user: Translate the below assembly code into C programming language:

```asm
<slurp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  lea    D38(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L40
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L42
L40:
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L89
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L42
L89:
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L56
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L42
L56:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  je     L76
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x38(%rbp),%rdx
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L42
L76:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x18(%rbp),%rax
L42:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D38
type_infered: string
name: extract_symbolic_data
arguments: data_label: D36
type_infered: string
name: extract_symbolic_data
arguments: data_label: D27
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string
name: extract_symbolic_data
arguments: data_label: D22
type_infered: string

tool: D38: r

tool: D36: slurp(): could not read from: %s


tool: D27: slurp(): could not stat: %s


tool: D17: slurp(): could not allocate memory for: %s


tool: D22: could not read all %li bytes from file: %s


assistant: ```c
char *slurp(const char *filename) {
  FILE *file = fopen(filename, "r");
  if (file == NULL) {
    printf("slurp(): could not read from: %s\n", filename);
    return NULL;
  }
  struct stat s;
  int rc = stat(filename, &s);
  if (rc != 0) {
    printf("slurp(): could not stat: %s\n", filename);
    return NULL;
  }
  off_t length = s.st_size;
  char *result = malloc((size_t)length + 1);
  if (result == NULL) {
    printf("slurp(): could not allocate memory for: %s\n", filename);
    return NULL;
  }
  char *p = result;
  int actual = (int)fread(p, sizeof(char), (size_t)length, file);
  if (actual != length) {
    printf("could not read all %li bytes from file: %s\n", (long)length, filename);
    free(result);
    return NULL;
  }
  result[length] = '\0';
  fclose(file);
  return result;
}
```