ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x1,-0x20(%rbp)
  jmp    L27
L12:
  mov    $0x6,%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x1c(%rbp),%edx
  cltq
  mov    %dl,-0xc(%rbp,%rax,1)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0xc(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L27:
  cmpl   $0x4,-0x20(%rbp)
  jle    L12
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string
name: retrieve_data
arguments: tag: D26
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D3: rb

tool: D26: logo_arduino.bmp

tool: D11: %d 

assistant: ```c
int main() {
  FILE *p, *pp;
  int c;
  char d[4];
  p = fopen("logo_arduino.bmp", "rb");
  for (int x = 1; x <= 4; x++) {
    fseek(p, 6 - x, 0);
    c = getc(p);
    d[x - 1] = c;
    printf("%d ", d[x - 1]);
  }
  fclose(p);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rsi
  lea    D27(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0x5,%ebx
  lea    D28(%rip),%r12
L6:
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <getc@plt>
  movsbl %al,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  cmp    $0x1,%ebx
  jne    L6
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
data_type: string
name: disassemble_data
arguments: data_tag: D27
data_type: string
name: disassemble_data
arguments: data_tag: D28
data_type: string

tool: D18: rb

tool: D27: logo_arduino.bmp

tool: D28: %d 

assistant: ```c
int main() {
  FILE *p, *pp;
  int c;
  char d[4];
  p = fopen("logo_arduino.bmp", "rb");
  for (int x = 1; x <= 4; x++) {
    fseek(p, 6 - x, 0);
    c = getc(p);
    d[x - 1] = c;
    printf("%d ", d[x - 1]);
  }
  fclose(p);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%rsi
  lea    D17(%rip),%rdi
  push   %rbp
  lea    D24(%rip),%r12
  push   %rbx
  mov    $0x5,%ebx
  call   <fopen@plt>
  mov    %rax,%rbp
L8:
  mov    %ebx,%esi
  xor    %edx,%edx
  mov    %rbp,%rdi
  sub    $0x1,%ebx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %r12,%rdi
  movsbl %al,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%ebx
  jne    L8
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string
name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D24
type_infered: string

tool: D9: rb

tool: D17: logo_arduino.bmp

tool: D24: %d 

assistant: ```c
int main() {
  FILE *p, *pp;
  int c;
  char d[4];
  p = fopen("logo_arduino.bmp", "rb");
  for (int x = 1; x <= 4; x++) {
    fseek(p, 6 - x, 0);
    c = getc(p);
    d[x - 1] = c;
    printf("%d ", d[x - 1]);
  }
  fclose(p);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D26(%rip),%rsi
  lea    D14(%rip),%rdi
  push   %rbp
  lea    D17(%rip),%r12
  push   %rbx
  mov    $0x5,%ebx
  call   <fopen@plt>
  mov    %rax,%rbp
L2:
  mov    %ebx,%esi
  xor    %edx,%edx
  mov    %rbp,%rdi
  sub    $0x1,%ebx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %r12,%rdi
  movsbl %al,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%ebx
  jne    L2
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D26
type_guessed: string
name: retrieve_data
arguments: tag: D14
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string

tool: D26: rb

tool: D14: logo_arduino.bmp

tool: D17: %d 

assistant: ```c
int main() {
  FILE *p, *pp;
  int c;
  char d[4];
  p = fopen("logo_arduino.bmp", "rb");
  for (int x = 1; x <= 4; x++) {
    fseek(p, 6 - x, 0);
    c = getc(p);
    d[x - 1] = c;
    printf("%d ", d[x - 1]);
  }
  fclose(p);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  D14(%rip),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,D16(%rip)
  movss  D16(%rip),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float fac(float n) {
  static float f = 1;
  f = f * n;
  return (f);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fac>:
  endbr64
  mulss  D2(%rip),%xmm0
  movss  %xmm0,D8(%rip)
  ret
```

assistant: ```c
float fac(float n) {
  static float f = 1;
  f = f * n;
  return (f);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fac>:
  endbr64
  mulss  D13(%rip),%xmm0
  movss  %xmm0,D17(%rip)
  ret
```

assistant: ```c
float fac(float n) {
  static float f = 1;
  f = f * n;
  return (f);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fac>:
  endbr64
  mulss  D10(%rip),%xmm0
  movss  %xmm0,D1(%rip)
  ret
```

assistant: ```c
float fac(float n) {
  static float f = 1;
  f = f * n;
  return (f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_sigset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L27
L18:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  addq   $0x4,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L18
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
sigset_t _sigset(const int *signals) {
  sigset_t set;
  sigemptyset(&set);
  for (const int *sig = signals; *sig; sig++)
    sigaddset(&set, *sig);
  return set;
}
```
user: What is the c source code of the assembly code below:

```asm
<_sigset>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <sigemptyset@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L3
  lea    0x4(%rsp),%rbp
L8:
  mov    %rbp,%rdi
  call   <sigaddset@plt>
  add    $0x4,%rbx
  mov    (%rbx),%esi
  test   %esi,%esi
  jne    L8
L3:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sigset_t _sigset(const int *signals) {
  sigset_t set;
  sigemptyset(&set);
  for (const int *sig = signals; *sig; sig++)
    sigaddset(&set, *sig);
  return set;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_sigset>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L3
L7:
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <sigaddset@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  jne    L7
L3:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sigset_t _sigset(const int *signals) {
  sigset_t set;
  sigemptyset(&set);
  for (const int *sig = signals; *sig; sig++)
    sigaddset(&set, *sig);
  return set;
}
```
user: What is the c source code of the assembly code below:

```asm
<_sigset>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L3
L15:
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <sigaddset@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  jne    L15
L3:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sigset_t _sigset(const int *signals) {
  sigset_t set;
  sigemptyset(&set);
  for (const int *sig = signals; *sig; sig++)
    sigaddset(&set, *sig);
  return set;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jg     L13
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L41
L13:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L41
L39:
  subl   $0x1,-0xc(%rbp)
L41:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L39
  nop
L59:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L1
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
L1:
  subl   $0x1,-0xc(%rbp)
  jmp    L59
```

tool_calls: name: read_data
arguments: label: D41
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D0
type_guessed: string
name: read_data
arguments: label: D24
type_guessed: string

tool: D41: Enter the no1:

tool: D29: %d

tool: D0: Enter the no2:

tool: D24: GCD of %d & %d is: %d


assistant: ```c
int main() {
  int m = 0, n = 0, t = 0;
  printf("Enter the no1:\n");
  scanf("%d", &m);
  printf("Enter the no2:\n");
  scanf("%d", &n);
  if (m <= n) {
    t = m;
  } else {
    t = n;
  }
  while (m % t != 0) {
    t = t - 1;
  }
prev:
  if (n % t == 0) {
    printf("GCD of %d & %d is: %d\n", m, n, t);
    _exit(0);
  }
  t--;
  goto prev;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D34(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%ebx
  cmp    %ebx,%ecx
  cmovle %ecx,%ebx
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L40
L33:
  sub    $0x1,%ebx
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L33
L40:
  lea    D7(%rip),%rbp
  jmp    L47
L9:
  mov    %ebx,%ecx
  mov    %esi,%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
L11:
  sub    $0x1,%ebx
L47:
  mov    0x4(%rsp),%esi
  mov    %esi,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L9
  jmp    L11
```

tool_calls: name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D7
type: string

tool: D28: Enter the no1:

tool: D34: %d

tool: D9: Enter the no2:

tool: D7: GCD of %d & %d is: %d


assistant: ```c
int main() {
  int m = 0, n = 0, t = 0;
  printf("Enter the no1:\n");
  scanf("%d", &m);
  printf("Enter the no2:\n");
  scanf("%d", &n);
  if (m <= n) {
    t = m;
  } else {
    t = n;
  }
  while (m % t != 0) {
    t = t - 1;
  }
prev:
  if (n % t == 0) {
    printf("GCD of %d & %d is: %d\n", m, n, t);
    _exit(0);
  }
  t--;
  goto prev;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  cmp    %r8d,%esi
  mov    %r8d,%ebx
  cmovle %esi,%ebx
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L27:
  sub    $0x1,%ebx
L38:
  mov    %esi,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L27
  lea    D35(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r8d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L34
  mov    %r8d,%edx
  mov    %ebx,%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <_exit@plt>
  mov    0x4(%rsp),%r8d
  mov    (%rsp),%esi
L34:
  sub    $0x1,%ebx
  jmp    L6
```

tool_calls: name: read_data
arguments: data_tag: D28
type_guessed: string
name: read_data
arguments: data_tag: D19
type_guessed: string
name: read_data
arguments: data_tag: D33
type_guessed: string
name: read_data
arguments: data_tag: D35
type_guessed: string

tool: D28: Enter the no1:

tool: D19: %d

tool: D33: Enter the no2:

tool: D35: GCD of %d & %d is: %d


assistant: ```c
int main() {
  int m = 0, n = 0, t = 0;
  printf("Enter the no1:\n");
  scanf("%d", &m);
  printf("Enter the no2:\n");
  scanf("%d", &n);
  if (m <= n) {
    t = m;
  } else {
    t = n;
  }
  while (m % t != 0) {
    t = t - 1;
  }
prev:
  if (n % t == 0) {
    printf("GCD of %d & %d is: %d\n", m, n, t);
    _exit(0);
  }
  t--;
  goto prev;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  lea    D13(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  cmp    %r8d,%esi
  mov    %r8d,%ebx
  cmovle %esi,%ebx
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%ebx
L27:
  mov    %esi,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L9
  lea    D28(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r8d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L35
  mov    %r8d,%edx
  mov    %ebx,%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <_exit@plt>
  mov    0x4(%rsp),%r8d
  mov    (%rsp),%esi
L35:
  sub    $0x1,%ebx
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_tag: D33
data_type: string
name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D28
data_type: string

tool: D33: Enter the no1:

tool: D13: %d

tool: D5: Enter the no2:

tool: D28: GCD of %d & %d is: %d


assistant: ```c
int main() {
  int m = 0, n = 0, t = 0;
  printf("Enter the no1:\n");
  scanf("%d", &m);
  printf("Enter the no2:\n");
  scanf("%d", &n);
  if (m <= n) {
    t = m;
  } else {
    t = n;
  }
  while (m % t != 0) {
    t = t - 1;
  }
prev:
  if (n % t == 0) {
    printf("GCD of %d & %d is: %d\n", m, n, t);
    _exit(0);
  }
  t--;
  goto prev;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bindetections>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L31
L39:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L39
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L5:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jg     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void bindetections(double *zdet, long int ndet, double zmin, double zmax, int nbins, int *count) {
  int i;
  double dz = (zmax - zmin) / (nbins - 1);
  for (i = 0; i < nbins; i++) {
    count[i] = 0;
  }
  int binid;
  for (i = 0; i < ndet; i++) {
    binid = (int)floor(zdet[i] / dz);
    count[binid]++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bindetections>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rcx,%rbp
  subsd  %xmm0,%xmm1
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  test   %edx,%edx
  jle    L16
  mov    %rcx,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rcx,%rdx,4),%rdx
L30:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L30
L16:
  test   %r12,%r12
  jle    L3
  mov    $0x0,%ebx
L26:
  movsd  0x0(%r13,%rbx,8),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <floor@plt>
  cltq
  addl   $0x1,0x0(%rbp,%rax,4)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L26
L3:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bindetections(double *zdet, long int ndet, double zmin, double zmax, int nbins, int *count) {
  int i;
  double dz = (zmax - zmin) / (nbins - 1);
  for (i = 0; i < nbins; i++) {
    count[i] = 0;
  }
  int binid;
  for (i = 0; i < ndet; i++) {
    binid = (int)floor(zdet[i] / dz);
    count[binid]++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bindetections>:
  endbr64
  subsd  %xmm0,%xmm1
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  push   %r13
  cvtsi2sd %eax,%xmm0
  push   %r12
  mov    %rcx,%r13
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  divsd  %xmm0,%xmm1
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  test   %edx,%edx
  jle    L23
  movslq %edx,%rdx
  xor    %esi,%esi
  mov    %rcx,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L23:
  test   %rbp,%rbp
  jle    L19
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L7:
  movsd  (%r12,%rbx,8),%xmm0
  divsd  0x8(%rsp),%xmm0
  add    $0x1,%rbx
  call   <floor@plt>
  cltq
  addl   $0x1,0x0(%r13,%rax,4)
  cmp    %rbx,%rbp
  jne    L7
L19:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bindetections(double *zdet, long int ndet, double zmin, double zmax, int nbins, int *count) {
  int i;
  double dz = (zmax - zmin) / (nbins - 1);
  for (i = 0; i < nbins; i++) {
    count[i] = 0;
  }
  int binid;
  for (i = 0; i < ndet; i++) {
    binid = (int)floor(zdet[i] / dz);
    count[binid]++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bindetections>:
  endbr64
  subsd  %xmm0,%xmm1
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  push   %r13
  cvtsi2sd %eax,%xmm0
  push   %r12
  mov    %rcx,%r13
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  divsd  %xmm0,%xmm1
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  test   %edx,%edx
  jle    L7
  movslq %edx,%rdx
  xor    %esi,%esi
  mov    %rcx,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L7:
  test   %rbp,%rbp
  jle    L8
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L2:
  movsd  (%r12,%rbx,8),%xmm0
  divsd  0x8(%rsp),%xmm0
  add    $0x1,%rbx
  call   <floor@plt>
  cltq
  addl   $0x1,0x0(%r13,%rax,4)
  cmp    %rbx,%rbp
  jne    L2
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bindetections(double *zdet, long int ndet, double zmin, double zmax, int nbins, int *count) {
  int i;
  double dz = (zmax - zmin) / (nbins - 1);
  for (i = 0; i < nbins; i++) {
    count[i] = 0;
  }
  int binid;
  for (i = 0; i < ndet; i++) {
    binid = (int)floor(zdet[i] / dz);
    count[binid]++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <d@plt>
  mov    $0x0,%eax
  call   <e@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void c() {
  d();
  e();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<c>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <d@plt>
  mov    $0x0,%eax
  call   <e@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void c() {
  d();
  e();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<c>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <d@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <e@plt>
```

assistant: ```c
void c() {
  d();
  e();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<c>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <d@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <e@plt>
```

assistant: ```c
void c() {
  d();
  e();
}
```
user: What is the c source code of the assembly code below?

```asm
<pdwait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0xc(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  call   <select@plt>
  cmp    $0xffffffff,%eax
  jne    L6
  mov    $0xffffffff,%eax
  jmp    L12
L6:
  mov    $0x0,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int pdwait(int pfd) {
  fd_set fdset;
  FD_ZERO(&fdset);
  FD_SET(pfd, &fdset);
  return (select(pfd + 1, NULL, &fdset, NULL, NULL) == -1 ? -1 : 0);
}
```