ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<la_symbind32>:
  endbr64
  push   %rbx
  mov    (%rdi),%rdx
  mov    %rdi,%rbx
  mov    %esi,%ecx
  mov    (%r8),%r8d
  mov    %r9,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: symbind32: symname=%s, st_value=%#lx, ndx=%u, flags=%u


assistant: ```c
uintptr_t la_symbind32(Elf32_Sym *sym, unsigned int ndx, uintptr_t *refcook, uintptr_t *defcook, unsigned int *flags, const char *symname) {
  printf("symbind32: symname=%s, st_value=%#lx, ndx=%u, flags=%u\n", symname, (long int)sym->st_value, ndx, *flags);
  return sym->st_value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<la_symbind32>:
  endbr64
  push   %rbx
  mov    (%rdi),%rdx
  mov    %rdi,%rbx
  mov    %esi,%ecx
  mov    (%r8),%r8d
  mov    %r9,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: symbind32: symname=%s, st_value=%#lx, ndx=%u, flags=%u


assistant: ```c
uintptr_t la_symbind32(Elf32_Sym *sym, unsigned int ndx, uintptr_t *refcook, uintptr_t *defcook, unsigned int *flags, const char *symname) {
  printf("symbind32: symname=%s, st_value=%#lx, ndx=%u, flags=%u\n", symname, (long int)sym->st_value, ndx, *flags);
  return sym->st_value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L9:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rcx,1),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x8(%rbp)
  je     L20
  mov    $0x0,%eax
  jmp    L33
L20:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L10:
  cmpl   $0x0,-0x14(%rbp)
  jne    L9
  mov    -0x8(%rbp),%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int reverse(int x) {
  int result = 0;
  while (x != 0) {
    int new_result = result * 10 + x % 10;
    if (new_result / 10 != result)
      return 0;
    result = new_result;
    x /= 10;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reverse>:
  endbr64
  mov    %edi,%ecx
  test   %edi,%edi
  je     L7
  movslq %edi,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  mov    %edi,%esi
  sub    %eax,%esi
L15:
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  je     L10
  lea    (%rsi,%rsi,4),%edi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    (%rax,%rdi,2),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  cmp    %esi,%eax
  jne    L44
  mov    %edx,%esi
  jmp    L15
L7:
  mov    %edi,%esi
  jmp    L10
L44:
  mov    $0x0,%esi
L10:
  mov    %esi,%eax
  ret
```

assistant: ```c
int reverse(int x) {
  int result = 0;
  while (x != 0) {
    int new_result = result * 10 + x % 10;
    if (new_result / 10 != result)
      return 0;
    result = new_result;
    x /= 10;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse>:
  endbr64
  mov    %edi,%ecx
  test   %edi,%edi
  je     L11
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%r8
  sar    $0x1f,%edx
  sar    $0x22,%r8
  sub    %edx,%r8d
  lea    (%r8,%r8,4),%edx
  mov    %edi,%r8d
  add    %edx,%edx
  sub    %edx,%r8d
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L6:
  movslq %ecx,%rax
  mov    %ecx,%esi
  lea    (%r8,%r8,4),%edi
  imul   $0x66666667,%rax,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  mov    %ecx,%esi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  lea    (%rsi,%rdi,2),%esi
  movslq %esi,%rdx
  mov    %esi,%edi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%edi
  sar    $0x22,%rdx
  sub    %edi,%edx
  cmp    %r8d,%edx
  jne    L11
  mov    %esi,%r8d
L35:
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%ecx
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverse(int x) {
  int result = 0;
  while (x != 0) {
    int new_result = result * 10 + x % 10;
    if (new_result / 10 != result)
      return 0;
    result = new_result;
    x /= 10;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse>:
  endbr64
  mov    %edi,%ecx
  test   %edi,%edi
  je     L3
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%r8
  sar    $0x1f,%edx
  sar    $0x22,%r8
  sub    %edx,%r8d
  lea    (%r8,%r8,4),%edx
  mov    %edi,%r8d
  add    %edx,%edx
  sub    %edx,%r8d
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L16:
  movslq %ecx,%rax
  mov    %ecx,%esi
  lea    (%r8,%r8,4),%edi
  imul   $0x66666667,%rax,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  mov    %ecx,%esi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  lea    (%rsi,%rdi,2),%esi
  movslq %esi,%rdx
  mov    %esi,%edi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%edi
  sar    $0x22,%rdx
  sub    %edi,%edx
  cmp    %r8d,%edx
  jne    L3
  mov    %esi,%r8d
L34:
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%ecx
  jne    L16
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverse(int x) {
  int result = 0;
  while (x != 0) {
    int new_result = result * 10 + x % 10;
    if (new_result / 10 != result)
      return 0;
    result = new_result;
    x /= 10;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<promedio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L2
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double promedio(int cant, int arreglo[cant]) {
  int total = 0, i = 0;
  double resp = 0;
  for (i = 0; i < cant; i++) {
    total = +arreglo[i];
  }
  resp = (double)total / (double)cant;
  return resp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<promedio>:
  endbr64
  test   %edi,%edi
  jle    L24
  mov    $0x0,%eax
L0:
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L0
  movslq %edx,%rdx
  mov    (%rsi,%rdx,4),%eax
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L24:
  mov    $0x0,%eax
  jmp    L5
```

assistant: ```c
double promedio(int cant, int arreglo[cant]) {
  int total = 0, i = 0;
  double resp = 0;
  for (i = 0; i < cant; i++) {
    total = +arreglo[i];
  }
  resp = (double)total / (double)cant;
  return resp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<promedio>:
  endbr64
  test   %edi,%edi
  jle    L6
  lea    -0x1(%rdi),%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rsi,%rax,4),%xmm0
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L6:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double promedio(int cant, int arreglo[cant]) {
  int total = 0, i = 0;
  double resp = 0;
  for (i = 0; i < cant; i++) {
    total = +arreglo[i];
  }
  resp = (double)total / (double)cant;
  return resp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<promedio>:
  endbr64
  test   %edi,%edi
  jle    L1
  lea    -0x1(%rdi),%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rsi,%rax,4),%xmm0
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L1:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double promedio(int cant, int arreglo[cant]) {
  int total = 0, i = 0;
  double resp = 0;
  for (i = 0; i < cant; i++) {
    total = +arreglo[i];
  }
  resp = (double)total / (double)cant;
  return resp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<panic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  jmp    L3
```

assistant: ```c
__attribute__((__noreturn__)) void panic(const char *str) {
  printf(str);
  while (1) {
  }
  __builtin_unreachable();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<panic>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  call   <printf@plt>
L7:
  jmp    L7
```

assistant: ```c
__attribute__((__noreturn__)) void panic(const char *str) {
  printf(str);
  while (1) {
  }
  __builtin_unreachable();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<panic>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  call   <printf@plt>
L2:
  jmp    L2
```

assistant: ```c
__attribute__((__noreturn__)) void panic(const char *str) {
  printf(str);
  while (1) {
  }
  __builtin_unreachable();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<panic>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  call   <printf@plt>
L1:
  jmp    L1
```

assistant: ```c
__attribute__((__noreturn__)) void panic(const char *str) {
  printf(str);
  while (1) {
  }
  __builtin_unreachable();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <clear_screen@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <display_at@plt>
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <display_at@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D3: GeekSkool

tool: D5: HasGeek House

assistant: ```c
void main() {
  clear_screen();
  display_at("GeekSkool", 1, 1);
  display_at("HasGeek House", 1, 6);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clear_screen@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D12(%rip),%rdi
  call   <display_at@plt>
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D0(%rip),%rdi
  call   <display_at@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D0
type: string

tool: D12: GeekSkool

tool: D0: HasGeek House

assistant: ```c
void main() {
  clear_screen();
  display_at("GeekSkool", 1, 1);
  display_at("HasGeek House", 1, 6);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_screen@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <display_at@plt>
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <display_at@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
data_type: string
name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D17: GeekSkool

tool: D7: HasGeek House

assistant: ```c
void main() {
  clear_screen();
  display_at("GeekSkool", 1, 1);
  display_at("HasGeek House", 1, 6);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_screen@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <display_at@plt>
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <display_at@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type: string
name: unpack_data
arguments: tag: D8
type: string

tool: D6: GeekSkool

tool: D8: HasGeek House

assistant: ```c
void main() {
  clear_screen();
  display_at("GeekSkool", 1, 1);
  display_at("HasGeek House", 1, 6);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L15
L32:
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  add    %ecx,%edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <cola@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L15:
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L31
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L32
L31:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D0: %d

tool: D15: %d


tool: D6: %d %d %d

assistant: ```c
int main() {
  int t, e, f, c;
  scanf("%d", &t);
  while (scanf("%d %d %d", &e, &f, &c) == 3 && t) {
    printf("%d\n", cola(e + f, c));
    t--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    D16(%rip),%rbx
  lea    D9(%rip),%r13
  jmp    L28
L6:
  mov    0x10(%rsp),%edi
  add    0xc(%rsp),%edi
  mov    0x14(%rsp),%esi
  call   <cola@plt>
  mov    %eax,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  subl   $0x1,0x8(%rsp)
L28:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L4
  cmpl   $0x0,0x8(%rsp)
  jne    L6
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D13: %d

tool: D16: %d %d %d

tool: D9: %d


assistant: ```c
int main() {
  int t, e, f, c;
  scanf("%d", &t);
  while (scanf("%d %d %d", &e, &f, &c) == 3 && t) {
    printf("%d\n", cola(e + f, c));
    t--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  lea    D21(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  call   <scanf@plt>
  jmp    L22
L17:
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L33
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  add    0xc(%rsp),%edi
  call   <cola@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  subl   $0x1,0x8(%rsp)
L22:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  je     L17
L33:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D21
type_guessed: string
name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D0: %d

tool: D21: %d


tool: D3: %d %d %d

assistant: ```c
int main() {
  int t, e, f, c;
  scanf("%d", &t);
  while (scanf("%d %d %d", &e, &f, &c) == 3 && t) {
    printf("%d\n", cola(e + f, c));
    t--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%rdi
  lea    D11(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D27(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  call   <scanf@plt>
  jmp    L22
L4:
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L28
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  add    0xc(%rsp),%edi
  call   <cola@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  subl   $0x1,0x8(%rsp)
L22:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  je     L4
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D27
type_infered: string

tool: D10: %d

tool: D11: %d


tool: D27: %d %d %d

assistant: ```c
int main() {
  int t, e, f, c;
  scanf("%d", &t);
  while (scanf("%d %d %d", &e, &f, &c) == 3 && t) {
    printf("%d\n", cola(e + f, c));
    t--;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L17:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x26,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L10
  addl   $0xa,-0x8(%rbp)
  jmp    L39
L10:
  movl   $0x0,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L39:
  addl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0xf423f,-0x4(%rbp)
  jle    L17
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string

tool: D8: false branch


assistant: ```c
int main(void) {
  int x, c = 0;
  while (c < 1000000) {
    x = rand();
    if (__builtin_expect((x == 38), 1)) {
      x += 10;
    } else {
      x = 0;
      printf("false branch\n");
    }
    c++;
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebp
  lea    D7(%rip),%r12
  jmp    L32
L13:
  sub    $0x1,%ebp
  je     L30
L32:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  cmp    $0x26,%eax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x1,%esi
  call   <__builtin_expect@plt>
  add    $0xa,%ebx
  test   %rax,%rax
  jne    L13
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L13
L30:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: false branch


assistant: ```c
int main(void) {
  int x, c = 0;
  while (c < 1000000) {
    x = rand();
    if (__builtin_expect((x == 38), 1)) {
      x += 10;
    } else {
      x = 0;
      printf("false branch\n");
    }
    c++;
  }
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    $0xf4240,%ebp
  push   %rbx
  jmp    L30
  cs nopw 0x0(%rax,%rax,1)
L36:
  sub    $0x1,%ebp
  je     L21
L30:
  xor    %eax,%eax
  call   <rand@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  cmp    $0x26,%eax
  mov    %eax,%ebx
  sete   %dil
  add    $0xa,%ebx
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L36
  mov    %r12,%rdi
  xor    %ebx,%ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L30
L21:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D5: false branch


assistant: ```c
int main(void) {
  int x, c = 0;
  while (c < 1000000) {
    x = rand();
    if (__builtin_expect((x == 38), 1)) {
      x += 10;
    } else {
      x = 0;
      printf("false branch\n");
    }
    c++;
  }
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    $0xf4240,%ebp
  push   %rbx
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L30:
  sub    $0x1,%ebp
  je     L38
L14:
  xor    %eax,%eax
  call   <rand@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  cmp    $0x26,%eax
  mov    %eax,%ebx
  sete   %dil
  add    $0xa,%ebx
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L30
  mov    %r12,%rdi
  xor    %ebx,%ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L14
L38:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string

tool: D7: false branch


assistant: ```c
int main(void) {
  int x, c = 0;
  while (c < 1000000) {
    x = rand();
    if (__builtin_expect((x == 38), 1)) {
      x += 10;
    } else {
      x = 0;
      printf("false branch\n");
    }
    c++;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    $0x811c9dc5,%eax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L3:
  mov    -0x8(%rbp),%rax
  imul   $0x1000193,%rax,%rdx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  xor    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%rcx
  movabs $0x22df1bf99e8e2919,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x13,%rax
  imul   $0x3abad9,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t hash_func(char *key) {
  size_t h = 2166136261;
  int i;
  for (i = 0; key[i] != '\0'; ++i)
    h = (h * 16777619) ^ key[i];
  return h % 3848921;
}
```