user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L32:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L32
  sub    $0xad8,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x61ac8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  movl   $0x0,0x1c(%rsp)
  call   <scanf@plt>
  mov    0x1c(%rsp),%esi
  test   %esi,%esi
  jle    L15
  lea    0x20(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D41(%rip),%r13
  mov    %rbx,%r12
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <scanf@plt>
  mov    0x1c(%rsp),%esi
  add    $0x4,%r12
  cmp    %ebp,%esi
  jg     L45
  test   %esi,%esi
  jle    L15
  movss  D57(%rip),%xmm3
  movss  D19(%rip),%xmm4
  xor    %ebp,%ebp
  pxor   %xmm5,%xmm5
  nopw   0x0(%rax,%rax,1)
L52:
  movss  (%rbx),%xmm1
  movaps %xmm4,%xmm0
  movss  %xmm5,0xc(%rsp)
  add    $0x1,%ebp
  movss  %xmm3,0x8(%rsp)
  add    $0x4,%rbx
  call   <min@plt>
  movss  0x8(%rsp),%xmm3
  movss  -0x4(%rbx),%xmm1
  movss  %xmm0,0x4(%rsp)
  movaps %xmm3,%xmm0
  call   <max@plt>
  mov    0x1c(%rsp),%esi
  movss  0xc(%rsp),%xmm5
  addss  -0x4(%rbx),%xmm5
  movss  0x4(%rsp),%xmm4
  movaps %xmm0,%xmm3
  cmp    %ebp,%esi
  jg     L52
L43:
  pxor   %xmm0,%xmm0
  lea    D56(%rip),%rdi
  pxor   %xmm2,%xmm2
  mov    $0x3,%eax
  cvtsi2ss %esi,%xmm0
  pxor   %xmm1,%xmm1
  movss  %xmm3,0x8(%rsp)
  movss  %xmm4,0x4(%rsp)
  cvtss2sd %xmm3,%xmm1
  divss  %xmm0,%xmm5
  movaps %xmm4,%xmm0
  movss  %xmm5,0xc(%rsp)
  cvtss2sd %xmm5,%xmm2
  call   <printf@plt>
  movss  0x4(%rsp),%xmm4
  mov    $0x1,%eax
  movss  0x8(%rsp),%xmm3
  movss  D1(%rip),%xmm0
  movss  0xc(%rsp),%xmm5
  lea    D28(%rip),%rdi
  subss  %xmm4,%xmm3
  subss  %xmm3,%xmm0
  mulss  %xmm5,%xmm0
  mulss  %xmm5,%xmm0
  mulss  D9(%rip),%xmm0
  call   <printf@plt>
  mov    0x61ac8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x61ad8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  movss  D57(%rip),%xmm3
  movss  D19(%rip),%xmm4
  pxor   %xmm5,%xmm5
  jmp    L43
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D41
datatype: string
name: extract_symbolic_data
arguments: label: D57
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D19
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D56
datatype: string
name: extract_symbolic_data
arguments: label: D1
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D28
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: byte[4]

tool: D13: %d

tool: D41: %f

tool: {"D57": [0x00,0x00,0x80,0xbf]}

tool: {"D19": [0x00,0x00,0xf0,0x41]}

tool: D56: min=%f max=%f mean=%f n=%d


tool: {"D1": [0x00,0x00,0xa0,0x41]}

tool: D28: %.2f


tool: {"D9": [0x0a,0xd7,0x23,0x3c]}

assistant: ```c
int main() {
  int n = 0;
  float l[100010];
  scanf("%d", &n);
  for (int i = 0; i < n; ++i)
    scanf("%f", &l[i]);
  float mini = 30.f, maxi = -1.f, mean = 0.f;
  for (int i = 0; i < n; ++i) {
    mini = min(mini, l[i]);
    maxi = max(maxi, l[i]);
    mean += l[i];
  }
  mean = mean / (1.f * n);
  printf("min=%f max=%f mean=%f n=%d\n", mini, maxi, mean, n);
  printf("%.2f\n", (20.f - (maxi - mini)) * mean * mean * 0.01f);
  return 0;
}
```