ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<socket_local_server>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    $0x0,%edx
  mov    %ebp,%esi
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L49
  mov    %eax,%ebx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <socket_local_server_bind@plt>
  test   %eax,%eax
  js     L47
  mov    D10(%rip),%rax
  cmp    %ebp,(%rax)
  je     L24
L51:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebx
  jmp    L51
L24:
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <listen@plt>
  test   %eax,%eax
  jns    L51
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebx
  jmp    L51
L49:
  mov    $0xffffffff,%ebx
  jmp    L51
```

assistant: ```c
int socket_local_server(const char *name, int namespace, int type) {
  int err;
  int s;
  s = socket(AF_LOCAL, type, 0);
  if (s < 0)
    return -1;
  err = socket_local_server_bind(s, name, namespace);
  if (err < 0) {
    close(s);
    return -1;
  }
  if (type == SOCK_STREAM) {
    int ret;
    ret = listen(s, 4);
    if (ret < 0) {
      close(s);
      return -1;
    }
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<socket_local_server>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  xor    %edx,%edx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L38
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <socket_local_server_bind@plt>
  test   %eax,%eax
  js     L5
  mov    D13(%rip),%rax
  cmp    %ebx,(%rax)
  je     L29
L13:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  mov    $0x4,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  test   %eax,%eax
  jns    L13
L5:
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L13
  nopl   0x0(%rax)
L38:
  mov    $0xffffffff,%r12d
  jmp    L13
```

assistant: ```c
int socket_local_server(const char *name, int namespace, int type) {
  int err;
  int s;
  s = socket(AF_LOCAL, type, 0);
  if (s < 0)
    return -1;
  err = socket_local_server_bind(s, name, namespace);
  if (err < 0) {
    close(s);
    return -1;
  }
  if (type == SOCK_STREAM) {
    int ret;
    ret = listen(s, 4);
    if (ret < 0) {
      close(s);
      return -1;
    }
  }
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<socket_local_server>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  xor    %edx,%edx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L33
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <socket_local_server_bind@plt>
  test   %eax,%eax
  js     L19
  mov    D18(%rip),%rax
  cmp    %ebx,(%rax)
  je     L12
L50:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x4,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  test   %eax,%eax
  jns    L50
L19:
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L50
  nopl   0x0(%rax)
L33:
  mov    $0xffffffff,%r12d
  jmp    L50
```

assistant: ```c
int socket_local_server(const char *name, int namespace, int type) {
  int err;
  int s;
  s = socket(AF_LOCAL, type, 0);
  if (s < 0)
    return -1;
  err = socket_local_server_bind(s, name, namespace);
  if (err < 0) {
    close(s);
    return -1;
  }
  if (type == SOCK_STREAM) {
    int ret;
    ret = listen(s, 4);
    if (ret < 0) {
      close(s);
      return -1;
    }
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L20
  mov    -0x14(%rbp),%eax
  jmp    L4
L20:
  mov    $0x1,%eax
L4:
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L43
L18:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L0
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L43:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L18
  jmp    L61
L0:
  nop
L61:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D41
type_guessed: string
name: unpack_data
arguments: data_label: D21
type_guessed: string
name: unpack_data
arguments: data_label: D20
type_guessed: string
name: unpack_data
arguments: data_label: D48
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string
name: unpack_data
arguments: data_label: D31
type_guessed: string

tool: D41: This program adds a list of numbers.

tool: D21: Signal end of list with a 0.

tool: D20: or input how many numbers need add (press 0 to skip): 

tool: D48: %d

tool: D6:  ? 

tool: D31: The total is %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int index, value, total;
  printf("This program adds a list of numbers.\n");
  printf("Signal end of list with a 0.\n");
  printf("or input how many numbers need add (press 0 to skip): ");
  scanf("%d", &index);
  index = (index == 0) ? 1 : index;
  total = 0;
  while (index--) {
    printf(" ? ");
    scanf("%d", &value);
    if (value == 0)
      break;
    total += value;
  }
  printf("The total is %d\n", total);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L25
  sub    $0x1,%eax
  mov    %eax,(%rsp)
L25:
  mov    $0x0,%ebx
  lea    D20(%rip),%r13
  lea    0x4(%rsp),%r12
  lea    D15(%rip),%rbp
L20:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L34
  add    %eax,%ebx
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L20
L34:
  mov    %ebx,%esi
  lea    D62(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D56
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D20
type_guessed: string
name: disassemble_data
arguments: data_tag: D62
type_guessed: string

tool: D14: This program adds a list of numbers.

tool: D2: Signal end of list with a 0.

tool: D56: or input how many numbers need add (press 0 to skip): 

tool: D15: %d

tool: D20:  ? 

tool: D62: The total is %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int index, value, total;
  printf("This program adds a list of numbers.\n");
  printf("Signal end of list with a 0.\n");
  printf("or input how many numbers need add (press 0 to skip): ");
  scanf("%d", &index);
  index = (index == 0) ? 1 : index;
  total = 0;
  while (index--) {
    printf(" ? ");
    scanf("%d", &value);
    if (value == 0)
      break;
    total += value;
  }
  printf("The total is %d\n", total);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D30(%rip),%rdi
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D25(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    $0x1,%edx
  test   %eax,%eax
  cmove  %edx,%eax
  xor    %ebp,%ebp
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  jmp    L31
  nopl   0x0(%rax)
L11:
  add    %eax,%ebp
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L38
L31:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L11
L38:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D13
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D52
type: string
name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D57
type: string

tool: D30: This program adds a list of numbers.

tool: D13:  ? 

tool: D25: %d

tool: D52: Signal end of list with a 0.

tool: D34: or input how many numbers need add (press 0 to skip): 

tool: D57: The total is %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int index, value, total;
  printf("This program adds a list of numbers.\n");
  printf("Signal end of list with a 0.\n");
  printf("or input how many numbers need add (press 0 to skip): ");
  scanf("%d", &index);
  index = (index == 0) ? 1 : index;
  total = 0;
  while (index--) {
    printf(" ? ");
    scanf("%d", &value);
    if (value == 0)
      break;
    total += value;
  }
  printf("The total is %d\n", total);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%rdi
  lea    D27(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D51(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    $0x1,%edx
  test   %eax,%eax
  cmove  %edx,%eax
  xor    %ebp,%ebp
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  jmp    L24
  nopl   0x0(%rax)
L31:
  add    %eax,%ebp
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L21
L24:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L31
L21:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D51
datatype: string
name: disassemble_data
arguments: label: D4
datatype: string
name: disassemble_data
arguments: label: D12
datatype: string
name: disassemble_data
arguments: label: D23
datatype: string

tool: D10: This program adds a list of numbers.

tool: D27:  ? 

tool: D51: %d

tool: D4: Signal end of list with a 0.

tool: D12: or input how many numbers need add (press 0 to skip): 

tool: D23: The total is %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int index, value, total;
  printf("This program adds a list of numbers.\n");
  printf("Signal end of list with a 0.\n");
  printf("or input how many numbers need add (press 0 to skip): ");
  scanf("%d", &index);
  index = (index == 0) ? 1 : index;
  total = 0;
  while (index--) {
    printf(" ? ");
    scanf("%d", &value);
    if (value == 0)
      break;
    total += value;
  }
  printf("The total is %d\n", total);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  jne    L9
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <my_algebra@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int result = -1;
  if (argc == 4) {
    int op = atoi(argv[1]);
    int x = atoi(argv[2]);
    int y = atoi(argv[3]);
    printf("%d\n", my_algebra(op, x, y));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  cmp    $0x4,%edi
  je     L9
  mov    $0x0,%eax
  ret
L9:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <my_algebra@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int result = -1;
  if (argc == 4) {
    int op = atoi(argv[1]);
    int x = atoi(argv[2]);
    int y = atoi(argv[3]);
    printf("%d\n", my_algebra(op, x, y));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  cmp    $0x4,%edi
  je     L0
  xor    %eax,%eax
  ret
L0:
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <my_algebra@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int result = -1;
  if (argc == 4) {
    int op = atoi(argv[1]);
    int x = atoi(argv[2]);
    int y = atoi(argv[3]);
    printf("%d\n", my_algebra(op, x, y));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  cmp    $0x4,%edi
  je     L0
  xor    %eax,%eax
  ret
L0:
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <my_algebra@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D1
type: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int result = -1;
  if (argc == 4) {
    int op = atoi(argv[1]);
    int x = atoi(argv[2]);
    int y = atoi(argv[3]);
    printf("%d\n", my_algebra(op, x, y));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hashfn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L5:
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%esi
  mov    D8(%rip),%eax
  sub    $0x5,%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  imul   $0x8421085,%rax,%rax
  shr    $0x20,%rax
  mov    %rax,%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: byte[4]

tool: {"D8": [0x20,0x00,0x00,0x00]}

assistant: ```c
int hashfn(const char *key) {
  unsigned int hashed = 0;
  const char *c;
  static const int bits_per_int = sizeof(unsigned int) * 8;
  for (c = key; *c; c++) {
    hashed = (hashed << 5) | (hashed >> (bits_per_int - 5));
    hashed ^= *c;
  }
  return hashed % 31;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hashfn>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  mov    $0x0,%edx
L21:
  rol    $0x5,%edx
  movsbl %al,%eax
  xor    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L21
L16:
  mov    %edx,%ecx
  imul   $0x8421085,%rcx,%rcx
  shr    $0x20,%rcx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x4,%eax
  mov    %eax,%ecx
  shl    $0x5,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L24:
  mov    $0x0,%edx
  jmp    L16
```

assistant: ```c
int hashfn(const char *key) {
  unsigned int hashed = 0;
  const char *c;
  static const int bits_per_int = sizeof(unsigned int) * 8;
  for (c = key; *c; c++) {
    hashed = (hashed << 5) | (hashed >> (bits_per_int - 5));
    hashed ^= *c;
  }
  return hashed % 31;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hashfn>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L16
  xor    %edx,%edx
  nopl   (%rax)
L4:
  rol    $0x5,%edx
  add    $0x1,%rdi
  xor    %eax,%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L4
  mov    %edx,%ecx
  mov    %edx,%eax
  imul   $0x8421085,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x4,%eax
  mov    %eax,%ecx
  shl    $0x5,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hashfn(const char *key) {
  unsigned int hashed = 0;
  const char *c;
  static const int bits_per_int = sizeof(unsigned int) * 8;
  for (c = key; *c; c++) {
    hashed = (hashed << 5) | (hashed >> (bits_per_int - 5));
    hashed ^= *c;
  }
  return hashed % 31;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hashfn>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L17
  xor    %edx,%edx
  nopl   (%rax)
L7:
  rol    $0x5,%edx
  add    $0x1,%rdi
  xor    %eax,%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L7
  mov    %edx,%ecx
  mov    %edx,%eax
  imul   $0x8421085,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x4,%eax
  mov    %eax,%ecx
  shl    $0x5,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hashfn(const char *key) {
  unsigned int hashed = 0;
  const char *c;
  static const int bits_per_int = sizeof(unsigned int) * 8;
  for (c = key; *c; c++) {
    hashed = (hashed << 5) | (hashed >> (bits_per_int - 5));
    hashed ^= *c;
  }
  return hashed % 31;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<brew_beer>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movaps %xmm0,%xmm3
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  movaps %xmm2,%xmm0
  divss  %xmm3,%xmm0
  comiss D64(%rip),%xmm0
  ja     L81
  movss  D20(%rip),%xmm1
  comiss %xmm0,%xmm1
  ja     L66
L13:
  movss  0x8(%rsp),%xmm0
  divss  0xc(%rsp),%xmm0
  comiss D56(%rip),%xmm0
  ja     L76
  movss  D64(%rip),%xmm1
  comiss %xmm0,%xmm1
  ja     L27
L44:
  mov    $0x57,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  mulsd  D34(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    %rax,%rsi
  mov    $0x16,%edi
  call   <bottle@plt>
  mov    %rbx,%rax
  lea    0x58(%rbx),%rsi
  mov    $0x0,%edx
L69:
  cmpl   $0x1,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L69
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L81:
  lea    D57(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L66:
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L76:
  lea    D60(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L27:
  lea    D83(%rip),%rdi
  call   <printf@plt>
  jmp    L44
```

tool_calls: name: read_data
arguments: tag: D64
type_infered: f32
name: read_data
arguments: tag: D20
type_infered: f32
name: read_data
arguments: tag: D56
type_infered: f32
name: read_data
arguments: tag: D34
type_infered: f64
name: read_data
arguments: tag: D57
type_infered: string
name: read_data
arguments: tag: D46
type_infered: string
name: read_data
arguments: tag: D60
type_infered: string
name: read_data
arguments: tag: D83
type_infered: string

tool: D64: 10

tool: D20: 2.5

tool: D56: 20

tool: D34: 0.9

tool: D57: There is less water in the Atlatic...


tool: D46: Are you making porridge?


tool: D60: Are you kidding me? Budwiser?


tool: D83: Whoa! Feeling bitter?


assistant: ```c
int brew_beer(float barley, float hops, float water) {
  float vol;
  int *bottles;
  int i, n, nbottles;
  if (water / barley > 10.0) {
    printf("There is less water in the Atlatic...\n");
  } else if (water / barley < 2.5) {
    printf("Are you making porridge?\n");
  }
  if (water / hops > 20.0) {
    printf("Are you kidding me? Budwiser?\n");
  } else if (water / hops < 10.0) {
    printf("Whoa! Feeling bitter?\n");
  }
  nbottles = 22;
  bottles = (int *)malloc((sizeof(float) * nbottles - 1));
  vol = water * 0.9;
  bottle(vol, nbottles, bottles);
  n = 0;
  for (i = 0; i < nbottles; i++) {
    if (bottles[i] == 1)
      n++;
  }
  return n;
}
```