ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ppmWrite>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x1,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  mov    %rdi,%rcx
  lea    D26(%rip),%rdi
  push   %rbx
  mov    %edx,%ebx
  mov    $0x3,%edx
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12,%rdi
  imul   %ebp,%ebx
  lea    D12(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbx,2),%esi
  mov    %r12,%rcx
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <fwrite@plt>
```

tool_calls: name: unpack_data
arguments: label: D26
type_guessed: string
name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string

tool: D26: P6


tool: D12: %d %d


tool: D2: 255


assistant: ```c
void ppmWrite(FILE *fp, unsigned char *img, int ncols, int nrows) {
  fprintf(fp, "P6\n");
  fprintf(fp, "%d %d\n", ncols, nrows);
  fprintf(fp, "255\n");
  fwrite(img, ncols * nrows * 3, 1, fp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ppmWrite>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x1,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  mov    %rdi,%rcx
  lea    D9(%rip),%rdi
  push   %rbx
  mov    %edx,%ebx
  mov    $0x3,%edx
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12,%rdi
  imul   %ebp,%ebx
  lea    D27(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbx,2),%esi
  mov    %r12,%rcx
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <fwrite@plt>
```

tool_calls: name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D2
datatype: string

tool: D9: P6


tool: D27: %d %d


tool: D2: 255


assistant: ```c
void ppmWrite(FILE *fp, unsigned char *img, int ncols, int nrows) {
  fprintf(fp, "P6\n");
  fprintf(fp, "%d %d\n", ncols, nrows);
  fprintf(fp, "255\n");
  fwrite(img, ncols * nrows * 3, 1, fp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fnBinSearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L11
  mov    -0x4(%rbp),%eax
  jmp    L38
L11:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L17
  mov    $0xffffffff,%eax
  jmp    L38
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L59
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <fnBinSearch>
  jmp    L38
L59:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x28(%rbp),%edi
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <fnBinSearch>
L38:
  leave
  ret
```

assistant: ```c
int fnBinSearch(int a[], int n, int key, int low, int high) {
  int mid;
  mid = (low + high) / 2;
  if (key == a[mid])
    return mid;
  else if (low > high)
    return -1;
  else if (key < a[mid])
    return fnBinSearch(a, n, key, low, mid - 1);
  else
    return fnBinSearch(a, n, key, mid + 1, high);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fnBinSearch>:
  endbr64
  mov    %esi,%r9d
  mov    %edx,%esi
  lea    (%rcx,%r8,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %edx,%eax
  movslq %edx,%r10
  mov    (%rdi,%r10,4),%r10d
  cmp    %esi,%r10d
  je     L8
  cmp    %r8d,%ecx
  jg     L1
  sub    $0x8,%rsp
  cmp    %esi,%r10d
  jle    L21
  lea    -0x1(%rdx),%r8d
  mov    %esi,%edx
  mov    %r9d,%esi
  call   <fnBinSearch>
L16:
  add    $0x8,%rsp
  ret
L21:
  lea    0x1(%rdx),%ecx
  mov    %esi,%edx
  mov    %r9d,%esi
  call   <fnBinSearch>
  jmp    L16
L1:
  mov    $0xffffffff,%eax
  ret
L8:
  ret
```

assistant: ```c
int fnBinSearch(int a[], int n, int key, int low, int high) {
  int mid;
  mid = (low + high) / 2;
  if (key == a[mid])
    return mid;
  else if (low > high)
    return -1;
  else if (key < a[mid])
    return fnBinSearch(a, n, key, low, mid - 1);
  else
    return fnBinSearch(a, n, key, mid + 1, high);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fnBinSearch>:
  endbr64
  mov    %edx,%esi
  lea    (%rcx,%r8,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %edx,%esi
  je     L60
  cmp    %r8d,%ecx
  jle    L40
  jmp    L19
  nopl   0x0(%rax)
L29:
  lea    -0x1(%rax),%r8d
L2:
  lea    (%r8,%rcx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %esi,%edx
  je     L60
  cmp    %ecx,%r8d
  jl     L19
L40:
  cmp    %edx,%esi
  jl     L29
  lea    0x1(%rax),%ecx
  jmp    L2
  nopl   0x0(%rax)
L19:
  mov    $0xffffffff,%eax
L60:
  ret
```

assistant: ```c
int fnBinSearch(int a[], int n, int key, int low, int high) {
  int mid;
  mid = (low + high) / 2;
  if (key == a[mid])
    return mid;
  else if (low > high)
    return -1;
  else if (key < a[mid])
    return fnBinSearch(a, n, key, low, mid - 1);
  else
    return fnBinSearch(a, n, key, mid + 1, high);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fnBinSearch>:
  endbr64
  mov    %edx,%esi
  lea    (%rcx,%r8,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %edx,%esi
  je     L26
  cmp    %r8d,%ecx
  jle    L57
  jmp    L29
  nopl   0x0(%rax)
L11:
  lea    -0x1(%rax),%r8d
L59:
  lea    (%r8,%rcx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %esi,%edx
  je     L26
  cmp    %ecx,%r8d
  jl     L29
L57:
  cmp    %edx,%esi
  jl     L11
  lea    0x1(%rax),%ecx
  jmp    L59
  nopl   0x0(%rax)
L29:
  mov    $0xffffffff,%eax
L26:
  ret
```

assistant: ```c
int fnBinSearch(int a[], int n, int key, int low, int high) {
  int mid;
  mid = (low + high) / 2;
  if (key == a[mid])
    return mid;
  else if (low > high)
    return -1;
  else if (key < a[mid])
    return fnBinSearch(a, n, key, low, mid - 1);
  else
    return fnBinSearch(a, n, key, mid + 1, high);
}
```
user: What is the c source code of the assembly code below:

```asm
<clust_time_now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  test   %rax,%rax
  je     L0
  mov    $0x0,%eax
  jmp    L21
L0:
  mov    -0x18(%rbp),%rax
  imul   $0x3b9aca00,%rax,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  imul   $0x3e8,%rax,%rax
  add    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
uint64_t clust_time_now(void) {
  struct timeval tv;
  uint64_t time_now;
  if (gettimeofday(&tv, 0)) {
    return 0ULL;
  }
  time_now = (uint64_t)(tv.tv_sec) * 1000000000ULL;
  time_now += (uint64_t)(tv.tv_usec) * 1000ULL;
  return time_now;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clust_time_now>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L1
  imul   $0x3b9aca00,0x8(%rsp),%rdx
  imul   $0x3e8,(%rsp),%rax
  add    %rdx,%rax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t clust_time_now(void) {
  struct timeval tv;
  uint64_t time_now;
  if (gettimeofday(&tv, 0)) {
    return 0ULL;
  }
  time_now = (uint64_t)(tv.tv_sec) * 1000000000ULL;
  time_now += (uint64_t)(tv.tv_usec) * 1000ULL;
  return time_now;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clust_time_now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L10
  imul   $0x3b9aca00,0x8(%rsp),%rdx
  imul   $0x3e8,(%rsp),%rax
  add    %rdx,%rax
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t clust_time_now(void) {
  struct timeval tv;
  uint64_t time_now;
  if (gettimeofday(&tv, 0)) {
    return 0ULL;
  }
  time_now = (uint64_t)(tv.tv_sec) * 1000000000ULL;
  time_now += (uint64_t)(tv.tv_usec) * 1000ULL;
  return time_now;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clust_time_now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L15
  imul   $0x3b9aca00,0x8(%rsp),%rdx
  imul   $0x3e8,(%rsp),%rax
  add    %rdx,%rax
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t clust_time_now(void) {
  struct timeval tv;
  uint64_t time_now;
  if (gettimeofday(&tv, 0)) {
    return 0ULL;
  }
  time_now = (uint64_t)(tv.tv_sec) * 1000000000ULL;
  time_now += (uint64_t)(tv.tv_usec) * 1000ULL;
  return time_now;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  add    $0x14,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <goo@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int foo3() {
  int a;
  int *p;
  p = &a + 5;
  return goo(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo3>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rdi
  call   <goo@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo3() {
  int a;
  int *p;
  p = &a + 5;
  return goo(p);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo3>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rdi
  call   <goo@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo3() {
  int a;
  int *p;
  p = &a + 5;
  return goo(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo3>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rdi
  call   <goo@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo3() {
  int a;
  int *p;
  p = &a + 5;
  return goo(p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<process_votes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L32
L19:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x18(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L23
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  sub    %eax,-0x10(%rbp)
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x10(%rbp),%xmm2
  movq   %xmm2,%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,%esi
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L14
L23:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  sub    %eax,-0xc(%rbp)
  pxor   %xmm3,%xmm3
  cvtsi2sdl -0x10(%rbp),%xmm3
  movq   %xmm3,%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,%esi
  movq   %rax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L14:
  mov    -0x10(%rbp),%eax
  add    %eax,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  movq   %xmm0,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  movq   %rax,%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string

tool: D1: A %d %d


tool: D27: B %d %d


tool: D16: %.10f


assistant: ```c
void process_votes(int d, int *votes) {
  int total_w_a = 0, total_w_b = 0, total = 0;
  for (int i = 0; i < d; i++) {
    int a = votes[i << 1], b = votes[(i << 1) + 1];
    int w_a = a, w_b = b;
    total += a + b;
    if (a > b) {
      w_a -= (int)floor((a + b) / 2) + 1;
      printf("A %d %d\n", w_a, w_b);
    } else {
      w_b -= (int)floor((a + b) / 2) + 1;
      printf("B %d %d\n", w_a, w_b);
    }
    total_w_a += w_a;
    total_w_b += w_b;
  }
  printf("%.10f\n", abs(total_w_a - total_w_b) / (double)total);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<process_votes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L45
  mov    %rsi,%r14
  lea    (%rdi,%rdi,1),%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%r12d
  mov    $0x0,%r15d
  movl   $0x0,0x8(%rsp)
  mov    $0x0,%r13d
  jmp    L6
L48:
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <floor@plt>
  add    $0x1,%eax
  sub    %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mov    %ebx,%esi
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L11:
  add    %ebp,%r13d
  add    %ebx,0x8(%rsp)
  add    $0x2,%r12d
  cmp    0xc(%rsp),%r12d
  je     L42
L6:
  movslq %r12d,%rax
  mov    (%r14,%rax,4),%ebp
  mov    0x4(%r14,%rax,4),%ebx
  lea    0x0(%rbp,%rbx,1),%eax
  add    %eax,%r15d
  cmp    %ebx,%ebp
  jle    L48
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <floor@plt>
  add    $0x1,%eax
  sub    %eax,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mov    %ebx,%esi
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L11
L45:
  mov    $0x0,%r15d
  movl   $0x0,0x8(%rsp)
  mov    $0x0,%r13d
L42:
  mov    %r13d,%edi
  sub    0x8(%rsp),%edi
  call   <abs@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %r15d,%xmm1
  divsd  %xmm1,%xmm0
  lea    D23(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D6
type: string
name: parse_data
arguments: data_tag: D23
type: string

tool: D22: B %d %d


tool: D6: A %d %d


tool: D23: %.10f


assistant: ```c
void process_votes(int d, int *votes) {
  int total_w_a = 0, total_w_b = 0, total = 0;
  for (int i = 0; i < d; i++) {
    int a = votes[i << 1], b = votes[(i << 1) + 1];
    int w_a = a, w_b = b;
    total += a + b;
    if (a > b) {
      w_a -= (int)floor((a + b) / 2) + 1;
      printf("A %d %d\n", w_a, w_b);
    } else {
      w_b -= (int)floor((a + b) / 2) + 1;
      printf("B %d %d\n", w_a, w_b);
    }
    total_w_a += w_a;
    total_w_b += w_b;
  }
  printf("%.10f\n", abs(total_w_a - total_w_b) / (double)total);
}
```
user: What is the c source code of the assembly code below:

```asm
<process_votes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L31
  lea    (%rdi,%rdi,1),%eax
  movl   $0x0,0x8(%rsp)
  mov    %rsi,%r14
  xor    %ebp,%ebp
  mov    %eax,0xc(%rsp)
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L59:
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  mov    %r15d,%esi
  lea    D29(%rip),%rdi
  add    $0x1,%eax
  sub    %eax,%ebx
  mov    $0x1,%eax
  cvtsi2sd %ebx,%xmm0
  call   <printf@plt>
L42:
  add    %ebx,0x8(%rsp)
  add    %r15d,%r12d
  add    $0x2,%r13d
  cmp    %r13d,0xc(%rsp)
  je     L57
L13:
  movslq %r13d,%rax
  mov    (%r14,%rax,4),%ebx
  mov    0x4(%r14,%rax,4),%r15d
  lea    (%rbx,%r15,1),%eax
  mov    %eax,%edi
  add    %eax,%ebp
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    %r15d,%ebx
  jg     L59
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  lea    D4(%rip),%rdi
  cvtsi2sd %ebx,%xmm0
  add    $0x1,%eax
  sub    %eax,%r15d
  mov    $0x1,%eax
  mov    %r15d,%esi
  call   <printf@plt>
  jmp    L42
  nopl   0x0(%rax)
L57:
  mov    0x8(%rsp),%edi
  sub    %r12d,%edi
L55:
  call   <abs@plt>
  pxor   %xmm1,%xmm1
  add    $0x18,%rsp
  lea    D5(%rip),%rdi
  cvtsi2sd %ebp,%xmm1
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm1,%xmm0
  jmp    1080 <printf@plt>
  nop
L31:
  xor    %edi,%edi
  xor    %ebp,%ebp
  jmp    L55
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D29: A %d %d


tool: D4: B %d %d


tool: D5: %.10f


assistant: ```c
void process_votes(int d, int *votes) {
  int total_w_a = 0, total_w_b = 0, total = 0;
  for (int i = 0; i < d; i++) {
    int a = votes[i << 1], b = votes[(i << 1) + 1];
    int w_a = a, w_b = b;
    total += a + b;
    if (a > b) {
      w_a -= (int)floor((a + b) / 2) + 1;
      printf("A %d %d\n", w_a, w_b);
    } else {
      w_b -= (int)floor((a + b) / 2) + 1;
      printf("B %d %d\n", w_a, w_b);
    }
    total_w_a += w_a;
    total_w_b += w_b;
  }
  printf("%.10f\n", abs(total_w_a - total_w_b) / (double)total);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<process_votes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L45
  lea    (%rdi,%rdi,1),%eax
  movl   $0x0,0x4(%rsp)
  mov    %rsi,%r14
  xor    %ebp,%ebp
  mov    %eax,0x8(%rsp)
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L21:
  movslq %r13d,%rax
  mov    (%r14,%rax,4),%r15d
  mov    0x4(%r14,%rax,4),%ebx
  lea    (%r15,%rbx,1),%eax
  mov    %eax,%edi
  add    %eax,%ebp
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    %ebx,%r15d
  jle    L47
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  add    %ebx,%r12d
  add    $0x1,%eax
  lea    D8(%rip),%rdi
  add    $0x2,%r13d
  sub    %eax,%r15d
  mov    $0x1,%eax
  cvtsi2sd %r15d,%xmm0
  call   <printf@plt>
  add    %r15d,0x4(%rsp)
  cmp    0x8(%rsp),%r13d
  jne    L21
L29:
  mov    0x4(%rsp),%edi
  sub    %r12d,%edi
L33:
  call   <abs@plt>
  pxor   %xmm1,%xmm1
  add    $0x18,%rsp
  lea    D7(%rip),%rdi
  cvtsi2sd %ebp,%xmm1
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm1,%xmm0
  jmp    1080 <printf@plt>
  nopl   0x0(%rax)
L47:
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  mov    %ebx,%edx
  add    $0x2,%r13d
  cvtsi2sd %r15d,%xmm0
  add    $0x1,%eax
  lea    D23(%rip),%rdi
  sub    %eax,%edx
  mov    $0x1,%eax
  mov    %edx,%esi
  mov    %edx,0xc(%rsp)
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  add    %r15d,0x4(%rsp)
  add    %edx,%r12d
  cmp    %r13d,0x8(%rsp)
  jne    L21
  jmp    L29
  nopl   0x0(%rax)
L45:
  xor    %edi,%edi
  xor    %ebp,%ebp
  jmp    L33
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string
name: disassemble_data
arguments: label: D7
data_type: string
name: disassemble_data
arguments: label: D23
data_type: string

tool: D8: A %d %d


tool: D7: %.10f


tool: D23: B %d %d


assistant: ```c
void process_votes(int d, int *votes) {
  int total_w_a = 0, total_w_b = 0, total = 0;
  for (int i = 0; i < d; i++) {
    int a = votes[i << 1], b = votes[(i << 1) + 1];
    int w_a = a, w_b = b;
    total += a + b;
    if (a > b) {
      w_a -= (int)floor((a + b) / 2) + 1;
      printf("A %d %d\n", w_a, w_b);
    } else {
      w_b -= (int)floor((a + b) / 2) + 1;
      printf("B %d %d\n", w_a, w_b);
    }
    total_w_a += w_a;
    total_w_b += w_b;
  }
  printf("%.10f\n", abs(total_w_a - total_w_b) / (double)total);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kt_int_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L2:
  addl   $0x1,-0x4(%rbp)
L14:
  sarl   -0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int kt_int_log2(int n) {
  int tmp1 = n;
  int tmp2 = 0;
  while (tmp1 >>= 1) {
    tmp2++;
  }
  return tmp2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kt_int_log2>:
  endbr64
  sar    %edi
  je     L14
  mov    $0x0,%eax
L11:
  add    $0x1,%eax
  sar    %edi
  jne    L11
  ret
L14:
  mov    %edi,%eax
  ret
```

assistant: ```c
int kt_int_log2(int n) {
  int tmp1 = n;
  int tmp2 = 0;
  while (tmp1 >>= 1) {
    tmp2++;
  }
  return tmp2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kt_int_log2>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L0
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x1,%eax
  sar    %edi
  jne    L16
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
int kt_int_log2(int n) {
  int tmp1 = n;
  int tmp2 = 0;
  while (tmp1 >>= 1) {
    tmp2++;
  }
  return tmp2;
}
```