user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x1c4(%rbp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    -0x1c4(%rbp),%esi
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L16:
  cmp    %rdx,%rsp
  je     L67
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L16
L67:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L103
  orq    $0x0,-0x8(%rsp,%rax,1)
L103:
  mov    %rsp,%r12
  test   %esi,%esi
  jle    L162
  mov    %r12,%r13
  mov    $0x0,%ebx
  lea    D0(%rip),%r14
L74:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x1c4(%rbp),%esi
  add    $0x4,%r13
  cmp    %ebx,%esi
  jg     L74
L162:
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L135:
  cmp    %rdx,%rsp
  je     L159
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L135
L159:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L119
  orq    $0x0,-0x8(%rsp,%rax,1)
L119:
  mov    %rsp,%rbx
  lea    -0x1c0(%rbp),%rax
  lea    -0x30(%rbp),%rdx
L160:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L160
  test   %esi,%esi
  jle    L82
  mov    %r12,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%r12,%rcx,4),%rdi
L55:
  movslq (%rax),%rcx
  addl   $0x1,-0x1c0(%rbp,%rcx,4)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L55
L82:
  lea    -0x1bc(%rbp),%rax
L115:
  mov    -0x4(%rax),%ecx
  add    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L115
  sub    $0x1,%esi
  js     L121
  movslq %esi,%rax
L95:
  mov    (%r12,%rax,4),%esi
  movslq %esi,%rcx
  mov    -0x1c0(%rbp,%rcx,4),%edi
  lea    -0x1(%rdi),%edx
  movslq %edx,%rdi
  mov    %esi,(%rbx,%rdi,4)
  mov    %edx,-0x1c0(%rbp,%rcx,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L95
L121:
  cmpl   $0x0,-0x1c4(%rbp)
  jle    L93
  mov    $0x0,%r12d
  lea    D24(%rip),%r13
L110:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12
  cmp    %r12d,-0x1c4(%rbp)
  jg     L110
L93:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string
name: parse_data
arguments: tag: D24
datatype: string

tool: D0: %d

tool: D24: %d	

assistant: ```c
main() {
  int n;
  scanf("%d", &n);
  int a[n], i = 0;
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  int b[100], c[n];
  for (i = 0; i < 100; i++)
    b[i] = 0;
  for (i = 0; i < n; i++)
    b[a[i]] += 1;
  for (i = 1; i < 100; i++)
    b[i] += b[i - 1];
  for (i = n - 1; i >= 0; i--) {
    c[b[a[i]] - 1] = a[i];
    b[a[i]]--;
  }
  for (i = 0; i < n; i++)
    printf("%d\t", c[i]);
}
```