ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SDL_imageFilterAddByteToHalf>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %ecx,%r13d
  test   %rsi,%rsi
  je     L94
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L19
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <SDL_imageFilterMMXdetect@plt>
  cmp    $0x7,%ebx
  jbe    L0
  test   %rax,%rax
  jne    L72
L0:
  movzbl %r13b,%r13d
  mov    $0x0,%esi
L91:
  mov    $0x0,%edx
L3:
  movzbl 0x0(%rbp,%rdx,1),%eax
  shr    %al
  movzbl %al,%eax
  add    %r13d,%eax
  mov    $0xff,%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%rdx
  lea    (%rsi,%rdx,1),%eax
  cmp    %ebx,%eax
  jb     L3
  mov    $0x0,%eax
  jmp    L1
L72:
  movzbl %r13b,%r13d
  lea    D6(%rip),%r8
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SDL_imageFilterAddByteToHalfMMX@plt>
  mov    $0x0,%eax
  test   $0x7,%bl
  je     L1
  mov    %ebx,%esi
  and    $0xfffffff8,%esi
  cmp    %esi,%ebx
  jbe    L1
  mov    %esi,%eax
  add    %rax,%rbp
  add    %rax,%r12
  jmp    L91
L94:
  mov    $0xffffffff,%eax
  jmp    L1
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int SDL_imageFilterAddByteToHalf(unsigned char *Src1, unsigned char *Dest, unsigned int length, unsigned char C) {
  static unsigned char Mask[8] = {0x7F, 0x7F, 0x7F, 0x7F, 0x7F, 0x7F, 0x7F, 0x7F};
  unsigned int i, istart;
  int iC;
  unsigned char *cursrc1;
  unsigned char *curdest;
  int result;
  if ((Src1 == NULL) || (Dest == NULL))
    return (-1);
  if (length == 0)
    return (0);
  if ((SDL_imageFilterMMXdetect()) && (length > 7)) {
    SDL_imageFilterAddByteToHalfMMX(Src1, Dest, length, C, Mask);
    if ((length & 7) > 0) {
      istart = length & 0xfffffff8;
      cursrc1 = &Src1[istart];
      curdest = &Dest[istart];
    } else {
      return (0);
    }
  } else {
    istart = 0;
    cursrc1 = Src1;
    curdest = Dest;
  }
  iC = (int)C;
  for (i = istart; i < length; i++) {
    result = (int)(*cursrc1 / 2) + iC;
    if (result > 255)
      result = 255;
    *curdest = (unsigned char)result;
    cursrc1++;
    curdest++;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SDL_imageFilterAddByteToHalf>:
  endbr64
  test   %rdi,%rdi
  je     L17
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L80
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L13
L1:
  xor    %eax,%eax
L90:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  mov    %ecx,%r13d
  mov    %rdi,%rbp
  call   <SDL_imageFilterMMXdetect@plt>
  movzbl %r13b,%r13d
  test   %rax,%rax
  je     L32
  cmp    $0x7,%ebx
  ja     L64
L32:
  xor    %ecx,%ecx
L24:
  xor    %edx,%edx
  nop
L26:
  movzbl 0x0(%rbp,%rdx,1),%eax
  mov    $0xff,%esi
  shr    %al
  movzbl %al,%eax
  add    %r13d,%eax
  cmp    %esi,%eax
  cmovg  %esi,%eax
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%rdx
  lea    (%rcx,%rdx,1),%eax
  cmp    %eax,%ebx
  ja     L26
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L64:
  lea    D0(%rip),%r8
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SDL_imageFilterAddByteToHalfMMX@plt>
  test   $0x7,%bl
  je     L1
  mov    %ebx,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%eax
  add    %rax,%rbp
  add    %rax,%r12
  cmp    %ecx,%ebx
  jbe    L1
  jmp    L24
L80:
  mov    $0xffffffff,%eax
  jmp    L90
L17:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int SDL_imageFilterAddByteToHalf(unsigned char *Src1, unsigned char *Dest, unsigned int length, unsigned char C) {
  static unsigned char Mask[8] = {0x7F, 0x7F, 0x7F, 0x7F, 0x7F, 0x7F, 0x7F, 0x7F};
  unsigned int i, istart;
  int iC;
  unsigned char *cursrc1;
  unsigned char *curdest;
  int result;
  if ((Src1 == NULL) || (Dest == NULL))
    return (-1);
  if (length == 0)
    return (0);
  if ((SDL_imageFilterMMXdetect()) && (length > 7)) {
    SDL_imageFilterAddByteToHalfMMX(Src1, Dest, length, C, Mask);
    if ((length & 7) > 0) {
      istart = length & 0xfffffff8;
      cursrc1 = &Src1[istart];
      curdest = &Dest[istart];
    } else {
      return (0);
    }
  } else {
    istart = 0;
    cursrc1 = Src1;
    curdest = Dest;
  }
  iC = (int)C;
  for (i = istart; i < length; i++) {
    result = (int)(*cursrc1 / 2) + iC;
    if (result > 255)
      result = 255;
    *curdest = (unsigned char)result;
    cursrc1++;
    curdest++;
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xa,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L8:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atoi(char str[]) {
  int i, str_int, base;
  str_int = 0;
  base = 10;
  for (i = 0; str[i] != '\0'; i++) {
    str_int = base * str_int + (str[i] - '0');
  }
  return str_int;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<atoi>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  add    $0x1,%rdi
  mov    $0x0,%edx
L20:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L20
L14:
  mov    %edx,%eax
  ret
L18:
  mov    $0x0,%edx
  jmp    L14
```

assistant: ```c
int atoi(char str[]) {
  int i, str_int, base;
  str_int = 0;
  base = 10;
  for (i = 0; str[i] != '\0'; i++) {
    str_int = base * str_int + (str[i] - '0');
  }
  return str_int;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L3
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L9:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L9
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(char str[]) {
  int i, str_int, base;
  str_int = 0;
  base = 10;
  for (i = 0; str[i] != '\0'; i++) {
    str_int = base * str_int + (str[i] - '0');
  }
  return str_int;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L7
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L1:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L1
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(char str[]) {
  int i, str_int, base;
  str_int = 0;
  base = 10;
  for (i = 0; str[i] != '\0'; i++) {
    str_int = base * str_int + (str[i] - '0');
  }
  return str_int;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_bus_or_interface_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  sub    $0x1,%rax
  mov    $0x0,%edx
  cmp    $0xfe,%rax
  ja     L5
  movzbl (%rbx),%eax
  test   %al,%al
  je     L82
  mov    $0x1,%r9d
  mov    $0x1,%esi
  movabs $0x3ffffff43ffffff,%rdi
  mov    $0x0,%r10d
  jmp    L68
L145:
  add    $0x1,%r9d
  mov    %r10d,%edx
  jmp    L69
L125:
  cmp    $0x2a,%al
  je     L162
  lea    -0x41(%rax),%ecx
  cmp    $0x39,%cl
  ja     L187
  bt     %rcx,%rdi
  jae    L5
  mov    %esi,%edx
L69:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L105
L68:
  test   %edx,%edx
  je     L125
  cmp    $0x2e,%al
  je     L145
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  sub    $0x41,%ecx
  cmp    $0x19,%cl
  setbe  %cl
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  setbe  %r8b
  or     %r8b,%cl
  jne    L69
  cmp    $0x5f,%al
  je     L69
  cmp    $0x2d,%al
  jne    L63
  test   %ebp,%ebp
  jne    L69
L63:
  mov    $0x0,%edx
  jmp    L5
L162:
  cmpb   $0x0,0x1(%rbx)
  sete   %dl
  movzbl %dl,%edx
L5:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L187:
  cmp    $0x2d,%al
  jne    L5
  test   %ebp,%ebp
  je     L5
  mov    %esi,%edx
  jmp    L69
L82:
  mov    $0x0,%edx
  mov    $0x1,%r9d
L105:
  cmp    $0x1,%r9d
  setg   %al
  and    %eax,%edx
  jmp    L5
```

assistant: ```c
int check_bus_or_interface_name(const char *name, int hyphens_allowed) {
  unsigned long length = strlen(name);
  if (length == 0 || length > 255)
    return 0;
  const char *p = name;
  int segments = 1;
  int in_segment = 0;
  while (*p) {
    int alpha = (*p >= 'a' && *p <= 'z') || (*p >= 'A' && *p <= 'Z');
    int digit = *p >= '0' && *p <= '9';
    if (in_segment) {
      if (*p == '.') {
        ++segments;
        in_segment = 0;
      } else if (!alpha && !digit && *p != '_' && (!hyphens_allowed || *p != '-')) {
        return 0;
      }
    } else {
      if (*p == '*') {
        return *(p + 1) == '\0';
      } else if (!alpha && *p != '_' && (!hyphens_allowed || *p != '-')) {
        return 0;
      }
      in_segment = 1;
    }
    ++p;
  }
  return in_segment && segments >= 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_bus_or_interface_name>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %r8d,%r8d
  sub    $0x1,%rax
  cmp    $0xfe,%rax
  ja     L181
  movzbl (%rbx),%eax
  test   %al,%al
  je     L181
  movabs $0x3ffffff43ffffff,%rcx
  mov    $0x1,%edi
  nopl   0x0(%rax)
L41:
  test   %r8d,%r8d
  je     L20
  cmp    $0x2e,%al
  je     L2
  mov    %eax,%edx
  lea    -0x30(%rax),%esi
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  setbe  %dl
  cmp    $0x9,%sil
  setbe  %sil
  or     %sil,%dl
  jne    L88
  cmp    $0x5f,%al
  jne    L167
L88:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L41
  nopl   0x0(%rax,%rax,1)
L139:
  cmp    $0x1,%edi
  setg   %al
  and    %eax,%r8d
L181:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    $0x2a,%al
  je     L36
  lea    -0x41(%rax),%edx
  cmp    $0x39,%dl
  ja     L14
  bt     %rdx,%rcx
  jae    L181
L100:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  mov    $0x1,%r8d
  test   %al,%al
  jne    L41
  jmp    L139
  xchg   %ax,%ax
L2:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  add    $0x1,%edi
  xor    %r8d,%r8d
  test   %al,%al
  jne    L41
  jmp    L139
  nopl   0x0(%rax,%rax,1)
L36:
  xor    %r8d,%r8d
  cmpb   $0x0,0x1(%rbx)
  sete   %r8b
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L14:
  test   %ebp,%ebp
  je     L181
  cmp    $0x2d,%al
  je     L100
  jmp    L181
  nopw   0x0(%rax,%rax,1)
L167:
  test   %ebp,%ebp
  je     L152
  cmp    $0x2d,%al
  je     L88
L152:
  xor    %r8d,%r8d
  jmp    L181
```

assistant: ```c
int check_bus_or_interface_name(const char *name, int hyphens_allowed) {
  unsigned long length = strlen(name);
  if (length == 0 || length > 255)
    return 0;
  const char *p = name;
  int segments = 1;
  int in_segment = 0;
  while (*p) {
    int alpha = (*p >= 'a' && *p <= 'z') || (*p >= 'A' && *p <= 'Z');
    int digit = *p >= '0' && *p <= '9';
    if (in_segment) {
      if (*p == '.') {
        ++segments;
        in_segment = 0;
      } else if (!alpha && !digit && *p != '_' && (!hyphens_allowed || *p != '-')) {
        return 0;
      }
    } else {
      if (*p == '*') {
        return *(p + 1) == '\0';
      } else if (!alpha && *p != '_' && (!hyphens_allowed || *p != '-')) {
        return 0;
      }
      in_segment = 1;
    }
    ++p;
  }
  return in_segment && segments >= 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_bus_or_interface_name>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %r8d,%r8d
  sub    $0x1,%rax
  cmp    $0xfe,%rax
  ja     L51
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L51
  movabs $0x3ffffff43ffffff,%rsi
  mov    $0x1,%edi
  jmp    L189
  nopl   0x0(%rax)
L181:
  cmp    $0x2e,%dl
  je     L55
  mov    %edx,%eax
  lea    -0x30(%rdx),%ecx
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  setbe  %al
  cmp    $0x9,%cl
  setbe  %cl
  or     %ecx,%eax
  xor    $0x1,%eax
  cmp    $0x5f,%dl
  setne  %cl
  and    %cl,%al
  jne    L110
  mov    $0x1,%eax
  nop
L23:
  movzbl 0x1(%rbp),%edx
  add    $0x1,%rbp
  test   %dl,%dl
  je     L150
L189:
  test   %r8d,%r8d
  jne    L181
  cmp    $0x2a,%dl
  je     L94
  lea    -0x41(%rdx),%ecx
  cmp    $0x39,%cl
  ja     L1
  mov    %rsi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  je     L51
  mov    $0x1,%r8d
  jmp    L23
  nopl   (%rax)
L94:
  xor    %r8d,%r8d
  cmpb   $0x0,0x1(%rbp)
  sete   %r8b
L51:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L55:
  add    $0x1,%edi
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L1:
  test   %ebx,%ebx
  je     L51
  cmp    $0x2d,%dl
  jne    L51
  mov    $0x1,%eax
  mov    $0x1,%r8d
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L110:
  test   %ebx,%ebx
  je     L111
  cmp    $0x2d,%dl
  je     L23
L111:
  xor    %r8d,%r8d
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L150:
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  setg   %r8b
  and    %eax,%r8d
  jmp    L51
```

assistant: ```c
int check_bus_or_interface_name(const char *name, int hyphens_allowed) {
  unsigned long length = strlen(name);
  if (length == 0 || length > 255)
    return 0;
  const char *p = name;
  int segments = 1;
  int in_segment = 0;
  while (*p) {
    int alpha = (*p >= 'a' && *p <= 'z') || (*p >= 'A' && *p <= 'Z');
    int digit = *p >= '0' && *p <= '9';
    if (in_segment) {
      if (*p == '.') {
        ++segments;
        in_segment = 0;
      } else if (!alpha && !digit && *p != '_' && (!hyphens_allowed || *p != '-')) {
        return 0;
      }
    } else {
      if (*p == '*') {
        return *(p + 1) == '\0';
      } else if (!alpha && *p != '_' && (!hyphens_allowed || *p != '-')) {
        return 0;
      }
      in_segment = 1;
    }
    ++p;
  }
  return in_segment && segments >= 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testfp1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L17
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L17
  lea    D35(%rip),%rax
  jmp    L18
L17:
  lea    D0(%rip),%rax
L18:
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D32
data_type: string
name: read_data
arguments: data_label: D35
data_type: string
name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D30
data_type: string

tool: D32: x = %.2f - %.2f - %.2f - %.2f; x = 0.0? 

tool: D35: yes

tool: D0: NO!

tool: D30: [%s]


assistant: ```c
void testfp1(double x, double a) {
  printf("x = %.2f - %.2f - %.2f - %.2f; x = 0.0? ", x, a, a, a);
  x -= a;
  x -= a;
  x -= a;
  printf("[%s]\n", ((x == 0.0)) ? "yes" : "NO!");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<testfp1>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm3
  movsd  %xmm1,0x8(%rsp)
  lea    D32(%rip),%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  movq   %rbx,%xmm0
  movsd  0x8(%rsp),%xmm4
  subsd  %xmm4,%xmm0
  subsd  %xmm4,%xmm0
  subsd  %xmm4,%xmm0
  ucomisd D34(%rip),%xmm0
  jp     L23
  lea    D1(%rip),%rsi
  jne    L23
L16:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
L23:
  lea    D2(%rip),%rsi
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: label: D32
type: string
name: retrieve_data
arguments: label: D34
type: f64
name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D23
type: string
name: retrieve_data
arguments: label: D2
type: string

tool: D32: x = %.2f - %.2f - %.2f - %.2f; x = 0.0? 

tool: D34: 0

tool: D1: yes

tool: D23: [%s]


tool: D2: NO!

assistant: ```c
void testfp1(double x, double a) {
  printf("x = %.2f - %.2f - %.2f - %.2f; x = 0.0? ", x, a, a, a);
  x -= a;
  x -= a;
  x -= a;
  printf("[%s]\n", ((x == 0.0)) ? "yes" : "NO!");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<testfp1>:
  endbr64
  sub    $0x18,%rsp
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm2
  mov    $0x4,%eax
  lea    D17(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  subsd  %xmm1,%xmm0
  subsd  %xmm1,%xmm0
  subsd  %xmm1,%xmm0
  ucomisd D15(%rip),%xmm0
  jp     L25
  lea    D0(%rip),%rsi
  jne    L25
L3:
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  add    $0x18,%rsp
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L25:
  lea    D21(%rip),%rsi
  jmp    L3
```

tool_calls: name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D15
type_infered: f64
name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D21
type_infered: string

tool: D17: x = %.2f - %.2f - %.2f - %.2f; x = 0.0? 

tool: D15: 0

tool: D0: yes

tool: D16: [%s]


tool: D21: NO!

assistant: ```c
void testfp1(double x, double a) {
  printf("x = %.2f - %.2f - %.2f - %.2f; x = 0.0? ", x, a, a, a);
  x -= a;
  x -= a;
  x -= a;
  printf("[%s]\n", ((x == 0.0)) ? "yes" : "NO!");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<testfp1>:
  endbr64
  sub    $0x18,%rsp
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm2
  mov    $0x4,%eax
  lea    D48(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  subsd  %xmm1,%xmm0
  subsd  %xmm1,%xmm0
  subsd  %xmm1,%xmm0
  ucomisd D6(%rip),%xmm0
  jp     L29
  lea    D35(%rip),%rsi
  jne    L29
L25:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  add    $0x18,%rsp
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L29:
  lea    D22(%rip),%rsi
  jmp    L25
```

tool_calls: name: read_data
arguments: label: D48
type_infered: string
name: read_data
arguments: label: D6
type_infered: f64
name: read_data
arguments: label: D35
type_infered: string
name: read_data
arguments: label: D1
type_infered: string
name: read_data
arguments: label: D22
type_infered: string

tool: D48: x = %.2f - %.2f - %.2f - %.2f; x = 0.0? 

tool: D6: 0

tool: D35: yes

tool: D1: [%s]


tool: D22: NO!

assistant: ```c
void testfp1(double x, double a) {
  printf("x = %.2f - %.2f - %.2f - %.2f; x = 0.0? ", x, a, a, a);
  x -= a;
  x -= a;
  x -= a;
  printf("[%s]\n", ((x == 0.0)) ? "yes" : "NO!");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<avcodec_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D9(%rip),%eax
  test   %eax,%eax
  jne    L4
  movl   $0x1,D9(%rip)
  mov    $0x0,%eax
  call   <dsputil_static_init@plt>
  jmp    L14
L4:
  nop
L14:
  pop    %rbp
  ret
```

assistant: ```c
void avcodec_init(void) {
  static int inited = 0;
  if (inited != 0)
    return;
  inited = 1;
  dsputil_static_init();
}
```
user: Translate the below assembly code into C programming language:

```asm
<avcodec_init>:
  endbr64
  cmpl   $0x0,D19(%rip)
  je     L9
  ret
L9:
  sub    $0x8,%rsp
  movl   $0x1,D19(%rip)
  mov    $0x0,%eax
  call   <dsputil_static_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void avcodec_init(void) {
  static int inited = 0;
  if (inited != 0)
    return;
  inited = 1;
  dsputil_static_init();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<avcodec_init>:
  endbr64
  mov    D18(%rip),%eax
  test   %eax,%eax
  je     L6
  ret
  nop
L6:
  movl   $0x1,D18(%rip)
  xor    %eax,%eax
  jmp    1050 <dsputil_static_init@plt>
```

assistant: ```c
void avcodec_init(void) {
  static int inited = 0;
  if (inited != 0)
    return;
  inited = 1;
  dsputil_static_init();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<avcodec_init>:
  endbr64
  mov    D17(%rip),%eax
  test   %eax,%eax
  je     L5
  ret
  nop
L5:
  movl   $0x1,D17(%rip)
  xor    %eax,%eax
  jmp    1050 <dsputil_static_init@plt>
```

assistant: ```c
void avcodec_init(void) {
  static int inited = 0;
  if (inited != 0)
    return;
  inited = 1;
  dsputil_static_init();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D0(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L16
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <aprs_processreceivedline@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
L16:
  cmpq   $0x0,-0x18(%rbp)
  jne    L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D0: HA5KDR>APRS,TCPIP*,qAC,SIXTH::HA2NON-7 :teszt 1 2 3{01}

tool: D2: 


assistant: ```c
int main(void) {
  char *buf2 = "HA5KDR>APRS,TCPIP*,qAC,SIXTH::HA2NON-7 :teszt 1 2 3{01}";
  char *buf = strdup(buf2);
  char *tok;
  tok = strtok(buf, "\n");
  while (tok != NULL) {
    aprs_processreceivedline(tok, strlen(tok));
    tok = strtok(NULL, "\n");
  }
  free(buf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbx
  lea    D10(%rip),%r12
L9:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <aprs_processreceivedline@plt>
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L9
L12:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D10
type_infered: string

tool: D15: HA5KDR>APRS,TCPIP*,qAC,SIXTH::HA2NON-7 :teszt 1 2 3{01}

tool: D10: 


assistant: ```c
int main(void) {
  char *buf2 = "HA5KDR>APRS,TCPIP*,qAC,SIXTH::HA2NON-7 :teszt 1 2 3{01}";
  char *buf = strdup(buf2);
  char *tok;
  tok = strtok(buf, "\n");
  while (tok != NULL) {
    aprs_processreceivedline(tok, strlen(tok));
    tok = strtok(NULL, "\n");
  }
  free(buf);
  return 0;
}
```