ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ftp_i_textfrombrackets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L64
L43:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  jne    L60
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L115
L60:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L115
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L115:
  addl   $0x1,-0xc(%rbp)
L64:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
  cmpl   $0xffffffff,-0x8(%rbp)
  je     L13
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L100
L13:
  mov    $0x64,%eax
  jmp    L14
L100:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L103
  mov    $0x64,%eax
  jmp    L14
L103:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jge    L53
  mov    $0x65,%eax
  jmp    L14
L53:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ftp_i_memcpy@plt>
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int ftp_i_textfrombrackets(char *server_answer, char *dest, int maxlen) {
  int i = 0, inbracket = -1, outbracket = -1;
  while (*(server_answer + i) != '\0') {
    if (*(server_answer + i) == '(')
      inbracket = i;
    else if (*(server_answer + i) == ')')
      outbracket = i;
    i++;
  }
  if (inbracket == -1 || outbracket == -1)
    return 100;
  if (inbracket >= outbracket)
    return 100;
  if (outbracket - inbracket > maxlen)
    return 101;
  do {
    ftp_i_memcpy(dest, server_answer, inbracket + 1, outbracket - inbracket - 1);
    *(dest + outbracket - inbracket - 1) = '\0';
  } while (0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ftp_i_textfrombrackets>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L41
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  mov    $0xffffffff,%ebx
  mov    $0xffffffff,%r12d
  jmp    L27
L19:
  mov    %eax,%r12d
L67:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L21
L27:
  cmp    $0x28,%cl
  je     L19
  cmp    $0x29,%cl
  cmove  %eax,%ebx
  jmp    L67
L21:
  cmp    $0xffffffff,%r12d
  sete   %al
  cmp    $0xffffffff,%ebx
  sete   %cl
  or     %cl,%al
  jne    L63
  cmp    %ebx,%r12d
  jge    L63
  mov    %ebx,%ecx
  sub    %r12d,%ecx
  mov    $0x65,%eax
  cmp    %edx,%ecx
  jg     L14
  sub    $0x1,%ecx
  lea    0x1(%r12),%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <ftp_i_memcpy@plt>
  movslq %ebx,%rbx
  movslq %r12d,%r12
  sub    $0x1,%rbx
  sub    %r12,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    $0x0,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    $0x64,%eax
  ret
L63:
  mov    $0x64,%eax
  jmp    L14
```

assistant: ```c
int ftp_i_textfrombrackets(char *server_answer, char *dest, int maxlen) {
  int i = 0, inbracket = -1, outbracket = -1;
  while (*(server_answer + i) != '\0') {
    if (*(server_answer + i) == '(')
      inbracket = i;
    else if (*(server_answer + i) == ')')
      outbracket = i;
    i++;
  }
  if (inbracket == -1 || outbracket == -1)
    return 100;
  if (inbracket >= outbracket)
    return 100;
  if (outbracket - inbracket > maxlen)
    return 101;
  do {
    ftp_i_memcpy(dest, server_answer, inbracket + 1, outbracket - inbracket - 1);
    *(dest + outbracket - inbracket - 1) = '\0';
  } while (0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ftp_i_textfrombrackets>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L47
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    $0xffffffffffffffff,%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  jmp    L69
  cs nopw 0x0(%rax,%rax,1)
L74:
  cmp    $0x29,%cl
  cmove  %eax,%ebx
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L30
L69:
  cmp    $0x28,%cl
  jne    L74
  movslq %eax,%rbp
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L69
L30:
  cmp    $0xffffffff,%ebp
  sete   %al
  cmp    $0xffffffff,%ebx
  sete   %cl
  or     %cl,%al
  jne    L50
  cmp    %ebx,%ebp
  jge    L50
  mov    %ebx,%ecx
  mov    $0x65,%eax
  sub    %ebp,%ecx
  cmp    %edx,%ecx
  jg     L43
  movslq %ebx,%rbx
  mov    %rdi,%rsi
  sub    $0x1,%ecx
  mov    %r12,%rdi
  sub    $0x1,%rbx
  lea    0x1(%rbp),%edx
  xor    %eax,%eax
  call   <ftp_i_memcpy@plt>
  sub    %rbp,%rbx
  xor    %eax,%eax
  movb   $0x0,(%r12,%rbx,1)
L43:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  pop    %rbx
  mov    $0x64,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0x64,%eax
  ret
```

assistant: ```c
int ftp_i_textfrombrackets(char *server_answer, char *dest, int maxlen) {
  int i = 0, inbracket = -1, outbracket = -1;
  while (*(server_answer + i) != '\0') {
    if (*(server_answer + i) == '(')
      inbracket = i;
    else if (*(server_answer + i) == ')')
      outbracket = i;
    i++;
  }
  if (inbracket == -1 || outbracket == -1)
    return 100;
  if (inbracket >= outbracket)
    return 100;
  if (outbracket - inbracket > maxlen)
    return 101;
  do {
    ftp_i_memcpy(dest, server_answer, inbracket + 1, outbracket - inbracket - 1);
    *(dest + outbracket - inbracket - 1) = '\0';
  } while (0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ftp_i_textfrombrackets>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L12
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    $0xffffffffffffffff,%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L10:
  cmp    $0x29,%cl
  cmove  %eax,%ebx
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L6
L31:
  cmp    $0x28,%cl
  jne    L10
  movslq %eax,%rbp
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L31
L6:
  cmp    $0xffffffff,%ebp
  sete   %al
  cmp    $0xffffffff,%ebx
  sete   %cl
  or     %cl,%al
  jne    L61
  cmp    %ebp,%ebx
  jle    L61
  mov    %ebx,%ecx
  mov    $0x65,%eax
  sub    %ebp,%ecx
  cmp    %edx,%ecx
  jg     L54
  movslq %ebx,%rbx
  mov    %rdi,%rsi
  sub    $0x1,%ecx
  mov    %r12,%rdi
  sub    $0x1,%rbx
  lea    0x1(%rbp),%edx
  xor    %eax,%eax
  call   <ftp_i_memcpy@plt>
  sub    %rbp,%rbx
  xor    %eax,%eax
  movb   $0x0,(%r12,%rbx,1)
L54:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L61:
  pop    %rbx
  mov    $0x64,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x64,%eax
  ret
```

assistant: ```c
int ftp_i_textfrombrackets(char *server_answer, char *dest, int maxlen) {
  int i = 0, inbracket = -1, outbracket = -1;
  while (*(server_answer + i) != '\0') {
    if (*(server_answer + i) == '(')
      inbracket = i;
    else if (*(server_answer + i) == ')')
      outbracket = i;
    i++;
  }
  if (inbracket == -1 || outbracket == -1)
    return 100;
  if (inbracket >= outbracket)
    return 100;
  if (outbracket - inbracket > maxlen)
    return 101;
  do {
    ftp_i_memcpy(dest, server_answer, inbracket + 1, outbracket - inbracket - 1);
    *(dest + outbracket - inbracket - 1) = '\0';
  } while (0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D10
type: f64
name: parse_data
arguments: data_tag: D21
type: string

tool: D2: %d%d

tool: D10: 10000

tool: D21: %.1f

assistant: ```c
int main(void) {
  int w, h;
  scanf("%d%d", &w, &h);
  printf("%.1f", 10000. * w / (h * h));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rsp),%xmm0
  mulsd  D13(%rip),%xmm0
  imul   %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D29
datatype: string
name: read_data
arguments: tag: D13
datatype: f64
name: read_data
arguments: tag: D14
datatype: string

tool: D29: %d%d

tool: D13: 10000

tool: D14: %.1f

assistant: ```c
int main(void) {
  int w, h;
  scanf("%d%d", &w, &h);
  printf("%.1f", 10000. * w / (h * h));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rsp),%xmm0
  mulsd  D7(%rip),%xmm0
  lea    D3(%rip),%rdi
  imul   %eax,%eax
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D13
type: string
name: read_data
arguments: data_tag: D7
type: f64
name: read_data
arguments: data_tag: D3
type: string

tool: D13: %d%d

tool: D7: 10000

tool: D3: %.1f

assistant: ```c
int main(void) {
  int w, h;
  scanf("%d%d", &w, &h);
  printf("%.1f", 10000. * w / (h * h));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rsp),%xmm0
  mulsd  D26(%rip),%xmm0
  lea    D23(%rip),%rdi
  imul   %eax,%eax
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D26
type: f64
name: disassemble_data
arguments: label: D23
type: string

tool: D25: %d%d

tool: D26: 10000

tool: D23: %.1f

assistant: ```c
int main(void) {
  int w, h;
  scanf("%d%d", &w, &h);
  printf("%.1f", 10000. * w / (h * h));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strpos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L2
L3:
  mov    $0xffffffff,%eax
L2:
  leave
  ret
```

assistant: ```c
int strpos(const char *s, int c) {
  char *p = strchr(s, c);
  if (p)
    return (p - s);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L14
  sub    %ebx,%eax
L17:
  pop    %rbx
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L17
```

assistant: ```c
int strpos(const char *s, int c) {
  char *p = strchr(s, c);
  if (p)
    return (p - s);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  sub    %ebx,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int strpos(const char *s, int c) {
  char *p = strchr(s, c);
  if (p)
    return (p - s);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L8
  sub    %ebx,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int strpos(const char *s, int c) {
  char *p = strchr(s, c);
  if (p)
    return (p - s);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x7,%eax
  and    $0x4334b500,%eax
  je     L0
  mov    %eax,%edx
  sar    $0x18,%edx
  mov    %eax,%ecx
  shl    $0x10,%ecx
  and    $0xffffff,%eax
  or     %ecx,%eax
  mov    %dl,%ah
L13:
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
L0:
  mov    %eax,%edx
  sar    $0x18,%edx
  and    $0xffffff,%eax
  mov    %dl,%al
  jmp    L13
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy12;
        }
      } else {
        copy13 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy13;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x7,%eax
  mov    %eax,%edx
  and    $0x4334b500,%edx
  je     L5
  mov    %edx,%ecx
  and    $0x34b500,%eax
  sar    $0x18,%edx
  shl    $0x10,%ecx
  or     %ecx,%eax
  mov    %dl,%ah
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  and    $0x34b500,%eax
  xor    %al,%al
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy12;
        }
      } else {
        copy13 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy13;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x7,%eax
  and    $0x4334b500,%eax
  je     L9
  mov    %eax,%ecx
  movsbl %ah,%edx
  sar    $0x18,%ecx
  shl    $0x18,%edx
  mov    %cl,%ah
  and    $0xffffff,%eax
  or     %edx,%eax
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %al,%al
  xor    %edx,%edx
  shl    $0x18,%edx
  and    $0xffffff,%eax
  or     %edx,%eax
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy12;
        }
      } else {
        copy13 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy13;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<h_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L27
  cmpl   $0x3,-0x14(%rbp)
  jg     L51
  cmpl   $0x2,-0x14(%rbp)
  je     L108
  cmpl   $0x2,-0x14(%rbp)
  jg     L51
  cmpl   $0x0,-0x14(%rbp)
  je     L9
  cmpl   $0x1,-0x14(%rbp)
  je     L92
  jmp    L51
L9:
  lea    D49(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L92:
  lea    D23(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L108:
  lea    D7(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L27:
  lea    D45(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L51:
  nop
L20:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D49
data_type: string
name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D7
data_type: string
name: unpack_data
arguments: label: D45
data_type: string
name: unpack_data
arguments: label: D4
data_type: string

tool: D49: East

tool: D23: South

tool: D7: West

tool: D45: North

tool: D4: 	Enter a name for the player in %s position.


assistant: ```c
void h_name(const int pPos) {
  char *posName;
  switch (pPos) {
  case 0:
    posName = "East";
    break;
  case 1:
    posName = "South";
    break;
  case 2:
    posName = "West";
    break;
  case 3:
    posName = "North";
    break;
  default:
    break;
  }
  printf("\tEnter a name for the player in %s position.\n", posName);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<h_name>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  cmp    $0x2,%edi
  je     L12
  jg     L7
  lea    D34(%rip),%rsi
  test   %edi,%edi
  je     L12
  cmp    $0x1,%edi
  lea    D31(%rip),%rax
  cmove  %rax,%rsi
L12:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L7:
  cmp    $0x3,%edi
  lea    D18(%rip),%rax
  cmove  %rax,%rsi
  jmp    L12
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string
name: parse_data
arguments: tag: D34
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string

tool: D6: West

tool: D34: East

tool: D31: South

tool: D2: 	Enter a name for the player in %s position.


tool: D18: North

assistant: ```c
void h_name(const int pPos) {
  char *posName;
  switch (pPos) {
  case 0:
    posName = "East";
    break;
  case 1:
    posName = "South";
    break;
  case 2:
    posName = "West";
    break;
  case 3:
    posName = "North";
    break;
  default:
    break;
  }
  printf("\tEnter a name for the player in %s position.\n", posName);
}
```
user: Translate the below assembly code into C programming language:

```asm
<h_name>:
  endbr64
  lea    D56(%rip),%rsi
  cmp    $0x2,%edi
  je     L6
  jg     L0
  lea    D29(%rip),%rsi
  test   %edi,%edi
  je     L6
  cmp    $0x1,%edi
  lea    D12(%rip),%rax
  cmove  %rax,%rsi
L6:
  lea    D26(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    $0x3,%edi
  lea    D18(%rip),%rax
  lea    D26(%rip),%rdi
  cmove  %rax,%rsi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D56
type: string
name: retrieve_data
arguments: data_label: D29
type: string
name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D26
type: string
name: retrieve_data
arguments: data_label: D18
type: string

tool: D56: West

tool: D29: East

tool: D12: South

tool: D26: 	Enter a name for the player in %s position.


tool: D18: North

assistant: ```c
void h_name(const int pPos) {
  char *posName;
  switch (pPos) {
  case 0:
    posName = "East";
    break;
  case 1:
    posName = "South";
    break;
  case 2:
    posName = "West";
    break;
  case 3:
    posName = "North";
    break;
  default:
    break;
  }
  printf("\tEnter a name for the player in %s position.\n", posName);
}
```
user: Translate the below assembly code into C programming language:

```asm
<h_name>:
  endbr64
  lea    D42(%rip),%rsi
  cmp    $0x2,%edi
  je     L6
  jg     L27
  lea    D39(%rip),%rsi
  test   %edi,%edi
  je     L6
  cmp    $0x1,%edi
  lea    D36(%rip),%rax
  cmove  %rax,%rsi
L6:
  lea    D43(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L27:
  cmp    $0x3,%edi
  lea    D6(%rip),%rax
  lea    D43(%rip),%rdi
  cmove  %rax,%rsi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D42
type: string
name: read_data
arguments: data_tag: D39
type: string
name: read_data
arguments: data_tag: D36
type: string
name: read_data
arguments: data_tag: D43
type: string
name: read_data
arguments: data_tag: D6
type: string

tool: D42: West

tool: D39: East

tool: D36: South

tool: D43: 	Enter a name for the player in %s position.


tool: D6: North

assistant: ```c
void h_name(const int pPos) {
  char *posName;
  switch (pPos) {
  case 0:
    posName = "East";
    break;
  case 1:
    posName = "South";
    break;
  case 2:
    posName = "West";
    break;
  case 3:
    posName = "North";
    break;
  default:
    break;
  }
  printf("\tEnter a name for the player in %s position.\n", posName);
}
```