ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isJFC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  D60(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L10
  mov    $0x0,%eax
  jmp    L26
L10:
  movsd  D81(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x20(%rbp),%xmm1
  movsd  D64(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D81(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  D64(%rip),%xmm1
  movapd %xmm0,%xmm4
  divsd  %xmm1,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm5
  addsd  %xmm0,%xmm5
  movsd  %xmm5,-0x38(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  D45(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D46(%rip),%xmm1
  movapd %xmm0,%xmm6
  divsd  %xmm1,%xmm6
  movq   %xmm6,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x38(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D73(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L23
  movsd  -0x8(%rbp),%xmm0
  comisd D16(%rip),%xmm0
  jbe    L23
  mov    $0x1,%eax
  jmp    L47
L23:
  mov    $0x0,%eax
L47:
  and    $0x1,%eax
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D60
type: f64
name: extract_symbolic_data
arguments: tag: D81
type: f64
name: extract_symbolic_data
arguments: tag: D64
type: f64
name: extract_symbolic_data
arguments: tag: D45
type: f64
name: extract_symbolic_data
arguments: tag: D46
type: f64
name: extract_symbolic_data
arguments: tag: D73
type: byte[8]
name: extract_symbolic_data
arguments: tag: D16
type: f64

tool: D60: 1.3

tool: D81: 1

tool: D64: 5.2

tool: D45: 3.141592653589793

tool: D46: 180

tool: {"D73": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D16: 2

assistant: ```c
_Bool isJFC(double q, double e, double i) {
  if (q < 1.3)
    return 0;
  double t = 5.2 * (1 - e) / q + 2 * sqrt(q * (1 + e) / 5.2) * cos(i * 3.14159265358979323846264338327 / 180.);
  return t < 3 && t > 2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isJFC>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm2,%rbx
  mov    $0x0,%eax
  movsd  D23(%rip),%xmm2
  comisd %xmm0,%xmm2
  jbe    L5
L8:
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  movsd  D31(%rip),%xmm4
  movapd %xmm4,%xmm2
  subsd  %xmm1,%xmm2
  movsd  D39(%rip),%xmm3
  mulsd  %xmm3,%xmm2
  divsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rsp)
  addsd  %xmm4,%xmm1
  mulsd  %xmm0,%xmm1
  divsd  %xmm3,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L24
  sqrtsd %xmm1,%xmm1
  movsd  %xmm1,(%rsp)
L26:
  movq   %rbx,%xmm0
  mulsd  D5(%rip),%xmm0
  divsd  D44(%rip),%xmm0
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  D14(%rip),%xmm1
  mov    $0x0,%eax
  comisd %xmm0,%xmm1
  jbe    L4
  comisd D54(%rip),%xmm0
  seta   %al
  movzbl %al,%eax
L4:
  and    $0x1,%eax
  jmp    L8
L24:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movsd  %xmm0,(%rsp)
  jmp    L26
```

tool_calls: name: parse_data
arguments: data_label: D23
type_guessed: f64
name: parse_data
arguments: data_label: D31
type_guessed: f64
name: parse_data
arguments: data_label: D39
type_guessed: f64
name: parse_data
arguments: data_label: D5
type_guessed: f64
name: parse_data
arguments: data_label: D44
type_guessed: f64
name: parse_data
arguments: data_label: D14
type_guessed: byte[8]
name: parse_data
arguments: data_label: D54
type_guessed: f64

tool: D23: 1.3

tool: D31: 1

tool: D39: 5.2

tool: D5: 3.141592653589793

tool: D44: 180

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D54: 2

assistant: ```c
_Bool isJFC(double q, double e, double i) {
  if (q < 1.3)
    return 0;
  double t = 5.2 * (1 - e) / q + 2 * sqrt(q * (1 + e) / 5.2) * cos(i * 3.14159265358979323846264338327 / 180.);
  return t < 3 && t > 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isJFC>:
  endbr64
  movsd  D54(%rip),%xmm3
  xor    %eax,%eax
  comisd %xmm0,%xmm3
  jbe    L28
  ret
  nopl   (%rax)
L28:
  sub    $0x18,%rsp
  movsd  D30(%rip),%xmm5
  movsd  D2(%rip),%xmm4
  movapd %xmm5,%xmm3
  subsd  %xmm1,%xmm3
  addsd  %xmm5,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm4,%xmm3
  divsd  %xmm4,%xmm1
  divsd  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  movsd  %xmm3,(%rsp)
  ja     L36
  sqrtsd %xmm1,%xmm1
L4:
  mulsd  D33(%rip),%xmm2
  movsd  %xmm1,0x8(%rsp)
  divsd  D66(%rip),%xmm2
  movapd %xmm2,%xmm0
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm1
  xor    %eax,%eax
  addsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D29(%rip),%xmm0
  addsd  (%rsp),%xmm1
  comisd %xmm1,%xmm0
  jbe    L37
  comisd D12(%rip),%xmm1
  seta   %al
L37:
  add    $0x18,%rsp
  ret
L36:
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: tag: D54
type: f64
name: disassemble_data
arguments: tag: D30
type: f64
name: disassemble_data
arguments: tag: D2
type: f64
name: disassemble_data
arguments: tag: D33
type: f64
name: disassemble_data
arguments: tag: D66
type: f64
name: disassemble_data
arguments: tag: D29
type: byte[8]
name: disassemble_data
arguments: tag: D12
type: f64

tool: D54: 1.3

tool: D30: 1

tool: D2: 5.2

tool: D33: 3.141592653589793

tool: D66: 180

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D12: 2

assistant: ```c
_Bool isJFC(double q, double e, double i) {
  if (q < 1.3)
    return 0;
  double t = 5.2 * (1 - e) / q + 2 * sqrt(q * (1 + e) / 5.2) * cos(i * 3.14159265358979323846264338327 / 180.);
  return t < 3 && t > 2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isJFC>:
  endbr64
  movsd  D27(%rip),%xmm3
  xor    %eax,%eax
  comisd %xmm0,%xmm3
  jbe    L34
  ret
  nopl   (%rax)
L34:
  sub    $0x18,%rsp
  movsd  D12(%rip),%xmm5
  movsd  D14(%rip),%xmm4
  movapd %xmm5,%xmm3
  subsd  %xmm1,%xmm3
  addsd  %xmm5,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm4,%xmm3
  divsd  %xmm4,%xmm1
  divsd  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  movsd  %xmm3,(%rsp)
  ja     L3
  sqrtsd %xmm1,%xmm1
L35:
  mulsd  D7(%rip),%xmm2
  movsd  %xmm1,0x8(%rsp)
  divsd  D54(%rip),%xmm2
  movapd %xmm2,%xmm0
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm1
  xor    %eax,%eax
  addsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D53(%rip),%xmm0
  addsd  (%rsp),%xmm1
  comisd %xmm1,%xmm0
  jbe    L16
  comisd D68(%rip),%xmm1
  seta   %al
L16:
  add    $0x18,%rsp
  ret
L3:
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L35
```

tool_calls: name: disassemble_data
arguments: tag: D27
type_guessed: f64
name: disassemble_data
arguments: tag: D12
type_guessed: f64
name: disassemble_data
arguments: tag: D14
type_guessed: f64
name: disassemble_data
arguments: tag: D7
type_guessed: f64
name: disassemble_data
arguments: tag: D54
type_guessed: f64
name: disassemble_data
arguments: tag: D53
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D68
type_guessed: f64

tool: D27: 1.3

tool: D12: 1

tool: D14: 5.2

tool: D7: 3.141592653589793

tool: D54: 180

tool: {"D53": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D68: 2

assistant: ```c
_Bool isJFC(double q, double e, double i) {
  if (q < 1.3)
    return 0;
  double t = 5.2 * (1 - e) / q + 2 * sqrt(q * (1 + e) / 5.2) * cos(i * 3.14159265358979323846264338327 / 180.);
  return t < 3 && t > 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dec_to_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L11
L16:
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L11:
  cmpl   $0x0,-0xc(%rbp)
  jne    L16
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *dec_to_bin(int number) {
  char *digits;
  int n_digits;
  int i;
  int copy;
  i = 0;
  copy = number;
  while (copy) {
    digits[i] = copy % 2;
    copy /= 2;
    i++;
  }
  return digits;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dec_to_bin>:
  endbr64
  test   %edi,%edi
  je     L19
L13:
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  mov    %eax,%edi
  jne    L13
L19:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *dec_to_bin(int number) {
  char *digits;
  int n_digits;
  int i;
  int copy;
  i = 0;
  copy = number;
  while (copy) {
    digits[i] = copy % 2;
    copy /= 2;
    i++;
  }
  return digits;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dec_to_bin>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *dec_to_bin(int number) {
  char *digits;
  int n_digits;
  int i;
  int copy;
  i = 0;
  copy = number;
  while (copy) {
    digits[i] = copy % 2;
    copy /= 2;
    i++;
  }
  return digits;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dec_to_bin>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *dec_to_bin(int number) {
  char *digits;
  int n_digits;
  int i;
  int copy;
  i = 0;
  copy = number;
  while (copy) {
    digits[i] = copy % 2;
    copy /= 2;
    i++;
  }
  return digits;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_app_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    %rax,%rcx
  mov    $0x3,%edx
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <concatenate@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D18: app_dir_path

tool: D7: %s/usercache/%s/appcache/%s

assistant: ```c
char *get_app_directory(const char *nm_root, const char *user, const char *app_id) {
  return concatenate("%s/usercache/%s"
                     "/appcache/%s",
                     "app_dir_path", 3, nm_root, user, app_id);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_app_directory>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%r8
  mov    %rdx,%r9
  mov    $0x3,%edx
  lea    D4(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <concatenate@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string
name: parse_data
arguments: label: D3
data_type: string

tool: D4: app_dir_path

tool: D3: %s/usercache/%s/appcache/%s

assistant: ```c
char *get_app_directory(const char *nm_root, const char *user, const char *app_id) {
  return concatenate("%s/usercache/%s"
                     "/appcache/%s",
                     "app_dir_path", 3, nm_root, user, app_id);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_app_directory>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%r8
  lea    D18(%rip),%rdi
  mov    %rdx,%r9
  lea    D19(%rip),%rsi
  mov    $0x3,%edx
  jmp    1050 <concatenate@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string

tool: D18: %s/usercache/%s/appcache/%s

tool: D19: app_dir_path

assistant: ```c
char *get_app_directory(const char *nm_root, const char *user, const char *app_id) {
  return concatenate("%s/usercache/%s"
                     "/appcache/%s",
                     "app_dir_path", 3, nm_root, user, app_id);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_app_directory>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%r8
  lea    D18(%rip),%rdi
  mov    %rdx,%r9
  lea    D2(%rip),%rsi
  mov    $0x3,%edx
  jmp    1050 <concatenate@plt>
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D2
datatype: string

tool: D18: %s/usercache/%s/appcache/%s

tool: D2: app_dir_path

assistant: ```c
char *get_app_directory(const char *nm_root, const char *user, const char *app_id) {
  return concatenate("%s/usercache/%s"
                     "/appcache/%s",
                     "app_dir_path", 3, nm_root, user, app_id);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<draw_vert_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L15
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    $0xf800,%ecx
  mov    %eax,%edi
  call   <ili9340_draw_line_v@plt>
  jmp    L9
L15:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <ili9340_draw_line_v@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void draw_vert_line(int x, int y, int h, int color_mode) {
  if (color_mode) {
    ili9340_draw_line_v(x, y, h, 0xF800);
  } else {
    ili9340_draw_line_v(x, y, h, 0x0000);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<draw_vert_line>:
  endbr64
  sub    $0x8,%rsp
  test   %ecx,%ecx
  je     L15
  mov    $0xf800,%ecx
  call   <ili9340_draw_line_v@plt>
L14:
  add    $0x8,%rsp
  ret
L15:
  mov    $0x0,%ecx
  call   <ili9340_draw_line_v@plt>
  jmp    L14
```

assistant: ```c
void draw_vert_line(int x, int y, int h, int color_mode) {
  if (color_mode) {
    ili9340_draw_line_v(x, y, h, 0xF800);
  } else {
    ili9340_draw_line_v(x, y, h, 0x0000);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<draw_vert_line>:
  endbr64
  test   %ecx,%ecx
  je     L2
  mov    $0xf800,%ecx
  jmp    1050 <ili9340_draw_line_v@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %ecx,%ecx
  jmp    1050 <ili9340_draw_line_v@plt>
```

assistant: ```c
void draw_vert_line(int x, int y, int h, int color_mode) {
  if (color_mode) {
    ili9340_draw_line_v(x, y, h, 0xF800);
  } else {
    ili9340_draw_line_v(x, y, h, 0x0000);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<draw_vert_line>:
  endbr64
  test   %ecx,%ecx
  je     L4
  mov    $0xf800,%ecx
  jmp    1050 <ili9340_draw_line_v@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %ecx,%ecx
  jmp    1050 <ili9340_draw_line_v@plt>
```

assistant: ```c
void draw_vert_line(int x, int y, int h, int color_mode) {
  if (color_mode) {
    ili9340_draw_line_v(x, y, h, 0xF800);
  } else {
    ili9340_draw_line_v(x, y, h, 0x0000);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <sysloglevel@plt>
  mov    %eax,%ecx
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <vsyslog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void debug(int level, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(sysloglevel(level), format, ap);
  va_end(ap);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<debug>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %r12d,%edi
  call   <sysloglevel@plt>
  mov    %eax,%edi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <vsyslog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug(int level, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(sysloglevel(level), format, ap);
  va_end(ap);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<debug>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edi
  call   <sysloglevel@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void debug(int level, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(sysloglevel(level), format, ap);
  va_end(ap);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_194_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  notl   -0xc(%rbp)
  mov    -0x10(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_194_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D | S;
  stk3 = ~stk3;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_194_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  or     %edi,%eax
  not    %eax
  mov    %edi,%edx
  or     $0xff,%dl
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_194_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D | S;
  stk3 = ~stk3;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xrop3_194_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  mov    %edi,%edx
  or     %esi,%eax
  or     $0xff,%dl
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  and    %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_194_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D | S;
  stk3 = ~stk3;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_194_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  mov    %edi,%edx
  or     %esi,%eax
  or     $0xff,%dl
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  and    %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_194_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D | S;
  stk3 = ~stk3;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x130,%edi
  call   <hash@plt>
  mov    %eax,%r12d
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %eax,%ebx
  mov    $0xdeadbeef,%edi
  call   <hash@plt>
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: Hash results are %x, %x, %x


assistant: ```c
int main(int argc, char **argv) {
  printf("Hash results are %x, %x, %x\n", hash(0xdeadbeef), hash(0x00000001), hash(0x00000130));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x130,%edi
  call   <hash@plt>
  mov    %eax,%ebp
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %eax,%ebx
  mov    $0xdeadbeef,%edi
  call   <hash@plt>
  mov    %eax,%esi
  mov    %ebp,%ecx
  mov    %ebx,%edx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: Hash results are %x, %x, %x


assistant: ```c
int main(int argc, char **argv) {
  printf("Hash results are %x, %x, %x\n", hash(0xdeadbeef), hash(0x00000001), hash(0x00000130));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x130,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <hash@plt>
  mov    $0x1,%edi
  mov    %eax,%r13d
  call   <hash@plt>
  mov    $0xdeadbeef,%edi
  mov    %eax,%r12d
  call   <hash@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4: Hash results are %x, %x, %x


assistant: ```c
int main(int argc, char **argv) {
  printf("Hash results are %x, %x, %x\n", hash(0xdeadbeef), hash(0x00000001), hash(0x00000130));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x130,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <hash@plt>
  mov    $0x1,%edi
  mov    %eax,%r13d
  call   <hash@plt>
  mov    $0xdeadbeef,%edi
  mov    %eax,%r12d
  call   <hash@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: Hash results are %x, %x, %x


assistant: ```c
int main(int argc, char **argv) {
  printf("Hash results are %x, %x, %x\n", hash(0xdeadbeef), hash(0x00000001), hash(0x00000130));
  return 0;
}
```