ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ft_atoi>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L44
  lea    -0x30(%rax),%esi
  xor    %edx,%edx
  mov    $0x1,%ecx
  cmp    $0x9,%sil
  ja     L18
L41:
  add    $0x1,%edx
  xor    %r8d,%r8d
  movslq %edx,%rdx
  add    %rdx,%rdi
  nopw   0x0(%rax,%rax,1)
L23:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl -0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L23
  mov    %r8d,%eax
  neg    %eax
  cmp    $0xffffffff,%ecx
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L44:
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L18
  mov    $0x1,%edx
  mov    $0xffffffff,%ecx
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_atoi(char *input) {
  int res;
  int signe;
  int i;
  i = 0;
  signe = 1;
  if (input[0] == '-') {
    i = 1;
    signe = -1;
  }
  res = 0;
  while (input[i] && input[i] >= '0' && input[i] <= '9') {
    res = res * 10 + (input[i] - 48);
    i++;
  }
  if (signe == -1)
    return (-res);
  return (res);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_atoi>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L5
  lea    -0x30(%rax),%esi
  xor    %edx,%edx
  mov    $0x1,%ecx
  cmp    $0x9,%sil
  ja     L17
L43:
  add    $0x1,%edx
  xor    %r8d,%r8d
  movslq %edx,%rdx
  add    %rdx,%rdi
  nopw   0x0(%rax,%rax,1)
L31:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl -0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L31
  mov    %r8d,%eax
  neg    %eax
  cmp    $0xffffffff,%ecx
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L5:
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L17
  mov    $0x1,%edx
  mov    $0xffffffff,%ecx
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_atoi(char *input) {
  int res;
  int signe;
  int i;
  i = 0;
  signe = 1;
  if (input[0] == '-') {
    i = 1;
    signe = -1;
  }
  res = 0;
  while (input[i] && input[i] >= '0' && input[i] <= '9') {
    res = res * 10 + (input[i] - 48);
    i++;
  }
  if (signe == -1)
    return (-res);
  return (res);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reject>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string

tool: D3: Rejected


assistant: ```c
void reject() {
  printf("Rejected\n");
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reject>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D6: Rejected


assistant: ```c
void reject() {
  printf("Rejected\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reject>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: Rejected


assistant: ```c
void reject() {
  printf("Rejected\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<reject>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D0: Rejected


assistant: ```c
void reject() {
  printf("Rejected\n");
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <botan_fpe_init@plt>
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <botan_fpe_encrypt@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <botan_fpe_decrypt@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_guessed: string

tool: D13: %s 
 

assistant: ```c
int main(int argc, char *argv[]) {
  botan_fpe_init();
  printf("%s \n ", argv[1]);
  const char *enc = botan_fpe_encrypt(argv[1], 5, argv[3], argv[2]);
  printf("%s \n ", enc);
  const char *dec = botan_fpe_decrypt(enc, 5, argv[3], argv[2]);
  printf("%s \n ", dec);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <botan_fpe_init@plt>
  mov    0x8(%rbx),%rsi
  lea    D1(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x10(%rbx),%rcx
  mov    0x18(%rbx),%rdx
  mov    0x8(%rbx),%rdi
  mov    $0x5,%esi
  call   <botan_fpe_encrypt@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x10(%rbx),%rcx
  mov    0x18(%rbx),%rdx
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <botan_fpe_decrypt@plt>
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: %s 
 

assistant: ```c
int main(int argc, char *argv[]) {
  botan_fpe_init();
  printf("%s \n ", argv[1]);
  const char *enc = botan_fpe_encrypt(argv[1], 5, argv[3], argv[2]);
  printf("%s \n ", enc);
  const char *dec = botan_fpe_decrypt(enc, 5, argv[3], argv[2]);
  printf("%s \n ", dec);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <botan_fpe_init@plt>
  mov    0x8(%rbx),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x10(%rbx),%rcx
  mov    0x18(%rbx),%rdx
  mov    $0x5,%esi
  mov    0x8(%rbx),%rdi
  call   <botan_fpe_encrypt@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    0x10(%rbx),%rcx
  mov    0x18(%rbx),%rdx
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <botan_fpe_decrypt@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: %s 
 

assistant: ```c
int main(int argc, char *argv[]) {
  botan_fpe_init();
  printf("%s \n ", argv[1]);
  const char *enc = botan_fpe_encrypt(argv[1], 5, argv[3], argv[2]);
  printf("%s \n ", enc);
  const char *dec = botan_fpe_decrypt(enc, 5, argv[3], argv[2]);
  printf("%s \n ", dec);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <botan_fpe_init@plt>
  mov    0x8(%rbx),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x10(%rbx),%rcx
  mov    0x18(%rbx),%rdx
  mov    $0x5,%esi
  mov    0x8(%rbx),%rdi
  call   <botan_fpe_encrypt@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    0x10(%rbx),%rcx
  mov    0x18(%rbx),%rdx
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <botan_fpe_decrypt@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: %s 
 

assistant: ```c
int main(int argc, char *argv[]) {
  botan_fpe_init();
  printf("%s \n ", argv[1]);
  const char *enc = botan_fpe_encrypt(argv[1], 5, argv[3], argv[2]);
  printf("%s \n ", enc);
  const char *dec = botan_fpe_decrypt(enc, 5, argv[3], argv[2]);
  printf("%s \n ", dec);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8_to_ucs4_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <utf8_to_ucs4_buf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L8
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L8:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int utf8_to_ucs4_str(int *out, const unsigned char *in) {
  size_t in_size = strlen(in);
  int out_size = utf8_to_ucs4_buf(out, in, in_size);
  if (out_size >= 0)
    out[out_size] = 0;
  return out_size;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<utf8_to_ucs4_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <utf8_to_ucs4_buf@plt>
  test   %eax,%eax
  js     L8
  movslq %eax,%rdx
  movl   $0x0,0x0(%rbp,%rdx,4)
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int utf8_to_ucs4_str(int *out, const unsigned char *in) {
  size_t in_size = strlen(in);
  int out_size = utf8_to_ucs4_buf(out, in, in_size);
  if (out_size >= 0)
    out[out_size] = 0;
  return out_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_to_ucs4_str>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  call   <utf8_to_ucs4_buf@plt>
  test   %eax,%eax
  js     L0
  movslq %eax,%rdx
  movl   $0x0,(%rbx,%rdx,4)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int utf8_to_ucs4_str(int *out, const unsigned char *in) {
  size_t in_size = strlen(in);
  int out_size = utf8_to_ucs4_buf(out, in, in_size);
  if (out_size >= 0)
    out[out_size] = 0;
  return out_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_to_ucs4_str>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  call   <utf8_to_ucs4_buf@plt>
  test   %eax,%eax
  js     L9
  movslq %eax,%rdx
  movl   $0x0,(%rbx,%rdx,4)
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int utf8_to_ucs4_str(int *out, const unsigned char *in) {
  size_t in_size = strlen(in);
  int out_size = utf8_to_ucs4_buf(out, in, in_size);
  if (out_size >= 0)
    out[out_size] = 0;
  return out_size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dos_copy_to_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L6
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L6
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isascii@plt>
  test   %rax,%rax
  jne    L4
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void dos_copy_to_info(char *to, int tosz, char *from, int fromsz) {
  int i;
  for (i = 0; i < tosz && i < fromsz && isascii(from[i]); i++)
    to[i] = from[i];
  to[i] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dos_copy_to_info>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  test   %esi,%esi
  jle    L38
  mov    %rdx,%r12
  mov    %esi,%r14d
  mov    $0x0,%ebx
L14:
  mov    %ebx,%ebp
  movsbl (%r12,%rbx,1),%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L23
  movzbl (%r12,%rbx,1),%eax
  mov    %al,0x0(%r13,%rbx,1)
  lea    0x1(%rbx),%ebp
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L14
L23:
  movslq %ebp,%rbp
  movb   $0x0,0x0(%r13,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  mov    $0x0,%ebp
  jmp    L23
```

assistant: ```c
void dos_copy_to_info(char *to, int tosz, char *from, int fromsz) {
  int i;
  for (i = 0; i < tosz && i < fromsz && isascii(from[i]); i++)
    to[i] = from[i];
  to[i] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dos_copy_to_info>:
  endbr64
  cmp    %ecx,%esi
  push   %r14
  mov    %rdi,%rax
  cmovle %esi,%ecx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %ecx,%ecx
  jle    L9
  mov    %ecx,%r14d
  mov    %rdi,%r12
  mov    %rdx,%rbx
  xor    %ebp,%ebp
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L10:
  movzbl (%rbx),%edx
  add    $0x1,%ebp
  add    $0x1,%rbx
  mov    %dl,(%r12)
  lea    0x1(%rax),%r12
  cmp    %r14d,%ebp
  je     L32
L6:
  movsbl (%rbx),%edi
  call   <isascii@plt>
  mov    %rax,%r8
  mov    %r12,%rax
  test   %r8,%r8
  jne    L10
L9:
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  movslq %ebp,%rbp
  lea    0x0(%r13,%rbp,1),%rax
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void dos_copy_to_info(char *to, int tosz, char *from, int fromsz) {
  int i;
  for (i = 0; i < tosz && i < fromsz && isascii(from[i]); i++)
    to[i] = from[i];
  to[i] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dos_copy_to_info>:
  endbr64
  cmp    %ecx,%esi
  push   %r14
  mov    %rdi,%rax
  cmovle %esi,%ecx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %ecx,%ecx
  jle    L39
  mov    %ecx,%r14d
  mov    %rdi,%r12
  mov    %rdx,%rbx
  xor    %ebp,%ebp
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%rbx),%edx
  add    $0x1,%ebp
  add    $0x1,%rbx
  mov    %dl,(%r12)
  lea    0x1(%rax),%r12
  cmp    %r14d,%ebp
  je     L18
L10:
  movsbl (%rbx),%edi
  call   <isascii@plt>
  mov    %rax,%r8
  mov    %r12,%rax
  test   %r8,%r8
  jne    L9
L39:
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  movslq %ebp,%rbp
  lea    0x0(%r13,%rbp,1),%rax
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void dos_copy_to_info(char *to, int tosz, char *from, int fromsz) {
  int i;
  for (i = 0; i < tosz && i < fromsz && isascii(from[i]); i++)
    to[i] = from[i];
  to[i] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_frame@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <print_frame@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D5: expected: 

tool: D1: received: 

assistant: ```c
void print_compare(struct can_frame *exp, struct can_frame *rec) {
  printf("expected: ");
  print_frame(exp);
  printf("received: ");
  print_frame(rec);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_compare>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_frame@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <print_frame@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D11
type: string

tool: D13: expected: 

tool: D11: received: 

assistant: ```c
void print_compare(struct can_frame *exp, struct can_frame *rec) {
  printf("expected: ");
  print_frame(exp);
  printf("received: ");
  print_frame(rec);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_compare>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <print_frame@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <print_frame@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string

tool: D7: expected: 

tool: D11: received: 

assistant: ```c
void print_compare(struct can_frame *exp, struct can_frame *rec) {
  printf("expected: ");
  print_frame(exp);
  printf("received: ");
  print_frame(rec);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_compare>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D8(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <print_frame@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <print_frame@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D19
type: string

tool: D8: expected: 

tool: D19: received: 

assistant: ```c
void print_compare(struct can_frame *exp, struct can_frame *rec) {
  printf("expected: ");
  print_frame(exp);
  printf("received: ");
  print_frame(rec);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_move_past_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L35
L13:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    $0x0,%eax
  jmp    L14
L31:
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
char *_move_past_whitespace(char *buf) {
  while (*buf != '\0' && isspace(*buf))
    buf++;
  if (*buf == '\0')
    return NULL;
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_move_past_whitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L0
L27:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L49
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L27
L0:
  mov    $0x0,%ebx
  jmp    L9
L49:
  cmpb   $0x0,(%rbx)
  je     L29
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
L29:
  mov    $0x0,%ebx
  jmp    L9
```

assistant: ```c
char *_move_past_whitespace(char *buf) {
  while (*buf != '\0' && isspace(*buf))
    buf++;
  if (*buf == '\0')
    return NULL;
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_move_past_whitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L29
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L28:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L36
L29:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
  cmpb   $0x0,(%r12)
  je     L36
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L36:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *_move_past_whitespace(char *buf) {
  while (*buf != '\0' && isspace(*buf))
    buf++;
  if (*buf == '\0')
    return NULL;
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_move_past_whitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L10
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L8
L10:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
  cmpb   $0x0,(%r12)
  je     L8
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L8:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *_move_past_whitespace(char *buf) {
  while (*buf != '\0' && isspace(*buf))
    buf++;
  if (*buf == '\0')
    return NULL;
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ws_random_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <random@plt>
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ws_random_mask(void) {
  if (sizeof(long) >= 4) {
    return (uint32_t)random();
  } else if (sizeof(long) == 2) {
    return (uint32_t)random() << 16 | (uint32_t)random();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ws_random_mask>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t ws_random_mask(void) {
  if (sizeof(long) >= 4) {
    return (uint32_t)random();
  } else if (sizeof(long) == 2) {
    return (uint32_t)random() << 16 | (uint32_t)random();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ws_random_mask>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t ws_random_mask(void) {
  if (sizeof(long) >= 4) {
    return (uint32_t)random();
  } else if (sizeof(long) == 2) {
    return (uint32_t)random() << 16 | (uint32_t)random();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ws_random_mask>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t ws_random_mask(void) {
  if (sizeof(long) >= 4) {
    return (uint32_t)random();
  } else if (sizeof(long) == 2) {
    return (uint32_t)random() << 16 | (uint32_t)random();
  }
}
```