ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_base>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rax
  xor    %edx,%edx
  div    %r13
  mov    %rdx,%rdi
  mov    %rax,%r14
  call   <dig2char@plt>
  mov    %r12d,%r8d
  mov    %al,-0x1(%rbx,%r12,1)
  mov    %rbp,%rax
  add    $0x1,%r12
  mov    %r14,%rbp
  cmp    %r13,%rax
  jae    L3
  mov    %r8d,%esi
  movslq %r8d,%rcx
  sar    %esi
  movb   $0x0,(%rbx,%rcx,1)
  je     L7
  lea    -0x2(%rcx,%rbx,1),%rdi
  lea    -0x1(%rcx,%rbx,1),%rdx
  mov    %rbx,%rax
  lea    -0x1(%rsi),%ecx
  sub    %rcx,%rdi
  nopl   0x0(%rax,%rax,1)
L20:
  movzbl (%rax),%ecx
  movzbl (%rdx),%esi
  sub    $0x1,%rdx
  add    $0x1,%rax
  mov    %sil,-0x1(%rax)
  mov    %cl,0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L20
L7:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int print_base(long unsigned int uval, char buf[], unsigned int base) {
  int i = 0;
  do {
    buf[i] = dig2char(uval % base);
    uval = uval / base;
    i++;
  } while (0 != uval);
  buf[i] = 0;
  int len = i;
  for (i = 0; i < (len / 2); i++) {
    char c = buf[i];
    buf[i] = buf[len - i - 1];
    buf[len - i - 1] = c;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_array_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <vcalloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L35
L39:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L35:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L39
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <vcalloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L34
L4:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  addl   $0x1,-0x18(%rbp)
L34:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get_string_type@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vfree@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: %s

assistant: ```c
char *get_array_type(int n, char **seq) {
  char *buf, *buf2;
  int a, tot = 0;
  buf2 = vcalloc(100, sizeof(char));
  for (tot = 0, a = 0; a < n; a++) {
    tot += strlen(seq[a]);
  }
  buf = vcalloc(tot + 1, sizeof(char));
  for (a = 0; a < n; a++) {
    strcat(buf, seq[a]);
  }
  sprintf(buf2, "%s", get_string_type(buf));
  vfree(buf);
  return buf2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_array_type>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <vcalloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L27
  mov    %rbx,%rbp
  lea    -0x1(%r12),%eax
  lea    0x8(%rbx,%rax,8),%r13
  mov    $0x0,%r12d
L24:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  add    %eax,%r12d
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L24
  lea    0x1(%r12),%edi
  mov    $0x1,%esi
  call   <vcalloc@plt>
  mov    %rax,%rbx
L7:
  mov    0x0(%rbp),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L7
L18:
  mov    %rbx,%rdi
  call   <get_string_type@plt>
  mov    %rax,%rdx
  lea    D0(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <vfree@plt>
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <vcalloc@plt>
  mov    %rax,%rbx
  jmp    L18
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: %s

assistant: ```c
char *get_array_type(int n, char **seq) {
  char *buf, *buf2;
  int a, tot = 0;
  buf2 = vcalloc(100, sizeof(char));
  for (tot = 0, a = 0; a < n; a++) {
    tot += strlen(seq[a]);
  }
  buf = vcalloc(tot + 1, sizeof(char));
  for (a = 0; a < n; a++) {
    strcat(buf, seq[a]);
  }
  sprintf(buf2, "%s", get_string_type(buf));
  vfree(buf);
  return buf2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_array_type>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x64,%edi
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <vcalloc@plt>
  mov    %rax,%r14
  test   %ebp,%ebp
  jle    L18
  lea    -0x1(%rbp),%eax
  xor    %r12d,%r12d
  mov    %rbx,%rbp
  lea    0x8(%rbx,%rax,8),%r13
  nopl   0x0(%rax)
L30:
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  call   <strlen@plt>
  add    %eax,%r12d
  cmp    %r13,%rbp
  jne    L30
  lea    0x1(%r12),%edi
  mov    $0x1,%esi
  call   <vcalloc@plt>
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <strcat@plt>
  cmp    %r13,%rbx
  jne    L21
L35:
  mov    %rbp,%rdi
  call   <get_string_type@plt>
  mov    %r14,%rdi
  lea    D0(%rip),%rsi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <vfree@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <vcalloc@plt>
  mov    %rax,%rbp
  jmp    L35
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: %s

assistant: ```c
char *get_array_type(int n, char **seq) {
  char *buf, *buf2;
  int a, tot = 0;
  buf2 = vcalloc(100, sizeof(char));
  for (tot = 0, a = 0; a < n; a++) {
    tot += strlen(seq[a]);
  }
  buf = vcalloc(tot + 1, sizeof(char));
  for (a = 0; a < n; a++) {
    strcat(buf, seq[a]);
  }
  sprintf(buf2, "%s", get_string_type(buf));
  vfree(buf);
  return buf2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_array_type>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x64,%edi
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <vcalloc@plt>
  mov    %rax,%r14
  test   %ebp,%ebp
  jle    L12
  lea    -0x1(%rbp),%eax
  xor    %r12d,%r12d
  mov    %rbx,%rbp
  lea    0x8(%rbx,%rax,8),%r13
  nopl   0x0(%rax)
L34:
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  call   <strlen@plt>
  add    %eax,%r12d
  cmp    %r13,%rbp
  jne    L34
  lea    0x1(%r12),%edi
  mov    $0x1,%esi
  call   <vcalloc@plt>
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <strcat@plt>
  cmp    %r13,%rbx
  jne    L8
L3:
  mov    %rbp,%rdi
  call   <get_string_type@plt>
  mov    %r14,%rdi
  lea    D2(%rip),%rsi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <vfree@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <vcalloc@plt>
  mov    %rax,%rbp
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D2: %s

assistant: ```c
char *get_array_type(int n, char **seq) {
  char *buf, *buf2;
  int a, tot = 0;
  buf2 = vcalloc(100, sizeof(char));
  for (tot = 0, a = 0; a < n; a++) {
    tot += strlen(seq[a]);
  }
  buf = vcalloc(tot + 1, sizeof(char));
  for (a = 0; a < n; a++) {
    strcat(buf, seq[a]);
  }
  sprintf(buf2, "%s", get_string_type(buf));
  vfree(buf);
  return buf2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abortmsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <vabortmsgerrno@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void abortmsg(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vabortmsgerrno(0, fmt, args);
  va_end(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<abortmsg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <vabortmsgerrno@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void abortmsg(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vabortmsgerrno(0, fmt, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<abortmsg>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <vabortmsgerrno@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void abortmsg(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vabortmsgerrno(0, fmt, args);
  va_end(args);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<abortmsg>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <vabortmsgerrno@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void abortmsg(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vabortmsgerrno(0, fmt, args);
  va_end(args);
}
```
user: What is the c source code of the assembly code below:

```asm
<XORblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L1
L13:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void XORblock(char const *src1, char const *src2, char *dst, size_t n) {
  size_t j;
  for (j = 0; j < n; ++j)
    dst[j] = src1[j] ^ src2[j];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<XORblock>:
  endbr64
  test   %rcx,%rcx
  je     L14
  mov    $0x0,%eax
L10:
  movzbl (%rdi,%rax,1),%r8d
  xor    (%rsi,%rax,1),%r8b
  mov    %r8b,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L10
L14:
  ret
```

assistant: ```c
void XORblock(char const *src1, char const *src2, char *dst, size_t n) {
  size_t j;
  for (j = 0; j < n; ++j)
    dst[j] = src1[j] ^ src2[j];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<XORblock>:
  endbr64
  test   %rcx,%rcx
  je     L18
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%rdi,%rax,1),%r8d
  xor    (%rsi,%rax,1),%r8b
  mov    %r8b,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L13
L18:
  ret
```

assistant: ```c
void XORblock(char const *src1, char const *src2, char *dst, size_t n) {
  size_t j;
  for (j = 0; j < n; ++j)
    dst[j] = src1[j] ^ src2[j];
}
```
user: What is the c source code of the assembly code below?

```asm
<XORblock>:
  endbr64
  test   %rcx,%rcx
  je     L52
  lea    0x1(%rsi),%r9
  mov    %rdx,%r8
  lea    -0x1(%rcx),%rax
  sub    %r9,%r8
  cmp    $0xe,%r8
  seta   %r9b
  cmp    $0x6,%rax
  seta   %r8b
  test   %r8b,%r9b
  je     L20
  lea    0x1(%rdi),%r9
  mov    %rdx,%r8
  sub    %r9,%r8
  cmp    $0xe,%r8
  jbe    L20
  mov    %rcx,%r8
  cmp    $0xe,%rax
  jbe    L120
  and    $0xfffffffffffffff0,%r8
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L23:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  pxor   %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L23
  mov    %rcx,%rax
  and    $0xfffffffffffffff0,%rax
  test   $0xf,%cl
  je     L52
  mov    %rcx,%r8
  sub    %rax,%r8
  lea    -0x1(%r8),%r9
  cmp    $0x6,%r9
  jbe    L12
L134:
  movq   (%rdi,%rax,1),%xmm0
  movq   (%rsi,%rax,1),%xmm1
  mov    %r8,%r9
  and    $0xfffffffffffffff8,%r9
  pxor   %xmm1,%xmm0
  movq   %xmm0,(%rdx,%rax,1)
  add    %r9,%rax
  cmp    %r9,%r8
  je     L52
L12:
  movzbl (%rdi,%rax,1),%r8d
  xor    (%rsi,%rax,1),%r8b
  mov    %r8b,(%rdx,%rax,1)
  lea    0x1(%rax),%r8
  cmp    %r8,%rcx
  jbe    L52
  movzbl 0x1(%rdi,%rax,1),%r8d
  xor    0x1(%rsi,%rax,1),%r8b
  mov    %r8b,0x1(%rdx,%rax,1)
  lea    0x2(%rax),%r8
  cmp    %r8,%rcx
  jbe    L52
  movzbl 0x2(%rdi,%rax,1),%r8d
  xor    0x2(%rsi,%rax,1),%r8b
  mov    %r8b,0x2(%rdx,%rax,1)
  lea    0x3(%rax),%r8
  cmp    %r8,%rcx
  jbe    L52
  movzbl 0x3(%rdi,%rax,1),%r8d
  xor    0x3(%rsi,%rax,1),%r8b
  mov    %r8b,0x3(%rdx,%rax,1)
  lea    0x4(%rax),%r8
  cmp    %r8,%rcx
  jbe    L52
  movzbl 0x4(%rdi,%rax,1),%r8d
  xor    0x4(%rsi,%rax,1),%r8b
  mov    %r8b,0x4(%rdx,%rax,1)
  lea    0x5(%rax),%r8
  cmp    %r8,%rcx
  jbe    L52
  movzbl 0x5(%rdi,%rax,1),%r8d
  xor    0x5(%rsi,%rax,1),%r8b
  mov    %r8b,0x5(%rdx,%rax,1)
  lea    0x6(%rax),%r8
  cmp    %r8,%rcx
  jbe    L52
  movzbl 0x6(%rdi,%rax,1),%ecx
  xor    0x6(%rsi,%rax,1),%cl
  mov    %cl,0x6(%rdx,%rax,1)
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl (%rdi,%rax,1),%r8d
  xor    (%rsi,%rax,1),%r8b
  mov    %r8b,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L14
L52:
  ret
L120:
  xor    %eax,%eax
  jmp    L134
```

assistant: ```c
void XORblock(char const *src1, char const *src2, char *dst, size_t n) {
  size_t j;
  for (j = 0; j < n; ++j)
    dst[j] = src1[j] ^ src2[j];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RemoveColorEscapeSequences>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  test   %rax,%rax
  je     L69
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  jne    L69
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L69
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  je     L69
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x37,%al
  jg     L69
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L69
  addl   $0x1,-0x8(%rbp)
  jmp    L24
L69:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7f,%al
  je     L29
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  jmp    L24
L29:
  nop
L24:
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void RemoveColorEscapeSequences(char *text) {
  int i, l;
  l = 0;
  for (i = 0; text[i]; i++) {
    if ((&text[i] && *(&text[i]) == '^' && *((&text[i]) + 1) && *((&text[i]) + 1) != '^' && *((&text[i]) + 1) <= '7' && *((&text[i]) + 1) >= '0')) {
      i++;
      continue;
    }
    if (text[i] > 0x7E)
      continue;
    text[l++] = text[i];
  }
  text[l] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RemoveColorEscapeSequences>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L57
  mov    %rdi,%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%r8d
  jmp    L20
L66:
  cmp    $0x7f,%al
  je     L23
L73:
  movslq %ecx,%rsi
  mov    %al,(%rdi,%rsi,1)
  lea    0x1(%rcx),%ecx
L23:
  add    $0x1,%edx
  movslq %edx,%r8
  lea    (%rdi,%r8,1),%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  je     L74
L20:
  cmp    $0x5e,%al
  jne    L66
  test   %rsi,%rsi
  je     L66
  movzbl 0x1(%rdi,%r8,1),%esi
  sub    $0x30,%esi
  cmp    $0x7,%sil
  ja     L73
  add    $0x1,%edx
  jmp    L23
L57:
  mov    $0x0,%ecx
L74:
  movslq %ecx,%rcx
  movb   $0x0,(%rdi,%rcx,1)
  ret
```

assistant: ```c
void RemoveColorEscapeSequences(char *text) {
  int i, l;
  l = 0;
  for (i = 0; text[i]; i++) {
    if ((&text[i] && *(&text[i]) == '^' && *((&text[i]) + 1) && *((&text[i]) + 1) != '^' && *((&text[i]) + 1) <= '7' && *((&text[i]) + 1) >= '0')) {
      i++;
      continue;
    }
    if (text[i] > 0x7E)
      continue;
    text[l++] = text[i];
  }
  text[l] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<RemoveColorEscapeSequences>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L32
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L59:
  cmp    $0x7f,%al
  je     L54
L63:
  movslq %ecx,%rsi
  add    $0x1,%ecx
  mov    %al,(%rdi,%rsi,1)
L54:
  add    $0x1,%edx
  movslq %edx,%rsi
  movzbl (%rdi,%rsi,1),%eax
  test   %al,%al
  je     L47
L62:
  cmp    $0x5e,%al
  jne    L59
  movzbl 0x1(%rdi,%rsi,1),%esi
  sub    $0x30,%esi
  cmp    $0x7,%sil
  ja     L63
  add    $0x1,%edx
  add    $0x1,%edx
  movslq %edx,%rsi
  movzbl (%rdi,%rsi,1),%eax
  test   %al,%al
  jne    L62
  cs nopw 0x0(%rax,%rax,1)
L47:
  movslq %ecx,%rcx
  add    %rcx,%rdi
L32:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void RemoveColorEscapeSequences(char *text) {
  int i, l;
  l = 0;
  for (i = 0; text[i]; i++) {
    if ((&text[i] && *(&text[i]) == '^' && *((&text[i]) + 1) && *((&text[i]) + 1) != '^' && *((&text[i]) + 1) <= '7' && *((&text[i]) + 1) >= '0')) {
      i++;
      continue;
    }
    if (text[i] > 0x7E)
      continue;
    text[l++] = text[i];
  }
  text[l] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<RemoveColorEscapeSequences>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    $0x7f,%al
  je     L56
L58:
  movslq %ecx,%rsi
  add    $0x1,%ecx
  mov    %al,(%rdi,%rsi,1)
L56:
  add    $0x1,%edx
  movslq %edx,%rsi
  movzbl (%rdi,%rsi,1),%eax
  test   %al,%al
  je     L51
L10:
  cmp    $0x5e,%al
  jne    L20
  movzbl 0x1(%rdi,%rsi,1),%esi
  sub    $0x30,%esi
  cmp    $0x7,%sil
  ja     L58
  add    $0x1,%edx
  add    $0x1,%edx
  movslq %edx,%rsi
  movzbl (%rdi,%rsi,1),%eax
  test   %al,%al
  jne    L10
  cs nopw 0x0(%rax,%rax,1)
L51:
  movslq %ecx,%rcx
  add    %rcx,%rdi
L0:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void RemoveColorEscapeSequences(char *text) {
  int i, l;
  l = 0;
  for (i = 0; text[i]; i++) {
    if ((&text[i] && *(&text[i]) == '^' && *((&text[i]) + 1) && *((&text[i]) + 1) != '^' && *((&text[i]) + 1) <= '7' && *((&text[i]) + 1) >= '0')) {
      i++;
      continue;
    }
    if (text[i] > 0x7E)
      continue;
    text[l++] = text[i];
  }
  text[l] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  cld
  rep movsb %ds:(%rsi),%es:(%rdi)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_memory(char *dest, const char *src, unsigned int n) {
  void *_ret = dest;
  __asm__("cld;rep;movsb" ::"D"((void *)(_ret)), "S"((void *)(src)), "c"((n)));
  return _ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_memory>:
  endbr64
  mov    %edx,%ecx
  cld
  rep movsb %ds:(%rsi),%es:(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *my_memory(char *dest, const char *src, unsigned int n) {
  void *_ret = dest;
  __asm__("cld;rep;movsb" ::"D"((void *)(_ret)), "S"((void *)(src)), "c"((n)));
  return _ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_memory>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%ecx
  cld
  rep movsb %ds:(%rsi),%es:(%rdi)
  ret
```

assistant: ```c
char *my_memory(char *dest, const char *src, unsigned int n) {
  void *_ret = dest;
  __asm__("cld;rep;movsb" ::"D"((void *)(_ret)), "S"((void *)(src)), "c"((n)));
  return _ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_memory>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%ecx
  cld
  rep movsb %ds:(%rsi),%es:(%rdi)
  ret
```

assistant: ```c
char *my_memory(char *dest, const char *src, unsigned int n) {
  void *_ret = dest;
  __asm__("cld;rep;movsb" ::"D"((void *)(_ret)), "S"((void *)(src)), "c"((n)));
  return _ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <setup_screen@plt>
  mov    $0x0,%eax
  call   <zombie_wrap@plt>
  mov    $0x0,%eax
  call   <cleanup_screen@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  setup_screen();
  zombie_wrap();
  cleanup_screen();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <setup_screen@plt>
  mov    $0x0,%eax
  call   <zombie_wrap@plt>
  mov    $0x0,%eax
  call   <cleanup_screen@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  setup_screen();
  zombie_wrap();
  cleanup_screen();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_screen@plt>
  xor    %eax,%eax
  call   <zombie_wrap@plt>
  xor    %eax,%eax
  call   <cleanup_screen@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  setup_screen();
  zombie_wrap();
  cleanup_screen();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_screen@plt>
  xor    %eax,%eax
  call   <zombie_wrap@plt>
  xor    %eax,%eax
  call   <cleanup_screen@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  setup_screen();
  zombie_wrap();
  cleanup_screen();
  return 0;
}
```