user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  lea    D45(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L60
L111:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L111
L60:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L132
L127:
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  mov    %rsp,%rbx
  call   <printf@plt>
  cmpl   $0x0,-0x2c(%rbp)
  jle    L22
  mov    %rbx,%r13
  xor    %r12d,%r12d
L40:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  cmp    %r12d,%esi
  jg     L40
  cmp    $0x1,%esi
  jle    L22
  lea    -0x2(%rsi),%r11d
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  add    $0x2,%r11
  nopl   0x0(%rax)
L45:
  movslq %r8d,%rdi
  cmp    %r9d,%esi
  jle    L129
  mov    (%rbx,%r8,4),%r10d
  mov    %r9,%rax
  mov    %r10d,%ecx
  nopw   0x0(%rax,%rax,1)
L112:
  mov    (%rbx,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L54
  mov    %edx,%ecx
  movslq %eax,%rdi
L54:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L112
  cmp    %r8d,%edi
  je     L129
  mov    %ecx,(%rbx,%r8,4)
  mov    %r10d,(%rbx,%rdi,4)
L129:
  add    $0x1,%r9
  add    $0x1,%r8
  cmp    %r11,%r9
  jne    L45
L22:
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  lea    D14(%rip),%r13
  test   %eax,%eax
  jle    L148
  nopl   (%rax)
L75:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L75
L148:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L132:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L127
L105:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D27
type_infered: string
name: unpack_data
arguments: data_tag: D45
type_infered: string
name: unpack_data
arguments: data_tag: D0
type_infered: string
name: unpack_data
arguments: data_tag: D28
type_infered: string
name: unpack_data
arguments: data_tag: D14
type_infered: string

tool: D27: 
 Enter the number of Elements: 

tool: D45: %d

tool: D0: 
 Enter the %d Elements: 

tool: D28: 
 The Sorted array is : 

tool: D14: %d 

assistant: ```c
int main() {
  int n, i, j, min, temp;
  printf("\n Enter the number of Elements: ");
  scanf("%d", &n);
  int a[n];
  printf("\n Enter the %d Elements: ", n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n - 1; i++) {
    min = i;
    for (j = i + 1; j < n; j++) {
      if (a[min] > a[j])
        min = j;
    }
    if (min != i) {
      temp = a[i];
      a[i] = a[min];
      a[min] = temp;
    }
  }
  printf("\n The Sorted array is : ");
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  return (0);
}
```