ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isCompressed>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    D3(%rip),%rsi
  cltq
  lea    -0x3(%rbx,%rax,1),%rdi
  call   <strcmp@plt>
  pop    %rbx
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string

tool: D3: .gz

assistant: ```c
int isCompressed(char *fn) {
  int fnlen;
  fnlen = strlen(fn);
  return strcmp(fn + fnlen - 3, ".gz") == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isCompressed>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    D9(%rip),%rsi
  cltq
  lea    -0x3(%rbx,%rax,1),%rdi
  call   <strcmp@plt>
  pop    %rbx
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: .gz

assistant: ```c
int isCompressed(char *fn) {
  int fnlen;
  fnlen = strlen(fn);
  return strcmp(fn + fnlen - 3, ".gz") == 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<binary_search_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L67
  mov    -0x4(%rbp),%eax
  jmp    L29
L67:
  cmpl   $0x0,-0x4(%rbp)
  jne    L66
  mov    $0xffffffff,%eax
  jmp    L29
L66:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L50
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <binary_search_r>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  je     L11
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  add    %eax,-0x8(%rbp)
  jmp    L11
L50:
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <binary_search_r>
  mov    %eax,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
L29:
  leave
  ret
```

assistant: ```c
int binary_search_r(int *arr, int size, int val) {
  int mid = size / 2;
  int idx;
  if (arr[mid] == val)
    return mid;
  if (!mid)
    return -1;
  if (arr[mid] < val) {
    idx = binary_search_r(arr + mid + 1, size - mid - 1, val);
    if (idx != -1)
      idx += mid + 1;
  } else {
    idx = binary_search_r(arr, mid, val);
  }
  return idx;
}
```
user: What is the c source code of the assembly code below:

```asm
<binary_search_r>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  mov    %ebx,%eax
  movslq %ebx,%rcx
  lea    0x0(,%rcx,4),%r8
  mov    (%rdi,%rcx,4),%ecx
  cmp    %edx,%ecx
  je     L6
  test   %ebx,%ebx
  je     L23
  cmp    %edx,%ecx
  jge    L13
  sub    %ebx,%esi
  sub    $0x1,%esi
  lea    0x4(%rdi,%r8,1),%rdi
  call   <binary_search_r>
  lea    0x1(%rax,%rbx,1),%edx
  cmp    $0xffffffff,%eax
  cmovne %edx,%eax
L6:
  pop    %rbx
  ret
L13:
  mov    %ebx,%esi
  call   <binary_search_r>
  jmp    L6
L23:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int binary_search_r(int *arr, int size, int val) {
  int mid = size / 2;
  int idx;
  if (arr[mid] == val)
    return mid;
  if (!mid)
    return -1;
  if (arr[mid] < val) {
    idx = binary_search_r(arr + mid + 1, size - mid - 1, val);
    if (idx != -1)
      idx += mid + 1;
  } else {
    idx = binary_search_r(arr, mid, val);
  }
  return idx;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<binary_search_r>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  jmp    L21
  nopl   0x0(%rax)
L0:
  test   %ebx,%ebx
  je     L12
  cmp    %edx,%eax
  jl     L4
L21:
  mov    %ebx,%esi
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    (%rdi,%rax,4),%eax
  cmp    %edx,%eax
  jne    L0
  mov    %ebx,%eax
L20:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  sub    %ebx,%esi
  lea    0x4(%rdi,%rcx,1),%rdi
  sub    $0x1,%esi
  call   <binary_search_r>
  cmp    $0xffffffff,%eax
  je     L20
  lea    0x1(%rax,%rbx,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
int binary_search_r(int *arr, int size, int val) {
  int mid = size / 2;
  int idx;
  if (arr[mid] == val)
    return mid;
  if (!mid)
    return -1;
  if (arr[mid] < val) {
    idx = binary_search_r(arr + mid + 1, size - mid - 1, val);
    if (idx != -1)
      idx += mid + 1;
  } else {
    idx = binary_search_r(arr, mid, val);
  }
  return idx;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<binary_search_r>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  push   %rbp
  push   %rbx
  jmp    L53
  nopl   (%rax)
L133:
  test   %esi,%esi
  je     L21
  cmp    %edx,%ecx
  jl     L63
L53:
  mov    %esi,%ebx
  mov    %esi,%eax
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  movslq %ebx,%rcx
  mov    %rcx,%rsi
  lea    0x0(,%rcx,4),%rdi
  mov    (%r8,%rcx,4),%ecx
  cmp    %edx,%ecx
  jne    L133
  mov    %esi,%eax
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  sub    %esi,%eax
  lea    0x4(%r8,%rdi,1),%rdi
  sub    $0x1,%eax
  jmp    L22
  nopl   0x0(%rax)
L57:
  test   %eax,%eax
  je     L21
  cmp    %esi,%edx
  jg     L76
L22:
  mov    %eax,%ebp
  mov    %eax,%ecx
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  movslq %ebp,%rsi
  mov    %rsi,%rax
  lea    0x0(,%rsi,4),%r8
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,%edx
  jne    L57
L7:
  cmp    $0xffffffff,%eax
  je     L24
  lea    0x1(%rax,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L76:
  sub    %eax,%ecx
  lea    0x4(%rdi,%r8,1),%rdi
  lea    -0x1(%rcx),%r12d
  jmp    L122
  nopl   (%rax)
L39:
  test   %r12d,%r12d
  je     L21
  cmp    %ecx,%edx
  jg     L115
L122:
  mov    %r12d,%eax
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  movslq %r12d,%rcx
  lea    0x0(,%rcx,4),%r8
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,%edx
  jne    L39
L169:
  cmp    $0xffffffff,%r12d
  je     L21
  lea    0x1(%r12,%rbp,1),%eax
  jmp    L7
L115:
  sub    %r12d,%eax
  lea    0x4(%rdi,%r8,1),%rdi
  lea    -0x1(%rax),%esi
  call   <binary_search_r>
  cmp    $0xffffffff,%eax
  je     L21
  lea    0x1(%r12,%rax,1),%r12d
  jmp    L169
```

assistant: ```c
int binary_search_r(int *arr, int size, int val) {
  int mid = size / 2;
  int idx;
  if (arr[mid] == val)
    return mid;
  if (!mid)
    return -1;
  if (arr[mid] < val) {
    idx = binary_search_r(arr + mid + 1, size - mid - 1, val);
    if (idx != -1)
      idx += mid + 1;
  } else {
    idx = binary_search_r(arr, mid, val);
  }
  return idx;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<AESIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x6f,%edi
  call   <IntRegister@plt>
  mov    $0x6f,%edi
  call   <IntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void AESIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  ;
  IntRegister(111, pfnHandler);
  IntEnable(111);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AESIntRegister>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6f,%edi
  call   <IntRegister@plt>
  mov    $0x6f,%edi
  call   <IntEnable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void AESIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  ;
  IntRegister(111, pfnHandler);
  IntEnable(111);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AESIntRegister>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6f,%edi
  call   <IntRegister@plt>
  mov    $0x6f,%edi
  add    $0x8,%rsp
  jmp    1070 <IntEnable@plt>
```

assistant: ```c
void AESIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  ;
  IntRegister(111, pfnHandler);
  IntEnable(111);
}
```
user: What is the c source code of the assembly code below:

```asm
<AESIntRegister>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6f,%edi
  call   <IntRegister@plt>
  mov    $0x6f,%edi
  add    $0x8,%rsp
  jmp    1070 <IntEnable@plt>
```

assistant: ```c
void AESIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  ;
  IntRegister(111, pfnHandler);
  IntEnable(111);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <get_stodep_value@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L15:
  mov    $0x0,%eax
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: st1 value was %i instead of 1


assistant: ```c
int main(int argc, char *argv[]) {
  int val;
  val = get_stodep_value();
  if (val != 1) {
    printf("st1 value was %i instead of 1\n", val);
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_stodep_value@plt>
  cmp    $0x1,%eax
  jne    L19
  mov    $0x0,%eax
L15:
  add    $0x8,%rsp
  ret
L19:
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: st1 value was %i instead of 1


assistant: ```c
int main(int argc, char *argv[]) {
  int val;
  val = get_stodep_value();
  if (val != 1) {
    printf("st1 value was %i instead of 1\n", val);
    return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_stodep_value@plt>
  cmp    $0x1,%eax
  jne    L12
  xor    %eax,%eax
L4:
  add    $0x8,%rsp
  ret
L12:
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D8
type: string

tool: D8: st1 value was %i instead of 1


assistant: ```c
int main(int argc, char *argv[]) {
  int val;
  val = get_stodep_value();
  if (val != 1) {
    printf("st1 value was %i instead of 1\n", val);
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_stodep_value@plt>
  cmp    $0x1,%eax
  jne    L13
  xor    %eax,%eax
L14:
  add    $0x8,%rsp
  ret
L13:
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L14
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: st1 value was %i instead of 1


assistant: ```c
int main(int argc, char *argv[]) {
  int val;
  val = get_stodep_value();
  if (val != 1) {
    printf("st1 value was %i instead of 1\n", val);
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L19:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atoi(const char *p) {
  int k = 0;
  while (*p) {
    k = (k << 3) + (k << 1) + (*p) - '0';
    p++;
  }
  return k;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atoi>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
  mov    $0x0,%edx
L26:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L26
L8:
  mov    %edx,%eax
  ret
L6:
  mov    $0x0,%edx
  jmp    L8
```

assistant: ```c
int atoi(const char *p) {
  int k = 0;
  while (*p) {
    k = (k << 3) + (k << 1) + (*p) - '0';
    p++;
  }
  return k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L10
  xchg   %ax,%ax
L12:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L12
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(const char *p) {
  int k = 0;
  while (*p) {
    k = (k << 3) + (k << 1) + (*p) - '0';
    p++;
  }
  return k;
}
```
user: What is the c source code of the assembly code below:

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L6
  xchg   %ax,%ax
L19:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L19
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(const char *p) {
  int k = 0;
  while (*p) {
    k = (k << 3) + (k << 1) + (*p) - '0';
    p++;
  }
  return k;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hparse_dntbl_sz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xb,-0x4(%rbp)
  jg     L15
  mov    -0x4(%rbp),%eax
  lea    0x5(%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  jmp    L16
L15:
  mov    $0x40000,%eax
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: f64

tool: D1: 2

assistant: ```c
int hparse_dntbl_sz(int len) {
  if (len < 12) {
    return (pow(2.0, (len + 5)));
  } else {
    return (262144);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hparse_dntbl_sz>:
  endbr64
  mov    $0x40000,%eax
  cmp    $0xb,%edi
  jle    L5
  ret
L5:
  sub    $0x8,%rsp
  add    $0x5,%edi
  movsd  D6(%rip),%xmm0
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: f64

tool: D6: 2

assistant: ```c
int hparse_dntbl_sz(int len) {
  if (len < 12) {
    return (pow(2.0, (len + 5)));
  } else {
    return (262144);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hparse_dntbl_sz>:
  endbr64
  cmp    $0xb,%edi
  jle    L2
  mov    $0x40000,%eax
  ret
  nop
L2:
  movsd  D8(%rip),%xmm0
  add    $0x5,%edi
  jmp    1050 <pow@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: f64

tool: D8: 2

assistant: ```c
int hparse_dntbl_sz(int len) {
  if (len < 12) {
    return (pow(2.0, (len + 5)));
  } else {
    return (262144);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hparse_dntbl_sz>:
  endbr64
  cmp    $0xb,%edi
  jle    L1
  mov    $0x40000,%eax
  ret
  nop
L1:
  movsd  D2(%rip),%xmm0
  add    $0x5,%edi
  jmp    1050 <pow@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: f64

tool: D2: 2

assistant: ```c
int hparse_dntbl_sz(int len) {
  if (len < 12) {
    return (pow(2.0, (len + 5)));
  } else {
    return (262144);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<doubles_scale_self>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void doubles_scale_self(double *v, int len, double scale) {
  for (int i = 0; i < len; i++)
    v[i] *= scale;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doubles_scale_self>:
  endbr64
  test   %esi,%esi
  jle    L12
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L4:
  movapd %xmm0,%xmm1
  mulsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L4
L12:
  ret
```

assistant: ```c
void doubles_scale_self(double *v, int len, double scale) {
  for (int i = 0; i < len; i++)
    v[i] *= scale;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<doubles_scale_self>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
L19:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rdi)
  cmp    %rax,%rdi
  jne    L19
L15:
  ret
```

assistant: ```c
void doubles_scale_self(double *v, int len, double scale) {
  for (int i = 0; i < len; i++)
    v[i] *= scale;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<doubles_scale_self>:
  endbr64
  test   %esi,%esi
  jle    L49
  cmp    $0x1,%esi
  je     L24
  mov    %esi,%edx
  movapd %xmm0,%xmm2
  mov    %rdi,%rax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L7:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L7
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L18
L1:
  cltq
  lea    (%rdi,%rax,8),%rax
  mulsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L49:
  ret
  xchg   %ax,%ax
L18:
  ret
L24:
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
void doubles_scale_self(double *v, int len, double scale) {
  for (int i = 0; i < len; i++)
    v[i] *= scale;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<forever>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: %d


assistant: ```c
void forever() {
  int z = 0;
  for (;;) {
    printf("%d\n", z);
    z += 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<forever>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
L3:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string

tool: D7: %d


assistant: ```c
void forever() {
  int z = 0;
  for (;;) {
    printf("%d\n", z);
    z += 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<forever>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %d


assistant: ```c
void forever() {
  int z = 0;
  for (;;) {
    printf("%d\n", z);
    z += 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<forever>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d


assistant: ```c
void forever() {
  int z = 0;
  for (;;) {
    printf("%d\n", z);
    z += 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<insert_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  subq   $0x4,-0x20(%rbp)
  subq   $0x4,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,D15(%rip)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    D15(%rip),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int insert_(int *k, int *lp, int *list, int *lptr, int *lnew) {
  static int lsav;
  --lptr;
  --list;
  lsav = lptr[*lp];
  lptr[*lp] = *lnew;
  list[*lnew] = *k;
  lptr[*lnew] = lsav;
  ++(*lnew);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_>:
  endbr64
  mov    %rdi,%r9
  mov    %rdx,%rdi
  sub    $0x4,%rcx
  movslq (%rsi),%rax
  lea    (%rcx,%rax,4),%rdx
  mov    (%rdx),%esi
  mov    (%r8),%eax
  mov    %eax,(%rdx)
  mov    (%r9),%edx
  cltq
  mov    %edx,-0x4(%rdi,%rax,4)
  movslq (%r8),%rax
  mov    %esi,(%rcx,%rax,4)
  addl   $0x1,(%r8)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int insert_(int *k, int *lp, int *list, int *lptr, int *lnew) {
  static int lsav;
  --lptr;
  --list;
  lsav = lptr[*lp];
  lptr[*lp] = *lnew;
  list[*lnew] = *k;
  lptr[*lnew] = lsav;
  ++(*lnew);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_>:
  endbr64
  movslq (%rsi),%rax
  sub    $0x4,%rcx
  mov    %rdx,%r9
  lea    (%rcx,%rax,4),%rdx
  movslq (%r8),%rax
  mov    (%rdx),%esi
  mov    %eax,(%rdx)
  mov    (%rdi),%edx
  mov    %edx,-0x4(%r9,%rax,4)
  movslq (%r8),%rax
  mov    %esi,(%rcx,%rax,4)
  xor    %eax,%eax
  addl   $0x1,(%r8)
  ret
```

assistant: ```c
int insert_(int *k, int *lp, int *list, int *lptr, int *lnew) {
  static int lsav;
  --lptr;
  --list;
  lsav = lptr[*lp];
  lptr[*lp] = *lnew;
  list[*lnew] = *k;
  lptr[*lnew] = lsav;
  ++(*lnew);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<insert_>:
  endbr64
  movslq (%rsi),%rax
  sub    $0x4,%rcx
  mov    %rdx,%r9
  lea    (%rcx,%rax,4),%rdx
  movslq (%r8),%rax
  mov    (%rdx),%esi
  mov    %eax,(%rdx)
  mov    (%rdi),%edx
  mov    %edx,-0x4(%r9,%rax,4)
  movslq (%r8),%rax
  mov    %esi,(%rcx,%rax,4)
  xor    %eax,%eax
  addl   $0x1,(%r8)
  ret
```

assistant: ```c
int insert_(int *k, int *lp, int *list, int *lptr, int *lnew) {
  static int lsav;
  --lptr;
  --list;
  lsav = lptr[*lp];
  lptr[*lp] = *lnew;
  list[*lnew] = *k;
  lptr[*lnew] = lsav;
  ++(*lnew);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test12>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int test12(void) {
  void *ptr;
  ptr = malloc(10);
  free(ptr);
  free(ptr);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test12>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int test12(void) {
  void *ptr;
  ptr = malloc(10);
  free(ptr);
  free(ptr);
  return 0;
}
```