ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<searchOne>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r14d
  mov    %eax,0x4(%rsp)
  call   <strlen@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  cmp    %ebx,%r14d
  jl     L63
  xor    %r13d,%r13d
  xor    %r15d,%r15d
  lea    D40(%rip),%r14
  jmp    L34
  nop
L1:
  test   %r13d,%r13d
  jle    L2
  mov    0x8(%rsp),%rcx
  mov    (%rcx,%rax,4),%r13d
L72:
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    (%r15,%rbx,1),%eax
  sub    %r13d,%eax
  cmp    0x4(%rsp),%eax
  jg     L63
L34:
  movslq %r13d,%rax
  movslq %r15d,%rcx
  movzbl (%r12,%rax,1),%edx
  cmp    %dl,0x0(%rbp,%rcx,1)
  jne    L1
  add    $0x1,%r13d
  lea    0x1(%r15),%esi
  cmp    %r13d,%ebx
  jle    L76
  mov    %esi,%r15d
  jmp    L72
  xchg   %ax,%ax
L2:
  add    $0x1,%r15d
  jmp    L72
  cs nopw 0x0(%rax,%rax,1)
L63:
  add    $0x18,%rsp
  lea    D49(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L76:
  add    $0x18,%rsp
  sub    %ebx,%esi
  mov    %r15d,%edx
  xor    %eax,%eax
  pop    %rbx
  lea    D29(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D26
datatype: string
name: retrieve_data
arguments: data_tag: D40
datatype: string
name: retrieve_data
arguments: data_tag: D49
datatype: string
name: retrieve_data
arguments: data_tag: D29
datatype: string

tool: D8:    i   j

tool: D26: ----------

tool: D40:  %3d %3d


tool: D49: Not found.

tool: D29: Position = %d - %d


assistant: ```c
void searchOne(char *source, char *key, int *next) {
  int sourceLength = strlen(source);
  int keyLength = strlen(key);
  int i = 0;
  int j = 0;
  int found = 0;
  printf("   i   j\n");
  printf("----------\n");
  while ((i + keyLength - j) <= sourceLength) {
    if (source[i] == key[j]) {
      i++;
      j++;
      if (j >= keyLength) {
        found = 1;
        break;
      }
    } else if (j > 0) {
      j = next[j];
    } else {
      i++;
    }
    printf(" %3d %3d\n", i, j);
  }
  if (found == 1) {
    printf("Position = %d - %d\n", i - keyLength, i - 1);
  } else {
    printf("Not found.\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<searchOne>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r14d
  mov    %eax,0x4(%rsp)
  call   <strlen@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  cmp    %ebx,%r14d
  jl     L8
  xor    %r13d,%r13d
  xor    %r15d,%r15d
  lea    D25(%rip),%r14
  jmp    L63
  nop
L54:
  test   %r13d,%r13d
  jle    L24
  mov    0x8(%rsp),%rcx
  mov    (%rcx,%rax,4),%r13d
L17:
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    (%r15,%rbx,1),%eax
  sub    %r13d,%eax
  cmp    0x4(%rsp),%eax
  jg     L8
L63:
  movslq %r13d,%rax
  movslq %r15d,%rcx
  movzbl (%r12,%rax,1),%edx
  cmp    %dl,0x0(%rbp,%rcx,1)
  jne    L54
  add    $0x1,%r13d
  lea    0x1(%r15),%esi
  cmp    %r13d,%ebx
  jle    L47
  mov    %esi,%r15d
  jmp    L17
  xchg   %ax,%ax
L24:
  add    $0x1,%r15d
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x18,%rsp
  lea    D29(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L47:
  add    $0x18,%rsp
  sub    %ebx,%esi
  mov    %r15d,%edx
  xor    %eax,%eax
  pop    %rbx
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D45
data_type: string
name: extract_symbolic_data
arguments: data_label: D25
data_type: string
name: extract_symbolic_data
arguments: data_label: D29
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D14:    i   j

tool: D45: ----------

tool: D25:  %3d %3d


tool: D29: Not found.

tool: D2: Position = %d - %d


assistant: ```c
void searchOne(char *source, char *key, int *next) {
  int sourceLength = strlen(source);
  int keyLength = strlen(key);
  int i = 0;
  int j = 0;
  int found = 0;
  printf("   i   j\n");
  printf("----------\n");
  while ((i + keyLength - j) <= sourceLength) {
    if (source[i] == key[j]) {
      i++;
      j++;
      if (j >= keyLength) {
        found = 1;
        break;
      }
    } else if (j > 0) {
      j = next[j];
    } else {
      i++;
    }
    printf(" %3d %3d\n", i, j);
  }
  if (found == 1) {
    printf("Position = %d - %d\n", i - keyLength, i - 1);
  } else {
    printf("Not found.\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gDouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: %lf

assistant: ```c
double gDouble() {
  double i;
  scanf("%lf", &i);
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gDouble>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1: %lf

assistant: ```c
double gDouble() {
  double i;
  scanf("%lf", &i);
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gDouble>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: %lf

assistant: ```c
double gDouble() {
  double i;
  scanf("%lf", &i);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gDouble>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3: %lf

assistant: ```c
double gDouble() {
  double i;
  scanf("%lf", &i);
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cleanup_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <net_cleanup@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void cleanup_exit(int err) {
  net_cleanup();
  exit(err);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cleanup_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <net_cleanup@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void cleanup_exit(int err) {
  net_cleanup();
  exit(err);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cleanup_exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <net_cleanup@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <exit@plt>
```

assistant: ```c
void cleanup_exit(int err) {
  net_cleanup();
  exit(err);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cleanup_exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <net_cleanup@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <exit@plt>
```

assistant: ```c
void cleanup_exit(int err) {
  net_cleanup();
  exit(err);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: Hello from deeper.c


assistant: ```c
int main(void) {
  printf("Hello from deeper.c\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: Hello from deeper.c


assistant: ```c
int main(void) {
  printf("Hello from deeper.c\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: Hello from deeper.c


assistant: ```c
int main(void) {
  printf("Hello from deeper.c\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: Hello from deeper.c


assistant: ```c
int main(void) {
  printf("Hello from deeper.c\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_ccache_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L37
  mov    $0x1,%eax
  jmp    L9
L37:
  mov    -0x8(%rbp),%rax
  mov    $0xf,%edx
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x1,%eax
  jmp    L9
L32:
  mov    $0x0,%eax
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D16
type_infered: string

tool: D1: /.ccache

tool: D16: /tmp/.icecream-

assistant: ```c
int is_ccache_path(const char *path) {
  if (strstr(path, "/.ccache") != NULL)
    return 1;
  if (strncmp(path, "/tmp/.icecream-", 15) == 0)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_ccache_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D17(%rip),%rsi
  call   <strstr@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L9
L1:
  pop    %rbx
  ret
L9:
  mov    $0xf,%edx
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L1
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string

tool: D17: /.ccache

tool: D5: /tmp/.icecream-

assistant: ```c
int is_ccache_path(const char *path) {
  if (strstr(path, "/.ccache") != NULL)
    return 1;
  if (strncmp(path, "/tmp/.icecream-", 15) == 0)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_ccache_path>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rsi
  mov    %rdi,%rbp
  call   <strstr@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L7
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  mov    $0xf,%edx
  lea    D19(%rip),%rsi
  call   <strncmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D19
type: string

tool: D18: /.ccache

tool: D19: /tmp/.icecream-

assistant: ```c
int is_ccache_path(const char *path) {
  if (strstr(path, "/.ccache") != NULL)
    return 1;
  if (strncmp(path, "/tmp/.icecream-", 15) == 0)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_ccache_path>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rsi
  mov    %rdi,%rbp
  call   <strstr@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L8
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  mov    $0xf,%edx
  lea    D16(%rip),%rsi
  call   <strncmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D16
data_type: string

tool: D14: /.ccache

tool: D16: /tmp/.icecream-

assistant: ```c
int is_ccache_path(const char *path) {
  if (strstr(path, "/.ccache") != NULL)
    return 1;
  if (strncmp(path, "/tmp/.icecream-", 15) == 0)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L36
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L36
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L36:
  addq   $0x1,-0x18(%rbp)
L31:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strlwr(char *s) {
  char *p = s;
  while (*s) {
    if ((*s >= 'A') && (*s <= 'Z'))
      *s += 'a' - 'A';
    s++;
  }
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strlwr>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L10
  mov    %rdi,%rcx
  jmp    L16
L3:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L10
L16:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L3
  add    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L3
L10:
  ret
```

assistant: ```c
char *strlwr(char *s) {
  char *p = s;
  while (*s) {
    if ((*s >= 'A') && (*s <= 'Z'))
      *s += 'a' - 'A';
    s++;
  }
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlwr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L15
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L22:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L12
  add    $0x20,%edx
  mov    %dl,(%rcx)
L12:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L22
L15:
  ret
```

assistant: ```c
char *strlwr(char *s) {
  char *p = s;
  while (*s) {
    if ((*s >= 'A') && (*s <= 'Z'))
      *s += 'a' - 'A';
    s++;
  }
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlwr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L29
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L4:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L31
  add    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L4
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L4
L29:
  ret
```

assistant: ```c
char *strlwr(char *s) {
  char *p = s;
  while (*s) {
    if ((*s >= 'A') && (*s <= 'Z'))
      *s += 'a' - 'A';
    s++;
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3f8(%rbp)
  jmp    L26
L4:
  cmpl   $0xa,-0x3f4(%rbp)
  je     L13
  mov    -0x3f4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x3f8(%rbp),%eax
  cltq
  mov    %dl,-0x3f0(%rbp,%rax,1)
  addl   $0x1,-0x3f8(%rbp)
  jmp    L26
L13:
  mov    -0x3f8(%rbp),%eax
  cltq
  movb   $0x0,-0x3f0(%rbp,%rax,1)
  movl   $0x0,-0x3f8(%rbp)
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse_string@plt>
L26:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x3f4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x3f4(%rbp)
  jne    L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int main(void) {
  char line[1000];
  int character;
  int index = 0;
  while ((character = getchar()) != EOF) {
    if (character != '\n') {
      line[index] = character;
      index++;
    } else {
      line[index] = '\0';
      index = 0;
      reverse_string(line);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L32
L7:
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  mov    %rbp,%rdi
  call   <reverse_string@plt>
  mov    $0x0,%ebx
L32:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L27
  cmp    $0xa,%eax
  je     L7
  movslq %ebx,%rdx
  mov    %al,(%rsp,%rdx,1)
  add    $0x1,%ebx
  jmp    L32
L27:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char line[1000];
  int character;
  int index = 0;
  while ((character = getchar()) != EOF) {
    if (character != '\n') {
      line[index] = character;
      index++;
    } else {
      line[index] = '\0';
      index = 0;
      reverse_string(line);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x3f0,%rsp
  mov    D3(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
L14:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  je     L30
L28:
  cmp    $0xa,%eax
  je     L29
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %al,(%rsp,%rdx,1)
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L28
L30:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L29:
  movslq %ebx,%rbx
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  xor    %ebx,%ebx
  call   <reverse_string@plt>
  jmp    L14
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char line[1000];
  int character;
  int index = 0;
  while ((character = getchar()) != EOF) {
    if (character != '\n') {
      line[index] = character;
      index++;
    } else {
      line[index] = '\0';
      index = 0;
      reverse_string(line);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x3f0,%rsp
  mov    D6(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
L27:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  je     L37
L21:
  cmp    $0xa,%eax
  je     L49
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %al,(%rsp,%rdx,1)
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L21
L37:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L49:
  movslq %ebx,%rbx
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  xor    %ebx,%ebx
  call   <reverse_string@plt>
  jmp    L27
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char line[1000];
  int character;
  int index = 0;
  while ((character = getchar()) != EOF) {
    if (character != '\n') {
      line[index] = character;
      index++;
    } else {
      line[index] = '\0';
      index = 0;
      reverse_string(line);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D59
type_infered: string
name: extract_symbolic_data
arguments: data_label: D42
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D57
type_infered: string
name: extract_symbolic_data
arguments: data_label: D23
type_infered: string

tool: D59: clp (coherent logic prover) 0.10


tool: D42: Copyright (C) 2011, 2012 University of Oslo and/or Dag Hovland.


tool: D6: This is free software.  You may redistribute copies of it under the terms of


tool: D18: the GNU General Public License <http://www.gnu.org/licenses/gpl.html>.


tool: D57: There is NO WARRANTY, to the extent permitted by law.



tool: D23: Written by Dag Hovland.


assistant: ```c
void print_version() {
  printf("clp (coherent logic prover) 0.10\n");
  printf("Copyright (C) 2011, 2012 University of Oslo and/or Dag Hovland.\n");
  printf("This is free software.  You may redistribute copies of it under the terms of\n");
  printf("the GNU General Public License <http://www.gnu.org/licenses/gpl.html>.\n");
  printf("There is NO WARRANTY, to the extent permitted by law.\n\n");
  printf("Written by Dag Hovland.\n");
}
```