user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L31:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L31
  sub    $0xae8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3d0ad8(%rsp)
  xor    %eax,%eax
  movl   $0xa,(%rsp)
  movl   $0x1e,0x4(%rsp)
  movl   $0x3c,0x8(%rsp)
  movl   $0x64,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x9,0x1c(%rsp)
  movl   $0x50,0x20(%rsp)
  movl   $0x28,0x24(%rsp)
  movl   $0x37,0x28(%rsp)
  movl   $0x16,0x2c(%rsp)
  movl   $0x63,0x30(%rsp)
  mov    %rsp,%rdi
  mov    $0xa,%ecx
  mov    $0xc,%edx
  mov    $0x0,%esi
  call   <findRank@plt>
  mov    (%rsp,%rax,4),%edx
  mov    $0xa,%esi
  lea    D96(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D89(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rsi
  lea    D99(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r13
  lea    0x1d0(%rsp),%rbx
  lea    0x3d0ad0(%rsp),%r12
  lea    D32(%rip),%rbp
L38:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <fscanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L38
  lea    D89(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rsi
  lea    D94(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r14
  lea    0x40(%rsp),%rbx
  lea    0x1d0(%rsp),%r12
  mov    %rbx,%rbp
  lea    D32(%rip),%r15
L47:
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <fscanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L47
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  lea    D63(%rip),%rsi
  lea    D124(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    D57(%rip),%r13
L26:
  lea    0x1d0(%rsp),%rdi
  mov    (%rbx),%ecx
  mov    $0xf423f,%edx
  mov    $0x0,%esi
  call   <findRank@plt>
  mov    0x1d0(%rsp,%rax,4),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L26
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D89(%rip),%rdi
  call   <puts@plt>
  mov    0x3d0ad8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x3d0ae8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D96
data_type: string
name: unpack_data
arguments: data_tag: D89
data_type: string
name: unpack_data
arguments: data_tag: D17
data_type: string
name: unpack_data
arguments: data_tag: D99
data_type: string
name: unpack_data
arguments: data_tag: D32
data_type: string
name: unpack_data
arguments: data_tag: D94
data_type: string
name: unpack_data
arguments: data_tag: D63
data_type: string
name: unpack_data
arguments: data_tag: D124
data_type: string
name: unpack_data
arguments: data_tag: D57
data_type: string

tool: D96: 
 The element with rank %d is %d


tool: D89: 





tool: D17: r

tool: D99: data.in

tool: D32: %d

tool: D94: data_rank.in

tool: D63: w

tool: D124: data_out.in

tool: D57: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int A[1000000], B[100];
  FILE *fp_num, *fp_rank, *fp_out;
  int a[] = {10, 30, 60, 100, 1, 2, 7, 9, 80, 40, 55, 22, 99};
  int size = sizeof(a) / sizeof(a[0]);
  int rank = 10;
  printf("\n The element with rank %d is %d\n", rank, a[findRank(a, 0, size - 1, rank)]);
  printf("\n");
  printf("\n\n\n\n\n");
  fp_num = fopen("data.in", "r");
  for (int i = 0; i < 1000000; i++)
    fscanf(fp_num, "%d", &A[i]);
  printf("\n\n\n\n\n");
  fp_rank = fopen("data_rank.in", "r");
  for (int i = 0; i < 100; i++)
    fscanf(fp_rank, "%d", &B[i]);
  fclose(fp_rank);
  fclose(fp_num);
  fp_out = fopen("data_out.in", "w");
  for (int i = 0; i < 100; i++) {
    fprintf(fp_out, "%d\n", A[findRank(A, 0, 1000000 - 1, B[i])]);
  }
  fclose(fp_out);
  printf("\n\n\n\n\n");
  return 0;
}
```