ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lbs_posix_add_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L0
  mov    %eax,%edx
  or     %ebp,%edx
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int lbs_posix_add_fd(int fd, int fdflags) {
  int orgfd = fcntl(fd, F_GETFD);
  if (orgfd < 0) {
    return -1;
  }
  return fcntl(fd, F_SETFD, orgfd | fdflags);
}
```
user: What is the c source code of the assembly code below?

```asm
<lbs_posix_add_fd>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L0
  mov    %eax,%edx
  mov    D15(%rip),%rax
  mov    %ebp,%edi
  or     %ebx,%edx
  mov    (%rax),%esi
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <fcntl@plt>
  xchg   %ax,%ax
L0:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int lbs_posix_add_fd(int fd, int fdflags) {
  int orgfd = fcntl(fd, F_GETFD);
  if (orgfd < 0) {
    return -1;
  }
  return fcntl(fd, F_SETFD, orgfd | fdflags);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lbs_posix_add_fd>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L9
  mov    %eax,%edx
  mov    D12(%rip),%rax
  mov    %ebp,%edi
  or     %ebx,%edx
  mov    (%rax),%esi
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <fcntl@plt>
  xchg   %ax,%ax
L9:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int lbs_posix_add_fd(int fd, int fdflags) {
  int orgfd = fcntl(fd, F_GETFD);
  if (orgfd < 0) {
    return -1;
  }
  return fcntl(fd, F_SETFD, orgfd | fdflags);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lerp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x1c(%rbp),%xmm0
  movss  D7(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x7f,0x43]}

assistant: ```c
uint8_t lerp(uint8_t a, uint8_t b, uint8_t t) {
  float T = (float)t / 255.0f;
  return (b - a) * t + b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lerp>:
  endbr64
  mov    %esi,%eax
  sub    %edi,%eax
  imul   %edx,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
uint8_t lerp(uint8_t a, uint8_t b, uint8_t t) {
  float T = (float)t / 255.0f;
  return (b - a) * t + b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lerp>:
  endbr64
  mov    %esi,%eax
  sub    %edi,%eax
  imul   %edx,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
uint8_t lerp(uint8_t a, uint8_t b, uint8_t t) {
  float T = (float)t / 255.0f;
  return (b - a) * t + b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_quicksort_partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x44(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x44(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x44(%rbp),%eax
  sub    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x44(%rbp),%eax
  imul   -0x40(%rbp),%eax
  mov    %eax,%edx
  mov    -0x44(%rbp),%eax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x40(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x24(%rbp)
L0:
  addl   $0x1,-0x28(%rbp)
  mov    -0x44(%rbp),%eax
  add    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    -0x50(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  js     L0
L15:
  subl   $0x1,-0x24(%rbp)
  mov    -0x44(%rbp),%eax
  neg    %rax
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x50(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jg     L15
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L17
  mov    -0x24(%rbp),%eax
  jmp    L13
L17:
  mov    -0x10(%rbp),%rcx
  mov    -0x44(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sort_swp@plt>
  jmp    L0
L13:
  leave
  ret
```

assistant: ```c
unsigned int _quicksort_partition(void *array, unsigned int lo, unsigned int hi, unsigned int el_size, int (*comp)(const void *, const void *)) {
  void *hold = malloc(el_size);
  void *pivot = ((char *)array) + el_size * lo;
  void *el_a = ((char *)array) + el_size * lo - el_size;
  void *el_b = ((char *)array) + el_size * hi + el_size;
  unsigned int i = lo - 1;
  unsigned int j = hi + 1;
  while (1) {
    do {
      i++;
      el_a = (char *)el_a + el_size;
    } while (comp(el_a, pivot) < 0);
    do {
      j--;
      el_b = (char *)el_b - el_size;
    } while (comp(el_b, pivot) > 0);
    if (i >= j)
      return j;
    sort_swp(el_a, el_b, el_size, hold);
  }
  free(hold);
  return j;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_quicksort_partition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r15d
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    %ecx,0x1c(%rsp)
  mov    %r8,%r12
  mov    %ecx,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  mov    %r13d,%edx
  mov    %r13d,%r14d
  imul   %r15d,%r14d
  lea    (%rbx,%r14,1),%r13
  mov    %edx,%ecx
  mov    %rcx,0x8(%rsp)
  sub    %rcx,%r14
  add    %rbx,%r14
  mov    %edx,%eax
  imul   %ebp,%eax
  add    %rcx,%rax
  add    %rax,%rbx
  sub    $0x1,%r15d
  add    $0x1,%ebp
L13:
  add    $0x1,%r15d
  add    0x8(%rsp),%r14
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   *%r12
  test   %eax,%eax
  js     L13
L11:
  sub    $0x1,%ebp
  sub    0x8(%rsp),%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   *%r12
  test   %eax,%eax
  jg     L11
  cmp    %ebp,%r15d
  jae    L4
  mov    0x10(%rsp),%rcx
  mov    0x1c(%rsp),%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <sort_swp@plt>
  jmp    L13
L4:
  mov    %ebp,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned int _quicksort_partition(void *array, unsigned int lo, unsigned int hi, unsigned int el_size, int (*comp)(const void *, const void *)) {
  void *hold = malloc(el_size);
  void *pivot = ((char *)array) + el_size * lo;
  void *el_a = ((char *)array) + el_size * lo - el_size;
  void *el_b = ((char *)array) + el_size * hi + el_size;
  unsigned int i = lo - 1;
  unsigned int j = hi + 1;
  while (1) {
    do {
      i++;
      el_a = (char *)el_a + el_size;
    } while (comp(el_a, pivot) < 0);
    do {
      j--;
      el_b = (char *)el_b - el_size;
    } while (comp(el_b, pivot) > 0);
    if (i >= j)
      return j;
    sort_swp(el_a, el_b, el_size, hold);
  }
  free(hold);
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_quicksort_partition>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %r15d,%r14d
  push   %r13
  mov    %rdi,%r13
  mov    %ecx,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  mov    %ecx,0x1c(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    0x18(%rsp),%esi
  mov    %rax,0x10(%rsp)
  mov    %edx,%eax
  imul   %r12d,%eax
  mov    %rdx,0x8(%rsp)
  add    $0x1,%r12d
  imul   %esi,%r14d
  add    %rdx,%rax
  lea    0x0(%r13,%rax,1),%r15
  lea    -0x1(%rsi),%eax
  mov    %eax,0x18(%rsp)
  lea    0x0(%r13,%r14,1),%rbp
  sub    %rdx,%r14
  neg    %rdx
  add    %r13,%r14
  mov    %rdx,%r13
  nop
L36:
  add    0x8(%rsp),%r14
  addl   $0x1,0x18(%rsp)
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   *%rbx
  test   %eax,%eax
  js     L36
  cs nopw 0x0(%rax,%rax,1)
L39:
  add    %r13,%r15
  sub    $0x1,%r12d
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   *%rbx
  test   %eax,%eax
  jg     L39
  cmp    %r12d,0x18(%rsp)
  jae    L26
  mov    0x10(%rsp),%rcx
  mov    0x1c(%rsp),%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <sort_swp@plt>
  jmp    L36
L26:
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned int _quicksort_partition(void *array, unsigned int lo, unsigned int hi, unsigned int el_size, int (*comp)(const void *, const void *)) {
  void *hold = malloc(el_size);
  void *pivot = ((char *)array) + el_size * lo;
  void *el_a = ((char *)array) + el_size * lo - el_size;
  void *el_b = ((char *)array) + el_size * hi + el_size;
  unsigned int i = lo - 1;
  unsigned int j = hi + 1;
  while (1) {
    do {
      i++;
      el_a = (char *)el_a + el_size;
    } while (comp(el_a, pivot) < 0);
    do {
      j--;
      el_b = (char *)el_b - el_size;
    } while (comp(el_b, pivot) > 0);
    if (i >= j)
      return j;
    sort_swp(el_a, el_b, el_size, hold);
  }
  free(hold);
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_quicksort_partition>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %r15d,%r14d
  push   %r13
  mov    %rdi,%r13
  mov    %ecx,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  mov    %ecx,0x1c(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    0x18(%rsp),%esi
  mov    %rax,0x10(%rsp)
  mov    %edx,%eax
  imul   %r12d,%eax
  mov    %rdx,0x8(%rsp)
  add    $0x1,%r12d
  imul   %esi,%r14d
  add    %rdx,%rax
  lea    0x0(%r13,%rax,1),%r15
  lea    -0x1(%rsi),%eax
  mov    %eax,0x18(%rsp)
  lea    0x0(%r13,%r14,1),%rbp
  sub    %rdx,%r14
  neg    %rdx
  add    %r13,%r14
  mov    %rdx,%r13
  nop
L8:
  add    0x8(%rsp),%r14
  addl   $0x1,0x18(%rsp)
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   *%rbx
  test   %eax,%eax
  js     L8
  cs nopw 0x0(%rax,%rax,1)
L20:
  add    %r13,%r15
  sub    $0x1,%r12d
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   *%rbx
  test   %eax,%eax
  jg     L20
  cmp    %r12d,0x18(%rsp)
  jae    L32
  mov    0x10(%rsp),%rcx
  mov    0x1c(%rsp),%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <sort_swp@plt>
  jmp    L8
L32:
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned int _quicksort_partition(void *array, unsigned int lo, unsigned int hi, unsigned int el_size, int (*comp)(const void *, const void *)) {
  void *hold = malloc(el_size);
  void *pivot = ((char *)array) + el_size * lo;
  void *el_a = ((char *)array) + el_size * lo - el_size;
  void *el_b = ((char *)array) + el_size * hi + el_size;
  unsigned int i = lo - 1;
  unsigned int j = hi + 1;
  while (1) {
    do {
      i++;
      el_a = (char *)el_a + el_size;
    } while (comp(el_a, pivot) < 0);
    do {
      j--;
      el_b = (char *)el_b - el_size;
    } while (comp(el_b, pivot) > 0);
    if (i >= j)
      return j;
    sort_swp(el_a, el_b, el_size, hold);
  }
  free(hold);
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotateString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverseString@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <reverseString@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverseString@plt>
  nop
  leave
  ret
```

assistant: ```c
void rotateString(char *buffer, size_t length, size_t increments) {
  increments %= length;
  reverseString(buffer, 0, increments);
  reverseString(buffer, increments, length);
  reverseString(buffer, 0, length);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rotateString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%r12
  mov    $0x0,%esi
  call   <reverseString@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <reverseString@plt>
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <reverseString@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rotateString(char *buffer, size_t length, size_t increments) {
  increments %= length;
  reverseString(buffer, 0, increments);
  reverseString(buffer, increments, length);
  reverseString(buffer, 0, length);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotateString>:
  endbr64
  mov    %rdx,%rax
  xor    %edx,%edx
  push   %r13
  div    %rsi
  push   %r12
  push   %rbp
  mov    %rsi,%r12
  mov    %rdi,%rbp
  xor    %esi,%esi
  mov    %rdx,%r13
  call   <reverseString@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <reverseString@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <reverseString@plt>
```

assistant: ```c
void rotateString(char *buffer, size_t length, size_t increments) {
  increments %= length;
  reverseString(buffer, 0, increments);
  reverseString(buffer, increments, length);
  reverseString(buffer, 0, length);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotateString>:
  endbr64
  mov    %rdx,%rax
  xor    %edx,%edx
  push   %r13
  div    %rsi
  push   %r12
  push   %rbp
  mov    %rsi,%r12
  mov    %rdi,%rbp
  xor    %esi,%esi
  mov    %rdx,%r13
  call   <reverseString@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <reverseString@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <reverseString@plt>
```

assistant: ```c
void rotateString(char *buffer, size_t length, size_t increments) {
  increments %= length;
  reverseString(buffer, 0, increments);
  reverseString(buffer, increments, length);
  reverseString(buffer, 0, length);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <skipspaces@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L1
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <next_is_not_constituent@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L15
L1:
  mov    $0x1,%eax
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: string

tool: D1: %lf

tool: D16: f64

assistant: ```c
int read_double(void *dest) {
  skipspaces();
  if (scanf("%lf", (double *)dest) == 1) {
    scanf("f64");
    return next_is_not_constituent() ? 0 : 1;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_double>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <skipspaces@plt>
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  je     L4
L1:
  pop    %rbx
  ret
L4:
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <next_is_not_constituent@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L1
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D18
datatype: string

tool: D8: %lf

tool: D18: f64

assistant: ```c
int read_double(void *dest) {
  skipspaces();
  if (scanf("%lf", (double *)dest) == 1) {
    scanf("f64");
    return next_is_not_constituent() ? 0 : 1;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_double>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <skipspaces@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x1,%r8d
  je     L3
  pop    %rbp
  ret
L3:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %eax,%eax
  call   <next_is_not_constituent@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string
name: read_data
arguments: tag: D19
type: string

tool: D7: %lf

tool: D19: f64

assistant: ```c
int read_double(void *dest) {
  skipspaces();
  if (scanf("%lf", (double *)dest) == 1) {
    scanf("f64");
    return next_is_not_constituent() ? 0 : 1;
  } else {
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<read_double>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <skipspaces@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x1,%r8d
  je     L3
  pop    %rbp
  ret
L3:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %eax,%eax
  call   <next_is_not_constituent@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string
name: unpack_data
arguments: label: D19
datatype: string

tool: D9: %lf

tool: D19: f64

assistant: ```c
int read_double(void *dest) {
  skipspaces();
  if (scanf("%lf", (double *)dest) == 1) {
    scanf("f64");
    return next_is_not_constituent() ? 0 : 1;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PrintHelp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: Usage: %s --username <username> --password <password> [options...]
 -f, --iface <ifname>
 -n, --dns <dns>
 -t, --hostname <hostname>
 -s, --udp-server <server>
 -c, --cli-version <client version>
 -h, --hash <hash>
 -D, --debug
 -o, --logoff


assistant: ```c
void PrintHelp(const char *argn) {
  printf("Usage: %s --username <username> --password <password> [options...]\n"
         " -f, --iface <ifname>\n"
         " -n, --dns <dns>\n"
         " -t, --hostname <hostname>\n"
         " -s, --udp-server <server>\n"
         " -c, --cli-version <client version>\n"
         " -h, --hash <hash>\n"
         " -D, --debug\n"
         " -o, --logoff\n",
         argn);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<PrintHelp>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5: Usage: %s --username <username> --password <password> [options...]
 -f, --iface <ifname>
 -n, --dns <dns>
 -t, --hostname <hostname>
 -s, --udp-server <server>
 -c, --cli-version <client version>
 -h, --hash <hash>
 -D, --debug
 -o, --logoff


assistant: ```c
void PrintHelp(const char *argn) {
  printf("Usage: %s --username <username> --password <password> [options...]\n"
         " -f, --iface <ifname>\n"
         " -n, --dns <dns>\n"
         " -t, --hostname <hostname>\n"
         " -s, --udp-server <server>\n"
         " -c, --cli-version <client version>\n"
         " -h, --hash <hash>\n"
         " -D, --debug\n"
         " -o, --logoff\n",
         argn);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<PrintHelp>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D4: Usage: %s --username <username> --password <password> [options...]
 -f, --iface <ifname>
 -n, --dns <dns>
 -t, --hostname <hostname>
 -s, --udp-server <server>
 -c, --cli-version <client version>
 -h, --hash <hash>
 -D, --debug
 -o, --logoff


assistant: ```c
void PrintHelp(const char *argn) {
  printf("Usage: %s --username <username> --password <password> [options...]\n"
         " -f, --iface <ifname>\n"
         " -n, --dns <dns>\n"
         " -t, --hostname <hostname>\n"
         " -s, --udp-server <server>\n"
         " -c, --cli-version <client version>\n"
         " -h, --hash <hash>\n"
         " -D, --debug\n"
         " -o, --logoff\n",
         argn);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<PrintHelp>:
  endbr64
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: Usage: %s --username <username> --password <password> [options...]
 -f, --iface <ifname>
 -n, --dns <dns>
 -t, --hostname <hostname>
 -s, --udp-server <server>
 -c, --cli-version <client version>
 -h, --hash <hash>
 -D, --debug
 -o, --logoff


assistant: ```c
void PrintHelp(const char *argn) {
  printf("Usage: %s --username <username> --password <password> [options...]\n"
         " -f, --iface <ifname>\n"
         " -n, --dns <dns>\n"
         " -t, --hostname <hostname>\n"
         " -s, --udp-server <server>\n"
         " -c, --cli-version <client version>\n"
         " -h, --hash <hash>\n"
         " -D, --debug\n"
         " -o, --logoff\n",
         argn);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <get@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <get@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L13
  pxor   %xmm0,%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jne    L13
  mov    $0x0,%eax
  call   <screwUp@plt>
  jmp    L3
L13:
  movss  -0xc(%rbp),%xmm0
  divss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D9
type_infered: string
name: parse_data
arguments: data_label: D25
type_infered: string

tool: D17: Enter your first number

tool: D9: Enter your second number (not 0)

tool: D25: Result: %f

assistant: ```c
void divide() {
  float firstNum = get("Enter your first number");
  float secondNum = get("Enter your second number (not 0)");
  if (secondNum == 0) {
    screwUp();
    return;
  }
  float result = firstNum / secondNum;
  printf("Result: %f", result);
}
```