user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_same_file>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    $0x18,%edi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %rax,%r12
  call   <stat@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <stat@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <lstat@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <lstat@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%r15d
  and    0x0(%rbp),%r15d
  jne    L106
  and    (%r12),%eax
  jne    L17
L76:
  mov    0x8(%r12),%rax
  mov    %rbp,%rdi
  cmp    %rax,0x8(%rbp)
  jne    L84
  mov    0x10(%r12),%rax
  cmp    %rax,0x10(%rbp)
  je     L66
L84:
  call   <free@plt>
  mov    %r12,%rdi
  xor    %r15d,%r15d
  call   <free@plt>
L49:
  pop    %rbp
  mov    %r15d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L106:
  and    (%r12),%eax
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %eax,%r15d
  jne    L71
L97:
  call   <stat@plt>
  mov    %r13,%rdi
  mov    %r12,%rsi
  call   <stat@plt>
  mov    0x8(%r12),%rax
  mov    %rbp,%rdi
  cmp    %rax,0x8(%rbp)
  jne    L92
  mov    0x10(%r12),%rax
  cmp    %rax,0x10(%rbp)
  je     L66
L92:
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbp
  mov    %r15d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L71:
  call   <stat@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <stat@plt>
  jmp    L76
  nopl   (%rax)
L82:
  mov    %rbp,%rdi
  mov    $0xffffffff,%r15d
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  jmp    L49
L66:
  call   <free@plt>
  mov    %r12,%rdi
  mov    $0xffffffff,%r15d
  call   <free@plt>
  jmp    L49
```

assistant: ```c
int is_same_file(char *file1, char *file2) {
  struct stat *buf1;
  struct stat *buf2;
  buf1 = (struct stat *)malloc(sizeof(struct stat));
  buf2 = (struct stat *)malloc(sizeof(struct stat));
  stat(file1, buf1);
  stat(file2, buf2);
  if (strcmp(file1, file2) == 0) {
    free(buf1);
    free(buf2);
    return -1;
  } else {
    lstat(file1, buf1);
    lstat(file2, buf2);
    if (!(buf1->st_mode & S_IFLNK) && !(buf2->st_mode & S_IFLNK)) {
      if ((buf1->st_dev == buf2->st_dev) && (buf1->st_ino == buf2->st_ino)) {
        free(buf1);
        free(buf2);
        return -1;
      } else {
        free(buf1);
        free(buf2);
        return 0;
      }
    } else if ((buf1->st_mode & S_IFLNK) && (buf2->st_mode & S_IFLNK)) {
      stat(file1, buf1);
      stat(file2, buf2);
      if ((buf1->st_dev == buf2->st_dev) && (buf1->st_ino == buf2->st_ino)) {
        free(buf1);
        free(buf2);
        return -1;
      } else {
        free(buf1);
        free(buf2);
        return 0;
      }
    } else if ((buf1->st_mode & S_IFLNK) && !(buf2->st_mode & S_IFLNK)) {
      stat(file1, buf1);
      stat(file2, buf2);
      if ((buf1->st_dev == buf2->st_dev) && (buf1->st_ino == buf2->st_ino)) {
        free(buf1);
        free(buf2);
        return -1;
      } else {
        free(buf1);
        free(buf2);
        return 0;
      }
    } else {
      stat(file1, buf1);
      stat(file2, buf2);
      if ((buf1->st_dev == buf2->st_dev) && (buf1->st_ino == buf2->st_ino)) {
        free(buf1);
        free(buf2);
        return -1;
      } else {
        free(buf1);
        free(buf2);
        return 0;
      }
    }
  }
}
```