user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x53202e412064655a,%rax
  mov    %rax,-0x13(%rbp)
  movw   $0x6168,-0xb(%rbp)
  movb   $0x77,-0x9(%rbp)
  movl   $0xa,-0x30(%rbp)
  movl   $0xc,-0x2c(%rbp)
  movl   $0xd,-0x28(%rbp)
  movl   $0xe,-0x24(%rbp)
  movl   $0x14,-0x20(%rbp)
  movl   $0x64655a,-0x17(%rbp)
  movl   $0x64,-0x30(%rbp)
  movzbl -0x16(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,-0x2c(%rbp)
  mov    $0x4,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x13(%rbp),%rdx
  lea    -0x17(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D62
type_infered: string
name: retrieve_data
arguments: data_label: D48
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D33
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D0
type_infered: string
name: retrieve_data
arguments: data_label: D60
type_infered: string
name: retrieve_data
arguments: data_label: D77
type_infered: string
name: retrieve_data
arguments: data_label: D38
type_infered: string

tool: D62: The size of an int %ld


tool: D48: The size of areas (int[]); %ld


tool: D12: The number of ints in areas: %ld


tool: D33: The first area is %d, the 2nd %d.


tool: D15: The size of a char: %ld


tool: D0: the size of name (char[]): %ld


tool: D60: The number of chars: %ld


tool: D77: The size of full_name (char[]): %ld


tool: D38: name="%s" and full_name="%s"


assistant: ```c
int main(int argc, char *argv[]) {
  char full_name[] = {'Z', 'e', 'd', ' ', 'A', '.', ' ', 'S', 'h', 'a', 'w'};
  int areas[] = {10, 12, 13, 14, 20};
  char name[] = "Zed";
  areas[0] = 100;
  areas[1] = name[1];
  printf("The size of an int %ld\n", sizeof(int));
  printf("The size of areas (int[]); %ld\n", sizeof(areas));
  printf("The number of ints in areas: %ld\n", sizeof(areas) / sizeof(int));
  printf("The first area is %d, the 2nd %d.\n", areas[0], areas[1]);
  printf("The size of a char: %ld\n", sizeof(char));
  printf("the size of name (char[]): %ld\n", sizeof(name));
  printf("The number of chars: %ld\n", sizeof(name) / sizeof(char));
  printf("The size of full_name (char[]): %ld\n", sizeof(full_name));
  printf("The number of chars: %ld\n", sizeof(full_name) / sizeof(char));
  printf("name=\"%s\" and full_name=\"%s\"\n", name, full_name);
  return 0;
}
```