user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D44(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rbx
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  test   %eax,%eax
  js     L13
  movl   $0x0,0x8(%rsp)
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  movl   $0x0,0x14(%rsp)
  lea    D41(%rip),%r15
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L66:
  addl   $0x1,0xc(%rsp)
L56:
  addl   $0x1,0x10(%rsp)
L64:
  addl   $0x1,0x1c(%rsp)
L99:
  lea    -0x51(%rax),%edx
  cmp    $0x13,%edx
  ja     L68
  add    $0x1,%r14d
L148:
  mov    %r15,%rdi
  add    $0x1,%r12d
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  test   %eax,%eax
  js     L95
  cmp    $0x64,%r12d
  je     L95
L84:
  cmp    $0x50,%eax
  jg     L66
  cmp    $0x3c,%eax
  jg     L56
  cmp    $0x28,%eax
  jg     L64
  je     L99
  add    $0x1,%r13d
L68:
  lea    -0x3d(%rax),%edx
  cmp    $0x13,%edx
  ja     L126
  addl   $0x1,0x18(%rsp)
  jmp    L148
L126:
  lea    -0x29(%rax),%edx
  cmp    $0x13,%edx
  ja     L24
  addl   $0x1,0x14(%rsp)
  jmp    L148
L24:
  cmp    $0x28,%eax
  jg     L148
  addl   $0x1,0x8(%rsp)
  jmp    L148
L95:
  mov    %r12d,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%r9d
  mov    %r13d,%r8d
  lea    D40(%rip),%rdi
  push   %rax
  mov    0x10(%rsp),%eax
  push   %rax
  mov    0x24(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x3c(%rsp),%ecx
  xor    %eax,%eax
  mov    0x30(%rsp),%edx
  mov    0x2c(%rsp),%esi
  call   <printf@plt>
  add    $0x20,%rsp
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D44
datatype: string
name: unpack_data
arguments: tag: D20
datatype: string
name: unpack_data
arguments: tag: D41
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D40
datatype: string

tool: D44: Enter the List of Marks (-1 to finish) 

tool: D20: %d

tool: D41: Got That!!.. Next 

tool: D5: No of Students: %d 


tool: D40:  A= %d 
 B= %d 
 C= %d 
 D= %d 
 E= %d 
 F= %d 
 G= %d 
 H= %d 


assistant: ```c
int main() {
  int len = 0, n, a = 0, b = 0, c = 0, d = 0, e = 0, f = 0, g = 0, h = 0;
  printf("Enter the List of Marks (-1 to finish) \n");
  scanf("%d", &n);
  while (n >= 0 && len < 100) {
    if (n > 80)
      a++;
    if (n > 60)
      b++;
    if (n > 40)
      c++;
    if (n < 40)
      d++;
    if (n > 80 && n <= 100)
      e++;
    if (n > 60 && n <= 80)
      f++;
    if (n > 40 && n <= 60)
      g++;
    if (n <= 40)
      h++;
    printf("Got That!!.. Next \n");
    scanf("%d", &n);
    len++;
  }
  if (len > 0) {
    printf("No of Students: %d \n", len);
    printf(" A= %d \n B= %d \n C= %d \n D= %d \n "
           "E= %d \n F= %d \n G= %d \n H= %d \n",
           a, b, c, d, e, f, g, h);
  }
  return 0;
}
```