ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<process_command_line_arguments>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   $0x0,(%rsi)
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L3
  mov    D3(%rip),%r13
  lea    0x8(%rdi),%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L14:
  mov    (%rbx),%rdx
  mov    %rbp,%rdi
  call   <set_option@plt>
  cmp    0x0(%r13),%rax
  sete   %al
  mov    0x8(%rbx),%rsi
  add    $0x10,%rbx
  movzbl %al,%eax
  add    %eax,%r12d
  test   %rsi,%rsi
  jne    L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int process_command_line_arguments(char *argv[], char **options) {
  char line[(8 * 1024)], opt[sizeof(line)], val[sizeof(line)], *p;
  FILE *fp = NULL;
  size_t i, cmd_line_opts_start = 0, line_no = 0;
  int errs = 0;
  options[0] = NULL;
  for (i = cmd_line_opts_start; argv[i] != NULL; i += 2) {
    if (set_option(options, &argv[i][0], &argv[i + 1][0]) == EXIT_FAILURE) {
      errs++;
    }
  }
  return errs;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<process_command_line_arguments>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   $0x0,(%rsi)
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L7
  mov    D9(%rip),%r13
  lea    0x8(%rdi),%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L10:
  mov    (%rbx),%rdx
  mov    %rbp,%rdi
  call   <set_option@plt>
  cmp    0x0(%r13),%rax
  sete   %al
  mov    0x8(%rbx),%rsi
  add    $0x10,%rbx
  movzbl %al,%eax
  add    %eax,%r12d
  test   %rsi,%rsi
  jne    L10
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int process_command_line_arguments(char *argv[], char **options) {
  char line[(8 * 1024)], opt[sizeof(line)], val[sizeof(line)], *p;
  FILE *fp = NULL;
  size_t i, cmd_line_opts_start = 0, line_no = 0;
  int errs = 0;
  options[0] = NULL;
  for (i = cmd_line_opts_start; argv[i] != NULL; i += 2) {
    if (set_option(options, &argv[i][0], &argv[i + 1][0]) == EXIT_FAILURE) {
      errs++;
    }
  }
  return errs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dictionary_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xa,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x6,%eax
  xor    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0xb,%eax
  xor    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xf,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned dictionary_hash(char *key) {
  int len;
  unsigned hash;
  int i;
  len = strlen(key);
  for (hash = 0, i = 0; i < len; i++) {
    hash += (unsigned)key[i];
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dictionary_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L27
  mov    %rbx,%rcx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%eax
L29:
  movsbl (%rcx),%edx
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L29
L23:
  lea    (%rax,%rax,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  pop    %rbx
  ret
L27:
  mov    $0x0,%eax
  jmp    L23
```

assistant: ```c
unsigned dictionary_hash(char *key) {
  int len;
  unsigned hash;
  int i;
  len = strlen(key);
  for (hash = 0, i = 0; i < len; i++) {
    hash += (unsigned)key[i];
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<dictionary_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L6
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L9:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L9
  lea    (%rax,%rax,8),%eax
  pop    %rbx
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
  nop
L6:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned dictionary_hash(char *key) {
  int len;
  unsigned hash;
  int i;
  len = strlen(key);
  for (hash = 0, i = 0; i < len; i++) {
    hash += (unsigned)key[i];
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<dictionary_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L11
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L8:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L8
  lea    (%rax,%rax,8),%eax
  pop    %rbx
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
  nop
L11:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned dictionary_hash(char *key) {
  int len;
  unsigned hash;
  int i;
  len = strlen(key);
  for (hash = 0, i = 0; i < len; i++) {
    hash += (unsigned)key[i];
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<udivhi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L26:
  mov    -0x14(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  shll   -0x14(%rbp)
  shll   -0x8(%rbp)
  mov    -0x4(%rbp),%eax
  or     -0x14(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jg     L15
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L15:
  addl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x1f,-0xc(%rbp)
  jle    L26
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint udivhi(uint num, uint den) {
  uint i, carry, quo = 0;
  for (i = 0; i < 32; i++) {
    carry = (int)num >> 31;
    num <<= 1;
    quo <<= 1;
    if ((carry | num) >= den) {
      num -= den;
      quo += 1;
    }
  }
  return quo;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<udivhi>:
  endbr64
  mov    $0x20,%ecx
  mov    $0x0,%edx
  jmp    L8
L2:
  sub    $0x1,%ecx
  je     L36
L8:
  mov    %edi,%eax
  sar    $0x1f,%eax
  add    %edi,%edi
  add    %edx,%edx
  or     %edi,%eax
  cmp    %esi,%eax
  jl     L2
  sub    %esi,%edi
  add    $0x1,%edx
  jmp    L2
L36:
  mov    %edx,%eax
  ret
```

assistant: ```c
uint udivhi(uint num, uint den) {
  uint i, carry, quo = 0;
  for (i = 0; i < 32; i++) {
    carry = (int)num >> 31;
    num <<= 1;
    quo <<= 1;
    if ((carry | num) >= den) {
      num -= den;
      quo += 1;
    }
  }
  return quo;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<udivhi>:
  endbr64
  mov    $0x20,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L14:
  mov    %edi,%eax
  add    %edi,%edi
  add    %r8d,%r8d
  sar    $0x1f,%eax
  or     %edi,%eax
  cmp    %esi,%eax
  jl     L2
  sub    %esi,%edi
  add    $0x1,%r8d
L2:
  sub    $0x1,%edx
  jne    L14
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint udivhi(uint num, uint den) {
  uint i, carry, quo = 0;
  for (i = 0; i < 32; i++) {
    carry = (int)num >> 31;
    num <<= 1;
    quo <<= 1;
    if ((carry | num) >= den) {
      num -= den;
      quo += 1;
    }
  }
  return quo;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<udivhi>:
  endbr64
  mov    $0x20,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L6:
  mov    %edi,%eax
  add    %edi,%edi
  add    %r8d,%r8d
  sar    $0x1f,%eax
  or     %edi,%eax
  cmp    %esi,%eax
  jl     L0
  sub    %esi,%edi
  add    $0x1,%r8d
L0:
  sub    $0x1,%edx
  jne    L6
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint udivhi(uint num, uint den) {
  uint i, carry, quo = 0;
  for (i = 0; i < 32; i++) {
    carry = (int)num >> 31;
    num <<= 1;
    quo <<= 1;
    if ((carry | num) >= den) {
      num -= den;
      quo += 1;
    }
  }
  return quo;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CmdIgnoreEnviron>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x4000,%eax
  test   %eax,%eax
  je     L14
  mov    -0x14(%rbp),%eax
  and    $0xbf,%ah
  cmp    $0x4,%eax
  je     L30
  cmp    $0x4,%eax
  jg     L19
  cmp    $0x1,%eax
  je     L53
  cmp    $0x3,%eax
  jne    L19
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <my_strdup@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L19
L53:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <my_strdup@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L19
L30:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <my_strdup@plt>
  mov    %rax,-0x10(%rbp)
  nop
L19:
  cmpq   $0x0,-0x10(%rbp)
  je     L14
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <getTexUntil@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ConvertString@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L60
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L60:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L14:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D19
type_infered: string

tool: D13: \end{minipage}

tool: D14: \end{htmlonly}

tool: D19: \end{rawhtml}

assistant: ```c
void CmdIgnoreEnviron(int code) {
  char *endtag = NULL;
  char *s = NULL;
  if (code & 0x4000) {
    switch (code & ~(0x4000)) {
    case 3:
      endtag = my_strdup("\\end{minipage}");
      break;
    case 1:
      endtag = my_strdup("\\end{htmlonly}");
      break;
    case 4:
      endtag = my_strdup("\\end{rawhtml}");
      break;
    }
    if (endtag) {
      s = getTexUntil(endtag, 0);
      ConvertString(endtag);
      if (s)
        free(s);
      free(endtag);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CmdIgnoreEnviron>:
  endbr64
  test   $0x4000,%edi
  je     L77
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  and    $0xffffbfff,%edi
  cmp    $0x3,%edi
  je     L19
  cmp    $0x4,%edi
  je     L71
  cmp    $0x1,%edi
  je     L11
L59:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  lea    D21(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbx
L55:
  test   %rbx,%rbx
  je     L59
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <getTexUntil@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <ConvertString@plt>
  test   %rbp,%rbp
  je     L61
  mov    %rbp,%rdi
  call   <free@plt>
L61:
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L59
L11:
  lea    D28(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbx
  jmp    L55
L71:
  lea    D0(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbx
  jmp    L55
L77:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D28
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D21: \end{minipage}

tool: D28: \end{htmlonly}

tool: D0: \end{rawhtml}

assistant: ```c
void CmdIgnoreEnviron(int code) {
  char *endtag = NULL;
  char *s = NULL;
  if (code & 0x4000) {
    switch (code & ~(0x4000)) {
    case 3:
      endtag = my_strdup("\\end{minipage}");
      break;
    case 1:
      endtag = my_strdup("\\end{htmlonly}");
      break;
    case 4:
      endtag = my_strdup("\\end{rawhtml}");
      break;
    }
    if (endtag) {
      s = getTexUntil(endtag, 0);
      ConvertString(endtag);
      if (s)
        free(s);
      free(endtag);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<CmdIgnoreEnviron>:
  endbr64
  test   $0x4000,%edi
  jne    L70
  ret
  nopl   (%rax)
L70:
  push   %r12
  and    $0xffffbfff,%edi
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L51
  cmp    $0x4,%edi
  je     L63
  cmp    $0x1,%edi
  je     L69
L59:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L63:
  lea    D21(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbp
L42:
  test   %rbp,%rbp
  je     L59
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <getTexUntil@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <ConvertString@plt>
  test   %r12,%r12
  je     L9
  mov    %r12,%rdi
  call   <free@plt>
L9:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
  nopl   (%rax)
L69:
  lea    D10(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbp
  jmp    L42
  nopl   0x0(%rax)
L51:
  lea    D26(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbp
  jmp    L42
```

tool_calls: name: read_data
arguments: tag: D21
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string

tool: D21: \end{rawhtml}

tool: D10: \end{htmlonly}

tool: D26: \end{minipage}

assistant: ```c
void CmdIgnoreEnviron(int code) {
  char *endtag = NULL;
  char *s = NULL;
  if (code & 0x4000) {
    switch (code & ~(0x4000)) {
    case 3:
      endtag = my_strdup("\\end{minipage}");
      break;
    case 1:
      endtag = my_strdup("\\end{htmlonly}");
      break;
    case 4:
      endtag = my_strdup("\\end{rawhtml}");
      break;
    }
    if (endtag) {
      s = getTexUntil(endtag, 0);
      ConvertString(endtag);
      if (s)
        free(s);
      free(endtag);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CmdIgnoreEnviron>:
  endbr64
  test   $0x4000,%edi
  jne    L69
  ret
  nopl   (%rax)
L69:
  push   %r12
  and    $0xffffbfff,%edi
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L71
  cmp    $0x4,%edi
  je     L14
  cmp    $0x1,%edi
  je     L67
L10:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  lea    D7(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbp
L31:
  test   %rbp,%rbp
  je     L10
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <getTexUntil@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <ConvertString@plt>
  test   %r12,%r12
  je     L57
  mov    %r12,%rdi
  call   <free@plt>
L57:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
  nopl   (%rax)
L67:
  lea    D16(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbp
  jmp    L31
  nopl   0x0(%rax)
L71:
  lea    D9(%rip),%rdi
  call   <my_strdup@plt>
  mov    %rax,%rbp
  jmp    L31
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string

tool: D7: \end{rawhtml}

tool: D16: \end{htmlonly}

tool: D9: \end{minipage}

assistant: ```c
void CmdIgnoreEnviron(int code) {
  char *endtag = NULL;
  char *s = NULL;
  if (code & 0x4000) {
    switch (code & ~(0x4000)) {
    case 3:
      endtag = my_strdup("\\end{minipage}");
      break;
    case 1:
      endtag = my_strdup("\\end{htmlonly}");
      break;
    case 4:
      endtag = my_strdup("\\end{rawhtml}");
      break;
    }
    if (endtag) {
      s = getTexUntil(endtag, 0);
      ConvertString(endtag);
      if (s)
        free(s);
      free(endtag);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movl   $0x0,-0x80(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
L20:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xe0(%rbp),%rax
  lea    D47(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  jmp    L2
L13:
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inverte@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L5:
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L2:
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D15
datatype: string
name: extract_symbolic_data
arguments: tag: D47
datatype: string
name: extract_symbolic_data
arguments: tag: D36
datatype: string
name: extract_symbolic_data
arguments: tag: D18
datatype: string

tool: D1: Palavra? 

tool: D15: %s

tool: D47: .

tool: D36: Resultado : %s e capicua


tool: D18: Resultado : %s nao e capicua


assistant: ```c
int main() {
  char strOriginal[100] = {}, strInvertida[100] = {};
  while (1) {
    printf("Palavra? ");
    scanf("%s", strOriginal);
    if (strcmp(strOriginal, ".") == 0)
      return 0;
    inverte(strOriginal, strInvertida);
    if (strcmp(strOriginal, strInvertida) == 0) {
      printf("Resultado : %s e capicua\n", strOriginal);
    } else {
      printf("Resultado : %s nao e capicua\n", strOriginal);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movl   $0x0,0xd0(%rsp)
  lea    D19(%rip),%r13
  lea    D31(%rip),%r12
  lea    D0(%rip),%rbp
  lea    D28(%rip),%r14
  jmp    L29
L11:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    %rsp,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L29:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
  lea    0x70(%rsp),%r15
  mov    %rsp,%rbx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <inverte@plt>
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D31
type: string
name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D28
type: string
name: extract_symbolic_data
arguments: label: D16
type: string

tool: D19: Palavra? 

tool: D31: %s

tool: D0: .

tool: D28: Resultado : %s nao e capicua


tool: D16: Resultado : %s e capicua


assistant: ```c
int main() {
  char strOriginal[100] = {}, strInvertida[100] = {};
  while (1) {
    printf("Palavra? ");
    scanf("%s", strOriginal);
    if (strcmp(strOriginal, ".") == 0)
      return 0;
    inverte(strOriginal, strInvertida);
    if (strcmp(strOriginal, strInvertida) == 0) {
      printf("Resultado : %s e capicua\n", strOriginal);
    } else {
      printf("Resultado : %s nao e capicua\n", strOriginal);
    }
  }
}
```