user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1dc(%rbp)
  movq   $0x0,-0x1d0(%rbp)
  movq   $0x0,-0x1c8(%rbp)
  movq   $0x0,-0x1c0(%rbp)
  movq   $0x0,-0x1b8(%rbp)
  movq   $0x0,-0x1b0(%rbp)
  movl   $0x0,-0x1e4(%rbp)
  jmp    L8
L38:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1e4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1e4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jle    L113
L6:
  cmpl   $0xa,-0x1dc(%rbp)
  je     L153
  mov    -0x1e4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x1d4(%rbp)
  mov    -0x1d4(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x1d4(%rbp)
  mov    -0x1e4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x1e4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  movl   $0x0,-0x1d8(%rbp)
  cmpl   $0x0,-0x1dc(%rbp)
  jne    L26
  mov    -0x1dc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1dc(%rbp)
  cltq
  mov    -0x1d4(%rbp),%edx
  mov    %edx,-0x1d0(%rbp,%rax,4)
  jmp    L19
L26:
  movl   $0x0,-0x1e0(%rbp)
  jmp    L83
L37:
  mov    -0x1e0(%rbp),%eax
  cltq
  mov    -0x1d0(%rbp,%rax,4),%eax
  cmp    %eax,-0x1d4(%rbp)
  jne    L53
  movl   $0x1,-0x1d8(%rbp)
L53:
  addl   $0x1,-0x1e0(%rbp)
L83:
  mov    -0x1e0(%rbp),%eax
  cmp    -0x1dc(%rbp),%eax
  jl     L37
  cmpl   $0x0,-0x1d8(%rbp)
  jne    L19
  mov    -0x1dc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1dc(%rbp)
  cltq
  mov    -0x1d4(%rbp),%edx
  mov    %edx,-0x1d0(%rbp,%rax,4)
L19:
  mov    -0x1e4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L6
  jmp    L132
L153:
  nop
L132:
  addl   $0x1,-0x1e4(%rbp)
L8:
  cmpl   $0x63,-0x1e4(%rbp)
  jle    L38
  jmp    L84
L113:
  nop
L84:
  movl   $0x0,-0x1e4(%rbp)
  jmp    L136
L80:
  mov    -0x1e4(%rbp),%eax
  cltq
  mov    -0x1d0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1e4(%rbp)
L136:
  mov    -0x1e4(%rbp),%eax
  cmp    -0x1dc(%rbp),%eax
  jl     L80
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L120
  call   <__stack_chk_fail@plt>
L120:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string

tool: D7: %d

tool: D19: %d 

assistant: ```c
int main() {
  int niz[100], i, k, counter = 0, n, temp, ima;
  int niz_pomocni[10] = {};
  for (i = 0; i < 100; i++) {
    scanf("%d", &niz[i]);
    if (niz[i] <= 0)
      break;
    do {
      if (counter == 10)
        break;
      n = niz[i] % 10;
      niz[i] /= 10;
      ima = 0;
      if (counter == 0)
        niz_pomocni[counter++] = n;
      else {
        for (k = 0; k < counter; k++) {
          if (niz_pomocni[k] == n)
            ima = 1;
        }
        if (ima == 0) {
          niz_pomocni[counter++] = n;
        }
      }
    } while (niz[i] != 0);
  }
  for (i = 0; i < counter; i++)
    printf("%d ", niz_pomocni[i]);
  return 0;
}
```