ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<givens>:
  endbr64
  push   %r14
  mov    %rcx,%r10
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L44
  movsd  0x8(%rcx),%xmm0
  mov    0x8(%rsi),%rax
  mov    %edi,%r12d
  lea    0x1(%rdi),%ebp
  mov    $0x10,%esi
  mov    $0x2,%ecx
  mov    $0x2,%r9d
  movsd  %xmm0,0x8(%rax)
  nopw   0x0(%rax,%rax,1)
L19:
  movslq %r9d,%rax
  mov    (%rbx,%rsi,1),%rdi
  lea    (%r10,%rax,8),%r8
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L31:
  movsd  -0x8(%r8,%rax,8),%xmm0
  mov    (%rbx,%rax,8),%rdx
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  movsd  %xmm0,(%rdx,%rsi,1)
  cmp    %rax,%rcx
  jne    L31
  lea    -0x1(%r9,%rcx,1),%eax
  add    $0x1,%rcx
  lea    0x1(%rax),%r9d
  cltq
  movsd  (%r10,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rsi,1)
  add    $0x8,%rsi
  cmp    %rcx,%rbp
  jne    L19
  mov    %r12d,%esi
  mov    $0x1,%edi
  call   <dvector@plt>
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    %rax,%r14
  mov    %rax,%rcx
  call   <tred2@plt>
  mov    %rbx,%rcx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <tqli@plt>
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <free_dvector@plt>
  mov    $0x2,%esi
  nopl   (%rax)
L14:
  mov    (%rbx,%rsi,8),%rcx
  lea    0x0(,%rsi,8),%rdi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L27:
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rcx,%rax,8),%xmm0
  add    %rdi,%rdx
  movsd  (%rdx),%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rsi
  jne    L27
  add    $0x1,%rsi
  cmp    %rsi,%rbp
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  movsd  0x8(%rcx),%xmm0
  mov    D7(%rip),%rbx
  mov    0x8(%rsi),%rax
  movsd  %xmm0,0x8(%rdx)
  mov    %rbx,0x8(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: f64

tool: D7: 1

assistant: ```c
void givens(int nx, double **vect, double *root, double *a) {
  int l, j, k;
  double *e;
  if (nx <= 1) {
    root[1] = a[1];
    vect[1][1] = 1.0;
    return;
  }
  for (k = 1, l = 1; k <= nx; k++) {
    for (j = 1; j < k; j++) {
      vect[k][j] = a[l];
      vect[j][k] = a[l++];
    }
    vect[k][k] = a[l++];
  }
  e = dvector(1, nx);
  tred2(vect, nx, root, e);
  tqli(root, e, nx, vect);
  free_dvector(e, 1);
  for (k = 1; k <= nx; k++)
    for (j = 1; j < k; j++) {
      double p = vect[k][j];
      vect[k][j] = vect[j][k];
      vect[j][k] = p;
    }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<autohelperowl_attackpat189>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xfffffffe,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x3,%eax
  sub    -0x24(%rbp),%eax
  mov    -0x4(%rbp),%esi
  mov    -0xc(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  je     L0
  mov    -0x8(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  jne    L0
  mov    $0x1,%eax
  jmp    L19
L0:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat189(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, A, B;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(1, -1, move, transformation);
  A = offset(0, -2, move, transformation);
  B = offset(-1, 0, move, transformation);
  return play_attack_defend_n((1 + 2 - (color)), 1, 2, move, a, B) && !play_attack_defend_n(color, 0, 1, move, A);
}
```
user: Translate the below assembly code into C programming language:

```asm
<autohelperowl_attackpat189>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%r13d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0xfffffffe,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%r14d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,%r9d
  mov    $0x3,%edi
  sub    %r12d,%edi
  mov    %r13d,%r8d
  mov    %ebx,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x0,%eax
  call   <play_attack_defend_n@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L19
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  mov    %r14d,%r8d
  mov    %ebx,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L4
```

assistant: ```c
int autohelperowl_attackpat189(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, A, B;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(1, -1, move, transformation);
  A = offset(0, -2, move, transformation);
  B = offset(-1, 0, move, transformation);
  return play_attack_defend_n((1 + 2 - (color)), 1, 2, move, a, B) && !play_attack_defend_n(color, 0, 1, move, A);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<autohelperowl_attackpat189>:
  endbr64
  push   %r14
  mov    $0x1,%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  push   %rbx
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0xfffffffe,%esi
  xor    %edi,%edi
  mov    %eax,%r14d
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  mov    %eax,%ebx
  call   <offset@plt>
  mov    $0x3,%edi
  mov    %r14d,%r8d
  mov    %r12d,%ecx
  mov    %eax,%r9d
  sub    %ebp,%edi
  mov    $0x2,%edx
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <play_attack_defend_n@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    $0x1,%edx
  call   <play_attack_defend_n@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  pop    %r13
  sete   %al
  pop    %r14
  movzbl %al,%eax
  ret
```

assistant: ```c
int autohelperowl_attackpat189(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, A, B;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(1, -1, move, transformation);
  A = offset(0, -2, move, transformation);
  B = offset(-1, 0, move, transformation);
  return play_attack_defend_n((1 + 2 - (color)), 1, 2, move, a, B) && !play_attack_defend_n(color, 0, 1, move, A);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<autohelperowl_attackpat189>:
  endbr64
  push   %r14
  mov    $0x1,%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  push   %rbx
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0xfffffffe,%esi
  xor    %edi,%edi
  mov    %eax,%r14d
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  mov    %eax,%ebx
  call   <offset@plt>
  mov    $0x3,%edi
  mov    %r14d,%r8d
  mov    %r12d,%ecx
  mov    %eax,%r9d
  sub    %ebp,%edi
  mov    $0x2,%edx
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <play_attack_defend_n@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    $0x1,%edx
  call   <play_attack_defend_n@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  pop    %r13
  sete   %al
  pop    %r14
  movzbl %al,%eax
  ret
```

assistant: ```c
int autohelperowl_attackpat189(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, A, B;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(1, -1, move, transformation);
  A = offset(0, -2, move, transformation);
  B = offset(-1, 0, move, transformation);
  return play_attack_defend_n((1 + 2 - (color)), 1, 2, move, a, B) && !play_attack_defend_n(color, 0, 1, move, A);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ind2state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x4,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x24(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L34
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L34:
  cmpl   $0x2,-0xc(%rbp)
  jle    L8
  movl   $0x2,-0xc(%rbp)
  jmp    L3
L18:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,(%rcx)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x10(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L3:
  cmpl   $0x0,-0xc(%rbp)
  jns    L18
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ind2state(int state[], int dims[], int ind) {
  int ndims = 4;
  int stride = dims[0];
  int i;
  int rest;
  ind += 1;
  for (i = 1; i < (4 - 1); i++) {
    stride *= dims[i];
  }
  for (i = (4 - 2); i >= 0; i--) {
    rest = ((ind - 1) % stride) + 1;
    state[i + 1] = (int)((ind - rest) / stride);
    ind = rest;
    stride = (int)(stride / dims[i]);
  }
  state[0] = ind - 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ind2state>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    (%rsi),%ecx
  lea    0x1(%rdx),%edi
  imul   0x4(%rsi),%ecx
  imul   0x8(%rsi),%ecx
  mov    $0x0,%esi
L5:
  lea    -0x1(%rdi),%eax
  cltd
  idiv   %ecx
  mov    %edx,%r10d
  mov    %edi,%eax
  lea    0x1(%rdx),%edi
  sub    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,0xc(%r9,%rsi,1)
  mov    %ecx,%eax
  cltd
  idivl  0x8(%r8,%rsi,1)
  mov    %eax,%ecx
  sub    $0x4,%rsi
  cmp    $0xfffffffffffffff4,%rsi
  jne    L5
  mov    %r10d,(%r9)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ind2state(int state[], int dims[], int ind) {
  int ndims = 4;
  int stride = dims[0];
  int i;
  int rest;
  ind += 1;
  for (i = 1; i < (4 - 1); i++) {
    stride *= dims[i];
  }
  for (i = (4 - 2); i >= 0; i--) {
    rest = ((ind - 1) % stride) + 1;
    state[i + 1] = (int)((ind - rest) / stride);
    ind = rest;
    stride = (int)(stride / dims[i]);
  }
  state[0] = ind - 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ind2state>:
  endbr64
  mov    (%rsi),%ecx
  mov    %rdi,%r9
  imul   0x4(%rsi),%ecx
  mov    %rsi,%r8
  imul   0x8(%rsi),%ecx
  lea    0x1(%rdx),%edi
  xor    %esi,%esi
L1:
  lea    -0x1(%rdi),%eax
  cltd
  idiv   %ecx
  mov    %edi,%eax
  lea    0x1(%rdx),%edi
  mov    %edx,%r10d
  sub    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,0xc(%r9,%rsi,1)
  mov    %ecx,%eax
  cltd
  idivl  0x8(%r8,%rsi,1)
  sub    $0x4,%rsi
  mov    %eax,%ecx
  cmp    $0xfffffffffffffff4,%rsi
  jne    L1
  mov    %r10d,(%r9)
  xor    %eax,%eax
  ret
```

assistant: ```c
int ind2state(int state[], int dims[], int ind) {
  int ndims = 4;
  int stride = dims[0];
  int i;
  int rest;
  ind += 1;
  for (i = 1; i < (4 - 1); i++) {
    stride *= dims[i];
  }
  for (i = (4 - 2); i >= 0; i--) {
    rest = ((ind - 1) % stride) + 1;
    state[i + 1] = (int)((ind - rest) / stride);
    ind = rest;
    stride = (int)(stride / dims[i]);
  }
  state[0] = ind - 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ind2state>:
  endbr64
  mov    %rsi,%r8
  mov    %edx,%eax
  mov    %edx,%esi
  mov    (%r8),%ecx
  imul   0x4(%r8),%ecx
  cltd
  imul   0x8(%r8),%ecx
  idiv   %ecx
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %edx,%r9d
  cltd
  idiv   %ecx
  mov    %eax,0xc(%rdi)
  mov    %ecx,%eax
  cltd
  idivl  0x8(%r8)
  mov    %eax,%ecx
  mov    %r9d,%eax
  cltd
  idiv   %ecx
  mov    %r9d,%eax
  sub    %edx,%eax
  mov    %edx,%esi
  cltd
  idiv   %ecx
  mov    %eax,0x8(%rdi)
  mov    %ecx,%eax
  cltd
  idivl  0x4(%r8)
  mov    %eax,%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %edx,%r8d
  cltd
  mov    %r8d,(%rdi)
  idiv   %ecx
  mov    %eax,0x4(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int ind2state(int state[], int dims[], int ind) {
  int ndims = 4;
  int stride = dims[0];
  int i;
  int rest;
  ind += 1;
  for (i = 1; i < (4 - 1); i++) {
    stride *= dims[i];
  }
  for (i = (4 - 2); i >= 0; i--) {
    rest = ((ind - 1) % stride) + 1;
    state[i + 1] = (int)((ind - rest) / stride);
    ind = rest;
    stride = (int)(stride / dims[i]);
  }
  state[0] = ind - 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sol_ptr_vector_steal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sol_ptr_vector_get@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sol_ptr_vector_del@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *sol_ptr_vector_steal(struct sol_ptr_vector *pv, uint16_t i) {
  void *result = sol_ptr_vector_get(pv, i);
  sol_ptr_vector_del(pv, i);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<sol_ptr_vector_steal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <sol_ptr_vector_get@plt>
  mov    %rax,%r12
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <sol_ptr_vector_del@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *sol_ptr_vector_steal(struct sol_ptr_vector *pv, uint16_t i) {
  void *result = sol_ptr_vector_get(pv, i);
  sol_ptr_vector_del(pv, i);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sol_ptr_vector_steal>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <sol_ptr_vector_get@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <sol_ptr_vector_del@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sol_ptr_vector_steal(struct sol_ptr_vector *pv, uint16_t i) {
  void *result = sol_ptr_vector_get(pv, i);
  sol_ptr_vector_del(pv, i);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sol_ptr_vector_steal>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <sol_ptr_vector_get@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <sol_ptr_vector_del@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sol_ptr_vector_steal(struct sol_ptr_vector *pv, uint16_t i) {
  void *result = sol_ptr_vector_get(pv, i);
  sol_ptr_vector_del(pv, i);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eu2hoLoopf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %ecx,-0x9c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x3,-0x60(%rbp)
  movq   $0x3,-0x58(%rbp)
  movq   $0x0,-0x68(%rbp)
  jmp    L65
L13:
  mov    -0x68(%rbp),%rax
  imul   -0x60(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x68(%rbp),%rax
  imul   -0x58(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  movq   $0x0,-0x70(%rbp)
  jmp    L28
L5:
  mov    -0x50(%rbp),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    -0x70(%rbp),%rax
  movsd  %xmm0,-0x40(%rbp,%rax,8)
  addq   $0x1,-0x70(%rbp)
L28:
  mov    -0x70(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  jb     L5
  mov    -0x9c(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <eu2ho@plt>
  mov    %eax,-0x74(%rbp)
  movq   $0x0,-0x70(%rbp)
  jmp    L0
L44:
  mov    -0x70(%rbp),%rax
  movsd  -0x20(%rbp,%rax,8),%xmm0
  mov    -0x48(%rbp),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x90(%rbp),%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x70(%rbp)
L0:
  mov    -0x70(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jb     L44
  addq   $0x1,-0x68(%rbp)
L65:
  mov    -0x68(%rbp),%rax
  cmp    -0x98(%rbp),%rax
  jb     L13
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int eu2hoLoopf(float *eu, float *ho, unsigned long long n, int p) {
  int trash;
  unsigned long long j, i, iIn, iOut, eustep = 3, hostep = 3;
  double euFlt[3], hoFlt[3];
#pragma omp parallel for default(shared) private(j, i, iIn, iOut, trash, euFlt, hoFlt) firstprivate(eustep, hostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * eustep;
    iOut = i * hostep;
    for (j = 0; j < eustep; j++) {
      euFlt[j] = (double)eu[iIn + j];
    }
    trash = eu2ho(euFlt, hoFlt, p);
    for (j = 0; j < hostep; j++) {
      ho[iOut + j] = (float)hoFlt[j];
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<eu2hoLoopf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L50
  mov    %ecx,%r14d
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  lea    (%rdx,%rdx,2),%r15
  mov    $0x0,%r13d
  lea    0x20(%rsp),%r12
  jmp    L44
L47:
  add    $0x3,%r13
  add    $0xc,%rbp
  add    $0xc,%rbx
  cmp    %r15,%r13
  je     L50
L44:
  mov    $0x0,%eax
L46:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%rax,4),%xmm0
  movsd  %xmm0,(%rsp,%rax,8)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L46
  mov    %rsp,%rdi
  mov    %r14d,%edx
  mov    %r12,%rsi
  call   <eu2ho@plt>
  mov    $0x0,%eax
L38:
  pxor   %xmm0,%xmm0
  cvtsd2ss (%r12,%rax,8),%xmm0
  movss  %xmm0,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L38
  jmp    L47
L50:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x1,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eu2hoLoopf(float *eu, float *ho, unsigned long long n, int p) {
  int trash;
  unsigned long long j, i, iIn, iOut, eustep = 3, hostep = 3;
  double euFlt[3], hoFlt[3];
#pragma omp parallel for default(shared) private(j, i, iIn, iOut, trash, euFlt, hoFlt) firstprivate(eustep, hostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * eustep;
    iOut = i * hostep;
    for (j = 0; j < eustep; j++) {
      euFlt[j] = (double)eu[iIn + j];
    }
    trash = eu2ho(euFlt, hoFlt, p);
    for (j = 0; j < hostep; j++) {
      ho[iOut + j] = (float)hoFlt[j];
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eu2hoLoopf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L24
  lea    (%rdx,%rdx,2),%rax
  mov    %ecx,%ebx
  mov    %rsi,%r13
  mov    %rdi,%r12
  mov    %rax,0x8(%rsp)
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r15
  lea    0x30(%rsp),%r14
  nopl   0x0(%rax)
L35:
  xor    %eax,%eax
L40:
  pxor   %xmm0,%xmm0
  cvtss2sd (%r12,%rax,4),%xmm0
  movsd  %xmm0,(%r15,%rax,8)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L40
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <eu2ho@plt>
  xor    %eax,%eax
L38:
  pxor   %xmm0,%xmm0
  cvtsd2ss (%r14,%rax,8),%xmm0
  movss  %xmm0,0x0(%r13,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L38
  add    $0x3,%rbp
  add    $0xc,%r13
  add    $0xc,%r12
  cmp    %rbp,0x8(%rsp)
  jne    L35
L24:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eu2hoLoopf(float *eu, float *ho, unsigned long long n, int p) {
  int trash;
  unsigned long long j, i, iIn, iOut, eustep = 3, hostep = 3;
  double euFlt[3], hoFlt[3];
#pragma omp parallel for default(shared) private(j, i, iIn, iOut, trash, euFlt, hoFlt) firstprivate(eustep, hostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * eustep;
    iOut = i * hostep;
    for (j = 0; j < eustep; j++) {
      euFlt[j] = (double)eu[iIn + j];
    }
    trash = eu2ho(euFlt, hoFlt, p);
    for (j = 0; j < hostep; j++) {
      ho[iOut + j] = (float)hoFlt[j];
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<eu2hoLoopf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L15
  mov    %ecx,%r13d
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  lea    0x30(%rsp),%r15
  lea    0x10(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L3:
  movq   0x0(%rbp),%xmm0
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12
  add    $0xc,%rbp
  add    $0xc,%rbx
  cvtps2pd %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  movsd  %xmm0,0x20(%rsp)
  call   <eu2ho@plt>
  cvtpd2ps 0x30(%rsp),%xmm0
  movlps %xmm0,-0xc(%rbx)
  pxor   %xmm0,%xmm0
  cvtsd2ss 0x40(%rsp),%xmm0
  movss  %xmm0,-0x4(%rbx)
  cmp    %r12,0x8(%rsp)
  jne    L3
L15:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x58,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eu2hoLoopf(float *eu, float *ho, unsigned long long n, int p) {
  int trash;
  unsigned long long j, i, iIn, iOut, eustep = 3, hostep = 3;
  double euFlt[3], hoFlt[3];
#pragma omp parallel for default(shared) private(j, i, iIn, iOut, trash, euFlt, hoFlt) firstprivate(eustep, hostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * eustep;
    iOut = i * hostep;
    for (j = 0; j < eustep; j++) {
      euFlt[j] = (double)eu[iIn + j];
    }
    trash = eu2ho(euFlt, hoFlt, p);
    for (j = 0; j < hostep; j++) {
      ho[iOut + j] = (float)hoFlt[j];
    }
  }
  return 1;
}
```