ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<stress_tsc_supported>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <pr_inf_skip@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: %s stressor will be skipped, CPU does not support the rdtsc instruction.


assistant: ```c
int stress_tsc_supported(const char *name) {
  pr_inf_skip("%s stressor will be skipped, CPU "
              "does not support the rdtsc instruction.\n",
              name);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<stress_tsc_supported>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <pr_inf_skip@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: %s stressor will be skipped, CPU does not support the rdtsc instruction.


assistant: ```c
int stress_tsc_supported(const char *name) {
  pr_inf_skip("%s stressor will be skipped, CPU "
              "does not support the rdtsc instruction.\n",
              name);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cleanup_new_book>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_book@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: Got CTRL-D, returning to menu...


assistant: ```c
void cleanup_new_book(struct book *x) {
  printf("Got CTRL-D, returning to menu...\n");
  free_book(x);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cleanup_new_book>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free_book@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: Got CTRL-D, returning to menu...


assistant: ```c
void cleanup_new_book(struct book *x) {
  printf("Got CTRL-D, returning to menu...\n");
  free_book(x);
}
```
user: What is the c source code of the assembly code below:

```asm
<cleanup_new_book>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free_book@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: Got CTRL-D, returning to menu...


assistant: ```c
void cleanup_new_book(struct book *x) {
  printf("Got CTRL-D, returning to menu...\n");
  free_book(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cleanup_new_book>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free_book@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: Got CTRL-D, returning to menu...


assistant: ```c
void cleanup_new_book(struct book *x) {
  printf("Got CTRL-D, returning to menu...\n");
  free_book(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb50,%rsp
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0xb48(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  jne    L99
L89:
  mov    0x8(%r13),%rdi
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L98
L73:
  mov    0x10(%r13),%rdi
  lea    D50(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L92
L66:
  mov    $0x0,%ebx
  lea    D32(%rip),%r14
L87:
  mov    %rsp,%rdi
  mov    %rbp,%rcx
  mov    $0xb48,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    $0xb48,%eax
  jne    L43
  add    $0x1,%ebx
  lea    0x4(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0xb40,%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    $0xb40,%eax
  je     L87
  mov    %r14,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L87
L99:
  mov    (%rsi),%rdi
  call   <usage@plt>
  jmp    L89
L98:
  mov    0x8(%r13),%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L73
L92:
  mov    0x10(%r13),%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L66
L43:
  mov    0x8(%r13),%rsi
  mov    %ebx,%edx
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0xb48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0xb50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string
name: read_data
arguments: data_label: D50
datatype: string
name: read_data
arguments: data_label: D32
datatype: string
name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D36
datatype: string

tool: D1: r

tool: D50: w

tool: D32: Error during write

tool: D21: Cannot open File %s for input


tool: D36: %s: converted %d blocks


assistant: ```c
main(int ac, char *av[]) {
  FILE *fi, *fo;
  char buf[2888];
  int n;
  if (ac != 3)
    usage(av[0]);
  fi = fopen(av[1], "r");
  if (fi == NULL) {
    printf("Cannot open File %s for input\n", av[1]);
    exit(-1);
  }
  fo = fopen(av[2], "w");
  if (fo == NULL) {
    printf("Cannot open File %s for input\n", av[2]);
    exit(-1);
  }
  n = 0;
  while (fread(buf, 1, 2888, fi) == 2888) {
    n++;
    if (fwrite(&buf[4], 1, 2880, fo) != 2880) {
      perror("Error during write");
      exit(-1);
    }
  }
  printf("%s: converted %d blocks\n", av[1], n);
  fclose(fi);
  fclose(fo);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb48(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  je     L7
  mov    (%rsi),%rdi
  call   <usage@plt>
L7:
  mov    0x8(%r14),%rdi
  lea    D27(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L20
L11:
  mov    0x10(%r14),%rdi
  lea    D56(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L85
L57:
  xor    %r12d,%r12d
  mov    %rsp,%rbx
  lea    D58(%rip),%r15
  nopl   (%rax)
L25:
  mov    %rbp,%rcx
  mov    $0xb48,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  cmp    $0xb48,%eax
  jne    L73
  lea    0x4(%rsp),%rdi
  mov    %r13,%rcx
  mov    $0xb40,%edx
  mov    $0x1,%esi
  add    $0x1,%r12d
  call   <fwrite@plt>
  cmp    $0xb40,%eax
  je     L25
  mov    %r15,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L73:
  mov    0x8(%r14),%rsi
  mov    %r12d,%edx
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0xb48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xb58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  mov    0x8(%r14),%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L11
L85:
  mov    0x10(%r14),%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L57
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D27
datatype: string
name: read_data
arguments: tag: D56
datatype: string
name: read_data
arguments: tag: D58
datatype: string
name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D39
datatype: string

tool: D27: r

tool: D56: w

tool: D58: Error during write

tool: D11: %s: converted %d blocks


tool: D39: Cannot open File %s for input


assistant: ```c
main(int ac, char *av[]) {
  FILE *fi, *fo;
  char buf[2888];
  int n;
  if (ac != 3)
    usage(av[0]);
  fi = fopen(av[1], "r");
  if (fi == NULL) {
    printf("Cannot open File %s for input\n", av[1]);
    exit(-1);
  }
  fo = fopen(av[2], "w");
  if (fo == NULL) {
    printf("Cannot open File %s for input\n", av[2]);
    exit(-1);
  }
  n = 0;
  while (fread(buf, 1, 2888, fi) == 2888) {
    n++;
    if (fwrite(&buf[4], 1, 2880, fo) != 2880) {
      perror("Error during write");
      exit(-1);
    }
  }
  printf("%s: converted %d blocks\n", av[1], n);
  fclose(fi);
  fclose(fo);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb48(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  je     L33
  mov    (%rsi),%rdi
  call   <usage@plt>
L33:
  mov    0x8(%r14),%rdi
  lea    D21(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L32
L37:
  mov    0x10(%r14),%rdi
  lea    D32(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L12
L3:
  xor    %r12d,%r12d
  mov    %rsp,%rbx
  lea    D8(%rip),%r15
  nopl   (%rax)
L81:
  mov    %rbp,%rcx
  mov    $0xb48,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  cmp    $0xb48,%eax
  jne    L86
  lea    0x4(%rsp),%rdi
  mov    %r13,%rcx
  mov    $0xb40,%edx
  mov    $0x1,%esi
  add    $0x1,%r12d
  call   <fwrite@plt>
  cmp    $0xb40,%eax
  je     L81
  mov    %r15,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L86:
  mov    0x8(%r14),%rsi
  mov    %r12d,%edx
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0xb48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0xb58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    0x8(%r14),%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L37
L12:
  mov    0x10(%r14),%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L3
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D32
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D23
type_infered: string
name: read_data
arguments: data_label: D30
type_infered: string

tool: D21: r

tool: D32: w

tool: D8: Error during write

tool: D23: %s: converted %d blocks


tool: D30: Cannot open File %s for input


assistant: ```c
main(int ac, char *av[]) {
  FILE *fi, *fo;
  char buf[2888];
  int n;
  if (ac != 3)
    usage(av[0]);
  fi = fopen(av[1], "r");
  if (fi == NULL) {
    printf("Cannot open File %s for input\n", av[1]);
    exit(-1);
  }
  fo = fopen(av[2], "w");
  if (fo == NULL) {
    printf("Cannot open File %s for input\n", av[2]);
    exit(-1);
  }
  n = 0;
  while (fread(buf, 1, 2888, fi) == 2888) {
    n++;
    if (fwrite(&buf[4], 1, 2880, fo) != 2880) {
      perror("Error during write");
      exit(-1);
    }
  }
  printf("%s: converted %d blocks\n", av[1], n);
  fclose(fi);
  fclose(fo);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x0,-0xa(%rbp)
  jmp    L14
L15:
  lea    -0xa(%rbp),%rax
  mov    %rax,%rdi
  call   <outside@plt>
  movzwl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xa(%rbp)
L14:
  movzwl -0xa(%rbp),%eax
  cwtl
  cmp    %eax,-0x14(%rbp)
  jg     L15
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void test1(int n, int *x) {
  short i;
  for (i = 0; i < n; i++) {
    outside(&i);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x0,0x6(%rsp)
  test   %edi,%edi
  jle    L28
  mov    %edi,%ebx
  lea    0x6(%rsp),%rbp
L1:
  mov    %rbp,%rdi
  call   <outside@plt>
  movzwl 0x6(%rsp),%eax
  add    $0x1,%eax
  mov    %ax,0x6(%rsp)
  cwtl
  cmp    %ebx,%eax
  jl     L1
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test1(int n, int *x) {
  short i;
  for (i = 0; i < n; i++) {
    outside(&i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  mov    %ax,0x6(%rsp)
  test   %edi,%edi
  jle    L23
  mov    %edi,%ebx
  lea    0x6(%rsp),%rbp
  nopl   0x0(%rax)
L16:
  mov    %rbp,%rdi
  call   <outside@plt>
  movzwl 0x6(%rsp),%eax
  add    $0x1,%eax
  mov    %ax,0x6(%rsp)
  cwtl
  cmp    %ebx,%eax
  jl     L16
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test1(int n, int *x) {
  short i;
  for (i = 0; i < n; i++) {
    outside(&i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  mov    %ax,0x6(%rsp)
  test   %edi,%edi
  jle    L10
  mov    %edi,%ebx
  lea    0x6(%rsp),%rbp
  nopl   0x0(%rax)
L24:
  mov    %rbp,%rdi
  call   <outside@plt>
  movzwl 0x6(%rsp),%eax
  add    $0x1,%eax
  mov    %ax,0x6(%rsp)
  cwtl
  cmp    %ebx,%eax
  jl     L24
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test1(int n, int *x) {
  short i;
  for (i = 0; i < n; i++) {
    outside(&i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<t6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  andl   $0xffffffe0,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int t6(int len, void *dummy, unsigned short *__restrict x) {
  len = len & ~31;
  unsigned int result = 0;
  __asm volatile("");
  for (int i = 0; i < len; i++)
    result += x[i];
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<t6>:
  endbr64
  and    $0xffffffe0,%edi
  jle    L5
  mov    %rdx,%rax
  lea    -0x1(%rdi),%ecx
  lea    0x2(%rdx,%rcx,2),%rsi
  mov    $0x0,%edx
L11:
  movzwl (%rax),%ecx
  add    %ecx,%edx
  add    $0x2,%rax
  cmp    %rsi,%rax
  jne    L11
L20:
  mov    %edx,%eax
  ret
L5:
  mov    $0x0,%edx
  jmp    L20
```

assistant: ```c
int t6(int len, void *dummy, unsigned short *__restrict x) {
  len = len & ~31;
  unsigned int result = 0;
  __asm volatile("");
  for (int i = 0; i < len; i++)
    result += x[i];
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<t6>:
  endbr64
  and    $0xffffffe0,%edi
  jle    L8
  lea    -0x1(%rdi),%eax
  lea    0x2(%rdx,%rax,2),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L17:
  movzwl (%rdx),%ecx
  add    $0x2,%rdx
  add    %ecx,%eax
  cmp    %rsi,%rdx
  jne    L17
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int t6(int len, void *dummy, unsigned short *__restrict x) {
  len = len & ~31;
  unsigned int result = 0;
  __asm volatile("");
  for (int i = 0; i < len; i++)
    result += x[i];
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<t6>:
  endbr64
  and    $0xffffffe0,%edi
  jle    L10
  shr    $0x3,%edi
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  lea    -0x1(%rdi),%eax
  shl    $0x4,%rax
  lea    0x10(%rdx,%rax,1),%rax
L5:
  movdqu (%rdx),%xmm0
  add    $0x10,%rdx
  movdqa %xmm0,%xmm3
  punpcklwd %xmm2,%xmm0
  punpckhwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rdx,%rax
  jne    L5
  movdqa %xmm1,%xmm0
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  ret
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int t6(int len, void *dummy, unsigned short *__restrict x) {
  len = len & ~31;
  unsigned int result = 0;
  __asm volatile("");
  for (int i = 0; i < len; i++)
    result += x[i];
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getCenterDisk>:
  endbr64
  push   %r14
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x10,%rsp
  mov    (%rsi),%rax
  movq   (%rdi),%xmm0
  mov    $0x2,%esi
  movq   %rax,%xmm3
  mov    %rax,%r14
  mov    %edx,%eax
  shr    $0x1f,%eax
  psubd  %xmm3,%xmm0
  lea    (%rax,%rdx,1),%edi
  sar    %edi
  movq   %xmm0,(%rsp)
  call   <pow@plt>
  mov    (%rsp),%edi
  mov    $0x2,%esi
  movd   %xmm0,%ebx
  call   <pow@plt>
  mov    0x4(%rsp),%edi
  mov    $0x2,%esi
  movss  %xmm0,0xc(%rsp)
  call   <pow@plt>
  addss  0xc(%rsp),%xmm0
  ucomiss D14(%rip),%xmm0
  jp     L2
  jne    L2
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
  nop
L2:
  movd   %ebx,%xmm2
  movq   (%rsp),%xmm5
  lea    D53(%rip),%r12
  divss  %xmm0,%xmm2
  cvtdq2ps %xmm5,%xmm1
  movlps %xmm1,(%rsp)
  mulss  D12(%rip),%xmm2
  movaps %xmm2,%xmm0
  subss  D2(%rip),%xmm0
  cvttss2si %xmm0,%edi
  call   <fabsf@plt>
  call   <sqrt@plt>
  movq   (%rsp),%xmm1
  movq   %r14,%xmm6
  mov    %r12,%rax
  shufps $0xe0,%xmm0,%xmm0
  mulps  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0xe1,%xmm0,%xmm0
  addps  %xmm0,%xmm2
  subps  %xmm0,%xmm1
  movq   D13(%rip),%xmm0
  movss  %xmm2,%xmm1
  mulps  %xmm0,%xmm1
  cvtdq2ps %xmm6,%xmm0
  addps  %xmm0,%xmm1
  cvttps2dq %xmm1,%xmm1
  movq   %xmm1,D8(%rip)
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D12
type_infered: f32
name: retrieve_data
arguments: data_tag: D2
type_infered: f32
name: retrieve_data
arguments: data_tag: D13
type_infered: byte[8]

tool: {"D14": [0x00,0x00,0x00,0x00]}

tool: D12: 4

tool: D2: 1

tool: {"D13": [0x00,0x00,0x00,0x3f,0x00,0x00,0x00,0x3f]}

assistant: ```c
int *getCenterDisk(int p1[], int p2[], int epsilon) {
  static int c[2];
  int x1 = p1[0], y1 = p1[1];
  int x2 = p2[0], y2 = p2[1];
  float r2 = pow(epsilon / 2, 2);
  int x = x1 - x2;
  int y = y1 - y2;
  float d2 = pow(x, 2) + pow(y, 2);
  if (d2 == 0) {
    return p1;
  }
  float e = fabsf(4 * (r2 / d2) - 1);
  float r = sqrt(e);
  c[0] = (int)(((x + y * r) / 2) + x2);
  c[1] = (int)(((y - x * r) / 2) + y2);
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  xor    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  imul   $0x293b497,%rax,%rax
  add    $0x527692e,%rax
  xor    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L25
L19:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <nextrand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x57619f1,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x1770,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <test_lookup@plt>
  addq   $0x1,-0x18(%rbp)
L25:
  cmpq   $0x5f5e0ff,-0x18(%rbp)
  jbe    L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: Running with %ld


assistant: ```c
void *read_table(void *val) {
  size_t id = (size_t)val;
  printf("Running with %ld\n", id);
  uint64_t rng = id ^ (id * 100) ^ ((id + 2) * 43234455);
  for (size_t i = 0; i < (100 * 100 * 100 * 100); i++) {
    test_lookup(nextrand(&rng) % (3000 * 2), id);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_table>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x0(%rbp,%rbp,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  xor    %rbp,%rax
  imul   $0x293b497,%rbp,%rdx
  add    $0x527692e,%rdx
  xor    %rdx,%rax
  mov    %rax,(%rsp)
  mov    $0x5f5e100,%ebx
  mov    %rsp,%r12
L14:
  mov    %r12,%rdi
  call   <nextrand@plt>
  movslq %eax,%rdx
  imul   $0x57619f1,%rdx,%rdx
  sar    $0x27,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1770,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <test_lookup@plt>
  sub    $0x1,%rbx
  jne    L14
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: Running with %ld


assistant: ```c
void *read_table(void *val) {
  size_t id = (size_t)val;
  printf("Running with %ld\n", id);
  uint64_t rng = id ^ (id * 100) ^ ((id + 2) * 43234455);
  for (size_t i = 0; i < (100 * 100 * 100 * 100); i++) {
    test_lookup(nextrand(&rng) % (3000 * 2), id);
  }
  return 0;
}
```