user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D8(%rip),%r13
  lea    -0x34(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  call   <scanf@plt>
  movslq -0x34(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L36
L62:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L62
L36:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L168
L69:
  mov    %rsp,%r12
  shl    $0x2,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0x34(%rbp)
  jle    L164
  xor    %ebx,%ebx
  lea    -0x2c(%rbp),%r14
  nopl   0x0(%rax)
L9:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,-0x34(%rbp)
  jg     L9
L164:
  lea    -0x30(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%ecx
  test   %ecx,%ecx
  jle    L93
  lea    -0x1(%rcx),%eax
  mov    -0x30(%rbp),%edi
  cmp    $0x2,%eax
  jbe    L142
  mov    %ecx,%edx
  movd   %edi,%xmm4
  pxor   %xmm1,%xmm1
  mov    %r12,%rax
  shr    $0x2,%edx
  pshufd $0x0,%xmm4,%xmm3
  movdqa %xmm1,%xmm2
  shl    $0x4,%rdx
  add    %r12,%rdx
  nopl   0x0(%rax)
L135:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pcmpeqd %xmm3,%xmm0
  pcmpeqd %xmm2,%xmm0
  psubd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L135
  movdqa %xmm1,%xmm0
  mov    %ecx,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%esi
  test   $0x3,%cl
  je     L137
L1:
  movslq %eax,%rdx
  xor    %r8d,%r8d
  lea    (%r12,%rdx,4),%rdx
  cmp    (%rdx),%edi
  setne  %r8b
  add    %r8d,%esi
  lea    0x1(%rax),%r8d
  cmp    %ecx,%r8d
  jge    L137
  cmp    0x4(%rdx),%edi
  je     L98
  add    $0x1,%esi
L98:
  add    $0x2,%eax
  cmp    %eax,%ecx
  jle    L137
  cmp    0x8(%rdx),%edi
  je     L137
  add    $0x1,%esi
L137:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L168:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L69
L93:
  xor    %esi,%esi
  jmp    L137
L142:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L1
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string

tool: D8: %d

tool: D11: %d


assistant: ```c
int main() {
  int a = 0, b = 0, c = 0, counter = 0;
  scanf("%d", &a);
  int arr[a];
  memset(arr, 0, sizeof(arr));
  for (int count = 0; count < a; ++count) {
    scanf("%d", &c);
    arr[count] = c;
  }
  scanf("%d", &b);
  for (int cc = 0; cc < a; ++cc) {
    if (arr[cc] != b)
      ++counter;
  }
  printf("%d\n", counter);
  counter = 0;
  return 0;
}
```