ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<boneyard>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rdi
  call   <niceprint@plt>
  mov    $0x14,%edi
  call   <d@plt>
  cmp    $0xe,%eax
  jbe    L18
  cmp    $0x12,%eax
  ja     L11
  mov    $0x4,%edi
  call   <d@plt>
  mov    $0x4,%edi
  mov    %eax,%ebx
  call   <d@plt>
  mov    $0x4,%edi
  add    %eax,%ebx
  call   <d@plt>
  lea    (%rbx,%rax,1),%edi
  pop    %rbx
  jmp    1090 <skeletons@plt>
L11:
  mov    $0x3,%edi
  call   <d@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    10b0 <minotaurskeletons@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: An eerie cavern littered with countless bones of various creatures. It is unclear if this is the natural graveyard for some Underdark species or the former lair of a fearsome predator. The characters can potentially gather useful material for crafting among the bones.



assistant: ```c
void boneyard(void) {
  unsigned d20;
  niceprint("An eerie cavern littered with countless bones of various creatures. "
            "It is unclear if this is the natural graveyard for some Underdark species "
            "or the former lair of a fearsome predator. The characters can potentially "
            "gather useful material for crafting among the bones.\n\n");
  d20 = d(20);
  if (d20 < 15)
    return;
  if (d20 < 19)
    skeletons(d(4) + d(4) + d(4));
  else
    minotaurskeletons(d(3));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<boneyard>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rdi
  call   <niceprint@plt>
  mov    $0x14,%edi
  call   <d@plt>
  cmp    $0xe,%eax
  jbe    L1
  cmp    $0x12,%eax
  ja     L12
  mov    $0x4,%edi
  call   <d@plt>
  mov    $0x4,%edi
  mov    %eax,%ebx
  call   <d@plt>
  mov    $0x4,%edi
  add    %eax,%ebx
  call   <d@plt>
  lea    (%rbx,%rax,1),%edi
  pop    %rbx
  jmp    1090 <skeletons@plt>
L12:
  mov    $0x3,%edi
  call   <d@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    10b0 <minotaurskeletons@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: An eerie cavern littered with countless bones of various creatures. It is unclear if this is the natural graveyard for some Underdark species or the former lair of a fearsome predator. The characters can potentially gather useful material for crafting among the bones.



assistant: ```c
void boneyard(void) {
  unsigned d20;
  niceprint("An eerie cavern littered with countless bones of various creatures. "
            "It is unclear if this is the natural graveyard for some Underdark species "
            "or the former lair of a fearsome predator. The characters can potentially "
            "gather useful material for crafting among the bones.\n\n");
  d20 = d(20);
  if (d20 < 15)
    return;
  if (d20 < 19)
    skeletons(d(4) + d(4) + d(4));
  else
    minotaurskeletons(d(3));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L85
L17:
  addq   $0x1,-0x38(%rbp)
L85:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L66
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L17
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L17
  jmp    L66
L87:
  cmpl   $0x1e,-0x3c(%rbp)
  jg     L56
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
L56:
  addl   $0x1,-0x3c(%rbp)
  addq   $0x1,-0x38(%rbp)
L66:
  mov    -0x3c(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jge    L36
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L36
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L36
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L87
L36:
  mov    -0x48(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x3c(%rbp),%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int get_digits(char **buf, int max) {
  char *p = *buf;
  char tmpbuf[32];
  int count = 0;
  while (*p && (*p < '0' || *p > '9')) {
    p++;
  }
  while (count < max && *p && *p >= '0' && *p <= '9') {
    if (count < 32 - 1)
      tmpbuf[count] = *p;
    count++;
    p++;
  }
  *buf = p;
  tmpbuf[count] = 0;
  return atoi(tmpbuf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_digits>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L66
  test   %dl,%dl
  je     L66
L96:
  add    $0x1,%rax
  movzbl (%rax),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L66
  test   %dl,%dl
  jne    L96
L66:
  test   %esi,%esi
  jle    L46
  mov    %rsp,%r8
  mov    $0x0,%edx
  jmp    L94
L55:
  add    $0x1,%edx
  add    $0x1,%rax
  add    $0x1,%r8
  cmp    %edx,%esi
  je     L53
L94:
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%r9d
  cmp    $0x9,%r9b
  ja     L27
  cmp    $0x1e,%edx
  jg     L55
  mov    %cl,(%r8)
  jmp    L55
L46:
  mov    $0x0,%edx
  jmp    L27
L53:
  mov    %esi,%edx
L27:
  mov    %rax,(%rdi)
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  mov    %rsp,%rdi
  call   <atoi@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x38,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_digits(char **buf, int max) {
  char *p = *buf;
  char tmpbuf[32];
  int count = 0;
  while (*p && (*p < '0' || *p > '9')) {
    p++;
  }
  while (count < max && *p && *p >= '0' && *p <= '9') {
    if (count < 32 - 1)
      tmpbuf[count] = *p;
    count++;
    p++;
  }
  *buf = p;
  tmpbuf[count] = 0;
  return atoi(tmpbuf);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_digits>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L17
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
L36:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L40
L17:
  test   %dl,%dl
  jne    L36
L40:
  test   %esi,%esi
  jle    L41
  mov    %rsp,%r10
  xor    %edx,%edx
  mov    %r10,%r8
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L12:
  cmp    $0x1e,%edx
  jg     L75
  mov    %cl,(%r8)
L75:
  add    $0x1,%edx
  add    $0x1,%rax
  add    $0x1,%r8
  cmp    %edx,%esi
  je     L64
L98:
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%r9d
  cmp    $0x9,%r9b
  jbe    L12
L64:
  mov    %rax,(%rdi)
  movslq %edx,%rdx
  mov    %r10,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <atoi@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L71
  add    $0x38,%rsp
  ret
L41:
  xor    %edx,%edx
  mov    %rsp,%r10
  jmp    L64
L71:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_digits(char **buf, int max) {
  char *p = *buf;
  char tmpbuf[32];
  int count = 0;
  while (*p && (*p < '0' || *p > '9')) {
    p++;
  }
  while (count < max && *p && *p >= '0' && *p <= '9') {
    if (count < 32 - 1)
      tmpbuf[count] = *p;
    count++;
    p++;
  }
  *buf = p;
  tmpbuf[count] = 0;
  return atoi(tmpbuf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_digits>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L15
  jmp    L103
  cs nopw 0x0(%rax,%rax,1)
L100:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L103
L15:
  test   %dl,%dl
  jne    L100
L103:
  test   %esi,%esi
  jle    L30
  mov    %rsp,%r10
  xor    %edx,%edx
  mov    %r10,%r8
  jmp    L91
  nopw   0x0(%rax,%rax,1)
L13:
  cmp    $0x1e,%edx
  jg     L50
  mov    %cl,(%r8)
L50:
  add    $0x1,%edx
  add    $0x1,%rax
  add    $0x1,%r8
  cmp    %edx,%esi
  je     L56
L91:
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%r9d
  cmp    $0x9,%r9b
  jbe    L13
L56:
  mov    %rax,(%rdi)
  movslq %edx,%rdx
  mov    %r10,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <atoi@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L97
  add    $0x38,%rsp
  ret
L30:
  xor    %edx,%edx
  mov    %rsp,%r10
  jmp    L56
L97:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_digits(char **buf, int max) {
  char *p = *buf;
  char tmpbuf[32];
  int count = 0;
  while (*p && (*p < '0' || *p > '9')) {
    p++;
  }
  while (count < max && *p && *p >= '0' && *p <= '9') {
    if (count < 32 - 1)
      tmpbuf[count] = *p;
    count++;
    p++;
  }
  *buf = p;
  tmpbuf[count] = 0;
  return atoi(tmpbuf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sp_istrcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L27:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L28
  mov    -0x14(%rbp),%eax
  jmp    L14
L28:
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
L12:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L40
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
L40:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int sp_istrcmp(const char *str1, const char *str2) {
  int result = 0;
  while (*str1 && *str2) {
    result = toupper(*str1) - toupper(*str2);
    if (result)
      return result;
    str1++, str2++;
  }
  return toupper(*str1) - toupper(*str2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sp_istrcmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L18
L15:
  cmpb   $0x0,0x0(%rbp)
  je     L18
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  sub    %eax,%ebx
  jne    L24
  add    $0x1,%r12
  add    $0x1,%rbp
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L15
L18:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  sub    %eax,%ebx
L24:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sp_istrcmp(const char *str1, const char *str2) {
  int result = 0;
  while (*str1 && *str2) {
    result = toupper(*str1) - toupper(*str2);
    if (result)
      return result;
    str1++, str2++;
  }
  return toupper(*str1) - toupper(*str2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sp_istrcmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  xor    %edi,%edi
  test   %al,%al
  jne    L48
  jmp    L46
  nopl   0x0(%rax)
L22:
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <toupper@plt>
  sub    %eax,%ebx
  mov    %ebx,%edi
  jne    L16
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %al,%al
  je     L46
L48:
  cmpb   $0x0,0x0(%rbp)
  movsbl %al,%edi
  jne    L22
L46:
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <toupper@plt>
  sub    %eax,%ebx
  mov    %ebx,%edi
L16:
  pop    %rbx
  mov    %edi,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sp_istrcmp(const char *str1, const char *str2) {
  int result = 0;
  while (*str1 && *str2) {
    result = toupper(*str1) - toupper(*str2);
    if (result)
      return result;
    str1++, str2++;
  }
  return toupper(*str1) - toupper(*str2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sp_istrcmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  xor    %edi,%edi
  test   %al,%al
  jne    L35
  jmp    L34
  nopl   0x0(%rax)
L9:
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <toupper@plt>
  sub    %eax,%ebx
  mov    %ebx,%edi
  jne    L33
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %al,%al
  je     L34
L35:
  cmpb   $0x0,0x0(%rbp)
  movsbl %al,%edi
  jne    L9
L34:
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <toupper@plt>
  sub    %eax,%ebx
  mov    %ebx,%edi
L33:
  pop    %rbx
  mov    %edi,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sp_istrcmp(const char *str1, const char *str2) {
  int result = 0;
  while (*str1 && *str2) {
    result = toupper(*str1) - toupper(*str2);
    if (result)
      return result;
    str1++, str2++;
  }
  return toupper(*str1) - toupper(*str2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  cmpl   $0x1,-0x20(%rbp)
  setle  %al
  movzbl %al,%eax
  cmp    %eax,-0x20(%rbp)
  setl   %al
  movzbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  sete   %al
  movzbl %al,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cmp    $0xfffffff9,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movl   $0x1,-0x10(%rbp,%rax,4)
  mov    $0x4,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2: %lu


assistant: ```c
int main(void) {
  int a = -1;
  int b = 2;
  int c = a == b == 2;
  int d = c<2> c >= 1;
  int e = d && c || 1;
  int f = (1, 2);
  int g[2];
  c = !c + +a != -7;
  (g)[b - 1] = 1;
  printf("%lu\n", sizeof(+(char)a));
  return - -c + d + e + f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: %lu


assistant: ```c
int main(void) {
  int a = -1;
  int b = 2;
  int c = a == b == 2;
  int d = c<2> c >= 1;
  int e = d && c || 1;
  int f = (1, 2);
  int g[2];
  c = !c + +a != -7;
  (g)[b - 1] = 1;
  printf("%lu\n", sizeof(+(char)a));
  return - -c + d + e + f;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %lu


assistant: ```c
int main(void) {
  int a = -1;
  int b = 2;
  int c = a == b == 2;
  int d = c<2> c >= 1;
  int e = d && c || 1;
  int f = (1, 2);
  int g[2];
  c = !c + +a != -7;
  (g)[b - 1] = 1;
  printf("%lu\n", sizeof(+(char)a));
  return - -c + d + e + f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: %lu


assistant: ```c
int main(void) {
  int a = -1;
  int b = 2;
  int c = a == b == 2;
  int d = c<2> c >= 1;
  int e = d && c || 1;
  int f = (1, 2);
  int g[2];
  c = !c + +a != -7;
  (g)[b - 1] = 1;
  printf("%lu\n", sizeof(+(char)a));
  return - -c + d + e + f;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<h>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L4
  cmpl   $0x3,-0x4(%rbp)
  jg     L4
  xorl   $0x1,-0x4(%rbp)
  andl   $0x3,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int h(int x) {
  if (x >= 0 && x <= 3) {
    x = x ^ 1;
    x = x & 3;
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<h>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  xor    $0x1,%edx
  cmp    $0x4,%edi
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int h(int x) {
  if (x >= 0 && x <= 3) {
    x = x ^ 1;
    x = x & 3;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<h>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  xor    $0x1,%edx
  cmp    $0x4,%edi
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int h(int x) {
  if (x >= 0 && x <= 3) {
    x = x ^ 1;
    x = x & 3;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<h>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  xor    $0x1,%edx
  cmp    $0x4,%edi
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int h(int x) {
  if (x >= 0 && x <= 3) {
    x = x ^ 1;
    x = x & 3;
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <fibo@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  jne    L1
  nop
  mov    $0x0,%eax
  call   <__VERIFIER_error@plt>
L1:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int x = 5;
  int result = fibo(x);
  if (result == 5) {
  ERROR:
    __VERIFIER_error();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fibo@plt>
  cmp    $0x5,%eax
  je     L15
L5:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L15:
  mov    $0x0,%eax
  call   <__VERIFIER_error@plt>
  jmp    L5
```

assistant: ```c
int main(void) {
  int x = 5;
  int result = fibo(x);
  if (result == 5) {
  ERROR:
    __VERIFIER_error();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fibo@plt>
  cmp    $0x5,%eax
  je     L6
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  xor    %eax,%eax
  call   <__VERIFIER_error@plt>
  jmp    L2
```

assistant: ```c
int main(void) {
  int x = 5;
  int result = fibo(x);
  if (result == 5) {
  ERROR:
    __VERIFIER_error();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fibo@plt>
  cmp    $0x5,%eax
  je     L2
L18:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L2:
  xor    %eax,%eax
  call   <__VERIFIER_error@plt>
  jmp    L18
```

assistant: ```c
int main(void) {
  int x = 5;
  int result = fibo(x);
  if (result == 5) {
  ERROR:
    __VERIFIER_error();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_sublist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jbe    L54
  mov    $0x0,%eax
  jmp    L39
L54:
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L46:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L25
  mov    $0x1,%eax
  jmp    L39
L25:
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L46
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
bool is_sublist(int *list_to_compare, int *base_list, size_t list_to_compare_element_count, size_t base_list_element_count) {
  int i;
  int loop_end = (base_list_element_count - list_to_compare_element_count);
  if (list_to_compare_element_count > base_list_element_count) {
    return false;
  }
  for (i = 0; i <= loop_end; i++) {
    if (!memcmp(list_to_compare, &base_list[i], list_to_compare_element_count * sizeof(int))) {
      return true;
    }
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_sublist>:
  endbr64
  mov    $0x0,%eax
  cmp    %rdx,%rcx
  jb     L35
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rcx,%r14
  sub    %edx,%r14d
  js     L1
  lea    0x0(,%rdx,4),%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
L5:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L7
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,%r14d
  jge    L5
  mov    $0x0,%eax
  jmp    L28
L1:
  mov    $0x0,%eax
  jmp    L28
L7:
  mov    $0x1,%eax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  ret
```

assistant: ```c
bool is_sublist(int *list_to_compare, int *base_list, size_t list_to_compare_element_count, size_t base_list_element_count) {
  int i;
  int loop_end = (base_list_element_count - list_to_compare_element_count);
  if (list_to_compare_element_count > base_list_element_count) {
    return false;
  }
  for (i = 0; i <= loop_end; i++) {
    if (!memcmp(list_to_compare, &base_list[i], list_to_compare_element_count * sizeof(int))) {
      return true;
    }
  }
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_sublist>:
  endbr64
  cmp    %rdx,%rcx
  jb     L23
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    %edx,%r14d
  js     L15
  mov    %rdi,%r13
  lea    0x0(,%rdx,4),%r12
  mov    %rsi,%rbx
  xor    %ebp,%ebp
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,%r14d
  jl     L15
L5:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L39
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L15:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool is_sublist(int *list_to_compare, int *base_list, size_t list_to_compare_element_count, size_t base_list_element_count) {
  int i;
  int loop_end = (base_list_element_count - list_to_compare_element_count);
  if (list_to_compare_element_count > base_list_element_count) {
    return false;
  }
  for (i = 0; i <= loop_end; i++) {
    if (!memcmp(list_to_compare, &base_list[i], list_to_compare_element_count * sizeof(int))) {
      return true;
    }
  }
  return false;
}
```