ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<kt_int_log2>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L2
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%eax
  sar    %edi
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
int kt_int_log2(int n) {
  int tmp1 = n;
  int tmp2 = 0;
  while (tmp1 >>= 1) {
    tmp2++;
  }
  return tmp2;
}
```
user: What is the c source code of the assembly code below?

```asm
<clock_settime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int clock_settime(clockid_t clock_id, const struct timespec *tp) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clock_settime>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int clock_settime(clockid_t clock_id, const struct timespec *tp) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clock_settime>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int clock_settime(clockid_t clock_id, const struct timespec *tp) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clock_settime>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int clock_settime(clockid_t clock_id, const struct timespec *tp) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_maxu4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x34(%rbp),%eax
  shr    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%eax
  shr    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x38(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jae    L3
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x30(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jae    L1
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jae    L35
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x28(%rbp)
L35:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jae    L17
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x24(%rbp)
L17:
  mov    -0x24(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  or     -0x30(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int _maxu4(unsigned int src1, unsigned int src2) {
  unsigned int res0, res1, res2, res3;
  unsigned int s1_0 = res0 = (src1 & 0xFF);
  unsigned int s1_1 = res1 = (src1 & 0xFF00) >> 8;
  unsigned int s1_2 = res2 = (src1 & 0xFF0000) >> 16;
  unsigned int s1_3 = res3 = (src1 & 0xFF000000) >> 24;
  unsigned int s2_0 = (src2 & 0xFF);
  unsigned int s2_1 = (src2 & 0xFF00) >> 8;
  unsigned int s2_2 = (src2 & 0xFF0000) >> 16;
  unsigned int s2_3 = (src2 & 0xFF000000) >> 24;
  if (s1_0 < s2_0)
    res0 = s2_0;
  if (s1_1 < s2_1)
    res1 = s2_1;
  if (s1_2 < s2_2)
    res2 = s2_2;
  if (s1_3 < s2_3)
    res3 = s2_3;
  return (res3 << 24) | (res2 << 16) | (res1 << 8) | res0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_maxu4>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%ecx
  mov    %edi,%eax
  shr    $0x18,%eax
  shr    $0x18,%esi
  cmp    %esi,%eax
  cmovb  %esi,%eax
  shl    $0x18,%eax
  movzbl %dil,%esi
  movzbl %cl,%edi
  cmp    %edi,%esi
  cmovb  %edi,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    $0x10,%esi
  movzbl %sil,%esi
  mov    %ecx,%edi
  shr    $0x10,%edi
  movzbl %dil,%edi
  cmp    %edi,%esi
  cmovb  %edi,%esi
  shl    $0x10,%esi
  or     %esi,%eax
  movzbl %dh,%edx
  movzbl %ch,%ecx
  cmp    %ecx,%edx
  cmovb  %ecx,%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int _maxu4(unsigned int src1, unsigned int src2) {
  unsigned int res0, res1, res2, res3;
  unsigned int s1_0 = res0 = (src1 & 0xFF);
  unsigned int s1_1 = res1 = (src1 & 0xFF00) >> 8;
  unsigned int s1_2 = res2 = (src1 & 0xFF0000) >> 16;
  unsigned int s1_3 = res3 = (src1 & 0xFF000000) >> 24;
  unsigned int s2_0 = (src2 & 0xFF);
  unsigned int s2_1 = (src2 & 0xFF00) >> 8;
  unsigned int s2_2 = (src2 & 0xFF0000) >> 16;
  unsigned int s2_3 = (src2 & 0xFF000000) >> 24;
  if (s1_0 < s2_0)
    res0 = s2_0;
  if (s1_1 < s2_1)
    res1 = s2_1;
  if (s1_2 < s2_2)
    res2 = s2_2;
  if (s1_3 < s2_3)
    res3 = s2_3;
  return (res3 << 24) | (res2 << 16) | (res1 << 8) | res0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_maxu4>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  shr    $0x18,%esi
  mov    %edi,%edx
  shr    $0x18,%eax
  cmp    %esi,%eax
  cmovb  %esi,%eax
  movzbl %dil,%esi
  movzbl %cl,%edi
  shl    $0x18,%eax
  cmp    %edi,%esi
  cmovb  %edi,%esi
  mov    %ecx,%edi
  movzbl %ch,%ecx
  shr    $0x10,%edi
  or     %esi,%eax
  mov    %edx,%esi
  movzbl %dil,%edi
  movzbl %dh,%edx
  shr    $0x10,%esi
  movzbl %sil,%esi
  cmp    %edi,%esi
  cmovb  %edi,%esi
  shl    $0x10,%esi
  or     %esi,%eax
  cmp    %ecx,%edx
  cmovb  %ecx,%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int _maxu4(unsigned int src1, unsigned int src2) {
  unsigned int res0, res1, res2, res3;
  unsigned int s1_0 = res0 = (src1 & 0xFF);
  unsigned int s1_1 = res1 = (src1 & 0xFF00) >> 8;
  unsigned int s1_2 = res2 = (src1 & 0xFF0000) >> 16;
  unsigned int s1_3 = res3 = (src1 & 0xFF000000) >> 24;
  unsigned int s2_0 = (src2 & 0xFF);
  unsigned int s2_1 = (src2 & 0xFF00) >> 8;
  unsigned int s2_2 = (src2 & 0xFF0000) >> 16;
  unsigned int s2_3 = (src2 & 0xFF000000) >> 24;
  if (s1_0 < s2_0)
    res0 = s2_0;
  if (s1_1 < s2_1)
    res1 = s2_1;
  if (s1_2 < s2_2)
    res2 = s2_2;
  if (s1_3 < s2_3)
    res3 = s2_3;
  return (res3 << 24) | (res2 << 16) | (res1 << 8) | res0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_maxu4>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  shr    $0x18,%esi
  mov    %edi,%edx
  shr    $0x18,%eax
  cmp    %esi,%eax
  cmovb  %esi,%eax
  movzbl %dil,%esi
  movzbl %cl,%edi
  shl    $0x18,%eax
  cmp    %edi,%esi
  cmovb  %edi,%esi
  mov    %ecx,%edi
  movzbl %ch,%ecx
  shr    $0x10,%edi
  or     %esi,%eax
  mov    %edx,%esi
  movzbl %dil,%edi
  movzbl %dh,%edx
  shr    $0x10,%esi
  movzbl %sil,%esi
  cmp    %edi,%esi
  cmovb  %edi,%esi
  shl    $0x10,%esi
  or     %esi,%eax
  cmp    %ecx,%edx
  cmovb  %ecx,%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int _maxu4(unsigned int src1, unsigned int src2) {
  unsigned int res0, res1, res2, res3;
  unsigned int s1_0 = res0 = (src1 & 0xFF);
  unsigned int s1_1 = res1 = (src1 & 0xFF00) >> 8;
  unsigned int s1_2 = res2 = (src1 & 0xFF0000) >> 16;
  unsigned int s1_3 = res3 = (src1 & 0xFF000000) >> 24;
  unsigned int s2_0 = (src2 & 0xFF);
  unsigned int s2_1 = (src2 & 0xFF00) >> 8;
  unsigned int s2_2 = (src2 & 0xFF0000) >> 16;
  unsigned int s2_3 = (src2 & 0xFF000000) >> 24;
  if (s1_0 < s2_0)
    res0 = s2_0;
  if (s1_1 < s2_1)
    res1 = s2_1;
  if (s1_2 < s2_2)
    res2 = s2_2;
  if (s1_3 < s2_3)
    res3 = s2_3;
  return (res3 << 24) | (res2 << 16) | (res1 << 8) | res0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<IP2Broadcast>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x80000000,-0xc(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L32:
  mov    -0xc(%rbp),%eax
  and    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L35
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  or     %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  and    %eax,-0x8(%rbp)
  sarl   -0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L36:
  cmpl   $0x1e,-0x4(%rbp)
  jle    L32
  jmp    L16
L35:
  nop
L16:
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
in_addr_t IP2Broadcast(in_addr_t IP, in_addr_t Mask) {
  in_addr_t bcIP;
  in_addr_t bit;
  in_addr_t notbit;
  int i;
  bit = 0x80000000;
  notbit = 0xFFFFFFFF;
  bcIP = 0;
  for (i = 0; i < 31; i++) {
    if ((bit & Mask) == 0)
      break;
    bcIP |= (IP & bit);
    notbit &= ~bit;
    bit = bit >> 1;
  }
  return bcIP;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IP2Broadcast>:
  endbr64
  test   %esi,%esi
  jns    L29
  mov    %edi,%ecx
  and    $0x80000000,%ecx
  mov    $0x1e,%edx
  mov    $0xc0000000,%eax
L10:
  test   %eax,%esi
  je     L5
  mov    %edi,%r8d
  and    %eax,%r8d
  or     %r8d,%ecx
  sar    %eax
  sub    $0x1,%edx
  jne    L10
L5:
  mov    %ecx,%eax
  ret
L29:
  mov    $0x0,%ecx
  jmp    L5
```

assistant: ```c
in_addr_t IP2Broadcast(in_addr_t IP, in_addr_t Mask) {
  in_addr_t bcIP;
  in_addr_t bit;
  in_addr_t notbit;
  int i;
  bit = 0x80000000;
  notbit = 0xFFFFFFFF;
  bcIP = 0;
  for (i = 0; i < 31; i++) {
    if ((bit & Mask) == 0)
      break;
    bcIP |= (IP & bit);
    notbit &= ~bit;
    bit = bit >> 1;
  }
  return bcIP;
}
```
user: What is the c source code of the assembly code below:

```asm
<IP2Broadcast>:
  endbr64
  mov    $0x1f,%edx
  mov    $0x80000000,%eax
  xor    %r8d,%r8d
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %edi,%ecx
  and    %eax,%ecx
  sar    %eax
  or     %ecx,%r8d
  sub    $0x1,%edx
  je     L27
L26:
  test   %eax,%esi
  jne    L4
L27:
  mov    %r8d,%eax
  ret
```

assistant: ```c
in_addr_t IP2Broadcast(in_addr_t IP, in_addr_t Mask) {
  in_addr_t bcIP;
  in_addr_t bit;
  in_addr_t notbit;
  int i;
  bit = 0x80000000;
  notbit = 0xFFFFFFFF;
  bcIP = 0;
  for (i = 0; i < 31; i++) {
    if ((bit & Mask) == 0)
      break;
    bcIP |= (IP & bit);
    notbit &= ~bit;
    bit = bit >> 1;
  }
  return bcIP;
}
```
user: What is the c source code of the assembly code below:

```asm
<IP2Broadcast>:
  endbr64
  mov    $0x1f,%edx
  mov    $0x80000000,%eax
  xor    %r8d,%r8d
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %edi,%ecx
  and    %eax,%ecx
  sar    %eax
  or     %ecx,%r8d
  sub    $0x1,%edx
  je     L16
L25:
  test   %eax,%esi
  jne    L1
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
in_addr_t IP2Broadcast(in_addr_t IP, in_addr_t Mask) {
  in_addr_t bcIP;
  in_addr_t bit;
  in_addr_t notbit;
  int i;
  bit = 0x80000000;
  notbit = 0xFFFFFFFF;
  bcIP = 0;
  for (i = 0; i < 31; i++) {
    if ((bit & Mask) == 0)
      break;
    bcIP |= (IP & bit);
    notbit &= ~bit;
    bit = bit >> 1;
  }
  return bcIP;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fatal_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void fatal_error(char *msg, ...) {
  puts(msg);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fatal_error>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fatal_error(char *msg, ...) {
  puts(msg);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fatal_error>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fatal_error(char *msg, ...) {
  puts(msg);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fatal_error>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fatal_error(char *msg, ...) {
  puts(msg);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L27
L6:
  movslq %r14d,%rdx
  mov    (%rbx,%rax,4),%ecx
  cmp    %ecx,(%rbx,%rdx,4)
  cmovg  %eax,%r14d
  add    $0x1,%rax
  cmp    $0x9,%eax
  jle    L6
L24:
  mov    (%rbx,%rbp,4),%eax
  mov    %eax,0x14(%rsp)
  mov    %r13,%r12
  lea    0x0(%r13,%rbp,8),%rax
  mov    %rax,0x18(%rsp)
  mov    %rax,%rsi
  mov    0x8(%rsp),%rdi
  call   <strcpy@plt>
  movslq %r14d,%r14
  lea    (%rbx,%r14,4),%r15
  mov    (%r15),%eax
  mov    %eax,(%rbx,%rbp,4)
  lea    0x0(%r13,%r14,8),%r14
  mov    %r14,%rsi
  mov    0x18(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,(%r15)
  mov    0x8(%rsp),%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  add    $0x1,%rbp
  cmp    $0x9,%rbp
  je     L53
L27:
  mov    %ebp,%r14d
  mov    %rbp,%rax
  cmp    $0x9,%ebp
  jle    L6
  jmp    L24
L53:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    0x50(%r13),%r13
  lea    D1(%rip),%rbp
L31:
  mov    %r12,%rdx
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  add    $0x8,%r12
  cmp    %r13,%r12
  jne    L31
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D1
type: string

tool: D16: 
 result:

tool: D1: 
 %5d%10s

assistant: ```c
void sort(int num[], char name[10][8]) {
  int i, j, min, templ;
  char temp2[8];
  for (i = 0; i < 10 - 1; i++) {
    min = i;
    for (j = i; j < 10; j++)
      if (num[min] > num[j])
        min = j;
    templ = num[i];
    strcpy(temp2, name[i]);
    num[i] = num[min];
    strcpy(name[i], name[min]);
    num[min] = templ;
    strcpy(name[min], temp2);
  }
  printf("\n result:\n");
  for (i = 0; i < 10; i++)
    printf("\n %5d%10s", num[i], name[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  push   %r15
  xor    %r8d,%r8d
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rsi,0x28(%rsp)
  lea    0x30(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r8d,%ecx
  mov    %rbp,%rdx
  mov    %r8,%rax
  nopl   0x0(%rax)
L39:
  movslq %ecx,%r14
  mov    (%rdx),%esi
  lea    (%r15,%r14,4),%rbx
  cmp    %esi,(%rbx)
  cmovg  %rdx,%rbx
  cmovg  %rax,%r14
  cmovg  %eax,%ecx
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    $0xa,%rax
  jne    L39
  mov    0x28(%rsp),%r13
  mov    0x0(%rbp),%ecx
  mov    %r12,%rdi
  mov    %r8,0x18(%rsp)
  add    $0x4,%rbp
  lea    0x0(%r13,%r8,8),%r10
  mov    %ecx,0x24(%rsp)
  lea    0x0(%r13,%r14,8),%r14
  mov    %r10,%rsi
  mov    %r10,0x10(%rsp)
  call   <strcpy@plt>
  mov    (%rbx),%eax
  mov    0x10(%rsp),%rdi
  mov    %r14,%rsi
  mov    %eax,-0x4(%rbp)
  call   <strcpy@plt>
  mov    0x24(%rsp),%ecx
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %ecx,(%rbx)
  call   <strcpy@plt>
  mov    0x18(%rsp),%r8
  add    $0x1,%r8
  cmp    $0x9,%r8
  jne    L9
  lea    D10(%rip),%rdi
  lea    0x50(%r13),%r12
  call   <puts@plt>
  lea    D8(%rip),%rbx
L21:
  mov    0x8(%rsp),%r15
  mov    %r13,%rdx
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x8,%r13
  mov    (%r15),%esi
  call   <printf@plt>
  mov    %r15,%rax
  add    $0x4,%rax
  mov    %rax,0x8(%rsp)
  cmp    %r13,%r12
  jne    L21
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D8
data_type: string

tool: D10: 
 result:

tool: D8: 
 %5d%10s

assistant: ```c
void sort(int num[], char name[10][8]) {
  int i, j, min, templ;
  char temp2[8];
  for (i = 0; i < 10 - 1; i++) {
    min = i;
    for (j = i; j < 10; j++)
      if (num[min] > num[j])
        min = j;
    templ = num[i];
    strcpy(temp2, name[i]);
    num[i] = num[min];
    strcpy(name[i], name[min]);
    num[min] = templ;
    strcpy(name[min], temp2);
  }
  printf("\n result:\n");
  for (i = 0; i < 10; i++)
    printf("\n %5d%10s", num[i], name[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ipiksrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L15
L55:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L50
L44:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x10(%rbp)
L50:
  cmpl   $0x0,-0x10(%rbp)
  jle    L51
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss -0x8(%rbp),%xmm0
  ja     L44
L51:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L13
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L13:
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L55
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ipiksrt(float arrayOfFloats[], int arrayLength, int arrayOfInts[]) {
  float fValue;
  int iValue;
  int position;
  for (int j = 1; j < arrayLength; j++) {
    fValue = arrayOfFloats[j];
    iValue = arrayOfInts[j];
    position = j;
    while (position > 0 && arrayOfFloats[position - 1] > fValue) {
      arrayOfFloats[position] = arrayOfFloats[position - 1];
      arrayOfInts[position] = arrayOfInts[position - 1];
      position--;
    }
    if (position != j) {
      arrayOfFloats[position] = fValue;
      arrayOfInts[position] = iValue;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ipiksrt>:
  endbr64
  cmp    $0x1,%esi
  jle    L77
  mov    %esi,%r9d
  mov    $0x1,%esi
  jmp    L71
L58:
  cmp    %r8d,%ecx
  je     L41
  movslq %ecx,%rcx
  movss  %xmm1,(%rdi,%rcx,4)
  mov    %r10d,(%rdx,%rcx,4)
L41:
  add    $0x1,%rsi
  cmp    %r9,%rsi
  je     L77
L71:
  movss  (%rdi,%rsi,4),%xmm1
  mov    (%rdx,%rsi,4),%r10d
  mov    %esi,%r8d
  mov    %rsi,%rax
  test   %esi,%esi
  jle    L41
L49:
  mov    %eax,%ecx
  movss  -0x4(%rdi,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  jbe    L58
  movss  %xmm0,(%rdi,%rax,4)
  mov    -0x4(%rdx,%rax,4),%ecx
  mov    %ecx,(%rdx,%rax,4)
  lea    -0x1(%rax),%ecx
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L49
  jmp    L58
L77:
  ret
```

assistant: ```c
void ipiksrt(float arrayOfFloats[], int arrayLength, int arrayOfInts[]) {
  float fValue;
  int iValue;
  int position;
  for (int j = 1; j < arrayLength; j++) {
    fValue = arrayOfFloats[j];
    iValue = arrayOfInts[j];
    position = j;
    while (position > 0 && arrayOfFloats[position - 1] > fValue) {
      arrayOfFloats[position] = arrayOfFloats[position - 1];
      arrayOfInts[position] = arrayOfInts[position - 1];
      position--;
    }
    if (position != j) {
      arrayOfFloats[position] = fValue;
      arrayOfInts[position] = iValue;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ipiksrt>:
  endbr64
  mov    %rdi,%rcx
  movslq %esi,%r10
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L20
  nopl   (%rax)
L18:
  movss  (%rcx,%r8,4),%xmm1
  mov    (%rdx,%r8,4),%r9d
  mov    %r8,%rax
  nopl   (%rax)
L3:
  movss  -0x4(%rcx,%rax,4),%xmm0
  mov    %eax,%edi
  lea    0x0(,%rax,4),%rsi
  comiss %xmm1,%xmm0
  jbe    L19
  mov    -0x4(%rdx,%rax,4),%esi
  movss  %xmm0,(%rcx,%rax,4)
  mov    %esi,(%rdx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jne    L3
  mov    %rdx,%rsi
  mov    %rcx,%rax
L29:
  movss  %xmm1,(%rax)
  mov    %r9d,(%rsi)
L28:
  add    $0x1,%r8
  cmp    %r8,%r10
  jne    L18
L20:
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  lea    (%rcx,%rsi,1),%rax
  add    %rdx,%rsi
  cmp    %r8d,%edi
  je     L28
  jmp    L29
```

assistant: ```c
void ipiksrt(float arrayOfFloats[], int arrayLength, int arrayOfInts[]) {
  float fValue;
  int iValue;
  int position;
  for (int j = 1; j < arrayLength; j++) {
    fValue = arrayOfFloats[j];
    iValue = arrayOfInts[j];
    position = j;
    while (position > 0 && arrayOfFloats[position - 1] > fValue) {
      arrayOfFloats[position] = arrayOfFloats[position - 1];
      arrayOfInts[position] = arrayOfInts[position - 1];
      position--;
    }
    if (position != j) {
      arrayOfFloats[position] = fValue;
      arrayOfInts[position] = iValue;
    }
  }
}
```