ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%ecx
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
datatype: string
name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D14: -DLIN64 

tool: D0: -DSIZEOF_VOID_P=%d -DSIZEOF_LONG=%d -DSIZEOF_INT=%d


assistant: ```c
int main() {
  if (sizeof(void *) == 8)
    printf("-DLIN64 ");
  else
    printf("-DLIN ");
  printf("-DSIZEOF_VOID_P=%d -DSIZEOF_LONG=%d -DSIZEOF_INT=%d\n", (int)sizeof(void *), (int)sizeof(long), (int)sizeof(int));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%ecx
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D19: -DLIN64 

tool: D3: -DSIZEOF_VOID_P=%d -DSIZEOF_LONG=%d -DSIZEOF_INT=%d


assistant: ```c
int main() {
  if (sizeof(void *) == 8)
    printf("-DLIN64 ");
  else
    printf("-DLIN ");
  printf("-DSIZEOF_VOID_P=%d -DSIZEOF_LONG=%d -DSIZEOF_INT=%d\n", (int)sizeof(void *), (int)sizeof(long), (int)sizeof(int));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%ecx
  xor    %eax,%eax
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D10
type_infered: string

tool: D17: -DLIN64 

tool: D10: -DSIZEOF_VOID_P=%d -DSIZEOF_LONG=%d -DSIZEOF_INT=%d


assistant: ```c
int main() {
  if (sizeof(void *) == 8)
    printf("-DLIN64 ");
  else
    printf("-DLIN ");
  printf("-DSIZEOF_VOID_P=%d -DSIZEOF_LONG=%d -DSIZEOF_INT=%d\n", (int)sizeof(void *), (int)sizeof(long), (int)sizeof(int));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%ecx
  xor    %eax,%eax
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D2
type: string

tool: D4: -DLIN64 

tool: D2: -DSIZEOF_VOID_P=%d -DSIZEOF_LONG=%d -DSIZEOF_INT=%d


assistant: ```c
int main() {
  if (sizeof(void *) == 8)
    printf("-DLIN64 ");
  else
    printf("-DLIN ");
  printf("-DSIZEOF_VOID_P=%d -DSIZEOF_LONG=%d -DSIZEOF_INT=%d\n", (int)sizeof(void *), (int)sizeof(long), (int)sizeof(int));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x7c5c2d2f,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
L6:
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L10:
  addl   $0x1,-0x14(%rbp)
L5:
  cmpl   $0x59d7,-0x14(%rbp)
  jle    L10
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  movzbl -0xd(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: %c

assistant: ```c
int main() {
  int i = 0, j;
  char ar[5] = {'/', '-', '\\', '|'};
  while (true) {
    for (j = 0; j < 23000; j++)
      ;
    printf("%c\r", ar[i % 7]);
    i++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x7c5c2d2f,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    $0x0,%ebx
  lea    D0(%rip),%rbp
  jmp    L21
L5:
  movslq %ebx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x2,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  cltq
  movsbl 0x3(%rsp,%rax,1),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
L21:
  mov    $0x59d8,%eax
L0:
  sub    $0x1,%eax
  jne    L0
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: %c

assistant: ```c
int main() {
  int i = 0, j;
  char ar[5] = {'/', '-', '\\', '|'};
  while (true) {
    for (j = 0; j < 23000; j++)
      ;
    printf("%c\r", ar[i % 7]);
    i++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x7c5c2d2f,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
L18:
  mov    $0x59d8,%eax
  nopl   (%rax)
L1:
  sub    $0x1,%eax
  jne    L1
  mov    %ebp,%edx
  mov    %ebp,%eax
  mov    %rbx,%rdi
  imul   $0x24924925,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebp,%eax
  add    $0x1,%ebp
  sub    %edx,%eax
  cltq
  movsbl 0x3(%rsp,%rax,1),%esi
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: %c

assistant: ```c
int main() {
  int i = 0, j;
  char ar[5] = {'/', '-', '\\', '|'};
  while (true) {
    for (j = 0; j < 23000; j++)
      ;
    printf("%c\r", ar[i % 7]);
    i++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D9(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x7c5c2d2f,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
L3:
  mov    $0x59d8,%eax
  nopl   (%rax)
L7:
  sub    $0x1,%eax
  jne    L7
  mov    %ebp,%edx
  mov    %ebp,%eax
  mov    %rbx,%rdi
  imul   $0x24924925,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebp,%eax
  add    $0x1,%ebp
  sub    %edx,%eax
  cltq
  movsbl 0x3(%rsp,%rax,1),%esi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: %c

assistant: ```c
int main() {
  int i = 0, j;
  char ar[5] = {'/', '-', '\\', '|'};
  while (true) {
    for (j = 0; j < 23000; j++)
      ;
    printf("%c\r", ar[i % 7]);
    i++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *f2(void *arg) {
  bar();
  foo();
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *f2(void *arg) {
  bar();
  foo();
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *f2(void *arg) {
  bar();
  foo();
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *f2(void *arg) {
  bar();
  foo();
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <gen_data@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *ifn = NULL;
  gen_data();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gen_data@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *ifn = NULL;
  gen_data();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gen_data@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *ifn = NULL;
  gen_data();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L55
L0:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  je     L7
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  jmp    L55
L7:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L55:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L14
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L14
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jg     L0
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int main() {
  int *x = alloca(sizeof(int));
  int *y = alloca(sizeof(int));
  int *d = alloca(sizeof(int));
  while (*x > 0 && *y > 0 && *d > 0) {
    if (__VERIFIER_nondet_int()) {
      *x = *x - 1;
      *d = __VERIFIER_nondet_int();
    } else {
      *x = __VERIFIER_nondet_int();
      *y = *y - 1;
      *d = *d - 1;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%r13
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%r12
  cmpl   $0x0,(%rbx)
  jg     L47
L55:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L2:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,(%rbx)
  subl   $0x1,0x0(%r13)
  mov    (%r12),%eax
  sub    $0x1,%eax
L27:
  mov    %eax,(%r12)
  cmpl   $0x0,(%rbx)
  jle    L55
L47:
  cmpl   $0x0,0x0(%r13)
  jle    L55
  cmpl   $0x0,(%r12)
  jle    L55
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  je     L2
  subl   $0x1,(%rbx)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  jmp    L27
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *x = alloca(sizeof(int));
  int *y = alloca(sizeof(int));
  int *d = alloca(sizeof(int));
  while (*x > 0 && *y > 0 && *d > 0) {
    if (__VERIFIER_nondet_int()) {
      *x = *x - 1;
      *d = __VERIFIER_nondet_int();
    } else {
      *x = __VERIFIER_nondet_int();
      *y = *y - 1;
      *d = *d - 1;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <alloca@plt>
  mov    (%rbx),%esi
  mov    %rax,%r12
  test   %esi,%esi
  jg     L68
  jmp    L62
  nop
L73:
  subl   $0x1,(%rbx)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,(%r12)
  mov    (%rbx),%ecx
  test   %ecx,%ecx
  jle    L62
L68:
  mov    0x0(%r13),%edx
  test   %edx,%edx
  jle    L62
  mov    (%r12),%eax
  test   %eax,%eax
  jle    L62
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L73
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,(%rbx)
  subl   $0x1,0x0(%r13)
  mov    (%r12),%eax
  sub    $0x1,%eax
  mov    %eax,(%r12)
  mov    (%rbx),%ecx
  test   %ecx,%ecx
  jg     L68
  xchg   %ax,%ax
L62:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  lea    -0x18(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *x = alloca(sizeof(int));
  int *y = alloca(sizeof(int));
  int *d = alloca(sizeof(int));
  while (*x > 0 && *y > 0 && *d > 0) {
    if (__VERIFIER_nondet_int()) {
      *x = *x - 1;
      *d = __VERIFIER_nondet_int();
    } else {
      *x = __VERIFIER_nondet_int();
      *y = *y - 1;
      *d = *d - 1;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <alloca@plt>
  mov    (%rbx),%edi
  mov    %rax,%r12
  test   %edi,%edi
  jle    L36
  nopl   (%rax)
L3:
  mov    0x0(%r13),%edx
  test   %edx,%edx
  jle    L36
  mov    (%r12),%eax
  test   %eax,%eax
  jle    L36
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  je     L43
  subl   $0x1,(%rbx)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,(%r12)
  mov    (%rbx),%esi
  test   %esi,%esi
  jg     L3
  nop
L36:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  lea    -0x18(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L43:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,(%rbx)
  subl   $0x1,0x0(%r13)
  subl   $0x1,(%r12)
  mov    (%rbx),%ecx
  test   %ecx,%ecx
  jg     L3
  jmp    L36
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *x = alloca(sizeof(int));
  int *y = alloca(sizeof(int));
  int *d = alloca(sizeof(int));
  while (*x > 0 && *y > 0 && *d > 0) {
    if (__VERIFIER_nondet_int()) {
      *x = *x - 1;
      *d = __VERIFIER_nondet_int();
    } else {
      *x = __VERIFIER_nondet_int();
      *y = *y - 1;
      *d = *d - 1;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ehrpwm_tb_set_period>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x8(%rbp)
  movzwl -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <ehrpwm_write@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int ehrpwm_tb_set_period(uint8_t module, unsigned short val) {
  ehrpwm_write(module, 0xA, val);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ehrpwm_tb_set_period>:
  endbr64
  sub    $0x8,%rsp
  movzwl %si,%edx
  mov    $0xa,%esi
  call   <ehrpwm_write@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ehrpwm_tb_set_period(uint8_t module, unsigned short val) {
  ehrpwm_write(module, 0xA, val);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ehrpwm_tb_set_period>:
  endbr64
  sub    $0x8,%rsp
  movzwl %si,%edx
  mov    $0xa,%esi
  call   <ehrpwm_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ehrpwm_tb_set_period(uint8_t module, unsigned short val) {
  ehrpwm_write(module, 0xA, val);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ehrpwm_tb_set_period>:
  endbr64
  sub    $0x8,%rsp
  movzwl %si,%edx
  mov    $0xa,%esi
  call   <ehrpwm_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ehrpwm_tb_set_period(uint8_t module, unsigned short val) {
  ehrpwm_write(module, 0xA, val);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<repaint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  jmp    L11
L1:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <inch@plt>
  or     -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,%edi
  call   <addch@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void repaint(int x, int y, int len, int attron, int attroff) {
  while (len-- > 0) {
    (void)move(y, x);
    addch((inch() | attron) & ~attroff);
    x++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<repaint>:
  endbr64
  test   %edx,%edx
  jle    L13
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %ecx,%r14d
  lea    (%rdx,%rdi,1),%ebp
  not    %r8d
  mov    %r8d,%r12d
L9:
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <inch@plt>
  or     %r14d,%eax
  mov    %eax,%edi
  and    %r12d,%edi
  call   <addch@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  ret
```

assistant: ```c
void repaint(int x, int y, int len, int attron, int attroff) {
  while (len-- > 0) {
    (void)move(y, x);
    addch((inch() | attron) & ~attroff);
    x++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<repaint>:
  endbr64
  push   %r14
  push   %r13
  lea    (%rdx,%rdi,1),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L7
  mov    %r8d,%ebx
  mov    %edi,%r14d
  mov    %esi,%r12d
  mov    %ecx,%ebp
  not    %ebx
  nopl   0x0(%rax)
L14:
  mov    %r14d,%esi
  mov    %r12d,%edi
  add    $0x1,%r14d
  call   <move@plt>
  xor    %eax,%eax
  call   <inch@plt>
  or     %ebp,%eax
  mov    %eax,%edi
  and    %ebx,%edi
  call   <addch@plt>
  cmp    %r13d,%r14d
  jne    L14
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void repaint(int x, int y, int len, int attron, int attroff) {
  while (len-- > 0) {
    (void)move(y, x);
    addch((inch() | attron) & ~attroff);
    x++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<repaint>:
  endbr64
  push   %r14
  push   %r13
  lea    (%rdx,%rdi,1),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L5
  mov    %r8d,%ebx
  mov    %edi,%r14d
  mov    %esi,%r12d
  mov    %ecx,%ebp
  not    %ebx
  nopl   0x0(%rax)
L18:
  mov    %r14d,%esi
  mov    %r12d,%edi
  add    $0x1,%r14d
  call   <move@plt>
  xor    %eax,%eax
  call   <inch@plt>
  or     %ebp,%eax
  mov    %eax,%edi
  and    %ebx,%edi
  call   <addch@plt>
  cmp    %r14d,%r13d
  jne    L18
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void repaint(int x, int y, int len, int attron, int attroff) {
  while (len-- > 0) {
    (void)move(y, x);
    addch((inch() | attron) & ~attroff);
    x++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<logout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <utmpname@plt>
  cmp    $0xffffffff,%eax
  jne    L4
  mov    $0x0,%eax
  jmp    L29
L4:
  mov    $0x0,%eax
  call   <setutent@plt>
  mov    -0x28(%rbp),%eax
  mov    -0x48(%rbp),%rcx
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <strncpy@plt>
  lea    -0x38(%rbp),%rdx
  lea    -0x24(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getutline_r@plt>
  test   %rax,%rax
  js     L33
  mov    -0x38(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <bzero@plt>
  mov    -0x38(%rbp),%rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,(%rbx)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <pututline@plt>
  test   %rax,%rax
  je     L33
  movl   $0x1,-0x3c(%rbp)
L33:
  mov    $0x0,%eax
  call   <endutent@plt>
  mov    -0x3c(%rbp),%eax
L29:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int logout(const char *line) {
  struct utmp tmp, utbuf;
  struct utmp *ut;
  int result = 0;
  if (utmpname(_PATH_UTMP) == -1)
    return 0;
  setutent();
  strncpy(tmp.ut_line, line, sizeof tmp.ut_line);
  if (getutline_r(&tmp, &utbuf, &ut) >= 0) {
    bzero(ut->ut_name, sizeof ut->ut_name);
    ut->ut_time = time(NULL);
    if (pututline(ut) != NULL)
      result = 1;
  }
  endutent();
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<logout>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <utmpname@plt>
  mov    $0x0,%ebp
  cmp    $0xffffffff,%eax
  je     L12
  mov    $0x0,%eax
  call   <setutent@plt>
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    0x18(%rsp),%edi
  call   <strncpy@plt>
  lea    0x8(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <getutline_r@plt>
  test   %rax,%rax
  jns    L29
L38:
  mov    $0x0,%eax
  call   <endutent@plt>
L12:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %ebp,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    0x8(%rsp),%rax
  mov    0x4(%rax),%edi
  mov    $0x4,%esi
  call   <bzero@plt>
  mov    0x8(%rsp),%rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rdi
  call   <pututline@plt>
  test   %rax,%rax
  setne  %bpl
  movzbl %bpl,%ebp
  jmp    L38
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int logout(const char *line) {
  struct utmp tmp, utbuf;
  struct utmp *ut;
  int result = 0;
  if (utmpname(_PATH_UTMP) == -1)
    return 0;
  setutent();
  strncpy(tmp.ut_line, line, sizeof tmp.ut_line);
  if (getutline_r(&tmp, &utbuf, &ut) >= 0) {
    bzero(ut->ut_name, sizeof ut->ut_name);
    ut->ut_time = time(NULL);
    if (pututline(ut) != NULL)
      result = 1;
  }
  endutent();
  return result;
}
```