user: 这段汇编代码用C语言表示是什么样的：

```asm
<d_name>:
  endbr64
  mov    %edi,%r8d
  movslq %edi,%rax
  lea    0x0(,%rax,8),%rcx
  sub    %rax,%rcx
  lea    D0(%rip),%rax
  add    %rax,%rcx
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%edi
  lea    0x7(%r8),%edx
  test   %r8d,%r8d
  cmovns %r8d,%edx
  sar    $0x3,%edx
  mov    %edx,%esi
  lea    0x41(%rax),%r9d
  mov    %r9b,0x2(%rcx)
  lea    0x31(%rdx),%r9d
  mov    %r9b,0x3(%rcx)
  movb   $0x0,0x6(%rcx)
  lea    -0x10(%r8),%r9d
  cmp    $0x1f,%r9d
  setbe  %r9b
  cmp    $0x1,%eax
  jg     L269
  test   %r9b,%r9b
  jne    L235
L269:
  cmp    $0x5,%eax
  jle    L177
  test   %r9b,%r9b
  jne    L184
L177:
  lea    -0x2(%rax),%r9d
  cmp    $0x3,%r9d
  setbe  %r9b
  cmp    $0xf,%r8d
  jg     L78
  test   %r9b,%r9b
  jne    L76
L78:
  cmp    $0x2f,%r8d
  jle    L107
  test   %r9b,%r9b
  jne    L138
L107:
  movb   $0x0,(%rcx)
L0:
  mov    %rcx,%rax
  ret
L235:
  sub    $0x1,%edx
  add    $0x1,%eax
  cmp    $0x1,%edx
  jle    L2
  cmp    $0x5,%eax
  jle    L235
L2:
  add    $0x41,%eax
  mov    %al,(%rcx)
  add    $0x31,%edx
  mov    %dl,0x1(%rcx)
L174:
  add    $0x1,%esi
  add    $0x1,%edi
  cmp    $0x5,%esi
  jg     L110
  cmp    $0x5,%edi
  jle    L174
L110:
  add    $0x41,%edi
  mov    %dil,0x4(%rcx)
  add    $0x31,%esi
  mov    %sil,0x5(%rcx)
  jmp    L0
L184:
  sub    $0x1,%edx
  sub    $0x1,%eax
  cmp    $0x1,%edx
  jle    L122
  cmp    $0x1,%eax
  jg     L184
L122:
  add    $0x41,%eax
  mov    %al,(%rcx)
  add    $0x31,%edx
  mov    %dl,0x1(%rcx)
L24:
  add    $0x1,%esi
  sub    $0x1,%edi
  cmp    $0x5,%esi
  jg     L252
  cmp    $0x1,%edi
  jg     L24
L252:
  add    $0x41,%edi
  mov    %dil,0x4(%rcx)
  add    $0x31,%esi
  mov    %sil,0x5(%rcx)
  jmp    L0
L76:
  add    $0x1,%edx
  sub    $0x1,%eax
  cmp    $0x5,%edx
  jg     L232
  cmp    $0x1,%eax
  jg     L76
L232:
  add    $0x41,%eax
  add    $0x31,%edx
L245:
  add    $0x1,%esi
  add    $0x1,%edi
  cmp    $0x5,%esi
  jg     L260
  cmp    $0x5,%edi
  jle    L245
L260:
  mov    %al,(%rcx)
  mov    %dl,0x1(%rcx)
  add    $0x41,%edi
  mov    %dil,0x4(%rcx)
  add    $0x31,%esi
  mov    %sil,0x5(%rcx)
  jmp    L0
L138:
  sub    $0x1,%edx
  sub    $0x1,%eax
  cmp    $0x1,%edx
  jle    L221
  cmp    $0x1,%eax
  jg     L138
L221:
  add    $0x41,%eax
  add    $0x31,%edx
L258:
  sub    $0x1,%esi
  add    $0x1,%edi
  cmp    $0x1,%esi
  jle    L60
  cmp    $0x5,%edi
  jle    L258
L60:
  mov    %al,(%rcx)
  mov    %dl,0x1(%rcx)
  add    $0x41,%edi
  mov    %dil,0x4(%rcx)
  add    $0x31,%esi
  mov    %sil,0x5(%rcx)
  jmp    L0
```

assistant: ```c
char *d_name(const int x) {
  static char a[64][7];
  char *s = a[x];
  int f, r, h, v;
  f = x % 8;
  r = x / 8;
  s[2] = 'A' + f;
  s[3] = '1' + r;
  s[6] = '\0';
  if (f < 2 && r > 1 && r < 6) {
    for (h = r, v = f; h > 1 && v < 6; --h, ++v)
      ;
    s[0] = 'A' + v;
    s[1] = '1' + h;
    for (h = r, v = f; h < 6 && v < 6; ++h, ++v)
      ;
    s[4] = 'A' + v;
    s[5] = '1' + h;
  } else if (f > 5 && r > 1 && r < 6) {
    for (h = r, v = f; h > 1 && v > 1; --h, --v)
      ;
    s[0] = 'A' + v;
    s[1] = '1' + h;
    for (h = r, v = f; h < 6 && v > 1; ++h, --v)
      ;
    s[4] = 'A' + v;
    s[5] = '1' + h;
  } else if (r < 2 && f > 1 && f < 6) {
    for (h = r, v = f; h < 6 && v > 1; ++h, --v)
      ;
    s[0] = 'A' + v;
    s[1] = '1' + h;
    for (h = r, v = f; h < 6 && v < 6; ++h, ++v)
      ;
    s[4] = 'A' + v;
    s[5] = '1' + h;
  } else if (r > 5 && f > 1 && f < 6) {
    for (h = r, v = f; h > 1 && v > 1; --h, --v)
      ;
    s[0] = 'A' + v;
    s[1] = '1' + h;
    for (h = r, v = f; h > 1 && v < 6; --h, ++v)
      ;
    s[4] = 'A' + v;
    s[5] = '1' + h;
  } else {
    s[0] = '\0';
  }
  return s;
}
```