user: 请从给定的汇编指令推导出C源代码：

```asm
<qromo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  movss  %xmm0,-0xac(%rbp)
  movss  %xmm1,-0xb0(%rbp)
  mov    %rsi,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D31(%rip),%xmm0
  movss  %xmm0,-0x8c(%rbp)
  movl   $0x1,-0x94(%rbp)
  jmp    L9
L47:
  mov    -0x94(%rbp),%ecx
  movss  -0xb0(%rbp),%xmm0
  mov    -0xac(%rbp),%edx
  mov    -0xa8(%rbp),%rax
  mov    -0xb8(%rbp),%r8
  mov    %ecx,%esi
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   *%r8
  movd   %xmm0,%eax
  mov    -0x94(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x50(%rbp,%rdx,4)
  cmpl   $0x4,-0x94(%rbp)
  jle    L37
  mov    -0x94(%rbp),%eax
  sub    $0x5,%eax
  lea    -0x50(%rbp),%rdx
  cltq
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x94(%rbp),%eax
  sub    $0x5,%eax
  lea    -0x90(%rbp),%rdx
  cltq
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%rdi
  lea    -0x98(%rbp),%rdx
  lea    -0x9c(%rbp),%rax
  mov    %rdx,%r8
  mov    %rax,%rcx
  mov    D44(%rip),%eax
  movd   %eax,%xmm0
  mov    $0x5,%edx
  call   <polint@plt>
  mov    -0x98(%rbp),%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movsd  %xmm0,-0xc0(%rbp)
  mov    -0x9c(%rbp),%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movsd  D49(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  comisd -0xc0(%rbp),%xmm0
  jbe    L37
  movss  -0x9c(%rbp),%xmm0
  jmp    L42
L37:
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x94(%rbp),%eax
  cltq
  movss  -0x50(%rbp,%rax,4),%xmm0
  movslq %edx,%rax
  movss  %xmm0,-0x50(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  cltq
  movss  -0x90(%rbp,%rax,4),%xmm0
  mov    -0x94(%rbp),%eax
  add    $0x1,%eax
  movss  D6(%rip),%xmm1
  divss  %xmm1,%xmm0
  cltq
  movss  %xmm0,-0x90(%rbp,%rax,4)
  addl   $0x1,-0x94(%rbp)
L9:
  cmpl   $0xe,-0x94(%rbp)
  jle    L47
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
  pxor   %xmm0,%xmm0
L42:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D31
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D44
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D49
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string

tool: D31: 1

tool: D44: 0

tool: {"D49": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D6: 9

tool: D17: Too many steps in routing qromo

assistant: ```c
float qromo(float (*func)(float), float a, float b, float (*choose)(float (*)(float), float, float, int)) {
  void polint(float xa[], float ya[], int n, float x, float *y, float *dy);
  void nrerror(char error_text[]);
  int j;
  float ss, dss, h[(14 + 1) + 1], s[(14 + 1) + 1];
  h[1] = 1.0;
  for (j = 1; j <= 14; j++) {
    s[j] = (*choose)(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) < 1.0e-6 * fabs(ss))
        return ss;
    }
    s[j + 1] = s[j];
    h[j + 1] = h[j] / 9.0;
  }
  nrerror("Too many steps in routing qromo");
  return 0.0;
}
```