ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_session_registers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L24:
  lea    -0xd(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tag_read_sessionreg@plt>
  addl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x6,-0xc(%rbp)
  jle    L24
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void print_session_registers(void) {
  char reg;
  int i;
  ;
  for (i = 0; i < 7; i++) {
    tag_read_sessionreg(i, &reg);
    ;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_session_registers>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0x7(%rsp),%rbp
L10:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <tag_read_sessionreg@plt>
  add    $0x1,%ebx
  cmp    $0x7,%ebx
  jne    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_session_registers(void) {
  char reg;
  int i;
  ;
  for (i = 0; i < 7; i++) {
    tag_read_sessionreg(i, &reg);
    ;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_session_registers>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  nopl   0x0(%rax)
L19:
  mov    %ebx,%edi
  mov    %rbp,%rsi
  add    $0x1,%ebx
  call   <tag_read_sessionreg@plt>
  cmp    $0x7,%ebx
  jne    L19
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_session_registers(void) {
  char reg;
  int i;
  ;
  for (i = 0; i < 7; i++) {
    tag_read_sessionreg(i, &reg);
    ;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_session_registers>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  nopl   0x0(%rax)
L9:
  mov    %ebx,%edi
  mov    %rbp,%rsi
  add    $0x1,%ebx
  call   <tag_read_sessionreg@plt>
  cmp    $0x7,%ebx
  jne    L9
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_session_registers(void) {
  char reg;
  int i;
  ;
  for (i = 0; i < 7; i++) {
    tag_read_sessionreg(i, &reg);
    ;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<morphological_feature_circularity_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L17:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L17
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: byte[8]

tool: {"D3": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x29,0x40]}

assistant: ```c
int morphological_feature_circularity_index(int *area, double *perim, int n_object, double *circ) {
  unsigned int i = 0;
  for (i = 0; i < n_object; i++) {
    circ[i] = 4.0 * 3.1415926535897932384626433832795 * area[i] / (perim[i] * perim[i]);
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<morphological_feature_circularity_index>:
  endbr64
  test   %edx,%edx
  je     L7
  lea    -0x1(%rdx),%r8d
  mov    $0x0,%eax
  movsd  D0(%rip),%xmm2
L14:
  movsd  (%rsi,%rax,8),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %r8,%rdx
  jne    L14
L7:
  mov    $0x1,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: byte[8]

tool: {"D0": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x29,0x40]}

assistant: ```c
int morphological_feature_circularity_index(int *area, double *perim, int n_object, double *circ) {
  unsigned int i = 0;
  for (i = 0; i < n_object; i++) {
    circ[i] = 4.0 * 3.1415926535897932384626433832795 * area[i] / (perim[i] * perim[i]);
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<morphological_feature_circularity_index>:
  endbr64
  test   %edx,%edx
  je     L2
  movsd  D4(%rip),%xmm2
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  pxor   %xmm0,%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L1
L2:
  mov    $0x1,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: byte[8]

tool: {"D4": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x29,0x40]}

assistant: ```c
int morphological_feature_circularity_index(int *area, double *perim, int n_object, double *circ) {
  unsigned int i = 0;
  for (i = 0; i < n_object; i++) {
    circ[i] = 4.0 * 3.1415926535897932384626433832795 * area[i] / (perim[i] * perim[i]);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<morphological_feature_circularity_index>:
  endbr64
  mov    %edx,%r8d
  mov    %rcx,%rdx
  test   %r8d,%r8d
  je     L30
  lea    0x8(%rsi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  cmp    $0x10,%rax
  jbe    L2
  lea    -0x1(%r8),%eax
  cmp    $0x2,%eax
  jbe    L2
  mov    %r8d,%ecx
  movapd D28(%rip),%xmm4
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L59:
  movdqu (%rdi,%rax,1),%xmm0
  movupd 0x10(%rsi,%rax,2),%xmm2
  movupd (%rsi,%rax,2),%xmm3
  cvtdq2pd %xmm0,%xmm1
  mulpd  %xmm2,%xmm2
  pshufd $0xee,%xmm0,%xmm0
  mulpd  %xmm4,%xmm1
  cvtdq2pd %xmm0,%xmm0
  mulpd  %xmm3,%xmm3
  mulpd  %xmm4,%xmm0
  divpd  %xmm3,%xmm1
  divpd  %xmm2,%xmm0
  movups %xmm1,(%rdx,%rax,2)
  movups %xmm0,0x10(%rdx,%rax,2)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L59
  mov    %r8d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r8b
  je     L30
  mov    %eax,%ecx
  pxor   %xmm0,%xmm0
  movsd  D28(%rip),%xmm2
  cvtsi2sdl (%rdi,%rcx,4),%xmm0
  movsd  (%rsi,%rcx,8),%xmm1
  mulsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rcx,8)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%r8d
  jbe    L30
  pxor   %xmm0,%xmm0
  movsd  (%rsi,%rcx,8),%xmm1
  add    $0x2,%eax
  cvtsi2sdl (%rdi,%rcx,4),%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rcx,8)
  cmp    %eax,%r8d
  jbe    L30
  pxor   %xmm0,%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
L30:
  mov    $0x1,%eax
  ret
L2:
  movsd  D28(%rip),%xmm2
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L79:
  pxor   %xmm0,%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L79
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D28
datatype: byte[16]

tool: {"D28": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x29,0x40,0x18,0x2d,0x44,0x54,0xfb,0x21,0x29,0x40]}

assistant: ```c
int morphological_feature_circularity_index(int *area, double *perim, int n_object, double *circ) {
  unsigned int i = 0;
  for (i = 0; i < n_object; i++) {
    circ[i] = 4.0 * 3.1415926535897932384626433832795 * area[i] / (perim[i] * perim[i]);
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uart_enable_rx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffff8a,%eax
  movzbl (%rax),%eax
  mov    $0xffff8a,%edx
  or     $0x50,%eax
  mov    %al,(%rdx)
  mov    $0x0,%eax
  call   <eri1_irq@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uart_enable_rx() {
  (*(volatile unsigned char *)(0xffff8a)) |= (1 << 6) | (1 << 4);
  eri1_irq();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uart_enable_rx>:
  endbr64
  sub    $0x8,%rsp
  movzbl 0xffff8a,%eax
  or     $0x50,%eax
  mov    %al,0xffff8a
  mov    $0x0,%eax
  call   <eri1_irq@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uart_enable_rx() {
  (*(volatile unsigned char *)(0xffff8a)) |= (1 << 6) | (1 << 4);
  eri1_irq();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uart_enable_rx>:
  endbr64
  movzbl 0xffff8a,%eax
  or     $0x50,%eax
  mov    %al,0xffff8a
  xor    %eax,%eax
  jmp    1050 <eri1_irq@plt>
```

assistant: ```c
void uart_enable_rx() {
  (*(volatile unsigned char *)(0xffff8a)) |= (1 << 6) | (1 << 4);
  eri1_irq();
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_enable_rx>:
  endbr64
  movzbl 0xffff8a,%eax
  or     $0x50,%eax
  mov    %al,0xffff8a
  xor    %eax,%eax
  jmp    1050 <eri1_irq@plt>
```

assistant: ```c
void uart_enable_rx() {
  (*(volatile unsigned char *)(0xffff8a)) |= (1 << 6) | (1 << 4);
  eri1_irq();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memstarts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L18
  mov    $0x0,%eax
  jmp    L11
L18:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L11:
  leave
  ret
```

assistant: ```c
bool memstarts(void const *data, size_t data_len, void const *prefix, size_t prefix_len) {
  if (prefix_len > data_len)
    return false;
  return !memcmp(data, prefix, prefix_len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memstarts>:
  endbr64
  mov    $0x0,%eax
  cmp    %rsi,%rcx
  ja     L8
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
bool memstarts(void const *data, size_t data_len, void const *prefix, size_t prefix_len) {
  if (prefix_len > data_len)
    return false;
  return !memcmp(data, prefix, prefix_len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memstarts>:
  endbr64
  cmp    %rsi,%rcx
  ja     L5
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool memstarts(void const *data, size_t data_len, void const *prefix, size_t prefix_len) {
  if (prefix_len > data_len)
    return false;
  return !memcmp(data, prefix, prefix_len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memstarts>:
  endbr64
  cmp    %rsi,%rcx
  ja     L1
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool memstarts(void const *data, size_t data_len, void const *prefix, size_t prefix_len) {
  if (prefix_len > data_len)
    return false;
  return !memcmp(data, prefix, prefix_len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x3,-0x18(%rbp)
  movq   -0x18(%rbp),%xmm0
  movq   %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: Output is %llu (expected 3)


assistant: ```c
int main() {
  unsigned long long in = 3;
  unsigned long long out;
  asm volatile("movq %1, %%xmm0\n\t"
               "movq %%xmm0, %0\n\t"
               : "=m"(out)
               : "m"(in));
  printf("Output is %llu (expected 3)\n", out);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x3,0x8(%rsp)
  movq   0x8(%rsp),%xmm0
  movq   %xmm0,0x10(%rsp)
  mov    0x10(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: D5: Output is %llu (expected 3)


assistant: ```c
int main() {
  unsigned long long in = 3;
  unsigned long long out;
  asm volatile("movq %1, %%xmm0\n\t"
               "movq %%xmm0, %0\n\t"
               : "=m"(out)
               : "m"(in));
  printf("Output is %llu (expected 3)\n", out);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x3,0x8(%rsp)
  movq   0x8(%rsp),%xmm0
  movq   %xmm0,0x10(%rsp)
  mov    0x10(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D3: Output is %llu (expected 3)


assistant: ```c
int main() {
  unsigned long long in = 3;
  unsigned long long out;
  asm volatile("movq %1, %%xmm0\n\t"
               "movq %%xmm0, %0\n\t"
               : "=m"(out)
               : "m"(in));
  printf("Output is %llu (expected 3)\n", out);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x3,0x8(%rsp)
  movq   0x8(%rsp),%xmm0
  movq   %xmm0,0x10(%rsp)
  mov    0x10(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: Output is %llu (expected 3)


assistant: ```c
int main() {
  unsigned long long in = 3;
  unsigned long long out;
  asm volatile("movq %1, %%xmm0\n\t"
               "movq %%xmm0, %0\n\t"
               : "=m"(out)
               : "m"(in));
  printf("Output is %llu (expected 3)\n", out);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_byte_sequence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L15
  movl   $0x1,-0xc(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L15
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L12
  mov    -0x8(%rbp),%rax
  jmp    L48
L12:
  nop
L15:
  addq   $0x1,-0x8(%rbp)
  jmp    L2
L48:
  pop    %rbp
  ret
```

assistant: ```c
void *find_byte_sequence(char *sequence, int num, int base_address) {
  char *c = (char *)base_address;
  while (1) {
    if (*c == sequence[0]) {
      int i;
      for (i = 1; i < num; i++) {
        if (*(c + i) == sequence[i]) {
        } else {
          break;
        }
        return (void *)c;
      }
    }
    c++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<find_byte_sequence>:
  endbr64
  movslq %edx,%rax
  movzbl (%rdi),%edx
  jmp    L4
L8:
  add    $0x1,%rax
L4:
  cmp    %dl,(%rax)
  jne    L8
  cmp    $0x1,%esi
  jle    L8
  movzbl 0x1(%rdi),%ecx
  cmp    %cl,0x1(%rax)
  jne    L8
  ret
```

assistant: ```c
void *find_byte_sequence(char *sequence, int num, int base_address) {
  char *c = (char *)base_address;
  while (1) {
    if (*c == sequence[0]) {
      int i;
      for (i = 1; i < num; i++) {
        if (*(c + i) == sequence[i]) {
        } else {
          break;
        }
        return (void *)c;
      }
    }
    c++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<find_byte_sequence>:
  endbr64
  cmp    $0x1,%esi
  movslq %edx,%rax
  movzbl (%rdi),%edx
  setg   %cl
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%rax
L37:
  cmp    %dl,(%rax)
  jne    L34
  test   %cl,%cl
  je     L34
  movzbl 0x1(%rdi),%esi
  cmp    %sil,0x1(%rax)
  jne    L34
  ret
```

assistant: ```c
void *find_byte_sequence(char *sequence, int num, int base_address) {
  char *c = (char *)base_address;
  while (1) {
    if (*c == sequence[0]) {
      int i;
      for (i = 1; i < num; i++) {
        if (*(c + i) == sequence[i]) {
        } else {
          break;
        }
        return (void *)c;
      }
    }
    c++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_byte_sequence>:
  endbr64
  cmp    $0x1,%esi
  movslq %edx,%rax
  movzbl (%rdi),%edx
  setg   %cl
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rax
L15:
  cmp    %dl,(%rax)
  jne    L16
  test   %cl,%cl
  je     L16
  movzbl 0x1(%rdi),%esi
  cmp    %sil,0x1(%rax)
  jne    L16
  ret
```

assistant: ```c
void *find_byte_sequence(char *sequence, int num, int base_address) {
  char *c = (char *)base_address;
  while (1) {
    if (*c == sequence[0]) {
      int i;
      for (i = 1; i < num; i++) {
        if (*(c + i) == sequence[i]) {
        } else {
          break;
        }
        return (void *)c;
      }
    }
    c++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_ireplace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <nullstr@plt>
  test   %rax,%rax
  je     L2
L21:
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  mov    %rbp,%rdi
  call   <nullstr@plt>
  test   %r12,%r12
  je     L21
  test   %rax,%rax
  jne    L21
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <stristr@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L21
  mov    %rax,%r15
  sub    %rbx,%r15
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r15,0x8(%rsp)
  mov    %rax,(%rsp)
  add    %rax,%r15
  cmp    $0x7fb,%r15
  ja     L21
  mov    D23(%rip),%ecx
  lea    0x1(%rcx),%eax
  movslq %eax,%r13
  imul   $0xffffffff92492493,%r13,%r13
  shr    $0x20,%r13
  add    %eax,%r13d
  sar    $0x2,%r13d
  cltd
  sub    %edx,%r13d
  lea    0x0(,%r13,8),%edx
  sub    %r13d,%edx
  mov    %eax,%r13d
  sub    %edx,%r13d
  mov    %r13d,D9(%rip)
  movslq %r13d,%r13
  shl    $0xb,%r13
  lea    D9(%rip),%rax
  add    %rax,%r13
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rdi
  add    %r13,%rdi
  mov    (%rsp),%rdx
  mov    %r12,%rsi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x7fc,%edx
  sub    %r15,%rdx
  lea    (%r14,%rax,1),%rsi
  lea    0x0(%r13,%r15,1),%rdi
  call   <strncpy@plt>
  movb   $0x0,0x7fc(%r13)
  mov    %r13,%rbx
  jmp    L21
```

assistant: ```c
const char *str_ireplace(const char *orig, const char *old, const char *pnew) {
  char *buf = NULL;
  const char *ptr = NULL;
  size_t len = 0, a = 0, b = 0;
  static char outbuf[7][2048];
  static int i = 0;
  if (nullstr(orig) || nullstr(old) || pnew == NULL) {
    return orig;
  }
  if ((ptr = stristr(orig, old)) == NULL || (a = ptr - orig) + (len = strlen(pnew)) >= (2048 - 4)) {
    return orig;
  }
  ++i, i %= 7;
  buf = outbuf[i];
  b = 2048 - 4 - a - len;
  strcpy(buf, orig);
  strncpy(buf + a, pnew, len);
  strncpy(buf + a + len, ptr + strlen(old), b);
  buf[2048 - 4] = 0;
  return (buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_ireplace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <nullstr@plt>
  test   %rax,%rax
  je     L26
L29:
  mov    %rbp,%r12
L16:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r13,%rdi
  call   <nullstr@plt>
  test   %rax,%rax
  jne    L29
  test   %r14,%r14
  je     L29
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <stristr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L29
  mov    %rax,%rbx
  mov    %r14,%rdi
  call   <strlen@plt>
  sub    %rbp,%rbx
  lea    (%rbx,%rax,1),%rcx
  mov    %rax,0x8(%rsp)
  cmp    $0x7fb,%rcx
  mov    %rcx,(%rsp)
  ja     L29
  mov    D8(%rip),%eax
  add    $0x1,%eax
  movslq %eax,%r12
  mov    %eax,%esi
  imul   $0xffffffff92492493,%r12,%r12
  sar    $0x1f,%esi
  shr    $0x20,%r12
  add    %eax,%r12d
  sar    $0x2,%r12d
  sub    %esi,%r12d
  lea    0x0(,%r12,8),%esi
  sub    %r12d,%esi
  sub    %esi,%eax
  mov    %rbp,%rsi
  movslq %eax,%r12
  lea    D24(%rip),%rax
  mov    %r12d,D21(%rip)
  shl    $0xb,%r12
  add    %rax,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rdx
  mov    %r14,%rsi
  lea    (%r12,%rbx,1),%rdi
  call   <strncpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    (%rsp),%rcx
  mov    $0x7fc,%edx
  lea    (%r15,%rax,1),%rsi
  sub    %rcx,%rdx
  lea    (%r12,%rcx,1),%rdi
  call   <strncpy@plt>
  movb   $0x0,0x7fc(%r12)
  jmp    L16
```

assistant: ```c
const char *str_ireplace(const char *orig, const char *old, const char *pnew) {
  char *buf = NULL;
  const char *ptr = NULL;
  size_t len = 0, a = 0, b = 0;
  static char outbuf[7][2048];
  static int i = 0;
  if (nullstr(orig) || nullstr(old) || pnew == NULL) {
    return orig;
  }
  if ((ptr = stristr(orig, old)) == NULL || (a = ptr - orig) + (len = strlen(pnew)) >= (2048 - 4)) {
    return orig;
  }
  ++i, i %= 7;
  buf = outbuf[i];
  b = 2048 - 4 - a - len;
  strcpy(buf, orig);
  strncpy(buf + a, pnew, len);
  strncpy(buf + a + len, ptr + strlen(old), b);
  buf[2048 - 4] = 0;
  return (buf);
}
```