ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <vwprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int wprintf(const wchar_t *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vwprintf(fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <vwprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int wprintf(const wchar_t *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vwprintf(fmt, ap);
  va_end(ap);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<addHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x50,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x4b,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x54,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *addHeader(char *dest, int *seq, char *buff, int sizeH, int sizeB) {
  *dest = 'P';
  *(dest + 1) = 'K';
  *(dest + 2) = 'T';
  memcpy(dest + 3, seq, sizeof(int));
  memcpy((dest + sizeH), buff, sizeB);
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<addHeader>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %r8d,%r13d
  movb   $0x50,(%rdi)
  movb   $0x4b,0x1(%rdi)
  movb   $0x54,0x2(%rdi)
  lea    0x3(%rdi),%rdi
  mov    $0x4,%edx
  mov    $0x0,%eax
  call   <memcpy@plt>
  movslq %ebp,%rdi
  add    %rbx,%rdi
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *addHeader(char *dest, int *seq, char *buff, int sizeH, int sizeB) {
  *dest = 'P';
  *(dest + 1) = 'K';
  *(dest + 2) = 'T';
  memcpy(dest + 3, seq, sizeof(int));
  memcpy((dest + sizeH), buff, sizeB);
  return dest;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<addHeader>:
  endbr64
  push   %r13
  mov    $0x4b50,%eax
  mov    %r8d,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    0x3(%rdi),%rdi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x4,%edx
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  mov    %ax,-0x3(%rdi)
  xor    %eax,%eax
  movb   $0x54,-0x1(%rdi)
  call   <memcpy@plt>
  movslq %ebx,%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  add    %r12,%rdi
  xor    %eax,%eax
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *addHeader(char *dest, int *seq, char *buff, int sizeH, int sizeB) {
  *dest = 'P';
  *(dest + 1) = 'K';
  *(dest + 2) = 'T';
  memcpy(dest + 3, seq, sizeof(int));
  memcpy((dest + sizeH), buff, sizeB);
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<addHeader>:
  endbr64
  push   %r13
  mov    $0x4b50,%eax
  mov    %r8d,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    0x3(%rdi),%rdi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x4,%edx
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  mov    %ax,-0x3(%rdi)
  xor    %eax,%eax
  movb   $0x54,-0x1(%rdi)
  call   <memcpy@plt>
  movslq %ebx,%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  add    %r12,%rdi
  xor    %eax,%eax
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *addHeader(char *dest, int *seq, char *buff, int sizeH, int sizeB) {
  *dest = 'P';
  *(dest + 1) = 'K';
  *(dest + 2) = 'T';
  memcpy(dest + 3, seq, sizeof(int));
  memcpy((dest + sizeH), buff, sizeB);
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<startsWith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jge    L3
  mov    $0x0,%eax
  jmp    L18
L3:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int startsWith(const char *str, const char *prefix) {
  if (strlen(str) < strlen(prefix))
    return 0;
  return memcmp(str, prefix, strlen(prefix)) == 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<startsWith>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%r12
  jge    L6
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L2
```

assistant: ```c
int startsWith(const char *str, const char *prefix) {
  if (strlen(str) < strlen(prefix))
    return 0;
  return memcmp(str, prefix, strlen(prefix)) == 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<startsWith>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  cmp    %rdx,%rbx
  jl     L4
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int startsWith(const char *str, const char *prefix) {
  if (strlen(str) < strlen(prefix))
    return 0;
  return memcmp(str, prefix, strlen(prefix)) == 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<startsWith>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  cmp    %rdx,%rbx
  jl     L8
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int startsWith(const char *str, const char *prefix) {
  if (strlen(str) < strlen(prefix))
    return 0;
  return memcmp(str, prefix, strlen(prefix)) == 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x61,-0x1(%rbp)
  jmp    L6
L10:
  movzbl -0x1(%rbp),%eax
  mov    %eax,%edx
  add    $0x1,%edx
  mov    %dl,-0x1(%rbp)
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L6:
  cmpb   $0x7a,-0x1(%rbp)
  jle    L10
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  char c;
  c = 'a';
  while (c <= 'z')
    ft_putchar(c++);
  ft_putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
L8:
  mov    %ebx,%edi
  call   <ft_putchar@plt>
  add    $0x1,%ebx
  cmp    $0x7b,%ebx
  jne    L8
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  char c;
  c = 'a';
  while (c <= 'z')
    ft_putchar(c++);
  ft_putchar('\n');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    $0x7b,%ebx
  jne    L5
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_print_alphabet(void) {
  char c;
  c = 'a';
  while (c <= 'z')
    ft_putchar(c++);
  ft_putchar('\n');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    $0x7b,%ebx
  jne    L4
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_print_alphabet(void) {
  char c;
  c = 'a';
  while (c <= 'z')
    ft_putchar(c++);
  ft_putchar('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<supcon_leni>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L112
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L30
L112:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L30:
  cmpl   $0x9,-0x8(%rbp)
  jg     L123
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L174
L123:
  cmpl   $0x63,-0x8(%rbp)
  jg     L46
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  jmp    L174
L46:
  cmpl   $0x3e7,-0x8(%rbp)
  jg     L66
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  jmp    L174
L66:
  cmpl   $0x270f,-0x8(%rbp)
  jg     L10
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L174
L10:
  cmpl   $0x1869f,-0x8(%rbp)
  jg     L3
  mov    -0x4(%rbp),%eax
  add    $0x5,%eax
  jmp    L174
L3:
  cmpl   $0xf423f,-0x8(%rbp)
  jg     L38
  mov    -0x4(%rbp),%eax
  add    $0x6,%eax
  jmp    L174
L38:
  cmpl   $0x98967f,-0x8(%rbp)
  jg     L4
  mov    -0x4(%rbp),%eax
  add    $0x7,%eax
  jmp    L174
L4:
  cmpl   $0x5f5e0ff,-0x8(%rbp)
  jg     L25
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  jmp    L174
L25:
  cmpl   $0x3b9ac9ff,-0x8(%rbp)
  jg     L101
  mov    -0x4(%rbp),%eax
  add    $0x9,%eax
  jmp    L174
L101:
  mov    $0xa,%eax
L174:
  pop    %rbp
  ret
```

assistant: ```c
int supcon_leni(int num) {
  int p;
  int sign;
  if (num < 0) {
    p = -num;
    sign = 1;
  } else {
    p = num;
    sign = 0;
  }
  if (p < 10)
    return sign + 1;
  if (p < 100)
    return sign + 2;
  if (p < 1000)
    return sign + 3;
  if (p < 10000)
    return sign + 4;
  if (p < 100000)
    return sign + 5;
  if (p < 1000000)
    return sign + 6;
  if (p < 10000000)
    return sign + 7;
  if (p < 100000000)
    return sign + 8;
  if (p < 1000000000)
    return sign + 9;
  return 10;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<supcon_leni>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L76
L62:
  cmp    $0x9,%edi
  jle    L35
  cmp    $0x63,%edi
  jle    L44
  cmp    $0x3e7,%edi
  jle    L66
  cmp    $0x270f,%edi
  jle    L4
  cmp    $0x1869f,%edi
  jle    L45
  cmp    $0xf423f,%edi
  jle    L42
  cmp    $0x98967f,%edi
  jle    L16
  cmp    $0x5f5e0ff,%edi
  jle    L64
  add    $0x9,%eax
  cmp    $0x3b9aca00,%edi
  mov    $0xa,%edx
  cmovge %edx,%eax
  ret
L76:
  neg    %edi
  mov    $0x1,%eax
  jmp    L62
L35:
  add    $0x1,%eax
  ret
L44:
  add    $0x2,%eax
  ret
L66:
  add    $0x3,%eax
  ret
L4:
  add    $0x4,%eax
  ret
L45:
  add    $0x5,%eax
  ret
L42:
  add    $0x6,%eax
  ret
L16:
  add    $0x7,%eax
  ret
L64:
  add    $0x8,%eax
  ret
```

assistant: ```c
int supcon_leni(int num) {
  int p;
  int sign;
  if (num < 0) {
    p = -num;
    sign = 1;
  } else {
    p = num;
    sign = 0;
  }
  if (p < 10)
    return sign + 1;
  if (p < 100)
    return sign + 2;
  if (p < 1000)
    return sign + 3;
  if (p < 10000)
    return sign + 4;
  if (p < 100000)
    return sign + 5;
  if (p < 1000000)
    return sign + 6;
  if (p < 10000000)
    return sign + 7;
  if (p < 100000000)
    return sign + 8;
  if (p < 1000000000)
    return sign + 9;
  return 10;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<supcon_leni>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jns    L65
  neg    %edi
  mov    $0x1,%eax
L65:
  cmp    $0x9,%edi
  jle    L28
  cmp    $0x63,%edi
  jle    L51
  cmp    $0x3e7,%edi
  jle    L80
  cmp    $0x270f,%edi
  jle    L33
  cmp    $0x1869f,%edi
  jle    L50
  cmp    $0xf423f,%edi
  jle    L43
  cmp    $0x98967f,%edi
  jle    L60
  cmp    $0x5f5e0ff,%edi
  jle    L35
  add    $0x9,%eax
  mov    $0xa,%edx
  cmp    $0x3b9aca00,%edi
  cmovge %edx,%eax
  ret
  nopl   (%rax)
L51:
  add    $0x2,%eax
  ret
  nopl   0x0(%rax)
L28:
  add    $0x1,%eax
  ret
  nopl   0x0(%rax)
L33:
  add    $0x4,%eax
  ret
  nopl   0x0(%rax)
L80:
  add    $0x3,%eax
  ret
  nopl   0x0(%rax)
L50:
  add    $0x5,%eax
  ret
  nopl   0x0(%rax)
L35:
  add    $0x8,%eax
  ret
  nopl   0x0(%rax)
L43:
  add    $0x6,%eax
  ret
  nopl   0x0(%rax)
L60:
  add    $0x7,%eax
  ret
```

assistant: ```c
int supcon_leni(int num) {
  int p;
  int sign;
  if (num < 0) {
    p = -num;
    sign = 1;
  } else {
    p = num;
    sign = 0;
  }
  if (p < 10)
    return sign + 1;
  if (p < 100)
    return sign + 2;
  if (p < 1000)
    return sign + 3;
  if (p < 10000)
    return sign + 4;
  if (p < 100000)
    return sign + 5;
  if (p < 1000000)
    return sign + 6;
  if (p < 10000000)
    return sign + 7;
  if (p < 100000000)
    return sign + 8;
  if (p < 1000000000)
    return sign + 9;
  return 10;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<supcon_leni>:
  endbr64
  push   %rbx
  test   %edi,%edi
  js     L91
  mov    $0x1,%eax
  mov    $0x2,%edx
  mov    $0x3,%ecx
  mov    $0x4,%esi
  mov    $0x5,%r8d
  mov    $0x6,%r9d
  mov    $0x9,%ebx
  mov    $0x7,%r10d
  mov    $0x8,%r11d
L79:
  cmp    $0x9,%edi
  jle    L41
  mov    %edx,%eax
  cmp    $0x63,%edi
  jle    L41
  mov    %ecx,%eax
  cmp    $0x3e7,%edi
  jle    L41
  mov    %esi,%eax
  cmp    $0x270f,%edi
  jle    L41
  mov    %r8d,%eax
  cmp    $0x1869f,%edi
  jle    L41
  mov    %r9d,%eax
  cmp    $0xf423f,%edi
  jle    L41
  mov    %r10d,%eax
  cmp    $0x98967f,%edi
  jle    L41
  mov    %r11d,%eax
  cmp    $0x5f5e0ff,%edi
  jle    L41
  cmp    $0x3b9ac9ff,%edi
  mov    $0xa,%eax
  cmovle %ebx,%eax
L41:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L91:
  neg    %edi
  mov    $0x2,%eax
  mov    $0x3,%edx
  mov    $0x4,%ecx
  mov    $0x5,%esi
  mov    $0x6,%r8d
  mov    $0x7,%r9d
  mov    $0x8,%r10d
  mov    $0x9,%r11d
  mov    $0xa,%ebx
  jmp    L79
```

assistant: ```c
int supcon_leni(int num) {
  int p;
  int sign;
  if (num < 0) {
    p = -num;
    sign = 1;
  } else {
    p = num;
    sign = 0;
  }
  if (p < 10)
    return sign + 1;
  if (p < 100)
    return sign + 2;
  if (p < 1000)
    return sign + 3;
  if (p < 10000)
    return sign + 4;
  if (p < 100000)
    return sign + 5;
  if (p < 1000000)
    return sign + 6;
  if (p < 10000000)
    return sign + 7;
  if (p < 100000000)
    return sign + 8;
  if (p < 1000000000)
    return sign + 9;
  return 10;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<receive_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  lea    D17(%rip),%r9
  lea    D0(%rip),%r8
  mov    $0x0,%ecx
  mov    $0x100,%edx
  lea    D6(%rip),%rsi
  mov    %eax,%edi
  call   <recvfrom@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L62
  mov    D0(%rip),%eax
  mov    %eax,%edi
  call   <inet_ntoa@plt>
  mov    %eax,%edi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L67
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <is_local_address@plt>
  test   %rax,%rax
  je     L45
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L59
L45:
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <parse_message@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L22
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L59
L22:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <handle_message@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <message_destroy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L59
L62:
  nop
  jmp    L59
L67:
  nop
L59:
  leave
  ret
```

assistant: ```c
void receive_message(const int fd) {
  static struct sockaddr_in source;
  static socklen_t size = sizeof(source);
  static unsigned char buffer[256];
  const ssize_t received = recvfrom(fd, buffer, 256, 0, (struct sockaddr *)&source, &size);
  if (received == -1) {
    return;
  }
  char *const ip = strdup(inet_ntoa(source.sin_addr));
  if (ip == NULL) {
    return;
  }
  if (is_local_address(ip)) {
    free(ip);
    return;
  }
  struct message *const message = parse_message(buffer, (size_t)received);
  if (message == NULL) {
    free(ip);
    return;
  }
  handle_message(ip, message);
  message_destroy(message);
  free(ip);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<receive_message>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D40(%rip),%r9
  lea    D41(%rip),%r8
  mov    $0x0,%ecx
  mov    $0x100,%edx
  lea    D22(%rip),%rsi
  call   <recvfrom@plt>
  cmp    $0xffffffff,%eax
  je     L35
  mov    %eax,%ebx
  mov    D41(%rip),%edi
  call   <inet_ntoa@plt>
  mov    %eax,%edi
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L35
  mov    %rax,%rdi
  call   <is_local_address@plt>
  test   %rax,%rax
  jne    L9
  movslq %ebx,%rsi
  lea    D22(%rip),%rdi
  call   <parse_message@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L21
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <handle_message@plt>
  mov    %rbx,%rdi
  call   <message_destroy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L35
L21:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L35
```

assistant: ```c
void receive_message(const int fd) {
  static struct sockaddr_in source;
  static socklen_t size = sizeof(source);
  static unsigned char buffer[256];
  const ssize_t received = recvfrom(fd, buffer, 256, 0, (struct sockaddr *)&source, &size);
  if (received == -1) {
    return;
  }
  char *const ip = strdup(inet_ntoa(source.sin_addr));
  if (ip == NULL) {
    return;
  }
  if (is_local_address(ip)) {
    free(ip);
    return;
  }
  struct message *const message = parse_message(buffer, (size_t)received);
  if (message == NULL) {
    free(ip);
    return;
  }
  handle_message(ip, message);
  message_destroy(message);
  free(ip);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<receive_message>:
  endbr64
  push   %r12
  lea    D24(%rip),%r12
  xor    %ecx,%ecx
  mov    $0x100,%edx
  push   %rbp
  lea    D33(%rip),%r9
  lea    D35(%rip),%r8
  mov    %r12,%rsi
  push   %rbx
  call   <recvfrom@plt>
  cmp    $0xffffffff,%eax
  je     L17
  mov    D35(%rip),%edi
  mov    %eax,%ebx
  call   <inet_ntoa@plt>
  mov    %eax,%edi
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L17
  mov    %rax,%rdi
  call   <is_local_address@plt>
  test   %rax,%rax
  jne    L0
  mov    %r12,%rdi
  movslq %ebx,%rsi
  call   <parse_message@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <handle_message@plt>
  mov    %r12,%rdi
  call   <message_destroy@plt>
L0:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10c0 <free@plt>
  nopl   0x0(%rax)
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void receive_message(const int fd) {
  static struct sockaddr_in source;
  static socklen_t size = sizeof(source);
  static unsigned char buffer[256];
  const ssize_t received = recvfrom(fd, buffer, 256, 0, (struct sockaddr *)&source, &size);
  if (received == -1) {
    return;
  }
  char *const ip = strdup(inet_ntoa(source.sin_addr));
  if (ip == NULL) {
    return;
  }
  if (is_local_address(ip)) {
    free(ip);
    return;
  }
  struct message *const message = parse_message(buffer, (size_t)received);
  if (message == NULL) {
    free(ip);
    return;
  }
  handle_message(ip, message);
  message_destroy(message);
  free(ip);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<receive_message>:
  endbr64
  push   %r12
  lea    D18(%rip),%r12
  xor    %ecx,%ecx
  mov    $0x100,%edx
  push   %rbp
  lea    D11(%rip),%r9
  lea    D28(%rip),%r8
  mov    %r12,%rsi
  push   %rbx
  call   <recvfrom@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    D28(%rip),%edi
  mov    %eax,%ebx
  call   <inet_ntoa@plt>
  mov    %eax,%edi
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  mov    %rax,%rdi
  call   <is_local_address@plt>
  test   %rax,%rax
  jne    L2
  mov    %r12,%rdi
  movslq %ebx,%rsi
  call   <parse_message@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <handle_message@plt>
  mov    %r12,%rdi
  call   <message_destroy@plt>
L2:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10c0 <free@plt>
  nopl   0x0(%rax)
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void receive_message(const int fd) {
  static struct sockaddr_in source;
  static socklen_t size = sizeof(source);
  static unsigned char buffer[256];
  const ssize_t received = recvfrom(fd, buffer, 256, 0, (struct sockaddr *)&source, &size);
  if (received == -1) {
    return;
  }
  char *const ip = strdup(inet_ntoa(source.sin_addr));
  if (ip == NULL) {
    return;
  }
  if (is_local_address(ip)) {
    free(ip);
    return;
  }
  struct message *const message = parse_message(buffer, (size_t)received);
  if (message == NULL) {
    free(ip);
    return;
  }
  handle_message(ip, message);
  message_destroy(message);
  free(ip);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_serial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L4:
  mov    $0x0,%eax
  call   <serial_received@plt>
  test   %rax,%rax
  je     L4
  mov    $0x3f8,%edi
  call   <inportb@plt>
  pop    %rbp
  ret
```

assistant: ```c
char read_serial() {
  while (serial_received() == 0)
    ;
  return inportb(0x3f8);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_serial>:
  endbr64
  sub    $0x8,%rsp
L0:
  mov    $0x0,%eax
  call   <serial_received@plt>
  test   %rax,%rax
  je     L0
  mov    $0x3f8,%edi
  call   <inportb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char read_serial() {
  while (serial_received() == 0)
    ;
  return inportb(0x3f8);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<read_serial>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <serial_received@plt>
  test   %rax,%rax
  je     L0
  mov    $0x3f8,%edi
  add    $0x8,%rsp
  jmp    1060 <inportb@plt>
```

assistant: ```c
char read_serial() {
  while (serial_received() == 0)
    ;
  return inportb(0x3f8);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_serial>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <serial_received@plt>
  test   %rax,%rax
  je     L4
  mov    $0x3f8,%edi
  add    $0x8,%rsp
  jmp    1060 <inportb@plt>
```

assistant: ```c
char read_serial() {
  while (serial_received() == 0)
    ;
  return inportb(0x3f8);
}
```