ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<plusOne>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L72
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L52
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,(%rsi)
  subl   $0x1,-0x8(%rbp)
L72:
  cmpl   $0x0,-0x8(%rbp)
  jns    L10
  jmp    L2
L52:
  nop
L2:
  mov    -0x28(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  cmpl   $0x0,-0xc(%rbp)
  jne    L55
  mov    -0x18(%rbp),%rax
  jmp    L78
L55:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L22:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x4(%rbp)
  jg     L22
  mov    -0x18(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
L78:
  pop    %rbp
  ret
```

assistant: ```c
int *plusOne(int *digits, int digitsSize, int *returnSize) {
  int r = 0;
  for (int i = digitsSize - 1; i >= 0; i--) {
    digits[i]++;
    r = digits[i] / 10;
    if (r == 0)
      break;
    digits[i] %= 10;
  }
  *returnSize = digitsSize;
  if (r == 0)
    return digits;
  for (int i = digitsSize; i > 0; i--)
    digits[i] = digits[i - 1];
  digits[0] = r;
  *returnSize = digitsSize + 1;
  return digits;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<plusOne>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  mov    %rdx,%r9
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L6
  push   %r12
  push   %rbp
  push   %rbx
  cltq
  shl    $0x2,%rax
  lea    (%r8,%rax,1),%rcx
  lea    0x4(%rax),%r11
  lea    -0x1(%rsi),%r10d
  shl    $0x2,%r10
  lea    -0x4(%r8,%rax,1),%rsi
  sub    %r10,%rsi
L39:
  mov    (%rcx),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ebp
  sar    $0x1f,%ebp
  mov    %edx,%ebx
  sub    %ebp,%ebx
  je     L0
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ebp
  sar    $0x1f,%ebp
  sub    %ebp,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rcx)
  sub    $0x4,%rcx
  cmp    %rsi,%rcx
  jne    L39
  mov    %edi,(%r9)
  test   %edi,%edi
  jle    L2
  lea    (%r8,%r11,1),%rax
  lea    -0x4(%r8,%r11,1),%rcx
  sub    %r10,%rcx
L23:
  mov    -0x4(%rax),%edx
  mov    %edx,(%rax)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L23
L2:
  mov    %ebx,(%r8)
  add    $0x1,%edi
L30:
  mov    %edi,(%r9)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    %eax,(%rcx)
  jmp    L30
L6:
  mov    %esi,(%r9)
  mov    %r8,%rax
  ret
```

assistant: ```c
int *plusOne(int *digits, int digitsSize, int *returnSize) {
  int r = 0;
  for (int i = digitsSize - 1; i >= 0; i--) {
    digits[i]++;
    r = digits[i] / 10;
    if (r == 0)
      break;
    digits[i] %= 10;
  }
  *returnSize = digitsSize;
  if (r == 0)
    return digits;
  for (int i = digitsSize; i > 0; i--)
    digits[i] = digits[i - 1];
  digits[0] = r;
  *returnSize = digitsSize + 1;
  return digits;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<plusOne>:
  endbr64
  push   %r13
  mov    %esi,%r9d
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  sub    $0x1,%r9d
  js     L29
  movslq %r9d,%rsi
  mov    %r9d,%r9d
  shl    $0x2,%rsi
  lea    0x0(,%r9,4),%r10
  lea    -0x4(%r12,%rsi,1),%r8
  lea    (%rdi,%rsi,1),%rcx
  sub    %r10,%r8
  lea    0x4(%rsi),%rdi
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L55:
  lea    (%rbx,%rbx,4),%edx
  sub    $0x4,%rcx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rcx)
  cmp    %r8,%rcx
  je     L34
L20:
  mov    (%rcx),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  mov    %eax,%r11d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r11d
  sar    $0x22,%rdx
  mov    %edx,%ebx
  sub    %r11d,%ebx
  jne    L55
  mov    %eax,(%rcx)
L29:
  mov    %ebp,0x0(%r13)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    %ebp,0x0(%r13)
  test   %ebp,%ebp
  jle    L14
  sub    %r10,%rsi
  sub    %r10,%rdi
  lea    0x4(,%r9,4),%rdx
  add    %r12,%rsi
  add    %r12,%rdi
  call   <memmove@plt>
L14:
  mov    %ebx,(%r12)
  add    $0x1,%ebp
  jmp    L29
```

assistant: ```c
int *plusOne(int *digits, int digitsSize, int *returnSize) {
  int r = 0;
  for (int i = digitsSize - 1; i >= 0; i--) {
    digits[i]++;
    r = digits[i] / 10;
    if (r == 0)
      break;
    digits[i] %= 10;
  }
  *returnSize = digitsSize;
  if (r == 0)
    return digits;
  for (int i = digitsSize; i > 0; i--)
    digits[i] = digits[i - 1];
  digits[0] = r;
  *returnSize = digitsSize + 1;
  return digits;
}
```
user: Translate the below assembly code into C programming language:

```asm
<plusOne>:
  endbr64
  push   %r13
  mov    %esi,%r9d
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  sub    $0x1,%r9d
  js     L57
  movslq %r9d,%rsi
  mov    %r9d,%r9d
  shl    $0x2,%rsi
  lea    0x0(,%r9,4),%r10
  lea    -0x4(%r12,%rsi,1),%r8
  lea    (%rdi,%rsi,1),%rcx
  sub    %r10,%r8
  lea    0x4(%rsi),%rdi
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L51:
  lea    (%rbx,%rbx,4),%edx
  sub    $0x4,%rcx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rcx)
  cmp    %r8,%rcx
  je     L52
L24:
  mov    (%rcx),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  mov    %eax,%r11d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r11d
  sar    $0x22,%rdx
  mov    %edx,%ebx
  sub    %r11d,%ebx
  jne    L51
  mov    %eax,(%rcx)
L57:
  mov    %ebp,0x0(%r13)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  mov    %ebp,0x0(%r13)
  test   %ebp,%ebp
  jle    L46
  sub    %r10,%rsi
  sub    %r10,%rdi
  lea    0x4(,%r9,4),%rdx
  add    %r12,%rsi
  add    %r12,%rdi
  call   <memmove@plt>
L46:
  mov    %ebx,(%r12)
  add    $0x1,%ebp
  jmp    L57
```

assistant: ```c
int *plusOne(int *digits, int digitsSize, int *returnSize) {
  int r = 0;
  for (int i = digitsSize - 1; i >= 0; i--) {
    digits[i]++;
    r = digits[i] / 10;
    if (r == 0)
      break;
    digits[i] %= 10;
  }
  *returnSize = digitsSize;
  if (r == 0)
    return digits;
  for (int i = digitsSize; i > 0; i--)
    digits[i] = digits[i - 1];
  digits[0] = r;
  *returnSize = digitsSize + 1;
  return digits;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  je     L15
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L50
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L52
L50:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L57
  movl   $0x1,-0x8(%rbp)
  jmp    L52
L57:
  addl   $0x1,-0x4(%rbp)
  jmp    L11
L15:
  nop
L52:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(char *p1, char *p2, int count) {
  int result = 0;
  for (int i = 0;; i++) {
    if (i == count) {
      break;
    }
    if (p1[i] < p2[i]) {
      result = -1;
      break;
    }
    if (p1[i] > p2[i]) {
      result = 1;
      break;
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memcmp>:
  endbr64
  test   %edx,%edx
  je     L11
  mov    %edx,%eax
  mov    $0x0,%ecx
L6:
  movzbl (%rdi,%rcx,1),%r9d
  movzbl (%rsi,%rcx,1),%r8d
  cmp    %r8b,%r9b
  jl     L19
  jg     L16
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jne    L6
  mov    $0x0,%eax
  ret
L11:
  mov    %edx,%eax
  ret
L19:
  mov    $0xffffffff,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(char *p1, char *p2, int count) {
  int result = 0;
  for (int i = 0;; i++) {
    if (i == count) {
      break;
    }
    if (p1[i] < p2[i]) {
      result = -1;
      break;
    }
    if (p1[i] > p2[i]) {
      result = 1;
      break;
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memcmp>:
  endbr64
  test   %edx,%edx
  je     L13
  mov    %edx,%edx
  xor    %eax,%eax
  jmp    L33
  xchg   %ax,%ax
L35:
  jg     L49
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L13
L33:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jge    L35
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(char *p1, char *p2, int count) {
  int result = 0;
  for (int i = 0;; i++) {
    if (i == count) {
      break;
    }
    if (p1[i] < p2[i]) {
      result = -1;
      break;
    }
    if (p1[i] > p2[i]) {
      result = 1;
      break;
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memcmp>:
  endbr64
  test   %edx,%edx
  je     L44
  mov    %edx,%edx
  xor    %eax,%eax
  jmp    L23
  xchg   %ax,%ax
L15:
  jg     L47
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L44
L23:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jge    L15
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(char *p1, char *p2, int count) {
  int result = 0;
  for (int i = 0;; i++) {
    if (i == count) {
      break;
    }
    if (p1[i] < p2[i]) {
      result = -1;
      break;
    }
    if (p1[i] > p2[i]) {
      result = 1;
      break;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: May 29, 2013 Wednesday


assistant: ```c
int main() {
  printf("May 29, 2013 Wednesday\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: May 29, 2013 Wednesday


assistant: ```c
int main() {
  printf("May 29, 2013 Wednesday\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: May 29, 2013 Wednesday


assistant: ```c
int main() {
  printf("May 29, 2013 Wednesday\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: May 29, 2013 Wednesday


assistant: ```c
int main() {
  printf("May 29, 2013 Wednesday\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x418(%rbp)
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: %A

assistant: ```c
int main() {
  double y = 0.0;
  char abuf[1024];
  sprintf(abuf, "%A", y);
  exit(strchr(abuf, 'P') == (char *)0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  pxor   %xmm0,%xmm0
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    $0x50,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <exit@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: %A

assistant: ```c
int main() {
  double y = 0.0;
  char abuf[1024];
  sprintf(abuf, "%A", y);
  exit(strchr(abuf, 'P') == (char *)0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  lea    D8(%rip),%rsi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    $0x50,%esi
  call   <strchr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <exit@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string

tool: D8: %A

assistant: ```c
int main() {
  double y = 0.0;
  char abuf[1024];
  sprintf(abuf, "%A", y);
  exit(strchr(abuf, 'P') == (char *)0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  lea    D3(%rip),%rsi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    $0x50,%esi
  call   <strchr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <exit@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: %A

assistant: ```c
int main() {
  double y = 0.0;
  char abuf[1024];
  sprintf(abuf, "%A", y);
  exit(strchr(abuf, 'P') == (char *)0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xa,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D5
type_infered: string

tool: D6: Doing it right:

tool: D10: %d minus %d is %d


tool: D5: Doing it wrong:

assistant: ```c
int main(int argc, char const *argv[]) {
  int ten = 10;
  int two = 2;
  printf("Doing it right:\n");
  printf("%d minus %d is %d\n", ten, 2, ten - two);
  printf("Doing it wrong:\n");
  printf("%d minus %d is %d\n", ten);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0x8,%ecx
  mov    $0x2,%edx
  mov    $0xa,%esi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type: string
name: disassemble_data
arguments: data_tag: D19
type: string
name: disassemble_data
arguments: data_tag: D27
type: string

tool: D15: Doing it right:

tool: D19: %d minus %d is %d


tool: D27: Doing it wrong:

assistant: ```c
int main(int argc, char const *argv[]) {
  int ten = 10;
  int two = 2;
  printf("Doing it right:\n");
  printf("%d minus %d is %d\n", ten, 2, ten - two);
  printf("Doing it wrong:\n");
  printf("%d minus %d is %d\n", ten);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  lea    D18(%rip),%rbp
  call   <puts@plt>
  mov    $0x8,%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    $0xa,%esi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D23
type: string
name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D6
type: string

tool: D23: Doing it right:

tool: D18: %d minus %d is %d


tool: D6: Doing it wrong:

assistant: ```c
int main(int argc, char const *argv[]) {
  int ten = 10;
  int two = 2;
  printf("Doing it right:\n");
  printf("%d minus %d is %d\n", ten, 2, ten - two);
  printf("Doing it wrong:\n");
  printf("%d minus %d is %d\n", ten);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rdi
  lea    D3(%rip),%rbp
  call   <puts@plt>
  mov    $0x8,%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    $0xa,%esi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string
name: parse_data
arguments: data_label: D25
type_infered: string

tool: D26: Doing it right:

tool: D3: %d minus %d is %d


tool: D25: Doing it wrong:

assistant: ```c
int main(int argc, char const *argv[]) {
  int ten = 10;
  int two = 2;
  printf("Doing it right:\n");
  printf("%d minus %d is %d\n", ten, 2, ten - two);
  printf("Doing it wrong:\n");
  printf("%d minus %d is %d\n", ten);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<LaneDetectorParser_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <LaneDetectorParser_internal@plt>
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L5
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <LaneDetectorParser_free@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int LaneDetectorParser_ext(int argc, char **argv, struct LaneDetectorParserInfo *args_info, struct LaneDetectorParser_params *params) {
  int result;
  result = LaneDetectorParser_internal(argc, argv, args_info, params, 0);
  if (result == EXIT_FAILURE) {
    LaneDetectorParser_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<LaneDetectorParser_ext>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  mov    $0x0,%r8d
  call   <LaneDetectorParser_internal@plt>
  mov    %eax,%ebx
  mov    D12(%rip),%rax
  cmp    %ebx,(%rax)
  je     L7
L18:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rbp,%rdi
  call   <LaneDetectorParser_free@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L18
```

assistant: ```c
int LaneDetectorParser_ext(int argc, char **argv, struct LaneDetectorParserInfo *args_info, struct LaneDetectorParser_params *params) {
  int result;
  result = LaneDetectorParser_internal(argc, argv, args_info, params, 0);
  if (result == EXIT_FAILURE) {
    LaneDetectorParser_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<LaneDetectorParser_ext>:
  endbr64
  push   %r12
  xor    %r8d,%r8d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  call   <LaneDetectorParser_internal@plt>
  mov    D7(%rip),%rbx
  mov    %eax,%r12d
  cmp    %eax,(%rbx)
  je     L7
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  mov    %rbp,%rdi
  call   <LaneDetectorParser_free@plt>
  mov    (%rbx),%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int LaneDetectorParser_ext(int argc, char **argv, struct LaneDetectorParserInfo *args_info, struct LaneDetectorParser_params *params) {
  int result;
  result = LaneDetectorParser_internal(argc, argv, args_info, params, 0);
  if (result == EXIT_FAILURE) {
    LaneDetectorParser_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LaneDetectorParser_ext>:
  endbr64
  push   %r12
  xor    %r8d,%r8d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  call   <LaneDetectorParser_internal@plt>
  mov    D9(%rip),%rbx
  mov    %eax,%r12d
  cmp    %eax,(%rbx)
  je     L6
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  mov    %rbp,%rdi
  call   <LaneDetectorParser_free@plt>
  mov    (%rbx),%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int LaneDetectorParser_ext(int argc, char **argv, struct LaneDetectorParserInfo *args_info, struct LaneDetectorParser_params *params) {
  int result;
  result = LaneDetectorParser_internal(argc, argv, args_info, params, 0);
  if (result == EXIT_FAILURE) {
    LaneDetectorParser_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```