ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<update_sum2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void update_sum2(double *beta, double *sum2, int n) {
  int i;
  for (i = 0; i < n; i++)
    sum2[i] += (beta[i] * beta[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<update_sum2>:
  endbr64
  test   %edx,%edx
  jle    L16
  mov    %edx,%edx
  mov    $0x0,%eax
L3:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L16:
  ret
```

assistant: ```c
void update_sum2(double *beta, double *sum2, int n) {
  int i;
  for (i = 0; i < n; i++)
    sum2[i] += (beta[i] * beta[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<update_sum2>:
  endbr64
  test   %edx,%edx
  jle    L6
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L0:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L0
L6:
  ret
```

assistant: ```c
void update_sum2(double *beta, double *sum2, int n) {
  int i;
  for (i = 0; i < n; i++)
    sum2[i] += (beta[i] * beta[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<update_sum2>:
  endbr64
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L53
  lea    0x8(%rdi),%rax
  cmp    %rax,%rsi
  je     L52
  cmp    $0x1,%edx
  je     L52
  mov    %edx,%esi
  xor    %eax,%eax
  shr    %esi
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L8:
  movupd (%rdi,%rax,1),%xmm0
  movupd (%rcx,%rax,1),%xmm2
  mulpd  %xmm0,%xmm0
  addpd  %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L8
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L53
  movsd  (%rdi,%rax,8),%xmm0
  lea    (%rcx,%rax,8),%rdx
  mulsd  %xmm0,%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  ret
  nop
L52:
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L14:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L14
L53:
  ret
```

assistant: ```c
void update_sum2(double *beta, double *sum2, int n) {
  int i;
  for (i = 0; i < n; i++)
    sum2[i] += (beta[i] * beta[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x118(%rbp)
  jmp    L10
L42:
  movl   $0x0,-0x114(%rbp)
  jmp    L12
L5:
  mov    -0x118(%rbp),%eax
  imul   -0x114(%rbp),%eax
  mov    -0x114(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x118(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %eax,-0x110(%rbp,%rdx,4)
  mov    -0x114(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x118(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    -0x110(%rbp,%rax,4),%ecx
  mov    -0x114(%rbp),%edx
  mov    -0x118(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x114(%rbp)
L12:
  cmpl   $0x7,-0x114(%rbp)
  jle    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x118(%rbp)
L10:
  cmpl   $0x7,-0x118(%rbp)
  jle    L42
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D10
type: string
name: parse_data
arguments: label: D4
type: string

tool: D10: Array Indices:

tool: D4: [%d][%d]=%d 

assistant: ```c
int main() {
  int x;
  int y;
  int array[8][8];
  printf("Array Indices:\n");
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      array[x][y] = x * y;
      printf("[%d][%d]=%d ", x, y, array[x][y]);
    }
    printf("\n");
  }
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r12d
  lea    D17(%rip),%r14
L7:
  mov    %r12d,%r13d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L12:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r13d,%ebp
  cmp    $0x8,%ebx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    $0x8,%r12d
  jne    L7
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D5: Array Indices:

tool: D17: [%d][%d]=%d 

assistant: ```c
int main() {
  int x;
  int y;
  int array[8][8];
  printf("Array Indices:\n");
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      array[x][y] = x * y;
      printf("[%d][%d]=%d ", x, y, array[x][y]);
    }
    printf("\n");
  }
  getchar();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%rdi
  lea    D3(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopl   0x0(%rax)
L1:
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L6:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %r12d,%ebp
  call   <printf@plt>
  cmp    $0x8,%ebx
  jne    L6
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0x8,%r12d
  jne    L1
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: D10: Array Indices:

tool: D3: [%d][%d]=%d 

assistant: ```c
int main() {
  int x;
  int y;
  int array[8][8];
  printf("Array Indices:\n");
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      array[x][y] = x * y;
      printf("[%d][%d]=%d ", x, y, array[x][y]);
    }
    printf("\n");
  }
  getchar();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rdi
  lea    D10(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopl   0x0(%rax)
L1:
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %r12d,%ebp
  call   <printf@plt>
  cmp    $0x8,%ebx
  jne    L8
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0x8,%r12d
  jne    L1
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string

tool: D5: Array Indices:

tool: D10: [%d][%d]=%d 

assistant: ```c
int main() {
  int x;
  int y;
  int array[8][8];
  printf("Array Indices:\n");
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      array[x][y] = x * y;
      printf("[%d][%d]=%d ", x, y, array[x][y]);
    }
    printf("\n");
  }
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <print_diagonal@plt>
  mov    $0x2,%edi
  call   <print_diagonal@plt>
  mov    $0xa,%edi
  call   <print_diagonal@plt>
  mov    $0xfffffffc,%edi
  call   <print_diagonal@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  print_diagonal(0);
  print_diagonal(2);
  print_diagonal(10);
  print_diagonal(-4);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <print_diagonal@plt>
  mov    $0x2,%edi
  call   <print_diagonal@plt>
  mov    $0xa,%edi
  call   <print_diagonal@plt>
  mov    $0xfffffffc,%edi
  call   <print_diagonal@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_diagonal(0);
  print_diagonal(2);
  print_diagonal(10);
  print_diagonal(-4);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <print_diagonal@plt>
  mov    $0x2,%edi
  call   <print_diagonal@plt>
  mov    $0xa,%edi
  call   <print_diagonal@plt>
  mov    $0xfffffffc,%edi
  call   <print_diagonal@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_diagonal(0);
  print_diagonal(2);
  print_diagonal(10);
  print_diagonal(-4);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <print_diagonal@plt>
  mov    $0x2,%edi
  call   <print_diagonal@plt>
  mov    $0xa,%edi
  call   <print_diagonal@plt>
  mov    $0xfffffffc,%edi
  call   <print_diagonal@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_diagonal(0);
  print_diagonal(2);
  print_diagonal(10);
  print_diagonal(-4);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calculate_stat_modifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L34
L28:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    $0x3,%edi
  call   <number_bits@plt>
  test   %eax,%eax
  je     L28
  mov    $0x3,%edi
  call   <number_bits@plt>
  test   %eax,%eax
  jne    L6
  negl   -0x4(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L25
  movl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int calculate_stat_modifier(int bonus) {
  int mod;
  mod = 1;
  while (!number_bits(3))
    mod++;
  if (!number_bits(3))
    mod *= -1;
  mod += bonus;
  if (mod == 0)
    mod = 1;
  return mod;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calculate_stat_modifier>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x1,%ebx
  jmp    L7
L19:
  add    $0x1,%ebx
L7:
  mov    $0x3,%edi
  call   <number_bits@plt>
  test   %eax,%eax
  je     L19
  mov    $0x3,%edi
  call   <number_bits@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  neg    %eax
  test   %edx,%edx
  cmove  %eax,%ebx
  mov    %ebx,%eax
  add    %ebp,%eax
  mov    $0x1,%edx
  cmove  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int calculate_stat_modifier(int bonus) {
  int mod;
  mod = 1;
  while (!number_bits(3))
    mod++;
  if (!number_bits(3))
    mod *= -1;
  mod += bonus;
  if (mod == 0)
    mod = 1;
  return mod;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calculate_stat_modifier>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%ebx
L9:
  mov    $0x3,%edi
  call   <number_bits@plt>
  test   %eax,%eax
  je     L5
  mov    $0x3,%edi
  call   <number_bits@plt>
  mov    $0x1,%edx
  mov    %eax,%r8d
  mov    %ebx,%eax
  neg    %eax
  test   %r8d,%r8d
  cmove  %eax,%ebx
  mov    %ebx,%eax
  add    %ebp,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int calculate_stat_modifier(int bonus) {
  int mod;
  mod = 1;
  while (!number_bits(3))
    mod++;
  if (!number_bits(3))
    mod *= -1;
  mod += bonus;
  if (mod == 0)
    mod = 1;
  return mod;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calculate_stat_modifier>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%ebx
L4:
  mov    $0x3,%edi
  call   <number_bits@plt>
  test   %eax,%eax
  je     L2
  mov    $0x3,%edi
  call   <number_bits@plt>
  mov    $0x1,%edx
  mov    %eax,%r8d
  mov    %ebx,%eax
  neg    %eax
  test   %r8d,%r8d
  cmove  %eax,%ebx
  mov    %ebx,%eax
  add    %ebp,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int calculate_stat_modifier(int bonus) {
  int mod;
  mod = 1;
  while (!number_bits(3))
    mod++;
  if (!number_bits(3))
    mod *= -1;
  mod += bonus;
  if (mod == 0)
    mod = 1;
  return mod;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <my_dlopen@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__thinthin_dlsym@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  call   *%rax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D28
type_infered: string

tool: D0: 003-f.wasm

tool: D5: f

tool: D28: f: %d


assistant: ```c
int main(void) {
  void *handle = my_dlopen("003-f.wasm");
  int (*f)(void) = __thinthin_dlsym((long)handle, "f");
  printf("f: %d\n", f());
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <my_dlopen@plt>
  movslq %eax,%rdi
  lea    D5(%rip),%rsi
  mov    $0x0,%eax
  call   <__thinthin_dlsym@plt>
  cltq
  call   *%rax
  mov    %eax,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string
name: disassemble_data
arguments: data_tag: D29
type_guessed: string

tool: D14: 003-f.wasm

tool: D5: f

tool: D29: f: %d


assistant: ```c
int main(void) {
  void *handle = my_dlopen("003-f.wasm");
  int (*f)(void) = __thinthin_dlsym((long)handle, "f");
  printf("f: %d\n", f());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <my_dlopen@plt>
  lea    D20(%rip),%rsi
  movslq %eax,%rdi
  xor    %eax,%eax
  call   <__thinthin_dlsym@plt>
  cltq
  call   *%rax
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string
name: disassemble_data
arguments: data_label: D20
datatype: string
name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D2: 003-f.wasm

tool: D20: f

tool: D7: f: %d


assistant: ```c
int main(void) {
  void *handle = my_dlopen("003-f.wasm");
  int (*f)(void) = __thinthin_dlsym((long)handle, "f");
  printf("f: %d\n", f());
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <my_dlopen@plt>
  lea    D0(%rip),%rsi
  movslq %eax,%rdi
  xor    %eax,%eax
  call   <__thinthin_dlsym@plt>
  cltq
  call   *%rax
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string

tool: D5: 003-f.wasm

tool: D0: f

tool: D17: f: %d


assistant: ```c
int main(void) {
  void *handle = my_dlopen("003-f.wasm");
  int (*f)(void) = __thinthin_dlsym((long)handle, "f");
  printf("f: %d\n", f());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deleteCirListDeque>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <freeCirListDeque@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void deleteCirListDeque(struct cirListDeque *q) {
  assert(q != 0);
  freeCirListDeque(q);
  free(q);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<deleteCirListDeque>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <freeCirListDeque@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void deleteCirListDeque(struct cirListDeque *q) {
  assert(q != 0);
  freeCirListDeque(q);
  free(q);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<deleteCirListDeque>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <freeCirListDeque@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void deleteCirListDeque(struct cirListDeque *q) {
  assert(q != 0);
  freeCirListDeque(q);
  free(q);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deleteCirListDeque>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <freeCirListDeque@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void deleteCirListDeque(struct cirListDeque *q) {
  assert(q != 0);
  freeCirListDeque(q);
  free(q);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find_similar_visual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <DisplayOfScreen@plt>
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <screen_number@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <visual_class@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <visual_depth@plt>
  mov    %eax,-0x18(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  or     %eax,%esi
  lea    -0x3c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <XGetVisualInfo@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L3
  mov    -0x3c(%rbp),%eax
  test   %eax,%eax
  jle    L3
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x38(%rbp)
L3:
  cmpq   $0x0,-0x28(%rbp)
  je     L54
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <XFree@plt>
L54:
  movq   $0x0,-0x28(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L7
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  or     %eax,%esi
  lea    -0x3c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <XGetVisualInfo@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L11
  mov    -0x3c(%rbp),%eax
  test   %eax,%eax
  jle    L11
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x38(%rbp)
L11:
  cmpq   $0x0,-0x28(%rbp)
  je     L52
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <XFree@plt>
L52:
  movq   $0x0,-0x28(%rbp)
L7:
  cmpq   $0x0,-0x38(%rbp)
  jne    L53
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <DefaultVisualOfScreen@plt>
  mov    %rax,-0x38(%rbp)
L53:
  mov    -0x38(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  leave
  ret
```

assistant: ```c
Visual *find_similar_visual(Screen *screen, Visual *old_visual) {
  Display *dpy = DisplayOfScreen(screen);
  XVisualInfo vi_in, *vi_out;
  Visual *result = 0;
  int out_count;
  vi_in.screen = screen_number(screen);
  vi_in.class = visual_class(screen, old_visual);
  vi_in.depth = visual_depth(screen, old_visual);
  vi_out = XGetVisualInfo(dpy, (VisualScreenMask | VisualClassMask | VisualDepthMask), &vi_in, &out_count);
  if (vi_out && out_count > 0)
    result = vi_out[0].visual;
  if (vi_out)
    XFree(vi_out);
  vi_out = 0;
  if (!result) {
    vi_out = XGetVisualInfo(dpy, (VisualScreenMask | VisualClassMask), &vi_in, &out_count);
    if (vi_out && out_count > 0)
      result = vi_out[0].visual;
    if (vi_out)
      XFree(vi_out);
    vi_out = 0;
  }
  if (!result)
    result = DefaultVisualOfScreen(screen);
  return result;
}
```