ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x14,%esi
  lea    D28(%rip),%rdi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x708,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x6f8(%rsp)
  xor    %eax,%eax
  lea    0xa0(%rsp),%rbx
  mov    %rsp,%r13
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L19:
  mov    $0x51,%esi
  mov    %rbx,%rdi
  mov    %ebp,%r12d
  call   <s_gets@plt>
  test   %rax,%rax
  je     L48
  cmpb   $0x0,(%rbx)
  je     L48
  mov    %rbx,0x0(%r13,%rbp,8)
  add    $0x1,%rbp
  add    $0x51,%rbx
  cmp    $0x14,%rbp
  jne    L19
  mov    $0x14,%esi
  mov    %r13,%rdi
  mov    $0x14,%r12d
  call   <sort@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
L42:
  xor    %ebx,%ebx
  xchg   %ax,%ax
L51:
  mov    0x0(%r13,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %ebx,%r12d
  jg     L51
L47:
  mov    0x6f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x708,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  mov    %r13,%rdi
  mov    %r12d,%esi
  call   <sort@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jne    L42
  jmp    L47
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D28
type_guessed: string
name: parse_data
arguments: data_label: D21
type_guessed: string
name: parse_data
arguments: data_label: D33
type_guessed: string

tool: D28: Input up to %d lines, then sort.


tool: D21: To stop, press the Enter key at a line's start.

tool: D33: 
Here's the sorted list:


assistant: ```c
int main(void) {
  char input[20][81];
  char *ptstr[20];
  int count = 0;
  int k;
  printf("Input up to %d lines, then sort.\n", 20);
  printf("To stop, press the Enter key at a line's start.\n");
  while (count < 20 && s_gets(input[count], 81) != NULL && input[count][0] != '\0') {
    ptstr[count] = input[count];
    count++;
  }
  sort(ptstr, count);
  puts("\nHere's the sorted list:\n");
  for (k = 0; k < count; k++)
    puts(ptstr[k]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<c_destructor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_mem@plt>
  jmp    L8
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_mem@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free_mem@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void c_destructor(void **tag, void **cell) {
  if (*tag == *cell) {
    free_mem(tag);
  } else {
    free_mem(tag);
    free_mem(cell);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<c_destructor>:
  endbr64
  push   %rbx
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  je     L15
  mov    %rsi,%rbx
  call   <free_mem@plt>
  mov    %rbx,%rdi
  call   <free_mem@plt>
L12:
  pop    %rbx
  ret
L15:
  call   <free_mem@plt>
  jmp    L12
```

assistant: ```c
void c_destructor(void **tag, void **cell) {
  if (*tag == *cell) {
    free_mem(tag);
  } else {
    free_mem(tag);
    free_mem(cell);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<c_destructor>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  je     L8
  push   %rbp
  mov    %rsi,%rbp
  call   <free_mem@plt>
  mov    %rbp,%rdi
  pop    %rbp
L8:
  jmp    1050 <free_mem@plt>
```

assistant: ```c
void c_destructor(void **tag, void **cell) {
  if (*tag == *cell) {
    free_mem(tag);
  } else {
    free_mem(tag);
    free_mem(cell);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<c_destructor>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  je     L4
  push   %rbp
  mov    %rsi,%rbp
  call   <free_mem@plt>
  mov    %rbp,%rdi
  pop    %rbp
L4:
  jmp    1050 <free_mem@plt>
```

assistant: ```c
void c_destructor(void **tag, void **cell) {
  if (*tag == *cell) {
    free_mem(tag);
  } else {
    free_mem(tag);
    free_mem(cell);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sock_nbsendto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L82
L62:
  nop
L5:
  lea    -0x14(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x4,%r9d
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <sendto@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L18
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L107
  mov    D19(%rip),%rax
  mov    (%rax),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L107
L18:
  mov    -0x28(%rbp),%eax
  sub    -0x10(%rbp),%eax
  jmp    L29
L107:
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L104
  mov    D19(%rip),%rax
  mov    (%rax),%rdx
  mov    D37(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L104
  jmp    L5
L104:
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L59
  mov    $0xffffffff,%eax
  jmp    L29
L59:
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x30(%rbp)
L82:
  cmpl   $0x0,-0x10(%rbp)
  jne    L62
  mov    -0x28(%rbp),%eax
  sub    -0x10(%rbp),%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L83
  call   <__stack_chk_fail@plt>
L83:
  leave
  ret
```

assistant: ```c
int sock_nbsendto(int s, void *buf, int len, char *hostname, int port) {
  int ret, comp = len;
  struct sockaddr_in sa;
  while (comp) {
  nbsendto_restart:
    ret = sendto(s, (char *)buf, comp, 0, (struct sockaddr *)&sa, sizeof(struct sockaddr_in));
    if (ret == 0 || (ret == -1 && errno == EWOULDBLOCK))
      return (len - comp);
    if (ret == -1 && errno == EINTR)
      goto nbsendto_restart;
    else if (ret == -1)
      return -1;
    comp -= ret;
    buf += ret;
  }
  return (len - comp);
}
```
user: What is the c source code of the assembly code below:

```asm
<sock_nbsendto>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L89
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  lea    0x4(%rsp),%r13
  jmp    L59
L35:
  mov    D30(%rip),%rcx
  mov    D35(%rip),%rdx
  mov    (%rdx),%rdi
  cmp    %rdi,(%rcx)
  je     L58
  mov    D30(%rip),%rcx
  mov    D36(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L16
L59:
  mov    $0x4,%r9d
  mov    %r13,%r8
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <sendto@plt>
  test   %eax,%eax
  je     L58
  cmp    $0xffffffff,%eax
  je     L35
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  jne    L59
L89:
  mov    %r14d,%eax
  jmp    L16
L58:
  mov    %r14d,%eax
  sub    %ebx,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_nbsendto(int s, void *buf, int len, char *hostname, int port) {
  int ret, comp = len;
  struct sockaddr_in sa;
  while (comp) {
  nbsendto_restart:
    ret = sendto(s, (char *)buf, comp, 0, (struct sockaddr *)&sa, sizeof(struct sockaddr_in));
    if (ret == 0 || (ret == -1 && errno == EWOULDBLOCK))
      return (len - comp);
    if (ret == -1 && errno == EINTR)
      goto nbsendto_restart;
    else if (ret == -1)
      return -1;
    comp -= ret;
    buf += ret;
  }
  return (len - comp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sock_nbsendto>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L54
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    %edx,%ebx
  lea    0x4(%rsp),%r14
  nopl   0x0(%rax,%rax,1)
L57:
  xor    %ecx,%ecx
  mov    $0x4,%r9d
  mov    %r14,%r8
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <sendto@plt>
  test   %eax,%eax
  je     L50
  cmp    $0xffffffff,%eax
  je     L85
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  jne    L57
  mov    %r13d,%eax
  xchg   %ax,%ax
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L85:
  mov    D1(%rip),%rdx
  mov    (%rdx),%rcx
  mov    D17(%rip),%rdx
  cmp    (%rdx),%rcx
  je     L50
  mov    D29(%rip),%rdx
  cmp    (%rdx),%rcx
  je     L57
  jmp    L36
  nopl   0x0(%rax)
L50:
  mov    %r13d,%eax
  sub    %ebx,%eax
  jmp    L36
L54:
  xor    %eax,%eax
  jmp    L36
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_nbsendto(int s, void *buf, int len, char *hostname, int port) {
  int ret, comp = len;
  struct sockaddr_in sa;
  while (comp) {
  nbsendto_restart:
    ret = sendto(s, (char *)buf, comp, 0, (struct sockaddr *)&sa, sizeof(struct sockaddr_in));
    if (ret == 0 || (ret == -1 && errno == EWOULDBLOCK))
      return (len - comp);
    if (ret == -1 && errno == EINTR)
      goto nbsendto_restart;
    else if (ret == -1)
      return -1;
    comp -= ret;
    buf += ret;
  }
  return (len - comp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_nbsendto>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L5
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    %edx,%ebx
  lea    0x4(%rsp),%r14
  nopl   0x0(%rax,%rax,1)
L84:
  xor    %ecx,%ecx
  mov    $0x4,%r9d
  mov    %r14,%r8
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <sendto@plt>
  test   %eax,%eax
  je     L98
  cmp    $0xffffffff,%eax
  je     L0
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  jne    L84
  mov    %r13d,%eax
  xchg   %ax,%ax
L76:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L0:
  mov    D8(%rip),%rdx
  mov    (%rdx),%rcx
  mov    D6(%rip),%rdx
  cmp    (%rdx),%rcx
  je     L98
  mov    D1(%rip),%rdx
  cmp    (%rdx),%rcx
  je     L84
  jmp    L76
  nopl   0x0(%rax)
L98:
  mov    %r13d,%eax
  sub    %ebx,%eax
  jmp    L76
L5:
  xor    %eax,%eax
  jmp    L76
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_nbsendto(int s, void *buf, int len, char *hostname, int port) {
  int ret, comp = len;
  struct sockaddr_in sa;
  while (comp) {
  nbsendto_restart:
    ret = sendto(s, (char *)buf, comp, 0, (struct sockaddr *)&sa, sizeof(struct sockaddr_in));
    if (ret == 0 || (ret == -1 && errno == EWOULDBLOCK))
      return (len - comp);
    if (ret == -1 && errno == EINTR)
      goto nbsendto_restart;
    else if (ret == -1)
      return -1;
    comp -= ret;
    buf += ret;
  }
  return (len - comp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L38
L2:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L12:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L4:
  cmpl   $0x2,-0x14(%rbp)
  jle    L12
  addl   $0x1,-0x18(%rbp)
L38:
  cmpl   $0x6,-0x18(%rbp)
  jle    L2
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string
name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D11
type: string

tool: D5: ssumors

tool: D20: # c::%s:len=%d


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ssumors", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D8(%rip),%r15
  jmp    L31
L37:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L12
L31:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L22:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L22
  jmp    L37
L12:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string
name: disassemble_data
arguments: data_tag: D13
data_type: string
name: disassemble_data
arguments: data_tag: D12
data_type: string

tool: D8: ssumors

tool: D13: # c::%s:len=%d


tool: D12: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ssumors", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D8(%rip),%r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L13:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L13
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L8
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D20
type_guessed: string

tool: D8: ssumors

tool: D3: # c::%s:len=%d


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ssumors", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D7(%rip),%r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L0:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L13:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L13
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L0
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string

tool: D7: ssumors

tool: D8: # c::%s:len=%d


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ssumors", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L4:
  addq   $0x2710,-0x18(%rbp)
  addq   $0x2710,-0x20(%rbp)
L10:
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x2710,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <pmemccpy@plt>
  test   %eax,%eax
  je     L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *os1;
  os1 = s1;
  while (!pmemccpy(s1, s2, 0, 10000)) {
    s1 += 10000;
    s2 += 10000;
  }
  return os1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcpy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdi,%rbp
  jmp    L13
L19:
  add    $0x2710,%rbp
  add    $0x2710,%rbx
L13:
  mov    $0x2710,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <pmemccpy@plt>
  test   %eax,%eax
  je     L19
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *os1;
  os1 = s1;
  while (!pmemccpy(s1, s2, 0, 10000)) {
    s1 += 10000;
    s2 += 10000;
  }
  return os1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x2710,%rbp
  add    $0x2710,%rbx
L13:
  xor    %edx,%edx
  mov    $0x2710,%ecx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <pmemccpy@plt>
  test   %eax,%eax
  je     L9
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *os1;
  os1 = s1;
  while (!pmemccpy(s1, s2, 0, 10000)) {
    s1 += 10000;
    s2 += 10000;
  }
  return os1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x2710,%rbp
  add    $0x2710,%rbx
L15:
  xor    %edx,%edx
  mov    $0x2710,%ecx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <pmemccpy@plt>
  test   %eax,%eax
  je     L17
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *os1;
  os1 = s1;
  while (!pmemccpy(s1, s2, 0, 10000)) {
    s1 += 10000;
    s2 += 10000;
  }
  return os1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crc16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movw   $0x0,-0x6(%rbp)
  jmp    L33
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x6(%rbp),%eax
  xor    %edx,%eax
  mov    %ax,-0x6(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L12:
  movzwl -0x6(%rbp),%eax
  test   %ax,%ax
  jns    L55
  shlw   -0x6(%rbp)
  xorw   $0x1021,-0x6(%rbp)
  jmp    L23
L55:
  shlw   -0x6(%rbp)
L23:
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x7,-0x4(%rbp)
  jle    L12
  addq   $0x1,-0x18(%rbp)
L33:
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
L18:
  movzwl -0x6(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int crc16(char *s) {
  unsigned short crc = 0;
  int ibit;
  while (!((s) == NULL ? 1 : (*(s) == '\000' ? 1 : 0))) {
    crc = (crc ^ (*s) << 8);
    for (ibit = 0; ibit < 8; ibit++)
      if (crc & 0x8000) {
        crc <<= 1;
        crc = crc ^ 4129;
      } else
        crc <<= 1;
    s++;
  }
  return ((int)crc);
}
```