user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsp),%xmm0
  lea    D63(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D96(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm5,%xmm5
  cvtss2sd 0x10(%rsp),%xmm5
  movapd %xmm5,%xmm0
  mulsd  D93(%rip),%xmm0
  divsd  D38(%rip),%xmm0
  pxor   %xmm7,%xmm7
  cvtsd2ss %xmm0,%xmm7
  movss  %xmm7,0xc(%rsp)
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L26
  lea    0x2(%rax,%rax,1),%ecx
  movaps %xmm7,%xmm0
  movaps %xmm7,%xmm3
  mov    $0x2,%eax
  pxor   %xmm1,%xmm1
  movss  D72(%rip),%xmm2
  movss  D118(%rip),%xmm4
L6:
  addss  %xmm3,%xmm1
  xorps  %xmm4,%xmm0
  movss  0xc(%rsp),%xmm6
  mulss  %xmm6,%xmm0
  mulss  %xmm6,%xmm0
  pxor   %xmm3,%xmm3
  cvtsi2ss %eax,%xmm3
  mulss  %xmm3,%xmm2
  lea    0x1(%rax),%edx
  pxor   %xmm3,%xmm3
  cvtsi2ss %edx,%xmm3
  mulss  %xmm3,%xmm2
  movaps %xmm0,%xmm3
  divss  %xmm2,%xmm3
  add    $0x2,%eax
  cmp    %ecx,%eax
  jne    L6
L17:
  cvtss2sd %xmm1,%xmm1
  movapd %xmm5,%xmm0
  lea    D24(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsp),%xmm0
  lea    D106(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L26:
  pxor   %xmm1,%xmm1
  jmp    L17
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D34
type: string
name: retrieve_data
arguments: tag: D63
type: string
name: retrieve_data
arguments: tag: D40
type: string
name: retrieve_data
arguments: tag: D96
type: string
name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D93
type: f64
name: retrieve_data
arguments: tag: D38
type: f32[2]
name: retrieve_data
arguments: tag: D72
type: f32
name: retrieve_data
arguments: tag: D118
type: byte[4]
name: retrieve_data
arguments: tag: D24
type: string
name: retrieve_data
arguments: tag: D106
type: string

tool: D14: Enter the Angle ....

tool: D34: %f

tool: D63: Angle = %g


tool: D40: Enter the Number of terms...

tool: D96: %d

tool: D29: No of terms = %d


tool: D93: 3.1416

tool: {"D38": [0.0,3.6015625]}

tool: D72: 1

tool: {"D118": [0x00,0x00,0x00,0x80]}

tool: D24:  Calculated value is :sin(%g) = %g


tool: D106: Built In function value is :sin(%g) = %g


assistant: ```c
int main(void) {
  float fAngD, fAngR;
  float fTerm, fNum, fDen, fVal;
  int i, iNum;
  printf("Enter the Angle ....\n");
  scanf("%f", &fAngD);
  printf("Angle = %g\n", fAngD);
  printf("Enter the Number of terms...\n");
  scanf("%d", &iNum);
  printf("No of terms = %d\n", iNum);
  fAngR = (fAngD * 3.1416) / 180;
  fNum = fAngR;
  fDen = 1.0;
  fVal = 0.0;
  fTerm = fNum / fDen;
  for (i = 1; i <= iNum; i++) {
    fVal = fVal + fTerm;
    fNum = -fNum * fAngR * fAngR;
    fDen = fDen * (2 * i) * (2 * i + 1);
    fTerm = fNum / fDen;
  }
  printf(" Calculated value is :sin(%g) = %g\n", fAngD, fVal);
  printf("Built In function value is :sin(%g) = %g\n", fAngD, sin(fAngR));
  return 0;
}
```