user: 这段汇编代码用C语言表示是什么样的：

```asm
<hexDump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <log_debug@plt>
  test   %ebp,%ebp
  je     L63
  js     L52
  movslq %ebp,%rax
  xor    %r14d,%r14d
  lea    D33(%rip),%r13
  mov    %rax,(%rsp)
  lea    0x10(%rsp),%rax
  lea    D20(%rip),%r15
  mov    %rax,0x8(%rsp)
  jmp    L125
  nopl   0x0(%rax,%rax,1)
L112:
  movslq %ebx,%rcx
  mov    %al,0x10(%rsp,%rcx,1)
L48:
  add    $0x1,%ebx
  add    $0x1,%r14
  movslq %ebx,%rbx
  movb   $0x0,0x10(%rsp,%rbx,1)
  cmp    (%rsp),%r14
  je     L119
L125:
  mov    %r14d,%ebx
  test   $0xf,%r14b
  jne    L35
  test   %r14,%r14
  je     L38
  mov    0x8(%rsp),%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <log_debug@plt>
L38:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <log_debug@plt>
L35:
  movzbl (%r12,%r14,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  and    $0xf,%ebx
  call   <log_debug@plt>
  movzbl (%r12,%r14,1),%eax
  lea    -0x20(%rax),%ecx
  cmp    $0x5e,%cl
  jbe    L112
  movslq %ebx,%rax
  movb   $0x2e,0x10(%rsp,%rax,1)
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L119:
  lea    D18(%rip),%rbx
  test   $0xf,%bpl
  je     L21
  nopl   (%rax)
L54:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <log_debug@plt>
  test   $0xf,%bpl
  jne    L54
L21:
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <log_debug@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L63:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x38,%rsp
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <log_debug@plt>
  nopl   0x0(%rax)
L52:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x38,%rsp
  mov    %ebp,%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <log_debug@plt>
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string
name: disassemble_data
arguments: tag: D33
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D4
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D47
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string

tool: D8: hexDump %p:


tool: D33:  %02x

tool: D20:   %04x 

tool: D4:   %s


tool: D18:    

tool: D47:   ZERO LENGTH


tool: D23:   NEGATIVE LENGTH: %i


assistant: ```c
void hexDump(void *addr, int len) {
  int i;
  unsigned char buff[17];
  unsigned char *pc = (unsigned char *)addr;
  (void)buff;
  log_debug("hexDump %p:\n", addr);
  if (len == 0) {
    log_debug("  ZERO LENGTH\n");
    return;
  }
  if (len < 0) {
    log_debug("  NEGATIVE LENGTH: %i\n", len);
    return;
  }
  for (i = 0; i < len; i++) {
    if ((i % 16) == 0) {
      if (i != 0) {
        log_debug("  %s\n", buff);
      }
      log_debug("  %04x ", i);
    }
    log_debug(" %02x", pc[i]);
    if ((pc[i] < 0x20) || (pc[i] > 0x7e)) {
      buff[i % 16] = '.';
    } else {
      buff[i % 16] = pc[i];
    }
    buff[(i % 16) + 1] = '\0';
  }
  while ((i % 16) != 0) {
    log_debug("   ");
    i++;
  }
  log_debug("  %s\n", buff);
}
```