ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L27
L28:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L14
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L33
L14:
  movsd  -0x8(%rbp),%xmm0
L33:
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L28
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: byte[8]

tool: {"D8": [0xea,0x8c,0xa0,0x39,0x59,0x3e,0x29,0xc6]}

assistant: ```c
double max_double(double *buff, int size) {
  double ret = -1e30;
  int i;
  for (i = 0; i < size; i++)
    ret = (ret < buff[i] ? buff[i] : ret);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max_double>:
  endbr64
  test   %esi,%esi
  jle    L11
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  movsd  D9(%rip),%xmm0
L9:
  movsd  (%rax),%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L9
  ret
L11:
  movsd  D9(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: byte[8]

tool: {"D9": [0xea,0x8c,0xa0,0x39,0x59,0x3e,0x29,0xc6]}

assistant: ```c
double max_double(double *buff, int size) {
  double ret = -1e30;
  int i;
  for (i = 0; i < size; i++)
    ret = (ret < buff[i] ? buff[i] : ret);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max_double>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  movsd  D15(%rip),%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax,%rax,1)
L17:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L17
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  movsd  D15(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: byte[8]

tool: {"D15": [0xea,0x8c,0xa0,0x39,0x59,0x3e,0x29,0xc6]}

assistant: ```c
double max_double(double *buff, int size) {
  double ret = -1e30;
  int i;
  for (i = 0; i < size; i++)
    ret = (ret < buff[i] ? buff[i] : ret);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<max_double>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  movsd  D12(%rip),%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax,%rax,1)
L18:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L18
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  movsd  D12(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
datatype: byte[8]

tool: {"D12": [0xea,0x8c,0xa0,0x39,0x59,0x3e,0x29,0xc6]}

assistant: ```c
double max_double(double *buff, int size) {
  double ret = -1e30;
  int i;
  for (i = 0; i < size; i++)
    ret = (ret < buff[i] ? buff[i] : ret);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x3e8,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L18
L14:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L36
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x78787879,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x4,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L15
L36:
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L15:
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L14
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: f(x)|sum(1,100),conditon(i%%3==0||i%%17==0)=%d


assistant: ```c
int main() {
  int i, startNum, endNum;
  int sum;
  sum = 0;
  startNum = 1;
  endNum = 1000;
  for (i = startNum; i <= endNum; i++) {
    if (i % 3 == 0 || i % 17 == 0) {
      sum = sum + i;
    }
  }
  printf("f(x)|sum(1,100),conditon(i%%3==0||i%%17==0)=%d\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x1,%edx
  jmp    L16
L31:
  add    %edx,%esi
L24:
  add    $0x1,%edx
  cmp    $0x3e9,%edx
  je     L48
L16:
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edx
  je     L31
  movslq %edx,%rax
  imul   $0x78787879,%rax,%rax
  sar    $0x23,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x4,%ecx
  add    %ecx,%eax
  cmp    %eax,%edx
  jne    L24
  jmp    L31
L48:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: f(x)|sum(1,100),conditon(i%%3==0||i%%17==0)=%d


assistant: ```c
int main() {
  int i, startNum, endNum;
  int sum;
  sum = 0;
  startNum = 1;
  endNum = 1000;
  for (i = startNum; i <= endNum; i++) {
    if (i % 3 == 0 || i % 17 == 0) {
      sum = sum + i;
    }
  }
  printf("f(x)|sum(1,100),conditon(i%%3==0||i%%17==0)=%d\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x1,%eax
  nop
L16:
  imul   $0xaaaaaaab,%eax,%edx
  cmp    $0x55555555,%edx
  jbe    L12
  imul   $0xf0f0f0f1,%eax,%edx
  cmp    $0xf0f0f0f,%edx
  ja     L7
L12:
  add    %eax,%esi
L7:
  add    $0x1,%eax
  cmp    $0x3e9,%eax
  jne    L16
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: f(x)|sum(1,100),conditon(i%%3==0||i%%17==0)=%d


assistant: ```c
int main() {
  int i, startNum, endNum;
  int sum;
  sum = 0;
  startNum = 1;
  endNum = 1000;
  for (i = startNum; i <= endNum; i++) {
    if (i % 3 == 0 || i % 17 == 0) {
      sum = sum + i;
    }
  }
  printf("f(x)|sum(1,100),conditon(i%%3==0||i%%17==0)=%d\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm12,%xmm12
  movdqa D2(%rip),%xmm7
  xor    %eax,%eax
  movdqa %xmm12,%xmm14
  movdqa %xmm12,%xmm13
  movdqa D5(%rip),%xmm8
  movdqa D11(%rip),%xmm11
  pcmpgtd %xmm7,%xmm13
  movdqa %xmm12,%xmm9
  pcmpgtd %xmm8,%xmm14
  nopw   0x0(%rax,%rax,1)
L7:
  movdqa %xmm11,%xmm3
  movdqa %xmm9,%xmm5
  movdqa %xmm14,%xmm2
  add    $0x1,%eax
  movdqa %xmm3,%xmm0
  movdqa %xmm9,%xmm4
  movdqa %xmm14,%xmm15
  paddd  D16(%rip),%xmm11
  punpckldq %xmm3,%xmm0
  pcmpgtd %xmm0,%xmm5
  pmuludq %xmm0,%xmm2
  movdqa %xmm0,%xmm6
  pmuludq %xmm8,%xmm6
  movdqa %xmm5,%xmm1
  pmuludq %xmm7,%xmm5
  pmuludq %xmm8,%xmm1
  paddq  %xmm2,%xmm1
  movdqa %xmm3,%xmm2
  punpckhdq %xmm3,%xmm2
  psllq  $0x20,%xmm1
  pcmpgtd %xmm2,%xmm4
  paddq  %xmm1,%xmm6
  movdqa %xmm2,%xmm10
  pmuludq %xmm2,%xmm15
  pmuludq %xmm8,%xmm10
  movdqa %xmm4,%xmm1
  pmuludq %xmm7,%xmm4
  pmuludq %xmm8,%xmm1
  paddq  %xmm15,%xmm1
  psllq  $0x20,%xmm1
  paddq  %xmm10,%xmm1
  shufps $0xdd,%xmm1,%xmm6
  psrad  $0x3,%xmm6
  movdqa %xmm6,%xmm1
  pslld  $0x4,%xmm1
  paddd  %xmm6,%xmm1
  movdqa %xmm13,%xmm6
  pmuludq %xmm0,%xmm6
  pmuludq %xmm7,%xmm0
  pcmpeqd %xmm3,%xmm1
  pcmpeqd %xmm9,%xmm1
  paddq  %xmm6,%xmm5
  psllq  $0x20,%xmm5
  paddq  %xmm5,%xmm0
  movdqa %xmm13,%xmm5
  pmuludq %xmm2,%xmm5
  pmuludq %xmm7,%xmm2
  paddq  %xmm5,%xmm4
  psllq  $0x20,%xmm4
  paddq  %xmm4,%xmm2
  shufps $0xdd,%xmm2,%xmm0
  movdqa %xmm0,%xmm2
  pslld  $0x1,%xmm2
  paddd  %xmm2,%xmm0
  pcmpeqd %xmm3,%xmm0
  pcmpeqd %xmm9,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm3,%xmm1
  paddd  %xmm1,%xmm12
  cmp    $0xfa,%eax
  jne    L7
  movdqa %xmm12,%xmm0
  lea    D13(%rip),%rdi
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm12
  movdqa %xmm12,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm12
  movd   %xmm12,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: byte[16]
name: disassemble_data
arguments: tag: D5
datatype: byte[16]
name: disassemble_data
arguments: tag: D11
datatype: byte[16]
name: disassemble_data
arguments: tag: D16
datatype: byte[16]
name: disassemble_data
arguments: tag: D13
datatype: string

tool: {"D2": [0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55]}

tool: {"D5": [0x79,0x78,0x78,0x78,0x79,0x78,0x78,0x78,0x79,0x78,0x78,0x78,0x79,0x78,0x78,0x78]}

tool: {"D11": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D16": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D13: f(x)|sum(1,100),conditon(i%%3==0||i%%17==0)=%d


assistant: ```c
int main() {
  int i, startNum, endNum;
  int sum;
  sum = 0;
  startNum = 1;
  endNum = 1000;
  for (i = startNum; i <= endNum; i++) {
    if (i % 3 == 0 || i % 17 == 0) {
      sum = sum + i;
    }
  }
  printf("f(x)|sum(1,100),conditon(i%%3==0||i%%17==0)=%d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  mov    $0x5f5e100,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x5f5e100,%ebx
L22:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  movslq %eax,%rdx
  addl   $0x1,(%rsp,%rdx,4)
  sub    $0x1,%ebx
  jne    L22
  mov    $0x0,%ebx
  lea    D36(%rip),%rbp
L24:
  mov    (%rsp,%rbx,4),%edx
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mulss  D23(%rip),%xmm0
  divss  D26(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L24
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D36
data_type: string
name: extract_symbolic_data
arguments: label: D23
data_type: byte[4]
name: extract_symbolic_data
arguments: label: D26
data_type: byte[4]

tool: D9: Voy a buscar %d numeros aleatorios entre 0 y 9, y contar su ocurrencia



tool: D36: El numero %d ocurrio %d veces, representando %f %% del total


tool: {"D23": [0x00,0x00,0xc8,0x42]}

tool: {"D26": [0x20,0xbc,0xbe,0x4c]}

assistant: ```c
int main() {
  unsigned int ocurrencias[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  float porcentajes[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int azar;
  unsigned int vuelta;
  printf("Voy a buscar %d numeros aleatorios entre 0 y 9, y contar su ocurrencia\n\n", 100000000);
  for (vuelta = 0; vuelta < 100000000; vuelta++) {
    azar = rand() % 10;
    ocurrencias[azar]++;
  }
  for (vuelta = 0; vuelta < 10; vuelta++) {
    porcentajes[vuelta] = (float)ocurrencias[vuelta] * 100 / 100000000;
    printf("El numero %d ocurrio %d veces, representando %f %% del total\n", vuelta, ocurrencias[vuelta], porcentajes[vuelta]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x5f5e100,%esi
  lea    D19(%rip),%rdi
  push   %rbp
  push   %rbx
  mov    $0x5f5e100,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  movslq %eax,%rdx
  addl   $0x1,(%rsp,%rdx,4)
  sub    $0x1,%ebx
  jne    L16
  xor    %ebx,%ebx
  mov    %rsp,%r12
  lea    D37(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%r12,%rbx,4),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  cvtsi2ss %rax,%xmm0
  mulss  D0(%rip),%xmm0
  mov    %rax,%rdx
  mov    $0x1,%eax
  divss  D7(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L19
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
data_type: string
name: parse_data
arguments: tag: D37
data_type: string
name: parse_data
arguments: tag: D0
data_type: byte[4]
name: parse_data
arguments: tag: D7
data_type: byte[4]

tool: D19: Voy a buscar %d numeros aleatorios entre 0 y 9, y contar su ocurrencia



tool: D37: El numero %d ocurrio %d veces, representando %f %% del total


tool: {"D0": [0x00,0x00,0xc8,0x42]}

tool: {"D7": [0x20,0xbc,0xbe,0x4c]}

assistant: ```c
int main() {
  unsigned int ocurrencias[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  float porcentajes[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int azar;
  unsigned int vuelta;
  printf("Voy a buscar %d numeros aleatorios entre 0 y 9, y contar su ocurrencia\n\n", 100000000);
  for (vuelta = 0; vuelta < 100000000; vuelta++) {
    azar = rand() % 10;
    ocurrencias[azar]++;
  }
  for (vuelta = 0; vuelta < 10; vuelta++) {
    porcentajes[vuelta] = (float)ocurrencias[vuelta] * 100 / 100000000;
    printf("El numero %d ocurrio %d veces, representando %f %% del total\n", vuelta, ocurrencias[vuelta], porcentajes[vuelta]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x5f5e100,%esi
  lea    D34(%rip),%rdi
  push   %rbp
  push   %rbx
  mov    $0x5f5e100,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  movslq %eax,%rdx
  addl   $0x1,(%rsp,%rdx,4)
  sub    $0x1,%ebx
  jne    L7
  xor    %ebx,%ebx
  mov    %rsp,%r12
  lea    D38(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%r12,%rbx,4),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  cvtsi2ss %rax,%xmm0
  mulss  D24(%rip),%xmm0
  mov    %rax,%rdx
  mov    $0x1,%eax
  divss  D23(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L17
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D34
type_guessed: string
name: disassemble_data
arguments: data_tag: D38
type_guessed: string
name: disassemble_data
arguments: data_tag: D24
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D23
type_guessed: byte[4]

tool: D34: Voy a buscar %d numeros aleatorios entre 0 y 9, y contar su ocurrencia



tool: D38: El numero %d ocurrio %d veces, representando %f %% del total


tool: {"D24": [0x00,0x00,0xc8,0x42]}

tool: {"D23": [0x20,0xbc,0xbe,0x4c]}

assistant: ```c
int main() {
  unsigned int ocurrencias[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  float porcentajes[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int azar;
  unsigned int vuelta;
  printf("Voy a buscar %d numeros aleatorios entre 0 y 9, y contar su ocurrencia\n\n", 100000000);
  for (vuelta = 0; vuelta < 100000000; vuelta++) {
    azar = rand() % 10;
    ocurrencias[azar]++;
  }
  for (vuelta = 0; vuelta < 10; vuelta++) {
    porcentajes[vuelta] = (float)ocurrencias[vuelta] * 100 / 100000000;
    printf("El numero %d ocurrio %d veces, representando %f %% del total\n", vuelta, ocurrencias[vuelta], porcentajes[vuelta]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<HexNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0xf,-0x14(%rbp)
  ja     L90
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D7(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movb   $0x30,-0x1(%rbp)
  jmp    L41
  movb   $0x31,-0x1(%rbp)
  jmp    L41
  movb   $0x32,-0x1(%rbp)
  jmp    L41
  movb   $0x33,-0x1(%rbp)
  jmp    L41
  movb   $0x34,-0x1(%rbp)
  jmp    L41
  movb   $0x35,-0x1(%rbp)
  jmp    L41
  movb   $0x36,-0x1(%rbp)
  jmp    L41
  movb   $0x37,-0x1(%rbp)
  jmp    L41
  movb   $0x38,-0x1(%rbp)
  jmp    L41
  movb   $0x39,-0x1(%rbp)
  jmp    L41
  movb   $0x41,-0x1(%rbp)
  jmp    L41
  movb   $0x42,-0x1(%rbp)
  jmp    L41
  movb   $0x43,-0x1(%rbp)
  jmp    L41
  movb   $0x44,-0x1(%rbp)
  jmp    L41
  movb   $0x45,-0x1(%rbp)
  jmp    L41
  movb   $0x46,-0x1(%rbp)
  jmp    L41
L90:
  movb   $0x30,-0x1(%rbp)
L41:
  movsbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int HexNumber(int c) {
  char s;
  switch (c) {
  case 0:
    s = '0';
    break;
  case 1:
    s = '1';
    break;
  case 2:
    s = '2';
    break;
  case 3:
    s = '3';
    break;
  case 4:
    s = '4';
    break;
  case 5:
    s = '5';
    break;
  case 6:
    s = '6';
    break;
  case 7:
    s = '7';
    break;
  case 8:
    s = '8';
    break;
  case 9:
    s = '9';
    break;
  case 10:
    s = 'A';
    break;
  case 11:
    s = 'B';
    break;
  case 12:
    s = 'C';
    break;
  case 13:
    s = 'D';
    break;
  case 14:
    s = 'E';
    break;
  case 15:
    s = 'F';
    break;
  default:
    s = '0';
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HexNumber>:
  endbr64
  cmp    $0xf,%edi
  ja     L104
  mov    %edi,%edi
  lea    D3(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x31,%eax
L77:
  movsbl %al,%eax
  ret
  mov    $0x32,%eax
  jmp    L77
  mov    $0x33,%eax
  jmp    L77
  mov    $0x34,%eax
  jmp    L77
  mov    $0x35,%eax
  jmp    L77
  mov    $0x36,%eax
  jmp    L77
  mov    $0x37,%eax
  jmp    L77
  mov    $0x38,%eax
  jmp    L77
  mov    $0x39,%eax
  jmp    L77
  mov    $0x41,%eax
  jmp    L77
  mov    $0x42,%eax
  jmp    L77
  mov    $0x43,%eax
  jmp    L77
  mov    $0x44,%eax
  jmp    L77
  mov    $0x45,%eax
  jmp    L77
  mov    $0x46,%eax
  jmp    L77
L104:
  mov    $0x30,%eax
  jmp    L77
```

assistant: ```c
int HexNumber(int c) {
  char s;
  switch (c) {
  case 0:
    s = '0';
    break;
  case 1:
    s = '1';
    break;
  case 2:
    s = '2';
    break;
  case 3:
    s = '3';
    break;
  case 4:
    s = '4';
    break;
  case 5:
    s = '5';
    break;
  case 6:
    s = '6';
    break;
  case 7:
    s = '7';
    break;
  case 8:
    s = '8';
    break;
  case 9:
    s = '9';
    break;
  case 10:
    s = 'A';
    break;
  case 11:
    s = 'B';
    break;
  case 12:
    s = 'C';
    break;
  case 13:
    s = 'D';
    break;
  case 14:
    s = 'E';
    break;
  case 15:
    s = 'F';
    break;
  default:
    s = '0';
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HexNumber>:
  endbr64
  sub    $0x1,%edi
  mov    $0x30,%eax
  cmp    $0xe,%edi
  ja     L7
  lea    D2(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L7:
  ret
```

assistant: ```c
int HexNumber(int c) {
  char s;
  switch (c) {
  case 0:
    s = '0';
    break;
  case 1:
    s = '1';
    break;
  case 2:
    s = '2';
    break;
  case 3:
    s = '3';
    break;
  case 4:
    s = '4';
    break;
  case 5:
    s = '5';
    break;
  case 6:
    s = '6';
    break;
  case 7:
    s = '7';
    break;
  case 8:
    s = '8';
    break;
  case 9:
    s = '9';
    break;
  case 10:
    s = 'A';
    break;
  case 11:
    s = 'B';
    break;
  case 12:
    s = 'C';
    break;
  case 13:
    s = 'D';
    break;
  case 14:
    s = 'E';
    break;
  case 15:
    s = 'F';
    break;
  default:
    s = '0';
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HexNumber>:
  endbr64
  sub    $0x1,%edi
  mov    $0x30,%eax
  cmp    $0xe,%edi
  ja     L4
  lea    D5(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L4:
  ret
```

assistant: ```c
int HexNumber(int c) {
  char s;
  switch (c) {
  case 0:
    s = '0';
    break;
  case 1:
    s = '1';
    break;
  case 2:
    s = '2';
    break;
  case 3:
    s = '3';
    break;
  case 4:
    s = '4';
    break;
  case 5:
    s = '5';
    break;
  case 6:
    s = '6';
    break;
  case 7:
    s = '7';
    break;
  case 8:
    s = '8';
    break;
  case 9:
    s = '9';
    break;
  case 10:
    s = 'A';
    break;
  case 11:
    s = 'B';
    break;
  case 12:
    s = 'C';
    break;
  case 13:
    s = 'D';
    break;
  case 14:
    s = 'E';
    break;
  case 15:
    s = 'F';
    break;
  default:
    s = '0';
  }
  return s;
}
```