ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<min_down>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ecx
  mov    %edx,%r10d
  mov    $0x1,%ebp
  jmp    L3
L81:
  mov    %ebp,%edx
  cmp    %r10d,%eax
  jge    L61
  mov    %r12d,%esi
  mov    0x0(%r13),%r14
  cmp    %r14,(%rdi,%r15,8)
  jle    L61
L13:
  mov    %ebp,%edx
  cmp    %esi,%ecx
  je     L61
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%rdx
  mov    (%rdx),%rax
  mov    %r8,(%rdx)
  cltq
  mov    %rax,(%r9)
  mov    %esi,%ecx
L3:
  lea    (%rcx,%rcx,1),%eax
  cmp    %r10d,%eax
  setle  %r11b
  movslq %eax,%rdx
  lea    (%rdi,%rdx,8),%rbx
  movslq %ecx,%rsi
  lea    (%rdi,%rsi,8),%r9
  lea    0x8(%rdi,%rdx,8),%r13
  lea    0x1(%rax),%r12d
  mov    $0x0,%edx
  mov    %rsi,%r15
  movslq %eax,%r14
  mov    %r14,-0x8(%rsp)
L61:
  test   %edx,%edx
  jne    L22
  test   %r11b,%r11b
  je     L22
  mov    (%r9),%r8
  cmp    %r8,(%rbx)
  jge    L81
  mov    %eax,%esi
  cmp    %r10d,%eax
  jge    L13
  mov    0x0(%r13),%rsi
  mov    -0x8(%rsp),%rdx
  cmp    %rsi,(%rdi,%rdx,8)
  mov    %r12d,%esi
  cmovle %eax,%esi
  jmp    L13
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void min_down(long long arr[], int i, int n) {
  int flag = 0;
  while (i * 2 <= n && flag == 0) {
    int t = arr[i * 2] < arr[i] ? i * 2 : i;
    if (i * 2 + 1 <= n && arr[t] > arr[i * 2 + 1])
      t = i * 2 + 1;
    if (t != i) {
      int temp = arr[t];
      arr[t] = arr[i];
      arr[i] = temp;
      i = t;
    } else
      flag = 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<min_down>:
  endbr64
  lea    (%rsi,%rsi,1),%ecx
  mov    %rdi,%rax
  cmp    %edx,%ecx
  jg     L44
L75:
  movslq %ecx,%rdi
  mov    (%rax,%rdi,8),%r10
  lea    0x0(,%rdi,8),%r11
  movslq %esi,%rdi
  lea    (%rax,%rdi,8),%r9
  mov    (%r9),%r8
  cmp    %r8,%r10
  jge    L85
  mov    %ecx,%edi
  cmp    %ecx,%edx
  jle    L30
  cmp    0x8(%rax,%r11,1),%r10
  jg     L59
L30:
  cmp    %esi,%edi
  je     L52
  movslq %edi,%rcx
  lea    (%rax,%rcx,8),%rsi
  mov    (%rsi),%rcx
  mov    %r8,(%rsi)
  movslq %ecx,%rcx
  mov    %rcx,(%r9)
  lea    (%rdi,%rdi,1),%ecx
  cmp    %edx,%ecx
  jg     L40
  mov    %edi,%esi
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L85:
  cmp    %ecx,%edx
  jle    L52
  cmp    0x8(%rax,%r11,1),%r8
  jle    L52
L59:
  lea    0x1(%rcx),%edi
  jmp    L30
L52:
  ret
  nopl   0x0(%rax)
L44:
  ret
  nopl   0x0(%rax)
L40:
  ret
```

assistant: ```c
void min_down(long long arr[], int i, int n) {
  int flag = 0;
  while (i * 2 <= n && flag == 0) {
    int t = arr[i * 2] < arr[i] ? i * 2 : i;
    if (i * 2 + 1 <= n && arr[t] > arr[i * 2 + 1])
      t = i * 2 + 1;
    if (t != i) {
      int temp = arr[t];
      arr[t] = arr[i];
      arr[i] = temp;
      i = t;
    } else
      flag = 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<min_down>:
  endbr64
  lea    (%rsi,%rsi,1),%ecx
  mov    %rdi,%rax
  cmp    %edx,%ecx
  jg     L72
L11:
  movslq %ecx,%rdi
  mov    (%rax,%rdi,8),%r10
  lea    0x0(,%rdi,8),%r11
  movslq %esi,%rdi
  lea    (%rax,%rdi,8),%r9
  mov    (%r9),%r8
  cmp    %r8,%r10
  jge    L95
  mov    %ecx,%edi
  cmp    %ecx,%edx
  jle    L9
  cmp    0x8(%rax,%r11,1),%r10
  jg     L51
L9:
  cmp    %esi,%edi
  je     L18
  movslq %edi,%rcx
  lea    (%rax,%rcx,8),%rsi
  mov    (%rsi),%rcx
  mov    %r8,(%rsi)
  movslq %ecx,%rcx
  mov    %rcx,(%r9)
  lea    (%rdi,%rdi,1),%ecx
  cmp    %edx,%ecx
  jg     L61
  mov    %edi,%esi
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L95:
  cmp    %ecx,%edx
  jle    L18
  cmp    0x8(%rax,%r11,1),%r8
  jle    L18
L51:
  lea    0x1(%rcx),%edi
  jmp    L9
L18:
  ret
  nopl   0x0(%rax)
L72:
  ret
  nopl   0x0(%rax)
L61:
  ret
```

assistant: ```c
void min_down(long long arr[], int i, int n) {
  int flag = 0;
  while (i * 2 <= n && flag == 0) {
    int t = arr[i * 2] < arr[i] ? i * 2 : i;
    if (i * 2 + 1 <= n && arr[t] > arr[i * 2 + 1])
      t = i * 2 + 1;
    if (t != i) {
      int temp = arr[t];
      arr[t] = arr[i];
      arr[i] = temp;
      i = t;
    } else
      flag = 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    %esi,%r11d
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  sub    %esi,%edx
  lea    0x1(%rdx),%r9d
  mov    %ecx,%r10d
  sub    %r13d,%r10d
  movslq %r9d,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rsi
  sub    %rax,%rsi
L125:
  cmp    %rsi,%rsp
  je     L121
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L125
L121:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L127
  orq    $0x0,-0x8(%rsp,%rax,1)
L127:
  mov    %rsp,%rdi
  movslq %r10d,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rbx
  and    $0xfffffffffffffff0,%rbx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rsi
  sub    %rax,%rsi
L51:
  cmp    %rsi,%rsp
  je     L56
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L51
L56:
  mov    %rbx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L134
  orq    $0x0,-0x8(%rsp,%rax,1)
L134:
  mov    %rsp,%rsi
  test   %r9d,%r9d
  jle    L176
  mov    %edx,%edx
  lea    0x4(,%rdx,4),%r12
  movslq %r11d,%rax
  lea    (%r8,%rax,4),%rbx
  mov    $0x0,%eax
L58:
  mov    (%rbx,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L58
L176:
  test   %r10d,%r10d
  jle    L152
  lea    0x1(%r10),%r12d
  movslq %r13d,%r13
  lea    (%r8,%r13,4),%rbx
  mov    $0x1,%eax
L159:
  mov    (%rbx,%rax,4),%edx
  mov    %edx,-0x4(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L159
L152:
  cmp    %ecx,%r11d
  jg     L18
  movslq %r11d,%rdx
  lea    (%r8,%rdx,4),%rax
  sub    %r11d,%ecx
  add    %rdx,%rcx
  lea    0x4(%r8,%rcx,4),%r11
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L100
L96:
  movslq %edx,%r8
  mov    (%rsi,%r8,4),%r8d
  mov    %r8d,(%rax)
  add    $0x1,%edx
L133:
  add    $0x4,%rax
  cmp    %rax,%r11
  je     L18
L100:
  cmp    %ecx,%r9d
  jle    L96
  cmp    %edx,%r10d
  je     L63
  movslq %ecx,%r8
  movslq %edx,%rbx
  mov    (%rsi,%rbx,4),%ebx
  cmp    %ebx,(%rdi,%r8,4)
  jge    L96
L63:
  movslq %ecx,%r8
  mov    (%rdi,%r8,4),%r8d
  mov    %r8d,(%rax)
  add    $0x1,%ecx
  jmp    L133
L18:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int *a, int p, int q, int r) {
  int l1, l2, i, j, k;
  l1 = q - p + 1;
  l2 = r - q;
  int left[l1];
  int right[l2];
  for (i = 0; i < l1; i++) {
    left[i] = a[p + i];
  }
  for (i = 0; i < l2; i++) {
    right[i] = a[q + i + 1];
  }
  i = 0;
  j = 0;
  for (k = p; k <= r; k++) {
    if (i < l1 && ((j == l2) || left[i] < right[j])) {
      a[k] = left[i];
      i++;
    } else {
      a[k] = right[j];
      j++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0xffffff85,%edi
  call   <reverse@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", reverse(-123));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff85,%edi
  call   <reverse@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", reverse(-123));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff85,%edi
  call   <reverse@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", reverse(-123));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff85,%edi
  call   <reverse@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", reverse(-123));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tamAI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x2,%eax
  shl    $0x6,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x3ff,%eax
  test   %eax,%eax
  jne    L12
  mov    -0x4(%rbp),%eax
  lea    0x3ff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xa,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L12:
  mov    -0x4(%rbp),%eax
  lea    0x3ff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xa,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int tamAI(unsigned int nbloques) {
  int tam_in = (nbloques / 4) * 64;
  if ((tam_in % 1024) == 0) {
    tam_in = tam_in / 1024;
  } else {
    tam_in = tam_in / 1024;
    tam_in++;
  }
  return (tam_in);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tamAI>:
  endbr64
  shr    $0x2,%edi
  shl    $0x6,%edi
  test   $0x3ff,%edi
  jne    L0
  lea    0x3ff(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0xa,%eax
  ret
L0:
  lea    0x3ff(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0xa,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int tamAI(unsigned int nbloques) {
  int tam_in = (nbloques / 4) * 64;
  if ((tam_in % 1024) == 0) {
    tam_in = tam_in / 1024;
  } else {
    tam_in = tam_in / 1024;
    tam_in++;
  }
  return (tam_in);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tamAI>:
  endbr64
  shr    $0x2,%edi
  shl    $0x6,%edi
  lea    0x3ff(%rdi),%eax
  cmovns %edi,%eax
  and    $0x3ff,%edi
  sar    $0xa,%eax
  cmp    $0x1,%edi
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int tamAI(unsigned int nbloques) {
  int tam_in = (nbloques / 4) * 64;
  if ((tam_in % 1024) == 0) {
    tam_in = tam_in / 1024;
  } else {
    tam_in = tam_in / 1024;
    tam_in++;
  }
  return (tam_in);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tamAI>:
  endbr64
  shr    $0x2,%edi
  shl    $0x6,%edi
  lea    0x3ff(%rdi),%eax
  cmovns %edi,%eax
  and    $0x3ff,%edi
  sar    $0xa,%eax
  cmp    $0x1,%edi
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int tamAI(unsigned int nbloques) {
  int tam_in = (nbloques / 4) * 64;
  if ((tam_in % 1024) == 0) {
    tam_in = tam_in / 1024;
  } else {
    tam_in = tam_in / 1024;
    tam_in++;
  }
  return (tam_in);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string
name: extract_symbolic_data
arguments: data_tag: D20
datatype: string
name: extract_symbolic_data
arguments: data_tag: D30
datatype: string

tool: D39: r

tool: D8: ./fst.txt

tool: D20: w

tool: D30: ./snd.txt

assistant: ```c
int main() {
  FILE *fst = fopen("./fst.txt", "r");
  FILE *snd = fopen("./snd.txt", "w");
  copy(fst, snd);
  fclose(fst);
  fclose(snd);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    D30(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <copy@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D30
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D3: r

tool: D6: ./fst.txt

tool: D30: w

tool: D0: ./snd.txt

assistant: ```c
int main() {
  FILE *fst = fopen("./fst.txt", "r");
  FILE *snd = fopen("./snd.txt", "w");
  copy(fst, snd);
  fclose(fst);
  fclose(snd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D39(%rip),%rsi
  lea    D23(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  lea    D6(%rip),%rsi
  lea    D2(%rip),%rdi
  mov    %rax,%r12
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <copy@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D39
type_guessed: string
name: read_data
arguments: data_tag: D23
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D39: r

tool: D23: ./fst.txt

tool: D6: w

tool: D2: ./snd.txt

assistant: ```c
int main() {
  FILE *fst = fopen("./fst.txt", "r");
  FILE *snd = fopen("./snd.txt", "w");
  copy(fst, snd);
  fclose(fst);
  fclose(snd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%rsi
  lea    D18(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  lea    D0(%rip),%rsi
  lea    D20(%rip),%rdi
  mov    %rax,%r12
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <copy@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string
name: retrieve_data
arguments: label: D18
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D20
type_infered: string

tool: D4: r

tool: D18: ./fst.txt

tool: D0: w

tool: D20: ./snd.txt

assistant: ```c
int main() {
  FILE *fst = fopen("./fst.txt", "r");
  FILE *snd = fopen("./snd.txt", "w");
  copy(fst, snd);
  fclose(fst);
  fclose(snd);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ddr_pll_config_x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x64,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <uart_putf@plt>
  mov    $0x44e00494,%eax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x44e00440,%eax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x44e004a0,%eax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0xfffffff8,%eax
  or     $0x4,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x44e00494,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x65,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <uart_putf@plt>
  nop
L19:
  mov    $0x44e00434,%eax
  mov    (%rax),%eax
  and    $0x100,%eax
  test   %eax,%eax
  je     L19
  mov    $0x66,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <uart_putf@plt>
  andl   $0xfff80000,-0x8(%rbp)
  orl    $0x19017,-0x8(%rbp)
  mov    $0x44e00440,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x67,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <uart_putf@plt>
  andl   $0xffffffe0,-0x4(%rbp)
  orl    $0x1,-0x4(%rbp)
  mov    $0x44e004a0,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x68,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <uart_putf@plt>
  mov    -0xc(%rbp),%eax
  or     $0x7,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x44e00494,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x69,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <uart_putf@plt>
  nop
L14:
  mov    $0x44e00434,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
  mov    $0x6a,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <uart_putf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D54
data_type: string

tool: D54: DEBUG%i


assistant: ```c
void ddr_pll_config_x(void) {
  uint32_t clkmode, clksel, div_m2;
  uart_putf("DEBUG%i\n", (100));
  clkmode = *(uint32_t *)(0x44E00494);
  clksel = *(uint32_t *)(0x44E00440);
  div_m2 = *(uint32_t *)(0x44E004A0);
  clkmode = (clkmode & 0xfffffff8) | 0x00000004;
  *(uint32_t *)(0x44E00494) = (uint32_t)(clkmode);
  uart_putf("DEBUG%i\n", (101));
  while ((*(uint32_t *)(0x44E00434) & 0x00000100) != 0x00000100)
    ;
  uart_putf("DEBUG%i\n", (102));
  clksel = clksel & (~0x7ffff);
  clksel = clksel | ((400 << 0x8) | ((24000000 / 1000000) - 1));
  *(uint32_t *)(0x44E00440) = (uint32_t)(clksel);
  uart_putf("DEBUG%i\n", (103));
  div_m2 = div_m2 & 0xFFFFFFE0;
  div_m2 = div_m2 | 1;
  *(uint32_t *)(0x44E004A0) = (uint32_t)(div_m2);
  uart_putf("DEBUG%i\n", (104));
  clkmode = (clkmode & 0xfffffff8) | 0x00000007;
  *(uint32_t *)(0x44E00494) = (uint32_t)(clkmode);
  uart_putf("DEBUG%i\n", (105));
  while ((*(uint32_t *)(0x44E00434) & 0x00000001) != 0x00000001)
    ;
  uart_putf("DEBUG%i\n", (106));
}
```
user: What is the c source code of the assembly code below?

```asm
<ddr_pll_config_x>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%esi
  lea    D1(%rip),%r13
  mov    %r13,%rdi
  call   <uart_putf@plt>
  mov    0x44e00440,%r12d
  mov    0x44e004a0,%ebp
  mov    0x44e00494,%ebx
  and    $0xfffffff8,%ebx
  mov    %ebx,%eax
  or     $0x4,%eax
  mov    %eax,0x44e00494
  mov    $0x65,%esi
  mov    %r13,%rdi
  call   <uart_putf@plt>
  mov    0x44e00434,%eax
  and    $0x100,%eax
L3:
  test   %eax,%eax
  je     L3
  mov    $0x66,%esi
  lea    D1(%rip),%r13
  mov    %r13,%rdi
  call   <uart_putf@plt>
  and    $0xfff80000,%r12d
  or     $0x19017,%r12d
  mov    %r12d,0x44e00440
  mov    $0x67,%esi
  mov    %r13,%rdi
  call   <uart_putf@plt>
  and    $0xffffffe0,%ebp
  or     $0x1,%ebp
  mov    %ebp,0x44e004a0
  mov    $0x68,%esi
  mov    %r13,%rdi
  call   <uart_putf@plt>
  or     $0x7,%ebx
  mov    %ebx,0x44e00494
  mov    $0x69,%esi
  mov    %r13,%rdi
  call   <uart_putf@plt>
  mov    0x44e00434,%eax
  and    $0x1,%eax
L14:
  test   %eax,%eax
  je     L14
  mov    $0x6a,%esi
  lea    D1(%rip),%rdi
  call   <uart_putf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: DEBUG%i


assistant: ```c
void ddr_pll_config_x(void) {
  uint32_t clkmode, clksel, div_m2;
  uart_putf("DEBUG%i\n", (100));
  clkmode = *(uint32_t *)(0x44E00494);
  clksel = *(uint32_t *)(0x44E00440);
  div_m2 = *(uint32_t *)(0x44E004A0);
  clkmode = (clkmode & 0xfffffff8) | 0x00000004;
  *(uint32_t *)(0x44E00494) = (uint32_t)(clkmode);
  uart_putf("DEBUG%i\n", (101));
  while ((*(uint32_t *)(0x44E00434) & 0x00000100) != 0x00000100)
    ;
  uart_putf("DEBUG%i\n", (102));
  clksel = clksel & (~0x7ffff);
  clksel = clksel | ((400 << 0x8) | ((24000000 / 1000000) - 1));
  *(uint32_t *)(0x44E00440) = (uint32_t)(clksel);
  uart_putf("DEBUG%i\n", (103));
  div_m2 = div_m2 & 0xFFFFFFE0;
  div_m2 = div_m2 | 1;
  *(uint32_t *)(0x44E004A0) = (uint32_t)(div_m2);
  uart_putf("DEBUG%i\n", (104));
  clkmode = (clkmode & 0xfffffff8) | 0x00000007;
  *(uint32_t *)(0x44E00494) = (uint32_t)(clkmode);
  uart_putf("DEBUG%i\n", (105));
  while ((*(uint32_t *)(0x44E00434) & 0x00000001) != 0x00000001)
    ;
  uart_putf("DEBUG%i\n", (106));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ddr_pll_config_x>:
  endbr64
  push   %r13
  mov    $0x64,%esi
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <uart_putf@plt>
  mov    0x44e00494,%ebx
  mov    %rbp,%rdi
  mov    $0x65,%esi
  mov    0x44e00440,%r13d
  mov    0x44e004a0,%r12d
  and    $0xfffffff8,%ebx
  mov    %ebx,%eax
  or     $0x4,%eax
  mov    %eax,0x44e00494
  call   <uart_putf@plt>
  testb  $0x1,0x44e00435
  jne    L1
L17:
  jmp    L17
  nopl   0x0(%rax)
L1:
  mov    $0x66,%esi
  mov    %rbp,%rdi
  and    $0xffffffe0,%r12d
  or     $0x7,%ebx
  call   <uart_putf@plt>
  and    $0xfff80000,%r13d
  mov    $0x67,%esi
  mov    %rbp,%rdi
  or     $0x19017,%r13d
  or     $0x1,%r12d
  mov    %r13d,0x44e00440
  call   <uart_putf@plt>
  mov    %r12d,0x44e004a0
  mov    $0x68,%esi
  mov    %rbp,%rdi
  call   <uart_putf@plt>
  mov    %ebx,0x44e00494
  mov    $0x69,%esi
  mov    %rbp,%rdi
  call   <uart_putf@plt>
  testb  $0x1,0x44e00434
  jne    L14
L2:
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    $0x6a,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <uart_putf@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: DEBUG%i


assistant: ```c
void ddr_pll_config_x(void) {
  uint32_t clkmode, clksel, div_m2;
  uart_putf("DEBUG%i\n", (100));
  clkmode = *(uint32_t *)(0x44E00494);
  clksel = *(uint32_t *)(0x44E00440);
  div_m2 = *(uint32_t *)(0x44E004A0);
  clkmode = (clkmode & 0xfffffff8) | 0x00000004;
  *(uint32_t *)(0x44E00494) = (uint32_t)(clkmode);
  uart_putf("DEBUG%i\n", (101));
  while ((*(uint32_t *)(0x44E00434) & 0x00000100) != 0x00000100)
    ;
  uart_putf("DEBUG%i\n", (102));
  clksel = clksel & (~0x7ffff);
  clksel = clksel | ((400 << 0x8) | ((24000000 / 1000000) - 1));
  *(uint32_t *)(0x44E00440) = (uint32_t)(clksel);
  uart_putf("DEBUG%i\n", (103));
  div_m2 = div_m2 & 0xFFFFFFE0;
  div_m2 = div_m2 | 1;
  *(uint32_t *)(0x44E004A0) = (uint32_t)(div_m2);
  uart_putf("DEBUG%i\n", (104));
  clkmode = (clkmode & 0xfffffff8) | 0x00000007;
  *(uint32_t *)(0x44E00494) = (uint32_t)(clkmode);
  uart_putf("DEBUG%i\n", (105));
  while ((*(uint32_t *)(0x44E00434) & 0x00000001) != 0x00000001)
    ;
  uart_putf("DEBUG%i\n", (106));
}
```