user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x63,%esi
  jle    L32
  mov    %esi,%eax
  mov    $0x0,%edx
L119:
  sub    $0x64,%eax
  add    $0x1,%edx
  cmp    $0x63,%eax
  jg     L119
  mov    %eax,0x4(%rsp)
L132:
  mov    0x4(%rsp),%eax
  cmp    $0x31,%eax
  jle    L167
  mov    $0x0,%ecx
L96:
  sub    $0x32,%eax
  add    $0x1,%ecx
  cmp    $0x31,%eax
  jg     L96
  mov    %eax,0x4(%rsp)
L111:
  mov    0x4(%rsp),%eax
  cmp    $0x13,%eax
  jle    L175
  mov    $0x0,%r8d
L177:
  sub    $0x14,%eax
  add    $0x1,%r8d
  cmp    $0x13,%eax
  jg     L177
  mov    %eax,0x4(%rsp)
L93:
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  jle    L90
  mov    $0x0,%r9d
L94:
  sub    $0xa,%eax
  add    $0x1,%r9d
  cmp    $0x9,%eax
  jg     L94
  mov    %eax,0x4(%rsp)
L198:
  mov    0x4(%rsp),%eax
  cmp    $0x4,%eax
  jle    L55
  mov    $0x0,%edi
L126:
  sub    $0x5,%eax
  add    $0x1,%edi
  cmp    $0x4,%eax
  jg     L126
  mov    %eax,0x4(%rsp)
L20:
  mov    0x4(%rsp),%r10d
  cmp    $0x1,%r10d
  jle    L199
  mov    %r10d,%eax
L207:
  sub    $0x2,%eax
  cmp    $0x1,%eax
  jg     L207
  lea    -0x2(%r10),%eax
  shr    %eax
  lea    0x1(%rax),%r11d
  neg    %eax
  lea    -0x2(%r10,%rax,2),%eax
  mov    %eax,0x4(%rsp)
L208:
  mov    0x4(%rsp),%r10d
  test   %r10d,%r10d
  jle    L19
  mov    %r10d,%eax
L105:
  sub    $0x1,%eax
  jne    L105
  movl   $0x0,0x4(%rsp)
L68:
  sub    $0x8,%rsp
  push   %r10
  push   %r11
  push   %rdi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L155
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L32:
  mov    $0x0,%edx
  jmp    L132
L167:
  mov    $0x0,%ecx
  jmp    L111
L175:
  mov    $0x0,%r8d
  jmp    L93
L90:
  mov    $0x0,%r9d
  jmp    L198
L55:
  mov    $0x0,%edi
  jmp    L20
L199:
  mov    $0x0,%r11d
  jmp    L208
L19:
  mov    $0x0,%r10d
  jmp    L68
L155:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D10
data_type: string

tool: D17: %d

tool: D10: %d
%d nota(s) de R$ 100,00
%d nota(s) de R$ 50,00
%d nota(s) de R$ 20,00
%d nota(s) de R$ 10,00
%d nota(s) de R$ 5,00
%d nota(s) de R$ 2,00
%d nota(s) de R$ 1,00


assistant: ```c
int main() {
  int valor, fixo, acumulador;
  int contador100 = 0;
  int contador50 = 0;
  int contador20 = 0;
  int contador10 = 0;
  int contador5 = 0;
  int contador2 = 0;
  int contador1 = 0;
  scanf("%d", &valor);
  fixo = valor;
  while (valor >= 100) {
    acumulador = valor - 100;
    valor = acumulador;
    contador100 += 1;
  }
  while (valor >= 50) {
    acumulador = valor - 50;
    valor = acumulador;
    contador50 += 1;
  }
  while (valor >= 20) {
    acumulador = valor - 20;
    valor = acumulador;
    contador20 += 1;
  }
  while (valor >= 10) {
    acumulador = valor - 10;
    valor = acumulador;
    contador10 += 1;
  }
  while (valor >= 5) {
    acumulador = valor - 5;
    valor = acumulador;
    contador5 += 1;
  }
  while (valor >= 2) {
    acumulador = valor - 2;
    valor = acumulador;
    contador2 += 1;
  }
  while (valor >= 1) {
    acumulador = valor - 1;
    valor = acumulador;
    contador1 += 1;
  }
  printf("%d\n%d nota(s) de R$ 100,00\n%d nota(s) de R$ 50,00\n%d nota(s) de R$ 20,00\n%d nota(s) de R$ 10,00\n%d nota(s) de R$ 5,00\n%d nota(s) de R$ 2,00\n%d nota(s) de R$ 1,00\n", fixo, contador100, contador50, contador20, contador10, contador5, contador2, contador1);
  return 0;
}
```