ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<mult_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x24(%rsp)
  mov    %r8,-0x20(%rsp)
  mov    %r9,-0x18(%rsp)
  test   %edi,%edi
  jle    L10
  mov    %edx,%r12d
  test   %edx,%edx
  jle    L10
  mov    %esi,%r10d
  lea    0x8(%rcx),%rax
  movslq %edx,%rbx
  mov    %rcx,%r13
  mov    %rax,-0x8(%rsp)
  lea    -0x1(%r10),%eax
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  mov    %rax,-0x10(%rsp)
  lea    0x0(,%rbx,8),%rsi
  xor    %ebp,%ebp
  pxor   %xmm2,%xmm2
  xchg   %ax,%ax
L11:
  mov    -0x8(%rsp),%rdi
  movslq %r15d,%rax
  mov    -0x20(%rsp),%r8
  lea    0x0(%r13,%rax,8),%r11
  add    -0x10(%rsp),%rax
  lea    (%rdi,%rax,8),%rcx
  mov    -0x18(%rsp),%rdi
  movslq %r14d,%rax
  lea    (%rdi,%rax,8),%r9
  xor    %edi,%edi
  nopl   0x0(%rax)
L15:
  mov    %r8,%rdx
  mov    %r11,%rax
  movapd %xmm2,%xmm1
  test   %r10d,%r10d
  jle    L38
  nop
L37:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L37
L38:
  movsd  %xmm1,(%r9,%rdi,8)
  add    $0x1,%rdi
  add    $0x8,%r8
  cmp    %rdi,%rbx
  jne    L15
  add    $0x1,%ebp
  add    %r12d,%r14d
  add    %r10d,%r15d
  cmp    %ebp,-0x24(%rsp)
  jne    L11
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mult_matrix(int n, int m, int o, double *a, double *b, double *r) {
  int i, j, k;
  for (i = 0; i < n; i++)
    for (j = 0; j < o; j++) {
      double sum = 0;
      for (k = 0; k < m; k++)
        sum += (a[i * m + k] * b[k * o + j]);
      r[i * o + j] = sum;
    }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<data_numcards>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rdx
  mov    -0x44(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <data_gethand@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L24
L28:
  addl   $0x1,-0x34(%rbp)
L24:
  cmpl   $0x6,-0x34(%rbp)
  jg     L39
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  jns    L28
L39:
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
int data_numcards(int p) {
  int hand[7];
  data_gethand(p, hand);
  int numcards;
  for (numcards = 0; numcards < 7 && hand[numcards] > -1; numcards++)
    ;
  return numcards;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<data_numcards>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <data_gethand@plt>
  mov    %rbx,%rax
  mov    $0x0,%edx
L29:
  cmpl   $0x0,(%rax)
  js     L15
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    $0x7,%edx
  jne    L29
L15:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %edx,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int data_numcards(int p) {
  int hand[7];
  data_gethand(p, hand);
  int numcards;
  for (numcards = 0; numcards < 7 && hand[numcards] > -1; numcards++)
    ;
  return numcards;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<data_numcards>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <data_gethand@plt>
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    (%rbx,%rax,4),%edx
  mov    %eax,%r8d
  test   %edx,%edx
  js     L28
  add    $0x1,%rax
  cmp    $0x7,%rax
  jne    L23
  mov    $0x7,%r8d
L28:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int data_numcards(int p) {
  int hand[7];
  data_gethand(p, hand);
  int numcards;
  for (numcards = 0; numcards < 7 && hand[numcards] > -1; numcards++)
    ;
  return numcards;
}
```
user: Translate the below assembly code into C programming language:

```asm
<data_numcards>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <data_gethand@plt>
  mov    (%rsp),%r8d
  test   %r8d,%r8d
  js     L10
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L41
  mov    0x8(%rsp),%esi
  test   %esi,%esi
  js     L107
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  js     L108
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  js     L126
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  js     L27
  mov    0x18(%rsp),%eax
  not    %eax
  shr    $0x1f,%eax
  add    $0x6,%eax
L3:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L115
  add    $0x38,%rsp
  ret
L10:
  xor    %eax,%eax
  jmp    L3
L41:
  mov    $0x1,%eax
  jmp    L3
L107:
  mov    $0x2,%eax
  jmp    L3
L108:
  mov    $0x3,%eax
  jmp    L3
L126:
  mov    $0x4,%eax
  jmp    L3
L27:
  mov    $0x5,%eax
  jmp    L3
L115:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int data_numcards(int p) {
  int hand[7];
  data_gethand(p, hand);
  int numcards;
  for (numcards = 0; numcards < 7 && hand[numcards] > -1; numcards++)
    ;
  return numcards;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nameof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <name1@plt>
  mov    %eax,%edi
  call   <skin@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L40
  mov    -0x8(%rbp),%rax
  mov    $0x21,%esi
  mov    %rax,%rdi
  call   <charcount@plt>
  cmp    $0x1,%eax
  jg     L24
L40:
  mov    -0x8(%rbp),%rax
  jmp    L66
L24:
  mov    -0x8(%rbp),%rax
  mov    $0x21,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  subq   $0x1,-0x10(%rbp)
  jmp    L61
L77:
  subq   $0x1,-0x10(%rbp)
L61:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L8
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x21,%al
  jne    L77
L8:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x21,%al
  jne    L50
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  jmp    L66
L50:
  mov    -0x8(%rbp),%rax
L66:
  leave
  ret
```

assistant: ```c
char *nameof(struct message *mp, int reptype) {
  char *cp, *cp2;
  cp = skin(name1(mp, reptype));
  if (reptype != 0 || charcount(cp, '!') < 2)
    return (cp);
  cp2 = strrchr(cp, '!');
  cp2--;
  while (cp2 > cp && *cp2 != '!')
    cp2--;
  if (*cp2 == '!')
    return (cp2 + 1);
  return (cp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nameof>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  call   <name1@plt>
  mov    %eax,%edi
  call   <skin@plt>
  mov    %rax,%rbx
  test   %ebp,%ebp
  je     L45
L42:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L45:
  mov    $0x21,%esi
  mov    %rax,%rdi
  call   <charcount@plt>
  cmp    $0x1,%eax
  jle    L42
  mov    $0x21,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jae    L23
L27:
  cmpb   $0x21,(%rax)
  je     L11
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L27
  mov    %rbx,%rax
L23:
  cmpb   $0x21,(%rax)
  jne    L42
L11:
  lea    0x1(%rax),%rbx
  jmp    L42
```

assistant: ```c
char *nameof(struct message *mp, int reptype) {
  char *cp, *cp2;
  cp = skin(name1(mp, reptype));
  if (reptype != 0 || charcount(cp, '!') < 2)
    return (cp);
  cp2 = strrchr(cp, '!');
  cp2--;
  while (cp2 > cp && *cp2 != '!')
    cp2--;
  if (*cp2 == '!')
    return (cp2 + 1);
  return (cp);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<nameof>:
  endbr64
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <name1@plt>
  mov    %eax,%edi
  call   <skin@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  je     L23
L27:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x21,%esi
  mov    %rax,%rdi
  call   <charcount@plt>
  cmp    $0x1,%eax
  jle    L27
  mov    $0x21,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  sub    $0x1,%rax
  cmp    %rax,%r12
  jb     L59
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L62:
  sub    $0x1,%rax
  cmp    %rax,%r12
  je     L8
L59:
  cmpb   $0x21,(%rax)
  jne    L62
L68:
  lea    0x1(%rax),%r12
  jmp    L27
  nopl   0x0(%rax)
L8:
  cmpb   $0x21,(%rax)
  je     L68
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *nameof(struct message *mp, int reptype) {
  char *cp, *cp2;
  cp = skin(name1(mp, reptype));
  if (reptype != 0 || charcount(cp, '!') < 2)
    return (cp);
  cp2 = strrchr(cp, '!');
  cp2--;
  while (cp2 > cp && *cp2 != '!')
    cp2--;
  if (*cp2 == '!')
    return (cp2 + 1);
  return (cp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nameof>:
  endbr64
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <name1@plt>
  mov    %eax,%edi
  call   <skin@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  je     L36
L44:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    $0x21,%esi
  mov    %rax,%rdi
  call   <charcount@plt>
  cmp    $0x1,%eax
  jle    L44
  mov    $0x21,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  sub    $0x1,%rax
  cmp    %rax,%r12
  jb     L7
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L37:
  sub    $0x1,%rax
  cmp    %rax,%r12
  je     L65
L7:
  cmpb   $0x21,(%rax)
  jne    L37
L1:
  lea    0x1(%rax),%r12
  jmp    L44
  nopl   0x0(%rax)
L65:
  cmpb   $0x21,(%rax)
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *nameof(struct message *mp, int reptype) {
  char *cp, *cp2;
  cp = skin(name1(mp, reptype));
  if (reptype != 0 || charcount(cp, '!') < 2)
    return (cp);
  cp2 = strrchr(cp, '!');
  cp2--;
  while (cp2 > cp && *cp2 != '!')
    cp2--;
  if (*cp2 == '!')
    return (cp2 + 1);
  return (cp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  jmp    L1
L46:
  movl   $0x0,-0x34(%rbp)
  jmp    L38
L48:
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L38:
  cmpl   $0x2,-0x34(%rbp)
  jle    L48
  addl   $0x1,-0x38(%rbp)
L1:
  cmpl   $0x2,-0x38(%rbp)
  jle    L46
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <soma_diagonal_s@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D19
datatype: string
name: read_data
arguments: label: D8
datatype: string

tool: D11: Informe a pos [%d][%d]: 

tool: D19: %d

tool: D8: Soma da diagonal secundaria: %d


assistant: ```c
void main() {
  int i, j, mat[3][3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf("Informe a pos [%d][%d]: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  printf("Soma da diagonal secundaria: %d\n", soma_diagonal_s(mat));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  mov    $0x0,%r12d
  lea    D16(%rip),%r14
  lea    D26(%rip),%r13
  jmp    L37
L5:
  add    $0x1,%r12
  add    $0xc,%r15
  cmp    $0x3,%r12
  je     L44
L37:
  mov    %r12d,0xc(%rsp)
  mov    %r15,%rbp
  mov    $0x0,%ebx
L24:
  mov    %ebx,%edx
  mov    0xc(%rsp),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x3,%ebx
  jne    L24
  jmp    L5
L44:
  lea    0x10(%rsp),%rdi
  call   <soma_diagonal_s@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D26
data_type: string
name: read_data
arguments: data_label: D25
data_type: string

tool: D16: Informe a pos [%d][%d]: 

tool: D26: %d

tool: D25: Soma da diagonal secundaria: %d


assistant: ```c
void main() {
  int i, j, mat[3][3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf("Informe a pos [%d][%d]: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  printf("Soma da diagonal secundaria: %d\n", soma_diagonal_s(mat));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,(%rsp)
L13:
  mov    (%rsp),%rbx
  mov    %ebp,%r14d
  xor    %r15d,%r15d
L26:
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%r15d
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    $0x3,%r15d
  jne    L26
  add    $0x1,%rbp
  addq   $0xc,(%rsp)
  cmp    $0x3,%rbp
  jne    L13
  mov    0x8(%rsp),%rdi
  call   <soma_diagonal_s@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string
name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D11
data_type: string

tool: D9: Informe a pos [%d][%d]: 

tool: D14: %d

tool: D11: Soma da diagonal secundaria: %d


assistant: ```c
void main() {
  int i, j, mat[3][3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf("Informe a pos [%d][%d]: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  printf("Soma da diagonal secundaria: %d\n", soma_diagonal_s(mat));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,(%rsp)
L16:
  mov    (%rsp),%rbx
  mov    %ebp,%r14d
  xor    %r15d,%r15d
L9:
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%r15d
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    $0x3,%r15d
  jne    L9
  add    $0x1,%rbp
  addq   $0xc,(%rsp)
  cmp    $0x3,%rbp
  jne    L16
  mov    0x8(%rsp),%rdi
  call   <soma_diagonal_s@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D16
datatype: string

tool: D10: Informe a pos [%d][%d]: 

tool: D12: %d

tool: D16: Soma da diagonal secundaria: %d


assistant: ```c
void main() {
  int i, j, mat[3][3];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf("Informe a pos [%d][%d]: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  printf("Soma da diagonal secundaria: %d\n", soma_diagonal_s(mat));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<days_pmonth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L25
  cmpl   $0x76b,-0x18(%rbp)
  jg     L16
  addl   $0x76c,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L25
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L30
  addl   $0x1,-0x4(%rbp)
  jmp    L25
L30:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L25
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string

tool: D7: 

assistant: ```c
int days_pmonth(int month, int year) {
  static const int mtab[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int ndays;
  ndays = mtab[month];
  if (month == 1) {
    if (year < 1900)
      year += 1900;
    if (year % 4 == 0) {
      if (year % 100 != 0)
        ndays++;
      else if (year % 400 == 0)
        ndays++;
    }
  }
  return (ndays);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<days_pmonth>:
  endbr64
  mov    %esi,%eax
  cmp    $0x1,%edi
  je     L6
  movslq %edi,%rdi
  lea    D0(%rip),%rax
  mov    (%rax,%rdi,4),%edx
L29:
  mov    %edx,%eax
  ret
L6:
  lea    0x76c(%rsi),%edx
  cmp    $0x76c,%esi
  cmovl  %edx,%eax
  mov    $0x1c,%edx
  test   $0x3,%al
  jne    L29
  movslq %eax,%rcx
  imul   $0x51eb851f,%rcx,%rcx
  sar    $0x25,%rcx
  cltd
  sub    %edx,%ecx
  imul   $0x64,%ecx,%ecx
  mov    $0x1d,%edx
  cmp    %ecx,%eax
  jne    L29
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x27,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x190,%edx,%edx
  cmp    %edx,%eax
  sete   %dl
  movzbl %dl,%edx
  add    $0x1c,%edx
  jmp    L29
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: 

assistant: ```c
int days_pmonth(int month, int year) {
  static const int mtab[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int ndays;
  ndays = mtab[month];
  if (month == 1) {
    if (year < 1900)
      year += 1900;
    if (year % 4 == 0) {
      if (year % 100 != 0)
        ndays++;
      else if (year % 400 == 0)
        ndays++;
    }
  }
  return (ndays);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<days_pmonth>:
  endbr64
  cmp    $0x1,%edi
  je     L8
  movslq %edi,%rdi
  lea    D3(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  lea    0x76c(%rsi),%eax
  cmp    $0x76c,%esi
  cmovl  %eax,%esi
  mov    $0x1c,%eax
  test   $0x3,%sil
  jne    L28
  imul   $0xc28f5c29,%esi,%esi
  mov    $0x1d,%eax
  add    $0x51eb850,%esi
  mov    %esi,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L28
  ror    $0x4,%esi
  xor    %eax,%eax
  cmp    $0xa3d70b,%esi
  setb   %al
  add    $0x1c,%eax
L28:
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: 

assistant: ```c
int days_pmonth(int month, int year) {
  static const int mtab[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int ndays;
  ndays = mtab[month];
  if (month == 1) {
    if (year < 1900)
      year += 1900;
    if (year % 4 == 0) {
      if (year % 100 != 0)
        ndays++;
      else if (year % 400 == 0)
        ndays++;
    }
  }
  return (ndays);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<days_pmonth>:
  endbr64
  cmp    $0x1,%edi
  je     L2
  movslq %edi,%rdi
  lea    D4(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    0x76c(%rsi),%eax
  cmp    $0x76c,%esi
  cmovl  %eax,%esi
  mov    $0x1c,%eax
  test   $0x3,%sil
  jne    L28
  imul   $0xc28f5c29,%esi,%esi
  mov    $0x1d,%eax
  add    $0x51eb850,%esi
  mov    %esi,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L28
  ror    $0x4,%esi
  xor    %eax,%eax
  cmp    $0xa3d70b,%esi
  setb   %al
  add    $0x1c,%eax
L28:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: 

assistant: ```c
int days_pmonth(int month, int year) {
  static const int mtab[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int ndays;
  ndays = mtab[month];
  if (month == 1) {
    if (year < 1900)
      year += 1900;
    if (year % 4 == 0) {
      if (year % 100 != 0)
        ndays++;
      else if (year % 400 == 0)
        ndays++;
    }
  }
  return (ndays);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <subtract@plt>
  mov    %rax,%rdi
  mov    $0x6d,%ecx
  lea    D14(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  call   <_assert_int_equal@plt>
  mov    $0xfffffffd,%esi
  mov    $0x3,%edi
  call   <subtract@plt>
  mov    %rax,%rdi
  mov    $0x6e,%ecx
  lea    D14(%rip),%rax
  mov    %rax,%rdx
  mov    $0x6,%esi
  call   <_assert_int_equal@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_infered: string

tool: D14: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Odie/cmocka/refs/heads/master/example/calculator_test.c

assistant: ```c
void test_subtract(void **state) {
  (void)state;
  _assert_int_equal(((unsigned long long)((size_t)(subtract(3, 3)))), ((unsigned long long)((size_t)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Odie/cmocka/refs/heads/master/example/calculator_test.c", 109);
  _assert_int_equal(((unsigned long long)((size_t)(subtract(3, -3)))), ((unsigned long long)((size_t)(6))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Odie/cmocka/refs/heads/master/example/calculator_test.c", 110);
}
```