ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<res_mailok>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L68
  add    $0x1,%rdi
  mov    %eax,%r8d
  test   %eax,%eax
  je     L49
  xor    %edx,%edx
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L27:
  test   %edx,%edx
  jne    L12
  cmp    $0x2e,%eax
  je     L47
L12:
  cmp    $0x5c,%eax
  sete   %al
  xor    $0x1,%edx
  add    $0x1,%rdi
  and    %eax,%edx
  movsbl -0x1(%rdi),%eax
  mov    %eax,%r8d
  test   %eax,%eax
  je     L49
L53:
  lea    -0x21(%rax),%ecx
  cmp    $0x5d,%ecx
  jbe    L27
  xor    %r8d,%r8d
L49:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  jmp    1050 <res_hnok@plt>
```

assistant: ```c
int res_mailok(const char *dn) {
  int ch, escaped = 0;
  if (*dn == '\0')
    return (1);
  while ((ch = *dn++) != '\0') {
    if (!((ch) > 0x20 && (ch) < 0x7f))
      return (0);
    if (!escaped && ((ch) == 0x2e))
      break;
    if (escaped)
      escaped = 0;
    else if (((ch) == 0x5c))
      escaped = 1;
  }
  if (((ch) == 0x2e))
    return (res_hnok(dn));
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <thr0@plt>
  mov    $0x0,%edi
  call   <thr1@plt>
  mov    $0x0,%edi
  call   <thr2@plt>
  mov    $0x0,%edi
  call   <thr3@plt>
  mov    $0x0,%edi
  call   <thr4@plt>
  mov    $0x0,%edi
  call   <thr5@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_0:
  thr0(0);
__CPROVER_ASYNC_1:
  thr1(0);
__CPROVER_ASYNC_2:
  thr2(0);
__CPROVER_ASYNC_3:
  thr3(0);
__CPROVER_ASYNC_4:
  thr4(0);
__CPROVER_ASYNC_5:
  thr5(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <thr0@plt>
  mov    $0x0,%edi
  call   <thr1@plt>
  mov    $0x0,%edi
  call   <thr2@plt>
  mov    $0x0,%edi
  call   <thr3@plt>
  mov    $0x0,%edi
  call   <thr4@plt>
  mov    $0x0,%edi
  call   <thr5@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_0:
  thr0(0);
__CPROVER_ASYNC_1:
  thr1(0);
__CPROVER_ASYNC_2:
  thr2(0);
__CPROVER_ASYNC_3:
  thr3(0);
__CPROVER_ASYNC_4:
  thr4(0);
__CPROVER_ASYNC_5:
  thr5(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <thr0@plt>
  xor    %edi,%edi
  call   <thr1@plt>
  xor    %edi,%edi
  call   <thr2@plt>
  xor    %edi,%edi
  call   <thr3@plt>
  xor    %edi,%edi
  call   <thr4@plt>
  xor    %edi,%edi
  call   <thr5@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_0:
  thr0(0);
__CPROVER_ASYNC_1:
  thr1(0);
__CPROVER_ASYNC_2:
  thr2(0);
__CPROVER_ASYNC_3:
  thr3(0);
__CPROVER_ASYNC_4:
  thr4(0);
__CPROVER_ASYNC_5:
  thr5(0);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <thr0@plt>
  xor    %edi,%edi
  call   <thr1@plt>
  xor    %edi,%edi
  call   <thr2@plt>
  xor    %edi,%edi
  call   <thr3@plt>
  xor    %edi,%edi
  call   <thr4@plt>
  xor    %edi,%edi
  call   <thr5@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_0:
  thr0(0);
__CPROVER_ASYNC_1:
  thr1(0);
__CPROVER_ASYNC_2:
  thr2(0);
__CPROVER_ASYNC_3:
  thr3(0);
__CPROVER_ASYNC_4:
  thr4(0);
__CPROVER_ASYNC_5:
  thr5(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<complainx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %rdi,-0x1d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L11
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L11:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x1d8(%rbp),%rdx
  mov    -0x1c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x1c4(%rbp),%ecx
  mov    -0x1d8(%rbp),%rdx
  lea    -0x1c0(%rbp),%rax
  mov    $0xffffffff,%r8d
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <vscomplain@plt>
  mov    -0x1c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  lea    -0x1c0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void complainx(const char *fmt, ...) {
  char buf[256];
  va_list ap;
  va_start(ap, fmt);
  vscomplain(buf, sizeof(buf), fmt, ap, -1);
  va_end(ap);
  (void)write(STDERR_FILENO, buf, strlen(buf));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<complainx>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rsp,%rbp
  mov    $0xffffffff,%r8d
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <vscomplain@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void complainx(const char *fmt, ...) {
  char buf[256];
  va_list ap;
  va_start(ap, fmt);
  vscomplain(buf, sizeof(buf), fmt, ap, -1);
  va_end(ap);
  (void)write(STDERR_FILENO, buf, strlen(buf));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<complainx>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %r13d,%ecx
  mov    $0xffffffff,%r8d
  mov    %rbp,%rdi
  call   <vscomplain@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %eax,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void complainx(const char *fmt, ...) {
  char buf[256];
  va_list ap;
  va_start(ap, fmt);
  vscomplain(buf, sizeof(buf), fmt, ap, -1);
  va_end(ap);
  (void)write(STDERR_FILENO, buf, strlen(buf));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<complainx>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %r13d,%ecx
  mov    $0xffffffff,%r8d
  mov    %rbp,%rdi
  call   <vscomplain@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %eax,%edx
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void complainx(const char *fmt, ...) {
  char buf[256];
  va_list ap;
  va_start(ap, fmt);
  vscomplain(buf, sizeof(buf), fmt, ap, -1);
  va_end(ap);
  (void)write(STDERR_FILENO, buf, strlen(buf));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: Hello world!


assistant: ```c
int main() {
  printf("Hello world!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: Hello world!


assistant: ```c
int main() {
  printf("Hello world!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: Hello world!


assistant: ```c
int main() {
  printf("Hello world!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: Hello world!


assistant: ```c
int main() {
  printf("Hello world!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MakeInverseOrdering>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L30:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *MakeInverseOrdering(const int order[], int num, int invorder[]) {
  int i;
  for (i = 0; i < num; ++i)
    invorder[i] = -1;
  for (i = 0; i < num; ++i)
    invorder[order[i]] = i;
  return invorder;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MakeInverseOrdering>:
  endbr64
  mov    %rdx,%rax
  test   %esi,%esi
  jle    L16
  mov    %rdx,%rcx
  lea    -0x1(%rsi),%edx
  lea    0x4(%rax,%rdx,4),%rdx
L1:
  movl   $0xffffffff,(%rcx)
  add    $0x4,%rcx
  cmp    %rdx,%rcx
  jne    L1
  mov    %esi,%esi
  mov    $0x0,%ecx
L4:
  movslq (%rdi,%rcx,4),%r8
  mov    %ecx,(%rax,%r8,4)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L4
L16:
  ret
```

assistant: ```c
int *MakeInverseOrdering(const int order[], int num, int invorder[]) {
  int i;
  for (i = 0; i < num; ++i)
    invorder[i] = -1;
  for (i = 0; i < num; ++i)
    invorder[order[i]] = i;
  return invorder;
}
```
user: What is the c source code of the assembly code below:

```asm
<MakeInverseOrdering>:
  endbr64
  mov    %rdx,%r8
  test   %esi,%esi
  jle    L10
  push   %rbp
  mov    %rdi,%rbp
  mov    %r8,%rdi
  push   %rbx
  movslq %esi,%rbx
  mov    $0xff,%esi
  lea    0x0(,%rbx,4),%rdx
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  nopl   0x0(%rax)
L15:
  movslq 0x0(%rbp,%rax,4),%rdx
  mov    %eax,(%r8,%rdx,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L15
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  mov    %rdx,%rax
  ret
```

assistant: ```c
int *MakeInverseOrdering(const int order[], int num, int invorder[]) {
  int i;
  for (i = 0; i < num; ++i)
    invorder[i] = -1;
  for (i = 0; i < num; ++i)
    invorder[order[i]] = i;
  return invorder;
}
```
user: What is the c source code of the assembly code below:

```asm
<MakeInverseOrdering>:
  endbr64
  mov    %rdx,%r8
  test   %esi,%esi
  jle    L6
  push   %rbp
  mov    %rdi,%rbp
  mov    %r8,%rdi
  push   %rbx
  movslq %esi,%rbx
  mov    $0xff,%esi
  lea    0x0(,%rbx,4),%rdx
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  movslq 0x0(%rbp,%rax,4),%rdx
  mov    %eax,(%r8,%rdx,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L10
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  mov    %rdx,%rax
  ret
```

assistant: ```c
int *MakeInverseOrdering(const int order[], int num, int invorder[]) {
  int i;
  for (i = 0; i < num; ++i)
    invorder[i] = -1;
  for (i = 0; i < num; ++i)
    invorder[order[i]] = i;
  return invorder;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gaus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  D34(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D11(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L12:
  mov    $0x0,%eax
  call   <rand@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x20(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  D6(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L24
  movsd  -0x18(%rbp),%xmm0
  jmp    L28
L24:
  jmp    L12
L28:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D34
type_infered: f64
name: disassemble_data
arguments: data_tag: D11
type_infered: f64
name: disassemble_data
arguments: data_tag: D6
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D4
type_infered: byte[8]

tool: D34: 2.7182818

tool: D11: 2147483647

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x12,0xc0]}

assistant: ```c
double gaus() {
  double rnd_x, rnd_y, gauss;
  double e = 2.7182818, rmax = 2147483647;
  for (;;) {
    rnd_x = (rand() / rmax * 2 - 1);
    rnd_y = (rand() / rmax);
    gauss = pow(e, -0.5 * 9 * rnd_x * rnd_x);
    if (rnd_y < gauss)
      return rnd_x;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<gaus>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  divsd  D12(%rip),%xmm0
  addsd  %xmm0,%xmm0
  subsd  D7(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%eax
  call   <rand@plt>
  movq   %xmm0,%rbx
  movsd  D4(%rip),%xmm1
  movsd  0x8(%rsp),%xmm2
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mov    D13(%rip),%rax
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  divsd  D12(%rip),%xmm0
  comisd %xmm0,%xmm1
  jbe    L4
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
data_type: f64
name: extract_symbolic_data
arguments: tag: D7
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D4
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D13
data_type: f64

tool: D12: 2147483647

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x12,0xc0]}

tool: D13: 2.7182818

assistant: ```c
double gaus() {
  double rnd_x, rnd_y, gauss;
  double e = 2.7182818, rmax = 2147483647;
  for (;;) {
    rnd_x = (rand() / rmax * 2 - 1);
    rnd_y = (rand() / rmax);
    gauss = pow(e, -0.5 * 9 * rnd_x * rnd_x);
    if (rnd_y < gauss)
      return rnd_x;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gaus>:
  endbr64
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <rand@plt>
  divsd  D9(%rip),%xmm0
  xor    %eax,%eax
  addsd  %xmm0,%xmm0
  subsd  D30(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  call   <rand@plt>
  movsd  (%rsp),%xmm3
  movsd  D28(%rip),%xmm1
  mov    D37(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm3,%xmm1
  movq   %rax,%xmm0
  mulsd  %xmm3,%xmm1
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  divsd  D9(%rip),%xmm2
  comisd %xmm2,%xmm0
  jbe    L4
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: f64
name: retrieve_data
arguments: data_label: D30
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D28
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D37
type_infered: f64

tool: D9: 2147483647

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x12,0xc0]}

tool: D37: 2.7182818

assistant: ```c
double gaus() {
  double rnd_x, rnd_y, gauss;
  double e = 2.7182818, rmax = 2147483647;
  for (;;) {
    rnd_x = (rand() / rmax * 2 - 1);
    rnd_y = (rand() / rmax);
    gauss = pow(e, -0.5 * 9 * rnd_x * rnd_x);
    if (rnd_y < gauss)
      return rnd_x;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gaus>:
  endbr64
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <rand@plt>
  divsd  D31(%rip),%xmm0
  xor    %eax,%eax
  addsd  %xmm0,%xmm0
  subsd  D43(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  call   <rand@plt>
  movsd  (%rsp),%xmm3
  movsd  D49(%rip),%xmm1
  mov    D29(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm3,%xmm1
  movq   %rax,%xmm0
  mulsd  %xmm3,%xmm1
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  divsd  D31(%rip),%xmm2
  comisd %xmm2,%xmm0
  jbe    L7
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D31
data_type: f64
name: parse_data
arguments: data_label: D43
data_type: byte[8]
name: parse_data
arguments: data_label: D49
data_type: byte[8]
name: parse_data
arguments: data_label: D29
data_type: f64

tool: D31: 2147483647

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0x12,0xc0]}

tool: D29: 2.7182818

assistant: ```c
double gaus() {
  double rnd_x, rnd_y, gauss;
  double e = 2.7182818, rmax = 2147483647;
  for (;;) {
    rnd_x = (rand() / rmax * 2 - 1);
    rnd_y = (rand() / rmax);
    gauss = pow(e, -0.5 * 9 * rnd_x * rnd_x);
    if (rnd_y < gauss)
      return rnd_x;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printCodeBook>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L39
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D15: %c: 

tool: D19: %d 

assistant: ```c
void printCodeBook(int **codebook, int numRow) {
  int row;
  for (row = 0; row < numRow; row++) {
    printf("%c: ", codebook[row][0]);
    int col = 1;
    while (codebook[row][col] != -1) {
      printf("%d ", codebook[row][col]);
      col++;
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printCodeBook>:
  endbr64
  test   %esi,%esi
  jle    L38
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r15
  lea    D17(%rip),%r14
  lea    D14(%rip),%r12
L11:
  mov    %r13,%rbp
  mov    0x0(%r13),%rax
  mov    (%rax),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%r13),%rax
  mov    0x4(%rax),%esi
  cmp    $0xffffffff,%esi
  je     L1
  mov    $0x8,%ebx
L12:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  add    $0x4,%rbx
  cmp    $0xffffffff,%esi
  jne    L12
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%r13
  cmp    %r15,%r13
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: D17: %c: 

tool: D14: %d 

assistant: ```c
void printCodeBook(int **codebook, int numRow) {
  int row;
  for (row = 0; row < numRow; row++) {
    printf("%c: ", codebook[row][0]);
    int col = 1;
    while (codebook[row][col] != -1) {
      printf("%d ", codebook[row][col]);
      col++;
    }
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printCodeBook>:
  endbr64
  test   %esi,%esi
  jle    L20
  push   %r14
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r14
  push   %r13
  lea    0x8(%rdi,%rax,8),%r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  nopl   0x0(%rax)
L11:
  mov    (%r14),%rax
  mov    %r12,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%r14),%rax
  mov    0x4(%rax),%esi
  cmp    $0xffffffff,%esi
  je     L31
  mov    $0x8,%ebx
  nop
L32:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%r14),%rax
  mov    (%rax,%rbx,1),%esi
  add    $0x4,%rbx
  cmp    $0xffffffff,%esi
  jne    L32
L31:
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    %r13,%r14
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D18: %c: 

tool: D9: %d 

assistant: ```c
void printCodeBook(int **codebook, int numRow) {
  int row;
  for (row = 0; row < numRow; row++) {
    printf("%c: ", codebook[row][0]);
    int col = 1;
    while (codebook[row][col] != -1) {
      printf("%d ", codebook[row][col]);
      col++;
    }
    printf("\n");
  }
}
```