ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x838,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x828(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L42
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  mov    %rbx,%r12
  xchg   %ax,%ax
L38:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebp,%eax
  jg     L38
  test   %eax,%eax
  jle    L42
  movslq %eax,%r8
  xor    %esi,%esi
  lea    0x50(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L45:
  mov    (%rbx,%rsi,4),%ecx
  test   %ecx,%ecx
  jle    L66
  add    $0x1,%ecx
  mov    $0x1,%eax
  mov    $0x1,%edx
L18:
  lea    (%rax,%rax,1),%edi
  add    $0x1,%eax
  test   $0x1,%dl
  cmovne %edi,%eax
  add    $0x1,%edx
  cmp    %edx,%ecx
  jne    L18
  mov    %eax,0x0(%rbp,%rsi,4)
  add    $0x1,%rsi
  cmp    %r8,%rsi
  jne    L45
L36:
  xor    %ebx,%ebx
  lea    D16(%rip),%r12
  nopl   (%rax)
L15:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L15
L42:
  mov    0x828(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x838,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L66:
  mov    $0x1,%eax
  mov    %eax,0x0(%rbp,%rsi,4)
  add    $0x1,%rsi
  cmp    %r8,%rsi
  jne    L45
  jmp    L36
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string
name: extract_symbolic_data
arguments: label: D16
type: string

tool: D7: %d

tool: D16: %d


assistant: ```c
int main() {
  int i, j, n, h, k, m, t, p;
  int test[15], val[500];
  scanf("%d", &t);
  for (m = 0; m < t; m++)
    scanf("%d", &test[m]);
  for (k = 0; k < t; k++) {
    if (test[k] == 0)
      h = 1;
    else {
      h = 1;
      for (j = 1; j <= test[k]; j++) {
        if (j % 2 != 0)
          h = 2 * h;
        else if (j % 2 == 0)
          h = h + 1;
      }
    }
    val[k] = h;
  }
  for (p = 0; p < t; p++)
    printf("%d\n", val[p]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x838,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x828(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L13
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  mov    %rbx,%r12
  xchg   %ax,%ax
L3:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebp,%eax
  jg     L3
  test   %eax,%eax
  jle    L13
  movslq %eax,%r8
  xor    %esi,%esi
  lea    0x50(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L91:
  mov    (%rbx,%rsi,4),%ecx
  test   %ecx,%ecx
  jle    L36
  add    $0x1,%ecx
  mov    $0x1,%eax
  mov    $0x1,%edx
L31:
  lea    (%rax,%rax,1),%edi
  add    $0x1,%eax
  test   $0x1,%dl
  cmovne %edi,%eax
  add    $0x1,%edx
  cmp    %edx,%ecx
  jne    L31
  mov    %eax,0x0(%rbp,%rsi,4)
  add    $0x1,%rsi
  cmp    %r8,%rsi
  jne    L91
L0:
  xor    %ebx,%ebx
  lea    D8(%rip),%r12
  nopl   (%rax)
L67:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L67
L13:
  mov    0x828(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x838,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L36:
  mov    $0x1,%eax
  mov    %eax,0x0(%rbp,%rsi,4)
  add    $0x1,%rsi
  cmp    %r8,%rsi
  jne    L91
  jmp    L0
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D8
type: string

tool: D17: %d

tool: D8: %d


assistant: ```c
int main() {
  int i, j, n, h, k, m, t, p;
  int test[15], val[500];
  scanf("%d", &t);
  for (m = 0; m < t; m++)
    scanf("%d", &test[m]);
  for (k = 0; k < t; k++) {
    if (test[k] == 0)
      h = 1;
    else {
      h = 1;
      for (j = 1; j <= test[k]; j++) {
        if (j % 2 != 0)
          h = 2 * h;
        else if (j % 2 == 0)
          h = h + 1;
      }
    }
    val[k] = h;
  }
  for (p = 0; p < t; p++)
    printf("%d\n", val[p]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <tmpfile@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  test   %rax,%rax
  je     L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  FILE *fp = tmpfile();
  if (ftell(fp) != 0) {
    abort();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tmpfile@plt>
  mov    %rax,%rdi
  call   <ftell@plt>
  test   %rax,%rax
  jne    L19
L4:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L19:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L4
```

assistant: ```c
int main() {
  FILE *fp = tmpfile();
  if (ftell(fp) != 0) {
    abort();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tmpfile@plt>
  mov    %rax,%rdi
  call   <ftell@plt>
  test   %rax,%rax
  jne    L6
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L0
```

assistant: ```c
int main() {
  FILE *fp = tmpfile();
  if (ftell(fp) != 0) {
    abort();
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tmpfile@plt>
  mov    %rax,%rdi
  call   <ftell@plt>
  test   %rax,%rax
  jne    L4
L13:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L4:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L13
```

assistant: ```c
int main() {
  FILE *fp = tmpfile();
  if (ftell(fp) != 0) {
    abort();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L7
L65:
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jne    L73
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jne    L73
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L110
L73:
  cmpl   $0x0,-0xc(%rbp)
  jns    L84
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L110
L84:
  cmpl   $0x0,-0xc(%rbp)
  jne    L113
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L110
L113:
  mov    -0x20(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L76
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L110
L76:
  mov    -0x20(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L110:
  addl   $0x1,-0x14(%rbp)
L7:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L65
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D63
type_guessed: string
name: parse_data
arguments: data_label: D22
type_guessed: string
name: parse_data
arguments: data_label: D36
type_guessed: string

tool: D63: %d

tool: D22: %d %d %d

tool: D36: Case %d: %d


assistant: ```c
int main() {
  int t, n, k, p, i, m, temp;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d %d %d", &n, &k, &p);
    temp = n - k;
    m = p - temp;
    if (n == k && k == p)
      printf("Case %d: %d\n", i, n);
    else if (m < 0)
      printf("Case %d: %d\n", i, k + p);
    else if (m == 0)
      printf("Case %d: %d\n", i, n);
    else {
      if (m % n == 0)
        printf("Case %d: %d\n", i, n);
      else
        printf("Case %d: %d\n", i, m % n);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L66
  mov    $0x1,%ebx
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D27(%rip),%rbp
  lea    D26(%rip),%r14
  jmp    L98
L16:
  mov    %ecx,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L33
L62:
  add    %esi,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L33:
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jl     L66
L98:
  lea    0xc(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    %ecx,%edi
  sub    %edx,%edi
  mov    %esi,%eax
  sub    %edi,%eax
  cmp    %esi,%edx
  jne    L97
  cmp    %edx,%ecx
  je     L16
L97:
  test   %eax,%eax
  js     L62
  je     L120
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L126
  mov    %ecx,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L33
L120:
  mov    %ecx,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L33
L126:
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L33
L66:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D27
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string

tool: D15: %d

tool: D27: %d %d %d

tool: D26: Case %d: %d


assistant: ```c
int main() {
  int t, n, k, p, i, m, temp;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d %d %d", &n, &k, &p);
    temp = n - k;
    m = p - temp;
    if (n == k && k == p)
      printf("Case %d: %d\n", i, n);
    else if (m < 0)
      printf("Case %d: %d\n", i, k + p);
    else if (m == 0)
      printf("Case %d: %d\n", i, n);
    else {
      if (m % n == 0)
        printf("Case %d: %d\n", i, n);
      else
        printf("Case %d: %d\n", i, m % n);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L29
  mov    $0x1,%r15d
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  lea    D4(%rip),%rbx
  lea    D2(%rip),%r14
  jmp    L6
  nopl   0x0(%rax)
L39:
  je     L104
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L104
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L16:
  add    $0x1,%r15d
  cmp    %r15d,0x8(%rsp)
  jl     L29
L6:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  mov    %r8d,%esi
  sub    %edx,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  cmp    %ecx,%edx
  jne    L49
  cmp    %edx,%r8d
  je     L104
L49:
  test   %eax,%eax
  jns    L39
  mov    %r15d,%esi
  add    %ecx,%edx
  mov    %r14,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,0x8(%rsp)
  jge    L6
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L104:
  mov    %r8d,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L16
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D2
type: string

tool: D10: %d

tool: D4: %d %d %d

tool: D2: Case %d: %d


assistant: ```c
int main() {
  int t, n, k, p, i, m, temp;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d %d %d", &n, &k, &p);
    temp = n - k;
    m = p - temp;
    if (n == k && k == p)
      printf("Case %d: %d\n", i, n);
    else if (m < 0)
      printf("Case %d: %d\n", i, k + p);
    else if (m == 0)
      printf("Case %d: %d\n", i, n);
    else {
      if (m % n == 0)
        printf("Case %d: %d\n", i, n);
      else
        printf("Case %d: %d\n", i, m % n);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D16(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L38
  mov    $0x1,%r15d
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  lea    D4(%rip),%rbx
  lea    D25(%rip),%r14
  jmp    L74
  nopl   0x0(%rax)
L65:
  je     L69
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L69
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L35:
  add    $0x1,%r15d
  cmp    %r15d,0x8(%rsp)
  jl     L38
L74:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  mov    %r8d,%esi
  sub    %edx,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  cmp    %ecx,%edx
  jne    L47
  cmp    %edx,%r8d
  je     L69
L47:
  test   %eax,%eax
  jns    L65
  mov    %r15d,%esi
  add    %ecx,%edx
  mov    %r14,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,0x8(%rsp)
  jge    L74
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L69:
  mov    %r8d,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L35
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D25
type: string

tool: D16: %d

tool: D4: %d %d %d

tool: D25: Case %d: %d


assistant: ```c
int main() {
  int t, n, k, p, i, m, temp;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d %d %d", &n, &k, &p);
    temp = n - k;
    m = p - temp;
    if (n == k && k == p)
      printf("Case %d: %d\n", i, n);
    else if (m < 0)
      printf("Case %d: %d\n", i, k + p);
    else if (m == 0)
      printf("Case %d: %d\n", i, n);
    else {
      if (m % n == 0)
        printf("Case %d: %d\n", i, n);
      else
        printf("Case %d: %d\n", i, m % n);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L12
L23:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
L12:
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  cmpl   $0x63,-0xc(%rbp)
  jle    L23
L4:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int split(char *str, const char *delim, char *outlist[]) {
  char *token;
  int count = 0;
  token = strtok(str, delim);
  while (token != NULL && count < (100)) {
    outlist[count++] = token;
    token = strtok(NULL, delim);
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<split>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <strtok@plt>
  test   %rax,%rax
  je     L26
  mov    $0x1,%ebx
L12:
  mov    %ebx,%r13d
  mov    %rax,-0x8(%r12,%rbx,8)
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  test   %rax,%rax
  setne  %cl
  cmp    $0x63,%ebx
  setle  %dl
  add    $0x1,%rbx
  test   %dl,%cl
  jne    L12
L14:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  mov    $0x0,%r13d
  jmp    L14
```

assistant: ```c
int split(char *str, const char *delim, char *outlist[]) {
  char *token;
  int count = 0;
  token = strtok(str, delim);
  while (token != NULL && count < (100)) {
    outlist[count++] = token;
    token = strtok(NULL, delim);
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<split>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L11
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rax,-0x8(%r12,%rbx,8)
  xor    %edi,%edi
  mov    %rbp,%rsi
  mov    %ebx,%r13d
  call   <strtok@plt>
  test   %rax,%rax
  setne  %cl
  cmp    $0x63,%ebx
  setle  %dl
  add    $0x1,%rbx
  test   %dl,%cl
  jne    L14
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int split(char *str, const char *delim, char *outlist[]) {
  char *token;
  int count = 0;
  token = strtok(str, delim);
  while (token != NULL && count < (100)) {
    outlist[count++] = token;
    token = strtok(NULL, delim);
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<split>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L17
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rax,-0x8(%r12,%rbx,8)
  xor    %edi,%edi
  mov    %rbp,%rsi
  mov    %ebx,%r13d
  call   <strtok@plt>
  test   %rax,%rax
  setne  %cl
  cmp    $0x63,%ebx
  setle  %dl
  add    $0x1,%rbx
  test   %dl,%cl
  jne    L5
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L17:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int split(char *str, const char *delim, char *outlist[]) {
  char *token;
  int count = 0;
  token = strtok(str, delim);
  while (token != NULL && count < (100)) {
    outlist[count++] = token;
    token = strtok(NULL, delim);
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L17
L29:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L29
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const void *s1, const void *s2) {
  while (*(char *)s1 && (*(char *)s1 == *(char *)s2))
    s1++, s2++;
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L13
L28:
  cmp    %al,(%rsi)
  jne    L13
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L28
L13:
  movzbl %al,%eax
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const void *s1, const void *s2) {
  while (*(char *)s1 && (*(char *)s1 == *(char *)s2))
    s1++, s2++;
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcmp>:
  endbr64
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L20:
  cmp    %al,(%rsi)
  jne    L0
  add    $0x1,%rdi
  add    $0x1,%rsi
L13:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L20
  xor    %eax,%eax
L0:
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const void *s1, const void *s2) {
  while (*(char *)s1 && (*(char *)s1 == *(char *)s2))
    s1++, s2++;
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L28:
  cmp    %al,(%rsi)
  jne    L11
  add    $0x1,%rdi
  add    $0x1,%rsi
L18:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L28
  xor    %eax,%eax
L11:
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const void *s1, const void *s2) {
  while (*(char *)s1 && (*(char *)s1 == *(char *)s2))
    s1++, s2++;
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Q_box>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  movsd  %xmm4,-0x40(%rbp)
  movsd  %xmm5,-0x48(%rbp)
  movsd  %xmm6,-0x50(%rbp)
  movsd  %xmm7,-0x58(%rbp)
  movsd  -0x58(%rbp),%xmm6
  movsd  -0x50(%rbp),%xmm5
  movsd  -0x48(%rbp),%xmm4
  movsd  -0x40(%rbp),%xmm3
  movsd  -0x30(%rbp),%xmm2
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   0x10(%rbp)
  movapd %xmm6,%xmm7
  movapd %xmm5,%xmm6
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <Q_outlet_box@plt>
  add    $0x10,%rsp
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x34(%rbp),%edx
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  0x10(%rbp),%xmm3
  mov    %edx,%edi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <Q_inlet_box@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L4
  movsd  -0x10(%rbp),%xmm0
  jmp    L18
L4:
  movsd  -0x8(%rbp),%xmm0
L18:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double Q_box(double HW, double TW, double B, double D, int type, double S0, double L, double n, double ke, double g) {
  double Q_outlet_control = Q_outlet_box(HW, TW, B, D, S0, L, n, ke, g);
  double Q_inlet_control = Q_inlet_box(HW, B, D, type, g);
  return ((Q_outlet_control) < (Q_inlet_control) ? (Q_outlet_control) : (Q_inlet_control));
}
```