user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  lea    0x48(%rsp),%rbp
  mov    %rax,0x28(%rsp)
  nopl   0x0(%rax)
L2:
  lea    -0x18(%rbp),%rbx
  nopl   0x0(%rax)
L1:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %rbp,%rbx
  jne    L1
  add    $0x6,%r13
  lea    0x18(%rbx),%rbp
  cmp    $0x24,%r13
  jne    L2
  movl   $0x2,0x1c(%rsp)
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  movl   $0x0,0x14(%rsp)
L128:
  lea    0x3(%r14,%r14,1),%eax
  mov    0x28(%rsp),%rdx
  mov    %r14d,%ebp
  xor    %ebx,%ebx
  sar    %eax
  mov    0x14(%rsp),%r15d
  add    $0x1,%r14d
  add    $0x4,%ebp
  cltq
  mov    %rdx,%r11
  add    $0x18,%rdx
  mov    %r14d,0x18(%rsp)
  lea    (%rax,%rax,2),%rax
  mov    %rdx,0x28(%rsp)
  mov    %r14d,%ecx
  mov    %r15d,%r9d
  add    %rax,%rax
  mov    %ebp,%r14d
  mov    %r11,%r15
  mov    %rdx,%rbp
  mov    %rax,0x20(%rsp)
L98:
  cmp    0x14(%rsp),%ebx
  je     L108
  xor    %eax,%eax
  cmp    %r9d,%r14d
  je     L56
L59:
  cmp    0x18(%rsp),%ebx
  je     L57
  cmp    %ecx,%r14d
  je     L57
L12:
  cmp    %ebx,0x1c(%rsp)
  jne    L105
  mov    0x68(%rsp),%esi
  lea    (%rax,%rsi,2),%eax
  add    %esi,%eax
L105:
  lea    0x3(%rbx,%rbx,1),%esi
  lea    D10(%rip),%rdi
  mov    %ecx,0x10(%rsp)
  sar    %esi
  mov    %r9d,0xc(%rsp)
  movslq %esi,%rsi
  add    0x20(%rsp),%rsi
  sub    0x30(%rsp,%rsi,4),%eax
  mov    %eax,%esi
  mov    %eax,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%r9d
  cmp    %esi,%r13d
  cmovl  %esi,%r13d
  add    $0x1,%ebx
  add    $0x1,%ecx
  add    $0x1,%r9d
  add    $0x1,%r14d
  add    $0x4,%r15
  add    $0x4,%rbp
  cmp    $0x3,%ebx
  jne    L98
  mov    0x18(%rsp),%r14d
  addl   $0x1,0x14(%rsp)
  addl   $0x1,0x1c(%rsp)
  cmp    $0x3,%r14d
  jne    L128
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L125
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L57:
  mov    0x0(%rbp),%esi
  lea    (%rax,%rsi,2),%eax
  add    %esi,%eax
  jmp    L12
  nopl   (%rax)
L56:
  mov    (%r15),%eax
  mov    %eax,%esi
  add    %eax,%eax
  add    %esi,%eax
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L108:
  mov    (%r15),%esi
  lea    (%rsi,%rsi,1),%eax
  add    %esi,%eax
  jmp    L59
L125:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string
name: parse_data
arguments: tag: D10
data_type: string

tool: D2: %d

tool: D10: Block sum = %d


assistant: ```c
int main() {
  int arr[6][6];
  int i, j, k, kmax, l, lmax, maxSum = 0, currentSum = 0, maxer;
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6; j++) {
      scanf("%d", &arr[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      currentSum = 0;
      kmax = i + 3;
      lmax = j + 3;
      maxer = (kmax - 1) + (lmax - 1);
      for (k = i; k < kmax; k++) {
        for (l = j; l < lmax; l++) {
          if (k == j || k + j == maxer) {
            currentSum += arr[k][j];
          }
        }
      }
      currentSum -= arr[(i + kmax) / 2][(j + lmax) / 2];
      printf("Block sum = %d\n", currentSum);
      if (currentSum > maxSum) {
        maxSum = currentSum;
      }
    }
  }
  printf("%d", maxSum);
  return 0;
}
```