ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<loghprob>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  mov    %ecx,%edx
  shr    $0x1f,%edx
  sub    $0x18,%rsp
  cmp    %esi,%ecx
  setg   %al
  or     %dl,%al
  jne    L19
  cmp    %ebp,%ecx
  jle    L10
L19:
  movsd  D7(%rip),%xmm0
L22:
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %edi,%r12d
  mov    %ebp,%r14d
  movsd  D7(%rip),%xmm0
  mov    %esi,%edi
  mov    %r12d,%r13d
  sub    %ecx,%r14d
  sub    %esi,%r13d
  cmp    %r13d,%r14d
  jg     L22
  mov    %ecx,%esi
  call   <logbino@plt>
  mov    %r14d,%esi
  mov    %r13d,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <logbino@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %ebp,%esi
  mov    %r12d,%edi
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <logbino@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  subsd  %xmm0,%xmm1
  pop    %r13
  pop    %r14
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: byte[8]

tool: {"D7": [0xea,0x8c,0xa0,0x39,0x59,0x3e,0x29,0xc6]}

assistant: ```c
double loghprob(int n, int a, int m, int k) {
  double ytop, ybot;
  if (k < 0)
    return -1.0e30;
  if (k > a)
    return -1.0e30;
  if (k > m)
    return -1.0e30;
  if ((m - k) > (n - a))
    return -1.0e30;
  ytop = logbino(a, k) + logbino(n - a, m - k);
  ybot = logbino(n, m);
  return ytop - ybot;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_perfect_matches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %rdi,-0x7f8(%rbp)
  mov    %rsi,-0x800(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7f0(%rbp)
  mov    -0x800(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x7ec(%rbp)
  mov    -0x7f8(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L2
L23:
  mov    -0x800(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x7e8(%rbp)
  cmpq   $0x0,-0x7e8(%rbp)
  je     L2
  addl   $0x1,-0x7f0(%rbp)
  mov    -0x7ec(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x7e8(%rbp),%rax
  add    %rax,%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L2:
  cmpq   $0x0,-0x7e8(%rbp)
  jne    L23
  mov    -0x7f0(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int count_perfect_matches(char *upstream_sequence, char *motif) {
  int i;
  char *search_string;
  char current_string[2000];
  int n = 0;
  int motif_length;
  motif_length = strlen(motif);
  strcpy(current_string, upstream_sequence);
  while (search_string != NULL) {
    search_string = strstr(current_string, motif);
    if (search_string != NULL) {
      n++;
      strcpy(current_string, search_string + motif_length);
    }
  }
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<count_perfect_matches>:
  endbr64
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x7e0,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_perfect_matches(char *upstream_sequence, char *motif) {
  int i;
  char *search_string;
  char current_string[2000];
  int n = 0;
  int motif_length;
  motif_length = strlen(motif);
  strcpy(current_string, upstream_sequence);
  while (search_string != NULL) {
    search_string = strstr(current_string, motif);
    if (search_string != NULL) {
      n++;
      strcpy(current_string, search_string + motif_length);
    }
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_perfect_matches>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %r12d,%r12d
  movslq %eax,%r13
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L24
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    (%rax,%r13,1),%rsi
  mov    %rbx,%rdi
  add    $0x1,%r12d
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L10
L24:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x7e8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_perfect_matches(char *upstream_sequence, char *motif) {
  int i;
  char *search_string;
  char current_string[2000];
  int n = 0;
  int motif_length;
  motif_length = strlen(motif);
  strcpy(current_string, upstream_sequence);
  while (search_string != NULL) {
    search_string = strstr(current_string, motif);
    if (search_string != NULL) {
      n++;
      strcpy(current_string, search_string + motif_length);
    }
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count_perfect_matches>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %r12d,%r12d
  movslq %eax,%r13
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L28
  cs nopw 0x0(%rax,%rax,1)
L2:
  lea    (%rax,%r13,1),%rsi
  mov    %rbx,%rdi
  add    $0x1,%r12d
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L2
L28:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x7e8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_perfect_matches(char *upstream_sequence, char *motif) {
  int i;
  char *search_string;
  char current_string[2000];
  int n = 0;
  int motif_length;
  motif_length = strlen(motif);
  strcpy(current_string, upstream_sequence);
  while (search_string != NULL) {
    search_string = strstr(current_string, motif);
    if (search_string != NULL) {
      n++;
      strcpy(current_string, search_string + motif_length);
    }
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getinp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
L28:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L17
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L40
L17:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L49
  addq   $0x1,-0x18(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L28
  cmpl   $0x0,-0xc(%rbp)
  jne    L13
  mov    $0x0,%edi
  call   <isatty@plt>
  test   %eax,%eax
  jne    L9
L13:
  mov    $0x1,%edi
  call   <exit@plt>
L9:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
L40:
  leave
  ret
```

assistant: ```c
void getinp(char *p, int l) {
  char *ep = p + l - 1;
  int e;
  while ((e = read(0, p, 1)) == 1) {
    if (*p == '\n') {
      *p = 0;
      return;
    }
    if (p < ep)
      p++;
  }
  if (e || !isatty(0))
    exit(1);
  *p = 0;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getinp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movslq %esi,%rsi
  lea    -0x1(%rdi,%rsi,1),%rbp
  jmp    L58
L51:
  cmp    %rbp,%rbx
  adc    $0x0,%rbx
L58:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L28
  cmpb   $0xa,(%rbx)
  jne    L51
L52:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  test   %eax,%eax
  jne    L29
  mov    $0x0,%edi
  call   <isatty@plt>
  test   %eax,%eax
  jne    L52
L29:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L52
```

assistant: ```c
void getinp(char *p, int l) {
  char *ep = p + l - 1;
  int e;
  while ((e = read(0, p, 1)) == 1) {
    if (*p == '\n') {
      *p = 0;
      return;
    }
    if (p < ep)
      p++;
  }
  if (e || !isatty(0))
    exit(1);
  *p = 0;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getinp>:
  endbr64
  push   %rbp
  movslq %esi,%rsi
  push   %rbx
  lea    -0x1(%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L53:
  cmpb   $0xa,(%rbx)
  je     L46
  cmp    %rbp,%rbx
  adc    $0x0,%rbx
L47:
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L53
  test   %eax,%eax
  je     L52
  mov    $0x1,%edi
  call   <exit@plt>
L46:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  xor    %edi,%edi
  call   <isatty@plt>
  test   %eax,%eax
  jne    L46
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L46
```

assistant: ```c
void getinp(char *p, int l) {
  char *ep = p + l - 1;
  int e;
  while ((e = read(0, p, 1)) == 1) {
    if (*p == '\n') {
      *p = 0;
      return;
    }
    if (p < ep)
      p++;
  }
  if (e || !isatty(0))
    exit(1);
  *p = 0;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getinp>:
  endbr64
  push   %rbp
  movslq %esi,%rsi
  push   %rbx
  lea    -0x1(%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L24:
  cmpb   $0xa,(%rbx)
  je     L23
  cmp    %rbp,%rbx
  adc    $0x0,%rbx
L37:
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L24
  test   %eax,%eax
  je     L36
  mov    $0x1,%edi
  call   <exit@plt>
L23:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  xor    %edi,%edi
  call   <isatty@plt>
  test   %eax,%eax
  jne    L23
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L23
```

assistant: ```c
void getinp(char *p, int l) {
  char *ep = p + l - 1;
  int e;
  while ((e = read(0, p, 1)) == 1) {
    if (*p == '\n') {
      *p = 0;
      return;
    }
    if (p < ep)
      p++;
  }
  if (e || !isatty(0))
    exit(1);
  *p = 0;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<http_get_status>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L13:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L40
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L37
  mov    $0x0,%eax
  jmp    L33
L55:
  addq   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L55
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L33:
  leave
  ret
```

assistant: ```c
int http_get_status(const char *buf) {
  const char *p = buf;
  while (*p != ' ' && *p != '\0')
    p++;
  if (*p != ' ')
    return 0;
  while (*p == ' ')
    p++;
  return atoi(p);
}
```
user: What is the c source code of the assembly code below:

```asm
<http_get_status>:
  endbr64
  movzbl (%rdi),%edx
  test   $0xdf,%dl
  je     L24
L30:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   $0xdf,%dl
  jne    L30
L24:
  mov    $0x0,%eax
  cmp    $0x20,%dl
  jne    L21
  sub    $0x8,%rsp
  cmpb   $0x20,(%rdi)
  jne    L36
L46:
  add    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  je     L46
L36:
  call   <atoi@plt>
  add    $0x8,%rsp
  ret
L21:
  ret
```

assistant: ```c
int http_get_status(const char *buf) {
  const char *p = buf;
  while (*p != ' ' && *p != '\0')
    p++;
  if (*p != ' ')
    return 0;
  while (*p == ' ')
    p++;
  return atoi(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<http_get_status>:
  endbr64
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L35:
  add    $0x1,%rdi
L37:
  movzbl (%rdi),%eax
  test   $0xdf,%al
  jne    L35
  cmp    $0x20,%al
  je     L27
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rdi
L27:
  cmpb   $0x20,(%rdi)
  je     L3
  jmp    1050 <atoi@plt>
```

assistant: ```c
int http_get_status(const char *buf) {
  const char *p = buf;
  while (*p != ' ' && *p != '\0')
    p++;
  if (*p != ' ')
    return 0;
  while (*p == ' ')
    p++;
  return atoi(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<http_get_status>:
  endbr64
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    $0x1,%rdi
L3:
  movzbl (%rdi),%eax
  test   $0xdf,%al
  jne    L22
  cmp    $0x20,%al
  je     L1
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  je     L1
  jmp    1050 <atoi@plt>
```

assistant: ```c
int http_get_status(const char *buf) {
  const char *p = buf;
  while (*p != ' ' && *p != '\0')
    p++;
  if (*p != ' ')
    return 0;
  while (*p == ' ')
    p++;
  return atoi(p);
}
```
user: What is the c source code of the assembly code below:

```asm
<spc_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L1:
  subq   $0x1,-0x28(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L10:
  cmpq   $0x0,-0x28(%rbp)
  jne    L1
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
volatile void *spc_memset(volatile void *dst, int c, size_t len) {
  volatile char *buf;
  for (buf = (volatile char *)dst; len; buf[--len] = c)
    ;
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<spc_memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L9
  lea    -0x1(%rdi,%rdx,1),%rdx
L5:
  mov    %rdx,%rcx
  mov    %sil,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rcx
  jne    L5
L9:
  ret
```

assistant: ```c
volatile void *spc_memset(volatile void *dst, int c, size_t len) {
  volatile char *buf;
  for (buf = (volatile char *)dst; len; buf[--len] = c)
    ;
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<spc_memset>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdi,%rdx,1),%rcx
  test   %rdx,%rdx
  je     L16
  nopl   0x0(%rax)
L12:
  mov    %rcx,%rdx
  mov    %sil,(%rcx)
  sub    $0x1,%rcx
  cmp    %rax,%rdx
  jne    L12
L16:
  ret
```

assistant: ```c
volatile void *spc_memset(volatile void *dst, int c, size_t len) {
  volatile char *buf;
  for (buf = (volatile char *)dst; len; buf[--len] = c)
    ;
  return dst;
}
```
user: What is the c source code of the assembly code below?

```asm
<spc_memset>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdi,%rdx,1),%rcx
  test   %rdx,%rdx
  je     L15
  nopl   0x0(%rax)
L17:
  mov    %rcx,%rdx
  mov    %sil,(%rcx)
  sub    $0x1,%rcx
  cmp    %rax,%rdx
  jne    L17
L15:
  ret
```

assistant: ```c
volatile void *spc_memset(volatile void *dst, int c, size_t len) {
  volatile char *buf;
  for (buf = (volatile char *)dst; len; buf[--len] = c)
    ;
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<safe_close_above_stdio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jg     L0
  mov    $0xffffffff,%eax
  jmp    L11
L0:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <safe_close@plt>
L11:
  leave
  ret
```

assistant: ```c
int safe_close_above_stdio(int fd) {
  if (fd < 3)
    return -1;
  return safe_close(fd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<safe_close_above_stdio>:
  endbr64
  cmp    $0x2,%edi
  jle    L6
  sub    $0x8,%rsp
  call   <safe_close@plt>
  add    $0x8,%rsp
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int safe_close_above_stdio(int fd) {
  if (fd < 3)
    return -1;
  return safe_close(fd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<safe_close_above_stdio>:
  endbr64
  cmp    $0x2,%edi
  jle    L8
  jmp    1050 <safe_close@plt>
  xchg   %ax,%ax
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int safe_close_above_stdio(int fd) {
  if (fd < 3)
    return -1;
  return safe_close(fd);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<safe_close_above_stdio>:
  endbr64
  cmp    $0x2,%edi
  jle    L7
  jmp    1050 <safe_close@plt>
  xchg   %ax,%ax
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int safe_close_above_stdio(int fd) {
  if (fd < 3)
    return -1;
  return safe_close(fd);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L2
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <panic@plt>
L2:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <panic@plt>
L13:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D3
data_type: string

tool: D11: realloc: size 0


tool: D3: realloc: out of memory


assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *newptr;
  if (size == 0)
    panic("realloc: size 0\n");
  newptr = realloc(ptr, size);
  if (!newptr) {
    free(ptr);
    panic("realloc: out of memory\n");
  }
  return newptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrealloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L21
L9:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  lea    D1(%rip),%rdi
  call   <panic@plt>
  jmp    L9
L28:
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D5(%rip),%rdi
  call   <panic@plt>
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D1: realloc: size 0


tool: D5: realloc: out of memory


assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *newptr;
  if (size == 0)
    panic("realloc: size 0\n");
  newptr = realloc(ptr, size);
  if (!newptr) {
    free(ptr);
    panic("realloc: out of memory\n");
  }
  return newptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrealloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L19
L18:
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
L38:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L19:
  lea    D15(%rip),%rdi
  mov    %rsi,0x8(%rsp)
  call   <panic@plt>
  mov    0x8(%rsp),%rsi
  jmp    L18
L12:
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D2(%rip),%rdi
  call   <panic@plt>
  jmp    L38
```

tool_calls: name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string

tool: D15: realloc: size 0


tool: D2: realloc: out of memory


assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *newptr;
  if (size == 0)
    panic("realloc: size 0\n");
  newptr = realloc(ptr, size);
  if (!newptr) {
    free(ptr);
    panic("realloc: out of memory\n");
  }
  return newptr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xrealloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L26
L30:
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
L39:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L26:
  lea    D13(%rip),%rdi
  mov    %rsi,0x8(%rsp)
  call   <panic@plt>
  mov    0x8(%rsp),%rsi
  jmp    L30
L3:
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D12(%rip),%rdi
  call   <panic@plt>
  jmp    L39
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string

tool: D13: realloc: size 0


tool: D12: realloc: out of memory


assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *newptr;
  if (size == 0)
    panic("realloc: size 0\n");
  newptr = realloc(ptr, size);
  if (!newptr) {
    free(ptr);
    panic("realloc: out of memory\n");
  }
  return newptr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: hello github!!!!

assistant: ```c
int main(int charc, char **argv) {
  printf("hello github!!!!");
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D2: hello github!!!!

assistant: ```c
int main(int charc, char **argv) {
  printf("hello github!!!!");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: hello github!!!!

assistant: ```c
int main(int charc, char **argv) {
  printf("hello github!!!!");
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: D8: hello github!!!!

assistant: ```c
int main(int charc, char **argv) {
  printf("hello github!!!!");
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<minhafuncao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int minhafuncao() {
  int x = 0;
  x++;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<minhafuncao>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int minhafuncao() {
  int x = 0;
  x++;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<minhafuncao>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int minhafuncao() {
  int x = 0;
  x++;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<minhafuncao>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int minhafuncao() {
  int x = 0;
  x++;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<toLowerCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L13
  cmpl   $0x5a,-0x4(%rbp)
  jg     L13
  subl   $0x41,-0x4(%rbp)
  addl   $0x61,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int toLowerCase(int x) {
  if (x >= 'A' && x <= 'Z') {
    x -= 'A';
    x += 'a';
  }
  return x;
}
```