ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fibonacci_search>:
  endbr64
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  lea    -0x1(%r13),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <fibonacci@plt>
  mov    (%rsp),%ecx
  cmp    %ecx,%r13d
  jl     L30
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %edx,%eax
  add    $0x1,%rdx
  mov    -0x4(%r14,%rdx,4),%ecx
  cmp    %r13d,%ecx
  jle    L16
L95:
  lea    -0x1(%rcx),%edx
  cmp    %edx,%r13d
  jge    L98
  sub    %r13d,%ecx
  movslq %r12d,%rdx
  sub    $0x2,%ecx
  shl    $0x2,%rdx
  add    %r13,%rcx
  lea    (%rbx,%rdx,1),%rdi
  lea    0x4(%rbx,%rdx,1),%rdx
  lea    0x4(%rbx,%rcx,4),%rsi
  cs nopw 0x0(%rax,%rax,1)
L128:
  mov    (%rdi),%ecx
  add    $0x4,%rdx
  mov    %ecx,-0x4(%rdx)
  cmp    %rdx,%rsi
  jne    L128
L98:
  test   %r12d,%r12d
  js     L115
  xor    %ecx,%ecx
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L49:
  lea    -0x2(%rdx),%r12d
  mov    %esi,%eax
  cmp    %ecx,%r12d
  jl     L115
L72:
  lea    -0x1(%rax),%esi
  movslq %esi,%rdx
  mov    (%rsp,%rdx,4),%edi
  add    %ecx,%edi
  lea    -0x1(%rdi),%r8d
  mov    %edi,%edx
  movslq %r8d,%rdi
  cmp    %ebp,(%rbx,%rdi,4)
  jg     L49
  jge    L86
  mov    %edx,%ecx
  sub    $0x2,%eax
  cmp    %ecx,%r12d
  jge    L72
L115:
  mov    $0xffffffff,%r8d
L36:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x60,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L86:
  cmp    %r12d,%r8d
  jle    L36
  jmp    L115
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  jmp    L95
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fibonacci_search(int *a, int key, int n) {
  int low = 0, high = n - 1;
  int mid = 0;
  int k = 0, i;
  int F[20];
  fibonacci(F);
  while (n > F[k] - 1)
    ++k;
  for (i = n; i < F[k] - 1; ++i)
    a[i] = a[high];
  while (low <= high) {
    mid = low + F[k - 1] - 1;
    if (a[mid] > key) {
      high = mid - 1;
      k = k - 1;
    } else if (a[mid] < key) {
      low = mid + 1;
      k = k - 2;
    } else {
      if (mid <= high)
        return mid;
      else
        return -1;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L31
L48:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D11(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  D88(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  D88(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L16
L5:
  movss  -0x4(%rbp),%xmm0
  movss  D73(%rip),%xmm1
  xorps  %xmm1,%xmm0
  mulss  -0x4(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  imul   -0x10(%rbp),%eax
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
  movss  -0xc(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L16:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  comisd D15(%rip),%xmm0
  ja     L5
  pxor   %xmm1,%xmm1
  cvtss2sd -0x8(%rbp),%xmm1
  movsd  D20(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L5
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rdx
  mov    -0x14(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1e,-0x14(%rbp)
L31:
  cmpl   $0x168,-0x14(%rbp)
  jle    L48
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D52
type: string
name: retrieve_data
arguments: data_tag: D12
type: f64
name: retrieve_data
arguments: data_tag: D11
type: f32[2]
name: retrieve_data
arguments: data_tag: D88
type: byte[4]
name: retrieve_data
arguments: data_tag: D73
type: byte[4]
name: retrieve_data
arguments: data_tag: D15
type: f64[2]
name: retrieve_data
arguments: data_tag: D20
type: byte[8]
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D52: The Cosine series will be :

tool: D12: 3.1415

tool: {"D11": [0.0,3.6015625]}

tool: {"D88": [0x00,0x00,0x80,0x3f]}

tool: {"D73": [0x00,0x00,0x00,0x80]}

tool: {"D15": [1e-6,-1e-6]}

tool: {"D20": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0xbe]}

tool: D9: 		Cos(%d)=%f

assistant: ```c
int main(void) {
  int loop, n;
  float value, sum = 0, term;
  printf("The Cosine series will be :\n");
  for (loop = 0; loop <= 360; loop = loop + 30) {
    value = loop * 3.1415 / 180;
    term = 1;
    sum = 1;
    n = 1;
    while ((term > 0.000001) || (term < -0.000001)) {
      term = (-1) * value * value * term / ((2 * n) * (2 * n - 1));
      n++;
      sum += term;
    }
    printf("\t\tCos(%d)=%f", loop, sum);
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D44(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
L2:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D35(%rip),%xmm0
  divsd  D55(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movaps %xmm0,%xmm3
  xorps  D10(%rip),%xmm3
  mulss  %xmm0,%xmm3
  movss  D18(%rip),%xmm1
  movaps %xmm1,%xmm0
  mov    $0x1,%edx
  movsd  D78(%rip),%xmm4
L22:
  mulss  %xmm3,%xmm1
  lea    -0x1(%rdx,%rdx,1),%eax
  imul   %edx,%eax
  add    %eax,%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  divss  %xmm2,%xmm1
  add    $0x1,%edx
  addss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  comisd %xmm4,%xmm2
  ja     L22
  movsd  D23(%rip),%xmm5
  comisd %xmm2,%xmm5
  ja     L22
  cvtss2sd %xmm0,%xmm0
  mov    %ebx,%esi
  lea    D25(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1e,%ebx
  cmp    $0x186,%ebx
  jne    L2
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D44
type_infered: string
name: unpack_data
arguments: data_label: D35
type_infered: f64
name: unpack_data
arguments: data_label: D55
type_infered: f32[2]
name: unpack_data
arguments: data_label: D10
type_infered: byte[16]
name: unpack_data
arguments: data_label: D18
type_infered: byte[4]
name: unpack_data
arguments: data_label: D78
type_infered: f64
name: unpack_data
arguments: data_label: D23
type_infered: byte[8]
name: unpack_data
arguments: data_label: D25
type_infered: string

tool: D44: The Cosine series will be :

tool: D35: 3.1415

tool: {"D55": [0.0,3.6015625]}

tool: {"D10": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D18": [0x00,0x00,0x80,0x3f]}

tool: D78: 1e-06

tool: {"D23": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0xbe]}

tool: D25: 		Cos(%d)=%f

assistant: ```c
int main(void) {
  int loop, n;
  float value, sum = 0, term;
  printf("The Cosine series will be :\n");
  for (loop = 0; loop <= 360; loop = loop + 30) {
    value = loop * 3.1415 / 180;
    term = 1;
    sum = 1;
    n = 1;
    while ((term > 0.000001) || (term < -0.000001)) {
      term = (-1) * value * value * term / ((2 * n) * (2 * n - 1));
      n++;
      sum += term;
    }
    printf("\t\tCos(%d)=%f", loop, sum);
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D68(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  lea    D47(%rip),%rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  movsd  D72(%rip),%xmm4
  movsd  D11(%rip),%xmm5
  nop
L16:
  pxor   %xmm0,%xmm0
  movss  D29(%rip),%xmm1
  mov    $0x1,%edx
  cvtsi2sd %ebp,%xmm0
  mulsd  D96(%rip),%xmm0
  divsd  D54(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movaps %xmm0,%xmm3
  xorps  D50(%rip),%xmm3
  mulss  %xmm0,%xmm3
  movaps %xmm1,%xmm0
  nopw   0x0(%rax,%rax,1)
L5:
  lea    -0x1(%rdx,%rdx,1),%eax
  mulss  %xmm3,%xmm1
  pxor   %xmm2,%xmm2
  imul   %edx,%eax
  add    $0x1,%edx
  add    %eax,%eax
  cvtsi2ss %eax,%xmm2
  divss  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  comisd %xmm4,%xmm2
  addss  %xmm1,%xmm0
  ja     L5
  comisd %xmm2,%xmm5
  ja     L5
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    $0xa,%edi
  add    $0x1e,%ebp
  call   <putchar@plt>
  mov    D72(%rip),%rax
  cmp    $0x186,%ebp
  movq   %rax,%xmm4
  mov    D11(%rip),%rax
  movq   %rax,%xmm5
  jne    L16
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D68
data_type: string
name: disassemble_data
arguments: label: D47
data_type: string
name: disassemble_data
arguments: label: D72
data_type: f64
name: disassemble_data
arguments: label: D11
data_type: byte[8]
name: disassemble_data
arguments: label: D29
data_type: byte[4]
name: disassemble_data
arguments: label: D96
data_type: f64
name: disassemble_data
arguments: label: D54
data_type: f32[2]
name: disassemble_data
arguments: label: D50
data_type: byte[16]

tool: D68: The Cosine series will be :

tool: D47: 		Cos(%d)=%f

tool: D72: 1e-06

tool: {"D11": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0xbe]}

tool: {"D29": [0x00,0x00,0x80,0x3f]}

tool: D96: 3.1415

tool: {"D54": [0.0,3.6015625]}

tool: {"D50": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int loop, n;
  float value, sum = 0, term;
  printf("The Cosine series will be :\n");
  for (loop = 0; loop <= 360; loop = loop + 30) {
    value = loop * 3.1415 / 180;
    term = 1;
    sum = 1;
    n = 1;
    while ((term > 0.000001) || (term < -0.000001)) {
      term = (-1) * value * value * term / ((2 * n) * (2 * n - 1));
      n++;
      sum += term;
    }
    printf("\t\tCos(%d)=%f", loop, sum);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D94(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  lea    D68(%rip),%rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  movsd  D84(%rip),%xmm4
  movsd  D13(%rip),%xmm5
  nop
L23:
  pxor   %xmm0,%xmm0
  movss  D29(%rip),%xmm1
  mov    $0x1,%edx
  cvtsi2sd %ebp,%xmm0
  mulsd  D39(%rip),%xmm0
  divsd  D1(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movaps %xmm0,%xmm3
  xorps  D19(%rip),%xmm3
  mulss  %xmm0,%xmm3
  movaps %xmm1,%xmm0
  nopw   0x0(%rax,%rax,1)
L24:
  lea    -0x1(%rdx,%rdx,1),%eax
  mulss  %xmm3,%xmm1
  pxor   %xmm2,%xmm2
  imul   %edx,%eax
  add    $0x1,%edx
  add    %eax,%eax
  cvtsi2ss %eax,%xmm2
  divss  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  comisd %xmm4,%xmm2
  addss  %xmm1,%xmm0
  ja     L24
  comisd %xmm2,%xmm5
  ja     L24
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    $0xa,%edi
  add    $0x1e,%ebp
  call   <putchar@plt>
  mov    D84(%rip),%rax
  cmp    $0x186,%ebp
  movq   %rax,%xmm4
  mov    D13(%rip),%rax
  movq   %rax,%xmm5
  jne    L23
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D94
type_infered: string
name: extract_symbolic_data
arguments: label: D68
type_infered: string
name: extract_symbolic_data
arguments: label: D84
type_infered: f64
name: extract_symbolic_data
arguments: label: D13
type_infered: byte[8]
name: extract_symbolic_data
arguments: label: D29
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D39
type_infered: f64
name: extract_symbolic_data
arguments: label: D1
type_infered: f32[2]
name: extract_symbolic_data
arguments: label: D19
type_infered: byte[16]

tool: D94: The Cosine series will be :

tool: D68: 		Cos(%d)=%f

tool: D84: 1e-06

tool: {"D13": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0xbe]}

tool: {"D29": [0x00,0x00,0x80,0x3f]}

tool: D39: 3.1415

tool: {"D1": [0.0,3.6015625]}

tool: {"D19": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int loop, n;
  float value, sum = 0, term;
  printf("The Cosine series will be :\n");
  for (loop = 0; loop <= 360; loop = loop + 30) {
    value = loop * 3.1415 / 180;
    term = 1;
    sum = 1;
    n = 1;
    while ((term > 0.000001) || (term < -0.000001)) {
      term = (-1) * value * value * term / ((2 * n) * (2 * n - 1));
      n++;
      sum += term;
    }
    printf("\t\tCos(%d)=%f", loop, sum);
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<json_fmt_revokecert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <doasprintf@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <warn@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D8
type_infered: string

tool: D1: resource: revoke-cert
certificate: %s

tool: D8: asprintf

assistant: ```c
char *json_fmt_revokecert(const char *cert) {
  char *p;
  p = doasprintf("{"
                 "\"resource\": \"revoke-cert\", "
                 "\"certificate\": \"%s\""
                 "}",
                 cert);
  if (NULL == p)
    warn("asprintf");
  return (p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<json_fmt_revokecert>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  lea    D18(%rip),%rdi
  call   <doasprintf@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
L17:
  mov    %rbx,%rax
  pop    %rbx
  ret
L4:
  lea    D14(%rip),%rdi
  call   <warn@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: label: D18
type_infered: string
name: read_data
arguments: label: D14
type_infered: string

tool: D18: resource: revoke-cert
certificate: %s

tool: D14: asprintf

assistant: ```c
char *json_fmt_revokecert(const char *cert) {
  char *p;
  p = doasprintf("{"
                 "\"resource\": \"revoke-cert\", "
                 "\"certificate\": \"%s\""
                 "}",
                 cert);
  if (NULL == p)
    warn("asprintf");
  return (p);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<json_fmt_revokecert>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D18(%rip),%rdi
  call   <doasprintf@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  lea    D10(%rip),%rdi
  call   <warn@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string

tool: D18: resource: revoke-cert
certificate: %s

tool: D10: asprintf

assistant: ```c
char *json_fmt_revokecert(const char *cert) {
  char *p;
  p = doasprintf("{"
                 "\"resource\": \"revoke-cert\", "
                 "\"certificate\": \"%s\""
                 "}",
                 cert);
  if (NULL == p)
    warn("asprintf");
  return (p);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<json_fmt_revokecert>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <doasprintf@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D14(%rip),%rdi
  call   <warn@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: string

tool: D4: resource: revoke-cert
certificate: %s

tool: D14: asprintf

assistant: ```c
char *json_fmt_revokecert(const char *cert) {
  char *p;
  p = doasprintf("{"
                 "\"resource\": \"revoke-cert\", "
                 "\"certificate\": \"%s\""
                 "}",
                 cert);
  if (NULL == p)
    warn("asprintf");
  return (p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<count_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L102:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0xc,%eax
  je     L51
  cmp    $0xc,%eax
  jg     L85
  cmp    $0xa,%eax
  je     L51
  cmp    $0xa,%eax
  jg     L85
  cmp    $0x8,%eax
  je     L12
  cmp    $0x9,%eax
  je     L19
  jmp    L85
L51:
  movl   $0x1,-0xc(%rbp)
  jmp    L74
L19:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  and    $0xfff8,%eax
  add    $0x9,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L74
L12:
  subl   $0x1,-0xc(%rbp)
  jmp    L74
L85:
  addl   $0x1,-0xc(%rbp)
  nop
L74:
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L102
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_spaces(int current, char *buffer) {
  char *buf;
  int cur;
  cur = current;
  for (buf = buffer; *buf != '\0'; ++buf) {
    switch (*buf) {
    case '\n':
    case 014:
      cur = 1;
      break;
    case '\t':
      cur = ((cur - 1) & 0177770) + 8 + 1;
      break;
    case 010:
      --cur;
      break;
    default:
      ++cur;
      break;
    }
  }
  return (cur);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_spaces>:
  endbr64
  mov    %edi,%eax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L42
L71:
  ret
L54:
  sub    $0xa,%edx
  test   $0xfd,%dl
  je     L25
L87:
  add    $0x1,%eax
  jmp    L62
L82:
  sub    $0x1,%eax
  and    $0xfff8,%eax
  add    $0x9,%eax
  jmp    L62
L25:
  mov    $0x1,%eax
L62:
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L71
L42:
  cmp    $0x9,%dl
  je     L82
  jg     L54
  cmp    $0x8,%dl
  jne    L87
  sub    $0x1,%eax
  jmp    L62
```

assistant: ```c
int count_spaces(int current, char *buffer) {
  char *buf;
  int cur;
  cur = current;
  for (buf = buffer; *buf != '\0'; ++buf) {
    switch (*buf) {
    case '\n':
    case 014:
      cur = 1;
      break;
    case '\t':
      cur = ((cur - 1) & 0177770) + 8 + 1;
      break;
    case 010:
      --cur;
      break;
    default:
      ++cur;
      break;
    }
  }
  return (cur);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_spaces>:
  endbr64
  movzbl (%rsi),%edx
  mov    %edi,%eax
  test   %dl,%dl
  jne    L1
  jmp    L52
  nop
L34:
  cmp    $0x8,%dl
  jne    L89
  sub    $0x1,%eax
L35:
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  test   %dl,%dl
  je     L52
L1:
  cmp    $0x9,%dl
  je     L75
  jle    L34
  sub    $0xa,%edx
  and    $0xfd,%edx
  je     L93
L89:
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%eax
  test   %dl,%dl
  jne    L1
L52:
  ret
  cs nopw 0x0(%rax,%rax,1)
L93:
  mov    $0x1,%eax
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L75:
  sub    $0x1,%eax
  and    $0xfff8,%eax
  add    $0x9,%eax
  jmp    L35
```

assistant: ```c
int count_spaces(int current, char *buffer) {
  char *buf;
  int cur;
  cur = current;
  for (buf = buffer; *buf != '\0'; ++buf) {
    switch (*buf) {
    case '\n':
    case 014:
      cur = 1;
      break;
    case '\t':
      cur = ((cur - 1) & 0177770) + 8 + 1;
      break;
    case 010:
      --cur;
      break;
    default:
      ++cur;
      break;
    }
  }
  return (cur);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_spaces>:
  endbr64
  movzbl (%rsi),%edx
  mov    %edi,%eax
  test   %dl,%dl
  jne    L47
  jmp    L20
  nop
L94:
  cmp    $0x8,%dl
  jne    L83
  sub    $0x1,%eax
L96:
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  test   %dl,%dl
  je     L20
L47:
  cmp    $0x9,%dl
  je     L71
  jle    L94
  sub    $0xa,%edx
  and    $0xfd,%edx
  je     L59
L83:
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%eax
  test   %dl,%dl
  jne    L47
L20:
  ret
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    $0x1,%eax
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L71:
  sub    $0x1,%eax
  and    $0xfff8,%eax
  add    $0x9,%eax
  jmp    L96
```

assistant: ```c
int count_spaces(int current, char *buffer) {
  char *buf;
  int cur;
  cur = current;
  for (buf = buffer; *buf != '\0'; ++buf) {
    switch (*buf) {
    case '\n':
    case 014:
      cur = 1;
      break;
    case '\t':
      cur = ((cur - 1) & 0177770) + 8 + 1;
      break;
    case 010:
      --cur;
      break;
    default:
      ++cur;
      break;
    }
  }
  return (cur);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L35:
  movl   $0x1,-0xc(%rbp)
  jmp    L25
L12:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L25:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L12
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L23:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type_guessed: string
name: read_data
arguments: tag: D9
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string

tool: D18: %d

tool: D9: %d 

tool: D19: %d


assistant: ```c
int main() {
  int size, counter;
  scanf("%d", &size);
  counter = 1;
  for (int row = 0; row < size; row++, counter++) {
    for (int column = 1; column < size; column++, counter++) {
      printf("%d ", counter);
    }
    printf("%d\n", counter);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%r13d
  mov    $0x1,%eax
  lea    D26(%rip),%r12
  mov    $0x1,%r15d
  lea    D0(%rip),%r14
  cmpl   $0x0,0x4(%rsp)
  jg     L44
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %eax,0x4(%rsp)
  jg     L29
L33:
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  lea    0x1(%rbx),%eax
  cmp    %r13d,0x4(%rsp)
  jle    L9
L44:
  mov    %eax,%ebx
  mov    %r15d,%ebp
  sub    %eax,%ebp
  cmpl   $0x1,0x4(%rsp)
  jg     L29
  jmp    L33
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D24
data_type: string
name: disassemble_data
arguments: tag: D26
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string

tool: D24: %d

tool: D26: %d 

tool: D0: %d


assistant: ```c
int main() {
  int size, counter;
  scanf("%d", &size);
  counter = 1;
  for (int row = 0; row < size; row++, counter++) {
    for (int column = 1; column < size; column++, counter++) {
      printf("%d ", counter);
    }
    printf("%d\n", counter);
  }
  return 0;
}
```