ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_null_terminator>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L10
  mov    %rdx,%rdi
  test   %rdx,%rdx
  je     L27
  mov    %rsi,%rbp
  call   <size_less_null@plt>
  cmp    %rbp,%rax
  jb     L33
  movb   $0x0,(%rbx,%rbp,1)
  xor    %r8d,%r8d
L17:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %eax,%r8d
  mov    $0x1,%edx
  movb   $0x0,(%rbx,%rax,1)
  sub    %ebp,%r8d
  add    $0x1,%r8d
  test   %r8d,%r8d
  cmovle %edx,%r8d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L27:
  mov    $0xffffffff,%r8d
  jmp    L17
L10:
  mov    $0xfffffffe,%r8d
  jmp    L17
```

assistant: ```c
int set_null_terminator(char *buf, size_t len_before_terminator, size_t buf_size) {
  int truncated = 0;
  size_t buf_terminator_size;
  if (!buf)
    return -2;
  if (buf_size <= 0)
    return -1;
  buf_terminator_size = size_less_null(buf_size);
  if (len_before_terminator > buf_terminator_size) {
    truncated = (int)(((int)(buf_terminator_size - len_before_terminator)) + 1);
    if (!(truncated >= 1))
      truncated = 1;
    len_before_terminator = buf_terminator_size;
  }
  if (len_before_terminator <= 0)
    len_before_terminator = 0;
  buf[len_before_terminator] = 0;
  if (!truncated)
    return 0;
  else
    return truncated;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<deallocateAll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <deallocateObjectMemory@plt>
  mov    $0x0,%eax
  call   <deallocateMethodLookupCache@plt>
  mov    $0x0,%eax
  call   <deallocateFileStreamTable@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void deallocateAll() {
  deallocateObjectMemory();
  deallocateMethodLookupCache();
  deallocateFileStreamTable();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<deallocateAll>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <deallocateObjectMemory@plt>
  mov    $0x0,%eax
  call   <deallocateMethodLookupCache@plt>
  mov    $0x0,%eax
  call   <deallocateFileStreamTable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void deallocateAll() {
  deallocateObjectMemory();
  deallocateMethodLookupCache();
  deallocateFileStreamTable();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deallocateAll>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <deallocateObjectMemory@plt>
  xor    %eax,%eax
  call   <deallocateMethodLookupCache@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <deallocateFileStreamTable@plt>
```

assistant: ```c
void deallocateAll() {
  deallocateObjectMemory();
  deallocateMethodLookupCache();
  deallocateFileStreamTable();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<deallocateAll>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <deallocateObjectMemory@plt>
  xor    %eax,%eax
  call   <deallocateMethodLookupCache@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <deallocateFileStreamTable@plt>
```

assistant: ```c
void deallocateAll() {
  deallocateObjectMemory();
  deallocateMethodLookupCache();
  deallocateFileStreamTable();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<numero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L108
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D18(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D18(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L6
  mov    $0x1,%eax
  jmp    L6
  mov    $0x2,%eax
  jmp    L6
  mov    $0x3,%eax
  jmp    L6
  mov    $0x4,%eax
  jmp    L6
  mov    $0x5,%eax
  jmp    L6
  mov    $0x6,%eax
  jmp    L6
  mov    $0x7,%eax
  jmp    L6
  mov    $0x8,%eax
  jmp    L6
  mov    $0x9,%eax
  jmp    L6
L108:
  mov    $0xffffffff,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int numero(char c) {
  switch (c) {
  case '0':
    return 0;
    break;
  case '1':
    return 1;
    break;
  case '2':
    return 2;
    break;
  case '3':
    return 3;
    break;
  case '4':
    return 4;
    break;
  case '5':
    return 5;
    break;
  case '6':
    return 6;
    break;
  case '7':
    return 7;
    break;
  case '8':
    return 8;
    break;
  case '9':
    return 9;
    break;
  default:
    return -1;
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<numero>:
  endbr64
  sub    $0x30,%edi
  cmp    $0x9,%dil
  ja     L5
  movzbl %dil,%edi
  lea    D2(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
L5:
  mov    $0xffffffff,%eax
  ret
  mov    $0x0,%eax
  ret
```

assistant: ```c
int numero(char c) {
  switch (c) {
  case '0':
    return 0;
    break;
  case '1':
    return 1;
    break;
  case '2':
    return 2;
    break;
  case '3':
    return 3;
    break;
  case '4':
    return 4;
    break;
  case '5':
    return 5;
    break;
  case '6':
    return 6;
    break;
  case '7':
    return 7;
    break;
  case '8':
    return 8;
    break;
  case '9':
    return 9;
    break;
  default:
    return -1;
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<numero>:
  endbr64
  lea    -0x30(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x30,%eax
  cmp    $0xa,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
```

assistant: ```c
int numero(char c) {
  switch (c) {
  case '0':
    return 0;
    break;
  case '1':
    return 1;
    break;
  case '2':
    return 2;
    break;
  case '3':
    return 3;
    break;
  case '4':
    return 4;
    break;
  case '5':
    return 5;
    break;
  case '6':
    return 6;
    break;
  case '7':
    return 7;
    break;
  case '8':
    return 8;
    break;
  case '9':
    return 9;
    break;
  default:
    return -1;
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<numero>:
  endbr64
  lea    -0x30(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x30,%eax
  cmp    $0xa,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
```

assistant: ```c
int numero(char c) {
  switch (c) {
  case '0':
    return 0;
    break;
  case '1':
    return 1;
    break;
  case '2':
    return 2;
    break;
  case '3':
    return 3;
    break;
  case '4':
    return 4;
    break;
  case '5':
    return 5;
    break;
  case '6':
    return 6;
    break;
  case '7':
    return 7;
    break;
  case '8':
    return 8;
    break;
  case '9':
    return 9;
    break;
  default:
    return -1;
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <meson_test_main_foo@plt>
  cmp    $0xa,%eax
  je     L8
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L27
L8:
  mov    $0x0,%eax
  call   <meson_test_subproj_foo@plt>
  cmp    $0x14,%eax
  je     L32
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L27
L32:
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D16: Failed meson_test_main_foo


tool: D5: Failed meson_test_subproj_foo


assistant: ```c
int main(void) {
  if (meson_test_main_foo() != 10) {
    printf("Failed meson_test_main_foo\n");
    return 1;
  }
  if (meson_test_subproj_foo() != 20) {
    printf("Failed meson_test_subproj_foo\n");
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <meson_test_main_foo@plt>
  cmp    $0xa,%eax
  je     L17
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L2:
  add    $0x8,%rsp
  ret
L17:
  mov    $0x0,%eax
  call   <meson_test_subproj_foo@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x14,%edx
  je     L2
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D10: Failed meson_test_main_foo


tool: D12: Failed meson_test_subproj_foo


assistant: ```c
int main(void) {
  if (meson_test_main_foo() != 10) {
    printf("Failed meson_test_main_foo\n");
    return 1;
  }
  if (meson_test_subproj_foo() != 20) {
    printf("Failed meson_test_subproj_foo\n");
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <meson_test_main_foo@plt>
  cmp    $0xa,%eax
  je     L21
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L17:
  add    $0x8,%rsp
  ret
L21:
  xor    %eax,%eax
  call   <meson_test_subproj_foo@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x14,%r8d
  je     L17
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L17
```

tool_calls: name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D1
type: string

tool: D8: Failed meson_test_main_foo


tool: D1: Failed meson_test_subproj_foo


assistant: ```c
int main(void) {
  if (meson_test_main_foo() != 10) {
    printf("Failed meson_test_main_foo\n");
    return 1;
  }
  if (meson_test_subproj_foo() != 20) {
    printf("Failed meson_test_subproj_foo\n");
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <meson_test_main_foo@plt>
  cmp    $0xa,%eax
  je     L6
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L12:
  add    $0x8,%rsp
  ret
L6:
  xor    %eax,%eax
  call   <meson_test_subproj_foo@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x14,%r8d
  je     L12
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: label: D10
datatype: string
name: disassemble_data
arguments: label: D17
datatype: string

tool: D10: Failed meson_test_main_foo


tool: D17: Failed meson_test_subproj_foo


assistant: ```c
int main(void) {
  if (meson_test_main_foo() != 10) {
    printf("Failed meson_test_main_foo\n");
    return 1;
  }
  if (meson_test_subproj_foo() != 20) {
    printf("Failed meson_test_subproj_foo\n");
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<md5_hash>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x67452301,%edi
  call   <UINT32_C@plt>
  mov    %eax,0x0(%rbp)
  mov    $0xefcdab89,%edi
  call   <UINT32_C@plt>
  mov    %eax,0x4(%rbp)
  mov    $0x98badcfe,%edi
  call   <UINT32_C@plt>
  mov    %eax,0x8(%rbp)
  mov    $0x10325476,%edi
  call   <UINT32_C@plt>
  mov    %eax,0xc(%rbp)
  cmp    $0x3f,%r13d
  jle    L26
  mov    %r14,%rbx
  lea    -0x40(%r13),%r12d
  shr    $0x6,%r12d
  mov    %r12d,%eax
  shl    $0x8,%rax
  lea    0x100(%r14,%rax,1),%r15
L55:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <md5_compress@plt>
  add    $0x100,%rbx
  cmp    %r15,%rbx
  jne    L55
  mov    %r12d,%eax
  neg    %eax
  shl    $0x6,%eax
  lea    -0x40(%r13,%rax,1),%ebx
  add    $0x1,%r12d
  shl    $0x6,%r12d
L31:
  movslq %r12d,%r12
  lea    (%r14,%r12,4),%rsi
  mov    %rsp,%rdi
  mov    %ebx,%edx
  call   <memcpy@plt>
  movslq %ebx,%rax
  shl    $0x2,%rax
  movl   $0x80,(%rsp,%rax,1)
  add    $0x1,%ebx
  mov    $0x40,%edx
  sub    %ebx,%edx
  cmp    $0x7,%edx
  jle    L15
  mov    $0x38,%edx
  sub    %ebx,%edx
  lea    0x4(%rsp,%rax,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
L44:
  lea    0x0(,%r13,8),%eax
  mov    %eax,0x38(%rsp)
  sar    $0x1d,%r13d
  mov    %r13d,0x3c(%rsp)
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <md5_compress@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  mov    %r13d,%ebx
  mov    $0x0,%r12d
  jmp    L31
L15:
  mov    %rsp,%rbx
  lea    0x4(%rsp,%rax,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <md5_compress@plt>
  mov    $0x38,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  jmp    L44
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void md5_hash(const uint8_t *message, uint32_t len, uint32_t hash[4]) {
  hash[0] = UINT32_C(0x67452301);
  hash[1] = UINT32_C(0xEFCDAB89);
  hash[2] = UINT32_C(0x98BADCFE);
  hash[3] = UINT32_C(0x10325476);
  uint32_t i;
  for (i = 0; len - i >= 64; i += 64)
    md5_compress(hash, (uint32_t *)(message + i));
  uint32_t block[16];
  uint8_t *byteBlock = (uint8_t *)block;
  uint32_t rem = len - i;
  memcpy(byteBlock, message + i, rem);
  byteBlock[rem] = 0x80;
  rem++;
  if (64 - rem >= 8)
    memset(byteBlock + rem, 0, 56 - rem);
  else {
    memset(byteBlock + rem, 0, 64 - rem);
    md5_compress(hash, block);
    memset(block, 0, 56);
  }
  block[14] = len << 3;
  block[15] = len >> 29;
  md5_compress(hash, block);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<md5_hash>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x67452301,%edi
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <UINT32_C@plt>
  mov    $0xefcdab89,%edi
  mov    %eax,0x0(%rbp)
  call   <UINT32_C@plt>
  mov    $0x98badcfe,%edi
  mov    %eax,0x4(%rbp)
  call   <UINT32_C@plt>
  mov    $0x10325476,%edi
  mov    %eax,0x8(%rbp)
  call   <UINT32_C@plt>
  mov    %eax,0xc(%rbp)
  cmp    $0x3f,%r12d
  jle    L3
  lea    -0x40(%r12),%eax
  mov    %r15,%rbx
  mov    %eax,%r14d
  mov    %eax,0xc(%rsp)
  shr    $0x6,%r14d
  mov    %r14d,%eax
  shl    $0x8,%rax
  lea    0x100(%r15,%rax,1),%r13
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x100,%rbx
  call   <md5_compress@plt>
  cmp    %rbx,%r13
  jne    L11
  mov    %r14d,%eax
  add    $0x1,%r14d
  mov    0xc(%rsp),%ebx
  shl    $0x6,%r14d
  shl    $0x6,%eax
  movslq %r14d,%r14
  sub    %eax,%ebx
  lea    (%r15,%r14,4),%r15
L5:
  lea    0x10(%rsp),%r13
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rax
  mov    $0x40,%edx
  add    $0x1,%ebx
  shl    $0x2,%rax
  sub    %ebx,%edx
  movl   $0x80,0x10(%rsp,%rax,1)
  lea    0x4(%r13,%rax,1),%rdi
  cmp    $0x7,%edx
  jle    L52
  mov    $0x38,%edx
  xor    %esi,%esi
  sub    %ebx,%edx
  call   <memset@plt>
L57:
  lea    0x0(,%r12,8),%eax
  mov    %r13,%rsi
  sar    $0x1d,%r12d
  mov    %rbp,%rdi
  mov    %eax,0x48(%rsp)
  mov    %r12d,0x4c(%rsp)
  call   <md5_compress@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L52:
  xor    %esi,%esi
  call   <memset@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <md5_compress@plt>
  mov    $0x38,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%ebx
  jmp    L5
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void md5_hash(const uint8_t *message, uint32_t len, uint32_t hash[4]) {
  hash[0] = UINT32_C(0x67452301);
  hash[1] = UINT32_C(0xEFCDAB89);
  hash[2] = UINT32_C(0x98BADCFE);
  hash[3] = UINT32_C(0x10325476);
  uint32_t i;
  for (i = 0; len - i >= 64; i += 64)
    md5_compress(hash, (uint32_t *)(message + i));
  uint32_t block[16];
  uint8_t *byteBlock = (uint8_t *)block;
  uint32_t rem = len - i;
  memcpy(byteBlock, message + i, rem);
  byteBlock[rem] = 0x80;
  rem++;
  if (64 - rem >= 8)
    memset(byteBlock + rem, 0, 56 - rem);
  else {
    memset(byteBlock + rem, 0, 64 - rem);
    md5_compress(hash, block);
    memset(block, 0, 56);
  }
  block[14] = len << 3;
  block[15] = len >> 29;
  md5_compress(hash, block);
}
```
user: Translate the below assembly code into C programming language:

```asm
<md5_hash>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x67452301,%edi
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <UINT32_C@plt>
  mov    $0xefcdab89,%edi
  mov    %eax,0x0(%rbp)
  call   <UINT32_C@plt>
  mov    $0x98badcfe,%edi
  mov    %eax,0x4(%rbp)
  call   <UINT32_C@plt>
  mov    $0x10325476,%edi
  mov    %eax,0x8(%rbp)
  call   <UINT32_C@plt>
  mov    %eax,0xc(%rbp)
  cmp    $0x3f,%r12d
  jle    L13
  lea    -0x40(%r12),%eax
  mov    %r15,%rbx
  mov    %eax,%r14d
  mov    %eax,0xc(%rsp)
  shr    $0x6,%r14d
  mov    %r14d,%eax
  shl    $0x8,%rax
  lea    0x100(%r15,%rax,1),%r13
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x100,%rbx
  call   <md5_compress@plt>
  cmp    %rbx,%r13
  jne    L59
  mov    %r14d,%eax
  add    $0x1,%r14d
  mov    0xc(%rsp),%ebx
  shl    $0x6,%r14d
  shl    $0x6,%eax
  movslq %r14d,%r14
  sub    %eax,%ebx
  lea    (%r15,%r14,4),%r15
L42:
  lea    0x10(%rsp),%r13
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rax
  mov    $0x40,%edx
  add    $0x1,%ebx
  shl    $0x2,%rax
  sub    %ebx,%edx
  movl   $0x80,0x10(%rsp,%rax,1)
  lea    0x4(%r13,%rax,1),%rdi
  cmp    $0x7,%edx
  jle    L35
  mov    $0x38,%edx
  xor    %esi,%esi
  sub    %ebx,%edx
  call   <memset@plt>
L19:
  lea    0x0(,%r12,8),%eax
  sar    $0x1d,%r12d
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movd   %eax,%xmm0
  movd   %r12d,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x48(%rsp)
  call   <md5_compress@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L35:
  xor    %esi,%esi
  call   <memset@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <md5_compress@plt>
  mov    $0x38,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r12d,%ebx
  jmp    L42
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void md5_hash(const uint8_t *message, uint32_t len, uint32_t hash[4]) {
  hash[0] = UINT32_C(0x67452301);
  hash[1] = UINT32_C(0xEFCDAB89);
  hash[2] = UINT32_C(0x98BADCFE);
  hash[3] = UINT32_C(0x10325476);
  uint32_t i;
  for (i = 0; len - i >= 64; i += 64)
    md5_compress(hash, (uint32_t *)(message + i));
  uint32_t block[16];
  uint8_t *byteBlock = (uint8_t *)block;
  uint32_t rem = len - i;
  memcpy(byteBlock, message + i, rem);
  byteBlock[rem] = 0x80;
  rem++;
  if (64 - rem >= 8)
    memset(byteBlock + rem, 0, 56 - rem);
  else {
    memset(byteBlock + rem, 0, 64 - rem);
    md5_compress(hash, block);
    memset(block, 0, 56);
  }
  block[14] = len << 3;
  block[15] = len >> 29;
  md5_compress(hash, block);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rcx
  mov    %edx,%eax
  jmp    L5
L32:
  mov    %rsi,%rdx
  lea    0x1(%rdx),%rsi
  movzbl (%rdx),%edx
  movsbl %dl,%edi
  mov    %rcx,%rdx
  lea    0x1(%rdx),%rcx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%edi
  mov    %edi,%ebx
  test   %ebx,%ebx
  je     L5
  mov    %ebx,%eax
  jmp    L13
L5:
  mov    %eax,%edx
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jne    L32
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int bcmp(b1, b2, n)
register char *b1, *b2;
register int n;
{
  register int i;
  while (n--) {
    if (i = *b2++ - *b1++)
      return i;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bcmp>:
  endbr64
  mov    %edx,%edx
  mov    $0x0,%ecx
L15:
  cmp    %rdx,%rcx
  je     L0
  movsbl (%rsi,%rcx,1),%eax
  movsbl (%rdi,%rcx,1),%r8d
  add    $0x1,%rcx
  sub    %r8d,%eax
  je     L15
  jmp    L10
L0:
  mov    $0x0,%eax
L10:
  ret
```

assistant: ```c
int bcmp(b1, b2, n)
register char *b1, *b2;
register int n;
{
  register int i;
  while (n--) {
    if (i = *b2++ - *b1++)
      return i;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bcmp>:
  endbr64
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl (%rsi,%rcx,1),%eax
  movsbl (%rdi,%rcx,1),%r8d
  add    $0x1,%rcx
  sub    %r8d,%eax
  jne    L14
L15:
  cmp    %rdx,%rcx
  jne    L27
  xor    %eax,%eax
L14:
  ret
```

assistant: ```c
int bcmp(b1, b2, n)
register char *b1, *b2;
register int n;
{
  register int i;
  while (n--) {
    if (i = *b2++ - *b1++)
      return i;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bcmp>:
  endbr64
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%rsi,%rcx,1),%eax
  movsbl (%rdi,%rcx,1),%r8d
  add    $0x1,%rcx
  sub    %r8d,%eax
  jne    L27
L3:
  cmp    %rcx,%rdx
  jne    L10
  xor    %eax,%eax
L27:
  ret
```

assistant: ```c
int bcmp(b1, b2, n)
register char *b1, *b2;
register int n;
{
  register int i;
  while (n--) {
    if (i = *b2++ - *b1++)
      return i;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<VIM_MARB_SetThumbbufMem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x240c,%edi
  call   <VIM_HIF_SetReg8@plt>
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x240b,%edi
  call   <VIM_HIF_SetReg8@plt>
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x240a,%edi
  call   <VIM_HIF_SetReg8@plt>
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    %edx,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x240f,%edi
  call   <VIM_HIF_SetReg8@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x240e,%edi
  call   <VIM_HIF_SetReg8@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x240d,%edi
  call   <VIM_HIF_SetReg8@plt>
  nop
  leave
  ret
```

assistant: ```c
void VIM_MARB_SetThumbbufMem(unsigned long StartAdd, unsigned long Size) {
  VIM_HIF_SetReg8((0x2400 + 0x00C), (unsigned char)StartAdd);
  VIM_HIF_SetReg8((0x2400 + 0x00B), (unsigned char)(StartAdd >> 8));
  VIM_HIF_SetReg8((0x2400 + 0x00A), (unsigned char)(StartAdd >> 16));
  VIM_HIF_SetReg8((0x2400 + 0x00F), (unsigned char)(StartAdd + Size));
  VIM_HIF_SetReg8((0x2400 + 0x00E), (unsigned char)((StartAdd + Size) >> 8));
  VIM_HIF_SetReg8((0x2400 + 0x00D), (unsigned char)((StartAdd + Size) >> 16));
}
```