ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_cvccv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x4,%eax
  jle    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L1
  mov    $0x1,%eax
  jmp    L37
L1:
  mov    $0x0,%eax
L37:
  leave
  ret
```

assistant: ```c
int is_cvccv(char *s) {
  if ((strlen(s) >= 5) && is_consonant(s[0]) && is_vowel(s[1]) && is_consonant(s[2]) && is_consonant(s[3]) && is_vowel(s[4])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_cvccv>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x4,%edx
  jg     L53
L13:
  pop    %rbx
  ret
L53:
  movsbl (%rbx),%edi
  call   <is_consonant@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L13
  movsbl 0x1(%rbx),%edi
  call   <is_vowel@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L13
  movsbl 0x2(%rbx),%edi
  call   <is_consonant@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L13
  movsbl 0x3(%rbx),%edi
  call   <is_consonant@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L13
  movsbl 0x4(%rbx),%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L13
```

assistant: ```c
int is_cvccv(char *s) {
  if ((strlen(s) >= 5) && is_consonant(s[0]) && is_vowel(s[1]) && is_consonant(s[2]) && is_consonant(s[3]) && is_vowel(s[4])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_cvccv>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x4,%eax
  jg     L46
L7:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  movsbl (%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L7
  movsbl 0x1(%rbx),%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L7
  movsbl 0x2(%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L7
  movsbl 0x3(%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L7
  movsbl 0x4(%rbx),%edi
  call   <is_vowel@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_cvccv(char *s) {
  if ((strlen(s) >= 5) && is_consonant(s[0]) && is_vowel(s[1]) && is_consonant(s[2]) && is_consonant(s[3]) && is_vowel(s[4])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_cvccv>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x4,%eax
  jg     L15
L22:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  movsbl (%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L22
  movsbl 0x1(%rbx),%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L22
  movsbl 0x2(%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L22
  movsbl 0x3(%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L22
  movsbl 0x4(%rbx),%edi
  call   <is_vowel@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_cvccv(char *s) {
  if ((strlen(s) >= 5) && is_consonant(s[0]) && is_vowel(s[1]) && is_consonant(s[2]) && is_consonant(s[3]) && is_vowel(s[4])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x6,-0x38(%rbp)
  movl   $0x1,-0x34(%rbp)
  movl   $0x7,-0x4c(%rbp)
  movl   $0x1,-0x48(%rbp)
  movl   $0x5,-0x44(%rbp)
  movl   $0x4,-0x54(%rbp)
  movl   $0x3,-0x50(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x4c(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x70(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L88
L9:
  lea    -0x20(%rbp),%rcx
  lea    -0x54(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <stdlib_ndarray_broadcast_shapes@plt>
  mov    %rax,-0x68(%rbp)
  cmpq   $0x0,-0x68(%rbp)
  je     L83
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L30
L83:
  addl   $0x1,-0x74(%rbp)
L88:
  cmpl   $0xf423f,-0x74(%rbp)
  jle    L9
L30:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x70(%rbp),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    $0x8,%eax
  je     L36
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L36:
  mov    -0x1c(%rbp),%eax
  cmp    $0x7,%eax
  je     L10
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  mov    -0x18(%rbp),%eax
  cmp    $0x6,%eax
  je     L31
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  mov    -0x14(%rbp),%eax
  cmp    $0x5,%eax
  je     L89
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L89:
  movsd  -0x60(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D36
type: string

tool: D36: unexpected result


assistant: ```c
double benchmark() {
  double elapsed;
  int8_t status;
  double t;
  int i;
  int64_t sh1[] = {8, 1, 6, 1};
  int64_t sh2[] = {7, 1, 5};
  int64_t ndims[] = {4, 3};
  int64_t *shapes[] = {sh1, sh2};
  int64_t out[] = {0, 0, 0, 0};
  t = tic();
  for (i = 0; i < 1000000; i++) {
    status = stdlib_ndarray_broadcast_shapes(2, shapes, ndims, out);
    if (status != 0) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (out[0] != 8) {
    printf("unexpected result\n");
  }
  if (out[1] != 7) {
    printf("unexpected result\n");
  }
  if (out[2] != 6) {
    printf("unexpected result\n");
  }
  if (out[3] != 5) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<benchmark>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x8,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x6,0x28(%rsp)
  movl   $0x1,0x2c(%rsp)
  movl   $0x7,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x5,0x1c(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,0x30(%rsp)
  lea    0x14(%rsp),%rax
  mov    %rax,0x38(%rsp)
  movl   $0x0,0x40(%rsp)
  movl   $0x0,0x44(%rsp)
  movl   $0x0,0x48(%rsp)
  movl   $0x0,0x4c(%rsp)
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r14
  mov    $0xf4240,%ebx
  lea    0x40(%rsp),%rbp
L73:
  lea    0xc(%rsp),%rdx
  lea    0x30(%rsp),%rsi
  mov    %rbp,%rcx
  mov    $0x2,%edi
  call   <stdlib_ndarray_broadcast_shapes@plt>
  test   %rax,%rax
  jne    L36
  sub    $0x1,%ebx
  jne    L73
  jmp    L94
L36:
  lea    D23(%rip),%rdi
  call   <printf@plt>
L94:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r14,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  cmpl   $0x8,0x40(%rsp)
  jne    L57
L80:
  cmpl   $0x7,0x44(%rsp)
  jne    L41
L78:
  cmpl   $0x6,0x48(%rsp)
  jne    L92
L40:
  cmpl   $0x5,0x4c(%rsp)
  jne    L104
L71:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  movq   %rbx,%xmm0
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L57:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L80
L41:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L78
L92:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L104:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
datatype: string

tool: D23: unexpected result


assistant: ```c
double benchmark() {
  double elapsed;
  int8_t status;
  double t;
  int i;
  int64_t sh1[] = {8, 1, 6, 1};
  int64_t sh2[] = {7, 1, 5};
  int64_t ndims[] = {4, 3};
  int64_t *shapes[] = {sh1, sh2};
  int64_t out[] = {0, 0, 0, 0};
  t = tic();
  for (i = 0; i < 1000000; i++) {
    status = stdlib_ndarray_broadcast_shapes(2, shapes, ndims, out);
    if (status != 0) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (out[0] != 8) {
    printf("unexpected result\n");
  }
  if (out[1] != 7) {
    printf("unexpected result\n");
  }
  if (out[2] != 6) {
    printf("unexpected result\n");
  }
  if (out[3] != 5) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<benchmark>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x100000008,%rax
  lea    0x50(%rsp),%r13
  lea    0x1c(%rsp),%r12
  movl   $0x5,0x2c(%rsp)
  movq   $0x0,0x50(%rsp)
  lea    0x40(%rsp),%rbp
  movq   $0x0,0x58(%rsp)
  mov    %rax,0x30(%rsp)
  sub    $0x2,%rax
  mov    %rax,0x38(%rsp)
  add    $0x1,%rax
  mov    %rax,0x24(%rsp)
  movabs $0x300000004,%rax
  mov    %rax,0x1c(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x40(%rsp)
  lea    0x24(%rsp),%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L54
  nopl   (%rax)
L22:
  sub    $0x1,%ebx
  je     L13
L54:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x2,%edi
  call   <stdlib_ndarray_broadcast_shapes@plt>
  test   %rax,%rax
  je     L22
  lea    D3(%rip),%rdi
  call   <printf@plt>
L13:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  cmpl   $0x8,0x50(%rsp)
  movq   %xmm0,%rbx
  je     L38
  lea    D3(%rip),%rdi
  call   <printf@plt>
L38:
  cmpl   $0x7,0x54(%rsp)
  je     L32
  lea    D3(%rip),%rdi
  call   <printf@plt>
L32:
  cmpl   $0x6,0x58(%rsp)
  je     L11
  lea    D3(%rip),%rdi
  call   <printf@plt>
L11:
  cmpl   $0x5,0x5c(%rsp)
  je     L8
  lea    D3(%rip),%rdi
  call   <printf@plt>
L8:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x78,%rsp
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: unexpected result


assistant: ```c
double benchmark() {
  double elapsed;
  int8_t status;
  double t;
  int i;
  int64_t sh1[] = {8, 1, 6, 1};
  int64_t sh2[] = {7, 1, 5};
  int64_t ndims[] = {4, 3};
  int64_t *shapes[] = {sh1, sh2};
  int64_t out[] = {0, 0, 0, 0};
  t = tic();
  for (i = 0; i < 1000000; i++) {
    status = stdlib_ndarray_broadcast_shapes(2, shapes, ndims, out);
    if (status != 0) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (out[0] != 8) {
    printf("unexpected result\n");
  }
  if (out[1] != 7) {
    printf("unexpected result\n");
  }
  if (out[2] != 6) {
    printf("unexpected result\n");
  }
  if (out[3] != 5) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<benchmark>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x78,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%r13
  lea    0x18(%rsp),%r12
  mov    D46(%rip),%rax
  movaps %xmm0,0x30(%rsp)
  lea    0x40(%rsp),%rbp
  mov    %rax,0x20(%rsp)
  mov    D53(%rip),%rax
  movl   $0x5,0x28(%rsp)
  mov    %rax,0x18(%rsp)
  lea    0x30(%rsp),%rax
  movq   %rax,%xmm0
  lea    0x20(%rsp),%rax
  movq   %rax,%xmm1
  xor    %eax,%eax
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,0x40(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x50(%rsp)
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L39
  nopl   0x0(%rax)
L59:
  sub    $0x1,%ebx
  je     L53
L39:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x2,%edi
  call   <stdlib_ndarray_broadcast_shapes@plt>
  test   %rax,%rax
  je     L59
  lea    D20(%rip),%rdi
  call   <printf@plt>
L53:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  cmpl   $0x8,0x50(%rsp)
  movq   %xmm0,%rbx
  je     L23
  lea    D20(%rip),%rdi
  call   <printf@plt>
L23:
  cmpl   $0x7,0x54(%rsp)
  je     L56
  lea    D20(%rip),%rdi
  call   <printf@plt>
L56:
  cmpl   $0x6,0x58(%rsp)
  je     L9
  lea    D20(%rip),%rdi
  call   <printf@plt>
L9:
  cmpl   $0x5,0x5c(%rsp)
  je     L21
  lea    D20(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type: byte[16]
name: extract_symbolic_data
arguments: tag: D46
type: byte[8]
name: extract_symbolic_data
arguments: tag: D53
type: byte[8]
name: extract_symbolic_data
arguments: tag: D20
type: string

tool: {"D19": [0x08,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D46": [0x07,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D53": [0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D20: unexpected result


assistant: ```c
double benchmark() {
  double elapsed;
  int8_t status;
  double t;
  int i;
  int64_t sh1[] = {8, 1, 6, 1};
  int64_t sh2[] = {7, 1, 5};
  int64_t ndims[] = {4, 3};
  int64_t *shapes[] = {sh1, sh2};
  int64_t out[] = {0, 0, 0, 0};
  t = tic();
  for (i = 0; i < 1000000; i++) {
    status = stdlib_ndarray_broadcast_shapes(2, shapes, ndims, out);
    if (status != 0) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (out[0] != 8) {
    printf("unexpected result\n");
  }
  if (out[1] != 7) {
    printf("unexpected result\n");
  }
  if (out[2] != 6) {
    printf("unexpected result\n");
  }
  if (out[3] != 5) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_depth_shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L5:
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: D8:  

assistant: ```c
void print_depth_shift(FILE *fp, int depth) {
  int j;
  for (j = 0; j < depth; j++) {
    fprintf(fp, " ");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_depth_shift>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D7(%rip),%r13
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string

tool: D7:  

assistant: ```c
void print_depth_shift(FILE *fp, int depth) {
  int j;
  for (j = 0; j < depth; j++) {
    fprintf(fp, " ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_depth_shift>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0:  

assistant: ```c
void print_depth_shift(FILE *fp, int depth) {
  int j;
  for (j = 0; j < depth; j++) {
    fprintf(fp, " ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_depth_shift>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L3:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7:  

assistant: ```c
void print_depth_shift(FILE *fp, int depth) {
  int j;
  for (j = 0; j < depth; j++) {
    fprintf(fp, " ");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<genMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L25
L30:
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L35:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x5(%rcx),%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L35
  addl   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  nop
  nop
  leave
  ret
```

assistant: ```c
void genMat(int **mat, int row, int col) {
  srand(time(NULL));
  for (int i = 0; i < row; i++) {
    for (int j = 0; j < col; j++) {
      mat[i][j] = rand() % (10 - 5 + 1) + 5;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<genMat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L19
  mov    %r12,%rbp
  lea    -0x1(%rbx),%eax
  lea    0x8(%r12,%rax,8),%r14
  lea    -0x1(%r13),%eax
  lea    0x4(,%rax,4),%r12
  jmp    L16
L0:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    0x0(%rbp),%rcx
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x5,%eax
  mov    %eax,(%rcx,%rbx,1)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
L8:
  add    $0x8,%rbp
  cmp    %r14,%rbp
  je     L19
L16:
  mov    $0x0,%ebx
  test   %r13d,%r13d
  jg     L0
  jmp    L8
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void genMat(int **mat, int row, int col) {
  srand(time(NULL));
  for (int i = 0; i < row; i++) {
    for (int j = 0; j < col; j++) {
      mat[i][j] = rand() % (10 - 5 + 1) + 5;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<genMat>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L38
  lea    -0x1(%rbx),%eax
  lea    0x8(%r14,%rax,8),%r12
  lea    -0x1(%rbp),%eax
  lea    0x4(,%rax,4),%rbx
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %r13d,%r13d
  test   %ebp,%ebp
  jle    L12
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%r14),%rcx
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%esi
  shr    $0x20,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x5,%eax
  mov    %eax,(%rcx,%r13,1)
  add    $0x4,%r13
  cmp    %r13,%rbx
  jne    L26
L12:
  add    $0x8,%r14
  cmp    %r12,%r14
  jne    L27
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void genMat(int **mat, int row, int col) {
  srand(time(NULL));
  for (int i = 0; i < row; i++) {
    for (int j = 0; j < col; j++) {
      mat[i][j] = rand() % (10 - 5 + 1) + 5;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<genMat>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebp,%ebp
  jle    L37
  test   %ebx,%ebx
  jle    L37
  lea    -0x1(%rbp),%eax
  shl    $0x2,%rbx
  lea    0x8(%r13,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <rand@plt>
  mov    0x0(%r13),%rcx
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%esi
  shr    $0x20,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x5,%eax
  mov    %eax,(%rcx,%r12,1)
  add    $0x4,%r12
  cmp    %r12,%rbx
  jne    L7
  add    $0x8,%r13
  cmp    %rbp,%r13
  jne    L8
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void genMat(int **mat, int row, int col) {
  srand(time(NULL));
  for (int i = 0; i < row; i++) {
    for (int j = 0; j < col; j++) {
      mat[i][j] = rand() % (10 - 5 + 1) + 5;
    }
  }
}
```