user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0xa,%r14d
  movl   $0xb,0xc(%rsp)
  mov    $0x1,%r15d
  movl   $0x1,0x8(%rsp)
  mov    $0xb,%r12d
  movsd  D1(%rip),%xmm6
  movsd  %xmm6,(%rsp)
  jmp    L40
L131:
  add    $0x1,%r12d
  cmp    $0x63,%r12d
  jg     L44
L40:
  mov    $0x0,%esi
  mov    %r14d,%edi
  call   <digit_usage@plt>
  mov    %eax,%ebp
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <digit_usage@plt>
  mov    %eax,%ebx
  mov    %ebp,%r13d
  and    %eax,%r13d
  cmp    %r13d,%ebp
  sete   %al
  cmp    %r13d,%ebx
  sete   %dl
  or     %dl,%al
  jne    L131
  cmp    $0x1,%r13d
  jbe    L131
  mov    %r13d,%edi
  call   <log2@plt>
  movapd %xmm0,%xmm2
  movsd  (%rsp),%xmm3
  movapd %xmm3,%xmm1
  andpd  %xmm0,%xmm1
  movsd  D4(%rip),%xmm4
  ucomisd %xmm1,%xmm4
  jbe    L42
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  movsd  D23(%rip),%xmm5
  andpd  %xmm5,%xmm2
  subsd  %xmm2,%xmm1
  andnpd %xmm0,%xmm3
  movapd %xmm3,%xmm2
  orpd   %xmm1,%xmm2
L42:
  ucomisd %xmm0,%xmm2
  jp     L131
  jne    L131
  mov    %ebp,%edi
  xor    %r13d,%edi
  call   <log2@plt>
  movq   %xmm0,%rbp
  xor    %r13d,%ebx
  mov    %ebx,%edi
  call   <log2@plt>
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sd %r14d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r12d,%xmm1
  divsd  %xmm1,%xmm0
  movq   %rbp,%xmm1
  divsd  %xmm2,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L131
  jne    L131
  mov    0x8(%rsp),%eax
  imul   %r14d,%eax
  mov    %eax,0x8(%rsp)
  imul   %r12d,%r15d
  jmp    L131
L44:
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%r12d
  cmp    $0x63,%r12d
  jg     L31
  mov    0xc(%rsp),%r14d
  mov    %r12d,0xc(%rsp)
  jmp    L40
L31:
  mov    $0x2,%ebx
L107:
  mov    %r15d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jle    L34
  mov    0x8(%rsp),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L165
  mov    %r15d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L165
L100:
  mov    0x8(%rsp),%eax
  cltd
  idiv   %ebx
  mov    %eax,0x8(%rsp)
  mov    %r15d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%r15d
  mov    0x8(%rsp),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L165
  mov    %r15d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L100
L165:
  add    $0x1,%ebx
  jmp    L107
L34:
  mov    %r15d,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: byte[8]
name: parse_data
arguments: tag: D4
type: byte[8]
name: parse_data
arguments: tag: D23
type: byte[8]
name: parse_data
arguments: tag: D0
type: string

tool: {"D1": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D0: %d


assistant: ```c
int main(int argc, char **argv) {
  double cc, n2, d2;
  int n, nn, d, dd, c;
  int np = 1, dp = 1;
  for (n = 100 / 10; n < 100; n++) {
    for (d = n + 1; d < 100; d++) {
      nn = digit_usage(n, 0);
      dd = digit_usage(d, 0);
      c = nn & dd;
      if (c == 0 || c == 1 || (nn ^ c) == 0 || (dd ^ c) == 0)
        continue;
      cc = log2(c);
      if (cc != floor(cc))
        continue;
      n2 = log2(nn ^ c);
      d2 = log2(dd ^ c);
      if ((double)n / d == n2 / d2) {
        np *= n;
        dp *= d;
      }
    }
  }
  n = 2;
  while (n < sqrt(dp)) {
    while (np % n == 0 && dp % n == 0) {
      np /= n;
      dp /= n;
    }
    n++;
  }
  printf("%d\n", dp);
  return 0;
}
```