ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<IN_AL_DX>:
  endbr64
  mov    $0xec,%edi
  jmp    1050 <_c_setbyte@plt>
```

assistant: ```c
void IN_AL_DX() {
  ;
  _c_setbyte(0xec);
  ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<IN_AL_DX>:
  endbr64
  mov    $0xec,%edi
  jmp    1050 <_c_setbyte@plt>
```

assistant: ```c
void IN_AL_DX() {
  ;
  _c_setbyte(0xec);
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L3
L20:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L32
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
L32:
  addq   $0x2,-0x18(%rbp)
L3:
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  mov    -0x10(%rbp),%rax
  lea    0x26c0cc91(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (!(state[0UL] > local1)) {
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 792422477UL) + 0xfffffffff7856444UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x2626d7d6,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (!(state[0UL] > local1)) {
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 792422477UL) + 0xfffffffff7856444UL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x2626d7d6,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (!(state[0UL] > local1)) {
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 792422477UL) + 0xfffffffff7856444UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x2626d7d6,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (!(state[0UL] > local1)) {
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 792422477UL) + 0xfffffffff7856444UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ulmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <dump_error@plt>
L30:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L37
L25:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L7
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <dump_error@plt>
L7:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L25
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string
name: extract_symbolic_data
arguments: data_tag: D18
type: string

tool: D2: allocation failure 1 in ulmatrix()

tool: D18: allocation failure 2 in ulmatrix()

assistant: ```c
unsigned long **ulmatrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  unsigned long **m;
  m = (unsigned long **)malloc((unsigned)(nrh - nrl + 1) * sizeof(unsigned long *));
  if (!m)
    dump_error("allocation failure 1 in ulmatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (unsigned long *)malloc((unsigned)(nch - ncl + 1) * sizeof(unsigned long));
    if (!m[i])
      dump_error("allocation failure 2 in ulmatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ulmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %ecx,%r15d
  mov    %esi,%eax
  sub    %edi,%eax
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L45
L4:
  movslq %r14d,%rbx
  lea    0x0(,%rbx,8),%rax
  sub    %rax,%rbp
  cmp    %r14d,%r13d
  jl     L27
  sub    %r12d,%r15d
  lea    0x8(,%r15,8),%r14d
  movslq %r12d,%r12
  shl    $0x3,%r12
  neg    %r12
  lea    D8(%rip),%r15
  jmp    L54
L45:
  lea    D6(%rip),%rdi
  call   <dump_error@plt>
  jmp    L4
L9:
  add    %r12,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jl     L27
L54:
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  test   %rax,%rax
  jne    L9
  mov    %r15,%rdi
  call   <dump_error@plt>
  jmp    L9
L27:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D8: allocation failure 2 in ulmatrix()

tool: D6: allocation failure 1 in ulmatrix()

assistant: ```c
unsigned long **ulmatrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  unsigned long **m;
  m = (unsigned long **)malloc((unsigned)(nrh - nrl + 1) * sizeof(unsigned long *));
  if (!m)
    dump_error("allocation failure 1 in ulmatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (unsigned long *)malloc((unsigned)(nch - ncl + 1) * sizeof(unsigned long));
    if (!m[i])
      dump_error("allocation failure 2 in ulmatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ulmatrix>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  sub    %edi,%eax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    0x8(,%rax,8),%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L32
L18:
  movslq %r12d,%r14
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r12d,%ebp
  jl     L12
  sub    %ebx,%r13d
  shl    $0x3,%rbx
  lea    0x8(,%r13,8),%r12d
  neg    %rbx
  lea    D4(%rip),%r13
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L40:
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jl     L12
L69:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  jne    L40
  mov    %r13,%rdi
  call   <dump_error@plt>
  mov    (%r15,%r14,8),%rax
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L69
L12:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L32:
  lea    D19(%rip),%rdi
  call   <dump_error@plt>
  jmp    L18
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string
name: unpack_data
arguments: data_label: D19
data_type: string

tool: D4: allocation failure 2 in ulmatrix()

tool: D19: allocation failure 1 in ulmatrix()

assistant: ```c
unsigned long **ulmatrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  unsigned long **m;
  m = (unsigned long **)malloc((unsigned)(nrh - nrl + 1) * sizeof(unsigned long *));
  if (!m)
    dump_error("allocation failure 1 in ulmatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (unsigned long *)malloc((unsigned)(nch - ncl + 1) * sizeof(unsigned long));
    if (!m[i])
      dump_error("allocation failure 2 in ulmatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ulmatrix>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  sub    %edi,%eax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    0x8(,%rax,8),%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L23
L59:
  movslq %r12d,%r14
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r12d,%ebp
  jl     L30
  sub    %ebx,%r13d
  shl    $0x3,%rbx
  lea    0x8(,%r13,8),%r12d
  neg    %rbx
  lea    D12(%rip),%r13
  nopl   (%rax)
L48:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  je     L61
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L48
L30:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %r13,%rdi
  call   <dump_error@plt>
  add    %rbx,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L48
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L23:
  lea    D14(%rip),%rdi
  call   <dump_error@plt>
  jmp    L59
```

tool_calls: name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D14
type_infered: string

tool: D12: allocation failure 2 in ulmatrix()

tool: D14: allocation failure 1 in ulmatrix()

assistant: ```c
unsigned long **ulmatrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  unsigned long **m;
  m = (unsigned long **)malloc((unsigned)(nrh - nrl + 1) * sizeof(unsigned long *));
  if (!m)
    dump_error("allocation failure 1 in ulmatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (unsigned long *)malloc((unsigned)(nch - ncl + 1) * sizeof(unsigned long));
    if (!m[i])
      dump_error("allocation failure 2 in ulmatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_uitobase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x1,%edi
  call   <ft_strnew@plt>
  mov    %rax,D32(%rip)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L9
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <ft_uitobase>
L9:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    D32(%rip),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_chrjoin@plt>
  mov    %rax,D31(%rip)
  mov    D31(%rip),%rax
  leave
  ret
```

assistant: ```c
char *ft_uitobase(unsigned int n, char *str) {
  unsigned int base;
  static char *ret;
  ret = ft_strnew(1);
  base = (unsigned int)ft_strlen(str);
  if (n >= base)
    ft_uitobase(n / base, str);
  ret = ft_chrjoin(ret, str[(n % base)]);
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_uitobase>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x1,%edi
  call   <ft_strnew@plt>
  mov    %rax,D4(%rip)
  mov    %rbp,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%r12d
  cmp    %ebx,%eax
  jbe    L7
L8:
  mov    %ebx,%eax
  mov    $0x0,%edx
  div    %r12d
  movsbl 0x0(%rbp,%rdx,1),%esi
  mov    D4(%rip),%rdi
  call   <ft_chrjoin@plt>
  mov    %rax,D29(%rip)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    %ebx,%eax
  mov    $0x0,%edx
  div    %r12d
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <ft_uitobase>
  jmp    L8
```

assistant: ```c
char *ft_uitobase(unsigned int n, char *str) {
  unsigned int base;
  static char *ret;
  ret = ft_strnew(1);
  base = (unsigned int)ft_strlen(str);
  if (n >= base)
    ft_uitobase(n / base, str);
  ret = ft_chrjoin(ret, str[(n % base)]);
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_uitobase>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <ft_strnew@plt>
  mov    %rbp,%rdi
  mov    %rax,D4(%rip)
  call   <ft_strlen@plt>
  mov    %eax,%r12d
  cmp    %ebx,%eax
  jbe    L14
L6:
  mov    %ebx,%eax
  xor    %edx,%edx
  mov    D4(%rip),%rdi
  div    %r12d
  movsbl 0x0(%rbp,%rdx,1),%esi
  call   <ft_chrjoin@plt>
  pop    %rbx
  pop    %rbp
  mov    %rax,D10(%rip)
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  mov    %ebx,%eax
  xor    %edx,%edx
  mov    %rbp,%rsi
  div    %r12d
  mov    %eax,%edi
  call   <ft_uitobase>
  jmp    L6
```

assistant: ```c
char *ft_uitobase(unsigned int n, char *str) {
  unsigned int base;
  static char *ret;
  ret = ft_strnew(1);
  base = (unsigned int)ft_strlen(str);
  if (n >= base)
    ft_uitobase(n / base, str);
  ret = ft_chrjoin(ret, str[(n % base)]);
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_uitobase>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  sub    $0x18,%rsp
  call   <ft_strnew@plt>
  mov    %rbp,%rdi
  mov    %rax,D74(%rip)
  call   <ft_strlen@plt>
  mov    D74(%rip),%rdi
  mov    %eax,%r12d
  cmp    %ebx,%eax
  jbe    L2
L50:
  mov    %ebx,%eax
  xor    %edx,%edx
  div    %r12d
  movsbl 0x0(%rbp,%rdx,1),%esi
  call   <ft_chrjoin@plt>
  mov    %rax,D23(%rip)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L2:
  mov    %ebx,%eax
  xor    %edx,%edx
  mov    $0x1,%edi
  div    %r12d
  mov    %eax,%r13d
  call   <ft_strnew@plt>
  mov    %rbp,%rdi
  mov    %rax,D23(%rip)
  call   <ft_strlen@plt>
  mov    D23(%rip),%rdi
  mov    %eax,%r14d
  cmp    %eax,%r13d
  jae    L8
L58:
  mov    %r13d,%eax
  xor    %edx,%edx
  div    %r14d
  movsbl 0x0(%rbp,%rdx,1),%esi
  call   <ft_chrjoin@plt>
  mov    %rax,D23(%rip)
  mov    %rax,%rdi
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r13d,%eax
  xor    %edx,%edx
  mov    $0x1,%edi
  div    %r14d
  mov    %eax,%r15d
  call   <ft_strnew@plt>
  mov    %rbp,%rdi
  mov    %rax,D23(%rip)
  call   <ft_strlen@plt>
  mov    %eax,%ecx
  cmp    %eax,%r15d
  jae    L29
L57:
  mov    %r15d,%eax
  xor    %edx,%edx
  mov    D23(%rip),%rdi
  div    %ecx
  movsbl 0x0(%rbp,%rdx,1),%esi
  call   <ft_chrjoin@plt>
  mov    %rax,D23(%rip)
  mov    %rax,%rdi
  jmp    L58
  nop
L29:
  mov    %r15d,%eax
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    %ecx,0xc(%rsp)
  div    %ecx
  mov    %eax,%edi
  call   <ft_uitobase>
  mov    0xc(%rsp),%ecx
  jmp    L57
```

assistant: ```c
char *ft_uitobase(unsigned int n, char *str) {
  unsigned int base;
  static char *ret;
  ret = ft_strnew(1);
  base = (unsigned int)ft_strlen(str);
  if (n >= base)
    ft_uitobase(n / base, str);
  ret = ft_chrjoin(ret, str[(n % base)]);
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <foo@plt>
  cmp    $0xfffffffe,%eax
  je     L9
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L9:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (foo() != 0xfffffffffffffffeULL)
    __builtin_abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  cmp    $0xfffffffe,%eax
  jne    L13
L19:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L13:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
  jmp    L19
```

assistant: ```c
int main() {
  if (foo() != 0xfffffffffffffffeULL)
    __builtin_abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  cmp    $0xfffffffe,%eax
  je     L4
  xor    %eax,%eax
  call   <__builtin_abort@plt>
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo() != 0xfffffffffffffffeULL)
    __builtin_abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  cmp    $0xfffffffe,%eax
  je     L0
  xor    %eax,%eax
  call   <__builtin_abort@plt>
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo() != 0xfffffffffffffffeULL)
    __builtin_abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<funrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x38(%rbp)
  mov    %rdi,-0x40(%rbp)
  mov    %rsi,-0x48(%rbp)
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D34(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D49(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x30(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  movapd %xmm1,%xmm2
  divsd  -0x18(%rbp),%xmm2
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mulsd  -0x20(%rbp),%xmm1
  divsd  -0x18(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x48(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: f64
name: extract_symbolic_data
arguments: data_tag: D0
type: f64
name: extract_symbolic_data
arguments: data_tag: D34
type: f64
name: extract_symbolic_data
arguments: data_tag: D49
type: f64
name: extract_symbolic_data
arguments: data_tag: D26
type: f64

tool: D8: 160

tool: D0: 9.47

tool: D34: 0.98

tool: D49: 0.0375

tool: D26: 0.011

assistant: ```c
int funrk(x, ya, eq)
double x, ya[2], eq[2];
{
  double va, ra, kf, la, j, MC;
  va = (double)160.0;
  ra = (double)9.47;
  kf = (double)0.98;
  la = (double)0.0375;
  j = (double)0.011;
  MC = (double)0.0;
  eq[0] = (va / la) - (ra / la) * ya[0] - (kf * ya[1]) / la;
  eq[1] = (kf * ya[0] - MC) / j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<funrk>:
  endbr64
  movsd  D17(%rip),%xmm2
  mulsd  (%rdi),%xmm2
  movsd  D13(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D41(%rip),%xmm0
  movapd %xmm0,%xmm2
  mulsd  0x8(%rdi),%xmm2
  divsd  D42(%rip),%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,(%rsi)
  mulsd  (%rdi),%xmm0
  divsd  D38(%rip),%xmm0
  movsd  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D41
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D42
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D38
type_guessed: f64

tool: {"D17": [0x12,0x11,0x11,0x11,0x11,0x91,0x6f,0x40]}

tool: {"D13": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0xb0,0x40]}

tool: D41: 0.98

tool: D42: 0.0375

tool: D38: 0.011

assistant: ```c
int funrk(x, ya, eq)
double x, ya[2], eq[2];
{
  double va, ra, kf, la, j, MC;
  va = (double)160.0;
  ra = (double)9.47;
  kf = (double)0.98;
  la = (double)0.0375;
  j = (double)0.011;
  MC = (double)0.0;
  eq[0] = (va / la) - (ra / la) * ya[0] - (kf * ya[1]) / la;
  eq[1] = (kf * ya[0] - MC) / j;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<funrk>:
  endbr64
  movsd  D29(%rip),%xmm2
  mulsd  (%rdi),%xmm2
  movsd  D9(%rip),%xmm0
  movapd %xmm0,%xmm1
  movsd  D22(%rip),%xmm0
  subsd  %xmm2,%xmm1
  movsd  0x8(%rdi),%xmm2
  mulsd  %xmm0,%xmm2
  divsd  D14(%rip),%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,(%rsi)
  mulsd  (%rdi),%xmm0
  divsd  D24(%rip),%xmm0
  movsd  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D29
type_guessed: byte[8]
name: read_data
arguments: data_tag: D9
type_guessed: byte[8]
name: read_data
arguments: data_tag: D22
type_guessed: f64
name: read_data
arguments: data_tag: D14
type_guessed: f64
name: read_data
arguments: data_tag: D24
type_guessed: f64

tool: {"D29": [0x12,0x11,0x11,0x11,0x11,0x91,0x6f,0x40]}

tool: {"D9": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0xb0,0x40]}

tool: D22: 0.98

tool: D14: 0.0375

tool: D24: 0.011

assistant: ```c
int funrk(x, ya, eq)
double x, ya[2], eq[2];
{
  double va, ra, kf, la, j, MC;
  va = (double)160.0;
  ra = (double)9.47;
  kf = (double)0.98;
  la = (double)0.0375;
  j = (double)0.011;
  MC = (double)0.0;
  eq[0] = (va / la) - (ra / la) * ya[0] - (kf * ya[1]) / la;
  eq[1] = (kf * ya[0] - MC) / j;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<funrk>:
  endbr64
  movsd  D18(%rip),%xmm2
  mulsd  (%rdi),%xmm2
  movsd  D44(%rip),%xmm0
  movapd %xmm0,%xmm1
  movsd  D16(%rip),%xmm0
  subsd  %xmm2,%xmm1
  movsd  0x8(%rdi),%xmm2
  mulsd  %xmm0,%xmm2
  divsd  D17(%rip),%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,(%rsi)
  mulsd  (%rdi),%xmm0
  divsd  D47(%rip),%xmm0
  movsd  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
datatype: byte[8]
name: retrieve_data
arguments: tag: D44
datatype: byte[8]
name: retrieve_data
arguments: tag: D16
datatype: f64
name: retrieve_data
arguments: tag: D17
datatype: f64
name: retrieve_data
arguments: tag: D47
datatype: f64

tool: {"D18": [0x12,0x11,0x11,0x11,0x11,0x91,0x6f,0x40]}

tool: {"D44": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0xb0,0x40]}

tool: D16: 0.98

tool: D17: 0.0375

tool: D47: 0.011

assistant: ```c
int funrk(x, ya, eq)
double x, ya[2], eq[2];
{
  double va, ra, kf, la, j, MC;
  va = (double)160.0;
  ra = (double)9.47;
  kf = (double)0.98;
  la = (double)0.0375;
  j = (double)0.011;
  MC = (double)0.0;
  eq[0] = (va / la) - (ra / la) * ya[0] - (kf * ya[1]) / la;
  eq[1] = (kf * ya[0] - MC) / j;
}
```