ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<change_state>:
  endbr64
  mov    D5(%rip),%rdx
  mov    (%rdx),%eax
  test   %eax,%eax
  jne    L85
  cmp    $0x22,%edi
  je     L113
  cmp    $0x27,%edi
  je     L45
  cmp    $0x23,%esi
  jne    L167
  cmp    $0x64,%edi
  jne    L167
  movl   $0x3,(%rdx)
  mov    $0x3,%eax
  ret
  nopl   (%rax)
L85:
  cmp    $0x1,%eax
  je     L133
  cmp    $0x2,%eax
  je     L13
  cmp    $0x3,%eax
  je     L114
  cmp    $0x4,%eax
  je     L19
L46:
  ret
  nopl   (%rax)
L113:
  movl   $0x2,(%rdx)
  mov    $0x2,%eax
  ret
  nopl   0x0(%rax)
L114:
  cmp    $0xa,%edi
  jne    L46
L62:
  movl   $0x0,(%rdx)
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L167:
  cmp    $0x2f,%esi
  jne    L46
  cmp    $0x2a,%edi
  jne    L46
  movl   $0x4,(%rdx)
  mov    $0x4,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L133:
  cmp    $0x27,%edi
  je     L62
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  movl   $0x1,(%rdx)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L13:
  cmp    $0x22,%edi
  je     L62
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  cmp    $0x2a,%esi
  jne    L46
  cmp    $0x2f,%edi
  je     L62
  jmp    L46
```

assistant: ```c
int change_state(int cur_char, int last_char) {
  extern int state;
  if (state == 0) {
    if (cur_char == '"') {
      state = 2;
    } else if (cur_char == '\'') {
      state = 1;
    } else if (last_char == '#' && cur_char == 'd') {
      state = 3;
    } else if (last_char == '/' && cur_char == '*') {
      state = 4;
    } else {
      state = 0;
    }
  } else if (state == 1) {
    if (cur_char == '\'') {
      state = 0;
    } else {
      state = 1;
    }
  } else if (state == 2) {
    if (cur_char == '"') {
      state = 0;
    } else {
      state = 2;
    }
  } else if (state == 3) {
    if (cur_char == '\n') {
      state = 0;
    } else {
      state = 3;
    }
  } else if (state == 4) {
    if (last_char == '*' && cur_char == '/') {
      state = 0;
    } else {
      state = 4;
    }
  } else {
  }
  return state;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<change_state>:
  endbr64
  mov    D5(%rip),%rdx
  mov    (%rdx),%eax
  test   %eax,%eax
  jne    L145
  cmp    $0x22,%edi
  je     L113
  cmp    $0x27,%edi
  je     L52
  cmp    $0x23,%esi
  jne    L65
  cmp    $0x64,%edi
  jne    L65
  movl   $0x3,(%rdx)
  mov    $0x3,%eax
  ret
  nopl   (%rax)
L145:
  cmp    $0x1,%eax
  je     L28
  cmp    $0x2,%eax
  je     L12
  cmp    $0x3,%eax
  je     L167
  cmp    $0x4,%eax
  je     L129
L31:
  ret
  nopl   (%rax)
L113:
  movl   $0x2,(%rdx)
  mov    $0x2,%eax
  ret
  nopl   0x0(%rax)
L167:
  cmp    $0xa,%edi
  jne    L31
L34:
  movl   $0x0,(%rdx)
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L65:
  cmp    $0x2f,%esi
  jne    L31
  cmp    $0x2a,%edi
  jne    L31
  movl   $0x4,(%rdx)
  mov    $0x4,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  cmp    $0x27,%edi
  je     L34
  ret
  cs nopw 0x0(%rax,%rax,1)
L52:
  movl   $0x1,(%rdx)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L12:
  cmp    $0x22,%edi
  je     L34
  ret
  cs nopw 0x0(%rax,%rax,1)
L129:
  cmp    $0x2a,%esi
  jne    L31
  cmp    $0x2f,%edi
  je     L34
  jmp    L31
```

assistant: ```c
int change_state(int cur_char, int last_char) {
  extern int state;
  if (state == 0) {
    if (cur_char == '"') {
      state = 2;
    } else if (cur_char == '\'') {
      state = 1;
    } else if (last_char == '#' && cur_char == 'd') {
      state = 3;
    } else if (last_char == '/' && cur_char == '*') {
      state = 4;
    } else {
      state = 0;
    }
  } else if (state == 1) {
    if (cur_char == '\'') {
      state = 0;
    } else {
      state = 1;
    }
  } else if (state == 2) {
    if (cur_char == '"') {
      state = 0;
    } else {
      state = 2;
    }
  } else if (state == 3) {
    if (cur_char == '\n') {
      state = 0;
    } else {
      state = 3;
    }
  } else if (state == 4) {
    if (last_char == '*' && cur_char == '/') {
      state = 0;
    } else {
      state = 4;
    }
  } else {
  }
  return state;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBOTGMode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40050000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x41c,%eax
  cltq
  movq   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void USBOTGMode(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  (*((volatile uint8_t *)(ui32Base + 0x0000041C))) = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<USBOTGMode>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x40050000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x41c,%ebx
  movslq %ebx,%rbx
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void USBOTGMode(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  (*((volatile uint8_t *)(ui32Base + 0x0000041C))) = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<USBOTGMode>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x40050000,%ebx
  sete   %dil
  add    $0x41c,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void USBOTGMode(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  (*((volatile uint8_t *)(ui32Base + 0x0000041C))) = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<USBOTGMode>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x40050000,%ebx
  sete   %dil
  add    $0x41c,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void USBOTGMode(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  (*((volatile uint8_t *)(ui32Base + 0x0000041C))) = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string_emitter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void string_emitter(char c, void *data) {
  char **output_string = (char **)data;
  *((*output_string)++) = c;
  **output_string = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string_emitter>:
  endbr64
  mov    (%rsi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  mov    %dil,(%rax)
  mov    (%rsi),%rax
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
void string_emitter(char c, void *data) {
  char **output_string = (char **)data;
  *((*output_string)++) = c;
  **output_string = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<string_emitter>:
  endbr64
  mov    (%rsi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  mov    %dil,(%rax)
  mov    (%rsi),%rax
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
void string_emitter(char c, void *data) {
  char **output_string = (char **)data;
  *((*output_string)++) = c;
  **output_string = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<L_macNs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <L_mult@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <L_add_c@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int32_t L_macNs(int32_t L_var3, int16_t var1, int16_t var2) {
  int32_t L_var_out;
  L_var_out = L_mult(var1, var2);
  L_var_out = L_add_c(L_var3, L_var_out);
  return (L_var_out);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<L_macNs>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  mov    %edx,%esi
  call   <L_mult@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <L_add_c@plt>
  pop    %rbx
  ret
```

assistant: ```c
int32_t L_macNs(int32_t L_var3, int16_t var1, int16_t var2) {
  int32_t L_var_out;
  L_var_out = L_mult(var1, var2);
  L_var_out = L_add_c(L_var3, L_var_out);
  return (L_var_out);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<L_macNs>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  mov    %edx,%esi
  call   <L_mult@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <L_add_c@plt>
```

assistant: ```c
int32_t L_macNs(int32_t L_var3, int16_t var1, int16_t var2) {
  int32_t L_var_out;
  L_var_out = L_mult(var1, var2);
  L_var_out = L_add_c(L_var3, L_var_out);
  return (L_var_out);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<L_macNs>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  mov    %edx,%esi
  call   <L_mult@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <L_add_c@plt>
```

assistant: ```c
int32_t L_macNs(int32_t L_var3, int16_t var1, int16_t var2) {
  int32_t L_var_out;
  L_var_out = L_mult(var1, var2);
  L_var_out = L_add_c(L_var3, L_var_out);
  return (L_var_out);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L10:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double my_pow(int a) {
  int i, prod;
  prod = 1;
  for (i = 0; i < a; i++) {
    prod = prod * 10;
  }
  return prod;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_pow>:
  endbr64
  test   %edi,%edi
  jle    L9
  mov    $0x1,%eax
  mov    $0x0,%edx
L18:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    $0x1,%edx
  cmp    %edx,%edi
  jne    L18
L27:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ret
L9:
  mov    $0x1,%eax
  jmp    L27
```

assistant: ```c
double my_pow(int a) {
  int i, prod;
  prod = 1;
  for (i = 0; i < a; i++) {
    prod = prod * 10;
  }
  return prod;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_pow>:
  endbr64
  test   %edi,%edi
  jle    L1
  mov    $0x1,%eax
  xor    %edx,%edx
  nop
L12:
  lea    (%rax,%rax,4),%eax
  add    $0x1,%edx
  add    %eax,%eax
  cmp    %edx,%edi
  jne    L12
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ret
  nopl   (%rax)
L1:
  movsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double my_pow(int a) {
  int i, prod;
  prod = 1;
  for (i = 0; i < a; i++) {
    prod = prod * 10;
  }
  return prod;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_pow>:
  endbr64
  test   %edi,%edi
  jle    L12
  mov    %edi,%ecx
  cmp    $0x1,%edi
  je     L35
  movq   D13(%rip),%xmm0
  mov    %edi,%edx
  xor    %eax,%eax
  shr    %edx
  nopl   (%rax)
L15:
  movdqa %xmm0,%xmm1
  add    $0x1,%eax
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %eax,%edx
  jne    L15
  movd   %xmm0,%edi
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%eax
  imul   %eax,%edi
  and    $0x1,%ecx
  je     L3
L35:
  lea    (%rdi,%rdi,4),%edi
  add    %edi,%edi
L3:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  ret
  nopl   0x0(%rax)
L12:
  movsd  D17(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_infered: byte[8]
name: read_data
arguments: label: D17
type_infered: byte[8]

tool: {"D13": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double my_pow(int a) {
  int i, prod;
  prod = 1;
  for (i = 0; i < a; i++) {
    prod = prod * 10;
  }
  return prod;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_next_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L53
L49:
  addq   $0x1,-0x8(%rbp)
L53:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L49
  jmp    L29
L12:
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_next_arg(char *buffer) {
  while (buffer[0] != 0 && !isspace(buffer[0]))
    buffer++;
  while (buffer[0] != 0 && isspace(buffer[0]))
    buffer++;
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_next_arg>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L46
L43:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L43
L46:
  mov    %rbx,%rax
  jmp    L88
L41:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L23
L26:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L86
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L26
  mov    %rbx,%rax
  jmp    L88
L23:
  mov    %rbx,%rax
  jmp    L88
L86:
  mov    %rbx,%rax
L88:
  pop    %rbx
  ret
```

assistant: ```c
char *get_next_arg(char *buffer) {
  while (buffer[0] != 0 && !isspace(buffer[0]))
    buffer++;
  while (buffer[0] != 0 && isspace(buffer[0]))
    buffer++;
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_next_arg>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L10
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L6
L10:
  call   <isspace@plt>
  test   %rax,%rax
  je     L9
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L53:
  add    $0x1,%r12
L30:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L6
  call   <isspace@plt>
  test   %rax,%rax
  jne    L53
L6:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *get_next_arg(char *buffer) {
  while (buffer[0] != 0 && !isspace(buffer[0]))
    buffer++;
  while (buffer[0] != 0 && isspace(buffer[0]))
    buffer++;
  return buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_next_arg>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L21
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L67:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L6
L21:
  call   <isspace@plt>
  test   %rax,%rax
  je     L67
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%r12
L33:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L6
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
L6:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *get_next_arg(char *buffer) {
  while (buffer[0] != 0 && !isspace(buffer[0]))
    buffer++;
  while (buffer[0] != 0 && isspace(buffer[0]))
    buffer++;
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LexIsInlineComment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x23,-0x4(%rbp)
  jne    L0
  mov    $0x1,%eax
  jmp    L7
L0:
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int LexIsInlineComment(char c) {
  if (c == '#') {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LexIsInlineComment>:
  endbr64
  cmp    $0x23,%dil
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int LexIsInlineComment(char c) {
  if (c == '#') {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<LexIsInlineComment>:
  endbr64
  xor    %eax,%eax
  cmp    $0x23,%dil
  sete   %al
  ret
```

assistant: ```c
int LexIsInlineComment(char c) {
  if (c == '#') {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LexIsInlineComment>:
  endbr64
  xor    %eax,%eax
  cmp    $0x23,%dil
  sete   %al
  ret
```

assistant: ```c
int LexIsInlineComment(char c) {
  if (c == '#') {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x94(%rbp),%edx
  lea    -0x90(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: in usleep: usec = %d


assistant: ```c
int usleep(useconds_t usec) {
  char szBuf[128];
  sprintf(szBuf, "in usleep: usec = %d\n", usec);
  ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usleep>:
  endbr64
  sub    $0x98,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D5(%rip),%rsi
  call   <sprintf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x98,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: in usleep: usec = %d


assistant: ```c
int usleep(useconds_t usec) {
  char szBuf[128];
  sprintf(szBuf, "in usleep: usec = %d\n", usec);
  ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usleep>:
  endbr64
  sub    $0x98,%rsp
  mov    %edi,%edx
  lea    D5(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <sprintf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x98,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: in usleep: usec = %d


assistant: ```c
int usleep(useconds_t usec) {
  char szBuf[128];
  sprintf(szBuf, "in usleep: usec = %d\n", usec);
  ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usleep>:
  endbr64
  sub    $0x98,%rsp
  mov    %edi,%edx
  lea    D6(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <sprintf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x98,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: in usleep: usec = %d


assistant: ```c
int usleep(useconds_t usec) {
  char szBuf[128];
  sprintf(szBuf, "in usleep: usec = %d\n", usec);
  ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmplx_square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <creal@plt>
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <creal@plt>
  movapd %xmm0,%xmm2
  mulsd  -0x20(%rbp),%xmm2
  movsd  %xmm2,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <cimag@plt>
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <cimag@plt>
  mulsd  -0x28(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <creal@plt>
  addsd  %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <cimag@plt>
  mulsd  -0x20(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    D1(%rip),%rax
  movss  (%rax),%xmm0
  mulss  -0x4(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
complex cmplx_square(complex z) {
  float real = creal(z) * creal(z) - cimag(z) * cimag(z);
  float imag = 2.0 * creal(z) * cimag(z);
  return real + I * imag;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmplx_square>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x28,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <creal@plt>
  movq   %xmm0,%rbx
  movss  0xc(%rsp),%xmm0
  call   <creal@plt>
  movapd %xmm0,%xmm3
  movq   %rbx,%xmm4
  mulsd  %xmm4,%xmm3
  movsd  %xmm3,0x10(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <cimag@plt>
  movq   %xmm0,%rbx
  movss  0xc(%rsp),%xmm0
  call   <cimag@plt>
  movq   %xmm0,%r14
  movss  0xc(%rsp),%xmm0
  call   <creal@plt>
  movsd  %xmm0,0x18(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <cimag@plt>
  movapd %xmm0,%xmm1
  movsd  0x18(%rsp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    D2(%rip),%rax
  mulss  (%rax),%xmm0
  movq   %rbx,%xmm2
  movq   %r14,%xmm5
  mulsd  %xmm5,%xmm2
  movsd  0x10(%rsp),%xmm1
  subsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  addss  %xmm1,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
complex cmplx_square(complex z) {
  float real = creal(z) * creal(z) - cimag(z) * cimag(z);
  float imag = 2.0 * creal(z) * cimag(z);
  return real + I * imag;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cmplx_square>:
  endbr64
  sub    $0x38,%rsp
  movss  %xmm0,0x10(%rsp)
  call   <creal@plt>
  movss  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  call   <creal@plt>
  movsd  0x8(%rsp),%xmm3
  movss  0x10(%rsp),%xmm2
  mulsd  %xmm0,%xmm3
  movaps %xmm2,%xmm0
  movsd  %xmm3,0x28(%rsp)
  call   <cimag@plt>
  movss  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  movss  %xmm2,0x18(%rsp)
  call   <cimag@plt>
  movss  0x18(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movaps %xmm2,%xmm0
  movss  %xmm2,0x24(%rsp)
  call   <creal@plt>
  movss  0x24(%rsp),%xmm2
  movsd  %xmm0,0x18(%rsp)
  movaps %xmm2,%xmm0
  call   <cimag@plt>
  movsd  0x18(%rsp),%xmm1
  mov    D2(%rip),%rax
  movsd  0x28(%rsp),%xmm3
  addsd  %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  0x10(%rsp),%xmm1
  cvtsd2ss %xmm0,%xmm0
  mulss  (%rax),%xmm0
  add    $0x38,%rsp
  subsd  %xmm1,%xmm3
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm3,%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
complex cmplx_square(complex z) {
  float real = creal(z) * creal(z) - cimag(z) * cimag(z);
  float imag = 2.0 * creal(z) * cimag(z);
  return real + I * imag;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmplx_square>:
  endbr64
  sub    $0x38,%rsp
  movss  %xmm0,0x10(%rsp)
  call   <creal@plt>
  movss  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  call   <creal@plt>
  movsd  0x8(%rsp),%xmm3
  movss  0x10(%rsp),%xmm2
  mulsd  %xmm0,%xmm3
  movaps %xmm2,%xmm0
  movsd  %xmm3,0x28(%rsp)
  call   <cimag@plt>
  movss  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  movss  %xmm2,0x18(%rsp)
  call   <cimag@plt>
  movss  0x18(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movaps %xmm2,%xmm0
  movss  %xmm2,0x24(%rsp)
  call   <creal@plt>
  movss  0x24(%rsp),%xmm2
  movsd  %xmm0,0x18(%rsp)
  movaps %xmm2,%xmm0
  call   <cimag@plt>
  movsd  0x18(%rsp),%xmm1
  mov    D6(%rip),%rax
  movsd  0x28(%rsp),%xmm3
  addsd  %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  0x10(%rsp),%xmm1
  cvtsd2ss %xmm0,%xmm0
  mulss  (%rax),%xmm0
  add    $0x38,%rsp
  subsd  %xmm1,%xmm3
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm3,%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
complex cmplx_square(complex z) {
  float real = creal(z) * creal(z) - cimag(z) * cimag(z);
  float imag = 2.0 * creal(z) * cimag(z);
  return real + I * imag;
}
```