ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sieve_of_eratosthenes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    0x4(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %ebp,%ebp
  js     L129
  lea    0x1(%rbp),%edx
  lea    (%rax,%rdx,4),%rdx
L119:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L119
  movl   $0x0,(%rbx)
  movl   $0x0,0x4(%rbx)
  cmp    $0x1,%ebp
  jle    L108
L12:
  lea    0x1(%rbp),%r8d
  mov    $0x8,%edx
  mov    $0x4,%edi
  mov    $0x0,%r13d
  mov    $0x2,%eax
  jmp    L35
L25:
  add    $0x1,%eax
  add    $0x2,%edi
  add    $0x4,%rdx
  cmp    %r8d,%eax
  je     L40
L35:
  cmpl   $0x1,(%rdx,%rbx,1)
  jne    L25
  add    $0x1,%r13d
  mov    %edi,%ecx
  cmp    %edi,%ebp
  jl     L25
  movslq %edi,%rsi
  lea    (%rbx,%rsi,4),%rsi
L3:
  movl   $0x0,(%rsi)
  add    %eax,%ecx
  add    %rdx,%rsi
  cmp    %ecx,%ebp
  jge    L3
  jmp    L25
L5:
  add    $0x1,%eax
  add    $0x4,%rbx
  cmp    %eax,%ebp
  jl     L149
L11:
  cmpl   $0x1,(%rbx)
  jne    L5
  movslq %edx,%rsi
  mov    (%r12),%rcx
  mov    %eax,(%rcx,%rsi,4)
  lea    0x1(%rdx),%edx
  jmp    L5
L40:
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
L24:
  mov    $0x0,%edx
  mov    $0x0,%eax
  jmp    L11
L129:
  movl   $0x0,(%rax)
  movl   $0x0,0x4(%rax)
  cmp    $0x1,%ebp
  jg     L12
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    $0x0,%r13d
L149:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L108:
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    $0x0,%r13d
  jmp    L24
```

assistant: ```c
int sieve_of_eratosthenes(int **primes, const int max) {
  int *isPrime = (int *)malloc(sizeof(int) * (max + 1));
  int i;
  for (i = 0; i <= max; ++i)
    isPrime[i] = 1;
  isPrime[0] = 0;
  isPrime[1] = 0;
  int count = 0;
  for (i = 2; i <= max; ++i) {
    if (isPrime[i] == 1) {
      ++count;
      int j;
      for (j = 2 * i; j <= max; j += i)
        isPrime[j] = 0;
    }
  }
  *primes = (int *)malloc(sizeof(int) * count);
  int j = 0;
  for (i = 0; i <= max; ++i) {
    if (isPrime[i] == 1) {
      (*primes)[j++] = i;
    }
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sieve_of_eratosthenes>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x4(,%rsi,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  js     L26
  movslq %r12d,%rdx
  lea    0x4(%rax,%rdx,4),%rdx
  nopl   0x0(%rax)
L59:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L59
  movq   $0x0,0x0(%rbp)
  cmp    $0x1,%r12d
  jle    L6
  mov    $0x8,%eax
  mov    $0x4,%edi
  xor    %r13d,%r13d
  mov    $0x2,%edx
  jmp    L41
  nopl   (%rax)
L92:
  lea    0x1(%rdx),%ecx
  add    $0x2,%edi
  add    $0x4,%rax
  cmp    %edx,%r12d
  je     L55
L105:
  mov    %ecx,%edx
L41:
  cmpl   $0x1,0x0(%rbp,%rax,1)
  jne    L92
  add    $0x1,%r13d
  mov    %edi,%ecx
  cmp    %edi,%r12d
  jl     L92
  movslq %edi,%rsi
  lea    0x0(%rbp,%rsi,4),%rsi
  nopl   0x0(%rax,%rax,1)
L40:
  add    %edx,%ecx
  movl   $0x0,(%rsi)
  add    %rax,%rsi
  cmp    %ecx,%r12d
  jge    L40
  lea    0x1(%rdx),%ecx
  add    $0x2,%edi
  add    $0x4,%rax
  cmp    %edx,%r12d
  jne    L105
  nop
L55:
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
L62:
  mov    %rbp,%rcx
  xor    %esi,%esi
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L48:
  cmpl   $0x1,(%rcx)
  jne    L90
  movslq %esi,%rdi
  add    $0x1,%esi
  mov    %edx,(%rax,%rdi,4)
L90:
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%r12d
  jge    L48
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  movq   $0x0,(%rax)
  xor    %edi,%edi
  xor    %r13d,%r13d
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  xor    %edi,%edi
  xor    %r13d,%r13d
  call   <malloc@plt>
  mov    %rax,(%rbx)
  jmp    L62
```

assistant: ```c
int sieve_of_eratosthenes(int **primes, const int max) {
  int *isPrime = (int *)malloc(sizeof(int) * (max + 1));
  int i;
  for (i = 0; i <= max; ++i)
    isPrime[i] = 1;
  isPrime[0] = 0;
  isPrime[1] = 0;
  int count = 0;
  for (i = 2; i <= max; ++i) {
    if (isPrime[i] == 1) {
      ++count;
      int j;
      for (j = 2 * i; j <= max; j += i)
        isPrime[j] = 0;
    }
  }
  *primes = (int *)malloc(sizeof(int) * count);
  int j = 0;
  for (i = 0; i <= max; ++i) {
    if (isPrime[i] == 1) {
      (*primes)[j++] = i;
    }
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sieve_of_eratosthenes>:
  endbr64
  push   %r13
  lea    0x1(%rsi),%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%r13,4),%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r12d,%r12d
  js     L158
  cmp    $0x2,%r12d
  jle    L153
  mov    %r13d,%edx
  movdqa D9(%rip),%xmm0
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %rax,%rdx
L80:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L80
  mov    %r13d,%eax
  and    $0xfffffffc,%eax
  and    $0x3,%r13d
  je     L101
L99:
  movslq %eax,%rdx
  movl   $0x1,(%rbx,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jl     L101
  add    $0x2,%eax
  movl   $0x1,0x4(%rbx,%rcx,1)
  cmp    %r12d,%eax
  jg     L101
  movl   $0x1,0x8(%rbx,%rcx,1)
L101:
  movq   $0x0,(%rbx)
  cmp    $0x1,%r12d
  jle    L120
  mov    $0x8,%eax
  mov    $0x4,%edi
  xor    %r13d,%r13d
  mov    $0x2,%edx
  jmp    L7
  nop
L49:
  lea    0x1(%rdx),%ecx
  add    $0x2,%edi
  add    $0x4,%rax
  cmp    %edx,%r12d
  je     L110
L58:
  mov    %ecx,%edx
L7:
  cmpl   $0x1,(%rbx,%rax,1)
  jne    L49
  add    $0x1,%r13d
  mov    %edi,%ecx
  cmp    %edi,%r12d
  jl     L49
  movslq %edi,%rsi
  lea    (%rbx,%rsi,4),%rsi
  nopl   0x0(%rax)
L11:
  add    %edx,%ecx
  movl   $0x0,(%rsi)
  add    %rax,%rsi
  cmp    %ecx,%r12d
  jge    L11
  lea    0x1(%rdx),%ecx
  add    $0x2,%edi
  add    $0x4,%rax
  cmp    %edx,%r12d
  jne    L58
  nop
L110:
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
L14:
  mov    %rbx,%rcx
  xor    %esi,%esi
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L113:
  cmpl   $0x1,(%rcx)
  jne    L97
  movslq %esi,%rdi
  add    $0x1,%esi
  mov    %edx,(%rax,%rdi,4)
L97:
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%r12d
  jge    L113
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L158:
  movq   $0x0,(%rax)
  xor    %edi,%edi
  xor    %r13d,%r13d
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L153:
  xor    %eax,%eax
  jmp    L99
L120:
  xor    %edi,%edi
  xor    %r13d,%r13d
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  jmp    L14
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: byte[16]

tool: {"D9": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int sieve_of_eratosthenes(int **primes, const int max) {
  int *isPrime = (int *)malloc(sizeof(int) * (max + 1));
  int i;
  for (i = 0; i <= max; ++i)
    isPrime[i] = 1;
  isPrime[0] = 0;
  isPrime[1] = 0;
  int count = 0;
  for (i = 2; i <= max; ++i) {
    if (isPrime[i] == 1) {
      ++count;
      int j;
      for (j = 2 * i; j <= max; j += i)
        isPrime[j] = 0;
    }
  }
  *primes = (int *)malloc(sizeof(int) * count);
  int j = 0;
  for (i = 0; i <= max; ++i) {
    if (isPrime[i] == 1) {
      (*primes)[j++] = i;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L10:
  mov    $0x3e8,%edi
  call   <usleep@plt>
L12:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <check@plt>
  test   %rax,%rax
  jne    L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void loop(void) {
  int a = 0;
  while (check(a)) {
    usleep(1000);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
  jmp    L10
L18:
  mov    $0x3e8,%edi
  call   <usleep@plt>
L10:
  mov    $0x0,%edi
  call   <check@plt>
  test   %rax,%rax
  jne    L18
  add    $0x8,%rsp
  ret
```

assistant: ```c
void loop(void) {
  int a = 0;
  while (check(a)) {
    usleep(1000);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x3e8,%edi
  call   <usleep@plt>
L14:
  xor    %edi,%edi
  call   <check@plt>
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  ret
```

assistant: ```c
void loop(void) {
  int a = 0;
  while (check(a)) {
    usleep(1000);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0x3e8,%edi
  call   <usleep@plt>
L17:
  xor    %edi,%edi
  call   <check@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  ret
```

assistant: ```c
void loop(void) {
  int a = 0;
  while (check(a)) {
    usleep(1000);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bm_graypixel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9(%rbp),%rcx
  lea    -0xa(%rbp),%rdx
  lea    -0xb(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <bm_get_rgb@plt>
  movzbl -0xb(%rbp),%eax
  movzbl %al,%eax
  imul   $0x84e,%eax,%edx
  movzbl -0xa(%rbp),%eax
  movzbl %al,%eax
  imul   $0x1bf0,%eax,%eax
  add    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  imul   $0x2d2,%eax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x68db8bad,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xc,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
unsigned int bm_graypixel(unsigned int c) {
  unsigned char R, G, B;
  bm_get_rgb(c, &R, &G, &B);
  return (2126 * R + 7152 * G + 722 * B) / 10000;
}
```
user: What is the c source code of the assembly code below?

```asm
<bm_graypixel>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rcx
  lea    0x6(%rsp),%rdx
  lea    0x5(%rsp),%rsi
  call   <bm_get_rgb@plt>
  movzbl 0x5(%rsp),%eax
  imul   $0x84e,%eax,%eax
  movzbl 0x6(%rsp),%edx
  imul   $0x1bf0,%edx,%edx
  add    %edx,%eax
  movzbl 0x7(%rsp),%edx
  imul   $0x2d2,%edx,%edx
  add    %edx,%eax
  cltq
  imul   $0x68db8bad,%rax,%rax
  sar    $0x2c,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int bm_graypixel(unsigned int c) {
  unsigned char R, G, B;
  bm_get_rgb(c, &R, &G, &B);
  return (2126 * R + 7152 * G + 722 * B) / 10000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bm_graypixel>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdx
  lea    0x7(%rsp),%rcx
  lea    0x5(%rsp),%rsi
  call   <bm_get_rgb@plt>
  movzbl 0x5(%rsp),%eax
  movzbl 0x6(%rsp),%edx
  imul   $0x84e,%eax,%eax
  imul   $0x1bf0,%edx,%edx
  add    %edx,%eax
  movzbl 0x7(%rsp),%edx
  imul   $0x2d2,%edx,%edx
  add    %edx,%eax
  mov    $0xd1b71759,%edx
  imul   %rdx,%rax
  shr    $0x2d,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int bm_graypixel(unsigned int c) {
  unsigned char R, G, B;
  bm_get_rgb(c, &R, &G, &B);
  return (2126 * R + 7152 * G + 722 * B) / 10000;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bm_graypixel>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdx
  lea    0x7(%rsp),%rcx
  lea    0x5(%rsp),%rsi
  call   <bm_get_rgb@plt>
  movzbl 0x5(%rsp),%eax
  movzbl 0x6(%rsp),%edx
  imul   $0x84e,%eax,%eax
  imul   $0x1bf0,%edx,%edx
  add    %edx,%eax
  movzbl 0x7(%rsp),%edx
  imul   $0x2d2,%edx,%edx
  add    %edx,%eax
  mov    $0xd1b71759,%edx
  imul   %rdx,%rax
  shr    $0x2d,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int bm_graypixel(unsigned int c) {
  unsigned char R, G, B;
  bm_get_rgb(c, &R, &G, &B);
  return (2126 * R + 7152 * G + 722 * B) / 10000;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<EEPROMBlockProtectSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x400af004,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x400af030,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
L1:
  mov    $0x400af018,%eax
  mov    (%rax),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L1
  mov    $0x400af018,%eax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t EEPROMBlockProtectSet(uint32_t ui32Block, uint32_t ui32Protect) {
  ;
  (*((volatile unsigned long *)(0x400AF004))) = ui32Block;
  (*((volatile unsigned long *)(0x400AF030))) = ui32Protect;
  while ((*((volatile unsigned long *)(0x400AF018))) & 0x00000001) {
  }
  return ((*((volatile unsigned long *)(0x400AF018))));
}
```
user: What is the c source code of the assembly code below:

```asm
<EEPROMBlockProtectSet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x8(%rsp),%rax
  mov    %rax,0x400af004
  mov    -0x10(%rsp),%rax
  mov    %rax,0x400af030
L7:
  mov    0x400af018,%rax
  test   $0x1,%al
  jne    L7
  mov    0x400af018,%rax
  ret
```

assistant: ```c
uint32_t EEPROMBlockProtectSet(uint32_t ui32Block, uint32_t ui32Protect) {
  ;
  (*((volatile unsigned long *)(0x400AF004))) = ui32Block;
  (*((volatile unsigned long *)(0x400AF030))) = ui32Protect;
  while ((*((volatile unsigned long *)(0x400AF018))) & 0x00000001) {
  }
  return ((*((volatile unsigned long *)(0x400AF018))));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<EEPROMBlockProtectSet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x8(%rsp),%rax
  mov    %rax,0x400af004
  mov    -0x10(%rsp),%rax
  mov    %rax,0x400af030
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x400af018,%rax
  test   $0x1,%al
  jne    L7
  mov    0x400af018,%rax
  ret
```

assistant: ```c
uint32_t EEPROMBlockProtectSet(uint32_t ui32Block, uint32_t ui32Protect) {
  ;
  (*((volatile unsigned long *)(0x400AF004))) = ui32Block;
  (*((volatile unsigned long *)(0x400AF030))) = ui32Protect;
  while ((*((volatile unsigned long *)(0x400AF018))) & 0x00000001) {
  }
  return ((*((volatile unsigned long *)(0x400AF018))));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EEPROMBlockProtectSet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x8(%rsp),%rax
  mov    %rax,0x400af004
  mov    -0x10(%rsp),%rax
  mov    %rax,0x400af030
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x400af018,%rax
  test   $0x1,%al
  jne    L1
  mov    0x400af018,%rax
  ret
```

assistant: ```c
uint32_t EEPROMBlockProtectSet(uint32_t ui32Block, uint32_t ui32Protect) {
  ;
  (*((volatile unsigned long *)(0x400AF004))) = ui32Block;
  (*((volatile unsigned long *)(0x400AF030))) = ui32Protect;
  while ((*((volatile unsigned long *)(0x400AF018))) & 0x00000001) {
  }
  return ((*((volatile unsigned long *)(0x400AF018))));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alocaMatriz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  movl   $0x1,-0xc(%rbp)
  jmp    L16
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **alocaMatriz(int linhas, int colunas) {
  int i;
  int **matriz = malloc(linhas * sizeof(int *));
  matriz[0] = malloc(linhas * colunas * sizeof(int));
  for (i = 1; i < linhas; i++)
    matriz[i] = &matriz[0][i * colunas];
  return matriz;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alocaMatriz>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12d,%edi
  imul   %ebx,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  cmp    $0x1,%r12d
  jle    L9
  movslq %ebx,%rsi
  shl    $0x2,%rsi
  lea    0x8(%rbp),%rax
  lea    -0x2(%r12),%edx
  lea    0x10(%rbp,%rdx,8),%rdi
  mov    %rsi,%rdx
L15:
  mov    %rdx,%rcx
  add    0x0(%rbp),%rcx
  mov    %rcx,(%rax)
  add    %rsi,%rdx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L15
L9:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int **alocaMatriz(int linhas, int colunas) {
  int i;
  int **matriz = malloc(linhas * sizeof(int *));
  matriz[0] = malloc(linhas * colunas * sizeof(int));
  for (i = 1; i < linhas; i++)
    matriz[i] = &matriz[0][i * colunas];
  return matriz;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<alocaMatriz>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  shl    $0x3,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %ebp,%edi
  imul   %ebx,%edi
  mov    %rax,%r12
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  cmp    $0x1,%ebp
  jle    L19
  movslq %ebx,%rsi
  lea    -0x2(%rbp),%ecx
  lea    0x8(%r12),%rdx
  shl    $0x2,%rsi
  lea    0x10(%r12,%rcx,8),%rdi
  mov    %rsi,%rcx
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    (%r12),%rax
L3:
  add    %rcx,%rax
  add    $0x8,%rdx
  add    %rsi,%rcx
  mov    %rax,-0x8(%rdx)
  cmp    %rdi,%rdx
  jne    L8
L19:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int **alocaMatriz(int linhas, int colunas) {
  int i;
  int **matriz = malloc(linhas * sizeof(int *));
  matriz[0] = malloc(linhas * colunas * sizeof(int));
  for (i = 1; i < linhas; i++)
    matriz[i] = &matriz[0][i * colunas];
  return matriz;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pr_bytesmsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L3:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D19
datatype: string
name: read_data
arguments: tag: D0
datatype: string

tool: D19: %s

tool: D0: %02x

assistant: ```c
void pr_bytesmsg(const char *msg, unsigned char *bytes, size_t nbytes) {
  size_t i;
  printf("%s", msg);
  for (i = 0; i < nbytes; i++)
    printf("%02x", bytes[i]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pr_bytesmsg>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12,%r12
  je     L18
  mov    %rbp,%rbx
  add    %r12,%rbp
  lea    D13(%rip),%r12
L3:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L3
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D13
datatype: string

tool: D6: %s

tool: D13: %02x

assistant: ```c
void pr_bytesmsg(const char *msg, unsigned char *bytes, size_t nbytes) {
  size_t i;
  printf("%s", msg);
  for (i = 0; i < nbytes; i++)
    printf("%02x", bytes[i]);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pr_bytesmsg>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L17
  add    %rbx,%rbp
  lea    D14(%rip),%r12
  xchg   %ax,%ax
L12:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L12
L17:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string

tool: D7: %s

tool: D14: %02x

assistant: ```c
void pr_bytesmsg(const char *msg, unsigned char *bytes, size_t nbytes) {
  size_t i;
  printf("%s", msg);
  for (i = 0; i < nbytes; i++)
    printf("%02x", bytes[i]);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pr_bytesmsg>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L12
  add    %rbx,%rbp
  lea    D13(%rip),%r12
  xchg   %ax,%ax
L13:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L13
L12:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string

tool: D1: %s

tool: D13: %02x

assistant: ```c
void pr_bytesmsg(const char *msg, unsigned char *bytes, size_t nbytes) {
  size_t i;
  printf("%s", msg);
  for (i = 0; i < nbytes; i++)
    printf("%02x", bytes[i]);
  printf("\n");
}
```