ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L69:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%eax
  je     L69
  cmp    $0x20,%al
  je     L69
  movb   $0x0,0x1(%rbp)
  cmp    $0x2f,%eax
  ja     L223
  movabs $0x8c2000000400,%rax
  bt     %rbx,%rax
  jae    L223
L68:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L223:
  cmp    $0x2d,%ebx
  je     L53
L32:
  movsbl %bl,%r12d
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L137
  lea    -0x2d(%rbx),%eax
  cmp    $0x1,%eax
  ja     L142
L137:
  mov    %r12d,%edi
  call   <isdigit@plt>
  mov    $0x0,%r13d
  test   %rax,%rax
  je     L243
  mov    $0x1,%r12d
L133:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L133
L243:
  cmp    $0x2e,%ebx
  je     L33
L22:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L43
  mov    $0x30,%ebx
  jmp    L68
L53:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  lea    -0x9(%rax),%eax
  cmp    $0x1,%eax
  jbe    L136
  cmp    $0x20,%r12d
  je     L136
  mov    D3(%rip),%rax
  cmp    %r12d,(%rax)
  je     L136
  mov    %r12d,%edi
  call   <ungetch@plt>
  mov    %r12d,%ebx
  jmp    L32
L136:
  mov    %r12d,%edi
  call   <ungetch@plt>
  jmp    L68
L142:
  add    $0x1,%rbp
L214:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %rbp,%rcx
  mov    %al,0x0(%rbp)
  cmp    $0x20,%al
  je     L127
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L127
  add    $0x1,%rbp
  lea    -0x9(%rax),%edx
  cmp    $0x1,%edx
  ja     L214
L127:
  movb   $0x0,(%rcx)
  mov    $0x31,%ebx
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L68
  mov    %eax,%edi
  call   <ungetch@plt>
  jmp    L68
L33:
  lea    0x1(%r13),%r12d
  movslq %r12d,%r12
L170:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L170
  jmp    L22
L43:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x30,%ebx
  jmp    L68
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  char word[10];
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (c == '%' || c == '+' || c == '/' || c == '\n' || c == '*') {
    return c;
  }
  i = 0;
  if (c == '-') {
    if ((c = getch()) == ' ' || c == '\t' || c == EOF || c == '\n') {
      ungetch(c);
      return '-';
    } else
      ungetch(c);
  }
  if (!isdigit(c) && c != '.' && c != '-') {
    while ((s[++i] = c = getch()) != ' ' && c != EOF && c != '\n' && c != '\t')
      ;
    s[i] = '\0';
    if (c != EOF)
      ungetch(c);
    return '1';
  }
  if (isdigit(c))
    while (isdigit(s[++i] = c = getch()))
      ;
  if (c == '.') {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %esi,%ebx
  mov    %edx,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r9d
  shr    $0x1f,%r9d
  add    %eax,%r9d
  sar    %r9d
  lea    0x1(%r9),%r8d
  mov    %edx,%eax
  sub    %esi,%eax
  add    $0x1,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L6:
  cmp    %rdx,%rsp
  je     L61
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L61:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L81
  orq    $0x0,-0x8(%rsp,%rax,1)
L81:
  mov    %rsp,%r11
  cmp    %r9d,%ebx
  jg     L103
  cmp    %r8d,%r10d
  jl     L103
  mov    %ebx,%esi
  mov    $0x1,%eax
  jmp    L120
L141:
  add    $0x1,%r8d
  mov    %edi,%edx
L107:
  mov    %eax,%edi
  mov    %edx,-0x4(%r11,%rax,4)
  add    $0x1,%rax
  cmp    %r9d,%esi
  jg     L153
  cmp    %r10d,%r8d
  jg     L153
L120:
  movslq %esi,%rdx
  mov    (%rcx,%rdx,4),%edx
  movslq %r8d,%rdi
  mov    (%rcx,%rdi,4),%edi
  cmp    %edi,%edx
  jg     L141
  add    $0x1,%esi
  jmp    L107
L103:
  mov    %ebx,%esi
  mov    $0x0,%edi
L153:
  cmp    %esi,%r9d
  jl     L59
  movslq %esi,%rax
  movslq %edi,%rdx
  sub    %rax,%rdx
  lea    (%r11,%rdx,4),%r12
L64:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r9d
  jge    L64
  lea    0x1(%rdi,%r9,1),%edi
  sub    %esi,%edi
L59:
  cmp    %r8d,%r10d
  jl     L48
  movslq %r8d,%rax
  movslq %edi,%rdx
  sub    %rax,%rdx
  lea    (%r11,%rdx,4),%rsi
L92:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r10d
  jge    L92
  sub    %r8d,%edi
  lea    0x1(%rdi,%r10,1),%edi
L48:
  test   %edi,%edi
  jle    L11
  mov    %edi,%edi
  movslq %ebx,%rbx
  lea    (%rcx,%rbx,4),%rcx
  mov    $0x0,%eax
L127:
  mov    (%r11,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L127
L11:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L142
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L142:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __merge(int *a, int l, int r) {
  int m = (l + r) / 2;
  int i = l;
  int j = m + 1;
  int k = 0;
  int t[r - l + 1];
  while (i <= m && j <= r) {
    t[k++] = (a[i] <= a[j]) ? a[i++] : a[j++];
  }
  while (i <= m) {
    t[k++] = a[i++];
  }
  while (j <= r) {
    t[k++] = a[j++];
  }
  i = l;
  j = 0;
  while (j < k) {
    a[i++] = t[j++];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L34
  mov    $0xffffffff,%eax
  jmp    L20
L34:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L38
  mov    -0x14(%rbp),%eax
  jmp    L20
L38:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <find>
L20:
  leave
  ret
```

assistant: ```c
int find(int nums[], int target, int size, int index) {
  if (index >= size)
    return -1;
  if (nums[index] == target)
    return index;
  return find(nums, target, size, index + 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find>:
  endbr64
  cmp    %edx,%ecx
  jge    L18
  movslq %ecx,%r8
  mov    %ecx,%eax
  cmp    %esi,(%rdi,%r8,4)
  je     L11
  sub    $0x8,%rsp
  add    $0x1,%ecx
  call   <find>
  add    $0x8,%rsp
  ret
L18:
  mov    $0xffffffff,%eax
  ret
L11:
  ret
```

assistant: ```c
int find(int nums[], int target, int size, int index) {
  if (index >= size)
    return -1;
  if (nums[index] == target)
    return index;
  return find(nums, target, size, index + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find>:
  endbr64
  cmp    %ecx,%edx
  jle    L36
  movslq %ecx,%rcx
  jmp    L1
  nopl   (%rax)
L14:
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jle    L36
L1:
  mov    %ecx,%eax
  cmp    %esi,(%rdi,%rcx,4)
  jne    L14
  ret
L36:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int find(int nums[], int target, int size, int index) {
  if (index >= size)
    return -1;
  if (nums[index] == target)
    return index;
  return find(nums, target, size, index + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<find>:
  endbr64
  cmp    %ecx,%edx
  jle    L15
  movslq %ecx,%rcx
  jmp    L20
  nopl   (%rax)
L8:
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jle    L15
L20:
  mov    %ecx,%eax
  cmp    %esi,(%rdi,%rcx,4)
  jne    L8
  ret
L15:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int find(int nums[], int target, int size, int index) {
  if (index >= size)
    return -1;
  if (nums[index] == target)
    return index;
  return find(nums, target, size, index + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_column_address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x21,%edi
  call   <send_command@plt>
  mov    $0x0,%edi
  call   <send_command@plt>
  mov    $0x7f,%edi
  call   <send_command@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_column_address() {
  send_command(0x21);
  send_command(0x00);
  send_command(127);
}
```
user: What is the c source code of the assembly code below?

```asm
<set_column_address>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x21,%edi
  call   <send_command@plt>
  mov    $0x0,%edi
  call   <send_command@plt>
  mov    $0x7f,%edi
  call   <send_command@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void set_column_address() {
  send_command(0x21);
  send_command(0x00);
  send_command(127);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set_column_address>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x21,%edi
  call   <send_command@plt>
  xor    %edi,%edi
  call   <send_command@plt>
  mov    $0x7f,%edi
  add    $0x8,%rsp
  jmp    1050 <send_command@plt>
```

assistant: ```c
void set_column_address() {
  send_command(0x21);
  send_command(0x00);
  send_command(127);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_column_address>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x21,%edi
  call   <send_command@plt>
  xor    %edi,%edi
  call   <send_command@plt>
  mov    $0x7f,%edi
  add    $0x8,%rsp
  jmp    1050 <send_command@plt>
```

assistant: ```c
void set_column_address() {
  send_command(0x21);
  send_command(0x00);
  send_command(127);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_245_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  not    %eax
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_245_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~*D;
  stk1 = T | stk2;
  *D = stk1;
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_245_0_0>:
  endbr64
  movzbl (%rdi),%eax
  not    %eax
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_245_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~*D;
  stk1 = T | stk2;
  *D = stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rop3_245_0_0>:
  endbr64
  movzbl (%rdi),%eax
  not    %eax
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_245_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~*D;
  stk1 = T | stk2;
  *D = stk1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rop3_245_0_0>:
  endbr64
  movzbl (%rdi),%eax
  not    %eax
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_245_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~*D;
  stk1 = T | stk2;
  *D = stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *substr(char *origin, int from) {
  int len = strlen(origin);
  char *result = (char *)malloc(sizeof(char) * (len - from + 1));
  strcpy(result, origin + from);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<substr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  sub    %ebp,%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *substr(char *origin, int from) {
  int len = strlen(origin);
  char *result = (char *)malloc(sizeof(char) * (len - from + 1));
  strcpy(result, origin + from);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<substr>:
  endbr64
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    %ebp,%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *substr(char *origin, int from) {
  int len = strlen(origin);
  char *result = (char *)malloc(sizeof(char) * (len - from + 1));
  strcpy(result, origin + from);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<substr>:
  endbr64
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    %ebp,%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *substr(char *origin, int from) {
  int len = strlen(origin);
  char *result = (char *)malloc(sizeof(char) * (len - from + 1));
  strcpy(result, origin + from);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<spaced_primes_closest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L29:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D32(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cmp    %eax,-0x14(%rbp)
  jae    L30
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D32(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  jmp    L21
L30:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    D44(%rip),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L29
  mov    D44(%rip),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D32(%rip),%rax
  mov    (%rdx,%rax,1),%eax
L21:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D32
type_guessed: string
name: retrieve_data
arguments: tag: D44
type_guessed: byte[4]

tool: D32: 

tool: {"D44": [0x22,0x00,0x00,0x00]}

assistant: ```c
unsigned int spaced_primes_closest(unsigned int num) {
  static const unsigned int primes[] = {11, 19, 37, 73, 109, 163, 251, 367, 557, 823, 1237, 1861, 2777, 4177, 6247, 9371, 14057, 21089, 31627, 47431, 71143, 106721, 160073, 240101, 360163, 540217, 810343, 1215497, 1823231, 2734867, 4102283, 6153409, 9230113, 13845163};
  static const unsigned int nprimes = sizeof(primes) / sizeof(primes[0]);
  unsigned int i;
  for (i = 0; i < nprimes; i++)
    if (primes[i] > num)
      return primes[i];
  return primes[nprimes - 1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<spaced_primes_closest>:
  endbr64
  lea    D5(%rip),%rax
  lea    0x88(%rax),%rcx
L16:
  mov    (%rax),%edx
  cmp    %edi,%edx
  ja     L9
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L16
  mov    $0xd342ab,%edx
L9:
  mov    %edx,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: 

assistant: ```c
unsigned int spaced_primes_closest(unsigned int num) {
  static const unsigned int primes[] = {11, 19, 37, 73, 109, 163, 251, 367, 557, 823, 1237, 1861, 2777, 4177, 6247, 9371, 14057, 21089, 31627, 47431, 71143, 106721, 160073, 240101, 360163, 540217, 810343, 1215497, 1823231, 2734867, 4102283, 6153409, 9230113, 13845163};
  static const unsigned int nprimes = sizeof(primes) / sizeof(primes[0]);
  unsigned int i;
  for (i = 0; i < nprimes; i++)
    if (primes[i] > num)
      return primes[i];
  return primes[nprimes - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<spaced_primes_closest>:
  endbr64
  lea    D4(%rip),%rax
  mov    $0xb,%r8d
  lea    0x84(%rax),%rdx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L24:
  cmp    %rdx,%rax
  je     L26
  mov    (%rax),%r8d
  add    $0x4,%rax
L9:
  cmp    %r8d,%edi
  jae    L24
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L26:
  mov    $0xd342ab,%r8d
  mov    %r8d,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: 

assistant: ```c
unsigned int spaced_primes_closest(unsigned int num) {
  static const unsigned int primes[] = {11, 19, 37, 73, 109, 163, 251, 367, 557, 823, 1237, 1861, 2777, 4177, 6247, 9371, 14057, 21089, 31627, 47431, 71143, 106721, 160073, 240101, 360163, 540217, 810343, 1215497, 1823231, 2734867, 4102283, 6153409, 9230113, 13845163};
  static const unsigned int nprimes = sizeof(primes) / sizeof(primes[0]);
  unsigned int i;
  for (i = 0; i < nprimes; i++)
    if (primes[i] > num)
      return primes[i];
  return primes[nprimes - 1];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<spaced_primes_closest>:
  endbr64
  lea    D5(%rip),%rax
  lea    0x88(%rax),%rdx
  jmp    L24
  nopl   0x0(%rax)
L6:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L2
L24:
  mov    (%rax),%r8d
  cmp    %edi,%r8d
  jbe    L6
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L2:
  mov    $0xd342ab,%r8d
  mov    %r8d,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: 

assistant: ```c
unsigned int spaced_primes_closest(unsigned int num) {
  static const unsigned int primes[] = {11, 19, 37, 73, 109, 163, 251, 367, 557, 823, 1237, 1861, 2777, 4177, 6247, 9371, 14057, 21089, 31627, 47431, 71143, 106721, 160073, 240101, 360163, 540217, 810343, 1215497, 1823231, 2734867, 4102283, 6153409, 9230113, 13845163};
  static const unsigned int nprimes = sizeof(primes) / sizeof(primes[0]);
  unsigned int i;
  for (i = 0; i < nprimes; i++)
    if (primes[i] > num)
      return primes[i];
  return primes[nprimes - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cforth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <init_io@plt>
  mov    $0x0,%eax
  call   <init_forth@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <execute_word@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: app

assistant: ```c
cforth() {
  void *up;
  init_io();
  up = (void *)init_forth();
  execute_word("app", up);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cforth>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_io@plt>
  mov    $0x0,%eax
  call   <init_forth@plt>
  mov    %rax,%rsi
  lea    D5(%rip),%rdi
  call   <execute_word@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: app

assistant: ```c
cforth() {
  void *up;
  init_io();
  up = (void *)init_forth();
  execute_word("app", up);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cforth>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_io@plt>
  xor    %eax,%eax
  call   <init_forth@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  mov    %rax,%rsi
  jmp    1090 <execute_word@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D5: app

assistant: ```c
cforth() {
  void *up;
  init_io();
  up = (void *)init_forth();
  execute_word("app", up);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cforth>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_io@plt>
  xor    %eax,%eax
  call   <init_forth@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  mov    %rax,%rsi
  jmp    1090 <execute_word@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: app

assistant: ```c
cforth() {
  void *up;
  init_io();
  up = (void *)init_forth();
  execute_word("app", up);
}
```
user: Translate the below assembly code into C programming language:

```asm
<power10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L6
  mov    $0x1,%eax
  jmp    L11
L6:
  cmpl   $0x0,-0x14(%rbp)
  jns    L48
  mov    $0x0,%eax
  jmp    L11
L48:
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L2
L26:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L26
  mov    -0x8(%rbp),%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int power10(y)
int y;
{
  if (y == 0) {
    return 1;
  } else if (y < 0) {
    return 0;
  } else {
    int ret = 1;
    int i;
    for (i = 1; i <= y; i++) {
      ret *= 10;
    }
    return ret;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<power10>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L9
  mov    $0x0,%eax
  js     L9
  add    $0x1,%edi
  mov    $0x1,%edx
  mov    $0x1,%eax
L16:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L16
L9:
  ret
```

assistant: ```c
int power10(y)
int y;
{
  if (y == 0) {
    return 1;
  } else if (y < 0) {
    return 0;
  } else {
    int ret = 1;
    int i;
    for (i = 1; i <= y; i++) {
      ret *= 10;
    }
    return ret;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<power10>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L24
  mov    $0x0,%eax
  js     L24
  add    $0x1,%edi
  mov    $0x1,%edx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L28:
  lea    (%rax,%rax,4),%eax
  add    $0x1,%edx
  add    %eax,%eax
  cmp    %edi,%edx
  jne    L28
L24:
  ret
```

assistant: ```c
int power10(y)
int y;
{
  if (y == 0) {
    return 1;
  } else if (y < 0) {
    return 0;
  } else {
    int ret = 1;
    int i;
    for (i = 1; i <= y; i++) {
      ret *= 10;
    }
    return ret;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power10>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L42
  mov    $0x0,%eax
  js     L42
  cmp    $0x1,%edi
  je     L15
  movq   D4(%rip),%xmm0
  mov    %edi,%edx
  shr    %edx
  nopl   (%rax)
L30:
  movdqa %xmm0,%xmm1
  add    $0x1,%eax
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %eax,%edx
  jne    L30
  movd   %xmm0,%eax
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%edx
  imul   %edx,%eax
  and    $0x1,%edi
  je     L5
L40:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
L42:
  ret
  nopl   0x0(%rax)
L5:
  ret
  nopl   0x0(%rax)
L15:
  mov    $0x1,%eax
  jmp    L40
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: byte[8]

tool: {"D4": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int power10(y)
int y;
{
  if (y == 0) {
    return 1;
  } else if (y < 0) {
    return 0;
  } else {
    int ret = 1;
    int i;
    for (i = 1; i <= y; i++) {
      ret *= 10;
    }
    return ret;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<event_uninit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <signal_table_clean@plt>
  mov    $0x0,%eax
  call   <fd_list_clean@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void event_uninit(void) {
  signal_table_clean();
  fd_list_clean();
}
```