ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<update_oven>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    %r9,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x38(%rbp)
  je     L13
  mov    $0x31,%edx
  jmp    L21
L13:
  mov    $0x30,%edx
L21:
  cmpl   $0x0,-0x3c(%rbp)
  je     L57
  mov    $0x2,%eax
  jmp    L24
L57:
  mov    $0x0,%eax
L24:
  add    %edx,%eax
  mov    %al,-0x25(%rbp)
  lea    -0x25(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <rs232_send@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x58(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x9,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <rs232_read@plt>
  mov    %eax,-0x24(%rbp)
  movb   $0x0,-0x17(%rbp)
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jg     L35
  mov    $0xffffffff,%eax
  jmp    L0
L35:
  mov    $0x0,%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: %3d %3d

assistant: ```c
int update_oven(int fd, int lamp, int fan, int *t1, int *t2, struct timeval *tv) {
  char buf = '0' + (lamp ? 1 : 0) + (fan ? 2 : 0);
  char rxbuf[16];
  int i;
  int res = rs232_send(fd, &buf, 1);
  gettimeofday(tv, NULL);
  res = rs232_read(fd, rxbuf, 9);
  rxbuf[9] = 0;
  res = sscanf(rxbuf, "%3d %3d", t1, t2);
  if (res < 2)
    return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<update_oven>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %rcx,%rbp
  mov    %r8,%r12
  mov    %r9,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  setne  %al
  add    %eax,%eax
  cmp    $0x1,%esi
  sbb    $0xcf,%al
  mov    %al,0xf(%rsp)
  lea    0xf(%rsp),%rsi
  mov    $0x1,%edx
  call   <rs232_send@plt>
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <gettimeofday@plt>
  lea    0x10(%rsp),%r13
  mov    $0x9,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <rs232_read@plt>
  movb   $0x0,0x19(%rsp)
  mov    %r12,%rcx
  mov    %rbp,%rdx
  lea    D2(%rip),%rsi
  mov    %r13,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  setle  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: %3d %3d

assistant: ```c
int update_oven(int fd, int lamp, int fan, int *t1, int *t2, struct timeval *tv) {
  char buf = '0' + (lamp ? 1 : 0) + (fan ? 2 : 0);
  char rxbuf[16];
  int i;
  int res = rs232_send(fd, &buf, 1);
  gettimeofday(tv, NULL);
  res = rs232_read(fd, rxbuf, 9);
  rxbuf[9] = 0;
  res = sscanf(rxbuf, "%3d %3d", t1, t2);
  if (res < 2)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<update_oven>:
  endbr64
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  mov    $0x1,%edx
  setne  %al
  add    %eax,%eax
  cmp    $0x1,%esi
  lea    0xf(%rsp),%rsi
  sbb    $0xcf,%al
  mov    %al,0xf(%rsp)
  call   <rs232_send@plt>
  xor    %esi,%esi
  mov    %r14,%rdi
  lea    0x10(%rsp),%r14
  call   <gettimeofday@plt>
  mov    $0x9,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <rs232_read@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rdi
  lea    D1(%rip),%rsi
  movb   $0x0,0x19(%rsp)
  call   <sscanf@plt>
  cmp    $0x1,%eax
  setle  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string

tool: D1: %3d %3d

assistant: ```c
int update_oven(int fd, int lamp, int fan, int *t1, int *t2, struct timeval *tv) {
  char buf = '0' + (lamp ? 1 : 0) + (fan ? 2 : 0);
  char rxbuf[16];
  int i;
  int res = rs232_send(fd, &buf, 1);
  gettimeofday(tv, NULL);
  res = rs232_read(fd, rxbuf, 9);
  rxbuf[9] = 0;
  res = sscanf(rxbuf, "%3d %3d", t1, t2);
  if (res < 2)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<update_oven>:
  endbr64
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  mov    $0x1,%edx
  setne  %al
  add    %eax,%eax
  cmp    $0x1,%esi
  lea    0xf(%rsp),%rsi
  sbb    $0xcf,%al
  mov    %al,0xf(%rsp)
  call   <rs232_send@plt>
  xor    %esi,%esi
  mov    %r14,%rdi
  lea    0x10(%rsp),%r14
  call   <gettimeofday@plt>
  mov    $0x9,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <rs232_read@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rdi
  lea    D9(%rip),%rsi
  movb   $0x0,0x19(%rsp)
  call   <sscanf@plt>
  cmp    $0x1,%eax
  setle  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D9: %3d %3d

assistant: ```c
int update_oven(int fd, int lamp, int fan, int *t1, int *t2, struct timeval *tv) {
  char buf = '0' + (lamp ? 1 : 0) + (fan ? 2 : 0);
  char rxbuf[16];
  int i;
  int res = rs232_send(fd, &buf, 1);
  gettimeofday(tv, NULL);
  res = rs232_read(fd, rxbuf, 9);
  rxbuf[9] = 0;
  res = sscanf(rxbuf, "%3d %3d", t1, t2);
  if (res < 2)
    return -1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_si_scaling>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x474d6b20,-0xd(%rbp)
  movb   $0x54,-0x9(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  mov    %eax,%edi
  call   <log10f@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L27
  mov    -0x18(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  add    $0x3,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L2
L27:
  mov    $0x0,%eax
L2:
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L25
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%edx
  mov    -0x38(%rbp),%rax
  mov    %dl,(%rax)
L25:
  cmpq   $0x0,-0x40(%rbp)
  je     L1
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
L1:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    D4(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <powf@plt>
  movsd  -0x28(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: f64

tool: D4: 10

assistant: ```c
double _si_scaling(double val, int max_num, char *prefix, int *exp) {
  const char prefixes[5] = {' ', 'k', 'M', 'G', 'T'};
  int exponent = log10f(fabs(val));
  int d = exponent >= max_num ? ((exponent - max_num + 3) / 3) : 0;
  if (prefix)
    *prefix = prefixes[d];
  if (exp)
    *exp = d * 3;
  return val / powf(10.0, d * 3);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_si_scaling>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x474d6b20,0x3(%rsp)
  movb   $0x54,0x7(%rsp)
  call   <fabs@plt>
  mov    %eax,%edi
  call   <log10f@plt>
  mov    $0x0,%edx
  cmp    %r13d,%eax
  jl     L36
  sub    %r13d,%eax
  add    $0x3,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
L36:
  test   %r12,%r12
  je     L12
  movslq %edx,%rax
  movzbl 0x3(%rsp,%rax,1),%eax
  mov    %al,(%r12)
L12:
  test   %rbp,%rbp
  je     L35
  lea    (%rdx,%rdx,2),%eax
  mov    %eax,0x0(%rbp)
L35:
  lea    (%rdx,%rdx,2),%edi
  movsd  D5(%rip),%xmm0
  call   <powf@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: f64

tool: D5: 10

assistant: ```c
double _si_scaling(double val, int max_num, char *prefix, int *exp) {
  const char prefixes[5] = {' ', 'k', 'M', 'G', 'T'};
  int exponent = log10f(fabs(val));
  int d = exponent >= max_num ? ((exponent - max_num + 3) / 3) : 0;
  if (prefix)
    *prefix = prefixes[d];
  if (exp)
    *exp = d * 3;
  return val / powf(10.0, d * 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_si_scaling>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x474d6b20,0x3(%rsp)
  movb   $0x54,0x7(%rsp)
  call   <fabs@plt>
  mov    %eax,%edi
  call   <log10f@plt>
  cmp    %r12d,%eax
  jl     L49
  sub    %r12d,%eax
  mov    $0xaaaaaaab,%edx
  add    $0x3,%eax
  imul   %rdx,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%edi
L4:
  test   %rbp,%rbp
  je     L32
  cltq
  movzbl 0x3(%rsp,%rax,1),%eax
  mov    %al,0x0(%rbp)
L32:
  test   %rbx,%rbx
  je     L11
  mov    %edi,(%rbx)
L11:
  movsd  D3(%rip),%xmm0
  call   <powf@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  divsd  %xmm1,%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L4
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: f64

tool: D3: 10

assistant: ```c
double _si_scaling(double val, int max_num, char *prefix, int *exp) {
  const char prefixes[5] = {' ', 'k', 'M', 'G', 'T'};
  int exponent = log10f(fabs(val));
  int d = exponent >= max_num ? ((exponent - max_num + 3) / 3) : 0;
  if (prefix)
    *prefix = prefixes[d];
  if (exp)
    *exp = d * 3;
  return val / powf(10.0, d * 3);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_si_scaling>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x474d6b20,0x3(%rsp)
  movb   $0x54,0x7(%rsp)
  call   <fabs@plt>
  mov    %eax,%edi
  call   <log10f@plt>
  cmp    %r12d,%eax
  jl     L5
  sub    %r12d,%eax
  mov    $0xaaaaaaab,%edx
  add    $0x3,%eax
  imul   %rdx,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%edi
L8:
  test   %rbp,%rbp
  je     L2
  cltq
  movzbl 0x3(%rsp,%rax,1),%eax
  mov    %al,0x0(%rbp)
L2:
  test   %rbx,%rbx
  je     L41
  mov    %edi,(%rbx)
L41:
  movsd  D7(%rip),%xmm0
  call   <powf@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  divsd  %xmm1,%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L8
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
datatype: f64

tool: D7: 10

assistant: ```c
double _si_scaling(double val, int max_num, char *prefix, int *exp) {
  const char prefixes[5] = {' ', 'k', 'M', 'G', 'T'};
  int exponent = log10f(fabs(val));
  int d = exponent >= max_num ? ((exponent - max_num + 3) / 3) : 0;
  if (prefix)
    *prefix = prefixes[d];
  if (exp)
    *exp = d * 3;
  return val / powf(10.0, d * 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L70
L18:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movq   $0x0,-0x20(%rbp)
  jmp    L28
L60:
  movq   $0x0,-0x28(%rbp)
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x14(%rbp,%rax,4)
  addq   $0x1,-0x20(%rbp)
L28:
  mov    -0x30(%rbp),%rax
  cmp    %rax,-0x20(%rbp)
  jb     L60
  addl   $0x1,-0x34(%rbp)
L70:
  cmpl   $0x2,-0x34(%rbp)
  jle    L18
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L43
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jne    L43
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L43:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D25
data_type: string

tool: D5: %lu

tool: D16: Hromadky jsou v poradku.

tool: D25: Polevku nelze varit.

assistant: ```c
int main(int argc, char const *argvc[]) {
  int values[3] = {0};
  for (int i = 0; i < 3; i++) {
    unsigned long N;
    scanf("%lu", &N);
    getchar();
    for (unsigned long x = 0; x < N; x++) {
      unsigned long a = 0;
      scanf("%lu", &a);
      values[i] = values[i] | a;
    }
  }
  if (values[0] == values[1] && values[1] == values[2])
    printf("Hromadky jsou v poradku.");
  else
    printf("Polevku nelze varit.");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x1c(%rsp)
  movl   $0x0,0x24(%rsp)
  lea    0x1c(%rsp),%rbp
  lea    0x28(%rsp),%r13
  lea    D27(%rip),%r12
L51:
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L69
  mov    $0x0,%ebx
L34:
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  or     %eax,0x0(%rbp)
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  ja     L34
L69:
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L51
  mov    0x20(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jne    L13
  cmp    0x24(%rsp),%eax
  je     L9
L13:
  lea    D3(%rip),%rdi
  call   <printf@plt>
L57:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L57
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D3
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D27: %lu

tool: D3: Polevku nelze varit.

tool: D10: Hromadky jsou v poradku.

assistant: ```c
int main(int argc, char const *argvc[]) {
  int values[3] = {0};
  for (int i = 0; i < 3; i++) {
    unsigned long N;
    scanf("%lu", &N);
    getchar();
    for (unsigned long x = 0; x < N; x++) {
      unsigned long a = 0;
      scanf("%lu", &a);
      values[i] = values[i] | a;
    }
  }
  if (values[0] == values[1] && values[1] == values[2])
    printf("Hromadky jsou v poradku.");
  else
    printf("Polevku nelze varit.");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbp
  lea    0x28(%rsp),%r15
  movq   $0x0,0x1c(%rsp)
  movl   $0x0,0x24(%rsp)
  lea    0x8(%rsp),%r14
  lea    0x10(%rsp),%r13
L64:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L60
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  movq   $0x0,0x10(%rsp)
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  or     %eax,0x0(%rbp)
  cmp    %rbx,0x8(%rsp)
  ja     L1
L60:
  add    $0x4,%rbp
  cmp    %r15,%rbp
  jne    L64
  mov    0x20(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jne    L2
  cmp    0x24(%rsp),%eax
  je     L13
L2:
  lea    D26(%rip),%rdi
  call   <printf@plt>
L48:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L48
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D6
data_type: string

tool: D10: %lu

tool: D26: Polevku nelze varit.

tool: D6: Hromadky jsou v poradku.

assistant: ```c
int main(int argc, char const *argvc[]) {
  int values[3] = {0};
  for (int i = 0; i < 3; i++) {
    unsigned long N;
    scanf("%lu", &N);
    getchar();
    for (unsigned long x = 0; x < N; x++) {
      unsigned long a = 0;
      scanf("%lu", &a);
      values[i] = values[i] | a;
    }
  }
  if (values[0] == values[1] && values[1] == values[2])
    printf("Hromadky jsou v poradku.");
  else
    printf("Polevku nelze varit.");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbp
  lea    0x28(%rsp),%r15
  movq   $0x0,0x1c(%rsp)
  movl   $0x0,0x24(%rsp)
  lea    0x8(%rsp),%r14
  lea    0x10(%rsp),%r13
L10:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L66
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  movq   $0x0,0x10(%rsp)
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  or     %eax,0x0(%rbp)
  cmp    %rbx,0x8(%rsp)
  ja     L26
L66:
  add    $0x4,%rbp
  cmp    %r15,%rbp
  jne    L10
  mov    0x20(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jne    L16
  cmp    0x24(%rsp),%eax
  je     L31
L16:
  lea    D6(%rip),%rdi
  call   <printf@plt>
L68:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L68
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D24
data_type: string
name: unpack_data
arguments: data_label: D6
data_type: string
name: unpack_data
arguments: data_label: D15
data_type: string

tool: D24: %lu

tool: D6: Polevku nelze varit.

tool: D15: Hromadky jsou v poradku.

assistant: ```c
int main(int argc, char const *argvc[]) {
  int values[3] = {0};
  for (int i = 0; i < 3; i++) {
    unsigned long N;
    scanf("%lu", &N);
    getchar();
    for (unsigned long x = 0; x < N; x++) {
      unsigned long a = 0;
      scanf("%lu", &a);
      values[i] = values[i] | a;
    }
  }
  if (values[0] == values[1] && values[1] == values[2])
    printf("Hromadky jsou v poradku.");
  else
    printf("Polevku nelze varit.");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set_ticker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x40(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x3e8,%rax,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <setitimer@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
extern void set_ticker(int n_msecs) {
  struct itimerval new_timeset;
  long n_sec = n_msecs / 1000;
  long n_usecs = (n_msecs % 1000) * 1000L;
  new_timeset.it_value.tv_sec = n_sec;
  new_timeset.it_value.tv_usec = n_usecs;
  new_timeset.it_interval.tv_sec = n_sec;
  new_timeset.it_interval.tv_usec = n_usecs;
  setitimer(ITIMER_REAL, &new_timeset, NULL);
}
```
user: What is the c source code of the assembly code below?

```asm
<set_ticker>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rdi
  imul   $0x3e8,%rdi,%rdi
  mov    %rdx,0x10(%rsp)
  mov    %rdi,0x18(%rsp)
  mov    %rdx,(%rsp)
  mov    %rdi,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void set_ticker(int n_msecs) {
  struct itimerval new_timeset;
  long n_sec = n_msecs / 1000;
  long n_usecs = (n_msecs % 1000) * 1000L;
  new_timeset.it_value.tv_sec = n_sec;
  new_timeset.it_value.tv_usec = n_usecs;
  new_timeset.it_interval.tv_sec = n_sec;
  new_timeset.it_interval.tv_usec = n_usecs;
  setitimer(ITIMER_REAL, &new_timeset, NULL);
}
```