ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uwsgi_cheap_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *uwsgi_cheap_string(char *buf, int len) {
  int i;
  char *cheap_buf = buf - 1;
  for (i = 0; i < len; i++) {
    *cheap_buf++ = buf[i];
  }
  buf[len - 1] = 0;
  return buf - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uwsgi_cheap_string>:
  endbr64
  lea    -0x1(%rdi),%r8
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%ecx
  add    %rdi,%rcx
  mov    %r8,%rax
L18:
  add    $0x1,%rax
  movzbl (%rax),%edx
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L18
L19:
  movslq %esi,%rsi
  movb   $0x0,-0x1(%rdi,%rsi,1)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *uwsgi_cheap_string(char *buf, int len) {
  int i;
  char *cheap_buf = buf - 1;
  for (i = 0; i < len; i++) {
    *cheap_buf++ = buf[i];
  }
  buf[len - 1] = 0;
  return buf - 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uwsgi_cheap_string>:
  endbr64
  push   %rbp
  lea    -0x1(%rdi),%r8
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L1
  mov    %rdi,%rsi
  mov    %rbx,%rdx
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %rax,%r8
L1:
  movb   $0x0,-0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *uwsgi_cheap_string(char *buf, int len) {
  int i;
  char *cheap_buf = buf - 1;
  for (i = 0; i < len; i++) {
    *cheap_buf++ = buf[i];
  }
  buf[len - 1] = 0;
  return buf - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uwsgi_cheap_string>:
  endbr64
  push   %rbp
  lea    -0x1(%rdi),%r8
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L9
  mov    %rdi,%rsi
  mov    %rbx,%rdx
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %rax,%r8
L9:
  movb   $0x0,-0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *uwsgi_cheap_string(char *buf, int len) {
  int i;
  char *cheap_buf = buf - 1;
  for (i = 0; i < len; i++) {
    *cheap_buf++ = buf[i];
  }
  buf[len - 1] = 0;
  return buf - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Operand_label12_rtoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_label12_rtoa(unsigned int *valp, unsigned int pc) {
  *valp += pc;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Operand_label12_rtoa>:
  endbr64
  add    %esi,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Operand_label12_rtoa(unsigned int *valp, unsigned int pc) {
  *valp += pc;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Operand_label12_rtoa>:
  endbr64
  add    %esi,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_label12_rtoa(unsigned int *valp, unsigned int pc) {
  *valp += pc;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Operand_label12_rtoa>:
  endbr64
  add    %esi,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_label12_rtoa(unsigned int *valp, unsigned int pc) {
  *valp += pc;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<px>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %edi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L30
  pxor   %xmm0,%xmm0
  jmp    L17
L30:
  cmpl   $0x1,-0x18(%rbp)
  jne    L23
  movss  -0x14(%rbp),%xmm0
  jmp    L17
L23:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%edi
  movd   %eax,%xmm0
  call   <px>
  movss  -0x1c(%rbp),%xmm2
  subss  %xmm0,%xmm2
  movss  %xmm2,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm3,%xmm3
  cvtsi2ss %eax,%xmm3
  movss  %xmm3,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%edi
  movd   %eax,%xmm0
  call   <px>
  movss  -0x20(%rbp),%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x1c(%rbp),%xmm0
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x18(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
L17:
  leave
  ret
```

assistant: ```c
float px(float x, int n) {
  float val;
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return x;
  } else {
    val = (2 * (n - 1) * x - px(x, n - 1) - (n - 1) * px(x, n - 2)) / n;
    return val;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<px>:
  endbr64
  test   %edi,%edi
  je     L27
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movaps %xmm0,%xmm2
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jne    L9
L29:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    -0x1(%rdi),%ebp
  lea    0x0(%rbp,%rbp,1),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm2,%xmm0
  movss  %xmm0,0x8(%rsp)
  mov    %ebp,%edi
  movss  %xmm2,0xc(%rsp)
  movaps %xmm2,%xmm0
  call   <px>
  movss  0x8(%rsp),%xmm3
  subss  %xmm0,%xmm3
  movss  %xmm3,0x8(%rsp)
  lea    -0x2(%rbx),%edi
  movss  0xc(%rsp),%xmm0
  call   <px>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  mulss  %xmm0,%xmm1
  movss  0x8(%rsp),%xmm0
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
  jmp    L29
L27:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float px(float x, int n) {
  float val;
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return x;
  } else {
    val = (2 * (n - 1) * x - px(x, n - 1) - (n - 1) * px(x, n - 2)) / n;
    return val;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<px>:
  endbr64
  test   %edi,%edi
  je     L11
  push   %rbp
  movaps %xmm0,%xmm1
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jne    L19
  add    $0x18,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rdi),%ebp
  pxor   %xmm2,%xmm2
  movss  %xmm0,0xc(%rsp)
  lea    0x0(%rbp,%rbp,1),%eax
  mov    %ebp,%edi
  cvtsi2ss %eax,%xmm2
  mulss  %xmm0,%xmm2
  movss  %xmm2,0x8(%rsp)
  call   <px>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  lea    -0x2(%rbx),%edi
  subss  %xmm0,%xmm2
  movaps %xmm1,%xmm0
  movss  %xmm2,0x8(%rsp)
  call   <px>
  movss  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  mulss  %xmm1,%xmm0
  subss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  pop    %rbx
  pop    %rbp
  divss  %xmm0,%xmm2
  movaps %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L11:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float px(float x, int n) {
  float val;
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return x;
  } else {
    val = (2 * (n - 1) * x - px(x, n - 1) - (n - 1) * px(x, n - 2)) / n;
    return val;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<computeArea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    0x10(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    -0x10(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%edx
  mov    0x18(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    -0x8(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  sub    -0x18(%rbp),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  imul   %ecx,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    0x10(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    0x18(%rbp),%eax
  sub    -0x28(%rbp),%eax
  imul   %edx,%eax
  add    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
  int left = (A > E ? A : E), right = ((C > G ? G : C) > left ? (C > G ? G : C) : left);
  int bottom = (B > F ? B : F), top = ((D > H ? H : D) > bottom ? (D > H ? H : D) : bottom);
  return (C - A) * (D - B) - (right - left) * (top - bottom) + (G - E) * (H - F);
}
```
user: What is the c source code of the assembly code below?

```asm
<computeArea>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  mov    0x18(%rsp),%edi
  mov    0x20(%rsp),%esi
  cmp    %ebx,%r8d
  mov    %ebx,%ebp
  cmovge %r8d,%ebp
  cmp    %r10d,%r9d
  mov    %r10d,%r11d
  cmovge %r9d,%r11d
  mov    %edx,%eax
  sub    %ebx,%eax
  mov    %ecx,%ebx
  sub    %r10d,%ebx
  imul   %ebx,%eax
  cmp    %edi,%edx
  cmovg  %edi,%edx
  cmp    %ebp,%edx
  cmovl  %ebp,%edx
  sub    %ebp,%edx
  cmp    %esi,%ecx
  cmovg  %esi,%ecx
  cmp    %r11d,%ecx
  cmovl  %r11d,%ecx
  sub    %r11d,%ecx
  imul   %ecx,%edx
  sub    %edx,%eax
  sub    %r8d,%edi
  mov    %edi,%edx
  sub    %r9d,%esi
  imul   %esi,%edx
  add    %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
  int left = (A > E ? A : E), right = ((C > G ? G : C) > left ? (C > G ? G : C) : left);
  int bottom = (B > F ? B : F), top = ((D > H ? H : D) > bottom ? (D > H ? H : D) : bottom);
  return (C - A) * (D - B) - (right - left) * (top - bottom) + (G - E) * (H - F);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<computeArea>:
  endbr64
  push   %rbp
  mov    %esi,%r10d
  mov    %edx,%eax
  push   %rbx
  mov    %edi,%ebx
  mov    %r10d,%r11d
  mov    0x18(%rsp),%edi
  cmp    %ebx,%r8d
  mov    %ebx,%ebp
  mov    0x20(%rsp),%esi
  cmovge %r8d,%ebp
  cmp    %r10d,%r9d
  cmovge %r9d,%r11d
  sub    %ebx,%eax
  mov    %ecx,%ebx
  sub    %r10d,%ebx
  imul   %ebx,%eax
  cmp    %edi,%edx
  pop    %rbx
  cmovg  %edi,%edx
  cmp    %ebp,%edx
  cmovl  %ebp,%edx
  sub    %ebp,%edx
  cmp    %esi,%ecx
  pop    %rbp
  cmovg  %esi,%ecx
  cmp    %r11d,%ecx
  cmovl  %r11d,%ecx
  sub    %r8d,%edi
  sub    %r9d,%esi
  sub    %r11d,%ecx
  imul   %ecx,%edx
  sub    %edx,%eax
  mov    %edi,%edx
  imul   %esi,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
  int left = (A > E ? A : E), right = ((C > G ? G : C) > left ? (C > G ? G : C) : left);
  int bottom = (B > F ? B : F), top = ((D > H ? H : D) > bottom ? (D > H ? H : D) : bottom);
  return (C - A) * (D - B) - (right - left) * (top - bottom) + (G - E) * (H - F);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<computeArea>:
  endbr64
  push   %rbp
  mov    %esi,%r10d
  mov    %edx,%eax
  push   %rbx
  mov    %edi,%ebx
  mov    %r10d,%r11d
  mov    0x18(%rsp),%edi
  cmp    %ebx,%r8d
  mov    %ebx,%ebp
  mov    0x20(%rsp),%esi
  cmovge %r8d,%ebp
  cmp    %r10d,%r9d
  cmovge %r9d,%r11d
  sub    %ebx,%eax
  mov    %ecx,%ebx
  sub    %r10d,%ebx
  imul   %ebx,%eax
  cmp    %edi,%edx
  pop    %rbx
  cmovg  %edi,%edx
  cmp    %ebp,%edx
  cmovl  %ebp,%edx
  sub    %ebp,%edx
  cmp    %esi,%ecx
  pop    %rbp
  cmovg  %esi,%ecx
  cmp    %r11d,%ecx
  cmovl  %r11d,%ecx
  sub    %r8d,%edi
  sub    %r9d,%esi
  sub    %r11d,%ecx
  imul   %ecx,%edx
  sub    %edx,%eax
  mov    %edi,%edx
  imul   %esi,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
  int left = (A > E ? A : E), right = ((C > G ? G : C) > left ? (C > G ? G : C) : left);
  int bottom = (B > F ? B : F), top = ((D > H ? H : D) > bottom ? (D > H ? H : D) : bottom);
  return (C - A) * (D - B) - (right - left) * (top - bottom) + (G - E) * (H - F);
}
```
user: What is the c source code of the assembly code below:

```asm
<eeprom_read_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <eeprom_read_block@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
uint16_t eeprom_read_word(const uint16_t *addr) {
  uint16_t ret = 0;
  eeprom_read_block(&ret, addr, 2);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eeprom_read_word>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x2,%edx
  call   <eeprom_read_block@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t eeprom_read_word(const uint16_t *addr) {
  uint16_t ret = 0;
  eeprom_read_block(&ret, addr, 2);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eeprom_read_word>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <eeprom_read_block@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t eeprom_read_word(const uint16_t *addr) {
  uint16_t ret = 0;
  eeprom_read_block(&ret, addr, 2);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<eeprom_read_word>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <eeprom_read_block@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t eeprom_read_word(const uint16_t *addr) {
  uint16_t ret = 0;
  eeprom_read_block(&ret, addr, 2);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x50(%rbp)
  movl   $0x5,-0x4c(%rbp)
  movl   $0x1,-0x48(%rbp)
  movl   $0x8,-0x44(%rbp)
  movl   $0x4,-0x40(%rbp)
  movl   $0x42,-0x3c(%rbp)
  movl   $0xc,-0x38(%rbp)
  movl   $0x5a,-0x34(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0x3,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x12,-0x54(%rbp)
  mov    -0x54(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <InsertionSort@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L27
L21:
  mov    -0x58(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x58(%rbp)
L27:
  mov    -0x58(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L21
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: %d


assistant: ```c
void main() {
  int i;
  int nums[] = {3, 5, 1, 8, 4, 66, 12, 90, 2, 1, 5, 7, 9, 3, 5, 5, 3, 2};
  int length = sizeof(nums) / sizeof(nums[0]);
  InsertionSort(nums, length);
  for (i = 0; i < length; ++i)
    printf("%d\n", nums[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x3,(%rsp)
  movl   $0x5,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x42,0x14(%rsp)
  movl   $0xc,0x18(%rsp)
  movl   $0x5a,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x5,0x28(%rsp)
  movl   $0x7,0x2c(%rsp)
  movl   $0x9,0x30(%rsp)
  movl   $0x3,0x34(%rsp)
  movl   $0x5,0x38(%rsp)
  movl   $0x5,0x3c(%rsp)
  movl   $0x3,0x40(%rsp)
  movl   $0x2,0x44(%rsp)
  mov    %rsp,%rbx
  mov    $0x12,%esi
  mov    %rbx,%rdi
  call   <InsertionSort@plt>
  lea    0x48(%rsp),%r12
  lea    D3(%rip),%rbp
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: %d


assistant: ```c
void main() {
  int i;
  int nums[] = {3, 5, 1, 8, 4, 66, 12, 90, 2, 1, 5, 7, 9, 3, 5, 5, 3, 2};
  int length = sizeof(nums) / sizeof(nums[0]);
  InsertionSort(nums, length);
  for (i = 0; i < length; ++i)
    printf("%d\n", nums[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x12,%esi
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x500000003,%rax
  mov    %rsp,%rbx
  lea    0x48(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x800000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x4200000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x5a0000000c,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x300000009,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x500000005,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x200000003,%rax
  mov    %rax,0x40(%rsp)
  call   <InsertionSort@plt>
  nopl   0x0(%rax)
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: %d


assistant: ```c
void main() {
  int i;
  int nums[] = {3, 5, 1, 8, 4, 66, 12, 90, 2, 1, 5, 7, 9, 3, 5, 5, 3, 2};
  int length = sizeof(nums) / sizeof(nums[0]);
  InsertionSort(nums, length);
  for (i = 0; i < length; ++i)
    printf("%d\n", nums[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x12,%esi
  push   %rbp
  lea    D53(%rip),%rbp
  push   %rbx
  sub    $0x50,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    D50(%rip),%rax
  lea    0x48(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D8(%rip),%xmm0
  mov    %rbx,%rdi
  mov    %rax,0x40(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D54(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D28(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <InsertionSort@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L14
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D53
data_type: string
name: retrieve_data
arguments: label: D11
data_type: byte[16]
name: retrieve_data
arguments: label: D50
data_type: byte[8]
name: retrieve_data
arguments: label: D8
data_type: byte[16]
name: retrieve_data
arguments: label: D54
data_type: byte[16]
name: retrieve_data
arguments: label: D28
data_type: byte[16]

tool: D53: %d


tool: {"D11": [0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D50": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D8": [0x04,0x00,0x00,0x00,0x42,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x5a,0x00,0x00,0x00]}

tool: {"D54": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D28": [0x09,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

assistant: ```c
void main() {
  int i;
  int nums[] = {3, 5, 1, 8, 4, 66, 12, 90, 2, 1, 5, 7, 9, 3, 5, 5, 3, 2};
  int length = sizeof(nums) / sizeof(nums[0]);
  InsertionSort(nums, length);
  for (i = 0; i < length; ++i)
    printf("%d\n", nums[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L55
  mov    $0x1,%eax
  jmp    L99
L55:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L86
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L86
  mov    $0x1,%eax
  jmp    L99
L86:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L87
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L87
  mov    $0x1,%eax
  jmp    L99
L87:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L38
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L38
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L38
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L38
  mov    $0x1,%eax
  jmp    L99
L38:
  mov    $0x0,%eax
L99:
  leave
  ret
```

assistant: ```c
int is_number(char s[]) {
  if (isdigit(s[0]))
    return 1;
  if (s[0] == '-' && isdigit(s[1]))
    return 1;
  if (s[0] == '.' && isdigit(s[1]))
    return 1;
  if (strlen(s) > 1 && s[0] == '-' && s[1] == '.' && isdigit(s[2]))
    return 1;
  return 0;
}
```