ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D53(%rip),%rbp
  lea    D41(%rip),%rsi
  mov    %rbp,%rdi
  call   <countStrStr@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <countStrStr@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  lea    D68(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <countStrStr@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  lea    D40(%rip),%rsi
  mov    %rbp,%rdi
  call   <countStrStr@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  lea    D38(%rip),%rsi
  mov    %rbp,%rdi
  call   <countStrStr@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  lea    D33(%rip),%rsi
  call   <countStrStr@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D53
type_infered: string
name: unpack_data
arguments: label: D41
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D68
type_infered: string
name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D40
type_infered: string
name: unpack_data
arguments: label: D38
type_infered: string
name: unpack_data
arguments: label: D33
type_infered: string

tool: D53: Hello

tool: D41: H

tool: D4: l

tool: D68: el

tool: D23: Helelo

tool: D40: o

tool: D38: j

tool: D33: llO

assistant: ```c
int main(int argc, char **argv) {
  assert(countStrStr("Hello", "H") == 1);
  assert(countStrStr("Hello", "l") == 2);
  assert(countStrStr("Helelo", "el") == 2);
  assert(countStrStr("Hello", "o") == 1);
  assert(countStrStr("Hello", "j") == 0);
  assert(countStrStr("Hello", "llO") == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<threeSumClosest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L65
  cmpl   $0x2,-0x2c(%rbp)
  jg     L77
L65:
  mov    $0x0,%eax
  jmp    L49
L77:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <threeSumClosestQSort@plt>
  movl   $0x0,-0x14(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L7
L34:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <twoSumClosestDif@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L20
  mov    -0x30(%rbp),%eax
  jmp    L49
L20:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rax,%rbx
  jge    L2
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L2:
  addl   $0x1,-0x18(%rbp)
L7:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L34
  mov    -0x30(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
L49:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int threeSumClosest(int *nums, int numsSize, int target) {
  if (nums == NULL || numsSize < 3) {
    return 0;
  }
  threeSumClosestQSort(nums, 0, numsSize - 1);
  int dif = 0;
  int minDif = INT_MAX;
  int i = 0;
  for (i = 1; i < numsSize - 1;) {
    dif = twoSumClosestDif(nums, numsSize, i, target - nums[i - 1]);
    if (dif == 0) {
      return target;
    } else if (abs(dif) < abs(minDif)) {
      minDif = dif;
    }
    i++;
  }
  return target + minDif;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<threeSumClosest>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %rdi,%rdi
  je     L15
  mov    %rdi,%r12
  mov    %edx,%r14d
  cmp    $0x2,%esi
  jle    L15
  lea    -0x1(%rsi),%r15d
  mov    %r15d,%edx
  mov    $0x0,%esi
  call   <threeSumClosestQSort@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%r13d
  mov    $0x1,%ebp
L21:
  mov    %r14d,%ecx
  sub    -0x4(%r12,%rbp,4),%ecx
  mov    %ebp,%edx
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <twoSumClosestDif@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L2
  mov    %eax,%edi
  call   <abs@plt>
  mov    %rax,(%rsp)
  mov    %r13d,%edi
  call   <abs@plt>
  cmp    %rax,(%rsp)
  cmovl  %ebx,%r13d
  add    $0x1,%rbp
  cmp    %ebp,%r15d
  jg     L21
  lea    0x0(%r13,%r14,1),%eax
  jmp    L41
L15:
  mov    $0x0,%eax
L41:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  mov    %r14d,%eax
  jmp    L41
```

assistant: ```c
int threeSumClosest(int *nums, int numsSize, int target) {
  if (nums == NULL || numsSize < 3) {
    return 0;
  }
  threeSumClosestQSort(nums, 0, numsSize - 1);
  int dif = 0;
  int minDif = INT_MAX;
  int i = 0;
  for (i = 1; i < numsSize - 1;) {
    dif = twoSumClosestDif(nums, numsSize, i, target - nums[i - 1]);
    if (dif == 0) {
      return target;
    } else if (abs(dif) < abs(minDif)) {
      minDif = dif;
    }
    i++;
  }
  return target + minDif;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<threeSumClosest>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0x8(%rsp)
  test   %rdi,%rdi
  je     L33
  mov    %esi,%r14d
  cmp    $0x2,%esi
  jle    L33
  lea    -0x1(%rsi),%eax
  xor    %esi,%esi
  mov    %rdi,%rbp
  mov    $0x1,%r15d
  mov    %eax,%edx
  mov    %eax,0xc(%rsp)
  call   <threeSumClosestQSort@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%r12d
  xchg   %ax,%ax
L20:
  mov    0x8(%rsp),%ecx
  mov    %r15d,%edx
  sub    -0x4(%rbp,%r15,4),%ecx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <twoSumClosestDif@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L25
  mov    %eax,%edi
  call   <abs@plt>
  mov    %r12d,%edi
  mov    %rax,%rbx
  call   <abs@plt>
  cmp    %rax,%rbx
  cmovl  %r13d,%r12d
  add    $0x1,%r15
  cmp    %r15d,0xc(%rsp)
  jg     L20
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  add    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L25:
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int threeSumClosest(int *nums, int numsSize, int target) {
  if (nums == NULL || numsSize < 3) {
    return 0;
  }
  threeSumClosestQSort(nums, 0, numsSize - 1);
  int dif = 0;
  int minDif = INT_MAX;
  int i = 0;
  for (i = 1; i < numsSize - 1;) {
    dif = twoSumClosestDif(nums, numsSize, i, target - nums[i - 1]);
    if (dif == 0) {
      return target;
    } else if (abs(dif) < abs(minDif)) {
      minDif = dif;
    }
    i++;
  }
  return target + minDif;
}
```
user: What is the c source code of the assembly code below:

```asm
<threeSumClosest>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0x8(%rsp)
  test   %rdi,%rdi
  je     L38
  mov    %esi,%r14d
  cmp    $0x2,%esi
  jle    L38
  lea    -0x1(%rsi),%eax
  xor    %esi,%esi
  mov    %rdi,%rbp
  mov    $0x1,%r15d
  mov    %eax,%edx
  mov    %eax,0xc(%rsp)
  call   <threeSumClosestQSort@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%r12d
  xchg   %ax,%ax
L31:
  mov    0x8(%rsp),%ecx
  mov    %r15d,%edx
  sub    -0x4(%rbp,%r15,4),%ecx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <twoSumClosestDif@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L16
  mov    %eax,%edi
  call   <abs@plt>
  mov    %r12d,%edi
  mov    %rax,%rbx
  call   <abs@plt>
  cmp    %rax,%rbx
  cmovl  %r13d,%r12d
  add    $0x1,%r15
  cmp    %r15d,0xc(%rsp)
  jg     L31
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  add    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L16:
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int threeSumClosest(int *nums, int numsSize, int target) {
  if (nums == NULL || numsSize < 3) {
    return 0;
  }
  threeSumClosestQSort(nums, 0, numsSize - 1);
  int dif = 0;
  int minDif = INT_MAX;
  int i = 0;
  for (i = 1; i < numsSize - 1;) {
    dif = twoSumClosestDif(nums, numsSize, i, target - nums[i - 1]);
    if (dif == 0) {
      return target;
    } else if (abs(dif) < abs(minDif)) {
      minDif = dif;
    }
    i++;
  }
  return target + minDif;
}
```
user: What is the c source code of the assembly code below?

```asm
<derivative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print@plt>
  jmp    L1
L8:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L35:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x0,-0x8(%rbp)
  jns    L35
  subl   $0x1,-0x20(%rbp)
L1:
  cmpl   $0x0,-0x20(%rbp)
  jg     L8
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: string
name: extract_symbolic_data
arguments: label: D17
data_type: string

tool: D10: Derivative of 

tool: D20: is 

tool: D17: 


assistant: ```c
void derivative(double *poly, int n, int r) {
  printf("Derivative of ");
  print(poly, n);
  for (; r > 0; r--)
    for (int i = n - 1, j = 0; i >= 0; i--, j++)
      poly[i] *= j;
  printf("is ");
  print(poly, n);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<derivative>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <print@plt>
  test   %ebp,%ebp
  jle    L26
  lea    -0x1(%rbx),%eax
  cltq
  lea    (%r12,%rax,8),%rcx
L22:
  test   %ebx,%ebx
  jle    L7
  mov    %rcx,%rdx
  mov    $0x0,%eax
L36:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%eax
  sub    $0x8,%rdx
  cmp    %eax,%ebx
  jne    L36
L7:
  sub    $0x1,%ebp
  jne    L22
L26:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <print@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D8
type: string

tool: D21: Derivative of 

tool: D29: is 

tool: D8: 


assistant: ```c
void derivative(double *poly, int n, int r) {
  printf("Derivative of ");
  print(poly, n);
  for (; r > 0; r--)
    for (int i = n - 1, j = 0; i >= 0; i--, j++)
      poly[i] *= j;
  printf("is ");
  print(poly, n);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<derivative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <print@plt>
  test   %ebx,%ebx
  jle    L23
  lea    -0x1(%rbp),%edx
  movslq %edx,%rax
  lea    (%r12,%rax,8),%rsi
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %rsi,%rcx
  xor    %eax,%eax
  test   %edx,%edx
  js     L15
  nopl   0x0(%rax)
L18:
  pxor   %xmm0,%xmm0
  sub    $0x8,%rcx
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rcx),%xmm0
  add    $0x1,%eax
  movsd  %xmm0,0x8(%rcx)
  cmp    %eax,%ebp
  jne    L18
L15:
  sub    $0x1,%ebx
  jne    L32
L23:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    %ebp,%esi
  call   <print@plt>
  pop    %rbx
  lea    D27(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D11
type_infered: string
name: unpack_data
arguments: data_tag: D27
type_infered: string

tool: D7: Derivative of 

tool: D11: is 

tool: D27: 


assistant: ```c
void derivative(double *poly, int n, int r) {
  printf("Derivative of ");
  print(poly, n);
  for (; r > 0; r--)
    for (int i = n - 1, j = 0; i >= 0; i--, j++)
      poly[i] *= j;
  printf("is ");
  print(poly, n);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<derivative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D11(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <print@plt>
  test   %ebx,%ebx
  jle    L11
  mov    %ebp,%eax
  sub    $0x1,%eax
  js     L11
  lea    -0x1(%rbx),%ecx
  movslq %eax,%rdi
  mov    %ecx,%esi
  cmp    $0x2,%ebx
  jle    L42
  lea    (%r12,%rdi,8),%rcx
L63:
  mov    %rcx,%rdx
  xor    %eax,%eax
  xchg   %ax,%ax
L35:
  pxor   %xmm1,%xmm1
  movsd  (%rdx),%xmm0
  sub    $0x8,%rdx
  cvtsi2sd %eax,%xmm1
  add    $0x1,%eax
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  cmp    %eax,%ebp
  jne    L35
  lea    -0x1(%rsi),%ebx
  sub    $0x2,%esi
  cmp    $0x1,%esi
  jg     L63
  lea    -0x1(%rbx),%ecx
L42:
  lea    (%r12,%rdi,8),%rsi
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    %rsi,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L8:
  pxor   %xmm0,%xmm0
  sub    $0x8,%rdx
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rdx),%xmm0
  add    $0x1,%eax
  movsd  %xmm0,0x8(%rdx)
  cmp    %ebp,%eax
  jne    L8
  test   %ecx,%ecx
  je     L11
  sub    $0x1,%ecx
  jmp    L41
  xchg   %ax,%ax
L11:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    %ebp,%esi
  call   <print@plt>
  pop    %rbx
  lea    D18(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
type: string
name: unpack_data
arguments: label: D21
type: string
name: unpack_data
arguments: label: D18
type: string

tool: D11: Derivative of 

tool: D21: is 

tool: D18: 


assistant: ```c
void derivative(double *poly, int n, int r) {
  printf("Derivative of ");
  print(poly, n);
  for (; r > 0; r--)
    for (int i = n - 1, j = 0; i >= 0; i--, j++)
      poly[i] *= j;
  printf("is ");
  print(poly, n);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x18(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <parse_opts@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L53
  mov    -0x10(%rbp),%eax
  jmp    L60
L53:
  mov    -0x18(%rbp),%eax
  lea    -0x14(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sock_alloc@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L56
  mov    $0xffffffff,%eax
  jmp    L60
L56:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L43
  lea    -0x14(%rbp),%rax
  jmp    L47
L43:
  mov    $0x0,%eax
L47:
  mov    -0xc(%rbp),%edx
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <io_dispatch@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
L60:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int sockfd;
  int listen = 0;
  struct sockaddr_in addr;
  int rc = 0;
  memset(&addr, 0, sizeof(addr));
  rc = parse_opts(argc, argv, &addr, &listen);
  if (rc) {
    return rc;
  }
  sockfd = sock_alloc(listen, &addr);
  if (sockfd < 0)
    return -1;
  rc = io_dispatch(sockfd, listen ? NULL : &addr);
  close(sockfd);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  lea    0x4(%rsp),%r12
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rsp,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <parse_opts@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L48
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  mov    %r12,%rsi
  mov    (%rsp),%edi
  call   <sock_alloc@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L49
  mov    %r12,%rsi
  cmpl   $0x0,(%rsp)
  mov    $0x0,%eax
  cmovne %rax,%rsi
  mov    %ebp,%edi
  call   <io_dispatch@plt>
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L25
L49:
  mov    $0xffffffff,%ebx
  jmp    L25
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int sockfd;
  int listen = 0;
  struct sockaddr_in addr;
  int rc = 0;
  memset(&addr, 0, sizeof(addr));
  rc = parse_opts(argc, argv, &addr, &listen);
  if (rc) {
    return rc;
  }
  sockfd = sock_alloc(listen, &addr);
  if (sockfd < 0)
    return -1;
  rc = io_dispatch(sockfd, listen ? NULL : &addr);
  close(sockfd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  movl   $0x0,(%rsp)
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %r12d,%edi
  mov    %rsp,%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <parse_opts@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L6
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    (%rsp),%edi
  mov    %rbx,%rsi
  call   <sock_alloc@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L49
  xor    %eax,%eax
  cmpl   $0x0,(%rsp)
  mov    %ebp,%edi
  cmove  %rbx,%rax
  mov    %rax,%rsi
  call   <io_dispatch@plt>
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L42
L49:
  or     $0xffffffff,%r12d
  jmp    L42
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int sockfd;
  int listen = 0;
  struct sockaddr_in addr;
  int rc = 0;
  memset(&addr, 0, sizeof(addr));
  rc = parse_opts(argc, argv, &addr, &listen);
  if (rc) {
    return rc;
  }
  sockfd = sock_alloc(listen, &addr);
  if (sockfd < 0)
    return -1;
  rc = io_dispatch(sockfd, listen ? NULL : &addr);
  close(sockfd);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  movl   $0x0,(%rsp)
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %r12d,%edi
  mov    %rsp,%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <parse_opts@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L47
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    (%rsp),%edi
  mov    %rbx,%rsi
  call   <sock_alloc@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L26
  xor    %eax,%eax
  cmpl   $0x0,(%rsp)
  mov    %ebp,%edi
  cmove  %rbx,%rax
  mov    %rax,%rsi
  call   <io_dispatch@plt>
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L8
L26:
  or     $0xffffffff,%r12d
  jmp    L8
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int sockfd;
  int listen = 0;
  struct sockaddr_in addr;
  int rc = 0;
  memset(&addr, 0, sizeof(addr));
  rc = parse_opts(argc, argv, &addr, &listen);
  if (rc) {
    return rc;
  }
  sockfd = sock_alloc(listen, &addr);
  if (sockfd < 0)
    return -1;
  rc = io_dispatch(sockfd, listen ? NULL : &addr);
  close(sockfd);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    %rdx,%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
int hash_num(x, size)
int x;
int size;
{ return (((((long)(x)) < 0) ? -((long)(x)) : ((long)(x))) % (size)); }
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_num>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  mov    %eax,%eax
  movslq %esi,%rsi
  cqto
  idiv   %rsi
  mov    %edx,%eax
  ret
```

assistant: ```c
int hash_num(x, size)
int x;
int size;
{ return (((((long)(x)) < 0) ? -((long)(x)) : ((long)(x))) % (size)); }
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_num>:
  endbr64
  mov    %edi,%eax
  movslq %esi,%rsi
  neg    %eax
  cmovs  %edi,%eax
  mov    %eax,%eax
  cqto
  idiv   %rsi
  mov    %edx,%eax
  ret
```

assistant: ```c
int hash_num(x, size)
int x;
int size;
{ return (((((long)(x)) < 0) ? -((long)(x)) : ((long)(x))) % (size)); }
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash_num>:
  endbr64
  mov    %edi,%eax
  movslq %esi,%rsi
  neg    %eax
  cmovs  %edi,%eax
  mov    %eax,%eax
  cqto
  idiv   %rsi
  mov    %edx,%eax
  ret
```

assistant: ```c
int hash_num(x, size)
int x;
int size;
{ return (((((long)(x)) < 0) ? -((long)(x)) : ((long)(x))) % (size)); }
```