ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FATORACAO>:
  endbr64
  cmp    $0x1,%rdi
  je     L6
  mov    $0x2,%ecx
  mov    $0x1,%r8d
  nopl   (%rax)
L39:
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L1
  mov    %rax,%rdi
  mov    %rcx,%r8
  cmp    $0x1,%rax
  jne    L39
  mov    %r8,%rax
  ret
  nopl   (%rax)
L1:
  add    $0x1,%rcx
  cmp    $0x1,%rdi
  jne    L39
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long int FATORACAO(long int n) {
  long int numero = n;
  long int divisor = 1;
  long int resto;
  long int i = 2;
  while (numero != 1) {
    resto = numero % i;
    if (resto == 0) {
      divisor = i;
      numero /= i;
    } else
      i++;
  }
  return divisor;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sun_geometric_mean_longitude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movsd  D49(%rip),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D7(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  D47(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    D19(%rip),%rdx
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <fmod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <radians@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type: f64
name: read_data
arguments: tag: D49
type: f64
name: read_data
arguments: tag: D7
type: f64
name: read_data
arguments: tag: D47
type: f64
name: read_data
arguments: tag: D19
type: f64

tool: D18: 0.0003032

tool: D49: 2

tool: D7: 36000.76983

tool: D47: 280.46646

tool: D19: 360

assistant: ```c
double sun_geometric_mean_longitude(double tm) {
  double rc = fmod(pow(0.0003032 * tm, 2.0) + 36000.76983 * tm + 280.46646, 360.0);
  return radians(rc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sun_geometric_mean_longitude>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  mulsd  D23(%rip),%xmm0
  movsd  D7(%rip),%xmm1
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %rbx,%xmm0
  mulsd  D20(%rip),%xmm0
  addsd  %xmm1,%xmm0
  addsd  D48(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  movsd  D18(%rip),%xmm0
  call   <fmod@plt>
  call   <radians@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D23
type_infered: f64
name: read_data
arguments: data_tag: D7
type_infered: f64
name: read_data
arguments: data_tag: D20
type_infered: f64
name: read_data
arguments: data_tag: D48
type_infered: f64
name: read_data
arguments: data_tag: D18
type_infered: f64

tool: D23: 0.0003032

tool: D7: 2

tool: D20: 36000.76983

tool: D48: 280.46646

tool: D18: 360

assistant: ```c
double sun_geometric_mean_longitude(double tm) {
  double rc = fmod(pow(0.0003032 * tm, 2.0) + 36000.76983 * tm + 280.46646, 360.0);
  return radians(rc);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sun_geometric_mean_longitude>:
  endbr64
  sub    $0x18,%rsp
  movsd  D3(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  mulsd  D36(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  mulsd  D46(%rip),%xmm2
  cvtsi2sd %rax,%xmm0
  addsd  %xmm2,%xmm0
  addsd  D27(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  movsd  D45(%rip),%xmm0
  call   <fmod@plt>
  add    $0x18,%rsp
  jmp    1090 <radians@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: f64
name: parse_data
arguments: data_tag: D36
type_infered: f64
name: parse_data
arguments: data_tag: D46
type_infered: f64
name: parse_data
arguments: data_tag: D27
type_infered: f64
name: parse_data
arguments: data_tag: D45
type_infered: f64

tool: D3: 2

tool: D36: 0.0003032

tool: D46: 36000.76983

tool: D27: 280.46646

tool: D45: 360

assistant: ```c
double sun_geometric_mean_longitude(double tm) {
  double rc = fmod(pow(0.0003032 * tm, 2.0) + 36000.76983 * tm + 280.46646, 360.0);
  return radians(rc);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sun_geometric_mean_longitude>:
  endbr64
  sub    $0x18,%rsp
  movsd  D48(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  mulsd  D19(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  mulsd  D0(%rip),%xmm2
  cvtsi2sd %rax,%xmm0
  addsd  %xmm2,%xmm0
  addsd  D9(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  movsd  D39(%rip),%xmm0
  call   <fmod@plt>
  add    $0x18,%rsp
  jmp    1090 <radians@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D48
type_guessed: f64
name: retrieve_data
arguments: data_tag: D19
type_guessed: f64
name: retrieve_data
arguments: data_tag: D0
type_guessed: f64
name: retrieve_data
arguments: data_tag: D9
type_guessed: f64
name: retrieve_data
arguments: data_tag: D39
type_guessed: f64

tool: D48: 2

tool: D19: 0.0003032

tool: D0: 36000.76983

tool: D9: 280.46646

tool: D39: 360

assistant: ```c
double sun_geometric_mean_longitude(double tm) {
  double rc = fmod(pow(0.0003032 * tm, 2.0) + 36000.76983 * tm + 280.46646, 360.0);
  return radians(rc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L44:
  cmp    %rdx,%rsp
  je     L57
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L44
L57:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L41
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L41:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L27
L13:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L27:
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L13
  mov    -0x50(%rbp),%eax
  mov    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <Noble@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D25
type_guessed: string
name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string

tool: D25: Enter the size of array : 

tool: D37: %d

tool: D29: Noble Integer = %d

assistant: ```c
int main() {
  int n;
  printf("Enter the size of array : ");
  scanf("%d", &n);
  int A[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &A[i]);
  }
  printf("Noble Integer = %d", Noble(n, A));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edi
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L14:
  cmp    %rdx,%rsp
  je     L29
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L14
L29:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L39
  orq    $0x0,-0x8(%rsp,%rax,1)
L39:
  mov    %rsp,%r14
  test   %edi,%edi
  jle    L58
  mov    %r14,%r12
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L52:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%edi
  add    $0x4,%r12
  cmp    %ebx,%edi
  jg     L52
L58:
  mov    %r14,%rsi
  call   <Noble@plt>
  mov    %eax,%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D38
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D31
type_guessed: string

tool: D38: Enter the size of array : 

tool: D0: %d

tool: D31: Noble Integer = %d

assistant: ```c
int main() {
  int n;
  printf("Enter the size of array : ");
  scanf("%d", &n);
  int A[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &A[i]);
  }
  printf("Noble Integer = %d", Noble(n, A));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  lea    -0x2c(%rbp),%rsi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L3
L14:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L14
L3:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L36
L13:
  mov    %rsp,%r14
  test   %edi,%edi
  jle    L24
  mov    %r14,%r12
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edi
  cmp    %ebx,%edi
  jg     L28
L24:
  mov    %r14,%rsi
  call   <Noble@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L36:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L13
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D24
type: string
name: parse_data
arguments: data_label: D17
type: string

tool: D19: Enter the size of array : 

tool: D24: %d

tool: D17: Noble Integer = %d

assistant: ```c
int main() {
  int n;
  printf("Enter the size of array : ");
  scanf("%d", &n);
  int A[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &A[i]);
  }
  printf("Noble Integer = %d", Noble(n, A));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  lea    -0x2c(%rbp),%rsi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L23
L64:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L64
L23:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L20
L47:
  mov    %rsp,%r14
  test   %edi,%edi
  jle    L39
  mov    %r14,%r12
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edi
  cmp    %ebx,%edi
  jg     L55
L39:
  mov    %r14,%rsi
  call   <Noble@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L20:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L47
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D28
datatype: string
name: unpack_data
arguments: label: D27
datatype: string
name: unpack_data
arguments: label: D17
datatype: string

tool: D28: Enter the size of array : 

tool: D27: %d

tool: D17: Noble Integer = %d

assistant: ```c
int main() {
  int n;
  printf("Enter the size of array : ");
  scanf("%d", &n);
  int A[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &A[i]);
  }
  printf("Noble Integer = %d", Noble(n, A));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ssprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ssvprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void ssprintf(struct simple_string *s, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  ssvprintf(s, format, ap);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ssprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <ssvprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ssprintf(struct simple_string *s, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  ssvprintf(s, format, ap);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ssprintf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ssvprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ssprintf(struct simple_string *s, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  ssvprintf(s, format, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ssprintf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ssvprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ssprintf(struct simple_string *s, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  ssvprintf(s, format, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<series6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L6
L13:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L4
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  movsd  D43(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L58
L4:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0xc(%rbp),%xmm2
  movsd  D43(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L58:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L15
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L26
L15:
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L26:
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L13
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D42
data_type: string
name: read_data
arguments: tag: D43
data_type: f64
name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D60
data_type: string
name: read_data
arguments: tag: D28
data_type: string

tool: D42: (1/%d)

tool: D43: 1

tool: D10: (-1/%d)

tool: D22: +

tool: D60: .


tool: D28: Sum Of The Above series is %f


assistant: ```c
void series6(int n) {
  double sum = 0.0;
  int i;
  for (i = 1; i <= n; i++) {
    if (i % 2 != 0) {
      printf("(1/%d)", i);
      sum += 1.0 / i;
    } else {
      printf("(-1/%d)", i);
      sum -= 1.0 / i;
    }
    i != n ? printf("+") : printf(".\n");
  }
  printf("Sum Of The Above series is %f\n", sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<series6>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L66
  mov    %edi,%ebp
  mov    $0x1,%ebx
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  lea    D25(%rip),%r13
  lea    D21(%rip),%r12
  jmp    L55
L14:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  movsd  D13(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  0x8(%rsp),%xmm2
  subsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rsp)
L68:
  cmp    %ebx,%ebp
  je     L37
  mov    $0x2b,%edi
  call   <putchar@plt>
L69:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L2
L55:
  test   $0x1,%bl
  je     L14
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  movsd  D13(%rip),%xmm0
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  jmp    L68
L37:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L69
L66:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L2:
  movsd  0x8(%rsp),%xmm0
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type: string
name: unpack_data
arguments: data_tag: D21
type: string
name: unpack_data
arguments: data_tag: D13
type: f64
name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D16
type: string

tool: D25: (-1/%d)

tool: D21: (1/%d)

tool: D13: 1

tool: D12: .

tool: D16: Sum Of The Above series is %f


assistant: ```c
void series6(int n) {
  double sum = 0.0;
  int i;
  for (i = 1; i <= n; i++) {
    if (i % 2 != 0) {
      printf("(1/%d)", i);
      sum += 1.0 / i;
    } else {
      printf("(-1/%d)", i);
      sum -= 1.0 / i;
    }
    i != n ? printf("+") : printf(".\n");
  }
  printf("Sum Of The Above series is %f\n", sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<series6>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edi,%edi
  jle    L66
  pxor   %xmm4,%xmm4
  mov    %edi,%ebp
  mov    $0x1,%ebx
  movsd  %xmm4,0x8(%rsp)
  lea    D54(%rip),%r13
  lea    D6(%rip),%r12
  lea    D43(%rip),%r14
  jmp    L2
L79:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movsd  D30(%rip),%xmm0
  cvtsi2sd %ebx,%xmm1
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebx,%ebp
  je     L3
L73:
  mov    $0x2b,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jl     L6
L2:
  mov    %ebx,%esi
  test   $0x1,%bl
  jne    L79
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movsd  D30(%rip),%xmm0
  movsd  0x8(%rsp),%xmm2
  cvtsi2sd %ebx,%xmm1
  divsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rsp)
  cmp    %ebx,%ebp
  jne    L73
L3:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    %ebx,%ebp
  jge    L2
L6:
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  mov    $0x1,%eax
  lea    D26(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L66:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_label: D54
type: string
name: parse_data
arguments: data_label: D6
type: string
name: parse_data
arguments: data_label: D43
type: string
name: parse_data
arguments: data_label: D30
type: f64
name: parse_data
arguments: data_label: D26
type: string

tool: D54: (-1/%d)

tool: D6: (1/%d)

tool: D43: .

tool: D30: 1

tool: D26: Sum Of The Above series is %f


assistant: ```c
void series6(int n) {
  double sum = 0.0;
  int i;
  for (i = 1; i <= n; i++) {
    if (i % 2 != 0) {
      printf("(1/%d)", i);
      sum += 1.0 / i;
    } else {
      printf("(-1/%d)", i);
      sum -= 1.0 / i;
    }
    i != n ? printf("+") : printf(".\n");
  }
  printf("Sum Of The Above series is %f\n", sum);
}
```