ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<fourier_coef_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L5
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x38(%rbp),%rcx
  mov    -0x18(%rbp),%edx
  mov    %rcx,%rsi
  mov    %edx,%edi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fourier_coef@plt>
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void fourier_coef_array(int n, double *ca, double *sa, double *vals, int m, double *coefs) {
  for (int i = 0; i < m; i++) {
    coefs[i] = 0;
  }
  for (int i = 0; i < n; i++) {
    fourier_coef(ca[i], sa[i], vals[i], m, coefs);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fourier_coef_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%r15
  mov    %r8d,%ebp
  mov    %r9,%r12
  test   %r8d,%r8d
  jle    L0
  mov    %r9,%rax
  lea    -0x1(%r8),%edx
  lea    0x8(%r9,%rdx,8),%rdx
L39:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L39
L0:
  test   %edi,%edi
  jle    L20
  mov    %edi,%eax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%ebx
L14:
  movsd  0x0(%r13,%rbx,8),%xmm0
  mov    %r12,%rsi
  mov    %ebp,%edi
  movsd  (%r15,%rbx,8),%xmm2
  movsd  (%r14,%rbx,8),%xmm1
  call   <fourier_coef@plt>
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L14
L20:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void fourier_coef_array(int n, double *ca, double *sa, double *vals, int m, double *coefs) {
  for (int i = 0; i < m; i++) {
    coefs[i] = 0;
  }
  for (int i = 0; i < n; i++) {
    fourier_coef(ca[i], sa[i], vals[i], m, coefs);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fourier_coef_array>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  test   %r8d,%r8d
  jle    L21
  movslq %r8d,%rdx
  xor    %esi,%esi
  mov    %r9,%rdi
  shl    $0x3,%rdx
  call   <memset@plt>
L21:
  test   %ebx,%ebx
  jle    L0
  movslq %ebx,%rax
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L13:
  movsd  0x0(%r13,%rbx,8),%xmm0
  movsd  (%r15,%rbx,8),%xmm2
  mov    %r12,%rsi
  mov    %ebp,%edi
  movsd  (%r14,%rbx,8),%xmm1
  add    $0x1,%rbx
  call   <fourier_coef@plt>
  cmp    %rbx,0x8(%rsp)
  jne    L13
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void fourier_coef_array(int n, double *ca, double *sa, double *vals, int m, double *coefs) {
  for (int i = 0; i < m; i++) {
    coefs[i] = 0;
  }
  for (int i = 0; i < n; i++) {
    fourier_coef(ca[i], sa[i], vals[i], m, coefs);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fourier_coef_array>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  test   %r8d,%r8d
  jle    L6
  movslq %r8d,%rdx
  xor    %esi,%esi
  mov    %r9,%rdi
  shl    $0x3,%rdx
  call   <memset@plt>
L6:
  test   %ebx,%ebx
  jle    L24
  movslq %ebx,%rax
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L15:
  movsd  0x0(%r13,%rbx,8),%xmm0
  movsd  (%r15,%rbx,8),%xmm2
  mov    %r12,%rsi
  mov    %ebp,%edi
  movsd  (%r14,%rbx,8),%xmm1
  add    $0x1,%rbx
  call   <fourier_coef@plt>
  cmp    %rbx,0x8(%rsp)
  jne    L15
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void fourier_coef_array(int n, double *ca, double *sa, double *vals, int m, double *coefs) {
  for (int i = 0; i < m; i++) {
    coefs[i] = 0;
  }
  for (int i = 0; i < n; i++) {
    fourier_coef(ca[i], sa[i], vals[i], m, coefs);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_boolean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x12(%rbp)
  lea    -0x12(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D14(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  movl   $0x1,-0x18(%rbp)
  lea    -0x12(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L20
  lea    -0x12(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L20
  lea    -0x12(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L30
L20:
  movl   $0x0,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
data_type: string
name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D11
data_type: string
name: parse_data
arguments: tag: D8
data_type: string

tool: D14:  %10s

tool: D9: 0

tool: D11: no

tool: D8: false

assistant: ```c
int read_boolean(s)
char *s;
{
  char p[10];
  int result;
  p[0] = '\0';
  sscanf(s, " %10s", p);
  result = 1;
  if ((strcmp(p, "0") == 0) || (strcmp(p, "no") == 0) || (strcmp(p, "false") == 0)) {
    result = 0;
  };
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_boolean>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0xe(%rsp)
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rdx
  lea    D11(%rip),%rsi
  call   <sscanf@plt>
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L25
  mov    %rbx,%rdi
  lea    D32(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L25
  mov    %rbx,%rdi
  lea    D36(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L25:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x20,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D6
type: string
name: parse_data
arguments: data_label: D32
type: string
name: parse_data
arguments: data_label: D36
type: string

tool: D11:  %10s

tool: D6: 0

tool: D32: no

tool: D36: false

assistant: ```c
int read_boolean(s)
char *s;
{
  char p[10];
  int result;
  p[0] = '\0';
  sscanf(s, " %10s", p);
  result = 1;
  if ((strcmp(p, "0") == 0) || (strcmp(p, "no") == 0) || (strcmp(p, "false") == 0)) {
    result = 0;
  };
  return (result);
}
```
user: What is the c source code of the assembly code below:

```asm
<read_boolean>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  movb   $0x0,0xe(%rsp)
  mov    %rbp,%rdx
  call   <sscanf@plt>
  cmpb   $0x30,0xe(%rsp)
  jne    L52
  movzbl 0xf(%rsp),%eax
  test   %eax,%eax
  jne    L52
L36:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  cmpb   $0x6e,0xe(%rsp)
  je     L78
L34:
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L36
L78:
  cmpb   $0x6f,0xf(%rsp)
  jne    L34
  movzbl 0x10(%rsp),%eax
  test   %eax,%eax
  je     L36
  jmp    L34
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D1:  %10s

tool: D6: false

assistant: ```c
int read_boolean(s)
char *s;
{
  char p[10];
  int result;
  p[0] = '\0';
  sscanf(s, " %10s", p);
  result = 1;
  if ((strcmp(p, "0") == 0) || (strcmp(p, "no") == 0) || (strcmp(p, "false") == 0)) {
    result = 0;
  };
  return (result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_boolean>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  movb   $0x0,0xe(%rsp)
  mov    %rbp,%rdx
  call   <sscanf@plt>
  cmpb   $0x30,0xe(%rsp)
  jne    L18
  movzbl 0xf(%rsp),%eax
  test   %eax,%eax
  jne    L18
L11:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  cmpb   $0x6e,0xe(%rsp)
  je     L32
L77:
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L11
L32:
  cmpb   $0x6f,0xf(%rsp)
  jne    L77
  movzbl 0x10(%rsp),%eax
  test   %eax,%eax
  je     L11
  jmp    L77
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string

tool: D12:  %10s

tool: D6: false

assistant: ```c
int read_boolean(s)
char *s;
{
  char p[10];
  int result;
  p[0] = '\0';
  sscanf(s, " %10s", p);
  result = 1;
  if ((strcmp(p, "0") == 0) || (strcmp(p, "no") == 0) || (strcmp(p, "false") == 0)) {
    result = 0;
  };
  return (result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x9,%r12d
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L145:
  mov    %r13d,%r15d
  mov    $0x3,%ebp
  add    $0x1,%r13d
  nopl   0x0(%rax)
L9:
  mov    %r14d,%eax
  add    $0x1,%r14d
  lea    0x3(%rax),%r8d
  sub    $0x2,%eax
  and    $0xfffffffd,%eax
  je     L3
  test   $0x1,%r14b
  je     L25
  imul   $0xaaaaaaab,%r14d,%eax
  cmp    $0x55555555,%eax
  jbe    L25
  test   $0x3,%r14b
  je     L25
  imul   $0xcccccccd,%r14d,%edx
  cmp    $0x33333333,%edx
  jbe    L25
  ror    %eax
  cmp    $0x2aaaaaaa,%eax
  jbe    L25
  imul   $0xb6db6db7,%r14d,%eax
  cmp    $0x24924924,%eax
  jbe    L25
  test   $0x7,%r14b
  je     L25
  mov    %r14d,%eax
  cltd
  idiv   %r12d
  test   %edx,%edx
  je     L25
  mov    %r8d,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  je     L25
  test   $0x3,%r8b
  je     L25
  mov    %r8d,%eax
  mov    $0x5,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L25
  mov    %r8d,%eax
  mov    $0x6,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L25
  mov    %r8d,%eax
  mov    $0x7,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L25
  test   $0x7,%r8b
  je     L25
  mov    %r8d,%eax
  cltd
  idiv   %r12d
  test   %edx,%edx
  je     L25
  mov    %r8d,%edx
  mov    %r14d,%esi
  lea    D1(%rip),%rdi
  add    $0x1,%r15d
  call   <printf@plt>
L25:
  cmp    %r13d,%r15d
  jne    L9
L24:
  cmp    $0xa,%r15d
  jne    L145
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  add    $0x1,%r15d
  mov    %r8d,%edx
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    %r13d,%r15d
  jne    L9
  jmp    L24
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D14: (%d , %d)


tool: D1: (%d, %d)


assistant: ```c
int main() {
  int fp, sp, i, n;
  i = 0;
  n = 0;
  fp = 1;
  sp = 1;
  while (i < 10) {
    n++;
    while (i != n) {
      fp++;
      sp = fp + 2;
      if (fp == 3 || fp == 5) {
        i++;
        printf("(%d , %d)\n", fp, sp);
      } else {
        if (fp % 2 != 0 && fp % 3 != 0 && fp % 4 != 0 && fp % 5 != 0 && fp % 6 != 0 && fp % 7 != 0 && fp % 8 != 0 && fp % 9 != 0 && sp % 2 != 0 && sp % 3 != 0 && sp % 4 != 0 && sp % 5 != 0 && sp % 6 != 0 && sp % 7 != 0 && sp % 8 != 0 && sp % 9 != 0) {
          i++;
          printf("(%d, %d)\n", fp, sp);
        }
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x9,%r12d
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L111:
  mov    %r13d,%r15d
  mov    $0x3,%ebp
  add    $0x1,%r13d
  nopl   0x0(%rax)
L178:
  mov    %r14d,%eax
  add    $0x1,%r14d
  lea    0x3(%rax),%r8d
  sub    $0x2,%eax
  and    $0xfffffffd,%eax
  je     L83
  test   $0x1,%r14b
  je     L103
  imul   $0xaaaaaaab,%r14d,%eax
  cmp    $0x55555555,%eax
  jbe    L103
  test   $0x3,%r14b
  je     L103
  imul   $0xcccccccd,%r14d,%edx
  cmp    $0x33333333,%edx
  jbe    L103
  ror    %eax
  cmp    $0x2aaaaaaa,%eax
  jbe    L103
  imul   $0xb6db6db7,%r14d,%eax
  cmp    $0x24924924,%eax
  jbe    L103
  test   $0x7,%r14b
  je     L103
  mov    %r14d,%eax
  cltd
  idiv   %r12d
  test   %edx,%edx
  je     L103
  mov    %r8d,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  je     L103
  test   $0x3,%r8b
  je     L103
  mov    %r8d,%eax
  mov    $0x5,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L103
  mov    %r8d,%eax
  mov    $0x6,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L103
  mov    %r8d,%eax
  mov    $0x7,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L103
  test   $0x7,%r8b
  je     L103
  mov    %r8d,%eax
  cltd
  idiv   %r12d
  test   %edx,%edx
  je     L103
  mov    %r8d,%edx
  mov    %r14d,%esi
  lea    D13(%rip),%rdi
  add    $0x1,%r15d
  call   <printf@plt>
L103:
  cmp    %r13d,%r15d
  jne    L178
L80:
  cmp    $0xa,%r15d
  jne    L111
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L83:
  add    $0x1,%r15d
  mov    %r8d,%edx
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    %r13d,%r15d
  jne    L178
  jmp    L80
```

tool_calls: name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D15: (%d , %d)


tool: D13: (%d, %d)


assistant: ```c
int main() {
  int fp, sp, i, n;
  i = 0;
  n = 0;
  fp = 1;
  sp = 1;
  while (i < 10) {
    n++;
    while (i != n) {
      fp++;
      sp = fp + 2;
      if (fp == 3 || fp == 5) {
        i++;
        printf("(%d , %d)\n", fp, sp);
      } else {
        if (fp % 2 != 0 && fp % 3 != 0 && fp % 4 != 0 && fp % 5 != 0 && fp % 6 != 0 && fp % 7 != 0 && fp % 8 != 0 && fp % 9 != 0 && sp % 2 != 0 && sp % 3 != 0 && sp % 4 != 0 && sp % 5 != 0 && sp % 6 != 0 && sp % 7 != 0 && sp % 8 != 0 && sp % 9 != 0) {
          i++;
          printf("(%d, %d)\n", fp, sp);
        }
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L77:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L30
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x8(%rbp)
L36:
  cmpl   $0x0,-0x8(%rbp)
  jns    L77
  jmp    L61
L30:
  nop
  jmp    L61
L45:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L50
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L61:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  jmp    L24
L50:
  nop
L24:
  leave
  ret
```

assistant: ```c
void str_trim(char **s) {
  int i;
  int len = strlen(*s);
  for (i = len - 1; i >= 0; i--)
    if ((*s)[i] <= ' ')
      (*s)[i] = 0;
    else
      break;
  while (**s)
    if (**s <= ' ')
      (*s)++;
    else
      return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L34
  movslq %edx,%rdx
  movslq %eax,%rcx
  sub    $0x2,%rcx
  lea    -0x1(%rax),%eax
  sub    %rax,%rcx
L25:
  mov    %rdx,%rax
  add    (%rbx),%rax
  cmpb   $0x20,(%rax)
  jg     L34
  movb   $0x0,(%rax)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L25
L34:
  mov    (%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jg     L59
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%dl
  je     L59
L38:
  mov    %rax,(%rbx)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jg     L59
  test   %dl,%dl
  jne    L38
L59:
  pop    %rbx
  ret
```

assistant: ```c
void str_trim(char **s) {
  int i;
  int len = strlen(*s);
  for (i = len - 1; i >= 0; i--)
    if ((*s)[i] <= ' ')
      (*s)[i] = 0;
    else
      break;
  while (**s)
    if (**s <= ' ')
      (*s)++;
    else
      return;
}
```
user: What is the c source code of the assembly code below?

```asm
<str_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L85
  movslq %eax,%rsi
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  sub    $0x2,%rsi
  sub    %rcx,%rsi
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L95:
  sub    $0x1,%rdx
  movb   $0x0,(%rcx)
  cmp    %rdx,%rsi
  je     L85
L55:
  mov    (%rbx),%rax
  lea    (%rax,%rdx,1),%rcx
  cmpb   $0x20,(%rcx)
  jle    L95
L93:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jg     L60
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%dl
  jne    L47
  jmp    L60
  nop
L50:
  test   %dl,%dl
  je     L60
L47:
  mov    %rax,(%rbx)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jle    L50
L60:
  pop    %rbx
  ret
  nopl   (%rax)
L85:
  mov    (%rbx),%rax
  jmp    L93
```

assistant: ```c
void str_trim(char **s) {
  int i;
  int len = strlen(*s);
  for (i = len - 1; i >= 0; i--)
    if ((*s)[i] <= ' ')
      (*s)[i] = 0;
    else
      break;
  while (**s)
    if (**s <= ' ')
      (*s)++;
    else
      return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L38
  movslq %eax,%rsi
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  sub    $0x2,%rsi
  sub    %rcx,%rsi
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L3:
  sub    $0x1,%rdx
  movb   $0x0,(%rcx)
  cmp    %rdx,%rsi
  je     L38
L20:
  mov    (%rbx),%rax
  lea    (%rax,%rdx,1),%rcx
  cmpb   $0x20,(%rcx)
  jle    L3
L55:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jg     L94
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%dl
  jne    L13
  jmp    L94
  nop
L18:
  test   %dl,%dl
  je     L94
L13:
  mov    %rax,(%rbx)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jle    L18
L94:
  pop    %rbx
  ret
  nopl   (%rax)
L38:
  mov    (%rbx),%rax
  jmp    L55
```

assistant: ```c
void str_trim(char **s) {
  int i;
  int len = strlen(*s);
  for (i = len - 1; i >= 0; i--)
    if ((*s)[i] <= ' ')
      (*s)[i] = 0;
    else
      break;
  while (**s)
    if (**s <= ' ')
      (*s)++;
    else
      return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L26:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L26
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D16
type_infered: string

tool: D13: %d

tool: D16: %d %d %d


assistant: ```c
int main() {
  int times_swap;
  int count;
  int a, b, c;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &times_swap);
  for (count = 0; count < times_swap; count++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d\n", a, b, c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L3
  mov    $0x0,%ebx
  lea    0x14(%rsp),%rbp
L5:
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rdx
  call   <rotr@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jg     L5
L3:
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D17
type_guessed: string

tool: D11: %d

tool: D17: %d %d %d


assistant: ```c
int main() {
  int times_swap;
  int count;
  int a, b, c;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &times_swap);
  for (count = 0; count < times_swap; count++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d\n", a, b, c);
  return 0;
}
```