ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<parsepvd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %edi,%ebp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    $0x8000,%esi
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  je     L33
  mov    $0x8000,%ebx
  mov    %rsp,%r13
  jmp    L45
L63:
  add    $0x800,%rbx
L45:
  mov    $0x800,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L33
  movzbl (%rsp),%eax
  cmp    $0x1,%al
  je     L17
  cmp    $0xff,%al
  jne    L63
  mov    $0xffffffff,%eax
  jmp    L33
L17:
  movzbl 0x54(%rsp),%eax
  shl    $0x8,%eax
  movzbl 0x55(%rsp),%edx
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl 0x56(%rsp),%edx
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl 0x57(%rsp),%edx
  add    %edx,%eax
  cltq
  shl    $0xb,%rax
  mov    %rax,(%r12)
  mov    %ebx,%eax
L33:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parsepvd(int isofd, unsigned char *mediasum, long long *isosize) {
  unsigned char buf[2048];
  long long offset;
  unsigned char *p __attribute__((unused));
  if (lseek(isofd, 16 * 2048, SEEK_SET) == -1)
    return ((long long)-1);
  offset = (16 * 2048);
  for (; 1;) {
    if (read(isofd, buf, 2048L) == -1)
      return ((long long)-1);
    if (buf[0] == 1)
      break;
    else if (buf[0] == 255)
      return ((long long)-1);
    offset += 2048L;
  }
  *isosize = (buf[84] * 0x1000000 + buf[84 + 1] * 0x10000 + buf[84 + 2] * 0x100 + buf[84 + 3]) * 2048LL;
  return offset;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parsepvd>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    $0x8000,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  je     L33
  mov    $0x8000,%ebx
  mov    %rsp,%r12
  jmp    L29
  nopl   0x0(%rax)
L11:
  movzbl (%rsp),%eax
  cmp    $0x1,%al
  je     L37
  cmp    $0xff,%al
  je     L33
  add    $0x800,%rbx
L29:
  mov    $0x800,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  jne    L11
L33:
  mov    $0xffffffff,%eax
L64:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L37:
  movzbl 0x54(%rsp),%eax
  movzbl 0x55(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x56(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x57(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  cltq
  shl    $0xb,%rax
  mov    %rax,0x0(%r13)
  mov    %ebx,%eax
  jmp    L64
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parsepvd(int isofd, unsigned char *mediasum, long long *isosize) {
  unsigned char buf[2048];
  long long offset;
  unsigned char *p __attribute__((unused));
  if (lseek(isofd, 16 * 2048, SEEK_SET) == -1)
    return ((long long)-1);
  offset = (16 * 2048);
  for (; 1;) {
    if (read(isofd, buf, 2048L) == -1)
      return ((long long)-1);
    if (buf[0] == 1)
      break;
    else if (buf[0] == 255)
      return ((long long)-1);
    offset += 2048L;
  }
  *isosize = (buf[84] * 0x1000000 + buf[84 + 1] * 0x10000 + buf[84 + 2] * 0x100 + buf[84 + 3]) * 2048LL;
  return offset;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parsepvd>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    $0x8000,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  je     L68
  mov    $0x8000,%ebx
  mov    %rsp,%r12
  jmp    L33
  nopl   0x0(%rax)
L51:
  movzbl (%rsp),%eax
  cmp    $0x1,%al
  je     L27
  cmp    $0xff,%al
  je     L68
  add    $0x800,%rbx
L33:
  mov    $0x800,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  jne    L51
L68:
  mov    $0xffffffff,%eax
L65:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L27:
  movzbl 0x54(%rsp),%eax
  movzbl 0x55(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x56(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x57(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  cltq
  shl    $0xb,%rax
  mov    %rax,0x0(%r13)
  mov    %ebx,%eax
  jmp    L65
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parsepvd(int isofd, unsigned char *mediasum, long long *isosize) {
  unsigned char buf[2048];
  long long offset;
  unsigned char *p __attribute__((unused));
  if (lseek(isofd, 16 * 2048, SEEK_SET) == -1)
    return ((long long)-1);
  offset = (16 * 2048);
  for (; 1;) {
    if (read(isofd, buf, 2048L) == -1)
      return ((long long)-1);
    if (buf[0] == 1)
      break;
    else if (buf[0] == 255)
      return ((long long)-1);
    offset += 2048L;
  }
  *isosize = (buf[84] * 0x1000000 + buf[84 + 1] * 0x10000 + buf[84 + 2] * 0x100 + buf[84 + 3]) * 2048LL;
  return offset;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<signal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x1,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <semop@plt>
  cmp    $0xffffffff,%eax
  jne    L0
  mov    $0xffffffff,%eax
  jmp    L7
L0:
  mov    $0x0,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int signal(int semid) {
  struct sembuf operacion;
  operacion.sem_num = 0;
  operacion.sem_op = 1;
  operacion.sem_flg = 0;
  if (semop(semid, &operacion, 1) == -1) {
    return (-1);
  } else {
    return (0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<signal>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movl   $0x1,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x1,%edx
  call   <semop@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int signal(int semid) {
  struct sembuf operacion;
  operacion.sem_num = 0;
  operacion.sem_op = 1;
  operacion.sem_flg = 0;
  if (semop(semid, &operacion, 1) == -1) {
    return (-1);
  } else {
    return (0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<signal>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x1,(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <semop@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int signal(int semid) {
  struct sembuf operacion;
  operacion.sem_num = 0;
  operacion.sem_op = 1;
  operacion.sem_flg = 0;
  if (semop(semid, &operacion, 1) == -1) {
    return (-1);
  } else {
    return (0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<signal>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x1,(%rsp)
  movups %xmm0,0x8(%rsp)
  call   <semop@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int signal(int semid) {
  struct sembuf operacion;
  operacion.sem_num = 0;
  operacion.sem_op = 1;
  operacion.sem_flg = 0;
  if (semop(semid, &operacion, 1) == -1) {
    return (-1);
  } else {
    return (0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hex2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L13:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L41
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L13
L41:
  subl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L63
L83:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L60
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x20(%rax),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L60:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x2f,-0x11(%rbp)
  jle    L3
  cmpb   $0x39,-0x11(%rbp)
  jg     L3
  movsbl -0x11(%rbp),%eax
  sub    $0x30,%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L3:
  cmpb   $0x40,-0x11(%rbp)
  jle    L14
  cmpb   $0x46,-0x11(%rbp)
  jg     L14
  movsbl -0x11(%rbp),%eax
  sub    $0x37,%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L14:
  shll   $0x4,-0x4(%rbp)
  subl   $0x1,-0xc(%rbp)
L63:
  cmpl   $0x0,-0xc(%rbp)
  jns    L83
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hex2int(char *crcstr) {
  int s = 0, i, v = 0, m = 1;
  char d;
  do {
    s++;
  } while ((crcstr[s] != 0) && (crcstr[s] != ' '));
  s--;
  for (i = s; i >= 0; i--) {
    if (crcstr[i] >= 'a')
      crcstr[i] -= 32;
    d = crcstr[i];
    if ((d >= '0') && (d <= '9'))
      v += m * (int)(d - '0');
    if ((d >= 'A') && (d <= 'F'))
      v += m * (10 + (int)(d - 'A'));
    m = m * 16;
  };
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex2int>:
  endbr64
  mov    $0x0,%eax
L17:
  mov    %eax,%ecx
  movzbl 0x1(%rdi,%rax,1),%edx
  mov    %rax,%rsi
  add    $0x1,%rax
  test   $0xdf,%dl
  jne    L17
  test   %ecx,%ecx
  js     L21
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,1),%rdx
  lea    -0x1(%rdi,%rcx,1),%r8
  mov    %esi,%esi
  sub    %rsi,%r8
  mov    $0x1,%ecx
  mov    $0x0,%esi
  jmp    L10
L6:
  lea    -0x41(%rax),%edi
  cmp    $0x5,%dil
  ja     L29
  movsbl %al,%eax
  sub    $0x37,%eax
  imul   %ecx,%eax
  add    %eax,%esi
L29:
  shl    $0x4,%ecx
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  je     L8
L10:
  mov    %rdx,%rdi
  movzbl (%rdx),%eax
  cmp    $0x60,%al
  jle    L64
  sub    $0x20,%eax
  mov    %al,(%rdx)
L64:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edi
  cmp    $0x9,%dil
  ja     L6
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   %ecx,%eax
  add    %eax,%esi
  jmp    L29
L21:
  mov    $0x0,%esi
L8:
  mov    %esi,%eax
  ret
```

assistant: ```c
int hex2int(char *crcstr) {
  int s = 0, i, v = 0, m = 1;
  char d;
  do {
    s++;
  } while ((crcstr[s] != 0) && (crcstr[s] != ' '));
  s--;
  for (i = s; i >= 0; i--) {
    if (crcstr[i] >= 'a')
      crcstr[i] -= 32;
    d = crcstr[i];
    if ((d >= '0') && (d <= '9'))
      v += m * (int)(d - '0');
    if ((d >= 'A') && (d <= 'F'))
      v += m * (10 + (int)(d - 'A'));
    m = m * 16;
  };
  return v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hex2int>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  movzbl 0x1(%rdi,%rax,1),%edx
  movslq %eax,%rcx
  mov    %rax,%rsi
  add    $0x1,%rax
  and    $0xdf,%edx
  jne    L2
  lea    -0x1(%rdi,%rcx,1),%r9
  lea    (%rdi,%rcx,1),%rdx
  xor    %r8d,%r8d
  mov    $0x1,%edi
  sub    %rsi,%r9
  jmp    L19
  nopl   (%rax)
L62:
  lea    -0x20(%rax),%ecx
  mov    %cl,(%rdx)
  mov    %ecx,%eax
L46:
  sub    $0x41,%ecx
  cmp    $0x5,%cl
  ja     L57
  sub    $0x37,%eax
  movsbl %al,%eax
  imul   %edi,%eax
  add    %eax,%r8d
L57:
  sub    $0x1,%rdx
  shl    $0x4,%edi
  cmp    %rdx,%r9
  je     L14
L19:
  movzbl (%rdx),%eax
  mov    %eax,%ecx
  cmp    $0x60,%al
  jg     L62
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L46
  movsbl %sil,%esi
  sub    $0x1,%rdx
  imul   %edi,%esi
  shl    $0x4,%edi
  add    %esi,%r8d
  cmp    %rdx,%r9
  jne    L19
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hex2int(char *crcstr) {
  int s = 0, i, v = 0, m = 1;
  char d;
  do {
    s++;
  } while ((crcstr[s] != 0) && (crcstr[s] != ' '));
  s--;
  for (i = s; i >= 0; i--) {
    if (crcstr[i] >= 'a')
      crcstr[i] -= 32;
    d = crcstr[i];
    if ((d >= '0') && (d <= '9'))
      v += m * (int)(d - '0');
    if ((d >= 'A') && (d <= 'F'))
      v += m * (10 + (int)(d - 'A'));
    m = m * 16;
  };
  return v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hex2int>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L17:
  movzbl 0x1(%rdi,%rax,1),%edx
  movslq %eax,%rcx
  mov    %rax,%rsi
  add    $0x1,%rax
  and    $0xdf,%edx
  jne    L17
  lea    -0x1(%rdi,%rcx,1),%r9
  lea    (%rdi,%rcx,1),%rdx
  xor    %r8d,%r8d
  mov    $0x1,%edi
  sub    %rsi,%r9
  jmp    L1
  nopl   (%rax)
L6:
  lea    -0x20(%rax),%ecx
  mov    %cl,(%rdx)
  mov    %ecx,%eax
L28:
  sub    $0x41,%ecx
  cmp    $0x5,%cl
  ja     L37
  sub    $0x37,%eax
  movsbl %al,%eax
  imul   %edi,%eax
  add    %eax,%r8d
L37:
  sub    $0x1,%rdx
  shl    $0x4,%edi
  cmp    %rdx,%r9
  je     L15
L1:
  movzbl (%rdx),%eax
  mov    %eax,%ecx
  cmp    $0x60,%al
  jg     L6
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L28
  movsbl %sil,%esi
  sub    $0x1,%rdx
  imul   %edi,%esi
  shl    $0x4,%edi
  add    %esi,%r8d
  cmp    %rdx,%r9
  jne    L1
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hex2int(char *crcstr) {
  int s = 0, i, v = 0, m = 1;
  char d;
  do {
    s++;
  } while ((crcstr[s] != 0) && (crcstr[s] != ' '));
  s--;
  for (i = s; i >= 0; i--) {
    if (crcstr[i] >= 'a')
      crcstr[i] -= 32;
    d = crcstr[i];
    if ((d >= '0') && (d <= '9'))
      v += m * (int)(d - '0');
    if ((d >= 'A') && (d <= 'F'))
      v += m * (10 + (int)(d - 'A'));
    m = m * 16;
  };
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rbx
  mov    -0x28(%rbp),%r12
  jmp    L4
L23:
  movzbl (%rbx),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  jne    L39
  mov    %rbx,%rax
  jmp    L32
L39:
  add    $0x1,%rbx
  sub    $0x1,%r12
L4:
  test   %r12,%r12
  jne    L23
  mov    $0x0,%eax
L32:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void *memchr(const void *s, int ucharwanted, size_t size) {
  register const char *scan;
  register size_t n;
  scan = (const char *)s;
  for (n = size; n > 0; n--)
    if (*scan == (char)ucharwanted)
      return ((void *)scan);
    else
      scan++;
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<memchr>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L23
  add    %rdi,%rdx
L7:
  cmp    %sil,(%rax)
  je     L24
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L7
  mov    $0x0,%eax
  ret
L23:
  mov    $0x0,%eax
L24:
  ret
```

assistant: ```c
void *memchr(const void *s, int ucharwanted, size_t size) {
  register const char *scan;
  register size_t n;
  scan = (const char *)s;
  for (n = size; n > 0; n--)
    if (*scan == (char)ucharwanted)
      return ((void *)scan);
    else
      scan++;
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memchr>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L29
  add    %rdi,%rdx
  jmp    L10
  nopl   0x0(%rax)
L39:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L29
L10:
  cmp    %sil,(%rax)
  jne    L39
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr(const void *s, int ucharwanted, size_t size) {
  register const char *scan;
  register size_t n;
  scan = (const char *)s;
  for (n = size; n > 0; n--)
    if (*scan == (char)ucharwanted)
      return ((void *)scan);
    else
      scan++;
  return (NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memchr>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L25
  add    %rdi,%rdx
  jmp    L19
  nopl   0x0(%rax)
L16:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L25
L19:
  cmp    %sil,(%rax)
  jne    L16
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr(const void *s, int ucharwanted, size_t size) {
  register const char *scan;
  register size_t n;
  scan = (const char *)s;
  for (n = size; n > 0; n--)
    if (*scan == (char)ucharwanted)
      return ((void *)scan);
    else
      scan++;
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stror80>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L0
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x60,%eax
  test   %eax,%eax
  je     L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L18:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stror80(char *t) {
  while (*t) {
    if ((*t & 0x7f) >= 0x20) {
      *t |= 0x80;
    }
    t++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stror80>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L32
L16:
  ret
L37:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
L32:
  test   $0x60,%al
  je     L37
  or     $0xffffff80,%eax
  mov    %al,(%rdi)
  jmp    L37
```

assistant: ```c
void stror80(char *t) {
  while (*t) {
    if ((*t & 0x7f) >= 0x20) {
      *t |= 0x80;
    }
    t++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stror80>:
  endbr64
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L10:
  test   $0x60,%al
  je     L19
  or     $0xffffff80,%eax
  mov    %al,(%rdi)
L19:
  add    $0x1,%rdi
L21:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
  ret
```

assistant: ```c
void stror80(char *t) {
  while (*t) {
    if ((*t & 0x7f) >= 0x20) {
      *t |= 0x80;
    }
    t++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stror80>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  nopl   0x0(%rax,%rax,1)
L8:
  test   $0x60,%al
  je     L18
  or     $0xffffff80,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L8
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L8
L10:
  ret
```

assistant: ```c
void stror80(char *t) {
  while (*t) {
    if ((*t & 0x7f) >= 0x20) {
      *t |= 0x80;
    }
    t++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x6769726f,-0x12(%rbp)
  movb   $0x0,-0xe(%rbp)
  movl   $0x64636261,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x12(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0xd(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D10
type_infered: string
name: read_data
arguments: tag: D34
type_infered: string
name: read_data
arguments: tag: D43
type_infered: string
name: read_data
arguments: tag: D40
type_infered: string
name: read_data
arguments: tag: D23
type_infered: string

tool: D10: replaceoriginal

tool: D34: address of string literal %p


tool: D43: original: 
(%s)


tool: D40: offset: (%s)


tool: D23: final string: 
(%s)


assistant: ```c
int main() {
  char *original_literal = "replaceoriginal";
  printf("address of string literal %p\n", original_literal);
  char *original = (char *)malloc(sizeof(char) * 50);
  strncpy(original, original_literal, (strlen(original_literal) + 1) * sizeof(char *));
  printf("original: \n(%s)\n", original);
  char substr[] = "orig";
  char newstr[] = "abcd";
  char *offset = strstr(original, substr);
  printf("offset: (%s)\n", offset);
  int size = strlen(newstr) * sizeof(char);
  strncpy(offset, newstr, size);
  printf("final string: \n(%s)\n", original);
  return 0;
}
```