ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<atoi>:
  endbr64
  mov    %edi,%edx
  mov    %rsi,%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L4:
  movslq %edx,%rax
  mov    %edx,%ecx
  add    $0x1,%r9d
  add    $0x1,%r8
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %edx,%ecx
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r8)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L4
  movslq %r9d,%r9
  movb   $0x0,(%rsi,%r9,1)
  ret
```

assistant: ```c
void atoi(int n, char *str) {
  int sign;
  if ((sign == n) < 0)
    n = -n;
  int i = 0;
  do {
    str[i++] = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    str[i++] = '-';
  str[i] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atoi>:
  endbr64
  mov    %edi,%edx
  mov    %rsi,%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L2:
  movslq %edx,%rax
  mov    %edx,%ecx
  add    $0x1,%r9d
  add    $0x1,%r8
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %edx,%ecx
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r8)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L2
  movslq %r9d,%r9
  movb   $0x0,(%rsi,%r9,1)
  ret
```

assistant: ```c
void atoi(int n, char *str) {
  int sign;
  if ((sign == n) < 0)
    n = -n;
  int i = 0;
  do {
    str[i++] = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    str[i++] = '-';
  str[i] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cdf_ctime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ctime_r@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x20(%rbp),%rax
  jmp    L11
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D9(%rip),%rdx
  mov    $0x1a,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x20(%rbp),%rax
L11:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: *Bad* 0x%16.16llx


assistant: ```c
char *cdf_ctime(const time_t *sec, char *buf) {
  char *ptr = ctime_r(sec, buf);
  if (ptr != NULL)
    return buf;
  (void)snprintf(buf, 26, "*Bad* 0x%16.16llx\n", (long long)*sec);
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cdf_ctime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <ctime_r@plt>
  test   %rax,%rax
  je     L19
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    0x0(%rbp),%rcx
  lea    D4(%rip),%rdx
  mov    $0x1a,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: *Bad* 0x%16.16llx


assistant: ```c
char *cdf_ctime(const time_t *sec, char *buf) {
  char *ptr = ctime_r(sec, buf);
  if (ptr != NULL)
    return buf;
  (void)snprintf(buf, 26, "*Bad* 0x%16.16llx\n", (long long)*sec);
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cdf_ctime>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <ctime_r@plt>
  test   %rax,%rax
  je     L4
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%rcx
  mov    %r12,%rdi
  mov    $0x1a,%esi
  lea    D4(%rip),%rdx
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: *Bad* 0x%16.16llx


assistant: ```c
char *cdf_ctime(const time_t *sec, char *buf) {
  char *ptr = ctime_r(sec, buf);
  if (ptr != NULL)
    return buf;
  (void)snprintf(buf, 26, "*Bad* 0x%16.16llx\n", (long long)*sec);
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cdf_ctime>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <ctime_r@plt>
  test   %rax,%rax
  je     L5
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%rcx
  mov    %r12,%rdi
  mov    $0x1a,%esi
  lea    D1(%rip),%rdx
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: *Bad* 0x%16.16llx


assistant: ```c
char *cdf_ctime(const time_t *sec, char *buf) {
  char *ptr = ctime_r(sec, buf);
  if (ptr != NULL)
    return buf;
  (void)snprintf(buf, 26, "*Bad* 0x%16.16llx\n", (long long)*sec);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<engine_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <block_signals@plt>
  mov    $0x18,%esi
  mov    $0x50,%edi
  call   <engine_screen_init@plt>
  mov    $0x0,%eax
  call   <engine_windows_init@plt>
  mov    $0x0,%edi
  call   <engine_keymap@plt>
  mov    $0x0,%eax
  call   <restore_signals@plt>
  mov    $0x0,%eax
  call   <register_signal_handler@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
bool engine_init() {
  block_signals();
  engine_screen_init(80, 24);
  engine_windows_init();
  engine_keymap(NULL);
  restore_signals();
  register_signal_handler();
  return true;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<engine_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <block_signals@plt>
  mov    $0x18,%esi
  mov    $0x50,%edi
  call   <engine_screen_init@plt>
  mov    $0x0,%eax
  call   <engine_windows_init@plt>
  mov    $0x0,%edi
  call   <engine_keymap@plt>
  mov    $0x0,%eax
  call   <restore_signals@plt>
  mov    $0x0,%eax
  call   <register_signal_handler@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool engine_init() {
  block_signals();
  engine_screen_init(80, 24);
  engine_windows_init();
  engine_keymap(NULL);
  restore_signals();
  register_signal_handler();
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<engine_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <block_signals@plt>
  mov    $0x18,%esi
  mov    $0x50,%edi
  call   <engine_screen_init@plt>
  xor    %eax,%eax
  call   <engine_windows_init@plt>
  xor    %edi,%edi
  call   <engine_keymap@plt>
  xor    %eax,%eax
  call   <restore_signals@plt>
  xor    %eax,%eax
  call   <register_signal_handler@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool engine_init() {
  block_signals();
  engine_screen_init(80, 24);
  engine_windows_init();
  engine_keymap(NULL);
  restore_signals();
  register_signal_handler();
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<engine_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <block_signals@plt>
  mov    $0x18,%esi
  mov    $0x50,%edi
  call   <engine_screen_init@plt>
  xor    %eax,%eax
  call   <engine_windows_init@plt>
  xor    %edi,%edi
  call   <engine_keymap@plt>
  xor    %eax,%eax
  call   <restore_signals@plt>
  xor    %eax,%eax
  call   <register_signal_handler@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool engine_init() {
  block_signals();
  engine_screen_init(80, 24);
  engine_windows_init();
  engine_keymap(NULL);
  restore_signals();
  register_signal_handler();
  return true;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<whathappens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getKey@plt>
  cmpl   $0x1,-0x10(%rbp)
  jne    L8
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <winner@plt>
  jmp    L4
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <looser@plt>
L4:
  mov    $0x0,%eax
  call   <sizeY@plt>
  mov    %eax,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <getKeyPrompt@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: 

assistant: ```c
void whathappens(int master[], int turn, int win) {
  getKey();
  if (win == 1)
    winner(turn);
  else
    looser(master);
  getKeyPrompt("", 1, sizeY());
}
```
user: Translate the below assembly code into C programming language:

```asm
<whathappens>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    $0x0,%eax
  call   <getKey@plt>
  cmp    $0x1,%ebx
  je     L11
  mov    %rbp,%rdi
  call   <looser@plt>
L19:
  mov    $0x0,%eax
  call   <sizeY@plt>
  mov    %eax,%edx
  mov    $0x1,%esi
  lea    D0(%rip),%rdi
  call   <getKeyPrompt@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    %r12d,%edi
  call   <winner@plt>
  jmp    L19
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: 

assistant: ```c
void whathappens(int master[], int turn, int win) {
  getKey();
  if (win == 1)
    winner(turn);
  else
    looser(master);
  getKeyPrompt("", 1, sizeY());
}
```
user: What is the c source code of the assembly code below:

```asm
<whathappens>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <getKey@plt>
  cmp    $0x1,%ebx
  je     L14
  mov    %rbp,%rdi
  call   <looser@plt>
L17:
  xor    %eax,%eax
  call   <sizeY@plt>
  pop    %rbx
  pop    %rbp
  mov    $0x1,%esi
  mov    %eax,%edx
  lea    D3(%rip),%rdi
  pop    %r12
  jmp    1090 <getKeyPrompt@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12d,%edi
  call   <winner@plt>
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string

tool: 

assistant: ```c
void whathappens(int master[], int turn, int win) {
  getKey();
  if (win == 1)
    winner(turn);
  else
    looser(master);
  getKeyPrompt("", 1, sizeY());
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<whathappens>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <getKey@plt>
  cmp    $0x1,%ebx
  je     L5
  mov    %rbp,%rdi
  call   <looser@plt>
L14:
  xor    %eax,%eax
  call   <sizeY@plt>
  pop    %rbx
  pop    %rbp
  mov    $0x1,%esi
  mov    %eax,%edx
  lea    D2(%rip),%rdi
  pop    %r12
  jmp    1090 <getKeyPrompt@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%edi
  call   <winner@plt>
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: 

assistant: ```c
void whathappens(int master[], int turn, int win) {
  getKey();
  if (win == 1)
    winner(turn);
  else
    looser(master);
  getKeyPrompt("", 1, sizeY());
}
```
user: What is the c source code of the assembly code below:

```asm
<test_no_clause>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L3:
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0xf,-0x4(%rbp)
  jle    L3
  addl   $0x1,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_no_clause() {
  int i;
#pragma omp target teams distribute parallel for
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for
  ++i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_no_clause>:
  endbr64
  ret
```

assistant: ```c
void test_no_clause() {
  int i;
#pragma omp target teams distribute parallel for
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for
  ++i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_no_clause>:
  endbr64
  ret
```

assistant: ```c
void test_no_clause() {
  int i;
#pragma omp target teams distribute parallel for
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for
  ++i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_no_clause>:
  endbr64
  ret
```

assistant: ```c
void test_no_clause() {
  int i;
#pragma omp target teams distribute parallel for
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for
  ++i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<intersect>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf50,%rsp
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    %ecx,%ebp
  mov    %r8,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1f4,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0xfa0(%rsp),%rdi
  mov    $0x1f4,%ecx
  rep stos %rax,%es:(%rdi)
  cmp    %ebp,%esi
  mov    %ebp,%edi
  cmovle %esi,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r10
  test   %r12d,%r12d
  jle    L75
  mov    %r14,%rax
  lea    -0x1(%r12),%edx
  lea    0x4(%r14,%rdx,4),%rcx
L13:
  movslq (%rax),%rdx
  addl   $0x1,(%rsp,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L13
L75:
  test   %ebp,%ebp
  jle    L4
  mov    %r13,%rax
  lea    -0x1(%rbp),%edx
  lea    0x4(%r13,%rdx,4),%rcx
L76:
  movslq (%rax),%rdx
  addl   $0x1,0xfa0(%rsp,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L76
L4:
  mov    %rsp,%r11
  lea    0xfa0(%rsp),%rsi
  mov    $0x0,%r8d
  jmp    L100
L27:
  add    $0x1,%r8d
  add    $0x4,%r11
  add    $0x4,%rsi
  cmp    $0x3e8,%r8d
  je     L95
L100:
  mov    %r11,%r9
  mov    (%r11),%ecx
  test   %ecx,%ecx
  je     L27
L63:
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L27
  mov    (%rbx),%edx
  lea    0x1(%rdx),%edi
  mov    %edi,(%rbx)
  movslq %edx,%rdx
  mov    %r8d,(%r10,%rdx,4)
  sub    $0x1,%ecx
  mov    %ecx,(%r9)
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  test   %ecx,%ecx
  jne    L63
  jmp    L27
L95:
  mov    0x1f48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    %r10,%rax
  add    $0x1f50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *intersect(int *nums1, int nums1Size, int *nums2, int nums2Size, int *returnSize) {
  int arr1[1000] = {0};
  int arr2[1000] = {0};
  int min = nums1Size > nums2Size ? nums2Size : nums1Size;
  int i;
  int *ret = (int *)malloc(sizeof(int) * min);
  for (i = 0; i < nums1Size; i++) {
    arr1[nums1[i]]++;
  }
  for (i = 0; i < nums2Size; i++) {
    arr2[nums2[i]]++;
  }
  for (i = 0; i < 1000; i++) {
    while (arr1[i] != 0 && arr2[i] != 0) {
      ret[(*returnSize)++] = i;
      arr1[i]--;
      arr2[i]--;
    }
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<intersect>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  mov    %r8,%rbx
  lea    0x10(%rsp),%r8
  mov    %ecx,%r13d
  mov    %rdi,%r12
  mov    $0x1f4,%ecx
  mov    %r8,%rdi
  cmp    %r13d,%esi
  lea    0xfb0(%rsp),%r15
  mov    %esi,%r14d
  mov    %r8,0x8(%rsp)
  mov    %rdx,%rbp
  rep stos %rax,%es:(%rdi)
  mov    $0x1f4,%ecx
  mov    %r15,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r13d,%edi
  cmovle %esi,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  test   %r14d,%r14d
  mov    0x8(%rsp),%r8
  mov    %rax,%r11
  jle    L80
  lea    -0x1(%r14),%edx
  mov    %r12,%rax
  lea    0x4(%r12,%rdx,4),%rcx
L66:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,0x10(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L66
  mov    0x10(%rsp),%eax
L2:
  test   %r13d,%r13d
  jle    L42
  lea    -0x1(%r13),%ecx
  mov    %rbp,%rdx
  lea    0x4(%rbp,%rcx,4),%rsi
L20:
  movslq (%rdx),%rcx
  add    $0x4,%rdx
  addl   $0x1,0xfb0(%rsp,%rcx,4)
  cmp    %rsi,%rdx
  jne    L20
L42:
  mov    %r15,%r9
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L109:
  test   %eax,%eax
  je     L87
  mov    (%r9),%esi
  mov    %eax,%r10d
  sub    %esi,%r10d
  sub    %eax,%esi
  jmp    L9
  nopl   0x0(%rax)
L100:
  movslq (%rbx),%rdx
  sub    $0x1,%eax
  mov    %eax,(%r8)
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rbx)
  mov    %edi,(%r11,%rdx,4)
  lea    (%rsi,%rax,1),%edx
  mov    %edx,(%r9)
  je     L87
L9:
  cmp    %r10d,%eax
  jne    L100
L87:
  add    $0x1,%edi
  add    $0x4,%r8
  add    $0x4,%r9
  cmp    $0x3e8,%edi
  je     L53
  mov    (%r8),%eax
  jmp    L109
L53:
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0x1f68,%rsp
  mov    %r11,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L80:
  xor    %eax,%eax
  jmp    L2
L108:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *intersect(int *nums1, int nums1Size, int *nums2, int nums2Size, int *returnSize) {
  int arr1[1000] = {0};
  int arr2[1000] = {0};
  int min = nums1Size > nums2Size ? nums2Size : nums1Size;
  int i;
  int *ret = (int *)malloc(sizeof(int) * min);
  for (i = 0; i < nums1Size; i++) {
    arr1[nums1[i]]++;
  }
  for (i = 0; i < nums2Size; i++) {
    arr2[nums2[i]]++;
  }
  for (i = 0; i < 1000; i++) {
    while (arr1[i] != 0 && arr2[i] != 0) {
      ret[(*returnSize)++] = i;
      arr1[i]--;
      arr2[i]--;
    }
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<intersect>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  mov    %r8,%rbx
  lea    0x10(%rsp),%r8
  mov    %ecx,%r13d
  mov    %rdi,%r12
  mov    $0x1f4,%ecx
  mov    %r8,%rdi
  cmp    %r13d,%esi
  lea    0xfb0(%rsp),%r15
  mov    %esi,%r14d
  mov    %r8,0x8(%rsp)
  mov    %rdx,%rbp
  rep stos %rax,%es:(%rdi)
  mov    $0x1f4,%ecx
  mov    %r15,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r13d,%edi
  cmovle %esi,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  test   %r14d,%r14d
  mov    0x8(%rsp),%r8
  mov    %rax,%r11
  jle    L40
  lea    -0x1(%r14),%edx
  mov    %r12,%rax
  lea    0x4(%r12,%rdx,4),%rcx
L64:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,0x10(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L64
L40:
  test   %r13d,%r13d
  jle    L14
  lea    -0x1(%r13),%edx
  mov    %rbp,%rax
  lea    0x4(%rbp,%rdx,4),%rcx
L75:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,0xfb0(%rsp,%rdx,4)
  cmp    %rax,%rcx
  jne    L75
L14:
  mov    %r15,%r9
  xor    %edi,%edi
L85:
  mov    (%r8),%eax
  test   %eax,%eax
  je     L30
  mov    (%r9),%esi
  mov    %eax,%r10d
  sub    %esi,%r10d
  sub    %eax,%esi
  jmp    L59
  nopl   0x0(%rax)
L32:
  movslq (%rbx),%rdx
  sub    $0x1,%eax
  mov    %eax,(%r8)
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%rbx)
  mov    %edi,(%r11,%rdx,4)
  lea    (%rsi,%rax,1),%edx
  mov    %edx,(%r9)
  je     L30
L59:
  cmp    %r10d,%eax
  jne    L32
L30:
  add    $0x1,%edi
  add    $0x4,%r8
  add    $0x4,%r9
  cmp    $0x3e8,%edi
  jne    L85
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x1f68,%rsp
  mov    %r11,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *intersect(int *nums1, int nums1Size, int *nums2, int nums2Size, int *returnSize) {
  int arr1[1000] = {0};
  int arr2[1000] = {0};
  int min = nums1Size > nums2Size ? nums2Size : nums1Size;
  int i;
  int *ret = (int *)malloc(sizeof(int) * min);
  for (i = 0; i < nums1Size; i++) {
    arr1[nums1[i]]++;
  }
  for (i = 0; i < nums2Size; i++) {
    arr2[nums2[i]]++;
  }
  for (i = 0; i < 1000; i++) {
    while (arr1[i] != 0 && arr2[i] != 0) {
      ret[(*returnSize)++] = i;
      arr1[i]--;
      arr2[i]--;
    }
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<glmGenerateRandomVector3f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rbx
  movsd  D16(%rip),%xmm0
  movapd %xmm0,%xmm1
  mov    D7(%rip),%eax
  movd   %eax,%xmm0
  call   <glmRandomNumberf@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  movsd  D26(%rip),%xmm0
  movapd %xmm0,%xmm1
  mov    D15(%rip),%eax
  movd   %eax,%xmm0
  call   <glmRandomNumberf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  movss  D9(%rip),%xmm0
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <cos@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x14(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  movd   %xmm0,%eax
  mov    -0x28(%rbp),%rdx
  add    $0x4,%rdx
  movd   %eax,%xmm0
  mulss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rdx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D16
type_infered: byte[8]
name: parse_data
arguments: label: D7
type_infered: byte[4]
name: parse_data
arguments: label: D26
type_infered: f64
name: parse_data
arguments: label: D15
type_infered: byte[4]
name: parse_data
arguments: label: D9
type_infered: byte[4]

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D7": [0x00,0x00,0x80,0xbf]}

tool: D26: 6.283185307179586

tool: {"D15": [0x00,0x00,0x00,0x00]}

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmGenerateRandomVector3f(float v[3]) {
  float a, r;
  v[2] = glmRandomNumberf(-1.0f, 1.0f);
  a = glmRandomNumberf(0.0f, 6.283185307179586476925286766559);
  r = sqrt(1.0f - v[2] * v[2]);
  v[0] = r * cos(a);
  v[1] = r * sin(a);
}
```
user: What is the c source code of the assembly code below?

```asm
<glmGenerateRandomVector3f>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  movsd  D1(%rip),%xmm1
  movss  D2(%rip),%xmm0
  call   <glmRandomNumberf@plt>
  movss  %xmm0,0x8(%rbx)
  movsd  D30(%rip),%xmm1
  pxor   %xmm0,%xmm0
  call   <glmRandomNumberf@plt>
  movss  %xmm0,0x8(%rsp)
  movss  0x8(%rbx),%xmm0
  mulss  %xmm0,%xmm0
  movss  D21(%rip),%xmm1
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  call   <sqrt@plt>
  movss  %xmm0,0xc(%rsp)
  movss  0x8(%rsp),%xmm0
  call   <cos@plt>
  mulss  0xc(%rsp),%xmm0
  movss  %xmm0,(%rbx)
  movss  0x8(%rsp),%xmm0
  call   <sin@plt>
  mulss  0xc(%rsp),%xmm0
  movss  %xmm0,0x4(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: byte[8]
name: parse_data
arguments: data_label: D2
type: byte[4]
name: parse_data
arguments: data_label: D30
type: f64
name: parse_data
arguments: data_label: D21
type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D2": [0x00,0x00,0x80,0xbf]}

tool: D30: 6.283185307179586

tool: {"D21": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmGenerateRandomVector3f(float v[3]) {
  float a, r;
  v[2] = glmRandomNumberf(-1.0f, 1.0f);
  a = glmRandomNumberf(0.0f, 6.283185307179586476925286766559);
  r = sqrt(1.0f - v[2] * v[2]);
  v[0] = r * cos(a);
  v[1] = r * sin(a);
}
```