ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floats_quat_to_angleaxis>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  mov    $0x4,%esi
  call   <floats_normalize@plt>
  lea    0x14(%rsp),%rdi
  mov    $0x3,%esi
  call   <floats_magnitude@plt>
  movss  0x10(%rsp),%xmm1
  movss  %xmm0,0xc(%rsp)
  call   <atan2@plt>
  lea    (%rax,%rax,1),%edi
  call   <mod2pi@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%rbx)
  movss  0xc(%rsp),%xmm2
  ucomiss D3(%rip),%xmm2
  jp     L14
  jne    L14
  movl   $0x3f800000,0x4(%rbx)
  movl   $0x0,0x8(%rbx)
  pxor   %xmm0,%xmm0
  jmp    L5
L14:
  movss  0x14(%rsp),%xmm0
  movss  0xc(%rsp),%xmm3
  divss  %xmm3,%xmm0
  movss  %xmm0,0x4(%rbx)
  movss  0x18(%rsp),%xmm0
  divss  %xmm3,%xmm0
  movss  %xmm0,0x8(%rbx)
  movss  0x1c(%rsp),%xmm0
  divss  %xmm3,%xmm0
L5:
  movss  %xmm0,0xc(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x00]}

assistant: ```c
void floats_quat_to_angleaxis(const float _q[4], float r[4]) {
  float q[4];
  floats_normalize(_q, 4, q);
  float mag = floats_magnitude(&q[1], 3);
  r[0] = (float)mod2pi(2 * atan2(mag, q[0]));
  if (mag != 0) {
    r[1] = q[1] / mag;
    r[2] = q[2] / mag;
    r[3] = q[3] / mag;
  } else {
    r[1] = 1;
    r[2] = 0;
    r[3] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<floats_quat_to_angleaxis>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  call   <floats_normalize@plt>
  lea    0x14(%rsp),%rdi
  mov    $0x3,%esi
  call   <floats_magnitude@plt>
  movss  0x10(%rsp),%xmm1
  movss  %xmm0,0xc(%rsp)
  call   <atan2@plt>
  lea    (%rax,%rax,1),%edi
  call   <mod2pi@plt>
  movss  0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %rax,%xmm1
  ucomiss %xmm2,%xmm0
  movss  %xmm1,(%rbx)
  jp     L33
  jne    L33
  movq   $0x3f800000,0x4(%rbx)
  pxor   %xmm1,%xmm1
L23:
  movss  %xmm1,0xc(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  movss  0x14(%rsp),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rbx)
  movss  0x18(%rsp),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rbx)
  movss  0x1c(%rsp),%xmm1
  divss  %xmm0,%xmm1
  jmp    L23
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_quat_to_angleaxis(const float _q[4], float r[4]) {
  float q[4];
  floats_normalize(_q, 4, q);
  float mag = floats_magnitude(&q[1], 3);
  r[0] = (float)mod2pi(2 * atan2(mag, q[0]));
  if (mag != 0) {
    r[1] = q[1] / mag;
    r[2] = q[2] / mag;
    r[3] = q[3] / mag;
  } else {
    r[1] = 1;
    r[2] = 0;
    r[3] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<floats_quat_to_angleaxis>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  call   <floats_normalize@plt>
  lea    0x14(%rsp),%rdi
  mov    $0x3,%esi
  call   <floats_magnitude@plt>
  movss  0x10(%rsp),%xmm1
  movss  %xmm0,0xc(%rsp)
  call   <atan2@plt>
  lea    (%rax,%rax,1),%edi
  call   <mod2pi@plt>
  movss  0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  pxor   %xmm3,%xmm3
  cvtsi2ss %rax,%xmm1
  ucomiss %xmm3,%xmm0
  movss  %xmm1,(%rbx)
  jp     L14
  jne    L14
  mov    D7(%rip),%rax
  pxor   %xmm1,%xmm1
  mov    %rax,0x4(%rbx)
L2:
  movss  %xmm1,0xc(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x30,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movss  0x14(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  divss  %xmm0,%xmm1
  divss  %xmm0,%xmm2
  unpcklps %xmm2,%xmm1
  movlps %xmm1,0x4(%rbx)
  movss  0x1c(%rsp),%xmm1
  divss  %xmm0,%xmm1
  jmp    L2
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: f32[2]

tool: {"D7": [1.0,0.0]}

assistant: ```c
void floats_quat_to_angleaxis(const float _q[4], float r[4]) {
  float q[4];
  floats_normalize(_q, 4, q);
  float mag = floats_magnitude(&q[1], 3);
  r[0] = (float)mod2pi(2 * atan2(mag, q[0]));
  if (mag != 0) {
    r[1] = q[1] / mag;
    r[2] = q[2] / mag;
    r[3] = q[3] / mag;
  } else {
    r[1] = 1;
    r[2] = 0;
    r[3] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bubble_sort_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L26
L6:
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L43:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L19
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L19:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L43
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <print@plt>
  subl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x0,-0x8(%rbp)
  jns    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void bubble_sort_reverse(int v[], int length) {
  for (int i = length - 1; i >= 0; i--) {
    for (int j = 0; j < i; j++) {
      if (v[i] < v[j]) {
        swap(v, i, j);
      }
    }
    print(v, i, length);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bubble_sort_reverse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L0
  mov    %rdi,%rbp
  lea    -0x2(%rsi),%r15d
  cltq
  lea    (%rdi,%rax,4),%r12
  jmp    L35
L42:
  lea    0x1(%rbx),%rax
  cmp    %rbx,%r13
  je     L52
  mov    %rax,%rbx
L5:
  mov    %ebx,%edx
  mov    0x0(%rbp,%rbx,4),%eax
  cmp    %eax,(%r12)
  jge    L42
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L42
L52:
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <print@plt>
L53:
  sub    $0x1,%r15d
  sub    $0x4,%r12
L35:
  lea    0x1(%r15),%r14d
  mov    %r15d,%r13d
  mov    $0x0,%ebx
  test   %r14d,%r14d
  jg     L5
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <print@plt>
  test   %r15d,%r15d
  jns    L53
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bubble_sort_reverse(int v[], int length) {
  for (int i = length - 1; i >= 0; i--) {
    for (int j = 0; j < i; j++) {
      if (v[i] < v[j]) {
        swap(v, i, j);
      }
    }
    print(v, i, length);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bubble_sort_reverse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  sub    $0x1,%r13d
  js     L41
  movslq %r13d,%rax
  lea    -0x1(%r13),%r15d
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  lea    (%rdi,%rax,4),%r14
  mov    %r15,%r12
  test   %r13d,%r13d
  jg     L47
  jmp    L46
  nopl   (%rax)
L30:
  lea    0x1(%rbx),%rax
  cmp    %rbx,%r15
  je     L33
L71:
  mov    %rax,%rbx
L47:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %ebx,%edx
  cmp    %eax,(%r14)
  jge    L30
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    0x1(%rbx),%rax
  cmp    %rbx,%r15
  jne    L71
L33:
  mov    0xc(%rsp),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <print@plt>
L12:
  mov    %r12d,%r13d
  sub    $0x4,%r14
  xor    %ebx,%ebx
  lea    -0x1(%r13),%r15d
  mov    %r15,%r12
  test   %r13d,%r13d
  jg     L47
L46:
  mov    0xc(%rsp),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <print@plt>
  test   %r12d,%r12d
  jns    L12
L41:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bubble_sort_reverse(int v[], int length) {
  for (int i = length - 1; i >= 0; i--) {
    for (int j = 0; j < i; j++) {
      if (v[i] < v[j]) {
        swap(v, i, j);
      }
    }
    print(v, i, length);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubble_sort_reverse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  sub    $0x1,%r13d
  js     L40
  movslq %r13d,%rax
  lea    -0x1(%r13),%r15d
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  lea    (%rdi,%rax,4),%r14
  mov    %r15,%r12
  test   %r13d,%r13d
  jg     L5
  jmp    L47
  nopl   (%rax)
L8:
  lea    0x1(%rbx),%rax
  cmp    %rbx,%r15
  je     L4
L23:
  mov    %rax,%rbx
L5:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %ebx,%edx
  cmp    %eax,(%r14)
  jge    L8
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    0x1(%rbx),%rax
  cmp    %rbx,%r15
  jne    L23
L4:
  mov    0xc(%rsp),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <print@plt>
L1:
  mov    %r12d,%r13d
  sub    $0x4,%r14
  xor    %ebx,%ebx
  lea    -0x1(%r13),%r15d
  mov    %r15,%r12
  test   %r13d,%r13d
  jg     L5
L47:
  mov    0xc(%rsp),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <print@plt>
  test   %r12d,%r12d
  jns    L1
L40:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bubble_sort_reverse(int v[], int length) {
  for (int i = length - 1; i >= 0; i--) {
    for (int j = 0; j < i; j++) {
      if (v[i] < v[j]) {
        swap(v, i, j);
      }
    }
    print(v, i, length);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <gethostname@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  jne    L0
  mov    $0x1,%eax
  jmp    L13
L0:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D6: %s


assistant: ```c
int main() {
  struct hostent *hostinfo;
  char socket_host[255];
  gethostname(socket_host, sizeof(socket_host));
  hostinfo = gethostbyname(socket_host);
  if (hostinfo == NULL)
    return 1;
  printf("%s\n", socket_host);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0xff,%esi
  mov    %rbx,%rdi
  call   <gethostname@plt>
  mov    %rbx,%rdi
  call   <gethostbyname@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L6
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L6:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x110,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: %s


assistant: ```c
int main() {
  struct hostent *hostinfo;
  char socket_host[255];
  gethostname(socket_host, sizeof(socket_host));
  hostinfo = gethostbyname(socket_host);
  if (hostinfo == NULL)
    return 1;
  printf("%s\n", socket_host);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xff,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gethostname@plt>
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L17
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L17:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x110,%rsp
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %s


assistant: ```c
int main() {
  struct hostent *hostinfo;
  char socket_host[255];
  gethostname(socket_host, sizeof(socket_host));
  hostinfo = gethostbyname(socket_host);
  if (hostinfo == NULL)
    return 1;
  printf("%s\n", socket_host);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xff,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gethostname@plt>
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L14
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L14:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x110,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4: %s


assistant: ```c
int main() {
  struct hostent *hostinfo;
  char socket_host[255];
  gethostname(socket_host, sizeof(socket_host));
  hostinfo = gethostbyname(socket_host);
  if (hostinfo == NULL)
    return 1;
  printf("%s\n", socket_host);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L79
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  mov    $0x0,%edi
  jmp    L84
L45:
  cmp    $0x31,%eax
  jle    L14
  sub    $0x32,%eax
  add    $0x1,%edx
L9:
  test   %eax,%eax
  jle    L124
L84:
  cmp    $0x63,%eax
  jle    L45
  sub    $0x64,%eax
  add    $0x1,%esi
  jmp    L9
L14:
  cmp    $0x13,%eax
  jle    L10
  sub    $0x14,%eax
  add    $0x1,%ecx
  jmp    L9
L10:
  cmp    $0x9,%eax
  jle    L67
  sub    $0xa,%eax
  add    $0x1,%r8d
  jmp    L9
L67:
  cmp    $0x4,%eax
  jle    L52
  sub    $0x5,%eax
  add    $0x1,%r9d
  jmp    L9
L52:
  sub    $0x1,%eax
  add    $0x1,%edi
  jmp    L9
L124:
  mov    %eax,0x4(%rsp)
L101:
  sub    $0x8,%rsp
  push   %rdi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L79:
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  mov    $0x0,%edi
  jmp    L101
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D22
type_infered: string
name: extract_symbolic_data
arguments: data_label: D23
type_infered: string

tool: D0: Please enter the amount of money you wish to withdraw: 

tool: D22: %d

tool: D23: You recieved %d hundred(s)
 You recieved %d fifty(s)
 You recieved %d twenty(s)
 You recieved %d ten(s)
 You recieved %d five(s)
 You recieved %d one(s)


assistant: ```c
int main() {
  int numChange = 0;
  int billsChange[] = {0, 0, 0, 0, 0, 0};
  printf("Please enter the amount of money you wish to withdraw: ");
  scanf("%d", &numChange);
  while (numChange > 0) {
    if (numChange >= 100) {
      numChange -= 100;
      billsChange[5]++;
    } else if (numChange >= 50) {
      numChange -= 50;
      billsChange[4]++;
    } else if (numChange >= 20) {
      numChange -= 20;
      billsChange[3]++;
    } else if (numChange >= 10) {
      numChange -= 10;
      billsChange[2]++;
    } else if (numChange >= 5) {
      numChange -= 5;
      billsChange[1]++;
    } else if (numChange >= 1) {
      numChange -= 1;
      billsChange[0]++;
    }
  }
  printf("You recieved %d hundred(s)\n You recieved %d fifty(s)\n You recieved %d twenty(s)\n You recieved %d ten(s)\n You recieved %d five(s)\n You recieved %d one(s)\n", billsChange[5], billsChange[4], billsChange[3], billsChange[2], billsChange[1], billsChange[0]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  xor    %esi,%esi
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  xor    %edi,%edi
  test   %eax,%eax
  jg     L12
  jmp    L130
  nopl   (%rax)
L92:
  sub    $0x64,%eax
  add    $0x1,%esi
L124:
  test   %eax,%eax
  je     L54
L12:
  cmp    $0x63,%eax
  jg     L92
  cmp    $0x31,%eax
  jle    L79
  sub    $0x32,%eax
  add    $0x1,%edx
  test   %eax,%eax
  jne    L12
L54:
  movl   $0x0,0x4(%rsp)
L130:
  sub    $0x8,%rsp
  xor    %eax,%eax
  push   %rdi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  cmp    $0x13,%eax
  jle    L36
  sub    $0x14,%eax
  add    $0x1,%ecx
  jmp    L124
  nopl   (%rax)
L36:
  cmp    $0x9,%eax
  jle    L93
  sub    $0xa,%eax
  add    $0x1,%r8d
  jmp    L124
L93:
  cmp    $0x4,%eax
  jle    L66
  sub    $0x5,%eax
  add    $0x1,%r9d
  jmp    L124
L66:
  sub    $0x1,%eax
  add    $0x1,%edi
  jmp    L124
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D16
datatype: string

tool: D11: Please enter the amount of money you wish to withdraw: 

tool: D0: %d

tool: D16: You recieved %d hundred(s)
 You recieved %d fifty(s)
 You recieved %d twenty(s)
 You recieved %d ten(s)
 You recieved %d five(s)
 You recieved %d one(s)


assistant: ```c
int main() {
  int numChange = 0;
  int billsChange[] = {0, 0, 0, 0, 0, 0};
  printf("Please enter the amount of money you wish to withdraw: ");
  scanf("%d", &numChange);
  while (numChange > 0) {
    if (numChange >= 100) {
      numChange -= 100;
      billsChange[5]++;
    } else if (numChange >= 50) {
      numChange -= 50;
      billsChange[4]++;
    } else if (numChange >= 20) {
      numChange -= 20;
      billsChange[3]++;
    } else if (numChange >= 10) {
      numChange -= 10;
      billsChange[2]++;
    } else if (numChange >= 5) {
      numChange -= 5;
      billsChange[1]++;
    } else if (numChange >= 1) {
      numChange -= 1;
      billsChange[0]++;
    }
  }
  printf("You recieved %d hundred(s)\n You recieved %d fifty(s)\n You recieved %d twenty(s)\n You recieved %d ten(s)\n You recieved %d five(s)\n You recieved %d one(s)\n", billsChange[5], billsChange[4], billsChange[3], billsChange[2], billsChange[1], billsChange[0]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  xor    %esi,%esi
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  xor    %edi,%edi
  test   %eax,%eax
  jg     L98
  jmp    L68
  nopl   (%rax)
L103:
  sub    $0x64,%eax
  add    $0x1,%esi
L59:
  test   %eax,%eax
  je     L135
L98:
  cmp    $0x63,%eax
  jg     L103
  cmp    $0x31,%eax
  jle    L37
  sub    $0x32,%eax
  add    $0x1,%edx
  test   %eax,%eax
  jne    L98
L135:
  movl   $0x0,0x4(%rsp)
L68:
  sub    $0x8,%rsp
  xor    %eax,%eax
  push   %rdi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  cmp    $0x13,%eax
  jle    L78
  sub    $0x14,%eax
  add    $0x1,%ecx
  jmp    L59
  nopl   (%rax)
L78:
  cmp    $0x9,%eax
  jle    L82
  sub    $0xa,%eax
  add    $0x1,%r8d
  jmp    L59
L82:
  cmp    $0x4,%eax
  jle    L55
  sub    $0x5,%eax
  add    $0x1,%r9d
  jmp    L59
L55:
  sub    $0x1,%eax
  add    $0x1,%edi
  jmp    L59
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
datatype: string
name: unpack_data
arguments: label: D7
datatype: string
name: unpack_data
arguments: label: D21
datatype: string

tool: D18: Please enter the amount of money you wish to withdraw: 

tool: D7: %d

tool: D21: You recieved %d hundred(s)
 You recieved %d fifty(s)
 You recieved %d twenty(s)
 You recieved %d ten(s)
 You recieved %d five(s)
 You recieved %d one(s)


assistant: ```c
int main() {
  int numChange = 0;
  int billsChange[] = {0, 0, 0, 0, 0, 0};
  printf("Please enter the amount of money you wish to withdraw: ");
  scanf("%d", &numChange);
  while (numChange > 0) {
    if (numChange >= 100) {
      numChange -= 100;
      billsChange[5]++;
    } else if (numChange >= 50) {
      numChange -= 50;
      billsChange[4]++;
    } else if (numChange >= 20) {
      numChange -= 20;
      billsChange[3]++;
    } else if (numChange >= 10) {
      numChange -= 10;
      billsChange[2]++;
    } else if (numChange >= 5) {
      numChange -= 5;
      billsChange[1]++;
    } else if (numChange >= 1) {
      numChange -= 1;
      billsChange[0]++;
    }
  }
  printf("You recieved %d hundred(s)\n You recieved %d fifty(s)\n You recieved %d twenty(s)\n You recieved %d ten(s)\n You recieved %d five(s)\n You recieved %d one(s)\n", billsChange[5], billsChange[4], billsChange[3], billsChange[2], billsChange[1], billsChange[0]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IntervalsOverlap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L24
  mov    -0x1c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L26
L24:
  mov    $0x0,%eax
  jmp    L22
L26:
  mov    $0x1,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int IntervalsOverlap(int astart, int asize, int bstart, int bsize) {
  int aend = astart + asize;
  int bend = bstart + bsize;
  if (astart >= bend || bstart >= aend) {
    return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<IntervalsOverlap>:
  endbr64
  add    %edx,%ecx
  cmp    %ecx,%edi
  setge  %al
  add    %esi,%edi
  cmp    %edx,%edi
  setle  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int IntervalsOverlap(int astart, int asize, int bstart, int bsize) {
  int aend = astart + asize;
  int bend = bstart + bsize;
  if (astart >= bend || bstart >= aend) {
    return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<IntervalsOverlap>:
  endbr64
  add    %edx,%ecx
  cmp    %ecx,%edi
  setge  %al
  add    %esi,%edi
  cmp    %edx,%edi
  setle  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int IntervalsOverlap(int astart, int asize, int bstart, int bsize) {
  int aend = astart + asize;
  int bend = bstart + bsize;
  if (astart >= bend || bstart >= aend) {
    return 0;
  }
  return 1;
}
```