ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<line_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L12
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L26
  addl   $0x1,-0x4(%rbp)
  jmp    L31
L26:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
L31:
  addq   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L3
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
L3:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int line_length(p)
char *p;
{
  int col = 1;
  while (*p != '\n' && *p != '\0') {
    if (*p != '\t') {
      col++;
    } else {
      col += 8 - ((col - 1) % 8);
    }
    p++;
  }
  return (col - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<line_length>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0xa,%dl
  je     L29
  test   %dl,%dl
  je     L29
  mov    $0x1,%eax
  mov    $0x8,%esi
  jmp    L26
L10:
  lea    -0x1(%rax),%edx
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  add    %ecx,%edx
  and    $0x7,%edx
  sub    %ecx,%edx
  mov    %esi,%ecx
  sub    %edx,%ecx
  add    %ecx,%eax
L60:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  cmp    $0xa,%dl
  je     L11
  test   %dl,%dl
  je     L11
L26:
  cmp    $0x9,%dl
  je     L10
  add    $0x1,%eax
  jmp    L60
L29:
  mov    $0x1,%eax
L11:
  sub    $0x1,%eax
  ret
```

assistant: ```c
int line_length(p)
char *p;
{
  int col = 1;
  while (*p != '\n' && *p != '\0') {
    if (*p != '\t') {
      col++;
    } else {
      col += 8 - ((col - 1) % 8);
    }
    p++;
  }
  return (col - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<line_length>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0xa,%dl
  je     L24
  test   %dl,%dl
  je     L24
  mov    $0x1,%eax
  mov    $0x8,%esi
  jmp    L66
  nopl   0x0(%rax)
L27:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  add    $0x1,%eax
  cmp    $0xa,%dl
  je     L69
L14:
  test   %dl,%dl
  je     L69
L66:
  cmp    $0x9,%dl
  jne    L27
  lea    -0x1(%rax),%edx
  mov    %esi,%ecx
  add    $0x1,%rdi
  and    $0x7,%edx
  sub    %edx,%ecx
  movzbl (%rdi),%edx
  add    %ecx,%eax
  cmp    $0xa,%dl
  jne    L14
L69:
  sub    $0x1,%eax
  ret
  nopl   (%rax)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int line_length(p)
char *p;
{
  int col = 1;
  while (*p != '\n' && *p != '\0') {
    if (*p != '\t') {
      col++;
    } else {
      col += 8 - ((col - 1) % 8);
    }
    p++;
  }
  return (col - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<line_length>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0xa,%dl
  je     L53
  test   %dl,%dl
  je     L53
  mov    $0x1,%eax
  mov    $0x8,%esi
  jmp    L14
  nopl   0x0(%rax)
L29:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  add    $0x1,%eax
  cmp    $0xa,%dl
  je     L36
L39:
  test   %dl,%dl
  je     L36
L14:
  cmp    $0x9,%dl
  jne    L29
  lea    -0x1(%rax),%edx
  mov    %esi,%ecx
  add    $0x1,%rdi
  and    $0x7,%edx
  sub    %edx,%ecx
  movzbl (%rdi),%edx
  add    %ecx,%eax
  cmp    $0xa,%dl
  jne    L39
L36:
  sub    $0x1,%eax
  ret
  nopl   (%rax)
L53:
  xor    %eax,%eax
  ret
```

assistant: ```c
int line_length(p)
char *p;
{
  int col = 1;
  while (*p != '\n' && *p != '\0') {
    if (*p != '\t') {
      col++;
    } else {
      col += 8 - ((col - 1) % 8);
    }
    p++;
  }
  return (col - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<change_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <dirname@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L23
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edi
  jmp    L27
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
L27:
  mov    -0x50(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    %edi,%ecx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
datatype: string

tool: D9: %s/%.*s.%s

assistant: ```c
char *change_extension(const char *path, const char *ext) {
  char *d = strdup(path), *f = strdup(path);
  char *dir = dirname(d), *fn = basename(f);
  char *endfn = strrchr(fn, '.');
  char *newpath;
  asprintf(&newpath, "%s/%.*s.%s", dir, endfn ? (int)(endfn - fn) : (int)strlen(fn), fn, ext);
  free(d);
  free(f);
  return newpath;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<change_extension>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <dirname@plt>
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <basename@plt>
  mov    %rax,%rbx
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L23
  mov    %eax,%ecx
  sub    %ebx,%ecx
L17:
  mov    %rsp,%rdi
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r13,%rdx
  lea    D4(%rip),%rsi
  call   <asprintf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  jmp    L17
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: %s/%.*s.%s

assistant: ```c
char *change_extension(const char *path, const char *ext) {
  char *d = strdup(path), *f = strdup(path);
  char *dir = dirname(d), *fn = basename(f);
  char *endfn = strrchr(fn, '.');
  char *newpath;
  asprintf(&newpath, "%s/%.*s.%s", dir, endfn ? (int)(endfn - fn) : (int)strlen(fn), fn, ext);
  free(d);
  free(f);
  return newpath;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<change_extension>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strdup@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <dirname@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <basename@plt>
  mov    $0x2e,%esi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L12
  mov    %eax,%ecx
  sub    %ebx,%ecx
L16:
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r13,%rdx
  mov    %rsp,%rdi
  lea    D0(%rip),%rsi
  call   <asprintf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L12:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  jmp    L16
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: %s/%.*s.%s

assistant: ```c
char *change_extension(const char *path, const char *ext) {
  char *d = strdup(path), *f = strdup(path);
  char *dir = dirname(d), *fn = basename(f);
  char *endfn = strrchr(fn, '.');
  char *newpath;
  asprintf(&newpath, "%s/%.*s.%s", dir, endfn ? (int)(endfn - fn) : (int)strlen(fn), fn, ext);
  free(d);
  free(f);
  return newpath;
}
```
user: What is the c source code of the assembly code below?

```asm
<change_extension>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strdup@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <dirname@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <basename@plt>
  mov    $0x2e,%esi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L18
  mov    %eax,%ecx
  sub    %ebx,%ecx
L22:
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r13,%rdx
  mov    %rsp,%rdi
  lea    D7(%rip),%rsi
  call   <asprintf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L18:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  jmp    L22
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: %s/%.*s.%s

assistant: ```c
char *change_extension(const char *path, const char *ext) {
  char *d = strdup(path), *f = strdup(path);
  char *dir = dirname(d), *fn = basename(f);
  char *endfn = strrchr(fn, '.');
  char *newpath;
  asprintf(&newpath, "%s/%.*s.%s", dir, endfn ? (int)(endfn - fn) : (int)strlen(fn), fn, ext);
  free(d);
  free(f);
  return newpath;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_sentence_of_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L68
L48:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L23
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L27
L23:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <words_count_region@plt>
  cmp    %eax,-0x2c(%rbp)
  jne    L54
  mov    -0x38(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  jmp    L62
L54:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L27:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L25
  addl   $0x1,-0xc(%rbp)
L25:
  addl   $0x1,-0x14(%rbp)
L68:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L48
  mov    $0xffffffff,%eax
L62:
  leave
  ret
```

assistant: ```c
int find_sentence_of_length(char *text, int sentence_length, int *found_start, int *found_end) {
  int i, start_pos = 0, end_pos, line_number = 0;
  int length = strlen(text);
  for (i = 0; i < length; i++) {
    if ((text[i] == '.') || (i == length - 1)) {
      end_pos = i;
      if (words_count_region(text, start_pos, end_pos) == sentence_length) {
        *found_start = start_pos;
        *found_end = end_pos;
        return line_number;
      }
      start_pos = end_pos + 1;
    }
    if (text[i] == 13)
      line_number++;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_sentence_of_length>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %esi,0xc(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  call   <strlen@plt>
  test   %eax,%eax
  jle    L3
  mov    %eax,%r14d
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%r15d
  lea    -0x1(%rax),%r13d
  jmp    L15
L71:
  mov    0x4(%rsp),%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <words_count_region@plt>
  cmp    0xc(%rsp),%eax
  je     L18
  mov    0x8(%rsp),%r15d
  add    $0x1,%r15d
L19:
  cmpb   $0xd,0x0(%rbp,%rbx,1)
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L8
L15:
  mov    %ebx,0x8(%rsp)
  mov    %ebx,0x4(%rsp)
  cmpb   $0x2e,0x0(%rbp,%rbx,1)
  je     L71
  cmp    %ebx,%r13d
  jne    L19
  jmp    L71
L18:
  mov    0x10(%rsp),%rax
  mov    %r15d,(%rax)
  mov    0x18(%rsp),%rax
  mov    0x4(%rsp),%edx
  mov    %edx,(%rax)
  jmp    L0
L8:
  mov    $0xffffffff,%r12d
L0:
  mov    %r12d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  mov    $0xffffffff,%r12d
  jmp    L0
```

assistant: ```c
int find_sentence_of_length(char *text, int sentence_length, int *found_start, int *found_end) {
  int i, start_pos = 0, end_pos, line_number = 0;
  int length = strlen(text);
  for (i = 0; i < length; i++) {
    if ((text[i] == '.') || (i == length - 1)) {
      end_pos = i;
      if (words_count_region(text, start_pos, end_pos) == sentence_length) {
        *found_start = start_pos;
        *found_end = end_pos;
        return line_number;
      }
      start_pos = end_pos + 1;
    }
    if (text[i] == 13)
      line_number++;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_sentence_of_length>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  mov    %esi,0xc(%rsp)
  mov    %rdx,0x10(%rsp)
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%eax
  mov    %eax,0x8(%rsp)
  test   %ecx,%ecx
  jg     L37
  jmp    L53
  nop
L55:
  add    $0x1,%ebp
L22:
  cmp    $0xd,%al
  sete   %al
  add    $0x1,%rbx
  movzbl %al,%eax
  add    %eax,%r14d
  cmp    %ecx,%ebp
  jge    L53
L37:
  movzbl (%r12,%rbx,1),%eax
  mov    %ebx,%ebp
  mov    %ebx,%r15d
  cmp    $0x2e,%al
  je     L30
  cmp    %ebx,0x8(%rsp)
  jne    L55
L30:
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %ecx,0x4(%rsp)
  call   <words_count_region@plt>
  cmp    0xc(%rsp),%eax
  mov    0x4(%rsp),%ecx
  je     L9
  lea    0x1(%rbp),%r13d
  movzbl (%r12,%rbx,1),%eax
  mov    %r13d,%ebp
  jmp    L22
  nopl   0x0(%rax)
L53:
  mov    $0xffffffff,%r14d
L65:
  add    $0x28,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    0x10(%rsp),%rax
  mov    %r13d,(%rax)
  mov    0x18(%rsp),%rax
  mov    %r15d,(%rax)
  jmp    L65
```

assistant: ```c
int find_sentence_of_length(char *text, int sentence_length, int *found_start, int *found_end) {
  int i, start_pos = 0, end_pos, line_number = 0;
  int length = strlen(text);
  for (i = 0; i < length; i++) {
    if ((text[i] == '.') || (i == length - 1)) {
      end_pos = i;
      if (words_count_region(text, start_pos, end_pos) == sentence_length) {
        *found_start = start_pos;
        *found_end = end_pos;
        return line_number;
      }
      start_pos = end_pos + 1;
    }
    if (text[i] == 13)
      line_number++;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_sentence_of_length>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  mov    %esi,0xc(%rsp)
  mov    %rdx,0x10(%rsp)
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%eax
  mov    %eax,0x8(%rsp)
  test   %ecx,%ecx
  jg     L48
  jmp    L55
  nop
L9:
  add    $0x1,%ebp
L78:
  cmp    $0xd,%al
  sete   %al
  add    $0x1,%rbx
  movzbl %al,%eax
  add    %eax,%r14d
  cmp    %ecx,%ebp
  jge    L55
L48:
  movzbl (%r12,%rbx,1),%eax
  mov    %ebx,%ebp
  mov    %ebx,%r15d
  cmp    $0x2e,%al
  je     L31
  cmp    %ebx,0x8(%rsp)
  jne    L9
L31:
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %ecx,0x4(%rsp)
  call   <words_count_region@plt>
  cmp    0xc(%rsp),%eax
  mov    0x4(%rsp),%ecx
  je     L44
  lea    0x1(%rbp),%r13d
  movzbl (%r12,%rbx,1),%eax
  mov    %r13d,%ebp
  jmp    L78
  nopl   0x0(%rax)
L55:
  mov    $0xffffffff,%r14d
L28:
  add    $0x28,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  mov    0x10(%rsp),%rax
  mov    %r13d,(%rax)
  mov    0x18(%rsp),%rax
  mov    %r15d,(%rax)
  jmp    L28
```

assistant: ```c
int find_sentence_of_length(char *text, int sentence_length, int *found_start, int *found_end) {
  int i, start_pos = 0, end_pos, line_number = 0;
  int length = strlen(text);
  for (i = 0; i < length; i++) {
    if ((text[i] == '.') || (i == length - 1)) {
      end_pos = i;
      if (words_count_region(text, start_pos, end_pos) == sentence_length) {
        *found_start = start_pos;
        *found_end = end_pos;
        return line_number;
      }
      start_pos = end_pos + 1;
    }
    if (text[i] == 13)
      line_number++;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_remove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <get_node@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L11
L14:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <remove_node@plt>
L11:
  leave
  ret
```

assistant: ```c
void *list_remove(struct list *list, unsigned int index) {
  struct node *node = get_node(list, index);
  if (node == NULL) {
    return NULL;
  }
  return remove_node(list, node);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<list_remove>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <get_node@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <remove_node@plt>
L5:
  pop    %rbx
  ret
```

assistant: ```c
void *list_remove(struct list *list, unsigned int index) {
  struct node *node = get_node(list, index);
  if (node == NULL) {
    return NULL;
  }
  return remove_node(list, node);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<list_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <get_node@plt>
  test   %rax,%rax
  je     L6
  mov    %rbp,%rdi
  mov    %rax,%rsi
  pop    %rbp
  jmp    1070 <remove_node@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *list_remove(struct list *list, unsigned int index) {
  struct node *node = get_node(list, index);
  if (node == NULL) {
    return NULL;
  }
  return remove_node(list, node);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<list_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <get_node@plt>
  test   %rax,%rax
  je     L7
  mov    %rbp,%rdi
  mov    %rax,%rsi
  pop    %rbp
  jmp    1070 <remove_node@plt>
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *list_remove(struct list *list, unsigned int index) {
  struct node *node = get_node(list, index);
  if (node == NULL) {
    return NULL;
  }
  return remove_node(list, node);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<closePlayLog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %esi,-0x128(%rbp)
  mov    %rdx,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2f73676f6c,%rax
  mov    $0x0,%edx
  mov    %rax,-0x110(%rbp)
  mov    %rdx,-0x108(%rbp)
  lea    -0x100(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1d,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  mov    %ax,(%rdx)
  add    $0x2,%rdx
  mov    %al,(%rdx)
  add    $0x1,%rdx
  mov    -0x128(%rbp),%edx
  lea    -0x110(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  jne    L23
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L23:
  mov    -0x118(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x124(%rbp),%ecx
  mov    -0x130(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  lea    D48(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L19:
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string
name: disassemble_data
arguments: tag: D22
datatype: string
name: disassemble_data
arguments: tag: D42
datatype: string
name: disassemble_data
arguments: tag: D33
datatype: string
name: disassemble_data
arguments: tag: D48
datatype: string

tool: D9: logs/TripletsLog-%d.txt

tool: D22: at

tool: D42: 
	ERR: Couldn't close %s

tool: D33: # Game closed successfully!


tool: D48: # Winner: %s - %d moves

assistant: ```c
void closePlayLog(int playNumber, int gameCounter, char playerName[]) {
  FILE *playLog;
  char logName[255] = "logs/";
  sprintf(logName, "logs/TripletsLog-%d.txt", gameCounter);
  playLog = fopen(logName, "at");
  if (playLog == NULL) {
    printf("\n\tERR: Couldn't close %s", logName);
  } else {
    fprintf(playLog, "# Game closed successfully!\n");
    fprintf(playLog, "# Winner: %s - %d moves", playerName, playNumber);
  }
  fclose(playLog);
}
```