ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <library_func2@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string

tool: D2: [-] => %d


assistant: ```c
int main() {
  int res = 1;
  res += library_func2();
  printf("[-] => %d\n", res);
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <library_func2@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: [-] => %d


assistant: ```c
int main() {
  int res = 1;
  res += library_func2();
  printf("[-] => %d\n", res);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <library_func2@plt>
  lea    D8(%rip),%rdi
  lea    0x1(%rax),%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: [-] => %d


assistant: ```c
int main() {
  int res = 1;
  res += library_func2();
  printf("[-] => %d\n", res);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <library_func2@plt>
  lea    D5(%rip),%rdi
  lea    0x1(%rax),%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string

tool: D5: [-] => %d


assistant: ```c
int main() {
  int res = 1;
  res += library_func2();
  printf("[-] => %d\n", res);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sprintf(char *str, const char *format, ...) {
  va_list args;
  int retval;
  va_start(args, format);
  retval = vsprintf(str, format, args);
  va_end(args);
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sprintf(char *str, const char *format, ...) {
  va_list args;
  int retval;
  va_start(args, format);
  retval = vsprintf(str, format, args);
  va_end(args);
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sprintf(char *str, const char *format, ...) {
  va_list args;
  int retval;
  va_start(args, format);
  retval = vsprintf(str, format, args);
  va_end(args);
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%edx
  mov    $0x7,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xc,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    $0xa,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xd,%edx
  mov    $0xd,%esi
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x9,%edx
  mov    $0x9,%esi
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xb,%edx
  mov    $0xb,%esi
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1b,%edx
  mov    $0x1b,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1b,%edx
  mov    $0x1b,%esi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_guessed: string
name: retrieve_data
arguments: data_label: D59
type_guessed: string
name: retrieve_data
arguments: data_label: D49
type_guessed: string
name: retrieve_data
arguments: data_label: D30
type_guessed: string
name: retrieve_data
arguments: data_label: D69
type_guessed: string
name: retrieve_data
arguments: data_label: D84
type_guessed: string
name: retrieve_data
arguments: data_label: D88
type_guessed: string
name: retrieve_data
arguments: data_label: D61
type_guessed: string
name: retrieve_data
arguments: data_label: D67
type_guessed: string

tool: D18: a: %d \%03o


tool: D59: b: %d \%03o


tool: D49: f: %d \%03o


tool: D30: n: %d \%03o


tool: D69: r: %d \%03o


tool: D84: t: %d \%03o


tool: D88: v: %d \%03o


tool: D61: e: %d \%03o


tool: D67: E: %d \%03o


assistant: ```c
int main() {
  printf("a: %d \\%03o\n", '\a', '\a');
  printf("b: %d \\%03o\n", '\b', '\b');
  printf("f: %d \\%03o\n", '\f', '\f');
  printf("n: %d \\%03o\n", '\n', '\n');
  printf("r: %d \\%03o\n", '\r', '\r');
  printf("t: %d \\%03o\n", '\t', '\t');
  printf("v: %d \\%03o\n", '\v', '\v');
  printf("e: %d \\%03o\n", '\e', '\e');
  printf("E: %d \\%03o\n", '\E', '\E');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edx
  mov    $0x7,%esi
  lea    D71(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D62(%rip),%rdi
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xc,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    $0xa,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0xd,%edx
  mov    $0xd,%esi
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%edx
  mov    $0x9,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0xb,%edx
  mov    $0xb,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x1b,%edx
  mov    $0x1b,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x1b,%edx
  mov    $0x1b,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D71
datatype: string
name: disassemble_data
arguments: label: D62
datatype: string
name: disassemble_data
arguments: label: D28
datatype: string
name: disassemble_data
arguments: label: D35
datatype: string
name: disassemble_data
arguments: label: D59
datatype: string
name: disassemble_data
arguments: label: D23
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D19
datatype: string
name: disassemble_data
arguments: label: D30
datatype: string

tool: D71: a: %d \%03o


tool: D62: b: %d \%03o


tool: D28: f: %d \%03o


tool: D35: n: %d \%03o


tool: D59: r: %d \%03o


tool: D23: t: %d \%03o


tool: D27: v: %d \%03o


tool: D19: e: %d \%03o


tool: D30: E: %d \%03o


assistant: ```c
int main() {
  printf("a: %d \\%03o\n", '\a', '\a');
  printf("b: %d \\%03o\n", '\b', '\b');
  printf("f: %d \\%03o\n", '\f', '\f');
  printf("n: %d \\%03o\n", '\n', '\n');
  printf("r: %d \\%03o\n", '\r', '\r');
  printf("t: %d \\%03o\n", '\t', '\t');
  printf("v: %d \\%03o\n", '\v', '\v');
  printf("e: %d \\%03o\n", '\e', '\e');
  printf("E: %d \\%03o\n", '\E', '\E');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edx
  mov    $0x7,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xc,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    $0xa,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0xd,%edx
  mov    $0xd,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%edx
  mov    $0x9,%esi
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    $0xb,%edx
  mov    $0xb,%esi
  lea    D66(%rip),%rdi
  call   <printf@plt>
  mov    $0x1b,%edx
  mov    $0x1b,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x1b,%edx
  mov    $0x1b,%esi
  lea    D68(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D43
type: string
name: retrieve_data
arguments: data_label: D48
type: string
name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D39
type: string
name: retrieve_data
arguments: data_label: D38
type: string
name: retrieve_data
arguments: data_label: D59
type: string
name: retrieve_data
arguments: data_label: D66
type: string
name: retrieve_data
arguments: data_label: D14
type: string
name: retrieve_data
arguments: data_label: D68
type: string

tool: D43: a: %d \%03o


tool: D48: b: %d \%03o


tool: D4: f: %d \%03o


tool: D39: n: %d \%03o


tool: D38: r: %d \%03o


tool: D59: t: %d \%03o


tool: D66: v: %d \%03o


tool: D14: e: %d \%03o


tool: D68: E: %d \%03o


assistant: ```c
int main() {
  printf("a: %d \\%03o\n", '\a', '\a');
  printf("b: %d \\%03o\n", '\b', '\b');
  printf("f: %d \\%03o\n", '\f', '\f');
  printf("n: %d \\%03o\n", '\n', '\n');
  printf("r: %d \\%03o\n", '\r', '\r');
  printf("t: %d \\%03o\n", '\t', '\t');
  printf("v: %d \\%03o\n", '\v', '\v');
  printf("e: %d \\%03o\n", '\e', '\e');
  printf("E: %d \\%03o\n", '\E', '\E');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edx
  mov    $0x7,%esi
  lea    D76(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D67(%rip),%rdi
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xc,%esi
  lea    D66(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    $0xa,%esi
  lea    D52(%rip),%rdi
  call   <printf@plt>
  mov    $0xd,%edx
  mov    $0xd,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%edx
  mov    $0x9,%esi
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    $0xb,%edx
  mov    $0xb,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x1b,%edx
  mov    $0x1b,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x1b,%edx
  mov    $0x1b,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D76
type_guessed: string
name: retrieve_data
arguments: data_label: D67
type_guessed: string
name: retrieve_data
arguments: data_label: D66
type_guessed: string
name: retrieve_data
arguments: data_label: D52
type_guessed: string
name: retrieve_data
arguments: data_label: D32
type_guessed: string
name: retrieve_data
arguments: data_label: D64
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string
name: retrieve_data
arguments: data_label: D39
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string

tool: D76: a: %d \%03o


tool: D67: b: %d \%03o


tool: D66: f: %d \%03o


tool: D52: n: %d \%03o


tool: D32: r: %d \%03o


tool: D64: t: %d \%03o


tool: D16: v: %d \%03o


tool: D39: e: %d \%03o


tool: D12: E: %d \%03o


assistant: ```c
int main() {
  printf("a: %d \\%03o\n", '\a', '\a');
  printf("b: %d \\%03o\n", '\b', '\b');
  printf("f: %d \\%03o\n", '\f', '\f');
  printf("n: %d \\%03o\n", '\n', '\n');
  printf("r: %d \\%03o\n", '\r', '\r');
  printf("t: %d \\%03o\n", '\t', '\t');
  printf("v: %d \\%03o\n", '\v', '\v');
  printf("e: %d \\%03o\n", '\e', '\e');
  printf("E: %d \\%03o\n", '\E', '\E');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  lea    -0x14(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <uncompress@plt>
  mov    %eax,-0xc(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L2
  mov    -0x14(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L2:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int unz(char *out, int *outlen, char *in, int inlen) {
  int e;
  uLong u_outlen = *outlen;
  uLong u_inlen = inlen;
  e = uncompress((Bytef *)out, &u_outlen, (Bytef *)in, u_inlen);
  if (e == Z_OK)
    *outlen = (int)u_outlen;
  return (e);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unz>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <uncompress@plt>
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L11
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  jmp    L9
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int unz(char *out, int *outlen, char *in, int inlen) {
  int e;
  uLong u_outlen = *outlen;
  uLong u_inlen = inlen;
  e = uncompress((Bytef *)out, &u_outlen, (Bytef *)in, u_inlen);
  if (e == Z_OK)
    *outlen = (int)u_outlen;
  return (e);
}
```
user: What is the c source code of the assembly code below:

```asm
<unz>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  call   <uncompress@plt>
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L11
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int unz(char *out, int *outlen, char *in, int inlen) {
  int e;
  uLong u_outlen = *outlen;
  uLong u_inlen = inlen;
  e = uncompress((Bytef *)out, &u_outlen, (Bytef *)in, u_inlen);
  if (e == Z_OK)
    *outlen = (int)u_outlen;
  return (e);
}
```
user: Translate the below assembly code into C programming language:

```asm
<unz>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  call   <uncompress@plt>
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L9
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int unz(char *out, int *outlen, char *in, int inlen) {
  int e;
  uLong u_outlen = *outlen;
  uLong u_inlen = inlen;
  e = uncompress((Bytef *)out, &u_outlen, (Bytef *)in, u_inlen);
  if (e == Z_OK)
    *outlen = (int)u_outlen;
  return (e);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<malloc_char_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  call   <error_and_exit@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *malloc_char_string(int dim1) {
  char *string;
  string = malloc(sizeof(char) * dim1);
  if (string == NULL)
    error_and_exit();
  return string;
}
```
user: What is the c source code of the assembly code below:

```asm
<malloc_char_string>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
L3:
  mov    %rbx,%rax
  pop    %rbx
  ret
L1:
  mov    $0x0,%eax
  call   <error_and_exit@plt>
  jmp    L3
```

assistant: ```c
char *malloc_char_string(int dim1) {
  char *string;
  string = malloc(sizeof(char) * dim1);
  if (string == NULL)
    error_and_exit();
  return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<malloc_char_string>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <error_and_exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *malloc_char_string(int dim1) {
  char *string;
  string = malloc(sizeof(char) * dim1);
  if (string == NULL)
    error_and_exit();
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<malloc_char_string>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  call   <error_and_exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *malloc_char_string(int dim1) {
  char *string;
  string = malloc(sizeof(char) * dim1);
  if (string == NULL)
    error_and_exit();
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gut_parse_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gut_parse_long@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L88
  cmpl   $0xfffffffd,-0x14(%rbp)
  je     L88
  mov    -0x14(%rbp),%eax
  jmp    L36
L88:
  cmpl   $0xfffffffd,-0x14(%rbp)
  jne    L72
  mov    -0x10(%rbp),%rdx
  mov    D43(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L116
L72:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  jle    L104
L116:
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffd,%eax
  jmp    L36
L104:
  cmpl   $0xfffffffd,-0x14(%rbp)
  jne    L110
  mov    -0x10(%rbp),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L10
L110:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  jge    L44
L10:
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffd,%eax
  jmp    L36
L44:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int gut_parse_int(const char *s, int *result) {
  long val;
  int err;
  err = gut_parse_long(s, &val);
  if ((err != 0) && (err != -3)) {
    return err;
  }
  if (((err == -3) && (val == LONG_MIN)) || (val < ((long)INT_MIN))) {
    *result = INT_MIN;
    return -3;
  }
  if (((err == -3) && (val == LONG_MAX)) || (val > ((long)INT_MAX))) {
    *result = INT_MAX;
    return -3;
  }
  *result = (int)val;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<gut_parse_int>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <gut_parse_long@plt>
  test   %eax,%eax
  je     L71
  cmp    $0xfffffffd,%eax
  jne    L97
L71:
  cmp    $0xfffffffd,%eax
  je     L16
  mov    (%rsp),%rax
  mov    D3(%rip),%rdx
  movslq (%rdx),%rdx
  cmp    %rax,%rdx
  jg     L55
L31:
  mov    D9(%rip),%rdx
  movslq (%rdx),%rdx
  cmp    %rax,%rdx
  jl     L96
  mov    %eax,(%rbx)
  mov    $0x0,%eax
L97:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L91
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  mov    (%rsp),%rax
  mov    D50(%rip),%rdx
  cmp    (%rdx),%rax
  je     L55
  mov    D3(%rip),%rdx
  movslq (%rdx),%rdx
  cmp    %rdx,%rax
  jl     L55
  mov    D24(%rip),%rdx
  cmp    (%rdx),%rax
  jne    L31
L96:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  mov    $0xfffffffd,%eax
  jmp    L97
L55:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  mov    $0xfffffffd,%eax
  jmp    L97
L91:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gut_parse_int(const char *s, int *result) {
  long val;
  int err;
  err = gut_parse_long(s, &val);
  if ((err != 0) && (err != -3)) {
    return err;
  }
  if (((err == -3) && (val == LONG_MIN)) || (val < ((long)INT_MIN))) {
    *result = INT_MIN;
    return -3;
  }
  if (((err == -3) && (val == LONG_MAX)) || (val > ((long)INT_MAX))) {
    *result = INT_MAX;
    return -3;
  }
  *result = (int)val;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gut_parse_int>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <gut_parse_long@plt>
  test   %eax,%eax
  je     L113
  cmp    $0xfffffffd,%eax
  je     L113
L84:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L103
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L113:
  mov    D37(%rip),%rdx
  mov    (%rdx),%ecx
  mov    (%rsp),%rdx
  cmp    $0xfffffffd,%eax
  je     L58
  movslq %ecx,%rax
  cmp    %rax,%rdx
  jl     L52
L30:
  mov    D43(%rip),%rax
  movslq (%rax),%rcx
  mov    %rcx,%rax
  cmp    %rdx,%rcx
  jl     L104
  mov    %edx,(%rbx)
  xor    %eax,%eax
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L58:
  mov    D2(%rip),%rax
  cmp    %rdx,(%rax)
  je     L52
  movslq %ecx,%rax
  cmp    %rax,%rdx
  jl     L52
  mov    D23(%rip),%rax
  cmp    %rdx,(%rax)
  jne    L30
  mov    D43(%rip),%rax
  mov    (%rax),%eax
L104:
  mov    %eax,(%rbx)
  mov    $0xfffffffd,%eax
  jmp    L84
L52:
  mov    %ecx,(%rbx)
  mov    $0xfffffffd,%eax
  jmp    L84
L103:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gut_parse_int(const char *s, int *result) {
  long val;
  int err;
  err = gut_parse_long(s, &val);
  if ((err != 0) && (err != -3)) {
    return err;
  }
  if (((err == -3) && (val == LONG_MIN)) || (val < ((long)INT_MIN))) {
    *result = INT_MIN;
    return -3;
  }
  if (((err == -3) && (val == LONG_MAX)) || (val > ((long)INT_MAX))) {
    *result = INT_MAX;
    return -3;
  }
  *result = (int)val;
  return 0;
}
```