ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<R_DestroyVolatileAssets>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <R_ShutdownCustomColors@plt>
  xor    %eax,%eax
  call   <R_ShutdownShadows@plt>
  xor    %eax,%eax
  call   <R_ShutdownOutlines@plt>
  xor    %eax,%eax
  call   <R_ShutdownCoronas@plt>
  xor    %eax,%eax
  call   <R_ShutdownOcclusionQueries@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10e0 <R_ShutdownSkeletalCache@plt>
```

assistant: ```c
void R_DestroyVolatileAssets(void) {
  R_ShutdownCustomColors();
  R_ShutdownShadows();
  R_ShutdownOutlines();
  R_ShutdownCoronas();
  R_ShutdownOcclusionQueries();
  R_ShutdownSkeletalCache();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L7:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L7
  sub    $0xe50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x4e40(%rbp)
  lea    D67(%rip),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x4e38(%rbp)
  lea    -0x4e30(%rbp),%rax
  mov    $0x4e20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x4e47(%rbp),%rcx
  lea    -0x4e46(%rbp),%rdx
  mov    -0x4e40(%rbp),%rax
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movw   $0x0,-0x4e42(%rbp)
  jmp    L31
L25:
  lea    -0x4e44(%rbp),%rdx
  mov    -0x4e40(%rbp),%rax
  lea    D51(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movzwl -0x4e44(%rbp),%eax
  cwtl
  sub    $0x1,%eax
  movslq %eax,%rdx
  movzwl -0x4e30(%rbp,%rdx,2),%edx
  add    $0x1,%edx
  mov    %edx,%ecx
  movslq %eax,%rdx
  mov    %cx,-0x4e30(%rbp,%rdx,2)
  cltq
  movzwl -0x4e30(%rbp,%rax,2),%eax
  movswl %ax,%edx
  mov    -0x4e38(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  movzwl -0x4e42(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4e42(%rbp)
L31:
  movzwl -0x4e46(%rbp),%eax
  cmp    %ax,-0x4e42(%rbp)
  jl     L25
  mov    -0x4e38(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    $0x0,%eax
  call   <fcloseall@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D35
data_type: string
name: unpack_data
arguments: tag: D67
data_type: string
name: unpack_data
arguments: tag: D11
data_type: string
name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D51
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string

tool: D31: r

tool: D35: INP.TXT

tool: D67: w

tool: D11: OUT.TXT

tool: D8: %hd %hhd

tool: D51: %hd

tool: D4: %hd 

assistant: ```c
int main() {
  FILE *fi = fopen("INP.TXT", "r"), *fo = fopen("OUT.TXT", "w");
  short n, i, a, b[10000] = {};
  char m;
  fscanf(fi, "%hd %hhd", &n, &m);
  for (i = 0; i < n; i++) {
    fscanf(fi, "%hd", &a);
    fprintf(fo, "%hd ", ++b[a - 1]);
  }
  fputc(10, fo);
  fcloseall();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L33:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L33
  sub    $0xe48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e38(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rsi
  lea    D5(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  lea    D19(%rip),%rsi
  lea    D50(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    0x10(%rsp),%rdi
  mov    $0x4e20,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0xb(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    D49(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  cmpw   $0x0,0xc(%rsp)
  jle    L7
  mov    $0x0,%ebx
  lea    0xe(%rsp),%r15
  lea    D28(%rip),%r14
  lea    D32(%rip),%r13
L13:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movswl 0xe(%rsp),%eax
  sub    $0x1,%eax
  cltq
  movzwl 0x10(%rsp,%rax,2),%ecx
  lea    0x1(%rcx),%edx
  mov    %dx,0x10(%rsp,%rax,2)
  movswl %dx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    %bx,0xc(%rsp)
  jg     L13
L7:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    $0x0,%eax
  call   <fcloseall@plt>
  mov    0x4e38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x4e48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D50
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D49
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D32
type_guessed: string

tool: D27: r

tool: D5: INP.TXT

tool: D19: w

tool: D50: OUT.TXT

tool: D49: %hd %hhd

tool: D28: %hd

tool: D32: %hd 

assistant: ```c
int main() {
  FILE *fi = fopen("INP.TXT", "r"), *fo = fopen("OUT.TXT", "w");
  short n, i, a, b[10000] = {};
  char m;
  fscanf(fi, "%hd %hhd", &n, &m);
  for (i = 0; i < n; i++) {
    fscanf(fi, "%hd", &a);
    fprintf(fo, "%hd ", ++b[a - 1]);
  }
  fputc(10, fo);
  fcloseall();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0xe48,%rsp
  lea    D67(%rip),%rsi
  lea    D59(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x4e38(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    D41(%rip),%rsi
  lea    D44(%rip),%rdi
  mov    %rax,%rbx
  call   <fopen@plt>
  xor    %esi,%esi
  lea    0x10(%rsp),%rdi
  mov    $0x4e20,%edx
  mov    %rax,%rbp
  call   <memset@plt>
  xor    %eax,%eax
  lea    0xb(%rsp),%rcx
  mov    %rbx,%rdi
  lea    0xc(%rsp),%rdx
  lea    D3(%rip),%rsi
  call   <fscanf@plt>
  cmpw   $0x0,0xc(%rsp)
  jle    L0
  xor    %r15d,%r15d
  lea    0xe(%rsp),%r14
  lea    D11(%rip),%r13
  lea    D13(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  movswl 0xe(%rsp),%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r15d
  sub    $0x1,%eax
  cltq
  movzwl 0x10(%rsp,%rax,2),%ecx
  lea    0x1(%rcx),%edx
  mov    %dx,0x10(%rsp,%rax,2)
  movswl %dx,%edx
  call   <fprintf@plt>
  cmp    %r15w,0xc(%rsp)
  jg     L26
L0:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  xor    %eax,%eax
  call   <fcloseall@plt>
  mov    0x4e38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x4e48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D67
type: string
name: unpack_data
arguments: tag: D59
type: string
name: unpack_data
arguments: tag: D41
type: string
name: unpack_data
arguments: tag: D44
type: string
name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D11
type: string
name: unpack_data
arguments: tag: D13
type: string

tool: D67: r

tool: D59: INP.TXT

tool: D41: w

tool: D44: OUT.TXT

tool: D3: %hd %hhd

tool: D11: %hd

tool: D13: %hd 

assistant: ```c
int main() {
  FILE *fi = fopen("INP.TXT", "r"), *fo = fopen("OUT.TXT", "w");
  short n, i, a, b[10000] = {};
  char m;
  fscanf(fi, "%hd %hhd", &n, &m);
  for (i = 0; i < n; i++) {
    fscanf(fi, "%hd", &a);
    fprintf(fo, "%hd ", ++b[a - 1]);
  }
  fputc(10, fo);
  fcloseall();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L1:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L1
  sub    $0xe48,%rsp
  lea    D28(%rip),%rsi
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x4e38(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    D33(%rip),%rsi
  lea    D63(%rip),%rdi
  mov    %rax,%rbx
  call   <fopen@plt>
  xor    %esi,%esi
  lea    0x10(%rsp),%rdi
  mov    $0x4e20,%edx
  mov    %rax,%rbp
  call   <memset@plt>
  xor    %eax,%eax
  lea    0xb(%rsp),%rcx
  mov    %rbx,%rdi
  lea    0xc(%rsp),%rdx
  lea    D12(%rip),%rsi
  call   <fscanf@plt>
  cmpw   $0x0,0xc(%rsp)
  jle    L28
  xor    %r15d,%r15d
  lea    0xe(%rsp),%r14
  lea    D40(%rip),%r13
  lea    D61(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  movswl 0xe(%rsp),%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r15d
  sub    $0x1,%eax
  cltq
  movzwl 0x10(%rsp,%rax,2),%ecx
  lea    0x1(%rcx),%edx
  mov    %dx,0x10(%rsp,%rax,2)
  movswl %dx,%edx
  call   <fprintf@plt>
  cmp    %r15w,0xc(%rsp)
  jg     L5
L28:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  xor    %eax,%eax
  call   <fcloseall@plt>
  mov    0x4e38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x4e48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D33
type_infered: string
name: retrieve_data
arguments: data_tag: D63
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D40
type_infered: string
name: retrieve_data
arguments: data_tag: D61
type_infered: string

tool: D28: r

tool: D8: INP.TXT

tool: D33: w

tool: D63: OUT.TXT

tool: D12: %hd %hhd

tool: D40: %hd

tool: D61: %hd 

assistant: ```c
int main() {
  FILE *fi = fopen("INP.TXT", "r"), *fo = fopen("OUT.TXT", "w");
  short n, i, a, b[10000] = {};
  char m;
  fscanf(fi, "%hd %hhd", &n, &m);
  for (i = 0; i < n; i++) {
    fscanf(fi, "%hd", &a);
    fprintf(fo, "%hd ", ++b[a - 1]);
  }
  fputc(10, fo);
  fcloseall();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strrchr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  and    $0xfffffffffffffff8,%r12
  movslq %esi,%r13
  movabs $0x101010101010101,%rax
  imul   %rax,%r13
  lea    0x0(,%rdi,8),%rsi
  mov    $0x1,%edi
  call   <__insn_shl@plt>
  lea    -0x1(%rax),%rdi
  mov    %rdi,%rbp
  or     (%r12),%rbp
  mov    $0x1,%esi
  call   <__insn_v1shrui@plt>
  and    %r13,%rax
  mov    %rax,%rbx
  xor    %rbp,%rbx
  mov    $0x0,%r14d
  mov    $0x7,%r15d
  jmp    L37
L67:
  mov    %rbp,%rdi
  call   <__insn_ctz@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  sub    $0x1,%rdx
  and    %rdx,%rbx
  jmp    L14
L45:
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L30
  add    $0x8,%r12
  mov    (%r12),%rbx
L37:
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <__insn_v1cmpeqi@plt>
  mov    %rax,%rbp
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <__insn_v1cmpeq@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L45
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L67
L14:
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  mov    $0x1,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L45
  mov    %rbx,%rdi
  call   <__insn_clz@plt>
  sar    $0x3,%eax
  cltq
  mov    %r15,%r14
  sub    %rax,%r14
  add    %r12,%r14
  jmp    L45
L30:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  const uintptr_t s_int = (uintptr_t)s;
  const uint64_t *p = (const uint64_t *)(s_int & -8);
  const uint64_t goal = 0x0101010101010101ULL * (uint8_t)c;
  const uint64_t before_mask = (__insn_shl(1ULL, (s_int << 3)) - 1);
  uint64_t v = (*p | before_mask) ^ (goal & __insn_v1shrui(before_mask, 1));
  const char *found = NULL;
  uint64_t zero_matches, goal_matches;
  while (1) {
    zero_matches = __insn_v1cmpeqi(v, 0);
    goal_matches = __insn_v1cmpeq(v, goal);
    if (__builtin_expect(goal_matches != 0, 0)) {
      if (__builtin_expect(zero_matches != 0, 0)) {
        int first_nul = __insn_ctz(zero_matches);
        goal_matches &= ((2ULL << first_nul) - 1);
      }
      if (__builtin_expect(goal_matches != 0, 1))
        found = ((char *)p) + 7 - (__insn_clz(goal_matches) >> 3);
    }
    if (__builtin_expect(zero_matches != 0, 0))
      return (char *)found;
    v = *++p;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strrchr>:
  endbr64
  movabs $0x101010101010101,%rax
  push   %r15
  push   %r14
  push   %r13
  movslq %esi,%r13
  lea    0x0(,%rdi,8),%rsi
  push   %r12
  imul   %rax,%r13
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  and    $0xfffffffffffffff8,%rbx
  sub    $0x18,%rsp
  call   <__insn_shl@plt>
  mov    (%rbx),%r12
  mov    $0x1,%esi
  lea    -0x1(%rax),%rdi
  or     %rdi,%r12
  call   <__insn_v1shrui@plt>
  movq   $0x0,0x8(%rsp)
  and    %r13,%rax
  mov    %rax,%rbp
  xor    %r12,%rbp
  jmp    L12
  nopl   0x0(%rax)
L50:
  xor    %esi,%esi
  mov    %r15d,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L29
L24:
  mov    0x8(%rbx),%rbp
  add    $0x8,%rbx
L12:
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <__insn_v1cmpeqi@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  mov    %rax,%r12
  call   <__insn_v1cmpeq@plt>
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %r14b
  xor    %esi,%esi
  xor    %r15d,%r15d
  mov    %r14d,%edi
  call   <__builtin_expect@plt>
  test   %r12,%r12
  setne  %r15b
  test   %rax,%rax
  je     L50
  xor    %esi,%esi
  mov    %r15d,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L33
L40:
  mov    $0x1,%esi
  mov    %r14d,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L50
  mov    %rbp,%rdi
  mov    $0x7,%r14d
  call   <__insn_clz@plt>
  xor    %esi,%esi
  mov    %r15d,%edi
  sar    $0x3,%eax
  cltq
  sub    %rax,%r14
  lea    (%rbx,%r14,1),%rax
  mov    %rax,0x8(%rsp)
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L24
L29:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r12,%rdi
  xor    %r14d,%r14d
  call   <__insn_ctz@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  lea    -0x1(%rdx),%rax
  and    %rax,%rbp
  setne  %r14b
  jmp    L40
```

assistant: ```c
char *strrchr(const char *s, int c) {
  const uintptr_t s_int = (uintptr_t)s;
  const uint64_t *p = (const uint64_t *)(s_int & -8);
  const uint64_t goal = 0x0101010101010101ULL * (uint8_t)c;
  const uint64_t before_mask = (__insn_shl(1ULL, (s_int << 3)) - 1);
  uint64_t v = (*p | before_mask) ^ (goal & __insn_v1shrui(before_mask, 1));
  const char *found = NULL;
  uint64_t zero_matches, goal_matches;
  while (1) {
    zero_matches = __insn_v1cmpeqi(v, 0);
    goal_matches = __insn_v1cmpeq(v, goal);
    if (__builtin_expect(goal_matches != 0, 0)) {
      if (__builtin_expect(zero_matches != 0, 0)) {
        int first_nul = __insn_ctz(zero_matches);
        goal_matches &= ((2ULL << first_nul) - 1);
      }
      if (__builtin_expect(goal_matches != 0, 1))
        found = ((char *)p) + 7 - (__insn_clz(goal_matches) >> 3);
    }
    if (__builtin_expect(zero_matches != 0, 0))
      return (char *)found;
    v = *++p;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strrchr>:
  endbr64
  movabs $0x101010101010101,%rax
  push   %r15
  push   %r14
  push   %r13
  movslq %esi,%r13
  lea    0x0(,%rdi,8),%rsi
  push   %r12
  imul   %rax,%r13
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  and    $0xfffffffffffffff8,%rbx
  sub    $0x18,%rsp
  call   <__insn_shl@plt>
  mov    (%rbx),%r12
  mov    $0x1,%esi
  lea    -0x1(%rax),%rdi
  or     %rdi,%r12
  call   <__insn_v1shrui@plt>
  movq   $0x0,0x8(%rsp)
  and    %r13,%rax
  mov    %rax,%rbp
  xor    %r12,%rbp
  jmp    L9
  nopl   0x0(%rax)
L12:
  xor    %esi,%esi
  mov    %r15d,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L46
L6:
  mov    0x8(%rbx),%rbp
  add    $0x8,%rbx
L9:
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <__insn_v1cmpeqi@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  mov    %rax,%r12
  call   <__insn_v1cmpeq@plt>
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %r14b
  xor    %esi,%esi
  xor    %r15d,%r15d
  mov    %r14d,%edi
  call   <__builtin_expect@plt>
  test   %r12,%r12
  setne  %r15b
  test   %rax,%rax
  je     L12
  xor    %esi,%esi
  mov    %r15d,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L8
L10:
  mov    $0x1,%esi
  mov    %r14d,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L12
  mov    %rbp,%rdi
  mov    $0x7,%r14d
  call   <__insn_clz@plt>
  xor    %esi,%esi
  mov    %r15d,%edi
  sar    $0x3,%eax
  cltq
  sub    %rax,%r14
  lea    (%rbx,%r14,1),%rax
  mov    %rax,0x8(%rsp)
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L6
L46:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r12,%rdi
  xor    %r14d,%r14d
  call   <__insn_ctz@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  lea    -0x1(%rdx),%rax
  and    %rax,%rbp
  setne  %r14b
  jmp    L10
```

assistant: ```c
char *strrchr(const char *s, int c) {
  const uintptr_t s_int = (uintptr_t)s;
  const uint64_t *p = (const uint64_t *)(s_int & -8);
  const uint64_t goal = 0x0101010101010101ULL * (uint8_t)c;
  const uint64_t before_mask = (__insn_shl(1ULL, (s_int << 3)) - 1);
  uint64_t v = (*p | before_mask) ^ (goal & __insn_v1shrui(before_mask, 1));
  const char *found = NULL;
  uint64_t zero_matches, goal_matches;
  while (1) {
    zero_matches = __insn_v1cmpeqi(v, 0);
    goal_matches = __insn_v1cmpeq(v, goal);
    if (__builtin_expect(goal_matches != 0, 0)) {
      if (__builtin_expect(zero_matches != 0, 0)) {
        int first_nul = __insn_ctz(zero_matches);
        goal_matches &= ((2ULL << first_nul) - 1);
      }
      if (__builtin_expect(goal_matches != 0, 1))
        found = ((char *)p) + 7 - (__insn_clz(goal_matches) >> 3);
    }
    if (__builtin_expect(zero_matches != 0, 0))
      return (char *)found;
    v = *++p;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<WriteOutputData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %ecx,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x60(%rbp)
  je     L31
  lea    D23(%rip),%rax
  mov    %rax,-0x48(%rbp)
  jmp    L39
L31:
  lea    D33(%rip),%rax
  mov    %rax,-0x48(%rbp)
L39:
  mov    -0x48(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L38
L35:
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <OutStringFromChar@plt>
  lea    -0x40(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  lea    D18(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  addl   $0x1,-0x4c(%rbp)
L38:
  mov    -0x4c(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L35
  mov    -0x68(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x12,%edx
  mov    $0x1,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D23
datatype: string
name: unpack_data
arguments: data_tag: D33
datatype: string
name: unpack_data
arguments: data_tag: D26
datatype: string
name: unpack_data
arguments: data_tag: D18
datatype: string
name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D23: right

tool: D33: left

tool: D26: <table align = "%s">
<tr>

tool: D18: <td>%s</td>

tool: D0: 
</table><br><br>


assistant: ```c
void WriteOutputData(char *output, int cch, FILE *outfile, int baselevel) {
  char out[50];
  char *align;
  if (baselevel)
    align = "right";
  else
    align = "left";
  fprintf(outfile, "<table align = \"%s\">\n<tr>", align);
  for (int i = 0; i < cch; i++) {
    OutStringFromChar(output[i], out);
    fprintf(outfile, "<td>%s</td>", out);
  }
  fprintf(outfile, "\n</table><br><br>\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<WriteOutputData>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  lea    D41(%rip),%rdx
  lea    D5(%rip),%rax
  cmove  %rax,%rdx
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  test   %ebp,%ebp
  jle    L6
  mov    %r13,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r13,%rax,1),%r14
  lea    D28(%rip),%r13
L22:
  mov    %rsp,%rbp
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <OutStringFromChar@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L22
L6:
  mov    %r12,%rcx
  mov    $0x12,%edx
  mov    $0x1,%esi
  lea    D46(%rip),%rdi
  call   <fwrite@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D41
type_infered: string
name: extract_symbolic_data
arguments: label: D5
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D46
type_infered: string

tool: D41: right

tool: D5: left

tool: D14: <table align = "%s">
<tr>

tool: D28: <td>%s</td>

tool: D46: 
</table><br><br>


assistant: ```c
void WriteOutputData(char *output, int cch, FILE *outfile, int baselevel) {
  char out[50];
  char *align;
  if (baselevel)
    align = "right";
  else
    align = "left";
  fprintf(outfile, "<table align = \"%s\">\n<tr>", align);
  for (int i = 0; i < cch; i++) {
    OutStringFromChar(output[i], out);
    fprintf(outfile, "<td>%s</td>", out);
  }
  fprintf(outfile, "\n</table><br><br>\n");
}
```