ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L24
  mov    $0x1,%r13d
  lea    0xc(%rsp),%r15
  lea    D14(%rip),%r12
  lea    D3(%rip),%r14
L16:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L13
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
L30:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L30
L13:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    0x10(%rsp,%rax,4),%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  cmp    %r13d,0x8(%rsp)
  jge    L16
L24:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
data_type: string
name: parse_data
arguments: data_label: D3
data_type: string

tool: D14: %d

tool: D3: Case %d: %d


assistant: ```c
int main() {
  int t, n, a[15], i, c, j;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d", &n);
    for (j = 0; j < n; j++)
      scanf("%d", &a[j]);
    c = a[n / 2];
    printf("Case %d: %d\n", i, c);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L25
  mov    $0x1,%r13d
  lea    0xc(%rsp),%r15
  lea    D8(%rip),%r14
L13:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L7
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L20
L7:
  mov    %eax,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  add    $0x1,%r13d
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    0x10(%rsp,%rax,4),%edx
  call   <printf@plt>
  cmp    %r13d,0x8(%rsp)
  jge    L13
L25:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string

tool: D5: %d

tool: D8: Case %d: %d


assistant: ```c
int main() {
  int t, n, a[15], i, c, j;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d", &n);
    for (j = 0; j < n; j++)
      scanf("%d", &a[j]);
    c = a[n / 2];
    printf("Case %d: %d\n", i, c);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L6
  mov    $0x1,%r13d
  lea    0xc(%rsp),%r15
  lea    D6(%rip),%r14
L26:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L19
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L48
L19:
  mov    %eax,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  add    $0x1,%r13d
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    0x10(%rsp,%rax,4),%edx
  call   <printf@plt>
  cmp    %r13d,0x8(%rsp)
  jge    L26
L6:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D0: %d

tool: D6: Case %d: %d


assistant: ```c
int main() {
  int t, n, a[15], i, c, j;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d", &n);
    for (j = 0; j < n; j++)
      scanf("%d", &a[j]);
    c = a[n / 2];
    printf("Case %d: %d\n", i, c);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GCD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L2
  mov    -0x8(%rbp),%eax
  jmp    L17
L2:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <GCD>
L17:
  leave
  ret
```

assistant: ```c
int GCD(int x, int y) {
  if (x % y == 0)
    return y;
  return GCD(y, x % y);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GCD>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L3
  mov    %esi,%eax
  ret
L3:
  sub    $0x8,%rsp
  mov    %edx,%esi
  call   <GCD>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int GCD(int x, int y) {
  if (x % y == 0)
    return y;
  return GCD(y, x % y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GCD>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L3
  ret
```

assistant: ```c
int GCD(int x, int y) {
  if (x % y == 0)
    return y;
  return GCD(y, x % y);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<GCD>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L2
  ret
```

assistant: ```c
int GCD(int x, int y) {
  if (x % y == 0)
    return y;
  return GCD(y, x % y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xc,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: Hello world


assistant: ```c
int main(void) {
  write(1, "Hello world\n", 12);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edx
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: Hello world


assistant: ```c
int main(void) {
  write(1, "Hello world\n", 12);
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edx
  mov    $0x1,%edi
  lea    D0(%rip),%rsi
  call   <write@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: Hello world


assistant: ```c
int main(void) {
  write(1, "Hello world\n", 12);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edx
  mov    $0x1,%edi
  lea    D7(%rip),%rsi
  call   <write@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: Hello world


assistant: ```c
int main(void) {
  write(1, "Hello world\n", 12);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cipxfaddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cipxfaddr(int unit) {
  int result = 1;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cipxfaddr>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cipxfaddr(int unit) {
  int result = 1;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cipxfaddr>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cipxfaddr(int unit) {
  int result = 1;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <inputMat@plt>
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <inputMat@plt>
  lea    -0x30(%rbp),%rdx
  lea    -0x60(%rbp),%rcx
  lea    -0x90(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <addMat@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <printMat@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string
name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D9
data_type: string

tool: D8: Enter The Value of Matrix A (%dx%d) 


tool: D12: Enter The Value of Matrix B (%dx%d) 


tool: D9: ANS: 

assistant: ```c
int main() {
  int i, j;
  int matA[3][3], matB[3][3], matC[3][3];
  printf("Enter The Value of Matrix A (%dx%d) \n", 3, 3);
  inputMat(matA);
  printf("Enter The Value of Matrix B (%dx%d) \n", 3, 3);
  inputMat(matB);
  addMat(matA, matB, matC);
  printf("ANS: \n");
  printMat(matC);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <inputMat@plt>
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x30(%rsp),%r12
  mov    %r12,%rdi
  call   <inputMat@plt>
  lea    0x60(%rsp),%rbx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <addMat@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <printMat@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D24
type: string
name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D9
type: string

tool: D24: Enter The Value of Matrix A (%dx%d) 


tool: D1: Enter The Value of Matrix B (%dx%d) 


tool: D9: ANS: 

assistant: ```c
int main() {
  int i, j;
  int matA[3][3], matB[3][3], matC[3][3];
  printf("Enter The Value of Matrix A (%dx%d) \n", 3, 3);
  inputMat(matA);
  printf("Enter The Value of Matrix B (%dx%d) \n", 3, 3);
  inputMat(matB);
  addMat(matA, matB, matC);
  printf("ANS: \n");
  printMat(matC);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D22(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x30(%rsp),%r13
  lea    0x60(%rsp),%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <inputMat@plt>
  mov    $0x3,%edx
  mov    $0x3,%esi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <inputMat@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <addMat@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <printMat@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D22
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D28
type_infered: string

tool: D22: Enter The Value of Matrix A (%dx%d) 


tool: D19: Enter The Value of Matrix B (%dx%d) 


tool: D28: ANS: 

assistant: ```c
int main() {
  int i, j;
  int matA[3][3], matB[3][3], matC[3][3];
  printf("Enter The Value of Matrix A (%dx%d) \n", 3, 3);
  inputMat(matA);
  printf("Enter The Value of Matrix B (%dx%d) \n", 3, 3);
  inputMat(matB);
  addMat(matA, matB, matC);
  printf("ANS: \n");
  printMat(matC);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D29(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x30(%rsp),%r13
  lea    0x60(%rsp),%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <inputMat@plt>
  mov    $0x3,%edx
  mov    $0x3,%esi
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <inputMat@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <addMat@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <printMat@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
type: string
name: extract_symbolic_data
arguments: label: D5
type: string
name: extract_symbolic_data
arguments: label: D23
type: string

tool: D29: Enter The Value of Matrix A (%dx%d) 


tool: D5: Enter The Value of Matrix B (%dx%d) 


tool: D23: ANS: 

assistant: ```c
int main() {
  int i, j;
  int matA[3][3], matB[3][3], matC[3][3];
  printf("Enter The Value of Matrix A (%dx%d) \n", 3, 3);
  inputMat(matA);
  printf("Enter The Value of Matrix B (%dx%d) \n", 3, 3);
  inputMat(matB);
  addMat(matA, matB, matC);
  printf("ANS: \n");
  printMat(matC);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gmx_potential@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_potential(argc, argv);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_potential@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_potential(argc, argv);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_potential@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_potential(argc, argv);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_potential@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_potential(argc, argv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<handle_openat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <get_syscall_params@plt>
  mov    %rax,-0x78(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x70(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  movslq %ecx,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  movslq %ecx,%rax
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  mov    %rsp,%rdx
  sub    %rsi,%rdx
L10:
  cmp    %rdx,%rsp
  je     L34
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L10
L34:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L14
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L14:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x58(%rbp),%rax
  mov    -0x68(%rbp),%rsi
  mov    %ecx,%edx
  mov    %rax,%rdi
  call   <get_syscall_str@plt>
  mov    -0x68(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <handle_open_common@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void handle_openat() {
  long params[4];
  long rc = get_syscall_params(4, params);
  char path[PATH_MAX];
  get_syscall_str(params[1], path, sizeof(path));
  handle_open_common(rc, path);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<handle_openat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rsi
  mov    $0x4,%edi
  call   <get_syscall_params@plt>
  mov    %rax,%rbx
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  movslq %edx,%rax
  add    $0xf,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L30:
  cmp    %rcx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L30
L21:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L19
  orq    $0x0,-0x8(%rsp,%rax,1)
L19:
  mov    %rsp,%rsi
  mov    -0x38(%rbp),%rdi
  call   <get_syscall_str@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <handle_open_common@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    -0x8(%rbp),%rbx
  leave
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handle_openat() {
  long params[4];
  long rc = get_syscall_params(4, params);
  char path[PATH_MAX];
  get_syscall_str(params[1], path, sizeof(path));
  handle_open_common(rc, path);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<handle_openat>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r12
  lea    -0x40(%rbp),%rsi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <get_syscall_params@plt>
  mov    %rsp,%rcx
  mov    %rax,%r12
  mov    D3(%rip),%rax
  movslq (%rax),%rdx
  mov    %rdx,%r8
  add    $0xf,%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L33
L39:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L39
L33:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L26
L28:
  mov    -0x38(%rbp),%rdi
  mov    %rsp,%rsi
  mov    %r8d,%edx
  call   <get_syscall_str@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <handle_open_common@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax)
L26:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L28
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handle_openat() {
  long params[4];
  long rc = get_syscall_params(4, params);
  char path[PATH_MAX];
  get_syscall_str(params[1], path, sizeof(path));
  handle_open_common(rc, path);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<handle_openat>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r12
  lea    -0x40(%rbp),%rsi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <get_syscall_params@plt>
  mov    %rsp,%rcx
  mov    %rax,%r12
  mov    D5(%rip),%rax
  movslq (%rax),%rdx
  mov    %rdx,%r8
  add    $0xf,%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L37
L7:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L7
L37:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L24
L44:
  mov    -0x38(%rbp),%rdi
  mov    %rsp,%rsi
  mov    %r8d,%edx
  call   <get_syscall_str@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <handle_open_common@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax)
L24:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L44
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handle_openat() {
  long params[4];
  long rc = get_syscall_params(4, params);
  char path[PATH_MAX];
  get_syscall_str(params[1], path, sizeof(path));
  handle_open_common(rc, path);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<data_valid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  je     L21
  mov    $0x0,%eax
  jmp    L33
L21:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  mov    $0x1,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int data_valid(int *data, int size, int value) {
  int i;
  for (i = 0; i < size; i++) {
    if (data[i] != value) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<data_valid>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rcx
L1:
  cmp    %edx,(%rax)
  jne    L29
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L1
  mov    $0x1,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
L29:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int data_valid(int *data, int size, int value) {
  int i;
  for (i = 0; i < size; i++) {
    if (data[i] != value) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<data_valid>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L11
L39:
  cmp    %edx,(%rdi)
  je     L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int data_valid(int *data, int size, int value) {
  int i;
  for (i = 0; i < size; i++) {
    if (data[i] != value) {
      return 0;
    }
  }
  return 1;
}
```