ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  add    $0xb0c,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
        } else {
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        }
      } else {
        state[local1] = state[0UL] - state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned short)61968;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  add    $0xb0c,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
        } else {
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        }
      } else {
        state[local1] = state[0UL] - state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned short)61968;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<DMA_Reset_All>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  jmp    L59
L62:
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  cltq
  add    $0x20007000,%rax
  movl   $0x80000000,(%rax)
  addl   $0x1,-0x8(%rbp)
L59:
  cmpl   $0xe,-0x8(%rbp)
  jle    L62
  movl   $0x0,-0x4(%rbp)
  jmp    L65
L83:
  movl   $0x0,-0x8(%rbp)
  jmp    L25
L72:
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L71
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  cltq
  add    $0x20007000,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L57
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  jmp    L57
L71:
  nop
L57:
  addl   $0x1,-0x8(%rbp)
L25:
  cmpl   $0xe,-0x8(%rbp)
  jle    L72
L65:
  cmpl   $0x7fff,-0x4(%rbp)
  jne    L83
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DMA_Reset_All() {
  int i;
  for (i = 0; i <= 14; ++i)
    *(volatile int *)((volatile void *)(0x20007000) + (i)*0x100 + 0x00) = 1 << 31;
  int Reset = 0;
  while (Reset != 0x7fff) {
    for (i = 0; i <= 14; ++i) {
      if (Reset & (1 << i))
        continue;
      if ((*(volatile int *)((volatile void *)(0x20007000) + (i)*0x100 + 0x00) & 1 << 31) == 0)
        Reset |= (1 << i);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<DMA_Reset_All>:
  endbr64
  mov    $0x20007000,%eax
L62:
  movl   $0x80000000,(%rax)
  add    $0x100,%rax
  cmp    $0x20007f00,%rax
  jne    L62
  mov    $0x0,%eax
  mov    $0x1,%r9d
  jmp    L35
L42:
  add    $0x1,%ecx
  add    $0x100,%rdx
  cmp    $0xf,%ecx
  je     L17
L68:
  bt     %ecx,%eax
  jb     L42
  mov    (%rdx),%esi
  mov    %eax,%edi
  mov    %r9d,%r8d
  shl    %cl,%r8d
  or     %r8d,%eax
  test   %esi,%esi
  cmovs  %edi,%eax
  jmp    L42
L17:
  cmp    $0x7fff,%eax
  je     L46
L35:
  mov    $0x20007000,%edx
  mov    $0x0,%ecx
  jmp    L68
L46:
  ret
```

assistant: ```c
void DMA_Reset_All() {
  int i;
  for (i = 0; i <= 14; ++i)
    *(volatile int *)((volatile void *)(0x20007000) + (i)*0x100 + 0x00) = 1 << 31;
  int Reset = 0;
  while (Reset != 0x7fff) {
    for (i = 0; i <= 14; ++i) {
      if (Reset & (1 << i))
        continue;
      if ((*(volatile int *)((volatile void *)(0x20007000) + (i)*0x100 + 0x00) & 1 << 31) == 0)
        Reset |= (1 << i);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DMA_Reset_All>:
  endbr64
  mov    $0x20007000,%eax
  nopl   0x0(%rax)
L28:
  movl   $0x80000000,(%rax)
  add    $0x100,%rax
  cmp    $0x20007f00,%rax
  jne    L28
  xor    %eax,%eax
  mov    $0x1,%r9d
  nopl   0x0(%rax)
L0:
  mov    $0x20007000,%edx
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L4:
  bt     %ecx,%eax
  jb     L10
  mov    (%rdx),%esi
  mov    %r9d,%r8d
  mov    %eax,%edi
  shl    %cl,%r8d
  or     %r8d,%eax
  test   %esi,%esi
  cmovs  %edi,%eax
L10:
  add    $0x1,%ecx
  add    $0x100,%rdx
  cmp    $0xf,%ecx
  jne    L4
  cmp    $0x7fff,%eax
  jne    L0
  ret
```

assistant: ```c
void DMA_Reset_All() {
  int i;
  for (i = 0; i <= 14; ++i)
    *(volatile int *)((volatile void *)(0x20007000) + (i)*0x100 + 0x00) = 1 << 31;
  int Reset = 0;
  while (Reset != 0x7fff) {
    for (i = 0; i <= 14; ++i) {
      if (Reset & (1 << i))
        continue;
      if ((*(volatile int *)((volatile void *)(0x20007000) + (i)*0x100 + 0x00) & 1 << 31) == 0)
        Reset |= (1 << i);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DMA_Reset_All>:
  endbr64
  movl   $0x80000000,0x20007000
  xor    %eax,%eax
  movl   $0x80000000,0x20007100
  movl   $0x80000000,0x20007200
  movl   $0x80000000,0x20007300
  movl   $0x80000000,0x20007400
  movl   $0x80000000,0x20007500
  movl   $0x80000000,0x20007600
  movl   $0x80000000,0x20007700
  movl   $0x80000000,0x20007800
  movl   $0x80000000,0x20007900
  movl   $0x80000000,0x20007a00
  movl   $0x80000000,0x20007b00
  movl   $0x80000000,0x20007c00
  movl   $0x80000000,0x20007d00
  movl   $0x80000000,0x20007e00
  nopl   0x0(%rax,%rax,1)
L122:
  test   $0x1,%al
  jne    L91
  mov    0x20007000,%ecx
  mov    %eax,%edx
  or     $0x1,%edx
  test   %ecx,%ecx
  cmovns %edx,%eax
L91:
  test   $0x2,%al
  jne    L3
  mov    0x20007100,%ecx
  mov    %eax,%edx
  or     $0x2,%edx
  test   %ecx,%ecx
  cmovns %edx,%eax
L3:
  test   $0x4,%al
  jne    L44
  mov    0x20007200,%ecx
  mov    %eax,%edx
  or     $0x4,%edx
  test   %ecx,%ecx
  cmovns %edx,%eax
L44:
  test   $0x8,%al
  jne    L1
  mov    0x20007300,%ecx
  mov    %eax,%edx
  or     $0x8,%edx
  test   %ecx,%ecx
  cmovns %edx,%eax
L1:
  test   $0x10,%al
  jne    L112
  mov    0x20007400,%ecx
  mov    %eax,%edx
  or     $0x10,%edx
  test   %ecx,%ecx
  cmovns %edx,%eax
L112:
  test   $0x20,%al
  jne    L16
  mov    0x20007500,%ecx
  mov    %eax,%edx
  or     $0x20,%edx
  test   %ecx,%ecx
  cmovns %edx,%eax
L16:
  test   $0x40,%al
  jne    L111
  mov    0x20007600,%ecx
  mov    %eax,%edx
  or     $0x40,%edx
  test   %ecx,%ecx
  cmovns %edx,%eax
L111:
  test   $0x80,%al
  jne    L134
  mov    0x20007700,%ecx
  mov    %eax,%edx
  or     $0x80,%dl
  test   %ecx,%ecx
  cmovns %edx,%eax
L134:
  test   $0x1,%ah
  jne    L145
  mov    0x20007800,%ecx
  mov    %eax,%edx
  or     $0x1,%dh
  test   %ecx,%ecx
  cmovns %edx,%eax
L145:
  test   $0x2,%ah
  jne    L13
  mov    0x20007900,%ecx
  mov    %eax,%edx
  or     $0x2,%dh
  test   %ecx,%ecx
  cmovns %edx,%eax
L13:
  test   $0x4,%ah
  jne    L157
  mov    0x20007a00,%ecx
  mov    %eax,%edx
  or     $0x4,%dh
  test   %ecx,%ecx
  cmovns %edx,%eax
L157:
  test   $0x8,%ah
  jne    L21
  mov    0x20007b00,%ecx
  mov    %eax,%edx
  or     $0x8,%dh
  test   %ecx,%ecx
  cmovns %edx,%eax
L21:
  test   $0x10,%ah
  jne    L26
  mov    0x20007c00,%ecx
  mov    %eax,%edx
  or     $0x10,%dh
  test   %ecx,%ecx
  cmovns %edx,%eax
L26:
  test   $0x20,%ah
  jne    L9
  mov    0x20007d00,%ecx
  mov    %eax,%edx
  or     $0x20,%dh
  test   %ecx,%ecx
  cmovns %edx,%eax
L9:
  mov    %eax,%esi
  shr    $0xe,%esi
  jne    L5
  mov    0x20007e00,%edx
  test   %edx,%edx
  js     L122
  or     $0x40,%ah
L5:
  cmp    $0x7fff,%eax
  jne    L122
  ret
```

assistant: ```c
void DMA_Reset_All() {
  int i;
  for (i = 0; i <= 14; ++i)
    *(volatile int *)((volatile void *)(0x20007000) + (i)*0x100 + 0x00) = 1 << 31;
  int Reset = 0;
  while (Reset != 0x7fff) {
    for (i = 0; i <= 14; ++i) {
      if (Reset & (1 << i))
        continue;
      if ((*(volatile int *)((volatile void *)(0x20007000) + (i)*0x100 + 0x00) & 1 << 31) == 0)
        Reset |= (1 << i);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ADCSequenceDMAEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rax),%esi
  mov    -0x8(%rbp),%eax
  mov    $0x100,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rax,%rdx
  mov    %esi,%eax
  or     %ecx,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ADCSequenceDMAEnable(uint32_t ui32Base, uint32_t ui32SequenceNum) {
  ;
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) |= 0x100 << ui32SequenceNum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ADCSequenceDMAEnable>:
  endbr64
  movslq %edi,%rdi
  mov    (%rdi),%edx
  mov    $0x100,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  or     %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void ADCSequenceDMAEnable(uint32_t ui32Base, uint32_t ui32SequenceNum) {
  ;
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) |= 0x100 << ui32SequenceNum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ADCSequenceDMAEnable>:
  endbr64
  movslq %edi,%rdi
  mov    $0x100,%eax
  mov    %esi,%ecx
  mov    (%rdi),%edx
  shl    %cl,%eax
  or     %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void ADCSequenceDMAEnable(uint32_t ui32Base, uint32_t ui32SequenceNum) {
  ;
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) |= 0x100 << ui32SequenceNum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ADCSequenceDMAEnable>:
  endbr64
  movslq %edi,%rdi
  mov    $0x100,%eax
  mov    %esi,%ecx
  mov    (%rdi),%edx
  shl    %cl,%eax
  or     %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void ADCSequenceDMAEnable(uint32_t ui32Base, uint32_t ui32SequenceNum) {
  ;
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) |= 0x100 << ui32SequenceNum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L20
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  jmp    L3
L20:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
L3:
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D24
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string

tool: D20: Enter three values one after the another:

tool: D24: %d %d %d

tool: D13: The maxium number entered is:%d

assistant: ```c
int main() {
  int a, b, c;
  int max = 0;
  printf("Enter three values one after the another:");
  scanf("%d %d %d", &a, &b, &c);
  max = a > b ? a > c ? a : c : b > c ? b : c;
  printf("The maxium number entered is:%d", max);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jle    L13
  mov    0x14(%rsp),%esi
  cmp    %esi,%eax
  cmovge %eax,%esi
L21:
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x1,%eax
  add    $0x28,%rsp
  ret
L13:
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  jmp    L21
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
datatype: string
name: parse_data
arguments: label: D24
datatype: string
name: parse_data
arguments: label: D10
datatype: string

tool: D16: Enter three values one after the another:

tool: D24: %d %d %d

tool: D10: The maxium number entered is:%d

assistant: ```c
int main() {
  int a, b, c;
  int max = 0;
  printf("Enter three values one after the another:");
  scanf("%d %d %d", &a, &b, &c);
  max = a > b ? a > c ? a : c : b > c ? b : c;
  printf("The maxium number entered is:%d", max);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jle    L23
  mov    0x14(%rsp),%esi
  cmp    %esi,%eax
  cmovge %eax,%esi
L26:
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x1,%eax
  add    $0x28,%rsp
  ret
L23:
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  jmp    L26
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
datatype: string
name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D15
datatype: string

tool: D13: Enter three values one after the another:

tool: D5: %d %d %d

tool: D15: The maxium number entered is:%d

assistant: ```c
int main() {
  int a, b, c;
  int max = 0;
  printf("Enter three values one after the another:");
  scanf("%d %d %d", &a, &b, &c);
  max = a > b ? a > c ? a : c : b > c ? b : c;
  printf("The maxium number entered is:%d", max);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jle    L26
  mov    0x14(%rsp),%esi
  cmp    %esi,%eax
  cmovge %eax,%esi
L8:
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x1,%eax
  add    $0x28,%rsp
  ret
L26:
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  jmp    L8
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D23
datatype: string
name: read_data
arguments: tag: D22
datatype: string

tool: D8: Enter three values one after the another:

tool: D23: %d %d %d

tool: D22: The maxium number entered is:%d

assistant: ```c
int main() {
  int a, b, c;
  int max = 0;
  printf("Enter three values one after the another:");
  scanf("%d %d %d", &a, &b, &c);
  max = a > b ? a > c ? a : c : b > c ? b : c;
  printf("The maxium number entered is:%d", max);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main() {
  int a = 0;
  foo(&a);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <foo@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a = 0;
  foo(&a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <foo@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a = 0;
  foo(&a);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <foo@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a = 0;
  foo(&a);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<iprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0xe8,%rsp
  mov    %rdi,-0x108(%rbp)
  mov    %rsi,-0xd8(%rbp)
  mov    %rdx,-0xd0(%rbp)
  mov    %rcx,-0xc8(%rbp)
  mov    %r8,-0xc0(%rbp)
  mov    %r9,-0xb8(%rbp)
  test   %al,%al
  je     L40
  movaps %xmm0,-0xb0(%rbp)
  movaps %xmm1,-0xa0(%rbp)
  movaps %xmm2,-0x90(%rbp)
  movaps %xmm3,-0x80(%rbp)
  movaps %xmm4,-0x70(%rbp)
  movaps %xmm5,-0x60(%rbp)
  movaps %xmm6,-0x50(%rbp)
  movaps %xmm7,-0x40(%rbp)
L40:
  mov    %fs:0x28,%rax
  mov    %rax,-0xe8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x100(%rbp)
  mov    -0x108(%rbp),%rdx
  mov    -0xfc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xfc(%rbp),%edx
  mov    -0x108(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ts_formatlength@plt>
  mov    %eax,-0x100(%rbp)
  mov    -0xfc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x100(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0xf8(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L15:
  cmp    %rdx,%rsp
  je     L26
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L15
L26:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L33
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L33:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0xf0(%rbp)
  mov    -0x108(%rbp),%rdx
  mov    -0xfc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xfc(%rbp),%edx
  mov    -0x108(%rbp),%rcx
  mov    -0xf0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ts_formatstring@plt>
  mov    %eax,-0x100(%rbp)
  mov    -0x100(%rbp),%edx
  mov    -0xf0(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <_write@plt>
  mov    %eax,-0x100(%rbp)
  mov    -0xfc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    %rbx,%rsp
  mov    -0x100(%rbp),%eax
  mov    -0xe8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int iprintf(const char *fmt, ...) {
  int length = 0;
  va_list va;
  va_start(va, fmt);
  length = ts_formatlength(fmt, va);
  va_end(va);
  {
    char buf[length];
    va_start(va, fmt);
    length = ts_formatstring(buf, fmt, va);
    length = _write(1, buf, length);
    va_end(va);
  }
  return length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<iprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <ts_formatlength@plt>
  mov    %eax,%ebx
  mov    %r13d,%edi
  call   <va_end@plt>
  movslq %ebx,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L35:
  cmp    %rdx,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L12:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L36
  orq    $0x0,-0x8(%rsp,%rax,1)
L36:
  mov    %r12,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <ts_formatstring@plt>
  mov    %eax,%edx
  mov    %rsp,%rsi
  mov    $0x1,%edi
  call   <_write@plt>
  mov    %eax,%ebx
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    %ebx,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int iprintf(const char *fmt, ...) {
  int length = 0;
  va_list va;
  va_start(va, fmt);
  length = ts_formatlength(fmt, va);
  va_end(va);
  {
    char buf[length];
    va_start(va, fmt);
    length = ts_formatstring(buf, fmt, va);
    length = _write(1, buf, length);
    va_end(va);
  }
  return length;
}
```