ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<__hsail_atomic_wrapinc_u32>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%r12
  lea    0x1(%r12),%rdx
  cmp    %rbp,%r12
  jl     L9
  xor    %edx,%edx
L9:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <__sync_bool_compare_and_swap@plt>
  test   %eax,%eax
  je     L3
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t __hsail_atomic_wrapinc_u32(uint32_t *ptr, uint32_t a) {
  int done = 0;
  uint32_t old_value;
  uint32_t new_value;
  while (!done) {
    old_value = *ptr;
    new_value = (old_value >= a) ? 0 : (old_value + 1);
    done = __sync_bool_compare_and_swap(ptr, old_value, new_value);
  }
  return old_value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<WaitForXfer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x1e8480,-0x10(%rbp)
L4:
  lea    -0x11(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x34,%esi
  mov    %rax,%rdi
  call   <bbm_read@plt>
  subl   $0x1,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jle    L50
  movzbl -0x11(%rbp),%eax
  movzbl %al,%eax
  and    $0x2,%eax
  test   %eax,%eax
  jne    L4
L50:
  movzbl -0x11(%rbp),%eax
  movzbl %al,%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L8
  movl   $0x4,-0xc(%rbp)
  jmp    L33
L8:
  lea    -0x11(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x34,%esi
  mov    %rax,%rdi
  call   <bbm_read@plt>
  movzbl -0x11(%rbp),%eax
  test   %al,%al
  jns    L63
  movl   $0x2,-0xc(%rbp)
  jmp    L33
L63:
  movl   $0x0,-0xc(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
signed int WaitForXfer(void *handle) {
  signed int i;
  signed int res = 0;
  unsigned char status;
  i = 100 * 20000;
  do {
    bbm_read(handle, 0x0034, &status);
    i--;
  } while ((i > 0) && (status & 0x02));
  if (status & 0x02) {
    res = 4;
  } else {
    bbm_read(handle, 0x0034, &status);
    if (status & 0x80)
      res = 2;
    else
      res = 0;
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<WaitForXfer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdx
  mov    $0x34,%esi
  call   <bbm_read@plt>
  mov    $0x1e847f,%ebx
  lea    0x7(%rsp),%r12
L16:
  testb  $0x2,0x7(%rsp)
  je     L37
  mov    %r12,%rdx
  mov    $0x34,%esi
  mov    %rbp,%rdi
  call   <bbm_read@plt>
  sub    $0x1,%ebx
  jne    L16
  testb  $0x2,0x7(%rsp)
  je     L37
  mov    $0x4,%eax
L40:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  lea    0x7(%rsp),%rdx
  mov    $0x34,%esi
  mov    %rbp,%rdi
  call   <bbm_read@plt>
  movsbl 0x7(%rsp),%eax
  shr    $0x1f,%eax
  add    %eax,%eax
  jmp    L40
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed int WaitForXfer(void *handle) {
  signed int i;
  signed int res = 0;
  unsigned char status;
  i = 100 * 20000;
  do {
    bbm_read(handle, 0x0034, &status);
    i--;
  } while ((i > 0) && (status & 0x02));
  if (status & 0x02) {
    res = 4;
  } else {
    bbm_read(handle, 0x0034, &status);
    if (status & 0x80)
      res = 2;
    else
      res = 0;
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<WaitForXfer>:
  endbr64
  push   %r12
  mov    $0x34,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1e847f,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r12
  mov    %r12,%rdx
  call   <bbm_read@plt>
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdx
  mov    $0x34,%esi
  mov    %rbp,%rdi
  call   <bbm_read@plt>
  sub    $0x1,%ebx
  je     L53
L38:
  testb  $0x2,0x7(%rsp)
  jne    L1
L47:
  mov    %r12,%rdx
  mov    $0x34,%esi
  mov    %rbp,%rdi
  call   <bbm_read@plt>
  movsbl 0x7(%rsp),%eax
  shr    $0x1f,%eax
  add    %eax,%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L53:
  testb  $0x2,0x7(%rsp)
  je     L47
  mov    $0x4,%eax
  jmp    L29
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed int WaitForXfer(void *handle) {
  signed int i;
  signed int res = 0;
  unsigned char status;
  i = 100 * 20000;
  do {
    bbm_read(handle, 0x0034, &status);
    i--;
  } while ((i > 0) && (status & 0x02));
  if (status & 0x02) {
    res = 4;
  } else {
    bbm_read(handle, 0x0034, &status);
    if (status & 0x80)
      res = 2;
    else
      res = 0;
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WaitForXfer>:
  endbr64
  push   %r12
  mov    $0x34,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1e847f,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r12
  mov    %r12,%rdx
  call   <bbm_read@plt>
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r12,%rdx
  mov    $0x34,%esi
  mov    %rbp,%rdi
  call   <bbm_read@plt>
  sub    $0x1,%ebx
  je     L6
L13:
  testb  $0x2,0x7(%rsp)
  jne    L23
L52:
  mov    %r12,%rdx
  mov    $0x34,%esi
  mov    %rbp,%rdi
  call   <bbm_read@plt>
  movsbl 0x7(%rsp),%eax
  shr    $0x1f,%eax
  add    %eax,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L6:
  testb  $0x2,0x7(%rsp)
  je     L52
  mov    $0x4,%eax
  jmp    L27
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed int WaitForXfer(void *handle) {
  signed int i;
  signed int res = 0;
  unsigned char status;
  i = 100 * 20000;
  do {
    bbm_read(handle, 0x0034, &status);
    i--;
  } while ((i > 0) && (status & 0x02));
  if (status & 0x02) {
    res = 4;
  } else {
    bbm_read(handle, 0x0034, &status);
    if (status & 0x80)
      res = 2;
    else
      res = 0;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  movl   $0x0,-0x20(%rbp)
  jmp    L6
L35:
  movl   $0x0,-0x1c(%rbp)
  jmp    L2
L18:
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  movl   $0x0,(%rcx,%rdx,4)
  addl   $0x1,-0x1c(%rbp)
L2:
  mov    -0x1c(%rbp),%edx
  cmp    -0x24(%rbp),%edx
  jl     L18
  addl   $0x1,-0x20(%rbp)
L6:
  mov    -0x20(%rbp),%edx
  cmp    -0x24(%rbp),%edx
  jl     L35
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void initialize(int n, bool a[n][n]) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++)
      a[i][j] = false;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<initialize>:
  endbr64
  movslq %edi,%r8
  test   %edi,%edi
  jle    L4
  shl    $0x2,%r8
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rdx
  mov    $0x0,%ecx
  mov    %edi,%esi
  neg    %rsi
  shl    $0x2,%rsi
L20:
  lea    (%rsi,%rdx,1),%rax
L9:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L9
  add    $0x1,%ecx
  add    %r8,%rdx
  cmp    %ecx,%edi
  jne    L20
L4:
  ret
```

assistant: ```c
void initialize(int n, bool a[n][n]) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++)
      a[i][j] = false;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initialize>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L0
  mov    %rbp,%r12
  mov    %rsi,%rcx
  shl    $0x2,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rcx,%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x1,%ebx
  call   <memset@plt>
  mov    %rax,%rcx
  add    %rbp,%rcx
  cmp    %ebx,%r12d
  jne    L9
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void initialize(int n, bool a[n][n]) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++)
      a[i][j] = false;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<initialize>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L11
  mov    %rbp,%r12
  mov    %rsi,%rcx
  shl    $0x2,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rcx,%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x1,%ebx
  call   <memset@plt>
  mov    %rax,%rcx
  add    %rbp,%rcx
  cmp    %ebx,%r12d
  jne    L16
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void initialize(int n, bool a[n][n]) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++)
      a[i][j] = false;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L9
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  test   %edx,%edx
  jne    L29
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L9:
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L45:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x2c(%rbp),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <add>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L45
L29:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: %s


assistant: ```c
void add(char *v, char *digits, int n_digits, int position, int max) {
  if (position == max) {
    v[position] = '\0';
    if (atoi(v) % 7 == 0)
      printf("%s\n", v);
  } else {
    int i;
    for (i = 0; i < n_digits; i++) {
      v[position] = digits[i];
      add(v, digits, n_digits, position + 1, max);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %ecx,%r12d
  mov    %r8d,0x4(%rsp)
  cmp    %r8d,%ecx
  je     L36
  mov    %rsi,%r14
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L26
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%rax
  mov    %rax,0x8(%rsp)
  movslq %ecx,%r15
L42:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp,%r15,1)
  lea    0x1(%r12),%ecx
  mov    0x4(%rsp),%r8d
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <add>
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L42
L26:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  movslq %ecx,%r12
  movb   $0x0,(%rdi,%r12,1)
  call   <atoi@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  cmp    %ecx,%eax
  jne    L26
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: %s


assistant: ```c
void add(char *v, char *digits, int n_digits, int position, int max) {
  if (position == max) {
    v[position] = '\0';
    if (atoi(v) % 7 == 0)
      printf("%s\n", v);
  } else {
    int i;
    for (i = 0; i < n_digits; i++) {
      v[position] = digits[i];
      add(v, digits, n_digits, position + 1, max);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r8d,%ecx
  je     L17
  mov    %edx,%r12d
  test   %edx,%edx
  jle    L7
  lea    -0x1(%rdx),%eax
  movslq %ecx,%r14
  mov    %rsi,%r13
  mov    %rsi,%rbx
  lea    0x1(%rsi,%rax,1),%rax
  add    %rdi,%r14
  lea    0x1(%rcx),%ebp
  mov    %rax,0x8(%rsp)
L20:
  movzbl (%rbx),%eax
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  mov    %r8d,0x4(%rsp)
  add    $0x1,%rbx
  mov    %al,(%r14)
  call   <add>
  cmp    0x8(%rsp),%rbx
  mov    0x4(%rsp),%r8d
  jne    L20
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  movslq %ecx,%rcx
  movb   $0x0,(%rdi,%rcx,1)
  call   <atoi@plt>
  imul   $0xb6db6db7,%eax,%eax
  add    $0x12492492,%eax
  cmp    $0x24924924,%eax
  ja     L7
  add    $0x18,%rsp
  mov    %r15,%rsi
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: %s


assistant: ```c
void add(char *v, char *digits, int n_digits, int position, int max) {
  if (position == max) {
    v[position] = '\0';
    if (atoi(v) % 7 == 0)
      printf("%s\n", v);
  } else {
    int i;
    for (i = 0; i < n_digits; i++) {
      v[position] = digits[i];
      add(v, digits, n_digits, position + 1, max);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Modulus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L5
  movsd  -0x8(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L5:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double Modulus(double arg1, double arg2) {
  int i;
  double ret_val;
  ret_val = arg1;
  i = ret_val / arg2;
  ret_val -= i * arg2;
  if (ret_val < 0.0)
    ret_val += arg2;
  return ret_val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Modulus>:
  endbr64
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mulsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  ja     L16
L3:
  ret
L16:
  addsd  %xmm1,%xmm0
  jmp    L3
```

assistant: ```c
double Modulus(double arg1, double arg2) {
  int i;
  double ret_val;
  ret_val = arg1;
  i = ret_val / arg2;
  ret_val -= i * arg2;
  if (ret_val < 0.0)
    ret_val += arg2;
  return ret_val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Modulus>:
  endbr64
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mulsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  ja     L9
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double Modulus(double arg1, double arg2) {
  int i;
  double ret_val;
  ret_val = arg1;
  i = ret_val / arg2;
  ret_val -= i * arg2;
  if (ret_val < 0.0)
    ret_val += arg2;
  return ret_val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Modulus>:
  endbr64
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mulsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  ja     L2
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double Modulus(double arg1, double arg2) {
  int i;
  double ret_val;
  ret_val = arg1;
  i = ret_val / arg2;
  ret_val -= i * arg2;
  if (ret_val < 0.0)
    ret_val += arg2;
  return ret_val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lock_reg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    %dx,-0x2c(%rbp)
  mov    %ax,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x18,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x20(%rbp)
  movzwl -0x30(%rbp),%eax
  mov    %ax,-0x1e(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int lock_reg(int fd, int cmd, short l_type, short l_whence, off_t l_start, off_t l_len) {
  struct flock lock;
  memset(&lock, 0, sizeof(struct flock));
  lock.l_type = l_type;
  lock.l_whence = l_whence;
  lock.l_start = l_start;
  lock.l_len = l_len;
  return fcntl(fd, cmd, &lock);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lock_reg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,%ebx
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %r8,%r12
  mov    %r9,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  mov    $0x18,%edx
  mov    $0x0,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  mov    %r14w,0x10(%rsp)
  mov    %r13w,0x12(%rsp)
  mov    %r12,0x20(%rsp)
  mov    %rbp,0x18(%rsp)
  mov    %r15,%rdx
  mov    %ebx,%esi
  mov    0xc(%rsp),%edi
  call   <fcntl@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lock_reg(int fd, int cmd, short l_type, short l_whence, off_t l_start, off_t l_len) {
  struct flock lock;
  memset(&lock, 0, sizeof(struct flock));
  lock.l_type = l_type;
  lock.l_whence = l_whence;
  lock.l_start = l_start;
  lock.l_len = l_len;
  return fcntl(fd, cmd, &lock);
}
```
user: What is the c source code of the assembly code below:

```asm
<lock_reg>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  mov    $0x18,%edx
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r8
  mov    %r8,%rdi
  mov    %r8,0x8(%rsp)
  call   <memset@plt>
  mov    0x8(%rsp),%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %r15w,0x10(%rsp)
  mov    %r14w,0x12(%rsp)
  mov    %r13,0x20(%rsp)
  mov    %rbx,0x18(%rsp)
  call   <fcntl@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lock_reg(int fd, int cmd, short l_type, short l_whence, off_t l_start, off_t l_len) {
  struct flock lock;
  memset(&lock, 0, sizeof(struct flock));
  lock.l_type = l_type;
  lock.l_whence = l_whence;
  lock.l_start = l_start;
  lock.l_len = l_len;
  return fcntl(fd, cmd, &lock);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lock_reg>:
  endbr64
  push   %r13
  movq   %r9,%xmm0
  movq   %r8,%xmm1
  shl    $0x10,%ecx
  push   %r12
  punpcklqdq %xmm1,%xmm0
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  movzwl %dx,%ebx
  mov    $0x18,%edx
  or     %ecx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  movaps %xmm0,(%rsp)
  mov    %r13,%rdi
  call   <memset@plt>
  movdqa (%rsp),%xmm0
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %ebx,0x10(%rsp)
  movups %xmm0,0x18(%rsp)
  call   <fcntl@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lock_reg(int fd, int cmd, short l_type, short l_whence, off_t l_start, off_t l_len) {
  struct flock lock;
  memset(&lock, 0, sizeof(struct flock));
  lock.l_type = l_type;
  lock.l_whence = l_whence;
  lock.l_start = l_start;
  lock.l_len = l_len;
  return fcntl(fd, cmd, &lock);
}
```