user: 这段汇编代码用C语言表示是什么样的?

```asm
<getStringBraceParam>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  test   %rbp,%rbp
  je     L166
  movzbl 0x0(%rbp),%edx
  mov    %rdi,%rbx
  lea    0x1(%rbp),%rax
  cmp    $0x20,%dl
  jne    L131
  nopw   0x0(%rax,%rax,1)
L67:
  mov    %rax,(%rbx)
  mov    %rax,%rbp
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L67
L131:
  cmp    $0x5c,%dl
  je     L92
  lea    0x1(%rbp),%r9
  cmp    $0x7b,%dl
  jne    L58
  movzbl 0x1(%rbp),%eax
  test   %al,%al
  je     L37
  mov    %r9,%rsi
  mov    $0x1,%edi
  xor    %r8d,%r8d
  jmp    L52
  nopl   0x0(%rax)
L21:
  cmp    $0x7d,%al
  je     L26
L132:
  test   %edi,%edi
  setne  %cl
L103:
  movzbl 0x1(%rsi),%edx
  lea    0x1(%rsi),%r12
  mov    %eax,%r8d
  test   %dl,%dl
  je     L123
L79:
  test   %cl,%cl
  je     L123
  mov    %r12,%rsi
  mov    %edx,%eax
L52:
  cmp    $0x7b,%al
  jne    L21
  cmp    $0x5c,%r8b
  je     L132
  movzbl 0x1(%rsi),%edx
  add    $0x1,%edi
  mov    $0x1,%ecx
  lea    0x1(%rsi),%r12
  mov    %eax,%r8d
  test   %dl,%dl
  jne    L79
  xchg   %ax,%ax
L123:
  sub    %rbp,%rsi
  sub    $0x1,%esi
L72:
  mov    %r9,%rdi
  call   <my_strndup@plt>
  mov    %r12,(%rbx)
  mov    %r12,%rcx
  mov    $0x6,%edi
  mov    %rax,%r13
  mov    %rax,%rdx
  lea    D6(%rip),%rsi
  xor    %eax,%eax
  call   <diagnostics@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %r9,(%rbx)
  mov    $0x1,%esi
L139:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <my_strndup@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  cmp    $0x5c,%r8b
  je     L132
  sub    $0x1,%edi
  setne  %cl
  jmp    L103
  nopl   (%rax)
L92:
  mov    %rbp,%rax
  jmp    L11
  nopl   (%rax)
L142:
  mov    (%rbx),%rax
L11:
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl 0x1(%rax),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L142
  mov    (%rbx),%rdx
  lea    D16(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <diagnostics@plt>
  mov    (%rbx),%rsi
  sub    %ebp,%esi
  jmp    L139
  nopl   (%rax)
L166:
  add    $0x8,%rsp
  lea    D19(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <my_strdup@plt>
L37:
  mov    %r9,%r12
  mov    $0xffffffff,%esi
  jmp    L72
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D19
type: string

tool: D6: Extract parameter=<%s> after=<%s>

tool: D16: getstringbraceparam \ before='%s'

tool: 

assistant: ```c
char *getStringBraceParam(char **s) {
  char *p_start, *p, *parameter, last;
  int braces;
  if (*s == NULL)
    return my_strdup("");
  while (**s == ' ')
    (*s)++;
  if (**s == '\n') {
    while (**s == ' ')
      (*s)++;
  }
  p_start = *s;
  if (**s == '\\') {
    do {
      (*s)++;
    } while (isalpha(**s));
    diagnostics(1, "getstringbraceparam \\ before='%s'", *s);
    return my_strndup(p_start, (*s) - p_start);
  }
  if (**s != '{') {
    (*s)++;
    return my_strndup(p_start, 1);
  }
  p_start++;
  p = p_start;
  last = '\0';
  braces = 1;
  while (*p != '\0' && braces > 0) {
    if (*p == '{' && last != '\\')
      braces++;
    if (*p == '}' && last != '\\')
      braces--;
    last = *p;
    p++;
  }
  parameter = my_strndup(p_start, p - p_start - 1);
  *s = p;
  diagnostics(6, "Extract parameter=<%s> after=<%s>", parameter, *s);
  return parameter;
}
```