ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<vector_erase>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %ecx,%r10d
  mov    (%rsi),%eax
  mov    %r9d,%ecx
  sub    %r8d,%ecx
  cmp    %ecx,%eax
  jbe    L35
  mov    %r8d,%ebx
  mov    %r9d,%ebp
  cmp    %r9d,%eax
  ja     L16
L3:
  sub    %ebp,%ebx
  add    %ebx,(%r12)
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <vector_delete@plt>
  jmp    L20
L16:
  mov    (%rdi),%rdi
  sub    %r9d,%eax
  mov    %eax,%edx
  imul   %r10d,%edx
  mov    %r9d,%esi
  imul   %r10d,%esi
  add    %rdi,%rsi
  mov    %r10d,%eax
  imul   %r8d,%eax
  add    %rax,%rdi
  call   <memmove@plt>
  jmp    L3
```

assistant: ```c
void vector_erase(char **data, unsigned int *size, unsigned int *capacity, unsigned int data_size, unsigned int beg, unsigned int end) {
  unsigned int block_size = end - beg;
  if (block_size >= *size) {
    vector_delete(data, size, capacity);
    return;
  }
  if (end < *size) {
    memmove((*data + beg * data_size), (*data + end * data_size), (*size - end) * data_size);
  }
  *size -= block_size;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vector_erase>:
  endbr64
  push   %r12
  mov    %ecx,%r10d
  mov    %r9d,%ecx
  mov    %rsi,%r12
  push   %rbp
  sub    %r8d,%ecx
  push   %rbx
  mov    (%rsi),%eax
  cmp    %ecx,%eax
  jbe    L9
  mov    %r8d,%ebx
  mov    %r9d,%ebp
  cmp    %r9d,%eax
  ja     L14
  sub    %ebp,%ebx
  add    %eax,%ebx
  mov    %ebx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  sub    %r9d,%eax
  mov    %r9d,%esi
  mov    (%rdi),%rdi
  sub    %ebp,%ebx
  mov    %eax,%edx
  imul   %r10d,%esi
  mov    %r10d,%eax
  imul   %r8d,%eax
  imul   %r10d,%edx
  add    %rdi,%rsi
  add    %rax,%rdi
  call   <memmove@plt>
  mov    (%r12),%eax
  add    %eax,%ebx
  mov    %ebx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <vector_delete@plt>
```

assistant: ```c
void vector_erase(char **data, unsigned int *size, unsigned int *capacity, unsigned int data_size, unsigned int beg, unsigned int end) {
  unsigned int block_size = end - beg;
  if (block_size >= *size) {
    vector_delete(data, size, capacity);
    return;
  }
  if (end < *size) {
    memmove((*data + beg * data_size), (*data + end * data_size), (*size - end) * data_size);
  }
  *size -= block_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vector_erase>:
  endbr64
  push   %r12
  mov    %ecx,%r10d
  mov    %r9d,%ecx
  mov    %rsi,%r12
  push   %rbp
  sub    %r8d,%ecx
  push   %rbx
  mov    (%rsi),%eax
  cmp    %ecx,%eax
  jbe    L11
  mov    %r8d,%ebx
  mov    %r9d,%ebp
  cmp    %r9d,%eax
  ja     L4
  sub    %ebp,%ebx
  add    %eax,%ebx
  mov    %ebx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  sub    %r9d,%eax
  mov    %r9d,%esi
  mov    (%rdi),%rdi
  sub    %ebp,%ebx
  mov    %eax,%edx
  imul   %r10d,%esi
  mov    %r10d,%eax
  imul   %r8d,%eax
  imul   %r10d,%edx
  add    %rdi,%rsi
  add    %rax,%rdi
  call   <memmove@plt>
  mov    (%r12),%eax
  add    %eax,%ebx
  mov    %ebx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <vector_delete@plt>
```

assistant: ```c
void vector_erase(char **data, unsigned int *size, unsigned int *capacity, unsigned int data_size, unsigned int beg, unsigned int end) {
  unsigned int block_size = end - beg;
  if (block_size >= *size) {
    vector_delete(data, size, capacity);
    return;
  }
  if (end < *size) {
    memmove((*data + beg * data_size), (*data + end * data_size), (*size - end) * data_size);
  }
  *size -= block_size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<permuteString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x34(%rbp)
  jne    L48
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <checkdict@plt>
  test   %rax,%rax
  je     L13
  mov    -0x40(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L13
L48:
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L50:
  mov    -0x4(%rbp),%edx
  mov    -0x34(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%r8d
  mov    -0x40(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r9
  mov    %rax,%rdi
  call   <permuteString>
  mov    -0x34(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L50
L13:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L60
  mov    $0x1,%eax
  jmp    L16
L60:
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int permuteString(FILE *ofp, char **dictionary, char permute[], const char *submission, int permuteStart, int *flag) {
  int i;
  if (permuteStart == strlen(permute)) {
    if (checkdict(ofp, dictionary, permute, submission))
      *flag = 1;
  } else {
    for (i = permuteStart; i < strlen(permute); i++) {
      swap(permute, permuteStart, i);
      permuteString(ofp, dictionary, permute, submission, permuteStart + 1, flag);
      swap(permute, i, permuteStart);
    }
  }
  if (*flag == 1) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<permuteString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%rbx
  mov    %rcx,%r14
  mov    %r8d,%r12d
  mov    %r9,%r13
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %r12d,%ebp
  lea    0x1(%r12),%r15d
  cmp    %r12d,%eax
  je     L4
L30:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L35
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    %r13,%r9
  mov    %r15d,%r8d
  mov    %r14,%rcx
  mov    %rbx,%rdx
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <permuteString>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <swap@plt>
  add    $0x1,%ebp
  jmp    L30
L4:
  mov    %r14,%rcx
  mov    %rbx,%rdx
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <checkdict@plt>
  test   %rax,%rax
  je     L35
  movl   $0x1,0x0(%r13)
L35:
  cmpl   $0x1,0x0(%r13)
  sete   %al
  movzbl %al,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int permuteString(FILE *ofp, char **dictionary, char permute[], const char *submission, int permuteStart, int *flag) {
  int i;
  if (permuteStart == strlen(permute)) {
    if (checkdict(ofp, dictionary, permute, submission))
      *flag = 1;
  } else {
    for (i = permuteStart; i < strlen(permute); i++) {
      swap(permute, permuteStart, i);
      permuteString(ofp, dictionary, permute, submission, permuteStart + 1, flag);
      swap(permute, i, permuteStart);
    }
  }
  if (*flag == 1) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<permuteString>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %ebp,%ebx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp),%ecx
  mov    %ecx,0xc(%rsp)
  cmp    %ebp,%eax
  je     L36
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L18
L23:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%r8d
  mov    %r12,%r9
  mov    %r15,%rcx
  mov    (%rsp),%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <permuteString>
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %ebp,%edx
  call   <swap@plt>
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L23
L18:
  xor    %eax,%eax
  cmpl   $0x1,(%r12)
  sete   %al
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    (%rsp),%rdi
  mov    %r15,%rcx
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <checkdict@plt>
  test   %rax,%rax
  je     L18
  movl   $0x1,(%r12)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int permuteString(FILE *ofp, char **dictionary, char permute[], const char *submission, int permuteStart, int *flag) {
  int i;
  if (permuteStart == strlen(permute)) {
    if (checkdict(ofp, dictionary, permute, submission))
      *flag = 1;
  } else {
    for (i = permuteStart; i < strlen(permute); i++) {
      swap(permute, permuteStart, i);
      permuteString(ofp, dictionary, permute, submission, permuteStart + 1, flag);
      swap(permute, i, permuteStart);
    }
  }
  if (*flag == 1) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<permuteString>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %ebp,%ebx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp),%ecx
  mov    %ecx,0xc(%rsp)
  cmp    %ebp,%eax
  je     L38
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L15
L16:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%r8d
  mov    %r12,%r9
  mov    %r15,%rcx
  mov    (%rsp),%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <permuteString>
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %ebp,%edx
  call   <swap@plt>
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
L15:
  xor    %eax,%eax
  cmpl   $0x1,(%r12)
  sete   %al
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  mov    (%rsp),%rdi
  mov    %r15,%rcx
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <checkdict@plt>
  test   %rax,%rax
  je     L15
  movl   $0x1,(%r12)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int permuteString(FILE *ofp, char **dictionary, char permute[], const char *submission, int permuteStart, int *flag) {
  int i;
  if (permuteStart == strlen(permute)) {
    if (checkdict(ofp, dictionary, permute, submission))
      *flag = 1;
  } else {
    for (i = permuteStart; i < strlen(permute); i++) {
      swap(permute, permuteStart, i);
      permuteString(ofp, dictionary, permute, submission, permuteStart + 1, flag);
      swap(permute, i, permuteStart);
    }
  }
  if (*flag == 1) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: command not implemented


assistant: ```c
struct operation *nop(struct operation *op, struct device *dev, off_t off, off_t max, size_t len) {
  do {
    printf("command not implemented\n");
    return NULL;
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nop>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4: command not implemented


assistant: ```c
struct operation *nop(struct operation *op, struct device *dev, off_t off, off_t max, size_t len) {
  do {
    printf("command not implemented\n");
    return NULL;
  } while (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<nop>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: command not implemented


assistant: ```c
struct operation *nop(struct operation *op, struct device *dev, off_t off, off_t max, size_t len) {
  do {
    printf("command not implemented\n");
    return NULL;
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nop>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: command not implemented


assistant: ```c
struct operation *nop(struct operation *op, struct device *dev, off_t off, off_t max, size_t len) {
  do {
    printf("command not implemented\n");
    return NULL;
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hd_cust>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D0(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D18(%rip)
  test   %eax,%eax
  jne    L3
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
datatype: string

tool: D18: No header has been defined for the customer table


assistant: ```c
int hd_cust(FILE *f) {
  static int count = 0;
  if (!count++)
    printf("No header has been defined for the customer table\n");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hd_cust>:
  endbr64
  mov    D0(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D22(%rip)
  test   %eax,%eax
  je     L3
  mov    $0x0,%eax
  ret
L3:
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D22
type_guessed: string

tool: D22: No header has been defined for the customer table


assistant: ```c
int hd_cust(FILE *f) {
  static int count = 0;
  if (!count++)
    printf("No header has been defined for the customer table\n");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<hd_cust>:
  endbr64
  mov    D8(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D22(%rip)
  test   %eax,%eax
  je     L1
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D22
type_guessed: string

tool: D22: No header has been defined for the customer table


assistant: ```c
int hd_cust(FILE *f) {
  static int count = 0;
  if (!count++)
    printf("No header has been defined for the customer table\n");
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hd_cust>:
  endbr64
  mov    D19(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D28(%rip)
  test   %eax,%eax
  je     L2
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
data_type: string

tool: D28: No header has been defined for the customer table


assistant: ```c
int hd_cust(FILE *f) {
  static int count = 0;
  if (!count++)
    printf("No header has been defined for the customer table\n");
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nand_read_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x1e(%rbp)
  mov    $0x90,%edi
  call   <nand_write_cmmd@plt>
  mov    $0x0,%edi
  call   <nand_write_addr@plt>
  movb   $0x0,-0x1e(%rbp)
  jmp    L10
L4:
  movzbl -0x1e(%rbp),%eax
  movzbl %al,%ebx
  mov    $0x0,%eax
  call   <nand_read_one_byte@plt>
  movslq %ebx,%rdx
  mov    %al,-0x1d(%rbp,%rdx,1)
  movzbl -0x1e(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1e(%rbp)
L10:
  movzbl -0x1e(%rbp),%eax
  cmp    $0x4,%al
  jbe    L4
  mov    $0x0,%eax
  call   <nand_chip_disable@plt>
  lea    -0x1d(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <uart_tx_multiple_bytes@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void nand_read_id(void) {
  unsigned char maf_id[5];
  volatile unsigned char var = 0;
  nand_write_cmmd(0x90);
  nand_write_addr(0x00);
  for (var = 0; var < 5; var++) {
    maf_id[var] = nand_read_one_byte();
  }
  nand_chip_disable();
  uart_tx_multiple_bytes(maf_id, 5);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nand_read_id>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x2(%rsp)
  mov    $0x90,%edi
  call   <nand_write_cmmd@plt>
  mov    $0x0,%edi
  call   <nand_write_addr@plt>
  movb   $0x0,0x2(%rsp)
  movzbl 0x2(%rsp),%eax
  cmp    $0x4,%al
  ja     L12
L2:
  movzbl 0x2(%rsp),%ebx
  mov    $0x0,%eax
  call   <nand_read_one_byte@plt>
  movzbl %bl,%ebx
  mov    %al,0x3(%rsp,%rbx,1)
  movzbl 0x2(%rsp),%eax
  add    $0x1,%eax
  mov    %al,0x2(%rsp)
  movzbl 0x2(%rsp),%eax
  cmp    $0x4,%al
  jbe    L2
L12:
  mov    $0x0,%eax
  call   <nand_chip_disable@plt>
  lea    0x3(%rsp),%rdi
  mov    $0x5,%esi
  call   <uart_tx_multiple_bytes@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nand_read_id(void) {
  unsigned char maf_id[5];
  volatile unsigned char var = 0;
  nand_write_cmmd(0x90);
  nand_write_addr(0x00);
  for (var = 0; var < 5; var++) {
    maf_id[var] = nand_read_one_byte();
  }
  nand_chip_disable();
  uart_tx_multiple_bytes(maf_id, 5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nand_read_id>:
  endbr64
  push   %rbx
  mov    $0x90,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x2(%rsp)
  call   <nand_write_cmmd@plt>
  xor    %edi,%edi
  call   <nand_write_addr@plt>
  movb   $0x0,0x2(%rsp)
  movzbl 0x2(%rsp),%eax
  cmp    $0x4,%al
  ja     L10
  nopl   (%rax)
L15:
  movzbl 0x2(%rsp),%ebx
  xor    %eax,%eax
  call   <nand_read_one_byte@plt>
  mov    %al,0x3(%rsp,%rbx,1)
  movzbl 0x2(%rsp),%eax
  add    $0x1,%eax
  mov    %al,0x2(%rsp)
  movzbl 0x2(%rsp),%eax
  cmp    $0x4,%al
  jbe    L15
L10:
  xor    %eax,%eax
  call   <nand_chip_disable@plt>
  lea    0x3(%rsp),%rdi
  mov    $0x5,%esi
  call   <uart_tx_multiple_bytes@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nand_read_id(void) {
  unsigned char maf_id[5];
  volatile unsigned char var = 0;
  nand_write_cmmd(0x90);
  nand_write_addr(0x00);
  for (var = 0; var < 5; var++) {
    maf_id[var] = nand_read_one_byte();
  }
  nand_chip_disable();
  uart_tx_multiple_bytes(maf_id, 5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nand_read_id>:
  endbr64
  push   %rbx
  mov    $0x90,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x2(%rsp)
  call   <nand_write_cmmd@plt>
  xor    %edi,%edi
  call   <nand_write_addr@plt>
  movb   $0x0,0x2(%rsp)
  movzbl 0x2(%rsp),%eax
  cmp    $0x4,%al
  ja     L1
  nopl   (%rax)
L26:
  movzbl 0x2(%rsp),%ebx
  xor    %eax,%eax
  call   <nand_read_one_byte@plt>
  mov    %al,0x3(%rsp,%rbx,1)
  movzbl 0x2(%rsp),%eax
  add    $0x1,%eax
  mov    %al,0x2(%rsp)
  movzbl 0x2(%rsp),%eax
  cmp    $0x4,%al
  jbe    L26
L1:
  xor    %eax,%eax
  call   <nand_chip_disable@plt>
  lea    0x3(%rsp),%rdi
  mov    $0x5,%esi
  call   <uart_tx_multiple_bytes@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nand_read_id(void) {
  unsigned char maf_id[5];
  volatile unsigned char var = 0;
  nand_write_cmmd(0x90);
  nand_write_addr(0x00);
  for (var = 0; var < 5; var++) {
    maf_id[var] = nand_read_one_byte();
  }
  nand_chip_disable();
  uart_tx_multiple_bytes(maf_id, 5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L14
L19:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L19
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(int n) {
  int sum = 0, i;
  for (i = 1; i <= n; ++i) {
    sum += i;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func>:
  endbr64
  test   %edi,%edi
  jle    L5
  add    $0x1,%edi
  mov    $0x1,%eax
  mov    $0x0,%edx
L13:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L13
L12:
  mov    %edx,%eax
  ret
L5:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
int func(int n) {
  int sum = 0, i;
  for (i = 1; i <= n; ++i) {
    sum += i;
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func>:
  endbr64
  test   %edi,%edi
  jle    L13
  add    $0x1,%edi
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L1:
  add    %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L1
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int func(int n) {
  int sum = 0, i;
  for (i = 1; i <= n; ++i) {
    sum += i;
  }
  return sum;
}
```