ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<encodeIFormat>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  js     L13
L15:
  mov    %r13d,%edi
  mov    $0x5,%esi
  call   <leftShift@plt>
  mov    $0x5,%esi
  lea    (%rax,%r12,1),%edi
  call   <leftShift@plt>
  mov    $0x10,%esi
  lea    (%rax,%rbp,1),%edi
  call   <leftShift@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  mov    $0x10,%edi
  call   <twoToThePowerOf@plt>
  add    %eax,%ebx
  jmp    L15
```

assistant: ```c
int encodeIFormat(int opcode, int rs, int rt, int immediate) {
  if (immediate < 0)
    immediate = immediate + twoToThePowerOf(16);
  return leftShift(leftShift(leftShift(opcode, 5) + rs, 5) + rt, 16) + immediate;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<encodeIFormat>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  js     L7
L15:
  mov    %r13d,%edi
  mov    $0x5,%esi
  call   <leftShift@plt>
  mov    $0x5,%esi
  lea    (%rax,%r12,1),%edi
  call   <leftShift@plt>
  mov    $0x10,%esi
  lea    (%rax,%rbp,1),%edi
  call   <leftShift@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x10,%edi
  call   <twoToThePowerOf@plt>
  add    %eax,%ebx
  jmp    L15
```

assistant: ```c
int encodeIFormat(int opcode, int rs, int rt, int immediate) {
  if (immediate < 0)
    immediate = immediate + twoToThePowerOf(16);
  return leftShift(leftShift(leftShift(opcode, 5) + rs, 5) + rt, 16) + immediate;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  mov    $0x1,%ebp
  test   %esi,%esi
  jle    L91
L23:
  mov    $0x1,%ecx
  lea    -0x1(%rsp),%rdi
L87:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,(%rdi,%rcx,1)
  mov    %eax,%edx
  mov    %ecx,%esi
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L87
L9:
  movslq %esi,%rsi
  movb   $0x0,(%rsp,%rsi,1)
  mov    %rsp,%rdi
  call   <strlen@plt>
  mov    %eax,%r9d
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L14
  mov    %rsp,%rax
  movslq %r9d,%rdx
  add    %rax,%rdx
  mov    $0x0,%ecx
L8:
  movzbl -0x1(%rdx),%esi
  movzbl (%rax),%edi
  mov    %dil,-0x1(%rdx)
  mov    %sil,(%rax)
  add    $0x1,%ecx
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %r8d,%ecx
  jl     L8
  cmp    $0xffffffff,%ebp
  je     L53
L15:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L91:
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  mov    $0xffffffff,%ebp
  test   %esi,%esi
  jne    L23
  jmp    L9
L14:
  cmp    $0xffffffff,%ebp
  jne    L15
  lea    0x1(%rax),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  test   %r9d,%r9d
  jle    L27
  jmp    L37
L53:
  lea    0x1(%r9),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
L37:
  movslq %r9d,%rdx
  lea    (%rsp,%rdx,1),%rax
  lea    -0x1(%rsp,%rdx,1),%rcx
  lea    -0x1(%r9),%edx
  sub    %rdx,%rcx
L94:
  movzbl -0x1(%rax),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L94
L27:
  movb   $0x2d,(%rsp)
  jmp    L15
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa(char *buf, int a) {
  char array[100];
  int i = 0, length;
  int temp, flag;
  flag = a > 0 ? 1 : (-1);
  temp = a > 0 ? a : -a;
  while (temp) {
    array[i] = temp % 10 + '0';
    temp /= 10;
    i++;
  }
  array[i] = '\0';
  length = strlen(array);
  for (i = 0; i < length / 2; i++) {
    temp = array[length - 1 - i];
    array[length - 1 - i] = array[i];
    array[i] = temp;
  }
  if (flag == -1) {
    array[length + 1] = '\0';
    for (i = length; i > 0; i--) {
      array[i] = array[i - 1];
    }
    array[0] = '-';
  }
  strcpy(buf, array);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itoa>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  test   %esi,%esi
  jle    L17
L71:
  mov    $0x1,%ecx
  mov    %rsp,%r12
  mov    $0xcccccccd,%edi
  lea    -0x1(%rsp),%r8
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %eax,%edx
  imul   %rdi,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  add    $0x30,%eax
  mov    %al,(%r8,%rcx,1)
  mov    %edx,%eax
  movslq %ecx,%rdx
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L51
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %eax,%r9d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L46
L121:
  movslq %r9d,%r10
  mov    %r12,%rax
  xor    %ecx,%ecx
  lea    (%r12,%r10,1),%rdx
  xchg   %ax,%ax
L79:
  movzbl -0x1(%rdx),%esi
  movzbl (%rax),%edi
  add    $0x1,%ecx
  sub    $0x1,%rdx
  add    $0x1,%rax
  mov    %dil,(%rdx)
  mov    %sil,-0x1(%rax)
  cmp    %r8d,%ecx
  jl     L79
  cmp    $0xffffffff,%ebx
  je     L80
L52:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0xffffffff,%ebx
  jne    L71
  mov    %rsp,%r12
  movb   $0x0,(%rsp)
  mov    $0xffffffff,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %eax,%r9d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jg     L121
L24:
  lea    0x1(%r9),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  cmp    $0x1,%r9d
  jne    L85
  mov    $0x1,%r10d
  jmp    L68
L80:
  lea    0x1(%r9),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
L68:
  sub    $0x1,%r9d
  lea    -0x1(%r10),%rsi
  lea    0x1(%rsp),%rdi
  mov    %r10,%rdx
  movslq %r9d,%r9
  sub    %r9,%rsi
  add    %r12,%rsi
  call   <memmove@plt>
L85:
  movb   $0x2d,(%rsp)
  jmp    L52
  nopl   0x0(%rax)
L46:
  cmp    $0xffffffff,%ebx
  jne    L52
  jmp    L24
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa(char *buf, int a) {
  char array[100];
  int i = 0, length;
  int temp, flag;
  flag = a > 0 ? 1 : (-1);
  temp = a > 0 ? a : -a;
  while (temp) {
    array[i] = temp % 10 + '0';
    temp /= 10;
    i++;
  }
  array[i] = '\0';
  length = strlen(array);
  for (i = 0; i < length / 2; i++) {
    temp = array[length - 1 - i];
    array[length - 1 - i] = array[i];
    array[i] = temp;
  }
  if (flag == -1) {
    array[length + 1] = '\0';
    for (i = length; i > 0; i--) {
      array[i] = array[i - 1];
    }
    array[0] = '-';
  }
  strcpy(buf, array);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itoa>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  test   %esi,%esi
  jle    L52
L65:
  mov    $0x1,%ecx
  mov    %rsp,%r12
  mov    $0xcccccccd,%edi
  lea    -0x1(%rsp),%r8
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %eax,%edx
  imul   %rdi,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  add    $0x30,%eax
  mov    %al,(%r8,%rcx,1)
  mov    %edx,%eax
  movslq %ecx,%rdx
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L54
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %eax,%r9d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L105
L97:
  movslq %r9d,%r10
  mov    %r12,%rax
  xor    %ecx,%ecx
  lea    (%r12,%r10,1),%rdx
  xchg   %ax,%ax
L62:
  movzbl -0x1(%rdx),%esi
  movzbl (%rax),%edi
  add    $0x1,%ecx
  sub    $0x1,%rdx
  add    $0x1,%rax
  mov    %dil,(%rdx)
  mov    %sil,-0x1(%rax)
  cmp    %r8d,%ecx
  jl     L62
  cmp    $0xffffffff,%ebx
  je     L102
L87:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  mov    $0xffffffff,%ebx
  jne    L65
  mov    %rsp,%r12
  movb   $0x0,(%rsp)
  mov    $0xffffffff,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %eax,%r9d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jg     L97
L123:
  lea    0x1(%r9),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  cmp    $0x1,%r9d
  jne    L45
  mov    $0x1,%r10d
  jmp    L17
L102:
  lea    0x1(%r9),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
L17:
  sub    $0x1,%r9d
  lea    -0x1(%r10),%rsi
  lea    0x1(%rsp),%rdi
  mov    %r10,%rdx
  movslq %r9d,%r9
  sub    %r9,%rsi
  add    %r12,%rsi
  call   <memmove@plt>
L45:
  movb   $0x2d,(%rsp)
  jmp    L87
  nopl   0x0(%rax)
L105:
  cmp    $0xffffffff,%ebx
  jne    L87
  jmp    L123
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa(char *buf, int a) {
  char array[100];
  int i = 0, length;
  int temp, flag;
  flag = a > 0 ? 1 : (-1);
  temp = a > 0 ? a : -a;
  while (temp) {
    array[i] = temp % 10 + '0';
    temp /= 10;
    i++;
  }
  array[i] = '\0';
  length = strlen(array);
  for (i = 0; i < length / 2; i++) {
    temp = array[length - 1 - i];
    array[length - 1 - i] = array[i];
    array[i] = temp;
  }
  if (flag == -1) {
    array[length + 1] = '\0';
    for (i = length; i > 0; i--) {
      array[i] = array[i - 1];
    }
    array[0] = '-';
  }
  strcpy(buf, array);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rop3_117_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_117_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = S | stk3;
  stk1 = *D & stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rop3_117_0_1>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%eax
  not    %eax
  or     %esi,%eax
  and    (%rdi),%al
  mov    %eax,%edi
  not    %edi
  and    %esi,%edi
  or     %edx,%eax
  not    %eax
  or     %edi,%eax
  not    %esi
  and    %edx,%esi
  and    (%rcx),%sil
  or     %esi,%eax
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void rop3_117_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = S | stk3;
  stk1 = *D & stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_117_0_1>:
  endbr64
  mov    %edx,%eax
  mov    %rdi,%rcx
  not    %eax
  or     %esi,%eax
  and    (%rdi),%al
  mov    %eax,%edi
  or     %edx,%eax
  not    %edi
  not    %eax
  and    %esi,%edi
  not    %esi
  or     %edi,%eax
  and    %edx,%esi
  and    (%rcx),%sil
  or     %esi,%eax
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void rop3_117_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = S | stk3;
  stk1 = *D & stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rop3_117_0_1>:
  endbr64
  mov    %edx,%eax
  mov    %rdi,%rcx
  not    %eax
  or     %esi,%eax
  and    (%rdi),%al
  mov    %eax,%edi
  or     %edx,%eax
  not    %edi
  not    %eax
  and    %esi,%edi
  not    %esi
  or     %edi,%eax
  and    %edx,%esi
  and    (%rcx),%sil
  or     %esi,%eax
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void rop3_117_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = S | stk3;
  stk1 = *D & stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<format_output_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %ecx,-0x40(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x15,-0x24(%rbp)
  subl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  movb   $0x0,-0x20(%rbp,%rax,1)
L23:
  mov    -0x34(%rbp),%eax
  cltd
  idivl  -0x40(%rbp)
  mov    %edx,%eax
  subl   $0x1,-0x24(%rbp)
  cltq
  lea    D3(%rip),%rdx
  movzbl (%rax,%rdx,1),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x34(%rbp),%eax
  cltd
  idivl  -0x40(%rbp)
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L25
  cmpl   $0x0,-0x24(%rbp)
  jne    L23
L25:
  movsbl -0x44(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x20(%rbp),%rdx
  lea    (%rdx,%rax,1),%rdi
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  call   <format_output_str@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: 0123456789ABCDEF

assistant: ```c
void format_output_uint(uint32_t value, int align, int w, int base, char pad) {
  char buf[21];
  int idx = sizeof(buf);
  buf[--idx] = 0;
  do {
    buf[--idx] = "0123456789ABCDEF"[value % base];
    value /= base;
  } while (value != 0 && idx != 0);
  format_output_str(buf + idx, align, w, pad);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<format_output_uint>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %esi,%r11d
  mov    %edx,%ebx
  mov    %ecx,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x14(%rsp)
  mov    $0x13,%esi
  lea    D3(%rip),%rcx
L3:
  mov    %esi,%r10d
  mov    %edi,%eax
  cltd
  idiv   %r9d
  movslq %edx,%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rsp,%rsi,1)
  mov    %eax,%edi
  test   %eax,%eax
  setne  %dl
  test   %esi,%esi
  setne  %al
  sub    $0x1,%rsi
  test   %al,%dl
  jne    L3
  movsbl %r8b,%ecx
  movslq %r10d,%r10
  lea    (%rsp,%r10,1),%rdi
  mov    %ebx,%edx
  mov    %r11d,%esi
  call   <format_output_str@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: 0123456789ABCDEF

assistant: ```c
void format_output_uint(uint32_t value, int align, int w, int base, char pad) {
  char buf[21];
  int idx = sizeof(buf);
  buf[--idx] = 0;
  do {
    buf[--idx] = "0123456789ABCDEF"[value % base];
    value /= base;
  } while (value != 0 && idx != 0);
  format_output_str(buf + idx, align, w, pad);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<format_output_uint>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  mov    %edi,%eax
  mov    %ecx,%r10d
  push   %rbx
  mov    %esi,%r11d
  mov    $0x13,%r9d
  lea    D3(%rip),%rcx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  movb   $0x0,0x14(%rsp)
  mov    %rsp,%rdi
  nopl   0x0(%rax,%rax,1)
L1:
  cltd
  movslq %r9d,%rbx
  idiv   %r10d
  movslq %edx,%rdx
  test   %eax,%eax
  movzbl (%rcx,%rdx,1),%edx
  setne  %sil
  test   %r9d,%r9d
  mov    %dl,(%rdi,%r9,1)
  setne  %dl
  sub    $0x1,%r9
  test   %dl,%sil
  jne    L1
  add    %rbx,%rdi
  movsbl %r8b,%ecx
  mov    %r12d,%edx
  mov    %r11d,%esi
  call   <format_output_str@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: 0123456789ABCDEF

assistant: ```c
void format_output_uint(uint32_t value, int align, int w, int base, char pad) {
  char buf[21];
  int idx = sizeof(buf);
  buf[--idx] = 0;
  do {
    buf[--idx] = "0123456789ABCDEF"[value % base];
    value /= base;
  } while (value != 0 && idx != 0);
  format_output_str(buf + idx, align, w, pad);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<format_output_uint>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  mov    %edi,%eax
  mov    %ecx,%r10d
  push   %rbx
  mov    %esi,%r11d
  mov    $0x13,%r9d
  lea    D3(%rip),%rcx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  movb   $0x0,0x14(%rsp)
  mov    %rsp,%rdi
  nopl   0x0(%rax,%rax,1)
L14:
  cltd
  movslq %r9d,%rbx
  idiv   %r10d
  movslq %edx,%rdx
  test   %eax,%eax
  movzbl (%rcx,%rdx,1),%edx
  setne  %sil
  test   %r9d,%r9d
  mov    %dl,(%rdi,%r9,1)
  setne  %dl
  sub    $0x1,%r9
  test   %dl,%sil
  jne    L14
  add    %rbx,%rdi
  movsbl %r8b,%ecx
  mov    %r12d,%edx
  mov    %r11d,%esi
  call   <format_output_str@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: 0123456789ABCDEF

assistant: ```c
void format_output_uint(uint32_t value, int align, int w, int base, char pad) {
  char buf[21];
  int idx = sizeof(buf);
  buf[--idx] = 0;
  do {
    buf[--idx] = "0123456789ABCDEF"[value % base];
    value /= base;
  } while (value != 0 && idx != 0);
  format_output_str(buf + idx, align, w, pad);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<matrixMult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x68(%rbp),%rax
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L4
L5:
  movl   $0x0,-0x5c(%rbp)
  jmp    L62
L43:
  movl   $0x0,-0x54(%rbp)
  jmp    L20
L65:
  mov    -0x58(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x5c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x58(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x54(%rbp),%eax
  add    %edx,%eax
  cltq
  movss  -0x50(%rbp,%rax,4),%xmm2
  mov    -0x54(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x5c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x58(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x5c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x54(%rbp)
L20:
  cmpl   $0x3,-0x54(%rbp)
  jle    L65
  addl   $0x1,-0x5c(%rbp)
L62:
  cmpl   $0x3,-0x5c(%rbp)
  jle    L43
  addl   $0x1,-0x58(%rbp)
L4:
  cmpl   $0x3,-0x58(%rbp)
  jle    L5
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void matrixMult(float a[16], const float b[16]) {
  int i, j, k;
  float aa[16];
  memcpy(aa, a, sizeof(aa));
  memset(a, 0, 16 * sizeof(float));
  for (j = 0; j < 4; j++) {
    for (i = 0; i < 4; i++) {
      for (k = 0; k < 4; k++) {
        a[4 * j + i] += aa[4 * j + k] * b[4 * k + i];
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matrixMult>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x40,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,%r9
  mov    %r12,%rdi
  mov    $0x0,%r10d
L6:
  lea    0x40(%rbx),%rsi
  mov    %rdi,%rcx
  mov    $0x0,%r8d
L26:
  lea    -0x40(%rsi),%rax
  mov    %r9,%rdx
L31:
  movss  (%rdx),%xmm0
  mulss  (%rax),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x4,%rdx
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L31
  add    $0x1,%r8d
  add    $0x4,%rcx
  add    $0x4,%rsi
  cmp    $0x4,%r8d
  jne    L26
  add    $0x10,%r9
  add    $0x4,%r10d
  add    $0x10,%rdi
  cmp    $0x10,%r10d
  jne    L6
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void matrixMult(float a[16], const float b[16]) {
  int i, j, k;
  float aa[16];
  memcpy(aa, a, sizeof(aa));
  memset(a, 0, 16 * sizeof(float));
  for (j = 0; j < 4; j++) {
    for (i = 0; i < 4; i++) {
      for (k = 0; k < 4; k++) {
        a[4 * j + i] += aa[4 * j + k] * b[4 * k + i];
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrixMult>:
  endbr64
  push   %r12
  mov    $0x40,%edx
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  mov    $0x40,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rbx,%r9
  mov    %rbp,%rdi
  xor    %r10d,%r10d
  lea    0x40(%r12),%r11
L37:
  mov    %r11,%rsi
  mov    %rdi,%rcx
  xor    %r8d,%r8d
L20:
  movss  (%rcx),%xmm1
  lea    -0x40(%rsi),%rax
  mov    %r9,%rdx
L11:
  movss  (%rdx),%xmm0
  mulss  (%rax),%xmm0
  add    $0x10,%rax
  add    $0x4,%rdx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rcx)
  cmp    %rax,%rsi
  jne    L11
  add    $0x1,%r8d
  add    $0x4,%rcx
  add    $0x4,%rsi
  cmp    $0x4,%r8d
  jne    L20
  add    $0x4,%r10d
  add    $0x10,%r9
  add    $0x10,%rdi
  cmp    $0x10,%r10d
  jne    L37
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void matrixMult(float a[16], const float b[16]) {
  int i, j, k;
  float aa[16];
  memcpy(aa, a, sizeof(aa));
  memset(a, 0, 16 * sizeof(float));
  for (j = 0; j < 4; j++) {
    for (i = 0; i < 4; i++) {
      for (k = 0; k < 4; k++) {
        a[4 * j + i] += aa[4 * j + k] * b[4 * k + i];
      }
    }
  }
}
```