ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<Read_Status_Register>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <CE_Low@plt>
  mov    $0x5,%edi
  call   <Send_Byte@plt>
  xor    %eax,%eax
  call   <Get_Byte@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <CE_High@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned char Read_Status_Register() {
  unsigned char byte = 0;
  CE_Low();
  Send_Byte(0x05);
  byte = Get_Byte();
  CE_High();
  return byte;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Read_Status_Register>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <CE_Low@plt>
  mov    $0x5,%edi
  call   <Send_Byte@plt>
  xor    %eax,%eax
  call   <Get_Byte@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <CE_High@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned char Read_Status_Register() {
  unsigned char byte = 0;
  CE_Low();
  Send_Byte(0x05);
  byte = Get_Byte();
  CE_High();
  return byte;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L6:
  cmpl   $0xa,-0x4(%rbp)
  jne    L29
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L6
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d


assistant: ```c
main() {
  int code;
  int end = getchar();
  int newLineCounter = 0;
  while ((code = getchar()) != end) {
    if (code == '\n') {
      ++newLineCounter;
    }
    printf("%d\n", newLineCounter);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  mov    $0x0,%ebx
  lea    D3(%rip),%r12
  jmp    L15
L19:
  cmp    $0xa,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L15:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    %eax,%ebp
  jne    L19
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string

tool: D3: %d


assistant: ```c
main() {
  int code;
  int end = getchar();
  int newLineCounter = 0;
  while ((code = getchar()) != end) {
    if (code == '\n') {
      ++newLineCounter;
    }
    printf("%d\n", newLineCounter);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <getchar@plt>
  mov    %eax,%ebp
  jmp    L0
  nopl   0x0(%rax)
L8:
  cmp    $0xa,%eax
  mov    %r12,%rdi
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  mov    %ebx,%esi
  call   <printf@plt>
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,%ebp
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: %d


assistant: ```c
main() {
  int code;
  int end = getchar();
  int newLineCounter = 0;
  while ((code = getchar()) != end) {
    if (code == '\n') {
      ++newLineCounter;
    }
    printf("%d\n", newLineCounter);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <getchar@plt>
  mov    %eax,%ebp
  jmp    L15
  nopl   0x0(%rax)
L5:
  cmp    $0xa,%eax
  mov    %r12,%rdi
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  mov    %ebx,%esi
  call   <printf@plt>
L15:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,%ebp
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: %d


assistant: ```c
main() {
  int code;
  int end = getchar();
  int newLineCounter = 0;
  while ((code = getchar()) != end) {
    if (code == '\n') {
      ++newLineCounter;
    }
    printf("%d\n", newLineCounter);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L24
L0:
  lea    -0x44(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x44(%rbp),%ebx
  mov    $0x5,%edi
  call   <sqrtl@plt>
  add    $0x3,%rax
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <powl@plt>
  fstpt  -0x30(%rbp)
  push   -0x28(%rbp)
  push   -0x30(%rbp)
  call   <log10l@plt>
  add    $0x10,%rsp
  add    $0x1,%eax
  mov    %eax,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L3
L14:
  fldt   -0x30(%rbp)
  fldt   0xda7(%rip)        # 2020 <_fini+0xd34>
  fdivrp %st,%st(1)
  fstpt  -0x30(%rbp)
  addl   $0x1,-0x3c(%rbp)
L3:
  mov    -0x38(%rbp),%eax
  sub    $0x3,%eax
  cmp    %eax,-0x3c(%rbp)
  jl     L14
  push   -0x28(%rbp)
  push   -0x30(%rbp)
  call   <floor@plt>
  add    $0x10,%rsp
  mov    %eax,-0x34(%rbp)
  mov    -0x40(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x40(%rbp)
L24:
  mov    -0x48(%rbp),%eax
  cmp    %eax,-0x40(%rbp)
  jl     L0
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type_guessed: string
name: read_data
arguments: data_tag: D23
type_guessed: string

tool: D16: %d

tool: D23: Case #%d: %03d


assistant: ```c
int main(int argc, char *argv[]) {
  int T;
  int i;
  int j;
  int exponent;
  int digits;
  long double num;
  int final;
  scanf("%d", &T);
  for (i = 0; i < T; i++) {
    scanf("%d", &exponent);
    num = powl(3 + sqrtl(5), exponent);
    digits = (int)log10l(num) + 1;
    for (j = 0; j < digits - 3; j++) {
      num /= 10;
    }
    final = floor(num);
    printf("Case #%d: %03d\n", i + 1, final);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x10(%rsp)
  jle    L44
  mov    $0x0,%ebx
  lea    0x14(%rsp),%r13
  lea    D25(%rip),%r12
  lea    D6(%rip),%rbp
L14:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%r14d
  mov    $0x5,%edi
  call   <sqrtl@plt>
  lea    0x3(%rax),%rdi
  mov    %r14d,%esi
  call   <powl@plt>
  fld    %st(0)
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <log10l@plt>
  add    $0x10,%rsp
  cmp    $0x2,%eax
  jle    L30
  sub    $0x2,%eax
  mov    $0x0,%edx
L40:
  fldt   (%rsp)
  fdivs  0xd95(%rip)        # 2014 <_fini+0xd38>
  fstpt  (%rsp)
  add    $0x1,%edx
  cmp    %edx,%eax
  jne    L40
L30:
  push   0x8(%rsp)
  push   0x8(%rsp)
  call   <floor@plt>
  mov    %eax,%edx
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  cmp    0x10(%rsp),%ebx
  jl     L14
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D25: %d

tool: D6: Case #%d: %03d


assistant: ```c
int main(int argc, char *argv[]) {
  int T;
  int i;
  int j;
  int exponent;
  int digits;
  long double num;
  int final;
  scanf("%d", &T);
  for (i = 0; i < T; i++) {
    scanf("%d", &exponent);
    num = powl(3 + sqrtl(5), exponent);
    digits = (int)log10l(num) + 1;
    for (j = 0; j < digits - 3; j++) {
      num /= 10;
    }
    final = floor(num);
    printf("Case #%d: %03d\n", i + 1, final);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%edi
  test   %edi,%edi
  jle    L33
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r13
  lea    D17(%rip),%r12
  xchg   %ax,%ax
L34:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%r14d
  mov    $0x5,%edi
  call   <sqrtl@plt>
  lea    0x3(%rax),%rdi
  mov    %r14d,%esi
  call   <powl@plt>
  sub    $0x10,%rsp
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x10(%rsp)
  call   <log10l@plt>
  pop    %rcx
  pop    %rsi
  fldt   (%rsp)
  cmp    $0x2,%eax
  flds   0xe5e(%rip)        # 2014 <_fini+0xd28>
  jle    L36
  sub    $0x2,%eax
  xor    %edx,%edx
  nopl   (%rax)
L39:
  fdivr  %st,%st(1)
  add    $0x1,%edx
  cmp    %edx,%eax
  jne    L39
  fstp   %st(0)
  jmp    L59
  nopl   (%rax)
L36:
  fstp   %st(0)
  nopw   0x0(%rax,%rax,1)
L59:
  sub    $0x10,%rsp
  add    $0x1,%ebx
  fstpt  (%rsp)
  call   <floor@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    0x10(%rsp),%ebx
  jl     L34
L33:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string

tool: D2: %d

tool: D17: Case #%d: %03d


assistant: ```c
int main(int argc, char *argv[]) {
  int T;
  int i;
  int j;
  int exponent;
  int digits;
  long double num;
  int final;
  scanf("%d", &T);
  for (i = 0; i < T; i++) {
    scanf("%d", &exponent);
    num = powl(3 + sqrtl(5), exponent);
    digits = (int)log10l(num) + 1;
    for (j = 0; j < digits - 3; j++) {
      num /= 10;
    }
    final = floor(num);
    printf("Case #%d: %03d\n", i + 1, final);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%edi
  test   %edi,%edi
  jle    L59
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r13
  lea    D12(%rip),%r12
  xchg   %ax,%ax
L54:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%r14d
  mov    $0x5,%edi
  call   <sqrtl@plt>
  lea    0x3(%rax),%rdi
  mov    %r14d,%esi
  call   <powl@plt>
  sub    $0x10,%rsp
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x10(%rsp)
  call   <log10l@plt>
  pop    %rcx
  pop    %rsi
  fldt   (%rsp)
  cmp    $0x2,%eax
  flds   0xe5e(%rip)        # 2014 <_fini+0xd28>
  jle    L27
  sub    $0x2,%eax
  xor    %edx,%edx
  nopl   (%rax)
L43:
  fdivr  %st,%st(1)
  add    $0x1,%edx
  cmp    %edx,%eax
  jne    L43
  fstp   %st(0)
  jmp    L35
  nopl   (%rax)
L27:
  fstp   %st(0)
  nopw   0x0(%rax,%rax,1)
L35:
  sub    $0x10,%rsp
  add    $0x1,%ebx
  fstpt  (%rsp)
  call   <floor@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    0x10(%rsp),%ebx
  jl     L54
L59:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
type_infered: string
name: parse_data
arguments: tag: D12
type_infered: string

tool: D17: %d

tool: D12: Case #%d: %03d


assistant: ```c
int main(int argc, char *argv[]) {
  int T;
  int i;
  int j;
  int exponent;
  int digits;
  long double num;
  int final;
  scanf("%d", &T);
  for (i = 0; i < T; i++) {
    scanf("%d", &exponent);
    num = powl(3 + sqrtl(5), exponent);
    digits = (int)log10l(num) + 1;
    for (j = 0; j < digits - 3; j++) {
      num /= 10;
    }
    final = floor(num);
    printf("Case #%d: %03d\n", i + 1, final);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%edi
  call   <cont_add@plt>
  mov    $0x7,%edi
  call   <cont_add@plt>
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  cont_add(4);
  return cont_add(7);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <cont_add@plt>
  mov    $0x7,%edi
  call   <cont_add@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  cont_add(4);
  return cont_add(7);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <cont_add@plt>
  mov    $0x7,%edi
  add    $0x8,%rsp
  jmp    1050 <cont_add@plt>
```

assistant: ```c
int main() {
  cont_add(4);
  return cont_add(7);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <cont_add@plt>
  mov    $0x7,%edi
  add    $0x8,%rsp
  jmp    1050 <cont_add@plt>
```

assistant: ```c
int main() {
  cont_add(4);
  return cont_add(7);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bcm2835_rng_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x40000,%esi
  mov    $0x104004,%edi
  call   <bcm2835_write@plt>
  mov    $0x1,%esi
  mov    $0x104000,%edi
  call   <bcm2835_write@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int bcm2835_rng_init(void) {
  bcm2835_write(((0 + 0x104000) + 0x4), 0x40000);
  bcm2835_write(((0 + 0x104000) + 0x0), 0x1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bcm2835_rng_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40000,%esi
  mov    $0x104004,%edi
  call   <bcm2835_write@plt>
  mov    $0x1,%esi
  mov    $0x104000,%edi
  call   <bcm2835_write@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bcm2835_rng_init(void) {
  bcm2835_write(((0 + 0x104000) + 0x4), 0x40000);
  bcm2835_write(((0 + 0x104000) + 0x0), 0x1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bcm2835_rng_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40000,%esi
  mov    $0x104004,%edi
  call   <bcm2835_write@plt>
  mov    $0x1,%esi
  mov    $0x104000,%edi
  call   <bcm2835_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bcm2835_rng_init(void) {
  bcm2835_write(((0 + 0x104000) + 0x4), 0x40000);
  bcm2835_write(((0 + 0x104000) + 0x0), 0x1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bcm2835_rng_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40000,%esi
  mov    $0x104004,%edi
  call   <bcm2835_write@plt>
  mov    $0x1,%esi
  mov    $0x104000,%edi
  call   <bcm2835_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bcm2835_rng_init(void) {
  bcm2835_write(((0 + 0x104000) + 0x4), 0x40000);
  bcm2835_write(((0 + 0x104000) + 0x0), 0x1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L3
  mov    -0x14(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <b@plt>
  mov    %eax,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D5: l(%d)


assistant: ```c
int l(int param1) {
  int g1;
  printf("l(%d)\n", param1);
  g1 = param1;
  if (param1 > 1) {
    g1 = b(param1 + 2);
  }
  return g1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<l>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jg     L6
L7:
  mov    %ebx,%eax
  pop    %rbx
  ret
L6:
  lea    0x2(%rbx),%edi
  call   <b@plt>
  mov    %eax,%ebx
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string

tool: D7: l(%d)


assistant: ```c
int l(int param1) {
  int g1;
  printf("l(%d)\n", param1);
  g1 = param1;
  if (param1 > 1) {
    g1 = b(param1 + 2);
  }
  return g1;
}
```
user: What is the c source code of the assembly code below:

```asm
<l>:
  endbr64
  push   %r12
  mov    %edi,%esi
  mov    %edi,%r12d
  lea    D0(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%r12d
  jg     L9
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  lea    0x2(%r12),%edi
  pop    %r12
  jmp    1060 <b@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D0: l(%d)


assistant: ```c
int l(int param1) {
  int g1;
  printf("l(%d)\n", param1);
  g1 = param1;
  if (param1 > 1) {
    g1 = b(param1 + 2);
  }
  return g1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<l>:
  endbr64
  push   %r12
  mov    %edi,%esi
  mov    %edi,%r12d
  lea    D4(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%r12d
  jg     L7
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  lea    0x2(%r12),%edi
  pop    %r12
  jmp    1060 <b@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string

tool: D4: l(%d)


assistant: ```c
int l(int param1) {
  int g1;
  printf("l(%d)\n", param1);
  g1 = param1;
  if (param1 > 1) {
    g1 = b(param1 + 2);
  }
  return g1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stristr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2c(%rbp)
  jmp    L73
L88:
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jae    L16
  mov    $0x0,%eax
  jmp    L2
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L88
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L34
L87:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    -0x18(%rbp),%rax
  jmp    L2
L34:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L87
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x30(%rbp)
L73:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jae    L16
  mov    $0x0,%eax
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *stristr(const char *String, const char *Pattern) {
  char *pptr, *sptr, *start;
  unsigned int slen, plen;
  for (start = (char *)String, pptr = (char *)Pattern, slen = strlen(String), plen = strlen(Pattern); slen >= plen; start++, slen--) {
    while (toupper((int)*start) != toupper((int)*Pattern)) {
      start++;
      slen--;
      if (slen < plen)
        return (NULL);
    }
    sptr = start;
    pptr = (char *)Pattern;
    while (toupper((int)*sptr) == toupper((int)*pptr)) {
      sptr++;
      pptr++;
      if ('\0' == *pptr)
        return (start);
    }
  }
  return (NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stristr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  cmp    %eax,%r12d
  jb     L67
L89:
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  movsbl 0x0(%r13),%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L25
  add    $0x1,%rbp
  sub    $0x1,%r12d
  cmp    %r12d,%r14d
  jbe    L89
  mov    $0x0,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  mov    $0x0,%eax
  jmp    L3
L25:
  mov    $0x0,%ebx
L35:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %rax,%r15
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <toupper@plt>
  cmp    %rax,%r15
  jne    L34
  add    $0x1,%rbx
  cmpb   $0x0,0x0(%r13,%rbx,1)
  jne    L35
  mov    %rbp,%rax
  jmp    L3
L34:
  add    $0x1,%rbp
  sub    $0x1,%r12d
  cmp    %r12d,%r14d
  jbe    L89
  mov    $0x0,%eax
  jmp    L3
```

assistant: ```c
char *stristr(const char *String, const char *Pattern) {
  char *pptr, *sptr, *start;
  unsigned int slen, plen;
  for (start = (char *)String, pptr = (char *)Pattern, slen = strlen(String), plen = strlen(Pattern); slen >= plen; start++, slen--) {
    while (toupper((int)*start) != toupper((int)*Pattern)) {
      start++;
      slen--;
      if (slen < plen)
        return (NULL);
    }
    sptr = start;
    pptr = (char *)Pattern;
    while (toupper((int)*sptr) == toupper((int)*pptr)) {
      sptr++;
      pptr++;
      if ('\0' == *pptr)
        return (start);
    }
  }
  return (NULL);
}
```