user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x38(%rbp),%xmm2
  movsd  D79(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  movsd  -0x28(%rbp),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movsd  -0x30(%rbp),%xmm0
  movq   %rax,%xmm1
  subsd  %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movq   D2(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  -0x48(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x38(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L3
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  je     L44
L3:
  mov    -0x30(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x38(%rbp),%xmm2
  movsd  D79(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  movsd  -0x28(%rbp),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L16
L44:
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L29
L16:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L29:
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D53
type_infered: string
name: parse_data
arguments: data_tag: D79
type_infered: byte[8]
name: parse_data
arguments: data_tag: D2
type_infered: byte[8]
name: parse_data
arguments: data_tag: D67
type_infered: string
name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string
name: parse_data
arguments: data_tag: D50
type_infered: string

tool: D53: %lf %lf %lf

tool: {"D79": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D67: Impossivel calcular

tool: D19: R1 = %.5lf


tool: D20: R2 = %.5lf


tool: D50: pause

assistant: ```c
int main() {
  double A, B, C, R1, R2, delta;
  scanf("%lf %lf %lf", &A, &B, &C);
  delta = pow(B, 2) - 4 * A * C;
  R1 = (-B + sqrt(delta)) / (2 * A);
  R2 = (-B - sqrt(delta)) / (2 * A);
  if (A == 0 || (pow(B, 2) - 4 * A * C) < 0)
    printf("Impossivel calcular\n");
  else {
    printf("R1 = %.5lf\n", R1);
    printf("R2 = %.5lf\n", R2);
  }
  system("pause");
  return 0;
}
```