ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmd_wattron>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x2,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L20
  mov    (%rbx),%rdi
  lea    0x10(%rsp),%rdx
  lea    D1(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L40
  mov    0x8(%rbx),%rdi
  lea    0xc(%rsp),%rdx
  lea    D15(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L40
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0x10(%rsp),%rdi
  mov    0xc(%rsp),%esi
  call   <wattron@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D3(%rip),%rdi
  call   <report_error@plt>
  jmp    L20
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D1: %p

tool: D15: %d

tool: D3: BAD ARGUMENT

assistant: ```c
void cmd_wattron(int nargs, char **args) {
  WINDOW *win;
  int attr;
  if (check_arg_count(nargs, 2) == 1)
    return;
  if (sscanf(args[0], "%p", &win) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &attr) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(wattron(win, attr));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L12:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__print_int@plt>
  addl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0x4,-0x8(%rbp)
  jle    L12
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  int a = 3;
  for (i = 0; i < 5; i++) {
    __print_int(a);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  int a = 3;
  for (i = 0; i < 5; i++) {
    __print_int(a);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x3,%edi
  call   <__print_int@plt>
  mov    $0x3,%edi
  call   <__print_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  int a = 3;
  for (i = 0; i < 5; i++) {
    __print_int(a);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5,%ebx
L4:
  mov    $0x3,%edi
  call   <__print_int@plt>
  sub    $0x1,%ebx
  jne    L4
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  int a = 3;
  for (i = 0; i < 5; i++) {
    __print_int(a);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_longarraymul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L25:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_longmul@plt>
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %eax,%edx
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <_longadd@plt>
L7:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jg     L25
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
unsigned _longarraymul(unsigned *uarray, int lg, unsigned factor) {
  unsigned ovfl, carry;
  carry = 0;
  ovfl = 0;
  for (; lg-- > 0;) {
    carry += ovfl;
    ovfl = factor;
    _longmul(uarray, &ovfl);
    _longadd(uarray++, &carry);
  }
  return carry + ovfl;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_longarraymul>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  test   %esi,%esi
  jle    L14
  mov    %edx,%ebp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r13
  mov    %rsp,%r12
L12:
  mov    (%rsp),%eax
  add    %eax,0x4(%rsp)
  mov    %ebp,(%rsp)
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <_longmul@plt>
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edi
  call   <_longadd@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L12
L14:
  mov    (%rsp),%eax
  add    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned _longarraymul(unsigned *uarray, int lg, unsigned factor) {
  unsigned ovfl, carry;
  carry = 0;
  ovfl = 0;
  for (; lg-- > 0;) {
    carry += ovfl;
    ovfl = factor;
    _longmul(uarray, &ovfl);
    _longadd(uarray++, &carry);
  }
  return carry + ovfl;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_longarraymul>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  mov    %edx,%ebp
  mov    %rdi,%rbx
  xor    %edx,%edx
  lea    0x4(%rdi,%rax,4),%r14
  mov    %rsp,%r13
  lea    0x4(%rsp),%r12
  xor    %eax,%eax
  jmp    L36
  xchg   %ax,%ax
L40:
  mov    0x4(%rsp),%eax
  mov    (%rsp),%edx
L36:
  add    %edx,%eax
  mov    %rbx,%rdi
  mov    %r13,%rsi
  mov    %ebp,(%rsp)
  mov    %eax,0x4(%rsp)
  call   <_longmul@plt>
  mov    %ebx,%edi
  mov    %r12,%rsi
  add    $0x4,%rbx
  call   <_longadd@plt>
  cmp    %r14,%rbx
  jne    L40
  mov    (%rsp),%eax
  add    0x4(%rsp),%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  jmp    L3
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned _longarraymul(unsigned *uarray, int lg, unsigned factor) {
  unsigned ovfl, carry;
  carry = 0;
  ovfl = 0;
  for (; lg-- > 0;) {
    carry += ovfl;
    ovfl = factor;
    _longmul(uarray, &ovfl);
    _longadd(uarray++, &carry);
  }
  return carry + ovfl;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_longarraymul>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  mov    %edx,%ebp
  mov    %rdi,%rbx
  xor    %edx,%edx
  lea    0x4(%rdi,%rax,4),%r14
  mov    %rsp,%r13
  lea    0x4(%rsp),%r12
  xor    %eax,%eax
  jmp    L33
  xchg   %ax,%ax
L38:
  mov    0x4(%rsp),%eax
  mov    (%rsp),%edx
L33:
  add    %edx,%eax
  mov    %rbx,%rdi
  mov    %r13,%rsi
  mov    %ebp,(%rsp)
  mov    %eax,0x4(%rsp)
  call   <_longmul@plt>
  mov    %ebx,%edi
  mov    %r12,%rsi
  add    $0x4,%rbx
  call   <_longadd@plt>
  cmp    %rbx,%r14
  jne    L38
  mov    (%rsp),%eax
  add    0x4(%rsp),%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  jmp    L34
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned _longarraymul(unsigned *uarray, int lg, unsigned factor) {
  unsigned ovfl, carry;
  carry = 0;
  ovfl = 0;
  for (; lg-- > 0;) {
    carry += ovfl;
    ovfl = factor;
    _longmul(uarray, &ovfl);
    _longadd(uarray++, &carry);
  }
  return carry + ovfl;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<handle_connection_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x25b97,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D13: QEMU_ERROR: 

tool: D7: unable to connect to shm %d


assistant: ```c
void handle_connection_error(void) {
  {
    printf("QEMU_ERROR: ");
    printf("unable to connect to shm %d\n", 154519);
    exit(-1);
  };
  exit(-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<handle_connection_error>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x25b97,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string

tool: D12: QEMU_ERROR: 

tool: D10: unable to connect to shm %d


assistant: ```c
void handle_connection_error(void) {
  {
    printf("QEMU_ERROR: ");
    printf("unable to connect to shm %d\n", 154519);
    exit(-1);
  };
  exit(-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<handle_connection_error>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x25b97,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D11
data_type: string
name: unpack_data
arguments: data_label: D5
data_type: string

tool: D11: QEMU_ERROR: 

tool: D5: unable to connect to shm %d


assistant: ```c
void handle_connection_error(void) {
  {
    printf("QEMU_ERROR: ");
    printf("unable to connect to shm %d\n", 154519);
    exit(-1);
  };
  exit(-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_connection_error>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x25b97,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D0
type_infered: string

tool: D16: QEMU_ERROR: 

tool: D0: unable to connect to shm %d


assistant: ```c
void handle_connection_error(void) {
  {
    printf("QEMU_ERROR: ");
    printf("unable to connect to shm %d\n", 154519);
    exit(-1);
  };
  exit(-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<tty_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L2
L13:
  cmpb   $0xa,-0x1(%rbp)
  jne    L11
  mov    -0x14(%rbp),%eax
  mov    $0xd,%esi
  mov    %eax,%edi
  call   <tty_putc@plt>
L11:
  movsbl -0x1(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <tty_putc@plt>
L2:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void tty_puts(int chan, char *s) {
  char c;
  while ((c = *s++) != '\0') {
    if (c == '\n') {
      tty_putc(chan, '\r');
    }
    tty_putc(chan, c);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tty_puts>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  lea    0x1(%rsi),%rbp
  movzbl (%rsi),%ebx
  test   %bl,%bl
  jne    L20
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  movsbl %bl,%esi
  mov    %r12d,%edi
  call   <tty_putc@plt>
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%ebx
  test   %bl,%bl
  je     L10
L20:
  cmp    $0xa,%bl
  jne    L24
  mov    $0xd,%esi
  mov    %r12d,%edi
  call   <tty_putc@plt>
  jmp    L24
```

assistant: ```c
void tty_puts(int chan, char *s) {
  char c;
  while ((c = *s++) != '\0') {
    if (c == '\n') {
      tty_putc(chan, '\r');
    }
    tty_putc(chan, c);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tty_puts>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebx
  test   %bl,%bl
  je     L0
  mov    %edi,%r12d
  lea    0x1(%rsi),%rbp
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl %bl,%esi
  mov    %r12d,%edi
  add    $0x1,%rbp
  call   <tty_putc@plt>
  movzbl -0x1(%rbp),%ebx
  test   %bl,%bl
  je     L0
L40:
  cmp    $0xa,%bl
  jne    L9
  mov    $0xd,%esi
  mov    %r12d,%edi
  call   <tty_putc@plt>
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void tty_puts(int chan, char *s) {
  char c;
  while ((c = *s++) != '\0') {
    if (c == '\n') {
      tty_putc(chan, '\r');
    }
    tty_putc(chan, c);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tty_puts>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x1(%rsi),%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  jne    L20
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <tty_putc@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  je     L44
L20:
  cmp    $0xa,%sil
  jne    L19
  mov    $0xd,%esi
  mov    %ebp,%edi
  call   <tty_putc@plt>
  mov    $0xa,%esi
  jmp    L19
  nopl   (%rax)
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void tty_puts(int chan, char *s) {
  char c;
  while ((c = *s++) != '\0') {
    if (c == '\n') {
      tty_putc(chan, '\r');
    }
    tty_putc(chan, c);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  long int a = 4L;
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int main() {
  long int a = 4L;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int main() {
  long int a = 4L;
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int main() {
  long int a = 4L;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0xa,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L27
L33:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  imul   %edx,%eax
  add    %eax,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L27:
  cmpl   $0x8,-0x34(%rbp)
  jle    L33
  mov    -0x38(%rbp),%edx
  movslq %edx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,-0x38(%rbp)
  cmpl   $0xa,-0x38(%rbp)
  jne    L29
  movl   $0x0,-0x38(%rbp)
L29:
  mov    -0x38(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int check_digit(int *UCN) {
  int value = 0;
  int multiplier[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (int i = 0; i < 9; i++)
    value += UCN[i] * multiplier[i];
  value %= 11;
  if (value == 10)
    value = 0;
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_digit>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0xa,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  mov    $0x0,%ecx
  mov    %rsp,%rsi
L9:
  mov    (%rdi,%rax,1),%edx
  imul   (%rax,%rsi,1),%edx
  add    %edx,%ecx
  add    $0x4,%rax
  cmp    $0x24,%rax
  jne    L9
  movslq %ecx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    $0xa,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_digit(int *UCN) {
  int value = 0;
  int multiplier[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (int i = 0; i < 9; i++)
    value += UCN[i] * multiplier[i];
  value %= 11;
  if (value == 10)
    value = 0;
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_digit>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x2,%edx
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x800000004,%rax
  mov    %rax,0x4(%rsp)
  movabs $0xa00000005,%rax
  mov    %rax,0xc(%rsp)
  movabs $0x700000009,%rax
  mov    %rax,0x14(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x1c(%rsp)
  xor    %eax,%eax
  jmp    L29
  nopl   (%rax)
L27:
  mov    (%rsp,%rax,1),%edx
L29:
  imul   (%rdi,%rax,1),%edx
  add    $0x4,%rax
  add    %edx,%ecx
  cmp    $0x24,%rax
  jne    L27
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  xor    %edx,%edx
  cmp    $0xa,%eax
  cmove  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_digit(int *UCN) {
  int value = 0;
  int multiplier[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (int i = 0; i < 9; i++)
    value += UCN[i] * multiplier[i];
  value %= 11;
  if (value == 10)
    value = 0;
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_digit>:
  endbr64
  movdqa D6(%rip),%xmm2
  movdqu (%rdi),%xmm0
  movdqu (%rdi),%xmm1
  movdqa D3(%rip),%xmm3
  pmuludq %xmm2,%xmm0
  psrlq  $0x20,%xmm2
  mov    0x20(%rdi),%eax
  psrlq  $0x20,%xmm1
  pmuludq %xmm2,%xmm1
  movdqu 0x10(%rdi),%xmm2
  lea    (%rax,%rax,2),%edx
  pmuludq %xmm3,%xmm2
  psrlq  $0x20,%xmm3
  pshufd $0x8,%xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  movdqu 0x10(%rdi),%xmm1
  pshufd $0x8,%xmm2,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm3,%xmm1
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm2
  paddd  %xmm2,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  lea    (%rax,%rdx,2),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  cmp    $0xa,%eax
  cmove  %edx,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: byte[16]
name: retrieve_data
arguments: data_tag: D3
datatype: byte[16]

tool: {"D6": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D3": [0x0a,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int check_digit(int *UCN) {
  int value = 0;
  int multiplier[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (int i = 0; i < 9; i++)
    value += UCN[i] * multiplier[i];
  value %= 11;
  if (value == 10)
    value = 0;
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<valid_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movb   $0x0,-0x11(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  je     L12
  mov    $0x0,%eax
  jmp    L19
L12:
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L9
L43:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  movzbl -0x11(%rbp),%eax
  xor    %edx,%eax
  mov    %al,-0x11(%rbp)
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L43
L16:
  lea    -0x12(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  movzbl -0x12(%rbp),%eax
  cmp    %al,-0x11(%rbp)
  sete   %al
  movzbl %al,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: *%02hhx

assistant: ```c
int valid_checksum(char *str) {
  char *ptr = str;
  unsigned char c_cksum = 0;
  unsigned char r_cksum;
  if (str[0] != '$')
    return 0;
  str++;
  for (ptr = str; *ptr && (*ptr != '*'); ptr++)
    c_cksum ^= *ptr;
  sscanf(ptr, "*%02hhx", &r_cksum);
  return c_cksum == r_cksum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<valid_checksum>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  cmpb   $0x24,(%rdi)
  jne    L12
  mov    %rdi,%rax
  lea    0x1(%rdi),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L14
  cmp    $0x2a,%al
  je     L14
  mov    $0x0,%ebx
L20:
  xor    %eax,%ebx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L41
  cmp    $0x2a,%al
  jne    L20
L41:
  lea    0x7(%rsp),%rdx
  lea    D9(%rip),%rsi
  call   <sscanf@plt>
  cmp    %bl,0x7(%rsp)
  sete   %dl
  movzbl %dl,%edx
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L14:
  mov    $0x0,%ebx
  jmp    L41
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D9: *%02hhx

assistant: ```c
int valid_checksum(char *str) {
  char *ptr = str;
  unsigned char c_cksum = 0;
  unsigned char r_cksum;
  if (str[0] != '$')
    return 0;
  str++;
  for (ptr = str; *ptr && (*ptr != '*'); ptr++)
    c_cksum ^= *ptr;
  sscanf(ptr, "*%02hhx", &r_cksum);
  return c_cksum == r_cksum;
}
```