ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<momrand_main_mt19937ar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x123,(%rsp)
  movq   $0x234,0x8(%rsp)
  movq   $0x345,0x10(%rsp)
  movq   $0x456,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0x4,%esi
  call   <momrand_init_by_array@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <momrand_genrand_int32@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L18:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L12
  mov    $0x0,%eax
  call   <momrand_genrand_int32@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    $0x4,%eax
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L18
L12:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <momrand_genrand_real2@plt>
  lea    D40(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D40(%rip),%rbp
L16:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L0
  mov    $0x0,%eax
  call   <momrand_genrand_real2@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    $0x4,%eax
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L16
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D5
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D40
type_guessed: string

tool: D6: 1000 outputs of genrand_int32()

tool: D5: %10lu 

tool: D3: 
1000 outputs of genrand_real2()

tool: D40: %10.8f 

assistant: ```c
int momrand_main_mt19937ar(void) {
  int i;
  unsigned long init[4] = {0x123, 0x234, 0x345, 0x456}, length = 4;
  momrand_init_by_array(init, length);
  printf("1000 outputs of genrand_int32()\n");
  for (i = 0; i < 1000; i++) {
    printf("%10lu ", momrand_genrand_int32());
    if (i % 5 == 4)
      printf("\n");
  }
  printf("\n1000 outputs of genrand_real2()\n");
  for (i = 0; i < 1000; i++) {
    printf("%10.8f ", momrand_genrand_real2());
    if (i % 5 == 4)
      printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<momrand_main_mt19937ar>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  lea    D17(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x123,(%rsp)
  movq   $0x234,0x8(%rsp)
  movq   $0x345,0x10(%rsp)
  movq   $0x456,0x18(%rsp)
  call   <momrand_init_by_array@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <momrand_genrand_int32@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L37
L2:
  xor    %eax,%eax
  call   <momrand_genrand_int32@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  sub    $0x33333334,%eax
  cmp    $0x33333332,%eax
  ja     L36
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x3e8,%ebx
  jne    L2
L37:
  lea    D3(%rip),%rdi
  lea    D19(%rip),%rbp
  xor    %ebx,%ebx
  call   <puts@plt>
  xor    %eax,%eax
  call   <momrand_genrand_real2@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L43
L12:
  xor    %eax,%eax
  call   <momrand_genrand_real2@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  sub    $0x33333334,%eax
  cmp    $0x33333332,%eax
  ja     L22
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x3e8,%ebx
  jne    L12
L43:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D3
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string

tool: D17: %10lu 

tool: D16: 1000 outputs of genrand_int32()

tool: D3: 
1000 outputs of genrand_real2()

tool: D19: %10.8f 

assistant: ```c
int momrand_main_mt19937ar(void) {
  int i;
  unsigned long init[4] = {0x123, 0x234, 0x345, 0x456}, length = 4;
  momrand_init_by_array(init, length);
  printf("1000 outputs of genrand_int32()\n");
  for (i = 0; i < 1000; i++) {
    printf("%10lu ", momrand_genrand_int32());
    if (i % 5 == 4)
      printf("\n");
  }
  printf("\n1000 outputs of genrand_real2()\n");
  for (i = 0; i < 1000; i++) {
    printf("%10.8f ", momrand_genrand_real2());
    if (i % 5 == 4)
      printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<momrand_main_mt19937ar>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  lea    D22(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x38,%rsp
  movdqa D58(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D16(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <momrand_init_by_array@plt>
  lea    D48(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <momrand_genrand_int32@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
  nopl   (%rax)
L36:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L37
L0:
  xor    %eax,%eax
  call   <momrand_genrand_int32@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  sub    $0x33333334,%eax
  cmp    $0x33333332,%eax
  ja     L36
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x3e8,%ebx
  jne    L0
L37:
  lea    D1(%rip),%rdi
  lea    D18(%rip),%rbp
  mov    $0x1,%ebx
  call   <puts@plt>
  xor    %eax,%eax
  call   <momrand_genrand_real2@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L21
L16:
  xor    %eax,%eax
  call   <momrand_genrand_real2@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  sub    $0x33333334,%eax
  cmp    $0x33333332,%eax
  ja     L73
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x3e8,%ebx
  jne    L16
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: tag: D58
type_guessed: byte[16]
name: extract_symbolic_data
arguments: tag: D16
type_guessed: byte[16]
name: extract_symbolic_data
arguments: tag: D48
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D18
type_guessed: string

tool: D22: %10lu 

tool: {"D58": [0x23,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x02,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x45,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x56,0x04,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D48: 1000 outputs of genrand_int32()

tool: D1: 
1000 outputs of genrand_real2()

tool: D18: %10.8f 

assistant: ```c
int momrand_main_mt19937ar(void) {
  int i;
  unsigned long init[4] = {0x123, 0x234, 0x345, 0x456}, length = 4;
  momrand_init_by_array(init, length);
  printf("1000 outputs of genrand_int32()\n");
  for (i = 0; i < 1000; i++) {
    printf("%10lu ", momrand_genrand_int32());
    if (i % 5 == 4)
      printf("\n");
  }
  printf("\n1000 outputs of genrand_real2()\n");
  for (i = 0; i < 1000; i++) {
    printf("%10.8f ", momrand_genrand_real2());
    if (i % 5 == 4)
      printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<error_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L2
  mov    $0x1,%eax
  jmp    L36
L2:
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L11
  mov    $0x1,%eax
  jmp    L36
L11:
  mov    $0x0,%eax
L36:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string

tool: D9: control reaches end of non-void function

tool: D10: suggest parentheses around assignment used as truth value

assistant: ```c
int error_line(char *line) {
  if (strstr(line, "control reaches end of non-void function")) {
    return 1;
  } else if (strstr(line, "suggest parentheses around assignment used as truth value")) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<error_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D15(%rip),%rsi
  call   <strstr@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L8
L6:
  pop    %rbx
  ret
L8:
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D15
type: string
name: read_data
arguments: data_label: D7
type: string

tool: D15: control reaches end of non-void function

tool: D7: suggest parentheses around assignment used as truth value

assistant: ```c
int error_line(char *line) {
  if (strstr(line, "control reaches end of non-void function")) {
    return 1;
  } else if (strstr(line, "suggest parentheses around assignment used as truth value")) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error_line>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rsi
  mov    %rdi,%rbp
  call   <strstr@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L3
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  lea    D19(%rip),%rsi
  call   <strstr@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D1: control reaches end of non-void function

tool: D19: suggest parentheses around assignment used as truth value

assistant: ```c
int error_line(char *line) {
  if (strstr(line, "control reaches end of non-void function")) {
    return 1;
  } else if (strstr(line, "suggest parentheses around assignment used as truth value")) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<error_line>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rsi
  mov    %rdi,%rbp
  call   <strstr@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L8
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  call   <strstr@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type: string
name: parse_data
arguments: tag: D4
type: string

tool: D15: control reaches end of non-void function

tool: D4: suggest parentheses around assignment used as truth value

assistant: ```c
int error_line(char *line) {
  if (strstr(line, "control reaches end of non-void function")) {
    return 1;
  } else if (strstr(line, "suggest parentheses around assignment used as truth value")) {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ccu_clk_uldiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L27
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  jmp    L5
L27:
  shll   -0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L27
L5:
  pop    %rbp
  ret
```

assistant: ```c
__u64 ccu_clk_uldiv(__u64 dividend, __u32 divisior) {
  __u64 tmpDiv = (__u64)divisior;
  __u64 tmpQuot = 0;
  __s32 shift = 0;
  if (!divisior) {
    return (__u32)dividend / divisior;
  }
  while (!(tmpDiv & ((__u64)1 << 63))) {
    tmpDiv <<= 1;
    shift++;
  }
  do {
    if (dividend >= tmpDiv) {
      dividend -= tmpDiv;
      tmpQuot = (tmpQuot << 1) | 1;
    } else {
      tmpQuot = (tmpQuot << 1) | 0;
    }
    tmpDiv >>= 1;
    shift--;
  } while (shift >= 0);
  return tmpQuot;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ccu_clk_uldiv>:
  endbr64
  test   %esi,%esi
  je     L7
L10:
  jmp    L10
L7:
  mov    $0x0,%ecx
  mov    %edi,%eax
  cltd
  idiv   %ecx
  ret
```

assistant: ```c
__u64 ccu_clk_uldiv(__u64 dividend, __u32 divisior) {
  __u64 tmpDiv = (__u64)divisior;
  __u64 tmpQuot = 0;
  __s32 shift = 0;
  if (!divisior) {
    return (__u32)dividend / divisior;
  }
  while (!(tmpDiv & ((__u64)1 << 63))) {
    tmpDiv <<= 1;
    shift++;
  }
  do {
    if (dividend >= tmpDiv) {
      dividend -= tmpDiv;
      tmpQuot = (tmpQuot << 1) | 1;
    } else {
      tmpQuot = (tmpQuot << 1) | 0;
    }
    tmpDiv >>= 1;
    shift--;
  } while (shift >= 0);
  return tmpQuot;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ccu_clk_uldiv>:
  endbr64
  test   %esi,%esi
  je     L15
L4:
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L15:
  ud2
```

assistant: ```c
__u64 ccu_clk_uldiv(__u64 dividend, __u32 divisior) {
  __u64 tmpDiv = (__u64)divisior;
  __u64 tmpQuot = 0;
  __s32 shift = 0;
  if (!divisior) {
    return (__u32)dividend / divisior;
  }
  while (!(tmpDiv & ((__u64)1 << 63))) {
    tmpDiv <<= 1;
    shift++;
  }
  do {
    if (dividend >= tmpDiv) {
      dividend -= tmpDiv;
      tmpQuot = (tmpQuot << 1) | 1;
    } else {
      tmpQuot = (tmpQuot << 1) | 0;
    }
    tmpDiv >>= 1;
    shift--;
  } while (shift >= 0);
  return tmpQuot;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ccu_clk_uldiv>:
  endbr64
  test   %esi,%esi
  je     L15
L12:
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L15:
  ud2
```

assistant: ```c
__u64 ccu_clk_uldiv(__u64 dividend, __u32 divisior) {
  __u64 tmpDiv = (__u64)divisior;
  __u64 tmpQuot = 0;
  __s32 shift = 0;
  if (!divisior) {
    return (__u32)dividend / divisior;
  }
  while (!(tmpDiv & ((__u64)1 << 63))) {
    tmpDiv <<= 1;
    shift++;
  }
  do {
    if (dividend >= tmpDiv) {
      dividend -= tmpDiv;
      tmpQuot = (tmpQuot << 1) | 1;
    } else {
      tmpQuot = (tmpQuot << 1) | 0;
    }
    tmpDiv >>= 1;
    shift--;
  } while (shift >= 0);
  return tmpQuot;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L11
  movq   $0x0,-0x20(%rbp)
  jmp    L2
L16:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x20(%rbp)
L2:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L16
  jmp    L5
L11:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L27
L1:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subq   $0x1,-0x18(%rbp)
L27:
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
L5:
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memmove(void *dstptr, const void *srcptr, size_t size) {
  unsigned char *dst = (unsigned char *)dstptr;
  const unsigned char *src = (const unsigned char *)srcptr;
  if (dst < src)
    for (size_t i = 0; i < size; i++) {
      dst[i] = src[i];
    }
  else
    for (size_t i = size; i != 0; i--) {
      dst[i - 1] = src[i - 1];
    }
  return dstptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jb     L39
  test   %rdx,%rdx
  je     L47
L40:
  sub    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  jne    L40
L0:
  ret
L47:
  ret
L39:
  test   %rdx,%rdx
  je     L0
  mov    $0x0,%ecx
L19:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L19
  ret
```

assistant: ```c
void *memmove(void *dstptr, const void *srcptr, size_t size) {
  unsigned char *dst = (unsigned char *)dstptr;
  const unsigned char *src = (const unsigned char *)srcptr;
  if (dst < src)
    for (size_t i = 0; i < size; i++) {
      dst[i] = src[i];
    }
  else
    for (size_t i = size; i != 0; i--) {
      dst[i - 1] = src[i - 1];
    }
  return dstptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jb     L44
  test   %rdx,%rdx
  je     L20
  nopl   0x0(%rax)
L10:
  sub    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  jne    L10
L4:
  ret
  cs nopw 0x0(%rax,%rax,1)
L44:
  test   %rdx,%rdx
  je     L4
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L17
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  ret
```

assistant: ```c
void *memmove(void *dstptr, const void *srcptr, size_t size) {
  unsigned char *dst = (unsigned char *)dstptr;
  const unsigned char *src = (const unsigned char *)srcptr;
  if (dst < src)
    for (size_t i = 0; i < size; i++) {
      dst[i] = src[i];
    }
  else
    for (size_t i = size; i != 0; i--) {
      dst[i - 1] = src[i - 1];
    }
  return dstptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rax
  cmp    %rsi,%rdi
  jb     L104
  test   %rdx,%rdx
  je     L62
  nopl   0x0(%rax)
L16:
  sub    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  jne    L16
L62:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L104:
  test   %rdx,%rdx
  je     L62
  lea    0x1(%rsi),%rdi
  mov    %r8,%rcx
  lea    -0x1(%rdx),%rdx
  sub    %rdi,%rcx
  cmp    $0xe,%rcx
  jbe    L132
  cmp    $0x6,%rdx
  jbe    L132
  mov    %rax,%rcx
  cmp    $0xe,%rdx
  jbe    L129
  and    $0xfffffffffffffff0,%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L45:
  movdqu (%rsi,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rcx
  jne    L45
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rdx
  test   $0xf,%al
  je     L62
  mov    %rax,%rcx
  sub    %rdx,%rcx
  lea    -0x1(%rcx),%rdi
  cmp    $0x6,%rdi
  jbe    L126
L11:
  mov    (%rsi,%rdx,1),%rdi
  mov    %rdi,(%r8,%rdx,1)
  mov    %rcx,%rdi
  and    $0xfffffffffffffff8,%rdi
  add    %rdi,%rdx
  cmp    %rdi,%rcx
  je     L62
L126:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L62
  movzbl 0x1(%rsi,%rdx,1),%ecx
  mov    %cl,0x1(%r8,%rdx,1)
  lea    0x2(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L62
  movzbl 0x2(%rsi,%rdx,1),%ecx
  mov    %cl,0x2(%r8,%rdx,1)
  lea    0x3(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L62
  movzbl 0x3(%rsi,%rdx,1),%ecx
  mov    %cl,0x3(%r8,%rdx,1)
  lea    0x4(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L62
  movzbl 0x4(%rsi,%rdx,1),%ecx
  mov    %cl,0x4(%r8,%rdx,1)
  lea    0x5(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L62
  movzbl 0x5(%rsi,%rdx,1),%ecx
  mov    %cl,0x5(%r8,%rdx,1)
  lea    0x6(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L62
  movzbl 0x6(%rsi,%rdx,1),%eax
  mov    %al,0x6(%r8,%rdx,1)
  mov    %r8,%rax
  ret
  nop
L132:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L102:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L102
  jmp    L62
L129:
  xor    %edx,%edx
  jmp    L11
```

assistant: ```c
void *memmove(void *dstptr, const void *srcptr, size_t size) {
  unsigned char *dst = (unsigned char *)dstptr;
  const unsigned char *src = (const unsigned char *)srcptr;
  if (dst < src)
    for (size_t i = 0; i < size; i++) {
      dst[i] = src[i];
    }
  else
    for (size_t i = size; i != 0; i--) {
      dst[i - 1] = src[i - 1];
    }
  return dstptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L0
L30:
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L0
  mov    -0x4(%rbp),%eax
  jmp    L37
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L30
  mov    $0x0,%eax
L37:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  (void)argc;
  (void)argv;
  while ((c = getchar()) != EOF) {
    if (c & 0x80)
      return c;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L19:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L11
  test   $0x80,%al
  je     L19
  jmp    L28
L11:
  mov    $0x0,%eax
L28:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  (void)argc;
  (void)argv;
  while ((c = getchar()) != EOF) {
    if (c & 0x80)
      return c;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    D2(%rip),%rbx
  jmp    L5
  xchg   %ax,%ax
L7:
  test   $0x80,%al
  jne    L28
L5:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L7
  xor    %eax,%eax
L28:
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  (void)argc;
  (void)argv;
  while ((c = getchar()) != EOF) {
    if (c & 0x80)
      return c;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    D3(%rip),%rbx
  jmp    L23
  xchg   %ax,%ax
L17:
  test   $0x80,%al
  jne    L15
L23:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L17
  xor    %eax,%eax
L15:
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  (void)argc;
  (void)argv;
  while ((c = getchar()) != EOF) {
    if (c & 0x80)
      return c;
  }
  return 0;
}
```