ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<expmod_helper>:
  endbr64
  mov    %rdi,%r9
  mov    %rcx,%r8
  mov    %rdx,%rdi
  test   %rsi,%rsi
  je     L31
  nopw   0x0(%rax,%rax,1)
L25:
  test   $0x1,%sil
  jne    L21
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %r9,%rax
  imul   %r9,%rax
  cqto
  idiv   %rdi
  sar    %rsi
  mov    %rdx,%r9
  jne    L25
L31:
  mov    %r8,%rax
  ret
L21:
  mov    %r8,%rax
  imul   %r9,%rax
  cqto
  idiv   %rdi
  mov    %rdx,%r8
  sub    $0x1,%rsi
  jne    L25
  mov    %r8,%rax
  ret
```

assistant: ```c
long expmod_helper(long x, long n, long m, long acc) {
  if (0 == n) {
    return acc;
  } else if (n % 2 == 0) {
    return expmod_helper((x * x) % m, n / 2, m, acc);
  } else {
    return expmod_helper(x, n - 1, m, (x * acc) % m);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <kacharf@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: Kelime harf sayisi >> %d

assistant: ```c
int main(int argc, char **argv) {
  char kelime[100];
  gets(kelime);
  printf("Kelime harf sayisi >> %d", kacharf(kelime));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <kacharf@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: Kelime harf sayisi >> %d

assistant: ```c
int main(int argc, char **argv) {
  char kelime[100];
  gets(kelime);
  printf("Kelime harf sayisi >> %d", kacharf(kelime));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <kacharf@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: Kelime harf sayisi >> %d

assistant: ```c
int main(int argc, char **argv) {
  char kelime[100];
  gets(kelime);
  printf("Kelime harf sayisi >> %d", kacharf(kelime));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <kacharf@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: Kelime harf sayisi >> %d

assistant: ```c
int main(int argc, char **argv) {
  char kelime[100];
  gets(kelime);
  printf("Kelime harf sayisi >> %d", kacharf(kelime));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<json_read_object>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <json_internal_read_object@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int json_read_object(struct json_buffer *jb, const struct json_attr_t *attrs) {
  int st;
  st = json_internal_read_object(jb, attrs, NULL, 0);
  return st;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<json_read_object>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  call   <json_internal_read_object@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int json_read_object(struct json_buffer *jb, const struct json_attr_t *attrs) {
  int st;
  st = json_internal_read_object(jb, attrs, NULL, 0);
  return st;
}
```
user: What is the c source code of the assembly code below?

```asm
<json_read_object>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    1050 <json_internal_read_object@plt>
```

assistant: ```c
int json_read_object(struct json_buffer *jb, const struct json_attr_t *attrs) {
  int st;
  st = json_internal_read_object(jb, attrs, NULL, 0);
  return st;
}
```
user: What is the c source code of the assembly code below:

```asm
<json_read_object>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    1050 <json_internal_read_object@plt>
```

assistant: ```c
int json_read_object(struct json_buffer *jb, const struct json_attr_t *attrs) {
  int st;
  st = json_internal_read_object(jb, attrs, NULL, 0);
  return st;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mat4_transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L34
L31:
  movl   $0x0,-0x54(%rbp)
  jmp    L18
L1:
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  %xmm0,-0x50(%rbp,%rax,4)
  addl   $0x1,-0x54(%rbp)
L18:
  cmpl   $0x3,-0x54(%rbp)
  jle    L1
  addl   $0x1,-0x58(%rbp)
L34:
  cmpl   $0x3,-0x58(%rbp)
  jle    L31
  mov    -0x70(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mat4_copy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
void mat4_transpose(const float m[4][4], float out[4][4]) {
  int i, j;
  float ret[4][4] = {};
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      ret[i][j] = m[j][i];
  mat4_copy(ret, out);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mat4_transpose>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  mov    %rsp,%rax
  lea    0x40(%rsp),%rdx
L17:
  movss  (%rdi),%xmm0
  movss  %xmm0,(%rax)
  movss  0x10(%rdi),%xmm0
  movss  %xmm0,0x4(%rax)
  movss  0x20(%rdi),%xmm0
  movss  %xmm0,0x8(%rax)
  movss  0x30(%rdi),%xmm0
  movss  %xmm0,0xc(%rax)
  add    $0x4,%rdi
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L17
  mov    %rsp,%rdi
  mov    $0x0,%eax
  call   <mat4_copy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat4_transpose(const float m[4][4], float out[4][4]) {
  int i, j;
  float ret[4][4] = {};
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      ret[i][j] = m[j][i];
  mat4_copy(ret, out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mat4_transpose>:
  endbr64
  sub    $0x58,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  movaps %xmm0,(%rsp)
  lea    0x40(%rsp),%rdx
  movaps %xmm0,0x10(%rsp)
  mov    %r8,%rax
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
L12:
  movss  (%rdi),%xmm0
  add    $0x10,%rax
  add    $0x4,%rdi
  movss  %xmm0,-0x10(%rax)
  movss  0xc(%rdi),%xmm0
  movss  %xmm0,-0xc(%rax)
  movss  0x1c(%rdi),%xmm0
  movss  %xmm0,-0x8(%rax)
  movss  0x2c(%rdi),%xmm0
  movss  %xmm0,-0x4(%rax)
  cmp    %rdx,%rax
  jne    L12
  xor    %eax,%eax
  mov    %r8,%rdi
  call   <mat4_copy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x58,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat4_transpose(const float m[4][4], float out[4][4]) {
  int i, j;
  float ret[4][4] = {};
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      ret[i][j] = m[j][i];
  mat4_copy(ret, out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mat4_transpose>:
  endbr64
  sub    $0x58,%rsp
  movups (%rdi),%xmm0
  movups 0x20(%rdi),%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movups 0x10(%rdi),%xmm1
  movups 0x30(%rdi),%xmm4
  mov    %rsp,%rdi
  movaps %xmm0,%xmm2
  unpckhps %xmm3,%xmm0
  unpcklps %xmm3,%xmm2
  movaps %xmm1,%xmm3
  unpckhps %xmm4,%xmm1
  unpcklps %xmm4,%xmm3
  movaps %xmm2,%xmm4
  unpckhps %xmm3,%xmm2
  unpcklps %xmm3,%xmm4
  movaps %xmm2,0x10(%rsp)
  movaps %xmm0,%xmm2
  unpckhps %xmm1,%xmm0
  unpcklps %xmm1,%xmm2
  movaps %xmm4,(%rsp)
  movaps %xmm2,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <mat4_copy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x58,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat4_transpose(const float m[4][4], float out[4][4]) {
  int i, j;
  float ret[4][4] = {};
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      ret[i][j] = m[j][i];
  mat4_copy(ret, out);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x5,-0x4(%rbp)
  jmp    L11
L1:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  subl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x0,-0x4(%rbp)
  jg     L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D5: Hello, world!

assistant: ```c
int main(int argc, char **argv) {
  int i = 5;
  while (i > 0) {
    puts("Hello, world!");
    i = i - 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: Hello, world!

assistant: ```c
int main(int argc, char **argv) {
  int i = 5;
  while (i > 0) {
    puts("Hello, world!");
    i = i - 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2: Hello, world!

assistant: ```c
int main(int argc, char **argv) {
  int i = 5;
  while (i > 0) {
    puts("Hello, world!");
    i = i - 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x8,%rsp
L1:
  mov    %rbp,%rdi
  call   <puts@plt>
  sub    $0x1,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: Hello, world!

assistant: ```c
int main(int argc, char **argv) {
  int i = 5;
  while (i > 0) {
    puts("Hello, world!");
    i = i - 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fib_recursive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L8
  movq   $0x0,-0x18(%rbp)
  jmp    L30
L8:
  cmpl   $0x1,-0x24(%rbp)
  jne    L10
  movq   $0x1,-0x18(%rbp)
  jmp    L30
L10:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib@plt>
  mov    %rax,%rbx
  mov    -0x24(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib@plt>
  add    %rbx,%rax
  mov    %rax,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long fib_recursive(int n) {
  long result;
  static long map[45];
  if (n == 0)
    result = 0;
  else if (n == 1)
    result = 1;
  else
    result = fib(n - 1) + fib(n - 2);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<fib_recursive>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  je     L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jne    L11
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    -0x1(%rdi),%edi
  call   <fib@plt>
  mov    %rax,%rbp
  lea    -0x2(%rbx),%edi
  call   <fib@plt>
  add    %rbp,%rax
  jmp    L18
L19:
  ret
```

assistant: ```c
long fib_recursive(int n) {
  long result;
  static long map[45];
  if (n == 0)
    result = 0;
  else if (n == 1)
    result = 1;
  else
    result = fib(n - 1) + fib(n - 2);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fib_recursive>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L15
  push   %rbp
  mov    $0x1,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
  nopl   0x0(%rax)
L8:
  lea    -0x1(%rdi),%edi
  call   <fib@plt>
  lea    -0x2(%rbx),%edi
  mov    %rax,%rbp
  call   <fib@plt>
  add    $0x8,%rsp
  add    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long fib_recursive(int n) {
  long result;
  static long map[45];
  if (n == 0)
    result = 0;
  else if (n == 1)
    result = 1;
  else
    result = fib(n - 1) + fib(n - 2);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fib_recursive>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L4
  push   %rbp
  mov    $0x1,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
  nopl   0x0(%rax)
L18:
  lea    -0x1(%rdi),%edi
  call   <fib@plt>
  lea    -0x2(%rbx),%edi
  mov    %rax,%rbp
  call   <fib@plt>
  add    $0x8,%rsp
  add    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long fib_recursive(int n) {
  long result;
  static long map[45];
  if (n == 0)
    result = 0;
  else if (n == 1)
    result = 1;
  else
    result = fib(n - 1) + fib(n - 2);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    %rax,-0x18(%rbp)
  je     L6
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <err_sys@plt>
L6:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: D2: write error

assistant: ```c
void Write(int fd, void *ptr, size_t nbytes) {
  if (write(fd, ptr, nbytes) != nbytes)
    err_sys("write error");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Write>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <write@plt>
  cmp    %rbx,%rax
  jne    L13
L16:
  pop    %rbx
  ret
L13:
  lea    D7(%rip),%rdi
  call   <err_sys@plt>
  jmp    L16
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: write error

assistant: ```c
void Write(int fd, void *ptr, size_t nbytes) {
  if (write(fd, ptr, nbytes) != nbytes)
    err_sys("write error");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Write>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <write@plt>
  cmp    %rbx,%rax
  jne    L0
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  lea    D7(%rip),%rdi
  pop    %rbx
  jmp    1060 <err_sys@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: write error

assistant: ```c
void Write(int fd, void *ptr, size_t nbytes) {
  if (write(fd, ptr, nbytes) != nbytes)
    err_sys("write error");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Write>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <write@plt>
  cmp    %rbx,%rax
  jne    L5
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  lea    D1(%rip),%rdi
  pop    %rbx
  jmp    1060 <err_sys@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: write error

assistant: ```c
void Write(int fd, void *ptr, size_t nbytes) {
  if (write(fd, ptr, nbytes) != nbytes)
    err_sys("write error");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<OnTimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x14,%edi
  call   <glutTimerFunc@plt>
  nop
  leave
  ret
```

assistant: ```c
void OnTimer(int value) {
  glutPostRedisplay();
  glutTimerFunc(20, &OnTimer, value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<OnTimer>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  mov    %ebx,%edx
  mov    D5(%rip),%rsi
  mov    $0x14,%edi
  call   <glutTimerFunc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void OnTimer(int value) {
  glutPostRedisplay();
  glutTimerFunc(20, &OnTimer, value);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<OnTimer>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <glutPostRedisplay@plt>
  mov    D9(%rip),%rsi
  mov    %r12d,%edx
  mov    $0x14,%edi
  pop    %r12
  jmp    1070 <glutTimerFunc@plt>
```

assistant: ```c
void OnTimer(int value) {
  glutPostRedisplay();
  glutTimerFunc(20, &OnTimer, value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OnTimer>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <glutPostRedisplay@plt>
  mov    D4(%rip),%rsi
  mov    %r12d,%edx
  mov    $0x14,%edi
  pop    %r12
  jmp    1070 <glutTimerFunc@plt>
```

assistant: ```c
void OnTimer(int value) {
  glutPostRedisplay();
  glutTimerFunc(20, &OnTimer, value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OPENSSL_showfatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void OPENSSL_showfatal(const char *fmta, ...) {
  va_list ap;
  va_start(ap, fmta);
  vfprintf(stderr, fmta, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<OPENSSL_showfatal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void OPENSSL_showfatal(const char *fmta, ...) {
  va_list ap;
  va_start(ap, fmta);
  vfprintf(stderr, fmta, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OPENSSL_showfatal>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void OPENSSL_showfatal(const char *fmta, ...) {
  va_list ap;
  va_start(ap, fmta);
  vfprintf(stderr, fmta, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<OPENSSL_showfatal>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void OPENSSL_showfatal(const char *fmta, ...) {
  va_list ap;
  va_start(ap, fmta);
  vfprintf(stderr, fmta, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D9
datatype: string

tool: D13: 

tool: D9: %d 

assistant: ```c
void dump(int a[], int size) {
  int i = 0;
  printf("\r\n");
  for (i = 0; i < size; i++) {
    printf("%d ", a[i]);
  }
  printf("\r\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dump>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L10
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D9(%rip),%rbp
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L15
L10:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string
name: read_data
arguments: label: D9
type_guessed: string

tool: D0: 

tool: D9: %d 

assistant: ```c
void dump(int a[], int size) {
  int i = 0;
  printf("\r\n");
  for (i = 0; i < size; i++) {
    printf("%d ", a[i]);
  }
  printf("\r\n");
  return;
}
```