ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0xdeadbeef,%esi
  mov    $0x0,%edi
  call   <bad@plt>
  cmp    $0xdeadbeef,%eax
  je     L18
L13:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L18:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L13
```

assistant: ```c
main() {
  if (sizeof(long) != 4)
    exit(0);
  if (bad(0, 0xdeadbeef) == 0xdeadbeef)
    abort();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <exit@plt>
  xor    %edi,%edi
  mov    $0xdeadbeef,%esi
  call   <bad@plt>
  cmp    $0xdeadbeef,%eax
  je     L5
L11:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L5:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L11
```

assistant: ```c
main() {
  if (sizeof(long) != 4)
    exit(0);
  if (bad(0, 0xdeadbeef) == 0xdeadbeef)
    abort();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <exit@plt>
  xor    %edi,%edi
  mov    $0xdeadbeef,%esi
  call   <bad@plt>
  cmp    $0xdeadbeef,%eax
  je     L9
L5:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L9:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L5
```

assistant: ```c
main() {
  if (sizeof(long) != 4)
    exit(0);
  if (bad(0, 0xdeadbeef) == 0xdeadbeef)
    abort();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bin2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x9,-0x4(%rbp)
  ja     L19
  movzbl -0x4(%rbp),%eax
  add    $0x30,%eax
  jmp    L0
L19:
  movzbl -0x4(%rbp),%eax
  add    $0x37,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char bin2hex(unsigned char a) {
  if (a < 10)
    return '0' + a;
  else
    return 'A' - 10 + a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bin2hex>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%dil
  cmovbe %edx,%eax
  ret
```

assistant: ```c
unsigned char bin2hex(unsigned char a) {
  if (a < 10)
    return '0' + a;
  else
    return 'A' - 10 + a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bin2hex>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%dil
  cmovbe %edx,%eax
  ret
```

assistant: ```c
unsigned char bin2hex(unsigned char a) {
  if (a < 10)
    return '0' + a;
  else
    return 'A' - 10 + a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bin2hex>:
  endbr64
  lea    0x30(%rdi),%edx
  lea    0x37(%rdi),%eax
  cmp    $0x9,%dil
  cmovbe %edx,%eax
  ret
```

assistant: ```c
unsigned char bin2hex(unsigned char a) {
  if (a < 10)
    return '0' + a;
  else
    return 'A' - 10 + a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  movl   $0xa,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L23
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L38
L23:
  nop
  movl   $0x0,-0x8(%rbp)
L43:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  je     L49
  subl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L43
L49:
  nop
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L19:
  mov    -0x8(%rbp),%eax
  sub    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L19
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int sum = 0;
  int i, n = 10;
  i = 0;
  for (;;) {
    if (i >= n) {
      break;
    }
    sum += i;
    i++;
  }
  for (i = 0;; i++) {
    if (i == n / 2) {
      break;
    }
    sum -= 1;
  }
  i = 0;
  for (; i < n / 3;) {
    sum -= i;
    i++;
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x25,%eax
  ret
```

assistant: ```c
int main() {
  int sum = 0;
  int i, n = 10;
  i = 0;
  for (;;) {
    if (i >= n) {
      break;
    }
    sum += i;
    i++;
  }
  for (i = 0;; i++) {
    if (i == n / 2) {
      break;
    }
    sum -= 1;
  }
  i = 0;
  for (; i < n / 3;) {
    sum -= i;
    i++;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x25,%eax
  ret
```

assistant: ```c
int main() {
  int sum = 0;
  int i, n = 10;
  i = 0;
  for (;;) {
    if (i >= n) {
      break;
    }
    sum += i;
    i++;
  }
  for (i = 0;; i++) {
    if (i == n / 2) {
      break;
    }
    sum -= 1;
  }
  i = 0;
  for (; i < n / 3;) {
    sum -= i;
    i++;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x25,%eax
  ret
```

assistant: ```c
int main() {
  int sum = 0;
  int i, n = 10;
  i = 0;
  for (;;) {
    if (i >= n) {
      break;
    }
    sum += i;
    i++;
  }
  for (i = 0;; i++) {
    if (i == n / 2) {
      break;
    }
    sum -= 1;
  }
  i = 0;
  for (; i < n / 3;) {
    sum -= i;
    i++;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MyGemm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L11:
  mov    -0x18(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    $0x4,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L7:
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    $0x4,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  imul   0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%r8
  mov    -0x10(%rbp),%eax
  imul   0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%r9
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%r10d
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  sub    $0x8,%rsp
  mov    0x20(%rbp),%edi
  push   %rdi
  push   %r8
  mov    0x10(%rbp),%edi
  push   %rdi
  mov    %r10d,%r8d
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <Gemm_P_Ger@plt>
  add    $0x20,%rsp
  addl   $0x4,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  addl   $0x4,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j += 4) {
    int jb = ((n - j) < (4) ? (n - j) : (4));
    for (int i = 0; i < m; i += 4) {
      int ib = ((m - i) < (4) ? (m - i) : (4));
      Gemm_P_Ger(ib, jb, k, &A[(0) * ldA + (i)], ldA, &B[(j)*ldB + (0)], ldB, &C[(j)*ldC + (i)], ldC);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,0x20(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %rcx,0x30(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %r9,0x38(%rsp)
  mov    0x80(%rsp),%r14d
  mov    0x90(%rsp),%r15d
  test   %esi,%esi
  jle    L38
  mov    %esi,%eax
  mov    %esi,0x14(%rsp)
  lea    0x0(,%r15,4),%esi
  mov    %esi,0x24(%rsp)
  lea    0x0(,%r14,4),%esi
  mov    %esi,0x28(%rsp)
  lea    -0x4(%rax),%edx
  sub    $0x1,%eax
  and    $0xfffffffc,%eax
  sub    %eax,%edx
  mov    %edx,0x2c(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x0,0x18(%rsp)
  lea    -0x4(%rdi),%edx
  lea    -0x1(%rdi),%eax
  and    $0xfffffffc,%eax
  sub    %eax,%edx
  mov    %edx,%r13d
L18:
  mov    $0x4,%eax
  mov    0x14(%rsp),%ecx
  cmp    %eax,%ecx
  cmovle %ecx,%eax
  mov    %eax,0x8(%rsp)
  mov    0x20(%rsp),%ebx
  test   %ebx,%ebx
  jle    L19
  movslq 0x1c(%rsp),%rax
  mov    0x38(%rsp),%rdx
  lea    (%rdx,%rax,8),%rax
  mov    %rax,(%rsp)
  mov    0x30(%rsp),%r12
  movslq 0x18(%rsp),%rax
  mov    0x88(%rsp),%rcx
  lea    (%rcx,%rax,8),%rbp
L34:
  mov    $0x4,%edi
  cmp    %edi,%ebx
  cmovle %ebx,%edi
  sub    $0x8,%rsp
  push   %r15
  push   %rbp
  push   %r14
  mov    0x20(%rsp),%r9
  mov    0x30(%rsp),%r8d
  mov    %r12,%rcx
  mov    0x2c(%rsp),%edx
  mov    0x28(%rsp),%esi
  mov    $0x0,%eax
  call   <Gemm_P_Ger@plt>
  sub    $0x4,%ebx
  add    $0x20,%r12
  add    $0x20,%rbp
  add    $0x20,%rsp
  cmp    %r13d,%ebx
  jne    L34
L19:
  subl   $0x4,0x14(%rsp)
  mov    0x14(%rsp),%eax
  mov    0x24(%rsp),%edx
  add    %edx,0x18(%rsp)
  mov    0x28(%rsp),%esi
  add    %esi,0x1c(%rsp)
  cmp    0x2c(%rsp),%eax
  jne    L18
L38:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j += 4) {
    int jb = ((n - j) < (4) ? (n - j) : (4));
    for (int i = 0; i < m; i += 4) {
      int ib = ((m - i) < (4) ? (m - i) : (4));
      Gemm_P_Ger(ib, jb, k, &A[(0) * ldA + (i)], ldA, &B[(j)*ldB + (0)], ldB, &C[(j)*ldC + (i)], ldC);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,0x20(%rsp)
  mov    %rcx,0x30(%rsp)
  mov    %r9,0x38(%rsp)
  test   %esi,%esi
  jle    L27
  mov    %esi,%eax
  mov    %esi,0x14(%rsp)
  mov    0x90(%rsp),%esi
  mov    %edx,%ebp
  lea    -0x4(%rax),%edx
  sub    $0x1,%eax
  lea    -0x4(%rdi),%r12d
  mov    %ebp,0x10(%rsp)
  shl    $0x2,%esi
  and    $0xfffffffc,%eax
  mov    %r8d,%r14d
  movl   $0x0,0x1c(%rsp)
  sub    %eax,%edx
  mov    %esi,0x24(%rsp)
  lea    -0x1(%rdi),%eax
  mov    0x80(%rsp),%esi
  and    $0xfffffffc,%eax
  mov    %edx,0x2c(%rsp)
  lea    0x0(,%rsi,4),%ecx
  sub    %eax,%r12d
  movl   $0x0,0x18(%rsp)
  mov    %ecx,0x28(%rsp)
  mov    %r12d,0xc(%rsp)
  nopl   0x0(%rax,%rax,1)
L4:
  mov    0x14(%rsp),%eax
  mov    $0x4,%r12d
  mov    0x20(%rsp),%ebx
  cmp    %r12d,%eax
  cmovle %eax,%r12d
  test   %ebx,%ebx
  jle    L35
  movslq 0x1c(%rsp),%rax
  mov    0x38(%rsp),%rsi
  mov    0x88(%rsp),%rdx
  mov    0x30(%rsp),%rbp
  lea    (%rsi,%rax,8),%r13
  movslq 0x18(%rsp),%rax
  lea    (%rdx,%rax,8),%r15
  mov    %r14d,%eax
  mov    %r15,%r14
  mov    %rbp,%r15
  mov    %eax,%ebp
  nopl   0x0(%rax)
L3:
  mov    $0x4,%edi
  mov    %r15,%rcx
  mov    %r13,%r9
  mov    %ebp,%r8d
  cmp    %edi,%ebx
  mov    %r12d,%esi
  cmovle %ebx,%edi
  sub    $0x8,%rsp
  sub    $0x4,%ebx
  add    $0x20,%r15
  mov    0x98(%rsp),%eax
  push   %rax
  push   %r14
  mov    0x98(%rsp),%eax
  add    $0x20,%r14
  push   %rax
  mov    0x30(%rsp),%edx
  xor    %eax,%eax
  call   <Gemm_P_Ger@plt>
  add    $0x20,%rsp
  cmp    0xc(%rsp),%ebx
  jne    L3
  mov    %ebp,%r14d
L35:
  mov    0x24(%rsp),%edx
  subl   $0x4,0x14(%rsp)
  add    %edx,0x18(%rsp)
  mov    0x14(%rsp),%eax
  mov    0x28(%rsp),%edx
  add    %edx,0x1c(%rsp)
  cmp    0x2c(%rsp),%eax
  jne    L4
L27:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j += 4) {
    int jb = ((n - j) < (4) ? (n - j) : (4));
    for (int i = 0; i < m; i += 4) {
      int ib = ((m - i) < (4) ? (m - i) : (4));
      Gemm_P_Ger(ib, jb, k, &A[(0) * ldA + (i)], ldA, &B[(j)*ldB + (0)], ldB, &C[(j)*ldC + (i)], ldC);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,0x38(%rsp)
  mov    %rcx,0x20(%rsp)
  test   %esi,%esi
  jle    L30
  test   %edi,%edi
  jle    L30
  mov    0x90(%rsp),%eax
  mov    %edx,%r12d
  lea    -0x4(%rsi),%edx
  mov    %r9,%r15
  mov    %esi,0x14(%rsp)
  mov    %r8d,%r13d
  shl    $0x2,%eax
  mov    %r12d,0x10(%rsp)
  cltq
  shl    $0x3,%rax
  mov    %rax,0x28(%rsp)
  mov    0x88(%rsp),%rax
  mov    %rax,0x18(%rsp)
  mov    0x80(%rsp),%eax
  shl    $0x2,%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,0x30(%rsp)
  mov    %esi,%eax
  sub    $0x1,%eax
  and    $0xfffffffc,%eax
  sub    %eax,%edx
  lea    -0x1(%rdi),%eax
  mov    %edx,0x3c(%rsp)
  and    $0xfffffffc,%eax
  lea    -0x4(%rdi),%edx
  sub    %eax,%edx
  mov    %edx,0xc(%rsp)
  nopl   0x0(%rax)
L16:
  mov    0x14(%rsp),%eax
  mov    $0x4,%ebp
  mov    0x20(%rsp),%r12
  mov    0x18(%rsp),%r14
  mov    0x38(%rsp),%ebx
  cmp    %ebp,%eax
  cmovle %eax,%ebp
  mov    %r13d,%eax
  mov    %r14,%r13
  mov    %r12,%r14
  mov    %eax,%r12d
L11:
  mov    $0x4,%edi
  mov    %r14,%rcx
  mov    %r15,%r9
  mov    %r12d,%r8d
  cmp    %edi,%ebx
  mov    %ebp,%esi
  cmovle %ebx,%edi
  sub    $0x8,%rsp
  sub    $0x4,%ebx
  add    $0x20,%r14
  mov    0x98(%rsp),%eax
  push   %rax
  push   %r13
  mov    0x98(%rsp),%eax
  add    $0x20,%r13
  push   %rax
  mov    0x30(%rsp),%edx
  xor    %eax,%eax
  call   <Gemm_P_Ger@plt>
  add    $0x20,%rsp
  cmp    %ebx,0xc(%rsp)
  jne    L11
  subl   $0x4,0x14(%rsp)
  mov    0x28(%rsp),%rsi
  mov    %r12d,%r13d
  add    %rsi,0x18(%rsp)
  mov    0x14(%rsp),%eax
  add    0x30(%rsp),%r15
  cmp    0x3c(%rsp),%eax
  jne    L16
L30:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j += 4) {
    int jb = ((n - j) < (4) ? (n - j) : (4));
    for (int i = 0; i < m; i += 4) {
      int ib = ((m - i) < (4) ? (m - i) : (4));
      Gemm_P_Ger(ib, jb, k, &A[(0) * ldA + (i)], ldA, &B[(j)*ldB + (0)], ldB, &C[(j)*ldC + (i)], ldC);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L28
L7:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x18(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L7
  mov    -0x1c(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sockMerchant@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D16
type_infered: string

tool: D2: %i

tool: D16: %d


assistant: ```c
int main() {
  int n;
  scanf("%i", &n);
  int *ar = malloc(sizeof(int) * n);
  for (int ar_i = 0; ar_i < n; ar_i++) {
    scanf("%i", &ar[ar_i]);
  }
  int result = sockMerchant(n, ar);
  printf("%d\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L3
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L17:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%edi
  add    $0x4,%rbp
  cmp    %ebx,%edi
  jg     L17
L3:
  mov    %r13,%rsi
  call   <sockMerchant@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D28
type_infered: string

tool: D5: %i

tool: D28: %d


assistant: ```c
int main() {
  int n;
  scanf("%i", &n);
  int *ar = malloc(sizeof(int) * n);
  for (int ar_i = 0; ar_i < n; ar_i++) {
    scanf("%i", &ar[ar_i]);
  }
  int result = sockMerchant(n, ar);
  printf("%d\n", result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%r13
  test   %edi,%edi
  jle    L4
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    %ebx,%edi
  jg     L17
L4:
  mov    %r13,%rsi
  call   <sockMerchant@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D8
data_type: string

tool: D0: %i

tool: D8: %d


assistant: ```c
int main() {
  int n;
  scanf("%i", &n);
  int *ar = malloc(sizeof(int) * n);
  for (int ar_i = 0; ar_i < n; ar_i++) {
    scanf("%i", &ar[ar_i]);
  }
  int result = sockMerchant(n, ar);
  printf("%d\n", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%r13
  test   %edi,%edi
  jle    L15
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    %ebx,%edi
  jg     L19
L15:
  mov    %r13,%rsi
  call   <sockMerchant@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D16
datatype: string

tool: D5: %i

tool: D16: %d


assistant: ```c
int main() {
  int n;
  scanf("%i", &n);
  int *ar = malloc(sizeof(int) * n);
  for (int ar_i = 0; ar_i < n; ar_i++) {
    scanf("%i", &ar[ar_i]);
  }
  int result = sockMerchant(n, ar);
  printf("%d\n", result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<indenter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L55
L58:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L14
  mov    $0x7c,%edi
  call   <putchar@plt>
  jmp    L48
L14:
  mov    $0x20,%edi
  call   <putchar@plt>
L48:
  addl   $0x1,-0x8(%rbp)
L55:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L58
  mov    $0x2b,%edi
  call   <putchar@plt>
  movl   $0x2,-0x4(%rbp)
  jmp    L23
L69:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L20
  mov    $0x2d,%edi
  call   <putchar@plt>
L20:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L69
  mov    $0x3e,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void indenter(int indentation, int trait) {
  for (int i = 1; i < indentation; i++)
    if (i % trait == 0)
      putchar('|');
    else
      putchar(' ');
  putchar('+');
  for (int i = 2; i < trait; i++)
    if (indentation % trait == 0)
      putchar('-');
  putchar('>');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<indenter>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  cmp    $0x1,%edi
  jle    L83
  mov    $0x1,%ebx
  jmp    L24
L76:
  mov    $0x20,%edi
  call   <putchar@plt>
L11:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L83
L24:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L76
  mov    $0x7c,%edi
  call   <putchar@plt>
  jmp    L11
L83:
  mov    $0x2b,%edi
  call   <putchar@plt>
  cmp    $0x2,%ebp
  jle    L90
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  mov    %edx,%r12d
  mov    $0x2,%ebx
  jmp    L14
L10:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L90
L14:
  test   %r12d,%r12d
  jne    L10
  mov    $0x2d,%edi
  call   <putchar@plt>
  jmp    L10
L90:
  mov    $0x3e,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void indenter(int indentation, int trait) {
  for (int i = 1; i < indentation; i++)
    if (i % trait == 0)
      putchar('|');
    else
      putchar(' ');
  putchar('+');
  for (int i = 2; i < trait; i++)
    if (indentation % trait == 0)
      putchar('-');
  putchar('>');
}
```
user: Translate the below assembly code into C programming language:

```asm
<indenter>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x1,%edi
  jle    L18
  mov    $0x1,%ebx
  jmp    L83
  nopl   0x0(%rax)
L70:
  mov    $0x7c,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  je     L18
L83:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  je     L70
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L83
L18:
  mov    $0x2b,%edi
  call   <putchar@plt>
  cmp    $0x2,%ebp
  jle    L82
  mov    %r12d,%eax
  mov    $0x2,%ebx
  cltd
  idiv   %ebp
  mov    %edx,%r12d
  jmp    L11
  nopl   0x0(%rax)
L90:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L82
L11:
  test   %r12d,%r12d
  jne    L90
  mov    $0x2d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L11
L82:
  pop    %rbx
  mov    $0x3e,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
```

assistant: ```c
void indenter(int indentation, int trait) {
  for (int i = 1; i < indentation; i++)
    if (i % trait == 0)
      putchar('|');
    else
      putchar(' ');
  putchar('+');
  for (int i = 2; i < trait; i++)
    if (indentation % trait == 0)
      putchar('-');
  putchar('>');
}
```