ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x500000001,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x1f0000000c,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000283,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x7b00000005,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4100000138,%rax
  mov    %rax,0x20(%rsp)
  call   <avg8bt@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x1,%eax
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main(void) {
  uint8_t arr[10] = {1, 5, 12, 31, 643, 1, 5, 123, 312, 65};
  printf("%d\r\n", avg8bt(arr, 10));
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D29(%rip),%xmm0
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D28(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <avg8bt@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x1,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D29
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D3
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D28
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D21
type_infered: string

tool: {"D29": [0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

tool: {"D3": [0x38,0x01,0x00,0x00,0x41,0x00,0x00,0x00]}

tool: {"D28": [0x83,0x02,0x00,0x00,0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x7b,0x00,0x00,0x00]}

tool: D21: %d


assistant: ```c
int main(void) {
  uint8_t arr[10] = {1, 5, 12, 31, 643, 1, 5, 123, 312, 65};
  printf("%d\r\n", avg8bt(arr, 10));
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D18(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movsd  D18(%rip),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
data_type: byte[8]
name: unpack_data
arguments: data_label: D13
data_type: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
double f_prime(double x) {
  double y;
  y = 3 * (x - 1) * (x - 1);
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f_prime>:
  endbr64
  subsd  D10(%rip),%xmm0
  movapd %xmm0,%xmm1
  mulsd  D4(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type: byte[8]
name: retrieve_data
arguments: data_label: D4
type: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
double f_prime(double x) {
  double y;
  y = 3 * (x - 1) * (x - 1);
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f_prime>:
  endbr64
  subsd  D12(%rip),%xmm0
  movsd  D1(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D1
type_infered: byte[8]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
double f_prime(double x) {
  double y;
  y = 3 * (x - 1) * (x - 1);
  return y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f_prime>:
  endbr64
  subsd  D5(%rip),%xmm0
  movsd  D17(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: byte[8]
name: read_data
arguments: label: D17
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
double f_prime(double x) {
  double y;
  y = 3 * (x - 1) * (x - 1);
  return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UARTModemStatusGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  and    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long UARTModemStatusGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned long *)(ulBase + 0x00000018))) & (0x00000001));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UARTModemStatusGet>:
  endbr64
  mov    0x18(%rdi),%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned long UARTModemStatusGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned long *)(ulBase + 0x00000018))) & (0x00000001));
}
```
user: What is the c source code of the assembly code below?

```asm
<UARTModemStatusGet>:
  endbr64
  mov    0x18(%rdi),%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned long UARTModemStatusGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned long *)(ulBase + 0x00000018))) & (0x00000001));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UARTModemStatusGet>:
  endbr64
  mov    0x18(%rdi),%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned long UARTModemStatusGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned long *)(ulBase + 0x00000018))) & (0x00000001));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L56
L23:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L22
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L40
L22:
  mov    -0xc(%rbp),%eax
  cmp    $0xc,%eax
  jle    L51
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L40
L51:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <rfact@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L40:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L56:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L23
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D84
datatype: string
name: parse_data
arguments: data_label: D28
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D33
datatype: string
name: parse_data
arguments: data_label: D88
datatype: string
name: parse_data
arguments: data_label: D65
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string
name: parse_data
arguments: data_label: D39
datatype: string

tool: D84: This program calculates factorials.

tool: D28: Enter a value in the range 0-12 (q to quit):

tool: D4: No negative numbers, please.

tool: D33: Keep input under13.

tool: D88: loop: %d factorial = %ld


tool: D65: recursion: %d factorial = %ld


tool: D3: %d

tool: D39: Bye.

assistant: ```c
int main(void) {
  int num;
  printf("This program calculates factorials.\n");
  printf("Enter a value in the range 0-12 (q to quit):\n");
  while (scanf("%d", &num) == 1) {
    if (num < 0) {
      printf("No negative numbers, please.\n");
    } else if (num > 12) {
      printf("Keep input under13.\n");
    } else {
      printf("loop: %d factorial = %ld\n", num, fact(num));
      printf("recursion: %d factorial = %ld\n", num, rfact(num));
    }
    printf("Enter a value in the range 0-12 (q to quit):\n");
  }
  printf("Bye.\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D84(%rip),%rdi
  call   <puts@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  lea    D82(%rip),%rbx
  lea    D67(%rip),%r13
  lea    D86(%rip),%r12
  lea    D31(%rip),%rbp
  jmp    L21
L44:
  lea    D64(%rip),%rdi
  call   <puts@plt>
  jmp    L29
L45:
  call   <fact@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <rfact@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L29:
  lea    D59(%rip),%rdi
  call   <puts@plt>
L21:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L58
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L44
  cmp    $0xc,%edi
  jle    L45
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L29
L58:
  lea    D81(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D84
type_infered: string
name: read_data
arguments: label: D59
type_infered: string
name: read_data
arguments: label: D82
type_infered: string
name: read_data
arguments: label: D67
type_infered: string
name: read_data
arguments: label: D86
type_infered: string
name: read_data
arguments: label: D31
type_infered: string
name: read_data
arguments: label: D64
type_infered: string
name: read_data
arguments: label: D81
type_infered: string

tool: D84: This program calculates factorials.

tool: D59: Enter a value in the range 0-12 (q to quit):

tool: D82: %d

tool: D67: loop: %d factorial = %ld


tool: D86: recursion: %d factorial = %ld


tool: D31: Keep input under13.

tool: D64: No negative numbers, please.

tool: D81: Bye.

assistant: ```c
int main(void) {
  int num;
  printf("This program calculates factorials.\n");
  printf("Enter a value in the range 0-12 (q to quit):\n");
  while (scanf("%d", &num) == 1) {
    if (num < 0) {
      printf("No negative numbers, please.\n");
    } else if (num > 12) {
      printf("Keep input under13.\n");
    } else {
      printf("loop: %d factorial = %ld\n", num, fact(num));
      printf("recursion: %d factorial = %ld\n", num, rfact(num));
    }
    printf("Enter a value in the range 0-12 (q to quit):\n");
  }
  printf("Bye.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D46(%rip),%rdi
  lea    D44(%rip),%r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  lea    D64(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D21(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L4
L29:
  mov    %r13,%rdi
  call   <puts@plt>
L69:
  mov    %r12,%rdi
  call   <puts@plt>
L4:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L67
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L36
  cmp    $0xc,%edi
  jg     L29
  call   <fact@plt>
  mov    0x4(%rsp),%esi
  mov    %r15,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <rfact@plt>
  mov    0x4(%rsp),%esi
  mov    %r14,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L69
  nopl   (%rax)
L36:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L69
  xchg   %ax,%ax
L67:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D46
type: string
name: extract_symbolic_data
arguments: data_tag: D44
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D27
type: string
name: extract_symbolic_data
arguments: data_tag: D64
type: string
name: extract_symbolic_data
arguments: data_tag: D21
type: string
name: extract_symbolic_data
arguments: data_tag: D38
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string

tool: D46: This program calculates factorials.

tool: D44: loop: %d factorial = %ld


tool: D8: recursion: %d factorial = %ld


tool: D27: Keep input under13.

tool: D64: Enter a value in the range 0-12 (q to quit):

tool: D21: %d

tool: D38: No negative numbers, please.

tool: D16: Bye.

assistant: ```c
int main(void) {
  int num;
  printf("This program calculates factorials.\n");
  printf("Enter a value in the range 0-12 (q to quit):\n");
  while (scanf("%d", &num) == 1) {
    if (num < 0) {
      printf("No negative numbers, please.\n");
    } else if (num > 12) {
      printf("Keep input under13.\n");
    } else {
      printf("loop: %d factorial = %ld\n", num, fact(num));
      printf("recursion: %d factorial = %ld\n", num, rfact(num));
    }
    printf("Enter a value in the range 0-12 (q to quit):\n");
  }
  printf("Bye.\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  lea    D66(%rip),%rdi
  lea    D22(%rip),%r15
  push   %r14
  lea    D45(%rip),%r14
  push   %r13
  lea    D41(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D51(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L49
L40:
  mov    %r13,%rdi
  call   <puts@plt>
L16:
  mov    %r12,%rdi
  call   <puts@plt>
L49:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L60
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L7
  cmp    $0xc,%edi
  jg     L40
  call   <fact@plt>
  mov    0x4(%rsp),%esi
  mov    %r15,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <rfact@plt>
  mov    0x4(%rsp),%esi
  mov    %r14,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L16
  nopl   (%rax)
L7:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  jmp    L16
  xchg   %ax,%ax
L60:
  lea    D75(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D66
type_guessed: string
name: disassemble_data
arguments: data_label: D22
type_guessed: string
name: disassemble_data
arguments: data_label: D45
type_guessed: string
name: disassemble_data
arguments: data_label: D41
type_guessed: string
name: disassemble_data
arguments: data_label: D12
type_guessed: string
name: disassemble_data
arguments: data_label: D51
type_guessed: string
name: disassemble_data
arguments: data_label: D17
type_guessed: string
name: disassemble_data
arguments: data_label: D75
type_guessed: string

tool: D66: This program calculates factorials.

tool: D22: loop: %d factorial = %ld


tool: D45: recursion: %d factorial = %ld


tool: D41: Keep input under13.

tool: D12: Enter a value in the range 0-12 (q to quit):

tool: D51: %d

tool: D17: No negative numbers, please.

tool: D75: Bye.

assistant: ```c
int main(void) {
  int num;
  printf("This program calculates factorials.\n");
  printf("Enter a value in the range 0-12 (q to quit):\n");
  while (scanf("%d", &num) == 1) {
    if (num < 0) {
      printf("No negative numbers, please.\n");
    } else if (num > 12) {
      printf("Keep input under13.\n");
    } else {
      printf("loop: %d factorial = %ld\n", num, fact(num));
      printf("recursion: %d factorial = %ld\n", num, rfact(num));
    }
    printf("Enter a value in the range 0-12 (q to quit):\n");
  }
  printf("Bye.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L33
L9:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L31
  addq   $0x1,-0x8(%rbp)
L33:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  jmp    L29
L31:
  nop
L29:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t strspn(const char *str1, const char *str2) {
  size_t i = 0;
  for (; str1[i]; ++i) {
    if (!strchr(str2, str1[i]))
      break;
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<strspn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L0
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L14:
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L37
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%esi
  test   %sil,%sil
  jne    L14
L37:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    $0x0,%ebx
  jmp    L37
```

assistant: ```c
size_t strspn(const char *str1, const char *str2) {
  size_t i = 0;
  for (; str1[i]; ++i) {
    if (!strchr(str2, str1[i]))
      break;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strspn>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L13
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%r12
  movsbl (%rbx,%r12,1),%esi
  test   %sil,%sil
  je     L45
L16:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L35
L45:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  xor    %r12d,%r12d
  jmp    L45
```

assistant: ```c
size_t strspn(const char *str1, const char *str2) {
  size_t i = 0;
  for (; str1[i]; ++i) {
    if (!strchr(str2, str1[i]))
      break;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strspn>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L32
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%r12
  movsbl (%rbx,%r12,1),%esi
  test   %sil,%sil
  je     L4
L37:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L12
L4:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  xor    %r12d,%r12d
  jmp    L4
```

assistant: ```c
size_t strspn(const char *str1, const char *str2) {
  size_t i = 0;
  for (; str1[i]; ++i) {
    if (!strchr(str2, str1[i]))
      break;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <kalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdup(char const *str) {
  size_t len;
  char *out;
  len = strlen(str);
  out = kalloc(len + 1);
  memcpy(out, str, len);
  *(out + len) = '\0';
  return (out);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rax),%rdi
  call   <kalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(char const *str) {
  size_t len;
  char *out;
  len = strlen(str);
  out = kalloc(len + 1);
  memcpy(out, str, len);
  *(out + len) = '\0';
  return (out);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <kalloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(char const *str) {
  size_t len;
  char *out;
  len = strlen(str);
  out = kalloc(len + 1);
  memcpy(out, str, len);
  *(out + len) = '\0';
  return (out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <kalloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(char const *str) {
  size_t len;
  char *out;
  len = strlen(str);
  out = kalloc(len + 1);
  memcpy(out, str, len);
  *(out + len) = '\0';
  return (out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: %p


assistant: ```c
int main() {
  char *v = (char *)malloc(0);
  printf("%p\n", v);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %p


assistant: ```c
int main() {
  char *v = (char *)malloc(0);
  printf("%p\n", v);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <malloc@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: %p


assistant: ```c
int main() {
  char *v = (char *)malloc(0);
  printf("%p\n", v);
}
```