ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  test   $0x10,%al
  je     L6
  test   $0x8,%al
  je     L30
  lea    (%rax,%rax,1),%rdx
  jmp    L21
L30:
  mov    %eax,%esi
  shl    $0x8,%esi
  sar    $0x18,%esi
  movzbl %sil,%esi
  shl    $0x18,%rsi
  movabs $0xffffffff00ffffff,%rdx
  and    %rax,%rdx
  or     %rsi,%rdx
  sar    $0x18,%eax
  movzbl %al,%eax
  shl    $0x10,%rax
  and    $0xffffffffff00ffff,%rdx
  or     %rax,%rdx
  jmp    L21
L6:
  mov    %rax,%rdi
  shr    $0x20,%rdi
  shl    $0x30,%rdi
  mov    %rax,%rsi
  shr    $0x30,%rsi
  shl    $0x20,%rsi
  mov    %eax,%edx
  or     %rdi,%rdx
  or     %rsi,%rdx
  mov    %rax,%rsi
  shr    $0x10,%rsi
  mov    %si,%dx
  movzwl %ax,%eax
  shl    $0x10,%rax
  movabs $0xffffffff0000ffff,%rsi
  and    %rsi,%rdx
  or     %rax,%rdx
L21:
  movabs $0xeee1729a46ef9ea2,%rax
  imul   %rax,%rdx
  mov    %rdx,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else {
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy11;
      }
    } else {
      copy12 = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy12;
      copy12 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy12;
    }
    output[0UL] = (state[0UL] * 943156777UL) * 495144311008221650UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%rcx
  add    $0x136ff696,%rax
  test   $0x10,%al
  je     L11
  test   $0x8,%al
  je     L9
  add    %rax,%rax
  jmp    L1
  nopl   (%rax)
L11:
  mov    %rax,%rdi
  mov    %rax,%rsi
  mov    %eax,%edx
  shr    $0x20,%rdi
  shr    $0x30,%rsi
  shl    $0x30,%rdi
  shl    $0x20,%rsi
  or     %rdi,%rdx
  or     %rsi,%rdx
  mov    %rax,%rsi
  movzwl %ax,%eax
  shr    $0x10,%rsi
  shl    $0x10,%rax
  mov    %si,%dx
  movabs $0xffffffff0000ffff,%rsi
  and    %rsi,%rdx
  or     %rdx,%rax
L1:
  movabs $0xeee1729a46ef9ea2,%rdx
  imul   %rdx,%rax
  mov    %rax,(%rcx)
  ret
  nopl   0x0(%rax)
L9:
  movabs $0xffffffff00ffffff,%rdx
  mov    %rax,%rsi
  shl    $0x8,%rsi
  and    %rax,%rdx
  sar    $0x18,%eax
  and    $0xff000000,%esi
  movzbl %al,%eax
  or     %rsi,%rdx
  shl    $0x10,%rax
  and    $0xffffffffff00ffff,%rdx
  or     %rdx,%rax
  jmp    L1
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else {
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy11;
      }
    } else {
      copy12 = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy12;
      copy12 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy12;
    }
    output[0UL] = (state[0UL] * 943156777UL) * 495144311008221650UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  movq   %rax,%xmm1
  pshuflw $0xb1,%xmm1,%xmm0
  movq   %xmm0,%rdx
  test   $0x10,%al
  je     L9
  test   $0x8,%al
  je     L14
  lea    (%rax,%rax,1),%rdx
L9:
  movabs $0xeee1729a46ef9ea2,%rax
  imul   %rax,%rdx
  mov    %rdx,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %eax,%ecx
  xor    %edx,%edx
  sar    $0x18,%ecx
  mov    %cl,%dl
  mov    %eax,%ecx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %cl,%dh
  movabs $0xffffffff0000ffff,%rcx
  movzwl %dx,%edx
  and    %rcx,%rax
  shl    $0x10,%rdx
  or     %rax,%rdx
  jmp    L9
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else {
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy11;
      }
    } else {
      copy12 = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy12;
      copy12 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy12;
    }
    output[0UL] = (state[0UL] * 943156777UL) * 495144311008221650UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<newname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x1c(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0xff,-0x1c(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L27
  addq   $0x1,-0x10(%rbp)
  jmp    L8
L27:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L14:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *newname(char *old, int pat) {
  char *new;
  char *base;
  assert(old != NULL);
  assert(strlen(old) > 0);
  assert(pat != 0);
  assert(pat <= 0xff);
  new = strdup(old);
  if (new) {
    if ((base = strrchr(new, '/')))
      base++;
    else
      base = new;
    memset(base, pat, strlen(base));
  }
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<newname>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %ebp,%ebp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0xff,%ebp
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%r12
  test   %rax,%rax
  cmove  %rbx,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <memset@plt>
L1:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *newname(char *old, int pat) {
  char *new;
  char *base;
  assert(old != NULL);
  assert(strlen(old) > 0);
  assert(pat != 0);
  assert(pat <= 0xff);
  new = strdup(old);
  if (new) {
    if ((base = strrchr(new, '/')))
      base++;
    else
      base = new;
    memset(base, pat, strlen(base));
  }
  return new;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<newname>:
  endbr64
  push   %r13
  test   %rdi,%rdi
  push   %r12
  mov    %rdi,%r12
  setne  %dil
  push   %rbp
  movzbl %dil,%edi
  mov    %esi,%ebp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %ebp,%ebp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0xff,%ebp
  setle  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%r13
  test   %rax,%rax
  cmove  %r12,%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %eax,%edx
  call   <memset@plt>
L0:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *newname(char *old, int pat) {
  char *new;
  char *base;
  assert(old != NULL);
  assert(strlen(old) > 0);
  assert(pat != 0);
  assert(pat <= 0xff);
  new = strdup(old);
  if (new) {
    if ((base = strrchr(new, '/')))
      base++;
    else
      base = new;
    memset(base, pat, strlen(base));
  }
  return new;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<newname>:
  endbr64
  push   %r13
  test   %rdi,%rdi
  push   %r12
  mov    %rdi,%r12
  setne  %dil
  push   %rbp
  movzbl %dil,%edi
  mov    %esi,%ebp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %ebp,%ebp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0xff,%ebp
  setle  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%r13
  test   %rax,%rax
  cmove  %r12,%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %eax,%edx
  call   <memset@plt>
L8:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *newname(char *old, int pat) {
  char *new;
  char *base;
  assert(old != NULL);
  assert(strlen(old) > 0);
  assert(pat != 0);
  assert(pat <= 0xff);
  new = strdup(old);
  if (new) {
    if ((base = strrchr(new, '/')))
      base++;
    else
      base = new;
    memset(base, pat, strlen(base));
  }
  return new;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<percentage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  imul   $0x3e8,%rax,%rax
  mov    -0x20(%rbp),%rdx
  mov    (%rdx),%rcx
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  js     L15
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L0
L15:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L0:
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: f64

tool: D4: 10

assistant: ```c
float percentage(unsigned long long *free, unsigned long long *total) {
  unsigned long long result = (*free) * (unsigned long long)1000 / (*total);
  return result / 10.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<percentage>:
  endbr64
  imul   $0x3e8,(%rdi),%rax
  mov    $0x0,%edx
  divq   (%rsi)
  test   %rax,%rax
  js     L5
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L10:
  divsd  D5(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
L5:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: f64

tool: D5: 10

assistant: ```c
float percentage(unsigned long long *free, unsigned long long *total) {
  unsigned long long result = (*free) * (unsigned long long)1000 / (*total);
  return result / 10.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<percentage>:
  endbr64
  imul   $0x3e8,(%rdi),%rax
  xor    %edx,%edx
  divq   (%rsi)
  test   %rax,%rax
  js     L2
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  D12(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  divsd  D12(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
data_type: f64

tool: D12: 10

assistant: ```c
float percentage(unsigned long long *free, unsigned long long *total) {
  unsigned long long result = (*free) * (unsigned long long)1000 / (*total);
  return result / 10.0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<percentage>:
  endbr64
  imul   $0x3e8,(%rdi),%rax
  xor    %edx,%edx
  divq   (%rsi)
  test   %rax,%rax
  js     L8
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  D5(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  divsd  D5(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: f64

tool: D5: 10

assistant: ```c
float percentage(unsigned long long *free, unsigned long long *total) {
  unsigned long long result = (*free) * (unsigned long long)1000 / (*total);
  return result / 10.0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<push_node_stack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ex_realloc@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void push_node_stack(unsigned int node, unsigned int **stack, unsigned int *stack_size) {
  unsigned int new_stack_size = ++(*stack_size);
  *stack = (unsigned int *)ex_realloc(*stack, sizeof(unsigned int) * new_stack_size);
  (*stack)[new_stack_size - 1] = node;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<push_node_stack>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    (%rdx),%ebx
  lea    0x1(%rbx),%esi
  mov    %esi,(%rdx)
  shl    $0x2,%esi
  mov    0x0(%rbp),%rdi
  call   <ex_realloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %ebx,%ebx
  mov    %r12d,(%rax,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void push_node_stack(unsigned int node, unsigned int **stack, unsigned int *stack_size) {
  unsigned int new_stack_size = ++(*stack_size);
  *stack = (unsigned int *)ex_realloc(*stack, sizeof(unsigned int) * new_stack_size);
  (*stack)[new_stack_size - 1] = node;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<push_node_stack>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdx),%ebx
  mov    0x0(%rbp),%rdi
  lea    0x1(%rbx),%esi
  mov    %esi,(%rdx)
  shl    $0x2,%esi
  call   <ex_realloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %r12d,(%rax,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void push_node_stack(unsigned int node, unsigned int **stack, unsigned int *stack_size) {
  unsigned int new_stack_size = ++(*stack_size);
  *stack = (unsigned int *)ex_realloc(*stack, sizeof(unsigned int) * new_stack_size);
  (*stack)[new_stack_size - 1] = node;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<push_node_stack>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdx),%ebx
  mov    0x0(%rbp),%rdi
  lea    0x1(%rbx),%esi
  mov    %esi,(%rdx)
  shl    $0x2,%esi
  call   <ex_realloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %r12d,(%rax,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void push_node_stack(unsigned int node, unsigned int **stack, unsigned int *stack_size) {
  unsigned int new_stack_size = ++(*stack_size);
  *stack = (unsigned int *)ex_realloc(*stack, sizeof(unsigned int) * new_stack_size);
  (*stack)[new_stack_size - 1] = node;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ADI16BitsSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x1c(%rbp)
  movl   $0x10,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    $0xfe,%eax
  add    %edx,%eax
  cltq
  mov    %rax,%rdx
  movzwl -0x1c(%rbp),%eax
  mov    %ax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ADI16BitsSet(uint32_t ui32Base, uint32_t ui32Reg, uint16_t ui16Val) {
  uint32_t ui32RegOffset;
  ;
  ;
  ui32RegOffset = 0x00000010;
  (*((volatile unsigned short *)(ui32Base + ui32RegOffset + (ui32Reg & 0xFE)))) = ui16Val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ADI16BitsSet>:
  endbr64
  and    $0xfe,%esi
  lea    0x10(%rsi,%rdi,1),%eax
  cltq
  mov    %dx,(%rax)
  ret
```

assistant: ```c
void ADI16BitsSet(uint32_t ui32Base, uint32_t ui32Reg, uint16_t ui16Val) {
  uint32_t ui32RegOffset;
  ;
  ;
  ui32RegOffset = 0x00000010;
  (*((volatile unsigned short *)(ui32Base + ui32RegOffset + (ui32Reg & 0xFE)))) = ui16Val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ADI16BitsSet>:
  endbr64
  and    $0xfe,%esi
  lea    0x10(%rsi,%rdi,1),%eax
  cltq
  mov    %dx,(%rax)
  ret
```

assistant: ```c
void ADI16BitsSet(uint32_t ui32Base, uint32_t ui32Reg, uint16_t ui16Val) {
  uint32_t ui32RegOffset;
  ;
  ;
  ui32RegOffset = 0x00000010;
  (*((volatile unsigned short *)(ui32Base + ui32RegOffset + (ui32Reg & 0xFE)))) = ui16Val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ADI16BitsSet>:
  endbr64
  and    $0xfe,%esi
  lea    0x10(%rsi,%rdi,1),%eax
  cltq
  mov    %dx,(%rax)
  ret
```

assistant: ```c
void ADI16BitsSet(uint32_t ui32Base, uint32_t ui32Reg, uint16_t ui16Val) {
  uint32_t ui32RegOffset;
  ;
  ;
  ui32RegOffset = 0x00000010;
  (*((volatile unsigned short *)(ui32Base + ui32RegOffset + (ui32Reg & 0xFE)))) = ui16Val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L39
L20:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
L21:
  addl   $0x1,-0x14(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L20
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x10(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D24
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D24: Input array length:

tool: D4: %d


tool: D7: %-5d

assistant: ```c
void main() {
  int N;
  int *a;
  int i;
  printf("Input array length:");
  scanf("%d\n", &N);
  a = (int *)calloc(N, sizeof(int));
  for (i = 0; i < N; i++) {
    a[i] = i + 1;
    printf("%-5d", a[i]);
    if ((i + 1) % 10 == 0)
      printf("\n");
  }
  free(a);
  a = NULL;
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    $0x4,%esi
  mov    0x4(%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%r13
  cmpl   $0x0,0x4(%rsp)
  jle    L17
  movl   $0x1,(%rax)
  mov    $0x1,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%r13),%rbp
  mov    $0x1,%ebx
  lea    D29(%rip),%r12
  jmp    L51
L6:
  add    $0x4,%rbp
L51:
  cmp    %ebx,0x4(%rsp)
  jle    L17
  add    $0x1,%ebx
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %eax,%ebx
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L6
L17:
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D20
data_type: string
name: read_data
arguments: data_tag: D14
data_type: string
name: read_data
arguments: data_tag: D29
data_type: string

tool: D20: Input array length:

tool: D14: %d


tool: D29: %-5d

assistant: ```c
void main() {
  int N;
  int *a;
  int i;
  printf("Input array length:");
  scanf("%d\n", &N);
  a = (int *)calloc(N, sizeof(int));
  for (i = 0; i < N; i++) {
    a[i] = i + 1;
    printf("%-5d", a[i]);
    if ((i + 1) % 10 == 0)
      printf("\n");
  }
  free(a);
  a = NULL;
  printf("\n");
}
```