user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D31(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L56:
  mov    $0x3,%ebp
  mov    $0x1,%edx
  mov    $0x1,%esi
  cmp    %ebp,%ebx
  cmovle %ebx,%ebp
  xor    %r12d,%r12d
  shl    $0x2,%ebp
  movslq %ebp,%rbp
  add    %r14,%rbp
  test   %ebx,%ebx
  sete   %r12b
  lea    0x1(%rbp),%r13
  mov    %r12d,%edi
  call   <fn1@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %ebx,%edi
  call   <fn1@plt>
  mov    $0x3,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L86
  lea    0x3(%r15),%rdi
  mov    $0x4,%edx
  lea    D41(%rip),%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L18
L86:
  xor    %eax,%eax
  call   <abort@plt>
L18:
  xor    %esi,%esi
  mov    $0x1,%edx
  mov    %r12d,%edi
  call   <fn1@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <fn1@plt>
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L29
  lea    0x4(%r15),%rdi
  mov    $0x8,%edx
  lea    D20(%rip),%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L10
L29:
  xor    %eax,%eax
  call   <abort@plt>
L10:
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <fn1@plt>
  xor    %esi,%esi
  mov    $0x1,%edx
  mov    %ebx,%edi
  call   <fn1@plt>
  mov    $0x3,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L42
  lea    0x3(%r15),%rdi
  mov    $0x4,%edx
  lea    D7(%rip),%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L11
L42:
  xor    %eax,%eax
  call   <abort@plt>
L11:
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r12d,%edi
  call   <fn1@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <fn1@plt>
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L78
  lea    0x4(%r12),%rdi
  mov    $0x8,%edx
  lea    D48(%rip),%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L47
L78:
  xor    %eax,%eax
  call   <abort@plt>
L47:
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L56
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
type_infered: string
name: extract_symbolic_data
arguments: tag: D41
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D48
type_infered: string

tool: D31: abcdefghijklmnop

tool: D41: RST

tool: D20: HIJKLMN

tool: D7: OPQ

tool: D48: ABCDEFG

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    const char *p = "abcdefghijklmnop" + (i < 3 ? i : 3) * 4;
    const char *q;
    fn1(i ? 0 : 1, 1, 1);
    q = fn1(i, 0, 0);
    if (memcmp(q, p + 1, 3) != 0 || memcmp(q + 3, "RST", 4) != 0)
      abort();
    fn1(i ? 0 : 1, 0, 1);
    q = fn1(i, 1, 0);
    if (memcmp(q, p, 4) != 0 || memcmp(q + 4, "HIJKLMN", 8) != 0)
      abort();
    fn1(i ? 0 : 1, 1, 0);
    q = fn1(i, 0, 1);
    if (memcmp(q, p + 1, 3) != 0 || memcmp(q + 3, "OPQ", 4) != 0)
      abort();
    fn1(i ? 0 : 1, 0, 0);
    q = fn1(i, 1, 1);
    if (memcmp(q, p, 4) != 0 || memcmp(q + 4, "ABCDEFG", 8) != 0)
      abort();
  }
  return 0;
}
```