ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<partition_test_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  lea    0x1(%rdi),%edi
  movslq %edi,%rdi
  lea    0x0(,%rdi,4),%r13
  imul   %rdi,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <partition_dbl_restr_numbers@plt>
  lea    0xb(%r13),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L35
L66:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L66
L35:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L19
L61:
  shr    $0x2,%r13
  movslq %ebx,%rax
  mov    %rsp,%r12
  add    $0x1,%r13
  imul   %rax,%r13
  mov    (%r15,%r13,4),%eax
  mov    %r13,-0x48(%rbp)
  test   %eax,%eax
  jle    L4
  xor    %r13d,%r13d
  lea    -0x3c(%rbp),%r14
  nopw   0x0(%rax,%rax,1)
L74:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    %r14,%r9
  mov    %r12,%r8
  mov    %r13d,%ecx
  call   <partition_restr_from_id@plt>
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <partition_to_id@plt>
  cmp    %r13d,%eax
  je     L53
  mov    %r13d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
L53:
  mov    -0x48(%rbp),%rax
  add    $0x1,%r13d
  cmp    %r13d,(%r15,%rax,4)
  jg     L74
L4:
  mov    %r15,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L19:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L61
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: There was an error on id %d.


assistant: ```c
void partition_test_id(int n) {
  int(*p)[n + 1][n + 1] = malloc(((n + 1) * (n + 1) * sizeof(int)));
  partition_dbl_restr_numbers(p, n, 1);
  int part[n], num_part;
  int i;
  for (i = 0; i < (*p)[n][n]; i++) {
    partition_restr_from_id(p, n, 1, i, part, &num_part);
    int res = partition_to_id(p, n, part);
    if (res != i) {
      printf("There was an error on id %d.\n", i);
    }
  }
  free(p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<partition_test_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  lea    0x1(%rdi),%edi
  movslq %edi,%rdi
  lea    0x0(,%rdi,4),%r13
  imul   %rdi,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <partition_dbl_restr_numbers@plt>
  lea    0xb(%r13),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L3
L10:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L10
L3:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L52
L87:
  shr    $0x2,%r13
  movslq %ebx,%rax
  mov    %rsp,%r12
  add    $0x1,%r13
  imul   %rax,%r13
  mov    (%r15,%r13,4),%eax
  mov    %r13,-0x48(%rbp)
  test   %eax,%eax
  jle    L17
  xor    %r13d,%r13d
  lea    -0x3c(%rbp),%r14
  nopw   0x0(%rax,%rax,1)
L44:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    %r14,%r9
  mov    %r12,%r8
  mov    %r13d,%ecx
  call   <partition_restr_from_id@plt>
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <partition_to_id@plt>
  cmp    %r13d,%eax
  je     L93
  mov    %r13d,%esi
  lea    D7(%rip),%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  mov    -0x48(%rbp),%rax
  cmp    %r13d,(%r15,%rax,4)
  jg     L44
L17:
  mov    %r15,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L93:
  mov    -0x48(%rbp),%rax
  add    $0x1,%r13d
  cmp    %r13d,(%r15,%rax,4)
  jg     L44
  jmp    L17
L52:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L87
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: There was an error on id %d.


assistant: ```c
void partition_test_id(int n) {
  int(*p)[n + 1][n + 1] = malloc(((n + 1) * (n + 1) * sizeof(int)));
  partition_dbl_restr_numbers(p, n, 1);
  int part[n], num_part;
  int i;
  for (i = 0; i < (*p)[n][n]; i++) {
    partition_restr_from_id(p, n, 1, i, part, &num_part);
    int res = partition_to_id(p, n, part);
    if (res != i) {
      printf("There was an error on id %d.\n", i);
    }
  }
  free(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<input_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    -0x10(%rbp),%rax
  movw   $0x0,(%rax)
  jmp    L39
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  cmp    %rax,-0x20(%rbp)
  jae    L20
  mov    $0x0,%eax
  jmp    L22
L20:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L39:
  mov    $0x1,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int input_short(int flag, unsigned short *out, const unsigned char **in, const unsigned char *end) {
  if (!flag)
    *out = 0;
  else if (*in + 2 > end)
    return 0;
  else {
    *out = ((*in)[0] << 8) | (*in)[1];
    *in += 2;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<input_short>:
  endbr64
  test   %edi,%edi
  jne    L13
  movw   $0x0,(%rsi)
  mov    $0x1,%eax
  ret
L13:
  mov    (%rdx),%rdi
  lea    0x2(%rdi),%r8
  mov    $0x0,%eax
  cmp    %r8,%rcx
  jb     L18
  movzbl (%rdi),%ecx
  shl    $0x8,%ecx
  movzbl 0x1(%rdi),%eax
  or     %ecx,%eax
  mov    %ax,(%rsi)
  addq   $0x2,(%rdx)
  mov    $0x1,%eax
L18:
  ret
```

assistant: ```c
int input_short(int flag, unsigned short *out, const unsigned char **in, const unsigned char *end) {
  if (!flag)
    *out = 0;
  else if (*in + 2 > end)
    return 0;
  else {
    *out = ((*in)[0] << 8) | (*in)[1];
    *in += 2;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<input_short>:
  endbr64
  test   %edi,%edi
  jne    L19
  xor    %eax,%eax
  mov    %ax,(%rsi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rdx),%r8
  xor    %eax,%eax
  lea    0x2(%r8),%rdi
  cmp    %rcx,%rdi
  ja     L11
  movzwl (%r8),%eax
  rol    $0x8,%ax
  mov    %ax,(%rsi)
  mov    $0x1,%eax
  mov    %rdi,(%rdx)
L11:
  ret
```

assistant: ```c
int input_short(int flag, unsigned short *out, const unsigned char **in, const unsigned char *end) {
  if (!flag)
    *out = 0;
  else if (*in + 2 > end)
    return 0;
  else {
    *out = ((*in)[0] << 8) | (*in)[1];
    *in += 2;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<input_short>:
  endbr64
  test   %edi,%edi
  jne    L8
  xor    %eax,%eax
  mov    %ax,(%rsi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rdx),%r8
  xor    %eax,%eax
  lea    0x2(%r8),%rdi
  cmp    %rcx,%rdi
  ja     L19
  movzwl (%r8),%eax
  rol    $0x8,%ax
  mov    %ax,(%rsi)
  mov    $0x1,%eax
  mov    %rdi,(%rdx)
L19:
  ret
```

assistant: ```c
int input_short(int flag, unsigned short *out, const unsigned char **in, const unsigned char *end) {
  if (!flag)
    *out = 0;
  else if (*in + 2 > end)
    return 0;
  else {
    *out = ((*in)[0] << 8) | (*in)[1];
    *in += 2;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void strcopy(char *dest, char *src, int length) {
  strncpy(dest, src, length);
  dest[length] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strcopy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%ebx
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strcopy(char *dest, char *src, int length) {
  strncpy(dest, src, length);
  dest[length] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcopy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  mov    %ebx,%edx
  sub    $0x8,%rsp
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strcopy(char *dest, char *src, int length) {
  strncpy(dest, src, length);
  dest[length] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcopy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  mov    %ebx,%edx
  sub    $0x8,%rsp
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strcopy(char *dest, char *src, int length) {
  strncpy(dest, src, length);
  dest[length] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L0
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jne    L0
  mov    $0x1,%eax
  jmp    L13
L0:
  mov    $0x2,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int foo(float a, float b) {
  if (a == b)
    return 1;
  else
    return 2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  ucomiss %xmm1,%xmm0
  jp     L14
  mov    $0x1,%eax
  jne    L14
L21:
  ret
L14:
  mov    $0x2,%eax
  jmp    L21
```

assistant: ```c
int foo(float a, float b) {
  if (a == b)
    return 1;
  else
    return 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  ucomiss %xmm1,%xmm0
  jp     L5
  mov    $0x1,%eax
  jne    L5
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int foo(float a, float b) {
  if (a == b)
    return 1;
  else
    return 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  ucomiss %xmm1,%xmm0
  jp     L6
  mov    $0x1,%eax
  jne    L6
  ret
  nopl   0x0(%rax)
L6:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int foo(float a, float b) {
  if (a == b)
    return 1;
  else
    return 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L60
  mov    $0x0,%eax
  jmp    L116
L60:
  cmpl   $0x3,-0x14(%rbp)
  jg     L52
  mov    $0x1,%eax
  jmp    L116
L52:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L70
  mov    $0x0,%eax
  jmp    L116
L70:
  cmpl   $0x8,-0x14(%rbp)
  jg     L49
  mov    $0x1,%eax
  jmp    L116
L49:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L3
  mov    $0x0,%eax
  jmp    L116
L3:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x5,-0x8(%rbp)
  jmp    L154
L46:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L129
  mov    $0x0,%eax
  jmp    L116
L129:
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L108
  mov    $0x0,%eax
  jmp    L116
L108:
  addl   $0x6,-0x8(%rbp)
L154:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L46
  mov    $0x1,%eax
L116:
  leave
  ret
```

assistant: ```c
bool is_prime(int n) {
  if (n <= 1)
    return false;
  if (n < 4)
    return true;
  if (n % 2 == 0)
    return false;
  if (n < 9)
    return true;
  if (n % 3 == 0)
    return false;
  int r = floor(sqrt(n));
  int f = 5;
  while (f <= r) {
    if (n % f == 0)
      return false;
    if (n % (f + 2) == 0)
      return false;
    f += 6;
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L65
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jle    L41
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L41
  mov    $0x1,%eax
  cmp    $0x8,%edi
  jle    L41
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  jne    L86
L41:
  pop    %rbx
  ret
L86:
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%edi
  cmp    $0x4,%eax
  jle    L17
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L41
  movslq %ebx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x2,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L41
  mov    $0x5,%ecx
L114:
  mov    %ecx,%esi
  add    $0x6,%ecx
  cmp    %ecx,%edi
  jl     L30
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  je     L41
  add    $0x8,%esi
  mov    %ebx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  jne    L114
  jmp    L41
L30:
  mov    $0x1,%eax
  jmp    L41
L17:
  mov    $0x1,%eax
  jmp    L41
L65:
  ret
```

assistant: ```c
bool is_prime(int n) {
  if (n <= 1)
    return false;
  if (n < 4)
    return true;
  if (n % 2 == 0)
    return false;
  if (n < 9)
    return true;
  if (n % 3 == 0)
    return false;
  int r = floor(sqrt(n));
  int f = 5;
  while (f <= r) {
    if (n % f == 0)
      return false;
    if (n % (f + 2) == 0)
      return false;
    f += 6;
  }
  return true;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L109
  push   %r12
  mov    %edi,%r12d
  cmp    $0x3,%edi
  jle    L34
  test   $0x1,%dil
  je     L93
  cmp    $0x8,%edi
  jle    L34
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L98
L93:
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   (%rax)
L98:
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%edi
  cmp    $0x4,%eax
  jle    L34
  imul   $0xcccccccd,%r12d,%eax
  add    $0x19999999,%eax
  cmp    $0x33333332,%eax
  jbe    L93
  imul   $0xb6db6db7,%r12d,%eax
  add    $0x12492492,%eax
  cmp    $0x24924924,%eax
  jbe    L93
  mov    $0x5,%ecx
  jmp    L86
L18:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L93
  mov    %r12d,%eax
  add    $0x8,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L93
L86:
  mov    %ecx,%esi
  add    $0x6,%ecx
  cmp    %ecx,%edi
  jge    L18
L34:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L109:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool is_prime(int n) {
  if (n <= 1)
    return false;
  if (n < 4)
    return true;
  if (n % 2 == 0)
    return false;
  if (n < 9)
    return true;
  if (n % 3 == 0)
    return false;
  int r = floor(sqrt(n));
  int f = 5;
  while (f <= r) {
    if (n % f == 0)
      return false;
    if (n % (f + 2) == 0)
      return false;
    f += 6;
  }
  return true;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L96
  push   %r12
  mov    %edi,%r12d
  cmp    $0x3,%edi
  jle    L29
  test   $0x1,%dil
  je     L94
  cmp    $0x8,%edi
  jle    L29
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L82
L94:
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   (%rax)
L82:
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%edi
  cmp    $0x4,%eax
  jle    L29
  imul   $0xcccccccd,%r12d,%eax
  add    $0x19999999,%eax
  cmp    $0x33333332,%eax
  jbe    L94
  imul   $0xb6db6db7,%r12d,%eax
  add    $0x12492492,%eax
  cmp    $0x24924924,%eax
  jbe    L94
  mov    $0x5,%ecx
  jmp    L28
L16:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L94
  mov    %r12d,%eax
  add    $0x8,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L94
L28:
  mov    %ecx,%esi
  add    $0x6,%ecx
  cmp    %ecx,%edi
  jge    L16
L29:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L96:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool is_prime(int n) {
  if (n <= 1)
    return false;
  if (n < 4)
    return true;
  if (n % 2 == 0)
    return false;
  if (n < 9)
    return true;
  if (n % 3 == 0)
    return false;
  int r = floor(sqrt(n));
  int f = 5;
  while (f <= r) {
    if (n % f == 0)
      return false;
    if (n % (f + 2) == 0)
      return false;
    f += 6;
  }
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<udiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L21
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <raise@plt>
  jmp    L21
L12:
  shll   -0x18(%rbp)
  shll   -0x4(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jns    L12
  jmp    L69
L20:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  ja     L45
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L45:
  shrl   -0x18(%rbp)
  shrl   -0x4(%rbp)
L69:
  cmpl   $0x0,-0x4(%rbp)
  jne    L20
  cmpq   $0x0,-0x20(%rbp)
  je     L22
  mov    -0x20(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
L22:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int udiv(unsigned int num, unsigned int den, unsigned int *rem_p) {
  unsigned int quot = 0, qbit = 1;
  if (den == 0) {
    raise(SIGFPE);
  }
  while ((signed int)den >= 0) {
    den <<= 1;
    qbit <<= 1;
  }
  while (qbit) {
    if (den <= num) {
      num -= den;
      quot += qbit;
    }
    den >>= 1;
    qbit >>= 1;
  }
  if (rem_p)
    *rem_p = num;
  return quot;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<udiv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rdx,%r12
  test   %esi,%esi
  je     L87
  js     L36
L56:
  mov    $0x1,%eax
L29:
  add    %eax,%eax
  add    %ebx,%ebx
  jns    L29
  test   %eax,%eax
  je     L48
L26:
  mov    $0x0,%ecx
  jmp    L10
L87:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  jmp    L56
L36:
  mov    $0x1,%eax
  jmp    L26
L57:
  shr    %ebx
  shr    %eax
  je     L90
L10:
  cmp    %ebx,%ebp
  jb     L57
  sub    %ebx,%ebp
  add    %eax,%ecx
  jmp    L57
L48:
  mov    %eax,%ecx
L90:
  test   %r12,%r12
  je     L76
  mov    %ebp,(%r12)
L76:
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int udiv(unsigned int num, unsigned int den, unsigned int *rem_p) {
  unsigned int quot = 0, qbit = 1;
  if (den == 0) {
    raise(SIGFPE);
  }
  while ((signed int)den >= 0) {
    den <<= 1;
    qbit <<= 1;
  }
  while (qbit) {
    if (den <= num) {
      num -= den;
      quot += qbit;
    }
    den >>= 1;
    qbit >>= 1;
  }
  if (rem_p)
    *rem_p = num;
  return quot;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<udiv>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  je     L50
  mov    $0x1,%eax
  js     L22
L8:
  mov    $0x1,%eax
  nop
L47:
  add    %eax,%eax
  add    %ebx,%ebx
  jns    L47
  test   %eax,%eax
  je     L11
L22:
  xor    %r8d,%r8d
  nopl   (%rax)
L77:
  cmp    %ebx,%ebp
  jb     L66
  sub    %ebx,%ebp
  add    %eax,%r8d
L66:
  shr    %ebx
  shr    %eax
  jne    L77
L5:
  test   %r12,%r12
  je     L42
  mov    %ebp,(%r12)
L42:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L50:
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  jmp    L8
L11:
  xor    %r8d,%r8d
  jmp    L5
```

assistant: ```c
unsigned int udiv(unsigned int num, unsigned int den, unsigned int *rem_p) {
  unsigned int quot = 0, qbit = 1;
  if (den == 0) {
    raise(SIGFPE);
  }
  while ((signed int)den >= 0) {
    den <<= 1;
    qbit <<= 1;
  }
  while (qbit) {
    if (den <= num) {
      num -= den;
      quot += qbit;
    }
    den >>= 1;
    qbit >>= 1;
  }
  if (rem_p)
    *rem_p = num;
  return quot;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<udiv>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  je     L72
  mov    $0x1,%eax
  js     L89
L7:
  mov    $0x1,%eax
  nop
L84:
  add    %eax,%eax
  add    %ebx,%ebx
  jns    L84
  test   %eax,%eax
  je     L49
L89:
  xor    %r8d,%r8d
  nopl   (%rax)
L83:
  cmp    %ebx,%ebp
  jb     L34
  sub    %ebx,%ebp
  add    %eax,%r8d
L34:
  shr    %ebx
  shr    %eax
  jne    L83
L0:
  test   %r12,%r12
  je     L87
  mov    %ebp,(%r12)
L87:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L72:
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  jmp    L7
L49:
  xor    %r8d,%r8d
  jmp    L0
```

assistant: ```c
unsigned int udiv(unsigned int num, unsigned int den, unsigned int *rem_p) {
  unsigned int quot = 0, qbit = 1;
  if (den == 0) {
    raise(SIGFPE);
  }
  while ((signed int)den >= 0) {
    den <<= 1;
    qbit <<= 1;
  }
  while (qbit) {
    if (den <= num) {
      num -= den;
      quot += qbit;
    }
    den >>= 1;
    qbit >>= 1;
  }
  if (rem_p)
    *rem_p = num;
  return quot;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uh_usb_parse_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L13:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  jne    L13
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int uh_usb_parse_path(char *buf) {
  int pos = 0;
  while (buf[pos] != ';') {
    pos++;
  }
  pos = pos + 1;
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uh_usb_parse_path>:
  endbr64
  cmpb   $0x3b,(%rdi)
  je     L28
  mov    $0x1,%edx
L29:
  mov    %edx,%eax
  add    $0x1,%rdx
  cmpb   $0x3b,-0x1(%rdi,%rdx,1)
  jne    L29
L24:
  add    $0x1,%eax
  ret
L28:
  mov    $0x0,%eax
  jmp    L24
```

assistant: ```c
int uh_usb_parse_path(char *buf) {
  int pos = 0;
  while (buf[pos] != ';') {
    pos++;
  }
  pos = pos + 1;
  return pos;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uh_usb_parse_path>:
  endbr64
  cmpb   $0x3b,(%rdi)
  je     L6
  mov    $0x1,%edx
  xchg   %ax,%ax
L10:
  mov    %edx,%eax
  add    $0x1,%rdx
  cmpb   $0x3b,-0x1(%rdi,%rdx,1)
  jne    L10
  add    $0x1,%eax
  ret
  nopl   0x0(%rax)
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int uh_usb_parse_path(char *buf) {
  int pos = 0;
  while (buf[pos] != ';') {
    pos++;
  }
  pos = pos + 1;
  return pos;
}
```