ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fatfs_get_substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L157
  cmpl   $0x0,-0x30(%rbp)
  jg     L77
L157:
  mov    $0xffffffff,%eax
  jmp    L6
L77:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L64
  movb   $0x2f,-0x11(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L96
L64:
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  je     L61
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L114
L61:
  movb   $0x5c,-0x11(%rbp)
  addq   $0x3,-0x28(%rbp)
  jmp    L96
L114:
  mov    $0xffffffff,%eax
  jmp    L6
L96:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L46
L118:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x11(%rbp)
  jne    L54
  addl   $0x1,-0xc(%rbp)
L54:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L73
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x11(%rbp)
  je     L73
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L73
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L73:
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L118
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L113
  mov    $0x0,%eax
  jmp    L6
L113:
  mov    $0xffffffff,%eax
L6:
  leave
  ret
```

assistant: ```c
int fatfs_get_substring(char *path, int levelreq, char *output, int max_len) {
  int i;
  int pathlen = 0;
  int levels = 0;
  int copypnt = 0;
  char expectedchar;
  if (!path || max_len <= 0)
    return -1;
  if (*path == '/') {
    expectedchar = '/';
    path++;
  } else if (path[1] == ':' || path[2] == '\\') {
    expectedchar = '\\';
    path += 3;
  } else
    return -1;
  pathlen = (int)strlen(path);
  for (i = 0; i < pathlen; i++) {
    if (*path == expectedchar)
      levels++;
    if ((levels == levelreq) && (*path != expectedchar) && (copypnt < (max_len - 1)))
      output[copypnt++] = *path;
    path++;
  }
  output[copypnt] = '\0';
  if (output[0] != '\0')
    return 0;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fatfs_get_substring>:
  endbr64
  test   %rdi,%rdi
  je     L134
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    %ecx,%r14d
  test   %ecx,%ecx
  jle    L44
  movzbl (%rdi),%ebp
  lea    0x1(%rdi),%rbx
  cmp    $0x2f,%bpl
  je     L68
  cmpb   $0x3a,0x1(%rdi)
  je     L93
  cmpb   $0x5c,0x2(%rdi)
  jne    L130
L93:
  lea    0x3(%rdi),%rbx
  mov    $0x5c,%ebp
L68:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L1
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rcx
  mov    $0x0,%esi
  mov    $0x0,%edx
  sub    $0x1,%r14d
  jmp    L108
L82:
  add    $0x1,%edx
L19:
  add    $0x1,%rbx
  cmp    %rcx,%rbx
  je     L10
L108:
  movzbl (%rbx),%eax
  cmp    %bpl,%al
  je     L82
  cmp    %edx,%r12d
  jne    L19
  cmp    %esi,%r14d
  jle    L19
  movslq %esi,%rdi
  mov    %al,0x0(%r13,%rdi,1)
  lea    0x1(%rsi),%esi
  jmp    L19
L1:
  mov    $0x0,%esi
L10:
  movslq %esi,%rsi
  movb   $0x0,0x0(%r13,%rsi,1)
  cmpb   $0x1,0x0(%r13)
  sbb    %eax,%eax
L111:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  mov    $0xffffffff,%eax
  jmp    L111
L130:
  mov    $0xffffffff,%eax
  jmp    L111
L134:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fatfs_get_substring(char *path, int levelreq, char *output, int max_len) {
  int i;
  int pathlen = 0;
  int levels = 0;
  int copypnt = 0;
  char expectedchar;
  if (!path || max_len <= 0)
    return -1;
  if (*path == '/') {
    expectedchar = '/';
    path++;
  } else if (path[1] == ':' || path[2] == '\\') {
    expectedchar = '\\';
    path += 3;
  } else
    return -1;
  pathlen = (int)strlen(path);
  for (i = 0; i < pathlen; i++) {
    if (*path == expectedchar)
      levels++;
    if ((levels == levelreq) && (*path != expectedchar) && (copypnt < (max_len - 1)))
      output[copypnt++] = *path;
    path++;
  }
  output[copypnt] = '\0';
  if (output[0] != '\0')
    return 0;
  else
    return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<fatfs_get_substring>:
  endbr64
  test   %rdi,%rdi
  je     L57
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %ecx,%ecx
  jle    L130
  movzbl (%rdi),%ebp
  mov    %esi,%r12d
  mov    %rdx,%r14
  lea    0x1(%rdi),%rbx
  cmp    $0x2f,%bpl
  je     L74
  cmpb   $0x3a,0x1(%rdi)
  je     L42
  cmpb   $0x5c,0x2(%rdi)
  jne    L130
L42:
  lea    0x3(%rdi),%rbx
  mov    $0x5c,%ebp
L74:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L128
  sub    $0x1,%eax
  xor    %esi,%esi
  xor    %edx,%edx
  sub    $0x1,%r13d
  lea    0x1(%rbx,%rax,1),%rdi
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L33:
  cmp    %edx,%r12d
  je     L129
L26:
  add    $0x1,%rbx
  cmp    %rbx,%rdi
  je     L44
L79:
  movzbl (%rbx),%eax
  cmp    %bpl,%al
  jne    L33
  add    $0x1,%rbx
  add    $0x1,%edx
  cmp    %rbx,%rdi
  jne    L79
L44:
  movslq %esi,%rsi
  add    %r14,%rsi
L2:
  movb   $0x0,(%rsi)
  cmpb   $0x1,(%r14)
  sbb    %eax,%eax
L100:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L129:
  cmp    %esi,%r13d
  jle    L26
  movslq %esi,%rcx
  add    $0x1,%esi
  mov    %al,(%r14,%rcx,1)
  jmp    L26
  nopl   0x0(%rax)
L128:
  mov    %r14,%rsi
  jmp    L2
L130:
  mov    $0xffffffff,%eax
  jmp    L100
L57:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int fatfs_get_substring(char *path, int levelreq, char *output, int max_len) {
  int i;
  int pathlen = 0;
  int levels = 0;
  int copypnt = 0;
  char expectedchar;
  if (!path || max_len <= 0)
    return -1;
  if (*path == '/') {
    expectedchar = '/';
    path++;
  } else if (path[1] == ':' || path[2] == '\\') {
    expectedchar = '\\';
    path += 3;
  } else
    return -1;
  pathlen = (int)strlen(path);
  for (i = 0; i < pathlen; i++) {
    if (*path == expectedchar)
      levels++;
    if ((levels == levelreq) && (*path != expectedchar) && (copypnt < (max_len - 1)))
      output[copypnt++] = *path;
    path++;
  }
  output[copypnt] = '\0';
  if (output[0] != '\0')
    return 0;
  else
    return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fatfs_get_substring>:
  endbr64
  test   %rdi,%rdi
  je     L42
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %ecx,%ecx
  jle    L41
  movzbl (%rdi),%ebp
  mov    %esi,%r12d
  mov    %rdx,%r14
  lea    0x1(%rdi),%rbx
  cmp    $0x2f,%bpl
  je     L136
  cmpb   $0x3a,0x1(%rdi)
  je     L83
  cmpb   $0x5c,0x2(%rdi)
  jne    L41
L83:
  lea    0x3(%rdi),%rbx
  mov    $0x5c,%ebp
L136:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L121
  sub    $0x1,%eax
  xor    %esi,%esi
  xor    %edx,%edx
  sub    $0x1,%r13d
  lea    0x1(%rbx,%rax,1),%rdi
  jmp    L141
  nopw   0x0(%rax,%rax,1)
L49:
  cmp    %edx,%r12d
  je     L51
L22:
  add    $0x1,%rbx
  cmp    %rdi,%rbx
  je     L88
L141:
  movzbl (%rbx),%eax
  cmp    %bpl,%al
  jne    L49
  add    $0x1,%rbx
  add    $0x1,%edx
  cmp    %rdi,%rbx
  jne    L141
L88:
  movslq %esi,%rsi
  add    %r14,%rsi
L109:
  movb   $0x0,(%rsi)
  cmpb   $0x1,(%r14)
  sbb    %eax,%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  cmp    %esi,%r13d
  jle    L22
  movslq %esi,%rcx
  add    $0x1,%esi
  mov    %al,(%r14,%rcx,1)
  jmp    L22
  nopl   0x0(%rax)
L121:
  mov    %r14,%rsi
  jmp    L109
L41:
  mov    $0xffffffff,%eax
  jmp    L2
L42:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int fatfs_get_substring(char *path, int levelreq, char *output, int max_len) {
  int i;
  int pathlen = 0;
  int levels = 0;
  int copypnt = 0;
  char expectedchar;
  if (!path || max_len <= 0)
    return -1;
  if (*path == '/') {
    expectedchar = '/';
    path++;
  } else if (path[1] == ':' || path[2] == '\\') {
    expectedchar = '\\';
    path += 3;
  } else
    return -1;
  pathlen = (int)strlen(path);
  for (i = 0; i < pathlen; i++) {
    if (*path == expectedchar)
      levels++;
    if ((levels == levelreq) && (*path != expectedchar) && (copypnt < (max_len - 1)))
      output[copypnt++] = *path;
    path++;
  }
  output[copypnt] = '\0';
  if (output[0] != '\0')
    return 0;
  else
    return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<arraysAreEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L28
  mov    $0x0,%eax
  jmp    L16
L28:
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L35
  mov    $0x1,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int arraysAreEqual(char *array1, char *array2, int length) {
  for (int i = 0; i < length; ++i) {
    if (*(array1 + i) != *(array2 + i)) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arraysAreEqual>:
  endbr64
  test   %edx,%edx
  jle    L0
  mov    %edx,%edx
  mov    $0x0,%eax
L28:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jne    L2
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L28
  mov    $0x1,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int arraysAreEqual(char *array1, char *array2, int length) {
  for (int i = 0; i < length; ++i) {
    if (*(array1 + i) != *(array2 + i)) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<arraysAreEqual>:
  endbr64
  test   %edx,%edx
  jle    L20
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L36
  nop
L14:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L20
L36:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L14
  xor    %eax,%eax
  ret
  nopl   (%rax)
L20:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int arraysAreEqual(char *array1, char *array2, int length) {
  for (int i = 0; i < length; ++i) {
    if (*(array1 + i) != *(array2 + i)) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arraysAreEqual>:
  endbr64
  test   %edx,%edx
  jle    L7
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L29
  nop
L16:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L7
L29:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L16
  xor    %eax,%eax
  ret
  nopl   (%rax)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int arraysAreEqual(char *array1, char *array2, int length) {
  for (int i = 0; i < length; ++i) {
    if (*(array1 + i) != *(array2 + i)) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f2sc_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  je     L3
  movss  D3(%rip),%xmm0
  jmp    L27
L3:
  movss  D19(%rip),%xmm0
L27:
  movss  %xmm0,-0x14(%rbp)
  jmp    L36
L23:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0x14(%rbp),%xmm0
  movd   %xmm0,%eax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movd   %eax,%xmm0
  call   <lrintf@plt>
  mov    %al,(%rbx)
L36:
  subl   $0x1,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L23
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: byte[4]
name: disassemble_data
arguments: data_label: D19
type_infered: f32

tool: {"D3": [0x00,0x00,0xfe,0x42]}

tool: D19: 1

assistant: ```c
void f2sc_array(float *src, signed char *dest, int count, int normalize) {
  float normfact;
  normfact = normalize ? (1.0 * 0x7F) : 1.0;
  while (--count >= 0) {
    dest[count] = lrintf(src[count] * normfact);
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f2sc_array>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    D6(%rip),%r13d
  test   %ecx,%ecx
  jne    L20
  mov    D4(%rip),%r13d
L20:
  sub    $0x1,%ebx
  js     L13
  movslq %ebx,%rbx
L2:
  movd   %r13d,%xmm0
  mulss  0x0(%rbp,%rbx,4),%xmm0
  call   <lrintf@plt>
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L2
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: byte[4]
name: retrieve_data
arguments: tag: D4
type: f32

tool: {"D6": [0x00,0x00,0xfe,0x42]}

tool: D4: 1

assistant: ```c
void f2sc_array(float *src, signed char *dest, int count, int normalize) {
  float normfact;
  normfact = normalize ? (1.0 * 0x7F) : 1.0;
  while (--count >= 0) {
    dest[count] = lrintf(src[count] * normfact);
  };
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f2sc_array>:
  endbr64
  push   %r14
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  movss  D13(%rip),%xmm1
  movd   %xmm1,%r14d
  test   %ecx,%ecx
  jne    L10
  movss  D5(%rip),%xmm2
  movd   %xmm2,%r14d
L10:
  sub    $0x1,%ebx
  js     L8
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L14:
  movd   %r14d,%xmm0
  mulss  0x0(%rbp,%rbx,4),%xmm0
  call   <lrintf@plt>
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L14
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
datatype: byte[4]
name: read_data
arguments: data_tag: D5
datatype: f32

tool: {"D13": [0x00,0x00,0xfe,0x42]}

tool: D5: 1

assistant: ```c
void f2sc_array(float *src, signed char *dest, int count, int normalize) {
  float normfact;
  normfact = normalize ? (1.0 * 0x7F) : 1.0;
  while (--count >= 0) {
    dest[count] = lrintf(src[count] * normfact);
  };
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f2sc_array>:
  endbr64
  push   %r14
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  movss  D5(%rip),%xmm1
  movd   %xmm1,%r14d
  test   %ecx,%ecx
  jne    L11
  movss  D12(%rip),%xmm2
  movd   %xmm2,%r14d
L11:
  sub    $0x1,%ebx
  js     L16
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L29:
  movd   %r14d,%xmm0
  mulss  0x0(%rbp,%rbx,4),%xmm0
  call   <lrintf@plt>
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L29
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: byte[4]
name: extract_symbolic_data
arguments: data_label: D12
type: f32

tool: {"D5": [0x00,0x00,0xfe,0x42]}

tool: D12: 1

assistant: ```c
void f2sc_array(float *src, signed char *dest, int count, int normalize) {
  float normfact;
  normfact = normalize ? (1.0 * 0x7F) : 1.0;
  while (--count >= 0) {
    dest[count] = lrintf(src[count] * normfact);
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<varbcfConcatenatedlines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  cmpl   $0x0,-0x24(%rbp)
  je     L78
  cmpq   $0x0,-0x30(%rbp)
  jne    L82
L78:
  mov    $0x0,%eax
  jmp    L12
L82:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L2
L21:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  addl   $0x1,-0x14(%rbp)
L42:
  addq   $0x1,-0x10(%rbp)
L2:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jne    L21
  mov    -0x38(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L35
L37:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x1,%rdx
  mov    %rdx,(%rax)
L40:
  addq   $0x1,-0x10(%rbp)
L35:
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L37
  mov    -0x8(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
const char **varbcfConcatenatedlines(int l, const char *str, int *nlines) {
  int n = 0;
  const char *p;
  const char **list;
  *nlines = 0;
  if (l == 0 || str == 0)
    return 0;
  for (p = str; p != str + l; ++p)
    if (*p == 0)
      ++n;
  *nlines = n;
  list = calloc(n, sizeof(void *));
  list[0] = str;
  for (p = str, n = 1; p < str + l - 1; ++p)
    if (*p == 0)
      list[n++] = p + 1;
  return list;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<varbcfConcatenatedlines>:
  endbr64
  movl   $0x0,(%rdx)
  test   %edi,%edi
  je     L60
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L38
  movslq %edi,%rbp
  lea    (%rsi,%rbp,1),%rcx
  mov    %rsi,%rax
  mov    $0x0,%edi
L15:
  cmpb   $0x1,(%rax)
  adc    $0x0,%edi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L15
  mov    %edi,(%rdx)
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rbx,(%rax)
  lea    -0x1(%rbx,%rbp,1),%rdi
  cmp    %rdi,%rbx
  jae    L3
  lea    0x1(%rbx),%rdx
  mov    $0x1,%esi
  jmp    L53
L50:
  lea    0x1(%rdx),%rcx
  cmp    %rdx,%rdi
  je     L3
  mov    %rcx,%rdx
L53:
  cmpb   $0x0,-0x1(%rdx)
  jne    L50
  movslq %esi,%rcx
  mov    %rdx,(%rax,%rcx,8)
  lea    0x1(%rsi),%esi
  jmp    L50
L38:
  mov    $0x0,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L60:
  mov    $0x0,%eax
  ret
```

assistant: ```c
const char **varbcfConcatenatedlines(int l, const char *str, int *nlines) {
  int n = 0;
  const char *p;
  const char **list;
  *nlines = 0;
  if (l == 0 || str == 0)
    return 0;
  for (p = str; p != str + l; ++p)
    if (*p == 0)
      ++n;
  *nlines = n;
  list = calloc(n, sizeof(void *));
  list[0] = str;
  for (p = str, n = 1; p < str + l - 1; ++p)
    if (*p == 0)
      list[n++] = p + 1;
  return list;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<varbcfConcatenatedlines>:
  endbr64
  movl   $0x0,(%rdx)
  test   %edi,%edi
  je     L56
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L13
  movslq %edi,%rbp
  mov    %rsi,%rax
  xor    %edi,%edi
  lea    (%rsi,%rbp,1),%rcx
  nopl   0x0(%rax)
L20:
  cmpb   $0x1,(%rax)
  adc    $0x0,%edi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L20
  mov    %edi,(%rdx)
  mov    $0x8,%esi
  call   <calloc@plt>
  lea    -0x1(%rbx,%rbp,1),%rsi
  mov    %rbx,(%rax)
  cmp    %rsi,%rbx
  jae    L21
  mov    $0x1,%ecx
  nopl   (%rax)
L4:
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  jne    L14
  movslq %ecx,%rdx
  add    $0x1,%ecx
  mov    %rbx,(%rax,%rdx,8)
L14:
  cmp    %rsi,%rbx
  jne    L4
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L56:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char **varbcfConcatenatedlines(int l, const char *str, int *nlines) {
  int n = 0;
  const char *p;
  const char **list;
  *nlines = 0;
  if (l == 0 || str == 0)
    return 0;
  for (p = str; p != str + l; ++p)
    if (*p == 0)
      ++n;
  *nlines = n;
  list = calloc(n, sizeof(void *));
  list[0] = str;
  for (p = str, n = 1; p < str + l - 1; ++p)
    if (*p == 0)
      list[n++] = p + 1;
  return list;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L37
L12:
  movl   $0x0,-0x8(%rbp)
  nop
L24:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L25
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cmp    %eax,-0x4(%rbp)
  ja     L24
L25:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L49
  mov    -0x18(%rbp),%rax
  jmp    L16
L49:
  addq   $0x1,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
char *strstr(const char *src, const char *search) {
  unsigned len = strlen(search);
  while (*src) {
    unsigned i = 0;
    while (src[i] == search[i] && i++ < len)
      ;
    if (i == len)
      return (char *)src;
    else
      src++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L7
  mov    %eax,%edi
  mov    $0x0,%r8d
  jmp    L40
L14:
  mov    %rsi,%rdx
L23:
  mov    %edx,%ecx
  movzbl 0x0(%rbp,%rdx,1),%esi
  cmp    %sil,(%rbx,%rdx,1)
  jne    L77
  lea    0x1(%rdx),%ecx
  lea    0x1(%rdx),%rsi
  cmp    %rdi,%rdx
  jne    L14
L77:
  cmp    %eax,%ecx
  je     L49
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L78
L40:
  mov    %r8,%rdx
  jmp    L23
L78:
  mov    $0x0,%eax
  jmp    L24
L7:
  mov    $0x0,%eax
  jmp    L24
L49:
  mov    %rbx,%rax
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(const char *src, const char *search) {
  unsigned len = strlen(search);
  while (*src) {
    unsigned i = 0;
    while (src[i] == search[i] && i++ < len)
      ;
    if (i == len)
      return (char *)src;
    else
      src++;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L47
  mov    %eax,%edx
  lea    0x1(%rbp,%rdx,1),%r8
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x1,%rdx
  add    $0x1,%ecx
  cmp    %r8,%rdx
  je     L20
  mov    %ecx,%edi
  movzbl (%rbx,%rdi,1),%edi
L8:
  cmp    %dil,(%rdx)
  je     L21
L20:
  cmp    %eax,%ecx
  je     L42
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L13
L47:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L42:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(const char *src, const char *search) {
  unsigned len = strlen(search);
  while (*src) {
    unsigned i = 0;
    while (src[i] == search[i] && i++ < len)
      ;
    if (i == len)
      return (char *)src;
    else
      src++;
  }
  return NULL;
}
```