ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<IsSbrSettingAvail>:
  endbr64
  cmp    $0x7cff,%edx
  ja     L1
  xor    %eax,%eax
  ret
  nop
L1:
  shr    %edx
  sub    $0x8,%rsp
  mov    %edx,(%rcx)
  call   <getSbrTuningTableIndex@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
unsigned int IsSbrSettingAvail(unsigned int bitrate, unsigned int numOutputChannels, unsigned int sampleRateInput, unsigned int *sampleRateCore) {
  int idx = -1;
  ;
  ;
  ;
  ;
  if (sampleRateInput < 32000) {
    ;
    return 0;
  };
  ;
  *sampleRateCore = sampleRateInput / 2;
  ;
  idx = getSbrTuningTableIndex(bitrate, numOutputChannels, *sampleRateCore);
  ;
  ;
  ;
  return (idx == -1) ? 0 : 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_radii_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L8:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *get_radii_range(int minr, int maxr) {
  int i, len;
  int *r;
  len = maxr - minr + 1;
  r = xmalloc(sizeof(*r) * len);
  for (i = 0; i < len; i++) {
    r[i] = minr + i;
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_radii_range>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    %edi,%esi
  mov    %esi,%ebp
  lea    0x1(%rsi),%r12d
  lea    0x0(,%r12,4),%edi
  call   <xmalloc@plt>
  test   %r12d,%r12d
  jle    L7
  mov    %ebx,%edx
  mov    %rax,%rcx
  lea    0x1(%rbp,%rbx,1),%esi
L15:
  mov    %edx,(%rcx)
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %esi,%edx
  jne    L15
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *get_radii_range(int minr, int maxr) {
  int i, len;
  int *r;
  len = maxr - minr + 1;
  r = xmalloc(sizeof(*r) * len);
  for (i = 0; i < len; i++) {
    r[i] = minr + i;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_radii_range>:
  endbr64
  push   %r12
  sub    %edi,%esi
  push   %rbp
  lea    0x1(%rsi),%r12d
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%r12,4),%edi
  call   <xmalloc@plt>
  test   %r12d,%r12d
  jle    L14
  mov    %ebx,%edi
  mov    %rax,%rdx
  lea    0x1(%rbp,%rbx,1),%ecx
  nopl   (%rax)
L15:
  mov    %edi,(%rdx)
  add    $0x1,%edi
  add    $0x4,%rdx
  cmp    %ecx,%edi
  jne    L15
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *get_radii_range(int minr, int maxr) {
  int i, len;
  int *r;
  len = maxr - minr + 1;
  r = xmalloc(sizeof(*r) * len);
  for (i = 0; i < len; i++) {
    r[i] = minr + i;
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_radii_range>:
  endbr64
  push   %r12
  sub    %edi,%esi
  push   %rbp
  lea    0x1(%rsi),%ebp
  mov    %esi,%r12d
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbp,4),%edi
  call   <xmalloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L34
  cmp    $0x2,%r12d
  jbe    L22
  mov    %ebp,%edx
  movd   %ebx,%xmm4
  movdqa D14(%rip),%xmm1
  movdqa D9(%rip),%xmm2
  shr    $0x2,%edx
  pshufd $0x0,%xmm4,%xmm3
  shl    $0x4,%rdx
  add    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L10:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm2,%xmm1
  paddd  %xmm3,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L10
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  and    $0x3,%ebp
  je     L34
L62:
  movslq %eax,%rdx
  lea    (%rbx,%rax,1),%esi
  mov    %esi,(%r8,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %eax,%r12d
  jle    L34
  lea    (%rbx,%rdx,1),%esi
  add    $0x2,%eax
  mov    %esi,0x4(%r8,%rcx,1)
  cmp    %edx,%r12d
  jle    L34
  add    %eax,%ebx
  mov    %ebx,0x8(%r8,%rcx,1)
L34:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
L22:
  xor    %eax,%eax
  jmp    L62
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: byte[16]
name: read_data
arguments: data_label: D9
type_guessed: byte[16]

tool: {"D14": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D9": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int *get_radii_range(int minr, int maxr) {
  int i, len;
  int *r;
  len = maxr - minr + 1;
  r = xmalloc(sizeof(*r) * len);
  for (i = 0; i < len; i++) {
    r[i] = minr + i;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %edx,-0x4(%rbp)
  jmp    L96
L27:
  movzbl (%rax),%esi
  movzbl (%rcx),%edx
  cmp    %dl,%sil
  je     L72
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L44
  mov    $0xffffffff,%eax
  jmp    L97
L44:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L48
  mov    $0x1,%eax
  jmp    L97
L48:
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl (%rcx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L97
L72:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  test   %dl,%dl
  je     L81
  add    $0x1,%rcx
L96:
  mov    -0x4(%rbp),%edx
  lea    -0x1(%rdx),%esi
  mov    %esi,-0x4(%rbp)
  test   %edx,%edx
  jg     L27
  jmp    L85
L81:
  nop
L85:
  mov    $0x0,%eax
L97:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(s1, s2, n)
register char *s1, *s2;
int n;
{
  while (n-- > 0) {
    if (*s1 != *s2) {
      if (!*s1)
        return -1;
      if (!*s2)
        return 1;
      return (*s1 - *s2);
    }
    if (*s1++ == 0)
      break;
    s2++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmp>:
  endbr64
  test   %edx,%edx
  jle    L53
  mov    %edx,%edx
  mov    $0x0,%eax
L5:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L16
  test   %cl,%cl
  je     L34
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
  mov    $0x0,%eax
  ret
L16:
  test   %cl,%cl
  je     L43
  mov    $0x1,%eax
  test   %r8b,%r8b
  je     L56
  movsbl %cl,%eax
  movsbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L53:
  mov    $0x0,%eax
  ret
L43:
  mov    $0xffffffff,%eax
  ret
L34:
  mov    $0x0,%eax
L56:
  ret
```

assistant: ```c
int strncmp(s1, s2, n)
register char *s1, *s2;
int n;
{
  while (n-- > 0) {
    if (*s1 != *s2) {
      if (!*s1)
        return -1;
      if (!*s2)
        return 1;
      return (*s1 - *s2);
    }
    if (*s1++ == 0)
      break;
    s2++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strncmp>:
  endbr64
  test   %edx,%edx
  jle    L69
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L46
  nop
L36:
  test   %cl,%cl
  je     L69
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L69
L46:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L36
  test   %cl,%cl
  je     L38
  mov    $0x1,%eax
  test   %r8b,%r8b
  jne    L47
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
L38:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strncmp(s1, s2, n)
register char *s1, *s2;
int n;
{
  while (n-- > 0) {
    if (*s1 != *s2) {
      if (!*s1)
        return -1;
      if (!*s2)
        return 1;
      return (*s1 - *s2);
    }
    if (*s1++ == 0)
      break;
    s2++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmp>:
  endbr64
  test   %edx,%edx
  jle    L29
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L21
  nop
L6:
  test   %cl,%cl
  je     L29
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L29
L21:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L6
  test   %cl,%cl
  je     L44
  mov    $0x1,%eax
  test   %r8b,%r8b
  jne    L33
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
L44:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strncmp(s1, s2, n)
register char *s1, *s2;
int n;
{
  while (n-- > 0) {
    if (*s1 != *s2) {
      if (!*s1)
        return -1;
      if (!*s2)
        return 1;
      return (*s1 - *s2);
    }
    if (*s1++ == 0)
      break;
    s2++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x24(%rbp),%xmm1
  movss  -0x20(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x1c(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  D22(%rip),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  D47(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd -0x10(%rbp),%xmm3
  movq   %xmm3,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D28
type_guessed: string
name: disassemble_data
arguments: label: D22
type_guessed: byte[4]
name: disassemble_data
arguments: label: D47
type_guessed: byte[4]
name: disassemble_data
arguments: label: D44
type_guessed: string

tool: D1: Enter the marks of each subject: 

tool: D28: %f %f %f %f %f

tool: {"D22": [0x00,0x00,0xfa,0x43]}

tool: {"D47": [0x00,0x00,0xc8,0x42]}

tool: D44: The total is %f and the average is %f


assistant: ```c
int main() {
  float s1, s2, s3, s4, s5;
  float total, avg;
  printf("Enter the marks of each subject: ");
  scanf("%f %f %f %f %f", &s1, &s2, &s3, &s4, &s5);
  total = (s1 + s2 + s3 + s4 + s5);
  avg = (total / 500) * 100;
  printf("The total is %f and the average is %f\n", total, avg);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  addss  0x8(%rsp),%xmm0
  addss  0xc(%rsp),%xmm0
  addss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  movaps %xmm0,%xmm1
  divss  D39(%rip),%xmm1
  mulss  D25(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D15(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D31
type_guessed: string
name: parse_data
arguments: data_tag: D39
type_guessed: byte[4]
name: parse_data
arguments: data_tag: D25
type_guessed: byte[4]
name: parse_data
arguments: data_tag: D15
type_guessed: string

tool: D3: Enter the marks of each subject: 

tool: D31: %f %f %f %f %f

tool: {"D39": [0x00,0x00,0xfa,0x43]}

tool: {"D25": [0x00,0x00,0xc8,0x42]}

tool: D15: The total is %f and the average is %f


assistant: ```c
int main() {
  float s1, s2, s3, s4, s5;
  float total, avg;
  printf("Enter the marks of each subject: ");
  scanf("%f %f %f %f %f", &s1, &s2, &s3, &s4, &s5);
  total = (s1 + s2 + s3 + s4 + s5);
  avg = (total / 500) * 100;
  printf("The total is %f and the average is %f\n", total, avg);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    D28(%rip),%rdi
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  addss  0x8(%rsp),%xmm0
  lea    D49(%rip),%rdi
  addss  0xc(%rsp),%xmm0
  addss  0x10(%rsp),%xmm0
  mov    $0x2,%eax
  addss  0x14(%rsp),%xmm0
  movaps %xmm0,%xmm1
  divss  D22(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  mulss  D33(%rip),%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_infered: string
name: unpack_data
arguments: data_tag: D28
type_infered: string
name: unpack_data
arguments: data_tag: D49
type_infered: string
name: unpack_data
arguments: data_tag: D22
type_infered: byte[4]
name: unpack_data
arguments: data_tag: D33
type_infered: byte[4]

tool: D14: Enter the marks of each subject: 

tool: D28: %f %f %f %f %f

tool: D49: The total is %f and the average is %f


tool: {"D22": [0x00,0x00,0xfa,0x43]}

tool: {"D33": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int main() {
  float s1, s2, s3, s4, s5;
  float total, avg;
  printf("Enter the marks of each subject: ");
  scanf("%f %f %f %f %f", &s1, &s2, &s3, &s4, &s5);
  total = (s1 + s2 + s3 + s4 + s5);
  avg = (total / 500) * 100;
  printf("The total is %f and the average is %f\n", total, avg);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D43(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    D32(%rip),%rdi
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  addss  0x8(%rsp),%xmm0
  lea    D12(%rip),%rdi
  addss  0xc(%rsp),%xmm0
  addss  0x10(%rsp),%xmm0
  mov    $0x2,%eax
  addss  0x14(%rsp),%xmm0
  movaps %xmm0,%xmm1
  divss  D25(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  mulss  D40(%rip),%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D43
type_infered: string
name: extract_symbolic_data
arguments: data_label: D32
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_label: D40
type_infered: byte[4]

tool: D43: Enter the marks of each subject: 

tool: D32: %f %f %f %f %f

tool: D12: The total is %f and the average is %f


tool: {"D25": [0x00,0x00,0xfa,0x43]}

tool: {"D40": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int main() {
  float s1, s2, s3, s4, s5;
  float total, avg;
  printf("Enter the marks of each subject: ");
  scanf("%f %f %f %f %f", &s1, &s2, &s3, &s4, &s5);
  total = (s1 + s2 + s3 + s4 + s5);
  avg = (total / 500) * 100;
  printf("The total is %f and the average is %f\n", total, avg);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<processchunked>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x5(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L11
  mov    $0x0,%eax
  jmp    L4
L11:
  mov    $0x1,%eax
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: %d %d %d


assistant: ```c
int processchunked(char *resp, int size) {
  char *p = resp + size - 5;
  printf("%d %d %d\n", *(p - 1), *p, *(p + 1));
  if (*p == '0' && *(p - 1) == '\n' && *(p + 1) == '\r') {
    return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<processchunked>:
  endbr64
  push   %rbx
  movslq %esi,%rsi
  lea    -0x5(%rsi,%rdi,1),%rbx
  movsbl 0x1(%rbx),%ecx
  movsbl (%rbx),%edx
  movsbl -0x1(%rbx),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  cmpb   $0x30,(%rbx)
  je     L26
L18:
  pop    %rbx
  ret
L26:
  cmpb   $0xa,-0x1(%rbx)
  jne    L18
  cmpb   $0xd,0x1(%rbx)
  setne  %al
  movzbl %al,%eax
  jmp    L18
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: %d %d %d


assistant: ```c
int processchunked(char *resp, int size) {
  char *p = resp + size - 5;
  printf("%d %d %d\n", *(p - 1), *p, *(p + 1));
  if (*p == '0' && *(p - 1) == '\n' && *(p + 1) == '\r') {
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<processchunked>:
  endbr64
  movslq %esi,%rsi
  push   %rbx
  lea    -0x5(%rsi,%rdi,1),%rbx
  lea    D9(%rip),%rdi
  movsbl 0x1(%rbx),%ecx
  movsbl (%rbx),%edx
  movsbl -0x1(%rbx),%esi
  call   <printf@plt>
  cmpb   $0x30,(%rbx)
  mov    $0x1,%eax
  je     L1
L9:
  pop    %rbx
  ret
L1:
  cmpb   $0xa,-0x1(%rbx)
  jne    L9
  xor    %eax,%eax
  cmpb   $0xd,0x1(%rbx)
  pop    %rbx
  setne  %al
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string

tool: D9: %d %d %d


assistant: ```c
int processchunked(char *resp, int size) {
  char *p = resp + size - 5;
  printf("%d %d %d\n", *(p - 1), *p, *(p + 1));
  if (*p == '0' && *(p - 1) == '\n' && *(p + 1) == '\r') {
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<processchunked>:
  endbr64
  movslq %esi,%rsi
  push   %rbx
  lea    -0x5(%rsi,%rdi,1),%rbx
  lea    D6(%rip),%rdi
  movsbl 0x1(%rbx),%ecx
  movsbl (%rbx),%edx
  movsbl -0x1(%rbx),%esi
  call   <printf@plt>
  cmpb   $0x30,(%rbx)
  mov    $0x1,%eax
  je     L0
L3:
  pop    %rbx
  ret
L0:
  cmpb   $0xa,-0x1(%rbx)
  jne    L3
  xor    %eax,%eax
  cmpb   $0xd,0x1(%rbx)
  pop    %rbx
  setne  %al
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: %d %d %d


assistant: ```c
int processchunked(char *resp, int size) {
  char *p = resp + size - 5;
  printf("%d %d %d\n", *(p - 1), *p, *(p + 1));
  if (*p == '0' && *(p - 1) == '\n' && *(p + 1) == '\r') {
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,(%rbx)
  jmp    L5
L4:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,(%rbx)
L5:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
data_type: string

tool: D15:  

assistant: ```c
char **parse_line(char *line) {
  char **tokens = malloc((strlen(line) + 1) * sizeof(char *));
  int tokIdx = 0;
  tokens[tokIdx] = strtok(line, " ");
  while (tokens[tokIdx] != NULL) {
    tokIdx++;
    tokens[tokIdx] = strtok(NULL, " ");
  }
  return tokens;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L18
  lea    0x8(%r12),%rbx
  lea    D11(%rip),%rbp
L11:
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  test   %rax,%rax
  jne    L11
L18:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type: string

tool: D11:  

assistant: ```c
char **parse_line(char *line) {
  char **tokens = malloc((strlen(line) + 1) * sizeof(char *));
  int tokIdx = 0;
  tokens[tokIdx] = strtok(line, " ");
  while (tokens[tokIdx] != NULL) {
    tokIdx++;
    tokens[tokIdx] = strtok(NULL, " ");
  }
  return tokens;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_line>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L13
  lea    0x8(%r12),%rbx
  nopl   (%rax)
L1:
  mov    %rbp,%rsi
  xor    %edi,%edi
  add    $0x8,%rbx
  call   <strtok@plt>
  mov    %rax,-0x8(%rbx)
  test   %rax,%rax
  jne    L1
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string

tool: D7:  

assistant: ```c
char **parse_line(char *line) {
  char **tokens = malloc((strlen(line) + 1) * sizeof(char *));
  int tokIdx = 0;
  tokens[tokIdx] = strtok(line, " ");
  while (tokens[tokIdx] != NULL) {
    tokIdx++;
    tokens[tokIdx] = strtok(NULL, " ");
  }
  return tokens;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_line>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L19
  lea    0x8(%r12),%rbx
  nopl   (%rax)
L4:
  mov    %rbp,%rsi
  xor    %edi,%edi
  add    $0x8,%rbx
  call   <strtok@plt>
  mov    %rax,-0x8(%rbx)
  test   %rax,%rax
  jne    L4
L19:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D6:  

assistant: ```c
char **parse_line(char *line) {
  char **tokens = malloc((strlen(line) + 1) * sizeof(char *));
  int tokIdx = 0;
  tokens[tokIdx] = strtok(line, " ");
  while (tokens[tokIdx] != NULL) {
    tokIdx++;
    tokens[tokIdx] = strtok(NULL, " ");
  }
  return tokens;
}
```