ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<__mem_eq_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(%rsi),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L40
L7:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L7
L40:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L8
L4:
  xor    %esi,%esi
  mov    %r12,%rdx
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  lea    -0x10(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L4
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __mem_eq_0(const char *mem, size_t len) {
  char buffer[len];
  memset(buffer, 0, len);
  return memcmp(mem, buffer, len) == 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__mem_eq_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(%rsi),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L34
L11:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L11
L34:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L17
L45:
  xor    %esi,%esi
  mov    %r12,%rdx
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  lea    -0x10(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L17:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L45
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __mem_eq_0(const char *mem, size_t len) {
  char buffer[len];
  memset(buffer, 0, len);
  return memcmp(mem, buffer, len) == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<start_summer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    $0xb,%edi
  call   <echo_to_all@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D9: The days grow longer and hotter as summer grips the world.


assistant: ```c
void start_summer(void) {
  echo_to_all(11, "The days grow longer and hotter as summer grips the world.\r\n", 0);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<start_summer>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  lea    D8(%rip),%rsi
  mov    $0xb,%edi
  call   <echo_to_all@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: The days grow longer and hotter as summer grips the world.


assistant: ```c
void start_summer(void) {
  echo_to_all(11, "The days grow longer and hotter as summer grips the world.\r\n", 0);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<start_summer>:
  endbr64
  xor    %edx,%edx
  lea    D5(%rip),%rsi
  mov    $0xb,%edi
  jmp    1050 <echo_to_all@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: The days grow longer and hotter as summer grips the world.


assistant: ```c
void start_summer(void) {
  echo_to_all(11, "The days grow longer and hotter as summer grips the world.\r\n", 0);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<start_summer>:
  endbr64
  xor    %edx,%edx
  lea    D7(%rip),%rsi
  mov    $0xb,%edi
  jmp    1050 <echo_to_all@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: The days grow longer and hotter as summer grips the world.


assistant: ```c
void start_summer(void) {
  echo_to_all(11, "The days grow longer and hotter as summer grips the world.\r\n", 0);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sleep_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L19
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
  mov    %eax,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void sleep_s(unsigned int seconds) {
  for (; seconds; seconds = sleep(seconds))
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sleep_s>:
  endbr64
  test   %edi,%edi
  je     L16
  sub    $0x8,%rsp
L2:
  call   <sleep@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L2
  add    $0x8,%rsp
  ret
L16:
  ret
```

assistant: ```c
void sleep_s(unsigned int seconds) {
  for (; seconds; seconds = sleep(seconds))
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sleep_s>:
  endbr64
  test   %edi,%edi
  je     L10
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L19:
  call   <sleep@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L19
  add    $0x8,%rsp
  ret
L10:
  ret
```

assistant: ```c
void sleep_s(unsigned int seconds) {
  for (; seconds; seconds = sleep(seconds))
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<sleep_s>:
  endbr64
  test   %edi,%edi
  je     L13
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L15:
  call   <sleep@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L15
  add    $0x8,%rsp
  ret
L13:
  ret
```

assistant: ```c
void sleep_s(unsigned int seconds) {
  for (; seconds; seconds = sleep(seconds))
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<free_submatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_submatrix(b, nrl, nrh, ncl, nch) float **b;
int nrl, nrh, ncl, nch;
{
  if (nrh + ncl + nch)
    nch = nch;
  free((char *)(b + nrl));
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_submatrix>:
  endbr64
  sub    $0x8,%rsp
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void free_submatrix(b, nrl, nrh, ncl, nch) float **b;
int nrl, nrh, ncl, nch;
{
  if (nrh + ncl + nch)
    nch = nch;
  free((char *)(b + nrl));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<free_submatrix>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rdi
  jmp    1050 <free@plt>
```

assistant: ```c
void free_submatrix(b, nrl, nrh, ncl, nch) float **b;
int nrl, nrh, ncl, nch;
{
  if (nrh + ncl + nch)
    nch = nch;
  free((char *)(b + nrl));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<accept_posfin_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L34
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <isfinite@plt>
  test   %rax,%rax
  je     L34
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L34
  mov    $0x1,%eax
  jmp    L21
L34:
  mov    $0x0,%eax
L21:
  leave
  ret
```

assistant: ```c
bool accept_posfin_double(void *val) {
  const double *dval = (const double *)val;
  return (val && isfinite(*dval) && *dval > 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DVIVisortDown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L49
L21:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L7
L48:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x10(%rbp)
L7:
  cmpl   $0x0,-0x10(%rbp)
  jle    L12
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  ja     L48
L12:
  addl   $0x1,-0x14(%rbp)
L49:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DVIVisortDown(int n, double dvec[], int ivec[]) {
  double dtemp;
  int i, itemp, j;
  for (i = 1; i < n; i++) {
    for (j = i; j > 0 && dvec[j - 1] < dvec[j]; j--) {
      {
        itemp = ivec[(j - 1)];
        ivec[(j - 1)] = ivec[(j)];
        ivec[(j)] = itemp;
        dtemp = dvec[(j - 1)];
        dvec[(j - 1)] = dvec[(j)];
        dvec[(j)] = dtemp;
      }
    }
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DVIVisortDown>:
  endbr64
  cmp    $0x1,%edi
  jle    L65
  lea    0x8(%rsi),%r11
  lea    0x4(%rdx),%r10
  mov    $0x1,%r9d
  jmp    L45
L61:
  add    $0x1,%r9d
  add    $0x8,%r11
  add    $0x4,%r10
  cmp    %r9d,%edi
  je     L65
L45:
  test   %r9d,%r9d
  jle    L61
  mov    %r10,%rdx
  mov    %r11,%rax
L29:
  movsd  (%rax),%xmm0
  comisd -0x8(%rax),%xmm0
  jbe    L61
  mov    -0x4(%rdx),%ecx
  mov    (%rdx),%r8d
  mov    %r8d,-0x4(%rdx)
  mov    %ecx,(%rdx)
  movsd  -0x8(%rax),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,-0x8(%rax)
  movsd  %xmm0,(%rax)
  sub    $0x8,%rax
  sub    $0x4,%rdx
  cmp    %rsi,%rax
  jne    L29
  jmp    L61
L65:
  ret
```

assistant: ```c
void DVIVisortDown(int n, double dvec[], int ivec[]) {
  double dtemp;
  int i, itemp, j;
  for (i = 1; i < n; i++) {
    for (j = i; j > 0 && dvec[j - 1] < dvec[j]; j--) {
      {
        itemp = ivec[(j - 1)];
        ivec[(j - 1)] = ivec[(j)];
        ivec[(j)] = itemp;
        dtemp = dvec[(j - 1)];
        dvec[(j - 1)] = dvec[(j)];
        dvec[(j)] = dtemp;
      }
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<DVIVisortDown>:
  endbr64
  lea    0x8(%rsi),%r11
  lea    0x4(%rdx),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%edi
  jle    L39
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r9,%rdx
  mov    %r11,%rax
  cs nopw 0x0(%rax,%rax,1)
L33:
  movsd  -0x8(%rax),%xmm0
  movsd  (%rax),%xmm1
  comisd %xmm0,%xmm1
  jbe    L30
  mov    -0x4(%rdx),%ecx
  mov    (%rdx),%r8d
  sub    $0x8,%rax
  sub    $0x4,%rdx
  mov    %r8d,(%rdx)
  mov    %ecx,0x4(%rdx)
  movsd  %xmm1,(%rax)
  movsd  %xmm0,0x8(%rax)
  cmp    %rsi,%rax
  jne    L33
L30:
  add    $0x1,%r10d
  add    $0x8,%r11
  add    $0x4,%r9
  cmp    %r10d,%edi
  jne    L8
  ret
L39:
  ret
```

assistant: ```c
void DVIVisortDown(int n, double dvec[], int ivec[]) {
  double dtemp;
  int i, itemp, j;
  for (i = 1; i < n; i++) {
    for (j = i; j > 0 && dvec[j - 1] < dvec[j]; j--) {
      {
        itemp = ivec[(j - 1)];
        ivec[(j - 1)] = ivec[(j)];
        ivec[(j)] = itemp;
        dtemp = dvec[(j - 1)];
        dvec[(j - 1)] = dvec[(j)];
        dvec[(j)] = dtemp;
      }
    }
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DVIVisortDown>:
  endbr64
  lea    0x8(%rsi),%r9
  lea    0x4(%rdx),%rcx
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jle    L1
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %rcx,%rdx
  mov    %r9,%rax
  cs nopw 0x0(%rax,%rax,1)
L39:
  movupd -0x8(%rax),%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  shufpd $0x1,%xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L18
  rolq   $0x20,-0x4(%rdx)
  sub    $0x8,%rax
  sub    $0x4,%rdx
  movups %xmm2,(%rax)
  cmp    %rsi,%rax
  jne    L39
L18:
  add    $0x1,%r8d
  add    $0x8,%r9
  add    $0x4,%rcx
  cmp    %r8d,%edi
  jne    L24
  ret
L1:
  ret
```

assistant: ```c
void DVIVisortDown(int n, double dvec[], int ivec[]) {
  double dtemp;
  int i, itemp, j;
  for (i = 1; i < n; i++) {
    for (j = i; j > 0 && dvec[j - 1] < dvec[j]; j--) {
      {
        itemp = ivec[(j - 1)];
        ivec[(j - 1)] = ivec[(j)];
        ivec[(j)] = itemp;
        dtemp = dvec[(j - 1)];
        dvec[(j - 1)] = dvec[(j)];
        dvec[(j)] = dtemp;
      }
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__ghdl_snprintf_g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D1(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: %g

assistant: ```c
int __ghdl_snprintf_g(char *buf, unsigned int len, double val) {
  snprintf(buf, len, "%g", val);
  return strlen(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<__ghdl_snprintf_g>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D8(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: %g

assistant: ```c
int __ghdl_snprintf_g(char *buf, unsigned int len, double val) {
  snprintf(buf, len, "%g", val);
  return strlen(buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__ghdl_snprintf_g>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdx
  mov    %rdi,%rbp
  call   <snprintf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type: string

tool: D2: %g

assistant: ```c
int __ghdl_snprintf_g(char *buf, unsigned int len, double val) {
  snprintf(buf, len, "%g", val);
  return strlen(buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<__ghdl_snprintf_g>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdx
  mov    %rdi,%rbp
  call   <snprintf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %g

assistant: ```c
int __ghdl_snprintf_g(char *buf, unsigned int len, double val) {
  snprintf(buf, len, "%g", val);
  return strlen(buf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x18(%rbp),%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x14(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm3,%xmm3
  cvtss2sd -0x10(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm4,%xmm4
  cvtss2sd -0xc(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D39
type_guessed: string
name: unpack_data
arguments: label: D30
type_guessed: string
name: unpack_data
arguments: label: D10
type_guessed: string

tool: D11: Ingrese el primer numero (a): 

tool: D2: %f

tool: D39: Ingrese el segundo numero (b): 

tool: D30: 
(a + b) * (a - b): %.2f


tool: D10: a^2 - b^2: %.2f


assistant: ```c
int main() {
  float a, b, f, s;
  printf("Ingrese el primer numero (a): ");
  scanf("%f", &a);
  printf("Ingrese el segundo numero (b): ");
  scanf("%f", &b);
  f = (a + b) * (a - b);
  s = a * a - b * b;
  printf("\n(a + b) * (a - b): %.2f\n", f);
  printf("a^2 - b^2: %.2f\n", s);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  movss  0x14(%rsp),%xmm2
  movd   %ebx,%xmm0
  addss  %xmm2,%xmm0
  movd   %ebx,%xmm3
  movss  %xmm2,0xc(%rsp)
  subss  %xmm2,%xmm3
  mulss  %xmm3,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movd   %ebx,%xmm0
  mulss  %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  mulss  %xmm1,%xmm1
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D23(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D26
data_type: string
name: parse_data
arguments: data_tag: D39
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string
name: parse_data
arguments: data_tag: D23
data_type: string

tool: D18: Ingrese el primer numero (a): 

tool: D26: %f

tool: D39: Ingrese el segundo numero (b): 

tool: D19: 
(a + b) * (a - b): %.2f


tool: D23: a^2 - b^2: %.2f


assistant: ```c
int main() {
  float a, b, f, s;
  printf("Ingrese el primer numero (a): ");
  scanf("%f", &a);
  printf("Ingrese el segundo numero (b): ");
  scanf("%f", &b);
  f = (a + b) * (a - b);
  s = a * a - b * b;
  printf("\n(a + b) * (a - b): %.2f\n", f);
  printf("a^2 - b^2: %.2f\n", s);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  lea    D39(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  movss  0x14(%rsp),%xmm2
  lea    D43(%rip),%rdi
  mov    $0x1,%eax
  movaps %xmm1,%xmm0
  movaps %xmm1,%xmm3
  movss  %xmm1,0xc(%rsp)
  addss  %xmm2,%xmm0
  subss  %xmm2,%xmm3
  movss  %xmm2,0x8(%rsp)
  mulss  %xmm3,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm1
  mulss  %xmm2,%xmm2
  subss  %xmm2,%xmm1
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D49
data_type: string
name: parse_data
arguments: data_label: D39
data_type: string
name: parse_data
arguments: data_label: D36
data_type: string
name: parse_data
arguments: data_label: D43
data_type: string
name: parse_data
arguments: data_label: D21
data_type: string

tool: D49: Ingrese el primer numero (a): 

tool: D39: %f

tool: D36: Ingrese el segundo numero (b): 

tool: D43: 
(a + b) * (a - b): %.2f


tool: D21: a^2 - b^2: %.2f


assistant: ```c
int main() {
  float a, b, f, s;
  printf("Ingrese el primer numero (a): ");
  scanf("%f", &a);
  printf("Ingrese el segundo numero (b): ");
  scanf("%f", &b);
  f = (a + b) * (a - b);
  s = a * a - b * b;
  printf("\n(a + b) * (a - b): %.2f\n", f);
  printf("a^2 - b^2: %.2f\n", s);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  lea    D41(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  movss  0x14(%rsp),%xmm2
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  movaps %xmm1,%xmm0
  movaps %xmm1,%xmm3
  movss  %xmm1,0xc(%rsp)
  addss  %xmm2,%xmm0
  subss  %xmm2,%xmm3
  movss  %xmm2,0x8(%rsp)
  mulss  %xmm3,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm1
  mulss  %xmm2,%xmm2
  subss  %xmm2,%xmm1
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D46
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D41
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D47
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D36
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D30
type_guessed: string

tool: D46: Ingrese el primer numero (a): 

tool: D41: %f

tool: D47: Ingrese el segundo numero (b): 

tool: D36: 
(a + b) * (a - b): %.2f


tool: D30: a^2 - b^2: %.2f


assistant: ```c
int main() {
  float a, b, f, s;
  printf("Ingrese el primer numero (a): ");
  scanf("%f", &a);
  printf("Ingrese el segundo numero (b): ");
  scanf("%f", &b);
  f = (a + b) * (a - b);
  s = a * a - b * b;
  printf("\n(a + b) * (a - b): %.2f\n", f);
  printf("a^2 - b^2: %.2f\n", s);
  return 0;
}
```