ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reg_tokens_advance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L11:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L11
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *reg_tokens_advance(char *ptr, char *colname, char *seps) {
  char *optr = colname;
  while (!strchr(seps, *ptr))
    *optr++ = *ptr++;
  *optr = '\0';
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reg_tokens_advance>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  jmp    L2
L6:
  add    $0x1,%rbx
  add    $0x1,%rbp
  movzbl -0x1(%rbx),%eax
  mov    %al,-0x1(%rbp)
L2:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L6
  movb   $0x0,0x0(%rbp)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *reg_tokens_advance(char *ptr, char *colname, char *seps) {
  char *optr = colname;
  while (!strchr(seps, *ptr))
    *optr++ = *ptr++;
  *optr = '\0';
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reg_tokens_advance>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  movsb  %ds:(%rsi),%es:(%rdi)
  mov    %rsi,%rbp
  mov    %rdi,%rbx
L0:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L3
  movb   $0x0,(%rbx)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *reg_tokens_advance(char *ptr, char *colname, char *seps) {
  char *optr = colname;
  while (!strchr(seps, *ptr))
    *optr++ = *ptr++;
  *optr = '\0';
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reg_tokens_advance>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  movsb  %ds:(%rsi),%es:(%rdi)
  mov    %rsi,%rbp
  mov    %rdi,%rbx
L12:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L16
  movb   $0x0,(%rbx)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *reg_tokens_advance(char *ptr, char *colname, char *seps) {
  char *optr = colname;
  while (!strchr(seps, *ptr))
    *optr++ = *ptr++;
  *optr = '\0';
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BSP_FreezeL1Dcache>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1840044,%eax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  orq    $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x1840044,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x1840044,%eax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  nopl   0xa
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BSP_FreezeL1Dcache(void) {
  unsigned long tmp;
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)(0x01840044));
    __v;
  });
  tmp |= 0x1;
  ({
    unsigned long __v = tmp;
    (*(volatile unsigned long *)(0x01840044) = (__v));
    __v;
  });
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)(0x01840044));
    __v;
  });
  asm("	NOP 10");
}
```
user: What is the c source code of the assembly code below:

```asm
<BSP_FreezeL1Dcache>:
  endbr64
  mov    0x1840044,%rax
  or     $0x1,%rax
  mov    %rax,0x1840044
  mov    0x1840044,%rax
  nopl   0xa
  ret
```

assistant: ```c
void BSP_FreezeL1Dcache(void) {
  unsigned long tmp;
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)(0x01840044));
    __v;
  });
  tmp |= 0x1;
  ({
    unsigned long __v = tmp;
    (*(volatile unsigned long *)(0x01840044) = (__v));
    __v;
  });
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)(0x01840044));
    __v;
  });
  asm("	NOP 10");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BSP_FreezeL1Dcache>:
  endbr64
  mov    0x1840044,%rax
  or     $0x1,%rax
  mov    %rax,0x1840044
  mov    0x1840044,%rax
  nopl   0xa
  ret
```

assistant: ```c
void BSP_FreezeL1Dcache(void) {
  unsigned long tmp;
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)(0x01840044));
    __v;
  });
  tmp |= 0x1;
  ({
    unsigned long __v = tmp;
    (*(volatile unsigned long *)(0x01840044) = (__v));
    __v;
  });
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)(0x01840044));
    __v;
  });
  asm("	NOP 10");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BSP_FreezeL1Dcache>:
  endbr64
  mov    0x1840044,%rax
  or     $0x1,%rax
  mov    %rax,0x1840044
  mov    0x1840044,%rax
  nopl   0xa
  ret
```

assistant: ```c
void BSP_FreezeL1Dcache(void) {
  unsigned long tmp;
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)(0x01840044));
    __v;
  });
  tmp |= 0x1;
  ({
    unsigned long __v = tmp;
    (*(volatile unsigned long *)(0x01840044) = (__v));
    __v;
  });
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)(0x01840044));
    __v;
  });
  asm("	NOP 10");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SSIIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x40008000,-0x18(%rbp)
  jne    L3
  mov    $0x17,%eax
  jmp    L8
L3:
  mov    $0x32,%eax
L8:
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <IntRegister@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void SSIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  unsigned long ulInt;
  ;
  ulInt = (ulBase == 0x40008000) ? 23 : 50;
  IntRegister(ulInt, pfnHandler);
  IntEnable(ulInt);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SSIIntRegister>:
  endbr64
  push   %rbx
  cmp    $0x40008000,%rdi
  mov    $0x17,%ebx
  mov    $0x32,%eax
  cmovne %rax,%rbx
  mov    %rbx,%rdi
  call   <IntRegister@plt>
  mov    %rbx,%rdi
  call   <IntEnable@plt>
  pop    %rbx
  ret
```

assistant: ```c
void SSIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  unsigned long ulInt;
  ;
  ulInt = (ulBase == 0x40008000) ? 23 : 50;
  IntRegister(ulInt, pfnHandler);
  IntEnable(ulInt);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SSIIntRegister>:
  endbr64
  push   %rbp
  cmp    $0x40008000,%rdi
  mov    $0x32,%eax
  mov    $0x17,%ebp
  cmovne %rax,%rbp
  mov    %rbp,%rdi
  call   <IntRegister@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <IntEnable@plt>
```

assistant: ```c
void SSIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  unsigned long ulInt;
  ;
  ulInt = (ulBase == 0x40008000) ? 23 : 50;
  IntRegister(ulInt, pfnHandler);
  IntEnable(ulInt);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SSIIntRegister>:
  endbr64
  push   %rbp
  cmp    $0x40008000,%rdi
  mov    $0x32,%eax
  mov    $0x17,%ebp
  cmovne %rax,%rbp
  mov    %rbp,%rdi
  call   <IntRegister@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <IntEnable@plt>
```

assistant: ```c
void SSIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  unsigned long ulInt;
  ;
  ulInt = (ulBase == 0x40008000) ? 23 : 50;
  IntRegister(ulInt, pfnHandler);
  IntEnable(ulInt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x5,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L31
  cmpl   $0x0,-0x8(%rbp)
  je     L31
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  test   %eax,%eax
  je     L31
  mov    $0x1,%eax
  jmp    L12
L31:
  mov    $0x0,%eax
L12:
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: %d

assistant: ```c
void main() {
  int x = 1, y = 0, z = 5;
  int a = x && y && z++;
  printf("%d", z);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: %d

assistant: ```c
void main() {
  int x = 1, y = 0, z = 5;
  int a = x && y && z++;
  printf("%d", z);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x5,%esi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %d

assistant: ```c
void main() {
  int x = 1, y = 0, z = 5;
  int a = x && y && z++;
  printf("%d", z);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x5,%esi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: %d

assistant: ```c
void main() {
  int x = 1, y = 0, z = 5;
  int a = x && y && z++;
  printf("%d", z);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test14>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x64,%edi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x64,%edx
  mov    $0x61,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  add    $0x63,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int test14(void) {
  char *p = alloca(100);
  size_t ret;
  memset(p, 'a', 100);
  p[100 - 1] = 0;
  ret = strlen(p);
  ;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test14>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x64,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    $0x64,%edx
  mov    $0x61,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x0,0x63(%rbx)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  mov    -0x8(%rbp),%rbx
  leave
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test14(void) {
  char *p = alloca(100);
  size_t ret;
  memset(p, 'a', 100);
  p[100 - 1] = 0;
  ret = strlen(p);
  ;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test14>:
  endbr64
  push   %rbp
  mov    $0x64,%edi
  mov    %rsp,%rbp
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x64,%edx
  mov    $0x61,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x0,0x63(%r12)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  mov    -0x8(%rbp),%r12
  leave
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test14(void) {
  char *p = alloca(100);
  size_t ret;
  memset(p, 'a', 100);
  p[100 - 1] = 0;
  ret = strlen(p);
  ;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test14>:
  endbr64
  push   %rbp
  mov    $0x64,%edi
  mov    %rsp,%rbp
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x64,%edx
  mov    $0x61,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x0,0x63(%r12)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  mov    -0x8(%rbp),%r12
  leave
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test14(void) {
  char *p = alloca(100);
  size_t ret;
  memset(p, 'a', 100);
  p[100 - 1] = 0;
  ret = strlen(p);
  ;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ipacl_do_request_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x38(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <getservbyname@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L36
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  jmp    L15
L36:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <getprotobyname@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  jmp    L15
L19:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  mov    %eax,%edi
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <ipacl_do_request@plt>
L15:
  leave
  ret
```

assistant: ```c
int ipacl_do_request_s(const int reqport, int *const restrict pfh, const char *const restrict ip, const char *const restrict protocol, const char *const restrict port) {
  struct servent *ps;
  struct protoent *pp;
  assert(reqport >= 0);
  assert(pfh != NULL);
  assert(ip != NULL);
  assert(protocol != NULL);
  assert(port != NULL);
  ps = getservbyname(port, protocol);
  if (ps == NULL)
    return EINVAL;
  pp = getprotobyname(protocol);
  if (pp == NULL)
    return EINVAL;
  return ipacl_do_request(reqport, pfh, ip, pp->p_proto, ntohs(ps->s_port));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipacl_do_request_s>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%rbx
  mov    %r8,%rbp
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  test   %r13,%r13
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r14,%r14
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <getservbyname@plt>
  test   %rax,%rax
  je     L39
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <getprotobyname@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    0x0(%rbp),%edi
  call   <ntohs@plt>
  mov    %eax,%r8d
  mov    (%rbx),%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <ipacl_do_request@plt>
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jmp    L27
L1:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jmp    L27
```

assistant: ```c
int ipacl_do_request_s(const int reqport, int *const restrict pfh, const char *const restrict ip, const char *const restrict protocol, const char *const restrict port) {
  struct servent *ps;
  struct protoent *pp;
  assert(reqport >= 0);
  assert(pfh != NULL);
  assert(ip != NULL);
  assert(protocol != NULL);
  assert(port != NULL);
  ps = getservbyname(port, protocol);
  if (ps == NULL)
    return EINVAL;
  pp = getprotobyname(protocol);
  if (pp == NULL)
    return EINVAL;
  return ipacl_do_request(reqport, pfh, ip, pp->p_proto, ntohs(ps->s_port));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ipacl_do_request_s>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  not    %edi
  push   %r12
  shr    $0x1f,%edi
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r15,%r15
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <getservbyname@plt>
  test   %rax,%rax
  je     L7
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <getprotobyname@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
  mov    (%r12),%edi
  call   <ntohs@plt>
  mov    0x0(%rbp),%ecx
  mov    %r15,%rdx
  pop    %rbp
  mov    %r14,%rsi
  pop    %r12
  mov    %r13d,%edi
  mov    %eax,%r8d
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <ipacl_do_request@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  mov    D5(%rip),%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    (%rax),%eax
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ipacl_do_request_s(const int reqport, int *const restrict pfh, const char *const restrict ip, const char *const restrict protocol, const char *const restrict port) {
  struct servent *ps;
  struct protoent *pp;
  assert(reqport >= 0);
  assert(pfh != NULL);
  assert(ip != NULL);
  assert(protocol != NULL);
  assert(port != NULL);
  ps = getservbyname(port, protocol);
  if (ps == NULL)
    return EINVAL;
  pp = getprotobyname(protocol);
  if (pp == NULL)
    return EINVAL;
  return ipacl_do_request(reqport, pfh, ip, pp->p_proto, ntohs(ps->s_port));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ipacl_do_request_s>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  not    %edi
  push   %r12
  shr    $0x1f,%edi
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r15,%r15
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <getservbyname@plt>
  test   %rax,%rax
  je     L16
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <getprotobyname@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
  mov    (%r12),%edi
  call   <ntohs@plt>
  mov    0x0(%rbp),%ecx
  mov    %r15,%rdx
  pop    %rbp
  mov    %r14,%rsi
  pop    %r12
  mov    %r13d,%edi
  mov    %eax,%r8d
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <ipacl_do_request@plt>
  nopw   0x0(%rax,%rax,1)
L16:
  mov    D4(%rip),%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    (%rax),%eax
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ipacl_do_request_s(const int reqport, int *const restrict pfh, const char *const restrict ip, const char *const restrict protocol, const char *const restrict port) {
  struct servent *ps;
  struct protoent *pp;
  assert(reqport >= 0);
  assert(pfh != NULL);
  assert(ip != NULL);
  assert(protocol != NULL);
  assert(port != NULL);
  ps = getservbyname(port, protocol);
  if (ps == NULL)
    return EINVAL;
  pp = getprotobyname(protocol);
  if (pp == NULL)
    return EINVAL;
  return ipacl_do_request(reqport, pfh, ip, pp->p_proto, ntohs(ps->s_port));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FIPS_ecdsa_verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %r8,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0xffffffff,-0x3c(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L7:
  cmp    %rdx,%rsp
  je     L28
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L28:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L36
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L36:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x60(%rbp),%rdi
  lea    -0x40(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x58(%rbp),%rsi
  mov    -0x50(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <FIPS_digest@plt>
  mov    -0x40(%rbp),%edx
  mov    -0x68(%rbp),%rcx
  mov    -0x30(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <FIPS_ecdsa_verify_digest@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x40(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <OPENSSL_cleanse@plt>
  mov    -0x3c(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int FIPS_ecdsa_verify(EC_KEY *key, const unsigned char *msg, size_t msglen, const EVP_MD *mhash, ECDSA_SIG *s) {
  int ret = -1;
  unsigned char dig[EVP_MAX_MD_SIZE];
  unsigned int dlen;
  FIPS_digest(msg, msglen, dig, &dlen, mhash);
  ret = FIPS_ecdsa_verify_digest(key, dig, dlen, s);
  OPENSSL_cleanse(dig, dlen);
  return ret;
}
```