duptab_next@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L26
L39:
  cmpl   $0x1,(%rsp)
  jle    L65
  mov    $0x0,%ebx
L6:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %eax,0x4(%rsp)
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <duptab_add@plt>
  add    $0x1,%rbx
  cmp    %ebx,(%rsp)
  jg     L6
  jmp    L65
L26:
  mov    %r12,%rdi
  call   <duptab_count@plt>
  test   %rax,%rax
  je     L25
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  mov    %r12,%rdi
  call   <duptab_free@plt>
  mov    %rax,%r12
  jmp    L17
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct duptab *dedup_cluster(struct duptab *in) {
  struct duptab *out = duptab_new();
  ino_t *inos;
  int icnt, i;
  struct stat st;
  for (inos = duptab_first(in, &icnt, &st); inos != NULL; inos = duptab_next(in, &icnt, &st)) {
    if (icnt < 2)
      continue;
    for (i = 0; i < icnt; i++) {
      st.st_ino = inos[i];
      duptab_add(out, &st, 0, NULL);
    }
  }
  if (duptab_count(out) == 0)
    out = duptab_free(out);
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dedup_cluster>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%r15
  call   <duptab_new@plt>
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    %rax,%r13
  call   <duptab_first@plt>
  test   %rax,%rax
  je     L37
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L61:
  cmpl   $0x1,(%rsp)
  jle    L42
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x0(%rbp,%rbx,4),%eax
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  mov    %eax,0x4(%rsp)
  call   <duptab_add@plt>
  cmp    %ebx,(%rsp)
  jg     L5
L42:
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <duptab_next@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L61
L37:
  mov    %r13,%rdi
  call   <duptab_count@plt>
  test   %rax,%rax
  je     L43
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  mov    %r13,%rdi
  call   <duptab_free@plt>
  mov    %rax,%r13
  jmp    L13
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct duptab *dedup_cluster(struct duptab *in) {
  struct duptab *out = duptab_new();
  ino_t *inos;
  int icnt, i;
  struct stat st;
  for (inos = duptab_first(in, &icnt, &st); inos != NULL; inos = duptab_next(in, &icnt, &st)) {
    if (icnt < 2)
      continue;
    for (i = 0; i < icnt; i++) {
      st.st_ino = inos[i];
      duptab_add(out, &st, 0, NULL);
    }
  }
  if (duptab_count(out) == 0)
    out = duptab_free(out);
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dedup_cluster>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%r15
  call   <duptab_new@plt>
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    %rax,%r13
  call   <duptab_first@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L23:
  cmpl   $0x1,(%rsp)
  jle    L69
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x0(%rbp,%rbx,4),%eax
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  mov    %eax,0x4(%rsp)
  call   <duptab_add@plt>
  cmp    %ebx,(%rsp)
  jg     L29
L69:
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <duptab_next@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L23
L6:
  mov    %r13,%rdi
  call   <duptab_count@plt>
  test   %rax,%rax
  je     L0
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  mov    %r13,%rdi
  call   <duptab_free@plt>
  mov    %rax,%r13
  jmp    L15
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct duptab *dedup_cluster(struct duptab *in) {
  struct duptab *out = duptab_new();
  ino_t *inos;
  int icnt, i;
  struct stat st;
  for (inos = duptab_first(in, &icnt, &st); inos != NULL; inos = duptab_next(in, &icnt, &st)) {
    if (icnt < 2)
      continue;
    for (i = 0; i < icnt; i++) {
      st.st_ino = inos[i];
      duptab_add(out, &st, 0, NULL);
    }
  }
  if (duptab_count(out) == 0)
    out = duptab_free(out);
  return out;
}
```