ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  lea    D21(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L34
L53:
  lea    D46(%rip),%rdx
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D69(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L2
L44:
  lea    0x10(%rsp),%rbp
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L86
L88:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <remove@plt>
  test   %rax,%rax
  jne    L69
L8:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x408,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L69:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L8
L86:
  lea    D78(%rip),%rdi
  call   <printf@plt>
  jmp    L88
L34:
  lea    D85(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L53
L2:
  lea    D85(%rip),%rdi
  mov    %rax,0x8(%rsp)
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rdx
  jmp    L44
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D21
type: string
name: retrieve_data
arguments: data_label: D46
type: string
name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D69
type: string
name: retrieve_data
arguments: data_label: D8
type: string
name: retrieve_data
arguments: data_label: D78
type: string
name: retrieve_data
arguments: data_label: D85
type: string

tool: D10: sulong_test_file

tool: D21: w

tool: D46: hello world!

tool: D4: write this to the writeableFile: %s


tool: D69: r

tool: D8: error removing file!


tool: D78: error!

tool: D85: error opening file!


assistant: ```c
int main() {
  FILE *writeableFile = fopen("sulong_test_file", "w");
  if (writeableFile == NULL) {
    printf("error opening file!\n");
    exit(1);
  }
  const char *text = "hello world!";
  fprintf(writeableFile, "write this to the writeableFile: %s\n", text);
  fclose(writeableFile);
  FILE *readableFile = fopen("sulong_test_file", "r");
  if (readableFile == NULL) {
    printf("error opening file!\n");
    exit(2);
  }
  char buff[1000];
  if (fgets(buff, 1000, readableFile) == NULL) {
    printf("error!");
  }
  puts(buff);
  if (remove("sulong_test_file")) {
    printf("error removing file!\n");
    exit(3);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getdirentries>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__lseek@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <__getdents@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L0
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
L0:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
ssize_t getdirentries(int fd, char *buf, size_t nbytes, off_t *basep) {
  off_t base = __lseek(fd, (off_t)0, SEEK_CUR);
  ssize_t result;
  result = __getdents(fd, buf, nbytes);
  if (result != -1)
    *basep = base;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getdirentries>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %rcx,%r12
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <__lseek@plt>
  mov    %eax,%r13d
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <__getdents@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    %r13d,(%r12)
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
ssize_t getdirentries(int fd, char *buf, size_t nbytes, off_t *basep) {
  off_t base = __lseek(fd, (off_t)0, SEEK_CUR);
  ssize_t result;
  result = __getdents(fd, buf, nbytes);
  if (result != -1)
    *basep = base;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getdirentries>:
  endbr64
  mov    D7(%rip),%rax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rax),%edx
  mov    %rcx,%rbx
  call   <__lseek@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <__getdents@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    %r13d,(%rbx)
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
ssize_t getdirentries(int fd, char *buf, size_t nbytes, off_t *basep) {
  off_t base = __lseek(fd, (off_t)0, SEEK_CUR);
  ssize_t result;
  result = __getdents(fd, buf, nbytes);
  if (result != -1)
    *basep = base;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getdirentries>:
  endbr64
  mov    D7(%rip),%rax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rax),%edx
  mov    %rcx,%rbx
  call   <__lseek@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <__getdents@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    %r13d,(%rbx)
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
ssize_t getdirentries(int fd, char *buf, size_t nbytes, off_t *basep) {
  off_t base = __lseek(fd, (off_t)0, SEEK_CUR);
  ssize_t result;
  result = __getdents(fd, buf, nbytes);
  if (result != -1)
    *basep = base;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<cvCeil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int cvCeil(double value) {
  int i = (int)value;
  return i + (i < value);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cvCeil>:
  endbr64
  cvttsd2si %xmm0,%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int cvCeil(double value) {
  int i = (int)value;
  return i + (i < value);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cvCeil>:
  endbr64
  cvttsd2si %xmm0,%edx
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  cvtsi2sd %edx,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  add    %edx,%eax
  ret
```

assistant: ```c
int cvCeil(double value) {
  int i = (int)value;
  return i + (i < value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cvCeil>:
  endbr64
  cvttsd2si %xmm0,%edx
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  cvtsi2sd %edx,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  add    %edx,%eax
  ret
```

assistant: ```c
int cvCeil(double value) {
  int i = (int)value;
  return i + (i < value);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<permutationWithRecurrence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L17
L8:
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <permutationR@plt>
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
int permutationWithRecurrence(char *string) {
  if (string == NULL) {
    return -1;
  }
  permutationR(string, string);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<permutationWithRecurrence>:
  endbr64
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  call   <permutationR@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int permutationWithRecurrence(char *string) {
  if (string == NULL) {
    return -1;
  }
  permutationR(string, string);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<permutationWithRecurrence>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  call   <permutationR@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int permutationWithRecurrence(char *string) {
  if (string == NULL) {
    return -1;
  }
  permutationR(string, string);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<permutationWithRecurrence>:
  endbr64
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  call   <permutationR@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int permutationWithRecurrence(char *string) {
  if (string == NULL) {
    return -1;
  }
  permutationR(string, string);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<subtract_times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L11
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0xf4240(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
L11:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  js     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void subtract_times(struct timeval *etime, struct timeval *sttime) {
  etime->tv_sec -= sttime->tv_sec;
  etime->tv_usec -= sttime->tv_usec;
  while (etime->tv_usec < 0) {
    etime->tv_usec += 1000000;
    etime->tv_sec--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<subtract_times>:
  endbr64
  mov    0x8(%rdi),%rdx
  sub    0x8(%rsi),%rdx
  mov    %rdx,0x8(%rdi)
  mov    (%rdi),%rax
  sub    (%rsi),%rax
  mov    %rax,(%rdi)
  jns    L9
  sub    $0x1,%rdx
L3:
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  add    $0xf4240,%rax
  js     L3
  mov    %rax,(%rdi)
  mov    %rcx,0x8(%rdi)
L9:
  ret
```

assistant: ```c
void subtract_times(struct timeval *etime, struct timeval *sttime) {
  etime->tv_sec -= sttime->tv_sec;
  etime->tv_usec -= sttime->tv_usec;
  while (etime->tv_usec < 0) {
    etime->tv_usec += 1000000;
    etime->tv_sec--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<subtract_times>:
  endbr64
  mov    0x8(%rdi),%rdx
  mov    (%rdi),%rax
  sub    0x8(%rsi),%rdx
  sub    (%rsi),%rax
  mov    %rdx,0x8(%rdi)
  mov    %rax,(%rdi)
  jns    L13
  sub    $0x1,%rdx
  nop
L19:
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  add    $0xf4240,%rax
  js     L19
  mov    %rax,(%rdi)
  mov    %rcx,0x8(%rdi)
L13:
  ret
```

assistant: ```c
void subtract_times(struct timeval *etime, struct timeval *sttime) {
  etime->tv_sec -= sttime->tv_sec;
  etime->tv_usec -= sttime->tv_usec;
  while (etime->tv_usec < 0) {
    etime->tv_usec += 1000000;
    etime->tv_sec--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subtract_times>:
  endbr64
  movdqu (%rsi),%xmm1
  movdqu (%rdi),%xmm0
  psubq  %xmm1,%xmm0
  movhlps %xmm0,%xmm2
  movq   %xmm0,%rax
  movups %xmm0,(%rdi)
  movq   %xmm2,%rdx
  test   %rax,%rax
  jns    L5
  sub    $0x1,%rdx
  nopl   0x0(%rax)
L14:
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  add    $0xf4240,%rax
  js     L14
  mov    %rax,(%rdi)
  mov    %rcx,0x8(%rdi)
L5:
  ret
```

assistant: ```c
void subtract_times(struct timeval *etime, struct timeval *sttime) {
  etime->tv_sec -= sttime->tv_sec;
  etime->tv_usec -= sttime->tv_usec;
  while (etime->tv_usec < 0) {
    etime->tv_usec += 1000000;
    etime->tv_sec--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BigEndianWriteU16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BigEndianWriteU16(uint16_t value, uint8_t *bytes) {
  bytes[0] = (uint8_t)(value >> 8);
  bytes[1] = (uint8_t)value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BigEndianWriteU16>:
  endbr64
  mov    %edi,%eax
  sar    $0x8,%eax
  cltq
  mov    %rax,(%rsi)
  movslq %edi,%rdi
  mov    %rdi,0x8(%rsi)
  ret
```

assistant: ```c
void BigEndianWriteU16(uint16_t value, uint8_t *bytes) {
  bytes[0] = (uint8_t)(value >> 8);
  bytes[1] = (uint8_t)value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BigEndianWriteU16>:
  endbr64
  mov    %edi,%eax
  movslq %edi,%rdi
  sar    $0x8,%eax
  mov    %rdi,0x8(%rsi)
  cltq
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void BigEndianWriteU16(uint16_t value, uint8_t *bytes) {
  bytes[0] = (uint8_t)(value >> 8);
  bytes[1] = (uint8_t)value;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BigEndianWriteU16>:
  endbr64
  mov    %edi,%eax
  movslq %edi,%rdi
  sar    $0x8,%eax
  movq   %rdi,%xmm1
  cltq
  movq   %rax,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rsi)
  ret
```

assistant: ```c
void BigEndianWriteU16(uint16_t value, uint8_t *bytes) {
  bytes[0] = (uint8_t)(value >> 8);
  bytes[1] = (uint8_t)value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USART2_IrqHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  jmp    L9
```

assistant: ```c
__attribute__((weak)) void USART2_IrqHandler(void) {
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<USART2_IrqHandler>:
  endbr64
L7:
  jmp    L7
```

assistant: ```c
__attribute__((weak)) void USART2_IrqHandler(void) {
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<USART2_IrqHandler>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
__attribute__((weak)) void USART2_IrqHandler(void) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<USART2_IrqHandler>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
__attribute__((weak)) void USART2_IrqHandler(void) {
  while (1)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str2wide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <mbstowcs@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
wchar_t *str2wide(char *src) {
  int len = mbstowcs(NULL, src, 0) + 1;
  wchar_t *dest = malloc((len + 1) * sizeof(wchar_t));
  mbstowcs(dest, src, len);
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str2wide>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%edx
  mov    %rdi,%rsi
  mov    $0x0,%edi
  call   <mbstowcs@plt>
  mov    %eax,%ebx
  lea    0x8(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x1(%rbx),%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
wchar_t *str2wide(char *src) {
  int len = mbstowcs(NULL, src, 0) + 1;
  wchar_t *dest = malloc((len + 1) * sizeof(wchar_t));
  mbstowcs(dest, src, len);
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str2wide>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  xor    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  call   <mbstowcs@plt>
  lea    0x8(,%rax,4),%edi
  mov    %eax,%ebx
  call   <malloc@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
wchar_t *str2wide(char *src) {
  int len = mbstowcs(NULL, src, 0) + 1;
  wchar_t *dest = malloc((len + 1) * sizeof(wchar_t));
  mbstowcs(dest, src, len);
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str2wide>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  xor    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  call   <mbstowcs@plt>
  lea    0x8(,%rax,4),%edi
  mov    %eax,%ebx
  call   <malloc@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
wchar_t *str2wide(char *src) {
  int len = mbstowcs(NULL, src, 0) + 1;
  wchar_t *dest = malloc((len + 1) * sizeof(wchar_t));
  mbstowcs(dest, src, len);
  return dest;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L29:
  cmp    %rdx,%rsp
  je     L31
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L29
L31:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L51
  orq    $0x0,-0x8(%rsp,%rax,1)
L51:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L55
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,4),%r15
L67:
  mov    $0x0,%eax
  call   <rand_float@plt>
  mulss  D24(%rip),%xmm0
  subss  D2(%rip),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %r15,%rbx
  jne    L67
L55:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L52
  mov    $0x0,%ebx
L71:
  mov    $0x1,%edx
  mov    %r14,%rsi
  movss  D28(%rip),%xmm0
  mov    %r12d,%edi
  call   <stdlib_strided_dsvariancepn@plt>
  ucomisd %xmm0,%xmm0
  jp     L61
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L71
L52:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L91:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L61:
  lea    D5(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L91
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
data_type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D2
data_type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D28
data_type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: {"D24": [0x00,0x40,0x9c,0x46]}

tool: {"D2": [0x00,0x40,0x1c,0x46]}

tool: {"D28": [0x00,0x00,0x80,0x3f]}

tool: D5: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dsvariancepn(len, 1.0f, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L13
L90:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L90
L13:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L113
L9:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L86
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,4),%r14
  nopl   0x0(%rax)
L82:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand_float@plt>
  mulss  D39(%rip),%xmm0
  subss  D18(%rip),%xmm0
  movss  %xmm0,-0x4(%r15)
  cmp    %r14,%r15
  jne    L82
L86:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L16
  xor    %r14d,%r14d
  jmp    L109
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L16
L109:
  movss  D32(%rip),%xmm0
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dsvariancepn@plt>
  ucomisd %xmm0,%xmm0
  jnp    L2
  lea    D11(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L110:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L110
  cs nopw 0x0(%rax,%rax,1)
L113:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L9
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_infered: byte[4]
name: unpack_data
arguments: data_label: D18
type_infered: byte[4]
name: unpack_data
arguments: data_label: D32
type_infered: byte[4]
name: unpack_data
arguments: data_label: D11
type_infered: string

tool: {"D39": [0x00,0x40,0x9c,0x46]}

tool: {"D18": [0x00,0x40,0x1c,0x46]}

tool: {"D32": [0x00,0x00,0x80,0x3f]}

tool: D11: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dsvariancepn(len, 1.0f, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```