ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2d,(%rsp)
  movl   $0x43,0x4(%rsp)
  movl   $0x5d,0x8(%rsp)
  movl   $0x38,0xc(%rsp)
  movl   $0x19,0x10(%rsp)
  movl   $0x49,0x14(%rsp)
  movl   $0x30,0x18(%rsp)
  movl   $0x22,0x1c(%rsp)
  movl   $0x37,0x20(%rsp)
  movl   $0x58,0x24(%rsp)
  pxor   %xmm0,%xmm0
  mov    %rsp,%rax
  lea    0x28(%rsp),%rdx
L24:
  add    $0x4,%rax
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rax),%xmm1
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L24
  divss  D0(%rip),%xmm0
  mov    $0x0,%esi
  mov    %rsp,%rax
  lea    0x28(%rsp),%rcx
L29:
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rax),%xmm1
  comiss %xmm0,%xmm1
  seta   %dl
  movzbl %dl,%edx
  add    %edx,%esi
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L29
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: byte[4]
name: unpack_data
arguments: data_label: D13
datatype: string

tool: {"D0": [0x00,0x00,0x20,0x41]}

tool: D13: %d

assistant: ```c
int main() {
  int a[10] = {45, 67, 93, 56, 25, 73, 48, 34, 55, 88}, *p, n = 0;
  float aver = 0;
  for (p = a; p < a + 10; aver += *p++)
    ;
  for (aver /= 10, p = a; p < a + 10; p++)
    if (*p > aver)
      n++;
  printf("%d", n);
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x2d,%esi
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x430000002d,%rax
  lea    0x28(%rsp),%rcx
  mov    %rax,(%rsp)
  movabs $0x380000005d,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x4900000019,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x2200000030,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x5800000037,%rax
  mov    %rax,0x20(%rsp)
  mov    %rsp,%rax
  mov    %rax,%rdx
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    (%rdx),%esi
L40:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdx
  cvtsi2ss %esi,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rcx,%rdx
  jne    L12
  mov    $0x2d,%edx
  xor    %esi,%esi
  divss  D1(%rip),%xmm0
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L37:
  mov    (%rax),%edx
L4:
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  xor    %edx,%edx
  comiss %xmm0,%xmm1
  seta   %dl
  add    $0x4,%rax
  add    %edx,%esi
  cmp    %rcx,%rax
  jne    L37
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: byte[4]
name: read_data
arguments: tag: D5
type_guessed: string

tool: {"D1": [0x00,0x00,0x20,0x41]}

tool: D5: %d

assistant: ```c
int main() {
  int a[10] = {45, 67, 93, 56, 25, 73, 48, 34, 55, 88}, *p, n = 0;
  float aver = 0;
  for (p = a; p < a + 10; aver += *p++)
    ;
  for (aver /= 10, p = a; p < a + 10; p++)
    if (*p > aver)
      n++;
  printf("%d", n);
  getchar();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: %d

assistant: ```c
int main() {
  int a[10] = {45, 67, 93, 56, 25, 73, 48, 34, 55, 88}, *p, n = 0;
  float aver = 0;
  for (p = a; p < a + 10; aver += *p++)
    ;
  for (aver /= 10, p = a; p < a + 10; p++)
    if (*p > aver)
      n++;
  printf("%d", n);
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L6
L15:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L18
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L6
L18:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L6:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0xa,-0x1(%rbp)
  jne    L15
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char ch;
  while ((ch = getchar()) != '\n') {
    if (isalpha(ch))
      putchar(ch + 1);
    else
      putchar(ch);
  }
  putchar(ch);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L12
L13:
  mov    %ebp,%edi
  call   <putchar@plt>
L12:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%al
  je     L21
  movsbl %bl,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L13
  lea    0x1(%rbx),%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L12
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  char ch;
  while ((ch = getchar()) != '\n') {
    if (isalpha(ch))
      putchar(ch + 1);
    else
      putchar(ch);
  }
  putchar(ch);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%al
  je     L33
L31:
  movsbl %bl,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L21
  lea    0x1(%rbx),%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%al
  jne    L31
L33:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %ebp,%edi
  call   <putchar@plt>
  jmp    L23
```

assistant: ```c
int main(void) {
  char ch;
  while ((ch = getchar()) != '\n') {
    if (isalpha(ch))
      putchar(ch + 1);
    else
      putchar(ch);
  }
  putchar(ch);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%al
  je     L1
L3:
  movsbl %bl,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L33
  lea    0x1(%rbx),%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%al
  jne    L3
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %ebp,%edi
  call   <putchar@plt>
  jmp    L22
```

assistant: ```c
int main(void) {
  char ch;
  while ((ch = getchar()) != '\n') {
    if (isalpha(ch))
      putchar(ch + 1);
    else
      putchar(ch);
  }
  putchar(ch);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L0
L9:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
char *strdup(const char *str) {
  char *sp = malloc(strlen(str) + 1);
  if (sp == NULL) {
    return NULL;
  }
  strcpy(sp, str);
  return sp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strdup(const char *str) {
  char *sp = malloc(strlen(str) + 1);
  if (sp == NULL) {
    return NULL;
  }
  strcpy(sp, str);
  return sp;
}
```
user: What is the c source code of the assembly code below:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *str) {
  char *sp = malloc(strlen(str) + 1);
  if (sp == NULL) {
    return NULL;
  }
  strcpy(sp, str);
  return sp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *str) {
  char *sp = malloc(strlen(str) + 1);
  if (sp == NULL) {
    return NULL;
  }
  strcpy(sp, str);
  return sp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<b_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L8
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <error@plt>
  jmp    L19
L8:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  mov    $0x31,%edi
  call   <error@plt>
L19:
  leave
  ret
```

assistant: ```c
int b_time(int argc, char *argv[]) {
  if (argc > 1)
    return error(1, argv[0]);
  return error(49, argv[0]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<b_time>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jg     L0
  mov    (%rsi),%rsi
  mov    $0x31,%edi
  call   <error@plt>
L2:
  add    $0x8,%rsp
  ret
L0:
  mov    (%rsi),%rsi
  mov    $0x1,%edi
  call   <error@plt>
  jmp    L2
```

assistant: ```c
int b_time(int argc, char *argv[]) {
  if (argc > 1)
    return error(1, argv[0]);
  return error(49, argv[0]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<b_time>:
  endbr64
  mov    (%rsi),%rsi
  cmp    $0x1,%edi
  jg     L1
  mov    $0x31,%edi
  jmp    1050 <error@plt>
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0x1,%edi
  jmp    1050 <error@plt>
```

assistant: ```c
int b_time(int argc, char *argv[]) {
  if (argc > 1)
    return error(1, argv[0]);
  return error(49, argv[0]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<b_time>:
  endbr64
  mov    (%rsi),%rsi
  cmp    $0x1,%edi
  jg     L4
  mov    $0x31,%edi
  jmp    1050 <error@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0x1,%edi
  jmp    1050 <error@plt>
```

assistant: ```c
int b_time(int argc, char *argv[]) {
  if (argc > 1)
    return error(1, argv[0]);
  return error(49, argv[0]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BEPackInt32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) void BEPackInt32(uint8_t container[4], int32_t data) {
  container[0] = (uint8_t)(data >> 24);
  container[1] = (uint8_t)(data >> 16);
  container[2] = (uint8_t)(data >> 8);
  container[3] = (uint8_t)data;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BEPackInt32>:
  endbr64
  mov    %esi,%eax
  sar    $0x18,%eax
  cltq
  mov    %rax,(%rdi)
  mov    %esi,%eax
  sar    $0x10,%eax
  cltq
  mov    %rax,0x8(%rdi)
  mov    %esi,%eax
  sar    $0x8,%eax
  cltq
  mov    %rax,0x10(%rdi)
  movslq %esi,%rsi
  mov    %rsi,0x18(%rdi)
  ret
```

assistant: ```c
__attribute__((always_)) void BEPackInt32(uint8_t container[4], int32_t data) {
  container[0] = (uint8_t)(data >> 24);
  container[1] = (uint8_t)(data >> 16);
  container[2] = (uint8_t)(data >> 8);
  container[3] = (uint8_t)data;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BEPackInt32>:
  endbr64
  mov    %esi,%eax
  sar    $0x18,%eax
  cltq
  mov    %rax,(%rdi)
  mov    %esi,%eax
  sar    $0x10,%eax
  cltq
  mov    %rax,0x8(%rdi)
  mov    %esi,%eax
  movslq %esi,%rsi
  sar    $0x8,%eax
  mov    %rsi,0x18(%rdi)
  cltq
  mov    %rax,0x10(%rdi)
  ret
```

assistant: ```c
__attribute__((always_)) void BEPackInt32(uint8_t container[4], int32_t data) {
  container[0] = (uint8_t)(data >> 24);
  container[1] = (uint8_t)(data >> 16);
  container[2] = (uint8_t)(data >> 8);
  container[3] = (uint8_t)data;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BEPackInt32>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  movd   %esi,%xmm3
  sar    $0x18,%eax
  sar    $0x8,%edx
  movd   %eax,%xmm0
  mov    %esi,%eax
  movd   %edx,%xmm1
  sar    $0x10,%eax
  punpckldq %xmm3,%xmm1
  movd   %eax,%xmm4
  punpckldq %xmm4,%xmm0
  punpcklqdq %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  pcmpgtd %xmm0,%xmm1
  movdqa %xmm0,%xmm2
  punpckldq %xmm1,%xmm2
  punpckhdq %xmm1,%xmm0
  movups %xmm2,(%rdi)
  movups %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
__attribute__((always_)) void BEPackInt32(uint8_t container[4], int32_t data) {
  container[0] = (uint8_t)(data >> 24);
  container[1] = (uint8_t)(data >> 16);
  container[2] = (uint8_t)(data >> 8);
  container[3] = (uint8_t)data;
}
```
user: What is the c source code of the assembly code below?

```asm
<heapify_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L11
L0:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <shift_up@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L0
  nop
  leave
  ret
```

assistant: ```c
void heapify_up(void *array, int asize, int esize, int compare(void *key1, void *key2)) {
  int i = 2;
  while (i <= asize) {
    shift_up(array, i, esize, compare);
    i++;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<heapify_up>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %rcx,%r14
  mov    $0x2,%ebx
L11:
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <shift_up@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  ret
```

assistant: ```c
void heapify_up(void *array, int asize, int esize, int compare(void *key1, void *key2)) {
  int i = 2;
  while (i <= asize) {
    shift_up(array, i, esize, compare);
    i++;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<heapify_up>:
  endbr64
  cmp    $0x1,%esi
  jle    L19
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L1:
  mov    %ebx,%esi
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <shift_up@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void heapify_up(void *array, int asize, int esize, int compare(void *key1, void *key2)) {
  int i = 2;
  while (i <= asize) {
    shift_up(array, i, esize, compare);
    i++;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<heapify_up>:
  endbr64
  cmp    $0x1,%esi
  jle    L8
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L10:
  mov    %ebx,%esi
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <shift_up@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void heapify_up(void *array, int asize, int esize, int compare(void *key1, void *key2)) {
  int i = 2;
  while (i <= asize) {
    shift_up(array, i, esize, compare);
    i++;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<raise_g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x3,-0x4(%rbp)
  jle    L19
  addl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x3,-0x8(%rbp)
  jle    L12
  nop
  pop    %rbp
  ret
```

assistant: ```c
void raise_g(double vcov[4], double gcon[4][4], double vcon[4]) {
  int i, j;
  for (i = 0; i < 4; i++) {
    vcon[i] = 0.;
    for (j = 0; j < 4; j++)
      vcon[i] += gcon[i][j] * vcov[j];
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<raise_g>:
  endbr64
  lea    0x20(%rdx),%r9
L14:
  mov    %rdx,%rcx
  movq   $0x0,(%rdx)
  mov    %rsi,%r8
  mov    $0x0,%eax
L3:
  movsd  (%r8,%rax,1),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  cmp    $0x20,%rax
  jne    L3
  add    $0x8,%rdx
  add    $0x20,%rsi
  cmp    %r9,%rdx
  jne    L14
  ret
```

assistant: ```c
void raise_g(double vcov[4], double gcon[4][4], double vcon[4]) {
  int i, j;
  for (i = 0; i < 4; i++) {
    vcon[i] = 0.;
    for (j = 0; j < 4; j++)
      vcon[i] += gcon[i][j] * vcov[j];
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<raise_g>:
  endbr64
  lea    0x80(%rsi),%rcx
L19:
  movq   $0x0,(%rdx)
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
L8:
  movsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    $0x20,%rax
  jne    L8
  add    $0x20,%rsi
  add    $0x8,%rdx
  cmp    %rcx,%rsi
  jne    L19
  ret
```

assistant: ```c
void raise_g(double vcov[4], double gcon[4][4], double vcon[4]) {
  int i, j;
  for (i = 0; i < 4; i++) {
    vcon[i] = 0.;
    for (j = 0; j < 4; j++)
      vcon[i] += gcon[i][j] * vcov[j];
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L12:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L4
L13:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L4:
  cmpl   $0x2,-0x8(%rbp)
  jle    L13
  addl   $0x1,-0xc(%rbp)
L25:
  cmpl   $0x2,-0xc(%rbp)
  jle    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(int (*p)[3]) {
  int i, j, temp;
  for (i = 0; i < 3; i++) {
    for (j = i + 1; j < 3; j++) {
      temp = *(*(p + i) + j);
      *(*(p + i) + j) = *(*(p + j) + i);
      *(*(p + j) + i) = temp;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  mov    $0x0,%r9d
  mov    $0x1,%r10d
  mov    $0x1,%edx
  jmp    L6
L17:
  mov    %r10d,%r9d
  mov    %edx,%r10d
L6:
  movslq %r9d,%rax
  movslq %edx,%rcx
  lea    (%rax,%rax,2),%rsi
  add    %rcx,%rsi
  lea    (%rdi,%rsi,4),%rsi
  mov    (%rsi),%r8d
  lea    (%rcx,%rcx,2),%rcx
  add    %rcx,%rax
  lea    (%rdi,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,(%rsi)
  mov    %r8d,(%rax)
  add    $0x1,%edx
  cmp    $0x2,%edx
  jle    L6
  lea    0x1(%r10),%edx
  cmp    $0x2,%edx
  jle    L17
  ret
```

assistant: ```c
void reverse(int (*p)[3]) {
  int i, j, temp;
  for (i = 0; i < 3; i++) {
    for (j = i + 1; j < 3; j++) {
      temp = *(*(p + i) + j);
      *(*(p + i) + j) = *(*(p + j) + i);
      *(*(p + j) + i) = temp;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  mov    $0x1,%r10d
  mov    $0x1,%esi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L26:
  movslq %esi,%rax
  lea    (%rcx,%rcx,2),%rdx
  add    %rax,%rdx
  lea    (%rax,%rax,2),%rax
  add    %rcx,%rax
  lea    (%rdi,%rdx,4),%rdx
  lea    (%rdi,%rax,4),%rax
  mov    (%rdx),%r8d
  mov    (%rax),%r9d
  mov    %r9d,(%rdx)
  mov    %r8d,(%rax)
  cmp    $0x2,%esi
  je     L39
  mov    $0x2,%esi
  jmp    L26
  nopl   0x0(%rax)
L39:
  lea    0x1(%r10),%esi
  cmp    $0x2,%r10d
  jne    L32
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  movslq %r10d,%rcx
  mov    %esi,%r10d
  jmp    L26
```

assistant: ```c
void reverse(int (*p)[3]) {
  int i, j, temp;
  for (i = 0; i < 3; i++) {
    for (j = i + 1; j < 3; j++) {
      temp = *(*(p + i) + j);
      *(*(p + i) + j) = *(*(p + j) + i);
      *(*(p + j) + i) = temp;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse>:
  endbr64
  mov    $0x1,%r10d
  mov    $0x1,%esi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L16:
  movslq %esi,%rax
  lea    (%rcx,%rcx,2),%rdx
  add    %rax,%rdx
  lea    (%rax,%rax,2),%rax
  add    %rcx,%rax
  lea    (%rdi,%rdx,4),%rdx
  lea    (%rdi,%rax,4),%rax
  mov    (%rdx),%r8d
  mov    (%rax),%r9d
  mov    %r9d,(%rdx)
  mov    %r8d,(%rax)
  cmp    $0x2,%esi
  je     L14
  mov    $0x2,%esi
  jmp    L16
  nopl   0x0(%rax)
L14:
  lea    0x1(%r10),%esi
  cmp    $0x2,%r10d
  jne    L28
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  movslq %r10d,%rcx
  mov    %esi,%r10d
  jmp    L16
```

assistant: ```c
void reverse(int (*p)[3]) {
  int i, j, temp;
  for (i = 0; i < 3; i++) {
    for (j = i + 1; j < 3; j++) {
      temp = *(*(p + i) + j);
      *(*(p + i) + j) = *(*(p + j) + i);
      *(*(p + j) + i) = temp;
    }
  }
}
```