ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L7
L16:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L11
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
L11:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int r;
  while ((r = *s1 - *s2) == 0 && *s1 != '\0') {
    s1++, s2++;
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl %dl,%eax
  movsbl (%rsi),%ecx
  sub    %ecx,%eax
  test   %dl,%dl
  je     L8
  test   %eax,%eax
  jne    L8
  mov    $0x1,%edx
L0:
  movzbl (%rdi,%rdx,1),%ecx
  movsbl %cl,%eax
  movsbl (%rsi,%rdx,1),%r8d
  sub    %r8d,%eax
  add    $0x1,%rdx
  test   %cl,%cl
  je     L8
  test   %eax,%eax
  je     L0
L8:
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int r;
  while ((r = *s1 - *s2) == 0 && *s1 != '\0') {
    s1++, s2++;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%ecx
  mov    $0x1,%edx
  mov    %eax,%r8d
  sub    %ecx,%eax
  je     L4
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L12:
  movsbl (%rdi,%rdx,1),%ecx
  movsbl (%rsi,%rdx,1),%r9d
  add    $0x1,%rdx
  mov    %ecx,%r8d
  sub    %r9d,%ecx
  jne    L28
L4:
  test   %r8b,%r8b
  jne    L12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %ecx,%eax
  ret
L9:
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int r;
  while ((r = *s1 - *s2) == 0 && *s1 != '\0') {
    s1++, s2++;
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%ecx
  mov    $0x1,%edx
  mov    %eax,%r8d
  sub    %ecx,%eax
  je     L15
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L23:
  movsbl (%rdi,%rdx,1),%ecx
  movsbl (%rsi,%rdx,1),%r9d
  add    $0x1,%rdx
  mov    %ecx,%r8d
  sub    %r9d,%ecx
  jne    L38
L15:
  test   %r8b,%r8b
  jne    L23
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %ecx,%eax
  ret
L2:
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int r;
  while ((r = *s1 - *s2) == 0 && *s1 != '\0') {
    s1++, s2++;
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edx
  mov    $0xde,%esi
  mov    $0x6f,%edi
  call   <f@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: 


assistant: ```c
void main(void) {
  int x;
  x = f(111, 222, 000);
  print_int(x);
  print_string("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0xde,%esi
  mov    $0x6f,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D3(%rip),%rdi
  call   <print_string@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: 


assistant: ```c
void main(void) {
  int x;
  x = f(111, 222, 000);
  print_int(x);
  print_string("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0xde,%esi
  mov    $0x6f,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <print_string@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: 


assistant: ```c
void main(void) {
  int x;
  x = f(111, 222, 000);
  print_int(x);
  print_string("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0xde,%esi
  mov    $0x6f,%edi
  call   <f@plt>
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <print_string@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: 


assistant: ```c
void main(void) {
  int x;
  x = f(111, 222, 000);
  print_int(x);
  print_string("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L7
L13:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L7:
  cmpl   $0x1,-0x14(%rbp)
  jg     L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int factorial(int n) {
  int r;
  for (r = 1; n > 1; r *= (n--))
    ;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<factorial>:
  endbr64
  cmp    $0x1,%edi
  jle    L4
  mov    $0x1,%eax
L0:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L0
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int factorial(int n) {
  int r;
  for (r = 1; n > 1; r *= (n--))
    ;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L1
  xchg   %ax,%ax
L4:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L4
  ret
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
int factorial(int n) {
  int r;
  for (r = 1; n > 1; r *= (n--))
    ;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L2
  xchg   %ax,%ax
L8:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L8
  ret
  xchg   %ax,%ax
L2:
  ret
```

assistant: ```c
int factorial(int n) {
  int r;
  for (r = 1; n > 1; r *= (n--))
    ;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parsestring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L20
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L96
L20:
  movl   $0x1,-0x14(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L96
L56:
  cmpl   $0x0,-0x14(%rbp)
  jne    L76
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L100
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L100
L76:
  cmpl   $0x0,-0x14(%rbp)
  je     L77
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L77
  addq   $0x1,-0x28(%rbp)
  jmp    L100
L77:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L53
  cmpb   $0x60,-0x15(%rbp)
  jle    L53
  cmpb   $0x7a,-0x15(%rbp)
  jg     L53
  movzbl -0x15(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x15(%rbp)
L53:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl -0x15(%rbp),%edx
  mov    %dl,(%rax)
L96:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
L100:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x40(%rbp)
  je     L49
  mov    -0x40(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
L49:
  mov    -0x30(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *parsestring(char *srcptr, char *dest, int nlen, char **nextptr) {
  char *s = srcptr;
  char *d = dest;
  int nInString = 0;
  char c;
  if (*srcptr == '\'' || *srcptr == '\"') {
    nInString = 1;
    srcptr++;
  }
  while (*srcptr) {
    if (!nInString && (*srcptr == ' ' || *srcptr == ','))
      break;
    else if (nInString && *s == *srcptr) {
      srcptr++;
      break;
    }
    c = *srcptr++;
    if (!nInString && c >= 'a' && c <= 'z')
      c -= 32;
    *d++ = c;
  }
  *d = '\0';
  if (nextptr)
    *nextptr = srcptr;
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parsestring>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x27,%al
  je     L138
  mov    %rdi,%r9
  mov    $0x0,%r11d
  cmp    $0x22,%al
  je     L138
L72:
  movzbl (%r9),%edx
  lea    0x1(%r9),%r8
  mov    %rsi,%r10
  test   %dl,%dl
  je     L66
  push   %rbx
  jmp    L81
L138:
  lea    0x1(%rdi),%r9
  mov    $0x1,%r11d
  jmp    L72
L79:
  cmp    %dl,(%rdi)
  je     L14
  mov    %r8,%r9
  jmp    L40
L14:
  add    $0x1,%r9
L78:
  movb   $0x0,(%r10)
  test   %rcx,%rcx
  je     L85
  mov    %r9,(%rcx)
L85:
  mov    %rsi,%rax
  pop    %rbx
  ret
L110:
  mov    %r8,%r9
  lea    -0x61(%rdx),%ebx
  lea    -0x20(%rdx),%eax
  cmp    $0x1a,%bl
  cmovb  %eax,%edx
L40:
  add    $0x1,%r10
  mov    %dl,-0x1(%r10)
  movzbl (%r9),%edx
  add    $0x1,%r8
  test   %dl,%dl
  je     L78
L81:
  lea    -0x1(%r8),%r9
  test   %r11d,%r11d
  jne    L79
  cmp    $0x20,%dl
  je     L78
  cmp    $0x2c,%dl
  jne    L110
  jmp    L78
L66:
  movb   $0x0,(%rsi)
  test   %rcx,%rcx
  je     L39
  mov    %r9,(%rcx)
L39:
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *parsestring(char *srcptr, char *dest, int nlen, char **nextptr) {
  char *s = srcptr;
  char *d = dest;
  int nInString = 0;
  char c;
  if (*srcptr == '\'' || *srcptr == '\"') {
    nInString = 1;
    srcptr++;
  }
  while (*srcptr) {
    if (!nInString && (*srcptr == ' ' || *srcptr == ','))
      break;
    else if (nInString && *s == *srcptr) {
      srcptr++;
      break;
    }
    c = *srcptr++;
    if (!nInString && c >= 'a' && c <= 'z')
      c -= 32;
    *d++ = c;
  }
  *d = '\0';
  if (nextptr)
    *nextptr = srcptr;
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parsestring>:
  endbr64
  movzbl (%rdi),%edx
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  cmp    $0x27,%dl
  je     L4
  mov    %rdi,%r10
  xor    %r11d,%r11d
  cmp    $0x22,%dl
  je     L4
L9:
  lea    0x1(%r10),%r8
  mov    %r12,%r9
  test   %dl,%dl
  jne    L22
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L23:
  cmp    $0x20,%dl
  je     L3
  cmp    $0x2c,%dl
  je     L3
  lea    -0x61(%rdx),%ebx
  lea    -0x20(%rdx),%eax
  mov    %r8,%r10
  cmp    $0x1a,%bl
  cmovb  %eax,%edx
L84:
  mov    %dl,(%r9)
  movzbl (%r8),%edx
  add    $0x1,%r9
  add    $0x1,%r8
  test   %dl,%dl
  je     L3
L22:
  lea    -0x1(%r8),%r10
  test   %r11d,%r11d
  je     L23
  mov    %r8,%r10
  cmp    %dl,(%rdi)
  jne    L84
L3:
  movb   $0x0,(%r9)
  test   %rcx,%rcx
  je     L43
  mov    %r10,(%rcx)
L43:
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L4:
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%r10
  mov    $0x1,%r11d
  jmp    L9
```

assistant: ```c
char *parsestring(char *srcptr, char *dest, int nlen, char **nextptr) {
  char *s = srcptr;
  char *d = dest;
  int nInString = 0;
  char c;
  if (*srcptr == '\'' || *srcptr == '\"') {
    nInString = 1;
    srcptr++;
  }
  while (*srcptr) {
    if (!nInString && (*srcptr == ' ' || *srcptr == ','))
      break;
    else if (nInString && *s == *srcptr) {
      srcptr++;
      break;
    }
    c = *srcptr++;
    if (!nInString && c >= 'a' && c <= 'z')
      c -= 32;
    *d++ = c;
  }
  *d = '\0';
  if (nextptr)
    *nextptr = srcptr;
  return dest;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parsestring>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  cmp    $0x27,%dl
  je     L57
  cmp    $0x22,%dl
  je     L57
  mov    %rsi,%r8
  test   %dl,%dl
  je     L63
  nopl   0x0(%rax,%rax,1)
L61:
  cmp    $0x20,%dl
  je     L63
  cmp    $0x2c,%dl
  je     L63
  lea    -0x61(%rdx),%r9d
  add    $0x1,%rdi
  add    $0x1,%r8
  cmp    $0x19,%r9b
  ja     L78
  sub    $0x20,%edx
  mov    %dl,-0x1(%r8)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L61
  nopw   0x0(%rax,%rax,1)
L63:
  movb   $0x0,(%r8)
  test   %rcx,%rcx
  je     L40
  mov    %rdi,(%rcx)
L40:
  ret
  nopl   (%rax)
L78:
  mov    %dl,-0x1(%r8)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L61
  jmp    L63
  nopl   (%rax)
L57:
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%r9
  mov    %rax,%r8
  test   %dl,%dl
  jne    L29
  nop
L68:
  mov    %r9,%rdi
  jmp    L63
  nopl   (%rax)
L113:
  mov    %dl,(%r8)
  movzbl (%r9),%edx
  add    $0x1,%r8
  test   %dl,%dl
  je     L68
L29:
  add    $0x1,%r9
  cmp    (%rdi),%dl
  jne    L113
  mov    %r9,%rdi
  jmp    L63
```

assistant: ```c
char *parsestring(char *srcptr, char *dest, int nlen, char **nextptr) {
  char *s = srcptr;
  char *d = dest;
  int nInString = 0;
  char c;
  if (*srcptr == '\'' || *srcptr == '\"') {
    nInString = 1;
    srcptr++;
  }
  while (*srcptr) {
    if (!nInString && (*srcptr == ' ' || *srcptr == ','))
      break;
    else if (nInString && *s == *srcptr) {
      srcptr++;
      break;
    }
    c = *srcptr++;
    if (!nInString && c >= 'a' && c <= 'z')
      c -= 32;
    *d++ = c;
  }
  *d = '\0';
  if (nextptr)
    *nextptr = srcptr;
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<can_direct_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xdff00000,%eax
  cmp    $0x200000,%eax
  jne    L21
  mov    $0x1,%eax
  jmp    L55
L21:
  mov    -0x4(%rbp),%eax
  and    $0xde000000,%eax
  cmp    $0x6000000,%eax
  jne    L16
  mov    $0x1,%eax
  jmp    L55
L16:
  mov    -0x4(%rbp),%eax
  and    $0xdff00000,%eax
  test   %eax,%eax
  jne    L23
  mov    $0x1,%eax
  jmp    L55
L23:
  mov    $0x0,%eax
L55:
  pop    %rbp
  ret
```

assistant: ```c
int can_direct_read(int address) {
  if ((address & 0xDFF00000) == 0x200000)
    return 1;
  if ((address & 0xDE000000) == 0x6000000)
    return 1;
  if ((address & 0xDFF00000) == 0)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<can_direct_read>:
  endbr64
  mov    %edi,%eax
  and    $0xde000000,%eax
  cmp    $0x6000000,%eax
  sete   %al
  test   $0xdfd00000,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int can_direct_read(int address) {
  if ((address & 0xDFF00000) == 0x200000)
    return 1;
  if ((address & 0xDE000000) == 0x6000000)
    return 1;
  if ((address & 0xDFF00000) == 0)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<can_direct_read>:
  endbr64
  mov    %edi,%eax
  and    $0xde000000,%eax
  cmp    $0x6000000,%eax
  sete   %al
  and    $0xdfd00000,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int can_direct_read(int address) {
  if ((address & 0xDFF00000) == 0x200000)
    return 1;
  if ((address & 0xDE000000) == 0x6000000)
    return 1;
  if ((address & 0xDFF00000) == 0)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<can_direct_read>:
  endbr64
  mov    %edi,%eax
  and    $0xde000000,%eax
  cmp    $0x6000000,%eax
  sete   %al
  and    $0xdfd00000,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int can_direct_read(int address) {
  if ((address & 0xDFF00000) == 0x200000)
    return 1;
  if ((address & 0xDE000000) == 0x6000000)
    return 1;
  if ((address & 0xDFF00000) == 0)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<optcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L5
L56:
  mov    -0x40(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x30(%rbp)
  movl   $0x1,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jl     L15
  jmp    L22
L59:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L22
  movl   $0x0,-0x28(%rbp)
L22:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L102
  cmpl   $0x0,-0x28(%rbp)
  jne    L59
  jmp    L102
L15:
  movl   $0x0,-0x28(%rbp)
L102:
  cmpl   $0x0,-0x28(%rbp)
  je     L5
  addl   $0x1,-0x24(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
L5:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  cmpl   $0x1,-0x24(%rbp)
  jle    L76
  mov    $0xffffffff,%eax
  jmp    L78
L76:
  mov    -0x2c(%rbp),%eax
L78:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int optcmp(char *wrdptr, char **optionpp) {
  char *optptr, *wptr;
  int i = 0, index = 0, consistent, match = 0;
  while (**optionpp) {
    optptr = *optionpp++;
    wptr = wrdptr;
    i++;
    consistent = 1;
    if ((int)strlen(optptr) >= (int)strlen(wptr))
      while (*wptr && consistent) {
        if (*wptr++ != *optptr++)
          consistent = 0;
      }
    else
      consistent = 0;
    if (consistent) {
      match++;
      index = i;
    }
  }
  if (match > 1)
    return (-1);
  else
    return (index);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<optcmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%rbx
  cmpb   $0x0,(%rbx)
  je     L81
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    $0x0,%r15d
  movl   $0x0,0xc(%rsp)
  mov    $0x0,%r13d
  jmp    L64
L60:
  add    $0x1,%rax
  movzbl (%r12,%rax,1),%edx
  test   %dl,%dl
  je     L35
L48:
  cmp    %dl,(%rbx,%rax,1)
  je     L60
L15:
  mov    0x0(%rbp),%rbx
  cmpb   $0x0,(%rbx)
  je     L4
L64:
  add    $0x8,%rbp
  add    $0x1,%r13d
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %eax,%r14d
  jg     L15
  movzbl (%r12),%edx
  test   %dl,%dl
  je     L35
  mov    $0x0,%eax
  jmp    L48
L35:
  add    $0x1,%r15d
  mov    %r13d,0xc(%rsp)
  jmp    L15
L4:
  cmp    $0x2,%r15d
  mov    $0xffffffff,%eax
  cmovl  0xc(%rsp),%eax
  mov    %eax,0xc(%rsp)
L9:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L81:
  movl   $0x0,0xc(%rsp)
  jmp    L9
```

assistant: ```c
int optcmp(char *wrdptr, char **optionpp) {
  char *optptr, *wptr;
  int i = 0, index = 0, consistent, match = 0;
  while (**optionpp) {
    optptr = *optionpp++;
    wptr = wrdptr;
    i++;
    consistent = 1;
    if ((int)strlen(optptr) >= (int)strlen(wptr))
      while (*wptr && consistent) {
        if (*wptr++ != *optptr++)
          consistent = 0;
      }
    else
      consistent = 0;
    if (consistent) {
      match++;
      index = i;
    }
  }
  if (match > 1)
    return (-1);
  else
    return (index);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<optcmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%rbx
  cmpb   $0x0,(%rbx)
  je     L16
  mov    %rdi,%r13
  mov    %rsi,%r15
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  call   <strlen@plt>
  movl   $0x0,0xc(%rsp)
  mov    %eax,%r12d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L77:
  mov    (%r15),%rbx
  cmpb   $0x0,(%rbx)
  je     L15
L12:
  mov    %rbx,%rdi
  add    $0x8,%r15
  add    $0x1,%ebp
  call   <strlen@plt>
  cmp    %eax,%r12d
  jg     L77
  mov    %r13,%rax
L3:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L73
  add    $0x1,%rbx
  add    $0x1,%rax
  cmp    %dl,-0x1(%rbx)
  je     L3
  mov    (%r15),%rbx
  cmpb   $0x0,(%rbx)
  jne    L12
L15:
  cmpl   $0x2,0xc(%rsp)
  mov    $0xffffffff,%eax
  cmovge %eax,%r14d
L86:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  addl   $0x1,0xc(%rsp)
  mov    %ebp,%r14d
  jmp    L77
L16:
  xor    %r14d,%r14d
  jmp    L86
```

assistant: ```c
int optcmp(char *wrdptr, char **optionpp) {
  char *optptr, *wptr;
  int i = 0, index = 0, consistent, match = 0;
  while (**optionpp) {
    optptr = *optionpp++;
    wptr = wrdptr;
    i++;
    consistent = 1;
    if ((int)strlen(optptr) >= (int)strlen(wptr))
      while (*wptr && consistent) {
        if (*wptr++ != *optptr++)
          consistent = 0;
      }
    else
      consistent = 0;
    if (consistent) {
      match++;
      index = i;
    }
  }
  if (match > 1)
    return (-1);
  else
    return (index);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<optcmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%rbx
  cmpb   $0x0,(%rbx)
  je     L87
  mov    %rdi,%r13
  mov    %rsi,%r15
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  call   <strlen@plt>
  movl   $0x0,0xc(%rsp)
  mov    %eax,%r12d
  jmp    L70
  nopl   0x0(%rax,%rax,1)
L86:
  mov    (%r15),%rbx
  cmpb   $0x0,(%rbx)
  je     L79
L70:
  mov    %rbx,%rdi
  add    $0x8,%r15
  add    $0x1,%ebp
  call   <strlen@plt>
  cmp    %eax,%r12d
  jg     L86
  mov    %r13,%rax
L88:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L41
  add    $0x1,%rbx
  add    $0x1,%rax
  cmp    %dl,-0x1(%rbx)
  je     L88
  mov    (%r15),%rbx
  cmpb   $0x0,(%rbx)
  jne    L70
L79:
  cmpl   $0x2,0xc(%rsp)
  mov    $0xffffffff,%eax
  cmovge %eax,%r14d
L35:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  addl   $0x1,0xc(%rsp)
  mov    %ebp,%r14d
  jmp    L86
L87:
  xor    %r14d,%r14d
  jmp    L35
```

assistant: ```c
int optcmp(char *wrdptr, char **optionpp) {
  char *optptr, *wptr;
  int i = 0, index = 0, consistent, match = 0;
  while (**optionpp) {
    optptr = *optionpp++;
    wptr = wrdptr;
    i++;
    consistent = 1;
    if ((int)strlen(optptr) >= (int)strlen(wptr))
      while (*wptr && consistent) {
        if (*wptr++ != *optptr++)
          consistent = 0;
      }
    else
      consistent = 0;
    if (consistent) {
      match++;
      index = i;
    }
  }
  if (match > 1)
    return (-1);
  else
    return (index);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mostra_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D1: %i


assistant: ```c
void mostra_int(void *info) {
  int *p = (int *)info;
  printf("%i\n", *p);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mostra_int>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: %i


assistant: ```c
void mostra_int(void *info) {
  int *p = (int *)info;
  printf("%i\n", *p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mostra_int>:
  endbr64
  mov    (%rdi),%esi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: %i


assistant: ```c
void mostra_int(void *info) {
  int *p = (int *)info;
  printf("%i\n", *p);
}
```