ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<waitfor>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
L4:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jbe    L38
L23:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <feof@plt>
  test   %rax,%rax
  jne    L22
  mov    %ebp,%eax
  add    $0x1,%ebp
  cmp    %bl,(%r12,%rax,1)
  je     L4
  xor    %ebp,%ebp
  mov    %r12,%rdi
  cmp    %bl,(%r12)
  sete   %bpl
  call   <strlen@plt>
  cmp    %ebp,%eax
  ja     L23
L38:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L22:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int waitfor(char *end) {
  unsigned int i = 0;
  char c;
  while (i < strlen(end)) {
    c = getchar();
    if (feof(stdin))
      return 0;
    else if (c == end[i])
      i++;
    else if (c == end[0])
      i = 1;
    else
      i = 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<waitfor>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
L39:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jbe    L36
L32:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <feof@plt>
  test   %rax,%rax
  jne    L33
  mov    %ebp,%eax
  add    $0x1,%ebp
  cmp    %bl,(%r12,%rax,1)
  je     L39
  xor    %ebp,%ebp
  mov    %r12,%rdi
  cmp    %bl,(%r12)
  sete   %bpl
  call   <strlen@plt>
  cmp    %ebp,%eax
  ja     L32
L36:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L33:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int waitfor(char *end) {
  unsigned int i = 0;
  char c;
  while (i < strlen(end)) {
    c = getchar();
    if (feof(stdin))
      return 0;
    else if (c == end[i])
      i++;
    else if (c == end[0])
      i = 1;
    else
      i = 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parseTypeCodeToString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  movsbl -0xc(%rbp),%eax
  sub    $0x31,%eax
  cmp    $0x4,%eax
  ja     L12
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D10(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x8(%rbp),%rax
  movabs $0x676f725020333739,%rcx
  mov    %rcx,(%rax)
  movl   $0x6d6172,0x8(%rax)
  jmp    L40
  mov    -0x8(%rbp),%rax
  movl   $0x4346534e,(%rax)
  movb   $0x0,0x4(%rax)
  jmp    L40
  mov    -0x8(%rbp),%rax
  movabs $0x676f725020333638,%rcx
  mov    %rcx,(%rax)
  movl   $0x6d6172,0x8(%rax)
  jmp    L40
  mov    -0x8(%rbp),%rax
  movabs $0x74616e7265746e49,%rsi
  movabs $0x6f43206c616e6f69,%rdi
  mov    %rsi,(%rax)
  mov    %rdi,0x8(%rax)
  movabs $0x6f6974617265706f,%rsi
  mov    %rsi,0x10(%rax)
  movw   $0x6e,0x18(%rax)
  jmp    L40
  mov    -0x8(%rbp),%rax
  movabs $0x726576736e617254,%rdi
  mov    %rdi,(%rax)
  movw   $0x6573,0x8(%rax)
  movb   $0x0,0xa(%rax)
  jmp    L40
L12:
  mov    -0x8(%rbp),%rax
  movl   $0x2d2d2d,(%rax)
  nop
L40:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
parseTypeCodeToString(char *to, const char from) {
  switch (from) {
  case '1': {
    strcpy(to, "973 Program");
    break;
  }
  case '2': {
    strcpy(to, "NSFC");
    break;
  }
  case '3': {
    strcpy(to, "863 Program");
    break;
  }
  case '4': {
    strcpy(to, "International Cooperation");
    break;
  }
  case '5': {
    strcpy(to, "Transverse");
    break;
  }
  default: {
    strcpy(to, "---");
    break;
  }
  }
  return to;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parseTypeCodeToString>:
  endbr64
  mov    %rdi,%rax
  sub    $0x31,%esi
  cmp    $0x4,%sil
  ja     L1
  movzbl %sil,%esi
  lea    D7(%rip),%rcx
  movslq (%rcx,%rsi,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  movabs $0x676f725020333739,%rdi
  mov    %rdi,(%rax)
  movl   $0x6d6172,0x8(%rax)
  ret
  movl   $0x4346534e,(%rdi)
  movb   $0x0,0x4(%rdi)
  ret
  movabs $0x676f725020333638,%rcx
  mov    %rcx,(%rdi)
  movl   $0x6d6172,0x8(%rdi)
  ret
  movabs $0x74616e7265746e49,%rdx
  movabs $0x6f43206c616e6f69,%rcx
  mov    %rdx,(%rdi)
  mov    %rcx,0x8(%rdi)
  movabs $0x6f6974617265706f,%rdi
  mov    %rdi,0x10(%rax)
  movw   $0x6e,0x18(%rax)
  ret
  movabs $0x726576736e617254,%rcx
  mov    %rcx,(%rdi)
  movw   $0x6573,0x8(%rdi)
  movb   $0x0,0xa(%rdi)
  ret
L1:
  movl   $0x2d2d2d,(%rdi)
  ret
```

assistant: ```c
parseTypeCodeToString(char *to, const char from) {
  switch (from) {
  case '1': {
    strcpy(to, "973 Program");
    break;
  }
  case '2': {
    strcpy(to, "NSFC");
    break;
  }
  case '3': {
    strcpy(to, "863 Program");
    break;
  }
  case '4': {
    strcpy(to, "International Cooperation");
    break;
  }
  case '5': {
    strcpy(to, "Transverse");
    break;
  }
  default: {
    strcpy(to, "---");
    break;
  }
  }
  return to;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  cltq
  imul   %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <rchold@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L1
L30:
  mov    -0x18(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L37:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L37
  addl   $0x1,-0x18(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L30
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void chold(float *A, int N) {
  int stride, i, j, t;
  float *U22;
  U22 = (float *)malloc(sizeof(float) * N * N);
  stride = N;
  rchold(A, N, stride, U22);
  for (i = 0; i < N; ++i) {
    t = i * N;
    for (j = 0; j < i; ++j) {
      A[t + j] = 0.;
    }
  }
  free(U22);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<chold>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  movslq %esi,%r12
  mov    %esi,%edi
  imul   %esi,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rcx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <rchold@plt>
  test   %ebx,%ebx
  jle    L40
  lea    0x0(,%r12,4),%rdi
  lea    0x0(%r13,%rdi,1),%rsi
  lea    0x4(%rdi),%r8
  lea    0x4(%r13,%rdi,1),%rdx
  mov    $0x0,%ecx
  jmp    L31
L19:
  test   %ecx,%ecx
  jle    L43
  mov    %rsi,%rax
L21:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L21
L43:
  add    %rdi,%rsi
  add    %r8,%rdx
L31:
  add    $0x1,%ecx
  cmp    %ecx,%ebx
  jne    L19
L40:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void chold(float *A, int N) {
  int stride, i, j, t;
  float *U22;
  U22 = (float *)malloc(sizeof(float) * N * N);
  stride = N;
  rchold(A, N, stride, U22);
  for (i = 0; i < N; ++i) {
    t = i * N;
    for (j = 0; j < i; ++j) {
      A[t + j] = 0.;
    }
  }
  free(U22);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chold>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,%edi
  imul   %r12d,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    %rax,%rcx
  mov    %rax,%r13
  call   <rchold@plt>
  test   %r12d,%r12d
  jle    L5
  mov    %r12,%rbp
  shl    $0x2,%r12
  mov    $0x4,%r14d
  lea    (%rbx,%r12,1),%rcx
  xor    %ebx,%ebx
  jmp    L11
  nop
L10:
  mov    %r14,%rdx
  mov    %rcx,%rdi
  xor    %esi,%esi
  add    $0x4,%r14
  call   <memset@plt>
  mov    %rax,%rcx
  add    %r12,%rcx
L11:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L10
L5:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <free@plt>
```

assistant: ```c
void chold(float *A, int N) {
  int stride, i, j, t;
  float *U22;
  U22 = (float *)malloc(sizeof(float) * N * N);
  stride = N;
  rchold(A, N, stride, U22);
  for (i = 0; i < N; ++i) {
    t = i * N;
    for (j = 0; j < i; ++j) {
      A[t + j] = 0.;
    }
  }
  free(U22);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<chold>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,%edi
  imul   %r12d,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    %rax,%rcx
  mov    %rax,%r13
  call   <rchold@plt>
  cmp    $0x1,%r12d
  jle    L9
  mov    %r12,%rbp
  shl    $0x2,%r12
  mov    $0x4,%r14d
  lea    (%rbx,%r12,1),%rcx
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L1:
  mov    %r14,%rdx
  mov    %rcx,%rdi
  xor    %esi,%esi
  add    $0x1,%ebx
  call   <memset@plt>
  add    $0x4,%r14
  mov    %rax,%rcx
  add    %r12,%rcx
  cmp    %ebx,%ebp
  jne    L1
L9:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <free@plt>
```

assistant: ```c
void chold(float *A, int N) {
  int stride, i, j, t;
  float *U22;
  U22 = (float *)malloc(sizeof(float) * N * N);
  stride = N;
  rchold(A, N, stride, U22);
  for (i = 0; i < N; ++i) {
    t = i * N;
    for (j = 0; j < i; ++j) {
      A[t + j] = 0.;
    }
  }
  free(U22);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<qdist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L16:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x3,-0xc(%rbp)
  jle    L16
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D5(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: f64

tool: D5: 1

assistant: ```c
double qdist(double *q1, double *q2) {
  int i;
  double d = 0.;
  for (i = 0; i < 4; ++i)
    d += q1[i] * q2[i];
  return 1. - d * d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<qdist>:
  endbr64
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L1:
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    $0x20,%rax
  jne    L1
  mulsd  %xmm1,%xmm1
  movsd  D1(%rip),%xmm0
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: f64

tool: D1: 1

assistant: ```c
double qdist(double *q1, double *q2) {
  int i;
  double d = 0.;
  for (i = 0; i < 4; ++i)
    d += q1[i] * q2[i];
  return 1. - d * d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qdist>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
L5:
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    $0x20,%rax
  jne    L5
  mulsd  %xmm1,%xmm1
  movsd  D3(%rip),%xmm0
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: f64

tool: D3: 1

assistant: ```c
double qdist(double *q1, double *q2) {
  int i;
  double d = 0.;
  for (i = 0; i < 4; ++i)
    d += q1[i] * q2[i];
  return 1. - d * d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qdist>:
  endbr64
  movupd (%rdi),%xmm0
  movupd (%rsi),%xmm3
  pxor   %xmm1,%xmm1
  movupd 0x10(%rdi),%xmm2
  mulpd  %xmm3,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movupd 0x10(%rsi),%xmm0
  mulpd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D6(%rip),%xmm1
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: f64

tool: D6: 1

assistant: ```c
double qdist(double *q1, double *q2) {
  int i;
  double d = 0.;
  for (i = 0; i < 4; ++i)
    d += q1[i] * q2[i];
  return 1. - d * d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<postorderTraversal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <postO@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
int *postorderTraversal(struct TreeNode *root, int *returnSize) {
  int **returnArr = (int **)malloc(sizeof(int *));
  *returnArr = (int *)malloc(sizeof(int));
  *returnSize = 0;
  postO(root, returnSize, returnArr);
  return *returnArr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<postorderTraversal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movl   $0x0,0x0(%rbp)
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <postO@plt>
  mov    (%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *postorderTraversal(struct TreeNode *root, int *returnSize) {
  int **returnArr = (int **)malloc(sizeof(int *));
  *returnArr = (int *)malloc(sizeof(int));
  *returnSize = 0;
  postO(root, returnSize, returnArr);
  return *returnArr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<postorderTraversal>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x8,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,(%rbx)
  movl   $0x0,0x0(%rbp)
  call   <postO@plt>
  mov    (%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *postorderTraversal(struct TreeNode *root, int *returnSize) {
  int **returnArr = (int **)malloc(sizeof(int *));
  *returnArr = (int *)malloc(sizeof(int));
  *returnSize = 0;
  postO(root, returnSize, returnArr);
  return *returnArr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<postorderTraversal>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x8,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,(%rbx)
  movl   $0x0,0x0(%rbp)
  call   <postO@plt>
  mov    (%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *postorderTraversal(struct TreeNode *root, int *returnSize) {
  int **returnArr = (int **)malloc(sizeof(int *));
  *returnArr = (int *)malloc(sizeof(int));
  *returnSize = 0;
  postO(root, returnSize, returnArr);
  return *returnArr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<show_selection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x51,%eax
  je     L51
  cmp    $0x51,%eax
  jg     L78
  cmp    $0x43,%eax
  je     L9
  cmp    $0x43,%eax
  jg     L78
  cmp    $0x41,%eax
  je     L84
  cmp    $0x42,%eax
  je     L18
  jmp    L78
L51:
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L93
L84:
  mov    $0x41,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L93
L18:
  mov    $0x42,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L93
L9:
  mov    $0x43,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L93
L78:
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L93:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D53
data_type: string
name: read_data
arguments: label: D8
data_type: string
name: read_data
arguments: label: D25
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D4: Goodbye!

tool: D53: %s


tool: D8: Changing to menu item --> 

tool: D25: %s%c


tool: D2: Sorry, invalid option

assistant: ```c
int show_selection(char option) {
  switch (option) {
  case 'Q':
    printf("%s\n", "Goodbye!");
    break;
  case 'A':
    printf("%s%c\n", "Changing to menu item --> ", 'A');
    break;
  case 'B':
    printf("%s%c\n", "Changing to menu item --> ", 'B');
    break;
  case 'C':
    printf("%s%c\n", "Changing to menu item --> ", 'C');
    break;
  default:
    printf("%s\n", "Sorry, invalid option");
    break;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<show_selection>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x43,%dil
  je     L26
  jg     L16
  cmp    $0x41,%dil
  je     L45
  cmp    $0x42,%dil
  jne    L55
  mov    $0x42,%edx
  lea    D4(%rip),%rsi
  lea    D98(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L16:
  cmp    $0x51,%dil
  jne    L55
  lea    D49(%rip),%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L45:
  mov    $0x41,%edx
  lea    D4(%rip),%rsi
  lea    D98(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L26:
  mov    $0x43,%edx
  lea    D4(%rip),%rsi
  lea    D98(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L55:
  lea    D7(%rip),%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D98
type_infered: string
name: extract_symbolic_data
arguments: tag: D49
type_infered: string
name: extract_symbolic_data
arguments: tag: D23
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D4: Changing to menu item --> 

tool: D98: %s%c


tool: D49: Goodbye!

tool: D23: %s


tool: D7: Sorry, invalid option

assistant: ```c
int show_selection(char option) {
  switch (option) {
  case 'Q':
    printf("%s\n", "Goodbye!");
    break;
  case 'A':
    printf("%s%c\n", "Changing to menu item --> ", 'A');
    break;
  case 'B':
    printf("%s%c\n", "Changing to menu item --> ", 'B');
    break;
  case 'C':
    printf("%s%c\n", "Changing to menu item --> ", 'C');
    break;
  default:
    printf("%s\n", "Sorry, invalid option");
    break;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<show_selection>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x43,%dil
  je     L45
  jg     L37
  cmp    $0x41,%dil
  je     L28
  cmp    $0x42,%dil
  jne    L24
  mov    $0x42,%edx
  lea    D40(%rip),%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L37:
  cmp    $0x51,%dil
  jne    L24
  lea    D20(%rip),%rsi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  mov    $0x43,%edx
  lea    D40(%rip),%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L24:
  lea    D63(%rip),%rsi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L28:
  mov    $0x41,%edx
  lea    D40(%rip),%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D40
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D20
datatype: string
name: retrieve_data
arguments: data_label: D61
datatype: string
name: retrieve_data
arguments: data_label: D63
datatype: string

tool: D40: Changing to menu item --> 

tool: D2: %s%c


tool: D20: Goodbye!

tool: D61: %s


tool: D63: Sorry, invalid option

assistant: ```c
int show_selection(char option) {
  switch (option) {
  case 'Q':
    printf("%s\n", "Goodbye!");
    break;
  case 'A':
    printf("%s%c\n", "Changing to menu item --> ", 'A');
    break;
  case 'B':
    printf("%s%c\n", "Changing to menu item --> ", 'B');
    break;
  case 'C':
    printf("%s%c\n", "Changing to menu item --> ", 'C');
    break;
  default:
    printf("%s\n", "Sorry, invalid option");
    break;
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<show_selection>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x43,%dil
  je     L42
  jg     L16
  cmp    $0x41,%dil
  je     L26
  cmp    $0x42,%dil
  jne    L10
  mov    $0x42,%edx
  lea    D40(%rip),%rsi
  lea    D89(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L16:
  cmp    $0x51,%dil
  jne    L10
  lea    D75(%rip),%rsi
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    $0x43,%edx
  lea    D40(%rip),%rsi
  lea    D89(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L10:
  lea    D51(%rip),%rsi
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L26:
  mov    $0x41,%edx
  lea    D40(%rip),%rsi
  lea    D89(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D40
data_type: string
name: extract_symbolic_data
arguments: data_label: D89
data_type: string
name: extract_symbolic_data
arguments: data_label: D75
data_type: string
name: extract_symbolic_data
arguments: data_label: D65
data_type: string
name: extract_symbolic_data
arguments: data_label: D51
data_type: string

tool: D40: Changing to menu item --> 

tool: D89: %s%c


tool: D75: Goodbye!

tool: D65: %s


tool: D51: Sorry, invalid option

assistant: ```c
int show_selection(char option) {
  switch (option) {
  case 'Q':
    printf("%s\n", "Goodbye!");
    break;
  case 'A':
    printf("%s%c\n", "Changing to menu item --> ", 'A');
    break;
  case 'B':
    printf("%s%c\n", "Changing to menu item --> ", 'B');
    break;
  case 'C':
    printf("%s%c\n", "Changing to menu item --> ", 'C');
    break;
  default:
    printf("%s\n", "Sorry, invalid option");
    break;
  }
  return (0);
}
```