ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,0x58(%rsp)
  mov    %rdx,0x28(%rsp)
  cmp    %rsi,%rdx
  jbe    L23
  mov    %rsi,%r15
L120:
  mov    0x28(%rsp),%rsi
  mov    %r15,%rdi
  call   <split@plt>
  mov    %rax,0x30(%rsp)
  sub    $0x4,%rax
  mov    %rax,0x10(%rsp)
  cmp    %r15,%rax
  jbe    L155
L124:
  mov    0x10(%rsp),%rsi
  mov    %r15,%rdi
  call   <split@plt>
  mov    %rax,0x38(%rsp)
  sub    $0x4,%rax
  mov    %rax,0x18(%rsp)
  cmp    %r15,%rax
  jbe    L154
L19:
  mov    0x18(%rsp),%rsi
  mov    %r15,%rdi
  call   <split@plt>
  mov    %rax,0x40(%rsp)
  sub    $0x4,%rax
  mov    %rax,0x20(%rsp)
  cmp    %r15,%rax
  jbe    L164
L30:
  mov    0x20(%rsp),%rsi
  mov    %r15,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%r12
  mov    %rax,0x48(%rsp)
  cmp    %r15,%r12
  jbe    L158
L152:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%rbp
  mov    %rax,%rbx
  cmp    %r15,%rbp
  jbe    L8
  mov    %r15,%rax
  mov    %rbp,%r15
  mov    %rax,%rbp
L22:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%r14
  mov    %rax,(%rsp)
  cmp    %rbp,%r14
  jbe    L38
L170:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%r13
  mov    %rax,0x50(%rsp)
  cmp    %rbp,%r13
  jbe    L47
  mov    %rbx,0x8(%rsp)
  mov    %r13,%rbx
L85:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%rcx
  mov    %rax,%r13
  cmp    %rbp,%rcx
  jbe    L94
  mov    %rbx,%r13
  mov    %rax,%r8
  mov    %r12,%rbx
  mov    %rbp,%r12
L80:
  mov    %rcx,%rsi
  mov    %r12,%rdi
  mov    %r8,0x68(%rsp)
  mov    %rcx,0x60(%rsp)
  call   <split@plt>
  mov    0x58(%rsp),%rdi
  mov    %r12,%rsi
  lea    -0x4(%rax),%rdx
  mov    %rax,%rbp
  call   <quicksort>
  mov    0x60(%rsp),%rcx
  lea    0x4(%rbp),%r12
  mov    0x68(%rsp),%r8
  cmp    %r12,%rcx
  ja     L80
  mov    %rbx,%r12
  mov    %r13,%rbx
  mov    %r8,%r13
L94:
  lea    0x4(%r13),%rbp
  cmp    %rbp,%rbx
  ja     L85
  mov    0x8(%rsp),%rbx
L47:
  mov    0x50(%rsp),%rbp
  add    $0x4,%rbp
  cmp    %rbp,%r14
  ja     L170
L38:
  mov    (%rsp),%rbp
  add    $0x4,%rbp
  cmp    %rbp,%r15
  ja     L22
L8:
  lea    0x4(%rbx),%r15
  cmp    %r15,%r12
  ja     L152
L158:
  mov    0x48(%rsp),%r15
  add    $0x4,%r15
  cmp    %r15,0x20(%rsp)
  ja     L30
L164:
  mov    0x40(%rsp),%r15
  add    $0x4,%r15
  cmp    %r15,0x18(%rsp)
  ja     L19
L154:
  mov    0x38(%rsp),%r15
  add    $0x4,%r15
  cmp    %r15,0x10(%rsp)
  ja     L124
L155:
  mov    0x30(%rsp),%r15
  add    $0x4,%r15
  cmp    0x28(%rsp),%r15
  jb     L120
L23:
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quicksort(const int a[], int *low, int *high) {
  int *middle;
  if (low >= high) {
    return;
  }
  middle = split(low, high);
  quicksort(a, low, (middle - 1));
  quicksort(a, (middle + 1), high);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,0x58(%rsp)
  mov    %rdx,0x28(%rsp)
  cmp    %rsi,%rdx
  jbe    L30
  mov    %rsi,%r15
L141:
  mov    0x28(%rsp),%rsi
  mov    %r15,%rdi
  call   <split@plt>
  mov    %rax,0x30(%rsp)
  sub    $0x4,%rax
  mov    %rax,0x10(%rsp)
  cmp    %r15,%rax
  jbe    L111
L166:
  mov    0x10(%rsp),%rsi
  mov    %r15,%rdi
  call   <split@plt>
  mov    %rax,0x38(%rsp)
  sub    $0x4,%rax
  mov    %rax,0x18(%rsp)
  cmp    %r15,%rax
  jbe    L159
L98:
  mov    0x18(%rsp),%rsi
  mov    %r15,%rdi
  call   <split@plt>
  mov    %rax,0x40(%rsp)
  sub    $0x4,%rax
  mov    %rax,0x20(%rsp)
  cmp    %r15,%rax
  jbe    L5
L49:
  mov    0x20(%rsp),%rsi
  mov    %r15,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%r12
  mov    %rax,0x48(%rsp)
  cmp    %r15,%r12
  jbe    L152
L20:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%rbp
  mov    %rax,%rbx
  cmp    %r15,%rbp
  jbe    L40
  mov    %r15,%rax
  mov    %rbp,%r15
  mov    %rax,%rbp
L84:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%r14
  mov    %rax,(%rsp)
  cmp    %rbp,%r14
  jbe    L105
L128:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%r13
  mov    %rax,0x50(%rsp)
  cmp    %rbp,%r13
  jbe    L89
  mov    %rbx,0x8(%rsp)
  mov    %r13,%rbx
L92:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  lea    -0x4(%rax),%rcx
  mov    %rax,%r13
  cmp    %rbp,%rcx
  jbe    L42
  mov    %rbx,%r13
  mov    %rax,%r8
  mov    %r12,%rbx
  mov    %rbp,%r12
L121:
  mov    %rcx,%rsi
  mov    %r12,%rdi
  mov    %r8,0x68(%rsp)
  mov    %rcx,0x60(%rsp)
  call   <split@plt>
  mov    0x58(%rsp),%rdi
  mov    %r12,%rsi
  lea    -0x4(%rax),%rdx
  mov    %rax,%rbp
  call   <quicksort>
  mov    0x60(%rsp),%rcx
  lea    0x4(%rbp),%r12
  mov    0x68(%rsp),%r8
  cmp    %r12,%rcx
  ja     L121
  mov    %rbx,%r12
  mov    %r13,%rbx
  mov    %r8,%r13
L42:
  lea    0x4(%r13),%rbp
  cmp    %rbp,%rbx
  ja     L92
  mov    0x8(%rsp),%rbx
L89:
  mov    0x50(%rsp),%rbp
  add    $0x4,%rbp
  cmp    %rbp,%r14
  ja     L128
L105:
  mov    (%rsp),%rbp
  add    $0x4,%rbp
  cmp    %rbp,%r15
  ja     L84
L40:
  lea    0x4(%rbx),%r15
  cmp    %r15,%r12
  ja     L20
L152:
  mov    0x48(%rsp),%r15
  add    $0x4,%r15
  cmp    %r15,0x20(%rsp)
  ja     L49
L5:
  mov    0x40(%rsp),%r15
  add    $0x4,%r15
  cmp    %r15,0x18(%rsp)
  ja     L98
L159:
  mov    0x38(%rsp),%r15
  add    $0x4,%r15
  cmp    %r15,0x10(%rsp)
  ja     L166
L111:
  mov    0x30(%rsp),%r15
  add    $0x4,%r15
  cmp    0x28(%rsp),%r15
  jb     L141
L30:
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quicksort(const int a[], int *low, int *high) {
  int *middle;
  if (low >= high) {
    return;
  }
  middle = split(low, high);
  quicksort(a, low, (middle - 1));
  quicksort(a, (middle + 1), high);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  movss  %xmm0,-0x8(%rbp)
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
int g(int a, float b) {
  return;
  return a;
  return b;
  return 1;
  return 3.14;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
int g(int a, float b) {
  return;
  return a;
  return b;
  return 1;
  return 3.14;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
int g(int a, float b) {
  return;
  return a;
  return b;
  return 1;
  return 3.14;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
int g(int a, float b) {
  return;
  return a;
  return b;
  return 1;
  return 3.14;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,-0x68(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L54
L65:
  mov    -0x78(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x78(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x60(%rbp,%rdx,8)
  addl   $0x1,-0x78(%rbp)
L54:
  cmpl   $0x9,-0x78(%rbp)
  jle    L65
  mov    -0x68(%rbp),%rax
  movl   $0x1e,(%rax)
  mov    -0x68(%rbp),%rax
  mov    $0x2710,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1e,%eax
  je     L29
  mov    $0x0,%eax
  call   <abort@plt>
L29:
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movl   $0x9,-0x74(%rbp)
  jmp    L42
L75:
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <free@plt>
  subl   $0x1,-0x74(%rbp)
L42:
  cmpl   $0x0,-0x74(%rbp)
  jns    L75
  movl   $0x0,-0x70(%rbp)
  jmp    L17
L61:
  mov    -0x70(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x70(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x60(%rbp,%rdx,8)
  addl   $0x1,-0x70(%rbp)
L17:
  cmpl   $0x9,-0x70(%rbp)
  jle    L61
  mov    -0x48(%rbp),%rax
  mov    $0x4d3,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    $0x7b,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    $0x300c,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x0,%eax
  call   <__vmir_heap_print@plt>
  movl   $0x9,-0x6c(%rbp)
  jmp    L64
L40:
  mov    -0x6c(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <free@plt>
  subl   $0x1,-0x6c(%rbp)
L64:
  cmpl   $0x0,-0x6c(%rbp)
  jns    L40
  mov    $0x0,%eax
  call   <__vmir_heap_print@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

assistant: ```c
int main(void) {
  uint32_t *hej = malloc(32);
  void *vec[10];
  for (int i = 0; i < 10; i++)
    vec[i] = malloc(i * 10);
  *hej = 30;
  hej = realloc(hej, 10000);
  if (*hej != 30)
    abort();
  free(hej);
  for (int i = 9; i >= 0; i--)
    free(vec[i]);
  for (int i = 0; i < 10; i++)
    vec[i] = malloc(i * 10);
  vec[3] = realloc(vec[3], 1235);
  vec[3] = realloc(vec[3], 123);
  vec[3] = realloc(vec[3], 12300);
  free(vec[5]);
  vec[5] = NULL;
  vec[7] = realloc(vec[7], 0);
  __vmir_heap_print();
  for (int i = 9; i >= 0; i--)
    free(vec[i]);
  __vmir_heap_print();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rsp,%r12
  mov    %r12,%rbp
  mov    $0x0,%ebx
L1:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  add    $0xa,%ebx
  add    $0x8,%rbp
  cmp    $0x64,%ebx
  jne    L1
  movl   $0x1e,0x0(%r13)
  mov    $0x2710,%esi
  mov    %r13,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  cmpl   $0x1e,(%rax)
  jne    L19
L7:
  mov    %rbx,%rdi
  call   <free@plt>
  lea    0x48(%rsp),%rbx
  mov    %rbx,%rbp
L66:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    %rbp,%rax
  sub    $0x8,%rbp
  cmp    %r12,%rax
  jne    L66
  mov    %r12,%r13
  mov    $0x0,%ebp
L25:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  add    $0xa,%ebp
  add    $0x8,%r13
  cmp    $0x64,%ebp
  jne    L25
  mov    $0x4d3,%esi
  mov    0x18(%rsp),%rdi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    $0x7b,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    $0x300c,%esi
  call   <realloc@plt>
  mov    %rax,0x18(%rsp)
  mov    0x28(%rsp),%rdi
  call   <free@plt>
  movq   $0x0,0x28(%rsp)
  mov    $0x0,%esi
  mov    0x38(%rsp),%rdi
  call   <realloc@plt>
  mov    %rax,0x38(%rsp)
  mov    $0x0,%eax
  call   <__vmir_heap_print@plt>
L46:
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  sub    $0x8,%rbx
  cmp    %r12,%rax
  jne    L46
  mov    $0x0,%eax
  call   <__vmir_heap_print@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L7
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  uint32_t *hej = malloc(32);
  void *vec[10];
  for (int i = 0; i < 10; i++)
    vec[i] = malloc(i * 10);
  *hej = 30;
  hej = realloc(hej, 10000);
  if (*hej != 30)
    abort();
  free(hej);
  for (int i = 9; i >= 0; i--)
    free(vec[i]);
  for (int i = 0; i < 10; i++)
    vec[i] = malloc(i * 10);
  vec[3] = realloc(vec[3], 1235);
  vec[3] = realloc(vec[3], 123);
  vec[3] = realloc(vec[3], 12300);
  free(vec[5]);
  vec[5] = NULL;
  vec[7] = realloc(vec[7], 0);
  __vmir_heap_print();
  for (int i = 9; i >= 0; i--)
    free(vec[i]);
  __vmir_heap_print();
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x20,%edi
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <malloc@plt>
  mov    %r13,%rbp
  mov    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %ebx,%edi
  add    $0xa,%ebx
  add    $0x8,%rbp
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    $0x64,%ebx
  jne    L57
  movl   $0x1e,(%r12)
  mov    $0x2710,%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  cmpl   $0x1e,(%rax)
  mov    %rax,%rbp
  je     L59
  xor    %eax,%eax
  call   <abort@plt>
L59:
  mov    %rbp,%rdi
  lea    0x48(%rsp),%rbx
  call   <free@plt>
  mov    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L24:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    %rbp,%rax
  sub    $0x8,%rbp
  cmp    %r13,%rax
  jne    L24
  mov    %r13,%r12
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %ebp,%edi
  add    $0xa,%ebp
  add    $0x8,%r12
  call   <malloc@plt>
  mov    %rax,-0x8(%r12)
  cmp    $0x64,%ebp
  jne    L48
  mov    0x18(%rsp),%rdi
  mov    $0x4d3,%esi
  call   <realloc@plt>
  mov    $0x7b,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    $0x300c,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    0x28(%rsp),%rdi
  mov    %rax,0x18(%rsp)
  call   <free@plt>
  mov    0x38(%rsp),%rdi
  xor    %esi,%esi
  movq   $0x0,0x28(%rsp)
  call   <realloc@plt>
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <__vmir_heap_print@plt>
  nopl   0x0(%rax)
L35:
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  sub    $0x8,%rbx
  cmp    %r13,%rax
  jne    L35
  xor    %eax,%eax
  call   <__vmir_heap_print@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  uint32_t *hej = malloc(32);
  void *vec[10];
  for (int i = 0; i < 10; i++)
    vec[i] = malloc(i * 10);
  *hej = 30;
  hej = realloc(hej, 10000);
  if (*hej != 30)
    abort();
  free(hej);
  for (int i = 9; i >= 0; i--)
    free(vec[i]);
  for (int i = 0; i < 10; i++)
    vec[i] = malloc(i * 10);
  vec[3] = realloc(vec[3], 1235);
  vec[3] = realloc(vec[3], 123);
  vec[3] = realloc(vec[3], 12300);
  free(vec[5]);
  vec[5] = NULL;
  vec[7] = realloc(vec[7], 0);
  __vmir_heap_print();
  for (int i = 9; i >= 0; i--)
    free(vec[i]);
  __vmir_heap_print();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x20,%edi
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <malloc@plt>
  mov    %r13,%rbp
  mov    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  add    $0xa,%ebx
  add    $0x8,%rbp
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    $0x64,%ebx
  jne    L3
  movl   $0x1e,(%r12)
  mov    $0x2710,%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  cmpl   $0x1e,(%rax)
  mov    %rax,%rbp
  je     L54
  xor    %eax,%eax
  call   <abort@plt>
L54:
  mov    %rbp,%rdi
  lea    0x48(%rsp),%rbx
  call   <free@plt>
  mov    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    %rbp,%rax
  sub    $0x8,%rbp
  cmp    %r13,%rax
  jne    L27
  mov    %r13,%r12
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %ebp,%edi
  add    $0xa,%ebp
  add    $0x8,%r12
  call   <malloc@plt>
  mov    %rax,-0x8(%r12)
  cmp    $0x64,%ebp
  jne    L22
  mov    0x18(%rsp),%rdi
  mov    $0x4d3,%esi
  call   <realloc@plt>
  mov    $0x7b,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    $0x300c,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    0x28(%rsp),%rdi
  mov    %rax,0x18(%rsp)
  call   <free@plt>
  mov    0x38(%rsp),%rdi
  xor    %esi,%esi
  movq   $0x0,0x28(%rsp)
  call   <realloc@plt>
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <__vmir_heap_print@plt>
  nopl   0x0(%rax)
L5:
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  sub    $0x8,%rbx
  cmp    %r13,%rax
  jne    L5
  xor    %eax,%eax
  call   <__vmir_heap_print@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  uint32_t *hej = malloc(32);
  void *vec[10];
  for (int i = 0; i < 10; i++)
    vec[i] = malloc(i * 10);
  *hej = 30;
  hej = realloc(hej, 10000);
  if (*hej != 30)
    abort();
  free(hej);
  for (int i = 9; i >= 0; i--)
    free(vec[i]);
  for (int i = 0; i < 10; i++)
    vec[i] = malloc(i * 10);
  vec[3] = realloc(vec[3], 1235);
  vec[3] = realloc(vec[3], 123);
  vec[3] = realloc(vec[3], 12300);
  free(vec[5]);
  vec[5] = NULL;
  vec[7] = realloc(vec[7], 0);
  __vmir_heap_print();
  for (int i = 9; i >= 0; i--)
    free(vec[i]);
  __vmir_heap_print();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L8:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L3:
  cmpl   $0x0,-0x14(%rbp)
  jg     L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int reverse(int no) {
  int rev = 0;
  while (no > 0) {
    int r = no % 10;
    rev = rev * 10 + r;
    no = no / 10;
  }
  return rev;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  test   %edi,%edi
  jle    L16
  mov    $0x0,%edx
L10:
  lea    (%rdx,%rdx,4),%esi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %edi,%ecx
  sub    %edx,%ecx
  lea    (%rcx,%rsi,2),%edx
  mov    %edi,%ecx
  mov    %eax,%edi
  cmp    $0x9,%ecx
  jg     L10
L5:
  mov    %edx,%eax
  ret
L16:
  mov    $0x0,%edx
  jmp    L5
```

assistant: ```c
int reverse(int no) {
  int rev = 0;
  while (no > 0) {
    int r = no % 10;
    rev = rev * 10 + r;
    no = no / 10;
  }
  return rev;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L12
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L3:
  mov    %edi,%eax
  mov    %edi,%ecx
  lea    (%r8,%r8,4),%esi
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  lea    (%rcx,%rsi,2),%r8d
  cmp    $0x9,%edx
  jg     L3
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverse(int no) {
  int rev = 0;
  while (no > 0) {
    int r = no % 10;
    rev = rev * 10 + r;
    no = no / 10;
  }
  return rev;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverse>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L11
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L9:
  mov    %edi,%eax
  mov    %edi,%ecx
  lea    (%r8,%r8,4),%esi
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  lea    (%rcx,%rsi,2),%r8d
  cmp    $0x9,%edx
  jg     L9
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverse(int no) {
  int rev = 0;
  while (no > 0) {
    int r = no % 10;
    rev = rev * 10 + r;
    no = no / 10;
  }
  return rev;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x24,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  movq   $0x25,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x0,%eax
  call   <esperar@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  and    $0xffffffdf,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x0,%eax
  call   <esperar@plt>
  jmp    L1
```

assistant: ```c
int main(void) {
  volatile unsigned char *ddr_b = (unsigned char *)0x24;
  *ddr_b = *ddr_b | (0x20);
  volatile unsigned char *puerto_b = (unsigned char *)0x25;
  while (1) {
    *puerto_b = *puerto_b | (0x20);
    esperar();
    *puerto_b = *puerto_b & (~(0x20));
    esperar();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movzbl 0x24,%eax
  or     $0x20,%eax
  mov    %al,0x24
L9:
  movzbl 0x25,%eax
  or     $0x20,%eax
  mov    %al,0x25
  mov    $0x0,%eax
  call   <esperar@plt>
  movzbl 0x25,%eax
  and    $0xffffffdf,%eax
  mov    %al,0x25
  mov    $0x0,%eax
  call   <esperar@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  volatile unsigned char *ddr_b = (unsigned char *)0x24;
  *ddr_b = *ddr_b | (0x20);
  volatile unsigned char *puerto_b = (unsigned char *)0x25;
  while (1) {
    *puerto_b = *puerto_b | (0x20);
    esperar();
    *puerto_b = *puerto_b & (~(0x20));
    esperar();
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movzbl 0x24,%eax
  or     $0x20,%eax
  mov    %al,0x24
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl 0x25,%eax
  or     $0x20,%eax
  mov    %al,0x25
  xor    %eax,%eax
  call   <esperar@plt>
  movzbl 0x25,%eax
  and    $0xffffffdf,%eax
  mov    %al,0x25
  xor    %eax,%eax
  call   <esperar@plt>
  jmp    L2
```

assistant: ```c
int main(void) {
  volatile unsigned char *ddr_b = (unsigned char *)0x24;
  *ddr_b = *ddr_b | (0x20);
  volatile unsigned char *puerto_b = (unsigned char *)0x25;
  while (1) {
    *puerto_b = *puerto_b | (0x20);
    esperar();
    *puerto_b = *puerto_b & (~(0x20));
    esperar();
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movzbl 0x24,%eax
  or     $0x20,%eax
  mov    %al,0x24
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl 0x25,%eax
  or     $0x20,%eax
  mov    %al,0x25
  xor    %eax,%eax
  call   <esperar@plt>
  movzbl 0x25,%eax
  and    $0xffffffdf,%eax
  mov    %al,0x25
  xor    %eax,%eax
  call   <esperar@plt>
  jmp    L0
```

assistant: ```c
int main(void) {
  volatile unsigned char *ddr_b = (unsigned char *)0x24;
  *ddr_b = *ddr_b | (0x20);
  volatile unsigned char *puerto_b = (unsigned char *)0x25;
  while (1) {
    *puerto_b = *puerto_b | (0x20);
    esperar();
    *puerto_b = *puerto_b & (~(0x20));
    esperar();
  }
}
```