ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<WriteEnd>:
  endbr64
  push   %rbx
  mov    $0x5,%ebx
L0:
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  sub    $0x1,%ebx
  jne    L0
  mov    $0x3b9aca00,%esi
  xor    %edi,%edi
  pop    %rbx
  jmp    1070 <WriteTone@plt>
```

assistant: ```c
void WriteEnd() {
  for (int i = 0; i < 5; i++)
    WriteFSK(1);
  WriteTone(0, 1e9);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L18:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D9: 


assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  int i;
  i = 0;
  while (s[i])
    i++;
  write(fd, s, i);
  write(fd, "\n", 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmpb   $0x0,(%rdi)
  je     L12
  mov    $0x1,%eax
L29:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L29
L24:
  mov    %rdi,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  mov    $0x1,%edx
  lea    D0(%rip),%rsi
  mov    %ebx,%edi
  call   <write@plt>
  pop    %rbx
  ret
L12:
  mov    $0x0,%edx
  jmp    L24
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: 


assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  int i;
  i = 0;
  while (s[i])
    i++;
  write(fd, s, i);
  write(fd, "\n", 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r8
  mov    %esi,%ebp
  je     L27
  mov    $0x1,%eax
  nopl   0x0(%rax)
L3:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%r8,%rax,1)
  jne    L3
L2:
  mov    %ebp,%edi
  mov    %r8,%rsi
  call   <write@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    $0x1,%edx
  lea    D3(%rip),%rsi
  jmp    1050 <write@plt>
  nopl   0x0(%rax)
L27:
  xor    %edx,%edx
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: 


assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  int i;
  i = 0;
  while (s[i])
    i++;
  write(fd, s, i);
  write(fd, "\n", 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r8
  mov    %esi,%ebp
  je     L8
  mov    $0x1,%eax
  nopl   0x0(%rax)
L11:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%r8,%rax,1)
  jne    L11
L14:
  mov    %ebp,%edi
  mov    %r8,%rsi
  call   <write@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    $0x1,%edx
  lea    D2(%rip),%rsi
  jmp    1050 <write@plt>
  nopl   0x0(%rax)
L8:
  xor    %edx,%edx
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D2: 


assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  int i;
  i = 0;
  while (s[i])
    i++;
  write(fd, s, i);
  write(fd, "\n", 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pdist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double pdist(double *v1) {
  double ss = 0;
  ss += v1[0] * v1[0];
  ss += v1[1] * v1[1];
  ss += v1[2] * v1[2];
  return sqrt(ss);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pdist>:
  endbr64
  movsd  (%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm2
  ja     L1
  sqrtsd %xmm0,%xmm0
  ret
L1:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double pdist(double *v1) {
  double ss = 0;
  ss += v1[0] * v1[0];
  ss += v1[1] * v1[1];
  ss += v1[2] * v1[2];
  return sqrt(ss);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pdist>:
  endbr64
  movsd  (%rdi),%xmm0
  pxor   %xmm2,%xmm2
  mulsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  addsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm2
  ja     L0
  sqrtsd %xmm0,%xmm0
  ret
L0:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double pdist(double *v1) {
  double ss = 0;
  ss += v1[0] * v1[0];
  ss += v1[1] * v1[1];
  ss += v1[2] * v1[2];
  return sqrt(ss);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pdist>:
  endbr64
  movsd  (%rdi),%xmm0
  pxor   %xmm2,%xmm2
  mulsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  addsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm2
  ja     L6
  sqrtsd %xmm0,%xmm0
  ret
L6:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double pdist(double *v1) {
  double ss = 0;
  ss += v1[0] * v1[0];
  ss += v1[1] * v1[1];
  ss += v1[2] * v1[2];
  return sqrt(ss);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uDMAChannelAttributeDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  andq   $0x1f,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L29
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    $0x400ff01c,%edx
  cltq
  mov    %rax,(%rdx)
L29:
  mov    -0x10(%rbp),%rax
  and    $0x2,%eax
  test   %rax,%rax
  je     L28
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    $0x400ff034,%edx
  cltq
  mov    %rax,(%rdx)
L28:
  mov    -0x10(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    $0x400ff03c,%edx
  cltq
  mov    %rax,(%rdx)
L1:
  mov    -0x10(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L6
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    $0x400ff024,%edx
  cltq
  mov    %rax,(%rdx)
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uDMAChannelAttributeDisable(unsigned long ulChannelNum, unsigned long ulAttr) {
  ;

  ;
  ulChannelNum &= 0x1f;
  if (ulAttr & 0x00000001) {
    (*((volatile unsigned long *)(0x400FF000 + 0x0000001C))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000002) {
    (*((volatile unsigned long *)(0x400FF000 + 0x00000034))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000004) {
    (*((volatile unsigned long *)(0x400FF000 + 0x0000003C))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000008) {
    (*((volatile unsigned long *)(0x400FF000 + 0x00000024))) = 1 << ulChannelNum;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uDMAChannelAttributeDisable>:
  endbr64
  mov    %rdi,%rcx
  and    $0x1f,%ecx
  test   $0x1,%sil
  je     L32
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff01c
L32:
  test   $0x2,%sil
  je     L0
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff034
L0:
  test   $0x4,%sil
  je     L22
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff03c
L22:
  test   $0x8,%sil
  je     L27
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff024
L27:
  ret
```

assistant: ```c
void uDMAChannelAttributeDisable(unsigned long ulChannelNum, unsigned long ulAttr) {
  ;

  ;
  ulChannelNum &= 0x1f;
  if (ulAttr & 0x00000001) {
    (*((volatile unsigned long *)(0x400FF000 + 0x0000001C))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000002) {
    (*((volatile unsigned long *)(0x400FF000 + 0x00000034))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000004) {
    (*((volatile unsigned long *)(0x400FF000 + 0x0000003C))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000008) {
    (*((volatile unsigned long *)(0x400FF000 + 0x00000024))) = 1 << ulChannelNum;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uDMAChannelAttributeDisable>:
  endbr64
  mov    %rdi,%rcx
  and    $0x1f,%ecx
  test   $0x1,%sil
  je     L12
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff01c
L12:
  test   $0x2,%sil
  je     L20
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff034
L20:
  test   $0x4,%sil
  je     L9
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff03c
L9:
  and    $0x8,%esi
  je     L2
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff024
L2:
  ret
```

assistant: ```c
void uDMAChannelAttributeDisable(unsigned long ulChannelNum, unsigned long ulAttr) {
  ;

  ;
  ulChannelNum &= 0x1f;
  if (ulAttr & 0x00000001) {
    (*((volatile unsigned long *)(0x400FF000 + 0x0000001C))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000002) {
    (*((volatile unsigned long *)(0x400FF000 + 0x00000034))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000004) {
    (*((volatile unsigned long *)(0x400FF000 + 0x0000003C))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000008) {
    (*((volatile unsigned long *)(0x400FF000 + 0x00000024))) = 1 << ulChannelNum;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uDMAChannelAttributeDisable>:
  endbr64
  mov    %rdi,%rcx
  and    $0x1f,%ecx
  test   $0x1,%sil
  je     L34
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff01c
L34:
  test   $0x2,%sil
  je     L18
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff034
L18:
  test   $0x4,%sil
  je     L38
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff03c
L38:
  and    $0x8,%esi
  je     L30
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  mov    %rax,0x400ff024
L30:
  ret
```

assistant: ```c
void uDMAChannelAttributeDisable(unsigned long ulChannelNum, unsigned long ulAttr) {
  ;

  ;
  ulChannelNum &= 0x1f;
  if (ulAttr & 0x00000001) {
    (*((volatile unsigned long *)(0x400FF000 + 0x0000001C))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000002) {
    (*((volatile unsigned long *)(0x400FF000 + 0x00000034))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000004) {
    (*((volatile unsigned long *)(0x400FF000 + 0x0000003C))) = 1 << ulChannelNum;
  }
  if (ulAttr & 0x00000008) {
    (*((volatile unsigned long *)(0x400FF000 + 0x00000024))) = 1 << ulChannelNum;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x123,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    $0x123,%rax
  je     L3
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  je     L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  lea    -0x20(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L31
  mov    $0x0,%eax
  call   <abort@plt>
L31:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int main(void) {
  void *a, *a_1, *a_2;
  a = (void *)0x123;
#pragma acc data copyout(a_1, a_2)
#pragma acc kernels deviceptr(a)
  {
    a_1 = a;
    a_2 = &a;
  }
  if (a != (void *)0x123)
    abort();
  if (a_1 != a)
    abort();
  if (a_2 == &a)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  void *a, *a_1, *a_2;
  a = (void *)0x123;
#pragma acc data copyout(a_1, a_2)
#pragma acc kernels deviceptr(a)
  {
    a_1 = a;
    a_2 = &a;
  }
  if (a != (void *)0x123)
    abort();
  if (a_1 != a)
    abort();
  if (a_2 == &a)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  void *a, *a_1, *a_2;
  a = (void *)0x123;
#pragma acc data copyout(a_1, a_2)
#pragma acc kernels deviceptr(a)
  {
    a_1 = a;
    a_2 = &a;
  }
  if (a != (void *)0x123)
    abort();
  if (a_1 != a)
    abort();
  if (a_2 == &a)
    abort();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  void *a, *a_1, *a_2;
  a = (void *)0x123;
#pragma acc data copyout(a_1, a_2)
#pragma acc kernels deviceptr(a)
  {
    a_1 = a;
    a_2 = &a;
  }
  if (a != (void *)0x123)
    abort();
  if (a_1 != a)
    abort();
  if (a_2 == &a)
    abort();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TransformCounterC__0__Counter__overflow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <CounterToLocalTimeC__0__Counter__overflow@plt>
  mov    $0x0,%eax
  call   <TransformAlarmC__0__Counter__overflow@plt>
  mov    $0x0,%eax
  call   <Atm128Rfa1SerialP__Counter__overflow@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TransformCounterC__0__Counter__overflow(void) {
  CounterToLocalTimeC__0__Counter__overflow();
  TransformAlarmC__0__Counter__overflow();
  Atm128Rfa1SerialP__Counter__overflow();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TransformCounterC__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CounterToLocalTimeC__0__Counter__overflow@plt>
  mov    $0x0,%eax
  call   <TransformAlarmC__0__Counter__overflow@plt>
  mov    $0x0,%eax
  call   <Atm128Rfa1SerialP__Counter__overflow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void TransformCounterC__0__Counter__overflow(void) {
  CounterToLocalTimeC__0__Counter__overflow();
  TransformAlarmC__0__Counter__overflow();
  Atm128Rfa1SerialP__Counter__overflow();
}
```
user: What is the c source code of the assembly code below?

```asm
<TransformCounterC__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CounterToLocalTimeC__0__Counter__overflow@plt>
  xor    %eax,%eax
  call   <TransformAlarmC__0__Counter__overflow@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <Atm128Rfa1SerialP__Counter__overflow@plt>
```

assistant: ```c
void TransformCounterC__0__Counter__overflow(void) {
  CounterToLocalTimeC__0__Counter__overflow();
  TransformAlarmC__0__Counter__overflow();
  Atm128Rfa1SerialP__Counter__overflow();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TransformCounterC__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CounterToLocalTimeC__0__Counter__overflow@plt>
  xor    %eax,%eax
  call   <TransformAlarmC__0__Counter__overflow@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <Atm128Rfa1SerialP__Counter__overflow@plt>
```

assistant: ```c
void TransformCounterC__0__Counter__overflow(void) {
  CounterToLocalTimeC__0__Counter__overflow();
  TransformAlarmC__0__Counter__overflow();
  Atm128Rfa1SerialP__Counter__overflow();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_it_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L49
L35:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L15
  addl   $0x1,-0x8(%rbp)
L15:
  addl   $0x1,-0x4(%rbp)
L49:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L35
  cmpl   $0x2,-0x8(%rbp)
  jne    L23
  mov    $0x1,%eax
  jmp    L30
L23:
  mov    $0x0,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int is_it_prime(int num) {
  int prime = 0, count = 1;
  for (count > 0; count <= num; count++) {
    if (num % count == 0) {
      prime++;
    }
  }
  if (prime == 2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_it_prime>:
  endbr64
  test   %edi,%edi
  jle    L18
  lea    0x1(%rdi),%r8d
  mov    $0x1,%ecx
  mov    $0x0,%esi
L29:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L29
L3:
  cmp    $0x2,%esi
  sete   %al
  movzbl %al,%eax
  ret
L18:
  mov    $0x0,%esi
  jmp    L3
```

assistant: ```c
int is_it_prime(int num) {
  int prime = 0, count = 1;
  for (count > 0; count <= num; count++) {
    if (num % count == 0) {
      prime++;
    }
  }
  if (prime == 2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_it_prime>:
  endbr64
  test   %edi,%edi
  jle    L4
  lea    0x1(%rdi),%r8d
  mov    $0x1,%ecx
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L18
  xor    %eax,%eax
  cmp    $0x2,%esi
  sete   %al
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_it_prime(int num) {
  int prime = 0, count = 1;
  for (count > 0; count <= num; count++) {
    if (num % count == 0) {
      prime++;
    }
  }
  if (prime == 2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_it_prime>:
  endbr64
  test   %edi,%edi
  jle    L19
  lea    0x1(%rdi),%r8d
  mov    $0x1,%ecx
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L5
  xor    %eax,%eax
  cmp    $0x2,%esi
  sete   %al
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_it_prime(int num) {
  int prime = 0, count = 1;
  for (count > 0; count <= num; count++) {
    if (num % count == 0) {
      prime++;
    }
  }
  if (prime == 2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<hlist_del_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <hlist_unhashed@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__hlist_del@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <INIT_HLIST_NODE@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void hlist_del_init(struct hlist_node *n) {
  if (!hlist_unhashed(n)) {
    __hlist_del(n);
    INIT_HLIST_NODE(n);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hlist_del_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <hlist_unhashed@plt>
  test   %eax,%eax
  je     L2
L4:
  pop    %rbx
  ret
L2:
  mov    %rbx,%rdi
  call   <__hlist_del@plt>
  mov    %rbx,%rdi
  call   <INIT_HLIST_NODE@plt>
  jmp    L4
```

assistant: ```c
void hlist_del_init(struct hlist_node *n) {
  if (!hlist_unhashed(n)) {
    __hlist_del(n);
    INIT_HLIST_NODE(n);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hlist_del_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <hlist_unhashed@plt>
  test   %eax,%eax
  je     L7
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  call   <__hlist_del@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <INIT_HLIST_NODE@plt>
```

assistant: ```c
void hlist_del_init(struct hlist_node *n) {
  if (!hlist_unhashed(n)) {
    __hlist_del(n);
    INIT_HLIST_NODE(n);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hlist_del_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <hlist_unhashed@plt>
  test   %eax,%eax
  je     L2
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <__hlist_del@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <INIT_HLIST_NODE@plt>
```

assistant: ```c
void hlist_del_init(struct hlist_node *n) {
  if (!hlist_unhashed(n)) {
    __hlist_del(n);
    INIT_HLIST_NODE(n);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shr    $0x3,%rax
  or     $0xffffffb5,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  and    $0x33,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        state[0UL] = state[local1] << (((state[local1] >> (unsigned char)3) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      }
      if (state[0UL] > local1) {
        state[0UL] >>= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
        state[0UL] |= state[local1];
      } else {
        state[0UL] = state[local1] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 179841843UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  shr    $0x3,%rax
  and    $0x33,%eax
  or     $0x31,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        state[0UL] = state[local1] << (((state[local1] >> (unsigned char)3) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      }
      if (state[0UL] > local1) {
        state[0UL] >>= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
        state[0UL] |= state[local1];
      } else {
        state[0UL] = state[local1] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 179841843UL;
  }
}
```