ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<findbreak>:
  endbr64
  cmp    %edx,%esi
  jg     L15
  movslq %esi,%rax
  lea    0x1(%rsi),%r8d
  lea    -0x1(%rdx),%r10d
  mov    %esi,%ecx
  add    %rax,%rdi
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L4:
  cmp    $0xa,%al
  je     L68
  test   %al,%al
  je     L35
  mov    %r8d,%r9d
  cmp    $0x2d,%al
  jne    L9
  cmp    %ecx,%r10d
  cmovg  %r8d,%esi
L7:
  add    $0x1,%rdi
  add    $0x1,%ecx
  add    $0x1,%r8d
  cmp    %r9d,%edx
  jl     L15
L20:
  movzbl (%rdi),%eax
  mov    %ecx,%r9d
  cmp    $0x9,%al
  jne    L4
  mov    %r8d,%r9d
  movb   $0x20,(%rdi)
  add    $0x1,%ecx
  add    $0x1,%rdi
  add    $0x1,%r8d
  cmp    %r9d,%edx
  jge    L20
L15:
  mov    %esi,%r9d
L35:
  mov    %r9d,%eax
  ret
  nopl   (%rax)
L9:
  cmp    $0x20,%al
  cmove  %ecx,%esi
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L68:
  movb   $0x20,(%rdi)
  mov    %r9d,%eax
  ret
```

assistant: ```c
int findbreak(msg, min, max)
char *msg;
int min;
int max;
{
  int i, spot;
  char c;
  for (i = spot = min; i <= max; i++) {
    c = msg[i];
    if (c == '\t')
      msg[i] = ' ';
    if (c == '\n') {
      msg[i] = ' ';
      spot = i;
      break;
    }
    if (c == 0) {
      spot = i;
      break;
    }
    if (c == '-' && i < max - 1)
      spot = i + 1;
    if (c == ' ')
      spot = i;
  }
  return spot;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findbreak>:
  endbr64
  cmp    %edx,%esi
  jg     L47
  movslq %esi,%rax
  lea    0x1(%rsi),%r8d
  lea    -0x1(%rdx),%r10d
  mov    %esi,%ecx
  add    %rax,%rdi
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L7:
  cmp    $0xa,%al
  je     L49
  test   %al,%al
  je     L17
  mov    %r8d,%r9d
  cmp    $0x2d,%al
  jne    L75
  cmp    %ecx,%r10d
  cmovg  %r8d,%esi
L52:
  add    $0x1,%rdi
  add    $0x1,%ecx
  add    $0x1,%r8d
  cmp    %r9d,%edx
  jl     L47
L22:
  movzbl (%rdi),%eax
  mov    %ecx,%r9d
  cmp    $0x9,%al
  jne    L7
  mov    %r8d,%r9d
  movb   $0x20,(%rdi)
  add    $0x1,%ecx
  add    $0x1,%rdi
  add    $0x1,%r8d
  cmp    %r9d,%edx
  jge    L22
L47:
  mov    %esi,%r9d
L17:
  mov    %r9d,%eax
  ret
  nopl   (%rax)
L75:
  cmp    $0x20,%al
  cmove  %ecx,%esi
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L49:
  movb   $0x20,(%rdi)
  mov    %r9d,%eax
  ret
```

assistant: ```c
int findbreak(msg, min, max)
char *msg;
int min;
int max;
{
  int i, spot;
  char c;
  for (i = spot = min; i <= max; i++) {
    c = msg[i];
    if (c == '\t')
      msg[i] = ' ';
    if (c == '\n') {
      msg[i] = ' ';
      spot = i;
      break;
    }
    if (c == 0) {
      spot = i;
      break;
    }
    if (c == '-' && i < max - 1)
      spot = i + 1;
    if (c == ' ')
      spot = i;
  }
  return spot;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <setup@plt>
L4:
  mov    $0x0,%eax
  call   <keyscanner_main@plt>
  jmp    L4
```

assistant: ```c
int main(void) {
  setup();
  while (1) {
    keyscanner_main();
  }
  __builtin_unreachable();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <setup@plt>
L1:
  mov    $0x0,%eax
  call   <keyscanner_main@plt>
  jmp    L1
```

assistant: ```c
int main(void) {
  setup();
  while (1) {
    keyscanner_main();
  }
  __builtin_unreachable();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup@plt>
  nop
L4:
  xor    %eax,%eax
  call   <keyscanner_main@plt>
  jmp    L4
```

assistant: ```c
int main(void) {
  setup();
  while (1) {
    keyscanner_main();
  }
  __builtin_unreachable();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup@plt>
  nop
L9:
  xor    %eax,%eax
  call   <keyscanner_main@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  setup();
  while (1) {
    keyscanner_main();
  }
  __builtin_unreachable();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<FlashMassErase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400fd014,%eax
  movq   $0xa01,(%rax)
  mov    $0x400fd008,%eax
  mov    $0xa4420004,%edx
  mov    %rdx,(%rax)
  nop
L16:
  mov    $0x400fd008,%eax
  mov    (%rax),%rax
  and    $0x4,%eax
  test   %rax,%rax
  jne    L16
  mov    $0x400fd00c,%eax
  mov    (%rax),%rax
  and    $0xa01,%eax
  test   %rax,%rax
  je     L7
  mov    $0xffffffffffffffff,%rax
  jmp    L12
L7:
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
long FlashMassErase() {
  (*((volatile unsigned long *)(0x400FD000 + 0x00000014))) = (0x00000001 | 0x00000200 | 0x00000800);
  (*((volatile unsigned long *)(0x400FD000 + 0x00000008))) = 0xA4420000 | 0x00000004;
  while ((*((volatile unsigned long *)(0x400FD000 + 0x00000008))) & 0x00000004) {
  }
  if ((*((volatile unsigned long *)(0x400FD000 + 0x0000000C))) & (0x00000001 | 0x00000200 | 0x00000800)) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<FlashMassErase>:
  endbr64
  movq   $0xa01,0x400fd014
  mov    $0xa4420004,%eax
  mov    %rax,0x400fd008
L9:
  mov    0x400fd008,%rax
  test   $0x4,%al
  jne    L9
  mov    0x400fd00c,%rax
  test   $0xa01,%eax
  setne  %al
  movzbl %al,%eax
  neg    %rax
  ret
```

assistant: ```c
long FlashMassErase() {
  (*((volatile unsigned long *)(0x400FD000 + 0x00000014))) = (0x00000001 | 0x00000200 | 0x00000800);
  (*((volatile unsigned long *)(0x400FD000 + 0x00000008))) = 0xA4420000 | 0x00000004;
  while ((*((volatile unsigned long *)(0x400FD000 + 0x00000008))) & 0x00000004) {
  }
  if ((*((volatile unsigned long *)(0x400FD000 + 0x0000000C))) & (0x00000001 | 0x00000200 | 0x00000800)) {
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<FlashMassErase>:
  endbr64
  mov    $0xa4420004,%eax
  movq   $0xa01,0x400fd014
  mov    %rax,0x400fd008
  nopl   (%rax)
L3:
  mov    0x400fd008,%rax
  test   $0x4,%al
  jne    L3
  mov    0x400fd00c,%rax
  test   $0xa01,%eax
  setne  %al
  movzbl %al,%eax
  neg    %rax
  ret
```

assistant: ```c
long FlashMassErase() {
  (*((volatile unsigned long *)(0x400FD000 + 0x00000014))) = (0x00000001 | 0x00000200 | 0x00000800);
  (*((volatile unsigned long *)(0x400FD000 + 0x00000008))) = 0xA4420000 | 0x00000004;
  while ((*((volatile unsigned long *)(0x400FD000 + 0x00000008))) & 0x00000004) {
  }
  if ((*((volatile unsigned long *)(0x400FD000 + 0x0000000C))) & (0x00000001 | 0x00000200 | 0x00000800)) {
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FlashMassErase>:
  endbr64
  mov    $0xa4420004,%eax
  movq   $0xa01,0x400fd014
  mov    %rax,0x400fd008
  nopl   (%rax)
L9:
  mov    0x400fd008,%rax
  test   $0x4,%al
  jne    L9
  mov    0x400fd00c,%rax
  test   $0xa01,%eax
  setne  %al
  movzbl %al,%eax
  neg    %rax
  ret
```

assistant: ```c
long FlashMassErase() {
  (*((volatile unsigned long *)(0x400FD000 + 0x00000014))) = (0x00000001 | 0x00000200 | 0x00000800);
  (*((volatile unsigned long *)(0x400FD000 + 0x00000008))) = 0xA4420000 | 0x00000004;
  while ((*((volatile unsigned long *)(0x400FD000 + 0x00000008))) & 0x00000004) {
  }
  if ((*((volatile unsigned long *)(0x400FD000 + 0x0000000C))) & (0x00000001 | 0x00000200 | 0x00000800)) {
    return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_to_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L11
L2:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1b(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x1a(%rbp)
  movb   $0x0,-0x19(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0x1b(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,(%rbx)
  addq   $0x2,-0x28(%rbp)
  addl   $0x1,-0x2c(%rbp)
L11:
  mov    -0x2c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L2
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int str_to_bin(uint8_t *data, char *hexstring, int len) {
  char *pos = hexstring;
  for (int count = 0; count < len; count++) {
    char buf[3] = {pos[0], pos[1], 0};
    data[count] = (uint8_t)strtol(buf, NULL, 16);
    pos += 2;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_to_bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L23
  mov    %rsi,%rbx
  mov    %rdi,%rbp
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%r13
  lea    0x5(%rsp),%r12
L14:
  movzbl (%rbx),%eax
  mov    %al,0x5(%rsp)
  movzbl 0x1(%rbx),%eax
  mov    %al,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %rax,0x0(%rbp)
  add    $0x2,%rbx
  add    $0x8,%rbp
  cmp    %r13,%rbx
  jne    L14
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_to_bin(uint8_t *data, char *hexstring, int len) {
  char *pos = hexstring;
  for (int count = 0; count < len; count++) {
    char buf[3] = {pos[0], pos[1], 0};
    data[count] = (uint8_t)strtol(buf, NULL, 16);
    pos += 2;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_to_bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L18
  movslq %edx,%rdx
  mov    %rsi,%rbx
  lea    0x5(%rsp),%r12
  mov    %rdi,%rbp
  lea    (%rsi,%rdx,2),%r13
  nopl   0x0(%rax)
L1:
  movzbl (%rbx),%eax
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  movb   $0x0,0x7(%rsp)
  add    $0x2,%rbx
  add    $0x8,%rbp
  mov    %al,0x5(%rsp)
  movzbl -0x1(%rbx),%eax
  mov    %al,0x6(%rsp)
  call   <strtol@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r13,%rbx
  jne    L1
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_to_bin(uint8_t *data, char *hexstring, int len) {
  char *pos = hexstring;
  for (int count = 0; count < len; count++) {
    char buf[3] = {pos[0], pos[1], 0};
    data[count] = (uint8_t)strtol(buf, NULL, 16);
    pos += 2;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_to_bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L6
  movslq %edx,%rdx
  mov    %rsi,%rbx
  lea    0x4(%rsp),%r12
  mov    %rdi,%rbp
  lea    (%rsi,%rdx,2),%r13
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  mov    (%rbx),%al
  mov    0x1(%rbx),%ah
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  movb   $0x0,0x6(%rsp)
  add    $0x2,%rbx
  mov    %ax,0x4(%rsp)
  add    $0x8,%rbp
  call   <strtol@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r13,%rbx
  jne    L7
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_to_bin(uint8_t *data, char *hexstring, int len) {
  char *pos = hexstring;
  for (int count = 0; count < len; count++) {
    char buf[3] = {pos[0], pos[1], 0};
    data[count] = (uint8_t)strtol(buf, NULL, 16);
    pos += 2;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x100000(%rsp),%r11
L44:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L44
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <mo_init@plt>
  test   %rax,%rax
  jns    L72
  mov    $0xffffffff,%eax
  jmp    L34
L72:
  movl   $0x1,-0x100014(%rbp)
  jmp    L62
L56:
  mov    -0x100014(%rbp),%eax
  mov    %eax,%edi
  call   <mo_malloc@plt>
  mov    -0x100014(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x100010(%rbp,%rdx,8)
  addl   $0x1,-0x100014(%rbp)
L62:
  cmpl   $0x1ffff,-0x100014(%rbp)
  jle    L56
  movl   $0x1,-0x100014(%rbp)
  jmp    L25
L76:
  mov    -0x100014(%rbp),%eax
  cltq
  mov    -0x100010(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <mo_free@plt>
  addl   $0x1,-0x100014(%rbp)
L25:
  cmpl   $0x1ffff,-0x100014(%rbp)
  jle    L76
  mov    $0x0,%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

assistant: ```c
int main(void) {
  if (mo_init() < 0)
    return -1;
  int i;
  char *buf[(1 << 17)];
  for (i = 1; i < (1 << 17); i++) {
    buf[i] = mo_malloc(i);
  }
  for (i = 1; i < (1 << 17); i++) {
    mo_free(buf[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x100000(%rsp),%r11
L49:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L49
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x100008(%rsp)
  xor    %eax,%eax
  call   <mo_init@plt>
  test   %rax,%rax
  js     L18
  mov    $0x1,%ebx
L30:
  mov    %ebx,%edi
  call   <mo_malloc@plt>
  mov    %rax,(%rsp,%rbx,8)
  add    $0x1,%rbx
  cmp    $0x20000,%rbx
  jne    L30
  lea    0x8(%rsp),%rbx
  lea    0x100000(%rsp),%rbp
L15:
  mov    (%rbx),%rdi
  call   <mo_free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L15
  mov    $0x0,%eax
L54:
  mov    0x100008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x100018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L54
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  if (mo_init() < 0)
    return -1;
  int i;
  char *buf[(1 << 17)];
  for (i = 1; i < (1 << 17); i++) {
    buf[i] = mo_malloc(i);
  }
  for (i = 1; i < (1 << 17); i++) {
    mo_free(buf[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x100000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x100008(%rsp)
  xor    %eax,%eax
  call   <mo_init@plt>
  test   %rax,%rax
  js     L55
  mov    $0x1,%ebx
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %ebx,%edi
  call   <mo_malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    $0x20000,%rbx
  jne    L27
  lea    0x8(%rsp),%rbx
  lea    0x100000(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <mo_free@plt>
  cmp    %rbp,%rbx
  jne    L41
  xor    %eax,%eax
L35:
  mov    0x100008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x100018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  or     $0xffffffff,%eax
  jmp    L35
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  if (mo_init() < 0)
    return -1;
  int i;
  char *buf[(1 << 17)];
  for (i = 1; i < (1 << 17); i++) {
    buf[i] = mo_malloc(i);
  }
  for (i = 1; i < (1 << 17); i++) {
    mo_free(buf[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x100000(%rsp),%r11
L55:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L55
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x100008(%rsp)
  xor    %eax,%eax
  call   <mo_init@plt>
  test   %rax,%rax
  js     L5
  mov    $0x1,%ebx
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %ebx,%edi
  call   <mo_malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    $0x20000,%rbx
  jne    L45
  lea    0x8(%rsp),%rbx
  lea    0x100000(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <mo_free@plt>
  cmp    %rbp,%rbx
  jne    L19
  xor    %eax,%eax
L50:
  mov    0x100008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x100018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  or     $0xffffffff,%eax
  jmp    L50
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  if (mo_init() < 0)
    return -1;
  int i;
  char *buf[(1 << 17)];
  for (i = 1; i < (1 << 17); i++) {
    buf[i] = mo_malloc(i);
  }
  for (i = 1; i < (1 << 17); i++) {
    mo_free(buf[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_fstat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _fstat(int file, struct stat *st) {
  errno = ENOTSUP;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_fstat>:
  endbr64
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fstat(int file, struct stat *st) {
  errno = ENOTSUP;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_fstat>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fstat(int file, struct stat *st) {
  errno = ENOTSUP;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<_fstat>:
  endbr64
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _fstat(int file, struct stat *st) {
  errno = ENOTSUP;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setToNull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L33
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L7
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <Safe_free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L36
L33:
  nop
  jmp    L36
L7:
  nop
L36:
  leave
  ret
```

assistant: ```c
void setToNull(void **item) {
  if (!item)
    return;
  if (!*item)
    return;
  Safe_free(*item);
  *item = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<setToNull>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L16
  call   <Safe_free@plt>
  movq   $0x0,(%rbx)
L16:
  pop    %rbx
  ret
L9:
  ret
```

assistant: ```c
void setToNull(void **item) {
  if (!item)
    return;
  if (!*item)
    return;
  Safe_free(*item);
  *item = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setToNull>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L10
  call   <Safe_free@plt>
  movq   $0x0,(%rbx)
L10:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
void setToNull(void **item) {
  if (!item)
    return;
  if (!*item)
    return;
  Safe_free(*item);
  *item = NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<setToNull>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  call   <Safe_free@plt>
  movq   $0x0,(%rbx)
L4:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void setToNull(void **item) {
  if (!item)
    return;
  if (!*item)
    return;
  Safe_free(*item);
  *item = NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_status_no_robust>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <pthread_mutexattr_setrobust@plt>
  test   %rax,%rax
  jne    L49
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pthread_mutex_init@plt>
  test   %rax,%rax
  jne    L49
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_lock@plt>
  test   %rax,%rax
  jne    L49
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_unlock@plt>
  test   %rax,%rax
  jne    L49
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_destroy@plt>
  test   %rax,%rax
  jne    L49
  movl   $0x0,-0x4(%rbp)
L49:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int test_status_no_robust(pthread_mutex_t *mutex, pthread_mutexattr_t *attr) {
  int result = 1;
  if (pthread_mutexattr_setrobust(attr, PTHREAD_MUTEX_STALLED) == 0 && pthread_mutex_init(mutex, attr) == 0 && pthread_mutex_lock(mutex) == 0 && pthread_mutex_unlock(mutex) == 0 && pthread_mutex_destroy(mutex) == 0)
    result = 0;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_status_no_robust>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <pthread_mutexattr_setrobust@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L42
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L42:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <pthread_mutex_init@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L12
  mov    %rbp,%rdi
  call   <pthread_mutex_lock@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L12
  mov    %rbp,%rdi
  call   <pthread_mutex_unlock@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L12
  mov    %rbp,%rdi
  call   <pthread_mutex_destroy@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L12
```

assistant: ```c
int test_status_no_robust(pthread_mutex_t *mutex, pthread_mutexattr_t *attr) {
  int result = 1;
  if (pthread_mutexattr_setrobust(attr, PTHREAD_MUTEX_STALLED) == 0 && pthread_mutex_init(mutex, attr) == 0 && pthread_mutex_lock(mutex) == 0 && pthread_mutex_unlock(mutex) == 0 && pthread_mutex_destroy(mutex) == 0)
    result = 0;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_status_no_robust>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <pthread_mutexattr_setrobust@plt>
  test   %rax,%rax
  je     L9
L13:
  mov    $0x1,%eax
L33:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <pthread_mutex_init@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rdi
  call   <pthread_mutex_lock@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rdi
  call   <pthread_mutex_unlock@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rdi
  call   <pthread_mutex_destroy@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L33
```

assistant: ```c
int test_status_no_robust(pthread_mutex_t *mutex, pthread_mutexattr_t *attr) {
  int result = 1;
  if (pthread_mutexattr_setrobust(attr, PTHREAD_MUTEX_STALLED) == 0 && pthread_mutex_init(mutex, attr) == 0 && pthread_mutex_lock(mutex) == 0 && pthread_mutex_unlock(mutex) == 0 && pthread_mutex_destroy(mutex) == 0)
    result = 0;
  return result;
}
```