user: Demonstrate the C code that generates the assembly output below:

```asm
<division>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  mov    0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L42
  mov    0x20(%rbp),%rax
  movl   $0xffffffff,(%rax)
  jmp    L16
L42:
  movl   $0x0,-0x18(%rbp)
  jmp    L119
L59:
  movl   $0x0,-0x14(%rbp)
  jmp    L6
L11:
  movl   $0x0,-0x10(%rbp)
  jmp    L93
L65:
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jge    L86
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L86
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  imul   -0x10(%rbp),%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x50(%rbp),%rax
  mov    (%rax),%edx
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  imul   -0x10(%rbp),%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L98
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x48(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%esi
  cltd
  idiv   %esi
  jmp    L61
L98:
  mov    $0x0,%eax
L61:
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L86:
  addl   $0x1,-0x10(%rbp)
L93:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L65
  addl   $0x1,-0x14(%rbp)
L6:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L11
  addl   $0x1,-0x18(%rbp)
L119:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L59
  mov    0x20(%rbp),%rax
  movl   $0x1,(%rax)
  nop
L16:
  pop    %rbp
  ret
```

assistant: ```c
void division(int *image1, int *width1, int *height1, int *depth1, int *image2, int *width2, int *height2, int *depth2, int *ret) {
  int i = 0, j = 0, d = 0;
  if (*depth1 != *depth2) {
    *ret = -1;
    return;
  }
  for (i = 0; i < *height1; i++) {
    for (j = 0; j < *width1; j++) {
      for (d = 0; d < *depth1; d++) {
        if (i < *height2 && j < *width2) {
          int index1 = ((*height1) * (j) + (i) + (*width1) * (*height1) * (d));
          int index2 = ((*height2) * (j) + (i) + (*width2) * (*height2) * (d));
          int res = (image2[index2] != 0) ? image1[index1] / image2[index2] : 0;
          image1[index1] = res;
        }
      }
    }
  }
  *ret = 1;
  return;
}
```