ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cfg_parse_options>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x1,%r13d
  lea    D6(%rip),%r14
L67:
  movslq %r13d,%rbx
L24:
  mov    %ebx,%r13d
  lea    0x1(%rbx),%eax
  cmp    %eax,(%r12)
  jle    L59
  lea    0x40(%rsp),%rcx
  mov    %rsp,%rdx
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r14,%rsi
  call   <sscanf@plt>
  lea    0x1(%rbx),%rdx
  cmp    $0x2,%eax
  je     L17
  mov    %rdx,%rbx
  jmp    L24
L17:
  mov    0x8(%rbp,%rbx,8),%rdx
  lea    0x40(%rsp),%rsi
  mov    %rsp,%rdi
  call   <cfg_parse_option@plt>
  mov    (%r12),%edx
  lea    -0x1(%rdx),%eax
  cmp    %eax,%r13d
  jge    L58
  movslq %r13d,%rax
L23:
  mov    0x10(%rbp,%rax,8),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
  mov    (%r12),%edx
  add    $0x1,%rax
  lea    -0x1(%rdx),%ecx
  cmp    %eax,%ecx
  jg     L23
L58:
  sub    $0x2,%edx
  mov    %edx,(%r12)
  jmp    L67
L59:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string

tool: D6: -%63[^:]:%63s

assistant: ```c
void cfg_parse_options(int *argc, char **argv) {
  char section[64], tag[64];
  int i, j;
  for (i = 1; i + 1 < *argc;) {
    if (2 == sscanf(argv[i], "-%63[^:]:%63s", section, tag)) {
      cfg_parse_option(section, tag, argv[i + 1]);
      for (j = i; j < *argc - 1; j++)
        argv[j] = argv[j + 2];
      (*argc) -= 2;
    } else {
      i++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cfg_parse_options>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0xa8,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  mov    (%rdi),%eax
  jmp    L56
  xchg   %ax,%ax
L29:
  mov    (%r15,%rbx,8),%rdi
  lea    0x50(%rsp),%rbp
  lea    0x10(%rsp),%r14
  mov    %r13,%rsi
  mov    %rbp,%rcx
  mov    %r14,%rdx
  add    $0x1,%rbx
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L28
  mov    0x8(%rsp),%rax
  mov    (%rax),%eax
L56:
  lea    0x1(%rbx),%edx
  mov    %ebx,%r12d
  cmp    %eax,%edx
  jl     L29
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    (%r15,%rbx,8),%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <cfg_parse_option@plt>
  mov    0x8(%rsp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  cmp    %edx,%r12d
  jge    L27
  lea    -0x2(%rax),%r14d
  movslq %r12d,%rbx
  mov    %r14d,%eax
  lea    0x0(,%rbx,8),%rdi
  sub    %r12d,%eax
  lea    0x10(%r15,%rdi,1),%rsi
  add    %r15,%rdi
  lea    0x8(,%rax,8),%rdx
  call   <memmove@plt>
L49:
  mov    0x8(%rsp),%rcx
  mov    %r14d,%eax
  mov    %r14d,(%rcx)
  jmp    L56
L27:
  lea    -0x2(%rax),%r14d
  movslq %r12d,%rbx
  jmp    L49
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: -%63[^:]:%63s

assistant: ```c
void cfg_parse_options(int *argc, char **argv) {
  char section[64], tag[64];
  int i, j;
  for (i = 1; i + 1 < *argc;) {
    if (2 == sscanf(argv[i], "-%63[^:]:%63s", section, tag)) {
      cfg_parse_option(section, tag, argv[i + 1]);
      for (j = i; j < *argc - 1; j++)
        argv[j] = argv[j + 2];
      (*argc) -= 2;
    } else {
      i++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cfg_parse_options>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0xa8,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  mov    (%rdi),%eax
  jmp    L62
  xchg   %ax,%ax
L22:
  mov    (%r15,%rbx,8),%rdi
  lea    0x50(%rsp),%rbp
  lea    0x10(%rsp),%r14
  mov    %r13,%rsi
  mov    %rbp,%rcx
  mov    %r14,%rdx
  add    $0x1,%rbx
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L40
  mov    0x8(%rsp),%rax
  mov    (%rax),%eax
L62:
  lea    0x1(%rbx),%edx
  mov    %ebx,%r12d
  cmp    %eax,%edx
  jl     L22
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    (%r15,%rbx,8),%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <cfg_parse_option@plt>
  mov    0x8(%rsp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  cmp    %edx,%r12d
  jge    L38
  lea    -0x2(%rax),%r14d
  movslq %r12d,%rbx
  mov    %r14d,%eax
  lea    0x0(,%rbx,8),%rdi
  sub    %r12d,%eax
  lea    0x10(%r15,%rdi,1),%rsi
  add    %r15,%rdi
  lea    0x8(,%rax,8),%rdx
  call   <memmove@plt>
L24:
  mov    0x8(%rsp),%rcx
  mov    %r14d,%eax
  mov    %r14d,(%rcx)
  jmp    L62
L38:
  lea    -0x2(%rax),%r14d
  movslq %r12d,%rbx
  jmp    L24
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: -%63[^:]:%63s

assistant: ```c
void cfg_parse_options(int *argc, char **argv) {
  char section[64], tag[64];
  int i, j;
  for (i = 1; i + 1 < *argc;) {
    if (2 == sscanf(argv[i], "-%63[^:]:%63s", section, tag)) {
      cfg_parse_option(section, tag, argv[i + 1]);
      for (j = i; j < *argc - 1; j++)
        argv[j] = argv[j + 2];
      (*argc) -= 2;
    } else {
      i++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<diff_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  test   %eax,%eax
  jns    L0
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x3b9aca00,%eax
  mov    %eax,-0x4(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int diff_ms(const struct timespec *t1, const struct timespec *t2) {
  struct timespec diff;
  diff.tv_sec = t1->tv_sec - t2->tv_sec;
  diff.tv_nsec = t1->tv_nsec - t2->tv_nsec;
  if (diff.tv_nsec < 0) {
    diff.tv_sec--;
    diff.tv_nsec += 1000000000;
  }
  return (diff.tv_sec * 1000 + diff.tv_nsec / 1000000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<diff_ms>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  mov    0x4(%rdi),%edx
  sub    0x4(%rsi),%edx
  js     L17
L1:
  imul   $0x3e8,%eax,%eax
  movslq %edx,%rcx
  imul   $0x431bde83,%rcx,%rcx
  sar    $0x32,%rcx
  sar    $0x1f,%edx
  sub    %edx,%ecx
  add    %ecx,%eax
  ret
L17:
  sub    $0x1,%eax
  add    $0x3b9aca00,%edx
  jmp    L1
```

assistant: ```c
int diff_ms(const struct timespec *t1, const struct timespec *t2) {
  struct timespec diff;
  diff.tv_sec = t1->tv_sec - t2->tv_sec;
  diff.tv_nsec = t1->tv_nsec - t2->tv_nsec;
  if (diff.tv_nsec < 0) {
    diff.tv_sec--;
    diff.tv_nsec += 1000000000;
  }
  return (diff.tv_sec * 1000 + diff.tv_nsec / 1000000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<diff_ms>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  sub    (%rsi),%eax
  sub    0x4(%rsi),%edx
  jns    L3
  sub    $0x1,%eax
  add    $0x3b9aca00,%edx
L3:
  movslq %edx,%rcx
  imul   $0x3e8,%eax,%eax
  sar    $0x1f,%edx
  imul   $0x431bde83,%rcx,%rcx
  sar    $0x32,%rcx
  sub    %edx,%ecx
  add    %ecx,%eax
  ret
```

assistant: ```c
int diff_ms(const struct timespec *t1, const struct timespec *t2) {
  struct timespec diff;
  diff.tv_sec = t1->tv_sec - t2->tv_sec;
  diff.tv_nsec = t1->tv_nsec - t2->tv_nsec;
  if (diff.tv_nsec < 0) {
    diff.tv_sec--;
    diff.tv_nsec += 1000000000;
  }
  return (diff.tv_sec * 1000 + diff.tv_nsec / 1000000);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<diff_ms>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  sub    (%rsi),%eax
  sub    0x4(%rsi),%edx
  jns    L1
  sub    $0x1,%eax
  add    $0x3b9aca00,%edx
L1:
  movslq %edx,%rcx
  imul   $0x3e8,%eax,%eax
  sar    $0x1f,%edx
  imul   $0x431bde83,%rcx,%rcx
  sar    $0x32,%rcx
  sub    %edx,%ecx
  add    %ecx,%eax
  ret
```

assistant: ```c
int diff_ms(const struct timespec *t1, const struct timespec *t2) {
  struct timespec diff;
  diff.tv_sec = t1->tv_sec - t2->tv_sec;
  diff.tv_nsec = t1->tv_nsec - t2->tv_nsec;
  if (diff.tv_nsec < 0) {
    diff.tv_sec--;
    diff.tv_nsec += 1000000000;
  }
  return (diff.tv_sec * 1000 + diff.tv_nsec / 1000000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strmapi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x1c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L11
  cmpq   $0x0,-0x30(%rbp)
  jne    L25
L11:
  mov    $0x0,%eax
  jmp    L7
L25:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L57
  mov    $0x0,%eax
  jmp    L7
L8:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    -0x1c(%rbp),%eax
  mov    -0x30(%rbp),%rcx
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%rcx
  mov    %al,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L57:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  cmpq   $0x0,-0x28(%rbp)
  jne    L8
L42:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  unsigned int i;
  char *dest;
  i = 0;
  if (s == NULL || f == NULL)
    return (NULL);
  dest = (char *)malloc(sizeof(*s) * ft_strlen(s) + 1);
  if (dest == NULL)
    return (NULL);
  while (*s && s != NULL) {
    dest[i] = f(i, (char)*s++);
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strmapi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L53
  mov    %rdi,%rbp
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L53
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L52
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L5
  mov    $0x0,%ebx
L77:
  add    $0x1,%rbp
  mov    %ebx,%r12d
  add    %r13,%r12
  movsbl %sil,%esi
  mov    %ebx,%edi
  call   *%r14
  mov    %al,(%r12)
  add    $0x1,%ebx
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  jne    L77
L55:
  mov    %ebx,%ebx
  movb   $0x0,0x0(%r13,%rbx,1)
L24:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    $0x0,%ebx
  jmp    L55
L53:
  mov    $0x0,%r13d
  jmp    L24
L52:
  mov    $0x0,%r13d
  jmp    L24
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  unsigned int i;
  char *dest;
  i = 0;
  if (s == NULL || f == NULL)
    return (NULL);
  dest = (char *)malloc(sizeof(*s) * ft_strlen(s) + 1);
  if (dest == NULL)
    return (NULL);
  while (*s && s != NULL) {
    dest[i] = f(i, (char)*s++);
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strmapi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L4
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%r14
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  movsbl (%r14),%esi
  test   %sil,%sil
  je     L30
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  mov    %ebx,%ebp
  mov    %ebx,%edi
  add    $0x1,%r14
  add    $0x1,%ebx
  call   *%r13
  add    %r12,%rbp
  mov    %al,0x0(%rbp)
  movsbl (%r14),%esi
  test   %sil,%sil
  jne    L8
  add    %r12,%rbx
L51:
  movb   $0x0,(%rbx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L4:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L30:
  mov    %rax,%rbx
  jmp    L51
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  unsigned int i;
  char *dest;
  i = 0;
  if (s == NULL || f == NULL)
    return (NULL);
  dest = (char *)malloc(sizeof(*s) * ft_strlen(s) + 1);
  if (dest == NULL)
    return (NULL);
  while (*s && s != NULL) {
    dest[i] = f(i, (char)*s++);
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_strmapi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L47
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L47
  mov    %rdi,%r14
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L47
  movsbl (%r14),%esi
  test   %sil,%sil
  je     L11
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L37:
  mov    %ebx,%ebp
  mov    %ebx,%edi
  add    $0x1,%r14
  add    $0x1,%ebx
  call   *%r13
  add    %r12,%rbp
  mov    %al,0x0(%rbp)
  movsbl (%r14),%esi
  test   %sil,%sil
  jne    L37
  add    %r12,%rbx
L4:
  movb   $0x0,(%rbx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L47:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L11:
  mov    %rax,%rbx
  jmp    L4
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  unsigned int i;
  char *dest;
  i = 0;
  if (s == NULL || f == NULL)
    return (NULL);
  dest = (char *)malloc(sizeof(*s) * ft_strlen(s) + 1);
  if (dest == NULL)
    return (NULL);
  while (*s && s != NULL) {
    dest[i] = f(i, (char)*s++);
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bs_disconnect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int bs_disconnect(int fd) {
  close(fd);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<bs_disconnect>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bs_disconnect(int fd) {
  close(fd);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bs_disconnect>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bs_disconnect(int fd) {
  close(fd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bs_disconnect>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bs_disconnect(int fd) {
  close(fd);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fromMilli>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x636ba875fd33dc87,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x19,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x5265c00,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L5
  addq   $0x5265c00,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rcx
  movabs $0x4a90be587de6e565,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x14,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x4a90be587de6e565,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x14,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x36ee80,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x45e7b272f608770f,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xe,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x45e7b272f608770f,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xe,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xea60,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3e8,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  imul   $0x989680,%rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0x186a0,%rax,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long fromMilli(long ms) {
  int h, m, s, l;
  ms %= 86400000L;
  if (ms < 0)
    ms += 86400000L;
  h = (int)(ms / 3600000L);
  ms %= 3600000L;
  m = (int)(ms / 60000L);
  ms %= 60000L;
  s = (int)(ms / 1000L);
  l = (int)(ms % 1000L);
  return (((long)h * 10000000L) + ((long)m * 100000L) + ((long)s * 1000) + (long)l);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fromMilli>:
  endbr64
  movabs $0x636ba875fd33dc87,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x19,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rsi
  sub    %rax,%rsi
  imul   $0x5265c00,%rsi,%rax
  sub    %rax,%rdi
  mov    %rdi,%rsi
  lea    0x5265c00(%rdi),%rax
  cmovs  %rax,%rsi
  movabs $0x4a90be587de6e565,%rcx
  mov    %rsi,%rax
  imul   %rcx
  mov    %rdx,%rcx
  sar    $0x14,%rcx
  mov    %rsi,%r8
  sar    $0x3f,%r8
  mov    %rcx,%rdi
  sub    %r8,%rdi
  imul   $0x36ee80,%rdi,%rax
  mov    %rsi,%rdi
  sub    %rax,%rdi
  movabs $0x45e7b272f608770f,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0xe,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rsi
  sub    %rax,%rsi
  imul   $0xea60,%rsi,%r9
  sub    %r9,%rdi
  mov    %rdi,%rsi
  sub    %r8,%rcx
  movslq %ecx,%rcx
  imul   $0x989680,%rcx,%rcx
  sub    %rax,%rdx
  movslq %edx,%rdx
  imul   $0x186a0,%rdx,%rdx
  add    %rdx,%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x7,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  movslq %edx,%rax
  imul   $0x3e8,%rax,%rax
  add    %rax,%rcx
  imul   $0x3e8,%rdx,%rdx
  sub    %rdx,%rsi
  movslq %esi,%rsi
  lea    (%rcx,%rsi,1),%rax
  ret
```

assistant: ```c
long fromMilli(long ms) {
  int h, m, s, l;
  ms %= 86400000L;
  if (ms < 0)
    ms += 86400000L;
  h = (int)(ms / 3600000L);
  ms %= 3600000L;
  m = (int)(ms / 60000L);
  ms %= 60000L;
  s = (int)(ms / 1000L);
  l = (int)(ms % 1000L);
  return (((long)h * 10000000L) + ((long)m * 100000L) + ((long)s * 1000) + (long)l);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fromMilli>:
  endbr64
  movabs $0x636ba875fd33dc87,%rdx
  mov    %rdi,%rax
  movabs $0x4a90be587de6e565,%rsi
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x19,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  imul   $0x5265c00,%rcx,%rax
  sub    %rax,%rdi
  lea    0x5265c00(%rdi),%rax
  mov    %rdi,%rcx
  cmovs  %rax,%rcx
  mov    %rcx,%rax
  mul    %rsi
  mov    %rdx,%rdi
  mov    %rdx,%rsi
  shr    $0x14,%rdi
  shr    $0x14,%rsi
  imul   $0x36ee80,%rdi,%rax
  imul   $0x989680,%rsi,%rsi
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rcx,%rdi
  movabs $0x45e7b272f608771,%rcx
  shr    $0x5,%rdx
  mov    %rdx,%rax
  mul    %rcx
  mov    %rdx,%rax
  shr    $0x5,%rdx
  shr    $0x5,%rax
  imul   $0x186a0,%rdx,%rdx
  imul   $0xea60,%rax,%rcx
  mov    %rdi,%rax
  add    %rdx,%rsi
  sub    %rcx,%rax
  add    %rsi,%rax
  ret
```

assistant: ```c
long fromMilli(long ms) {
  int h, m, s, l;
  ms %= 86400000L;
  if (ms < 0)
    ms += 86400000L;
  h = (int)(ms / 3600000L);
  ms %= 3600000L;
  m = (int)(ms / 60000L);
  ms %= 60000L;
  s = (int)(ms / 1000L);
  l = (int)(ms % 1000L);
  return (((long)h * 10000000L) + ((long)m * 100000L) + ((long)s * 1000) + (long)l);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fromMilli>:
  endbr64
  movabs $0x636ba875fd33dc87,%rdx
  mov    %rdi,%rax
  movabs $0x4a90be587de6e565,%rsi
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x19,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  imul   $0x5265c00,%rcx,%rax
  sub    %rax,%rdi
  lea    0x5265c00(%rdi),%rax
  mov    %rdi,%rcx
  cmovs  %rax,%rcx
  mov    %rcx,%rax
  mul    %rsi
  mov    %rdx,%rdi
  mov    %rdx,%rsi
  shr    $0x14,%rdi
  shr    $0x14,%rsi
  imul   $0x36ee80,%rdi,%rax
  imul   $0x989680,%rsi,%rsi
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rcx,%rdi
  movabs $0x45e7b272f608771,%rcx
  shr    $0x5,%rdx
  mov    %rdx,%rax
  mul    %rcx
  mov    %rdx,%rax
  shr    $0x5,%rdx
  shr    $0x5,%rax
  imul   $0x186a0,%rdx,%rdx
  imul   $0xea60,%rax,%rcx
  mov    %rdi,%rax
  add    %rdx,%rsi
  sub    %rcx,%rax
  add    %rsi,%rax
  ret
```

assistant: ```c
long fromMilli(long ms) {
  int h, m, s, l;
  ms %= 86400000L;
  if (ms < 0)
    ms += 86400000L;
  h = (int)(ms / 3600000L);
  ms %= 3600000L;
  m = (int)(ms / 60000L);
  ms %= 60000L;
  s = (int)(ms / 1000L);
  l = (int)(ms % 1000L);
  return (((long)h * 10000000L) + ((long)m * 100000L) + ((long)s * 1000) + (long)l);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L0:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  cmpl   $0x9,-0x8(%rbp)
  jle    L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f(void) {
  int i, v = 0;
#pragma acc loop gang reduction(+ : v)
  for (i = 0; i < 10; i++)
    v++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int i, v = 0;
#pragma acc loop gang reduction(+ : v)
  for (i = 0; i < 10; i++)
    v++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int i, v = 0;
#pragma acc loop gang reduction(+ : v)
  for (i = 0; i < 10; i++)
    v++;
}
```