ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<cleanupDCOPsocket>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jne    L17
L18:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x1018,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  cltq
  mov    $0x3a,%esi
  mov    %r12,%rdi
  movb   $0x0,-0x1(%r12,%rax,1)
  call   <strchr@plt>
  test   %rax,%rax
  je     L28
  lea    0x1(%rax),%rdi
  call   <unlink@plt>
L28:
  mov    %rsp,%rbp
  mov    %r12,%rcx
  mov    $0x1000,%esi
  mov    %rbp,%rdi
  lea    D5(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  jmp    L18
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: iceauth remove netid='%s'

assistant: ```c
void cleanupDCOPsocket(char *buffer) {
  char cmd[4096];
  const char *socket_file;
  int l;
  l = strlen(buffer);
  if (!l)
    return;
  buffer[l - 1] = '\0';
  socket_file = strchr(buffer, ':');
  if (socket_file)
    socket_file++;
  if (socket_file)
    unlink(socket_file);
  snprintf(cmd, 4096, "iceauth remove netid='%s'", buffer);
  system(cmd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L55:
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L15:
  mov    -0x8(%rbp),%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  cmpl   $0x9,-0x8(%rbp)
  jne    L22
  cmpl   $0x9,-0x4(%rbp)
  je     L20
L22:
  mov    $0x2c,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
L20:
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0x9,-0x4(%rbp)
  jle    L15
  addl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0x9,-0x8(%rbp)
  jle    L55
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int n;
  int i;
  for (n = 0; n <= 9; n++) {
    for (i = 0; i <= 9; i++) {
      putchar('0' + n);
      putchar('0' + i);
      if (n != 9 || i != 9) {
        putchar(',');
        putchar(' ');
      }
    }
  }
  putchar('\n');
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x30,%r14d
  mov    $0x0,%r12d
  mov    $0x0,%r15d
  jmp    L44
L3:
  mov    %ebp,%ebx
L16:
  mov    $0x2c,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  lea    0x1(%rbx),%ebp
  cmp    $0x9,%ebx
  je     L31
  mov    %r13d,%edi
  call   <putchar@plt>
  lea    0x31(%rbx),%edi
  call   <putchar@plt>
  cmp    $0x9,%r12d
  jne    L3
  cmp    $0x9,%ebp
  jne    L3
L29:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  add    $0x1,%r12d
  add    $0x1,%r14d
  cmp    $0xa,%r12d
  je     L29
L44:
  mov    %r14d,%r13d
  mov    %r14d,%edi
  call   <putchar@plt>
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    %r15d,%ebx
  jmp    L16
```

assistant: ```c
int main(void) {
  int n;
  int i;
  for (n = 0; n <= 9; n++) {
    for (i = 0; i <= 9; i++) {
      putchar('0' + n);
      putchar('0' + i);
      if (n != 9 || i != 9) {
        putchar(',');
        putchar(' ');
      }
    }
  }
  putchar('\n');
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
L13:
  lea    0x30(%rbp),%r13d
  xor    %ebx,%ebx
  mov    %r13d,%edi
  call   <putchar@plt>
  mov    $0x30,%edi
  call   <putchar@plt>
L14:
  mov    $0x2c,%edi
  lea    0x1(%rbx),%r12d
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    $0x9,%ebx
  je     L21
  mov    %r13d,%edi
  call   <putchar@plt>
  lea    0x31(%rbx),%edi
  call   <putchar@plt>
  cmp    $0x9,%ebp
  jne    L53
  cmp    $0x9,%r12d
  jne    L53
L37:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  add    $0x1,%ebp
  cmp    $0xa,%ebp
  jne    L13
  jmp    L37
  nopl   0x0(%rax)
L53:
  mov    %r12d,%ebx
  jmp    L14
```

assistant: ```c
int main(void) {
  int n;
  int i;
  for (n = 0; n <= 9; n++) {
    for (i = 0; i <= 9; i++) {
      putchar('0' + n);
      putchar('0' + i);
      if (n != 9 || i != 9) {
        putchar(',');
        putchar(' ');
      }
    }
  }
  putchar('\n');
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
L4:
  lea    0x30(%rbp),%r13d
  xor    %ebx,%ebx
  mov    %r13d,%edi
  call   <putchar@plt>
  mov    $0x30,%edi
  call   <putchar@plt>
L25:
  mov    $0x2c,%edi
  lea    0x1(%rbx),%r12d
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    $0x9,%ebx
  je     L5
  mov    %r13d,%edi
  call   <putchar@plt>
  lea    0x31(%rbx),%edi
  call   <putchar@plt>
  cmp    $0x9,%ebp
  jne    L6
  cmp    $0x9,%r12d
  jne    L6
L39:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  add    $0x1,%ebp
  cmp    $0xa,%ebp
  jne    L4
  jmp    L39
  nopl   0x0(%rax)
L6:
  mov    %r12d,%ebx
  jmp    L25
```

assistant: ```c
int main(void) {
  int n;
  int i;
  for (n = 0; n <= 9; n++) {
    for (i = 0; i <= 9; i++) {
      putchar('0' + n);
      putchar('0' + i);
      if (n != 9 || i != 9) {
        putchar(',');
        putchar(' ');
      }
    }
  }
  putchar('\n');
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<displayboard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L3:
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x2,-0x4(%rbp)
  jle    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0x2,-0x8(%rbp)
  jle    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0:  %c 

assistant: ```c
void displayboard(char *board[]) {
  int i, j;
  printf("\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++)
      printf(" %c ", board[i][j]);
    printf("\n");
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<displayboard>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rbp
  add    $0x18,%r13
  lea    D9(%rip),%r12
  jmp    L29
L37:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L27
L29:
  mov    $0x0,%ebx
L0:
  mov    0x0(%rbp),%rax
  movsbl (%rax,%rbx,1),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L0
  jmp    L37
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string

tool: D9:  %c 

assistant: ```c
void displayboard(char *board[]) {
  int i, j;
  printf("\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++)
      printf(" %c ", board[i][j]);
    printf("\n");
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<displayboard>:
  endbr64
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  push   %rbx
  lea    0x18(%rbp),%r13
  sub    $0x8,%rsp
  call   <putchar@plt>
L2:
  xor    %ebx,%ebx
L15:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  movsbl (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x3,%rbx
  jne    L15
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L2
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D0:  %c 

assistant: ```c
void displayboard(char *board[]) {
  int i, j;
  printf("\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++)
      printf(" %c ", board[i][j]);
    printf("\n");
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<displayboard>:
  endbr64
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  push   %rbx
  lea    0x18(%rbp),%r13
  sub    $0x8,%rsp
  call   <putchar@plt>
L16:
  xor    %ebx,%ebx
L10:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  movsbl (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x3,%rbx
  jne    L10
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L16
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3:  %c 

assistant: ```c
void displayboard(char *board[]) {
  int i, j;
  printf("\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++)
      printf(" %c ", board[i][j]);
    printf("\n");
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getDebugIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  jmp    L8
L19:
  mov    $0xffffffff,%eax
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0: GSQINDEX

assistant: ```c
int getDebugIndex() {
  char *indexString;
  int index;
  if ((indexString = getenv("GSQINDEX")) != NULL) {
    index = atoi(indexString);
    return index;
  } else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getDebugIndex>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L16
  mov    %rax,%rdi
  call   <atoi@plt>
L9:
  add    $0x8,%rsp
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L9
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: GSQINDEX

assistant: ```c
int getDebugIndex() {
  char *indexString;
  int index;
  if ((indexString = getenv("GSQINDEX")) != NULL) {
    index = atoi(indexString);
    return index;
  } else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getDebugIndex>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <atoi@plt>
  nopl   (%rax)
L5:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: GSQINDEX

assistant: ```c
int getDebugIndex() {
  char *indexString;
  int index;
  if ((indexString = getenv("GSQINDEX")) != NULL) {
    index = atoi(indexString);
    return index;
  } else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getDebugIndex>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <atoi@plt>
  nopl   (%rax)
L4:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: GSQINDEX

assistant: ```c
int getDebugIndex() {
  char *indexString;
  int index;
  if ((indexString = getenv("GSQINDEX")) != NULL) {
    index = atoi(indexString);
    return index;
  } else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x3f60a4d,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  lea    0x50edd68c(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x4cf7cc3f,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x4cf7cc3f,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x4cf7cc3f,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iswhite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x20,-0x4(%rbp)
  je     L10
  cmpb   $0x9,-0x4(%rbp)
  jne    L1
L10:
  mov    $0x1,%eax
  jmp    L0
L1:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int iswhite(char c) {
  if (c == ' ' || c == '\t')
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iswhite>:
  endbr64
  cmp    $0x20,%dil
  sete   %al
  cmp    $0x9,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int iswhite(char c) {
  if (c == ' ' || c == '\t')
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<iswhite>:
  endbr64
  cmp    $0x20,%dil
  sete   %al
  cmp    $0x9,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int iswhite(char c) {
  if (c == ' ' || c == '\t')
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iswhite>:
  endbr64
  cmp    $0x20,%dil
  sete   %al
  cmp    $0x9,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int iswhite(char c) {
  if (c == ' ' || c == '\t')
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <quick_increase@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L25:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <quick_decrease@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L15
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: %d 

assistant: ```c
void quick_sort(int *front, int *end) {
  int i;
  int size = end - front;
  quick_increase(front, end);
  for (i = 0; i <= size; ++i)
    printf("%d ", *(front + i));
  printf("\n");
  quick_decrease(front, end);
  for (i = 0; i <= size; ++i)
    printf("%d ", *(front + i));
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quick_sort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rsi,%rbx
  sub    %rdi,%rbx
  sar    $0x2,%rbx
  call   <quick_increase@plt>
  test   %ebx,%ebx
  js     L12
  mov    %ebx,%r12d
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L20:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <quick_decrease@plt>
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L28:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L28
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <quick_decrease@plt>
  jmp    L32
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D0: %d 

assistant: ```c
void quick_sort(int *front, int *end) {
  int i;
  int size = end - front;
  quick_increase(front, end);
  for (i = 0; i <= size; ++i)
    printf("%d ", *(front + i));
  printf("\n");
  quick_decrease(front, end);
  for (i = 0; i <= size; ++i)
    printf("%d ", *(front + i));
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quick_sort>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    %rdi,%rbx
  sar    $0x2,%rbx
  call   <quick_increase@plt>
  test   %ebx,%ebx
  js     L8
  mov    %ebx,%r12d
  lea    D5(%rip),%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L16:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jge    L16
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <quick_decrease@plt>
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jge    L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <quick_decrease@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D5: %d 

assistant: ```c
void quick_sort(int *front, int *end) {
  int i;
  int size = end - front;
  quick_increase(front, end);
  for (i = 0; i <= size; ++i)
    printf("%d ", *(front + i));
  printf("\n");
  quick_decrease(front, end);
  for (i = 0; i <= size; ++i)
    printf("%d ", *(front + i));
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quick_sort>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    %rdi,%rbx
  sar    $0x2,%rbx
  call   <quick_increase@plt>
  test   %ebx,%ebx
  js     L17
  mov    %ebx,%r12d
  lea    D1(%rip),%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L22:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jge    L22
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <quick_decrease@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jge    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <quick_decrease@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: %d 

assistant: ```c
void quick_sort(int *front, int *end) {
  int i;
  int size = end - front;
  quick_increase(front, end);
  for (i = 0; i <= size; ++i)
    printf("%d ", *(front + i));
  printf("\n");
  quick_decrease(front, end);
  for (i = 0; i <= size; ++i)
    printf("%d ", *(front + i));
  return;
}
```