ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<anulli>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void anulli(int *x, int p) {
  int i;
  for (i = 0; i < p; i++) {
    x[i] = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<anulli>:
  endbr64
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L5:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L5
L10:
  ret
```

assistant: ```c
void anulli(int *x, int p) {
  int i;
  for (i = 0; i < p; i++) {
    x[i] = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<anulli>:
  endbr64
  test   %esi,%esi
  jle    L3
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void anulli(int *x, int p) {
  int i;
  for (i = 0; i < p; i++) {
    x[i] = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<anulli>:
  endbr64
  test   %esi,%esi
  jle    L3
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void anulli(int *x, int p) {
  int i;
  for (i = 0; i < p; i++) {
    x[i] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: test!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("test!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string

tool: D5: test!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("test!\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: test!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("test!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: test!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("test!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wmatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <nmatch@plt>
  test   %eax,%eax
  jne    L34
  mov    $0x0,%eax
  jmp    L16
L34:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L9
  mov    $0x1,%eax
L16:
  leave
  ret
```

assistant: ```c
bool wmatch(char *word) {
  for (int i = 0; i < strlen(word) - 1; i++) {
    if (nmatch(word[i], word[i + 1]) == false)
      return false;
  }
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wmatch>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L19
  movsbl 0x1(%rbp,%rbx,1),%esi
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <nmatch@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  jne    L14
  jmp    L17
L19:
  mov    $0x1,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool wmatch(char *word) {
  for (int i = 0; i < strlen(word) - 1; i++) {
    if (nmatch(word[i], word[i + 1]) == false)
      return false;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wmatch>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax)
L3:
  movsbl 0x1(%rbp,%rbx,1),%esi
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <nmatch@plt>
  test   %eax,%eax
  je     L14
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L3
  mov    $0x1,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool wmatch(char *word) {
  for (int i = 0; i < strlen(word) - 1; i++) {
    if (nmatch(word[i], word[i + 1]) == false)
      return false;
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wmatch>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax)
L24:
  movsbl 0x1(%rbp,%rbx,1),%esi
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <nmatch@plt>
  test   %eax,%eax
  je     L6
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L24
  mov    $0x1,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool wmatch(char *word) {
  for (int i = 0; i < strlen(word) - 1; i++) {
    if (nmatch(word[i], word[i + 1]) == false)
      return false;
  }
  return true;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(void) {
  int i = 1;
  int *ii = &i;
  !ii;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 1;
  int *ii = &i;
  !ii;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 1;
  int *ii = &i;
  !ii;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 1;
  int *ii = &i;
  !ii;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strstr1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L26
L10:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp2@plt>
  test   %rax,%rax
  jne    L7
  mov    -0x8(%rbp),%rax
  jmp    L38
L7:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    $0x0,%eax
L38:
  leave
  ret
```

assistant: ```c
char *strstr1(const char *s1, const char *s2) {
  while (*s1 != '\0') {
    if (strcmp2(s1, s2) == 0)
      return s1;
    s1++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strstr1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x0,(%rdi)
  je     L10
L3:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp2@plt>
  test   %rax,%rax
  je     L26
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L3
  mov    $0x0,%eax
  jmp    L33
L10:
  mov    $0x0,%eax
  jmp    L33
L26:
  mov    %rbx,%rax
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strstr1(const char *s1, const char *s2) {
  while (*s1 != '\0') {
    if (strcmp2(s1, s2) == 0)
      return s1;
    s1++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strstr1>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L16
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L23:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L10
L30:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp2@plt>
  test   %rax,%rax
  jne    L23
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strstr1(const char *s1, const char *s2) {
  while (*s1 != '\0') {
    if (strcmp2(s1, s2) == 0)
      return s1;
    s1++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strstr1>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L35
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L39
L37:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp2@plt>
  test   %rax,%rax
  jne    L27
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strstr1(const char *s1, const char *s2) {
  while (*s1 != '\0') {
    if (strcmp2(s1, s2) == 0)
      return s1;
    s1++;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <PopulateRoomArray@plt>
  mov    $0x0,%eax
  call   <WriteRoomFiles@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  srand(time(NULL));
  PopulateRoomArray();
  WriteRoomFiles();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <PopulateRoomArray@plt>
  mov    $0x0,%eax
  call   <WriteRoomFiles@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  srand(time(NULL));
  PopulateRoomArray();
  WriteRoomFiles();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <PopulateRoomArray@plt>
  xor    %eax,%eax
  call   <WriteRoomFiles@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  srand(time(NULL));
  PopulateRoomArray();
  WriteRoomFiles();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <PopulateRoomArray@plt>
  xor    %eax,%eax
  call   <WriteRoomFiles@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  srand(time(NULL));
  PopulateRoomArray();
  WriteRoomFiles();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0xa,-0x10(%rbp)
  movsd  D51(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movss  D15(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    D57(%rip),%eax
  cmp    $0x28,%eax
  jle    L3
  mov    D57(%rip),%eax
  cmp    $0x3b,%eax
  jg     L3
  mov    $0x4,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
L3:
  mov    D57(%rip),%eax
  cmp    $0x4,%eax
  je     L49
  cmp    $0x5,%eax
  jmp    L6
L49:
  nop
L6:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D51
data_type: f64
name: read_data
arguments: label: D15
data_type: f32
name: read_data
arguments: label: D57
data_type: byte[4]
name: read_data
arguments: label: D12
data_type: string

tool: D51: 1

tool: D15: 33

tool: {"D57": [0x2b,0x00,0x00,0x00]}

tool: D12: valami %d 


assistant: ```c
int main(int argc, char **argv) {
  const static int i = 43;
  long volatile int egy = 10;
  double a = 1.0;
  float b = (float)33;
  if (i > 40 && i < 60) {
    printf("valami %d \n", sizeof(int));
  } else {
    switch (i) {
    case 5:
      break;
    case 4:
      break;
    default:
      break;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movq   $0xa,0x8(%rsp)
  mov    $0x4,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: valami %d 


assistant: ```c
int main(int argc, char **argv) {
  const static int i = 43;
  long volatile int egy = 10;
  double a = 1.0;
  float b = (float)33;
  if (i > 40 && i < 60) {
    printf("valami %d \n", sizeof(int));
  } else {
    switch (i) {
    case 5:
      break;
    case 4:
      break;
    default:
      break;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%esi
  lea    D7(%rip),%rdi
  movq   $0xa,0x8(%rsp)
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D7: valami %d 


assistant: ```c
int main(int argc, char **argv) {
  const static int i = 43;
  long volatile int egy = 10;
  double a = 1.0;
  float b = (float)33;
  if (i > 40 && i < 60) {
    printf("valami %d \n", sizeof(int));
  } else {
    switch (i) {
    case 5:
      break;
    case 4:
      break;
    default:
      break;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%esi
  lea    D8(%rip),%rdi
  movq   $0xa,0x8(%rsp)
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: valami %d 


assistant: ```c
int main(int argc, char **argv) {
  const static int i = 43;
  long volatile int egy = 10;
  double a = 1.0;
  float b = (float)33;
  if (i > 40 && i < 60) {
    printf("valami %d \n", sizeof(int));
  } else {
    switch (i) {
    case 5:
      break;
    case 4:
      break;
    default:
      break;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L9
L0:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dst, const char *src) {
  while (*src) {
    *dst = *src;
    dst++;
    src++;
  }
  *dst = '\0';
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L1
L8:
  mov    %dl,(%rax)
  add    $0x1,%rax
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L8
L1:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *dst, const char *src) {
  while (*src) {
    *dst = *src;
    dst++;
    src++;
  }
  *dst = '\0';
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L9
  xchg   %ax,%ax
L5:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L5
L9:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *dst, const char *src) {
  while (*src) {
    *dst = *src;
    dst++;
    src++;
  }
  *dst = '\0';
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L0
  xchg   %ax,%ax
L11:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L11
L0:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *dst, const char *src) {
  while (*src) {
    *dst = *src;
    dst++;
    src++;
  }
  *dst = '\0';
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<maskfarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x28(%rbp),%rcx
  lea    -0x2c(%rbp),%rdx
  mov    -0x48(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fmin_withindex@plt>
  mov    -0x48(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L20
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x4c(%rbp)
  jne    L3
  movss  -0x2c(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
L3:
  addq   $0x4,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L20:
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L13
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
void maskfarray(float *in, unsigned char *mask, size_t size, unsigned char f1_b0) {
  size_t index;
  float min, *fpt = in, *ffpt;
  unsigned char *mpt = mask;
  fmin_withindex(in, size, &min, &index);
  ffpt = fpt + size;
  for (; fpt < ffpt; fpt++, mpt++)
    if (*mpt == f1_b0)
      *fpt = min;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<maskfarray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %r13,%rsi
  call   <fmin_withindex@plt>
  lea    (%rbx,%r13,4),%rax
  cmp    %rax,%rbx
  jae    L25
  movss  0xc(%rsp),%xmm0
  jmp    L14
L28:
  add    $0x4,%rbx
  add    $0x1,%rbp
  cmp    %rbx,%rax
  jbe    L25
L14:
  cmp    %r12b,0x0(%rbp)
  jne    L28
  movss  %xmm0,(%rbx)
  jmp    L28
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void maskfarray(float *in, unsigned char *mask, size_t size, unsigned char f1_b0) {
  size_t index;
  float min, *fpt = in, *ffpt;
  unsigned char *mpt = mask;
  fmin_withindex(in, size, &min, &index);
  ffpt = fpt + size;
  for (; fpt < ffpt; fpt++, mpt++)
    if (*mpt == f1_b0)
      *fpt = min;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<maskfarray>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  call   <fmin_withindex@plt>
  lea    (%rbx,%r12,4),%rax
  cmp    %rax,%rbx
  jae    L0
  movss  0xc(%rsp),%xmm0
  nopw   0x0(%rax,%rax,1)
L5:
  cmp    %bpl,0x0(%r13)
  jne    L21
  movss  %xmm0,(%rbx)
L21:
  add    $0x4,%rbx
  add    $0x1,%r13
  cmp    %rbx,%rax
  ja     L5
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void maskfarray(float *in, unsigned char *mask, size_t size, unsigned char f1_b0) {
  size_t index;
  float min, *fpt = in, *ffpt;
  unsigned char *mpt = mask;
  fmin_withindex(in, size, &min, &index);
  ffpt = fpt + size;
  for (; fpt < ffpt; fpt++, mpt++)
    if (*mpt == f1_b0)
      *fpt = min;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<maskfarray>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  call   <fmin_withindex@plt>
  lea    (%rbx,%r12,4),%rax
  cmp    %rax,%rbx
  jae    L14
  movss  0xc(%rsp),%xmm0
  nopw   0x0(%rax,%rax,1)
L30:
  cmp    %bpl,0x0(%r13)
  jne    L16
  movss  %xmm0,(%rbx)
L16:
  add    $0x4,%rbx
  add    $0x1,%r13
  cmp    %rbx,%rax
  ja     L30
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void maskfarray(float *in, unsigned char *mask, size_t size, unsigned char f1_b0) {
  size_t index;
  float min, *fpt = in, *ffpt;
  unsigned char *mpt = mask;
  fmin_withindex(in, size, &min, &index);
  ffpt = fpt + size;
  for (; fpt < ffpt; fpt++, mpt++)
    if (*mpt == f1_b0)
      *fpt = min;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wurm_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <wurm_vsnprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void wurm_snprintf(char *s, size_t n, const char *format, ...) {
  va_list arg;
  va_start(arg, format);
  wurm_vsnprintf(s, n, format, arg);
  va_end(arg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wurm_snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <wurm_vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void wurm_snprintf(char *s, size_t n, const char *format, ...) {
  va_list arg;
  va_start(arg, format);
  wurm_vsnprintf(s, n, format, arg);
  va_end(arg);
}
```