ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D13(%rip),%rdi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D14(%rip),%rdi
  mov    0x10(%rsp),%eax
  cmp    %edx,%esi
  mov    %edx,%ecx
  cmovle %esi,%ecx
  cmp    %eax,%esi
  mov    0x14(%rsp),%esi
  cmovg  %eax,%ecx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  cmp    %eax,%esi
  cmovge %ecx,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string

tool: D9: Please enter 4 numbers separated by spaces > 

tool: D13: %d%d%d%d

tool: D14: %d is the smallest

assistant: ```c
int main() {
  int a, b, c, d;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d%d%d%d", &a, &b, &c, &d);
  int smallest;
  smallest = a;
  if (a > b)
    smallest = b;
  if (b > c)
    smallest = c;
  if (c > d)
    smallest = d;
  else if (a > d)
    smallest = d;
  printf("%d is the smallest", smallest);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ComputeSeq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L30:
  movl   $0x1,-0x8(%rbp)
  jmp    L13
L0:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L0
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Truelen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L30
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L53
L6:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L53:
  cmpl   $0x3e7,-0xc(%rbp)
  jle    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void ComputeSeq(char *actual_cand, char *base, int expo[1000]) {
  int i, j, k;
  for (i = 0, k = 0; i < Truelen(base); i++)
    for (j = 1; j <= expo[i]; j++, k++)
      actual_cand[k] = base[i];
  for (i = k; i < 1000; i++)
    actual_cand[i] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ComputeSeq>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L41
L19:
  movzbl (%r12,%rbp,1),%eax
  mov    %al,(%rdx)
  mov    %ecx,%eax
  add    $0x1,%ecx
  add    $0x1,%rdx
  add    $0x2,%eax
  sub    %ebx,%eax
  cmp    %eax,(%rsi)
  jge    L19
L25:
  add    $0x1,%rbp
  add    $0x4,%r13
  mov    %ecx,%ebx
L41:
  mov    %r12,%rdi
  call   <Truelen@plt>
  cmp    %ebp,%eax
  jle    L62
  mov    %r13,%rsi
  movslq %ebx,%rdx
  add    %r14,%rdx
  mov    %ebx,%ecx
  cmpl   $0x0,0x0(%r13)
  jg     L19
  jmp    L25
L62:
  cmp    $0x3e7,%ebx
  jg     L38
  movslq %ebx,%rdx
  lea    (%r14,%rdx,1),%rax
  lea    0x1(%r14,%rdx,1),%rdx
  mov    $0x3e7,%ecx
  sub    %ebx,%ecx
  add    %rcx,%rdx
L33:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L33
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void ComputeSeq(char *actual_cand, char *base, int expo[1000]) {
  int i, j, k;
  for (i = 0, k = 0; i < Truelen(base); i++)
    for (j = 1; j <= expo[i]; j++, k++)
      actual_cand[k] = base[i];
  for (i = k; i < 1000; i++)
    actual_cand[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<ComputeSeq>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14,%rdi
  call   <Truelen@plt>
  cmp    %r13d,%eax
  jle    L0
  nopw   0x0(%rax,%rax,1)
L31:
  mov    (%r12),%edi
  movslq %ebp,%rcx
  mov    %ebp,%esi
  add    %rbx,%rcx
  test   %edi,%edi
  jle    L32
L64:
  movzbl (%r14,%r13,1),%eax
  add    $0x1,%rcx
  mov    %al,-0x1(%rcx)
  mov    %esi,%eax
  add    $0x1,%esi
  add    $0x2,%eax
  sub    %ebp,%eax
  cmp    %eax,(%r12)
  jge    L64
L32:
  mov    %r14,%rdi
  add    $0x1,%r13
  add    $0x4,%r12
  movslq %esi,%rbp
  call   <Truelen@plt>
  cmp    %r13d,%eax
  jg     L31
L0:
  cmp    $0x3e7,%ebp
  jg     L2
  mov    $0x3e8,%eax
  add    %rbp,%rbx
  sub    %ebp,%eax
  cmp    $0x8,%eax
  jae    L23
  test   $0x4,%al
  jne    L25
  test   %eax,%eax
  je     L2
  movb   $0x0,(%rbx)
  test   $0x2,%al
  jne    L106
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  lea    0x8(%rbx),%rdi
  mov    %eax,%edx
  movq   $0x0,(%rbx)
  movq   $0x0,-0x8(%rbx,%rdx,1)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rbx
  add    %ebx,%eax
  shr    $0x3,%eax
  mov    %eax,%ecx
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L106:
  xor    %edx,%edx
  mov    %dx,-0x2(%rbx,%rax,1)
  jmp    L2
L25:
  movl   $0x0,(%rbx)
  movl   $0x0,-0x4(%rbx,%rax,1)
  jmp    L2
```

assistant: ```c
void ComputeSeq(char *actual_cand, char *base, int expo[1000]) {
  int i, j, k;
  for (i = 0, k = 0; i < Truelen(base); i++)
    for (j = 1; j <= expo[i]; j++, k++)
      actual_cand[k] = base[i];
  for (i = k; i < 1000; i++)
    actual_cand[i] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ComputeSeq>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14,%rdi
  call   <Truelen@plt>
  cmp    %r13d,%eax
  jle    L80
  nopw   0x0(%rax,%rax,1)
L76:
  mov    (%r12),%edi
  movslq %ebp,%rcx
  mov    %ebp,%esi
  add    %rbx,%rcx
  test   %edi,%edi
  jle    L3
L62:
  movzbl (%r14,%r13,1),%eax
  add    $0x1,%rcx
  mov    %al,-0x1(%rcx)
  mov    %esi,%eax
  add    $0x1,%esi
  add    $0x2,%eax
  sub    %ebp,%eax
  cmp    (%r12),%eax
  jle    L62
L3:
  mov    %r14,%rdi
  add    $0x1,%r13
  add    $0x4,%r12
  movslq %esi,%rbp
  call   <Truelen@plt>
  cmp    %r13d,%eax
  jg     L76
L80:
  cmp    $0x3e7,%ebp
  jg     L22
  mov    $0x3e8,%eax
  add    %rbp,%rbx
  sub    %ebp,%eax
  cmp    $0x8,%eax
  jae    L32
  test   $0x4,%al
  jne    L90
  test   %eax,%eax
  je     L22
  movb   $0x0,(%rbx)
  test   $0x2,%al
  jne    L77
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  lea    0x8(%rbx),%rdi
  mov    %eax,%edx
  movq   $0x0,(%rbx)
  movq   $0x0,-0x8(%rbx,%rdx,1)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rbx
  add    %ebx,%eax
  shr    $0x3,%eax
  mov    %eax,%ecx
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L77:
  xor    %edx,%edx
  mov    %dx,-0x2(%rbx,%rax,1)
  jmp    L22
L90:
  movl   $0x0,(%rbx)
  movl   $0x0,-0x4(%rbx,%rax,1)
  jmp    L22
```

assistant: ```c
void ComputeSeq(char *actual_cand, char *base, int expo[1000]) {
  int i, j, k;
  for (i = 0, k = 0; i < Truelen(base); i++)
    for (j = 1; j <= expo[i]; j++, k++)
      actual_cand[k] = base[i];
  for (i = k; i < 1000; i++)
    actual_cand[i] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x68,%edi
  call   <putchar@plt>
  mov    $0x69,%edi
  call   <putchar@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hi() {
  putchar('h');
  putchar('i');
}
```
user: What is the c source code of the assembly code below:

```asm
<hi>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x68,%edi
  call   <putchar@plt>
  mov    $0x69,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void hi() {
  putchar('h');
  putchar('i');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hi>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x68,%edi
  call   <putchar@plt>
  mov    $0x69,%edi
  add    $0x8,%rsp
  jmp    1050 <putchar@plt>
```

assistant: ```c
void hi() {
  putchar('h');
  putchar('i');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hi>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x68,%edi
  call   <putchar@plt>
  mov    $0x69,%edi
  add    $0x8,%rsp
  jmp    1050 <putchar@plt>
```

assistant: ```c
void hi() {
  putchar('h');
  putchar('i');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Interpolate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x30(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jne    L14
  mov    -0x40(%rbp),%rax
  jmp    L1
L14:
  mov    -0x48(%rbp),%rax
  sub    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   -0x18(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
L1:
  pop    %rbp
  ret
```

assistant: ```c
long Interpolate(long p, long p1, long p2, long v1, long v2) {
  long dp, dv, di;
  if (p1 == p2)
    return v1;
  dv = v2 - v1;
  dp = p2 - p1;
  di = p - p1;
  return v1 + ((long)(di * dv) / dp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Interpolate>:
  endbr64
  mov    %rsi,%r9
  mov    %rcx,%rsi
  mov    %rcx,%rax
  cmp    %rdx,%r9
  je     L2
  sub    %rcx,%r8
  sub    %r9,%rdi
  mov    %r8,%rax
  imul   %rdi,%rax
  mov    %rdx,%rcx
  sub    %r9,%rcx
  cqto
  idiv   %rcx
  add    %rsi,%rax
L2:
  ret
```

assistant: ```c
long Interpolate(long p, long p1, long p2, long v1, long v2) {
  long dp, dv, di;
  if (p1 == p2)
    return v1;
  dv = v2 - v1;
  dp = p2 - p1;
  di = p - p1;
  return v1 + ((long)(di * dv) / dp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Interpolate>:
  endbr64
  mov    %rcx,%r9
  cmp    %rdx,%rsi
  je     L3
  sub    %rcx,%r8
  sub    %rsi,%rdi
  sub    %rsi,%rdx
  mov    %r8,%rax
  imul   %rdi,%rax
  mov    %rdx,%rdi
  cqto
  idiv   %rdi
  add    %rax,%r9
L3:
  mov    %r9,%rax
  ret
```

assistant: ```c
long Interpolate(long p, long p1, long p2, long v1, long v2) {
  long dp, dv, di;
  if (p1 == p2)
    return v1;
  dv = v2 - v1;
  dp = p2 - p1;
  di = p - p1;
  return v1 + ((long)(di * dv) / dp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Interpolate>:
  endbr64
  mov    %rcx,%r9
  cmp    %rdx,%rsi
  je     L8
  sub    %rcx,%r8
  sub    %rsi,%rdi
  sub    %rsi,%rdx
  mov    %r8,%rax
  imul   %rdi,%rax
  mov    %rdx,%rdi
  cqto
  idiv   %rdi
  add    %rax,%r9
L8:
  mov    %r9,%rax
  ret
```

assistant: ```c
long Interpolate(long p, long p1, long p2, long v1, long v2) {
  long dp, dv, di;
  if (p1 == p2)
    return v1;
  dv = v2 - v1;
  dp = p2 - p1;
  di = p - p1;
  return v1 + ((long)(di * dv) / dp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  shr    $0x3,%rax
  or     $0xbab5,%ax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  shr    $0x3,%ax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L53
  movzwl -0xa(%rbp),%eax
  shr    $0x4,%ax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L2
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L53
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %ax,-0xa(%rbp)
  jmp    L53
L2:
  movzwl -0xa(%rbp),%eax
  shr    $0x4,%ax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L17
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  movzbl -0xb(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L53
L17:
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%edx
  movzwl -0xa(%rbp),%eax
  shr    %ax
  movzwl %ax,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %ax,-0xa(%rbp)
L53:
  movzwl -0xa(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        if (!(state[0UL] & (unsigned short)1)) {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        }
      } else if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] >>= ((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL;
      }
    } else if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
    }
    output[0UL] = state[0UL] << (unsigned short)3;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shr    $0x3,%rax
  shl    $0x3,%eax
  or     $0xd5a8,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        if (!(state[0UL] & (unsigned short)1)) {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        }
      } else if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] >>= ((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL;
      }
    } else if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
    }
    output[0UL] = state[0UL] << (unsigned short)3;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shr    $0x3,%rax
  shl    $0x3,%eax
  or     $0xd5a8,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        if (!(state[0UL] & (unsigned short)1)) {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        }
      } else if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] >>= ((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL;
      }
    } else if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
    }
    output[0UL] = state[0UL] << (unsigned short)3;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<eval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x30(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    %rdx,%rcx
  mov    %rdi,%rdx
  mov    %eax,%edi
  call   <copy@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L13
L11:
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <make@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%r8
  mov    -0x8(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    %rdi,%r9
  mov    %eax,%edi
  call   <times@plt>
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <copy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void eval(int *w, int mwidth, int *individuum, int *result) {
  assert(w[0] >= 0);
  copy(mwidth, mwidth, individuum + mwidth * mwidth * w[0], result);
  for (int i = 1; w[i] >= 0; i++) {
    int *accu = make(mwidth, mwidth);
    times(mwidth, mwidth, mwidth, result, individuum + mwidth * mwidth * w[i], accu);
    copy(mwidth, mwidth, accu, result);
    free(accu);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eval>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    (%rdi),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %ebx,%r15d
  imul   %ebx,%r15d
  mov    %r15d,%eax
  imul   0x0(%rbp),%eax
  cltq
  lea    (%r14,%rax,4),%rdx
  mov    %r13,%rcx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <copy@plt>
  lea    0x4(%rbp),%r12
  cmpl   $0x0,0x4(%rbp)
  js     L7
L11:
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <make@plt>
  mov    %rax,%rbp
  mov    %r15d,%eax
  imul   (%r12),%eax
  cltq
  mov    %rbp,%r9
  lea    (%r14,%rax,4),%r8
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <times@plt>
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <copy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x4,%r12
  cmpl   $0x0,(%r12)
  jns    L11
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void eval(int *w, int mwidth, int *individuum, int *result) {
  assert(w[0] >= 0);
  copy(mwidth, mwidth, individuum + mwidth * mwidth * w[0], result);
  for (int i = 1; w[i] >= 0; i++) {
    int *accu = make(mwidth, mwidth);
    times(mwidth, mwidth, mwidth, result, individuum + mwidth * mwidth * w[i], accu);
    copy(mwidth, mwidth, accu, result);
    free(accu);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eval>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %ebx,%r15d
  imul   %ebx,%r15d
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    0x0(%rbp),%eax
  mov    %r13,%rcx
  mov    %ebx,%esi
  mov    %ebx,%edi
  imul   %r15d,%eax
  cltq
  lea    (%r14,%rax,4),%rdx
  call   <copy@plt>
  mov    0x4(%rbp),%edx
  test   %edx,%edx
  js     L12
  lea    0x4(%rbp),%r12
  nopl   0x0(%rax)
L3:
  mov    %ebx,%esi
  mov    %ebx,%edi
  add    $0x4,%r12
  call   <make@plt>
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rax,%rbp
  mov    -0x4(%r12),%eax
  mov    %ebx,%edi
  mov    %rbp,%r9
  imul   %r15d,%eax
  cltq
  lea    (%r14,%rax,4),%r8
  call   <times@plt>
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <copy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    (%r12),%eax
  test   %eax,%eax
  jns    L3
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void eval(int *w, int mwidth, int *individuum, int *result) {
  assert(w[0] >= 0);
  copy(mwidth, mwidth, individuum + mwidth * mwidth * w[0], result);
  for (int i = 1; w[i] >= 0; i++) {
    int *accu = make(mwidth, mwidth);
    times(mwidth, mwidth, mwidth, result, individuum + mwidth * mwidth * w[i], accu);
    copy(mwidth, mwidth, accu, result);
    free(accu);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eval>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %ebx,%r15d
  imul   %ebx,%r15d
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    0x0(%rbp),%eax
  mov    %r13,%rcx
  mov    %ebx,%esi
  mov    %ebx,%edi
  imul   %r15d,%eax
  cltq
  lea    (%r14,%rax,4),%rdx
  call   <copy@plt>
  mov    0x4(%rbp),%edx
  test   %edx,%edx
  js     L10
  lea    0x4(%rbp),%r12
  nopl   0x0(%rax)
L13:
  mov    %ebx,%esi
  mov    %ebx,%edi
  add    $0x4,%r12
  call   <make@plt>
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rax,%rbp
  mov    -0x4(%r12),%eax
  mov    %ebx,%edi
  mov    %rbp,%r9
  imul   %r15d,%eax
  cltq
  lea    (%r14,%rax,4),%r8
  call   <times@plt>
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <copy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    (%r12),%eax
  test   %eax,%eax
  jns    L13
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void eval(int *w, int mwidth, int *individuum, int *result) {
  assert(w[0] >= 0);
  copy(mwidth, mwidth, individuum + mwidth * mwidth * w[0], result);
  for (int i = 1; w[i] >= 0; i++) {
    int *accu = make(mwidth, mwidth);
    times(mwidth, mwidth, mwidth, result, individuum + mwidth * mwidth * w[i], accu);
    copy(mwidth, mwidth, accu, result);
    free(accu);
  }
}
```