ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmgr_backtrace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x68(%rbp)
  lea    -0x60(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <backtrace@plt>
  mov    %eax,-0x6c(%rbp)
  mov    -0x6c(%rbp),%edx
  lea    -0x60(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <backtrace_symbols@plt>
  mov    %rax,-0x68(%rbp)
  movl   $0x1,-0x70(%rbp)
  jmp    L10
L5:
  addl   $0x1,-0x70(%rbp)
L10:
  mov    -0x70(%rbp),%eax
  cmp    -0x6c(%rbp),%eax
  jl     L5
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
void cmgr_backtrace(void) {
  void *trace[10];
  char **messages = NULL;
  int i, trace_size;
  trace_size = backtrace(trace, 10);
  messages = backtrace_symbols(trace, trace_size);
  for (i = 1; i < trace_size; i++) {
    ;
  }
  free(messages);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmgr_backtrace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <backtrace@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <backtrace_symbols@plt>
  mov    %rax,%rdi
  cmp    $0x1,%ebx
  jle    L16
  mov    $0x1,%edx
L3:
  add    $0x1,%edx
  cmp    %edx,%ebx
  jne    L3
L16:
  call   <free@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmgr_backtrace(void) {
  void *trace[10];
  char **messages = NULL;
  int i, trace_size;
  trace_size = backtrace(trace, 10);
  messages = backtrace_symbols(trace, trace_size);
  for (i = 1; i < trace_size; i++) {
    ;
  }
  free(messages);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cmgr_backtrace>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <backtrace@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <backtrace_symbols@plt>
  mov    %rax,%rdi
  call   <free@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x60,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmgr_backtrace(void) {
  void *trace[10];
  char **messages = NULL;
  int i, trace_size;
  trace_size = backtrace(trace, 10);
  messages = backtrace_symbols(trace, trace_size);
  for (i = 1; i < trace_size; i++) {
    ;
  }
  free(messages);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmgr_backtrace>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <backtrace@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <backtrace_symbols@plt>
  mov    %rax,%rdi
  call   <free@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x60,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmgr_backtrace(void) {
  void *trace[10];
  char **messages = NULL;
  int i, trace_size;
  trace_size = backtrace(trace, 10);
  messages = backtrace_symbols(trace, trace_size);
  for (i = 1; i < trace_size; i++) {
    ;
  }
  free(messages);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd8(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int snprintf(char *str, size_t n, const char *fmt, ...) {
  va_list ap;
  int rval;
  va_start(ap, fmt);
  rval = vsprintf(str, fmt, ap);
  va_end(ap);
  return (rval);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<snprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int snprintf(char *str, size_t n, const char *fmt, ...) {
  va_list ap;
  int rval;
  va_start(ap, fmt);
  rval = vsprintf(str, fmt, ap);
  va_end(ap);
  return (rval);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<snprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rdx,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int snprintf(char *str, size_t n, const char *fmt, ...) {
  va_list ap;
  int rval;
  va_start(ap, fmt);
  rval = vsprintf(str, fmt, ap);
  va_end(ap);
  return (rval);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<snprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rdx,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int snprintf(char *str, size_t n, const char *fmt, ...) {
  va_list ap;
  int rval;
  va_start(ap, fmt);
  rval = vsprintf(str, fmt, ap);
  va_end(ap);
  return (rval);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<state_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L4
  lea    D19(%rip),%rax
  jmp    L2
L4:
  cmpl   $0x0,-0x4(%rbp)
  jne    L17
  lea    D33(%rip),%rax
  jmp    L2
L17:
  cmpl   $0x1,-0x4(%rbp)
  jne    L38
  lea    D25(%rip),%rax
  jmp    L2
L38:
  lea    D18(%rip),%rax
L2:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type_infered: string
name: extract_symbolic_data
arguments: tag: D33
type_infered: string
name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D18
type_infered: string

tool: D19: unknown

tool: D33: sleeping

tool: D25: active

tool: D18: internal error

assistant: ```c
char *state_name(int i) {
  if (i == -1) {
    return "unknown";
  }
  if (i == 0) {
    return "sleeping";
  }
  if (i == 1) {
    return "active";
  }
  return "internal error";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<state_name>:
  endbr64
  lea    D17(%rip),%rax
  cmp    $0xffffffff,%edi
  je     L8
  lea    D8(%rip),%rax
  test   %edi,%edi
  je     L8
  cmp    $0x1,%edi
  lea    D35(%rip),%rax
  lea    D28(%rip),%rdx
  cmove  %rdx,%rax
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string
name: extract_symbolic_data
arguments: data_label: D35
type: string
name: extract_symbolic_data
arguments: data_label: D28
type: string

tool: D17: unknown

tool: D8: sleeping

tool: D35: internal error

tool: D28: active

assistant: ```c
char *state_name(int i) {
  if (i == -1) {
    return "unknown";
  }
  if (i == 0) {
    return "sleeping";
  }
  if (i == 1) {
    return "active";
  }
  return "internal error";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<state_name>:
  endbr64
  lea    D11(%rip),%rax
  cmp    $0xffffffff,%edi
  je     L12
  lea    D30(%rip),%rax
  test   %edi,%edi
  je     L12
  cmp    $0x1,%edi
  lea    D26(%rip),%rax
  lea    D12(%rip),%rdx
  cmove  %rdx,%rax
L12:
  ret
```

tool_calls: name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D30
type: string
name: read_data
arguments: label: D26
type: string
name: read_data
arguments: label: D12
type: string

tool: D11: unknown

tool: D30: sleeping

tool: D26: internal error

tool: D12: active

assistant: ```c
char *state_name(int i) {
  if (i == -1) {
    return "unknown";
  }
  if (i == 0) {
    return "sleeping";
  }
  if (i == 1) {
    return "active";
  }
  return "internal error";
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<state_name>:
  endbr64
  lea    D32(%rip),%rax
  cmp    $0xffffffff,%edi
  je     L11
  lea    D15(%rip),%rax
  test   %edi,%edi
  je     L11
  cmp    $0x1,%edi
  lea    D19(%rip),%rax
  lea    D38(%rip),%rdx
  cmove  %rdx,%rax
L11:
  ret
```

tool_calls: name: read_data
arguments: tag: D32
type_guessed: string
name: read_data
arguments: tag: D15
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D38
type_guessed: string

tool: D32: unknown

tool: D15: sleeping

tool: D19: internal error

tool: D38: active

assistant: ```c
char *state_name(int i) {
  if (i == -1) {
    return "unknown";
  }
  if (i == 0) {
    return "sleeping";
  }
  if (i == 1) {
    return "active";
  }
  return "internal error";
}
```
user: What is the c source code of the assembly code below?

```asm
<MHD_str_equal_caseless_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  jmp    L34
L46:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  je     L17
  movsbl -0x12(%rbp),%eax
  mov    %eax,%edi
  call   <toasciilower@plt>
  mov    %rax,%rbx
  movsbl -0x11(%rbp),%eax
  mov    %eax,%edi
  call   <toasciilower@plt>
  cmp    %rax,%rbx
  je     L17
  mov    $0x0,%eax
  jmp    L23
L17:
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
L34:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
L23:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int MHD_str_equal_caseless_(const char *str1, const char *str2) {
  while (0 != (*str1)) {
    const char c1 = *str1;
    const char c2 = *str2;
    if ((c1 != c2) && (toasciilower(c1) != toasciilower(c2)))
      return 0;
    str1++;
    str2++;
  }
  return 0 == (*str2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MHD_str_equal_caseless_>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L27
L39:
  cmpb   $0x0,0x0(%rbp)
  sete   %al
  movzbl %al,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  add    $0x1,%r12
  add    $0x1,%rbp
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L39
L27:
  movzbl 0x0(%rbp),%ebx
  cmp    %dil,%bl
  je     L14
  movsbl %dil,%edi
  call   <toasciilower@plt>
  mov    %rax,%r13
  movsbl %bl,%edi
  call   <toasciilower@plt>
  cmp    %rax,%r13
  je     L14
  mov    $0x0,%eax
  jmp    L4
```

assistant: ```c
int MHD_str_equal_caseless_(const char *str1, const char *str2) {
  while (0 != (*str1)) {
    const char c1 = *str1;
    const char c2 = *str2;
    if ((c1 != c2) && (toasciilower(c1) != toasciilower(c2)))
      return 0;
    str1++;
    str2++;
  }
  return 0 == (*str2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MHD_str_equal_caseless_>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
  nopl   0x0(%rax)
L34:
  movzbl 0x0(%rbp),%ebx
  cmp    %dil,%bl
  je     L0
  call   <toasciilower@plt>
  movsbl %bl,%edi
  mov    %rax,%r13
  call   <toasciilower@plt>
  cmp    %rax,%r13
  jne    L38
L0:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %dil,%dil
  jne    L34
L7:
  xor    %eax,%eax
  cmpb   $0x0,0x0(%rbp)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L38:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int MHD_str_equal_caseless_(const char *str1, const char *str2) {
  while (0 != (*str1)) {
    const char c1 = *str1;
    const char c2 = *str2;
    if ((c1 != c2) && (toasciilower(c1) != toasciilower(c2)))
      return 0;
    str1++;
    str2++;
  }
  return 0 == (*str2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MHD_str_equal_caseless_>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L9
  nopl   0x0(%rax)
L34:
  movzbl 0x0(%rbp),%ebx
  cmp    %dil,%bl
  je     L8
  call   <toasciilower@plt>
  movsbl %bl,%edi
  mov    %rax,%r13
  call   <toasciilower@plt>
  cmp    %rax,%r13
  jne    L14
L8:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %dil,%dil
  jne    L34
L9:
  xor    %eax,%eax
  cmpb   $0x0,0x0(%rbp)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int MHD_str_equal_caseless_(const char *str1, const char *str2) {
  while (0 != (*str1)) {
    const char c1 = *str1;
    const char c2 = *str2;
    if ((c1 != c2) && (toasciilower(c1) != toasciilower(c2)))
      return 0;
    str1++;
    str2++;
  }
  return 0 == (*str2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%eax
  cltq
  mov    (%rsi,%rax,4),%edx
  mov    -0x20(%rbp),%eax
  cltq
  mov    %edx,(%rcx,%rax,4)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int deck[][13], int x1, int y1, int x2, int y2) {
  int j;
  j = deck[x1][y1];
  deck[x1][y1] = deck[x2][y2];
  deck[x2][y2] = j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap>:
  endbr64
  mov    %rdi,%rax
  movslq %esi,%rsi
  lea    (%rsi,%rsi,2),%rdi
  lea    (%rsi,%rdi,4),%rsi
  lea    (%rax,%rsi,4),%rsi
  movslq %edx,%rdx
  mov    (%rsi,%rdx,4),%edi
  movslq %ecx,%rcx
  lea    (%rcx,%rcx,2),%r9
  lea    (%rcx,%r9,4),%rcx
  lea    (%rax,%rcx,4),%rax
  movslq %r8d,%r8
  mov    (%rax,%r8,4),%ecx
  mov    %ecx,(%rsi,%rdx,4)
  mov    %edi,(%rax,%r8,4)
  ret
```

assistant: ```c
void swap(int deck[][13], int x1, int y1, int x2, int y2) {
  int j;
  j = deck[x1][y1];
  deck[x1][y1] = deck[x2][y2];
  deck[x2][y2] = j;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %ecx,%rcx
  mov    %rdi,%rax
  movslq %edx,%rdx
  lea    (%rsi,%rsi,2),%rdi
  lea    (%rcx,%rcx,2),%r9
  movslq %r8d,%r8
  lea    (%rsi,%rdi,4),%rsi
  lea    (%rcx,%r9,4),%rcx
  lea    (%rax,%rsi,4),%rsi
  lea    (%rax,%rcx,4),%rax
  mov    (%rsi,%rdx,4),%edi
  mov    (%rax,%r8,4),%ecx
  mov    %ecx,(%rsi,%rdx,4)
  mov    %edi,(%rax,%r8,4)
  ret
```

assistant: ```c
void swap(int deck[][13], int x1, int y1, int x2, int y2) {
  int j;
  j = deck[x1][y1];
  deck[x1][y1] = deck[x2][y2];
  deck[x2][y2] = j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %ecx,%rcx
  mov    %rdi,%rax
  movslq %edx,%rdx
  lea    (%rsi,%rsi,2),%rdi
  lea    (%rcx,%rcx,2),%r9
  movslq %r8d,%r8
  lea    (%rsi,%rdi,4),%rsi
  lea    (%rcx,%r9,4),%rcx
  lea    (%rax,%rsi,4),%rsi
  lea    (%rax,%rcx,4),%rax
  mov    (%rsi,%rdx,4),%edi
  mov    (%rax,%r8,4),%ecx
  mov    %ecx,(%rsi,%rdx,4)
  mov    %edi,(%rax,%r8,4)
  ret
```

assistant: ```c
void swap(int deck[][13], int x1, int y1, int x2, int y2) {
  int j;
  j = deck[x1][y1];
  deck[x1][y1] = deck[x2][y2];
  deck[x2][y2] = j;
}
```
user: What is the c source code of the assembly code below?

```asm
<dek_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L9:
  mov    -0x8(%rbp),%eax
  rol    $0x5,%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int dek_hash(const char *str, unsigned int len) {
  unsigned int hash;
  unsigned int c;
  hash = len;
  c = 0;
  while ((c = (unsigned int)*str++))
    hash = ((hash << 5) ^ (hash >> 27)) ^ (c);
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dek_hash>:
  endbr64
  mov    %esi,%eax
  lea    0x1(%rdi),%rcx
  movsbl (%rdi),%edx
  test   %edx,%edx
  je     L0
L17:
  rol    $0x5,%eax
  xor    %edx,%eax
  add    $0x1,%rcx
  movsbl -0x1(%rcx),%edx
  test   %edx,%edx
  jne    L17
L0:
  ret
```

assistant: ```c
unsigned int dek_hash(const char *str, unsigned int len) {
  unsigned int hash;
  unsigned int c;
  hash = len;
  c = 0;
  while ((c = (unsigned int)*str++))
    hash = ((hash << 5) ^ (hash >> 27)) ^ (c);
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dek_hash>:
  endbr64
  movsbl (%rdi),%edx
  mov    %esi,%eax
  lea    0x1(%rdi),%rcx
  test   %edx,%edx
  je     L15
  nopl   0x0(%rax)
L5:
  rol    $0x5,%eax
  add    $0x1,%rcx
  xor    %edx,%eax
  movsbl -0x1(%rcx),%edx
  test   %edx,%edx
  jne    L5
L15:
  ret
```

assistant: ```c
unsigned int dek_hash(const char *str, unsigned int len) {
  unsigned int hash;
  unsigned int c;
  hash = len;
  c = 0;
  while ((c = (unsigned int)*str++))
    hash = ((hash << 5) ^ (hash >> 27)) ^ (c);
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dek_hash>:
  endbr64
  movsbl (%rdi),%edx
  mov    %esi,%eax
  lea    0x1(%rdi),%rcx
  test   %edx,%edx
  je     L3
  nopl   0x0(%rax)
L13:
  rol    $0x5,%eax
  add    $0x1,%rcx
  xor    %edx,%eax
  movsbl -0x1(%rcx),%edx
  test   %edx,%edx
  jne    L13
L3:
  ret
```

assistant: ```c
unsigned int dek_hash(const char *str, unsigned int len) {
  unsigned int hash;
  unsigned int c;
  hash = len;
  c = 0;
  while ((c = (unsigned int)*str++))
    hash = ((hash << 5) ^ (hash >> 27)) ^ (c);
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrixLowerTriangularInverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   %eax,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <Malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L67
L5:
  movl   $0x0,-0x1c(%rbp)
  jmp    L4
L96:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L96
  addl   $0x1,-0x20(%rbp)
L67:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L5
  mov    -0x2c(%rbp),%edx
  mov    -0x2c(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <linpackDTRDI@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <matrixNew@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L38
L22:
  movl   $0x0,-0x1c(%rbp)
  jmp    L68
L74:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L32
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L2
L32:
  pxor   %xmm0,%xmm0
L2:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L68:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L74
  addl   $0x1,-0x20(%rbp)
L38:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L22
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **matrixLowerTriangularInverse(double **matrix, int n) {
  int i, j, k, info;
  double *t, **result;
  t = (double *)Malloc(n * n * sizeof(double));
  k = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      t[k] = matrix[j][i];
      k++;
    }
  }
  info = linpackDTRDI(t, n, n);
  result = matrixNew(n, n);
  k = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      result[j][i] = i > j ? 0.0 : t[k];
      k++;
    }
  }
  free(t);
  return (result);
}
```