ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lvector>:
  endbr64
  push   %rbp
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  push   %rbx
  lea    0x10(,%rsi,8),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
L7:
  mov    $0x1,%eax
  add    $0x8,%rsp
  sub    %rbp,%rax
  lea    (%rbx,%rax,8),%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  lea    D6(%rip),%rdi
  call   <nrerror@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: allocation failure in lvector()

assistant: ```c
unsigned long *lvector(long nl, long nh) {
  unsigned long *v;
  v = (unsigned long *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned long)));
  if (!v)
    nrerror("allocation failure in lvector()");
  return v - nl + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lvector>:
  endbr64
  push   %rbp
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  push   %rbx
  lea    0x10(,%rsi,8),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L13
L11:
  mov    $0x1,%eax
  add    $0x8,%rsp
  sub    %rbp,%rax
  lea    (%rbx,%rax,8),%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D0: allocation failure in lvector()

assistant: ```c
unsigned long *lvector(long nl, long nh) {
  unsigned long *v;
  v = (unsigned long *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned long)));
  if (!v)
    nrerror("allocation failure in lvector()");
  return v - nl + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L70:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L88
  movl   $0x0,-0x10(%rbp)
  jmp    L110
L55:
  movl   $0x0,-0xc(%rbp)
  jmp    L65
L106:
  cmpl   $0x0,-0x10(%rbp)
  je     L49
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  je     L49
  cmpl   $0x0,-0xc(%rbp)
  je     L49
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L98
L49:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L37
L98:
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L37:
  addl   $0x1,-0xc(%rbp)
L65:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L106
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L110:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L55
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
L88:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D6
type_infered: string
name: extract_symbolic_data
arguments: tag: D40
type_infered: string
name: extract_symbolic_data
arguments: tag: D47
type_infered: string

tool: D14: %d%d


tool: D6: #

tool: D40: .

tool: D47: 


assistant: ```c
int main() {
  int h, w, i, j;
  while (1) {
    scanf("%d%d\n", &h, &w);
    if (h == 0)
      break;
    for (i = 0; i < h; i++) {
      for (j = 0; j < w; j++) {
        if (i == 0 || i == h - 1 || j == 0 || j == w - 1)
          printf("#");
        else
          printf(".");
      }
      printf("\n");
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D30(%rip),%r15
  lea    D7(%rip),%r14
  jmp    L79
L88:
  mov    %r12,%rdi
  call   <printf@plt>
L135:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jle    L69
L101:
  test   %ebp,%ebp
  je     L88
  mov    (%rsp),%ecx
  lea    -0x1(%rcx),%edx
  cmp    %ebp,%edx
  je     L88
  test   %ebx,%ebx
  je     L88
  sub    $0x1,%eax
  cmp    %ebx,%eax
  je     L88
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L135
L69:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,(%rsp)
  jle    L27
L38:
  mov    0x4(%rsp),%eax
  mov    $0x0,%ebx
  test   %eax,%eax
  jg     L101
  jmp    L69
L27:
  lea    D20(%rip),%rdi
  call   <printf@plt>
L79:
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L124
  mov    $0x0,%ebp
  lea    D34(%rip),%r12
  lea    D20(%rip),%r13
  jg     L38
  jmp    L27
L124:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D30
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D20
type_infered: string
name: disassemble_data
arguments: data_tag: D34
type_infered: string

tool: D30: %d%d


tool: D7: .

tool: D20: 


tool: D34: #

assistant: ```c
int main() {
  int h, w, i, j;
  while (1) {
    scanf("%d%d\n", &h, &w);
    if (h == 0)
      break;
    for (i = 0; i < h; i++) {
      for (j = 0; j < w; j++) {
        if (i == 0 || i == h - 1 || j == 0 || j == w - 1)
          printf("#");
        else
          printf(".");
      }
      printf("\n");
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x14(%rsp),%r15
  mov    %rax,0x8(%rsp)
  nop
L66:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  je     L107
  mov    $0x0,%ebx
  lea    D18(%rip),%r13
  jle    L90
  xchg   %ax,%ax
L13:
  mov    0x14(%rsp),%eax
  xor    %r14d,%r14d
  test   %eax,%eax
  jg     L82
  jmp    L86
  nopl   (%rax)
L23:
  mov    0x10(%rsp),%edx
  lea    -0x1(%rdx),%ecx
  cmp    %ebx,%ecx
  je     L125
  test   %r14d,%r14d
  je     L125
  sub    $0x1,%eax
  cmp    %r14d,%eax
  je     L125
  mov    %r13,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  cmp    %r14d,%eax
  jle    L86
  nopl   (%rax)
L82:
  test   %ebx,%ebx
  jne    L23
L125:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  cmp    %r14d,%eax
  jg     L82
L86:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L13
L90:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L66
L107:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L128
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L128:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D10
type: string
name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D18
type: string

tool: D7: 


tool: D10: #

tool: D0: %d%d


tool: D18: .

assistant: ```c
int main() {
  int h, w, i, j;
  while (1) {
    scanf("%d%d\n", &h, &w);
    if (h == 0)
      break;
    for (i = 0; i < h; i++) {
      for (j = 0; j < w; j++) {
        if (i == 0 || i == h - 1 || j == 0 || j == w - 1)
          printf("#");
        else
          printf(".");
      }
      printf("\n");
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x14(%rsp),%r15
  mov    %rax,0x8(%rsp)
  nop
L74:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  je     L6
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
  jle    L86
  xchg   %ax,%ax
L88:
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  jle    L97
  xor    %r14d,%r14d
  test   %ebx,%ebx
  jne    L141
  jmp    L114
  nopl   0x0(%rax)
L79:
  test   %r14d,%r14d
  je     L142
  sub    $0x1,%ecx
  cmp    %r14d,%ecx
  je     L142
  mov    %r13,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%r14d
  jge    L97
  nopw   0x0(%rax,%rax,1)
L141:
  mov    0x10(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L79
L142:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%r14d
  jl     L141
L97:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L88
L86:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L74
  xchg   %ax,%ax
L114:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0x14(%rsp)
  jg     L114
  jmp    L97
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L132
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L132:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D23
type_infered: string
name: unpack_data
arguments: tag: D24
type_infered: string
name: unpack_data
arguments: tag: D1
type_infered: string

tool: D12: .

tool: D23: 


tool: D24: %d%d


tool: D1: #

assistant: ```c
int main() {
  int h, w, i, j;
  while (1) {
    scanf("%d%d\n", &h, &w);
    if (h == 0)
      break;
    for (i = 0; i < h; i++) {
      for (j = 0; j < w; j++) {
        if (i == 0 || i == h - 1 || j == 0 || j == w - 1)
          printf("#");
        else
          printf(".");
      }
      printf("\n");
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__imlib_SubCopyToRGB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  lea    -0x14(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  and    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  lea    -0x14(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  and    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  lea    -0x14(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __imlib_SubCopyToRGB(unsigned int color, unsigned int *dst) {
  unsigned int tmp;
  do {
    tmp = (((unsigned char *)(dst))[2]) - (((unsigned char *)(&color))[2]);
    ((unsigned char *)(dst))[2] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[1]) - (((unsigned char *)(&color))[1]);
    ((unsigned char *)(dst))[1] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[0]) - (((unsigned char *)(&color))[0]);
    ((unsigned char *)(dst))[0] = (tmp & (~(tmp >> 8)));
    ;
  } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__imlib_SubCopyToRGB>:
  endbr64
  push   %rbx
  mov    %edi,%ecx
  mov    %rsi,%rdx
  movzbl 0x2(%rsi),%esi
  shr    $0x10,%edi
  movzbl %sil,%eax
  movzbl %dil,%r8d
  sub    %r8d,%eax
  shr    $0x8,%eax
  not    %eax
  sub    %edi,%esi
  and    %esi,%eax
  mov    %al,0x2(%rdx)
  movzbl 0x1(%rdx),%esi
  movzbl %ch,%edi
  movzbl %sil,%eax
  sub    %edi,%eax
  shr    $0x8,%eax
  not    %eax
  sub    %edi,%esi
  and    %esi,%eax
  mov    %al,0x1(%rdx)
  movzbl (%rdx),%esi
  movzbl %sil,%eax
  movzbl %cl,%edi
  sub    %edi,%eax
  shr    $0x8,%eax
  not    %eax
  sub    %ecx,%esi
  and    %esi,%eax
  mov    %al,(%rdx)
  pop    %rbx
  ret
```

assistant: ```c
void __imlib_SubCopyToRGB(unsigned int color, unsigned int *dst) {
  unsigned int tmp;
  do {
    tmp = (((unsigned char *)(dst))[2]) - (((unsigned char *)(&color))[2]);
    ((unsigned char *)(dst))[2] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[1]) - (((unsigned char *)(&color))[1]);
    ((unsigned char *)(dst))[1] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[0]) - (((unsigned char *)(&color))[0]);
    ((unsigned char *)(dst))[0] = (tmp & (~(tmp >> 8)));
    ;
  } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__imlib_SubCopyToRGB>:
  endbr64
  mov    %edi,%ecx
  push   %rbx
  shr    $0x10,%edi
  movzbl 0x2(%rsi),%eax
  movzbl %dil,%r8d
  mov    %rsi,%rdx
  pop    %rbx
  mov    %eax,%esi
  sub    %r8d,%eax
  shr    $0x8,%eax
  sub    %edi,%esi
  movzbl %ch,%edi
  not    %eax
  and    %esi,%eax
  mov    %al,0x2(%rdx)
  movzbl 0x1(%rdx),%eax
  mov    %eax,%esi
  sub    %edi,%eax
  shr    $0x8,%eax
  sub    %edi,%esi
  movzbl %cl,%edi
  not    %eax
  and    %esi,%eax
  mov    %al,0x1(%rdx)
  movzbl (%rdx),%eax
  mov    %eax,%esi
  sub    %edi,%eax
  shr    $0x8,%eax
  sub    %ecx,%esi
  not    %eax
  and    %esi,%eax
  mov    %al,(%rdx)
  ret
```

assistant: ```c
void __imlib_SubCopyToRGB(unsigned int color, unsigned int *dst) {
  unsigned int tmp;
  do {
    tmp = (((unsigned char *)(dst))[2]) - (((unsigned char *)(&color))[2]);
    ((unsigned char *)(dst))[2] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[1]) - (((unsigned char *)(&color))[1]);
    ((unsigned char *)(dst))[1] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[0]) - (((unsigned char *)(&color))[0]);
    ((unsigned char *)(dst))[0] = (tmp & (~(tmp >> 8)));
    ;
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__imlib_SubCopyToRGB>:
  endbr64
  mov    %edi,%ecx
  push   %rbx
  shr    $0x10,%edi
  movzbl 0x2(%rsi),%eax
  movzbl %dil,%r8d
  mov    %rsi,%rdx
  pop    %rbx
  mov    %eax,%esi
  sub    %r8d,%eax
  shr    $0x8,%eax
  sub    %edi,%esi
  movzbl %ch,%edi
  not    %eax
  and    %esi,%eax
  mov    %al,0x2(%rdx)
  movzbl 0x1(%rdx),%eax
  mov    %eax,%esi
  sub    %edi,%eax
  shr    $0x8,%eax
  sub    %edi,%esi
  movzbl %cl,%edi
  not    %eax
  and    %esi,%eax
  mov    %al,0x1(%rdx)
  movzbl (%rdx),%eax
  mov    %eax,%esi
  sub    %edi,%eax
  shr    $0x8,%eax
  sub    %ecx,%esi
  not    %eax
  and    %esi,%eax
  mov    %al,(%rdx)
  ret
```

assistant: ```c
void __imlib_SubCopyToRGB(unsigned int color, unsigned int *dst) {
  unsigned int tmp;
  do {
    tmp = (((unsigned char *)(dst))[2]) - (((unsigned char *)(&color))[2]);
    ((unsigned char *)(dst))[2] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[1]) - (((unsigned char *)(&color))[1]);
    ((unsigned char *)(dst))[1] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[0]) - (((unsigned char *)(&color))[0]);
    ((unsigned char *)(dst))[0] = (tmp & (~(tmp >> 8)));
    ;
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x4(%rbp)
  jmp    L5
L16:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <integerBreak@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x14,-0x4(%rbp)
  jle    L16
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: i = %d : %d


assistant: ```c
int main(void) {
  for (int i = 2; i < 21; i++) {
    printf("i = %d : %d\n", i, integerBreak(i));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2,%ebx
  lea    D6(%rip),%rbp
L0:
  mov    %ebx,%edi
  call   <integerBreak@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x15,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string

tool: D6: i = %d : %d


assistant: ```c
int main(void) {
  for (int i = 2; i < 21; i++) {
    printf("i = %d : %d\n", i, integerBreak(i));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  call   <integerBreak@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x15,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: i = %d : %d


assistant: ```c
int main(void) {
  for (int i = 2; i < 21; i++) {
    printf("i = %d : %d\n", i, integerBreak(i));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  call   <integerBreak@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x15,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: i = %d : %d


assistant: ```c
int main(void) {
  for (int i = 2; i < 21; i++) {
    printf("i = %d : %d\n", i, integerBreak(i));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kernel_lu>:
  endbr64
  test   %edi,%edi
  jle    L148
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    0x3e80(%rsi),%r9
  lea    -0x1(%rdi),%eax
  mov    %rax,-0x8(%rsp)
  mov    %rsi,%r8
  mov    %rsi,%rbx
  mov    %rsi,%r11
  mov    $0x1,%edi
  movl   $0xffffffff,-0xc(%rsp)
  mov    $0x0,%r10d
  jmp    L32
L106:
  mov    %r14,%rcx
  mov    %r9,%rax
L53:
  movsd  (%rax),%xmm1
  mulsd  (%rcx),%xmm1
  movsd  (%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  add    $0x3e80,%rcx
  cmp    %rdx,%rax
  jne    L53
L26:
  add    $0x1,%rsi
  add    $0x3e88,%r13
  add    $0x8,%r14
  add    $0x8,%rdx
L105:
  movsd  -0x8(%r15,%rsi,8),%xmm0
  divsd  0x0(%r13),%xmm0
  movsd  %xmm0,-0x8(%r15,%rsi,8)
  cmp    %rdi,%rsi
  je     L21
  test   %esi,%esi
  jg     L106
  jmp    L26
L21:
  add    $0x1,%r10
  add    $0x8,%r11
  add    $0x3e88,%rbx
  add    $0x3e80,%r8
  addl   $0x1,-0xc(%rsp)
  add    $0x3e80,%r9
  add    $0x1,%rdi
L32:
  mov    %r10d,%r14d
  cmp    %r10d,%ebp
  jle    L63
  lea    0x8(%r8),%rdx
  mov    %ebp,%eax
  sub    %edi,%eax
  add    %r10,%rax
  lea    (%rdx,%rax,8),%r15
  mov    -0xc(%rsp),%eax
  lea    (%rdx,%rax,8),%rsi
  mov    %rbx,%rcx
  mov    %r11,%r13
  jmp    L42
L24:
  movsd  (%rax),%xmm1
  mulsd  (%rdx),%xmm1
  movsd  (%rcx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  add    $0x3e80,%rdx
  cmp    %rsi,%rax
  jne    L24
L15:
  add    $0x8,%r13
  add    $0x8,%rcx
  cmp    %r15,%rcx
  je     L63
L42:
  mov    %r13,%rdx
  mov    %r8,%rax
  test   %r14d,%r14d
  jg     L24
  jmp    L15
L63:
  cmp    -0x8(%rsp),%r10
  je     L93
  test   %edi,%edi
  jle    L21
  mov    %r9,%r15
  lea    0x8(%r12),%r14
  lea    0x3e88(%r8),%rdx
  mov    %r12,%r13
  mov    $0x1,%esi
  jmp    L105
L93:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L148:
  ret
```

assistant: ```c
void kernel_lu(int n, double A[2000 + 0][2000 + 0]) {
  int i, j, k;
#pragma scop
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      for (k = 0; k < j; k++) {
        A[i][j] -= A[i][k] * A[k][j];
      }
      A[i][j] /= A[j][j];
    }
    for (j = i; j < n; j++) {
      for (k = 0; k < i; k++) {
        A[i][j] -= A[i][k] * A[k][j];
      }
    }
  }
#pragma endscop
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kernel_lu>:
  endbr64
  test   %edi,%edi
  jle    L52
  push   %r15
  lea    0x3e80(%rsi),%r10
  mov    %rsi,%r11
  xor    %r8d,%r8d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    $0xffffffff,%ebp
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %ebp,%eax
  mov    %r13,%rcx
  mov    %r12,%r9
  mov    %r8d,%edi
  lea    0x8(%r11,%rax,8),%rsi
  nopl   0x0(%rax,%rax,1)
L22:
  test   %r8d,%r8d
  je     L39
  movsd  (%rcx),%xmm1
  mov    %r9,%rdx
  mov    %r11,%rax
  nop
L11:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    $0x3e80,%rdx
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rsi,%rax
  jne    L11
L39:
  add    $0x1,%edi
  add    $0x8,%r9
  add    $0x8,%rcx
  cmp    %edi,%ebx
  jg     L22
  lea    0x1(%r8),%r15d
  cmp    %r15d,%ebx
  je     L28
  movsd  (%r10),%xmm1
  lea    0x8(%r14),%rdi
  lea    0x8(%r10),%rcx
  mov    %r14,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L2:
  divsd  (%rsi),%xmm1
  lea    0x1(%rax),%r9d
  movsd  %xmm1,-0x8(%rcx)
  cmp    %r8d,%eax
  je     L13
  movsd  (%rcx),%xmm1
  mov    %rdi,%rdx
  mov    %r10,%rax
  nopl   0x0(%rax)
L47:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    $0x3e80,%rdx
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rcx
  jne    L47
  add    $0x3e88,%rsi
  add    $0x8,%rdi
  add    $0x8,%rcx
  mov    %r9d,%eax
  jmp    L2
  nopl   0x0(%rax)
L13:
  add    $0x8,%r12
  add    $0x3e88,%r13
  add    $0x1,%ebp
  mov    %r15d,%r8d
  add    $0x3e80,%r11
  add    $0x3e80,%r10
  jmp    L33
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  ret
```

assistant: ```c
void kernel_lu(int n, double A[2000 + 0][2000 + 0]) {
  int i, j, k;
#pragma scop
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      for (k = 0; k < j; k++) {
        A[i][j] -= A[i][k] * A[k][j];
      }
      A[i][j] /= A[j][j];
    }
    for (j = i; j < n; j++) {
      for (k = 0; k < i; k++) {
        A[i][j] -= A[i][k] * A[k][j];
      }
    }
  }
#pragma endscop
}
```