ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<treedir>:
  endbr64
  movsd  (%rdi),%xmm0
  addsd  0x10(%rdi),%xmm0
  xor    %eax,%eax
  movsd  D8(%rip),%xmm1
  movsd  (%rsi),%xmm2
  mulsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  movsd  0x8(%rdi),%xmm0
  addsd  0x18(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  0x8(%rsi),%xmm1
  seta   %al
  lea    0x2(%rax),%edx
  comisd %xmm0,%xmm1
  cmova  %edx,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int treedir(double *bb, double *x) {
  int d = 0;
  if (x[0] > (bb[0] + bb[2]) / 2.0)
    d += 1;
  if (x[1] > (bb[1] + bb[3]) / 2.0)
    d += 2;
  return d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<treedir>:
  endbr64
  movsd  (%rdi),%xmm0
  addsd  0x10(%rdi),%xmm0
  xor    %eax,%eax
  movsd  D3(%rip),%xmm1
  movsd  (%rsi),%xmm2
  mulsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  movsd  0x8(%rdi),%xmm0
  addsd  0x18(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  0x8(%rsi),%xmm1
  seta   %al
  lea    0x2(%rax),%edx
  comisd %xmm0,%xmm1
  cmova  %edx,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int treedir(double *bb, double *x) {
  int d = 0;
  if (x[0] > (bb[0] + bb[2]) / 2.0)
    d += 1;
  if (x[1] > (bb[1] + bb[3]) / 2.0)
    d += 2;
  return d;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x7b,-0xc(%rbp)
  movl   $0x5,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L31
L6:
  nop
L20:
  cmpl   $0x3,-0x4(%rbp)
  jle    L20
L24:
  cmpl   $0x1,-0x8(%rbp)
  jle    L6
L31:
  cmpl   $0x4,-0xc(%rbp)
  jle    L24
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i = 123, j = 5, k = 1;
  while (i < 5) {
    while (j < 2) {
      while (k < 4) {
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int i = 123, j = 5, k = 1;
  while (i < 5) {
    while (j < 2) {
      while (k < 4) {
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i = 123, j = 5, k = 1;
  while (i < 5) {
    while (j < 2) {
      while (k < 4) {
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i = 123, j = 5, k = 1;
  while (i < 5) {
    while (j < 2) {
      while (k < 4) {
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fact3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L4:
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L4
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fact3(int n) {
  int v = 1;
  for (int i = 1, max = n; i <= max; i++) {
    v *= i;
  }
  return v;
}
```
user: What is the c source code of the assembly code below:

```asm
<fact3>:
  endbr64
  test   %edi,%edi
  jle    L10
  add    $0x1,%edi
  mov    $0x1,%eax
  mov    $0x1,%edx
L22:
  imul   %eax,%edx
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L22
L2:
  mov    %edx,%eax
  ret
L10:
  mov    $0x1,%edx
  jmp    L2
```

assistant: ```c
int fact3(int n) {
  int v = 1;
  for (int i = 1, max = n; i <= max; i++) {
    v *= i;
  }
  return v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fact3>:
  endbr64
  test   %edi,%edi
  jle    L10
  add    $0x1,%edi
  mov    $0x1,%eax
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L15:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L15
  mov    %r8d,%eax
  ret
  nop
L10:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fact3(int n) {
  int v = 1;
  for (int i = 1, max = n; i <= max; i++) {
    v *= i;
  }
  return v;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fact3>:
  endbr64
  test   %edi,%edi
  jle    L2
  add    $0x1,%edi
  mov    $0x1,%eax
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L8:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L8
  mov    %r8d,%eax
  ret
  nop
L2:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fact3(int n) {
  int v = 1;
  for (int i = 1, max = n; i <= max; i++) {
    v *= i;
  }
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dt_binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  cltq
  imul   %edx,%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L29:
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L53:
  mov    -0x10(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  movsd  D0(%rip),%xmm0
  jmp    L2
L20:
  pxor   %xmm0,%xmm0
L2:
  mov    -0x10(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L53
  addl   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <dt@plt>
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sqrt_m@plt>
  mov    -0x24(%rbp),%edi
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <double_to_image@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: f64

tool: D0: 1e+20

assistant: ```c
void dt_binary(unsigned char *bimg, int rows, int cols, int step) {
  double *m = (double *)malloc(sizeof(m[0]) * rows * cols);
  int i, j;
  for (i = 0; i < rows; ++i) {
    for (j = 0; j < cols; ++j) {
      m[i * cols + j] = bimg[i * step + j] > 0 ? +1E20 : 0.0;
    }
  }
  dt(m, rows, cols);
  sqrt_m(m, rows * cols);
  double_to_image(m, rows, cols, bimg, step);
  free(m);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dt_binary>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %esi,%edi
  imul   %edx,%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L42
  mov    $0x0,%r8d
  mov    $0x0,%edi
  mov    $0x0,%esi
  lea    -0x1(%rbx),%r10d
  lea    0x8(%rax),%r9
  movsd  D1(%rip),%xmm1
  pxor   %xmm2,%xmm2
  jmp    L53
L9:
  movsd  %xmm0,(%rax)
  add    $0x1,%rdx
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L68
L31:
  movapd %xmm1,%xmm0
  cmpb   $0x0,(%rdx)
  jne    L9
  movapd %xmm2,%xmm0
  jmp    L9
L68:
  add    $0x1,%esi
  add    %ebx,%edi
  add    %r13d,%r8d
  cmp    %esi,%ebp
  je     L42
L53:
  test   %ebx,%ebx
  jle    L68
  movslq %r8d,%rdx
  add    %r14,%rdx
  movslq %edi,%rcx
  lea    (%r12,%rcx,8),%rax
  add    %r10,%rcx
  lea    (%r9,%rcx,8),%rcx
  jmp    L31
L42:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <dt@plt>
  mov    %ebp,%esi
  imul   %ebx,%esi
  mov    %r12,%rdi
  call   <sqrt_m@plt>
  mov    %r13d,%r8d
  mov    %r14,%rcx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <double_to_image@plt>
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: f64

tool: D1: 1e+20

assistant: ```c
void dt_binary(unsigned char *bimg, int rows, int cols, int step) {
  double *m = (double *)malloc(sizeof(m[0]) * rows * cols);
  int i, j;
  for (i = 0; i < rows; ++i) {
    for (j = 0; j < cols; ++j) {
      m[i * cols + j] = bimg[i * step + j] > 0 ? +1E20 : 0.0;
    }
  }
  dt(m, rows, cols);
  sqrt_m(m, rows * cols);
  double_to_image(m, rows, cols, bimg, step);
  free(m);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dt_binary>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  imul   %edx,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %ebp,%ebp
  jle    L25
  movsd  D6(%rip),%xmm1
  xor    %r8d,%r8d
  xor    %edi,%edi
  xor    %esi,%esi
  lea    -0x1(%r12),%r10d
  lea    0x8(%rax),%r9
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L36:
  test   %r12d,%r12d
  jle    L48
  movslq %edi,%rcx
  movslq %r8d,%rdx
  lea    (%r14,%rcx,8),%rax
  add    %r10,%rcx
  add    %r13,%rdx
  lea    (%r9,%rcx,8),%rcx
  nopl   0x0(%rax)
L23:
  cmpb   $0x0,(%rdx)
  movapd %xmm1,%xmm0
  jne    L7
  movapd %xmm2,%xmm0
L7:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  add    $0x1,%rdx
  cmp    %rcx,%rax
  jne    L23
L48:
  add    $0x1,%esi
  add    %r12d,%edi
  add    %ebx,%r8d
  cmp    %esi,%ebp
  jne    L36
L25:
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <dt@plt>
  mov    %ebp,%esi
  mov    %r14,%rdi
  imul   %r12d,%esi
  call   <sqrt_m@plt>
  mov    %r14,%rdi
  mov    %ebx,%r8d
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <double_to_image@plt>
  pop    %rbx
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <free@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: f64

tool: D6: 1e+20

assistant: ```c
void dt_binary(unsigned char *bimg, int rows, int cols, int step) {
  double *m = (double *)malloc(sizeof(m[0]) * rows * cols);
  int i, j;
  for (i = 0; i < rows; ++i) {
    for (j = 0; j < cols; ++j) {
      m[i * cols + j] = bimg[i * step + j] > 0 ? +1E20 : 0.0;
    }
  }
  dt(m, rows, cols);
  sqrt_m(m, rows * cols);
  double_to_image(m, rows, cols, bimg, step);
  free(m);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: World


assistant: ```c
void bar() {
  printf("World\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: World


assistant: ```c
void bar() {
  printf("World\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: World


assistant: ```c
void bar() {
  printf("World\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: World


assistant: ```c
void bar() {
  printf("World\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<valid_offset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <lseek64@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jns    L18
  mov    $0x0,%eax
  jmp    L26
L18:
  lea    -0x11(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L35
  mov    $0x0,%eax
  jmp    L26
L35:
  mov    $0x1,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int valid_offset(int fd, loff_t offset) {
  char ch;
  loff_t res;
  res = lseek64(fd, offset, 0);
  if (res < 0)
    return 0;
  if (read(fd, &ch, 1) < 1)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<valid_offset>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  call   <lseek64@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  js     L0
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %ebx,%edi
  call   <read@plt>
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int valid_offset(int fd, loff_t offset) {
  char ch;
  loff_t res;
  res = lseek64(fd, offset, 0);
  if (res < 0)
    return 0;
  if (read(fd, &ch, 1) < 1)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<valid_offset>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <lseek64@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L9
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int valid_offset(int fd, loff_t offset) {
  char ch;
  loff_t res;
  res = lseek64(fd, offset, 0);
  if (res < 0)
    return 0;
  if (read(fd, &ch, 1) < 1)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<valid_offset>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <lseek64@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L12
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int valid_offset(int fd, loff_t offset) {
  char ch;
  loff_t res;
  res = lseek64(fd, offset, 0);
  if (res < 0)
    return 0;
  if (read(fd, &ch, 1) < 1)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc8(%rbp),%rax
  cmp    $0x14,%rax
  jbe    L46
  movq   $0x14,-0xc8(%rbp)
L46:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc0(%rbp),%rax
  cmp    $0x14,%rax
  jbe    L24
  movq   $0x14,-0xc0(%rbp)
L24:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0x0,-0xb8(%rbp)
  jmp    L5
L22:
  mov    -0xb8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  lea    -0xb0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addq   $0x1,-0xb8(%rbp)
L5:
  mov    -0xc0(%rbp),%rax
  cmp    %rax,-0xb8(%rbp)
  jb     L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xc0(%rbp),%rdx
  mov    -0xc8(%rbp),%rax
  lea    -0xb0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <lru@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D20
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D3: Number of frames?

tool: D20:  %zu%*c

tool: D30: Number of pages?

tool: D2: %zu pages?


assistant: ```c
int main() {
  size_t i, n_frame, pages[20], n_page;
  puts("Number of frames?");
  scanf(" %zu%*c", &n_frame);
  if (n_frame > 20)
    n_frame = 20;
  putchar('\n');
  puts("Number of pages?");
  scanf(" %zu%*c", &n_page);
  if (n_page > 20)
    n_page = 20;
  putchar('\n');
  printf("%zu pages?\n", n_page);
  for (i = 0; i < n_page; ++i)
    scanf(" %zu%*c", pages + i);
  putchar('\n');
  lru(n_frame, pages, n_page);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x14,(%rsp)
  jbe    L29
  movq   $0x14,(%rsp)
L29:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x14,0x8(%rsp)
  jbe    L7
  movq   $0x14,0x8(%rsp)
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L15
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D8(%rip),%r12
L43:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%rbx
  add    $0x8,%rbp
  cmp    %rbx,0x8(%rsp)
  ja     L43
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rdi
  call   <lru@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D40
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string
name: parse_data
arguments: label: D20
type_guessed: string
name: parse_data
arguments: label: D7
type_guessed: string

tool: D40: Number of frames?

tool: D8:  %zu%*c

tool: D20: Number of pages?

tool: D7: %zu pages?


assistant: ```c
int main() {
  size_t i, n_frame, pages[20], n_page;
  puts("Number of frames?");
  scanf(" %zu%*c", &n_frame);
  if (n_frame > 20)
    n_frame = 20;
  putchar('\n');
  puts("Number of pages?");
  scanf(" %zu%*c", &n_page);
  if (n_page > 20)
    n_page = 20;
  putchar('\n');
  printf("%zu pages?\n", n_page);
  for (i = 0; i < n_page; ++i)
    scanf(" %zu%*c", pages + i);
  putchar('\n');
  lru(n_frame, pages, n_page);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D38(%rip),%rdi
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpq   $0x14,(%rsp)
  jbe    L18
  movq   $0x14,(%rsp)
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpq   $0x14,0x8(%rsp)
  jbe    L44
  movq   $0x14,0x8(%rsp)
L44:
  mov    $0xa,%edi
  lea    0x10(%rsp),%r13
  xor    %ebx,%ebx
  call   <putchar@plt>
  mov    0x8(%rsp),%rsi
  lea    D5(%rip),%rdi
  mov    %r13,%rbp
  call   <printf@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L22
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  add    $0x8,%rbp
  call   <scanf@plt>
  cmp    %rbx,0x8(%rsp)
  ja     L29
L22:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rdi
  mov    %r13,%rsi
  call   <lru@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D38
type: string
name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D33
type: string
name: read_data
arguments: tag: D5
type: string

tool: D38: Number of frames?

tool: D12:  %zu%*c

tool: D33: Number of pages?

tool: D5: %zu pages?


assistant: ```c
int main() {
  size_t i, n_frame, pages[20], n_page;
  puts("Number of frames?");
  scanf(" %zu%*c", &n_frame);
  if (n_frame > 20)
    n_frame = 20;
  putchar('\n');
  puts("Number of pages?");
  scanf(" %zu%*c", &n_page);
  if (n_page > 20)
    n_page = 20;
  putchar('\n');
  printf("%zu pages?\n", n_page);
  for (i = 0; i < n_page; ++i)
    scanf(" %zu%*c", pages + i);
  putchar('\n');
  lru(n_frame, pages, n_page);
  return 0;
}
```