ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <h_world@plt>
  mov    $0x0,%eax
  call   <g_world@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  h_world();
  g_world();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <h_world@plt>
  xor    %eax,%eax
  call   <g_world@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  h_world();
  g_world();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <h_world@plt>
  xor    %eax,%eax
  call   <g_world@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  h_world();
  g_world();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<runForLoop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
data_type: string
name: retrieve_data
arguments: data_tag: D29
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string

tool: D21: For loop to %d [ 

tool: D29: %d 

tool: D11: ]

assistant: ```c
void runForLoop(int limit) {
  printf("For loop to %d [ ", limit);
  for (int i = 0; i < limit; i++) {
    printf("%d ", i);
  }
  printf("]\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<runForLoop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %edi,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L10
  mov    $0x0,%ebx
  lea    D13(%rip),%r12
L3:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L3
L10:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D26
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string

tool: D26: For loop to %d [ 

tool: D13: %d 

tool: D27: ]

assistant: ```c
void runForLoop(int limit) {
  printf("For loop to %d [ ", limit);
  for (int i = 0; i < limit; i++) {
    printf("%d ", i);
  }
  printf("]\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<runForLoop>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  lea    D6(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L0
  xor    %ebx,%ebx
  lea    D13(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L7
L0:
  pop    %rbx
  lea    D25(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D25
datatype: string

tool: D6: For loop to %d [ 

tool: D13: %d 

tool: D25: ]

assistant: ```c
void runForLoop(int limit) {
  printf("For loop to %d [ ", limit);
  for (int i = 0; i < limit; i++) {
    printf("%d ", i);
  }
  printf("]\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<runForLoop>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  lea    D26(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L14
  xor    %ebx,%ebx
  lea    D24(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L5
L14:
  pop    %rbx
  lea    D3(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
type: string
name: disassemble_data
arguments: data_tag: D24
type: string
name: disassemble_data
arguments: data_tag: D3
type: string

tool: D26: For loop to %d [ 

tool: D24: %d 

tool: D3: ]

assistant: ```c
void runForLoop(int limit) {
  printf("For loop to %d [ ", limit);
  for (int i = 0; i < limit; i++) {
    printf("%d ", i);
  }
  printf("]\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  subl   $0x1,-0x1c(%rbp)
  jmp    L9
L1:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  subl   $0x1,-0x1c(%rbp)
L9:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count(int x[], int n) {
  int c;
  c = 0;
  n = n - 1;
  while (n >= 0) {
    c = c + x[n];
    n = n - 1;
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count>:
  endbr64
  sub    $0x1,%esi
  js     L0
  movslq %esi,%rsi
  mov    $0x0,%eax
L1:
  add    (%rdi,%rsi,4),%eax
  sub    $0x1,%rsi
  test   %esi,%esi
  jns    L1
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int count(int x[], int n) {
  int c;
  c = 0;
  n = n - 1;
  while (n >= 0) {
    c = c + x[n];
    n = n - 1;
  }
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count>:
  endbr64
  sub    $0x1,%esi
  js     L18
  movslq %esi,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L8:
  add    (%rdi,%rsi,4),%eax
  sub    $0x1,%rsi
  test   %esi,%esi
  jns    L8
  ret
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int count(int x[], int n) {
  int c;
  c = 0;
  n = n - 1;
  while (n >= 0) {
    c = c + x[n];
    n = n - 1;
  }
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<count>:
  endbr64
  mov    %esi,%r8d
  mov    %rdi,%rcx
  sub    $0x1,%r8d
  js     L6
  cmp    $0x2,%r8d
  jbe    L77
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  lea    -0x10(%rdi,%rax,4),%rdx
  mov    %esi,%edi
  shr    $0x2,%edi
  lea    -0x10(%rdx),%rax
  lea    -0x1(%rdi),%r9d
  mov    %rax,%rdi
  shl    $0x4,%r9
  sub    %r9,%rdi
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L11:
  sub    $0x10,%rax
L10:
  movdqu (%rdx),%xmm1
  mov    %rax,%rdx
  pshufd $0x1b,%xmm1,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L11
  movdqa %xmm0,%xmm1
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  sub    %edx,%r8d
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%esi
  je     L39
L59:
  movslq %r8d,%rdx
  lea    0x0(,%rdx,4),%rsi
  add    (%rcx,%rdx,4),%eax
  test   %r8d,%r8d
  je     L15
  add    -0x4(%rcx,%rsi,1),%eax
  cmp    $0x1,%r8d
  je     L15
  add    -0x8(%rcx,%rsi,1),%eax
  ret
  nopl   (%rax)
L6:
  xor    %eax,%eax
L15:
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  ret
L77:
  xor    %eax,%eax
  jmp    L59
```

assistant: ```c
int count(int x[], int n) {
  int c;
  c = 0;
  n = n - 1;
  while (n >= 0) {
    c = c + x[n];
    n = n - 1;
  }
  return c;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L61:
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  cmp    $0x2,%eax
  je     L41
  cmp    $0x2,%eax
  jg     L72
  test   %eax,%eax
  je     L68
  cmp    $0x1,%eax
  jne    L72
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <LinSearch@plt>
  jmp    L21
L41:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <BinSearch@plt>
  jmp    L21
L72:
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L68:
  nop
L21:
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jne    L61
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D85
datatype: string
name: parse_data
arguments: label: D75
datatype: string
name: parse_data
arguments: label: D79
datatype: string
name: parse_data
arguments: label: D20
datatype: string
name: parse_data
arguments: label: D80
datatype: string
name: parse_data
arguments: label: D36
datatype: string
name: parse_data
arguments: label: D95
datatype: string

tool: D85: 1. Linear Search


tool: D75: 2. Binary Search


tool: D79: 0. Exit


tool: D20: Enter Input: 

tool: D80: %d

tool: D36: Enter Number to Search: 

tool: D95: Invalid Input. Try Again.


assistant: ```c
int main() {
  int n;
  do {
    int A[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
    int num;
    printf("1. Linear Search\n");
    printf("2. Binary Search\n");
    printf("0. Exit\n");
    printf("Enter Input: ");
    scanf("%d", &n);
    switch (n) {
    case 1:
      printf("Enter Number to Search: ");
      scanf("%d", &num);
      LinSearch(A, 10, num);
      break;
    case 2:
      printf("Enter Number to Search: ");
      scanf("%d", &num);
      BinSearch(A, 10, num);
      break;
    case 0:
      break;
    default:
      printf("Invalid Input. Try Again.\n");
    }
  } while (n != 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%r13
  lea    D84(%rip),%r12
  lea    D67(%rip),%rbp
  lea    D15(%rip),%rbx
  jmp    L43
L36:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%edx
  mov    $0xa,%esi
  call   <LinSearch@plt>
L4:
  cmpl   $0x0,0x8(%rsp)
  je     L13
L43:
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x4,0x1c(%rsp)
  movl   $0x5,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  movl   $0x7,0x28(%rsp)
  movl   $0x8,0x2c(%rsp)
  movl   $0x9,0x30(%rsp)
  movl   $0xa,0x34(%rsp)
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x1,%eax
  je     L36
  cmp    $0x2,%eax
  je     L49
  test   %eax,%eax
  je     L4
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L49:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%edx
  mov    $0xa,%esi
  call   <BinSearch@plt>
  jmp    L4
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
type_guessed: string
name: retrieve_data
arguments: tag: D84
type_guessed: string
name: retrieve_data
arguments: tag: D67
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D32
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D24: 1. Linear Search


tool: D84: 2. Binary Search


tool: D67: 0. Exit


tool: D15: Enter Input: 

tool: D12: Enter Number to Search: 

tool: D32: %d

tool: D9: Invalid Input. Try Again.


assistant: ```c
int main() {
  int n;
  do {
    int A[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
    int num;
    printf("1. Linear Search\n");
    printf("2. Binary Search\n");
    printf("0. Exit\n");
    printf("Enter Input: ");
    scanf("%d", &n);
    switch (n) {
    case 1:
      printf("Enter Number to Search: ");
      scanf("%d", &num);
      LinSearch(A, 10, num);
      break;
    case 2:
      printf("Enter Number to Search: ");
      scanf("%d", &num);
      BinSearch(A, 10, num);
      break;
    case 0:
      break;
    default:
      printf("Invalid Input. Try Again.\n");
    }
  } while (n != 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x18(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L8
L5:
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%esi
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <clnt_create@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <clnt_destroy@plt>
  addl   $0x1,-0x28(%rbp)
  addl   $0x1,-0x24(%rbp)
L8:
  mov    -0x24(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  cmpl   $0x1,-0x20(%rbp)
  jne    L18
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  mov    -0x28(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D28
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string

tool: D12: tcp

tool: D28: Aimed : %d


tool: D0: Got : %d


tool: D8: %d


assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int progNum = atoi(argc[2]);
  char *proto = "tcp";
  CLIENT *clnt = NULL;
  int nbCall = atoi(argc[3]);
  int nbOk = 0;
  int i;
  for (i = 0; i < nbCall; i++) {
    clnt = clnt_create(argc[1], progNum, 1, proto);
    clnt_destroy(clnt);
    nbOk++;
  }
  if (run_mode == 1) {
    printf("Aimed : %d\n", nbCall);
    printf("Got : %d\n", nbOk);
  }
  test_status = (nbOk == nbCall) ? 0 : 1;
  printf("%d\n", test_status);
  return test_status;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  mov    0x18(%r12),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L28
  mov    $0x0,%ebx
  lea    D0(%rip),%r14
L1:
  mov    0x8(%r12),%rdi
  mov    %r14,%rcx
  mov    $0x1,%edx
  mov    %r13d,%esi
  call   <clnt_create@plt>
  mov    %rax,%rdi
  call   <clnt_destroy@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L1
  mov    %ebp,%eax
L16:
  cmp    %eax,%ebp
  setne  %bl
  movzbl %bl,%ebx
  mov    %ebx,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  mov    $0x0,%eax
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D15
type_infered: string

tool: D0: tcp

tool: D15: %d


assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int progNum = atoi(argc[2]);
  char *proto = "tcp";
  CLIENT *clnt = NULL;
  int nbCall = atoi(argc[3]);
  int nbOk = 0;
  int i;
  for (i = 0; i < nbCall; i++) {
    clnt = clnt_create(argc[1], progNum, 1, proto);
    clnt_destroy(clnt);
    nbOk++;
  }
  if (run_mode == 1) {
    printf("Aimed : %d\n", nbCall);
    printf("Got : %d\n", nbOk);
  }
  test_status = (nbOk == nbCall) ? 0 : 1;
  printf("%d\n", test_status);
  return test_status;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    0x18(%r14),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L1
  xor    %ebx,%ebx
  lea    D13(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L19:
  mov    0x8(%r14),%rdi
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    %r12d,%esi
  add    $0x1,%ebx
  call   <clnt_create@plt>
  mov    %rax,%rdi
  call   <clnt_destroy@plt>
  cmp    %ebx,%ebp
  jne    L19
  mov    %ebp,%eax
L8:
  xor    %r12d,%r12d
  cmp    %eax,%ebp
  lea    D2(%rip),%rdi
  setne  %r12b
  mov    %r12d,%esi
  call   <printf@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  xor    %eax,%eax
  jmp    L8
```

tool_calls: name: unpack_data
arguments: tag: D13
type_infered: string
name: unpack_data
arguments: tag: D2
type_infered: string

tool: D13: tcp

tool: D2: %d


assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int progNum = atoi(argc[2]);
  char *proto = "tcp";
  CLIENT *clnt = NULL;
  int nbCall = atoi(argc[3]);
  int nbOk = 0;
  int i;
  for (i = 0; i < nbCall; i++) {
    clnt = clnt_create(argc[1], progNum, 1, proto);
    clnt_destroy(clnt);
    nbOk++;
  }
  if (run_mode == 1) {
    printf("Aimed : %d\n", nbCall);
    printf("Got : %d\n", nbOk);
  }
  test_status = (nbOk == nbCall) ? 0 : 1;
  printf("%d\n", test_status);
  return test_status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    0x18(%r14),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L5
  xor    %ebx,%ebx
  lea    D10(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L26:
  mov    0x8(%r14),%rdi
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    %r12d,%esi
  add    $0x1,%ebx
  call   <clnt_create@plt>
  mov    %rax,%rdi
  call   <clnt_destroy@plt>
  cmp    %ebx,%ebp
  jne    L26
  mov    %ebp,%eax
L13:
  xor    %r12d,%r12d
  cmp    %eax,%ebp
  lea    D17(%rip),%rdi
  setne  %r12b
  mov    %r12d,%esi
  call   <printf@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  xor    %eax,%eax
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string

tool: D10: tcp

tool: D17: %d


assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int progNum = atoi(argc[2]);
  char *proto = "tcp";
  CLIENT *clnt = NULL;
  int nbCall = atoi(argc[3]);
  int nbOk = 0;
  int i;
  for (i = 0; i < nbCall; i++) {
    clnt = clnt_create(argc[1], progNum, 1, proto);
    clnt_destroy(clnt);
    nbOk++;
  }
  if (run_mode == 1) {
    printf("Aimed : %d\n", nbCall);
    printf("Got : %d\n", nbOk);
  }
  test_status = (nbOk == nbCall) ? 0 : 1;
  printf("%d\n", test_status);
  return test_status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: Hello World

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("Hello World");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: Hello World

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("Hello World");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: Hello World

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("Hello World");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: Hello World

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("Hello World");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <fib@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D21
datatype: string
name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D3
datatype: string

tool: D21: Input number: 

tool: D15: %d

tool: D3: fibonacci(%d) = %d


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int g3;
  int local0;
  printf("Input number: ");
  scanf("%d", &local0);
  g3 = fib(local0);
  printf("fibonacci(%d) = %d\n", local0, g3);
  return 0;
}
```