ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rfft4pt>:
  endbr64
  movss  0x4(%rdi),%xmm8
  movss  0x14(%rdi),%xmm0
  movss  0x8(%rdi),%xmm7
  movss  0x18(%rdi),%xmm4
  movaps %xmm8,%xmm9
  movss  (%rdi),%xmm2
  subss  %xmm0,%xmm8
  movss  0x10(%rdi),%xmm6
  addss  %xmm0,%xmm9
  movaps %xmm7,%xmm0
  movss  0xc(%rdi),%xmm5
  movss  0x1c(%rdi),%xmm3
  subss  %xmm4,%xmm0
  movaps %xmm2,%xmm1
  subss  %xmm6,%xmm2
  addss  %xmm6,%xmm1
  movaps %xmm5,%xmm6
  addss  %xmm4,%xmm7
  subss  %xmm3,%xmm6
  movaps %xmm8,%xmm4
  addss  %xmm3,%xmm5
  subss  %xmm0,%xmm8
  addss  %xmm0,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm10
  movaps %xmm9,%xmm11
  subss  %xmm7,%xmm1
  addss  %xmm6,%xmm2
  subss  %xmm6,%xmm3
  movaps %xmm8,%xmm6
  addss  %xmm7,%xmm10
  addss  %xmm5,%xmm11
  subss  %xmm4,%xmm6
  addss  %xmm8,%xmm4
  movss  D9(%rip),%xmm8
  movaps %xmm3,%xmm0
  subss  %xmm2,%xmm3
  subss  %xmm9,%xmm5
  addss  %xmm2,%xmm0
  mulss  %xmm8,%xmm4
  movaps %xmm6,%xmm2
  addss  %xmm6,%xmm6
  mulss  %xmm8,%xmm3
  unpcklps %xmm5,%xmm1
  movaps %xmm4,%xmm8
  subss  %xmm4,%xmm2
  movss  D11(%rip),%xmm4
  addss  %xmm0,%xmm8
  addss  %xmm0,%xmm0
  addss  %xmm3,%xmm2
  addss  %xmm3,%xmm8
  movaps %xmm10,%xmm3
  subss  %xmm11,%xmm10
  addss  %xmm11,%xmm3
  movaps %xmm2,%xmm12
  subss  %xmm6,%xmm2
  subss  %xmm8,%xmm0
  mulss  %xmm4,%xmm12
  movaps %xmm8,%xmm11
  mulss  %xmm4,%xmm11
  unpcklps %xmm10,%xmm3
  mulss  %xmm4,%xmm2
  mulss  %xmm4,%xmm0
  unpcklps %xmm12,%xmm11
  movlhps %xmm11,%xmm3
  unpcklps %xmm2,%xmm0
  movups %xmm3,(%rdi)
  movlhps %xmm0,%xmm1
  movups %xmm1,0x10(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: byte[4]
name: retrieve_data
arguments: label: D11
datatype: f32

tool: {"D9": [0xf3,0x04,0x35,0x3f]}

tool: D11: 0.5

assistant: ```c
void rfft4pt(float *ioptr) {
  float f0r, f0i, f1r, f1i, f2r, f2i, f3r, f3i;
  float t0r, t0i, t1r, t1i;
  float w0r = 1.0 / 1.414213562373095048801688724209698078569;
  const float Two = 2.0;
  const float scale = 0.5;
  f0r = ioptr[0];
  f0i = ioptr[1];
  f1r = ioptr[4];
  f1i = ioptr[5];
  f2r = ioptr[2];
  f2i = ioptr[3];
  f3r = ioptr[6];
  f3i = ioptr[7];
  t0r = f0r + f1r;
  t0i = f0i + f1i;
  f1r = f0r - f1r;
  f1i = f0i - f1i;
  t1r = f2r - f3r;
  t1i = f2i - f3i;
  f2r = f2r + f3r;
  f2i = f2i + f3i;
  f0r = t0r + f2r;
  f0i = t0i + f2i;
  f2r = t0r - f2r;
  f2i = f2i - t0i;
  f3r = f1r - t1i;
  f3i = f1i + t1r;
  f1r = f1r + t1i;
  f1i = f1i - t1r;
  t0r = f0r + f0i;
  t0i = f0r - f0i;
  t1r = f1r + f3r;
  t1i = f1i - f3i;
  f0r = f1i + f3i;
  f0i = f3r - f1r;
  f1r = t1r + w0r * f0r + w0r * f0i;
  f1i = t1i - w0r * f0r + w0r * f0i;
  f3r = Two * t1r - f1r;
  f3i = f1i - Two * t1i;
  ioptr[4] = f2r;
  ioptr[5] = f2i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
  ioptr[2] = scale * f1r;
  ioptr[3] = scale * f1i;
  ioptr[6] = scale * f3r;
  ioptr[7] = scale * f3i;
}
```
user: What is the c source code of the assembly code below?

```asm
<expf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  D38(%rip),%xmm0
  comiss -0x14(%rbp),%xmm0
  jb     L0
  pxor   %xmm0,%xmm0
  jmp    L12
L0:
  movss  -0x14(%rbp),%xmm1
  movss  D60(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x14(%rbp),%xmm1
  movss  D52(%rip),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  movss  D60(%rip),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  movss  D46(%rip),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  -0x8(%rbp),%xmm0
  movss  D41(%rip),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  -0x4(%rbp),%xmm0
  movss  D47(%rip),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  D61(%rip),%xmm0
  mulss  %xmm1,%xmm0
L12:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D38
datatype: byte[4]
name: read_data
arguments: data_label: D60
datatype: byte[4]
name: read_data
arguments: data_label: D52
datatype: byte[4]
name: read_data
arguments: data_label: D46
datatype: byte[4]
name: read_data
arguments: data_label: D41
datatype: byte[4]
name: read_data
arguments: data_label: D47
datatype: byte[4]
name: read_data
arguments: data_label: D61
datatype: byte[4]

tool: {"D38": [0x00,0x00,0x80,0xc0]}

tool: {"D60": [0x00,0x00,0x00,0x40]}

tool: {"D52": [0x00,0x00,0x80,0x3f]}

tool: {"D46": [0x00,0x00,0xc0,0x40]}

tool: {"D41": [0x00,0x00,0xc0,0x41]}

tool: {"D47": [0x00,0x00,0xf0,0x42]}

tool: {"D61": [0x55,0x95,0x0a,0x3e]}

assistant: ```c
float expf(float x) {
  if (x <= -4.f)
    return 0.f;
  x -= -2.f;
  float x2 = x * x;
  float x3 = x2 * x;
  float x4 = x2 * x2;
  float x5 = x2 * x3;
  return 0.1353352832366127f * (1.f + x + x2 / 2.f + x3 / 6.f + x4 / 24.f + x5 / 120.f);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expf>:
  endbr64
  movss  D51(%rip),%xmm1
  comiss %xmm0,%xmm1
  jae    L3
  addss  D62(%rip),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movaps %xmm0,%xmm3
  mulss  %xmm1,%xmm3
  addss  D77(%rip),%xmm0
  movaps %xmm1,%xmm2
  mulss  D72(%rip),%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm3,%xmm2
  divss  D26(%rip),%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm1,%xmm2
  divss  D21(%rip),%xmm2
  addss  %xmm2,%xmm0
  mulss  %xmm3,%xmm1
  divss  D59(%rip),%xmm1
  addss  %xmm1,%xmm0
  mulss  D15(%rip),%xmm0
  ret
L3:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D51
data_type: byte[4]
name: disassemble_data
arguments: data_label: D62
data_type: byte[4]
name: disassemble_data
arguments: data_label: D77
data_type: byte[4]
name: disassemble_data
arguments: data_label: D72
data_type: byte[4]
name: disassemble_data
arguments: data_label: D26
data_type: byte[4]
name: disassemble_data
arguments: data_label: D21
data_type: byte[4]
name: disassemble_data
arguments: data_label: D59
data_type: byte[4]
name: disassemble_data
arguments: data_label: D15
data_type: byte[4]

tool: {"D51": [0x00,0x00,0x80,0xc0]}

tool: {"D62": [0x00,0x00,0x00,0x40]}

tool: {"D77": [0x00,0x00,0x80,0x3f]}

tool: {"D72": [0x00,0x00,0x00,0x3f]}

tool: {"D26": [0x00,0x00,0xc0,0x40]}

tool: {"D21": [0x00,0x00,0xc0,0x41]}

tool: {"D59": [0x00,0x00,0xf0,0x42]}

tool: {"D15": [0x55,0x95,0x0a,0x3e]}

assistant: ```c
float expf(float x) {
  if (x <= -4.f)
    return 0.f;
  x -= -2.f;
  float x2 = x * x;
  float x3 = x2 * x;
  float x4 = x2 * x2;
  float x5 = x2 * x3;
  return 0.1353352832366127f * (1.f + x + x2 / 2.f + x3 / 6.f + x4 / 24.f + x5 / 120.f);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<expf>:
  endbr64
  movss  D47(%rip),%xmm1
  comiss %xmm0,%xmm1
  jae    L0
  addss  D48(%rip),%xmm0
  movss  D59(%rip),%xmm2
  movaps %xmm0,%xmm1
  movaps %xmm0,%xmm3
  mulss  %xmm0,%xmm1
  addss  D72(%rip),%xmm0
  mulss  %xmm1,%xmm2
  mulss  %xmm1,%xmm3
  addss  %xmm2,%xmm0
  movaps %xmm3,%xmm2
  divss  D30(%rip),%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm1,%xmm2
  divss  D17(%rip),%xmm2
  mulss  %xmm3,%xmm1
  addss  %xmm2,%xmm0
  divss  D22(%rip),%xmm1
  addss  %xmm1,%xmm0
  mulss  D35(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D47
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D48
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D59
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D72
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D30
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D17
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D22
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D35
type_guessed: byte[4]

tool: {"D47": [0x00,0x00,0x80,0xc0]}

tool: {"D48": [0x00,0x00,0x00,0x40]}

tool: {"D59": [0x00,0x00,0x00,0x3f]}

tool: {"D72": [0x00,0x00,0x80,0x3f]}

tool: {"D30": [0x00,0x00,0xc0,0x40]}

tool: {"D17": [0x00,0x00,0xc0,0x41]}

tool: {"D22": [0x00,0x00,0xf0,0x42]}

tool: {"D35": [0x55,0x95,0x0a,0x3e]}

assistant: ```c
float expf(float x) {
  if (x <= -4.f)
    return 0.f;
  x -= -2.f;
  float x2 = x * x;
  float x3 = x2 * x;
  float x4 = x2 * x2;
  float x5 = x2 * x3;
  return 0.1353352832366127f * (1.f + x + x2 / 2.f + x3 / 6.f + x4 / 24.f + x5 / 120.f);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expf>:
  endbr64
  movss  D78(%rip),%xmm1
  comiss %xmm0,%xmm1
  jae    L1
  addss  D40(%rip),%xmm0
  movss  D44(%rip),%xmm2
  movaps %xmm0,%xmm1
  movaps %xmm0,%xmm3
  mulss  %xmm0,%xmm1
  addss  D12(%rip),%xmm0
  mulss  %xmm1,%xmm2
  mulss  %xmm1,%xmm3
  addss  %xmm2,%xmm0
  movaps %xmm3,%xmm2
  divss  D67(%rip),%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm1,%xmm2
  divss  D8(%rip),%xmm2
  mulss  %xmm3,%xmm1
  addss  %xmm2,%xmm0
  divss  D45(%rip),%xmm1
  addss  %xmm1,%xmm0
  mulss  D22(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D78
type_guessed: byte[4]
name: read_data
arguments: label: D40
type_guessed: byte[4]
name: read_data
arguments: label: D44
type_guessed: byte[4]
name: read_data
arguments: label: D12
type_guessed: byte[4]
name: read_data
arguments: label: D67
type_guessed: byte[4]
name: read_data
arguments: label: D8
type_guessed: byte[4]
name: read_data
arguments: label: D45
type_guessed: byte[4]
name: read_data
arguments: label: D22
type_guessed: byte[4]

tool: {"D78": [0x00,0x00,0x80,0xc0]}

tool: {"D40": [0x00,0x00,0x00,0x40]}

tool: {"D44": [0x00,0x00,0x00,0x3f]}

tool: {"D12": [0x00,0x00,0x80,0x3f]}

tool: {"D67": [0x00,0x00,0xc0,0x40]}

tool: {"D8": [0x00,0x00,0xc0,0x41]}

tool: {"D45": [0x00,0x00,0xf0,0x42]}

tool: {"D22": [0x55,0x95,0x0a,0x3e]}

assistant: ```c
float expf(float x) {
  if (x <= -4.f)
    return 0.f;
  x -= -2.f;
  float x2 = x * x;
  float x3 = x2 * x;
  float x4 = x2 * x2;
  float x5 = x2 * x3;
  return 0.1353352832366127f * (1.f + x + x2 / 2.f + x3 / 6.f + x4 / 24.f + x5 / 120.f);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <_@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: test of string


assistant: ```c
int main() {
  printf(_("test of string\n"));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <_@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: test of string


assistant: ```c
int main() {
  printf(_("test of string\n"));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <_@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: test of string


assistant: ```c
int main() {
  printf(_("test of string\n"));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <_@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: test of string


assistant: ```c
int main() {
  printf(_("test of string\n"));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hal_uart_putstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  jmp    L36
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hal_uart_putchar@plt>
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  jmp    L38
L6:
  nop
L38:
  leave
  ret
```

assistant: ```c
void hal_uart_putstr(char *str) {
  if (!str)
    return;
  while (*str) {
    hal_uart_putchar(*str);
    str++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<hal_uart_putstr>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L25:
  movsbl %dil,%edi
  call   <hal_uart_putchar@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L25
L17:
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
void hal_uart_putstr(char *str) {
  if (!str)
    return;
  while (*str) {
    hal_uart_putchar(*str);
    str++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hal_uart_putstr>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L29
  nopl   (%rax)
L18:
  call   <hal_uart_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L18
L29:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L16:
  ret
```

assistant: ```c
void hal_uart_putstr(char *str) {
  if (!str)
    return;
  while (*str) {
    hal_uart_putchar(*str);
    str++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hal_uart_putstr>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
  nopl   (%rax)
L0:
  call   <hal_uart_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L0
L6:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void hal_uart_putstr(char *str) {
  if (!str)
    return;
  while (*str) {
    hal_uart_putchar(*str);
    str++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%edi
  call   <__iopl@plt>
  mov    $0xffffffff,%edi
  call   <__iopl@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  __iopl(3);
  __iopl(-1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <__iopl@plt>
  mov    $0xffffffff,%edi
  call   <__iopl@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  __iopl(3);
  __iopl(-1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <__iopl@plt>
  mov    $0xffffffff,%edi
  call   <__iopl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  __iopl(3);
  __iopl(-1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <__iopl@plt>
  mov    $0xffffffff,%edi
  call   <__iopl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  __iopl(3);
  __iopl(-1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<send_string_usart1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L2:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <send_char_usart1@plt>
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void send_string_usart1(char *str) {
  int i = 0;
  while (str[i] != 0) {
    send_char_usart1(str[i++]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_string_usart1>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  push   %rbx
  lea    0x1(%rdi),%rbx
L19:
  movsbl %al,%edi
  call   <send_char_usart1@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L19
  pop    %rbx
  ret
L7:
  ret
```

assistant: ```c
void send_string_usart1(char *str) {
  int i = 0;
  while (str[i] != 0) {
    send_char_usart1(str[i++]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_string_usart1>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  push   %rbx
  lea    0x1(%rdi),%rbx
L7:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <send_char_usart1@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L7
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void send_string_usart1(char *str) {
  int i = 0;
  while (str[i] != 0) {
    send_char_usart1(str[i++]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<send_string_usart1>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  push   %rbx
  lea    0x1(%rdi),%rbx
L5:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <send_char_usart1@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L5
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
void send_string_usart1(char *str) {
  int i = 0;
  while (str[i] != 0) {
    send_char_usart1(str[i++]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<putd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L13
L20:
  cmpl   $0x0,-0x18(%rbp)
  jne    L15
  cmpl   $0x0,-0x1c(%rbp)
  jne    L12
L15:
  mov    -0x18(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  lea    0x30(%rax),%edx
  mov    -0x28(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L59
L12:
  cmpl   $0x0,-0x2c(%rbp)
  je     L50
  mov    $0x30,%edx
  jmp    L19
L50:
  mov    $0x20,%edx
L19:
  mov    -0x28(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
L59:
  addl   $0x1,-0x1c(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L20
  mov    -0x28(%rbp),%edx
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

assistant: ```c
void putd(int number, int fw, int zeros) {
  char buf[10];
  int n;
  unsigned num;
  num = (unsigned)number;
  for (n = 0; n < fw; n++) {
    if (num || n == 0) {
      buf[fw - n - 1] = '0' + num % 10;
      num /= 10;
    } else
      buf[fw - n - 1] = zeros ? '0' : ' ';
  }
  write(1, buf, fw);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<putd>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %esi,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L51
  cmp    $0x1,%edx
  sbb    %r8d,%r8d
  and    $0xfffffff0,%r8d
  add    $0x30,%r8d
  lea    -0x1(%rsi),%eax
  mov    %eax,%esi
  mov    $0xcccccccd,%r11d
  mov    $0x0,%r10d
  jmp    L36
L52:
  movslq %eax,%rbx
  mov    %edi,%edx
  imul   %r11,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,0xe(%rsp,%rbx,1)
  mov    %edx,%edi
L11:
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  je     L51
L36:
  cmp    %eax,%esi
  je     L52
  test   %edi,%edi
  jne    L52
  movslq %eax,%rdx
  mov    %r8b,0xe(%rsp,%rdx,1)
  mov    %r10d,%edi
  jmp    L11
L51:
  lea    0xe(%rsp),%rsi
  mov    %r9d,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x20,%rsp
  pop    %rbx
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void putd(int number, int fw, int zeros) {
  char buf[10];
  int n;
  unsigned num;
  num = (unsigned)number;
  for (n = 0; n < fw; n++) {
    if (num || n == 0) {
      buf[fw - n - 1] = '0' + num % 10;
      num /= 10;
    } else
      buf[fw - n - 1] = zeros ? '0' : ' ';
  }
  write(1, buf, fw);
}
```
user: Translate the below assembly code into C programming language:

```asm
<putd>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L67
  cmp    $0x1,%edx
  lea    -0x1(%rsi),%esi
  mov    $0xcccccccd,%r11d
  sbb    %r8d,%r8d
  mov    %esi,%eax
  and    $0xfffffff0,%r8d
  add    $0x30,%r8d
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L14:
  movslq %eax,%rdx
  xor    %edi,%edi
  mov    %r8b,0xe(%rsp,%rdx,1)
  sub    $0x1,%eax
  jb     L67
L37:
  cmp    %eax,%esi
  je     L57
  test   %edi,%edi
  je     L14
L57:
  mov    %edi,%edx
  movslq %eax,%r10
  imul   %r11,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,0xe(%rsp,%r10,1)
  mov    %edx,%edi
  sub    $0x1,%eax
  jae    L37
L67:
  lea    0xe(%rsp),%rsi
  mov    %r9d,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x28,%rsp
  ret
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void putd(int number, int fw, int zeros) {
  char buf[10];
  int n;
  unsigned num;
  num = (unsigned)number;
  for (n = 0; n < fw; n++) {
    if (num || n == 0) {
      buf[fw - n - 1] = '0' + num % 10;
      num /= 10;
    } else
      buf[fw - n - 1] = zeros ? '0' : ' ';
  }
  write(1, buf, fw);
}
```
user: Translate the below assembly code into C programming language:

```asm
<putd>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L20
  cmp    $0x1,%edx
  lea    -0x1(%rsi),%esi
  mov    $0xcccccccd,%r11d
  sbb    %r8d,%r8d
  mov    %esi,%eax
  and    $0xfffffff0,%r8d
  add    $0x30,%r8d
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L53:
  movslq %eax,%rdx
  xor    %edi,%edi
  mov    %r8b,0xe(%rsp,%rdx,1)
  sub    $0x1,%eax
  jb     L20
L22:
  cmp    %eax,%esi
  je     L41
  test   %edi,%edi
  je     L53
L41:
  mov    %edi,%edx
  movslq %eax,%r10
  imul   %r11,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,0xe(%rsp,%r10,1)
  mov    %edx,%edi
  sub    $0x1,%eax
  jae    L22
L20:
  lea    0xe(%rsp),%rsi
  mov    %r9d,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x28,%rsp
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void putd(int number, int fw, int zeros) {
  char buf[10];
  int n;
  unsigned num;
  num = (unsigned)number;
  for (n = 0; n < fw; n++) {
    if (num || n == 0) {
      buf[fw - n - 1] = '0' + num % 10;
      num /= 10;
    } else
      buf[fw - n - 1] = zeros ? '0' : ' ';
  }
  write(1, buf, fw);
}
```