ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<medianOfMedians>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  push   %rbp
  lea    (%r8,%r8,4),%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0x4(%rsp)
  sub    %edx,%ecx
  mov    %ecx,%r12d
  mov    %edx,0x8(%rsp)
  add    $0x1,%r12d
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  je     L29
  xchg   %ax,%ax
L22:
  mov    0x8(%rsp),%eax
  lea    0x0(%rbp,%rax,1),%ebx
  mov    %eax,%r12d
  cmp    0x4(%rsp),%ebx
  jge    L11
  nopl   0x0(%rax)
L23:
  mov    %ebx,%edx
  lea    -0x1(%rbx),%ecx
  mov    %r13d,%r8d
  mov    %r14,%rsi
  sub    %ebp,%edx
  mov    %r15,%rdi
  mov    %ebx,%r12d
  add    %ebp,%ebx
  call   <_insertion@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L23
L11:
  mov    %ebp,%ebx
  shr    $0x1f,%ebx
  add    %ebp,%ebx
  sar    %ebx
  add    0x8(%rsp),%ebx
  cmpl   $0x4,0xc(%rsp)
  jle    L10
  lea    -0x1(%r12),%eax
  sub    %ebx,%r12d
  lea    0x0(%rbp,%rbp,4),%ecx
  mov    %ebp,%r13d
  mov    %eax,0x4(%rsp)
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  je     L14
  mov    %ebx,0x8(%rsp)
  mov    %ecx,%ebp
  jmp    L22
L29:
  mov    0x8(%rsp),%ebx
  mov    %r8d,%ebp
L14:
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    %ebp,%r8d
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <_insertion@plt>
  mov    %r12d,%eax
  add    $0x18,%rsp
  cltd
  idiv   %ebp
  sub    $0x1,%eax
  imul   %ebp,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    %ebp,%r8d
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <_insertion@plt>
  mov    0xc(%rsp),%eax
  imul   %ebp,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int medianOfMedians(void **ar, int (*cmp)(const void *, const void *), int left, int right, int gap) {
  int s, num;
  int span = 5 * gap;
  num = (right - left + 1) / span;
  if (num == 0) {
    _insertion(ar, cmp, left, right, gap);
    num = (right - left + 1) / gap;
    return left + gap * (num - 1) / 2;
  }
  for (s = left; s + span < right; s += span) {
    _insertion(ar, cmp, s, s + span - 1, gap);
  }
  if (num < 5) {
    _insertion(ar, cmp, left + span / 2, right, span);
    return left + num * span / 2;
  } else {
    return medianOfMedians(ar, cmp, left + span / 2, s - 1, 5 * gap);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<medianOfMedians>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  push   %rbp
  lea    (%r8,%r8,4),%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0x4(%rsp)
  sub    %edx,%ecx
  mov    %ecx,%r12d
  mov    %edx,0x8(%rsp)
  add    $0x1,%r12d
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  je     L21
  xchg   %ax,%ax
L12:
  mov    0x8(%rsp),%eax
  lea    0x0(%rbp,%rax,1),%ebx
  mov    %eax,%r12d
  cmp    0x4(%rsp),%ebx
  jge    L26
  nopl   0x0(%rax)
L16:
  mov    %ebx,%edx
  lea    -0x1(%rbx),%ecx
  mov    %r13d,%r8d
  mov    %r14,%rsi
  sub    %ebp,%edx
  mov    %r15,%rdi
  mov    %ebx,%r12d
  add    %ebp,%ebx
  call   <_insertion@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L16
L26:
  mov    %ebp,%ebx
  shr    $0x1f,%ebx
  add    %ebp,%ebx
  sar    %ebx
  add    0x8(%rsp),%ebx
  cmpl   $0x4,0xc(%rsp)
  jle    L30
  lea    -0x1(%r12),%eax
  sub    %ebx,%r12d
  lea    0x0(%rbp,%rbp,4),%ecx
  mov    %ebp,%r13d
  mov    %eax,0x4(%rsp)
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  je     L27
  mov    %ebx,0x8(%rsp)
  mov    %ecx,%ebp
  jmp    L12
L21:
  mov    0x8(%rsp),%ebx
  mov    %r8d,%ebp
L27:
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    %ebp,%r8d
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <_insertion@plt>
  mov    %r12d,%eax
  add    $0x18,%rsp
  cltd
  idiv   %ebp
  sub    $0x1,%eax
  imul   %ebp,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    %ebp,%r8d
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <_insertion@plt>
  mov    0xc(%rsp),%eax
  imul   %ebp,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int medianOfMedians(void **ar, int (*cmp)(const void *, const void *), int left, int right, int gap) {
  int s, num;
  int span = 5 * gap;
  num = (right - left + 1) / span;
  if (num == 0) {
    _insertion(ar, cmp, left, right, gap);
    num = (right - left + 1) / gap;
    return left + gap * (num - 1) / 2;
  }
  for (s = left; s + span < right; s += span) {
    _insertion(ar, cmp, s, s + span - 1, gap);
  }
  if (num < 5) {
    _insertion(ar, cmp, left + span / 2, right, span);
    return left + num * span / 2;
  } else {
    return medianOfMedians(ar, cmp, left + span / 2, s - 1, 5 * gap);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<idris2_usleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xf4240,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0x3e8,%edx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void idris2_usleep(int usec) {
  struct timespec t;
  t.tv_sec = usec / 1000000;
  t.tv_nsec = (usec % 1000000) * 1000;
  nanosleep(&t, NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<idris2_usleep>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0xf4240,%eax,%eax
  sub    %eax,%edi
  imul   $0x3e8,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void idris2_usleep(int usec) {
  struct timespec t;
  t.tv_sec = usec / 1000000;
  t.tv_nsec = (usec % 1000000) * 1000;
  nanosleep(&t, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<idris2_usleep>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0xf4240,%eax,%eax
  sub    %eax,%edi
  imul   $0x3e8,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void idris2_usleep(int usec) {
  struct timespec t;
  t.tv_sec = usec / 1000000;
  t.tv_nsec = (usec % 1000000) * 1000;
  nanosleep(&t, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<idris2_usleep>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  sub    %edx,%eax
  imul   $0xf4240,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%edi
  imul   $0x3e8,%edi,%edi
  movd   %edi,%xmm1
  mov    %rsp,%rdi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void idris2_usleep(int usec) {
  struct timespec t;
  t.tv_sec = usec / 1000000;
  t.tv_nsec = (usec % 1000000) * 1000;
  nanosleep(&t, NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Field_FindFirstSeparator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L15:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  jne    L5
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  jmp    L18
L5:
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jb     L15
  mov    $0x0,%eax
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *Field_FindFirstSeparator(char *s) {
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == ';') {
      return &s[i];
    }
  }
  return ((void *)0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Field_FindFirstSeparator>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rdi
  mov    %rbx,%rax
  add    %rbx,%rdi
L16:
  cmp    %rdi,%rax
  je     L17
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x3b,-0x1(%rax)
  jne    L16
  jmp    L20
L17:
  mov    $0x0,%edx
L20:
  mov    %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *Field_FindFirstSeparator(char *s) {
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == ';') {
      return &s[i];
    }
  }
  return ((void *)0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Field_FindFirstSeparator>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  add    %rbx,%rax
  jmp    L19
  nopl   (%rax)
L27:
  mov    %rdi,%r8
  add    $0x1,%rdi
  cmpb   $0x3b,-0x1(%rdi)
  je     L0
L19:
  cmp    %rax,%rdi
  jne    L27
  xor    %r8d,%r8d
L0:
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *Field_FindFirstSeparator(char *s) {
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == ';') {
      return &s[i];
    }
  }
  return ((void *)0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Field_FindFirstSeparator>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  add    %rbx,%rax
  jmp    L16
  nopl   (%rax)
L26:
  mov    %rdi,%r8
  add    $0x1,%rdi
  cmpb   $0x3b,-0x1(%rdi)
  je     L2
L16:
  cmp    %rax,%rdi
  jne    L26
  xor    %r8d,%r8d
L2:
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *Field_FindFirstSeparator(char *s) {
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == ';') {
      return &s[i];
    }
  }
  return ((void *)0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  and    $0x86006a00,%edx
  shr    $0x10,%eax
  and    $0x69,%eax
  mov    %al,%dl
  xor    $0x282562b8,%edx
  or     $0x40451f7c,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy12;
  char copy13;
  char copy14;
  char copy15;
  unsigned short copy17;
  unsigned short copy18;
  char copy19;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    if ((state[0UL] >> 1U) & 1U) {
      if ((state[0UL] >> 1U) & 1U) {
        if ((state[0UL] >> 4U) & 1U) {
          copy12 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
          copy14 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy14;
          copy14 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy14;
        }
      } else if (state[0UL] & 1U) {
        state[0UL] <<= ((state[0UL] >> 4U) & 7U) | 1UL;
        copy15 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy15;
      } else {
        state[0UL] <<= ((state[0UL] >> 1U) & 7U) | 1UL;
      }
    } else if ((state[0UL] >> 1U) & 1U) {
      copy17 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy17;
      copy18 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy18;
    } else {
      state[0UL] <<= ((state[0UL] >> 3U) & 7U) | 1UL;
      copy19 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy19;
    }
    output[0UL] = (state[0UL] ^ 673538744UL) | 1078271868U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  shr    $0x10,%eax
  and    $0x86006a00,%edx
  and    $0x69,%eax
  mov    %al,%dl
  xor    $0x282562b8,%edx
  or     $0x40451f7c,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy12;
  char copy13;
  char copy14;
  char copy15;
  unsigned short copy17;
  unsigned short copy18;
  char copy19;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    if ((state[0UL] >> 1U) & 1U) {
      if ((state[0UL] >> 1U) & 1U) {
        if ((state[0UL] >> 4U) & 1U) {
          copy12 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
          copy14 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy14;
          copy14 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy14;
        }
      } else if (state[0UL] & 1U) {
        state[0UL] <<= ((state[0UL] >> 4U) & 7U) | 1UL;
        copy15 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy15;
      } else {
        state[0UL] <<= ((state[0UL] >> 1U) & 7U) | 1UL;
      }
    } else if ((state[0UL] >> 1U) & 1U) {
      copy17 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy17;
      copy18 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy18;
    } else {
      state[0UL] <<= ((state[0UL] >> 3U) & 7U) | 1UL;
      copy19 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy19;
    }
    output[0UL] = (state[0UL] ^ 673538744UL) | 1078271868U;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  shr    $0x10,%eax
  and    $0x86006a00,%edx
  and    $0x69,%eax
  mov    %al,%dl
  xor    $0x282562b8,%edx
  or     $0x40451f7c,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy12;
  char copy13;
  char copy14;
  char copy15;
  unsigned short copy17;
  unsigned short copy18;
  char copy19;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    if ((state[0UL] >> 1U) & 1U) {
      if ((state[0UL] >> 1U) & 1U) {
        if ((state[0UL] >> 4U) & 1U) {
          copy12 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
          copy14 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy14;
          copy14 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy14;
        }
      } else if (state[0UL] & 1U) {
        state[0UL] <<= ((state[0UL] >> 4U) & 7U) | 1UL;
        copy15 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy15;
      } else {
        state[0UL] <<= ((state[0UL] >> 1U) & 7U) | 1UL;
      }
    } else if ((state[0UL] >> 1U) & 1U) {
      copy17 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy17;
      copy18 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy18;
    } else {
      state[0UL] <<= ((state[0UL] >> 3U) & 7U) | 1UL;
      copy19 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy19;
    }
    output[0UL] = (state[0UL] ^ 673538744UL) | 1078271868U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<extract_menu_item_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L26
  addq   $0x1,-0x18(%rbp)
  jmp    L26
L45:
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L45
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L40:
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L40
L17:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <copy_string@plt>
  leave
  ret
```

assistant: ```c
char *extract_menu_item_name(char *item_text) {
  char *p;
  if (*item_text == '*')
    item_text++;
  while (*item_text == ' ')
    item_text++;
  p = item_text;
  while (*p && *p != ':')
    p++;
  return copy_string(item_text, p - item_text);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extract_menu_item_name>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x2a,(%rdi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  cmpb   $0x20,(%rdi)
  jne    L42
L1:
  add    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  je     L1
L42:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  cmp    $0x3a,%al
  je     L10
  mov    %rdi,%rsi
L12:
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  je     L17
  cmp    $0x3a,%al
  jne    L12
L17:
  sub    %edi,%esi
  call   <copy_string@plt>
  add    $0x8,%rsp
  ret
L10:
  mov    %rdi,%rsi
  jmp    L17
```

assistant: ```c
char *extract_menu_item_name(char *item_text) {
  char *p;
  if (*item_text == '*')
    item_text++;
  while (*item_text == ' ')
    item_text++;
  p = item_text;
  while (*p && *p != ':')
    p++;
  return copy_string(item_text, p - item_text);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extract_menu_item_name>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2a,%al
  jne    L61
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  jne    L52
  nopw   0x0(%rax,%rax,1)
L66:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L61:
  cmp    $0x20,%al
  je     L66
L52:
  cmp    $0x3a,%al
  je     L35
  test   %al,%al
  je     L35
  mov    %rdi,%rsi
  nopw   0x0(%rax,%rax,1)
L58:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L2
  cmp    $0x3a,%al
  jne    L58
L2:
  sub    %edi,%esi
  jmp    1050 <copy_string@plt>
  nopw   0x0(%rax,%rax,1)
L35:
  xor    %esi,%esi
  jmp    1050 <copy_string@plt>
```

assistant: ```c
char *extract_menu_item_name(char *item_text) {
  char *p;
  if (*item_text == '*')
    item_text++;
  while (*item_text == ' ')
    item_text++;
  p = item_text;
  while (*p && *p != ':')
    p++;
  return copy_string(item_text, p - item_text);
}
```
user: Translate the below assembly code into C programming language:

```asm
<extract_menu_item_name>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2a,%al
  jne    L42
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  jne    L59
  nopw   0x0(%rax,%rax,1)
L63:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L42:
  cmp    $0x20,%al
  je     L63
L59:
  cmp    $0x3a,%al
  je     L47
  test   %al,%al
  je     L47
  mov    %rdi,%rsi
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L43
  cmp    $0x3a,%al
  jne    L19
L43:
  sub    %edi,%esi
  jmp    1050 <copy_string@plt>
  nopw   0x0(%rax,%rax,1)
L47:
  xor    %esi,%esi
  jmp    1050 <copy_string@plt>
```

assistant: ```c
char *extract_menu_item_name(char *item_text) {
  char *p;
  if (*item_text == '*')
    item_text++;
  while (*item_text == ' ')
    item_text++;
  p = item_text;
  while (*p && *p != ':')
    p++;
  return copy_string(item_text, p - item_text);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_only_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D24
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string
name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string

tool: D24: 
Error : Your string can't be transform to a number

tool: D6:  because it contains a alphabetical caracter

tool: D18: 
The only available caracter 

tool: D2: are digit



assistant: ```c
void print_only_number() {
  my_putstr("\nError : Your string can't be transform to a number");
  my_putstr(" because it contains a alphabetical caracter");
  my_putstr("\nThe only available caracter ");
  my_putstr("are digit\n\n");
  exit(-1);
}
```