ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<PutEscapedLitStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L71:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5f,%eax
  je     L50
  cmp    $0x5f,%eax
  jg     L83
  cmp    $0x25,%eax
  je     L17
  cmp    $0x5c,%eax
  je     L36
  jmp    L83
L50:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <PutLitStr@plt>
  jmp    L11
L17:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <PutLitStr@plt>
  jmp    L11
L36:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <PutLitStr@plt>
  jmp    L11
L83:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <PutLitChar@plt>
L11:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D12: \_

tool: D15: \%

tool: D4: \textbackslash{}

assistant: ```c
void PutEscapedLitStr(char *s) {
  int i = 0;
  while (s[i]) {
    switch (s[i]) {
    case '_':
      PutLitStr("\\_");
      break;
    case '%':
      PutLitStr("\\%");
      break;
    case '\\':
      PutLitStr("\\textbackslash{}");
      break;
    default:
      PutLitChar(s[i]);
    }
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<PutEscapedLitStr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L84
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x1(%rdi),%rbx
  lea    D2(%rip),%r13
  lea    D4(%rip),%r12
  lea    D7(%rip),%rbp
  jmp    L69
L65:
  mov    %r12,%rdi
  call   <PutLitStr@plt>
L62:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L67
L69:
  cmp    $0x5c,%al
  je     L52
  cmp    $0x5f,%al
  je     L65
  cmp    $0x25,%al
  je     L48
  movsbl %al,%edi
  call   <PutLitChar@plt>
  jmp    L62
L48:
  mov    %rbp,%rdi
  call   <PutLitStr@plt>
  jmp    L62
L52:
  mov    %r13,%rdi
  call   <PutLitStr@plt>
  jmp    L62
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L84:
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D7
type_infered: string

tool: D2: \textbackslash{}

tool: D4: \_

tool: D7: \%

assistant: ```c
void PutEscapedLitStr(char *s) {
  int i = 0;
  while (s[i]) {
    switch (s[i]) {
    case '_':
      PutLitStr("\\_");
      break;
    case '%':
      PutLitStr("\\%");
      break;
    case '\\':
      PutLitStr("\\textbackslash{}");
      break;
    default:
      PutLitChar(s[i]);
    }
    i++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PutEscapedLitStr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L66
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  jmp    L84
  nopl   0x0(%rax)
L83:
  cmp    $0x25,%al
  je     L16
  movsbl %al,%edi
  call   <PutLitChar@plt>
L47:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L76
L84:
  cmp    $0x5c,%al
  je     L59
  cmp    $0x5f,%al
  jne    L83
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <PutLitStr@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L84
L76:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    %r13,%rdi
  call   <PutLitStr@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rdi
  call   <PutLitStr@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L66:
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D4
type: string

tool: D6: \textbackslash{}

tool: D8: \_

tool: D4: \%

assistant: ```c
void PutEscapedLitStr(char *s) {
  int i = 0;
  while (s[i]) {
    switch (s[i]) {
    case '_':
      PutLitStr("\\_");
      break;
    case '%':
      PutLitStr("\\%");
      break;
    case '\\':
      PutLitStr("\\textbackslash{}");
      break;
    default:
      PutLitChar(s[i]);
    }
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<PutEscapedLitStr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  jmp    L40
  nopl   0x0(%rax)
L63:
  cmp    $0x25,%al
  je     L42
  movsbl %al,%edi
  call   <PutLitChar@plt>
L52:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L26
L40:
  cmp    $0x5c,%al
  je     L24
  cmp    $0x5f,%al
  jne    L63
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <PutLitStr@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L40
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %r13,%rdi
  call   <PutLitStr@plt>
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %rbp,%rdi
  call   <PutLitStr@plt>
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L18:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string
name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D6: \textbackslash{}

tool: D5: \_

tool: D3: \%

assistant: ```c
void PutEscapedLitStr(char *s) {
  int i = 0;
  while (s[i]) {
    switch (s[i]) {
    case '_':
      PutLitStr("\\_");
      break;
    case '%':
      PutLitStr("\\%");
      break;
    case '\\':
      PutLitStr("\\textbackslash{}");
      break;
    default:
      PutLitChar(s[i]);
    }
    i++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<exchange_ptrs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void exchange_ptrs(int **p1, int **p2) {
  int *t = *p1;
  *p1 = *p2;
  *p2 = t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exchange_ptrs>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void exchange_ptrs(int **p1, int **p2) {
  int *t = *p1;
  *p1 = *p2;
  *p2 = t;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<exchange_ptrs>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void exchange_ptrs(int **p1, int **p2) {
  int *t = *p1;
  *p1 = *p2;
  *p2 = t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exchange_ptrs>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void exchange_ptrs(int **p1, int **p2) {
  int *t = *p1;
  *p1 = *p2;
  *p2 = t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_keyfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <getpass@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jg     L6
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <bail@plt>
L6:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <update_keyfile@plt>
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D8: Enter pass phrase: 

tool: D7: Cannot cache an empty pass phrase.

assistant: ```c
int init_keyfile() {
  char *pw = getpass("Enter pass phrase: ");
  if (strlen(pw) <= 0)
    bail("Cannot cache an empty pass phrase.");
  return update_keyfile(pw);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_keyfile>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rdi
  call   <getpass@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L1
L10:
  mov    %rbx,%rdi
  call   <update_keyfile@plt>
  pop    %rbx
  ret
L1:
  lea    D11(%rip),%rdi
  call   <bail@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D11
datatype: string

tool: D9: Enter pass phrase: 

tool: D11: Cannot cache an empty pass phrase.

assistant: ```c
int init_keyfile() {
  char *pw = getpass("Enter pass phrase: ");
  if (strlen(pw) <= 0)
    bail("Cannot cache an empty pass phrase.");
  return update_keyfile(pw);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init_keyfile>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  call   <getpass@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  test   %rax,%rax
  je     L5
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <update_keyfile@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  lea    D5(%rip),%rdi
  call   <bail@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <update_keyfile@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D1: Enter pass phrase: 

tool: D5: Cannot cache an empty pass phrase.

assistant: ```c
int init_keyfile() {
  char *pw = getpass("Enter pass phrase: ");
  if (strlen(pw) <= 0)
    bail("Cannot cache an empty pass phrase.");
  return update_keyfile(pw);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init_keyfile>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  call   <getpass@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  test   %rax,%rax
  je     L2
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <update_keyfile@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D9(%rip),%rdi
  call   <bail@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <update_keyfile@plt>
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D9
datatype: string

tool: D3: Enter pass phrase: 

tool: D9: Cannot cache an empty pass phrase.

assistant: ```c
int init_keyfile() {
  char *pw = getpass("Enter pass phrase: ");
  if (strlen(pw) <= 0)
    bail("Cannot cache an empty pass phrase.");
  return update_keyfile(pw);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<traceslang_rawnamenode_hook_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <string_dup@plt>
  jmp    L13
L8:
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
void *traceslang_rawnamenode_hook_copy(void *hook) {
  char *rawname = (char *)hook;
  if (rawname) {
    return string_dup(rawname);
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<traceslang_rawnamenode_hook_copy>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <string_dup@plt>
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
void *traceslang_rawnamenode_hook_copy(void *hook) {
  char *rawname = (char *)hook;
  if (rawname) {
    return string_dup(rawname);
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<traceslang_rawnamenode_hook_copy>:
  endbr64
  test   %rdi,%rdi
  je     L9
  jmp    1050 <string_dup@plt>
  xchg   %ax,%ax
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *traceslang_rawnamenode_hook_copy(void *hook) {
  char *rawname = (char *)hook;
  if (rawname) {
    return string_dup(rawname);
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<traceslang_rawnamenode_hook_copy>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <string_dup@plt>
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *traceslang_rawnamenode_hook_copy(void *hook) {
  char *rawname = (char *)hook;
  if (rawname) {
    return string_dup(rawname);
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x3f60a4d,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  lea    -0x428e2735(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  char copy13;
  unsigned short copy16;
  unsigned short copy17;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
      if (!(state[0UL] < local1)) {
        copy16 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy16;
        copy17 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy17;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 777551592UL) - 1894163997U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x46843182,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  char copy13;
  unsigned short copy16;
  unsigned short copy17;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
      if (!(state[0UL] < local1)) {
        copy16 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy16;
        copy17 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy17;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 777551592UL) - 1894163997U;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x46843182,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  char copy13;
  unsigned short copy16;
  unsigned short copy17;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
      if (!(state[0UL] < local1)) {
        copy16 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy16;
        copy17 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy17;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 777551592UL) - 1894163997U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x46843182,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  char copy13;
  unsigned short copy16;
  unsigned short copy17;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
      if (!(state[0UL] < local1)) {
        copy16 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy16;
        copy17 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy17;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 777551592UL) - 1894163997U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psd_freeif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <psd_free@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void psd_freeif(void *block) {
  if (block != NULL) {
    psd_free(block);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<psd_freeif>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <psd_free@plt>
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
void psd_freeif(void *block) {
  if (block != NULL) {
    psd_free(block);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<psd_freeif>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <psd_free@plt>
  xchg   %ax,%ax
L5:
  ret
```

assistant: ```c
void psd_freeif(void *block) {
  if (block != NULL) {
    psd_free(block);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<psd_freeif>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <psd_free@plt>
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void psd_freeif(void *block) {
  if (block != NULL) {
    psd_free(block);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x1c(%rbp)
  mov    %al,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L56
L42:
  movsbl -0x18(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L58
  mov    -0x4(%rbp),%eax
  jmp    L45
L58:
  cmpl   $0x0,-0x4(%rbp)
  je     L21
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x18(%rbp)
L56:
  cmpl   $0x0,-0x8(%rbp)
  jg     L42
  jmp    L53
L21:
  nop
L53:
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
L45:
  leave
  ret
```

assistant: ```c
int readn(int fd, char ptr, int nbytes) {
  int nleft, nread;
  nleft = nbytes;
  while (nleft > 0) {
    nread = read(fd, ptr, nleft);
    if (nread < 0)
      return (nread);
    else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return (nbytes - nleft);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L13
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
L23:
  movsbl %bpl,%esi
  mov    %ebx,%edx
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L41
  je     L29
  sub    %eax,%ebx
  add    %eax,%ebp
  test   %ebx,%ebx
  jg     L23
L29:
  mov    %r13d,%eax
  sub    %ebx,%eax
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    %edx,%ebx
  jmp    L29
```

assistant: ```c
int readn(int fd, char ptr, int nbytes) {
  int nleft, nread;
  nleft = nbytes;
  while (nleft > 0) {
    nread = read(fd, ptr, nleft);
    if (nread < 0)
      return (nread);
    else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return (nbytes - nleft);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readn>:
  endbr64
  test   %edx,%edx
  jle    L49
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L15
  xchg   %ax,%ax
L28:
  je     L3
  sub    %eax,%r12d
  add    %eax,%r13d
  test   %r12d,%r12d
  jle    L3
L15:
  movsbl %r13b,%esi
  mov    %r12d,%edx
  mov    %ebx,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L28
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  sub    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readn(int fd, char ptr, int nbytes) {
  int nleft, nread;
  nleft = nbytes;
  while (nleft > 0) {
    nread = read(fd, ptr, nleft);
    if (nread < 0)
      return (nread);
    else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return (nbytes - nleft);
}
```