ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%rax
  mov    %rcx,%rdx
  mov    %fs:0x28,%rcx
  mov    %rcx,0x28(%rsp)
  xor    %ecx,%ecx
  movq   $0x0,0x18(%rsp)
  mov    %edi,(%rsp)
  movl   $0x3e8,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <doioctl@plt>
  test   %eax,%eax
  mov    $0xffffffff,%edx
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %edi,(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    (%rax),%edi
  movl   $0x3e8,0x4(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  call   <doioctl@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %edi,(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    (%rax),%edi
  movl   $0x3e8,0x4(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  call   <doioctl@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fff_gamln>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x58,%rsp
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D47(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D97(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D90(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D45(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D50(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D20(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    0x10(%rsp),%rax
  lea    0x40(%rsp),%rdx
  movapd %xmm0,%xmm1
  movsd  D72(%rip),%xmm7
  movsd  %xmm7,(%rsp)
  movsd  D89(%rip),%xmm2
L17:
  addsd  %xmm2,%xmm1
  movsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L17
  movq   %rbx,%xmm4
  addsd  D11(%rip),%xmm4
  movsd  %xmm4,0x8(%rsp)
  movapd %xmm4,%xmm0
  call   <log@plt>
  movq   %xmm0,%r14
  movsd  (%rsp),%xmm5
  mulsd  D56(%rip),%xmm5
  movapd %xmm5,%xmm0
  movq   %rbx,%xmm7
  divsd  %xmm7,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm6
  addsd  D28(%rip),%xmm6
  movapd %xmm6,%xmm0
  movq   %r14,%xmm5
  mulsd  %xmm5,%xmm0
  subsd  0x8(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x58,%rsp
  pop    %rbx
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D47
type_infered: f64
name: parse_data
arguments: label: D97
type_infered: byte[8]
name: parse_data
arguments: label: D90
type_infered: f64
name: parse_data
arguments: label: D45
type_infered: byte[8]
name: parse_data
arguments: label: D50
type_infered: byte[8]
name: parse_data
arguments: label: D20
type_infered: byte[8]
name: parse_data
arguments: label: D72
type_infered: f64
name: parse_data
arguments: label: D89
type_infered: byte[8]
name: parse_data
arguments: label: D11
type_infered: f64
name: parse_data
arguments: label: D56
type_infered: f64
name: parse_data
arguments: label: D28
type_infered: f64

tool: D47: 76.18009172947146

tool: {"D97": [0x56,0x36,0x14,0x2b,0x57,0xa0,0x55,0xc0]}

tool: D90: 24.01409824083091

tool: {"D45": [0x8c,0xcc,0xcd,0x8d,0x34,0xb5,0xf3,0xbf]}

tool: {"D50": [0xd8,0x12,0xec,0x19,0x73,0xcd,0x53,0x3f]}

tool: {"D20": [0x88,0x98,0x0e,0x1c,0x18,0xa1,0xd6,0xbe]}

tool: D72: 1.000000000190015

tool: {"D89": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D11: 5.5

tool: D56: 2.5066282746310007

tool: D28: 0.5

assistant: ```c
double fff_gamln(double x) {
  double coeff[] = {76.18009172947146, -86.50532032941677, 24.01409824083091, -1.231739572450155, .1208650973866179e-2, -.5395239384953e-5};
  const double stp = 2.5066282746310005;
  double y = x;
  double sum = 1.000000000190015;
  double out;
  int i;
  for (i = 0; i < 6; i++) {
    y += 1;
    sum += coeff[i] / y;
  }
  out = x + 5.5;
  out = (x + 0.5) * log(out) - out;
  return out + log(stp * sum / x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fff_gamln>:
  endbr64
  sub    $0x68,%rsp
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm2
  movsd  D68(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D34(%rip),%rax
  lea    0x50(%rsp),%rdx
  movsd  D56(%rip),%xmm3
  movsd  D95(%rip),%xmm0
  mov    %rax,0x28(%rsp)
  mov    D29(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D32(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D30(%rip),%rax
  mov    %rax,0x40(%rsp)
  mov    D18(%rip),%rax
  mov    %rax,0x48(%rsp)
  lea    0x20(%rsp),%rax
  jmp    L26
L3:
  movsd  (%rax),%xmm1
L26:
  addsd  %xmm0,%xmm2
  add    $0x8,%rax
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm3
  cmp    %rdx,%rax
  jne    L3
  movapd %xmm4,%xmm1
  addsd  D1(%rip),%xmm1
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm4,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  mulsd  D103(%rip),%xmm3
  movsd  0x8(%rsp),%xmm4
  movsd  %xmm0,(%rsp)
  divsd  %xmm4,%xmm3
  movapd %xmm3,%xmm0
  call   <log@plt>
  movsd  0x8(%rsp),%xmm4
  addsd  D98(%rip),%xmm4
  mulsd  (%rsp),%xmm4
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x68,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D68
type_infered: f64
name: read_data
arguments: data_label: D34
type_infered: byte[8]
name: read_data
arguments: data_label: D56
type_infered: f64
name: read_data
arguments: data_label: D95
type_infered: byte[8]
name: read_data
arguments: data_label: D29
type_infered: f64
name: read_data
arguments: data_label: D32
type_infered: byte[8]
name: read_data
arguments: data_label: D30
type_infered: byte[8]
name: read_data
arguments: data_label: D18
type_infered: byte[8]
name: read_data
arguments: data_label: D1
type_infered: f64
name: read_data
arguments: data_label: D103
type_infered: f64
name: read_data
arguments: data_label: D98
type_infered: f64

tool: D68: 76.18009172947146

tool: {"D34": [0x56,0x36,0x14,0x2b,0x57,0xa0,0x55,0xc0]}

tool: D56: 1.000000000190015

tool: {"D95": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D29: 24.01409824083091

tool: {"D32": [0x8c,0xcc,0xcd,0x8d,0x34,0xb5,0xf3,0xbf]}

tool: {"D30": [0xd8,0x12,0xec,0x19,0x73,0xcd,0x53,0x3f]}

tool: {"D18": [0x88,0x98,0x0e,0x1c,0x18,0xa1,0xd6,0xbe]}

tool: D1: 5.5

tool: D103: 2.5066282746310007

tool: D98: 0.5

assistant: ```c
double fff_gamln(double x) {
  double coeff[] = {76.18009172947146, -86.50532032941677, 24.01409824083091, -1.231739572450155, .1208650973866179e-2, -.5395239384953e-5};
  const double stp = 2.5066282746310005;
  double y = x;
  double sum = 1.000000000190015;
  double out;
  int i;
  for (i = 0; i < 6; i++) {
    y += 1;
    sum += coeff[i] / y;
  }
  out = x + 5.5;
  out = (x + 0.5) * log(out) - out;
  return out + log(stp * sum / x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fff_gamln>:
  endbr64
  sub    $0x38,%rsp
  movsd  D15(%rip),%xmm3
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  movsd  D42(%rip),%xmm4
  movapd %xmm2,%xmm5
  movsd  D22(%rip),%xmm0
  movsd  %xmm2,0x20(%rsp)
  addsd  %xmm3,%xmm1
  addsd  D6(%rip),%xmm5
  divsd  %xmm1,%xmm4
  addsd  %xmm3,%xmm1
  movsd  %xmm5,0x18(%rsp)
  divsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm1
  addsd  D68(%rip),%xmm4
  addsd  %xmm4,%xmm0
  movsd  D60(%rip),%xmm4
  divsd  %xmm1,%xmm4
  addsd  %xmm3,%xmm1
  addsd  %xmm0,%xmm4
  movsd  D28(%rip),%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm1
  movsd  %xmm1,0x28(%rsp)
  addsd  %xmm4,%xmm0
  movsd  D106(%rip),%xmm4
  divsd  %xmm1,%xmm4
  addsd  %xmm0,%xmm4
  movapd %xmm5,%xmm0
  movsd  %xmm4,0x10(%rsp)
  call   <log@plt>
  mov    D15(%rip),%rax
  movsd  0x28(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movsd  D79(%rip),%xmm0
  movsd  0x20(%rsp),%xmm2
  movq   %rax,%xmm3
  addsd  %xmm3,%xmm1
  divsd  %xmm1,%xmm0
  addsd  0x10(%rsp),%xmm0
  mulsd  D111(%rip),%xmm0
  movsd  %xmm2,0x10(%rsp)
  divsd  %xmm2,%xmm0
  call   <log@plt>
  movsd  0x10(%rsp),%xmm2
  addsd  D92(%rip),%xmm2
  mulsd  0x8(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm4
  movapd %xmm0,%xmm1
  add    $0x38,%rsp
  subsd  %xmm4,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D42
type_guessed: f64
name: disassemble_data
arguments: data_tag: D22
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D6
type_guessed: f64
name: disassemble_data
arguments: data_tag: D68
type_guessed: f64
name: disassemble_data
arguments: data_tag: D60
type_guessed: f64
name: disassemble_data
arguments: data_tag: D28
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D106
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D79
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D111
type_guessed: f64
name: disassemble_data
arguments: data_tag: D92
type_guessed: f64

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D42: 76.18009172947146

tool: {"D22": [0x56,0x36,0x14,0x2b,0x57,0xa0,0x55,0xc0]}

tool: D6: 5.5

tool: D68: 1.000000000190015

tool: D60: 24.01409824083091

tool: {"D28": [0x8c,0xcc,0xcd,0x8d,0x34,0xb5,0xf3,0xbf]}

tool: {"D106": [0xd8,0x12,0xec,0x19,0x73,0xcd,0x53,0x3f]}

tool: {"D79": [0x88,0x98,0x0e,0x1c,0x18,0xa1,0xd6,0xbe]}

tool: D111: 2.5066282746310007

tool: D92: 0.5

assistant: ```c
double fff_gamln(double x) {
  double coeff[] = {76.18009172947146, -86.50532032941677, 24.01409824083091, -1.231739572450155, .1208650973866179e-2, -.5395239384953e-5};
  const double stp = 2.5066282746310005;
  double y = x;
  double sum = 1.000000000190015;
  double out;
  int i;
  for (i = 0; i < 6; i++) {
    y += 1;
    sum += coeff[i] / y;
  }
  out = x + 5.5;
  out = (x + 0.5) * log(out) - out;
  return out + log(stp * sum / x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Sys_MemAllocate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <memThrow@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *Sys_MemAllocate(unsigned bytes) {
  void *ret = malloc(bytes);
  memThrow(0 == ret);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Sys_MemAllocate>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <memThrow@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *Sys_MemAllocate(unsigned bytes) {
  void *ret = malloc(bytes);
  memThrow(0 == ret);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Sys_MemAllocate>:
  endbr64
  push   %r12
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  sete   %dil
  call   <memThrow@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *Sys_MemAllocate(unsigned bytes) {
  void *ret = malloc(bytes);
  memThrow(0 == ret);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Sys_MemAllocate>:
  endbr64
  push   %r12
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  sete   %dil
  call   <memThrow@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *Sys_MemAllocate(unsigned bytes) {
  void *ret = malloc(bytes);
  memThrow(0 == ret);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<s6test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L55
  orl    $0x1,-0x4(%rbp)
L55:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L33
  orl    $0x2,-0x4(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L12
  orl    $0x4,-0x4(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L20
  orl    $0x8,-0x4(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L9
  orl    $0x10,-0x4(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L10
  orl    $0x20,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int s6test(double s[6]) {
  int retval = 0;
  if (s[0] > 0.)
    retval |= 0x1;
  if (s[1] > 0.)
    retval |= 0x2;
  if (s[2] > 0.)
    retval |= 0x4;
  if (s[3] > 0.)
    retval |= 0x8;
  if (s[4] > 0.)
    retval |= 0x10;
  if (s[5] > 0.)
    retval |= 0x20;
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<s6test>:
  endbr64
  movsd  (%rdi),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  movsd  0x8(%rdi),%xmm1
  mov    %eax,%edx
  or     $0x2,%edx
  comisd %xmm0,%xmm1
  cmova  %edx,%eax
  movsd  0x10(%rdi),%xmm0
  mov    %eax,%edx
  or     $0x4,%edx
  comisd D5(%rip),%xmm0
  cmova  %edx,%eax
  movsd  0x18(%rdi),%xmm0
  mov    %eax,%edx
  or     $0x8,%edx
  comisd D5(%rip),%xmm0
  cmova  %edx,%eax
  movsd  0x20(%rdi),%xmm0
  mov    %eax,%edx
  or     $0x10,%edx
  comisd D5(%rip),%xmm0
  cmova  %edx,%eax
  movsd  0x28(%rdi),%xmm0
  mov    %eax,%edx
  or     $0x20,%edx
  comisd D5(%rip),%xmm0
  cmova  %edx,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: f64

tool: D5: 0

assistant: ```c
int s6test(double s[6]) {
  int retval = 0;
  if (s[0] > 0.)
    retval |= 0x1;
  if (s[1] > 0.)
    retval |= 0x2;
  if (s[2] > 0.)
    retval |= 0x4;
  if (s[3] > 0.)
    retval |= 0x8;
  if (s[4] > 0.)
    retval |= 0x10;
  if (s[5] > 0.)
    retval |= 0x20;
  return retval;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<s6test>:
  endbr64
  movsd  (%rdi),%xmm1
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm1
  seta   %al
  mov    %eax,%edx
  or     $0x2,%edx
  comisd %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm1
  cmova  %edx,%eax
  mov    %eax,%edx
  or     $0x4,%edx
  comisd %xmm0,%xmm1
  movsd  0x18(%rdi),%xmm1
  cmova  %edx,%eax
  mov    %eax,%edx
  or     $0x8,%edx
  comisd %xmm0,%xmm1
  movsd  0x20(%rdi),%xmm1
  cmova  %edx,%eax
  mov    %eax,%edx
  or     $0x10,%edx
  comisd %xmm0,%xmm1
  movsd  0x28(%rdi),%xmm1
  cmova  %edx,%eax
  mov    %eax,%edx
  or     $0x20,%edx
  comisd %xmm0,%xmm1
  cmova  %edx,%eax
  ret
```

assistant: ```c
int s6test(double s[6]) {
  int retval = 0;
  if (s[0] > 0.)
    retval |= 0x1;
  if (s[1] > 0.)
    retval |= 0x2;
  if (s[2] > 0.)
    retval |= 0x4;
  if (s[3] > 0.)
    retval |= 0x8;
  if (s[4] > 0.)
    retval |= 0x10;
  if (s[5] > 0.)
    retval |= 0x20;
  return retval;
}
```
user: What is the c source code of the assembly code below:

```asm
<s6test>:
  endbr64
  movsd  (%rdi),%xmm1
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm1
  seta   %al
  mov    %eax,%edx
  or     $0x2,%edx
  comisd %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm1
  cmova  %edx,%eax
  mov    %eax,%edx
  or     $0x4,%edx
  comisd %xmm0,%xmm1
  movsd  0x18(%rdi),%xmm1
  cmova  %edx,%eax
  mov    %eax,%edx
  or     $0x8,%edx
  comisd %xmm0,%xmm1
  movsd  0x20(%rdi),%xmm1
  cmova  %edx,%eax
  mov    %eax,%edx
  or     $0x10,%edx
  comisd %xmm0,%xmm1
  movsd  0x28(%rdi),%xmm1
  cmova  %edx,%eax
  mov    %eax,%edx
  or     $0x20,%edx
  comisd %xmm0,%xmm1
  cmova  %edx,%eax
  ret
```

assistant: ```c
int s6test(double s[6]) {
  int retval = 0;
  if (s[0] > 0.)
    retval |= 0x1;
  if (s[1] > 0.)
    retval |= 0x2;
  if (s[2] > 0.)
    retval |= 0x4;
  if (s[3] > 0.)
    retval |= 0x8;
  if (s[4] > 0.)
    retval |= 0x10;
  if (s[5] > 0.)
    retval |= 0x20;
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<load_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L4:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x3ff,-0x8(%rbp)
  jle    L4
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int load_range(double less_than_this[], int interval) {
  int i;
  int so_far = interval;
  for (i = 0; i < 1024; i++) {
    less_than_this[i] = so_far;
    so_far += interval;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<load_range>:
  endbr64
  mov    %rdi,%rax
  lea    0x2000(%rdi),%rcx
  mov    %esi,%edx
L1:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rax)
  add    %esi,%edx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L1
  mov    $0x400,%eax
  ret
```

assistant: ```c
int load_range(double less_than_this[], int interval) {
  int i;
  int so_far = interval;
  for (i = 0; i < 1024; i++) {
    less_than_this[i] = so_far;
    so_far += interval;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<load_range>:
  endbr64
  lea    0x2000(%rdi),%rdx
  mov    %esi,%eax
  nopl   (%rax)
L6:
  pxor   %xmm0,%xmm0
  add    $0x8,%rdi
  cvtsi2sd %eax,%xmm0
  add    %esi,%eax
  movsd  %xmm0,-0x8(%rdi)
  cmp    %rdx,%rdi
  jne    L6
  mov    $0x400,%eax
  ret
```

assistant: ```c
int load_range(double less_than_this[], int interval) {
  int i;
  int so_far = interval;
  for (i = 0; i < 1024; i++) {
    less_than_this[i] = so_far;
    so_far += interval;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<load_range>:
  endbr64
  lea    0x0(,%rsi,4),%eax
  movd   %esi,%xmm1
  movd   %eax,%xmm3
  lea    (%rsi,%rsi,1),%eax
  lea    (%rax,%rsi,1),%edx
  movd   %eax,%xmm4
  lea    0x2000(%rdi),%rax
  movd   %edx,%xmm0
  punpckldq %xmm4,%xmm1
  punpckldq %xmm3,%xmm0
  pshufd $0x0,%xmm3,%xmm3
  punpcklqdq %xmm0,%xmm1
  nopl   0x0(%rax)
L7:
  movdqa %xmm1,%xmm0
  add    $0x20,%rdi
  paddd  %xmm3,%xmm1
  cvtdq2pd %xmm0,%xmm2
  pshufd $0xee,%xmm0,%xmm0
  movups %xmm2,-0x20(%rdi)
  cvtdq2pd %xmm0,%xmm0
  movups %xmm0,-0x10(%rdi)
  cmp    %rdi,%rax
  jne    L7
  mov    $0x400,%eax
  ret
```

assistant: ```c
int load_range(double less_than_this[], int interval) {
  int i;
  int so_far = interval;
  for (i = 0; i < 1024; i++) {
    less_than_this[i] = so_far;
    so_far += interval;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stringtoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L14
L62:
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L62
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L28
  mov    $0xffffffff,%eax
  jmp    L4
L28:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L117
L34:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L68
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L41
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jge    L68
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L68
  mov    $0xffffffff,%eax
  jmp    L4
L41:
  mov    $0xffffffff,%eax
  jmp    L4
L68:
  addl   $0x1,-0xc(%rbp)
L117:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L34
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L4:
  leave
  ret
```

assistant: ```c
int stringtoint(char *str) {
  int i = 0;
  int lettreDebut = 0;
  int tailleChaine = strlen(str);
  while (isspace(str[lettreDebut])) {
    lettreDebut++;
  }
  if (lettreDebut == tailleChaine)
    return -1;
  for (i = lettreDebut; i < tailleChaine; i++) {
    if (!isdigit(str[i])) {
      if (isspace(str[i])) {
        if (i < tailleChaine - 1) {
          if (!isspace(str[i + 1])) {
            return -1;
          }
        }
      } else
        return -1;
    }
  }
  return atoi(str);
}
```