ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<bn_c2i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L2
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bn_new@plt>
  test   %rax,%rax
  jne    L2
  mov    $0x0,%eax
  jmp    L47
L2:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <BN_bin2bn@plt>
  test   %eax,%eax
  jne    L21
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bn_free@plt>
  mov    $0x0,%eax
  jmp    L47
L21:
  mov    $0x1,%eax
L47:
  leave
  ret
```

assistant: ```c
int bn_c2i(ASN1_VALUE **pval, const unsigned char *cont, int len, int utype, char *free_cont, const ASN1_ITEM *it) {
  BIGNUM *bn;
  if (*pval == NULL) {
    if (bn_new(pval, it) == 0)
      return 0;
  }
  bn = (BIGNUM *)*pval;
  if (!BN_bin2bn(cont, len, bn)) {
    bn_free(pval, it);
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bn_c2i>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  mov    %r9,%r13
  cmpq   $0x0,(%rdi)
  je     L42
L44:
  mov    0x0(%rbp),%rdx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <BN_bin2bn@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L27
  mov    $0x1,%ebx
L47:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  mov    %r9,%rsi
  call   <bn_new@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  jne    L44
  jmp    L47
L27:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <bn_free@plt>
  jmp    L47
```

assistant: ```c
int bn_c2i(ASN1_VALUE **pval, const unsigned char *cont, int len, int utype, char *free_cont, const ASN1_ITEM *it) {
  BIGNUM *bn;
  if (*pval == NULL) {
    if (bn_new(pval, it) == 0)
      return 0;
  }
  bn = (BIGNUM *)*pval;
  if (!BN_bin2bn(cont, len, bn)) {
    bn_free(pval, it);
    return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bn_c2i>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    (%rdi),%rdx
  mov    %rdi,%rbp
  test   %rdx,%rdx
  je     L16
L9:
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <BN_bin2bn@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L28
  mov    $0x1,%r12d
L5:
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %r9,%rsi
  xor    %r12d,%r12d
  call   <bn_new@plt>
  test   %rax,%rax
  je     L5
  mov    0x0(%rbp),%rdx
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <bn_free@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int bn_c2i(ASN1_VALUE **pval, const unsigned char *cont, int len, int utype, char *free_cont, const ASN1_ITEM *it) {
  BIGNUM *bn;
  if (*pval == NULL) {
    if (bn_new(pval, it) == 0)
      return 0;
  }
  bn = (BIGNUM *)*pval;
  if (!BN_bin2bn(cont, len, bn)) {
    bn_free(pval, it);
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bn_c2i>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    (%rdi),%rdx
  mov    %rdi,%rbp
  test   %rdx,%rdx
  je     L33
L23:
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <BN_bin2bn@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L22
  mov    $0x1,%r12d
L15:
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %r9,%rsi
  xor    %r12d,%r12d
  call   <bn_new@plt>
  test   %rax,%rax
  je     L15
  mov    0x0(%rbp),%rdx
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <bn_free@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int bn_c2i(ASN1_VALUE **pval, const unsigned char *cont, int len, int utype, char *free_cont, const ASN1_ITEM *it) {
  BIGNUM *bn;
  if (*pval == NULL) {
    if (bn_new(pval, it) == 0)
      return 0;
  }
  bn = (BIGNUM *)*pval;
  if (!BN_bin2bn(cont, len, bn)) {
    bn_free(pval, it);
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bubble_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jle    L15
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <empurra_maior@plt>
  test   %rax,%rax
  je     L11
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubble_r>
  jmp    L11
L15:
  nop
L11:
  leave
  ret
```

assistant: ```c
void bubble_r(int *v, int n) {
  if (n <= 1)
    return;
  if (empurra_maior(v, n))
    bubble_r(v, n - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bubble_r>:
  endbr64
  cmp    $0x1,%esi
  jle    L22
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <empurra_maior@plt>
  test   %rax,%rax
  jne    L15
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    -0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <bubble_r>
  jmp    L21
L22:
  ret
```

assistant: ```c
void bubble_r(int *v, int n) {
  if (n <= 1)
    return;
  if (empurra_maior(v, n))
    bubble_r(v, n - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<bubble_r>:
  endbr64
  cmp    $0x1,%esi
  jle    L38
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L23:
  sub    $0x1,%ebx
  cmp    $0x1,%ebx
  je     L37
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <empurra_maior@plt>
  test   %rax,%rax
  jne    L23
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  ret
```

assistant: ```c
void bubble_r(int *v, int n) {
  if (n <= 1)
    return;
  if (empurra_maior(v, n))
    bubble_r(v, n - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bubble_r>:
  endbr64
  cmp    $0x1,%esi
  jle    L7
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L13:
  sub    $0x1,%ebx
  cmp    $0x1,%ebx
  je     L22
L12:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <empurra_maior@plt>
  test   %rax,%rax
  jne    L13
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  ret
```

assistant: ```c
void bubble_r(int *v, int n) {
  if (n <= 1)
    return;
  if (empurra_maior(v, n))
    bubble_r(v, n - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<AStar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x2078(%rbp)
  mov    %rsi,-0x2080(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2064(%rbp)
  jmp    L64
L23:
  mov    -0x2064(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x2078(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x2064(%rbp)
L64:
  cmpl   $0x3ffff,-0x2064(%rbp)
  jle    L23
  movl   $0x0,-0x206c(%rbp)
  jmp    L47
L71:
  movl   $0x0,-0x2068(%rbp)
  jmp    L81
L1:
  movl   $0x0,-0x2064(%rbp)
  jmp    L49
L58:
  mov    -0x2064(%rbp),%eax
  cltq
  movl   $0x0,-0x2060(%rbp,%rax,4)
  mov    -0x2064(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x1030(%rbp,%rax,4)
  addl   $0x1,-0x2064(%rbp)
L49:
  cmpl   $0x3ff,-0x2064(%rbp)
  jle    L58
  lea    -0x2070(%rbp),%rdi
  lea    -0x1030(%rbp),%rcx
  lea    -0x2060(%rbp),%rdx
  mov    -0x2068(%rbp),%esi
  mov    -0x206c(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <wray@plt>
  movl   $0x0,-0x2064(%rbp)
  jmp    L11
L27:
  mov    -0x2064(%rbp),%eax
  cltq
  mov    -0x2060(%rbp,%rax,4),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x2078(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x206c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x2068(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x2080(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x2064(%rbp),%eax
  cltq
  movss  -0x1030(%rbp,%rax,4),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x2064(%rbp),%eax
  cltq
  mov    -0x2060(%rbp,%rax,4),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x2078(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x2064(%rbp)
L11:
  mov    -0x2070(%rbp),%eax
  cmp    %eax,-0x2064(%rbp)
  jl     L27
  addl   $0x1,-0x2068(%rbp)
L81:
  cmpl   $0x2ff,-0x2068(%rbp)
  jle    L1
  addl   $0x1,-0x206c(%rbp)
L47:
  cmpl   $0xb3,-0x206c(%rbp)
  jle    L71
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

assistant: ```c
void AStar(float *f, float *g) {
  int line[512 * 2 + 10];
  float weight[512 * 2 + 10];
  int np, nr, i, numb;
  float snorm;
  for (i = 0; i < 512 * 512; ++i)
    f[i] = 0;
  for (np = 0; np < 180; ++np) {
    for (nr = 0; nr < 768; ++nr) {
      for (i = 0; i < 512 * 2; ++i) {
        line[i] = 0;
        weight[i] = 0.;
      }
      wray(np, nr, line, weight, &numb);
      for (i = 0; i < numb; ++i) {
        f[line[i]] += g[np * 768 + nr] * weight[i];
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AStar>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x78,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x2068(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rax
  lea    0x100000(%rdi),%rdx
L64:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L64
  mov    $0x0,%r12d
  lea    0xc(%rsp),%r13
  jmp    L30
L48:
  add    $0x1,%ebp
  cmp    $0x300,%ebp
  je     L72
L75:
  mov    $0x0,%eax
L77:
  movl   $0x0,0x10(%rsp,%rax,1)
  movl   $0x0,0x1040(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x1000,%rax
  jne    L77
  lea    0x1040(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %r13,%r8
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <wray@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L48
  lea    0x0(%rbp,%r15,1),%eax
  cltq
  lea    (%r14,%rax,4),%rdi
  mov    %ecx,%ecx
  mov    $0x0,%eax
  lea    0x1040(%rsp),%rsi
L13:
  movslq 0x10(%rsp,%rax,4),%rdx
  lea    (%rbx,%rdx,4),%rdx
  movss  (%rdi),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L13
  jmp    L48
L72:
  add    $0x1,%r12d
  cmp    $0xb4,%r12d
  je     L4
L30:
  lea    (%r12,%r12,2),%r15d
  shl    $0x8,%r15d
  mov    $0x0,%ebp
  jmp    L75
L4:
  mov    0x2068(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x2078,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void AStar(float *f, float *g) {
  int line[512 * 2 + 10];
  float weight[512 * 2 + 10];
  int np, nr, i, numb;
  float snorm;
  for (i = 0; i < 512 * 512; ++i)
    f[i] = 0;
  for (np = 0; np < 180; ++np) {
    for (nr = 0; nr < 768; ++nr) {
      for (i = 0; i < 512 * 2; ++i) {
        line[i] = 0;
        weight[i] = 0.;
      }
      wray(np, nr, line, weight, &numb);
      for (i = 0; i < numb; ++i) {
        f[line[i]] += g[np * 768 + nr] * weight[i];
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<AStar>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x88,%rsp
  mov    $0x100000,%edx
  xor    %r13d,%r13d
  mov    %rsi,(%rsp)
  xor    %esi,%esi
  mov    %rdi,%r14
  lea    0x20(%rsp),%r12
  lea    0x1050(%rsp),%rbp
  lea    0x1c(%rsp),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x2078(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
L19:
  lea    0x0(%r13,%r13,2),%eax
  xor    %ebx,%ebx
  shl    $0x8,%eax
  mov    %eax,0xc(%rsp)
L9:
  xor    %eax,%eax
  mov    $0x200,%ecx
  mov    %r12,%rdi
  mov    %r15,%r8
  rep stos %rax,%es:(%rdi)
  mov    $0x200,%ecx
  mov    %rbp,%rdi
  mov    %r12,%rdx
  rep stos %rax,%es:(%rdi)
  mov    %ebx,%esi
  mov    %rbp,%rcx
  mov    %r13d,%edi
  call   <wray@plt>
  movslq 0x1c(%rsp),%rcx
  test   %ecx,%ecx
  jle    L46
  mov    0xc(%rsp),%eax
  mov    (%rsp),%rsi
  add    %ebx,%eax
  mov    %eax,%eax
  lea    (%rsi,%rax,4),%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L25:
  movslq (%r12,%rax,4),%rdx
  movss  (%rdi),%xmm0
  mulss  0x0(%rbp,%rax,4),%xmm0
  add    $0x1,%rax
  lea    (%r14,%rdx,4),%rdx
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  cmp    %rax,%rcx
  jne    L25
L46:
  add    $0x1,%ebx
  cmp    $0x300,%ebx
  jne    L9
  add    $0x1,%r13d
  cmp    $0xb4,%r13d
  jne    L19
  mov    0x2078(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x2088,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void AStar(float *f, float *g) {
  int line[512 * 2 + 10];
  float weight[512 * 2 + 10];
  int np, nr, i, numb;
  float snorm;
  for (i = 0; i < 512 * 512; ++i)
    f[i] = 0;
  for (np = 0; np < 180; ++np) {
    for (nr = 0; nr < 768; ++nr) {
      for (i = 0; i < 512 * 2; ++i) {
        line[i] = 0;
        weight[i] = 0.;
      }
      wray(np, nr, line, weight, &numb);
      for (i = 0; i < numb; ++i) {
        f[line[i]] += g[np * 768 + nr] * weight[i];
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<AStar>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x88,%rsp
  mov    $0x100000,%edx
  xor    %r13d,%r13d
  mov    %rsi,(%rsp)
  xor    %esi,%esi
  mov    %rdi,%r14
  lea    0x20(%rsp),%r12
  lea    0x1050(%rsp),%rbp
  lea    0x1c(%rsp),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x2078(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
L41:
  lea    0x0(%r13,%r13,2),%eax
  xor    %ebx,%ebx
  shl    $0x8,%eax
  mov    %eax,0xc(%rsp)
L37:
  xor    %eax,%eax
  mov    $0x200,%ecx
  mov    %r12,%rdi
  mov    %r15,%r8
  rep stos %rax,%es:(%rdi)
  mov    $0x200,%ecx
  mov    %rbp,%rdi
  mov    %r12,%rdx
  rep stos %rax,%es:(%rdi)
  mov    %ebx,%esi
  mov    %rbp,%rcx
  mov    %r13d,%edi
  call   <wray@plt>
  movslq 0x1c(%rsp),%rcx
  test   %ecx,%ecx
  jle    L10
  mov    0xc(%rsp),%eax
  mov    (%rsp),%rsi
  add    %ebx,%eax
  mov    %eax,%eax
  lea    (%rsi,%rax,4),%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L7:
  movslq (%r12,%rax,4),%rdx
  movss  (%rdi),%xmm0
  mulss  0x0(%rbp,%rax,4),%xmm0
  add    $0x1,%rax
  lea    (%r14,%rdx,4),%rdx
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  cmp    %rax,%rcx
  jne    L7
L10:
  add    $0x1,%ebx
  cmp    $0x300,%ebx
  jne    L37
  add    $0x1,%r13d
  cmp    $0xb4,%r13d
  jne    L41
  mov    0x2078(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x2088,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void AStar(float *f, float *g) {
  int line[512 * 2 + 10];
  float weight[512 * 2 + 10];
  int np, nr, i, numb;
  float snorm;
  for (i = 0; i < 512 * 512; ++i)
    f[i] = 0;
  for (np = 0; np < 180; ++np) {
    for (nr = 0; nr < 768; ++nr) {
      for (i = 0; i < 512 * 2; ++i) {
        line[i] = 0;
        weight[i] = 0.;
      }
      wray(np, nr, line, weight, &numb);
      for (i = 0; i < numb; ++i) {
        f[line[i]] += g[np * 768 + nr] * weight[i];
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pack_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x5,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <encode_packchar@plt>
  lea    (%rax,%rax,1),%ebx
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <encode_packchar@plt>
  shl    $0x6,%eax
  xor    %eax,%ebx
  mov    -0x18(%rbp),%rax
  sub    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <encode_packchar@plt>
  shl    $0xb,%eax
  xor    %eax,%ebx
  mov    -0x18(%rbp),%rax
  sub    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <encode_packchar@plt>
  shl    $0x10,%eax
  xor    %eax,%ebx
  mov    -0x18(%rbp),%rax
  sub    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <encode_packchar@plt>
  shl    $0x15,%eax
  xor    %eax,%ebx
  mov    -0x18(%rbp),%rax
  sub    $0x5,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <encode_packchar@plt>
  shl    $0x1a,%eax
  xor    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint32_t pack_chars(const char *str) {
  const char *pos = (str + 5);
  return ((encode_packchar(*pos) << 1) ^ (encode_packchar(*(pos - 1)) << (1 + (5 * 1))) ^ (encode_packchar(*(pos - 2)) << (1 + (5 * 2))) ^ (encode_packchar(*(pos - 3)) << (1 + (5 * 3))) ^ (encode_packchar(*(pos - 4)) << (1 + (5 * 4))) ^ (encode_packchar(*(pos - 5)) << (1 + (5 * 5))));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pack_chars>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0x5(%rdi),%edi
  call   <encode_packchar@plt>
  mov    %eax,%ebp
  movsbl 0x4(%rbx),%edi
  call   <encode_packchar@plt>
  add    %ebp,%ebp
  shl    $0x6,%eax
  xor    %eax,%ebp
  movsbl 0x3(%rbx),%edi
  call   <encode_packchar@plt>
  shl    $0xb,%eax
  xor    %eax,%ebp
  movsbl 0x2(%rbx),%edi
  call   <encode_packchar@plt>
  shl    $0x10,%eax
  mov    %eax,%r12d
  xor    %ebp,%r12d
  movsbl 0x1(%rbx),%edi
  call   <encode_packchar@plt>
  shl    $0x15,%eax
  mov    %eax,%ebp
  xor    %r12d,%ebp
  movsbl (%rbx),%edi
  call   <encode_packchar@plt>
  shl    $0x1a,%eax
  xor    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t pack_chars(const char *str) {
  const char *pos = (str + 5);
  return ((encode_packchar(*pos) << 1) ^ (encode_packchar(*(pos - 1)) << (1 + (5 * 1))) ^ (encode_packchar(*(pos - 2)) << (1 + (5 * 2))) ^ (encode_packchar(*(pos - 3)) << (1 + (5 * 3))) ^ (encode_packchar(*(pos - 4)) << (1 + (5 * 4))) ^ (encode_packchar(*(pos - 5)) << (1 + (5 * 5))));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pack_chars>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0x5(%rdi),%edi
  call   <encode_packchar@plt>
  movsbl 0x4(%rbx),%edi
  mov    %eax,%ebp
  call   <encode_packchar@plt>
  movsbl 0x3(%rbx),%edi
  add    %ebp,%ebp
  shl    $0x6,%eax
  xor    %eax,%ebp
  call   <encode_packchar@plt>
  movsbl 0x2(%rbx),%edi
  shl    $0xb,%eax
  xor    %eax,%ebp
  call   <encode_packchar@plt>
  movsbl 0x1(%rbx),%edi
  shl    $0x10,%eax
  mov    %eax,%r12d
  call   <encode_packchar@plt>
  movsbl (%rbx),%edi
  xor    %ebp,%r12d
  shl    $0x15,%eax
  mov    %eax,%ebp
  call   <encode_packchar@plt>
  xor    %r12d,%ebp
  pop    %rbx
  shl    $0x1a,%eax
  xor    %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t pack_chars(const char *str) {
  const char *pos = (str + 5);
  return ((encode_packchar(*pos) << 1) ^ (encode_packchar(*(pos - 1)) << (1 + (5 * 1))) ^ (encode_packchar(*(pos - 2)) << (1 + (5 * 2))) ^ (encode_packchar(*(pos - 3)) << (1 + (5 * 3))) ^ (encode_packchar(*(pos - 4)) << (1 + (5 * 4))) ^ (encode_packchar(*(pos - 5)) << (1 + (5 * 5))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pack_chars>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0x5(%rdi),%edi
  call   <encode_packchar@plt>
  movsbl 0x4(%rbx),%edi
  mov    %eax,%ebp
  call   <encode_packchar@plt>
  movsbl 0x3(%rbx),%edi
  add    %ebp,%ebp
  shl    $0x6,%eax
  xor    %eax,%ebp
  call   <encode_packchar@plt>
  movsbl 0x2(%rbx),%edi
  shl    $0xb,%eax
  xor    %eax,%ebp
  call   <encode_packchar@plt>
  movsbl 0x1(%rbx),%edi
  shl    $0x10,%eax
  mov    %eax,%r12d
  call   <encode_packchar@plt>
  movsbl (%rbx),%edi
  xor    %ebp,%r12d
  shl    $0x15,%eax
  mov    %eax,%ebp
  call   <encode_packchar@plt>
  xor    %r12d,%ebp
  pop    %rbx
  shl    $0x1a,%eax
  xor    %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t pack_chars(const char *str) {
  const char *pos = (str + 5);
  return ((encode_packchar(*pos) << 1) ^ (encode_packchar(*(pos - 1)) << (1 + (5 * 1))) ^ (encode_packchar(*(pos - 2)) << (1 + (5 * 2))) ^ (encode_packchar(*(pos - 3)) << (1 + (5 * 3))) ^ (encode_packchar(*(pos - 4)) << (1 + (5 * 4))) ^ (encode_packchar(*(pos - 5)) << (1 + (5 * 5))));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L11
L14:
  mov    -0x18(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
char *base(char *s) {
  char *p;
  p = strrchr(s, '\\');
  if (p)
    return p + 1;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<base>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5c,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *base(char *s) {
  char *p;
  p = strrchr(s, '\\');
  if (p)
    return p + 1;
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<base>:
  endbr64
  push   %rbx
  mov    $0x5c,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *base(char *s) {
  char *p;
  p = strrchr(s, '\\');
  if (p)
    return p + 1;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<base>:
  endbr64
  push   %rbx
  mov    $0x5c,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *base(char *s) {
  char *p;
  p = strrchr(s, '\\');
  if (p)
    return p + 1;
  return s;
}
```