ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CreateType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
struct type *CreateType(char *text, struct fieldnode *fields) {
  struct type *newtype;
  struct symbol *newsym;
}
```
user: What is the c source code of the assembly code below:

```asm
<CreateType>:
  endbr64
  ret
```

assistant: ```c
struct type *CreateType(char *text, struct fieldnode *fields) {
  struct type *newtype;
  struct symbol *newsym;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CreateType>:
  endbr64
  ret
```

assistant: ```c
struct type *CreateType(char *text, struct fieldnode *fields) {
  struct type *newtype;
  struct symbol *newsym;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CreateType>:
  endbr64
  ret
```

assistant: ```c
struct type *CreateType(char *text, struct fieldnode *fields) {
  struct type *newtype;
  struct symbol *newsym;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<skip_to_blank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L26
L29:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L32
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L32
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L32:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skip_to_blank(char *s) {
  while (*s != ' ' && *s != '\t' && *s)
    s++;
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_to_blank>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   $0xdf,%dl
  je     L34
  cmp    $0x9,%dl
  je     L34
L22:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L34
  cmp    $0x9,%dl
  jne    L22
L34:
  ret
```

assistant: ```c
char *skip_to_blank(char *s) {
  while (*s != ' ' && *s != '\t' && *s)
    s++;
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<skip_to_blank>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   $0xdf,%dl
  jne    L13
  jmp    L10
  nopl   0x0(%rax)
L24:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  je     L10
L13:
  cmp    $0x9,%dl
  jne    L24
L10:
  ret
```

assistant: ```c
char *skip_to_blank(char *s) {
  while (*s != ' ' && *s != '\t' && *s)
    s++;
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_to_blank>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   $0xdf,%dl
  jne    L39
  jmp    L1
  nopl   0x0(%rax)
L35:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  je     L1
L39:
  cmp    $0x9,%dl
  jne    L35
L1:
  ret
```

assistant: ```c
char *skip_to_blank(char *s) {
  while (*s != ' ' && *s != '\t' && *s)
    s++;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Copy_V1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L151
  cmpq   $0x1,-0x18(%rbp)
  jne    L191
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <exegesis_copyblock@plt>
  jmp    L80
L191:
  cmpq   $0x2,-0x18(%rbp)
  jne    L49
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <exegesis_copyblock@plt>
  jmp    L80
L49:
  cmpq   $0x3,-0x18(%rbp)
  jne    L146
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <exegesis_copyblock@plt>
  jmp    L80
L146:
  cmpq   $0x4,-0x18(%rbp)
  jne    L23
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <exegesis_copyblock@plt>
  jmp    L80
L23:
  cmpq   $0x8,-0x18(%rbp)
  ja     L63
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x4,%ecx
  mov    %rax,%rdi
  call   <exegesis_overlap@plt>
  jmp    L80
L63:
  cmpq   $0x10,-0x18(%rbp)
  ja     L87
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x8,%ecx
  mov    %rax,%rdi
  call   <exegesis_overlap@plt>
  jmp    L80
L87:
  cmpq   $0x20,-0x18(%rbp)
  ja     L38
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x10,%ecx
  mov    %rax,%rdi
  call   <exegesis_overlap@plt>
  jmp    L80
L38:
  cmpq   $0x40,-0x18(%rbp)
  ja     L184
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x20,%ecx
  mov    %rax,%rdi
  call   <exegesis_overlap@plt>
  jmp    L80
L184:
  cmpq   $0x80,-0x18(%rbp)
  ja     L67
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x40,%ecx
  mov    %rax,%rdi
  call   <exegesis_overlap@plt>
  jmp    L80
L67:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <CopyRepMovsb@plt>
  jmp    L80
L151:
  nop
L80:
  leave
  ret
```

assistant: ```c
void Copy_V1(char *const dst, const char *const src, size_t count) {
  if (count == 0)
    return;
  if (count == 1)
    return exegesis_copyblock(dst, src, 1);
  if (count == 2)
    return exegesis_copyblock(dst, src, 2);
  if (count == 3)
    return exegesis_copyblock(dst, src, 3);
  if (count == 4)
    return exegesis_copyblock(dst, src, 4);
  if (count <= 8) {
    exegesis_overlap(dst, src, count, 4);
    return;
  };
  if (count <= 16) {
    exegesis_overlap(dst, src, count, 8);
    return;
  };
  if (count <= 32) {
    exegesis_overlap(dst, src, count, 16);
    return;
  };
  if (count <= 64) {
    exegesis_overlap(dst, src, count, 32);
    return;
  };
  if (count <= 128) {
    exegesis_overlap(dst, src, count, 64);
    return;
  };
  CopyRepMovsb(dst, src, count);
}
```
user: What is the c source code of the assembly code below:

```asm
<Copy_V1>:
  endbr64
  test   %rdx,%rdx
  je     L180
  sub    $0x8,%rsp
  cmp    $0x1,%rdx
  je     L138
  cmp    $0x2,%rdx
  je     L25
  cmp    $0x3,%rdx
  je     L110
  cmp    $0x4,%rdx
  je     L153
  cmp    $0x8,%rdx
  jbe    L29
  cmp    $0x10,%rdx
  jbe    L84
  cmp    $0x20,%rdx
  jbe    L96
  cmp    $0x40,%rdx
  jbe    L14
  cmp    $0x80,%rdx
  jbe    L94
  call   <CopyRepMovsb@plt>
L12:
  add    $0x8,%rsp
  ret
L138:
  call   <exegesis_copyblock@plt>
  jmp    L12
L25:
  call   <exegesis_copyblock@plt>
  jmp    L12
L110:
  call   <exegesis_copyblock@plt>
  jmp    L12
L153:
  call   <exegesis_copyblock@plt>
  jmp    L12
L29:
  mov    $0x4,%ecx
  call   <exegesis_overlap@plt>
  jmp    L12
L84:
  mov    $0x8,%ecx
  call   <exegesis_overlap@plt>
  jmp    L12
L96:
  mov    $0x10,%ecx
  call   <exegesis_overlap@plt>
  jmp    L12
L14:
  mov    $0x20,%ecx
  call   <exegesis_overlap@plt>
  jmp    L12
L94:
  mov    $0x40,%ecx
  call   <exegesis_overlap@plt>
  jmp    L12
L180:
  ret
```

assistant: ```c
void Copy_V1(char *const dst, const char *const src, size_t count) {
  if (count == 0)
    return;
  if (count == 1)
    return exegesis_copyblock(dst, src, 1);
  if (count == 2)
    return exegesis_copyblock(dst, src, 2);
  if (count == 3)
    return exegesis_copyblock(dst, src, 3);
  if (count == 4)
    return exegesis_copyblock(dst, src, 4);
  if (count <= 8) {
    exegesis_overlap(dst, src, count, 4);
    return;
  };
  if (count <= 16) {
    exegesis_overlap(dst, src, count, 8);
    return;
  };
  if (count <= 32) {
    exegesis_overlap(dst, src, count, 16);
    return;
  };
  if (count <= 64) {
    exegesis_overlap(dst, src, count, 32);
    return;
  };
  if (count <= 128) {
    exegesis_overlap(dst, src, count, 64);
    return;
  };
  CopyRepMovsb(dst, src, count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Copy_V1>:
  endbr64
  test   %rdx,%rdx
  je     L69
  cmp    $0x1,%rdx
  je     L36
  cmp    $0x2,%rdx
  je     L36
  cmp    $0x3,%rdx
  je     L36
  cmp    $0x4,%rdx
  je     L36
  cmp    $0x8,%rdx
  jbe    L65
  cmp    $0x10,%rdx
  jbe    L3
  cmp    $0x20,%rdx
  jbe    L23
  cmp    $0x40,%rdx
  jbe    L95
  cmp    $0x80,%rdx
  jbe    L38
  jmp    1080 <CopyRepMovsb@plt>
  nopw   0x0(%rax,%rax,1)
L36:
  jmp    1070 <exegesis_copyblock@plt>
  nopl   (%rax)
L69:
  ret
  nopl   0x0(%rax)
L65:
  mov    $0x4,%ecx
  jmp    1090 <exegesis_overlap@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x8,%ecx
  jmp    1090 <exegesis_overlap@plt>
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0x40,%ecx
  jmp    1090 <exegesis_overlap@plt>
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0x10,%ecx
  jmp    1090 <exegesis_overlap@plt>
  nopw   0x0(%rax,%rax,1)
L95:
  mov    $0x20,%ecx
  jmp    1090 <exegesis_overlap@plt>
```

assistant: ```c
void Copy_V1(char *const dst, const char *const src, size_t count) {
  if (count == 0)
    return;
  if (count == 1)
    return exegesis_copyblock(dst, src, 1);
  if (count == 2)
    return exegesis_copyblock(dst, src, 2);
  if (count == 3)
    return exegesis_copyblock(dst, src, 3);
  if (count == 4)
    return exegesis_copyblock(dst, src, 4);
  if (count <= 8) {
    exegesis_overlap(dst, src, count, 4);
    return;
  };
  if (count <= 16) {
    exegesis_overlap(dst, src, count, 8);
    return;
  };
  if (count <= 32) {
    exegesis_overlap(dst, src, count, 16);
    return;
  };
  if (count <= 64) {
    exegesis_overlap(dst, src, count, 32);
    return;
  };
  if (count <= 128) {
    exegesis_overlap(dst, src, count, 64);
    return;
  };
  CopyRepMovsb(dst, src, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Copy_V1>:
  endbr64
  test   %rdx,%rdx
  je     L22
  cmp    $0x1,%rdx
  je     L70
  cmp    $0x2,%rdx
  je     L70
  cmp    $0x3,%rdx
  je     L70
  cmp    $0x4,%rdx
  je     L70
  cmp    $0x8,%rdx
  jbe    L28
  cmp    $0x10,%rdx
  jbe    L45
  cmp    $0x20,%rdx
  jbe    L3
  cmp    $0x40,%rdx
  jbe    L75
  cmp    $0x80,%rdx
  jbe    L77
  jmp    1080 <CopyRepMovsb@plt>
  nopw   0x0(%rax,%rax,1)
L70:
  jmp    1070 <exegesis_copyblock@plt>
  nopl   (%rax)
L22:
  ret
  nopl   0x0(%rax)
L28:
  mov    $0x4,%ecx
  jmp    1090 <exegesis_overlap@plt>
  nopw   0x0(%rax,%rax,1)
L45:
  mov    $0x8,%ecx
  jmp    1090 <exegesis_overlap@plt>
  nopw   0x0(%rax,%rax,1)
L77:
  mov    $0x40,%ecx
  jmp    1090 <exegesis_overlap@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x10,%ecx
  jmp    1090 <exegesis_overlap@plt>
  nopw   0x0(%rax,%rax,1)
L75:
  mov    $0x20,%ecx
  jmp    1090 <exegesis_overlap@plt>
```

assistant: ```c
void Copy_V1(char *const dst, const char *const src, size_t count) {
  if (count == 0)
    return;
  if (count == 1)
    return exegesis_copyblock(dst, src, 1);
  if (count == 2)
    return exegesis_copyblock(dst, src, 2);
  if (count == 3)
    return exegesis_copyblock(dst, src, 3);
  if (count == 4)
    return exegesis_copyblock(dst, src, 4);
  if (count <= 8) {
    exegesis_overlap(dst, src, count, 4);
    return;
  };
  if (count <= 16) {
    exegesis_overlap(dst, src, count, 8);
    return;
  };
  if (count <= 32) {
    exegesis_overlap(dst, src, count, 16);
    return;
  };
  if (count <= 64) {
    exegesis_overlap(dst, src, count, 32);
    return;
  };
  if (count <= 128) {
    exegesis_overlap(dst, src, count, 64);
    return;
  };
  CopyRepMovsb(dst, src, count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xdc(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xdc(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L20
L24:
  lea    -0xd0(%rbp),%rdx
  mov    -0xd4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xd4(%rbp)
L20:
  mov    -0xdc(%rbp),%eax
  cmp    %eax,-0xd4(%rbp)
  jl     L24
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xd8(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xdc(%rbp),%ecx
  mov    -0xd8(%rbp),%eax
  lea    -0xd0(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <binary_search@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D56
data_type: string
name: disassemble_data
arguments: data_label: D53
data_type: string
name: disassemble_data
arguments: data_label: D33
data_type: string
name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D56: Enter total number of elements :

tool: D53: %d

tool: D33: Enter %d number :

tool: D2: Enter a number to find :

assistant: ```c
int main() {
  int n, i, arr[50], search;
  printf("Enter total number of elements :");
  scanf("%d", &n);
  printf("Enter %d number :", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Enter a number to find :");
  scanf("%d", &search);
  binary_search(search, n, arr);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L12
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D36(%rip),%r12
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L3
L12:
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdx
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <binary_search@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_infered: string
name: disassemble_data
arguments: tag: D36
type_infered: string
name: disassemble_data
arguments: tag: D20
type_infered: string
name: disassemble_data
arguments: tag: D57
type_infered: string

tool: D2: Enter total number of elements :

tool: D36: %d

tool: D20: Enter %d number :

tool: D57: Enter a number to find :

assistant: ```c
int main() {
  int n, i, arr[50], search;
  printf("Enter total number of elements :");
  scanf("%d", &n);
  printf("Enter %d number :", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Enter a number to find :");
  scanf("%d", &search);
  binary_search(search, n, arr);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D27(%rip),%rdi
  push   %r12
  lea    D31(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    %r13,%rbp
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L26
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L6
L26:
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %r13,%rdx
  call   <binary_search@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D27
type: string
name: read_data
arguments: label: D31
type: string
name: read_data
arguments: label: D25
type: string
name: read_data
arguments: label: D39
type: string

tool: D27: Enter total number of elements :

tool: D31: %d

tool: D25: Enter %d number :

tool: D39: Enter a number to find :

assistant: ```c
int main() {
  int n, i, arr[50], search;
  printf("Enter total number of elements :");
  scanf("%d", &n);
  printf("Enter %d number :", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Enter a number to find :");
  scanf("%d", &search);
  binary_search(search, n, arr);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%rdi
  push   %r12
  lea    D31(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    %r13,%rbp
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L12
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L28
L12:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %r13,%rdx
  call   <binary_search@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D31
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D12
type: string

tool: D0: Enter total number of elements :

tool: D31: %d

tool: D14: Enter %d number :

tool: D12: Enter a number to find :

assistant: ```c
int main() {
  int n, i, arr[50], search;
  printf("Enter total number of elements :");
  scanf("%d", &n);
  printf("Enter %d number :", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Enter a number to find :");
  scanf("%d", &search);
  binary_search(search, n, arr);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sbt_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D16(%rip),%eax
  test   %eax,%eax
  je     L4
  mov    $0x0,%eax
  call   <fidct_init@plt>
  movl   $0x0,D16(%rip)
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sbt_init() {
  static int first_pass = 1;
  if (first_pass) {
    fidct_init();
    first_pass = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sbt_init>:
  endbr64
  cmpl   $0x0,D14(%rip)
  jne    L4
  ret
L4:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fidct_init@plt>
  movl   $0x0,D14(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sbt_init() {
  static int first_pass = 1;
  if (first_pass) {
    fidct_init();
    first_pass = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sbt_init>:
  endbr64
  mov    D3(%rip),%eax
  test   %eax,%eax
  jne    L7
  ret
  nop
L7:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fidct_init@plt>
  movl   $0x0,D3(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sbt_init() {
  static int first_pass = 1;
  if (first_pass) {
    fidct_init();
    first_pass = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sbt_init>:
  endbr64
  mov    D8(%rip),%eax
  test   %eax,%eax
  jne    L7
  ret
  nop
L7:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fidct_init@plt>
  movl   $0x0,D8(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sbt_init() {
  static int first_pass = 1;
  if (first_pass) {
    fidct_init();
    first_pass = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x102c(%rbp)
  movl   $0x0,-0x1010(%rbp)
  jmp    L41
L30:
  movq   $0x0,-0x1020(%rbp)
  jmp    L21
L56:
  mov    -0x1020(%rbp),%rax
  mov    -0x1010(%rbp,%rax,4),%ecx
  mov    -0x102c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x1020(%rbp),%rax
  add    %rdx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
  mov    %edx,-0x1010(%rbp,%rax,4)
  addq   $0x1,-0x1020(%rbp)
L21:
  mov    -0x102c(%rbp),%eax
  cltq
  cmp    %rax,-0x1020(%rbp)
  jb     L56
  shll   -0x102c(%rbp)
L41:
  cmpl   $0x200,-0x102c(%rbp)
  jle    L30
  lea    -0x1034(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1034(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x1018(%rbp)
  movl   $0x0,-0x1028(%rbp)
  jmp    L78
L88:
  lea    -0x1030(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1030(%rbp),%eax
  mov    -0x1028(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x1018(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  mov    -0x1010(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1028(%rbp)
L78:
  mov    -0x1034(%rbp),%eax
  cmp    %eax,-0x1028(%rbp)
  jl     L88
  movl   $0x0,-0x1024(%rbp)
  jmp    L72
L43:
  mov    -0x1024(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1018(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1024(%rbp)
L72:
  mov    -0x1034(%rbp),%eax
  cmp    %eax,-0x1024(%rbp)
  jl     L43
  mov    -0x1018(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type: string
name: disassemble_data
arguments: label: D15
type: string

tool: D17: %d

tool: D15: %u


assistant: ```c
int main() {
  unsigned int s[1024];
  int cnt = 1;
  s[0] = 0;
  while (cnt <= 512) {
    for (size_t i = 0; i < cnt; i++) {
      s[cnt + i] = 1 - s[i];
    }
    cnt *= 2;
  }
  int q;
  scanf("%d", &q);
  unsigned int *output = malloc(sizeof(unsigned int) * q);
  for (int a0 = 0; a0 < q; a0++) {
    int x;
    scanf("%d", &x);
    output[a0] = s[x];
  }
  for (int a0 = 0; a0 < q; a0++) {
    printf("%u\n", output[a0]);
  }
  free(output);
  return 0;
}
```