ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<match>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <hasnoun@plt>
  test   %eax,%eax
  jne    L19
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %ebp,%edi
  call   <hasadjective@plt>
  test   %eax,%eax
  je     L38
  add    $0x4,%rbx
L19:
  mov    (%rbx),%esi
  test   %esi,%esi
  jne    L14
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L38:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int match(int obj, int noun, int *adjs) {
  int *aptr;
  if (!hasnoun(obj, noun))
    return (0);
  for (aptr = adjs; *aptr != 0; aptr++)
    if (!hasadjective(obj, *aptr))
      return (0);
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<match>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <hasnoun@plt>
  test   %eax,%eax
  jne    L29
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %ebp,%edi
  call   <hasadjective@plt>
  test   %eax,%eax
  je     L37
  add    $0x4,%rbx
L29:
  mov    (%rbx),%esi
  test   %esi,%esi
  jne    L25
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L37:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int match(int obj, int noun, int *adjs) {
  int *aptr;
  if (!hasnoun(obj, noun))
    return (0);
  for (aptr = adjs; *aptr != 0; aptr++)
    if (!hasadjective(obj, *aptr))
      return (0);
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hammingWeight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L16:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L19
  addl   $0x1,-0x8(%rbp)
L19:
  sarl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L16
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hammingWeight(uint32_t n) {
  int count = 0;
  for (int i = 0; i < 32; i++) {
    if (n & 0x0001) {
      count++;
    }
    n >>= 1;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hammingWeight>:
  endbr64
  mov    $0x20,%eax
  mov    $0x0,%edx
L9:
  mov    %edi,%ecx
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  sbb    $0xffffffff,%edx
  sar    %edi
  sub    $0x1,%eax
  jne    L9
  mov    %edx,%eax
  ret
```

assistant: ```c
int hammingWeight(uint32_t n) {
  int count = 0;
  for (int i = 0; i < 32; i++) {
    if (n & 0x0001) {
      count++;
    }
    n >>= 1;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hammingWeight>:
  endbr64
  mov    $0x20,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L6:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%r8d
  sar    %edi
  sub    $0x1,%eax
  jne    L6
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hammingWeight(uint32_t n) {
  int count = 0;
  for (int i = 0; i < 32; i++) {
    if (n & 0x0001) {
      count++;
    }
    n >>= 1;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hammingWeight>:
  endbr64
  mov    $0x20,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L6:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%r8d
  sar    %edi
  sub    $0x1,%eax
  jne    L6
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hammingWeight(uint32_t n) {
  int count = 0;
  for (int i = 0; i < 32; i++) {
    if (n & 0x0001) {
      count++;
    }
    n >>= 1;
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test19_remove_eldest_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x3,-0x10(%rbp)
  seta   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test19_remove_eldest_1(const struct l_hashtbl *h, unsigned long count) {
  (void)(h);
  (void)(count);
  return (count > 3) ? 1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test19_remove_eldest_1>:
  endbr64
  cmp    $0x3,%rsi
  seta   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int test19_remove_eldest_1(const struct l_hashtbl *h, unsigned long count) {
  (void)(h);
  (void)(count);
  return (count > 3) ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test19_remove_eldest_1>:
  endbr64
  xor    %eax,%eax
  cmp    $0x3,%rsi
  seta   %al
  ret
```

assistant: ```c
int test19_remove_eldest_1(const struct l_hashtbl *h, unsigned long count) {
  (void)(h);
  (void)(count);
  return (count > 3) ? 1 : 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test19_remove_eldest_1>:
  endbr64
  xor    %eax,%eax
  cmp    $0x3,%rsi
  seta   %al
  ret
```

assistant: ```c
int test19_remove_eldest_1(const struct l_hashtbl *h, unsigned long count) {
  (void)(h);
  (void)(count);
  return (count > 3) ? 1 : 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_81_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_81_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = S & stk3;
  stk1 = D | stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xrop3_81_1_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_81_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = S & stk3;
  stk1 = D | stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_81_1_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_81_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = S & stk3;
  stk1 = D | stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_81_1_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_81_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = S & stk3;
  stk1 = D | stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dinky>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L2
  mov    $0x0,%eax
  call   <oh_no@plt>
  jmp    L12
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <slinky@plt>
L12:
  nop
  leave
  ret
```

assistant: ```c
void dinky(int i) {
  if (i == 1) {
    oh_no();
  } else {
    slinky(i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dinky>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L1
  call   <slinky@plt>
L16:
  add    $0x8,%rsp
  ret
L1:
  mov    $0x0,%eax
  call   <oh_no@plt>
  jmp    L16
```

assistant: ```c
void dinky(int i) {
  if (i == 1) {
    oh_no();
  } else {
    slinky(i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dinky>:
  endbr64
  cmp    $0x1,%edi
  je     L6
  jmp    1060 <slinky@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  jmp    1070 <oh_no@plt>
```

assistant: ```c
void dinky(int i) {
  if (i == 1) {
    oh_no();
  } else {
    slinky(i);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<dinky>:
  endbr64
  cmp    $0x1,%edi
  je     L4
  jmp    1060 <slinky@plt>
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  jmp    1070 <oh_no@plt>
```

assistant: ```c
void dinky(int i) {
  if (i == 1) {
    oh_no();
  } else {
    slinky(i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<schnitt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L2
L43:
  movl   $0x1,-0x8(%rbp)
  jmp    L4
L20:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L34
  addl   $0x1,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L34:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L20
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L43
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int schnitt(int len, int *a, int *b, int *c) {
  int i, j, k;
  k = 0;
  for (i = 1; i <= len; i++)
    for (j = 1; j <= len; j++)
      if (a[i] == b[j]) {
        k++;
        c[k] = a[i];
      }
  return k;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<schnitt>:
  endbr64
  test   %edi,%edi
  jle    L49
  lea    0x4(%rsi),%r8
  lea    -0x1(%rdi),%eax
  shl    $0x2,%rax
  lea    0x8(%rsi,%rax,1),%r11
  lea    0x8(%rdx,%rax,1),%r9
  mov    $0x0,%edi
  jmp    L52
L24:
  add    $0x4,%rax
  cmp    %rax,%r9
  je     L55
L32:
  mov    (%r8),%esi
  cmp    (%rax),%esi
  jne    L24
  add    $0x1,%edi
  movslq %edi,%r10
  mov    %esi,(%rcx,%r10,4)
  jmp    L24
L55:
  add    $0x4,%r8
  cmp    %r11,%r8
  je     L61
L52:
  lea    0x4(%rdx),%rax
  jmp    L32
L49:
  mov    $0x0,%edi
L61:
  mov    %edi,%eax
  ret
```

assistant: ```c
int schnitt(int len, int *a, int *b, int *c) {
  int i, j, k;
  k = 0;
  for (i = 1; i <= len; i++)
    for (j = 1; j <= len; j++)
      if (a[i] == b[j]) {
        k++;
        c[k] = a[i];
      }
  return k;
}
```
user: What is the c source code of the assembly code below?

```asm
<schnitt>:
  endbr64
  test   %edi,%edi
  jle    L38
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi),%r8
  xor    %r9d,%r9d
  shl    $0x2,%rax
  lea    0x4(%rdx),%r10
  lea    0x8(%rsi,%rax,1),%r11
  lea    0x8(%rdx,%rax,1),%rsi
  nopl   0x0(%rax)
L36:
  mov    %r10,%rax
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%r8),%edx
  cmp    (%rax),%edx
  jne    L0
  add    $0x1,%r9d
  movslq %r9d,%rdi
  mov    %edx,(%rcx,%rdi,4)
L0:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L26
  add    $0x4,%r8
  cmp    %r11,%r8
  jne    L36
  mov    %r9d,%eax
  ret
L38:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int schnitt(int len, int *a, int *b, int *c) {
  int i, j, k;
  k = 0;
  for (i = 1; i <= len; i++)
    for (j = 1; j <= len; j++)
      if (a[i] == b[j]) {
        k++;
        c[k] = a[i];
      }
  return k;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<schnitt>:
  endbr64
  test   %edi,%edi
  jle    L38
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi),%r8
  xor    %r9d,%r9d
  shl    $0x2,%rax
  lea    0x4(%rdx),%r10
  lea    0x8(%rsi,%rax,1),%r11
  lea    0x8(%rdx,%rax,1),%rsi
  nopl   0x0(%rax)
L34:
  mov    %r10,%rax
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%r8),%edx
  cmp    (%rax),%edx
  jne    L37
  add    $0x1,%r9d
  movslq %r9d,%rdi
  mov    %edx,(%rcx,%rdi,4)
L37:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L2
  add    $0x4,%r8
  cmp    %r11,%r8
  jne    L34
  mov    %r9d,%eax
  ret
L38:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int schnitt(int len, int *a, int *b, int *c) {
  int i, j, k;
  k = 0;
  for (i = 1; i <= len; i++)
    for (j = 1; j <= len; j++)
      if (a[i] == b[j]) {
        k++;
        c[k] = a[i];
      }
  return k;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <subr@plt>
  mov    $0x1,%edi
  call   <end@plt>
  mov    $0x2,%edi
  call   <subr@plt>
  mov    $0x2,%edi
  call   <end@plt>
  mov    $0x3,%edi
  call   <subr@plt>
  mov    $0x3,%edi
  call   <end@plt>
  mov    $0x4,%edi
  call   <subr@plt>
  mov    $0x4,%edi
  call   <end@plt>
  mov    $0x5,%edi
  call   <subr@plt>
  mov    $0x5,%edi
  call   <subr2@plt>
  mov    $0x5,%edi
  call   <end@plt>
  mov    $0x6,%edi
  call   <subr@plt>
  mov    $0x6,%edi
  call   <subr2@plt>
  mov    $0x6,%edi
  call   <end@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  subr(1);
  end(1);
  subr(2);
  end(2);
  subr(3);
  end(3);
  subr(4);
  end(4);
  subr(5);
  subr2(5);
  end(5);
  subr(6);
  subr2(6);
  end(6);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <subr@plt>
  mov    $0x1,%edi
  call   <end@plt>
  mov    $0x2,%edi
  call   <subr@plt>
  mov    $0x2,%edi
  call   <end@plt>
  mov    $0x3,%edi
  call   <subr@plt>
  mov    $0x3,%edi
  call   <end@plt>
  mov    $0x4,%edi
  call   <subr@plt>
  mov    $0x4,%edi
  call   <end@plt>
  mov    $0x5,%edi
  call   <subr@plt>
  mov    $0x5,%edi
  call   <subr2@plt>
  mov    $0x5,%edi
  call   <end@plt>
  mov    $0x6,%edi
  call   <subr@plt>
  mov    $0x6,%edi
  call   <subr2@plt>
  mov    $0x6,%edi
  call   <end@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  subr(1);
  end(1);
  subr(2);
  end(2);
  subr(3);
  end(3);
  subr(4);
  end(4);
  subr(5);
  subr2(5);
  end(5);
  subr(6);
  subr2(6);
  end(6);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <subr@plt>
  mov    $0x1,%edi
  call   <end@plt>
  mov    $0x2,%edi
  call   <subr@plt>
  mov    $0x2,%edi
  call   <end@plt>
  mov    $0x3,%edi
  call   <subr@plt>
  mov    $0x3,%edi
  call   <end@plt>
  mov    $0x4,%edi
  call   <subr@plt>
  mov    $0x4,%edi
  call   <end@plt>
  mov    $0x5,%edi
  call   <subr@plt>
  mov    $0x5,%edi
  call   <subr2@plt>
  mov    $0x5,%edi
  call   <end@plt>
  mov    $0x6,%edi
  call   <subr@plt>
  mov    $0x6,%edi
  call   <subr2@plt>
  mov    $0x6,%edi
  call   <end@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  subr(1);
  end(1);
  subr(2);
  end(2);
  subr(3);
  end(3);
  subr(4);
  end(4);
  subr(5);
  subr2(5);
  end(5);
  subr(6);
  subr2(6);
  end(6);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <subr@plt>
  mov    $0x1,%edi
  call   <end@plt>
  mov    $0x2,%edi
  call   <subr@plt>
  mov    $0x2,%edi
  call   <end@plt>
  mov    $0x3,%edi
  call   <subr@plt>
  mov    $0x3,%edi
  call   <end@plt>
  mov    $0x4,%edi
  call   <subr@plt>
  mov    $0x4,%edi
  call   <end@plt>
  mov    $0x5,%edi
  call   <subr@plt>
  mov    $0x5,%edi
  call   <subr2@plt>
  mov    $0x5,%edi
  call   <end@plt>
  mov    $0x6,%edi
  call   <subr@plt>
  mov    $0x6,%edi
  call   <subr2@plt>
  mov    $0x6,%edi
  call   <end@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  subr(1);
  end(1);
  subr(2);
  end(2);
  subr(3);
  end(3);
  subr(4);
  end(4);
  subr(5);
  subr2(5);
  end(5);
  subr(6);
  subr2(6);
  end(6);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<collseq_table_lookup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x3c(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L31
  mov    -0x28(%rbp),%eax
  add    $0x5,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L31
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x3c(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L31
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x3c(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L23
L31:
  mov    $0xffffffff,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t collseq_table_lookup(const char *table, uint32_t wc) {
  uint32_t shift1 = ((const uint32_t *)table)[0];
  uint32_t index1 = wc >> shift1;
  uint32_t bound = ((const uint32_t *)table)[1];
  if (index1 < bound) {
    uint32_t lookup1 = ((const uint32_t *)table)[5 + index1];
    if (lookup1 != 0) {
      uint32_t shift2 = ((const uint32_t *)table)[2];
      uint32_t mask2 = ((const uint32_t *)table)[3];
      uint32_t index2 = (wc >> shift2) & mask2;
      uint32_t lookup2 = ((const uint32_t *)(table + lookup1))[index2];
      if (lookup2 != 0) {
        uint32_t mask3 = ((const uint32_t *)table)[4];
        uint32_t index3 = wc & mask3;
        uint32_t lookup3 = ((const uint32_t *)(table + lookup2))[index3];
        return lookup3;
      }
    }
  }
  return ~((uint32_t)0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<collseq_table_lookup>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%ecx
  mov    %esi,%edx
  sar    %cl,%edx
  cmp    0x4(%rdi),%edx
  jge    L26
  add    $0x5,%edx
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%edi
  test   %edi,%edi
  je     L13
  mov    0x8(%rax),%ecx
  mov    %esi,%edx
  sar    %cl,%edx
  and    0xc(%rax),%edx
  movslq %edx,%rdx
  movslq %edi,%rdi
  lea    (%rax,%rdx,4),%rdx
  mov    (%rdx,%rdi,1),%edx
  test   %edx,%edx
  je     L24
  and    0x10(%rax),%esi
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rax,%rsi,4),%rax
  mov    (%rax,%rdx,1),%eax
  ret
L26:
  mov    $0xffffffff,%eax
  ret
L13:
  mov    $0xffffffff,%eax
  ret
L24:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uint32_t collseq_table_lookup(const char *table, uint32_t wc) {
  uint32_t shift1 = ((const uint32_t *)table)[0];
  uint32_t index1 = wc >> shift1;
  uint32_t bound = ((const uint32_t *)table)[1];
  if (index1 < bound) {
    uint32_t lookup1 = ((const uint32_t *)table)[5 + index1];
    if (lookup1 != 0) {
      uint32_t shift2 = ((const uint32_t *)table)[2];
      uint32_t mask2 = ((const uint32_t *)table)[3];
      uint32_t index2 = (wc >> shift2) & mask2;
      uint32_t lookup2 = ((const uint32_t *)(table + lookup1))[index2];
      if (lookup2 != 0) {
        uint32_t mask3 = ((const uint32_t *)table)[4];
        uint32_t index3 = wc & mask3;
        uint32_t lookup3 = ((const uint32_t *)(table + lookup2))[index3];
        return lookup3;
      }
    }
  }
  return ~((uint32_t)0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<collseq_table_lookup>:
  endbr64
  mov    (%rdi),%ecx
  mov    %esi,%edx
  mov    %rdi,%rax
  sar    %cl,%edx
  cmp    0x4(%rdi),%edx
  jge    L2
  add    $0x5,%edx
  movslq %edx,%rdx
  movslq (%rdi,%rdx,4),%rdi
  test   %edi,%edi
  je     L2
  mov    0x8(%rax),%ecx
  mov    %esi,%edx
  sar    %cl,%edx
  and    0xc(%rax),%edx
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%rdx
  movslq (%rdx,%rdi,1),%rdx
  test   %edx,%edx
  je     L2
  and    0x10(%rax),%esi
  movslq %esi,%rsi
  lea    (%rax,%rsi,4),%rax
  mov    (%rax,%rdx,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uint32_t collseq_table_lookup(const char *table, uint32_t wc) {
  uint32_t shift1 = ((const uint32_t *)table)[0];
  uint32_t index1 = wc >> shift1;
  uint32_t bound = ((const uint32_t *)table)[1];
  if (index1 < bound) {
    uint32_t lookup1 = ((const uint32_t *)table)[5 + index1];
    if (lookup1 != 0) {
      uint32_t shift2 = ((const uint32_t *)table)[2];
      uint32_t mask2 = ((const uint32_t *)table)[3];
      uint32_t index2 = (wc >> shift2) & mask2;
      uint32_t lookup2 = ((const uint32_t *)(table + lookup1))[index2];
      if (lookup2 != 0) {
        uint32_t mask3 = ((const uint32_t *)table)[4];
        uint32_t index3 = wc & mask3;
        uint32_t lookup3 = ((const uint32_t *)(table + lookup2))[index3];
        return lookup3;
      }
    }
  }
  return ~((uint32_t)0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<collseq_table_lookup>:
  endbr64
  mov    (%rdi),%ecx
  mov    %esi,%edx
  mov    %rdi,%rax
  sar    %cl,%edx
  cmp    0x4(%rdi),%edx
  jge    L6
  add    $0x5,%edx
  movslq %edx,%rdx
  movslq (%rdi,%rdx,4),%rdi
  test   %edi,%edi
  je     L6
  mov    0x8(%rax),%ecx
  mov    %esi,%edx
  sar    %cl,%edx
  and    0xc(%rax),%edx
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%rdx
  movslq (%rdx,%rdi,1),%rdx
  test   %edx,%edx
  je     L6
  and    0x10(%rax),%esi
  movslq %esi,%rsi
  lea    (%rax,%rsi,4),%rax
  mov    (%rax,%rdx,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uint32_t collseq_table_lookup(const char *table, uint32_t wc) {
  uint32_t shift1 = ((const uint32_t *)table)[0];
  uint32_t index1 = wc >> shift1;
  uint32_t bound = ((const uint32_t *)table)[1];
  if (index1 < bound) {
    uint32_t lookup1 = ((const uint32_t *)table)[5 + index1];
    if (lookup1 != 0) {
      uint32_t shift2 = ((const uint32_t *)table)[2];
      uint32_t mask2 = ((const uint32_t *)table)[3];
      uint32_t index2 = (wc >> shift2) & mask2;
      uint32_t lookup2 = ((const uint32_t *)(table + lookup1))[index2];
      if (lookup2 != 0) {
        uint32_t mask3 = ((const uint32_t *)table)[4];
        uint32_t index3 = wc & mask3;
        uint32_t lookup3 = ((const uint32_t *)(table + lookup2))[index3];
        return lookup3;
      }
    }
  }
  return ~((uint32_t)0);
}
```