user: 请将以下的汇编代码转换成C语言代码：

```asm
<minDistance0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r15d
  mov    %eax,0x10(%rsp)
  call   <strlen@plt>
  lea    0x8(,%r15,8),%edi
  mov    %eax,%ebx
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %r15d,%r15d
  js     L109
  mov    0x18(%rsp),%r12
  lea    0x4(,%rbx,4),%r14d
  xor    %ecx,%ecx
  mov    %r12,%r15
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %r14d,%edi
  mov    %ecx,0x8(%rsp)
  add    $0x8,%r12
  call   <malloc@plt>
  mov    %r14d,%edx
  xor    %esi,%esi
  mov    %rax,-0x8(%r12)
  mov    %rax,%rdi
  call   <memset@plt>
  mov    0x8(%rsp),%ecx
  add    $0x1,%ecx
  cmp    %ecx,0x10(%rsp)
  jge    L43
  xor    %eax,%eax
  nopl   0x0(%rax)
L71:
  mov    (%r15),%rdx
  add    $0x8,%r15
  mov    %eax,(%rdx)
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %edx,0x10(%rsp)
  jne    L71
L109:
  test   %ebx,%ebx
  js     L58
  mov    0x18(%rsp),%rax
  mov    (%rax),%rcx
  movslq %ebx,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %eax,(%rcx,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,0x8(%rsp)
  jne    L5
L77:
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L116
  mov    $0x1,%r14d
  mov    0x18(%rsp),%rax
  mov    %r13,%r15
  sub    %r13d,%r14d
  mov    %r14d,0x14(%rsp)
  lea    0x8(%rax),%r12
  nopw   0x0(%rax,%rax,1)
L8:
  test   %ebx,%ebx
  jle    L70
  mov    (%r12),%rsi
  lea    -0x8(%r12),%r13
  mov    $0x1,%r14d
  jmp    L44
  nopl   (%rax)
L122:
  mov    %r10d,(%rsi,%r14,4)
  add    $0x1,%r14
  cmp    %r14d,%ebx
  jl     L70
L44:
  mov    0x0(%r13),%rax
  lea    0x0(,%r14,4),%rdx
  movzbl -0x1(%rbp,%r14,1),%ecx
  mov    -0x4(%rax,%rdx,1),%r10d
  cmp    %cl,(%r15)
  je     L122
  mov    -0x4(%rsi,%rdx,1),%esi
  mov    (%rax,%r14,4),%edi
  mov    %r10d,%edx
  call   <min@plt>
  mov    (%r12),%rsi
  add    $0x1,%eax
  mov    %eax,(%rsi,%r14,4)
  add    $0x1,%r14
  cmp    %r14d,%ebx
  jge    L44
L70:
  mov    0x14(%rsp),%eax
  add    $0x1,%r15
  add    $0x8,%r12
  add    %r15d,%eax
  cmp    %eax,0x10(%rsp)
  jge    L8
L116:
  movslq 0x10(%rsp),%r13
  mov    0x18(%rsp),%rax
  mov    0x8(%rsp),%rbx
  mov    (%rax,%r13,8),%rax
  mov    (%rax,%rbx,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  movslq %ebx,%rax
  mov    %rax,0x8(%rsp)
  jmp    L77
```

assistant: ```c
int minDistance0(char *s1, char *s2) {
  int len1 = strlen(s1), len2 = strlen(s2);
  int **mins = (int **)malloc(sizeof(int *) * (len1 + 1));
  for (int i = 0; i <= len1; i++) {
    mins[i] = (int *)malloc(sizeof(int) * (len2 + 1));
    memset(mins[i], 0, sizeof(int) * (len2 + 1));
  }
  for (int i = 0; i <= len1; i++)
    mins[i][0] = i;
  for (int i = 0; i <= len2; i++)
    mins[0][i] = i;
  for (int i = 1; i <= len1; i++)
    for (int j = 1; j <= len2; j++) {
      if (s1[i - 1] == s2[j - 1])
        mins[i][j] = mins[i - 1][j - 1];
      else
        mins[i][j] = min(mins[i - 1][j], mins[i][j - 1], mins[i - 1][j - 1]) + 1;
    }
  return mins[len1][len2];
}
```