ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_stop_word>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,(%rsp)
  lea    D25(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D23(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
L10:
  mov    $0x64,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L28
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L10
  mov    $0x0,%eax
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    $0x1,%eax
  jmp    L24
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
datatype: string
name: retrieve_data
arguments: data_tag: D25
datatype: string
name: retrieve_data
arguments: data_tag: D23
datatype: string

tool: D17: the

tool: D25: and

tool: D23: a

assistant: ```c
int is_stop_word(char *word) {
  char *stop_words[] = {"the", "and", "a"};
  int stop_words_len = sizeof(stop_words) / sizeof(char *);
  int i;
  for (i = 0; i < stop_words_len; i++) {
    if (strncmp(stop_words[i], word, 100) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_stop_word>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D23(%rip),%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D16(%rip),%rax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  mov    %rax,0x8(%rsp)
  lea    D28(%rip),%rax
  mov    %rax,0x10(%rsp)
L25:
  mov    $0x64,%edx
  mov    %rbp,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L27
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L17
  mov    (%rbx),%rdi
  jmp    L25
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
L34:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    $0x1,%eax
  jmp    L34
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D28
data_type: string

tool: D23: the

tool: D16: and

tool: D28: a

assistant: ```c
int is_stop_word(char *word) {
  char *stop_words[] = {"the", "and", "a"};
  int stop_words_len = sizeof(stop_words) / sizeof(char *);
  int i;
  for (i = 0; i < stop_words_len; i++) {
    if (strncmp(stop_words[i], word, 100) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_stop_word>:
  endbr64
  push   %r12
  lea    D28(%rip),%rcx
  push   %rbp
  movq   %rcx,%xmm0
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D6(%rip),%rax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  movq   %rax,%xmm1
  lea    D25(%rip),%rax
  mov    %rax,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
L14:
  mov    (%rbx),%rdi
  mov    $0x64,%edx
  mov    %rbp,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L17
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L14
  xor    %eax,%eax
L28:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%eax
  jmp    L28
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
datatype: string
name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D25
datatype: string

tool: D28: the

tool: D6: and

tool: D25: a

assistant: ```c
int is_stop_word(char *word) {
  char *stop_words[] = {"the", "and", "a"};
  int stop_words_len = sizeof(stop_words) / sizeof(char *);
  int i;
  for (i = 0; i < stop_words_len; i++) {
    if (strncmp(stop_words[i], word, 100) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_group>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  je     L24
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
L24:
  mov    $0x0,%eax
  jmp    L51
L4:
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x10(%rbp),%rax
  mov    %eax,%edi
  call   <getgrgid@plt>
  jmp    L51
L46:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getgrnam@plt>
L51:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
const struct group *find_group(const char *input) {
  if (!input || !input[0])
    return NULL;
  char *endptr;
  long int i = strtol(input, &endptr, 10);
  if (*endptr == '\0') {
    return getgrgid((gid_t)i);
  } else {
    return getgrnam(input);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_group>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L13
  cmpb   $0x0,(%rdi)
  je     L35
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L0
  mov    %eax,%edi
  call   <getgrgid@plt>
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  mov    %rbx,%rdi
  call   <getgrnam@plt>
  jmp    L35
L13:
  mov    %rdi,%rax
  jmp    L35
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const struct group *find_group(const char *input) {
  if (!input || !input[0])
    return NULL;
  char *endptr;
  long int i = strtol(input, &endptr, 10);
  if (*endptr == '\0') {
    return getgrgid((gid_t)i);
  } else {
    return getgrnam(input);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_group>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L33
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L11
  mov    $0xa,%edx
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L0
  mov    %eax,%edi
  call   <getgrgid@plt>
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  mov    %rbp,%rdi
  call   <getgrnam@plt>
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  jmp    L11
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const struct group *find_group(const char *input) {
  if (!input || !input[0])
    return NULL;
  char *endptr;
  long int i = strtol(input, &endptr, 10);
  if (*endptr == '\0') {
    return getgrgid((gid_t)i);
  } else {
    return getgrnam(input);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_group>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L16
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L48
  mov    $0xa,%edx
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L10
  mov    %eax,%edi
  call   <getgrgid@plt>
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  mov    %rbp,%rdi
  call   <getgrnam@plt>
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  jmp    L48
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const struct group *find_group(const char *input) {
  if (!input || !input[0])
    return NULL;
  char *endptr;
  long int i = strtol(input, &endptr, 10);
  if (*endptr == '\0') {
    return getgrgid((gid_t)i);
  } else {
    return getgrnam(input);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: %d 

assistant: ```c
void printArray(int *arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L15
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D2(%rip),%rbp
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L7
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: %d 

assistant: ```c
void printArray(int *arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: %d 

assistant: ```c
void printArray(int *arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: %d 

assistant: ```c
void printArray(int *arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__jiffies_to_tv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  imul   $0x2710,%rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movabs $0x431bde82d7b634db,%rdx
  mul    %rdx
  shr    $0x12,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  imul   $0xf4240,%rax,%rcx
  mov    -0x8(%rbp),%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __jiffies_to_tv(struct timeval *tv, unsigned long jiffies) {
  unsigned long long tvusec;
  tvusec = 10000ULL * jiffies;
  tv->tv_sec = tvusec / 1000000;
  tv->tv_usec = tvusec - 1000000 * tv->tv_sec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__jiffies_to_tv>:
  endbr64
  imul   $0x2710,%rsi,%rsi
  movabs $0x431bde82d7b634db,%rdx
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x12,%rdx
  mov    %rdx,(%rdi)
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x8(%rdi)
  ret
```

assistant: ```c
void __jiffies_to_tv(struct timeval *tv, unsigned long jiffies) {
  unsigned long long tvusec;
  tvusec = 10000ULL * jiffies;
  tv->tv_sec = tvusec / 1000000;
  tv->tv_usec = tvusec - 1000000 * tv->tv_sec;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__jiffies_to_tv>:
  endbr64
  imul   $0x2710,%rsi,%rsi
  movabs $0x431bde82d7b634db,%rdx
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x12,%rdx
  mov    %rdx,(%rdi)
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x8(%rdi)
  ret
```

assistant: ```c
void __jiffies_to_tv(struct timeval *tv, unsigned long jiffies) {
  unsigned long long tvusec;
  tvusec = 10000ULL * jiffies;
  tv->tv_sec = tvusec / 1000000;
  tv->tv_usec = tvusec - 1000000 * tv->tv_sec;
}
```
user: What is the c source code of the assembly code below?

```asm
<__jiffies_to_tv>:
  endbr64
  imul   $0x2710,%rsi,%rsi
  movabs $0x431bde82d7b634db,%rdx
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x12,%rdx
  imul   $0xf4240,%rdx,%rax
  movq   %rdx,%xmm0
  sub    %rax,%rsi
  movq   %rsi,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void __jiffies_to_tv(struct timeval *tv, unsigned long jiffies) {
  unsigned long long tvusec;
  tvusec = 10000ULL * jiffies;
  tv->tv_sec = tvusec / 1000000;
  tv->tv_usec = tvusec - 1000000 * tv->tv_sec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x3,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  jmp    L10
L48:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  jge    L21
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L22
L21:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L22:
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L48
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D29
type_guessed: string
name: parse_data
arguments: label: D22
type_guessed: string
name: parse_data
arguments: label: D4
type_guessed: string

tool: D29: %d%d%d

tool: D22: %d

tool: D4: %d + %d = %d

assistant: ```c
int main() {
  int m, n, a, b, N, i;
  scanf("%d%d%d", &N, &m, &n);
  i = 3, b = n;
  for (i = 3; i <= N; i++) {
    scanf("%d", &a);
    if ((m + n) < (a + b)) {
      m = b, n = a, b = a;
    } else
      b = a;
  }
  printf("%d + %d = %d", m, n, m + n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  cmpl   $0x2,0x14(%rsp)
  jle    L32
  mov    $0x3,%ebp
  lea    D23(%rip),%r12
  jmp    L3
L23:
  add    $0x1,%ebp
  cmp    %ebp,0x14(%rsp)
  jl     L32
L3:
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %ebx,%edx
  mov    0x10(%rsp),%ebx
  mov    0xc(%rsp),%eax
  add    0x8(%rsp),%eax
  lea    (%rbx,%rdx,1),%ecx
  cmp    %ecx,%eax
  jge    L23
  mov    %edx,0x8(%rsp)
  mov    %ebx,0xc(%rsp)
  jmp    L23
L32:
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  lea    (%rsi,%rdx,1),%ecx
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D11
datatype: string
name: parse_data
arguments: label: D23
datatype: string
name: parse_data
arguments: label: D10
datatype: string

tool: D11: %d%d%d

tool: D23: %d

tool: D10: %d + %d = %d

assistant: ```c
int main() {
  int m, n, a, b, N, i;
  scanf("%d%d%d", &N, &m, &n);
  i = 3, b = n;
  for (i = 3; i <= N; i++) {
    scanf("%d", &a);
    if ((m + n) < (a + b)) {
      m = b, n = a, b = a;
    } else
      b = a;
  }
  printf("%d + %d = %d", m, n, m + n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D20(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x2,0x14(%rsp)
  mov    0xc(%rsp),%ebx
  jle    L47
  mov    $0x3,%ebp
  lea    0x10(%rsp),%r13
  lea    D11(%rip),%r12
  nopl   (%rax)
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %ebx,%eax
  mov    0x10(%rsp),%ebx
  mov    0xc(%rsp),%edx
  add    0x8(%rsp),%edx
  lea    (%rbx,%rax,1),%ecx
  cmp    %ecx,%edx
  jge    L35
  mov    %eax,0x8(%rsp)
  mov    %ebx,0xc(%rsp)
L35:
  add    $0x1,%ebp
  cmp    %ebp,0x14(%rsp)
  jge    L8
  mov    0xc(%rsp),%edx
L19:
  mov    0x8(%rsp),%esi
  lea    D8(%rip),%rdi
  lea    (%rsi,%rdx,1),%ecx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  mov    %ebx,%edx
  jmp    L19
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D20
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D20: %d%d%d

tool: D11: %d

tool: D8: %d + %d = %d

assistant: ```c
int main() {
  int m, n, a, b, N, i;
  scanf("%d%d%d", &N, &m, &n);
  i = 3, b = n;
  for (i = 3; i <= N; i++) {
    scanf("%d", &a);
    if ((m + n) < (a + b)) {
      m = b, n = a, b = a;
    } else
      b = a;
  }
  printf("%d + %d = %d", m, n, m + n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x2,0x14(%rsp)
  mov    0xc(%rsp),%ebp
  jle    L70
  mov    $0x3,%ebx
  lea    0x10(%rsp),%r13
  lea    D21(%rip),%r12
  nopl   0x0(%rax)
L40:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  lea    (%rsi,%rdx,1),%ecx
  lea    (%rax,%rbp,1),%edi
  cmp    %edi,%ecx
  jge    L57
  mov    %ebp,0x8(%rsp)
  add    $0x1,%ebx
  mov    %eax,0xc(%rsp)
  cmp    0x14(%rsp),%ebx
  jg     L59
L73:
  mov    %eax,%ebp
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L57:
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jge    L73
L47:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  mov    %edi,%ecx
  mov    %eax,%edx
  mov    %ebp,%esi
  jmp    L47
L70:
  mov    0x8(%rsp),%esi
  mov    %ebp,%edx
  lea    0x0(%rbp,%rsi,1),%ecx
  jmp    L47
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D21
type_guessed: string
name: disassemble_data
arguments: data_label: D29
type_guessed: string

tool: D18: %d%d%d

tool: D21: %d

tool: D29: %d + %d = %d

assistant: ```c
int main() {
  int m, n, a, b, N, i;
  scanf("%d%d%d", &N, &m, &n);
  i = 3, b = n;
  for (i = 3; i <= N; i++) {
    scanf("%d", &a);
    if ((m + n) < (a + b)) {
      m = b, n = a, b = a;
    } else
      b = a;
  }
  printf("%d + %d = %d", m, n, m + n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Vector_Dot_Product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x2,-0x4(%rbp)
  jle    L4
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float Vector_Dot_Product(float vector1[3], float vector2[3]) {
  float op = 0;
  for (int c = 0; c < 3; c++) {
    op += vector1[c] * vector2[c];
  }
  return op;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Vector_Dot_Product>:
  endbr64
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L0:
  movss  (%rdi,%rax,1),%xmm0
  mulss  (%rsi,%rax,1),%xmm0
  addss  %xmm0,%xmm1
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L0
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float Vector_Dot_Product(float vector1[3], float vector2[3]) {
  float op = 0;
  for (int c = 0; c < 3; c++) {
    op += vector1[c] * vector2[c];
  }
  return op;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Vector_Dot_Product>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
L9:
  movss  (%rdi,%rax,1),%xmm0
  mulss  (%rsi,%rax,1),%xmm0
  add    $0x4,%rax
  addss  %xmm0,%xmm1
  cmp    $0xc,%rax
  jne    L9
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float Vector_Dot_Product(float vector1[3], float vector2[3]) {
  float op = 0;
  for (int c = 0; c < 3; c++) {
    op += vector1[c] * vector2[c];
  }
  return op;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Vector_Dot_Product>:
  endbr64
  movq   (%rsi),%xmm1
  movq   (%rdi),%xmm0
  mulps  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  addss  %xmm0,%xmm1
  shufps $0xe5,%xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  0x8(%rsi),%xmm0
  mulss  0x8(%rdi),%xmm0
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float Vector_Dot_Product(float vector1[3], float vector2[3]) {
  float op = 0;
  for (int c = 0; c < 3; c++) {
    op += vector1[c] * vector2[c];
  }
  return op;
}
```