ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<strict_strtoul>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rdx)
  call   <strlen@plt>
  test   %rax,%rax
  je     L57
  mov    %r13d,%edx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strtoul@plt>
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L57
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L60
  sub    %rbx,%rdx
  add    $0x1,%rdx
  cmp    %r12,%rdx
  jne    L57
  cmp    $0xa,%cl
  jne    L57
L60:
  mov    %rax,0x0(%rbp)
  xor    %eax,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    $0xffffffea,%eax
  jmp    L19
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strict_strtoul(const char *cp, unsigned int base, unsigned long *res) {
  char *tail;
  unsigned long val;
  size_t len;
  *res = 0;
  len = strlen(cp);
  if (len == 0)
    return -22;
  val = strtoul(cp, &tail, base);
  if (tail == cp)
    return -22;
  if ((*tail == '\0') || ((len == (size_t)(tail - cp) + 1) && (*tail == '\n'))) {
    *res = val;
    return 0;
  }
  return -22;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memWrite32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memWrite32(int val, unsigned char *p) {
  *(p + 0) = (val >> 0) & 0xFF;
  *(p + 1) = (val >> 8) & 0xFF;
  *(p + 2) = (val >> 16) & 0xFF;
  *(p + 3) = (val >> 24) & 0xFF;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memWrite32>:
  endbr64
  mov    %edi,%eax
  mov    %dil,(%rsi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rsi)
  mov    %edi,%edx
  sar    $0x10,%edx
  mov    %dl,0x2(%rsi)
  shr    $0x18,%eax
  mov    %al,0x3(%rsi)
  ret
```

assistant: ```c
void memWrite32(int val, unsigned char *p) {
  *(p + 0) = (val >> 0) & 0xFF;
  *(p + 1) = (val >> 8) & 0xFF;
  *(p + 2) = (val >> 16) & 0xFF;
  *(p + 3) = (val >> 24) & 0xFF;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memWrite32>:
  endbr64
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void memWrite32(int val, unsigned char *p) {
  *(p + 0) = (val >> 0) & 0xFF;
  *(p + 1) = (val >> 8) & 0xFF;
  *(p + 2) = (val >> 16) & 0xFF;
  *(p + 3) = (val >> 24) & 0xFF;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memWrite32>:
  endbr64
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void memWrite32(int val, unsigned char *p) {
  *(p + 0) = (val >> 0) & 0xFF;
  *(p + 1) = (val >> 8) & 0xFF;
  *(p + 2) = (val >> 16) & 0xFF;
  *(p + 3) = (val >> 24) & 0xFF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<map_netdb_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x7,%eax
  pop    %rbp
  ret
```

assistant: ```c
int map_netdb_error(int netdb_code) {
  switch (netdb_code) {
  default:
    return 7;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<map_netdb_error>:
  endbr64
  mov    $0x7,%eax
  ret
```

assistant: ```c
int map_netdb_error(int netdb_code) {
  switch (netdb_code) {
  default:
    return 7;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<map_netdb_error>:
  endbr64
  mov    $0x7,%eax
  ret
```

assistant: ```c
int map_netdb_error(int netdb_code) {
  switch (netdb_code) {
  default:
    return 7;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<map_netdb_error>:
  endbr64
  mov    $0x7,%eax
  ret
```

assistant: ```c
int map_netdb_error(int netdb_code) {
  switch (netdb_code) {
  default:
    return 7;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_to_int_u>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  jmp    L29
L46:
  mov    -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  or     %ebx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  addq   $0x1,-0x28(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L46
  jmp    L11
L42:
  mov    -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  or     %ebx,%eax
  mov    %eax,-0x18(%rbp)
  addq   $0x1,-0x28(%rbp)
L11:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int str_to_int_u(unsigned char *s) {
  unsigned int temp = 0;
  int loop = 4;
  while (loop--) {
    temp = (temp << 8) | (toupper(*s));
    if (*s)
      s++;
  }
  while (*s) {
    temp = (temp << 8) | (toupper(*s));
    s++;
  }
  return (temp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_to_int_u>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x4,%r12d
  mov    $0x0,%ebx
L20:
  shl    $0x8,%ebx
  movzbl 0x0(%rbp),%edi
  call   <toupper@plt>
  or     %eax,%ebx
  cmpb   $0x1,0x0(%rbp)
  sbb    $0xffffffffffffffff,%rbp
  sub    $0x1,%r12d
  jne    L20
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L29
L26:
  shl    $0x8,%ebx
  movzbl %dil,%edi
  call   <toupper@plt>
  or     %eax,%ebx
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L26
L29:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int str_to_int_u(unsigned char *s) {
  unsigned int temp = 0;
  int loop = 4;
  while (loop--) {
    temp = (temp << 8) | (toupper(*s));
    if (*s)
      s++;
  }
  while (*s) {
    temp = (temp << 8) | (toupper(*s));
    s++;
  }
  return (temp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_to_int_u>:
  endbr64
  push   %r12
  mov    $0x4,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%edi
  xor    %ebx,%ebx
L15:
  call   <toupper@plt>
  movzbl 0x0(%rbp),%edi
  shl    $0x8,%ebx
  or     %eax,%ebx
  test   %dil,%dil
  je     L24
  movzbl 0x1(%rbp),%edi
  add    $0x1,%rbp
L24:
  sub    $0x1,%r12d
  jne    L15
  test   %dil,%dil
  je     L33
  nopl   0x0(%rax)
L7:
  call   <toupper@plt>
  movzbl 0x1(%rbp),%edi
  shl    $0x8,%ebx
  add    $0x1,%rbp
  or     %eax,%ebx
  test   %dil,%dil
  jne    L7
L33:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int str_to_int_u(unsigned char *s) {
  unsigned int temp = 0;
  int loop = 4;
  while (loop--) {
    temp = (temp << 8) | (toupper(*s));
    if (*s)
      s++;
  }
  while (*s) {
    temp = (temp << 8) | (toupper(*s));
    s++;
  }
  return (temp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_to_int_u>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x4,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
L24:
  call   <toupper@plt>
  movzbl 0x0(%r13),%edi
  shl    $0x8,%ebx
  or     %eax,%ebx
  test   %dil,%dil
  je     L18
  movzbl 0x1(%r13),%edi
  lea    0x1(%r13),%rbp
  sub    $0x1,%r12d
  je     L23
  mov    %rbp,%r13
  jmp    L24
  nopl   0x0(%rax)
L39:
  call   <toupper@plt>
  shl    $0x8,%ebx
  movzbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  or     %eax,%ebx
L23:
  test   %dil,%dil
  jne    L39
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L18:
  sub    $0x1,%r12d
  jne    L24
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int str_to_int_u(unsigned char *s) {
  unsigned int temp = 0;
  int loop = 4;
  while (loop--) {
    temp = (temp << 8) | (toupper(*s));
    if (*s)
      s++;
  }
  while (*s) {
    temp = (temp << 8) | (toupper(*s));
    s++;
  }
  return (temp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xce4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  mov    $0xce4,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Util_Zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void Util_Zero(void *buf, size_t bufSize) {
  if (buf != ((void *)0)) {
    memset(buf, 0, bufSize);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Util_Zero>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
void Util_Zero(void *buf, size_t bufSize) {
  if (buf != ((void *)0)) {
    memset(buf, 0, bufSize);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Util_Zero>:
  endbr64
  mov    %rsi,%rdx
  test   %rdi,%rdi
  je     L7
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void Util_Zero(void *buf, size_t bufSize) {
  if (buf != ((void *)0)) {
    memset(buf, 0, bufSize);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Util_Zero>:
  endbr64
  mov    %rsi,%rdx
  test   %rdi,%rdi
  je     L9
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void Util_Zero(void *buf, size_t bufSize) {
  if (buf != ((void *)0)) {
    memset(buf, 0, bufSize);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sim_trim_endspc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L11:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L25:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L2
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L11
L2:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *sim_trim_endspc(char *cptr) {
  char *tptr;
  tptr = cptr + strlen(cptr);
  while ((--tptr >= cptr) && isspace(*tptr))
    *tptr = 0;
  return cptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<sim_trim_endspc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  ja     L20
L3:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L20
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jbe    L3
L20:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *sim_trim_endspc(char *cptr) {
  char *tptr;
  tptr = cptr + strlen(cptr);
  while ((--tptr >= cptr) && isspace(*tptr))
    *tptr = 0;
  return cptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sim_trim_endspc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jbe    L17
  jmp    L5
  nopl   0x0(%rax)
L8:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  ja     L5
L17:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *sim_trim_endspc(char *cptr) {
  char *tptr;
  tptr = cptr + strlen(cptr);
  while ((--tptr >= cptr) && isspace(*tptr))
    *tptr = 0;
  return cptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sim_trim_endspc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jbe    L38
  jmp    L6
  nopl   0x0(%rax)
L22:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  ja     L6
L38:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L22
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *sim_trim_endspc(char *cptr) {
  char *tptr;
  tptr = cptr + strlen(cptr);
  while ((--tptr >= cptr) && isspace(*tptr))
    *tptr = 0;
  return cptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__rk_allreduce_alg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__rk_allreduce_alg_v@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: f64

tool: D4: 1.1

assistant: ```c
int __rk_allreduce_alg(void *context) {
  double v = 1.1;
  struct cc_context *ctx = context;
  __rk_allreduce_alg_v(ctx, &v);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__rk_allreduce_alg>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rsi
  call   <__rk_allreduce_alg_v@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: f64

tool: D3: 1.1

assistant: ```c
int __rk_allreduce_alg(void *context) {
  double v = 1.1;
  struct cc_context *ctx = context;
  __rk_allreduce_alg_v(ctx, &v);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__rk_allreduce_alg>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  call   <__rk_allreduce_alg_v@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: f64

tool: D2: 1.1

assistant: ```c
int __rk_allreduce_alg(void *context) {
  double v = 1.1;
  struct cc_context *ctx = context;
  __rk_allreduce_alg_v(ctx, &v);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__rk_allreduce_alg>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  call   <__rk_allreduce_alg_v@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: f64

tool: D5: 1.1

assistant: ```c
int __rk_allreduce_alg(void *context) {
  double v = 1.1;
  struct cc_context *ctx = context;
  __rk_allreduce_alg_v(ctx, &v);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xfffffffe,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x5,%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  unsigned x = -2;
  return x >> (argc + 5);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  lea    0x5(%rdi),%ecx
  mov    $0xfffffffe,%eax
  shr    %cl,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  unsigned x = -2;
  return x >> (argc + 5);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  lea    0x5(%rdi),%ecx
  mov    $0xfffffffe,%eax
  shr    %cl,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  unsigned x = -2;
  return x >> (argc + 5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  lea    0x5(%rdi),%ecx
  mov    $0xfffffffe,%eax
  shr    %cl,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  unsigned x = -2;
  return x >> (argc + 5);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ADC_dato>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x100000a0,%eax
  movw   $0x8010,(%rax)
  mov    $0x0,%eax
  call   <ADC_escribeTxRAM@plt>
  mov    $0x0,%eax
  call   <ADC_escribeCommandRAM@plt>
  mov    $0x100000a8,%eax
  movw   $0x1200,(%rax)
  mov    $0x100000a4,%eax
  movzwl (%rax),%eax
  mov    $0x100000a4,%edx
  or     $0x8000,%ax
  mov    %ax,(%rdx)
  nop
L7:
  mov    $0x100000ac,%eax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L7
  mov    $0x100000ac,%eax
  movzwl (%rax),%eax
  mov    $0x100000ac,%edx
  or     $0x1,%eax
  mov    %ax,(%rdx)
  mov    $0x0,%eax
  call   <ADC_leeRxRAM@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ADC_dato() {
  int datoLeido;
  *((volatile unsigned short *)(0x10000000 + 0x00A0)) = 0x8000 | 66000000 / (2 * 2000000);
  ADC_escribeTxRAM();
  ADC_escribeCommandRAM();
  *((volatile unsigned short *)(0x10000000 + 0x00A8)) = 0x1000 | ((3 - 1) << 8);
  *((volatile unsigned short *)(0x10000000 + 0x00A4)) = *((volatile unsigned short *)(0x10000000 + 0x00A4)) | 0x8000;
  while (!(*((volatile unsigned short *)(0x10000000 + 0x00aC)) & 0x0001)) {
  }
  *((volatile unsigned short *)(0x10000000 + 0x00aC)) = *((volatile unsigned short *)(0x10000000 + 0x00aC)) | 0x0001;
  datoLeido = ADC_leeRxRAM();
  return datoLeido;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ADC_dato>:
  endbr64
  sub    $0x8,%rsp
  movw   $0x8010,0x100000a0
  mov    $0x0,%eax
  call   <ADC_escribeTxRAM@plt>
  mov    $0x0,%eax
  call   <ADC_escribeCommandRAM@plt>
  movw   $0x1200,0x100000a8
  movzwl 0x100000a4,%eax
  or     $0x8000,%ax
  mov    %ax,0x100000a4
L0:
  movzwl 0x100000ac,%eax
  test   $0x1,%al
  je     L0
  movzwl 0x100000ac,%eax
  or     $0x1,%eax
  mov    %ax,0x100000ac
  mov    $0x0,%eax
  call   <ADC_leeRxRAM@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ADC_dato() {
  int datoLeido;
  *((volatile unsigned short *)(0x10000000 + 0x00A0)) = 0x8000 | 66000000 / (2 * 2000000);
  ADC_escribeTxRAM();
  ADC_escribeCommandRAM();
  *((volatile unsigned short *)(0x10000000 + 0x00A8)) = 0x1000 | ((3 - 1) << 8);
  *((volatile unsigned short *)(0x10000000 + 0x00A4)) = *((volatile unsigned short *)(0x10000000 + 0x00A4)) | 0x8000;
  while (!(*((volatile unsigned short *)(0x10000000 + 0x00aC)) & 0x0001)) {
  }
  *((volatile unsigned short *)(0x10000000 + 0x00aC)) = *((volatile unsigned short *)(0x10000000 + 0x00aC)) | 0x0001;
  datoLeido = ADC_leeRxRAM();
  return datoLeido;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ADC_dato>:
  endbr64
  mov    $0xffff8010,%eax
  sub    $0x8,%rsp
  mov    %ax,0x100000a0
  xor    %eax,%eax
  call   <ADC_escribeTxRAM@plt>
  xor    %eax,%eax
  call   <ADC_escribeCommandRAM@plt>
  mov    $0x1200,%edx
  mov    %dx,0x100000a8
  movzwl 0x100000a4,%eax
  or     $0x8000,%ax
  mov    %ax,0x100000a4
  nopl   0x0(%rax)
L8:
  movzwl 0x100000ac,%eax
  test   $0x1,%al
  je     L8
  movzwl 0x100000ac,%eax
  or     $0x1,%eax
  mov    %ax,0x100000ac
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ADC_leeRxRAM@plt>
```

assistant: ```c
int ADC_dato() {
  int datoLeido;
  *((volatile unsigned short *)(0x10000000 + 0x00A0)) = 0x8000 | 66000000 / (2 * 2000000);
  ADC_escribeTxRAM();
  ADC_escribeCommandRAM();
  *((volatile unsigned short *)(0x10000000 + 0x00A8)) = 0x1000 | ((3 - 1) << 8);
  *((volatile unsigned short *)(0x10000000 + 0x00A4)) = *((volatile unsigned short *)(0x10000000 + 0x00A4)) | 0x8000;
  while (!(*((volatile unsigned short *)(0x10000000 + 0x00aC)) & 0x0001)) {
  }
  *((volatile unsigned short *)(0x10000000 + 0x00aC)) = *((volatile unsigned short *)(0x10000000 + 0x00aC)) | 0x0001;
  datoLeido = ADC_leeRxRAM();
  return datoLeido;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ADC_dato>:
  endbr64
  mov    $0xffff8010,%eax
  sub    $0x8,%rsp
  mov    %ax,0x100000a0
  xor    %eax,%eax
  call   <ADC_escribeTxRAM@plt>
  xor    %eax,%eax
  call   <ADC_escribeCommandRAM@plt>
  mov    $0x1200,%edx
  mov    %dx,0x100000a8
  movzwl 0x100000a4,%eax
  or     $0x8000,%ax
  mov    %ax,0x100000a4
  nopl   0x0(%rax)
L6:
  movzwl 0x100000ac,%eax
  test   $0x1,%al
  je     L6
  movzwl 0x100000ac,%eax
  or     $0x1,%eax
  mov    %ax,0x100000ac
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ADC_leeRxRAM@plt>
```

assistant: ```c
int ADC_dato() {
  int datoLeido;
  *((volatile unsigned short *)(0x10000000 + 0x00A0)) = 0x8000 | 66000000 / (2 * 2000000);
  ADC_escribeTxRAM();
  ADC_escribeCommandRAM();
  *((volatile unsigned short *)(0x10000000 + 0x00A8)) = 0x1000 | ((3 - 1) << 8);
  *((volatile unsigned short *)(0x10000000 + 0x00A4)) = *((volatile unsigned short *)(0x10000000 + 0x00A4)) | 0x8000;
  while (!(*((volatile unsigned short *)(0x10000000 + 0x00aC)) & 0x0001)) {
  }
  *((volatile unsigned short *)(0x10000000 + 0x00aC)) = *((volatile unsigned short *)(0x10000000 + 0x00aC)) | 0x0001;
  datoLeido = ADC_leeRxRAM();
  return datoLeido;
}
```
user: Translate the below assembly code into C programming language:

```asm
<handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  mov    %eax,-0xc(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void handler(int signum) {
  int status;
  pid_t pid;
  pid = waitpid(-1, &status, WNOHANG);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<handler>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handler(int signum) {
  int status;
  pid_t pid;
  pid = waitpid(-1, &status, WNOHANG);
}
```