user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<run>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  lea    (%rdi,%rdi,8),%ebx
  shl    $0x6,%ebx
  movslq %ebx,%rdi
  sub    $0x30,%rsp
  shl    $0x2,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L25
  lea    -0x1(%rbx),%eax
  pxor   %xmm2,%xmm2
  mov    %ebx,%edx
  movdqa D47(%rip),%xmm1
  cvtsi2ss %eax,%xmm2
  shr    $0x2,%edx
  movdqa D17(%rip),%xmm3
  mov    %rbp,%rax
  shl    $0x4,%rdx
  add    %rbp,%rdx
  shufps $0x0,%xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L26:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm3,%xmm1
  cvtdq2ps %xmm0,%xmm0
  divps  %xmm2,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L26
L25:
  xor    %esi,%esi
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movss  D59(%rip),%xmm4
  xor    %edx,%edx
  movss  D67(%rip),%xmm2
  movss  D36(%rip),%xmm1
  movss  D6(%rip),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  movaps %xmm4,%xmm3
  call   <FloatComputeBound@plt>
  xor    %esi,%esi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  mov    %r12d,%esi
  cvtsi2sdq 0x8(%rsp),%xmm2
  pxor   %xmm4,%xmm4
  movsd  D2(%rip),%xmm3
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x18(%rsp),%xmm1
  lea    D60(%rip),%rdi
  cvtsi2sdq (%rsp),%xmm4
  cvtsi2sd %ebx,%xmm0
  mulsd  D69(%rip),%xmm0
  subsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdq 0x10(%rsp),%xmm2
  mulsd  %xmm3,%xmm1
  divsd  %xmm3,%xmm0
  subsd  %xmm4,%xmm2
  divsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm1
  divsd  %xmm3,%xmm1
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D47
datatype: f32[4]
name: retrieve_data
arguments: tag: D17
datatype: byte[16]
name: retrieve_data
arguments: tag: D59
datatype: byte[4]
name: retrieve_data
arguments: tag: D67
datatype: byte[4]
name: retrieve_data
arguments: tag: D36
datatype: byte[4]
name: retrieve_data
arguments: tag: D6
datatype: byte[4]
name: retrieve_data
arguments: tag: D2
datatype: f64
name: retrieve_data
arguments: tag: D60
datatype: string
name: retrieve_data
arguments: tag: D69
datatype: byte[8]

tool: {"D47": [0.0,1.401298464324817e-45,2.802596928649634e-45,4.203895392974451e-45]}

tool: {"D17": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D59": [0x00,0x00,0xa0,0x3f]}

tool: {"D67": [0x00,0x00,0x00,0x3f]}

tool: {"D36": [0x00,0x00,0x00,0x3e]}

tool: {"D6": [0x00,0x00,0x90,0x3f]}

tool: D2: 1000

tool: D60: %d		%f


tool: {"D69": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0x10,0x40]}

assistant: ```c
void run(const int M) {
  float *A_cpu;
  const int N = 576;
  const int K = M * N;
  size_t bytes = sizeof(float) * K;
  A_cpu = (float *)malloc(bytes);
  int i;
  for (i = 0; i < K; i++) {
    A_cpu[i] = (float)i / (float)(K - 1);
  }
  struct timeval startTime, endTime;
  gettimeofday(&startTime, 0);
  FloatComputeBound(A_cpu, M * N, 1.125f, 0.125f, 0.5f, 1.25f, 1.25f, 0);
  gettimeofday(&endTime, 0);
  double ms = (((double)endTime.tv_sec - (double)startTime.tv_sec) * 1000.0 + ((double)endTime.tv_usec - (double)startTime.tv_usec) / 1000.0);
  double s = ms / 1000.0;
  double GFLOPs = (2 * 0 + 2048 + 2048) / 1.0e6 * 1024 * K / 1.0e3;
  double GFLOPsPerSec = (GFLOPs / s);
  printf("%d\t\t%f\n", M, GFLOPsPerSec);
  free(A_cpu);
}
```