ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<rtcGetDateTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  nop
L4:
  mov    $0x40010048,%eax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L4
  mov    $0x40010a20,%eax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x40010a24,%eax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  shr    $0x18,%eax
  and    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  shr    $0x10,%eax
  and    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  shr    $0x8,%eax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int rtcGetDateTime(unsigned int *year, unsigned int *month, unsigned int *day, unsigned int *hour, unsigned int *minute, unsigned int *second) {
  while ((*((volatile unsigned int *const)((0x40010000 + 0) + 0x48))))
    ;
  ;
  unsigned int tim0 = (*((volatile unsigned int *const)(0x40010a00 + 0x20)));
  unsigned int tim1 = (*((volatile unsigned int *const)(0x40010a00 + 0x24)));
  *year = tim1 >> 16;
  *month = (tim1 >> 8) & 0x0f;
  *day = (tim0 >> 24) & 0x1f;
  *hour = (tim0 >> 16) & 0x1f;
  *minute = (tim0 >> 8) & 0x3f;
  *second = tim0 & 0x3f;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rtcGetDateTime>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%rdi
  mov    %rdx,%rsi
L6:
  mov    0x40010048,%eax
  test   %eax,%eax
  jne    L6
  mov    0x40010a20,%eax
  mov    0x40010a24,%edx
  mov    %edx,%r11d
  shr    $0x10,%r11d
  mov    %r11d,(%r10)
  shr    $0x8,%edx
  and    $0xf,%edx
  mov    %edx,(%rdi)
  mov    %eax,%edx
  shr    $0x18,%edx
  and    $0x1f,%edx
  mov    %edx,(%rsi)
  mov    %eax,%edx
  shr    $0x10,%edx
  and    $0x1f,%edx
  mov    %edx,(%rcx)
  mov    %eax,%edx
  shr    $0x8,%edx
  and    $0x3f,%edx
  mov    %edx,(%r8)
  and    $0x3f,%eax
  mov    %eax,(%r9)
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int rtcGetDateTime(unsigned int *year, unsigned int *month, unsigned int *day, unsigned int *hour, unsigned int *minute, unsigned int *second) {
  while ((*((volatile unsigned int *const)((0x40010000 + 0) + 0x48))))
    ;
  ;
  unsigned int tim0 = (*((volatile unsigned int *const)(0x40010a00 + 0x20)));
  unsigned int tim1 = (*((volatile unsigned int *const)(0x40010a00 + 0x24)));
  *year = tim1 >> 16;
  *month = (tim1 >> 8) & 0x0f;
  *day = (tim0 >> 24) & 0x1f;
  *hour = (tim0 >> 16) & 0x1f;
  *minute = (tim0 >> 8) & 0x3f;
  *second = tim0 & 0x3f;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rtcGetDateTime>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  nopl   (%rax)
L2:
  mov    0x40010048,%eax
  test   %eax,%eax
  jne    L2
  mov    0x40010a20,%eax
  mov    0x40010a24,%edx
  mov    %edx,%r11d
  shr    $0x8,%edx
  and    $0xf,%edx
  shr    $0x10,%r11d
  mov    %r11d,(%r10)
  mov    %edx,(%rdi)
  mov    %eax,%edx
  shr    $0x18,%edx
  and    $0x1f,%edx
  mov    %edx,(%rsi)
  mov    %eax,%edx
  shr    $0x10,%edx
  and    $0x1f,%edx
  mov    %edx,(%rcx)
  mov    %eax,%edx
  and    $0x3f,%eax
  shr    $0x8,%edx
  and    $0x3f,%edx
  mov    %edx,(%r8)
  mov    %eax,(%r9)
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int rtcGetDateTime(unsigned int *year, unsigned int *month, unsigned int *day, unsigned int *hour, unsigned int *minute, unsigned int *second) {
  while ((*((volatile unsigned int *const)((0x40010000 + 0) + 0x48))))
    ;
  ;
  unsigned int tim0 = (*((volatile unsigned int *const)(0x40010a00 + 0x20)));
  unsigned int tim1 = (*((volatile unsigned int *const)(0x40010a00 + 0x24)));
  *year = tim1 >> 16;
  *month = (tim1 >> 8) & 0x0f;
  *day = (tim0 >> 24) & 0x1f;
  *hour = (tim0 >> 16) & 0x1f;
  *minute = (tim0 >> 8) & 0x3f;
  *second = tim0 & 0x3f;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rtcGetDateTime>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  nopl   (%rax)
L6:
  mov    0x40010048,%eax
  test   %eax,%eax
  jne    L6
  mov    0x40010a20,%eax
  mov    0x40010a24,%edx
  mov    %edx,%r11d
  shr    $0x8,%edx
  and    $0xf,%edx
  shr    $0x10,%r11d
  mov    %r11d,(%r10)
  mov    %edx,(%rdi)
  mov    %eax,%edx
  shr    $0x18,%edx
  and    $0x1f,%edx
  mov    %edx,(%rsi)
  mov    %eax,%edx
  shr    $0x10,%edx
  and    $0x1f,%edx
  mov    %edx,(%rcx)
  mov    %eax,%edx
  and    $0x3f,%eax
  shr    $0x8,%edx
  and    $0x3f,%edx
  mov    %edx,(%r8)
  mov    %eax,(%r9)
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int rtcGetDateTime(unsigned int *year, unsigned int *month, unsigned int *day, unsigned int *hour, unsigned int *minute, unsigned int *second) {
  while ((*((volatile unsigned int *const)((0x40010000 + 0) + 0x48))))
    ;
  ;
  unsigned int tim0 = (*((volatile unsigned int *const)(0x40010a00 + 0x20)));
  unsigned int tim1 = (*((volatile unsigned int *const)(0x40010a00 + 0x24)));
  *year = tim1 >> 16;
  *month = (tim1 >> 8) & 0x0f;
  *day = (tim0 >> 24) & 0x1f;
  *hour = (tim0 >> 16) & 0x1f;
  *minute = (tim0 >> 8) & 0x3f;
  *second = tim0 & 0x3f;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L54
L59:
  cmpb   $0x60,-0x1(%rbp)
  jle    L35
  cmpb   $0x7a,-0x1(%rbp)
  jle    L87
L35:
  cmpb   $0x40,-0x1(%rbp)
  jle    L60
  cmpb   $0x5a,-0x1(%rbp)
  jg     L60
L87:
  movzbl -0x1(%rbp),%eax
  add    $0x4,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x5a,-0x1(%rbp)
  jle    L38
  cmpb   $0x60,-0x1(%rbp)
  jle    L19
L38:
  cmpb   $0x7a,-0x1(%rbp)
  jle    L60
L19:
  movzbl -0x1(%rbp),%eax
  sub    $0x1a,%eax
  mov    %al,-0x1(%rbp)
L60:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L54:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0xa,-0x1(%rbp)
  jne    L59
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: %c

assistant: ```c
main() {
  char ch;
  while ((ch = getchar()) != '\n') {
    if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z')) {
      ch += 4;
      if ((ch > 'Z' && ch < 'a') || (ch > 'z'))
        ch -= 26;
    }
    printf("%c", ch);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  jmp    L58
L39:
  lea    -0x16(%rcx),%eax
L26:
  movsbl %al,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L58:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L15
  mov    %eax,%ecx
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L26
  add    $0x4,%eax
  lea    -0x57(%rcx),%edx
  cmp    $0x5,%dl
  jbe    L39
  cmp    $0x7a,%al
  jle    L26
  jmp    L39
L15:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D4: %c

assistant: ```c
main() {
  char ch;
  while ((ch = getchar()) != '\n') {
    if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z')) {
      ch += 4;
      if ((ch > 'Z' && ch < 'a') || (ch > 'z'))
        ch -= 26;
    }
    printf("%c", ch);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  jmp    L45
  xchg   %ax,%ax
L28:
  movsbl %al,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L45:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L12
  mov    %eax,%edx
  mov    %eax,%ecx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L28
  lea    -0x57(%rcx),%edx
  add    $0x4,%eax
  cmp    $0x5,%dl
  jbe    L59
  cmp    $0x7a,%al
  jle    L28
L59:
  lea    -0x16(%rcx),%eax
  jmp    L28
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string

tool: D6: %c

assistant: ```c
main() {
  char ch;
  while ((ch = getchar()) != '\n') {
    if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z')) {
      ch += 4;
      if ((ch > 'Z' && ch < 'a') || (ch > 'z'))
        ch -= 26;
    }
    printf("%c", ch);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  jmp    L35
  xchg   %ax,%ax
L42:
  movsbl %al,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L35:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L23
  mov    %eax,%edx
  mov    %eax,%ecx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L42
  lea    -0x57(%rcx),%edx
  add    $0x4,%eax
  cmp    $0x5,%dl
  jbe    L25
  cmp    $0x7a,%al
  jle    L42
L25:
  lea    -0x16(%rcx),%eax
  jmp    L42
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: %c

assistant: ```c
main() {
  char ch;
  while ((ch = getchar()) != '\n') {
    if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z')) {
      ch += 4;
      if ((ch > 'Z' && ch < 'a') || (ch > 'z'))
        ch -= 26;
    }
    printf("%c", ch);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no, noclone)) char *fn3(char *p) {
  *p = 0;
  return p + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn3>:
  endbr64
  movb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
__attribute__((no, noclone)) char *fn3(char *p) {
  *p = 0;
  return p + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fn3>:
  endbr64
  movb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
__attribute__((no, noclone)) char *fn3(char *p) {
  *p = 0;
  return p + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn3>:
  endbr64
  movb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
__attribute__((no, noclone)) char *fn3(char *p) {
  *p = 0;
  return p + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x5,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L29
  mov    $0x0,%eax
  jmp    L16
L29:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L80
  cmpl   $0x2,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L16
L80:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L43
  cmpl   $0x3,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L16
L56:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L20
  mov    $0x0,%eax
  jmp    L16
L20:
  addl   $0x2,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L101
  mov    $0x0,%eax
  jmp    L16
L101:
  addl   $0x4,-0x4(%rbp)
L43:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L56
  mov    $0x1,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
bool is_prime(int n) {
  int i = 5;
  if (n < 2) {
    return false;
  }
  if (n % 2 == 0) {
    return n == 2;
  }
  if (n % 3 == 0) {
    return n == 3;
  }
  while (i * i <= n) {
    if (n % i == 0) {
      return false;
    }
    i += 2;
    if (n % i == 0) {
      return false;
    }
    i += 4;
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L32
  test   $0x1,%dil
  je     L48
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  je     L1
  cmp    $0x18,%edi
  jle    L87
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L32
  movslq %edi,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x2,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L32
  mov    $0x5,%esi
L13:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jg     L82
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  je     L32
  add    $0x8,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  test   %edx,%edx
  jne    L13
L32:
  ret
L48:
  cmp    $0x2,%edi
  sete   %al
  movzbl %al,%eax
  ret
L1:
  cmp    $0x3,%edi
  sete   %al
  movzbl %al,%eax
  ret
L82:
  mov    $0x1,%eax
  ret
L87:
  mov    $0x1,%eax
  jmp    L32
```

assistant: ```c
bool is_prime(int n) {
  int i = 5;
  if (n < 2) {
    return false;
  }
  if (n % 2 == 0) {
    return n == 2;
  }
  if (n % 3 == 0) {
    return n == 3;
  }
  while (i * i <= n) {
    if (n % i == 0) {
      return false;
    }
    i += 2;
    if (n % i == 0) {
      return false;
    }
    i += 4;
  }
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L61
  test   $0x1,%dil
  je     L1
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L28
  cmp    $0x18,%edi
  jle    L69
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  je     L61
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %edi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L61
  mov    $0x5,%esi
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L83:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L61
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L61
L51:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jle    L83
L69:
  mov    $0x1,%edx
L61:
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %edx,%edx
  cmp    $0x2,%edi
  sete   %dl
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %edx,%edx
  cmp    $0x3,%edi
  sete   %dl
  mov    %edx,%eax
  ret
```

assistant: ```c
bool is_prime(int n) {
  int i = 5;
  if (n < 2) {
    return false;
  }
  if (n % 2 == 0) {
    return n == 2;
  }
  if (n % 3 == 0) {
    return n == 3;
  }
  while (i * i <= n) {
    if (n % i == 0) {
      return false;
    }
    i += 2;
    if (n % i == 0) {
      return false;
    }
    i += 4;
  }
  return true;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L15
  test   $0x1,%dil
  je     L69
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L87
  cmp    $0x18,%edi
  jle    L42
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  je     L15
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %edi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L15
  mov    $0x5,%esi
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L15
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L15
L29:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jle    L61
L42:
  mov    $0x1,%edx
L15:
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  xor    %edx,%edx
  cmp    $0x2,%edi
  sete   %dl
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L87:
  xor    %edx,%edx
  cmp    $0x3,%edi
  sete   %dl
  mov    %edx,%eax
  ret
```

assistant: ```c
bool is_prime(int n) {
  int i = 5;
  if (n < 2) {
    return false;
  }
  if (n % 2 == 0) {
    return n == 2;
  }
  if (n % 3 == 0) {
    return n == 3;
  }
  while (i * i <= n) {
    if (n % i == 0) {
      return false;
    }
    i += 2;
    if (n % i == 0) {
      return false;
    }
    i += 4;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_ident>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <read_ident@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  call   <new_ident@plt>
  mov    %rax,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_ident() {
  char *buf;
  buf = read_ident();
  if (!buf) {
    buf = new_ident();
  }
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_ident>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <read_ident@plt>
  test   %rax,%rax
  je     L6
L14:
  add    $0x8,%rsp
  ret
L6:
  call   <new_ident@plt>
  jmp    L14
```

assistant: ```c
char *get_ident() {
  char *buf;
  buf = read_ident();
  if (!buf) {
    buf = new_ident();
  }
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_ident>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <read_ident@plt>
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  jmp    1070 <new_ident@plt>
```

assistant: ```c
char *get_ident() {
  char *buf;
  buf = read_ident();
  if (!buf) {
    buf = new_ident();
  }
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ident>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <read_ident@plt>
  test   %rax,%rax
  je     L3
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  jmp    1070 <new_ident@plt>
```

assistant: ```c
char *get_ident() {
  char *buf;
  buf = read_ident();
  if (!buf) {
    buf = new_ident();
  }
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: Hello, World!


assistant: ```c
int main(void) {
#pragma omp parallel
  puts("Hello, World!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string

tool: D7: Hello, World!


assistant: ```c
int main(void) {
#pragma omp parallel
  puts("Hello, World!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: Hello, World!


assistant: ```c
int main(void) {
#pragma omp parallel
  puts("Hello, World!\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string

tool: D5: Hello, World!


assistant: ```c
int main(void) {
#pragma omp parallel
  puts("Hello, World!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i2d_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  jmp    L0
L15:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L0:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void i2d_array(const int *src, double *dest, int count, double scale) {
  while (--count >= 0) {
    dest[count] = scale * src[count];
  };
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<i2d_array>:
  endbr64
  sub    $0x1,%edx
  js     L9
  movslq %edx,%rdx
L8:
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rdi,%rdx,4),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L8
L9:
  ret
```

assistant: ```c
void i2d_array(const int *src, double *dest, int count, double scale) {
  while (--count >= 0) {
    dest[count] = scale * src[count];
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2d_array>:
  endbr64
  sub    $0x1,%edx
  js     L12
  movslq %edx,%rdx
  nopl   0x0(%rax)
L14:
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rdi,%rdx,4),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L14
L12:
  ret
```

assistant: ```c
void i2d_array(const int *src, double *dest, int count, double scale) {
  while (--count >= 0) {
    dest[count] = scale * src[count];
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i2d_array>:
  endbr64
  sub    $0x1,%edx
  js     L11
  movslq %edx,%rdx
  nopl   0x0(%rax)
L9:
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rdi,%rdx,4),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L9
L11:
  ret
```

assistant: ```c
void i2d_array(const int *src, double *dest, int count, double scale) {
  while (--count >= 0) {
    dest[count] = scale * src[count];
  };
}
```