user: 请从给定的汇编指令推导出C源代码：

```asm
<for_1pipe>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x20,%esi
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  test   %rax,%rax
  je     L24
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  lea    D16(%rip),%rdx
  test   %rax,%rax
  je     L17
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdx
L17:
  movq   %rbp,%xmm0
  movq   %rdx,%xmm1
  movq   $0x0,0x20(%rsp)
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,0x10(%rsp)
L64:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L66
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  lea    D16(%rip),%rdx
  test   %rax,%rax
  je     L78
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdx
L78:
  movq   %rbx,%xmm0
  movq   %rdx,%xmm2
  movq   $0x0,0x70(%rsp)
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x60(%rsp)
  call   <fork@plt>
  test   %eax,%eax
  jne    L86
L59:
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  call   <fork@plt>
  test   %eax,%eax
  je     L38
  xor    %edi,%edi
  call   <close@plt>
  mov    0x8(%rsp),%edi
  xor    %esi,%esi
  call   <dup2@plt>
  mov    0xc(%rsp),%edi
  call   <close@plt>
  mov    0x60(%rsp),%rdi
  lea    0x60(%rsp),%rsi
  mov    %r12,%rdx
  call   <execve@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L4:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    $0x1,%edi
  call   <close@plt>
  mov    0xc(%rsp),%edi
  mov    $0x1,%esi
  call   <dup2@plt>
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    0x10(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdx
  call   <execve@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L4
  nopl   0x0(%rax)
L66:
  mov    %rbx,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  call   <fork@plt>
  test   %eax,%eax
  je     L59
L86:
  lea    0x4(%rsp),%rsi
  xor    %edx,%edx
  mov    %eax,%edi
  call   <waitpid@plt>
  jmp    L4
  xchg   %ax,%ax
L24:
  mov    %rbp,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  jmp    L64
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_infered: string

tool: 

assistant: ```c
void for_1pipe(char *ip1, char *ip2, char *envp[]) {
  int pipefd[2];
  int pid1, pid2, stat;
  char *myargv[10];
  if (strstr(ip1, " ") != NULL) {
    char *a1 = {""}, *a2 = {""};
    char *tmp = strrchr(ip1, ' ');
    if (tmp != NULL) {
      *tmp = '\0';
      a1 = tmp + 1;
    }
    a2 = ip1;
    myargv[0] = a2;
    myargv[1] = a1;
    myargv[2] = NULL;
  } else {
    myargv[0] = ip1;
    myargv[1] = NULL;
  }
  char *argv2[10];
  if (strstr(ip2, " ") != NULL) {
    char *a3 = {""}, *a4 = {""};
    char *tmp = strrchr(ip2, ' ');
    if (tmp != NULL) {
      *tmp = '\0';
      a3 = tmp + 1;
    }
    a4 = ip2;
    argv2[0] = a4;
    argv2[1] = a3;
    argv2[2] = NULL;
  } else {
    argv2[0] = ip2;
    argv2[1] = NULL;
  }
  pid1 = fork();
  if (pid1 == 0) {
    pipe(pipefd);
    pid2 = fork();
    if (pid2 == 0) {
      close(1);
      dup2(pipefd[1], 1);
      close(pipefd[0]);
      execve(myargv[0], myargv, envp);
      exit(0);
    } else {
      close(0);
      dup2(pipefd[0], 0);
      close(pipefd[1]);
      execve(argv2[0], argv2, envp);
      exit(1);
    }
  } else {
    waitpid(pid1, &stat, 0);
    return;
  }
}
```