ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo(int *x) {
  free(x);
  free(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void foo(int *x) {
  free(x);
  free(x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void foo(int *x) {
  free(x);
  free(x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void foo(int *x) {
  free(x);
  free(x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<initv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  movsd  %xmm1,-0x18(%rbp)
  movsd  %xmm2,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void initv(double *r, const double x, const double y, const double z) {
  r[0] = x;
  r[1] = y;
  r[2] = z;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<initv>:
  endbr64
  movsd  %xmm0,(%rdi)
  movsd  %xmm1,0x8(%rdi)
  movsd  %xmm2,0x10(%rdi)
  ret
```

assistant: ```c
void initv(double *r, const double x, const double y, const double z) {
  r[0] = x;
  r[1] = y;
  r[2] = z;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<initv>:
  endbr64
  movsd  %xmm0,(%rdi)
  movsd  %xmm1,0x8(%rdi)
  movsd  %xmm2,0x10(%rdi)
  ret
```

assistant: ```c
void initv(double *r, const double x, const double y, const double z) {
  r[0] = x;
  r[1] = y;
  r[2] = z;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<initv>:
  endbr64
  unpcklpd %xmm1,%xmm0
  movsd  %xmm2,0x10(%rdi)
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void initv(double *r, const double x, const double y, const double z) {
  r[0] = x;
  r[1] = y;
  r[2] = z;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<append_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L8
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <concat@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  jmp    L4
L8:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <concat@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L4:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: 

assistant: ```c
void append_to(char **target, const char *a) {
  char *dst = *target;
  if (!dst)
    *target = concat("", a);
  else {
    char *tmp = concat(dst, a);
    free(dst);
    *target = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<append_to>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%r12
  test   %r12,%r12
  je     L0
  mov    %r12,%rdi
  call   <concat@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <free@plt>
L16:
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  lea    D4(%rip),%rdi
  call   <concat@plt>
  mov    %rax,%rbp
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: 

assistant: ```c
void append_to(char **target, const char *a) {
  char *dst = *target;
  if (!dst)
    *target = concat("", a);
  else {
    char *tmp = concat(dst, a);
    free(dst);
    *target = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<append_to>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%r12
  mov    %rdi,%rbx
  test   %r12,%r12
  je     L0
  mov    %r12,%rdi
  call   <concat@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <free@plt>
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  lea    D0(%rip),%rdi
  call   <concat@plt>
  mov    %rax,%rbp
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: 

assistant: ```c
void append_to(char **target, const char *a) {
  char *dst = *target;
  if (!dst)
    *target = concat("", a);
  else {
    char *tmp = concat(dst, a);
    free(dst);
    *target = tmp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<append_to>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%r12
  mov    %rdi,%rbx
  test   %r12,%r12
  je     L1
  mov    %r12,%rdi
  call   <concat@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <free@plt>
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L1:
  lea    D5(%rip),%rdi
  call   <concat@plt>
  mov    %rax,%rbp
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string

tool: 

assistant: ```c
void append_to(char **target, const char *a) {
  char *dst = *target;
  if (!dst)
    *target = concat("", a);
  else {
    char *tmp = concat(dst, a);
    free(dst);
    *target = tmp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SLS_atimes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L7
  mov    -0x8(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <SLS_dsprstx@plt>
  jmp    L2
L7:
  mov    -0x8(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <SLS_dsprsax@plt>
L2:
  leave
  ret
```

assistant: ```c
int SLS_atimes(const unsigned long n, double x[], double r[], const int itrnsp, const double sa[], const unsigned long ija[]) {
  if (itrnsp)
    return SLS_dsprstx(sa, ija, x, r, n);
  else
    return SLS_dsprsax(sa, ija, x, r, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<SLS_atimes>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r10
  mov    %rsi,%rax
  mov    %r8,%rdi
  mov    %r9,%rsi
  test   %ecx,%ecx
  je     L1
  mov    %r10,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <SLS_dsprstx@plt>
L14:
  add    $0x8,%rsp
  ret
L1:
  mov    %r10,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <SLS_dsprsax@plt>
  jmp    L14
```

assistant: ```c
int SLS_atimes(const unsigned long n, double x[], double r[], const int itrnsp, const double sa[], const unsigned long ija[]) {
  if (itrnsp)
    return SLS_dsprstx(sa, ija, x, r, n);
  else
    return SLS_dsprsax(sa, ija, x, r, n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<SLS_atimes>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r10
  test   %ecx,%ecx
  mov    %r8,%rdi
  mov    %rdx,%rcx
  mov    %r9,%rsi
  mov    %rax,%r8
  mov    %r10,%rdx
  je     L5
  jmp    1060 <SLS_dsprstx@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  jmp    1070 <SLS_dsprsax@plt>
```

assistant: ```c
int SLS_atimes(const unsigned long n, double x[], double r[], const int itrnsp, const double sa[], const unsigned long ija[]) {
  if (itrnsp)
    return SLS_dsprstx(sa, ija, x, r, n);
  else
    return SLS_dsprsax(sa, ija, x, r, n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SLS_atimes>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r10
  test   %ecx,%ecx
  mov    %r8,%rdi
  mov    %rdx,%rcx
  mov    %r9,%rsi
  mov    %rax,%r8
  mov    %r10,%rdx
  je     L2
  jmp    1060 <SLS_dsprstx@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  jmp    1070 <SLS_dsprsax@plt>
```

assistant: ```c
int SLS_atimes(const unsigned long n, double x[], double r[], const int itrnsp, const double sa[], const unsigned long ija[]) {
  if (itrnsp)
    return SLS_dsprstx(sa, ija, x, r, n);
  else
    return SLS_dsprsax(sa, ija, x, r, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetBW>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L16
  cmpl   $0x3,-0x4(%rbp)
  jg     L74
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  cmpl   $0x1,-0x4(%rbp)
  je     L48
  jmp    L74
L16:
  lea    D11(%rip),%rax
  jmp    L71
L4:
  lea    D10(%rip),%rax
  jmp    L71
L48:
  lea    D22(%rip),%rax
  jmp    L71
L74:
  lea    D29(%rip),%rax
L71:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D29
datatype: string

tool: D11: 10M

tool: D10: 20M

tool: D22: 40M

tool: D29: N/A

assistant: ```c
char *GetBW(int BW) {
  switch (BW) {
  case 3:
    return "10M";
  case 0:
    return "20M";
  case 1:
    return "40M";
  default:
    return "N/A";
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetBW>:
  endbr64
  lea    D7(%rip),%rax
  cmp    $0x1,%edi
  je     L6
  lea    D0(%rip),%rax
  cmp    $0x3,%edi
  je     L6
  test   %edi,%edi
  lea    D24(%rip),%rax
  lea    D20(%rip),%rdx
  cmove  %rdx,%rax
L6:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D24
data_type: string
name: extract_symbolic_data
arguments: data_tag: D20
data_type: string

tool: D7: 40M

tool: D0: 10M

tool: D24: N/A

tool: D20: 20M

assistant: ```c
char *GetBW(int BW) {
  switch (BW) {
  case 3:
    return "10M";
  case 0:
    return "20M";
  case 1:
    return "40M";
  default:
    return "N/A";
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetBW>:
  endbr64
  lea    D27(%rip),%rax
  cmp    $0x1,%edi
  je     L7
  lea    D0(%rip),%rax
  cmp    $0x3,%edi
  je     L7
  test   %edi,%edi
  lea    D25(%rip),%rax
  lea    D20(%rip),%rdx
  cmove  %rdx,%rax
L7:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D27
type: string
name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D25
type: string
name: retrieve_data
arguments: label: D20
type: string

tool: D27: 40M

tool: D0: 10M

tool: D25: N/A

tool: D20: 20M

assistant: ```c
char *GetBW(int BW) {
  switch (BW) {
  case 3:
    return "10M";
  case 0:
    return "20M";
  case 1:
    return "40M";
  default:
    return "N/A";
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GetBW>:
  endbr64
  lea    D36(%rip),%rax
  cmp    $0x1,%edi
  je     L0
  lea    D39(%rip),%rax
  cmp    $0x3,%edi
  je     L0
  test   %edi,%edi
  lea    D24(%rip),%rax
  lea    D13(%rip),%rdx
  cmove  %rdx,%rax
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D36
data_type: string
name: retrieve_data
arguments: label: D39
data_type: string
name: retrieve_data
arguments: label: D24
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D36: 40M

tool: D39: 10M

tool: D24: N/A

tool: D13: 20M

assistant: ```c
char *GetBW(int BW) {
  switch (BW) {
  case 3:
    return "10M";
  case 0:
    return "20M";
  case 1:
    return "40M";
  default:
    return "N/A";
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<unscrun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rdx
  mov    %rsi,%rax
  mov    (%rdx),%rcx
  mov    %rcx,%rsi
  shr    $0x18,%rsi
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  mov    %sil,(%rcx)
  mov    (%rdx),%rcx
  mov    %rcx,%rsi
  shr    $0x10,%rsi
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  mov    %sil,(%rcx)
  mov    (%rdx),%rcx
  mov    %rcx,%rsi
  shr    $0x8,%rsi
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  mov    %sil,(%rcx)
  mov    %rdx,%rcx
  lea    0x8(%rcx),%rdx
  mov    (%rcx),%rsi
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  mov    %sil,(%rcx)
  mov    (%rdx),%rcx
  shr    $0x18,%rcx
  mov    %rcx,%rsi
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  mov    %sil,(%rcx)
  mov    (%rdx),%rcx
  mov    %rcx,%rsi
  shr    $0x10,%rsi
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  mov    %sil,(%rcx)
  mov    (%rdx),%rcx
  shr    $0x8,%rcx
  mov    %rcx,%rsi
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  mov    %sil,(%rcx)
  mov    (%rdx),%rcx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  mov    %ecx,%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unscrun(register unsigned long *outof, register unsigned char *into) {
  *into++ = (*outof >> 24) & 0xffL;
  *into++ = (*outof >> 16) & 0xffL;
  *into++ = (*outof >> 8) & 0xffL;
  *into++ = *outof++ & 0xffL;
  *into++ = (*outof >> 24) & 0xffL;
  *into++ = (*outof >> 16) & 0xffL;
  *into++ = (*outof >> 8) & 0xffL;
  *into++ = *outof & 0xffL;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unscrun>:
  endbr64
  mov    (%rdi),%rax
  shr    $0x18,%rax
  mov    %al,(%rsi)
  mov    (%rdi),%rax
  shr    $0x10,%rax
  mov    %al,0x1(%rsi)
  mov    (%rdi),%rax
  movzbl %ah,%eax
  mov    %al,0x2(%rsi)
  mov    (%rdi),%rax
  mov    %al,0x3(%rsi)
  mov    0x8(%rdi),%rax
  shr    $0x18,%rax
  mov    %al,0x4(%rsi)
  mov    0x8(%rdi),%rax
  shr    $0x10,%rax
  mov    %al,0x5(%rsi)
  mov    0x8(%rdi),%rax
  movzbl %ah,%eax
  mov    %al,0x6(%rsi)
  mov    0x8(%rdi),%rax
  mov    %al,0x7(%rsi)
  ret
```

assistant: ```c
void unscrun(register unsigned long *outof, register unsigned char *into) {
  *into++ = (*outof >> 24) & 0xffL;
  *into++ = (*outof >> 16) & 0xffL;
  *into++ = (*outof >> 8) & 0xffL;
  *into++ = *outof++ & 0xffL;
  *into++ = (*outof >> 24) & 0xffL;
  *into++ = (*outof >> 16) & 0xffL;
  *into++ = (*outof >> 8) & 0xffL;
  *into++ = *outof & 0xffL;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unscrun>:
  endbr64
  mov    (%rdi),%rax
  shr    $0x18,%rax
  mov    %al,(%rsi)
  mov    (%rdi),%rax
  shr    $0x10,%rax
  mov    %al,0x1(%rsi)
  mov    (%rdi),%rax
  mov    %ah,0x2(%rsi)
  mov    (%rdi),%rax
  mov    %al,0x3(%rsi)
  mov    0x8(%rdi),%rax
  shr    $0x18,%rax
  mov    %al,0x4(%rsi)
  mov    0x8(%rdi),%rax
  shr    $0x10,%rax
  mov    %al,0x5(%rsi)
  mov    0x8(%rdi),%rax
  mov    %ah,0x6(%rsi)
  mov    0x8(%rdi),%rax
  mov    %al,0x7(%rsi)
  ret
```

assistant: ```c
void unscrun(register unsigned long *outof, register unsigned char *into) {
  *into++ = (*outof >> 24) & 0xffL;
  *into++ = (*outof >> 16) & 0xffL;
  *into++ = (*outof >> 8) & 0xffL;
  *into++ = *outof++ & 0xffL;
  *into++ = (*outof >> 24) & 0xffL;
  *into++ = (*outof >> 16) & 0xffL;
  *into++ = (*outof >> 8) & 0xffL;
  *into++ = *outof & 0xffL;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unscrun>:
  endbr64
  mov    (%rdi),%rax
  shr    $0x18,%rax
  mov    %al,(%rsi)
  mov    (%rdi),%rax
  shr    $0x10,%rax
  mov    %al,0x1(%rsi)
  mov    (%rdi),%rax
  mov    %ah,0x2(%rsi)
  mov    (%rdi),%rax
  mov    %al,0x3(%rsi)
  mov    0x8(%rdi),%rax
  shr    $0x18,%rax
  mov    %al,0x4(%rsi)
  mov    0x8(%rdi),%rax
  shr    $0x10,%rax
  mov    %al,0x5(%rsi)
  mov    0x8(%rdi),%rax
  mov    %ah,0x6(%rsi)
  mov    0x8(%rdi),%rax
  mov    %al,0x7(%rsi)
  ret
```

assistant: ```c
void unscrun(register unsigned long *outof, register unsigned char *into) {
  *into++ = (*outof >> 24) & 0xffL;
  *into++ = (*outof >> 16) & 0xffL;
  *into++ = (*outof >> 8) & 0xffL;
  *into++ = *outof++ & 0xffL;
  *into++ = (*outof >> 24) & 0xffL;
  *into++ = (*outof >> 16) & 0xffL;
  *into++ = (*outof >> 8) & 0xffL;
  *into++ = *outof & 0xffL;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: A .c is used to end a C program filename.


assistant: ```c
int main(void) {
  printf("A .c is used to end a C program filename.\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: A .c is used to end a C program filename.


assistant: ```c
int main(void) {
  printf("A .c is used to end a C program filename.\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: A .c is used to end a C program filename.


assistant: ```c
int main(void) {
  printf("A .c is used to end a C program filename.\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: A .c is used to end a C program filename.


assistant: ```c
int main(void) {
  printf("A .c is used to end a C program filename.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bsearch_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int bsearch_strcmp(const void *v1, const void *v2) {
  const char *s1 = *(const char **)v1;
  const char *s2 = *(const char **)v2;
  return strcmp(s1, s2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bsearch_strcmp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bsearch_strcmp(const void *v1, const void *v2) {
  const char *s1 = *(const char **)v1;
  const char *s2 = *(const char **)v2;
  return strcmp(s1, s2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bsearch_strcmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int bsearch_strcmp(const void *v1, const void *v2) {
  const char *s1 = *(const char **)v1;
  const char *s2 = *(const char **)v2;
  return strcmp(s1, s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bsearch_strcmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int bsearch_strcmp(const void *v1, const void *v2) {
  const char *s1 = *(const char **)v1;
  const char *s2 = *(const char **)v2;
  return strcmp(s1, s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Q_CleanStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L81:
  cmpq   $0x0,-0x8(%rbp)
  je     L88
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  jne    L88
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L88
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  je     L88
  addq   $0x1,-0x8(%rbp)
  jmp    L89
L88:
  cmpl   $0x1f,-0x14(%rbp)
  jle    L89
  cmpl   $0x7e,-0x14(%rbp)
  jg     L89
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
L89:
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L81
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *Q_CleanStr(char *string) {
  char *d = string;
  char *s = string;
  int c;
  while ((c = *s) != 0) {
    if ((s && *(s) == '^' && *((s) + 1) && *((s) + 1) != '^')) {
      s++;
    } else if (c >= 0x20 && c <= 0x7E) {
      *d++ = c;
    }
    s++;
  }
  *d = '\0';
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Q_CleanStr>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L60
  mov    %rdi,%rsi
  mov    %rdi,%r9
  jmp    L26
L70:
  lea    0x1(%rsi),%rcx
  jmp    L10
L28:
  movsbl %dl,%r8d
  sub    $0x20,%r8d
  mov    %rsi,%rcx
  cmp    $0x5e,%r8d
  jbe    L58
L10:
  lea    0x1(%rcx),%rsi
  movzbl 0x1(%rcx),%edx
  test   %dl,%dl
  je     L88
L26:
  cmp    $0x5e,%dl
  jne    L28
  test   %rsi,%rsi
  je     L28
  movzbl 0x1(%rsi),%ecx
  cmp    $0x5e,%cl
  je     L58
  test   %cl,%cl
  jne    L70
L58:
  mov    %dl,(%r9)
  mov    %rsi,%rcx
  lea    0x1(%r9),%r9
  jmp    L10
L60:
  mov    %rdi,%r9
L88:
  movb   $0x0,(%r9)
  ret
```

assistant: ```c
char *Q_CleanStr(char *string) {
  char *d = string;
  char *s = string;
  int c;
  while ((c = *s) != 0) {
    if ((s && *(s) == '^' && *((s) + 1) && *((s) + 1) != '^')) {
      s++;
    } else if (c >= 0x20 && c <= 0x7E) {
      *d++ = c;
    }
    s++;
  }
  *d = '\0';
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Q_CleanStr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L33
  mov    %rdi,%rsi
  mov    %rdi,%r9
  jmp    L47
  cs nopw 0x0(%rax,%rax,1)
L71:
  movsbl %dl,%r8d
  mov    %rsi,%rcx
  sub    $0x20,%r8d
  cmp    $0x5e,%r8d
  jbe    L54
L77:
  movzbl 0x1(%rcx),%edx
  lea    0x1(%rcx),%rsi
  test   %dl,%dl
  je     L60
L47:
  cmp    $0x5e,%dl
  jne    L71
  movzbl 0x1(%rsi),%ecx
  cmp    $0x5e,%cl
  je     L54
  test   %cl,%cl
  je     L54
  movzbl 0x2(%rsi),%edx
  lea    0x1(%rsi),%rcx
  lea    0x1(%rcx),%rsi
  test   %dl,%dl
  jne    L47
L60:
  movb   $0x0,(%r9)
  ret
  nopl   0x0(%rax)
L54:
  mov    %dl,(%r9)
  mov    %rsi,%rcx
  add    $0x1,%r9
  jmp    L77
  nopl   0x0(%rax)
L33:
  mov    %rdi,%r9
  movb   $0x0,(%r9)
  ret
```

assistant: ```c
char *Q_CleanStr(char *string) {
  char *d = string;
  char *s = string;
  int c;
  while ((c = *s) != 0) {
    if ((s && *(s) == '^' && *((s) + 1) && *((s) + 1) != '^')) {
      s++;
    } else if (c >= 0x20 && c <= 0x7E) {
      *d++ = c;
    }
    s++;
  }
  *d = '\0';
  return string;
}
```