ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<divmodsi4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x1,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L31
L63:
  shlq   -0x28(%rbp)
  shlq   -0x10(%rbp)
L31:
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L29
  cmpq   $0x0,-0x10(%rbp)
  je     L29
  mov    -0x28(%rbp),%rax
  and    $0x80000000,%eax
  test   %rax,%rax
  je     L63
  jmp    L29
L81:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L61
  mov    -0x28(%rbp),%rax
  sub    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  or     %rax,-0x8(%rbp)
L61:
  sarq   -0x10(%rbp)
  shrq   -0x28(%rbp)
L29:
  cmpq   $0x0,-0x10(%rbp)
  jne    L81
  cmpl   $0x0,-0x14(%rbp)
  je     L21
  mov    -0x20(%rbp),%rax
  jmp    L3
L21:
  mov    -0x8(%rbp),%rax
L3:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long divmodsi4(int modwanted, unsigned long num, unsigned long den) {
  long int bit = 1;
  long int res = 0;
  long prevden;
  while (den < num && bit && !(den & (1L << 31))) {
    den <<= 1;
    bit <<= 1;
  }
  while (bit) {
    if (num >= den) {
      num -= den;
      res |= bit;
    }
    bit >>= 1;
    den >>= 1;
  }
  if (modwanted)
    return num;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<divmodsi4>:
  endbr64
  cmp    %rsi,%rdx
  jae    L86
  test   $0x80000000,%edx
  jne    L119
  mov    $0x1,%ecx
L2:
  add    %rdx,%rdx
  add    %rcx,%rcx
  cmp    %rdx,%rsi
  jbe    L22
  test   %rcx,%rcx
  je     L22
  test   $0x80000000,%edx
  je     L2
L15:
  mov    $0x0,%eax
  jmp    L87
L22:
  mov    %rcx,%rax
  test   %rcx,%rcx
  jne    L15
L71:
  test   %edi,%edi
  cmovne %rsi,%rax
  ret
L14:
  shr    %rdx
  sar    %rcx
  je     L71
L87:
  cmp    %rdx,%rsi
  jb     L14
  sub    %rdx,%rsi
  or     %rcx,%rax
  jmp    L14
L86:
  mov    $0x1,%ecx
  jmp    L15
L119:
  mov    $0x1,%ecx
  jmp    L15
```

assistant: ```c
unsigned long divmodsi4(int modwanted, unsigned long num, unsigned long den) {
  long int bit = 1;
  long int res = 0;
  long prevden;
  while (den < num && bit && !(den & (1L << 31))) {
    den <<= 1;
    bit <<= 1;
  }
  while (bit) {
    if (num >= den) {
      num -= den;
      res |= bit;
    }
    bit >>= 1;
    den >>= 1;
  }
  if (modwanted)
    return num;
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<divmodsi4>:
  endbr64
  mov    $0x1,%ecx
  cmp    %rsi,%rdx
  jb     L47
  jmp    L3
L71:
  add    %rdx,%rdx
  add    %rcx,%rcx
  cmp    %rdx,%rsi
  jbe    L33
  test   %rcx,%rcx
  je     L63
L47:
  test   $0x80000000,%edx
  je     L71
L3:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L64:
  cmp    %rdx,%rsi
  jb     L49
  sub    %rdx,%rsi
  or     %rcx,%rax
L49:
  shr    %rdx
  sar    %rcx
  jne    L64
  test   %edi,%edi
  cmovne %rsi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  test   %rcx,%rcx
  jne    L3
L63:
  xor    %eax,%eax
  test   %edi,%edi
  cmovne %rsi,%rax
  ret
```

assistant: ```c
unsigned long divmodsi4(int modwanted, unsigned long num, unsigned long den) {
  long int bit = 1;
  long int res = 0;
  long prevden;
  while (den < num && bit && !(den & (1L << 31))) {
    den <<= 1;
    bit <<= 1;
  }
  while (bit) {
    if (num >= den) {
      num -= den;
      res |= bit;
    }
    bit >>= 1;
    den >>= 1;
  }
  if (modwanted)
    return num;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<divmodsi4>:
  endbr64
  mov    $0x1,%ecx
  cmp    %rsi,%rdx
  jb     L18
  jmp    L55
L65:
  add    %rdx,%rdx
  add    %rcx,%rcx
  cmp    %rdx,%rsi
  jbe    L15
  test   %rcx,%rcx
  je     L49
L18:
  test   $0x80000000,%edx
  je     L65
L55:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    %rsi,%rdx
  ja     L47
  sub    %rdx,%rsi
  or     %rcx,%rax
L47:
  shr    %rdx
  sar    %rcx
  jne    L0
  test   %edi,%edi
  cmovne %rsi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  test   %rcx,%rcx
  jne    L55
L49:
  xor    %eax,%eax
  test   %edi,%edi
  cmovne %rsi,%rax
  ret
```

assistant: ```c
unsigned long divmodsi4(int modwanted, unsigned long num, unsigned long den) {
  long int bit = 1;
  long int res = 0;
  long prevden;
  while (den < num && bit && !(den & (1L << 31))) {
    den <<= 1;
    bit <<= 1;
  }
  while (bit) {
    if (num >= den) {
      num -= den;
      res |= bit;
    }
    bit >>= 1;
    den >>= 1;
  }
  if (modwanted)
    return num;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<etr_side_perimeter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  D4(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: f32

tool: D4: 3

assistant: ```c
float etr_side_perimeter(float perimeter) {
  float side = perimeter / 3;
  return side;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<etr_side_perimeter>:
  endbr64
  divss  D3(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: f32

tool: D3: 3

assistant: ```c
float etr_side_perimeter(float perimeter) {
  float side = perimeter / 3;
  return side;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<etr_side_perimeter>:
  endbr64
  divss  D8(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: f32

tool: D8: 3

assistant: ```c
float etr_side_perimeter(float perimeter) {
  float side = perimeter / 3;
  return side;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<etr_side_perimeter>:
  endbr64
  divss  D0(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: f32

tool: D0: 3

assistant: ```c
float etr_side_perimeter(float perimeter) {
  float side = perimeter / 3;
  return side;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<verifPerm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    -0xc(%rbp),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L10
  mov    $0x1,%eax
  jmp    L29
L10:
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int verifPerm(char *rep) {
  struct stat repStat;
  stat(rep, &repStat);
  if (repStat.st_mode & S_IRUSR)
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<verifPerm>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    D4(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int verifPerm(char *rep) {
  struct stat repStat;
  stat(rep, &repStat);
  if (repStat.st_mode & S_IRUSR)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<verifPerm>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    D6(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int verifPerm(char *rep) {
  struct stat repStat;
  stat(rep, &repStat);
  if (repStat.st_mode & S_IRUSR)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<verifPerm>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    D3(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int verifPerm(char *rep) {
  struct stat repStat;
  stat(rep, &repStat);
  if (repStat.st_mode & S_IRUSR)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vbtree_node_level>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L13:
  addl   $0x1,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int vbtree_node_level(int n) {
  int level = 0;
  while (n % 2 == 0) {
    level++;
    n /= 2;
  }
  return level;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<vbtree_node_level>:
  endbr64
  test   $0x1,%dil
  jne    L12
  mov    $0x0,%edx
L6:
  add    $0x1,%edx
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  mov    %eax,%edi
  test   $0x1,%al
  je     L6
L17:
  mov    %edx,%eax
  ret
L12:
  mov    $0x0,%edx
  jmp    L17
```

assistant: ```c
int vbtree_node_level(int n) {
  int level = 0;
  while (n % 2 == 0) {
    level++;
    n /= 2;
  }
  return level;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vbtree_node_level>:
  endbr64
  xor    %r8d,%r8d
  test   $0x1,%dil
  jne    L2
  nopl   (%rax)
L11:
  mov    %edi,%eax
  add    $0x1,%r8d
  shr    $0x1f,%eax
  add    %edi,%eax
  mov    %eax,%edi
  sar    %edi
  test   $0x2,%al
  je     L11
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int vbtree_node_level(int n) {
  int level = 0;
  while (n % 2 == 0) {
    level++;
    n /= 2;
  }
  return level;
}
```
user: What is the c source code of the assembly code below:

```asm
<vbtree_node_level>:
  endbr64
  xor    %r8d,%r8d
  test   $0x1,%dil
  jne    L19
  nopl   (%rax)
L7:
  mov    %edi,%eax
  add    $0x1,%r8d
  shr    $0x1f,%eax
  add    %edi,%eax
  mov    %eax,%edi
  sar    %edi
  test   $0x2,%al
  je     L7
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int vbtree_node_level(int n) {
  int level = 0;
  while (n % 2 == 0) {
    level++;
    n /= 2;
  }
  return level;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cut_suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ends_with@plt>
  test   %rax,%rax
  je     L0
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    %rax,%rbx
  mov    %rbx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L11
L0:
  mov    $0x0,%eax
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int cut_suffix(char str[], const char suffix[]) {
  if (ends_with(str, suffix)) {
    str[strlen(str) - strlen(suffix)] = '\0';
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cut_suffix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <ends_with@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L16
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    %rax,%r12
  movb   $0x0,(%rbx,%r12,1)
  mov    $0x1,%eax
  jmp    L17
```

assistant: ```c
int cut_suffix(char str[], const char suffix[]) {
  if (ends_with(str, suffix)) {
    str[strlen(str) - strlen(suffix)] = '\0';
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cut_suffix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <ends_with@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L5
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  sub    %rax,%r12
  mov    $0x1,%eax
  movb   $0x0,(%rbx,%r12,1)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cut_suffix(char str[], const char suffix[]) {
  if (ends_with(str, suffix)) {
    str[strlen(str) - strlen(suffix)] = '\0';
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cut_suffix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <ends_with@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L9
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  sub    %rax,%r12
  mov    $0x1,%eax
  movb   $0x0,(%rbx,%r12,1)
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cut_suffix(char str[], const char suffix[]) {
  if (ends_with(str, suffix)) {
    str[strlen(str) - strlen(suffix)] = '\0';
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mktime_utc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <setenv@plt>
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <setenv@plt>
  jmp    L14
L15:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <unsetenv@plt>
L14:
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: TZ

assistant: ```c
time_t mktime_utc(struct tm *tm, const char *tzbuf) {
  char *old_tz = getenv("TZ");
  time_t ret;
  setenv("TZ", tzbuf, 1);
  tzset();
  ret = mktime(tm);
  if (old_tz)
    setenv("TZ", old_tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mktime_utc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  lea    D18(%rip),%r13
  mov    %r13,%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <setenv@plt>
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    %rbp,%rdi
  call   <mktime@plt>
  mov    %eax,%ebp
  test   %rbx,%rbx
  je     L3
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <setenv@plt>
L8:
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  lea    D18(%rip),%rdi
  call   <unsetenv@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: string

tool: D18: TZ

assistant: ```c
time_t mktime_utc(struct tm *tm, const char *tzbuf) {
  char *old_tz = getenv("TZ");
  time_t ret;
  setenv("TZ", tzbuf, 1);
  tzset();
  ret = mktime(tm);
  if (old_tz)
    setenv("TZ", old_tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mktime_utc>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <getenv@plt>
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12,%rdi
  call   <mktime@plt>
  mov    %eax,%r12d
  test   %rbp,%rbp
  je     L1
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <setenv@plt>
L13:
  xor    %eax,%eax
  call   <tzset@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L1:
  mov    %r13,%rdi
  call   <unsetenv@plt>
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: TZ

assistant: ```c
time_t mktime_utc(struct tm *tm, const char *tzbuf) {
  char *old_tz = getenv("TZ");
  time_t ret;
  setenv("TZ", tzbuf, 1);
  tzset();
  ret = mktime(tm);
  if (old_tz)
    setenv("TZ", old_tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mktime_utc>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <getenv@plt>
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12,%rdi
  call   <mktime@plt>
  mov    %eax,%r12d
  test   %rbp,%rbp
  je     L3
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <setenv@plt>
L4:
  xor    %eax,%eax
  call   <tzset@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdi
  call   <unsetenv@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: TZ

assistant: ```c
time_t mktime_utc(struct tm *tm, const char *tzbuf) {
  char *old_tz = getenv("TZ");
  time_t ret;
  setenv("TZ", tzbuf, 1);
  tzset();
  ret = mktime(tm);
  if (old_tz)
    setenv("TZ", old_tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<layer_mixN_backward>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L5:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void layer_mixN_backward(const int N, const int *table, const double *params, const double *delta, double *din) {
  for (int i = 0; i < N; i++) {
    din[table[2 * i]] += delta[table[2 * i + 1]] * params[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<layer_mixN_backward>:
  endbr64
  mov    %rdx,%r10
  test   %edi,%edi
  jle    L6
  mov    %edi,%edi
  mov    $0x0,%eax
L9:
  movslq (%rsi,%rax,8),%rdx
  lea    (%r8,%rdx,8),%rdx
  movslq 0x4(%rsi,%rax,8),%r9
  movsd  (%rcx,%r9,8),%xmm0
  mulsd  (%r10,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L9
L6:
  ret
```

assistant: ```c
void layer_mixN_backward(const int N, const int *table, const double *params, const double *delta, double *din) {
  for (int i = 0; i < N; i++) {
    din[table[2 * i]] += delta[table[2 * i + 1]] * params[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<layer_mixN_backward>:
  endbr64
  mov    %rdx,%r10
  test   %edi,%edi
  jle    L8
  movslq %edi,%rdi
  xor    %eax,%eax
L12:
  movslq (%rsi,%rax,8),%rdx
  movslq 0x4(%rsi,%rax,8),%r9
  lea    (%r8,%rdx,8),%rdx
  movsd  (%rcx,%r9,8),%xmm0
  mulsd  (%r10,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rdi
  jne    L12
L8:
  ret
```

assistant: ```c
void layer_mixN_backward(const int N, const int *table, const double *params, const double *delta, double *din) {
  for (int i = 0; i < N; i++) {
    din[table[2 * i]] += delta[table[2 * i + 1]] * params[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<layer_mixN_backward>:
  endbr64
  mov    %rdx,%r10
  test   %edi,%edi
  jle    L14
  movslq %edi,%rdi
  xor    %eax,%eax
L12:
  movslq (%rsi,%rax,8),%rdx
  movslq 0x4(%rsi,%rax,8),%r9
  lea    (%r8,%rdx,8),%rdx
  movsd  (%rcx,%r9,8),%xmm0
  mulsd  (%r10,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rdi
  jne    L12
L14:
  ret
```

assistant: ```c
void layer_mixN_backward(const int N, const int *table, const double *params, const double *delta, double *din) {
  for (int i = 0; i < N; i++) {
    din[table[2 * i]] += delta[table[2 * i + 1]] * params[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <set_wifi_light@plt>
  mov    $0x1,%edi
  call   <set_wifi_light@plt>
  mov    $0x0,%eax
  call   <get_cpu_utilisation@plt>
L3:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <get_battery_lights@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <set_wifi_light@plt>
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%edi
  call   <set_num_and_caps_lights@plt>
  mov    $0x0,%eax
  call   <update_keyboard_backlight@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L20
  mov    $0x1,%eax
  jmp    L6
L20:
  mov    $0x4,%eax
L6:
  mov    %eax,%edi
  call   <sleep@plt>
  jmp    L3
```

assistant: ```c
int main(void) {
  int battery_lights;
  int urgent;
  set_wifi_light(0);
  set_wifi_light(1);
  get_cpu_utilisation();
  while (1) {
    battery_lights = get_battery_lights(&urgent);
    set_wifi_light(!!(battery_lights & 4));
    set_num_and_caps_lights(battery_lights & 0x3);
    update_keyboard_backlight();
    sleep(urgent ? 1 : 4);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <set_wifi_light@plt>
  mov    $0x1,%edi
  call   <set_wifi_light@plt>
  mov    $0x0,%eax
  call   <get_cpu_utilisation@plt>
  lea    0x4(%rsp),%rbp
L5:
  mov    %rbp,%rdi
  call   <get_battery_lights@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  shr    $0x2,%edi
  and    $0x1,%edi
  call   <set_wifi_light@plt>
  and    $0x3,%ebx
  mov    %ebx,%edi
  call   <set_num_and_caps_lights@plt>
  mov    $0x0,%eax
  call   <update_keyboard_backlight@plt>
  cmpl   $0x1,0x4(%rsp)
  sbb    %edi,%edi
  and    $0x3,%edi
  add    $0x1,%edi
  call   <sleep@plt>
  jmp    L5
```

assistant: ```c
int main(void) {
  int battery_lights;
  int urgent;
  set_wifi_light(0);
  set_wifi_light(1);
  get_cpu_utilisation();
  while (1) {
    battery_lights = get_battery_lights(&urgent);
    set_wifi_light(!!(battery_lights & 4));
    set_num_and_caps_lights(battery_lights & 0x3);
    update_keyboard_backlight();
    sleep(urgent ? 1 : 4);
  }
}
```