ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<dyn_lock_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <d0_lockmutex@plt>
  jmp    L14
L7:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <d0_unlockmutex@plt>
L14:
  nop
  leave
  ret
```

assistant: ```c
void dyn_lock_function(int mode, struct CRYPTO_dynlock_value *l, const char *file, int line) {
  void *m = (void *)l;
  if (mode & CRYPTO_LOCK)
    d0_lockmutex(m);
  else
    d0_unlockmutex(m);
}
```
user: What is the c source code of the assembly code below?

```asm
<dyn_lock_function>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %rsi,%rdi
  mov    D3(%rip),%rdx
  and    (%rdx),%eax
  je     L16
  call   <d0_lockmutex@plt>
L15:
  add    $0x8,%rsp
  ret
L16:
  call   <d0_unlockmutex@plt>
  jmp    L15
```

assistant: ```c
void dyn_lock_function(int mode, struct CRYPTO_dynlock_value *l, const char *file, int line) {
  void *m = (void *)l;
  if (mode & CRYPTO_LOCK)
    d0_lockmutex(m);
  else
    d0_unlockmutex(m);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dyn_lock_function>:
  endbr64
  mov    D1(%rip),%rax
  mov    %edi,%r8d
  mov    %rsi,%rdi
  and    (%rax),%r8d
  je     L0
  jmp    1060 <d0_lockmutex@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  jmp    1070 <d0_unlockmutex@plt>
```

assistant: ```c
void dyn_lock_function(int mode, struct CRYPTO_dynlock_value *l, const char *file, int line) {
  void *m = (void *)l;
  if (mode & CRYPTO_LOCK)
    d0_lockmutex(m);
  else
    d0_unlockmutex(m);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dyn_lock_function>:
  endbr64
  mov    D1(%rip),%rax
  mov    %edi,%r8d
  mov    %rsi,%rdi
  and    (%rax),%r8d
  je     L4
  jmp    1060 <d0_lockmutex@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  jmp    1070 <d0_unlockmutex@plt>
```

assistant: ```c
void dyn_lock_function(int mode, struct CRYPTO_dynlock_value *l, const char *file, int line) {
  void *m = (void *)l;
  if (mode & CRYPTO_LOCK)
    d0_lockmutex(m);
  else
    d0_unlockmutex(m);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L11
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L45
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L54
L45:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    $0xffffffff,%eax
  jmp    L54
L2:
  mov    $0x0,%eax
L54:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1) {
    if (*s1 != *s2)
      return *s1 - *s2;
    s1++;
    s2++;
  }
  if (*s2)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
L8:
  movzbl (%rsi),%edx
  cmp    %al,%dl
  jne    L18
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L8
L24:
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
L18:
  movsbl %al,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1) {
    if (*s1 != *s2)
      return *s1 - *s2;
    s1++;
    s2++;
  }
  if (*s2)
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcmp>:
  endbr64
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L3:
  movsbl (%rsi),%edx
  cmp    %al,%dl
  jne    L29
  add    $0x1,%rdi
  add    $0x1,%rsi
L5:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L3
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
  xchg   %ax,%ax
L29:
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1) {
    if (*s1 != *s2)
      return *s1 - *s2;
    s1++;
    s2++;
  }
  if (*s2)
    return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L21:
  movsbl (%rsi),%edx
  cmp    %al,%dl
  jne    L9
  add    $0x1,%rdi
  add    $0x1,%rsi
L8:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L21
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
  xchg   %ax,%ax
L9:
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1) {
    if (*s1 != *s2)
      return *s1 - *s2;
    s1++;
    s2++;
  }
  if (*s2)
    return -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_it_faggot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <random_int@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  cmp    %edx,-0x4(%rbp)
  jle    L18
  mov    $0x1,%eax
  jmp    L11
L18:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int do_it_faggot(int p) {
  if (random_int() % 100 < p) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_it_faggot>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <random_int@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  cmp    %ebx,%eax
  setl   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int do_it_faggot(int p) {
  if (random_int() % 100 < p) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_it_faggot>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <random_int@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  cmp    %ebx,%eax
  pop    %rbx
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int do_it_faggot(int p) {
  if (random_int() % 100 < p) {
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_it_faggot>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <random_int@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  cmp    %ebx,%eax
  pop    %rbx
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int do_it_faggot(int p) {
  if (random_int() % 100 < p) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uq_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L18
  mov    $0xffffffff,%eax
  jmp    L16
L18:
  mov    -0x24(%rbp),%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L7
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L20:
  cmpq   $0x0,-0x20(%rbp)
  je     L69
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L69:
  mov    $0x1,%eax
  jmp    L16
L7:
  mov    -0x24(%rbp),%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L55
  cmpq   $0x0,-0x18(%rbp)
  je     L89
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L89:
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <getyesno@plt>
  jmp    L16
L55:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
L16:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: ?Internal error: uq_ok()

assistant: ```c
int uq_ok(char *preface, char *prompt, int mask, char **help, int dflt) {
  int rc, len;
  char *text = 0L;
  if (!prompt)
    return (-1);
  if ((mask & 3) == 1) {
    {
      if (preface)
        printf("%s\n", preface);
      if (prompt)
        printf("%s\n", prompt);
      return (1);
    }
  } else if ((mask & 3) == 3) {
    {
      if (preface)
        printf("%s\n", preface);
      return (getyesno(prompt, 0));
    }
  } else {
    printf("?Internal error: uq_ok()\n");
    return (-1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uq_ok>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L14
  mov    %rsi,%rbp
  mov    %edx,%ebx
  and    $0x3,%ebx
  cmp    $0x1,%ebx
  je     L25
  cmp    $0x3,%ebx
  jne    L65
  test   %rdi,%rdi
  je     L31
  call   <puts@plt>
L31:
  mov    $0x0,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <getyesno@plt>
  mov    %eax,%ebx
L60:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  test   %rdi,%rdi
  je     L3
  call   <puts@plt>
L3:
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L60
L65:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%ebx
  jmp    L60
L14:
  mov    $0xffffffff,%ebx
  jmp    L60
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: ?Internal error: uq_ok()

assistant: ```c
int uq_ok(char *preface, char *prompt, int mask, char **help, int dflt) {
  int rc, len;
  char *text = 0L;
  if (!prompt)
    return (-1);
  if ((mask & 3) == 1) {
    {
      if (preface)
        printf("%s\n", preface);
      if (prompt)
        printf("%s\n", prompt);
      return (1);
    }
  } else if ((mask & 3) == 3) {
    {
      if (preface)
        printf("%s\n", preface);
      return (getyesno(prompt, 0));
    }
  } else {
    printf("?Internal error: uq_ok()\n");
    return (-1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uq_ok>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L45
  and    $0x3,%edx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  cmp    $0x1,%edx
  je     L5
  cmp    $0x3,%edx
  jne    L1
  test   %rdi,%rdi
  je     L62
  call   <puts@plt>
L62:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <getyesno@plt>
L5:
  test   %rdi,%rdi
  je     L21
  call   <puts@plt>
L21:
  mov    %rbp,%rdi
  call   <puts@plt>
L32:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L1:
  lea    D5(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
  jmp    L32
L45:
  mov    $0xffffffff,%r12d
  jmp    L32
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string

tool: D5: ?Internal error: uq_ok()

assistant: ```c
int uq_ok(char *preface, char *prompt, int mask, char **help, int dflt) {
  int rc, len;
  char *text = 0L;
  if (!prompt)
    return (-1);
  if ((mask & 3) == 1) {
    {
      if (preface)
        printf("%s\n", preface);
      if (prompt)
        printf("%s\n", prompt);
      return (1);
    }
  } else if ((mask & 3) == 3) {
    {
      if (preface)
        printf("%s\n", preface);
      return (getyesno(prompt, 0));
    }
  } else {
    printf("?Internal error: uq_ok()\n");
    return (-1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uq_ok>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L59
  and    $0x3,%edx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  cmp    $0x1,%edx
  je     L40
  cmp    $0x3,%edx
  jne    L3
  test   %rdi,%rdi
  je     L44
  call   <puts@plt>
L44:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <getyesno@plt>
L40:
  test   %rdi,%rdi
  je     L20
  call   <puts@plt>
L20:
  mov    %rbp,%rdi
  call   <puts@plt>
L54:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L3:
  lea    D3(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
  jmp    L54
L59:
  mov    $0xffffffff,%r12d
  jmp    L54
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: ?Internal error: uq_ok()

assistant: ```c
int uq_ok(char *preface, char *prompt, int mask, char **help, int dflt) {
  int rc, len;
  char *text = 0L;
  if (!prompt)
    return (-1);
  if ((mask & 3) == 1) {
    {
      if (preface)
        printf("%s\n", preface);
      if (prompt)
        printf("%s\n", prompt);
      return (1);
    }
  } else if ((mask & 3) == 3) {
    {
      if (preface)
        printf("%s\n", preface);
      return (getyesno(prompt, 0));
    }
  } else {
    printf("?Internal error: uq_ok()\n");
    return (-1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_uri_scheme>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D39(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x6,-0x48(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L11
L1:
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,8),%rcx
  mov    -0x44(%rbp),%edx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x44(%rbp),%eax
  jmp    L0
L3:
  addl   $0x1,-0x4c(%rbp)
L11:
  mov    -0x4c(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L1
  mov    $0x0,%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D37
type: string
name: parse_data
arguments: data_tag: D0
type: string
name: parse_data
arguments: data_tag: D39
type: string
name: parse_data
arguments: data_tag: D12
type: string
name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D1
type: string

tool: D37: http:

tool: D0: https:

tool: D39: file:

tool: D12: ftp:

tool: D2: git:

tool: D1: gopher:

assistant: ```c
int is_uri_scheme(char *p) {
  char *scheme[] = {"http:", "https:", "file:", "ftp:", "git:", "gopher:"};
  int i, len, nschemes = sizeof(scheme) / sizeof(scheme[0]);
  for (i = 0; i < nschemes; ++i) {
    len = strlen(scheme[i]);
    if (!strncmp(p, scheme[i], len))
      return len;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_uri_scheme>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,(%rsp)
  lea    D34(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D51(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D29(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D52(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D24(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    %rsp,%rbp
  lea    0x30(%rsp),%r14
L26:
  mov    0x0(%rbp),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L29
  add    $0x8,%rbp
  cmp    %r14,%rbp
  jne    L26
  mov    $0x0,%ebx
L29:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    %ebx,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D38
data_type: string
name: retrieve_data
arguments: data_label: D34
data_type: string
name: retrieve_data
arguments: data_label: D51
data_type: string
name: retrieve_data
arguments: data_label: D29
data_type: string
name: retrieve_data
arguments: data_label: D52
data_type: string
name: retrieve_data
arguments: data_label: D24
data_type: string

tool: D38: http:

tool: D34: https:

tool: D51: file:

tool: D29: ftp:

tool: D52: git:

tool: D24: gopher:

assistant: ```c
int is_uri_scheme(char *p) {
  char *scheme[] = {"http:", "https:", "file:", "ftp:", "git:", "gopher:"};
  int i, len, nschemes = sizeof(scheme) / sizeof(scheme[0]);
  for (i = 0; i < nschemes; ++i) {
    len = strlen(scheme[i]);
    if (!strncmp(p, scheme[i], len))
      return len;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_uri_scheme>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    D58(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  lea    D54(%rip),%rax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%r14
  mov    %rax,0x8(%rsp)
  lea    D41(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D5(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D14(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D17(%rip),%rax
  mov    %rax,0x28(%rsp)
L27:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%edx
  mov    %eax,%r12d
  call   <strncmp@plt>
  test   %eax,%eax
  je     L25
  add    $0x8,%rbx
  cmp    %r14,%rbx
  je     L13
  mov    (%rbx),%rbp
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %r12d,%r12d
L25:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x40,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D58
type_guessed: string
name: disassemble_data
arguments: data_tag: D54
type_guessed: string
name: disassemble_data
arguments: data_tag: D41
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D17
type_guessed: string

tool: D58: http:

tool: D54: https:

tool: D41: file:

tool: D5: ftp:

tool: D14: git:

tool: D17: gopher:

assistant: ```c
int is_uri_scheme(char *p) {
  char *scheme[] = {"http:", "https:", "file:", "ftp:", "git:", "gopher:"};
  int i, len, nschemes = sizeof(scheme) / sizeof(scheme[0]);
  for (i = 0; i < nschemes; ++i) {
    len = strlen(scheme[i]);
    if (!strncmp(p, scheme[i], len))
      return len;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_uri_scheme>:
  endbr64
  push   %r14
  lea    D1(%rip),%rcx
  push   %r13
  movq   %rcx,%xmm0
  lea    D20(%rip),%rcx
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  lea    D44(%rip),%rax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%r14
  movq   %rax,%xmm1
  lea    D45(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  lea    D12(%rip),%rax
  movaps %xmm0,(%rsp)
  movq   %rcx,%xmm0
  lea    D3(%rip),%rcx
  movq   %rax,%xmm3
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
  movq   %rcx,%xmm0
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,0x20(%rsp)
L15:
  mov    (%rbx),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%edx
  mov    %eax,%r12d
  call   <strncmp@plt>
  test   %eax,%eax
  je     L28
  add    $0x8,%rbx
  cmp    %rbx,%r14
  jne    L15
  xor    %r12d,%r12d
L28:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x40,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string
name: extract_symbolic_data
arguments: data_label: D20
data_type: string
name: extract_symbolic_data
arguments: data_label: D44
data_type: string
name: extract_symbolic_data
arguments: data_label: D45
data_type: string
name: extract_symbolic_data
arguments: data_label: D12
data_type: string
name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D1: http:

tool: D20: file:

tool: D44: https:

tool: D45: ftp:

tool: D12: gopher:

tool: D3: git:

assistant: ```c
int is_uri_scheme(char *p) {
  char *scheme[] = {"http:", "https:", "file:", "ftp:", "git:", "gopher:"};
  int i, len, nschemes = sizeof(scheme) / sizeof(scheme[0]);
  for (i = 0; i < nschemes; ++i) {
    len = strlen(scheme[i]);
    if (!strncmp(p, scheme[i], len))
      return len;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_bitlen_rsa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x0,%ecx
  mov    $0x0,%esi
  call   <RSA_get0_key@plt>
  mov    (%rsp),%rdi
  call   <BN_num_bits@plt>
  cmp    $0x20,%eax
  jle    L4
L34:
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <PEMerr@plt>
  mov    $0x0,%r12d
L9:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    %r12d,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    %rbx,%rdi
  call   <RSA_bits@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <RSA_size@plt>
  mov    %eax,%r14d
  test   %ebp,%ebp
  je     L41
  movl   $0x31415352,0x0(%r13)
  jmp    L9
L41:
  movl   $0x32415352,0x0(%r13)
  lea    0x8(%rsp),%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <RSA_get0_key@plt>
  mov    0x8(%rsp),%rdi
  call   <BN_num_bytes@plt>
  cmp    %r14d,%eax
  jg     L34
  lea    0xf(%r12),%ebp
  sar    $0x4,%ebp
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <RSA_get0_factors@plt>
  lea    0x20(%rsp),%rcx
  lea    0x30(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  mov    %rbx,%rdi
  call   <RSA_get0_crt_params@plt>
  mov    0x20(%rsp),%rdi
  call   <BN_num_bytes@plt>
  cmp    %ebp,%eax
  jg     L34
  mov    0x10(%rsp),%rdi
  call   <BN_num_bytes@plt>
  cmp    %ebp,%eax
  jg     L34
  mov    0x18(%rsp),%rdi
  call   <BN_num_bytes@plt>
  cmp    %ebp,%eax
  jg     L34
  mov    0x28(%rsp),%rdi
  call   <BN_num_bytes@plt>
  cmp    %ebp,%eax
  jg     L34
  mov    0x30(%rsp),%rdi
  call   <BN_num_bytes@plt>
  cmp    %ebp,%eax
  jle    L9
  jmp    L34
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_bitlen_rsa(RSA *rsa, int ispub, unsigned int *pmagic) {
  int nbyte, hnbyte, bitlen;
  const BIGNUM *e;
  RSA_get0_key(rsa, NULL, &e, NULL);
  if (BN_num_bits(e) > 32)
    goto badkey;
  bitlen = RSA_bits(rsa);
  nbyte = RSA_size(rsa);
  hnbyte = (bitlen + 15) >> 4;
  if (ispub) {
    *pmagic = 0x31415352L;
    return bitlen;
  } else {
    const BIGNUM *d, *p, *q, *iqmp, *dmp1, *dmq1;
    *pmagic = 0x32415352L;
    RSA_get0_key(rsa, NULL, NULL, &d);
    if (BN_num_bytes(d) > nbyte)
      goto badkey;
    RSA_get0_factors(rsa, &p, &q);
    RSA_get0_crt_params(rsa, &dmp1, &dmq1, &iqmp);
    if ((BN_num_bytes(iqmp) > hnbyte) || (BN_num_bytes(p) > hnbyte) || (BN_num_bytes(q) > hnbyte) || (BN_num_bytes(dmp1) > hnbyte) || (BN_num_bytes(dmq1) > hnbyte))
      goto badkey;
  }
  return bitlen;
badkey:
  PEMerr(PEM_F_CHECK_BITLEN_RSA, PEM_R_UNSUPPORTED_KEY_COMPONENTS);
  return 0;
}
```