ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crStrcpy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L2
  ret
```

assistant: ```c
void crStrcpy(char *dest, const char *src) {
  while ((*dest++ = *src++))
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ts_section>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ts_get_unitstart@plt>
  test   %eax,%eax
  jne    L15
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ts_payload@plt>
  jmp    L4
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ts_payload@plt>
  add    $0x4,%rax
L4:
  leave
  ret
```

assistant: ```c
uint8_t *ts_section(uint8_t *p_ts) {
  if (!ts_get_unitstart(p_ts))
    return ts_payload(p_ts);
  return ts_payload(p_ts) + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ts_section>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ts_get_unitstart@plt>
  test   %eax,%eax
  je     L19
  mov    %rbx,%rdi
  call   <ts_payload@plt>
  add    $0x4,%rax
L14:
  pop    %rbx
  ret
L19:
  mov    %rbx,%rdi
  call   <ts_payload@plt>
  jmp    L14
```

assistant: ```c
uint8_t *ts_section(uint8_t *p_ts) {
  if (!ts_get_unitstart(p_ts))
    return ts_payload(p_ts);
  return ts_payload(p_ts) + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ts_section>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <ts_get_unitstart@plt>
  mov    %rbp,%rdi
  test   %eax,%eax
  je     L5
  call   <ts_payload@plt>
  pop    %rbp
  add    $0x4,%rax
  ret
  nop
L5:
  pop    %rbp
  jmp    1070 <ts_payload@plt>
```

assistant: ```c
uint8_t *ts_section(uint8_t *p_ts) {
  if (!ts_get_unitstart(p_ts))
    return ts_payload(p_ts);
  return ts_payload(p_ts) + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ts_section>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <ts_get_unitstart@plt>
  mov    %rbp,%rdi
  test   %eax,%eax
  je     L5
  call   <ts_payload@plt>
  pop    %rbp
  add    $0x4,%rax
  ret
  nop
L5:
  pop    %rbp
  jmp    1070 <ts_payload@plt>
```

assistant: ```c
uint8_t *ts_section(uint8_t *p_ts) {
  if (!ts_get_unitstart(p_ts))
    return ts_payload(p_ts);
  return ts_payload(p_ts) + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<px_strstrip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <px_strrstrip@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <px_strlstrip@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <px_free@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *px_strstrip(char *string) {
  char *tmp = px_strrstrip(string);
  string = px_strlstrip(tmp);
  px_free(tmp);
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<px_strstrip>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <px_strrstrip@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <px_strlstrip@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <px_free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *px_strstrip(char *string) {
  char *tmp = px_strrstrip(string);
  string = px_strlstrip(tmp);
  px_free(tmp);
  return string;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<px_strstrip>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <px_strrstrip@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <px_strlstrip@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <px_free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *px_strstrip(char *string) {
  char *tmp = px_strrstrip(string);
  string = px_strlstrip(tmp);
  px_free(tmp);
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<px_strstrip>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <px_strrstrip@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <px_strlstrip@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <px_free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *px_strstrip(char *string) {
  char *tmp = px_strrstrip(string);
  string = px_strlstrip(tmp);
  px_free(tmp);
  return string;
}
```
user: What is the c source code of the assembly code below?

```asm
<memchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L37
  mov    -0x8(%rbp),%rax
  jmp    L15
L37:
  addq   $0x1,-0x8(%rbp)
L20:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L14
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  const char *p = (const char *)s;
  while (n--) {
    if (*p == c) {
      return (void *)p;
    }
    p++;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memchr>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L21
  add    %rdi,%rdx
L11:
  movsbl (%rax),%ecx
  cmp    %esi,%ecx
  je     L6
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L11
  mov    $0x0,%eax
  ret
L21:
  mov    $0x0,%eax
L6:
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  const char *p = (const char *)s;
  while (n--) {
    if (*p == c) {
      return (void *)p;
    }
    p++;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memchr>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L17
  add    %rdi,%rdx
  jmp    L5
  nopl   0x0(%rax)
L30:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L17
L5:
  movsbl (%rax),%ecx
  cmp    %esi,%ecx
  jne    L30
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  const char *p = (const char *)s;
  while (n--) {
    if (*p == c) {
      return (void *)p;
    }
    p++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memchr>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L39
  add    %rdi,%rdx
  jmp    L32
  nopl   0x0(%rax)
L21:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L39
L32:
  movsbl (%rax),%ecx
  cmp    %esi,%ecx
  jne    L21
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  const char *p = (const char *)s;
  while (n--) {
    if (*p == c) {
      return (void *)p;
    }
    p++;
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x15120f0c09060300,%rax
  movabs $0x2d2a2724211e1b18,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L20
L3:
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x34(%rbp)
L20:
  cmpl   $0xf,-0x34(%rbp)
  jle    L3
  movl   $0x0,-0x34(%rbp)
  jmp    L52
L17:
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  addl   $0x1,-0x34(%rbp)
L52:
  cmpl   $0xf,-0x34(%rbp)
  jle    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main1() {
  char cb[16] = {0, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45};
  char ca[16];
  int i;
  for (i = 0; i < 16; i++) {
    ca[i] = cb[i];
  }
  for (i = 0; i < 16; i++) {
    if (ca[i] != cb[i])
      abort();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x15120f0c09060300,%rax
  movabs $0x2d2a2724211e1b18,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    $0x0,%eax
L34:
  movzbl (%rsp,%rax,1),%edx
  mov    %dl,0x10(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L34
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L50
L40:
  add    $0x1,%rbx
  cmp    $0x10,%rbx
  je     L26
L50:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %al,0x10(%rsp,%rbx,1)
  je     L40
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L40
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main1() {
  char cb[16] = {0, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45};
  char ca[16];
  int i;
  for (i = 0; i < 16; i++) {
    ca[i] = cb[i];
  }
  for (i = 0; i < 16; i++) {
    if (ca[i] != cb[i])
      abort();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main1>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  push   %rbx
  sub    $0x38,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movaps %xmm0,(%rsp)
  jmp    L14
  nop
L36:
  movzbl (%rsp,%rax,1),%edx
L14:
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L36
  xor    %ebx,%ebx
  xor    %eax,%eax
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%rsp,%rbx,1),%eax
L8:
  cmp    %al,0x0(%rbp,%rbx,1)
  je     L30
  xor    %eax,%eax
  call   <abort@plt>
L30:
  add    $0x1,%rbx
  cmp    $0x10,%rbx
  jne    L2
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: byte[16]

tool: {"D0": [0x00,0x03,0x06,0x09,0x0c,0x0f,0x12,0x15,0x18,0x1b,0x1e,0x21,0x24,0x27,0x2a,0x2d]}

assistant: ```c
int main1() {
  char cb[16] = {0, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45};
  char ca[16];
  int i;
  for (i = 0; i < 16; i++) {
    ca[i] = cb[i];
  }
  for (i = 0; i < 16; i++) {
    if (ca[i] != cb[i])
      abort();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main1>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main1() {
  char cb[16] = {0, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45};
  char ca[16];
  int i;
  for (i = 0; i < 16; i++) {
    ca[i] = cb[i];
  }
  for (i = 0; i < 16; i++) {
    if (ca[i] != cb[i])
      abort();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xb4(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xb4(%rbp),%edx
  lea    -0x60(%rbp),%rcx
  lea    -0xb0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <str_ncmp@plt>
  cmp    $0x1,%eax
  jne    L14
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L14:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string
name: parse_data
arguments: label: D61
data_type: string
name: parse_data
arguments: label: D41
data_type: string
name: parse_data
arguments: label: D39
data_type: string
name: parse_data
arguments: label: D48
data_type: string
name: parse_data
arguments: label: D4
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D0: Input a string 1: 

tool: D61: %s

tool: D41: Input a string 2: 

tool: D39: Number of comparison?: 

tool: D48: %d

tool: D4:  Something different


tool: D8:  Same


assistant: ```c
int main() {
  int n;
  char str1[80];
  char str2[80];
  printf("Input a string 1: ");
  scanf("%s", str1);
  printf("Input a string 2: ");
  scanf("%s", str2);
  printf("Number of comparison?: ");
  scanf("%d", &n);
  if (str_ncmp(str1, str2, n) == 1) {
    printf(" Something different\n");
  } else {
    printf(" Same\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D29(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    0x60(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <str_ncmp@plt>
  cmp    $0x1,%eax
  je     L4
  lea    D53(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D50
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D49
datatype: string
name: extract_symbolic_data
arguments: data_tag: D55
datatype: string
name: extract_symbolic_data
arguments: data_tag: D30
datatype: string
name: extract_symbolic_data
arguments: data_tag: D53
datatype: string
name: extract_symbolic_data
arguments: data_tag: D34
datatype: string

tool: D50: Input a string 1: 

tool: D29: %s

tool: D49: Input a string 2: 

tool: D55: Number of comparison?: 

tool: D30: %d

tool: D53:  Same


tool: D34:  Something different


assistant: ```c
int main() {
  int n;
  char str1[80];
  char str2[80];
  printf("Input a string 1: ");
  scanf("%s", str1);
  printf("Input a string 2: ");
  scanf("%s", str2);
  printf("Number of comparison?: ");
  scanf("%d", &n);
  if (str_ncmp(str1, str2, n) == 1) {
    printf(" Something different\n");
  } else {
    printf(" Same\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%rdi
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x60(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <str_ncmp@plt>
  cmp    $0x1,%eax
  je     L29
  lea    D63(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0xc0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D51
type_infered: string
name: read_data
arguments: data_label: D31
type_infered: string
name: read_data
arguments: data_label: D63
type_infered: string
name: read_data
arguments: data_label: D4
type_infered: string

tool: D14: Input a string 1: 

tool: D12: %s

tool: D24: Input a string 2: 

tool: D51: Number of comparison?: 

tool: D31: %d

tool: D63:  Same


tool: D4:  Something different


assistant: ```c
int main() {
  int n;
  char str1[80];
  char str2[80];
  printf("Input a string 1: ");
  scanf("%s", str1);
  printf("Input a string 2: ");
  scanf("%s", str2);
  printf("Number of comparison?: ");
  scanf("%d", &n);
  if (str_ncmp(str1, str2, n) == 1) {
    printf(" Something different\n");
  } else {
    printf(" Same\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%rdi
  lea    D20(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x60(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <str_ncmp@plt>
  cmp    $0x1,%eax
  je     L20
  lea    D8(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0xc0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_infered: string
name: unpack_data
arguments: data_tag: D20
type_infered: string
name: unpack_data
arguments: data_tag: D34
type_infered: string
name: unpack_data
arguments: data_tag: D18
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D29
type_infered: string

tool: D17: Input a string 1: 

tool: D20: %s

tool: D34: Input a string 2: 

tool: D18: Number of comparison?: 

tool: D1: %d

tool: D8:  Same


tool: D29:  Something different


assistant: ```c
int main() {
  int n;
  char str1[80];
  char str2[80];
  printf("Input a string 1: ");
  scanf("%s", str1);
  printf("Input a string 2: ");
  scanf("%s", str2);
  printf("Number of comparison?: ");
  scanf("%d", &n);
  if (str_ncmp(str1, str2, n) == 1) {
    printf(" Something different\n");
  } else {
    printf(" Same\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<teste_macros>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D74(%rip),%r14
  mov    $0x1,%r13d
  lea    D78(%rip),%r12
L23:
  mov    %ebx,%edi
  call   <mostra_bin@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13d,%eax
  mov    %ebp,%ecx
  shl    %cl,%eax
  or     %eax,%ebx
  mov    %ebx,%edi
  call   <mostra_bin@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    $0x40,%ebp
  jne    L23
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%ebp
  lea    D74(%rip),%r14
  mov    $0x1,%r13d
  lea    D78(%rip),%r12
L27:
  mov    %ebx,%edi
  call   <mostra_bin@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13d,%eax
  mov    %ebp,%ecx
  shl    %cl,%eax
  not    %eax
  and    %eax,%ebx
  mov    %ebx,%edi
  call   <mostra_bin@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    $0x40,%ebp
  jne    L27
  lea    D99(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%ebp
  mov    $0x1,%r15d
  lea    D74(%rip),%r14
  lea    D78(%rip),%r13
L25:
  mov    %r15d,%r12d
  mov    %ebp,%ecx
  shl    %cl,%r12d
  mov    %r12d,%edi
  call   <mostra_bin@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %r12d,%ebx
  mov    %ebx,%edi
  call   <mostra_bin@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    $0x40,%ebp
  jne    L25
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D58
data_type: string
name: unpack_data
arguments: data_label: D46
data_type: string
name: unpack_data
arguments: data_label: D74
data_type: string
name: unpack_data
arguments: data_label: D78
data_type: string
name: unpack_data
arguments: data_label: D47
data_type: string
name: unpack_data
arguments: data_label: D99
data_type: string

tool: D58: :: TESTE DAS MACROS ::


tool: D46: 
Testando a macro set_bit(var,bit): 


tool: D74: 	 -> 	

tool: D78: 


tool: D47: 
Testando a macro clear_bit(var,bit): 


tool: D99: 
Testando a macro cpl_bit(var,bit): 


assistant: ```c
void teste_macros() {
  int i, portC = 0, size = 8 * sizeof(int);
  printf(":: TESTE DAS MACROS ::\n");
  printf("\nTestando a macro set_bit(var,bit): \n");
  getchar();
  for (i = 0; i < 2 * size; i++) {
    mostra_bin(portC);
    printf("\t -> \t");
    mostra_bin(portC |= (1 << i));
    printf("\n");
  }
  printf("\nTestando a macro clear_bit(var,bit): \n");
  getchar();
  for (i = 0; i < 2 * size; i++) {
    mostra_bin(portC);
    printf("\t -> \t");
    mostra_bin(portC &= ~(1 << i));
    printf("\n");
  }
  printf("\nTestando a macro cpl_bit(var,bit): \n");
  getchar();
  for (i = 0; i < 2 * size; i++) {
    mostra_bin(1 << i);
    printf("\t -> \t");
    mostra_bin(portC ^= (1 << i));
    printf("\n");
  }
}
```