user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcoloncmp2>:
  endbr64
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rdx,%rdx
  mov    %esi,0xc(%rsp)
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  lea    0x1(%rbx),%eax
  xor    %edi,%edi
  mov    %r13,%rbx
  cmp    $0x100,%eax
  setbe  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x1,%r14d
  setbe  %dil
  call   <assert@plt>
  movzbl 0x0(%r13),%eax
  cmp    $0x3a,%al
  jne    L25
  movzbl 0x1(%r13),%eax
  lea    0x1(%r13),%rbx
L25:
  test   %al,%al
  je     L88
  cs nopw 0x0(%rax,%rax,1)
L123:
  mov    $0x1,%edi
  cmp    %rbx,%r13
  je     L166
  xor    %edi,%edi
  cmpb   $0x3a,-0x1(%rbx)
  sete   %dil
L166:
  call   <assert@plt>
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L181
  mov    %r12,%r15
  test   %r14d,%r14d
  jne    L57
  jmp    L155
  nopl   (%rax)
L222:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  cmp    %rbp,%rax
  jne    L135
  movsbl 0x1(%r15),%edi
  add    $0x1,%r15
  lea    0x1(%rbx),%rbp
  test   %dil,%dil
  je     L278
  mov    %rbp,%rbx
L155:
  cmpb   $0x0,(%rbx)
  jne    L222
L26:
  mov    0xc(%rsp),%eax
  mov    %rbx,%rbp
  movsbl %dil,%r8d
  cmp    $0xffffffff,%eax
  je     L296
L264:
  cmp    %eax,%r8d
  jne    L50
  jmp    L296
  nopl   (%rax)
L60:
  lea    0x1(%rbp),%rbx
  cmp    $0x3a,%al
  je     L156
  mov    %rbx,%rbp
L50:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L60
L88:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L178:
  cmp    %dil,%al
  jne    L53
  movzbl 0x1(%r15),%edi
  add    $0x1,%r15
  lea    0x1(%rbx),%rbp
  test   %dil,%dil
  je     L278
  mov    %rbp,%rbx
L57:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L178
  jmp    L26
  nop
L156:
  cmpb   $0x0,0x1(%rbp)
  jne    L123
  jmp    L88
  nopl   0x0(%rax)
L278:
  movzbl 0x1(%rbx),%eax
L31:
  test   %al,%al
  je     L163
  cmp    $0x3a,%al
  jne    L50
L163:
  movzbl (%r15),%edi
  mov    0xc(%rsp),%eax
  movsbl %dil,%r8d
  cmp    $0xffffffff,%eax
  jne    L264
  nopl   0x0(%rax)
L296:
  cmp    $0x8,%dil
  je     L211
L247:
  mov    %r8d,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L50
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L135:
  movzbl (%rbx),%eax
  mov    %rbx,%rbp
  jmp    L31
L53:
  mov    %rbx,%rbp
  jmp    L31
L211:
  movzbl -0x1(%r15),%eax
  jmp    L197
  cs nopw 0x0(%rax,%rax,1)
L86:
  movsbl 0x2(%r15),%r8d
  add    $0x2,%r15
  cmp    $0x8,%r8b
  jne    L247
L197:
  cmp    %al,0x1(%r15)
  je     L86
  mov    $0x8,%r8d
  jmp    L247
L181:
  movzbl (%rbx),%eax
  mov    %r12,%r15
  mov    %rbx,%rbp
  jmp    L31
```

assistant: ```c
int strcoloncmp2(char *candidate, int end, const char *list, int sen) {
  const char *l = list;
  char *c, c2;
  assert(candidate != NULL && list != NULL);
  assert(end >= -1 && end <= 255);
  assert(sen == 0 || sen == 1);
  if (*l == ':')
    l++;
  while (*l) {
    assert(l == list || l[-1] == ':');
    for (c = candidate; *c && *l; c++, l++)
      if ((sen && *c != *l) || (!sen && tolower(*c) != tolower(*l)))
        break;
    if ((*l == '\0' || *l == ':') && (*c == end || end == -1)) {
      if (*c == '\b') {
        c2 = c[-1];
        while (*c == '\b' && c[1] == c2)
          c += 2;
      }
      if (!isdigit(*c))
        return 1;
    }
    while (*l && *l++ != ':')
      ;
  }
  return 0;
}
```