ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_andnot>:
  endbr64
  cmp    $0x40,%ecx
  jg     L1
  mov    (%rdx),%rax
  not    %rax
  and    (%rsi),%rax
  mov    %rax,(%rdi)
  ret
L1:
  sub    $0x8,%rsp
  call   <__bitmap_andnot@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bitmap_andnot(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src1 & ~(*src2);
  else
    __bitmap_andnot(dst, src1, src2, nbits);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bitmap_andnot>:
  endbr64
  cmp    $0x40,%ecx
  jg     L5
  mov    (%rdx),%rax
  not    %rax
  and    (%rsi),%rax
  mov    %rax,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  jmp    1050 <__bitmap_andnot@plt>
```

assistant: ```c
void bitmap_andnot(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src1 & ~(*src2);
  else
    __bitmap_andnot(dst, src1, src2, nbits);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitmap_andnot>:
  endbr64
  cmp    $0x40,%ecx
  jg     L2
  mov    (%rdx),%rax
  not    %rax
  and    (%rsi),%rax
  mov    %rax,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  jmp    1050 <__bitmap_andnot@plt>
```

assistant: ```c
void bitmap_andnot(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src1 & ~(*src2);
  else
    __bitmap_andnot(dst, src1, src2, nbits);
}
```
user: What is the c source code of the assembly code below?

```asm
<f__icvt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jle    L44
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L5
L44:
  cmpq   $0x0,-0x20(%rbp)
  jns    L34
  mov    -0x20(%rbp),%rax
  neg    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L5
L34:
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  movb   $0x30,D5(%rip)
  lea    D5(%rip),%rax
  jmp    L49
L5:
  mov    $0x17,%ebx
L38:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  add    $0x30,%eax
  sub    $0x1,%ebx
  mov    %eax,%ecx
  movslq %ebx,%rax
  lea    D20(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L38
  mov    $0x17,%eax
  sub    %ebx,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  movslq %ebx,%rax
  lea    D20(%rip),%rdx
  add    %rdx,%rax
L49:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *f__icvt(long value, int *ndigit, int *sign, int base) {
  static char buf[23 + 1];
  register int i;
  unsigned long uvalue;
  if (value > 0) {
    uvalue = value;
    *sign = 0;
  } else if (value < 0) {
    uvalue = -value;
    *sign = 1;
  } else {
    *sign = 0;
    *ndigit = 1;
    buf[23 - 1] = '0';
    return &buf[23 - 1];
  }
  i = 23;
  do {
    buf[--i] = (char)((uvalue % base) + '0');
    uvalue /= base;
  } while (uvalue > 0);
  *ndigit = 23 - i;
  return &buf[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f__icvt>:
  endbr64
  mov    %rsi,%r9
  mov    $0x0,%eax
  test   %rdi,%rdi
  jle    L12
L31:
  mov    %eax,(%rdx)
  mov    $0x16,%esi
  movslq %ecx,%rcx
  lea    D8(%rip),%r10
L29:
  mov    %esi,%r8d
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    $0x30,%edx
  mov    %dl,(%r10,%rsi,1)
  mov    %rdi,%rdx
  mov    %rax,%rdi
  sub    $0x1,%rsi
  cmp    %rdx,%rcx
  jbe    L29
  mov    $0x17,%eax
  sub    %r8d,%eax
  mov    %eax,(%r9)
  movslq %r8d,%rax
  lea    D8(%rip),%rdx
  add    %rdx,%rax
  ret
L12:
  jns    L2
  neg    %rdi
  mov    $0x1,%eax
  jmp    L31
L2:
  movl   $0x0,(%rdx)
  movl   $0x1,(%rsi)
  movb   $0x30,D36(%rip)
  lea    D36(%rip),%rax
  ret
```

assistant: ```c
char *f__icvt(long value, int *ndigit, int *sign, int base) {
  static char buf[23 + 1];
  register int i;
  unsigned long uvalue;
  if (value > 0) {
    uvalue = value;
    *sign = 0;
  } else if (value < 0) {
    uvalue = -value;
    *sign = 1;
  } else {
    *sign = 0;
    *ndigit = 1;
    buf[23 - 1] = '0';
    return &buf[23 - 1];
  }
  i = 23;
  do {
    buf[--i] = (char)((uvalue % base) + '0');
    uvalue /= base;
  } while (uvalue > 0);
  *ndigit = 23 - i;
  return &buf[i];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f__icvt>:
  endbr64
  mov    %rsi,%r9
  xor    %eax,%eax
  test   %rdi,%rdi
  jle    L30
L22:
  mov    %eax,(%rdx)
  movslq %ecx,%rcx
  mov    $0x16,%esi
  lea    D1(%rip),%r8
  nop
L21:
  mov    %rdi,%rax
  xor    %edx,%edx
  movslq %esi,%r10
  div    %rcx
  add    $0x30,%edx
  mov    %dl,(%r8,%rsi,1)
  mov    %rdi,%rdx
  sub    $0x1,%rsi
  mov    %rax,%rdi
  cmp    %rcx,%rdx
  jae    L21
  mov    $0x17,%eax
  sub    %r10d,%eax
  mov    %eax,(%r9)
  lea    (%r8,%r10,1),%rax
  ret
  nopl   0x0(%rax)
L30:
  je     L10
  neg    %rdi
  mov    $0x1,%eax
  jmp    L22
  nopl   0x0(%rax)
L10:
  movl   $0x0,(%rdx)
  lea    D11(%rip),%rax
  movl   $0x1,(%rsi)
  movb   $0x30,D11(%rip)
  ret
```

assistant: ```c
char *f__icvt(long value, int *ndigit, int *sign, int base) {
  static char buf[23 + 1];
  register int i;
  unsigned long uvalue;
  if (value > 0) {
    uvalue = value;
    *sign = 0;
  } else if (value < 0) {
    uvalue = -value;
    *sign = 1;
  } else {
    *sign = 0;
    *ndigit = 1;
    buf[23 - 1] = '0';
    return &buf[23 - 1];
  }
  i = 23;
  do {
    buf[--i] = (char)((uvalue % base) + '0');
    uvalue /= base;
  } while (uvalue > 0);
  *ndigit = 23 - i;
  return &buf[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f__icvt>:
  endbr64
  mov    %rsi,%r9
  xor    %eax,%eax
  test   %rdi,%rdi
  jle    L24
L9:
  mov    %eax,(%rdx)
  movslq %ecx,%rcx
  mov    $0x16,%esi
  lea    D3(%rip),%r8
  nop
L25:
  mov    %rdi,%rax
  xor    %edx,%edx
  movslq %esi,%r10
  div    %rcx
  add    $0x30,%edx
  mov    %dl,(%r8,%rsi,1)
  mov    %rdi,%rdx
  sub    $0x1,%rsi
  mov    %rax,%rdi
  cmp    %rcx,%rdx
  jae    L25
  mov    $0x17,%eax
  sub    %r10d,%eax
  mov    %eax,(%r9)
  lea    (%r8,%r10,1),%rax
  ret
  nopl   0x0(%rax)
L24:
  je     L28
  neg    %rdi
  mov    $0x1,%eax
  jmp    L9
  nopl   0x0(%rax)
L28:
  movl   $0x0,(%rdx)
  lea    D2(%rip),%rax
  movl   $0x1,(%rsi)
  movb   $0x30,D2(%rip)
  ret
```

assistant: ```c
char *f__icvt(long value, int *ndigit, int *sign, int base) {
  static char buf[23 + 1];
  register int i;
  unsigned long uvalue;
  if (value > 0) {
    uvalue = value;
    *sign = 0;
  } else if (value < 0) {
    uvalue = -value;
    *sign = 1;
  } else {
    *sign = 0;
    *ndigit = 1;
    buf[23 - 1] = '0';
    return &buf[23 - 1];
  }
  i = 23;
  do {
    buf[--i] = (char)((uvalue % base) + '0');
    uvalue /= base;
  } while (uvalue > 0);
  *ndigit = 23 - i;
  return &buf[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x383231,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(void) {
  char num[10] = "128";
  printf("%d\n", atoi(num));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x383231,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  lea    0xe(%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(void) {
  char num[10] = "128";
  printf("%d\n", atoi(num));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  xor    %eax,%eax
  movq   $0x383231,0xe(%rsp)
  mov    %ax,0x16(%rsp)
  call   <atoi@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main(void) {
  char num[10] = "128";
  printf("%d\n", atoi(num));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  xor    %eax,%eax
  movq   $0x383231,0xe(%rsp)
  mov    %ax,0x16(%rsp)
  call   <atoi@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main(void) {
  char num[10] = "128";
  printf("%d\n", atoi(num));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isANumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L15
  mov    $0x0,%eax
  jmp    L35
L15:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    $0x1,%eax
L35:
  leave
  ret
```

assistant: ```c
int isANumber(const char *str) {
  int i;
  for (i = 0; str[i]; ++i)
    if (!isdigit(str[i]))
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isANumber>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L31
  add    $0x1,%rbx
L10:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L9
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L10
  mov    $0x1,%eax
L9:
  pop    %rbx
  ret
L31:
  mov    $0x1,%eax
  jmp    L9
```

assistant: ```c
int isANumber(const char *str) {
  int i;
  for (i = 0; str[i]; ++i)
    if (!isdigit(str[i]))
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<isANumber>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L11
  add    $0x1,%rbx
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L32:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L11
L2:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L32
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isANumber(const char *str) {
  int i;
  for (i = 0; str[i]; ++i)
    if (!isdigit(str[i]))
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isANumber>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
  add    $0x1,%rbx
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L38:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L6
L37:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L38
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isANumber(const char *str) {
  int i;
  for (i = 0; str[i]; ++i)
    if (!isdigit(str[i]))
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remoteLCM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x48(%rbp)
  mov    %ecx,-0x54(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%ecx
  mov    -0x54(%rbp),%edx
  lea    -0x30(%rbp),%rax
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x50(%rbp),%rcx
  lea    -0x30(%rbp),%rsi
  mov    -0x44(%rbp),%eax
  mov    $0x4,%r9d
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  jne    L30
  mov    $0xffffffff,%eax
  jmp    L13
L30:
  lea    -0x30(%rbp),%rsi
  mov    -0x44(%rbp),%eax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x20,%edx
  mov    %eax,%edi
  call   <recvfrom@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0xffffffff,-0x34(%rbp)
  jne    L40
  mov    $0xffffffff,%eax
  jmp    L13
L40:
  mov    -0x34(%rbp),%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  mov    -0x60(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
type: string
name: parse_data
arguments: data_label: D7
type: string

tool: D15: lcm %u %u

tool: D7: %d

assistant: ```c
int remoteLCM(int sock, struct sockaddr_in *pAddr, uint32_t m, uint32_t n, uint32_t *pResult) {
  char str[32];
  int i;
  sprintf(str, "lcm %u %u", n, m);
  if (-1 == sendto(sock, str, strlen(str), 0, (struct sockaddr *)pAddr, sizeof(*pAddr)))
    return -1;
  if ((i = recvfrom(sock, str, 32, 0, NULL, NULL)) == -1)
    return -1;
  str[i] = '\0';
  sscanf(str, "%d", pResult);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<remoteLCM>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r13
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %r8,%rbp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x28(%rsp)
  xor    %ecx,%ecx
  mov    %rsp,%r12
  mov    %eax,%ecx
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x4,%r9d
  mov    %r13,%r8
  mov    $0x0,%ecx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    %rsp,%rsi
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x20,%edx
  mov    %ebx,%edi
  call   <recvfrom@plt>
  cmp    $0xffffffff,%eax
  je     L27
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    %rsp,%rdi
  mov    %rbp,%rdx
  lea    D0(%rip),%rsi
  call   <sscanf@plt>
  mov    $0x0,%eax
L27:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D2: lcm %u %u

tool: D0: %d

assistant: ```c
int remoteLCM(int sock, struct sockaddr_in *pAddr, uint32_t m, uint32_t n, uint32_t *pResult) {
  char str[32];
  int i;
  sprintf(str, "lcm %u %u", n, m);
  if (-1 == sendto(sock, str, strlen(str), 0, (struct sockaddr *)pAddr, sizeof(*pAddr)))
    return -1;
  if ((i = recvfrom(sock, str, 32, 0, NULL, NULL)) == -1)
    return -1;
  str[i] = '\0';
  sscanf(str, "%d", pResult);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<remoteLCM>:
  endbr64
  push   %r13
  mov    %edx,%r9d
  mov    %ecx,%edx
  mov    %r8,%r13
  push   %r12
  mov    %r9d,%ecx
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D2(%rip),%rsi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    $0x4,%r9d
  mov    %rbx,%r8
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  je     L25
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x20,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <recvfrom@plt>
  cmp    $0xffffffff,%eax
  je     L25
  cltq
  mov    %r13,%rdx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%rax,1)
  call   <sscanf@plt>
  xor    %eax,%eax
L17:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0xffffffff,%eax
  jmp    L17
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D15
data_type: string

tool: D2: lcm %u %u

tool: D15: %d

assistant: ```c
int remoteLCM(int sock, struct sockaddr_in *pAddr, uint32_t m, uint32_t n, uint32_t *pResult) {
  char str[32];
  int i;
  sprintf(str, "lcm %u %u", n, m);
  if (-1 == sendto(sock, str, strlen(str), 0, (struct sockaddr *)pAddr, sizeof(*pAddr)))
    return -1;
  if ((i = recvfrom(sock, str, 32, 0, NULL, NULL)) == -1)
    return -1;
  str[i] = '\0';
  sscanf(str, "%d", pResult);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<remoteLCM>:
  endbr64
  push   %r13
  mov    %edx,%r9d
  mov    %ecx,%edx
  mov    %r8,%r13
  push   %r12
  mov    %r9d,%ecx
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D18(%rip),%rsi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    $0x4,%r9d
  mov    %rbx,%r8
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  je     L19
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x20,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <recvfrom@plt>
  cmp    $0xffffffff,%eax
  je     L19
  cltq
  mov    %r13,%rdx
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%rax,1)
  call   <sscanf@plt>
  xor    %eax,%eax
L37:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0xffffffff,%eax
  jmp    L37
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: string

tool: D18: lcm %u %u

tool: D13: %d

assistant: ```c
int remoteLCM(int sock, struct sockaddr_in *pAddr, uint32_t m, uint32_t n, uint32_t *pResult) {
  char str[32];
  int i;
  sprintf(str, "lcm %u %u", n, m);
  if (-1 == sendto(sock, str, strlen(str), 0, (struct sockaddr *)pAddr, sizeof(*pAddr)))
    return -1;
  if ((i = recvfrom(sock, str, 32, 0, NULL, NULL)) == -1)
    return -1;
  str[i] = '\0';
  sscanf(str, "%d", pResult);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L55
  mov    $0x1,%eax
  jmp    L39
L55:
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  cmpq   $0x0,-0x10(%rbp)
  je     L14
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L44
L14:
  mov    $0x0,%eax
  jmp    L39
L44:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L39:
  leave
  ret
```

assistant: ```c
int read_binary(unsigned char *dest, const unsigned char **src, size_t amount) {
  if (amount == 0)
    return 1;
  if (!dest || !src || !*src)
    return 0;
  memcpy(dest, *src, amount);
  *src += amount;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<read_binary>:
  endbr64
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L32
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L19
  test   %rsi,%rsi
  je     L19
  mov    (%rsi),%rsi
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L24
  call   <memcpy@plt>
  add    %rbx,0x0(%rbp)
  mov    $0x1,%eax
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x0,%eax
  jmp    L24
L32:
  ret
```

assistant: ```c
int read_binary(unsigned char *dest, const unsigned char **src, size_t amount) {
  if (amount == 0)
    return 1;
  if (!dest || !src || !*src)
    return 0;
  memcpy(dest, *src, amount);
  *src += amount;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_binary>:
  endbr64
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L17
  test   %rdi,%rdi
  je     L4
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L34
  mov    (%rsi),%rsi
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L8
  mov    %rdx,%rbx
  call   <memcpy@plt>
  add    %rbx,0x0(%rbp)
  mov    $0x1,%eax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L17:
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int read_binary(unsigned char *dest, const unsigned char **src, size_t amount) {
  if (amount == 0)
    return 1;
  if (!dest || !src || !*src)
    return 0;
  memcpy(dest, *src, amount);
  *src += amount;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_binary>:
  endbr64
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L19
  test   %rdi,%rdi
  je     L27
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L35
  mov    (%rsi),%rsi
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L12
  mov    %rdx,%rbx
  call   <memcpy@plt>
  add    %rbx,0x0(%rbp)
  mov    $0x1,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L19:
  ret
  nopl   0x0(%rax)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int read_binary(unsigned char *dest, const unsigned char **src, size_t amount) {
  if (amount == 0)
    return 1;
  if (!dest || !src || !*src)
    return 0;
  memcpy(dest, *src, amount);
  *src += amount;
  return 1;
}
```