ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L97
  mov    $0x0,%ebp
  lea    D24(%rip),%r12
L18:
  mov    %ebp,%ebx
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %sil,0x10(%rsp,%rbp,1)
  movsbl %sil,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  cltd
  sub    %edx,%esi
  mov    %esi,0xc(%rsp)
  lea    0x1(%rbp),%edx
  add    $0x1,%rbp
  cmp    $0x9,%eax
  jg     L18
  test   %edx,%edx
  jle    L97
  mov    $0x0,%ebp
  lea    D33(%rip),%r12
  jmp    L119
L19:
  lea    0x1(%rax),%ecx
  add    $0x1,%rdx
  cmp    %eax,%ebx
  jle    L80
  mov    %ecx,%eax
L37:
  cmp    %ebp,%eax
  je     L19
  movzbl (%rdx),%edi
  cmp    %dil,0x10(%rsp,%rbp,1)
  jne    L19
  add    $0x1,%esi
  movb   $0x63,(%rdx)
  jmp    L19
L80:
  movsbl 0x10(%rsp,%rbp,1),%eax
  mov    %esi,%edx
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L16:
  add    $0x1,%rbp
  lea    -0x1(%rbp),%eax
  cmp    %ebx,%eax
  jge    L97
L119:
  cmpb   $0x63,0x10(%rsp,%rbp,1)
  je     L16
  lea    0x10(%rsp),%rdx
  mov    $0x0,%eax
  mov    $0x1,%esi
  jmp    L37
L97:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D39
type_guessed: string
name: disassemble_data
arguments: data_tag: D24
type_guessed: string
name: disassemble_data
arguments: data_tag: D33
type_guessed: string

tool: D29: Input the number :

tool: D39: %d

tool: D24: %d


tool: D33: %d - %d


assistant: ```c
int main() {
  char arr[20];
  int modnum;
  int number;
  int i = 0, counter = 1, j, k;
  printf("Input the number :");
  scanf("%d", &number);
  while (number > 0) {
    modnum = number % 10;
    arr[i] = modnum;
    printf("%d\n", arr[i]);
    number /= 10;
    i++;
  }
  for (j = 0; j < i; j++) {
    if (arr[j] == 'c')
      continue;
    for (k = 0; k < i; k++) {
      if (j != k) {
        if (arr[j] == arr[k]) {
          counter++;
          arr[k] = 'c';
        }
      }
    }
    printf("%d - %d\n", arr[j], counter);
    counter = 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D36(%rip),%rdi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L24
  nopl   0x0(%rax,%rax,1)
L12:
  movslq %eax,%rsi
  cltd
  mov    %rbp,%rdi
  mov    %r13d,%r14d
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %al,(%r12,%r13,1)
  mov    %eax,%esi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  movslq 0xc(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x9,%edx
  jg     L12
  lea    0x1(%r14),%ebx
  xor    %ebp,%ebp
  lea    D12(%rip),%r13
  mov    %rbx,%r14
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl (%r12,%rbp,1),%esi
  cmp    $0x63,%sil
  je     L78
  mov    %r12,%rdx
  xor    %eax,%eax
  mov    $0x1,%r8d
  xchg   %ax,%ax
L26:
  cmp    %ebp,%eax
  je     L6
  cmp    %sil,(%rdx)
  jne    L6
  movb   $0x63,(%rdx)
  movsbl (%r12,%rbp,1),%esi
  add    $0x1,%r8d
L6:
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %r14d,%eax
  jne    L26
  mov    %r8d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L78:
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L0
L24:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D36
type_infered: string
name: extract_symbolic_data
arguments: label: D23
type_infered: string
name: extract_symbolic_data
arguments: label: D19
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D36: Input the number :

tool: D23: %d


tool: D19: %d

tool: D12: %d - %d


assistant: ```c
int main() {
  char arr[20];
  int modnum;
  int number;
  int i = 0, counter = 1, j, k;
  printf("Input the number :");
  scanf("%d", &number);
  while (number > 0) {
    modnum = number % 10;
    arr[i] = modnum;
    printf("%d\n", arr[i]);
    number /= 10;
    i++;
  }
  for (j = 0; j < i; j++) {
    if (arr[j] == 'c')
      continue;
    for (k = 0; k < i; k++) {
      if (j != k) {
        if (arr[j] == arr[k]) {
          counter++;
          arr[k] = 'c';
        }
      }
    }
    printf("%d - %d\n", arr[j], counter);
    counter = 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%rdi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L51
  nopl   0x0(%rax,%rax,1)
L22:
  movslq %eax,%rsi
  cltd
  mov    %rbp,%rdi
  mov    %r13d,%r14d
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %al,(%r12,%r13,1)
  mov    %eax,%esi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  movslq 0xc(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x9,%edx
  jg     L22
  lea    0x1(%r14),%ebx
  xor    %ebp,%ebp
  lea    D18(%rip),%r13
  mov    %rbx,%r14
  nopw   0x0(%rax,%rax,1)
L54:
  movsbl (%r12,%rbp,1),%esi
  cmp    $0x63,%sil
  je     L63
  mov    %r12,%rdx
  xor    %eax,%eax
  mov    $0x1,%r8d
  xchg   %ax,%ax
L15:
  cmp    %ebp,%eax
  je     L75
  cmp    %sil,(%rdx)
  jne    L75
  movb   $0x63,(%rdx)
  movsbl (%r12,%rbp,1),%esi
  add    $0x1,%r8d
L75:
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %eax,%r14d
  jne    L15
  mov    %r8d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L63:
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L54
L51:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string

tool: D5: Input the number :

tool: D9: %d


tool: D3: %d

tool: D18: %d - %d


assistant: ```c
int main() {
  char arr[20];
  int modnum;
  int number;
  int i = 0, counter = 1, j, k;
  printf("Input the number :");
  scanf("%d", &number);
  while (number > 0) {
    modnum = number % 10;
    arr[i] = modnum;
    printf("%d\n", arr[i]);
    number /= 10;
    i++;
  }
  for (j = 0; j < i; j++) {
    if (arr[j] == 'c')
      continue;
    for (k = 0; k < i; k++) {
      if (j != k) {
        if (arr[j] == arr[k]) {
          counter++;
          arr[k] = 'c';
        }
      }
    }
    printf("%d - %d\n", arr[j], counter);
    counter = 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L6:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *xfree(void *ptr) {
  if (ptr)
    free(ptr);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xfree>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *xfree(void *ptr) {
  if (ptr)
    free(ptr);
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xfree>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *xfree(void *ptr) {
  if (ptr)
    free(ptr);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xfree>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *xfree(void *ptr) {
  if (ptr)
    free(ptr);
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  jmp    L12
L7:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L10
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L10:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L12:
  cmpl   $0x0,-0x18(%rbp)
  jne    L7
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
data_type: string

tool: D1: EOF or read error on tty


assistant: ```c
void read_bytes(int fd, unsigned char *buf, int maxlen) {
  while (maxlen) {
    int bytes = read(fd, buf, maxlen);
    if (bytes <= 0)
      die("EOF or read error on tty\n");
    maxlen -= bytes;
    buf += bytes;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_bytes>:
  endbr64
  test   %edx,%edx
  je     L39
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%ebp
  lea    D1(%rip),%r14
  jmp    L0
L25:
  movslq %ebx,%rax
  add    %rax,%r12
  sub    %ebx,%ebp
  je     L47
L0:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L25
  mov    %r14,%rdi
  call   <die@plt>
  jmp    L25
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: EOF or read error on tty


assistant: ```c
void read_bytes(int fd, unsigned char *buf, int maxlen) {
  while (maxlen) {
    int bytes = read(fd, buf, maxlen);
    if (bytes <= 0)
      die("EOF or read error on tty\n");
    maxlen -= bytes;
    buf += bytes;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_bytes>:
  endbr64
  test   %edx,%edx
  je     L31
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  jmp    L36
  nopl   0x0(%rax)
L13:
  movslq %ebx,%rax
  add    %rax,%r12
  sub    %ebx,%ebp
  je     L24
L36:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L13
  mov    %r14,%rdi
  call   <die@plt>
  movslq %ebx,%rax
  add    %rax,%r12
  sub    %ebx,%ebp
  jne    L36
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: EOF or read error on tty


assistant: ```c
void read_bytes(int fd, unsigned char *buf, int maxlen) {
  while (maxlen) {
    int bytes = read(fd, buf, maxlen);
    if (bytes <= 0)
      die("EOF or read error on tty\n");
    maxlen -= bytes;
    buf += bytes;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_bytes>:
  endbr64
  test   %edx,%edx
  je     L36
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  jmp    L39
  nopl   0x0(%rax)
L13:
  movslq %ebx,%rax
  add    %rax,%r12
  sub    %ebx,%ebp
  je     L22
L39:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L13
  mov    %r14,%rdi
  call   <die@plt>
  movslq %ebx,%rax
  add    %rax,%r12
  sub    %ebx,%ebp
  jne    L39
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: EOF or read error on tty


assistant: ```c
void read_bytes(int fd, unsigned char *buf, int maxlen) {
  while (maxlen) {
    int bytes = read(fd, buf, maxlen);
    if (bytes <= 0)
      die("EOF or read error on tty\n");
    maxlen -= bytes;
    buf += bytes;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L50
L66:
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  mov    $0x69,%edx
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <display_standard_menu@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L56
  mov    $0x0,%eax
  call   <task1_main@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L50
L56:
  cmpl   $0x2,-0x4(%rbp)
  jne    L41
  mov    $0x0,%eax
  call   <task2_main@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L50
L41:
  cmpl   $0x3,-0x4(%rbp)
  jne    L50
  movl   $0xffffffff,-0x8(%rbp)
L50:
  cmpl   $0x0,-0x8(%rbp)
  jns    L66
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D15: 1. Task 1 - InternetLite
2. Task 2 - Broadway Revenue
3. Exit Lab 7

tool: D6: Lab 7: Main Menu

assistant: ```c
int main(void) {
  int option = 0, lab_state = 0;
  while (lab_state >= 0) {
    option = display_standard_menu("Lab 7: Main Menu", "1. Task 1 - InternetLite\n2. Task 2 - Broadway Revenue\n3. Exit Lab 7", 'i', 3, 1);
    if (option == 1) {
      lab_state = task1_main();
    } else if (option == 2) {
      lab_state = task2_main();
    } else if (option == 3) {
      lab_state = -1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D12(%rip),%r12
  lea    D13(%rip),%rbp
  jmp    L58
L53:
  mov    $0x0,%eax
  call   <task1_main@plt>
  mov    %eax,%ebx
L40:
  test   %ebx,%ebx
  js     L1
L58:
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  mov    $0x69,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <display_standard_menu@plt>
  cmp    $0x1,%eax
  je     L53
  cmp    $0x2,%eax
  je     L21
  cmp    $0x3,%eax
  jne    L40
L1:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    $0x0,%eax
  call   <task2_main@plt>
  mov    %eax,%ebx
  jmp    L40
```

tool_calls: name: disassemble_data
arguments: data_label: D12
data_type: string
name: disassemble_data
arguments: data_label: D13
data_type: string

tool: D12: 1. Task 1 - InternetLite
2. Task 2 - Broadway Revenue
3. Exit Lab 7

tool: D13: Lab 7: Main Menu

assistant: ```c
int main(void) {
  int option = 0, lab_state = 0;
  while (lab_state >= 0) {
    option = display_standard_menu("Lab 7: Main Menu", "1. Task 1 - InternetLite\n2. Task 2 - Broadway Revenue\n3. Exit Lab 7", 'i', 3, 1);
    if (option == 1) {
      lab_state = task1_main();
    } else if (option == 2) {
      lab_state = task2_main();
    } else if (option == 3) {
      lab_state = -1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x3,%ecx
  mov    $0x69,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x1,%r8d
  call   <display_standard_menu@plt>
  cmp    $0x1,%eax
  je     L45
  cmp    $0x2,%eax
  je     L44
  cmp    $0x3,%eax
  jne    L48
L39:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  call   <task1_main@plt>
L19:
  test   %eax,%eax
  jns    L48
  jmp    L39
  nopl   (%rax)
L44:
  xor    %eax,%eax
  call   <task2_main@plt>
  jmp    L19
```

tool_calls: name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D5
type: string

tool: D8: 1. Task 1 - InternetLite
2. Task 2 - Broadway Revenue
3. Exit Lab 7

tool: D5: Lab 7: Main Menu

assistant: ```c
int main(void) {
  int option = 0, lab_state = 0;
  while (lab_state >= 0) {
    option = display_standard_menu("Lab 7: Main Menu", "1. Task 1 - InternetLite\n2. Task 2 - Broadway Revenue\n3. Exit Lab 7", 'i', 3, 1);
    if (option == 1) {
      lab_state = task1_main();
    } else if (option == 2) {
      lab_state = task2_main();
    } else if (option == 3) {
      lab_state = -1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x3,%ecx
  mov    $0x69,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x1,%r8d
  call   <display_standard_menu@plt>
  cmp    $0x1,%eax
  je     L56
  cmp    $0x2,%eax
  je     L44
  cmp    $0x3,%eax
  jne    L1
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  xor    %eax,%eax
  call   <task1_main@plt>
L36:
  test   %eax,%eax
  jns    L1
  jmp    L4
  nopl   (%rax)
L44:
  xor    %eax,%eax
  call   <task2_main@plt>
  jmp    L36
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D13: 1. Task 1 - InternetLite
2. Task 2 - Broadway Revenue
3. Exit Lab 7

tool: D2: Lab 7: Main Menu

assistant: ```c
int main(void) {
  int option = 0, lab_state = 0;
  while (lab_state >= 0) {
    option = display_standard_menu("Lab 7: Main Menu", "1. Task 1 - InternetLite\n2. Task 2 - Broadway Revenue\n3. Exit Lab 7", 'i', 3, 1);
    if (option == 1) {
      lab_state = task1_main();
    } else if (option == 2) {
      lab_state = task2_main();
    } else if (option == 3) {
      lab_state = -1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<removeDigitFromStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x28(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L28:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L5
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L18
  cmpl   $0x0,-0x4(%rbp)
  je     L10
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  jmp    L42
L5:
  nop
  jmp    L42
L10:
  nop
L42:
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  cmpl   $0x0,-0x4(%rbp)
  jne    L35
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void removeDigitFromStr(char str[], char digit, char result[]) {
  int indStr, indResult;
  for (indStr = 0, indResult = 0; str[indStr] != '\0'; indStr++) {
    if (str[indStr] == digit)
      continue;
    if (str[indStr] == '0' && indResult == 0) {
      continue;
    }
    result[indResult] = str[indStr];
    indResult++;
  }
  if (indResult == 0) {
    result[indResult] = '0';
    indResult++;
  }
  result[indResult] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<removeDigitFromStr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  add    $0x1,%rdi
  mov    $0x0,%ecx
  jmp    L15
L13:
  movslq %ecx,%r8
  mov    %al,(%rdx,%r8,1)
  add    $0x1,%ecx
L57:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L86
L15:
  cmp    %al,%sil
  je     L57
  test   %ecx,%ecx
  jne    L13
  cmp    $0x30,%al
  jne    L13
  mov    $0x0,%ecx
  jmp    L57
L86:
  test   %ecx,%ecx
  je     L2
L84:
  movslq %ecx,%rcx
  movb   $0x0,(%rdx,%rcx,1)
  ret
L2:
  movb   $0x30,(%rdx)
  mov    $0x1,%ecx
  jmp    L84
```

assistant: ```c
void removeDigitFromStr(char str[], char digit, char result[]) {
  int indStr, indResult;
  for (indStr = 0, indResult = 0; str[indStr] != '\0'; indStr++) {
    if (str[indStr] == digit)
      continue;
    if (str[indStr] == '0' && indResult == 0) {
      continue;
    }
    result[indResult] = str[indStr];
    indResult++;
  }
  if (indResult == 0) {
    result[indResult] = '0';
    indResult++;
  }
  result[indResult] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<removeDigitFromStr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L34
  add    $0x1,%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L29:
  cmp    %al,%sil
  je     L53
  test   %ecx,%ecx
  jne    L43
  cmp    $0x30,%al
  je     L46
L43:
  movslq %ecx,%r8
  add    $0x1,%ecx
  mov    %al,(%rdx,%r8,1)
L53:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L29
  test   %ecx,%ecx
  je     L34
  movslq %ecx,%rcx
  movb   $0x0,(%rdx,%rcx,1)
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  xor    %ecx,%ecx
  jmp    L53
  nopl   0x0(%rax)
L34:
  mov    $0x1,%ecx
  movb   $0x30,(%rdx)
  movb   $0x0,(%rdx,%rcx,1)
  ret
```

assistant: ```c
void removeDigitFromStr(char str[], char digit, char result[]) {
  int indStr, indResult;
  for (indStr = 0, indResult = 0; str[indStr] != '\0'; indStr++) {
    if (str[indStr] == digit)
      continue;
    if (str[indStr] == '0' && indResult == 0) {
      continue;
    }
    result[indResult] = str[indStr];
    indResult++;
  }
  if (indResult == 0) {
    result[indResult] = '0';
    indResult++;
  }
  result[indResult] = '\0';
}
```