ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<binstrstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L29
L30:
  cmpq   $0x0,-0x28(%rbp)
  jne    L76
  mov    $0x0,%eax
  jmp    L29
L76:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jae    L62
  mov    $0x0,%eax
  jmp    L29
L62:
  movq   $0x0,-0x8(%rbp)
  jmp    L63
L91:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L97
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  jmp    L29
L97:
  addq   $0x1,-0x8(%rbp)
L63:
  mov    -0x20(%rbp),%rax
  sub    -0x30(%rbp),%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L91
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
char *binstrstr(const char *haystack, size_t hsize, const char *needle, size_t nsize) {
  size_t p;
  if (haystack == NULL)
    return NULL;
  if (needle == NULL)
    return NULL;
  if (hsize < nsize)
    return NULL;
  for (p = 0; p <= (hsize - nsize); ++p) {
    if (memcmp(haystack + p, needle, nsize) == 0) {
      return (char *)(haystack + p);
    }
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binstrstr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r14
  test   %rdx,%rdx
  sete   %al
  cmp    %rcx,%rsi
  setb   %dl
  or     %dl,%al
  jne    L36
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %rcx,%r13
  test   %rdi,%rdi
  je     L36
  sub    %rcx,%r12
  mov    $0x0,%ebx
L47:
  lea    (%r15,%rbx,1),%rbp
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L29
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jbe    L47
  mov    $0x0,%ebp
L29:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    $0x0,%ebp
  jmp    L29
```

assistant: ```c
char *binstrstr(const char *haystack, size_t hsize, const char *needle, size_t nsize) {
  size_t p;
  if (haystack == NULL)
    return NULL;
  if (needle == NULL)
    return NULL;
  if (hsize < nsize)
    return NULL;
  for (p = 0; p <= (hsize - nsize); ++p) {
    if (memcmp(haystack + p, needle, nsize) == 0) {
      return (char *)(haystack + p);
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<binstrstr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  sete   %al
  cmp    %rcx,%rsi
  setb   %dl
  or     %dl,%al
  jne    L55
  mov    %rdi,%r14
  test   %rdi,%rdi
  je     L55
  mov    %rsi,%rbp
  mov    %rcx,%r15
  xor    %ebx,%ebx
  sub    %rcx,%rbp
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  ja     L55
L42:
  lea    (%r14,%rbx,1),%r12
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L11
L50:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  xor    %r12d,%r12d
  jmp    L50
```

assistant: ```c
char *binstrstr(const char *haystack, size_t hsize, const char *needle, size_t nsize) {
  size_t p;
  if (haystack == NULL)
    return NULL;
  if (needle == NULL)
    return NULL;
  if (hsize < nsize)
    return NULL;
  for (p = 0; p <= (hsize - nsize); ++p) {
    if (memcmp(haystack + p, needle, nsize) == 0) {
      return (char *)(haystack + p);
    }
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binstrstr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  sete   %al
  cmp    %rcx,%rsi
  setb   %dl
  or     %dl,%al
  jne    L1
  mov    %rdi,%r14
  test   %rdi,%rdi
  je     L1
  mov    %rsi,%rbp
  mov    %rcx,%r15
  xor    %ebx,%ebx
  sub    %rcx,%rbp
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  ja     L1
L3:
  lea    (%r14,%rbx,1),%r12
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L45
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r12d,%r12d
  jmp    L16
```

assistant: ```c
char *binstrstr(const char *haystack, size_t hsize, const char *needle, size_t nsize) {
  size_t p;
  if (haystack == NULL)
    return NULL;
  if (needle == NULL)
    return NULL;
  if (hsize < nsize)
    return NULL;
  for (p = 0; p <= (hsize - nsize); ++p) {
    if (memcmp(haystack + p, needle, nsize) == 0) {
      return (char *)(haystack + p);
    }
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rcx
  mov    %rcx,%rax
  xor    $0x29be1cdb,%rax
  mov    %rax,%rdx
  cmp    $0x29be1cdb,%rcx
  je     L2
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  mov    %rax,%rdx
L2:
  and    $0x1603b040,%edx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        state[local1] = state[0UL] << (((state[0UL] >> 2UL) & 7UL) | 1UL);
        state[0UL] = state[local1] >> (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy12 = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = copy12;
        copy12 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 387166272UL) & 913307615UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movabs $0xffffffff00000000,%rdx
  mov    (%rdi),%rcx
  mov    %rcx,%rax
  xor    $0x29be1cdb,%rax
  and    %rax,%rdx
  cmp    $0x29be1cdb,%rcx
  je     L5
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  mov    %rax,%rdx
L5:
  and    $0x1603b040,%edx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        state[local1] = state[0UL] << (((state[0UL] >> 2UL) & 7UL) | 1UL);
        state[0UL] = state[local1] >> (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy12 = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = copy12;
        copy12 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 387166272UL) & 913307615UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movabs $0xffffffff00000000,%rdx
  mov    (%rdi),%rcx
  mov    %rcx,%rax
  xor    $0x29be1cdb,%rax
  and    %rax,%rdx
  cmp    $0x29be1cdb,%rcx
  je     L7
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  mov    %rax,%rdx
L7:
  and    $0x1603b040,%edx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        state[local1] = state[0UL] << (((state[0UL] >> 2UL) & 7UL) | 1UL);
        state[0UL] = state[local1] >> (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy12 = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = copy12;
        copy12 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 387166272UL) & 913307615UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  jmp    L113
L30:
  addl   $0x1,-0xc(%rbp)
L113:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L30
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L11:
  addl   $0x1,-0xc(%rbp)
L41:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L11
  movl   $0x0,-0xc(%rbp)
  jmp    L64
L49:
  movl   $0x0,-0x8(%rbp)
  jmp    L70
L94:
  addl   $0x1,-0x8(%rbp)
L70:
  cmpl   $0x3f,-0x8(%rbp)
  jle    L94
  addl   $0x1,-0xc(%rbp)
L64:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L49
  movl   $0x0,-0xc(%rbp)
  jmp    L118
L92:
  movl   $0x0,-0x8(%rbp)
  jmp    L167
L90:
  movl   $0x0,-0x4(%rbp)
  jmp    L51
L16:
  addl   $0x1,-0x4(%rbp)
L51:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L16
  addl   $0x1,-0x8(%rbp)
L167:
  cmpl   $0x3f,-0x8(%rbp)
  jle    L90
  addl   $0x1,-0xc(%rbp)
L118:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L92
  movl   $0x0,-0xc(%rbp)
  jmp    L129
L126:
  addl   $0x1,-0xc(%rbp)
L129:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L126
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L26:
  addl   $0x1,-0xc(%rbp)
L32:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(void) {
  int i, j, k;
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
  }
#pragma omp for ordered(1) collapse(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
  }
#pragma omp for collapse(2) ordered(1)
  for (i = 0; i < 64; i++)
    for (j = 0; j < 64; j++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
    }
#pragma omp for ordered(2) collapse(3)
  for (i = 0; i < 64; i++)
    for (j = 0; j < 64; j++)
      for (k = 0; k < 64; k++) {
#pragma omp ordered depend(sink : i - 1, j - 2)
#pragma omp ordered depend(source)
      }
#pragma omp ordered depend(sink : j)
#pragma omp ordered depend(source)
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1) depend(sink : i - 2)
#pragma omp ordered depend(source) depend(source)
  }
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1) depend(source) depend(sink : i - 2)
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  mov    $0x40,%eax
L35:
  sub    $0x1,%eax
  jne    L35
  mov    $0x40,%eax
L64:
  sub    $0x1,%eax
  jne    L64
  mov    $0x40,%edx
L57:
  mov    $0x40,%eax
L58:
  sub    $0x1,%eax
  jne    L58
  sub    $0x1,%edx
  jne    L57
  mov    $0x40,%ecx
L52:
  mov    $0x40,%edx
L63:
  mov    $0x40,%eax
L27:
  sub    $0x1,%eax
  jne    L27
  sub    $0x1,%edx
  jne    L63
  sub    $0x1,%ecx
  jne    L52
  mov    $0x40,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  mov    $0x40,%eax
L81:
  sub    $0x1,%eax
  jne    L81
  ret
```

assistant: ```c
void foo(void) {
  int i, j, k;
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
  }
#pragma omp for ordered(1) collapse(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
  }
#pragma omp for collapse(2) ordered(1)
  for (i = 0; i < 64; i++)
    for (j = 0; j < 64; j++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
    }
#pragma omp for ordered(2) collapse(3)
  for (i = 0; i < 64; i++)
    for (j = 0; j < 64; j++)
      for (k = 0; k < 64; k++) {
#pragma omp ordered depend(sink : i - 1, j - 2)
#pragma omp ordered depend(source)
      }
#pragma omp ordered depend(sink : j)
#pragma omp ordered depend(source)
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1) depend(sink : i - 2)
#pragma omp ordered depend(source) depend(source)
  }
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1) depend(source) depend(sink : i - 2)
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  int i, j, k;
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
  }
#pragma omp for ordered(1) collapse(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
  }
#pragma omp for collapse(2) ordered(1)
  for (i = 0; i < 64; i++)
    for (j = 0; j < 64; j++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
    }
#pragma omp for ordered(2) collapse(3)
  for (i = 0; i < 64; i++)
    for (j = 0; j < 64; j++)
      for (k = 0; k < 64; k++) {
#pragma omp ordered depend(sink : i - 1, j - 2)
#pragma omp ordered depend(source)
      }
#pragma omp ordered depend(sink : j)
#pragma omp ordered depend(source)
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1) depend(sink : i - 2)
#pragma omp ordered depend(source) depend(source)
  }
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1) depend(source) depend(sink : i - 2)
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  int i, j, k;
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
  }
#pragma omp for ordered(1) collapse(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
  }
#pragma omp for collapse(2) ordered(1)
  for (i = 0; i < 64; i++)
    for (j = 0; j < 64; j++) {
#pragma omp ordered depend(sink : i - 1)
#pragma omp ordered depend(source)
    }
#pragma omp for ordered(2) collapse(3)
  for (i = 0; i < 64; i++)
    for (j = 0; j < 64; j++)
      for (k = 0; k < 64; k++) {
#pragma omp ordered depend(sink : i - 1, j - 2)
#pragma omp ordered depend(source)
      }
#pragma omp ordered depend(sink : j)
#pragma omp ordered depend(source)
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1) depend(sink : i - 2)
#pragma omp ordered depend(source) depend(source)
  }
#pragma omp for ordered(1)
  for (i = 0; i < 64; i++) {
#pragma omp ordered depend(sink : i - 1) depend(source) depend(sink : i - 2)
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strntoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L7:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L13:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L17
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L17:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x40(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int strntoul(const char *str, int length, int base) {
  char buf[length + 1];
  memcpy(buf, str, length);
  buf[length] = '\0';
  return strtoul(buf, NULL, base);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strntoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L16:
  cmp    %rdx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L16
L15:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L7
  orq    $0x0,-0x8(%rsp,%rax,1)
L7:
  mov    %ebx,%edx
  mov    %rdi,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  mov    %r12d,%edx
  mov    $0x0,%esi
  mov    %rsp,%rdi
  call   <strtoul@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int strntoul(const char *str, int length, int base) {
  char buf[length + 1];
  memcpy(buf, str, length);
  buf[length] = '\0';
  return strtoul(buf, NULL, base);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strntoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %edx,%r12d
  push   %rbx
  movslq %esi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rbx),%eax
  mov    %rsp,%rcx
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L41
L11:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L11
L41:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L25
L7:
  mov    %rdi,%rsi
  mov    %ebx,%edx
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <strtoul@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  xchg   %ax,%ax
L25:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L7
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int strntoul(const char *str, int length, int base) {
  char buf[length + 1];
  memcpy(buf, str, length);
  buf[length] = '\0';
  return strtoul(buf, NULL, base);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strntoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %edx,%r12d
  push   %rbx
  movslq %esi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rbx),%eax
  mov    %rsp,%rcx
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L15
L8:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L8
L15:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L42
L7:
  mov    %rdi,%rsi
  mov    %ebx,%edx
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <strtoul@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  xchg   %ax,%ax
L42:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L7
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int strntoul(const char *str, int length, int base) {
  char buf[length + 1];
  memcpy(buf, str, length);
  buf[length] = '\0';
  return strtoul(buf, NULL, base);
}
```
user: What is the c source code of the assembly code below?

```asm
<numUpper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L19
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L19
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int numUpper(char ch, int count) {
  int tempCount = count;
  if (isalpha(ch) && isupper(ch)) {
    tempCount++;
  }
  return tempCount;
}
```
user: What is the c source code of the assembly code below:

```asm
<numUpper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L2
L5:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    %ebp,%edi
  call   <isupper@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebx
  jmp    L5
```

assistant: ```c
int numUpper(char ch, int count) {
  int tempCount = count;
  if (isalpha(ch) && isupper(ch)) {
    tempCount++;
  }
  return tempCount;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numUpper>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L8
L7:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L8:
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L7
  add    $0x8,%rsp
  lea    0x1(%rbx),%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int numUpper(char ch, int count) {
  int tempCount = count;
  if (isalpha(ch) && isupper(ch)) {
    tempCount++;
  }
  return tempCount;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numUpper>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L3
L1:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  lea    0x1(%rbx),%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int numUpper(char ch, int count) {
  int tempCount = count;
  if (isalpha(ch) && isupper(ch)) {
    tempCount++;
  }
  return tempCount;
}
```