ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L20
  mov    $0x1,%ebx
  lea    D13(%rip),%r15
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L28:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L28
L20:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D33(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D27
type: string
name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D33
type: string
name: unpack_data
arguments: data_label: D49
type: string

tool: D4: How many grades will you be entering? 

tool: D27: %i

tool: D13: Enter a grade #%i: 

tool: D33: 
Grade average = %.2f


tool: D49: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter a grade #%i: ", i);
    scanf("%i", &grade);
    gradeTotal += grade;
    if (grade < 65) {
      ++failureCount;
    }
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D46(%rip),%rdi
  push   %r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L10
  mov    $0x1,%ebx
  lea    D47(%rip),%r15
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L6:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L6
L10:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D13(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D46
datatype: string
name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D47
datatype: string
name: read_data
arguments: tag: D13
datatype: string
name: read_data
arguments: tag: D35
datatype: string

tool: D46: How many grades will you be entering? 

tool: D3: %i

tool: D47: Enter a grade #%i: 

tool: D13: 
Grade average = %.2f


tool: D35: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter a grade #%i: ", i);
    scanf("%i", &grade);
    gradeTotal += grade;
    if (grade < 65) {
      ++failureCount;
    }
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<jambu_aut_ad_full>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <AESEncrypt@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  xor    %edx,%eax
  xor    $0x1,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  xor    $0x80,%dl
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void jambu_aut_ad_full(const unsigned int *rk, unsigned int *stateS, unsigned int *stateR) {
  AESEncrypt(rk, stateS);
  stateS[0] ^= stateR[0] ^ 0x01;
  stateS[1] ^= stateR[1];
  stateS[2] ^= 0x80;
  stateR[0] ^= stateS[2];
  stateR[1] ^= stateS[3];
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jambu_aut_ad_full>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <AESEncrypt@plt>
  mov    (%rbx),%eax
  xor    0x0(%rbp),%eax
  xor    $0x1,%eax
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%eax
  xor    %eax,0x4(%rbx)
  mov    0x8(%rbx),%eax
  xor    $0x80,%al
  mov    %eax,0x8(%rbx)
  xor    %eax,0x0(%rbp)
  mov    0xc(%rbx),%eax
  xor    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void jambu_aut_ad_full(const unsigned int *rk, unsigned int *stateS, unsigned int *stateR) {
  AESEncrypt(rk, stateS);
  stateS[0] ^= stateR[0] ^ 0x01;
  stateS[1] ^= stateR[1];
  stateS[2] ^= 0x80;
  stateR[0] ^= stateS[2];
  stateR[1] ^= stateS[3];
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jambu_aut_ad_full>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <AESEncrypt@plt>
  mov    (%rbx),%eax
  xor    0x0(%rbp),%eax
  xor    $0x1,%eax
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%eax
  xor    %eax,0x4(%rbx)
  mov    0x8(%rbx),%eax
  xor    $0x80,%al
  mov    %eax,0x8(%rbx)
  xor    %eax,0x0(%rbp)
  mov    0xc(%rbx),%eax
  xor    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void jambu_aut_ad_full(const unsigned int *rk, unsigned int *stateS, unsigned int *stateR) {
  AESEncrypt(rk, stateS);
  stateS[0] ^= stateR[0] ^ 0x01;
  stateS[1] ^= stateR[1];
  stateS[2] ^= 0x80;
  stateR[0] ^= stateS[2];
  stateR[1] ^= stateS[3];
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<jambu_aut_ad_full>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <AESEncrypt@plt>
  mov    (%rbx),%eax
  xor    0x0(%rbp),%eax
  xor    $0x1,%eax
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%eax
  xor    %eax,0x4(%rbx)
  mov    0x8(%rbx),%eax
  xor    $0x80,%al
  mov    %eax,0x8(%rbx)
  xor    %eax,0x0(%rbp)
  mov    0xc(%rbx),%eax
  xor    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void jambu_aut_ad_full(const unsigned int *rk, unsigned int *stateS, unsigned int *stateR) {
  AESEncrypt(rk, stateS);
  stateS[0] ^= stateR[0] ^ 0x01;
  stateS[1] ^= stateR[1];
  stateS[2] ^= 0x80;
  stateR[0] ^= stateS[2];
  stateR[1] ^= stateS[3];
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<case_utils_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void case_utils_min() {
  assert(((1) < (3) ? (1) : (3)) == 1);
  assert(((1) < (-3) ? (1) : (-3)) == -3);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<case_utils_min>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void case_utils_min() {
  assert(((1) < (3) ? (1) : (3)) == 1);
  assert(((1) < (-3) ? (1) : (-3)) == -3);
}
```
user: What is the c source code of the assembly code below:

```asm
<case_utils_min>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <assert@plt>
```

assistant: ```c
void case_utils_min() {
  assert(((1) < (3) ? (1) : (3)) == 1);
  assert(((1) < (-3) ? (1) : (-3)) == -3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<case_utils_min>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <assert@plt>
```

assistant: ```c
void case_utils_min() {
  assert(((1) < (3) ? (1) : (3)) == 1);
  assert(((1) < (-3) ? (1) : (-3)) == -3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<try_connect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
L24:
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1e,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <SK_connect@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L6
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <log_to_file@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  jmp    L7
L6:
  mov    -0x4(%rbp),%eax
  jmp    L22
L7:
  jmp    L24
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string

tool: D0: connect timeout

assistant: ```c
int try_connect(char *hostname, int port) {
  int sock;
  for (;;) {
    sock = SK_connect(hostname, port, 30);
    if (sock < 0) {
      log_to_file(hostname, port, "connect timeout");
      sleep(3);
      continue;
    }
    return sock;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<try_connect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    D2(%rip),%r12
L3:
  mov    $0x1e,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <SK_connect@plt>
  test   %eax,%eax
  js     L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <log_to_file@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: connect timeout

assistant: ```c
int try_connect(char *hostname, int port) {
  int sock;
  for (;;) {
    sock = SK_connect(hostname, port, 30);
    if (sock < 0) {
      log_to_file(hostname, port, "connect timeout");
      sleep(3);
      continue;
    }
    return sock;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<try_connect>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
L18:
  mov    $0x1e,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <SK_connect@plt>
  test   %eax,%eax
  js     L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <log_to_file@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6: connect timeout

assistant: ```c
int try_connect(char *hostname, int port) {
  int sock;
  for (;;) {
    sock = SK_connect(hostname, port, 30);
    if (sock < 0) {
      log_to_file(hostname, port, "connect timeout");
      sleep(3);
      continue;
    }
    return sock;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<try_connect>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
L7:
  mov    $0x1e,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <SK_connect@plt>
  test   %eax,%eax
  js     L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <log_to_file@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D1: connect timeout

assistant: ```c
int try_connect(char *hostname, int port) {
  int sock;
  for (;;) {
    sock = SK_connect(hostname, port, 30);
    if (sock < 0) {
      log_to_file(hostname, port, "connect timeout");
      sleep(3);
      continue;
    }
    return sock;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<call_with_0_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  xor    %rax,%rax
  call   *%rdx
  mov    %rax,%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long call_with_0_arg(int (*func)(), int argc, char **argv) {
  long ret;
  __asm__ __volatile__("xor %%rax, %%rax\n\t"
                       "call *%1\n\t"
                       "movq %%rax, %0"
                       : "=r"(ret)
                       : "r"(func)
                       : "rax");
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call_with_0_arg>:
  endbr64
  xor    %rax,%rax
  call   *%rdi
  mov    %rax,%rdi
  mov    %rdi,%rax
  ret
```

assistant: ```c
long call_with_0_arg(int (*func)(), int argc, char **argv) {
  long ret;
  __asm__ __volatile__("xor %%rax, %%rax\n\t"
                       "call *%1\n\t"
                       "movq %%rax, %0"
                       : "=r"(ret)
                       : "r"(func)
                       : "rax");
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<call_with_0_arg>:
  endbr64
  xor    %rax,%rax
  call   *%rdi
  mov    %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long call_with_0_arg(int (*func)(), int argc, char **argv) {
  long ret;
  __asm__ __volatile__("xor %%rax, %%rax\n\t"
                       "call *%1\n\t"
                       "movq %%rax, %0"
                       : "=r"(ret)
                       : "r"(func)
                       : "rax");
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<call_with_0_arg>:
  endbr64
  xor    %rax,%rax
  call   *%rdi
  mov    %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long call_with_0_arg(int (*func)(), int argc, char **argv) {
  long ret;
  __asm__ __volatile__("xor %%rax, %%rax\n\t"
                       "call *%1\n\t"
                       "movq %%rax, %0"
                       : "=r"(ret)
                       : "r"(func)
                       : "rax");
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inverte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L8
  mov    $0x1,%eax
  jmp    L15
L8:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <inverte>
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d

assistant: ```c
int inverte(int n) {
  if (n <= 1)
    return 1;
  else {
    printf("%d", (n % 10));
  }
  return inverte((int)(n / 10));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<inverte>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L6
  push   %rbx
  movslq %edi,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %edi,%esi
  sub    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <inverte>
  pop    %rbx
  ret
L6:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: %d

assistant: ```c
int inverte(int n) {
  if (n <= 1)
    return 1;
  else {
    printf("%d", (n % 10));
  }
  return inverte((int)(n / 10));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<inverte>:
  endbr64
  cmp    $0x1,%edi
  jle    L19
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    $0xcccccccd,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %ebp,%ebx
  mov    %ebp,%esi
  mov    %r13,%rdi
  imul   %r12,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%eax
  mov    %ebx,%ebp
  cmp    $0x13,%eax
  jg     L6
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: %d

assistant: ```c
int inverte(int n) {
  if (n <= 1)
    return 1;
  else {
    printf("%d", (n % 10));
  }
  return inverte((int)(n / 10));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inverte>:
  endbr64
  cmp    $0x1,%edi
  jle    L1
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    $0xcccccccd,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %ebp,%ebx
  mov    %ebp,%esi
  mov    %r13,%rdi
  imul   %r12,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%eax
  mov    %ebx,%ebp
  cmp    $0x13,%eax
  jg     L19
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
int inverte(int n) {
  if (n <= 1)
    return 1;
  else {
    printf("%d", (n % 10));
  }
  return inverte((int)(n / 10));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x24(%rbp)
  jne    L12
  movl   $0x4,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int f1(int val) {
  int *p;
  if (val == 0) {
    int val = 4;
    p = &val;
  }
  return (*p + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f1>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int f1(int val) {
  int *p;
  if (val == 0) {
    int val = 4;
    p = &val;
  }
  return (*p + 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f1>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int f1(int val) {
  int *p;
  if (val == 0) {
    int val = 4;
    p = &val;
  }
  return (*p + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<f1>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int f1(int val) {
  int *p;
  if (val == 0) {
    int val = 4;
    p = &val;
  }
  return (*p + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(int i, int b) {
  int j = 1;
  if (b)
    j = i;
  return j - i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  test   %esi,%esi
  mov    $0x1,%eax
  cmovne %edi,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int foo(int i, int b) {
  int j = 1;
  if (b)
    j = i;
  return j - i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  mov    $0x1,%eax
  xor    %edx,%edx
  sub    %edi,%eax
  test   %esi,%esi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int foo(int i, int b) {
  int j = 1;
  if (b)
    j = i;
  return j - i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  mov    $0x1,%eax
  xor    %edx,%edx
  sub    %edi,%eax
  test   %esi,%esi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int foo(int i, int b) {
  int j = 1;
  if (b)
    j = i;
  return j - i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_linear_search_returns_middle_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x20(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  movl   $0x2,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  lea    -0x14(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <linear_search@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  je     L13
  mov    $0x16,%ecx
  lea    D8(%rip),%rax
  mov    %rax,%rdx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__test_fail@plt>
L13:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string
name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D9
data_type: string

tool: D8: test_linear_search_returns_middle_index

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c

tool: D9: index == 1

assistant: ```c
void test_linear_search_returns_middle_index(void) {
  int length = 3;
  int array[] = {1, 2, 3};
  int element = 2;
  int index = linear_search(array, length, element);
  ((void)((index == 1) ? ((void)0) : __test_fail("index == 1", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c", __FUNCTION__, 22)));
}
```