ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<waitConexion>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x10,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <accept@plt>
  mov    %eax,(%rbx)
  cmp    $0xffffffff,%eax
  je     L7
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%edi
  call   <inet_ntoa@plt>
  mov    %eax,%esi
  lea    0x20(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L7:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x50,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D29
type_infered: string
name: parse_data
arguments: tag: D15
type_infered: string
name: parse_data
arguments: tag: D16
type_infered: string

tool: D29: I have been connected from:

tool: D15: 	IP address: %s


tool: D16: 	port: %u


assistant: ```c
int waitConexion(int serverSock, int *psockConnection) {
  struct sockaddr_in cAddr;
  socklen_t sockLen;
  char str[30];
  sockLen = sizeof(cAddr);
  if ((*psockConnection = accept(serverSock, (struct sockaddr *)&cAddr, &sockLen)) == -1) {
    return -1;
  }
  printf("I have been connected from:\n");
  strcpy(str, inet_ntoa(cAddr.sin_addr));
  printf("\tIP address: %s\n", str);
  printf("\tport: %u\n", (unsigned int)cAddr.sin_port);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<waitConexion>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  movl   $0x10,0xc(%rsp)
  call   <accept@plt>
  mov    %eax,(%rbx)
  cmp    $0xffffffff,%eax
  je     L11
  lea    D16(%rip),%rdi
  lea    0x20(%rsp),%rbp
  call   <puts@plt>
  mov    0x18(%rsp),%edi
  call   <inet_ntoa@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L11:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string

tool: D16: I have been connected from:

tool: D25: 	IP address: %s


tool: D15: 	port: %u


assistant: ```c
int waitConexion(int serverSock, int *psockConnection) {
  struct sockaddr_in cAddr;
  socklen_t sockLen;
  char str[30];
  sockLen = sizeof(cAddr);
  if ((*psockConnection = accept(serverSock, (struct sockaddr *)&cAddr, &sockLen)) == -1) {
    return -1;
  }
  printf("I have been connected from:\n");
  strcpy(str, inet_ntoa(cAddr.sin_addr));
  printf("\tIP address: %s\n", str);
  printf("\tport: %u\n", (unsigned int)cAddr.sin_port);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<waitConexion>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  movl   $0x10,0xc(%rsp)
  call   <accept@plt>
  mov    %eax,(%rbx)
  cmp    $0xffffffff,%eax
  je     L3
  lea    D4(%rip),%rdi
  lea    0x20(%rsp),%rbp
  call   <puts@plt>
  mov    0x18(%rsp),%edi
  call   <inet_ntoa@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L3:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string

tool: D4: I have been connected from:

tool: D11: 	IP address: %s


tool: D10: 	port: %u


assistant: ```c
int waitConexion(int serverSock, int *psockConnection) {
  struct sockaddr_in cAddr;
  socklen_t sockLen;
  char str[30];
  sockLen = sizeof(cAddr);
  if ((*psockConnection = accept(serverSock, (struct sockaddr *)&cAddr, &sockLen)) == -1) {
    return -1;
  }
  printf("I have been connected from:\n");
  strcpy(str, inet_ntoa(cAddr.sin_addr));
  printf("\tIP address: %s\n", str);
  printf("\tport: %u\n", (unsigned int)cAddr.sin_port);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L36
L11:
  lea    D4(%rip),%rax
L36:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D7
type: string

tool: D4: NULL

tool: D7: %s = %s


assistant: ```c
int callback(void *NotUsed, int argc, char **argv, char **azColName) {
  int i;
  for (i = 0; i < argc; ++i) {
    printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<callback>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L13
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D12(%rip),%r15
  lea    D13(%rip),%r14
L12:
  mov    (%r12,%rbx,8),%rdx
  test   %rdx,%rdx
  cmove  %r15,%rdx
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string

tool: D12: NULL

tool: D13: %s = %s


assistant: ```c
int callback(void *NotUsed, int argc, char **argv, char **azColName) {
  int i;
  for (i = 0; i < argc; ++i) {
    printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<callback>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L14
  mov    %rdx,%r12
  mov    %rcx,%r15
  movslq %esi,%rbp
  xor    %ebx,%ebx
  lea    D15(%rip),%r14
  lea    D12(%rip),%r13
  nop
L8:
  mov    (%r12,%rbx,8),%rdx
  mov    (%r15,%rbx,8),%rsi
  mov    %r14,%rdi
  test   %rdx,%rdx
  cmove  %r13,%rdx
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L8
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D12
type_infered: string

tool: D15: %s = %s


tool: D12: NULL

assistant: ```c
int callback(void *NotUsed, int argc, char **argv, char **azColName) {
  int i;
  for (i = 0; i < argc; ++i) {
    printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<callback>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L20
  mov    %rdx,%r12
  mov    %rcx,%r15
  movslq %esi,%rbp
  xor    %ebx,%ebx
  lea    D10(%rip),%r13
  lea    D4(%rip),%r14
  jmp    L2
  nopl   0x0(%rax)
L43:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L20
L2:
  mov    (%r12,%rbx,8),%rdx
  mov    (%r15,%rbx,8),%rsi
  test   %rdx,%rdx
  jne    L43
  mov    %r14,%rdx
  jmp    L43
  nopl   (%rax)
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D10
type: string
name: read_data
arguments: tag: D4
type: string

tool: D10: %s = %s


tool: D4: NULL

assistant: ```c
int callback(void *NotUsed, int argc, char **argv, char **azColName) {
  int i;
  for (i = 0; i < argc; ++i) {
    printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L24
L25:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L24:
  cmpl   $0x0,-0x10(%rbp)
  jne    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D27
type: string
name: read_data
arguments: data_tag: D24
type: string

tool: D27: %d

tool: D24: Revrse of %d is 

assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  printf("Revrse of %d is ", a);
  for (int i = a; i != 0; i = i / 10) {
    int rem = i % 10;
    printf("%d", rem);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L29
  lea    D12(%rip),%rbp
L23:
  movslq %esi,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  test   %ebx,%ebx
  jne    L23
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type: string
name: disassemble_data
arguments: data_label: D18
type: string

tool: D12: %d

tool: D18: Revrse of %d is 

assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  printf("Revrse of %d is ", a);
  for (int i = a; i != 0; i = i / 10) {
    int rem = i % 10;
    printf("%d", rem);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L18
  cs nopw 0x0(%rax,%rax,1)
L0:
  movslq %esi,%rbx
  mov    %esi,%eax
  mov    %rbp,%rdi
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  call   <printf@plt>
  mov    %ebx,%esi
  test   %ebx,%ebx
  jne    L0
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: string

tool: D12: %d

tool: D11: Revrse of %d is 

assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  printf("Revrse of %d is ", a);
  for (int i = a; i != 0; i = i / 10) {
    int rem = i % 10;
    printf("%d", rem);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L2
  cs nopw 0x0(%rax,%rax,1)
L22:
  movslq %esi,%rbx
  mov    %esi,%eax
  mov    %rbp,%rdi
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  call   <printf@plt>
  mov    %ebx,%esi
  test   %ebx,%ebx
  jne    L22
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D15: %d

tool: D1: Revrse of %d is 

assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  printf("Revrse of %d is ", a);
  for (int i = a; i != 0; i = i / 10) {
    int rem = i % 10;
    printf("%d", rem);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sgn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L3
  mov    $0x0,%eax
  jmp    L34
L3:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L30
  mov    $0xffffffff,%eax
  jmp    L34
L30:
  mov    $0x1,%eax
L34:
  leave
  ret
```

assistant: ```c
int sgn(double x) {
  if (fabs(x) < 1e-14)
    return 0;
  else if (x < 0)
    return -1;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sgn>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <fabs@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jle    L2
  pxor   %xmm0,%xmm0
  movq   %rbx,%xmm1
  comisd %xmm1,%xmm0
  mov    $0xffffffff,%eax
  mov    $0x1,%edx
  cmovbe %edx,%eax
L2:
  pop    %rbx
  ret
```

assistant: ```c
int sgn(double x) {
  if (fabs(x) < 1e-14)
    return 0;
  else if (x < 0)
    return -1;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sgn>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <fabs@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jle    L9
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  mov    $0xffffffff,%eax
  mov    $0x1,%edx
  comisd %xmm0,%xmm1
  cmovbe %edx,%eax
L9:
  add    $0x18,%rsp
  ret
```

assistant: ```c
int sgn(double x) {
  if (fabs(x) < 1e-14)
    return 0;
  else if (x < 0)
    return -1;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sgn>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <fabs@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jle    L1
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  mov    $0xffffffff,%eax
  mov    $0x1,%edx
  comisd %xmm0,%xmm1
  cmovbe %edx,%eax
L1:
  add    $0x18,%rsp
  ret
```

assistant: ```c
int sgn(double x) {
  if (fabs(x) < 1e-14)
    return 0;
  else if (x < 0)
    return -1;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_001@plt>
  mov    $0x0,%eax
  call   <test_002@plt>
  mov    $0x0,%eax
  call   <test_003@plt>
  mov    $0x0,%eax
  call   <test_004@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_001();
  test_002();
  test_003();
  test_004();
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_001@plt>
  mov    $0x0,%eax
  call   <test_002@plt>
  mov    $0x0,%eax
  call   <test_003@plt>
  mov    $0x0,%eax
  call   <test_004@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_001();
  test_002();
  test_003();
  test_004();
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_001@plt>
  xor    %eax,%eax
  call   <test_002@plt>
  xor    %eax,%eax
  call   <test_003@plt>
  xor    %eax,%eax
  call   <test_004@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_001();
  test_002();
  test_003();
  test_004();
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_001@plt>
  xor    %eax,%eax
  call   <test_002@plt>
  xor    %eax,%eax
  call   <test_003@plt>
  xor    %eax,%eax
  call   <test_004@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_001();
  test_002();
  test_003();
  test_004();
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<irc_info_info_irc_nick_color_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <irc_nick_find_color@plt>
  jmp    L0
L18:
  mov    $0x0,%eax
L0:
  leave
  ret
```

assistant: ```c
const char *irc_info_info_irc_nick_color_cb(void *data, const char *info_name, const char *arguments) {
  (void)data;
  (void)info_name;
  return (arguments && arguments[0]) ? irc_nick_find_color(arguments) : NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<irc_info_info_irc_nick_color_cb>:
  endbr64
  test   %rdx,%rdx
  je     L2
  mov    $0x0,%eax
  cmpb   $0x0,(%rdx)
  je     L16
  sub    $0x8,%rsp
  mov    %rdx,%rdi
  call   <irc_nick_find_color@plt>
  add    $0x8,%rsp
  ret
L2:
  mov    %rdx,%rax
  ret
L16:
  ret
```

assistant: ```c
const char *irc_info_info_irc_nick_color_cb(void *data, const char *info_name, const char *arguments) {
  (void)data;
  (void)info_name;
  return (arguments && arguments[0]) ? irc_nick_find_color(arguments) : NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<irc_info_info_irc_nick_color_cb>:
  endbr64
  mov    %rdx,%rdi
  test   %rdx,%rdx
  je     L16
  cmpb   $0x0,(%rdx)
  je     L16
  jmp    1050 <irc_nick_find_color@plt>
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *irc_info_info_irc_nick_color_cb(void *data, const char *info_name, const char *arguments) {
  (void)data;
  (void)info_name;
  return (arguments && arguments[0]) ? irc_nick_find_color(arguments) : NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<irc_info_info_irc_nick_color_cb>:
  endbr64
  mov    %rdx,%rdi
  test   %rdx,%rdx
  je     L10
  cmpb   $0x0,(%rdx)
  je     L10
  jmp    1050 <irc_nick_find_color@plt>
  cs nopw 0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *irc_info_info_irc_nick_color_cb(void *data, const char *info_name, const char *arguments) {
  (void)data;
  (void)info_name;
  return (arguments && arguments[0]) ? irc_nick_find_color(arguments) : NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_cmd_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L24:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L25
  addl   $0x1,-0x8(%rbp)
L25:
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L24
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_cmd_count(char *cmds) {
  int len = strlen(cmds);
  int i;
  int cmd_count = 0;
  for (i = 0; i < len; i++) {
    if (cmds[i] == '\n') {
      cmd_count++;
    }
  }
  return cmd_count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_cmd_count>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L10
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%eax
L12:
  cmpb   $0xa,(%rdx)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L12
L2:
  pop    %rbx
  ret
L10:
  mov    $0x0,%eax
  jmp    L2
```

assistant: ```c
int get_cmd_count(char *cmds) {
  int len = strlen(cmds);
  int i;
  int cmd_count = 0;
  for (i = 0; i < len; i++) {
    if (cmds[i] == '\n') {
      cmd_count++;
    }
  }
  return cmd_count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_cmd_count>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L2:
  xor    %edx,%edx
  cmpb   $0xa,(%rdi)
  sete   %dl
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L2
  pop    %rbx
  ret
  nopl   (%rax)
L9:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int get_cmd_count(char *cmds) {
  int len = strlen(cmds);
  int i;
  int cmd_count = 0;
  for (i = 0; i < len; i++) {
    if (cmds[i] == '\n') {
      cmd_count++;
    }
  }
  return cmd_count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ls_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L13
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L13:
  leave
  ret
```

assistant: ```c
size_t ls_strlen(const char *a) {
  if (a == NULL) {
    return 0;
  }
  return strlen(a);
}
```