ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Pnl_SavePanelState>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <Pnl_GetPlatform@plt>
```

assistant: ```c
void Pnl_SavePanelState(void) {
  int Platform;
  Platform = Pnl_GetPlatform();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Pnl_SavePanelState>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <Pnl_GetPlatform@plt>
```

assistant: ```c
void Pnl_SavePanelState(void) {
  int Platform;
  Platform = Pnl_GetPlatform();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  call   <baz@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int __attribute__((annotate("realtime"))) main() {
  int barbar;
  foo(barbar);
  baz();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  call   <baz@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __attribute__((annotate("realtime"))) main() {
  int barbar;
  foo(barbar);
  baz();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <foo@plt>
  xor    %eax,%eax
  call   <baz@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __attribute__((annotate("realtime"))) main() {
  int barbar;
  foo(barbar);
  baz();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <foo@plt>
  xor    %eax,%eax
  call   <baz@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __attribute__((annotate("realtime"))) main() {
  int barbar;
  foo(barbar);
  baz();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<V3DMPMemDup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L44
  cmpl   $0x0,-0x1c(%rbp)
  jg     L23
L44:
  mov    -0x8(%rbp),%rax
  jmp    L0
L23:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  mov    -0x8(%rbp),%rax
  jmp    L0
L31:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
void *V3DMPMemDup(const void *buf, int total) {
  void *rtn_buf = NULL;
  if ((buf == NULL) || (total <= 0))
    return (rtn_buf);
  rtn_buf = malloc(total);
  if (rtn_buf == NULL)
    return (rtn_buf);
  else
    memcpy(rtn_buf, buf, total);
  return (rtn_buf);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<V3DMPMemDup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L25
  mov    %rdi,%r12
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L25
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L26
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L26:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    $0x0,%ebp
  jmp    L26
```

assistant: ```c
void *V3DMPMemDup(const void *buf, int total) {
  void *rtn_buf = NULL;
  if ((buf == NULL) || (total <= 0))
    return (rtn_buf);
  rtn_buf = malloc(total);
  if (rtn_buf == NULL)
    return (rtn_buf);
  else
    memcpy(rtn_buf, buf, total);
  return (rtn_buf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<V3DMPMemDup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L26
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L26
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L6
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L26:
  xor    %r13d,%r13d
  pop    %rbp
  pop    %r12
  mov    %r13,%rax
  pop    %r13
  ret
```

assistant: ```c
void *V3DMPMemDup(const void *buf, int total) {
  void *rtn_buf = NULL;
  if ((buf == NULL) || (total <= 0))
    return (rtn_buf);
  rtn_buf = malloc(total);
  if (rtn_buf == NULL)
    return (rtn_buf);
  else
    memcpy(rtn_buf, buf, total);
  return (rtn_buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<V3DMPMemDup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L20
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L20
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L1
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L1:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L20:
  xor    %r13d,%r13d
  pop    %rbp
  pop    %r12
  mov    %r13,%rax
  pop    %r13
  ret
```

assistant: ```c
void *V3DMPMemDup(const void *buf, int total) {
  void *rtn_buf = NULL;
  if ((buf == NULL) || (total <= 0))
    return (rtn_buf);
  rtn_buf = malloc(total);
  if (rtn_buf == NULL)
    return (rtn_buf);
  else
    memcpy(rtn_buf, buf, total);
  return (rtn_buf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_dir_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L121
  cmpq   $0x0,-0x20(%rbp)
  jne    L107
L121:
  mov    D47(%rip),%rax
  mov    (%rax),%edx
  mov    D59(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L106
L107:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L145
L94:
  subq   $0x1,-0x8(%rbp)
L145:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L171
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L94
  jmp    L171
L41:
  subq   $0x1,-0x8(%rbp)
L171:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L52
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L41
  jmp    L52
L167:
  subq   $0x1,-0x8(%rbp)
L52:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L89
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L167
L89:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L158
  cmpq   $0x1,-0x28(%rbp)
  ja     L165
  mov    D51(%rip),%rax
  mov    (%rax),%edx
  mov    D59(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L106
L165:
  mov    -0x20(%rbp),%rax
  movb   $0x2e,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L137
L158:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L92
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L130
L92:
  mov    D51(%rip),%rax
  mov    (%rax),%edx
  mov    D59(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L106
L130:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L137:
  mov    -0x20(%rbp),%rax
L106:
  leave
  ret
```

assistant: ```c
char *get_dir_name(const char *srcpath, char *dstdir, size_t dstdirlen) {
  const char *p;
  int len;
  if ((srcpath == NULL) || (dstdir == NULL)) {
    errno = EINVAL;
    return (NULL);
  }
  p = srcpath + strlen(srcpath) - 1;
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  while ((p >= srcpath) && (*p != '/')) {
    p--;
  }
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  if (p < srcpath) {
    if (dstdirlen < 2) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    dstdir[0] = '.';
    dstdir[1] = '\0';
  } else {
    len = p - srcpath + 1;
    if ((len <= 0) || (len >= dstdirlen)) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    (void)strncpy(dstdir, srcpath, len);
    dstdir[len] = '\0';
  }
  return (dstdir);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_dir_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L154
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  test   %rsi,%rsi
  je     L154
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  cmp    %rdx,%rbx
  jae    L203
L8:
  cmpb   $0x2f,(%rdx)
  jne    L38
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L8
  mov    %rbx,%rdx
L91:
  cmpb   $0x2f,(%rdx)
  je     L33
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  jbe    L91
L223:
  cmp    %rdx,%rbx
  jae    L65
L84:
  cmpb   $0x2f,(%rdx)
  jne    L64
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  jb     L84
L64:
  cmp    %rdx,%rbx
  ja     L65
  sub    %rbx,%rdx
  add    $0x1,%edx
  test   %edx,%edx
  jle    L40
  movslq %edx,%r13
  cmp    %r12,%r13
  jae    L40
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    %rbp,%rax
  jmp    L226
L154:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D51(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L226
L38:
  cmp    %rdx,%rbx
  jbe    L91
  jmp    L223
L33:
  cmp    %rdx,%rbx
  jb     L84
  jmp    L64
L117:
  mov    D41(%rip),%rax
  mov    (%rax),%edx
  mov    D51(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L226
L40:
  mov    D41(%rip),%rax
  mov    (%rax),%edx
  mov    D51(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L226
L203:
  jbe    L91
L65:
  cmp    $0x1,%r12
  jbe    L117
  movb   $0x2e,0x0(%rbp)
  movb   $0x0,0x1(%rbp)
  mov    %rbp,%rax
L226:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_dir_name(const char *srcpath, char *dstdir, size_t dstdirlen) {
  const char *p;
  int len;
  if ((srcpath == NULL) || (dstdir == NULL)) {
    errno = EINVAL;
    return (NULL);
  }
  p = srcpath + strlen(srcpath) - 1;
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  while ((p >= srcpath) && (*p != '/')) {
    p--;
  }
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  if (p < srcpath) {
    if (dstdirlen < 2) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    dstdir[0] = '.';
    dstdir[1] = '\0';
  } else {
    len = p - srcpath + 1;
    if ((len <= 0) || (len >= dstdirlen)) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    (void)strncpy(dstdir, srcpath, len);
    dstdir[len] = '\0';
  }
  return (dstdir);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_dir_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L18
  mov    %rdi,%rbp
  mov    %rdx,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
  cmp    %rcx,%rbp
  jb     L76
  jmp    L84
  nopl   0x0(%rax)
L176:
  sub    $0x1,%rcx
  cmp    %rcx,%rbp
  je     L6
L76:
  cmpb   $0x2f,(%rcx)
  je     L176
  jmp    L123
L84:
  ja     L146
  nopw   0x0(%rax,%rax,1)
L6:
  movzbl (%rcx),%edi
  cmp    $0x2f,%dil
  je     L34
  sub    $0x1,%rcx
L123:
  cmp    %rcx,%rbp
  jbe    L6
  cmp    %rbp,%rcx
  ja     L184
  jmp    L146
  nopl   0x0(%rax)
L121:
  sub    $0x1,%rcx
  cmp    %rcx,%rbp
  jae    L80
L184:
  movzbl (%rcx),%edi
L107:
  cmp    $0x2f,%dil
  je     L121
L80:
  cmp    %rcx,%rbp
  jbe    L83
L146:
  cmp    $0x1,%r12
  jbe    L110
  mov    $0x2e,%eax
  mov    %ax,(%rbx)
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L83:
  sub    %rbp,%rcx
  lea    0x1(%rcx),%edx
  test   %edx,%edx
  jle    L110
  movslq %edx,%r13
  cmp    %r12,%r13
  jae    L110
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r13,1)
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  cmp    %rcx,%rbp
  jb     L107
  jmp    L80
  nopw   0x0(%rax,%rax,1)
L18:
  mov    D32(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L110:
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_dir_name(const char *srcpath, char *dstdir, size_t dstdirlen) {
  const char *p;
  int len;
  if ((srcpath == NULL) || (dstdir == NULL)) {
    errno = EINVAL;
    return (NULL);
  }
  p = srcpath + strlen(srcpath) - 1;
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  while ((p >= srcpath) && (*p != '/')) {
    p--;
  }
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  if (p < srcpath) {
    if (dstdirlen < 2) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    dstdir[0] = '.';
    dstdir[1] = '\0';
  } else {
    len = p - srcpath + 1;
    if ((len <= 0) || (len >= dstdirlen)) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    (void)strncpy(dstdir, srcpath, len);
    dstdir[len] = '\0';
  }
  return (dstdir);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_dir_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L30
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L30
  mov    %rdi,%rbp
  mov    %rdx,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
  cmp    %rcx,%rbp
  jb     L13
  jmp    L150
  nopl   0x0(%rax)
L14:
  sub    $0x1,%rcx
  cmp    %rcx,%rbp
  je     L132
L13:
  cmpb   $0x2f,(%rcx)
  je     L14
  jmp    L57
L150:
  ja     L86
  nopw   0x0(%rax,%rax,1)
L132:
  cmpb   $0x2f,(%rcx)
  je     L85
  sub    $0x1,%rcx
L57:
  cmp    %rcx,%rbp
  jbe    L132
  cmp    %rbp,%rcx
  jbe    L86
  nopl   0x0(%rax,%rax,1)
L7:
  cmpb   $0x2f,(%rcx)
  jne    L89
  sub    $0x1,%rcx
L85:
  cmp    %rcx,%rbp
  jb     L7
L89:
  cmp    %rcx,%rbp
  ja     L86
  sub    %rbp,%rcx
  lea    0x1(%rcx),%edx
  test   %edx,%edx
  jle    L158
  movslq %edx,%r13
  cmp    %r12,%r13
  jae    L158
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r13,1)
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L86:
  cmp    $0x1,%r12
  jbe    L158
  mov    $0x2e,%eax
  mov    %ax,(%rbx)
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L30:
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L158:
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_dir_name(const char *srcpath, char *dstdir, size_t dstdirlen) {
  const char *p;
  int len;
  if ((srcpath == NULL) || (dstdir == NULL)) {
    errno = EINVAL;
    return (NULL);
  }
  p = srcpath + strlen(srcpath) - 1;
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  while ((p >= srcpath) && (*p != '/')) {
    p--;
  }
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  if (p < srcpath) {
    if (dstdirlen < 2) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    dstdir[0] = '.';
    dstdir[1] = '\0';
  } else {
    len = p - srcpath + 1;
    if ((len <= 0) || (len >= dstdirlen)) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    (void)strncpy(dstdir, srcpath, len);
    dstdir[len] = '\0';
  }
  return (dstdir);
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_fiblist_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_fiblist_matrix(m, nrl, nrh, ncl, nch) struct fiblist ***m;
long nch, ncl, nrh, nrl;
{
  free((char *)(m[nrl] + ncl - 1));
  free((char *)(m + nrl - 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<free_fiblist_matrix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x0(,%rsi,8),%rbp
  mov    (%rdi,%rsi,8),%rax
  lea    -0x8(%rax,%rcx,8),%rdi
  call   <free@plt>
  lea    -0x8(%rbx,%rbp,1),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_fiblist_matrix(m, nrl, nrh, ncl, nch) struct fiblist ***m;
long nch, ncl, nrh, nrl;
{
  free((char *)(m[nrl] + ncl - 1));
  free((char *)(m + nrl - 1));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_fiblist_matrix>:
  endbr64
  push   %rbp
  lea    0x0(,%rsi,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi,%rsi,8),%rax
  lea    -0x8(%rax,%rcx,8),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  lea    -0x8(%rbx,%rbp,1),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_fiblist_matrix(m, nrl, nrh, ncl, nch) struct fiblist ***m;
long nch, ncl, nrh, nrl;
{
  free((char *)(m[nrl] + ncl - 1));
  free((char *)(m + nrl - 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RotateScalePointX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  %xmm3,-0x20(%rbp)
  movss  %xmm4,-0x24(%rbp)
  movss  %xmm5,-0x28(%rbp)
  movss  %xmm6,-0x2c(%rbp)
  movss  -0x14(%rbp),%xmm0
  subss  -0x1c(%rbp),%xmm0
  movss  -0x28(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x18(%rbp),%xmm0
  subss  -0x20(%rbp),%xmm0
  movss  -0x2c(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  movd   %eax,%xmm0
  call   <Cos@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm7
  mulss  -0x8(%rbp),%xmm7
  movss  %xmm7,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  movd   %eax,%xmm0
  call   <Sin@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm1
  mulss  -0x4(%rbp),%xmm1
  movss  -0x30(%rbp),%xmm0
  subss  %xmm1,%xmm0
  addss  -0x1c(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float RotateScalePointX(float x, float y, float centerX, float centerY, float degrees, float scaleX, float scaleY) {
  float dx = (x - centerX) * scaleX;
  float dy = (y - centerY) * scaleY;
  return (Cos(degrees) * dx) - (Sin(degrees) * dy) + centerX;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RotateScalePointX>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm2,0x8(%rsp)
  subss  %xmm2,%xmm0
  mulss  %xmm5,%xmm0
  movss  %xmm0,(%rsp)
  subss  %xmm3,%xmm1
  mulss  %xmm6,%xmm1
  movss  %xmm1,0x4(%rsp)
  movss  %xmm4,0xc(%rsp)
  movaps %xmm4,%xmm0
  call   <Cos@plt>
  movaps %xmm0,%xmm7
  mulss  (%rsp),%xmm7
  movss  %xmm7,(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <Sin@plt>
  movss  0x4(%rsp),%xmm1
  mulss  %xmm0,%xmm1
  movss  (%rsp),%xmm0
  subss  %xmm1,%xmm0
  addss  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
float RotateScalePointX(float x, float y, float centerX, float centerY, float degrees, float scaleX, float scaleY) {
  float dx = (x - centerX) * scaleX;
  float dy = (y - centerY) * scaleY;
  return (Cos(degrees) * dx) - (Sin(degrees) * dy) + centerX;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RotateScalePointX>:
  endbr64
  subss  %xmm3,%xmm1
  subss  %xmm2,%xmm0
  sub    $0x18,%rsp
  movss  %xmm2,0xc(%rsp)
  movss  %xmm4,0x8(%rsp)
  mulss  %xmm5,%xmm0
  movaps %xmm1,%xmm7
  mulss  %xmm6,%xmm7
  movss  %xmm0,(%rsp)
  movaps %xmm4,%xmm0
  movss  %xmm7,0x4(%rsp)
  call   <Cos@plt>
  movss  (%rsp),%xmm1
  movss  0x8(%rsp),%xmm4
  mulss  %xmm0,%xmm1
  movaps %xmm4,%xmm0
  movss  %xmm1,(%rsp)
  call   <Sin@plt>
  movss  0x4(%rsp),%xmm3
  movss  (%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  add    $0x18,%rsp
  mulss  %xmm0,%xmm3
  subss  %xmm3,%xmm1
  movaps %xmm1,%xmm0
  addss  %xmm2,%xmm0
  ret
```

assistant: ```c
float RotateScalePointX(float x, float y, float centerX, float centerY, float degrees, float scaleX, float scaleY) {
  float dx = (x - centerX) * scaleX;
  float dy = (y - centerY) * scaleY;
  return (Cos(degrees) * dx) - (Sin(degrees) * dy) + centerX;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RotateScalePointX>:
  endbr64
  subss  %xmm3,%xmm1
  subss  %xmm2,%xmm0
  sub    $0x18,%rsp
  movss  %xmm2,0xc(%rsp)
  movss  %xmm4,0x8(%rsp)
  mulss  %xmm5,%xmm0
  movaps %xmm1,%xmm7
  mulss  %xmm6,%xmm7
  movss  %xmm0,(%rsp)
  movaps %xmm4,%xmm0
  movss  %xmm7,0x4(%rsp)
  call   <Cos@plt>
  movss  (%rsp),%xmm1
  movss  0x8(%rsp),%xmm4
  mulss  %xmm0,%xmm1
  movaps %xmm4,%xmm0
  movss  %xmm1,(%rsp)
  call   <Sin@plt>
  movss  0x4(%rsp),%xmm3
  movss  (%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  add    $0x18,%rsp
  mulss  %xmm0,%xmm3
  subss  %xmm3,%xmm1
  movaps %xmm1,%xmm0
  addss  %xmm2,%xmm0
  ret
```

assistant: ```c
float RotateScalePointX(float x, float y, float centerX, float centerY, float degrees, float scaleX, float scaleY) {
  float dx = (x - centerX) * scaleX;
  float dy = (y - centerY) * scaleY;
  return (Cos(degrees) * dx) - (Sin(degrees) * dy) + centerX;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trmv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L36:
  mov    -0xc(%rbp),%edx
  mov    %edx,-0x10(%rbp)
  jmp    L35
L10:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movsd  (%rdx),%xmm1
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  movsd  (%rcx,%rdx,8),%xmm2
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movsd  (%rdx),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  addl   $0x1,-0x10(%rbp)
L35:
  mov    -0x10(%rbp),%edx
  cmp    -0x14(%rbp),%edx
  jl     L10
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%edx
  cmp    -0x14(%rbp),%edx
  jl     L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void trmv(int n, double A[][n], double x[n], double y[n]) {
  int i, j;
  for (j = 0; j < n; j++)
    for (i = j; i < n; i++) {
      y[j] = y[j] + A[i][j] * x[i];
    }
}
```