ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_206_1_1>:
  endbr64
  mov    %edx,%eax
  not    %edx
  and    (%rdi),%dl
  or     %esi,%eax
  or     %esi,%edx
  mov    %eax,%ecx
  and    (%rdi),%al
  not    %ecx
  and    %ecx,%edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_206_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = *D & stk3;
  stk1 = S | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dal_reg_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  ja     L1
  cmpl   $0x1fffff,-0x8(%rbp)
  jbe    L2
L1:
  mov    $0xffffffff,%eax
  jmp    L25
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nss_macsec_reg_read@plt>
  mov    $0x0,%eax
L25:
  leave
  ret
```

assistant: ```c
int dal_reg_read(unsigned int dev_id, unsigned int reg_addr, unsigned int *pvalue) {
  if ((dev_id >= 3) || (reg_addr >= 0x200000)) {
    return -1;
  }
  nss_macsec_reg_read(dev_id, reg_addr, pvalue);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dal_reg_read>:
  endbr64
  cmp    $0x2,%edi
  ja     L3
  cmp    $0x1fffff,%esi
  ja     L3
  sub    $0x8,%rsp
  call   <nss_macsec_reg_read@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dal_reg_read(unsigned int dev_id, unsigned int reg_addr, unsigned int *pvalue) {
  if ((dev_id >= 3) || (reg_addr >= 0x200000)) {
    return -1;
  }
  nss_macsec_reg_read(dev_id, reg_addr, pvalue);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dal_reg_read>:
  endbr64
  cmp    $0x2,%edi
  ja     L4
  cmp    $0x1fffff,%esi
  ja     L4
  sub    $0x8,%rsp
  call   <nss_macsec_reg_read@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dal_reg_read(unsigned int dev_id, unsigned int reg_addr, unsigned int *pvalue) {
  if ((dev_id >= 3) || (reg_addr >= 0x200000)) {
    return -1;
  }
  nss_macsec_reg_read(dev_id, reg_addr, pvalue);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dal_reg_read>:
  endbr64
  cmp    $0x2,%edi
  ja     L0
  cmp    $0x1fffff,%esi
  ja     L0
  sub    $0x8,%rsp
  call   <nss_macsec_reg_read@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dal_reg_read(unsigned int dev_id, unsigned int reg_addr, unsigned int *pvalue) {
  if ((dev_id >= 3) || (reg_addr >= 0x200000)) {
    return -1;
  }
  nss_macsec_reg_read(dev_id, reg_addr, pvalue);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverse(char *str) {
  int len = strlen(str);
  int i = 0;
  char temp;
  for (i = 0; i < len / 2; i++) {
    temp = str[i];
    str[i] = str[len - i - 1];
    str[len - i - 1] = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L6
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  mov    $0x0,%eax
L5:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%rdx),%esi
  mov    %sil,(%rbx,%rax,1)
  mov    %cl,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%edi
  jg     L5
L6:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *str) {
  int len = strlen(str);
  int i = 0;
  char temp;
  for (i = 0; i < len / 2; i++) {
    temp = str[i];
    str[i] = str[len - i - 1];
    str[len - i - 1] = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L11
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L18:
  movzbl (%rdx),%esi
  movzbl (%rbx,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rbx,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%edi
  jg     L18
L11:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *str) {
  int len = strlen(str);
  int i = 0;
  char temp;
  for (i = 0; i < len / 2; i++) {
    temp = str[i];
    str[i] = str[len - i - 1];
    str[len - i - 1] = temp;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L6
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L11:
  movzbl (%rdx),%esi
  movzbl (%rbx,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rbx,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%edi
  jg     L11
L6:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *str) {
  int len = strlen(str);
  int i = 0;
  char temp;
  for (i = 0; i < len / 2; i++) {
    temp = str[i];
    str[i] = str[len - i - 1];
    str[len - i - 1] = temp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ihex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %edi,-0x3c(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movq   D15(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L20
L27:
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movsd  -0x28(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x48(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x2c(%rbp)
L20:
  mov    -0x2c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L27
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: qword
name: disassemble_data
arguments: data_label: D12
datatype: f64

tool: D15: 9223372036854775807

tool: D12: 16

assistant: ```c
void ihex(double x, int nhx, char chx[]) {
  int i;
  double y;
  char hx[] = "0123456789ABCDEF";
  y = fabs(x);
  for (i = 0; i < nhx; i++) {
    y = 16. * (y - floor(y));
    chx[i] = hx[(int)y];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ihex>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movb   $0x0,0x10(%rsp)
  andpd  D2(%rip),%xmm0
  test   %edi,%edi
  jle    L30
  mov    %rsi,%rax
  lea    -0x1(%rdi),%edx
  lea    0x1(%rsi,%rdx,1),%rcx
  movsd  D0(%rip),%xmm5
  movsd  D2(%rip),%xmm3
  movsd  D22(%rip),%xmm6
  movsd  D45(%rip),%xmm4
  jmp    L8
L23:
  subsd  %xmm2,%xmm0
  mulsd  %xmm4,%xmm0
  cvttsd2si %xmm0,%edx
  movslq %edx,%rdx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L30
L8:
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  andpd  %xmm3,%xmm1
  ucomisd %xmm1,%xmm5
  jbe    L23
  cvttsd2si %xmm0,%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdx,%xmm1
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  andpd  %xmm6,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm3,%xmm2
  andnpd %xmm0,%xmm2
  orpd   %xmm1,%xmm2
  jmp    L23
L30:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x28,%rsp
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: qword[2]
name: parse_data
arguments: data_tag: D0
datatype: byte[8]
name: parse_data
arguments: data_tag: D22
datatype: byte[8]
name: parse_data
arguments: data_tag: D45
datatype: f64

tool: {"D2": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D45: 16

assistant: ```c
void ihex(double x, int nhx, char chx[]) {
  int i;
  double y;
  char hx[] = "0123456789ABCDEF";
  y = fabs(x);
  for (i = 0; i < nhx; i++) {
    y = 16. * (y - floor(y));
    chx[i] = hx[(int)y];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ihex>:
  endbr64
  sub    $0x28,%rsp
  movdqa D29(%rip),%xmm1
  movq   D41(%rip),%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm1,(%rsp)
  andpd  %xmm3,%xmm0
  test   %edi,%edi
  jle    L26
  lea    -0x1(%rdi),%eax
  movsd  D34(%rip),%xmm5
  movsd  D26(%rip),%xmm4
  movsd  D30(%rip),%xmm6
  lea    0x1(%rsi,%rax,1),%rdx
  nopl   (%rax)
L8:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  andpd  %xmm3,%xmm1
  ucomisd %xmm1,%xmm5
  jbe    L7
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  andpd  %xmm6,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm3,%xmm2
  andnpd %xmm0,%xmm2
  orpd   %xmm1,%xmm2
L7:
  subsd  %xmm2,%xmm0
  add    $0x1,%rsi
  mulsd  %xmm4,%xmm0
  cvttsd2si %xmm0,%eax
  cltq
  movzbl (%rsp,%rax,1),%eax
  mov    %al,-0x1(%rsi)
  cmp    %rsi,%rdx
  jne    L8
L26:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_guessed: byte[16]
name: extract_symbolic_data
arguments: tag: D41
type_guessed: qword
name: extract_symbolic_data
arguments: tag: D34
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D26
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D30
type_guessed: byte[8]

tool: {"D29": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: D41: 9223372036854775807

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: D26: 16

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void ihex(double x, int nhx, char chx[]) {
  int i;
  double y;
  char hx[] = "0123456789ABCDEF";
  y = fabs(x);
  for (i = 0; i < nhx; i++) {
    y = 16. * (y - floor(y));
    chx[i] = hx[(int)y];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ihex>:
  endbr64
  sub    $0x28,%rsp
  movdqa D47(%rip),%xmm1
  movq   D0(%rip),%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm1,(%rsp)
  andpd  %xmm3,%xmm0
  test   %edi,%edi
  jle    L2
  lea    -0x1(%rdi),%eax
  movsd  D19(%rip),%xmm5
  movsd  D34(%rip),%xmm4
  movsd  D31(%rip),%xmm6
  lea    0x1(%rsi,%rax,1),%rdx
  nopl   (%rax)
L11:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  andpd  %xmm3,%xmm1
  ucomisd %xmm1,%xmm5
  jbe    L9
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  andpd  %xmm6,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm3,%xmm2
  andnpd %xmm0,%xmm2
  orpd   %xmm1,%xmm2
L9:
  subsd  %xmm2,%xmm0
  add    $0x1,%rsi
  mulsd  %xmm4,%xmm0
  cvttsd2si %xmm0,%eax
  cltq
  movzbl (%rsp,%rax,1),%eax
  mov    %al,-0x1(%rsi)
  cmp    %rsi,%rdx
  jne    L11
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D47
data_type: byte[16]
name: read_data
arguments: tag: D0
data_type: qword
name: read_data
arguments: tag: D19
data_type: byte[8]
name: read_data
arguments: tag: D34
data_type: f64
name: read_data
arguments: tag: D31
data_type: byte[8]

tool: {"D47": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: D0: 9223372036854775807

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: D34: 16

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void ihex(double x, int nhx, char chx[]) {
  int i;
  double y;
  char hx[] = "0123456789ABCDEF";
  y = fabs(x);
  for (i = 0; i < nhx; i++) {
    y = 16. * (y - floor(y));
    chx[i] = hx[(int)y];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<json_emits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L6
L4:
  movsbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <json_emitc@plt>
L6:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void json_emits(struct json_writer *writer, const char *s) {
  char c;
  while ((c = *s++) != '\0')
    json_emitc(writer, c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<json_emits>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L13
L6:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <json_emitc@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L6
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void json_emits(struct json_writer *writer, const char *s) {
  char c;
  while ((c = *s++) != '\0')
    json_emitc(writer, c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<json_emits>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L13
  mov    %rdi,%rbp
  nopl   0x0(%rax)
L7:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <json_emitc@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L7
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void json_emits(struct json_writer *writer, const char *s) {
  char c;
  while ((c = *s++) != '\0')
    json_emitc(writer, c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<json_emits>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L15
  mov    %rdi,%rbp
  nopl   0x0(%rax)
L19:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <json_emitc@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L19
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void json_emits(struct json_writer *writer, const char *s) {
  char c;
  while ((c = *s++) != '\0')
    json_emitc(writer, c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x17447d68,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  add    $0x1ee34d44,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> 2UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 2UL) & 15UL) | 1UL)));
        state[0UL] |= ((state[0UL] + state[local1]) & 15UL) << 2UL;
      }
      if (state[0UL] > local1) {
        state[local1] |= ((state[local1] >> (((state[local1] >> 4UL) & 7UL) | 1UL)) & 15UL) << 2UL;
        state[local1] >>= ((state[local1] >> 4UL) & 7UL) | 1UL;
      } else {
        state[local1] = state[0UL] | state[local1];
        state[local1] |= (((state[local1] >> ((state[0UL] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[0UL] & 15UL) | 1UL)))) & 15UL) << 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 518212932UL) << 1UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  lea    0xf3d9fb8(%rax,%rax,1),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> 2UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 2UL) & 15UL) | 1UL)));
        state[0UL] |= ((state[0UL] + state[local1]) & 15UL) << 2UL;
      }
      if (state[0UL] > local1) {
        state[local1] |= ((state[local1] >> (((state[local1] >> 4UL) & 7UL) | 1UL)) & 15UL) << 2UL;
        state[local1] >>= ((state[local1] >> 4UL) & 7UL) | 1UL;
      } else {
        state[local1] = state[0UL] | state[local1];
        state[local1] |= (((state[local1] >> ((state[0UL] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[0UL] & 15UL) | 1UL)))) & 15UL) << 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 518212932UL) << 1UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  lea    0xf3d9fb8(%rax,%rax,1),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> 2UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 2UL) & 15UL) | 1UL)));
        state[0UL] |= ((state[0UL] + state[local1]) & 15UL) << 2UL;
      }
      if (state[0UL] > local1) {
        state[local1] |= ((state[local1] >> (((state[local1] >> 4UL) & 7UL) | 1UL)) & 15UL) << 2UL;
        state[local1] >>= ((state[local1] >> 4UL) & 7UL) | 1UL;
      } else {
        state[local1] = state[0UL] | state[local1];
        state[local1] |= (((state[local1] >> ((state[0UL] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[0UL] & 15UL) | 1UL)))) & 15UL) << 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 518212932UL) << 1UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<b_defstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L2
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: byte 1 %d


assistant: ```c
void b_defstring(int len, char *str) {
  char *s;
  for (s = str; s < str + len; s++)
    print("byte 1 %d\n", (*s) & 0377);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<b_defstring>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rdi
  lea    (%rsi,%rdi,1),%rbp
  cmp    %rbp,%rsi
  jae    L14
  mov    %rsi,%rbx
  lea    D0(%rip),%r12
L2:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <print@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L2
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: byte 1 %d


assistant: ```c
void b_defstring(int len, char *str) {
  char *s;
  for (s = str; s < str + len; s++)
    print("byte 1 %d\n", (*s) & 0377);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<b_defstring>:
  endbr64
  movslq %edi,%rdi
  push   %r12
  push   %rbp
  lea    (%rsi,%rdi,1),%rbp
  push   %rbx
  cmp    %rbp,%rsi
  jae    L16
  mov    %rsi,%rbx
  lea    D4(%rip),%r12
  xchg   %ax,%ax
L8:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <print@plt>
  cmp    %rbp,%rbx
  jne    L8
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: byte 1 %d


assistant: ```c
void b_defstring(int len, char *str) {
  char *s;
  for (s = str; s < str + len; s++)
    print("byte 1 %d\n", (*s) & 0377);
}
```