ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<to_fd>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D8(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L24
  lea    D3(%rip),%rdi
  call   <fail@plt>
L24:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    $0x1,%eax
  je     L5
  lea    D26(%rip),%rdi
  call   <fail@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D3
datatype: string
name: unpack_data
arguments: data_label: D26
datatype: string

tool: D8: %hhx

tool: D3: scanf

tool: D26: write

assistant: ```c
void to_fd(int fd) {
  char byte;
  if (scanf("%hhx", &byte) != 1)
    fail("scanf");
  if (write(fd, (const void *)&byte, 1) != 1)
    fail("write");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<to_fd>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D4(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L2
  lea    D23(%rip),%rdi
  call   <fail@plt>
L2:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    $0x1,%eax
  je     L15
  lea    D9(%rip),%rdi
  call   <fail@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string
name: disassemble_data
arguments: tag: D23
type_guessed: string
name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D4: %hhx

tool: D23: scanf

tool: D9: write

assistant: ```c
void to_fd(int fd) {
  char byte;
  if (scanf("%hhx", &byte) != 1)
    fail("scanf");
  if (write(fd, (const void *)&byte, 1) != 1)
    fail("write");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_string_into_new_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *copy_string_into_new_buf(const char *src) {
  const int len = strlen(src) + 1;
  char *buf = malloc(len);
  assert(buf && "Failed to alloc");
  strncpy(buf, src, len);
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_string_into_new_buf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_string_into_new_buf(const char *src) {
  const int len = strlen(src) + 1;
  char *buf = malloc(len);
  assert(buf && "Failed to alloc");
  strncpy(buf, src, len);
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<copy_string_into_new_buf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *copy_string_into_new_buf(const char *src) {
  const int len = strlen(src) + 1;
  char *buf = malloc(len);
  assert(buf && "Failed to alloc");
  strncpy(buf, src, len);
  return buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_string_into_new_buf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *copy_string_into_new_buf(const char *src) {
  const int len = strlen(src) + 1;
  char *buf = malloc(len);
  assert(buf && "Failed to alloc");
  strncpy(buf, src, len);
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <recurser_void@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  recurser_void();
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <recurser_void@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  recurser_void();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <recurser_void@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  recurser_void();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <recurser_void@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  recurser_void();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_unlock@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  mov    -0x4(%rbp),%eax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <syserr@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: unlock failed

assistant: ```c
void unlock(pthread_mutex_t *l) {
  int err;
  if ((err = pthread_mutex_unlock(l)) != 0)
    syserr(err, "unlock failed");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<unlock>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutex_unlock@plt>
  test   %eax,%eax
  jne    L10
L8:
  add    $0x8,%rsp
  ret
L10:
  lea    D3(%rip),%rsi
  mov    %eax,%edi
  call   <syserr@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: unlock failed

assistant: ```c
void unlock(pthread_mutex_t *l) {
  int err;
  if ((err = pthread_mutex_unlock(l)) != 0)
    syserr(err, "unlock failed");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unlock>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutex_unlock@plt>
  test   %eax,%eax
  jne    L3
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  lea    D6(%rip),%rsi
  mov    %eax,%edi
  add    $0x8,%rsp
  jmp    1060 <syserr@plt>
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: unlock failed

assistant: ```c
void unlock(pthread_mutex_t *l) {
  int err;
  if ((err = pthread_mutex_unlock(l)) != 0)
    syserr(err, "unlock failed");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unlock>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutex_unlock@plt>
  test   %eax,%eax
  jne    L1
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  lea    D3(%rip),%rsi
  mov    %eax,%edi
  add    $0x8,%rsp
  jmp    1060 <syserr@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: unlock failed

assistant: ```c
void unlock(pthread_mutex_t *l) {
  int err;
  if ((err = pthread_mutex_unlock(l)) != 0)
    syserr(err, "unlock failed");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <uname@plt>
  test   %rax,%rax
  je     L15
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L17
L15:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D41
datatype: string
name: extract_symbolic_data
arguments: data_label: D32
datatype: string
name: extract_symbolic_data
arguments: data_label: D20
datatype: string
name: extract_symbolic_data
arguments: data_label: D52
datatype: string
name: extract_symbolic_data
arguments: data_label: D36
datatype: string
name: extract_symbolic_data
arguments: data_label: D57
datatype: string

tool: D41: uname

tool: D32: sysname:%s


tool: D20: nodename:%s


tool: D52: release:%s


tool: D36: version:%s


tool: D57: machine:%s


assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname name;
  if (uname(&name) != 0) {
    perror("uname");
    return -1;
  }
  printf("sysname:%s\n", name.sysname);
  printf("nodename:%s\n", name.nodename);
  printf("release:%s\n", name.release);
  printf("version:%s\n", name.version);
  printf("machine:%s\n", name.machine);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  test   %rax,%rax
  jne    L18
  mov    (%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L15:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x38,%rsp
  ret
L18:
  lea    D46(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L15
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string
name: parse_data
arguments: data_label: D50
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D31
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D46
type_infered: string

tool: D5: sysname:%s


tool: D50: nodename:%s


tool: D0: release:%s


tool: D31: version:%s


tool: D1: machine:%s


tool: D46: uname

assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname name;
  if (uname(&name) != 0) {
    perror("uname");
    return -1;
  }
  printf("sysname:%s\n", name.sysname);
  printf("nodename:%s\n", name.nodename);
  printf("release:%s\n", name.release);
  printf("version:%s\n", name.version);
  printf("machine:%s\n", name.machine);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  test   %rax,%rax
  jne    L0
  mov    (%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L29:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x38,%rsp
  ret
L0:
  lea    D46(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%eax
  jmp    L29
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
data_type: string
name: parse_data
arguments: tag: D50
data_type: string
name: parse_data
arguments: tag: D4
data_type: string
name: parse_data
arguments: tag: D21
data_type: string
name: parse_data
arguments: tag: D44
data_type: string
name: parse_data
arguments: tag: D46
data_type: string

tool: D11: sysname:%s


tool: D50: nodename:%s


tool: D4: release:%s


tool: D21: version:%s


tool: D44: machine:%s


tool: D46: uname

assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname name;
  if (uname(&name) != 0) {
    perror("uname");
    return -1;
  }
  printf("sysname:%s\n", name.sysname);
  printf("nodename:%s\n", name.nodename);
  printf("release:%s\n", name.release);
  printf("version:%s\n", name.version);
  printf("machine:%s\n", name.machine);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  test   %rax,%rax
  jne    L4
  mov    (%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L19:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x38,%rsp
  ret
L4:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%eax
  jmp    L19
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D41
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D40
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D41: sysname:%s


tool: D12: nodename:%s


tool: D18: release:%s


tool: D40: version:%s


tool: D27: machine:%s


tool: D6: uname

assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname name;
  if (uname(&name) != 0) {
    perror("uname");
    return -1;
  }
  printf("sysname:%s\n", name.sysname);
  printf("nodename:%s\n", name.nodename);
  printf("release:%s\n", name.release);
  printf("version:%s\n", name.version);
  printf("machine:%s\n", name.machine);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parseadminlevel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <findLine@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  jmp    L33
L15:
  cmpl   $0x1d,-0x1c(%rbp)
  jle    L12
  mov    -0x1c(%rbp),%eax
  sub    $0x1e,%eax
  jmp    L33
L12:
  mov    $0x0,%eax
L33:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: string

tool: D6: Admn:

assistant: ```c
int parseadminlevel(FILE *plr_file, int level) {
  char *fromFile = findLine(plr_file, "Admn:");
  if (fromFile != NULL)
    return atoi(fromFile);
  if (level >= 30)
    return level - 30;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<parseadminlevel>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  lea    D3(%rip),%rsi
  call   <findLine@plt>
  test   %rax,%rax
  jne    L14
  lea    -0x1e(%rbx),%eax
  cmp    $0x1d,%ebx
  mov    $0x0,%edx
  cmovle %edx,%eax
L11:
  pop    %rbx
  ret
L14:
  mov    %rax,%rdi
  call   <atoi@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: Admn:

assistant: ```c
int parseadminlevel(FILE *plr_file, int level) {
  char *fromFile = findLine(plr_file, "Admn:");
  if (fromFile != NULL)
    return atoi(fromFile);
  if (level >= 30)
    return level - 30;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parseadminlevel>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  lea    D2(%rip),%rsi
  call   <findLine@plt>
  test   %rax,%rax
  jne    L3
  lea    -0x1e(%rbx),%eax
  xor    %edx,%edx
  cmp    $0x1d,%ebx
  pop    %rbx
  cmovle %edx,%eax
  ret
  nopl   (%rax)
L3:
  mov    %rax,%rdi
  pop    %rbx
  jmp    1060 <atoi@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: Admn:

assistant: ```c
int parseadminlevel(FILE *plr_file, int level) {
  char *fromFile = findLine(plr_file, "Admn:");
  if (fromFile != NULL)
    return atoi(fromFile);
  if (level >= 30)
    return level - 30;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parseadminlevel>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  lea    D3(%rip),%rsi
  call   <findLine@plt>
  test   %rax,%rax
  jne    L4
  lea    -0x1e(%rbx),%eax
  xor    %edx,%edx
  cmp    $0x1d,%ebx
  pop    %rbx
  cmovle %edx,%eax
  ret
  nopl   (%rax)
L4:
  mov    %rax,%rdi
  pop    %rbx
  jmp    1060 <atoi@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Admn:

assistant: ```c
int parseadminlevel(FILE *plr_file, int level) {
  char *fromFile = findLine(plr_file, "Admn:");
  if (fromFile != NULL)
    return atoi(fromFile);
  if (level >= 30)
    return level - 30;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bigmult>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r8d
  mov    %rdx,%rbx
  lea    0xfa0(%rdx),%rdx
  mov    %rbx,%rax
L4:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
  mov    (%rdi),%esi
  test   %esi,%esi
  jle    L39
  lea    0x4(%rbx),%rcx
  add    $0x4,%rdi
  lea    -0x1(%rsi),%eax
  lea    0x8(%rbx,%rax,4),%r9
L25:
  mov    %r8d,%edx
  imul   (%rdi),%edx
  add    (%rcx),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%eax
  add    %eax,0x4(%rcx)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,(%rcx)
  add    $0x4,%rcx
  add    $0x4,%rdi
  cmp    %r9,%rcx
  jne    L25
L39:
  lea    0x1(%rsi),%ebp
  movslq %ebp,%rax
  shl    $0x2,%rax
  lea    (%rbx,%rax,1),%rdi
  mov    (%rdi),%edx
  cmp    $0x9,%edx
  jle    L6
  lea    0x4(%rbx,%rax,1),%rcx
L11:
  mov    %rdi,%rsi
  mov    %rcx,%rdi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rcx)
  mov    (%rsi),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,(%rsi)
  mov    %ebp,%esi
  add    $0x1,%ebp
  add    $0x4,%rcx
  mov    -0x4(%rcx),%edx
  cmp    $0x9,%edx
  jg     L11
L6:
  test   %edx,%edx
  cmove  %esi,%ebp
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L57
  movslq %ebp,%rbp
  lea    D2(%rip),%r12
L60:
  mov    (%rbx,%rbp,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%rbp
  test   %ebp,%ebp
  jg     L60
L57:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D17: Big integers multi small integer: 

tool: D2: %d

assistant: ```c
int bigmult(int a[], unsigned int b, int c[]) {
  int len, i;
  for (i = 0; i < 1000; i++)
    c[i] = 0;
  len = a[0];
  for (i = 1; i <= len; i++) {
    c[i] += a[i] * b;
    c[i + 1] += c[i] / 10;
    c[i] %= 10;
  }
  while (c[++len] >= 10) {
    c[len + 1] = c[len] / 10;
    c[len] %= 10;
  }
  if (c[len] == 0)
    len--;
  printf("Big integers multi small integer: ");
  for (i = len; i >= 1; i--)
    printf("%d", c[i]);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bigmult>:
  endbr64
  push   %r12
  mov    %rdi,%r9
  xor    %eax,%eax
  mov    %esi,%r8d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  add    $0x8,%rdx
  movq   $0x0,-0x8(%rdx)
  mov    %rbx,%rcx
  movq   $0x0,0xf90(%rdx)
  mov    %rdx,%rdi
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0xfa0,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  mov    (%r9),%esi
  test   %esi,%esi
  jle    L31
  lea    -0x1(%rsi),%eax
  lea    0x4(%r9),%rdi
  lea    0x4(%rbx),%rcx
  lea    (%rdx,%rax,4),%r9
  nopl   0x0(%rax)
L16:
  mov    (%rdi),%edx
  add    $0x4,%rdi
  imul   %r8d,%edx
  add    (%rcx),%edx
  movslq %edx,%rax
  mov    %edx,%r10d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%r10d
  sar    $0x22,%rax
  sub    %r10d,%eax
  add    %eax,0x4(%rcx)
  add    $0x4,%rcx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rcx)
  cmp    %rcx,%r9
  jne    L16
L31:
  lea    0x1(%rsi),%ebp
  movslq %ebp,%rdx
  shl    $0x2,%rdx
  lea    (%rbx,%rdx,1),%rdi
  mov    (%rdi),%eax
  cmp    $0x9,%eax
  jle    L58
  lea    0x4(%rbx,%rdx,1),%rcx
  mov    $0xcccccccd,%r8d
  nopw   0x0(%rax,%rax,1)
L19:
  imul   %r8,%rax
  mov    %rdi,%rsi
  mov    %rcx,%rdi
  add    $0x4,%rcx
  shr    $0x23,%rax
  mov    %eax,-0x4(%rcx)
  movslq (%rsi),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%r9d
  sar    $0x1f,%r9d
  sar    $0x22,%rax
  sub    %r9d,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,(%rsi)
  mov    -0x4(%rcx),%eax
  mov    %ebp,%esi
  add    $0x1,%ebp
  cmp    $0x9,%eax
  jg     L19
L58:
  test   %eax,%eax
  lea    D1(%rip),%rdi
  cmove  %esi,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L15
  movslq %ebp,%rbp
  lea    D4(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L59:
  mov    (%rbx,%rbp,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    $0x1,%rbp
  call   <printf@plt>
  test   %ebp,%ebp
  jg     L59
L15:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string

tool: D1: Big integers multi small integer: 

tool: D4: %d

assistant: ```c
int bigmult(int a[], unsigned int b, int c[]) {
  int len, i;
  for (i = 0; i < 1000; i++)
    c[i] = 0;
  len = a[0];
  for (i = 1; i <= len; i++) {
    c[i] += a[i] * b;
    c[i + 1] += c[i] / 10;
    c[i] %= 10;
  }
  while (c[++len] >= 10) {
    c[len + 1] = c[len] / 10;
    c[len] %= 10;
  }
  if (c[len] == 0)
    len--;
  printf("Big integers multi small integer: ");
  for (i = len; i >= 1; i--)
    printf("%d", c[i]);
  printf("\n");
}
```