ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<reorder_rows>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %ecx,0x8(%rsp)
  mov    %r8d,0xc(%rsp)
  cmp    %rdi,%rsi
  je     L49
  mov    0x8(%rsp),%eax
  mov    %rdi,%r15
  test   %eax,%eax
  jle    L24
L45:
  mov    0xc(%rsp),%eax
  movslq 0x8(%rsp),%r12
  xor    %r14d,%r14d
  lea    0x0(,%rax,8),%r13d
  nopl   0x0(%rax)
L4:
  movslq 0x0(%rbp,%r14,4),%rax
  mov    (%r15,%r14,8),%rdi
  mov    %r13d,%edx
  add    $0x1,%r14
  mov    (%rbx,%rax,8),%rsi
  call   <memcpy@plt>
  cmp    %r14,%r12
  jne    L4
  cmp    (%rsp),%rbx
  je     L26
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %r8d,%esi
  mov    %ecx,%edi
  mov    %ecx,%r14d
  call   <new_matrix2@plt>
  mov    %rax,%r15
  test   %r14d,%r14d
  jg     L45
L26:
  mov    (%rsp),%rdi
  mov    0xc(%rsp),%ecx
  mov    %r15,%rsi
  mov    0x8(%rsp),%edx
  call   <matrix_copy@plt>
  add    $0x18,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free_matrix2@plt>
```

assistant: ```c
void reorder_rows(double **Y, double **X, int *idx, int n, int m) {
  int i;
  double **Y2 = (X == Y ? new_matrix2(n, m) : Y);
  for (i = 0; i < n; i++)
    memcpy(Y2[i], X[idx[i]], m * sizeof(double));
  if (X == Y) {
    matrix_copy(Y, Y2, n, m);
    free_matrix2(Y2);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: Hola mundo!

assistant: ```c
int main(void) {
  printf("Hola mundo!");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8: Hola mundo!

assistant: ```c
int main(void) {
  printf("Hola mundo!");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Hola mundo!

assistant: ```c
int main(void) {
  printf("Hola mundo!");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: Hola mundo!

assistant: ```c
int main(void) {
  printf("Hola mundo!");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SortComp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L24
  mov    $0x1,%eax
  jmp    L21
L24:
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L12
  ucomisd %xmm1,%xmm0
  jne    L12
  mov    $0x0,%eax
  jmp    L21
L12:
  mov    $0xffffffff,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int SortComp(const void *x, const void *y) {
  const double *xx = (const double *)x;
  const double *yy = (const double *)y;
  if (*xx > *yy)
    return 1;
  else {
    if (*xx == *yy)
      return 0;
    else
      return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SortComp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm0,%xmm1
  ja     L6
  ucomisd %xmm0,%xmm1
  setp   %al
  movzbl %al,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
  neg    %eax
L6:
  ret
```

assistant: ```c
int SortComp(const void *x, const void *y) {
  const double *xx = (const double *)x;
  const double *yy = (const double *)y;
  if (*xx > *yy)
    return 1;
  else {
    if (*xx == *yy)
      return 0;
    else
      return -1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SortComp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm0,%xmm1
  ja     L8
  xor    %edx,%edx
  ucomisd %xmm0,%xmm1
  setp   %dl
  cmove  %edx,%eax
  neg    %eax
L8:
  ret
```

assistant: ```c
int SortComp(const void *x, const void *y) {
  const double *xx = (const double *)x;
  const double *yy = (const double *)y;
  if (*xx > *yy)
    return 1;
  else {
    if (*xx == *yy)
      return 0;
    else
      return -1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SortComp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm0,%xmm1
  ja     L1
  xor    %edx,%edx
  ucomisd %xmm0,%xmm1
  setp   %dl
  cmove  %edx,%eax
  neg    %eax
L1:
  ret
```

assistant: ```c
int SortComp(const void *x, const void *y) {
  const double *xx = (const double *)x;
  const double *yy = (const double *)y;
  if (*xx > *yy)
    return 1;
  else {
    if (*xx == *yy)
      return 0;
    else
      return -1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<echo_e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L23
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L23
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int echo_e(char **tab) {
  int i;
  i = 2;
  while (tab[i] != NULL) {
    if (!(tab[i][0] == 92))
      my_putstr(tab[i++]);
  }
  my_putchar('\n');
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<echo_e>:
  endbr64
  push   %rbx
  lea    0x10(%rdi),%rbx
L29:
  mov    (%rbx),%rdi
L26:
  test   %rdi,%rdi
  je     L1
  cmpb   $0x5c,(%rdi)
  je     L26
  call   <my_putstr@plt>
  add    $0x8,%rbx
  jmp    L29
L1:
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int echo_e(char **tab) {
  int i;
  i = 2;
  while (tab[i] != NULL) {
    if (!(tab[i][0] == 92))
      my_putstr(tab[i++]);
  }
  my_putchar('\n');
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<echo_e>:
  endbr64
  push   %rbx
  lea    0x10(%rdi),%rbx
L36:
  mov    (%rbx),%rdi
  jmp    L33
  xchg   %ax,%ax
L12:
  cmpb   $0x5c,(%rdi)
  jne    L23
L33:
  test   %rdi,%rdi
  jne    L12
  mov    $0xa,%edi
  call   <my_putchar@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  call   <my_putstr@plt>
  add    $0x8,%rbx
  jmp    L36
```

assistant: ```c
int echo_e(char **tab) {
  int i;
  i = 2;
  while (tab[i] != NULL) {
    if (!(tab[i][0] == 92))
      my_putstr(tab[i++]);
  }
  my_putchar('\n');
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<echo_e>:
  endbr64
  push   %rbx
  mov    0x10(%rdi),%r8
  test   %r8,%r8
  je     L26
  lea    0x18(%rdi),%rbx
L27:
  cmpb   $0x5c,(%r8)
  jne    L30
L4:
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %r8,%rdi
  add    $0x8,%rbx
  call   <my_putstr@plt>
  mov    -0x8(%rbx),%r8
  test   %r8,%r8
  jne    L27
L26:
  mov    $0xa,%edi
  call   <my_putchar@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int echo_e(char **tab) {
  int i;
  i = 2;
  while (tab[i] != NULL) {
    if (!(tab[i][0] == 92))
      my_putstr(tab[i++]);
  }
  my_putchar('\n');
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x98(%rbp)
  jmp    L4
L31:
  movl   $0x0,-0x94(%rbp)
  jmp    L32
L5:
  lea    -0x90(%rbp),%rdx
  mov    -0x94(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x98(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x94(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x50(%rbp,%rax,4)
  addl   $0x1,-0x94(%rbp)
L32:
  cmpl   $0x3,-0x94(%rbp)
  jle    L5
  addl   $0x1,-0x98(%rbp)
L4:
  cmpl   $0x3,-0x98(%rbp)
  jle    L31
  lea    -0x50(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inverse@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <printMatrix@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D9: %f

tool: D7: Inverse is:


assistant: ```c
int main(int argc, char *argv[]) {
  float a[4][4], a_inv[4][4];
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      scanf("%f", &a[i][j]);
      a_inv[i][j] = 0;
    }
  }
  inverse(a, a_inv);
  printf("Inverse is:\n");
  printMatrix(a_inv);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x40(%rsp),%rbp
  mov    $0x0,%r14d
  lea    D8(%rip),%r13
L0:
  mov    $0x0,%ebx
L28:
  lea    (%rbx,%r12,1),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movl   $0x0,0x0(%rbp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  jne    L28
  add    $0x4,%r14
  add    $0x10,%r12
  add    $0x10,%rbp
  cmp    $0x10,%r14
  jne    L0
  lea    0x40(%rsp),%rbx
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <inverse@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printMatrix@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string
name: unpack_data
arguments: label: D19
type_infered: string

tool: D8: %f

tool: D19: Inverse is:


assistant: ```c
int main(int argc, char *argv[]) {
  float a[4][4], a_inv[4][4];
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      scanf("%f", &a[i][j]);
      a_inv[i][j] = 0;
    }
  }
  inverse(a, a_inv);
  printf("Inverse is:\n");
  printMatrix(a_inv);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x50(%rsp),%r14
  mov    %rbp,0x8(%rsp)
  mov    %r14,%rbx
L1:
  xor    %r15d,%r15d
L17:
  lea    (%r15,%rbp,1),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movl   $0x0,(%rbx,%r15,1)
  add    $0x4,%r15
  cmp    $0x10,%r15
  jne    L17
  add    $0x4,%r13
  add    $0x10,%rbp
  add    $0x10,%rbx
  cmp    $0x10,%r13
  jne    L1
  mov    0x8(%rsp),%rdi
  mov    %r14,%rsi
  call   <inverse@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printMatrix@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string

tool: D2: %f

tool: D1: Inverse is:


assistant: ```c
int main(int argc, char *argv[]) {
  float a[4][4], a_inv[4][4];
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      scanf("%f", &a[i][j]);
      a_inv[i][j] = 0;
    }
  }
  inverse(a, a_inv);
  printf("Inverse is:\n");
  printMatrix(a_inv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x50(%rsp),%r14
  mov    %rbp,0x8(%rsp)
  mov    %r14,%rbx
L3:
  xor    %r15d,%r15d
L10:
  lea    (%r15,%rbp,1),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movl   $0x0,(%rbx,%r15,1)
  add    $0x4,%r15
  cmp    $0x10,%r15
  jne    L10
  add    $0x4,%r13
  add    $0x10,%rbp
  add    $0x10,%rbx
  cmp    $0x10,%r13
  jne    L3
  mov    0x8(%rsp),%rdi
  mov    %r14,%rsi
  call   <inverse@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printMatrix@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D9: %f

tool: D8: Inverse is:


assistant: ```c
int main(int argc, char *argv[]) {
  float a[4][4], a_inv[4][4];
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      scanf("%f", &a[i][j]);
      a_inv[i][j] = 0;
    }
  }
  inverse(a, a_inv);
  printf("Inverse is:\n");
  printMatrix(a_inv);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  jmp    L18
L17:
  subl   $0x2,-0x4(%rbp)
L18:
  cmpl   $0x1,-0x4(%rbp)
  jg     L17
  cmpl   $0x1,-0x4(%rbp)
  jle    L24
  addl   $0x38,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  nop
  leave
  ret
```

assistant: ```c
void test4() {
  int a = 5;
  while (a > 1)
    a -= 2;
  if (a > 1) {
    a = a + 56;
  }
  foo(a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test4>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test4() {
  int a = 5;
  while (a > 1)
    a -= 2;
  if (a > 1) {
    a = a + 56;
  }
  foo(a);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test4>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <foo@plt>
```

assistant: ```c
void test4() {
  int a = 5;
  while (a > 1)
    a -= 2;
  if (a > 1) {
    a = a + 56;
  }
  foo(a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test4>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <foo@plt>
```

assistant: ```c
void test4() {
  int a = 5;
  while (a > 1)
    a -= 2;
  if (a > 1) {
    a = a + 56;
  }
  foo(a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_89_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_89_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T | stk3;
  stk1 = D ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_89_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%ecx
  not    %ecx
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  mov    %esi,%edx
  or     %ecx,%edx
  xor    $0xff,%dl
  and    %edx,%eax
  and    %ecx,%esi
  movzbl %sil,%esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_89_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T | stk3;
  stk1 = D ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_89_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%ecx
  shl    $0x8,%esi
  not    %ecx
  or     %eax,%esi
  mov    %esi,%eax
  mov    %esi,%edx
  and    %ecx,%esi
  or     %ecx,%edx
  not    %eax
  movzbl %sil,%esi
  or     %edi,%eax
  xor    $0xff,%dl
  and    %edx,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_89_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T | stk3;
  stk1 = D ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_89_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%ecx
  shl    $0x8,%esi
  not    %ecx
  or     %eax,%esi
  mov    %esi,%eax
  mov    %esi,%edx
  and    %ecx,%esi
  or     %ecx,%edx
  not    %eax
  movzbl %sil,%esi
  or     %edi,%eax
  xor    $0xff,%dl
  and    %edx,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_89_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T | stk3;
  stk1 = D ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multiplication>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rdx,%r12
  mov    %ecx,%ebx
  mov    %r8,%rbp
  mov    %esi,0x4(%rsp)
  lea    (%rsi,%rcx,1),%r14d
  lea    0x1(%r14),%r15d
  mov    $0x4,%esi
  mov    %r15d,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L95
  lea    0x4(%rax),%r9
  mov    0x8(%rsp),%rdx
  mov    %rdx,%rdi
  mov    %esi,%eax
  lea    0x1(%rdx,%rax,1),%r10
  mov    %ebx,%eax
  lea    0x1(%r12,%rax,1),%r8
L119:
  test   %ebx,%ebx
  js     L69
  mov    %r12,%rdx
  mov    %r9,%rax
L9:
  movzbl (%rdi),%ecx
  movzbl (%rdx),%esi
  imul   %esi,%ecx
  add    %ecx,(%rax)
  add    $0x4,%rax
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L9
L69:
  add    $0x4,%r9
  add    $0x1,%rdi
  cmp    %r10,%rdi
  jne    L119
L95:
  test   %r15d,%r15d
  js     L75
  movslq %r15d,%rax
  lea    0x0(%r13,%rax,4),%rax
  movslq %r14d,%rdx
  lea    0x1(%r14),%ecx
  sub    %rcx,%rdx
  lea    0x0(%r13,%rdx,4),%rsi
  mov    $0x0,%ecx
L67:
  mov    %ecx,%edx
  add    (%rax),%edx
  mov    %edx,%ecx
  shr    $0x8,%ecx
  and    $0xff,%edx
  mov    %edx,(%rax)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L67
  cmpl   $0x0,0x0(%r13)
  je     L7
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %r15d,%r14d
  jmp    L101
L7:
  test   %r15d,%r15d
  jle    L19
  lea    0x4(%r13),%rax
  mov    %r14d,%edx
  lea    0x8(%r13,%rdx,4),%rcx
L112:
  mov    (%rax),%edx
  mov    %edx,-0x4(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L112
L19:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  test   %r14d,%r14d
  js     L73
L101:
  movslq %r14d,%rax
  lea    0x0(%r13,%rax,4),%rdx
L120:
  mov    (%rdx),%ecx
  mov    %cl,0x0(%rbp,%rax,1)
  sub    $0x1,%rax
  sub    $0x4,%rdx
  test   %eax,%eax
  jns    L120
L73:
  mov    %r14d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  cmpl   $0x0,0x0(%r13)
  je     L19
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %r15d,%r14d
  jmp    L73
```

assistant: ```c
int multiplication(unsigned char *a, int a_len, unsigned char *b, int b_len, unsigned char *multires) {
  int i, j, k, m = 0;
  unsigned int *cross = (unsigned int *)calloc(a_len + b_len + 1, sizeof(unsigned int));
  for (i = 0; i <= a_len; i++)
    for (j = 0, k = i + 1; j <= b_len; j++, k++)
      cross[k] += a[i] * b[j];
  k = a_len + b_len + 1;
  for (i = k; i >= 0; i--) {
    cross[i] += m;
    m = cross[i] >> 8;
    cross[i] &= 0xff;
  }
  if (cross[0] == 0) {
    for (i = 0; i < k; i++)
      cross[i] = cross[i + 1];
    k--;
  }
  realloc(multires, k);
  for (i = k; i >= 0; i--)
    multires[i] = cross[i];
  return k;
}
```