user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    D82(%rip),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D55(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L15
L57:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    D55(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  addl   $0x1,-0x20(%rbp)
L15:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jl     L57
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L14
L1:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  cmp    %eax,%edx
  jne    L47
  mov    -0x2c(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L47:
  addl   $0x1,-0x1c(%rbp)
L14:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L1
  cmpl   $0x0,-0x24(%rbp)
  jne    L51
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L51:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D55
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D82
data_type: string
name: parse_data
arguments: data_label: D67
data_type: string
name: parse_data
arguments: data_label: D42
data_type: string
name: parse_data
arguments: data_label: D22
data_type: string

tool: D18: Please enter a positive integer: 

tool: D55: %d

tool: D20: You entered positive integer: %d


tool: D82: r

tool: D67: ./Data1.txt

tool: D42: Number %d found at index %d.


tool: D22: Integer NOT FOUND.

assistant: ```c
int main(int argc, char *argv[]) {
  int userInt = 0;
  printf("Please enter a positive integer: ");
  scanf("%d", &userInt);
  printf("You entered positive integer: %d\n", userInt);
  int *intData = NULL;
  int intSize = 0;
  int foundUserInt = 0;
  FILE *fileHandle = fopen("./Data1.txt", "r");
  {
    fscanf(fileHandle, "%d", &intSize);
    intData = (int *)(malloc(sizeof(int) * intSize));
    for (int intFor1 = 0; intFor1 < intSize; intFor1++) {
      fscanf(fileHandle, "%d", &intData[intFor1]);
    }
  }
  fclose(fileHandle);
  for (int intFor1 = 0; intFor1 < intSize; intFor1++) {
    if (userInt == intData[intFor1]) {
      printf("Number %d found at index %d.\n", userInt, intFor1);
      foundUserInt++;
    }
  }
  if (!foundUserInt) {
    printf("Integer NOT FOUND.\n");
  }
}
```