ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<func>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L12
L26:
  ret
L12:
  test   %rsi,%rsi
  je     L38
  mov    $0x3,%eax
  test   %rdx,%rdx
  jne    L26
  test   %rcx,%rcx
  sete   %al
  movzbl %al,%eax
  ret
L38:
  mov    $0x2,%eax
  jmp    L26
```

assistant: ```c
int func(char *cp1, char *cp2, char *cp3, char *cp4) {
  if (cp1)
    return 1;
  if (cp2 == NULL)
    return 2;
  if (NULL != cp3)
    return 3;
  return cp4 != 0 ? 0 : 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L27
L21:
  ret
  nop
L27:
  test   %rsi,%rsi
  je     L22
  mov    $0x3,%eax
  test   %rdx,%rdx
  jne    L21
  xor    %eax,%eax
  test   %rcx,%rcx
  sete   %al
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int func(char *cp1, char *cp2, char *cp3, char *cp4) {
  if (cp1)
    return 1;
  if (cp2 == NULL)
    return 2;
  if (NULL != cp3)
    return 3;
  return cp4 != 0 ? 0 : 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L8
L11:
  ret
  nop
L8:
  test   %rsi,%rsi
  je     L19
  mov    $0x3,%eax
  test   %rdx,%rdx
  jne    L11
  xor    %eax,%eax
  test   %rcx,%rcx
  sete   %al
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int func(char *cp1, char *cp2, char *cp3, char *cp4) {
  if (cp1)
    return 1;
  if (cp2 == NULL)
    return 2;
  if (NULL != cp3)
    return 3;
  return cp4 != 0 ? 0 : 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <listprocess@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: inside ps 


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  printf("inside ps \n");
  listprocess();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <listprocess@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: inside ps 


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  printf("inside ps \n");
  listprocess();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <listprocess@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3: inside ps 


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  printf("inside ps \n");
  listprocess();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <listprocess@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: inside ps 


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  printf("inside ps \n");
  listprocess();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D18: i: %d, j: %d


assistant: ```c
int main() {
  int i, j;
  i = 1;
  j = 2;
  printf("i: %d, j: %d\n", i, j);
  i += j;
  j = i - j;
  i -= j;
  ;
  printf("i: %d, j: %d\n", i, j);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: i: %d, j: %d


assistant: ```c
int main() {
  int i, j;
  i = 1;
  j = 2;
  printf("i: %d, j: %d\n", i, j);
  i += j;
  j = i - j;
  i -= j;
  ;
  printf("i: %d, j: %d\n", i, j);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D7: i: %d, j: %d


assistant: ```c
int main() {
  int i, j;
  i = 1;
  j = 2;
  printf("i: %d, j: %d\n", i, j);
  i += j;
  j = i - j;
  i -= j;
  ;
  printf("i: %d, j: %d\n", i, j);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: i: %d, j: %d


assistant: ```c
int main() {
  int i, j;
  i = 1;
  j = 2;
  printf("i: %d, j: %d\n", i, j);
  i += j;
  j = i - j;
  i -= j;
  ;
  printf("i: %d, j: %d\n", i, j);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zero_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zero_arr(uint32_t str[], size_t size) {
  int i;
  for (i = 0; i < size; i++) {
    str[i] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zero_arr>:
  endbr64
  test   %rsi,%rsi
  je     L3
  mov    %rdi,%rax
  lea    (%rdi,%rsi,8),%rdx
L14:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L14
L3:
  ret
```

assistant: ```c
void zero_arr(uint32_t str[], size_t size) {
  int i;
  for (i = 0; i < size; i++) {
    str[i] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zero_arr>:
  endbr64
  test   %rsi,%rsi
  je     L3
  lea    0x0(,%rsi,8),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void zero_arr(uint32_t str[], size_t size) {
  int i;
  for (i = 0; i < size; i++) {
    str[i] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zero_arr>:
  endbr64
  test   %rsi,%rsi
  je     L4
  lea    0x0(,%rsi,8),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void zero_arr(uint32_t str[], size_t size) {
  int i;
  for (i = 0; i < size; i++) {
    str[i] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc4(%rbp)
  jmp    L41
L24:
  mov    -0xc4(%rbp),%eax
  cltq
  movl   $0x0,-0xc0(%rbp,%rax,4)
  mov    -0xc4(%rbp),%eax
  cltq
  movl   $0x0,-0x60(%rbp,%rax,4)
  addl   $0x1,-0xc4(%rbp)
L41:
  cmpl   $0x13,-0xc4(%rbp)
  jle    L24
  lea    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc4(%rbp)
  jmp    L10
L34:
  lea    -0xc0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xc4(%rbp)
L10:
  mov    -0xc8(%rbp),%eax
  cmp    %eax,-0xc4(%rbp)
  jle    L34
  mov    -0xc8(%rbp),%edx
  lea    -0x60(%rbp),%rcx
  lea    -0xc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <next_generation@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d

assistant: ```c
int main() {
  int current[21], next[21], lenght, len_help;
  for (len_help = 0; len_help < 20; len_help++) {
    current[len_help] = 0;
    next[len_help] = 0;
  }
  scanf("%d", &lenght);
  for (len_help = 1; len_help <= lenght; len_help++) {
    scanf("%d", &current[len_help]);
  }
  next_generation(current, next, lenght);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
L25:
  movl   $0x0,0x10(%rsp,%rax,1)
  movl   $0x0,0x70(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x50,%rax
  jne    L25
  lea    0xc(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L13
  lea    0x14(%rsp),%rbp
  mov    $0x1,%ebx
  lea    D9(%rip),%r12
L36:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%edx
  add    $0x4,%rbp
  cmp    %ebx,%edx
  jge    L36
L13:
  lea    0x70(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <next_generation@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: %d

assistant: ```c
int main() {
  int current[21], next[21], lenght, len_help;
  for (len_help = 0; len_help < 20; len_help++) {
    current[len_help] = 0;
    next[len_help] = 0;
  }
  scanf("%d", &lenght);
  for (len_help = 1; len_help <= lenght; len_help++) {
    scanf("%d", &current[len_help]);
  }
  next_generation(current, next, lenght);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  pxor   %xmm0,%xmm0
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L29
  lea    0x14(%rsp),%rbp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebx,%edx
  jge    L6
L29:
  lea    0x70(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <next_generation@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  int current[21], next[21], lenght, len_help;
  for (len_help = 0; len_help < 20; len_help++) {
    current[len_help] = 0;
    next[len_help] = 0;
  }
  scanf("%d", &lenght);
  for (len_help = 1; len_help <= lenght; len_help++) {
    scanf("%d", &current[len_help]);
  }
  next_generation(current, next, lenght);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  pxor   %xmm0,%xmm0
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L17
  lea    0x14(%rsp),%rbp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebx,%edx
  jge    L19
L17:
  lea    0x70(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <next_generation@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: %d

assistant: ```c
int main() {
  int current[21], next[21], lenght, len_help;
  for (len_help = 0; len_help < 20; len_help++) {
    current[len_help] = 0;
    next[len_help] = 0;
  }
  scanf("%d", &lenght);
  for (len_help = 1; len_help <= lenght; len_help++) {
    scanf("%d", &current[len_help]);
  }
  next_generation(current, next, lenght);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CHAR2BCD3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L33:
  addl   $0x1,-0x4(%rbp)
  movzbl -0x14(%rbp),%eax
  sub    $0x64,%eax
  mov    %al,-0x14(%rbp)
L10:
  cmpb   $0x63,-0x14(%rbp)
  jg     L33
  shll   $0x4,-0x4(%rbp)
  jmp    L2
L11:
  addl   $0x1,-0x4(%rbp)
  movzbl -0x14(%rbp),%eax
  sub    $0xa,%eax
  mov    %al,-0x14(%rbp)
L2:
  cmpb   $0x9,-0x14(%rbp)
  jg     L11
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movsbl -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int CHAR2BCD3(char input) {
  int high = 0;
  while (input >= 100) {
    high++;
    input -= 100;
  }
  high <<= 4;
  while (input >= 10) {
    high++;
    input -= 10;
  }
  return (high << 4) | input;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CHAR2BCD3>:
  endbr64
  mov    %edi,%edx
  cmp    $0x63,%dil
  jle    L1
  lea    -0x64(%rdi),%edx
  mov    $0x1,%eax
L7:
  shl    $0x4,%eax
  cmp    $0x9,%dl
  jle    L27
L31:
  add    $0x1,%eax
  sub    $0xa,%edx
  cmp    $0x9,%dl
  jg     L31
L27:
  shl    $0x4,%eax
  movsbl %dl,%edx
  or     %edx,%eax
  ret
L1:
  mov    $0x0,%eax
  jmp    L7
```

assistant: ```c
unsigned int CHAR2BCD3(char input) {
  int high = 0;
  while (input >= 100) {
    high++;
    input -= 100;
  }
  high <<= 4;
  while (input >= 10) {
    high++;
    input -= 10;
  }
  return (high << 4) | input;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CHAR2BCD3>:
  endbr64
  mov    %edi,%edx
  cmp    $0x63,%dil
  jle    L34
  lea    -0x64(%rdi),%edx
  mov    $0x10,%eax
L1:
  cmp    $0x9,%dl
  jle    L14
  nopl   0x0(%rax)
L2:
  sub    $0xa,%edx
  add    $0x1,%eax
  cmp    $0x9,%dl
  ja     L2
L14:
  shl    $0x4,%eax
  movsbl %dl,%edx
  or     %edx,%eax
  ret
  nopl   0x0(%rax)
L34:
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
unsigned int CHAR2BCD3(char input) {
  int high = 0;
  while (input >= 100) {
    high++;
    input -= 100;
  }
  high <<= 4;
  while (input >= 10) {
    high++;
    input -= 10;
  }
  return (high << 4) | input;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CHAR2BCD3>:
  endbr64
  mov    %edi,%eax
  cmp    $0x63,%dil
  jle    L21
  lea    -0x64(%rdi),%eax
  mov    $0x100,%edx
  mov    $0x10,%ecx
L1:
  cmp    $0x9,%al
  jle    L61
  mov    %eax,%esi
  sub    $0xa,%eax
  lea    0x1(%rcx),%edx
  cmp    $0x9,%al
  jbe    L48
  lea    -0x14(%rsi),%eax
  lea    0x2(%rcx),%edx
  cmp    $0x9,%al
  jbe    L48
  lea    -0x1e(%rsi),%eax
  lea    0x3(%rcx),%edx
  cmp    $0x9,%al
  jbe    L48
  lea    -0x28(%rsi),%eax
  lea    0x4(%rcx),%edx
  cmp    $0x9,%al
  jbe    L48
  lea    -0x32(%rsi),%eax
  lea    0x5(%rcx),%edx
  cmp    $0x9,%al
  jbe    L48
  lea    -0x3c(%rsi),%eax
  lea    0x6(%rcx),%edx
  cmp    $0x9,%al
  jbe    L48
  lea    -0x46(%rsi),%eax
  lea    0x7(%rcx),%edx
  cmp    $0x9,%al
  jbe    L48
  lea    -0x50(%rsi),%eax
  lea    0x8(%rcx),%edx
  cmp    $0x9,%al
  jbe    L48
  lea    0x9(%rcx),%edx
  lea    -0x5a(%rsi),%eax
L48:
  shl    $0x4,%edx
L61:
  movsbl %al,%eax
  or     %edx,%eax
  ret
  xchg   %ax,%ax
L21:
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L1
```

assistant: ```c
unsigned int CHAR2BCD3(char input) {
  int high = 0;
  while (input >= 100) {
    high++;
    input -= 100;
  }
  high <<= 4;
  while (input >= 10) {
    high++;
    input -= 10;
  }
  return (high << 4) | input;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<thread1_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x214(%rbp)
  jmp    L22
L19:
  mov    -0x228(%rbp),%rcx
  mov    -0x214(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  lea    D2(%rip),%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x210(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <qemu_write@plt>
  mov    $0x186a0,%edi
  call   <usleep@plt>
  addl   $0x1,-0x214(%rbp)
L22:
  cmpl   $0x9,-0x214(%rbp)
  jle    L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: thread1: %d %s


assistant: ```c
void *thread1_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 10; i++) {
    snprintf(buf, sizeof(buf), "thread1: %d %s\n", i, (char *)arg);
    qemu_write(1, buf, strlen(buf));
    usleep(100 * 1000);
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<thread1_func>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D3(%rip),%r13
L14:
  mov    %rsp,%rbp
  mov    %r12,%r8
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <qemu_write@plt>
  mov    $0x186a0,%edi
  call   <usleep@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L14
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: thread1: %d %s


assistant: ```c
void *thread1_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 10; i++) {
    snprintf(buf, sizeof(buf), "thread1: %d %s\n", i, (char *)arg);
    qemu_write(1, buf, strlen(buf));
    usleep(100 * 1000);
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread1_func>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%ecx
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <qemu_write@plt>
  mov    $0x186a0,%edi
  call   <usleep@plt>
  cmp    $0xa,%ebx
  jne    L11
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: thread1: %d %s


assistant: ```c
void *thread1_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 10; i++) {
    snprintf(buf, sizeof(buf), "thread1: %d %s\n", i, (char *)arg);
    qemu_write(1, buf, strlen(buf));
    usleep(100 * 1000);
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread1_func>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%ecx
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <qemu_write@plt>
  mov    $0x186a0,%edi
  call   <usleep@plt>
  cmp    $0xa,%ebx
  jne    L18
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: thread1: %d %s


assistant: ```c
void *thread1_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 10; i++) {
    snprintf(buf, sizeof(buf), "thread1: %d %s\n", i, (char *)arg);
    qemu_write(1, buf, strlen(buf));
    usleep(100 * 1000);
  }
  return NULL;
}
```