ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <bundled_version@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  xor    %eax,%eax
  mov    0x4(%rsp),%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
L18:
  xor    %eax,%eax
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L18
  mov    $0x5,%ebx
  lea    D38(%rip),%rbp
L0:
  xor    %eax,%eax
  call   <bar@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L0
  mov    $0x5,%ebx
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D6(%rip),%rbp
L26:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <foo_bar@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L26
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D24
datatype: string
name: retrieve_data
arguments: label: D36
datatype: string
name: retrieve_data
arguments: label: D38
datatype: string
name: retrieve_data
arguments: label: D6
datatype: string

tool: D24: foo: %d


tool: D36: libbundled version: %d.%d.%d


tool: D38: bar: %d


tool: D6: foo bar: %d,%d


assistant: ```c
int main(int argc, char const *argv[]) {
  int major, minor, version;
  int f, b, i;
  bundled_version(&major, &minor, &version);
  printf("libbundled version: %d.%d.%d\n", major, minor, version);
  for (i = 0; i < 5; ++i) {
    printf("foo: %d\n", foo());
  }
  for (i = 0; i < 5; ++i) {
    printf("bar: %d\n", bar());
  }
  for (i = 0; i < 5; ++i) {
    foo_bar(&f, &b);
    printf("foo bar: %d,%d\n", f, b);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <bundled_version@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  xor    %eax,%eax
  mov    0x4(%rsp),%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
L13:
  xor    %eax,%eax
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L13
  mov    $0x5,%ebx
  lea    D16(%rip),%rbp
L28:
  xor    %eax,%eax
  call   <bar@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L28
  mov    $0x5,%ebx
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D8(%rip),%rbp
L35:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <foo_bar@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L35
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D13
data_type: string
name: read_data
arguments: data_label: D36
data_type: string
name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D8
data_type: string

tool: D13: foo: %d


tool: D36: libbundled version: %d.%d.%d


tool: D16: bar: %d


tool: D8: foo bar: %d,%d


assistant: ```c
int main(int argc, char const *argv[]) {
  int major, minor, version;
  int f, b, i;
  bundled_version(&major, &minor, &version);
  printf("libbundled version: %d.%d.%d\n", major, minor, version);
  for (i = 0; i < 5; ++i) {
    printf("foo: %d\n", foo());
  }
  for (i = 0; i < 5; ++i) {
    printf("bar: %d\n", bar());
  }
  for (i = 0; i < 5; ++i) {
    foo_bar(&f, &b);
    printf("foo bar: %d,%d\n", f, b);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<log_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <usart_put@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <usart_put@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <usart_put@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string

tool: D3: ERROR: 

tool: D16: 


assistant: ```c
void log_error(char *string) {
  usart_put("ERROR: ");
  usart_put(string);
  usart_put("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<log_error>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rdi
  call   <usart_put@plt>
  mov    %rbx,%rdi
  call   <usart_put@plt>
  lea    D9(%rip),%rdi
  call   <usart_put@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string

tool: D5: ERROR: 

tool: D9: 


assistant: ```c
void log_error(char *string) {
  usart_put("ERROR: ");
  usart_put(string);
  usart_put("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<log_error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D17(%rip),%rdi
  call   <usart_put@plt>
  mov    %rbp,%rdi
  call   <usart_put@plt>
  lea    D10(%rip),%rdi
  pop    %rbp
  jmp    1050 <usart_put@plt>
```

tool_calls: name: read_data
arguments: tag: D17
type_infered: string
name: read_data
arguments: tag: D10
type_infered: string

tool: D17: ERROR: 

tool: D10: 


assistant: ```c
void log_error(char *string) {
  usart_put("ERROR: ");
  usart_put(string);
  usart_put("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log_error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  call   <usart_put@plt>
  mov    %rbp,%rdi
  call   <usart_put@plt>
  lea    D5(%rip),%rdi
  pop    %rbp
  jmp    1050 <usart_put@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D13: ERROR: 

tool: D5: 


assistant: ```c
void log_error(char *string) {
  usart_put("ERROR: ");
  usart_put(string);
  usart_put("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PDJPG_TransIDCT_Horiz>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rax
  movswl (%rdi),%edx
  imul   $0x5b,%edx,%edx
  movswl 0x8(%rdi),%ecx
  imul   $0x5b,%ecx,%ecx
  movswl 0x4(%rdi),%r11d
  imul   $0x76,%r11d,%ebx
  imul   $0x31,%r11d,%r11d
  movswl 0xc(%rdi),%r8d
  imul   $0x76,%r8d,%ebp
  imul   $0x31,%r8d,%r8d
  lea    (%rdx,%rbx,1),%edi
  add    %ecx,%edi
  add    %r8d,%edi
  lea    (%rdx,%r11,1),%r9d
  sub    %ecx,%r9d
  sub    %ebp,%r9d
  mov    %edx,%r10d
  sub    %r11d,%r10d
  sub    %ecx,%r10d
  add    %ebp,%r10d
  sub    %ebx,%edx
  add    %ecx,%edx
  sub    %r8d,%edx
  movswl 0x2(%rax),%r12d
  movswl 0x6(%rax),%r11d
  movswl 0xa(%rax),%ecx
  movswl 0xe(%rax),%eax
  imul   $0x7e,%r12d,%r8d
  imul   $0x6a,%r11d,%ebx
  add    %ebx,%r8d
  imul   $0x47,%ecx,%ebx
  add    %ebx,%r8d
  lea    (%rax,%rax,4),%ebx
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%r8d
  imul   $0x6a,%r12d,%ebx
  imul   $0xffffffe7,%r11d,%ebp
  add    %ebp,%ebx
  mov    %ecx,%r13d
  shl    $0x6,%r13d
  mov    %ecx,%ebp
  sub    %r13d,%ebp
  lea    (%rbx,%rbp,2),%ebp
  imul   $0xffffffb9,%eax,%ebx
  add    %ebx,%ebp
  imul   $0x47,%r12d,%ebx
  mov    %r11d,%r14d
  shl    $0x6,%r14d
  mov    %r11d,%r13d
  sub    %r14d,%r13d
  lea    (%rbx,%r13,2),%ebx
  lea    (%rcx,%rcx,4),%r13d
  lea    0x0(%r13,%r13,4),%r13d
  add    %r13d,%ebx
  imul   $0x6a,%eax,%r13d
  add    %r13d,%ebx
  lea    (%r12,%r12,4),%r12d
  lea    (%r12,%r12,4),%r12d
  imul   $0xffffffb9,%r11d,%r11d
  add    %r12d,%r11d
  imul   $0x6a,%ecx,%ecx
  add    %r11d,%ecx
  mov    %eax,%r11d
  shl    $0x6,%r11d
  sub    %r11d,%eax
  lea    (%rcx,%rax,2),%eax
  lea    (%rdi,%r8,1),%ecx
  mov    %ecx,(%rsi)
  lea    (%r9,%rbp,1),%ecx
  mov    %ecx,0x4(%rsi)
  lea    (%r10,%rbx,1),%ecx
  mov    %ecx,0x8(%rsi)
  lea    (%rdx,%rax,1),%ecx
  mov    %ecx,0xc(%rsi)
  sub    %eax,%edx
  mov    %edx,0x10(%rsi)
  sub    %ebx,%r10d
  mov    %r10d,0x14(%rsi)
  sub    %ebp,%r9d
  mov    %r9d,0x18(%rsi)
  sub    %r8d,%edi
  mov    %edi,0x1c(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void PDJPG_TransIDCT_Horiz(short *iblk, int *oblk) {
  int a, b, c, d, e, f;
  int i, j, k, l;
  int m, n, o, p;
  a = iblk[0] * 91;
  b = iblk[4] * 91;
  c = iblk[2] * 118;
  d = iblk[2] * 49;
  e = iblk[6] * 118;
  f = iblk[6] * 49;
  i = a + c + b + f;
  j = a + d - b - e;
  k = a - d - b + e;
  l = a - c + b - f;
  m = iblk[1] * 126 + iblk[3] * 106 + iblk[5] * 71 + iblk[7] * 25;
  n = iblk[1] * 106 - iblk[3] * 25 - iblk[5] * 126 - iblk[7] * 71;
  o = iblk[1] * 71 - iblk[3] * 126 + iblk[5] * 25 + iblk[7] * 106;
  p = iblk[1] * 25 - iblk[3] * 71 + iblk[5] * 106 - iblk[7] * 126;
  oblk[0] = i + m;
  oblk[1] = j + n;
  oblk[2] = k + o;
  oblk[3] = l + p;
  oblk[4] = l - p;
  oblk[5] = k - o;
  oblk[6] = j - n;
  oblk[7] = i - m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<PDJPG_TransIDCT_Horiz>:
  endbr64
  push   %r14
  mov    %rdi,%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movswl (%rdi),%edx
  movswl 0x4(%rdi),%r11d
  movswl 0x8(%rdi),%ecx
  imul   $0x5b,%edx,%edx
  movswl 0xc(%rdi),%r8d
  movswl 0x2(%rax),%r12d
  imul   $0x76,%r11d,%ebx
  imul   $0x31,%r11d,%r11d
  imul   $0x5b,%ecx,%ecx
  mov    %edx,%r10d
  imul   $0x76,%r8d,%ebp
  lea    (%rdx,%rbx,1),%edi
  imul   $0x31,%r8d,%r8d
  lea    (%rdx,%r11,1),%r9d
  sub    %r11d,%r10d
  sub    %ebx,%edx
  movswl 0x6(%rax),%r11d
  add    %ecx,%edi
  add    %ecx,%edx
  sub    %ecx,%r9d
  sub    %ecx,%r10d
  movswl 0xa(%rax),%ecx
  movswl 0xe(%rax),%eax
  sub    %ebp,%r9d
  imul   $0x6a,%r11d,%ebx
  add    %r8d,%edi
  sub    %r8d,%edx
  add    %ebp,%r10d
  imul   $0x7e,%r12d,%r8d
  mov    %ecx,%r13d
  mov    %r11d,%r14d
  imul   $0xffffffe7,%r11d,%ebp
  shl    $0x6,%r13d
  shl    $0x6,%r14d
  add    %ebx,%r8d
  imul   $0x47,%ecx,%ebx
  add    %ebx,%r8d
  lea    (%rax,%rax,4),%ebx
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%r8d
  imul   $0x6a,%r12d,%ebx
  add    %ebp,%ebx
  mov    %ecx,%ebp
  sub    %r13d,%ebp
  mov    %r11d,%r13d
  lea    (%rbx,%rbp,2),%ebp
  sub    %r14d,%r13d
  imul   $0xffffffb9,%eax,%ebx
  add    %ebx,%ebp
  imul   $0x47,%r12d,%ebx
  lea    (%r12,%r12,4),%r12d
  lea    (%r12,%r12,4),%r12d
  lea    (%rbx,%r13,2),%ebx
  lea    (%rcx,%rcx,4),%r13d
  lea    0x0(%r13,%r13,4),%r13d
  add    %r13d,%ebx
  imul   $0xffffffb9,%r11d,%r11d
  imul   $0x6a,%ecx,%ecx
  imul   $0x6a,%eax,%r13d
  add    %r12d,%r11d
  add    %r11d,%ecx
  mov    %eax,%r11d
  shl    $0x6,%r11d
  add    %r13d,%ebx
  sub    %r11d,%eax
  lea    (%rcx,%rax,2),%eax
  lea    (%rdi,%r8,1),%ecx
  sub    %r8d,%edi
  mov    %ecx,(%rsi)
  lea    (%r9,%rbp,1),%ecx
  sub    %ebp,%r9d
  mov    %ecx,0x4(%rsi)
  lea    (%r10,%rbx,1),%ecx
  sub    %ebx,%r10d
  pop    %rbx
  mov    %ecx,0x8(%rsi)
  lea    (%rdx,%rax,1),%ecx
  sub    %eax,%edx
  pop    %rbp
  mov    %ecx,0xc(%rsi)
  pop    %r12
  mov    %edx,0x10(%rsi)
  pop    %r13
  mov    %r10d,0x14(%rsi)
  pop    %r14
  mov    %r9d,0x18(%rsi)
  mov    %edi,0x1c(%rsi)
  ret
```

assistant: ```c
void PDJPG_TransIDCT_Horiz(short *iblk, int *oblk) {
  int a, b, c, d, e, f;
  int i, j, k, l;
  int m, n, o, p;
  a = iblk[0] * 91;
  b = iblk[4] * 91;
  c = iblk[2] * 118;
  d = iblk[2] * 49;
  e = iblk[6] * 118;
  f = iblk[6] * 49;
  i = a + c + b + f;
  j = a + d - b - e;
  k = a - d - b + e;
  l = a - c + b - f;
  m = iblk[1] * 126 + iblk[3] * 106 + iblk[5] * 71 + iblk[7] * 25;
  n = iblk[1] * 106 - iblk[3] * 25 - iblk[5] * 126 - iblk[7] * 71;
  o = iblk[1] * 71 - iblk[3] * 126 + iblk[5] * 25 + iblk[7] * 106;
  p = iblk[1] * 25 - iblk[3] * 71 + iblk[5] * 106 - iblk[7] * 126;
  oblk[0] = i + m;
  oblk[1] = j + n;
  oblk[2] = k + o;
  oblk[3] = l + p;
  oblk[4] = l - p;
  oblk[5] = k - o;
  oblk[6] = j - n;
  oblk[7] = i - m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<PDJPG_TransIDCT_Horiz>:
  endbr64
  push   %r14
  mov    %rdi,%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movswl (%rdi),%edx
  movswl 0x4(%rdi),%r11d
  movswl 0x8(%rdi),%ecx
  imul   $0x5b,%edx,%edx
  movswl 0xc(%rdi),%r8d
  movswl 0x2(%rax),%r12d
  imul   $0x76,%r11d,%ebx
  imul   $0x31,%r11d,%r11d
  imul   $0x5b,%ecx,%ecx
  mov    %edx,%r10d
  imul   $0x76,%r8d,%ebp
  lea    (%rdx,%rbx,1),%edi
  imul   $0x31,%r8d,%r8d
  lea    (%rdx,%r11,1),%r9d
  sub    %r11d,%r10d
  sub    %ebx,%edx
  movswl 0x6(%rax),%r11d
  add    %ecx,%edi
  add    %ecx,%edx
  sub    %ecx,%r9d
  sub    %ecx,%r10d
  movswl 0xa(%rax),%ecx
  movswl 0xe(%rax),%eax
  sub    %ebp,%r9d
  imul   $0x6a,%r11d,%ebx
  add    %r8d,%edi
  sub    %r8d,%edx
  add    %ebp,%r10d
  imul   $0x7e,%r12d,%r8d
  mov    %ecx,%r13d
  mov    %r11d,%r14d
  imul   $0xffffffe7,%r11d,%ebp
  shl    $0x6,%r13d
  shl    $0x6,%r14d
  add    %ebx,%r8d
  imul   $0x47,%ecx,%ebx
  add    %ebx,%r8d
  lea    (%rax,%rax,4),%ebx
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%r8d
  imul   $0x6a,%r12d,%ebx
  add    %ebp,%ebx
  mov    %ecx,%ebp
  sub    %r13d,%ebp
  mov    %r11d,%r13d
  lea    (%rbx,%rbp,2),%ebp
  sub    %r14d,%r13d
  imul   $0xffffffb9,%eax,%ebx
  add    %ebx,%ebp
  imul   $0x47,%r12d,%ebx
  lea    (%r12,%r12,4),%r12d
  lea    (%r12,%r12,4),%r12d
  lea    (%rbx,%r13,2),%ebx
  lea    (%rcx,%rcx,4),%r13d
  lea    0x0(%r13,%r13,4),%r13d
  add    %r13d,%ebx
  imul   $0xffffffb9,%r11d,%r11d
  imul   $0x6a,%ecx,%ecx
  imul   $0x6a,%eax,%r13d
  add    %r12d,%r11d
  add    %r11d,%ecx
  mov    %eax,%r11d
  shl    $0x6,%r11d
  add    %r13d,%ebx
  sub    %r11d,%eax
  lea    (%rcx,%rax,2),%eax
  lea    (%rdi,%r8,1),%ecx
  sub    %r8d,%edi
  mov    %ecx,(%rsi)
  lea    (%r9,%rbp,1),%ecx
  sub    %ebp,%r9d
  mov    %ecx,0x4(%rsi)
  lea    (%r10,%rbx,1),%ecx
  sub    %ebx,%r10d
  pop    %rbx
  mov    %ecx,0x8(%rsi)
  lea    (%rdx,%rax,1),%ecx
  sub    %eax,%edx
  pop    %rbp
  mov    %ecx,0xc(%rsi)
  pop    %r12
  mov    %edx,0x10(%rsi)
  pop    %r13
  mov    %r10d,0x14(%rsi)
  pop    %r14
  mov    %r9d,0x18(%rsi)
  mov    %edi,0x1c(%rsi)
  ret
```

assistant: ```c
void PDJPG_TransIDCT_Horiz(short *iblk, int *oblk) {
  int a, b, c, d, e, f;
  int i, j, k, l;
  int m, n, o, p;
  a = iblk[0] * 91;
  b = iblk[4] * 91;
  c = iblk[2] * 118;
  d = iblk[2] * 49;
  e = iblk[6] * 118;
  f = iblk[6] * 49;
  i = a + c + b + f;
  j = a + d - b - e;
  k = a - d - b + e;
  l = a - c + b - f;
  m = iblk[1] * 126 + iblk[3] * 106 + iblk[5] * 71 + iblk[7] * 25;
  n = iblk[1] * 106 - iblk[3] * 25 - iblk[5] * 126 - iblk[7] * 71;
  o = iblk[1] * 71 - iblk[3] * 126 + iblk[5] * 25 + iblk[7] * 106;
  p = iblk[1] * 25 - iblk[3] * 71 + iblk[5] * 106 - iblk[7] * 126;
  oblk[0] = i + m;
  oblk[1] = j + n;
  oblk[2] = k + o;
  oblk[3] = l + p;
  oblk[4] = l - p;
  oblk[5] = k - o;
  oblk[6] = j - n;
  oblk[7] = i - m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<diff_timespec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    (%rax),%rax
  mov    %rax,(%rcx)
  mov    %rdx,0x8(%rcx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3b9aca00,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,0x8(%rax)
L0:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%eax
  sub    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,0x8(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void diff_timespec(struct timespec *t1, struct timespec *t2, struct timespec *result) {
  *result = *t2;
  if (t1->tv_nsec > t2->tv_nsec) {
    result->tv_nsec += 1000000000UL;
    result->tv_sec -= 1;
  }
  result->tv_nsec -= t1->tv_nsec;
  result->tv_sec -= t1->tv_sec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<diff_timespec>:
  endbr64
  movdqu (%rsi),%xmm0
  movups %xmm0,(%rdx)
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  jle    L4
  addq   $0x3b9aca00,(%rdx)
  subl   $0x1,0x8(%rdx)
L4:
  mov    (%rdi),%rax
  sub    %rax,(%rdx)
  mov    0x8(%rdi),%eax
  sub    %eax,0x8(%rdx)
  ret
```

assistant: ```c
void diff_timespec(struct timespec *t1, struct timespec *t2, struct timespec *result) {
  *result = *t2;
  if (t1->tv_nsec > t2->tv_nsec) {
    result->tv_nsec += 1000000000UL;
    result->tv_sec -= 1;
  }
  result->tv_nsec -= t1->tv_nsec;
  result->tv_sec -= t1->tv_sec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<diff_timespec>:
  endbr64
  movdqu (%rsi),%xmm0
  movups %xmm0,(%rdx)
  mov    (%rdi),%r8
  cmp    (%rsi),%r8
  jg     L1
  mov    (%rdx),%rcx
  mov    0x8(%rdx),%eax
  sub    0x8(%rdi),%eax
  sub    %r8,%rcx
  mov    %eax,0x8(%rdx)
  mov    %rcx,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    (%rdx),%rax
  lea    0x3b9aca00(%rax),%rcx
  mov    0x8(%rdx),%eax
  mov    %rcx,(%rdx)
  mov    (%rdi),%r8
  sub    $0x1,%eax
  mov    %eax,0x8(%rdx)
  sub    %r8,%rcx
  sub    0x8(%rdi),%eax
  mov    %rcx,(%rdx)
  mov    %eax,0x8(%rdx)
  ret
```

assistant: ```c
void diff_timespec(struct timespec *t1, struct timespec *t2, struct timespec *result) {
  *result = *t2;
  if (t1->tv_nsec > t2->tv_nsec) {
    result->tv_nsec += 1000000000UL;
    result->tv_sec -= 1;
  }
  result->tv_nsec -= t1->tv_nsec;
  result->tv_sec -= t1->tv_sec;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<diff_timespec>:
  endbr64
  movdqu (%rsi),%xmm0
  movups %xmm0,(%rdx)
  mov    (%rdi),%r8
  cmp    (%rsi),%r8
  jg     L9
  mov    (%rdx),%rcx
  mov    0x8(%rdx),%eax
  sub    0x8(%rdi),%eax
  sub    %r8,%rcx
  mov    %eax,0x8(%rdx)
  mov    %rcx,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    (%rdx),%rax
  lea    0x3b9aca00(%rax),%rcx
  mov    0x8(%rdx),%eax
  mov    %rcx,(%rdx)
  mov    (%rdi),%r8
  sub    $0x1,%eax
  mov    %eax,0x8(%rdx)
  sub    %r8,%rcx
  sub    0x8(%rdi),%eax
  mov    %rcx,(%rdx)
  mov    %eax,0x8(%rdx)
  ret
```

assistant: ```c
void diff_timespec(struct timespec *t1, struct timespec *t2, struct timespec *result) {
  *result = *t2;
  if (t1->tv_nsec > t2->tv_nsec) {
    result->tv_nsec += 1000000000UL;
    result->tv_sec -= 1;
  }
  result->tv_nsec -= t1->tv_nsec;
  result->tv_sec -= t1->tv_sec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  nop
  leave
  ret
```

assistant: ```c
void test() {
  int a = 0;
  if (0)
    a = 1;
  expecti(a, 0);
  if (1)
    a = 1;
  expecti(a, 1);
  if (0) {
    a = 0;
  } else
    expecti(a, 1);
  if (1) {
    a = 0;
  }
  expecti(a, 0);
  if (0)
    expecti(0, 1);
  else {
    expecti(1, 1);
  }
  if (1) {
    expecti(1, 1);
  } else
    a = 1;
  expecti(a, 0);
  if (1) {
    if (0) {
      expecti(1, 0);
    } else
      expecti(1, 1);
    if (1) {
      if (1)
        expecti(1, 1);
      else {
        expecti(1, 0);
      }
    } else
      expecti(0, 1);
  } else {
    expecti(1, 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test() {
  int a = 0;
  if (0)
    a = 1;
  expecti(a, 0);
  if (1)
    a = 1;
  expecti(a, 1);
  if (0) {
    a = 0;
  } else
    expecti(a, 1);
  if (1) {
    a = 0;
  }
  expecti(a, 0);
  if (0)
    expecti(0, 1);
  else {
    expecti(1, 1);
  }
  if (1) {
    expecti(1, 1);
  } else
    a = 1;
  expecti(a, 0);
  if (1) {
    if (0) {
      expecti(1, 0);
    } else
      expecti(1, 1);
    if (1) {
      if (1)
        expecti(1, 1);
      else {
        expecti(1, 0);
      }
    } else
      expecti(0, 1);
  } else {
    expecti(1, 1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <expecti@plt>
```

assistant: ```c
void test() {
  int a = 0;
  if (0)
    a = 1;
  expecti(a, 0);
  if (1)
    a = 1;
  expecti(a, 1);
  if (0) {
    a = 0;
  } else
    expecti(a, 1);
  if (1) {
    a = 0;
  }
  expecti(a, 0);
  if (0)
    expecti(0, 1);
  else {
    expecti(1, 1);
  }
  if (1) {
    expecti(1, 1);
  } else
    a = 1;
  expecti(a, 0);
  if (1) {
    if (0) {
      expecti(1, 0);
    } else
      expecti(1, 1);
    if (1) {
      if (1)
        expecti(1, 1);
      else {
        expecti(1, 0);
      }
    } else
      expecti(0, 1);
  } else {
    expecti(1, 1);
  }
}
```