user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L117
L20:
  lea    -0x38(%rbp),%rdi
  lea    -0xa(%rbp),%rax
  lea    0x1(%rax),%r8
  lea    -0x34(%rbp),%rcx
  lea    -0xa(%rbp),%rdx
  lea    -0x3c(%rbp),%rax
  lea    -0x30(%rbp),%rsi
  push   %rsi
  lea    -0xa(%rbp),%rsi
  push   %rsi
  mov    %rdi,%r9
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x10,%rsp
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x2f,%eax
  je     L145
  cmp    $0x2f,%eax
  jg     L63
  cmp    $0x2d,%eax
  je     L4
  cmp    $0x2d,%eax
  jg     L63
  cmp    $0x2a,%eax
  je     L65
  cmp    $0x2b,%eax
  jne    L63
  mov    -0x3c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%ecx
  imul   %eax,%ecx
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%eax
  imul   %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L63
L4:
  mov    -0x3c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  imul   %edx,%eax
  mov    -0x38(%rbp),%ecx
  mov    -0x34(%rbp),%edx
  imul   %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L63
L65:
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L63
L145:
  mov    -0x3c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x1c(%rbp)
  nop
L63:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x3e8,-0x24(%rbp)
  jmp    L30
L116:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L12
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L12
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %eax,-0x14(%rbp)
L12:
  subl   $0x1,-0x24(%rbp)
L30:
  cmpl   $0x0,-0x24(%rbp)
  jg     L116
  mov    -0x14(%rbp),%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L117:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jl     L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D19
datatype: string

tool: D11: %d

tool: D1: %d %c %d %c %d %c %d

tool: D19: %d/%d = %d/%d


assistant: ```c
int main() {
  char a[2];
  int i, j, k, n1, n2, d1, d2;
  int ans[4], loop;
  scanf("%d", &loop);
  for (i = 0; i < loop; i++) {
    scanf("%d %c %d %c %d %c %d", &n1, &a[0], &d1, &a[1], &n2, &a[0], &d2);
    switch (a[1]) {
    case '+':
      ans[0] = (n1 * d2 + n2 * d1);
      ans[1] = (d1 * d2);
      break;
    case '-':
      ans[0] = (n1 * d2 - n2 * d1);
      ans[1] = (d1 * d2);
      break;
    case '*':
      ans[0] = (n1 * n2);
      ans[1] = (d1 * d2);
      break;
    case '/':
      ans[0] = (n1 * d2);
      ans[1] = (n2 * d1);
      break;
    }
    ans[2] = ans[0];
    ans[3] = ans[1];
    for (j = 1000; j > 0; j--) {
      if (ans[2] % j == 0 && ans[3] % j == 0) {
        ans[2] = ans[2] / j;
        ans[3] = ans[3] / j;
      }
    }
    printf("%d/%d = %d/%d\n", ans[0], ans[1], ans[2], ans[3]);
  }
  return 0;
}
```