ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<GetZSCIIShift>:
  endbr64
  cmp    $0x20,%dil
  je     L9
  cmp    $0xa,%dil
  je     L2
  lea    -0x61(%rdi),%edx
  xor    %eax,%eax
  cmp    $0x19,%dl
  jbe    L11
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x19,%dil
  seta   %al
  add    $0x1,%eax
  ret
L2:
  mov    $0xffffffff,%eax
L11:
  ret
L9:
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int GetZSCIIShift(char ch) {
  if (ch == ' ')
    return -2;
  if (ch == '\n')
    return -1;
  if ('a' <= ch && ch <= 'z')
    return 0;
  if ('A' <= ch && ch <= 'Z')
    return 1;
  return 2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetZSCIIShift>:
  endbr64
  cmp    $0x20,%dil
  je     L12
  cmp    $0xa,%dil
  je     L11
  lea    -0x61(%rdi),%edx
  xor    %eax,%eax
  cmp    $0x19,%dl
  jbe    L8
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x19,%dil
  seta   %al
  add    $0x1,%eax
  ret
L11:
  mov    $0xffffffff,%eax
L8:
  ret
L12:
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int GetZSCIIShift(char ch) {
  if (ch == ' ')
    return -2;
  if (ch == '\n')
    return -1;
  if ('a' <= ch && ch <= 'z')
    return 0;
  if ('A' <= ch && ch <= 'Z')
    return 1;
  return 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<emit_cdq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <assem_debug@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: cdq


assistant: ```c
void emit_cdq() {
  assem_debug("cdq\n");
  assert(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<emit_cdq>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <assem_debug@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string

tool: D3: cdq


assistant: ```c
void emit_cdq() {
  assem_debug("cdq\n");
  assert(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<emit_cdq>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <assem_debug@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: cdq


assistant: ```c
void emit_cdq() {
  assem_debug("cdq\n");
  assert(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<emit_cdq>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <assem_debug@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: cdq


assistant: ```c
void emit_cdq() {
  assem_debug("cdq\n");
  assert(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quaternion_identity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  D1(%rip),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: byte[4]

tool: {"D1": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void quaternion_identity(float out[4]) {
  out[0] = 0.0f;
  out[1] = 0.0f;
  out[2] = 0.0f;
  out[3] = 1.0f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quaternion_identity>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x0,0x4(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0x3f800000,0xc(%rdi)
  ret
```

assistant: ```c
void quaternion_identity(float out[4]) {
  out[0] = 0.0f;
  out[1] = 0.0f;
  out[2] = 0.0f;
  out[3] = 1.0f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quaternion_identity>:
  endbr64
  movabs $0x3f80000000000000,%rax
  movq   $0x0,(%rdi)
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void quaternion_identity(float out[4]) {
  out[0] = 0.0f;
  out[1] = 0.0f;
  out[2] = 0.0f;
  out[3] = 1.0f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<quaternion_identity>:
  endbr64
  movaps D5(%rip),%xmm0
  movups %xmm0,(%rdi)
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f]}

assistant: ```c
void quaternion_identity(float out[4]) {
  out[0] = 0.0f;
  out[1] = 0.0f;
  out[2] = 0.0f;
  out[3] = 1.0f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sedb_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L51
L92:
  addq   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L92
  jmp    L100
L44:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L95
  movl   $0x0,-0xc(%rbp)
  jmp    L100
L95:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x2f,%eax
  cmp    $0x2e,%eax
  seta   %dl
  test   %dl,%dl
  jne    L13
  movabs $0x600000000801,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L13
  addq   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L100
L13:
  nop
L100:
  cmpl   $0x0,-0xc(%rbp)
  jne    L44
  jmp    L47
L84:
  addq   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L84
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *sedb_basename(char *path) {
  char *result = path;
  int again = 1;
  while (*result)
    result++;
  while (again) {
    result--;
    if (result == path) {
      again = 0;
    } else {
      switch (*result) {
      case '\\':
      case '/':
      case ':':
      case ']':
        result++;
        again = 0;
        break;
      default:
        break;
      }
    }
  }
  while (*result == ' ')
    result++;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sedb_basename>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    %rdi,%rax
L12:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L12
L6:
  movabs $0x600000000801,%rsi
L45:
  mov    %rax,%rcx
  sub    $0x1,%rax
  cmp    %rax,%rdi
  je     L64
  movzbl (%rax),%edx
  sub    $0x2f,%edx
  cmp    $0x2e,%dl
  ja     L45
  bt     %rdx,%rsi
  jae    L45
L17:
  cmpb   $0x20,(%rcx)
  jne    L89
L15:
  add    $0x1,%rcx
  cmpb   $0x20,(%rcx)
  je     L15
L89:
  mov    %rcx,%rax
  ret
L1:
  mov    %rdi,%rax
  jmp    L6
L64:
  mov    %rax,%rcx
  jmp    L17
```

assistant: ```c
char *sedb_basename(char *path) {
  char *result = path;
  int again = 1;
  while (*result)
    result++;
  while (again) {
    result--;
    if (result == path) {
      again = 0;
    } else {
      switch (*result) {
      case '\\':
      case '/':
      case ':':
      case ']':
        result++;
        again = 0;
        break;
      default:
        break;
      }
    }
  }
  while (*result == ' ')
    result++;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sedb_basename>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L44
  nopl   0x0(%rax)
L63:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L63
L44:
  movabs $0x600000000801,%rcx
L42:
  mov    %rax,%r8
  sub    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %rax,%rdi
  je     L56
L30:
  sub    $0x2f,%edx
  cmp    $0x2e,%dl
  ja     L42
  bt     %rdx,%rcx
  jb     L71
  mov    %rax,%r8
  sub    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %rax,%rdi
  jne    L30
L56:
  mov    %rdi,%r8
  cmpb   $0x20,(%r8)
  jne    L70
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%r8
L71:
  cmpb   $0x20,(%r8)
  je     L3
L70:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *sedb_basename(char *path) {
  char *result = path;
  int again = 1;
  while (*result)
    result++;
  while (again) {
    result--;
    if (result == path) {
      again = 0;
    } else {
      switch (*result) {
      case '\\':
      case '/':
      case ':':
      case ']':
        result++;
        again = 0;
        break;
      default:
        break;
      }
    }
  }
  while (*result == ' ')
    result++;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sedb_basename>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L54
  mov    %rdi,%rcx
  xchg   %ax,%ax
L41:
  add    $0x1,%rcx
  mov    %eax,%edx
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L41
L77:
  movabs $0x600000000801,%rsi
  jmp    L86
  nopl   0x0(%rax)
L24:
  movzbl -0x1(%rax),%edx
  mov    %rax,%rcx
L86:
  lea    -0x1(%rcx),%rax
  cmp    %rax,%rdi
  je     L69
  sub    $0x2f,%edx
  cmp    $0x2e,%dl
  ja     L24
  bt     %rdx,%rsi
  jae    L24
  movzbl (%rcx),%edx
  mov    %rcx,%rax
L69:
  cmp    $0x20,%dl
  jne    L73
  nopl   0x0(%rax)
L33:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L33
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  movzbl -0x1(%rdi),%edx
  mov    %rdi,%rcx
  jmp    L77
  nopl   0x0(%rax)
L73:
  ret
```

assistant: ```c
char *sedb_basename(char *path) {
  char *result = path;
  int again = 1;
  while (*result)
    result++;
  while (again) {
    result--;
    if (result == path) {
      again = 0;
    } else {
      switch (*result) {
      case '\\':
      case '/':
      case ':':
      case ']':
        result++;
        again = 0;
        break;
      default:
        break;
      }
    }
  }
  while (*result == ' ')
    result++;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<parameter2double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <cdoAbort@plt>
L4:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: Float parameter >%s< contains invalid character at position %d!

assistant: ```c
double parameter2double(const char *string) {
  char *endptr = NULL;
  double fval = strtod(string, &endptr);
  if (*endptr != 0)
    cdoAbort("Float parameter >%s< contains invalid character at position %d!", string, (int)(endptr - string + 1));
  return (fval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parameter2double>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  call   <strtod@plt>
  movq   %xmm0,%rbp
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L28
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  movq   %rbp,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  sub    %rbx,%rdx
  add    $0x1,%edx
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  call   <cdoAbort@plt>
  jmp    L24
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: Float parameter >%s< contains invalid character at position %d!

assistant: ```c
double parameter2double(const char *string) {
  char *endptr = NULL;
  double fval = strtod(string, &endptr);
  if (*endptr != 0)
    cdoAbort("Float parameter >%s< contains invalid character at position %d!", string, (int)(endptr - string + 1));
  return (fval);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parameter2double>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  call   <strtod@plt>
  mov    0x10(%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L5
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  pop    %rbp
  ret
  nop
L5:
  sub    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%edx
  call   <cdoAbort@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L13
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: Float parameter >%s< contains invalid character at position %d!

assistant: ```c
double parameter2double(const char *string) {
  char *endptr = NULL;
  double fval = strtod(string, &endptr);
  if (*endptr != 0)
    cdoAbort("Float parameter >%s< contains invalid character at position %d!", string, (int)(endptr - string + 1));
  return (fval);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parameter2double>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  call   <strtod@plt>
  mov    0x10(%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L15
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  pop    %rbp
  ret
  nop
L15:
  sub    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%edx
  call   <cdoAbort@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L16
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: Float parameter >%s< contains invalid character at position %d!

assistant: ```c
double parameter2double(const char *string) {
  char *endptr = NULL;
  double fval = strtod(string, &endptr);
  if (*endptr != 0)
    cdoAbort("Float parameter >%s< contains invalid character at position %d!", string, (int)(endptr - string + 1));
  return (fval);
}
```
user: What is the c source code of the assembly code below?

```asm
<usbdev_ioctl_me_o2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x14(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int usbdev_ioctl_me_o2(int fd, int test_num) {
  int cmd = 0;
  struct usbdevfs_ioctl wrapper;
  wrapper.ifno = 1;
  wrapper.ioctl_code = test_num;
  cmd = 1;
  return ioctl(fd, cmd, &wrapper);
}
```
user: What is the c source code of the assembly code below:

```asm
<usbdev_ioctl_me_o2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rdx
  mov    $0x1,%esi
  call   <ioctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int usbdev_ioctl_me_o2(int fd, int test_num) {
  int cmd = 0;
  struct usbdevfs_ioctl wrapper;
  wrapper.ifno = 1;
  wrapper.ioctl_code = test_num;
  cmd = 1;
  return ioctl(fd, cmd, &wrapper);
}
```
user: What is the c source code of the assembly code below?

```asm
<usbdev_ioctl_me_o2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %esi,0x4(%rsp)
  mov    $0x1,%esi
  movl   $0x1,(%rsp)
  call   <ioctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int usbdev_ioctl_me_o2(int fd, int test_num) {
  int cmd = 0;
  struct usbdevfs_ioctl wrapper;
  wrapper.ifno = 1;
  wrapper.ioctl_code = test_num;
  cmd = 1;
  return ioctl(fd, cmd, &wrapper);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usbdev_ioctl_me_o2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %esi,0x4(%rsp)
  mov    $0x1,%esi
  movl   $0x1,(%rsp)
  call   <ioctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int usbdev_ioctl_me_o2(int fd, int test_num) {
  int cmd = 0;
  struct usbdevfs_ioctl wrapper;
  wrapper.ifno = 1;
  wrapper.ioctl_code = test_num;
  cmd = 1;
  return ioctl(fd, cmd, &wrapper);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mulRL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  mov    -0x8(%rbp),%eax
  movzwl %ax,%edx
  mov    -0xc(%rbp),%eax
  movzwl %ax,%eax
  imul   %edx,%eax
  jmp    L2
L7:
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  imul   %edx,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int32_t mulRL(int left, uint32_t inRL, uint32_t vRL) {
  if (left) {
    return (int16_t)(inRL & 0xFFFF) * (int16_t)(vRL & 0xFFFF);
  } else {
    return (int16_t)(inRL >> 16) * (int16_t)(vRL >> 16);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mulRL>:
  endbr64
  test   %edi,%edi
  je     L9
  movzwl %si,%eax
  movzwl %dx,%edx
  imul   %edx,%eax
  ret
L9:
  sar    $0x10,%esi
  sar    $0x10,%edx
  mov    %esi,%eax
  imul   %edx,%eax
  ret
```

assistant: ```c
int32_t mulRL(int left, uint32_t inRL, uint32_t vRL) {
  if (left) {
    return (int16_t)(inRL & 0xFFFF) * (int16_t)(vRL & 0xFFFF);
  } else {
    return (int16_t)(inRL >> 16) * (int16_t)(vRL >> 16);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mulRL>:
  endbr64
  test   %edi,%edi
  je     L6
  movzwl %si,%eax
  movzwl %dx,%edx
  imul   %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  sar    $0x10,%esi
  sar    $0x10,%edx
  mov    %esi,%eax
  imul   %edx,%eax
  ret
```

assistant: ```c
int32_t mulRL(int left, uint32_t inRL, uint32_t vRL) {
  if (left) {
    return (int16_t)(inRL & 0xFFFF) * (int16_t)(vRL & 0xFFFF);
  } else {
    return (int16_t)(inRL >> 16) * (int16_t)(vRL >> 16);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mulRL>:
  endbr64
  test   %edi,%edi
  je     L1
  movzwl %si,%eax
  movzwl %dx,%edx
  imul   %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  sar    $0x10,%esi
  sar    $0x10,%edx
  mov    %esi,%eax
  imul   %edx,%eax
  ret
```

assistant: ```c
int32_t mulRL(int left, uint32_t inRL, uint32_t vRL) {
  if (left) {
    return (int16_t)(inRL & 0xFFFF) * (int16_t)(vRL & 0xFFFF);
  } else {
    return (int16_t)(inRL >> 16) * (int16_t)(vRL >> 16);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L17:
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L38:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L38
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *mult(double **a, double *x, int N) {
  int o = 0, m = 0;
  double *t = calloc(N, sizeof(double));
  for (o = 0; o < N; o++) {
    for (m = 0; m < N; ++m) {
      t[o] = a[o][m] * x[m] + t[o];
    }
  }
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mult>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    $0x8,%esi
  mov    %edx,%edi
  call   <calloc@plt>
  test   %r12d,%r12d
  jle    L10
  mov    %rbp,%rdi
  mov    %rax,%rcx
  mov    %r12d,%r8d
  shl    $0x3,%r8
  lea    (%r8,%rax,1),%r9
L24:
  mov    $0x0,%edx
L7:
  mov    (%rdi),%rsi
  movsd  (%rsi,%rdx,1),%xmm0
  mulsd  (%rbx,%rdx,1),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rdx
  cmp    %rdx,%r8
  jne    L7
  add    $0x8,%rdi
  add    $0x8,%rcx
  cmp    %r9,%rcx
  jne    L24
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *mult(double **a, double *x, int N) {
  int o = 0, m = 0;
  double *t = calloc(N, sizeof(double));
  for (o = 0; o < N; o++) {
    for (m = 0; m < N; ++m) {
      t[o] = a[o][m] * x[m] + t[o];
    }
  }
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mult>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %edx,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %edx,%ebx
  call   <calloc@plt>
  test   %ebx,%ebx
  jle    L12
  mov    %ebx,%edi
  mov    %r12,%r8
  mov    %rax,%rcx
  lea    (%rax,%rdi,8),%r9
  nopl   0x0(%rax)
L0:
  mov    (%r8),%rsi
  movsd  (%rcx),%xmm1
  xor    %edx,%edx
  nopl   0x0(%rax)
L3:
  movsd  (%rsi,%rdx,8),%xmm0
  mulsd  0x0(%rbp,%rdx,8),%xmm0
  add    $0x1,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rdx,%rdi
  jne    L3
  add    $0x8,%rcx
  add    $0x8,%r8
  cmp    %rcx,%r9
  jne    L0
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *mult(double **a, double *x, int N) {
  int o = 0, m = 0;
  double *t = calloc(N, sizeof(double));
  for (o = 0; o < N; o++) {
    for (m = 0; m < N; ++m) {
      t[o] = a[o][m] * x[m] + t[o];
    }
  }
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mult>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %edx,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %edx,%ebx
  call   <calloc@plt>
  test   %ebx,%ebx
  jle    L17
  mov    %ebx,%edi
  mov    %r12,%r8
  mov    %rax,%rcx
  lea    (%rax,%rdi,8),%r9
  nopl   0x0(%rax)
L21:
  mov    (%r8),%rsi
  movsd  (%rcx),%xmm1
  xor    %edx,%edx
  nopl   0x0(%rax)
L14:
  movsd  (%rsi,%rdx,8),%xmm0
  mulsd  0x0(%rbp,%rdx,8),%xmm0
  add    $0x1,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rdx,%rdi
  jne    L14
  add    $0x8,%rcx
  add    $0x8,%r8
  cmp    %rcx,%r9
  jne    L21
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *mult(double **a, double *x, int N) {
  int o = 0, m = 0;
  double *t = calloc(N, sizeof(double));
  for (o = 0; o < N; o++) {
    for (m = 0; m < N; ++m) {
      t[o] = a[o][m] * x[m] + t[o];
    }
  }
  return t;
}
```