ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<test21>:
  endbr64
  cmp    %esi,%edi
  sete   %al
  movzbl %al,%eax
  cmp    $0x1,%edx
  adc    $0x0,%eax
  ret
```

assistant: ```c
int test21(int a, int b, int c, int d) {
  int x = a == b;
  int y = c == 0;
  return x + y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test21>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  sete   %al
  cmp    $0x1,%edx
  adc    $0x0,%eax
  ret
```

assistant: ```c
int test21(int a, int b, int c, int d) {
  int x = a == b;
  int y = c == 0;
  return x + y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test21>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  sete   %al
  cmp    $0x1,%edx
  adc    $0x0,%eax
  ret
```

assistant: ```c
int test21(int a, int b, int c, int d) {
  int x = a == b;
  int y = c == 0;
  return x + y;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xc3000(%rsp),%r11
L30:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L30
  sub    $0x580,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc3578(%rbp),%rdx
  lea    -0xc3580(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0xc3550(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc3550(%rbp),%rax
  mov    %rax,-0xc3568(%rbp)
  mov    -0xc3550(%rbp),%rax
  mov    %rax,-0xc3560(%rbp)
  movq   $0x1,-0xc3558(%rbp)
  jmp    L80
L79:
  lea    -0xc3550(%rbp),%rdx
  mov    -0xc3558(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc3558(%rbp),%rax
  mov    -0xc3550(%rbp,%rax,8),%rdx
  mov    -0xc3568(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <max@plt>
  mov    %rax,-0xc3568(%rbp)
  mov    -0xc3558(%rbp),%rax
  mov    -0xc3550(%rbp,%rax,8),%rdx
  mov    -0xc3560(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <min@plt>
  mov    %rax,-0xc3560(%rbp)
  addq   $0x1,-0xc3558(%rbp)
L80:
  mov    -0xc3580(%rbp),%rax
  cmp    %rax,-0xc3558(%rbp)
  jl     L79
  jmp    L57
L89:
  lea    -0xc3570(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc3570(%rbp),%rax
  cmp    %rax,-0xc3560(%rbp)
  jg     L52
  mov    -0xc3570(%rbp),%rax
  cmp    %rax,-0xc3568(%rbp)
  jl     L52
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L57
L52:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L57:
  mov    -0xc3578(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0xc3578(%rbp)
  test   %rax,%rax
  jne    L89
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
type_infered: string
name: retrieve_data
arguments: label: D44
type_infered: string
name: retrieve_data
arguments: label: D51
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string

tool: D18: %lld%lld

tool: D44: %lld

tool: D51: Yes


tool: D6: No


assistant: ```c
int main(void) {
  long long int n, q, ar[100009], ma, mi, i, t;
  scanf("%lld%lld", &n, &q);
  scanf("%lld", &ar[0]);
  ma = ar[0];
  mi = ar[0];
  for (i = 1; i < n; i++) {
    scanf("%lld", &ar[i]);
    ma = max(ma, ar[i]);
    mi = min(mi, ar[i]);
  }
  while (q--) {
    scanf("%lld", &t);
    if (t >= mi && t <= ma)
      printf("Yes\n");
    else
      printf("No\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0x578,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc3568(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  lea    0x20(%rsp),%rsi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x20(%rsp),%rbx
  cmpq   $0x1,0x8(%rsp)
  jle    L66
  lea    0x28(%rsp),%rbp
  mov    %rbx,%r12
  mov    $0x1,%r13d
  lea    D47(%rip),%r14
L44:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x0(%rbp),%rsi
  mov    %rbx,%rdi
  call   <max@plt>
  mov    %rax,%rbx
  mov    0x0(%rbp),%rsi
  mov    %r12,%rdi
  call   <min@plt>
  mov    %rax,%r12
  add    $0x1,%r13
  add    $0x8,%rbp
  cmp    %r13,0x8(%rsp)
  jg     L44
L25:
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L17
  lea    0x18(%rsp),%r13
  lea    D47(%rip),%rbp
  lea    D14(%rip),%r14
  lea    D46(%rip),%r15
  jmp    L50
L66:
  mov    %rbx,%r12
  jmp    L25
L12:
  mov    %r14,%rdi
  call   <printf@plt>
L72:
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L17
L50:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  cmp    %rbx,%rax
  jg     L12
  cmp    %r12,%rax
  jl     L12
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L72
L17:
  mov    0xc3568(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0xc3578,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D47
type: string
name: unpack_data
arguments: data_tag: D14
type: string
name: unpack_data
arguments: data_tag: D46
type: string

tool: D6: %lld%lld

tool: D47: %lld

tool: D14: No


tool: D46: Yes


assistant: ```c
int main(void) {
  long long int n, q, ar[100009], ma, mi, i, t;
  scanf("%lld%lld", &n, &q);
  scanf("%lld", &ar[0]);
  ma = ar[0];
  mi = ar[0];
  for (i = 1; i < n; i++) {
    scanf("%lld", &ar[i]);
    ma = max(ma, ar[i]);
    mi = min(mi, ar[i]);
  }
  while (q--) {
    scanf("%lld", &t);
    if (t >= mi && t <= ma)
      printf("Yes\n");
    else
      printf("No\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L41:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L41
  sub    $0x578,%rsp
  lea    D9(%rip),%rdi
  lea    D11(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0xc3568(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmpq   $0x1,0x8(%rsp)
  mov    0x20(%rsp),%rbp
  jle    L9
  lea    0x28(%rsp),%rbx
  mov    %rbp,%r12
  mov    $0x1,%r13d
  nopl   0x0(%rax)
L58:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <scanf@plt>
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <max@plt>
  mov    -0x8(%rbx),%rsi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <min@plt>
  mov    %rax,%r12
  cmp    %r13,0x8(%rsp)
  jg     L58
L71:
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L20
  lea    0x18(%rsp),%rbx
  lea    D31(%rip),%r13
  lea    D0(%rip),%r15
  jmp    L98
  nopl   0x0(%rax)
L63:
  mov    %r13,%rdi
  call   <printf@plt>
L39:
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L20
L98:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  cmp    %rbp,%rax
  jg     L63
  cmp    %r12,%rax
  jl     L63
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L39
  nopl   0x0(%rax)
L20:
  mov    0xc3568(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xc3578,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    %rbp,%r12
  jmp    L71
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D31
type_guessed: string
name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D9: %lld%lld

tool: D11: %lld

tool: D31: No


tool: D0: Yes


assistant: ```c
int main(void) {
  long long int n, q, ar[100009], ma, mi, i, t;
  scanf("%lld%lld", &n, &q);
  scanf("%lld", &ar[0]);
  ma = ar[0];
  mi = ar[0];
  for (i = 1; i < n; i++) {
    scanf("%lld", &ar[i]);
    ma = max(ma, ar[i]);
    mi = min(mi, ar[i]);
  }
  while (q--) {
    scanf("%lld", &t);
    if (t >= mi && t <= ma)
      printf("Yes\n");
    else
      printf("No\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L22:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L22
  sub    $0x578,%rsp
  lea    D9(%rip),%rdi
  lea    D36(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0xc3568(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmpq   $0x1,0x8(%rsp)
  mov    0x20(%rsp),%rbp
  jle    L38
  lea    0x28(%rsp),%rbx
  mov    %rbp,%r12
  mov    $0x1,%r13d
  nopl   0x0(%rax)
L34:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <scanf@plt>
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <max@plt>
  mov    -0x8(%rbx),%rsi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <min@plt>
  mov    %rax,%r12
  cmp    %r13,0x8(%rsp)
  jg     L34
L53:
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L51
  lea    0x18(%rsp),%rbx
  lea    D33(%rip),%r13
  lea    D17(%rip),%r15
  nop
L32:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  cmp    %rbp,%rax
  jg     L26
  mov    %r15,%rdi
  cmp    %r12,%rax
  jge    L77
L26:
  mov    %r13,%rdi
L77:
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L32
L51:
  mov    0xc3568(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0xc3578,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  mov    %rbp,%r12
  jmp    L53
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string
name: retrieve_data
arguments: tag: D36
datatype: string
name: retrieve_data
arguments: tag: D33
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D9: %lld%lld

tool: D36: %lld

tool: D33: No


tool: D17: Yes


assistant: ```c
int main(void) {
  long long int n, q, ar[100009], ma, mi, i, t;
  scanf("%lld%lld", &n, &q);
  scanf("%lld", &ar[0]);
  ma = ar[0];
  mi = ar[0];
  for (i = 1; i < n; i++) {
    scanf("%lld", &ar[i]);
    ma = max(ma, ar[i]);
    mi = min(mi, ar[i]);
  }
  while (q--) {
    scanf("%lld", &t);
    if (t >= mi && t <= ma)
      printf("Yes\n");
    else
      printf("No\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bin2oct>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r15
  mov    $0x0,%r14d
  mov    $0x0,%ebx
  lea    D6(%rip),%r13
  jmp    L130
L144:
  cmp    $0x72,%eax
  mov    $0x1,%eax
  cmove  %eax,%ebx
L130:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <getopt@plt>
  cmp    $0xffffffff,%eax
  je     L31
  cmp    $0x68,%eax
  jne    L144
  mov    $0x1,%r14d
  jmp    L130
L31:
  test   %r14d,%r14d
  jne    L123
  test   %ebx,%ebx
  je     L115
  cmp    $0x2,%r12d
  jle    L83
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L83:
  mov    %r15,%rdi
  call   <noArgument@plt>
  cmp    $0x2,%r12d
  jne    L78
L20:
  mov    $0x1,%r13d
  lea    D33(%rip),%r14
  jmp    L99
L115:
  cmp    $0x1,%r12d
  jle    L22
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L22:
  mov    %r15,%rdi
  call   <noArgument@plt>
L78:
  lea    D1(%rip),%rdi
  call   <printf@plt>
L90:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L81:
  mov    0x0(%rbp,%r13,8),%rdi
  mov    $0x8,%edx
  mov    $0x2,%esi
  call   <convertBase@plt>
L164:
  add    $0x1,%r13
  cmp    %r13d,%r12d
  jle    L78
L99:
  test   %ebx,%ebx
  je     L81
  mov    0x0(%rbp,%r13,8),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L164
  mov    0x0(%rbp,%r13,8),%rdi
  mov    $0x2,%edx
  mov    $0x8,%esi
  call   <convertBase@plt>
  jmp    L164
L123:
  mov    %r15,%rdi
  call   <showUsage@plt>
  jmp    L90
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D14
datatype: string
name: disassemble_data
arguments: label: D33
datatype: string
name: disassemble_data
arguments: label: D28
datatype: string
name: disassemble_data
arguments: label: D1
datatype: string

tool: D6: rh

tool: D14: BIN: 

tool: D33: -r

tool: D28: OCT: 

tool: D1: 


assistant: ```c
void bin2oct(int argc, char **argv, char *applet) {
  int opt = 0;
  bool reverse = false;
  bool pr_help = false;
  while ((opt = getopt(argc, argv, "rh")) != -1) {
    switch (opt) {
    case 'r':
      reverse = true;
      break;
    case 'h':
      pr_help = true;
      break;
    }
  }
  if (!pr_help) {
    if (reverse) {
      if (argc > 2) {
        printf("BIN: ");
      } else {
        noArgument(applet);
      }
    } else {
      if (argc > 1) {
        printf("OCT: ");
      } else {
        noArgument(applet);
      }
    }
    for (int i = 1; i < argc; i++) {
      if (reverse) {
        if (strcmp(argv[i], "-r") == 0) {
          continue;
        }
        convertBase(argv[i], 8, 2);
      } else {
        convertBase(argv[i], 2, 8);
      }
    }
    printf("\n");
  } else {
    showUsage(applet);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bin2oct>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  jmp    L69
  nopl   0x0(%rax)
L78:
  cmp    $0x72,%eax
  cmove  %r14d,%ebx
L69:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <getopt@plt>
  cmp    $0xffffffff,%eax
  je     L109
  cmp    $0x68,%eax
  jne    L78
  mov    $0x1,%r15d
  jmp    L69
  nop
L109:
  test   %r15d,%r15d
  jne    L135
  test   %ebx,%ebx
  je     L77
  cmp    $0x2,%r12d
  jle    L3
  lea    D37(%rip),%rdi
  call   <printf@plt>
  jmp    L89
  nopl   (%rax)
L77:
  cmp    $0x1,%r12d
  jle    L49
  lea    D14(%rip),%rdi
  call   <printf@plt>
L89:
  mov    $0x1,%r13d
  lea    D19(%rip),%r14
  jmp    L27
  nopl   (%rax)
L13:
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L20
  mov    0x0(%rbp,%r13,8),%rdi
  mov    $0x2,%edx
  mov    $0x8,%esi
  call   <convertBase@plt>
L20:
  add    $0x1,%r13
  cmp    %r13d,%r12d
  jle    L139
L27:
  mov    0x0(%rbp,%r13,8),%rdi
  test   %ebx,%ebx
  jne    L13
  mov    $0x8,%edx
  mov    $0x2,%esi
  call   <convertBase@plt>
  jmp    L20
  nopl   0x0(%rax)
L135:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <showUsage@plt>
L3:
  mov    0x8(%rsp),%rdi
  call   <noArgument@plt>
  cmp    $0x2,%r12d
  je     L89
  jmp    L139
  cs nopw 0x0(%rax,%rax,1)
L49:
  mov    0x8(%rsp),%rdi
  call   <noArgument@plt>
L139:
  add    $0x18,%rsp
  lea    D35(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
datatype: string
name: extract_symbolic_data
arguments: label: D37
datatype: string
name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string
name: extract_symbolic_data
arguments: label: D35
datatype: string

tool: D29: rh

tool: D37: BIN: 

tool: D14: OCT: 

tool: D19: -r

tool: D35: 


assistant: ```c
void bin2oct(int argc, char **argv, char *applet) {
  int opt = 0;
  bool reverse = false;
  bool pr_help = false;
  while ((opt = getopt(argc, argv, "rh")) != -1) {
    switch (opt) {
    case 'r':
      reverse = true;
      break;
    case 'h':
      pr_help = true;
      break;
    }
  }
  if (!pr_help) {
    if (reverse) {
      if (argc > 2) {
        printf("BIN: ");
      } else {
        noArgument(applet);
      }
    } else {
      if (argc > 1) {
        printf("OCT: ");
      } else {
        noArgument(applet);
      }
    }
    for (int i = 1; i < argc; i++) {
      if (reverse) {
        if (strcmp(argv[i], "-r") == 0) {
          continue;
        }
        convertBase(argv[i], 8, 2);
      } else {
        convertBase(argv[i], 2, 8);
      }
    }
    printf("\n");
  } else {
    showUsage(applet);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bin2oct>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  jmp    L145
  nopl   0x0(%rax)
L83:
  cmp    $0x72,%eax
  cmove  %r14d,%r12d
L145:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <getopt@plt>
  cmp    $0xffffffff,%eax
  je     L112
  cmp    $0x68,%eax
  jne    L83
  mov    $0x1,%r15d
  jmp    L145
  xchg   %ax,%ax
L112:
  test   %r15d,%r15d
  jne    L25
  test   %r12d,%r12d
  je     L47
  cmp    $0x2,%ebx
  jg     L144
  mov    0x8(%rsp),%rdi
  call   <noArgument@plt>
  cmp    $0x2,%ebx
  jne    L42
L54:
  mov    $0x1,%r12d
  lea    D34(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L78:
  mov    0x0(%rbp,%r12,8),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
  mov    0x0(%rbp,%r12,8),%rdi
  mov    $0x2,%edx
  mov    $0x8,%esi
  call   <convertBase@plt>
L11:
  add    $0x1,%r12
  cmp    %r12d,%ebx
  jg     L78
L42:
  add    $0x18,%rsp
  lea    D23(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
L47:
  cmp    $0x1,%ebx
  jle    L49
  lea    D46(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
  nop
L137:
  mov    0x0(%rbp,%r12,8),%rdi
  mov    $0x8,%edx
  mov    $0x2,%esi
  add    $0x1,%r12
  call   <convertBase@plt>
  cmp    %r12d,%ebx
  jg     L137
  jmp    L42
  nop
L25:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <showUsage@plt>
  nopl   0x0(%rax,%rax,1)
L144:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  nopl   0x0(%rax)
L49:
  mov    0x8(%rsp),%rdi
  call   <noArgument@plt>
  jmp    L42
```

tool_calls: name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D23
type_guessed: string
name: parse_data
arguments: data_tag: D46
type_guessed: string
name: parse_data
arguments: data_tag: D28
type_guessed: string

tool: D29: rh

tool: D34: -r

tool: D23: 


tool: D46: OCT: 

tool: D28: BIN: 

assistant: ```c
void bin2oct(int argc, char **argv, char *applet) {
  int opt = 0;
  bool reverse = false;
  bool pr_help = false;
  while ((opt = getopt(argc, argv, "rh")) != -1) {
    switch (opt) {
    case 'r':
      reverse = true;
      break;
    case 'h':
      pr_help = true;
      break;
    }
  }
  if (!pr_help) {
    if (reverse) {
      if (argc > 2) {
        printf("BIN: ");
      } else {
        noArgument(applet);
      }
    } else {
      if (argc > 1) {
        printf("OCT: ");
      } else {
        noArgument(applet);
      }
    }
    for (int i = 1; i < argc; i++) {
      if (reverse) {
        if (strcmp(argv[i], "-r") == 0) {
          continue;
        }
        convertBase(argv[i], 8, 2);
      } else {
        convertBase(argv[i], 2, 8);
      }
    }
    printf("\n");
  } else {
    showUsage(applet);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hammingDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L14:
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  and    $0x1,%eax
  add    %eax,-0x8(%rbp)
  sarl   -0x14(%rbp)
  sarl   -0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L14
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hammingDistance(int x, int y) {
  int diff = 0;
  for (int i = 0; i < 32; i++) {
    diff += ((x & 1) ^ (y & 1));
    x >>= 1;
    y >>= 1;
  }
  return diff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hammingDistance>:
  endbr64
  mov    $0x20,%edx
  mov    $0x0,%ecx
L0:
  mov    %edi,%eax
  xor    %esi,%eax
  and    $0x1,%eax
  add    %eax,%ecx
  sar    %edi
  sar    %esi
  sub    $0x1,%edx
  jne    L0
  mov    %ecx,%eax
  ret
```

assistant: ```c
int hammingDistance(int x, int y) {
  int diff = 0;
  for (int i = 0; i < 32; i++) {
    diff += ((x & 1) ^ (y & 1));
    x >>= 1;
    y >>= 1;
  }
  return diff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hammingDistance>:
  endbr64
  mov    $0x20,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L1:
  mov    %edi,%eax
  sar    %edi
  xor    %esi,%eax
  sar    %esi
  and    $0x1,%eax
  add    %eax,%r8d
  sub    $0x1,%edx
  jne    L1
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hammingDistance(int x, int y) {
  int diff = 0;
  for (int i = 0; i < 32; i++) {
    diff += ((x & 1) ^ (y & 1));
    x >>= 1;
    y >>= 1;
  }
  return diff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hammingDistance>:
  endbr64
  mov    $0x20,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L2:
  mov    %edi,%eax
  sar    %edi
  xor    %esi,%eax
  sar    %esi
  and    $0x1,%eax
  add    %eax,%r8d
  sub    $0x1,%edx
  jne    L2
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hammingDistance(int x, int y) {
  int diff = 0;
  for (int i = 0; i < 32; i++) {
    diff += ((x & 1) ^ (y & 1));
    x >>= 1;
    y >>= 1;
  }
  return diff;
}
```