ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<setargs>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%r13d
  cmp    $0x2d,%r13d
  jne    L80
  cmpb   $0x71,0x1(%rdi)
  je     L81
L80:
  lea    D34(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L23
  cmp    $0x2d,%r13d
  jne    L54
  cmpb   $0x66,0x1(%rbp)
  jne    L54
  cmpb   $0x0,0x2(%rbp)
  lea    D18(%rip),%rdi
  jne    L54
L46:
  call   <perror@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <exit@plt>
  nopl   0x0(%rax)
L81:
  cmpb   $0x0,0x2(%rdi)
  jne    L80
L23:
  mov    %rbx,(%r12)
L86:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L54:
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L86
  lea    D9(%rip),%rdi
  jmp    L46
```

tool_calls: name: unpack_data
arguments: data_label: D34
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D34: --query

tool: D18: -f not implemented

tool: D15: --file

tool: D9: --file not implemented

assistant: ```c
void setargs(char *flag, char *arg, char **query, FILE **out) {
  if (!strcmp(flag, "-q")) {
    *query = arg;
    return;
  }
  if (!strcmp(flag, "--query")) {
    *query = arg;
    return;
  }
  if (!strcmp(flag, "-f")) {
    perror("-f not implemented");
    exit(1);
    return;
  }
  if (!strcmp(flag, "--file")) {
    perror("--file not implemented");
    exit(1);
    return;
  }
  (void)out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setargs>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%r13d
  cmp    $0x2d,%r13d
  jne    L34
  cmpb   $0x71,0x1(%rdi)
  je     L57
L34:
  lea    D33(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L76
  cmp    $0x2d,%r13d
  jne    L26
  cmpb   $0x66,0x1(%rbp)
  jne    L26
  cmpb   $0x0,0x2(%rbp)
  lea    D4(%rip),%rdi
  jne    L26
L63:
  call   <perror@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <exit@plt>
  nopl   0x0(%rax)
L57:
  cmpb   $0x0,0x2(%rdi)
  jne    L34
L76:
  mov    %rbx,(%r12)
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L26:
  lea    D35(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L80
  lea    D37(%rip),%rdi
  jmp    L63
```

tool_calls: name: retrieve_data
arguments: tag: D33
datatype: string
name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D35
datatype: string
name: retrieve_data
arguments: tag: D37
datatype: string

tool: D33: --query

tool: D4: -f not implemented

tool: D35: --file

tool: D37: --file not implemented

assistant: ```c
void setargs(char *flag, char *arg, char **query, FILE **out) {
  if (!strcmp(flag, "-q")) {
    *query = arg;
    return;
  }
  if (!strcmp(flag, "--query")) {
    *query = arg;
    return;
  }
  if (!strcmp(flag, "-f")) {
    perror("-f not implemented");
    exit(1);
    return;
  }
  if (!strcmp(flag, "--file")) {
    perror("--file not implemented");
    exit(1);
    return;
  }
  (void)out;
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_random_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  or     -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t make_random_addr(uint32_t mask, uint8_t subnet) {
  uint32_t addr;
  addr = random();
  return (ntohl(addr >> subnet) | mask);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<make_random_addr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <random@plt>
  mov    %ebp,%ecx
  sar    %cl,%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t make_random_addr(uint32_t mask, uint8_t subnet) {
  uint32_t addr;
  addr = random();
  return (ntohl(addr >> subnet) | mask);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_random_addr>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <random@plt>
  mov    %ebp,%ecx
  sar    %cl,%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t make_random_addr(uint32_t mask, uint8_t subnet) {
  uint32_t addr;
  addr = random();
  return (ntohl(addr >> subnet) | mask);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_random_addr>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <random@plt>
  mov    %ebp,%ecx
  sar    %cl,%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t make_random_addr(uint32_t mask, uint8_t subnet) {
  uint32_t addr;
  addr = random();
  return (ntohl(addr >> subnet) | mask);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<w>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    0x10(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int w(int i1, int i2, int i3, int i4, int i5, int i6, int i7) {
  int a = f(i5);
  return i1 + i2 + i3 + i4 + a + i6 + i7;
}
```
user: Translate the below assembly code into C programming language:

```asm
<w>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r14d
  mov    %edx,%r13d
  mov    %ecx,%r12d
  mov    %r8d,%edi
  mov    %r9d,%ebp
  call   <f@plt>
  add    %r14d,%ebx
  add    %r13d,%ebx
  add    %r12d,%ebx
  add    %ebx,%eax
  add    %ebp,%eax
  add    0x30(%rsp),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int w(int i1, int i2, int i3, int i4, int i5, int i6, int i7) {
  int a = f(i5);
  return i1 + i2 + i3 + i4 + a + i6 + i7;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<w>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %r8d,%edi
  add    %r14d,%ebx
  add    %r13d,%ebx
  call   <f@plt>
  add    %r12d,%ebx
  add    %ebx,%eax
  add    %ebp,%eax
  add    0x30(%rsp),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int w(int i1, int i2, int i3, int i4, int i5, int i6, int i7) {
  int a = f(i5);
  return i1 + i2 + i3 + i4 + a + i6 + i7;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<w>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %r8d,%edi
  add    %r14d,%ebx
  add    %r13d,%ebx
  call   <f@plt>
  add    %r12d,%ebx
  add    %ebx,%eax
  add    %ebp,%eax
  add    0x30(%rsp),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int w(int i1, int i2, int i3, int i4, int i5, int i6, int i7) {
  int a = f(i5);
  return i1 + i2 + i3 + i4 + a + i6 + i7;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<astpnprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  movq   $0x0,-0xb8(%rbp)
  mov    -0xd8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0xc8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xbc(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xc8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xb8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rax
  sub    -0xb8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0xd0(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void astpnprintf(char **str, size_t *size, const char *fmt, ...) {
  va_list args;
  size_t newsiz = 0;
  va_start(args, fmt);
  vsnprintf(*str, *size, fmt, args);
  va_end(args);
  newsiz = strnlen(*str, *size);
  *str += newsiz;
  *size -= newsiz;
}
```
user: Translate the below assembly code into C programming language:

```asm
<astpnprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rdx,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    (%rbx),%rsi
  mov    0x0(%rbp),%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    0x0(%rbp),%r12
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <strnlen@plt>
  add    %rax,%r12
  mov    %r12,0x0(%rbp)
  sub    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void astpnprintf(char **str, size_t *size, const char *fmt, ...) {
  va_list args;
  size_t newsiz = 0;
  va_start(args, fmt);
  vsnprintf(*str, *size, fmt, args);
  va_end(args);
  newsiz = strnlen(*str, *size);
  *str += newsiz;
  *size -= newsiz;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<astpnprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    (%rbx),%rsi
  mov    0x0(%rbp),%rdi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    (%rbx),%r12
  mov    0x0(%rbp),%r13
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strnlen@plt>
  add    %rax,%r13
  sub    %rax,%r12
  mov    %r13,0x0(%rbp)
  mov    %r12,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void astpnprintf(char **str, size_t *size, const char *fmt, ...) {
  va_list args;
  size_t newsiz = 0;
  va_start(args, fmt);
  vsnprintf(*str, *size, fmt, args);
  va_end(args);
  newsiz = strnlen(*str, *size);
  *str += newsiz;
  *size -= newsiz;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<astpnprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    (%rbx),%rsi
  mov    0x0(%rbp),%rdi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    (%rbx),%r12
  mov    0x0(%rbp),%r13
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strnlen@plt>
  add    %rax,%r13
  sub    %rax,%r12
  mov    %r13,0x0(%rbp)
  mov    %r12,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void astpnprintf(char **str, size_t *size, const char *fmt, ...) {
  va_list args;
  size_t newsiz = 0;
  va_start(args, fmt);
  vsnprintf(*str, *size, fmt, args);
  va_end(args);
  newsiz = strnlen(*str, *size);
  *str += newsiz;
  *size -= newsiz;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dumpreg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0xf,-0x4(%rbp)
  jle    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string

tool: D1: %02X 

assistant: ```c
void dumpreg(unsigned char *buf) {
  int i;
  for (i = 0; i < 16; i++) {
    printf("%02X ", buf[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dumpreg>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x10(%rdi),%r12
  lea    D4(%rip),%rbp
L5:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string

tool: D4: %02X 

assistant: ```c
void dumpreg(unsigned char *buf) {
  int i;
  for (i = 0; i < 16; i++) {
    printf("%02X ", buf[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dumpreg>:
  endbr64
  push   %r12
  lea    0x10(%rdi),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L9:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: %02X 

assistant: ```c
void dumpreg(unsigned char *buf) {
  int i;
  for (i = 0; i < 16; i++) {
    printf("%02X ", buf[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dumpreg>:
  endbr64
  push   %r12
  lea    0x10(%rdi),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L0:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: %02X 

assistant: ```c
void dumpreg(unsigned char *buf) {
  int i;
  for (i = 0; i < 16; i++) {
    printf("%02X ", buf[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D25(%rip),%rsi
  lea    D23(%rip),%rbp
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    D85(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
L2:
  mov    %rbp,%rdx
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L2
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  lea    D0(%rip),%rsi
  lea    D23(%rip),%rbp
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    D48(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  lea    D66(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
L1:
  mov    %rbp,%rdx
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L1
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D23
type_guessed: string
name: read_data
arguments: data_tag: D85
type_guessed: string
name: read_data
arguments: data_tag: D26
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D48
type_guessed: string
name: read_data
arguments: data_tag: D66
type_guessed: string

tool: D25: w

tool: D23: Lyrics.txt

tool: D85: Hey This is inital file..

tool: D26: r

tool: D0: a

tool: D48: 
here we have a simple line

tool: D66: 
here we have another simple line

assistant: ```c
int main() {
  char *pline;
  FILE *fptr;
  fptr = fopen("Lyrics.txt", "w");
  fprintf(fptr, "Hey This is inital file..");
  fclose(fptr);
  fptr = fopen("Lyrics.txt", "r");
  pline = (char *)malloc(200 * sizeof(char));
  while (1) {
    fgets(pline, 200, fptr);
    puts(pline);
    if (feof(fptr)) {
      break;
    }
  }
  fclose(fptr);
  free(pline);
  fptr = fopen("Lyrics.txt", "a");
  fprintf(fptr, "\nhere we have a simple line");
  fprintf(fptr, "\nhere we have another simple line");
  fclose(fptr);
  fptr = fopen("Lyrics.txt", "r");
  pline = (char *)malloc(200 * sizeof(char));
  while (1) {
    fgets(pline, 200, fptr);
    puts(pline);
    if (feof(fptr)) {
      break;
    }
  }
  fclose(fptr);
  free(pline);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%rsi
  lea    D66(%rip),%r14
  push   %r13
  lea    D65(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  lea    D60(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    $0xc8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L0:
  mov    %r12,%rdx
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L0
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D18(%rip),%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  lea    D48(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  lea    D61(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    $0xc8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
L15:
  mov    %r12,%rdx
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L15
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D22
type_guessed: string
name: unpack_data
arguments: data_label: D66
type_guessed: string
name: unpack_data
arguments: data_label: D65
type_guessed: string
name: unpack_data
arguments: data_label: D60
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D48
type_guessed: string
name: unpack_data
arguments: data_label: D61
type_guessed: string

tool: D22: w

tool: D66: r

tool: D65: Lyrics.txt

tool: D60: Hey This is inital file..

tool: D18: a

tool: D48: 
here we have a simple line

tool: D61: 
here we have another simple line

assistant: ```c
int main() {
  char *pline;
  FILE *fptr;
  fptr = fopen("Lyrics.txt", "w");
  fprintf(fptr, "Hey This is inital file..");
  fclose(fptr);
  fptr = fopen("Lyrics.txt", "r");
  pline = (char *)malloc(200 * sizeof(char));
  while (1) {
    fgets(pline, 200, fptr);
    puts(pline);
    if (feof(fptr)) {
      break;
    }
  }
  fclose(fptr);
  free(pline);
  fptr = fopen("Lyrics.txt", "a");
  fprintf(fptr, "\nhere we have a simple line");
  fprintf(fptr, "\nhere we have another simple line");
  fclose(fptr);
  fptr = fopen("Lyrics.txt", "r");
  pline = (char *)malloc(200 * sizeof(char));
  while (1) {
    fgets(pline, 200, fptr);
    puts(pline);
    if (feof(fptr)) {
      break;
    }
  }
  fclose(fptr);
  free(pline);
  return 0;
}
```