ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<xattrkv_new>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %eax,%eax
  je     L6
  mov    D38(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%edx
  mov    D32(%rip),%rax
  or     (%rax),%edx
  mov    D19(%rip),%rax
  or     (%rax),%edx
  mov    D2(%rip),%rax
  or     (%rax),%edx
  mov    D28(%rip),%rax
  mov    (%rax),%esi
  mov    D21(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbp
  ret
  xchg   %ax,%ax
L6:
  mov    $0xffffffff,%eax
  jmp    L21
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xattrkv_new(char *dbname) {
  struct stat dbs;
  int ok = stat(dbname, &dbs);
  if (ok != 0) {
    int db = open(dbname, O_CREAT | O_RDWR, S_IRUSR | S_IWUSR | S_IRGRP | S_IWGRP);
    return db;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo() {
  int *x;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int foo() {
  int *x;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo() {
  int *x;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo() {
  int *x;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
L6:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%edi
  call   <abs@plt>
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L6
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void itoa(int n, char s[]) {
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itoa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %rsi,%r12
  mov    $0x0,%ebp
L11:
  movslq %edi,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %ebp,%edx
  add    $0x1,%ebp
  add    $0x30,%eax
  mov    %al,(%r12)
  mov    %ebx,%edi
  add    $0x1,%r12
  test   %ebx,%ebx
  jne    L11
  test   %r14d,%r14d
  js     L14
L26:
  movslq %ebp,%rbp
  movb   $0x0,0x0(%r13,%rbp,1)
  mov    %r13,%rdi
  call   <reverse@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  movslq %ebp,%rbp
  movb   $0x2d,0x0(%r13,%rbp,1)
  lea    0x2(%rdx),%ebp
  jmp    L26
```

assistant: ```c
void itoa(int n, char s[]) {
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L15:
  movslq %edi,%rbx
  mov    %edi,%eax
  add    $0x1,%r14
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r13d,%edx
  mov    %ebx,%edi
  add    $0x1,%r13d
  add    $0x30,%eax
  mov    %al,-0x1(%r14)
  test   %ebx,%ebx
  jne    L15
  test   %r12d,%r12d
  jns    L14
  movslq %r13d,%r13
  movb   $0x2d,0x0(%rbp,%r13,1)
  lea    0x2(%rdx),%r13d
L14:
  movslq %r13d,%r13
  pop    %rbx
  mov    %rbp,%rdi
  movb   $0x0,0x0(%rbp,%r13,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <reverse@plt>
```

assistant: ```c
void itoa(int n, char s[]) {
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<itoa>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L4:
  movslq %edi,%rbx
  mov    %edi,%eax
  add    $0x1,%r14
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r13d,%edx
  mov    %ebx,%edi
  add    $0x1,%r13d
  add    $0x30,%eax
  mov    %al,-0x1(%r14)
  test   %ebx,%ebx
  jne    L4
  test   %r12d,%r12d
  jns    L5
  movslq %r13d,%r13
  movb   $0x2d,0x0(%rbp,%r13,1)
  lea    0x2(%rdx),%r13d
L5:
  movslq %r13d,%r13
  pop    %rbx
  mov    %rbp,%rdi
  movb   $0x0,0x0(%rbp,%r13,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <reverse@plt>
```

assistant: ```c
void itoa(int n, char s[]) {
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uninitvar_vsnprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x5c(%rbp)
  mov    -0x34(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x5c(%rbp),%ecx
  mov    -0x58(%rbp),%rdx
  mov    -0x50(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x5c(%rbp),%ecx
  mov    -0x58(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x5c(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x50(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x5c(%rbp),%ecx
  mov    -0x58(%rbp),%rdx
  mov    -0x50(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x34(%rbp),%ecx
  mov    -0x58(%rbp),%rdx
  mov    -0x50(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_vsnprintf(char *S, size_t N, char *Format, va_list Arg) {
  char *s1, *s2;
  size_t n1, n2;
  char *format1, *format2;
  va_list arg;
  (void)vsnprintf(s1, n1, format1, arg);
  (void)vsnprintf(s2, N, Format, Arg);
  (void)vsnprintf(S, n2, Format, Arg);
  (void)vsnprintf(S, N, format2, Arg);
  (void)vsnprintf(S, N, Format, Arg);
  (void)vsnprintf(S, N, Format, arg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninitvar_vsnprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    $0x0,%r14d
  mov    %r14d,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void uninitvar_vsnprintf(char *S, size_t N, char *Format, va_list Arg) {
  char *s1, *s2;
  size_t n1, n2;
  char *format1, *format2;
  va_list arg;
  (void)vsnprintf(s1, n1, format1, arg);
  (void)vsnprintf(s2, N, Format, Arg);
  (void)vsnprintf(S, n2, Format, Arg);
  (void)vsnprintf(S, N, format2, Arg);
  (void)vsnprintf(S, N, Format, Arg);
  (void)vsnprintf(S, N, Format, arg);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uninitvar_vsnprintf>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %ecx,%r14d
  mov    %r15d,%ecx
  push   %r13
  mov    %rdx,%r13
  xor    %edx,%edx
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <vsnprintf@plt>
```

assistant: ```c
void uninitvar_vsnprintf(char *S, size_t N, char *Format, va_list Arg) {
  char *s1, *s2;
  size_t n1, n2;
  char *format1, *format2;
  va_list arg;
  (void)vsnprintf(s1, n1, format1, arg);
  (void)vsnprintf(s2, N, Format, Arg);
  (void)vsnprintf(S, n2, Format, Arg);
  (void)vsnprintf(S, N, format2, Arg);
  (void)vsnprintf(S, N, Format, Arg);
  (void)vsnprintf(S, N, Format, arg);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<uninitvar_vsnprintf>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %ecx,%r14d
  mov    %r15d,%ecx
  push   %r13
  mov    %rdx,%r13
  xor    %edx,%edx
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <vsnprintf@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <vsnprintf@plt>
```

assistant: ```c
void uninitvar_vsnprintf(char *S, size_t N, char *Format, va_list Arg) {
  char *s1, *s2;
  size_t n1, n2;
  char *format1, *format2;
  va_list arg;
  (void)vsnprintf(s1, n1, format1, arg);
  (void)vsnprintf(s2, N, Format, Arg);
  (void)vsnprintf(S, n2, Format, Arg);
  (void)vsnprintf(S, N, format2, Arg);
  (void)vsnprintf(S, N, Format, Arg);
  (void)vsnprintf(S, N, Format, arg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ShiftRows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x5(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x5(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x9(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x9(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xd(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xd(%rax),%rdx
  movzbl -0x2(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x6(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xa(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x6(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xe(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xa(%rax),%rdx
  movzbl -0x2(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xe(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0xf(%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0xf(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xb(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xb(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x7(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x7(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x2(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ShiftRows(unsigned char state[16]) {
  unsigned char temp;
  unsigned char temp2;
  temp = state[1];
  state[1] = state[5];
  state[5] = state[9];
  state[9] = state[13];
  state[13] = temp;
  temp = state[2];
  temp2 = state[6];
  state[2] = state[10];
  state[6] = state[14];
  state[10] = temp;
  state[14] = temp2;
  temp = state[15];
  state[15] = state[11];
  state[11] = state[7];
  state[7] = state[3];
  state[3] = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ShiftRows>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x1(%rdi)
  movzbl 0x9(%rdi),%edx
  mov    %dl,0x5(%rdi)
  movzbl 0xd(%rdi),%edx
  mov    %dl,0x9(%rdi)
  mov    %al,0xd(%rdi)
  movzbl 0x2(%rdi),%edx
  movzbl 0x6(%rdi),%eax
  movzbl 0xa(%rdi),%ecx
  mov    %cl,0x2(%rdi)
  movzbl 0xe(%rdi),%ecx
  mov    %cl,0x6(%rdi)
  mov    %dl,0xa(%rdi)
  mov    %al,0xe(%rdi)
  movzbl 0xf(%rdi),%eax
  movzbl 0xb(%rdi),%edx
  mov    %dl,0xf(%rdi)
  movzbl 0x7(%rdi),%edx
  mov    %dl,0xb(%rdi)
  movzbl 0x3(%rdi),%edx
  mov    %dl,0x7(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void ShiftRows(unsigned char state[16]) {
  unsigned char temp;
  unsigned char temp2;
  temp = state[1];
  state[1] = state[5];
  state[5] = state[9];
  state[9] = state[13];
  state[13] = temp;
  temp = state[2];
  temp2 = state[6];
  state[2] = state[10];
  state[6] = state[14];
  state[10] = temp;
  state[14] = temp2;
  temp = state[15];
  state[15] = state[11];
  state[11] = state[7];
  state[7] = state[3];
  state[3] = temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ShiftRows>:
  endbr64
  movzbl 0x5(%rdi),%edx
  movzbl 0x1(%rdi),%eax
  movzbl 0xa(%rdi),%ecx
  mov    %dl,0x1(%rdi)
  movzbl 0x9(%rdi),%edx
  mov    %dl,0x5(%rdi)
  movzbl 0xd(%rdi),%edx
  mov    %al,0xd(%rdi)
  movzbl 0x6(%rdi),%eax
  mov    %dl,0x9(%rdi)
  movzbl 0x2(%rdi),%edx
  mov    %cl,0x2(%rdi)
  movzbl 0xe(%rdi),%ecx
  mov    %dl,0xa(%rdi)
  movzbl 0xb(%rdi),%edx
  mov    %al,0xe(%rdi)
  movzbl 0xf(%rdi),%eax
  mov    %dl,0xf(%rdi)
  movzbl 0x7(%rdi),%edx
  mov    %cl,0x6(%rdi)
  mov    %dl,0xb(%rdi)
  movzbl 0x3(%rdi),%edx
  mov    %al,0x3(%rdi)
  mov    %dl,0x7(%rdi)
  ret
```

assistant: ```c
void ShiftRows(unsigned char state[16]) {
  unsigned char temp;
  unsigned char temp2;
  temp = state[1];
  state[1] = state[5];
  state[5] = state[9];
  state[9] = state[13];
  state[13] = temp;
  temp = state[2];
  temp2 = state[6];
  state[2] = state[10];
  state[6] = state[14];
  state[10] = temp;
  state[14] = temp2;
  temp = state[15];
  state[15] = state[11];
  state[11] = state[7];
  state[7] = state[3];
  state[3] = temp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ShiftRows>:
  endbr64
  movzbl 0x5(%rdi),%edx
  movzbl 0x1(%rdi),%eax
  movzbl 0xa(%rdi),%ecx
  mov    %dl,0x1(%rdi)
  movzbl 0x9(%rdi),%edx
  mov    %dl,0x5(%rdi)
  movzbl 0xd(%rdi),%edx
  mov    %al,0xd(%rdi)
  movzbl 0x6(%rdi),%eax
  mov    %dl,0x9(%rdi)
  movzbl 0x2(%rdi),%edx
  mov    %cl,0x2(%rdi)
  movzbl 0xe(%rdi),%ecx
  mov    %dl,0xa(%rdi)
  movzbl 0xb(%rdi),%edx
  mov    %al,0xe(%rdi)
  movzbl 0xf(%rdi),%eax
  mov    %dl,0xf(%rdi)
  movzbl 0x7(%rdi),%edx
  mov    %cl,0x6(%rdi)
  mov    %dl,0xb(%rdi)
  movzbl 0x3(%rdi),%edx
  mov    %al,0x3(%rdi)
  mov    %dl,0x7(%rdi)
  ret
```

assistant: ```c
void ShiftRows(unsigned char state[16]) {
  unsigned char temp;
  unsigned char temp2;
  temp = state[1];
  state[1] = state[5];
  state[5] = state[9];
  state[9] = state[13];
  state[13] = temp;
  temp = state[2];
  temp2 = state[6];
  state[2] = state[10];
  state[6] = state[14];
  state[10] = temp;
  state[14] = temp2;
  temp = state[15];
  state[15] = state[11];
  state[11] = state[7];
  state[7] = state[3];
  state[3] = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wrap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int wrap(char *buf, int len, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = vsnprintf(buf, len, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wrap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int wrap(char *buf, int len, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = vsnprintf(buf, len, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wrap>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int wrap(char *buf, int len, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = vsnprintf(buf, len, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wrap>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int wrap(char *buf, int len, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = vsnprintf(buf, len, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_210_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_210_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_210_1_1>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  movzbl %sil,%edx
  mov    %edx,%esi
  shl    $0x8,%esi
  or     %edx,%esi
  mov    %eax,%edx
  not    %edx
  movzbl %dl,%edx
  xor    %esi,%edx
  or     %esi,%eax
  mov    %edx,%ecx
  xor    $0xff,%cl
  and    %ecx,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_210_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrop3_210_1_1>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%edx
  mov    %edi,%eax
  mov    %edx,%esi
  shl    $0x8,%eax
  shl    $0x8,%esi
  or     %edi,%eax
  or     %edx,%esi
  mov    %eax,%edx
  or     %esi,%eax
  not    %edx
  movzbl %dl,%edx
  xor    %esi,%edx
  mov    %edx,%ecx
  xor    $0xff,%cl
  and    %ecx,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_210_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```