ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<japi_delete_grammar>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D0(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <do_send@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <send_idlist@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: DELGRAM


assistant: ```c
void japi_delete_grammar(int sd, char *idlist) {
  do_send(sd, "DELGRAM\n");
  send_idlist(sd, idlist);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<japi_delete_grammar>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D2(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <do_send@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <send_idlist@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: DELGRAM


assistant: ```c
void japi_delete_grammar(int sd, char *idlist) {
  do_send(sd, "DELGRAM\n");
  send_idlist(sd, idlist);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mkdirp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L32
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L32
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L4
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  mov    -0x18(%rbp),%rax
  movb   $0x2f,(%rax)
L4:
  addq   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  leave
  ret
```

assistant: ```c
int mkdirp(const char *dir, mode_t mode) {
  char *tmp = strdup(dir);
  char *p = tmp;
  size_t len;
  len = strlen(tmp);
  if (tmp[len - 1] == '/')
    tmp[len - 1] = '\0';
  for (; *p; p++)
    if (*p == '/') {
      *p = '\0';
      mkdir(tmp, mode);
      *p = '/';
    }
  free(tmp);
  return mkdir(dir, mode);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mkdirp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbp,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  je     L26
L27:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L51
  mov    %rbp,%rbx
  jmp    L64
L26:
  movb   $0x0,(%rax)
  jmp    L27
L37:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L51
L64:
  cmp    $0x2f,%al
  jne    L37
  movb   $0x0,(%rbx)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  movb   $0x2f,(%rbx)
  jmp    L37
L51:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <mkdir@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mkdirp(const char *dir, mode_t mode) {
  char *tmp = strdup(dir);
  char *p = tmp;
  size_t len;
  len = strlen(tmp);
  if (tmp[len - 1] == '/')
    tmp[len - 1] = '\0';
  for (; *p; p++)
    if (*p == '/') {
      *p = '\0';
      mkdir(tmp, mode);
      *p = '/';
    }
  free(tmp);
  return mkdir(dir, mode);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mkdirp>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    -0x1(%rbp,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  jne    L52
  movb   $0x0,(%rax)
L52:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L38
  mov    %rbp,%rbx
  jmp    L58
  xchg   %ax,%ax
L46:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L38
L58:
  cmp    $0x2f,%al
  jne    L46
  movb   $0x0,(%rbx)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <mkdir@plt>
  movb   $0x2f,-0x1(%rbx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L58
L38:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <mkdir@plt>
```

assistant: ```c
int mkdirp(const char *dir, mode_t mode) {
  char *tmp = strdup(dir);
  char *p = tmp;
  size_t len;
  len = strlen(tmp);
  if (tmp[len - 1] == '/')
    tmp[len - 1] = '\0';
  for (; *p; p++)
    if (*p == '/') {
      *p = '\0';
      mkdir(tmp, mode);
      *p = '/';
    }
  free(tmp);
  return mkdir(dir, mode);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mkdirp>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    -0x1(%rbp,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  jne    L25
  movb   $0x0,(%rax)
L25:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L35
  mov    %rbp,%rbx
  nopl   0x0(%rax)
L50:
  cmp    $0x2f,%al
  je     L53
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L50
L35:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <mkdir@plt>
  nopl   (%rax)
L53:
  movb   $0x0,(%rbx)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <mkdir@plt>
  movb   $0x2f,-0x1(%rbx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L50
  jmp    L35
```

assistant: ```c
int mkdirp(const char *dir, mode_t mode) {
  char *tmp = strdup(dir);
  char *p = tmp;
  size_t len;
  len = strlen(tmp);
  if (tmp[len - 1] == '/')
    tmp[len - 1] = '\0';
  for (; *p; p++)
    if (*p == '/') {
      *p = '\0';
      mkdir(tmp, mode);
      *p = '/';
    }
  free(tmp);
  return mkdir(dir, mode);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<capi20_isinstalled>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <loadlib@plt>
  test   %rax,%rax
  jns    L4
  mov    $0x1009,%eax
  jmp    L2
L4:
  mov    $0x0,%eax
  call   <fptr_capi20_isinstalled@plt>
L2:
  pop    %rbp
  ret
```

assistant: ```c
unsigned capi20_isinstalled(void) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_isinstalled();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<capi20_isinstalled>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <loadlib@plt>
  mov    %rax,%rdx
  mov    $0x1009,%eax
  test   %rdx,%rdx
  js     L0
  mov    $0x0,%eax
  call   <fptr_capi20_isinstalled@plt>
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned capi20_isinstalled(void) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_isinstalled();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<capi20_isinstalled>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <loadlib@plt>
  test   %rax,%rax
  js     L0
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <fptr_capi20_isinstalled@plt>
  nop
L0:
  mov    $0x1009,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned capi20_isinstalled(void) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_isinstalled();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<capi20_isinstalled>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <loadlib@plt>
  test   %rax,%rax
  js     L8
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <fptr_capi20_isinstalled@plt>
  nop
L8:
  mov    $0x1009,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned capi20_isinstalled(void) {
  if (loadlib() < 0)
    return 0x1009;
  return fptr_capi20_isinstalled();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  lea    D69(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbp
  mov    %rbp,%r12
  mov    $0x0,%ebx
  lea    D45(%rip),%r14
  lea    D16(%rip),%r13
L46:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    $0x5,%ebx
  jne    L46
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    0x20(%rsp),%r13
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D45(%rip),%r15
  lea    D16(%rip),%r14
L9:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    $0x5,%ebx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rbp),%r15
  lea    D44(%rip),%r14
  jmp    L29
L37:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L23
L75:
  mov    0x0(%rbp),%esi
  cmp    (%rbx),%esi
  jne    L37
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L23:
  add    $0x4,%rbp
  cmp    %r15,%rbp
  je     L1
L29:
  lea    0x14(%r13),%r12
  mov    %r13,%rbx
  jmp    L75
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D69
type: string
name: read_data
arguments: data_tag: D45
type: string
name: read_data
arguments: data_tag: D16
type: string
name: read_data
arguments: data_tag: D14
type: string
name: read_data
arguments: data_tag: D20
type: string
name: read_data
arguments: data_tag: D44
type: string

tool: D69: Vetor 1:

tool: D45: Introduza %d numero: 

tool: D16: %d

tool: D14: Vetor 2:

tool: D20: Comuns:

tool: D44:  %d

assistant: ```c
int main() {
  int i, j, v1[5] = {}, v2[5] = {};
  printf("Vetor 1:\n");
  for (i = 0; i < 5; i++) {
    printf("Introduza %d numero: ", i + 1);
    scanf("%d", &v1[i]);
  }
  printf("Vetor 2:\n");
  for (i = 0; i < 5; i++) {
    printf("Introduza %d numero: ", i + 1);
    scanf("%d", &v2[i]);
  }
  printf("\n");
  printf("Comuns:");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      if (v1[i] == v2[j]) {
        printf(" %d", v1[i]);
      }
    }
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  lea    D24(%rip),%rdi
  push   %r14
  lea    D39(%rip),%r14
  push   %r13
  lea    D49(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x30(%rsp)
  mov    %rbp,%r12
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <puts@plt>
L21:
  add    $0x1,%ebx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L21
  lea    D37(%rip),%rdi
  lea    0x20(%rsp),%r12
  xor    %ebx,%ebx
  call   <puts@plt>
  mov    %r12,%r15
L34:
  add    $0x1,%ebx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x4,%r15
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L34
  mov    $0xa,%edi
  lea    0x14(%rbp),%r14
  lea    0x14(%r12),%r15
  call   <putchar@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  lea    D40(%rip),%r13
  call   <printf@plt>
L32:
  mov    %r12,%rbx
L56:
  mov    0x0(%rbp),%esi
  cmp    (%rbx),%esi
  je     L49
L10:
  add    $0x4,%rbx
  cmp    %rbx,%r15
  jne    L56
  add    $0x4,%rbp
  cmp    %r14,%rbp
  jne    L32
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L49:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L10
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D39
datatype: string
name: unpack_data
arguments: tag: D49
datatype: string
name: unpack_data
arguments: tag: D37
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D40
datatype: string

tool: D24: Vetor 1:

tool: D39: %d

tool: D49: Introduza %d numero: 

tool: D37: Vetor 2:

tool: D7: Comuns:

tool: D40:  %d

assistant: ```c
int main() {
  int i, j, v1[5] = {}, v2[5] = {};
  printf("Vetor 1:\n");
  for (i = 0; i < 5; i++) {
    printf("Introduza %d numero: ", i + 1);
    scanf("%d", &v1[i]);
  }
  printf("Vetor 2:\n");
  for (i = 0; i < 5; i++) {
    printf("Introduza %d numero: ", i + 1);
    scanf("%d", &v2[i]);
  }
  printf("\n");
  printf("Comuns:");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      if (v1[i] == v2[j]) {
        printf(" %d", v1[i]);
      }
    }
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wait_kbc_sendready>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L13:
  mov    $0x64,%edi
  call   <inb@plt>
  and    $0x2,%eax
  test   %eax,%eax
  je     L8
  jmp    L13
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wait_kbc_sendready(void) {
  for (;;) {
    if ((inb(0x0064) & 0x02) == 0) {
      return;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wait_kbc_sendready>:
  endbr64
  sub    $0x8,%rsp
L3:
  mov    $0x64,%edi
  call   <inb@plt>
  test   $0x2,%al
  jne    L3
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_kbc_sendready(void) {
  for (;;) {
    if ((inb(0x0064) & 0x02) == 0) {
      return;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wait_kbc_sendready>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x64,%edi
  call   <inb@plt>
  test   $0x2,%al
  jne    L6
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_kbc_sendready(void) {
  for (;;) {
    if ((inb(0x0064) & 0x02) == 0) {
      return;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wait_kbc_sendready>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x64,%edi
  call   <inb@plt>
  test   $0x2,%al
  jne    L6
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_kbc_sendready(void) {
  for (;;) {
    if ((inb(0x0064) & 0x02) == 0) {
      return;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<aes_ecbenc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  jmp    L24
L10:
  mov    -0x58(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x50(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <aes_cipher@plt>
  addq   $0x10,-0x28(%rbp)
L24:
  mov    -0x28(%rbp),%rax
  add    $0xf,%rax
  cmp    %rax,-0x48(%rbp)
  ja     L10
  lea    -0x20(%rbp),%rdx
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <aes_pkcs7padding@plt>
  mov    %ax,-0x2a(%rbp)
  movswq -0x2a(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x58(%rbp),%rax
  add    %rax,%rcx
  mov    -0x50(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <aes_cipher@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
void aes_ecbenc(const int bits, const char *in, const size_t length, const char *key, char *out) {
  char blk[16];
  for (size_t d = 0; d + 15 < length; d += 16) {
    aes_cipher(bits, in + d, key, out + d);
  }
  short quot = aes_pkcs7padding(in, length, blk);
  aes_cipher(bits, blk, key, out + length - quot);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<aes_ecbenc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%r12d
  mov    %rsi,(%rsp)
  mov    %rdx,%r15
  mov    %rcx,%r13
  mov    %r8,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0xf,%rdx
  jbe    L17
  mov    %rsi,%rbx
  mov    %r8,%rbp
  lea    -0x10(%rdx),%rax
  and    $0xfffffffffffffff0,%rax
  lea    0x10(%rsi,%rax,1),%r14
L25:
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <aes_cipher@plt>
  add    $0x10,%rbx
  add    $0x10,%rbp
  cmp    %r14,%rbx
  jne    L25
L17:
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    (%rsp),%rdi
  call   <aes_pkcs7padding@plt>
  movswq %ax,%rax
  sub    %rax,%r15
  mov    0x8(%rsp),%rcx
  add    %r15,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <aes_cipher@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_ecbenc(const int bits, const char *in, const size_t length, const char *key, char *out) {
  char blk[16];
  for (size_t d = 0; d + 15 < length; d += 16) {
    aes_cipher(bits, in + d, key, out + d);
  }
  short quot = aes_pkcs7padding(in, length, blk);
  aes_cipher(bits, blk, key, out + length - quot);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aes_ecbenc>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0xf,%rdx
  jbe    L11
  lea    -0x10(%rdx),%rax
  mov    %rsi,%rbx
  mov    %r8,%rbp
  and    $0xfffffffffffffff0,%rax
  lea    0x10(%rsi,%rax,1),%r12
  nopl   (%rax)
L24:
  mov    %rbp,%rcx
  mov    %rbx,%rsi
  mov    %r15,%rdx
  mov    %r14d,%edi
  call   <aes_cipher@plt>
  add    $0x10,%rbx
  add    $0x10,%rbp
  cmp    %r12,%rbx
  jne    L24
L11:
  mov    (%rsp),%rdi
  lea    0x10(%rsp),%rbp
  mov    %r13,%rsi
  mov    %rbp,%rdx
  call   <aes_pkcs7padding@plt>
  mov    0x8(%rsp),%rcx
  mov    %r15,%rdx
  mov    %rbp,%rsi
  movswq %ax,%rax
  mov    %r14d,%edi
  sub    %rax,%r13
  add    %r13,%rcx
  call   <aes_cipher@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_ecbenc(const int bits, const char *in, const size_t length, const char *key, char *out) {
  char blk[16];
  for (size_t d = 0; d + 15 < length; d += 16) {
    aes_cipher(bits, in + d, key, out + d);
  }
  short quot = aes_pkcs7padding(in, length, blk);
  aes_cipher(bits, blk, key, out + length - quot);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aes_ecbenc>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0xf,%rdx
  jbe    L27
  lea    -0x10(%rdx),%rax
  mov    %rsi,%rbx
  mov    %r8,%rbp
  and    $0xfffffffffffffff0,%rax
  lea    0x10(%rsi,%rax,1),%r12
  nopl   (%rax)
L9:
  mov    %rbp,%rcx
  mov    %rbx,%rsi
  mov    %r15,%rdx
  mov    %r14d,%edi
  call   <aes_cipher@plt>
  add    $0x10,%rbx
  add    $0x10,%rbp
  cmp    %r12,%rbx
  jne    L9
L27:
  mov    (%rsp),%rdi
  lea    0x10(%rsp),%rbp
  mov    %r13,%rsi
  mov    %rbp,%rdx
  call   <aes_pkcs7padding@plt>
  mov    0x8(%rsp),%rcx
  mov    %r15,%rdx
  mov    %rbp,%rsi
  movswq %ax,%rax
  mov    %r14d,%edi
  sub    %rax,%r13
  add    %r13,%rcx
  call   <aes_cipher@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_ecbenc(const int bits, const char *in, const size_t length, const char *key, char *out) {
  char blk[16];
  for (size_t d = 0; d + 15 < length; d += 16) {
    aes_cipher(bits, in + d, key, out + d);
  }
  short quot = aes_pkcs7padding(in, length, blk);
  aes_cipher(bits, blk, key, out + length - quot);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  mov    $0x1,%edi
  call   <sleep@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string

tool: D7: alive


assistant: ```c
int main() {
  while (1) {
    sleep(1);
    printf("alive\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
L3:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string

tool: D5: alive


assistant: ```c
int main() {
  while (1) {
    sleep(1);
    printf("alive\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
  nopl   0x0(%rax)
L6:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string

tool: D2: alive


assistant: ```c
int main() {
  while (1) {
    sleep(1);
    printf("alive\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  nopl   0x0(%rax)
L2:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: alive


assistant: ```c
int main() {
  while (1) {
    sleep(1);
    printf("alive\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mg_send_digest_auth_request>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <mg_printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: HTTP/1.1 401 Unauthorized
WWW-Authenticate: Digest qop="auth", realm="%s", nonce="%lu"
Content-Length: 0



assistant: ```c
void mg_send_digest_auth_request(struct mg_connection *c, const char *domain) {
  mg_printf(c,
            "HTTP/1.1 401 Unauthorized\r\n"
            "WWW-Authenticate: Digest qop=\"auth\", "
            "realm=\"%s\", nonce=\"%lu\"\r\n"
            "Content-Length: 0\r\n\r\n",
            domain, (unsigned long)time(NULL));
}
```