user: 这段汇编代码用C语言表示是什么样的?

```asm
<com_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movb   $0x0,D14(%rip)
  cmpq   $0x0,-0x8(%rbp)
  jne    L80
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  lea    D74(%rip),%rax
  jmp    L111
L80:
  nop
L6:
  jmp    L204
L60:
  cmpl   $0x0,-0x10(%rbp)
  jne    L22
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  lea    D74(%rip),%rax
  jmp    L111
L22:
  addq   $0x1,-0x8(%rbp)
L204:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x20,-0x10(%rbp)
  jle    L60
  cmpl   $0x2f,-0x10(%rbp)
  jne    L137
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L137
  jmp    L38
L207:
  addq   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L207
  jmp    L6
L137:
  cmpl   $0x22,-0x10(%rbp)
  jne    L122
  addq   $0x1,-0x8(%rbp)
L183:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x22,-0x10(%rbp)
  je     L170
  cmpl   $0x0,-0x10(%rbp)
  jne    L143
L170:
  mov    -0xc(%rbp),%eax
  cltq
  lea    D14(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  lea    D14(%rip),%rax
  jmp    L111
L143:
  cmpl   $0x3ff,-0xc(%rbp)
  jg     L183
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    D14(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  addl   $0x1,-0xc(%rbp)
  jmp    L183
L122:
  cmpl   $0x3ff,-0xc(%rbp)
  jg     L70
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    D14(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  addl   $0x1,-0xc(%rbp)
L70:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x20,-0x10(%rbp)
  jg     L122
  cmpl   $0x400,-0xc(%rbp)
  jne    L49
  movl   $0x0,-0xc(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cltq
  lea    D14(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  lea    D14(%rip),%rax
L111:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D74
data_type: string

tool: 

assistant: ```c
char *com_parse(char **data_p) {
  int c;
  int len;
  char *data;
  static char com_token[128];
  data = *data_p;
  len = 0;
  com_token[0] = 0;
  if (!data) {
    *data_p = ((void *)0);
    return "";
  }
skipwhite:
  while ((c = *data) <= ' ') {
    if (c == 0) {
      *data_p = ((void *)0);
      return "";
    }
    data++;
  }
  if (c == '/' && data[1] == '/') {
    while (*data && *data != '\n') {
      data++;
    }
    goto skipwhite;
  }
  if (c == '\"') {
    data++;
    while (1) {
      c = *data++;
      if (c == '\"' || !c) {
        com_token[len] = 0;
        *data_p = data;
        return com_token;
      }
      if (len < 1024) {
        com_token[len] = c;
        len++;
      }
    }
  }
  do {
    if (len < 1024) {
      com_token[len] = c;
      len++;
    }
    data++;
    c = *data;
  } while (c > 32);
  if (len == 1024) {
    len = 0;
  }
  com_token[len] = 0;
  *data_p = data;
  return com_token;
}
```