ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movw   $0x0,-0x10(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L17
L3:
  movl   $0x0,-0x3c(%rbp)
  jmp    L62
L66:
  movl   $0x0,-0x38(%rbp)
  jmp    L32
L43:
  movl   $0x1,-0x34(%rbp)
  jmp    L18
L8:
  lea    -0x30(%rbp),%rdi
  mov    -0x34(%rbp),%ecx
  mov    -0x38(%rbp),%edx
  mov    -0x3c(%rbp),%esi
  mov    -0x40(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <wordExist@plt>
  addl   $0x1,-0x34(%rbp)
L18:
  cmpl   $0x4,-0x34(%rbp)
  jle    L8
  addl   $0x1,-0x38(%rbp)
L32:
  cmpl   $0x7,-0x38(%rbp)
  jle    L43
  addl   $0x1,-0x3c(%rbp)
L62:
  cmpl   $0x3,-0x3c(%rbp)
  jle    L66
  addl   $0x1,-0x40(%rbp)
L17:
  cmpl   $0x3,-0x40(%rbp)
  jle    L3
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: pause

assistant: ```c
int main(void) {
  char word[34] = {'\0'};
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      for (int d = 0; d < 8; d++) {
        for (int n = 1; n <= ((4) > (4) ? (4) : (4)); n++) {
          wordExist(i, j, d, n, word);
        }
      }
    }
  }
  system("pause");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movw   $0x0,0x20(%rsp)
  mov    $0x0,%r13d
  mov    %rsp,%r14
  jmp    L5
L56:
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  je     L66
L75:
  mov    $0x1,%ebx
L8:
  mov    %r14,%r8
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <wordExist@plt>
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L8
  jmp    L56
L66:
  add    $0x1,%r12d
  cmp    $0x4,%r12d
  je     L77
L47:
  mov    $0x0,%ebp
  jmp    L75
L77:
  add    $0x1,%r13d
  cmp    $0x4,%r13d
  je     L89
L5:
  mov    $0x0,%r12d
  jmp    L47
L89:
  lea    D6(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: pause

assistant: ```c
int main(void) {
  char word[34] = {'\0'};
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      for (int d = 0; d < 8; d++) {
        for (int n = 1; n <= ((4) > (4) ? (4) : (4)); n++) {
          wordExist(i, j, d, n, word);
        }
      }
    }
  }
  system("pause");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %rsp,%r14
  mov    %ax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
L35:
  xor    %r12d,%r12d
L9:
  xor    %ebp,%ebp
  nop
L15:
  mov    $0x1,%ebx
L38:
  mov    %ebx,%ecx
  mov    %r14,%r8
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <wordExist@plt>
  cmp    $0x5,%ebx
  jne    L38
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L15
  add    $0x1,%r12d
  cmp    $0x4,%r12d
  jne    L9
  add    $0x1,%r13d
  cmp    $0x4,%r13d
  jne    L35
  lea    D9(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: pause

assistant: ```c
int main(void) {
  char word[34] = {'\0'};
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      for (int d = 0; d < 8; d++) {
        for (int n = 1; n <= ((4) > (4) ? (4) : (4)); n++) {
          wordExist(i, j, d, n, word);
        }
      }
    }
  }
  system("pause");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %rsp,%r14
  mov    %ax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
L41:
  xor    %r12d,%r12d
L3:
  xor    %ebp,%ebp
  nop
L40:
  mov    $0x1,%ebx
L49:
  mov    %ebx,%ecx
  mov    %r14,%r8
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <wordExist@plt>
  cmp    $0x5,%ebx
  jne    L49
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L40
  add    $0x1,%r12d
  cmp    $0x4,%r12d
  jne    L3
  add    $0x1,%r13d
  cmp    $0x4,%r13d
  jne    L41
  lea    D7(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D7: pause

assistant: ```c
int main(void) {
  char word[34] = {'\0'};
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      for (int d = 0; d < 8; d++) {
        for (int n = 1; n <= ((4) > (4) ? (4) : (4)); n++) {
          wordExist(i, j, d, n, word);
        }
      }
    }
  }
  system("pause");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<SzToSt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L16:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
SzToSt(sz, st) char *sz;
char *st;
{
  int cch;
  char *pch;
  pch = st + 1;
  while (*sz)
    *pch++ = *sz++;
  st[0] = pch - st - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SzToSt>:
  endbr64
  lea    0x1(%rsi),%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L2
L14:
  add    $0x1,%rdi
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
L2:
  sub    %rsi,%rax
  sub    $0x1,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
SzToSt(sz, st) char *sz;
char *st;
{
  int cch;
  char *pch;
  pch = st + 1;
  while (*sz)
    *pch++ = *sz++;
  st[0] = pch - st - 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<SzToSt>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L13
  nop
L1:
  add    $0x1,%rdi
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L1
  sub    %rsi,%rdx
  lea    -0x1(%rdx),%eax
L13:
  mov    %al,(%rsi)
  ret
```

assistant: ```c
SzToSt(sz, st) char *sz;
char *st;
{
  int cch;
  char *pch;
  pch = st + 1;
  while (*sz)
    *pch++ = *sz++;
  st[0] = pch - st - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SzToSt>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L8
  nop
L4:
  add    $0x1,%rdi
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L4
  sub    %rsi,%rdx
  lea    -0x1(%rdx),%eax
L8:
  mov    %al,(%rsi)
  ret
```

assistant: ```c
SzToSt(sz, st) char *sz;
char *st;
{
  int cch;
  char *pch;
  pch = st + 1;
  while (*sz)
    *pch++ = *sz++;
  st[0] = pch - st - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<outExpo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  %xmm3,-0x10(%rbp)
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x10(%rbp),%xmm0
  jp     L7
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x10(%rbp),%xmm0
  jne    L7
  movss  -0x8(%rbp),%xmm0
  addss  -0xc(%rbp),%xmm0
  jmp    L18
L7:
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x18(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  D4(%rip),%xmm0
  mulss  %xmm1,%xmm0
  divss  -0x10(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <powf@plt>
  mov    $0x1,%edx
  sub    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: f64
name: parse_data
arguments: label: D4
type_infered: byte[4]

tool: D3: 1.001

tool: {"D4": [0x00,0x00,0x20,0xc1]}

assistant: ```c
float outExpo(float t, float b, float c, float d) {
  if (t == d)
    return b + c;
  return c * 1.001 * (-powf(2, -10 * t / d) + 1) + b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<outExpo>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm2,0xc(%rsp)
  ucomiss %xmm3,%xmm0
  jp     L9
  jne    L9
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
L5:
  add    $0x18,%rsp
  ret
L9:
  mulss  D14(%rip),%xmm0
  divss  %xmm3,%xmm0
  cvttss2si %xmm0,%esi
  mov    $0x2,%edi
  call   <powf@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  mulsd  D1(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D1
type_guessed: f64

tool: {"D14": [0x00,0x00,0x20,0xc1]}

tool: D1: 1.001

assistant: ```c
float outExpo(float t, float b, float c, float d) {
  if (t == d)
    return b + c;
  return c * 1.001 * (-powf(2, -10 * t / d) + 1) + b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<outExpo>:
  endbr64
  ucomiss %xmm3,%xmm0
  jp     L17
  jne    L17
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  sub    $0x18,%rsp
  mov    $0x2,%edi
  mulss  D6(%rip),%xmm0
  movss  %xmm2,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  divss  %xmm3,%xmm0
  cvttss2si %xmm0,%esi
  call   <powf@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm1
  mov    %eax,%r8d
  mov    $0x1,%eax
  sub    %r8d,%eax
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  mulsd  D0(%rip),%xmm2
  cvtsi2sd %eax,%xmm0
  add    $0x18,%rsp
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: byte[4]
name: unpack_data
arguments: data_label: D0
data_type: f64

tool: {"D6": [0x00,0x00,0x20,0xc1]}

tool: D0: 1.001

assistant: ```c
float outExpo(float t, float b, float c, float d) {
  if (t == d)
    return b + c;
  return c * 1.001 * (-powf(2, -10 * t / d) + 1) + b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<outExpo>:
  endbr64
  ucomiss %xmm3,%xmm0
  jp     L7
  jne    L7
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  sub    $0x18,%rsp
  mov    $0x2,%edi
  mulss  D19(%rip),%xmm0
  movss  %xmm2,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  divss  %xmm3,%xmm0
  cvttss2si %xmm0,%esi
  call   <powf@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm1
  mov    %eax,%r8d
  mov    $0x1,%eax
  sub    %r8d,%eax
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  mulsd  D4(%rip),%xmm2
  cvtsi2sd %eax,%xmm0
  add    $0x18,%rsp
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
type_guessed: byte[4]
name: disassemble_data
arguments: label: D4
type_guessed: f64

tool: {"D19": [0x00,0x00,0x20,0xc1]}

tool: D4: 1.001

assistant: ```c
float outExpo(float t, float b, float c, float d) {
  if (t == d)
    return b + c;
  return c * 1.001 * (-powf(2, -10 * t / d) + 1) + b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<needsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <match@plt>
  test   %rax,%rax
  je     L31
  mov    $0x0,%eax
  jmp    L29
L31:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <number@plt>
  test   %eax,%eax
  jne    L44
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  movl   $0x1,-0xc(%rbp)
L44:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L37
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    -0xc(%rbp),%eax
  neg    %eax
  mov    %eax,-0xc(%rbp)
L37:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <needbrack@plt>
  mov    -0xc(%rbp),%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D34
data_type: string
name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D28
data_type: string

tool: D34: ]

tool: D4: must be constant

tool: D28: negative size illegal

assistant: ```c
needsub() {
  int num[1];
  if (match("]"))
    return (0);
  if (!number(num)) {
    error("must be constant");
    num[0] = 1;
  }
  if (num[0] < 0) {
    error("negative size illegal");
    num[0] = (-num[0]);
  }
  needbrack("]");
  return (num[0]);
}
```
user: What is the c source code of the assembly code below?

```asm
<needsub>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <match@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L4
L58:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L65
  add    $0x18,%rsp
  ret
L4:
  lea    0x4(%rsp),%rdi
  call   <number@plt>
  test   %eax,%eax
  je     L42
  cmpl   $0x0,0x4(%rsp)
  js     L28
L10:
  lea    D19(%rip),%rdi
  call   <needbrack@plt>
  mov    0x4(%rsp),%eax
  jmp    L58
L42:
  lea    D0(%rip),%rdi
  call   <error@plt>
  movl   $0x1,0x4(%rsp)
  jmp    L10
L28:
  lea    D32(%rip),%rdi
  call   <error@plt>
  negl   0x4(%rsp)
  jmp    L10
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type_guessed: string
name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D32
type_guessed: string

tool: D19: ]

tool: D0: must be constant

tool: D32: negative size illegal

assistant: ```c
needsub() {
  int num[1];
  if (match("]"))
    return (0);
  if (!number(num)) {
    error("must be constant");
    num[0] = 1;
  }
  if (num[0] < 0) {
    error("negative size illegal");
    num[0] = (-num[0]);
  }
  needbrack("]");
  return (num[0]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<needsub>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <match@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L39
L47:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  lea    0x4(%rsp),%rdi
  call   <number@plt>
  test   %eax,%eax
  je     L15
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jns    L55
  lea    D3(%rip),%rdi
  call   <error@plt>
  negl   0x4(%rsp)
L55:
  mov    %rbp,%rdi
  call   <needbrack@plt>
  mov    0x4(%rsp),%eax
  jmp    L47
  nopl   0x0(%rax)
L15:
  lea    D8(%rip),%rdi
  call   <error@plt>
  mov    %rbp,%rdi
  movl   $0x1,0x4(%rsp)
  call   <needbrack@plt>
  mov    0x4(%rsp),%eax
  jmp    L47
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: D2: ]

tool: D3: negative size illegal

tool: D8: must be constant

assistant: ```c
needsub() {
  int num[1];
  if (match("]"))
    return (0);
  if (!number(num)) {
    error("must be constant");
    num[0] = 1;
  }
  if (num[0] < 0) {
    error("negative size illegal");
    num[0] = (-num[0]);
  }
  needbrack("]");
  return (num[0]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<needsub>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <match@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L2
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  lea    0x4(%rsp),%rdi
  call   <number@plt>
  test   %eax,%eax
  je     L53
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jns    L28
  lea    D25(%rip),%rdi
  call   <error@plt>
  negl   0x4(%rsp)
L28:
  mov    %rbp,%rdi
  call   <needbrack@plt>
  mov    0x4(%rsp),%eax
  jmp    L48
  nopl   0x0(%rax)
L53:
  lea    D7(%rip),%rdi
  call   <error@plt>
  mov    %rbp,%rdi
  movl   $0x1,0x4(%rsp)
  call   <needbrack@plt>
  mov    0x4(%rsp),%eax
  jmp    L48
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D7
type: string

tool: D13: ]

tool: D25: negative size illegal

tool: D7: must be constant

assistant: ```c
needsub() {
  int num[1];
  if (match("]"))
    return (0);
  if (!number(num)) {
    error("must be constant");
    num[0] = 1;
  }
  if (num[0] < 0) {
    error("negative size illegal");
    num[0] = (-num[0]);
  }
  needbrack("]");
  return (num[0]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L3:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  je     L99
  movq   $0x1,-0x30(%rbp)
  movq   $0x2,-0x28(%rbp)
  movq   $0x4,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  cmp    $0x1,%rax
  je     L90
  mov    -0x38(%rbp),%rax
  cmp    $0x2,%rax
  je     L90
  mov    -0x38(%rbp),%rax
  cmp    $0x3,%rax
  jne    L80
L90:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L78
L80:
  movq   $0x4,-0x10(%rbp)
  jmp    L95
L94:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  addq   $0x1,-0x10(%rbp)
L95:
  mov    -0x38(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jle    L94
  mov    -0x18(%rbp),%rcx
  movabs $0x8fa3faf33c2d72e3,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0xb,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xe42,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L91
  mov    -0x18(%rbp),%rcx
  movabs $0x8fa3faf33c2d72e3,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0xb,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L3
L91:
  mov    -0x18(%rbp),%rcx
  movabs $0x8fa3faf33c2d72e3,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0xb,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L78:
  jmp    L3
L99:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string

tool: D4: %lld

tool: D18: 1

tool: D26: %lld


assistant: ```c
int main(void) {
  long long a1, a2, a3, a4, num, i;
  while (1) {
    scanf("%lld", &num);
    if (num == 0)
      break;
    a1 = 1, a2 = 2, a3 = 4;
    if (num == 1 || num == 2 || num == 3) {
      printf("1\n");
    } else {
      for (i = 4; i <= num; i++) {
        a4 = a1 + a2 + a3;
        a1 = a2, a2 = a3, a3 = a4;
      }
      if (a4 % 3650 == 0) {
        printf("%lld\n", a4 / 3650);
      } else {
        printf("%lld\n", a4 / 3650 + 1);
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rbp
  lea    D24(%rip),%r13
  movabs $0x8fa3faf33c2d72e3,%r12
  lea    D8(%rip),%r14
  jmp    L1
L29:
  cmp    $0x3,%rax
  jle    L56
  lea    0x1(%rax),%rsi
  mov    $0x4,%ecx
  mov    $0x4,%ebx
  mov    $0x2,%edx
  mov    $0x1,%eax
L62:
  mov    %rbx,%rdi
  add    %rdx,%rax
  add    %rax,%rbx
  add    $0x1,%rcx
  mov    %rdx,%rax
  mov    %rdi,%rdx
  cmp    %rcx,%rsi
  jne    L62
L56:
  mov    %rbx,%rax
  imul   %r12
  lea    (%rdx,%rbx,1),%rax
  sar    $0xb,%rax
  mov    %rbx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xe42,%rax,%rax
  cmp    %rax,%rbx
  jne    L64
  mov    %rbx,%rax
  imul   %r12
  lea    (%rdx,%rbx,1),%rsi
  sar    $0xb,%rsi
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L1:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  je     L69
  lea    -0x1(%rax),%rdx
  cmp    $0x2,%rdx
  ja     L29
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L1
L64:
  mov    %rbx,%rax
  imul   %r12
  lea    (%rdx,%rbx,1),%rsi
  sar    $0xb,%rsi
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rsi
  add    $0x1,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
L69:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string

tool: D2: %lld

tool: D24: 1

tool: D8: %lld


assistant: ```c
int main(void) {
  long long a1, a2, a3, a4, num, i;
  while (1) {
    scanf("%lld", &num);
    if (num == 0)
      break;
    a1 = 1, a2 = 2, a3 = 4;
    if (num == 1 || num == 2 || num == 3) {
      printf("1\n");
    } else {
      for (i = 4; i <= num; i++) {
        a4 = a1 + a2 + a3;
        a1 = a2, a2 = a3, a3 = a4;
      }
      if (a4 % 3650 == 0) {
        printf("%lld\n", a4 / 3650);
      } else {
        printf("%lld\n", a4 / 3650 + 1);
      }
    }
  }
  return 0;
}
```