ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<corner_dtrinv_4x4_lib4>:
  endbr64
  movsd  0x10(%rdi),%xmm1
  movsd  0x48(%rdi),%xmm6
  movsd  (%rdi),%xmm0
  movsd  0x28(%rdi),%xmm5
  movq   D9(%rip),%xmm4
  movapd %xmm1,%xmm3
  movapd %xmm6,%xmm2
  movsd  %xmm1,0x28(%rsi)
  movsd  %xmm5,0x50(%rsi)
  movsd  %xmm0,(%rsi)
  xorpd  %xmm4,%xmm3
  xorpd  %xmm4,%xmm2
  movsd  %xmm6,0x78(%rsi)
  mulsd  0x8(%rdi),%xmm3
  mulsd  0x40(%rdi),%xmm2
  mulsd  %xmm0,%xmm3
  mulsd  %xmm5,%xmm2
  movsd  %xmm3,0x20(%rsi)
  movapd %xmm3,%xmm10
  movsd  %xmm2,0x70(%rsi)
  movsd  0x20(%rdi),%xmm9
  movsd  0x38(%rdi),%xmm7
  movsd  0x18(%rdi),%xmm8
  mulsd  %xmm9,%xmm10
  mulsd  %xmm0,%xmm8
  mulsd  %xmm7,%xmm3
  mulsd  0x30(%rdi),%xmm0
  mulsd  %xmm1,%xmm9
  mulsd  %xmm7,%xmm1
  addsd  %xmm10,%xmm8
  movapd %xmm2,%xmm10
  addsd  %xmm3,%xmm0
  mulsd  %xmm8,%xmm10
  mulsd  %xmm9,%xmm2
  mulsd  %xmm6,%xmm0
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm8
  mulsd  %xmm9,%xmm5
  addsd  %xmm10,%xmm0
  addsd  %xmm2,%xmm1
  xorpd  %xmm4,%xmm8
  xorpd  %xmm4,%xmm0
  xorpd  %xmm4,%xmm5
  movsd  %xmm8,0x40(%rsi)
  xorpd  %xmm4,%xmm1
  movsd  %xmm0,0x60(%rsi)
  movsd  %xmm5,0x48(%rsi)
  movsd  %xmm1,0x68(%rsi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: f32[2]

tool: {"D9": [0.0,-0.0]}

assistant: ```c
void corner_dtrinv_4x4_lib4(double *fact, double *C) {
  const int bs = 4;
  double c_00 = 0.0, c_10 = 0.0, c_11 = 0.0, c_20 = 0.0, c_21 = 0.0, c_22 = 0.0, c_30 = 0.0, c_31 = 0.0, c_32 = 0.0, c_33 = 0.0, d_20 = 0.0, d_21 = 0.0, d_30 = 0.0, d_31 = 0.0;
  c_00 = fact[0];
  c_11 = fact[2];
  c_22 = fact[5];
  c_33 = fact[9];
  C[0 + bs * 0] = c_00;
  C[1 + bs * 1] = c_11;
  C[2 + bs * 2] = c_22;
  C[3 + bs * 3] = c_33;
  c_10 = fact[1];
  c_32 = fact[8];
  c_10 = -c_11 * c_10 * c_00;
  c_32 = -c_33 * c_32 * c_22;
  C[0 + bs * 1] = c_10;
  C[2 + bs * 3] = c_32;
  c_21 = fact[4];
  c_31 = fact[7];
  c_20 = c_21 * c_10;
  c_30 = c_31 * c_10;
  c_21 = c_21 * c_11;
  c_31 = c_31 * c_11;
  c_20 += fact[3] * c_00;
  c_30 += fact[6] * c_00;
  d_20 = c_22 * c_20;
  d_30 = c_32 * c_20;
  d_21 = c_22 * c_21;
  d_31 = c_32 * c_21;
  d_30 += c_33 * c_30;
  d_31 += c_33 * c_31;
  C[0 + bs * 2] = -d_20;
  C[0 + bs * 3] = -d_30;
  C[1 + bs * 2] = -d_21;
  C[1 + bs * 3] = -d_31;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<corner_dtrinv_4x4_lib4>:
  endbr64
  movupd 0x20(%rdi),%xmm3
  movsd  0x10(%rdi),%xmm1
  movsd  0x48(%rdi),%xmm6
  movsd  (%rdi),%xmm0
  movapd %xmm3,%xmm4
  movapd %xmm1,%xmm5
  movsd  %xmm1,0x28(%rsi)
  unpckhpd %xmm3,%xmm3
  unpckhpd %xmm4,%xmm4
  movapd %xmm6,%xmm2
  movsd  %xmm0,(%rsi)
  movsd  %xmm4,0x50(%rsi)
  movapd %xmm4,%xmm7
  movq   D7(%rip),%xmm4
  movsd  %xmm6,0x78(%rsi)
  xorpd  %xmm4,%xmm5
  xorpd  %xmm4,%xmm2
  mulsd  0x8(%rdi),%xmm5
  mulsd  0x40(%rdi),%xmm2
  mulsd  %xmm0,%xmm5
  mulsd  %xmm7,%xmm2
  movsd  %xmm5,0x20(%rsi)
  movapd %xmm5,%xmm10
  movsd  %xmm2,0x70(%rsi)
  movsd  0x20(%rdi),%xmm9
  movsd  0x38(%rdi),%xmm7
  movsd  0x18(%rdi),%xmm8
  mulsd  %xmm9,%xmm10
  mulsd  %xmm0,%xmm8
  mulsd  %xmm7,%xmm5
  mulsd  0x30(%rdi),%xmm0
  mulsd  %xmm1,%xmm9
  mulsd  %xmm7,%xmm1
  addsd  %xmm10,%xmm8
  movapd %xmm2,%xmm10
  addsd  %xmm5,%xmm0
  mulsd  %xmm8,%xmm10
  unpcklpd %xmm9,%xmm8
  mulsd  %xmm9,%xmm2
  mulsd  %xmm6,%xmm0
  mulsd  %xmm6,%xmm1
  mulpd  %xmm8,%xmm3
  xorpd  D0(%rip),%xmm3
  addsd  %xmm10,%xmm0
  movups %xmm3,0x40(%rsi)
  addsd  %xmm2,%xmm1
  xorpd  %xmm4,%xmm0
  xorpd  %xmm4,%xmm1
  movsd  %xmm0,0x60(%rsi)
  movsd  %xmm1,0x68(%rsi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: f32[2]
name: disassemble_data
arguments: label: D0
datatype: f32[4]

tool: {"D7": [0.0,-0.0]}

tool: {"D0": [0.0,-0.0,0.0,-0.0]}

assistant: ```c
void corner_dtrinv_4x4_lib4(double *fact, double *C) {
  const int bs = 4;
  double c_00 = 0.0, c_10 = 0.0, c_11 = 0.0, c_20 = 0.0, c_21 = 0.0, c_22 = 0.0, c_30 = 0.0, c_31 = 0.0, c_32 = 0.0, c_33 = 0.0, d_20 = 0.0, d_21 = 0.0, d_30 = 0.0, d_31 = 0.0;
  c_00 = fact[0];
  c_11 = fact[2];
  c_22 = fact[5];
  c_33 = fact[9];
  C[0 + bs * 0] = c_00;
  C[1 + bs * 1] = c_11;
  C[2 + bs * 2] = c_22;
  C[3 + bs * 3] = c_33;
  c_10 = fact[1];
  c_32 = fact[8];
  c_10 = -c_11 * c_10 * c_00;
  c_32 = -c_33 * c_32 * c_22;
  C[0 + bs * 1] = c_10;
  C[2 + bs * 3] = c_32;
  c_21 = fact[4];
  c_31 = fact[7];
  c_20 = c_21 * c_10;
  c_30 = c_31 * c_10;
  c_21 = c_21 * c_11;
  c_31 = c_31 * c_11;
  c_20 += fact[3] * c_00;
  c_30 += fact[6] * c_00;
  d_20 = c_22 * c_20;
  d_30 = c_32 * c_20;
  d_21 = c_22 * c_21;
  d_31 = c_32 * c_21;
  d_30 += c_33 * c_30;
  d_31 += c_33 * c_31;
  C[0 + bs * 2] = -d_20;
  C[0 + bs * 3] = -d_30;
  C[1 + bs * 2] = -d_21;
  C[1 + bs * 3] = -d_31;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UARTCharGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xa,%rax
  mov    (%rax),%eax
  and    $0x4000,%eax
  test   %eax,%eax
  je     L13
  nop
L0:
  mov    -0x8(%rbp),%rax
  add    $0xb,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  test   %eax,%eax
  je     L0
  jmp    L6
L13:
  nop
L14:
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  mov    (%rax),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L14
L6:
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  mov    (%rax),%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t UARTCharGet(uint32_t ui32Base) {
  ;
  if ((*((volatile uint16_t *)(ui32Base + 0xA))) & 0x4000) {
    while (!(((*((volatile uint16_t *)(ui32Base + 0xB))) & 0x1F00) >> 8)) {
    }
  } else {
    while (!((*((volatile uint16_t *)(ui32Base + 0x5))) & 0x40)) {
    }
  }
  return ((*((volatile uint16_t *)(ui32Base + 0x7))) & 0xFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UARTCharGet>:
  endbr64
  mov    0xa(%rdi),%eax
  test   $0x40,%ah
  je     L20
L35:
  mov    0xb(%rdi),%eax
  test   $0x1f,%ah
  je     L35
L15:
  mov    0x7(%rdi),%eax
  movzbl %al,%eax
  ret
L20:
  mov    0x5(%rdi),%eax
  test   $0x40,%al
  je     L20
  jmp    L15
```

assistant: ```c
int32_t UARTCharGet(uint32_t ui32Base) {
  ;
  if ((*((volatile uint16_t *)(ui32Base + 0xA))) & 0x4000) {
    while (!(((*((volatile uint16_t *)(ui32Base + 0xB))) & 0x1F00) >> 8)) {
    }
  } else {
    while (!((*((volatile uint16_t *)(ui32Base + 0x5))) & 0x40)) {
    }
  }
  return ((*((volatile uint16_t *)(ui32Base + 0x7))) & 0xFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTCharGet>:
  endbr64
  mov    0xa(%rdi),%eax
  test   $0x40,%ah
  je     L2
  lea    0xb(%rdi),%rdx
L25:
  mov    (%rdx),%eax
  test   $0x1f,%ah
  je     L25
  mov    0x7(%rdi),%eax
  movzbl %al,%eax
  ret
  xchg   %ax,%ax
L2:
  lea    0x5(%rdi),%rdx
  nopl   0x0(%rax)
L15:
  mov    (%rdx),%eax
  test   $0x40,%al
  je     L15
  mov    0x7(%rdi),%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int32_t UARTCharGet(uint32_t ui32Base) {
  ;
  if ((*((volatile uint16_t *)(ui32Base + 0xA))) & 0x4000) {
    while (!(((*((volatile uint16_t *)(ui32Base + 0xB))) & 0x1F00) >> 8)) {
    }
  } else {
    while (!((*((volatile uint16_t *)(ui32Base + 0x5))) & 0x40)) {
    }
  }
  return ((*((volatile uint16_t *)(ui32Base + 0x7))) & 0xFF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UARTCharGet>:
  endbr64
  mov    0xa(%rdi),%eax
  test   $0x40,%ah
  je     L15
  lea    0xb(%rdi),%rdx
L4:
  mov    (%rdx),%eax
  test   $0x1f,%ah
  je     L4
  mov    0x7(%rdi),%eax
  movzbl %al,%eax
  ret
  xchg   %ax,%ax
L15:
  lea    0x5(%rdi),%rdx
  nopl   0x0(%rax)
L25:
  mov    (%rdx),%eax
  test   $0x40,%al
  je     L25
  mov    0x7(%rdi),%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int32_t UARTCharGet(uint32_t ui32Base) {
  ;
  if ((*((volatile uint16_t *)(ui32Base + 0xA))) & 0x4000) {
    while (!(((*((volatile uint16_t *)(ui32Base + 0xB))) & 0x1F00) >> 8)) {
    }
  } else {
    while (!((*((volatile uint16_t *)(ui32Base + 0x5))) & 0x40)) {
    }
  }
  return ((*((volatile uint16_t *)(ui32Base + 0x7))) & 0xFF);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string
name: disassemble_data
arguments: label: D13
type: string

tool: D1: abcd

tool: D13: %s

assistant: ```c
int main(int argc, char **argv) {
  char *s;
  s = malloc(64);
  strcpy(s, "abcd");
  printf("%s", s);
  free(s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string
name: disassemble_data
arguments: data_label: D16
type_infered: string

tool: D1: abcd

tool: D16: %s

assistant: ```c
int main(int argc, char **argv) {
  char *s;
  s = malloc(64);
  strcpy(s, "abcd");
  printf("%s", s);
  free(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x40,%edi
  call   <malloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D18
datatype: string

tool: D5: abcd

tool: D18: %s

assistant: ```c
int main(int argc, char **argv) {
  char *s;
  s = malloc(64);
  strcpy(s, "abcd");
  printf("%s", s);
  free(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x40,%edi
  call   <malloc@plt>
  lea    D11(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
datatype: string
name: disassemble_data
arguments: tag: D19
datatype: string

tool: D11: abcd

tool: D19: %s

assistant: ```c
int main(int argc, char **argv) {
  char *s;
  s = malloc(64);
  strcpy(s, "abcd");
  printf("%s", s);
  free(s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<show_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: fbtest 0.1 -- framebuffer test utility


assistant: ```c
__attribute__((__noreturn__)) void show_version() {
  printf("fbtest 0.1 -- framebuffer test utility\n");
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<show_version>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: fbtest 0.1 -- framebuffer test utility


assistant: ```c
__attribute__((__noreturn__)) void show_version() {
  printf("fbtest 0.1 -- framebuffer test utility\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show_version>:
  endbr64
  push   %rax
  pop    %rax
  lea    D5(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string

tool: D5: fbtest 0.1 -- framebuffer test utility


assistant: ```c
__attribute__((__noreturn__)) void show_version() {
  printf("fbtest 0.1 -- framebuffer test utility\n");
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<show_version>:
  endbr64
  push   %rax
  pop    %rax
  lea    D0(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: fbtest 0.1 -- framebuffer test utility


assistant: ```c
__attribute__((__noreturn__)) void show_version() {
  printf("fbtest 0.1 -- framebuffer test utility\n");
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<endswith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L21
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jne    L21
  mov    $0x1,%eax
  jmp    L27
L21:
  mov    $0x0,%eax
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
bool endswith(const char *input, const char *suffix) {
  const char *hit = strstr(input, suffix);
  return (hit != NULL) && (strlen(hit) == strlen(suffix));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<endswith>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  call   <strstr@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L1
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbp
  sete   %al
  movzbl %al,%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool endswith(const char *input, const char *suffix) {
  const char *hit = strstr(input, suffix);
  return (hit != NULL) && (strlen(hit) == strlen(suffix));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<endswith>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L4
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool endswith(const char *input, const char *suffix) {
  const char *hit = strstr(input, suffix);
  return (hit != NULL) && (strlen(hit) == strlen(suffix));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<endswith>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool endswith(const char *input, const char *suffix) {
  const char *hit = strstr(input, suffix);
  return (hit != NULL) && (strlen(hit) == strlen(suffix));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mm_ivtsign_ps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x80000000,%edi
  call   <_mm_set1_epi32@plt>
  mov    %eax,%edi
  call   <_mm_castsi128_ps@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_ps@plt>
  leave
  ret
```

assistant: ```c
__attribute__((always_)) __m128 mm_ivtsign_ps(const __m128 xmm0) {
  const __m128 mask = _mm_castsi128_ps(_mm_set1_epi32(0x80000000));
  return _mm_xor_ps(xmm0, mask);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mm_ivtsign_ps>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x80000000,%edi
  call   <_mm_set1_epi32@plt>
  mov    %eax,%edi
  call   <_mm_castsi128_ps@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <_mm_xor_ps@plt>
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) __m128 mm_ivtsign_ps(const __m128 xmm0) {
  const __m128 mask = _mm_castsi128_ps(_mm_set1_epi32(0x80000000));
  return _mm_xor_ps(xmm0, mask);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mm_ivtsign_ps>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x80000000,%edi
  call   <_mm_set1_epi32@plt>
  mov    %eax,%edi
  call   <_mm_castsi128_ps@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <_mm_xor_ps@plt>
```

assistant: ```c
__attribute__((always_)) __m128 mm_ivtsign_ps(const __m128 xmm0) {
  const __m128 mask = _mm_castsi128_ps(_mm_set1_epi32(0x80000000));
  return _mm_xor_ps(xmm0, mask);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mm_ivtsign_ps>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x80000000,%edi
  call   <_mm_set1_epi32@plt>
  mov    %eax,%edi
  call   <_mm_castsi128_ps@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <_mm_xor_ps@plt>
```

assistant: ```c
__attribute__((always_)) __m128 mm_ivtsign_ps(const __m128 xmm0) {
  const __m128 mask = _mm_castsi128_ps(_mm_set1_epi32(0x80000000));
  return _mm_xor_ps(xmm0, mask);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<picAssert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <reportError@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void picAssert(uint8_t test, const char *message) {
  if (!test)
    reportError(message);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<picAssert>:
  endbr64
  test   %edi,%edi
  je     L7
  ret
L7:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <reportError@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void picAssert(uint8_t test, const char *message) {
  if (!test)
    reportError(message);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<picAssert>:
  endbr64
  test   %edi,%edi
  je     L0
  ret
  nopl   0x0(%rax)
L0:
  mov    %rsi,%rdi
  jmp    1050 <reportError@plt>
```

assistant: ```c
void picAssert(uint8_t test, const char *message) {
  if (!test)
    reportError(message);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<picAssert>:
  endbr64
  test   %edi,%edi
  je     L9
  ret
  nopl   0x0(%rax)
L9:
  mov    %rsi,%rdi
  jmp    1050 <reportError@plt>
```

assistant: ```c
void picAssert(uint8_t test, const char *message) {
  if (!test)
    reportError(message);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L92:
  cmp    %rcx,%rsp
  je     L88
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L92
L88:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L100
  orq    $0x0,-0x8(%rsp,%rax,1)
L100:
  mov    %rsp,%r14
  test   %edx,%edx
  jle    L79
  mov    %r14,%r12
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
L20:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x30(%rbp)
  jg     L20
L79:
  lea    -0x2c(%rbp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x4(%r14),%r12
  mov    $0x0,%ebx
  lea    D39(%rip),%r13
  cmp    %edx,-0x30(%rbp)
  jge    L37
L106:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L37:
  add    %ebx,%eax
  mov    $0x0,%esi
  cmp    %ebx,%eax
  jle    L41
  sub    %ebx,%eax
  lea    -0x1(%rax),%eax
  add    %rbx,%rax
  lea    (%r14,%rax,4),%rdx
  mov    %r12,%rax
  mov    $0x0,%esi
L16:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L16
L41:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  add    $0x1,%rbx
  add    $0x4,%r12
  lea    -0x1(%rax),%ecx
  mov    -0x30(%rbp),%edx
  sub    %ecx,%edx
  cmp    %ebx,%edx
  jl     L106
  jmp    L37
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D39
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string

tool: D39: %d


tool: D9: %d

assistant: ```c
int main() {
  int n;
  scanf("%d\n", &n);
  int A[n];
  for (int i = 0; i <= n - 1; i++) {
    scanf("%d", &A[i]);
  }
  int k;
  scanf("%d\n", &k);
  for (int a = 0; a <= n - (k - 1); a++) {
    int sum;
    sum = 0;
    for (int b = a; b <= k + a - 1; b++) {
      for (int c = 1; c <= 1; c++)
        sum = sum + A[(b - 1)];
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x40(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x40(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L22
L63:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L63
L22:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L15
L98:
  mov    %rsp,%r12
  test   %edx,%edx
  jle    L65
  mov    %r12,%r14
  xor    %r13d,%r13d
  lea    D18(%rip),%r15
  nopl   0x0(%rax)
L37:
  mov    %r14,%rsi
  mov    %r15,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  cmp    %r13d,-0x40(%rbp)
  jg     L37
L65:
  lea    -0x3c(%rbp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  lea    -0x1(%rax),%edx
  cmp    %edx,-0x40(%rbp)
  jl     L8
  lea    -0x4(%r12),%r14
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L38:
  add    %r13d,%eax
  xor    %esi,%esi
  cmp    %r13d,%eax
  jle    L106
  sub    %r13d,%eax
  xor    %esi,%esi
  sub    $0x1,%eax
  add    %r13,%rax
  lea    (%r12,%rax,4),%rdx
  mov    %r14,%rax
  nopl   0x0(%rax)
L41:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L41
L106:
  mov    %rbx,%rdi
  add    $0x1,%r13
  add    $0x4,%r14
  call   <printf@plt>
  mov    -0x3c(%rbp),%eax
  mov    -0x40(%rbp),%edx
  lea    -0x1(%rax),%ecx
  sub    %ecx,%edx
  cmp    %r13d,%edx
  jge    L38
L8:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L15:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L98
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D18
type: string

tool: D4: %d


tool: D18: %d

assistant: ```c
int main() {
  int n;
  scanf("%d\n", &n);
  int A[n];
  for (int i = 0; i <= n - 1; i++) {
    scanf("%d", &A[i]);
  }
  int k;
  scanf("%d\n", &k);
  for (int a = 0; a <= n - (k - 1); a++) {
    int sum;
    sum = 0;
    for (int b = a; b <= k + a - 1; b++) {
      for (int c = 1; c <= 1; c++)
        sum = sum + A[(b - 1)];
    }
    printf("%d\n", sum);
  }
  return 0;
}
```