ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    $0xa,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    $0xa,%edx
  movb   $0x7a,0x2(%rax)
  mov    %rax,%rsi
  call   <memcpy@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char *foo;
  char *bar;
  foo = (char *)malloc(10);
  bar = (char *)malloc(10);
  bar[2] = 'z';
  memcpy(foo, bar, 10);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    $0xa,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    $0xa,%edx
  movb   $0x7a,0x2(%rax)
  mov    %rax,%rsi
  call   <memcpy@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char *foo;
  char *bar;
  foo = (char *)malloc(10);
  bar = (char *)malloc(10);
  bar[2] = 'z';
  memcpy(foo, bar, 10);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BCHECK_SCORE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %ecx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    %r9,-0x58(%rbp)
  mov    $0x0,%r12d
  mov    %r12d,%ebx
  mov    %ebx,%r14d
  mov    %r14d,%r13d
  mov    %r13d,-0x2c(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L7
L68:
  mov    -0x50(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x50(%rbp)
  mov    (%rax),%ebx
  test   %ebx,%ebx
  jne    L34
  add    $0x1,%r13d
  movslq %r13d,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  add    $0x1,%r14d
  movslq %r14d,%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x2c(%rbp)
  add    $0x1,%r12d
  jmp    L7
L34:
  test   %ebx,%ebx
  jle    L28
  mov    %ebx,%edx
  imul   0x18(%rbp),%edx
  mov    0x10(%rbp),%eax
  add    %edx,%eax
  sub    %eax,-0x2c(%rbp)
  add    %ebx,%r14d
  add    %ebx,%r12d
  jmp    L7
L28:
  mov    %ebx,%edx
  imul   0x18(%rbp),%edx
  mov    0x10(%rbp),%eax
  sub    %edx,%eax
  sub    %eax,-0x2c(%rbp)
  sub    %ebx,%r13d
  sub    %ebx,%r12d
L7:
  cmp    -0x44(%rbp),%r13d
  jl     L68
  cmp    -0x48(%rbp),%r14d
  jl     L68
  mov    0x20(%rbp),%rax
  mov    %r12d,(%rax)
  mov    -0x2c(%rbp),%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int BCHECK_SCORE(const unsigned char *A, const unsigned char *B, int M, int N, int *S, int **w, int g, int h, int *nres) {
  register int i, j, op, nc;
  int *Ssave;
  int score;
  score = i = j = op = nc = 0;
  Ssave = S;
  while (i < M || j < N) {
    op = *S++;
    if (op == 0) {
      score = w[A[++i]][B[++j]] + score;
      nc++;
    } else if (op > 0) {
      score = score - (g + op * h);
      j += op;
      nc += op;
    } else {
      score = score - (g - op * h);
      i -= op;
      nc -= op;
    }
  }
  *nres = nc;
  return score;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BCHECK_SCORE>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r10d
  mov    %ecx,%r12d
  mov    0x38(%rsp),%r13d
  mov    0x40(%rsp),%r14d
  test   %edx,%edx
  jg     L31
  test   %ecx,%ecx
  jle    L12
L31:
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%ecx
  mov    $0x0,%edx
L66:
  add    $0x4,%r8
  mov    -0x4(%r8),%eax
  test   %eax,%eax
  jne    L0
  add    $0x1,%edx
  add    $0x1,%ecx
  movslq %edx,%rax
  movzbl (%rbx,%rax,1),%eax
  movslq %ecx,%r11
  movzbl 0x0(%rbp,%r11,1),%r11d
  mov    (%r9,%rax,8),%rax
  add    (%rax,%r11,4),%esi
  add    $0x1,%edi
L55:
  cmp    %r10d,%edx
  jl     L66
  cmp    %r12d,%ecx
  jl     L66
L40:
  mov    0x48(%rsp),%rax
  mov    %edi,(%rax)
  mov    %esi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  jle    L59
  mov    %eax,%r11d
  imul   %r14d,%r11d
  add    %r13d,%r11d
  sub    %r11d,%esi
  add    %eax,%ecx
  add    %eax,%edi
  jmp    L55
L59:
  mov    %eax,%r15d
  imul   %r14d,%r15d
  mov    %r13d,%r11d
  sub    %r15d,%r11d
  sub    %r11d,%esi
  sub    %eax,%edx
  sub    %eax,%edi
  jmp    L55
L12:
  mov    $0x0,%esi
  mov    $0x0,%edi
  jmp    L40
```

assistant: ```c
int BCHECK_SCORE(const unsigned char *A, const unsigned char *B, int M, int N, int *S, int **w, int g, int h, int *nres) {
  register int i, j, op, nc;
  int *Ssave;
  int score;
  score = i = j = op = nc = 0;
  Ssave = S;
  while (i < M || j < N) {
    op = *S++;
    if (op == 0) {
      score = w[A[++i]][B[++j]] + score;
      nc++;
    } else if (op > 0) {
      score = score - (g + op * h);
      j += op;
      nc += op;
    } else {
      score = score - (g - op * h);
      i -= op;
      nc -= op;
    }
  }
  *nres = nc;
  return score;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BCHECK_SCORE>:
  endbr64
  push   %r15
  mov    %edx,%r11d
  xor    %r10d,%r10d
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    0x38(%rsp),%r14d
  mov    0x40(%rsp),%r13d
  test   %edx,%edx
  jg     L75
  test   %ecx,%ecx
  jle    L49
L75:
  xor    %ecx,%ecx
  xor    %edx,%edx
  nopl   (%rax)
L22:
  mov    (%r8),%eax
  add    $0x4,%r8
  test   %eax,%eax
  jne    L66
  add    $0x1,%edx
  add    $0x1,%ecx
  add    $0x1,%esi
  movslq %edx,%rax
  movslq %ecx,%rdi
  movzbl (%rbx,%rax,1),%eax
  movzbl 0x0(%rbp,%rdi,1),%edi
  mov    (%r9,%rax,8),%rax
  add    (%rax,%rdi,4),%r10d
L3:
  cmp    %r11d,%edx
  jl     L22
  cmp    %r12d,%ecx
  jl     L22
L49:
  mov    0x48(%rsp),%rax
  mov    %esi,(%rax)
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %eax,%edi
  imul   %r13d,%edi
  test   %eax,%eax
  jle    L78
  add    %r14d,%edi
  add    %eax,%ecx
  add    %eax,%esi
  sub    %edi,%r10d
  jmp    L3
  xchg   %ax,%ax
L78:
  mov    %r14d,%r15d
  sub    %eax,%edx
  sub    %eax,%esi
  sub    %edi,%r15d
  sub    %r15d,%r10d
  jmp    L3
```

assistant: ```c
int BCHECK_SCORE(const unsigned char *A, const unsigned char *B, int M, int N, int *S, int **w, int g, int h, int *nres) {
  register int i, j, op, nc;
  int *Ssave;
  int score;
  score = i = j = op = nc = 0;
  Ssave = S;
  while (i < M || j < N) {
    op = *S++;
    if (op == 0) {
      score = w[A[++i]][B[++j]] + score;
      nc++;
    } else if (op > 0) {
      score = score - (g + op * h);
      j += op;
      nc += op;
    } else {
      score = score - (g - op * h);
      i -= op;
      nc -= op;
    }
  }
  *nres = nc;
  return score;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BCHECK_SCORE>:
  endbr64
  push   %r15
  mov    %edx,%r11d
  xor    %r10d,%r10d
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    0x38(%rsp),%r14d
  mov    0x40(%rsp),%r13d
  test   %edx,%edx
  jg     L69
  test   %ecx,%ecx
  jle    L59
L69:
  xor    %ecx,%ecx
  xor    %edx,%edx
  nopl   (%rax)
L52:
  mov    (%r8),%eax
  add    $0x4,%r8
  test   %eax,%eax
  jne    L54
  add    $0x1,%edx
  add    $0x1,%ecx
  add    $0x1,%esi
  movslq %edx,%rax
  movslq %ecx,%rdi
  movzbl (%rbx,%rax,1),%eax
  movzbl 0x0(%rbp,%rdi,1),%edi
  mov    (%r9,%rax,8),%rax
  add    (%rax,%rdi,4),%r10d
L25:
  cmp    %r11d,%edx
  jl     L52
  cmp    %r12d,%ecx
  jl     L52
L59:
  mov    0x48(%rsp),%rax
  mov    %esi,(%rax)
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %eax,%edi
  imul   %r13d,%edi
  test   %eax,%eax
  jle    L44
  add    %r14d,%edi
  add    %eax,%ecx
  add    %eax,%esi
  sub    %edi,%r10d
  jmp    L25
  xchg   %ax,%ax
L44:
  mov    %r14d,%r15d
  sub    %eax,%edx
  sub    %eax,%esi
  sub    %edi,%r15d
  sub    %r15d,%r10d
  jmp    L25
```

assistant: ```c
int BCHECK_SCORE(const unsigned char *A, const unsigned char *B, int M, int N, int *S, int **w, int g, int h, int *nres) {
  register int i, j, op, nc;
  int *Ssave;
  int score;
  score = i = j = op = nc = 0;
  Ssave = S;
  while (i < M || j < N) {
    op = *S++;
    if (op == 0) {
      score = w[A[++i]][B[++j]] + score;
      nc++;
    } else if (op > 0) {
      score = score - (g + op * h);
      j += op;
      nc += op;
    } else {
      score = score - (g - op * h);
      i -= op;
      nc -= op;
    }
  }
  *nres = nc;
  return score;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CG_Text_Height>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %esi,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <MenuFontToHandle@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <trap_R_Font_HeightPixels@plt>
  leave
  ret
```

assistant: ```c
int CG_Text_Height(const char *text, float scale, int iMenuFont) {
  int iFontIndex = MenuFontToHandle(iMenuFont);
  return trap_R_Font_HeightPixels(iFontIndex, scale);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CG_Text_Height>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    %esi,%edi
  call   <MenuFontToHandle@plt>
  mov    %eax,%edi
  movss  0xc(%rsp),%xmm0
  call   <trap_R_Font_HeightPixels@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int CG_Text_Height(const char *text, float scale, int iMenuFont) {
  int iFontIndex = MenuFontToHandle(iMenuFont);
  return trap_R_Font_HeightPixels(iFontIndex, scale);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CG_Text_Height>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%edi
  movss  %xmm0,0xc(%rsp)
  call   <MenuFontToHandle@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  mov    %eax,%edi
  jmp    1060 <trap_R_Font_HeightPixels@plt>
```

assistant: ```c
int CG_Text_Height(const char *text, float scale, int iMenuFont) {
  int iFontIndex = MenuFontToHandle(iMenuFont);
  return trap_R_Font_HeightPixels(iFontIndex, scale);
}
```
user: Translate the below assembly code into C programming language:

```asm
<CG_Text_Height>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%edi
  movss  %xmm0,0xc(%rsp)
  call   <MenuFontToHandle@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  mov    %eax,%edi
  jmp    1060 <trap_R_Font_HeightPixels@plt>
```

assistant: ```c
int CG_Text_Height(const char *text, float scale, int iMenuFont) {
  int iFontIndex = MenuFontToHandle(iMenuFont);
  return trap_R_Font_HeightPixels(iFontIndex, scale);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gen_multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L16
  cmpl   $0x2,-0x4(%rbp)
  jl     L0
  mov    -0x4(%rbp),%eax
  sub    $0x8,%eax
  cmp    $0x1,%eax
  ja     L0
  mov    $0x0,%eax
  call   <gen_multiply_by_two@plt>
  jmp    L12
L16:
  mov    $0x0,%eax
  call   <gen_immediate2@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <output_number@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <gen_call@plt>
  jmp    L12
L0:
  nop
L12:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D3: ccmul

assistant: ```c
void gen_multiply(int type, int size) {
  switch (type) {
  case (2 << 2):
  case ((2 << 2) + 1):
    gen_multiply_by_two();
    break;
  case 2:
    gen_immediate2();
    output_number(size);
    newline();
    gen_call("ccmul");
    break;
  default:
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gen_multiply>:
  endbr64
  push   %rbx
  cmp    $0x2,%edi
  je     L22
  sub    $0x8,%edi
  cmp    $0x1,%edi
  ja     L11
  mov    $0x0,%eax
  call   <gen_multiply_by_two@plt>
L11:
  pop    %rbx
  ret
L22:
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <gen_immediate2@plt>
  mov    %ebx,%edi
  call   <output_number@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  lea    D3(%rip),%rdi
  call   <gen_call@plt>
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: ccmul

assistant: ```c
void gen_multiply(int type, int size) {
  switch (type) {
  case (2 << 2):
  case ((2 << 2) + 1):
    gen_multiply_by_two();
    break;
  case 2:
    gen_immediate2();
    output_number(size);
    newline();
    gen_call("ccmul");
    break;
  default:
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gen_multiply>:
  endbr64
  cmp    $0x2,%edi
  je     L3
  mov    %edi,%eax
  sub    $0x8,%eax
  cmp    $0x1,%eax
  ja     L16
  xor    %eax,%eax
  jmp    1090 <gen_multiply_by_two@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  call   <gen_immediate2@plt>
  mov    %ebp,%edi
  call   <output_number@plt>
  xor    %eax,%eax
  call   <newline@plt>
  lea    D6(%rip),%rdi
  pop    %rbp
  jmp    10d0 <gen_call@plt>
L16:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: ccmul

assistant: ```c
void gen_multiply(int type, int size) {
  switch (type) {
  case (2 << 2):
  case ((2 << 2) + 1):
    gen_multiply_by_two();
    break;
  case 2:
    gen_immediate2();
    output_number(size);
    newline();
    gen_call("ccmul");
    break;
  default:
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gen_multiply>:
  endbr64
  cmp    $0x2,%edi
  je     L0
  mov    %edi,%eax
  sub    $0x8,%eax
  cmp    $0x1,%eax
  ja     L7
  xor    %eax,%eax
  jmp    1090 <gen_multiply_by_two@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  call   <gen_immediate2@plt>
  mov    %ebp,%edi
  call   <output_number@plt>
  xor    %eax,%eax
  call   <newline@plt>
  lea    D5(%rip),%rdi
  pop    %rbp
  jmp    10d0 <gen_call@plt>
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: ccmul

assistant: ```c
void gen_multiply(int type, int size) {
  switch (type) {
  case (2 << 2):
  case ((2 << 2) + 1):
    gen_multiply_by_two();
    break;
  case 2:
    gen_immediate2();
    output_number(size);
    newline();
    gen_call("ccmul");
    break;
  default:
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L8:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
datatype: string
name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D15: %d 

tool: 

assistant: ```c
void random1(int length, int size) {
  int i;
  for (i = 0; i < length; i++) {
    printf("%d ", rand() % size);
  }
  puts("");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<random1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L3
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D10(%rip),%r13
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L6
L3:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D10: %d 

tool: 

assistant: ```c
void random1(int length, int size) {
  int i;
  for (i = 0; i < length; i++) {
    printf("%d ", rand() % size);
  }
  puts("");
}
```
user: Translate the below assembly code into C programming language:

```asm
<random1>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L2:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <rand@plt>
  mov    %r13,%rdi
  cltd
  idiv   %ebp
  mov    %edx,%esi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L2
  add    $0x8,%rsp
  lea    D20(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  lea    D20(%rip),%rdi
  jmp    1070 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: string

tool: D4: %d 

tool: 

assistant: ```c
void random1(int length, int size) {
  int i;
  for (i = 0; i < length; i++) {
    printf("%d ", rand() % size);
  }
  puts("");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<random1>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L12:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <rand@plt>
  mov    %r13,%rdi
  cltd
  idiv   %ebp
  mov    %edx,%esi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L12
  add    $0x8,%rsp
  lea    D12(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D12(%rip),%rdi
  jmp    1070 <puts@plt>
```

tool_calls: name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D12
data_type: string

tool: D21: %d 

tool: 

assistant: ```c
void random1(int length, int size) {
  int i;
  for (i = 0; i < length; i++) {
    printf("%d ", rand() % size);
  }
  puts("");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ismatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  cmpb   $0x7b,-0x4(%rbp)
  jne    L68
  cmpb   $0x7d,-0x8(%rbp)
  jne    L68
  mov    $0x1,%eax
  jmp    L53
L68:
  cmpb   $0x28,-0x4(%rbp)
  jne    L14
  cmpb   $0x29,-0x8(%rbp)
  jne    L14
  mov    $0x1,%eax
  jmp    L53
L14:
  cmpb   $0x5b,-0x4(%rbp)
  jne    L21
  cmpb   $0x5d,-0x8(%rbp)
  jne    L21
  mov    $0x1,%eax
  jmp    L53
L21:
  mov    $0x0,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
int ismatch(char a, char b) {
  if (a == '{' && b == '}')
    return 1;
  else if (a == '(' && b == ')')
    return 1;
  else if (a == '[' && b == ']')
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ismatch>:
  endbr64
  cmp    $0x7b,%dil
  jne    L25
  mov    $0x1,%eax
  cmp    $0x7d,%sil
  je     L9
L25:
  cmp    $0x28,%dil
  jne    L8
  mov    $0x1,%eax
  cmp    $0x29,%sil
  je     L9
L8:
  cmp    $0x5b,%dil
  sete   %dl
  cmp    $0x5d,%sil
  sete   %al
  movzbl %al,%eax
  and    %edx,%eax
L9:
  ret
```

assistant: ```c
int ismatch(char a, char b) {
  if (a == '{' && b == '}')
    return 1;
  else if (a == '(' && b == ')')
    return 1;
  else if (a == '[' && b == ']')
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ismatch>:
  endbr64
  cmp    $0x7b,%dil
  jne    L3
  mov    $0x1,%eax
  cmp    $0x7d,%sil
  jne    L3
L29:
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  cmp    $0x28,%dil
  jne    L28
  mov    $0x1,%eax
  cmp    $0x29,%sil
  je     L29
L28:
  cmp    $0x5b,%dil
  sete   %dl
  xor    %eax,%eax
  cmp    $0x5d,%sil
  sete   %al
  and    %edx,%eax
  ret
```

assistant: ```c
int ismatch(char a, char b) {
  if (a == '{' && b == '}')
    return 1;
  else if (a == '(' && b == ')')
    return 1;
  else if (a == '[' && b == ']')
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ismatch>:
  endbr64
  cmp    $0x7b,%dil
  jne    L35
  mov    $0x1,%eax
  cmp    $0x7d,%sil
  jne    L35
L3:
  ret
  cs nopw 0x0(%rax,%rax,1)
L35:
  cmp    $0x28,%dil
  jne    L38
  mov    $0x1,%eax
  cmp    $0x29,%sil
  je     L3
L38:
  cmp    $0x5b,%dil
  sete   %dl
  xor    %eax,%eax
  cmp    $0x5d,%sil
  sete   %al
  and    %edx,%eax
  ret
```

assistant: ```c
int ismatch(char a, char b) {
  if (a == '{' && b == '}')
    return 1;
  else if (a == '(' && b == ')')
    return 1;
  else if (a == '[' && b == ']')
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <somatorio@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: %d


assistant: ```c
void main(void) {
  int max = 5;
  printf("%d\n", somatorio(max));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <somatorio@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d


assistant: ```c
void main(void) {
  int max = 5;
  printf("%d\n", somatorio(max));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <somatorio@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: %d


assistant: ```c
void main(void) {
  int max = 5;
  printf("%d\n", somatorio(max));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <somatorio@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string

tool: D8: %d


assistant: ```c
void main(void) {
  int max = 5;
  printf("%d\n", somatorio(max));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<paintCellHorizontalBorder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L6:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D12
type: string

tool: D5: +-

tool: D12: +


assistant: ```c
void paintCellHorizontalBorder(int rowLength) {
  for (int i = 0; i < rowLength; i++) {
    printf("+-");
  }
  printf("+\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<paintCellHorizontalBorder>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L9
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
L18:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L18
L9:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D7
type_infered: string

tool: D2: +-

tool: D7: +


assistant: ```c
void paintCellHorizontalBorder(int rowLength) {
  for (int i = 0; i < rowLength; i++) {
    printf("+-");
  }
  printf("+\n");
}
```