ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<get_float_from_within_string>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  jmp    L111
  nopl   (%rax)
L43:
  add    $0x1,%rbp
L111:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L43
  movsbl 0x0(%rbp),%edi
  cmp    $0x2d,%dil
  je     L36
  cmp    $0x2e,%dil
  je     L116
  call   <isdigit@plt>
  mov    $0x1,%r12d
  xor    %ebx,%ebx
  test   %rax,%rax
  je     L37
L101:
  lea    0x1(%rbp),%r15
  jmp    L89
  xchg   %ax,%ax
L114:
  cmpb   $0x2e,(%r15)
  jne    L37
  cmp    $0x1,%ebx
  je     L37
  mov    $0x1,%ebx
L41:
  add    $0x1,%r15
L89:
  movsbl (%r15),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L99
  movsbl (%r15),%edi
  cmp    $0xa,%dil
  je     L99
  test   %dil,%dil
  je     L99
  call   <isdigit@plt>
  test   %rax,%rax
  je     L114
  mov    $0x1,%r12d
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L99:
  test   %r12d,%r12d
  jne    L6
L37:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L116:
  xor    %r12d,%r12d
  mov    $0x1,%ebx
  jmp    L101
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r14,%rdx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L37
  mov    %r15,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L101
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: %lf

assistant: ```c
int get_float_from_within_string(char **str, double *val) {
  char *p, *valstart;
  int decimal_point_cnt = 0, has_digits = 0;
  p = *str;
  while (isspace(*p))
    p++;
  valstart = p;
  switch (*p) {
  case ('-'):
    break;
  case ('.'):
    decimal_point_cnt = 1;
    break;
  default:
    if (!isdigit(*p))
      return (0);
    has_digits = 1;
    break;
  }
  p++;
  while (!isspace(*p) && *p != ('\n') && *p != ('\0')) {
    if (isdigit(*p))
      has_digits = 1;
    else if (*p == '.') {
      if (++decimal_point_cnt > 1)
        return (0);
    } else
      return (0);
    p++;
  }
  if (!has_digits || sscanf(valstart, "%lf", val) != 1)
    return (0);
  *str = p;
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_float_from_within_string>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  jmp    L73
  nopl   (%rax)
L153:
  add    $0x1,%rbp
L73:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L153
  movsbl 0x0(%rbp),%edi
  cmp    $0x2d,%dil
  je     L92
  cmp    $0x2e,%dil
  je     L115
  call   <isdigit@plt>
  mov    $0x1,%r12d
  xor    %ebx,%ebx
  test   %rax,%rax
  je     L112
L11:
  lea    0x1(%rbp),%r15
  jmp    L9
  xchg   %ax,%ax
L61:
  cmpb   $0x2e,(%r15)
  jne    L112
  cmp    $0x1,%ebx
  je     L112
  mov    $0x1,%ebx
L111:
  add    $0x1,%r15
L9:
  movsbl (%r15),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L63
  movsbl (%r15),%edi
  cmp    $0xa,%dil
  je     L63
  test   %dil,%dil
  je     L63
  call   <isdigit@plt>
  test   %rax,%rax
  je     L61
  mov    $0x1,%r12d
  jmp    L111
  nopl   0x0(%rax,%rax,1)
L63:
  test   %r12d,%r12d
  jne    L84
L112:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L115:
  xor    %r12d,%r12d
  mov    $0x1,%ebx
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L84:
  mov    %r14,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L112
  mov    %r15,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L92:
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: %lf

assistant: ```c
int get_float_from_within_string(char **str, double *val) {
  char *p, *valstart;
  int decimal_point_cnt = 0, has_digits = 0;
  p = *str;
  while (isspace(*p))
    p++;
  valstart = p;
  switch (*p) {
  case ('-'):
    break;
  case ('.'):
    decimal_point_cnt = 1;
    break;
  default:
    if (!isdigit(*p))
      return (0);
    has_digits = 1;
    break;
  }
  p++;
  while (!isspace(*p) && *p != ('\n') && *p != ('\0')) {
    if (isdigit(*p))
      has_digits = 1;
    else if (*p == '.') {
      if (++decimal_point_cnt > 1)
        return (0);
    } else
      return (0);
    p++;
  }
  if (!has_digits || sscanf(valstart, "%lf", val) != 1)
    return (0);
  *str = p;
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<InitEmulation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <RTC_Init@plt>
  test   %rax,%rax
  je     L21
  mov    $0x0,%eax
  call   <ROM_Init@plt>
  test   %rax,%rax
  je     L21
  mov    $0x0,%eax
  call   <AddrSpac_Init@plt>
  test   %rax,%rax
  je     L21
  mov    $0x1,%eax
  jmp    L10
L21:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int InitEmulation(void) {
  if (RTC_Init())
    if (ROM_Init())
      if (AddrSpac_Init()) {
        return 1;
      }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InitEmulation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <RTC_Init@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L14
L27:
  add    $0x8,%rsp
  ret
L14:
  call   <ROM_Init@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L27
  call   <AddrSpac_Init@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L27
```

assistant: ```c
int InitEmulation(void) {
  if (RTC_Init())
    if (ROM_Init())
      if (AddrSpac_Init()) {
        return 1;
      }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InitEmulation>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <RTC_Init@plt>
  test   %rax,%rax
  jne    L5
L10:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <ROM_Init@plt>
  test   %rax,%rax
  je     L10
  xor    %eax,%eax
  call   <AddrSpac_Init@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int InitEmulation(void) {
  if (RTC_Init())
    if (ROM_Init())
      if (AddrSpac_Init()) {
        return 1;
      }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<InitEmulation>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <RTC_Init@plt>
  test   %rax,%rax
  jne    L3
L10:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <ROM_Init@plt>
  test   %rax,%rax
  je     L10
  xor    %eax,%eax
  call   <AddrSpac_Init@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int InitEmulation(void) {
  if (RTC_Init())
    if (ROM_Init())
      if (AddrSpac_Init()) {
        return 1;
      }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<u24_to_bigendian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void u24_to_bigendian(uint8_t *dst, uint32_t u24) {
  dst[0] = (u24 >> 16) & 0xFF;
  dst[1] = (u24 >> 8) & 0xFF;
  dst[2] = u24 & 0xFF;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<u24_to_bigendian>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  mov    %edx,0x4(%rdi)
  and    $0xff,%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void u24_to_bigendian(uint8_t *dst, uint32_t u24) {
  dst[0] = (u24 >> 16) & 0xFF;
  dst[1] = (u24 >> 8) & 0xFF;
  dst[2] = u24 & 0xFF;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<u24_to_bigendian>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,0x4(%rdi)
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void u24_to_bigendian(uint8_t *dst, uint32_t u24) {
  dst[0] = (u24 >> 16) & 0xFF;
  dst[1] = (u24 >> 8) & 0xFF;
  dst[2] = u24 & 0xFF;
}
```
user: Translate the below assembly code into C programming language:

```asm
<u24_to_bigendian>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,0x4(%rdi)
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void u24_to_bigendian(uint8_t *dst, uint32_t u24) {
  dst[0] = (u24 >> 16) & 0xFF;
  dst[1] = (u24 >> 8) & 0xFF;
  dst[2] = u24 & 0xFF;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fib@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
  jmp    L2
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: D3: F_%llu = %llu


assistant: ```c
int main() {
  unsigned long long int a = 0;
  for (;;) {
    printf("F_%llu = %llu\n", a + 1, fib(a));
    a++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
L2:
  mov    %rbx,%rdi
  call   <fib@plt>
  mov    %eax,%edx
  add    $0x1,%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: F_%llu = %llu


assistant: ```c
int main() {
  unsigned long long int a = 0;
  for (;;) {
    printf("F_%llu = %llu\n", a + 1, fib(a));
    a++;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <fib@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: F_%llu = %llu


assistant: ```c
int main() {
  unsigned long long int a = 0;
  for (;;) {
    printf("F_%llu = %llu\n", a + 1, fib(a));
    a++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <fib@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D6: F_%llu = %llu


assistant: ```c
int main() {
  unsigned long long int a = 0;
  for (;;) {
    printf("F_%llu = %llu\n", a + 1, fib(a));
    a++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<digitstring_fraction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x2b,-0x4(%rbp)
  je     L86
  cmpl   $0x2d,-0x4(%rbp)
  jne    L79
L86:
  addq   $0x1,-0x18(%rbp)
  jmp    L79
L51:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2e,-0x4(%rbp)
  jne    L62
  mov    -0x8(%rbp),%eax
  jmp    L81
L62:
  cmpl   $0x2f,-0x4(%rbp)
  jle    L76
  cmpl   $0x39,-0x4(%rbp)
  jg     L55
  addl   $0x1,-0x8(%rbp)
L79:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L51
  jmp    L26
L76:
  nop
  jmp    L26
L55:
  nop
L26:
  mov    $0x0,%eax
L81:
  pop    %rbp
  ret
```

assistant: ```c
int digitstring_fraction(char *left, char *right) {
  int symbol = *left;
  int digits = 0;
  if ((symbol == '+') || (symbol == '-'))
    left++;
  while (left < right) {
    symbol = *left++;
    if (symbol == '.')
      return digits;
    if (symbol < '0')
      break;
    if (symbol > '9')
      break;
    digits++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<digitstring_fraction>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%rdi
  cmp    %rdi,%rsi
  jbe    L42
  sub    %rdi,%rsi
  mov    $0x0,%edx
L54:
  mov    %edx,%ecx
  movzbl (%rdi,%rdx,1),%eax
  cmp    $0x2e,%al
  je     L58
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L10
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L54
  mov    $0x0,%ecx
  jmp    L58
L42:
  mov    $0x0,%ecx
  jmp    L58
L10:
  mov    $0x0,%ecx
L58:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int digitstring_fraction(char *left, char *right) {
  int symbol = *left;
  int digits = 0;
  if ((symbol == '+') || (symbol == '-'))
    left++;
  while (left < right) {
    symbol = *left++;
    if (symbol == '.')
      return digits;
    if (symbol < '0')
      break;
    if (symbol > '9')
      break;
    digits++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<digitstring_fraction>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%rdi
  cmp    %rdi,%rsi
  jbe    L29
  sub    %rdi,%rsi
  xor    %edx,%edx
  jmp    L5
  nop
L14:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L29
L5:
  movsbl (%rdi,%rdx,1),%eax
  mov    %edx,%r8d
  cmp    $0x2e,%al
  je     L49
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L14
L29:
  xor    %r8d,%r8d
L49:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int digitstring_fraction(char *left, char *right) {
  int symbol = *left;
  int digits = 0;
  if ((symbol == '+') || (symbol == '-'))
    left++;
  while (left < right) {
    symbol = *left++;
    if (symbol == '.')
      return digits;
    if (symbol < '0')
      break;
    if (symbol > '9')
      break;
    digits++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<digitstring_fraction>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%rdi
  cmp    %rdi,%rsi
  jbe    L10
  sub    %rdi,%rsi
  xor    %edx,%edx
  jmp    L5
  nop
L12:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L10
L5:
  movsbl (%rdi,%rdx,1),%eax
  mov    %edx,%r8d
  cmp    $0x2e,%al
  je     L47
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L12
L10:
  xor    %r8d,%r8d
L47:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int digitstring_fraction(char *left, char *right) {
  int symbol = *left;
  int digits = 0;
  if ((symbol == '+') || (symbol == '-'))
    left++;
  while (left < right) {
    symbol = *left++;
    if (symbol == '.')
      return digits;
    if (symbol < '0')
      break;
    if (symbol > '9')
      break;
    digits++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L3
L28:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,-0x1c(%rbp)
L3:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L28
  cmpl   $0x0,-0x20(%rbp)
  js     L15
  mov    $0x0,%eax
  jmp    L42
L15:
  nop
  mov    $0xffffffff,%eax
L42:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
int main() {
  char in[11];
  int i = 0;
  int j = 0;
  int c = 0;
  while (__VERIFIER_nondet_int()) {
    j = c;
    i = i * 10U + j;
    c = in[i];
  }
  if (!(i >= 0)) {
    goto ERROR;
  }
  return 0;
ERROR:
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L7
L0:
  lea    (%rbx,%rbx,4),%eax
  lea    0x0(%rbp,%rax,2),%eax
  mov    %eax,%ebx
  cltq
  movsbl 0xd(%rsp,%rax,1),%ebp
L7:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L0
  mov    %ebx,%eax
  sar    $0x1f,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char in[11];
  int i = 0;
  int j = 0;
  int c = 0;
  while (__VERIFIER_nondet_int()) {
    j = c;
    i = i * 10U + j;
    c = in[i];
  }
  if (!(i >= 0)) {
    goto ERROR;
  }
  return 0;
ERROR:
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  jmp    L4
L5:
  lea    (%rbx,%rbx,4),%eax
  lea    0x0(%rbp,%rax,2),%ebx
  movslq %ebx,%rax
  movsbl 0xd(%rsp,%rax,1),%ebp
L4:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L5
  mov    %ebx,%eax
  sar    $0x1f,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char in[11];
  int i = 0;
  int j = 0;
  int c = 0;
  while (__VERIFIER_nondet_int()) {
    j = c;
    i = i * 10U + j;
    c = in[i];
  }
  if (!(i >= 0)) {
    goto ERROR;
  }
  return 0;
ERROR:
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  jmp    L20
L1:
  lea    (%rbx,%rbx,4),%eax
  lea    0x0(%rbp,%rax,2),%ebx
  movslq %ebx,%rax
  movsbl 0xd(%rsp,%rax,1),%ebp
L20:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L1
  mov    %ebx,%eax
  sar    $0x1f,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char in[11];
  int i = 0;
  int j = 0;
  int c = 0;
  while (__VERIFIER_nondet_int()) {
    j = c;
    i = i * 10U + j;
    c = in[i];
  }
  if (!(i >= 0)) {
    goto ERROR;
  }
  return 0;
ERROR:
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chrPutc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L0
  cmpq   $0x0,-0x20(%rbp)
  je     L0
  cmpq   $0x0,-0x28(%rbp)
  je     L0
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L0
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  sub    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L48
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L48:
  cmpq   $0x0,-0x10(%rbp)
  je     L0
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <star_strlcpy@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
L0:
  nop
  leave
  ret
```

assistant: ```c
void chrPutc(const char *str1, char *str2, size_t str2_length, size_t *iposn) {
  size_t size1;
  size_t size2;
  if (str1 && str2 && str2_length > 0) {
    size2 = str2_length - 1;
    if (*iposn < size2) {
      size1 = strlen(str1);
      size2 -= *iposn;
      if (size2 < size1)
        size1 = size2;
      if (size1 > 0) {
        star_strlcpy(str2 + *iposn, str1, size1 + 1);
        *iposn += size1;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<chrPutc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%r13
  test   %rsi,%rsi
  setne  %cl
  test   %rdx,%rdx
  setne  %al
  test   %al,%cl
  je     L45
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %rdi,%rdi
  jne    L49
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  lea    -0x1(%rdx),%rbx
  mov    0x0(%r13),%r14
  cmp    %rbx,%r14
  jae    L45
  call   <strlen@plt>
  sub    %r14,%rbx
  cmp    %rax,%rbx
  cmovbe %rbx,%rax
  mov    %rax,%rbx
  test   %rax,%rax
  je     L45
  lea    0x1(%rax),%rdx
  lea    0x0(%rbp,%r14,1),%rdi
  mov    %r12,%rsi
  call   <star_strlcpy@plt>
  add    %rbx,0x0(%r13)
  jmp    L45
```

assistant: ```c
void chrPutc(const char *str1, char *str2, size_t str2_length, size_t *iposn) {
  size_t size1;
  size_t size2;
  if (str1 && str2 && str2_length > 0) {
    size2 = str2_length - 1;
    if (*iposn < size2) {
      size1 = strlen(str1);
      size2 -= *iposn;
      if (size2 < size1)
        size1 = size2;
      if (size1 > 0) {
        star_strlcpy(str2 + *iposn, str1, size1 + 1);
        *iposn += size1;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chrPutc>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  test   %rsi,%rsi
  setne  %cl
  test   %rdx,%rdx
  mov    %rsi,0x8(%rsp)
  setne  %al
  test   %al,%cl
  je     L48
  mov    %rdi,%r12
  test   %rdi,%rdi
  jne    L27
L48:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x0(%r13),%r14
  lea    -0x1(%rdx),%rbx
  cmp    %rbx,%r14
  jae    L48
  call   <strlen@plt>
  sub    %r14,%rbx
  mov    0x8(%rsp),%rsi
  cmp    %rax,%rbx
  cmovbe %rbx,%rax
  test   %rax,%rax
  mov    %rax,%rbx
  je     L48
  lea    (%rsi,%r14,1),%rdi
  lea    0x1(%rax),%rdx
  mov    %r12,%rsi
  call   <star_strlcpy@plt>
  add    %rbx,0x0(%r13)
  jmp    L48
```

assistant: ```c
void chrPutc(const char *str1, char *str2, size_t str2_length, size_t *iposn) {
  size_t size1;
  size_t size2;
  if (str1 && str2 && str2_length > 0) {
    size2 = str2_length - 1;
    if (*iposn < size2) {
      size1 = strlen(str1);
      size2 -= *iposn;
      if (size2 < size1)
        size1 = size2;
      if (size1 > 0) {
        star_strlcpy(str2 + *iposn, str1, size1 + 1);
        *iposn += size1;
      }
    }
  }
}
```