ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<StrAppendMax>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rdx,%rbp
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbx),%rdx
  sub    %rax,%rdx
  jne    L8
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strncat@plt>
```

assistant: ```c
char *StrAppendMax(char *target, size_t max, const char *source) {
  assert((0 != (target)));
  assert((0 != (source)));
  assert(max > 0);
  max -= strlen((target)) + 1;
  return (max > 0) ? strncat(target, source, max) : target;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<StrAppendMax>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rdx,%rbp
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbx),%rdx
  sub    %rax,%rdx
  jne    L6
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strncat@plt>
```

assistant: ```c
char *StrAppendMax(char *target, size_t max, const char *source) {
  assert((0 != (target)));
  assert((0 != (source)));
  assert(max > 0);
  max -= strlen((target)) + 1;
  return (max > 0) ? strncat(target, source, max) : target;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<allocateIntStarArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **allocateIntStarArray(int num) {
  int **ptr = (int **)malloc(num * sizeof(int *));
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<allocateIntStarArray>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x3,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int **allocateIntStarArray(int num) {
  int **ptr = (int **)malloc(num * sizeof(int *));
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<allocateIntStarArray>:
  endbr64
  shl    $0x3,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
int **allocateIntStarArray(int num) {
  int **ptr = (int **)malloc(num * sizeof(int *));
  return ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0xb,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L5:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L18:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(char word[]) {
  unsigned int h = 11;
  for (int i = 0; word[i] != '\n' && word[i] != '\0'; i++) {
    h = h * 31 + word[i];
  }
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xa,%al
  je     L18
  test   %al,%al
  je     L18
  add    $0x1,%rdi
  mov    $0xb,%ecx
L35:
  mov    %ecx,%edx
  shl    $0x5,%edx
  sub    %ecx,%edx
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%ecx
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  cmp    $0xa,%al
  je     L11
  test   %al,%al
  jne    L35
L11:
  mov    %ecx,%eax
  ret
L18:
  mov    $0xb,%ecx
  jmp    L11
```

assistant: ```c
unsigned int hash(char word[]) {
  unsigned int h = 11;
  for (int i = 0; word[i] != '\n' && word[i] != '\0'; i++) {
    h = h * 31 + word[i];
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0xa,%al
  je     L38
  test   %al,%al
  je     L38
  add    $0x1,%rdi
  mov    $0xb,%r8d
  nopl   0x0(%rax)
L7:
  mov    %r8d,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %r8d,%edx
  lea    (%rax,%rdx,1),%r8d
  movsbl -0x1(%rdi),%eax
  cmp    $0xa,%al
  je     L8
  test   %al,%al
  jne    L7
L8:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L38:
  mov    $0xb,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int hash(char word[]) {
  unsigned int h = 11;
  for (int i = 0; word[i] != '\n' && word[i] != '\0'; i++) {
    h = h * 31 + word[i];
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0xa,%al
  je     L33
  test   %al,%al
  je     L33
  add    $0x1,%rdi
  mov    $0xb,%r8d
  nopl   0x0(%rax)
L23:
  mov    %r8d,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %r8d,%edx
  lea    (%rax,%rdx,1),%r8d
  movsbl -0x1(%rdi),%eax
  cmp    $0xa,%al
  je     L7
  test   %al,%al
  jne    L23
L7:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L33:
  mov    $0xb,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int hash(char word[]) {
  unsigned int h = 11;
  for (int i = 0; word[i] != '\n' && word[i] != '\0'; i++) {
    h = h * 31 + word[i];
  }
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L17:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L5
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
L5:
  addl   $0x1,-0x10(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L17
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string
name: unpack_data
arguments: label: D29
datatype: string

tool: D7: %d

tool: D29: %d


assistant: ```c
int main() {
  int n, soma, repeticao, acumulador;
  scanf("%d", &n);
  for (repeticao = 0; repeticao < n; repeticao++) {
    scanf("%d", &soma);
    if (soma % 2 == 0) {
      acumulador += soma;
    }
  }
  printf("%d\n", acumulador);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L1
  mov    $0x0,%ebp
  lea    D24(%rip),%r12
L2:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rbx,%rax,1),%edx
  test   $0x1,%al
  cmove  %edx,%ebx
  add    $0x1,%ebp
  cmp    %ebp,(%rsp)
  jg     L2
L1:
  mov    %ebx,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D24
type_guessed: string
name: read_data
arguments: tag: D18
type_guessed: string

tool: D24: %d

tool: D18: %d


assistant: ```c
int main() {
  int n, soma, repeticao, acumulador;
  scanf("%d", &n);
  for (repeticao = 0; repeticao < n; repeticao++) {
    scanf("%d", &soma);
    if (soma % 2 == 0) {
      acumulador += soma;
    }
  }
  printf("%d\n", acumulador);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L8
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r13
  xchg   %ax,%ax
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   $0x1,%al
  lea    0x0(%rbp,%rax,1),%edx
  cmove  %edx,%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L7
L8:
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type_guessed: string
name: retrieve_data
arguments: label: D16
type_guessed: string

tool: D10: %d

tool: D16: %d


assistant: ```c
int main() {
  int n, soma, repeticao, acumulador;
  scanf("%d", &n);
  for (repeticao = 0; repeticao < n; repeticao++) {
    scanf("%d", &soma);
    if (soma % 2 == 0) {
      acumulador += soma;
    }
  }
  printf("%d\n", acumulador);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L20
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r13
  xchg   %ax,%ax
L14:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   $0x1,%al
  lea    0x0(%rbp,%rax,1),%edx
  cmove  %edx,%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L14
L20:
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string

tool: D4: %d

tool: D18: %d


assistant: ```c
int main() {
  int n, soma, repeticao, acumulador;
  scanf("%d", &n);
  for (repeticao = 0; repeticao < n; repeticao++) {
    scanf("%d", &soma);
    if (soma % 2 == 0) {
      acumulador += soma;
    }
  }
  printf("%d\n", acumulador);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findsym>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <findloc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L17
  mov    -0x4(%rbp),%eax
  jmp    L0
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <findglob@plt>
L0:
  leave
  ret
```

assistant: ```c
int findsym(char *s) {
  int y;
  if ((y = findloc(s)) != 0)
    return y;
  return findglob(s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findsym>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <findloc@plt>
  test   %eax,%eax
  je     L7
L11:
  pop    %rbx
  ret
L7:
  mov    %rbx,%rdi
  call   <findglob@plt>
  jmp    L11
```

assistant: ```c
int findsym(char *s) {
  int y;
  if ((y = findloc(s)) != 0)
    return y;
  return findglob(s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<findsym>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <findloc@plt>
  test   %eax,%eax
  je     L1
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <findglob@plt>
```

assistant: ```c
int findsym(char *s) {
  int y;
  if ((y = findloc(s)) != 0)
    return y;
  return findglob(s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<findsym>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <findloc@plt>
  test   %eax,%eax
  je     L9
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <findglob@plt>
```

assistant: ```c
int findsym(char *s) {
  int y;
  if ((y = findloc(s)) != 0)
    return y;
  return findglob(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %rdi,-0x2038(%rbp)
  mov    %rsi,-0x2040(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2038(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x2030(%rbp)
  cmpq   $0x0,-0x2030(%rbp)
  jne    L11
  mov    $0xffffffff,%eax
  jmp    L1
L11:
  mov    -0x2040(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x2028(%rbp)
  cmpq   $0x0,-0x2028(%rbp)
  jne    L82
  mov    -0x2030(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0xfffffffe,%eax
  jmp    L1
L54:
  mov    -0x2028(%rbp),%rcx
  mov    -0x2020(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %rax,-0x2018(%rbp)
  cmpq   $0x0,-0x2018(%rbp)
  je     L43
  mov    -0x2018(%rbp),%rax
  cmp    -0x2020(%rbp),%rax
  jae    L82
L43:
  mov    -0x2030(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x2028(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  cmpq   $0x0,-0x2018(%rbp)
  jne    L77
  mov    $0xfffffffd,%eax
  jmp    L1
L77:
  mov    $0xfffffffc,%eax
  jmp    L1
L82:
  mov    -0x2030(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x2000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x2020(%rbp)
  cmpq   $0x0,-0x2020(%rbp)
  jne    L54
  mov    -0x2030(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x2028(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L71
  call   <__stack_chk_fail@plt>
L71:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string
name: unpack_data
arguments: data_label: D13
type: string

tool: D9: r

tool: D13: w

assistant: ```c
int copy(const char *fn_in, const char *fn_out) {
  FILE *fd1 = fopen(fn_in, "r");
  if (!fd1)
    return -1;
  FILE *fd2 = fopen(fn_out, "w");
  if (!fd2) {
    fclose(fd1);
    return -2;
  }
  size_t l1;
  unsigned char buffer[8192];
  while ((l1 = fread(buffer, 1, sizeof buffer, fd1)) > 0) {
    size_t l2 = fwrite(buffer, 1, l1, fd2);
    if (l2 == 0 || l2 < l1) {
      fclose(fd1);
      fclose(fd2);
      if (l2 == 0)
        return -3;
      return -4;
    }
  }
  fclose(fd1);
  fclose(fd2);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L69
  mov    %rax,%r13
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L2
  mov    %rsp,%r12
L11:
  mov    %r13,%rcx
  mov    $0x2000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L57
  mov    %r14,%rcx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L59
  cmp    %rax,%rbx
  jbe    L11
L59:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  cmp    $0x1,%rbp
  mov    $0xfffffffc,%eax
  adc    $0x0,%eax
  jmp    L84
L2:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    $0xfffffffe,%eax
  jmp    L84
L57:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L84:
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L67
  add    $0x2010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L69:
  mov    $0xffffffff,%eax
  jmp    L84
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D7: r

tool: D3: w

assistant: ```c
int copy(const char *fn_in, const char *fn_out) {
  FILE *fd1 = fopen(fn_in, "r");
  if (!fd1)
    return -1;
  FILE *fd2 = fopen(fn_out, "w");
  if (!fd2) {
    fclose(fd1);
    return -2;
  }
  size_t l1;
  unsigned char buffer[8192];
  while ((l1 = fread(buffer, 1, sizeof buffer, fd1)) > 0) {
    size_t l2 = fwrite(buffer, 1, l1, fd2);
    if (l2 == 0 || l2 < l1) {
      fclose(fd1);
      fclose(fd2);
      if (l2 == 0)
        return -3;
      return -4;
    }
  }
  fclose(fd1);
  fclose(fd2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbp
  lea    D14(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L48
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L90
  mov    %rsp,%r12
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %r14,%rcx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L79
  cmp    %rax,%rbx
  ja     L79
L7:
  mov    %r13,%rcx
  mov    $0x2000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L27
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L63:
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  add    $0x2010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  cmp    $0x1,%rbp
  mov    $0xfffffffc,%eax
  adc    $0x0,%eax
  jmp    L63
L48:
  mov    $0xffffffff,%eax
  jmp    L63
L90:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    $0xfffffffe,%eax
  jmp    L63
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D14: r

tool: D6: w

assistant: ```c
int copy(const char *fn_in, const char *fn_out) {
  FILE *fd1 = fopen(fn_in, "r");
  if (!fd1)
    return -1;
  FILE *fd2 = fopen(fn_out, "w");
  if (!fd2) {
    fclose(fd1);
    return -2;
  }
  size_t l1;
  unsigned char buffer[8192];
  while ((l1 = fread(buffer, 1, sizeof buffer, fd1)) > 0) {
    size_t l2 = fwrite(buffer, 1, l1, fd2);
    if (l2 == 0 || l2 < l1) {
      fclose(fd1);
      fclose(fd2);
      if (l2 == 0)
        return -3;
      return -4;
    }
  }
  fclose(fd1);
  fclose(fd2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbp
  lea    D18(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L70
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L45
  mov    %rsp,%r12
  jmp    L94
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %r14,%rcx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L21
  cmp    %rax,%rbx
  ja     L21
L94:
  mov    %r13,%rcx
  mov    $0x2000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L25
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L87:
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L65
  add    $0x2010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  cmp    $0x1,%rbp
  mov    $0xfffffffc,%eax
  adc    $0x0,%eax
  jmp    L87
L70:
  mov    $0xffffffff,%eax
  jmp    L87
L45:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    $0xfffffffe,%eax
  jmp    L87
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
data_type: string
name: retrieve_data
arguments: data_tag: D12
data_type: string

tool: D18: r

tool: D12: w

assistant: ```c
int copy(const char *fn_in, const char *fn_out) {
  FILE *fd1 = fopen(fn_in, "r");
  if (!fd1)
    return -1;
  FILE *fd2 = fopen(fn_out, "w");
  if (!fd2) {
    fclose(fd1);
    return -2;
  }
  size_t l1;
  unsigned char buffer[8192];
  while ((l1 = fread(buffer, 1, sizeof buffer, fd1)) > 0) {
    size_t l2 = fwrite(buffer, 1, l1, fd2);
    if (l2 == 0 || l2 < l1) {
      fclose(fd1);
      fclose(fd2);
      if (l2 == 0)
        return -3;
      return -4;
    }
  }
  fclose(fd1);
  fclose(fd2);
  return 0;
}
```