ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<tv_sub>:
  endbr64
  mov    0x8(%rdi),%rdx
  sub    0x8(%rsi),%rdx
  mov    %rdx,0x8(%rdi)
  mov    (%rdi),%rax
  sub    (%rsi),%rax
  js     L7
  mov    %rax,(%rdi)
  ret
L7:
  add    $0xf4240,%rax
  mov    %rax,(%rdi)
  sub    $0x1,%rdx
  mov    %rdx,0x8(%rdi)
  ret
```

assistant: ```c
void tv_sub(struct timeval *tva, struct timeval *tvb) {
  tva->tv_sec -= tvb->tv_sec;
  tva->tv_usec -= tvb->tv_usec;
  if (tva->tv_usec < 0) {
    tva->tv_usec += 1000000;
    tva->tv_sec--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tv_sub>:
  endbr64
  mov    0x8(%rdi),%rdx
  sub    0x8(%rsi),%rdx
  mov    %rdx,0x8(%rdi)
  mov    (%rdi),%rax
  sub    (%rsi),%rax
  js     L9
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax)
L9:
  add    $0xf4240,%rax
  sub    $0x1,%rdx
  mov    %rax,(%rdi)
  mov    %rdx,0x8(%rdi)
  ret
```

assistant: ```c
void tv_sub(struct timeval *tva, struct timeval *tvb) {
  tva->tv_sec -= tvb->tv_sec;
  tva->tv_usec -= tvb->tv_usec;
  if (tva->tv_usec < 0) {
    tva->tv_usec += 1000000;
    tva->tv_sec--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tv_sub>:
  endbr64
  mov    0x8(%rdi),%rdx
  sub    0x8(%rsi),%rdx
  mov    %rdx,0x8(%rdi)
  mov    (%rdi),%rax
  sub    (%rsi),%rax
  js     L8
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax)
L8:
  add    $0xf4240,%rax
  sub    $0x1,%rdx
  mov    %rax,(%rdi)
  mov    %rdx,0x8(%rdi)
  ret
```

assistant: ```c
void tv_sub(struct timeval *tva, struct timeval *tvb) {
  tva->tv_sec -= tvb->tv_sec;
  tva->tv_usec -= tvb->tv_usec;
  if (tva->tv_usec < 0) {
    tva->tv_usec += 1000000;
    tva->tv_sec--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Com_BlockChecksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mdfour@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  xor    %eax,%edx
  mov    -0x18(%rbp),%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned int Com_BlockChecksum(void *buffer, int length) {
  int digest[4];
  unsigned int val;
  mdfour((unsigned char *)digest, (unsigned char *)buffer, length);
  val = digest[0] ^ digest[1] ^ digest[2] ^ digest[3];
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Com_BlockChecksum>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <mdfour@plt>
  mov    (%rsp),%eax
  xor    0x4(%rsp),%eax
  xor    0x8(%rsp),%eax
  xor    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int Com_BlockChecksum(void *buffer, int length) {
  int digest[4];
  unsigned int val;
  mdfour((unsigned char *)digest, (unsigned char *)buffer, length);
  val = digest[0] ^ digest[1] ^ digest[2] ^ digest[3];
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<Com_BlockChecksum>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %r8,%rsi
  call   <mdfour@plt>
  mov    (%rsp),%eax
  xor    0x4(%rsp),%eax
  xor    0x8(%rsp),%eax
  xor    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int Com_BlockChecksum(void *buffer, int length) {
  int digest[4];
  unsigned int val;
  mdfour((unsigned char *)digest, (unsigned char *)buffer, length);
  val = digest[0] ^ digest[1] ^ digest[2] ^ digest[3];
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Com_BlockChecksum>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %r8,%rsi
  call   <mdfour@plt>
  mov    (%rsp),%eax
  xor    0x4(%rsp),%eax
  xor    0x8(%rsp),%eax
  xor    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int Com_BlockChecksum(void *buffer, int length) {
  int digest[4];
  unsigned int val;
  mdfour((unsigned char *)digest, (unsigned char *)buffer, length);
  val = digest[0] ^ digest[1] ^ digest[2] ^ digest[3];
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <main_demo_aa@plt>
  mov    %eax,D3(%rip)
  mov    D3(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  static int res;
  res = main_demo_aa();
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <main_demo_aa@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  static int res;
  res = main_demo_aa();
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <main_demo_aa@plt>
```

assistant: ```c
int main(void) {
  static int res;
  res = main_demo_aa();
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <main_demo_aa@plt>
```

assistant: ```c
int main(void) {
  static int res;
  res = main_demo_aa();
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D51(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    D112(%rip),%rdi
  call   <puts@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D89(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L49
  mov    %rax,%rdi
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    D90(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L21
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L12:
  lea    D119(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L49:
  lea    D117(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L21:
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rdx
  mov    %rsi,%rcx
  imul   %rdx,%rcx
  lea    D84(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D51
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string
name: extract_symbolic_data
arguments: data_tag: D112
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string
name: extract_symbolic_data
arguments: data_tag: D89
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D90
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D119
data_type: string
name: extract_symbolic_data
arguments: data_tag: D20
data_type: string
name: extract_symbolic_data
arguments: data_tag: D117
data_type: string
name: extract_symbolic_data
arguments: data_tag: D84
data_type: string

tool: D51: Content-Type:text/html


tool: D3: <html>
<head>

tool: D112: <title>Resultado de la multiplicacion</title>

tool: D27: </head>
<h1>Resultado de la multiplicacion:</h1>

tool: D89: <body>

tool: D11: QUERY_STRING

tool: D90: m=%ld&n=%ld

tool: D7: <p>Error: los datos deben ser numericos.</p>

tool: D119: </body>

tool: D20: </html>

tool: D117: <p>Error pasando datos desde el formulario al prog. CGI</p>

tool: D84: <h3>El producto de %ld y %ld es %ld.</h3>

assistant: ```c
int main(void) {
  char *datos;
  long m, n;
  printf("Content-Type:text/html\n\n");
  printf("<html>\n<head>\n");
  printf("<title>Resultado de la multiplicacion</title>\n");
  printf("</head>\n<h1>Resultado de la multiplicacion:</h1>\n");
  printf("<body>\n");
  datos = getenv("QUERY_STRING");
  if (datos == NULL)
    printf("<p>Error pasando datos desde el formulario al prog. CGI</p>");
  else if (sscanf(datos, "m=%ld&n=%ld", &m, &n) != 2)
    printf("<p>Error: los datos deben ser numericos.</p>");
  else
    printf("<h3>El producto de %ld y %ld es %ld.</h3>", m, n, m * n);
  printf("</body>\n");
  printf("</html>\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D77(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  lea    D108(%rip),%rdi
  call   <puts@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    D47(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rdi
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    D89(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L4
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L49:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    D78(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rdx
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  mov    %rsi,%rcx
  imul   %rdx,%rcx
  call   <printf@plt>
  jmp    L49
L12:
  lea    D116(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L49
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D77
type_guessed: string
name: parse_data
arguments: label: D49
type_guessed: string
name: parse_data
arguments: label: D108
type_guessed: string
name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D47
type_guessed: string
name: parse_data
arguments: label: D89
type_guessed: string
name: parse_data
arguments: label: D40
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string
name: parse_data
arguments: label: D78
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string
name: parse_data
arguments: label: D116
type_guessed: string

tool: D77: Content-Type:text/html


tool: D49: <html>
<head>

tool: D108: <title>Resultado de la multiplicacion</title>

tool: D2: </head>
<h1>Resultado de la multiplicacion:</h1>

tool: D18: <body>

tool: D47: QUERY_STRING

tool: D89: m=%ld&n=%ld

tool: D40: <p>Error: los datos deben ser numericos.</p>

tool: D13: </body>

tool: D78: </html>

tool: D19: <h3>El producto de %ld y %ld es %ld.</h3>

tool: D116: <p>Error pasando datos desde el formulario al prog. CGI</p>

assistant: ```c
int main(void) {
  char *datos;
  long m, n;
  printf("Content-Type:text/html\n\n");
  printf("<html>\n<head>\n");
  printf("<title>Resultado de la multiplicacion</title>\n");
  printf("</head>\n<h1>Resultado de la multiplicacion:</h1>\n");
  printf("<body>\n");
  datos = getenv("QUERY_STRING");
  if (datos == NULL)
    printf("<p>Error pasando datos desde el formulario al prog. CGI</p>");
  else if (sscanf(datos, "m=%ld&n=%ld", &m, &n) != 2)
    printf("<p>Error: los datos deben ser numericos.</p>");
  else
    printf("<h3>El producto de %ld y %ld es %ld.</h3>", m, n, m * n);
  printf("</body>\n");
  printf("</html>\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D32(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D57(%rip),%rdi
  call   <puts@plt>
  lea    D60(%rip),%rdi
  call   <puts@plt>
  lea    D105(%rip),%rdi
  call   <puts@plt>
  lea    D73(%rip),%rdi
  call   <puts@plt>
  lea    D45(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L39
  mov    %rax,%rdi
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    D69(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L1
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L29:
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    D71(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rdx
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  mov    %rsi,%rcx
  imul   %rdx,%rcx
  call   <printf@plt>
  jmp    L29
L39:
  lea    D77(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L29
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D32
data_type: string
name: parse_data
arguments: data_label: D57
data_type: string
name: parse_data
arguments: data_label: D60
data_type: string
name: parse_data
arguments: data_label: D105
data_type: string
name: parse_data
arguments: data_label: D73
data_type: string
name: parse_data
arguments: data_label: D45
data_type: string
name: parse_data
arguments: data_label: D69
data_type: string
name: parse_data
arguments: data_label: D39
data_type: string
name: parse_data
arguments: data_label: D30
data_type: string
name: parse_data
arguments: data_label: D71
data_type: string
name: parse_data
arguments: data_label: D49
data_type: string
name: parse_data
arguments: data_label: D77
data_type: string

tool: D32: Content-Type:text/html


tool: D57: <html>
<head>

tool: D60: <title>Resultado de la multiplicacion</title>

tool: D105: </head>
<h1>Resultado de la multiplicacion:</h1>

tool: D73: <body>

tool: D45: QUERY_STRING

tool: D69: m=%ld&n=%ld

tool: D39: <p>Error: los datos deben ser numericos.</p>

tool: D30: </body>

tool: D71: </html>

tool: D49: <h3>El producto de %ld y %ld es %ld.</h3>

tool: D77: <p>Error pasando datos desde el formulario al prog. CGI</p>

assistant: ```c
int main(void) {
  char *datos;
  long m, n;
  printf("Content-Type:text/html\n\n");
  printf("<html>\n<head>\n");
  printf("<title>Resultado de la multiplicacion</title>\n");
  printf("</head>\n<h1>Resultado de la multiplicacion:</h1>\n");
  printf("<body>\n");
  datos = getenv("QUERY_STRING");
  if (datos == NULL)
    printf("<p>Error pasando datos desde el formulario al prog. CGI</p>");
  else if (sscanf(datos, "m=%ld&n=%ld", &m, &n) != 2)
    printf("<p>Error: los datos deben ser numericos.</p>");
  else
    printf("<h3>El producto de %ld y %ld es %ld.</h3>", m, n, m * n);
  printf("</body>\n");
  printf("</html>\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initLevel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L27:
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L33:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movb   $0x20,(%rdx,%rax,1)
  addl   $0x1,-0x8(%rbp)
L32:
  cmpl   $0x27,-0x8(%rbp)
  jle    L33
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x13,-0x4(%rbp)
  jle    L27
  mov    -0x20(%rbp),%rax
  movl   $0x14,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0xa,0x4(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void initLevel(char level[40][20], int snakePos[1][2]) {
  int currentRow;
  int currentCol;
  for (currentCol = 0; currentCol < 20; currentCol++) {
    for (currentRow = 0; currentRow < 40; currentRow++) {
      level[currentRow][currentCol] = ' ';
    }
  }
  snakePos[0][0] = 40 / 2;
  snakePos[0][1] = 20 / 2;
}
```
user: What is the c source code of the assembly code below?

```asm
<initLevel>:
  endbr64
  mov    %rdi,%rcx
  lea    0x320(%rdi),%rdx
  add    $0x334,%rcx
L19:
  lea    -0x320(%rdx),%rax
L12:
  movb   $0x20,(%rax)
  add    $0x14,%rax
  cmp    %rdx,%rax
  jne    L12
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L19
  movl   $0x14,(%rsi)
  movl   $0xa,0x4(%rsi)
  ret
```

assistant: ```c
void initLevel(char level[40][20], int snakePos[1][2]) {
  int currentRow;
  int currentCol;
  for (currentCol = 0; currentCol < 20; currentCol++) {
    for (currentRow = 0; currentRow < 40; currentRow++) {
      level[currentRow][currentCol] = ' ';
    }
  }
  snakePos[0][0] = 40 / 2;
  snakePos[0][1] = 20 / 2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<initLevel>:
  endbr64
  mov    %rdi,%rcx
  lea    0x320(%rdi),%rdx
  add    $0x334,%rcx
  nopl   (%rax)
L7:
  lea    -0x320(%rdx),%rax
  nop
L1:
  movb   $0x20,(%rax)
  add    $0x14,%rax
  cmp    %rdx,%rax
  jne    L1
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rdx
  jne    L7
  movabs $0xa00000014,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void initLevel(char level[40][20], int snakePos[1][2]) {
  int currentRow;
  int currentCol;
  for (currentCol = 0; currentCol < 20; currentCol++) {
    for (currentRow = 0; currentRow < 40; currentRow++) {
      level[currentRow][currentCol] = ' ';
    }
  }
  snakePos[0][0] = 40 / 2;
  snakePos[0][1] = 20 / 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<initLevel>:
  endbr64
  movdqa D17(%rip),%xmm0
  mov    %rsi,%rcx
  mov    %rdi,%rax
  lea    0x320(%rdi),%rdx
  nopl   0x0(%rax)
L8:
  movb   $0x20,0x10(%rax)
  add    $0x14,%rax
  movups %xmm0,-0x14(%rax)
  movb   $0x20,-0x3(%rax)
  movb   $0x20,-0x2(%rax)
  movb   $0x20,-0x1(%rax)
  cmp    %rdx,%rax
  jne    L8
  mov    D5(%rip),%rax
  mov    %rax,(%rcx)
  ret
```

tool_calls: name: read_data
arguments: tag: D17
type_guessed: byte[16]
name: read_data
arguments: tag: D5
type_guessed: byte[8]

tool: {"D17": [0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20]}

tool: {"D5": [0x14,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

assistant: ```c
void initLevel(char level[40][20], int snakePos[1][2]) {
  int currentRow;
  int currentCol;
  for (currentCol = 0; currentCol < 20; currentCol++) {
    for (currentRow = 0; currentRow < 40; currentRow++) {
      level[currentRow][currentCol] = ' ';
    }
  }
  snakePos[0][0] = 40 / 2;
  snakePos[0][1] = 20 / 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fast_InvSqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movabs $0xbfcdd6a18f6a6f55,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  shr    %rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x18(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  D6(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x18(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  D6(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type: f64
name: read_data
arguments: tag: D6
type: f64

tool: D15: 0.5

tool: D6: 3

assistant: ```c
double fast_InvSqrt(double x) {
  const unsigned long long int R = 0xBFCDD6A18F6A6F55ULL;
  union {
    double f;
    unsigned long long int ul;
  } y;
  y.f = x;
  y.ul = (R - y.ul) >> 1;
  y.f = 0.5 * y.f * (3.0 - x * y.f * y.f);
  y.f = 0.5 * y.f * (3.0 - x * y.f * y.f);
  return y.f;
}
```
user: What is the c source code of the assembly code below?

```asm
<fast_InvSqrt>:
  endbr64
  movabs $0xbfcdd6a18f6a6f55,%rax
  movq   %xmm0,-0x8(%rsp)
  sub    -0x8(%rsp),%rax
  shr    %rax
  movq   %rax,%xmm1
  movq   %rax,%xmm4
  mulsd  %xmm0,%xmm4
  mulsd  %xmm1,%xmm4
  movsd  D8(%rip),%xmm3
  movapd %xmm3,%xmm2
  subsd  %xmm4,%xmm2
  movsd  D12(%rip),%xmm4
  mulsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
  mulsd  %xmm4,%xmm1
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: f64
name: unpack_data
arguments: data_label: D12
data_type: f64

tool: D8: 3

tool: D12: 0.5

assistant: ```c
double fast_InvSqrt(double x) {
  const unsigned long long int R = 0xBFCDD6A18F6A6F55ULL;
  union {
    double f;
    unsigned long long int ul;
  } y;
  y.f = x;
  y.ul = (R - y.ul) >> 1;
  y.f = 0.5 * y.f * (3.0 - x * y.f * y.f);
  y.f = 0.5 * y.f * (3.0 - x * y.f * y.f);
  return y.f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fast_InvSqrt>:
  endbr64
  movq   %xmm0,-0x8(%rsp)
  movsd  D11(%rip),%xmm3
  movabs $0xbfcdd6a18f6a6f55,%rax
  sub    -0x8(%rsp),%rax
  shr    %rax
  movq   %rax,%xmm4
  movq   %rax,%xmm1
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm2
  movsd  D12(%rip),%xmm4
  mulsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm1
  subsd  %xmm0,%xmm3
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_guessed: f64
name: read_data
arguments: tag: D12
type_guessed: f64

tool: D11: 3

tool: D12: 0.5

assistant: ```c
double fast_InvSqrt(double x) {
  const unsigned long long int R = 0xBFCDD6A18F6A6F55ULL;
  union {
    double f;
    unsigned long long int ul;
  } y;
  y.f = x;
  y.ul = (R - y.ul) >> 1;
  y.f = 0.5 * y.f * (3.0 - x * y.f * y.f);
  y.f = 0.5 * y.f * (3.0 - x * y.f * y.f);
  return y.f;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fast_InvSqrt>:
  endbr64
  movq   %xmm0,-0x8(%rsp)
  movsd  D11(%rip),%xmm3
  movabs $0xbfcdd6a18f6a6f55,%rax
  sub    -0x8(%rsp),%rax
  shr    %rax
  movq   %rax,%xmm4
  movq   %rax,%xmm1
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm2
  movsd  D3(%rip),%xmm4
  mulsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm1
  subsd  %xmm0,%xmm3
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_infered: f64
name: unpack_data
arguments: data_tag: D3
type_infered: f64

tool: D11: 3

tool: D3: 0.5

assistant: ```c
double fast_InvSqrt(double x) {
  const unsigned long long int R = 0xBFCDD6A18F6A6F55ULL;
  union {
    double f;
    unsigned long long int ul;
  } y;
  y.f = x;
  y.ul = (R - y.ul) >> 1;
  y.f = 0.5 * y.f * (3.0 - x * y.f * y.f);
  y.f = 0.5 * y.f * (3.0 - x * y.f * y.f);
  return y.f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fac@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D29
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: string

tool: D15: input an integer number:

tool: D29: %d

tool: D14: %d! = %4ld

assistant: ```c
void main() {
  int m;
  long int sum;
  long int fac(int);
  printf("input an integer number:");
  scanf("%d", &m);
  sum = fac(m);
  printf("%d! = %4ld", m, sum);
}
```