ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wpa_cmd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L44
  movb   $0x0,(%rdx)
L44:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L4
  test   %rbx,%rbx
  je     L97
  test   %r13,%r13
  je     L97
  mov    %r12d,0xc(%rsp)
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    D39(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x7d0,%edx
  mov    $0x1,%esi
  call   <poll@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  jbe    L58
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    D39(%rip),%rdx
  or     (%rdx),%eax
  and    0x14(%rsp),%eax
  je     L100
  lea    -0x1(%r13),%edx
  cmp    $0x1,%r13
  mov    $0x1,%eax
  cmove  %eax,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L4
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  jmp    L4
L97:
  mov    $0x0,%eax
L4:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L76
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  mov    $0xffffffff,%eax
  jmp    L4
L100:
  mov    $0xffffffff,%eax
  jmp    L4
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t wpa_cmd(int fd, const char *cmd, char *buffer, size_t len) {
  int retval;
  ssize_t bytes;
  struct pollfd pfd;
  if (buffer)
    *buffer = '\0';
  bytes = write(fd, cmd, strlen(cmd));
  if (bytes == -1)
    return -1;
  if (buffer == NULL || len == 0)
    return 0;
  pfd.fd = fd;
  pfd.events = POLLIN | POLLHUP;
  pfd.revents = 0;
  retval = poll(&pfd, 1, 2000);
  if (retval == -1)
    return -1;
  if (retval == 0 || !(pfd.revents & (POLLIN | POLLHUP)))
    return -1;
  bytes = read(fd, buffer, len == 1 ? 1 : len - 1);
  if (bytes != -1)
    buffer[bytes] = '\0';
  return bytes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wpa_cmd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L26
  movb   $0x0,(%rdx)
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %rcx,%r13
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L97
  xor    %eax,%eax
  test   %r13,%r13
  je     L3
  lea    0xc(%rsp),%rdi
  mov    $0x7d0,%edx
  mov    $0x1,%esi
  mov    D18(%rip),%r14
  mov    D2(%rip),%rbp
  mov    %r12d,0xc(%rsp)
  mov    (%r14),%eax
  movl   $0x0,0x14(%rsp)
  or     0x0(%rbp),%eax
  mov    %eax,0x10(%rsp)
  call   <poll@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  jbe    L97
  mov    (%r14),%eax
  or     0x0(%rbp),%eax
  and    0x14(%rsp),%eax
  je     L97
  cmp    $0x1,%r13
  lea    -0x1(%r13),%edx
  mov    $0x1,%eax
  mov    %rbx,%rsi
  cmove  %eax,%edx
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L3
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
L3:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L26:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L97
  xor    %eax,%eax
  jmp    L3
  xchg   %ax,%ax
L97:
  mov    $0xffffffff,%eax
  jmp    L3
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t wpa_cmd(int fd, const char *cmd, char *buffer, size_t len) {
  int retval;
  ssize_t bytes;
  struct pollfd pfd;
  if (buffer)
    *buffer = '\0';
  bytes = write(fd, cmd, strlen(cmd));
  if (bytes == -1)
    return -1;
  if (buffer == NULL || len == 0)
    return 0;
  pfd.fd = fd;
  pfd.events = POLLIN | POLLHUP;
  pfd.revents = 0;
  retval = poll(&pfd, 1, 2000);
  if (retval == -1)
    return -1;
  if (retval == 0 || !(pfd.revents & (POLLIN | POLLHUP)))
    return -1;
  bytes = read(fd, buffer, len == 1 ? 1 : len - 1);
  if (bytes != -1)
    buffer[bytes] = '\0';
  return bytes;
}
```
user: What is the c source code of the assembly code below:

```asm
<wpa_cmd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L19
  movb   $0x0,(%rdx)
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %rcx,%r13
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L47
  xor    %eax,%eax
  test   %r13,%r13
  je     L52
  movd   %r12d,%xmm0
  lea    0x8(%rsp),%rdi
  mov    $0x7d0,%edx
  mov    D18(%rip),%r14
  mov    D19(%rip),%rbp
  mov    $0x1,%esi
  movl   $0x0,0x10(%rsp)
  mov    (%r14),%eax
  or     0x0(%rbp),%eax
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x8(%rsp)
  call   <poll@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  jbe    L47
  mov    (%r14),%eax
  or     0x0(%rbp),%eax
  and    0x10(%rsp),%eax
  je     L47
  cmp    $0x1,%r13
  lea    -0x1(%r13),%edx
  mov    $0x1,%eax
  mov    %rbx,%rsi
  cmove  %eax,%edx
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L52
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
L52:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L47
  xor    %eax,%eax
  jmp    L52
  xchg   %ax,%ax
L47:
  mov    $0xffffffff,%eax
  jmp    L52
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t wpa_cmd(int fd, const char *cmd, char *buffer, size_t len) {
  int retval;
  ssize_t bytes;
  struct pollfd pfd;
  if (buffer)
    *buffer = '\0';
  bytes = write(fd, cmd, strlen(cmd));
  if (bytes == -1)
    return -1;
  if (buffer == NULL || len == 0)
    return 0;
  pfd.fd = fd;
  pfd.events = POLLIN | POLLHUP;
  pfd.revents = 0;
  retval = poll(&pfd, 1, 2000);
  if (retval == -1)
    return -1;
  if (retval == 0 || !(pfd.revents & (POLLIN | POLLHUP)))
    return -1;
  bytes = read(fd, buffer, len == 1 ? 1 : len - 1);
  if (bytes != -1)
    buffer[bytes] = '\0';
  return bytes;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__yy_bcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x20(%rbp),%r12
  mov    -0x28(%rbp),%r13
  mov    -0x2c(%rbp),%ebx
  jmp    L16
L4:
  mov    %r12,%rdx
  lea    0x1(%rdx),%r12
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L16:
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  test   %eax,%eax
  jg     L4
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void __yy_bcopy(from, to, count) char *from;
char *to;
int count;
{
  register char *f = from;
  register char *t = to;
  register int i = count;
  while (i-- > 0)
    *t++ = *f++;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__yy_bcopy>:
  endbr64
  test   %edx,%edx
  jle    L17
  mov    %edx,%edx
  mov    $0x0,%eax
L19:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
L17:
  ret
```

assistant: ```c
void __yy_bcopy(from, to, count) char *from;
char *to;
int count;
{
  register char *f = from;
  register char *t = to;
  register int i = count;
  while (i-- > 0)
    *t++ = *f++;
}
```
user: What is the c source code of the assembly code below?

```asm
<__yy_bcopy>:
  endbr64
  test   %edx,%edx
  jle    L9
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L15:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L15
L9:
  ret
```

assistant: ```c
void __yy_bcopy(from, to, count) char *from;
char *to;
int count;
{
  register char *f = from;
  register char *t = to;
  register int i = count;
  while (i-- > 0)
    *t++ = *f++;
}
```
user: What is the c source code of the assembly code below?

```asm
<__yy_bcopy>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%edi
  test   %edx,%edx
  jle    L86
  lea    0x1(%rcx),%r8
  mov    %rsi,%rax
  sub    %r8,%rax
  cmp    $0xe,%rax
  jbe    L28
  cmp    $0x6,%edi
  jbe    L28
  cmp    $0xe,%edi
  jbe    L145
  mov    %edx,%r8d
  xor    %eax,%eax
  shr    $0x4,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L20:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L20
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%r8d
  sub    %eax,%edi
  lea    (%rcx,%r8,1),%r9
  add    %rsi,%r8
  cmp    %eax,%edx
  je     L7
L77:
  sub    %eax,%edx
  lea    -0x1(%rdx),%r10d
  cmp    $0x6,%r10d
  jbe    L0
  mov    (%rcx,%rax,1),%rcx
  mov    %rcx,(%rsi,%rax,1)
  mov    %edx,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%ecx
  sub    %eax,%edi
  add    %rcx,%r9
  add    %rcx,%r8
  cmp    %eax,%edx
  je     L86
L0:
  movzbl (%r9),%eax
  mov    %al,(%r8)
  test   %edi,%edi
  jle    L86
  movzbl 0x1(%r9),%eax
  mov    %al,0x1(%r8)
  cmp    $0x1,%edi
  jle    L86
  movzbl 0x2(%r9),%eax
  mov    %al,0x2(%r8)
  cmp    $0x2,%edi
  jle    L86
  movzbl 0x3(%r9),%eax
  mov    %al,0x3(%r8)
  cmp    $0x3,%edi
  jle    L86
  movzbl 0x4(%r9),%eax
  mov    %al,0x4(%r8)
  cmp    $0x4,%edi
  jle    L86
  movzbl 0x5(%r9),%eax
  mov    %al,0x5(%r8)
  cmp    $0x5,%edi
  jle    L86
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%r8)
  ret
  nopl   (%rax)
L28:
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L102:
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L102
L86:
  ret
L145:
  mov    %rsi,%r8
  mov    %rcx,%r9
  xor    %eax,%eax
  jmp    L77
L7:
  ret
```

assistant: ```c
void __yy_bcopy(from, to, count) char *from;
char *to;
int count;
{
  register char *f = from;
  register char *t = to;
  register int i = count;
  while (i-- > 0)
    *t++ = *f++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  js     L2
  movl   $0x0,-0x18(%rbp)
  jmp    L28
L36:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x2,-0x18(%rbp)
L28:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L36
  jmp    L32
L2:
  nop
L32:
  pop    %rbp
  ret
```

assistant: ```c
void swab(const void *p_src_, void *p_dst_, ssize_t n) {
  const uint8_t *p_src = p_src_;
  uint8_t *p_dst = p_dst_;
  if (n < 0)
    return;
  for (ssize_t i = 0; i < n - 1; i += 2) {
    uint8_t i_tmp = p_src[i + 0];
    p_dst[i + 0] = p_src[i + 1];
    p_dst[i + 1] = i_tmp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swab>:
  endbr64
  test   %edx,%edx
  js     L7
  sub    $0x1,%edx
  test   %edx,%edx
  jle    L7
  mov    $0x0,%eax
L5:
  mov    (%rdi,%rax,4),%ecx
  mov    0x4(%rdi,%rax,4),%r8d
  mov    %r8d,(%rsi,%rax,4)
  mov    %ecx,0x4(%rsi,%rax,4)
  add    $0x2,%rax
  cmp    %eax,%edx
  jg     L5
L7:
  ret
```

assistant: ```c
void swab(const void *p_src_, void *p_dst_, ssize_t n) {
  const uint8_t *p_src = p_src_;
  uint8_t *p_dst = p_dst_;
  if (n < 0)
    return;
  for (ssize_t i = 0; i < n - 1; i += 2) {
    uint8_t i_tmp = p_src[i + 0];
    p_dst[i + 0] = p_src[i + 1];
    p_dst[i + 1] = i_tmp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swab>:
  endbr64
  test   %edx,%edx
  js     L11
  sub    $0x1,%edx
  test   %edx,%edx
  jle    L11
  xor    %eax,%eax
  nopl   0x0(%rax)
L24:
  mov    (%rdi,%rax,4),%ecx
  mov    0x4(%rdi,%rax,4),%r8d
  mov    %ecx,0x4(%rsi,%rax,4)
  mov    %r8d,(%rsi,%rax,4)
  add    $0x2,%rax
  cmp    %eax,%edx
  jg     L24
L11:
  ret
```

assistant: ```c
void swab(const void *p_src_, void *p_dst_, ssize_t n) {
  const uint8_t *p_src = p_src_;
  uint8_t *p_dst = p_dst_;
  if (n < 0)
    return;
  for (ssize_t i = 0; i < n - 1; i += 2) {
    uint8_t i_tmp = p_src[i + 0];
    p_dst[i + 0] = p_src[i + 1];
    p_dst[i + 1] = i_tmp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swab>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  js     L16
  lea    -0x1(%rdx),%edi
  test   %edi,%edi
  jle    L16
  mov    %rsi,%rax
  sub    %rcx,%rax
  sub    $0x4,%rax
  cmp    $0x8,%rax
  jbe    L39
  sub    $0x2,%edx
  mov    %edx,%edi
  shr    %edi
  add    $0x1,%edi
  cmp    $0x1,%edx
  jbe    L40
  mov    %edi,%edx
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  nopl   0x0(%rax,%rax,1)
L35:
  movdqu (%rcx,%rax,1),%xmm1
  pshufd $0xb1,%xmm1,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L35
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L71
L19:
  movq   (%rcx,%rax,8),%xmm0
  pshufd $0xe1,%xmm0,%xmm0
  movq   %xmm0,(%rsi,%rax,8)
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L67:
  movq   (%rcx,%rax,4),%xmm0
  pshufd $0xe1,%xmm0,%xmm0
  movq   %xmm0,(%rsi,%rax,4)
  add    $0x2,%rax
  cmp    %eax,%edi
  jg     L67
L16:
  ret
L40:
  xor    %eax,%eax
  jmp    L19
  nopl   0x0(%rax)
L71:
  ret
```

assistant: ```c
void swab(const void *p_src_, void *p_dst_, ssize_t n) {
  const uint8_t *p_src = p_src_;
  uint8_t *p_dst = p_dst_;
  if (n < 0)
    return;
  for (ssize_t i = 0; i < n - 1; i += 2) {
    uint8_t i_tmp = p_src[i + 0];
    p_dst[i + 0] = p_src[i + 1];
    p_dst[i + 1] = i_tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nodes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  D11(%rip),%xmm0
  movsd  %xmm0,(%rax)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L6
L3:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L3
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
datatype: byte[8]
name: parse_data
arguments: data_tag: D0
datatype: f64

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0xc0]}

tool: D0: 10

assistant: ```c
void nodes(int n, double *x) {
  double step;
  int i;
  x[0] = -5.0;
  step = 10.0 / (double)n;
  for (i = 1; i <= n; i++) {
    x[i] = x[i - 1] + step;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nodes>:
  endbr64
  mov    D7(%rip),%rax
  mov    %rax,(%rsi)
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  movsd  D14(%rip),%xmm1
  divsd  %xmm0,%xmm1
  test   %edi,%edi
  jle    L13
  mov    %rsi,%rax
  lea    -0x1(%rdi),%edx
  lea    0x8(%rsi,%rdx,8),%rdx
L15:
  movapd %xmm1,%xmm0
  addsd  (%rax),%xmm0
  movsd  %xmm0,0x8(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L15
L13:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: byte[8]
name: retrieve_data
arguments: tag: D14
data_type: f64

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0xc0]}

tool: D14: 10

assistant: ```c
void nodes(int n, double *x) {
  double step;
  int i;
  x[0] = -5.0;
  step = 10.0 / (double)n;
  for (i = 1; i <= n; i++) {
    x[i] = x[i - 1] + step;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nodes>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D11(%rip),%xmm0
  movsd  D16(%rip),%xmm1
  cvtsi2sd %edi,%xmm2
  movsd  %xmm0,(%rsi)
  divsd  %xmm2,%xmm1
  test   %edi,%edi
  jle    L24
  add    $0x8,%rsi
  lea    -0x1(%rdi),%eax
  lea    (%rsi,%rax,8),%rax
  jmp    L12
  nopl   (%rax)
L25:
  add    $0x8,%rsi
L12:
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  cmp    %rax,%rsi
  jne    L25
L24:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: byte[8]
name: parse_data
arguments: data_tag: D16
type_infered: f64

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0xc0]}

tool: D16: 10

assistant: ```c
void nodes(int n, double *x) {
  double step;
  int i;
  x[0] = -5.0;
  step = 10.0 / (double)n;
  for (i = 1; i <= n; i++) {
    x[i] = x[i - 1] + step;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<nodes>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D8(%rip),%xmm0
  movsd  D10(%rip),%xmm1
  cvtsi2sd %edi,%xmm2
  movsd  %xmm0,(%rsi)
  divsd  %xmm2,%xmm1
  test   %edi,%edi
  jle    L3
  lea    -0x1(%rdi),%edx
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdx,8),%rdx
  nopl   0x0(%rax)
L10:
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L10
L3:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: byte[8]
name: disassemble_data
arguments: label: D10
type: f64

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0xc0]}

tool: D10: 10

assistant: ```c
void nodes(int n, double *x) {
  double step;
  int i;
  x[0] = -5.0;
  step = 10.0 / (double)n;
  for (i = 1; i <= n; i++) {
    x[i] = x[i - 1] + step;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  jmp    L19
L4:
  mov    $0x0,%eax
  call   <barrier@plt>
L19:
  mov    $0xc0013018,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void flush(void) {
  while ((*(volatile unsigned char *)0xc0013018) & (1 << 3))
    barrier();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<flush>:
  endbr64
  movabs 0xc0013018,%al
  test   $0x8,%al
  je     L3
  push   %rbx
  mov    $0xc0013018,%ebx
L15:
  mov    $0x0,%eax
  call   <barrier@plt>
  movzbl (%rbx),%eax
  test   $0x8,%al
  jne    L15
  pop    %rbx
  ret
L3:
  ret
```

assistant: ```c
void flush(void) {
  while ((*(volatile unsigned char *)0xc0013018) & (1 << 3))
    barrier();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flush>:
  endbr64
  push   %rbx
  mov    $0xc0013018,%ebx
  movzbl (%rbx),%eax
  test   $0x8,%al
  je     L1
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <barrier@plt>
  movzbl (%rbx),%eax
  test   $0x8,%al
  jne    L9
L1:
  pop    %rbx
  ret
```

assistant: ```c
void flush(void) {
  while ((*(volatile unsigned char *)0xc0013018) & (1 << 3))
    barrier();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<flush>:
  endbr64
  push   %rbx
  mov    $0xc0013018,%ebx
  movzbl (%rbx),%eax
  test   $0x8,%al
  je     L8
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  call   <barrier@plt>
  movzbl (%rbx),%eax
  test   $0x8,%al
  jne    L10
L8:
  pop    %rbx
  ret
```

assistant: ```c
void flush(void) {
  while ((*(volatile unsigned char *)0xc0013018) & (1 << 3))
    barrier();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_protocol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  jg     L35
  mov    $0x1,%eax
  jmp    L31
L35:
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L0
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L32
L0:
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L32
  mov    $0x1,%eax
  jmp    L31
L32:
  mov    $0x0,%eax
L31:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string
name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D17
datatype: string

tool: D2: GET

tool: D11: POST

tool: D17: HTTP/1.

assistant: ```c
int check_protocol(char *buffer) {
  if (strlen(buffer) < 3)
    return 1;
  if ((strncmp(buffer, "GET", 3) == 0) || (strncmp(buffer, "POST", 4) == 0))
    if (strstr(buffer, "HTTP/1."))
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_protocol>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0x2,%edx
  jg     L28
L35:
  pop    %rbx
  ret
L28:
  mov    $0x3,%edx
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L15
  mov    $0x4,%edx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L35
L15:
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L35
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D11
type_guessed: string

tool: D12: GET

tool: D3: POST

tool: D11: HTTP/1.

assistant: ```c
int check_protocol(char *buffer) {
  if (strlen(buffer) < 3)
    return 1;
  if ((strncmp(buffer, "GET", 3) == 0) || (strncmp(buffer, "POST", 4) == 0))
    if (strstr(buffer, "HTTP/1."))
      return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_protocol>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x2,%r8d
  jg     L4
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  mov    $0x3,%edx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L13
  mov    $0x4,%edx
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L1
L13:
  mov    %rbp,%rdi
  lea    D20(%rip),%rsi
  call   <strstr@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string

tool: D15: GET

tool: D1: POST

tool: D20: HTTP/1.

assistant: ```c
int check_protocol(char *buffer) {
  if (strlen(buffer) < 3)
    return 1;
  if ((strncmp(buffer, "GET", 3) == 0) || (strncmp(buffer, "POST", 4) == 0))
    if (strstr(buffer, "HTTP/1."))
      return 1;
  return 0;
}
```