ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<decToBinUl>:
  endbr64
  test   %rdi,%rdi
  je     L9
  xor    %edx,%edx
  mov    $0x1,%eax
L35:
  add    %rax,%rax
  mov    %edx,%r8d
  lea    0x1(%rdx),%edx
  cmp    %rax,%rdi
  jae    L35
  movslq %r8d,%rdx
  shr    %rax
  lea    0x4(%rsi,%rdx,4),%rcx
L27:
  mov    %rdi,%rdx
  sub    %rax,%rdx
  js     L1
L19:
  movl   $0x1,(%rsi)
  add    $0x4,%rsi
  shr    %rax
  cmp    %rsi,%rcx
  je     L24
  mov    %rdx,%rdi
  mov    %rdi,%rdx
  sub    %rax,%rdx
  jns    L19
L1:
  movl   $0x0,(%rsi)
  add    $0x4,%rsi
  shr    %rax
  cmp    %rcx,%rsi
  jne    L27
L24:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L9:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int decToBinUl(unsigned long long n, int binary[]) {
  unsigned long long i = 1;
  int y = 0, x = 0;
  while (i <= n) {
    i *= 2;
    x++;
  }
  i /= 2;
  x--;
  for (y = x; y >= 0; y--) {
    if ((long)(n - i) >= 0) {
      n -= i;
      binary[x - y] = 1;
    } else {
      binary[x - y] = 0;
    }
    i /= 2;
  }
  return (int)x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<op_ED_0x54>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <NEG@plt>
  mov    $0x4,%edi
  call   <T_WAIT_UNTIL@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void op_ED_0x54(void) {
  NEG();
  T_WAIT_UNTIL(4);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_ED_0x54>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <NEG@plt>
  mov    $0x4,%edi
  call   <T_WAIT_UNTIL@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void op_ED_0x54(void) {
  NEG();
  T_WAIT_UNTIL(4);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_ED_0x54>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <NEG@plt>
  mov    $0x4,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_ED_0x54(void) {
  NEG();
  T_WAIT_UNTIL(4);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<op_ED_0x54>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <NEG@plt>
  mov    $0x4,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_ED_0x54(void) {
  NEG();
  T_WAIT_UNTIL(4);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <init@plt>
  mov    $0x0,%eax
  call   <finalise@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init(argc, argv);
  finalise();
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <init@plt>
  mov    $0x0,%eax
  call   <finalise@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init(argc, argv);
  finalise();
  return EXIT_SUCCESS;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <init@plt>
  xor    %eax,%eax
  call   <finalise@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init(argc, argv);
  finalise();
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <init@plt>
  xor    %eax,%eax
  call   <finalise@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init(argc, argv);
  finalise();
  return EXIT_SUCCESS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<curses_str_cap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <tigetstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L8
L4:
  mov    -0x8(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
char *curses_str_cap(const char *name) {
  char *str = tigetstr((char *)name);
  if (str == (char *)-1) {
    return NULL;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<curses_str_cap>:
  endbr64
  sub    $0x8,%rsp
  call   <tigetstr@plt>
  cmp    $0xffffffffffffffff,%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *curses_str_cap(const char *name) {
  char *str = tigetstr((char *)name);
  if (str == (char *)-1) {
    return NULL;
  }
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<curses_str_cap>:
  endbr64
  sub    $0x8,%rsp
  call   <tigetstr@plt>
  xor    %edx,%edx
  cmp    $0xffffffffffffffff,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *curses_str_cap(const char *name) {
  char *str = tigetstr((char *)name);
  if (str == (char *)-1) {
    return NULL;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<curses_str_cap>:
  endbr64
  sub    $0x8,%rsp
  call   <tigetstr@plt>
  xor    %edx,%edx
  cmp    $0xffffffffffffffff,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *curses_str_cap(const char *name) {
  char *str = tigetstr((char *)name);
  if (str == (char *)-1) {
    return NULL;
  }
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<asn1_print_boolean_ctx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  je     L66
  cmpl   $0x0,-0x1c(%rbp)
  je     L16
  jmp    L64
L66:
  lea    D20(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L62
L16:
  lea    D15(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L62
L64:
  lea    D23(%rip),%rax
  mov    %rax,-0x8(%rbp)
  nop
L62:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_puts@plt>
  test   %rax,%rax
  jg     L41
  mov    $0x0,%eax
  jmp    L43
L41:
  mov    $0x1,%eax
L43:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D20
datatype: string
name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D23
datatype: string

tool: D20: BOOL ABSENT

tool: D15: FALSE

tool: D23: TRUE

assistant: ```c
int asn1_print_boolean_ctx(BIO *out, int boolval, const ASN1_PCTX *pctx) {
  const char *str;
  switch (boolval) {
  case -1:
    str = "BOOL ABSENT";
    break;
  case 0:
    str = "FALSE";
    break;
  default:
    str = "TRUE";
    break;
  }
  if (BIO_puts(out, str) <= 0)
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<asn1_print_boolean_ctx>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  lea    D8(%rip),%rsi
  cmp    $0xffffffff,%eax
  je     L5
  test   %eax,%eax
  lea    D27(%rip),%rsi
  lea    D21(%rip),%rax
  cmove  %rax,%rsi
L5:
  call   <BIO_puts@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D27
datatype: string
name: parse_data
arguments: tag: D21
datatype: string

tool: D8: BOOL ABSENT

tool: D27: TRUE

tool: D21: FALSE

assistant: ```c
int asn1_print_boolean_ctx(BIO *out, int boolval, const ASN1_PCTX *pctx) {
  const char *str;
  switch (boolval) {
  case -1:
    str = "BOOL ABSENT";
    break;
  case 0:
    str = "FALSE";
    break;
  default:
    str = "TRUE";
    break;
  }
  if (BIO_puts(out, str) <= 0)
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<asn1_print_boolean_ctx>:
  endbr64
  mov    %esi,%eax
  sub    $0x8,%rsp
  lea    D10(%rip),%rsi
  cmp    $0xffffffff,%eax
  je     L3
  test   %eax,%eax
  lea    D29(%rip),%rsi
  lea    D16(%rip),%rax
  cmove  %rax,%rsi
L3:
  call   <BIO_puts@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D29
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string

tool: D10: BOOL ABSENT

tool: D29: TRUE

tool: D16: FALSE

assistant: ```c
int asn1_print_boolean_ctx(BIO *out, int boolval, const ASN1_PCTX *pctx) {
  const char *str;
  switch (boolval) {
  case -1:
    str = "BOOL ABSENT";
    break;
  case 0:
    str = "FALSE";
    break;
  default:
    str = "TRUE";
    break;
  }
  if (BIO_puts(out, str) <= 0)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<asn1_print_boolean_ctx>:
  endbr64
  mov    %esi,%eax
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  cmp    $0xffffffff,%eax
  je     L4
  test   %eax,%eax
  lea    D15(%rip),%rsi
  lea    D10(%rip),%rax
  cmove  %rax,%rsi
L4:
  call   <BIO_puts@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D2: BOOL ABSENT

tool: D15: TRUE

tool: D10: FALSE

assistant: ```c
int asn1_print_boolean_ctx(BIO *out, int boolval, const ASN1_PCTX *pctx) {
  const char *str;
  switch (boolval) {
  case -1:
    str = "BOOL ABSENT";
    break;
  case 0:
    str = "FALSE";
    break;
  default:
    str = "TRUE";
    break;
  }
  if (BIO_puts(out, str) <= 0)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<append_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L29:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L29
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L0
L3:
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
L0:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L3
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *append_number(char *target, int num) {
  int n = 0, i = 0;
  do {
    target[n++] = (num % 10) + '0';
    num /= 10;
  } while (num);
  target[n] = 0;
  while ((n - 1) > i) {
    char x = target[--n];
    target[n] = target[i];
    target[i++] = x;
  }
  return target + i + n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<append_number>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%r8
  mov    $0x0,%edi
L16:
  mov    %edi,%r9d
  add    $0x1,%edi
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%esi
  add    $0x30,%esi
  mov    %sil,(%r8)
  mov    %edx,%esi
  add    $0x1,%r8
  test   %edx,%edx
  jne    L16
  movslq %edi,%rdx
  movb   $0x0,(%rax,%rdx,1)
  test   %r9d,%r9d
  jle    L19
  movslq %r9d,%rcx
  mov    $0x0,%edx
L9:
  movzbl (%rax,%rcx,1),%esi
  movzbl (%rax,%rdx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  mov    %sil,(%rax,%rdx,1)
  add    $0x1,%rdx
  sub    $0x1,%rcx
  cmp    %edx,%ecx
  jg     L9
  lea    -0x1(%r9),%edx
  shr    %edx
  lea    0x1(%rdx),%esi
  mov    %r9d,%edi
  sub    %edx,%edi
L19:
  movslq %esi,%rsi
  movslq %edi,%rdi
  add    %rdi,%rsi
  add    %rsi,%rax
  ret
```

assistant: ```c
char *append_number(char *target, int num) {
  int n = 0, i = 0;
  do {
    target[n++] = (num % 10) + '0';
    num /= 10;
  } while (num);
  target[n] = 0;
  while ((n - 1) > i) {
    char x = target[--n];
    target[n] = target[i];
    target[i++] = x;
  }
  return target + i + n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_number>:
  endbr64
  mov    %rdi,%r9
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  movslq %esi,%rdx
  mov    %esi,%ecx
  mov    %eax,%r8d
  add    $0x1,%r9
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  lea    0x1(%rax),%eax
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%esi
  add    $0x30,%esi
  mov    %sil,-0x1(%r9)
  mov    %edx,%esi
  test   %edx,%edx
  jne    L8
  cltq
  add    %rdi,%rax
  movb   $0x0,(%rax)
  test   %r8d,%r8d
  je     L9
  movslq %r8d,%rax
  xor    %edx,%edx
  mov    %rax,%rcx
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rdi,%rcx,1),%esi
  movzbl (%rdi,%rdx,1),%r9d
  mov    %r9b,(%rdi,%rcx,1)
  sub    $0x1,%rcx
  mov    %sil,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L7
  sub    $0x1,%r8d
  shr    %r8d
  mov    %r8d,%edx
  add    $0x1,%r8d
  sub    %rdx,%rax
  movslq %r8d,%r8
  add    %r8,%rax
  add    %rdi,%rax
L9:
  ret
```

assistant: ```c
char *append_number(char *target, int num) {
  int n = 0, i = 0;
  do {
    target[n++] = (num % 10) + '0';
    num /= 10;
  } while (num);
  target[n] = 0;
  while ((n - 1) > i) {
    char x = target[--n];
    target[n] = target[i];
    target[i++] = x;
  }
  return target + i + n;
}
```
user: What is the c source code of the assembly code below?

```asm
<append_number>:
  endbr64
  mov    %rdi,%r9
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  movslq %esi,%rdx
  mov    %esi,%ecx
  mov    %eax,%r8d
  add    $0x1,%r9
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  lea    0x1(%rax),%eax
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%esi
  add    $0x30,%esi
  mov    %sil,-0x1(%r9)
  mov    %edx,%esi
  test   %edx,%edx
  jne    L3
  cltq
  add    %rdi,%rax
  movb   $0x0,(%rax)
  test   %r8d,%r8d
  je     L24
  movslq %r8d,%rax
  xor    %edx,%edx
  mov    %rax,%rcx
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl (%rdi,%rcx,1),%esi
  movzbl (%rdi,%rdx,1),%r9d
  mov    %r9b,(%rdi,%rcx,1)
  sub    $0x1,%rcx
  mov    %sil,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %ecx,%edx
  jl     L4
  sub    $0x1,%r8d
  shr    %r8d
  mov    %r8d,%edx
  add    $0x1,%r8d
  sub    %rdx,%rax
  movslq %r8d,%r8
  add    %r8,%rax
  add    %rdi,%rax
L24:
  ret
```

assistant: ```c
char *append_number(char *target, int num) {
  int n = 0, i = 0;
  do {
    target[n++] = (num % 10) + '0';
    num /= 10;
  } while (num);
  target[n] = 0;
  while ((n - 1) > i) {
    char x = target[--n];
    target[n] = target[i];
    target[i++] = x;
  }
  return target + i + n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fput_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  add    $0xb,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
L49:
  mov    -0x38(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %dl,-0x25(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  jle    L39
  movzbl -0x25(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0x25(%rbp)
  jmp    L13
L39:
  movzbl -0x25(%rbp),%edx
  mov    $0x30,%eax
  sub    %edx,%eax
  mov    %al,-0x25(%rbp)
L13:
  subq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl -0x25(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x38(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  jne    L49
  cmpl   $0x0,-0x24(%rbp)
  jns    L21
  subq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x2d,(%rax)
L21:
  mov    -0x20(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputs@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
void fput_int(int fd, int n) {
  char mem[12], *stack = mem + (sizeof(mem) / sizeof(mem[0])) - 1;
  int copy = n;
  *stack = 0;
  do {
    char c = n % 10;
    if (n > 0)
      c += '0';
    else
      c = '0' - c;
    *--stack = c;
  } while (n /= 10);
  if (copy < 0)
    *--stack = '-';
  fputs(fd, stack);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fput_int>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%r8d
  mov    %esi,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x17(%rsp)
  mov    %esi,%edx
  lea    0x17(%rsp),%rsi
  mov    $0x30,%edi
  jmp    L2
L49:
  mov    %rcx,%rsi
L2:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%r10d
  mov    %edi,%ecx
  sub    %eax,%ecx
  test   %edx,%edx
  mov    %r10d,%eax
  cmovle %ecx,%eax
  lea    -0x1(%rsi),%rcx
  mov    %al,-0x1(%rsi)
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  jne    L49
  test   %r9d,%r9d
  js     L32
L45:
  mov    %rcx,%rsi
  mov    %r8d,%edi
  call   <fputs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  ret
L32:
  movb   $0x2d,-0x1(%rcx)
  lea    -0x2(%rsi),%rcx
  jmp    L45
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fput_int(int fd, int n) {
  char mem[12], *stack = mem + (sizeof(mem) / sizeof(mem[0])) - 1;
  int copy = n;
  *stack = 0;
  do {
    char c = n % 10;
    if (n > 0)
      c += '0';
    else
      c = '0' - c;
    *--stack = c;
  } while (n /= 10);
  if (copy < 0)
    *--stack = '-';
  fputs(fd, stack);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fput_int>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%r11d
  mov    %esi,%edx
  mov    %edi,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%rsi
  movb   $0x0,0x17(%rsp)
  mov    $0x30,%r9d
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %r8,%rsi
L19:
  movslq %edx,%rax
  mov    %edx,%ecx
  mov    %edx,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  mov    %r9d,%ecx
  lea    0x30(%rdi),%r8d
  sub    %edi,%ecx
  test   %edx,%edx
  mov    %r8d,%edx
  lea    -0x1(%rsi),%r8
  cmovle %ecx,%edx
  mov    %dl,-0x1(%rsi)
  mov    %eax,%edx
  test   %eax,%eax
  jne    L30
  test   %r11d,%r11d
  jns    L28
  movb   $0x2d,-0x1(%r8)
  lea    -0x2(%rsi),%r8
L28:
  mov    %r8,%rsi
  mov    %r10d,%edi
  call   <fputs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fput_int(int fd, int n) {
  char mem[12], *stack = mem + (sizeof(mem) / sizeof(mem[0])) - 1;
  int copy = n;
  *stack = 0;
  do {
    char c = n % 10;
    if (n > 0)
      c += '0';
    else
      c = '0' - c;
    *--stack = c;
  } while (n /= 10);
  if (copy < 0)
    *--stack = '-';
  fputs(fd, stack);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fput_int>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%r10d
  mov    %esi,%r9d
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%rdi
  movb   $0x0,0x17(%rsp)
  mov    $0x30,%r11d
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x30,%esi
  mov    %eax,%edx
  mov    %sil,-0x1(%rdi)
  test   %eax,%eax
  je     L38
L48:
  mov    %r8,%rdi
L50:
  movslq %edx,%rax
  mov    %edx,%ecx
  lea    -0x1(%rdi),%r8
  mov    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%esi
  test   %edx,%edx
  jg     L11
  mov    %r11d,%edx
  sub    %esi,%edx
  mov    %dl,-0x1(%rdi)
  mov    %eax,%edx
  test   %eax,%eax
  jne    L48
L38:
  test   %r9d,%r9d
  jns    L33
  movb   $0x2d,-0x1(%r8)
  lea    -0x2(%rdi),%r8
L33:
  mov    %r8,%rsi
  mov    %r10d,%edi
  call   <fputs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fput_int(int fd, int n) {
  char mem[12], *stack = mem + (sizeof(mem) / sizeof(mem[0])) - 1;
  int copy = n;
  *stack = 0;
  do {
    char c = n % 10;
    if (n > 0)
      c += '0';
    else
      c = '0' - c;
    *--stack = c;
  } while (n /= 10);
  if (copy < 0)
    *--stack = '-';
  fputs(fd, stack);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D2: i : %d


tool: D4: sizeof(i++) is: %d


assistant: ```c
int main() {
  int i;
  i = 10;
  printf("i : %d\n", i);
  printf("sizeof(i++) is: %d\n", sizeof(i++));
  printf("i : %d\n", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%esi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D17: i : %d


tool: D6: sizeof(i++) is: %d


assistant: ```c
int main() {
  int i;
  i = 10;
  printf("i : %d\n", i);
  printf("sizeof(i++) is: %d\n", sizeof(i++));
  printf("i : %d\n", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D5
type_infered: string

tool: D4: i : %d


tool: D5: sizeof(i++) is: %d


assistant: ```c
int main() {
  int i;
  i = 10;
  printf("i : %d\n", i);
  printf("sizeof(i++) is: %d\n", sizeof(i++));
  printf("i : %d\n", i);
  return 0;
}
```