user: 下面的汇编指令对应的C源代码是什么：

```asm
<extract_accepted_languages>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  cmpq   $0x0,-0x88(%rbp)
  je     L126
  mov    -0x88(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x70(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  cmpl   $0x0,-0x74(%rbp)
  je     L17
  addl   $0x1,-0x78(%rbp)
  jmp    L79
L54:
  mov    -0x68(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  test   %eax,%eax
  je     L86
  cmp    $0x2c,%eax
  jne    L80
  jmp    L86
L146:
  addq   $0x1,-0x70(%rbp)
L86:
  mov    -0x70(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L146
  mov    -0x78(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x70(%rbp),%rdx
  mov    %rdx,-0x60(%rbp,%rax,8)
  mov    -0x68(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  addl   $0x1,-0x78(%rbp)
  mov    -0x68(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x68(%rbp)
  movb   $0x0,(%rax)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x70(%rbp)
  nop
L80:
  addq   $0x1,-0x68(%rbp)
L79:
  cmpl   $0x9,-0x78(%rbp)
  jle    L54
L126:
  nop
  jmp    L7
L17:
  nop
  jmp    L7
L33:
  nop
L7:
  mov    -0x78(%rbp),%eax
  cltq
  movq   $0x0,-0x60(%rbp,%rax,8)
  mov    -0x78(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L84
L141:
  mov    -0x78(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rdx
  mov    -0x78(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x78(%rbp)
L84:
  mov    -0x78(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  test   %rax,%rax
  jne    L141
  mov    -0x78(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D19
type_infered: string

tool: D1: found %d languages


tool: D19:   %d: '%s'


assistant: ```c
int extract_accepted_languages(const char *headerline) {
  int cnt = 0;
  char *langarr[10] = {0};
  if (headerline == NULL || *headerline == '\0') {
  } else {
    int len = strlen(headerline);
    char *copy = strdup(headerline);
    char *tmp = copy;
    if (!len)
      goto finish;
    cnt++;
    while (cnt < 10) {
      switch (*tmp) {
      case ',':
      case '\0':
        while (*copy == ' ')
          copy++;
        langarr[cnt - 1] = copy;
        if (!*tmp)
          goto finish;
        ++cnt;
        *tmp++ = '\0';
        copy = tmp;
        break;
      default:;
      }
      ++tmp;
    }
  }
finish:
  langarr[cnt] = NULL;
  printf("found %d languages\n", cnt);
  cnt = 0;
  while (langarr[cnt]) {
    printf("  %d: '%s'\n", cnt, langarr[cnt]);
    cnt++;
  }
  return cnt;
}
```