user: 这段汇编代码用C语言表示是什么样的:

```asm
<softfloat_shiftRightJamM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  sar    $0x5,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L8
  mov    -0x24(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L43
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L43:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L122:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L74
  subl   $0x1,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L122
  jmp    L107
L74:
  nop
L107:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L106
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x30(%rbp)
  mov    -0x28(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L15
  mov    -0x24(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    -0x38(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    %eax,%edi
  call   <softfloat_shortShiftRightJamM@plt>
  cmpl   $0x0,-0x14(%rbp)
  jne    L50
  jmp    L29
L15:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L25
L72:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x30(%rbp)
  addq   $0x4,-0x8(%rbp)
  subl   $0x1,-0x10(%rbp)
L25:
  cmpl   $0x0,-0x10(%rbp)
  jne    L72
L50:
  mov    -0x24(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L106:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movl   $0x0,(%rax)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L106
  nop
L29:
  cmpl   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  or     $0x1,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
L5:
  nop
  leave
  ret
```

assistant: ```c
void softfloat_shiftRightJamM(uint_fast8_t size_words, const uint32_t *aPtr, uint32_t dist, uint32_t *zPtr) {
  uint32_t wordJam, wordDist, *ptr;
  uint_fast8_t i, innerDist;
  wordJam = 0;
  wordDist = dist >> 5;
  if (wordDist) {
    if (size_words < wordDist)
      wordDist = size_words;
    ptr = (uint32_t *)(aPtr + 0);
    i = wordDist;
    do {
      wordJam = *ptr++;
      if (wordJam)
        break;
      --i;
    } while (i);
    ptr = zPtr;
  }
  if (wordDist < size_words) {
    aPtr += (wordDist);
    innerDist = dist & 31;
    if (innerDist) {
      softfloat_shortShiftRightJamM(size_words - wordDist, aPtr, innerDist, zPtr + 0);
      if (!wordDist)
        goto wordJam;
    } else {
      aPtr += 0;
      ptr = zPtr + 0;
      for (i = size_words - wordDist; i; --i) {
        *ptr = *aPtr;
        aPtr += 1;
        ptr += 1;
      }
    }
    ptr = zPtr + ((size_words) - (wordDist));
  }
  do {
    *ptr++ = 0;
    --wordDist;
  } while (wordDist);
wordJam:
  if (wordJam)
    zPtr[0] |= 1;
}
```