ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<wave_to_sndlib_format>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x102,-0x4(%rbp)
  je     L243
  cmpl   $0x102,-0x4(%rbp)
  jg     L306
  cmpl   $0x101,-0x4(%rbp)
  je     L143
  cmpl   $0x101,-0x4(%rbp)
  jg     L306
  cmpl   $0x7,-0x4(%rbp)
  je     L212
  cmpl   $0x7,-0x4(%rbp)
  jg     L306
  cmpl   $0x6,-0x4(%rbp)
  je     L288
  cmpl   $0x6,-0x4(%rbp)
  jg     L306
  cmpl   $0x1,-0x4(%rbp)
  je     L254
  cmpl   $0x3,-0x4(%rbp)
  je     L23
  jmp    L306
L254:
  cmpl   $0x20,-0x8(%rbp)
  je     L158
  cmpl   $0x20,-0x8(%rbp)
  jg     L307
  cmpl   $0x18,-0x8(%rbp)
  je     L358
  cmpl   $0x18,-0x8(%rbp)
  jg     L307
  cmpl   $0x8,-0x8(%rbp)
  je     L351
  cmpl   $0x10,-0x8(%rbp)
  je     L179
  jmp    L307
L351:
  mov    $0x7,%eax
  jmp    L217
L179:
  cmpl   $0x0,-0xc(%rbp)
  je     L124
  mov    $0xa,%eax
  jmp    L217
L124:
  mov    $0x1,%eax
  jmp    L217
L158:
  cmpl   $0x0,-0xc(%rbp)
  je     L194
  mov    $0xb,%eax
  jmp    L217
L194:
  mov    $0x5,%eax
  jmp    L217
L358:
  cmpl   $0x0,-0xc(%rbp)
  je     L69
  mov    $0x10,%eax
  jmp    L217
L69:
  mov    $0x8,%eax
  jmp    L217
L307:
  mov    $0x7,%eax
  jmp    L217
L23:
  cmpl   $0x0,-0xc(%rbp)
  je     L38
  mov    $0xc,%eax
  jmp    L217
L38:
  mov    $0x4,%eax
  jmp    L217
L288:
  cmpl   $0x8,-0x8(%rbp)
  jne    L50
  mov    $0x6,%eax
  jmp    L217
L212:
  cmpl   $0x8,-0x8(%rbp)
  jne    L281
  mov    $0x2,%eax
  jmp    L217
L143:
  mov    $0x2,%eax
  jmp    L217
L243:
  mov    $0x6,%eax
  jmp    L217
L50:
  nop
  jmp    L306
L281:
  nop
L306:
  mov    $0xffffffff,%eax
L217:
  pop    %rbp
  ret
```

assistant: ```c
int wave_to_sndlib_format(int osf, int bps, int little) {
  switch (osf) {
  case 1:
    switch (bps) {
    case 8:
      return (7);
      break;
    case 16:
      if (little)
        return (10);
      else
        return (1);
      break;
    case 32:
      if (little)
        return (11);
      else
        return (5);
      break;
    case 24:
      if (little)
        return (16);
      else
        return (8);
      break;
    default:
      return (7);
      break;
    }
    break;
  case 3:
    if (little)
      return (12);
    else
      return (4);
    break;
  case 6:
    if (bps == 8)
      return (6);
    break;
  case 7:
    if (bps == 8)
      return (2);
    break;
  case 0x101:
    return (2);
    break;
  case 0x102:
    return (6);
    break;
  }
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wave_to_sndlib_format>:
  endbr64
  cmp    $0x7,%edi
  je     L51
  jg     L47
  cmp    $0x3,%edi
  je     L45
  cmp    $0x6,%edi
  jne    L40
  cmp    $0x8,%esi
  mov    $0xffffffff,%eax
  cmove  %edi,%eax
  ret
L40:
  cmp    $0x1,%edi
  jne    L8
  cmp    $0x18,%esi
  je     L19
  cmp    $0x20,%esi
  je     L36
  mov    $0x7,%eax
  cmp    $0x10,%esi
  jne    L31
  test   %edx,%edx
  mov    $0xa,%eax
  cmove  %edi,%eax
  ret
L8:
  mov    $0xffffffff,%eax
  ret
L47:
  mov    $0x2,%eax
  cmp    $0x101,%edi
  je     L31
  cmp    $0x102,%edi
  mov    $0xffffffff,%eax
  mov    $0x6,%edx
  cmove  %edx,%eax
  ret
L36:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffffa,%eax
  add    $0xb,%eax
  ret
L19:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0x10,%eax
  ret
L45:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0xc,%eax
  ret
L51:
  cmp    $0x8,%esi
  sete   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,2),%eax
L31:
  ret
```

assistant: ```c
int wave_to_sndlib_format(int osf, int bps, int little) {
  switch (osf) {
  case 1:
    switch (bps) {
    case 8:
      return (7);
      break;
    case 16:
      if (little)
        return (10);
      else
        return (1);
      break;
    case 32:
      if (little)
        return (11);
      else
        return (5);
      break;
    case 24:
      if (little)
        return (16);
      else
        return (8);
      break;
    default:
      return (7);
      break;
    }
    break;
  case 3:
    if (little)
      return (12);
    else
      return (4);
    break;
  case 6:
    if (bps == 8)
      return (6);
    break;
  case 7:
    if (bps == 8)
      return (2);
    break;
  case 0x101:
    return (2);
    break;
  case 0x102:
    return (6);
    break;
  }
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wave_to_sndlib_format>:
  endbr64
  cmp    $0x7,%edi
  je     L74
  jg     L72
  cmp    $0x3,%edi
  je     L25
  cmp    $0x6,%edi
  jne    L31
  cmp    $0x8,%esi
  mov    $0xffffffff,%eax
  cmove  %edi,%eax
  ret
  nopl   (%rax)
L72:
  mov    $0x2,%eax
  cmp    $0x101,%edi
  je     L86
  cmp    $0x102,%edi
  mov    $0x6,%edx
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax)
L31:
  cmp    $0x1,%edi
  jne    L85
  cmp    $0x18,%esi
  je     L71
  cmp    $0x20,%esi
  je     L83
  mov    $0x7,%eax
  cmp    $0x10,%esi
  je     L38
L86:
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0xc,%eax
  ret
  nopl   0x0(%rax)
L74:
  xor    %eax,%eax
  cmp    $0x8,%esi
  sete   %al
  lea    -0x1(%rax,%rax,2),%eax
  ret
  nopl   (%rax)
L38:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff7,%eax
  add    $0xa,%eax
  ret
  nopl   0x0(%rax)
L71:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0x10,%eax
  ret
  nopl   0x0(%rax)
L83:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffffa,%eax
  add    $0xb,%eax
  ret
```

assistant: ```c
int wave_to_sndlib_format(int osf, int bps, int little) {
  switch (osf) {
  case 1:
    switch (bps) {
    case 8:
      return (7);
      break;
    case 16:
      if (little)
        return (10);
      else
        return (1);
      break;
    case 32:
      if (little)
        return (11);
      else
        return (5);
      break;
    case 24:
      if (little)
        return (16);
      else
        return (8);
      break;
    default:
      return (7);
      break;
    }
    break;
  case 3:
    if (little)
      return (12);
    else
      return (4);
    break;
  case 6:
    if (bps == 8)
      return (6);
    break;
  case 7:
    if (bps == 8)
      return (2);
    break;
  case 0x101:
    return (2);
    break;
  case 0x102:
    return (6);
    break;
  }
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wave_to_sndlib_format>:
  endbr64
  cmp    $0x7,%edi
  je     L24
  jg     L40
  cmp    $0x3,%edi
  je     L41
  cmp    $0x6,%edi
  jne    L79
  cmp    $0x8,%esi
  mov    $0xffffffff,%eax
  cmove  %edi,%eax
  ret
  nopl   (%rax)
L40:
  mov    $0x2,%eax
  cmp    $0x101,%edi
  je     L65
  cmp    $0x102,%edi
  mov    $0x6,%edx
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax)
L79:
  cmp    $0x1,%edi
  jne    L69
  cmp    $0x18,%esi
  je     L3
  cmp    $0x20,%esi
  je     L10
  mov    $0x7,%eax
  cmp    $0x10,%esi
  je     L20
L65:
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0xc,%eax
  ret
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
  cmp    $0x8,%esi
  sete   %al
  lea    -0x1(%rax,%rax,2),%eax
  ret
  nopl   (%rax)
L20:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff7,%eax
  add    $0xa,%eax
  ret
  nopl   0x0(%rax)
L3:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0x10,%eax
  ret
  nopl   0x0(%rax)
L10:
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffffa,%eax
  add    $0xb,%eax
  ret
```

assistant: ```c
int wave_to_sndlib_format(int osf, int bps, int little) {
  switch (osf) {
  case 1:
    switch (bps) {
    case 8:
      return (7);
      break;
    case 16:
      if (little)
        return (10);
      else
        return (1);
      break;
    case 32:
      if (little)
        return (11);
      else
        return (5);
      break;
    case 24:
      if (little)
        return (16);
      else
        return (8);
      break;
    default:
      return (7);
      break;
    }
    break;
  case 3:
    if (little)
      return (12);
    else
      return (4);
    break;
  case 6:
    if (bps == 8)
      return (6);
    break;
  case 7:
    if (bps == 8)
      return (2);
    break;
  case 0x101:
    return (2);
    break;
  case 0x102:
    return (6);
    break;
  }
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L1:
  mov    -0x4(%rbp),%eax
  add    $0x46,%eax
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x4,-0x4(%rbp)
  jle    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D18: Random chars :

tool: D4: %c, 

assistant: ```c
int main() {
  char ch;
  int i;
  printf("Random chars :\n");
  for (i = 1; i < 5; i++) {
    ch = 70 + i;
    printf("%c, ", ch);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x47,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x48,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x49,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4a,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D4
datatype: string

tool: D0: Random chars :

tool: D4: %c, 

assistant: ```c
int main() {
  char ch;
  int i;
  printf("Random chars :\n");
  for (i = 1; i < 5; i++) {
    ch = 70 + i;
    printf("%c, ", ch);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  lea    D16(%rip),%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0x47,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x48,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x49,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4a,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string

tool: D18: Random chars :

tool: D16: %c, 

assistant: ```c
int main() {
  char ch;
  int i;
  printf("Random chars :\n");
  for (i = 1; i < 5; i++) {
    ch = 70 + i;
    printf("%c, ", ch);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D2(%rip),%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0x47,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x48,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x49,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4a,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D2
type: string

tool: D0: Random chars :

tool: D2: %c, 

assistant: ```c
int main() {
  char ch;
  int i;
  printf("Random chars :\n");
  for (i = 1; i < 5; i++) {
    ch = 70 + i;
    printf("%c, ", ch);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L100
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <ajust_double@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  ucomisd D100(%rip),%xmm0
  jp     L16
  movsd  -0x8(%rbp),%xmm0
  ucomisd D100(%rip),%xmm0
  je     L13
L16:
  movsd  -0x8(%rbp),%xmm0
  ucomisd D52(%rip),%xmm0
  jp     L12
  movsd  -0x8(%rbp),%xmm0
  ucomisd D52(%rip),%xmm0
  je     L13
L12:
  movsd  -0x8(%rbp),%xmm0
  ucomisd D86(%rip),%xmm0
  jp     L57
  movsd  -0x8(%rbp),%xmm0
  ucomisd D86(%rip),%xmm0
  je     L13
L57:
  movsd  -0x8(%rbp),%xmm0
  ucomisd D38(%rip),%xmm0
  jp     L47
  movsd  -0x8(%rbp),%xmm0
  ucomisd D38(%rip),%xmm0
  je     L13
L47:
  movsd  -0x8(%rbp),%xmm0
  ucomisd D65(%rip),%xmm0
  jp     L104
  movsd  -0x8(%rbp),%xmm0
  ucomisd D65(%rip),%xmm0
  je     L13
L104:
  movsd  -0x8(%rbp),%xmm0
  ucomisd D34(%rip),%xmm0
  jp     L100
  movsd  -0x8(%rbp),%xmm0
  ucomisd D34(%rip),%xmm0
  jne    L100
L13:
  movl   $0x1,-0xc(%rbp)
L100:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D100
data_type: f64
name: unpack_data
arguments: data_label: D52
data_type: f64
name: unpack_data
arguments: data_label: D86
data_type: f64
name: unpack_data
arguments: data_label: D38
data_type: f64
name: unpack_data
arguments: data_label: D65
data_type: f64
name: unpack_data
arguments: data_label: D34
data_type: f64

tool: D100: 0.0073

tool: D52: 0.0094

tool: D86: 0.0115

tool: D38: 0.0074

tool: D65: 0.0095

tool: D34: 0.0116

assistant: ```c
int is_address(id)
double id;
{
  int ret = 0;
  if (id > 0) {
    double tmp;
    tmp = ajust_double(id - (int)id);
    if (tmp == 0.0073 || tmp == 0.0094 || tmp == 0.0115 || tmp == 0.0074 || tmp == 0.0095 || tmp == 0.0116)
      ret = 1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x5,-0x18(%rbp)
  ja     L118
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D11(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L119
  mov    $0x0,%eax
  jmp    L119
  mov    $0x1,%eax
  jmp    L119
  mov    $0x1,%eax
  jmp    L119
  mov    $0x0,%eax
  jmp    L119
  mov    $0x1,%eax
  jmp    L119
L118:
  mov    -0x18(%rbp),%rcx
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x2,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  test   %rdx,%rdx
  je     L107
  lea    -0x2(%rdx),%rax
  cmp    $0x2,%rax
  ja     L90
L107:
  mov    $0x0,%eax
  jmp    L119
L90:
  movq   $0x5,-0x8(%rbp)
  jmp    L49
L156:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L94
  mov    $0x0,%eax
  jmp    L119
L94:
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L36
  mov    $0x0,%eax
  jmp    L119
L36:
  addq   $0x6,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%rax
  imul   %rax,%rax
  cmp    %rax,-0x18(%rbp)
  jae    L156
  mov    $0x1,%eax
L119:
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(unsigned long long n) {
  unsigned long long i;
  switch (n) {
  case 0:
    return 0;
  case 1:
    return 0;
  case 2:
    return 1;
  case 3:
    return 1;
  case 4:
    return 0;
  case 5:
    return 1;
  }
  switch (n % 6) {
  case 0:
  case 2:
  case 3:
  case 4:
    return 0;
  }
  for (i = 5; (i) * (i) <= n; i += 6) {
    if ((n % (i)) == 0)
      return 0;
    if ((n % (i + 2)) == 0)
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x4,%rdi
  je     L23
  ja     L106
  cmp    $0x1,%rdi
  seta   %al
  movzbl %al,%eax
  ret
L106:
  mov    $0x1,%eax
  cmp    $0x5,%rdi
  jne    L30
L41:
  ret
L30:
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  add    %rax,%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  mov    $0x0,%eax
  mov    $0x1d,%esi
  bt     %rdx,%rsi
  jb     L41
  cmp    $0x18,%rdi
  jbe    L59
  movabs $0xcccccccccccccccd,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rdi
  je     L47
  movabs $0x2492492492492493,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rax,%rdx
  shr    $0x2,%rdx
  lea    0x0(,%rdx,8),%rax
  sub    %rdx,%rax
  cmp    %rax,%rdi
  je     L104
  mov    $0x5,%esi
L10:
  mov    %rsi,%rdi
  add    $0x6,%rsi
  mov    %rsi,%rax
  imul   %rsi,%rax
  cmp    %rcx,%rax
  ja     L44
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  test   %rdx,%rdx
  je     L53
  add    $0x8,%rdi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rdi
  test   %rdx,%rdx
  jne    L10
  mov    $0x0,%eax
  jmp    L41
L44:
  mov    $0x1,%eax
  ret
L23:
  mov    $0x0,%eax
  ret
L59:
  mov    $0x1,%eax
  ret
L47:
  mov    $0x0,%eax
  ret
L104:
  mov    $0x0,%eax
  ret
L53:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_prime(unsigned long long n) {
  unsigned long long i;
  switch (n) {
  case 0:
    return 0;
  case 1:
    return 0;
  case 2:
    return 1;
  case 3:
    return 1;
  case 4:
    return 0;
  case 5:
    return 1;
  }
  switch (n % 6) {
  case 0:
  case 2:
  case 3:
  case 4:
    return 0;
  }
  for (i = 5; (i) * (i) <= n; i += 6) {
    if ((n % (i)) == 0)
      return 0;
    if ((n % (i + 2)) == 0)
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_prime>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x5,%rdi
  ja     L79
  lea    D4(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L79:
  mov    %rdi,%rax
  mov    $0xffffffffffffffe2,%rsi
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  mov    %rdi,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  xor    %eax,%eax
  bt     %rdx,%rsi
  jae    L85
  cmp    $0x18,%rdi
  jbe    L22
  movabs $0xcccccccccccccccd,%rdx
  movabs $0x3333333333333333,%rsi
  imul   %rdi,%rdx
  cmp    %rsi,%rdx
  jbe    L85
  movabs $0x6db6db6db6db6db7,%rdx
  movabs $0x2492492492492492,%rsi
  imul   %rdi,%rdx
  cmp    %rsi,%rdx
  jbe    L85
  mov    $0x5,%esi
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L50:
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rsi
  test   %rdx,%rdx
  je     L58
  add    $0x8,%rdi
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rdi
  test   %rdx,%rdx
  je     L58
L4:
  mov    %rsi,%rdi
  add    $0x6,%rsi
  mov    %rsi,%rax
  imul   %rsi,%rax
  cmp    %rcx,%rax
  jbe    L50
L22:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  xor    %eax,%eax
L85:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: 

assistant: ```c
int is_prime(unsigned long long n) {
  unsigned long long i;
  switch (n) {
  case 0:
    return 0;
  case 1:
    return 0;
  case 2:
    return 1;
  case 3:
    return 1;
  case 4:
    return 0;
  case 5:
    return 1;
  }
  switch (n % 6) {
  case 0:
  case 2:
  case 3:
  case 4:
    return 0;
  }
  for (i = 5; (i) * (i) <= n; i += 6) {
    if ((n % (i)) == 0)
      return 0;
    if ((n % (i + 2)) == 0)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_prime>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x5,%rdi
  ja     L72
  lea    D7(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L72:
  mov    %rdi,%rax
  mov    $0xffffffffffffffe2,%rsi
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  mov    %rdi,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  xor    %eax,%eax
  bt     %rdx,%rsi
  jae    L64
  cmp    $0x18,%rdi
  jbe    L49
  movabs $0xcccccccccccccccd,%rdx
  movabs $0x3333333333333333,%rsi
  imul   %rdi,%rdx
  cmp    %rsi,%rdx
  jbe    L64
  movabs $0x6db6db6db6db6db7,%rdx
  movabs $0x2492492492492492,%rsi
  imul   %rdi,%rdx
  cmp    %rsi,%rdx
  jbe    L64
  mov    $0x5,%esi
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rsi
  test   %rdx,%rdx
  je     L59
  add    $0x8,%rdi
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rdi
  test   %rdx,%rdx
  je     L59
L7:
  mov    %rsi,%rdi
  add    $0x6,%rsi
  mov    %rsi,%rax
  imul   %rsi,%rax
  cmp    %rcx,%rax
  jbe    L16
L49:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
L64:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: 

assistant: ```c
int is_prime(unsigned long long n) {
  unsigned long long i;
  switch (n) {
  case 0:
    return 0;
  case 1:
    return 0;
  case 2:
    return 1;
  case 3:
    return 1;
  case 4:
    return 0;
  case 5:
    return 1;
  }
  switch (n % 6) {
  case 0:
  case 2:
  case 3:
  case 4:
    return 0;
  }
  for (i = 5; (i) * (i) <= n; i += 6) {
    if ((n % (i)) == 0)
      return 0;
    if ((n % (i + 2)) == 0)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<register_write_rs690>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1ff,%eax
  or     $0x2,%ah
  mov    %eax,%esi
  mov    $0x78,%edi
  call   <register_write@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x7c,%edi
  call   <register_write@plt>
  mov    $0x7f,%esi
  mov    $0x78,%edi
  call   <register_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void register_write_rs690(unsigned int key, unsigned int val) {
  register_write(0x78, (key & 0x1ff) | (1 << 9));
  register_write(0x7c, val);
  register_write(0x78, 0x7f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<register_write_rs690>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  and    $0x1ff,%edi
  mov    %edi,%esi
  or     $0x200,%esi
  mov    $0x78,%edi
  call   <register_write@plt>
  mov    %ebx,%esi
  mov    $0x7c,%edi
  call   <register_write@plt>
  mov    $0x7f,%esi
  mov    $0x78,%edi
  call   <register_write@plt>
  pop    %rbx
  ret
```

assistant: ```c
void register_write_rs690(unsigned int key, unsigned int val) {
  register_write(0x78, (key & 0x1ff) | (1 << 9));
  register_write(0x7c, val);
  register_write(0x78, 0x7f);
}
```
user: What is the c source code of the assembly code below?

```asm
<register_write_rs690>:
  endbr64
  push   %rbp
  and    $0x1ff,%edi
  mov    %esi,%ebp
  mov    %edi,%esi
  mov    $0x78,%edi
  or     $0x200,%esi
  call   <register_write@plt>
  mov    %ebp,%esi
  mov    $0x7c,%edi
  call   <register_write@plt>
  mov    $0x7f,%esi
  mov    $0x78,%edi
  pop    %rbp
  jmp    1050 <register_write@plt>
```

assistant: ```c
void register_write_rs690(unsigned int key, unsigned int val) {
  register_write(0x78, (key & 0x1ff) | (1 << 9));
  register_write(0x7c, val);
  register_write(0x78, 0x7f);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<register_write_rs690>:
  endbr64
  push   %rbp
  and    $0x1ff,%edi
  mov    %esi,%ebp
  mov    %edi,%esi
  mov    $0x78,%edi
  or     $0x200,%esi
  call   <register_write@plt>
  mov    %ebp,%esi
  mov    $0x7c,%edi
  call   <register_write@plt>
  mov    $0x7f,%esi
  mov    $0x78,%edi
  pop    %rbp
  jmp    1050 <register_write@plt>
```

assistant: ```c
void register_write_rs690(unsigned int key, unsigned int val) {
  register_write(0x78, (key & 0x1ff) | (1 << 9));
  register_write(0x7c, val);
  register_write(0x78, 0x7f);
}
```