ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  lea    0x8(%rsp),%r13
  mov    %rbp,%rbx
  lea    D0(%rip),%r12
L11:
  lea    0x46(%rbp),%eax
  sub    %ebx,%eax
  mov    %al,(%rbx)
  lea    0x3(%rsp),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: %s


assistant: ```c
int main() {
  int a = 'A';
  int b = 'F';
  int arr_count = b - a;
  char arr[arr_count];
  for (int i = 0; i < arr_count; i++) {
    arr[i] = b - i;
    printf("%s\n", arr);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  lea    0x8(%rsp),%r14
  mov    %rbp,%rbx
  lea    0x46(%rbp),%r12d
L4:
  mov    %r12d,%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %ebx,%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L4
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: %s


assistant: ```c
int main() {
  int a = 'A';
  int b = 'F';
  int arr_count = b - a;
  char arr[arr_count];
  for (int i = 0; i < arr_count; i++) {
    arr[i] = b - i;
    printf("%s\n", arr);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  lea    0x8(%rsp),%r14
  mov    %rbp,%rbx
  lea    0x46(%rbp),%r12d
L13:
  mov    %r12d,%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %ebx,%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: %s


assistant: ```c
int main() {
  int a = 'A';
  int b = 'F';
  int arr_count = b - a;
  char arr[arr_count];
  for (int i = 0; i < arr_count; i++) {
    arr[i] = b - i;
    printf("%s\n", arr);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ipow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L2
L13:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L1
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L1:
  sarl   -0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x14(%rbp)
L2:
  cmpl   $0x0,-0x18(%rbp)
  jne    L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ipow(int base, int exp) {
  int value = 1;
  while (exp) {
    if (exp & 1) {
      value *= base;
    }
    exp >>= 1;
    base *= base;
  }
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipow>:
  endbr64
  test   %esi,%esi
  je     L14
  mov    $0x1,%eax
  jmp    L49
L4:
  imul   %edi,%edi
  sar    %esi
  je     L28
L49:
  test   $0x1,%sil
  je     L4
  imul   %edi,%eax
  jmp    L4
L28:
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ipow(int base, int exp) {
  int value = 1;
  while (exp) {
    if (exp & 1) {
      value *= base;
    }
    exp >>= 1;
    base *= base;
  }
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ipow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L28
  nopl   (%rax)
L24:
  test   $0x1,%sil
  je     L18
  imul   %edi,%eax
L18:
  imul   %edi,%edi
  sar    %esi
  jne    L24
  ret
  nopl   0x0(%rax)
L28:
  ret
```

assistant: ```c
int ipow(int base, int exp) {
  int value = 1;
  while (exp) {
    if (exp & 1) {
      value *= base;
    }
    exp >>= 1;
    base *= base;
  }
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ipow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L11
  nopl   (%rax)
L26:
  test   $0x1,%sil
  je     L6
  imul   %edi,%eax
L6:
  imul   %edi,%edi
  sar    %esi
  jne    L26
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
int ipow(int base, int exp) {
  int value = 1;
  while (exp) {
    if (exp & 1) {
      value *= base;
    }
    exp >>= 1;
    base *= base;
  }
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__mp_logtwo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L6
L26:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
  shrq   -0x18(%rbp)
L6:
  cmpq   $0x0,-0x18(%rbp)
  jne    L26
  cmpb   $0x0,-0x1(%rbp)
  je     L19
  movzbl -0x1(%rbp),%eax
  sub    $0x1,%eax
  jmp    L34
L19:
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char __mp_logtwo(unsigned long n) {
  unsigned char l;
  for (l = 0; n > 0; l++, n >>= 1)
    ;
  return (unsigned char)((l == 0) ? 0 : l - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<__mp_logtwo>:
  endbr64
  test   %rdi,%rdi
  je     L4
  mov    $0x0,%eax
L12:
  mov    %eax,%edx
  add    $0x1,%eax
  shr    %rdi
  jne    L12
  test   %al,%al
  cmovne %edx,%eax
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned char __mp_logtwo(unsigned long n) {
  unsigned char l;
  for (l = 0; n > 0; l++, n >>= 1)
    ;
  return (unsigned char)((l == 0) ? 0 : l - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__mp_logtwo>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L19
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %eax,%edx
  add    $0x1,%eax
  shr    %rdi
  jne    L3
  test   %al,%al
  cmovne %edx,%eax
  ret
L19:
  ret
```

assistant: ```c
unsigned char __mp_logtwo(unsigned long n) {
  unsigned char l;
  for (l = 0; n > 0; l++, n >>= 1)
    ;
  return (unsigned char)((l == 0) ? 0 : l - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__mp_logtwo>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L11
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %eax,%edx
  add    $0x1,%eax
  shr    %rdi
  jne    L0
  test   %al,%al
  cmovne %edx,%eax
  ret
L11:
  ret
```

assistant: ```c
unsigned char __mp_logtwo(unsigned long n) {
  unsigned char l;
  for (l = 0; n > 0; l++, n >>= 1)
    ;
  return (unsigned char)((l == 0) ? 0 : l - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tracef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void tracef(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tracef>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%edi
  call   <va_end@plt>
  pop    %rbx
  ret
```

assistant: ```c
void tracef(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tracef>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %rdi,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  ret
```

assistant: ```c
void tracef(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tracef>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %rdi,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  ret
```

assistant: ```c
void tracef(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mbox_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L3
  lea    D46(%rip),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%edx
  lea    D46(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L3:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D46
type: string
name: read_data
arguments: label: D31
type: string
name: read_data
arguments: label: D10
type: string

tool: D46: char_dev

tool: D31: Can't open device file: %s


tool: D10: Try creating a device file with: sudo mknod %s c %d 0


assistant: ```c
int mbox_open() {
  int file_desc;
  file_desc = open("char_dev", 0);
  if (file_desc < 0) {
    printf("Can't open device file: %s\n", "char_dev");
    printf("Try creating a device file with: sudo mknod %s c %d 0\n", "char_dev", 100);
    exit(-1);
  }
  return file_desc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mbox_open>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D32(%rip),%rdi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L11
L18:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    D32(%rip),%rbp
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%edx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L18
```

tool_calls: name: read_data
arguments: label: D32
type_infered: string
name: read_data
arguments: label: D9
type_infered: string
name: read_data
arguments: label: D7
type_infered: string

tool: D32: char_dev

tool: D9: Can't open device file: %s


tool: D7: Try creating a device file with: sudo mknod %s c %d 0


assistant: ```c
int mbox_open() {
  int file_desc;
  file_desc = open("char_dev", 0);
  if (file_desc < 0) {
    printf("Can't open device file: %s\n", "char_dev");
    printf("Try creating a device file with: sudo mknod %s c %d 0\n", "char_dev", 100);
    exit(-1);
  }
  return file_desc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mbox_open>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  lea    D20(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L2
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x64,%edx
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D24
type: string
name: parse_data
arguments: data_label: D28
type: string

tool: D20: char_dev

tool: D24: Can't open device file: %s


tool: D28: Try creating a device file with: sudo mknod %s c %d 0


assistant: ```c
int mbox_open() {
  int file_desc;
  file_desc = open("char_dev", 0);
  if (file_desc < 0) {
    printf("Can't open device file: %s\n", "char_dev");
    printf("Try creating a device file with: sudo mknod %s c %d 0\n", "char_dev", 100);
    exit(-1);
  }
  return file_desc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mbox_open>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L4
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L4:
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x64,%edx
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D23
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D12: char_dev

tool: D23: Can't open device file: %s


tool: D13: Try creating a device file with: sudo mknod %s c %d 0


assistant: ```c
int mbox_open() {
  int file_desc;
  file_desc = open("char_dev", 0);
  if (file_desc < 0) {
    printf("Can't open device file: %s\n", "char_dev");
    printf("Try creating a device file with: sudo mknod %s c %d 0\n", "char_dev", 100);
    exit(-1);
  }
  return file_desc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<border_clr_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void border_clr_mask(volatile uint32_t reg, uint32_t mask) {
  *(&reg) &= ~mask;
  *(&reg) &= ~mask;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<border_clr_mask>:
  endbr64
  mov    %edi,-0x4(%rsp)
  mov    %esi,-0x8(%rsp)
  mov    -0x8(%rsp),%eax
  mov    -0x4(%rsp),%edx
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x8(%rsp),%eax
  mov    -0x4(%rsp),%edx
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x4(%rsp)
  ret
```

assistant: ```c
void border_clr_mask(volatile uint32_t reg, uint32_t mask) {
  *(&reg) &= ~mask;
  *(&reg) &= ~mask;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<border_clr_mask>:
  endbr64
  mov    %edi,-0x4(%rsp)
  mov    %esi,-0x8(%rsp)
  mov    -0x8(%rsp),%eax
  mov    -0x4(%rsp),%edx
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x8(%rsp),%eax
  mov    -0x4(%rsp),%edx
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x4(%rsp)
  ret
```

assistant: ```c
void border_clr_mask(volatile uint32_t reg, uint32_t mask) {
  *(&reg) &= ~mask;
  *(&reg) &= ~mask;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cumprod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L11:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  lea    0x0(,%rdx,4),%rsi
  mov    -0x18(%rbp),%rdx
  add    %rsi,%rdx
  imul   %ecx,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jbe    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cumprod(unsigned *const out, const unsigned *const v, unsigned n) {
  unsigned i;
  out[0] = 1;
  for (i = 1; i <= n; ++i)
    out[i] = out[i - 1] * v[i - 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cumprod>:
  endbr64
  movl   $0x1,(%rdi)
  test   %edx,%edx
  je     L11
  mov    $0x1,%eax
L19:
  lea    -0x1(%rax),%r8d
  mov    %eax,%r9d
  mov    (%rdi,%r8,4),%ecx
  imul   (%rsi,%r8,4),%ecx
  mov    %ecx,(%rdi,%r9,4)
  add    $0x1,%eax
  cmp    %eax,%edx
  jae    L19
L11:
  ret
```

assistant: ```c
void cumprod(unsigned *const out, const unsigned *const v, unsigned n) {
  unsigned i;
  out[0] = 1;
  for (i = 1; i <= n; ++i)
    out[i] = out[i - 1] * v[i - 1];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cumprod>:
  endbr64
  movl   $0x1,(%rdi)
  test   %edx,%edx
  je     L26
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  mov    $0x1,%eax
  xor    %r9d,%r9d
  jmp    L17
L3:
  mov    %r8d,%r9d
  mov    (%rdi,%r9,4),%ecx
L17:
  imul   (%rsi,%r9,4),%ecx
  mov    %eax,%r10d
  add    $0x1,%eax
  add    $0x1,%r8d
  mov    %ecx,(%rdi,%r10,4)
  cmp    %eax,%edx
  jae    L3
L26:
  ret
```

assistant: ```c
void cumprod(unsigned *const out, const unsigned *const v, unsigned n) {
  unsigned i;
  out[0] = 1;
  for (i = 1; i <= n; ++i)
    out[i] = out[i - 1] * v[i - 1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cumprod>:
  endbr64
  movl   $0x1,(%rdi)
  test   %edx,%edx
  je     L28
  mov    (%rsi),%eax
  mov    $0x1,%r8d
  mov    %eax,0x4(%rdi)
  mov    $0x2,%eax
  cmp    $0x1,%edx
  je     L28
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r8d,%r9d
  mov    %eax,%r10d
  add    $0x1,%eax
  add    $0x1,%r8d
  mov    (%rsi,%r9,4),%ecx
  imul   (%rdi,%r9,4),%ecx
  mov    %ecx,(%rdi,%r10,4)
  cmp    %eax,%edx
  jae    L0
L28:
  ret
```

assistant: ```c
void cumprod(unsigned *const out, const unsigned *const v, unsigned n) {
  unsigned i;
  out[0] = 1;
  for (i = 1; i <= n; ++i)
    out[i] = out[i - 1] * v[i - 1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rearValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L8
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L3
L8:
  mov    $0xff676981,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int rearValue(int Q[], int *front, int *rear) {
  if (*rear != -1)
    return Q[*rear];
  else
    return -9999999;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rearValue>:
  endbr64
  mov    (%rdx),%eax
  cmp    $0xffffffff,%eax
  je     L3
  cltq
  mov    (%rdi,%rax,4),%eax
  ret
L3:
  mov    $0xff676981,%eax
  ret
```

assistant: ```c
int rearValue(int Q[], int *front, int *rear) {
  if (*rear != -1)
    return Q[*rear];
  else
    return -9999999;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rearValue>:
  endbr64
  movslq (%rdx),%rax
  cmp    $0xffffffff,%eax
  je     L2
  mov    (%rdi,%rax,4),%eax
  ret
L2:
  mov    $0xff676981,%eax
  ret
```

assistant: ```c
int rearValue(int Q[], int *front, int *rear) {
  if (*rear != -1)
    return Q[*rear];
  else
    return -9999999;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rearValue>:
  endbr64
  movslq (%rdx),%rax
  cmp    $0xffffffff,%eax
  je     L9
  mov    (%rdi,%rax,4),%eax
  ret
L9:
  mov    $0xff676981,%eax
  ret
```

assistant: ```c
int rearValue(int Q[], int *front, int *rear) {
  if (*rear != -1)
    return Q[*rear];
  else
    return -9999999;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shellsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L37:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L37
  jmp    L32
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <insertionsortinc@plt>
L32:
  cmpl   $0x1,-0x4(%rbp)
  jg     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void shellsort(long *array, int length) {
  int increment = 1;
  while (increment < length) {
    increment = increment * 3 + 1;
  }
  while (increment > 1) {
    increment /= 3;
    insertionsortinc(array, length, increment);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shellsort>:
  endbr64
  cmp    $0x1,%esi
  jle    L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    $0x1,%ebx
L28:
  lea    0x1(%rbx,%rbx,2),%ebx
  cmp    %ebx,%ebp
  jg     L28
L11:
  mov    %ebx,%r12d
  movslq %ebx,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%ebx
  sub    %ebx,%edx
  mov    %edx,%ebx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <insertionsortinc@plt>
  cmp    $0x5,%r12d
  jg     L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

assistant: ```c
void shellsort(long *array, int length) {
  int increment = 1;
  while (increment < length) {
    increment = increment * 3 + 1;
  }
  while (increment > 1) {
    increment /= 3;
    insertionsortinc(array, length, increment);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shellsort>:
  endbr64
  cmp    $0x1,%esi
  jle    L17
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L11:
  lea    0x1(%rbx,%rbx,2),%ebx
  cmp    %ebx,%r13d
  jg     L11
  nopl   0x0(%rax)
L8:
  movslq %ebx,%rbx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %rbx,%rbp
  imul   $0x55555556,%rbx,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rbx
  sub    %eax,%ebx
  mov    %ebx,%edx
  call   <insertionsortinc@plt>
  cmp    $0x5,%ebp
  jg     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L17:
  ret
```

assistant: ```c
void shellsort(long *array, int length) {
  int increment = 1;
  while (increment < length) {
    increment = increment * 3 + 1;
  }
  while (increment > 1) {
    increment /= 3;
    insertionsortinc(array, length, increment);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shellsort>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L0:
  lea    0x1(%rbx,%rbx,2),%ebx
  cmp    %ebx,%r13d
  jg     L0
  nopl   0x0(%rax)
L9:
  movslq %ebx,%rbx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %rbx,%rbp
  imul   $0x55555556,%rbx,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rbx
  sub    %eax,%ebx
  mov    %ebx,%edx
  call   <insertionsortinc@plt>
  cmp    $0x5,%ebp
  jg     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L15:
  ret
```

assistant: ```c
void shellsort(long *array, int length) {
  int increment = 1;
  while (increment < length) {
    increment = increment * 3 + 1;
  }
  while (increment > 1) {
    increment /= 3;
    insertionsortinc(array, length, increment);
  }
}
```