ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rdi
  lea    D7(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %r12,%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %esi,%eax
  mov    %eax,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D7
data_type: string

tool: D12: %d

tool: D7: %d


assistant: ```c
int main() {
  int h, r, b;
  scanf("%d", &h);
  b = h * h;
  r = b * h;
  printf("%d\n", b);
  printf("%d\n", r);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  lea    D0(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %r12,%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %esi,%eax
  mov    %eax,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D14: %d

tool: D0: %d


assistant: ```c
int main() {
  int h, r, b;
  scanf("%d", &h);
  b = h * h;
  r = b * h;
  printf("%d\n", b);
  printf("%d\n", r);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<llz_shortenrg2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L15:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L15
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double llz_shortenrg2(double *buf, int frame_len) {
  int i;
  double x;
  double enrg;
  enrg = 0.0;
  x = 0.0;
  for (i = 0; i < frame_len; i++) {
    x = buf[i];
    enrg += x * x;
  }
  return enrg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<llz_shortenrg2>:
  endbr64
  test   %esi,%esi
  jle    L12
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm1,%xmm1
L10:
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L10
L17:
  movapd %xmm1,%xmm0
  ret
L12:
  pxor   %xmm1,%xmm1
  jmp    L17
```

assistant: ```c
double llz_shortenrg2(double *buf, int frame_len) {
  int i;
  double x;
  double enrg;
  enrg = 0.0;
  x = 0.0;
  for (i = 0; i < frame_len; i++) {
    x = buf[i];
    enrg += x * x;
  }
  return enrg;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<llz_shortenrg2>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  pxor   %xmm1,%xmm1
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L15:
  movsd  (%rdi),%xmm0
  add    $0x8,%rdi
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdi
  jne    L15
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double llz_shortenrg2(double *buf, int frame_len) {
  int i;
  double x;
  double enrg;
  enrg = 0.0;
  x = 0.0;
  for (i = 0; i < frame_len; i++) {
    x = buf[i];
    enrg += x * x;
  }
  return enrg;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<llz_shortenrg2>:
  endbr64
  test   %esi,%esi
  jle    L32
  cmp    $0x1,%esi
  je     L16
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L7:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L7
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L19
L5:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  ret
  nop
L19:
  ret
  nopl   0x0(%rax)
L32:
  pxor   %xmm0,%xmm0
  ret
L16:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
double llz_shortenrg2(double *buf, int frame_len) {
  int i;
  double x;
  double enrg;
  enrg = 0.0;
  x = 0.0;
  for (i = 0; i < frame_len; i++) {
    x = buf[i];
    enrg += x * x;
  }
  return enrg;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<array_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  movl   $0xb,-0x1c(%rbp)
  movl   $0xd,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <showarray_1@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void array_1(void) {
  int primes[] = {2, 3, 5, 7, 9, 11, 13};
  showarray_1(primes);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<array_1>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  movl   $0xb,0x14(%rsp)
  movl   $0xd,0x18(%rsp)
  mov    %rsp,%rdi
  call   <showarray_1@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void array_1(void) {
  int primes[] = {2, 3, 5, 7, 9, 11, 13};
  showarray_1(primes);
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_1>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x300000002,%rax
  mov    %rsp,%rdi
  movl   $0xd,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xb00000009,%rax
  mov    %rax,0x10(%rsp)
  call   <showarray_1@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void array_1(void) {
  int primes[] = {2, 3, 5, 7, 9, 11, 13};
  showarray_1(primes);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<array_1>:
  endbr64
  sub    $0x38,%rsp
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D14(%rip),%rax
  mov    %rsp,%rdi
  movl   $0xd,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <showarray_1@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: byte[16]
name: extract_symbolic_data
arguments: tag: D14
datatype: byte[8]

tool: {"D10": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D14": [0x09,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

assistant: ```c
void array_1(void) {
  int primes[] = {2, 3, 5, 7, 9, 11, 13};
  showarray_1(primes);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Operand_bs16_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_bs16_encode(unsigned int *valp) {
  int error;
  error = (*valp & ~(0 << 4)) != 0;
  *valp = *valp >> 4;
  return error;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Operand_bs16_encode>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,%edx
  shr    $0x4,%edx
  mov    %edx,(%rdi)
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int Operand_bs16_encode(unsigned int *valp) {
  int error;
  error = (*valp & ~(0 << 4)) != 0;
  *valp = *valp >> 4;
  return error;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Operand_bs16_encode>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,%edx
  shr    $0x4,%edx
  test   %eax,%eax
  setne  %al
  mov    %edx,(%rdi)
  movzbl %al,%eax
  ret
```

assistant: ```c
int Operand_bs16_encode(unsigned int *valp) {
  int error;
  error = (*valp & ~(0 << 4)) != 0;
  *valp = *valp >> 4;
  return error;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Operand_bs16_encode>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,%edx
  shr    $0x4,%edx
  test   %eax,%eax
  setne  %al
  mov    %edx,(%rdi)
  movzbl %al,%eax
  ret
```

assistant: ```c
int Operand_bs16_encode(unsigned int *valp) {
  int error;
  error = (*valp & ~(0 << 4)) != 0;
  *valp = *valp >> 4;
  return error;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L2
L0:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L2:
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int m, int n) {
  int tmp;
  while (m) {
    tmp = m;
    m = n % m;
    n = tmp;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  jne    L0
  mov    %esi,%edi
  jmp    L21
L16:
  mov    %edx,%edi
L0:
  cltd
  idiv   %edi
  mov    %edi,%eax
  test   %edx,%edx
  jne    L16
L21:
  mov    %edi,%eax
  ret
```

assistant: ```c
int gcd(int m, int n) {
  int tmp;
  while (m) {
    tmp = m;
    m = n % m;
    n = tmp;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%eax
  test   %edi,%edi
  jne    L3
  jmp    L11
  nop
L16:
  mov    %edx,%r8d
L3:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L16
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int m, int n) {
  int tmp;
  while (m) {
    tmp = m;
    m = n % m;
    n = tmp;
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcd>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%eax
  test   %edi,%edi
  jne    L16
  jmp    L25
  nop
L7:
  mov    %edx,%r8d
L16:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L7
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int m, int n) {
  int tmp;
  while (m) {
    tmp = m;
    m = n % m;
    n = tmp;
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<csc_strfill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L2
  jmp    L10
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L2:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *csc_strfill(char *s, int padto, int ch) {
  int i;
  if ((i = strlen(s)) < padto) {
    for (; i < padto; i++) {
      s[i] = (char)ch;
    }
    s[i] = 0;
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<csc_strfill>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  call   <strlen@plt>
  cmp    %r12d,%eax
  jge    L8
  movslq %eax,%rcx
  lea    0x0(%rbp,%rcx,1),%rdx
  lea    0x1(%rbp,%rcx,1),%rcx
  lea    -0x1(%r12),%esi
  sub    %eax,%esi
  lea    (%rcx,%rsi,1),%rax
L19:
  mov    %bl,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L19
  movslq %r12d,%r12
  movb   $0x0,0x0(%rbp,%r12,1)
L8:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *csc_strfill(char *s, int padto, int ch) {
  int i;
  if ((i = strlen(s)) < padto) {
    for (; i < padto; i++) {
      s[i] = (char)ch;
    }
    s[i] = 0;
  }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<csc_strfill>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L7
  lea    -0x1(%rbx),%edx
  movsbl %bpl,%esi
  sub    %eax,%edx
  cltq
  add    $0x1,%rdx
  lea    (%r12,%rax,1),%rdi
  call   <memset@plt>
  movb   $0x0,(%r12,%rbx,1)
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *csc_strfill(char *s, int padto, int ch) {
  int i;
  if ((i = strlen(s)) < padto) {
    for (; i < padto; i++) {
      s[i] = (char)ch;
    }
    s[i] = 0;
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<csc_strfill>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L9
  lea    -0x1(%rbx),%edx
  movsbl %bpl,%esi
  sub    %eax,%edx
  cltq
  add    $0x1,%rdx
  lea    (%r12,%rax,1),%rdi
  call   <memset@plt>
  movb   $0x0,(%r12,%rbx,1)
L9:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *csc_strfill(char *s, int padto, int ch) {
  int i;
  if ((i = strlen(s)) < padto) {
    for (; i < padto; i++) {
      s[i] = (char)ch;
    }
    s[i] = 0;
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<db_init_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <random_value@plt>
  mov    $0x40000000,%edi
  call   <db_init@plt>
  nop
  leave
  ret
```

assistant: ```c
void db_init_test(int show) {
  random_value();
  db_init((1024 * 1024 * 1024));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<db_init_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <random_value@plt>
  mov    $0x40000000,%edi
  call   <db_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void db_init_test(int show) {
  random_value();
  db_init((1024 * 1024 * 1024));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<db_init_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random_value@plt>
  mov    $0x40000000,%edi
  add    $0x8,%rsp
  jmp    1060 <db_init@plt>
```

assistant: ```c
void db_init_test(int show) {
  random_value();
  db_init((1024 * 1024 * 1024));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<db_init_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random_value@plt>
  mov    $0x40000000,%edi
  add    $0x8,%rsp
  jmp    1060 <db_init@plt>
```

assistant: ```c
void db_init_test(int show) {
  random_value();
  db_init((1024 * 1024 * 1024));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <testmod_display_version@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  testmod_display_version();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testmod_display_version@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  testmod_display_version();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testmod_display_version@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  testmod_display_version();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testmod_display_version@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  testmod_display_version();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modulus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double modulus(double *x, int n) {
  int i;
  double res;
  res = 0.0;
  for (i = 0; i < n; i++) {
    res += x[i] * x[i];
  }
  return (sqrt(res));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<modulus>:
  endbr64
  test   %esi,%esi
  jle    L2
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L13:
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L13
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L38
L29:
  sqrtsd %xmm0,%xmm0
  ret
L2:
  pxor   %xmm0,%xmm0
  jmp    L29
L38:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double modulus(double *x, int n) {
  int i;
  double res;
  res = 0.0;
  for (i = 0; i < n; i++) {
    res += x[i] * x[i];
  }
  return (sqrt(res));
}
```
user: Translate the below assembly code into C programming language:

```asm
<modulus>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%rax,8),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L24:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L24
  ucomisd %xmm0,%xmm2
  ja     L5
  sqrtsd %xmm0,%xmm0
  ret
L16:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L5:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double modulus(double *x, int n) {
  int i;
  double res;
  res = 0.0;
  for (i = 0; i < n; i++) {
    res += x[i] * x[i];
  }
  return (sqrt(res));
}
```
user: Translate the below assembly code into C programming language:

```asm
<modulus>:
  endbr64
  test   %esi,%esi
  jle    L41
  cmp    $0x1,%esi
  je     L17
  mov    %esi,%edx
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  shr    %edx
  movapd %xmm3,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L29:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L29
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L31
L2:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L31:
  ucomisd %xmm0,%xmm3
  ja     L5
  sqrtsd %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L41:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L17:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L2
L5:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double modulus(double *x, int n) {
  int i;
  double res;
  res = 0.0;
  for (i = 0; i < n; i++) {
    res += x[i] * x[i];
  }
  return (sqrt(res));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_level_ground@plt>
  test   %eax,%eax
  jne    L2
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    $0x0,%eax
  call   <test_terrain@plt>
  test   %eax,%eax
  jne    L26
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  mov    $0x0,%eax
  call   <test_mountain@plt>
  test   %eax,%eax
  jne    L15
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    $0x0,%eax
  call   <test_valley@plt>
  test   %eax,%eax
  jne    L1
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
type: string
name: extract_symbolic_data
arguments: tag: D33
type: string
name: extract_symbolic_data
arguments: tag: D8
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string
name: extract_symbolic_data
arguments: tag: D10
type: string

tool: D34: Level ground test failed!

tool: D33: Terrain test failed!

tool: D8: Mountain test failed!

tool: D5: Valley test failed!

tool: D10: %d tests failed.


assistant: ```c
int main() {
  int counter = 0;
  if (!test_level_ground()) {
    printf("Level ground test failed!\n");
    counter++;
  }
  if (!test_terrain()) {
    printf("Terrain test failed!\n");
    counter++;
  }
  if (!test_mountain()) {
    printf("Mountain test failed!\n");
    counter++;
  }
  if (!test_valley()) {
    printf("Valley test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```