ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remove_rows>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rdx,%r12
  call   <calc_row@plt>
  mov    %eax,%r13d
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <calc_index@plt>
  mov    %eax,%ebx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <calc_index@plt>
  cmp    %eax,%ebx
  jge    L4
  movslq %ebx,%rcx
  lea    (%r12,%rcx,1),%rdx
  lea    0x1(%r12,%rcx,1),%rcx
  sub    $0x1,%eax
  sub    %ebx,%eax
  add    %rcx,%rax
  jmp    L26
L33:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L4
L26:
  cmpb   $0x71,(%rdx)
  je     L33
  movb   $0x2a,(%rdx)
  jmp    L33
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void remove_rows(int n, int index, char *board) {
  int row = calc_row(n, index);
  int col_start = calc_index(n, row, 0);
  int col_end = calc_index(n, row, n);
  for (int i = col_start; i < col_end; i++) {
    if (board[i] != 'q') {
      board[i] = '*';
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<remove_rows>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <calc_row@plt>
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <calc_index@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <calc_index@plt>
  cmp    %eax,%ebx
  jge    L25
  movslq %ebx,%rdx
  sub    $0x1,%eax
  lea    0x0(%r13,%rdx,1),%rcx
  sub    %ebx,%eax
  lea    0x1(%r13,%rdx,1),%rdx
  add    %rdx,%rax
  nopl   (%rax)
L6:
  cmpb   $0x71,(%rcx)
  je     L27
  movb   $0x2a,(%rcx)
L27:
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jne    L6
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void remove_rows(int n, int index, char *board) {
  int row = calc_row(n, index);
  int col_start = calc_index(n, row, 0);
  int col_end = calc_index(n, row, n);
  for (int i = col_start; i < col_end; i++) {
    if (board[i] != 'q') {
      board[i] = '*';
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_rows>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <calc_row@plt>
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <calc_index@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <calc_index@plt>
  cmp    %eax,%ebx
  jge    L14
  movslq %ebx,%rdx
  sub    $0x1,%eax
  lea    0x0(%r13,%rdx,1),%rcx
  sub    %ebx,%eax
  lea    0x1(%r13,%rdx,1),%rdx
  add    %rdx,%rax
  nopl   (%rax)
L27:
  cmpb   $0x71,(%rcx)
  je     L19
  movb   $0x2a,(%rcx)
L19:
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jne    L27
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void remove_rows(int n, int index, char *board) {
  int row = calc_row(n, index);
  int col_start = calc_index(n, row, 0);
  int col_end = calc_index(n, row, n);
  for (int i = col_start; i < col_end; i++) {
    if (board[i] != 'q') {
      board[i] = '*';
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<call3a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void call3a(char *cp, short *sp, int *ip, long *lp) {
  cp = 0;
  sp = 0;
  ip = 0;
  lp = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<call3a>:
  endbr64
  ret
```

assistant: ```c
void call3a(char *cp, short *sp, int *ip, long *lp) {
  cp = 0;
  sp = 0;
  ip = 0;
  lp = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call3a>:
  endbr64
  ret
```

assistant: ```c
void call3a(char *cp, short *sp, int *ip, long *lp) {
  cp = 0;
  sp = 0;
  ip = 0;
  lp = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<call3a>:
  endbr64
  ret
```

assistant: ```c
void call3a(char *cp, short *sp, int *ip, long *lp) {
  cp = 0;
  sp = 0;
  ip = 0;
  lp = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L16:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_strlen(const char *str) {
  int i;
  i = 0;
  while (*str++) {
    i++;
  }
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strlen>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L9
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L4:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L4
L14:
  mov    %ecx,%eax
  ret
L9:
  mov    $0x0,%ecx
  jmp    L14
```

assistant: ```c
int ft_strlen(const char *str) {
  int i;
  i = 0;
  while (*str++) {
    i++;
  }
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L11
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L2:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L2
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strlen(const char *str) {
  int i;
  i = 0;
  while (*str++) {
    i++;
  }
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L16
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L14:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L14
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strlen(const char *str) {
  int i;
  i = 0;
  while (*str++) {
    i++;
  }
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tokenizeEnvVar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <theNshMalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L4:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
L13:
  cmpq   $0x0,-0x10(%rbp)
  jne    L4
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7: !

assistant: ```c
char **tokenizeEnvVar(char *givenVar, char **values) {
  char *varCopy = (char *)theNshMalloc((int)(strlen(givenVar) + 1));
  strcpy(varCopy, givenVar);
  char *temp = strtok(varCopy, "!");
  int i = 0;
  while (temp != NULL) {
    values[i++] = temp;
    temp = strtok(NULL, "!");
  }
  values[i] = (char *)NULL;
  return values;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tokenizeEnvVar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <theNshMalloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L1
  mov    $0x1,%ebx
  lea    D5(%rip),%r13
L8:
  mov    %ebx,%r12d
  mov    %rax,-0x8(%rbp,%rbx,8)
  mov    %r13,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L8
L22:
  movslq %r12d,%r12
  movq   $0x0,0x0(%rbp,%r12,8)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    $0x0,%r12d
  jmp    L22
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: !

assistant: ```c
char **tokenizeEnvVar(char *givenVar, char **values) {
  char *varCopy = (char *)theNshMalloc((int)(strlen(givenVar) + 1));
  strcpy(varCopy, givenVar);
  char *temp = strtok(varCopy, "!");
  int i = 0;
  while (temp != NULL) {
    values[i++] = temp;
    temp = strtok(NULL, "!");
  }
  values[i] = (char *)NULL;
  return values;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tokenizeEnvVar>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <theNshMalloc@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rbp
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L0
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rax,-0x8(%r12,%rbx,8)
  mov    %rbp,%rsi
  xor    %edi,%edi
  movslq %ebx,%r13
  add    $0x1,%rbx
  call   <strtok@plt>
  test   %rax,%rax
  jne    L2
  lea    (%r12,%r13,8),%rax
L26:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  mov    %r12,%rax
  jmp    L26
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: !

assistant: ```c
char **tokenizeEnvVar(char *givenVar, char **values) {
  char *varCopy = (char *)theNshMalloc((int)(strlen(givenVar) + 1));
  strcpy(varCopy, givenVar);
  char *temp = strtok(varCopy, "!");
  int i = 0;
  while (temp != NULL) {
    values[i++] = temp;
    temp = strtok(NULL, "!");
  }
  values[i] = (char *)NULL;
  return values;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tokenizeEnvVar>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <theNshMalloc@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rbp
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L19
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rax,-0x8(%r12,%rbx,8)
  mov    %rbp,%rsi
  xor    %edi,%edi
  movslq %ebx,%r13
  add    $0x1,%rbx
  call   <strtok@plt>
  test   %rax,%rax
  jne    L20
  lea    (%r12,%r13,8),%rax
L29:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  mov    %r12,%rax
  jmp    L29
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: !

assistant: ```c
char **tokenizeEnvVar(char *givenVar, char **values) {
  char *varCopy = (char *)theNshMalloc((int)(strlen(givenVar) + 1));
  strcpy(varCopy, givenVar);
  char *temp = strtok(varCopy, "!");
  int i = 0;
  while (temp != NULL) {
    values[i++] = temp;
    temp = strtok(NULL, "!");
  }
  values[i] = (char *)NULL;
  return values;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D9
type: string

tool: D10: %s: 	

tool: D9: %7.3f 

assistant: ```c
void print_array(const char *name, float *arr, int d1) {
  int i;
  printf("%s: \t", name);
  for (i = 0; i < d1; i++)
    printf("%7.3f ", arr[i]);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %rdi,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L16
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D19(%rip),%rbp
L12:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L12
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D19
type_infered: string

tool: D14: %s: 	

tool: D19: %7.3f 

assistant: ```c
void print_array(const char *name, float *arr, int d1) {
  int i;
  printf("%s: \t", name);
  for (i = 0; i < d1; i++)
    printf("%7.3f ", arr[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_array>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L8
  lea    -0x1(%rbp),%eax
  lea    D15(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L19:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  cvtss2sd -0x4(%rbx),%xmm0
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
L8:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string
name: extract_symbolic_data
arguments: tag: D15
type: string

tool: D3: %s: 	

tool: D15: %7.3f 

assistant: ```c
void print_array(const char *name, float *arr, int d1) {
  int i;
  printf("%s: \t", name);
  for (i = 0; i < d1; i++)
    printf("%7.3f ", arr[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_array>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L10
  lea    -0x1(%rbp),%eax
  lea    D6(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L3:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  cvtss2sd -0x4(%rbx),%xmm0
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
L10:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D6
type: string

tool: D9: %s: 	

tool: D6: %7.3f 

assistant: ```c
void print_array(const char *name, float *arr, int d1) {
  int i;
  printf("%s: \t", name);
  for (i = 0; i < d1; i++)
    printf("%7.3f ", arr[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fnv_64a_64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1b3,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1b3,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1b3,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1b3,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x20,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  movzbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1b3,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x28,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  movzbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1b3,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x30,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  movzbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1b3,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x38,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  movzbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1b3,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t fnv_64a_64(uint64_t oid, uint64_t hval) {
  hval ^= oid & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 8 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 16 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 24 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 32 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 40 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 48 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 56 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  return hval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fnv_64a_64>:
  endbr64
  mov    %edi,%eax
  movzbl %dil,%edx
  xor    %esi,%edx
  imul   $0x1b3,%edx,%edx
  movzbl %ah,%ecx
  xor    %edx,%ecx
  imul   $0x1b3,%ecx,%ecx
  mov    %edi,%edx
  sar    $0x10,%edx
  movzbl %dl,%edx
  xor    %ecx,%edx
  imul   $0x1b3,%edx,%edx
  mov    %edi,%ecx
  shr    $0x18,%ecx
  xor    %edx,%ecx
  imul   $0x1b3,%ecx,%edi
  mov    %eax,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  movzbl %dl,%edx
  xor    %edi,%edx
  imul   $0x1b3,%edx,%edx
  mov    %eax,%esi
  mov    $0x28,%ecx
  sar    %cl,%esi
  movzbl %sil,%ecx
  xor    %edx,%ecx
  imul   $0x1b3,%ecx,%edi
  mov    %eax,%edx
  mov    $0x30,%ecx
  sar    %cl,%edx
  movzbl %dl,%edx
  xor    %edi,%edx
  imul   $0x1b3,%edx,%edx
  mov    $0x38,%ecx
  sar    %cl,%eax
  movzbl %al,%eax
  xor    %edx,%eax
  imul   $0x1b3,%eax,%eax
  ret
```

assistant: ```c
uint64_t fnv_64a_64(uint64_t oid, uint64_t hval) {
  hval ^= oid & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 8 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 16 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 24 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 32 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 40 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 48 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 56 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  return hval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fnv_64a_64>:
  endbr64
  movzbl %dil,%edx
  mov    %edi,%eax
  xor    %esi,%edx
  movzbl %ah,%ecx
  mov    %eax,%esi
  imul   $0x1b3,%edx,%edx
  xor    %edx,%ecx
  mov    %edi,%edx
  imul   $0x1b3,%ecx,%ecx
  sar    $0x10,%edx
  movzbl %dl,%edx
  xor    %ecx,%edx
  mov    %edi,%ecx
  imul   $0x1b3,%edx,%edx
  shr    $0x18,%ecx
  xor    %edx,%ecx
  mov    %eax,%edx
  imul   $0x1b3,%ecx,%edi
  mov    $0x20,%ecx
  sar    %cl,%edx
  mov    $0x28,%ecx
  movzbl %dl,%edx
  sar    %cl,%esi
  xor    %edi,%edx
  movzbl %sil,%ecx
  imul   $0x1b3,%edx,%edx
  xor    %edx,%ecx
  mov    %eax,%edx
  imul   $0x1b3,%ecx,%edi
  mov    $0x30,%ecx
  sar    %cl,%edx
  mov    $0x38,%ecx
  movzbl %dl,%edx
  sar    %cl,%eax
  xor    %edi,%edx
  movzbl %al,%eax
  imul   $0x1b3,%edx,%edx
  xor    %edx,%eax
  imul   $0x1b3,%eax,%eax
  ret
```

assistant: ```c
uint64_t fnv_64a_64(uint64_t oid, uint64_t hval) {
  hval ^= oid & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 8 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 16 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 24 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 32 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 40 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 48 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 56 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  return hval;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fnv_64a_64>:
  endbr64
  movzbl %dil,%edx
  mov    %edi,%eax
  xor    %esi,%edx
  movzbl %ah,%ecx
  mov    %eax,%esi
  imul   $0x1b3,%edx,%edx
  xor    %edx,%ecx
  mov    %edi,%edx
  imul   $0x1b3,%ecx,%ecx
  sar    $0x10,%edx
  movzbl %dl,%edx
  xor    %ecx,%edx
  mov    %edi,%ecx
  imul   $0x1b3,%edx,%edx
  shr    $0x18,%ecx
  xor    %edx,%ecx
  mov    %eax,%edx
  imul   $0x1b3,%ecx,%edi
  mov    $0x20,%ecx
  sar    %cl,%edx
  mov    $0x28,%ecx
  movzbl %dl,%edx
  sar    %cl,%esi
  xor    %edi,%edx
  movzbl %sil,%ecx
  imul   $0x1b3,%edx,%edx
  xor    %edx,%ecx
  mov    %eax,%edx
  imul   $0x1b3,%ecx,%edi
  mov    $0x30,%ecx
  sar    %cl,%edx
  mov    $0x38,%ecx
  movzbl %dl,%edx
  sar    %cl,%eax
  xor    %edi,%edx
  movzbl %al,%eax
  imul   $0x1b3,%edx,%edx
  xor    %edx,%eax
  imul   $0x1b3,%eax,%eax
  ret
```

assistant: ```c
uint64_t fnv_64a_64(uint64_t oid, uint64_t hval) {
  hval ^= oid & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 8 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 16 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 24 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 32 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 40 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 48 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  hval ^= oid >> 56 & 0xff;
  hval *= ((uint64_t)0x100000001b3ULL);
  return hval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ServerData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <ServerByte@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  leave
  ret
```

assistant: ```c
ServerData(buf, n) int n;
char *buf;
{
  int i;
  for (i = 0; i < n; i++)
    ServerByte(buf[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ServerData>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L10:
  movsbl (%rbx),%edi
  mov    $0x0,%eax
  call   <ServerByte@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  ret
```

assistant: ```c
ServerData(buf, n) int n;
char *buf;
{
  int i;
  for (i = 0; i < n; i++)
    ServerByte(buf[i]);
}
```