ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<long_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%ecx
  mov    $0x1000,%edx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int long_read(int *cfd, char *buf, int current_length) {
  ssize_t length_read = recv(*cfd, buf + current_length, 4096, MSG_DONTWAIT);
  return length_read;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<long_read>:
  endbr64
  sub    $0x8,%rsp
  movslq %edx,%rdx
  add    %rdx,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x1000,%edx
  mov    (%rdi),%edi
  call   <recv@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int long_read(int *cfd, char *buf, int current_length) {
  ssize_t length_read = recv(*cfd, buf + current_length, 4096, MSG_DONTWAIT);
  return length_read;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<long_read>:
  endbr64
  mov    D4(%rip),%rax
  movslq %edx,%rdx
  mov    (%rdi),%edi
  add    %rdx,%rsi
  mov    $0x1000,%edx
  mov    (%rax),%ecx
  jmp    1050 <recv@plt>
```

assistant: ```c
int long_read(int *cfd, char *buf, int current_length) {
  ssize_t length_read = recv(*cfd, buf + current_length, 4096, MSG_DONTWAIT);
  return length_read;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<long_read>:
  endbr64
  mov    D0(%rip),%rax
  movslq %edx,%rdx
  mov    (%rdi),%edi
  add    %rdx,%rsi
  mov    $0x1000,%edx
  mov    (%rax),%ecx
  jmp    1050 <recv@plt>
```

assistant: ```c
int long_read(int *cfd, char *buf, int current_length) {
  ssize_t length_read = recv(*cfd, buf + current_length, 4096, MSG_DONTWAIT);
  return length_read;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_blanks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L10
L13:
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_blanks(char *s) {
  while (isblank(*s))
    s++;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip_blanks>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L5
L2:
  add    $0x1,%rbx
L5:
  movsbl (%rbx),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L2
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skip_blanks(char *s) {
  while (isblank(*s))
    s++;
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_blanks>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12
L11:
  movsbl (%r12),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L0
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_blanks(char *s) {
  while (isblank(*s))
    s++;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<skip_blanks>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%r12
L2:
  movsbl (%r12),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_blanks(char *s) {
  while (isblank(*s))
    s++;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L12:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L12
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int power(int x, int y) {
  int prod = 1;
  int i;
  for (i = 1; i <= y; ++i)
    prod = prod * x;
  return prod;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L7
  add    $0x1,%esi
  mov    $0x1,%eax
  mov    $0x1,%edx
L28:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L28
L6:
  mov    %edx,%eax
  ret
L7:
  mov    $0x1,%edx
  jmp    L6
```

assistant: ```c
int power(int x, int y) {
  int prod = 1;
  int i;
  for (i = 1; i <= y; ++i)
    prod = prod * x;
  return prod;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L1
  add    $0x1,%esi
  mov    $0x1,%eax
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L0
  mov    %r8d,%eax
  ret
  nop
L1:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int power(int x, int y) {
  int prod = 1;
  int i;
  for (i = 1; i <= y; ++i)
    prod = prod * x;
  return prod;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L6
  add    $0x1,%esi
  mov    $0x1,%eax
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L3:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L3
  mov    %r8d,%eax
  ret
  nop
L6:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int power(int x, int y) {
  int prod = 1;
  int i;
  for (i = 1; i <= y; ++i)
    prod = prod * x;
  return prod;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Vec_StrSortCompare1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L4
  mov    $0xffffffff,%eax
  jmp    L27
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L25
  mov    $0x1,%eax
  jmp    L27
L25:
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int Vec_StrSortCompare1(char *pp1, char *pp2) {
  if (*pp1 < *pp2)
    return -1;
  if (*pp1 > *pp2)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Vec_StrSortCompare1>:
  endbr64
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dl,%cl
  jl     L1
  setg   %al
  movzbl %al,%eax
L1:
  ret
```

assistant: ```c
int Vec_StrSortCompare1(char *pp1, char *pp2) {
  if (*pp1 < *pp2)
    return -1;
  if (*pp1 > *pp2)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Vec_StrSortCompare1>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int Vec_StrSortCompare1(char *pp1, char *pp2) {
  if (*pp1 < *pp2)
    return -1;
  if (*pp1 > *pp2)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Vec_StrSortCompare1>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int Vec_StrSortCompare1(char *pp1, char *pp2) {
  if (*pp1 < *pp2)
    return -1;
  if (*pp1 > *pp2)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<list_pkgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    $0x75300,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x60(%rbp),%rax
  movl   $0x0,(%rax)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x58(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x100000,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x58(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L22
L24:
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L4
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L4:
  addq   $0x1,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x60(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    -0x30(%rbp),%rcx
  mov    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crc32@plt>
  mov    %rax,(%rbx)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x60(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x60(%rbp),%rax
  mov    %edx,(%rax)
L22:
  cmpq   $0x0,-0x30(%rbp)
  jne    L24
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long *list_pkgs(const char *path, const unsigned long initcrc, char *buf, int *out) {
  unsigned long *pkgs;
  ssize_t len;
  int fd;
  char *curr, *next;
  pkgs = malloc(sizeof(unsigned long) * (60000));
  *out = 0;
  fd = open(path, O_RDONLY);
  len = read(fd, buf, (1024 * 1024));
  close(fd);
  buf[len] = '\0';
  for (curr = buf; NULL != curr; ++*out) {
    next = strchr(curr + 1, ' ');
    if (NULL != next)
      next[0] = '\0';
    ++curr;
    pkgs[*out] = crc32(initcrc, (unsigned char *)curr, strlen(curr));
    curr = next;
  }
  return pkgs;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<list_pkgs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    $0x75300,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  movl   $0x0,(%r12)
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    %rbp,%rdi
  call   <open@plt>
  mov    %eax,%ebp
  mov    $0x100000,%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,%r13
  mov    %ebp,%edi
  call   <close@plt>
  movb   $0x0,(%rbx,%r13,1)
  test   %rbx,%rbx
  jne    L17
  jmp    L0
L27:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  movslq (%r12),%rax
  lea    (%r14,%rax,8),%r13
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <crc32@plt>
  mov    %rax,0x0(%r13)
  addl   $0x1,(%r12)
L17:
  lea    0x1(%rbx),%rbp
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L27
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  movslq (%r12),%rax
  lea    (%r14,%rax,8),%rbx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <crc32@plt>
  mov    %rax,(%rbx)
  addl   $0x1,(%r12)
L0:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long *list_pkgs(const char *path, const unsigned long initcrc, char *buf, int *out) {
  unsigned long *pkgs;
  ssize_t len;
  int fd;
  char *curr, *next;
  pkgs = malloc(sizeof(unsigned long) * (60000));
  *out = 0;
  fd = open(path, O_RDONLY);
  len = read(fd, buf, (1024 * 1024));
  close(fd);
  buf[len] = '\0';
  for (curr = buf; NULL != curr; ++*out) {
    next = strchr(curr + 1, ' ');
    if (NULL != next)
      next[0] = '\0';
    ++curr;
    pkgs[*out] = crc32(initcrc, (unsigned char *)curr, strlen(curr));
    curr = next;
  }
  return pkgs;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<list_pkgs>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x75300,%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  movl   $0x0,(%r12)
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    $0x100000,%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <read@plt>
  mov    %ebp,%edi
  mov    %rax,%r15
  call   <close@plt>
  movb   $0x0,(%rbx,%r15,1)
  test   %rbx,%rbx
  je     L1
  nopl   0x0(%rax)
L20:
  lea    0x1(%rbx),%rbp
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L26
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %eax,%edx
  movslq (%r12),%rax
  lea    0x0(%r13,%rax,8),%r15
  call   <crc32@plt>
  mov    %rax,(%r15)
  addl   $0x1,(%r12)
  jmp    L20
  nopl   0x0(%rax)
L26:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %eax,%edx
  movslq (%r12),%rax
  lea    0x0(%r13,%rax,8),%rbx
  call   <crc32@plt>
  mov    %rax,(%rbx)
  addl   $0x1,(%r12)
L1:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long *list_pkgs(const char *path, const unsigned long initcrc, char *buf, int *out) {
  unsigned long *pkgs;
  ssize_t len;
  int fd;
  char *curr, *next;
  pkgs = malloc(sizeof(unsigned long) * (60000));
  *out = 0;
  fd = open(path, O_RDONLY);
  len = read(fd, buf, (1024 * 1024));
  close(fd);
  buf[len] = '\0';
  for (curr = buf; NULL != curr; ++*out) {
    next = strchr(curr + 1, ' ');
    if (NULL != next)
      next[0] = '\0';
    ++curr;
    pkgs[*out] = crc32(initcrc, (unsigned char *)curr, strlen(curr));
    curr = next;
  }
  return pkgs;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<list_pkgs>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x75300,%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  movl   $0x0,(%r12)
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    $0x100000,%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <read@plt>
  mov    %ebp,%edi
  mov    %rax,%r15
  call   <close@plt>
  movb   $0x0,(%rbx,%r15,1)
  test   %rbx,%rbx
  je     L9
  nopl   0x0(%rax)
L11:
  lea    0x1(%rbx),%rbp
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %eax,%edx
  movslq (%r12),%rax
  lea    0x0(%r13,%rax,8),%r15
  call   <crc32@plt>
  mov    %rax,(%r15)
  addl   $0x1,(%r12)
  jmp    L11
  nopl   0x0(%rax)
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %eax,%edx
  movslq (%r12),%rax
  lea    0x0(%r13,%rax,8),%rbx
  call   <crc32@plt>
  mov    %rax,(%rbx)
  addl   $0x1,(%r12)
L9:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long *list_pkgs(const char *path, const unsigned long initcrc, char *buf, int *out) {
  unsigned long *pkgs;
  ssize_t len;
  int fd;
  char *curr, *next;
  pkgs = malloc(sizeof(unsigned long) * (60000));
  *out = 0;
  fd = open(path, O_RDONLY);
  len = read(fd, buf, (1024 * 1024));
  close(fd);
  buf[len] = '\0';
  for (curr = buf; NULL != curr; ++*out) {
    next = strchr(curr + 1, ' ');
    if (NULL != next)
      next[0] = '\0';
    ++curr;
    pkgs[*out] = crc32(initcrc, (unsigned char *)curr, strlen(curr));
    curr = next;
  }
  return pkgs;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hashLen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L53
L40:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L47
  addl   $0x1,-0x8(%rbp)
  jmp    L43
L47:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L43
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L74
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L23
L43:
  addl   $0x1,-0x4(%rbp)
L53:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  jmp    L23
L74:
  nop
L23:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int hashLen(const char *s) {
  int len = 0;
  int idx = 0;
  while (s[idx]) {
    if (isxdigit(s[idx]))
      ++len;
    else if (isblank(s[idx]))
      ;
    else if (isspace(s[idx]))
      break;
    else {
      len = -1;
      break;
    }
    ++idx;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashLen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L6
  mov    $0x0,%ebp
  jmp    L31
L21:
  movsbl (%rbx),%edi
  call   <isblank@plt>
  test   %rax,%rax
  je     L12
L46:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L38
L31:
  movsbl %dil,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L21
  add    $0x1,%ebp
  jmp    L46
L12:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmove  %eax,%ebp
L38:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0x0,%ebp
  jmp    L38
```

assistant: ```c
int hashLen(const char *s) {
  int len = 0;
  int idx = 0;
  while (s[idx]) {
    if (isxdigit(s[idx]))
      ++len;
    else if (isblank(s[idx]))
      ;
    else if (isspace(s[idx]))
      break;
    else {
      len = -1;
      break;
    }
    ++idx;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hashLen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L33
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L32:
  add    $0x1,%r12d
L40:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L43
L33:
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L32
  movsbl (%rbx),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L40
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmove  %eax,%r12d
L43:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int hashLen(const char *s) {
  int len = 0;
  int idx = 0;
  while (s[idx]) {
    if (isxdigit(s[idx]))
      ++len;
    else if (isblank(s[idx]))
      ;
    else if (isspace(s[idx]))
      break;
    else {
      len = -1;
      break;
    }
    ++idx;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hashLen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L48
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x1,%r12d
L43:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L0
L48:
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L45
  movsbl (%rbx),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L43
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmove  %eax,%r12d
L0:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int hashLen(const char *s) {
  int len = 0;
  int idx = 0;
  while (s[idx]) {
    if (isxdigit(s[idx]))
      ++len;
    else if (isblank(s[idx]))
      ;
    else if (isspace(s[idx]))
      break;
    else {
      len = -1;
      break;
    }
    ++idx;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<help_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <pit_version@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: D8: No kidding :-)

assistant: ```c
void help_version() {
  puts("No kidding :-)");
  pit_version();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<help_version>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <pit_version@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: No kidding :-)

assistant: ```c
void help_version() {
  puts("No kidding :-)");
  pit_version();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<help_version>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <pit_version@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: No kidding :-)

assistant: ```c
void help_version() {
  puts("No kidding :-)");
  pit_version();
}
```
user: What is the c source code of the assembly code below:

```asm
<help_version>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <pit_version@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: No kidding :-)

assistant: ```c
void help_version() {
  puts("No kidding :-)");
  pit_version();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ISRMemManage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L0:
  jmp    L0
```

assistant: ```c
void ISRMemManage(void) {
  while (1)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ISRMemManage>:
  endbr64
L8:
  jmp    L8
```

assistant: ```c
void ISRMemManage(void) {
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ISRMemManage>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
void ISRMemManage(void) {
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ISRMemManage>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
void ISRMemManage(void) {
  while (1)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1ac(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1a0(%rbp)
  movl   $0x1,-0x19c(%rbp)
  mov    -0x1ac(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1ac(%rbp)
  movl   $0x2,-0x1a8(%rbp)
  jmp    L3
L31:
  mov    -0x1a8(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1a8(%rbp),%eax
  sub    $0x2,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a8(%rbp)
L3:
  mov    -0x1ac(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jl     L31
  movl   $0x0,-0x1a4(%rbp)
  jmp    L14
L44:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1a4(%rbp)
L14:
  mov    -0x1ac(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L44
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D0: %d

tool: D2: %d 

assistant: ```c
int main() {
  int fib[100];
  int n;
  scanf("%d", &n);
  fib[0] = 0;
  fib[1] = 1;
  n--;
  for (int i = 2; i < n; i++)
    fib[i] = fib[i - 1] + fib[i - 2];
  for (int i = 0; i < n; i++)
    printf("%d ", fib[i]);
}
```