ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L0
L1:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  js     L77
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L55
L77:
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jns    L88
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L88
L55:
  addl   $0x1,-0x18(%rbp)
L88:
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  js     L20
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L79
L20:
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jns    L44
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L44
L79:
  addl   $0x1,-0x14(%rbp)
L44:
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jle    L126
  addl   $0x1,-0x10(%rbp)
L126:
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jns    L123
  addl   $0x1,-0xc(%rbp)
L123:
  addl   $0x1,-0x1c(%rbp)
L0:
  cmpl   $0x5,-0x1c(%rbp)
  jle    L1
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D16
type: string
name: unpack_data
arguments: data_label: D49
type: string
name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D23
type: string

tool: D24: %d

tool: D16: %d valor(es) par(es)


tool: D49: %d valor(es) impar(es)


tool: D0: %d valor(es) positivo(s)


tool: D23: %d valor(es) negativo(s)


assistant: ```c
int main() {
  int i, n, esum = 0, osum = 0, psum = 0, nsum = 0;
  for (i = 1; i <= 5; i++) {
    scanf("%d", &n);
    if (n >= 0 && n % 2 == 0 || n < 0 && n % 2 == -0) {
      esum++;
    }
    if (n >= 0 && n % 2 != 0 || n < 0 && n % 2 != -0) {
      osum++;
    }
    if (n > 0) {
      psum++;
    }
    if (n < 0) {
      nsum++;
    }
  }
  printf("%d valor(es) par(es)\n", esum);
  printf("%d valor(es) impar(es)\n", osum);
  printf("%d valor(es) positivo(s)\n", psum);
  printf("%d valor(es) negativo(s)\n", nsum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x5,%ebx
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  lea    D5(%rip),%r15
  jmp    L40
L67:
  cmp    $0x80000000,%eax
  sbb    $0xffffffff,%r14d
  jmp    L20
L38:
  mov    %r13d,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    %r14d,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  add    $0x1,%r12d
L66:
  test   %eax,%eax
  jle    L67
  add    $0x1,%ebp
L20:
  sub    $0x1,%ebx
  je     L38
L40:
  lea    0x4(%rsp),%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   $0x1,%al
  jne    L9
  add    $0x1,%r13d
  jmp    L66
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D35
type_guessed: string
name: extract_symbolic_data
arguments: tag: D26
type_guessed: string

tool: D5: %d

tool: D24: %d valor(es) par(es)


tool: D9: %d valor(es) impar(es)


tool: D35: %d valor(es) positivo(s)


tool: D26: %d valor(es) negativo(s)


assistant: ```c
int main() {
  int i, n, esum = 0, osum = 0, psum = 0, nsum = 0;
  for (i = 1; i <= 5; i++) {
    scanf("%d", &n);
    if (n >= 0 && n % 2 == 0 || n < 0 && n % 2 == -0) {
      esum++;
    }
    if (n >= 0 && n % 2 != 0 || n < 0 && n % 2 != -0) {
      osum++;
    }
    if (n > 0) {
      psum++;
    }
    if (n < 0) {
      nsum++;
    }
  }
  printf("%d valor(es) par(es)\n", esum);
  printf("%d valor(es) impar(es)\n", osum);
  printf("%d valor(es) positivo(s)\n", psum);
  printf("%d valor(es) negativo(s)\n", nsum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0x14(%rsp),%r15
L1:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   $0x1,%al
  jne    L34
  add    $0x1,%r13d
  test   %eax,%eax
  jle    L59
L28:
  add    $0x1,%ebp
L44:
  sub    $0x1,%ebx
  jne    L1
  mov    %r13d,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%r12d
  test   %eax,%eax
  jg     L28
L59:
  cmp    $0x1,%eax
  sbbl   $0xffffffff,0xc(%rsp)
  jmp    L44
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type: string
name: disassemble_data
arguments: data_tag: D25
type: string
name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D40
type: string
name: disassemble_data
arguments: data_tag: D1
type: string

tool: D17: %d

tool: D25: %d valor(es) par(es)


tool: D6: %d valor(es) impar(es)


tool: D40: %d valor(es) positivo(s)


tool: D1: %d valor(es) negativo(s)


assistant: ```c
int main() {
  int i, n, esum = 0, osum = 0, psum = 0, nsum = 0;
  for (i = 1; i <= 5; i++) {
    scanf("%d", &n);
    if (n >= 0 && n % 2 == 0 || n < 0 && n % 2 == -0) {
      esum++;
    }
    if (n >= 0 && n % 2 != 0 || n < 0 && n % 2 != -0) {
      osum++;
    }
    if (n > 0) {
      psum++;
    }
    if (n < 0) {
      nsum++;
    }
  }
  printf("%d valor(es) par(es)\n", esum);
  printf("%d valor(es) impar(es)\n", osum);
  printf("%d valor(es) positivo(s)\n", psum);
  printf("%d valor(es) negativo(s)\n", nsum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D25(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0x14(%rsp),%r15
L43:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   $0x1,%al
  jne    L42
  add    $0x1,%r13d
  test   %eax,%eax
  jle    L9
L58:
  add    $0x1,%ebp
L3:
  sub    $0x1,%ebx
  jne    L43
  mov    %r13d,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%r12d
  test   %eax,%eax
  jg     L58
L9:
  cmp    $0x1,%eax
  sbbl   $0xffffffff,0xc(%rsp)
  jmp    L3
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
data_type: string
name: unpack_data
arguments: data_tag: D19
data_type: string
name: unpack_data
arguments: data_tag: D23
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string
name: unpack_data
arguments: data_tag: D47
data_type: string

tool: D25: %d

tool: D19: %d valor(es) par(es)


tool: D23: %d valor(es) impar(es)


tool: D14: %d valor(es) positivo(s)


tool: D47: %d valor(es) negativo(s)


assistant: ```c
int main() {
  int i, n, esum = 0, osum = 0, psum = 0, nsum = 0;
  for (i = 1; i <= 5; i++) {
    scanf("%d", &n);
    if (n >= 0 && n % 2 == 0 || n < 0 && n % 2 == -0) {
      esum++;
    }
    if (n >= 0 && n % 2 != 0 || n < 0 && n % 2 != -0) {
      osum++;
    }
    if (n > 0) {
      psum++;
    }
    if (n < 0) {
      nsum++;
    }
  }
  printf("%d valor(es) par(es)\n", esum);
  printf("%d valor(es) impar(es)\n", osum);
  printf("%d valor(es) positivo(s)\n", psum);
  printf("%d valor(es) negativo(s)\n", nsum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hashit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L16
L0:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x6,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x10,%rax
  add    %rdx,%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long int hashit(char *str) {
  unsigned long int hash = 0;
  int c;
  while ((c = *str++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return (hash);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hashit>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L12
  mov    $0x0,%eax
L17:
  imul   $0x1003f,%rax,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L17
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long int hashit(char *str) {
  unsigned long int hash = 0;
  int c;
  while ((c = *str++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return (hash);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hashit>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  xor    %eax,%eax
  test   %dl,%dl
  je     L2
  nopw   0x0(%rax,%rax,1)
L16:
  imul   $0x1003f,%rax,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L16
  ret
L2:
  ret
```

assistant: ```c
unsigned long int hashit(char *str) {
  unsigned long int hash = 0;
  int c;
  while ((c = *str++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return (hash);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hashit>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  xor    %eax,%eax
  test   %dl,%dl
  je     L11
  nopw   0x0(%rax,%rax,1)
L4:
  imul   $0x1003f,%rax,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L4
  ret
L11:
  ret
```

assistant: ```c
unsigned long int hashit(char *str) {
  unsigned long int hash = 0;
  int c;
  while ((c = *str++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return (hash);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<search>:
  endbr64
  mov    %edx,%r9d
  sub    $0x1,%esi
  js     L92
  mov    $0x0,%ecx
  jmp    L25
L129:
  movslq %esi,%r10
  cmp    (%rdi,%r10,4),%edx
  je     L140
L145:
  cmp    %r9d,%edx
  jle    L79
  cmp    %r9d,%r8d
  jle    L18
L79:
  lea    0x1(%rax),%ecx
L130:
  cmp    %esi,%ecx
  jg     L109
L25:
  mov    %esi,%edx
  sub    %ecx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %r9d,%edx
  je     L117
  movslq %ecx,%r8
  mov    (%rdi,%r8,4),%r8d
  cmp    %r8d,%edx
  je     L129
  jge    L145
  cmp    %r9d,%edx
  jge    L103
  movslq %esi,%rdx
  cmp    %r9d,(%rdi,%rdx,4)
  jl     L103
  lea    0x1(%rax),%ecx
  jmp    L130
L140:
  add    $0x1,%ecx
  sub    $0x1,%esi
  jmp    L130
L18:
  lea    -0x1(%rax),%esi
  jmp    L130
L103:
  lea    -0x1(%rax),%esi
  jmp    L130
L109:
  mov    $0x0,%eax
  ret
L92:
  mov    $0x0,%eax
  ret
L117:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool search(int *nums, int numsSize, int target) {
  int lo = 0;
  int hi = numsSize - 1;
  while (lo <= hi) {
    int mid = lo + (hi - lo) / 2;
    if (nums[mid] == target) {
      return true;
    }
    if (nums[lo] == nums[mid] && nums[mid] == nums[hi]) {
      lo++;
      hi--;
    } else if (nums[lo] <= nums[mid]) {
      if (nums[lo] <= target && target < nums[mid]) {
        hi = mid - 1;
      } else {
        lo = mid + 1;
      }
    } else {
      if (nums[mid] < target && target <= nums[hi]) {
        lo = mid + 1;
      } else {
        hi = mid - 1;
      }
    }
  }
  return false;
}
```
user: What is the c source code of the assembly code below?

```asm
<search>:
  endbr64
  mov    %rdi,%r8
  sub    $0x1,%esi
  js     L75
  xor    %ecx,%ecx
  jmp    L92
L43:
  jge    L55
  cmp    %edx,%edi
  jge    L80
  movslq %esi,%rdi
  cmp    %edx,(%r8,%rdi,4)
  jl     L80
L11:
  lea    0x1(%rax),%ecx
L61:
  cmp    %ecx,%esi
  jl     L75
L92:
  mov    %esi,%eax
  sub    %ecx,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  cmp    %edx,%edi
  je     L13
  movslq %ecx,%r9
  mov    (%r8,%r9,4),%r9d
  cmp    %r9d,%edi
  jne    L43
  movslq %esi,%r10
  cmp    (%r8,%r10,4),%edi
  je     L21
L55:
  cmp    %edx,%r9d
  jg     L11
  cmp    %edx,%edi
  jle    L11
L80:
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L92
L75:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L21:
  add    $0x1,%ecx
  sub    $0x1,%esi
  jmp    L61
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool search(int *nums, int numsSize, int target) {
  int lo = 0;
  int hi = numsSize - 1;
  while (lo <= hi) {
    int mid = lo + (hi - lo) / 2;
    if (nums[mid] == target) {
      return true;
    }
    if (nums[lo] == nums[mid] && nums[mid] == nums[hi]) {
      lo++;
      hi--;
    } else if (nums[lo] <= nums[mid]) {
      if (nums[lo] <= target && target < nums[mid]) {
        hi = mid - 1;
      } else {
        lo = mid + 1;
      }
    } else {
      if (nums[mid] < target && target <= nums[hi]) {
        lo = mid + 1;
      } else {
        hi = mid - 1;
      }
    }
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<search>:
  endbr64
  mov    %rdi,%r8
  sub    $0x1,%esi
  js     L20
  xor    %ecx,%ecx
  jmp    L107
L71:
  jge    L27
  cmp    %edx,%edi
  jge    L13
  movslq %esi,%rdi
  cmp    %edx,(%r8,%rdi,4)
  jl     L13
L102:
  lea    0x1(%rax),%ecx
L12:
  cmp    %ecx,%esi
  jl     L20
L107:
  mov    %esi,%eax
  sub    %ecx,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  cmp    %edx,%edi
  je     L90
  movslq %ecx,%r9
  mov    (%r8,%r9,4),%r9d
  cmp    %r9d,%edi
  jne    L71
  movslq %esi,%r10
  cmp    (%r8,%r10,4),%edi
  je     L98
L27:
  cmp    %edx,%r9d
  jg     L102
  cmp    %edx,%edi
  jle    L102
L13:
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L107
L20:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L98:
  add    $0x1,%ecx
  sub    $0x1,%esi
  jmp    L12
L90:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool search(int *nums, int numsSize, int target) {
  int lo = 0;
  int hi = numsSize - 1;
  while (lo <= hi) {
    int mid = lo + (hi - lo) / 2;
    if (nums[mid] == target) {
      return true;
    }
    if (nums[lo] == nums[mid] && nums[mid] == nums[hi]) {
      lo++;
      hi--;
    } else if (nums[lo] <= nums[mid]) {
      if (nums[lo] <= target && target < nums[mid]) {
        hi = mid - 1;
      } else {
        lo = mid + 1;
      }
    } else {
      if (nums[mid] < target && target <= nums[hi]) {
        lo = mid + 1;
      } else {
        hi = mid - 1;
      }
    }
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ASCIIZ128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %ecx,%eax
  mov    %dl,-0x10(%rbp)
  mov    %al,-0x14(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L1
  movzbl -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <A2C128_A@plt>
  jmp    L30
L1:
  cmpl   $0x2,-0xc(%rbp)
  jne    L2
  movzbl -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <A2C128_B@plt>
  jmp    L30
L2:
  movzbl -0x14(%rbp),%edx
  movzbl -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <A2C128_C@plt>
L30:
  nop
  leave
  ret
```

assistant: ```c
void ASCIIZ128(unsigned char **ppOutPos, int CharacterSet, unsigned char c1, unsigned char c2) {
  if (CharacterSet == 1)
    A2C128_A(ppOutPos, c1);
  else if (CharacterSet == 2)
    A2C128_B(ppOutPos, c1);
  else
    A2C128_C(ppOutPos, c1, c2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ASCIIZ128>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L39
  cmp    $0x2,%esi
  je     L16
  movzbl %cl,%ecx
  movzbl %dl,%esi
  mov    %ecx,%edx
  call   <A2C128_C@plt>
L30:
  add    $0x8,%rsp
  ret
L39:
  movzbl %dl,%esi
  call   <A2C128_A@plt>
  jmp    L30
L16:
  movzbl %dl,%esi
  call   <A2C128_B@plt>
  jmp    L30
```

assistant: ```c
void ASCIIZ128(unsigned char **ppOutPos, int CharacterSet, unsigned char c1, unsigned char c2) {
  if (CharacterSet == 1)
    A2C128_A(ppOutPos, c1);
  else if (CharacterSet == 2)
    A2C128_B(ppOutPos, c1);
  else
    A2C128_C(ppOutPos, c1, c2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ASCIIZ128>:
  endbr64
  movzbl %dl,%r8d
  cmp    $0x1,%esi
  je     L7
  cmp    $0x2,%esi
  je     L2
  movzbl %cl,%edx
  mov    %r8d,%esi
  jmp    1070 <A2C128_C@plt>
  nopl   (%rax)
L2:
  mov    %r8d,%esi
  jmp    1080 <A2C128_B@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r8d,%esi
  jmp    1090 <A2C128_A@plt>
```

assistant: ```c
void ASCIIZ128(unsigned char **ppOutPos, int CharacterSet, unsigned char c1, unsigned char c2) {
  if (CharacterSet == 1)
    A2C128_A(ppOutPos, c1);
  else if (CharacterSet == 2)
    A2C128_B(ppOutPos, c1);
  else
    A2C128_C(ppOutPos, c1, c2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ASCIIZ128>:
  endbr64
  movzbl %dl,%r8d
  cmp    $0x1,%esi
  je     L3
  cmp    $0x2,%esi
  je     L5
  movzbl %cl,%edx
  mov    %r8d,%esi
  jmp    1070 <A2C128_C@plt>
  nopl   (%rax)
L5:
  mov    %r8d,%esi
  jmp    1080 <A2C128_B@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r8d,%esi
  jmp    1090 <A2C128_A@plt>
```

assistant: ```c
void ASCIIZ128(unsigned char **ppOutPos, int CharacterSet, unsigned char c1, unsigned char c2) {
  if (CharacterSet == 1)
    A2C128_A(ppOutPos, c1);
  else if (CharacterSet == 2)
    A2C128_B(ppOutPos, c1);
  else
    A2C128_C(ppOutPos, c1, c2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pcg_setseq_16_rxs_m_xs_16_boundedrand_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  neg    %eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x8(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pcg_setseq_16_rxs_m_xs_16_random_r@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L1
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
uint16_t pcg_setseq_16_rxs_m_xs_16_boundedrand_r(struct pcg_state_setseq_16 *rng, uint16_t bound) {
  uint16_t threshold = ((uint16_t)(-bound)) % bound;
  for (;;) {
    uint16_t r = pcg_setseq_16_rxs_m_xs_16_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pcg_setseq_16_rxs_m_xs_16_boundedrand_r>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %esi,%eax
  neg    %eax
  cltd
  idiv   %esi
  mov    %edx,%ebp
L8:
  mov    %rbx,%rdi
  call   <pcg_setseq_16_rxs_m_xs_16_random_r@plt>
  cmp    %eax,%ebp
  jg     L8
  cltd
  idiv   %r12d
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint16_t pcg_setseq_16_rxs_m_xs_16_boundedrand_r(struct pcg_state_setseq_16 *rng, uint16_t bound) {
  uint16_t threshold = ((uint16_t)(-bound)) % bound;
  for (;;) {
    uint16_t r = pcg_setseq_16_rxs_m_xs_16_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pcg_setseq_16_rxs_m_xs_16_boundedrand_r>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    %esi,%r12d
  neg    %eax
  push   %rbp
  cltd
  push   %rbx
  mov    %rdi,%rbx
  idiv   %esi
  mov    %edx,%ebp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rdi
  call   <pcg_setseq_16_rxs_m_xs_16_random_r@plt>
  cmp    %eax,%ebp
  jg     L6
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  pop    %r12
  mov    %edx,%eax
  ret
```

assistant: ```c
uint16_t pcg_setseq_16_rxs_m_xs_16_boundedrand_r(struct pcg_state_setseq_16 *rng, uint16_t bound) {
  uint16_t threshold = ((uint16_t)(-bound)) % bound;
  for (;;) {
    uint16_t r = pcg_setseq_16_rxs_m_xs_16_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pcg_setseq_16_rxs_m_xs_16_boundedrand_r>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    %esi,%r12d
  neg    %eax
  push   %rbp
  cltd
  push   %rbx
  mov    %rdi,%rbx
  idiv   %esi
  mov    %edx,%ebp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdi
  call   <pcg_setseq_16_rxs_m_xs_16_random_r@plt>
  cmp    %eax,%ebp
  jg     L2
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  pop    %r12
  mov    %edx,%eax
  ret
```

assistant: ```c
uint16_t pcg_setseq_16_rxs_m_xs_16_boundedrand_r(struct pcg_state_setseq_16 *rng, uint16_t bound) {
  uint16_t threshold = ((uint16_t)(-bound)) % bound;
  for (;;) {
    uint16_t r = pcg_setseq_16_rxs_m_xs_16_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ui_cancellation_resume>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  mov    $0x0,%eax
  call   <ui_cancellation_enabled@plt>
  test   %rax,%rax
  je     L23
  mov    $0x1,%eax
  jmp    L5
L23:
  mov    $0x0,%eax
L5:
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <noraw@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void ui_cancellation_resume(int state) {
  if (state) {
    assert(ui_cancellation_enabled() && "Invalid cancellation resume");
    noraw();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ui_cancellation_resume>:
  endbr64
  test   %edi,%edi
  jne    L1
  ret
L1:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ui_cancellation_enabled@plt>
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <noraw@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ui_cancellation_resume(int state) {
  if (state) {
    assert(ui_cancellation_enabled() && "Invalid cancellation resume");
    noraw();
  }
}
```