ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebp,%ebp
  jle    L39
  mov    %eax,%ebx
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L30:
  test   %ebp,%ebp
  jle    L39
L3:
  test   %ebx,%ebx
  jle    L39
  xor    %eax,%eax
  sub    $0x1,%ebx
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x29,%eax
  jg     L30
  xor    %eax,%eax
  sub    $0x1,%ebp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  test   %ebp,%ebp
  jg     L3
L39:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  int random;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x > 0 && y > 0) {
    random = __VERIFIER_nondet_int();
    if (random < 42) {
      x = x - 1;
      random = __VERIFIER_nondet_int();
      y = random;
    } else {
      y = y - 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebp,%ebp
  jle    L6
  mov    %eax,%ebx
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L19:
  test   %ebp,%ebp
  jle    L6
L48:
  test   %ebx,%ebx
  jle    L6
  xor    %eax,%eax
  sub    $0x1,%ebx
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x29,%eax
  jg     L19
  xor    %eax,%eax
  sub    $0x1,%ebp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  test   %ebp,%ebp
  jg     L48
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  int random;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x > 0 && y > 0) {
    random = __VERIFIER_nondet_int();
    if (random < 42) {
      x = x - 1;
      random = __VERIFIER_nondet_int();
      y = random;
    } else {
      y = y - 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hide_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L9
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rbx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x20,(%rax)
L9:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void hide_args(int argc, char **argv) {
  if (argc > 1) {
    char *arg_end;
    arg_end = argv[argc - 1] + strlen(argv[argc - 1]);
    *arg_end = ' ';
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<hide_args>:
  endbr64
  cmp    $0x1,%edi
  jg     L8
  ret
L8:
  push   %rbx
  movslq %edi,%rdi
  mov    -0x8(%rsi,%rdi,8),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x20,(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void hide_args(int argc, char **argv) {
  if (argc > 1) {
    char *arg_end;
    arg_end = argv[argc - 1] + strlen(argv[argc - 1]);
    *arg_end = ' ';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hide_args>:
  endbr64
  cmp    $0x1,%edi
  jg     L6
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  movslq %edi,%rdi
  push   %rbx
  mov    -0x8(%rsi,%rdi,8),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x20,(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void hide_args(int argc, char **argv) {
  if (argc > 1) {
    char *arg_end;
    arg_end = argv[argc - 1] + strlen(argv[argc - 1]);
    *arg_end = ' ';
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hide_args>:
  endbr64
  cmp    $0x1,%edi
  jg     L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  movslq %edi,%rdi
  push   %rbx
  mov    -0x8(%rsi,%rdi,8),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x20,(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void hide_args(int argc, char **argv) {
  if (argc > 1) {
    char *arg_end;
    arg_end = argv[argc - 1] + strlen(argv[argc - 1]);
    *arg_end = ' ';
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<HandleSIGTERM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <KillAllSaverChildrenSigHandler@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <raise@plt>
  nop
  leave
  ret
```

assistant: ```c
void HandleSIGTERM(int signo) {
  KillAllSaverChildrenSigHandler(signo);
  raise(signo);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<HandleSIGTERM>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <KillAllSaverChildrenSigHandler@plt>
  mov    %ebx,%edi
  call   <raise@plt>
  pop    %rbx
  ret
```

assistant: ```c
void HandleSIGTERM(int signo) {
  KillAllSaverChildrenSigHandler(signo);
  raise(signo);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HandleSIGTERM>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <KillAllSaverChildrenSigHandler@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <raise@plt>
```

assistant: ```c
void HandleSIGTERM(int signo) {
  KillAllSaverChildrenSigHandler(signo);
  raise(signo);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<HandleSIGTERM>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <KillAllSaverChildrenSigHandler@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <raise@plt>
```

assistant: ```c
void HandleSIGTERM(int signo) {
  KillAllSaverChildrenSigHandler(signo);
  raise(signo);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_start_hardware>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x11005400,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movl   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _start_hardware(void) {
  unsigned int reg = ((0x11000000) | (((0x0) & 0x00000003) << 16) | (((0) & 0x000000FF) << 2) | (((0x15) & 0x0000001F) << 10));
  ((*(volatile unsigned int *)(reg)) = 0x00000001);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_start_hardware>:
  endbr64
  movl   $0x1,0x11005400
  ret
```

assistant: ```c
void _start_hardware(void) {
  unsigned int reg = ((0x11000000) | (((0x0) & 0x00000003) << 16) | (((0) & 0x000000FF) << 2) | (((0x15) & 0x0000001F) << 10));
  ((*(volatile unsigned int *)(reg)) = 0x00000001);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_start_hardware>:
  endbr64
  movl   $0x1,0x11005400
  ret
```

assistant: ```c
void _start_hardware(void) {
  unsigned int reg = ((0x11000000) | (((0x0) & 0x00000003) << 16) | (((0) & 0x000000FF) << 2) | (((0x15) & 0x0000001F) << 10));
  ((*(volatile unsigned int *)(reg)) = 0x00000001);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__fdim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0xc(%rbp)
  mov    D46(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  je     L61
  mov    D46(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L61
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L70
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L70
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L70
L61:
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  jmp    L0
L70:
  movsd  -0x20(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L33
  pxor   %xmm0,%xmm0
  jmp    L0
L33:
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fpclassify@plt>
  mov    D27(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jne    L6
  mov    D48(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
L6:
  movsd  -0x8(%rbp),%xmm0
L0:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double __fdim(double x, double y) {
  int clsx = fpclassify(x);
  int clsy = fpclassify(y);
  if (clsx == FP_NAN || clsy == FP_NAN || (y < 0 && clsx == FP_INFINITE && clsy == FP_INFINITE))
    return x - y;
  if (x <= y)
    return 0.0;
  double r = x - y;
  if (fpclassify(r) == FP_INFINITE)
    __set_errno(ERANGE);
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__fdim>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <fpclassify@plt>
  movsd  (%rsp),%xmm1
  mov    %eax,%ebx
  movapd %xmm1,%xmm0
  call   <fpclassify@plt>
  movsd  (%rsp),%xmm1
  mov    D37(%rip),%rdx
  movsd  0x8(%rsp),%xmm2
  mov    (%rdx),%edx
  cmp    %eax,%edx
  je     L77
  cmp    %ebx,%edx
  je     L77
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L59
L16:
  comisd %xmm2,%xmm1
  jb     L18
L3:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  subsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <fpclassify@plt>
  mov    D12(%rip),%rdx
  movsd  (%rsp),%xmm0
  cmp    (%rdx),%eax
  jne    L3
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  movsd  (%rsp),%xmm0
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L59:
  mov    D12(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %eax,%edx
  jne    L16
  cmp    %ebx,%edx
  jne    L16
L77:
  subsd  %xmm1,%xmm2
  add    $0x10,%rsp
  pop    %rbx
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
double __fdim(double x, double y) {
  int clsx = fpclassify(x);
  int clsy = fpclassify(y);
  if (clsx == FP_NAN || clsy == FP_NAN || (y < 0 && clsx == FP_INFINITE && clsy == FP_INFINITE))
    return x - y;
  if (x <= y)
    return 0.0;
  double r = x - y;
  if (fpclassify(r) == FP_INFINITE)
    __set_errno(ERANGE);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__fdim>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <fpclassify@plt>
  movsd  (%rsp),%xmm1
  mov    %eax,%ebx
  movapd %xmm1,%xmm0
  call   <fpclassify@plt>
  movsd  (%rsp),%xmm1
  mov    D3(%rip),%rdx
  movsd  0x8(%rsp),%xmm2
  mov    (%rdx),%edx
  cmp    %eax,%edx
  je     L41
  cmp    %ebx,%edx
  je     L41
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L29
L26:
  comisd %xmm2,%xmm1
  jb     L25
L45:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  subsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <fpclassify@plt>
  mov    D0(%rip),%rdx
  movsd  (%rsp),%xmm0
  cmp    (%rdx),%eax
  jne    L45
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  movsd  (%rsp),%xmm0
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L29:
  mov    D0(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %eax,%edx
  jne    L26
  cmp    %ebx,%edx
  jne    L26
L41:
  subsd  %xmm1,%xmm2
  add    $0x10,%rsp
  pop    %rbx
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
double __fdim(double x, double y) {
  int clsx = fpclassify(x);
  int clsy = fpclassify(y);
  if (clsx == FP_NAN || clsy == FP_NAN || (y < 0 && clsx == FP_INFINITE && clsy == FP_INFINITE))
    return x - y;
  if (x <= y)
    return 0.0;
  double r = x - y;
  if (fpclassify(r) == FP_INFINITE)
    __set_errno(ERANGE);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exp_spaced_spaced_vector2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  movsd  %xmm0,-0x50(%rbp)
  movsd  %xmm1,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  mov    -0x50(%rbp),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x58(%rbp),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  mov    -0x5c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L16
L1:
  movsd  -0x28(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x48(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  movsd  -0x30(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  addl   $0x1,-0x34(%rbp)
L16:
  mov    -0x34(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L1
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void exp_spaced_spaced_vector2(double *v, double lower, double upper, int n) {
  double expMin = exp(lower);
  double expMax = exp(upper);
  double delta = (expMax - expMin) / (n - 1);
  double accDelta = 0;
  for (int i = 0; i < n; ++i) {
    v[i] = log(expMin + accDelta);
    accDelta += delta;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<exp_spaced_spaced_vector2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  movq   %xmm1,%rbx
  mov    %esi,%ebp
  call   <exp@plt>
  movsd  %xmm0,0x10(%rsp)
  movq   %rbx,%xmm0
  call   <exp@plt>
  subsd  0x10(%rsp),%xmm0
  lea    -0x1(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rsp)
  test   %ebp,%ebp
  jle    L17
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%rbp
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L12:
  movsd  0x10(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movsd  %xmm0,(%rbx)
  movsd  0x8(%rsp),%xmm2
  addsd  0x18(%rsp),%xmm2
  movsd  %xmm2,0x8(%rsp)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L12
L17:
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void exp_spaced_spaced_vector2(double *v, double lower, double upper, int n) {
  double expMin = exp(lower);
  double expMax = exp(upper);
  double delta = (expMax - expMin) / (n - 1);
  double accDelta = 0;
  for (int i = 0; i < n; ++i) {
    v[i] = log(expMin + accDelta);
    accDelta += delta;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<exp_spaced_spaced_vector2>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  lea    -0x1(%rbp),%eax
  pxor   %xmm1,%xmm1
  subsd  0x10(%rsp),%xmm0
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rsp)
  test   %ebp,%ebp
  jle    L10
  lea    0x8(%rbx,%rax,8),%rbp
  pxor   %xmm1,%xmm1
  nopw   0x0(%rax,%rax,1)
L4:
  movsd  0x10(%rsp),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  addsd  %xmm1,%xmm0
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  0x18(%rsp),%xmm1
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L4
L10:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void exp_spaced_spaced_vector2(double *v, double lower, double upper, int n) {
  double expMin = exp(lower);
  double expMax = exp(upper);
  double delta = (expMax - expMin) / (n - 1);
  double accDelta = 0;
  for (int i = 0; i < n; ++i) {
    v[i] = log(expMin + accDelta);
    accDelta += delta;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<exp_spaced_spaced_vector2>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  lea    -0x1(%rbp),%eax
  pxor   %xmm1,%xmm1
  subsd  0x10(%rsp),%xmm0
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rsp)
  test   %ebp,%ebp
  jle    L12
  lea    0x8(%rbx,%rax,8),%rbp
  pxor   %xmm1,%xmm1
  nopw   0x0(%rax,%rax,1)
L5:
  movsd  0x10(%rsp),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  addsd  %xmm1,%xmm0
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  0x18(%rsp),%xmm1
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L5
L12:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void exp_spaced_spaced_vector2(double *v, double lower, double upper, int n) {
  double expMin = exp(lower);
  double expMax = exp(upper);
  double delta = (expMax - expMin) / (n - 1);
  double accDelta = 0;
  for (int i = 0; i < n; ++i) {
    v[i] = log(expMin + accDelta);
    accDelta += delta;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sqrtlfr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <mpfr_inits@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpfr_set_ld@plt>
  add    $0x10,%rsp
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpfr_sqrt@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpfr_get_ld@plt>
  fstpt  -0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <mpfr_clears@plt>
  fldt   -0x10(%rbp)
  leave
  ret
```

assistant: ```c
long double sqrtlfr(long double d) {
  mpfr_t frx;
  mpfr_inits(frx, NULL);
  mpfr_set_ld(frx, d, GMP_RNDN);
  mpfr_sqrt(frx, frx, GMP_RNDN);
  long double ret = mpfr_get_ld(frx, GMP_RNDN);
  mpfr_clears(frx, NULL);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqrtlfr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpfr_inits@plt>
  mov    D4(%rip),%rbp
  push   0x38(%rsp)
  push   0x38(%rsp)
  mov    0x0(%rbp),%esi
  mov    %ebx,%edi
  call   <mpfr_set_ld@plt>
  mov    0x0(%rbp),%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpfr_sqrt@plt>
  mov    0x0(%rbp),%esi
  mov    %ebx,%edi
  call   <mpfr_get_ld@plt>
  fstpt  0x10(%rsp)
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <mpfr_clears@plt>
  fldt   0x10(%rsp)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long double sqrtlfr(long double d) {
  mpfr_t frx;
  mpfr_inits(frx, NULL);
  mpfr_set_ld(frx, d, GMP_RNDN);
  mpfr_sqrt(frx, frx, GMP_RNDN);
  long double ret = mpfr_get_ld(frx, GMP_RNDN);
  mpfr_clears(frx, NULL);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sqrtlfr>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %ebp,%edi
  sub    $0x18,%rsp
  call   <mpfr_inits@plt>
  mov    D6(%rip),%rbx
  push   0x38(%rsp)
  mov    %ebp,%edi
  push   0x38(%rsp)
  mov    (%rbx),%esi
  call   <mpfr_set_ld@plt>
  mov    (%rbx),%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpfr_sqrt@plt>
  mov    (%rbx),%esi
  mov    %ebp,%edi
  call   <mpfr_get_ld@plt>
  mov    %ebp,%edi
  xor    %esi,%esi
  fstpt  0x10(%rsp)
  call   <mpfr_clears@plt>
  fldt   0x10(%rsp)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long double sqrtlfr(long double d) {
  mpfr_t frx;
  mpfr_inits(frx, NULL);
  mpfr_set_ld(frx, d, GMP_RNDN);
  mpfr_sqrt(frx, frx, GMP_RNDN);
  long double ret = mpfr_get_ld(frx, GMP_RNDN);
  mpfr_clears(frx, NULL);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqrtlfr>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %ebp,%edi
  sub    $0x18,%rsp
  call   <mpfr_inits@plt>
  mov    D6(%rip),%rbx
  push   0x38(%rsp)
  mov    %ebp,%edi
  push   0x38(%rsp)
  mov    (%rbx),%esi
  call   <mpfr_set_ld@plt>
  mov    (%rbx),%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpfr_sqrt@plt>
  mov    (%rbx),%esi
  mov    %ebp,%edi
  call   <mpfr_get_ld@plt>
  mov    %ebp,%edi
  xor    %esi,%esi
  fstpt  0x10(%rsp)
  call   <mpfr_clears@plt>
  fldt   0x10(%rsp)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long double sqrtlfr(long double d) {
  mpfr_t frx;
  mpfr_inits(frx, NULL);
  mpfr_set_ld(frx, d, GMP_RNDN);
  mpfr_sqrt(frx, frx, GMP_RNDN);
  long double ret = mpfr_get_ld(frx, GMP_RNDN);
  mpfr_clears(frx, NULL);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<biggest_common_divisor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L46:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L40
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L40
  mov    -0x4(%rbp),%eax
  jmp    L41
L40:
  subl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x4(%rbp)
  jg     L46
  mov    $0xffffffff,%eax
L41:
  pop    %rbp
  ret
```

assistant: ```c
int biggest_common_divisor(int num, int den) {
  int i;
  for (i = num; i > 0; i--) {
    if (num % i == 0 && den % i == 0)
      return i;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<biggest_common_divisor>:
  endbr64
  test   %edi,%edi
  jle    L14
  mov    %edi,%ecx
  jmp    L23
L68:
  sub    $0x1,%ecx
  je     L34
L23:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L68
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L68
  jmp    L52
L34:
  mov    $0xffffffff,%ecx
L52:
  mov    %ecx,%eax
  ret
L14:
  mov    $0xffffffff,%ecx
  jmp    L52
```

assistant: ```c
int biggest_common_divisor(int num, int den) {
  int i;
  for (i = num; i > 0; i--) {
    if (num % i == 0 && den % i == 0)
      return i;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<biggest_common_divisor>:
  endbr64
  test   %edi,%edi
  jle    L7
  mov    %edi,%r8d
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %edi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L10
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L23
L10:
  sub    $0x1,%r8d
  jne    L3
L7:
  mov    $0xffffffff,%r8d
L23:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int biggest_common_divisor(int num, int den) {
  int i;
  for (i = num; i > 0; i--) {
    if (num % i == 0 && den % i == 0)
      return i;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<biggest_common_divisor>:
  endbr64
  test   %edi,%edi
  jle    L17
  mov    %edi,%r8d
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %edi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L12
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L7
L12:
  sub    $0x1,%r8d
  jne    L1
L17:
  mov    $0xffffffff,%r8d
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int biggest_common_divisor(int num, int den) {
  int i;
  for (i = num; i > 0; i--) {
    if (num % i == 0 && den % i == 0)
      return i;
  }
  return -1;
}
```