ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<itoa>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    -0x2(%rsi),%eax
  cmp    $0x22,%eax
  setbe  %dil
  call   <assert@plt>
  test   %r12,%r12
  je     L54
  test   %rbp,%rbp
  je     L54
  cmp    $0x1,%rbp
  je     L88
  test   %ebx,%ebx
  jns    L115
  cmp    $0x2,%rbp
  jne    L115
L88:
  movb   $0x0,(%r12)
  lea    D21(%rip),%rax
L9:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L76
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L115:
  mov    0xc(%rsp),%eax
  sub    $0x1,%rbp
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r15
  lea    D3(%rip),%r14
  shr    $0x1f,%eax
  sub    %rax,%rbp
  mov    %rbp,(%rsp)
  xor    %ebp,%ebp
  jmp    L41
  nopl   0x0(%rax)
L108:
  cmp    %rbx,(%rsp)
  jbe    L88
L41:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <div@plt>
  mov    0x20(%rsp),%edi
  mov    0x18(%rsp),%rbp
  call   <abs@plt>
  mov    %rbx,%rdx
  add    $0x1,%rbx
  movzbl (%r14,%rax,1),%eax
  mov    %al,-0x1(%r12,%rbx,1)
  test   %rbp,%rbp
  jne    L108
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L49
  movb   $0x2d,(%r12,%rbx,1)
  lea    0x2(%rdx),%rbx
L49:
  movb   $0x0,(%r12,%rbx,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x38,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <reverse@plt>
  nopl   0x0(%rax)
L54:
  lea    D21(%rip),%rax
  jmp    L9
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: 

tool: D3: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
const char *itoa(int n, int base, char *buffer, size_t size) {
  size_t i = 0;
  size_t max_digits;
  div_t quot_rem = {n, 0};
  assert(base > 1 && base <= 36);
  if (buffer == NULL || size == 0)
    return "";
  if (size == 1 || (n < 0 && size == 2)) {
    buffer[0] = '\0';
    return "";
  }
  max_digits = size - 1 - (n < 0 ? 1 : 0);
  do {
    quot_rem = div(quot_rem.quot, base);
    buffer[i++] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[abs(quot_rem.rem)];
  } while (quot_rem.quot != 0 && i < max_digits);
  if (quot_rem.quot == 0) {
    if (n < 0)
      buffer[i++] = '-';
    buffer[i] = '\0';
    return reverse(buffer);
  } else {
    buffer[0] = '\0';
    return "";
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L71
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L7
L71:
  mov    $0x1,%eax
  jmp    L19
L7:
  mov    $0x0,%eax
L19:
  mov    %eax,-0xc(%rbp)
  jmp    L10
L110:
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L110
L16:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L99
  movl   $0x1,-0x10(%rbp)
L99:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <file_is_exist@plt>
  test   %eax,%eax
  jne    L124
  mov    -0x8(%rbp),%rax
  mov    $0x1ff,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jns    L124
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L61
L124:
  cmpl   $0x0,-0x10(%rbp)
  jne    L40
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  addl   $0x1,-0xc(%rbp)
  jmp    L10
L40:
  nop
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L61:
  leave
  ret
```

assistant: ```c
int my_mkdir(const char *directory) {
  int quit = 0;
  int tmpi;
  char *dir;
  dir = my_strdup(directory);
  for (tmpi = (*dir == '/' || *dir == '\\'); 1; tmpi++) {
    for (; dir[tmpi] && (dir[tmpi] != '/' && dir[tmpi] != '\\'); tmpi++)
      ;
    if (!dir[tmpi])
      quit = 1;
    dir[tmpi] = '\0';
    if (!file_is_exist(dir)) {
      if (mkdir(dir, 0777) < 0) {
        free(dir);
        return -1;
      }
    }
    if (quit)
      break;
    else
      dir[tmpi] = '/';
  }
  free(dir);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_mkdir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <my_strdup@plt>
  mov    %rax,%rbp
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  sete   %bl
  cmp    $0x5c,%al
  sete   %al
  or     %eax,%ebx
  movzbl %bl,%ebx
  add    %rbp,%rbx
L38:
  mov    %rbx,%r12
  movzbl (%rbx),%eax
  test   %al,%al
  je     L3
  cmp    $0x2f,%al
  je     L50
  cmp    $0x5c,%al
  je     L50
L52:
  add    $0x1,%rbx
  jmp    L38
L50:
  movb   $0x0,(%r12)
  mov    %rbp,%rdi
  call   <file_is_exist@plt>
  test   %eax,%eax
  je     L13
L44:
  movb   $0x2f,(%r12)
  jmp    L52
L3:
  mov    %rbp,%rdi
  call   <file_is_exist@plt>
  test   %eax,%eax
  je     L55
L108:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L68:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jns    L44
L105:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L68
L55:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jns    L108
  jmp    L105
```

assistant: ```c
int my_mkdir(const char *directory) {
  int quit = 0;
  int tmpi;
  char *dir;
  dir = my_strdup(directory);
  for (tmpi = (*dir == '/' || *dir == '\\'); 1; tmpi++) {
    for (; dir[tmpi] && (dir[tmpi] != '/' && dir[tmpi] != '\\'); tmpi++)
      ;
    if (!dir[tmpi])
      quit = 1;
    dir[tmpi] = '\0';
    if (!file_is_exist(dir)) {
      if (mkdir(dir, 0777) < 0) {
        free(dir);
        return -1;
      }
    }
    if (quit)
      break;
    else
      dir[tmpi] = '/';
  }
  free(dir);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_mkdir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <my_strdup@plt>
  mov    %rax,%rbp
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  sete   %bl
  cmp    $0x5c,%al
  sete   %al
  or     %eax,%ebx
  movzbl %bl,%ebx
  add    %rbp,%rbx
L85:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L37
  mov    %rbp,%rdi
  call   <file_is_exist@plt>
  test   %eax,%eax
  je     L101
L74:
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L102:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  cmp    $0x2f,%al
  je     L90
  cmp    $0x5c,%al
  je     L90
  add    $0x1,%rbx
  jmp    L85
  xchg   %ax,%ax
L90:
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <file_is_exist@plt>
  test   %eax,%eax
  je     L61
L67:
  movb   $0x2f,(%rbx)
  add    $0x1,%rbx
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L61:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jns    L67
L38:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L102
  nopl   0x0(%rax)
L101:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jns    L74
  jmp    L38
```

assistant: ```c
int my_mkdir(const char *directory) {
  int quit = 0;
  int tmpi;
  char *dir;
  dir = my_strdup(directory);
  for (tmpi = (*dir == '/' || *dir == '\\'); 1; tmpi++) {
    for (; dir[tmpi] && (dir[tmpi] != '/' && dir[tmpi] != '\\'); tmpi++)
      ;
    if (!dir[tmpi])
      quit = 1;
    dir[tmpi] = '\0';
    if (!file_is_exist(dir)) {
      if (mkdir(dir, 0777) < 0) {
        free(dir);
        return -1;
      }
    }
    if (quit)
      break;
    else
      dir[tmpi] = '/';
  }
  free(dir);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_mkdir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <my_strdup@plt>
  mov    %rax,%rbp
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  sete   %bl
  cmp    $0x5c,%al
  sete   %al
  or     %eax,%ebx
  movzbl %bl,%ebx
  add    %rbp,%rbx
L0:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L15
  mov    %rbp,%rdi
  call   <file_is_exist@plt>
  test   %eax,%eax
  je     L23
L77:
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  cmp    $0x2f,%al
  je     L96
  cmp    $0x5c,%al
  je     L96
  add    $0x1,%rbx
  jmp    L0
  xchg   %ax,%ax
L96:
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <file_is_exist@plt>
  test   %eax,%eax
  je     L95
L49:
  movb   $0x2f,(%rbx)
  add    $0x1,%rbx
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L95:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jns    L49
L29:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L13
  nopl   0x0(%rax)
L23:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jns    L77
  jmp    L29
```

assistant: ```c
int my_mkdir(const char *directory) {
  int quit = 0;
  int tmpi;
  char *dir;
  dir = my_strdup(directory);
  for (tmpi = (*dir == '/' || *dir == '\\'); 1; tmpi++) {
    for (; dir[tmpi] && (dir[tmpi] != '/' && dir[tmpi] != '\\'); tmpi++)
      ;
    if (!dir[tmpi])
      quit = 1;
    dir[tmpi] = '\0';
    if (!file_is_exist(dir)) {
      if (mkdir(dir, 0777) < 0) {
        free(dir);
        return -1;
      }
    }
    if (quit)
      break;
    else
      dir[tmpi] = '/';
  }
  free(dir);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DESIntDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x44038000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L59
  mov    -0x8(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  jne    L59
  mov    -0x8(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  jne    L59
  mov    -0x8(%rbp),%eax
  and    $0x10000,%eax
  test   %eax,%eax
  jne    L59
  mov    -0x8(%rbp),%eax
  and    $0x20000,%eax
  test   %eax,%eax
  jne    L59
  mov    -0x8(%rbp),%eax
  and    $0x40000,%eax
  test   %eax,%eax
  je     L2
L59:
  mov    $0x1,%eax
  jmp    L9
L2:
  mov    $0x0,%eax
L9:
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x7fd0,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  and    $0x7,%eax
  not    %eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  sub    $0x7fd0,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  and    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0x40,%eax
  cltq
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  movzwl %ax,%eax
  not    %eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  add    $0x40,%eax
  cltq
  mov    %rax,%rdx
  mov    %ecx,%eax
  and    %esi,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void DESIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x44038000);
  ASSERT((ui32IntFlags & 0x00000001) || (ui32IntFlags & 0x00000002) || (ui32IntFlags & 0x00000004) || (ui32IntFlags & 0x00010000) || (ui32IntFlags & 0x00020000) || (ui32IntFlags & 0x00040000));
  (*((volatile uint32_t *)(ui32Base + 0xFFFF8030))) &= ~((ui32IntFlags & 0x00070000) >> 16);
  (*((volatile uint32_t *)(ui32Base + 0x00000040))) &= ~(ui32IntFlags & 0x0000ffff);
}
```
user: What is the c source code of the assembly code below?

```asm
<DESIntDisable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0x44038000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  test   $0x70007,%ebp
  setne  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  mov    -0x7fd0(%ebx),%edx
  mov    %ebp,%eax
  sar    $0x10,%eax
  and    $0x7,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x7fd0(%ebx)
  add    $0x40,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  movzwl %bp,%ebp
  not    %ebp
  and    %eax,%ebp
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void DESIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x44038000);
  ASSERT((ui32IntFlags & 0x00000001) || (ui32IntFlags & 0x00000002) || (ui32IntFlags & 0x00000004) || (ui32IntFlags & 0x00010000) || (ui32IntFlags & 0x00020000) || (ui32IntFlags & 0x00040000));
  (*((volatile uint32_t *)(ui32Base + 0xFFFF8030))) &= ~((ui32IntFlags & 0x00070000) >> 16);
  (*((volatile uint32_t *)(ui32Base + 0x00000040))) &= ~(ui32IntFlags & 0x0000ffff);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<DESIntDisable>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x44038000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  test   $0x70007,%ebp
  setne  %dil
  call   <ASSERT@plt>
  mov    %ebp,%eax
  mov    -0x7fd0(%ebx),%edx
  movzwl %bp,%ebp
  sar    $0x10,%eax
  not    %ebp
  and    $0x7,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x7fd0(%ebx)
  add    $0x40,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  and    %eax,%ebp
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void DESIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x44038000);
  ASSERT((ui32IntFlags & 0x00000001) || (ui32IntFlags & 0x00000002) || (ui32IntFlags & 0x00000004) || (ui32IntFlags & 0x00010000) || (ui32IntFlags & 0x00020000) || (ui32IntFlags & 0x00040000));
  (*((volatile uint32_t *)(ui32Base + 0xFFFF8030))) &= ~((ui32IntFlags & 0x00070000) >> 16);
  (*((volatile uint32_t *)(ui32Base + 0x00000040))) &= ~(ui32IntFlags & 0x0000ffff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<DESIntDisable>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x44038000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  test   $0x70007,%ebp
  setne  %dil
  call   <ASSERT@plt>
  mov    %ebp,%eax
  mov    -0x7fd0(%ebx),%edx
  movzwl %bp,%ebp
  sar    $0x10,%eax
  not    %ebp
  and    $0x7,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x7fd0(%ebx)
  add    $0x40,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  and    %eax,%ebp
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void DESIntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x44038000);
  ASSERT((ui32IntFlags & 0x00000001) || (ui32IntFlags & 0x00000002) || (ui32IntFlags & 0x00000004) || (ui32IntFlags & 0x00010000) || (ui32IntFlags & 0x00020000) || (ui32IntFlags & 0x00040000));
  (*((volatile uint32_t *)(ui32Base + 0xFFFF8030))) &= ~((ui32IntFlags & 0x00070000) >> 16);
  (*((volatile uint32_t *)(ui32Base + 0x00000040))) &= ~(ui32IntFlags & 0x0000ffff);
}
```
user: What is the c source code of the assembly code below:

```asm
<html_para>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <write_break@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <write_string@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: <P>

assistant: ```c
void html_para(void) {
  write_break();
  write_string("<P>");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<html_para>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <write_break@plt>
  lea    D0(%rip),%rdi
  call   <write_string@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: <P>

assistant: ```c
void html_para(void) {
  write_break();
  write_string("<P>");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<html_para>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <write_break@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <write_string@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: <P>

assistant: ```c
void html_para(void) {
  write_break();
  write_string("<P>");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<html_para>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <write_break@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <write_string@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: <P>

assistant: ```c
void html_para(void) {
  write_break();
  write_string("<P>");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_char_2D_AP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_char_2D_AP(char **char_2D_AP, int nrow) {
  int i;
  for (i = 0; i < nrow; i++) {
    free(char_2D_AP[i]);
  }
  free(char_2D_AP);
}
```
user: What is the c source code of the assembly code below?

```asm
<free_char_2D_AP>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L5
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L10:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L10
L5:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free_char_2D_AP(char **char_2D_AP, int nrow) {
  int i;
  for (i = 0; i < nrow; i++) {
    free(char_2D_AP[i]);
  }
  free(char_2D_AP);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<free_char_2D_AP>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L4
L15:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_char_2D_AP(char **char_2D_AP, int nrow) {
  int i;
  for (i = 0; i < nrow; i++) {
    free(char_2D_AP[i]);
  }
  free(char_2D_AP);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_char_2D_AP>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L7
L12:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_char_2D_AP(char **char_2D_AP, int nrow) {
  int i;
  for (i = 0; i < nrow; i++) {
    free(char_2D_AP[i]);
  }
  free(char_2D_AP);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emitln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: 


assistant: ```c
void emitln(const char *s) {
  emit(s);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<emitln>:
  endbr64
  sub    $0x8,%rsp
  call   <emit@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: 


assistant: ```c
void emitln(const char *s) {
  emit(s);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<emitln>:
  endbr64
  sub    $0x8,%rsp
  call   <emit@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: 


assistant: ```c
void emitln(const char *s) {
  emit(s);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<emitln>:
  endbr64
  sub    $0x8,%rsp
  call   <emit@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: 


assistant: ```c
void emitln(const char *s) {
  emit(s);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<plainstring_lessequal_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  movsd  %xmm0,-0x120(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x120(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <cstr_loaddouble@plt>
  lea    -0x110(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <plainstring_lessequal@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int plainstring_lessequal_double(const struct plainstring *this_string, double d) {
  char buffer[0xFF];
  cstr_loaddouble(buffer, d);
  return plainstring_lessequal(this_string, buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<plainstring_lessequal_double>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <cstr_loaddouble@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <plainstring_lessequal@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int plainstring_lessequal_double(const struct plainstring *this_string, double d) {
  char buffer[0xFF];
  cstr_loaddouble(buffer, d);
  return plainstring_lessequal(this_string, buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<plainstring_lessequal_double>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <cstr_loaddouble@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <plainstring_lessequal@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int plainstring_lessequal_double(const struct plainstring *this_string, double d) {
  char buffer[0xFF];
  cstr_loaddouble(buffer, d);
  return plainstring_lessequal(this_string, buffer);
}
```