user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  mov    $0x0,%r15d
  push   %r14
  mov    $0x0,%r14d
  push   %r13
  mov    $0x0,%r13d
  push   %r12
  push   %rbp
  mov    $0x0,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D57(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x8(%rsp)
  test   %eax,%eax
  jle    L64
  xor    %r12d,%r12d
  lea    D72(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%esi
  shr    $0x20,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%esi
  add    %esi,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  je     L80
  cmp    $0x5,%edx
  ja     L23
  movslq (%rbx,%rdx,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  addl   $0x1,0xc(%rsp)
  nopl   (%rax)
L23:
  add    $0x1,%r12d
  cmp    %r12d,0x14(%rsp)
  jg     L44
L64:
  mov    %ebp,%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15d,%esi
  lea    D89(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%esi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%esi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
  addl   $0x1,0x8(%rsp)
  jmp    L23
  nopw   0x0(%rax,%rax,1)
  add    $0x1,%r15d
  jmp    L23
  nopl   0x0(%rax)
  add    $0x1,%r13d
  jmp    L23
  nopl   0x0(%rax)
  add    $0x1,%r14d
  jmp    L23
  nopl   0x0(%rax)
L80:
  add    $0x1,%ebp
  jmp    L23
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D52
type_guessed: string
name: read_data
arguments: label: D57
type_guessed: string
name: read_data
arguments: label: D36
type_guessed: string
name: read_data
arguments: label: D89
type_guessed: string
name: read_data
arguments: label: D59
type_guessed: string
name: read_data
arguments: label: D88
type_guessed: string
name: read_data
arguments: label: D6
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string

tool: D52: How many times do you want to roll the die?

tool: D57:  %d

tool: D36: 
Ones: %d


tool: D89: Twos: %d


tool: D59: Threes: %d


tool: D88: Fours: %d


tool: D6: Fives: %d


tool: D15: Sixes: %d


assistant: ```c
int main() {
  int x = 0;
  int Die;
  int Counter;
  int Ones = 0;
  int Twos = 0;
  int Threes = 0;
  int Fours = 0;
  int Fives = 0;
  int Sixes = 0;
  srand(time(NULL));
  printf("How many times do you want to roll the die?\n");
  scanf(" %d", &Counter);
  while (x < Counter) {
    Die = rand() % 6 + 1;
    if (Die == 1) {
      Ones++;
    } else if (Die == 2) {
      Twos++;
    } else if (Die == 3) {
      Threes++;
    } else if (Die == 4) {
      Fours++;
    } else if (Die == 5) {
      Fives++;
    } else if (Die == 6) {
      Sixes++;
    }
    x++;
  }
  printf("\nOnes: %d\n", Ones);
  printf("Twos: %d\n", Twos);
  printf("Threes: %d\n", Threes);
  printf("Fours: %d\n", Fours);
  printf("Fives: %d\n", Fives);
  printf("Sixes: %d\n", Sixes);
  return 0;
}
```