ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  movl   $0x0,-0x44(%rbp)
  mov    %rax,-0x58(%rbp)
  mov    -0x3c(%rbp),%eax
  test   %eax,%eax
  jle    L46
  nopl   0x0(%rax)
L135:
  mov    -0x58(%rbp),%rsi
  mov    %rbx,%rdi
  mov    %rsp,-0x50(%rbp)
  call   <scanf@plt>
  movslq -0x40(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rdx
  sub    %rdi,%rcx
  cmp    %rcx,%rsp
  je     L6
L107:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L107
L6:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L80
  orq    $0x0,-0x8(%rsp,%rdx,1)
L80:
  mov    %rax,%rdx
  mov    %rsp,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%r12
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L86
L96:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L96
L86:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L111
L126:
  mov    %rsp,%r14
  test   %esi,%esi
  jle    L82
  mov    %r12,%r15
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  add    $0x4,%r15
  call   <scanf@plt>
  mov    -0x40(%rbp),%esi
  cmp    %r13d,%esi
  jg     L3
  test   %esi,%esi
  jle    L82
  mov    %r14,%r15
  xor    %r13d,%r13d
  nopl   (%rax)
L76:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  add    $0x4,%r15
  call   <scanf@plt>
  mov    -0x40(%rbp),%esi
  cmp    %r13d,%esi
  jg     L76
L82:
  mov    %r12,%rdi
  call   <sort@plt>
  mov    -0x40(%rbp),%esi
  mov    %r14,%rdi
  call   <sort@plt>
  mov    -0x40(%rbp),%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sum@plt>
  addl   $0x1,-0x44(%rbp)
  mov    -0x50(%rbp),%rsp
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  jg     L135
L46:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L111:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L126
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: %d

assistant: ```c
int main() {
  int n, t, i, j;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n);
    int a[n], b[n];
    for (j = 0; j < n; j++) {
      scanf("%d", &a[j]);
    }
    for (j = 0; j < n; j++) {
      scanf("%d", &b[j]);
    }
    sort(a, n);
    sort(b, n);
    sum(a, b, n);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  movl   $0x0,-0x44(%rbp)
  mov    %rax,-0x58(%rbp)
  mov    -0x3c(%rbp),%eax
  test   %eax,%eax
  jle    L56
  nopl   0x0(%rax)
L62:
  mov    -0x58(%rbp),%rsi
  mov    %rbx,%rdi
  mov    %rsp,-0x50(%rbp)
  call   <scanf@plt>
  movslq -0x40(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rdx
  sub    %rdi,%rcx
  cmp    %rcx,%rsp
  je     L76
L129:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L129
L76:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L75
  orq    $0x0,-0x8(%rsp,%rdx,1)
L75:
  mov    %rax,%rdx
  mov    %rsp,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%r12
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L9
L35:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L35
L9:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L121
L36:
  mov    %rsp,%r14
  test   %esi,%esi
  jle    L42
  mov    %r12,%r15
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  add    $0x4,%r15
  call   <scanf@plt>
  mov    -0x40(%rbp),%esi
  cmp    %r13d,%esi
  jg     L30
  test   %esi,%esi
  jle    L42
  mov    %r14,%r15
  xor    %r13d,%r13d
  nopl   (%rax)
L16:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  add    $0x4,%r15
  call   <scanf@plt>
  mov    -0x40(%rbp),%esi
  cmp    %r13d,%esi
  jg     L16
L42:
  mov    %r12,%rdi
  call   <sort@plt>
  mov    -0x40(%rbp),%esi
  mov    %r14,%rdi
  call   <sort@plt>
  mov    -0x40(%rbp),%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sum@plt>
  addl   $0x1,-0x44(%rbp)
  mov    -0x50(%rbp),%rsp
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  jg     L62
L56:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L121:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L36
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: %d

assistant: ```c
int main() {
  int n, t, i, j;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n);
    int a[n], b[n];
    for (j = 0; j < n; j++) {
      scanf("%d", &a[j]);
    }
    for (j = 0; j < n; j++) {
      scanf("%d", &b[j]);
    }
    sort(a, n);
    sort(b, n);
    sum(a, b, n);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<attrs_cleanout_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9d,-0x3c(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L50
L34:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  mov    -0x3c(%rbp),%eax
  and    $0x1,%eax
  xor    %edx,%eax
  test   %al,%al
  jne    L49
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L27
  addq   $0x1,-0x8(%rbp)
  jmp    L29
L27:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
  jmp    L29
L49:
  nop
L29:
  addq   $0x1,-0x10(%rbp)
L50:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jb     L34
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int attrs_cleanout_name(char *del_name, size_t *num_attrs, char **names, size_t *value_lengths, char **values, int flag) {
  size_t i, w;
  for (w = i = 0; i < *num_attrs; i++) {
    if ((strcmp(names[i], del_name) == 0) ^ (flag & 1))
      continue;
    if (w == i) {
      w++;
      continue;
    }
    names[w] = names[i];
    value_lengths[w] = value_lengths[i];
    values[w] = values[i];
    names[i] = values[i] = NULL;
    value_lengths[i] = 0;
    w++;
  }
  *num_attrs = w;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<attrs_cleanout_name>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,%r13
  mov    (%rsi),%rbp
  test   %rbp,%rbp
  je     L12
  mov    %rdx,%r12
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  mov    %r9d,%eax
  and    $0x1,%eax
  mov    %al,0xf(%rsp)
  jmp    L52
L10:
  add    $0x1,%rbp
L51:
  add    $0x1,%rbx
  cmp    %rbx,0x0(%r13)
  jbe    L12
L52:
  mov    (%r12,%rbx,8),%rdi
  mov    (%rsp),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  cmp    0xf(%rsp),%al
  jne    L51
  cmp    %rbp,%rbx
  je     L10
  mov    (%r12,%rbx,8),%rax
  mov    %rax,(%r12,%rbp,8)
  mov    (%r14,%rbx,8),%rax
  mov    %rax,(%r14,%rbp,8)
  mov    (%r15,%rbx,8),%rax
  mov    %rax,(%r15,%rbp,8)
  movq   $0x0,(%r15,%rbx,8)
  movq   $0x0,(%r12,%rbx,8)
  movq   $0x0,(%r14,%rbx,8)
  add    $0x1,%rbp
  jmp    L51
L12:
  mov    %rbp,0x0(%r13)
  mov    $0x1,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int attrs_cleanout_name(char *del_name, size_t *num_attrs, char **names, size_t *value_lengths, char **values, int flag) {
  size_t i, w;
  for (w = i = 0; i < *num_attrs; i++) {
    if ((strcmp(names[i], del_name) == 0) ^ (flag & 1))
      continue;
    if (w == i) {
      w++;
      continue;
    }
    names[w] = names[i];
    value_lengths[w] = value_lengths[i];
    values[w] = values[i];
    names[i] = values[i] = NULL;
    value_lengths[i] = 0;
    w++;
  }
  *num_attrs = w;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<attrs_cleanout_name>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%r14
  mov    %rsi,(%rsp)
  test   %r14,%r14
  je     L12
  mov    %r9d,%eax
  mov    %rdi,%r15
  mov    %rdx,%rbp
  mov    %rcx,%r12
  and    $0x1,%eax
  mov    %r8,%r13
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  mov    %al,0xf(%rsp)
  nopl   (%rax)
L8:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  cmp    0xf(%rsp),%al
  jne    L0
  lea    0x1(%r14),%rax
  cmp    %rbx,%r14
  je     L34
  mov    0x0(%rbp,%rbx,8),%rcx
  mov    %rcx,0x0(%rbp,%r14,8)
  mov    (%r12,%rbx,8),%rcx
  mov    %rcx,(%r12,%r14,8)
  mov    0x0(%r13,%rbx,8),%rcx
  mov    %rcx,0x0(%r13,%r14,8)
  mov    %rax,%r14
  movq   $0x0,0x0(%r13,%rbx,8)
  movq   $0x0,0x0(%rbp,%rbx,8)
  movq   $0x0,(%r12,%rbx,8)
L0:
  mov    (%rsp),%rax
  add    $0x1,%rbx
  cmp    %rbx,(%rax)
  ja     L8
L12:
  mov    (%rsp),%rax
  mov    %r14,(%rax)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rax,%r14
  jmp    L0
```

assistant: ```c
int attrs_cleanout_name(char *del_name, size_t *num_attrs, char **names, size_t *value_lengths, char **values, int flag) {
  size_t i, w;
  for (w = i = 0; i < *num_attrs; i++) {
    if ((strcmp(names[i], del_name) == 0) ^ (flag & 1))
      continue;
    if (w == i) {
      w++;
      continue;
    }
    names[w] = names[i];
    value_lengths[w] = value_lengths[i];
    values[w] = values[i];
    names[i] = values[i] = NULL;
    value_lengths[i] = 0;
    w++;
  }
  *num_attrs = w;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<attrs_cleanout_name>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%r14
  mov    %rsi,(%rsp)
  test   %r14,%r14
  je     L28
  mov    %r9d,%eax
  mov    %rdi,%r15
  mov    %rdx,%rbp
  mov    %rcx,%r12
  and    $0x1,%eax
  mov    %r8,%r13
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  mov    %al,0xf(%rsp)
  nopl   (%rax)
L42:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  cmp    0xf(%rsp),%al
  jne    L38
  lea    0x1(%r14),%rax
  cmp    %rbx,%r14
  je     L47
  mov    0x0(%rbp,%rbx,8),%rcx
  mov    %rcx,0x0(%rbp,%r14,8)
  mov    (%r12,%rbx,8),%rcx
  mov    %rcx,(%r12,%r14,8)
  mov    0x0(%r13,%rbx,8),%rcx
  mov    %rcx,0x0(%r13,%r14,8)
  mov    %rax,%r14
  movq   $0x0,0x0(%r13,%rbx,8)
  movq   $0x0,0x0(%rbp,%rbx,8)
  movq   $0x0,(%r12,%rbx,8)
L38:
  mov    (%rsp),%rax
  add    $0x1,%rbx
  cmp    %rbx,(%rax)
  ja     L42
L28:
  mov    (%rsp),%rax
  mov    %r14,(%rax)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %rax,%r14
  jmp    L38
```

assistant: ```c
int attrs_cleanout_name(char *del_name, size_t *num_attrs, char **names, size_t *value_lengths, char **values, int flag) {
  size_t i, w;
  for (w = i = 0; i < *num_attrs; i++) {
    if ((strcmp(names[i], del_name) == 0) ^ (flag & 1))
      continue;
    if (w == i) {
      w++;
      continue;
    }
    names[w] = names[i];
    value_lengths[w] = value_lengths[i];
    values[w] = values[i];
    names[i] = values[i] = NULL;
    value_lengths[i] = 0;
    w++;
  }
  *num_attrs = w;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<coco_min_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jb     L12
  movsd  -0x8(%rbp),%xmm0
  jmp    L18
L12:
  movsd  -0x10(%rbp),%xmm0
L18:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double coco_min_double(const double a, const double b) {
  if (a <= b) {
    return a;
  } else {
    return b;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<coco_min_double>:
  endbr64
  movapd %xmm0,%xmm2
  cmplesd %xmm1,%xmm2
  andpd  %xmm2,%xmm0
  andnpd %xmm1,%xmm2
  orpd   %xmm2,%xmm0
  ret
```

assistant: ```c
double coco_min_double(const double a, const double b) {
  if (a <= b) {
    return a;
  } else {
    return b;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<coco_min_double>:
  endbr64
  movapd %xmm0,%xmm2
  cmplesd %xmm1,%xmm2
  andpd  %xmm2,%xmm0
  andnpd %xmm1,%xmm2
  orpd   %xmm2,%xmm0
  ret
```

assistant: ```c
double coco_min_double(const double a, const double b) {
  if (a <= b) {
    return a;
  } else {
    return b;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<coco_min_double>:
  endbr64
  movapd %xmm0,%xmm2
  cmplesd %xmm1,%xmm2
  andpd  %xmm2,%xmm0
  andnpd %xmm1,%xmm2
  orpd   %xmm2,%xmm0
  ret
```

assistant: ```c
double coco_min_double(const double a, const double b) {
  if (a <= b) {
    return a;
  } else {
    return b;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ZopfliGetDistExtraBitsValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  ja     L13
  mov    $0x0,%eax
  jmp    L6
L13:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  bsr    %eax,%eax
  xor    $0x1f,%eax
  xor    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  sub    $0x1,%eax
  and    %edx,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
unsigned ZopfliGetDistExtraBitsValue(unsigned dist) {
  if (dist < 5) {
    return 0;
  }
  int l = 31 ^ __builtin_clz(dist - 1);
  return (dist - (1 + (1 << l))) & ((1 << (l - 1)) - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ZopfliGetDistExtraBitsValue>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x4,%edi
  jbe    L1
  sub    $0x1,%edi
  bsr    %edi,%esi
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%edx
  mov    %edx,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  sub    %edx,%edi
  and    %edi,%eax
L1:
  ret
```

assistant: ```c
unsigned ZopfliGetDistExtraBitsValue(unsigned dist) {
  if (dist < 5) {
    return 0;
  }
  int l = 31 ^ __builtin_clz(dist - 1);
  return (dist - (1 + (1 << l))) & ((1 << (l - 1)) - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ZopfliGetDistExtraBitsValue>:
  endbr64
  xor    %eax,%eax
  cmp    $0x4,%edi
  jbe    L5
  sub    $0x1,%edi
  mov    $0x1,%edx
  bsr    %edi,%esi
  mov    %edx,%eax
  lea    -0x1(%rsi),%ecx
  shl    %cl,%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  sub    $0x1,%eax
  sub    %edx,%edi
  and    %edi,%eax
L5:
  ret
```

assistant: ```c
unsigned ZopfliGetDistExtraBitsValue(unsigned dist) {
  if (dist < 5) {
    return 0;
  }
  int l = 31 ^ __builtin_clz(dist - 1);
  return (dist - (1 + (1 << l))) & ((1 << (l - 1)) - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ZopfliGetDistExtraBitsValue>:
  endbr64
  xor    %eax,%eax
  cmp    $0x4,%edi
  jbe    L8
  sub    $0x1,%edi
  mov    $0x1,%edx
  bsr    %edi,%esi
  mov    %edx,%eax
  lea    -0x1(%rsi),%ecx
  shl    %cl,%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  sub    $0x1,%eax
  sub    %edx,%edi
  and    %edi,%eax
L8:
  ret
```

assistant: ```c
unsigned ZopfliGetDistExtraBitsValue(unsigned dist) {
  if (dist < 5) {
    return 0;
  }
  int l = 31 ^ __builtin_clz(dist - 1);
  return (dist - (1 + (1 << l))) & ((1 << (l - 1)) - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<resultlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L11
L4:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L11:
  leave
  ret
```

assistant: ```c
int resultlen(const char *result) {
  const char *hpos = strchr(result, '-');
  if (hpos)
    return hpos - result;
  return strlen(result);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<resultlen>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  sub    %ebx,%eax
L8:
  pop    %rbx
  ret
L3:
  mov    %rbx,%rdi
  call   <strlen@plt>
  jmp    L8
```

assistant: ```c
int resultlen(const char *result) {
  const char *hpos = strchr(result, '-');
  if (hpos)
    return hpos - result;
  return strlen(result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<resultlen>:
  endbr64
  push   %rbp
  mov    $0x2d,%esi
  mov    %rdi,%rbp
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  sub    %ebp,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
int resultlen(const char *result) {
  const char *hpos = strchr(result, '-');
  if (hpos)
    return hpos - result;
  return strlen(result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<resultlen>:
  endbr64
  push   %rbp
  mov    $0x2d,%esi
  mov    %rdi,%rbp
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  sub    %ebp,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
int resultlen(const char *result) {
  const char *hpos = strchr(result, '-');
  if (hpos)
    return hpos - result;
  return strlen(result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ss2i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x60,-0x4(%rbp)
  jle    L12
  cmpb   $0x7a,-0x4(%rbp)
  jg     L12
  movzbl -0x4(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x4(%rbp)
L12:
  movsbl -0x4(%rbp),%eax
  sub    $0x9,%eax
  cmp    $0x75,%eax
  ja     L114
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D14(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D14(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L173
  mov    $0x0,%eax
  jmp    L173
  mov    $0x0,%eax
  jmp    L173
  mov    $0x1,%eax
  jmp    L173
  mov    $0x2,%eax
  jmp    L173
  mov    $0x3,%eax
  jmp    L173
  mov    $0x3,%eax
  jmp    L173
  mov    $0x4,%eax
  jmp    L173
  mov    $0x5,%eax
  jmp    L173
  mov    $0x6,%eax
  jmp    L173
  mov    $0x7,%eax
  jmp    L173
  mov    $0x3,%eax
  jmp    L173
  mov    $0xffffffff,%eax
  jmp    L173
  mov    $0xffffffff,%eax
  jmp    L173
  mov    $0xffffffff,%eax
  jmp    L173
L114:
  mov    $0xfffffffe,%eax
L173:
  pop    %rbp
  ret
```

assistant: ```c
char ss2i(char c) {
  if (c >= 'a' && c <= 'z')
    c += 'A' - 'a';
  switch (c) {
  case '.':
    return 0;
  case '-':
    return 0;
  case 'X':
    return 0;
  case 'H':
    return 1;
  case 'E':
    return 2;
  case 'C':
    return 3;
  case '~':
    return 3;
  case 'S':
    return 4;
  case 'T':
    return 5;
  case 'G':
    return 6;
  case 'B':
    return 7;
  case 'I':
    return 3;
  case ' ':
    return -1;
  case '\t':
    return -1;
  case '\n':
    return -1;
  }
  return -2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ss2i>:
  endbr64
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovb  %eax,%edi
  sub    $0x9,%edi
  cmp    $0x75,%dil
  ja     L1
  movzbl %dil,%edi
  lea    D0(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0xffffffff,%eax
  ret
  mov    $0xffffffff,%eax
  ret
  mov    $0xffffffff,%eax
  ret
L1:
  mov    $0xfffffffe,%eax
  ret
  mov    $0x0,%eax
  ret
```

assistant: ```c
char ss2i(char c) {
  if (c >= 'a' && c <= 'z')
    c += 'A' - 'a';
  switch (c) {
  case '.':
    return 0;
  case '-':
    return 0;
  case 'X':
    return 0;
  case 'H':
    return 1;
  case 'E':
    return 2;
  case 'C':
    return 3;
  case '~':
    return 3;
  case 'S':
    return 4;
  case 'T':
    return 5;
  case 'G':
    return 6;
  case 'B':
    return 7;
  case 'I':
    return 3;
  case ' ':
    return -1;
  case '\t':
    return -1;
  case '\n':
    return -1;
  }
  return -2;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <link@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <link@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string
name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D8
datatype: string
name: read_data
arguments: data_label: D48
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D0: malloc.c

tool: D5: sysmalloc.c

tool: D8: Using memory allocation package: %s


tool: D48: mallocwrapper.c

tool: D4: plainwrapper.c

assistant: ```c
int main() {
  unlink("malloc.c");
  printf("Using memory allocation package: %s\n", "sysmalloc.c");
  link("plainwrapper.c", "mallocwrapper.c");
  link("sysmalloc.c", "malloc.c");
  return 0;
}
```