user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x271000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x271028(%rsp)
  xor    %eax,%eax
  lea    0x138820(%rsp),%rdi
  mov    $0x138800,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x18(%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L27
  lea    0x1c(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L33
L98:
  add    $0xc80,%rsi
  add    $0x1,%ecx
  cmp    %edi,%ecx
  je     L163
L60:
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rax
  mov    %edi,%edx
  sub    %ecx,%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x4,%rdx
  add    %rax,%rdx
  mov    (%rsi),%rax
  add    0x138820(%rsp,%rdx,8),%rax
  cmp    %rax,(%r9)
  jle    L98
  mov    %rax,(%r9)
  jmp    L98
L163:
  mov    %edi,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  mov    -0xc80(%r11),%rax
  add    0x20(%rsp,%rdx,8),%rax
  mov    %rax,(%r11)
  add    %rax,(%r9)
  add    $0x1,%rbx
  add    $0x8,%r10
  add    $0x8,%r11
  add    $0x1,%edi
  cmp    %r13,%rbx
  je     L175
L8:
  mov    %r10,%r9
  mov    -0xc80(%r10),%rax
  mov    %rax,(%r10)
  cmp    $0x1,%ebp
  jle    L163
  lea    (%r10,%r12,1),%rsi
  mov    %ebx,%ecx
  jmp    L60
L175:
  add    $0x1,%ebp
  sub    $0xc80,%r12
  cmp    %r8d,%ebp
  je     L134
L177:
  mov    %r15,%r10
  sub    %r12,%r10
  mov    %r14,%r11
  sub    %r12,%r11
  mov    %ebp,%edi
  mov    $0x1,%ebx
  jmp    L8
L27:
  mov    0x271028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x271038,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L134:
  lea    -0x1(%r8),%eax
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x7,%rax
  lea    0x138820(%rsp,%rax,1),%rdx
  mov    (%rdx),%rsi
  lea    0x8(%rdx),%rax
  mov    0x4(%rsp),%ebx
  lea    -0x2(%rbx),%ecx
  lea    0x10(%rdx,%rcx,8),%rcx
L104:
  mov    (%rax),%rdx
  cmp    %rdx,%rsi
  cmovg  %rdx,%rsi
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L104
L71:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L27
L33:
  mov    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%r8d
  test   %r8d,%r8d
  jle    L139
  lea    0x20(%rsp),%rbp
  mov    $0x0,%ebx
L54:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x1c(%rsp),%r8d
  add    $0x8,%rbp
  cmp    %ebx,%r8d
  jg     L54
L139:
  mov    $0xfffffffffffff380,%r12
  mov    $0x1,%ebp
  cmp    $0x1,%r8d
  jle    L174
  lea    0x138820(%rsp),%r15
  lea    0x20(%rsp),%r14
  mov    %r8d,0x4(%rsp)
  lea    0x1(%r8),%r13d
  jmp    L177
L174:
  lea    -0x1(%r8),%eax
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x7,%rax
  mov    0x138820(%rsp,%rax,1),%rsi
  jmp    L71
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D8
type_infered: string
name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D15: %d

tool: D8: %lld


tool: D1: %lld

assistant: ```c
int main() {
  int t, n, i, j, k;
  long long tmp, a[400][400], p[400][400] = {};
  for (scanf("%d", &t); t--; printf("%lld\n", tmp)) {
    scanf("%d", &n);
    for (i = 0; i < n; ++i)
      scanf("%lld", *a + i);
    for (i = 1; i < n; ++i)
      for (j = 0; j < n; ++j) {
        p[i][j] = p[i - 1][j];
        for (k = 1; k < i; ++k) {
          tmp = p[k - 1][j] + p[i - k][(j + k) % n];
          if (tmp < p[i][j])
            p[i][j] = tmp;
        }
        p[i][j] += a[i][j] = a[i - 1][j] + a[0][(i + j) % n];
      }
    long long *m = p[n - 1];
    tmp = *m;
    for (i = 1; i < n; ++i)
      if (m[i] < tmp)
        tmp = m[i];
  }
  return 0;
}
```