ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<test_string_nocase_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movabs $0x2073692073696874,%rcx
  mov    %rcx,-0x6c(%rbp)
  movl   $0x65742061,-0x64(%rbp)
  movw   $0x7473,-0x60(%rbp)
  movb   $0x0,-0x5e(%rbp)
  mov    %rcx,-0x5d(%rbp)
  movl   $0x65742061,-0x55(%rbp)
  movw   $0x7573,-0x51(%rbp)
  movb   $0x0,-0x4f(%rbp)
  movabs $0x2073692073696874,%rax
  movabs $0x20747365742061,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x4e(%rbp)
  movl   $0x65742061,-0x46(%rbp)
  movw   $0x7473,-0x42(%rbp)
  movb   $0x0,-0x40(%rbp)
  movabs $0x2073692073696854,%rax
  mov    %rax,-0x3f(%rbp)
  movl   $0x65742061,-0x37(%rbp)
  movw   $0x7473,-0x33(%rbp)
  movb   $0x0,-0x31(%rbp)
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rdi
  call   <string_nocase_hash@plt>
  mov    %rax,%rbx
  lea    -0x5d(%rbp),%rax
  mov    %rax,%rdi
  call   <string_nocase_hash@plt>
  cmp    %rax,%rbx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rdi
  call   <string_nocase_hash@plt>
  mov    %rax,%rbx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <string_nocase_hash@plt>
  cmp    %rax,%rbx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rdi
  call   <string_nocase_hash@plt>
  mov    %rax,%rbx
  lea    -0x3f(%rbp),%rax
  mov    %rax,%rdi
  call   <string_nocase_hash@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rdi
  call   <string_nocase_hash@plt>
  mov    %rax,%rbx
  lea    -0x4e(%rbp),%rax
  mov    %rax,%rdi
  call   <string_nocase_hash@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void test_string_nocase_hash(void) {
  char test1[] = "this is a test";
  char test2[] = "this is a tesu";
  char test3[] = "this is a test ";
  char test4[] = "this is a test";
  char test5[] = "This is a test";
  assert(string_nocase_hash(test1) != string_nocase_hash(test2));
  assert(string_nocase_hash(test1) != string_nocase_hash(test3));
  assert(string_nocase_hash(test1) == string_nocase_hash(test5));
  assert(string_nocase_hash(test1) == string_nocase_hash(test4));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_string_nocase_hash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movabs $0x2073692073696874,%rax
  mov    %rax,0x4(%rsp)
  movl   $0x65742061,0xc(%rsp)
  movw   $0x7473,0x10(%rsp)
  movb   $0x0,0x12(%rsp)
  mov    %rax,0x13(%rsp)
  movl   $0x65742061,0x1b(%rsp)
  movw   $0x7573,0x1f(%rsp)
  movb   $0x0,0x21(%rsp)
  movabs $0x2073692073696874,%rdx
  movabs $0x20747365742061,%rcx
  mov    %rdx,0x40(%rsp)
  mov    %rcx,0x48(%rsp)
  mov    %rax,0x22(%rsp)
  movl   $0x65742061,0x2a(%rsp)
  movw   $0x7473,0x2e(%rsp)
  movb   $0x0,0x30(%rsp)
  lea    -0x20(%rax),%rax
  mov    %rax,0x31(%rsp)
  movl   $0x65742061,0x39(%rsp)
  movw   $0x7473,0x3d(%rsp)
  movb   $0x0,0x3f(%rsp)
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <string_nocase_hash@plt>
  mov    %rax,%rbp
  lea    0x13(%rsp),%rdi
  call   <string_nocase_hash@plt>
  cmp    %rax,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <string_nocase_hash@plt>
  mov    %rax,%rbp
  lea    0x40(%rsp),%rdi
  call   <string_nocase_hash@plt>
  cmp    %rax,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <string_nocase_hash@plt>
  mov    %rax,%rbp
  lea    0x31(%rsp),%rdi
  call   <string_nocase_hash@plt>
  cmp    %rax,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <string_nocase_hash@plt>
  mov    %rax,%rbx
  lea    0x22(%rsp),%rdi
  call   <string_nocase_hash@plt>
  cmp    %rax,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_string_nocase_hash(void) {
  char test1[] = "this is a test";
  char test2[] = "this is a tesu";
  char test3[] = "this is a test ";
  char test4[] = "this is a test";
  char test5[] = "This is a test";
  assert(string_nocase_hash(test1) != string_nocase_hash(test2));
  assert(string_nocase_hash(test1) != string_nocase_hash(test3));
  assert(string_nocase_hash(test1) == string_nocase_hash(test5));
  assert(string_nocase_hash(test1) == string_nocase_hash(test4));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_string_nocase_hash>:
  endbr64
  push   %rbp
  mov    $0x7473,%edi
  mov    $0x7473,%edx
  mov    $0x7573,%ecx
  push   %rbx
  mov    $0x7473,%esi
  sub    $0x68,%rsp
  movdqa D2(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x2073692073696874,%rax
  lea    0x4(%rsp),%rbp
  mov    %di,0x3d(%rsp)
  mov    %rbp,%rdi
  mov    %dx,0x10(%rsp)
  mov    %cx,0x1f(%rsp)
  mov    %si,0x2e(%rsp)
  movaps %xmm0,0x40(%rsp)
  movl   $0x65742061,0xc(%rsp)
  mov    %rax,0x4(%rsp)
  mov    %rax,0x13(%rsp)
  mov    %rax,0x22(%rsp)
  sub    $0x20,%rax
  movb   $0x0,0x12(%rsp)
  movl   $0x65742061,0x1b(%rsp)
  movb   $0x0,0x21(%rsp)
  movl   $0x65742061,0x2a(%rsp)
  movb   $0x0,0x30(%rsp)
  mov    %rax,0x31(%rsp)
  movl   $0x65742061,0x39(%rsp)
  movb   $0x0,0x3f(%rsp)
  call   <string_nocase_hash@plt>
  lea    0x13(%rsp),%rdi
  mov    %rax,%rbx
  call   <string_nocase_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <string_nocase_hash@plt>
  lea    0x40(%rsp),%rdi
  mov    %rax,%rbx
  call   <string_nocase_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <string_nocase_hash@plt>
  lea    0x31(%rsp),%rdi
  mov    %rax,%rbx
  call   <string_nocase_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <string_nocase_hash@plt>
  lea    0x22(%rsp),%rdi
  mov    %rax,%rbp
  call   <string_nocase_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type: byte[16]

tool: {"D2": [0x74,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x74,0x65,0x73,0x74,0x20,0x00]}

assistant: ```c
void test_string_nocase_hash(void) {
  char test1[] = "this is a test";
  char test2[] = "this is a tesu";
  char test3[] = "this is a test ";
  char test4[] = "this is a test";
  char test5[] = "This is a test";
  assert(string_nocase_hash(test1) != string_nocase_hash(test2));
  assert(string_nocase_hash(test1) != string_nocase_hash(test3));
  assert(string_nocase_hash(test1) == string_nocase_hash(test5));
  assert(string_nocase_hash(test1) == string_nocase_hash(test4));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_string_nocase_hash>:
  endbr64
  push   %rbp
  mov    $0x7473,%edi
  mov    $0x7473,%edx
  mov    $0x7573,%ecx
  push   %rbx
  mov    $0x7473,%esi
  sub    $0x68,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x2073692073696874,%rax
  lea    0x4(%rsp),%rbp
  mov    %di,0x3d(%rsp)
  mov    %rbp,%rdi
  mov    %dx,0x10(%rsp)
  mov    %cx,0x1f(%rsp)
  mov    %si,0x2e(%rsp)
  movaps %xmm0,0x40(%rsp)
  movl   $0x65742061,0xc(%rsp)
  mov    %rax,0x4(%rsp)
  mov    %rax,0x13(%rsp)
  mov    %rax,0x22(%rsp)
  sub    $0x20,%rax
  movb   $0x0,0x12(%rsp)
  movl   $0x65742061,0x1b(%rsp)
  movb   $0x0,0x21(%rsp)
  movl   $0x65742061,0x2a(%rsp)
  movb   $0x0,0x30(%rsp)
  mov    %rax,0x31(%rsp)
  movl   $0x65742061,0x39(%rsp)
  movb   $0x0,0x3f(%rsp)
  call   <string_nocase_hash@plt>
  lea    0x13(%rsp),%rdi
  mov    %rax,%rbx
  call   <string_nocase_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <string_nocase_hash@plt>
  lea    0x40(%rsp),%rdi
  mov    %rax,%rbx
  call   <string_nocase_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <string_nocase_hash@plt>
  lea    0x31(%rsp),%rdi
  mov    %rax,%rbx
  call   <string_nocase_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <string_nocase_hash@plt>
  lea    0x22(%rsp),%rdi
  mov    %rax,%rbp
  call   <string_nocase_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: byte[16]

tool: {"D1": [0x74,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x74,0x65,0x73,0x74,0x20,0x00]}

assistant: ```c
void test_string_nocase_hash(void) {
  char test1[] = "this is a test";
  char test2[] = "this is a tesu";
  char test3[] = "this is a test ";
  char test4[] = "this is a test";
  char test5[] = "This is a test";
  assert(string_nocase_hash(test1) != string_nocase_hash(test2));
  assert(string_nocase_hash(test1) != string_nocase_hash(test3));
  assert(string_nocase_hash(test1) == string_nocase_hash(test5));
  assert(string_nocase_hash(test1) == string_nocase_hash(test4));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TimerPrescaleMatchGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xff,-0x8(%rbp)
  jne    L6
  mov    -0x4(%rbp),%eax
  add    $0x40,%eax
  cltq
  mov    (%rax),%rax
  jmp    L19
L6:
  mov    -0x4(%rbp),%eax
  add    $0x44,%eax
  cltq
  mov    (%rax),%rax
L19:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t TimerPrescaleMatchGet(uint32_t ui32Base, uint32_t ui32Timer) {
  ;
  ;
  return ((ui32Timer == 0x000000FF) ? (*((volatile unsigned long *)(ui32Base + 0x00000040))) : (*((volatile unsigned long *)(ui32Base + 0x00000044))));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TimerPrescaleMatchGet>:
  endbr64
  cmp    $0xff,%esi
  je     L2
  add    $0x44,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rax
  ret
L2:
  add    $0x40,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rax
  ret
```

assistant: ```c
uint32_t TimerPrescaleMatchGet(uint32_t ui32Base, uint32_t ui32Timer) {
  ;
  ;
  return ((ui32Timer == 0x000000FF) ? (*((volatile unsigned long *)(ui32Base + 0x00000040))) : (*((volatile unsigned long *)(ui32Base + 0x00000044))));
}
```
user: What is the c source code of the assembly code below:

```asm
<TimerPrescaleMatchGet>:
  endbr64
  cmp    $0xff,%esi
  je     L1
  add    $0x44,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x40,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rax
  ret
```

assistant: ```c
uint32_t TimerPrescaleMatchGet(uint32_t ui32Base, uint32_t ui32Timer) {
  ;
  ;
  return ((ui32Timer == 0x000000FF) ? (*((volatile unsigned long *)(ui32Base + 0x00000040))) : (*((volatile unsigned long *)(ui32Base + 0x00000044))));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TimerPrescaleMatchGet>:
  endbr64
  cmp    $0xff,%esi
  je     L6
  add    $0x44,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x40,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rax
  ret
```

assistant: ```c
uint32_t TimerPrescaleMatchGet(uint32_t ui32Base, uint32_t ui32Timer) {
  ;
  ;
  return ((ui32Timer == 0x000000FF) ? (*((volatile unsigned long *)(ui32Base + 0x00000040))) : (*((volatile unsigned long *)(ui32Base + 0x00000044))));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<readNextString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movb   $0x3,-0x1(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L19
L80:
  movzbl -0x1(%rbp),%eax
  cmp    $0x3,%eax
  je     L24
  cmp    $0x4,%eax
  je     L117
  jmp    L111
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L106
  movb   $0x4,-0x1(%rbp)
  jmp    L118
L106:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L118
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L118
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L118
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L118
  mov    $0x68,%eax
  jmp    L50
L117:
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getStringAndHash@plt>
  jmp    L50
L118:
  nop
L111:
  addq   $0x1,-0x18(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L80
  mov    $0x68,%eax
L50:
  leave
  ret
```

assistant: ```c
unsigned int readNextString(char *start, char **first, char **last, unsigned int *hash) {
  unsigned char state = 3;
  ++start;
  while (start[0] != '\0') {
    switch (state) {
    case 3:
      if (start[0] == ':') {
        state = 4;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        return 104;
      }
      break;
    case 4:
      return getStringAndHash(start, first, last, hash);
    }
    ++start;
  }
  return 104;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readNextString>:
  endbr64
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L14
  lea    0x1(%rdi),%rdi
  mov    $0x3,%r8d
  mov    $0x4,%r9d
  jmp    L54
L5:
  cmp    $0x3a,%al
  je     L47
  lea    -0x9(%rax),%r10d
  cmp    $0x1,%r10b
  jbe    L61
  cmp    $0x20,%al
  je     L61
  mov    $0x68,%eax
  ret
L47:
  mov    %r9d,%r8d
L61:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L30
L54:
  cmp    $0x3,%r8b
  je     L5
  cmp    $0x4,%r8b
  jne    L61
  sub    $0x8,%rsp
  call   <getStringAndHash@plt>
  add    $0x8,%rsp
  ret
L30:
  mov    $0x68,%eax
  ret
L14:
  mov    $0x68,%eax
  ret
```

assistant: ```c
unsigned int readNextString(char *start, char **first, char **last, unsigned int *hash) {
  unsigned char state = 3;
  ++start;
  while (start[0] != '\0') {
    switch (state) {
    case 3:
      if (start[0] == ':') {
        state = 4;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        return 104;
      }
      break;
    case 4:
      return getStringAndHash(start, first, last, hash);
    }
    ++start;
  }
  return 104;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readNextString>:
  endbr64
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r8
  test   %al,%al
  je     L1
  add    $0x2,%rdi
  cmp    $0x3a,%al
  je     L58
L8:
  cmp    $0x20,%al
  je     L78
  cmp    $0x9,%al
  je     L78
  cmp    $0xa,%al
  jne    L1
L78:
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  je     L1
  add    $0x1,%rdi
  cmp    $0x3a,%al
  jne    L8
L58:
  cmpb   $0x0,0x1(%r8)
  lea    0x1(%r8),%rdi
  je     L1
  jmp    1050 <getStringAndHash@plt>
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0x68,%eax
  ret
```

assistant: ```c
unsigned int readNextString(char *start, char **first, char **last, unsigned int *hash) {
  unsigned char state = 3;
  ++start;
  while (start[0] != '\0') {
    switch (state) {
    case 3:
      if (start[0] == ':') {
        state = 4;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        return 104;
      }
      break;
    case 4:
      return getStringAndHash(start, first, last, hash);
    }
    ++start;
  }
  return 104;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readNextString>:
  endbr64
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r8
  test   %al,%al
  je     L56
  add    $0x2,%rdi
  cmp    $0x3a,%al
  je     L35
L79:
  cmp    $0x20,%al
  je     L38
  cmp    $0x9,%al
  je     L38
  cmp    $0xa,%al
  jne    L56
L38:
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  je     L56
  add    $0x1,%rdi
  cmp    $0x3a,%al
  jne    L79
L35:
  cmpb   $0x0,0x1(%r8)
  lea    0x1(%r8),%rdi
  je     L56
  jmp    1050 <getStringAndHash@plt>
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    $0x68,%eax
  ret
```

assistant: ```c
unsigned int readNextString(char *start, char **first, char **last, unsigned int *hash) {
  unsigned char state = 3;
  ++start;
  while (start[0] != '\0') {
    switch (state) {
    case 3:
      if (start[0] == ':') {
        state = 4;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        return 104;
      }
      break;
    case 4:
      return getStringAndHash(start, first, last, hash);
    }
    ++start;
  }
  return 104;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ldiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t ans;
  ans.quot = numer / denom;
  ans.rem = numer - ans.quot * denom;
  return ans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t ans;
  ans.quot = numer / denom;
  ans.rem = numer - ans.quot * denom;
  return ans;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t ans;
  ans.quot = numer / denom;
  ans.rem = numer - ans.quot * denom;
  return ans;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t ans;
  ans.quot = numer / denom;
  ans.rem = numer - ans.quot * denom;
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L55
L0:
  mov    -0x8(%rbp),%rax
  mov    %eax,%edi
  call   <point@plt>
  test   %eax,%eax
  jne    L20
  mov    $0x1,%eax
  jmp    L55
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    $0x0,%eax
  jmp    L55
L1:
  mov    $0x1,%eax
L55:
  leave
  ret
```

assistant: ```c
int real(char *s) {
  if (s == 0)
    return (0);
  if (!point((int)s))
    return (1);
  if (*s == 0)
    return (0);
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<real>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  call   <point@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L1
  cmpb   $0x0,(%rbx)
  setne  %al
  movzbl %al,%eax
L1:
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
int real(char *s) {
  if (s == 0)
    return (0);
  if (!point((int)s))
    return (1);
  if (*s == 0)
    return (0);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<real>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
  push   %rbx
  mov    %rdi,%rbx
  call   <point@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L11
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  setne  %al
L11:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
int real(char *s) {
  if (s == 0)
    return (0);
  if (!point((int)s))
    return (1);
  if (*s == 0)
    return (0);
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<real>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  call   <point@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L17
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  setne  %al
L17:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
int real(char *s) {
  if (s == 0)
    return (0);
  if (!point((int)s))
    return (1);
  if (*s == 0)
    return (0);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dot(double *a, double *b) {
  double ss = 0;
  ss += a[0] * b[0];
  ss += a[1] * b[1];
  ss += a[2] * b[2];
  return ss;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dot>:
  endbr64
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  addsd  D5(%rip),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: f64

tool: D5: 0

assistant: ```c
double dot(double *a, double *b) {
  double ss = 0;
  ss += a[0] * b[0];
  ss += a[1] * b[1];
  ss += a[2] * b[2];
  return ss;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dot>:
  endbr64
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  addsd  D7(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: f64

tool: D7: 0

assistant: ```c
double dot(double *a, double *b) {
  double ss = 0;
  ss += a[0] * b[0];
  ss += a[1] * b[1];
  ss += a[2] * b[2];
  return ss;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dot>:
  endbr64
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  addsd  D5(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: f64

tool: D5: 0

assistant: ```c
double dot(double *a, double *b) {
  double ss = 0;
  ss += a[0] * b[0];
  ss += a[1] * b[1];
  ss += a[2] * b[2];
  return ss;
}
```