ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<itoa>:
  endbr64
  mov    %edi,%r8d
  test   %edi,%edi
  js     L18
  add    $0x1,%rsi
  mov    %edi,%edx
L24:
  mov    %edx,%edi
L40:
  mov    %rsi,%rcx
  add    $0x1,%rsi
  mov    %edi,%r9d
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edi
  cmp    $0x9,%r9d
  jg     L40
  movb   $0x0,(%rcx)
L29:
  sub    $0x1,%rcx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  mov    %edx,%esi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%rcx)
  mov    %edx,%esi
  mov    %eax,%edx
  cmp    $0x9,%esi
  jg     L29
  test   %r8d,%r8d
  js     L23
L22:
  ret
L18:
  add    $0x2,%rsi
  mov    %edi,%edx
  neg    %edx
  jmp    L24
L23:
  movb   $0x2d,-0x1(%rcx)
  jmp    L22
```

assistant: ```c
void itoa(int number, char *buf) {
  buf++;
  int negative = number < 0;
  if (negative) {
    buf++;
    number = -number;
  }
  int shifter = number;
  do {
    buf++;
    shifter /= 10;
  } while (shifter > 0);
  *--buf = '\0';
  do {
    *--buf = '0' + (number % 10);
    number /= 10;
  } while (number > 0);
  if (negative)
    *--buf = '-';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<itoa>:
  endbr64
  mov    %edi,%r8d
  test   %edi,%edi
  js     L8
  add    $0x1,%rsi
  mov    %edi,%ecx
L40:
  mov    %ecx,%eax
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L12:
  mov    %eax,%eax
  mov    %rsi,%rdx
  lea    0x1(%rsi),%rsi
  mov    %rax,%rdi
  imul   %r9,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  jg     L12
  movb   $0x0,(%rdx)
  mov    $0xcccccccd,%r9d
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %ecx,%eax
  mov    %ecx,%esi
  sub    $0x1,%rdx
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%rdx)
  mov    %ecx,%esi
  mov    %eax,%ecx
  cmp    $0x9,%esi
  jg     L46
  test   %r8d,%r8d
  js     L3
  ret
  nopl   0x0(%rax)
L3:
  movb   $0x2d,-0x1(%rdx)
  ret
  nopl   (%rax)
L8:
  mov    %edi,%ecx
  add    $0x2,%rsi
  neg    %ecx
  jmp    L40
```

assistant: ```c
void itoa(int number, char *buf) {
  buf++;
  int negative = number < 0;
  if (negative) {
    buf++;
    number = -number;
  }
  int shifter = number;
  do {
    buf++;
    shifter /= 10;
  } while (shifter > 0);
  *--buf = '\0';
  do {
    *--buf = '0' + (number % 10);
    number /= 10;
  } while (number > 0);
  if (negative)
    *--buf = '-';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<itoa>:
  endbr64
  mov    %edi,%r8d
  test   %edi,%edi
  js     L26
  add    $0x1,%rsi
  mov    %edi,%ecx
L20:
  mov    %ecx,%eax
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L40:
  mov    %eax,%eax
  mov    %rsi,%rdx
  lea    0x1(%rsi),%rsi
  mov    %rax,%rdi
  imul   %r9,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  jg     L40
  movb   $0x0,(%rdx)
  mov    $0xcccccccd,%r9d
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %ecx,%eax
  mov    %ecx,%esi
  sub    $0x1,%rdx
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%rdx)
  mov    %ecx,%esi
  mov    %eax,%ecx
  cmp    $0x9,%esi
  jg     L11
  test   %r8d,%r8d
  js     L15
  ret
  nopl   0x0(%rax)
L15:
  movb   $0x2d,-0x1(%rdx)
  ret
  nopl   (%rax)
L26:
  mov    %edi,%ecx
  add    $0x2,%rsi
  neg    %ecx
  jmp    L20
```

assistant: ```c
void itoa(int number, char *buf) {
  buf++;
  int negative = number < 0;
  if (negative) {
    buf++;
    number = -number;
  }
  int shifter = number;
  do {
    buf++;
    shifter /= 10;
  } while (shifter > 0);
  *--buf = '\0';
  do {
    *--buf = '0' + (number % 10);
    number /= 10;
  } while (number > 0);
  if (negative)
    *--buf = '-';
}
```
user: Translate the below assembly code into C programming language:

```asm
<pthread_yield>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <sched_yield@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pthread_yield(void) {
  sched_yield();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pthread_yield>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sched_yield@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pthread_yield(void) {
  sched_yield();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pthread_yield>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sched_yield@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pthread_yield(void) {
  sched_yield();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pthread_yield>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sched_yield@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pthread_yield(void) {
  sched_yield();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<k2_random_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int k2_random_int(int min, int max_inclusive) {
  int range = max_inclusive - min + 1;
  int val = rand() % range;
  return val + min;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<k2_random_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  sub    %ebp,%ebx
  lea    0x1(%rbx),%esi
  cltd
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int k2_random_int(int min, int max_inclusive) {
  int range = max_inclusive - min + 1;
  int val = rand() % range;
  return val + min;
}
```
user: Translate the below assembly code into C programming language:

```asm
<k2_random_int>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    %ebp,%ebx
  sub    $0x8,%rsp
  call   <rand@plt>
  lea    0x1(%rbx),%esi
  add    $0x8,%rsp
  cltd
  pop    %rbx
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int k2_random_int(int min, int max_inclusive) {
  int range = max_inclusive - min + 1;
  int val = rand() % range;
  return val + min;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<k2_random_int>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    %ebp,%ebx
  sub    $0x8,%rsp
  call   <rand@plt>
  lea    0x1(%rbx),%esi
  add    $0x8,%rsp
  cltd
  pop    %rbx
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int k2_random_int(int min, int max_inclusive) {
  int range = max_inclusive - min + 1;
  int val = rand() % range;
  return val + min;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<MatrixDouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x1,-0xc(%rbp)
  jmp    L5
L7:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **MatrixDouble(int M, int N) {
  double **out;
  int m;
  out = (double **)calloc(M, sizeof(double *));
  out[0] = (double *)calloc(M * N, sizeof(double));
  for (m = 1; m < M; m++)
    out[m] = out[m - 1] + N;
  return out;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MatrixDouble>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    %r12d,%edi
  imul   %ebx,%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  cmp    $0x1,%r12d
  jle    L16
  movslq %ebx,%rcx
  shl    $0x3,%rcx
  mov    %rbp,%rax
  lea    -0x1(%r12),%edx
  lea    0x0(%rbp,%rdx,8),%rsi
L17:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L17
L16:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double **MatrixDouble(int M, int N) {
  double **out;
  int m;
  out = (double **)calloc(M, sizeof(double *));
  out[0] = (double *)calloc(M * N, sizeof(double));
  for (m = 1; m < M; m++)
    out[m] = out[m - 1] + N;
  return out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MatrixDouble>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  imul   %ebx,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,(%r12)
  cmp    $0x1,%ebp
  jle    L2
  movslq %ebx,%rcx
  lea    -0x1(%rbp),%esi
  lea    0x8(%r12),%rdx
  shl    $0x3,%rcx
  lea    (%r12,%rsi,8),%rsi
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    $0x8,%rdx
L24:
  add    %rcx,%rax
  mov    %rax,(%rdx)
  cmp    %rsi,%rdx
  jne    L22
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double **MatrixDouble(int M, int N) {
  double **out;
  int m;
  out = (double **)calloc(M, sizeof(double *));
  out[0] = (double *)calloc(M * N, sizeof(double));
  for (m = 1; m < M; m++)
    out[m] = out[m - 1] + N;
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<MatrixDouble>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  imul   %ebx,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,(%r12)
  cmp    $0x1,%ebp
  jle    L2
  movslq %ebx,%rcx
  lea    -0x2(%rbp),%esi
  lea    0x8(%r12),%rdx
  shl    $0x3,%rcx
  lea    0x10(%r12,%rsi,8),%rsi
  nopl   (%rax)
L7:
  add    %rcx,%rax
  add    $0x8,%rdx
  mov    %rax,-0x8(%rdx)
  cmp    %rsi,%rdx
  jne    L7
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double **MatrixDouble(int M, int N) {
  double **out;
  int m;
  out = (double **)calloc(M, sizeof(double *));
  out[0] = (double *)calloc(M * N, sizeof(double));
  for (m = 1; m < M; m++)
    out[m] = out[m - 1] + N;
  return out;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninitvar_strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_strrchr(const char *s, int c) {
  char *str;
  int character;
  (void)strrchr(str, c);
  (void)strrchr(s, character);
  (void)strrchr(s, c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uninitvar_strrchr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%edi
  call   <strrchr@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uninitvar_strrchr(const char *s, int c) {
  char *str;
  int character;
  (void)strrchr(str, c);
  (void)strrchr(s, character);
  (void)strrchr(s, c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninitvar_strrchr>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <strrchr@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <strrchr@plt>
```

assistant: ```c
void uninitvar_strrchr(const char *s, int c) {
  char *str;
  int character;
  (void)strrchr(str, c);
  (void)strrchr(s, character);
  (void)strrchr(s, c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uninitvar_strrchr>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <strrchr@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <strrchr@plt>
```

assistant: ```c
void uninitvar_strrchr(const char *s, int c) {
  char *str;
  int character;
  (void)strrchr(str, c);
  (void)strrchr(s, character);
  (void)strrchr(s, c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<unrom_access>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  cmpl   $0x7fff,-0x4(%rbp)
  jbe    L19
  cmpl   $0xffff,-0x4(%rbp)
  ja     L19
  movzbl -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <unrom_switchprg@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
void unrom_access(unsigned int address, unsigned char data) {
  if (address > 0x7fff && address < 0x10000)
    unrom_switchprg(data);
}
```
user: Translate the below assembly code into C programming language:

```asm
<unrom_access>:
  endbr64
  sub    $0x8000,%edi
  cmp    $0x7fff,%edi
  jbe    L0
  ret
L0:
  sub    $0x8,%rsp
  movzbl %sil,%edi
  call   <unrom_switchprg@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void unrom_access(unsigned int address, unsigned char data) {
  if (address > 0x7fff && address < 0x10000)
    unrom_switchprg(data);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unrom_access>:
  endbr64
  sub    $0x8000,%edi
  cmp    $0x7fff,%edi
  jbe    L9
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl %sil,%edi
  jmp    1050 <unrom_switchprg@plt>
```

assistant: ```c
void unrom_access(unsigned int address, unsigned char data) {
  if (address > 0x7fff && address < 0x10000)
    unrom_switchprg(data);
}
```
user: What is the c source code of the assembly code below?

```asm
<unrom_access>:
  endbr64
  sub    $0x8000,%edi
  cmp    $0x7fff,%edi
  jbe    L2
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl %sil,%edi
  jmp    1050 <unrom_switchprg@plt>
```

assistant: ```c
void unrom_access(unsigned int address, unsigned char data) {
  if (address > 0x7fff && address < 0x10000)
    unrom_switchprg(data);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isreg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
  movzbl (%rbx),%eax
  cmp    $0x72,%al
  jne    L28
  lea    0x1(%rbx),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L28
  lea    0x1(%rbx),%rax
  movzbl (%rax),%eax
  cmp    $0x34,%al
  jg     L28
  lea    0x2(%rbx),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  lea    0x1(%rbx),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  jmp    L48
L28:
  mov    $0xffffffff,%eax
L48:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
isreg(as) char *as;
{
  register char *s;
  s = as;
  if (s[0] == 'r' && s[1] >= '0' && s[1] <= '4' && s[2] == 0)
    return (s[1] - '0');
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isreg>:
  endbr64
  cmpb   $0x72,(%rdi)
  jne    L17
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x4,%dl
  ja     L12
  cmpb   $0x0,0x2(%rdi)
  jne    L27
  movsbl %al,%eax
  sub    $0x30,%eax
  ret
L17:
  mov    $0xffffffff,%eax
  ret
L12:
  mov    $0xffffffff,%eax
  ret
L27:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
isreg(as) char *as;
{
  register char *s;
  s = as;
  if (s[0] == 'r' && s[1] >= '0' && s[1] <= '4' && s[2] == 0)
    return (s[1] - '0');
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isreg>:
  endbr64
  cmpb   $0x72,(%rdi)
  jne    L0
  movzbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x4,%al
  ja     L0
  cmpb   $0x0,0x2(%rdi)
  jne    L0
  movsbl %al,%eax
  ret
  xchg   %ax,%ax
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
isreg(as) char *as;
{
  register char *s;
  s = as;
  if (s[0] == 'r' && s[1] >= '0' && s[1] <= '4' && s[2] == 0)
    return (s[1] - '0');
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isreg>:
  endbr64
  cmpb   $0x72,(%rdi)
  jne    L8
  movzbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x4,%al
  ja     L8
  cmpb   $0x0,0x2(%rdi)
  jne    L8
  movsbl %al,%eax
  ret
  xchg   %ax,%ax
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
isreg(as) char *as;
{
  register char *s;
  s = as;
  if (s[0] == 'r' && s[1] >= '0' && s[1] <= '4' && s[2] == 0)
    return (s[1] - '0');
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <gen_disk@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gen_disk(-1, 1, NULL, 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <gen_disk@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gen_disk(-1, 1, NULL, 1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <gen_disk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gen_disk(-1, 1, NULL, 1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <gen_disk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gen_disk(-1, 1, NULL, 1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L3
L19:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L3:
  cmpq   $0x0,-0x18(%rbp)
  jne    L19
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  while (n > 0)
    ((char *)s)[n--] = c;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L3
L2:
  sub    $0x1,%rdx
  mov    %sil,0x1(%rax,%rdx,1)
  jne    L2
L3:
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  while (n > 0)
    ((char *)s)[n--] = c;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memset>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdx,%rdx
  je     L3
  movsbl %sil,%esi
  lea    0x1(%rdi),%rdi
  call   <memset@plt>
L3:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  while (n > 0)
    ((char *)s)[n--] = c;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdx,%rdx
  je     L3
  movsbl %sil,%esi
  lea    0x1(%rdi),%rdi
  call   <memset@plt>
L3:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  while (n > 0)
    ((char *)s)[n--] = c;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x170,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x15c(%rbp)
  movl   $0x0,-0x158(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x150(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x164(%rbp)
  jmp    L18
L64:
  movl   $0x0,-0x160(%rbp)
  movl   $0x0,-0x154(%rbp)
  jmp    L43
L48:
  mov    -0x164(%rbp),%eax
  cltq
  movzbl -0x150(%rbp,%rax,1),%edx
  mov    -0x160(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L27
  movl   $0x1,-0x154(%rbp)
L27:
  addl   $0x1,-0x160(%rbp)
L43:
  mov    -0x160(%rbp),%eax
  cmp    -0x158(%rbp),%eax
  jge    L53
  cmpl   $0x0,-0x154(%rbp)
  je     L48
L53:
  cmpl   $0x0,-0x154(%rbp)
  jne    L19
  mov    -0x164(%rbp),%eax
  cltq
  movzbl -0x150(%rbp,%rax,1),%edx
  mov    -0x15c(%rbp),%eax
  cltq
  mov    %dl,-0xe0(%rbp,%rax,1)
  mov    -0x164(%rbp),%eax
  cltq
  movzbl -0x150(%rbp,%rax,1),%edx
  mov    -0x158(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x15c(%rbp)
  addl   $0x1,-0x158(%rbp)
L19:
  addl   $0x1,-0x164(%rbp)
L18:
  lea    -0x150(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x164(%rbp)
  jl     L64
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D13: Rimovitore di lettere duplicate

tool: D1: 
Inserisci stringa: 

assistant: ```c
int main() {
  char input[100], output[100];
  char visti[100];
  int i, k, m = 0, n = 0;
  bool trovato;
  printf("Rimovitore di lettere duplicate");
  printf("\nInserisci stringa: ");
  gets(input);
  for (i = 0; i < strlen(input); i++) {
    for (k = 0, trovato = false; k < n && !trovato; k++) {
      if (input[i] == visti[k]) {
        trovato = true;
      }
    }
    if (!trovato) {
      output[m] = input[i];
      visti[n] = input[i];
      m++, n++;
    }
  }
  puts(output);
  return 0;
}
```