user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_n_param>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %rdx,-0x138(%rbp)
  mov    %ecx,-0x13c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %eax,%edi
  call   <atoi@plt>
  mov    %eax,-0x118(%rbp)
  movl   $0x0,-0x120(%rbp)
  movl   $0x0,-0x11c(%rbp)
  mov    -0x130(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x114(%rbp)
  cmpq   $0x0,-0x128(%rbp)
  jne    L70
  mov    $0x1,%eax
  jmp    L121
L123:
  movl   $0x0,-0x11c(%rbp)
  jmp    L49
L85:
  mov    -0x120(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x11c(%rbp),%eax
  cltq
  mov    %dl,-0x110(%rbp,%rax,1)
  addl   $0x1,-0x120(%rbp)
  addl   $0x1,-0x11c(%rbp)
L49:
  mov    -0x120(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L120
  mov    -0x11c(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jle    L85
L120:
  addl   $0x1,-0x120(%rbp)
  mov    -0x11c(%rbp),%eax
  cltq
  movb   $0x0,-0x110(%rbp,%rax,1)
  mov    -0x13c(%rbp),%edx
  mov    -0x130(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L75
  movl   $0x0,-0x11c(%rbp)
  jmp    L127
L29:
  mov    -0x120(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  mov    -0x11c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x138(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x120(%rbp)
  addl   $0x1,-0x11c(%rbp)
L127:
  mov    -0x120(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  je     L5
  mov    -0x120(%rbp),%eax
  cmp    -0x118(%rbp),%eax
  jl     L29
L5:
  mov    -0x11c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x138(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L121
L50:
  addl   $0x1,-0x120(%rbp)
L75:
  mov    -0x120(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  je     L107
  mov    -0x120(%rbp),%eax
  cmp    -0x118(%rbp),%eax
  jl     L50
L107:
  addl   $0x1,-0x120(%rbp)
L70:
  mov    -0x120(%rbp),%eax
  cmp    -0x118(%rbp),%eax
  jl     L123
  mov    $0x1,%eax
L121:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: CONTENT_LENGTH

assistant: ```c
int find_n_param(char *buffer, char *nomeobj, char *valore_out, int n_max) {
  int param_length = atoi(getenv("CONTENT_LENGTH"));
  int i = 0, j = 0;
  char nomeparam[255];
  int n_nomeobj = strlen(nomeobj);
  if (buffer == NULL)
    return 1;
  while (i < param_length) {
    j = 0;
    while ((buffer[i] != '=') && (j <= n_nomeobj)) {
      nomeparam[j] = buffer[i];
      i++;
      j++;
    }
    i++;
    nomeparam[j] = '\0';
    if (strncmp(nomeparam, nomeobj, n_max) == 0) {
      j = 0;
      while ((buffer[i] != '&') && (i < param_length)) {
        valore_out[j] = buffer[i];
        i++;
        j++;
      }
      valore_out[j] = '\0';
      return 0;
    } else {
      while ((buffer[i] != '&') && (i < param_length))
        i++;
      i++;
    }
  }
  return 1;
}
```