user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x1390(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %eax,%r14d
  lea    0x1(%rax),%r13d
  lea    0x0(,%r13,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  shl    $0x2,%r13
  mov    $0x0,%r12d
L90:
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %r12d,%eax
  mov    %rdi,(%rbx,%rax,8)
  mov    %r13,%rdx
  mov    $0x0,%esi
  call   <memset@plt>
  add    $0x1,%r12d
  cmp    %r12d,%r14d
  jae    L90
  test   %ebp,%ebp
  je     L41
  mov    %rsp,%r12
  lea    0x8(%rbx),%rsi
  lea    -0x1(%rbp),%eax
  lea    0x1(%rsp,%rax,1),%r13
  lea    0x0(,%rbp,4),%r11
  jmp    L42
L51:
  mov    (%rsi),%r8
  mov    -0x8(%rsi),%rdi
  mov    (%rdi,%rax,1),%edi
  add    $0x1,%edi
  mov    %edi,(%r8,%rdx,1)
L47:
  add    $0x1,%rcx
  add    $0x4,%rax
  add    $0x4,%rdx
  cmp    %r11,%rax
  je     L96
L97:
  cmp    (%rcx),%r10b
  je     L51
  mov    -0x8(%rsi),%rdi
  mov    (%rdi,%rdx,1),%r9d
  mov    (%rsi),%rdi
  mov    (%rdi,%rax,1),%r8d
  cmp    %r8d,%r9d
  jb     L108
  mov    %r9d,(%rdi,%rdx,1)
  jmp    L47
L108:
  mov    %r8d,(%rdi,%rdx,1)
  jmp    L47
L96:
  add    $0x1,%r12
  add    $0x8,%rsi
  cmp    %r13,%r12
  je     L41
L42:
  movzbl (%r12),%r10d
  lea    0x1390(%rsp),%rcx
  mov    $0x4,%edx
  mov    $0x0,%eax
  jmp    L97
L41:
  mov    (%rbx,%rbp,8),%rax
  mov    (%rax,%rbp,4),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%r12
  lea    0x8(%rbx,%rbp,8),%rbp
L104:
  mov    (%r12),%rdi
  call   <free@plt>
  add    $0x8,%r12
  cmp    %r12,%rbp
  jne    L104
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x2730,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string
name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D2: %s

tool: D5: %u


assistant: ```c
int main() {
  char a[5001];
  char b[5001];
  scanf("%s", a);
  scanf("%s", b);
  unsigned int len = strlen(a);
  unsigned int **c = malloc(sizeof(unsigned int *) * (len + 1));
  for (unsigned int i = 0; i <= len; i++) {
    c[i] = malloc(sizeof(unsigned int) * (len + 1));
    memset(c[i], 0, sizeof(unsigned int) * (len + 1));
  }
  for (unsigned int i = 1; i <= len; i++) {
    for (unsigned int j = 1; j <= len; j++) {
      if (a[i - 1] == b[j - 1]) {
        c[i][j] = c[i - 1][j - 1] + 1;
      } else {
        if (c[i - 1][j] >= c[i][j - 1]) {
          c[i][j] = c[i - 1][j];
        } else {
          c[i][j] = c[i][j - 1];
        }
      }
    }
  }
  printf("%u\n", c[len][len]);
  for (unsigned int i = 0; i <= len; i++) {
    free(c[i]);
  }
  free(c);
  return 0;
}
```