ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<int_reverse_cmp>:
  endbr64
  mov    0x4(%rdi),%edx
  sub    0x4(%rsi),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  test   %edx,%edx
  mov    $0xffffffff,%edx
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int int_reverse_cmp(const void *a, const void *b) {
  int c = ((int *)a)[1] - ((int *)b)[1];
  return c > 0 ? -1 : (c < 0 ? 1 : 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<path_join>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  sub    $0x2,%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  cltq
  sub    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *path_join(const char *first, const char *second) {
  size_t flen = strlen(first);
  size_t slen = strlen(second);
  do {
    assert(flen <= SIZE_MAX - 2);
  } while (0);
  do {
    assert(flen + 2 <= SIZE_MAX - slen);
  } while (0);
  size_t len = flen + slen + 1;
  char *rv = malloc(len + 1);
  do {
    assert(rv != NULL);
  } while (0);
  memcpy(rv, first, flen);
  rv[flen] = '/';
  memcpy(rv + flen + 1, second, slen);
  rv[len] = '\0';
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<path_join>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    D4(%rip),%rbx
  mov    (%rbx),%eax
  sub    $0x2,%eax
  cltq
  cmp    %rbp,%rax
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x2(%rbp),%rdx
  movslq (%rbx),%rax
  sub    %r12,%rax
  cmp    %rax,%rdx
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x0(%rbp,%r12,1),%r15
  lea    0x2(%r15),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x2f,(%rbx,%rbp,1)
  lea    0x1(%rbx,%rbp,1),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
  movb   $0x0,0x1(%rbx,%r15,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *path_join(const char *first, const char *second) {
  size_t flen = strlen(first);
  size_t slen = strlen(second);
  do {
    assert(flen <= SIZE_MAX - 2);
  } while (0);
  do {
    assert(flen + 2 <= SIZE_MAX - slen);
  } while (0);
  size_t len = flen + slen + 1;
  char *rv = malloc(len + 1);
  do {
    assert(rv != NULL);
  } while (0);
  memcpy(rv, first, flen);
  rv[flen] = '/';
  memcpy(rv + flen + 1, second, slen);
  rv[len] = '\0';
  return rv;
}
```
user: What is the c source code of the assembly code below:

```asm
<path_join>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    D2(%rip),%r12
  xor    %edi,%edi
  mov    %rax,%r13
  mov    (%r12),%eax
  lea    (%rbx,%r13,1),%r15
  sub    $0x2,%eax
  cltq
  cmp    %rbx,%rax
  setae  %dil
  call   <assert@plt>
  movslq (%r12),%rax
  lea    0x2(%rbx),%rdx
  xor    %edi,%edi
  sub    %r13,%rax
  cmp    %rax,%rdx
  setbe  %dil
  call   <assert@plt>
  lea    0x2(%r15),%rdi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x2f,(%r12,%rbx,1)
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    0x1(%r12,%rbx,1),%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%r12,%r15,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *path_join(const char *first, const char *second) {
  size_t flen = strlen(first);
  size_t slen = strlen(second);
  do {
    assert(flen <= SIZE_MAX - 2);
  } while (0);
  do {
    assert(flen + 2 <= SIZE_MAX - slen);
  } while (0);
  size_t len = flen + slen + 1;
  char *rv = malloc(len + 1);
  do {
    assert(rv != NULL);
  } while (0);
  memcpy(rv, first, flen);
  rv[flen] = '/';
  memcpy(rv + flen + 1, second, slen);
  rv[len] = '\0';
  return rv;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<path_join>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    D4(%rip),%r12
  xor    %edi,%edi
  mov    %rax,%r13
  mov    (%r12),%eax
  lea    (%rbx,%r13,1),%r15
  sub    $0x2,%eax
  cltq
  cmp    %rbx,%rax
  setae  %dil
  call   <assert@plt>
  movslq (%r12),%rax
  lea    0x2(%rbx),%rdx
  xor    %edi,%edi
  sub    %r13,%rax
  cmp    %rax,%rdx
  setbe  %dil
  call   <assert@plt>
  lea    0x2(%r15),%rdi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x2f,(%r12,%rbx,1)
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    0x1(%r12,%rbx,1),%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%r12,%r15,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *path_join(const char *first, const char *second) {
  size_t flen = strlen(first);
  size_t slen = strlen(second);
  do {
    assert(flen <= SIZE_MAX - 2);
  } while (0);
  do {
    assert(flen + 2 <= SIZE_MAX - slen);
  } while (0);
  size_t len = flen + slen + 1;
  char *rv = malloc(len + 1);
  do {
    assert(rv != NULL);
  } while (0);
  memcpy(rv, first, flen);
  rv[flen] = '/';
  memcpy(rv + flen + 1, second, slen);
  rv[len] = '\0';
  return rv;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pause_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L1:
  addl   $0x1,-0x4(%rbp)
L59:
  cmpl   $0xee6b27f,-0x4(%rbp)
  jle    L1
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  jmp    L45
L54:
  addl   $0x1,-0x4(%rbp)
L45:
  cmpl   $0x1dcd64ff,-0x4(%rbp)
  jle    L54
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  jmp    L62
L31:
  addl   $0x1,-0x4(%rbp)
L62:
  cmpl   $0x2cb4177f,-0x4(%rbp)
  jle    L31
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  jmp    L18
L53:
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x3178cb7f,-0x4(%rbp)
  jle    L53
  mov    $0xd,%edi
  call   <my_putchar@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pause_system() {
  int i;
  i = 0;
  while (i < 250000000)
    i++;
  my_putchar('.');
  while (i < 500000000)
    i++;
  my_putchar('.');
  while (i < 750000000)
    i++;
  my_putchar('.');
  while (i < 830000000)
    i++;
  my_putchar('\r');
  return (i);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pause_system>:
  endbr64
  push   %rbx
  mov    $0xee6b280,%eax
L37:
  sub    $0x1,%eax
  jne    L37
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  mov    $0xee6b280,%eax
L39:
  sub    $0x1,%eax
  jne    L39
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  mov    $0x1dcd6500,%ebx
L12:
  add    $0x1,%ebx
  cmp    $0x2cb41780,%ebx
  jne    L12
  mov    $0x2e,%edi
  call   <my_putchar@plt>
L21:
  add    $0x1,%ebx
  cmp    $0x3178cb80,%ebx
  jne    L21
  mov    $0xd,%edi
  call   <my_putchar@plt>
  mov    $0x3178cb80,%eax
  pop    %rbx
  ret
```

assistant: ```c
int pause_system() {
  int i;
  i = 0;
  while (i < 250000000)
    i++;
  my_putchar('.');
  while (i < 500000000)
    i++;
  my_putchar('.');
  while (i < 750000000)
    i++;
  my_putchar('.');
  while (i < 830000000)
    i++;
  my_putchar('\r');
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pause_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  mov    $0xd,%edi
  call   <my_putchar@plt>
  mov    $0x3178cb80,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pause_system() {
  int i;
  i = 0;
  while (i < 250000000)
    i++;
  my_putchar('.');
  while (i < 500000000)
    i++;
  my_putchar('.');
  while (i < 750000000)
    i++;
  my_putchar('.');
  while (i < 830000000)
    i++;
  my_putchar('\r');
  return (i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pause_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  mov    $0x2e,%edi
  call   <my_putchar@plt>
  mov    $0xd,%edi
  call   <my_putchar@plt>
  mov    $0x3178cb80,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pause_system() {
  int i;
  i = 0;
  while (i < 250000000)
    i++;
  my_putchar('.');
  while (i < 500000000)
    i++;
  my_putchar('.');
  while (i < 750000000)
    i++;
  my_putchar('.');
  while (i < 830000000)
    i++;
  my_putchar('\r');
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sys_select>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x30(%rbp)
  je     L46
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L6
L46:
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
L6:
  mov    D8(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0x48(%rbp),%rdi
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <select@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L4
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  cmpq   $0x0,-0x38(%rbp)
  je     L30
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
L30:
  cmpq   $0x0,-0x40(%rbp)
  je     L4
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
L4:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int sys_select(int maxfd, fd_set *readfds, fd_set *writefds, fd_set *errorfds, struct timeval *tval) {
  int ret;
  fd_set *readfds2, readfds_buf;
  if (readfds) {
    readfds2 = readfds;
  } else {
    readfds2 = &readfds_buf;
    FD_ZERO(readfds2);
  }
  errno = 0;
  ret = select(maxfd, readfds2, writefds, errorfds, tval);
  if (ret <= 0) {
    FD_ZERO(readfds2);
    if (writefds)
      FD_ZERO(writefds);
    if (errorfds)
      FD_ZERO(errorfds);
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sys_select>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L15
L64:
  mov    D6(%rip),%rax
  movq   $0x0,(%rax)
  mov    %r14,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <select@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L38
L65:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  mov    %ebp,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  jmp    L64
L38:
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  test   %r13,%r13
  je     L5
  mov    %r13,%rdi
  call   <FD_ZERO@plt>
L5:
  test   %r12,%r12
  je     L65
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  jmp    L65
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_select(int maxfd, fd_set *readfds, fd_set *writefds, fd_set *errorfds, struct timeval *tval) {
  int ret;
  fd_set *readfds2, readfds_buf;
  if (readfds) {
    readfds2 = readfds;
  } else {
    readfds2 = &readfds_buf;
    FD_ZERO(readfds2);
  }
  errno = 0;
  ret = select(maxfd, readfds2, writefds, errorfds, tval);
  if (ret <= 0) {
    FD_ZERO(readfds2);
    if (writefds)
      FD_ZERO(writefds);
    if (errorfds)
      FD_ZERO(errorfds);
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sys_select>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L40
L34:
  mov    D4(%rip),%rax
  mov    %r12d,%edi
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  movq   $0x0,(%rax)
  call   <select@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L11
L67:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L11:
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  test   %r14,%r14
  je     L17
  mov    %r14,%rdi
  call   <FD_ZERO@plt>
L17:
  test   %r13,%r13
  je     L67
  mov    %r13,%rdi
  call   <FD_ZERO@plt>
  jmp    L67
  nopl   0x0(%rax)
L40:
  lea    0x14(%rsp),%rbp
  mov    %r8,0x8(%rsp)
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    0x8(%rsp),%r8
  jmp    L34
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_select(int maxfd, fd_set *readfds, fd_set *writefds, fd_set *errorfds, struct timeval *tval) {
  int ret;
  fd_set *readfds2, readfds_buf;
  if (readfds) {
    readfds2 = readfds;
  } else {
    readfds2 = &readfds_buf;
    FD_ZERO(readfds2);
  }
  errno = 0;
  ret = select(maxfd, readfds2, writefds, errorfds, tval);
  if (ret <= 0) {
    FD_ZERO(readfds2);
    if (writefds)
      FD_ZERO(writefds);
    if (errorfds)
      FD_ZERO(errorfds);
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sys_select>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L49
L4:
  mov    D3(%rip),%rax
  mov    %r12d,%edi
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  movq   $0x0,(%rax)
  call   <select@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L27
L50:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L27:
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  test   %r14,%r14
  je     L15
  mov    %r14,%rdi
  call   <FD_ZERO@plt>
L15:
  test   %r13,%r13
  je     L50
  mov    %r13,%rdi
  call   <FD_ZERO@plt>
  jmp    L50
  nopl   0x0(%rax)
L49:
  lea    0x14(%rsp),%rbp
  mov    %r8,0x8(%rsp)
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    0x8(%rsp),%r8
  jmp    L4
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_select(int maxfd, fd_set *readfds, fd_set *writefds, fd_set *errorfds, struct timeval *tval) {
  int ret;
  fd_set *readfds2, readfds_buf;
  if (readfds) {
    readfds2 = readfds;
  } else {
    readfds2 = &readfds_buf;
    FD_ZERO(readfds2);
  }
  errno = 0;
  ret = select(maxfd, readfds2, writefds, errorfds, tval);
  if (ret <= 0) {
    FD_ZERO(readfds2);
    if (writefds)
      FD_ZERO(writefds);
    if (errorfds)
      FD_ZERO(errorfds);
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L0:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L24
  lea    D8(%rip),%rax
  jmp    L1
L24:
  lea    D11(%rip),%rax
L1:
  mov    -0x4(%rbp),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x7f,-0x4(%rbp)
  jle    L0
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string
name: disassemble_data
arguments: data_tag: D11
type_infered: string
name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D8:     

tool: D11: not 

tool: D3: %c is %sdigit


assistant: ```c
int main() {
  int c;
  for (c = 0; c < 128; c++) {
    printf("%c is %sdigit\n", c, isdigit(c) ? "    " : "not ");
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
  lea    D3(%rip),%r12
  lea    D13(%rip),%rbp
L6:
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  mov    %r12,%rdx
  cmovne %r13,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    $0x80,%ebx
  jne    L6
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string

tool: D0:     

tool: D3: not 

tool: D13: %c is %sdigit


assistant: ```c
int main() {
  int c;
  for (c = 0; c < 128; c++) {
    printf("%c is %sdigit\n", c, isdigit(c) ? "    " : "not ");
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L2:
  mov    %ebx,%edi
  call   <isdigit@plt>
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  test   %rax,%rax
  cmovne %r12,%rdx
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x80,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D23
type: string
name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D20
type: string

tool: D23: %c is %sdigit


tool: D1:     

tool: D20: not 

assistant: ```c
int main() {
  int c;
  for (c = 0; c < 128; c++) {
    printf("%c is %sdigit\n", c, isdigit(c) ? "    " : "not ");
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L19:
  mov    %ebx,%edi
  call   <isdigit@plt>
  mov    %r12,%rdx
  test   %rax,%rax
  jne    L11
  mov    %r13,%rdx
L11:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x80,%ebx
  jne    L19
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D24
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D21: not 

tool: D24:     

tool: D4: %c is %sdigit


assistant: ```c
int main() {
  int c;
  for (c = 0; c < 128; c++) {
    printf("%c is %sdigit\n", c, isdigit(c) ? "    " : "not ");
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<starts_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D1: %s

assistant: ```c
int starts_with(char *str, char *word) {
  int len;
  char *first_word;
  len = strlen(str);
  first_word = (char *)malloc((len + 1) * sizeof(char));
  sscanf(str, "%s", first_word);
  return !strcmp(word, first_word);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<starts_with>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %s

assistant: ```c
int starts_with(char *str, char *word) {
  int len;
  char *first_word;
  len = strlen(str);
  first_word = (char *)malloc((len + 1) * sizeof(char));
  sscanf(str, "%s", first_word);
  return !strcmp(word, first_word);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<starts_with>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  lea    D1(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdx
  call   <sscanf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  pop    %rbp
  pop    %r12
  test   %eax,%eax
  pop    %r13
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string

tool: D1: %s

assistant: ```c
int starts_with(char *str, char *word) {
  int len;
  char *first_word;
  len = strlen(str);
  first_word = (char *)malloc((len + 1) * sizeof(char));
  sscanf(str, "%s", first_word);
  return !strcmp(word, first_word);
}
```