user: 这段汇编代码用C语言表示是什么样的：

```asm
<count_4>:
  endbr64
  push   %r15
  mov    $0xd,%ecx
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    %rdi,0x8(%rsp)
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  jmp    L81
  nopl   0x0(%rax)
L79:
  call   <toupper@plt>
  add    $0x1,%r12d
  sub    $0x41,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
L112:
  mov    $0x1,%ebx
L81:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0x7e,%eax
  je     L89
  lea    -0x41(%rdi),%eax
  cmp    $0x39,%eax
  jbe    L79
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  ja     L91
  add    $0x1,%r13d
  jmp    L112
L91:
  cmp    $0x20,%edi
  sete   %al
  xor    $0x1,%ebx
  or     %bl,%al
  jne    L115
  sub    $0x9,%edi
  cmp    $0x1,%edi
  ja     L112
L115:
  add    $0x1,%ebp
  jmp    L112
L89:
  mov    %ebp,%esi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  lea    0x78(%rsp),%rbp
  xor    %ebx,%ebx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  nopl   0x0(%rax,%rax,1)
L96:
  mov    (%rax),%edx
  cmp    %edx,%ebx
  cmovl  %edx,%ebx
  add    $0x4,%rax
  cmp    %rax,%rbp
  jne    L96
  lea    D20(%rip),%r15
  lea    D60(%rip),%r13
  lea    D15(%rip),%r12
  nopl   (%rax)
L101:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r14
  jmp    L155
  nopl   0x0(%rax,%rax,1)
L104:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %rbp,%r14
  je     L1
L155:
  cmp    %ebx,(%r14)
  jge    L104
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %rbp,%r14
  jne    L155
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  sub    $0x1,%ebx
  jae    L101
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  mov    $0x41,%ebx
  call   <printf@plt>
  lea    D33(%rip),%rbp
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x5b,%ebx
  jne    L0
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L136
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L136:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D46
datatype: string
name: parse_data
arguments: data_label: D20
datatype: string
name: parse_data
arguments: data_label: D60
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D51
datatype: string
name: parse_data
arguments: data_label: D52
datatype: string
name: parse_data
arguments: data_label: D33
datatype: string

tool: D46: So you had %d words with %d letters and %d numbers




tool: D20: Times x %d|

tool: D60:    

tool: D15:  * 

tool: D51: ----------------------------------------------------------------------------------------

tool: D52:   Letter |

tool: D33:  %c 

assistant: ```c
void count_4(void) {
  int x, c, nr_maxim, state, lit, nre, words;
  nr_maxim = lit = nre = words = 0;
  int litere[27] = {0};
  state = 0;
  while ((c = getchar()) != '~') {
    if (c >= 'A' && c <= 'z') {
      c = toupper(c);
      litere[c - 'A']++;
      lit++;
      state = 1;
    } else if (c >= '0' && c <= '9') {
      nre++;
      state = 1;
    } else if (c == ' ' || c == '\t' || c == '\n')
      state = 0;
    if (state == 0) {
      words++;
      state = 1;
    }
  }
  printf("So you had %d words with %d letters and %d numbers\n\n\n", words, lit, nre);
  for (x = 0; x < 26; x++) {
    if (nr_maxim < litere[x]) {
      nr_maxim = litere[x];
    }
  }
  for (x = nr_maxim; x >= 0; x--) {
    while (x <= nr_maxim) {
      printf("Times x %d|", x);
      break;
    }
    for (c = 0; c < 26; c++) {
      if (litere[c] >= x)
        printf(" * ");
      else
        printf("   ");
    }
    putchar('\n');
    puts("----------------------------------------------------------------------------------------");
  }
  printf("  Letter |");
  for (x = 65; x < 91; x++)
    printf(" %c ", x);
}
```