ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<test_comparison>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x20(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L19
  mov    $0xffffffff,%eax
  jmp    L94
L19:
  lea    -0x20(%rbp),%rax
  add    $0x4,%rax
  cmp    %rax,-0x28(%rbp)
  je     L43
  mov    $0xffffffff,%eax
  jmp    L94
L43:
  lea    -0x20(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  ja     L5
  mov    $0xffffffff,%eax
  jmp    L94
L5:
  lea    -0x20(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jae    L37
  mov    $0xffffffff,%eax
  jmp    L94
L37:
  lea    -0x20(%rbp),%rax
  add    $0x14,%rax
  cmp    %rax,-0x28(%rbp)
  jne    L62
  mov    $0xffffffff,%eax
  jmp    L94
L62:
  mov    $0x0,%eax
L94:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  leave
  ret
```

assistant: ```c
int test_comparison() {
  int x[] = {1, 2, 3, 4, 5};
  int *y = x + 1;
  if (!(x != y))
    return -1;
  if (!(x + 1 == y))
    return -1;
  if (!(x < y))
    return -1;
  if (!(x <= y))
    return -1;
  if (!(x + 5 != y))
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_comparison>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int test_comparison() {
  int x[] = {1, 2, 3, 4, 5};
  int *y = x + 1;
  if (!(x != y))
    return -1;
  if (!(x + 1 == y))
    return -1;
  if (!(x < y))
    return -1;
  if (!(x <= y))
    return -1;
  if (!(x + 5 != y))
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_comparison>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test_comparison() {
  int x[] = {1, 2, 3, 4, 5};
  int *y = x + 1;
  if (!(x != y))
    return -1;
  if (!(x + 1 == y))
    return -1;
  if (!(x < y))
    return -1;
  if (!(x <= y))
    return -1;
  if (!(x + 5 != y))
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_comparison>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test_comparison() {
  int x[] = {1, 2, 3, 4, 5};
  int *y = x + 1;
  if (!(x != y))
    return -1;
  if (!(x + 1 == y))
    return -1;
  if (!(x < y))
    return -1;
  if (!(x <= y))
    return -1;
  if (!(x + 5 != y))
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BusFaultISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L6:
  jmp    L6
```

assistant: ```c
void BusFaultISR(void) {
  while (1) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BusFaultISR>:
  endbr64
L8:
  jmp    L8
```

assistant: ```c
void BusFaultISR(void) {
  while (1) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BusFaultISR>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void BusFaultISR(void) {
  while (1) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BusFaultISR>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
void BusFaultISR(void) {
  while (1) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cast_uint_to_IPv4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x1,%esi
  mov    $0x10,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl %al,%esi
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%ecx
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%edx
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edi
  mov    -0x8(%rbp),%rax
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %edi,%edx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: %d.%d.%d.%d

assistant: ```c
char *cast_uint_to_IPv4(uint32_t ip) {
  char *_ip = (char *)calloc(16, sizeof(char));
  sprintf(_ip, "%d.%d.%d.%d", (ip >> 24) & 0xFF, (ip >> 16) & 0xFF, (ip >> 8) & 0xFF, ip & 0xFF);
  return _ip;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cast_uint_to_IPv4>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%esi
  mov    $0x10,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  movzbl %bh,%eax
  mov    %eax,%r8d
  mov    %ebx,%ecx
  sar    $0x10,%ecx
  movzbl %cl,%ecx
  mov    %ebx,%edx
  shr    $0x18,%edx
  movzbl %bl,%r9d
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: %d.%d.%d.%d

assistant: ```c
char *cast_uint_to_IPv4(uint32_t ip) {
  char *_ip = (char *)calloc(16, sizeof(char));
  sprintf(_ip, "%d.%d.%d.%d", (ip >> 24) & 0xFF, (ip >> 16) & 0xFF, (ip >> 8) & 0xFF, ip & 0xFF);
  return _ip;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cast_uint_to_IPv4>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    $0x10,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %ebx,%ecx
  mov    %ebx,%edx
  movzbl %bl,%r9d
  sar    $0x10,%ecx
  mov    %rax,%r12
  movzbl %bh,%eax
  shr    $0x18,%edx
  mov    %r12,%rdi
  mov    %eax,%r8d
  lea    D5(%rip),%rsi
  movzbl %cl,%ecx
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: %d.%d.%d.%d

assistant: ```c
char *cast_uint_to_IPv4(uint32_t ip) {
  char *_ip = (char *)calloc(16, sizeof(char));
  sprintf(_ip, "%d.%d.%d.%d", (ip >> 24) & 0xFF, (ip >> 16) & 0xFF, (ip >> 8) & 0xFF, ip & 0xFF);
  return _ip;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cast_uint_to_IPv4>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    $0x10,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %ebx,%ecx
  mov    %ebx,%edx
  movzbl %bl,%r9d
  sar    $0x10,%ecx
  mov    %rax,%r12
  movzbl %bh,%eax
  shr    $0x18,%edx
  mov    %r12,%rdi
  mov    %eax,%r8d
  lea    D4(%rip),%rsi
  movzbl %cl,%ecx
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: %d.%d.%d.%d

assistant: ```c
char *cast_uint_to_IPv4(uint32_t ip) {
  char *_ip = (char *)calloc(16, sizeof(char));
  sprintf(_ip, "%d.%d.%d.%d", (ip >> 24) & 0xFF, (ip >> 16) & 0xFF, (ip >> 8) & 0xFF, ip & 0xFF);
  return _ip;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x63,-0x4(%rbp)
  movl   $0x64,-0xc(%rbp)
  jmp    L22
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_bouncy@plt>
  test   %rax,%rax
  je     L12
  addl   $0x1,-0x8(%rbp)
  jmp    L21
L12:
  addl   $0x1,-0x4(%rbp)
L21:
  addl   $0x1,-0xc(%rbp)
L22:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <is_ratio_reached@plt>
  test   %eax,%eax
  je     L6
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string

tool: D2: The first number that satisfies the condition is %i


assistant: ```c
int main() {
  int i, bouncy = 0, non_bouncy = 99;
  for (i = 100; !is_ratio_reached(bouncy, non_bouncy); i++) {
    if (is_bouncy(i)) {
      bouncy++;
    } else {
      non_bouncy++;
    }
  }
  printf("The first number that satisfies the condition is %i\n", i - 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x63,%r12d
  mov    $0x0,%ebp
  mov    $0x64,%ebx
  jmp    L27
L3:
  add    $0x1,%r12d
L32:
  add    $0x1,%ebx
L27:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <is_ratio_reached@plt>
  test   %eax,%eax
  jne    L34
  mov    %ebx,%edi
  call   <is_bouncy@plt>
  test   %rax,%rax
  je     L3
  add    $0x1,%ebp
  jmp    L32
L34:
  lea    -0x1(%rbx),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: The first number that satisfies the condition is %i


assistant: ```c
int main() {
  int i, bouncy = 0, non_bouncy = 99;
  for (i = 100; !is_ratio_reached(bouncy, non_bouncy); i++) {
    if (is_bouncy(i)) {
      bouncy++;
    } else {
      non_bouncy++;
    }
  }
  printf("The first number that satisfies the condition is %i\n", i - 1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x63,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x64,%ebx
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x1,%ebp
L26:
  add    $0x1,%ebx
L36:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <is_ratio_reached@plt>
  test   %eax,%eax
  jne    L14
  mov    %ebx,%edi
  call   <is_bouncy@plt>
  test   %rax,%rax
  jne    L29
  add    $0x1,%r12d
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L14:
  lea    -0x1(%rbx),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: The first number that satisfies the condition is %i


assistant: ```c
int main() {
  int i, bouncy = 0, non_bouncy = 99;
  for (i = 100; !is_ratio_reached(bouncy, non_bouncy); i++) {
    if (is_bouncy(i)) {
      bouncy++;
    } else {
      non_bouncy++;
    }
  }
  printf("The first number that satisfies the condition is %i\n", i - 1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x63,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x64,%ebx
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%ebp
L29:
  add    $0x1,%ebx
L0:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <is_ratio_reached@plt>
  test   %eax,%eax
  jne    L26
  mov    %ebx,%edi
  call   <is_bouncy@plt>
  test   %rax,%rax
  jne    L6
  add    $0x1,%r12d
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L26:
  lea    -0x1(%rbx),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: The first number that satisfies the condition is %i


assistant: ```c
int main() {
  int i, bouncy = 0, non_bouncy = 99;
  for (i = 100; !is_ratio_reached(bouncy, non_bouncy); i++) {
    if (is_bouncy(i)) {
      bouncy++;
    } else {
      non_bouncy++;
    }
  }
  printf("The first number that satisfies the condition is %i\n", i - 1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<PLD_strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L15:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x16(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x15(%rbp)
  movzbl -0x16(%rbp),%eax
  cmp    -0x15(%rbp),%al
  jne    L18
  subl   $0x1,-0x34(%rbp)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L0
L18:
  movsbl -0x15(%rbp),%eax
  movsbl -0x16(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x34(%rbp)
L0:
  cmpl   $0x0,-0x34(%rbp)
  jg     L15
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int PLD_strncasecmp(char *s1, char *s2, int n) {
  char *ds1 = s1, *ds2 = s2;
  char c1, c2;
  int result = 0;
  while (n > 0) {
    c1 = tolower(*ds1);
    c2 = tolower(*ds2);
    if (c1 == c2) {
      n--;
      ds1++;
      ds2++;
    } else {
      result = c2 - c1;
      n = 0;
    }
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PLD_strncasecmp>:
  endbr64
  test   %edx,%edx
  jle    L15
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%r13
  jmp    L34
L48:
  add    $0x1,%rbp
  add    $0x1,%r12
  cmp    %rbp,%r13
  je     L9
L34:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movsbl (%r12),%edi
  call   <tolower@plt>
  cmp    %al,%bl
  je     L48
  movsbl %al,%eax
  movsbl %bl,%ebx
  sub    %ebx,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0x0,%eax
  jmp    L2
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int PLD_strncasecmp(char *s1, char *s2, int n) {
  char *ds1 = s1, *ds2 = s2;
  char c1, c2;
  int result = 0;
  while (n > 0) {
    c1 = tolower(*ds1);
    c2 = tolower(*ds2);
    if (c1 == c2) {
      n--;
      ds1++;
      ds2++;
    } else {
      result = c2 - c1;
      n = 0;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PLD_strncasecmp>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  add    %rdi,%r12
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L11
L29:
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  movsbl %al,%ebx
  call   <tolower@plt>
  cmp    %al,%bl
  je     L6
  add    $0x8,%rsp
  movsbl %al,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%r13
  add    $0x1,%rbp
  cmp    %r12,%r13
  jne    L29
L11:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int PLD_strncasecmp(char *s1, char *s2, int n) {
  char *ds1 = s1, *ds2 = s2;
  char c1, c2;
  int result = 0;
  while (n > 0) {
    c1 = tolower(*ds1);
    c2 = tolower(*ds2);
    if (c1 == c2) {
      n--;
      ds1++;
      ds2++;
    } else {
      result = c2 - c1;
      n = 0;
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<PLD_strncasecmp>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  add    %rdi,%r12
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L13
L26:
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  movsbl %al,%ebx
  call   <tolower@plt>
  cmp    %al,%bl
  je     L14
  add    $0x8,%rsp
  movsbl %al,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%r13
  add    $0x1,%rbp
  cmp    %r12,%r13
  jne    L26
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int PLD_strncasecmp(char *s1, char *s2, int n) {
  char *ds1 = s1, *ds2 = s2;
  char c1, c2;
  int result = 0;
  while (n > 0) {
    c1 = tolower(*ds1);
    c2 = tolower(*ds2);
    if (c1 == c2) {
      n--;
      ds1++;
      ds2++;
    } else {
      result = c2 - c1;
      n = 0;
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x6,-0x24(%rbp)
  movl   $0x58,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x8,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <HeapSort@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L21
L28:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L21:
  cmpl   $0x9,-0x34(%rbp)
  jle    L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: %d 

assistant: ```c
int main() {
  int ar[10] = {1, 4, 2, 6, 88, 5, 8, 2, 9, 3};
  HeapSort(ar);
  int i;
  for (i = 0; i < 10; i++)
    printf("%d ", ar[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x58,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x8,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <HeapSort@plt>
  lea    0x28(%rsp),%r12
  lea    D4(%rip),%rbp
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L10
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: %d 

assistant: ```c
int main() {
  int ar[10] = {1, 4, 2, 6, 88, 5, 8, 2, 9, 3};
  HeapSort(ar);
  int i;
  for (i = 0; i < 10; i++)
    printf("%d ", ar[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x400000001,%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x600000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000058,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x200000008,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000009,%rax
  mov    %rax,0x20(%rsp)
  call   <HeapSort@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: %d 

assistant: ```c
int main() {
  int ar[10] = {1, 4, 2, 6, 88, 5, 8, 2, 9, 3};
  HeapSort(ar);
  int i;
  for (i = 0; i < 10; i++)
    printf("%d ", ar[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    D24(%rip),%rax
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D35(%rip),%xmm0
  mov    %rbx,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <HeapSort@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L8
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D20
type: string
name: unpack_data
arguments: label: D17
type: byte[16]
name: unpack_data
arguments: label: D24
type: byte[8]
name: unpack_data
arguments: label: D35
type: byte[16]

tool: D20: %d 

tool: {"D17": [0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D24": [0x09,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D35": [0x58,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int ar[10] = {1, 4, 2, 6, 88, 5, 8, 2, 9, 3};
  HeapSort(ar);
  int i;
  for (i = 0; i < 10; i++)
    printf("%d ", ar[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<remove0blocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L28:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L9
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    (%rdx),%rdx
  mov    %rdx,(%rax)
L9:
  addl   $0x8,-0x14(%rbp)
  addq   $0x8,-0x10(%rbp)
L3:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L28
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void remove0blocks(unsigned char *pIn, int *inSize) {
  long long *in = (long long *)pIn;
  long long *out = (long long *)pIn;
  int i;
  for (i = 0; i < *inSize; i += 8, in++)
    if (*in)
      *out++ = *in;
  *inSize -= (in - out) * 8;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<remove0blocks>:
  endbr64
  mov    (%rsi),%edx
  test   %edx,%edx
  jle    L0
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L2
L39:
  add    $0x8,%eax
  add    $0x8,%rdi
  mov    (%rsi),%edx
  cmp    %eax,%edx
  jle    L40
L2:
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  je     L39
  mov    %rdx,(%rcx)
  lea    0x8(%rcx),%rcx
  jmp    L39
L0:
  mov    %rdi,%rcx
L40:
  sub    %rcx,%rdi
  sub    %edi,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void remove0blocks(unsigned char *pIn, int *inSize) {
  long long *in = (long long *)pIn;
  long long *out = (long long *)pIn;
  int i;
  for (i = 0; i < *inSize; i += 8, in++)
    if (*in)
      *out++ = *in;
  *inSize -= (in - out) * 8;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<remove0blocks>:
  endbr64
  mov    (%rsi),%r8d
  test   %r8d,%r8d
  jle    L1
  lea    -0x1(%r8),%eax
  shr    $0x3,%eax
  add    $0x1,%eax
  lea    (%rdi,%rax,8),%rcx
  mov    %rdi,%rax
  nopl   (%rax)
L24:
  mov    (%rax),%rdx
  test   %rdx,%rdx
  je     L21
  mov    %rdx,(%rdi)
  add    $0x8,%rdi
L21:
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L24
  sub    %edi,%ecx
  sub    %ecx,%r8d
  mov    %r8d,(%rsi)
  ret
  nopl   0x0(%rax)
L1:
  xor    %ecx,%ecx
  sub    %ecx,%r8d
  mov    %r8d,(%rsi)
  ret
```

assistant: ```c
void remove0blocks(unsigned char *pIn, int *inSize) {
  long long *in = (long long *)pIn;
  long long *out = (long long *)pIn;
  int i;
  for (i = 0; i < *inSize; i += 8, in++)
    if (*in)
      *out++ = *in;
  *inSize -= (in - out) * 8;
}
```
user: What is the c source code of the assembly code below?

```asm
<remove0blocks>:
  endbr64
  mov    (%rsi),%r8d
  test   %r8d,%r8d
  jle    L2
  lea    -0x1(%r8),%eax
  shr    $0x3,%eax
  add    $0x1,%eax
  lea    (%rdi,%rax,8),%rcx
  mov    %rdi,%rax
  nopl   (%rax)
L7:
  mov    (%rax),%rdx
  test   %rdx,%rdx
  je     L5
  mov    %rdx,(%rdi)
  add    $0x8,%rdi
L5:
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L7
  sub    %edi,%ecx
  sub    %ecx,%r8d
  mov    %r8d,(%rsi)
  ret
  nopl   0x0(%rax)
L2:
  xor    %ecx,%ecx
  sub    %ecx,%r8d
  mov    %r8d,(%rsi)
  ret
```

assistant: ```c
void remove0blocks(unsigned char *pIn, int *inSize) {
  long long *in = (long long *)pIn;
  long long *out = (long long *)pIn;
  int i;
  for (i = 0; i < *inSize; i += 8, in++)
    if (*in)
      *out++ = *in;
  *inSize -= (in - out) * 8;
}
```