ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x78(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x78(%rbp),%rdx
  lea    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D6
type_infered: string

tool: D16: %7s

tool: D6: %s##%s##

assistant: ```c
int main(int argc, const char *argv[]) {
  char string[8];
  char string2[8];
  scanf("%7s", string);
  scanf("%7s", string2);
  printf("%s##%s##", string, string2);
  char buffer[100] = "";
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D19(%rip),%r12
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D19: %7s

tool: D1: %s##%s##

assistant: ```c
int main(int argc, const char *argv[]) {
  char string[8];
  char string2[8];
  scanf("%7s", string);
  scanf("%7s", string2);
  printf("%s##%s##", string, string2);
  char buffer[100] = "";
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
type_guessed: string
name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D19: %7s

tool: D5: %s##%s##

assistant: ```c
int main(int argc, const char *argv[]) {
  char string[8];
  char string2[8];
  scanf("%7s", string);
  scanf("%7s", string2);
  printf("%s##%s##", string, string2);
  char buffer[100] = "";
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
data_type: string
name: extract_symbolic_data
arguments: data_label: D13
data_type: string

tool: D17: %7s

tool: D13: %s##%s##

assistant: ```c
int main(int argc, const char *argv[]) {
  char string[8];
  char string2[8];
  scanf("%7s", string);
  scanf("%7s", string2);
  printf("%s##%s##", string, string2);
  char buffer[100] = "";
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x4,-0x24(%rbp)
  mov    -0x24(%rbp),%ecx
  lea    -0x20(%rbp),%rax
  mov    $0x5,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <searchInsert2@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%ecx
  lea    -0x20(%rbp),%rax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <searchInsert2@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%ecx
  lea    -0x20(%rbp),%rax
  mov    $0x7,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <searchInsert2@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%ecx
  lea    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <searchInsert2@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D22
type: string

tool: D22: %d


assistant: ```c
int main() {
  int a[] = {1, 3, 5, 6}, len = sizeof a / sizeof a[0];
  printf("%d\n", searchInsert2(a, len, 5));
  printf("%d\n", searchInsert2(a, len, 2));
  printf("%d\n", searchInsert2(a, len, 7));
  printf("%d\n", searchInsert2(a, len, 0));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  mov    %rsp,%rbp
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <searchInsert2@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <searchInsert2@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <searchInsert2@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <searchInsert2@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d


assistant: ```c
int main() {
  int a[] = {1, 3, 5, 6}, len = sizeof a / sizeof a[0];
  printf("%d\n", searchInsert2(a, len, 5));
  printf("%d\n", searchInsert2(a, len, 2));
  printf("%d\n", searchInsert2(a, len, 7));
  printf("%d\n", searchInsert2(a, len, 0));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  mov    $0x4,%esi
  push   %rbp
  lea    D6(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000001,%rax
  mov    %rsp,%r12
  mov    %r12,%rdi
  mov    %rax,(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x8(%rsp)
  call   <searchInsert2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int main() {
  int a[] = {1, 3, 5, 6}, len = sizeof a / sizeof a[0];
  printf("%d\n", searchInsert2(a, len, 5));
  printf("%d\n", searchInsert2(a, len, 2));
  printf("%d\n", searchInsert2(a, len, 7));
  printf("%d\n", searchInsert2(a, len, 0));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  mov    $0x4,%esi
  push   %rbp
  lea    D17(%rip),%rbp
  sub    $0x28,%rsp
  movdqa D2(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  movaps %xmm0,(%rsp)
  call   <searchInsert2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <searchInsert2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: byte[16]

tool: D17: %d


tool: {"D2": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[] = {1, 3, 5, 6}, len = sizeof a / sizeof a[0];
  printf("%d\n", searchInsert2(a, len, 5));
  printf("%d\n", searchInsert2(a, len, 2));
  printf("%d\n", searchInsert2(a, len, 7));
  printf("%d\n", searchInsert2(a, len, 0));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<simple_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int simple_loop(int *a, int n) {
  int sum = 0;
  for (int i = 0; i < n; ++i)
    sum += a[i];
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simple_loop>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L6:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L6
L14:
  mov    %edx,%eax
  ret
L15:
  mov    $0x0,%edx
  jmp    L14
```

assistant: ```c
int simple_loop(int *a, int n) {
  int sum = 0;
  for (int i = 0; i < n; ++i)
    sum += a[i];
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<simple_loop>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L5
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int simple_loop(int *a, int n) {
  int sum = 0;
  for (int i = 0; i < n; ++i)
    sum += a[i];
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<simple_loop>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L46
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L21
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L53:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L53
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L59
L43:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L66
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L66
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L46:
  xor    %eax,%eax
L66:
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  ret
L21:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L43
```

assistant: ```c
int simple_loop(int *a, int n) {
  int sum = 0;
  for (int i = 0; i < n; ++i)
    sum += a[i];
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <socket_open@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1c74,%esi
  mov    %eax,%edi
  call   <socket_bind@plt>
  mov    -0x4(%rbp),%eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <socket_listen@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <socket_server@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int server;
  server = socket_open();
  socket_bind(server, 7284);
  socket_listen(server, 10);
  socket_server(server);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <socket_open@plt>
  mov    %eax,%ebx
  mov    $0x1c74,%esi
  mov    %eax,%edi
  call   <socket_bind@plt>
  mov    $0xa,%esi
  mov    %ebx,%edi
  call   <socket_listen@plt>
  mov    %ebx,%edi
  call   <socket_server@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int server;
  server = socket_open();
  socket_bind(server, 7284);
  socket_listen(server, 10);
  socket_server(server);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <socket_open@plt>
  mov    $0x1c74,%esi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <socket_bind@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  call   <socket_listen@plt>
  mov    %ebp,%edi
  call   <socket_server@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int server;
  server = socket_open();
  socket_bind(server, 7284);
  socket_listen(server, 10);
  socket_server(server);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <socket_open@plt>
  mov    $0x1c74,%esi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <socket_bind@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  call   <socket_listen@plt>
  mov    %ebp,%edi
  call   <socket_server@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int server;
  server = socket_open();
  socket_bind(server, 7284);
  socket_listen(server, 10);
  socket_server(server);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nandll_read_page>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x800,-0x4(%rbp)
  mov    $0x70200004,%eax
  mov    (%rax),%rax
  mov    $0x70200004,%edx
  and    $0xfffffffffffffffd,%rax
  mov    %rax,(%rdx)
  mov    $0x70200008,%eax
  movq   $0x0,(%rax)
  mov    $0x7020000c,%eax
  movq   $0x0,(%rax)
  mov    $0x7020000c,%eax
  movq   $0x0,(%rax)
  mov    $0x7020000c,%edx
  mov    -0x20(%rbp),%rax
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  shr    $0x8,%rax
  mov    $0x7020000c,%edx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  shr    $0x10,%rax
  mov    $0x7020000c,%edx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    $0x70200008,%eax
  movq   $0x30,(%rax)
  nop
L26:
  mov    $0x70200028,%eax
  mov    (%rax),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L26
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L11:
  mov    $0x70200010,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L11
  mov    $0x70200004,%eax
  mov    (%rax),%rax
  mov    $0x70200004,%edx
  or     $0x2,%rax
  mov    %rax,(%rdx)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int nandll_read_page(unsigned char *buf, unsigned long addr) {
  int i;
  int page_size = 2048;
  ((*(volatile unsigned long *)(0x70200000 + 0x04)) &= ~(1 << 1));
  (*(volatile unsigned long *)(0x70200000 + 0x08)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr)&0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr >> 8) & 0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr >> 16) & 0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x08)) = 0x30;
  do {
    while (!((*(volatile unsigned long *)(0x70200000 + 0x28)) & (1 << 0)))
      ;
  } while (0);
  for (i = 0; i < page_size; i++) {
    *buf++ = (*(volatile unsigned char *)(0x70200000 + 0x10));
  }
  ((*(volatile unsigned long *)(0x70200000 + 0x04)) |= (1 << 1));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<nandll_read_page>:
  endbr64
  mov    %rsi,%rax
  mov    0x70200004,%rdx
  and    $0xfffffffffffffffd,%rdx
  mov    %rdx,0x70200004
  movq   $0x0,0x70200008
  movq   $0x0,0x7020000c
  movq   $0x0,0x7020000c
  movzbl %sil,%edx
  mov    %rdx,0x7020000c
  movzbl %ah,%edx
  mov    %rdx,0x7020000c
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    %rax,0x7020000c
  movq   $0x30,0x70200008
L1:
  mov    0x70200028,%rax
  test   $0x1,%al
  je     L1
  lea    0x800(%rdi),%rdx
L7:
  add    $0x1,%rdi
  movzbl 0x70200010,%eax
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rdx
  jne    L7
  mov    0x70200004,%rax
  or     $0x2,%rax
  mov    %rax,0x70200004
  mov    $0x0,%eax
  ret
```

assistant: ```c
int nandll_read_page(unsigned char *buf, unsigned long addr) {
  int i;
  int page_size = 2048;
  ((*(volatile unsigned long *)(0x70200000 + 0x04)) &= ~(1 << 1));
  (*(volatile unsigned long *)(0x70200000 + 0x08)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr)&0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr >> 8) & 0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr >> 16) & 0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x08)) = 0x30;
  do {
    while (!((*(volatile unsigned long *)(0x70200000 + 0x28)) & (1 << 0)))
      ;
  } while (0);
  for (i = 0; i < page_size; i++) {
    *buf++ = (*(volatile unsigned char *)(0x70200000 + 0x10));
  }
  ((*(volatile unsigned long *)(0x70200000 + 0x04)) |= (1 << 1));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nandll_read_page>:
  endbr64
  mov    0x70200004,%rdx
  mov    %rsi,%rax
  and    $0xfffffffffffffffd,%rdx
  mov    %rdx,0x70200004
  movzbl %sil,%edx
  movq   $0x0,0x70200008
  movq   $0x0,0x7020000c
  movq   $0x0,0x7020000c
  mov    %rdx,0x7020000c
  movzbl %ah,%edx
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    %rdx,0x7020000c
  mov    %rax,0x7020000c
  movq   $0x30,0x70200008
  nopl   0x0(%rax)
L19:
  mov    0x70200028,%rax
  test   $0x1,%al
  je     L19
  lea    0x800(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl 0x70200010,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rdx,%rdi
  jne    L11
  mov    0x70200004,%rax
  or     $0x2,%rax
  mov    %rax,0x70200004
  xor    %eax,%eax
  ret
```

assistant: ```c
int nandll_read_page(unsigned char *buf, unsigned long addr) {
  int i;
  int page_size = 2048;
  ((*(volatile unsigned long *)(0x70200000 + 0x04)) &= ~(1 << 1));
  (*(volatile unsigned long *)(0x70200000 + 0x08)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr)&0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr >> 8) & 0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr >> 16) & 0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x08)) = 0x30;
  do {
    while (!((*(volatile unsigned long *)(0x70200000 + 0x28)) & (1 << 0)))
      ;
  } while (0);
  for (i = 0; i < page_size; i++) {
    *buf++ = (*(volatile unsigned char *)(0x70200000 + 0x10));
  }
  ((*(volatile unsigned long *)(0x70200000 + 0x04)) |= (1 << 1));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nandll_read_page>:
  endbr64
  mov    0x70200004,%rdx
  mov    %rsi,%rax
  and    $0xfffffffffffffffd,%rdx
  mov    %rdx,0x70200004
  movzbl %sil,%edx
  movq   $0x0,0x70200008
  movq   $0x0,0x7020000c
  movq   $0x0,0x7020000c
  mov    %rdx,0x7020000c
  movzbl %ah,%edx
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    %rdx,0x7020000c
  mov    %rax,0x7020000c
  movq   $0x30,0x70200008
  nopl   0x0(%rax)
L1:
  mov    0x70200028,%rax
  test   $0x1,%al
  je     L1
  lea    0x800(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl 0x70200010,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rdx,%rdi
  jne    L13
  mov    0x70200004,%rax
  or     $0x2,%rax
  mov    %rax,0x70200004
  xor    %eax,%eax
  ret
```

assistant: ```c
int nandll_read_page(unsigned char *buf, unsigned long addr) {
  int i;
  int page_size = 2048;
  ((*(volatile unsigned long *)(0x70200000 + 0x04)) &= ~(1 << 1));
  (*(volatile unsigned long *)(0x70200000 + 0x08)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = 0;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr)&0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr >> 8) & 0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x0c)) = (addr >> 16) & 0xff;
  (*(volatile unsigned long *)(0x70200000 + 0x08)) = 0x30;
  do {
    while (!((*(volatile unsigned long *)(0x70200000 + 0x28)) & (1 << 0)))
      ;
  } while (0);
  for (i = 0; i < page_size; i++) {
    *buf++ = (*(volatile unsigned char *)(0x70200000 + 0x10));
  }
  ((*(volatile unsigned long *)(0x70200000 + 0x04)) |= (1 << 1));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<teredo_recverr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
ssize_t teredo_recverr(int fd) {
  (void)fd;
  errno = EAGAIN;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<teredo_recverr>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t teredo_recverr(int fd) {
  (void)fd;
  errno = EAGAIN;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<teredo_recverr>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t teredo_recverr(int fd) {
  (void)fd;
  errno = EAGAIN;
  return -1;
}
```