user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dij>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L16
  lea    0x30(%rsp),%rax
  lea    -0x1(%rsi),%edx
  lea    0x34(%rsp,%rdx,4),%rdx
L83:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L83
  movslq %r13d,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r14,%rax,8),%rdi
  mov    %ebp,%esi
  mov    $0x0,%eax
  mov    $0x270f,%r8d
  jmp    L90
L179:
  mov    %edx,(%rsp,%rax,4)
  mov    %ecx,0x60(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L16
L90:
  mov    (%rdi,%rax,4),%edx
  mov    %r13d,%ecx
  test   %edx,%edx
  jne    L179
  mov    %edx,%ecx
  mov    %r8d,%edx
  jmp    L179
L16:
  movslq %r13d,%rax
  movl   $0x1,0x30(%rsp,%rax,4)
  movl   $0x0,(%rsp,%rax,4)
  movslq %r12d,%rax
  cmpl   $0x1,0x30(%rsp,%rax,4)
  je     L73
  lea    0x30(%rsp),%rbx
  jmp    L119
L6:
  add    $0x1,%rdx
  add    $0x28,%rcx
  cmp    %rdx,%rdi
  je     L86
L155:
  cmpl   $0x1,(%rbx,%rdx,4)
  je     L6
  mov    (%rcx),%esi
  test   %esi,%esi
  je     L6
  add    (%rsp,%r9,4),%esi
  cmp    (%r8,%rdx,4),%esi
  jge    L6
  mov    %esi,(%r8,%rdx,4)
  mov    %eax,0x60(%rsp,%rdx,4)
  jmp    L6
L86:
  movslq %r12d,%rax
  cmpl   $0x1,0x30(%rsp,%rax,4)
  je     L73
L119:
  mov    %rsp,%rdi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <srch_min@plt>
  movslq %eax,%rdx
  movl   $0x1,0x30(%rsp,%rdx,4)
  test   %ebp,%ebp
  jle    L86
  lea    (%r14,%rdx,4),%rcx
  mov    %ebp,%edi
  mov    $0x0,%edx
  movslq %eax,%r9
  mov    %rsp,%r8
  jmp    L155
L73:
  cmp    %r12d,%r13d
  je     L187
  mov    %r12d,%eax
  mov    $0x0,%edx
L93:
  mov    %edx,%ebx
  cltq
  mov    0x60(%rsp,%rax,4),%eax
  mov    %eax,0x90(%rsp,%rdx,4)
  add    $0x1,%rdx
  cmp    %eax,%r13d
  jne    L93
  test   %ebx,%ebx
  js     L187
  movslq %ebx,%rbx
  mov    $0x0,%r13d
  lea    D7(%rip),%r14
L139:
  mov    0x90(%rsp,%rbx,4),%ebp
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebp
  mov    $0x1,%eax
  cmove  %eax,%r13d
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L139
  cmp    $0x1,%r13d
  jne    L187
L11:
  mov    $0x6e,%edi
  call   <putchar@plt>
  movslq %r12d,%r12
  mov    (%rsp,%r12,4),%eax
  mov    0xb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L161
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L187:
  mov    %r12d,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L161:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string

tool: D7: v%d->

tool: D11: v%d

assistant: ```c
int dij(int a[10][10], int n, int v1, int v2) {
  int length[10], set[10], path[10], i, j, s, z, tmp, temp[10], c = 0, f = 0;
  s = v1;
  z = v2;
  int srch_min(int[], int[], int);
  for (i = 0; i < n; i++)
    set[i] = 0;
  for (i = 0; i < n; i++) {
    if (a[s][i] == 0) {
      length[i] = 9999;
      path[i] = 0;
    } else {
      length[i] = a[s][i];
      path[i] = s;
    }
  }
  set[s] = 1;
  length[s] = 0;
  while (set[z] != 1) {
    j = srch_min(length, set, n);
    set[j] = 1;
    for (i = 0; i < n; i++) {
      if (set[i] != 1) {
        if (a[i][j] != 0) {
          if (length[j] + a[i][j] < length[i]) {
            length[i] = length[j] + a[i][j];
            path[i] = j;
          }
        }
      }
    }
  }
  j = 0;
  i = z;
  while (i != s) {
    tmp = path[i];
    temp[j] = tmp;
    i = tmp;
    j++;
    c++;
  }
  for (j = c - 1; j >= 0; j--) {
    printf("v%d->", temp[j]);
    if (temp[j] == z)
      f = 1;
  }
  if (f != 1)
    printf("v%d", z);
  printf("n");
  return length[z];
}
```