ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<str_starts_with>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    %rax,%r12
  jb     L5
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *str_starts_with(const char *const haystack, const char *const needle) {
  const size_t stacklen = strlen(haystack);
  const size_t ndllen = strlen(needle);
  if (stacklen < ndllen)
    return NULL;
  return (memcmp(haystack, needle, ndllen) == 0) ? haystack : NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_starts_with>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    %rax,%r12
  jb     L4
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *str_starts_with(const char *const haystack, const char *const needle) {
  const size_t stacklen = strlen(haystack);
  const size_t ndllen = strlen(needle);
  if (stacklen < ndllen)
    return NULL;
  return (memcmp(haystack, needle, ndllen) == 0) ? haystack : NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sequence_log_likelihood_alldisk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L23
L20:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    %eax,%ecx
  lea    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <kahan_accum@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
L23:
  mov    -0x30(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L20
  mov    -0x28(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int sequence_log_likelihood_alldisk(double *p, FILE *fi_s) {
  double accum = 0.0;
  double compensation = 0.0;
  double s;
  while (fread(&s, sizeof(double), 1, fi_s)) {
    accum = kahan_accum(accum, &compensation, log(s));
  }
  *p = accum;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sequence_log_likelihood_alldisk>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  mov    D9(%rip),%rbx
  lea    0x10(%rsp),%r12
  jmp    L5
L19:
  movsd  0x10(%rsp),%xmm0
  call   <log@plt>
  mov    %eax,%esi
  lea    0x8(%rsp),%rdi
  movq   %rbx,%xmm0
  call   <kahan_accum@plt>
  movq   %xmm0,%rbx
L5:
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbx,0x0(%r13)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: f64

tool: D9: 0

assistant: ```c
int sequence_log_likelihood_alldisk(double *p, FILE *fi_s) {
  double accum = 0.0;
  double compensation = 0.0;
  double s;
  while (fread(&s, sizeof(double), 1, fi_s)) {
    accum = kahan_accum(accum, &compensation, log(s));
  }
  *p = accum;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<sequence_log_likelihood_alldisk>:
  endbr64
  push   %r14
  pxor   %xmm1,%xmm1
  push   %r13
  movq   %xmm1,%r14
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x8(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  jmp    L17
  nopl   0x0(%rax)
L4:
  movsd  0x10(%rsp),%xmm0
  call   <log@plt>
  movq   %r14,%xmm0
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <kahan_accum@plt>
  movq   %xmm0,%r14
L17:
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L4
  mov    %r14,0x0(%r13)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sequence_log_likelihood_alldisk(double *p, FILE *fi_s) {
  double accum = 0.0;
  double compensation = 0.0;
  double s;
  while (fread(&s, sizeof(double), 1, fi_s)) {
    accum = kahan_accum(accum, &compensation, log(s));
  }
  *p = accum;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sequence_log_likelihood_alldisk>:
  endbr64
  push   %r14
  pxor   %xmm1,%xmm1
  push   %r13
  movq   %xmm1,%r14
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x8(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  jmp    L24
  nopl   0x0(%rax)
L3:
  movsd  0x10(%rsp),%xmm0
  call   <log@plt>
  movq   %r14,%xmm0
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <kahan_accum@plt>
  movq   %xmm0,%r14
L24:
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L3
  mov    %r14,0x0(%r13)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sequence_log_likelihood_alldisk(double *p, FILE *fi_s) {
  double accum = 0.0;
  double compensation = 0.0;
  double s;
  while (fread(&s, sizeof(double), 1, fi_s)) {
    accum = kahan_accum(accum, &compensation, log(s));
  }
  *p = accum;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7e0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xfa,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x7ec(%rbp)
  movl   $0x0,-0x7f4(%rbp)
  movl   $0x0,-0x7f0(%rbp)
  movl   $0x0,-0x7e8(%rbp)
  lea    -0x7f8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L29
L16:
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7ec(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7ec(%rbp)
L29:
  mov    -0x7f8(%rbp),%eax
  cmp    %eax,-0x7ec(%rbp)
  jl     L16
  mov    -0x7e0(%rbp),%eax
  mov    %eax,-0x7f0(%rbp)
  mov    -0x7e0(%rbp),%eax
  mov    %eax,-0x7f4(%rbp)
  mov    -0x7f8(%rbp),%esi
  lea    -0x7f0(%rbp),%rcx
  lea    -0x7f4(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    -0x7f4(%rbp),%edx
  mov    -0x7f0(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x7e4(%rbp)
  mov    -0x7e4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type: string

tool: D14: %d

assistant: ```c
int main() {
  int arr[500] = {0};
  int i = 0, size, min = 0, max = 0;
  int Sum = 0;
  scanf("%d", &size);
  for (; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  max = arr[0];
  min = arr[0];
  minmax(arr, size, &min, &max);
  int sum = min + max;
  printf("%d", sum);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0xfa,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L19
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D26(%rip),%r12
L27:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L27
L19:
  mov    0x10(%rsp),%eax
  mov    %eax,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  add    0x8(%rsp),%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x7f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type_guessed: string

tool: D26: %d

assistant: ```c
int main() {
  int arr[500] = {0};
  int i = 0, size, min = 0, max = 0;
  int Sum = 0;
  scanf("%d", &size);
  for (; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  max = arr[0];
  min = arr[0];
  minmax(arr, size, &min, &max);
  int sum = min + max;
  printf("%d", sum);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xfa,%ecx
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x8(%rsp)
  mov    %r13,%rdi
  movl   $0x0,0xc(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L24
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L18:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L18
L24:
  mov    0x10(%rsp),%eax
  mov    %r13,%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %eax,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  add    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: %d

assistant: ```c
int main() {
  int arr[500] = {0};
  int i = 0, size, min = 0, max = 0;
  int Sum = 0;
  scanf("%d", &size);
  for (; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  max = arr[0];
  min = arr[0];
  minmax(arr, size, &min, &max);
  int sum = min + max;
  printf("%d", sum);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xfa,%ecx
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x8(%rsp)
  mov    %r13,%rdi
  movl   $0x0,0xc(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L22
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L23
L22:
  mov    0x10(%rsp),%eax
  mov    %r13,%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %eax,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  add    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: %d

assistant: ```c
int main() {
  int arr[500] = {0};
  int i = 0, size, min = 0, max = 0;
  int Sum = 0;
  scanf("%d", &size);
  for (; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  max = arr[0];
  min = arr[0];
  minmax(arr, size, &min, &max);
  int sum = min + max;
  printf("%d", sum);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L4
L2:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    %rax,-0x8(%rbp)
  jae    L5
  mov    $0x0,%eax
  jmp    L21
L5:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L2
  mov    $0x1,%eax
L21:
  leave
  ret
```

assistant: ```c
bool write_line(FILE *fp, const char *line) {
  size_t cnt = 0;
  size_t len = strlen(line);
  while (cnt < len) {
    size_t n = fwrite(line + cnt, 1, len - cnt, fp);
    if (n < len - cnt)
      return false;
    cnt += n;
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L20
  mov    %rax,%r12
  mov    $0x0,%ebx
L34:
  mov    %r12,%rbp
  sub    %rbx,%rbp
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r14,%rcx
  mov    %rbp,%rdx
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    %rax,%rbp
  ja     L44
  add    %rax,%rbx
  cmp    %rbx,%r12
  ja     L34
  mov    $0x1,%eax
  jmp    L48
L20:
  mov    $0x1,%eax
  jmp    L48
L44:
  mov    $0x0,%eax
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
bool write_line(FILE *fp, const char *line) {
  size_t cnt = 0;
  size_t len = strlen(line);
  while (cnt < len) {
    size_t n = fwrite(line + cnt, 1, len - cnt, fp);
    if (n < len - cnt)
      return false;
    cnt += n;
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_line>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rdi
  mov    %rsi,(%rsp)
  call   <strlen@plt>
  test   %rax,%rax
  je     L19
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%rdi
  mov    %rax,%rdx
  mov    %rax,%rbx
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    %rax,%rbx
  ja     L1
L19:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool write_line(FILE *fp, const char *line) {
  size_t cnt = 0;
  size_t len = strlen(line);
  while (cnt < len) {
    size_t n = fwrite(line + cnt, 1, len - cnt, fp);
    if (n < len - cnt)
      return false;
    cnt += n;
  }
  return true;
}
```
user: What is the c source code of the assembly code below?

```asm
<write_line>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rdi
  mov    %rsi,(%rsp)
  call   <strlen@plt>
  test   %rax,%rax
  je     L5
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%rdi
  mov    %rax,%rdx
  mov    %rax,%rbx
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    %rax,%rbx
  ja     L2
L5:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool write_line(FILE *fp, const char *line) {
  size_t cnt = 0;
  size_t len = strlen(line);
  while (cnt < len) {
    size_t n = fwrite(line + cnt, 1, len - cnt, fp);
    if (n < len - cnt)
      return false;
    cnt += n;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bubble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L33:
  movl   $0x0,-0x8(%rbp)
  jmp    L42
L38:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L2
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L2:
  addl   $0x1,-0x8(%rbp)
L42:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L38
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L33
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble(int vet[], int n) {
  int a, j, i;
  for (j = 0; j < n - j; j++) {
    for (i = 0; i < n - j - 1; i++) {
      if (vet[i + 1] < vet[i]) {
        a = vet[i + 1];
        vet[i + 1] = vet[i];
        vet[i] = a;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bubble>:
  endbr64
  test   %esi,%esi
  jle    L55
  lea    -0x1(%rsi),%r9d
  lea    0x4(%rdi),%r10
  jmp    L14
L74:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L52
L18:
  mov    0x4(%rax),%edx
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jge    L74
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L74
L52:
  lea    -0x1(%r9),%edx
  mov    %esi,%eax
  sub    %r9d,%eax
  cmp    %eax,%r9d
  jle    L55
  mov    %edx,%r9d
L14:
  test   %r9d,%r9d
  jle    L52
  mov    %rdi,%rax
  lea    -0x1(%r9),%edx
  lea    (%r10,%rdx,4),%r8
  jmp    L18
L55:
  ret
```

assistant: ```c
void bubble(int vet[], int n) {
  int a, j, i;
  for (j = 0; j < n - j; j++) {
    for (i = 0; i < n - j - 1; i++) {
      if (vet[i + 1] < vet[i]) {
        a = vet[i + 1];
        vet[i + 1] = vet[i];
        vet[i] = a;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bubble>:
  endbr64
  test   %esi,%esi
  jle    L56
  lea    -0x1(%rsi),%r9d
  lea    0x4(%rdi),%r11
L3:
  lea    -0x1(%r9),%r10d
  test   %r9d,%r9d
  jle    L2
  lea    -0x1(%r9),%edx
  mov    %rdi,%rax
  mov    %rdx,%r10
  lea    (%r11,%rdx,4),%r8
  nopw   0x0(%rax,%rax,1)
L35:
  mov    0x4(%rax),%edx
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jge    L52
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
L52:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L35
L2:
  mov    %esi,%eax
  sub    %r9d,%eax
  cmp    %eax,%r9d
  jle    L56
  mov    %r10d,%r9d
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L56:
  ret
```

assistant: ```c
void bubble(int vet[], int n) {
  int a, j, i;
  for (j = 0; j < n - j; j++) {
    for (i = 0; i < n - j - 1; i++) {
      if (vet[i + 1] < vet[i]) {
        a = vet[i + 1];
        vet[i + 1] = vet[i];
        vet[i] = a;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bubble>:
  endbr64
  test   %esi,%esi
  jle    L50
  lea    -0x1(%rsi),%r9d
  lea    0x4(%rdi),%r11
L13:
  lea    -0x1(%r9),%r10d
  test   %r9d,%r9d
  jle    L24
  lea    -0x1(%r9),%eax
  mov    %rdi,%rdx
  mov    %rax,%r10
  lea    (%r11,%rax,4),%r8
  nopw   0x0(%rax,%rax,1)
L44:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L53
  movq   %xmm1,(%rdx)
L53:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L44
L24:
  mov    %esi,%eax
  sub    %r9d,%eax
  cmp    %eax,%r9d
  jle    L50
  mov    %r10d,%r9d
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L50:
  ret
```

assistant: ```c
void bubble(int vet[], int n) {
  int a, j, i;
  for (j = 0; j < n - j; j++) {
    for (i = 0; i < n - j - 1; i++) {
      if (vet[i + 1] < vet[i]) {
        a = vet[i + 1];
        vet[i + 1] = vet[i];
        vet[i] = a;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xor_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L14
L4:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void xor_bytes(uint8_t *out, const uint8_t *a, const uint8_t *b, const size_t len) {
  for (size_t i = 0; i < len; ++i) {
    out[i] = a[i] ^ b[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<xor_bytes>:
  endbr64
  test   %rcx,%rcx
  je     L3
  mov    $0x0,%eax
L14:
  mov    (%rsi,%rax,4),%r8d
  xor    (%rdx,%rax,4),%r8d
  mov    %r8d,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L14
L3:
  ret
```

assistant: ```c
void xor_bytes(uint8_t *out, const uint8_t *a, const uint8_t *b, const size_t len) {
  for (size_t i = 0; i < len; ++i) {
    out[i] = a[i] ^ b[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xor_bytes>:
  endbr64
  test   %rcx,%rcx
  je     L15
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  mov    (%rsi,%rax,4),%r8d
  xor    (%rdx,%rax,4),%r8d
  mov    %r8d,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L7
L15:
  ret
```

assistant: ```c
void xor_bytes(uint8_t *out, const uint8_t *a, const uint8_t *b, const size_t len) {
  for (size_t i = 0; i < len; ++i) {
    out[i] = a[i] ^ b[i];
  }
}
```