ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L21
L24:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x2c(%rbp)
L21:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L24
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%ecx
  mov    -0x34(%rbp),%esi
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <producer_consumer@plt>
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string

tool: D28: %d %d %d

tool: D8: %d

tool: D0: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  double start, end;
  float d;
  int i, n, size, nt;
  int *buff;
  int *vec;
  scanf("%d %d %d", &nt, &n, &size);
  buff = (int *)malloc(size * sizeof(int));
  vec = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    scanf("%d", &vec[i]);
  start = omp_get_wtime();
  producer_consumer(buff, size, vec, n);
  end = omp_get_wtime();
  printf("%lf\n", end - start);
  free(buff);
  free(vec);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    0xc(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmpl   $0x0,0xc(%rsp)
  jle    L13
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D20(%rip),%r12
L20:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L20
L13:
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rbx
  mov    0xc(%rsp),%ecx
  mov    %r13,%rdx
  mov    0x10(%rsp),%esi
  mov    %r14,%rdi
  call   <producer_consumer@plt>
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %rbx,%xmm1
  subsd  %xmm1,%xmm0
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D20
datatype: string
name: read_data
arguments: label: D21
datatype: string

tool: D9: %d %d %d

tool: D20: %d

tool: D21: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  double start, end;
  float d;
  int i, n, size, nt;
  int *buff;
  int *vec;
  scanf("%d %d %d", &nt, &n, &size);
  buff = (int *)malloc(size * sizeof(int));
  vec = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    scanf("%d", &vec[i]);
  start = omp_get_wtime();
  producer_consumer(buff, size, vec, n);
  end = omp_get_wtime();
  printf("%lf\n", end - start);
  free(buff);
  free(vec);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x1c(%rsp),%rdx
  lea    0x24(%rsp),%rsi
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    0x1c(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L13
  mov    %r13,%rbp
  xor    %ebx,%ebx
  lea    D11(%rip),%r12
  nopl   (%rax)
L12:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x1c(%rsp)
  jg     L12
L13:
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    0x1c(%rsp),%ecx
  mov    0x20(%rsp),%esi
  mov    %r13,%rdx
  mov    %r14,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <producer_consumer@plt>
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  subsd  0x8(%rsp),%xmm0
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D13
datatype: string
name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D10
datatype: string

tool: D13: %d %d %d

tool: D11: %d

tool: D10: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  double start, end;
  float d;
  int i, n, size, nt;
  int *buff;
  int *vec;
  scanf("%d %d %d", &nt, &n, &size);
  buff = (int *)malloc(size * sizeof(int));
  vec = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    scanf("%d", &vec[i]);
  start = omp_get_wtime();
  producer_consumer(buff, size, vec, n);
  end = omp_get_wtime();
  printf("%lf\n", end - start);
  free(buff);
  free(vec);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D19(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x1c(%rsp),%rdx
  lea    0x24(%rsp),%rsi
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    0x1c(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L10
  mov    %r13,%rbp
  xor    %ebx,%ebx
  lea    D5(%rip),%r12
  nopl   (%rax)
L18:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x1c(%rsp)
  jg     L18
L10:
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    0x1c(%rsp),%ecx
  mov    0x20(%rsp),%esi
  mov    %r13,%rdx
  mov    %r14,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <producer_consumer@plt>
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  subsd  0x8(%rsp),%xmm0
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
type: string
name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D23
type: string

tool: D19: %d %d %d

tool: D5: %d

tool: D23: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  double start, end;
  float d;
  int i, n, size, nt;
  int *buff;
  int *vec;
  scanf("%d %d %d", &nt, &n, &size);
  buff = (int *)malloc(size * sizeof(int));
  vec = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    scanf("%d", &vec[i]);
  start = omp_get_wtime();
  producer_consumer(buff, size, vec, n);
  end = omp_get_wtime();
  printf("%lf\n", end - start);
  free(buff);
  free(vec);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L6:
  mov    $0x0,%eax
  call   <playgame@plt>
  mov    $0x0,%eax
  call   <playagain@plt>
  test   %rax,%rax
  jne    L6
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D29
datatype: string
name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D23
datatype: string

tool: D29: Reflex
------

How's your reflexes? In this game see how accurately you can tell how
much time has elapsed. The computer will give you a number of seconds.
When you are ready press ENTER to start the timer, then press ENTER
again when you think the given amount of time has elapsed.


tool: D3: 







	Cymon's Games

	http://WWW.CYMONSGAMES.COM


   This game and its code is a 2008 Cymon's Games game.
   If you have enjoyed this game or would just like to have a new game
   each week please visit:
   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs
   for everyone, beginners and advanced users alike.



tool: D23: 
	Press ENTER to continue...







assistant: ```c
int main(void) {
  puts("Reflex\n------\n\n"
       "How's your reflexes? In this game see how accurately you can tell how\n"
       "much time has elapsed. The computer will give you a number of seconds.\n"
       "When you are ready press ENTER to start the timer, then press ENTER\n"
       "again when you think the given amount of time has elapsed.\n");
  srand(time(NULL));
  do
    playgame();
  while (playagain());
  puts("\n\n\n\n\n\n\n\n\tCymon's Games\n\n\thttp://WWW.CYMONSGAMES.COM\n\n\n"
       "   This game and its code is a 2008 Cymon's Games game.\n"
       "   If you have enjoyed this game or would just like to have a new game\n"
       "   each week please visit:\n"
       "   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs\n"
       "   for everyone, beginners and advanced users alike.\n\n");
  printf("\n\tPress ENTER to continue...\n\n\n\n\n\n");
  getchar();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L3:
  mov    $0x0,%eax
  call   <playgame@plt>
  mov    $0x0,%eax
  call   <playagain@plt>
  test   %rax,%rax
  jne    L3
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string
name: retrieve_data
arguments: tag: D20
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D0: Reflex
------

How's your reflexes? In this game see how accurately you can tell how
much time has elapsed. The computer will give you a number of seconds.
When you are ready press ENTER to start the timer, then press ENTER
again when you think the given amount of time has elapsed.


tool: D20: 







	Cymon's Games

	http://WWW.CYMONSGAMES.COM


   This game and its code is a 2008 Cymon's Games game.
   If you have enjoyed this game or would just like to have a new game
   each week please visit:
   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs
   for everyone, beginners and advanced users alike.



tool: D5: 
	Press ENTER to continue...







assistant: ```c
int main(void) {
  puts("Reflex\n------\n\n"
       "How's your reflexes? In this game see how accurately you can tell how\n"
       "much time has elapsed. The computer will give you a number of seconds.\n"
       "When you are ready press ENTER to start the timer, then press ENTER\n"
       "again when you think the given amount of time has elapsed.\n");
  srand(time(NULL));
  do
    playgame();
  while (playagain());
  puts("\n\n\n\n\n\n\n\n\tCymon's Games\n\n\thttp://WWW.CYMONSGAMES.COM\n\n\n"
       "   This game and its code is a 2008 Cymon's Games game.\n"
       "   If you have enjoyed this game or would just like to have a new game\n"
       "   each week please visit:\n"
       "   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs\n"
       "   for everyone, beginners and advanced users alike.\n\n");
  printf("\n\tPress ENTER to continue...\n\n\n\n\n\n");
  getchar();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <playgame@plt>
  xor    %eax,%eax
  call   <playagain@plt>
  test   %rax,%rax
  jne    L5
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D17
type: string
name: retrieve_data
arguments: data_label: D23
type: string

tool: D12: Reflex
------

How's your reflexes? In this game see how accurately you can tell how
much time has elapsed. The computer will give you a number of seconds.
When you are ready press ENTER to start the timer, then press ENTER
again when you think the given amount of time has elapsed.


tool: D17: 







	Cymon's Games

	http://WWW.CYMONSGAMES.COM


   This game and its code is a 2008 Cymon's Games game.
   If you have enjoyed this game or would just like to have a new game
   each week please visit:
   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs
   for everyone, beginners and advanced users alike.



tool: D23: 
	Press ENTER to continue...







assistant: ```c
int main(void) {
  puts("Reflex\n------\n\n"
       "How's your reflexes? In this game see how accurately you can tell how\n"
       "much time has elapsed. The computer will give you a number of seconds.\n"
       "When you are ready press ENTER to start the timer, then press ENTER\n"
       "again when you think the given amount of time has elapsed.\n");
  srand(time(NULL));
  do
    playgame();
  while (playagain());
  puts("\n\n\n\n\n\n\n\n\tCymon's Games\n\n\thttp://WWW.CYMONSGAMES.COM\n\n\n"
       "   This game and its code is a 2008 Cymon's Games game.\n"
       "   If you have enjoyed this game or would just like to have a new game\n"
       "   each week please visit:\n"
       "   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs\n"
       "   for everyone, beginners and advanced users alike.\n\n");
  printf("\n\tPress ENTER to continue...\n\n\n\n\n\n");
  getchar();
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <playgame@plt>
  xor    %eax,%eax
  call   <playagain@plt>
  test   %rax,%rax
  jne    L7
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type_infered: string
name: retrieve_data
arguments: data_tag: D22
type_infered: string
name: retrieve_data
arguments: data_tag: D25
type_infered: string

tool: D21: Reflex
------

How's your reflexes? In this game see how accurately you can tell how
much time has elapsed. The computer will give you a number of seconds.
When you are ready press ENTER to start the timer, then press ENTER
again when you think the given amount of time has elapsed.


tool: D22: 







	Cymon's Games

	http://WWW.CYMONSGAMES.COM


   This game and its code is a 2008 Cymon's Games game.
   If you have enjoyed this game or would just like to have a new game
   each week please visit:
   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs
   for everyone, beginners and advanced users alike.



tool: D25: 
	Press ENTER to continue...







assistant: ```c
int main(void) {
  puts("Reflex\n------\n\n"
       "How's your reflexes? In this game see how accurately you can tell how\n"
       "much time has elapsed. The computer will give you a number of seconds.\n"
       "When you are ready press ENTER to start the timer, then press ENTER\n"
       "again when you think the given amount of time has elapsed.\n");
  srand(time(NULL));
  do
    playgame();
  while (playagain());
  puts("\n\n\n\n\n\n\n\n\tCymon's Games\n\n\thttp://WWW.CYMONSGAMES.COM\n\n\n"
       "   This game and its code is a 2008 Cymon's Games game.\n"
       "   If you have enjoyed this game or would just like to have a new game\n"
       "   each week please visit:\n"
       "   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs\n"
       "   for everyone, beginners and advanced users alike.\n\n");
  printf("\n\tPress ENTER to continue...\n\n\n\n\n\n");
  getchar();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_prime_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x21,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  lea    D4(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D4: %d

assistant: ```c
char *set_prime_string(int prime) {
  char *prime_string = malloc(sizeof(char) * 32 + 1);
  snprintf(prime_string, 32, "%d", prime);
  return prime_string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_prime_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x21,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%ecx
  lea    D1(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: %d

assistant: ```c
char *set_prime_string(int prime) {
  char *prime_string = malloc(sizeof(char) * 32 + 1);
  snprintf(prime_string, 32, "%d", prime);
  return prime_string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_prime_string>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x21,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%ecx
  mov    $0x20,%esi
  lea    D7(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: %d

assistant: ```c
char *set_prime_string(int prime) {
  char *prime_string = malloc(sizeof(char) * 32 + 1);
  snprintf(prime_string, 32, "%d", prime);
  return prime_string;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_prime_string>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x21,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%ecx
  mov    $0x20,%esi
  lea    D9(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: %d

assistant: ```c
char *set_prime_string(int prime) {
  char *prime_string = malloc(sizeof(char) * 32 + 1);
  snprintf(prime_string, 32, "%d", prime);
  return prime_string;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<epolltopoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movw   $0x0,-0x2(%rbp)
  mov    D99(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L40
  mov    D44(%rip),%rax
  movzwl (%rax),%eax
  or     %ax,-0x2(%rbp)
L40:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L4
  mov    D17(%rip),%rax
  movzwl (%rax),%eax
  or     %ax,-0x2(%rbp)
L4:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L9
  mov    D45(%rip),%rax
  movzwl (%rax),%eax
  or     %ax,-0x2(%rbp)
L9:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L28
  mov    D54(%rip),%rax
  movzwl (%rax),%eax
  or     %ax,-0x2(%rbp)
L28:
  mov    D77(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L45
  mov    D64(%rip),%rax
  movzwl (%rax),%eax
  or     %ax,-0x2(%rbp)
L45:
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short epolltopoll(unsigned int events) {
  short e = 0;
  if (events & EPOLLIN)
    e |= POLLIN;
  if (events & EPOLLOUT)
    e |= POLLOUT;
  if (events & EPOLLERR)
    e |= POLLERR;
  if (events & EPOLLPRI)
    e |= POLLPRI;
  if (events & EPOLLHUP)
    e |= POLLHUP;
  return e;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<epolltopoll>:
  endbr64
  mov    D14(%rip),%rax
  mov    %edi,%edx
  and    (%rax),%edx
  mov    $0x0,%eax
  je     L17
  mov    D45(%rip),%rax
  movzwl (%rax),%eax
L17:
  mov    D43(%rip),%rdx
  mov    %edi,%ecx
  and    (%rdx),%ecx
  je     L45
  mov    D42(%rip),%rdx
  or     (%rdx),%ax
L45:
  mov    D11(%rip),%rdx
  mov    %edi,%esi
  and    (%rdx),%esi
  je     L5
  mov    D54(%rip),%rdx
  or     (%rdx),%ax
L5:
  mov    D46(%rip),%rdx
  mov    %edi,%ecx
  and    (%rdx),%ecx
  je     L20
  mov    D29(%rip),%rdx
  or     (%rdx),%ax
L20:
  mov    D50(%rip),%rdx
  and    (%rdx),%edi
  je     L35
  mov    D64(%rip),%rdx
  or     (%rdx),%ax
L35:
  ret
```

assistant: ```c
short epolltopoll(unsigned int events) {
  short e = 0;
  if (events & EPOLLIN)
    e |= POLLIN;
  if (events & EPOLLOUT)
    e |= POLLOUT;
  if (events & EPOLLERR)
    e |= POLLERR;
  if (events & EPOLLPRI)
    e |= POLLPRI;
  if (events & EPOLLHUP)
    e |= POLLHUP;
  return e;
}
```