ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<xlog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L16
L7:
  shrq   -0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  cmpq   $0x0,-0x18(%rbp)
  jne    L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int xlog2(size_t x) {
  int r = -1;
  while (x != 0) {
    x >>= 1;
    r++;
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xlog2>:
  endbr64
  test   %rdi,%rdi
  je     L12
  mov    $0xffffffff,%eax
L4:
  add    $0x1,%eax
  shr    %rdi
  jne    L4
  ret
L12:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int xlog2(size_t x) {
  int r = -1;
  while (x != 0) {
    x >>= 1;
    r++;
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xlog2>:
  endbr64
  mov    $0xffffffff,%eax
  test   %rdi,%rdi
  je     L18
  xchg   %ax,%ax
L14:
  add    $0x1,%eax
  shr    %rdi
  jne    L14
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
int xlog2(size_t x) {
  int r = -1;
  while (x != 0) {
    x >>= 1;
    r++;
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xlog2>:
  endbr64
  mov    $0xffffffff,%eax
  test   %rdi,%rdi
  je     L4
  xchg   %ax,%ax
L5:
  add    $0x1,%eax
  shr    %rdi
  jne    L5
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
int xlog2(size_t x) {
  int r = -1;
  while (x != 0) {
    x >>= 1;
    r++;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%ecx
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x28(%rbp),%edx
  sub    %rdx,%rax
  movslq %eax,%rdx
  cmp    %rdx,%rax
  je     L16
  mov    $0x1,%ecx
L16:
  mov    %eax,-0x18(%rbp)
  mov    %ecx,%eax
  and    $0x1,%eax
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
__attribute__((no, noclone)) int fn1(int x, unsigned int y) {
  int res;
  int ovf = __builtin_sub_overflow(x, y, &res);
  int res2 = res;
  int res3 = res2 - 2;
  (void)ovf;
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fn1>:
  endbr64
  mov    %edi,%eax
  sub    %esi,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int fn1(int x, unsigned int y) {
  int res;
  int ovf = __builtin_sub_overflow(x, y, &res);
  int res2 = res;
  int res3 = res2 - 2;
  (void)ovf;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn1>:
  endbr64
  mov    %edi,%eax
  sub    %esi,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int fn1(int x, unsigned int y) {
  int res;
  int ovf = __builtin_sub_overflow(x, y, &res);
  int res2 = res;
  int res3 = res2 - 2;
  (void)ovf;
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn1>:
  endbr64
  mov    %edi,%eax
  sub    %esi,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int fn1(int x, unsigned int y) {
  int res;
  int ovf = __builtin_sub_overflow(x, y, &res);
  int res2 = res;
  int res3 = res2 - 2;
  (void)ovf;
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<newcol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jne    L10
  mov    -0x8(%rbp),%eax
  or     $0x7,%eax
  add    $0x1,%eax
  jmp    L14
L10:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <char_len@plt>
  mov    -0x8(%rbp),%edx
  add    %edx,%eax
L14:
  leave
  ret
```

assistant: ```c
int newcol(ch, col)
int ch, col;
{
  if (ch == '\t')
    return (col | 7) + 1;
  return col + char_len(ch);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<newcol>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x9,%edi
  je     L13
  mov    $0x0,%eax
  call   <char_len@plt>
  add    %ebx,%eax
L2:
  pop    %rbx
  ret
L13:
  or     $0x7,%ebx
  lea    0x1(%rbx),%eax
  jmp    L2
```

assistant: ```c
int newcol(ch, col)
int ch, col;
{
  if (ch == '\t')
    return (col | 7) + 1;
  return col + char_len(ch);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<newcol>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x9,%edi
  je     L1
  xor    %eax,%eax
  call   <char_len@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  or     $0x7,%ebx
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int newcol(ch, col)
int ch, col;
{
  if (ch == '\t')
    return (col | 7) + 1;
  return col + char_len(ch);
}
```
user: What is the c source code of the assembly code below?

```asm
<newcol>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x9,%edi
  je     L4
  xor    %eax,%eax
  call   <char_len@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  or     $0x7,%ebx
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int newcol(ch, col)
int ch, col;
{
  if (ch == '\t')
    return (col | 7) + 1;
  return col + char_len(ch);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<funge_discard_tos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <funge_thread_stack@plt>
  mov    %eax,%edx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <funge_stack_pop@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int32_t funge_discard_tos(int32_t funge_char __attribute__((unused))) {
  int32_t val;
  int32_t rc;
  rc = funge_stack_pop(funge_thread_stack(), &val);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<funge_discard_tos>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <funge_thread_stack@plt>
  mov    %eax,%edi
  lea    0x4(%rsp),%rsi
  call   <funge_stack_pop@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t funge_discard_tos(int32_t funge_char __attribute__((unused))) {
  int32_t val;
  int32_t rc;
  rc = funge_stack_pop(funge_thread_stack(), &val);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<funge_discard_tos>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <funge_thread_stack@plt>
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <funge_stack_pop@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t funge_discard_tos(int32_t funge_char __attribute__((unused))) {
  int32_t val;
  int32_t rc;
  rc = funge_stack_pop(funge_thread_stack(), &val);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<funge_discard_tos>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <funge_thread_stack@plt>
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <funge_stack_pop@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t funge_discard_tos(int32_t funge_char __attribute__((unused))) {
  int32_t val;
  int32_t rc;
  rc = funge_stack_pop(funge_thread_stack(), &val);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RotateSentences>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L48:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L22
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  test   %al,%al
  je     L23
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L23:
  subl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x0,-0x4(%rbp)
  jns    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L48
  nop
  nop
  leave
  ret
```

assistant: ```c
void RotateSentences(char (*string)[100], int row, int column) {
  for (int i = 0; i < column; i++) {
    for (int j = row - 1; j >= 0; j--) {
      if (string[j][i])
        printf("%c", string[j][i]);
    }
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RotateSentences>:
  endbr64
  test   %edx,%edx
  jle    L70
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r13d
  movslq %esi,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  lea    -0x64(%rdi,%rax,1),%r12
  lea    -0x63(%rdi,%rax,1),%r14
  lea    -0x1(%rdx),%eax
  add    %rax,%r14
  jmp    L43
L62:
  sub    $0x1,%ebx
  sub    $0x64,%rbp
  cmp    $0xffffffff,%ebx
  je     L12
L8:
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L62
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L62
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12
  cmp    %r14,%r12
  je     L25
L43:
  mov    %r13d,%ebx
  sub    $0x1,%ebx
  js     L12
  mov    %r12,%rbp
  jmp    L8
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L70:
  ret
```

assistant: ```c
void RotateSentences(char (*string)[100], int row, int column) {
  for (int i = 0; i < column; i++) {
    for (int j = row - 1; j >= 0; j--) {
      if (string[j][i])
        printf("%c", string[j][i]);
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RotateSentences>:
  endbr64
  test   %edx,%edx
  jle    L4
  push   %r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  movslq %esi,%rsi
  lea    (%rsi,%rsi,4),%rax
  push   %r12
  lea    (%rax,%rax,4),%rax
  push   %rbp
  shl    $0x2,%rax
  push   %rbx
  lea    -0x63(%rdi,%rax,1),%r14
  lea    -0x64(%rdi,%rax,1),%r12
  lea    -0x1(%rdx),%eax
  add    %rax,%r14
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r12,%rbp
  mov    %r13d,%ebx
  test   %r13d,%r13d
  jns    L5
  jmp    L67
  nopl   (%rax)
L51:
  sub    $0x1,%ebx
  sub    $0x64,%rbp
  cmp    $0xffffffff,%ebx
  je     L67
L5:
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L51
  call   <putchar@plt>
  sub    $0x1,%ebx
  sub    $0x64,%rbp
  cmp    $0xffffffff,%ebx
  jne    L5
L67:
  mov    $0xa,%edi
  add    $0x1,%r12
  call   <putchar@plt>
  cmp    %r14,%r12
  jne    L27
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  ret
```

assistant: ```c
void RotateSentences(char (*string)[100], int row, int column) {
  for (int i = 0; i < column; i++) {
    for (int j = row - 1; j >= 0; j--) {
      if (string[j][i])
        printf("%c", string[j][i]);
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RotateSentences>:
  endbr64
  test   %edx,%edx
  jle    L35
  push   %r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  movslq %esi,%rsi
  lea    (%rsi,%rsi,4),%rax
  push   %r12
  lea    (%rax,%rax,4),%rax
  push   %rbp
  shl    $0x2,%rax
  push   %rbx
  lea    -0x63(%rdi,%rax,1),%r14
  lea    -0x64(%rdi,%rax,1),%r12
  lea    -0x1(%rdx),%eax
  add    %rax,%r14
  nopw   0x0(%rax,%rax,1)
L1:
  test   %r13d,%r13d
  js     L16
  mov    %r12,%rbp
  mov    %r13d,%ebx
  jmp    L67
  nopl   (%rax)
L24:
  sub    $0x1,%ebx
  sub    $0x64,%rbp
  cmp    $0xffffffff,%ebx
  je     L16
L67:
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L24
  call   <putchar@plt>
  sub    $0x1,%ebx
  sub    $0x64,%rbp
  cmp    $0xffffffff,%ebx
  jne    L67
L16:
  mov    $0xa,%edi
  add    $0x1,%r12
  call   <putchar@plt>
  cmp    %r14,%r12
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  ret
```

assistant: ```c
void RotateSentences(char (*string)[100], int row, int column) {
  for (int i = 0; i < column; i++) {
    for (int j = row - 1; j >= 0; j--) {
      if (string[j][i])
        printf("%c", string[j][i]);
    }
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<set_interrupts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <get_status@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L11
  orl    $0x1,-0x4(%rbp)
  orl    $0xff00,-0x4(%rbp)
  jmp    L12
L11:
  andl   $0xfffffffe,-0x4(%rbp)
  andl   $0xffff00ff,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <set_status@plt>
  nop
  leave
  ret
```

assistant: ```c
void set_interrupts(int yesOrNo) {
  int t = get_status();
  if (yesOrNo) {
    t |= 0x00000001;
    t |= 0x0000ff00;
  } else {
    t &= ~0x00000001;
    t &= ~0x0000ff00;
  }
  set_status(t);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_interrupts>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <get_status@plt>
  mov    %eax,%edx
  or     $0xff01,%edx
  and    $0xffff00fe,%eax
  test   %ebx,%ebx
  cmove  %eax,%edx
  mov    %edx,%edi
  call   <set_status@plt>
  pop    %rbx
  ret
```

assistant: ```c
void set_interrupts(int yesOrNo) {
  int t = get_status();
  if (yesOrNo) {
    t |= 0x00000001;
    t |= 0x0000ff00;
  } else {
    t &= ~0x00000001;
    t &= ~0x0000ff00;
  }
  set_status(t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_interrupts>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <get_status@plt>
  mov    %eax,%edx
  and    $0xffff00fe,%eax
  or     $0xff01,%edx
  test   %ebx,%ebx
  pop    %rbx
  cmove  %eax,%edx
  mov    %edx,%edi
  jmp    1070 <set_status@plt>
```

assistant: ```c
void set_interrupts(int yesOrNo) {
  int t = get_status();
  if (yesOrNo) {
    t |= 0x00000001;
    t |= 0x0000ff00;
  } else {
    t &= ~0x00000001;
    t &= ~0x0000ff00;
  }
  set_status(t);
}
```
user: What is the c source code of the assembly code below:

```asm
<set_interrupts>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <get_status@plt>
  mov    %eax,%edx
  and    $0xffff00fe,%eax
  or     $0xff01,%edx
  test   %ebx,%ebx
  pop    %rbx
  cmove  %eax,%edx
  mov    %edx,%edi
  jmp    1070 <set_status@plt>
```

assistant: ```c
void set_interrupts(int yesOrNo) {
  int t = get_status();
  if (yesOrNo) {
    t |= 0x00000001;
    t |= 0x0000ff00;
  } else {
    t &= ~0x00000001;
    t &= ~0x0000ff00;
  }
  set_status(t);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L69
L36:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L69:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L36
  mov    -0x18(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L77
  cmpl   $0x0,-0xc(%rbp)
  jne    L77
  movb   $0x50,-0x21(%rbp)
  jmp    L76
L77:
  cmpl   $0x1,-0x10(%rbp)
  jne    L14
  cmpl   $0x1,-0xc(%rbp)
  jne    L14
  movb   $0x49,-0x21(%rbp)
  jmp    L76
L14:
  movb   $0x4e,-0x21(%rbp)
L76:
  movsbl -0x21(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
datatype: string
name: read_data
arguments: data_label: D19
datatype: string

tool: D14:  %d

tool: D19: %d %d %c


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, sum = 0, val = 0, i, b1, b2;
  char code;
  scanf(" %d", &n);
  for (i = 1; i <= n; ++i) {
    sum += val + i;
    val += i;
  }
  b1 = val % 2;
  b2 = sum % 2;
  if (b1 == 0 && b2 == 0) {
    code = 'P';
  } else if (b1 == 1 && b2 == 1) {
    code = 'I';
  } else {
    code = 'N';
  }
  printf("%d %d %c\n", val, sum, code);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L55
  add    $0x1,%ecx
  mov    $0x1,%eax
  mov    $0x0,%esi
  mov    $0x0,%edx
L17:
  add    %eax,%esi
  add    %esi,%edx
  add    $0x1,%eax
  cmp    %eax,%ecx
  jne    L17
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  lea    (%rsi,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%edi
  and    $0x1,%edi
  sub    %ecx,%edi
  mov    $0x50,%ecx
  mov    %eax,%r8d
  or     %edi,%r8d
  je     L10
  cmp    $0x1,%eax
  jne    L78
  mov    $0x49,%ecx
  cmp    $0x1,%edi
  jne    L78
L10:
  movsbl %cl,%ecx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L78:
  mov    $0x4e,%ecx
  jmp    L10
L55:
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x50,%ecx
  jmp    L10
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D12:  %d

tool: D5: %d %d %c


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, sum = 0, val = 0, i, b1, b2;
  char code;
  scanf(" %d", &n);
  for (i = 1; i <= n; ++i) {
    sum += val + i;
    val += i;
  }
  b1 = val % 2;
  b2 = sum % 2;
  if (b1 == 0 && b2 == 0) {
    code = 'P';
  } else if (b1 == 1 && b2 == 1) {
    code = 'I';
  } else {
    code = 'N';
  }
  printf("%d %d %c\n", val, sum, code);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L10
  add    $0x1,%ecx
  mov    $0x1,%eax
  xor    %esi,%esi
  xor    %edx,%edx
  nopl   (%rax)
L9:
  add    %eax,%esi
  add    $0x1,%eax
  add    %esi,%edx
  cmp    %eax,%ecx
  jne    L9
  mov    %esi,%edi
  mov    %esi,%eax
  mov    $0x50,%ecx
  or     %edx,%edi
  and    $0x1,%eax
  and    $0x1,%edi
  je     L49
  and    %edx,%eax
  cmp    $0x1,%al
  sbb    %ecx,%ecx
  and    $0x5,%ecx
  add    $0x49,%ecx
L49:
  movsbl %cl,%ecx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L10:
  xor    %esi,%esi
  xor    %edx,%edx
  mov    $0x50,%ecx
  jmp    L49
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string

tool: D4:  %d

tool: D1: %d %d %c


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, sum = 0, val = 0, i, b1, b2;
  char code;
  scanf(" %d", &n);
  for (i = 1; i <= n; ++i) {
    sum += val + i;
    val += i;
  }
  b1 = val % 2;
  b2 = sum % 2;
  if (b1 == 0 && b2 == 0) {
    code = 'P';
  } else if (b1 == 1 && b2 == 1) {
    code = 'I';
  } else {
    code = 'N';
  }
  printf("%d %d %c\n", val, sum, code);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L27
  add    $0x1,%ecx
  mov    $0x1,%eax
  xor    %esi,%esi
  xor    %edx,%edx
  nopl   (%rax)
L41:
  add    %eax,%esi
  add    $0x1,%eax
  add    %esi,%edx
  cmp    %eax,%ecx
  jne    L41
  mov    %esi,%edi
  mov    %esi,%eax
  mov    $0x50,%ecx
  or     %edx,%edi
  and    $0x1,%eax
  and    $0x1,%edi
  je     L7
  and    %edx,%eax
  cmp    $0x1,%al
  sbb    %ecx,%ecx
  and    $0x5,%ecx
  add    $0x49,%ecx
L7:
  movsbl %cl,%ecx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L27:
  xor    %esi,%esi
  xor    %edx,%edx
  mov    $0x50,%ecx
  jmp    L7
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D2
datatype: string

tool: D5:  %d

tool: D2: %d %d %c


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, sum = 0, val = 0, i, b1, b2;
  char code;
  scanf(" %d", &n);
  for (i = 1; i <= n; ++i) {
    sum += val + i;
    val += i;
  }
  b1 = val % 2;
  b2 = sum % 2;
  if (b1 == 0 && b2 == 0) {
    code = 'P';
  } else if (b1 == 1 && b2 == 1) {
    code = 'I';
  } else {
    code = 'N';
  }
  printf("%d %d %c\n", val, sum, code);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x7,%eax
  and    $0x4334b500,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  shr    %eax
  xor    $0x1a16edc4,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < 0U) {
      state[0UL] &= state[local1];
      local1++;
    }
    local1 = 0UL;
    while (local1 < 0U) {
      copy11 = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
      *((unsigned short *)(&state[local1]) + 1) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 875420553UL) >> 1U;
  }
}
```