ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_vendor>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  sub    $0x30,%rsp
  lea    0x14(%rsp),%r8
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <cpuid@plt>
  movd   0x14(%rsp),%xmm1
  movd   0xc(%rsp),%xmm0
  lea    0x18(%rsp),%rbp
  mov    0x10(%rsp),%eax
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x24(%rsp)
  punpckldq %xmm1,%xmm0
  mov    %eax,0x20(%rsp)
  movq   %xmm0,0x18(%rsp)
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L33
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x2,%eax
  test   %r8d,%r8d
  je     L33
  mov    0x8(%rsp),%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L33
  xor    %eax,%eax
  and    $0x5,%dh
  setne  %al
L33:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x30,%rsp
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
type: string
name: parse_data
arguments: data_tag: D13
type: string

tool: D16: GenuineIntel

tool: D13: AuthenticAMD

assistant: ```c
int get_vendor(void) {
  int eax, ebx, ecx, edx;
  char vendor[13];
  cpuid(0, &eax, &ebx, &ecx, &edx);
  *(int *)(&vendor[0]) = ebx;
  *(int *)(&vendor[4]) = edx;
  *(int *)(&vendor[8]) = ecx;
  vendor[12] = (char)0;
  if (!strcmp(vendor, "GenuineIntel"))
    return 1;
  if (!strcmp(vendor, "AuthenticAMD"))
    return 2;
  if ((eax == 0) || ((eax & 0x500) != 0))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cil_keeperWriter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <__startrek_entry_pt_Writer@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cil_keeperWriter(void) {
  {
    __startrek_entry_pt_Writer();
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cil_keeperWriter>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__startrek_entry_pt_Writer@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cil_keeperWriter(void) {
  {
    __startrek_entry_pt_Writer();
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cil_keeperWriter>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <__startrek_entry_pt_Writer@plt>
```

assistant: ```c
void cil_keeperWriter(void) {
  {
    __startrek_entry_pt_Writer();
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cil_keeperWriter>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <__startrek_entry_pt_Writer@plt>
```

assistant: ```c
void cil_keeperWriter(void) {
  {
    __startrek_entry_pt_Writer();
    return;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfbc(%rbp)
  jmp    L6
L63:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xfc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfc0(%rbp),%eax
  cmp    $0x2a,%eax
  je     L104
  mov    -0xfc0(%rbp),%edx
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfbc(%rbp)
L6:
  cmpl   $0x3e7,-0xfbc(%rbp)
  jle    L63
  jmp    L93
L104:
  nop
L93:
  movl   $0x0,-0xfb8(%rbp)
  jmp    L54
L96:
  movl   $0x0,-0xfb4(%rbp)
  jmp    L50
L106:
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfb4(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L3
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,-0xfc0(%rbp)
  mov    -0xfb4(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  mov    -0xfb4(%rbp),%eax
  add    $0x1,%eax
  mov    -0xfc0(%rbp),%edx
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
L3:
  addl   $0x1,-0xfb4(%rbp)
L50:
  mov    -0xfbc(%rbp),%eax
  sub    -0xfb8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xfb4(%rbp)
  jl     L106
  addl   $0x1,-0xfb8(%rbp)
L54:
  mov    -0xfbc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xfb8(%rbp)
  jl     L96
  movl   $0x0,-0xfb8(%rbp)
  jmp    L56
L99:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xfb8(%rbp)
L56:
  mov    -0xfb8(%rbp),%eax
  cmp    -0xfbc(%rbp),%eax
  jl     L99
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
data_type: string
name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D21: Input number: 

tool: D13: %d

tool: D2: %d


assistant: ```c
void main() {
  int numbers[1000], temp, amountOfNumbers, i, l;
  for (amountOfNumbers = 0; amountOfNumbers < 1000; amountOfNumbers++) {
    printf("Input number: ");
    scanf("%d", &temp);
    if (temp == 42)
      break;
    numbers[amountOfNumbers] = temp;
  }
  for (i = 0; i < (amountOfNumbers - 1); i++) {
    for (l = 0; l < amountOfNumbers - i - 1; l++) {
      if (numbers[l] > numbers[l + 1]) {
        temp = numbers[l];
        numbers[l] = numbers[l + 1];
        numbers[l + 1] = temp;
      }
    }
  }
  for (i = 0; i < amountOfNumbers; i++)
    printf("%d\n", numbers[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfc8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D20(%rip),%r15
  lea    0x1c(%rsp),%r14
  lea    D21(%rip),%r13
L17:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  cmp    $0x2a,%eax
  je     L120
  mov    %eax,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x3e8,%ebx
  jne    L17
  mov    $0x3e7,%edi
  jmp    L91
L120:
  lea    -0x1(%rbx),%edi
  test   %edi,%edi
  jle    L30
L91:
  mov    $0x0,%r8d
  lea    0x4(%r12),%r10
  mov    $0x1,%r9d
  jmp    L107
L36:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L45
L99:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L36
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  mov    %edx,0xc(%rsp)
  mov    %r9d,%r8d
  jmp    L36
L45:
  sub    $0x1,%edi
  je     L60
L107:
  test   %edi,%edi
  jle    L45
  lea    -0x1(%rdi),%eax
  lea    (%r10,%rax,4),%rsi
  mov    %r12,%rax
  jmp    L99
L60:
  test   %r8b,%r8b
  je     L30
  mov    0xc(%rsp),%eax
  mov    %eax,0x1c(%rsp)
L30:
  test   %ebx,%ebx
  jle    L70
  lea    -0x1(%rbx),%eax
  lea    0x4(%r12,%rax,4),%rbp
  lea    D7(%rip),%rbx
L11:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L11
L70:
  mov    0xfc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  add    $0xfd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D20
type: string
name: disassemble_data
arguments: label: D21
type: string
name: disassemble_data
arguments: label: D7
type: string

tool: D20: Input number: 

tool: D21: %d

tool: D7: %d


assistant: ```c
void main() {
  int numbers[1000], temp, amountOfNumbers, i, l;
  for (amountOfNumbers = 0; amountOfNumbers < 1000; amountOfNumbers++) {
    printf("Input number: ");
    scanf("%d", &temp);
    if (temp == 42)
      break;
    numbers[amountOfNumbers] = temp;
  }
  for (i = 0; i < (amountOfNumbers - 1); i++) {
    for (l = 0; l < amountOfNumbers - i - 1; l++) {
      if (numbers[l] > numbers[l + 1]) {
        temp = numbers[l];
        numbers[l] = numbers[l + 1];
        numbers[l + 1] = temp;
      }
    }
  }
  for (i = 0; i < amountOfNumbers; i++)
    printf("%d\n", numbers[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  jmp    L31
  nop
L22:
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x3e8,%rbx
  je     L2
L31:
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x2a,%eax
  jne    L22
  lea    -0x1(%rbx),%r9d
  mov    %r9d,%r10d
  test   %r9d,%r9d
  jle    L79
L80:
  xor    %r8d,%r8d
  lea    -0x2(%rbp),%ebx
  lea    0x14(%rsp),%r11
  xor    %edi,%edi
  xchg   %ax,%ax
L105:
  mov    %r9d,%eax
  sub    %edi,%eax
  test   %eax,%eax
  jle    L20
  mov    %ebx,%edx
  lea    0x10(%rsp),%rax
  sub    %edi,%edx
  lea    (%r11,%rdx,4),%rsi
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L117
  mov    %ecx,(%rax)
  mov    %edx,%r15d
  mov    $0x1,%r8d
  mov    %edx,0x4(%rax)
L117:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L38
L20:
  add    $0x1,%edi
  cmp    %edi,%r10d
  jg     L105
  test   %r8b,%r8b
  je     L79
  mov    %r15d,0xc(%rsp)
L79:
  test   %ebp,%ebp
  je     L35
  lea    0x10(%rsp),%rbx
  lea    0x14(%rsp,%r9,4),%r12
  lea    D26(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L62:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L62
L35:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  mov    $0x3e7,%r10d
  mov    $0x3e8,%ebp
  mov    $0x3e7,%r9d
  jmp    L80
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D26
type_guessed: string

tool: D14: Input number: 

tool: D27: %d

tool: D26: %d


assistant: ```c
void main() {
  int numbers[1000], temp, amountOfNumbers, i, l;
  for (amountOfNumbers = 0; amountOfNumbers < 1000; amountOfNumbers++) {
    printf("Input number: ");
    scanf("%d", &temp);
    if (temp == 42)
      break;
    numbers[amountOfNumbers] = temp;
  }
  for (i = 0; i < (amountOfNumbers - 1); i++) {
    for (l = 0; l < amountOfNumbers - i - 1; l++) {
      if (numbers[l] > numbers[l + 1]) {
        temp = numbers[l];
        numbers[l] = numbers[l + 1];
        numbers[l + 1] = temp;
      }
    }
  }
  for (i = 0; i < amountOfNumbers; i++)
    printf("%d\n", numbers[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D27(%rip),%r14
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  jmp    L18
  nop
L25:
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x3e8,%rbx
  je     L128
L18:
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x2a,%eax
  jne    L25
  lea    -0x1(%rbx),%r9d
  mov    %r9d,%r10d
  test   %r9d,%r9d
  jle    L35
L17:
  xor    %r8d,%r8d
  lea    -0x2(%rbp),%ebx
  lea    0x14(%rsp),%r11
  xor    %edi,%edi
  xchg   %ax,%ax
L68:
  mov    %r9d,%eax
  sub    %edi,%eax
  test   %eax,%eax
  jle    L46
  mov    %ebx,%eax
  lea    0x10(%rsp),%rdx
  sub    %edi,%eax
  lea    (%r11,%rax,4),%rsi
  cs nopw 0x0(%rax,%rax,1)
L101:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %ecx,%eax
  jge    L87
  movq   %xmm1,(%rdx)
  movd   %xmm0,%r15d
  mov    $0x1,%r8d
L87:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L101
L46:
  add    $0x1,%edi
  cmp    %edi,%r10d
  jg     L68
  test   %r8b,%r8b
  je     L35
  mov    %r15d,0xc(%rsp)
L35:
  test   %ebp,%ebp
  je     L48
  lea    0x10(%rsp),%rbx
  lea    0x14(%rsp,%r9,4),%r12
  lea    D23(%rip),%rbp
  nopl   0x0(%rax)
L31:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L31
L48:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L128:
  mov    $0x3e7,%r10d
  mov    $0x3e8,%ebp
  mov    $0x3e7,%r9d
  jmp    L17
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D27
type_infered: string
name: unpack_data
arguments: data_tag: D12
type_infered: string
name: unpack_data
arguments: data_tag: D23
type_infered: string

tool: D27: Input number: 

tool: D12: %d

tool: D23: %d


assistant: ```c
void main() {
  int numbers[1000], temp, amountOfNumbers, i, l;
  for (amountOfNumbers = 0; amountOfNumbers < 1000; amountOfNumbers++) {
    printf("Input number: ");
    scanf("%d", &temp);
    if (temp == 42)
      break;
    numbers[amountOfNumbers] = temp;
  }
  for (i = 0; i < (amountOfNumbers - 1); i++) {
    for (l = 0; l < amountOfNumbers - i - 1; l++) {
      if (numbers[l] > numbers[l + 1]) {
        temp = numbers[l];
        numbers[l] = numbers[l + 1];
        numbers[l + 1] = temp;
      }
    }
  }
  for (i = 0; i < amountOfNumbers; i++)
    printf("%d\n", numbers[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writebits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L17:
  mov    -0x10(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  and    $0x7,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L39
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  jmp    L37
L39:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %edx,(%rax)
L37:
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void writebits(uint8_t *dst, int from, int len, uint16_t data) {
  int bit;
  for (bit = 0; bit < len; bit++) {
    int val = (data & (1 << bit));
    int obyte = (from + bit) >> 3;
    int bitpos = (from + bit) & 0x07;
    if (val)
      dst[obyte] = dst[obyte] | (1 << bitpos);
    else
      dst[obyte] = dst[obyte] & ~(1 << bitpos);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<writebits>:
  endbr64
  test   %edx,%edx
  jle    L23
  push   %rbx
  mov    %esi,%r10d
  mov    %edx,%r9d
  mov    %ecx,%r11d
  mov    $0x0,%eax
  mov    $0x1,%r8d
  jmp    L2
L18:
  movslq %edx,%rdx
  mov    %r8d,%ebx
  mov    %esi,%ecx
  shl    %cl,%ebx
  mov    %ebx,%ecx
  not    %ecx
  and    %ecx,(%rdi,%rdx,4)
L10:
  add    $0x1,%eax
  cmp    %eax,%r9d
  je     L3
L2:
  lea    (%rax,%r10,1),%ecx
  mov    %ecx,%edx
  sar    $0x3,%edx
  mov    %ecx,%esi
  and    $0x7,%esi
  mov    %r8d,%ebx
  mov    %eax,%ecx
  shl    %cl,%ebx
  test   %r11d,%ebx
  je     L18
  movslq %edx,%rdx
  mov    %r8d,%ebx
  mov    %esi,%ecx
  shl    %cl,%ebx
  or     %ebx,(%rdi,%rdx,4)
  jmp    L10
L3:
  pop    %rbx
  ret
L23:
  ret
```

assistant: ```c
void writebits(uint8_t *dst, int from, int len, uint16_t data) {
  int bit;
  for (bit = 0; bit < len; bit++) {
    int val = (data & (1 << bit));
    int obyte = (from + bit) >> 3;
    int bitpos = (from + bit) & 0x07;
    if (val)
      dst[obyte] = dst[obyte] | (1 << bitpos);
    else
      dst[obyte] = dst[obyte] & ~(1 << bitpos);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<writebits>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%edi
  test   %edx,%edx
  jle    L5
  push   %rbx
  mov    %esi,%r9d
  mov    %ecx,%r10d
  xor    %edx,%edx
  mov    $0x1,%esi
  nopl   0x0(%rax,%rax,1)
L4:
  lea    (%rdx,%r9,1),%ecx
  mov    %esi,%ebx
  mov    %ecx,%eax
  and    $0x7,%ecx
  sar    $0x3,%eax
  cltq
  lea    (%r8,%rax,4),%r11
  mov    %esi,%eax
  shl    %cl,%eax
  mov    %edx,%ecx
  shl    %cl,%ebx
  mov    (%r11),%ecx
  or     %eax,%ecx
  not    %eax
  and    (%r11),%eax
  test   %r10d,%ebx
  cmovne %ecx,%eax
  add    $0x1,%edx
  mov    %eax,(%r11)
  cmp    %edx,%edi
  jne    L4
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void writebits(uint8_t *dst, int from, int len, uint16_t data) {
  int bit;
  for (bit = 0; bit < len; bit++) {
    int val = (data & (1 << bit));
    int obyte = (from + bit) >> 3;
    int bitpos = (from + bit) & 0x07;
    if (val)
      dst[obyte] = dst[obyte] | (1 << bitpos);
    else
      dst[obyte] = dst[obyte] & ~(1 << bitpos);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writebits>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%r9d
  mov    %edx,%edi
  mov    %ecx,%r10d
  xor    %eax,%eax
  mov    $0x1,%esi
  test   %edx,%edx
  jle    L23
  push   %r14
  push   %rbx
  nopl   (%rax)
L0:
  lea    (%rax,%r9,1),%ecx
  mov    %esi,%r14d
  mov    %ecx,%edx
  and    $0x7,%ecx
  sar    $0x3,%edx
  movslq %edx,%rdx
  lea    (%r8,%rdx,4),%r11
  mov    %esi,%edx
  shl    %cl,%edx
  mov    %eax,%ecx
  mov    (%r11),%ebx
  shl    %cl,%r14d
  test   %r10d,%r14d
  je     L16
  or     %ebx,%edx
  add    $0x1,%eax
  mov    %edx,(%r11)
  cmp    %edi,%eax
  jne    L0
  pop    %rbx
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  not    %edx
  add    $0x1,%eax
  and    %ebx,%edx
  mov    %edx,(%r11)
  cmp    %eax,%edi
  jne    L0
  pop    %rbx
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  ret
```

assistant: ```c
void writebits(uint8_t *dst, int from, int len, uint16_t data) {
  int bit;
  for (bit = 0; bit < len; bit++) {
    int val = (data & (1 << bit));
    int obyte = (from + bit) >> 3;
    int bitpos = (from + bit) & 0x07;
    if (val)
      dst[obyte] = dst[obyte] | (1 << bitpos);
    else
      dst[obyte] = dst[obyte] & ~(1 << bitpos);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fulltest>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <swap256@plt>
  lea    0x20(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap256@plt>
  mov    %r12,%r8
  mov    %rbp,%rdi
  mov    %rbp,%r9
L43:
  mov    (%r8),%edx
  mov    %edx,%eax
  shl    $0x8,%eax
  movzbl %dh,%ecx
  or     %ecx,%eax
  shl    $0x10,%eax
  mov    %edx,%ecx
  shr    $0x8,%ecx
  and    $0xff00,%ecx
  sar    $0x18,%edx
  or     %ecx,%edx
  or     %edx,%eax
  mov    (%rdi),%ecx
  mov    %ecx,%edx
  shl    $0x8,%edx
  movzbl %ch,%esi
  or     %esi,%edx
  shl    $0x10,%edx
  mov    %ecx,%esi
  shr    $0x8,%esi
  and    $0xff00,%esi
  mov    %ecx,%r10d
  sar    $0x18,%r10d
  or     %r10d,%esi
  or     %esi,%edx
  mov    %edx,(%rdi)
  cmp    %ecx,%eax
  jg     L15
  jl     L11
  add    $0x4,%r8
  add    $0x4,%rdi
  cmp    %r9,%r8
  jne    L43
  mov    $0x1,%eax
L28:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    $0x0,%eax
  jmp    L28
L11:
  mov    $0x1,%eax
  jmp    L28
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fulltest(const unsigned char *hash, const unsigned char *target) {
  unsigned char hash_swap[32], target_swap[32];
  uint32_t *hash32 = (uint32_t *)hash_swap;
  uint32_t *target32 = (uint32_t *)target_swap;
  int i;
  int rc = 1;
  swap256(hash_swap, hash);
  swap256(target_swap, target);
  for (i = 0; i < 32 / 4; i++) {
    uint32_t h32tmp = (((uint32_t)(((((uint16_t)((hash32[i]) & 0xFFFF)) & 0xFF) << 8) | (((uint16_t)((hash32[i]) & 0xFFFF)) >> 8)) << 16) | (uint32_t)(((((uint16_t)((hash32[i]) >> 16)) & 0xFF) << 8) | (((uint16_t)((hash32[i]) >> 16)) >> 8)));
    uint32_t t32tmp = target32[i];
    target32[i] = (((uint32_t)(((((uint16_t)((target32[i]) & 0xFFFF)) & 0xFF) << 8) | (((uint16_t)((target32[i]) & 0xFFFF)) >> 8)) << 16) | (uint32_t)(((((uint16_t)((target32[i]) >> 16)) & 0xFF) << 8) | (((uint16_t)((target32[i]) >> 16)) >> 8)));
    if (h32tmp > t32tmp) {
      rc = 0;
      break;
    }
    if (h32tmp < t32tmp) {
      rc = 1;
      break;
    }
  }
  return (rc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fulltest>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%rbx
  mov    %r12,%rdi
  call   <swap256@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <swap256@plt>
  mov    %r12,%rsi
  mov    %rbx,%rcx
  lea    0x40(%rsp),%r9
  nopl   0x0(%rax,%rax,1)
L42:
  mov    (%rsi),%edx
  movzwl (%rsi),%eax
  mov    %edx,%edi
  rol    $0x8,%ax
  shr    $0x8,%edi
  shl    $0x10,%eax
  and    $0xff00,%edi
  sar    $0x18,%edx
  or     %edi,%eax
  mov    (%rcx),%edi
  or     %edx,%eax
  movzwl (%rcx),%edx
  mov    %edi,%r8d
  rol    $0x8,%dx
  shr    $0x8,%r8d
  and    $0xff00,%r8d
  shl    $0x10,%edx
  or     %r8d,%edx
  mov    %edi,%r8d
  sar    $0x18,%r8d
  or     %r8d,%edx
  mov    %edx,(%rcx)
  cmp    %edi,%eax
  jg     L5
  jl     L10
  add    $0x4,%rcx
  add    $0x4,%rsi
  cmp    %r9,%rcx
  jne    L42
L10:
  mov    $0x1,%eax
L13:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  jmp    L13
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fulltest(const unsigned char *hash, const unsigned char *target) {
  unsigned char hash_swap[32], target_swap[32];
  uint32_t *hash32 = (uint32_t *)hash_swap;
  uint32_t *target32 = (uint32_t *)target_swap;
  int i;
  int rc = 1;
  swap256(hash_swap, hash);
  swap256(target_swap, target);
  for (i = 0; i < 32 / 4; i++) {
    uint32_t h32tmp = (((uint32_t)(((((uint16_t)((hash32[i]) & 0xFFFF)) & 0xFF) << 8) | (((uint16_t)((hash32[i]) & 0xFFFF)) >> 8)) << 16) | (uint32_t)(((((uint16_t)((hash32[i]) >> 16)) & 0xFF) << 8) | (((uint16_t)((hash32[i]) >> 16)) >> 8)));
    uint32_t t32tmp = target32[i];
    target32[i] = (((uint32_t)(((((uint16_t)((target32[i]) & 0xFFFF)) & 0xFF) << 8) | (((uint16_t)((target32[i]) & 0xFFFF)) >> 8)) << 16) | (uint32_t)(((((uint16_t)((target32[i]) >> 16)) & 0xFF) << 8) | (((uint16_t)((target32[i]) >> 16)) >> 8)));
    if (h32tmp > t32tmp) {
      rc = 0;
      break;
    }
    if (h32tmp < t32tmp) {
      rc = 1;
      break;
    }
  }
  return (rc);
}
```