ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<minDistance>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  call   <strlen@plt>
  mov    %eax,0x1c(%rsp)
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,0xc(%rsp)
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  test   %ebx,%ebx
  js     L1
  mov    %rax,%rdx
  lea    0x1(%rbx),%ecx
  mov    $0x0,%eax
L77:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L77
L1:
  cmpl   $0x0,0x1c(%rsp)
  jle    L83
  movl   $0x1,0x18(%rsp)
  jmp    L74
L17:
  mov    %edx,0x0(%r13)
  add    $0x1,%rbp
  add    $0x4,%rbx
  cmp    %ebp,0xc(%rsp)
  jl     L68
L18:
  mov    %rbx,%r13
  mov    %r12d,%edx
  mov    (%rbx),%r12d
  movzbl -0x1(%r15,%rbp,1),%eax
  cmp    %al,(%r14)
  je     L17
  mov    -0x4(%rbx),%edi
  mov    %r12d,%esi
  call   <min@plt>
  lea    0x1(%rax),%edx
  jmp    L17
L68:
  mov    0x10(%rsp),%rcx
  mov    0x18(%rsp),%eax
  mov    %eax,(%rcx)
  add    $0x1,%eax
  mov    %eax,0x18(%rsp)
  add    $0x1,%r14
  cmp    %eax,0x1c(%rsp)
  jl     L83
L74:
  mov    0x10(%rsp),%rax
  mov    (%rax),%r12d
  cmpl   $0x0,0xc(%rsp)
  jle    L68
  lea    0x4(%rax),%rbx
  mov    $0x1,%ebp
  jmp    L18
L83:
  movslq 0xc(%rsp),%rax
  mov    0x10(%rsp),%rcx
  mov    (%rcx,%rax,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int minDistance(char *s1, char *s2) {
  int len1 = strlen(s1), len2 = strlen(s2);
  int *cur = (int *)malloc(sizeof(int) * (len2 + 1));
  int pre = 0;
  for (int i = 0; i <= len2; i++)
    cur[i] = i;
  for (int i = 1; i <= len1; i++) {
    pre = cur[0];
    for (int j = 1; j <= len2; j++) {
      int t = cur[j];
      cur[j] = s1[i - 1] == s2[j - 1] ? pre : min(cur[j - 1], cur[j], pre) + 1;
      pre = t;
    }
    cur[0] = i;
  }
  return cur[len2];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<minDistance>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,0xc(%rsp)
  call   <strlen@plt>
  lea    0x4(,%rax,4),%edi
  mov    %eax,%r14d
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %r14d,%r14d
  js     L44
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %eax,%esi
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %esi,%r14d
  jne    L21
L44:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L60
  mov    (%rsp),%rax
  movl   $0x1,0x8(%rsp)
  mov    (%rax),%r15d
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rsp),%rax
  mov    $0x1,%ebp
  lea    0x4(%rax),%rbx
  test   %r14d,%r14d
  jle    L26
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r15d,%edx
  movzbl -0x1(%r12,%rbp,1),%eax
  mov    (%rbx),%r15d
  cmp    %al,0x0(%r13)
  je     L31
  mov    -0x4(%rbx),%edi
  mov    %r15d,%esi
  call   <min@plt>
  lea    0x1(%rax),%edx
L31:
  add    $0x1,%rbp
  mov    %edx,(%rbx)
  add    $0x4,%rbx
  cmp    %ebp,%r14d
  jge    L8
L26:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%r15d
  add    $0x1,%r13
  mov    %r15d,(%rax)
  lea    0x1(%r15),%eax
  cmp    %eax,0xc(%rsp)
  jl     L60
  mov    %eax,0x8(%rsp)
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L60:
  mov    (%rsp),%rax
  movslq %r14d,%rcx
  mov    (%rax,%rcx,4),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int minDistance(char *s1, char *s2) {
  int len1 = strlen(s1), len2 = strlen(s2);
  int *cur = (int *)malloc(sizeof(int) * (len2 + 1));
  int pre = 0;
  for (int i = 0; i <= len2; i++)
    cur[i] = i;
  for (int i = 1; i <= len1; i++) {
    pre = cur[0];
    for (int j = 1; j <= len2; j++) {
      int t = cur[j];
      cur[j] = s1[i - 1] == s2[j - 1] ? pre : min(cur[j - 1], cur[j], pre) + 1;
      pre = t;
    }
    cur[0] = i;
  }
  return cur[len2];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<minDistance>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,0xc(%rsp)
  call   <strlen@plt>
  lea    0x1(%rax),%ebp
  mov    %eax,%r15d
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  test   %r15d,%r15d
  js     L139
  cmp    $0x2,%r15d
  jle    L28
  mov    %ebp,%edx
  movdqa D12(%rip),%xmm0
  movdqa D17(%rip),%xmm2
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rax,%rdx,1),%rdx
  nop
L0:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L0
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  and    $0x3,%ebp
  je     L139
L68:
  mov    (%rsp),%rsi
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    %eax,(%rsi,%rdx,4)
  lea    0x1(%rax),%edx
  cmp    %edx,%r15d
  jl     L139
  add    $0x2,%eax
  mov    %edx,0x4(%rsi,%rcx,1)
  cmp    %eax,%r15d
  jl     L139
  mov    %eax,0x8(%rsi,%rcx,1)
L139:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L131
  mov    (%rsp),%rax
  movl   $0x1,0x8(%rsp)
  mov    (%rax),%edx
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rsp),%rax
  mov    $0x1,%ebp
  lea    0x4(%rax),%rbx
  test   %r15d,%r15d
  jg     L79
  jmp    L108
  nopl   0x0(%rax)
L29:
  mov    -0x4(%rbx),%edi
  mov    %r12d,%esi
  add    $0x1,%rbp
  add    $0x4,%rbx
  call   <min@plt>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %ebp,%r15d
  jl     L108
L135:
  mov    %r12d,%edx
L79:
  mov    (%rbx),%r12d
  movzbl -0x1(%r13,%rbp,1),%eax
  cmp    %al,(%r14)
  jne    L29
  add    $0x1,%rbp
  mov    %edx,(%rbx)
  add    $0x4,%rbx
  cmp    %ebp,%r15d
  jge    L135
L108:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  add    $0x1,%r14
  mov    %edx,(%rax)
  lea    0x1(%rdx),%eax
  cmp    %eax,0xc(%rsp)
  jl     L131
  mov    %eax,0x8(%rsp)
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L131:
  mov    (%rsp),%rax
  movslq %r15d,%r8
  mov    (%rax,%r8,4),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  xor    %eax,%eax
  jmp    L68
```

tool_calls: name: parse_data
arguments: data_tag: D12
type: byte[16]
name: parse_data
arguments: data_tag: D17
type: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D17": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int minDistance(char *s1, char *s2) {
  int len1 = strlen(s1), len2 = strlen(s2);
  int *cur = (int *)malloc(sizeof(int) * (len2 + 1));
  int pre = 0;
  for (int i = 0; i <= len2; i++)
    cur[i] = i;
  for (int i = 1; i <= len1; i++) {
    pre = cur[0];
    for (int j = 1; j <= len2; j++) {
      int t = cur[j];
      cur[j] = s1[i - 1] == s2[j - 1] ? pre : min(cur[j - 1], cur[j], pre) + 1;
      pre = t;
    }
    cur[0] = i;
  }
  return cur[len2];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn0000000140001290>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fn000000014000193C@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fn0000000140001290() {
  fn000000014000193C();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fn0000000140001290>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fn000000014000193C@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fn0000000140001290() {
  fn000000014000193C();
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fn0000000140001290>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <fn000000014000193C@plt>
```

assistant: ```c
void fn0000000140001290() {
  fn000000014000193C();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn0000000140001290>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <fn000000014000193C@plt>
```

assistant: ```c
void fn0000000140001290() {
  fn000000014000193C();
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Fin_Buzzer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  sar    $0x8,%eax
  mov    %al,-0xf(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %al,-0xe(%rbp)
  mov    -0x28(%rbp),%eax
  sar    $0x8,%eax
  mov    %al,-0xd(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %al,-0xc(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x42,%esi
  mov    $0x0,%edi
  call   <Fin_Cmnd@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int Fin_Buzzer(int msec, int freq) {
  unsigned char IoBuffer[9];
  int res;
  IoBuffer[2] = (char)(msec >> 8);
  IoBuffer[3] = (char)(msec);
  IoBuffer[4] = (char)(freq >> 8);
  IoBuffer[5] = (char)(freq);
  res = Fin_Cmnd(0, 'B', IoBuffer);
  return (res);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Fin_Buzzer>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %fs:0x28,%rcx
  mov    %rcx,0x18(%rsp)
  xor    %ecx,%ecx
  movzbl %dh,%ecx
  mov    %cl,0x11(%rsp)
  mov    %dil,0x12(%rsp)
  movzbl %ah,%ecx
  mov    %cl,0x13(%rsp)
  mov    %sil,0x14(%rsp)
  lea    0xf(%rsp),%rdx
  mov    $0x42,%esi
  mov    $0x0,%edi
  call   <Fin_Cmnd@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Fin_Buzzer(int msec, int freq) {
  unsigned char IoBuffer[9];
  int res;
  IoBuffer[2] = (char)(msec >> 8);
  IoBuffer[3] = (char)(msec);
  IoBuffer[4] = (char)(freq >> 8);
  IoBuffer[5] = (char)(freq);
  res = Fin_Cmnd(0, 'B', IoBuffer);
  return (res);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Fin_Buzzer>:
  endbr64
  rol    $0x8,%di
  sub    $0x28,%rsp
  rol    $0x8,%si
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rdx
  mov    %di,0x11(%rsp)
  xor    %edi,%edi
  mov    %si,0x13(%rsp)
  mov    $0x42,%esi
  call   <Fin_Cmnd@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Fin_Buzzer(int msec, int freq) {
  unsigned char IoBuffer[9];
  int res;
  IoBuffer[2] = (char)(msec >> 8);
  IoBuffer[3] = (char)(msec);
  IoBuffer[4] = (char)(freq >> 8);
  IoBuffer[5] = (char)(freq);
  res = Fin_Cmnd(0, 'B', IoBuffer);
  return (res);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Fin_Buzzer>:
  endbr64
  rol    $0x8,%di
  sub    $0x28,%rsp
  rol    $0x8,%si
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rdx
  mov    %di,0x11(%rsp)
  xor    %edi,%edi
  mov    %si,0x13(%rsp)
  mov    $0x42,%esi
  call   <Fin_Cmnd@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Fin_Buzzer(int msec, int freq) {
  unsigned char IoBuffer[9];
  int res;
  IoBuffer[2] = (char)(msec >> 8);
  IoBuffer[3] = (char)(msec);
  IoBuffer[4] = (char)(freq >> 8);
  IoBuffer[5] = (char)(freq);
  res = Fin_Cmnd(0, 'B', IoBuffer);
  return (res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  js     L7
  movabs $0x8000000000000000,%rax
  mov    %rax,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long f2(unsigned long long x) {
  if (x < 0x8000000000000000ULL)
    x = 0x8000000000000000ULL;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f2>:
  endbr64
  movabs $0x8000000000000000,%rax
  cmp    %rax,%rdi
  cmovae %rdi,%rax
  ret
```

assistant: ```c
unsigned long long f2(unsigned long long x) {
  if (x < 0x8000000000000000ULL)
    x = 0x8000000000000000ULL;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f2>:
  endbr64
  movabs $0x8000000000000000,%rax
  cmp    %rax,%rdi
  cmovae %rdi,%rax
  ret
```

assistant: ```c
unsigned long long f2(unsigned long long x) {
  if (x < 0x8000000000000000ULL)
    x = 0x8000000000000000ULL;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f2>:
  endbr64
  movabs $0x8000000000000000,%rax
  cmp    %rax,%rdi
  cmovae %rdi,%rax
  ret
```

assistant: ```c
unsigned long long f2(unsigned long long x) {
  if (x < 0x8000000000000000ULL)
    x = 0x8000000000000000ULL;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x32,-0xd4(%rbp)
  movl   $0x0,-0xd8(%rbp)
  jmp    L6
L12:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0xd8(%rbp),%eax
  cltq
  mov    %edx,-0xd0(%rbp,%rax,4)
  addl   $0x1,-0xd8(%rbp)
L6:
  mov    -0xd8(%rbp),%eax
  cmp    -0xd4(%rbp),%eax
  jl     L12
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xd4(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xd4(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insertion_sort@plt>
  mov    -0xd4(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D4
type: string

tool: D10: out of order:


tool: D4: in order:


assistant: ```c
int main() {
  int ar[50];
  int size = 50;
  int c;
  for (c = 0; c < size; c++)
    ar[c] = rand() % 100;
  printf("out of order:\n");
  print_array(ar, size);
  printf("in order:\n");
  insertion_sort(ar, size);
  print_array(ar, size);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0xc8(%rsp),%rbp
L19:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L19
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    $0x32,%esi
  mov    %rbx,%rdi
  call   <print_array@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbx,%rdi
  call   <insertion_sort@plt>
  mov    $0x32,%esi
  mov    %rbx,%rdi
  call   <print_array@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D14
type: string

tool: D8: out of order:


tool: D14: in order:


assistant: ```c
int main() {
  int ar[50];
  int size = 50;
  int c;
  for (c = 0; c < size; c++)
    ar[c] = rand() % 100;
  printf("out of order:\n");
  print_array(ar, size);
  printf("in order:\n");
  insertion_sort(ar, size);
  print_array(ar, size);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xc8(%rsp),%rbx
  mov    %rbp,%r12
L8:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L8
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <insertion_sort@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string

tool: D19: out of order:


tool: D14: in order:


assistant: ```c
int main() {
  int ar[50];
  int size = 50;
  int c;
  for (c = 0; c < size; c++)
    ar[c] = rand() % 100;
  printf("out of order:\n");
  print_array(ar, size);
  printf("in order:\n");
  insertion_sort(ar, size);
  print_array(ar, size);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xc8(%rsp),%rbx
  mov    %rbp,%r12
L17:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L17
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <insertion_sort@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type_infered: string
name: disassemble_data
arguments: label: D15
type_infered: string

tool: D12: out of order:


tool: D15: in order:


assistant: ```c
int main() {
  int ar[50];
  int size = 50;
  int c;
  for (c = 0; c < size; c++)
    ar[c] = rand() % 100;
  printf("out of order:\n");
  print_array(ar, size);
  printf("in order:\n");
  insertion_sort(ar, size);
  print_array(ar, size);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<merge_increase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfe0,%rsp
  mov    %rdi,-0xfd8(%rbp)
  mov    %rsi,-0xfe0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xfd8(%rbp),%rax
  cmp    -0xfe0(%rbp),%rax
  jae    L100
  mov    -0xfe0(%rbp),%rax
  sub    -0xfd8(%rbp),%rax
  sar    $0x2,%rax
  mov    %eax,-0xfcc(%rbp)
  mov    -0xfcc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xfd8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0xfb8(%rbp)
  mov    -0xfb8(%rbp),%rdx
  mov    -0xfd8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <merge_increase>
  mov    -0xfb8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xfe0(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <merge_increase>
  mov    -0xfd8(%rbp),%rax
  mov    %rax,-0xfc8(%rbp)
  mov    -0xfb8(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0xfc0(%rbp)
  movl   $0x0,-0xfd0(%rbp)
  jmp    L12
L59:
  mov    -0xfc8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xfc0(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L16
  mov    -0xfc8(%rbp),%rax
  cmp    -0xfb8(%rbp),%rax
  jbe    L94
L16:
  mov    -0xfc0(%rbp),%rax
  cmp    -0xfe0(%rbp),%rax
  jbe    L14
L94:
  mov    -0xfc8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xfd0(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addq   $0x4,-0xfc8(%rbp)
  jmp    L80
L14:
  mov    -0xfc0(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xfd0(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addq   $0x4,-0xfc0(%rbp)
L80:
  addl   $0x1,-0xfd0(%rbp)
L12:
  mov    -0xfd0(%rbp),%eax
  cmp    -0xfcc(%rbp),%eax
  jle    L59
  movl   $0x0,-0xfd0(%rbp)
  jmp    L43
L19:
  mov    -0xfd0(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xfd8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xfd0(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xfd0(%rbp)
L43:
  mov    -0xfd0(%rbp),%eax
  cmp    -0xfcc(%rbp),%eax
  jle    L19
  jmp    L3
L100:
  nop
L3:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void merge_increase(int *front, int *end) {
  if (front >= end)
    return;
  int size = end - front;
  int *mid = front + size / 2;
  merge_increase(front, mid);
  merge_increase(mid + 1, end);
  int *left = front;
  int *right = mid + 1;
  int tmp_sort[1000];
  int i;
  for (i = 0; i <= size; ++i) {
    if (*left < *right && left <= mid || right > end) {
      tmp_sort[i] = *left;
      left++;
    } else {
      tmp_sort[i] = *right;
      right++;
    }
  }
  for (i = 0; i <= size; ++i)
    *(front + i) = tmp_sort[i];
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<merge_increase>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    %rsi,%rdi
  jb     L42
L44:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0xfb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%r14
  sub    %rdi,%r14
  sar    $0x2,%r14
  mov    %r14d,%eax
  shr    $0x1f,%eax
  add    %r14d,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r13
  mov    %r13,%rsi
  call   <merge_increase>
  lea    0x4(%r13),%rbx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <merge_increase>
  test   %r14d,%r14d
  js     L44
  mov    %rsp,%rax
  mov    %r14d,%r14d
  lea    0x4(%rsp,%r14,4),%rdi
  mov    %rbp,%rdx
  jmp    L9
L86:
  add    $0x4,%rdx
L49:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L54
L9:
  mov    (%rdx),%ecx
  mov    (%rbx),%esi
  cmp    %rdx,%r13
  jb     L38
  cmp    %esi,%ecx
  jl     L86
L38:
  cmp    %rbx,%r12
  jb     L86
  add    $0x4,%rbx
  mov    %esi,%ecx
  jmp    L49
L54:
  lea    0x4(,%r14,4),%rcx
  mov    $0x0,%eax
L80:
  mov    (%rsp,%rax,1),%edx
  mov    %edx,0x0(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L80
  jmp    L44
L72:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge_increase(int *front, int *end) {
  if (front >= end)
    return;
  int size = end - front;
  int *mid = front + size / 2;
  merge_increase(front, mid);
  merge_increase(mid + 1, end);
  int *left = front;
  int *right = mid + 1;
  int tmp_sort[1000];
  int i;
  for (i = 0; i <= size; ++i) {
    if (*left < *right && left <= mid || right > end) {
      tmp_sort[i] = *left;
      left++;
    } else {
      tmp_sort[i] = *right;
      right++;
    }
  }
  for (i = 0; i <= size; ++i)
    *(front + i) = tmp_sort[i];
  return;
}
```