user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D58(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  add    0x8(%rsp),%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  js     L101
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D59(%rip),%r12
  lea    D32(%rip),%r13
  jmp    L152
L144:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jl     L101
L152:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jne    L144
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L144
L101:
  cmpl   $0x0,0xc(%rsp)
  js     L102
  lea    0x50(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D59(%rip),%r12
  lea    D32(%rip),%r13
  jmp    L6
L150:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jl     L102
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    %ebx,0xc(%rsp)
  jne    L150
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L150
L102:
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%r8d
  mov    %esi,%eax
  add    %r8d,%eax
  js     L99
  lea    0x10(%rsp),%r13
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  lea    0x50(%rsp),%r12
  lea    D59(%rip),%r14
  jmp    L26
L117:
  mov    (%rdx),%ecx
  imul   (%r12,%rax,4),%ecx
  add    %ecx,%edi
L49:
  add    $0x1,%rax
  sub    $0x4,%rdx
  cmp    %rbp,%rax
  je     L173
L94:
  mov    %ebx,%ecx
  sub    %eax,%ecx
  cmp    %ecx,%esi
  jl     L49
  cmp    %eax,%r8d
  jge    L117
  jmp    L49
L173:
  mov    %edi,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%r8d
  add    $0x1,%rbp
  add    $0x4,%r13
  lea    (%rsi,%r8,1),%eax
  cmp    %ebx,%eax
  jl     L99
L26:
  mov    %r13,%rdx
  mov    $0x0,%eax
  mov    $0x0,%edi
  test   %ebx,%ebx
  jns    L94
  jmp    L173
L99:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D58
type_infered: string
name: retrieve_data
arguments: data_label: D27
type_infered: string
name: retrieve_data
arguments: data_label: D59
type_infered: string
name: retrieve_data
arguments: data_label: D32
type_infered: string

tool: D58: %d %d

tool: D27: %d


tool: D59: %d 

tool: D32: 


assistant: ```c
int main() {
  int a[15], b[15];
  int n1, n2, p, j, i, c, n;
  scanf("%d %d", &n1, &n2);
  printf("%d\n", n1 + n2);
  for (p = 0; p <= n1; p++) {
    scanf("%d ", &a[p]);
    if (p == n1) {
      scanf("\n");
    } else {
      continue;
    }
  }
  for (j = 0; j <= n2; j++) {
    scanf("%d ", &b[j]);
    if (j == n2) {
      scanf("\n");
    } else {
      continue;
    }
  }
  for (i = 0; i <= n1 + n2; i++) {
    c = 0;
    for (n = 0; n <= i; n++) {
      if (i - n <= n1 && n <= n2) {
        c = a[i - n] * b[n] + c;
      } else {
        continue;
      }
    }
    printf("%d ", c);
  }
  return 0;
}
```