ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  sub    $0x58,%rsp
  movaps D14(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x30(%rsp),%rbp
  mov    D30(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  movaps D10(%rip),%xmm0
  mov    %r12,%rdi
  mov    %rax,0x40(%rsp)
  movl   $0x3ecccccd,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <median@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <median@plt>
  movss  0xc(%rsp),%xmm2
  mov    $0x2,%eax
  lea    D13(%rip),%rdi
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x5,%esi
  call   <printFloatArray@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printFloatArray@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type: f32[4]
name: extract_symbolic_data
arguments: data_tag: D30
type: f32[2]
name: extract_symbolic_data
arguments: data_tag: D10
type: f32[4]
name: extract_symbolic_data
arguments: data_tag: D13
type: string

tool: {"D14": [3.1414999961853027,2.0999999046325684,16.329999923706055,14.0]}

tool: {"D30": [1.100000023841858,16.0]}

tool: {"D10": [3.4000000953674316,7.0,22.329999923706055,31.600000381469727]}

tool: D13: Median value for a1: %f
Median value for a2: %f


assistant: ```c
int main(void) {
  float a1[5] = {3.1415, 2.1, 16.33, 14, 0.4};
  float a2[6] = {3.4, 7, 22.33, 31.6, 1.1, 16};
  float medianA1, medianA2;
  medianA1 = median(a1, 5);
  medianA2 = median(a2, 6);
  printf("Median value for a1: %f\nMedian value for a2: %f\n", medianA1, medianA2);
  printFloatArray(a1, 5);
  printFloatArray(a2, 6);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <cubeRoot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D32
type: string
name: retrieve_data
arguments: data_tag: D2
type: string

tool: D10: This program return the cube root of a number.

tool: D19:  ? 

tool: D32: %d

tool: D2: The cube root is %g.


assistant: ```c
int main(int argc, const char *argv[]) {
  int x;
  printf("This program return the cube root of a number.");
  printf(" ? ");
  scanf("%d", &x);
  printf("The cube root is %g.\n", cubeRoot(x));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <cubeRoot@plt>
  lea    D12(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D25
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string

tool: D25: This program return the cube root of a number.

tool: D14:  ? 

tool: D2: %d

tool: D12: The cube root is %g.


assistant: ```c
int main(int argc, const char *argv[]) {
  int x;
  printf("This program return the cube root of a number.");
  printf(" ? ");
  scanf("%d", &x);
  printf("The cube root is %g.\n", cubeRoot(x));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <cubeRoot@plt>
  lea    D10(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D33
type_guessed: string
name: disassemble_data
arguments: tag: D29
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string

tool: D33: This program return the cube root of a number.

tool: D29:  ? 

tool: D12: %d

tool: D10: The cube root is %g.


assistant: ```c
int main(int argc, const char *argv[]) {
  int x;
  printf("This program return the cube root of a number.");
  printf(" ? ");
  scanf("%d", &x);
  printf("The cube root is %g.\n", cubeRoot(x));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <cubeRoot@plt>
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type_infered: string
name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D24
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string

tool: D11: This program return the cube root of a number.

tool: D15:  ? 

tool: D24: %d

tool: D19: The cube root is %g.


assistant: ```c
int main(int argc, const char *argv[]) {
  int x;
  printf("This program return the cube root of a number.");
  printf(" ? ");
  scanf("%d", &x);
  printf("The cube root is %g.\n", cubeRoot(x));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ShMemFree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <munmap@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  cmpl   $0x0,-0x28(%rbp)
  je     L2
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <shm_unlink@plt>
  mov    %eax,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ShMemFree(unsigned char *p, char *memname, int size, int unlink, int fd) {
  int s = 0;
  munmap(p, size);
  close(fd);
  if (unlink)
    s = shm_unlink(memname);
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ShMemFree>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %edx,%esi
  mov    %ecx,%ebx
  mov    %r8d,%ebp
  call   <munmap@plt>
  mov    %ebp,%edi
  call   <close@plt>
  test   %ebx,%ebx
  jne    L19
L14:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %r12,%rdi
  call   <shm_unlink@plt>
  mov    %eax,%ebx
  jmp    L14
```

assistant: ```c
int ShMemFree(unsigned char *p, char *memname, int size, int unlink, int fd) {
  int s = 0;
  munmap(p, size);
  close(fd);
  if (unlink)
    s = shm_unlink(memname);
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ShMemFree>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edx,%esi
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <munmap@plt>
  mov    %ebp,%edi
  call   <close@plt>
  test   %ebx,%ebx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <shm_unlink@plt>
```

assistant: ```c
int ShMemFree(unsigned char *p, char *memname, int size, int unlink, int fd) {
  int s = 0;
  munmap(p, size);
  close(fd);
  if (unlink)
    s = shm_unlink(memname);
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ShMemFree>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edx,%esi
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <munmap@plt>
  mov    %ebp,%edi
  call   <close@plt>
  test   %ebx,%ebx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <shm_unlink@plt>
```

assistant: ```c
int ShMemFree(unsigned char *p, char *memname, int size, int unlink, int fd) {
  int s = 0;
  munmap(p, size);
  close(fd);
  if (unlink)
    s = shm_unlink(memname);
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<target_data_list_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <util_list_start@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <util_list_next@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L12
L19:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <util_list_remove@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <target_data_free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <util_list_next@plt>
  mov    %rax,-0x8(%rbp)
L12:
  cmpq   $0x0,-0x10(%rbp)
  jne    L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <util_list_free@plt>
  nop
  leave
  ret
```

assistant: ```c
void target_data_list_free(struct util_list *data) {
  struct target_data *td, *n;
  for (td = util_list_start(data), n = util_list_next(data, td); td != NULL; td = n, n = util_list_next(data, td)) {
    util_list_remove(data, td);
    target_data_free(td);
  }
  util_list_free(data);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<target_data_list_free>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <util_list_start@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <util_list_next@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L8
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <util_list_remove@plt>
  mov    %rbp,%rdi
  call   <target_data_free@plt>
  mov    %rbx,%rbp
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <util_list_next@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  jne    L14
L8:
  mov    %r12,%rdi
  call   <util_list_free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void target_data_list_free(struct util_list *data) {
  struct target_data *td, *n;
  for (td = util_list_start(data), n = util_list_next(data, td); td != NULL; td = n, n = util_list_next(data, td)) {
    util_list_remove(data, td);
    target_data_free(td);
  }
  util_list_free(data);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<target_data_list_free>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <util_list_start@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <util_list_next@plt>
  test   %rbp,%rbp
  je     L6
  mov    %rax,%rbx
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <util_list_remove@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rbp
  call   <target_data_free@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <util_list_next@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  jne    L8
L6:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <util_list_free@plt>
```

assistant: ```c
void target_data_list_free(struct util_list *data) {
  struct target_data *td, *n;
  for (td = util_list_start(data), n = util_list_next(data, td); td != NULL; td = n, n = util_list_next(data, td)) {
    util_list_remove(data, td);
    target_data_free(td);
  }
  util_list_free(data);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<target_data_list_free>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <util_list_start@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <util_list_next@plt>
  test   %rbp,%rbp
  je     L13
  mov    %rax,%rbx
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <util_list_remove@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rbp
  call   <target_data_free@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <util_list_next@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  jne    L3
L13:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <util_list_free@plt>
```

assistant: ```c
void target_data_list_free(struct util_list *data) {
  struct target_data *td, *n;
  for (td = util_list_start(data), n = util_list_next(data, td); td != NULL; td = n, n = util_list_next(data, td)) {
    util_list_remove(data, td);
    target_data_free(td);
  }
  util_list_free(data);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<conv_argb8888_0rgb1555>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %ecx,-0x48(%rbp)
  mov    %r8d,-0x4c(%rbp)
  mov    %r9d,-0x50(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L18
L11:
  movl   $0x0,-0x24(%rbp)
  jmp    L33
L34:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0x13,%eax
  and    $0x1f,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0xb,%eax
  and    $0x1f,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0x3,%eax
  and    $0x1f,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0xa,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x5,%eax
  or     %edx,%eax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  or     -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x24(%rbp)
L33:
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L34
  addl   $0x1,-0x28(%rbp)
  mov    -0x4c(%rbp),%eax
  sar    %eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x50(%rbp),%eax
  sar    $0x2,%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x10(%rbp)
L18:
  mov    -0x28(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void conv_argb8888_0rgb1555(void *output_, const void *input_, int width, int height, int out_stride, int in_stride) {
  int h, w;
  const uint32_t *input = (const uint32_t *)input_;
  uint16_t *output = (uint16_t *)output_;
  for (h = 0; h < height; h++, output += out_stride >> 1, input += in_stride >> 2) {
    for (w = 0; w < width; w++) {
      uint32_t col = input[w];
      uint16_t r = (col >> 19) & 0x1f;
      uint16_t g = (col >> 11) & 0x1f;
      uint16_t b = (col >> 3) & 0x1f;
      output[w] = (r << 10) | (g << 5) | (b << 0);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<conv_argb8888_0rgb1555>:
  endbr64
  test   %ecx,%ecx
  jle    L0
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r10d
  mov    %ecx,%r11d
  sar    %r8d
  movslq %r8d,%rbp
  shl    $0x2,%rbp
  sar    $0x2,%r9d
  movslq %r9d,%rbx
  shl    $0x2,%rbx
  mov    $0x0,%r9d
  mov    %edx,%r8d
  jmp    L23
L2:
  mov    (%rsi,%rcx,4),%edx
  mov    %edx,%eax
  shr    $0x9,%eax
  and    $0x7c00,%eax
  mov    %edx,%r12d
  shr    $0x6,%r12d
  and    $0x3e0,%r12d
  or     %r12d,%eax
  sar    $0x3,%edx
  and    $0x1f,%edx
  or     %edx,%eax
  mov    %eax,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%r8
  jne    L2
L49:
  add    $0x1,%r9d
  add    %rbp,%rdi
  add    %rbx,%rsi
  cmp    %r9d,%r11d
  je     L1
L23:
  mov    $0x0,%ecx
  test   %r10d,%r10d
  jg     L2
  jmp    L49
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  ret
```

assistant: ```c
void conv_argb8888_0rgb1555(void *output_, const void *input_, int width, int height, int out_stride, int in_stride) {
  int h, w;
  const uint32_t *input = (const uint32_t *)input_;
  uint16_t *output = (uint16_t *)output_;
  for (h = 0; h < height; h++, output += out_stride >> 1, input += in_stride >> 2) {
    for (w = 0; w < width; w++) {
      uint32_t col = input[w];
      uint16_t r = (col >> 19) & 0x1f;
      uint16_t g = (col >> 11) & 0x1f;
      uint16_t b = (col >> 3) & 0x1f;
      output[w] = (r << 10) | (g << 5) | (b << 0);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<conv_argb8888_0rgb1555>:
  endbr64
  test   %ecx,%ecx
  jle    L37
  sar    %r8d
  sar    $0x2,%r9d
  push   %r12
  mov    %edx,%r10d
  push   %rbp
  movslq %r8d,%rbp
  mov    %ecx,%r11d
  movslq %edx,%r8
  push   %rbx
  movslq %r9d,%rbx
  shl    $0x2,%rbp
  xor    %r9d,%r9d
  shl    $0x2,%rbx
  nopl   (%rax)
L12:
  xor    %ecx,%ecx
  test   %r10d,%r10d
  jle    L5
  nopw   0x0(%rax,%rax,1)
L34:
  mov    (%rsi,%rcx,4),%edx
  mov    %edx,%eax
  mov    %edx,%r12d
  sar    $0x3,%edx
  shr    $0x9,%eax
  shr    $0x6,%r12d
  and    $0x1f,%edx
  and    $0x7c00,%eax
  and    $0x3e0,%r12d
  or     %r12d,%eax
  or     %edx,%eax
  mov    %eax,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L34
L5:
  add    $0x1,%r9d
  add    %rbp,%rdi
  add    %rbx,%rsi
  cmp    %r9d,%r11d
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  ret
```

assistant: ```c
void conv_argb8888_0rgb1555(void *output_, const void *input_, int width, int height, int out_stride, int in_stride) {
  int h, w;
  const uint32_t *input = (const uint32_t *)input_;
  uint16_t *output = (uint16_t *)output_;
  for (h = 0; h < height; h++, output += out_stride >> 1, input += in_stride >> 2) {
    for (w = 0; w < width; w++) {
      uint32_t col = input[w];
      uint16_t r = (col >> 19) & 0x1f;
      uint16_t g = (col >> 11) & 0x1f;
      uint16_t b = (col >> 3) & 0x1f;
      output[w] = (r << 10) | (g << 5) | (b << 0);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TableHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x8,-0x8(%rbp)
  jmp    L26
L12:
  mov    -0x8(%rbp),%eax
  cmp    $0x19,%eax
  jbe    L20
  mov    -0x8(%rbp),%eax
  sub    $0x1a,%eax
  mov    %eax,-0x8(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  xor    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x7,-0x8(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int TableHash(const char *Key, int Len) {
  unsigned int Hash = Len;
  int Offset;
  int Count;
  for (Count = 0, Offset = 8; Count < Len; Count++, Offset += 7) {
    if (Offset > sizeof(unsigned int) * 8 - 7)
      Offset -= sizeof(unsigned int) * 8 - 6;
    Hash ^= *Key++ << Offset;
  }
  return Hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<TableHash>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L21
  mov    %rdi,%r8
  lea    -0x1(%rsi),%edx
  add    %rdx,%rdi
  mov    $0x8,%ecx
  jmp    L8
L26:
  sub    $0x13,%ecx
  cmp    $0x19,%edx
  cmovbe %edx,%ecx
  add    $0x1,%r8
L8:
  movsbl (%r8),%edx
  shl    %cl,%edx
  xor    %edx,%eax
  lea    0x7(%rcx),%edx
  cmp    %rdi,%r8
  jne    L26
L21:
  ret
```

assistant: ```c
unsigned int TableHash(const char *Key, int Len) {
  unsigned int Hash = Len;
  int Offset;
  int Count;
  for (Count = 0, Offset = 8; Count < Len; Count++, Offset += 7) {
    if (Offset > sizeof(unsigned int) * 8 - 7)
      Offset -= sizeof(unsigned int) * 8 - 6;
    Hash ^= *Key++ << Offset;
  }
  return Hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TableHash>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L26
  lea    -0x1(%rsi),%esi
  mov    $0x8,%ecx
  add    %rdi,%rsi
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L15:
  sub    $0x13,%ecx
  cmp    $0x19,%edx
  cmovbe %edx,%ecx
  add    $0x1,%rdi
L28:
  movsbl (%rdi),%edx
  shl    %cl,%edx
  xor    %edx,%eax
  lea    0x7(%rcx),%edx
  cmp    %rsi,%rdi
  jne    L15
L26:
  ret
```

assistant: ```c
unsigned int TableHash(const char *Key, int Len) {
  unsigned int Hash = Len;
  int Offset;
  int Count;
  for (Count = 0, Offset = 8; Count < Len; Count++, Offset += 7) {
    if (Offset > sizeof(unsigned int) * 8 - 7)
      Offset -= sizeof(unsigned int) * 8 - 6;
    Hash ^= *Key++ << Offset;
  }
  return Hash;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TableHash>:
  endbr64
  test   %esi,%esi
  jle    L40
  movsbl (%rdi),%eax
  lea    0x1(%rdi),%r8
  shl    $0x8,%eax
  xor    %esi,%eax
  cmp    $0x1,%esi
  je     L3
  lea    -0x2(%rsi),%edx
  mov    $0x8,%ecx
  lea    0x2(%rdi,%rdx,1),%rdi
  mov    $0xf,%edx
  nopl   0x0(%rax,%rax,1)
L11:
  cmp    $0x19,%edx
  jbe    L5
  movsbl (%r8),%esi
  mov    %ecx,%edx
  sub    $0x13,%ecx
  add    $0x1,%r8
  sub    $0xc,%edx
  shl    %cl,%esi
  xor    %esi,%eax
  cmp    %r8,%rdi
  jne    L11
  ret
  nop
L5:
  movsbl (%r8),%esi
  mov    %edx,%ecx
  add    $0x1,%r8
  shl    %cl,%esi
  xor    %esi,%eax
  lea    0x7(%rdx),%esi
  cmp    %r8,%rdi
  je     L3
  mov    %edx,%ecx
  mov    %esi,%edx
  jmp    L11
  nopl   0x0(%rax)
L40:
  mov    %esi,%eax
L3:
  ret
```

assistant: ```c
unsigned int TableHash(const char *Key, int Len) {
  unsigned int Hash = Len;
  int Offset;
  int Count;
  for (Count = 0, Offset = 8; Count < Len; Count++, Offset += 7) {
    if (Offset > sizeof(unsigned int) * 8 - 7)
      Offset -= sizeof(unsigned int) * 8 - 6;
    Hash ^= *Key++ << Offset;
  }
  return Hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_station_ifname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <if_nametoindex@plt>
  test   %rax,%rax
  jle    L24
  lea    D23(%rip),%rax
  jmp    L7
L24:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <if_nametoindex@plt>
  test   %rax,%rax
  jle    L27
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <if_nametoindex@plt>
  test   %rax,%rax
  jle    L27
  lea    D51(%rip),%rax
  jmp    L7
L27:
  lea    D51(%rip),%rax
L7:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D23
datatype: string
name: parse_data
arguments: label: D26
datatype: string
name: parse_data
arguments: label: D51
datatype: string

tool: D23: eth1

tool: D26: wlan1

tool: D51: wlan0

assistant: ```c
char *get_station_ifname(void) {
  if (if_nametoindex("eth1") > 0)
    return "eth1";
  if (if_nametoindex("wlan1") > 0 && if_nametoindex("wlan0") > 0)
    return "wlan0";
  return "wlan0";
}
```