user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x4c(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4c(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L6
L31:
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
  mov    -0x40(%rbp),%eax
  cltq
  movsd  D87(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp,%rax,8)
  addl   $0x1,-0x40(%rbp)
L6:
  cmpl   $0x4,-0x40(%rbp)
  jle    L31
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x1,-0x3c(%rbp)
  jmp    L15
L28:
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L87
L22:
  movl   $0x0,-0x34(%rbp)
  jmp    L32
L58:
  mov    -0x38(%rbp),%eax
  cltq
  movsd  -0x30(%rbp,%rax,8),%xmm1
  mov    -0x4c(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D87(%rip),%xmm2
  divsd  %xmm2,%xmm0
  movsd  D62(%rip),%xmm3
  movapd %xmm0,%xmm2
  divsd  %xmm3,%xmm2
  mov    -0x38(%rbp),%eax
  cltq
  movsd  -0x30(%rbp,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x38(%rbp),%eax
  cltq
  movsd  %xmm0,-0x30(%rbp,%rax,8)
  addl   $0x1,-0x34(%rbp)
L32:
  cmpl   $0xb,-0x34(%rbp)
  jle    L58
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L87:
  cmpl   $0x4,-0x38(%rbp)
  jle    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x3c(%rbp)
L15:
  mov    -0x48(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  jle    L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L85
  call   <__stack_chk_fail@plt>
L85:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string
name: parse_data
arguments: tag: D78
datatype: string
name: parse_data
arguments: tag: D84
datatype: string
name: parse_data
arguments: tag: D95
datatype: string
name: parse_data
arguments: tag: D28
datatype: string
name: parse_data
arguments: tag: D87
datatype: f64
name: parse_data
arguments: tag: D53
datatype: string
name: parse_data
arguments: tag: D62
datatype: f64
name: parse_data
arguments: tag: D42
datatype: string

tool: D0: Enter interest rate: 

tool: D78: %d

tool: D84: Enter number of years: 

tool: D95: 
Years

tool: D28: %6d%%

tool: D87: 100

tool: D53: %3d	

tool: D62: 12

tool: D42: %7.2f

assistant: ```c
int main(void) {
  int rate, higher_rate, num_years;
  double value[5];
  printf("Enter interest rate: ");
  scanf("%d", &rate);
  printf("Enter number of years: ");
  scanf("%d", &num_years);
  printf("\nYears");
  higher_rate = rate;
  for (int i = 0; i < ((int)(sizeof(value) / sizeof(value[0]))); i += 1) {
    printf("%6d%%", higher_rate);
    higher_rate += 1;
    value[i] = 100.00;
  }
  printf("\n");
  for (int year = 1; year <= num_years; year += 1) {
    printf("%3d\t", year);
    for (int i = 0; i < ((int)(sizeof(value) / sizeof(value[0]))); i += 1) {
      for (int j = 0; j < 12; j += 1) {
        value[i] += (rate + i) / 100.0 / 12.0 * value[i];
      }
      printf("%7.2f", value[i]);
    }
    printf("\n");
  }
  return 0;
}
```