ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<___pthread_spin_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <dlock_unlock@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <o_pthread_spin_unlock@plt>
  leave
  ret
```

assistant: ```c
int ___pthread_spin_unlock(pthread_spinlock_t *spin, char *lname, char *fn, int ln) {
  ;
  dlock_unlock(spin, (int)pthread_self());
  return o_pthread_spin_unlock(spin);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<___pthread_spin_unlock>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <dlock_unlock@plt>
  mov    %rbx,%rdi
  call   <o_pthread_spin_unlock@plt>
  pop    %rbx
  ret
```

assistant: ```c
int ___pthread_spin_unlock(pthread_spinlock_t *spin, char *lname, char *fn, int ln) {
  ;
  dlock_unlock(spin, (int)pthread_self());
  return o_pthread_spin_unlock(spin);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<___pthread_spin_unlock>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <pthread_self@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <dlock_unlock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <o_pthread_spin_unlock@plt>
```

assistant: ```c
int ___pthread_spin_unlock(pthread_spinlock_t *spin, char *lname, char *fn, int ln) {
  ;
  dlock_unlock(spin, (int)pthread_self());
  return o_pthread_spin_unlock(spin);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<___pthread_spin_unlock>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <pthread_self@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <dlock_unlock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <o_pthread_spin_unlock@plt>
```

assistant: ```c
int ___pthread_spin_unlock(pthread_spinlock_t *spin, char *lname, char *fn, int ln) {
  ;
  dlock_unlock(spin, (int)pthread_self());
  return o_pthread_spin_unlock(spin);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shelld_reap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  nop
L4:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void shelld_reap(int sig) {
  pid_t pid;
  while ((pid = waitpid(-1, NULL, WNOHANG)) > 0) {
    ;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<shelld_reap>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
L8:
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %eax,%eax
  jg     L8
  pop    %rbx
  ret
```

assistant: ```c
void shelld_reap(int sig) {
  pid_t pid;
  while ((pid = waitpid(-1, NULL, WNOHANG)) > 0) {
    ;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<shelld_reap>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %eax,%eax
  jg     L9
  pop    %rbx
  ret
```

assistant: ```c
void shelld_reap(int sig) {
  pid_t pid;
  while ((pid = waitpid(-1, NULL, WNOHANG)) > 0) {
    ;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shelld_reap>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %eax,%eax
  jg     L9
  pop    %rbx
  ret
```

assistant: ```c
void shelld_reap(int sig) {
  pid_t pid;
  while ((pid = waitpid(-1, NULL, WNOHANG)) > 0) {
    ;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L0:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  cmpl   $0x9,-0x4(%rbp)
  ja     L0
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
size_t int_len(int nb) {
  int count;
  unsigned int n;
  n = nb < 0 ? -nb : nb;
  count = nb < 0 ? 1 : 0;
  while (n >= 10) {
    n /= 10;
    count++;
  }
  return (count + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<int_len>:
  endbr64
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  shr    $0x1f,%edi
  cmp    $0x9,%edx
  jbe    L1
  mov    $0xcccccccd,%ecx
L19:
  mov    %edx,%eax
  mov    %edx,%edx
  imul   %rcx,%rdx
  shr    $0x23,%rdx
  add    $0x1,%edi
  cmp    $0x63,%eax
  ja     L19
L1:
  lea    0x1(%rdi),%eax
  cltq
  ret
```

assistant: ```c
size_t int_len(int nb) {
  int count;
  unsigned int n;
  n = nb < 0 ? -nb : nb;
  count = nb < 0 ? 1 : 0;
  while (n >= 10) {
    n /= 10;
    count++;
  }
  return (count + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_len>:
  endbr64
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  shr    $0x1f,%edi
  cmp    $0x9,%edx
  jle    L8
  mov    $0xcccccccd,%ecx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %edx,%edx
  add    $0x1,%edi
  mov    %rdx,%rax
  imul   %rcx,%rdx
  shr    $0x23,%rdx
  cmp    $0x63,%eax
  ja     L9
L8:
  lea    0x1(%rdi),%eax
  cltq
  ret
```

assistant: ```c
size_t int_len(int nb) {
  int count;
  unsigned int n;
  n = nb < 0 ? -nb : nb;
  count = nb < 0 ? 1 : 0;
  while (n >= 10) {
    n /= 10;
    count++;
  }
  return (count + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<int_len>:
  endbr64
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  shr    $0x1f,%edi
  cmp    $0x9,%edx
  jle    L11
  mov    $0xcccccccd,%ecx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %edx,%edx
  add    $0x1,%edi
  mov    %rdx,%rax
  imul   %rcx,%rdx
  shr    $0x23,%rdx
  cmp    $0x63,%eax
  ja     L16
L11:
  lea    0x1(%rdi),%eax
  cltq
  ret
```

assistant: ```c
size_t int_len(int nb) {
  int count;
  unsigned int n;
  n = nb < 0 ? -nb : nb;
  count = nb < 0 ? 1 : 0;
  while (n >= 10) {
    n /= 10;
    count++;
  }
  return (count + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<point_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L7:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L5:
  cmpl   $0x2,-0xc(%rbp)
  jle    L7
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double point_product(double *vec_1, double *vec_2) {
  double point;
  int i;
  point = 0.0;
  for (i = 0; i < 3; i++) {
    point += vec_1[i] * vec_2[i];
  }
  return point;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<point_product>:
  endbr64
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L2:
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L2
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double point_product(double *vec_1, double *vec_2) {
  double point;
  int i;
  point = 0.0;
  for (i = 0; i < 3; i++) {
    point += vec_1[i] * vec_2[i];
  }
  return point;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<point_product>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
L8:
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    $0x18,%rax
  jne    L8
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double point_product(double *vec_1, double *vec_2) {
  double point;
  int i;
  point = 0.0;
  for (i = 0; i < 3; i++) {
    point += vec_1[i] * vec_2[i];
  }
  return point;
}
```
user: What is the c source code of the assembly code below?

```asm
<point_product>:
  endbr64
  movupd (%rdi),%xmm0
  movupd (%rsi),%xmm2
  pxor   %xmm1,%xmm1
  mulpd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rsi),%xmm0
  mulsd  0x10(%rdi),%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double point_product(double *vec_1, double *vec_2) {
  double point;
  int i;
  point = 0.0;
  for (i = 0; i < 3; i++) {
    point += vec_1[i] * vec_2[i];
  }
  return point;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_tokens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L62
L72:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L33
  jmp    L70
L118:
  addq   $0x1,-0x8(%rbp)
L70:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L118
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
  jmp    L119
L114:
  addq   $0x1,-0x8(%rbp)
L119:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L114
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
  jmp    L14
L33:
  nop
L14:
  mov    -0xc(%rbp),%eax
L62:
  pop    %rbp
  ret
```

assistant: ```c
int get_tokens(char *line, char delimiter, char **tokens, int tokens_length) {
  int count = 0;
  char *position = line;
  if (!line) {
    return 0;
  }
  while (*position != '\0') {
    if (count >= tokens_length) {
      break;
    }
    while (*position == delimiter) {
      position++;
    }
    if (*position != '\0') {
      tokens[count] = position;
      count++;
      while (*position != delimiter && *position != '\0') {
        position++;
      }
      if (*position != '\0') {
        *position = '\0';
        position++;
      }
    }
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_tokens>:
  endbr64
  test   %rdi,%rdi
  je     L3
  mov    $0x0,%r8d
L39:
  mov    %r8d,%r9d
  jmp    L70
L4:
  test   %al,%al
  jne    L35
L70:
  movzbl (%rdi),%eax
  cmp    %r8d,%ecx
  jle    L16
  test   %al,%al
  je     L16
  cmp    %sil,%al
  jne    L35
L130:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    %sil,%al
  je     L130
  jmp    L4
L35:
  mov    %rdi,(%rdx,%r8,8)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  cmp    %al,%sil
  je     L17
L29:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  cmp    %sil,%al
  jne    L29
L17:
  test   %al,%al
  je     L46
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
L46:
  add    $0x1,%r8
  jmp    L39
L3:
  mov    $0x0,%r9d
L16:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int get_tokens(char *line, char delimiter, char **tokens, int tokens_length) {
  int count = 0;
  char *position = line;
  if (!line) {
    return 0;
  }
  while (*position != '\0') {
    if (count >= tokens_length) {
      break;
    }
    while (*position == delimiter) {
      position++;
    }
    if (*position != '\0') {
      tokens[count] = position;
      count++;
      while (*position != delimiter && *position != '\0') {
        position++;
      }
      if (*position != '\0') {
        *position = '\0';
        position++;
      }
    }
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_tokens>:
  endbr64
  test   %rdi,%rdi
  je     L67
  xor    %r9d,%r9d
L11:
  movzbl (%rdi),%eax
  cmp    %r9d,%ecx
  mov    %r9d,%r10d
  setle  %r8b
  test   %al,%al
  je     L110
  test   %r8b,%r8b
  jne    L110
  cmp    %al,%sil
  jne    L120
  nopl   0x0(%rax,%rax,1)
L91:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    %sil,%al
  je     L91
  test   %al,%al
  jne    L120
L110:
  mov    %r10d,%eax
  ret
  nopl   (%rax)
L120:
  mov    %rdi,(%rdx,%r9,8)
  movzbl (%rdi),%eax
  cmp    %al,%sil
  jne    L88
  jmp    L101
  cs nopw 0x0(%rax,%rax,1)
L115:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    %sil,%al
  je     L101
L88:
  test   %al,%al
  jne    L115
L0:
  add    $0x1,%r9
  jmp    L11
L101:
  test   %sil,%sil
  je     L0
  movb   $0x0,(%rdi)
  add    $0x1,%r9
  add    $0x1,%rdi
  jmp    L11
L67:
  xor    %r10d,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int get_tokens(char *line, char delimiter, char **tokens, int tokens_length) {
  int count = 0;
  char *position = line;
  if (!line) {
    return 0;
  }
  while (*position != '\0') {
    if (count >= tokens_length) {
      break;
    }
    while (*position == delimiter) {
      position++;
    }
    if (*position != '\0') {
      tokens[count] = position;
      count++;
      while (*position != delimiter && *position != '\0') {
        position++;
      }
      if (*position != '\0') {
        *position = '\0';
        position++;
      }
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_tokens>:
  endbr64
  test   %rdi,%rdi
  je     L75
  movzbl (%rdi),%eax
  xor    %r9d,%r9d
L28:
  cmp    %r9d,%ecx
  mov    %r9d,%r10d
  setle  %r8b
  test   %al,%al
  je     L80
  test   %r8b,%r8b
  jne    L80
  cmp    %al,%sil
  jne    L1
  nopl   0x0(%rax,%rax,1)
L95:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    %sil,%al
  je     L95
  test   %al,%al
  jne    L1
L80:
  mov    %r10d,%eax
  ret
  nopl   (%rax)
L1:
  mov    %rdi,(%rdx,%r9,8)
  movzbl (%rdi),%eax
  cmp    %al,%sil
  jne    L36
  jmp    L78
  cs nopw 0x0(%rax,%rax,1)
L89:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    %sil,%al
  je     L78
L36:
  test   %al,%al
  jne    L89
L45:
  add    $0x1,%r9
  jmp    L28
L78:
  test   %sil,%sil
  je     L45
  movb   $0x0,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%r9
  add    $0x1,%rdi
  jmp    L28
L75:
  xor    %r10d,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int get_tokens(char *line, char delimiter, char **tokens, int tokens_length) {
  int count = 0;
  char *position = line;
  if (!line) {
    return 0;
  }
  while (*position != '\0') {
    if (count >= tokens_length) {
      break;
    }
    while (*position == delimiter) {
      position++;
    }
    if (*position != '\0') {
      tokens[count] = position;
      count++;
      while (*position != delimiter && *position != '\0') {
        position++;
      }
      if (*position != '\0') {
        *position = '\0';
        position++;
      }
    }
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<polToKartez>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void polToKartez(double pruvodic, double fiRad, double *px, double *py) {
  *px = pruvodic * cos(fiRad);
  *py = pruvodic * sin(fiRad);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<polToKartez>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  movapd %xmm1,%xmm0
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movq   %rbx,%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm0,(%r12)
  movq   %rbx,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void polToKartez(double pruvodic, double fiRad, double *px, double *py) {
  *px = pruvodic * cos(fiRad);
  *py = pruvodic * sin(fiRad);
}
```
user: Translate the below assembly code into C programming language:

```asm
<polToKartez>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x18(%rsp),%rdi
  movapd %xmm1,%xmm0
  lea    0x10(%rsp),%rsi
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  0x18(%rsp),%xmm2
  movsd  %xmm0,0x0(%rbp)
  movsd  %xmm2,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void polToKartez(double pruvodic, double fiRad, double *px, double *py) {
  *px = pruvodic * cos(fiRad);
  *py = pruvodic * sin(fiRad);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<polToKartez>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x18(%rsp),%rdi
  movapd %xmm1,%xmm0
  lea    0x10(%rsp),%rsi
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  0x18(%rsp),%xmm2
  movsd  %xmm0,0x0(%rbp)
  movsd  %xmm2,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void polToKartez(double pruvodic, double fiRad, double *px, double *py) {
  *px = pruvodic * cos(fiRad);
  *py = pruvodic * sin(fiRad);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<load_u64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
uint64_t load_u64(uint8_t *buf) {
  uint64_t ret;
  memcpy(&ret, buf, sizeof(ret));
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<load_u64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t load_u64(uint8_t *buf) {
  uint64_t ret;
  memcpy(&ret, buf, sizeof(ret));
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<load_u64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t load_u64(uint8_t *buf) {
  uint64_t ret;
  memcpy(&ret, buf, sizeof(ret));
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<load_u64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t load_u64(uint8_t *buf) {
  uint64_t ret;
  memcpy(&ret, buf, sizeof(ret));
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L26
L3:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <sub3@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <eq@plt>
  addl   $0x1,-0x10(%rbp)
L26:
  cmpl   $0x3,-0x10(%rbp)
  jle    L3
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
main() {
  int i;
  for (i = 0; i < 4; i++) {
    const int j = i;
    int k;
    sub3(&j);
    k = j;
    eq(k, k);
  }
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0x4(%rsp),%rbp
L9:
  mov    %ebx,0x4(%rsp)
  mov    %rbp,%rdi
  call   <sub3@plt>
  mov    0x4(%rsp),%edi
  mov    %edi,%esi
  call   <eq@plt>
  add    $0x1,%ebx
  cmp    $0x4,%ebx
  jne    L9
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int i;
  for (i = 0; i < 4; i++) {
    const int j = i;
    int k;
    sub3(&j);
    k = j;
    eq(k, k);
  }
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
L7:
  mov    %rbp,%rdi
  mov    %ebx,0x4(%rsp)
  add    $0x1,%ebx
  call   <sub3@plt>
  mov    0x4(%rsp),%edi
  mov    %edi,%esi
  call   <eq@plt>
  cmp    $0x4,%ebx
  jne    L7
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int i;
  for (i = 0; i < 4; i++) {
    const int j = i;
    int k;
    sub3(&j);
    k = j;
    eq(k, k);
  }
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
L0:
  mov    %rbp,%rdi
  mov    %ebx,0x4(%rsp)
  add    $0x1,%ebx
  call   <sub3@plt>
  mov    0x4(%rsp),%edi
  mov    %edi,%esi
  call   <eq@plt>
  cmp    $0x4,%ebx
  jne    L0
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int i;
  for (i = 0; i < 4; i++) {
    const int j = i;
    int k;
    sub3(&j);
    k = j;
    eq(k, k);
  }
  exit(0);
}
```