user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_min_steps>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmp    $0x1,%edi
  je     L185
  movslq %edi,%r13
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    0x0(,%r13,4),%rax
  lea    (%rsi,%rax,1),%r15
  mov    (%r15),%r12d
  cmp    $0xffffffff,%r12d
  je     L5
L185:
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L5:
  lea    -0x1(%rdi),%r12d
  cmp    $0x2,%edi
  je     L64
  lea    -0x4(%rsi,%rax,1),%rdx
  mov    (%rdx),%r14d
  cmp    $0xffffffff,%r14d
  je     L189
L127:
  lea    0x1(%r14),%r12d
  test   $0x1,%bl
  je     L196
L44:
  imul   $0xaaaaaaab,%ebx,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L118
L89:
  mov    %r12d,(%r15)
  jmp    L185
  nop
L118:
  imul   $0x55555556,%r13,%r13
  sar    $0x1f,%ebx
  mov    %rbp,%rsi
  shr    $0x20,%r13
  sub    %ebx,%r13d
  mov    %r13d,%edi
  call   <get_min_steps>
  add    $0x1,%eax
  cmp    %r12d,%eax
  jge    L89
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <get_min_steps>
  lea    0x1(%rax),%r12d
  jmp    L89
  nopl   (%rax)
L189:
  lea    -0x2(%rdi),%edi
  mov    %rdx,0x8(%rsp)
  call   <get_min_steps>
  test   $0x1,%r12b
  mov    0x8(%rsp),%rdx
  lea    0x1(%rax),%r14d
  je     L123
L141:
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L45
L61:
  mov    %r14d,(%rdx)
  jmp    L127
  nopl   0x0(%rax,%rax,1)
L64:
  mov    $0x1,%edi
  call   <get_min_steps>
  test   %eax,%eax
  jns    L89
  jmp    L134
  nopl   0x0(%rax)
L196:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  mov    %edx,%edi
  mov    %edx,0x8(%rsp)
  call   <get_min_steps>
  mov    0x8(%rsp),%edx
  cmp    %r14d,%eax
  jge    L44
  mov    %edx,%r12d
L134:
  mov    %r12d,%edi
  mov    %rbp,%rsi
  call   <get_min_steps>
  lea    0x1(%rax),%r12d
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L45:
  movslq %r12d,%rdi
  mov    %r12d,%eax
  mov    %rbp,%rsi
  mov    %rdx,0x8(%rsp)
  imul   $0x55555556,%rdi,%rdi
  sar    $0x1f,%eax
  shr    $0x20,%rdi
  mov    %edi,%r12d
  sub    %eax,%r12d
  mov    %r12d,%edi
  call   <get_min_steps>
  mov    0x8(%rsp),%rdx
  add    $0x1,%eax
  cmp    %r14d,%eax
  jge    L61
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <get_min_steps>
  mov    0x8(%rsp),%rdx
  lea    0x1(%rax),%r14d
  jmp    L61
  nopl   0x0(%rax)
L123:
  mov    %r12d,%edi
  mov    %rbp,%rsi
  mov    %rdx,0x10(%rsp)
  shr    $0x1f,%edi
  mov    %eax,0x1c(%rsp)
  add    %r12d,%edi
  sar    %edi
  mov    %edi,0x8(%rsp)
  call   <get_min_steps>
  mov    0x1c(%rsp),%ecx
  mov    0x8(%rsp),%edi
  mov    0x10(%rsp),%rdx
  cmp    %eax,%ecx
  jle    L141
  mov    %rbp,%rsi
  mov    %rdx,0x8(%rsp)
  call   <get_min_steps>
  mov    0x8(%rsp),%rdx
  lea    0x1(%rax),%r14d
  jmp    L141
```

assistant: ```c
int get_min_steps(int n, int *memo) {
  int res;
  if (n == 1)
    return 0;
  if (memo[n] != -1)
    return memo[n];
  res = 1 + get_min_steps(n - 1, memo);
  if (n % 2 == 0) {
    if (res > (1 + get_min_steps(n / 2, memo)))
      res = 1 + get_min_steps(n / 2, memo);
  }
  if (n % 3 == 0) {
    if (res > (1 + get_min_steps(n / 3, memo)))
      res = 1 + get_min_steps(n / 3, memo);
  }
  memo[n] = res;
  return res;
}
```