ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<makedname>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %ecx,%r13d
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %r14d,%rdx
  lea    0x2(%rdx,%rax,1),%rdx
  movslq %r13d,%r13
  mov    $0x0,%eax
  cmp    %r13,%rdx
  ja     L52
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L32
L44:
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L44
L32:
  cmpb   $0x2f,-0x1(%rbx)
  je     L16
  movb   $0x2f,(%rbx)
  lea    0x1(%rbx),%rbx
L16:
  lea    -0x1(%r14),%esi
  test   %r14d,%r14d
  je     L58
  lea    -0x1(%r14),%ecx
  mov    $0x0,%eax
L8:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L8
  mov    %esi,%esi
  lea    0x1(%rbx,%rsi,1),%rbx
L58:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int makedname(d, f, out, outlen)
char *d;
char *f;
char *out;
int outlen;
{
  char *cp;
  int length;
  length = strlen(f);
  if (strlen(d) + length + 2 > outlen)
    return (0);
  for (cp = out; *d; *cp++ = *d++)
    ;
  if (*(cp - 1) != '/')
    *cp++ = '/';
  while (length--)
    *cp++ = *f++;
  *cp = '\0';
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<makedname>:
  endbr64
  push   %r14
  push   %r13
  movslq %ecx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  movslq %r14d,%rdx
  lea    0x2(%rdx,%rax,1),%rdx
  xor    %eax,%eax
  cmp    %r13,%rdx
  ja     L18
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L1
  nopw   0x0(%rax,%rax,1)
L23:
  add    $0x1,%rbp
  mov    %edx,%ecx
  mov    %dl,(%rbx)
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  jne    L23
L26:
  cmp    $0x2f,%cl
  je     L57
  movb   $0x2f,(%rbx)
  add    $0x1,%rbx
L57:
  lea    -0x1(%r14),%esi
  test   %r14d,%r14d
  je     L53
  mov    %esi,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L33:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L33
  lea    0x1(%rbx,%rsi,1),%rbx
L53:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movzbl -0x1(%rbx),%ecx
  jmp    L26
```

assistant: ```c
int makedname(d, f, out, outlen)
char *d;
char *f;
char *out;
int outlen;
{
  char *cp;
  int length;
  length = strlen(f);
  if (strlen(d) + length + 2 > outlen)
    return (0);
  for (cp = out; *d; *cp++ = *d++)
    ;
  if (*(cp - 1) != '/')
    *cp++ = '/';
  while (length--)
    *cp++ = *f++;
  *cp = '\0';
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<makedname>:
  endbr64
  push   %r14
  movslq %ecx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  movslq %r12d,%rdx
  lea    0x2(%rdx,%rax,1),%rdx
  xor    %eax,%eax
  cmp    %r14,%rdx
  ja     L96
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L179
  nopw   0x0(%rax,%rax,1)
L168:
  add    $0x1,%rbp
  mov    %eax,%edx
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L168
L131:
  cmp    $0x2f,%dl
  je     L71
  movb   $0x2f,(%rbx)
  add    $0x1,%rbx
L71:
  lea    -0x1(%r12),%ecx
  mov    %ecx,%edi
  test   %r12d,%r12d
  je     L125
  lea    0x1(%r13),%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  cmp    $0xe,%rax
  jbe    L219
  cmp    $0x6,%ecx
  jbe    L219
  cmp    $0xe,%ecx
  jbe    L170
  mov    %r12d,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
  nopw   0x0(%rax,%rax,1)
L132:
  movdqu 0x0(%r13,%rax,1),%xmm0
  movups %xmm0,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L132
  mov    %r12d,%eax
  mov    %ecx,%edi
  and    $0xfffffff0,%eax
  mov    %eax,%edx
  sub    %eax,%edi
  lea    0x0(%r13,%rdx,1),%r8
  add    %rbx,%rdx
  cmp    %eax,%r12d
  je     L177
L83:
  sub    %eax,%r12d
  lea    -0x1(%r12),%esi
  cmp    $0x6,%esi
  jbe    L60
  mov    0x0(%r13,%rax,1),%rsi
  mov    %rsi,(%rbx,%rax,1)
  mov    %r12d,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%esi
  sub    %eax,%edi
  add    %rsi,%r8
  add    %rsi,%rdx
  cmp    %eax,%r12d
  je     L177
L60:
  movzbl (%r8),%eax
  mov    %al,(%rdx)
  test   %edi,%edi
  je     L177
  movzbl 0x1(%r8),%eax
  mov    %al,0x1(%rdx)
  cmp    $0x1,%edi
  je     L177
  movzbl 0x2(%r8),%eax
  mov    %al,0x2(%rdx)
  cmp    $0x2,%edi
  je     L177
  movzbl 0x3(%r8),%eax
  mov    %al,0x3(%rdx)
  cmp    $0x3,%edi
  je     L177
  movzbl 0x4(%r8),%eax
  mov    %al,0x4(%rdx)
  cmp    $0x4,%edi
  je     L177
  movzbl 0x5(%r8),%eax
  mov    %al,0x5(%rdx)
  cmp    $0x5,%edi
  je     L177
  movzbl 0x6(%r8),%eax
  mov    %al,0x6(%rdx)
L177:
  mov    %ecx,%ecx
  lea    0x1(%rbx,%rcx,1),%rbx
L125:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
L96:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L219:
  mov    %ecx,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L69:
  movzbl 0x0(%r13,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L69
  mov    %ecx,%ecx
  lea    0x1(%rbx,%rcx,1),%rbx
  jmp    L125
  cs nopw 0x0(%rax,%rax,1)
L179:
  movzbl -0x1(%rbx),%edx
  jmp    L131
L170:
  mov    %rbx,%rdx
  mov    %r13,%r8
  xor    %eax,%eax
  jmp    L83
```

assistant: ```c
int makedname(d, f, out, outlen)
char *d;
char *f;
char *out;
int outlen;
{
  char *cp;
  int length;
  length = strlen(f);
  if (strlen(d) + length + 2 > outlen)
    return (0);
  for (cp = out; *d; *cp++ = *d++)
    ;
  if (*(cp - 1) != '/')
    *cp++ = '/';
  while (length--)
    *cp++ = *f++;
  *cp = '\0';
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x24(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L19
L26:
  movq   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <execve@plt>
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: ./exec-null

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 0)
    return 0;
  char *exec_argv[1], *exec_envp[1];
  exec_argv[0] = exec_envp[0] = NULL;
  return execve("./exec-null", exec_argv, exec_envp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  test   %edi,%edi
  jne    L22
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x28,%rsp
  ret
L22:
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <execve@plt>
  jmp    L9
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D7: ./exec-null

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 0)
    return 0;
  char *exec_argv[1], *exec_envp[1];
  exec_argv[0] = exec_envp[0] = NULL;
  return execve("./exec-null", exec_argv, exec_envp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L10
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    D0(%rip),%rdi
  call   <execve@plt>
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: ./exec-null

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 0)
    return 0;
  char *exec_argv[1], *exec_envp[1];
  exec_argv[0] = exec_envp[0] = NULL;
  return execve("./exec-null", exec_argv, exec_envp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L4
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    D2(%rip),%rdi
  call   <execve@plt>
L4:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: ./exec-null

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 0)
    return 0;
  char *exec_argv[1], *exec_envp[1];
  exec_argv[0] = exec_envp[0] = NULL;
  return execve("./exec-null", exec_argv, exec_envp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jacmodhs76>:
  endbr64
  movsd  D9(%rip),%xmm1
  movsd  %xmm1,(%rsi)
  movq   $0x0,0x8(%rsi)
  movq   $0x0,0x10(%rsi)
  movq   $0x0,0x18(%rsi)
  movq   $0x0,0x20(%rsi)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movq   $0x0,0x30(%rsi)
  movq   $0x0,0x38(%rsi)
  movq   $0x0,0x40(%rsi)
  movq   $0x0,0x48(%rsi)
  movsd  %xmm1,0x50(%rsi)
  movq   $0x0,0x58(%rsi)
  movq   $0x0,0x60(%rsi)
  movq   $0x0,0x68(%rsi)
  movq   $0x0,0x70(%rsi)
  movsd  %xmm0,0x78(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: f64
name: retrieve_data
arguments: data_label: D10
type_infered: byte[8]

tool: D9: 1

tool: {"D10": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xe6,0x3f]}

assistant: ```c
void jacmodhs76(double *p, double *jac, int m, int n, void *data) {
  register int j = 0;
  jac[j++] = 1.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = sqrt(0.5);
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 1.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = sqrt(0.5);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<jacmodhs76>:
  endbr64
  movsd  D15(%rip),%xmm1
  movsd  D0(%rip),%xmm0
  movq   $0x0,0x8(%rsi)
  movq   $0x0,0x10(%rsi)
  movq   $0x0,0x18(%rsi)
  movq   $0x0,0x20(%rsi)
  movq   $0x0,0x30(%rsi)
  movq   $0x0,0x38(%rsi)
  movq   $0x0,0x40(%rsi)
  movq   $0x0,0x48(%rsi)
  movq   $0x0,0x58(%rsi)
  movq   $0x0,0x60(%rsi)
  movq   $0x0,0x68(%rsi)
  movq   $0x0,0x70(%rsi)
  movsd  %xmm1,(%rsi)
  movsd  %xmm0,0x28(%rsi)
  movsd  %xmm1,0x50(%rsi)
  movsd  %xmm0,0x78(%rsi)
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
type_infered: f64
name: read_data
arguments: data_label: D0
type_infered: byte[8]

tool: D15: 1

tool: {"D0": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xe6,0x3f]}

assistant: ```c
void jacmodhs76(double *p, double *jac, int m, int n, void *data) {
  register int j = 0;
  jac[j++] = 1.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = sqrt(0.5);
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 1.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = sqrt(0.5);
}
```
user: What is the c source code of the assembly code below:

```asm
<jacmodhs76>:
  endbr64
  movq   D10(%rip),%xmm2
  movapd D13(%rip),%xmm1
  pxor   %xmm0,%xmm0
  movups %xmm0,0x10(%rsi)
  movups %xmm2,(%rsi)
  movups %xmm1,0x20(%rsi)
  movups %xmm0,0x30(%rsi)
  movups %xmm0,0x40(%rsi)
  movups %xmm2,0x50(%rsi)
  movups %xmm0,0x60(%rsi)
  movups %xmm1,0x70(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: label: D10
data_type: f64
name: parse_data
arguments: label: D13
data_type: f64[2]

tool: D10: 1

tool: {"D13": [0.0,0.7071067811865476]}

assistant: ```c
void jacmodhs76(double *p, double *jac, int m, int n, void *data) {
  register int j = 0;
  jac[j++] = 1.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = sqrt(0.5);
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 1.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = 0.0;
  jac[j++] = sqrt(0.5);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D67(%rip),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  movsd  D47(%rip),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D14(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  D59(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D71(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D84(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D73(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x5,-0x70(%rbp)
  movl   $0x2,-0x6c(%rbp)
  mov    -0x6c(%rbp),%edx
  lea    -0x60(%rbp),%rcx
  mov    -0x70(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <stdlib_strided_dnanmax@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  movq   %rax,%xmm0
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D67
data_type: f64
name: retrieve_data
arguments: data_label: D47
data_type: f64
name: retrieve_data
arguments: data_label: D5
data_type: f64
name: retrieve_data
arguments: data_label: D14
data_type: f64
name: retrieve_data
arguments: data_label: D59
data_type: f64
name: retrieve_data
arguments: data_label: D71
data_type: f64
name: retrieve_data
arguments: data_label: D84
data_type: f64
name: retrieve_data
arguments: data_label: D73
data_type: f64
name: retrieve_data
arguments: data_label: D21
data_type: string

tool: D67: 1

tool: D47: 2

tool: D5: 3

tool: D14: 4

tool: D59: 5

tool: D71: 6

tool: D84: 7

tool: D73: 8

tool: D21: max: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 0.0 / 0.0, 0.0 / 0.0};
  int64_t N = 5;
  int64_t stride = 2;
  double v = stdlib_strided_dnanmax(N, x, stride);
  printf("max: %lf\n", v);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D52(%rip),%rax
  mov    %rax,(%rsp)
  mov    D68(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D88(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D2(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D44(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D64(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D78(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D1(%rip),%rax
  mov    %rax,0x38(%rsp)
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,0x40(%rsp)
  movsd  %xmm0,0x48(%rsp)
  mov    %rsp,%rsi
  mov    $0x2,%edx
  mov    $0x5,%edi
  call   <stdlib_strided_dnanmax@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x68,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D52
data_type: f64
name: parse_data
arguments: data_tag: D68
data_type: f64
name: parse_data
arguments: data_tag: D88
data_type: f64
name: parse_data
arguments: data_tag: D2
data_type: f64
name: parse_data
arguments: data_tag: D44
data_type: f64
name: parse_data
arguments: data_tag: D64
data_type: f64
name: parse_data
arguments: data_tag: D78
data_type: f64
name: parse_data
arguments: data_tag: D1
data_type: f64
name: parse_data
arguments: data_tag: D69
data_type: string

tool: D52: 1

tool: D68: 2

tool: D88: 3

tool: D2: 4

tool: D44: 5

tool: D64: 6

tool: D78: 7

tool: D1: 8

tool: D69: max: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 0.0 / 0.0, 0.0 / 0.0};
  int64_t N = 5;
  int64_t stride = 2;
  double v = stdlib_strided_dnanmax(N, x, stride);
  printf("max: %lf\n", v);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x68,%rsp
  mov    $0x5,%edi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  divsd  %xmm0,%xmm0
  mov    D53(%rip),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  mov    D83(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D46(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D64(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D24(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D69(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D3(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D66(%rip),%rax
  mov    %rax,0x38(%rsp)
  movsd  %xmm0,0x40(%rsp)
  movsd  %xmm0,0x48(%rsp)
  call   <stdlib_strided_dnanmax@plt>
  lea    D72(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D53
type_infered: f64
name: read_data
arguments: tag: D83
type_infered: f64
name: read_data
arguments: tag: D46
type_infered: f64
name: read_data
arguments: tag: D64
type_infered: f64
name: read_data
arguments: tag: D24
type_infered: f64
name: read_data
arguments: tag: D69
type_infered: f64
name: read_data
arguments: tag: D3
type_infered: f64
name: read_data
arguments: tag: D66
type_infered: f64
name: read_data
arguments: tag: D72
type_infered: string

tool: D53: 1

tool: D83: 2

tool: D46: 3

tool: D64: 4

tool: D24: 5

tool: D69: 6

tool: D3: 7

tool: D66: 8

tool: D72: max: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 0.0 / 0.0, 0.0 / 0.0};
  int64_t N = 5;
  int64_t stride = 2;
  double v = stdlib_strided_dnanmax(N, x, stride);
  printf("max: %lf\n", v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    $0x5,%edi
  mov    $0x2,%edx
  movapd D45(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movapd D3(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movapd D43(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movapd D30(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  unpcklpd %xmm0,%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <stdlib_strided_dnanmax@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D45
type_infered: f64[2]
name: read_data
arguments: tag: D3
type_infered: f64[2]
name: read_data
arguments: tag: D43
type_infered: f64[2]
name: read_data
arguments: tag: D30
type_infered: f64[2]
name: read_data
arguments: tag: D40
type_infered: string

tool: {"D45": [1.0,2.0]}

tool: {"D3": [3.0,4.0]}

tool: {"D43": [5.0,6.0]}

tool: {"D30": [7.0,8.0]}

tool: D40: max: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 0.0 / 0.0, 0.0 / 0.0};
  int64_t N = 5;
  int64_t stride = 2;
  double v = stdlib_strided_dnanmax(N, x, stride);
  printf("max: %lf\n", v);
}
```
user: Translate the below assembly code into C programming language:

```asm
<handle_exception>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void handle_exception() {
  void *p = malloc(1024);
  free(p);
  free(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<handle_exception>:
  endbr64
  push   %rbx
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void handle_exception() {
  void *p = malloc(1024);
  free(p);
  free(p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<handle_exception>:
  endbr64
  push   %rbp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void handle_exception() {
  void *p = malloc(1024);
  free(p);
  free(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<handle_exception>:
  endbr64
  push   %rbp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void handle_exception() {
  void *p = malloc(1024);
  free(p);
  free(p);
}
```