ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<charset_conv_iso_8859_1_to_utf8>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    (%rdi,%rsi,1),%rbp
  cmp    %rbp,%rdi
  jae    L132
  mov    %rdi,%rbx
  mov    %rdi,%rax
  mov    $0x0,%edi
  jmp    L49
L14:
  add    $0x2,%rdi
  jmp    L127
L78:
  add    $0x1,%rdi
L127:
  add    $0x1,%rax
  cmp    %rax,%rbp
  je     L42
L49:
  movzbl (%rax),%edx
  test   %dl,%dl
  js     L14
  jne    L78
L42:
  add    $0x1,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L112
  mov    %rax,%rcx
  jmp    L129
L52:
  mov    %edx,%esi
  shr    $0x6,%sil
  sub    $0x40,%esi
  mov    %sil,(%rcx)
  and    $0x3f,%edx
  add    $0xffffff80,%edx
  mov    %dl,0x1(%rcx)
  add    $0x2,%rcx
L138:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L11
L129:
  movzbl (%rbx),%edx
  test   %dl,%dl
  js     L52
  je     L11
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  jmp    L138
L21:
  mov    %rcx,%rax
  jmp    L112
L132:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L21
L11:
  movb   $0x0,(%rcx)
L112:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *charset_conv_iso_8859_1_to_utf8(const char *iso, size_t len) {
  size_t utf8len = 0;
  const unsigned char *isoend = iso + len;
  const unsigned char *isocur = iso;
  char *utf8str = NULL;
  unsigned char *utf8cur = NULL;
  while (isocur < isoend) {
    if ((*isocur) & 0x80) {
      utf8len += 2;
    } else if (*isocur) {
      utf8len += 1;
    } else {
      break;
    }
    ++isocur;
  }
  utf8str = malloc(utf8len + 1);
  if (utf8str == NULL)
    return NULL;
  utf8cur = utf8str;
  for (isocur = iso; isocur < isoend; ++isocur) {
    if ((*isocur) & 0x80) {
      utf8cur[0] = 0xc0 + ((*isocur) >> 6);
      utf8cur[1] = 0x80 + ((*isocur) & 0x3f);
      utf8cur += 2;
    } else if (*isocur) {
      *utf8cur = *isocur;
      utf8cur += 1;
    } else {
      break;
    }
  }
  *utf8cur = '\0';
  return utf8str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<charset_conv_iso_8859_1_to_utf8>:
  endbr64
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rbp,%rdi
  jae    L80
  mov    %rdi,%rbx
  mov    %rdi,%rax
  xor    %edi,%edi
  jmp    L66
  nopl   0x0(%rax)
L52:
  add    $0x1,%rdi
  test   %dl,%dl
  je     L84
  add    $0x1,%rax
  cmp    %rax,%rbp
  je     L140
L66:
  movzbl (%rax),%edx
  test   %dl,%dl
  jns    L52
  add    $0x1,%rax
  add    $0x2,%rdi
  cmp    %rax,%rbp
  jne    L66
L140:
  add    $0x1,%rdi
L84:
  call   <malloc@plt>
  test   %rax,%rax
  je     L133
  mov    %rax,%rcx
  jmp    L55
L8:
  je     L130
  add    $0x1,%rbx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  cmp    %rbx,%rbp
  je     L130
L55:
  movzbl (%rbx),%edx
  test   %dl,%dl
  jns    L8
  mov    %edx,%esi
  and    $0x3f,%edx
  add    $0x1,%rbx
  add    $0x2,%rcx
  shr    $0x6,%sil
  add    $0xffffff80,%edx
  sub    $0x40,%esi
  mov    %dl,-0x1(%rcx)
  mov    %sil,-0x2(%rcx)
  cmp    %rbx,%rbp
  jne    L55
L130:
  movb   $0x0,(%rcx)
L129:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L80:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L133
  mov    %rcx,%rax
  jmp    L130
L133:
  xor    %eax,%eax
  jmp    L129
```

assistant: ```c
char *charset_conv_iso_8859_1_to_utf8(const char *iso, size_t len) {
  size_t utf8len = 0;
  const unsigned char *isoend = iso + len;
  const unsigned char *isocur = iso;
  char *utf8str = NULL;
  unsigned char *utf8cur = NULL;
  while (isocur < isoend) {
    if ((*isocur) & 0x80) {
      utf8len += 2;
    } else if (*isocur) {
      utf8len += 1;
    } else {
      break;
    }
    ++isocur;
  }
  utf8str = malloc(utf8len + 1);
  if (utf8str == NULL)
    return NULL;
  utf8cur = utf8str;
  for (isocur = iso; isocur < isoend; ++isocur) {
    if ((*isocur) & 0x80) {
      utf8cur[0] = 0xc0 + ((*isocur) >> 6);
      utf8cur[1] = 0x80 + ((*isocur) & 0x3f);
      utf8cur += 2;
    } else if (*isocur) {
      *utf8cur = *isocur;
      utf8cur += 1;
    } else {
      break;
    }
  }
  *utf8cur = '\0';
  return utf8str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<charset_conv_iso_8859_1_to_utf8>:
  endbr64
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rbp,%rdi
  jae    L25
  mov    %rdi,%rbx
  mov    %rdi,%rax
  xor    %edi,%edi
  jmp    L149
  nopl   0x0(%rax)
L68:
  add    $0x1,%rdi
  test   %dl,%dl
  je     L42
  add    $0x1,%rax
  cmp    %rax,%rbp
  je     L90
L149:
  movzbl (%rax),%edx
  test   %dl,%dl
  jns    L68
  add    $0x1,%rax
  add    $0x2,%rdi
  cmp    %rax,%rbp
  jne    L149
L90:
  add    $0x1,%rdi
L42:
  call   <malloc@plt>
  test   %rax,%rax
  je     L122
  mov    %rax,%rcx
  jmp    L61
L113:
  je     L89
  add    $0x1,%rbx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  cmp    %rbx,%rbp
  je     L89
L61:
  movzbl (%rbx),%edx
  test   %dl,%dl
  jns    L113
  mov    %edx,%esi
  and    $0x3f,%edx
  add    $0x1,%rbx
  add    $0x2,%rcx
  shr    $0x6,%sil
  add    $0xffffff80,%edx
  sub    $0x40,%esi
  mov    %dl,-0x1(%rcx)
  mov    %sil,-0x2(%rcx)
  cmp    %rbx,%rbp
  jne    L61
L89:
  movb   $0x0,(%rcx)
L106:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L122
  mov    %rcx,%rax
  jmp    L89
L122:
  xor    %eax,%eax
  jmp    L106
```

assistant: ```c
char *charset_conv_iso_8859_1_to_utf8(const char *iso, size_t len) {
  size_t utf8len = 0;
  const unsigned char *isoend = iso + len;
  const unsigned char *isocur = iso;
  char *utf8str = NULL;
  unsigned char *utf8cur = NULL;
  while (isocur < isoend) {
    if ((*isocur) & 0x80) {
      utf8len += 2;
    } else if (*isocur) {
      utf8len += 1;
    } else {
      break;
    }
    ++isocur;
  }
  utf8str = malloc(utf8len + 1);
  if (utf8str == NULL)
    return NULL;
  utf8cur = utf8str;
  for (isocur = iso; isocur < isoend; ++isocur) {
    if ((*isocur) & 0x80) {
      utf8cur[0] = 0xc0 + ((*isocur) >> 6);
      utf8cur[1] = 0x80 + ((*isocur) & 0x3f);
      utf8cur += 2;
    } else if (*isocur) {
      *utf8cur = *isocur;
      utf8cur += 1;
    } else {
      break;
    }
  }
  *utf8cur = '\0';
  return utf8str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wait_for>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L18:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L26:
  lea    -0xc(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L18
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void wait_for(struct timespec delay) {
  struct timespec rest = {};
  while (nanosleep(&delay, &rest) == -1) {
    delay = rest;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wait_for>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    0x14(%rsp),%rbx
  jmp    L5
L7:
  mov    0x14(%rsp),%eax
  mov    %eax,0xc(%rsp)
L5:
  lea    0xc(%rsp),%rdi
  mov    %rbx,%rsi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L7
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  pop    %rbx
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wait_for(struct timespec delay) {
  struct timespec rest = {};
  while (nanosleep(&delay, &rest) == -1) {
    delay = rest;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wait_for>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x14(%rsp),%rbp
  lea    0xc(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x14(%rsp),%eax
  mov    %eax,0xc(%rsp)
L20:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wait_for(struct timespec delay) {
  struct timespec rest = {};
  while (nanosleep(&delay, &rest) == -1) {
    delay = rest;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<wait_for>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x14(%rsp),%rbp
  lea    0xc(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L13:
  mov    0x14(%rsp),%eax
  mov    %eax,0xc(%rsp)
L29:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L13
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wait_for(struct timespec delay) {
  struct timespec rest = {};
  while (nanosleep(&delay, &rest) == -1) {
    delay = rest;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__modsi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L0
  negq   -0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
L0:
  cmpq   $0x0,-0x20(%rbp)
  jns    L29
  negq   -0x20(%rbp)
L29:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <divmodsi4@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L22
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L3
L22:
  mov    -0x8(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
long __modsi3(long numerator, long denominator) {
  int sign = 0;
  long dividend;
  long modul;
  if (numerator < 0) {
    numerator = -numerator;
    sign = 1;
  }
  if (denominator < 0) {
    denominator = -denominator;
  }
  modul = divmodsi4(1, numerator, denominator);
  if (sign)
    return -modul;
  return modul;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__modsi3>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L11
  mov    %rsi,%rdx
  neg    %rdx
  cmovs  %rsi,%rdx
  mov    %rdi,%rsi
  mov    $0x1,%edi
  call   <divmodsi4@plt>
L18:
  add    $0x8,%rsp
  ret
L11:
  mov    %rsi,%rdx
  neg    %rdx
  cmovs  %rsi,%rdx
  neg    %rdi
  mov    %rdi,%rsi
  mov    $0x1,%edi
  call   <divmodsi4@plt>
  neg    %rax
  jmp    L18
```

assistant: ```c
long __modsi3(long numerator, long denominator) {
  int sign = 0;
  long dividend;
  long modul;
  if (numerator < 0) {
    numerator = -numerator;
    sign = 1;
  }
  if (denominator < 0) {
    denominator = -denominator;
  }
  modul = divmodsi4(1, numerator, denominator);
  if (sign)
    return -modul;
  return modul;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__modsi3>:
  endbr64
  mov    %rsi,%rdx
  neg    %rdx
  cmovs  %rsi,%rdx
  test   %rdi,%rdi
  js     L4
  mov    %rdi,%rsi
  mov    $0x1,%edi
  jmp    1050 <divmodsi4@plt>
L4:
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  mov    $0x1,%edi
  neg    %rsi
  call   <divmodsi4@plt>
  add    $0x8,%rsp
  neg    %rax
  ret
```

assistant: ```c
long __modsi3(long numerator, long denominator) {
  int sign = 0;
  long dividend;
  long modul;
  if (numerator < 0) {
    numerator = -numerator;
    sign = 1;
  }
  if (denominator < 0) {
    denominator = -denominator;
  }
  modul = divmodsi4(1, numerator, denominator);
  if (sign)
    return -modul;
  return modul;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__modsi3>:
  endbr64
  mov    %rsi,%rdx
  neg    %rdx
  cmovs  %rsi,%rdx
  test   %rdi,%rdi
  js     L1
  mov    %rdi,%rsi
  mov    $0x1,%edi
  jmp    1050 <divmodsi4@plt>
L1:
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  mov    $0x1,%edi
  neg    %rsi
  call   <divmodsi4@plt>
  add    $0x8,%rsp
  neg    %rax
  ret
```

assistant: ```c
long __modsi3(long numerator, long denominator) {
  int sign = 0;
  long dividend;
  long modul;
  if (numerator < 0) {
    numerator = -numerator;
    sign = 1;
  }
  if (denominator < 0) {
    denominator = -denominator;
  }
  modul = divmodsi4(1, numerator, denominator);
  if (sign)
    return -modul;
  return modul;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_am_tag_read_str_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rbx
  jmp    L79
L47:
  add    $0x1,%rbx
L79:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L47
  mov    %rbx,%r12
  jmp    L0
L26:
  add    $0x1,%rbx
L0:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L4
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  jne    L26
L4:
  mov    -0x20(%rbp),%rax
  mov    %rbx,(%rax)
  lea    -0x1(%rbx),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L15
  sub    $0x1,%rbx
  jmp    L9
L51:
  sub    $0x1,%rbx
L9:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L51
L15:
  mov    %rbx,%rax
  sub    %r12,%rax
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <_am_tag_strdup@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *_am_tag_read_str_val(const char *src, const char **out_tail) {
  register const char *s = src, *t;
  while (isspace(*s))
    ++s;
  t = s;
  while (*s && *s != '\n')
    ++s;
  *out_tail = s;
  if (isspace(*(s - 1))) {
    --s;
    while (isspace(*s))
      --s;
  }
  return _am_tag_strdup(t, s - t);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_am_tag_read_str_val>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  jmp    L77
L55:
  add    $0x1,%rbp
L77:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L55
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L80
  cmp    $0xa,%al
  je     L80
  mov    %rbp,%rbx
L75:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L31
  cmp    $0xa,%al
  jne    L75
L31:
  mov    %rbx,(%r12)
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L4
  sub    $0x1,%rbx
L29:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L4
  sub    $0x1,%rbx
  jmp    L29
L80:
  mov    %rbp,%rbx
  jmp    L31
L4:
  mov    %ebx,%esi
  sub    %ebp,%esi
  mov    %rbp,%rdi
  call   <_am_tag_strdup@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *_am_tag_read_str_val(const char *src, const char **out_tail) {
  register const char *s = src, *t;
  while (isspace(*s))
    ++s;
  t = s;
  while (*s && *s != '\n')
    ++s;
  *out_tail = s;
  if (isspace(*(s - 1))) {
    --s;
    while (isspace(*s))
      --s;
  }
  return _am_tag_strdup(t, s - t);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_am_tag_read_str_val>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L74
L10:
  add    $0x1,%rbp
L74:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  movzbl 0x0(%rbp),%eax
  mov    %rbp,%rbx
  test   %al,%al
  jne    L39
  jmp    L89
  nop
L83:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L89
L39:
  cmp    $0xa,%al
  jne    L83
L89:
  mov    %rbx,(%r12)
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
L63:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  pop    %rbx
  sub    %ebp,%esi
  pop    %rbp
  pop    %r12
  jmp    1070 <_am_tag_strdup@plt>
  nopw   0x0(%rax,%rax,1)
L31:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  jmp    L63
```

assistant: ```c
char *_am_tag_read_str_val(const char *src, const char **out_tail) {
  register const char *s = src, *t;
  while (isspace(*s))
    ++s;
  t = s;
  while (*s && *s != '\n')
    ++s;
  *out_tail = s;
  if (isspace(*(s - 1))) {
    --s;
    while (isspace(*s))
      --s;
  }
  return _am_tag_strdup(t, s - t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_am_tag_read_str_val>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L41
L38:
  add    $0x1,%rbp
L41:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L38
  movzbl 0x0(%rbp),%eax
  mov    %rbp,%rbx
  test   %al,%al
  jne    L49
  jmp    L6
  nop
L42:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L6
L49:
  cmp    $0xa,%al
  jne    L42
L6:
  mov    %rbx,(%r12)
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L59
L12:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  pop    %rbx
  sub    %ebp,%esi
  pop    %rbp
  pop    %r12
  jmp    1070 <_am_tag_strdup@plt>
  nopw   0x0(%rax,%rax,1)
L59:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L59
  jmp    L12
```

assistant: ```c
char *_am_tag_read_str_val(const char *src, const char **out_tail) {
  register const char *s = src, *t;
  while (isspace(*s))
    ++s;
  t = s;
  while (*s && *s != '\n')
    ++s;
  *out_tail = s;
  if (isspace(*(s - 1))) {
    --s;
    while (isspace(*s))
      --s;
  }
  return _am_tag_strdup(t, s - t);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x38(%rbp),%rdx
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L1
L12:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x38(%rbp),%ebx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <base_to_10@plt>
  mov    %eax,%ebx
  mov    -0x38(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <base_to_10@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L1:
  mov    -0x3c(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L12
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D15
type: string

tool: D22: %d%d

tool: D17: %s

tool: D15: %d %d


assistant: ```c
int main() {
  int num, base;
  char str[20];
  scanf("%d%d", &num, &base);
  for (int i = 0; i < num; i++) {
    scanf("%s", str);
    printf("%d %d\n", base_to_10(str, base), base_to_10(reverse(str), base));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L16
  mov    $0x0,%r12d
  lea    0x10(%rsp),%rbp
  lea    D25(%rip),%r14
  lea    D16(%rip),%r13
L14:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <base_to_10@plt>
  mov    %eax,%ebx
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <base_to_10@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r12d,0x8(%rsp)
  jg     L14
L16:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string
name: disassemble_data
arguments: data_tag: D25
type: string
name: disassemble_data
arguments: data_tag: D16
type: string

tool: D5: %d%d

tool: D25: %s

tool: D16: %d %d


assistant: ```c
int main() {
  int num, base;
  char str[20];
  scanf("%d%d", &num, &base);
  for (int i = 0; i < num; i++) {
    scanf("%s", str);
    printf("%d %d\n", base_to_10(str, base), base_to_10(reverse(str), base));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D11(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L9
  xor    %r14d,%r14d
  lea    0x10(%rsp),%rbx
  lea    D1(%rip),%r13
  lea    D21(%rip),%rbp
  nopl   0x0(%rax)
L10:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <scanf@plt>
  mov    0xc(%rsp),%r12d
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rax,%rdi
  mov    %r12d,%esi
  call   <base_to_10@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <base_to_10@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %r14d,0x8(%rsp)
  jg     L10
L9:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D1
type: string
name: read_data
arguments: data_tag: D21
type: string

tool: D11: %d%d

tool: D1: %s

tool: D21: %d %d


assistant: ```c
int main() {
  int num, base;
  char str[20];
  scanf("%d%d", &num, &base);
  for (int i = 0; i < num; i++) {
    scanf("%s", str);
    printf("%d %d\n", base_to_10(str, base), base_to_10(reverse(str), base));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  lea    D14(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L6
  xor    %r14d,%r14d
  lea    0x10(%rsp),%rbx
  lea    D1(%rip),%r13
  lea    D24(%rip),%rbp
  nopl   0x0(%rax)
L18:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <scanf@plt>
  mov    0xc(%rsp),%r12d
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rax,%rdi
  mov    %r12d,%esi
  call   <base_to_10@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <base_to_10@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %r14d,0x8(%rsp)
  jg     L18
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D1
datatype: string
name: read_data
arguments: tag: D24
datatype: string

tool: D14: %d%d

tool: D1: %s

tool: D24: %d %d


assistant: ```c
int main() {
  int num, base;
  char str[20];
  scanf("%d%d", &num, &base);
  for (int i = 0; i < num; i++) {
    scanf("%s", str);
    printf("%d %d\n", base_to_10(str, base), base_to_10(reverse(str), base));
  }
  return 0;
}
```