ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x756e696c,0x3(%rsp)
  movb   $0x78,0x7(%rsp)
  cmp    $0x1,%edi
  jle    L37
  cmp    $0x2,%edi
  je     L42
  lea    D23(%rip),%rdi
  call   <printf@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  ret
L42:
  mov    0x8(%rsi),%rdi
  lea    0x3(%rsp),%r8
  mov    $0x5,%edx
  mov    %r8,%rsi
  call   <memcmp@plt>
  test   %eax,%eax
  jg     L7
  je     L40
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L40:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L37:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L7:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D33
type: string
name: parse_data
arguments: data_label: D12
type: string
name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D38
type: string

tool: D23: LESS!


tool: D33: TOO SOUR!


tool: D12: Just right!


tool: D3: MOAR!


tool: D38: TOO SPICEY!


assistant: ```c
void main(int argc, char *argv[]) {
  char answer[5] = "linux";
  if (argc < 2) {
    printf("MOAR!\n");
    return;
  }
  if (argc > 2) {
    printf("LESS!\n");
    return;
  }
  int comp = (memcmp(argv[1], answer, sizeof(answer)));
  if (comp > 0) {
    printf("TOO SPICEY!\n");
    return;
  }
  if (comp < 0) {
    printf("TOO SOUR!\n");
    return;
  }
  if (comp == 0) {
    printf("Just right!\n");
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x756e696c,0x3(%rsp)
  movb   $0x78,0x7(%rsp)
  cmp    $0x1,%edi
  jle    L12
  cmp    $0x2,%edi
  je     L39
  lea    D35(%rip),%rdi
  call   <printf@plt>
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L39:
  mov    0x8(%rsi),%rdi
  lea    0x3(%rsp),%r8
  mov    $0x5,%edx
  mov    %r8,%rsi
  call   <memcmp@plt>
  test   %eax,%eax
  jg     L13
  je     L69
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L69:
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L12:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L13:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D35
type_guessed: string
name: unpack_data
arguments: label: D4
type_guessed: string
name: unpack_data
arguments: label: D46
type_guessed: string
name: unpack_data
arguments: label: D13
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string

tool: D35: LESS!


tool: D4: TOO SOUR!


tool: D46: Just right!


tool: D13: MOAR!


tool: D5: TOO SPICEY!


assistant: ```c
void main(int argc, char *argv[]) {
  char answer[5] = "linux";
  if (argc < 2) {
    printf("MOAR!\n");
    return;
  }
  if (argc > 2) {
    printf("LESS!\n");
    return;
  }
  int comp = (memcmp(argv[1], answer, sizeof(answer)));
  if (comp > 0) {
    printf("TOO SPICEY!\n");
    return;
  }
  if (comp < 0) {
    printf("TOO SOUR!\n");
    return;
  }
  if (comp == 0) {
    printf("Just right!\n");
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L20:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L16
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L16
  mov    $0x1,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x2,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <hash@plt>
L16:
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x64,-0x4(%rbp)
  jle    L20
  nop
  nop
  leave
  ret
```

assistant: ```c
void test() {
  int i, j, k;
  for (i = 0; i <= 100; i++) {
    if ((i + 1) % 2 == 0) {
      if ((i + 1) % 3 == 0) {
        {
          hash(1);
          hash(i);
          hash(((i - 1) / 2));
          hash(((i - 2) / 3));
        };
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  jmp    L7
L19:
  cmp    $0x65,%ebx
  je     L33
L7:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %ebx,%edx
  and    $0x1,%edx
  or     %edx,%eax
  jne    L19
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  lea    -0x1(%rbp),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <hash@plt>
  sub    $0x2,%ebp
  movslq %ebp,%rdi
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rdi
  sar    $0x1f,%ebp
  sub    %ebp,%edi
  call   <hash@plt>
  jmp    L19
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test() {
  int i, j, k;
  for (i = 0; i <= 100; i++) {
    if ((i + 1) % 2 == 0) {
      if ((i + 1) % 3 == 0) {
        {
          hash(1);
          hash(i);
          hash(((i - 1) / 2));
          hash(((i - 2) / 3));
        };
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L34
  nopl   (%rax)
L19:
  cmp    $0x65,%ebx
  je     L17
L34:
  lea    0x1(%rbx),%eax
  mov    %ebx,%ebp
  mov    %rax,%rbx
  imul   %r12,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %ebx,%edx
  and    $0x1,%edx
  or     %edx,%eax
  jne    L19
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  lea    -0x1(%rbp),%edi
  sub    $0x2,%ebp
  sar    %edi
  call   <hash@plt>
  movslq %ebp,%rdi
  sar    $0x1f,%ebp
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rdi
  sub    %ebp,%edi
  call   <hash@plt>
  cmp    $0x65,%ebx
  jne    L34
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test() {
  int i, j, k;
  for (i = 0; i <= 100; i++) {
    if ((i + 1) % 2 == 0) {
      if ((i + 1) % 3 == 0) {
        {
          hash(1);
          hash(i);
          hash(((i - 1) / 2));
          hash(((i - 2) / 3));
        };
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L17
  nopl   (%rax)
L20:
  cmp    $0x65,%ebx
  je     L18
L17:
  lea    0x1(%rbx),%eax
  mov    %ebx,%ebp
  mov    %rax,%rbx
  imul   %r12,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %ebx,%edx
  and    $0x1,%edx
  or     %edx,%eax
  jne    L20
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  lea    -0x1(%rbp),%edi
  sub    $0x2,%ebp
  sar    %edi
  call   <hash@plt>
  movslq %ebp,%rdi
  sar    $0x1f,%ebp
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rdi
  sub    %ebp,%edi
  call   <hash@plt>
  cmp    $0x65,%ebx
  jne    L17
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test() {
  int i, j, k;
  for (i = 0; i <= 100; i++) {
    if ((i + 1) % 2 == 0) {
      if ((i + 1) % 3 == 0) {
        {
          hash(1);
          hash(i);
          hash(((i - 1) / 2));
          hash(((i - 2) / 3));
        };
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SCR_Strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L56:
  cmpq   $0x0,-0x8(%rbp)
  je     L63
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  jne    L63
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L63
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  je     L63
  addq   $0x2,-0x8(%rbp)
  jmp    L29
L63:
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int SCR_Strlen(const char *str) {
  const char *s = str;
  int count = 0;
  while (*s) {
    if ((s && *(s) == '^' && *((s) + 1) && *((s) + 1) != '^')) {
      s += 2;
    } else {
      count++;
      s++;
    }
  }
  return count;
}
```
user: What is the c source code of the assembly code below:

```asm
<SCR_Strlen>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L44
  mov    $0x0,%edx
  jmp    L56
L50:
  add    $0x1,%edx
  add    $0x1,%rdi
L9:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L66
L56:
  cmp    $0x5e,%al
  jne    L50
  test   %rdi,%rdi
  je     L50
  movzbl 0x1(%rdi),%eax
  cmp    $0x5e,%al
  je     L50
  test   %al,%al
  je     L50
  add    $0x2,%rdi
  jmp    L9
L44:
  mov    $0x0,%edx
L66:
  mov    %edx,%eax
  ret
```

assistant: ```c
int SCR_Strlen(const char *str) {
  const char *s = str;
  int count = 0;
  while (*s) {
    if ((s && *(s) == '^' && *((s) + 1) && *((s) + 1) != '^')) {
      s += 2;
    } else {
      count++;
      s++;
    }
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SCR_Strlen>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
L23:
  test   %al,%al
  je     L50
L58:
  movzbl 0x1(%rdi),%edx
  cmp    $0x5e,%al
  je     L33
L27:
  mov    %edx,%eax
  add    $0x1,%r8d
  add    $0x1,%rdi
  test   %al,%al
  jne    L58
L50:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  cmp    $0x5e,%dl
  je     L27
  test   %dl,%dl
  je     L27
  movzbl 0x2(%rdi),%eax
  add    $0x2,%rdi
  jmp    L23
```

assistant: ```c
int SCR_Strlen(const char *str) {
  const char *s = str;
  int count = 0;
  while (*s) {
    if ((s && *(s) == '^' && *((s) + 1) && *((s) + 1) != '^')) {
      s += 2;
    } else {
      count++;
      s++;
    }
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SCR_Strlen>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
L2:
  test   %al,%al
  je     L12
L31:
  movzbl 0x1(%rdi),%edx
  cmp    $0x5e,%al
  je     L16
L56:
  mov    %edx,%eax
  add    $0x1,%r8d
  add    $0x1,%rdi
  test   %al,%al
  jne    L31
L12:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  cmp    $0x5e,%dl
  je     L56
  test   %dl,%dl
  je     L56
  movzbl 0x2(%rdi),%eax
  add    $0x2,%rdi
  jmp    L2
```

assistant: ```c
int SCR_Strlen(const char *str) {
  const char *s = str;
  int count = 0;
  while (*s) {
    if ((s && *(s) == '^' && *((s) + 1) && *((s) + 1) != '^')) {
      s += 2;
    } else {
      count++;
      s++;
    }
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pnx833x_gpio_select_function_alt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1f,-0x4(%rbp)
  ja     L8
  mov    $0xb7e0f014,%eax
  mov    (%rax),%rsi
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  movslq %eax,%rdx
  mov    $0xb7e0f014,%eax
  or     %rsi,%rdx
  mov    %rdx,(%rax)
  jmp    L10
L8:
  mov    $0xb7e0f068,%eax
  mov    (%rax),%rsi
  mov    -0x4(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  movslq %eax,%rdx
  mov    $0xb7e0f068,%eax
  or     %rsi,%rdx
  mov    %rdx,(%rax)
L10:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pnx833x_gpio_select_function_alt(unsigned int pin) {
  if (pin < 32)
    do {
      ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF014))) |= (1 << (pin)));
    } while (0);
  else
    do {
      ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF068))) |= (1 << (pin & 31)));
    } while (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pnx833x_gpio_select_function_alt>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x1f,%edi
  ja     L1
  mov    $0xb7e0f014,%edx
  mov    (%rdx),%rsi
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  or     %rsi,%rax
  mov    %rax,(%rdx)
  ret
L1:
  mov    $0xb7e0f068,%edx
  mov    (%rdx),%rsi
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  or     %rsi,%rax
  mov    %rax,(%rdx)
  ret
```

assistant: ```c
void pnx833x_gpio_select_function_alt(unsigned int pin) {
  if (pin < 32)
    do {
      ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF014))) |= (1 << (pin)));
    } while (0);
  else
    do {
      ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF068))) |= (1 << (pin & 31)));
    } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pnx833x_gpio_select_function_alt>:
  endbr64
  mov    %edi,%ecx
  mov    $0xb7e0f014,%edx
  cmp    $0x1f,%edi
  jbe    L9
  mov    $0xb7e0f068,%edx
L9:
  mov    $0x1,%eax
  mov    (%rdx),%rsi
  shl    %cl,%eax
  cltq
  or     %rsi,%rax
  mov    %rax,(%rdx)
  ret
```

assistant: ```c
void pnx833x_gpio_select_function_alt(unsigned int pin) {
  if (pin < 32)
    do {
      ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF014))) |= (1 << (pin)));
    } while (0);
  else
    do {
      ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF068))) |= (1 << (pin & 31)));
    } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pnx833x_gpio_select_function_alt>:
  endbr64
  mov    %edi,%ecx
  mov    $0xb7e0f014,%edx
  cmp    $0x1f,%edi
  jbe    L0
  mov    $0xb7e0f068,%edx
L0:
  mov    $0x1,%eax
  mov    (%rdx),%rsi
  shl    %cl,%eax
  cltq
  or     %rsi,%rax
  mov    %rax,(%rdx)
  ret
```

assistant: ```c
void pnx833x_gpio_select_function_alt(unsigned int pin) {
  if (pin < 32)
    do {
      ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF014))) |= (1 << (pin)));
    } while (0);
  else
    do {
      ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF068))) |= (1 << (pin & 31)));
    } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<st_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L9
L14:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x18,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
L9:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L14
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
u_int st_hash(const char *name, size_t len, int tabsz) {
  u_int key = 0;
  assert((name != NULL));
  while (len--) {
    key += *name++;
    key = (key << 8) | (key >> 24);
  }
  return (key % tabsz);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<st_hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  je     L16
  lea    (%rbx,%r12,1),%rsi
  mov    $0x0,%eax
L10:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edx
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0x8,%eax
  sar    $0x18,%edx
  or     %edx,%eax
  cmp    %rbx,%rsi
  jne    L10
L23:
  cltd
  idiv   %ebp
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    $0x0,%eax
  jmp    L23
```

assistant: ```c
u_int st_hash(const char *name, size_t len, int tabsz) {
  u_int key = 0;
  assert((name != NULL));
  while (len--) {
    key += *name++;
    key = (key << 8) | (key >> 24);
  }
  return (key % tabsz);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<st_hash>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  je     L9
  lea    (%rbx,%r12,1),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%rbx),%edx
  add    $0x1,%rbx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x18,%edx
  shl    $0x8,%eax
  or     %edx,%eax
  cmp    %rsi,%rbx
  jne    L6
  cltd
  pop    %rbx
  idiv   %ebp
  pop    %rbp
  pop    %r12
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  ret
```

assistant: ```c
u_int st_hash(const char *name, size_t len, int tabsz) {
  u_int key = 0;
  assert((name != NULL));
  while (len--) {
    key += *name++;
    key = (key << 8) | (key >> 24);
  }
  return (key % tabsz);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<st_hash>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  je     L0
  lea    (%rbx,%r12,1),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  movsbl (%rbx),%edx
  add    $0x1,%rbx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x18,%edx
  shl    $0x8,%eax
  or     %edx,%eax
  cmp    %rsi,%rbx
  jne    L7
  cltd
  pop    %rbx
  idiv   %ebp
  pop    %rbp
  pop    %r12
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  ret
```

assistant: ```c
u_int st_hash(const char *name, size_t len, int tabsz) {
  u_int key = 0;
  assert((name != NULL));
  while (len--) {
    key += *name++;
    key = (key << 8) | (key >> 24);
  }
  return (key % tabsz);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_traverser>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %rcx,%r13
  call   <rtavl_t_prev@plt>
  test   %ebx,%ebx
  jne    L29
  mov    $0xffffffff,%ecx
  test   %rax,%rax
  je     L29
L30:
  mov    (%rax),%edx
L108:
  mov    %r13,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%r14d
L137:
  mov    %rbp,%rdi
  call   <rtavl_t_next@plt>
  mov    %rbp,%rdi
  call   <rtavl_t_cur@plt>
  test   %rax,%rax
  je     L54
  mov    (%rax),%edx
  cmp    %ebx,%edx
  je     L23
L96:
  mov    %ebx,%ecx
  mov    %r13,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%r14d
L23:
  mov    %rbp,%rdi
  call   <rtavl_t_next@plt>
  sub    $0x1,%r12d
  test   %rax,%rax
  je     L97
  cmp    %ebx,%r12d
  je     L39
L97:
  cmp    %ebx,%r12d
  je     L84
  test   %rax,%rax
  je     L74
  lea    0x1(%rbx),%edx
  cmp    %edx,(%rax)
  je     L84
  mov    %edx,%ecx
  test   %rax,%rax
  jne    L42
  mov    $0xffffffff,%edx
  jmp    L1
L29:
  mov    $0x1,%r14d
  test   %ebx,%ebx
  jle    L137
  test   %rax,%rax
  je     L73
  lea    -0x1(%rbx),%ecx
  cmp    %ecx,(%rax)
  jne    L30
  jmp    L137
L54:
  mov    $0xffffffff,%edx
  jmp    L96
L39:
  lea    0x1(%rbx),%edx
  mov    $0xffffffff,%ecx
  cmovne %edx,%ecx
L42:
  mov    (%rax),%edx
L1:
  mov    %r13,%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%r14d
L84:
  mov    %rbp,%rdi
  call   <rtavl_t_prev@plt>
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L73:
  lea    -0x1(%rbx),%ecx
  mov    $0xffffffff,%edx
  jmp    L108
L74:
  lea    0x1(%rbx),%ecx
  mov    $0xffffffff,%edx
  jmp    L1
```

tool_calls: name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D26
type: string

tool: D1:    %s traverser ahead of %d, but should be ahead of %d.


tool: D6:    %s traverser at %d, but should be at %d.


tool: D26:    %s traverser behind %d, but should be behind %d.


assistant: ```c
int check_traverser(struct rtavl_traverser *trav, int i, int n, const char *label) {
  int okay = 1;
  int *cur, *prev, *next;
  prev = rtavl_t_prev(trav);
  if ((i == 0 && prev != NULL) || (i > 0 && (prev == NULL || *prev != i - 1))) {
    printf("   %s traverser ahead of %d, but should be ahead of %d.\n", label, prev != NULL ? *prev : -1, i == 0 ? -1 : i - 1);
    okay = 0;
  }
  rtavl_t_next(trav);
  cur = rtavl_t_cur(trav);
  if (cur == NULL || *cur != i) {
    printf("   %s traverser at %d, but should be at %d.\n", label, cur != NULL ? *cur : -1, i);
    okay = 0;
  }
  next = rtavl_t_next(trav);
  if ((i == n - 1 && next != NULL) || (i != n - 1 && (next == NULL || *next != i + 1))) {
    printf("   %s traverser behind %d, but should be behind %d.\n", label, next != NULL ? *next : -1, i == n - 1 ? -1 : i + 1);
    okay = 0;
  }
  rtavl_t_prev(trav);
  return okay;
}
```