ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r12
  lea    0x40(%rsp),%r13
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r13,%rdi
  call   <gets@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L10
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
L10:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L25
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
L25:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L27
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
L27:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D13
type: string

tool: D0: input three line :

tool: D13: now the order is:
%s
%s
%s


assistant: ```c
int main() {
  void swap(char *, char *);
  char str1[20], str2[20], str3[20];
  printf("input three line :\n");
  gets(str1);
  gets(str2);
  gets(str3);
  if (strcmp(str1, str2) > 0)
    swap(str1, str2);
  if (strcmp(str1, str3) > 0)
    swap(str1, str3);
  if (strcmp(str2, str3) > 0)
    swap(str2, str3);
  printf("now the order is:\n%s\n%s\n%s\n", str1, str2, str3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r12
  lea    0x40(%rsp),%r13
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r13,%rdi
  call   <gets@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L10
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
L10:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L15
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
L15:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L37
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
L37:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_guessed: string
name: extract_symbolic_data
arguments: label: D15
type_guessed: string

tool: D10: input three line :

tool: D15: now the order is:
%s
%s
%s


assistant: ```c
int main() {
  void swap(char *, char *);
  char str1[20], str2[20], str3[20];
  printf("input three line :\n");
  gets(str1);
  gets(str2);
  gets(str3);
  if (strcmp(str1, str2) > 0)
    swap(str1, str2);
  if (strcmp(str1, str3) > 0)
    swap(str1, str3);
  if (strcmp(str2, str3) > 0)
    swap(str2, str3);
  printf("now the order is:\n%s\n%s\n%s\n", str1, str2, str3);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_empty_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <count@plt>
  test   %rax,%rax
  jne    L17
  lea    -0xc(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <count_opt@plt>
  test   %rax,%rax
  jne    L17
  mov    $0x1,%eax
  jmp    L35
L17:
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int test_empty_array() {
  int array[] = {};
  return 0 == count(array, 0) && 0 == count_opt(array, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_empty_array>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  call   <count@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L9
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
L9:
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  call   <count_opt@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L29
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_empty_array() {
  int array[] = {};
  return 0 == count(array, 0) && 0 == count_opt(array, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_empty_array>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <count@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L8
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <count_opt@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L16
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_empty_array() {
  int array[] = {};
  return 0 == count(array, 0) && 0 == count_opt(array, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_empty_array>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <count@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L3
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <count_opt@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L27
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_empty_array() {
  int array[] = {};
  return 0 == count(array, 0) && 0 == count_opt(array, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<arraydiff_kernel_rect_bwd_f32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L2:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  comiss %xmm3,%xmm0
  jbe    L12
  movss  D7(%rip),%xmm0
  jmp    L4
L12:
  pxor   %xmm0,%xmm0
L4:
  mulss  %xmm2,%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L2
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void arraydiff_kernel_rect_bwd_f32(size_t dim, const float *x, const float *dy, float *dx) {
  for (size_t i = 0; i < dim; i++) {
    float x_i = x[i];
    dx[i] += dy[i] * (x_i > 0.0f);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<arraydiff_kernel_rect_bwd_f32>:
  endbr64
  test   %rdi,%rdi
  je     L8
  mov    $0x0,%eax
  pxor   %xmm3,%xmm3
  movss  D7(%rip),%xmm2
  movaps %xmm3,%xmm4
L15:
  movss  (%rsi,%rax,4),%xmm1
  movaps %xmm3,%xmm0
  cmpltss %xmm1,%xmm0
  movaps %xmm2,%xmm1
  andps  %xmm0,%xmm1
  andnps %xmm4,%xmm0
  orps   %xmm1,%xmm0
  mulss  (%rdx,%rax,4),%xmm0
  addss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L15
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void arraydiff_kernel_rect_bwd_f32(size_t dim, const float *x, const float *dy, float *dx) {
  for (size_t i = 0; i < dim; i++) {
    float x_i = x[i];
    dx[i] += dy[i] * (x_i > 0.0f);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arraydiff_kernel_rect_bwd_f32>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm3,%xmm3
  test   %rdi,%rdi
  je     L19
  nop
L21:
  movss  (%rsi,%rax,4),%xmm2
  movss  (%rcx,%rax,4),%xmm0
  movss  (%rdx,%rax,4),%xmm1
  comiss %xmm3,%xmm2
  ja     L16
  mulss  %xmm3,%xmm1
L16:
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L21
L19:
  ret
```

assistant: ```c
void arraydiff_kernel_rect_bwd_f32(size_t dim, const float *x, const float *dy, float *dx) {
  for (size_t i = 0; i < dim; i++) {
    float x_i = x[i];
    dx[i] += dy[i] * (x_i > 0.0f);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arraydiff_kernel_rect_bwd_f32>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm3,%xmm3
  test   %rdi,%rdi
  je     L7
  nop
L0:
  movss  (%rsi,%rax,4),%xmm2
  movss  (%rcx,%rax,4),%xmm0
  movss  (%rdx,%rax,4),%xmm1
  comiss %xmm3,%xmm2
  ja     L5
  mulss  %xmm3,%xmm1
L5:
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L0
L7:
  ret
```

assistant: ```c
void arraydiff_kernel_rect_bwd_f32(size_t dim, const float *x, const float *dy, float *dx) {
  for (size_t i = 0; i < dim; i++) {
    float x_i = x[i];
    dx[i] += dy[i] * (x_i > 0.0f);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: 
Bom dia, Ola Mundo


assistant: ```c
int main() {
  printf("\nBom dia, Ola Mundo\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: 
Bom dia, Ola Mundo


assistant: ```c
int main() {
  printf("\nBom dia, Ola Mundo\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: 
Bom dia, Ola Mundo


assistant: ```c
int main() {
  printf("\nBom dia, Ola Mundo\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: 
Bom dia, Ola Mundo


assistant: ```c
int main() {
  printf("\nBom dia, Ola Mundo\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<n_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L7
L18:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jbe    L16
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  ja     L16
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L18
L16:
  mov    -0x4(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int n_digits(const unsigned char source[], int position, int length) {
  int i;
  for (i = position; ((source[i] >= '0') && (source[i] <= '9')) && (i < length); i++)
    ;
  return i - position;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<n_digits>:
  endbr64
  mov    %rdi,%r9
  movslq %esi,%rax
  movzbl (%rdi,%rax,1),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L28
  cmp    %edx,%esi
  jge    L28
  lea    0x1(%rsi),%ecx
  movslq %ecx,%rcx
L12:
  mov    %ecx,%eax
  movzbl (%r9,%rcx,1),%edi
  sub    $0x30,%edi
  cmp    $0x9,%dil
  setbe  %r8b
  cmp    %ecx,%edx
  setg   %dil
  add    $0x1,%rcx
  test   %dil,%r8b
  jne    L12
L24:
  sub    %esi,%eax
  ret
L28:
  mov    %esi,%eax
  jmp    L24
```

assistant: ```c
int n_digits(const unsigned char source[], int position, int length) {
  int i;
  for (i = position; ((source[i] >= '0') && (source[i] <= '9')) && (i < length); i++)
    ;
  return i - position;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<n_digits>:
  endbr64
  movslq %esi,%rax
  mov    %rdi,%r9
  movzbl (%rdi,%rax,1),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L16
  cmp    %edx,%esi
  jge    L16
  lea    0x1(%rsi),%ecx
  movslq %ecx,%rcx
  nop
L18:
  movzbl (%r9,%rcx,1),%edi
  mov    %ecx,%eax
  sub    $0x30,%edi
  cmp    $0x9,%dil
  setbe  %r8b
  cmp    %ecx,%edx
  setg   %dil
  add    $0x1,%rcx
  test   %dil,%r8b
  jne    L18
  sub    %esi,%eax
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int n_digits(const unsigned char source[], int position, int length) {
  int i;
  for (i = position; ((source[i] >= '0') && (source[i] <= '9')) && (i < length); i++)
    ;
  return i - position;
}
```
user: What is the c source code of the assembly code below:

```asm
<n_digits>:
  endbr64
  movslq %esi,%rax
  mov    %rdi,%r9
  movzbl (%rdi,%rax,1),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L27
  cmp    %edx,%esi
  jge    L27
  lea    0x1(%rsi),%ecx
  movslq %ecx,%rcx
  nop
L21:
  movzbl (%r9,%rcx,1),%edi
  mov    %ecx,%eax
  sub    $0x30,%edi
  cmp    $0x9,%dil
  setbe  %r8b
  cmp    %ecx,%edx
  setg   %dil
  add    $0x1,%rcx
  test   %dil,%r8b
  jne    L21
  sub    %esi,%eax
  ret
  nopl   0x0(%rax)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int n_digits(const unsigned char source[], int position, int length) {
  int i;
  for (i = position; ((source[i] >= '0') && (source[i] <= '9')) && (i < length); i++)
    ;
  return i - position;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cond_signal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_cond_signal@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  mov    -0x4(%rbp),%eax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <syserr@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: cond signal failed

assistant: ```c
void cond_signal(pthread_cond_t *c) {
  int err;
  if ((err = pthread_cond_signal(c)) != 0) {
    syserr(err, "cond signal failed");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cond_signal>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_cond_signal@plt>
  test   %eax,%eax
  jne    L10
L14:
  add    $0x8,%rsp
  ret
L10:
  lea    D8(%rip),%rsi
  mov    %eax,%edi
  call   <syserr@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: cond signal failed

assistant: ```c
void cond_signal(pthread_cond_t *c) {
  int err;
  if ((err = pthread_cond_signal(c)) != 0) {
    syserr(err, "cond signal failed");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cond_signal>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_cond_signal@plt>
  test   %eax,%eax
  jne    L8
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  lea    D8(%rip),%rsi
  mov    %eax,%edi
  add    $0x8,%rsp
  jmp    1060 <syserr@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: cond signal failed

assistant: ```c
void cond_signal(pthread_cond_t *c) {
  int err;
  if ((err = pthread_cond_signal(c)) != 0) {
    syserr(err, "cond signal failed");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cond_signal>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_cond_signal@plt>
  test   %eax,%eax
  jne    L5
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  lea    D4(%rip),%rsi
  mov    %eax,%edi
  add    $0x8,%rsp
  jmp    1060 <syserr@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D4: cond signal failed

assistant: ```c
void cond_signal(pthread_cond_t *c) {
  int err;
  if ((err = pthread_cond_signal(c)) != 0) {
    syserr(err, "cond signal failed");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  movslq %ebx,%rcx
  mov    %rcx,-0x48(%rbp)
  lea    0xf(,%rcx,4),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L41:
  cmp    %rcx,%rsp
  je     L120
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L41
L120:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L4
  orq    $0x0,-0x8(%rsp,%rdx,1)
L4:
  mov    %rsp,%r12
  test   %ebx,%ebx
  jle    L106
  mov    %r12,%rdx
  lea    -0x2(%rax),%eax
  lea    0x4(%r12,%rax,4),%rax
L43:
  movl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rax,%rdx
  jne    L43
  test   %r14d,%r14d
  jle    L70
L126:
  mov    $0x0,%eax
  call   <rnd@plt>
  cltd
  idiv   %ebx
  mov    %edx,%eax
  cmpl   $0x0,(%r12,%rax,4)
  je     L126
  mov    %edx,%edx
  movl   $0x0,(%r12,%rdx,4)
  sub    $0x1,%r14d
  test   %r14d,%r14d
  jg     L126
  test   %ebx,%ebx
  jle    L103
L70:
  mov    $0x0,%eax
  jmp    L1
L147:
  movb   $0x20,0x1(%r13)
  add    $0x2,%r13
L61:
  add    $0x1,%rax
  cmp    %eax,%ebx
  jle    L103
L1:
  movzbl (%r15,%rax,1),%edx
  mov    %dl,0x0(%r13)
  cmpl   $0x0,(%r12,%rax,4)
  je     L147
  add    $0x1,%r13
  jmp    L61
L106:
  test   %r14d,%r14d
  jg     L126
L103:
  mov    -0x48(%rbp),%rax
  movzbl (%r15,%rax,1),%eax
  mov    %al,0x0(%r13)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void split(const char *s, char *result, int n) {
  int l = strlen(s) - 1;
  int space_holders[l];
  for (int i = 0; i < l; i++) {
    space_holders[i] = (!0);
  }
  for (int spaces = n; spaces > 0; spaces--) {
    do {
      unsigned int r = rnd() % l;
      if (space_holders[r]) {
        space_holders[r] = 0;
        break;
      }
    } while ((!0));
  }
  for (int i = 0; i < l; i++) {
    *result = s[i];
    result++;
    if (!space_holders[i]) {
      *result = ' ';
      result++;
    }
  }
  *result = s[l];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    -0x1(%rax),%ebx
  movslq %ebx,%rcx
  lea    0xf(,%rcx,4),%rdx
  mov    %rcx,-0x48(%rbp)
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L113
L7:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L7
L113:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L9
L150:
  mov    %rsp,%r12
  test   %ebx,%ebx
  jle    L70
  sub    $0x2,%eax
  mov    %r12,%rdx
  lea    0x4(%r12,%rax,4),%rax
  nopw   0x0(%rax,%rax,1)
L122:
  movl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rax,%rdx
  jne    L122
  test   %r14d,%r14d
  jle    L1
  nopl   0x0(%rax)
L73:
  xor    %eax,%eax
  call   <rnd@plt>
  cltd
  idiv   %ebx
  mov    (%r12,%rdx,4),%ecx
  test   %ecx,%ecx
  je     L73
  movl   $0x0,(%r12,%rdx,4)
  sub    $0x1,%r14d
  jne    L73
  test   %ebx,%ebx
  jle    L83
L1:
  xor    %eax,%eax
  jmp    L77
L14:
  add    $0x1,%rax
  add    $0x1,%r13
  cmp    %eax,%ebx
  jle    L83
L77:
  movzbl (%r15,%rax,1),%edx
  mov    %dl,0x0(%r13)
  mov    (%r12,%rax,4),%edx
  test   %edx,%edx
  jne    L14
  add    $0x1,%rax
  movb   $0x20,0x1(%r13)
  add    $0x2,%r13
  cmp    %eax,%ebx
  jg     L77
L83:
  mov    -0x48(%rbp),%rax
  movzbl (%r15,%rax,1),%eax
  mov    %al,0x0(%r13)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L9:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L150
L70:
  test   %r14d,%r14d
  jg     L73
  jmp    L83
L88:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void split(const char *s, char *result, int n) {
  int l = strlen(s) - 1;
  int space_holders[l];
  for (int i = 0; i < l; i++) {
    space_holders[i] = (!0);
  }
  for (int spaces = n; spaces > 0; spaces--) {
    do {
      unsigned int r = rnd() % l;
      if (space_holders[r]) {
        space_holders[r] = 0;
        break;
      }
    } while ((!0));
  }
  for (int i = 0; i < l; i++) {
    *result = s[i];
    result++;
    if (!space_holders[i]) {
      *result = ' ';
      result++;
    }
  }
  *result = s[l];
}
```