user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L61
L23:
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x0,-0x58(%rbp)
  movl   $0x0,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L59:
  cmp    %rdx,%rsp
  je     L148
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L59
L148:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L29
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L29:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L65
L25:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x54(%rbp)
L65:
  mov    -0x5c(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L25
  mov    -0x5c(%rbp),%eax
  cmp    $0x1,%eax
  je     L134
  mov    -0x5c(%rbp),%eax
  cmp    $0x2,%eax
  jne    L100
L134:
  mov    -0x5c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,-0x50(%rbp)
  jmp    L17
L100:
  mov    -0x5c(%rbp),%eax
  cmp    $0x3,%eax
  jne    L130
  mov    -0x40(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    0x4(%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x50(%rbp)
  jmp    L17
L130:
  movl   $0x1,-0x54(%rbp)
  jmp    L144
L50:
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,-0x50(%rbp)
  addl   $0x1,-0x58(%rbp)
  addl   $0x1,-0x54(%rbp)
L144:
  mov    -0x5c(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x54(%rbp)
  jl     L50
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  imul   -0x58(%rbp),%eax
  mov    %eax,%edx
  mov    -0x50(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x5c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x40(%rbp),%rax
  mov    0x4(%rax),%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x50(%rbp)
L17:
  mov    -0x50(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
L61:
  mov    -0x60(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x60(%rbp)
  test   %eax,%eax
  jne    L23
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string

tool: D12: %d


tool: D22: %d

assistant: ```c
int main() {
  int t;
  scanf("%d\n", &t);
  while (t--) {
    int n, y, temp, x = 0, i, sum = 0, j = 0;
    scanf("%d", &n);
    int a[n];
    for (i = 0; i < n; i++) {
      scanf("%d", &a[i]);
    }
    if (n == 1 || n == 2) {
      sum = a[n - 1];
      goto A;
    } else if (n == 3) {
      sum = a[2] + a[0] + a[1];
      goto A;
    }
    for (i = 1; i < n - 2; i++) {
      sum = sum + a[i];
      x++;
    }
    sum = sum + a[0] * (x) + a[n - 1] + 2 * a[1];
  A:
    printf("%d\n", sum);
  }
  return 0;
}
```