user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  movl   $0x64,-0x30(%rbp)
  movsd  D57(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x30(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movq   $0x40000000,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x30(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,%esi
  lea    D112(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movb   $0x0,-0x31(%rbp)
  movsbl -0x31(%rbp),%eax
  mov    -0x30(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl -0x31(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  D15(%rip),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%rax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0xa,-0x28(%rbp)
  movl   $0xb,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D57
type_guessed: f64
name: retrieve_data
arguments: data_tag: D47
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D22
type_guessed: string
name: retrieve_data
arguments: data_tag: D112
type_guessed: string
name: retrieve_data
arguments: data_tag: D41
type_guessed: string
name: retrieve_data
arguments: data_tag: D15
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D59
type_guessed: string
name: retrieve_data
arguments: data_tag: D56
type_guessed: string
name: retrieve_data
arguments: data_tag: D98
type_guessed: string
name: retrieve_data
arguments: data_tag: D58
type_guessed: string

tool: D57: 1.2

tool: D47: You have %d bugs at the imaginari rate %f.


tool: D17: The entire of universe has %ld bugs.


tool: D22: You are expected to have %f bugs.


tool: D112: That is only a %e portion of the universe.


tool: D41: Which means you should care %d%%.


tool: {"D15": [0xcd,0xcc,0x44,0x41]}

tool: D59: Xablau %e


tool: D56: %c


tool: D98: %d


tool: D58: The total number is %d

assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("You have %d bugs at the imaginari rate %f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 1024L * 1024L * 1024L;
  printf("The entire of universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You are expected to have %f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char null_byte = '\0';
  int care_percentage = bugs * null_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  printf("Xablau %e\n", null_byte * 12.3f);
  printf("%c\n", '\0');
  printf("%d\n", '\0');
  printf("%d\n", 'a');
  unsigned int x = 10;
  unsigned y = 11;
  printf("The total number is %d", x * y);
  return 0;
}
```