ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_table_create>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L69
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L70:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rbx,%rax,8)
  jne    L70
  lea    0x8(,%rdx,8),%edi
L12:
  call   <malloc@plt>
  mov    (%rbx),%rdi
  mov    %rax,%rbp
  mov    %rax,%r12
  sub    %rbx,%rbp
  test   %rdi,%rdi
  jne    L7
  jmp    L19
  nopl   (%rax)
L67:
  call   <strcpy@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L19
L7:
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  lea    (%rbx,%rbp,1),%rax
  mov    %rdi,(%rax)
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L67
  add    $0x8,%rbx
  movq   $0x0,(%rax)
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L7
L19:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L69:
  mov    $0x8,%edi
  jmp    L12
```

assistant: ```c
char **str_table_create(char *src[]) {
  int i;
  int n;
  int len;
  char **str_table_new;
  for (n = 0; src[n] != NULL; n++)
    ;
  str_table_new = (char **)malloc(sizeof(char *) * (n + 1));
  for (i = 0; src[i] != NULL; i++) {
    len = strlen(src[i]);
    str_table_new[i] = (char *)malloc(sizeof(char) * (len + 1));
    if (src[i] != NULL) {
      strcpy(str_table_new[i], src[i]);
    } else {
      str_table_new[i] = NULL;
    }
  }
  return str_table_new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_table_create>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L46
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rbx,%rax,8)
  jne    L17
  lea    0x8(,%rdx,8),%edi
L34:
  call   <malloc@plt>
  mov    (%rbx),%rdi
  mov    %rax,%rbp
  mov    %rax,%r12
  sub    %rbx,%rbp
  test   %rdi,%rdi
  je     L54
  nopl   0x0(%rax,%rax,1)
L13:
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  lea    0x0(%rbp,%rbx,1),%rax
  mov    %rdi,(%rax)
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L65
  call   <strcpy@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L13
L54:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  add    $0x8,%rbx
  movq   $0x0,(%rax)
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L13
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    $0x8,%edi
  jmp    L34
```

assistant: ```c
char **str_table_create(char *src[]) {
  int i;
  int n;
  int len;
  char **str_table_new;
  for (n = 0; src[n] != NULL; n++)
    ;
  str_table_new = (char **)malloc(sizeof(char *) * (n + 1));
  for (i = 0; src[i] != NULL; i++) {
    len = strlen(src[i]);
    str_table_new[i] = (char *)malloc(sizeof(char) * (len + 1));
    if (src[i] != NULL) {
      strcpy(str_table_new[i], src[i]);
    } else {
      str_table_new[i] = NULL;
    }
  }
  return str_table_new;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L32
  mov    $0x1,%eax
  jmp    L19
L32:
  cmpl   $0x0,-0x4(%rbp)
  jns    L23
  mov    $0xffffffff,%eax
  jmp    L19
L23:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int compare_str(const void *key1, const void *key2) {
  int retval;
  if ((retval = strcmp((const char *)key1, (const char *)key2)) > 0)
    return 1;
  else if (retval < 0)
    return -1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compare_str>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  cltd
  test   %eax,%eax
  mov    $0x1,%eax
  cmovle %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int compare_str(const void *key1, const void *key2) {
  int retval;
  if ((retval = strcmp((const char *)key1, (const char *)key2)) > 0)
    return 1;
  else if (retval < 0)
    return -1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare_str>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    $0x1,%edx
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  setne  %al
  neg    %eax
  test   %r8d,%r8d
  cmovg  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int compare_str(const void *key1, const void *key2) {
  int retval;
  if ((retval = strcmp((const char *)key1, (const char *)key2)) > 0)
    return 1;
  else if (retval < 0)
    return -1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compare_str>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    $0x1,%edx
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  setne  %al
  neg    %eax
  test   %r8d,%r8d
  cmovg  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int compare_str(const void *key1, const void *key2) {
  int retval;
  if ((retval = strcmp((const char *)key1, (const char *)key2)) > 0)
    return 1;
  else if (retval < 0)
    return -1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x80(%rbp)
  jmp    L38
L48:
  movl   $0x32,-0x7c(%rbp)
  jmp    L0
L30:
  mov    -0x7c(%rbp),%ecx
  mov    -0x80(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <print_header@plt>
  mov    -0x7c(%rbp),%edx
  mov    -0x80(%rbp),%ecx
  mov    -0x78(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <print_clb@plt>
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <print_footer@plt>
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  addl   $0xa,-0x7c(%rbp)
L0:
  cmpl   $0x64,-0x7c(%rbp)
  jle    L30
  addl   $0x1,-0x80(%rbp)
L38:
  cmpl   $0xa,-0x80(%rbp)
  jle    L48
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D8
data_type: string

tool: D15: frac_FI%d_I%d.xml

tool: D8: w

assistant: ```c
int main(void) {
  FILE *fpout;
  char fname[100];
  for (int i_FI = 5; i_FI <= 10; i_FI++) {
    for (int i_clbI = 50; i_clbI <= 100; i_clbI += 10) {
      sprintf(fname, "frac_FI%d_I%d.xml", i_FI, i_clbI);
      fpout = fopen(fname, "w");
      print_header(fpout);
      print_clb(fpout, i_FI, i_clbI);
      print_footer(fpout);
      fclose(fpout);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x5,%r12d
  mov    %rsp,%r13
  lea    D9(%rip),%r15
  lea    D7(%rip),%r14
L15:
  mov    $0x32,%ebp
L22:
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <print_header@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <print_clb@plt>
  mov    %rbx,%rdi
  call   <print_footer@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0xa,%ebp
  cmp    $0x6e,%ebp
  jne    L22
  add    $0x1,%r12d
  cmp    $0xb,%r12d
  jne    L15
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string
name: unpack_data
arguments: label: D7
type: string

tool: D9: frac_FI%d_I%d.xml

tool: D7: w

assistant: ```c
int main(void) {
  FILE *fpout;
  char fname[100];
  for (int i_FI = 5; i_FI <= 10; i_FI++) {
    for (int i_clbI = 50; i_clbI <= 100; i_clbI += 10) {
      sprintf(fname, "frac_FI%d_I%d.xml", i_FI, i_clbI);
      fpout = fopen(fname, "w");
      print_header(fpout);
      print_clb(fpout, i_FI, i_clbI);
      print_footer(fpout);
      fclose(fpout);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0x32,%r15d
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %r15d,%ecx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <print_header@plt>
  mov    %r15d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <print_clb@plt>
  mov    %rbp,%rdi
  add    $0xa,%r15d
  call   <print_footer@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  cmp    $0x6e,%r15d
  jne    L3
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L13
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D13: frac_FI%d_I%d.xml

tool: D5: w

assistant: ```c
int main(void) {
  FILE *fpout;
  char fname[100];
  for (int i_FI = 5; i_FI <= 10; i_FI++) {
    for (int i_clbI = 50; i_clbI <= 100; i_clbI += 10) {
      sprintf(fname, "frac_FI%d_I%d.xml", i_FI, i_clbI);
      fpout = fopen(fname, "w");
      print_header(fpout);
      print_clb(fpout, i_FI, i_clbI);
      print_footer(fpout);
      fclose(fpout);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x32,%r15d
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %r15d,%ecx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <print_header@plt>
  mov    %r15d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <print_clb@plt>
  mov    %rbp,%rdi
  add    $0xa,%r15d
  call   <print_footer@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  cmp    $0x6e,%r15d
  jne    L15
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L23
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string
name: unpack_data
arguments: label: D19
data_type: string

tool: D1: frac_FI%d_I%d.xml

tool: D19: w

assistant: ```c
int main(void) {
  FILE *fpout;
  char fname[100];
  for (int i_FI = 5; i_FI <= 10; i_FI++) {
    for (int i_clbI = 50; i_clbI <= 100; i_clbI += 10) {
      sprintf(fname, "frac_FI%d_I%d.xml", i_FI, i_clbI);
      fpout = fopen(fname, "w");
      print_header(fpout);
      print_clb(fpout, i_FI, i_clbI);
      print_footer(fpout);
      fclose(fpout);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L17
L15:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L17:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D24
data_type: string
name: disassemble_data
arguments: tag: D48
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D40
data_type: string

tool: D24: Enter a number: 

tool: D48: %d

tool: D28: Enter the values for the tickets: 

tool: D19: %d %d %d %d

tool: D40: %lf


assistant: ```c
int main(void) {
  int t, t1, t2, t3, t4;
  printf("Enter a number: ");
  scanf("%d", &t);
  while (t--) {
    printf("Enter the values for the tickets: ");
    scanf("%d %d %d %d", &t1, &t2, &t3, &t4);
    printf("%lf\n", (double)t1 / (t2 + t3));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L27
  lea    D30(%rip),%r13
  lea    0x14(%rsp),%r12
  lea    D33(%rip),%rbp
  lea    D9(%rip),%rbx
L22:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %r12,%r8
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mov    0x10(%rsp),%eax
  add    0xc(%rsp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L22
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: tag: D44
type_guessed: string
name: extract_symbolic_data
arguments: tag: D30
type_guessed: string
name: extract_symbolic_data
arguments: tag: D33
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D29: Enter a number: 

tool: D44: %d

tool: D30: Enter the values for the tickets: 

tool: D33: %d %d %d %d

tool: D9: %lf


assistant: ```c
int main(void) {
  int t, t1, t2, t3, t4;
  printf("Enter a number: ");
  scanf("%d", &t);
  while (t--) {
    printf("Enter the values for the tickets: ");
    scanf("%d %d %d %d", &t1, &t2, &t3, &t4);
    printf("%lf\n", (double)t1 / (t2 + t3));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L10
  lea    D32(%rip),%r15
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    D12(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  add    0xc(%rsp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x8(%rsp),%xmm0
  lea    D15(%rip),%rdi
  cvtsi2sd %eax,%xmm1
  mov    $0x1,%eax
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L3
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D32
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string

tool: D9: Enter a number: 

tool: D24: %d

tool: D32: Enter the values for the tickets: 

tool: D12: %d %d %d %d

tool: D15: %lf


assistant: ```c
int main(void) {
  int t, t1, t2, t3, t4;
  printf("Enter a number: ");
  scanf("%d", &t);
  while (t--) {
    printf("Enter the values for the tickets: ");
    scanf("%d %d %d %d", &t1, &t2, &t3, &t4);
    printf("%lf\n", (double)t1 / (t2 + t3));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D2(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L12
  lea    D25(%rip),%r15
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    D22(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  add    0xc(%rsp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x8(%rsp),%xmm0
  lea    D3(%rip),%rdi
  cvtsi2sd %eax,%xmm1
  mov    $0x1,%eax
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L17
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D1
type_infered: string
name: disassemble_data
arguments: data_label: D25
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: string
name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D2: Enter a number: 

tool: D1: %d

tool: D25: Enter the values for the tickets: 

tool: D22: %d %d %d %d

tool: D3: %lf


assistant: ```c
int main(void) {
  int t, t1, t2, t3, t4;
  printf("Enter a number: ");
  scanf("%d", &t);
  while (t--) {
    printf("Enter the values for the tickets: ");
    scanf("%d %d %d %d", &t1, &t2, &t3, &t4);
    printf("%lf\n", (double)t1 / (t2 + t3));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x9,-0x30(%rbp)
  movl   $0x8,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <print_arr@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <insertion_sort@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: 


assistant: ```c
int main() {
  int arr[] = {9, 8, 6, 7, 3, 5, 4, 1, 2};
  print_arr(arr, 9);
  printf("\n");
  insertion_sort(arr, 9);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x9,(%rsp)
  movl   $0x8,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x4,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  mov    %rsp,%rbx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <print_arr@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <insertion_sort@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: 


assistant: ```c
int main() {
  int arr[] = {9, 8, 6, 7, 3, 5, 4, 1, 2};
  print_arr(arr, 9);
  printf("\n");
  insertion_sort(arr, 9);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x9,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x800000009,%rax
  mov    %rsp,%rbp
  movl   $0x2,0x20(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000003,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000004,%rax
  mov    %rax,0x18(%rsp)
  call   <print_arr@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <insertion_sort@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: 


assistant: ```c
int main() {
  int arr[] = {9, 8, 6, 7, 3, 5, 4, 1, 2};
  print_arr(arr, 9);
  printf("\n");
  insertion_sort(arr, 9);
  return 0;
}
```