user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<InsertInString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %ecx,%ecx
  js     L84
  mov    %rdx,%r14
  mov    %rsi,%rdi
  mov    %ecx,%r12d
  mov    %rsi,-0x50(%rbp)
  call   <GetStringLength@plt>
  mov    %r14,%rdi
  mov    %eax,-0x44(%rbp)
  call   <GetStringLength@plt>
  mov    -0x44(%rbp),%ecx
  mov    %eax,%r9d
  test   %ecx,%ecx
  setle  %al
  test   %r9d,%r9d
  setle  %dl
  or     %dl,%al
  jne    L84
  cmp    %ecx,%r12d
  mov    -0x50(%rbp),%r8
  jge    L84
  lea    (%rcx,%r9,1),%edi
  lea    D4(%rip),%rsi
  mov    %r8,-0x58(%rbp)
  mov    %r9d,-0x50(%rbp)
  mov    %ecx,-0x44(%rbp)
  call   <GetStackSize@plt>
  mov    %rsp,%rsi
  mov    -0x58(%rbp),%r8
  mov    -0x50(%rbp),%r9d
  cltq
  mov    -0x44(%rbp),%ecx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L33
L71:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L71
L33:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L127
L70:
  mov    %rsp,%r11
  xor    %ebx,%ebx
  mov    $0xffffffff,%r13d
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L97:
  mov    %eax,%r13d
L6:
  cmp    %ebx,%r12d
  je     L50
L12:
  movzbl (%r8,%rbx,1),%esi
  lea    0x1(%r13),%eax
  add    $0x1,%rbx
  movslq %eax,%rdx
  mov    %sil,(%r11,%rdx,1)
  cmp    %ebx,%ecx
  jg     L97
  lea    0x2(%r13),%edx
  mov    %r11,%rsi
  mov    %r15,%rdi
  movslq %edx,%rax
  movb   $0x0,(%r11,%rax,1)
  call   <ReturnOutputMallocStack@plt>
  jmp    L17
  nopl   0x0(%rax)
L84:
  mov    %r15,%rdi
  call   <ReturnNullMallocStack@plt>
L17:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L50:
  movslq %r13d,%rax
  test   %r9d,%r9d
  mov    %r9d,%edx
  mov    %r14,%rsi
  lea    0x1(%r11,%rax,1),%rdi
  mov    $0x1,%eax
  mov    %r8,-0x60(%rbp)
  cmovle %rax,%rdx
  mov    %ecx,-0x58(%rbp)
  mov    %r11,-0x50(%rbp)
  mov    %r9d,-0x44(%rbp)
  call   <memcpy@plt>
  mov    -0x44(%rbp),%r9d
  xor    %edx,%edx
  mov    -0x60(%rbp),%r8
  mov    -0x58(%rbp),%ecx
  mov    -0x50(%rbp),%r11
  lea    -0x1(%r9),%eax
  test   %r9d,%r9d
  cmovle %edx,%eax
  lea    0x1(%r13,%rax,1),%r13d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L127:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L70
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: char

assistant: ```c
char *InsertInString(char *output, char *input, char *addition, const int index) {
  if (index < 0)
    return ReturnNullMallocStack(output);
  int length1 = GetStringLength(input);
  int length2 = GetStringLength(addition);
  if (length1 < 1 || length2 < 1 || index > length1 - 1) {
    return ReturnNullMallocStack(output);
  }
  int length0 = length1 + length2;
  char output2[GetStackSize(length0, "char")];
  int i0 = -1;
  int i = 0;
  for (i = 0; i < length1; i++) {
    if (i == index) {
      int i2 = 0;
      for (i2 = 0; i2 < length2; i2++) {
        i0++;
        output2[i0] = addition[i2];
      }
    }
    i0++;
    output2[i0] = input[i];
  }
  i0++;
  output2[i0] = '\0';
  return ReturnOutputMallocStack(output, output2, i0);
}
```