ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L110
L71:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L71
L110:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L117
L65:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L98
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L107:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D8(%rip),%xmm0
  subsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L107
L98:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L83
  xor    %r14d,%r14d
  jmp    L80
  nopl   0x0(%rax)
L43:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L83
L80:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dasumpw@plt>
  ucomisd %xmm0,%xmm0
  jnp    L43
  lea    D23(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L14:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L83:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L117:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L65
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: f64
name: parse_data
arguments: label: D1
type_guessed: f64
name: parse_data
arguments: label: D23
type_guessed: string

tool: D8: 20000

tool: D1: 10000

tool: D23: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dasumpw(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L34
L65:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L65
L34:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L11
L29:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L15
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D16(%rip),%xmm0
  subsd  D27(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L7
L15:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L103
  xor    %r14d,%r14d
  jmp    L116
  nopl   0x0(%rax)
L91:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L103
L116:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dasumpw@plt>
  ucomisd %xmm0,%xmm0
  jnp    L91
  lea    D19(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L114:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L103:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L114
  cs nopw 0x0(%rax,%rax,1)
L11:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L29
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type: f64
name: extract_symbolic_data
arguments: label: D27
type: f64
name: extract_symbolic_data
arguments: label: D19
type: string

tool: D16: 20000

tool: D27: 10000

tool: D19: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dasumpw(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sayac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L12:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sayac(char *arr) {
  int i = 0;
  while (*(arr + i) != '\0') {
    i++;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sayac>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L5
  mov    $0x1,%eax
L3:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L3
L24:
  mov    %edx,%eax
  ret
L5:
  mov    $0x0,%edx
  jmp    L24
```

assistant: ```c
int sayac(char *arr) {
  int i = 0;
  while (*(arr + i) != '\0') {
    i++;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sayac>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  xchg   %ax,%ax
L5:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L5
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sayac(char *arr) {
  int i = 0;
  while (*(arr + i) != '\0') {
    i++;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sayac>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L13
  mov    $0x1,%eax
  xchg   %ax,%ax
L15:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L15
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sayac(char *arr) {
  int i = 0;
  while (*(arr + i) != '\0') {
    i++;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dynamixelSetRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edi
  mov    -0xc(%rbp),%esi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  mov    $0x64,%edi
  call   <write_block@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x32,%edi
  call   <jet_sleep@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int dynamixelSetRegister(int servo, int reg, int length, int value) {
  int val0 = value & 255;
  int val1 = value >> 8;
  int ret = write_block(100, servo, reg, length, val0, val1);
  jet_sleep(50);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dynamixelSetRegister>:
  endbr64
  push   %rbx
  mov    %ecx,%r9d
  sar    $0x8,%r9d
  movzbl %cl,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %edi,%esi
  mov    $0x64,%edi
  call   <write_block@plt>
  mov    %eax,%ebx
  mov    $0x32,%edi
  call   <jet_sleep@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int dynamixelSetRegister(int servo, int reg, int length, int value) {
  int val0 = value & 255;
  int val1 = value >> 8;
  int ret = write_block(100, servo, reg, length, val0, val1);
  jet_sleep(50);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dynamixelSetRegister>:
  endbr64
  push   %r12
  mov    %ecx,%r9d
  movzbl %cl,%r8d
  mov    %edx,%ecx
  sar    $0x8,%r9d
  mov    %esi,%edx
  mov    %edi,%esi
  mov    $0x64,%edi
  call   <write_block@plt>
  mov    $0x32,%edi
  mov    %eax,%r12d
  call   <jet_sleep@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int dynamixelSetRegister(int servo, int reg, int length, int value) {
  int val0 = value & 255;
  int val1 = value >> 8;
  int ret = write_block(100, servo, reg, length, val0, val1);
  jet_sleep(50);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dynamixelSetRegister>:
  endbr64
  push   %r12
  mov    %ecx,%r9d
  movzbl %cl,%r8d
  mov    %edx,%ecx
  sar    $0x8,%r9d
  mov    %esi,%edx
  mov    %edi,%esi
  mov    $0x64,%edi
  call   <write_block@plt>
  mov    $0x32,%edi
  mov    %eax,%r12d
  call   <jet_sleep@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int dynamixelSetRegister(int servo, int reg, int length, int value) {
  int val0 = value & 255;
  int val1 = value >> 8;
  int ret = write_block(100, servo, reg, length, val0, val1);
  jet_sleep(50);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
L40:
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L29
L12:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  cmp    $0x2f,%al
  jle    L53
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  cmp    $0x39,%al
  jg     L53
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L31
L53:
  nop
L31:
  addl   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L12
  mov    -0x14(%rbp),%eax
  add    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L40
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D18
type_guessed: string

tool: D5: %s

tool: D18: input=%d


assistant: ```c
int main(void) {
  int sum = 0, i = 0;
  int temp = 0;
  char input[5];
  while (1) {
    scanf("%s", input);
    for (i = 0, temp = 0; input[i] != '\0'; i++) {
      if (input[i] < '0' || input[i] > '9')
        continue;
      temp = temp * 10 + input[i] - '0';
    }
    sum += temp;
    printf("input=%d\n", sum);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0x3(%rsp),%r14
  lea    D4(%rip),%r13
  mov    $0x0,%r12d
  lea    D7(%rip),%rbp
  jmp    L24
L14:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L23
L57:
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L14
  lea    (%rcx,%rcx,4),%ecx
  movsbl %al,%eax
  lea    -0x30(%rax,%rcx,2),%ecx
  jmp    L14
L0:
  mov    %r12d,%ecx
L23:
  add    %ecx,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L24:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movzbl 0x3(%rsp),%eax
  test   %al,%al
  je     L0
  lea    0x3(%rsp),%rdx
  mov    %r12d,%ecx
  jmp    L57
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string

tool: D4: %s

tool: D7: input=%d


assistant: ```c
int main(void) {
  int sum = 0, i = 0;
  int temp = 0;
  char input[5];
  while (1) {
    scanf("%s", input);
    for (i = 0, temp = 0; input[i] != '\0'; i++) {
      if (input[i] < '0' || input[i] > '9')
        continue;
      temp = temp * 10 + input[i] - '0';
    }
    sum += temp;
    printf("input=%d\n", sum);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movsbl 0x3(%rsp),%eax
  test   %al,%al
  je     L37
  mov    %rbp,%rdx
  xor    %ecx,%ecx
L14:
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L2
  lea    (%rcx,%rcx,4),%ecx
  lea    -0x30(%rax,%rcx,2),%ecx
L2:
  movsbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L14
  add    %ecx,%ebx
L37:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L17
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string

tool: D7: %s

tool: D13: input=%d


assistant: ```c
int main(void) {
  int sum = 0, i = 0;
  int temp = 0;
  char input[5];
  while (1) {
    scanf("%s", input);
    for (i = 0, temp = 0; input[i] != '\0'; i++) {
      if (input[i] < '0' || input[i] > '9')
        continue;
      temp = temp * 10 + input[i] - '0';
    }
    sum += temp;
    printf("input=%d\n", sum);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl 0x3(%rsp),%eax
  test   %al,%al
  je     L24
  lea    -0x30(%rax),%edx
  movsbl %dl,%eax
  cmp    $0xa,%dl
  movsbl 0x4(%rsp),%edx
  cmovae %r14d,%eax
  test   %dl,%dl
  je     L61
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L16
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rdx,%rax,2),%eax
L16:
  movsbl 0x5(%rsp),%edx
  test   %dl,%dl
  je     L61
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L29
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rdx,%rax,2),%eax
L29:
  movsbl 0x6(%rsp),%edx
  test   %dl,%dl
  je     L61
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L61
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rdx,%rax,2),%eax
L61:
  add    %eax,%ebx
L24:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L36
```

tool_calls: name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D6
datatype: string

tool: D12: %s

tool: D6: input=%d


assistant: ```c
int main(void) {
  int sum = 0, i = 0;
  int temp = 0;
  char input[5];
  while (1) {
    scanf("%s", input);
    for (i = 0, temp = 0; input[i] != '\0'; i++) {
      if (input[i] < '0' || input[i] > '9')
        continue;
      temp = temp * 10 + input[i] - '0';
    }
    sum += temp;
    printf("input=%d\n", sum);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xdr_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xdr_int@plt>
  test   %eax,%eax
  jne    L18
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L24
L18:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    D14(%rip),%rax
  mov    (%rax),%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
bool_t xdr_char(XDR *xdrs, char *cp) {
  int i;
  i = (*cp);
  if (!xdr_int(xdrs, &i)) {
    return FALSE;
  }
  *cp = i;
  return TRUE;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xdr_char>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movsbl (%rsi),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <xdr_int@plt>
  test   %eax,%eax
  je     L24
  mov    0x4(%rsp),%eax
  mov    %al,(%rbx)
  mov    D13(%rip),%rax
  mov    (%rax),%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  ret
L24:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L4
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_char(XDR *xdrs, char *cp) {
  int i;
  i = (*cp);
  if (!xdr_int(xdrs, &i)) {
    return FALSE;
  }
  *cp = i;
  return TRUE;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xdr_char>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movsbl (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  call   <xdr_int@plt>
  test   %eax,%eax
  je     L19
  mov    0x4(%rsp),%eax
  mov    %al,(%rbx)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  jmp    L23
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_char(XDR *xdrs, char *cp) {
  int i;
  i = (*cp);
  if (!xdr_int(xdrs, &i)) {
    return FALSE;
  }
  *cp = i;
  return TRUE;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xdr_char>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movsbl (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  call   <xdr_int@plt>
  test   %eax,%eax
  je     L3
  mov    0x4(%rsp),%eax
  mov    %al,(%rbx)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  jmp    L1
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_char(XDR *xdrs, char *cp) {
  int i;
  i = (*cp);
  if (!xdr_int(xdrs, &i)) {
    return FALSE;
  }
  *cp = i;
  return TRUE;
}
```
user: Translate the below assembly code into C programming language:

```asm
<psvec3_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vec3_negative@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_negative(struct vec3 *result, struct vec3 *a) {
  vec3_negative((float *)result, (float *)a);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<psvec3_negative>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec3_negative@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_negative(struct vec3 *result, struct vec3 *a) {
  vec3_negative((float *)result, (float *)a);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<psvec3_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec3_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_negative(struct vec3 *result, struct vec3 *a) {
  vec3_negative((float *)result, (float *)a);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<psvec3_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec3_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_negative(struct vec3 *result, struct vec3 *a) {
  vec3_negative((float *)result, (float *)a);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<invertString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x54(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L45:
  cmp    %rdx,%rsp
  je     L7
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L45
L7:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L13
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L13:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L22
L27:
  mov    -0x54(%rbp),%eax
  sub    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x58(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  addl   $0x1,-0x58(%rbp)
L22:
  mov    -0x54(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jge    L27
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void invertString(char *inverterized) {
  int size = strlen(inverterized) - 1;
  char *invertable = inverterized;
  char output[size];
  int x = 0;
  while (size >= x) {
    output[x] = invertable[size - x];
    ++x;
  }
  strcpy(invertable, output);
}
```