user: 这段汇编代码用C语言表示是什么样的？

```asm
<my_main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L8
L41:
  mov    $0x64,%edi
  lea    D13(%rip),%r15
  lea    D62(%rip),%r14
  call   <scgc_new@plt>
  lea    D10(%rip),%rsi
  lea    D3(%rip),%rdi
  mov    %rax,0x10(%rsp)
  lea    D68(%rip),%r13
  lea    D74(%rip),%r12
  call   <fopen@plt>
  mov    0x10(%rsp),%rdx
  lea    0x10(%rsp),%rcx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fprintf@plt>
  movl   $0x186a0,0xc(%rsp)
  nop
L44:
  mov    0x10(%rsp),%rbx
  mov    $0x20,%edi
  call   <scgc_new@plt>
  mov    $0x20,%edi
  mov    %rax,(%rbx)
  mov    0x10(%rsp),%rbx
  call   <scgc_new@plt>
  mov    $0x20,%edi
  mov    %rax,0x8(%rbx)
  mov    0x10(%rsp),%rbx
  call   <scgc_new@plt>
  mov    $0x20,%edi
  mov    %rax,0x10(%rbx)
  mov    0x10(%rsp),%rax
  mov    0x10(%rax),%rbx
  call   <scgc_new@plt>
  mov    $0x20,%edi
  mov    %rax,(%rbx)
  mov    0x10(%rsp),%rax
  mov    0x10(%rax),%rbx
  call   <scgc_new@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  mov    %rax,0x8(%rbx)
  mov    0x10(%rsp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rdx
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    0x10(%rsp),%rax
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    0x8(%rax),%rax
  mov    (%rax),%rdx
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    0x10(%rsp),%rax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    0x10(%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rdx
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    0x10(%rsp),%rax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    0x10(%rax),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rdx
  xor    %eax,%eax
  call   <fprintf@plt>
  subl   $0x1,0xc(%rsp)
  jne    L44
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    0x8(%rsi),%rdi
  lea    D11(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L41
  call   <scgc_enable_print_gc_info@plt>
  jmp    L41
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D62
type_guessed: string
name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string
name: disassemble_data
arguments: label: D68
type_guessed: string
name: disassemble_data
arguments: label: D74
type_guessed: string
name: disassemble_data
arguments: label: D7
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string

tool: D13: test1 %p


tool: D62: test2 %p


tool: D10: w

tool: D3: .tmp_out

tool: D68: test3 %p


tool: D74: test4 %p


tool: D7: my %p %p


tool: D11: -enable_gc_info

assistant: ```c
int my_main(int argc, char *argv[]) {
  if (argc == 2 && strcmp(argv[1], "-enable_gc_info") == 0) {
    scgc_enable_print_gc_info();
  }
  void **my = scgc_new(100);
  FILE *fp = fopen(".tmp_out", "w");
  fprintf(fp, "my %p %p\n", (void *)my, (void *)&my);
  for (int i = 0; i < 100000; i++) {
    my[0] = scgc_new(32);
    my[1] = scgc_new(32);
    my[2] = scgc_new(32);
    ((void **)my[2])[0] = scgc_new(32);
    ((void **)my[2])[1] = scgc_new(32);
    fprintf(fp, "test1 %p\n", ((void **)my[0])[0]);
    fprintf(fp, "test2 %p\n", ((void **)my[1])[0]);
    fprintf(fp, "test3 %p\n", ((void ***)my[2])[0][0]);
    fprintf(fp, "test4 %p\n", ((void ***)my[2])[1][0]);
  }
  fclose(fp);
  return 0;
}
```