user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L84
L97:
  movl   $0x0,-0x50(%rbp)
  jmp    L16
L101:
  lea    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x50(%rbp)
L16:
  cmpl   $0x3,-0x50(%rbp)
  jle    L101
  addl   $0x1,-0x54(%rbp)
L84:
  cmpl   $0x2,-0x54(%rbp)
  jle    L97
  movl   $0x0,-0x54(%rbp)
  jmp    L175
L176:
  movl   $0x0,-0x48(%rbp)
  movl   $0x1,-0x50(%rbp)
  jmp    L79
L76:
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x48(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L80
  mov    -0x50(%rbp),%eax
  mov    %eax,-0x48(%rbp)
L80:
  addl   $0x1,-0x50(%rbp)
L79:
  cmpl   $0x3,-0x50(%rbp)
  jle    L76
  movl   $0x0,-0x50(%rbp)
  jmp    L142
L144:
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x48(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L50
  movl   $0x0,-0x44(%rbp)
  jmp    L103
L106:
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x50(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jl     L73
  addl   $0x1,-0x44(%rbp)
L103:
  cmpl   $0x2,-0x44(%rbp)
  jle    L106
  jmp    L95
L73:
  nop
L95:
  cmpl   $0x3,-0x44(%rbp)
  jne    L50
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x4c(%rbp)
L50:
  addl   $0x1,-0x50(%rbp)
L142:
  cmpl   $0x3,-0x50(%rbp)
  jle    L144
  addl   $0x1,-0x54(%rbp)
L175:
  cmpl   $0x2,-0x54(%rbp)
  jle    L176
  cmpl   $0x0,-0x4c(%rbp)
  jne    L112
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L112:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L111
  call   <__stack_chk_fail@plt>
L111:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D3
type_infered: string
name: disassemble_data
arguments: tag: D16
type_infered: string

tool: D7: %d

tool: D3: %d


tool: D16: NO

assistant: ```c
int main() {
  int i, j, a[3][4], flag = 0, col, r;
  for (i = 0; i < 3; i++)
    for (j = 0; j < 4; j++)
      scanf("%d", &a[i][j]);
  for (i = 0; i < 3; i++) {
    col = 0;
    for (j = 1; j < 4; j++)
      if (a[i][j] > a[i][col])
        col = j;
    for (j = 0; j < 4; j++) {
      if (a[i][j] == a[i][col]) {
        for (r = 0; r < 3; r++)
          if (a[r][j] < a[i][j])
            break;
        if (r == 3) {
          printf("%d\n", a[i][j]);
          flag = 1;
        }
      }
    }
  }
  if (!flag)
    printf("NO\n");
  return 0;
}
```