ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<dmat_mul_a3>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    $0x1,%edx
  push   %rbx
  sub    $0x30,%rsp
  mov    0x68(%rsp),%r13d
  movsd  %xmm0,0x20(%rsp)
  mov    0x78(%rsp),%r14
  mov    %r8,0x18(%rsp)
  mov    0x80(%rsp),%ebx
  mov    %r9,0x10(%rsp)
  mov    0x70(%rsp),%r9
  mov    %r13d,%r8d
  mov    %r13d,%ecx
  push   $0x0
  push   $0x0
  push   $0x0
  mov    %r9,0x20(%rsp)
  call   <dsym_mul_kernel@plt>
  add    $0x18,%rsp
  mov    %r13d,%r8d
  mov    %r13d,%ecx
  push   $0x0
  mov    $0x1,%edx
  mov    %rbp,%rdi
  push   %rbx
  push   $0x1
  mov    0x20(%rsp),%r9
  mov    0x30(%rsp),%rsi
  call   <dsym_mul_kernel@plt>
  add    $0x18,%rsp
  mov    %r14,%r9
  mov    %r13d,%r8d
  push   $0x0
  mov    %r13d,%ecx
  mov    $0x1,%edx
  mov    %r15,%rsi
  push   $0x0
  mov    %r12,%rdi
  push   $0x0
  call   <dsym_mul_kernel@plt>
  add    $0x18,%rsp
  mov    %r14,%r9
  mov    %r13d,%r8d
  push   $0x0
  mov    %r13d,%ecx
  mov    $0x1,%edx
  mov    %rbp,%rdi
  push   $0x0
  push   $0x1
  mov    0x28(%rsp),%rsi
  call   <dsym_mul_kernel@plt>
  add    $0x20,%rsp
  test   %ebx,%ebx
  jne    L1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  movsd  0x18(%rsp),%xmm0
  add    $0x28,%rsp
  mov    %r13d,%esi
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <dmat_sym@plt>
```

assistant: ```c
void dmat_mul_a3(double **ax1, double **ax2, double **b11, double **b12, double **b21, double **b22, int n, double **cx1, double **cx2, double f, int flag) {
  dsym_mul_kernel(ax1, b11, 1., n, n, cx1, 0., 0, 0);
  dsym_mul_kernel(ax2, b21, 1., n, n, cx1, 1., flag, 0);
  dsym_mul_kernel(ax1, b12, 1., n, n, cx2, 0., 0, 0);
  dsym_mul_kernel(ax2, b22, 1., n, n, cx2, 1., 0, 0);
  if (flag)
    dmat_sym(cx2, n, f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dmat_mul_a3>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    $0x1,%edx
  push   %rbx
  sub    $0x30,%rsp
  mov    0x68(%rsp),%r13d
  movsd  %xmm0,0x20(%rsp)
  mov    0x78(%rsp),%r14
  mov    %r8,0x18(%rsp)
  mov    0x80(%rsp),%ebx
  mov    %r9,0x10(%rsp)
  mov    0x70(%rsp),%r9
  mov    %r13d,%r8d
  mov    %r13d,%ecx
  push   $0x0
  push   $0x0
  push   $0x0
  mov    %r9,0x20(%rsp)
  call   <dsym_mul_kernel@plt>
  add    $0x18,%rsp
  mov    %r13d,%r8d
  mov    %r13d,%ecx
  push   $0x0
  mov    $0x1,%edx
  mov    %rbp,%rdi
  push   %rbx
  push   $0x1
  mov    0x20(%rsp),%r9
  mov    0x30(%rsp),%rsi
  call   <dsym_mul_kernel@plt>
  add    $0x18,%rsp
  mov    %r14,%r9
  mov    %r13d,%r8d
  push   $0x0
  mov    %r13d,%ecx
  mov    $0x1,%edx
  mov    %r15,%rsi
  push   $0x0
  mov    %r12,%rdi
  push   $0x0
  call   <dsym_mul_kernel@plt>
  add    $0x18,%rsp
  mov    %r14,%r9
  mov    %r13d,%r8d
  push   $0x0
  mov    %r13d,%ecx
  mov    $0x1,%edx
  mov    %rbp,%rdi
  push   $0x0
  push   $0x1
  mov    0x28(%rsp),%rsi
  call   <dsym_mul_kernel@plt>
  add    $0x20,%rsp
  test   %ebx,%ebx
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L6:
  movsd  0x18(%rsp),%xmm0
  add    $0x28,%rsp
  mov    %r13d,%esi
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <dmat_sym@plt>
```

assistant: ```c
void dmat_mul_a3(double **ax1, double **ax2, double **b11, double **b12, double **b21, double **b22, int n, double **cx1, double **cx2, double f, int flag) {
  dsym_mul_kernel(ax1, b11, 1., n, n, cx1, 0., 0, 0);
  dsym_mul_kernel(ax2, b21, 1., n, n, cx1, 1., flag, 0);
  dsym_mul_kernel(ax1, b12, 1., n, n, cx2, 0., 0, 0);
  dsym_mul_kernel(ax2, b22, 1., n, n, cx2, 1., 0, 0);
  if (flag)
    dmat_sym(cx2, n, f);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<csx_free_match_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <match_table_free@plt>
L6:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
unsigned csx_free_match_table(struct csx_match_table **mt) {
  if (mt && *mt)
    match_table_free(mt);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<csx_free_match_table>:
  endbr64
  test   %rdi,%rdi
  je     L8
  cmpq   $0x0,(%rdi)
  je     L8
  sub    $0x8,%rsp
  call   <match_table_free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned csx_free_match_table(struct csx_match_table **mt) {
  if (mt && *mt)
    match_table_free(mt);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<csx_free_match_table>:
  endbr64
  test   %rdi,%rdi
  je     L10
  cmpq   $0x0,(%rdi)
  je     L10
  sub    $0x8,%rsp
  call   <match_table_free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned csx_free_match_table(struct csx_match_table **mt) {
  if (mt && *mt)
    match_table_free(mt);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<csx_free_match_table>:
  endbr64
  test   %rdi,%rdi
  je     L2
  cmpq   $0x0,(%rdi)
  je     L2
  sub    $0x8,%rsp
  call   <match_table_free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned csx_free_match_table(struct csx_match_table **mt) {
  if (mt && *mt)
    match_table_free(mt);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jle    L16
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L16:
  cmpq   $0x0,-0x10(%rbp)
  jne    L1
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    $0x0,%ecx
  lea    D24(%rip),%rax
  mov    %rax,%rdx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <execl@plt>
L1:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D24
type_infered: string
name: read_data
arguments: tag: D4
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string

tool: D9: exec end


tool: D24: ok

tool: D4: echo

tool: D20: /bin/echo

assistant: ```c
int main() {
  pid_t pid;
  pid = fork();
  if (pid > 0) {
    int status;
    wait(&status);
    printf("exec end\n");
  } else if (pid == 0) {
    sleep(3);
    execl("/bin/echo", "echo", "ok", (char *)0);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jg     L37
  jne    L6
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    $0x0,%ecx
  lea    D34(%rip),%rdx
  lea    D1(%rip),%rsi
  lea    D30(%rip),%rdi
  call   <execl@plt>
  jmp    L6
L37:
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D34
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D23
type_infered: string

tool: D34: ok

tool: D1: echo

tool: D30: /bin/echo

tool: D23: exec end


assistant: ```c
int main() {
  pid_t pid;
  pid = fork();
  if (pid > 0) {
    int status;
    wait(&status);
    printf("exec end\n");
  } else if (pid == 0) {
    sleep(3);
    execl("/bin/echo", "echo", "ok", (char *)0);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jg     L11
  je     L42
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L11:
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L42:
  mov    $0x3,%edi
  call   <sleep@plt>
  xor    %ecx,%ecx
  lea    D2(%rip),%rdx
  lea    D9(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <execl@plt>
  jmp    L3
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type_infered: string
name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string
name: disassemble_data
arguments: data_label: D23
type_infered: string

tool: D14: exec end


tool: D2: ok

tool: D9: echo

tool: D23: /bin/echo

assistant: ```c
int main() {
  pid_t pid;
  pid = fork();
  if (pid > 0) {
    int status;
    wait(&status);
    printf("exec end\n");
  } else if (pid == 0) {
    sleep(3);
    execl("/bin/echo", "echo", "ok", (char *)0);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jg     L30
  je     L49
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L30:
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L49:
  mov    $0x3,%edi
  call   <sleep@plt>
  xor    %ecx,%ecx
  lea    D27(%rip),%rdx
  lea    D34(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <execl@plt>
  jmp    L43
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D27
type_guessed: string
name: retrieve_data
arguments: data_tag: D34
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D17: exec end


tool: D27: ok

tool: D34: echo

tool: D0: /bin/echo

assistant: ```c
int main() {
  pid_t pid;
  pid = fork();
  if (pid > 0) {
    int status;
    wait(&status);
    printf("exec end\n");
  } else if (pid == 0) {
    sleep(3);
    execl("/bin/echo", "echo", "ok", (char *)0);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <varinfo5_main@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  varinfo5_main();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <varinfo5_main@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  varinfo5_main();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <varinfo5_main@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  varinfo5_main();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <varinfo5_main@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  varinfo5_main();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<iszero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L79
L12:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L62
  mov    $0x0,%eax
  jmp    L64
L62:
  subl   $0x4,-0xc(%rbp)
  addq   $0x4,-0x8(%rbp)
L79:
  cmpl   $0x3,-0xc(%rbp)
  jg     L12
  jmp    L78
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L52
  mov    $0x0,%eax
  jmp    L64
L52:
  subl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L78:
  cmpl   $0x0,-0xc(%rbp)
  jg     L3
  mov    $0x1,%eax
L64:
  pop    %rbp
  ret
```

assistant: ```c
int iszero(void *s, size_t n) {
  char *p;
  int cnt;
  p = (char *)s;
  cnt = n;
  for (; cnt >= 4; cnt -= 4, p += 4) {
    if (*(uint32_t *)p != 0x0)
      return 0;
  }
  for (; cnt > 0; cnt--, p++) {
    if (*p != 0x0)
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<iszero>:
  endbr64
  mov    %esi,%eax
  cmp    $0x3,%esi
  jle    L48
L18:
  cmpl   $0x0,(%rdi)
  jne    L26
  sub    $0x4,%eax
  add    $0x4,%rdi
  cmp    $0x3,%eax
  jg     L18
L48:
  test   %eax,%eax
  jle    L47
  mov    %eax,%eax
  add    %rdi,%rax
L34:
  cmpb   $0x0,(%rdi)
  jne    L17
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L34
  mov    $0x1,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
L47:
  mov    $0x1,%eax
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int iszero(void *s, size_t n) {
  char *p;
  int cnt;
  p = (char *)s;
  cnt = n;
  for (; cnt >= 4; cnt -= 4, p += 4) {
    if (*(uint32_t *)p != 0x0)
      return 0;
  }
  for (; cnt > 0; cnt--, p++) {
    if (*p != 0x0)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<iszero>:
  endbr64
  mov    %esi,%eax
  cmp    $0x3,%esi
  jg     L49
  jmp    L47
  nopl   (%rax)
L29:
  sub    $0x4,%eax
  add    $0x4,%rdi
  cmp    $0x3,%eax
  jle    L47
L49:
  mov    (%rdi),%edx
  test   %edx,%edx
  je     L29
L62:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L47:
  test   %eax,%eax
  jle    L88
  cltq
  add    %rdi,%rax
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L88
L15:
  cmpb   $0x0,(%rdi)
  je     L37
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L88:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iszero(void *s, size_t n) {
  char *p;
  int cnt;
  p = (char *)s;
  cnt = n;
  for (; cnt >= 4; cnt -= 4, p += 4) {
    if (*(uint32_t *)p != 0x0)
      return 0;
  }
  for (; cnt > 0; cnt--, p++) {
    if (*p != 0x0)
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<iszero>:
  endbr64
  mov    %esi,%eax
  cmp    $0x3,%esi
  jg     L71
  jmp    L65
  nopl   (%rax)
L74:
  sub    $0x4,%eax
  add    $0x4,%rdi
  cmp    $0x3,%eax
  jle    L65
L71:
  mov    (%rdi),%edx
  test   %edx,%edx
  je     L74
L73:
  xor    %eax,%eax
L27:
  ret
  nopl   (%rax)
L65:
  test   %eax,%eax
  jle    L43
  cmpb   $0x0,(%rdi)
  jne    L73
  sub    $0x1,%eax
  je     L43
  cmpb   $0x0,0x1(%rdi)
  jne    L73
  cmp    $0x1,%eax
  je     L27
  xor    %eax,%eax
  cmpb   $0x0,0x2(%rdi)
  sete   %al
  ret
L43:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iszero(void *s, size_t n) {
  char *p;
  int cnt;
  p = (char *)s;
  cnt = n;
  for (; cnt >= 4; cnt -= 4, p += 4) {
    if (*(uint32_t *)p != 0x0)
      return 0;
  }
  for (; cnt > 0; cnt--, p++) {
    if (*p != 0x0)
      return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cfunction_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  D12(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movss  D7(%rip),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_guessed: f32
name: retrieve_data
arguments: data_tag: D7
type_guessed: f32

tool: D12: 7

tool: D7: 8

assistant: ```c
void cfunction_(float *a, float *b) {
  *a = 7.0;
  *b = 8.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cfunction_>:
  endbr64
  movl   $0x40e00000,(%rdi)
  movl   $0x41000000,(%rsi)
  ret
```

assistant: ```c
void cfunction_(float *a, float *b) {
  *a = 7.0;
  *b = 8.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cfunction_>:
  endbr64
  movl   $0x40e00000,(%rdi)
  movl   $0x41000000,(%rsi)
  ret
```

assistant: ```c
void cfunction_(float *a, float *b) {
  *a = 7.0;
  *b = 8.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cfunction_>:
  endbr64
  movl   $0x40e00000,(%rdi)
  movl   $0x41000000,(%rsi)
  ret
```

assistant: ```c
void cfunction_(float *a, float *b) {
  *a = 7.0;
  *b = 8.0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x80000000,%eax
  mov    %rax,0x8(%rsp)
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  mov    (%rax),%esi
  lea    D55(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0xff,%esi
  mov    $0x91000000,%ebx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fillScreen@plt>
  mov    $0x1e8480,%edi
  mov    $0x0,%eax
  call   <usleep@plt>
  lea    D53(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ecx
  mov    $0xff,%edx
  mov    $0x0,%esi
  mov    $0xdeadbeef,%edi
  mov    $0x0,%eax
  call   <fillScreen@plt>
  mov    $0x1e8480,%edi
  mov    $0x0,%eax
  call   <usleep@plt>
  mov    $0xdeadbeef,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  movl   $0xdeadbeef,(%rax)
  mov    0x8(%rsp),%rax
  mov    (%rax),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1e8480,%edi
  mov    $0x0,%eax
  call   <usleep@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0xff,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fillScreen@plt>
  mov    $0x1e8480,%edi
  mov    $0x0,%eax
  call   <usleep@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
L6:
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string
name: disassemble_data
arguments: data_tag: D55
type_guessed: string
name: disassemble_data
arguments: data_tag: D31
type_guessed: string
name: disassemble_data
arguments: data_tag: D53
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string
name: disassemble_data
arguments: data_tag: D12
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D0: Startup.

tool: D55: Reading from AR: 0x%08x


tool: D31: Filling the screen red at current vmem address.

tool: D53: Filling the screen green at new vmem address.

tool: D19: Writing to AR (this should remap the bus to 0x%08x)


tool: D12: Filling the screen blue at old vmem address. NOTHING SHOULD HAPPEN!

tool: D9: Test done, looping.

assistant: ```c
int main() {
  unsigned char *firstVmem = (unsigned char *)0x91000000;
  unsigned char *secondVmem = (unsigned char *)0xDEADBEEF;
  unsigned int *volatile ar = (unsigned int *)0x80000000U;
  printf("Startup.\n");
  printf("Reading from AR: 0x%08x\n", *ar);
  printf("Filling the screen red at current vmem address.\n");
  fillScreen(firstVmem, 0xff, 0, 0);
  usleep(2 * 1000000);
  printf("Filling the screen green at new vmem address.\n");
  fillScreen(secondVmem, 0, 0xff, 0);
  usleep(2 * 1000000);
  printf("Writing to AR (this should remap the bus to 0x%08x)\n", 0xDEADBEEF);
  *ar = 0xDEADBEEF;
  printf("Reading from AR: 0x%08x\n", *ar);
  usleep(2 * 1000000);
  printf("Filling the screen blue at old vmem address. NOTHING SHOULD HAPPEN!\n");
  fillScreen(firstVmem, 0, 0, 0xff);
  usleep(2 * 1000000);
  printf("Test done, looping.\n");
  while (1)
    ;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x80000000,%eax
  lea    D50(%rip),%rdi
  lea    D51(%rip),%r12
  push   %rbp
  mov    $0x91000000,%ebp
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  mov    %r12,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0xff,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fillScreen@plt>
  mov    $0x1e8480,%edi
  xor    %eax,%eax
  call   <usleep@plt>
  lea    D62(%rip),%rdi
  call   <puts@plt>
  xor    %ecx,%ecx
  mov    $0xff,%edx
  xor    %esi,%esi
  mov    $0xdeadbeef,%edi
  xor    %eax,%eax
  call   <fillScreen@plt>
  mov    $0x1e8480,%edi
  xor    %eax,%eax
  call   <usleep@plt>
  mov    $0xdeadbeef,%esi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  mov    %r12,%rdi
  movl   $0xdeadbeef,(%rax)
  mov    0x8(%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1e8480,%edi
  xor    %eax,%eax
  call   <usleep@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0xff,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fillScreen@plt>
  mov    $0x1e8480,%edi
  xor    %eax,%eax
  call   <usleep@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
L2:
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_label: D50
data_type: string
name: unpack_data
arguments: data_label: D51
data_type: string
name: unpack_data
arguments: data_label: D33
data_type: string
name: unpack_data
arguments: data_label: D62
data_type: string
name: unpack_data
arguments: data_label: D42
data_type: string
name: unpack_data
arguments: data_label: D14
data_type: string
name: unpack_data
arguments: data_label: D39
data_type: string

tool: D50: Startup.

tool: D51: Reading from AR: 0x%08x


tool: D33: Filling the screen red at current vmem address.

tool: D62: Filling the screen green at new vmem address.

tool: D42: Writing to AR (this should remap the bus to 0x%08x)


tool: D14: Filling the screen blue at old vmem address. NOTHING SHOULD HAPPEN!

tool: D39: Test done, looping.

assistant: ```c
int main() {
  unsigned char *firstVmem = (unsigned char *)0x91000000;
  unsigned char *secondVmem = (unsigned char *)0xDEADBEEF;
  unsigned int *volatile ar = (unsigned int *)0x80000000U;
  printf("Startup.\n");
  printf("Reading from AR: 0x%08x\n", *ar);
  printf("Filling the screen red at current vmem address.\n");
  fillScreen(firstVmem, 0xff, 0, 0);
  usleep(2 * 1000000);
  printf("Filling the screen green at new vmem address.\n");
  fillScreen(secondVmem, 0, 0xff, 0);
  usleep(2 * 1000000);
  printf("Writing to AR (this should remap the bus to 0x%08x)\n", 0xDEADBEEF);
  *ar = 0xDEADBEEF;
  printf("Reading from AR: 0x%08x\n", *ar);
  usleep(2 * 1000000);
  printf("Filling the screen blue at old vmem address. NOTHING SHOULD HAPPEN!\n");
  fillScreen(firstVmem, 0, 0, 0xff);
  usleep(2 * 1000000);
  printf("Test done, looping.\n");
  while (1)
    ;
  return 0;
}
```