ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<verify_binary_clauses>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %edx,%edi
  mov    (%rax),%edx
  cmp    %esi,%edx
  je     L20
  cmp    %ecx,%edx
  jne    L80
  mov    $0x1,%edx
  sub    %r8d,%edx
  cmp    %edx,0x4(%rax)
  jne    L80
  cmp    %esi,0x8(%rax)
  jne    L80
  mov    $0x1,%ecx
  sub    %edi,%ecx
  mov    $0x1,%edx
  cmp    %ecx,0xc(%rax)
  je     L24
L80:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <exit@plt>
  mov    $0x0,%edx
L24:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L20:
  mov    $0x1,%edx
  sub    %edi,%edx
  cmp    %edx,0x4(%rax)
  jne    L52
  cmp    %ecx,0x8(%rax)
  jne    L52
  mov    $0x1,%ecx
  sub    %r8d,%ecx
  mov    $0x1,%edx
  cmp    %ecx,0xc(%rax)
  je     L24
L52:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <exit@plt>
  mov    $0x0,%edx
  jmp    L24
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: VBC problem..

assistant: ```c
int verify_binary_clauses(int *varssigns, int var1, int sign1, int var2, int sign2) {
  if (var1 == *varssigns) {
    if ((*(varssigns + 1) != 1 - sign1) || (var2 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign2)) {
      printf("VBC problem..");
      exit(30);
      return 0;
    }
  } else {
    if ((var2 != *varssigns) || (*(varssigns + 1) != 1 - sign2) || (var1 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign1)) {
      printf("VBC problem..");
      exit(30);
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<verify_binary_clauses>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%edi
  cmp    %esi,%edi
  je     L60
  cmp    %ecx,%edi
  jne    L21
  mov    $0x1,%ecx
  mov    %ecx,%edi
  sub    %r8d,%edi
  cmp    %edi,0x4(%rax)
  jne    L21
  cmp    %esi,0x8(%rax)
  jne    L21
  sub    %edx,%ecx
  cmp    %ecx,0xc(%rax)
  jne    L21
  mov    $0x1,%r8d
  jmp    L38
  nopl   0x0(%rax)
L60:
  mov    $0x1,%esi
  mov    %esi,%edi
  sub    %edx,%edi
  cmp    %edi,0x4(%rax)
  jne    L21
  cmp    %ecx,0x8(%rax)
  je     L58
L21:
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L58:
  sub    %r8d,%esi
  mov    $0x1,%r8d
  cmp    %esi,0xc(%rax)
  jne    L21
L38:
  mov    %r8d,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: VBC problem..

assistant: ```c
int verify_binary_clauses(int *varssigns, int var1, int sign1, int var2, int sign2) {
  if (var1 == *varssigns) {
    if ((*(varssigns + 1) != 1 - sign1) || (var2 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign2)) {
      printf("VBC problem..");
      exit(30);
      return 0;
    }
  } else {
    if ((var2 != *varssigns) || (*(varssigns + 1) != 1 - sign2) || (var1 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign1)) {
      printf("VBC problem..");
      exit(30);
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<verify_binary_clauses>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%edi
  cmp    %esi,%edi
  je     L66
  cmp    %ecx,%edi
  jne    L83
  mov    $0x1,%ecx
  mov    %ecx,%edi
  sub    %r8d,%edi
  cmp    %edi,0x4(%rax)
  jne    L83
  cmp    %esi,0x8(%rax)
  jne    L83
  sub    %edx,%ecx
  cmp    %ecx,0xc(%rax)
  jne    L83
  mov    $0x1,%r8d
  jmp    L30
  nopl   0x0(%rax)
L66:
  mov    $0x1,%esi
  mov    %esi,%edi
  sub    %edx,%edi
  cmp    %edi,0x4(%rax)
  jne    L83
  cmp    %ecx,0x8(%rax)
  je     L80
L83:
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L80:
  sub    %r8d,%esi
  mov    $0x1,%r8d
  cmp    %esi,0xc(%rax)
  jne    L83
L30:
  mov    %r8d,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: VBC problem..

assistant: ```c
int verify_binary_clauses(int *varssigns, int var1, int sign1, int var2, int sign2) {
  if (var1 == *varssigns) {
    if ((*(varssigns + 1) != 1 - sign1) || (var2 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign2)) {
      printf("VBC problem..");
      exit(30);
      return 0;
    }
  } else {
    if ((var2 != *varssigns) || (*(varssigns + 1) != 1 - sign2) || (var1 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign1)) {
      printf("VBC problem..");
      exit(30);
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xmallocz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0xffffffffffffffff,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L3
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <panic@plt>
L3:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: xmallocz: data too large to fit into virtual memory space


assistant: ```c
void *xmallocz(size_t size) {
  void *ptr;
  if (__builtin_expect(!!(size + 1 < size), 0))
    panic("xmallocz: data too large to fit into virtual "
          "memory space\n");
  ptr = xmalloc(size + 1);
  ((char *)ptr)[size] = 0;
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xmallocz>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0xffffffffffffffff,%rdi
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L17
L7:
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
L17:
  lea    D2(%rip),%rdi
  call   <panic@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: xmallocz: data too large to fit into virtual memory space


assistant: ```c
void *xmallocz(size_t size) {
  void *ptr;
  if (__builtin_expect(!!(size + 1 < size), 0))
    panic("xmallocz: data too large to fit into virtual "
          "memory space\n");
  ptr = xmalloc(size + 1);
  ((char *)ptr)[size] = 0;
  return ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<xmallocz>:
  endbr64
  cmp    $0xffffffffffffffff,%rdi
  push   %rbx
  mov    %rdi,%rbx
  sete   %dil
  xor    %esi,%esi
  movzbl %dil,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L2
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
  nop
L2:
  lea    D7(%rip),%rdi
  call   <panic@plt>
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: xmallocz: data too large to fit into virtual memory space


assistant: ```c
void *xmallocz(size_t size) {
  void *ptr;
  if (__builtin_expect(!!(size + 1 < size), 0))
    panic("xmallocz: data too large to fit into virtual "
          "memory space\n");
  ptr = xmalloc(size + 1);
  ((char *)ptr)[size] = 0;
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xmallocz>:
  endbr64
  cmp    $0xffffffffffffffff,%rdi
  push   %rbx
  mov    %rdi,%rbx
  sete   %dil
  xor    %esi,%esi
  movzbl %dil,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L9
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
  nop
L9:
  lea    D4(%rip),%rdi
  call   <panic@plt>
  lea    0x1(%rbx),%rdi
  call   <xmalloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: xmallocz: data too large to fit into virtual memory space


assistant: ```c
void *xmallocz(size_t size) {
  void *ptr;
  if (__builtin_expect(!!(size + 1 < size), 0))
    panic("xmallocz: data too large to fit into virtual "
          "memory space\n");
  ptr = xmalloc(size + 1);
  ((char *)ptr)[size] = 0;
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  cmpl   $0x2,-0x34(%rbp)
  je     L28
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <Usage@plt>
L28:
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x24(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x28(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L3
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <Usage@plt>
L3:
  mov    -0x28(%rbp),%edx
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  lea    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <Trap@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D28
type: string
name: parse_data
arguments: data_tag: D37
type: string
name: parse_data
arguments: data_tag: D24
type: string
name: parse_data
arguments: data_tag: D9
type: string

tool: D28: Enter a, b, and n

tool: D37: %lf %lf %d

tool: D24: With n = %d trapezoids, our estimate


tool: D9: of the integral from %f to %f = %.14e


assistant: ```c
int main(int argc, char *argv[]) {
  double global_result = 0.0;
  double a, b;
  int n;
  int thread_count;
  if (argc != 2)
    Usage(argv[0]);
  thread_count = strtol(argv[1], NULL, 10);
  printf("Enter a, b, and n\n");
  scanf("%lf %lf %d", &a, &b, &n);
  if (n % thread_count != 0)
    Usage(argv[0]);
#pragma omp parallel num_threads(thread_count)
  Trap(a, b, n, &global_result);
  printf("With n = %d trapezoids, our estimate\n", n);
  printf("of the integral from %f to %f = %.14e\n", a, b, global_result);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  cmp    $0x2,%edi
  jne    L12
L18:
  mov    0x8(%rbp),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%ebx
  lea    D37(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L49
L27:
  lea    0x10(%rsp),%rsi
  mov    0xc(%rsp),%edi
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  call   <Trap@plt>
  mov    0xc(%rsp),%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  lea    D34(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    (%rsi),%rdi
  call   <Usage@plt>
  jmp    L18
L49:
  mov    0x0(%rbp),%rdi
  call   <Usage@plt>
  jmp    L27
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D37
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D34
type_guessed: string

tool: D37: Enter a, b, and n

tool: D8: %lf %lf %d

tool: D2: With n = %d trapezoids, our estimate


tool: D34: of the integral from %f to %f = %.14e


assistant: ```c
int main(int argc, char *argv[]) {
  double global_result = 0.0;
  double a, b;
  int n;
  int thread_count;
  if (argc != 2)
    Usage(argv[0]);
  thread_count = strtol(argv[1], NULL, 10);
  printf("Enter a, b, and n\n");
  scanf("%lf %lf %d", &a, &b, &n);
  if (n % thread_count != 0)
    Usage(argv[0]);
#pragma omp parallel num_threads(thread_count)
  Trap(a, b, n, &global_result);
  printf("With n = %d trapezoids, our estimate\n", n);
  printf("of the integral from %f to %f = %.14e\n", a, b, global_result);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  cmp    $0x2,%edi
  je     L11
  mov    (%rsi),%rdi
  call   <Usage@plt>
L11:
  mov    0x8(%rbp),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  lea    D33(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  lea    0x20(%rsp),%rdx
  lea    0xc(%rsp),%rcx
  lea    D21(%rip),%rdi
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    %edi,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L27
L9:
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  lea    0x10(%rsp),%rsi
  call   <Trap@plt>
  mov    0xc(%rsp),%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  lea    D15(%rip),%rdi
  movsd  0x18(%rsp),%xmm0
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    0x0(%rbp),%rdi
  call   <Usage@plt>
  mov    0xc(%rsp),%edi
  jmp    L9
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D33
data_type: string
name: retrieve_data
arguments: label: D21
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string

tool: D33: Enter a, b, and n

tool: D21: %lf %lf %d

tool: D2: With n = %d trapezoids, our estimate


tool: D15: of the integral from %f to %f = %.14e


assistant: ```c
int main(int argc, char *argv[]) {
  double global_result = 0.0;
  double a, b;
  int n;
  int thread_count;
  if (argc != 2)
    Usage(argv[0]);
  thread_count = strtol(argv[1], NULL, 10);
  printf("Enter a, b, and n\n");
  scanf("%lf %lf %d", &a, &b, &n);
  if (n % thread_count != 0)
    Usage(argv[0]);
#pragma omp parallel num_threads(thread_count)
  Trap(a, b, n, &global_result);
  printf("With n = %d trapezoids, our estimate\n", n);
  printf("of the integral from %f to %f = %.14e\n", a, b, global_result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  cmp    $0x2,%edi
  je     L11
  mov    (%rsi),%rdi
  call   <Usage@plt>
L11:
  mov    0x8(%rbp),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  lea    0x20(%rsp),%rdx
  lea    0xc(%rsp),%rcx
  lea    D12(%rip),%rdi
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    %edi,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L28
L37:
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  lea    0x10(%rsp),%rsi
  call   <Trap@plt>
  mov    0xc(%rsp),%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  lea    D30(%rip),%rdi
  movsd  0x18(%rsp),%xmm0
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    0x0(%rbp),%rdi
  call   <Usage@plt>
  mov    0xc(%rsp),%edi
  jmp    L37
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D32
type: string
name: parse_data
arguments: label: D30
type: string

tool: D14: Enter a, b, and n

tool: D12: %lf %lf %d

tool: D32: With n = %d trapezoids, our estimate


tool: D30: of the integral from %f to %f = %.14e


assistant: ```c
int main(int argc, char *argv[]) {
  double global_result = 0.0;
  double a, b;
  int n;
  int thread_count;
  if (argc != 2)
    Usage(argv[0]);
  thread_count = strtol(argv[1], NULL, 10);
  printf("Enter a, b, and n\n");
  scanf("%lf %lf %d", &a, &b, &n);
  if (n % thread_count != 0)
    Usage(argv[0]);
#pragma omp parallel num_threads(thread_count)
  Trap(a, b, n, &global_result);
  printf("With n = %d trapezoids, our estimate\n", n);
  printf("of the integral from %f to %f = %.14e\n", a, b, global_result);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<msg_setr_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <starMallocAtomic@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <cnfImprt@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <msgSetr@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <starFree@plt>
  nop
  leave
  ret
```

assistant: ```c
void msg_setr_(char *const TOKEN, float *const RVALUE, int TOKEN_length) {
  float rvalue;
  char *token;
  ;
  rvalue = *RVALUE;
  token = starMallocAtomic(TOKEN_length + 1);
  cnfImprt(TOKEN, TOKEN_length, token);
  msgSetr(token, rvalue);
  starFree(token);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<msg_setr_>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    (%rsi),%r13d
  lea    0x1(%rdx),%edi
  call   <starMallocAtomic@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <cnfImprt@plt>
  movd   %r13d,%xmm0
  mov    %rbx,%rdi
  call   <msgSetr@plt>
  mov    %rbx,%rdi
  call   <starFree@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void msg_setr_(char *const TOKEN, float *const RVALUE, int TOKEN_length) {
  float rvalue;
  char *token;
  ;
  rvalue = *RVALUE;
  token = starMallocAtomic(TOKEN_length + 1);
  cnfImprt(TOKEN, TOKEN_length, token);
  msgSetr(token, rvalue);
  starFree(token);
}
```
user: What is the c source code of the assembly code below?

```asm
<msg_setr_>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    0x1(%rdx),%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    $0x10,%rsp
  movss  (%rsi),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <starMallocAtomic@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <cnfImprt@plt>
  movss  0xc(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <msgSetr@plt>
  add    $0x10,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <starFree@plt>
```

assistant: ```c
void msg_setr_(char *const TOKEN, float *const RVALUE, int TOKEN_length) {
  float rvalue;
  char *token;
  ;
  rvalue = *RVALUE;
  token = starMallocAtomic(TOKEN_length + 1);
  cnfImprt(TOKEN, TOKEN_length, token);
  msgSetr(token, rvalue);
  starFree(token);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<msg_setr_>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    0x1(%rdx),%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    $0x10,%rsp
  movss  (%rsi),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <starMallocAtomic@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <cnfImprt@plt>
  movss  0xc(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <msgSetr@plt>
  add    $0x10,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <starFree@plt>
```

assistant: ```c
void msg_setr_(char *const TOKEN, float *const RVALUE, int TOKEN_length) {
  float rvalue;
  char *token;
  ;
  rvalue = *RVALUE;
  token = starMallocAtomic(TOKEN_length + 1);
  cnfImprt(TOKEN, TOKEN_length, token);
  msgSetr(token, rvalue);
  starFree(token);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trimSpace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L16:
  subq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L28
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L16
L28:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  leave
  ret
```

assistant: ```c
char *trimSpace(char *ptr, char *start) {
  char *p = ptr - 1;
  while (p > start && isspace(*p))
    --p;
  return p + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trimSpace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    -0x1(%rdi),%rbx
  cmp    %rsi,%rbx
  jbe    L10
L9:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L10
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L9
  mov    %rbp,%rbx
L10:
  lea    0x1(%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *trimSpace(char *ptr, char *start) {
  char *p = ptr - 1;
  while (p > start && isspace(*p))
    --p;
  return p + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<trimSpace>:
  endbr64
  push   %r12
  lea    -0x1(%rdi),%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    %rsi,%r12
  ja     L22
  jmp    L49
  nopl   0x0(%rax)
L6:
  lea    -0x1(%r12),%rax
  cmp    %rax,%rbx
  je     L31
  mov    %rax,%r12
L22:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
  add    $0x1,%r12
L31:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L49:
  mov    %rdi,%r12
  jmp    L31
```

assistant: ```c
char *trimSpace(char *ptr, char *start) {
  char *p = ptr - 1;
  while (p > start && isspace(*p))
    --p;
  return p + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trimSpace>:
  endbr64
  push   %r12
  lea    -0x1(%rdi),%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    %rsi,%r12
  ja     L16
  jmp    L19
  nopl   0x0(%rax)
L27:
  lea    -0x1(%r12),%rax
  cmp    %rax,%rbx
  je     L42
  mov    %rax,%r12
L16:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
  add    $0x1,%r12
L42:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L19:
  mov    %rdi,%r12
  jmp    L42
```

assistant: ```c
char *trimSpace(char *ptr, char *start) {
  char *p = ptr - 1;
  while (p > start && isspace(*p))
    --p;
  return p + 1;
}
```