ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<upcase_c>:
  endbr64
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char upcase_c(char c) {
  if ((c >= 'a') && (c <= 'z')) {
    return c - 0x20;
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<upcase_c>:
  endbr64
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char upcase_c(char c) {
  if ((c >= 'a') && (c <= 'z')) {
    return c - 0x20;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<upcase_c>:
  endbr64
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char upcase_c(char c) {
  if ((c >= 'a') && (c <= 'z')) {
    return c - 0x20;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sieve>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L98:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L98
  sub    $0xc68,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  cmpl   $0x0,(%rdi)
  jle    L4
  mov    %rsi,%rbx
  mov    $0x0,%ebp
L21:
  mov    %rbx,0x8(%rsp)
  mov    (%rbx),%edi
  call   <is_prime@plt>
  test   %rax,%rax
  jne    L84
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,(%r12)
  jg     L21
  jmp    L4
L84:
  mov    0x0(%r13),%eax
  add    $0x1,%eax
  mov    %eax,0x0(%r13)
  mov    0x8(%rsp),%rsi
  mov    (%rsi),%edx
  cltq
  mov    %edx,(%r15,%rax,4)
L4:
  mov    0x0(%r13),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    (%r12),%eax
  test   %eax,%eax
  jle    L69
  movslq 0x0(%r13),%rdx
  mov    (%r15,%rdx,4),%edi
  mov    %r14,%rcx
  lea    -0x1(%rax),%eax
  lea    0x4(%r14,%rax,4),%r8
  mov    $0xffffffff,%ebx
  jmp    L43
L64:
  add    $0x4,%rcx
  cmp    %r8,%rcx
  je     L61
L43:
  mov    (%rcx),%esi
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L64
  add    $0x1,%ebx
  movslq %ebx,%rax
  mov    %esi,0x10(%rsp,%rax,4)
  jmp    L64
L69:
  mov    $0xffffffff,%ebx
L61:
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  lea    0x1(%rbx),%edx
  mov    %edx,(%r12)
  shl    $0x2,%edx
  lea    0x10(%rsp),%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  movslq 0x0(%r13),%rax
  mov    (%r15,%rax,4),%ebp
  movslq %ebx,%rbx
  mov    0x10(%rsp,%rbx,4),%edi
  call   <sqrt@plt>
  cmp    %eax,%ebp
  jle    L109
L33:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x9c68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L109:
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sieve>
  jmp    L33
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sieve(int *list_len, int list[], int primes[], int *primes_index) {
  int i;
  int work_index, work[10000];
  for (i = 0; i < *list_len; i++) {
    if (is_prime(list[i])) {
      primes[++(*primes_index)] = list[i];
      break;
    }
  }
  assert(*primes_index >= 0);
  work_index = -1;
  for (i = 0; i < *list_len; i++)
    if (list[i] % primes[*primes_index] != 0)
      work[++work_index] = list[i];
  assert(work_index >= 0);
  *list_len = work_index + 1;
  memcpy(list, work, sizeof(work[0]) * *list_len);
  if (primes[*primes_index] > sqrt(work[work_index]))
    return;
  sieve(list_len, list, primes, primes_index);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sieve>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L90:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L90
  sub    $0xc68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%r12
  test   %eax,%eax
  jle    L2
  mov    %rsi,%rbx
  xor    %r15d,%r15d
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x1,%r15d
  add    $0x4,%rbx
  cmp    %r15d,0x0(%rbp)
  jle    L2
L4:
  mov    (%rbx),%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L56
  mov    (%r12),%eax
  add    $0x1,%eax
  mov    %eax,(%r12)
  mov    (%rbx),%edx
  cltq
  mov    %edx,(%r14,%rax,4)
L2:
  mov    (%r12),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jle    L18
  movslq (%r12),%rdx
  sub    $0x1,%eax
  mov    %r13,%rcx
  mov    $0xffffffff,%ebx
  lea    0x4(%r13,%rax,4),%r8
  mov    (%r14,%rdx,4),%edi
  xchg   %ax,%ax
L96:
  mov    (%rcx),%esi
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L95
  add    $0x1,%ebx
  movslq %ebx,%rax
  mov    %esi,0x10(%rsp,%rax,4)
L95:
  add    $0x4,%rcx
  cmp    %rcx,%r8
  jne    L96
  mov    %ebx,%edi
  lea    0x1(%rbx),%r15d
  not    %edi
  lea    0x0(,%r15,4),%edx
  shr    $0x1f,%edi
L1:
  mov    %edx,0xc(%rsp)
  movslq %ebx,%rbx
  call   <assert@plt>
  mov    %r15d,0x0(%rbp)
  mov    0xc(%rsp),%edx
  mov    %r13,%rdi
  lea    0x10(%rsp),%rsi
  call   <memcpy@plt>
  movslq (%r12),%rax
  mov    0x10(%rsp,%rbx,4),%edi
  mov    (%r14,%rax,4),%r15d
  call   <sqrt@plt>
  cmp    %eax,%r15d
  jg     L38
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sieve>
L38:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x9c68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L18:
  xor    %edx,%edx
  xor    %r15d,%r15d
  xor    %edi,%edi
  mov    $0xffffffff,%ebx
  jmp    L1
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sieve(int *list_len, int list[], int primes[], int *primes_index) {
  int i;
  int work_index, work[10000];
  for (i = 0; i < *list_len; i++) {
    if (is_prime(list[i])) {
      primes[++(*primes_index)] = list[i];
      break;
    }
  }
  assert(*primes_index >= 0);
  work_index = -1;
  for (i = 0; i < *list_len; i++)
    if (list[i] % primes[*primes_index] != 0)
      work[++work_index] = list[i];
  assert(work_index >= 0);
  *list_len = work_index + 1;
  memcpy(list, work, sizeof(work[0]) * *list_len);
  if (primes[*primes_index] > sqrt(work[work_index]))
    return;
  sieve(list_len, list, primes, primes_index);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sieve>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L106:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L106
  sub    $0xc68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%r12
  test   %eax,%eax
  jle    L39
  mov    %rsi,%rbx
  xor    %r15d,%r15d
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L85:
  add    $0x1,%r15d
  add    $0x4,%rbx
  cmp    %r15d,0x0(%rbp)
  jle    L39
L28:
  mov    (%rbx),%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L85
  mov    (%r12),%eax
  add    $0x1,%eax
  mov    %eax,(%r12)
  mov    (%rbx),%edx
  cltq
  mov    %edx,(%r14,%rax,4)
L39:
  mov    (%r12),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jle    L10
  movslq (%r12),%rdx
  sub    $0x1,%eax
  mov    %r13,%rcx
  mov    $0xffffffff,%ebx
  lea    0x4(%r13,%rax,4),%r8
  mov    (%r14,%rdx,4),%edi
  xchg   %ax,%ax
L40:
  mov    (%rcx),%esi
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L41
  add    $0x1,%ebx
  movslq %ebx,%rax
  mov    %esi,0x10(%rsp,%rax,4)
L41:
  add    $0x4,%rcx
  cmp    %rcx,%r8
  jne    L40
  mov    %ebx,%edi
  lea    0x1(%rbx),%r15d
  not    %edi
  lea    0x0(,%r15,4),%edx
  shr    $0x1f,%edi
L11:
  mov    %edx,0xc(%rsp)
  movslq %ebx,%rbx
  call   <assert@plt>
  mov    %r15d,0x0(%rbp)
  mov    0xc(%rsp),%edx
  mov    %r13,%rdi
  lea    0x10(%rsp),%rsi
  call   <memcpy@plt>
  movslq (%r12),%rax
  mov    0x10(%rsp,%rbx,4),%edi
  mov    (%r14,%rax,4),%r15d
  call   <sqrt@plt>
  cmp    %eax,%r15d
  jg     L96
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sieve>
L96:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  add    $0x9c68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L10:
  xor    %edx,%edx
  xor    %r15d,%r15d
  xor    %edi,%edi
  mov    $0xffffffff,%ebx
  jmp    L11
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sieve(int *list_len, int list[], int primes[], int *primes_index) {
  int i;
  int work_index, work[10000];
  for (i = 0; i < *list_len; i++) {
    if (is_prime(list[i])) {
      primes[++(*primes_index)] = list[i];
      break;
    }
  }
  assert(*primes_index >= 0);
  work_index = -1;
  for (i = 0; i < *list_len; i++)
    if (list[i] % primes[*primes_index] != 0)
      work[++work_index] = list[i];
  assert(work_index >= 0);
  *list_len = work_index + 1;
  memcpy(list, work, sizeof(work[0]) * *list_len);
  if (primes[*primes_index] > sqrt(work[work_index]))
    return;
  sieve(list_len, list, primes, primes_index);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<free_buff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void free_buff(void *buff) {
  if (buff)
    free(buff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_buff>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
void free_buff(void *buff) {
  if (buff)
    free(buff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<free_buff>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L5:
  ret
```

assistant: ```c
void free_buff(void *buff) {
  if (buff)
    free(buff);
}
```
user: What is the c source code of the assembly code below?

```asm
<free_buff>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
void free_buff(void *buff) {
  if (buff)
    free(buff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0xfe,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x4(%rbp)
  js     L12
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    $0x28,%rax
  cmp    %rax,%rdx
  jb     L5
L12:
  nop
  pop    %rbp
  ret
```

assistant: ```c
f(int s, char *p) {
  int i;
  for (i = s; i >= 0 && &p[i] < &p[40]; i++) {
    p[i] = -2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  test   %edi,%edi
  js     L36
  movslq %edi,%rax
  add    %rsi,%rax
  lea    0x28(%rsi),%rdx
  cmp    %rdx,%rax
  jae    L36
  movb   $0xfe,(%rax)
  lea    0x1(%rdi),%eax
  cltq
  add    %rax,%rsi
  mov    %rsi,%rax
  add    $0x1,%edi
  sub    %esi,%edi
L19:
  cmp    %rax,%rdx
  jbe    L36
  movb   $0xfe,(%rax)
  add    $0x1,%rax
  mov    %edi,%ecx
  add    %eax,%ecx
  jns    L19
L36:
  mov    $0x0,%eax
  ret
```

assistant: ```c
f(int s, char *p) {
  int i;
  for (i = s; i >= 0 && &p[i] < &p[40]; i++) {
    p[i] = -2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f>:
  endbr64
  test   %edi,%edi
  js     L8
  movslq %edi,%rdi
  lea    0x28(%rsi),%rcx
  lea    (%rsi,%rdi,1),%rdx
  cmp    %rcx,%rdx
  jae    L8
  mov    $0x28,%eax
  lea    0x1(%rsi,%rdi,1),%rsi
  sub    %rdi,%rax
  cmp    %rsi,%rcx
  mov    $0x1,%ecx
  cmovb  %rcx,%rax
  movabs $0xfefefefefefefefe,%rcx
  cmp    $0x8,%rax
  jb     L21
  lea    0x8(%rdx),%rsi
  mov    %rcx,(%rdx)
  and    $0xfffffffffffffff8,%rsi
  mov    %rcx,-0x8(%rdx,%rax,1)
  sub    %rsi,%rdx
  add    %rdx,%rax
  and    $0xfffffffffffffff8,%rax
  cmp    $0x8,%rax
  jb     L8
  and    $0xfffffffffffffff8,%rax
  xor    %edx,%edx
L18:
  mov    %rcx,(%rsi,%rdx,1)
  add    $0x8,%rdx
  cmp    %rax,%rdx
  jb     L18
L8:
  ret
  nopl   (%rax)
L21:
  test   $0x4,%al
  jne    L53
  test   %rax,%rax
  je     L8
  movb   $0xfe,(%rdx)
  test   $0x2,%al
  je     L8
  mov    $0xfffffefe,%ecx
  mov    %cx,-0x2(%rdx,%rax,1)
  ret
L53:
  movl   $0xfefefefe,(%rdx)
  movl   $0xfefefefe,-0x4(%rdx,%rax,1)
  ret
```

assistant: ```c
f(int s, char *p) {
  int i;
  for (i = s; i >= 0 && &p[i] < &p[40]; i++) {
    p[i] = -2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  test   %edi,%edi
  js     L65
  movslq %edi,%rdi
  lea    0x28(%rsi),%rcx
  lea    (%rsi,%rdi,1),%rdx
  cmp    %rcx,%rdx
  jae    L65
  mov    $0x28,%eax
  lea    0x1(%rsi,%rdi,1),%rsi
  sub    %rdi,%rax
  cmp    %rsi,%rcx
  mov    $0x1,%ecx
  cmovb  %rcx,%rax
  movabs $0xfefefefefefefefe,%rcx
  cmp    $0x8,%rax
  jb     L25
  lea    0x8(%rdx),%rsi
  mov    %rcx,(%rdx)
  and    $0xfffffffffffffff8,%rsi
  mov    %rcx,-0x8(%rdx,%rax,1)
  sub    %rsi,%rdx
  add    %rdx,%rax
  and    $0xfffffffffffffff8,%rax
  cmp    $0x8,%rax
  jb     L65
  and    $0xfffffffffffffff8,%rax
  xor    %edx,%edx
L45:
  mov    %rcx,(%rsi,%rdx,1)
  add    $0x8,%rdx
  cmp    %rax,%rdx
  jb     L45
L65:
  ret
  nopl   (%rax)
L25:
  test   $0x4,%al
  jne    L10
  test   %rax,%rax
  je     L65
  movb   $0xfe,(%rdx)
  test   $0x2,%al
  je     L65
  mov    $0xfffffefe,%ecx
  mov    %cx,-0x2(%rdx,%rax,1)
  ret
L10:
  movl   $0xfefefefe,(%rdx)
  movl   $0xfefefefe,-0x4(%rdx,%rax,1)
  ret
```

assistant: ```c
f(int s, char *p) {
  int i;
  for (i = s; i >= 0 && &p[i] < &p[40]; i++) {
    p[i] = -2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int check_file(const char *f) {
  struct stat cst;
  return lstat(f, &cst);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_file(const char *f) {
  struct stat cst;
  return lstat(f, &cst);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_file(const char *f) {
  struct stat cst;
  return lstat(f, &cst);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_file(const char *f) {
  struct stat cst;
  return lstat(f, &cst);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ltspfs_rmdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L24:
  cmp    %rdx,%rsp
  je     L0
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L24
L0:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L46
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L46:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <get_fn@plt>
  test   %rax,%rax
  je     L6
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <eacces@plt>
  mov    %rbx,%rsp
  jmp    L21
L6:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <rmdir@plt>
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <status_return@plt>
  mov    %rbx,%rsp
L21:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void ltspfs_rmdir(int sockfd, XDR *in) {
  char path[PATH_MAX];
  if (get_fn(sockfd, in, path)) {
    eacces(sockfd);
    return;
  }
  status_return(sockfd, rmdir(path));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ltspfs_rmdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    D9(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L0:
  cmp    %rdx,%rsp
  je     L29
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L0
L29:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L41
  orq    $0x0,-0x8(%rsp,%rax,1)
L41:
  mov    %rsp,%r13
  mov    %rsp,%rdx
  mov    %ebx,%edi
  call   <get_fn@plt>
  test   %rax,%rax
  jne    L15
  mov    %r13,%rdi
  call   <rmdir@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <status_return@plt>
  mov    %r12,%rsp
L21:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L15:
  mov    %ebx,%edi
  call   <eacces@plt>
  mov    %r12,%rsp
  jmp    L21
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ltspfs_rmdir(int sockfd, XDR *in) {
  char path[PATH_MAX];
  if (get_fn(sockfd, in, path)) {
    eacces(sockfd);
    return;
  }
  status_return(sockfd, rmdir(path));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ltspfs_rmdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %rsp,%rcx
  mov    %rsp,%rbx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L24
L42:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L42
L24:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L61
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <get_fn@plt>
  test   %rax,%rax
  jne    L21
L10:
  mov    %rsp,%rdi
  call   <rmdir@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <status_return@plt>
  mov    %rbx,%rsp
L78:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r12d,%edi
  call   <eacces@plt>
  mov    %rbx,%rsp
  jmp    L78
  nopl   (%rax)
L61:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <get_fn@plt>
  test   %rax,%rax
  je     L10
  jmp    L21
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ltspfs_rmdir(int sockfd, XDR *in) {
  char path[PATH_MAX];
  if (get_fn(sockfd, in, path)) {
    eacces(sockfd);
    return;
  }
  status_return(sockfd, rmdir(path));
}
```
user: What is the c source code of the assembly code below?

```asm
<ltspfs_rmdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %rsp,%rcx
  mov    %rsp,%rbx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L27
L72:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L72
L27:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L65
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <get_fn@plt>
  test   %rax,%rax
  jne    L15
L50:
  mov    %rsp,%rdi
  call   <rmdir@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <status_return@plt>
  mov    %rbx,%rsp
L40:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12d,%edi
  call   <eacces@plt>
  mov    %rbx,%rsp
  jmp    L40
  nopl   (%rax)
L65:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <get_fn@plt>
  test   %rax,%rax
  je     L50
  jmp    L15
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ltspfs_rmdir(int sockfd, XDR *in) {
  char path[PATH_MAX];
  if (get_fn(sockfd, in, path)) {
    eacces(sockfd);
    return;
  }
  status_return(sockfd, rmdir(path));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<openssl_error_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <ERR_get_error@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ERR_reason_error_string@plt>
  leave
  ret
```

assistant: ```c
const char *openssl_error_string(void) {
  unsigned long error_code = ERR_get_error();
  return ERR_reason_error_string(error_code);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<openssl_error_string>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ERR_get_error@plt>
  mov    %rax,%rdi
  call   <ERR_reason_error_string@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
const char *openssl_error_string(void) {
  unsigned long error_code = ERR_get_error();
  return ERR_reason_error_string(error_code);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<openssl_error_string>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ERR_get_error@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <ERR_reason_error_string@plt>
```

assistant: ```c
const char *openssl_error_string(void) {
  unsigned long error_code = ERR_get_error();
  return ERR_reason_error_string(error_code);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<openssl_error_string>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ERR_get_error@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <ERR_reason_error_string@plt>
```

assistant: ```c
const char *openssl_error_string(void) {
  unsigned long error_code = ERR_get_error();
  return ERR_reason_error_string(error_code);
}
```