ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edx,%eax
  sub    %edi,%eax
  pxor   %xmm4,%xmm4
  cvtsi2sd %eax,%xmm4
  movsd  %xmm4,0x8(%rsp)
  sub    %esi,%ecx
  pxor   %xmm5,%xmm5
  cvtsi2sd %ecx,%xmm5
  movsd  %xmm5,0x10(%rsp)
  cmp    %edi,%edx
  jl     L12
  mov    %edi,%ebx
  mov    %edx,%r12d
  mov    %r8d,%r13d
  mov    $0x0,%ebp
  pxor   %xmm6,%xmm6
  cvtsi2sd %esi,%xmm6
  movsd  %xmm6,0x18(%rsp)
L13:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  0x10(%rsp),%xmm0
  divsd  0x8(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  cvttsd2si %xmm0,%esi
  mov    %r13d,%edx
  mov    %ebx,%edi
  call   <draw_pixel@plt>
  add    $0x1,%ebx
  add    $0x1,%ebp
  cmp    %ebx,%r12d
  jge    L13
L12:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void print_line(int x1, int y1, int x2, int y2, int color) {
  double dx = x2 - x1;
  double dy = y2 - y1;
  int x, y;
  for (x = x1; x <= x2; x++) {
    y = y1 + dy * (x - x1) / dx;
    draw_pixel(x, y, color);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_line>:
  endbr64
  mov    %edx,%eax
  pxor   %xmm4,%xmm4
  sub    %esi,%ecx
  push   %r13
  sub    %edi,%eax
  pxor   %xmm5,%xmm5
  push   %r12
  cvtsi2sd %eax,%xmm4
  push   %rbp
  cvtsi2sd %ecx,%xmm5
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm5,0x10(%rsp)
  cmp    %edi,%edx
  jl     L14
  pxor   %xmm6,%xmm6
  mov    %edi,%r12d
  mov    %edx,%ebx
  mov    %r8d,%ebp
  cvtsi2sd %esi,%xmm6
  xor    %r13d,%r13d
  movsd  %xmm6,0x18(%rsp)
  nopl   (%rax)
L0:
  pxor   %xmm0,%xmm0
  mov    %r12d,%edi
  mov    %ebp,%edx
  add    $0x1,%r12d
  cvtsi2sd %r13d,%xmm0
  mulsd  0x10(%rsp),%xmm0
  add    $0x1,%r13d
  divsd  0x8(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  cvttsd2si %xmm0,%esi
  call   <draw_pixel@plt>
  cmp    %r12d,%ebx
  jge    L0
L14:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void print_line(int x1, int y1, int x2, int y2, int color) {
  double dx = x2 - x1;
  double dy = y2 - y1;
  int x, y;
  for (x = x1; x <= x2; x++) {
    y = y1 + dy * (x - x1) / dx;
    draw_pixel(x, y, color);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_line>:
  endbr64
  mov    %edx,%eax
  pxor   %xmm4,%xmm4
  sub    %esi,%ecx
  push   %r13
  sub    %edi,%eax
  pxor   %xmm5,%xmm5
  push   %r12
  cvtsi2sd %eax,%xmm4
  push   %rbp
  cvtsi2sd %ecx,%xmm5
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm5,0x10(%rsp)
  cmp    %edi,%edx
  jl     L6
  pxor   %xmm6,%xmm6
  mov    %edi,%r12d
  mov    %edx,%ebx
  mov    %r8d,%ebp
  cvtsi2sd %esi,%xmm6
  xor    %r13d,%r13d
  movsd  %xmm6,0x18(%rsp)
  nopl   (%rax)
L10:
  pxor   %xmm0,%xmm0
  mov    %r12d,%edi
  mov    %ebp,%edx
  add    $0x1,%r12d
  cvtsi2sd %r13d,%xmm0
  mulsd  0x10(%rsp),%xmm0
  add    $0x1,%r13d
  divsd  0x8(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  cvttsd2si %xmm0,%esi
  call   <draw_pixel@plt>
  cmp    %r12d,%ebx
  jge    L10
L6:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void print_line(int x1, int y1, int x2, int y2, int color) {
  double dx = x2 - x1;
  double dy = y2 - y1;
  int x, y;
  for (x = x1; x <= x2; x++) {
    y = y1 + dy * (x - x1) / dx;
    draw_pixel(x, y, color);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<llz_shortenrg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L12:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L12
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double llz_shortenrg(double *buf, double *win, int frame_len) {
  int i;
  double x;
  double enrg;
  enrg = 0.0;
  x = 0.0;
  for (i = 0; i < frame_len; i++) {
    x = buf[i];
    x *= win[i];
    enrg += x * x;
  }
  return enrg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<llz_shortenrg>:
  endbr64
  test   %edx,%edx
  jle    L19
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L13:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L13
L28:
  movapd %xmm1,%xmm0
  ret
L19:
  pxor   %xmm1,%xmm1
  jmp    L28
```

assistant: ```c
double llz_shortenrg(double *buf, double *win, int frame_len) {
  int i;
  double x;
  double enrg;
  enrg = 0.0;
  x = 0.0;
  for (i = 0; i < frame_len; i++) {
    x = buf[i];
    x *= win[i];
    enrg += x * x;
  }
  return enrg;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<llz_shortenrg>:
  endbr64
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L19:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L19
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double llz_shortenrg(double *buf, double *win, int frame_len) {
  int i;
  double x;
  double enrg;
  enrg = 0.0;
  x = 0.0;
  for (i = 0; i < frame_len; i++) {
    x = buf[i];
    x *= win[i];
    enrg += x * x;
  }
  return enrg;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<llz_shortenrg>:
  endbr64
  test   %edx,%edx
  jle    L38
  cmp    $0x1,%edx
  je     L8
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L24:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L24
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L1
L32:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  ret
  nopl   0x0(%rax)
L38:
  pxor   %xmm0,%xmm0
  ret
L8:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L32
```

assistant: ```c
double llz_shortenrg(double *buf, double *win, int frame_len) {
  int i;
  double x;
  double enrg;
  enrg = 0.0;
  x = 0.0;
  for (i = 0; i < frame_len; i++) {
    x = buf[i];
    x *= win[i];
    enrg += x * x;
  }
  return enrg;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<task2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L13:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0x1869f,-0x8(%rbp)
  jle    L13
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: %d thread %d running Task 2


assistant: ```c
void task2(int id) {
  printf("%d thread %d running Task 2\n", id, (int)pthread_self());
  int i;
  int sum = 0;
  for (i = 0; i < 100000; i++) {
    sum += i;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<task2>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x186a0,%eax
L1:
  sub    $0x1,%eax
  jne    L1
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string

tool: D8: %d thread %d running Task 2


assistant: ```c
void task2(int id) {
  printf("%d thread %d running Task 2\n", id, (int)pthread_self());
  int i;
  int sum = 0;
  for (i = 0; i < 100000; i++) {
    sum += i;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<task2>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <pthread_self@plt>
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string

tool: D7: %d thread %d running Task 2


assistant: ```c
void task2(int id) {
  printf("%d thread %d running Task 2\n", id, (int)pthread_self());
  int i;
  int sum = 0;
  for (i = 0; i < 100000; i++) {
    sum += i;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<task2>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <pthread_self@plt>
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: %d thread %d running Task 2


assistant: ```c
void task2(int id) {
  printf("%d thread %d running Task 2\n", id, (int)pthread_self());
  int i;
  int sum = 0;
  for (i = 0; i < 100000; i++) {
    sum += i;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unpermute_indices>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %edx,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x70(%rbp)
  movl   $0x2,-0x6c(%rbp)
  movl   $0x1,-0x68(%rbp)
  movl   $0x0,-0x64(%rbp)
  movl   $0x1,-0x60(%rbp)
  movl   $0x2,-0x5c(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x1,-0x54(%rbp)
  movl   $0x2,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0x1,-0x48(%rbp)
  movl   $0x1,-0x44(%rbp)
  movl   $0x2,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x84(%rbp),%eax
  cltq
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x70,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x80(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x80(%rbp),%rax
  add    $0x4,%rax
  mov    -0x84(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x4,%rdx
  add    %rbp,%rdx
  sub    $0x6c,%rdx
  mov    (%rdx),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x78(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  mov    -0x84(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x4,%rdx
  add    %rbp,%rdx
  sub    $0x68,%rdx
  mov    (%rdx),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x78(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void unpermute_indices(int *i, const int *pi, const int ifa) {
  const int axis_permut[6][4] = {{0, 2, 1, 0}, {1, 2, 0, 1}, {2, 0, 1, 1}, {2, 1, 0, 0}, {0, 1, 2, 1}, {1, 0, 2, 0}};
  i[axis_permut[ifa][0]] = pi[0];
  i[axis_permut[ifa][1]] = pi[1];
  i[axis_permut[ifa][2]] = pi[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unpermute_indices>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movl   $0x1,0x28(%rsp)
  movl   $0x2,0x30(%rsp)
  movl   $0x1,0x34(%rsp)
  movl   $0x0,0x38(%rsp)
  movl   $0x0,0x40(%rsp)
  movl   $0x1,0x44(%rsp)
  movl   $0x2,0x48(%rsp)
  movl   $0x1,0x50(%rsp)
  movl   $0x0,0x54(%rsp)
  movl   $0x2,0x58(%rsp)
  mov    (%rsi),%ecx
  movslq %edx,%rdx
  shl    $0x4,%rdx
  movslq (%rsp,%rdx,1),%rax
  mov    %ecx,(%rdi,%rax,4)
  mov    0x4(%rsi),%ecx
  movslq 0x4(%rsp,%rdx,1),%rax
  mov    %ecx,(%rdi,%rax,4)
  mov    0x8(%rsi),%ecx
  movslq 0x8(%rsp,%rdx,1),%rax
  mov    %ecx,(%rdi,%rax,4)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x78,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unpermute_indices(int *i, const int *pi, const int ifa) {
  const int axis_permut[6][4] = {{0, 2, 1, 0}, {1, 2, 0, 1}, {2, 0, 1, 1}, {2, 1, 0, 0}, {0, 1, 2, 1}, {1, 0, 2, 0}};
  i[axis_permut[ifa][0]] = pi[0];
  i[axis_permut[ifa][1]] = pi[1];
  i[axis_permut[ifa][2]] = pi[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unpermute_indices>:
  endbr64
  sub    $0x78,%rsp
  movslq %edx,%rdx
  mov    (%rsi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x200000000,%rax
  shl    $0x4,%rdx
  movq   $0x2,0x20(%rsp)
  movq   $0x1,0x50(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x1,0x28(%rsp)
  movl   $0x0,0x38(%rsp)
  mov    %rax,(%rsp)
  add    $0x1,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x30(%rsp)
  sub    $0x2,%rax
  mov    %rax,0x40(%rsp)
  movslq (%rsp,%rdx,1),%rax
  movl   $0x2,0x48(%rsp)
  mov    %ecx,(%rdi,%rax,4)
  movslq 0x4(%rsp,%rdx,1),%rax
  mov    0x4(%rsi),%ecx
  movl   $0x2,0x58(%rsp)
  mov    %ecx,(%rdi,%rax,4)
  movslq 0x8(%rsp,%rdx,1),%rax
  mov    0x8(%rsi),%ecx
  mov    %ecx,(%rdi,%rax,4)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unpermute_indices(int *i, const int *pi, const int ifa) {
  const int axis_permut[6][4] = {{0, 2, 1, 0}, {1, 2, 0, 1}, {2, 0, 1, 1}, {2, 1, 0, 0}, {0, 1, 2, 1}, {1, 0, 2, 0}};
  i[axis_permut[ifa][0]] = pi[0];
  i[axis_permut[ifa][1]] = pi[1];
  i[axis_permut[ifa][2]] = pi[2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<unpermute_indices>:
  endbr64
  sub    $0x78,%rsp
  mov    %rsi,%rcx
  movslq %edx,%rdx
  mov    %rdi,%rax
  mov    %fs:0x28,%rsi
  mov    %rsi,0x68(%rsp)
  xor    %esi,%esi
  mov    D35(%rip),%rsi
  shl    $0x4,%rdx
  mov    (%rcx),%edi
  movl   $0x1,0x8(%rsp)
  mov    %rsi,(%rsp)
  mov    D29(%rip),%rsi
  movl   $0x0,0x18(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    D12(%rip),%rsi
  movl   $0x1,0x28(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    D42(%rip),%rsi
  movl   $0x0,0x38(%rsp)
  mov    %rsi,0x30(%rsp)
  mov    D47(%rip),%rsi
  movl   $0x2,0x48(%rsp)
  mov    %rsi,0x40(%rsp)
  mov    D6(%rip),%rsi
  movl   $0x2,0x58(%rsp)
  mov    %rsi,0x50(%rsp)
  movslq (%rsp,%rdx,1),%rsi
  mov    %edi,(%rax,%rsi,4)
  movslq 0x4(%rsp,%rdx,1),%rsi
  mov    0x4(%rcx),%edi
  movslq 0x8(%rsp,%rdx,1),%rdx
  mov    %edi,(%rax,%rsi,4)
  mov    0x8(%rcx),%ecx
  mov    %ecx,(%rax,%rdx,4)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D35
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D29
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D12
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D42
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D47
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D6
type_guessed: byte[8]

tool: {"D35": [0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D29": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D12": [0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D42": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D47": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D6": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void unpermute_indices(int *i, const int *pi, const int ifa) {
  const int axis_permut[6][4] = {{0, 2, 1, 0}, {1, 2, 0, 1}, {2, 0, 1, 1}, {2, 1, 0, 0}, {0, 1, 2, 1}, {1, 0, 2, 0}};
  i[axis_permut[ifa][0]] = pi[0];
  i[axis_permut[ifa][1]] = pi[1];
  i[axis_permut[ifa][2]] = pi[2];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L51
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
L51:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L46
L57:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L57
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <pegaMapa@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L20:
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L52:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L52
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L20
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <buscaCaminho@plt>
  mov    $0x0,%eax
  call   <move@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: %c 

assistant: ```c
int main(int argc, char const *argv[]) {
  int map_size = 0, i, j;
  char **map;
  if (argc >= 2) {
    map_size = atoi(argv[1]);
  }
  map = (char **)malloc(sizeof(char *) * map_size);
  for (i = 0; i < map_size; i++) {
    map[i] = (char *)malloc(sizeof(char) * map_size);
  }
  pegaMapa(map, map_size);
  for (i = 0; i < map_size; i++) {
    for (j = 0; j < map_size; j++) {
      printf("%c ", map[i][j]);
    }
    printf("\n");
  }
  buscaCaminho(map, map_size);
  move();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jg     L31
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  movl   $0x0,(%rsp)
L44:
  mov    (%rsp),%esi
  mov    0x8(%rsp),%rdi
  call   <pegaMapa@plt>
  jmp    L6
L31:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %eax,(%rsp)
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,0x8(%rsp)
  test   %ebx,%ebx
  jle    L44
  mov    %rax,%r14
  mov    %ebx,0x4(%rsp)
  lea    -0x1(%rbx),%eax
  lea    0x8(%rbp,%rax,8),%r15
  mov    %rbp,%rbx
L15:
  mov    (%rsp),%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L15
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <pegaMapa@plt>
  lea    D7(%rip),%r13
L22:
  mov    %r14,%r12
  mov    0x4(%rsp),%ebp
  mov    $0x0,%ebx
L20:
  mov    (%r12),%rax
  movsbl (%rax,%rbx,1),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%r14
  cmp    %r15,%r14
  jne    L22
L6:
  mov    (%rsp),%esi
  mov    0x8(%rsp),%rdi
  call   <buscaCaminho@plt>
  mov    $0x0,%eax
  call   <move@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: %c 

assistant: ```c
int main(int argc, char const *argv[]) {
  int map_size = 0, i, j;
  char **map;
  if (argc >= 2) {
    map_size = atoi(argv[1]);
  }
  map = (char **)malloc(sizeof(char *) * map_size);
  for (i = 0; i < map_size; i++) {
    map[i] = (char *)malloc(sizeof(char) * map_size);
  }
  pegaMapa(map, map_size);
  for (i = 0; i < map_size; i++) {
    for (j = 0; j < map_size; j++) {
      printf("%c ", map[i][j]);
    }
    printf("\n");
  }
  buscaCaminho(map, map_size);
  move();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jg     L17
  xor    %edi,%edi
  xor    %r14d,%r14d
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
L38:
  mov    0x8(%rsp),%rdi
  mov    %r14d,%esi
  call   <pegaMapa@plt>
L15:
  mov    0x8(%rsp),%rdi
  mov    %r14d,%esi
  call   <buscaCaminho@plt>
  xor    %eax,%eax
  call   <move@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    0x0(,%rax,8),%edi
  mov    %eax,%r14d
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
  test   %r14d,%r14d
  jle    L38
  mov    %rax,%rbx
  lea    -0x1(%r14),%eax
  lea    0x8(%rbp,%rax,8),%r13
  nopl   0x0(%rax)
L32:
  mov    %r14d,%edi
  add    $0x8,%rbp
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r13,%rbp
  jne    L32
  mov    0x8(%rsp),%rdi
  mov    %r14d,%esi
  lea    D5(%rip),%r12
  mov    %r14d,%ebp
  call   <pegaMapa@plt>
  nopl   0x0(%rax)
L55:
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L20:
  mov    (%rbx),%rax
  mov    %r12,%rdi
  movsbl (%rax,%r15,1),%esi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L20
  mov    $0xa,%edi
  add    $0x8,%rbx
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L55
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D5: %c 

assistant: ```c
int main(int argc, char const *argv[]) {
  int map_size = 0, i, j;
  char **map;
  if (argc >= 2) {
    map_size = atoi(argv[1]);
  }
  map = (char **)malloc(sizeof(char *) * map_size);
  for (i = 0; i < map_size; i++) {
    map[i] = (char *)malloc(sizeof(char) * map_size);
  }
  pegaMapa(map, map_size);
  for (i = 0; i < map_size; i++) {
    for (j = 0; j < map_size; j++) {
      printf("%c ", map[i][j]);
    }
    printf("\n");
  }
  buscaCaminho(map, map_size);
  move();
  return 0;
}
```