ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<primes>:
  endbr64
  cmp    $0x2,%edi
  jle    L53
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax)
L45:
  xor    %esi,%esi
  mov    $0x2,%ecx
  cmp    $0x4,%r12d
  jle    L18
  nopl   (%rax)
L6:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %r12d,%eax
  jl     L6
  test   %esi,%esi
  je     L18
L54:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  jne    L45
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L18:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L54
L53:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: %d	

assistant: ```c
void primes(int cap) {
  int i, j, composite;
  for (i = 2; i < cap; ++i) {
    composite = 0;
    for (j = 2; j * j < i; ++j) {
      composite += !(i % j);
    }
    if (!composite) {
      printf("%d\t", i);
    }
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<primes>:
  endbr64
  cmp    $0x2,%edi
  jle    L60
  push   %r13
  mov    $0x4,%eax
  lea    -0x1(%rdi),%r13d
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r13d,%r12d
  jle    L2
  cmp    %r12d,%ebx
  jle    L46
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %esi,%esi
  mov    $0x2,%ecx
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %r12d,%eax
  jl     L25
  test   %esi,%esi
  je     L36
L3:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  jne    L1
L46:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L60:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: %d	

assistant: ```c
void primes(int cap) {
  int i, j, composite;
  for (i = 2; i < cap; ++i) {
    composite = 0;
    for (j = 2; j * j < i; ++j) {
      composite += !(i % j);
    }
    if (!composite) {
      printf("%d\t", i);
    }
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<qsolv>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movsd  %xmm2,0x10(%rsp)
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movapd %xmm1,%xmm3
  movsd  %xmm1,(%rsp)
  mulsd  %xmm1,%xmm3
  movsd  %xmm0,0x8(%rsp)
  mulsd  D72(%rip),%xmm0
  movapd %xmm0,%xmm5
  mulsd  %xmm2,%xmm5
  movapd %xmm5,%xmm7
  movsd  %xmm3,0x20(%rsp)
  movapd %xmm3,%xmm5
  movsd  %xmm7,0x28(%rsp)
  subsd  %xmm7,%xmm5
  movapd %xmm5,%xmm0
  movq   %xmm5,%r14
  call   <Sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm7
  addsd  %xmm2,%xmm7
  movsd  (%rsp),%xmm4
  subsd  %xmm4,%xmm0
  movsd  %xmm7,0x18(%rsp)
  divsd  %xmm7,%xmm0
  movsd  %xmm0,0x0(%rbp)
  movapd %xmm4,%xmm6
  xorpd  D69(%rip),%xmm6
  movq   %xmm6,%rbp
  movq   %r14,%xmm0
  call   <Sqrt@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  subsd  %xmm1,%xmm0
  divsd  0x18(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  movq   %r14,%xmm0
  call   <Sqrt@plt>
  subsd  (%rsp),%xmm0
  call   <isinf@plt>
  movsd  D72(%rip),%xmm0
  test   %rax,%rax
  je     L5
L62:
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L5:
  movq   %r14,%xmm0
  call   <Sqrt@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  subsd  %xmm1,%xmm0
  call   <isinf@plt>
  movsd  D72(%rip),%xmm0
  test   %rax,%rax
  jne    L62
  movsd  0x8(%rsp),%xmm0
  call   <isnan@plt>
  movsd  D20(%rip),%xmm0
  test   %rax,%rax
  jne    L62
  movsd  (%rsp),%xmm0
  call   <isnan@plt>
  movsd  D20(%rip),%xmm0
  test   %rax,%rax
  jne    L62
  movsd  0x10(%rsp),%xmm0
  call   <isnan@plt>
  movsd  D20(%rip),%xmm0
  test   %rax,%rax
  jne    L62
  movsd  D41(%rip),%xmm0
  movsd  0x28(%rsp),%xmm7
  comisd 0x20(%rsp),%xmm7
  ja     L62
  pxor   %xmm0,%xmm0
  jmp    L62
```

tool_calls: name: retrieve_data
arguments: data_tag: D72
datatype: f64
name: retrieve_data
arguments: data_tag: D69
datatype: byte[16]
name: retrieve_data
arguments: data_tag: D20
datatype: f64
name: retrieve_data
arguments: data_tag: D41
datatype: f64

tool: D72: 4

tool: {"D69": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D20: 3

tool: D41: 2

assistant: ```c
double qsolv(double a, double b, double c, double *x1, double *x2) {
  *x1 = (-b + Sqrt(b * b - 4 * a * c)) / (2 * a);
  *x2 = (-b - Sqrt(b * b - 4 * a * c)) / (2 * a);
  if (isinf(-b + Sqrt(b * b - 4 * a * c)) || isinf(-b - Sqrt(b * b - 4 * a * c)))
    return 4.0;
  if (isnan(a) || isnan(b) || isnan(c))
    return 3.0;
  if (b * b < 4 * a * c)
    return 2.0;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<qsolv>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm7
  movapd %xmm1,%xmm5
  mov    %rdi,%rbp
  push   %rbx
  mulsd  %xmm1,%xmm5
  mov    %rsi,%rbx
  sub    $0x48,%rsp
  movsd  D27(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  mulsd  %xmm7,%xmm0
  movapd %xmm5,%xmm1
  movsd  %xmm5,0x30(%rsp)
  movsd  %xmm2,0x28(%rsp)
  movsd  %xmm7,0x10(%rsp)
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm0,0x38(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  call   <Sqrt@plt>
  movsd  0x10(%rsp),%xmm7
  movsd  (%rsp),%xmm4
  movsd  0x18(%rsp),%xmm1
  movapd %xmm7,%xmm3
  subsd  %xmm4,%xmm0
  movapd %xmm4,%xmm6
  addsd  %xmm7,%xmm3
  xorpd  D32(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
  divsd  %xmm3,%xmm0
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm0,0x0(%rbp)
  movapd %xmm1,%xmm0
  call   <Sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm1
  subsd  %xmm0,%xmm2
  movapd %xmm1,%xmm0
  divsd  %xmm3,%xmm2
  movsd  %xmm2,(%rbx)
  call   <Sqrt@plt>
  subsd  (%rsp),%xmm0
  call   <isinf@plt>
  movsd  0x18(%rsp),%xmm1
  test   %rax,%rax
  je     L23
L13:
  mov    D27(%rip),%rax
  movq   %rax,%xmm0
L42:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  movapd %xmm1,%xmm0
  call   <Sqrt@plt>
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  jne    L13
  movsd  0x10(%rsp),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L44
L10:
  movsd  D44(%rip),%xmm0
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  movsd  (%rsp),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L10
  movsd  0x28(%rsp),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L10
  movsd  0x38(%rsp),%xmm5
  comisd 0x30(%rsp),%xmm5
  movsd  D49(%rip),%xmm0
  ja     L42
  pxor   %xmm0,%xmm0
  jmp    L42
```

tool_calls: name: parse_data
arguments: label: D27
type_infered: f64
name: parse_data
arguments: label: D32
type_infered: byte[16]
name: parse_data
arguments: label: D44
type_infered: f64
name: parse_data
arguments: label: D49
type_infered: f64

tool: D27: 4

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D44: 3

tool: D49: 2

assistant: ```c
double qsolv(double a, double b, double c, double *x1, double *x2) {
  *x1 = (-b + Sqrt(b * b - 4 * a * c)) / (2 * a);
  *x2 = (-b - Sqrt(b * b - 4 * a * c)) / (2 * a);
  if (isinf(-b + Sqrt(b * b - 4 * a * c)) || isinf(-b - Sqrt(b * b - 4 * a * c)))
    return 4.0;
  if (isnan(a) || isnan(b) || isnan(c))
    return 3.0;
  if (b * b < 4 * a * c)
    return 2.0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qsolv>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm7
  movapd %xmm1,%xmm5
  mov    %rdi,%rbp
  push   %rbx
  mulsd  %xmm1,%xmm5
  mov    %rsi,%rbx
  sub    $0x48,%rsp
  movsd  D5(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  mulsd  %xmm7,%xmm0
  movapd %xmm5,%xmm1
  movsd  %xmm5,0x30(%rsp)
  movsd  %xmm2,0x28(%rsp)
  movsd  %xmm7,0x10(%rsp)
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm0,0x38(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  call   <Sqrt@plt>
  movsd  0x10(%rsp),%xmm7
  movsd  (%rsp),%xmm4
  movsd  0x18(%rsp),%xmm1
  movapd %xmm7,%xmm3
  subsd  %xmm4,%xmm0
  movapd %xmm4,%xmm6
  addsd  %xmm7,%xmm3
  xorpd  D20(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
  divsd  %xmm3,%xmm0
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm0,0x0(%rbp)
  movapd %xmm1,%xmm0
  call   <Sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm1
  subsd  %xmm0,%xmm2
  movapd %xmm1,%xmm0
  divsd  %xmm3,%xmm2
  movsd  %xmm2,(%rbx)
  call   <Sqrt@plt>
  subsd  (%rsp),%xmm0
  call   <isinf@plt>
  movsd  0x18(%rsp),%xmm1
  test   %rax,%rax
  je     L16
L8:
  mov    D5(%rip),%rax
  movq   %rax,%xmm0
L22:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  movapd %xmm1,%xmm0
  call   <Sqrt@plt>
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  jne    L8
  movsd  0x10(%rsp),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L48
L1:
  movsd  D18(%rip),%xmm0
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  movsd  (%rsp),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L1
  movsd  0x28(%rsp),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L1
  movsd  0x38(%rsp),%xmm5
  comisd 0x30(%rsp),%xmm5
  movsd  D26(%rip),%xmm0
  ja     L22
  pxor   %xmm0,%xmm0
  jmp    L22
```

tool_calls: name: parse_data
arguments: tag: D5
type: f64
name: parse_data
arguments: tag: D20
type: byte[16]
name: parse_data
arguments: tag: D18
type: f64
name: parse_data
arguments: tag: D26
type: f64

tool: D5: 4

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D18: 3

tool: D26: 2

assistant: ```c
double qsolv(double a, double b, double c, double *x1, double *x2) {
  *x1 = (-b + Sqrt(b * b - 4 * a * c)) / (2 * a);
  *x2 = (-b - Sqrt(b * b - 4 * a * c)) / (2 * a);
  if (isinf(-b + Sqrt(b * b - 4 * a * c)) || isinf(-b - Sqrt(b * b - 4 * a * c)))
    return 4.0;
  if (isnan(a) || isnan(b) || isnan(c))
    return 3.0;
  if (b * b < 4 * a * c)
    return 2.0;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cantJugadores>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L14:
  mov    $0x14,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <getint@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L14
  cmpl   $0x14,-0x4(%rbp)
  jg     L14
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: Cuantos jugadores? ...(Maximo %d)... 

assistant: ```c
int cantJugadores(void) {
  int jugadores;
  do
    jugadores = getint("Cuantos jugadores? ...(Maximo %d)... ", 20);
  while (jugadores <= 0 || jugadores > 20);
  return jugadores;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cantJugadores>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
L4:
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <getint@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x13,%edx
  ja     L4
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: Cuantos jugadores? ...(Maximo %d)... 

assistant: ```c
int cantJugadores(void) {
  int jugadores;
  do
    jugadores = getint("Cuantos jugadores? ...(Maximo %d)... ", 20);
  while (jugadores <= 0 || jugadores > 20);
  return jugadores;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cantJugadores>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  nopl   0x0(%rax)
L8:
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <getint@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x13,%edx
  ja     L8
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D8: Cuantos jugadores? ...(Maximo %d)... 

assistant: ```c
int cantJugadores(void) {
  int jugadores;
  do
    jugadores = getint("Cuantos jugadores? ...(Maximo %d)... ", 20);
  while (jugadores <= 0 || jugadores > 20);
  return jugadores;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cantJugadores>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
  nopl   0x0(%rax)
L6:
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <getint@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x13,%edx
  ja     L6
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: Cuantos jugadores? ...(Maximo %d)... 

assistant: ```c
int cantJugadores(void) {
  int jugadores;
  do
    jugadores = getint("Cuantos jugadores? ...(Maximo %d)... ", 20);
  while (jugadores <= 0 || jugadores > 20);
  return jugadores;
}
```
user: What is the c source code of the assembly code below?

```asm
<setHue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  mov    %esi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L13:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <RGBtoHSL@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0x2c(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <HSLtoRGB@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x3,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void setHue(unsigned char *data, float value, int imageSize) {
  int i;
  for (i = 0; i < imageSize; i += 3) {
    float *hsl = RGBtoHSL(data[i], data[i + 1], data[i + 2]);
    hsl[0] *= value;
    int *rgb = HSLtoRGB(hsl[0], hsl[1], hsl[2]);
    data[i] = rgb[0];
    data[i + 1] = rgb[1];
    data[i + 2] = rgb[2];
    free(rgb);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setHue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  test   %esi,%esi
  jle    L10
  mov    %esi,%r12d
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L1:
  movzbl 0x2(%rbx),%edx
  movzbl 0x1(%rbx),%esi
  movzbl (%rbx),%edi
  call   <RGBtoHSL@plt>
  movss  0xc(%rsp),%xmm0
  mulss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  movss  0x8(%rax),%xmm2
  movss  0x4(%rax),%xmm1
  call   <HSLtoRGB@plt>
  mov    %rax,%rdi
  mov    (%rax),%eax
  mov    %al,(%rbx)
  mov    0x4(%rdi),%eax
  mov    %al,0x1(%rbx)
  mov    0x8(%rdi),%eax
  mov    %al,0x2(%rbx)
  call   <free@plt>
  add    $0x3,%ebp
  add    $0x3,%rbx
  cmp    %ebp,%r12d
  jg     L1
L10:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void setHue(unsigned char *data, float value, int imageSize) {
  int i;
  for (i = 0; i < imageSize; i += 3) {
    float *hsl = RGBtoHSL(data[i], data[i + 1], data[i + 2]);
    hsl[0] *= value;
    int *rgb = HSLtoRGB(hsl[0], hsl[1], hsl[2]);
    data[i] = rgb[0];
    data[i + 1] = rgb[1];
    data[i + 2] = rgb[2];
    free(rgb);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setHue>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r14
  movd   %xmm0,%r14d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nop
L11:
  movzbl 0x2(%rbx),%edx
  movzbl 0x1(%rbx),%esi
  add    $0x3,%r12d
  add    $0x3,%rbx
  movzbl -0x3(%rbx),%edi
  call   <RGBtoHSL@plt>
  movd   %r14d,%xmm0
  mulss  (%rax),%xmm0
  movss  0x8(%rax),%xmm2
  movss  0x4(%rax),%xmm1
  movss  %xmm0,(%rax)
  call   <HSLtoRGB@plt>
  mov    %rax,%rdi
  mov    (%rax),%eax
  mov    %al,-0x3(%rbx)
  mov    0x4(%rdi),%eax
  mov    %al,-0x2(%rbx)
  mov    0x8(%rdi),%eax
  mov    %al,-0x1(%rbx)
  call   <free@plt>
  cmp    %r12d,%ebp
  jg     L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  xchg   %ax,%ax
L18:
  ret
```

assistant: ```c
void setHue(unsigned char *data, float value, int imageSize) {
  int i;
  for (i = 0; i < imageSize; i += 3) {
    float *hsl = RGBtoHSL(data[i], data[i + 1], data[i + 2]);
    hsl[0] *= value;
    int *rgb = HSLtoRGB(hsl[0], hsl[1], hsl[2]);
    data[i] = rgb[0];
    data[i + 1] = rgb[1];
    data[i + 2] = rgb[2];
    free(rgb);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setHue>:
  endbr64
  test   %esi,%esi
  jle    L13
  push   %r14
  movd   %xmm0,%r14d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nop
L3:
  movzbl 0x2(%rbx),%edx
  movzbl 0x1(%rbx),%esi
  add    $0x3,%r12d
  add    $0x3,%rbx
  movzbl -0x3(%rbx),%edi
  call   <RGBtoHSL@plt>
  movd   %r14d,%xmm0
  mulss  (%rax),%xmm0
  movss  0x8(%rax),%xmm2
  movss  0x4(%rax),%xmm1
  movss  %xmm0,(%rax)
  call   <HSLtoRGB@plt>
  mov    %rax,%rdi
  mov    (%rax),%eax
  mov    %al,-0x3(%rbx)
  mov    0x4(%rdi),%eax
  mov    %al,-0x2(%rbx)
  mov    0x8(%rdi),%eax
  mov    %al,-0x1(%rbx)
  call   <free@plt>
  cmp    %r12d,%ebp
  jg     L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  xchg   %ax,%ax
L13:
  ret
```

assistant: ```c
void setHue(unsigned char *data, float value, int imageSize) {
  int i;
  for (i = 0; i < imageSize; i += 3) {
    float *hsl = RGBtoHSL(data[i], data[i + 1], data[i + 2]);
    hsl[0] *= value;
    int *rgb = HSLtoRGB(hsl[0], hsl[1], hsl[2]);
    data[i] = rgb[0];
    data[i + 1] = rgb[1];
    data[i + 2] = rgb[2];
    free(rgb);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<e_lsr_zpx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <e_zpx@plt>
  mov    $0x0,%eax
  call   <e_lsr@plt>
  mov    $0x0,%eax
  call   <e_writeback@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void e_lsr_zpx() {
  e_zpx();
  e_lsr();
  e_writeback();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<e_lsr_zpx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <e_zpx@plt>
  mov    $0x0,%eax
  call   <e_lsr@plt>
  mov    $0x0,%eax
  call   <e_writeback@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void e_lsr_zpx() {
  e_zpx();
  e_lsr();
  e_writeback();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<e_lsr_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_zpx@plt>
  xor    %eax,%eax
  call   <e_lsr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <e_writeback@plt>
```

assistant: ```c
void e_lsr_zpx() {
  e_zpx();
  e_lsr();
  e_writeback();
}
```
user: Translate the below assembly code into C programming language:

```asm
<e_lsr_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_zpx@plt>
  xor    %eax,%eax
  call   <e_lsr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <e_writeback@plt>
```

assistant: ```c
void e_lsr_zpx() {
  e_zpx();
  e_lsr();
  e_writeback();
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_unescape>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L1
  lea    0x1(%rax),%rax
  lea    D2(%rip),%r9
  jmp    L178
L105:
  lea    0x1(%rbx),%rdx
  movzbl 0x1(%rbx),%esi
  lea    -0x30(%rsi),%ecx
  cmp    $0x46,%cl
  ja     L0
  movzbl %cl,%ecx
  movslq (%r9,%rcx,4),%rcx
  add    %r9,%rcx
  notrack jmp *%rcx
  mov    %rax,%rcx
  movb   $0x0,-0x1(%rax)
  lea    0x4(%rbx),%rsi
  mov    %rdx,%r10
  cmp    %rsi,%rdx
  jae    L70
  mov    %rsi,%r10
L56:
  movzbl (%rdx),%r8d
  lea    -0x30(%r8),%esi
  cmp    $0x7,%sil
  ja     L4
  movzbl -0x1(%rcx),%esi
  lea    -0x30(%r8,%rsi,8),%esi
  mov    %sil,-0x1(%rcx)
  add    $0x1,%rdx
  cmp    %rdx,%r10
  jne    L56
L70:
  lea    -0x1(%r10),%rdx
L75:
  lea    0x1(%rdx),%rbx
  movzbl 0x1(%rdx),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L89
L178:
  cmp    $0x5c,%dl
  je     L105
  mov    %rax,%rcx
  mov    %dl,-0x1(%rax)
  mov    %rbx,%rdx
  jmp    L75
L4:
  mov    %rdx,%r10
  jmp    L70
  mov    %rax,%rcx
  movb   $0x7,-0x1(%rax)
  jmp    L75
  mov    %rax,%rcx
  movb   $0x8,-0x1(%rax)
  jmp    L75
  mov    %rax,%rcx
  movb   $0xc,-0x1(%rax)
  jmp    L75
  mov    %rax,%rcx
  movb   $0xa,-0x1(%rax)
  jmp    L75
  mov    %rax,%rcx
  movb   $0xd,-0x1(%rax)
  jmp    L75
  mov    %rax,%rcx
  movb   $0x9,-0x1(%rax)
  jmp    L75
  mov    %rax,%rcx
  movb   $0xb,-0x1(%rax)
  jmp    L75
L0:
  mov    %rax,%rcx
  mov    %sil,-0x1(%rax)
  jmp    L75
L1:
  mov    %rax,%rcx
L89:
  movb   $0x0,(%rcx)
  mov    %rdi,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *str_unescape(const char *source) {
  const char *p = source;
  const char *octal;
  char *dest = calloc(strlen(source) + 1, sizeof(char));
  char *q = dest;
  while (*p) {
    if (*p == '\\') {
      p++;
      switch (*p) {
      case '0' ... '7':
        *q = 0;
        octal = p;
        while ((p < octal + 3) && (*p >= '0') && (*p <= '7')) {
          *q = (*q * 8) + (*p - '0');
          p++;
        }
        q++;
        p--;
        break;
      case 'a':
        *q++ = '\a';
        break;
      case 'b':
        *q++ = '\b';
        break;
      case 'f':
        *q++ = '\f';
        break;
      case 'n':
        *q++ = '\n';
        break;
      case 'r':
        *q++ = '\r';
        break;
      case 't':
        *q++ = '\t';
        break;
      case 'v':
        *q++ = '\v';
        break;
      default:
        *q++ = *p;
        break;
      }
    } else {
      *q++ = *p;
    }
    p++;
  }
  *q = 0;
  return dest;
}
```