ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<mat4_ortho>:
  endbr64
  movaps %xmm0,%xmm7
  movss  D19(%rip),%xmm6
  addss  %xmm1,%xmm0
  movq   $0x0,0x4(%rdi)
  subss  %xmm1,%xmm7
  movq   $0x0,0xc(%rdi)
  movaps %xmm6,%xmm10
  movaps %xmm6,%xmm9
  movaps %xmm6,%xmm8
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x20(%rdi)
  divss  %xmm7,%xmm10
  movaps %xmm2,%xmm7
  addss  %xmm3,%xmm2
  movl   $0x0,0x2c(%rdi)
  subss  %xmm3,%xmm7
  movss  %xmm6,0x3c(%rdi)
  divss  %xmm7,%xmm9
  movaps %xmm4,%xmm7
  addss  %xmm5,%xmm4
  subss  %xmm5,%xmm7
  mulss  %xmm10,%xmm0
  movaps %xmm10,%xmm11
  movss  %xmm0,0x30(%rdi)
  divss  %xmm7,%xmm8
  movss  D10(%rip),%xmm7
  mulss  %xmm7,%xmm11
  mulss  %xmm9,%xmm7
  mulss  %xmm9,%xmm2
  movss  %xmm11,(%rdi)
  movss  %xmm7,0x14(%rdi)
  movss  %xmm2,0x34(%rdi)
  mulss  %xmm8,%xmm4
  movaps %xmm8,%xmm7
  addss  %xmm8,%xmm7
  movss  %xmm7,0x28(%rdi)
  movss  %xmm4,0x38(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: f32
name: parse_data
arguments: data_label: D10
type_infered: byte[4]

tool: D19: 1

tool: {"D10": [0x00,0x00,0x00,0xc0]}

assistant: ```c
void mat4_ortho(float *dst, float left, float right, float bottom, float top, float near, float far) {
  float lr = 1 / (left - right);
  float bt = 1 / (bottom - top);
  float nf = 1 / (near - far);
  dst[0] = -2 * lr;
  dst[1] = 0;
  dst[2] = 0;
  dst[3] = 0;
  dst[4] = 0;
  dst[5] = -2 * bt;
  dst[6] = 0;
  dst[7] = 0;
  dst[8] = 0;
  dst[9] = 0;
  dst[10] = 2 * nf;
  dst[11] = 0;
  dst[12] = (left + right) * lr;
  dst[13] = (top + bottom) * bt;
  dst[14] = (far + near) * nf;
  dst[15] = 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<smp_kv_keyIsequal_bystrs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <smp_str_cmp@plt>
  test   %eax,%eax
  jne    L1
  mov    $0x0,%eax
  jmp    L3
L1:
  mov    $0xfffffffe,%eax
L3:
  leave
  ret
```

assistant: ```c
int smp_kv_keyIsequal_bystrs(const struct smp_str_s *key1, const struct smp_str_s *key2) {
  if (smp_str_cmp(key1, key2) == (0))
    return (0);
  return (-2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<smp_kv_keyIsequal_bystrs>:
  endbr64
  sub    $0x8,%rsp
  call   <smp_str_cmp@plt>
  test   %eax,%eax
  mov    $0xfffffffe,%edx
  cmovne %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int smp_kv_keyIsequal_bystrs(const struct smp_str_s *key1, const struct smp_str_s *key2) {
  if (smp_str_cmp(key1, key2) == (0))
    return (0);
  return (-2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<smp_kv_keyIsequal_bystrs>:
  endbr64
  sub    $0x8,%rsp
  call   <smp_str_cmp@plt>
  mov    $0xfffffffe,%edx
  test   %eax,%eax
  cmovne %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int smp_kv_keyIsequal_bystrs(const struct smp_str_s *key1, const struct smp_str_s *key2) {
  if (smp_str_cmp(key1, key2) == (0))
    return (0);
  return (-2);
}
```
user: What is the c source code of the assembly code below?

```asm
<smp_kv_keyIsequal_bystrs>:
  endbr64
  sub    $0x8,%rsp
  call   <smp_str_cmp@plt>
  mov    $0xfffffffe,%edx
  test   %eax,%eax
  cmovne %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int smp_kv_keyIsequal_bystrs(const struct smp_str_s *key1, const struct smp_str_s *key2) {
  if (smp_str_cmp(key1, key2) == (0))
    return (0);
  return (-2);
}
```
user: What is the c source code of the assembly code below:

```asm
<bar1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x31,-0x4(%rbp)
  jg     L2
  addl   $0xa,-0x4(%rbp)
  jmp    L1
L2:
  subl   $0xa,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int bar1(int c) {
  if (c < 50)
    c += 10;
  else
    c -= 10;
  return c * c;
}
```
user: What is the c source code of the assembly code below:

```asm
<bar1>:
  endbr64
  lea    0xa(%rdi),%edx
  lea    -0xa(%rdi),%eax
  cmp    $0x31,%edi
  cmovle %edx,%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int bar1(int c) {
  if (c < 50)
    c += 10;
  else
    c -= 10;
  return c * c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar1>:
  endbr64
  cmp    $0x31,%edi
  lea    0xa(%rdi),%edx
  lea    -0xa(%rdi),%eax
  cmovle %edx,%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int bar1(int c) {
  if (c < 50)
    c += 10;
  else
    c -= 10;
  return c * c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bar1>:
  endbr64
  cmp    $0x31,%edi
  lea    0xa(%rdi),%edx
  lea    -0xa(%rdi),%eax
  cmovle %edx,%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int bar1(int c) {
  if (c < 50)
    c += 10;
  else
    c -= 10;
  return c * c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_redirect_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0xfffffffe,-0x14(%rbp)
  je     L73
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L23
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  test   %eax,%eax
  jns    L60
  movl   $0x16,-0x4(%rbp)
  jmp    L60
L23:
  mov    -0x14(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  test   %eax,%eax
  jns    L25
  movl   $0x16,-0x4(%rbp)
  jmp    L10
L25:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <dup2@plt>
  test   %eax,%eax
  jns    L48
  movl   $0x16,-0x4(%rbp)
  jmp    L48
L73:
  nop
  jmp    L10
L60:
  nop
  jmp    L10
L48:
  nop
L10:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _redirect_fd(int nfd, int ofd) {
  int res = 0;
  switch (nfd) {
  case (-1):
    if (close(ofd) < 0)
      res = 22;
    break;
  case (-2):
    break;
  default:
    assert(nfd >= 0);
    if (close(ofd) < 0) {
      res = 22;
      break;
    }
    if (dup2(nfd, ofd) < 0)
      res = 22;
    break;
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_redirect_fd>:
  endbr64
  mov    $0x0,%eax
  cmp    $0xfffffffe,%edi
  je     L33
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0xffffffff,%edi
  jne    L14
  mov    %esi,%edi
  call   <close@plt>
  sar    $0x1f,%eax
  and    $0x16,%eax
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    %eax,%edx
  mov    $0x16,%eax
  test   %edx,%edx
  js     L20
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <dup2@plt>
  sar    $0x1f,%eax
  and    $0x16,%eax
  jmp    L20
L33:
  ret
```

assistant: ```c
int _redirect_fd(int nfd, int ofd) {
  int res = 0;
  switch (nfd) {
  case (-1):
    if (close(ofd) < 0)
      res = 22;
    break;
  case (-2):
    break;
  default:
    assert(nfd >= 0);
    if (close(ofd) < 0) {
      res = 22;
      break;
    }
    if (dup2(nfd, ofd) < 0)
      res = 22;
    break;
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_redirect_fd>:
  endbr64
  xor    %eax,%eax
  cmp    $0xfffffffe,%edi
  je     L50
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  jne    L32
  mov    %esi,%edi
  call   <close@plt>
  test   %eax,%eax
  js     L52
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %r12d,%edi
  call   <close@plt>
  test   %eax,%eax
  jns    L9
L52:
  add    $0x8,%rsp
  mov    $0x16,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  ret
  nopl   0x0(%rax)
L9:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <dup2@plt>
  test   %eax,%eax
  jns    L14
  jmp    L52
```

assistant: ```c
int _redirect_fd(int nfd, int ofd) {
  int res = 0;
  switch (nfd) {
  case (-1):
    if (close(ofd) < 0)
      res = 22;
    break;
  case (-2):
    break;
  default:
    assert(nfd >= 0);
    if (close(ofd) < 0) {
      res = 22;
      break;
    }
    if (dup2(nfd, ofd) < 0)
      res = 22;
    break;
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_redirect_fd>:
  endbr64
  xor    %eax,%eax
  cmp    $0xfffffffe,%edi
  je     L31
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  jne    L21
  mov    %esi,%edi
  call   <close@plt>
  test   %eax,%eax
  js     L11
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %r12d,%edi
  call   <close@plt>
  test   %eax,%eax
  jns    L12
L11:
  add    $0x8,%rsp
  mov    $0x16,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  ret
  nopl   0x0(%rax)
L12:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <dup2@plt>
  test   %eax,%eax
  jns    L30
  jmp    L11
```

assistant: ```c
int _redirect_fd(int nfd, int ofd) {
  int res = 0;
  switch (nfd) {
  case (-1):
    if (close(ofd) < 0)
      res = 22;
    break;
  case (-2):
    break;
  default:
    assert(nfd >= 0);
    if (close(ofd) < 0) {
      res = 22;
      break;
    }
    if (dup2(nfd, ofd) < 0)
      res = 22;
    break;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L27
L0:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L27:
  cmpl   $0x3,-0x18(%rbp)
  jle    L0
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D2: test1: argc %d


tool: D7: j %d


assistant: ```c
void test1(int argc, char **argv) {
  int x, i, j;
  unsigned char *ptr;
  printf("test1: argc %d\n", argc);
  x = argc;
  j = 0;
  ptr = (unsigned char *)&x;
  for (i = 0; i < 4; i++) {
    j += *ptr++;
  }
  printf("j %d\n", j);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test1>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  lea    0x4(%rsp),%rax
  mov    $0x0,%esi
  lea    0x8(%rsp),%rcx
L15:
  add    $0x1,%rax
  movzbl -0x1(%rax),%edx
  add    %edx,%esi
  cmp    %rcx,%rax
  jne    L15
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
datatype: string
name: extract_symbolic_data
arguments: tag: D13
datatype: string

tool: D12: test1: argc %d


tool: D13: j %d


assistant: ```c
void test1(int argc, char **argv) {
  int x, i, j;
  unsigned char *ptr;
  printf("test1: argc %d\n", argc);
  x = argc;
  j = 0;
  ptr = (unsigned char *)&x;
  for (i = 0; i < 4; i++) {
    j += *ptr++;
  }
  printf("j %d\n", j);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test1>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    %edi,%ebx
  lea    D7(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  lea    0x4(%rsp),%rax
  xor    %esi,%esi
  lea    0x8(%rsp),%rcx
L2:
  movzbl (%rax),%edx
  add    $0x1,%rax
  add    %edx,%esi
  cmp    %rcx,%rax
  jne    L2
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  lea    D3(%rip),%rdi
  pop    %rbx
  jmp    1070 <printf@plt>
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D3
data_type: string

tool: D7: test1: argc %d


tool: D3: j %d


assistant: ```c
void test1(int argc, char **argv) {
  int x, i, j;
  unsigned char *ptr;
  printf("test1: argc %d\n", argc);
  x = argc;
  j = 0;
  ptr = (unsigned char *)&x;
  for (i = 0; i < 4; i++) {
    j += *ptr++;
  }
  printf("j %d\n", j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test1>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    %edi,%ebx
  lea    D11(%rip),%rdi
  call   <printf@plt>
  movzbl %bh,%eax
  movzbl %bl,%edx
  lea    D15(%rip),%rdi
  add    %eax,%edx
  mov    %ebx,%eax
  shr    $0x18,%ebx
  shr    $0x10,%eax
  movzbl %al,%eax
  add    %edx,%eax
  lea    (%rbx,%rax,1),%esi
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D15
data_type: string

tool: D11: test1: argc %d


tool: D15: j %d


assistant: ```c
void test1(int argc, char **argv) {
  int x, i, j;
  unsigned char *ptr;
  printf("test1: argc %d\n", argc);
  x = argc;
  j = 0;
  ptr = (unsigned char *)&x;
  for (i = 0; i < 4; i++) {
    j += *ptr++;
  }
  printf("j %d\n", j);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sleep_ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,D7(%rip)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void sleep_ns(int nanoseconds) {
  static struct timespec time;
  struct timespec rem;
  time.tv_nsec = nanoseconds;
  nanosleep(&time, &rem);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sleep_ns>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,D13(%rip)
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_ns(int nanoseconds) {
  static struct timespec time;
  struct timespec rem;
  time.tv_nsec = nanoseconds;
  nanosleep(&time, &rem);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sleep_ns>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %edi,D16(%rip)
  lea    D16(%rip),%rdi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_ns(int nanoseconds) {
  static struct timespec time;
  struct timespec rem;
  time.tv_nsec = nanoseconds;
  nanosleep(&time, &rem);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sleep_ns>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %edi,D18(%rip)
  lea    D18(%rip),%rdi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_ns(int nanoseconds) {
  static struct timespec time;
  struct timespec rem;
  time.tv_nsec = nanoseconds;
  nanosleep(&time, &rem);
}
```
user: What is the c source code of the assembly code below?

```asm
<xrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  jne    L0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L0:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: not enough virtual memory!

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  register void *val = realloc(ptr, size);
  if (val == 0)
    error("not enough virtual memory!");
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrealloc>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
L4:
  mov    %rbx,%rax
  pop    %rbx
  ret
L3:
  lea    D9(%rip),%rdi
  call   <error@plt>
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: not enough virtual memory!

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  register void *val = realloc(ptr, size);
  if (val == 0)
    error("not enough virtual memory!");
  return val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L13:
  mov    %r12,%rax
  pop    %r12
  ret
L11:
  lea    D3(%rip),%rdi
  call   <error@plt>
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string

tool: D3: not enough virtual memory!

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  register void *val = realloc(ptr, size);
  if (val == 0)
    error("not enough virtual memory!");
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L12:
  mov    %r12,%rax
  pop    %r12
  ret
L14:
  lea    D8(%rip),%rdi
  call   <error@plt>
  jmp    L12
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string

tool: D8: not enough virtual memory!

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  register void *val = realloc(ptr, size);
  if (val == 0)
    error("not enough virtual memory!");
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x74(%rbp)
  movl   $0x1,-0x78(%rbp)
  jmp    L0
L38:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x78(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L60
  addl   $0x1,-0x74(%rbp)
  jmp    L18
L60:
  movl   $0x1,-0x74(%rbp)
L18:
  cmpl   $0x6,-0x74(%rbp)
  jle    L68
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L55
L68:
  addl   $0x1,-0x78(%rbp)
L0:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x78(%rbp)
  jl     L38
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L55:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D7
type: string
name: parse_data
arguments: label: D27
type: string

tool: D15: %s

tool: D7: YES


tool: D27: NO


assistant: ```c
int main() {
  char s[101];
  scanf("%s", s);
  int i, count = 1;
  for (i = 1; i < strlen(s); i++) {
    if (s[i] == s[i - 1])
      count++;
    else
      count = 1;
    if (count > 6) {
      printf("YES\n");
      return 0;
    }
  }
  printf("NO\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%ebx
  mov    $0x1,%r12d
  mov    %rsp,%rbp
  jmp    L65
L1:
  add    $0x1,%r12d
  cmp    $0x6,%r12d
  jg     L24
L10:
  add    $0x1,%rbx
L65:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L50
  movzbl -0x1(%rsp,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  je     L1
  mov    $0x1,%r12d
  jmp    L10
L24:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L50:
  lea    D21(%rip),%rdi
  call   <printf@plt>
L40:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D28
data_type: string
name: read_data
arguments: tag: D21
data_type: string

tool: D13: %s

tool: D28: YES


tool: D21: NO


assistant: ```c
int main() {
  char s[101];
  scanf("%s", s);
  int i, count = 1;
  for (i = 1; i < strlen(s); i++) {
    if (s[i] == s[i - 1])
      count++;
    else
      count = 1;
    if (count > 6) {
      printf("YES\n");
      return 0;
    }
  }
  printf("NO\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%rdi
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    -0x1(%rsp),%r13
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L45:
  mov    $0x1,%r12d
L7:
  add    $0x1,%rbx
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L20
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  jne    L45
  add    $0x1,%r12d
  cmp    $0x7,%r12d
  jne    L7
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L20:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
type: string
name: read_data
arguments: tag: D23
type: string
name: read_data
arguments: tag: D8
type: string

tool: D11: %s

tool: D23: YES


tool: D8: NO


assistant: ```c
int main() {
  char s[101];
  scanf("%s", s);
  int i, count = 1;
  for (i = 1; i < strlen(s); i++) {
    if (s[i] == s[i - 1])
      count++;
    else
      count = 1;
    if (count > 6) {
      printf("YES\n");
      return 0;
    }
  }
  printf("NO\n");
  return 0;
}
```