user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    $0xb,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L25:
  mov    %r13d,%edi
  lea    -0x9(%rbx),%r12d
  mov    %r13d,%r14d
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L255
L183:
  mov    %r12d,%edi
  call   <random_string@plt>
  mov    %r14d,%edx
  mov    %r15,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r15,%r13,1)
  mov    %r15,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L273
  cmp    %r14,%r15
  je     L109
  lea    D27(%rip),%rdi
  mov    %r14,%rdx
  mov    %r15,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L109:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  cmp    %ebx,%eax
  jg     L57
  sub    %eax,%r12d
  lea    0xa(%r12),%edi
  add    $0x9,%r12d
  cmp    $0xe,%r12d
  jbe    L65
  pxor   %xmm1,%xmm1
  pxor   %xmm5,%xmm5
  pxor   %xmm4,%xmm4
  movslq %eax,%rcx
  mov    %edi,%eax
  add    %r15,%rcx
  shr    $0x4,%eax
  lea    -0x1(%rax),%esi
  lea    0x10(%rcx),%rax
  shl    $0x4,%rsi
  add    %rax,%rsi
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x10,%rax
L58:
  movdqu (%rcx),%xmm0
  movdqa %xmm5,%xmm3
  mov    %rax,%rcx
  pcmpeqb %xmm5,%xmm0
  pand   D18(%rip),%xmm0
  pcmpgtb %xmm0,%xmm3
  movdqa %xmm0,%xmm2
  punpcklbw %xmm3,%xmm2
  punpckhbw %xmm3,%xmm0
  movdqa %xmm4,%xmm3
  pcmpgtw %xmm2,%xmm3
  movdqa %xmm2,%xmm6
  punpcklwd %xmm3,%xmm6
  punpckhwd %xmm3,%xmm2
  movdqa %xmm0,%xmm3
  paddd  %xmm6,%xmm1
  paddd  %xmm2,%xmm1
  movdqa %xmm4,%xmm2
  pcmpgtw %xmm0,%xmm2
  punpcklwd %xmm2,%xmm3
  punpckhwd %xmm2,%xmm0
  paddd  %xmm3,%xmm1
  paddd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L13
  movdqa %xmm1,%xmm0
  mov    %edi,%ecx
  psrldq $0x8,%xmm0
  and    $0xfffffff0,%ecx
  paddd  %xmm0,%xmm1
  add    %ecx,%edx
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %ecx,%edi
  je     L51
L60:
  movslq %edx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x1(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ebx,%ecx
  jg     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x2(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ebx,%ecx
  jg     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x3(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ebx,%ecx
  jg     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x4(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ebx,%ecx
  jg     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x5(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x6(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x7(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x8(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0x9(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0xa(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0xb(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0xc(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  lea    0xd(%rdx),%ecx
  adc    $0x0,%eax
  cmp    %ecx,%ebx
  jl     L51
  movslq %ecx,%rcx
  cmpb   $0x1,(%r15,%rcx,1)
  adc    $0x0,%eax
  add    $0xe,%edx
  cmp    %edx,%ebx
  jl     L51
  movslq %edx,%rdx
  cmpb   $0x1,(%r15,%rdx,1)
  adc    $0x0,%eax
L51:
  cmp    $0xa,%eax
  jne    L57
L149:
  mov    %rbp,%rdi
  add    $0x7d0,%ebx
  add    $0x7d0,%r13
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  cmp    $0xc35a,%ebx
  jne    L25
  lea    D44(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L149
L273:
  mov    %r15,%rdx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L109
  nopl   0x0(%rax,%rax,1)
L255:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L183
L65:
  xor    %eax,%eax
  jmp    L60
```

tool_calls: name: retrieve_data
arguments: label: D27
type_infered: string
name: retrieve_data
arguments: label: D18
type_infered: byte[16]
name: retrieve_data
arguments: label: D44
type_infered: string
name: retrieve_data
arguments: label: D31
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D4
type_infered: string

tool: D27: strncpy/2-1.c Test Failed, return is not as expected. Expected return: %p, But obtained: %p


tool: {"D18": [0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01]}

tool: D44: strncpy/2-1.c  Test Passed, The difference in the number of bytes for two strings (s1 and s2) have been appended with NULL bytes in s2

tool: D31: strncpy/2-1.c Test Failed, The difference in the number of bytes for two strings (s1 and s2) have not been appended with NULL bytes

tool: D5: strncpy/2-1.c Test failed, string copy failed. Expected string: %s, But got: %s


tool: D4: strncpy/2-1.c Failed to allocate memory

assistant: ```c
int main(void) {
  int i, j, c;
  char *ret_str;
  for (i = 1; i < 50000; i += 2000) {
    c = 0;
    char *sample_str_1;
    char *sample_str_2 = malloc(i + 10);
    if (sample_str_2 == NULL) {
      printf("strncpy/2-1.c"
             " Failed to allocate memory\n");
      exit(2);
    }
    sample_str_1 = random_string(i);
    ret_str = strncpy(sample_str_2, sample_str_1, i + 10);
    sample_str_2[i + 10] = '\0';
    if (strcmp(sample_str_1, sample_str_2) != 0) {
      printf("strncpy/2-1.c"
             " Test failed, string copy failed. "
             "Expected string: %s, But got: %s\n",
             sample_str_1, sample_str_2);
      exit(2);
    } else if (ret_str != sample_str_2) {
      printf("strncpy/2-1.c"
             " Test Failed, return is not as expected. "
             "Expected return: %p, But obtained: %p\n",
             sample_str_2, ret_str);
      exit(1);
    }
    for (j = strlen(sample_str_1); j < i + 10; j++) {
      if (sample_str_2[j] == '\0') {
        c++;
      }
    }
    if (c != 10) {
      printf("strncpy/2-1.c"
             " Test Failed, The difference in the number of bytes"
             " for two strings (s1 and s2) have not been appended"
             " with NULL bytes\n");
      exit(1);
    }
    free(sample_str_1);
    free(sample_str_2);
  }
  printf("strncpy/2-1.c"
         "  Test Passed, The difference in the number of bytes for two "
         "strings (s1 and s2) have been appended with NULL bytes in s2\n");
  exit(0);
}
```