ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<afficherGagnantPuissance4Solo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <gagnerPuissance4@plt>
  cmp    $0x5,%eax
  je     L70
  cmp    $0x5,%eax
  jg     L61
  cmp    $0x4,%eax
  je     L95
  cmp    $0x4,%eax
  jg     L61
  test   %eax,%eax
  je     L48
  cmp    $0x3,%eax
  jne    L61
L70:
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <coloration@plt>
  jmp    L61
L95:
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <coloration@plt>
  movl   $0x19,-0x8(%rbp)
  cmpl   $0x8,-0x14(%rbp)
  jg     L83
  cmpl   $0x3,-0x1c(%rbp)
  jne    L83
  movl   $0x1,-0x4(%rbp)
  jmp    L83
L48:
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <afficherPuissance4@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x5,-0x8(%rbp)
  jmp    L61
L83:
  nop
L61:
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <systemePoints@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D62
type: string
name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D69
type: string
name: disassemble_data
arguments: data_label: D18
type: string
name: disassemble_data
arguments: data_label: D54
type: string
name: disassemble_data
arguments: data_label: D48
type: string
name: disassemble_data
arguments: data_label: D47
type: string

tool: D62: 


tool: D5: 31

tool: D69: Dommage ! Vous avez perdu.


tool: D18: 32

tool: D54: Bravo ! Vous avez gagne.


tool: D48: clear

tool: D47: 
Match nul !


assistant: ```c
void afficherGagnantPuissance4Solo(int nbCoups, int modeDeJeux, int niveauDifficulte) {
  int nbPointsGagnes, nbPointsVIP;
  nbPointsGagnes = nbPointsVIP = 0;
  printf("\n");
  switch (gagnerPuissance4(1)) {
  case 3:
  case 3 + 2:
    coloration("Dommage ! Vous avez perdu.\n", "31");
    break;
  case 3 + 1:
    coloration("Bravo ! Vous avez gagne.\n", "32");
    nbPointsGagnes = 25;
    if (nbCoups <= 8 && niveauDifficulte == 3)
      nbPointsVIP = 1;
    break;
  case 0:
    system("clear");
    afficherPuissance4();
    printf("\nMatch nul !\n");
    nbPointsGagnes = 5;
    break;
  }
  nbPointsGagnes *= niveauDifficulte;
  systemePoints(nbPointsGagnes, nbPointsVIP, modeDeJeux);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<afficherGagnantPuissance4Solo>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %edx,%ebp
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <gagnerPuissance4@plt>
  cmp    $0x4,%eax
  je     L0
  mov    %eax,%ebx
  jg     L48
  test   %eax,%eax
  je     L63
  cmp    $0x3,%eax
  jne    L34
L72:
  lea    D50(%rip),%rsi
  lea    D59(%rip),%rdi
  call   <coloration@plt>
  mov    $0x0,%ebx
  mov    $0x0,%edi
  jmp    L89
L34:
  mov    $0x0,%ebx
  mov    $0x0,%edi
  jmp    L89
L48:
  cmp    $0x5,%eax
  je     L72
  mov    $0x0,%ebx
  mov    $0x0,%edi
L89:
  imul   %ebp,%edi
  mov    %r12d,%edx
  mov    %ebx,%esi
  call   <systemePoints@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  lea    D24(%rip),%rsi
  lea    D42(%rip),%rdi
  call   <coloration@plt>
  cmp    $0x8,%r13d
  setle  %al
  cmp    $0x3,%ebp
  sete   %bl
  movzbl %bl,%ebx
  and    %eax,%ebx
  mov    $0x19,%edi
  jmp    L89
L63:
  lea    D44(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <afficherPuissance4@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  jmp    L89
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
type_infered: string
name: extract_symbolic_data
arguments: tag: D50
type_infered: string
name: extract_symbolic_data
arguments: tag: D59
type_infered: string
name: extract_symbolic_data
arguments: tag: D24
type_infered: string
name: extract_symbolic_data
arguments: tag: D42
type_infered: string
name: extract_symbolic_data
arguments: tag: D44
type_infered: string
name: extract_symbolic_data
arguments: tag: D18
type_infered: string

tool: D20: 


tool: D50: 31

tool: D59: Dommage ! Vous avez perdu.


tool: D24: 32

tool: D42: Bravo ! Vous avez gagne.


tool: D44: clear

tool: D18: 
Match nul !


assistant: ```c
void afficherGagnantPuissance4Solo(int nbCoups, int modeDeJeux, int niveauDifficulte) {
  int nbPointsGagnes, nbPointsVIP;
  nbPointsGagnes = nbPointsVIP = 0;
  printf("\n");
  switch (gagnerPuissance4(1)) {
  case 3:
  case 3 + 2:
    coloration("Dommage ! Vous avez perdu.\n", "31");
    break;
  case 3 + 1:
    coloration("Bravo ! Vous avez gagne.\n", "32");
    nbPointsGagnes = 25;
    if (nbCoups <= 8 && niveauDifficulte == 3)
      nbPointsVIP = 1;
    break;
  case 0:
    system("clear");
    afficherPuissance4();
    printf("\nMatch nul !\n");
    nbPointsGagnes = 5;
    break;
  }
  nbPointsGagnes *= niveauDifficulte;
  systemePoints(nbPointsGagnes, nbPointsVIP, modeDeJeux);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<afficherGagnantPuissance4Solo>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D53(%rip),%rdi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x10,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  call   <gagnerPuissance4@plt>
  cmp    $0x4,%eax
  je     L7
  jg     L19
  test   %eax,%eax
  jne    L26
  lea    D32(%rip),%rdi
  mov    %eax,0xc(%rsp)
  call   <system@plt>
  xor    %eax,%eax
  call   <afficherPuissance4@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  add    $0x10,%rsp
  lea    (%rbx,%rbx,4),%edi
  mov    %r12d,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10f0 <systemePoints@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  cmp    $0x3,%eax
  jne    L38
L43:
  lea    D37(%rip),%rsi
  lea    D5(%rip),%rdi
  call   <coloration@plt>
  add    $0x10,%rsp
  mov    %r12d,%edx
  xor    %edi,%edi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  jmp    10f0 <systemePoints@plt>
  nopl   0x0(%rax)
L19:
  cmp    $0x5,%eax
  je     L43
L38:
  add    $0x10,%rsp
  mov    %r12d,%edx
  xor    %edi,%edi
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10f0 <systemePoints@plt>
  nopl   0x0(%rax)
L7:
  lea    D19(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <coloration@plt>
  cmp    $0x8,%ebp
  mov    %r12d,%edx
  setle  %al
  xor    %esi,%esi
  cmp    $0x3,%ebx
  sete   %sil
  add    $0x10,%rsp
  and    %eax,%esi
  lea    (%rbx,%rbx,4),%eax
  pop    %rbx
  pop    %rbp
  lea    (%rax,%rax,4),%edi
  pop    %r12
  jmp    10f0 <systemePoints@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D53
type_infered: string
name: retrieve_data
arguments: data_label: D32
type_infered: string
name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D37
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D19
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string

tool: D53: 


tool: D32: clear

tool: D7: 
Match nul !


tool: D37: 31

tool: D5: Dommage ! Vous avez perdu.


tool: D19: 32

tool: D15: Bravo ! Vous avez gagne.


assistant: ```c
void afficherGagnantPuissance4Solo(int nbCoups, int modeDeJeux, int niveauDifficulte) {
  int nbPointsGagnes, nbPointsVIP;
  nbPointsGagnes = nbPointsVIP = 0;
  printf("\n");
  switch (gagnerPuissance4(1)) {
  case 3:
  case 3 + 2:
    coloration("Dommage ! Vous avez perdu.\n", "31");
    break;
  case 3 + 1:
    coloration("Bravo ! Vous avez gagne.\n", "32");
    nbPointsGagnes = 25;
    if (nbCoups <= 8 && niveauDifficulte == 3)
      nbPointsVIP = 1;
    break;
  case 0:
    system("clear");
    afficherPuissance4();
    printf("\nMatch nul !\n");
    nbPointsGagnes = 5;
    break;
  }
  nbPointsGagnes *= niveauDifficulte;
  systemePoints(nbPointsGagnes, nbPointsVIP, modeDeJeux);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<afficherGagnantPuissance4Solo>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D64(%rip),%rdi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x10,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  call   <gagnerPuissance4@plt>
  cmp    $0x4,%eax
  je     L43
  jg     L24
  test   %eax,%eax
  jne    L30
  lea    D63(%rip),%rdi
  mov    %eax,0xc(%rsp)
  call   <system@plt>
  xor    %eax,%eax
  call   <afficherPuissance4@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  add    $0x10,%rsp
  lea    (%rbx,%rbx,4),%edi
  mov    %r12d,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10f0 <systemePoints@plt>
  nopw   0x0(%rax,%rax,1)
L30:
  cmp    $0x3,%eax
  jne    L17
L34:
  lea    D9(%rip),%rsi
  lea    D30(%rip),%rdi
  call   <coloration@plt>
  add    $0x10,%rsp
  mov    %r12d,%edx
  xor    %edi,%edi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  jmp    10f0 <systemePoints@plt>
  nopl   0x0(%rax)
L24:
  cmp    $0x5,%eax
  je     L34
L17:
  add    $0x10,%rsp
  mov    %r12d,%edx
  xor    %edi,%edi
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10f0 <systemePoints@plt>
  nopl   0x0(%rax)
L43:
  lea    D12(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <coloration@plt>
  cmp    $0x8,%ebp
  mov    %r12d,%edx
  setle  %al
  xor    %esi,%esi
  cmp    $0x3,%ebx
  sete   %sil
  add    $0x10,%rsp
  and    %eax,%esi
  lea    (%rbx,%rbx,4),%eax
  pop    %rbx
  pop    %rbp
  lea    (%rax,%rax,4),%edi
  pop    %r12
  jmp    10f0 <systemePoints@plt>
```

tool_calls: name: parse_data
arguments: tag: D64
datatype: string
name: parse_data
arguments: tag: D63
datatype: string
name: parse_data
arguments: tag: D29
datatype: string
name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D30
datatype: string
name: parse_data
arguments: tag: D12
datatype: string
name: parse_data
arguments: tag: D15
datatype: string

tool: D64: 


tool: D63: clear

tool: D29: 
Match nul !


tool: D9: 31

tool: D30: Dommage ! Vous avez perdu.


tool: D12: 32

tool: D15: Bravo ! Vous avez gagne.


assistant: ```c
void afficherGagnantPuissance4Solo(int nbCoups, int modeDeJeux, int niveauDifficulte) {
  int nbPointsGagnes, nbPointsVIP;
  nbPointsGagnes = nbPointsVIP = 0;
  printf("\n");
  switch (gagnerPuissance4(1)) {
  case 3:
  case 3 + 2:
    coloration("Dommage ! Vous avez perdu.\n", "31");
    break;
  case 3 + 1:
    coloration("Bravo ! Vous avez gagne.\n", "32");
    nbPointsGagnes = 25;
    if (nbCoups <= 8 && niveauDifficulte == 3)
      nbPointsVIP = 1;
    break;
  case 0:
    system("clear");
    afficherPuissance4();
    printf("\nMatch nul !\n");
    nbPointsGagnes = 5;
    break;
  }
  nbPointsGagnes *= niveauDifficulte;
  systemePoints(nbPointsGagnes, nbPointsVIP, modeDeJeux);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ipmi_vFlash_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D37(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D37
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D35
data_type: string

tool: 

tool: D29:    vFlash info Card

tool: D35:       Shows Extended SD Card information

assistant: ```c
void ipmi_vFlash_usage(void) {
  lprintf(5, "");
  lprintf(5, "   vFlash info Card");
  lprintf(5, "      Shows Extended SD Card information");
  lprintf(5, "");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ipmi_vFlash_usage>:
  endbr64
  push   %rbx
  lea    D25(%rip),%rbx
  mov    %rbx,%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  lea    D3(%rip),%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  lea    D0(%rip),%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  mov    %rbx,%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: 

tool: D3:    vFlash info Card

tool: D0:       Shows Extended SD Card information

assistant: ```c
void ipmi_vFlash_usage(void) {
  lprintf(5, "");
  lprintf(5, "   vFlash info Card");
  lprintf(5, "      Shows Extended SD Card information");
  lprintf(5, "");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ipmi_vFlash_usage>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rbp
  mov    $0x5,%edi
  mov    %rbp,%rsi
  call   <lprintf@plt>
  lea    D8(%rip),%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  lea    D25(%rip),%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  mov    %rbp,%rsi
  mov    $0x5,%edi
  pop    %rbp
  jmp    1050 <lprintf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D24
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D25
datatype: string

tool: 

tool: D8:    vFlash info Card

tool: D25:       Shows Extended SD Card information

assistant: ```c
void ipmi_vFlash_usage(void) {
  lprintf(5, "");
  lprintf(5, "   vFlash info Card");
  lprintf(5, "      Shows Extended SD Card information");
  lprintf(5, "");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ipmi_vFlash_usage>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    $0x5,%edi
  mov    %rbp,%rsi
  call   <lprintf@plt>
  lea    D5(%rip),%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  lea    D11(%rip),%rsi
  mov    $0x5,%edi
  call   <lprintf@plt>
  mov    %rbp,%rsi
  mov    $0x5,%edi
  pop    %rbp
  jmp    1050 <lprintf@plt>
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string
name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D11
data_type: string

tool: 

tool: D5:    vFlash info Card

tool: D11:       Shows Extended SD Card information

assistant: ```c
void ipmi_vFlash_usage(void) {
  lprintf(5, "");
  lprintf(5, "   vFlash info Card");
  lprintf(5, "      Shows Extended SD Card information");
  lprintf(5, "");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<writechunk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <dprintf@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L8
  mov    -0x4(%rbp),%eax
  jmp    L6
L8:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <writeall@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L22
  mov    -0x4(%rbp),%eax
  jmp    L6
L22:
  mov    -0x14(%rbp),%eax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <dprintf@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L38
  mov    -0x4(%rbp),%eax
  jmp    L6
L38:
  mov    -0x18(%rbp),%eax
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D11
type: string

tool: D6: %x


tool: D11: 


assistant: ```c
int writechunk(int fd, const char *data, int count) {
  int n;
  n = dprintf(fd, "%x\r\n", count);
  if (n < 0) {
    return n;
  }
  n = writeall(fd, data, count);
  if (n < 0) {
    return n;
  }
  n = dprintf(fd, "\r\n");
  if (n < 0) {
    return n;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<writechunk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%ebx
  lea    D12(%rip),%rsi
  mov    $0x0,%eax
  call   <dprintf@plt>
  test   %eax,%eax
  js     L12
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <writeall@plt>
  test   %eax,%eax
  js     L12
  lea    D7(%rip),%rsi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <dprintf@plt>
  test   %eax,%eax
  cmovns %ebx,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
data_type: string
name: retrieve_data
arguments: label: D7
data_type: string

tool: D12: %x


tool: D7: 


assistant: ```c
int writechunk(int fd, const char *data, int count) {
  int n;
  n = dprintf(fd, "%x\r\n", count);
  if (n < 0) {
    return n;
  }
  n = writeall(fd, data, count);
  if (n < 0) {
    return n;
  }
  n = dprintf(fd, "\r\n");
  if (n < 0) {
    return n;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writechunk>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  lea    D11(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <dprintf@plt>
  test   %eax,%eax
  js     L3
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <writeall@plt>
  test   %eax,%eax
  js     L3
  xor    %eax,%eax
  lea    D13(%rip),%rsi
  mov    %ebp,%edi
  call   <dprintf@plt>
  test   %eax,%eax
  cmovns %ebx,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type: string
name: parse_data
arguments: data_tag: D13
type: string

tool: D11: %x


tool: D13: 


assistant: ```c
int writechunk(int fd, const char *data, int count) {
  int n;
  n = dprintf(fd, "%x\r\n", count);
  if (n < 0) {
    return n;
  }
  n = writeall(fd, data, count);
  if (n < 0) {
    return n;
  }
  n = dprintf(fd, "\r\n");
  if (n < 0) {
    return n;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<writechunk>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  lea    D0(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <dprintf@plt>
  test   %eax,%eax
  js     L13
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <writeall@plt>
  test   %eax,%eax
  js     L13
  xor    %eax,%eax
  lea    D13(%rip),%rsi
  mov    %ebp,%edi
  call   <dprintf@plt>
  test   %eax,%eax
  cmovns %ebx,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string

tool: D0: %x


tool: D13: 


assistant: ```c
int writechunk(int fd, const char *data, int count) {
  int n;
  n = dprintf(fd, "%x\r\n", count);
  if (n < 0) {
    return n;
  }
  n = writeall(fd, data, count);
  if (n < 0) {
    return n;
  }
  n = dprintf(fd, "\r\n");
  if (n < 0) {
    return n;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wait_for_ack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L4:
  mov    $0x0,%eax
  call   <rgetchar@plt>
  cmp    $0x20,%al
  jne    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wait_for_ack() {
  while (rgetchar() != ' ')
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<wait_for_ack>:
  endbr64
  sub    $0x8,%rsp
L9:
  mov    $0x0,%eax
  call   <rgetchar@plt>
  cmp    $0x20,%al
  jne    L9
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_for_ack() {
  while (rgetchar() != ' ')
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wait_for_ack>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <rgetchar@plt>
  cmp    $0x20,%al
  jne    L2
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_for_ack() {
  while (rgetchar() != ' ')
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wait_for_ack>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <rgetchar@plt>
  cmp    $0x20,%al
  jne    L5
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_for_ack() {
  while (rgetchar() != ' ')
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  je     L60
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x28(%rbp),%rdx
  cltq
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L48:
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
L61:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L3
  mov    -0x28(%rbp),%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  lea    -0x28(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,(%rbx)
  jmp    L54
L3:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L54:
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L61
  jmp    L29
L60:
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L29:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void read_values(const char *buffer, const char *prefix, unsigned int *values, int count) {
  int i;
  buffer = strstr(buffer, prefix);
  if (buffer != NULL) {
    buffer += strlen(prefix);
    for (i = 0; i < count; i++) {
      while (isspace(*buffer)) {
        buffer++;
      }
      if (*buffer != '\0') {
        values[i] = strtoul(buffer, (char **)&buffer, 0);
      } else {
        values[i] = 0;
      }
    }
  } else {
    memset(values, 0, count * sizeof(unsigned int));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_values>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %ecx,%ebp
  call   <strstr@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L46
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,0x8(%rsp)
  test   %ebp,%ebp
  jle    L67
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%rbp
  lea    0x8(%rsp),%r12
  jmp    L59
L68:
  addq   $0x1,0x8(%rsp)
L59:
  mov    0x8(%rsp),%rax
  movsbl (%rax),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L68
  mov    0x8(%rsp),%rdi
  cmpb   $0x0,(%rdi)
  jne    L24
  movl   $0x0,(%rbx)
L51:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L59
L67:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    $0x0,%edx
  mov    %r12,%rsi
  call   <strtoul@plt>
  mov    %eax,(%rbx)
  jmp    L51
L46:
  lea    0x0(,%rbp,4),%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  jmp    L67
```

assistant: ```c
void read_values(const char *buffer, const char *prefix, unsigned int *values, int count) {
  int i;
  buffer = strstr(buffer, prefix);
  if (buffer != NULL) {
    buffer += strlen(prefix);
    for (i = 0; i < count; i++) {
      while (isspace(*buffer)) {
        buffer++;
      }
      if (*buffer != '\0') {
        values[i] = strtoul(buffer, (char **)&buffer, 0);
      } else {
        values[i] = 0;
      }
    }
  } else {
    memset(values, 0, count * sizeof(unsigned int));
  }
}
```