ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<check_executed_fifo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %rdi,%r12
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r14d
  mov    $0x0,%r15d
  lea    0x20(%rsp),%rbp
  lea    0x13(%rsp),%r13
  jmp    L72
L4:
  cmp    %r15,0x18(%rsp)
  jne    L25
L45:
  add    $0x1,%r14d
L72:
  mov    %r12,%rdi
  call   <feof@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L63
  mov    %r12,%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  lea    0x14(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %r13,%r8
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  cmp    $0x3,%eax
  jne    L47
  test   %r15,%r15
  jne    L4
  mov    0x18(%rsp),%r15
  jmp    L45
L47:
  lea    0x18(%rsp),%rdx
  mov    %r13,%rcx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L72
  cmp    0xc(%rsp),%r14d
  jne    L25
  mov    %ebx,%r14d
  mov    $0x0,%r15d
  jmp    L72
L63:
  mov    $0x1,%ebx
L25:
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    %ebx,%eax
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D15: Thread %lu: loop %i%c

tool: D5: Thread %lu: exiting%c

assistant: ```c
int check_executed_fifo(FILE *in, int num_threads, int num_iterations) {
  char buf[1024];
  unsigned long prev_thread = 0;
  int counter = 0;
  while (!feof(in)) {
    unsigned long thread_id;
    int iter;
    char nl;
    fgets(buf, 1024, in);
    if (sscanf(buf, "Thread %lu: loop %i%c", &thread_id, &iter, &nl) == 3) {
      if (prev_thread == 0)
        prev_thread = thread_id;
      else if (prev_thread != thread_id)
        return 0;
      counter++;
    } else if (sscanf(buf, "Thread %lu: exiting%c", &thread_id, &nl) == 2) {
      if (counter != num_iterations)
        return 0;
      prev_thread = 0;
      counter = 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_executed_fifo>:
  endbr64
  push   %r15
  lea    D1(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x20(%rsp),%rbx
  lea    0x13(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movq   $0x0,(%rsp)
L85:
  mov    %rbp,%rdi
  call   <feof@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L16
L68:
  mov    %rbp,%rdx
  mov    $0x400,%esi
  lea    0x18(%rsp),%r14
  mov    %rbx,%rdi
  call   <fgets@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  mov    %r13,%r8
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  jne    L19
  mov    (%rsp),%rdx
  mov    0x18(%rsp),%rax
  test   %rdx,%rdx
  je     L69
  cmp    %rax,%rdx
  jne    L56
L69:
  mov    %rbp,%rdi
  addl   $0x1,0x8(%rsp)
  mov    %rax,(%rsp)
  call   <feof@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L68
L16:
  mov    $0x1,%r12d
L56:
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x438,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbx,%rdi
  lea    D14(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L85
  mov    0xc(%rsp),%ecx
  cmp    %ecx,0x8(%rsp)
  jne    L56
  movl   $0x0,0x8(%rsp)
  movq   $0x0,(%rsp)
  jmp    L85
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string
name: parse_data
arguments: data_label: D14
type: string

tool: D1: Thread %lu: loop %i%c

tool: D14: Thread %lu: exiting%c

assistant: ```c
int check_executed_fifo(FILE *in, int num_threads, int num_iterations) {
  char buf[1024];
  unsigned long prev_thread = 0;
  int counter = 0;
  while (!feof(in)) {
    unsigned long thread_id;
    int iter;
    char nl;
    fgets(buf, 1024, in);
    if (sscanf(buf, "Thread %lu: loop %i%c", &thread_id, &iter, &nl) == 3) {
      if (prev_thread == 0)
        prev_thread = thread_id;
      else if (prev_thread != thread_id)
        return 0;
      counter++;
    } else if (sscanf(buf, "Thread %lu: exiting%c", &thread_id, &nl) == 2) {
      if (counter != num_iterations)
        return 0;
      prev_thread = 0;
      counter = 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_executed_fifo>:
  endbr64
  push   %r15
  lea    D6(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x20(%rsp),%rbx
  lea    0x13(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movq   $0x0,(%rsp)
L47:
  mov    %rbp,%rdi
  call   <feof@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L41
L43:
  mov    %rbp,%rdx
  mov    $0x400,%esi
  lea    0x18(%rsp),%r14
  mov    %rbx,%rdi
  call   <fgets@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  mov    %r13,%r8
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  jne    L71
  mov    (%rsp),%rdx
  mov    0x18(%rsp),%rax
  test   %rdx,%rdx
  je     L0
  cmp    %rax,%rdx
  jne    L10
L0:
  mov    %rbp,%rdi
  addl   $0x1,0x8(%rsp)
  mov    %rax,(%rsp)
  call   <feof@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L43
L41:
  mov    $0x1,%r12d
L10:
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x438,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbx,%rdi
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L47
  mov    0xc(%rsp),%ecx
  cmp    %ecx,0x8(%rsp)
  jne    L10
  movl   $0x0,0x8(%rsp)
  movq   $0x0,(%rsp)
  jmp    L47
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D6: Thread %lu: loop %i%c

tool: D2: Thread %lu: exiting%c

assistant: ```c
int check_executed_fifo(FILE *in, int num_threads, int num_iterations) {
  char buf[1024];
  unsigned long prev_thread = 0;
  int counter = 0;
  while (!feof(in)) {
    unsigned long thread_id;
    int iter;
    char nl;
    fgets(buf, 1024, in);
    if (sscanf(buf, "Thread %lu: loop %i%c", &thread_id, &iter, &nl) == 3) {
      if (prev_thread == 0)
        prev_thread = thread_id;
      else if (prev_thread != thread_id)
        return 0;
      counter++;
    } else if (sscanf(buf, "Thread %lu: exiting%c", &thread_id, &nl) == 2) {
      if (counter != num_iterations)
        return 0;
      prev_thread = 0;
      counter = 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  shr    $0x3,%eax
  or     $0x61bab5,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%ecx
  test   %ecx,%ecx
  je     L34
  mov    $0x0,%eax
  lea    0x4(%rsp),%rsi
  jmp    L58
L59:
  mov    %eax,%edx
  lea    (%rsi,%rdx,4),%rdx
  movzbl 0x2(%rdx),%edi
  movzbl 0x3(%rdx),%r8d
  mov    %r8b,0x2(%rdx)
  mov    %dil,0x3(%rdx)
L27:
  add    $0x2,%eax
  cmp    %eax,%ecx
  jbe    L34
L58:
  cmp    %eax,0x4(%rsp)
  jbe    L59
  mov    %eax,%edx
  lea    (%rsi,%rdx,4),%rdx
  movzbl 0x1(%rdx),%edi
  movzbl 0x2(%rdx),%r8d
  mov    %r8b,0x1(%rdx)
  movzbl (%rdx),%r8d
  mov    %r8b,0x2(%rdx)
  mov    %dil,(%rdx)
  jmp    L27
L34:
  mov    0x4(%rsp),%eax
  shr    $0x5,%rax
  and    $0x710ed6,%eax
  mov    %eax,(%r9)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x18,%rsp
  ret
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  char copy12;
  char copy13;
  char copy14;
  char copy15;
  char copy18;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy11;
          copy11 = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy12;
          copy12 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy13;
          copy14 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy14;
        }
      } else if (state[0UL] <= local1) {
        copy15 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy15;
      } else {
        copy18 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy18;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 237099718UL) >> 5U;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%ecx
  mov    0x4(%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  shr    $0x3,%ecx
  or     $0x61bab5,%ecx
  mov    %ecx,0x4(%rsp)
  test   %edi,%edi
  je     L36
  lea    0x4(%rsp),%r8
  jmp    L29
  nopl   (%rax)
L12:
  movzwl 0x1(%rdx),%ecx
  movzbl (%rdx),%r9d
  add    $0x2,%eax
  mov    %r9b,0x2(%rdx)
  mov    %cx,(%rdx)
  mov    0x4(%rsp),%ecx
  cmp    %edi,%eax
  jae    L36
L29:
  mov    %eax,%edx
  lea    (%r8,%rdx,4),%rdx
  cmp    %ecx,%eax
  jb     L12
  add    $0x2,%eax
  rolw   $0x8,0x2(%rdx)
  mov    0x4(%rsp),%ecx
  cmp    %edi,%eax
  jb     L29
L36:
  shr    $0x5,%ecx
  and    $0x710ed6,%ecx
  mov    %ecx,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x18,%rsp
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  char copy12;
  char copy13;
  char copy14;
  char copy15;
  char copy18;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy11;
          copy11 = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy12;
          copy12 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy13;
          copy14 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy14;
        }
      } else if (state[0UL] <= local1) {
        copy15 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy15;
      } else {
        copy18 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy18;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 237099718UL) >> 5U;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%ecx
  mov    0x4(%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  shr    $0x3,%ecx
  or     $0x61bab5,%ecx
  mov    %ecx,0x4(%rsp)
  test   %edi,%edi
  je     L29
  lea    0x4(%rsp),%r8
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %eax,%edx
  lea    (%r8,%rdx,4),%rdx
  cmp    %ecx,%eax
  jae    L24
  movzwl 0x1(%rdx),%ecx
  movzbl (%rdx),%r9d
  add    $0x2,%eax
  mov    %r9b,0x2(%rdx)
  mov    %cx,(%rdx)
  mov    0x4(%rsp),%ecx
  cmp    %eax,%edi
  ja     L18
L29:
  shr    $0x5,%ecx
  and    $0x710ed6,%ecx
  mov    %ecx,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L24:
  add    $0x2,%eax
  rolw   $0x8,0x2(%rdx)
  mov    0x4(%rsp),%ecx
  cmp    %edi,%eax
  jb     L18
  jmp    L29
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  char copy12;
  char copy13;
  char copy14;
  char copy15;
  char copy18;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy11;
          copy11 = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy12;
          copy12 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy13;
          copy14 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy14;
        }
      } else if (state[0UL] <= local1) {
        copy15 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy15;
      } else {
        copy18 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy18;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 237099718UL) >> 5U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fild_preg32_qword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0xdf,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  add    $0x28,%eax
  mov    %eax,%edi
  call   <put8@plt>
  nop
  leave
  ret
```

assistant: ```c
void fild_preg32_qword(int reg32) {
  put8(0xDF);
  put8(0x28 + reg32);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fild_preg32_qword>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xdf,%edi
  call   <put8@plt>
  lea    0x28(%rbx),%edi
  call   <put8@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fild_preg32_qword(int reg32) {
  put8(0xDF);
  put8(0x28 + reg32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fild_preg32_qword>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xdf,%edi
  call   <put8@plt>
  lea    0x28(%rbx),%edi
  pop    %rbx
  jmp    1050 <put8@plt>
```

assistant: ```c
void fild_preg32_qword(int reg32) {
  put8(0xDF);
  put8(0x28 + reg32);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fild_preg32_qword>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xdf,%edi
  call   <put8@plt>
  lea    0x28(%rbx),%edi
  pop    %rbx
  jmp    1050 <put8@plt>
```

assistant: ```c
void fild_preg32_qword(int reg32) {
  put8(0xDF);
  put8(0x28 + reg32);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L3:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *destination, const char *source) {
  char *ret = destination;
  while (*destination++ = *source++)
    ;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L8:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *strcpy(char *destination, const char *source) {
  char *ret = destination;
  while (*destination++ = *source++)
    ;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L8:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *strcpy(char *destination, const char *source) {
  char *ret = destination;
  while (*destination++ = *source++)
    ;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L8:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *strcpy(char *destination, const char *source) {
  char *ret = destination;
  while (*destination++ = *source++)
    ;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parse_owner>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L54
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_gid@plt>
  jmp    L51
L54:
  cmpq   $0x0,-0x28(%rbp)
  jne    L2
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_uid@plt>
  jmp    L51
L2:
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_gid@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L26
  mov    -0xc(%rbp),%eax
  jmp    L51
L26:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_uid@plt>
L51:
  leave
  ret
```

assistant: ```c
int parse_owner(char *str, uid_t *uid, gid_t *gid) {
  int r = 0;
  char *group;
  if (!uid)
    return parse_gid(str, gid);
  if (!gid)
    return parse_uid(str, uid);
  group = strchr(str, ':');
  *group++ = 0;
  r = parse_gid(group, gid);
  if (r)
    return r;
  return parse_uid(str, uid);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_owner>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  test   %rsi,%rsi
  je     L36
  mov    %rsi,%rbx
  test   %rdx,%rdx
  je     L59
  mov    $0x3a,%esi
  call   <strchr@plt>
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  mov    %r12,%rsi
  call   <parse_gid@plt>
  test   %eax,%eax
  je     L45
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    %rdx,%rsi
  call   <parse_gid@plt>
  jmp    L13
L59:
  call   <parse_uid@plt>
  jmp    L13
L45:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <parse_uid@plt>
  jmp    L13
```

assistant: ```c
int parse_owner(char *str, uid_t *uid, gid_t *gid) {
  int r = 0;
  char *group;
  if (!uid)
    return parse_gid(str, gid);
  if (!gid)
    return parse_uid(str, uid);
  group = strchr(str, ':');
  *group++ = 0;
  r = parse_gid(group, gid);
  if (r)
    return r;
  return parse_uid(str, uid);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_owner>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  test   %rsi,%rsi
  je     L21
  mov    %rsi,%r12
  test   %rdx,%rdx
  je     L11
  mov    $0x3a,%esi
  call   <strchr@plt>
  mov    %rbp,%rsi
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <parse_gid@plt>
  test   %eax,%eax
  je     L11
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L11:
  pop    %rbp
  mov    %r12,%rsi
  mov    %r13,%rdi
  pop    %r12
  pop    %r13
  jmp    1090 <parse_uid@plt>
L21:
  pop    %rbp
  mov    %rdx,%rsi
  pop    %r12
  pop    %r13
  jmp    1070 <parse_gid@plt>
```

assistant: ```c
int parse_owner(char *str, uid_t *uid, gid_t *gid) {
  int r = 0;
  char *group;
  if (!uid)
    return parse_gid(str, gid);
  if (!gid)
    return parse_uid(str, uid);
  group = strchr(str, ':');
  *group++ = 0;
  r = parse_gid(group, gid);
  if (r)
    return r;
  return parse_uid(str, uid);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_owner>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  test   %rsi,%rsi
  je     L18
  mov    %rsi,%r12
  test   %rdx,%rdx
  je     L13
  mov    $0x3a,%esi
  call   <strchr@plt>
  mov    %rbp,%rsi
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <parse_gid@plt>
  test   %eax,%eax
  je     L13
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L13:
  pop    %rbp
  mov    %r12,%rsi
  mov    %r13,%rdi
  pop    %r12
  pop    %r13
  jmp    1090 <parse_uid@plt>
L18:
  pop    %rbp
  mov    %rdx,%rsi
  pop    %r12
  pop    %r13
  jmp    1070 <parse_gid@plt>
```

assistant: ```c
int parse_owner(char *str, uid_t *uid, gid_t *gid) {
  int r = 0;
  char *group;
  if (!uid)
    return parse_gid(str, gid);
  if (!gid)
    return parse_uid(str, uid);
  group = strchr(str, ':');
  *group++ = 0;
  r = parse_gid(group, gid);
  if (r)
    return r;
  return parse_uid(str, uid);
}
```