ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x8c8,%rsp
  lea    D8(%rip),%rdi
  lea    D11(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28b8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x1a0(%rsp),%r13
  call   <scanf@plt>
  mov    %r13,%rdi
  movslq 0xc(%rsp),%r12
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <atoi@plt>
  mov    %eax,%r8d
  lea    -0x1(%r12),%eax
  cltq
  mov    %r8d,0x10(%rsp,%rax,4)
  test   %rbx,%rbx
  je     L12
  lea    0x10(%rsp,%r12,4),%rbx
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %edi,%edi
  mov    %rbp,%rsi
  sub    $0x4,%rbx
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L12
  call   <atoi@plt>
  mov    %eax,-0x4(%rbx)
  jmp    L39
L12:
  mov    0xc(%rsp),%eax
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  lea    D20(%rip),%rbp
  test   %eax,%eax
  jle    L62
L49:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %ebx,%edx
  je     L75
  mov    $0x20,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L49
L62:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x28c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L75:
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L49
  jmp    L62
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D20
type_infered: string

tool: D8: %d


tool: D11:  

tool: D20: %d

assistant: ```c
int main() {
  int n, i;
  int nums[100];
  char str[10000];
  char *p;
  scanf("%d\n", &n);
  i = n - 1;
  gets(str);
  p = strtok(str, " ");
  nums[i] = atoi(p);
  while (p != NULL) {
    p = strtok(NULL, " ");
    if (p != NULL) {
      i--;
      nums[i] = atoi(p);
    }
  }
  for (i = 0; i < n; i++) {
    printf("%d", nums[i]);
    if (i != n - 1)
      printf(" ");
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string
name: unpack_data
arguments: data_label: D0
datatype: string

tool: D2: %u

tool: D0: %0*d


assistant: ```c
int main() {
  unsigned int n = 0;
  scanf("%u", &n);
  printf("%0*d\n", n, 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%edx
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D8
data_type: string

tool: D18: %u

tool: D8: %0*d


assistant: ```c
int main() {
  unsigned int n = 0;
  scanf("%u", &n);
  printf("%0*d\n", n, 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %edx,%edx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D16: %u

tool: D4: %0*d


assistant: ```c
int main() {
  unsigned int n = 0;
  scanf("%u", &n);
  printf("%0*d\n", n, 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %edx,%edx
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string
name: retrieve_data
arguments: data_tag: D16
data_type: string

tool: D0: %u

tool: D16: %0*d


assistant: ```c
int main() {
  unsigned int n = 0;
  scanf("%u", &n);
  printf("%0*d\n", n, 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L56:
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L40:
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  je     L22
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L53
L22:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
L53:
  addl   $0x1,-0x14(%rbp)
L17:
  cmpl   $0x0,-0x14(%rbp)
  je     L40
  addl   $0x2,-0x10(%rbp)
L39:
  cmpl   $0x0,-0x10(%rbp)
  je     L56
  mov    -0xc(%rbp),%eax
  lea    0x34862837(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 + local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] - state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 881207351U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x5b661563(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 + local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] - state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 881207351U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x5b661563(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 + local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] - state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 881207351U;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x5b661563(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 + local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] - state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 881207351U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<android_panic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <android_vpanic@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void android_panic(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  android_vpanic(fmt, args);
  va_end(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<android_panic>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <android_vpanic@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void android_panic(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  android_vpanic(fmt, args);
  va_end(args);
}
```
user: What is the c source code of the assembly code below:

```asm
<android_panic>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <android_vpanic@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void android_panic(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  android_vpanic(fmt, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<android_panic>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <android_vpanic@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void android_panic(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  android_vpanic(fmt, args);
  va_end(args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L9:
  movl   $0x1,-0x8(%rbp)
  jmp    L20
L22:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L7
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L7:
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L22
  subl   $0x1,-0xc(%rbp)
L14:
  cmpl   $0x0,-0xc(%rbp)
  jg     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble_sort(int *a, int n) {
  for (int i = n - 1; i > 0; i--) {
    for (int j = 1; j <= i; j++) {
      if (a[j - 1] > a[j]) {
        int tmp = a[j];
        a[j] = a[j - 1];
        a[j - 1] = tmp;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  lea    0x4(%rdi),%r9
  test   %r8d,%r8d
  jg     L35
  ret
L27:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L57
L51:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L27
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L27
L57:
  sub    $0x1,%r8d
  je     L3
L35:
  test   %r8d,%r8d
  jle    L57
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L51
L3:
  ret
```

assistant: ```c
void bubble_sort(int *a, int n) {
  for (int i = n - 1; i > 0; i--) {
    for (int j = 1; j <= i; j++) {
      if (a[j - 1] > a[j]) {
        int tmp = a[j];
        a[j] = a[j - 1];
        a[j - 1] = tmp;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bubble_sort>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L6
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  nopl   (%rax)
L25:
  mov    -0x4(%rdi,%rax,4),%ecx
  mov    (%rdi,%rax,4),%edx
  cmp    %edx,%ecx
  jle    L14
  mov    %ecx,(%rdi,%rax,4)
  mov    %edx,-0x4(%rdi,%rax,4)
L14:
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L25
  sub    $0x1,%esi
  jne    L16
L6:
  ret
```

assistant: ```c
void bubble_sort(int *a, int n) {
  for (int i = n - 1; i > 0; i--) {
    for (int j = 1; j <= i; j++) {
      if (a[j - 1] > a[j]) {
        int tmp = a[j];
        a[j] = a[j - 1];
        a[j - 1] = tmp;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bubble_sort>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L0
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%edx
  nopl   (%rax)
L19:
  movq   -0x4(%rdi,%rdx,4),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L15
  movq   %xmm1,-0x4(%rdi,%rdx,4)
L15:
  add    $0x1,%rdx
  cmp    %edx,%esi
  jge    L19
  sub    $0x1,%esi
  jne    L6
L0:
  ret
```

assistant: ```c
void bubble_sort(int *a, int n) {
  for (int i = n - 1; i > 0; i--) {
    for (int j = 1; j <= i; j++) {
      if (a[j - 1] > a[j]) {
        int tmp = a[j];
        a[j] = a[j - 1];
        a[j - 1] = tmp;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mpi_get_i0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mpi_get_i0(int ng, int rang, int p) {
  int step = ng / p;
  return rang * step;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mpi_get_i0>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  imul   %esi,%eax
  ret
```

assistant: ```c
int mpi_get_i0(int ng, int rang, int p) {
  int step = ng / p;
  return rang * step;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mpi_get_i0>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  imul   %esi,%eax
  ret
```

assistant: ```c
int mpi_get_i0(int ng, int rang, int p) {
  int step = ng / p;
  return rang * step;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mpi_get_i0>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  imul   %esi,%eax
  ret
```

assistant: ```c
int mpi_get_i0(int ng, int rang, int p) {
  int step = ng / p;
  return rang * step;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<word_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L37
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  je     L2
  cmpl   $0x0,-0x10(%rbp)
  jne    L30
  addl   $0x1,-0xc(%rbp)
L30:
  movl   $0x1,-0x10(%rbp)
  jmp    L45
L2:
  movl   $0x0,-0x10(%rbp)
L45:
  addq   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int word_count(char pattern, char *s) {
  int in_word_flag = 0;
  int count = 0;
  char *ptr;
  ptr = s;
  while (*ptr) {
    if ((*ptr) != pattern) {
      if (in_word_flag == 0)
        count++;
      in_word_flag = 1;
    } else
      in_word_flag = 0;
    ptr++;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<word_count>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%r8d
  mov    $0x1,%r9d
  jmp    L41
L17:
  mov    %r8d,%edx
L11:
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  je     L19
L41:
  cmp    %al,%dil
  je     L17
  test   %edx,%edx
  jne    L11
  add    $0x1,%ecx
  mov    %r9d,%edx
  jmp    L11
L8:
  mov    $0x0,%ecx
L19:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int word_count(char pattern, char *s) {
  int in_word_flag = 0;
  int count = 0;
  char *ptr;
  ptr = s;
  while (*ptr) {
    if ((*ptr) != pattern) {
      if (in_word_flag == 0)
        count++;
      in_word_flag = 1;
    } else
      in_word_flag = 0;
    ptr++;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<word_count>:
  endbr64
  movzbl (%rsi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L52
  xor    %edx,%edx
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L8:
  test   %edx,%edx
  jne    L0
  add    $0x1,%r8d
  mov    $0x1,%edx
L0:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L52
L39:
  cmp    %al,%dil
  jne    L8
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  xor    %edx,%edx
  test   %al,%al
  jne    L39
L52:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int word_count(char pattern, char *s) {
  int in_word_flag = 0;
  int count = 0;
  char *ptr;
  ptr = s;
  while (*ptr) {
    if ((*ptr) != pattern) {
      if (in_word_flag == 0)
        count++;
      in_word_flag = 1;
    } else
      in_word_flag = 0;
    ptr++;
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<word_count>:
  endbr64
  movzbl (%rsi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L52
  xor    %edx,%edx
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L19:
  test   %edx,%edx
  jne    L40
  add    $0x1,%r8d
  mov    $0x1,%edx
L40:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L52
L31:
  cmp    %al,%dil
  jne    L19
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  xor    %edx,%edx
  test   %al,%al
  jne    L31
L52:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int word_count(char pattern, char *s) {
  int in_word_flag = 0;
  int count = 0;
  char *ptr;
  ptr = s;
  while (*ptr) {
    if ((*ptr) != pattern) {
      if (in_word_flag == 0)
        count++;
      in_word_flag = 1;
    } else
      in_word_flag = 0;
    ptr++;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parseFloatFromLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L8:
  addl   $0x1,-0xc(%rbp)
  nop
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jae    L14
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L14
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L14
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L14:
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x4(%rbp),%eax
  lea    D12(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void parseFloatFromLine(float *inOutFloat, char *stringToParse, unsigned int length) {
  unsigned int startIndex = 0;
  unsigned int endIndex = 0;
  while (endIndex < length && stringToParse[endIndex] != ' ' && stringToParse[endIndex] != '\n' && stringToParse[endIndex] != '\0') {
    ++endIndex;
    continue;
  }
  {
    static char valueBuffer[64];
    unsigned int valueLength = endIndex - startIndex - 1;
    memcpy(valueBuffer, &stringToParse[startIndex], valueLength);
    valueBuffer[valueLength] = '\0';
    *inOutFloat = (float)atof(valueBuffer);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parseFloatFromLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %edx,%edx
  je     L58
  mov    %rsi,%rdi
  mov    $0x0,%eax
L40:
  movzbl (%rdi),%ecx
  test   $0xdf,%cl
  je     L41
  cmp    $0xa,%cl
  jne    L28
L41:
  lea    -0x1(%rax),%ebx
  mov    %ebx,%edx
  lea    D4(%rip),%r12
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %ebx,%eax
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%edx
  jne    L40
  mov    %edx,%eax
  jmp    L41
L58:
  mov    %edx,%eax
  jmp    L41
```

assistant: ```c
void parseFloatFromLine(float *inOutFloat, char *stringToParse, unsigned int length) {
  unsigned int startIndex = 0;
  unsigned int endIndex = 0;
  while (endIndex < length && stringToParse[endIndex] != ' ' && stringToParse[endIndex] != '\n' && stringToParse[endIndex] != '\0') {
    ++endIndex;
    continue;
  }
  {
    static char valueBuffer[64];
    unsigned int valueLength = endIndex - startIndex - 1;
    memcpy(valueBuffer, &stringToParse[startIndex], valueLength);
    valueBuffer[valueLength] = '\0';
    *inOutFloat = (float)atof(valueBuffer);
  }
}
```