ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<GetOctOrDec>:
  endbr64
  sub    $0x8,%rsp
  movzbl (%rdi),%ecx
  mov    %rdi,%r9
  lea    -0x2b(%rcx),%eax
  test   $0xfd,%al
  jne    L45
  movzbl 0x1(%r9),%ecx
  lea    0x1(%rdi),%rdi
  test   %cl,%cl
  je     L21
L31:
  mov    %rdi,%r8
  mov    %ecx,%eax
  jmp    L79
  nopl   0x0(%rax)
L70:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  test   %al,%al
  je     L164
L79:
  sub    $0x30,%eax
  cmp    $0x7,%al
  jbe    L70
L103:
  xor    %r8d,%r8d
  jmp    L48
  nopl   (%rax)
L91:
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%al
  ja     L46
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  je     L105
L48:
  lea    -0x38(%rcx),%eax
  cmp    $0x1,%al
  ja     L91
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  mov    $0x1,%r8d
  test   %cl,%cl
  jne    L48
L105:
  mov    $0x1,%eax
L144:
  test   %r8d,%r8d
  je     L36
  test   %al,%al
  jne    L17
L36:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L45:
  test   %cl,%cl
  jne    L31
  jmp    L36
  cs nopw 0x0(%rax,%rax,1)
L46:
  cmp    $0x44,%cl
  jne    L137
  cmpb   $0x0,0x1(%rdi)
  jne    L36
  cmp    %rdi,%r9
  je     L36
L17:
  mov    %rsi,%rdx
  mov    %r9,%rdi
  lea    D16(%rip),%rsi
  call   <sscanf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L164:
  cmp    %r8,%r9
  je     L103
L21:
  mov    %rsi,%rdx
  mov    %r9,%rdi
  lea    D19(%rip),%rsi
  call   <sscanf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L137:
  xor    %eax,%eax
  jmp    L144
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D16: %d

tool: D19: %o

assistant: ```c
int GetOctOrDec(const char *s, int *Value) {
  const char *ss;
  int has_8_or_9 = 0;
  ss = s;
  if (*ss == '+' || *ss == '-')
    ss++;
  for (; *ss; ss++)
    if (*ss < '0' || *ss > '7')
      break;
  if (!*ss && ss != s) {
    sscanf(s, "%o", Value);
    return (0);
  }
  ss = s;
  if (*ss == '+' || *ss == '-')
    ss++;
  for (; *ss; ss++)
    if (*ss == '8' || *ss == '9')
      has_8_or_9 = 1;
    else if (*ss < '0' || *ss > '9')
      break;
  if ((*ss == 'D' && ss[1] == 0 && ss != s) || (has_8_or_9 && ss[0] == 0)) {
    sscanf(s, "%d", Value);
    return (0);
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetOctOrDec>:
  endbr64
  sub    $0x8,%rsp
  movzbl (%rdi),%ecx
  mov    %rdi,%r9
  lea    -0x2b(%rcx),%eax
  test   $0xfd,%al
  jne    L176
  movzbl 0x1(%r9),%ecx
  lea    0x1(%rdi),%rdi
  test   %cl,%cl
  je     L151
L105:
  mov    %rdi,%r8
  mov    %ecx,%eax
  jmp    L13
  nopl   0x0(%rax)
L134:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  test   %al,%al
  je     L23
L13:
  sub    $0x30,%eax
  cmp    $0x7,%al
  jbe    L134
L44:
  xor    %r8d,%r8d
  jmp    L175
  nopl   (%rax)
L55:
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%al
  ja     L188
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  je     L129
L175:
  lea    -0x38(%rcx),%eax
  cmp    $0x1,%al
  ja     L55
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  mov    $0x1,%r8d
  test   %cl,%cl
  jne    L175
L129:
  mov    $0x1,%eax
L186:
  test   %r8d,%r8d
  je     L93
  test   %al,%al
  jne    L36
L93:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L176:
  test   %cl,%cl
  jne    L105
  jmp    L93
  cs nopw 0x0(%rax,%rax,1)
L188:
  cmp    $0x44,%cl
  jne    L22
  cmpb   $0x0,0x1(%rdi)
  jne    L93
  cmp    %rdi,%r9
  je     L93
L36:
  mov    %rsi,%rdx
  mov    %r9,%rdi
  lea    D10(%rip),%rsi
  call   <sscanf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L23:
  cmp    %r8,%r9
  je     L44
L151:
  mov    %rsi,%rdx
  mov    %r9,%rdi
  lea    D19(%rip),%rsi
  call   <sscanf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L22:
  xor    %eax,%eax
  jmp    L186
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D10: %d

tool: D19: %o

assistant: ```c
int GetOctOrDec(const char *s, int *Value) {
  const char *ss;
  int has_8_or_9 = 0;
  ss = s;
  if (*ss == '+' || *ss == '-')
    ss++;
  for (; *ss; ss++)
    if (*ss < '0' || *ss > '7')
      break;
  if (!*ss && ss != s) {
    sscanf(s, "%o", Value);
    return (0);
  }
  ss = s;
  if (*ss == '+' || *ss == '-')
    ss++;
  for (; *ss; ss++)
    if (*ss == '8' || *ss == '9')
      has_8_or_9 = 1;
    else if (*ss < '0' || *ss > '9')
      break;
  if ((*ss == 'D' && ss[1] == 0 && ss != s) || (has_8_or_9 && ss[0] == 0)) {
    sscanf(s, "%d", Value);
    return (0);
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<disemvowel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L45
L14:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  movsbl -0x19(%rbp),%eax
  mov    %eax,%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L30
  subl   $0x1,-0x18(%rbp)
L30:
  addl   $0x1,-0x14(%rbp)
L45:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L14
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L20:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  movsbl -0x19(%rbp),%eax
  mov    %eax,%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  jne    L12
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x19(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L12:
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L20
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *disemvowel(char *str) {
  int lenStr = strlen(str);
  int lenStrNoVowels = lenStr;
  char *result;
  int i;
  char c;
  for (i = 0; i < lenStr; i++) {
    c = str[i];
    if (is_vowel(c)) {
      lenStrNoVowels--;
    }
  }
  result = (char *)calloc(lenStrNoVowels + 1, sizeof(char));
  int resultIndex = 0;
  for (i = 0; i < lenStr; i++) {
    c = str[i];
    if (!is_vowel(c)) {
      result[resultIndex] = c;
      resultIndex++;
    }
  }
  result[lenStrNoVowels] = '\0';
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<disemvowel>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L45
  mov    %rbx,%rbp
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%r13
L39:
  movsbl (%rbx),%edi
  call   <is_vowel@plt>
  cmp    $0x1,%rax
  adc    $0xffffffff,%r12d
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L39
  lea    0x1(%r12),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r15
  mov    $0x0,%r14d
  jmp    L31
L17:
  add    $0x1,%rbp
  cmp    %r13,%rbp
  je     L52
L31:
  movzbl 0x0(%rbp),%ebx
  movsbl %bl,%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  jne    L17
  movslq %r14d,%rax
  mov    %bl,(%r15,%rax,1)
  add    $0x1,%r14d
  jmp    L17
L45:
  lea    0x1(%rax),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r15
L52:
  movslq %r12d,%r12
  movb   $0x0,(%r15,%r12,1)
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *disemvowel(char *str) {
  int lenStr = strlen(str);
  int lenStrNoVowels = lenStr;
  char *result;
  int i;
  char c;
  for (i = 0; i < lenStr; i++) {
    c = str[i];
    if (is_vowel(c)) {
      lenStrNoVowels--;
    }
  }
  result = (char *)calloc(lenStrNoVowels + 1, sizeof(char));
  int resultIndex = 0;
  for (i = 0; i < lenStr; i++) {
    c = str[i];
    if (!is_vowel(c)) {
      result[resultIndex] = c;
      resultIndex++;
    }
  }
  result[lenStrNoVowels] = '\0';
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<disemvowel>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L38
  lea    -0x1(%rax),%eax
  mov    %rbx,%rbp
  lea    0x1(%rbx,%rax,1),%r13
  nopl   0x0(%rax)
L37:
  movsbl 0x0(%rbp),%edi
  call   <is_vowel@plt>
  cmp    $0x1,%rax
  adc    $0xffffffff,%r12d
  add    $0x1,%rbp
  cmp    %r13,%rbp
  jne    L37
  lea    0x1(%r12),%edi
  mov    $0x1,%esi
  xor    %r14d,%r14d
  call   <calloc@plt>
  mov    %rax,%r15
  nop
L17:
  movsbl (%rbx),%edi
  mov    %edi,%ebp
  call   <is_vowel@plt>
  test   %rax,%rax
  jne    L31
  movslq %r14d,%rax
  add    $0x1,%r14d
  mov    %bpl,(%r15,%rax,1)
L31:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L17
L4:
  movslq %r12d,%r12
  mov    %r15,%rax
  movb   $0x0,(%r15,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L38:
  lea    0x1(%rax),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r15
  jmp    L4
```

assistant: ```c
char *disemvowel(char *str) {
  int lenStr = strlen(str);
  int lenStrNoVowels = lenStr;
  char *result;
  int i;
  char c;
  for (i = 0; i < lenStr; i++) {
    c = str[i];
    if (is_vowel(c)) {
      lenStrNoVowels--;
    }
  }
  result = (char *)calloc(lenStrNoVowels + 1, sizeof(char));
  int resultIndex = 0;
  for (i = 0; i < lenStr; i++) {
    c = str[i];
    if (!is_vowel(c)) {
      result[resultIndex] = c;
      resultIndex++;
    }
  }
  result[lenStrNoVowels] = '\0';
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<disemvowel>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L41
  lea    -0x1(%rax),%eax
  mov    %rbx,%rbp
  lea    0x1(%rbx,%rax,1),%r13
  nopl   0x0(%rax)
L42:
  movsbl 0x0(%rbp),%edi
  call   <is_vowel@plt>
  cmp    $0x1,%rax
  adc    $0xffffffff,%r12d
  add    $0x1,%rbp
  cmp    %r13,%rbp
  jne    L42
  lea    0x1(%r12),%edi
  mov    $0x1,%esi
  xor    %r14d,%r14d
  call   <calloc@plt>
  mov    %rax,%r15
  nop
L44:
  movsbl (%rbx),%edi
  mov    %edi,%ebp
  call   <is_vowel@plt>
  test   %rax,%rax
  jne    L33
  movslq %r14d,%rax
  add    $0x1,%r14d
  mov    %bpl,(%r15,%rax,1)
L33:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L44
L45:
  movslq %r12d,%r12
  mov    %r15,%rax
  movb   $0x0,(%r15,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L41:
  lea    0x1(%rax),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r15
  jmp    L45
```

assistant: ```c
char *disemvowel(char *str) {
  int lenStr = strlen(str);
  int lenStrNoVowels = lenStr;
  char *result;
  int i;
  char c;
  for (i = 0; i < lenStr; i++) {
    c = str[i];
    if (is_vowel(c)) {
      lenStrNoVowels--;
    }
  }
  result = (char *)calloc(lenStrNoVowels + 1, sizeof(char));
  int resultIndex = 0;
  for (i = 0; i < lenStr; i++) {
    c = str[i];
    if (!is_vowel(c)) {
      result[resultIndex] = c;
      resultIndex++;
    }
  }
  result[lenStrNoVowels] = '\0';
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L13
  mov    $0x0,%eax
  jmp    L54
L13:
  cmpl   $0x3,-0x14(%rbp)
  jg     L119
  mov    $0x1,%eax
  jmp    L54
L119:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L91
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L84
L91:
  mov    $0x0,%eax
  jmp    L54
L84:
  cmpl   $0x18,-0x14(%rbp)
  jg     L50
  mov    $0x1,%eax
  jmp    L54
L50:
  movl   $0x5,-0x4(%rbp)
  jmp    L75
L110:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L72
  mov    -0x4(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L17
L72:
  mov    $0x0,%eax
  jmp    L54
L17:
  addl   $0x6,-0x4(%rbp)
L75:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L110
  mov    $0x1,%eax
L54:
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(int n) {
  if (n < 2)
    return 0;
  if (n < 4)
    return 1;
  if (n % 2 == 0 || n % 3 == 0)
    return 0;
  if (n < 25)
    return 1;
  for (int i = 5; i * i <= n; i += 6) {
    if (n % i == 0 || n % (i + 2) == 0)
      return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L62
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jle    L62
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L62
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L62
  mov    $0x1,%eax
  cmp    $0x18,%edi
  jle    L62
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L62
  movslq %edi,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x2,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L62
  mov    $0x5,%esi
L98:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jg     L107
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  je     L62
  add    $0x8,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  test   %edx,%edx
  jne    L98
  jmp    L62
L107:
  mov    $0x1,%eax
L62:
  ret
```

assistant: ```c
int is_prime(int n) {
  if (n < 2)
    return 0;
  if (n < 4)
    return 1;
  if (n % 2 == 0 || n % 3 == 0)
    return 0;
  if (n < 25)
    return 1;
  for (int i = 5; i * i <= n; i += 6) {
    if (n % i == 0 || n % (i + 2) == 0)
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L53
  mov    $0x1,%edx
  cmp    $0x3,%edi
  jle    L53
  xor    %edx,%edx
  test   $0x1,%dil
  je     L53
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x55555556,%rax,%rdx
  shr    $0x20,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,2),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  je     L53
  mov    $0x1,%edx
  cmp    $0x18,%ecx
  jle    L53
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  je     L53
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %edi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L53
  mov    $0x5,%esi
  jmp    L35
L21:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L53
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L53
L35:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jle    L21
  mov    $0x1,%edx
L53:
  mov    %edx,%eax
  ret
```

assistant: ```c
int is_prime(int n) {
  if (n < 2)
    return 0;
  if (n < 4)
    return 1;
  if (n % 2 == 0 || n % 3 == 0)
    return 0;
  if (n < 25)
    return 1;
  for (int i = 5; i * i <= n; i += 6) {
    if (n % i == 0 || n % (i + 2) == 0)
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L40
  mov    $0x1,%edx
  cmp    $0x3,%edi
  jle    L40
  xor    %edx,%edx
  test   $0x1,%dil
  je     L40
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x55555556,%rax,%rdx
  shr    $0x20,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,2),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  je     L40
  mov    $0x1,%edx
  cmp    $0x18,%ecx
  jle    L40
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  je     L40
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %edi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L40
  mov    $0x5,%esi
  jmp    L20
L22:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L40
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L40
L20:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jle    L22
  mov    $0x1,%edx
L40:
  mov    %edx,%eax
  ret
```

assistant: ```c
int is_prime(int n) {
  if (n < 2)
    return 0;
  if (n < 4)
    return 1;
  if (n % 2 == 0 || n % 3 == 0)
    return 0;
  if (n < 25)
    return 1;
  for (int i = 5; i * i <= n; i += 6) {
    if (n % i == 0 || n % (i + 2) == 0)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lcs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L15
  cmpl   $0x0,-0x28(%rbp)
  jne    L45
L15:
  mov    $0x0,%eax
  jmp    L9
L45:
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L41
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <lcs>
  add    $0x1,%eax
  jmp    L9
L41:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <lcs>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <lcs>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <max@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int lcs(char *X, char *Y, int m, int n) {
  if (m == 0 || n == 0)
    return 0;
  if (X[m - 1] == Y[n - 1])
    return 1 + lcs(X, Y, m - 1, n - 1);
  else
    return max(lcs(X, Y, m, n - 1), lcs(X, Y, m - 1, n));
}
```
user: Translate the below assembly code into C programming language:

```asm
<lcs>:
  endbr64
  test   %edx,%edx
  je     L48
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    %ecx,%ebx
  test   %ecx,%ecx
  je     L35
  movslq %edx,%rax
  movslq %ecx,%rdx
  movzbl -0x1(%rsi,%rdx,1),%esi
  cmp    %sil,-0x1(%rdi,%rax,1)
  je     L45
  lea    -0x1(%rbp),%edx
  mov    %r13,%rsi
  call   <lcs>
  mov    %eax,%r14d
  lea    -0x1(%rbx),%ecx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <lcs>
  mov    %eax,%edi
  mov    %r14d,%esi
  call   <max@plt>
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  lea    -0x1(%rcx),%ecx
  lea    -0x1(%rbp),%edx
  mov    %r13,%rsi
  call   <lcs>
  add    $0x1,%eax
  jmp    L30
L35:
  mov    $0x0,%eax
  jmp    L30
L48:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int lcs(char *X, char *Y, int m, int n) {
  if (m == 0 || n == 0)
    return 0;
  if (X[m - 1] == Y[n - 1])
    return 1 + lcs(X, Y, m - 1, n - 1);
  else
    return max(lcs(X, Y, m, n - 1), lcs(X, Y, m - 1, n));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lcs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L31
  test   %ecx,%ecx
  je     L31
  mov    %rdi,%r13
  lea    -0x1(%rcx),%eax
  movslq %edx,%rdi
  movslq %ecx,%rcx
  sub    %rcx,%rdi
  mov    %rsi,%rbp
  cltq
  xor    %r12d,%r12d
  add    %r13,%rdi
  jmp    L54
  xchg   %ax,%ax
L32:
  add    $0x1,%r12d
  test   %edx,%edx
  sete   %cl
  test   %eax,%eax
  sete   %sil
  sub    $0x1,%rax
  or     %sil,%cl
  jne    L36
L54:
  mov    %edx,%r14d
  movzbl 0x0(%rbp,%rax,1),%ebx
  lea    0x1(%rax),%ecx
  mov    %eax,%r15d
  sub    $0x1,%edx
  cmp    %bl,(%rdi,%rax,1)
  je     L32
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <lcs>
  mov    %r15d,%ecx
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <lcs>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <max@plt>
  add    %eax,%r12d
L36:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  xor    %r12d,%r12d
  jmp    L36
```

assistant: ```c
int lcs(char *X, char *Y, int m, int n) {
  if (m == 0 || n == 0)
    return 0;
  if (X[m - 1] == Y[n - 1])
    return 1 + lcs(X, Y, m - 1, n - 1);
  else
    return max(lcs(X, Y, m, n - 1), lcs(X, Y, m - 1, n));
}
```