ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<computeChainRuleFromProjOntoTriMatVertex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  call   <dotVectors@plt>
  movapd %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movaps %xmm0,%xmm1
  mulss  0x0(%rbp),%xmm1
  mulss  (%rbx),%xmm1
  movss  D3(%rip),%xmm2
  movaps %xmm2,%xmm3
  subss  %xmm1,%xmm3
  movss  %xmm3,(%r12)
  movaps %xmm0,%xmm3
  mulss  0x4(%rbp),%xmm3
  mulss  (%rbx),%xmm3
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm4
  subss  %xmm3,%xmm4
  movss  %xmm4,0x4(%r12)
  movaps %xmm0,%xmm3
  mulss  0x8(%rbp),%xmm3
  mulss  (%rbx),%xmm3
  movaps %xmm1,%xmm4
  subss  %xmm3,%xmm4
  movss  %xmm4,0x8(%r12)
  movaps %xmm0,%xmm3
  mulss  0x0(%rbp),%xmm3
  mulss  0x4(%rbx),%xmm3
  movaps %xmm1,%xmm4
  subss  %xmm3,%xmm4
  movss  %xmm4,0xc(%r12)
  movaps %xmm0,%xmm3
  mulss  0x4(%rbp),%xmm3
  mulss  0x4(%rbx),%xmm3
  movaps %xmm2,%xmm4
  subss  %xmm3,%xmm4
  movss  %xmm4,0x10(%r12)
  movaps %xmm0,%xmm3
  mulss  0x8(%rbp),%xmm3
  mulss  0x4(%rbx),%xmm3
  movaps %xmm1,%xmm4
  subss  %xmm3,%xmm4
  movss  %xmm4,0x14(%r12)
  movaps %xmm0,%xmm3
  mulss  0x0(%rbp),%xmm3
  mulss  0x8(%rbx),%xmm3
  movaps %xmm1,%xmm4
  subss  %xmm3,%xmm4
  movss  %xmm4,0x18(%r12)
  movaps %xmm0,%xmm3
  mulss  0x4(%rbp),%xmm3
  mulss  0x8(%rbx),%xmm3
  subss  %xmm3,%xmm1
  movss  %xmm1,0x1c(%r12)
  mulss  0x8(%rbp),%xmm0
  mulss  0x8(%rbx),%xmm0
  subss  %xmm0,%xmm2
  movss  %xmm2,0x20(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: f64
name: unpack_data
arguments: tag: D3
type_infered: byte[4]

tool: D2: 1

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void computeChainRuleFromProjOntoTriMatVertex(const float *point, const float *norm, float *mat) {
  float C;
  C = 1.0 / dotVectors(point, norm);
  mat[0] = 1 - C * point[0] * norm[0];
  mat[1] = 0.0 - C * point[1] * norm[0];
  mat[2] = 0.0 - C * point[2] * norm[0];
  mat[3] = 0.0 - C * point[0] * norm[1];
  mat[4] = 1 - C * point[1] * norm[1];
  mat[5] = 0.0 - C * point[2] * norm[1];
  mat[6] = 0.0 - C * point[0] * norm[2];
  mat[7] = 0.0 - C * point[1] * norm[2];
  mat[8] = 1 - C * point[2] * norm[2];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<computeChainRuleFromProjOntoTriMatVertex>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <dotVectors@plt>
  movss  D14(%rip),%xmm2
  movapd %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  movaps %xmm2,%xmm3
  divsd  %xmm1,%xmm0
  movss  0x0(%rbp),%xmm1
  cvtsd2ss %xmm0,%xmm0
  mulss  %xmm0,%xmm1
  mulss  (%rbx),%xmm1
  subss  %xmm1,%xmm3
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm4
  movss  %xmm3,(%r12)
  movss  0x4(%rbp),%xmm3
  mulss  %xmm0,%xmm3
  mulss  (%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x4(%r12)
  movss  0x8(%rbp),%xmm3
  movaps %xmm1,%xmm4
  mulss  %xmm0,%xmm3
  mulss  (%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x8(%r12)
  movss  0x0(%rbp),%xmm3
  movaps %xmm1,%xmm4
  mulss  %xmm0,%xmm3
  mulss  0x4(%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0xc(%r12)
  movss  0x4(%rbp),%xmm3
  movaps %xmm2,%xmm4
  mulss  %xmm0,%xmm3
  mulss  0x4(%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x10(%r12)
  movss  0x8(%rbp),%xmm3
  movaps %xmm1,%xmm4
  mulss  %xmm0,%xmm3
  mulss  0x4(%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x14(%r12)
  movss  0x0(%rbp),%xmm3
  movaps %xmm1,%xmm4
  mulss  %xmm0,%xmm3
  mulss  0x8(%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x18(%r12)
  movss  0x4(%rbp),%xmm3
  mulss  %xmm0,%xmm3
  mulss  0x8(%rbx),%xmm3
  subss  %xmm3,%xmm1
  movss  %xmm1,0x1c(%r12)
  mulss  0x8(%rbp),%xmm0
  mulss  0x8(%rbx),%xmm0
  pop    %rbx
  pop    %rbp
  subss  %xmm0,%xmm2
  movss  %xmm2,0x20(%r12)
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: f32
name: read_data
arguments: data_tag: D0
type_infered: f32[2]

tool: D14: 1

tool: {"D0": [0.0,1.875]}

assistant: ```c
void computeChainRuleFromProjOntoTriMatVertex(const float *point, const float *norm, float *mat) {
  float C;
  C = 1.0 / dotVectors(point, norm);
  mat[0] = 1 - C * point[0] * norm[0];
  mat[1] = 0.0 - C * point[1] * norm[0];
  mat[2] = 0.0 - C * point[2] * norm[0];
  mat[3] = 0.0 - C * point[0] * norm[1];
  mat[4] = 1 - C * point[1] * norm[1];
  mat[5] = 0.0 - C * point[2] * norm[1];
  mat[6] = 0.0 - C * point[0] * norm[2];
  mat[7] = 0.0 - C * point[1] * norm[2];
  mat[8] = 1 - C * point[2] * norm[2];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<computeChainRuleFromProjOntoTriMatVertex>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <dotVectors@plt>
  movss  D18(%rip),%xmm2
  movapd %xmm0,%xmm1
  movsd  D6(%rip),%xmm0
  movaps %xmm2,%xmm3
  divsd  %xmm1,%xmm0
  movss  0x0(%rbp),%xmm1
  cvtsd2ss %xmm0,%xmm0
  mulss  %xmm0,%xmm1
  mulss  (%rbx),%xmm1
  subss  %xmm1,%xmm3
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm4
  movss  %xmm3,(%r12)
  movss  0x4(%rbp),%xmm3
  mulss  %xmm0,%xmm3
  mulss  (%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x4(%r12)
  movss  0x8(%rbp),%xmm3
  movaps %xmm1,%xmm4
  mulss  %xmm0,%xmm3
  mulss  (%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x8(%r12)
  movss  0x0(%rbp),%xmm3
  movaps %xmm1,%xmm4
  mulss  %xmm0,%xmm3
  mulss  0x4(%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0xc(%r12)
  movss  0x4(%rbp),%xmm3
  movaps %xmm2,%xmm4
  mulss  %xmm0,%xmm3
  mulss  0x4(%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x10(%r12)
  movss  0x8(%rbp),%xmm3
  movaps %xmm1,%xmm4
  mulss  %xmm0,%xmm3
  mulss  0x4(%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x14(%r12)
  movss  0x0(%rbp),%xmm3
  movaps %xmm1,%xmm4
  mulss  %xmm0,%xmm3
  mulss  0x8(%rbx),%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,0x18(%r12)
  movss  0x4(%rbp),%xmm3
  mulss  %xmm0,%xmm3
  mulss  0x8(%rbx),%xmm3
  subss  %xmm3,%xmm1
  movss  %xmm1,0x1c(%r12)
  mulss  0x8(%rbp),%xmm0
  mulss  0x8(%rbx),%xmm0
  pop    %rbx
  pop    %rbp
  subss  %xmm0,%xmm2
  movss  %xmm2,0x20(%r12)
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_infered: f32
name: parse_data
arguments: data_tag: D6
type_infered: f32[2]

tool: D18: 1

tool: {"D6": [0.0,1.875]}

assistant: ```c
void computeChainRuleFromProjOntoTriMatVertex(const float *point, const float *norm, float *mat) {
  float C;
  C = 1.0 / dotVectors(point, norm);
  mat[0] = 1 - C * point[0] * norm[0];
  mat[1] = 0.0 - C * point[1] * norm[0];
  mat[2] = 0.0 - C * point[2] * norm[0];
  mat[3] = 0.0 - C * point[0] * norm[1];
  mat[4] = 1 - C * point[1] * norm[1];
  mat[5] = 0.0 - C * point[2] * norm[1];
  mat[6] = 0.0 - C * point[0] * norm[2];
  mat[7] = 0.0 - C * point[1] * norm[2];
  mat[8] = 1 - C * point[2] * norm[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stb_bitreverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  and    $0x55555555,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  and    $0xaaaaaaaa,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  and    $0xcccccccc,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  and    $0xf0f0f0f0,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  rol    $0x10,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int stb_bitreverse(unsigned int n) {
  n = ((n & 0xAAAAAAAA) >> 1) | ((n & 0x55555555) << 1);
  n = ((n & 0xCCCCCCCC) >> 2) | ((n & 0x33333333) << 2);
  n = ((n & 0xF0F0F0F0) >> 4) | ((n & 0x0F0F0F0F) << 4);
  n = ((n & 0xFF00FF00) >> 8) | ((n & 0x00FF00FF) << 8);
  return (n >> 16) | (n << 16);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stb_bitreverse>:
  endbr64
  mov    %edi,%eax
  shr    %edi
  and    $0x55555555,%edi
  add    %eax,%eax
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  shl    $0x2,%edi
  and    $0xcccccccc,%edi
  or     %edi,%eax
  mov    %eax,%edx
  shr    $0x4,%edx
  and    $0xf0f0f0f,%edx
  shl    $0x4,%eax
  and    $0xf0f0f0f0,%eax
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  shl    $0x8,%edx
  and    $0xff00ff00,%edx
  or     %edx,%eax
  rol    $0x10,%eax
  ret
```

assistant: ```c
unsigned int stb_bitreverse(unsigned int n) {
  n = ((n & 0xAAAAAAAA) >> 1) | ((n & 0x55555555) << 1);
  n = ((n & 0xCCCCCCCC) >> 2) | ((n & 0x33333333) << 2);
  n = ((n & 0xF0F0F0F0) >> 4) | ((n & 0x0F0F0F0F) << 4);
  n = ((n & 0xFF00FF00) >> 8) | ((n & 0x00FF00FF) << 8);
  return (n >> 16) | (n << 16);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stb_bitreverse>:
  endbr64
  mov    %edi,%eax
  shr    %edi
  add    %eax,%eax
  and    $0x55555555,%edi
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%edx
  shl    $0x2,%edi
  shr    $0x2,%edx
  and    $0xcccccccc,%edi
  and    $0x33333333,%edx
  or     %edi,%edx
  mov    %edx,%eax
  shl    $0x4,%edx
  shr    $0x4,%eax
  and    $0xf0f0f0f0,%edx
  and    $0xf0f0f0f,%eax
  or     %edx,%eax
  bswap  %eax
  ret
```

assistant: ```c
unsigned int stb_bitreverse(unsigned int n) {
  n = ((n & 0xAAAAAAAA) >> 1) | ((n & 0x55555555) << 1);
  n = ((n & 0xCCCCCCCC) >> 2) | ((n & 0x33333333) << 2);
  n = ((n & 0xF0F0F0F0) >> 4) | ((n & 0x0F0F0F0F) << 4);
  n = ((n & 0xFF00FF00) >> 8) | ((n & 0x00FF00FF) << 8);
  return (n >> 16) | (n << 16);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stb_bitreverse>:
  endbr64
  mov    %edi,%eax
  shr    %edi
  add    %eax,%eax
  and    $0x55555555,%edi
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%edx
  shl    $0x2,%edi
  shr    $0x2,%edx
  and    $0xcccccccc,%edi
  and    $0x33333333,%edx
  or     %edi,%edx
  mov    %edx,%eax
  shl    $0x4,%edx
  shr    $0x4,%eax
  and    $0xf0f0f0f0,%edx
  and    $0xf0f0f0f,%eax
  or     %edx,%eax
  bswap  %eax
  ret
```

assistant: ```c
unsigned int stb_bitreverse(unsigned int n) {
  n = ((n & 0xAAAAAAAA) >> 1) | ((n & 0x55555555) << 1);
  n = ((n & 0xCCCCCCCC) >> 2) | ((n & 0x33333333) << 2);
  n = ((n & 0xF0F0F0F0) >> 4) | ((n & 0x0F0F0F0F) << 4);
  n = ((n & 0xFF00FF00) >> 8) | ((n & 0x00FF00FF) << 8);
  return (n >> 16) | (n << 16);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L79
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L1
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L34
L26:
  addl   $0x1,-0xc(%rbp)
L79:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
const char *getNum(const int argc, const char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    char *ch = (char *)argv[i];
    while (*ch) {
      if (((*ch - '0') >= 0) && ((*ch - '0') <= 9))
        ch++;
      else
        break;
    }
    if (!(*ch))
      return argv[i];
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getNum>:
  endbr64
  cmp    $0x1,%edi
  jle    L21
  lea    0x8(%rsi),%r8
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rdi
  jmp    L68
L73:
  test   %al,%al
  je     L78
  add    $0x8,%r8
  cmp    %rdi,%r8
  je     L20
L68:
  mov    (%r8),%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  je     L78
  mov    %rsi,%rdx
L61:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L73
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L61
L78:
  mov    %rsi,%rax
  ret
L20:
  mov    $0x0,%esi
  jmp    L78
L21:
  mov    $0x0,%esi
  jmp    L78
```

assistant: ```c
const char *getNum(const int argc, const char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    char *ch = (char *)argv[i];
    while (*ch) {
      if (((*ch - '0') >= 0) && ((*ch - '0') <= 9))
        ch++;
      else
        break;
    }
    if (!(*ch))
      return argv[i];
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getNum>:
  endbr64
  cmp    $0x1,%edi
  jle    L57
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rcx
  lea    0x10(%rsi,%rax,8),%rsi
  nopl   (%rax)
L15:
  mov    (%rcx),%r8
  movzbl (%r8),%eax
  test   %al,%al
  je     L33
  mov    %r8,%rdx
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L52:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L33
L44:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L52
  add    $0x8,%rcx
  cmp    %rsi,%rcx
  jne    L15
L57:
  xor    %r8d,%r8d
L33:
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *getNum(const int argc, const char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    char *ch = (char *)argv[i];
    while (*ch) {
      if (((*ch - '0') >= 0) && ((*ch - '0') <= 9))
        ch++;
      else
        break;
    }
    if (!(*ch))
      return argv[i];
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getNum>:
  endbr64
  cmp    $0x1,%edi
  jle    L15
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rcx
  lea    0x10(%rsi,%rax,8),%rsi
  nopl   (%rax)
L19:
  mov    (%rcx),%r8
  movzbl (%r8),%eax
  test   %al,%al
  je     L49
  mov    %r8,%rdx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L28:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L49
L20:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L28
  add    $0x8,%rcx
  cmp    %rcx,%rsi
  jne    L19
L15:
  xor    %r8d,%r8d
L49:
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *getNum(const int argc, const char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    char *ch = (char *)argv[i];
    while (*ch) {
      if (((*ch - '0') >= 0) && ((*ch - '0') <= 9))
        ch++;
      else
        break;
    }
    if (!(*ch))
      return argv[i];
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<showHistogram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  lea    0x21(%rax),%esi
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x5c,-0x4(%rbp)
  jle    L5
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: %02d (%c) %d


assistant: ```c
int showHistogram(int *histogram) {
  int i;
  for (i = 0; i < 93; i++) {
    printf("%02d (%c) %d\n", i, i + '!', histogram[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<showHistogram>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L7:
  mov    0x0(%rbp,%rbx,4),%ecx
  lea    0x21(%rbx),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5d,%rbx
  jne    L7
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: %02d (%c) %d


assistant: ```c
int showHistogram(int *histogram) {
  int i;
  for (i = 0; i < 93; i++) {
    printf("%02d (%c) %d\n", i, i + '!', histogram[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<showHistogram>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L6:
  mov    0x0(%rbp,%rbx,4),%ecx
  lea    0x21(%rbx),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5d,%rbx
  jne    L6
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: %02d (%c) %d


assistant: ```c
int showHistogram(int *histogram) {
  int i;
  for (i = 0; i < 93; i++) {
    printf("%02d (%c) %d\n", i, i + '!', histogram[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<showHistogram>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L5:
  mov    0x0(%rbp,%rbx,4),%ecx
  lea    0x21(%rbx),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5d,%rbx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: %02d (%c) %d


assistant: ```c
int showHistogram(int *histogram) {
  int i;
  for (i = 0; i < 93; i++) {
    printf("%02d (%c) %d\n", i, i + '!', histogram[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isRot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x88(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x88(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x78(%rbp)
  cmpq   $0x0,-0x78(%rbp)
  je     L23
  mov    $0x1,%eax
  jmp    L1
L23:
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: new modified string is :%s, will find substring %s 


assistant: ```c
int isRot(char *s1, char *s2) {
  char *substr = NULL;
  char temp[100] = {0};
  strcpy(temp, s1);
  strcat(temp, s1);
  printf("new modified string is :%s, will find substring %s \n", temp, s2);
  substr = strstr(temp, s2);
  if (substr) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isRot>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  movzbl %al,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: new modified string is :%s, will find substring %s 


assistant: ```c
int isRot(char *s1, char *s2) {
  char *substr = NULL;
  char temp[100] = {0};
  strcpy(temp, s1);
  strcat(temp, s1);
  printf("new modified string is :%s, will find substring %s \n", temp, s2);
  substr = strstr(temp, s2);
  if (substr) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isRot>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x70,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2: new modified string is :%s, will find substring %s 


assistant: ```c
int isRot(char *s1, char *s2) {
  char *substr = NULL;
  char temp[100] = {0};
  strcpy(temp, s1);
  strcat(temp, s1);
  printf("new modified string is :%s, will find substring %s \n", temp, s2);
  substr = strstr(temp, s2);
  if (substr) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isRot>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x70,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: new modified string is :%s, will find substring %s 


assistant: ```c
int isRot(char *s1, char *s2) {
  char *substr = NULL;
  char temp[100] = {0};
  strcpy(temp, s1);
  strcat(temp, s1);
  printf("new modified string is :%s, will find substring %s \n", temp, s2);
  substr = strstr(temp, s2);
  if (substr) {
    return 1;
  } else {
    return 0;
  }
}
```