ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<roll>:
  endbr64
  lea    -0x1(%rdi),%eax
  pxor   %xmm2,%xmm2
  push   %rbx
  mov    %edi,%ebx
  cvtsi2sd %eax,%xmm2
  sub    $0x10,%rsp
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cltd
  shr    $0x11,%edx
  add    %edx,%eax
  and    $0x7fff,%eax
  sub    %edx,%eax
  cvtsi2sd %eax,%xmm0
  divsd  D15(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  addsd  D11(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  cmp    %eax,%ebx
  jle    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_infered: f64
name: parse_data
arguments: data_tag: D11
type_infered: f64

tool: D15: 32767

tool: D11: 0.5

assistant: ```c
int roll(int n) {
  int r;
  do
    r = ((rand() % 32768) / 32767.0) * (n - 1) + 0.5;
  while (r >= n);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<roll>:
  endbr64
  lea    -0x1(%rdi),%eax
  pxor   %xmm2,%xmm2
  push   %rbx
  mov    %edi,%ebx
  cvtsi2sd %eax,%xmm2
  sub    $0x10,%rsp
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cltd
  shr    $0x11,%edx
  add    %edx,%eax
  and    $0x7fff,%eax
  sub    %edx,%eax
  cvtsi2sd %eax,%xmm0
  divsd  D18(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  addsd  D5(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  cmp    %eax,%ebx
  jle    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
datatype: f64
name: read_data
arguments: data_tag: D5
datatype: f64

tool: D18: 32767

tool: D5: 0.5

assistant: ```c
int roll(int n) {
  int r;
  do
    r = ((rand() % 32768) / 32767.0) * (n - 1) + 0.5;
  while (r >= n);
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_linux_prctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void show_linux_prctl(void) {
  int rc;
  int arg2;
  char name[17] = {0};
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<show_linux_prctl>:
  endbr64
  ret
```

assistant: ```c
void show_linux_prctl(void) {
  int rc;
  int arg2;
  char name[17] = {0};
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<show_linux_prctl>:
  endbr64
  ret
```

assistant: ```c
void show_linux_prctl(void) {
  int rc;
  int arg2;
  char name[17] = {0};
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_linux_prctl>:
  endbr64
  ret
```

assistant: ```c
void show_linux_prctl(void) {
  int rc;
  int arg2;
  char name[17] = {0};
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<binString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  jmp    L35
L8:
  mov    -0x34(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L41
  mov    $0x31,%edx
  jmp    L39
L41:
  mov    $0x30,%edx
L39:
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  shll   -0x34(%rbp)
  addl   $0x1,-0x24(%rbp)
L35:
  cmpl   $0xf,-0x24(%rbp)
  jle    L8
  movb   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: %s

assistant: ```c
void binString(int n) {
  char bin[17];
  int x;
  for (x = 0; x < 16; x++) {
    bin[x] = n & 0x8000 ? '1' : '0';
    n <<= 1;
  }
  bin[16] = '\0';
  printf("%s", bin);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<binString>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x10(%rsp),%rcx
L7:
  test   $0x8000,%edi
  setne  %dl
  add    $0x30,%edx
  mov    %dl,(%rax)
  add    %edi,%edi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L7
  movb   $0x0,0x10(%rsp)
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: %s

assistant: ```c
void binString(int n) {
  char bin[17];
  int x;
  for (x = 0; x < 16; x++) {
    bin[x] = n & 0x8000 ? '1' : '0';
    n <<= 1;
  }
  bin[16] = '\0';
  printf("%s", bin);
}
```
user: Translate the below assembly code into C programming language:

```asm
<binString>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x10(%rsp),%rcx
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L17:
  test   $0x8000,%edi
  setne  %dl
  add    $0x1,%rax
  add    %edi,%edi
  add    $0x30,%edx
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  jne    L17
  lea    D2(%rip),%rdi
  movb   $0x0,0x10(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: %s

assistant: ```c
void binString(int n) {
  char bin[17];
  int x;
  for (x = 0; x < 16; x++) {
    bin[x] = n & 0x8000 ? '1' : '0';
    n <<= 1;
  }
  bin[16] = '\0';
  printf("%s", bin);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binString>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  test   $0x80,%ah
  mov    %rsp,%rsi
  movb   $0x0,0x10(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x40,%ah
  mov    %dl,(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x20,%ah
  mov    %dl,0x1(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x10,%ah
  mov    %dl,0x2(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x8,%ah
  mov    %dl,0x3(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x4,%ah
  mov    %dl,0x4(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x2,%ah
  mov    %dl,0x5(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x1,%ah
  mov    %dl,0x6(%rsp)
  setne  %dl
  add    $0x30,%edx
  mov    %dl,0x7(%rsp)
  mov    %edi,%edx
  lea    D5(%rip),%rdi
  shr    $0x7,%dl
  add    $0x30,%edx
  test   $0x40,%al
  mov    %dl,0x8(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x20,%al
  mov    %dl,0x9(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x10,%al
  mov    %dl,0xa(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x8,%al
  mov    %dl,0xb(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x4,%al
  mov    %dl,0xc(%rsp)
  setne  %dl
  add    $0x30,%edx
  test   $0x2,%al
  mov    %dl,0xd(%rsp)
  setne  %dl
  and    $0x1,%eax
  add    $0x30,%edx
  add    $0x30,%eax
  mov    %dl,0xe(%rsp)
  mov    %al,0xf(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: %s

assistant: ```c
void binString(int n) {
  char bin[17];
  int x;
  for (x = 0; x < 16; x++) {
    bin[x] = n & 0x8000 ? '1' : '0';
    n <<= 1;
  }
  bin[16] = '\0';
  printf("%s", bin);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wl_wep_code>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%r8
  mov    %rax,%rdx
  lea    0xc(%rax),%rsi
  mov    $0x0,%eax
L13:
  xor    (%rdx),%al
  add    (%rdx),%al
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L13
  movb   $0x0,(%rdi)
  test   %ecx,%ecx
  jle    L80
  movsbl %al,%esi
  mov    %ecx,%r11d
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  jmp    L66
L4:
  movslq %r9d,%rax
  mov    %edx,%r10d
  shr    $0x4,%r10b
  add    %r10b,(%rdi,%rax,1)
  shl    $0x2,%edx
  and    $0x3c,%edx
  add    $0x26,%edx
  mov    %dl,0x1(%rdi,%rax,1)
  movb   $0x0,0x2(%rdi,%rax,1)
L6:
  add    $0x1,%r9d
  add    $0x1,%rcx
  add    $0x1,%esi
  cmp    %r11,%rcx
  je     L80
L66:
  movsbl (%r8,%rcx,1),%edx
  xor    %esi,%edx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%eax
  lea    (%rax,%rax,2),%r10d
  mov    %ecx,%eax
  sub    %r10d,%eax
  cmp    $0x1,%eax
  je     L4
  cmp    $0x2,%eax
  je     L69
  test   %eax,%eax
  jne    L6
  movslq %r9d,%rax
  mov    %edx,%r10d
  shr    $0x2,%r10b
  add    $0x26,%r10d
  mov    %r10b,(%rdi,%rax,1)
  shl    $0x4,%edx
  and    $0x30,%edx
  add    $0x26,%edx
  mov    %dl,0x1(%rdi,%rax,1)
  movb   $0x0,0x2(%rdi,%rax,1)
  jmp    L6
L69:
  movslq %r9d,%rax
  mov    %edx,%r10d
  shr    $0x6,%r10b
  add    %r10b,(%rdi,%rax,1)
  and    $0x3f,%edx
  add    $0x26,%edx
  mov    %dl,0x1(%rdi,%rax,1)
  movb   $0x0,0x2(%rdi,%rax,1)
  add    $0x1,%r9d
  jmp    L6
L80:
  call   <strlen@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wl_wep_code(char *szCrypt, char *szDest, void *Data, int nLen) {
  int i;
  int t;
  int k;
  char bits;
  char *szData = (char *)Data;
  for (i = bits = 0; i < 12; i++) {
    bits ^= szCrypt[i];
    bits += szCrypt[i];
  }
  for (i = t = *szDest = 0; i < nLen; i++, t++) {
    k = szData[i] ^ (bits + i);
    switch (i % 3) {
    case 0:
      szDest[t] = ((k & 0xFC) >> 2) + '&';
      szDest[t + 1] = ((k & 0x03) << 4) + '&';
      szDest[t + 2] = '\0';
      break;
    case 1:
      szDest[t] += ((k & 0xF0) >> 4);
      szDest[t + 1] = ((k & 0x0F) << 2) + '&';
      szDest[t + 2] = '\0';
      break;
    case 2:
      szDest[t] += ((k & 0xC0) >> 6);
      szDest[t + 1] = (k & 0x3F) + '&';
      szDest[t + 2] = '\0';
      t++;
      break;
    }
  }
  return (strlen(szDest));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wl_wep_code>:
  endbr64
  mov    %rdx,%r9
  mov    %rsi,%r8
  lea    0xc(%rdi),%rdx
  xor    %eax,%eax
L11:
  xor    (%rdi),%al
  add    $0x1,%rdi
  add    -0x1(%rdi),%al
  cmp    %rdi,%rdx
  jne    L11
  movb   $0x0,(%r8)
  test   %ecx,%ecx
  jle    L76
  push   %r12
  movsbl %al,%esi
  xor    %r10d,%r10d
  push   %rbp
  mov    $0xaaaaaaab,%ebp
  push   %rbx
  movslq %ecx,%rbx
  xor    %ecx,%ecx
  jmp    L64
L72:
  mov    %eax,%edx
  shl    $0x4,%eax
  shr    $0x2,%dl
  and    $0x30,%eax
  add    $0x26,%edx
  add    $0x26,%eax
  mov    %dl,(%r11)
  mov    %al,(%r12)
  movb   $0x0,(%rdi)
L77:
  add    $0x1,%rcx
  add    $0x1,%r10d
  add    $0x1,%esi
  cmp    %rcx,%rbx
  je     L3
L64:
  mov    %ecx,%edx
  movsbl (%r9,%rcx,1),%eax
  imul   %rbp,%rdx
  xor    %esi,%eax
  shr    $0x21,%rdx
  lea    (%rdx,%rdx,2),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  movslq %r10d,%rdi
  lea    (%r8,%rdi,1),%r11
  lea    0x1(%r8,%rdi,1),%r12
  lea    0x2(%r8,%rdi,1),%rdi
  cmp    $0x1,%edx
  je     L38
  cmp    $0x2,%edx
  jne    L72
  mov    %eax,%edx
  and    $0x3f,%eax
  add    $0x1,%r10d
  add    $0x1,%rcx
  add    $0x26,%eax
  shr    $0x6,%dl
  add    $0x1,%r10d
  add    %dl,(%r11)
  add    $0x1,%esi
  mov    %al,(%r12)
  movb   $0x0,(%rdi)
  cmp    %rcx,%rbx
  jne    L64
L3:
  pop    %rbx
  mov    %r8,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <strlen@plt>
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %eax,%edx
  shl    $0x2,%eax
  and    $0x3c,%eax
  shr    $0x4,%dl
  add    %dl,(%r11)
  add    $0x26,%eax
  mov    %al,(%r12)
  movb   $0x0,(%rdi)
  jmp    L77
L76:
  mov    %r8,%rdi
  jmp    1050 <strlen@plt>
```

assistant: ```c
int wl_wep_code(char *szCrypt, char *szDest, void *Data, int nLen) {
  int i;
  int t;
  int k;
  char bits;
  char *szData = (char *)Data;
  for (i = bits = 0; i < 12; i++) {
    bits ^= szCrypt[i];
    bits += szCrypt[i];
  }
  for (i = t = *szDest = 0; i < nLen; i++, t++) {
    k = szData[i] ^ (bits + i);
    switch (i % 3) {
    case 0:
      szDest[t] = ((k & 0xFC) >> 2) + '&';
      szDest[t + 1] = ((k & 0x03) << 4) + '&';
      szDest[t + 2] = '\0';
      break;
    case 1:
      szDest[t] += ((k & 0xF0) >> 4);
      szDest[t + 1] = ((k & 0x0F) << 2) + '&';
      szDest[t + 2] = '\0';
      break;
    case 2:
      szDest[t] += ((k & 0xC0) >> 6);
      szDest[t + 1] = (k & 0x3F) + '&';
      szDest[t + 2] = '\0';
      t++;
      break;
    }
  }
  return (strlen(szDest));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wl_wep_code>:
  endbr64
  mov    %rdi,%rax
  push   %r15
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %r14
  mov    %ecx,%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl 0x1(%rax),%r15d
  movzbl 0x2(%rax),%r14d
  movzbl 0x3(%rax),%r13d
  movzbl 0x4(%rax),%r12d
  movzbl 0x5(%rax),%ebp
  movzbl 0x6(%rax),%ebx
  movzbl 0x7(%rax),%r11d
  movzbl 0x8(%rax),%r10d
  movzbl 0x9(%rax),%r9d
  movzbl 0xa(%rax),%r8d
  movzbl 0xb(%rax),%ecx
  movzbl (%rax),%eax
  movb   $0x0,(%rdi)
  add    %eax,%eax
  xor    %r15d,%eax
  add    %r15d,%eax
  xor    %r14d,%eax
  add    %r14d,%eax
  xor    %r13d,%eax
  add    %r13d,%eax
  xor    %r12d,%eax
  add    %r12d,%eax
  xor    %ebp,%eax
  add    %ebp,%eax
  xor    %ebx,%eax
  add    %ebx,%eax
  xor    %r11d,%eax
  add    %r11d,%eax
  xor    %r10d,%eax
  add    %r10d,%eax
  xor    %r9d,%eax
  add    %r9d,%eax
  xor    %r8d,%eax
  add    %r8d,%eax
  xor    %ecx,%eax
  add    %ecx,%eax
  test   %edx,%edx
  jle    L65
  movsbl %al,%r8d
  movslq %edx,%rbp
  xor    %r9d,%r9d
  xor    %r10d,%r10d
  mov    $0xaaaaaaab,%ebx
  jmp    L46
  nopl   (%rax)
L54:
  mov    %eax,%edx
  shl    $0x4,%eax
  shr    $0x2,%dl
  and    $0x30,%eax
  add    $0x26,%edx
  add    $0x26,%eax
  mov    %dl,(%r11)
  mov    %al,0x0(%r13)
  movb   $0x0,(%r12)
L27:
  add    $0x1,%r9
  add    $0x1,%r10d
  add    $0x1,%r8d
  cmp    %rbp,%r9
  je     L65
L46:
  mov    %r9d,%edx
  movsbl (%rsi,%r9,1),%eax
  imul   %rbx,%rdx
  xor    %r8d,%eax
  shr    $0x21,%rdx
  lea    (%rdx,%rdx,2),%ecx
  mov    %r9d,%edx
  sub    %ecx,%edx
  movslq %r10d,%rcx
  lea    (%rdi,%rcx,1),%r11
  lea    0x1(%rdi,%rcx,1),%r13
  lea    0x2(%rdi,%rcx,1),%r12
  cmp    $0x1,%edx
  je     L52
  cmp    $0x2,%edx
  jne    L54
  mov    %eax,%edx
  and    $0x3f,%eax
  add    $0x1,%r10d
  lea    0x26(%rax),%ecx
  shr    $0x6,%dl
  add    %dl,(%r11)
  mov    %cl,0x0(%r13)
  movb   $0x0,(%r12)
  jmp    L27
  nopl   (%rax)
L52:
  mov    %eax,%edx
  shl    $0x2,%eax
  and    $0x3c,%eax
  shr    $0x4,%dl
  add    %dl,(%r11)
  add    $0x26,%eax
  mov    %al,0x0(%r13)
  movb   $0x0,(%r12)
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L65:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <strlen@plt>
```

assistant: ```c
int wl_wep_code(char *szCrypt, char *szDest, void *Data, int nLen) {
  int i;
  int t;
  int k;
  char bits;
  char *szData = (char *)Data;
  for (i = bits = 0; i < 12; i++) {
    bits ^= szCrypt[i];
    bits += szCrypt[i];
  }
  for (i = t = *szDest = 0; i < nLen; i++, t++) {
    k = szData[i] ^ (bits + i);
    switch (i % 3) {
    case 0:
      szDest[t] = ((k & 0xFC) >> 2) + '&';
      szDest[t + 1] = ((k & 0x03) << 4) + '&';
      szDest[t + 2] = '\0';
      break;
    case 1:
      szDest[t] += ((k & 0xF0) >> 4);
      szDest[t + 1] = ((k & 0x0F) << 2) + '&';
      szDest[t + 2] = '\0';
      break;
    case 2:
      szDest[t] += ((k & 0xC0) >> 6);
      szDest[t + 1] = (k & 0x3F) + '&';
      szDest[t + 2] = '\0';
      t++;
      break;
    }
  }
  return (strlen(szDest));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L39
  mov    $0x0,%eax
  call   <clear@plt>
L39:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jg     L28
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L28
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D24
data_type: string
name: unpack_data
arguments: data_tag: D16
data_type: string
name: unpack_data
arguments: data_tag: D22
data_type: string

tool: D24: %d,%d


tool: D16: please input num between%d to %d: 

tool: D22: %d

assistant: ```c
int get(int a, int b) {
  int n;
  printf("%d,%d\n", a, b);
  do {
    printf("please input num between%d to %d: ", a, b);
    if (scanf("%d", &n))
      clear();
  } while (n < a || n > b);
  return (a + b) / n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D28(%rip),%r12
L25:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L43
L49:
  mov    0x4(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L25
  cmp    %ebp,%ecx
  jl     L25
  lea    0x0(%rbp,%rbx,1),%eax
  cltd
  idiv   %ecx
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  mov    $0x0,%eax
  call   <clear@plt>
  jmp    L49
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string

tool: D12: %d,%d


tool: D10: please input num between%d to %d: 

tool: D28: %d

assistant: ```c
int get(int a, int b) {
  int n;
  printf("%d,%d\n", a, b);
  do {
    printf("please input num between%d to %d: ", a, b);
    if (scanf("%d", &n))
      clear();
  } while (n < a || n > b);
  return (a + b) / n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get>:
  endbr64
  push   %r14
  mov    %esi,%edx
  lea    D19(%rip),%r14
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    %ebx,%edx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L47
L22:
  mov    0x4(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L49
  cmp    %ebp,%ecx
  jl     L49
  lea    0x0(%rbp,%rbx,1),%eax
  cltd
  idiv   %ecx
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L47:
  xor    %eax,%eax
  call   <clear@plt>
  jmp    L22
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D2
data_type: string
name: unpack_data
arguments: label: D4
data_type: string

tool: D19: please input num between%d to %d: 

tool: D2: %d

tool: D4: %d,%d


assistant: ```c
int get(int a, int b) {
  int n;
  printf("%d,%d\n", a, b);
  do {
    printf("please input num between%d to %d: ", a, b);
    if (scanf("%d", &n))
      clear();
  } while (n < a || n > b);
  return (a + b) / n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get>:
  endbr64
  push   %r14
  mov    %esi,%edx
  lea    D2(%rip),%r14
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  lea    D26(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %ebp,%edx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L38
  mov    0x4(%rsp),%ecx
  cmp    %ebp,%ecx
  jg     L53
  cmp    %ebx,%ecx
  jl     L53
L20:
  lea    (%rbx,%rbp,1),%eax
  cltd
  idiv   %ecx
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  call   <clear@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ecx,%ebx
  jg     L53
  cmp    %ecx,%ebp
  jl     L53
  jmp    L20
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D14
type_infered: string
name: parse_data
arguments: tag: D26
type_infered: string

tool: D2: please input num between%d to %d: 

tool: D14: %d

tool: D26: %d,%d


assistant: ```c
int get(int a, int b) {
  int n;
  printf("%d,%d\n", a, b);
  do {
    printf("please input num between%d to %d: ", a, b);
    if (scanf("%d", &n))
      clear();
  } while (n < a || n > b);
  return (a + b) / n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_data_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L17:
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L17
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string

tool: D13: %G 

tool: D4: %G

assistant: ```c
void print_data_double(double *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M - 1; j++) {
      printf("%G ", dat[i * M + j]);
    }
    printf("%G", dat[i * M + (M - 1)]);
    printf("\n");
  }
}
```