user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L94:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L94
  sub    $0xc68,%rsp
  lea    D20(%rip),%r13
  mov    %r13,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L120
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  cs nopw 0x0(%rax,%rax,1)
L122:
  lea    (%r12,%rbx,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  add    (%r12,%rbx,4),%ebp
  add    $0x1,%rbx
  cmp    %ebx,%ecx
  jg     L122
L188:
  lea    0x1(%rcx),%eax
  imul   %ecx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  mov    %ebp,%eax
  sar    %edx
  sub    %edx,%eax
  js     L175
  cltd
  idiv   %ecx
  mov    %edx,%esi
  test   %edx,%edx
  jne    L175
  lea    0x1(%rax),%edx
  test   %ecx,%ecx
  jle    L105
  lea    -0x1(%rcx),%edi
  cmp    $0x2,%edi
  jbe    L30
  mov    %ecx,%esi
  movd   %eax,%xmm6
  movdqa D29(%rip),%xmm5
  lea    0x10(%rsp),%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm6,%xmm0
  paddd  D19(%rip),%xmm0
  sub    $0x1,%esi
  pxor   %xmm2,%xmm2
  shl    $0x4,%rsi
  lea    0x20(%rsp,%rsi,1),%rsi
  nopl   0x0(%rax)
L3:
  movdqa (%rax),%xmm1
  movdqa %xmm0,%xmm3
  add    $0x10,%rax
  paddd  %xmm5,%xmm0
  movdqa %xmm1,%xmm4
  pcmpgtd %xmm3,%xmm1
  psubd  %xmm3,%xmm4
  pand   %xmm4,%xmm1
  paddd  %xmm1,%xmm2
  cmp    %rax,%rsi
  jne    L3
  movdqa %xmm2,%xmm0
  mov    %ecx,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  paddd  %xmm0,%xmm2
  add    %eax,%edx
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movd   %xmm2,%esi
  cmp    %eax,%ecx
  je     L105
L98:
  movslq %eax,%rdi
  mov    0x10(%rsp,%rdi,4),%edi
  cmp    %edx,%edi
  jg     L184
L41:
  lea    0x1(%rax),%edi
  lea    0x1(%rdx),%r8d
  cmp    %ecx,%edi
  jge    L105
  movslq %edi,%rdi
  mov    0x10(%rsp,%rdi,4),%edi
  cmp    %edi,%r8d
  jl     L85
L106:
  add    $0x2,%eax
  add    $0x2,%edx
  cmp    %ecx,%eax
  jge    L105
  cltq
  mov    0x10(%rsp,%rax,4),%eax
  cmp    %eax,%edx
  jge    L105
  sub    %edx,%eax
  add    %eax,%esi
L105:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L177
L175:
  lea    D4(%rip),%rdi
  call   <puts@plt>
L177:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x9c68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L184:
  sub    %edx,%edi
  add    %edi,%esi
  jmp    L41
L85:
  sub    %r8d,%edi
  add    %edi,%esi
  jmp    L106
L120:
  xor    %ebp,%ebp
  jmp    L188
L30:
  xor    %eax,%eax
  jmp    L98
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D20
data_type: string
name: parse_data
arguments: tag: D29
data_type: byte[16]
name: parse_data
arguments: tag: D19
data_type: byte[16]
name: parse_data
arguments: tag: D10
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D20:  %d

tool: {"D29": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D19": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D10: %d


tool: D4: -1

assistant: ```c
int main() {
  int vetor[10000];
  int i, n;
  int soma;
  int altura;
  int movimentos;
  scanf(" %d", &n);
  soma = 0;
  for (i = 0; i < n; i++) {
    scanf(" %d", &vetor[i]);
    soma += vetor[i];
  }
  soma -= (n * n + n) / 2;
  if (soma >= 0 && soma % n == 0) {
    movimentos = 0;
    altura = (soma / n) + 1;
    for (i = 0; i < n; i++) {
      if (vetor[i] > altura)
        movimentos += (vetor[i] - altura);
      altura++;
    }
    printf("%d\n", movimentos);
  } else {
    printf("-1\n");
  }
}
```