ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D34(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdx
  lea    0x14(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  cmp    %eax,%edx
  je     L4
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%eax
  je     L4
  cmp    %ecx,%edx
  jne    L37
L4:
  lea    D11(%rip),%rdi
  call   <printf@plt>
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L37:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D34
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string

tool: D34: Enter values of sides of triangle


tool: D28: %d%d%d

tool: D11: Isosceles triangle


tool: D12: Scalene triangle


assistant: ```c
int main() {
  int a, b, c;
  printf("Enter values of sides of triangle\n");
  scanf("%d%d%d", &a, &b, &c);
  if ((a == b) || (b == c) || (a == c)) {
    printf("Isosceles triangle\n");
  } else if ((a == b) && (b == c) && (c == a)) {
    printf("Equilateral and isosceles triangle\n");
  } else if ((a != b) && (b != c) && (c != a)) {
    printf("Scalene triangle\n");
  } else if ((b > a) && (b > c)) {
    if ((b * b) == ((a * a) + (c * c))) {
      printf("Right Triangle\n");
    } else
      printf("Not a right triangle\n");
  } else if ((a > b) && (a > c)) {
    if ((a * a) == ((b * b) + (c * c))) {
      printf("Right Triangle\n");
    } else
      printf("Not a right triangle\n");
  } else if ((c > a) && (c > b)) {
    if ((c * c) == ((a * a) + (b * b))) {
      printf("Right Triangle\n");
    } else
      printf("Not a right triangle\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdx
  lea    0x14(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  cmp    %eax,%edx
  je     L38
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%eax
  je     L38
  cmp    %ecx,%edx
  jne    L29
L38:
  lea    D37(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L29:
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D31
type_infered: string
name: read_data
arguments: tag: D38
type_infered: string
name: read_data
arguments: tag: D37
type_infered: string
name: read_data
arguments: tag: D35
type_infered: string

tool: D31: Enter values of sides of triangle


tool: D38: %d%d%d

tool: D37: Isosceles triangle


tool: D35: Scalene triangle


assistant: ```c
int main() {
  int a, b, c;
  printf("Enter values of sides of triangle\n");
  scanf("%d%d%d", &a, &b, &c);
  if ((a == b) || (b == c) || (a == c)) {
    printf("Isosceles triangle\n");
  } else if ((a == b) && (b == c) && (c == a)) {
    printf("Equilateral and isosceles triangle\n");
  } else if ((a != b) && (b != c) && (c != a)) {
    printf("Scalene triangle\n");
  } else if ((b > a) && (b > c)) {
    if ((b * b) == ((a * a) + (c * c))) {
      printf("Right Triangle\n");
    } else
      printf("Not a right triangle\n");
  } else if ((a > b) && (a > c)) {
    if ((a * a) == ((b * b) + (c * c))) {
      printf("Right Triangle\n");
    } else
      printf("Not a right triangle\n");
  } else if ((c > a) && (c > b)) {
    if ((c * c) == ((a * a) + (b * b))) {
      printf("Right Triangle\n");
    } else
      printf("Not a right triangle\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<new_encode_dev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0xff,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x14,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xfffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  shl    $0xc,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned new_encode_dev(dev_t dev) {
  unsigned v = 0xff;
  unsigned major = ((unsigned int)((dev) >> 20));
  unsigned minor = ((unsigned int)((dev) & ((1U << 20) - 1)));
  return (minor & 0xff) | (major << 8) | ((minor & ~v) << 12);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<new_encode_dev>:
  endbr64
  mov    %edi,%eax
  sar    $0x14,%eax
  shl    $0x8,%eax
  mov    %edi,%edx
  shl    $0xc,%edx
  and    $0xfff00000,%edx
  or     %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned new_encode_dev(dev_t dev) {
  unsigned v = 0xff;
  unsigned major = ((unsigned int)((dev) >> 20));
  unsigned minor = ((unsigned int)((dev) & ((1U << 20) - 1)));
  return (minor & 0xff) | (major << 8) | ((minor & ~v) << 12);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<new_encode_dev>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  movzbl %dil,%edi
  sar    $0x14,%eax
  shl    $0xc,%edx
  shl    $0x8,%eax
  and    $0xfff00000,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned new_encode_dev(dev_t dev) {
  unsigned v = 0xff;
  unsigned major = ((unsigned int)((dev) >> 20));
  unsigned minor = ((unsigned int)((dev) & ((1U << 20) - 1)));
  return (minor & 0xff) | (major << 8) | ((minor & ~v) << 12);
}
```
user: Translate the below assembly code into C programming language:

```asm
<new_encode_dev>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  movzbl %dil,%edi
  sar    $0x14,%eax
  shl    $0xc,%edx
  shl    $0x8,%eax
  and    $0xfff00000,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned new_encode_dev(dev_t dev) {
  unsigned v = 0xff;
  unsigned major = ((unsigned int)((dev) >> 20));
  unsigned minor = ((unsigned int)((dev) & ((1U << 20) - 1)));
  return (minor & 0xff) | (major << 8) | ((minor & ~v) << 12);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<C_mkIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  cmpq   $0x0,-0x58(%rbp)
  je     L20
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <C_mkOneLineComments@plt>
  jmp    L45
L20:
  mov    $0x0,%eax
L45:
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <C_mkIndexName@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x50(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <C_mkAssign@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L3
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  jmp    L19
L3:
  mov    $0x0,%ebx
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x5,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmpq   $0x0,-0x38(%rbp)
  je     L14
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L14:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string

tool: D18:     

tool: D17: 


assistant: ```c
char *C_mkIndex(char *name, char *indexNum, char *comments) {
  char *commentText = (comments) ? C_mkOneLineComments(comments) : NULL;
  char *varName = C_mkIndexName(name);
  char *assign = C_mkAssign(varName, indexNum);
  size_t length = ((commentText) ? strlen(commentText) + strlen("    ") : 0) + strlen(assign) + strlen("    ") + 5;
  char *index = UTIL_mallocStr(length);
  free(varName);
  strcpy(index, "    ");
  if (commentText) {
    strcat(index, commentText);
    strcat(index, "\n");
    strcat(index, "    ");
    free(commentText);
  }
  strcat(index, assign);
  free(assign);
  return index;
}
```
user: Translate the below assembly code into C programming language:

```asm
<C_mkIndex>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdx,%rdx
  je     L19
  mov    %rdx,%rdi
  call   <C_mkOneLineComments@plt>
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <C_mkIndexName@plt>
  mov    %rax,%r12
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <C_mkAssign@plt>
  mov    %rax,%rbp
  test   %r13,%r13
  je     L8
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    D21(%rip),%r14
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x5(%rbx,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D26(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r13,%rdi
  call   <free@plt>
L17:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <C_mkIndexName@plt>
  mov    %rax,%r12
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <C_mkAssign@plt>
  mov    %rax,%rbp
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    D21(%rip),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x5(%rbx,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string

tool: D21:     

tool: D26: 


assistant: ```c
char *C_mkIndex(char *name, char *indexNum, char *comments) {
  char *commentText = (comments) ? C_mkOneLineComments(comments) : NULL;
  char *varName = C_mkIndexName(name);
  char *assign = C_mkAssign(varName, indexNum);
  size_t length = ((commentText) ? strlen(commentText) + strlen("    ") : 0) + strlen(assign) + strlen("    ") + 5;
  char *index = UTIL_mallocStr(length);
  free(varName);
  strcpy(index, "    ");
  if (commentText) {
    strcat(index, commentText);
    strcat(index, "\n");
    strcat(index, "    ");
    free(commentText);
  }
  strcat(index, assign);
  free(assign);
  return index;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<C_mkIndex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  test   %rdx,%rdx
  je     L23
  mov    %rdx,%rdi
  call   <C_mkOneLineComments@plt>
  mov    %r12,%rdi
  mov    %rax,%r14
  call   <C_mkIndexName@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <C_mkAssign@plt>
  mov    %rax,%rbp
  test   %r14,%r14
  je     L11
  lea    D1(%rip),%r15
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  mov    %r15,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  lea    0x5(%r12,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <free@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    D25(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  mov    %r15,%rsi
  call   <strcat@plt>
  mov    %r14,%rdi
  call   <free@plt>
L13:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L23:
  call   <C_mkIndexName@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <C_mkAssign@plt>
  mov    %rax,%rbp
L11:
  mov    %rbp,%rdi
  lea    D1(%rip),%r14
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x5(%r12,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <free@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string
name: extract_symbolic_data
arguments: data_tag: D25
type: string

tool: D1:     

tool: D25: 


assistant: ```c
char *C_mkIndex(char *name, char *indexNum, char *comments) {
  char *commentText = (comments) ? C_mkOneLineComments(comments) : NULL;
  char *varName = C_mkIndexName(name);
  char *assign = C_mkAssign(varName, indexNum);
  size_t length = ((commentText) ? strlen(commentText) + strlen("    ") : 0) + strlen(assign) + strlen("    ") + 5;
  char *index = UTIL_mallocStr(length);
  free(varName);
  strcpy(index, "    ");
  if (commentText) {
    strcat(index, commentText);
    strcat(index, "\n");
    strcat(index, "    ");
    free(commentText);
  }
  strcat(index, assign);
  free(assign);
  return index;
}
```
user: Translate the below assembly code into C programming language:

```asm
<C_mkIndex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  test   %rdx,%rdx
  je     L28
  mov    %rdx,%rdi
  call   <C_mkOneLineComments@plt>
  mov    %r12,%rdi
  mov    %rax,%r14
  call   <C_mkIndexName@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <C_mkAssign@plt>
  mov    %rax,%rbp
  test   %r14,%r14
  je     L11
  lea    D7(%rip),%r15
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  mov    %r15,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  lea    0x5(%r12,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <free@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  mov    %r15,%rsi
  call   <strcat@plt>
  mov    %r14,%rdi
  call   <free@plt>
L27:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L28:
  call   <C_mkIndexName@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <C_mkAssign@plt>
  mov    %rax,%rbp
L11:
  mov    %rbp,%rdi
  lea    D7(%rip),%r14
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x5(%r12,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <free@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L27
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D7:     

tool: D8: 


assistant: ```c
char *C_mkIndex(char *name, char *indexNum, char *comments) {
  char *commentText = (comments) ? C_mkOneLineComments(comments) : NULL;
  char *varName = C_mkIndexName(name);
  char *assign = C_mkAssign(varName, indexNum);
  size_t length = ((commentText) ? strlen(commentText) + strlen("    ") : 0) + strlen(assign) + strlen("    ") + 5;
  char *index = UTIL_mallocStr(length);
  free(varName);
  strcpy(index, "    ");
  if (commentText) {
    strcat(index, commentText);
    strcat(index, "\n");
    strcat(index, "    ");
    free(commentText);
  }
  strcat(index, assign);
  free(assign);
  return index;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L8
  cmpl   $0x1,-0x18(%rbp)
  je     L41
  jmp    L66
L8:
  mov    $0x0,%eax
  jmp    L28
L41:
  mov    -0x14(%rbp),%eax
  cltq
  jmp    L28
L66:
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L59
L67:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <number_range@plt>
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L59:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L67
  mov    -0x8(%rbp),%rax
L28:
  leave
  ret
```

assistant: ```c
long dice(int number, int size) {
  int idice;
  long sum;
  switch (size) {
  case 0:
    return 0;
  case 1:
    return number;
  }
  for (idice = 0, sum = 0; idice < number; idice++) {
    sum += number_range(1, size);
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dice>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  test   %esi,%esi
  je     L13
  mov    %edi,%r13d
  mov    %esi,%r12d
  movslq %edi,%rbx
  cmp    $0x1,%esi
  je     L13
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  test   %edi,%edi
  jle    L13
L27:
  mov    %r12d,%esi
  mov    $0x1,%edi
  call   <number_range@plt>
  add    %rax,%rbx
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L27
L13:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long dice(int number, int size) {
  int idice;
  long sum;
  switch (size) {
  case 0:
    return 0;
  case 1:
    return number;
  }
  for (idice = 0, sum = 0; idice < number; idice++) {
    sum += number_range(1, size);
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dice>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L16
  mov    %edi,%r13d
  mov    %esi,%ebp
  movslq %edi,%r12
  cmp    $0x1,%esi
  je     L16
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  test   %edi,%edi
  jle    L16
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %ebp,%esi
  mov    $0x1,%edi
  add    $0x1,%ebx
  call   <number_range@plt>
  add    %rax,%r12
  cmp    %ebx,%r13d
  jne    L30
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long dice(int number, int size) {
  int idice;
  long sum;
  switch (size) {
  case 0:
    return 0;
  case 1:
    return number;
  }
  for (idice = 0, sum = 0; idice < number; idice++) {
    sum += number_range(1, size);
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dice>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L39
  mov    %edi,%r13d
  mov    %esi,%ebp
  movslq %edi,%r12
  cmp    $0x1,%esi
  je     L39
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  test   %edi,%edi
  jle    L39
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ebp,%esi
  mov    $0x1,%edi
  add    $0x1,%ebx
  call   <number_range@plt>
  add    %rax,%r12
  cmp    %ebx,%r13d
  jne    L18
L39:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long dice(int number, int size) {
  int idice;
  long sum;
  switch (size) {
  case 0:
    return 0;
  case 1:
    return number;
  }
  for (idice = 0, sum = 0; idice < number; idice++) {
    sum += number_range(1, size);
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<to_binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpq   $0x1,-0x18(%rbp)
  jbe    L9
  mov    -0x18(%rbp),%rax
  shr    %rax
  mov    %rax,%rdi
  call   <to_binary>
L9:
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    $0x30,%eax
  jmp    L18
L2:
  mov    $0x31,%eax
L18:
  mov    %eax,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void to_binary(unsigned long n) {
  int r;
  r = n % 2;
  if (n >= 2)
    to_binary(n / 2);
  putchar(r == 0 ? '0' : '1');
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<to_binary>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  and    $0x1,%ebx
  cmp    $0x1,%rdi
  ja     L7
L13:
  lea    0x30(%rbx),%edi
  call   <putchar@plt>
  pop    %rbx
  ret
L7:
  shr    %rdi
  call   <to_binary>
  jmp    L13
```

assistant: ```c
void to_binary(unsigned long n) {
  int r;
  r = n % 2;
  if (n >= 2)
    to_binary(n / 2);
  putchar(r == 0 ? '0' : '1');
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<to_binary>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  and    $0x1,%ebx
  cmp    $0x1,%rdi
  ja     L12
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
  nop
L12:
  mov    %rdi,%rax
  shr    %rax
  mov    %eax,%ebp
  and    $0x1,%ebp
  cmp    $0x1,%rax
  jne    L24
L5:
  lea    0x30(%rbp),%edi
  call   <putchar@plt>
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
  nopl   (%rax)
L24:
  mov    %rdi,%rax
  shr    $0x2,%rax
  mov    %eax,%r12d
  and    $0x1,%r12d
  cmp    $0x1,%rax
  je     L26
  shr    $0x3,%rdi
  call   <to_binary>
L26:
  lea    0x30(%r12),%edi
  call   <putchar@plt>
  jmp    L5
```

assistant: ```c
void to_binary(unsigned long n) {
  int r;
  r = n % 2;
  if (n >= 2)
    to_binary(n / 2);
  putchar(r == 0 ? '0' : '1');
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<to_binary>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  and    $0x1,%ebx
  cmp    $0x1,%rdi
  ja     L0
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
  nop
L0:
  mov    %rdi,%rax
  shr    %rax
  mov    %eax,%ebp
  and    $0x1,%ebp
  cmp    $0x1,%rax
  jne    L27
L18:
  lea    0x30(%rbp),%edi
  call   <putchar@plt>
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
  nopl   (%rax)
L27:
  mov    %rdi,%rax
  shr    $0x2,%rax
  mov    %eax,%r12d
  and    $0x1,%r12d
  cmp    $0x1,%rax
  je     L5
  shr    $0x3,%rdi
  call   <to_binary>
L5:
  lea    0x30(%r12),%edi
  call   <putchar@plt>
  jmp    L18
```

assistant: ```c
void to_binary(unsigned long n) {
  int r;
  r = n % 2;
  if (n >= 2)
    to_binary(n / 2);
  putchar(r == 0 ? '0' : '1');
  return;
}
```