ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<xdr_u_int64_t>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L65
  cmp    $0x82,%eax
  je     L87
  cmp    $0x80,%eax
  je     L86
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L75
L65:
  mov    $0x4,%edx
  call   <xdr_opaque@plt>
L75:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L87:
  mov    $0x4,%edx
  lea    0x4(%rsp),%esi
  call   <xdr_opaque@plt>
  test   %eax,%eax
  je     L53
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  jmp    L75
L53:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L75
L86:
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  jmp    L75
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int64_t(XDR *xdrs, u_int64_t *uint64_p) {
  u_int64_t x;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    return (xdr_opaque(xdrs, (caddr_t)uint64_p, sizeof(u_int64_t)));
  case XDR_DECODE:
    if (!xdr_opaque(xdrs, (caddr_t)&x, sizeof x)) {
      return (FALSE);
    }
    *uint64_p = x;
    return (TRUE);
  case XDR_FREE:
    return (TRUE);
  }
  return (FALSE);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xdr_u_int64_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L44
  cmp    $0x82,%eax
  je     L26
  cmp    $0x80,%eax
  je     L34
L2:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
L78:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x10,%rsp
  pop    %rbx
  ret
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x10,%rsp
  mov    $0x4,%edx
  pop    %rbx
  jmp    1070 <xdr_opaque@plt>
  nop
L34:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0x4,%edx
  lea    0x4(%rsp),%esi
  call   <xdr_opaque@plt>
  test   %eax,%eax
  je     L2
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  jmp    L78
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int64_t(XDR *xdrs, u_int64_t *uint64_p) {
  u_int64_t x;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    return (xdr_opaque(xdrs, (caddr_t)uint64_p, sizeof(u_int64_t)));
  case XDR_DECODE:
    if (!xdr_opaque(xdrs, (caddr_t)&x, sizeof x)) {
      return (FALSE);
    }
    *uint64_p = x;
    return (TRUE);
  case XDR_FREE:
    return (TRUE);
  }
  return (FALSE);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xdr_u_int64_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L3
  cmp    $0x82,%eax
  je     L10
  cmp    $0x80,%eax
  je     L8
L34:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
L47:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L76
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x10,%rsp
  mov    $0x4,%edx
  pop    %rbx
  jmp    1070 <xdr_opaque@plt>
  nop
L8:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x4,%edx
  lea    0x4(%rsp),%esi
  call   <xdr_opaque@plt>
  test   %eax,%eax
  je     L34
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L47
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int64_t(XDR *xdrs, u_int64_t *uint64_p) {
  u_int64_t x;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    return (xdr_opaque(xdrs, (caddr_t)uint64_p, sizeof(u_int64_t)));
  case XDR_DECODE:
    if (!xdr_opaque(xdrs, (caddr_t)&x, sizeof x)) {
      return (FALSE);
    }
    *uint64_p = x;
    return (TRUE);
  case XDR_FREE:
    return (TRUE);
  }
  return (FALSE);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sint_put>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jle    L2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <sint_put>
L2:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

assistant: ```c
void sint_put(signed int number, FILE *stream) {
  if (number > (signed int)9) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wconversion"
    sint_put(number / (signed int)10, stream);
#pragma GCC diagnostic pop
  }
  fputc('0' + (char)(number % (signed int)10), stream);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sint_put>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  cmp    $0x9,%edi
  jg     L13
L19:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  movsbl %dil,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  movslq %edi,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <sint_put>
  jmp    L19
```

assistant: ```c
void sint_put(signed int number, FILE *stream) {
  if (number > (signed int)9) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wconversion"
    sint_put(number / (signed int)10, stream);
#pragma GCC diagnostic pop
  }
  fputc('0' + (char)(number % (signed int)10), stream);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sint_put>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %rbp,%rbx
  sub    $0x18,%rsp
  cmp    $0x9,%ebp
  jg     L21
L31:
  imul   $0x66666667,%rbp,%rax
  mov    %ebx,%edx
  add    $0x18,%rsp
  mov    %r12,%rsi
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  movzbl %dil,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <fputc@plt>
  cs nopw 0x0(%rax,%rax,1)
L21:
  imul   $0x66666667,%rbp,%r13
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sar    $0x22,%r13
  sub    %eax,%r13d
  mov    %r13d,%r14d
  cmp    $0x63,%ebp
  jg     L9
L33:
  mov    $0xcccccccd,%eax
  mov    %r12,%rsi
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  jmp    L31
  nopl   (%rax)
L9:
  mov    $0xcccccccd,%edi
  mov    %r14,%r15
  imul   %rdi,%r15
  shr    $0x23,%r15
  mov    %r15d,%eax
  cmp    $0x3e7,%ebp
  jg     L55
L14:
  mov    $0xcccccccd,%edx
  mov    %r12,%rsi
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r15d
  lea    0x30(%r15),%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L55:
  imul   %rax,%rdi
  mov    %rax,0x8(%rsp)
  shr    $0x23,%rdi
  call   <sint_put>
  mov    0x8(%rsp),%rax
  jmp    L14
```

assistant: ```c
void sint_put(signed int number, FILE *stream) {
  if (number > (signed int)9) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wconversion"
    sint_put(number / (signed int)10, stream);
#pragma GCC diagnostic pop
  }
  fputc('0' + (char)(number % (signed int)10), stream);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sint_put>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %rbp,%rbx
  sub    $0x18,%rsp
  cmp    $0x9,%ebp
  jg     L52
L0:
  imul   $0x66666667,%rbp,%rax
  mov    %ebx,%edx
  add    $0x18,%rsp
  mov    %r12,%rsi
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  movzbl %dil,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <fputc@plt>
  cs nopw 0x0(%rax,%rax,1)
L52:
  imul   $0x66666667,%rbp,%r13
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sar    $0x22,%r13
  sub    %eax,%r13d
  mov    %r13d,%r14d
  cmp    $0x63,%ebp
  jg     L27
L29:
  mov    $0xcccccccd,%eax
  mov    %r12,%rsi
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  jmp    L0
  nopl   (%rax)
L27:
  mov    $0xcccccccd,%edi
  mov    %r14,%r15
  imul   %rdi,%r15
  shr    $0x23,%r15
  mov    %r15d,%eax
  cmp    $0x3e7,%ebp
  jg     L11
L3:
  mov    $0xcccccccd,%edx
  mov    %r12,%rsi
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r15d
  lea    0x30(%r15),%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L11:
  imul   %rax,%rdi
  mov    %rax,0x8(%rsp)
  shr    $0x23,%rdi
  call   <sint_put>
  mov    0x8(%rsp),%rax
  jmp    L3
```

assistant: ```c
void sint_put(signed int number, FILE *stream) {
  if (number > (signed int)9) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wconversion"
    sint_put(number / (signed int)10, stream);
#pragma GCC diagnostic pop
  }
  fputc('0' + (char)(number % (signed int)10), stream);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L14
L11:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rcx),%xmm0
  movsd  %xmm0,(%rax)
L14:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L11
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *reverse(double *a, int size) {
  int i = 0;
  double *b = malloc(size * sizeof(*b));
  while (--size >= 0)
    b[i++] = a[size];
  return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  sub    $0x1,%ebx
  js     L3
  movslq %ebx,%rdx
  mov    %rax,%rcx
L14:
  movsd  0x0(%rbp,%rdx,8),%xmm0
  movsd  %xmm0,(%rcx)
  sub    $0x1,%rdx
  add    $0x8,%rcx
  test   %edx,%edx
  jns    L14
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *reverse(double *a, int size) {
  int i = 0;
  double *b = malloc(size * sizeof(*b));
  while (--size >= 0)
    b[i++] = a[size];
  return b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,8),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  sub    $0x1,%ebx
  js     L7
  movslq %ebx,%rdx
  mov    %rax,%rcx
  cs nopw 0x0(%rax,%rax,1)
L3:
  movsd  0x0(%rbp,%rdx,8),%xmm0
  sub    $0x1,%rdx
  add    $0x8,%rcx
  movsd  %xmm0,-0x8(%rcx)
  test   %edx,%edx
  jns    L3
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *reverse(double *a, int size) {
  int i = 0;
  double *b = malloc(size * sizeof(*b));
  while (--size >= 0)
    b[i++] = a[size];
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%r12,8),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rax,%r8
  sub    $0x1,%edx
  js     L8
  lea    0x0(,%r12,8),%rax
  mov    %r12d,%ecx
  mov    %r12,%rbp
  shl    $0x3,%rcx
  mov    %rax,%rsi
  sub    %rcx,%rsi
  lea    (%r8,%rcx,1),%rdi
  lea    (%rbx,%rsi,1),%rcx
  lea    (%rbx,%rax,1),%rsi
  cmp    %rcx,%rdi
  setbe  %cl
  cmp    %rsi,%r8
  setae  %sil
  or     %sil,%cl
  je     L66
  cmp    $0x2,%edx
  jbe    L66
  mov    %r12d,%edi
  lea    -0x10(%rbx,%rax,1),%rsi
  mov    %r8,%rcx
  shr    %edi
  lea    -0x10(%rsi),%rax
  lea    -0x1(%rdi),%r9d
  mov    %rax,%rdi
  shl    $0x4,%r9
  sub    %r9,%rdi
  jmp    L54
  cs nopw 0x0(%rax,%rax,1)
L12:
  sub    $0x10,%rax
L54:
  movupd (%rsi),%xmm0
  add    $0x10,%rcx
  mov    %rax,%rsi
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,-0x10(%rcx)
  cmp    %rax,%rdi
  jne    L12
  mov    %ebp,%eax
  and    $0xfffffffe,%eax
  sub    %eax,%edx
  cmp    %eax,%ebp
  je     L8
  movslq %edx,%rdx
  cltq
  movsd  (%rbx,%rdx,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
L8:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
L66:
  movslq %edx,%rdx
  mov    %r8,%rax
  cs nopw 0x0(%rax,%rax,1)
L32:
  movsd  (%rbx,%rdx,8),%xmm0
  sub    $0x1,%rdx
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  test   %edx,%edx
  jns    L32
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *reverse(double *a, int size) {
  int i = 0;
  double *b = malloc(size * sizeof(*b));
  while (--size >= 0)
    b[i++] = a[size];
  return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L13
L0:
  shll   $0x8,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L13:
  cmpl   $0x0,-0x8(%rbp)
  jns    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_field(unsigned char f[], int n) {
  int i;
  int x;
  x = 0;
  for (i = n - 1; i >= 0; i--) {
    x <<= 8;
    x |= f[i];
  }
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_field>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  sub    $0x1,%edx
  js     L13
  movslq %edx,%rdx
  add    %rdi,%rdx
  movslq %esi,%rcx
  lea    -0x2(%rdi,%rcx,1),%rsi
  lea    -0x1(%rax),%eax
  sub    %rax,%rsi
  mov    $0x0,%eax
L16:
  shl    $0x8,%eax
  movzbl (%rdx),%ecx
  or     %ecx,%eax
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L16
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int get_field(unsigned char f[], int n) {
  int i;
  int x;
  x = 0;
  for (i = n - 1; i >= 0; i--) {
    x <<= 8;
    x |= f[i];
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_field>:
  endbr64
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L18
  movslq %esi,%rsi
  movslq %eax,%rdx
  mov    %eax,%eax
  lea    -0x2(%rdi,%rsi,1),%rsi
  add    %rdi,%rdx
  sub    %rax,%rsi
  xor    %eax,%eax
L17:
  movzbl (%rdx),%ecx
  shl    $0x8,%eax
  sub    $0x1,%rdx
  or     %ecx,%eax
  cmp    %rsi,%rdx
  jne    L17
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_field(unsigned char f[], int n) {
  int i;
  int x;
  x = 0;
  for (i = n - 1; i >= 0; i--) {
    x <<= 8;
    x |= f[i];
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_field>:
  endbr64
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L7
  movslq %esi,%rsi
  movslq %eax,%rdx
  mov    %eax,%eax
  lea    -0x2(%rdi,%rsi,1),%rsi
  add    %rdi,%rdx
  sub    %rax,%rsi
  xor    %eax,%eax
L8:
  movzbl (%rdx),%ecx
  shl    $0x8,%eax
  sub    $0x1,%rdx
  or     %ecx,%eax
  cmp    %rdx,%rsi
  jne    L8
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_field(unsigned char f[], int n) {
  int i;
  int x;
  x = 0;
  for (i = n - 1; i >= 0; i--) {
    x <<= 8;
    x |= f[i];
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_buffer_overflow_returns_false>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    $0xaa,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x12,-0x18(%rbp)
  movl   $0x34,-0x14(%rbp)
  movl   $0x56,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    $0xc,%ecx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <websafe_base64_encode@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0: test_buffer_overflow_returns_false

assistant: ```c
void test_buffer_overflow_returns_false() {
  test("test_buffer_overflow_returns_false");
  char out[4];
  memset(out, 0xaa, sizeof(out));
  uint8_t in[] = {0x12, 0x34, 0x56};
  assert(!websafe_base64_encode(out, 3, in, sizeof(in)));
  assert(out[3] == 0xaa);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_buffer_overflow_returns_false>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <test@plt>
  lea    0x14(%rsp),%rbx
  mov    $0x4,%edx
  mov    $0xaa,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movl   $0x12,0x8(%rsp)
  movl   $0x34,0xc(%rsp)
  movl   $0x56,0x10(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0xc,%ecx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <websafe_base64_encode@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D6: test_buffer_overflow_returns_false

assistant: ```c
void test_buffer_overflow_returns_false() {
  test("test_buffer_overflow_returns_false");
  char out[4];
  memset(out, 0xaa, sizeof(out));
  uint8_t in[] = {0x12, 0x34, 0x56};
  assert(!websafe_base64_encode(out, 3, in, sizeof(in)));
  assert(out[3] == 0xaa);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_buffer_overflow_returns_false>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  call   <test@plt>
  mov    $0x4,%edx
  mov    $0xaa,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    0x8(%rsp),%rdx
  mov    $0xc,%ecx
  mov    %rbp,%rdi
  movabs $0x3400000012,%rax
  mov    $0x3,%esi
  movl   $0x56,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <websafe_base64_encode@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: test_buffer_overflow_returns_false

assistant: ```c
void test_buffer_overflow_returns_false() {
  test("test_buffer_overflow_returns_false");
  char out[4];
  memset(out, 0xaa, sizeof(out));
  uint8_t in[] = {0x12, 0x34, 0x56};
  assert(!websafe_base64_encode(out, 3, in, sizeof(in)));
  assert(out[3] == 0xaa);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_buffer_overflow_returns_false>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  call   <test@plt>
  mov    $0x4,%edx
  mov    $0xaa,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D15(%rip),%rax
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rdi
  mov    $0xc,%ecx
  mov    $0x3,%esi
  movl   $0x56,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <websafe_base64_encode@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: byte[8]

tool: D16: test_buffer_overflow_returns_false

tool: {"D15": [0x12,0x00,0x00,0x00,0x34,0x00,0x00,0x00]}

assistant: ```c
void test_buffer_overflow_returns_false() {
  test("test_buffer_overflow_returns_false");
  char out[4];
  memset(out, 0xaa, sizeof(out));
  uint8_t in[] = {0x12, 0x34, 0x56};
  assert(!websafe_base64_encode(out, 3, in, sizeof(in)));
  assert(out[3] == 0xaa);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x8011,%eax
L7:
  sub    $0x1,%eax
  jne    L7
  mov    $0x8011,%eax
L3:
  sub    $0x1,%eax
  jne    L3
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int ix;
  int ondev = 0;
  int q = 0, h = 0;
#pragma acc parallel vector_length(32) copy(q) copy(ondev)
  {
    int t = q;
#pragma acc loop vector reduction(+ : t)
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      int val = ix;
      if (__builtin_acc_on_device(5)) {
        int g = 0, w = 0, v = 0;
        __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
        __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
        __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
        val = (g << 16) | (w << 8) | v;
        ondev = 1;
      }
      t += val;
    }
    q = t;
  }
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    int val = ix;
    if (ondev) {
      int g = 0;
      int w = 0;
      int v = ix % 32;
      val = (g << 16) | (w << 8) | v;
    }
    h += val;
  }
  if (q != h) {
    printf("t=%x expected %x\n", q, h);
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int ix;
  int ondev = 0;
  int q = 0, h = 0;
#pragma acc parallel vector_length(32) copy(q) copy(ondev)
  {
    int t = q;
#pragma acc loop vector reduction(+ : t)
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      int val = ix;
      if (__builtin_acc_on_device(5)) {
        int g = 0, w = 0, v = 0;
        __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
        __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
        __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
        val = (g << 16) | (w << 8) | v;
        ondev = 1;
      }
      t += val;
    }
    q = t;
  }
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    int val = ix;
    if (ondev) {
      int g = 0;
      int w = 0;
      int v = ix % 32;
      val = (g << 16) | (w << 8) | v;
    }
    h += val;
  }
  if (q != h) {
    printf("t=%x expected %x\n", q, h);
    return 1;
  }
  return 0;
}
```