ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<KMP>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <GetPrefixValue@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <KMPStringMatch@plt>
```

assistant: ```c
int KMP(const char *strPattern, int len, const char *strTarget) {
  GetPrefixValue(strPattern, len);
  return KMPStringMatch(strPattern, len, strTarget, strlen(strTarget));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D53(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <square@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  mov    $0x0,%eax
  call   <f@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D53
type: string
name: disassemble_data
arguments: data_label: D27
type: string
name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D25
type: string
name: disassemble_data
arguments: data_label: D13
type: string

tool: D53: square

tool: D27: Call function %s


tool: D9: 1. %d


tool: D25: f

tool: D13: 2. %d


assistant: ```c
int main() {
  printf("1. %d\n", (printf("Call function %s\n", "square"), square(4)));
  printf("2. %d\n", (printf("Call function %s\n", "f"), f(10)));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rsi
  lea    D41(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <square@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  mov    $0x0,%eax
  call   <f@plt>
  mov    %eax,%esi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string
name: retrieve_data
arguments: label: D41
datatype: string
name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D16
datatype: string
name: retrieve_data
arguments: label: D45
datatype: string

tool: D7: square

tool: D41: Call function %s


tool: D12: 1. %d


tool: D16: f

tool: D45: 2. %d


assistant: ```c
int main() {
  printf("1. %d\n", (printf("Call function %s\n", "square"), square(4)));
  printf("2. %d\n", (printf("Call function %s\n", "f"), f(10)));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D40(%rip),%rbp
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x4,%edi
  xor    %eax,%eax
  call   <square@plt>
  lea    D41(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  xor    %eax,%eax
  call   <f@plt>
  lea    D31(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D40
datatype: string
name: read_data
arguments: data_label: D8
datatype: string
name: read_data
arguments: data_label: D41
datatype: string
name: read_data
arguments: data_label: D23
datatype: string
name: read_data
arguments: data_label: D31
datatype: string

tool: D40: Call function %s


tool: D8: square

tool: D41: 1. %d


tool: D23: f

tool: D31: 2. %d


assistant: ```c
int main() {
  printf("1. %d\n", (printf("Call function %s\n", "square"), square(4)));
  printf("2. %d\n", (printf("Call function %s\n", "f"), f(10)));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  lea    D5(%rip),%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x4,%edi
  xor    %eax,%eax
  call   <square@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  xor    %eax,%eax
  call   <f@plt>
  lea    D35(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type: string
name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D35
type: string

tool: D16: Call function %s


tool: D5: square

tool: D2: 1. %d


tool: D9: f

tool: D35: 2. %d


assistant: ```c
int main() {
  printf("1. %d\n", (printf("Call function %s\n", "square"), square(4)));
  printf("2. %d\n", (printf("Call function %s\n", "f"), f(10)));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GC_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *GC_malloc(int x) {
  void *p = (void *)calloc(sizeof(char), x);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GC_malloc>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *GC_malloc(int x) {
  void *p = (void *)calloc(sizeof(char), x);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GC_malloc>:
  endbr64
  mov    %edi,%esi
  mov    $0x1,%edi
  jmp    1050 <calloc@plt>
```

assistant: ```c
void *GC_malloc(int x) {
  void *p = (void *)calloc(sizeof(char), x);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GC_malloc>:
  endbr64
  mov    %edi,%esi
  mov    $0x1,%edi
  jmp    1050 <calloc@plt>
```

assistant: ```c
void *GC_malloc(int x) {
  void *p = (void *)calloc(sizeof(char), x);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_pp0_balance_policy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <pp0_node_to_cpu@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    $0x63a,%esi
  mov    %eax,%edi
  call   <get_balance_policy@plt>
  leave
  ret
```

assistant: ```c
int get_pp0_balance_policy(uint64_t node, uint64_t *priority_level) {
  uint64_t cpu = pp0_node_to_cpu(node);
  return get_balance_policy(cpu, 0x63a, priority_level);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_pp0_balance_policy>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <pp0_node_to_cpu@plt>
  mov    %eax,%edi
  mov    %rbx,%rdx
  mov    $0x63a,%esi
  call   <get_balance_policy@plt>
  pop    %rbx
  ret
```

assistant: ```c
int get_pp0_balance_policy(uint64_t node, uint64_t *priority_level) {
  uint64_t cpu = pp0_node_to_cpu(node);
  return get_balance_policy(cpu, 0x63a, priority_level);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_pp0_balance_policy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  call   <pp0_node_to_cpu@plt>
  mov    %r12,%rdx
  mov    $0x63a,%esi
  pop    %r12
  mov    %eax,%edi
  jmp    1070 <get_balance_policy@plt>
```

assistant: ```c
int get_pp0_balance_policy(uint64_t node, uint64_t *priority_level) {
  uint64_t cpu = pp0_node_to_cpu(node);
  return get_balance_policy(cpu, 0x63a, priority_level);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_pp0_balance_policy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  call   <pp0_node_to_cpu@plt>
  mov    %r12,%rdx
  mov    $0x63a,%esi
  pop    %r12
  mov    %eax,%edi
  jmp    1070 <get_balance_policy@plt>
```

assistant: ```c
int get_pp0_balance_policy(uint64_t node, uint64_t *priority_level) {
  uint64_t cpu = pp0_node_to_cpu(node);
  return get_balance_policy(cpu, 0x63a, priority_level);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parsecmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L114
L123:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x10(%rbp)
L114:
  cmpl   $0x5,-0x10(%rbp)
  jle    L123
  jmp    L66
L17:
  addq   $0x1,-0x8(%rbp)
L66:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L147
L26:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L17
  jmp    L147
L16:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L207
L75:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L159
  nop
L38:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L47
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L38
L47:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jae    L165
L159:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L191
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L191:
  addq   $0x1,-0x8(%rbp)
L207:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L126
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
  jmp    L126
L165:
  nop
  jmp    L126
L156:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L126:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L172
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L156
L172:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L112
L147:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L16
  jmp    L145
L112:
  nop
L145:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int parsecmd(char *buf, int len, char **par) {
  char *ptr;
  int i, n = 0;
  ptr = buf;
  for (i = 0; i < 6; i++)
    par[i] = NULL;
  while ((*ptr == ' ' || *ptr == '\0') && (ptr < buf + len))
    ptr++;
  while (ptr < buf + len) {
    par[n++] = ptr;
    while (*ptr != ' ' && *ptr != '\0') {
      if (*ptr == '\"') {
        while (*(++ptr) != '\"' && ptr < buf + len)
          ;
        if (ptr >= buf + len)
          break;
      }
      if (*ptr == '\n')
        *ptr = '\0';
      ptr++;
    }
    while ((*ptr == ' ') && (ptr < buf + len)) {
      *ptr = '\0';
      ptr++;
    }
    if (*ptr == '\0')
      break;
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parsecmd>:
  endbr64
  lea    0x30(%rdx),%rcx
  mov    %rdx,%rax
L137:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L137
  testb  $0xdf,(%rdi)
  jne    L227
  movslq %esi,%rcx
  add    %rdi,%rcx
  cmp    %rcx,%rdi
  jae    L1
  mov    %rdi,%rax
L69:
  add    $0x1,%rax
  testb  $0xdf,(%rax)
  jne    L134
  cmp    %rcx,%rax
  jne    L69
  mov    $0x0,%r8d
L121:
  mov    %r8d,%eax
  ret
L185:
  add    $0x1,%rax
  cmpb   $0x22,(%rax)
  je     L127
  cmp    %rax,%rdi
  ja     L185
L127:
  cmp    %rax,%rdi
  jbe    L174
  mov    %rax,%rcx
  jmp    L61
L174:
  movzbl (%rax),%ecx
  cmp    %rax,%rdi
  jbe    L182
  cmp    $0x20,%cl
  jne    L182
L162:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  movzbl (%rax),%ecx
  cmp    %rax,%rdi
  jbe    L182
  cmp    $0x20,%cl
  je     L162
L182:
  add    $0x8,%rdx
  test   %cl,%cl
  je     L121
L203:
  cmp    %rax,%rdi
  jbe    L121
  add    $0x1,%r8d
  mov    %rax,(%rdx)
  movzbl (%rax),%esi
  test   $0xdf,%sil
  jne    L194
  jmp    L174
L34:
  lea    0x1(%rcx),%rax
  movzbl 0x1(%rcx),%esi
  test   $0xdf,%sil
  je     L174
L194:
  mov    %rax,%rcx
  cmp    $0x22,%sil
  je     L185
L61:
  cmpb   $0xa,(%rcx)
  jne    L34
  movb   $0x0,(%rcx)
  jmp    L34
L227:
  mov    %rdi,%rax
L134:
  mov    $0x0,%r8d
  movslq %esi,%rsi
  add    %rsi,%rdi
  jmp    L203
L1:
  mov    $0x0,%r8d
  jmp    L121
```

assistant: ```c
int parsecmd(char *buf, int len, char **par) {
  char *ptr;
  int i, n = 0;
  ptr = buf;
  for (i = 0; i < 6; i++)
    par[i] = NULL;
  while ((*ptr == ' ' || *ptr == '\0') && (ptr < buf + len))
    ptr++;
  while (ptr < buf + len) {
    par[n++] = ptr;
    while (*ptr != ' ' && *ptr != '\0') {
      if (*ptr == '\"') {
        while (*(++ptr) != '\"' && ptr < buf + len)
          ;
        if (ptr >= buf + len)
          break;
      }
      if (*ptr == '\n')
        *ptr = '\0';
      ptr++;
    }
    while ((*ptr == ' ') && (ptr < buf + len)) {
      *ptr = '\0';
      ptr++;
    }
    if (*ptr == '\0')
      break;
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parsecmd>:
  endbr64
  pxor   %xmm0,%xmm0
  movslq %esi,%rcx
  movups %xmm0,(%rdx)
  add    %rdi,%rcx
  movups %xmm0,0x10(%rdx)
  movups %xmm0,0x20(%rdx)
  testb  $0xdf,(%rdi)
  jne    L79
  cmp    %rcx,%rdi
  jb     L146
  jmp    L100
  nopl   0x0(%rax,%rax,1)
L75:
  cmp    %rcx,%rdi
  je     L100
L146:
  add    $0x1,%rdi
  testb  $0xdf,(%rdi)
  je     L75
L79:
  cmp    %rcx,%rdi
  jae    L100
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L127:
  mov    %rdi,-0x8(%rdx,%r8,8)
  movzbl (%rdi),%eax
  mov    %r8d,%r9d
  test   $0xdf,%al
  jne    L116
  jmp    L70
  nopl   0x0(%rax)
L219:
  movzbl (%rdi),%eax
  mov    %rdi,%rsi
L13:
  cmp    $0xa,%al
  jne    L123
  movb   $0x0,(%rdi)
L123:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rdi
  test   $0xdf,%al
  je     L70
L116:
  cmp    $0x22,%al
  jne    L219
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    %rcx,%rdi
  jae    L70
  nopl   0x0(%rax)
L144:
  cmp    $0x22,%al
  je     L95
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    %rcx,%rdi
  jb     L144
L70:
  cmp    $0x20,%al
  jne    L137
  cmp    %rcx,%rdi
  jb     L40
  jmp    L92
  nopl   0x0(%rax,%rax,1)
L226:
  cmp    %rcx,%rdi
  je     L92
L40:
  movb   $0x0,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  je     L226
L137:
  test   %al,%al
  je     L92
  add    $0x1,%r8
  cmp    %rcx,%rdi
  jb     L127
L92:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L95:
  cmp    %rcx,%rdi
  jae    L70
  mov    %rdi,%rsi
  jmp    L13
L100:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int parsecmd(char *buf, int len, char **par) {
  char *ptr;
  int i, n = 0;
  ptr = buf;
  for (i = 0; i < 6; i++)
    par[i] = NULL;
  while ((*ptr == ' ' || *ptr == '\0') && (ptr < buf + len))
    ptr++;
  while (ptr < buf + len) {
    par[n++] = ptr;
    while (*ptr != ' ' && *ptr != '\0') {
      if (*ptr == '\"') {
        while (*(++ptr) != '\"' && ptr < buf + len)
          ;
        if (ptr >= buf + len)
          break;
      }
      if (*ptr == '\n')
        *ptr = '\0';
      ptr++;
    }
    while ((*ptr == ' ') && (ptr < buf + len)) {
      *ptr = '\0';
      ptr++;
    }
    if (*ptr == '\0')
      break;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parsecmd>:
  endbr64
  pxor   %xmm0,%xmm0
  movslq %esi,%rsi
  movups %xmm0,(%rdx)
  add    %rdi,%rsi
  movups %xmm0,0x10(%rdx)
  movups %xmm0,0x20(%rdx)
  testb  $0xdf,(%rdi)
  jne    L230
  cmp    %rsi,%rdi
  jb     L84
  jmp    L98
  nopl   0x0(%rax,%rax,1)
L36:
  cmp    %rsi,%rdi
  je     L98
L84:
  add    $0x1,%rdi
  testb  $0xdf,(%rdi)
  je     L36
L230:
  cmp    %rsi,%rdi
  jae    L98
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L43:
  mov    %rdi,-0x8(%rdx,%r8,8)
  movzbl (%rdi),%eax
  mov    %r8d,%r9d
  test   $0xdf,%al
  jne    L38
  jmp    L141
  nopl   0x0(%rax)
L139:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   $0xdf,%al
  je     L144
L76:
  mov    %rcx,%rdi
L38:
  cmp    $0x22,%al
  je     L11
L39:
  cmp    $0xa,%al
  jne    L139
  movzbl 0x1(%rdi),%eax
  movb   $0x0,(%rdi)
  lea    0x1(%rdi),%rcx
  test   $0xdf,%al
  jne    L76
  cmp    $0x20,%al
  je     L2
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %rcx,%rdi
  test   %al,%al
  je     L68
  add    $0x1,%r8
  cmp    %rsi,%rcx
  jb     L43
L68:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L1:
  cmp    $0x22,%al
  je     L85
L11:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    %rsi,%rdi
  jb     L1
L141:
  mov    %rdi,%rcx
L144:
  cmp    $0x20,%al
  jne    L58
L2:
  cmp    %rsi,%rcx
  jb     L109
  jmp    L68
  cs nopw 0x0(%rax,%rax,1)
L59:
  cmp    %rsi,%rcx
  je     L68
L109:
  movb   $0x0,(%rcx)
  movzbl 0x1(%rcx),%eax
  add    $0x1,%rcx
  cmp    $0x20,%al
  je     L59
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L85:
  cmp    %rsi,%rdi
  jb     L39
  jmp    L141
L98:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int parsecmd(char *buf, int len, char **par) {
  char *ptr;
  int i, n = 0;
  ptr = buf;
  for (i = 0; i < 6; i++)
    par[i] = NULL;
  while ((*ptr == ' ' || *ptr == '\0') && (ptr < buf + len))
    ptr++;
  while (ptr < buf + len) {
    par[n++] = ptr;
    while (*ptr != ' ' && *ptr != '\0') {
      if (*ptr == '\"') {
        while (*(++ptr) != '\"' && ptr < buf + len)
          ;
        if (ptr >= buf + len)
          break;
      }
      if (*ptr == '\n')
        *ptr = '\0';
      ptr++;
    }
    while ((*ptr == ' ') && (ptr < buf + len)) {
      *ptr = '\0';
      ptr++;
    }
    if (*ptr == '\0')
      break;
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ZopfliGetDistExtraBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  jg     L10
  mov    $0x0,%eax
  jmp    L6
L10:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  bsr    %eax,%eax
  xor    $0x1f,%eax
  xor    $0x1f,%eax
  sub    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int ZopfliGetDistExtraBits(int dist) {
  if (dist < 5)
    return 0;
  return (31 ^ __builtin_clz(dist - 1)) - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ZopfliGetDistExtraBits>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x4,%edi
  jle    L1
  sub    $0x1,%edi
  bsr    %edi,%edi
  lea    -0x1(%rdi),%eax
L1:
  ret
```

assistant: ```c
int ZopfliGetDistExtraBits(int dist) {
  if (dist < 5)
    return 0;
  return (31 ^ __builtin_clz(dist - 1)) - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ZopfliGetDistExtraBits>:
  endbr64
  xor    %eax,%eax
  cmp    $0x4,%edi
  jle    L8
  sub    $0x1,%edi
  bsr    %edi,%edi
  lea    -0x1(%rdi),%eax
L8:
  ret
```

assistant: ```c
int ZopfliGetDistExtraBits(int dist) {
  if (dist < 5)
    return 0;
  return (31 ^ __builtin_clz(dist - 1)) - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ZopfliGetDistExtraBits>:
  endbr64
  xor    %eax,%eax
  cmp    $0x4,%edi
  jle    L1
  sub    $0x1,%edi
  bsr    %edi,%edi
  lea    -0x1(%rdi),%eax
L1:
  ret
```

assistant: ```c
int ZopfliGetDistExtraBits(int dist) {
  if (dist < 5)
    return 0;
  return (31 ^ __builtin_clz(dist - 1)) - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expand_column>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  movl   $0xfffffffe,-0xc(%rbp)
  jmp    L5
L8:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L5:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int expand_column(void **column, size_t new_max_rows, size_t element_size) {
  int ret = 0;
  void *tmp;
  tmp = realloc((void **)*column, new_max_rows * element_size);
  if (tmp == NULL) {
    ret = -2;
    goto out;
  }
  *column = tmp;
out:
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expand_column>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  imul   %rdx,%rsi
  mov    (%rdi),%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,(%rbx)
  mov    $0x0,%eax
L17:
  pop    %rbx
  ret
L3:
  mov    $0xfffffffe,%eax
  jmp    L17
```

assistant: ```c
int expand_column(void **column, size_t new_max_rows, size_t element_size) {
  int ret = 0;
  void *tmp;
  tmp = realloc((void **)*column, new_max_rows * element_size);
  if (tmp == NULL) {
    ret = -2;
    goto out;
  }
  *column = tmp;
out:
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<expand_column>:
  endbr64
  push   %rbx
  imul   %rdx,%rsi
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  mov    $0xfffffffe,%eax
  pop    %rbx
  ret
```

assistant: ```c
int expand_column(void **column, size_t new_max_rows, size_t element_size) {
  int ret = 0;
  void *tmp;
  tmp = realloc((void **)*column, new_max_rows * element_size);
  if (tmp == NULL) {
    ret = -2;
    goto out;
  }
  *column = tmp;
out:
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<expand_column>:
  endbr64
  push   %rbx
  imul   %rdx,%rsi
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  mov    $0xfffffffe,%eax
  pop    %rbx
  ret
```

assistant: ```c
int expand_column(void **column, size_t new_max_rows, size_t element_size) {
  int ret = 0;
  void *tmp;
  tmp = realloc((void **)*column, new_max_rows * element_size);
  if (tmp == NULL) {
    ret = -2;
    goto out;
  }
  *column = tmp;
out:
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L22
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L18
L22:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sync_time@plt>
  test   %rax,%rax
  je     L35
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L26
L35:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L26:
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D8: usage: %s <device>


tool: D7: Error occured while syncing time.

tool: D1: Time was synced!

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("usage: %s <device>\n", basename(argv[0]));
    return 1;
  }
  if (sync_time(argv[1], NULL)) {
    printf("Error occured while syncing time.\n");
  } else {
    printf("Time was synced!\n");
  }
  return 0;
}
```