ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L14:
  mov    -0x8(%rbp),%rax
  shl    $0x7,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash(char *str) {
  unsigned long v = 0L;
  for (; *str; str++) {
    v = ((v << 7) + *str);
  }
  return v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L19
  mov    $0x0,%eax
L6:
  shl    $0x7,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L6
  ret
L19:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long hash(char *str) {
  unsigned long v = 0L;
  for (; *str; str++) {
    v = ((v << 7) + *str);
  }
  return v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rdx
  xor    %eax,%eax
  test   %dl,%dl
  je     L6
  xchg   %ax,%ax
L19:
  shl    $0x7,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  movsbq (%rdi),%rdx
  test   %dl,%dl
  jne    L19
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
unsigned long hash(char *str) {
  unsigned long v = 0L;
  for (; *str; str++) {
    v = ((v << 7) + *str);
  }
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rdx
  xor    %eax,%eax
  test   %dl,%dl
  je     L16
  xchg   %ax,%ax
L8:
  shl    $0x7,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  movsbq (%rdi),%rdx
  test   %dl,%dl
  jne    L8
  ret
  nopl   0x0(%rax)
L16:
  ret
```

assistant: ```c
unsigned long hash(char *str) {
  unsigned long v = 0L;
  for (; *str; str++) {
    v = ((v << 7) + *str);
  }
  return v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<warp_mat4_fill_orthographic>:
  endbr64
  movss  D9(%rip),%xmm4
  xorps  %xmm4,%xmm0
  movss  D1(%rip),%xmm7
  mulss  %xmm7,%xmm0
  movaps %xmm3,%xmm6
  subss  %xmm2,%xmm6
  movaps %xmm0,%xmm5
  xorps  %xmm4,%xmm5
  subss  %xmm0,%xmm5
  movss  D16(%rip),%xmm0
  movaps %xmm0,%xmm8
  divss  %xmm5,%xmm8
  movss  %xmm8,(%rdi)
  movl   $0x0,0x4(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0x0,0xc(%rdi)
  movl   $0x0,0x10(%rdi)
  mulss  %xmm7,%xmm1
  addss  %xmm1,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,0x14(%rdi)
  movl   $0x0,0x18(%rdi)
  movl   $0x0,0x1c(%rdi)
  movl   $0x0,0x20(%rdi)
  movl   $0x0,0x24(%rdi)
  movss  D26(%rip),%xmm0
  divss  %xmm6,%xmm0
  movss  %xmm0,0x28(%rdi)
  movl   $0x0,0x2c(%rdi)
  movl   $0x0,0x30(%rdi)
  movl   $0x0,0x34(%rdi)
  addss  %xmm2,%xmm3
  xorps  %xmm4,%xmm3
  divss  %xmm6,%xmm3
  movss  %xmm3,0x38(%rdi)
  movl   $0x3f800000,0x3c(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: byte[4]
name: disassemble_data
arguments: label: D1
data_type: byte[4]
name: disassemble_data
arguments: label: D16
data_type: byte[4]
name: disassemble_data
arguments: label: D26
data_type: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x80]}

tool: {"D1": [0x00,0x00,0x00,0x3f]}

tool: {"D16": [0x00,0x00,0x00,0x40]}

tool: {"D26": [0x00,0x00,0x00,0xc0]}

assistant: ```c
extern void warp_mat4_fill_orthographic(float *matrix, float width, float height, float near, float far) {
  const float left = -width / 2, right = width / 2;
  const float top = height / 2, bottom = -height / 2;
  const float tz = -(far + near) / (far - near);
  const float m00 = 2.0f / (right - left);
  const float m11 = 2.0f / (top - bottom);
  const float m22 = -2.0f / (far - near);
  matrix[0] = m00;
  matrix[1] = 0;
  matrix[2] = 0;
  matrix[3] = 0;
  matrix[4] = 0;
  matrix[5] = m11;
  matrix[6] = 0;
  matrix[7] = 0;
  matrix[8] = 0;
  matrix[9] = 0;
  matrix[10] = m22;
  matrix[11] = 0;
  matrix[12] = 0;
  matrix[13] = 0;
  matrix[14] = tz;
  matrix[15] = 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<warp_mat4_fill_orthographic>:
  endbr64
  movss  D39(%rip),%xmm4
  movss  D22(%rip),%xmm7
  movaps %xmm3,%xmm6
  addss  %xmm2,%xmm3
  xorps  %xmm4,%xmm0
  subss  %xmm2,%xmm6
  movq   $0x0,0x4(%rdi)
  mulss  %xmm7,%xmm0
  movq   $0x0,0xc(%rdi)
  mulss  %xmm7,%xmm1
  xorps  %xmm4,%xmm3
  movq   $0x0,0x18(%rdi)
  divss  %xmm6,%xmm3
  movq   $0x0,0x20(%rdi)
  movq   $0x0,0x2c(%rdi)
  movl   $0x0,0x34(%rdi)
  movaps %xmm0,%xmm5
  movl   $0x3f800000,0x3c(%rdi)
  addss  %xmm1,%xmm1
  xorps  %xmm4,%xmm5
  subss  %xmm0,%xmm5
  movss  D33(%rip),%xmm0
  movaps %xmm0,%xmm8
  divss  %xmm1,%xmm0
  movss  %xmm3,0x38(%rdi)
  divss  %xmm5,%xmm8
  movss  %xmm0,0x14(%rdi)
  movss  D18(%rip),%xmm0
  divss  %xmm6,%xmm0
  movss  %xmm8,(%rdi)
  movss  %xmm0,0x28(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D39
type_infered: byte[4]
name: retrieve_data
arguments: label: D22
type_infered: byte[4]
name: retrieve_data
arguments: label: D33
type_infered: byte[4]
name: retrieve_data
arguments: label: D18
type_infered: byte[4]

tool: {"D39": [0x00,0x00,0x00,0x80]}

tool: {"D22": [0x00,0x00,0x00,0x3f]}

tool: {"D33": [0x00,0x00,0x00,0x40]}

tool: {"D18": [0x00,0x00,0x00,0xc0]}

assistant: ```c
extern void warp_mat4_fill_orthographic(float *matrix, float width, float height, float near, float far) {
  const float left = -width / 2, right = width / 2;
  const float top = height / 2, bottom = -height / 2;
  const float tz = -(far + near) / (far - near);
  const float m00 = 2.0f / (right - left);
  const float m11 = 2.0f / (top - bottom);
  const float m22 = -2.0f / (far - near);
  matrix[0] = m00;
  matrix[1] = 0;
  matrix[2] = 0;
  matrix[3] = 0;
  matrix[4] = 0;
  matrix[5] = m11;
  matrix[6] = 0;
  matrix[7] = 0;
  matrix[8] = 0;
  matrix[9] = 0;
  matrix[10] = m22;
  matrix[11] = 0;
  matrix[12] = 0;
  matrix[13] = 0;
  matrix[14] = tz;
  matrix[15] = 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<warp_mat4_fill_orthographic>:
  endbr64
  movss  D12(%rip),%xmm4
  movss  D38(%rip),%xmm7
  movaps %xmm3,%xmm6
  addss  %xmm2,%xmm3
  xorps  %xmm4,%xmm0
  subss  %xmm2,%xmm6
  movq   $0x0,0x4(%rdi)
  mulss  %xmm7,%xmm0
  movq   $0x0,0xc(%rdi)
  mulss  %xmm7,%xmm1
  xorps  %xmm4,%xmm3
  movq   $0x0,0x18(%rdi)
  divss  %xmm6,%xmm3
  movq   $0x0,0x20(%rdi)
  movq   $0x0,0x2c(%rdi)
  movl   $0x0,0x34(%rdi)
  movaps %xmm0,%xmm5
  movl   $0x3f800000,0x3c(%rdi)
  addss  %xmm1,%xmm1
  xorps  %xmm4,%xmm5
  subss  %xmm0,%xmm5
  movss  D7(%rip),%xmm0
  movaps %xmm0,%xmm8
  divss  %xmm1,%xmm0
  movss  %xmm3,0x38(%rdi)
  divss  %xmm5,%xmm8
  movss  %xmm0,0x14(%rdi)
  movss  D20(%rip),%xmm0
  divss  %xmm6,%xmm0
  movss  %xmm8,(%rdi)
  movss  %xmm0,0x28(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type_guessed: byte[4]
name: parse_data
arguments: tag: D38
type_guessed: byte[4]
name: parse_data
arguments: tag: D7
type_guessed: byte[4]
name: parse_data
arguments: tag: D20
type_guessed: byte[4]

tool: {"D12": [0x00,0x00,0x00,0x80]}

tool: {"D38": [0x00,0x00,0x00,0x3f]}

tool: {"D7": [0x00,0x00,0x00,0x40]}

tool: {"D20": [0x00,0x00,0x00,0xc0]}

assistant: ```c
extern void warp_mat4_fill_orthographic(float *matrix, float width, float height, float near, float far) {
  const float left = -width / 2, right = width / 2;
  const float top = height / 2, bottom = -height / 2;
  const float tz = -(far + near) / (far - near);
  const float m00 = 2.0f / (right - left);
  const float m11 = 2.0f / (top - bottom);
  const float m22 = -2.0f / (far - near);
  matrix[0] = m00;
  matrix[1] = 0;
  matrix[2] = 0;
  matrix[3] = 0;
  matrix[4] = 0;
  matrix[5] = m11;
  matrix[6] = 0;
  matrix[7] = 0;
  matrix[8] = 0;
  matrix[9] = 0;
  matrix[10] = m22;
  matrix[11] = 0;
  matrix[12] = 0;
  matrix[13] = 0;
  matrix[14] = tz;
  matrix[15] = 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<err_sys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void err_sys(char *msg) {
  perror(msg);
  exit(-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<err_sys>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void err_sys(char *msg) {
  perror(msg);
  exit(-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<err_sys>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err_sys(char *msg) {
  perror(msg);
  exit(-1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<err_sys>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err_sys(char *msg) {
  perror(msg);
  exit(-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdecode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L22
L44:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L35
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L35
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L35
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hexit@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hexit@plt>
  add    %ebx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x2,-0x20(%rbp)
  jmp    L57
L35:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L57:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L22:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void strdecode(char *to, const char *from) {
  for (; *from != '\0'; to++, from++) {
    if (from[0] == '%' && isxdigit(from[1]) && isxdigit(from[2])) {
      *to = hexit(from[1]) * 16 + hexit(from[2]);
      from += 2;
    } else {
      *to = *from;
    }
  }
  *to = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdecode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L19
L11:
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  movzbl (%rbx),%edx
  mov    %rbx,%rax
L3:
  mov    %dl,0x0(%rbp)
  add    $0x1,%rbp
  lea    0x1(%rax),%rbx
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L11
L19:
  cmp    $0x25,%al
  jne    L16
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L16
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L16
  movsbl 0x1(%rbx),%edi
  call   <hexit@plt>
  mov    %eax,%r12d
  movsbl 0x2(%rbx),%edi
  call   <hexit@plt>
  shl    $0x4,%r12d
  lea    (%r12,%rax,1),%edx
  lea    0x2(%rbx),%rax
  jmp    L3
```

assistant: ```c
void strdecode(char *to, const char *from) {
  for (; *from != '\0'; to++, from++) {
    if (from[0] == '%' && isxdigit(from[1]) && isxdigit(from[2])) {
      *to = hexit(from[1]) * 16 + hexit(from[2]);
      from += 2;
    } else {
      *to = *from;
    }
  }
  *to = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strdecode>:
  endbr64
  movzbl (%rsi),%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %al,%al
  je     L13
  mov    %rsi,%rbx
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rbx),%edx
  mov    %rbx,%rax
L22:
  mov    %dl,(%r12)
  lea    0x1(%rax),%rbx
  movzbl 0x1(%rax),%eax
  add    $0x1,%r12
  test   %al,%al
  je     L13
L28:
  cmp    $0x25,%al
  jne    L0
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L0
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L0
  movsbl 0x1(%rbx),%edi
  call   <hexit@plt>
  movsbl 0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <hexit@plt>
  shl    $0x4,%ebp
  lea    0x0(%rbp,%rax,1),%edx
  lea    0x2(%rbx),%rax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L13:
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

assistant: ```c
void strdecode(char *to, const char *from) {
  for (; *from != '\0'; to++, from++) {
    if (from[0] == '%' && isxdigit(from[1]) && isxdigit(from[2])) {
      *to = hexit(from[1]) * 16 + hexit(from[2]);
      from += 2;
    } else {
      *to = *from;
    }
  }
  *to = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdecode>:
  endbr64
  movzbl (%rsi),%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %al,%al
  je     L16
  mov    %rsi,%r12
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L78:
  mov    %r12,%rdx
L4:
  mov    %al,0x0(%rbp)
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rbp
  lea    0x1(%rdx),%r12
  test   %al,%al
  je     L16
L52:
  cmp    $0x25,%al
  jne    L78
  movsbl 0x1(%r12),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L21
L0:
  movzbl (%r12),%eax
  jmp    L78
  nopl   0x0(%rax)
L16:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  movsbl 0x2(%r12),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L0
  movsbl 0x1(%r12),%edi
  call   <hexit@plt>
  movsbl 0x2(%r12),%edi
  mov    %eax,%ebx
  call   <hexit@plt>
  shl    $0x4,%ebx
  lea    0x2(%r12),%rdx
  add    %ebx,%eax
  jmp    L4
```

assistant: ```c
void strdecode(char *to, const char *from) {
  for (; *from != '\0'; to++, from++) {
    if (from[0] == '%' && isxdigit(from[1]) && isxdigit(from[2])) {
      *to = hexit(from[1]) * 16 + hexit(from[2]);
      from += 2;
    } else {
      *to = *from;
    }
  }
  *to = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shift_in_move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x8,-0x4(%rbp)
  jle    L12
  mov    -0x18(%rbp),%rax
  lea    0x9(%rax),%rdx
  movzbl -0x1c(%rbp),%eax
  mov    %al,(%rdx)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int shift_in_move(char *delayedMoves, char newMove) {
  for (int i = 0; i < 9; i++) {
    delayedMoves[i] = delayedMoves[i + 1];
  }
  delayedMoves[9] = newMove;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shift_in_move>:
  endbr64
  mov    %rdi,%rax
  lea    0x9(%rdi),%rcx
L5:
  movzbl 0x1(%rax),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L5
  mov    %sil,0x9(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int shift_in_move(char *delayedMoves, char newMove) {
  for (int i = 0; i < 9; i++) {
    delayedMoves[i] = delayedMoves[i + 1];
  }
  delayedMoves[9] = newMove;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shift_in_move>:
  endbr64
  push   %rbx
  mov    $0x9,%edx
  mov    %esi,%ebx
  lea    0x1(%rdi),%rsi
  call   <memmove@plt>
  mov    %bl,0x9(%rax)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int shift_in_move(char *delayedMoves, char newMove) {
  for (int i = 0; i < 9; i++) {
    delayedMoves[i] = delayedMoves[i + 1];
  }
  delayedMoves[9] = newMove;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<shift_in_move>:
  endbr64
  push   %rbx
  mov    $0x9,%edx
  mov    %esi,%ebx
  lea    0x1(%rdi),%rsi
  call   <memmove@plt>
  mov    %bl,0x9(%rax)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int shift_in_move(char *delayedMoves, char newMove) {
  for (int i = 0; i < 9; i++) {
    delayedMoves[i] = delayedMoves[i + 1];
  }
  delayedMoves[9] = newMove;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getInteger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    -0xf(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <getLine@plt>
  jmp    L60
L133:
  cmpl   $0x0,-0x14(%rbp)
  je     L136
  cmpl   $0xa,-0x14(%rbp)
  je     L136
  cmpl   $0x0,-0x20(%rbp)
  jne    L13
  cmpl   $0x2d,-0x14(%rbp)
  jne    L13
  movl   $0x1,-0x1c(%rbp)
  jmp    L125
L13:
  cmpl   $0x0,-0x20(%rbp)
  jne    L143
  cmpl   $0x2b,-0x14(%rbp)
  je     L125
L143:
  subl   $0x30,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L71
  cmpl   $0x9,-0x14(%rbp)
  jle    L140
L71:
  mov    $0xfffea4c8,%eax
  jmp    L89
L140:
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
L125:
  addl   $0x1,-0x20(%rbp)
L60:
  mov    -0x20(%rbp),%eax
  cltq
  movzbl -0xf(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L136
  cmpl   $0x6,-0x20(%rbp)
  jle    L133
L136:
  cmpl   $0x1,-0x1c(%rbp)
  jne    L138
  negl   -0x18(%rbp)
L138:
  cmpl   $0xffffd8f1,-0x18(%rbp)
  jge    L16
  cmpl   $0xfffe7961,-0x18(%rbp)
  jne    L174
L16:
  cmpl   $0x270f,-0x18(%rbp)
  jle    L94
L174:
  mov    $0xfffea4c8,%eax
  jmp    L89
L94:
  mov    -0x18(%rbp),%eax
L89:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  leave
  ret
```

assistant: ```c
int getInteger() {
  char str[7];
  int c, i = 0, isNegative = 0, result = 0;
  getLine(str, 7);
  while (((c = str[i]) != EOF) && (i < 7)) {
    if (c == '\0' || c == '\n')
      break;
    if (i == 0 && c == '-')
      isNegative = 1;
    else if (i == 0 && c == '+')
      ;
    else {
      c -= 48;
      if (c < 0 || c > 9)
        return -88888;
      else
        result = (result * 10) + c;
    }
    i++;
  }
  if (isNegative == 1)
    result -= result + result;
  if ((result < -9999 && result != -99999) || (result > 9999))
    return -88888;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getInteger>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rdi
  mov    $0x7,%esi
  call   <getLine@plt>
  movsbl 0x1(%rsp),%eax
  mov    D8(%rip),%rdx
  mov    (%rdx),%r8d
  cmp    %r8d,%eax
  je     L120
  lea    0x2(%rsp),%rcx
  mov    $0x0,%esi
  mov    $0x0,%r9d
  mov    $0x0,%edx
  mov    $0x1,%r10d
  jmp    L148
L76:
  mov    %r10d,%r9d
L124:
  add    $0x1,%edx
  movsbl (%rcx),%eax
  add    $0x1,%rcx
  cmp    $0x6,%edx
  jg     L128
  cmp    %r8d,%eax
  je     L128
L148:
  test   %eax,%eax
  je     L128
  cmp    $0xa,%eax
  je     L128
  test   %edx,%edx
  sete   %dil
  cmp    $0x2d,%eax
  jne    L30
  test   %dil,%dil
  jne    L76
L30:
  cmp    $0x2b,%eax
  jne    L163
  test   %dil,%dil
  jne    L124
L163:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L36
  lea    (%rsi,%rsi,4),%esi
  lea    (%rax,%rsi,2),%esi
  jmp    L124
L128:
  mov    %esi,%eax
  neg    %eax
  cmp    $0x1,%r9d
  cmove  %eax,%esi
  cmp    $0xffffd8f1,%esi
  setl   %dl
  cmp    $0xfffe7961,%esi
  setne  %al
  test   %al,%dl
  jne    L123
  cmp    $0x270f,%esi
  jg     L123
L119:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  mov    %esi,%eax
  add    $0x18,%rsp
  ret
L123:
  mov    $0xfffea4c8,%esi
  jmp    L119
L120:
  mov    $0x0,%esi
  jmp    L119
L36:
  mov    $0xfffea4c8,%esi
  jmp    L119
L103:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInteger() {
  char str[7];
  int c, i = 0, isNegative = 0, result = 0;
  getLine(str, 7);
  while (((c = str[i]) != EOF) && (i < 7)) {
    if (c == '\0' || c == '\n')
      break;
    if (i == 0 && c == '-')
      isNegative = 1;
    else if (i == 0 && c == '+')
      ;
    else {
      c -= 48;
      if (c < 0 || c > 9)
        return -88888;
      else
        result = (result * 10) + c;
    }
    i++;
  }
  if (isNegative == 1)
    result -= result + result;
  if ((result < -9999 && result != -99999) || (result > 9999))
    return -88888;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getInteger>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x7,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rdi
  call   <getLine@plt>
  mov    D1(%rip),%rdx
  movsbl 0x1(%rsp),%eax
  mov    (%rdx),%esi
  cmp    %esi,%eax
  je     L81
  xor    %edx,%edx
  xor    %r8d,%r8d
  lea    0x2(%rsp),%rdi
  xor    %r9d,%r9d
  jmp    L186
  nopl   0x0(%rax)
L183:
  mov    $0x1,%r9d
L0:
  movsbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  cmp    %esi,%eax
  je     L189
L186:
  test   %eax,%eax
  je     L189
  cmp    $0xa,%eax
  je     L189
  test   %edx,%edx
  sete   %cl
  cmp    $0x2d,%eax
  jne    L14
  test   %cl,%cl
  jne    L183
L14:
  cmp    $0x2b,%eax
  jne    L83
  test   %cl,%cl
  jne    L0
L83:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L31
  lea    (%r8,%r8,4),%ecx
  lea    (%rax,%rcx,2),%r8d
  movsbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  cmp    %esi,%eax
  jne    L186
  xchg   %ax,%ax
L189:
  cmp    $0x1,%r9d
  je     L136
  cmp    $0x270f,%r8d
  jg     L31
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    %r8d,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L136:
  mov    %r8d,%eax
  neg    %eax
  cmp    $0x270f,%r8d
  jle    L26
  cmp    $0x1869f,%r8d
  jne    L31
L26:
  mov    %eax,%r8d
  jmp    L22
L31:
  mov    $0xfffea4c8,%r8d
  jmp    L22
L81:
  xor    %r8d,%r8d
  jmp    L22
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInteger() {
  char str[7];
  int c, i = 0, isNegative = 0, result = 0;
  getLine(str, 7);
  while (((c = str[i]) != EOF) && (i < 7)) {
    if (c == '\0' || c == '\n')
      break;
    if (i == 0 && c == '-')
      isNegative = 1;
    else if (i == 0 && c == '+')
      ;
    else {
      c -= 48;
      if (c < 0 || c > 9)
        return -88888;
      else
        result = (result * 10) + c;
    }
    i++;
  }
  if (isNegative == 1)
    result -= result + result;
  if ((result < -9999 && result != -99999) || (result > 9999))
    return -88888;
  return result;
}
```