ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<Loggin2S>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <ToLoggin2SScreen@plt>
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L109
L41:
  mov    $0x0,%eax
  call   <WantNum@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L103
  cmpl   $0x2,-0x4(%rbp)
  jg     L72
  cmpl   $0x0,-0x4(%rbp)
  je     L102
  cmpl   $0x1,-0x4(%rbp)
  jne    L72
  mov    $0x0,%eax
  call   <SaleGoods@plt>
  cmp    $0xfffffffe,%eax
  je     L30
  cmp    $0xffffffff,%eax
  jne    L109
  mov    $0x0,%eax
  call   <ShowGoodNotFound@plt>
  mov    $0x0,%eax
  call   <WantEnter@plt>
  jmp    L128
L30:
  mov    $0x0,%eax
  call   <ShowGoodsCountLess@plt>
  mov    $0x0,%eax
  call   <WantEnter@plt>
  nop
L128:
  jmp    L109
L103:
  mov    $0x0,%eax
  call   <StockGoods@plt>
  cmp    $0xffffffff,%eax
  jne    L109
  mov    $0x0,%eax
  call   <ShowGoodNotFound@plt>
  mov    $0x0,%eax
  call   <WantEnter@plt>
  jmp    L109
L102:
  mov    $0x0,%eax
  call   <ToMainScreen@plt>
  mov    $0x1,%eax
  jmp    L19
L72:
  mov    $0x0,%eax
  call   <ShowInputTypeError@plt>
  mov    $0x0,%eax
  call   <WantEnter@plt>
  mov    $0x0,%eax
  call   <ToLoggin2SScreen@plt>
L109:
  cmpl   $0x0,-0x4(%rbp)
  js     L41
  cmpl   $0x2,-0x4(%rbp)
  jg     L41
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int Loggin2S() {
  ToLoggin2SScreen();
  int type = -1;
  while (type < 0 || type > 2) {
    type = WantNum();
    switch (type) {
    case 1:
      switch (SaleGoods()) {
      case -1: {
        ShowGoodNotFound();
        WantEnter();
        break;
      }
      case -2: {
        ShowGoodsCountLess();
        WantEnter();
        break;
      }
      }
      break;
    case 2:
      if (StockGoods() == -1) {
        ShowGoodNotFound();
        WantEnter();
      };
      break;
    case 0:
      ToMainScreen();
      return 1;
    default: {
      ShowInputTypeError();
      WantEnter();
      ToLoggin2SScreen();
    }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Loggin2S>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ToLoggin2SScreen@plt>
L83:
  mov    $0x0,%eax
  call   <WantNum@plt>
  cmp    $0x1,%eax
  je     L19
  cmp    $0x2,%eax
  je     L11
  test   %eax,%eax
  je     L68
  mov    $0x0,%eax
  call   <ShowInputTypeError@plt>
  mov    $0x0,%eax
  call   <WantEnter@plt>
  mov    $0x0,%eax
  call   <ToLoggin2SScreen@plt>
  jmp    L83
L19:
  mov    $0x0,%eax
  call   <SaleGoods@plt>
  cmp    $0xfffffffe,%eax
  je     L28
  mov    $0x0,%edx
  cmp    $0xffffffff,%eax
  jne    L22
  mov    $0x0,%eax
  call   <ShowGoodNotFound@plt>
  mov    $0x0,%eax
  call   <WantEnter@plt>
  jmp    L6
L28:
  mov    $0x0,%eax
  call   <ShowGoodsCountLess@plt>
  mov    $0x0,%eax
  call   <WantEnter@plt>
  jmp    L6
L11:
  mov    $0x0,%eax
  call   <StockGoods@plt>
  cmp    $0xffffffff,%eax
  je     L1
L6:
  mov    $0x0,%edx
  jmp    L22
L1:
  mov    $0x0,%eax
  call   <ShowGoodNotFound@plt>
  mov    $0x0,%eax
  call   <WantEnter@plt>
  jmp    L6
L68:
  mov    $0x0,%eax
  call   <ToMainScreen@plt>
  mov    $0x1,%edx
L22:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Loggin2S() {
  ToLoggin2SScreen();
  int type = -1;
  while (type < 0 || type > 2) {
    type = WantNum();
    switch (type) {
    case 1:
      switch (SaleGoods()) {
      case -1: {
        ShowGoodNotFound();
        WantEnter();
        break;
      }
      case -2: {
        ShowGoodsCountLess();
        WantEnter();
        break;
      }
      }
      break;
    case 2:
      if (StockGoods() == -1) {
        ShowGoodNotFound();
        WantEnter();
      };
      break;
    case 0:
      ToMainScreen();
      return 1;
    default: {
      ShowInputTypeError();
      WantEnter();
      ToLoggin2SScreen();
    }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Loggin2S>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ToLoggin2SScreen@plt>
  xor    %eax,%eax
  call   <WantNum@plt>
  cmp    $0x1,%eax
  je     L71
L11:
  cmp    $0x2,%eax
  je     L49
  test   %eax,%eax
  je     L17
  xor    %eax,%eax
  call   <ShowInputTypeError@plt>
  xor    %eax,%eax
  call   <WantEnter@plt>
  xor    %eax,%eax
  call   <ToLoggin2SScreen@plt>
  xor    %eax,%eax
  call   <WantNum@plt>
  cmp    $0x1,%eax
  jne    L11
L71:
  xor    %eax,%eax
  call   <SaleGoods@plt>
  cmp    $0xfffffffe,%eax
  je     L88
  cmp    $0xffffffff,%eax
  je     L6
L2:
  xor    %eax,%eax
L72:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L17:
  xor    %eax,%eax
  call   <ToMainScreen@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L49:
  xor    %eax,%eax
  call   <StockGoods@plt>
  cmp    $0xffffffff,%eax
  jne    L2
L6:
  xor    %eax,%eax
  call   <ShowGoodNotFound@plt>
  xor    %eax,%eax
  call   <WantEnter@plt>
  xor    %eax,%eax
  jmp    L72
  cs nopw 0x0(%rax,%rax,1)
L88:
  xor    %eax,%eax
  call   <ShowGoodsCountLess@plt>
  xor    %eax,%eax
  call   <WantEnter@plt>
  xor    %eax,%eax
  jmp    L72
```

assistant: ```c
int Loggin2S() {
  ToLoggin2SScreen();
  int type = -1;
  while (type < 0 || type > 2) {
    type = WantNum();
    switch (type) {
    case 1:
      switch (SaleGoods()) {
      case -1: {
        ShowGoodNotFound();
        WantEnter();
        break;
      }
      case -2: {
        ShowGoodsCountLess();
        WantEnter();
        break;
      }
      }
      break;
    case 2:
      if (StockGoods() == -1) {
        ShowGoodNotFound();
        WantEnter();
      };
      break;
    case 0:
      ToMainScreen();
      return 1;
    default: {
      ShowInputTypeError();
      WantEnter();
      ToLoggin2SScreen();
    }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Loggin2S>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ToLoggin2SScreen@plt>
  xor    %eax,%eax
  call   <WantNum@plt>
  cmp    $0x1,%eax
  je     L63
L54:
  cmp    $0x2,%eax
  je     L9
  test   %eax,%eax
  je     L37
  xor    %eax,%eax
  call   <ShowInputTypeError@plt>
  xor    %eax,%eax
  call   <WantEnter@plt>
  xor    %eax,%eax
  call   <ToLoggin2SScreen@plt>
  xor    %eax,%eax
  call   <WantNum@plt>
  cmp    $0x1,%eax
  jne    L54
L63:
  xor    %eax,%eax
  call   <SaleGoods@plt>
  cmp    $0xfffffffe,%eax
  je     L7
  cmp    $0xffffffff,%eax
  je     L13
L47:
  xor    %eax,%eax
L73:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L37:
  xor    %eax,%eax
  call   <ToMainScreen@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <StockGoods@plt>
  cmp    $0xffffffff,%eax
  jne    L47
L13:
  xor    %eax,%eax
  call   <ShowGoodNotFound@plt>
  xor    %eax,%eax
  call   <WantEnter@plt>
  xor    %eax,%eax
  jmp    L73
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <ShowGoodsCountLess@plt>
  xor    %eax,%eax
  call   <WantEnter@plt>
  xor    %eax,%eax
  jmp    L73
```

assistant: ```c
int Loggin2S() {
  ToLoggin2SScreen();
  int type = -1;
  while (type < 0 || type > 2) {
    type = WantNum();
    switch (type) {
    case 1:
      switch (SaleGoods()) {
      case -1: {
        ShowGoodNotFound();
        WantEnter();
        break;
      }
      case -2: {
        ShowGoodsCountLess();
        WantEnter();
        break;
      }
      }
      break;
    case 2:
      if (StockGoods() == -1) {
        ShowGoodNotFound();
        WantEnter();
      };
      break;
    case 0:
      ToMainScreen();
      return 1;
    default: {
      ShowInputTypeError();
      WantEnter();
      ToLoggin2SScreen();
    }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GOP_MIU_BUS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <OALReadDeviceId@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x47,-0x4(%rbp)
  jne    L32
  movw   $0x5,-0x14(%rbp)
  jmp    L26
L32:
  cmpl   $0x50,-0x4(%rbp)
  jne    L30
  movw   $0x4,-0x14(%rbp)
  jmp    L26
L30:
  movw   $0x4,-0x14(%rbp)
L26:
  movzwl -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned short GOP_MIU_BUS(unsigned short MIU_BUS) {
  unsigned int devId = 0;
  devId = OALReadDeviceId(devId);
  if ((0x47) == devId) {
    ;
    MIU_BUS = 5;
  } else if ((0x50) == devId) {
    ;
    MIU_BUS = 0x4;
  } else {
    ;
    MIU_BUS = 0x4;
  };
  return MIU_BUS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GOP_MIU_BUS>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <OALReadDeviceId@plt>
  cmp    $0x47,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x4,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned short GOP_MIU_BUS(unsigned short MIU_BUS) {
  unsigned int devId = 0;
  devId = OALReadDeviceId(devId);
  if ((0x47) == devId) {
    ;
    MIU_BUS = 5;
  } else if ((0x50) == devId) {
    ;
    MIU_BUS = 0x4;
  } else {
    ;
    MIU_BUS = 0x4;
  };
  return MIU_BUS;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GOP_MIU_BUS>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <OALReadDeviceId@plt>
  cmp    $0x47,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  add    $0x4,%eax
  ret
```

assistant: ```c
unsigned short GOP_MIU_BUS(unsigned short MIU_BUS) {
  unsigned int devId = 0;
  devId = OALReadDeviceId(devId);
  if ((0x47) == devId) {
    ;
    MIU_BUS = 5;
  } else if ((0x50) == devId) {
    ;
    MIU_BUS = 0x4;
  } else {
    ;
    MIU_BUS = 0x4;
  };
  return MIU_BUS;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GOP_MIU_BUS>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <OALReadDeviceId@plt>
  cmp    $0x47,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  add    $0x4,%eax
  ret
```

assistant: ```c
unsigned short GOP_MIU_BUS(unsigned short MIU_BUS) {
  unsigned int devId = 0;
  devId = OALReadDeviceId(devId);
  if ((0x47) == devId) {
    ;
    MIU_BUS = 5;
  } else if ((0x50) == devId) {
    ;
    MIU_BUS = 0x4;
  } else {
    ;
    MIU_BUS = 0x4;
  };
  return MIU_BUS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<warning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <warn_routine@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void warning(const char *fmt, ...) {
  va_list params;
  va_start(params, fmt);
  warn_routine(fmt, params);
  va_end(params);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<warning>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <warn_routine@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void warning(const char *fmt, ...) {
  va_list params;
  va_start(params, fmt);
  warn_routine(fmt, params);
  va_end(params);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<warning>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <warn_routine@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void warning(const char *fmt, ...) {
  va_list params;
  va_start(params, fmt);
  warn_routine(fmt, params);
  va_end(params);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<warning>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <warn_routine@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void warning(const char *fmt, ...) {
  va_list params;
  va_start(params, fmt);
  warn_routine(fmt, params);
  va_end(params);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strdup@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x50(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <clean_string_get_word_count@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L38
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L14
L38:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  jmp    L19
L28:
  addq   $0x1,-0x30(%rbp)
L49:
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x38(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <ft_strdup@plt>
  mov    %rax,(%rbx)
  addq   $0x1,-0x38(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  add    %rax,-0x30(%rbp)
L19:
  mov    -0x38(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L49
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **ft_split(const char *str, const char *to_avoid) {
  size_t i;
  size_t j;
  size_t word_count;
  char *tmp;
  char **ret;
  i = 0;
  j = 0;
  tmp = ft_strdup(str);
  word_count = clean_string_get_word_count(tmp, to_avoid);
  if (!(ret = NULL) && !(ret = malloc(sizeof(char *) * (word_count + 1))))
    return (NULL);
  ret[word_count] = NULL;
  while (i < word_count) {
    while (tmp[j] == '\0')
      ++j;
    ret[i] = ft_strdup(tmp + j);
    ++i;
    j += ft_strlen(tmp + j);
  }
  free(tmp);
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  call   <ft_strdup@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <clean_string_get_word_count@plt>
  mov    %rax,%r15
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L51
  movq   $0x0,(%rax,%r15,8)
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  test   %r15,%r15
  jne    L3
L52:
  mov    %rbp,%rdi
  call   <free@plt>
L51:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  add    $0x1,%rbx
  lea    0x0(%rbp,%rbx,1),%r12
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  je     L41
L6:
  mov    %r12,%rdi
  call   <ft_strdup@plt>
  mov    %rax,(%r14,%r13,8)
  add    $0x1,%r13
  mov    %r12,%rdi
  call   <ft_strlen@plt>
  add    %rax,%rbx
  cmp    %r13,%r15
  je     L52
L3:
  lea    0x0(%rbp,%rbx,1),%r12
  cmpb   $0x0,(%r12)
  je     L41
  jmp    L6
```

assistant: ```c
char **ft_split(const char *str, const char *to_avoid) {
  size_t i;
  size_t j;
  size_t word_count;
  char *tmp;
  char **ret;
  i = 0;
  j = 0;
  tmp = ft_strdup(str);
  word_count = clean_string_get_word_count(tmp, to_avoid);
  if (!(ret = NULL) && !(ret = malloc(sizeof(char *) * (word_count + 1))))
    return (NULL);
  ret[word_count] = NULL;
  while (i < word_count) {
    while (tmp[j] == '\0')
      ++j;
    ret[i] = ft_strdup(tmp + j);
    ++i;
    j += ft_strlen(tmp + j);
  }
  free(tmp);
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_strdup@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <clean_string_get_word_count@plt>
  lea    0x8(,%rax,8),%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L19
  movq   $0x0,(%rax,%r15,8)
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  test   %r15,%r15
  je     L39
  nopl   0x0(%rax)
L32:
  lea    0x0(%rbp,%rbx,1),%r12
  cmpb   $0x0,(%r12)
  jne    L11
  nopl   0x0(%rax)
L17:
  add    $0x1,%rbx
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  lea    0x0(%rbp,%rbx,1),%r12
  je     L17
L11:
  mov    %r12,%rdi
  call   <ft_strdup@plt>
  mov    %r12,%rdi
  mov    %rax,(%r14,%r13,8)
  add    $0x1,%r13
  call   <ft_strlen@plt>
  add    %rax,%rbx
  cmp    %r13,%r15
  jne    L32
L39:
  mov    %rbp,%rdi
  call   <free@plt>
L19:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **ft_split(const char *str, const char *to_avoid) {
  size_t i;
  size_t j;
  size_t word_count;
  char *tmp;
  char **ret;
  i = 0;
  j = 0;
  tmp = ft_strdup(str);
  word_count = clean_string_get_word_count(tmp, to_avoid);
  if (!(ret = NULL) && !(ret = malloc(sizeof(char *) * (word_count + 1))))
    return (NULL);
  ret[word_count] = NULL;
  while (i < word_count) {
    while (tmp[j] == '\0')
      ++j;
    ret[i] = ft_strdup(tmp + j);
    ++i;
    j += ft_strlen(tmp + j);
  }
  free(tmp);
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_strdup@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <clean_string_get_word_count@plt>
  lea    0x8(,%rax,8),%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L30
  movq   $0x0,(%rax,%r15,8)
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  test   %r15,%r15
  je     L14
  nopl   0x0(%rax)
L38:
  lea    0x0(%rbp,%rbx,1),%r12
  cmpb   $0x0,(%r12)
  jne    L21
  nopl   0x0(%rax)
L23:
  add    $0x1,%rbx
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  lea    0x0(%rbp,%rbx,1),%r12
  je     L23
L21:
  mov    %r12,%rdi
  call   <ft_strdup@plt>
  mov    %r12,%rdi
  mov    %rax,(%r14,%r13,8)
  add    $0x1,%r13
  call   <ft_strlen@plt>
  add    %rax,%rbx
  cmp    %r13,%r15
  jne    L38
L14:
  mov    %rbp,%rdi
  call   <free@plt>
L30:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **ft_split(const char *str, const char *to_avoid) {
  size_t i;
  size_t j;
  size_t word_count;
  char *tmp;
  char **ret;
  i = 0;
  j = 0;
  tmp = ft_strdup(str);
  word_count = clean_string_get_word_count(tmp, to_avoid);
  if (!(ret = NULL) && !(ret = malloc(sizeof(char *) * (word_count + 1))))
    return (NULL);
  ret[word_count] = NULL;
  while (i < word_count) {
    while (tmp[j] == '\0')
      ++j;
    ret[i] = ft_strdup(tmp + j);
    ++i;
    j += ft_strlen(tmp + j);
  }
  free(tmp);
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<qstrncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L24
  cmpq   $0x0,-0x10(%rbp)
  je     L24
  cmpq   $0x0,-0x18(%rbp)
  jne    L48
L24:
  mov    -0x8(%rbp),%rax
  jmp    L14
L48:
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L11
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
char *qstrncpy(char *dst, size_t size, const char *src, size_t nbytes) {
  if (dst == NULL || size == 0 || src == NULL)
    return dst;
  if (nbytes >= size)
    nbytes = size - 1;
  memmove((void *)dst, (void *)src, nbytes);
  dst[nbytes] = '\0';
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<qstrncpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %rcx,%rbp
  test   %rax,%rax
  sete   %dl
  test   %rsi,%rsi
  sete   %cl
  or     %cl,%dl
  jne    L15
  test   %rdi,%rdi
  je     L15
  lea    -0x1(%rax),%rdx
  cmp    %rbp,%rax
  cmovbe %rdx,%rbp
  mov    %rbp,%rdx
  call   <memmove@plt>
  movb   $0x0,(%rbx,%rbp,1)
L15:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *qstrncpy(char *dst, size_t size, const char *src, size_t nbytes) {
  if (dst == NULL || size == 0 || src == NULL)
    return dst;
  if (nbytes >= size)
    nbytes = size - 1;
  memmove((void *)dst, (void *)src, nbytes);
  dst[nbytes] = '\0';
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<qstrncpy>:
  endbr64
  push   %r12
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %rdi,%r12
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  test   %rax,%rax
  sete   %dl
  test   %rsi,%rsi
  sete   %cl
  or     %cl,%dl
  jne    L15
  test   %rdi,%rdi
  je     L15
  lea    -0x1(%rax),%rdx
  cmp    %rbx,%rax
  cmovbe %rdx,%rbx
  mov    %rbx,%rdx
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbx,1)
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *qstrncpy(char *dst, size_t size, const char *src, size_t nbytes) {
  if (dst == NULL || size == 0 || src == NULL)
    return dst;
  if (nbytes >= size)
    nbytes = size - 1;
  memmove((void *)dst, (void *)src, nbytes);
  dst[nbytes] = '\0';
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<qstrncpy>:
  endbr64
  push   %r12
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %rdi,%r12
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  test   %rax,%rax
  sete   %dl
  test   %rsi,%rsi
  sete   %cl
  or     %cl,%dl
  jne    L9
  test   %rdi,%rdi
  je     L9
  lea    -0x1(%rax),%rdx
  cmp    %rbx,%rax
  cmovbe %rdx,%rbx
  mov    %rbx,%rdx
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbx,1)
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *qstrncpy(char *dst, size_t size, const char *src, size_t nbytes) {
  if (dst == NULL || size == 0 || src == NULL)
    return dst;
  if (nbytes >= size)
    nbytes = size - 1;
  memmove((void *)dst, (void *)src, nbytes);
  dst[nbytes] = '\0';
  return dst;
}
```