ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_exist_elem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L24
  mov    $0x1,%eax
  jmp    L32
L24:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  mov    $0x0,%eax
L32:
  leave
  ret
```

assistant: ```c
int is_exist_elem(char *elem, char **array, int elem_count) {
  int i;
  for (i = 0; i < elem_count; i++) {
    if (strcmp(array[i], elem) == 0)
      return (!(0));
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_exist_elem>:
  endbr64
  test   %edx,%edx
  jle    L18
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rsi,%rax,8),%r12
L26:
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L8
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L26
  mov    $0x0,%eax
  jmp    L15
L18:
  mov    $0x0,%eax
  ret
L8:
  mov    $0x1,%eax
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int is_exist_elem(char *elem, char **array, int elem_count) {
  int i;
  for (i = 0; i < elem_count; i++) {
    if (strcmp(array[i], elem) == 0)
      return (!(0));
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_exist_elem>:
  endbr64
  test   %edx,%edx
  jle    L26
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L7
  nopl   0x0(%rax)
L18:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L32
L7:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_exist_elem(char *elem, char **array, int elem_count) {
  int i;
  for (i = 0; i < elem_count; i++) {
    if (strcmp(array[i], elem) == 0)
      return (!(0));
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_exist_elem>:
  endbr64
  test   %edx,%edx
  jle    L16
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L3
  nopl   0x0(%rax)
L29:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L1
L3:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_exist_elem(char *elem, char **array, int elem_count) {
  int i;
  for (i = 0; i < elem_count; i++) {
    if (strcmp(array[i], elem) == 0)
      return (!(0));
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %edi,-0x334(%rbp)
  mov    %rsi,-0x340(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x330(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <createDic@plt>
  nop
L15:
  lea    -0x330(%rbp),%rax
  mov    %rax,%rdi
  call   <afficheMenu@plt>
  cmp    $0x1,%eax
  jne    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
main(int argc, char *argv[]) {
  char *dic[100];
  createDic(dic, 100);
  while (afficheMenu(dic) != 1) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x64,%esi
  call   <createDic@plt>
  mov    %rsp,%rbx
L1:
  mov    %rbx,%rdi
  call   <afficheMenu@plt>
  cmp    $0x1,%eax
  jne    L1
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x330,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main(int argc, char *argv[]) {
  char *dic[100];
  createDic(dic, 100);
  while (afficheMenu(dic) != 1) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x64,%esi
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <createDic@plt>
  nop
L13:
  mov    %rbx,%rdi
  call   <afficheMenu@plt>
  cmp    $0x1,%eax
  jne    L13
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x330,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main(int argc, char *argv[]) {
  char *dic[100];
  createDic(dic, 100);
  while (afficheMenu(dic) != 1) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x64,%esi
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <createDic@plt>
  nop
L15:
  mov    %rbx,%rdi
  call   <afficheMenu@plt>
  cmp    $0x1,%eax
  jne    L15
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x330,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main(int argc, char *argv[]) {
  char *dic[100];
  createDic(dic, 100);
  while (afficheMenu(dic) != 1) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_elf_store_u64L>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  shrq   $0x20,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0x10(%rbp),%rdx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _elf_store_u64L(unsigned char *to, unsigned long long v) {
  ((((char *)(to))[3] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to))[2] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to))[1] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to))[0] = ((unsigned int)((unsigned int)v) >> (0))));
  v >>= 32;
  ((((char *)(to + 4))[3] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to + 4))[2] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to + 4))[1] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to + 4))[0] = ((unsigned int)((unsigned int)v) >> (0))));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_elf_store_u64L>:
  endbr64
  mov    %rsi,%rax
  mov    %esi,%edx
  shr    $0x18,%edx
  mov    %dl,0x3(%rdi)
  mov    %esi,%edx
  shr    $0x10,%edx
  mov    %dl,0x2(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdi)
  mov    %sil,(%rdi)
  mov    %rsi,%rdx
  shr    $0x20,%rdx
  shr    $0x38,%rsi
  mov    %sil,0x7(%rdi)
  mov    %rax,%rcx
  shr    $0x30,%rcx
  mov    %cl,0x6(%rdi)
  shr    $0x28,%rax
  mov    %al,0x5(%rdi)
  mov    %dl,0x4(%rdi)
  ret
```

assistant: ```c
void _elf_store_u64L(unsigned char *to, unsigned long long v) {
  ((((char *)(to))[3] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to))[2] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to))[1] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to))[0] = ((unsigned int)((unsigned int)v) >> (0))));
  v >>= 32;
  ((((char *)(to + 4))[3] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to + 4))[2] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to + 4))[1] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to + 4))[0] = ((unsigned int)((unsigned int)v) >> (0))));
}
```
user: What is the c source code of the assembly code below:

```asm
<_elf_store_u64L>:
  endbr64
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void _elf_store_u64L(unsigned char *to, unsigned long long v) {
  ((((char *)(to))[3] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to))[2] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to))[1] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to))[0] = ((unsigned int)((unsigned int)v) >> (0))));
  v >>= 32;
  ((((char *)(to + 4))[3] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to + 4))[2] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to + 4))[1] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to + 4))[0] = ((unsigned int)((unsigned int)v) >> (0))));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_elf_store_u64L>:
  endbr64
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void _elf_store_u64L(unsigned char *to, unsigned long long v) {
  ((((char *)(to))[3] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to))[2] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to))[1] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to))[0] = ((unsigned int)((unsigned int)v) >> (0))));
  v >>= 32;
  ((((char *)(to + 4))[3] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to + 4))[2] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to + 4))[1] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to + 4))[0] = ((unsigned int)((unsigned int)v) >> (0))));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_udiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%esi
  mov    $0xfffffdea,%edi
  call   <udiv_i16@plt>
  cmp    $0x2446,%eax
  je     L9
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L7
L9:
  mov    $0x40,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int test_udiv(void) {
  if (udiv_i16(-534, 7) != 9286)
    return fail(0);
  return 0x40;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_udiv>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0xfffffdea,%edi
  call   <udiv_i16@plt>
  mov    %eax,%edx
  mov    $0x40,%eax
  cmp    $0x2446,%edx
  jne    L7
L17:
  add    $0x8,%rsp
  ret
L7:
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L17
```

assistant: ```c
int test_udiv(void) {
  if (udiv_i16(-534, 7) != 9286)
    return fail(0);
  return 0x40;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_udiv>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0xfffffdea,%edi
  call   <udiv_i16@plt>
  cmp    $0x2446,%eax
  jne    L4
  mov    $0x40,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <fail@plt>
```

assistant: ```c
int test_udiv(void) {
  if (udiv_i16(-534, 7) != 9286)
    return fail(0);
  return 0x40;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_udiv>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0xfffffdea,%edi
  call   <udiv_i16@plt>
  cmp    $0x2446,%eax
  jne    L1
  mov    $0x40,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <fail@plt>
```

assistant: ```c
int test_udiv(void) {
  if (udiv_i16(-534, 7) != 9286)
    return fail(0);
  return 0x40;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply289>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L4
L24:
  movl   $0x0,-0x3c(%rbp)
  jmp    L7
L8:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L7:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L8
  addl   $0x1,-0x40(%rbp)
L4:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L24
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply289(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply289>:
  endbr64
  test   %edi,%edi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L5:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L25:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L25
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  ret
```

assistant: ```c
void multiply289(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<multiply289>:
  endbr64
  test   %edi,%edi
  jle    L4
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L0
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L11
  pop    %rbx
  ret
L4:
  ret
```

assistant: ```c
void multiply289(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply289>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L44
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L8:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L10
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L10
  nopl   0x0(%rax)
L27:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L27
  cmp    -0x24(%rsp),%r11d
  je     L30
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L30
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L30
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L30:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L8
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L94:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L94
  mov    -0x18(%rsp),%r8
  jmp    L30
```

assistant: ```c
void multiply289(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<openFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xa8(%rbp),%rax
  mov    %rax,%rdi
  call   <getFileExt@plt>
  mov    %eax,%edx
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  mov    -0xa8(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x90(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x98(%rbp)
  jmp    L6
L25:
  mov    -0xa8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x98(%rbp)
L6:
  cmpq   $0x0,-0x98(%rbp)
  jne    L18
  mov    -0xa8(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L18:
  mov    -0x98(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D39
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D8
datatype: string
name: extract_symbolic_data
arguments: data_label: D22
datatype: string

tool: D39: gz

tool: D17: gunzip -c %s

tool: D8: r

tool: D22: The file %s does not exist!

assistant: ```c
FILE *openFile(const char *fname) {
  FILE *fp;
  char cmd[128];
  if (strcmp(getFileExt(fname), "gz") == 0) {
    sprintf(cmd, "gunzip -c %s", fname);
    fp = popen(cmd, "r");
  } else {
    fp = fopen(fname, "r");
  }
  if (fp == NULL) {
    error("The file %s does not exist!", fname);
  }
  return fp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<openFile>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  call   <getFileExt@plt>
  mov    %eax,%edi
  lea    D10(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
  mov    %rsp,%rbp
  mov    %rbx,%rdx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <popen@plt>
  mov    %rax,%rbp
L11:
  test   %rbp,%rbp
  je     L5
L18:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %rbp,%rax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L11
L5:
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <error@plt>
  jmp    L18
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D10
type: string
name: parse_data
arguments: tag: D15
type: string
name: parse_data
arguments: tag: D1
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D10: gz

tool: D15: gunzip -c %s

tool: D1: r

tool: D2: The file %s does not exist!

assistant: ```c
FILE *openFile(const char *fname) {
  FILE *fp;
  char cmd[128];
  if (strcmp(getFileExt(fname), "gz") == 0) {
    sprintf(cmd, "gunzip -c %s", fname);
    fp = popen(cmd, "r");
  } else {
    fp = fopen(fname, "r");
  }
  if (fp == NULL) {
    error("The file %s does not exist!", fname);
  }
  return fp;
}
```
user: What is the c source code of the assembly code below:

```asm
<openFile>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  call   <getFileExt@plt>
  lea    D26(%rip),%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L40
  mov    %rsp,%r12
  mov    %rbp,%rdx
  lea    D34(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  lea    D39(%rip),%rsi
  call   <popen@plt>
  mov    %rax,%r12
  test   %r12,%r12
  je     L43
L49:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x98,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L40:
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %r12,%r12
  jne    L49
L43:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <error@plt>
  jmp    L49
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D34
datatype: string
name: disassemble_data
arguments: data_tag: D39
datatype: string
name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D26: gz

tool: D34: gunzip -c %s

tool: D39: r

tool: D6: The file %s does not exist!

assistant: ```c
FILE *openFile(const char *fname) {
  FILE *fp;
  char cmd[128];
  if (strcmp(getFileExt(fname), "gz") == 0) {
    sprintf(cmd, "gunzip -c %s", fname);
    fp = popen(cmd, "r");
  } else {
    fp = fopen(fname, "r");
  }
  if (fp == NULL) {
    error("The file %s does not exist!", fname);
  }
  return fp;
}
```