ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x80(%rbp)
  movl   $0x2,-0x7c(%rbp)
  movl   $0x4,-0x78(%rbp)
  movl   $0x5,-0x74(%rbp)
  movl   $0x8,-0x70(%rbp)
  movl   $0xa,-0x6c(%rbp)
  movl   $0x10,-0x68(%rbp)
  movl   $0x14,-0x64(%rbp)
  movl   $0x19,-0x60(%rbp)
  movl   $0x20,-0x5c(%rbp)
  movl   $0x28,-0x58(%rbp)
  movl   $0x32,-0x54(%rbp)
  movl   $0x40,-0x50(%rbp)
  movl   $0x50,-0x4c(%rbp)
  movl   $0x64,-0x48(%rbp)
  movl   $0x7d,-0x44(%rbp)
  movl   $0xa0,-0x40(%rbp)
  movl   $0xc8,-0x3c(%rbp)
  movl   $0xfa,-0x38(%rbp)
  movl   $0x140,-0x34(%rbp)
  movl   $0x190,-0x30(%rbp)
  movl   $0x1f4,-0x2c(%rbp)
  movl   $0x320,-0x28(%rbp)
  movl   $0x3e8,-0x24(%rbp)
  movl   $0x640,-0x20(%rbp)
  movl   $0x7d0,-0x1c(%rbp)
  movl   $0xfa0,-0x18(%rbp)
  movl   $0x1f40,-0x14(%rbp)
  cmpl   $0x3,-0xa4(%rbp)
  je     L57
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
L57:
  mov    -0xb0(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x88(%rbp)
  mov    -0xb0(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x84(%rbp)
  movl   $0x0,-0x94(%rbp)
  jmp    L71
L37:
  movl   $0x0,-0x90(%rbp)
  jmp    L52
L21:
  mov    $0xff,%edi
  call   <putchar@plt>
  addl   $0x1,-0x90(%rbp)
L52:
  mov    -0x90(%rbp),%eax
  cmp    -0x88(%rbp),%eax
  jb     L21
  movl   $0x0,-0x8c(%rbp)
  jmp    L60
L8:
  mov    $0x0,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8c(%rbp)
L60:
  mov    -0x8c(%rbp),%eax
  cmp    -0x88(%rbp),%eax
  jb     L8
  addl   $0x1,-0x94(%rbp)
L71:
  mov    -0x94(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jb     L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  uint64_t divs[] = {1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, 64, 80, 100, 125, 160, 200, 250, 320, 400, 500, 800, 1000, 1600, 2000, 4000, 8000};
  if (argc != 3)
    exit(EXIT_FAILURE);
  unsigned halfwidth = strtol(argv[1], NULL, 10);
  unsigned cycles = strtol(argv[2], NULL, 10);
  for (unsigned cycle = 0; cycle < cycles; cycle++) {
    for (unsigned i = 0; i < halfwidth; i++)
      putchar(255);
    for (unsigned i = 0; i < halfwidth; i++)
      putchar(0);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  jne    L78
L16:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%r12d
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%r14d
  mov    $0x0,%r13d
  test   %eax,%eax
  jne    L9
L38:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L78:
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L16
L1:
  mov    $0xff,%edi
  call   <putchar@plt>
  mov    %ebx,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L1
  mov    $0x0,%ebx
L67:
  mov    $0x0,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L67
L71:
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  je     L38
L9:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jne    L1
  jmp    L71
```

assistant: ```c
int main(int argc, char **argv) {
  uint64_t divs[] = {1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, 64, 80, 100, 125, 160, 200, 250, 320, 400, 500, 800, 1000, 1600, 2000, 4000, 8000};
  if (argc != 3)
    exit(EXIT_FAILURE);
  unsigned halfwidth = strtol(argv[1], NULL, 10);
  unsigned cycles = strtol(argv[2], NULL, 10);
  for (unsigned cycle = 0; cycle < cycles; cycle++) {
    for (unsigned i = 0; i < halfwidth; i++)
      putchar(255);
    for (unsigned i = 0; i < halfwidth; i++)
      putchar(0);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  je     L28
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
L28:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  xor    %r13d,%r13d
  call   <strtol@plt>
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %eax,%r12d
  call   <strtol@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L15
  nop
L44:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  je     L20
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0xff,%edi
  mov    %ebx,%ebp
  lea    0x1(%rbx),%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L11
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L37:
  xor    %edi,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L37
L20:
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  jne    L44
L15:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  uint64_t divs[] = {1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, 64, 80, 100, 125, 160, 200, 250, 320, 400, 500, 800, 1000, 1600, 2000, 4000, 8000};
  if (argc != 3)
    exit(EXIT_FAILURE);
  unsigned halfwidth = strtol(argv[1], NULL, 10);
  unsigned cycles = strtol(argv[2], NULL, 10);
  for (unsigned cycle = 0; cycle < cycles; cycle++) {
    for (unsigned i = 0; i < halfwidth; i++)
      putchar(255);
    for (unsigned i = 0; i < halfwidth; i++)
      putchar(0);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  je     L15
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
L15:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  xor    %r13d,%r13d
  call   <strtol@plt>
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %eax,%r12d
  call   <strtol@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L36
  nop
L28:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  je     L18
  nopw   0x0(%rax,%rax,1)
L31:
  mov    $0xff,%edi
  mov    %ebx,%ebp
  lea    0x1(%rbx),%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L31
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L47:
  xor    %edi,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L47
L18:
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  jne    L28
L36:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  uint64_t divs[] = {1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, 64, 80, 100, 125, 160, 200, 250, 320, 400, 500, 800, 1000, 1600, 2000, 4000, 8000};
  if (argc != 3)
    exit(EXIT_FAILURE);
  unsigned halfwidth = strtol(argv[1], NULL, 10);
  unsigned cycles = strtol(argv[2], NULL, 10);
  for (unsigned cycle = 0; cycle < cycles; cycle++) {
    for (unsigned i = 0; i < halfwidth; i++)
      putchar(255);
    for (unsigned i = 0; i < halfwidth; i++)
      putchar(0);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x8,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L29
L18:
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L29:
  cmpl   $0x2,-0x3c(%rbp)
  jle    L18
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x24,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x9,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
datatype: string
name: extract_symbolic_data
arguments: label: D17
datatype: string
name: extract_symbolic_data
arguments: label: D24
datatype: string
name: extract_symbolic_data
arguments: label: D37
datatype: string

tool: D19: %d	

tool: D17: %d


tool: D24: sizeof() %d


tool: D37: length %d


assistant: ```c
int main() {
  int m[][3] = {1, 4, 7, 2, 5, 8, 3, 6, 9};
  int arr[][3] = {};
  int i, j, k = 2;
  for (i = 0; i < 3; i++) {
    printf("%d\t", m[k]);
  }
  printf("%d\n");
  printf("sizeof() %d\n", sizeof(m));
  printf("length %d\n", sizeof(m) / sizeof(m[0][0]));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x7,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x8,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  lea    0x18(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D34(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x24,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x9,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D34
type: string
name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D2
type: string

tool: D34: %d	

tool: D11: %d


tool: D28: sizeof() %d


tool: D2: length %d


assistant: ```c
int main() {
  int m[][3] = {1, 4, 7, 2, 5, 8, 3, 6, 9};
  int arr[][3] = {};
  int i, j, k = 2;
  for (i = 0; i < 3; i++) {
    printf("%d\t", m[k]);
  }
  printf("%d\n");
  printf("sizeof() %d\n", sizeof(m));
  printf("length %d\n", sizeof(m) / sizeof(m[0][0]));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D30(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x400000001,%rax
  lea    0x18(%rsp),%r12
  movl   $0x9,0x20(%rsp)
  mov    %r12,%rsi
  mov    %rax,(%rsp)
  movabs $0x200000007,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x800000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x24,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x9,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D30
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D9
data_type: string
name: disassemble_data
arguments: tag: D5
data_type: string

tool: D30: %d	

tool: D18: %d


tool: D9: sizeof() %d


tool: D5: length %d


assistant: ```c
int main() {
  int m[][3] = {1, 4, 7, 2, 5, 8, 3, 6, 9};
  int arr[][3] = {};
  int i, j, k = 2;
  for (i = 0; i < 3; i++) {
    printf("%d\t", m[k]);
  }
  printf("%d\n");
  printf("sizeof() %d\n", sizeof(m));
  printf("length %d\n", sizeof(m) / sizeof(m[0][0]));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  movdqa D35(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%r12
  movl   $0x9,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D40(%rip),%xmm0
  mov    %r12,%rsi
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x24,%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x9,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type: string
name: retrieve_data
arguments: label: D35
type: byte[16]
name: retrieve_data
arguments: label: D40
type: byte[16]
name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D31
type: string
name: retrieve_data
arguments: label: D29
type: string

tool: D10: %d	

tool: {"D35": [0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D40": [0x05,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D1: %d


tool: D31: sizeof() %d


tool: D29: length %d


assistant: ```c
int main() {
  int m[][3] = {1, 4, 7, 2, 5, 8, 3, 6, 9};
  int arr[][3] = {};
  int i, j, k = 2;
  for (i = 0; i < 3; i++) {
    printf("%d\t", m[k]);
  }
  printf("%d\n");
  printf("sizeof() %d\n", sizeof(m));
  printf("length %d\n", sizeof(m) / sizeof(m[0][0]));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<XConvertUcsToUtf8>:
  endbr64
  mov    %edi,%eax
  cmp    $0x7f,%edi
  jbe    L33
  cmp    $0x7ff,%edi
  jbe    L38
  cmp    $0xffff,%edi
  jbe    L39
  cmp    $0x1fffff,%edi
  jbe    L17
  cmp    $0xffffff,%edi
  ja     L31
  movb   $0xf8,(%rsi)
  mov    %edi,%edx
  shr    $0x12,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  mov    %edi,%edx
  shr    $0xc,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x3(%rsi)
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x4(%rsi)
  mov    $0x5,%eax
  ret
L33:
  mov    %dil,(%rsi)
  mov    $0x1,%eax
  ret
L38:
  mov    %edi,%edx
  shr    $0x6,%edx
  or     $0xffffffc0,%edx
  mov    %dl,(%rsi)
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x1(%rsi)
  mov    $0x2,%eax
  ret
L39:
  mov    %edi,%edx
  shr    $0xc,%edx
  or     $0xffffffe0,%edx
  mov    %dl,(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x2(%rsi)
  mov    $0x3,%eax
  ret
L17:
  mov    %edi,%edx
  shr    $0x12,%edx
  or     $0xfffffff0,%edx
  mov    %dl,(%rsi)
  mov    %edi,%edx
  shr    $0xc,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x3(%rsi)
  mov    $0x4,%eax
  ret
L31:
  movb   $0x3f,(%rsi)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int XConvertUcsToUtf8(unsigned int ucs, char *buf) {
  if (ucs < 0x000080) {
    buf[0] = ucs;
    return 1;
  } else if (ucs < 0x000800) {
    buf[0] = 0xC0 | (ucs >> 6);
    buf[1] = 0x80 | (ucs & 0x3F);
    return 2;
  } else if (ucs < 0x010000) {
    buf[0] = 0xE0 | (ucs >> 12);
    buf[1] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[2] = 0x80 | (ucs & 0x3F);
    return 3;
  } else if (ucs < 0x00200000) {
    buf[0] = 0xF0 | (ucs >> 18);
    buf[1] = 0x80 | ((ucs >> 12) & 0x3F);
    buf[2] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[3] = 0x80 | (ucs & 0x3F);
    return 4;
  } else if (ucs < 0x01000000) {
    buf[0] = 0xF8 | (ucs >> 24);
    buf[1] = 0x80 | ((ucs >> 18) & 0x3F);
    buf[2] = 0x80 | ((ucs >> 12) & 0x3F);
    buf[3] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[4] = 0x80 | (ucs & 0x3F);
    return 5;
  }
  buf[0] = '?';
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<XConvertUcsToUtf8>:
  endbr64
  mov    %edi,%eax
  cmp    $0x7f,%edi
  jbe    L41
  cmp    $0x7ff,%edi
  jbe    L15
  cmp    $0xffff,%edi
  jbe    L44
  cmp    $0x1fffff,%edi
  jbe    L19
  cmp    $0xffffff,%edi
  ja     L31
  mov    %edi,%edx
  and    $0x3f,%eax
  movb   $0xf8,(%rsi)
  shr    $0x12,%edx
  or     $0xffffff80,%eax
  or     $0xffffff80,%edx
  mov    %al,0x4(%rsi)
  mov    $0x5,%eax
  mov    %dl,0x1(%rsi)
  mov    %edi,%edx
  shr    $0xc,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x3(%rsi)
  ret
L41:
  mov    %dil,(%rsi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L44:
  mov    %edi,%edx
  and    $0x3f,%eax
  shr    $0xc,%edx
  or     $0xffffff80,%eax
  or     $0xffffffe0,%edx
  mov    %al,0x2(%rsi)
  mov    $0x3,%eax
  mov    %dl,(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %edi,%edx
  and    $0x3f,%eax
  shr    $0x6,%edx
  or     $0xffffff80,%eax
  or     $0xffffffc0,%edx
  mov    %al,0x1(%rsi)
  mov    $0x2,%eax
  mov    %dl,(%rsi)
  ret
  nopl   0x0(%rax)
L19:
  mov    %edi,%edx
  and    $0x3f,%eax
  shr    $0x12,%edx
  or     $0xffffff80,%eax
  or     $0xfffffff0,%edx
  mov    %al,0x3(%rsi)
  mov    $0x4,%eax
  mov    %dl,(%rsi)
  mov    %edi,%edx
  shr    $0xc,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  ret
  nopl   (%rax)
L31:
  movb   $0x3f,(%rsi)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int XConvertUcsToUtf8(unsigned int ucs, char *buf) {
  if (ucs < 0x000080) {
    buf[0] = ucs;
    return 1;
  } else if (ucs < 0x000800) {
    buf[0] = 0xC0 | (ucs >> 6);
    buf[1] = 0x80 | (ucs & 0x3F);
    return 2;
  } else if (ucs < 0x010000) {
    buf[0] = 0xE0 | (ucs >> 12);
    buf[1] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[2] = 0x80 | (ucs & 0x3F);
    return 3;
  } else if (ucs < 0x00200000) {
    buf[0] = 0xF0 | (ucs >> 18);
    buf[1] = 0x80 | ((ucs >> 12) & 0x3F);
    buf[2] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[3] = 0x80 | (ucs & 0x3F);
    return 4;
  } else if (ucs < 0x01000000) {
    buf[0] = 0xF8 | (ucs >> 24);
    buf[1] = 0x80 | ((ucs >> 18) & 0x3F);
    buf[2] = 0x80 | ((ucs >> 12) & 0x3F);
    buf[3] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[4] = 0x80 | (ucs & 0x3F);
    return 5;
  }
  buf[0] = '?';
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<XConvertUcsToUtf8>:
  endbr64
  mov    %edi,%eax
  cmp    $0x7f,%edi
  jbe    L39
  cmp    $0x7ff,%edi
  jbe    L24
  cmp    $0xffff,%edi
  jbe    L47
  cmp    $0x1fffff,%edi
  jbe    L19
  cmp    $0xffffff,%edi
  ja     L40
  mov    %edi,%edx
  and    $0x3f,%eax
  movb   $0xf8,(%rsi)
  shr    $0x12,%edx
  or     $0xffffff80,%eax
  or     $0xffffff80,%edx
  mov    %al,0x4(%rsi)
  mov    $0x5,%eax
  mov    %dl,0x1(%rsi)
  mov    %edi,%edx
  shr    $0xc,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x3(%rsi)
  ret
L39:
  mov    %dil,(%rsi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L47:
  mov    %edi,%edx
  and    $0x3f,%eax
  shr    $0xc,%edx
  or     $0xffffff80,%eax
  or     $0xffffffe0,%edx
  mov    %al,0x2(%rsi)
  mov    $0x3,%eax
  mov    %dl,(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %edi,%edx
  and    $0x3f,%eax
  shr    $0x6,%edx
  or     $0xffffff80,%eax
  or     $0xffffffc0,%edx
  mov    %al,0x1(%rsi)
  mov    $0x2,%eax
  mov    %dl,(%rsi)
  ret
  nopl   0x0(%rax)
L19:
  mov    %edi,%edx
  and    $0x3f,%eax
  shr    $0x12,%edx
  or     $0xffffff80,%eax
  or     $0xfffffff0,%edx
  mov    %al,0x3(%rsi)
  mov    $0x4,%eax
  mov    %dl,(%rsi)
  mov    %edi,%edx
  shr    $0xc,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rsi)
  mov    %edi,%edx
  shr    $0x6,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x2(%rsi)
  ret
  nopl   (%rax)
L40:
  movb   $0x3f,(%rsi)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int XConvertUcsToUtf8(unsigned int ucs, char *buf) {
  if (ucs < 0x000080) {
    buf[0] = ucs;
    return 1;
  } else if (ucs < 0x000800) {
    buf[0] = 0xC0 | (ucs >> 6);
    buf[1] = 0x80 | (ucs & 0x3F);
    return 2;
  } else if (ucs < 0x010000) {
    buf[0] = 0xE0 | (ucs >> 12);
    buf[1] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[2] = 0x80 | (ucs & 0x3F);
    return 3;
  } else if (ucs < 0x00200000) {
    buf[0] = 0xF0 | (ucs >> 18);
    buf[1] = 0x80 | ((ucs >> 12) & 0x3F);
    buf[2] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[3] = 0x80 | (ucs & 0x3F);
    return 4;
  } else if (ucs < 0x01000000) {
    buf[0] = 0xF8 | (ucs >> 24);
    buf[1] = 0x80 | ((ucs >> 18) & 0x3F);
    buf[2] = 0x80 | ((ucs >> 12) & 0x3F);
    buf[3] = 0x80 | ((ucs >> 6) & 0x3F);
    buf[4] = 0x80 | (ucs & 0x3F);
    return 5;
  }
  buf[0] = '?';
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<idiv_ceil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L0
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int idiv_ceil(int a, int b) {
  int d = a / b;
  if (d * b < a)
    d += 1;
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<idiv_ceil>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  imul   %eax,%esi
  cmp    %edi,%esi
  setl   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int idiv_ceil(int a, int b) {
  int d = a / b;
  if (d * b < a)
    d += 1;
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<idiv_ceil>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  xor    %edx,%edx
  imul   %eax,%esi
  cmp    %edi,%esi
  setl   %dl
  add    %edx,%eax
  ret
```

assistant: ```c
int idiv_ceil(int a, int b) {
  int d = a / b;
  if (d * b < a)
    d += 1;
  return d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<idiv_ceil>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  xor    %edx,%edx
  imul   %eax,%esi
  cmp    %edi,%esi
  setl   %dl
  add    %edx,%eax
  ret
```

assistant: ```c
int idiv_ceil(int a, int b) {
  int d = a / b;
  if (d * b < a)
    d += 1;
  return d;
}
```