ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  mov    $0x64,%edi
  call   <read_buffered@plt>
  mov    %rax,%rdx
  mov    0x4(%rsp),%ecx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    $0x64,%edi
  call   <buffered_write@plt>
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c = 0, t = 0;
  int p = 0;
  char *buf = read_buffered(100, STDIN_FILENO, &c);
  buffered_write(100, STDOUT_FILENO, buf, c);
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x64,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%esi
  call   <read_buffered@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x64,%edi
  mov    %rax,%rdx
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  call   <buffered_write@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c = 0, t = 0;
  int p = 0;
  char *buf = read_buffered(100, STDIN_FILENO, &c);
  buffered_write(100, STDOUT_FILENO, buf, c);
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x64,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D28(%rip),%rax
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%esi
  call   <read_buffered@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x64,%edi
  mov    %rax,%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <buffered_write@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c = 0, t = 0;
  int p = 0;
  char *buf = read_buffered(100, STDIN_FILENO, &c);
  buffered_write(100, STDOUT_FILENO, buf, c);
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2a,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <foo@plt>
  leave
  ret
```

assistant: ```c
int main(void) {
  int a = 42, foo(int a), b = 2;
  return foo(a + b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2c,%edi
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a = 42, foo(int a), b = 2;
  return foo(a + b);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    $0x2c,%edi
  jmp    1050 <foo@plt>
```

assistant: ```c
int main(void) {
  int a = 42, foo(int a), b = 2;
  return foo(a + b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x2c,%edi
  jmp    1050 <foo@plt>
```

assistant: ```c
int main(void) {
  int a = 42, foo(int a), b = 2;
  return foo(a + b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fparam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L61
L47:
  addl   $0x1,-0x18(%rbp)
L61:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L47
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L47
  jmp    L38
L80:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L59
L23:
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L38:
  cmpl   $0x3f,-0x18(%rbp)
  jg     L41
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L41
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L80
L41:
  movl   $0x0,-0x10(%rbp)
  jmp    L40
L102:
  addl   $0x1,-0x18(%rbp)
L40:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L102
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L102
  jmp    L109
L24:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L109:
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L24
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L59:
  leave
  ret
```

assistant: ```c
char *fparam(const char *str, char *args, int strleng) {
  int i = 0;
  int alen = strleng;
  char *b = (char *)malloc(64);
  int k = 0;
  for (; str[i] == ' ' || str[i] == '\t'; i++)
    ;
  for (; i < 64 && str[i] != ' ' && i < alen; i++, k++) {
    b[k] = str[i];
    if (str[i] == '\0') {
      *args = '\0';
      return b;
    }
  }
  int j = 0;
  for (; str[i] == ' ' || str[i] == '\t'; i++)
    ;
  for (; i < alen; i++, j++)
    args[j] = str[i];
  args[j] = 0;
  b[i] = 0;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fparam>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L21
  cmp    $0x9,%al
  jne    L175
L21:
  mov    $0x1,%eax
L150:
  mov    %eax,%ecx
  movzbl (%rbx,%rax,1),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L150
  cmp    $0x9,%dl
  je     L150
  cmp    $0x3f,%ecx
  jg     L141
  movslq %ecx,%rsi
  movzbl (%rbx,%rsi,1),%edx
  cmp    %ecx,%ebp
  jle    L154
  cmp    $0x20,%dl
  je     L154
L217:
  lea    0x1(%rcx),%eax
  cltq
  lea    -0x1(%rdi),%r8
  sub    %rsi,%r8
L199:
  mov    %dl,(%r8,%rax,1)
  test   %dl,%dl
  je     L130
  mov    %eax,%ecx
  cmp    $0x3f,%eax
  jg     L154
  movzbl (%rbx,%rax,1),%edx
  add    $0x1,%rax
  cmp    %ecx,%ebp
  jle    L154
  cmp    $0x20,%dl
  jne    L199
L154:
  movslq %ecx,%rax
  movzbl (%rbx,%rax,1),%eax
  cmp    $0x20,%al
  je     L142
  cmp    $0x9,%al
  jne    L141
L142:
  lea    0x1(%rcx),%eax
  cltq
L168:
  mov    %eax,%ecx
  movzbl (%rbx,%rax,1),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L168
  cmp    $0x9,%dl
  je     L168
L141:
  cmp    %ecx,%ebp
  jle    L22
  movslq %ecx,%rdx
  mov    %rdx,%rax
  mov    %r12,%rsi
  sub    %rdx,%rsi
L62:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L62
  mov    %ebp,%eax
  sub    %ecx,%eax
L133:
  cltq
  movb   $0x0,(%r12,%rax,1)
  movslq %ebp,%rbp
  movb   $0x0,(%rdi,%rbp,1)
L136:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L130:
  movb   $0x0,(%r12)
  jmp    L136
L22:
  mov    %ecx,%ebp
  mov    $0x0,%eax
  jmp    L133
L175:
  movzbl (%rbx),%edx
  test   %ebp,%ebp
  jle    L118
  mov    $0x0,%esi
  mov    $0x0,%ecx
  cmp    $0x20,%dl
  jne    L217
L118:
  mov    $0x0,%ecx
  jmp    L141
```

assistant: ```c
char *fparam(const char *str, char *args, int strleng) {
  int i = 0;
  int alen = strleng;
  char *b = (char *)malloc(64);
  int k = 0;
  for (; str[i] == ' ' || str[i] == '\t'; i++)
    ;
  for (; i < 64 && str[i] != ' ' && i < alen; i++, k++) {
    b[k] = str[i];
    if (str[i] == '\0') {
      *args = '\0';
      return b;
    }
  }
  int j = 0;
  for (; str[i] == ' ' || str[i] == '\t'; i++)
    ;
  for (; i < alen; i++, j++)
    args[j] = str[i];
  args[j] = 0;
  b[i] = 0;
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fparam>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x40,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%r8
  cmp    $0x20,%dl
  je     L172
  cmp    $0x9,%dl
  jne    L30
L172:
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L134:
  movzbl (%rbx,%rcx,1),%edx
  movslq %ecx,%rsi
  mov    %rcx,%rax
  lea    0x1(%rcx),%rcx
  cmp    $0x20,%dl
  je     L134
  cmp    $0x9,%dl
  je     L134
  cmp    $0x3f,%esi
  jg     L13
L148:
  cmp    %esi,%r12d
  jle    L99
  lea    0x1(%rsi),%eax
  lea    -0x1(%r8),%rdi
  cltq
  sub    %rsi,%rdi
  jmp    L39
  nopl   0x0(%rax)
L169:
  movzbl (%rbx,%rax,1),%edx
  mov    %eax,%ecx
  cmp    $0x3f,%eax
  jg     L60
  lea    0x1(%rax),%rsi
  cmp    %eax,%r12d
  jle    L60
  cmp    $0x20,%dl
  je     L60
  mov    %rsi,%rax
L39:
  mov    %dl,(%rdi,%rax,1)
  test   %dl,%dl
  jne    L169
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L60:
  cmp    $0x9,%dl
  jne    L184
L2:
  lea    0x1(%rcx),%edx
  movslq %edx,%rdx
  nopl   0x0(%rax,%rax,1)
L29:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %edx,%esi
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    $0x20,%cl
  je     L29
  cmp    $0x9,%cl
  je     L29
L13:
  cmp    %esi,%r12d
  jle    L99
  movslq %esi,%rax
  mov    %rbp,%rcx
  sub    %rax,%rcx
  nopl   (%rax)
L153:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%r12d
  jg     L153
  mov    %r12d,%eax
  sub    %esi,%eax
  cltq
  add    %rax,%rbp
  movslq %r12d,%rax
L99:
  movb   $0x0,0x0(%rbp)
  movb   $0x0,(%r8,%rax,1)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L184:
  cmp    $0x20,%dl
  je     L2
  mov    %ecx,%esi
  jmp    L13
  nopl   0x0(%rax)
L30:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L148
```

assistant: ```c
char *fparam(const char *str, char *args, int strleng) {
  int i = 0;
  int alen = strleng;
  char *b = (char *)malloc(64);
  int k = 0;
  for (; str[i] == ' ' || str[i] == '\t'; i++)
    ;
  for (; i < 64 && str[i] != ' ' && i < alen; i++, k++) {
    b[k] = str[i];
    if (str[i] == '\0') {
      *args = '\0';
      return b;
    }
  }
  int j = 0;
  for (; str[i] == ' ' || str[i] == '\t'; i++)
    ;
  for (; i < alen; i++, j++)
    args[j] = str[i];
  args[j] = 0;
  b[i] = 0;
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sortrnd@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: f64

tool: D4: 91648253

assistant: ```c
void sort(void **array, int size, int (*comp)(const void *, const void *)) {
  double seed = 91648253;
  sortrnd(array, size, comp, &seed);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rcx
  call   <sortrnd@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: f64

tool: D6: 91648253

assistant: ```c
void sort(void **array, int size, int (*comp)(const void *, const void *)) {
  double seed = 91648253;
  sortrnd(array, size, comp, &seed);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    %rsp,%rcx
  mov    %rax,(%rsp)
  call   <sortrnd@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: f64

tool: D6: 91648253

assistant: ```c
void sort(void **array, int size, int (*comp)(const void *, const void *)) {
  double seed = 91648253;
  sortrnd(array, size, comp, &seed);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sort>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    %rsp,%rcx
  mov    %rax,(%rsp)
  call   <sortrnd@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type: f64

tool: D6: 91648253

assistant: ```c
void sort(void **array, int size, int (*comp)(const void *, const void *)) {
  double seed = 91648253;
  sortrnd(array, size, comp, &seed);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: %d 

assistant: ```c
void display(int *list, int size) {
  int i = 0;
  for (i = 0; i < size; i++)
    printf("%d ", list[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<display>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D1(%rip),%rbp
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %d 

assistant: ```c
void display(int *list, int size) {
  int i = 0;
  for (i = 0; i < size; i++)
    printf("%d ", list[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<display>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: %d 

assistant: ```c
void display(int *list, int size) {
  int i = 0;
  for (i = 0; i < size; i++)
    printf("%d ", list[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<display>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: %d 

assistant: ```c
void display(int *list, int size) {
  int i = 0;
  for (i = 0; i < size; i++)
    printf("%d ", list[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_alpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x60,-0x4(%rbp)
  jle    L32
  cmpb   $0x7a,-0x4(%rbp)
  jg     L32
  mov    $0x1,%eax
  jmp    L37
L32:
  cmpb   $0x40,-0x4(%rbp)
  jle    L39
  cmpb   $0x5a,-0x4(%rbp)
  jg     L39
  mov    $0x1,%eax
  jmp    L37
L39:
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int is_alpha(char c) {
  if (c >= 'a' && c <= 'z')
    return (1);
  if (c >= 'A' && c <= 'Z')
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_alpha>:
  endbr64
  and    $0xffffffdf,%edi
  sub    $0x41,%edi
  cmp    $0x19,%dil
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_alpha(char c) {
  if (c >= 'a' && c <= 'z')
    return (1);
  if (c >= 'A' && c <= 'Z')
    return (1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_alpha>:
  endbr64
  and    $0xffffffdf,%edi
  xor    %eax,%eax
  sub    $0x41,%edi
  cmp    $0x19,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_alpha(char c) {
  if (c >= 'a' && c <= 'z')
    return (1);
  if (c >= 'A' && c <= 'Z')
    return (1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_alpha>:
  endbr64
  and    $0xffffffdf,%edi
  xor    %eax,%eax
  sub    $0x41,%edi
  cmp    $0x19,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_alpha(char c) {
  if (c >= 'a' && c <= 'z')
    return (1);
  if (c >= 'A' && c <= 'Z')
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L10
L31:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  and    $0x3,%eax
  test   %rax,%rax
  je     L35
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L66
L35:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L66:
  mov    -0x18(%rbp),%rax
  and    $0x3,%eax
  cmp    $0x3,%rax
  jne    L19
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L19:
  mov    -0x18(%rbp),%rax
  and    $0x3,%eax
  cmp    $0x2,%rax
  jne    L1
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L1:
  mov    -0x18(%rbp),%rax
  and    $0x3,%eax
  cmp    $0x1,%rax
  jne    L21
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L21:
  addl   $0x1,-0x1c(%rbp)
L10:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L31
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D27
type_infered: string
name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D5
type_infered: string

tool: D27: %d

tool: D28: %lld

tool: D13: 1


tool: D14: 3


tool: D21: 9


tool: D5: 7


assistant: ```c
int main() {
  int N, Cont;
  unsigned long long int Result, Num;
  scanf("%d", &N);
  for (Cont = 0; Cont < N; Cont++) {
    scanf("%lld", &Num);
    if (Num % 4 == 0 || Num == 0)
      printf("1\n", Result);
    else if (Num % 4 == 3)
      printf("3\n", Result);
    else if (Num % 4 == 2)
      printf("9\n", Result);
    else if (Num % 4 == 1)
      printf("7\n", Result);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D59(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L14
  mov    $0x0,%ebx
  lea    D55(%rip),%rbp
  lea    D56(%rip),%r12
  lea    D11(%rip),%r14
  lea    D19(%rip),%r13
  jmp    L59
L15:
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L30:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L14
L59:
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  mov    %rax,%rdx
  and    $0x3,%edx
  test   %rax,%rax
  je     L15
  test   %rdx,%rdx
  je     L15
  cmp    $0x3,%rdx
  je     L8
  cmp    $0x2,%rdx
  je     L40
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L30
L8:
  mov    $0x0,%esi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L40:
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L30
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D59
type_infered: string
name: retrieve_data
arguments: tag: D55
type_infered: string
name: retrieve_data
arguments: tag: D56
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D54
type_infered: string

tool: D59: %d

tool: D55: %lld

tool: D56: 1


tool: D11: 7


tool: D19: 9


tool: D54: 3


assistant: ```c
int main() {
  int N, Cont;
  unsigned long long int Result, Num;
  scanf("%d", &N);
  for (Cont = 0; Cont < N; Cont++) {
    scanf("%lld", &Num);
    if (Num % 4 == 0 || Num == 0)
      printf("1\n", Result);
    else if (Num % 4 == 3)
      printf("3\n", Result);
    else if (Num % 4 == 2)
      printf("9\n", Result);
    else if (Num % 4 == 1)
      printf("7\n", Result);
  }
  return 0;
}
```