ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<prefixf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  xor    %ebp,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rdi,%r12
  mov    %rsp,%r13
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x1000,%esi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r13,%rdi
  call   <prefix@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x1010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void prefixf(char *string, ...) {
  char buf[4096];
  va_list args;
  va_start(args, string);
  vsnprintf(buf, 4096, string, args);
  va_end(args);
  prefix(buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L24
  cmpl   $0x0,-0x8(%rbp)
  jne    L59
  jmp    L54
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L56
  mov    $0xffffffff,%eax
  jmp    L68
L56:
  mov    $0x1,%eax
  jmp    L68
L59:
  nop
  jmp    L1
L54:
  mov    $0x0,%eax
L68:
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while (1) {
    int a = tolower(*s1++);
    int b = tolower(*s2++);
    if ((a == b)) {
      if (a == 0)
        break;
      continue;
    }
    if (a < b)
      return -1;
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
L28:
  add    $0x1,%r12
  movsbl -0x1(%r12),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L1
  test   %ebx,%ebx
  jne    L28
L21:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  setge  %bl
  movzbl %bl,%ebx
  lea    -0x1(%rbx,%rbx,1),%ebx
  jmp    L21
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while (1) {
    int a = tolower(*s1++);
    int b = tolower(*s2++);
    if ((a == b)) {
      if (a == 0)
        break;
      continue;
    }
    if (a < b)
      return -1;
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
L18:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <tolower@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%r12d
  call   <tolower@plt>
  cmp    %eax,%r12d
  jne    L14
  test   %r12d,%r12d
  jne    L18
L5:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L14:
  setge  %r12b
  movzbl %r12b,%r12d
  lea    -0x1(%r12,%r12,1),%r12d
  jmp    L5
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while (1) {
    int a = tolower(*s1++);
    int b = tolower(*s2++);
    if ((a == b)) {
      if (a == 0)
        break;
      continue;
    }
    if (a < b)
      return -1;
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
L21:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <tolower@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%r12d
  call   <tolower@plt>
  cmp    %eax,%r12d
  jne    L4
  test   %r12d,%r12d
  jne    L21
L15:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L4:
  setge  %r12b
  movzbl %r12b,%r12d
  lea    -0x1(%r12,%r12,1),%r12d
  jmp    L15
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while (1) {
    int a = tolower(*s1++);
    int b = tolower(*s2++);
    if ((a == b)) {
      if (a == 0)
        break;
      continue;
    }
    if (a < b)
      return -1;
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<timeElapsed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double timeElapsed() {
  double time = 0.0;
  return (time);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<timeElapsed>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double timeElapsed() {
  double time = 0.0;
  return (time);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timeElapsed>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double timeElapsed() {
  double time = 0.0;
  return (time);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <gethostname@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *hostname() {
  char *hn;
  hn = NULL;
  hn = malloc(128 * sizeof(char));
  gethostname(hn, 128 * sizeof(char));
  return hn;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hostname>:
  endbr64
  push   %rbx
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <gethostname@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *hostname() {
  char *hn;
  hn = NULL;
  hn = malloc(128 * sizeof(char));
  gethostname(hn, 128 * sizeof(char));
  return hn;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hostname>:
  endbr64
  push   %r12
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    $0x80,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <gethostname@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *hostname() {
  char *hn;
  hn = NULL;
  hn = malloc(128 * sizeof(char));
  gethostname(hn, 128 * sizeof(char));
  return hn;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hostname>:
  endbr64
  push   %r12
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    $0x80,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <gethostname@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *hostname() {
  char *hn;
  hn = NULL;
  hn = malloc(128 * sizeof(char));
  gethostname(hn, 128 * sizeof(char));
  return hn;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  lea    -0x4(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int ft_putchar(char c) {
  write(1, &c, 1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_putchar>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int ft_putchar(char c) {
  write(1, &c, 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_putchar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %dil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int ft_putchar(char c) {
  write(1, &c, 1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putchar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %dil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int ft_putchar(char c) {
  write(1, &c, 1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  mov    %edx,-0x60(%rbp)
  mov    %ecx,-0x64(%rbp)
  mov    %r8d,-0x68(%rbp)
  mov    %r9d,-0x6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  mov    -0x5c(%rbp),%r12d
  cmpl   $0x0,-0x5c(%rbp)
  jne    L110
  movb   $0x30,-0x44(%rbp)
  movb   $0x0,-0x43(%rbp)
  mov    -0x6c(%rbp),%ecx
  mov    -0x68(%rbp),%edx
  lea    -0x44(%rbp),%rsi
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <prints@plt>
  jmp    L87
L110:
  cmpl   $0x0,-0x64(%rbp)
  je     L102
  cmpl   $0xa,-0x60(%rbp)
  jne    L102
  cmpl   $0x0,-0x5c(%rbp)
  jns    L102
  mov    $0x1,%r15d
  mov    -0x5c(%rbp),%eax
  neg    %eax
  mov    %eax,%r12d
L102:
  lea    -0x44(%rbp),%rbx
  add    $0xb,%rbx
  movb   $0x0,(%rbx)
  jmp    L4
L73:
  mov    -0x60(%rbp),%ecx
  mov    %r12d,%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  mov    %eax,%r13d
  cmp    $0x9,%r13d
  jle    L96
  mov    0x10(%rbp),%eax
  sub    $0x3a,%eax
  add    %eax,%r13d
L96:
  mov    %r13d,%eax
  add    $0x30,%eax
  sub    $0x1,%rbx
  mov    %al,(%rbx)
  mov    -0x60(%rbp),%edi
  mov    %r12d,%eax
  mov    $0x0,%edx
  div    %edi
  mov    %eax,%r12d
L4:
  test   %r12d,%r12d
  jne    L73
  test   %r15d,%r15d
  je     L0
  cmpl   $0x0,-0x68(%rbp)
  je     L31
  mov    -0x6c(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L31
  mov    -0x58(%rbp),%rax
  mov    $0x2d,%esi
  mov    %rax,%rdi
  call   <printchar@plt>
  add    $0x1,%r14d
  subl   $0x1,-0x68(%rbp)
  jmp    L0
L31:
  sub    $0x1,%rbx
  movb   $0x2d,(%rbx)
L0:
  mov    -0x6c(%rbp),%ecx
  mov    -0x68(%rbp),%edx
  mov    -0x58(%rbp),%rax
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <prints@plt>
  add    %r14d,%eax
L87:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  add    $0x48,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int printi(char **out, int i, int b, int sg, int width, int pad, int letbase) {
  char print_buf[12];
  register char *s;
  register int t, neg = 0, pc = 0;
  register unsigned int u = i;
  if (i == 0) {
    print_buf[0] = '0';
    print_buf[1] = '\0';
    return prints(out, print_buf, width, pad);
  }
  if (sg && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 12 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += letbase - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg) {
    if (width && (pad & 2)) {
      printchar(out, '-');
      ++pc;
      --width;
    } else {
      *--s = '-';
    }
  }
  return pc + prints(out, s, width, pad);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %esi,%eax
  mov    %edx,%esi
  mov    %r8d,%ebx
  mov    %r9d,%ebp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  test   %eax,%eax
  je     L74
  test   %ecx,%ecx
  setne  %cl
  cmp    $0xa,%esi
  sete   %dl
  test   %dl,%cl
  je     L52
  test   %eax,%eax
  js     L46
L52:
  mov    %eax,%ecx
  mov    $0x0,%r13d
L68:
  movb   $0x0,0x17(%rsp)
  lea    0x17(%rsp),%rdi
  mov    %esi,%r8d
  mov    0x50(%rsp),%eax
  lea    -0x3a(%rax),%r9d
  jmp    L117
L74:
  movb   $0x30,0xc(%rsp)
  movb   $0x0,0xd(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %r9d,%ecx
  mov    %r8d,%edx
  call   <prints@plt>
  jmp    L44
L46:
  neg    %eax
  mov    %eax,%ecx
  mov    $0x1,%r13d
  jmp    L68
L50:
  mov    %eax,%ecx
  mov    %r14,%rdi
L117:
  mov    %ecx,%eax
  mov    $0x0,%edx
  div    %esi
  lea    (%rdx,%r9,1),%eax
  cmp    $0x9,%edx
  cmovle %edx,%eax
  lea    -0x1(%rdi),%r14
  add    $0x30,%eax
  mov    %al,-0x1(%rdi)
  mov    %ecx,%eax
  mov    $0x0,%edx
  div    %r8d
  cmp    %ecx,%esi
  jbe    L50
  test   %r13d,%r13d
  je     L9
  test   %ebx,%ebx
  je     L80
  test   $0x2,%bpl
  jne    L99
L80:
  movb   $0x2d,-0x1(%r14)
  lea    -0x2(%rdi),%r14
  mov    $0x0,%r13d
L9:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <prints@plt>
  add    %r13d,%eax
L44:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L99:
  mov    $0x2d,%esi
  mov    %r12,%rdi
  call   <printchar@plt>
  sub    $0x1,%ebx
  jmp    L9
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int printi(char **out, int i, int b, int sg, int width, int pad, int letbase) {
  char print_buf[12];
  register char *s;
  register int t, neg = 0, pc = 0;
  register unsigned int u = i;
  if (i == 0) {
    print_buf[0] = '0';
    print_buf[1] = '\0';
    return prints(out, print_buf, width, pad);
  }
  if (sg && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 12 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += letbase - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg) {
    if (width && (pad & 2)) {
      printchar(out, '-');
      ++pc;
      --width;
    } else {
      *--s = '-';
    }
  }
  return pc + prints(out, s, width, pad);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printi>:
  endbr64
  push   %r14
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L37
  mov    %edx,%edi
  test   %ecx,%ecx
  setne  %dl
  cmp    $0xa,%edi
  sete   %al
  test   %al,%dl
  je     L66
  test   %esi,%esi
  js     L43
L66:
  xor    %ebx,%ebx
L119:
  mov    0x60(%rsp),%eax
  movb   $0x0,0x27(%rsp)
  lea    0x27(%rsp),%r10
  lea    -0x3a(%rax),%r8d
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L123:
  mov    %eax,%esi
  mov    %r14,%r10
L0:
  xor    %edx,%edx
  mov    %esi,%eax
  lea    -0x1(%r10),%r14
  div    %edi
  cmp    $0x9,%edx
  lea    (%rdx,%r8,1),%ecx
  cmovle %edx,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r10)
  cmp    %esi,%edi
  jbe    L123
  test   %ebx,%ebx
  jne    L96
L52:
  mov    %r9d,%ecx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <prints@plt>
  add    %ebx,%eax
L14:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  test   %r12d,%r12d
  je     L46
  test   $0x2,%r9b
  je     L46
  mov    $0x2d,%esi
  mov    %rbp,%rdi
  mov    %r9d,0xc(%rsp)
  sub    $0x1,%r12d
  call   <printchar@plt>
  mov    0xc(%rsp),%r9d
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L46:
  movb   $0x2d,-0x1(%r14)
  xor    %ebx,%ebx
  lea    -0x2(%r10),%r14
  jmp    L52
  nopl   (%rax)
L37:
  mov    $0x30,%eax
  lea    0x1c(%rsp),%rsi
  mov    %r9d,%ecx
  mov    %r8d,%edx
  mov    %ax,0x1c(%rsp)
  call   <prints@plt>
  jmp    L14
  nop
L43:
  neg    %esi
  mov    $0x1,%ebx
  jmp    L119
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int printi(char **out, int i, int b, int sg, int width, int pad, int letbase) {
  char print_buf[12];
  register char *s;
  register int t, neg = 0, pc = 0;
  register unsigned int u = i;
  if (i == 0) {
    print_buf[0] = '0';
    print_buf[1] = '\0';
    return prints(out, print_buf, width, pad);
  }
  if (sg && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 12 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += letbase - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg) {
    if (width && (pad & 2)) {
      printchar(out, '-');
      ++pc;
      --width;
    } else {
      *--s = '-';
    }
  }
  return pc + prints(out, s, width, pad);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printi>:
  endbr64
  push   %r13
  mov    %esi,%eax
  mov    %r9d,%r13d
  mov    %edx,%esi
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  test   %eax,%eax
  je     L120
  test   %ecx,%ecx
  setne  %cl
  cmp    $0xa,%esi
  sete   %dl
  test   %dl,%cl
  je     L51
  test   %eax,%eax
  js     L0
L51:
  mov    %eax,%ecx
  xor    %ebx,%ebx
L66:
  mov    0x60(%rsp),%eax
  movb   $0x0,0x27(%rsp)
  lea    0x27(%rsp),%r8
  lea    -0x3a(%rax),%r9d
  jmp    L47
  nop
L4:
  lea    0x30(%r9,%rdx,1),%edx
  mov    %dl,-0x1(%r8)
  cmp    %ecx,%esi
  ja     L18
L57:
  mov    %eax,%ecx
  mov    %rbp,%r8
L47:
  mov    %ecx,%eax
  xor    %edx,%edx
  lea    -0x1(%r8),%rbp
  div    %esi
  cmp    $0x9,%edx
  jg     L4
  add    $0x30,%edx
  mov    %dl,-0x1(%r8)
  cmp    %ecx,%esi
  jbe    L57
L18:
  test   %ebx,%ebx
  jne    L74
L3:
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <prints@plt>
  add    %ebx,%eax
L148:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L60
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  test   %r12d,%r12d
  je     L29
  test   $0x2,%r13b
  je     L29
  mov    $0x2d,%esi
  mov    %rdi,0x8(%rsp)
  sub    $0x1,%r12d
  call   <printchar@plt>
  mov    0x8(%rsp),%rdi
  jmp    L3
  nopl   (%rax)
L29:
  movb   $0x2d,-0x1(%rbp)
  xor    %ebx,%ebx
  lea    -0x2(%r8),%rbp
  jmp    L3
  nopl   0x0(%rax)
L120:
  mov    $0x30,%eax
  lea    0x1c(%rsp),%rsi
  mov    %r9d,%ecx
  mov    %r8d,%edx
  mov    %ax,0x1c(%rsp)
  call   <prints@plt>
  jmp    L148
  nopl   0x0(%rax)
L0:
  neg    %eax
  mov    $0x1,%ebx
  mov    %eax,%ecx
  jmp    L66
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int printi(char **out, int i, int b, int sg, int width, int pad, int letbase) {
  char print_buf[12];
  register char *s;
  register int t, neg = 0, pc = 0;
  register unsigned int u = i;
  if (i == 0) {
    print_buf[0] = '0';
    print_buf[1] = '\0';
    return prints(out, print_buf, width, pad);
  }
  if (sg && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 12 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += letbase - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg) {
    if (width && (pad & 2)) {
      printchar(out, '-');
      ++pc;
      --width;
    } else {
      *--s = '-';
    }
  }
  return pc + prints(out, s, width, pad);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gotoxy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  nop
  leave
  ret
```

assistant: ```c
void gotoxy(int x, int y) {
  move(y - 1, x - 1);
  refresh();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gotoxy>:
  endbr64
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%eax
  lea    -0x1(%rsi),%edi
  mov    %eax,%esi
  call   <move@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gotoxy(int x, int y) {
  move(y - 1, x - 1);
  refresh();
}
```
user: What is the c source code of the assembly code below?

```asm
<gotoxy>:
  endbr64
  lea    -0x1(%rdi),%r8d
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%edi
  mov    %r8d,%esi
  call   <move@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <refresh@plt>
```

assistant: ```c
void gotoxy(int x, int y) {
  move(y - 1, x - 1);
  refresh();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gotoxy>:
  endbr64
  lea    -0x1(%rdi),%r8d
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%edi
  mov    %r8d,%esi
  call   <move@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <refresh@plt>
```

assistant: ```c
void gotoxy(int x, int y) {
  move(y - 1, x - 1);
  refresh();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<autohelperowl_attackpat82>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jg     L17
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jle    L21
L17:
  mov    -0x20(%rbp),%edi
  mov    -0x10(%rbp),%esi
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  sub    $0x8,%rsp
  mov    -0xc(%rbp),%ecx
  push   %rcx
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <play_attack_defend2_n@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  je     L21
  mov    $0x1,%eax
  jmp    L29
L21:
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat82(struct pattern *patt, int transformation, int move, int color, int action) {
  int c, d, A, B;
  (void)patt;
  (void)color;
  (void)action;
  c = offset(-1, 0, move, transformation);
  d = offset(-1, 1, move, transformation);
  A = offset(-1, -1, move, transformation);
  B = offset(0, 1, move, transformation);
  return (owl_escape_value(A) > 0 || owl_escape_value(B) > 0) && play_attack_defend2_n(color, 0, 2, move, c, move, d);
}
```
user: Translate the below assembly code into C programming language:

```asm
<autohelperowl_attackpat82>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %esi,%ecx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,%r14d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,%r15d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,%r12d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%ebp
  mov    %r12d,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jle    L20
L7:
  sub    $0x8,%rsp
  push   %r15
  mov    %ebx,%r9d
  mov    %r14d,%r8d
  mov    %ebx,%ecx
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %r13d,%edi
  call   <play_attack_defend2_n@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  mov    %ebp,%edi
  call   <owl_escape_value@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jg     L7
  jmp    L4
```

assistant: ```c
int autohelperowl_attackpat82(struct pattern *patt, int transformation, int move, int color, int action) {
  int c, d, A, B;
  (void)patt;
  (void)color;
  (void)action;
  c = offset(-1, 0, move, transformation);
  d = offset(-1, 1, move, transformation);
  A = offset(-1, -1, move, transformation);
  B = offset(0, 1, move, transformation);
  return (owl_escape_value(A) > 0 || owl_escape_value(B) > 0) && play_attack_defend2_n(color, 0, 2, move, c, move, d);
}
```