ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<flush_fd>:
  endbr64
  push   %rbp
  movd   %edi,%xmm0
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  lea    -0x40(%rbp),%r13
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    D48(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x40(%rbp)
L116:
  movslq (%r12),%rax
  mov    %rsp,%rcx
  mov    %rsp,%r15
  mov    %rax,%r14
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L136
L48:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L48
L136:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L111
L40:
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <poll@plt>
  test   %eax,%eax
  js     L102
  je     L37
  mov    %r14d,%edx
  mov    %rsp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  test   %rax,%rax
  js     L87
  je     L37
L17:
  mov    %r15,%rsp
  jmp    L116
L102:
  mov    D58(%rip),%rax
  mov    D25(%rip),%rdx
  mov    (%rax),%eax
  cmp    (%rdx),%eax
  je     L17
L104:
  neg    %eax
L108:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L111:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L87:
  mov    D58(%rip),%rax
  mov    D25(%rip),%rdx
  mov    (%rax),%eax
  cmp    (%rdx),%eax
  je     L17
  mov    D69(%rip),%rdx
  cmp    (%rdx),%eax
  jne    L104
L37:
  xor    %eax,%eax
  jmp    L108
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int flush_fd(int fd) {
  struct pollfd pollfd = {
      .fd = fd,
      .events = POLLIN,
  };
  for (;;) {
    char buf[LINE_MAX];
    ssize_t l;
    int r;
    r = poll(&pollfd, 1, 0);
    if (r < 0) {
      if (errno == EINTR)
        continue;
      return -errno;
    } else if (r == 0)
      return 0;
    l = read(fd, buf, sizeof(buf));
    if (l < 0) {
      if (errno == EINTR)
        continue;
      if (errno == EAGAIN)
        return 0;
      return -errno;
    } else if (l == 0)
      return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,%ebp
  test   %esi,%esi
  jle    L189
  mov    $0x1,%ebx
L183:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L183
L189:
  lea    0x0(%rbp,%rbp,1),%r14d
  cmp    %r14d,%ebp
  jge    L126
  mov    %r14d,%r15d
  sub    %ebp,%r15d
  mov    $0x1,%r12d
  lea    0x1(%rbp),%r13d
  jmp    L135
L125:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L125
L96:
  lea    0x1(%r12),%eax
  cmp    %r15d,%r12d
  je     L126
  mov    %eax,%r12d
L135:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L125
  jmp    L96
L126:
  lea    0x1(%r14),%r12d
  mov    0xc(%rsp),%r13d
  add    %ebp,%r13d
  cmp    %r13d,%r12d
  jg     L70
  sub    %ebp,%r12d
  mov    $0x1,%r15d
  jmp    L161
L179:
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r15d,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L179
L157:
  add    $0x1,%r15d
  add    $0x1,%r12d
  lea    0x0(%rbp,%r12,1),%eax
  cmp    %r13d,%eax
  jg     L70
L161:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L179
  jmp    L157
L70:
  lea    0x1(%r13),%r12d
  add    %ebp,%r13d
  test   %ebp,%ebp
  jle    L85
  sub    %r14d,%r12d
  jmp    L77
L175:
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L175
L65:
  add    $0x1,%r12d
  lea    (%r14,%r12,1),%eax
  cmp    %eax,%r13d
  jl     L85
L77:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L175
  jmp    L65
L85:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void test(int M, int N) {
  int c1;
  int i, j;
  for (c1 = 1; c1 <= N; c1++) {
    {
      hash(1);
      hash(c1);
    };
  }
  for (c1 = N + 1; c1 <= 2 * N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - N;
      {
        hash(2);
        hash(i);
        hash(c1 - N);
      };
    }
  }
  for (c1 = 2 * N + 1; c1 <= M + N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - 2 * N;
      {
        hash(3);
        hash(i);
        hash(c1 - 2 * N);
      };
      j = c1 - N;
      {
        hash(2);
        hash(i);
        hash(c1 - N);
      };
    }
  }
  for (c1 = M + N + 1; c1 <= M + 2 * N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - 2 * N;
      {
        hash(3);
        hash(i);
        hash(c1 - 2 * N);
      };
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L137
L8:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L8
L137:
  lea    0x0(%rbp,%rbp,1),%r15d
  lea    0x1(%rbp),%eax
  cmp    %r15d,%eax
  jg     L59
  mov    %r15d,%r14d
  mov    $0x1,%r13d
  sub    %ebp,%r14d
  nopl   0x0(%rax)
L24:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L92
  nopl   0x0(%rax)
L75:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L75
L92:
  lea    0x1(%r13),%eax
  cmp    %r14d,%r13d
  je     L59
  mov    %eax,%r13d
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L59:
  add    %ebp,%r12d
  cmp    %r15d,%r12d
  jle    L89
  mov    %ebp,%eax
  mov    %r15d,%r13d
  sub    %r15d,%eax
  sub    %ebp,%r13d
  mov    %eax,0xc(%rsp)
  add    $0x1,%r13d
  nopl   0x0(%rax,%rax,1)
L135:
  mov    0xc(%rsp),%eax
  mov    $0x1,%ebx
  lea    (%rax,%r13,1),%r14d
  test   %ebp,%ebp
  jle    L110
  nopl   0x0(%rax)
L53:
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r14d,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L53
L110:
  add    $0x1,%r13d
  lea    0x0(%rbp,%r13,1),%eax
  cmp    %r12d,%eax
  jle    L135
L89:
  lea    0x0(%rbp,%r12,1),%r13d
  test   %ebp,%ebp
  jle    L80
  add    $0x1,%r12d
  sub    %r15d,%r12d
  nop
L58:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L26
  nopl   0x0(%rax)
L97:
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L97
L26:
  add    $0x1,%r12d
  lea    (%r15,%r12,1),%eax
  cmp    %eax,%r13d
  jge    L58
L80:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void test(int M, int N) {
  int c1;
  int i, j;
  for (c1 = 1; c1 <= N; c1++) {
    {
      hash(1);
      hash(c1);
    };
  }
  for (c1 = N + 1; c1 <= 2 * N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - N;
      {
        hash(2);
        hash(i);
        hash(c1 - N);
      };
    }
  }
  for (c1 = 2 * N + 1; c1 <= M + N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - 2 * N;
      {
        hash(3);
        hash(i);
        hash(c1 - 2 * N);
      };
      j = c1 - N;
      {
        hash(2);
        hash(i);
        hash(c1 - N);
      };
    }
  }
  for (c1 = M + N + 1; c1 <= M + 2 * N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - 2 * N;
      {
        hash(3);
        hash(i);
        hash(c1 - 2 * N);
      };
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L81
  mov    $0x1,%ebx
L30:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L30
  lea    0x0(%rbp,%rbp,1),%r15d
  lea    0x1(%rbp),%eax
  mov    %ebp,%r13d
  mov    $0x1,%r12d
  cmp    %r15d,%eax
  jg     L5
  nopw   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%ebx
  nopl   (%rax)
L136:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L136
  lea    0x1(%r12),%eax
  cmp    %r13d,%r12d
  je     L118
  mov    %eax,%r12d
  jmp    L22
L81:
  lea    (%rsi,%rsi,1),%r15d
  cmp    %r15d,%esi
  jge    L142
  xchg   %ax,%ax
L118:
  lea    0x1(%r15),%r12d
  add    %ebp,%r14d
  cmp    %r14d,%r12d
  jg     L130
  test   %ebp,%ebp
  jle    L130
L57:
  mov    %ebp,%eax
  sub    %ebp,%r12d
  sub    %r15d,%eax
  mov    %eax,0xc(%rsp)
  nopl   0x0(%rax)
L40:
  mov    0xc(%rsp),%eax
  mov    $0x1,%ebx
  lea    (%rax,%r12,1),%r13d
  nopl   (%rax)
L159:
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L159
  add    $0x1,%r12d
  lea    (%r12,%rbp,1),%eax
  cmp    %r14d,%eax
  jle    L40
L130:
  lea    0x1(%r14),%r12d
  add    %ebp,%r14d
  test   %ebp,%ebp
  jle    L109
  sub    %r15d,%r12d
  nopl   0x0(%rax)
L70:
  mov    $0x1,%ebx
  nopl   (%rax)
L162:
  mov    $0x3,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L162
  add    $0x1,%r12d
  lea    (%r15,%r12,1),%eax
  cmp    %r14d,%eax
  jle    L70
L109:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  lea    0x1(%r15),%r12d
  add    %ebp,%r14d
  cmp    %r14d,%r12d
  jle    L57
  jmp    L130
L142:
  add    %esi,%r14d
  jmp    L130
```

assistant: ```c
void test(int M, int N) {
  int c1;
  int i, j;
  for (c1 = 1; c1 <= N; c1++) {
    {
      hash(1);
      hash(c1);
    };
  }
  for (c1 = N + 1; c1 <= 2 * N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - N;
      {
        hash(2);
        hash(i);
        hash(c1 - N);
      };
    }
  }
  for (c1 = 2 * N + 1; c1 <= M + N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - 2 * N;
      {
        hash(3);
        hash(i);
        hash(c1 - 2 * N);
      };
      j = c1 - N;
      {
        hash(2);
        hash(i);
        hash(c1 - N);
      };
    }
  }
  for (c1 = M + N + 1; c1 <= M + 2 * N; c1++) {
    for (i = 1; i <= N; i++) {
      j = c1 - 2 * N;
      {
        hash(3);
        hash(i);
        hash(c1 - 2 * N);
      };
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x90(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x90(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D62
datatype: string
name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D17
datatype: string
name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D76
datatype: string
name: unpack_data
arguments: label: D18
datatype: string
name: unpack_data
arguments: label: D73
datatype: string
name: unpack_data
arguments: label: D3
datatype: string

tool: D62: 1000.10011

tool: D11: -100001.0011101

tool: D17: 111.111

tool: D24: -101.101

tool: D76: 111

tool: D18: 10.111

tool: D73: Enter number to convert from base 2 to 10: 

tool: D3: 
Enter number to convert from base 10 to 2: 

assistant: ```c
int main(void) {
  char str_buffer[64];
  puts(convert_2_to_10("1000.10011", str_buffer));
  puts(convert_2_to_10("-100001.0011101", str_buffer));
  puts(convert_10_to_2("111.111", str_buffer));
  puts(convert_10_to_2("-101.101", str_buffer));
  puts(convert_2_to_10("111", str_buffer));
  puts(convert_2_to_10("10.111", str_buffer));
  char input_buffer[64];
  printf("Enter number to convert from base 2 to 10: ");
  gets(input_buffer);
  puts(convert_2_to_10(input_buffer, str_buffer));
  printf("\nEnter number to convert from base 10 to 2: ");
  gets(input_buffer);
  puts(convert_10_to_2(input_buffer, str_buffer));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D25(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D39(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D37(%rip),%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D65(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x40(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    D77(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
type: string
name: disassemble_data
arguments: tag: D39
type: string
name: disassemble_data
arguments: tag: D37
type: string
name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D9
type: string
name: disassemble_data
arguments: tag: D65
type: string
name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D77
type: string

tool: D25: 1000.10011

tool: D39: -100001.0011101

tool: D37: 111.111

tool: D0: -101.101

tool: D9: 111

tool: D65: 10.111

tool: D5: Enter number to convert from base 2 to 10: 

tool: D77: 
Enter number to convert from base 10 to 2: 

assistant: ```c
int main(void) {
  char str_buffer[64];
  puts(convert_2_to_10("1000.10011", str_buffer));
  puts(convert_2_to_10("-100001.0011101", str_buffer));
  puts(convert_10_to_2("111.111", str_buffer));
  puts(convert_10_to_2("-101.101", str_buffer));
  puts(convert_2_to_10("111", str_buffer));
  puts(convert_2_to_10("10.111", str_buffer));
  char input_buffer[64];
  printf("Enter number to convert from base 2 to 10: ");
  gets(input_buffer);
  puts(convert_2_to_10(input_buffer, str_buffer));
  printf("\nEnter number to convert from base 10 to 2: ");
  gets(input_buffer);
  puts(convert_10_to_2(input_buffer, str_buffer));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%rdi
  push   %rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x40(%rsp),%r12
  mov    %rbp,%rsi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D49(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D30(%rip),%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D44(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string
name: unpack_data
arguments: data_tag: D49
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D44
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D61
type_guessed: string
name: unpack_data
arguments: data_tag: D54
type_guessed: string

tool: D4: 1000.10011

tool: D49: -100001.0011101

tool: D25: 111.111

tool: D30: -101.101

tool: D44: 111

tool: D15: 10.111

tool: D61: Enter number to convert from base 2 to 10: 

tool: D54: 
Enter number to convert from base 10 to 2: 

assistant: ```c
int main(void) {
  char str_buffer[64];
  puts(convert_2_to_10("1000.10011", str_buffer));
  puts(convert_2_to_10("-100001.0011101", str_buffer));
  puts(convert_10_to_2("111.111", str_buffer));
  puts(convert_10_to_2("-101.101", str_buffer));
  puts(convert_2_to_10("111", str_buffer));
  puts(convert_2_to_10("10.111", str_buffer));
  char input_buffer[64];
  printf("Enter number to convert from base 2 to 10: ");
  gets(input_buffer);
  puts(convert_2_to_10(input_buffer, str_buffer));
  printf("\nEnter number to convert from base 10 to 2: ");
  gets(input_buffer);
  puts(convert_10_to_2(input_buffer, str_buffer));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D48(%rip),%rdi
  push   %rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x40(%rsp),%r12
  mov    %rbp,%rsi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D30(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D79(%rip),%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D45(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <convert_2_to_10@plt>
  mov    %eax,%edi
  call   <puts@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <convert_10_to_2@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D48
datatype: string
name: parse_data
arguments: tag: D30
datatype: string
name: parse_data
arguments: tag: D79
datatype: string
name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D45
datatype: string
name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D26
datatype: string
name: parse_data
arguments: tag: D67
datatype: string

tool: D48: 1000.10011

tool: D30: -100001.0011101

tool: D79: 111.111

tool: D4: -101.101

tool: D45: 111

tool: D17: 10.111

tool: D26: Enter number to convert from base 2 to 10: 

tool: D67: 
Enter number to convert from base 10 to 2: 

assistant: ```c
int main(void) {
  char str_buffer[64];
  puts(convert_2_to_10("1000.10011", str_buffer));
  puts(convert_2_to_10("-100001.0011101", str_buffer));
  puts(convert_10_to_2("111.111", str_buffer));
  puts(convert_10_to_2("-101.101", str_buffer));
  puts(convert_2_to_10("111", str_buffer));
  puts(convert_2_to_10("10.111", str_buffer));
  char input_buffer[64];
  printf("Enter number to convert from base 2 to 10: ");
  gets(input_buffer);
  puts(convert_2_to_10(input_buffer, str_buffer));
  printf("\nEnter number to convert from base 10 to 2: ");
  gets(input_buffer);
  puts(convert_10_to_2(input_buffer, str_buffer));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  subq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  mov    %eax,%edi
  call   <pb@plt>
  cmpq   $0x1,-0x8(%rbp)
  jbe    L4
  mov    -0x8(%rbp),%rax
  sub    $0x2,%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L4:
  nop
  nop
  leave
  ret
```

assistant: ```c
run(unsigned long long n) {
  n--;
  while (1) {
    pb((int)(n & 1));
    if (n < 2)
      break;
    n = (n - 2) / 2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<run>:
  endbr64
  push   %rbx
  lea    -0x1(%rdi),%rbx
  jmp    L17
L13:
  sub    $0x2,%rbx
  shr    %rbx
L17:
  mov    %ebx,%edi
  and    $0x1,%edi
  call   <pb@plt>
  cmp    $0x1,%rbx
  ja     L13
  pop    %rbx
  ret
```

assistant: ```c
run(unsigned long long n) {
  n--;
  while (1) {
    pb((int)(n & 1));
    if (n < 2)
      break;
    n = (n - 2) / 2;
  }
}
```