ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D15(%rip),%r15
  jmp    L11
L36:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L39
L11:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L38:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L38
  jmp    L36
L39:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D4
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string

tool: D15: dstdev

tool: D4: # c::%s:len=%d


tool: D19: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dstdev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D14(%rip),%r15
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L10:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L10
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L8
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D10
type: string
name: retrieve_data
arguments: tag: D13
type: string

tool: D14: dstdev

tool: D10: # c::%s:len=%d


tool: D13: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dstdev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D28(%rip),%r15
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L3:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L10:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L10
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L3
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D16
type: string
name: disassemble_data
arguments: data_label: D0
type: string

tool: D28: dstdev

tool: D16: # c::%s:len=%d


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dstdev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<min_dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L22
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L4
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L4:
  addl   $0x1,-0xc(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L5
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double min_dvector(double *v, long nl, long nh) {
  int i;
  double m;
  m = v[nl];
  for (i = nl + 1; i <= nh; i++) {
    if (v[i] < m)
      m = v[i];
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<min_dvector>:
  endbr64
  movsd  (%rdi,%rsi,8),%xmm0
  add    $0x1,%esi
  movslq %esi,%rax
  cmp    %rax,%rdx
  jl     L18
  lea    (%rdi,%rax,8),%rax
  lea    0x8(%rdi,%rdx,8),%rdx
L12:
  movsd  (%rax),%xmm1
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L12
L18:
  ret
```

assistant: ```c
double min_dvector(double *v, long nl, long nh) {
  int i;
  double m;
  m = v[nl];
  for (i = nl + 1; i <= nh; i++) {
    if (v[i] < m)
      m = v[i];
  }
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<min_dvector>:
  endbr64
  movsd  (%rdi,%rsi,8),%xmm0
  add    $0x1,%esi
  movslq %esi,%rsi
  cmp    %rsi,%rdx
  jl     L10
  lea    (%rdi,%rsi,8),%rax
  lea    0x8(%rdi,%rdx,8),%rdx
  nopl   (%rax)
L3:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L3
L10:
  ret
```

assistant: ```c
double min_dvector(double *v, long nl, long nh) {
  int i;
  double m;
  m = v[nl];
  for (i = nl + 1; i <= nh; i++) {
    if (v[i] < m)
      m = v[i];
  }
  return m;
}
```
user: What is the c source code of the assembly code below:

```asm
<min_dvector>:
  endbr64
  movsd  (%rdi,%rsi,8),%xmm0
  add    $0x1,%esi
  movslq %esi,%rsi
  cmp    %rsi,%rdx
  jl     L11
  lea    (%rdi,%rsi,8),%rax
  lea    0x8(%rdi,%rdx,8),%rdx
  nopl   (%rax)
L17:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L17
L11:
  ret
```

assistant: ```c
double min_dvector(double *v, long nl, long nh) {
  int i;
  double m;
  m = v[nl];
  for (i = nl + 1; i <= nh; i++) {
    if (v[i] < m)
      m = v[i];
  }
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<freeargs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L2:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addq   $0x8,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void freeargs(char **args) {
  char **save = args;
  while (*args) {
    free(*args);
    args++;
  }
  free(save);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<freeargs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L18
  mov    %rbp,%rbx
L19:
  call   <free@plt>
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L19
L18:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void freeargs(char **args) {
  char **save = args;
  while (*args) {
    free(*args);
    args++;
  }
  free(save);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<freeargs>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L14
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L12:
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L12
L14:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void freeargs(char **args) {
  char **save = args;
  while (*args) {
    free(*args);
    args++;
  }
  free(save);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<freeargs>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L13
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L14:
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L14
L13:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void freeargs(char **args) {
  char **save = args;
  while (*args) {
    free(*args);
    args++;
  }
  free(save);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L18
  ucomisd -0x8(%rbp),%xmm0
  jne    L18
  mov    $0x1,%eax
  jmp    L3
L18:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int isInt(double x) {
  if (x == (int)x)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isInt>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  ucomisd %xmm0,%xmm1
  setnp  %al
  movzbl %al,%eax
  mov    $0x0,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int isInt(double x) {
  if (x == (int)x)
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<isInt>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  mov    $0x0,%edx
  cvtsi2sd %eax,%xmm1
  xor    %eax,%eax
  ucomisd %xmm0,%xmm1
  setnp  %al
  cmovne %edx,%eax
  ret
```

assistant: ```c
int isInt(double x) {
  if (x == (int)x)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isInt>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  mov    $0x0,%edx
  cvtsi2sd %eax,%xmm1
  xor    %eax,%eax
  ucomisd %xmm0,%xmm1
  setnp  %al
  cmovne %edx,%eax
  ret
```

assistant: ```c
int isInt(double x) {
  if (x == (int)x)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x3,%eax
  and    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  shr    %al
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  shr    %al
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  shr    %al
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x3,%eax
  and    $0x80,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  shr    %al
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  or     %edx,%eax
  and    $0xfffffff7,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  shr    %al
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  shr    %al
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  shr    %al
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ror(unsigned char *target) {
  int carry_left, carry_right;
  carry_right = (target[6] & 0x01) << 3;
  target[6] = (target[6] >> 1) | ((target[5] & 0x01) << 7);
  target[5] = (target[5] >> 1) | ((target[4] & 0x01) << 7);
  target[4] = (target[4] >> 1) | ((target[3] & 0x01) << 7);
  carry_left = (target[3] & 0x10) << 3;
  target[3] = (((target[3] >> 1) | ((target[2] & 0x01) << 7)) & ~0x08) | carry_right;
  target[2] = (target[2] >> 1) | ((target[1] & 0x01) << 7);
  target[1] = (target[1] >> 1) | ((target[0] & 0x01) << 7);
  target[0] = (target[0] >> 1) | carry_left;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ror>:
  endbr64
  mov    %rdi,%rax
  movzbl 0x6(%rdi),%esi
  movzbl 0x5(%rdi),%ecx
  mov    %esi,%edi
  shr    %dil
  mov    %ecx,%edx
  shl    $0x7,%edx
  or     %edi,%edx
  mov    %dl,0x6(%rax)
  movzbl 0x4(%rax),%edx
  shr    %cl
  mov    %edx,%edi
  shl    $0x7,%edi
  or     %edi,%ecx
  mov    %cl,0x5(%rax)
  movzbl 0x3(%rax),%r8d
  movzbl %r8b,%ecx
  shr    %dl
  mov    %ecx,%edi
  shl    $0x7,%edi
  or     %edi,%edx
  mov    %dl,0x4(%rax)
  movzbl 0x2(%rax),%edi
  shr    %r8b
  mov    %edi,%edx
  shl    $0x7,%edx
  or     %r8d,%edx
  and    $0xfffffff7,%edx
  shl    $0x3,%esi
  and    $0x8,%esi
  or     %esi,%edx
  mov    %dl,0x3(%rax)
  movzbl 0x1(%rax),%esi
  shr    %dil
  mov    %esi,%edx
  shl    $0x7,%edx
  or     %edi,%edx
  mov    %dl,0x2(%rax)
  movzbl (%rax),%edx
  shr    %sil
  mov    %edx,%edi
  shl    $0x7,%edi
  or     %edi,%esi
  mov    %sil,0x1(%rax)
  shl    $0x3,%ecx
  and    $0x80,%ecx
  shr    %dl
  or     %ecx,%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void ror(unsigned char *target) {
  int carry_left, carry_right;
  carry_right = (target[6] & 0x01) << 3;
  target[6] = (target[6] >> 1) | ((target[5] & 0x01) << 7);
  target[5] = (target[5] >> 1) | ((target[4] & 0x01) << 7);
  target[4] = (target[4] >> 1) | ((target[3] & 0x01) << 7);
  carry_left = (target[3] & 0x10) << 3;
  target[3] = (((target[3] >> 1) | ((target[2] & 0x01) << 7)) & ~0x08) | carry_right;
  target[2] = (target[2] >> 1) | ((target[1] & 0x01) << 7);
  target[1] = (target[1] >> 1) | ((target[0] & 0x01) << 7);
  target[0] = (target[0] >> 1) | carry_left;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ror>:
  endbr64
  movzbl 0x5(%rdi),%ecx
  movzbl 0x6(%rdi),%esi
  mov    %rdi,%rax
  mov    %ecx,%edx
  mov    %esi,%edi
  shr    %cl
  shr    %dil
  shl    $0x7,%edx
  or     %edi,%edx
  shl    $0x3,%esi
  mov    %dl,0x6(%rax)
  movzbl 0x4(%rax),%edx
  and    $0x8,%esi
  mov    %edx,%edi
  shr    %dl
  shl    $0x7,%edi
  or     %edi,%ecx
  mov    %cl,0x5(%rax)
  movzbl 0x3(%rax),%ecx
  mov    %ecx,%edi
  mov    %ecx,%r8d
  shl    $0x3,%ecx
  shl    $0x7,%edi
  shr    %r8b
  and    $0x80,%ecx
  or     %edi,%edx
  movzbl 0x2(%rax),%edi
  mov    %dl,0x4(%rax)
  mov    %edi,%edx
  shr    %dil
  shl    $0x7,%edx
  or     %r8d,%edx
  and    $0xfffffff7,%edx
  or     %esi,%edx
  movzbl 0x1(%rax),%esi
  mov    %dl,0x3(%rax)
  mov    %esi,%edx
  shr    %sil
  shl    $0x7,%edx
  or     %edi,%edx
  mov    %dl,0x2(%rax)
  movzbl (%rax),%edx
  mov    %edx,%edi
  shr    %dl
  shl    $0x7,%edi
  or     %ecx,%edx
  or     %edi,%esi
  mov    %dl,(%rax)
  mov    %sil,0x1(%rax)
  ret
```

assistant: ```c
void ror(unsigned char *target) {
  int carry_left, carry_right;
  carry_right = (target[6] & 0x01) << 3;
  target[6] = (target[6] >> 1) | ((target[5] & 0x01) << 7);
  target[5] = (target[5] >> 1) | ((target[4] & 0x01) << 7);
  target[4] = (target[4] >> 1) | ((target[3] & 0x01) << 7);
  carry_left = (target[3] & 0x10) << 3;
  target[3] = (((target[3] >> 1) | ((target[2] & 0x01) << 7)) & ~0x08) | carry_right;
  target[2] = (target[2] >> 1) | ((target[1] & 0x01) << 7);
  target[1] = (target[1] >> 1) | ((target[0] & 0x01) << 7);
  target[0] = (target[0] >> 1) | carry_left;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ror>:
  endbr64
  movzbl 0x5(%rdi),%ecx
  movzbl 0x6(%rdi),%esi
  mov    %rdi,%rax
  mov    %ecx,%edx
  mov    %esi,%edi
  shr    %cl
  shr    %dil
  shl    $0x7,%edx
  or     %edi,%edx
  shl    $0x3,%esi
  mov    %dl,0x6(%rax)
  movzbl 0x4(%rax),%edx
  and    $0x8,%esi
  mov    %edx,%edi
  shr    %dl
  shl    $0x7,%edi
  or     %edi,%ecx
  mov    %cl,0x5(%rax)
  movzbl 0x3(%rax),%ecx
  mov    %ecx,%edi
  mov    %ecx,%r8d
  shl    $0x3,%ecx
  shl    $0x7,%edi
  shr    %r8b
  and    $0x80,%ecx
  or     %edi,%edx
  movzbl 0x2(%rax),%edi
  mov    %dl,0x4(%rax)
  mov    %edi,%edx
  shr    %dil
  shl    $0x7,%edx
  or     %r8d,%edx
  and    $0xfffffff7,%edx
  or     %esi,%edx
  movzbl 0x1(%rax),%esi
  mov    %dl,0x3(%rax)
  mov    %esi,%edx
  shr    %sil
  shl    $0x7,%edx
  or     %edi,%edx
  mov    %dl,0x2(%rax)
  movzbl (%rax),%edx
  mov    %edx,%edi
  shr    %dl
  shl    $0x7,%edi
  or     %ecx,%edx
  or     %edi,%esi
  mov    %dl,(%rax)
  mov    %sil,0x1(%rax)
  ret
```

assistant: ```c
void ror(unsigned char *target) {
  int carry_left, carry_right;
  carry_right = (target[6] & 0x01) << 3;
  target[6] = (target[6] >> 1) | ((target[5] & 0x01) << 7);
  target[5] = (target[5] >> 1) | ((target[4] & 0x01) << 7);
  target[4] = (target[4] >> 1) | ((target[3] & 0x01) << 7);
  carry_left = (target[3] & 0x10) << 3;
  target[3] = (((target[3] >> 1) | ((target[2] & 0x01) << 7)) & ~0x08) | carry_right;
  target[2] = (target[2] >> 1) | ((target[1] & 0x01) << 7);
  target[1] = (target[1] >> 1) | ((target[0] & 0x01) << 7);
  target[0] = (target[0] >> 1) | carry_left;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_ILL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <kill@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int gen_ILL(void) {
  kill(getpid(), SIGILL);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen_ILL>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rax
  mov    (%rax),%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <kill@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int gen_ILL(void) {
  kill(getpid(), SIGILL);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_ILL>:
  endbr64
  push   %rbp
  mov    D1(%rip),%rax
  mov    (%rax),%ebp
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <kill@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_ILL(void) {
  kill(getpid(), SIGILL);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gen_ILL>:
  endbr64
  push   %rbp
  mov    D5(%rip),%rax
  mov    (%rax),%ebp
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <kill@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_ILL(void) {
  kill(getpid(), SIGILL);
  return 0;
}
```