user: What would the C source look like for the assembly code provided here?

```asm
<printSudoku>:
  endbr64
  push   %r15
  lea    D67(%rip),%r15
  push   %r14
  push   %r13
  lea    D40(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L54:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%r8
  mov    %ebp,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L46
  lea    D97(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L30:
  mov    $0x9,%ebx
  jmp    L127
  nopl   0x0(%rax,%rax,1)
L21:
  sub    $0x1,%ebx
  je     L110
L127:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%r8
  mov    %ebp,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L21
  xor    %eax,%eax
  lea    D54(%rip),%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L127
L110:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%r8
  mov    %ebp,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L145
L23:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%r8
  mov    %ebp,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L102
  lea    D97(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L134:
  xor    %ebx,%ebx
  lea    D34(%rip),%r14
  nopl   0x0(%rax)
L166:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %r14,%rdi
  mov    %rax,%r8
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L41
  mov    %r15,%rdi
L41:
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x9,%rbx
  jne    L166
  mov    $0x7c,%edi
  add    $0x1,%ebp
  add    $0x24,%r12
  call   <putchar@plt>
  cmp    $0x9,%ebp
  jne    L54
  lea    D97(%rip),%rdi
  xor    %eax,%eax
  mov    $0x9,%ebx
  call   <printf@plt>
  lea    D54(%rip),%rbp
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L163:
  sub    $0x1,%ebx
  je     L130
L9:
  mov    $0x9,%edi
  call   <sqrt@plt>
  mov    %rax,%r8
  mov    $0x9,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L163
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L9
L130:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <putchar@plt>
  xchg   %ax,%ax
L46:
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L102:
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L134
  nopl   0x0(%rax,%rax,1)
L145:
  mov    $0x2d,%edi
  call   <putchar@plt>
  jmp    L23
```

tool_calls: name: disassemble_data
arguments: tag: D67
data_type: string
name: disassemble_data
arguments: tag: D40
data_type: string
name: disassemble_data
arguments: tag: D97
data_type: string
name: disassemble_data
arguments: tag: D54
data_type: string
name: disassemble_data
arguments: tag: D34
data_type: string
name: disassemble_data
arguments: tag: D49
data_type: string

tool: D67: | 

tool: D40: %3d 

tool: D97: 

		

tool: D54: - - - 

tool: D34: , 

tool: D49: 
		

assistant: ```c
void printSudoku(int grid[9][9]) {
  int i, j;
  for (i = 0; i < 9; ++i) {
    if (i % ((int)sqrt(9)) == 0)
      printf("\n\n\t\t");
    else
      printf("\n\t\t");
    for (j = 0; j < 9; ++j)
      if (i % ((int)sqrt(9)) == 0)
        printf("- - - ");
    if (i % ((int)sqrt(9)) == 0)
      printf("-");
    if (i % ((int)sqrt(9)) == 0)
      printf("\n\n\t\t");
    else
      printf("\n\t\t");
    for (j = 0; j < 9; ++j) {
      if (j % ((int)sqrt(9)))
        printf(", ");
      else
        printf("| ");
      printf("%3d ", grid[i][j]);
    }
    printf("|");
  }
  printf("\n\n\t\t");
  for (j = 0; j < 9; ++j)
    if (i % ((int)sqrt(9)) == 0)
      printf("- - - ");
  printf("\n");
}
```