ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<packi32>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void packi32(unsigned char *buf, unsigned long int i) {
  *buf++ = i >> 24;
  *buf++ = i >> 16;
  *buf++ = i >> 8;
  *buf++ = i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn_5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x9,-0x4(%rbp)
  jle    L9
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fn_5(double *a, double *b, double *sum, double *prod) {
  int i = 0;
  for (i = 0; i < 10; i++)
    sum[i] = a[i] * b[i];
  prod[i] = a[i] * b[i];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fn_5>:
  endbr64
  mov    $0x0,%eax
L7:
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x50,%rax
  jne    L7
  movsd  0x50(%rdi),%xmm0
  mulsd  0x50(%rsi),%xmm0
  movsd  %xmm0,0x50(%rcx)
  ret
```

assistant: ```c
void fn_5(double *a, double *b, double *sum, double *prod) {
  int i = 0;
  for (i = 0; i < 10; i++)
    sum[i] = a[i] * b[i];
  prod[i] = a[i] * b[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fn_5>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L0:
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x50,%rax
  jne    L0
  movsd  0x50(%rdi),%xmm0
  mulsd  0x50(%rsi),%xmm0
  movsd  %xmm0,0x50(%rcx)
  ret
```

assistant: ```c
void fn_5(double *a, double *b, double *sum, double *prod) {
  int i = 0;
  for (i = 0; i < 10; i++)
    sum[i] = a[i] * b[i];
  prod[i] = a[i] * b[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn_5>:
  endbr64
  mov    %rsi,%rax
  lea    0x8(%rsi),%rsi
  cmp    %rsi,%rdx
  je     L3
  lea    0x8(%rdi),%rsi
  cmp    %rsi,%rdx
  je     L3
  movupd (%rdi),%xmm0
  movupd (%rax),%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rdx)
  movupd 0x10(%rdi),%xmm0
  movupd 0x10(%rax),%xmm2
  mulpd  %xmm2,%xmm0
  movups %xmm0,0x10(%rdx)
  movupd 0x20(%rdi),%xmm0
  movupd 0x20(%rax),%xmm3
  mulpd  %xmm3,%xmm0
  movups %xmm0,0x20(%rdx)
  movupd 0x30(%rdi),%xmm0
  movupd 0x30(%rax),%xmm4
  mulpd  %xmm4,%xmm0
  movups %xmm0,0x30(%rdx)
  movupd 0x40(%rdi),%xmm0
  movupd 0x40(%rax),%xmm5
  mulpd  %xmm5,%xmm0
  movups %xmm0,0x40(%rdx)
  movsd  0x50(%rdi),%xmm0
  mulsd  0x50(%rax),%xmm0
  movsd  %xmm0,0x50(%rcx)
  ret
L3:
  movsd  (%rdi),%xmm0
  mulsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdi),%xmm0
  mulsd  0x8(%rax),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rdi),%xmm0
  mulsd  0x10(%rax),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x18(%rdi),%xmm0
  mulsd  0x18(%rax),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x20(%rdi),%xmm0
  mulsd  0x20(%rax),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x28(%rdi),%xmm0
  mulsd  0x28(%rax),%xmm0
  movsd  %xmm0,0x28(%rdx)
  movsd  0x30(%rdi),%xmm0
  mulsd  0x30(%rax),%xmm0
  movsd  %xmm0,0x30(%rdx)
  movsd  0x38(%rdi),%xmm0
  mulsd  0x38(%rax),%xmm0
  movsd  %xmm0,0x38(%rdx)
  movsd  0x40(%rdi),%xmm0
  mulsd  0x40(%rax),%xmm0
  movsd  %xmm0,0x40(%rdx)
  movsd  0x48(%rdi),%xmm0
  mulsd  0x48(%rax),%xmm0
  movsd  %xmm0,0x48(%rdx)
  movsd  0x50(%rdi),%xmm0
  mulsd  0x50(%rax),%xmm0
  movsd  %xmm0,0x50(%rcx)
  ret
```

assistant: ```c
void fn_5(double *a, double *b, double *sum, double *prod) {
  int i = 0;
  for (i = 0; i < 10; i++)
    sum[i] = a[i] * b[i];
  prod[i] = a[i] * b[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_slant_coords>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,0x4(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mov    -0x10(%rbp),%edx
  sub    $0x1,%edx
  mov    %edx,0x4(%rax)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mov    -0x10(%rbp),%edx
  sub    $0x1,%edx
  mov    %edx,0x8(%rax)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0xc(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,0xc(%rdx)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,0x10(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mov    -0x10(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,0x10(%rax)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x14(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mov    -0x10(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,0x14(%rax)
  mov    $0x6,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int get_slant_coords(int coords[2][8], int x, int y) {
  coords[0][0] = x - 1;
  coords[1][0] = y;
  coords[0][1] = x;
  coords[1][1] = y - 1;
  coords[0][2] = x + 1;
  coords[1][2] = y - 1;
  coords[0][3] = x + 1;
  coords[1][3] = y;
  coords[0][4] = x;
  coords[1][4] = y + 1;
  coords[0][5] = x - 1;
  coords[1][5] = y + 1;
  return 6;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_slant_coords>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    %eax,(%rdi)
  mov    %edx,0x20(%rdi)
  mov    %esi,0x4(%rdi)
  lea    -0x1(%rdx),%r8d
  mov    %r8d,0x24(%rdi)
  lea    0x1(%rsi),%ecx
  mov    %ecx,0x8(%rdi)
  mov    %r8d,0x28(%rdi)
  mov    %ecx,0xc(%rdi)
  mov    %edx,0x2c(%rdi)
  mov    %esi,0x10(%rdi)
  add    $0x1,%edx
  mov    %edx,0x30(%rdi)
  mov    %eax,0x14(%rdi)
  mov    %edx,0x34(%rdi)
  mov    $0x6,%eax
  ret
```

assistant: ```c
unsigned int get_slant_coords(int coords[2][8], int x, int y) {
  coords[0][0] = x - 1;
  coords[1][0] = y;
  coords[0][1] = x;
  coords[1][1] = y - 1;
  coords[0][2] = x + 1;
  coords[1][2] = y - 1;
  coords[0][3] = x + 1;
  coords[1][3] = y;
  coords[0][4] = x;
  coords[1][4] = y + 1;
  coords[0][5] = x - 1;
  coords[1][5] = y + 1;
  return 6;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_slant_coords>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    -0x1(%rdx),%r8d
  mov    %edx,0x20(%rdi)
  lea    0x1(%rsi),%ecx
  mov    %edx,0x2c(%rdi)
  add    $0x1,%edx
  mov    %eax,(%rdi)
  mov    %eax,0x14(%rdi)
  mov    $0x6,%eax
  mov    %esi,0x4(%rdi)
  mov    %r8d,0x24(%rdi)
  mov    %ecx,0x8(%rdi)
  mov    %r8d,0x28(%rdi)
  mov    %ecx,0xc(%rdi)
  mov    %esi,0x10(%rdi)
  mov    %edx,0x30(%rdi)
  mov    %edx,0x34(%rdi)
  ret
```

assistant: ```c
unsigned int get_slant_coords(int coords[2][8], int x, int y) {
  coords[0][0] = x - 1;
  coords[1][0] = y;
  coords[0][1] = x;
  coords[1][1] = y - 1;
  coords[0][2] = x + 1;
  coords[1][2] = y - 1;
  coords[0][3] = x + 1;
  coords[1][3] = y;
  coords[0][4] = x;
  coords[1][4] = y + 1;
  coords[0][5] = x - 1;
  coords[1][5] = y + 1;
  return 6;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_slant_coords>:
  endbr64
  movd   %esi,%xmm1
  movd   %edx,%xmm2
  lea    -0x1(%rsi),%eax
  add    $0x1,%edx
  pshufd $0x0,%xmm1,%xmm0
  movd   %eax,%xmm3
  movd   %edx,%xmm4
  mov    $0x6,%eax
  paddd  D12(%rip),%xmm0
  movups %xmm0,(%rdi)
  pshufd $0x0,%xmm2,%xmm0
  paddd  D6(%rip),%xmm0
  movups %xmm0,0x20(%rdi)
  movd   %esi,%xmm0
  punpckldq %xmm3,%xmm0
  movq   %xmm0,0x10(%rdi)
  pshufd $0xe0,%xmm4,%xmm0
  movq   %xmm0,0x30(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_infered: byte[16]
name: retrieve_data
arguments: tag: D6
type_infered: byte[16]

tool: {"D12": [0xff,0xff,0xff,0xff,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D6": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x00,0x00,0x00,0x00]}

assistant: ```c
unsigned int get_slant_coords(int coords[2][8], int x, int y) {
  coords[0][0] = x - 1;
  coords[1][0] = y;
  coords[0][1] = x;
  coords[1][1] = y - 1;
  coords[0][2] = x + 1;
  coords[1][2] = y - 1;
  coords[0][3] = x + 1;
  coords[1][3] = y;
  coords[0][4] = x;
  coords[1][4] = y + 1;
  coords[0][5] = x - 1;
  coords[1][5] = y + 1;
  return 6;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_topnsel_quicksort>:
  endbr64
  push   %rbx
  mov    %esi,%r11d
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%rbx
  mov    %edx,%ecx
  cmp    %edx,%esi
  je     L90
  lea    0x1(%rsi),%esi
  mov    (%rbx),%r8
  jmp    L22
L53:
  movslq %ecx,%rax
L63:
  mov    %eax,%ecx
  cmp    %r8,(%rdi,%rax,8)
  jg     L40
  sub    $0x1,%rax
  mov    %eax,%ecx
  cmp    %eax,%esi
  jne    L63
L79:
  movslq %ecx,%rax
  cmp    %r8,(%rdi,%rax,8)
  jge    L51
  sub    $0x1,%ecx
L51:
  cmp    %r11d,%ecx
  je     L90
  movslq %ecx,%rax
  lea    (%rdi,%rax,8),%rax
  mov    (%rax),%rdx
  mov    (%rbx),%rsi
  mov    %rsi,(%rax)
  mov    %rdx,(%rbx)
L90:
  mov    %ecx,%eax
  pop    %rbx
  ret
L40:
  cmp    %eax,%esi
  je     L79
  cltq
  lea    (%rdi,%rax,8),%rax
  mov    (%rax),%r10
  mov    %r10,(%r9)
  mov    %rdx,(%rax)
L22:
  cmp    %ecx,%esi
  je     L79
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%r9
  mov    (%r9),%rdx
  cmp    %r8,%rdx
  jl     L53
  add    $0x1,%esi
  jmp    L22
```

assistant: ```c
int _topnsel_quicksort(long *data, int startidx, int endidx) {
  long pivot = data[startidx];
  int p = startidx + 1;
  int q = endidx;
  long swapbuf;
  if (startidx == endidx)
    return startidx;
  while (1) {
    while (1) {
      if (p == q || data[p] < pivot)
        break;
      p++;
    }
    if (p == q)
      break;
    while (1) {
      if (p == q || data[q] > pivot)
        break;
      q--;
    }
    if (p == q)
      break;
    swapbuf = data[p];
    data[p] = data[q];
    data[q] = swapbuf;
  }
  if (data[p] < pivot)
    p--;
  if (p != startidx) {
    swapbuf = data[p];
    data[p] = data[startidx];
    data[startidx] = swapbuf;
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_topnsel_quicksort>:
  endbr64
  mov    %edx,%eax
  movslq %esi,%rdx
  push   %rbp
  mov    %esi,%r8d
  shl    $0x3,%rdx
  push   %rbx
  mov    %esi,%ebx
  lea    (%rdi,%rdx,1),%rbp
  cmp    %eax,%esi
  je     L15
  mov    %rdi,%r10
  add    $0x1,%esi
  mov    0x0(%rbp),%rdi
  lea    0x8(%r10,%rdx,1),%rdx
  mov    (%rdx),%rcx
  cmp    %eax,%esi
  je     L92
L100:
  movslq %esi,%r11
  nopl   0x0(%rax)
L24:
  lea    0x0(,%r11,8),%rdx
  lea    (%r10,%rdx,1),%r9
  mov    (%r9),%r8
  cmp    %rdi,%r8
  jl     L85
  add    $0x1,%esi
  cmp    %eax,%esi
  jne    L100
  cmp    %rdi,0x8(%r10,%rdx,1)
  jl     L60
L80:
  mov    %eax,%r8d
  cmp    %ebx,%eax
  jne    L38
L15:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L85:
  movslq %eax,%rdx
  lea    (%r10,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L132:
  mov    (%rdx),%rcx
  cmp    %rdi,%rcx
  jg     L1
  sub    $0x1,%eax
  sub    $0x8,%rdx
  cmp    %esi,%eax
  jne    L132
L60:
  lea    -0x1(%rsi),%eax
  mov    %eax,%r8d
  cmp    %ebx,%eax
  je     L15
  jmp    L38
  nop
L1:
  cmp    %eax,%esi
  je     L80
  mov    %rcx,(%r9)
  mov    %r8,(%rdx)
  jmp    L24
L38:
  movslq %eax,%rdx
  mov    0x0(%rbp),%rdi
  lea    (%r10,%rdx,8),%rdx
  mov    (%rdx),%rcx
L51:
  mov    %eax,%r8d
  mov    %rdi,(%rdx)
  mov    %r8d,%eax
  mov    %rcx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  ret
L92:
  cmp    %rcx,%rdi
  jle    L51
  jmp    L60
```

assistant: ```c
int _topnsel_quicksort(long *data, int startidx, int endidx) {
  long pivot = data[startidx];
  int p = startidx + 1;
  int q = endidx;
  long swapbuf;
  if (startidx == endidx)
    return startidx;
  while (1) {
    while (1) {
      if (p == q || data[p] < pivot)
        break;
      p++;
    }
    if (p == q)
      break;
    while (1) {
      if (p == q || data[q] > pivot)
        break;
      q--;
    }
    if (p == q)
      break;
    swapbuf = data[p];
    data[p] = data[q];
    data[q] = swapbuf;
  }
  if (data[p] < pivot)
    p--;
  if (p != startidx) {
    swapbuf = data[p];
    data[p] = data[startidx];
    data[startidx] = swapbuf;
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_topnsel_quicksort>:
  endbr64
  mov    %edx,%eax
  movslq %esi,%rdx
  push   %rbp
  mov    %esi,%r8d
  shl    $0x3,%rdx
  push   %rbx
  mov    %esi,%ebx
  lea    (%rdi,%rdx,1),%rbp
  cmp    %eax,%esi
  je     L19
  mov    %rdi,%r10
  add    $0x1,%esi
  mov    0x0(%rbp),%rdi
  lea    0x8(%r10,%rdx,1),%rdx
  mov    (%rdx),%rcx
  cmp    %eax,%esi
  je     L23
L16:
  movslq %esi,%r11
  nopl   0x0(%rax)
L37:
  lea    0x0(,%r11,8),%rdx
  lea    (%r10,%rdx,1),%r9
  mov    (%r9),%r8
  cmp    %rdi,%r8
  jl     L75
  add    $0x1,%esi
  cmp    %eax,%esi
  jne    L16
  cmp    %rdi,0x8(%r10,%rdx,1)
  jl     L17
L125:
  mov    %eax,%r8d
  cmp    %ebx,%eax
  jne    L45
L19:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L75:
  movslq %eax,%rdx
  lea    (%r10,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L124:
  mov    (%rdx),%rcx
  cmp    %rdi,%rcx
  jg     L47
  sub    $0x1,%eax
  sub    $0x8,%rdx
  cmp    %esi,%eax
  jne    L124
L17:
  lea    -0x1(%rsi),%eax
  mov    %eax,%r8d
  cmp    %ebx,%eax
  je     L19
  jmp    L45
  nop
L47:
  cmp    %eax,%esi
  je     L125
  mov    %rcx,(%r9)
  mov    %r8,(%rdx)
  jmp    L37
L45:
  movslq %eax,%rdx
  mov    0x0(%rbp),%rdi
  lea    (%r10,%rdx,8),%rdx
  mov    (%rdx),%rcx
L42:
  mov    %eax,%r8d
  mov    %rdi,(%rdx)
  mov    %r8d,%eax
  mov    %rcx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  ret
L23:
  cmp    %rcx,%rdi
  jle    L42
  jmp    L17
```

assistant: ```c
int _topnsel_quicksort(long *data, int startidx, int endidx) {
  long pivot = data[startidx];
  int p = startidx + 1;
  int q = endidx;
  long swapbuf;
  if (startidx == endidx)
    return startidx;
  while (1) {
    while (1) {
      if (p == q || data[p] < pivot)
        break;
      p++;
    }
    if (p == q)
      break;
    while (1) {
      if (p == q || data[q] > pivot)
        break;
      q--;
    }
    if (p == q)
      break;
    swapbuf = data[p];
    data[p] = data[q];
    data[q] = swapbuf;
  }
  if (data[p] < pivot)
    p--;
  if (p != startidx) {
    swapbuf = data[p];
    data[p] = data[startidx];
    data[startidx] = swapbuf;
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<i2d_PKCS8PrivateKeyInfo_fp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY2PKCS8@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L13
L2:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <i2d_PKCS8_PRIV_KEY_INFO_fp@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <PKCS8_PRIV_KEY_INFO_free@plt>
  mov    -0xc(%rbp),%eax
L13:
  leave
  ret
```

assistant: ```c
int i2d_PKCS8PrivateKeyInfo_fp(FILE *fp, EVP_PKEY *key) {
  PKCS8_PRIV_KEY_INFO *p8inf;
  int ret;
  p8inf = EVP_PKEY2PKCS8(key);
  if (!p8inf)
    return 0;
  ret = i2d_PKCS8_PRIV_KEY_INFO_fp(fp, p8inf);
  PKCS8_PRIV_KEY_INFO_free(p8inf);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<i2d_PKCS8PrivateKeyInfo_fp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rdi
  call   <EVP_PKEY2PKCS8@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L6
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <i2d_PKCS8_PRIV_KEY_INFO_fp@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <PKCS8_PRIV_KEY_INFO_free@plt>
L6:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int i2d_PKCS8PrivateKeyInfo_fp(FILE *fp, EVP_PKEY *key) {
  PKCS8_PRIV_KEY_INFO *p8inf;
  int ret;
  p8inf = EVP_PKEY2PKCS8(key);
  if (!p8inf)
    return 0;
  ret = i2d_PKCS8_PRIV_KEY_INFO_fp(fp, p8inf);
  PKCS8_PRIV_KEY_INFO_free(p8inf);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i2d_PKCS8PrivateKeyInfo_fp>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  call   <EVP_PKEY2PKCS8@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbp
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <i2d_PKCS8_PRIV_KEY_INFO_fp@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <PKCS8_PRIV_KEY_INFO_free@plt>
L7:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int i2d_PKCS8PrivateKeyInfo_fp(FILE *fp, EVP_PKEY *key) {
  PKCS8_PRIV_KEY_INFO *p8inf;
  int ret;
  p8inf = EVP_PKEY2PKCS8(key);
  if (!p8inf)
    return 0;
  ret = i2d_PKCS8_PRIV_KEY_INFO_fp(fp, p8inf);
  PKCS8_PRIV_KEY_INFO_free(p8inf);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<i2d_PKCS8PrivateKeyInfo_fp>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  call   <EVP_PKEY2PKCS8@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbp
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <i2d_PKCS8_PRIV_KEY_INFO_fp@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <PKCS8_PRIV_KEY_INFO_free@plt>
L6:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int i2d_PKCS8PrivateKeyInfo_fp(FILE *fp, EVP_PKEY *key) {
  PKCS8_PRIV_KEY_INFO *p8inf;
  int ret;
  p8inf = EVP_PKEY2PKCS8(key);
  if (!p8inf)
    return 0;
  ret = i2d_PKCS8_PRIV_KEY_INFO_fp(fp, p8inf);
  PKCS8_PRIV_KEY_INFO_free(p8inf);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mysum@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: %d


assistant: ```c
int main(void) {
  int a = 3;
  int b = 20;
  int c = 0;
  c = mysum(a, b);
  printf("%d\n", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  mov    $0x3,%edi
  call   <mysum@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: %d


assistant: ```c
int main(void) {
  int a = 3;
  int b = 20;
  int c = 0;
  c = mysum(a, b);
  printf("%d\n", c);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  mov    $0x3,%edi
  call   <mysum@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main(void) {
  int a = 3;
  int b = 20;
  int c = 0;
  c = mysum(a, b);
  printf("%d\n", c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  mov    $0x3,%edi
  call   <mysum@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main(void) {
  int a = 3;
  int b = 20;
  int c = 0;
  c = mysum(a, b);
  printf("%d\n", c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WORealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <WOMallocShouldFail@plt>
  test   %rax,%rax
  je     L19
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L16
L19:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L16:
  leave
  ret
```

assistant: ```c
void *WORealloc(void *ptr, size_t size) {
  if (WOMallocShouldFail()) {
    errno = ENOMEM;
    return NULL;
  }
  return realloc(ptr, size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<WORealloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <WOMallocShouldFail@plt>
  test   %rax,%rax
  jne    L7
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <realloc@plt>
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
void *WORealloc(void *ptr, size_t size) {
  if (WOMallocShouldFail()) {
    errno = ENOMEM;
    return NULL;
  }
  return realloc(ptr, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<WORealloc>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <WOMallocShouldFail@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <realloc@plt>
  nop
L1:
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *WORealloc(void *ptr, size_t size) {
  if (WOMallocShouldFail()) {
    errno = ENOMEM;
    return NULL;
  }
  return realloc(ptr, size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<WORealloc>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <WOMallocShouldFail@plt>
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <realloc@plt>
  nop
L0:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *WORealloc(void *ptr, size_t size) {
  if (WOMallocShouldFail()) {
    errno = ENOMEM;
    return NULL;
  }
  return realloc(ptr, size);
}
```