ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_for_help>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  lea    D13(%rip),%rdi
  sub    $0x8,%rsp
  call   <checkForOption@plt>
  test   %rax,%rax
  jne    L10
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  call   <checkForOption@plt>
  test   %rax,%rax
  je     L4
L10:
  xor    %eax,%eax
  call   <print_help@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
  nopl   0x0(%rax)
L4:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string

tool: D13: --help

tool: D18: -help

assistant: ```c
void check_for_help(int argc, char *argv[]) {
  if (checkForOption("--help", argc, argv) || checkForOption("-help", argc, argv)) {
    print_help();
    exit(1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_for_help>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  lea    D11(%rip),%rdi
  sub    $0x8,%rsp
  call   <checkForOption@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <checkForOption@plt>
  test   %rax,%rax
  je     L19
L13:
  xor    %eax,%eax
  call   <print_help@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
  nopl   0x0(%rax)
L19:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D9
datatype: string

tool: D11: --help

tool: D9: -help

assistant: ```c
void check_for_help(int argc, char *argv[]) {
  if (checkForOption("--help", argc, argv) || checkForOption("-help", argc, argv)) {
    print_help();
    exit(1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L7:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  leave
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  while (*dest++)
    ;
  return strcpy(dest, src);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcat>:
  endbr64
  sub    $0x8,%rsp
L3:
  add    $0x1,%rdi
  cmpb   $0x0,-0x1(%rdi)
  jne    L3
  call   <strcpy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  while (*dest++)
    ;
  return strcpy(dest, src);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcat>:
  endbr64
  nopl   0x0(%rax)
L7:
  add    $0x1,%rdi
  cmpb   $0x0,-0x1(%rdi)
  jne    L7
  jmp    1050 <strcpy@plt>
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  while (*dest++)
    ;
  return strcpy(dest, src);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcat>:
  endbr64
  nopl   0x0(%rax)
L8:
  add    $0x1,%rdi
  cmpb   $0x0,-0x1(%rdi)
  jne    L8
  jmp    1050 <strcpy@plt>
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  while (*dest++)
    ;
  return strcpy(dest, src);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_to_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L25
L42:
  cmpl   $0x0,-0x14(%rbp)
  je     L15
  movsd  -0x8(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L15:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L37
  movsd  -0x10(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L48
L37:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L36
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L48
L36:
  movl   $0x1,-0x14(%rbp)
L48:
  addq   $0x1,-0x28(%rbp)
L25:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: f32[2]
name: read_data
arguments: data_label: D19
datatype: f64

tool: {"D4": [0.0,1.875]}

tool: D19: 10

assistant: ```c
double str_to_double(char *str) {
  double digits = 0.0;
  double divide = 1.0f;
  int met_dot = 0;
  while (*str) {
    if (met_dot) {
      divide *= 10.0;
    }
    if (isdigit(*str)) {
      digits *= 10.0;
      digits += ((*str) - '0');
    } else if ((*str) == '.' || (*str) == ',') {
      met_dot = 1;
    }
    str++;
  }
  return digits / divide;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_to_double>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  mov    D4(%rip),%r12
  mov    D54(%rip),%rbp
  test   %dil,%dil
  je     L30
  mov    $0x0,%r13d
  mov    D54(%rip),%rbp
  mov    D4(%rip),%r12
  mov    $0x1,%r14d
  jmp    L26
L33:
  movzbl (%rbx),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  jne    L41
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L30
  mov    %r14d,%r13d
L18:
  movq   %r12,%xmm2
  mulsd  D29(%rip),%xmm2
  movq   %xmm2,%r12
L26:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L33
  movq   %rbp,%xmm0
  mulsd  D29(%rip),%xmm0
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rbp
L41:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L30
  test   %r13d,%r13d
  je     L26
  jmp    L18
L30:
  movq   %rbp,%xmm0
  movq   %r12,%xmm3
  divsd  %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: f32[2]
name: parse_data
arguments: data_label: D54
type_guessed: f32[2]
name: parse_data
arguments: data_label: D29
type_guessed: f64

tool: {"D4": [0.0,1.875]}

tool: {"D54": [0.0,0.0]}

tool: D29: 10

assistant: ```c
double str_to_double(char *str) {
  double digits = 0.0;
  double divide = 1.0f;
  int met_dot = 0;
  while (*str) {
    if (met_dot) {
      divide *= 10.0;
    }
    if (isdigit(*str)) {
      digits *= 10.0;
      digits += ((*str) - '0');
    } else if ((*str) == '.' || (*str) == ',') {
      met_dot = 1;
    }
    str++;
  }
  return digits / divide;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_to_double>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L65
  movsd  D28(%rip),%xmm6
  pxor   %xmm5,%xmm5
  xor    %ebp,%ebp
  movq   %xmm5,%r14
  movsd  %xmm6,0x8(%rsp)
L45:
  call   <isdigit@plt>
  test   %rax,%rax
  je     L12
L40:
  movsd  D1(%rip),%xmm0
  movsbl (%rbx),%eax
  movq   %r14,%xmm4
  pxor   %xmm1,%xmm1
  mulsd  %xmm4,%xmm0
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movq   %xmm1,%r14
L26:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L19
  test   %ebp,%ebp
  je     L45
L47:
  movsd  D1(%rip),%xmm2
  mulsd  0x8(%rsp),%xmm2
  mov    $0x1,%ebp
  movsd  %xmm2,0x8(%rsp)
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L40
L12:
  movzbl (%rbx),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  jne    L26
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L47
L19:
  movq   %r14,%xmm0
  divsd  0x8(%rsp),%xmm0
L65:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type: f32[2]
name: extract_symbolic_data
arguments: label: D1
type: f64

tool: {"D28": [0.0,1.875]}

tool: D1: 10

assistant: ```c
double str_to_double(char *str) {
  double digits = 0.0;
  double divide = 1.0f;
  int met_dot = 0;
  while (*str) {
    if (met_dot) {
      divide *= 10.0;
    }
    if (isdigit(*str)) {
      digits *= 10.0;
      digits += ((*str) - '0');
    } else if ((*str) == '.' || (*str) == ',') {
      met_dot = 1;
    }
    str++;
  }
  return digits / divide;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_to_double>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L23
  movsd  D16(%rip),%xmm6
  pxor   %xmm5,%xmm5
  xor    %ebp,%ebp
  movq   %xmm5,%r14
  movsd  %xmm6,0x8(%rsp)
L53:
  call   <isdigit@plt>
  test   %rax,%rax
  je     L4
L16:
  movsd  D6(%rip),%xmm0
  movsbl (%rbx),%eax
  movq   %r14,%xmm4
  pxor   %xmm1,%xmm1
  mulsd  %xmm4,%xmm0
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movq   %xmm1,%r14
L31:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L29
  test   %ebp,%ebp
  je     L53
L65:
  movsd  D6(%rip),%xmm2
  mulsd  0x8(%rsp),%xmm2
  mov    $0x1,%ebp
  movsd  %xmm2,0x8(%rsp)
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L16
L4:
  movzbl (%rbx),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  jne    L31
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L65
L29:
  movq   %r14,%xmm0
  divsd  0x8(%rsp),%xmm0
L23:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_guessed: f32[2]
name: disassemble_data
arguments: data_tag: D6
type_guessed: f64

tool: {"D16": [0.0,1.875]}

tool: D6: 10

assistant: ```c
double str_to_double(char *str) {
  double digits = 0.0;
  double divide = 1.0f;
  int met_dot = 0;
  while (*str) {
    if (met_dot) {
      divide *= 10.0;
    }
    if (isdigit(*str)) {
      digits *= 10.0;
      digits += ((*str) - '0');
    } else if ((*str) == '.' || (*str) == ',') {
      met_dot = 1;
    }
    str++;
  }
  return digits / divide;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *t_fun(void *arg) {
  f();
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<t_fun>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *t_fun(void *arg) {
  f();
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<t_fun>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *t_fun(void *arg) {
  f();
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<t_fun>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *t_fun(void *arg) {
  f();
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_valid_stuff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: The serial number is valid!


assistant: ```c
int do_valid_stuff() {
  printf("The serial number is valid!\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_valid_stuff>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: The serial number is valid!


assistant: ```c
int do_valid_stuff() {
  printf("The serial number is valid!\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_valid_stuff>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5: The serial number is valid!


assistant: ```c
int do_valid_stuff() {
  printf("The serial number is valid!\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_valid_stuff>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: The serial number is valid!


assistant: ```c
int do_valid_stuff() {
  printf("The serial number is valid!\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_to_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L9
L7:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x28(%rbp)
  mov    %rdx,%rax
  mov    %rax,(%rcx)
  mov    -0x30(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x28(%rbp)
  mov    %rax,-0x30(%rbp)
  subq   $0x1,-0x8(%rbp)
  jmp    L1
L9:
  pop    %rbp
  ret
```

assistant: ```c
bool convert_to_base(uint8_t *digits, uint8_t numdigits, uint8_t base, uint64_t value) {
  int32_t i;
  if (base == 0)
    return false;
  for (i = numdigits - 1; i >= 0; i--) {
    digits[i] = value % base;
    value = value / base;
  }
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<convert_to_base>:
  endbr64
  mov    %rdx,%r8
  mov    %rcx,%rax
  lea    -0x8(%rdi,%rsi,8),%rcx
  test   %rdx,%rdx
  je     L14
L3:
  mov    $0x0,%edx
  div    %r8
  mov    %rdx,(%rcx)
  sub    $0x8,%rcx
  jmp    L3
L14:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool convert_to_base(uint8_t *digits, uint8_t numdigits, uint8_t base, uint64_t value) {
  int32_t i;
  if (base == 0)
    return false;
  for (i = numdigits - 1; i >= 0; i--) {
    digits[i] = value % base;
    value = value / base;
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_to_base>:
  endbr64
  mov    %rcx,%rax
  mov    %rdx,%r8
  lea    -0x8(%rdi,%rsi,8),%rcx
  test   %rdx,%rdx
  je     L14
  nopl   0x0(%rax)
L13:
  xor    %edx,%edx
  sub    $0x8,%rcx
  div    %r8
  mov    %rdx,0x8(%rcx)
  jmp    L13
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool convert_to_base(uint8_t *digits, uint8_t numdigits, uint8_t base, uint64_t value) {
  int32_t i;
  if (base == 0)
    return false;
  for (i = numdigits - 1; i >= 0; i--) {
    digits[i] = value % base;
    value = value / base;
  }
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_to_base>:
  endbr64
  mov    %rcx,%rax
  mov    %rdx,%r8
  lea    -0x8(%rdi,%rsi,8),%rcx
  test   %rdx,%rdx
  je     L17
  nopl   0x0(%rax)
L8:
  xor    %edx,%edx
  sub    $0x8,%rcx
  div    %r8
  mov    %rdx,0x8(%rcx)
  jmp    L8
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool convert_to_base(uint8_t *digits, uint8_t numdigits, uint8_t base, uint64_t value) {
  int32_t i;
  if (base == 0)
    return false;
  for (i = numdigits - 1; i >= 0; i--) {
    digits[i] = value % base;
    value = value / base;
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hashname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hashname(char *name) {
  int val = 0;
  int i = 1;
  while (*name != 0) {
    val += (*name) * i;
    i++;
    name++;
  }
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashname>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  mov    %rdi,%rdx
  mov    $0x0,%esi
  mov    $0x1,%r8d
  sub    %edi,%r8d
L13:
  lea    (%r8,%rdx,1),%ecx
  movsbl %al,%eax
  imul   %ecx,%eax
  add    %eax,%esi
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L13
L22:
  mov    %esi,%eax
  ret
L5:
  mov    $0x0,%esi
  jmp    L22
```

assistant: ```c
int hashname(char *name) {
  int val = 0;
  int i = 1;
  while (*name != 0) {
    val += (*name) * i;
    i++;
    name++;
  }
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hashname>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L11
  mov    $0x1,%ecx
  sub    %edi,%ecx
  nopl   (%rax)
L3:
  lea    (%rcx,%rdi,1),%edx
  add    $0x1,%rdi
  imul   %edx,%eax
  add    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L3
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hashname(char *name) {
  int val = 0;
  int i = 1;
  while (*name != 0) {
    val += (*name) * i;
    i++;
    name++;
  }
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<hashname>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L18
  mov    $0x1,%ecx
  sub    %edi,%ecx
  nopl   (%rax)
L7:
  lea    (%rcx,%rdi,1),%edx
  add    $0x1,%rdi
  imul   %edx,%eax
  add    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L7
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hashname(char *name) {
  int val = 0;
  int i = 1;
  while (*name != 0) {
    val += (*name) * i;
    i++;
    name++;
  }
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<findPossibleValues>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdi,%r10
  mov    %rsi,%r9
  mov    %edx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edx,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  lea    (%rdx,%rdx,8),%ecx
  mov    %r8d,%edx
  sub    %ecx,%edx
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%rdi,%rax,4),%rsi
  movslq %edx,%rax
  mov    (%rsi,%rax,4),%edi
  test   %edi,%edi
  jne    L69
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0x9,0x24(%rsp)
  mov    %rsi,%rax
  add    $0x24,%rsi
L57:
  movslq (%rax),%rcx
  movl   $0x0,(%rsp,%rcx,4)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L57
  movslq %edx,%rcx
  shl    $0x2,%rcx
  lea    (%r10,%rcx,1),%rax
  lea    0x144(%r10,%rcx,1),%rsi
L8:
  movslq (%rax),%rcx
  movl   $0x0,(%rsp,%rcx,4)
  add    $0x24,%rax
  cmp    %rsi,%rax
  jne    L8
  movslq %r8d,%rax
  imul   $0x4bda12f7,%rax,%rax
  sar    $0x23,%rax
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%eax
  cltq
  lea    (%rax,%rax,8),%rcx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cltq
  lea    (%rcx,%rax,1),%rdx
  shl    $0x2,%rdx
  lea    (%r10,%rdx,1),%rax
  lea    0x6c(%r10,%rdx,1),%rcx
L67:
  movslq (%rax),%rdx
  movl   $0x0,(%rsp,%rdx,4)
  movslq 0x4(%rax),%rdx
  movl   $0x0,(%rsp,%rdx,4)
  movslq 0x8(%rax),%rdx
  movl   $0x0,(%rsp,%rdx,4)
  add    $0x24,%rax
  cmp    %rcx,%rax
  jne    L67
  lea    0x4(%rsp),%rax
  lea    0x28(%rsp),%rcx
  jmp    L63
L46:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L82
L63:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L46
  movslq %edi,%rsi
  mov    %edx,(%r9,%rsi,4)
  add    $0x1,%edi
  jmp    L46
L69:
  mov    $0x0,%edi
L82:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %edi,%eax
  add    $0x38,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findPossibleValues(int S[][9], int A[], int cell_val) {
  int R = cell_val / 9;
  int C = cell_val % 9;
  int count = 0;
  if (S[R][C] != 0) {
    return count;
  }
  int tmp[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
  int i, j, tmp2;
  for (i = 0; i < 9; ++i) {
    tmp2 = S[R][i];
    tmp[tmp2] = 0;
  }
  for (i = 0; i < 9; ++i) {
    tmp2 = S[i][C];
    tmp[tmp2] = 0;
  }
  int BLK_R = (cell_val / 9 / 3) * 3;
  int BLK_C = (cell_val % 9 / 3) * 3;
  for (i = BLK_R; i < BLK_R + 3; ++i) {
    for (j = BLK_C; j < BLK_C + 3; ++j) {
      tmp2 = S[i][j];
      tmp[tmp2] = 0;
    }
  }
  for (i = 1; i < 10; i++) {
    if (tmp[i] != 0) {
      A[count] = tmp[i];
      ++count;
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findPossibleValues>:
  endbr64
  push   %rbx
  movslq %edx,%r11
  mov    %rdi,%r10
  imul   $0x38e38e39,%r11,%rcx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %r11d,%eax
  sar    $0x21,%rcx
  sar    $0x1f,%eax
  sub    %eax,%ecx
  movslq %ecx,%rax
  mov    %r11d,%ecx
  lea    (%rax,%rax,8),%edx
  lea    (%rax,%rax,8),%rax
  sub    %edx,%ecx
  lea    (%rdi,%rax,4),%rax
  movslq %ecx,%rdi
  mov    (%rax,%rdi,4),%r8d
  test   %r8d,%r8d
  jne    L31
  movabs $0x300000002,%rbx
  movl   $0x1,0x4(%rsp)
  mov    %rsi,%r9
  mov    %r11,%rsi
  mov    %rbx,0x8(%rsp)
  movabs $0x500000004,%rbx
  mov    %rbx,0x10(%rsp)
  movabs $0x700000006,%rbx
  mov    %rbx,0x18(%rsp)
  movabs $0x900000008,%rbx
  mov    %rbx,0x20(%rsp)
  lea    0x24(%rax),%rbx
  nopl   0x0(%rax,%rax,1)
L47:
  movslq (%rax),%rdx
  add    $0x4,%rax
  movl   $0x0,(%rsp,%rdx,4)
  cmp    %rbx,%rax
  jne    L47
  lea    0x0(,%rdi,4),%rdx
  lea    (%r10,%rdx,1),%rax
  lea    0x144(%r10,%rdx,1),%rbx
  nop
L11:
  movslq (%rax),%rdx
  add    $0x24,%rax
  movl   $0x0,(%rsp,%rdx,4)
  cmp    %rbx,%rax
  jne    L11
  imul   $0x4bda12f7,%r11,%r11
  sar    $0x1f,%esi
  sar    $0x1f,%ecx
  imul   $0x55555556,%rdi,%rdi
  sar    $0x23,%r11
  sub    %esi,%r11d
  shr    $0x20,%rdi
  lea    (%r11,%r11,2),%eax
  sub    %ecx,%edi
  cltq
  lea    (%rax,%rax,8),%rdx
  lea    (%rdi,%rdi,2),%eax
  cltq
  add    %rax,%rdx
  shl    $0x2,%rdx
  lea    (%r10,%rdx,1),%rax
  lea    0x6c(%r10,%rdx,1),%rcx
L7:
  movslq (%rax),%rdx
  add    $0x24,%rax
  movl   $0x0,(%rsp,%rdx,4)
  movslq -0x20(%rax),%rdx
  movl   $0x0,(%rsp,%rdx,4)
  movslq -0x1c(%rax),%rdx
  movl   $0x0,(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L7
  lea    0x4(%rsp),%rax
  lea    0x28(%rsp),%rcx
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L61
  movslq %r8d,%rsi
  add    $0x1,%r8d
  mov    %edx,(%r9,%rsi,4)
L61:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L17
L65:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x30,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %r8d,%r8d
  jmp    L65
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findPossibleValues(int S[][9], int A[], int cell_val) {
  int R = cell_val / 9;
  int C = cell_val % 9;
  int count = 0;
  if (S[R][C] != 0) {
    return count;
  }
  int tmp[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
  int i, j, tmp2;
  for (i = 0; i < 9; ++i) {
    tmp2 = S[R][i];
    tmp[tmp2] = 0;
  }
  for (i = 0; i < 9; ++i) {
    tmp2 = S[i][C];
    tmp[tmp2] = 0;
  }
  int BLK_R = (cell_val / 9 / 3) * 3;
  int BLK_C = (cell_val % 9 / 3) * 3;
  for (i = BLK_R; i < BLK_R + 3; ++i) {
    for (j = BLK_C; j < BLK_C + 3; ++j) {
      tmp2 = S[i][j];
      tmp[tmp2] = 0;
    }
  }
  for (i = 1; i < 10; i++) {
    if (tmp[i] != 0) {
      A[count] = tmp[i];
      ++count;
    }
  }
  return count;
}
```