ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  lea    D5(%rip),%rsi
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string
name: parse_data
arguments: tag: D7
data_type: string

tool: D5: Usage: ypkg command pkg1 [pkg2 ...]

ypkg is a simple command line for dealing with ypk package.

Commands:
  -h|--help                   Show usage
  -C|--remove                 Remove package
  -I|--install                Install package (pkg is leafpa.ypk not leafpad)
  -c|--check                  Check dependencies of package (pkg is leafpad.ypk not leafpad)
  -l|--list-files             List all files of installed package
  -k|--depend                 Show dependency of package
  -x|--unpack-binary          Unpack ypk package 
  -X|--unpack-info            Unpack ypkinfo 
  -b|--pack-directory         Pack directory to package
  -L|--list-installed         List all installed packages
  -s|--whatrequires           Show which package needs package
  -S|--whatprovides           Search which package provide this file
  --compare-version           Comprare two version strings 
  --color                     Colorize the output

  --absolute                  with -S, use absolute path

Options:
  -f|--force                  Override problems, Only work with install
       

tool: D7: %s


assistant: ```c
void usage() {
  char *usage = "Usage: ypkg command pkg1 [pkg2 ...]\n\nypkg is a simple command line for dealing with ypk package.\n\nCommands:\n  -h|--help                   Show usage\n  -C|--remove                 Remove package\n  -I|--install                Install package (pkg is leafpa.ypk not leafpad)\n  -c|--check                  Check dependencies of package (pkg is leafpad.ypk not leafpad)\n  -l|--list-files             List all files of installed package\n  -k|--depend                 Show dependency of package\n  -x|--unpack-binary          Unpack ypk package \n  -X|--unpack-info            Unpack ypkinfo \n  -b|--pack-directory         Pack directory to package\n  -L|--list-installed         List all installed packages\n  -s|--whatrequires           Show which package needs package\n  -S|--whatprovides           Search which package provide this file\n  --compare-version           Comprare two version strings \n  --color                     Colorize the output\n\n  --absolute                  with -S, use absolute path\n\nOptions:\n  -f|--force                  Override problems, Only work with install\n       ";
  printf("%s\n", usage);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L9
L15:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  while (*s2) {
    *s1 = *s2;
    s1++;
    s2++;
  }
  *s1 = '\0';
  return s1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L14
L15:
  mov    %dl,(%rax)
  add    $0x1,%rax
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L15
L14:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  while (*s2) {
    *s1 = *s2;
    s1++;
    s2++;
  }
  *s1 = '\0';
  return s1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L18
  xchg   %ax,%ax
L12:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L12
L18:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  while (*s2) {
    *s1 = *s2;
    s1++;
    s2++;
  }
  *s1 = '\0';
  return s1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L12
  xchg   %ax,%ax
L6:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L6
L12:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  while (*s2) {
    *s1 = *s2;
    s1++;
    s2++;
  }
  *s1 = '\0';
  return s1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x9,-0x18(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L20
L0:
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    -0x18(%rbp),%eax
  imul   %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  subl   $0x1,-0x18(%rbp)
L20:
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jg     L0
  mov    -0x1c(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    %edx,-0x14(%rbp)
  jne    L35
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L30
L35:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
datatype: string
name: unpack_data
arguments: label: D31
datatype: string
name: unpack_data
arguments: label: D39
datatype: string
name: unpack_data
arguments: label: D2
datatype: string

tool: D25: Enter the 10 digit ISBN code: 

tool: D31: %lld

tool: D39: Its a ISBN Code 


tool: D2: Its not a ISBN Code 


assistant: ```c
int main() {
  long long int code;
  int sum = 0, i = 9;
  printf("Enter the 10 digit ISBN code: ");
  scanf("%lld", &code);
  int r = code % 10;
  code = code / 10;
  while (code > 0) {
    sum += i * (code % 10);
    code /= 10;
    i--;
  }
  if (sum % 11 == r)
    printf("Its a ISBN Code \n");
  else
    printf("Its not a ISBN Code \n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rsi
  movabs $0x6666666666666667,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rsi,%r9
  sub    %rax,%r9
  mov    %rdx,(%rsp)
  cmp    $0x9,%rsi
  jle    L16
  mov    %rdx,%rcx
  mov    $0x9,%edi
  mov    $0x0,%r8d
  movabs $0x6666666666666667,%r10
L12:
  mov    %rcx,%rax
  imul   %r10
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  mov    %rcx,%rax
  sub    %rsi,%rax
  imul   %edi,%eax
  add    %eax,%r8d
  mov    %rcx,%rax
  mov    %rdx,%rcx
  sub    $0x1,%edi
  cmp    $0x9,%rax
  jg     L12
  mov    %rdx,(%rsp)
L32:
  movslq %r8d,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %r8d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%eax
  sub    %eax,%r8d
  cmp    %r9d,%r8d
  je     L21
  lea    D8(%rip),%rdi
  call   <printf@plt>
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L16:
  mov    $0x0,%r8d
  jmp    L32
L21:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type: string
name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D25
type: string

tool: D20: Enter the 10 digit ISBN code: 

tool: D24: %lld

tool: D8: Its not a ISBN Code 


tool: D25: Its a ISBN Code 


assistant: ```c
int main() {
  long long int code;
  int sum = 0, i = 9;
  printf("Enter the 10 digit ISBN code: ");
  scanf("%lld", &code);
  int r = code % 10;
  code = code / 10;
  while (code > 0) {
    sum += i * (code % 10);
    code /= 10;
    i--;
  }
  if (sum % 11 == r)
    printf("Its a ISBN Code \n");
  else
    printf("Its not a ISBN Code \n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D39(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rsi
  movabs $0x6666666666666667,%r10
  mov    %rsi,%rax
  mov    %rsi,%r9
  imul   %r10
  mov    %rsi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rcx
  sar    $0x2,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rax
  mov    %rcx,(%rsp)
  add    %rax,%rax
  sub    %rax,%r9
  cmp    $0x9,%rsi
  jle    L38
  mov    $0x9,%edi
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rcx,%rax
  imul   %r10
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  sub    %rsi,%rax
  imul   %edi,%eax
  sub    $0x1,%edi
  add    %eax,%r8d
  mov    %rcx,%rax
  mov    %rdx,%rcx
  cmp    $0x9,%rax
  jg     L28
  mov    %rdx,(%rsp)
L39:
  movslq %r8d,%rax
  mov    %r8d,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%eax
  sub    %eax,%r8d
  cmp    %r9d,%r8d
  je     L52
  lea    D6(%rip),%rdi
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L52:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L1
L38:
  xor    %r8d,%r8d
  jmp    L39
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D39
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D6
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string

tool: D39: Enter the 10 digit ISBN code: 

tool: D1: %lld

tool: D6: Its not a ISBN Code 


tool: D26: Its a ISBN Code 


assistant: ```c
int main() {
  long long int code;
  int sum = 0, i = 9;
  printf("Enter the 10 digit ISBN code: ");
  scanf("%lld", &code);
  int r = code % 10;
  code = code / 10;
  while (code > 0) {
    sum += i * (code % 10);
    code /= 10;
    i--;
  }
  if (sum % 11 == r)
    printf("Its a ISBN Code \n");
  else
    printf("Its not a ISBN Code \n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rsi
  movabs $0x6666666666666667,%r10
  mov    %rsi,%rax
  mov    %rsi,%r9
  imul   %r10
  mov    %rsi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rcx
  sar    $0x2,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rax
  mov    %rcx,(%rsp)
  add    %rax,%rax
  sub    %rax,%r9
  cmp    $0x9,%rsi
  jle    L59
  mov    $0x9,%edi
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rcx,%rax
  imul   %r10
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  sub    %rsi,%rax
  imul   %edi,%eax
  sub    $0x1,%edi
  add    %eax,%r8d
  mov    %rcx,%rax
  mov    %rdx,%rcx
  cmp    $0x9,%rax
  jg     L9
  mov    %rdx,(%rsp)
L8:
  movslq %r8d,%rax
  mov    %r8d,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%eax
  sub    %eax,%r8d
  cmp    %r9d,%r8d
  je     L47
  lea    D20(%rip),%rdi
  call   <printf@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L47:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L59:
  xor    %r8d,%r8d
  jmp    L8
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
datatype: string
name: disassemble_data
arguments: label: D39
datatype: string
name: disassemble_data
arguments: label: D20
datatype: string
name: disassemble_data
arguments: label: D11
datatype: string

tool: D15: Enter the 10 digit ISBN code: 

tool: D39: %lld

tool: D20: Its not a ISBN Code 


tool: D11: Its a ISBN Code 


assistant: ```c
int main() {
  long long int code;
  int sum = 0, i = 9;
  printf("Enter the 10 digit ISBN code: ");
  scanf("%lld", &code);
  int r = code % 10;
  code = code / 10;
  while (code > 0) {
    sum += i * (code % 10);
    code /= 10;
    i--;
  }
  if (sum % 11 == r)
    printf("Its a ISBN Code \n");
  else
    printf("Its not a ISBN Code \n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmdline_stdin_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
void cmdline_stdin_exit(struct cmdline *cl) {
  if (!cl)
    return;
  (void)cl;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cmdline_stdin_exit>:
  endbr64
  ret
```

assistant: ```c
void cmdline_stdin_exit(struct cmdline *cl) {
  if (!cl)
    return;
  (void)cl;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmdline_stdin_exit>:
  endbr64
  ret
```

assistant: ```c
void cmdline_stdin_exit(struct cmdline *cl) {
  if (!cl)
    return;
  (void)cl;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmdline_stdin_exit>:
  endbr64
  ret
```

assistant: ```c
void cmdline_stdin_exit(struct cmdline *cl) {
  if (!cl)
    return;
  (void)cl;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<resetTimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4000c004,%eax
  mov    (%rax),%eax
  mov    $0x4000c004,%edx
  or     $0x2,%eax
  mov    %eax,(%rdx)
  nop
  nop
  mov    $0x4000c004,%eax
  mov    (%rax),%eax
  mov    $0x4000c004,%edx
  and    $0xfffffffd,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void resetTimer() {
  (*(unsigned int *)0x4000C004) |= 0x2;
  __asm("nop");
  __asm("nop");
  (*(unsigned int *)0x4000C004) &= ~0x2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<resetTimer>:
  endbr64
  orl    $0x2,0x4000c004
  nop
  nop
  andl   $0xfffffffd,0x4000c004
  ret
```

assistant: ```c
void resetTimer() {
  (*(unsigned int *)0x4000C004) |= 0x2;
  __asm("nop");
  __asm("nop");
  (*(unsigned int *)0x4000C004) &= ~0x2;
}
```
user: What is the c source code of the assembly code below?

```asm
<resetTimer>:
  endbr64
  orl    $0x2,0x4000c004
  nop
  nop
  andl   $0xfffffffd,0x4000c004
  ret
```

assistant: ```c
void resetTimer() {
  (*(unsigned int *)0x4000C004) |= 0x2;
  __asm("nop");
  __asm("nop");
  (*(unsigned int *)0x4000C004) &= ~0x2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<resetTimer>:
  endbr64
  orl    $0x2,0x4000c004
  nop
  nop
  andl   $0xfffffffd,0x4000c004
  ret
```

assistant: ```c
void resetTimer() {
  (*(unsigned int *)0x4000C004) |= 0x2;
  __asm("nop");
  __asm("nop");
  (*(unsigned int *)0x4000C004) &= ~0x2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D166(%rip),%xmm0
  movss  %xmm0,-0x80(%rbp)
  movss  D178(%rip),%xmm0
  movss  %xmm0,-0x7c(%rbp)
  movss  D165(%rip),%xmm0
  movss  %xmm0,-0x78(%rbp)
  movss  D178(%rip),%xmm0
  movss  %xmm0,-0x74(%rbp)
  movss  D165(%rip),%xmm0
  movss  %xmm0,-0x70(%rbp)
  movss  D178(%rip),%xmm0
  movss  %xmm0,-0x6c(%rbp)
  movss  D165(%rip),%xmm0
  movss  %xmm0,-0x68(%rbp)
  movss  D10(%rip),%xmm0
  movss  %xmm0,-0x64(%rbp)
  movss  D108(%rip),%xmm0
  movss  %xmm0,-0x60(%rbp)
  movss  D45(%rip),%xmm0
  movss  %xmm0,-0x5c(%rbp)
  movss  D113(%rip),%xmm0
  movss  %xmm0,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x54(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x50(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x3c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  D113(%rip),%xmm0
  movss  %xmm0,-0x34(%rbp)
  movss  D113(%rip),%xmm0
  movss  %xmm0,-0x30(%rbp)
  movss  D113(%rip),%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movss  D113(%rip),%xmm0
  movss  %xmm0,-0x28(%rbp)
  movss  D113(%rip),%xmm0
  movss  %xmm0,-0x24(%rbp)
  movss  D113(%rip),%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  D113(%rip),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    -0x40(%rbp),%rdx
  lea    -0x80(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__ESBMC_check_stability@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D166
data_type: f32
name: unpack_data
arguments: label: D178
data_type: byte[4]
name: unpack_data
arguments: label: D165
data_type: f32
name: unpack_data
arguments: label: D10
data_type: byte[4]
name: unpack_data
arguments: label: D108
data_type: f32
name: unpack_data
arguments: label: D45
data_type: byte[4]
name: unpack_data
arguments: label: D113
data_type: f32

tool: D166: 1

tool: {"D178": [0x00,0x00,0x00,0xc0]}

tool: D165: 1.96875

tool: {"D10": [0x00,0x00,0xfc,0xbf]}

tool: D108: 0.65625

tool: {"D45": [0x00,0x00,0x20,0xbe]}

tool: D113: 0.03125

assistant: ```c
int main() {
  float a[] = {1.000000000000000, -2.000000000000000, 1.968750000000000, -2.000000000000000, 1.968750000000000, -2.000000000000000, 1.968750000000000, -1.968750000000000, 0.656250000000000, -0.156250000000000, 0.031250000000000, 0, 0};
  float b[] = {0, 0, 0, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0, 0, 0};
  assert(__ESBMC_check_stability(a, b));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,(%rsp)
  movss  D14(%rip),%xmm1
  movss  %xmm1,0x4(%rsp)
  movss  D16(%rip),%xmm0
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x10(%rsp)
  movss  %xmm1,0x14(%rsp)
  movss  %xmm0,0x18(%rsp)
  movl   $0xbffc0000,0x1c(%rsp)
  movl   $0x3f280000,0x20(%rsp)
  movl   $0xbe200000,0x24(%rsp)
  movss  D0(%rip),%xmm0
  movss  %xmm0,0x28(%rsp)
  movl   $0x0,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x40(%rsp)
  movl   $0x0,0x44(%rsp)
  movl   $0x0,0x48(%rsp)
  movss  %xmm0,0x4c(%rsp)
  movss  %xmm0,0x50(%rsp)
  movss  %xmm0,0x54(%rsp)
  movss  %xmm0,0x58(%rsp)
  movss  %xmm0,0x5c(%rsp)
  movss  %xmm0,0x60(%rsp)
  movss  %xmm0,0x64(%rsp)
  movl   $0x0,0x68(%rsp)
  movl   $0x0,0x6c(%rsp)
  movl   $0x0,0x70(%rsp)
  lea    0x40(%rsp),%rsi
  mov    %rsp,%rdi
  call   <__ESBMC_check_stability@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x88,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
datatype: byte[4]
name: disassemble_data
arguments: tag: D16
datatype: f32
name: disassemble_data
arguments: tag: D0
datatype: f32

tool: {"D14": [0x00,0x00,0x00,0xc0]}

tool: D16: 1.96875

tool: D0: 0.03125

assistant: ```c
int main() {
  float a[] = {1.000000000000000, -2.000000000000000, 1.968750000000000, -2.000000000000000, 1.968750000000000, -2.000000000000000, 1.968750000000000, -1.968750000000000, 0.656250000000000, -0.156250000000000, 0.031250000000000, 0, 0};
  float b[] = {0, 0, 0, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0, 0, 0};
  assert(__ESBMC_check_stability(a, b));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  movabs $0xc00000003f800000,%rax
  mov    %rsp,%rdi
  lea    0x40(%rsp),%rsi
  movq   $0x3d000000,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x68(%rsp)
  movl   $0x0,0x70(%rsp)
  mov    %rax,(%rsp)
  add    $0x7c0000,%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0xbffc00003ffc0000,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xbe2000003f280000,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x3d00000000000000,%rax
  mov    %rax,0x48(%rsp)
  add    $0x3d000000,%rax
  mov    %rax,0x50(%rsp)
  mov    %rax,0x58(%rsp)
  mov    %rax,0x60(%rsp)
  call   <__ESBMC_check_stability@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x88,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  float a[] = {1.000000000000000, -2.000000000000000, 1.968750000000000, -2.000000000000000, 1.968750000000000, -2.000000000000000, 1.968750000000000, -1.968750000000000, 0.656250000000000, -0.156250000000000, 0.031250000000000, 0, 0};
  float b[] = {0, 0, 0, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0.031250000000000, 0, 0, 0};
  assert(__ESBMC_check_stability(a, b));
  return 0;
}
```