ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<imgfree>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L11:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L11
L10:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int imgfree(int **img, int x, int y) {
  int i;
  for (i = 0; i < x; i++)
    free(img[i]);
  free(img);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<imgfree>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L9
L2:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int imgfree(int **img, int x, int y) {
  int i;
  for (i = 0; i < x; i++)
    free(img[i]);
  free(img);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<imgfree>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L0
L19:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int imgfree(int **img, int x, int y) {
  int i;
  for (i = 0; i < x; i++)
    free(img[i]);
  free(img);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Log2Ceil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
L13:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  ja     L13
L18:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long int Log2Ceil(unsigned long int Value) {
  unsigned long int val, bit = 0;
  do {
    bit++;
    val = 1 << bit;
  } while (val && Value > val);
  return bit;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Log2Ceil>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x1,%edx
L16:
  add    $0x1,%rcx
  mov    %edx,%eax
  shl    %cl,%eax
  cltq
  test   %rax,%rax
  je     L12
  cmp    %rdi,%rax
  jb     L16
L12:
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long int Log2Ceil(unsigned long int Value) {
  unsigned long int val, bit = 0;
  do {
    bit++;
    val = 1 << bit;
  } while (val && Value > val);
  return bit;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Log2Ceil>:
  endbr64
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rcx
  mov    %edx,%eax
  shl    %cl,%eax
  cltq
  test   %rax,%rax
  je     L0
  cmp    %rdi,%rax
  jb     L15
L0:
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long int Log2Ceil(unsigned long int Value) {
  unsigned long int val, bit = 0;
  do {
    bit++;
    val = 1 << bit;
  } while (val && Value > val);
  return bit;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Log2Ceil>:
  endbr64
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rcx
  mov    %edx,%eax
  shl    %cl,%eax
  cltq
  test   %rax,%rax
  je     L16
  cmp    %rdi,%rax
  jb     L13
L16:
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long int Log2Ceil(unsigned long int Value) {
  unsigned long int val, bit = 0;
  do {
    bit++;
    val = 1 << bit;
  } while (val && Value > val);
  return bit;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encode_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <encode_string_maybe@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L8
  mov    -0x8(%rbp),%rax
  jmp    L16
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <kstrdup@plt>
L16:
  leave
  ret
```

assistant: ```c
char *encode_string(const char *s) {
  char *encoded = encode_string_maybe(s);
  if (encoded != s)
    return encoded;
  else
    return kstrdup(s);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<encode_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <encode_string_maybe@plt>
  cmp    %rax,%rbx
  je     L5
L6:
  pop    %rbx
  ret
L5:
  mov    %rax,%rdi
  call   <kstrdup@plt>
  jmp    L6
```

assistant: ```c
char *encode_string(const char *s) {
  char *encoded = encode_string_maybe(s);
  if (encoded != s)
    return encoded;
  else
    return kstrdup(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encode_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <encode_string_maybe@plt>
  cmp    %rax,%rbp
  je     L4
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <kstrdup@plt>
```

assistant: ```c
char *encode_string(const char *s) {
  char *encoded = encode_string_maybe(s);
  if (encoded != s)
    return encoded;
  else
    return kstrdup(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encode_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <encode_string_maybe@plt>
  cmp    %rax,%rbp
  je     L5
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <kstrdup@plt>
```

assistant: ```c
char *encode_string(const char *s) {
  char *encoded = encode_string_maybe(s);
  if (encoded != s)
    return encoded;
  else
    return kstrdup(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RNApaln_cmdline_parser_required>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int RNApaln_cmdline_parser_required(struct RNApaln_args_info *args_info, const char *prog_name) {
  (void)(args_info);
  (void)(prog_name);
  return EXIT_SUCCESS;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RNApaln_cmdline_parser_required>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int RNApaln_cmdline_parser_required(struct RNApaln_args_info *args_info, const char *prog_name) {
  (void)(args_info);
  (void)(prog_name);
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RNApaln_cmdline_parser_required>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int RNApaln_cmdline_parser_required(struct RNApaln_args_info *args_info, const char *prog_name) {
  (void)(args_info);
  (void)(prog_name);
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RNApaln_cmdline_parser_required>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int RNApaln_cmdline_parser_required(struct RNApaln_args_info *args_info, const char *prog_name) {
  (void)(args_info);
  (void)(prog_name);
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<overlapAdd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L17
L28:
  mov    -0x20(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L5
L10:
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  movswl %ax,%edx
  mov    -0x24(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x1c(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x28(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L5:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  addl   $0x1,-0x20(%rbp)
L17:
  mov    -0x20(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void overlapAdd(int numSamples, int numChannels, short *out, short *rampDown, short *rampUp) {
  short *o;
  short *u;
  short *d;
  int i, t;
  for (i = 0; i < numChannels; i++) {
    o = out + i;
    u = rampUp + i;
    d = rampDown + i;
    for (t = 0; t < numSamples; t++) {
      *o = (*d * (numSamples - t) + *u * t) / numSamples;
      o += numChannels;
      d += numChannels;
      u += numChannels;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<overlapAdd>:
  endbr64
  test   %esi,%esi
  jle    L30
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%r11
  add    %r11,%r11
  mov    %rdx,%rbx
  mov    %r8,%r12
  mov    %rcx,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x2(%rdx,%rax,2),%r13
L15:
  mov    %rbx,%r8
  mov    %r12,%r9
  mov    %rbp,%r10
  test   %edi,%edi
  jle    L10
  mov    $0x0,%esi
  mov    $0x0,%ecx
L28:
  movswl (%r10,%rsi,1),%eax
  mov    %edi,%edx
  sub    %ecx,%edx
  imul   %edx,%eax
  movswl (%r9,%rsi,1),%edx
  imul   %ecx,%edx
  add    %edx,%eax
  cltd
  idiv   %edi
  mov    %ax,(%r8,%rsi,1)
  add    $0x1,%ecx
  add    %r11,%rsi
  cmp    %ecx,%edi
  jne    L28
L10:
  add    $0x2,%rbx
  add    $0x2,%r12
  add    $0x2,%rbp
  cmp    %r13,%rbx
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  ret
```

assistant: ```c
void overlapAdd(int numSamples, int numChannels, short *out, short *rampDown, short *rampUp) {
  short *o;
  short *u;
  short *d;
  int i, t;
  for (i = 0; i < numChannels; i++) {
    o = out + i;
    u = rampUp + i;
    d = rampDown + i;
    for (t = 0; t < numSamples; t++) {
      *o = (*d * (numSamples - t) + *u * t) / numSamples;
      o += numChannels;
      d += numChannels;
      u += numChannels;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<overlapAdd>:
  endbr64
  test   %esi,%esi
  jle    L27
  mov    %esi,%eax
  movslq %esi,%r11
  push   %rbx
  mov    %r8,%r10
  sub    $0x1,%eax
  add    %r11,%r11
  mov    %rdx,%r9
  mov    %rcx,%r8
  lea    0x2(%rdx,%rax,2),%rbx
  nopw   0x0(%rax,%rax,1)
L21:
  test   %edi,%edi
  jle    L12
  xor    %esi,%esi
  xor    %ecx,%ecx
L23:
  movswl (%r8,%rsi,1),%eax
  mov    %edi,%edx
  sub    %ecx,%edx
  imul   %edx,%eax
  movswl (%r10,%rsi,1),%edx
  imul   %ecx,%edx
  add    $0x1,%ecx
  add    %edx,%eax
  cltd
  idiv   %edi
  mov    %ax,(%r9,%rsi,1)
  add    %r11,%rsi
  cmp    %ecx,%edi
  jne    L23
L12:
  add    $0x2,%r9
  add    $0x2,%r10
  add    $0x2,%r8
  cmp    %rbx,%r9
  jne    L21
  pop    %rbx
  ret
L27:
  ret
```

assistant: ```c
void overlapAdd(int numSamples, int numChannels, short *out, short *rampDown, short *rampUp) {
  short *o;
  short *u;
  short *d;
  int i, t;
  for (i = 0; i < numChannels; i++) {
    o = out + i;
    u = rampUp + i;
    d = rampDown + i;
    for (t = 0; t < numSamples; t++) {
      *o = (*d * (numSamples - t) + *u * t) / numSamples;
      o += numChannels;
      d += numChannels;
      u += numChannels;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<overlapAdd>:
  endbr64
  test   %esi,%esi
  jle    L55
  movslq %esi,%r9
  mov    %esi,%eax
  add    %r9,%r9
  test   %edi,%edi
  jle    L55
  mov    %rcx,%r11
  mov    %rdx,%r10
  xor    %esi,%esi
  xor    %ecx,%ecx
  cmp    $0x1,%eax
  jne    L29
  nopl   0x0(%rax,%rax,1)
L57:
  movswl (%r11,%rsi,1),%eax
  mov    %edi,%edx
  sub    %ecx,%edx
  imul   %edx,%eax
  movswl (%r8,%rsi,1),%edx
  imul   %ecx,%edx
  add    $0x1,%ecx
  add    %edx,%eax
  cltd
  idiv   %edi
  mov    %ax,(%r10,%rsi,1)
  add    %r9,%rsi
  cmp    %edi,%ecx
  jne    L57
  ret
L55:
  ret
L29:
  sub    $0x1,%eax
  push   %rbx
  lea    0x2(%rdx,%rax,2),%rbx
  nopl   0x0(%rax,%rax,1)
L59:
  xor    %esi,%esi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L40:
  movswl (%r11,%rsi,1),%eax
  mov    %edi,%edx
  sub    %ecx,%edx
  imul   %edx,%eax
  movswl (%r8,%rsi,1),%edx
  imul   %ecx,%edx
  add    $0x1,%ecx
  add    %edx,%eax
  cltd
  idiv   %edi
  mov    %ax,(%r10,%rsi,1)
  add    %r9,%rsi
  cmp    %ecx,%edi
  jne    L40
  add    $0x2,%r10
  add    $0x2,%r8
  add    $0x2,%r11
  cmp    %rbx,%r10
  jne    L59
  pop    %rbx
  ret
```

assistant: ```c
void overlapAdd(int numSamples, int numChannels, short *out, short *rampDown, short *rampUp) {
  short *o;
  short *u;
  short *d;
  int i, t;
  for (i = 0; i < numChannels; i++) {
    o = out + i;
    u = rampUp + i;
    d = rampDown + i;
    for (t = 0; t < numSamples; t++) {
      *o = (*d * (numSamples - t) + *u * t) / numSamples;
      o += numChannels;
      d += numChannels;
      u += numChannels;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<std_deviationr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  cmpq   $0x1,-0x20(%rbp)
  jg     L39
  mov    D9(%rip),%rax
  jmp    L11
L39:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L0
L13:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x28(%rbp),%xmm1
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x28(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L13
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
L11:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type: f64

tool: D9: 0

assistant: ```c
double std_deviationr(double *values, long int max, double mean) {
  long int j;
  double dev;
  if (max <= 1)
    return 0.;
  dev = 0.;
  for (j = 0; j < max; j++) {
    dev += ((double)values[j] - mean) * ((double)values[j] - mean);
  }
  return sqrt(dev / (double)(max - 1));
}
```
user: What is the c source code of the assembly code below?

```asm
<std_deviationr>:
  endbr64
  cmp    $0x1,%rsi
  jle    L6
  movapd %xmm0,%xmm2
  mov    %rdi,%rax
  lea    (%rdi,%rsi,8),%rdx
  pxor   %xmm0,%xmm0
L14:
  movsd  (%rax),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L14
  sub    $0x1,%rsi
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L3
  sqrtsd %xmm0,%xmm0
  ret
L3:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
L6:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double std_deviationr(double *values, long int max, double mean) {
  long int j;
  double dev;
  if (max <= 1)
    return 0.;
  dev = 0.;
  for (j = 0; j < max; j++) {
    dev += ((double)values[j] - mean) * ((double)values[j] - mean);
  }
  return sqrt(dev / (double)(max - 1));
}
```
user: What is the c source code of the assembly code below:

```asm
<std_deviationr>:
  endbr64
  movapd %xmm0,%xmm2
  cmp    $0x1,%rsi
  jle    L21
  pxor   %xmm3,%xmm3
  lea    (%rdi,%rsi,8),%rax
  movapd %xmm3,%xmm0
  nopw   0x0(%rax,%rax,1)
L4:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L4
  sub    $0x1,%rsi
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm3
  ja     L23
  sqrtsd %xmm0,%xmm0
  ret
  nopl   (%rax)
L21:
  pxor   %xmm0,%xmm0
  ret
L23:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double std_deviationr(double *values, long int max, double mean) {
  long int j;
  double dev;
  if (max <= 1)
    return 0.;
  dev = 0.;
  for (j = 0; j < max; j++) {
    dev += ((double)values[j] - mean) * ((double)values[j] - mean);
  }
  return sqrt(dev / (double)(max - 1));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<std_deviationr>:
  endbr64
  movapd %xmm0,%xmm3
  cmp    $0x1,%rsi
  jle    L4
  mov    %rsi,%rdx
  movapd %xmm0,%xmm4
  pxor   %xmm5,%xmm5
  mov    %rdi,%rax
  shr    %rdx
  unpcklpd %xmm4,%xmm4
  movapd %xmm5,%xmm0
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L15:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  subpd  %xmm4,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L15
  mov    %rsi,%rax
  and    $0xfffffffffffffffe,%rax
  test   $0x1,%sil
  je     L23
  movsd  (%rdi,%rax,8),%xmm1
  subsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L23:
  sub    $0x1,%rsi
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm5
  ja     L19
  sqrtsd %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  pxor   %xmm0,%xmm0
  ret
L19:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double std_deviationr(double *values, long int max, double mean) {
  long int j;
  double dev;
  if (max <= 1)
    return 0.;
  dev = 0.;
  for (j = 0; j < max; j++) {
    dev += ((double)values[j] - mean) * ((double)values[j] - mean);
  }
  return sqrt(dev / (double)(max - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<format_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L13
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L13:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xc0(%rbp)
  mov    -0xd8(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc4(%rbp),%edx
  mov    -0xd8(%rbp),%rcx
  lea    -0xc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vasprintf@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc0(%rbp),%rax
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
char *format_string(const char *fmt, ...) {
  char *result = NULL;
  va_list ap;
  va_start(ap, fmt);
  vasprintf(&result, fmt, ap);
  va_end(ap);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<format_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <vasprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *format_string(const char *fmt, ...) {
  char *result = NULL;
  va_list ap;
  va_start(ap, fmt);
  vasprintf(&result, fmt, ap);
  va_end(ap);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<format_string>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <vasprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *format_string(const char *fmt, ...) {
  char *result = NULL;
  va_list ap;
  va_start(ap, fmt);
  vasprintf(&result, fmt, ap);
  va_end(ap);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<format_string>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <vasprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *format_string(const char *fmt, ...) {
  char *result = NULL;
  va_list ap;
  va_start(ap, fmt);
  vasprintf(&result, fmt, ap);
  va_end(ap);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2CSlaveIntEnableEx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  lea    0x80c(%rax),%rdx
  mov    (%rdx),%rcx
  add    $0x80c,%rax
  mov    %rax,%rdx
  mov    %rsi,%rax
  or     %rcx,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void I2CSlaveIntEnableEx(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000080C))) |= ui32IntFlags;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<I2CSlaveIntEnableEx>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x80c(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x80c(%rdx)
  ret
```

assistant: ```c
void I2CSlaveIntEnableEx(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000080C))) |= ui32IntFlags;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<I2CSlaveIntEnableEx>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x80c(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x80c(%rdx)
  ret
```

assistant: ```c
void I2CSlaveIntEnableEx(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000080C))) |= ui32IntFlags;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<I2CSlaveIntEnableEx>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x80c(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x80c(%rdx)
  ret
```

assistant: ```c
void I2CSlaveIntEnableEx(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000080C))) |= ui32IntFlags;
}
```