ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readv>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %edx,%edx
  jle    L19
  lea    -0x1(%rdx),%edx
  mov    %rsi,%rax
  xor    %r12d,%r12d
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  nop
L60:
  add    (%rax),%r12d
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L60
L20:
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L99
  mov    %r12d,%edx
  mov    %rax,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  mov    %eax,%r9d
  cmp    $0xffffffff,%eax
  je     L99
  test   %r13d,%r13d
  jle    L58
  lea    -0x1(%r13),%eax
  mov    %rbx,%rcx
  xor    %esi,%esi
  shl    $0x4,%rax
  lea    0x10(%rbx,%rax,1),%r10
  nopw   0x0(%rax,%rax,1)
L68:
  mov    (%rcx),%eax
  test   %eax,%eax
  jle    L40
  movslq %esi,%r8
  xor    %eax,%eax
  mov    %r8,%rdx
  add    %rbp,%r8
  cmp    %esi,%r9d
  jle    L40
  xchg   %ax,%ax
L62:
  movzbl (%r8,%rax,1),%edi
  mov    0x8(%rcx),%rsi
  add    $0x1,%edx
  mov    %dil,(%rsi,%rax,1)
  lea    0x1(%rax),%esi
  cmp    %esi,(%rcx)
  setg   %dil
  cmp    %edx,%r9d
  setg   %sil
  add    $0x1,%rax
  test   %sil,%dil
  jne    L62
  mov    %edx,%esi
L40:
  add    $0x10,%rcx
  cmp    %rcx,%r10
  jne    L68
L58:
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  xor    %r12d,%r12d
  jmp    L20
L99:
  mov    $0xffffffff,%r9d
  jmp    L58
```

assistant: ```c
ssize_t readv(int fd, const struct iovec *iov, int ioc) {
  ssize_t total = 0;
  for (int i = 0; i < ioc; i++) {
    total += iov[i].iov_len;
  }
  char *buffer = calloc(total, 1);
  if (buffer == NULL) {
    return -1;
  }
  ssize_t result = read(fd, buffer, total);
  if (result == -1) {
    return result;
  }
  int k = 0;
  for (int i = 0; i < ioc; i++) {
    for (int j = 0; j < iov[i].iov_len && k < result; j++, k++) {
      ((char *)iov[i].iov_base)[j] = buffer[k];
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readv>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %edx,%edx
  jle    L34
  lea    -0x1(%rdx),%edx
  cmp    $0x3,%edx
  jbe    L66
  mov    %edx,%ecx
  mov    %rsi,%rax
  pxor   %xmm1,%xmm1
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x6,%rcx
  lea    0x40(%rsi,%rcx,1),%rcx
  nopl   0x0(%rax)
L85:
  movdqu (%rax),%xmm0
  movdqu 0x10(%rax),%xmm3
  add    $0x40,%rax
  movdqu -0x20(%rax),%xmm2
  movdqu -0x10(%rax),%xmm4
  shufps $0x88,%xmm3,%xmm0
  shufps $0x88,%xmm4,%xmm2
  shufps $0x88,%xmm2,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rcx,%rax
  jne    L85
  movdqa %xmm1,%xmm0
  mov    %edx,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%r12d
L117:
  movslq %eax,%rdx
  lea    0x1(%rax),%ecx
  shl    $0x4,%rdx
  add    (%rbx,%rdx,1),%r12d
  cmp    %r13d,%ecx
  jge    L73
  lea    0x2(%rax),%ecx
  add    0x10(%rbx,%rdx,1),%r12d
  cmp    %ecx,%r13d
  jle    L73
  add    $0x3,%eax
  add    0x20(%rbx,%rdx,1),%r12d
  cmp    %eax,%r13d
  jle    L73
  add    0x30(%rbx,%rdx,1),%r12d
L73:
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L70
  mov    %r12d,%edx
  mov    %rax,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  mov    %eax,%r9d
  cmp    $0xffffffff,%eax
  je     L70
  test   %r13d,%r13d
  jle    L51
  lea    -0x1(%r13),%eax
  mov    %rbx,%rcx
  xor    %esi,%esi
  shl    $0x4,%rax
  lea    0x10(%rbx,%rax,1),%r10
  nopl   0x0(%rax)
L124:
  mov    (%rcx),%eax
  test   %eax,%eax
  jle    L142
  movslq %esi,%r8
  xor    %eax,%eax
  mov    %r8,%rdx
  add    %rbp,%r8
  cmp    %esi,%r9d
  jle    L142
  xchg   %ax,%ax
L91:
  movzbl (%r8,%rax,1),%edi
  mov    0x8(%rcx),%rsi
  add    $0x1,%edx
  mov    %dil,(%rsi,%rax,1)
  lea    0x1(%rax),%esi
  cmp    %esi,(%rcx)
  setg   %dil
  cmp    %edx,%r9d
  setg   %sil
  add    $0x1,%rax
  test   %sil,%dil
  jne    L91
  mov    %edx,%esi
L142:
  add    $0x10,%rcx
  cmp    %r10,%rcx
  jne    L124
L51:
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  xor    %r12d,%r12d
  jmp    L73
L66:
  xor    %eax,%eax
  xor    %r12d,%r12d
  jmp    L117
L70:
  mov    $0xffffffff,%r9d
  jmp    L51
```

assistant: ```c
ssize_t readv(int fd, const struct iovec *iov, int ioc) {
  ssize_t total = 0;
  for (int i = 0; i < ioc; i++) {
    total += iov[i].iov_len;
  }
  char *buffer = calloc(total, 1);
  if (buffer == NULL) {
    return -1;
  }
  ssize_t result = read(fd, buffer, total);
  if (result == -1) {
    return result;
  }
  int k = 0;
  for (int i = 0; i < ioc; i++) {
    for (int j = 0; j < iov[i].iov_len && k < result; j++, k++) {
      ((char *)iov[i].iov_base)[j] = buffer[k];
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<net_putc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  lea    -0x18(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L14
  mov    $0xffffffff,%eax
  jmp    L12
L14:
  mov    -0x18(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int net_putc(int fd, int c) {
  int r;
  r = write(fd, &c, 1);
  if (r == 0)
    return (-1);
  else
    return (c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<net_putc>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  test   %eax,%eax
  je     L14
  mov    0xc(%rsp),%eax
L16:
  add    $0x18,%rsp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int net_putc(int fd, int c) {
  int r;
  r = write(fd, &c, 1);
  if (r == 0)
    return (-1);
  else
    return (c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<net_putc>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  test   %eax,%eax
  je     L14
  mov    0xc(%rsp),%eax
L11:
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xffffffff,%eax
  jmp    L11
```

assistant: ```c
int net_putc(int fd, int c) {
  int r;
  r = write(fd, &c, 1);
  if (r == 0)
    return (-1);
  else
    return (c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<net_putc>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  test   %eax,%eax
  je     L10
  mov    0xc(%rsp),%eax
L11:
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%eax
  jmp    L11
```

assistant: ```c
int net_putc(int fd, int c) {
  int r;
  r = write(fd, &c, 1);
  if (r == 0)
    return (-1);
  else
    return (c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modifyArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    $0x2,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void modifyArray(int b[], int size) {
  int j;
  for (j = 0; j < size; j++) {
    b[j] += 2;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<modifyArray>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L11:
  addl   $0x2,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L11
L3:
  ret
```

assistant: ```c
void modifyArray(int b[], int size) {
  int j;
  for (j = 0; j < size; j++) {
    b[j] += 2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<modifyArray>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
L6:
  addl   $0x2,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L6
L12:
  ret
```

assistant: ```c
void modifyArray(int b[], int size) {
  int j;
  for (j = 0; j < size; j++) {
    b[j] += 2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<modifyArray>:
  endbr64
  test   %esi,%esi
  jle    L39
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L46
  mov    %esi,%edx
  movdqa D1(%rip),%xmm1
  mov    %rdi,%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L59:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  paddd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L59
  mov    %esi,%edx
  and    $0xfffffffc,%edx
  test   $0x3,%sil
  je     L42
L19:
  movslq %edx,%rax
  lea    0x1(%rdx),%ecx
  shl    $0x2,%rax
  addl   $0x2,(%rdi,%rax,1)
  cmp    %ecx,%esi
  jle    L39
  add    $0x2,%edx
  addl   $0x2,0x4(%rdi,%rax,1)
  cmp    %edx,%esi
  jle    L39
  addl   $0x2,0x8(%rdi,%rax,1)
L39:
  ret
  nopl   0x0(%rax)
L42:
  ret
L46:
  xor    %edx,%edx
  jmp    L19
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: byte[16]

tool: {"D1": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
void modifyArray(int b[], int size) {
  int j;
  for (j = 0; j < size; j++) {
    b[j] += 2;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<run_stdlib_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <test_abs@plt>
  mov    $0x0,%eax
  call   <test_labs@plt>
  mov    $0x0,%eax
  call   <test_llabs@plt>
  mov    $0x0,%eax
  call   <test_ldiv@plt>
  mov    $0x0,%eax
  call   <test_lldiv@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D7
type: string

tool: D12: Test POSIX stdlib.h functions

tool: D7: 
Running Test Case: %s


assistant: ```c
void run_stdlib_tests() {
  printf("\nRunning Test Case: %s\n", "Test POSIX stdlib.h functions");
  ;
  test_abs();
  test_labs();
  test_llabs();
  test_ldiv();
  test_lldiv();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<run_stdlib_tests>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <test_abs@plt>
  mov    $0x0,%eax
  call   <test_labs@plt>
  mov    $0x0,%eax
  call   <test_llabs@plt>
  mov    $0x0,%eax
  call   <test_ldiv@plt>
  mov    $0x0,%eax
  call   <test_lldiv@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
data_type: string
name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D14: Test POSIX stdlib.h functions

tool: D9: 
Running Test Case: %s


assistant: ```c
void run_stdlib_tests() {
  printf("\nRunning Test Case: %s\n", "Test POSIX stdlib.h functions");
  ;
  test_abs();
  test_labs();
  test_llabs();
  test_ldiv();
  test_lldiv();
}
```
user: Translate the below assembly code into C programming language:

```asm
<run_stdlib_tests>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <test_abs@plt>
  xor    %eax,%eax
  call   <test_labs@plt>
  xor    %eax,%eax
  call   <test_llabs@plt>
  xor    %eax,%eax
  call   <test_ldiv@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <test_lldiv@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D16
datatype: string

tool: D4: Test POSIX stdlib.h functions

tool: D16: 
Running Test Case: %s


assistant: ```c
void run_stdlib_tests() {
  printf("\nRunning Test Case: %s\n", "Test POSIX stdlib.h functions");
  ;
  test_abs();
  test_labs();
  test_llabs();
  test_ldiv();
  test_lldiv();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<run_stdlib_tests>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <test_abs@plt>
  xor    %eax,%eax
  call   <test_labs@plt>
  xor    %eax,%eax
  call   <test_llabs@plt>
  xor    %eax,%eax
  call   <test_ldiv@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <test_lldiv@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string

tool: D5: Test POSIX stdlib.h functions

tool: D13: 
Running Test Case: %s


assistant: ```c
void run_stdlib_tests() {
  printf("\nRunning Test Case: %s\n", "Test POSIX stdlib.h functions");
  ;
  test_abs();
  test_labs();
  test_llabs();
  test_ldiv();
  test_lldiv();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int a = 0;
  int *b = a;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 0;
  int *b = a;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 0;
  int *b = a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 0;
  int *b = a;
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<calloc2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L7:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void **calloc2(int n_row, int n_col, int size) {
  char **p;
  int k;
  p = (char **)malloc(sizeof(char *) * n_row);
  for (k = 0; k != n_row; ++k)
    p[k] = (char *)calloc(n_col, size);
  return (void **)p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<calloc2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%ebp
  mov    %edx,%r12d
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  je     L16
  mov    %rax,%rbx
  mov    %r13d,%r13d
  lea    (%rax,%r13,8),%r13
L11:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L11
L16:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void **calloc2(int n_row, int n_col, int size) {
  char **p;
  int k;
  p = (char **)malloc(sizeof(char *) * n_row);
  for (k = 0; k != n_row; ++k)
    p[k] = (char *)calloc(n_col, size);
  return (void **)p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calloc2>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  lea    0x0(,%r13,8),%edi
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  je     L3
  mov    %rax,%rbx
  lea    (%rax,%r13,8),%r13
L19:
  mov    %r12d,%esi
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <calloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r13,%rbx
  jne    L19
L3:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void **calloc2(int n_row, int n_col, int size) {
  char **p;
  int k;
  p = (char **)malloc(sizeof(char *) * n_row);
  for (k = 0; k != n_row; ++k)
    p[k] = (char *)calloc(n_col, size);
  return (void **)p;
}
```
user: What is the c source code of the assembly code below:

```asm
<calloc2>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  lea    0x0(,%r13,8),%edi
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  je     L4
  mov    %rax,%rbx
  lea    (%rax,%r13,8),%r13
L16:
  mov    %r12d,%esi
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <calloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r13,%rbx
  jne    L16
L4:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void **calloc2(int n_row, int n_col, int size) {
  char **p;
  int k;
  p = (char **)malloc(sizeof(char *) * n_row);
  for (k = 0; k != n_row; ++k)
    p[k] = (char *)calloc(n_col, size);
  return (void **)p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<substitute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  jmp    L8
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L0
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L0:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void substitute(char *str, int ch1, int ch2) {
  for (; *str; str++) {
    if (*str == ch1) {
      *str = ch2;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<substitute>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L5
L37:
  ret
L7:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L37
L5:
  movsbl %al,%eax
  cmp    %esi,%eax
  jne    L7
  mov    %dl,(%rdi)
  jmp    L7
```

assistant: ```c
void substitute(char *str, int ch1, int ch2) {
  for (; *str; str++) {
    if (*str == ch1) {
      *str = ch2;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<substitute>:
  endbr64
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L5:
  cmp    %esi,%eax
  jne    L14
  mov    %dl,(%rdi)
L14:
  add    $0x1,%rdi
L10:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L5
  ret
```

assistant: ```c
void substitute(char *str, int ch1, int ch2) {
  for (; *str; str++) {
    if (*str == ch1) {
      *str = ch2;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<substitute>:
  endbr64
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L35:
  add    $0x1,%rdi
L11:
  movsbl (%rdi),%eax
  test   %al,%al
  je     L24
L14:
  cmp    %esi,%eax
  jne    L35
  mov    %dl,(%rdi)
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L14
  ret
  xchg   %ax,%ax
L24:
  ret
```

assistant: ```c
void substitute(char *str, int ch1, int ch2) {
  for (; *str; str++) {
    if (*str == ch1) {
      *str = ch2;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_nibble_to_hex_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xf,-0x4(%rbp)
  jle    L24
  mov    $0x0,%eax
  jmp    L15
L24:
  cmpl   $0x9,-0x4(%rbp)
  jg     L32
  mov    $0x30,%edx
  jmp    L4
L32:
  mov    $0x57,%edx
L4:
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t _nibble_to_hex_char(uint8_t nibble) {
  if (nibble > 15)
    return (uint8_t)0;
  return (uint8_t)nibble + (nibble < 10 ? 48 : 87);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_nibble_to_hex_char>:
  endbr64
  mov    $0x0,%eax
  cmp    $0xf,%edi
  jg     L4
  cmp    $0xa,%edi
  mov    $0x30,%eax
  mov    $0x57,%edx
  cmovge %edx,%eax
  add    %edi,%eax
L4:
  ret
```

assistant: ```c
uint8_t _nibble_to_hex_char(uint8_t nibble) {
  if (nibble > 15)
    return (uint8_t)0;
  return (uint8_t)nibble + (nibble < 10 ? 48 : 87);
}
```
user: What is the c source code of the assembly code below:

```asm
<_nibble_to_hex_char>:
  endbr64
  xor    %eax,%eax
  cmp    $0xf,%edi
  jg     L7
  cmp    $0xa,%edi
  mov    $0x30,%eax
  mov    $0x57,%edx
  cmovge %edx,%eax
  add    %edi,%eax
L7:
  ret
```

assistant: ```c
uint8_t _nibble_to_hex_char(uint8_t nibble) {
  if (nibble > 15)
    return (uint8_t)0;
  return (uint8_t)nibble + (nibble < 10 ? 48 : 87);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_nibble_to_hex_char>:
  endbr64
  xor    %eax,%eax
  cmp    $0xf,%edi
  jg     L9
  cmp    $0xa,%edi
  mov    $0x30,%eax
  mov    $0x57,%edx
  cmovge %edx,%eax
  add    %edi,%eax
L9:
  ret
```

assistant: ```c
uint8_t _nibble_to_hex_char(uint8_t nibble) {
  if (nibble > 15)
    return (uint8_t)0;
  return (uint8_t)nibble + (nibble < 10 ? 48 : 87);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<busy_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L30:
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L0:
  mov    D13(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D9(%rip)
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x1869f,-0x4(%rbp)
  jle    L0
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void busy_wait(int n) {
  int i, j;
  static volatile int k = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < 100000; j++)
      k++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<busy_wait>:
  endbr64
  mov    %edi,%esi
  mov    $0x0,%ecx
  test   %edi,%edi
  jle    L11
L13:
  mov    $0x186a0,%edx
L20:
  mov    D18(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D11(%rip)
  sub    $0x1,%edx
  jne    L20
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L13
  ret
L11:
  ret
```

assistant: ```c
void busy_wait(int n) {
  int i, j;
  static volatile int k = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < 100000; j++)
      k++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<busy_wait>:
  endbr64
  mov    %edi,%esi
  test   %edi,%edi
  jle    L8
  xor    %ecx,%ecx
L11:
  mov    $0x186a0,%edx
  nopl   0x0(%rax)
L17:
  mov    D12(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D3(%rip)
  sub    $0x1,%edx
  jne    L17
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L11
L8:
  ret
```

assistant: ```c
void busy_wait(int n) {
  int i, j;
  static volatile int k = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < 100000; j++)
      k++;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<busy_wait>:
  endbr64
  mov    %edi,%esi
  test   %edi,%edi
  jle    L23
  xor    %ecx,%ecx
L18:
  mov    $0x186a0,%edx
  nopl   0x0(%rax)
L21:
  mov    D1(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D10(%rip)
  sub    $0x1,%edx
  jne    L21
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L18
L23:
  ret
```

assistant: ```c
void busy_wait(int n) {
  int i, j;
  static volatile int k = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < 100000; j++)
      k++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decimal_string_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L4
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x0,-0x4(%rbp)
  jg     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int decimal_string_length(int i) {
  int length = 1;
  if (i <= 0) {
    length++;
  }
  int current = abs(i);
  while (current > 0) {
    current /= 10;
    length++;
  }
  return length;
}
```