user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    -0x94(%rbp),%rsi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movslq -0x94(%rbp),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L38:
  cmp    %rdx,%rsp
  je     L32
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L38
L32:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L152
  orq    $0x0,-0x8(%rsp,%rdx,1)
L152:
  mov    %rsp,%r12
  mov    %r12,-0xa8(%rbp)
  lea    D40(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,-0x94(%rbp)
  jle    L28
  mov    $0x0,%ebx
  lea    D27(%rip),%r13
L31:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x94(%rbp),%eax
  add    $0x50,%r12
  cmp    %ebx,%eax
  jg     L31
  test   %eax,%eax
  jle    L28
  mov    $0x0,%r14d
  lea    -0x90(%rbp),%r15
  jmp    L22
L143:
  add    $0x1,%r12d
  add    $0x50,%rbx
  cmp    %r12d,-0x94(%rbp)
  jle    L3
L6:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jg     L143
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L143
L3:
  add    $0x1,%r14
  cmp    %r14d,-0x94(%rbp)
  jle    L28
L22:
  cmpl   $0x0,-0x94(%rbp)
  jle    L3
  lea    (%r14,%r14,4),%r13
  shl    $0x4,%r13
  mov    -0xa8(%rbp),%rbx
  add    %rbx,%r13
  mov    $0x0,%r12d
  jmp    L6
L28:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,-0x94(%rbp)
  jle    L147
  mov    -0xa8(%rbp),%rbx
  mov    $0x0,%r12d
  lea    D43(%rip),%r13
L77:
  add    $0x1,%r12d
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x50,%rbx
  cmp    -0x94(%rbp),%r12d
  jl     L77
L147:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D61
type_infered: string
name: parse_data
arguments: label: D48
type_infered: string
name: parse_data
arguments: label: D40
type_infered: string
name: parse_data
arguments: label: D27
type_infered: string
name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D43
type_infered: string

tool: D61: Enter the strength of the class: 

tool: D48: %d

tool: D40: Enter the names of the students:

tool: D27: %s

tool: D29: 
Students in the class: 

tool: D18: -----------------------

tool: D43: %d %s


assistant: ```c
int main() {
  int n, i, j;
  printf("Enter the strength of the class: ");
  scanf("%d", &n);
  char class[n][80];
  printf("Enter the names of the students:\n");
  for (i = 0; i < n; i++)
    scanf("%s", class[i]);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (strcmp(class[i], class[j]) <= 0) {
        char temp[80];
        strcpy(temp, class[i]);
        strcpy(class[i], class[j]);
        strcpy(class[j], temp);
      }
    }
  }
  printf("\nStudents in the class: \n");
  printf("-----------------------\n");
  for (i = 0; i < n; i++)
    printf("%d %s\n", i + 1, class[i]);
}
```