ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_net>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x20,0x14(%rsp)
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rax
  push   %rax
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  lea    D11(%rip),%rsi
  mov    $0x0,%eax
  call   <sscanf@plt>
  add    $0x10,%rsp
  cmp    $0x5,%eax
  je     L94
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  sub    $0x8,%rsp
  lea    0x8(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  mov    %eax,%edx
  add    $0x10,%rsp
  mov    $0x0,%eax
  cmp    $0x4,%edx
  je     L94
L76:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L94:
  mov    0x4(%rsp),%edi
  call   <isbyte@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L76
  mov    0x8(%rsp),%edi
  call   <isbyte@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L76
  mov    0xc(%rsp),%edi
  call   <isbyte@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L76
  mov    0x10(%rsp),%edi
  call   <isbyte@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L76
  mov    0x14(%rsp),%edx
  cmp    $0x20,%edx
  ja     L76
  mov    (%rsp),%eax
  mov    0x4(%rsp),%ecx
  shl    $0x18,%ecx
  mov    0x8(%rsp),%esi
  shl    $0x10,%esi
  or     %esi,%ecx
  or     0x10(%rsp),%ecx
  mov    0xc(%rsp),%esi
  shl    $0x8,%esi
  or     %esi,%ecx
  mov    %ecx,(%r12)
  test   %edx,%edx
  je     L92
  mov    $0x20,%ecx
  sub    %edx,%ecx
  mov    $0xffffffff,%edx
  shl    %cl,%edx
L92:
  mov    %edx,0x0(%rbp)
  jmp    L76
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D11
datatype: string
name: unpack_data
arguments: data_label: D0
datatype: string

tool: D11: %d.%d.%d.%d/%d%n

tool: D0: %d.%d.%d.%d%n

assistant: ```c
int parse_net(const char *spec, uint32_t *net, uint32_t *mask) {
  int n, a, b, c, d, slash = 32, len = 0;
  if ((sscanf(spec, "%d.%d.%d.%d/%d%n", &a, &b, &c, &d, &slash, &n) == 5 || sscanf(spec, "%d.%d.%d.%d%n", &a, &b, &c, &d, &n) == 4) && isbyte(a) && isbyte(b) && isbyte(c) && isbyte(d) && slash >= 0 && slash < 33) {
    len = n;
    *net = ((uint32_t)a << 24) | ((uint32_t)b << 16) | ((uint32_t)c << 8) | d;
    *mask = slash ? 0xffffffffU << (32 - slash) : 0;
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_net>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,(%rsp)
  lea    0x10(%rsp),%r12
  lea    0x20(%rsp),%rbx
  mov    %rdx,0x8(%rsp)
  lea    0x1c(%rsp),%r15
  mov    %rbx,%r9
  lea    0x18(%rsp),%r14
  lea    0x14(%rsp),%r13
  lea    D12(%rip),%rsi
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x20,0x24(%rsp)
  push   %r12
  lea    0x2c(%rsp),%rax
  push   %rax
  xor    %eax,%eax
  call   <sscanf@plt>
  pop    %rsi
  pop    %rdi
  cmp    $0x5,%eax
  je     L29
  sub    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rbx,%r9
  push   %r12
  mov    %r15,%r8
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sscanf@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0x4,%eax
  je     L29
L96:
  xor    %eax,%eax
L69:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    0x14(%rsp),%edi
  call   <isbyte@plt>
  test   %rax,%rax
  je     L96
  mov    0x18(%rsp),%edi
  call   <isbyte@plt>
  test   %rax,%rax
  je     L96
  mov    0x1c(%rsp),%edi
  call   <isbyte@plt>
  test   %rax,%rax
  je     L96
  mov    0x20(%rsp),%edi
  call   <isbyte@plt>
  test   %rax,%rax
  je     L96
  mov    0x24(%rsp),%edx
  cmp    $0x20,%edx
  ja     L96
  mov    0x14(%rsp),%ecx
  mov    0x18(%rsp),%esi
  mov    (%rsp),%rbx
  mov    0x10(%rsp),%eax
  shl    $0x10,%esi
  shl    $0x18,%ecx
  or     %esi,%ecx
  mov    0x1c(%rsp),%esi
  or     0x20(%rsp),%ecx
  shl    $0x8,%esi
  or     %esi,%ecx
  mov    %ecx,(%rbx)
  test   %edx,%edx
  je     L26
  mov    $0x20,%ecx
  sub    %edx,%ecx
  mov    $0xffffffff,%edx
  shl    %cl,%edx
L26:
  mov    0x8(%rsp),%rcx
  mov    %edx,(%rcx)
  jmp    L69
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string

tool: D12: %d.%d.%d.%d/%d%n

tool: D11: %d.%d.%d.%d%n

assistant: ```c
int parse_net(const char *spec, uint32_t *net, uint32_t *mask) {
  int n, a, b, c, d, slash = 32, len = 0;
  if ((sscanf(spec, "%d.%d.%d.%d/%d%n", &a, &b, &c, &d, &slash, &n) == 5 || sscanf(spec, "%d.%d.%d.%d%n", &a, &b, &c, &d, &n) == 4) && isbyte(a) && isbyte(b) && isbyte(c) && isbyte(d) && slash >= 0 && slash < 33) {
    len = n;
    *net = ((uint32_t)a << 24) | ((uint32_t)b << 16) | ((uint32_t)c << 8) | d;
    *mask = slash ? 0xffffffffU << (32 - slash) : 0;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_net>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,(%rsp)
  lea    0x10(%rsp),%r12
  lea    0x20(%rsp),%rbx
  mov    %rdx,0x8(%rsp)
  lea    0x1c(%rsp),%r15
  mov    %rbx,%r9
  lea    0x18(%rsp),%r14
  lea    0x14(%rsp),%r13
  lea    D3(%rip),%rsi
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x20,0x24(%rsp)
  push   %r12
  lea    0x2c(%rsp),%rax
  push   %rax
  xor    %eax,%eax
  call   <sscanf@plt>
  pop    %rsi
  pop    %rdi
  cmp    $0x5,%eax
  je     L75
  sub    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rbx,%r9
  push   %r12
  mov    %r15,%r8
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sscanf@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0x4,%eax
  je     L75
L7:
  xor    %eax,%eax
L52:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  mov    0x14(%rsp),%edi
  call   <isbyte@plt>
  test   %rax,%rax
  je     L7
  mov    0x18(%rsp),%edi
  call   <isbyte@plt>
  test   %rax,%rax
  je     L7
  mov    0x1c(%rsp),%edi
  call   <isbyte@plt>
  test   %rax,%rax
  je     L7
  mov    0x20(%rsp),%edi
  call   <isbyte@plt>
  test   %rax,%rax
  je     L7
  mov    0x24(%rsp),%edx
  cmp    $0x20,%edx
  ja     L7
  mov    0x14(%rsp),%ecx
  mov    0x18(%rsp),%esi
  mov    (%rsp),%rbx
  mov    0x10(%rsp),%eax
  shl    $0x10,%esi
  shl    $0x18,%ecx
  or     %esi,%ecx
  mov    0x1c(%rsp),%esi
  or     0x20(%rsp),%ecx
  shl    $0x8,%esi
  or     %esi,%ecx
  mov    %ecx,(%rbx)
  test   %edx,%edx
  je     L94
  mov    $0x20,%ecx
  sub    %edx,%ecx
  mov    $0xffffffff,%edx
  shl    %cl,%edx
L94:
  mov    0x8(%rsp),%rcx
  mov    %edx,(%rcx)
  jmp    L52
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D3: %d.%d.%d.%d/%d%n

tool: D0: %d.%d.%d.%d%n

assistant: ```c
int parse_net(const char *spec, uint32_t *net, uint32_t *mask) {
  int n, a, b, c, d, slash = 32, len = 0;
  if ((sscanf(spec, "%d.%d.%d.%d/%d%n", &a, &b, &c, &d, &slash, &n) == 5 || sscanf(spec, "%d.%d.%d.%d%n", &a, &b, &c, &d, &n) == 4) && isbyte(a) && isbyte(b) && isbyte(c) && isbyte(d) && slash >= 0 && slash < 33) {
    len = n;
    *net = ((uint32_t)a << 24) | ((uint32_t)b << 16) | ((uint32_t)c << 8) | d;
    *mask = slash ? 0xffffffffU << (32 - slash) : 0;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<msgnmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L36
  mov    $0x0,%eax
  jmp    L3
L36:
  movq   $0x0,-0x10(%rbp)
  jmp    L51
L49:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <msg_dequeue@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L33
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <msg_enqueue@plt>
  addq   $0x1,-0x10(%rbp)
L51:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L49
  jmp    L11
L33:
  nop
L11:
  mov    -0x10(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
size_t msgnmove(struct msg_queue *dst, struct msg_queue *src, size_t n) {
  size_t i;
  struct msg *mptr;
  if (n == 0)
    return 0;
  for (i = 0; i <= n - 1; i++) {
    mptr = msg_dequeue(src);
    if (mptr == NULL)
      break;
    msg_enqueue(dst, mptr);
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<msgnmove>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L12
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    $0x0,%ebx
L33:
  mov    %r12,%rdi
  call   <msg_dequeue@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L20
  mov    %r13,%rdi
  call   <msg_enqueue@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L33
  jmp    L12
L20:
  mov    %rbx,%rbp
L12:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t msgnmove(struct msg_queue *dst, struct msg_queue *src, size_t n) {
  size_t i;
  struct msg *mptr;
  if (n == 0)
    return 0;
  for (i = 0; i <= n - 1; i++) {
    mptr = msg_dequeue(src);
    if (mptr == NULL)
      break;
    msg_enqueue(dst, mptr);
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<msgnmove>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L7
  mov    %rdi,%r13
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  jmp    L37
L26:
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <msg_enqueue@plt>
  cmp    %rbx,%r12
  je     L7
L37:
  mov    %rbp,%rdi
  call   <msg_dequeue@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L26
  mov    %rbx,%r12
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t msgnmove(struct msg_queue *dst, struct msg_queue *src, size_t n) {
  size_t i;
  struct msg *mptr;
  if (n == 0)
    return 0;
  for (i = 0; i <= n - 1; i++) {
    mptr = msg_dequeue(src);
    if (mptr == NULL)
      break;
    msg_enqueue(dst, mptr);
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<msgnmove>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L27
  mov    %rdi,%r13
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  jmp    L28
L8:
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <msg_enqueue@plt>
  cmp    %rbx,%r12
  je     L27
L28:
  mov    %rbp,%rdi
  call   <msg_dequeue@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L8
  mov    %rbx,%r12
L27:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t msgnmove(struct msg_queue *dst, struct msg_queue *src, size_t n) {
  size_t i;
  struct msg *mptr;
  if (n == 0)
    return 0;
  for (i = 0; i <= n - 1; i++) {
    mptr = msg_dequeue(src);
    if (mptr == NULL)
      break;
    msg_enqueue(dst, mptr);
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<validate_class_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x33,-0x4(%rbp)
  je     L59
  cmpl   $0x33,-0x4(%rbp)
  jg     L72
  cmpl   $0x31,-0x4(%rbp)
  je     L15
  cmpl   $0x32,-0x4(%rbp)
  je     L36
  jmp    L72
L15:
  mov    $0x0,%eax
  jmp    L73
L36:
  mov    $0x1,%eax
  jmp    L73
L59:
  mov    $0x2,%eax
  jmp    L73
L72:
  mov    $0xffffffff,%eax
L73:
  pop    %rbp
  ret
```

assistant: ```c
int validate_class_input(int input) {
  switch (input) {
  case '1':
    return 0;
  case '2':
    return 1;
  case '3':
    return 2;
  default:
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<validate_class_input>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x32,%edi
  je     L17
  mov    $0x2,%eax
  cmp    $0x33,%edi
  je     L17
  cmp    $0x31,%edi
  setne  %al
  movzbl %al,%eax
  neg    %eax
L17:
  ret
```

assistant: ```c
int validate_class_input(int input) {
  switch (input) {
  case '1':
    return 0;
  case '2':
    return 1;
  case '3':
    return 2;
  default:
    return -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<validate_class_input>:
  endbr64
  lea    -0x31(%rdi),%eax
  mov    $0xffffffff,%edx
  cmp    $0x2,%eax
  cmova  %edx,%eax
  ret
```

assistant: ```c
int validate_class_input(int input) {
  switch (input) {
  case '1':
    return 0;
  case '2':
    return 1;
  case '3':
    return 2;
  default:
    return -1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<validate_class_input>:
  endbr64
  lea    -0x31(%rdi),%eax
  mov    $0xffffffff,%edx
  cmp    $0x2,%eax
  cmova  %edx,%eax
  ret
```

assistant: ```c
int validate_class_input(int input) {
  switch (input) {
  case '1':
    return 0;
  case '2':
    return 1;
  case '3':
    return 2;
  default:
    return -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_List>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_List_basics@plt>
  mov    $0x0,%eax
  call   <test_List_insert@plt>
  mov    $0x0,%eax
  call   <test_List_erase@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_List(void) {
  test_List_basics();
  test_List_insert();
  test_List_erase();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_List>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_List_basics@plt>
  mov    $0x0,%eax
  call   <test_List_insert@plt>
  mov    $0x0,%eax
  call   <test_List_erase@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_List(void) {
  test_List_basics();
  test_List_insert();
  test_List_erase();
}
```
user: What is the c source code of the assembly code below:

```asm
<test_List>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_List_basics@plt>
  xor    %eax,%eax
  call   <test_List_insert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <test_List_erase@plt>
```

assistant: ```c
void test_List(void) {
  test_List_basics();
  test_List_insert();
  test_List_erase();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_List>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_List_basics@plt>
  xor    %eax,%eax
  call   <test_List_insert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <test_List_erase@plt>
```

assistant: ```c
void test_List(void) {
  test_List_basics();
  test_List_insert();
  test_List_erase();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SumProduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L8:
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double SumProduct(int n, const double *x, const double *y) {
  double Sum = 0.0;
  for (int i = 0; i < n; ++i)
    Sum += (*x++) * (*y++);
  return Sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SumProduct>:
  endbr64
  test   %edi,%edi
  jle    L22
  mov    %edi,%edi
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L29:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L29
L12:
  movapd %xmm1,%xmm0
  ret
L22:
  pxor   %xmm1,%xmm1
  jmp    L12
```

assistant: ```c
double SumProduct(int n, const double *x, const double *y) {
  double Sum = 0.0;
  for (int i = 0; i < n; ++i)
    Sum += (*x++) * (*y++);
  return Sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SumProduct>:
  endbr64
  test   %edi,%edi
  jle    L5
  movslq %edi,%rdi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L18:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rdi,%rax
  jne    L18
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L5:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double SumProduct(int n, const double *x, const double *y) {
  double Sum = 0.0;
  for (int i = 0; i < n; ++i)
    Sum += (*x++) * (*y++);
  return Sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SumProduct>:
  endbr64
  test   %edi,%edi
  jle    L35
  cmp    $0x1,%edi
  je     L8
  mov    %edi,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L2:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rdx,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L2
  mov    %edi,%ecx
  and    $0xfffffffe,%ecx
  mov    %ecx,%eax
  shl    $0x3,%rax
  add    %rax,%rsi
  add    %rax,%rdx
  cmp    %ecx,%edi
  je     L16
L38:
  movsd  (%rsi),%xmm1
  mulsd  (%rdx),%xmm1
  addsd  %xmm1,%xmm0
  ret
  nopl   (%rax)
L16:
  ret
  nopl   0x0(%rax)
L35:
  pxor   %xmm0,%xmm0
  ret
L8:
  pxor   %xmm0,%xmm0
  jmp    L38
```

assistant: ```c
double SumProduct(int n, const double *x, const double *y) {
  double Sum = 0.0;
  for (int i = 0; i < n; ++i)
    Sum += (*x++) * (*y++);
  return Sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_comments>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x23,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *remove_comments(char *line) {
  char *comment;
  comment = strchr(line, '#');
  if (comment) {
    *comment = '\0';
  }
  return line;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<remove_comments>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x23,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *remove_comments(char *line) {
  char *comment;
  comment = strchr(line, '#');
  if (comment) {
    *comment = '\0';
  }
  return line;
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_comments>:
  endbr64
  push   %r12
  mov    $0x23,%esi
  mov    %rdi,%r12
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
L7:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *remove_comments(char *line) {
  char *comment;
  comment = strchr(line, '#');
  if (comment) {
    *comment = '\0';
  }
  return line;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<remove_comments>:
  endbr64
  push   %r12
  mov    $0x23,%esi
  mov    %rdi,%r12
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax)
L5:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *remove_comments(char *line) {
  char *comment;
  comment = strchr(line, '#');
  if (comment) {
    *comment = '\0';
  }
  return line;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<psvec2_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vec2_negative@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_negative(struct vec2 *result, struct vec2 *a) {
  vec2_negative((float *)result, (float *)a);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psvec2_negative>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec2_negative@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_negative(struct vec2 *result, struct vec2 *a) {
  vec2_negative((float *)result, (float *)a);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psvec2_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_negative(struct vec2 *result, struct vec2 *a) {
  vec2_negative((float *)result, (float *)a);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<psvec2_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_negative(struct vec2 *result, struct vec2 *a) {
  vec2_negative((float *)result, (float *)a);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x2000000,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L0:
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L10:
  cmpl   $0x9,-0xc(%rbp)
  jle    L0
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main2() {
  int *arr1 = (int *)0x02000000;
  *(arr1 + 2) = 0;
  for (int i = 0; i < 10; i++) {
    *(arr1 + 2) += 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main2>:
  endbr64
  mov    $0x1,%eax
L4:
  add    $0x1,%eax
  cmp    $0xb,%eax
  jne    L4
  movl   $0xa,0x2000008
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main2() {
  int *arr1 = (int *)0x02000000;
  *(arr1 + 2) = 0;
  for (int i = 0; i < 10; i++) {
    *(arr1 + 2) += 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main2>:
  endbr64
  movl   $0xa,0x2000008
  xor    %eax,%eax
  ret
```

assistant: ```c
int main2() {
  int *arr1 = (int *)0x02000000;
  *(arr1 + 2) = 0;
  for (int i = 0; i < 10; i++) {
    *(arr1 + 2) += 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main2>:
  endbr64
  movl   $0xa,0x2000008
  xor    %eax,%eax
  ret
```

assistant: ```c
int main2() {
  int *arr1 = (int *)0x02000000;
  *(arr1 + 2) = 0;
  for (int i = 0; i < 10; i++) {
    *(arr1 + 2) += 1;
  }
  return 0;
}
```