ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  D11(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D9(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D12(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D46
data_type: string
name: disassemble_data
arguments: label: D11
data_type: byte[8]
name: disassemble_data
arguments: label: D9
data_type: byte[8]
name: disassemble_data
arguments: label: D12
data_type: byte[8]
name: disassemble_data
arguments: label: D19
data_type: string

tool: D46: %lf %lf %lf

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D19: MEDIA = %.1lf


assistant: ```c
int main() {
  double a, b, c;
  double media;
  scanf("%lf %lf %lf", &a, &b, &c);
  media = (a * 2 + b * 3 + c * 5) / (2 + 3 + 5);
  printf("MEDIA = %.1lf\n", media);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  D33(%rip),%xmm1
  mulsd  0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  D30(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D19(%rip),%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D43
data_type: string
name: extract_symbolic_data
arguments: label: D33
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D30
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D19
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D15
data_type: string

tool: D43: %lf %lf %lf

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D15: MEDIA = %.1lf


assistant: ```c
int main() {
  double a, b, c;
  double media;
  scanf("%lf %lf %lf", &a, &b, &c);
  media = (a * 2 + b * 3 + c * 5) / (2 + 3 + 5);
  printf("MEDIA = %.1lf\n", media);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D20(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  movsd  D15(%rip),%xmm1
  lea    D35(%rip),%rdi
  mulsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D42(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D17(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D20
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: byte[8]
name: unpack_data
arguments: label: D35
type_guessed: string
name: unpack_data
arguments: label: D42
type_guessed: byte[8]
name: unpack_data
arguments: label: D17
type_guessed: byte[8]

tool: D20: %lf %lf %lf

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D35: MEDIA = %.1lf


tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
int main() {
  double a, b, c;
  double media;
  scanf("%lf %lf %lf", &a, &b, &c);
  media = (a * 2 + b * 3 + c * 5) / (2 + 3 + 5);
  printf("MEDIA = %.1lf\n", media);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D39(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  movsd  D32(%rip),%xmm1
  lea    D49(%rip),%rdi
  mulsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D13(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D37(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D39
data_type: string
name: unpack_data
arguments: tag: D32
data_type: byte[8]
name: unpack_data
arguments: tag: D49
data_type: string
name: unpack_data
arguments: tag: D13
data_type: byte[8]
name: unpack_data
arguments: tag: D37
data_type: byte[8]

tool: D39: %lf %lf %lf

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D49: MEDIA = %.1lf


tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
int main() {
  double a, b, c;
  double media;
  scanf("%lf %lf %lf", &a, &b, &c);
  media = (a * 2 + b * 3 + c * 5) / (2 + 3 + 5);
  printf("MEDIA = %.1lf\n", media);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_fstat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L20
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L19
L20:
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L7
L19:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int _fstat(int file, struct stat *st) {
  if ((STDOUT_FILENO == file) || (STDERR_FILENO == file)) {
    st->st_mode = S_IFCHR;
    return 0;
  } else {
    errno = EBADF;
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_fstat>:
  endbr64
  mov    D46(%rip),%rax
  cmp    %edi,(%rax)
  je     L8
  mov    D9(%rip),%rax
  cmp    %edi,(%rax)
  jne    L6
L8:
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  mov    $0x0,%eax
  ret
L6:
  mov    D38(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fstat(int file, struct stat *st) {
  if ((STDOUT_FILENO == file) || (STDERR_FILENO == file)) {
    st->st_mode = S_IFCHR;
    return 0;
  } else {
    errno = EBADF;
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_fstat>:
  endbr64
  mov    D38(%rip),%rax
  cmp    %edi,(%rax)
  je     L1
  mov    D25(%rip),%rax
  cmp    %edi,(%rax)
  jne    L6
L1:
  mov    D40(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D31(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fstat(int file, struct stat *st) {
  if ((STDOUT_FILENO == file) || (STDERR_FILENO == file)) {
    st->st_mode = S_IFCHR;
    return 0;
  } else {
    errno = EBADF;
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_fstat>:
  endbr64
  mov    D4(%rip),%rax
  cmp    %edi,(%rax)
  je     L15
  mov    D24(%rip),%rax
  cmp    %edi,(%rax)
  jne    L17
L15:
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    D49(%rip),%rax
  mov    (%rax),%edx
  mov    D45(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fstat(int file, struct stat *st) {
  if ((STDOUT_FILENO == file) || (STDERR_FILENO == file)) {
    st->st_mode = S_IFCHR;
    return 0;
  } else {
    errno = EBADF;
    return -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <A@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D5
datatype: string

tool: D26: enter main

tool: D16: &argc=%x
argv=%x
env=%x


tool: D9: &a=%x
%b=%x
&c=%x


tool: D5: exit main

assistant: ```c
main(int argc, char *argv[], char *env[]) {
  int a, b, c;
  printf("enter main\n");
  printf("&argc=%x\nargv=%x\nenv=%x\n", &argc, argv, env);
  printf("&a=%x\n%b=%x\n&c=%x\n", &a, &b, &c);
  a = 1;
  b = 2;
  c = 3;
  A(a, b);
  printf("exit main\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  mov    $0x2,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <A@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D23
type_guessed: string
name: unpack_data
arguments: tag: D4
type_guessed: string
name: unpack_data
arguments: tag: D21
type_guessed: string

tool: D13: enter main

tool: D23: &argc=%x
argv=%x
env=%x


tool: D4: &a=%x
%b=%x
&c=%x


tool: D21: exit main

assistant: ```c
main(int argc, char *argv[], char *env[]) {
  int a, b, c;
  printf("enter main\n");
  printf("&argc=%x\nargv=%x\nenv=%x\n", &argc, argv, env);
  printf("&a=%x\n%b=%x\n&c=%x\n", &a, &b, &c);
  a = 1;
  b = 2;
  c = 3;
  A(a, b);
  printf("exit main\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rcx
  xor    %eax,%eax
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  mov    $0x2,%esi
  movl   $0x1,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  call   <A@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D13
type_guessed: string
name: disassemble_data
arguments: data_label: D21
type_guessed: string
name: disassemble_data
arguments: data_label: D15
type_guessed: string

tool: D24: enter main

tool: D13: &argc=%x
argv=%x
env=%x


tool: D21: &a=%x
%b=%x
&c=%x


tool: D15: exit main

assistant: ```c
main(int argc, char *argv[], char *env[]) {
  int a, b, c;
  printf("enter main\n");
  printf("&argc=%x\nargv=%x\nenv=%x\n", &argc, argv, env);
  printf("&a=%x\n%b=%x\n&c=%x\n", &a, &b, &c);
  a = 1;
  b = 2;
  c = 3;
  A(a, b);
  printf("exit main\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rcx
  xor    %eax,%eax
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  mov    $0x2,%esi
  movl   $0x1,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  call   <A@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D11
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D30: enter main

tool: D11: &argc=%x
argv=%x
env=%x


tool: D10: &a=%x
%b=%x
&c=%x


tool: D14: exit main

assistant: ```c
main(int argc, char *argv[], char *env[]) {
  int a, b, c;
  printf("enter main\n");
  printf("&argc=%x\nargv=%x\nenv=%x\n", &argc, argv, env);
  printf("&a=%x\n%b=%x\n&c=%x\n", &a, &b, &c);
  a = 1;
  b = 2;
  c = 3;
  A(a, b);
  printf("exit main\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skip_nonspaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L24
L1:
  addq   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L27
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L1
L27:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skip_nonspaces(char *s) {
  while (*s && !(*s == ' ' || *s == '\t'))
    s++;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_nonspaces>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
L15:
  cmp    $0x20,%dl
  je     L16
  cmp    $0x9,%dl
  je     L16
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L15
L16:
  ret
L14:
  ret
```

assistant: ```c
char *skip_nonspaces(char *s) {
  while (*s && !(*s == ' ' || *s == '\t'))
    s++;
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<skip_nonspaces>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L29
  xchg   %ax,%ax
L6:
  cmp    $0x20,%dl
  je     L11
  cmp    $0x9,%dl
  je     L11
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L6
L11:
  ret
L29:
  ret
```

assistant: ```c
char *skip_nonspaces(char *s) {
  while (*s && !(*s == ' ' || *s == '\t'))
    s++;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skip_nonspaces>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L20
  xchg   %ax,%ax
L4:
  cmp    $0x20,%dl
  je     L21
  cmp    $0x9,%dl
  je     L21
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L4
L21:
  ret
L20:
  ret
```

assistant: ```c
char *skip_nonspaces(char *s) {
  while (*s && !(*s == ' ' || *s == '\t'))
    s++;
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<safe_ssl_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SSL_read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L14
  mov    -0x4(%rbp),%eax
  jmp    L16
L14:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <handle_ssl_error@plt>
L16:
  leave
  ret
```

assistant: ```c
int safe_ssl_read(SSL *ssl, uint8_t *buf, int bufsize) {
  int ret;
  ret = SSL_read(ssl, buf, bufsize);
  if (ret > 0)
    return ret;
  return handle_ssl_error(ssl, ret);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<safe_ssl_read>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <SSL_read@plt>
  test   %eax,%eax
  jle    L5
L7:
  pop    %rbx
  ret
L5:
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <handle_ssl_error@plt>
  jmp    L7
```

assistant: ```c
int safe_ssl_read(SSL *ssl, uint8_t *buf, int bufsize) {
  int ret;
  ret = SSL_read(ssl, buf, bufsize);
  if (ret > 0)
    return ret;
  return handle_ssl_error(ssl, ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<safe_ssl_read>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <SSL_read@plt>
  test   %eax,%eax
  jle    L1
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  jmp    1070 <handle_ssl_error@plt>
```

assistant: ```c
int safe_ssl_read(SSL *ssl, uint8_t *buf, int bufsize) {
  int ret;
  ret = SSL_read(ssl, buf, bufsize);
  if (ret > 0)
    return ret;
  return handle_ssl_error(ssl, ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<safe_ssl_read>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <SSL_read@plt>
  test   %eax,%eax
  jle    L6
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  jmp    1070 <handle_ssl_error@plt>
```

assistant: ```c
int safe_ssl_read(SSL *ssl, uint8_t *buf, int bufsize) {
  int ret;
  ret = SSL_read(ssl, buf, bufsize);
  if (ret > 0)
    return ret;
  return handle_ssl_error(ssl, ret);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <cSnake@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  cSnake();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cSnake@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  cSnake();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cSnake@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  cSnake();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cSnake@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  cSnake();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <strToInt@plt>
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <strToInt@plt>
  add    $0x19,%eax
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <strToInt@plt>
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D54
type_guessed: string
name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D47
type_guessed: string

tool: D29: -245

tool: D54: %i


tool: D25: 100

tool: D47: 13x5

assistant: ```c
int main(void) {
  int strToInt(char string[]);
  printf("%i\n", strToInt("-245"));
  printf("%i\n", strToInt("100") + 25);
  printf("%i\n", strToInt("13x5"));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rdi
  call   <strToInt@plt>
  mov    %eax,%esi
  lea    D30(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <strToInt@plt>
  lea    0x19(%rax),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <strToInt@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D30
type: string
name: parse_data
arguments: label: D39
type: string
name: parse_data
arguments: label: D15
type: string

tool: D8: -245

tool: D30: %i


tool: D39: 100

tool: D15: 13x5

assistant: ```c
int main(void) {
  int strToInt(char string[]);
  printf("%i\n", strToInt("-245"));
  printf("%i\n", strToInt("100") + 25);
  printf("%i\n", strToInt("13x5"));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D36(%rip),%rdi
  lea    D27(%rip),%rbp
  call   <strToInt@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <strToInt@plt>
  mov    %rbp,%rdi
  lea    0x19(%rax),%esi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <strToInt@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D36
type_guessed: string
name: retrieve_data
arguments: tag: D27
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string

tool: D36: -245

tool: D27: %i


tool: D9: 100

tool: D15: 13x5

assistant: ```c
int main(void) {
  int strToInt(char string[]);
  printf("%i\n", strToInt("-245"));
  printf("%i\n", strToInt("100") + 25);
  printf("%i\n", strToInt("13x5"));
  return 0;
}
```