ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<ssim_end1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  sub    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    D7(%rip),%eax
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    D28(%rip),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  add    %eax,%edx
  mov    D7(%rip),%eax
  add    %edx,%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  mov    D28(%rip),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: byte[4]
name: read_data
arguments: data_tag: D28
type_infered: byte[4]

tool: {"D7": [0xa0,0x01,0x00,0x00]}

tool: {"D28": [0xbb,0x99,0x03,0x00]}

assistant: ```c
float ssim_end1(int s1, int s2, int ss, int s12) {
  static const int ssim_c1 = (int)(.01 * .01 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 + .5);
  static const int ssim_c2 = (int)(.03 * .03 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 * 63 + .5);
  int fs1 = s1;
  int fs2 = s2;
  int fss = ss;
  int fs12 = s12;
  int vars = fss * 64 - fs1 * fs1 - fs2 * fs2;
  int covar = fs12 * 64 - fs1 * fs2;
  return (float)(2 * fs1 * fs2 + ssim_c1) * (float)(2 * covar + ssim_c2) / ((float)(fs1 * fs1 + fs2 * fs2 + ssim_c1) * (float)(vars + ssim_c2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ssim_end1>:
  endbr64
  mov    %edi,%r8d
  imul   %edi,%r8d
  mov    %esi,%eax
  imul   %esi,%eax
  imul   %esi,%edi
  shl    $0x6,%ecx
  sub    %edi,%ecx
  lea    0x399bb(%rcx,%rcx,1),%ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ecx,%xmm0
  lea    0x1a0(%rdi,%rdi,1),%ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  mulss  %xmm1,%xmm0
  shl    $0x6,%edx
  sub    %r8d,%edx
  sub    %eax,%edx
  add    $0x399bb,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  lea    0x1a0(%r8,%rax,1),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float ssim_end1(int s1, int s2, int ss, int s12) {
  static const int ssim_c1 = (int)(.01 * .01 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 + .5);
  static const int ssim_c2 = (int)(.03 * .03 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 * 63 + .5);
  int fs1 = s1;
  int fs2 = s2;
  int fss = ss;
  int fs12 = s12;
  int vars = fss * 64 - fs1 * fs1 - fs2 * fs2;
  int covar = fs12 * 64 - fs1 * fs2;
  return (float)(2 * fs1 * fs2 + ssim_c1) * (float)(2 * covar + ssim_c2) / ((float)(fs1 * fs1 + fs2 * fs2 + ssim_c1) * (float)(vars + ssim_c2));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ssim_end1>:
  endbr64
  mov    %edi,%r8d
  shl    $0x6,%ecx
  pxor   %xmm0,%xmm0
  mov    %esi,%eax
  imul   %edi,%r8d
  pxor   %xmm1,%xmm1
  shl    $0x6,%edx
  pxor   %xmm2,%xmm2
  imul   %esi,%edi
  imul   %esi,%eax
  sub    %r8d,%edx
  sub    %edi,%ecx
  lea    0x399bb(%rcx,%rcx,1),%ecx
  sub    %eax,%edx
  lea    0x1a0(%r8,%rax,1),%eax
  cvtsi2ss %ecx,%xmm0
  lea    0x1a0(%rdi,%rdi,1),%ecx
  add    $0x399bb,%edx
  cvtsi2ss %ecx,%xmm1
  cvtsi2ss %eax,%xmm2
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float ssim_end1(int s1, int s2, int ss, int s12) {
  static const int ssim_c1 = (int)(.01 * .01 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 + .5);
  static const int ssim_c2 = (int)(.03 * .03 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 * 63 + .5);
  int fs1 = s1;
  int fs2 = s2;
  int fss = ss;
  int fs12 = s12;
  int vars = fss * 64 - fs1 * fs1 - fs2 * fs2;
  int covar = fs12 * 64 - fs1 * fs2;
  return (float)(2 * fs1 * fs2 + ssim_c1) * (float)(2 * covar + ssim_c2) / ((float)(fs1 * fs1 + fs2 * fs2 + ssim_c1) * (float)(vars + ssim_c2));
}
```
user: What is the c source code of the assembly code below?

```asm
<ssim_end1>:
  endbr64
  mov    %edi,%r8d
  shl    $0x6,%ecx
  pxor   %xmm0,%xmm0
  mov    %esi,%eax
  imul   %edi,%r8d
  pxor   %xmm1,%xmm1
  shl    $0x6,%edx
  pxor   %xmm2,%xmm2
  imul   %esi,%edi
  imul   %esi,%eax
  sub    %r8d,%edx
  sub    %edi,%ecx
  lea    0x399bb(%rcx,%rcx,1),%ecx
  sub    %eax,%edx
  lea    0x1a0(%r8,%rax,1),%eax
  cvtsi2ss %ecx,%xmm0
  lea    0x1a0(%rdi,%rdi,1),%ecx
  add    $0x399bb,%edx
  cvtsi2ss %ecx,%xmm1
  cvtsi2ss %eax,%xmm2
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float ssim_end1(int s1, int s2, int ss, int s12) {
  static const int ssim_c1 = (int)(.01 * .01 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 + .5);
  static const int ssim_c2 = (int)(.03 * .03 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 * 63 + .5);
  int fs1 = s1;
  int fs2 = s2;
  int fss = ss;
  int fs12 = s12;
  int vars = fss * 64 - fs1 * fs1 - fs2 * fs2;
  int covar = fs12 * 64 - fs1 * fs2;
  return (float)(2 * fs1 * fs2 + ssim_c1) * (float)(2 * covar + ssim_c2) / ((float)(fs1 * fs1 + fs2 * fs2 + ssim_c1) * (float)(vars + ssim_c2));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<triad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void triad(int *a, int *b, int *c, int s, int numits) {
  int i;
triad:
  for (i = 0; i < numits; i++)
    c[i] = a[i] + s * b[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<triad>:
  endbr64
  mov    %rdi,%r9
  test   %r8d,%r8d
  jle    L3
  mov    %r8d,%r8d
  mov    $0x0,%eax
L17:
  mov    %ecx,%edi
  imul   (%rsi,%rax,4),%edi
  add    (%r9,%rax,4),%edi
  mov    %edi,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L17
L3:
  ret
```

assistant: ```c
void triad(int *a, int *b, int *c, int s, int numits) {
  int i;
triad:
  for (i = 0; i < numits; i++)
    c[i] = a[i] + s * b[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<triad>:
  endbr64
  mov    %rdi,%r9
  test   %r8d,%r8d
  jle    L6
  movslq %r8d,%r8
  xor    %eax,%eax
  nopl   0x0(%rax)
L14:
  mov    (%rsi,%rax,4),%edi
  imul   %ecx,%edi
  add    (%r9,%rax,4),%edi
  mov    %edi,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L14
L6:
  ret
```

assistant: ```c
void triad(int *a, int *b, int *c, int s, int numits) {
  int i;
triad:
  for (i = 0; i < numits; i++)
    c[i] = a[i] + s * b[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<triad>:
  endbr64
  test   %r8d,%r8d
  jle    L18
  lea    0x4(%rdi),%r9
  mov    %rdx,%rax
  sub    %r9,%rax
  cmp    $0x8,%rax
  lea    -0x1(%r8),%eax
  seta   %r9b
  cmp    $0x2,%eax
  seta   %al
  test   %al,%r9b
  je     L57
  lea    0x4(%rsi),%r9
  mov    %rdx,%rax
  sub    %r9,%rax
  cmp    $0x8,%rax
  jbe    L57
  movd   %ecx,%xmm4
  mov    %r8d,%r9d
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm2
  shr    $0x2,%r9d
  movdqa %xmm2,%xmm3
  shl    $0x4,%r9
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L17:
  movdqu (%rsi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rdi,%rax,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r9,%rax
  jne    L17
  mov    %r8d,%r9d
  and    $0xfffffffc,%r9d
  test   $0x3,%r8b
  je     L18
  mov    %r9d,%r10d
  mov    (%rsi,%r10,4),%r11d
  lea    0x0(,%r10,4),%rax
  imul   %ecx,%r11d
  add    (%rdi,%r10,4),%r11d
  mov    %r11d,(%rdx,%r10,4)
  lea    0x1(%r9),%r10d
  cmp    %r10d,%r8d
  jle    L18
  mov    0x4(%rsi,%rax,1),%r10d
  add    $0x2,%r9d
  imul   %ecx,%r10d
  add    0x4(%rdi,%rax,1),%r10d
  mov    %r10d,0x4(%rdx,%rax,1)
  cmp    %r9d,%r8d
  jle    L18
  imul   0x8(%rsi,%rax,1),%ecx
  add    0x8(%rdi,%rax,1),%ecx
  mov    %ecx,0x8(%rdx,%rax,1)
  ret
  xchg   %ax,%ax
L57:
  mov    %r8d,%r8d
  xor    %eax,%eax
  nopl   (%rax)
L27:
  mov    (%rsi,%rax,4),%r9d
  imul   %ecx,%r9d
  add    (%rdi,%rax,4),%r9d
  mov    %r9d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L27
L18:
  ret
```

assistant: ```c
void triad(int *a, int *b, int *c, int s, int numits) {
  int i;
triad:
  for (i = 0; i < numits; i++)
    c[i] = a[i] + s * b[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  movsd  D22(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L72
  movsd  D22(%rip),%xmm0
  jmp    L92
L72:
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L46
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jne    L46
  pxor   %xmm0,%xmm0
  jmp    L92
L46:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L35
  mov    -0x1c(%rbp),%eax
  neg    %eax
  mov    %eax,-0x10(%rbp)
L35:
  movl   $0x1,-0xc(%rbp)
  jmp    L30
L80:
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L80
  cmpl   $0x0,-0x1c(%rbp)
  jns    L62
  movsd  D22(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  jmp    L92
L62:
  movsd  -0x8(%rbp),%xmm0
L92:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D22
type_infered: f64

tool: D22: 1

assistant: ```c
double power(double base, int exponent) {
  double result = 1.0;
  int tmpExponent;
  if (exponent == 0) {
    return 1;
  }
  if (base == 0.0) {
    return 0;
  }
  if (exponent < 0) {
    tmpExponent = -exponent;
  }
  for (int i = 1; i <= tmpExponent; ++i) {
    result *= base;
  }
  if (exponent < 0) {
    return 1 / result;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<power>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L6
  ucomisd D11(%rip),%xmm0
  jp     L11
  pxor   %xmm0,%xmm0
  je     L22
L11:
  mov    %edi,%edx
  neg    %edx
  test   %edi,%edi
  mov    $0x0,%eax
  cmovns %eax,%edx
  add    $0x1,%edx
  mov    $0x1,%eax
  movsd  D31(%rip),%xmm0
L14:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L14
  test   %edi,%edi
  jns    L22
  movsd  D31(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
L6:
  movsd  D31(%rip),%xmm0
L22:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type: f64
name: extract_symbolic_data
arguments: label: D31
type: f64

tool: D11: 0

tool: D31: 1

assistant: ```c
double power(double base, int exponent) {
  double result = 1.0;
  int tmpExponent;
  if (exponent == 0) {
    return 1;
  }
  if (base == 0.0) {
    return 0;
  }
  if (exponent < 0) {
    tmpExponent = -exponent;
  }
  for (int i = 1; i <= tmpExponent; ++i) {
    result *= base;
  }
  if (exponent < 0) {
    return 1 / result;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<power>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L8
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm0
  jp     L25
  pxor   %xmm0,%xmm0
  je     L35
L25:
  mov    %edi,%eax
  xor    %edx,%edx
  mov    D6(%rip),%rcx
  neg    %eax
  test   %edi,%edi
  cmovs  %eax,%edx
  movq   %rcx,%xmm0
  mov    $0x1,%eax
  add    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L14:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L14
  test   %edi,%edi
  js     L3
L35:
  ret
L8:
  movsd  D6(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L3:
  movsd  D6(%rip),%xmm3
  divsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: f64

tool: D6: 1

assistant: ```c
double power(double base, int exponent) {
  double result = 1.0;
  int tmpExponent;
  if (exponent == 0) {
    return 1;
  }
  if (base == 0.0) {
    return 0;
  }
  if (exponent < 0) {
    tmpExponent = -exponent;
  }
  for (int i = 1; i <= tmpExponent; ++i) {
    result *= base;
  }
  if (exponent < 0) {
    return 1 / result;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<power>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L5
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm0
  jp     L11
  pxor   %xmm0,%xmm0
  je     L10
L11:
  mov    %edi,%eax
  xor    %edx,%edx
  mov    D7(%rip),%rcx
  neg    %eax
  test   %edi,%edi
  cmovs  %eax,%edx
  movq   %rcx,%xmm0
  mov    $0x1,%eax
  add    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L1:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L1
  test   %edi,%edi
  js     L12
L10:
  ret
L5:
  movsd  D7(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L12:
  movsd  D7(%rip),%xmm3
  divsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: f64

tool: D7: 1

assistant: ```c
double power(double base, int exponent) {
  double result = 1.0;
  int tmpExponent;
  if (exponent == 0) {
    return 1;
  }
  if (base == 0.0) {
    return 0;
  }
  if (exponent < 0) {
    tmpExponent = -exponent;
  }
  for (int i = 1; i <= tmpExponent; ++i) {
    result *= base;
  }
  if (exponent < 0) {
    return 1 / result;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L15:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %ebx,%ecx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L4:
  cmpl   $0x9,-0x14(%rbp)
  jle    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < 10; ++i)
    printf("%d %d %d\n", i, power(2, i), power(-3, i));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D8(%rip),%r12
L8:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %eax,%ebp
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,%edx
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L8
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < 10; ++i)
    printf("%d %d %d\n", i, power(2, i), power(-3, i));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L0:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %ebx,%esi
  mov    $0x2,%edi
  mov    %eax,%r12d
  call   <power@plt>
  mov    %ebx,%esi
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L0
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string

tool: D3: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < 10; ++i)
    printf("%d %d %d\n", i, power(2, i), power(-3, i));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L2:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %ebx,%esi
  mov    $0x2,%edi
  mov    %eax,%r12d
  call   <power@plt>
  mov    %ebx,%esi
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L2
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < 10; ++i)
    printf("%d %d %d\n", i, power(2, i), power(-3, i));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vec4_normalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movss  0x8(%rax),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  movss  0xc(%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  -0x8(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  ja     L15
  jmp    L5
L15:
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrtf@plt>
  mov    %eax,%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  -0x10(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  -0xc(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movss  -0x8(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
L5:
  nop
  leave
  ret
```

assistant: ```c
void vec4_normalize(float *dst) {
  float x = dst[0];
  float y = dst[1];
  float z = dst[2];
  float w = dst[3];
  float len = x * x + y * y + z * z + w * w;
  if (len > 0) {
    len = 1 / sqrtf(len);
    dst[0] = x * len;
    dst[1] = y * len;
    dst[2] = z * len;
    dst[3] = w * len;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vec4_normalize>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%r14d
  mov    0x4(%rdi),%r13d
  mov    0x8(%rdi),%r12d
  mov    0xc(%rdi),%ebp
  movd   %r14d,%xmm0
  mulss  %xmm0,%xmm0
  movd   %r13d,%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movd   %r12d,%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movd   %ebp,%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  comiss D6(%rip),%xmm0
  ja     L5
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    %rdi,%rbx
  call   <sqrtf@plt>
  mov    %eax,%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movd   %r14d,%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rbx)
  movd   %r13d,%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rbx)
  movd   %r12d,%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rbx)
  movd   %ebp,%xmm6
  mulss  %xmm0,%xmm6
  movss  %xmm6,0xc(%rbx)
  jmp    L3
```

tool_calls: name: unpack_data
arguments: tag: D6
type: f32

tool: D6: 0

assistant: ```c
void vec4_normalize(float *dst) {
  float x = dst[0];
  float y = dst[1];
  float z = dst[2];
  float w = dst[3];
  float len = x * x + y * y + z * z + w * w;
  if (len > 0) {
    len = 1 / sqrtf(len);
    dst[0] = x * len;
    dst[1] = y * len;
    dst[2] = z * len;
    dst[3] = w * len;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vec4_normalize>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  (%rdi),%xmm4
  movss  0x4(%rdi),%xmm3
  movss  0x8(%rdi),%xmm2
  movss  0xc(%rdi),%xmm1
  movaps %xmm4,%xmm0
  movaps %xmm3,%xmm5
  movss  %xmm4,0xc(%rsp)
  mulss  %xmm3,%xmm5
  movss  %xmm3,0x8(%rsp)
  mulss  %xmm4,%xmm0
  movss  %xmm2,0x4(%rsp)
  movss  %xmm1,(%rsp)
  addss  %xmm5,%xmm0
  movaps %xmm2,%xmm5
  mulss  %xmm2,%xmm5
  addss  %xmm5,%xmm0
  movaps %xmm1,%xmm5
  mulss  %xmm1,%xmm5
  addss  %xmm5,%xmm0
  comiss D1(%rip),%xmm0
  jbe    L3
  mov    %rdi,%rbx
  call   <sqrtf@plt>
  pxor   %xmm0,%xmm0
  movss  (%rsp),%xmm1
  movss  0xc(%rsp),%xmm4
  mov    %eax,%r8d
  mov    $0x1,%eax
  movss  0x8(%rsp),%xmm3
  movss  0x4(%rsp),%xmm2
  cltd
  idiv   %r8d
  cvtsi2ss %eax,%xmm0
  mulss  %xmm0,%xmm4
  mulss  %xmm0,%xmm3
  mulss  %xmm0,%xmm2
  mulss  %xmm0,%xmm1
  movss  %xmm4,(%rbx)
  movss  %xmm3,0x4(%rbx)
  movss  %xmm2,0x8(%rbx)
  movss  %xmm1,0xc(%rbx)
L3:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: f32

tool: D1: 0

assistant: ```c
void vec4_normalize(float *dst) {
  float x = dst[0];
  float y = dst[1];
  float z = dst[2];
  float w = dst[3];
  float len = x * x + y * y + z * z + w * w;
  if (len > 0) {
    len = 1 / sqrtf(len);
    dst[0] = x * len;
    dst[1] = y * len;
    dst[2] = z * len;
    dst[3] = w * len;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vec4_normalize>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movups (%rdi),%xmm4
  movss  0x4(%rdi),%xmm3
  movss  0x8(%rdi),%xmm2
  movss  0xc(%rdi),%xmm1
  mulss  %xmm3,%xmm3
  movaps %xmm4,%xmm0
  movaps %xmm4,(%rsp)
  mulss  %xmm4,%xmm0
  mulss  %xmm2,%xmm2
  mulss  %xmm1,%xmm1
  addss  %xmm3,%xmm0
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  comiss D7(%rip),%xmm0
  jbe    L4
  mov    %rdi,%rbx
  call   <sqrtf@plt>
  pxor   %xmm0,%xmm0
  movaps (%rsp),%xmm4
  mov    %eax,%r8d
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  cvtsi2ss %eax,%xmm0
  shufps $0x0,%xmm0,%xmm0
  mulps  %xmm4,%xmm0
  movups %xmm0,(%rbx)
L4:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: f32

tool: D7: 0

assistant: ```c
void vec4_normalize(float *dst) {
  float x = dst[0];
  float y = dst[1];
  float z = dst[2];
  float w = dst[3];
  float len = x * x + y * y + z * z + w * w;
  if (len > 0) {
    len = 1 / sqrtf(len);
    dst[0] = x * len;
    dst[1] = y * len;
    dst[2] = z * len;
    dst[3] = w * len;
  }
}
```