ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_CutOffOneElement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <file_LatestSlash@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L48
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L29
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L19
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L3
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L3
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L29
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L8
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L29
L48:
  nop
L29:
  leave
  ret
```

assistant: ```c
void file_CutOffOneElement(char *path) {
  while (1) {
    int i = file_LatestSlash(path);
    if (i == 0) {
      return;
    }
    if (i < 0) {
      path[0] = 0;
      return;
    } else {
      if (i == (int)strlen(path) - 1) {
        path[i] = 0;
        if (strlen(path) > 0) {
          if (path[strlen(path) - 1] == '.') {
            if (strlen(path) > 1) {
              if (path[strlen(path) - 2] == '.') {
                path[strlen(path) - 2] = 0;
                return;
              }
            }
            path[strlen(path) - 1] = 0;
          }
        }
      } else {
        path[i + 1] = 0;
        return;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<file_CutOffOneElement>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L93:
  mov    %rbp,%rdi
  call   <file_LatestSlash@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L48
  js     L87
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L71
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L93
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2e,-0x1(%rbp,%rax,1)
  jne    L93
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L33
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2e,-0x2(%rbp,%rax,1)
  je     L7
L33:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L93
L87:
  movb   $0x0,0x0(%rbp)
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x2(%rbp,%rax,1)
  jmp    L48
L71:
  movslq %ebx,%rbx
  movb   $0x0,0x1(%rbp,%rbx,1)
  jmp    L48
```

assistant: ```c
void file_CutOffOneElement(char *path) {
  while (1) {
    int i = file_LatestSlash(path);
    if (i == 0) {
      return;
    }
    if (i < 0) {
      path[0] = 0;
      return;
    } else {
      if (i == (int)strlen(path) - 1) {
        path[i] = 0;
        if (strlen(path) > 0) {
          if (path[strlen(path) - 1] == '.') {
            if (strlen(path) > 1) {
              if (path[strlen(path) - 2] == '.') {
                path[strlen(path) - 2] = 0;
                return;
              }
            }
            path[strlen(path) - 1] = 0;
          }
        }
      } else {
        path[i + 1] = 0;
        return;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<file_CutOffOneElement>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L4
  nop
L27:
  js     L91
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %ebx,%rdx
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L71
  movb   $0x0,0x0(%rbp,%rdx,1)
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L48
L4:
  mov    %rbp,%rdi
  call   <file_LatestSlash@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L27
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L91:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L71:
  movb   $0x0,0x1(%rbp,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2e,-0x1(%rbp,%rax,1)
  jne    L4
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L29
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2e,-0x2(%rbp,%rax,1)
  je     L33
L29:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L4
L33:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x2(%rbp,%rax,1)
  jmp    L34
```

assistant: ```c
void file_CutOffOneElement(char *path) {
  while (1) {
    int i = file_LatestSlash(path);
    if (i == 0) {
      return;
    }
    if (i < 0) {
      path[0] = 0;
      return;
    } else {
      if (i == (int)strlen(path) - 1) {
        path[i] = 0;
        if (strlen(path) > 0) {
          if (path[strlen(path) - 1] == '.') {
            if (strlen(path) > 1) {
              if (path[strlen(path) - 2] == '.') {
                path[strlen(path) - 2] = 0;
                return;
              }
            }
            path[strlen(path) - 1] = 0;
          }
        }
      } else {
        path[i + 1] = 0;
        return;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<file_CutOffOneElement>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L58
  nop
L12:
  js     L31
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %ebx,%rdx
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L10
  movb   $0x0,0x0(%rbp,%rdx,1)
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L97
L58:
  mov    %rbp,%rdi
  call   <file_LatestSlash@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L12
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  movb   $0x0,0x1(%rbp,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L97:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2e,-0x1(%rbp,%rax,1)
  jne    L58
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L53
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2e,-0x2(%rbp,%rax,1)
  je     L90
L53:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L58
L90:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x2(%rbp,%rax,1)
  jmp    L37
```

assistant: ```c
void file_CutOffOneElement(char *path) {
  while (1) {
    int i = file_LatestSlash(path);
    if (i == 0) {
      return;
    }
    if (i < 0) {
      path[0] = 0;
      return;
    } else {
      if (i == (int)strlen(path) - 1) {
        path[i] = 0;
        if (strlen(path) > 0) {
          if (path[strlen(path) - 1] == '.') {
            if (strlen(path) > 1) {
              if (path[strlen(path) - 2] == '.') {
                path[strlen(path) - 2] = 0;
                return;
              }
            }
            path[strlen(path) - 1] = 0;
          }
        }
      } else {
        path[i + 1] = 0;
        return;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L1:
  lea    -0x1c(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <setbit@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rcx
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D6
datatype: string
name: unpack_data
arguments: label: D20
datatype: string

tool: D5: type a long unsigned x and an integer n: sets the nth bit of x to 1

tool: D6: %lu %i

tool: D20: %lu %i %lu


assistant: ```c
int main() {
  unsigned long x, y;
  int n;
  printf("type a long unsigned x and an integer n: sets the nth bit of x to 1\n");
  while (1) {
    scanf("%lu %i", &x, &n);
    y = setbit(x, n);
    printf("%lu %i %lu\n", x, n, y);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D6(%rip),%rbp
  lea    D8(%rip),%rbx
L7:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <setbit@plt>
  mov    %rax,%rcx
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: unpack_data
arguments: data_tag: D23
datatype: string
name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D23: type a long unsigned x and an integer n: sets the nth bit of x to 1

tool: D6: %lu %i

tool: D8: %lu %i %lu


assistant: ```c
int main() {
  unsigned long x, y;
  int n;
  printf("type a long unsigned x and an integer n: sets the nth bit of x to 1\n");
  while (1) {
    scanf("%lu %i", &x, &n);
    y = setbit(x, n);
    printf("%lu %i %lu\n", x, n, y);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <setbit@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D2
type_guessed: string

tool: D1: type a long unsigned x and an integer n: sets the nth bit of x to 1

tool: D6: %lu %i

tool: D2: %lu %i %lu


assistant: ```c
int main() {
  unsigned long x, y;
  int n;
  printf("type a long unsigned x and an integer n: sets the nth bit of x to 1\n");
  while (1) {
    scanf("%lu %i", &x, &n);
    y = setbit(x, n);
    printf("%lu %i %lu\n", x, n, y);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <setbit@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D0
datatype: string

tool: D10: type a long unsigned x and an integer n: sets the nth bit of x to 1

tool: D11: %lu %i

tool: D0: %lu %i %lu


assistant: ```c
int main() {
  unsigned long x, y;
  int n;
  printf("type a long unsigned x and an integer n: sets the nth bit of x to 1\n");
  while (1) {
    scanf("%lu %i", &x, &n);
    y = setbit(x, n);
    printf("%lu %i %lu\n", x, n, y);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPalin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <reverseNum@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L17
  mov    $0x1,%eax
  jmp    L4
L17:
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
int isPalin(int num) {
  if (num == reverseNum(num)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isPalin>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <reverseNum@plt>
  cmp    %ebx,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isPalin(int num) {
  if (num == reverseNum(num)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPalin>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <reverseNum@plt>
  cmp    %ebx,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isPalin(int num) {
  if (num == reverseNum(num)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isPalin>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <reverseNum@plt>
  cmp    %ebx,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isPalin(int num) {
  if (num == reverseNum(num)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<int_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L13
L4:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x14(%rbp)
  jne    L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int int_digits(int n) {
  int d = 1;
  while (n) {
    n /= 10;
    d++;
  }
  return d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<int_digits>:
  endbr64
  test   %edi,%edi
  je     L0
  mov    $0x1,%edx
L23:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edi
  add    $0x1,%edx
  test   %eax,%eax
  jne    L23
L9:
  mov    %edx,%eax
  ret
L0:
  mov    $0x1,%edx
  jmp    L9
```

assistant: ```c
int int_digits(int n) {
  int d = 1;
  while (n) {
    n /= 10;
    d++;
  }
  return d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<int_digits>:
  endbr64
  mov    $0x1,%r8d
  test   %edi,%edi
  je     L3
  xchg   %ax,%ax
L17:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%edi
  jne    L17
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int int_digits(int n) {
  int d = 1;
  while (n) {
    n /= 10;
    d++;
  }
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<int_digits>:
  endbr64
  mov    $0x1,%r8d
  test   %edi,%edi
  je     L5
  xchg   %ax,%ax
L0:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%edi
  jne    L0
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int int_digits(int n) {
  int d = 1;
  while (n) {
    n /= 10;
    d++;
  }
  return d;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ascii_streq_icase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ascii_tolower@plt>
  mov    %al,-0xe(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ascii_tolower@plt>
  mov    %al,-0xd(%rbp)
  movzbl -0xe(%rbp),%eax
  cmp    -0xd(%rbp),%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
  cmpb   $0x0,-0xe(%rbp)
  je     L16
  cmpl   $0x0,-0xc(%rbp)
  jne    L7
L16:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
bool ascii_streq_icase(const char *s1, const char *s2) {
  unsigned char c1, c2;
  bool chars_equal;
  size_t i = 0;
  do {
    c1 = ascii_tolower(s1[i]);
    c2 = ascii_tolower(s2[i]);
    chars_equal = (c1 == c2);
    i++;
  } while (c1 && chars_equal);
  return chars_equal;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ascii_streq_icase>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
L8:
  movsbl (%r12),%edi
  call   <ascii_tolower@plt>
  mov    %eax,%ebx
  movsbl 0x0(%rbp),%edi
  call   <ascii_tolower@plt>
  cmp    %al,%bl
  sete   %al
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %bl,%bl
  je     L18
  test   %al,%al
  jne    L8
L18:
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool ascii_streq_icase(const char *s1, const char *s2) {
  unsigned char c1, c2;
  bool chars_equal;
  size_t i = 0;
  do {
    c1 = ascii_tolower(s1[i]);
    c2 = ascii_tolower(s2[i]);
    chars_equal = (c1 == c2);
    i++;
  } while (c1 && chars_equal);
  return chars_equal;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ascii_streq_icase>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xchg   %ax,%ax
L19:
  movsbl (%r12),%edi
  call   <ascii_tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <ascii_tolower@plt>
  cmp    %al,%bl
  sete   %al
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %bl,%bl
  je     L11
  test   %al,%al
  jne    L19
L11:
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool ascii_streq_icase(const char *s1, const char *s2) {
  unsigned char c1, c2;
  bool chars_equal;
  size_t i = 0;
  do {
    c1 = ascii_tolower(s1[i]);
    c2 = ascii_tolower(s2[i]);
    chars_equal = (c1 == c2);
    i++;
  } while (c1 && chars_equal);
  return chars_equal;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ascii_streq_icase>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xchg   %ax,%ax
L18:
  movsbl (%r12),%edi
  call   <ascii_tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <ascii_tolower@plt>
  cmp    %al,%bl
  sete   %al
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %bl,%bl
  je     L2
  test   %al,%al
  jne    L18
L2:
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool ascii_streq_icase(const char *s1, const char *s2) {
  unsigned char c1, c2;
  bool chars_equal;
  size_t i = 0;
  do {
    c1 = ascii_tolower(s1[i]);
    c2 = ascii_tolower(s2[i]);
    chars_equal = (c1 == c2);
    i++;
  } while (c1 && chars_equal);
  return chars_equal;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_segment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %edi,-0x2044(%rbp)
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x2000,-0x2038(%rbp)
  movl   $0x2000,-0x2034(%rbp)
  lea    -0x2030(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%eax
  mov    $0x400,%edx
  mov    %rsi,%rdi
  mov    %rdx,%rcx
  rep stos %rax,%es:(%rdi)
  jmp    L57
L22:
  mov    %r12,%rax
  mov    %eax,%edx
  mov    -0x2038(%rbp),%eax
  add    %eax,%edx
  mov    -0x2038(%rbp),%eax
  neg    %eax
  and    %edx,%eax
  mov    %r12,%rdx
  sub    %edx,%eax
  mov    %eax,%ebx
  movslq %ebx,%rax
  mov    %r13,%rdx
  sub    %r12,%rdx
  cmp    %rdx,%rax
  jle    L12
  mov    %r13,%rax
  sub    %r12,%rax
  mov    %eax,%ebx
L12:
  mov    -0x2044(%rbp),%eax
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    %eax,%r14d
  cmp    $0xffffffff,%r14d
  jne    L30
  cmp    -0x2034(%rbp),%ebx
  jle    L7
  mov    -0x2034(%rbp),%ebx
L7:
  lea    -0x2030(%rbp),%rcx
  mov    -0x2044(%rbp),%eax
  mov    %ebx,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
L30:
  movslq %ebx,%rax
  add    %rax,%r12
L57:
  cmp    %r13,%r12
  jb     L22
  nop
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  add    $0x2030,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
write_segment(new, ptr, end) int new;
register char *ptr, *end;
{
  register int i, nwrite, ret;
  char buf[80];
  extern int errno;
  int writesize = 1 << 13;
  int pagesize = 8192;
  char zeros[1 << 13];
  bzero(zeros, sizeof(zeros));
  for (i = 0; ptr < end;) {
    nwrite = (((int)ptr + writesize) & -writesize) - (int)ptr;
    if (nwrite > end - ptr)
      nwrite = end - ptr;
    ret = write(new, ptr, nwrite);
    if (ret == -1) {
      if (nwrite > pagesize)
        nwrite = pagesize;
      write(new, zeros, nwrite);
    }
    i += nwrite;
    ptr += nwrite;
  }
}
```