ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jne    L15
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L19
L15:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <substr>
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int substr(int c[], int low, int high) {
  int p;
  if (low == high)
    return c[high];
  else
    p = (c[low] + substr(c, low + 1, high));
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<substr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  cmp    %edx,%esi
  je     L6
  mov    %esi,%ebx
  lea    0x1(%rsi),%esi
  call   <substr>
  movslq %ebx,%rbx
  add    0x0(%rbp,%rbx,4),%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%eax
  jmp    L19
```

assistant: ```c
int substr(int c[], int low, int high) {
  int p;
  if (low == high)
    return c[high];
  else
    p = (c[low] + substr(c, low + 1, high));
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<substr>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edx
  je     L2
  mov    %edx,%eax
  movslq %esi,%r8
  sub    %esi,%eax
  lea    (%rdi,%r8,4),%rcx
  sub    $0x1,%eax
  add    %r8,%rax
  lea    0x4(%rdi,%rax,4),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  add    (%rcx),%eax
  add    $0x4,%rcx
  cmp    %rsi,%rcx
  jne    L13
L2:
  movslq %edx,%rdx
  add    (%rdi,%rdx,4),%eax
  ret
```

assistant: ```c
int substr(int c[], int low, int high) {
  int p;
  if (low == high)
    return c[high];
  else
    p = (c[low] + substr(c, low + 1, high));
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<substr>:
  endbr64
  mov    %esi,%ecx
  movslq %edx,%rsi
  mov    %rdi,%r8
  xor    %eax,%eax
  cmp    %ecx,%esi
  je     L30
  mov    %esi,%r9d
  sub    %ecx,%r9d
  lea    -0x1(%r9),%eax
  cmp    $0x2,%eax
  jbe    L33
  movslq %ecx,%rax
  pxor   %xmm0,%xmm0
  lea    (%rdi,%rax,4),%rdx
  mov    %r9d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%edi
  lea    0x10(%rdx),%rax
  shl    $0x4,%rdi
  add    %rax,%rdi
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x10,%rax
L66:
  movdqu (%rdx),%xmm1
  mov    %rax,%rdx
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L6
  movdqa %xmm0,%xmm1
  mov    %r9d,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  add    %edx,%ecx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%r9d
  je     L30
L78:
  movslq %ecx,%rdx
  lea    0x0(,%rdx,4),%rdi
  add    (%r8,%rdx,4),%eax
  lea    0x1(%rcx),%edx
  cmp    %esi,%edx
  je     L30
  add    $0x2,%ecx
  add    0x4(%r8,%rdi,1),%eax
  cmp    %ecx,%esi
  je     L30
  add    0x8(%r8,%rdi,1),%eax
L30:
  add    (%r8,%rsi,4),%eax
  ret
L33:
  xor    %eax,%eax
  jmp    L78
```

assistant: ```c
int substr(int c[], int low, int high) {
  int p;
  if (low == high)
    return c[high];
  else
    p = (c[low] + substr(c, low + 1, high));
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printDigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jg     L8
  mov    -0x4(%rbp),%eax
  cltq
  lea    D8(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L19
L8:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  lea    D8(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <printDigit>
L19:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D8: 0123456789

assistant: ```c
void printDigit(int n) {
  if (n < 10) {
    putchar("0123456789"[n]);
  } else {
    putchar("0123456789"[n % 10]);
    printDigit(n / 10);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printDigit>:
  endbr64
  push   %rbx
  cmp    $0x9,%edi
  jg     L16
  movslq %edi,%rdi
  lea    D18(%rip),%rax
  movsbl (%rax,%rdi,1),%edi
  call   <putchar@plt>
L5:
  pop    %rbx
  ret
L16:
  movslq %edi,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  movslq %edi,%rdi
  lea    D18(%rip),%rax
  movsbl (%rax,%rdi,1),%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  call   <printDigit>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D18
datatype: string

tool: D18: 0123456789

assistant: ```c
void printDigit(int n) {
  if (n < 10) {
    putchar("0123456789"[n]);
  } else {
    putchar("0123456789"[n % 10]);
    printDigit(n / 10);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printDigit>:
  endbr64
  push   %r13
  mov    $0xcccccccd,%r13d
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x9,%ebp
  jle    L10
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%ebx
  mov    %ebp,%eax
  imul   %r13,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  movsbl (%r12,%rax,1),%edi
  call   <putchar@plt>
  mov    %ebp,%eax
  movslq %ebx,%rbp
  cmp    $0x63,%eax
  jg     L5
L10:
  movsbl (%r12,%rbp,1),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4: 0123456789

assistant: ```c
void printDigit(int n) {
  if (n < 10) {
    putchar("0123456789"[n]);
  } else {
    putchar("0123456789"[n % 10]);
    printDigit(n / 10);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printDigit>:
  endbr64
  push   %r13
  mov    $0xcccccccd,%r13d
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x9,%ebp
  jle    L6
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebp,%ebx
  mov    %ebp,%eax
  imul   %r13,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  movsbl (%r12,%rax,1),%edi
  call   <putchar@plt>
  mov    %ebp,%eax
  movslq %ebx,%rbp
  cmp    $0x63,%eax
  jg     L1
L6:
  movsbl (%r12,%rbp,1),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: 0123456789

assistant: ```c
void printDigit(int n) {
  if (n < 10) {
    putchar("0123456789"[n]);
  } else {
    putchar("0123456789"[n % 10]);
    printDigit(n / 10);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ctz32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L12
  mov    $0x20,%eax
  jmp    L2
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzwl %ax,%eax
  test   %rax,%rax
  jne    L14
  addl   $0x10,-0xc(%rbp)
  sarq   $0x10,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl %al,%eax
  test   %rax,%rax
  jne    L1
  addl   $0x8,-0xc(%rbp)
  sarq   $0x8,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  and    $0xf,%eax
  test   %rax,%rax
  jne    L34
  addl   $0x4,-0xc(%rbp)
  sarq   $0x4,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%rax
  and    $0x3,%eax
  test   %rax,%rax
  jne    L64
  addl   $0x2,-0xc(%rbp)
  sarq   $0x2,-0x8(%rbp)
L64:
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L21
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t ctz32(uint32_t r1) {
  if (r1 == 0)
    return 32;
  uint32_t temp_r1 = r1;
  uint8_t n = 0;
  if ((temp_r1 & 0x0000ffff) == 0) {
    n += 16;
    temp_r1 = temp_r1 >> 16;
  }
  if ((temp_r1 & 0x000000ff) == 0) {
    n += 8;
    temp_r1 = temp_r1 >> 8;
  }
  if ((temp_r1 & 0x0000000f) == 0) {
    n += 4;
    temp_r1 = temp_r1 >> 4;
  }
  if ((temp_r1 & 0x00000003) == 0) {
    n += 2;
    temp_r1 = temp_r1 >> 2;
  }
  if ((temp_r1 & 0x00000001) == 0) {
    n += 1;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ctz32>:
  endbr64
  mov    $0x20,%eax
  test   %rdi,%rdi
  je     L38
  mov    $0x0,%eax
  test   %di,%di
  jne    L24
  sar    $0x10,%rdi
  mov    $0x10,%eax
L24:
  test   %dil,%dil
  jne    L10
  add    $0x8,%eax
  sar    $0x8,%rdi
L10:
  test   $0xf,%dil
  jne    L31
  add    $0x4,%eax
  sar    $0x4,%rdi
L31:
  test   $0x3,%dil
  jne    L49
  add    $0x2,%eax
  sar    $0x2,%rdi
L49:
  and    $0x1,%edi
  cmp    $0x1,%rdi
  adc    $0x0,%eax
L38:
  ret
```

assistant: ```c
uint8_t ctz32(uint32_t r1) {
  if (r1 == 0)
    return 32;
  uint32_t temp_r1 = r1;
  uint8_t n = 0;
  if ((temp_r1 & 0x0000ffff) == 0) {
    n += 16;
    temp_r1 = temp_r1 >> 16;
  }
  if ((temp_r1 & 0x000000ff) == 0) {
    n += 8;
    temp_r1 = temp_r1 >> 8;
  }
  if ((temp_r1 & 0x0000000f) == 0) {
    n += 4;
    temp_r1 = temp_r1 >> 4;
  }
  if ((temp_r1 & 0x00000003) == 0) {
    n += 2;
    temp_r1 = temp_r1 >> 2;
  }
  if ((temp_r1 & 0x00000001) == 0) {
    n += 1;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ctz32>:
  endbr64
  mov    $0x20,%eax
  test   %rdi,%rdi
  je     L39
  xor    %eax,%eax
  test   %di,%di
  jne    L15
  sar    $0x10,%rdi
  mov    $0x10,%eax
L15:
  test   %dil,%dil
  jne    L47
  add    $0x8,%eax
  sar    $0x8,%rdi
L47:
  test   $0xf,%dil
  jne    L29
  add    $0x4,%eax
  sar    $0x4,%rdi
L29:
  test   $0x3,%dil
  jne    L5
  add    $0x2,%eax
  sar    $0x2,%rdi
L5:
  and    $0x1,%edi
  cmp    $0x1,%rdi
  adc    $0x0,%eax
L39:
  ret
```

assistant: ```c
uint8_t ctz32(uint32_t r1) {
  if (r1 == 0)
    return 32;
  uint32_t temp_r1 = r1;
  uint8_t n = 0;
  if ((temp_r1 & 0x0000ffff) == 0) {
    n += 16;
    temp_r1 = temp_r1 >> 16;
  }
  if ((temp_r1 & 0x000000ff) == 0) {
    n += 8;
    temp_r1 = temp_r1 >> 8;
  }
  if ((temp_r1 & 0x0000000f) == 0) {
    n += 4;
    temp_r1 = temp_r1 >> 4;
  }
  if ((temp_r1 & 0x00000003) == 0) {
    n += 2;
    temp_r1 = temp_r1 >> 2;
  }
  if ((temp_r1 & 0x00000001) == 0) {
    n += 1;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ctz32>:
  endbr64
  mov    $0x20,%eax
  test   %rdi,%rdi
  je     L27
  test   %di,%di
  je     L3
  mov    $0x8,%edx
  xor    %eax,%eax
L49:
  test   %dil,%dil
  jne    L34
  sar    $0x8,%rdi
  mov    %edx,%eax
L34:
  test   $0xf,%dil
  jne    L1
  add    $0x4,%eax
  sar    $0x4,%rdi
L1:
  test   $0x3,%dil
  jne    L55
  add    $0x2,%eax
  sar    $0x2,%rdi
L55:
  and    $0x1,%edi
  cmp    $0x1,%rdi
  adc    $0x0,%eax
L27:
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  sar    $0x10,%rdi
  mov    $0x18,%edx
  mov    $0x10,%eax
  jmp    L49
```

assistant: ```c
uint8_t ctz32(uint32_t r1) {
  if (r1 == 0)
    return 32;
  uint32_t temp_r1 = r1;
  uint8_t n = 0;
  if ((temp_r1 & 0x0000ffff) == 0) {
    n += 16;
    temp_r1 = temp_r1 >> 16;
  }
  if ((temp_r1 & 0x000000ff) == 0) {
    n += 8;
    temp_r1 = temp_r1 >> 8;
  }
  if ((temp_r1 & 0x0000000f) == 0) {
    n += 4;
    temp_r1 = temp_r1 >> 4;
  }
  if ((temp_r1 & 0x00000003) == 0) {
    n += 2;
    temp_r1 = temp_r1 >> 2;
  }
  if ((temp_r1 & 0x00000001) == 0) {
    n += 1;
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inv_shift_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x1,%esi
  mov    $0x10,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L19:
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  shl    $0x2,%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  add    $0xd,%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  shl    $0x2,%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  add    $0xa,%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  shl    $0x2,%edx
  movslq %edx,%rdx
  lea    0x2(%rdx),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  add    $0x7,%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  shl    $0x2,%edx
  movslq %edx,%rdx
  lea    0x3(%rdx),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x3,-0xc(%rbp)
  jle    L19
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void inv_shift_row(unsigned char *instring) {
  unsigned char *buf;
  buf = calloc(16, sizeof(unsigned char));
  for (int i = 0; i < 4; i++) {
    buf[(4 * i)] = instring[(4 * i)];
    buf[(4 * i) + 1] = instring[((4 * i) + 1 + 12) % 16];
    buf[(4 * i) + 2] = instring[((4 * i) + 2 + 8) % 16];
    buf[(4 * i) + 3] = instring[((4 * i) + 3 + 4) % 16];
  }
  memcpy(instring, buf, 16);
  free(buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inv_shift_row>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x1,%esi
  mov    $0x10,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
L1:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  lea    0xd(%rax),%edx
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  add    %ecx,%edx
  and    $0xf,%edx
  sub    %ecx,%edx
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%edx
  mov    %dl,0x1(%rbx,%rax,1)
  lea    0xa(%rax),%edx
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  add    %ecx,%edx
  and    $0xf,%edx
  sub    %ecx,%edx
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%edx
  mov    %dl,0x2(%rbx,%rax,1)
  lea    0x7(%rax),%edx
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  add    %ecx,%edx
  and    $0xf,%edx
  sub    %ecx,%edx
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%edx
  mov    %dl,0x3(%rbx,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L1
  mov    $0x10,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void inv_shift_row(unsigned char *instring) {
  unsigned char *buf;
  buf = calloc(16, sizeof(unsigned char));
  for (int i = 0; i < 4; i++) {
    buf[(4 * i)] = instring[(4 * i)];
    buf[(4 * i) + 1] = instring[((4 * i) + 1 + 12) % 16];
    buf[(4 * i) + 2] = instring[((4 * i) + 2 + 8) % 16];
    buf[(4 * i) + 3] = instring[((4 * i) + 3 + 4) % 16];
  }
  memcpy(instring, buf, 16);
  free(buf);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inv_shift_row>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    %rdi,%r12
  mov    $0x10,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
L6:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  lea    0xd(%rax),%edx
  and    $0xf,%edx
  movzbl (%r12,%rdx,1),%edx
  mov    %dl,0x1(%rbp,%rax,1)
  lea    0xa(%rax),%edx
  and    $0xf,%edx
  movzbl (%r12,%rdx,1),%edx
  mov    %dl,0x2(%rbp,%rax,1)
  lea    0x7(%rax),%edx
  and    $0xf,%edx
  movzbl (%r12,%rdx,1),%edx
  mov    %dl,0x3(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L6
  mov    %r12,%rdi
  mov    %rbp,%rsi
  mov    $0x10,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <free@plt>
```

assistant: ```c
void inv_shift_row(unsigned char *instring) {
  unsigned char *buf;
  buf = calloc(16, sizeof(unsigned char));
  for (int i = 0; i < 4; i++) {
    buf[(4 * i)] = instring[(4 * i)];
    buf[(4 * i) + 1] = instring[((4 * i) + 1 + 12) % 16];
    buf[(4 * i) + 2] = instring[((4 * i) + 2 + 8) % 16];
    buf[(4 * i) + 3] = instring[((4 * i) + 3 + 4) % 16];
  }
  memcpy(instring, buf, 16);
  free(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inv_shift_row>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    %rdi,%r12
  mov    $0x10,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %r12,%rdi
  mov    $0x10,%edx
  mov    %rax,%rbp
  movzbl (%r12),%eax
  mov    %rbp,%rsi
  mov    %al,0x0(%rbp)
  movzbl 0xd(%r12),%eax
  mov    %al,0x1(%rbp)
  movzbl 0xa(%r12),%eax
  mov    %al,0x2(%rbp)
  movzbl 0x7(%r12),%eax
  mov    %al,0x3(%rbp)
  movzbl 0x4(%r12),%eax
  mov    %al,0x4(%rbp)
  movzbl 0x1(%r12),%eax
  mov    %al,0x5(%rbp)
  movzbl 0xe(%r12),%eax
  mov    %al,0x6(%rbp)
  movzbl 0xb(%r12),%eax
  mov    %al,0x7(%rbp)
  movzbl 0x8(%r12),%eax
  mov    %al,0x8(%rbp)
  movzbl 0x5(%r12),%eax
  mov    %al,0x9(%rbp)
  movzbl 0x2(%r12),%eax
  mov    %al,0xa(%rbp)
  movzbl 0xf(%r12),%eax
  mov    %al,0xb(%rbp)
  movzbl 0xc(%r12),%eax
  mov    %al,0xc(%rbp)
  movzbl 0x9(%r12),%eax
  mov    %al,0xd(%rbp)
  movzbl 0x6(%r12),%eax
  mov    %al,0xe(%rbp)
  movzbl 0x3(%r12),%eax
  mov    %al,0xf(%rbp)
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <free@plt>
```

assistant: ```c
void inv_shift_row(unsigned char *instring) {
  unsigned char *buf;
  buf = calloc(16, sizeof(unsigned char));
  for (int i = 0; i < 4; i++) {
    buf[(4 * i)] = instring[(4 * i)];
    buf[(4 * i) + 1] = instring[((4 * i) + 1 + 12) % 16];
    buf[(4 * i) + 2] = instring[((4 * i) + 2 + 8) % 16];
    buf[(4 * i) + 3] = instring[((4 * i) + 3 + 4) % 16];
  }
  memcpy(instring, buf, 16);
  free(buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CG_FitTextToWidth2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x420,%rsp
  mov    %rdi,%r14
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x400,%edx
  mov    %r14,%rsi
  call   <Q_strncpyz@plt>
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L83
  mov    %r14,%rbx
  mov    $0x0,%r12d
  lea    0x10(%rsp),%rbp
  jmp    L81
L90:
  mov    $0x0,%esi
  movss  0x8(%rsp),%xmm0
  mov    %r14,%rdi
  call   <CG_Text_Width@plt>
  comiss 0xc(%rsp),%xmm0
  jbe    L5
  test   %r12,%r12
  je     L37
  movb   $0xa,(%r12)
  lea    0x1(%r12),%r14
  mov    %r13,%rbx
  mov    $0x0,%r12d
  jmp    L9
L37:
  movzbl (%rbx),%eax
  mov    %al,0x1(%rbx)
  movb   $0xa,(%rbx)
  add    $0x2,%rbx
  mov    %r13,%r14
  jmp    L9
L5:
  mov    %r13,%rbx
L9:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L54
L81:
  add    $0x1,%rbp
  mov    %al,(%rbx)
  cmp    $0x20,%al
  cmove  %rbx,%r12
  lea    0x1(%rbx),%r13
  cmpb   $0xa,0x0(%rbp)
  jne    L90
  lea    0x2(%rbx),%r14
  movzbl 0x0(%rbp),%eax
  mov    %r13,%rbx
  jmp    L81
L83:
  mov    %r14,%rbx
L54:
  cmpb   $0xa,-0x1(%rbx)
  je     L42
  movb   $0xa,(%rbx)
  lea    0x1(%rbx),%rbx
L42:
  movb   $0x0,(%rbx)
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x420,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CG_FitTextToWidth2(char *instr, float scale, float w, int size) {
  char buffer[1024];
  char *s, *p, *c, *ls;
  int l;
  Q_strncpyz(buffer, instr, 1024);
  memset(instr, 0, size);
  c = s = instr;
  p = buffer;
  ls = ((void *)0);
  l = 0;
  while (*p) {
    *c = *p++;
    l++;
    if (*c == ' ') {
      ls = c;
    }
    c++;
    if (*p == '\n') {
      s = c + 1;
      l = 0;
    } else if (CG_Text_Width(s, scale, 0) > w) {
      if (ls) {
        *ls = '\n';
        s = ls + 1;
      } else {
        *c = *(c - 1);
        *(c - 1) = '\n';
        s = c++;
      }
      ls = ((void *)0);
      l = 0;
    }
  }
  if (c != buffer && (*(c - 1) != '\n')) {
    *c++ = '\n';
  }
  *c = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CG_FitTextToWidth2>:
  endbr64
  push   %r15
  mov    $0x400,%edx
  movd   %xmm0,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  mov    %r14,%rbx
  sub    $0x428,%rsp
  lea    0x10(%rsp),%rbp
  movss  %xmm1,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <Q_strncpyz@plt>
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L80
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rbp
  cmp    $0x20,%al
  mov    %al,(%rbx)
  lea    0x1(%rbx),%r13
  cmove  %rbx,%r12
  cmpb   $0xa,0x0(%rbp)
  jne    L4
  lea    0x2(%rbx),%r14
  mov    $0xa,%eax
  mov    %r13,%rbx
  jmp    L9
  nopl   0x0(%rax)
L4:
  xor    %esi,%esi
  movd   %r15d,%xmm0
  mov    %r14,%rdi
  call   <CG_Text_Width@plt>
  comiss 0xc(%rsp),%xmm0
  jbe    L26
  test   %r12,%r12
  je     L37
  movb   $0xa,(%r12)
  lea    0x1(%r12),%r14
  mov    %r13,%rbx
  xor    %r12d,%r12d
L19:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L9
L80:
  cmpb   $0xa,-0x1(%rbx)
  je     L57
  movb   $0xa,(%rbx)
  add    $0x1,%rbx
L57:
  movb   $0x0,(%rbx)
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  mov    %r13,%rbx
  jmp    L19
  nopl   (%rax)
L37:
  movzbl (%rbx),%eax
  mov    %r13,%r14
  movb   $0xa,(%rbx)
  add    $0x2,%rbx
  mov    %al,-0x1(%rbx)
  jmp    L19
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CG_FitTextToWidth2(char *instr, float scale, float w, int size) {
  char buffer[1024];
  char *s, *p, *c, *ls;
  int l;
  Q_strncpyz(buffer, instr, 1024);
  memset(instr, 0, size);
  c = s = instr;
  p = buffer;
  ls = ((void *)0);
  l = 0;
  while (*p) {
    *c = *p++;
    l++;
    if (*c == ' ') {
      ls = c;
    }
    c++;
    if (*p == '\n') {
      s = c + 1;
      l = 0;
    } else if (CG_Text_Width(s, scale, 0) > w) {
      if (ls) {
        *ls = '\n';
        s = ls + 1;
      } else {
        *c = *(c - 1);
        *(c - 1) = '\n';
        s = c++;
      }
      ls = ((void *)0);
      l = 0;
    }
  }
  if (c != buffer && (*(c - 1) != '\n')) {
    *c++ = '\n';
  }
  *c = '\0';
}
```