ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<AlignmentShuffle>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %edx,%r14d
  mov    %ecx,%r12d
  cmp    %rsi,%rdi
  je     L4
  mov    %rsi,%rbp
  test   %edx,%edx
  jle    L84
  mov    %edx,%r15d
  mov    $0x0,%ebx
L63:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    0x0(%r13,%rbx,8),%rdi
  call   <strcpy@plt>
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L63
L90:
  mov    $0x0,%eax
  movslq %r12d,%rcx
L32:
  mov    0x0(%r13,%rax,8),%rdx
  movb   $0x0,(%rdx,%rcx,1)
  add    $0x1,%rax
  cmp    %eax,%r14d
  jg     L32
L84:
  cmp    $0x1,%r12d
  jle    L5
  movslq %r12d,%rbx
  sub    $0x1,%rbx
  lea    -0x1(%r14),%eax
  lea    0x0(%r13,%rax,8),%rbp
L89:
  mov    $0x0,%eax
  call   <sre_random@plt>
  imul   %r12d,%eax
  test   %r14d,%r14d
  jle    L92
  mov    %r13,%rdx
  cltq
L30:
  mov    %rdx,%rdi
  mov    (%rdx),%rsi
  lea    (%rsi,%rax,1),%rcx
  movzbl (%rcx),%r8d
  movzbl (%rsi,%rbx,1),%esi
  mov    %sil,(%rcx)
  mov    (%rdx),%rcx
  mov    %r8b,(%rcx,%rbx,1)
  add    $0x8,%rdx
  cmp    %rbp,%rdi
  jne    L30
L92:
  sub    $0x1,%r12d
  sub    $0x1,%rbx
  cmp    $0x1,%r12d
  jne    L89
L5:
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  test   %edx,%edx
  jg     L90
  jmp    L84
```

assistant: ```c
int AlignmentShuffle(char **ali1, char **ali2, int nseq, int alen) {
  int i;
  int pos;
  char c;
  if (ali1 != ali2) {
    for (i = 0; i < nseq; i++)
      strcpy(ali1[i], ali2[i]);
  }
  for (i = 0; i < nseq; i++)
    ali1[i][alen] = '\0';
  for (; alen > 1; alen--) {
    pos = ((int)(sre_random() * (alen)));
    for (i = 0; i < nseq; i++) {
      c = ali1[i][pos];
      ali1[i][pos] = ali1[i][alen - 1];
      ali1[i][alen - 1] = c;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<AlignmentShuffle>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rsi,%rdi
  je     L20
  mov    %rsi,%r15
  movslq %edx,%r14
  xor    %ebx,%ebx
  test   %edx,%edx
  jle    L70
  nop
L80:
  mov    (%r15,%rbx,8),%rsi
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <strcpy@plt>
  cmp    %rbx,%r14
  jne    L80
L56:
  movslq %r13d,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%r12,%rax,8),%rdx
  add    $0x1,%rax
  movb   $0x0,(%rdx,%rcx,1)
  cmp    %eax,%ebp
  jg     L3
L70:
  cmp    $0x1,%r13d
  jle    L48
  movslq %r13d,%rbx
  lea    -0x1(%rbp),%eax
  sub    $0x1,%rbx
  lea    (%r12,%rax,8),%r14
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  call   <sre_random@plt>
  mov    %r12,%rdx
  imul   %r13d,%eax
  cltq
  test   %ebp,%ebp
  jle    L44
  nopl   0x0(%rax)
L25:
  mov    (%rdx),%rsi
  mov    %rdx,%rdi
  add    $0x8,%rdx
  lea    (%rsi,%rax,1),%rcx
  movzbl (%rsi,%rbx,1),%esi
  movzbl (%rcx),%r8d
  mov    %sil,(%rcx)
  mov    -0x8(%rdx),%rcx
  mov    %r8b,(%rcx,%rbx,1)
  cmp    %rdi,%r14
  jne    L25
L44:
  sub    $0x1,%r13d
  sub    $0x1,%rbx
  cmp    $0x1,%r13d
  jne    L13
L48:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  test   %edx,%edx
  jg     L56
  jmp    L70
```

assistant: ```c
int AlignmentShuffle(char **ali1, char **ali2, int nseq, int alen) {
  int i;
  int pos;
  char c;
  if (ali1 != ali2) {
    for (i = 0; i < nseq; i++)
      strcpy(ali1[i], ali2[i]);
  }
  for (i = 0; i < nseq; i++)
    ali1[i][alen] = '\0';
  for (; alen > 1; alen--) {
    pos = ((int)(sre_random() * (alen)));
    for (i = 0; i < nseq; i++) {
      c = ali1[i][pos];
      ali1[i][pos] = ali1[i][alen - 1];
      ali1[i][alen - 1] = c;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<AlignmentShuffle>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rsi,%rdi
  je     L30
  mov    %rsi,%r15
  movslq %edx,%r14
  xor    %ebx,%ebx
  test   %edx,%edx
  jle    L91
  nop
L44:
  mov    (%r15,%rbx,8),%rsi
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <strcpy@plt>
  cmp    %rbx,%r14
  jne    L44
L34:
  movslq %r13d,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%r12,%rax,8),%rdx
  add    $0x1,%rax
  movb   $0x0,(%rdx,%rcx,1)
  cmp    %eax,%ebp
  jg     L2
L91:
  cmp    $0x1,%r13d
  jle    L62
  movslq %r13d,%rbx
  lea    -0x1(%rbp),%eax
  sub    $0x1,%rbx
  lea    (%r12,%rax,8),%r14
  nopl   0x0(%rax)
L35:
  xor    %eax,%eax
  call   <sre_random@plt>
  mov    %r12,%rdx
  imul   %r13d,%eax
  cltq
  test   %ebp,%ebp
  jle    L73
  nopl   0x0(%rax)
L40:
  mov    (%rdx),%rsi
  mov    %rdx,%rdi
  add    $0x8,%rdx
  lea    (%rsi,%rax,1),%rcx
  movzbl (%rsi,%rbx,1),%esi
  movzbl (%rcx),%r8d
  mov    %sil,(%rcx)
  mov    -0x8(%rdx),%rcx
  mov    %r8b,(%rcx,%rbx,1)
  cmp    %r14,%rdi
  jne    L40
L73:
  sub    $0x1,%r13d
  sub    $0x1,%rbx
  cmp    $0x1,%r13d
  jne    L35
L62:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  test   %edx,%edx
  jg     L34
  jmp    L91
```

assistant: ```c
int AlignmentShuffle(char **ali1, char **ali2, int nseq, int alen) {
  int i;
  int pos;
  char c;
  if (ali1 != ali2) {
    for (i = 0; i < nseq; i++)
      strcpy(ali1[i], ali2[i]);
  }
  for (i = 0; i < nseq; i++)
    ali1[i][alen] = '\0';
  for (; alen > 1; alen--) {
    pos = ((int)(sre_random() * (alen)));
    for (i = 0; i < nseq; i++) {
      c = ali1[i][pos];
      ali1[i][pos] = ali1[i][alen - 1];
      ali1[i][alen - 1] = c;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D2(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: foo

assistant: ```c
char *bar(void) {
  const char *s = "foo";
  char *s1 = s;
  s1 = s;
  foo(s);
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: foo

assistant: ```c
char *bar(void) {
  const char *s = "foo";
  char *s1 = s;
  s1 = s;
  foo(s);
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bar>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  mov    %r12,%rdi
  call   <foo@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: foo

assistant: ```c
char *bar(void) {
  const char *s = "foo";
  char *s1 = s;
  s1 = s;
  foo(s);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<bar>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  mov    %r12,%rdi
  call   <foo@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string

tool: D2: foo

assistant: ```c
char *bar(void) {
  const char *s = "foo";
  char *s1 = s;
  s1 = s;
  foo(s);
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<my_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L85
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L2
  mov    $0xffffffff,%eax
  jmp    L27
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L37
  mov    $0x1,%eax
  jmp    L27
L37:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x1,%eax
  jmp    L27
L28:
  addl   $0x1,-0x4(%rbp)
L85:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L40
  mov    $0xffffffff,%eax
  jmp    L27
L40:
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int my_strcmp(char *s1, char *s2) {
  int i;
  i = 0;
  while (*(s1 + i) != '\0') {
    if (*(s1 + i) < *(s2 + i))
      return (-1);
    else if (*(s1 + i) > *(s2 + i))
      return (1);
    else if (*(s2 + i) == '\0')
      return (1);
    i++;
  }
  if (*(s2 + i) != '\0')
    return (-1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<my_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L25
  mov    $0x0,%ecx
L34:
  movzbl (%rsi,%rcx,1),%edx
  cmp    %al,%dl
  jg     L13
  test   %dl,%dl
  je     L10
  cmp    %al,%dl
  jl     L10
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  jne    L34
L3:
  movzbl (%rsi,%rcx,1),%eax
  neg    %al
  sbb    %eax,%eax
  ret
L25:
  mov    $0x0,%ecx
  jmp    L3
L13:
  mov    $0xffffffff,%eax
  ret
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int my_strcmp(char *s1, char *s2) {
  int i;
  i = 0;
  while (*(s1 + i) != '\0') {
    if (*(s1 + i) < *(s2 + i))
      return (-1);
    else if (*(s1 + i) > *(s2 + i))
      return (1);
    else if (*(s2 + i) == '\0')
      return (1);
    i++;
  }
  if (*(s2 + i) != '\0')
    return (-1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  xor    %ecx,%ecx
  jmp    L53
  nop
L37:
  test   %dl,%dl
  je     L14
  cmp    %al,%dl
  jl     L14
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L48
L53:
  movzbl (%rsi,%rcx,1),%edx
  cmp    %al,%dl
  jle    L37
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L48:
  add    %rcx,%rsi
L18:
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
```

assistant: ```c
int my_strcmp(char *s1, char *s2) {
  int i;
  i = 0;
  while (*(s1 + i) != '\0') {
    if (*(s1 + i) < *(s2 + i))
      return (-1);
    else if (*(s1 + i) > *(s2 + i))
      return (1);
    else if (*(s2 + i) == '\0')
      return (1);
    i++;
  }
  if (*(s2 + i) != '\0')
    return (-1);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L52
  xor    %ecx,%ecx
  jmp    L7
  nop
L21:
  test   %dl,%dl
  je     L46
  cmp    %al,%dl
  jl     L46
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L4
L7:
  movzbl (%rsi,%rcx,1),%edx
  cmp    %al,%dl
  jle    L21
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L4:
  add    %rcx,%rsi
L52:
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
```

assistant: ```c
int my_strcmp(char *s1, char *s2) {
  int i;
  i = 0;
  while (*(s1 + i) != '\0') {
    if (*(s1 + i) < *(s2 + i))
      return (-1);
    else if (*(s1 + i) > *(s2 + i))
      return (1);
    else if (*(s2 + i) == '\0')
      return (1);
    i++;
  }
  if (*(s2 + i) != '\0')
    return (-1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Inf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x7ff00000,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L9
  mov    -0x18(%rbp),%rax
  or     $0xffffffff80000000,%rax
  mov    %rax,-0x18(%rbp)
L9:
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double Inf(int sign) {
  union {
    double d;
    long x[2];
  } a;
  a.x[1] = (2047 << 20);
  a.x[0] = 0;
  if (sign < 0)
    a.x[1] |= (1 << 31);
  return a.d;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Inf>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double Inf(int sign) {
  union {
    double d;
    long x[2];
  } a;
  a.x[1] = (2047 << 20);
  a.x[0] = 0;
  if (sign < 0)
    a.x[1] |= (1 << 31);
  return a.d;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Inf>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double Inf(int sign) {
  union {
    double d;
    long x[2];
  } a;
  a.x[1] = (2047 << 20);
  a.x[0] = 0;
  if (sign < 0)
    a.x[1] |= (1 << 31);
  return a.d;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Inf>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double Inf(int sign) {
  union {
    double d;
    long x[2];
  } a;
  a.x[1] = (2047 << 20);
  a.x[0] = 0;
  if (sign < 0)
    a.x[1] |= (1 << 31);
  return a.d;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x24,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: tutu %c


assistant: ```c
int main(void) {
  printf("tutu %c\n", 0x24);
  for (;;)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x24,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
L1:
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: tutu %c


assistant: ```c
int main(void) {
  printf("tutu %c\n", 0x24);
  for (;;)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x24,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L1:
  jmp    L1
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: tutu %c


assistant: ```c
int main(void) {
  printf("tutu %c\n", 0x24);
  for (;;)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x24,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
L7:
  jmp    L7
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: tutu %c


assistant: ```c
int main(void) {
  printf("tutu %c\n", 0x24);
  for (;;)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <odd@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x3,-0x8(%rbp)
  je     L6
  mov    $0x1,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L6:
  mov    $0x0,%eax
  call   <odd1@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L4
  mov    $0x2,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L4:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D26
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D26: Error %d


tool: D11: Success

assistant: ```c
int main() {
  {
    int x = odd();
    if (x != 3) {
      printf("Error %d\n", (int)1);
      exit(1);
    };
  }
  {
    int y = odd1();
    if (y != 1) {
      printf("Error %d\n", (int)2);
      exit(2);
    };
  }
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <odd@plt>
  cmp    $0x3,%eax
  jne    L35
L22:
  mov    $0x0,%eax
  call   <odd1@plt>
  cmp    $0x1,%eax
  jne    L0
L14:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L35:
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L22
L0:
  mov    $0x2,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D1: Success

tool: D2: Error %d


assistant: ```c
int main() {
  {
    int x = odd();
    if (x != 3) {
      printf("Error %d\n", (int)1);
      exit(1);
    };
  }
  {
    int y = odd1();
    if (y != 1) {
      printf("Error %d\n", (int)2);
      exit(2);
    };
  }
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <odd@plt>
  cmp    $0x3,%eax
  je     L11
  lea    D25(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L11:
  xor    %eax,%eax
  call   <odd1@plt>
  cmp    $0x1,%eax
  je     L15
  lea    D25(%rip),%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L15:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type: string
name: extract_symbolic_data
arguments: data_label: D27
type: string

tool: D25: Error %d


tool: D27: Success

assistant: ```c
int main() {
  {
    int x = odd();
    if (x != 3) {
      printf("Error %d\n", (int)1);
      exit(1);
    };
  }
  {
    int y = odd1();
    if (y != 1) {
      printf("Error %d\n", (int)2);
      exit(2);
    };
  }
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <odd@plt>
  cmp    $0x3,%eax
  je     L2
  lea    D22(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  xor    %eax,%eax
  call   <odd1@plt>
  cmp    $0x1,%eax
  je     L12
  lea    D22(%rip),%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L12:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string

tool: D22: Error %d


tool: D28: Success

assistant: ```c
int main() {
  {
    int x = odd();
    if (x != 3) {
      printf("Error %d\n", (int)1);
      exit(1);
    };
  }
  {
    int y = odd1();
    if (y != 1) {
      printf("Error %d\n", (int)2);
      exit(2);
    };
  }
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L17
L24:
  subq   $0x1,-0x8(%rbp)
L17:
  cmpq   $0x0,-0x8(%rbp)
  je     L33
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L24
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L24
L33:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t string_chomp(char *str) {
  size_t len = strlen(str);
  while (len > 0 && (str[len - 1] == '\r' || str[len - 1] == '\n')) {
    len--;
  }
  str[len] = '\0';
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<string_chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  jmp    L5
L18:
  mov    %rcx,%rax
L5:
  test   %rax,%rax
  je     L8
  lea    -0x1(%rax),%rcx
  movzbl -0x1(%rbx,%rax,1),%edx
  cmp    $0xd,%dl
  je     L18
  cmp    $0xa,%dl
  je     L18
L8:
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
size_t string_chomp(char *str) {
  size_t len = strlen(str);
  while (len > 0 && (str[len - 1] == '\r' || str[len - 1] == '\n')) {
    len--;
  }
  str[len] = '\0';
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  jmp    L15
  nop
L18:
  movzbl -0x1(%rbx,%rax,1),%edx
  lea    -0x1(%rax),%rcx
  cmp    $0xd,%dl
  je     L38
  cmp    $0xa,%dl
  jne    L4
L38:
  mov    %rcx,%rax
L15:
  test   %rax,%rax
  jne    L18
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
L4:
  add    %rax,%rbx
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
size_t string_chomp(char *str) {
  size_t len = strlen(str);
  while (len > 0 && (str[len - 1] == '\r' || str[len - 1] == '\n')) {
    len--;
  }
  str[len] = '\0';
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<string_chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  jmp    L10
  nop
L20:
  movzbl -0x1(%rbx,%rax,1),%edx
  lea    -0x1(%rax),%rcx
  cmp    $0xd,%dl
  je     L21
  cmp    $0xa,%dl
  jne    L8
L21:
  mov    %rcx,%rax
L10:
  test   %rax,%rax
  jne    L20
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
L8:
  add    %rax,%rbx
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
size_t string_chomp(char *str) {
  size_t len = strlen(str);
  while (len > 0 && (str[len - 1] == '\r' || str[len - 1] == '\n')) {
    len--;
  }
  str[len] = '\0';
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L1:
  shlq   -0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: %lld


assistant: ```c
int main() {
  unsigned long long num;
  int i;
  num = 1;
  for (i = 0; i < 64; i++) {
    num *= 2;
    num += 1;
    printf("%lld\n", num);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x40,%ebp
  mov    $0x1,%ebx
  lea    D5(%rip),%r12
L4:
  lea    0x1(%rbx,%rbx,1),%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L4
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: %lld


assistant: ```c
int main() {
  unsigned long long num;
  int i;
  num = 1;
  for (i = 0; i < 64; i++) {
    num *= 2;
    num += 1;
    printf("%lld\n", num);
  }
  return 0;
}
```