ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<psycho_3_spl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa0(%rbp)
  jmp    L76
L58:
  mov    -0xa0(%rbp),%eax
  cltq
  movss  D16(%rip),%xmm0
  movss  %xmm0,-0x90(%rbp,%rax,4)
  addl   $0x1,-0xa0(%rbp)
L76:
  cmpl   $0x1f,-0xa0(%rbp)
  jle    L58
  movl   $0x1,-0xa0(%rbp)
  jmp    L83
L5:
  mov    -0xa0(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,-0x9c(%rbp)
  mov    -0x9c(%rbp),%eax
  cltq
  movss  -0x90(%rbp,%rax,4),%xmm1
  mov    -0xa0(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xb0(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L86
  mov    -0xa0(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xb0(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x9c(%rbp),%eax
  cltq
  movss  %xmm0,-0x90(%rbp,%rax,4)
L86:
  addl   $0x1,-0xa0(%rbp)
L83:
  cmpl   $0x200,-0xa0(%rbp)
  jle    L5
  movl   $0x0,-0xa0(%rbp)
  jmp    L13
L9:
  mov    -0xa0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xb8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  sub    $0xa,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x98(%rbp)
  mov    -0xa0(%rbp),%eax
  cltq
  movss  -0x90(%rbp,%rax,4),%xmm0
  cvtss2sd %xmm0,%xmm0
  comisd -0x98(%rbp),%xmm0
  jbe    L96
  mov    -0xa0(%rbp),%eax
  cltq
  movss  -0x90(%rbp,%rax,4),%xmm0
  cvtss2sd %xmm0,%xmm0
  jmp    L41
L96:
  movsd  -0x98(%rbp),%xmm0
L41:
  mov    -0xa0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xa0(%rbp)
L13:
  cmpl   $0x1f,-0xa0(%rbp)
  jle    L9
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D10
type_guessed: f64

tool: {"D16": [0x00,0x00,0x48,0xc3]}

tool: D10: 32768

assistant: ```c
void psycho_3_spl(double *Lsb, float *power, double *scale) {
  int i;
  float Xmax[32];
  for (i = 0; i < 32; i++) {
    Xmax[i] = -200.0;
  }
  for (i = 1; i < 513; i++) {
    int index = i >> 4;
    if (Xmax[index] < power[i])
      Xmax[index] = power[i];
  }
  for (i = 0; i < 32; i++) {
    double val = 20 * log10(scale[i] * 32768) - 10;
    Lsb[i] = ((Xmax[i]) > (val) ? (Xmax[i]) : (val));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<psycho_3_spl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x80(%rsp),%rdx
  movss  D12(%rip),%xmm0
L36:
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L36
  mov    $0x1,%edx
  jmp    L25
L9:
  cltq
  movss  %xmm0,(%rsp,%rax,4)
  add    $0x1,%rdx
  cmp    $0x201,%rdx
  je     L12
L25:
  mov    %edx,%eax
  sar    $0x4,%eax
  movss  (%rsi,%rdx,4),%xmm0
  movslq %eax,%rcx
  comiss (%rsp,%rcx,4),%xmm0
  ja     L9
  movss  (%rsp,%rcx,4),%xmm0
  jmp    L9
L12:
  mov    $0x0,%r12d
L64:
  movsd  D17(%rip),%xmm0
  mulsd  0x0(%rbp,%r12,8),%xmm0
  call   <log10@plt>
  lea    (%rax,%rax,4),%eax
  lea    -0xa(,%rax,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%rsp,%r12,4),%xmm1
  maxsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx,%r12,8)
  add    $0x1,%r12
  cmp    $0x20,%r12
  jne    L64
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D17
type_guessed: f64

tool: {"D12": [0x00,0x00,0x48,0xc3]}

tool: D17: 32768

assistant: ```c
void psycho_3_spl(double *Lsb, float *power, double *scale) {
  int i;
  float Xmax[32];
  for (i = 0; i < 32; i++) {
    Xmax[i] = -200.0;
  }
  for (i = 1; i < 513; i++) {
    int index = i >> 4;
    if (Xmax[index] < power[i])
      Xmax[index] = power[i];
  }
  for (i = 0; i < 32; i++) {
    double val = 20 * log10(scale[i] * 32768) - 10;
    Lsb[i] = ((Xmax[i]) > (val) ? (Xmax[i]) : (val));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<psycho_3_spl>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x98,%rsp
  movss  D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x80(%rsp),%rdx
  mov    %r12,%rax
L38:
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L38
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %eax,%edx
  movss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  sar    $0x4,%edx
  movslq %edx,%rdx
  maxss  (%rsp,%rdx,4),%xmm0
  movss  %xmm0,(%rsp,%rdx,4)
  cmp    $0x201,%rax
  jne    L0
  xor    %r13d,%r13d
  xchg   %ax,%ax
L34:
  movsd  D5(%rip),%xmm0
  mulsd  0x0(%rbp,%r13,8),%xmm0
  call   <log10@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    (%rax,%rax,4),%eax
  cvtss2sd (%r12,%r13,4),%xmm1
  lea    -0xa(,%rax,4),%eax
  cvtsi2sd %eax,%xmm0
  maxsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx,%r13,8)
  add    $0x1,%r13
  cmp    $0x20,%r13
  jne    L34
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: byte[4]
name: disassemble_data
arguments: data_label: D5
datatype: f64

tool: {"D4": [0x00,0x00,0x48,0xc3]}

tool: D5: 32768

assistant: ```c
void psycho_3_spl(double *Lsb, float *power, double *scale) {
  int i;
  float Xmax[32];
  for (i = 0; i < 32; i++) {
    Xmax[i] = -200.0;
  }
  for (i = 1; i < 513; i++) {
    int index = i >> 4;
    if (Xmax[index] < power[i])
      Xmax[index] = power[i];
  }
  for (i = 0; i < 32; i++) {
    double val = 20 * log10(scale[i] * 32768) - 10;
    Lsb[i] = ((Xmax[i]) > (val) ? (Xmax[i]) : (val));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<psycho_3_spl>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x98,%rsp
  movaps D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  nopl   (%rax)
L11:
  mov    %eax,%edx
  movss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  sar    $0x4,%edx
  movslq %edx,%rdx
  maxss  (%rsp,%rdx,4),%xmm0
  movss  %xmm0,(%rsp,%rdx,4)
  cmp    $0x201,%rax
  jne    L11
  xor    %r12d,%r12d
  mov    %rsp,%r13
  nopl   0x0(%rax)
L7:
  movsd  D19(%rip),%xmm0
  mulsd  0x0(%rbp,%r12,8),%xmm0
  call   <log10@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    (%rax,%rax,4),%eax
  cvtss2sd 0x0(%r13,%r12,4),%xmm1
  lea    -0xa(,%rax,4),%eax
  cvtsi2sd %eax,%xmm0
  maxsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx,%r12,8)
  add    $0x1,%r12
  cmp    $0x20,%r12
  jne    L7
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
datatype: byte[16]
name: retrieve_data
arguments: data_label: D19
datatype: f64

tool: {"D12": [0x00,0x00,0x48,0xc3,0x00,0x00,0x48,0xc3,0x00,0x00,0x48,0xc3,0x00,0x00,0x48,0xc3]}

tool: D19: 32768

assistant: ```c
void psycho_3_spl(double *Lsb, float *power, double *scale) {
  int i;
  float Xmax[32];
  for (i = 0; i < 32; i++) {
    Xmax[i] = -200.0;
  }
  for (i = 1; i < 513; i++) {
    int index = i >> 4;
    if (Xmax[index] < power[i])
      Xmax[index] = power[i];
  }
  for (i = 0; i < 32; i++) {
    double val = 20 * log10(scale[i] * 32768) - 10;
    Lsb[i] = ((Xmax[i]) > (val) ? (Xmax[i]) : (val));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<selinux_relabel_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void selinux_relabel_path(const char *path, const char *inside_path) {
  (void)path;
  (void)inside_path;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<selinux_relabel_path>:
  endbr64
  ret
```

assistant: ```c
void selinux_relabel_path(const char *path, const char *inside_path) {
  (void)path;
  (void)inside_path;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<selinux_relabel_path>:
  endbr64
  ret
```

assistant: ```c
void selinux_relabel_path(const char *path, const char *inside_path) {
  (void)path;
  (void)inside_path;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<selinux_relabel_path>:
  endbr64
  ret
```

assistant: ```c
void selinux_relabel_path(const char *path, const char *inside_path) {
  (void)path;
  (void)inside_path;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<start2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xc8,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: t2 %d


assistant: ```c
void start2() {
  int i = 200;
  while (1) {
    printf("t2 %d\n", i++);
    sleep(1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<start2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xc8,%esi
  lea    D1(%rip),%rbp
L4:
  lea    0x1(%rsi),%ebx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  jmp    L4
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: t2 %d


assistant: ```c
void start2() {
  int i = 200;
  while (1) {
    printf("t2 %d\n", i++);
    sleep(1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<start2>:
  endbr64
  push   %rbp
  mov    $0xc8,%esi
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  lea    0x1(%rsi),%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  jmp    L5
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D5: t2 %d


assistant: ```c
void start2() {
  int i = 200;
  while (1) {
    printf("t2 %d\n", i++);
    sleep(1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<start2>:
  endbr64
  push   %rbp
  mov    $0xc8,%esi
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  lea    0x1(%rsi),%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: t2 %d


assistant: ```c
void start2() {
  int i = 200;
  while (1) {
    printf("t2 %d\n", i++);
    sleep(1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wait_for_completion_interruptible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__wait_completion@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int wait_for_completion_interruptible(struct completion *work) {
  __wait_completion(work);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wait_for_completion_interruptible>:
  endbr64
  sub    $0x8,%rsp
  call   <__wait_completion@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wait_for_completion_interruptible(struct completion *work) {
  __wait_completion(work);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wait_for_completion_interruptible>:
  endbr64
  sub    $0x8,%rsp
  call   <__wait_completion@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wait_for_completion_interruptible(struct completion *work) {
  __wait_completion(work);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wait_for_completion_interruptible>:
  endbr64
  sub    $0x8,%rsp
  call   <__wait_completion@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wait_for_completion_interruptible(struct completion *work) {
  __wait_completion(work);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L3
L5:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  je     L3
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitcount(unsigned num) {
  int x = num;
  int cont;
  while (x != 0) {
    if (num != (x &= (x - 1)))
      ++cont;
  }
  return cont;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitcount>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L11
L4:
  lea    -0x1(%rax),%ecx
  and    %ecx,%eax
  cmp    %edi,%eax
  setne  %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  test   %eax,%eax
  jne    L4
L11:
  mov    %edx,%eax
  ret
```

assistant: ```c
int bitcount(unsigned num) {
  int x = num;
  int cont;
  while (x != 0) {
    if (num != (x &= (x - 1)))
      ++cont;
  }
  return cont;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitcount>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L8
  nopw   0x0(%rax,%rax,1)
L12:
  lea    -0x1(%rax),%edx
  and    %edx,%eax
  xor    %edx,%edx
  cmp    %edi,%eax
  setne  %dl
  add    %edx,%r8d
  test   %eax,%eax
  jne    L12
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitcount(unsigned num) {
  int x = num;
  int cont;
  while (x != 0) {
    if (num != (x &= (x - 1)))
      ++cont;
  }
  return cont;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitcount>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L13
  nopw   0x0(%rax,%rax,1)
L7:
  lea    -0x1(%rax),%edx
  and    %edx,%eax
  xor    %edx,%edx
  cmp    %eax,%edi
  setne  %dl
  add    %edx,%r8d
  test   %eax,%eax
  jne    L7
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitcount(unsigned num) {
  int x = num;
  int cont;
  while (x != 0) {
    if (num != (x &= (x - 1)))
      ++cont;
  }
  return cont;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D5
type: string

tool: D4: %c

tool: D5: %d

assistant: ```c
void main() {
  char xx;
  xx = getchar();
  printf("%c", xx);
  int d;
  scanf("%d", d);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D11: %c

tool: D6: %d

assistant: ```c
void main() {
  char xx;
  xx = getchar();
  printf("%c", xx);
  int d;
  scanf("%d", d);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D18(%rip),%rdi
  movsbl %al,%esi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <scanf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
data_type: string
name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D18: %c

tool: D3: %d

assistant: ```c
void main() {
  char xx;
  xx = getchar();
  printf("%c", xx);
  int d;
  scanf("%d", d);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D9(%rip),%rdi
  movsbl %al,%esi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D15(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <scanf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: string

tool: D9: %c

tool: D15: %d

assistant: ```c
void main() {
  char xx;
  xx = getchar();
  printf("%c", xx);
  int d;
  scanf("%d", d);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x40(%rbp),%eax
  test   %eax,%eax
  jns    L65
  mov    -0x40(%rbp),%eax
  neg    %eax
  mov    %eax,-0x40(%rbp)
  jmp    L65
L39:
  mov    -0x40(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x40(%rbp)
L65:
  mov    -0x40(%rbp),%eax
  test   %eax,%eax
  jg     L39
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L34
L50:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jle    L63
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x38(%rbp)
L63:
  addl   $0x1,-0x3c(%rbp)
L34:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L50
  cmpl   $0x0,-0x38(%rbp)
  jne    L68
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L68:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string
name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D27: %d

tool: D9: Cifrata %d se povtarq


tool: D7: nqma povtarqshti se cifri

assistant: ```c
int main() {
  int i;
  int digits[10] = {0};
  int number;
  scanf("%d", &number);
  if (number < 0) {
    number *= -1;
  }
  while (number > 0) {
    int helper = number % 10;
    digits[helper]++;
    number /= 10;
  }
  int repeat = 0;
  for (i = 0; i < 10; i++) {
    if (digits[i] > 1) {
      printf("Cifrata %d se povtarq\n", i);
      repeat = 1;
    }
  }
  if (!repeat) {
    printf("nqma povtarqshti se cifri\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  js     L81
  jle    L30
L86:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %edx,%eax
  mov    %esi,%edx
  cmp    $0x9,%eax
  jg     L86
  mov    %esi,0xc(%rsp)
L30:
  mov    $0x0,%ebx
  mov    $0x0,%eax
  lea    D20(%rip),%rbp
  jmp    L94
L81:
  neg    %edx
  jmp    L86
L8:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  je     L92
L94:
  mov    %ebx,%esi
  cmpl   $0x1,0x10(%rsp,%rbx,4)
  jle    L8
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L8
L92:
  test   %eax,%eax
  je     L43
L75:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L43:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L75
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D20
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D10: %d

tool: D20: Cifrata %d se povtarq


tool: D3: nqma povtarqshti se cifri

assistant: ```c
int main() {
  int i;
  int digits[10] = {0};
  int number;
  scanf("%d", &number);
  if (number < 0) {
    number *= -1;
  }
  while (number > 0) {
    int helper = number % 10;
    digits[helper]++;
    number /= 10;
  }
  int repeat = 0;
  for (i = 0; i < 10; i++) {
    if (digits[i] > 1) {
      printf("Cifrata %d se povtarq\n", i);
      repeat = 1;
    }
  }
  if (!repeat) {
    printf("nqma povtarqshti se cifri\n");
  }
}
```