ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<substitute>:
  endbr64
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x1,%rdi
L28:
  movsbl (%rdi),%eax
  test   %al,%al
  je     L7
L22:
  cmp    %esi,%eax
  jne    L11
  mov    %dl,(%rdi)
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L22
  ret
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void substitute(char *str, int ch1, int ch2) {
  for (; *str; str++) {
    if (*str == ch1)
      *str = ch2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rows_bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%ecx
  mov    %esi,%eax
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,%edx
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L29
  movsbl -0x18(%rbp),%eax
  add    %eax,%eax
  and    $0x1e,%eax
  or     $0x1,%eax
  mov    %al,-0xe(%rbp)
  jmp    L41
L29:
  movzbl -0x18(%rbp),%eax
  sar    %al
  or     $0x10,%eax
  mov    %al,-0xe(%rbp)
L41:
  movzbl -0x14(%rbp),%eax
  not    %eax
  and    -0x18(%rbp),%al
  and    -0xe(%rbp),%al
  mov    %al,-0xd(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L59:
  movsbl -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L96
  cmpl   $0x0,-0x8(%rbp)
  je     L103
  cmpl   $0x0,-0x4(%rbp)
  jne    L77
  mov    $0x1,%eax
  jmp    L63
L77:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L103
L96:
  cmpl   $0x0,-0x8(%rbp)
  jne    L85
  movl   $0x1,-0x8(%rbp)
L85:
  movsbl -0xd(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L103
  movl   $0x1,-0x4(%rbp)
L103:
  addl   $0x1,-0xc(%rbp)
L34:
  cmpl   $0x4,-0xc(%rbp)
  jle    L59
  cmpl   $0x0,-0x8(%rbp)
  je     L25
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L63
L25:
  mov    $0x0,%eax
L63:
  pop    %rbp
  ret
```

assistant: ```c
int rows_bad(char row1, char row2, int even) {
  int i, in_zeroes, group_okay;
  char block, row2_shift;
  if (even)
    row2_shift = ((row2 << 1) & 0x1F) | 0x01;
  else
    row2_shift = (row2 >> 1) | 0x10;
  block = ((row1 ^ row2) & row2) & ((row1 ^ row2_shift) & row2_shift);
  in_zeroes = 0;
  group_okay = 0;
  for (i = 0; i < 5; i++) {
    if (row1 & (1 << i)) {
      if (in_zeroes) {
        if (!group_okay)
          return 1;
        in_zeroes = 0;
        group_okay = 0;
      }
    } else {
      if (!in_zeroes)
        in_zeroes = 1;
      if (!(block & (1 << i)))
        group_okay = 1;
    }
  }
  if (in_zeroes)
    return !group_okay;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rows_bad>:
  endbr64
  mov    %edi,%r8d
  test   %edx,%edx
  je     L16
  lea    (%rsi,%rsi,1),%eax
  and    $0x1e,%eax
  or     $0x1,%eax
L29:
  mov    %edi,%edx
  not    %edx
  and    %esi,%edx
  and    %eax,%edx
  mov    $0x0,%edi
  mov    $0x0,%eax
  mov    $0x0,%ecx
  movsbl %r8b,%esi
  movsbl %dl,%edx
  mov    $0x1,%r8d
  mov    $0x0,%r9d
  jmp    L26
L16:
  mov    %esi,%eax
  sar    %al
  or     $0x10,%eax
  jmp    L29
L22:
  mov    %edx,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  jne    L74
  mov    %r8d,%edi
  mov    %r8d,%eax
L74:
  add    $0x1,%ecx
  cmp    $0x5,%ecx
  je     L51
L26:
  bt     %ecx,%esi
  jae    L22
  test   %eax,%eax
  je     L74
  test   %edi,%edi
  je     L17
  mov    %r9d,%edi
  mov    %r9d,%eax
  jmp    L74
L51:
  xor    $0x1,%edi
  test   %eax,%eax
  cmovne %edi,%eax
L17:
  ret
```

assistant: ```c
int rows_bad(char row1, char row2, int even) {
  int i, in_zeroes, group_okay;
  char block, row2_shift;
  if (even)
    row2_shift = ((row2 << 1) & 0x1F) | 0x01;
  else
    row2_shift = (row2 >> 1) | 0x10;
  block = ((row1 ^ row2) & row2) & ((row1 ^ row2_shift) & row2_shift);
  in_zeroes = 0;
  group_okay = 0;
  for (i = 0; i < 5; i++) {
    if (row1 & (1 << i)) {
      if (in_zeroes) {
        if (!group_okay)
          return 1;
        in_zeroes = 0;
        group_okay = 0;
      }
    } else {
      if (!in_zeroes)
        in_zeroes = 1;
      if (!(block & (1 << i)))
        group_okay = 1;
    }
  }
  if (in_zeroes)
    return !group_okay;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rows_bad>:
  endbr64
  test   %edx,%edx
  je     L24
  lea    (%rsi,%rsi,1),%eax
  and    $0x1e,%eax
  or     $0x1,%eax
L40:
  mov    %edi,%edx
  xor    %ecx,%ecx
  movsbl %dil,%edi
  not    %edx
  and    %esi,%edx
  xor    %esi,%esi
  and    %eax,%edx
  xor    %eax,%eax
  movsbl %dl,%edx
L59:
  bt     %ecx,%edi
  jae    L6
  test   %eax,%eax
  je     L35
  test   %esi,%esi
  je     L1
  xor    %esi,%esi
  xor    %eax,%eax
L35:
  add    $0x1,%ecx
  cmp    $0x5,%ecx
  jne    L59
  xor    $0x1,%esi
  test   %eax,%eax
  cmovne %esi,%eax
L1:
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %edx,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  jne    L35
  mov    $0x1,%esi
  mov    $0x1,%eax
  jmp    L35
  nopl   (%rax)
L24:
  mov    %esi,%eax
  sar    %al
  or     $0x10,%eax
  jmp    L40
```

assistant: ```c
int rows_bad(char row1, char row2, int even) {
  int i, in_zeroes, group_okay;
  char block, row2_shift;
  if (even)
    row2_shift = ((row2 << 1) & 0x1F) | 0x01;
  else
    row2_shift = (row2 >> 1) | 0x10;
  block = ((row1 ^ row2) & row2) & ((row1 ^ row2_shift) & row2_shift);
  in_zeroes = 0;
  group_okay = 0;
  for (i = 0; i < 5; i++) {
    if (row1 & (1 << i)) {
      if (in_zeroes) {
        if (!group_okay)
          return 1;
        in_zeroes = 0;
        group_okay = 0;
      }
    } else {
      if (!in_zeroes)
        in_zeroes = 1;
      if (!(block & (1 << i)))
        group_okay = 1;
    }
  }
  if (in_zeroes)
    return !group_okay;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rows_bad>:
  endbr64
  mov    %esi,%ecx
  test   %edx,%edx
  je     L190
  lea    (%rsi,%rsi,1),%eax
  and    $0x1e,%eax
  or     $0x1,%eax
L21:
  mov    %edi,%esi
  movsbl %dil,%edx
  not    %esi
  and    %ecx,%esi
  and    %eax,%esi
  and    $0x1,%edi
  jne    L183
  test   $0x1,%sil
  jne    L175
  mov    $0x1,%eax
  test   $0x2,%dl
  jne    L154
L84:
  movsbl %sil,%ecx
  test   $0x2,%sil
  jne    L210
  mov    $0x1,%eax
  test   $0x4,%dl
  jne    L170
L129:
  test   $0x4,%cl
  jne    L113
  mov    $0x1,%eax
  test   $0x8,%dl
  jne    L108
L60:
  test   $0x8,%cl
  jne    L144
  xor    %eax,%eax
  and    $0x10,%edx
  je     L44
  ret
  nopl   0x0(%rax)
L190:
  mov    %esi,%eax
  sar    %al
  or     $0x10,%eax
  jmp    L21
  nopl   0x0(%rax)
L175:
  mov    %edx,%eax
  sar    %eax
  and    $0x1,%eax
  je     L84
  ret
  nopw   0x0(%rax,%rax,1)
L183:
  mov    %edx,%eax
  sar    %eax
  and    $0x1,%eax
  je     L84
L154:
  mov    %edx,%eax
  sar    $0x2,%eax
  and    $0x1,%eax
  je     L245
  mov    %edx,%eax
  movsbl %sil,%ecx
  sar    $0x3,%eax
  and    $0x1,%eax
  je     L60
  sar    $0x4,%edx
  movsbl %sil,%ecx
  mov    %edx,%eax
  and    $0x1,%eax
  jne    L35
L189:
  and    $0x10,%ecx
  mov    $0x1,%edx
  cmove  %edx,%eax
  xor    $0x1,%eax
  ret
  xchg   %ax,%ax
L210:
  mov    %edx,%edi
  sar    $0x2,%edi
  and    $0x1,%edi
  je     L129
  test   %eax,%eax
  je     L32
L170:
  mov    %edx,%eax
  sar    $0x3,%eax
  and    $0x1,%eax
  je     L60
  sar    $0x4,%edx
  movsbl %sil,%ecx
  mov    %edx,%eax
  and    $0x1,%eax
  je     L189
  jmp    L35
L113:
  mov    %edx,%esi
  sar    $0x3,%esi
  and    $0x1,%esi
  je     L60
  test   %eax,%eax
  je     L146
L108:
  sar    $0x4,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  je     L189
L35:
  xor    %eax,%eax
  ret
  nop
L245:
  movsbl %sil,%ecx
  jmp    L129
  nopl   0x0(%rax)
L144:
  sar    $0x4,%edx
  and    $0x1,%edx
  je     L189
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  and    $0x10,%ecx
  mov    $0x1,%edx
  mov    $0x1,%eax
  cmove  %edx,%eax
  xor    $0x1,%eax
  ret
L146:
  mov    %esi,%eax
  ret
L32:
  mov    %edi,%eax
  ret
```

assistant: ```c
int rows_bad(char row1, char row2, int even) {
  int i, in_zeroes, group_okay;
  char block, row2_shift;
  if (even)
    row2_shift = ((row2 << 1) & 0x1F) | 0x01;
  else
    row2_shift = (row2 >> 1) | 0x10;
  block = ((row1 ^ row2) & row2) & ((row1 ^ row2_shift) & row2_shift);
  in_zeroes = 0;
  group_okay = 0;
  for (i = 0; i < 5; i++) {
    if (row1 & (1 << i)) {
      if (in_zeroes) {
        if (!group_okay)
          return 1;
        in_zeroes = 0;
        group_okay = 0;
      }
    } else {
      if (!in_zeroes)
        in_zeroes = 1;
      if (!(block & (1 << i)))
        group_okay = 1;
    }
  }
  if (in_zeroes)
    return !group_okay;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<line_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x28(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0xffffffff,%eax
  jmp    L47
L27:
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L54
  mov    $0xfffffffe,%eax
  jmp    L47
L54:
  movl   $0x0,-0x14(%rbp)
  jmp    L52
L38:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L8
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L8:
  addq   $0x1,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L52:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L64
  cmpl   $0x3f,-0x14(%rbp)
  jle    L38
L64:
  mov    $0x0,%eax
L47:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: r

assistant: ```c
int line_from_file(char *filename, char *linebuf) {
  char *s;
  int i;
  memset(linebuf, 0, 64);
  FILE *file = fopen(filename, "r");
  if (!file)
    return -1;
  s = fgets(linebuf, 64, file);
  if (!s)
    return -2;
  for (i = 0; (*s) && (i < 64); i++) {
    if (*s == '\n')
      *s = 0;
    s++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<line_from_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rdx
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L12
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L27
  mov    $0x0,%ecx
  jmp    L26
L79:
  add    $0x1,%rax
  add    $0x1,%ecx
  movzbl (%rax),%edx
  cmp    $0x3f,%ecx
  jg     L30
  test   %dl,%dl
  je     L30
L26:
  cmp    $0xa,%dl
  jne    L79
  movb   $0x0,(%rax)
  jmp    L79
L30:
  mov    $0x0,%eax
L105:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L105
L12:
  mov    $0xfffffffe,%eax
  jmp    L105
L27:
  mov    $0x0,%eax
  jmp    L105
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: r

assistant: ```c
int line_from_file(char *filename, char *linebuf) {
  char *s;
  int i;
  memset(linebuf, 0, 64);
  FILE *file = fopen(filename, "r");
  if (!file)
    return -1;
  s = fgets(linebuf, 64, file);
  if (!s)
    return -2;
  for (i = 0; (*s) && (i < 64); i++) {
    if (*s == '\n')
      *s = 0;
    s++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<line_from_file>:
  endbr64
  push   %r12
  mov    $0x40,%edx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L60
  mov    %rax,%rdx
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L4
  movzbl (%rax),%edx
  xor    %ecx,%ecx
  jmp    L39
L1:
  cmp    $0xa,%dl
  jne    L31
  movb   $0x0,(%rax)
L31:
  add    $0x1,%ecx
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x40,%ecx
  je     L77
L39:
  test   %dl,%dl
  jne    L1
L77:
  xor    %eax,%eax
L37:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L60:
  mov    $0xffffffff,%eax
  jmp    L37
L4:
  mov    $0xfffffffe,%eax
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D5: r

assistant: ```c
int line_from_file(char *filename, char *linebuf) {
  char *s;
  int i;
  memset(linebuf, 0, 64);
  FILE *file = fopen(filename, "r");
  if (!file)
    return -1;
  s = fgets(linebuf, 64, file);
  if (!s)
    return -2;
  for (i = 0; (*s) && (i < 64); i++) {
    if (*s == '\n')
      *s = 0;
    s++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<line_from_file>:
  endbr64
  push   %r12
  mov    $0x40,%edx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  lea    D0(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L77
  mov    %rax,%rdx
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L65
  movzbl (%rax),%edx
  xor    %ecx,%ecx
  jmp    L53
L57:
  add    $0x1,%ecx
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x40,%ecx
  je     L85
L53:
  test   %dl,%dl
  je     L85
L14:
  cmp    $0xa,%dl
  jne    L57
  movb   $0x0,(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  add    $0x1,%ecx
  test   %dl,%dl
  je     L85
  cmp    $0x40,%ecx
  jne    L14
  nop
L85:
  xor    %eax,%eax
L15:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L77:
  mov    $0xffffffff,%eax
  jmp    L15
L65:
  mov    $0xfffffffe,%eax
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D0: r

assistant: ```c
int line_from_file(char *filename, char *linebuf) {
  char *s;
  int i;
  memset(linebuf, 0, 64);
  FILE *file = fopen(filename, "r");
  if (!file)
    return -1;
  s = fgets(linebuf, 64, file);
  if (!s)
    return -2;
  for (i = 0; (*s) && (i < 64); i++) {
    if (*s == '\n')
      *s = 0;
    s++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fib_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L5
  cmpl   $0x1,-0x34(%rbp)
  jne    L20
L5:
  mov    -0x34(%rbp),%eax
  cltq
  jmp    L27
L20:
  cmpl   $0x13,-0x34(%rbp)
  jg     L42
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib_number>
  mov    %rax,%rbx
  mov    -0x34(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib_number>
  add    %rbx,%rax
  jmp    L27
L42:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib_number>
  mov    %rax,-0x28(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib_number>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long fib_number(int n) {
  long fn, fn1, fn2;
  if (n == 0 || n == 1)
    return (n);
  if (n < 20)
    return (fib_number(n - 1) + fib_number(n - 2));
#pragma omp task shared(fn1)
  { fn1 = fib_number(n - 1); }
#pragma omp task shared(fn2)
  { fn2 = fib_number(n - 2); }
#pragma omp taskwait
  fn = fn1 + fn2;
  return (fn);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fib_number>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movslq %edi,%rax
  cmp    $0x1,%edi
  jbe    L7
  cmp    $0x13,%edi
  jle    L21
  lea    -0x1(%rdi),%edi
  call   <fib_number>
  mov    %rax,%rbp
  lea    -0x2(%rbx),%edi
  call   <fib_number>
  add    %rbp,%rax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  lea    -0x1(%rdi),%edi
  call   <fib_number>
  mov    %rax,%rbp
  lea    -0x2(%rbx),%edi
  call   <fib_number>
  add    %rbp,%rax
  jmp    L7
```

assistant: ```c
long fib_number(int n) {
  long fn, fn1, fn2;
  if (n == 0 || n == 1)
    return (n);
  if (n < 20)
    return (fib_number(n - 1) + fib_number(n - 2));
#pragma omp task shared(fn1)
  { fn1 = fib_number(n - 1); }
#pragma omp task shared(fn2)
  { fn2 = fib_number(n - 2); }
#pragma omp taskwait
  fn = fn1 + fn2;
  return (fn);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<XDisplayName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <TEST@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: XDisplayName

assistant: ```c
char *XDisplayName(char *string) {
  TEST("XDisplayName", 0);
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<XDisplayName>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%esi
  lea    D6(%rip),%rdi
  call   <TEST@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: XDisplayName

assistant: ```c
char *XDisplayName(char *string) {
  TEST("XDisplayName", 0);
  return string;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<XDisplayName>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  call   <TEST@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: XDisplayName

assistant: ```c
char *XDisplayName(char *string) {
  TEST("XDisplayName", 0);
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<XDisplayName>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    %rdi,%r12
  lea    D5(%rip),%rdi
  call   <TEST@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D5: XDisplayName

assistant: ```c
char *XDisplayName(char *string) {
  TEST("XDisplayName", 0);
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tavl_assert_insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <tavl_probe@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x20(%rbp)
  jne    L11
  mov    $0x1,%eax
  jmp    L7
L11:
  mov    $0x0,%eax
L7:
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void(tavl_assert_insert)(struct tavl_table *table, void *item) {
  void **p = tavl_probe(table, item);
  assert(p != NULL && *p == item);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tavl_assert_insert>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <tavl_probe@plt>
  mov    $0x0,%edi
  test   %rax,%rax
  je     L1
  cmp    %rbx,(%rax)
  sete   %dil
  movzbl %dil,%edi
L1:
  call   <assert@plt>
  pop    %rbx
  ret
```

assistant: ```c
void(tavl_assert_insert)(struct tavl_table *table, void *item) {
  void **p = tavl_probe(table, item);
  assert(p != NULL && *p == item);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tavl_assert_insert>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <tavl_probe@plt>
  xor    %edi,%edi
  test   %rax,%rax
  je     L3
  xor    %edi,%edi
  cmp    %rbx,(%rax)
  sete   %dil
L3:
  pop    %rbx
  jmp    1060 <assert@plt>
```

assistant: ```c
void(tavl_assert_insert)(struct tavl_table *table, void *item) {
  void **p = tavl_probe(table, item);
  assert(p != NULL && *p == item);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tavl_assert_insert>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <tavl_probe@plt>
  xor    %edi,%edi
  test   %rax,%rax
  je     L6
  xor    %edi,%edi
  cmp    %rbx,(%rax)
  sete   %dil
L6:
  pop    %rbx
  jmp    1060 <assert@plt>
```

assistant: ```c
void(tavl_assert_insert)(struct tavl_table *table, void *item) {
  void **p = tavl_probe(table, item);
  assert(p != NULL && *p == item);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uart_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x20201030,%edi
  call   <mmio_write@plt>
  mov    $0x0,%esi
  mov    $0x20200094,%edi
  call   <mmio_write@plt>
  mov    $0x96,%edi
  call   <RPI_esperarMicroSeconds@plt>
  mov    $0xc000,%esi
  mov    $0x20200098,%edi
  call   <mmio_write@plt>
  mov    $0x96,%edi
  call   <RPI_esperarMicroSeconds@plt>
  mov    $0x0,%esi
  mov    $0x20200098,%edi
  call   <mmio_write@plt>
  mov    $0x7ff,%esi
  mov    $0x20201044,%edi
  call   <mmio_write@plt>
  mov    $0x1,%esi
  mov    $0x20201024,%edi
  call   <mmio_write@plt>
  mov    $0x28,%esi
  mov    $0x20201028,%edi
  call   <mmio_write@plt>
  mov    $0x60,%esi
  mov    $0x2020102c,%edi
  call   <mmio_write@plt>
  mov    $0x10,%esi
  mov    $0x20201038,%edi
  call   <mmio_write@plt>
  mov    $0x301,%esi
  mov    $0x20201030,%edi
  call   <mmio_write@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uart_init() {
  mmio_write((0x20201000 + 0x30), 0x00000000);
  mmio_write((0x20200000 + 0x94), 0x00000000);
  RPI_esperarMicroSeconds(150);
  mmio_write((0x20200000 + 0x98), (1 << 14) | (1 << 15));
  RPI_esperarMicroSeconds(150);
  mmio_write((0x20200000 + 0x98), 0x00000000);
  mmio_write((0x20201000 + 0x44), 0x7FF);
  mmio_write((0x20201000 + 0x24), 1);
  mmio_write((0x20201000 + 0x28), 40);
  mmio_write((0x20201000 + 0x2C), (3 << 5) | (1 << 6));
  mmio_write((0x20201000 + 0x38), 0x0010);
  mmio_write((0x20201000 + 0x30), (1 << 0) | (1 << 8) | (1 << 9));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uart_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x20201030,%edi
  call   <mmio_write@plt>
  mov    $0x0,%esi
  mov    $0x20200094,%edi
  call   <mmio_write@plt>
  mov    $0x96,%edi
  call   <RPI_esperarMicroSeconds@plt>
  mov    $0xc000,%esi
  mov    $0x20200098,%edi
  call   <mmio_write@plt>
  mov    $0x96,%edi
  call   <RPI_esperarMicroSeconds@plt>
  mov    $0x0,%esi
  mov    $0x20200098,%edi
  call   <mmio_write@plt>
  mov    $0x7ff,%esi
  mov    $0x20201044,%edi
  call   <mmio_write@plt>
  mov    $0x1,%esi
  mov    $0x20201024,%edi
  call   <mmio_write@plt>
  mov    $0x28,%esi
  mov    $0x20201028,%edi
  call   <mmio_write@plt>
  mov    $0x60,%esi
  mov    $0x2020102c,%edi
  call   <mmio_write@plt>
  mov    $0x10,%esi
  mov    $0x20201038,%edi
  call   <mmio_write@plt>
  mov    $0x301,%esi
  mov    $0x20201030,%edi
  call   <mmio_write@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uart_init() {
  mmio_write((0x20201000 + 0x30), 0x00000000);
  mmio_write((0x20200000 + 0x94), 0x00000000);
  RPI_esperarMicroSeconds(150);
  mmio_write((0x20200000 + 0x98), (1 << 14) | (1 << 15));
  RPI_esperarMicroSeconds(150);
  mmio_write((0x20200000 + 0x98), 0x00000000);
  mmio_write((0x20201000 + 0x44), 0x7FF);
  mmio_write((0x20201000 + 0x24), 1);
  mmio_write((0x20201000 + 0x28), 40);
  mmio_write((0x20201000 + 0x2C), (3 << 5) | (1 << 6));
  mmio_write((0x20201000 + 0x38), 0x0010);
  mmio_write((0x20201000 + 0x30), (1 << 0) | (1 << 8) | (1 << 9));
}
```