ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  cmp    -0x1c(%rbp),%al
  jne    L13
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L19
L13:
  mov    -0x18(%rbp),%rax
L19:
  leave
  ret
```

assistant: ```c
char *trim_end(char *string, char to_trim) {
  char last_char = string[strlen(string) - 1];
  if (last_char == to_trim) {
    char *new_string = string;
    new_string[strlen(string) - 1] = 0;
    return new_string;
  } else
    return string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim_end>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  cltq
  cmp    %bpl,-0x1(%rbx,%rax,1)
  je     L0
L6:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L6
```

assistant: ```c
char *trim_end(char *string, char to_trim) {
  char last_char = string[strlen(string) - 1];
  if (last_char == to_trim) {
    char *new_string = string;
    new_string[strlen(string) - 1] = 0;
    return new_string;
  } else
    return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trim_end>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  cmp    %bl,-0x1(%r12,%rax,1)
  je     L6
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim_end(char *string, char to_trim) {
  char last_char = string[strlen(string) - 1];
  if (last_char == to_trim) {
    char *new_string = string;
    new_string[strlen(string) - 1] = 0;
    return new_string;
  } else
    return string;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trim_end>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  cmp    %bl,-0x1(%r12,%rax,1)
  je     L0
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim_end(char *string, char to_trim) {
  char last_char = string[strlen(string) - 1];
  if (last_char == to_trim) {
    char *new_string = string;
    new_string[strlen(string) - 1] = 0;
    return new_string;
  } else
    return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getFileSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fileno@plt>
  mov    %eax,-0x10(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int64_t getFileSize(FILE *fp) {
  struct stat buf;
  int fd = fileno(fp);
  fstat(fd, &buf);
  int64_t size = buf.st_size;
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getFileSize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fileno@plt>
  mov    %eax,%edi
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t getFileSize(FILE *fp) {
  struct stat buf;
  int fd = fileno(fp);
  fstat(fd, &buf);
  int64_t size = buf.st_size;
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getFileSize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fileno@plt>
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t getFileSize(FILE *fp) {
  struct stat buf;
  int fd = fileno(fp);
  fstat(fd, &buf);
  int64_t size = buf.st_size;
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getFileSize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fileno@plt>
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t getFileSize(FILE *fp) {
  struct stat buf;
  int fd = fileno(fp);
  fstat(fd, &buf);
  int64_t size = buf.st_size;
  return size;
}
```
user: What is the c source code of the assembly code below?

```asm
<readSonar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,%rdx
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string

tool: D16: %.24s

tool: D34: %s


assistant: ```c
const char *readSonar() {
  time_t ticks = time(NULL);
  static char sonar[1025];
  sprintf(sonar, "%.24s", ctime(&ticks));
  printf("%s\n", sonar);
  return sonar;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<readSonar>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <ctime@plt>
  mov    %rax,%rdx
  lea    D11(%rip),%rsi
  lea    D23(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D11: %.24s

tool: D9: %s


assistant: ```c
const char *readSonar() {
  time_t ticks = time(NULL);
  static char sonar[1025];
  sprintf(sonar, "%.24s", ctime(&ticks));
  printf("%s\n", sonar);
  return sonar;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readSonar>:
  endbr64
  push   %r12
  xor    %edi,%edi
  lea    D25(%rip),%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  lea    D6(%rip),%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D6: %.24s

tool: D9: %s


assistant: ```c
const char *readSonar() {
  time_t ticks = time(NULL);
  static char sonar[1025];
  sprintf(sonar, "%.24s", ctime(&ticks));
  printf("%s\n", sonar);
  return sonar;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readSonar>:
  endbr64
  push   %r12
  xor    %edi,%edi
  lea    D22(%rip),%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %r12,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string

tool: D21: %.24s

tool: D17: %s


assistant: ```c
const char *readSonar() {
  time_t ticks = time(NULL);
  static char sonar[1025];
  sprintf(sonar, "%.24s", ctime(&ticks));
  printf("%s\n", sonar);
  return sonar;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L17:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <do_something@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  add    $0x9,%eax
  cmp    %eax,-0x4(%rbp)
  jg     L5
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L17
L5:
  nop
  leave
  ret
```

assistant: ```c
void f(int m, int n) {
  int j;
  for (j = m; j < m + 10 && j < n; j++)
    do_something(j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    0x9(%rdi),%r12d
  cmp    %esi,%edi
  jge    L20
L27:
  mov    %ebx,%edi
  call   <do_something@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jle    L20
  cmp    %r12d,%ebx
  jle    L27
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void f(int m, int n) {
  int j;
  for (j = m; j < m + 10 && j < n; j++)
    do_something(j);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  cmp    %esi,%edi
  jge    L26
  push   %r12
  lea    0x9(%rdi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L28:
  cmp    %ebx,%ebp
  jle    L25
L38:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <do_something@plt>
  cmp    %r12d,%ebx
  jle    L28
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  ret
```

assistant: ```c
void f(int m, int n) {
  int j;
  for (j = m; j < m + 10 && j < n; j++)
    do_something(j);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  cmp    %esi,%edi
  jge    L20
  push   %r12
  lea    0x9(%rdi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L31:
  cmp    %ebx,%ebp
  jle    L7
L28:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <do_something@plt>
  cmp    %r12d,%ebx
  jle    L31
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  ret
```

assistant: ```c
void f(int m, int n) {
  int j;
  for (j = m; j < m + 10 && j < n; j++)
    do_something(j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninivar_bsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <bsearch@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninivar_bsearch(void) {
  void *key;
  void *base;
  size_t num;
  size_t size;
  (void)bsearch(key, base, num, size, (int (*)(const void *, const void *))strcmp);
}
```
user: What is the c source code of the assembly code below?

```asm
<uninivar_bsearch>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <bsearch@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninivar_bsearch(void) {
  void *key;
  void *base;
  size_t num;
  size_t size;
  (void)bsearch(key, base, num, size, (int (*)(const void *, const void *))strcmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uninivar_bsearch>:
  endbr64
  mov    D6(%rip),%rax
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    (%rax),%r8
  jmp    1050 <bsearch@plt>
```

assistant: ```c
void uninivar_bsearch(void) {
  void *key;
  void *base;
  size_t num;
  size_t size;
  (void)bsearch(key, base, num, size, (int (*)(const void *, const void *))strcmp);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<uninivar_bsearch>:
  endbr64
  mov    D2(%rip),%rax
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    (%rax),%r8
  jmp    1050 <bsearch@plt>
```

assistant: ```c
void uninivar_bsearch(void) {
  void *key;
  void *base;
  size_t num;
  size_t size;
  (void)bsearch(key, base, num, size, (int (*)(const void *, const void *))strcmp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strstrip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strend@plt>
  mov    %rax,-0x8(%rbp)
  subq   $0x1,-0x8(%rbp)
  jmp    L23
L5:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  subq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L27
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L5
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  je     L5
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L5
L27:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strstrip(char *s) {
  char *p;
  p = strend(s);
  for (p--; p >= s && (*p == ' ' || *p == '>' || *p == '-'); p--)
    *p = '\0';
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strstrip>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strend@plt>
  sub    $0x1,%rax
  cmp    %rax,%rbx
  ja     L25
  lea    -0x1(%rbx),%rsi
  movabs $0x4000200100000000,%rcx
  jmp    L3
L18:
  bt     %rdx,%rcx
  jae    L25
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rsi,%rax
  je     L25
L3:
  movzbl (%rax),%edx
  cmp    $0x3e,%dl
  jbe    L18
L25:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *strstrip(char *s) {
  char *p;
  p = strend(s);
  for (p--; p >= s && (*p == ' ' || *p == '>' || *p == '-'); p--)
    *p = '\0';
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strstrip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strend@plt>
  sub    $0x1,%rax
  cmp    %rax,%r12
  ja     L28
  movabs $0xbfffdffeffffffff,%rsi
  lea    -0x1(%r12),%rcx
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl (%rax),%edx
  cmp    $0x3e,%dl
  jbe    L22
L28:
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L22:
  bt     %rdx,%rsi
  jb     L28
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L19
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strstrip(char *s) {
  char *p;
  p = strend(s);
  for (p--; p >= s && (*p == ' ' || *p == '>' || *p == '-'); p--)
    *p = '\0';
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strstrip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strend@plt>
  sub    $0x1,%rax
  cmp    %rax,%r12
  ja     L17
  movabs $0xbfffdffeffffffff,%rsi
  lea    -0x1(%r12),%rcx
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rax),%edx
  cmp    $0x3e,%dl
  jbe    L26
L17:
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L26:
  bt     %rdx,%rsi
  jb     L17
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L3
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strstrip(char *s) {
  char *p;
  p = strend(s);
  for (p--; p >= s && (*p == ' ' || *p == '>' || *p == '-'); p--)
    *p = '\0';
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *c_calloc(size_t num_elements, size_t size) {
  void *result = calloc(num_elements, size);
  assert(result != NULL);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<c_calloc>:
  endbr64
  push   %rbx
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *c_calloc(size_t num_elements, size_t size) {
  void *result = calloc(num_elements, size);
  assert(result != NULL);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<c_calloc>:
  endbr64
  push   %r12
  call   <calloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *c_calloc(size_t num_elements, size_t size) {
  void *result = calloc(num_elements, size);
  assert(result != NULL);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_calloc>:
  endbr64
  push   %r12
  call   <calloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *c_calloc(size_t num_elements, size_t size) {
  void *result = calloc(num_elements, size);
  assert(result != NULL);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0x4(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: Hello world


assistant: ```c
int pain() {
  int my_var = 3;
  printf("Hello world\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pain>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: Hello world


assistant: ```c
int pain() {
  int my_var = 3;
  printf("Hello world\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pain>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: Hello world


assistant: ```c
int pain() {
  int my_var = 3;
  printf("Hello world\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pain>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: Hello world


assistant: ```c
int pain() {
  int my_var = 3;
  printf("Hello world\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<makeEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L49
L18:
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L12:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L28
  addl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L37
L28:
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L12
L37:
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  sub    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j;
  int x = 0;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++) {
      if (*(s1 + i) == *(s2 + j)) {
        x = x + 2;
        printf("%d", x);
        *(s2 + j) = '\0';
        break;
      }
    }
  }
  return n1 + n2 - x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<makeEqual>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    %rdx,(%rsp)
  mov    %ecx,%r14d
  test   %esi,%esi
  jle    L45
  mov    %rdi,%r12
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r15
  mov    $0x0,%r13d
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%rbp
  jmp    L67
L26:
  add    $0x2,%r13d
  mov    %r13d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  movb   $0x0,(%rbx)
L24:
  add    $0x1,%r12
  cmp    %r15,%r12
  je     L18
L67:
  test   %r14d,%r14d
  jle    L24
  movzbl (%r12),%edx
  mov    (%rsp),%rax
L63:
  mov    %rax,%rbx
  cmp    (%rax),%dl
  je     L26
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L63
  jmp    L24
L45:
  mov    $0x0,%r13d
L18:
  mov    0xc(%rsp),%eax
  add    %r14d,%eax
  sub    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j;
  int x = 0;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++) {
      if (*(s1 + i) == *(s2 + j)) {
        x = x + 2;
        printf("%d", x);
        *(s2 + j) = '\0';
        break;
      }
    }
  }
  return n1 + n2 - x;
}
```