user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    D50(%rip),%r12
  lea    0x14(%rsp),%rbp
  lea    D58(%rip),%rbx
L53:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm0
  call   <f@plt>
  movq   %xmm0,%r14
  movss  0x14(%rsp),%xmm0
  call   <f@plt>
  movq   %r14,%xmm6
  mulsd  %xmm6,%xmm0
  pxor   %xmm7,%xmm7
  comisd %xmm7,%xmm0
  ja     L53
  pxor   %xmm5,%xmm5
  movss  %xmm5,0x8(%rsp)
  mov    $0x0,%ebx
  lea    D32(%rip),%rbp
  jmp    L54
L85:
  movss  0x8(%rsp),%xmm0
  call   <f@plt>
  movq   %xmm0,%r14
  movss  0x14(%rsp),%xmm0
  call   <f@plt>
  movq   %r14,%xmm7
  mulsd  %xmm7,%xmm0
  pxor   %xmm7,%xmm7
  comisd %xmm0,%xmm7
  ja     L70
L94:
  add    $0x1,%ebx
  movss  0x8(%rsp),%xmm0
  call   <f@plt>
  ucomisd D56(%rip),%xmm0
  jp     L54
  je     L27
L54:
  movss  0x8(%rsp),%xmm4
  movss  %xmm4,0xc(%rsp)
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  mulss  D40(%rip),%xmm0
  movss  %xmm0,0x8(%rsp)
  call   <f@plt>
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  movq   %xmm0,%r12
  mov    %ebx,%esi
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  mov    %rbp,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  movss  0xc(%rsp),%xmm4
  movss  0x8(%rsp),%xmm3
  ucomiss %xmm3,%xmm4
  jp     L97
  je     L27
L97:
  movss  0x10(%rsp),%xmm0
  call   <f@plt>
  movq   %xmm0,%r14
  movss  0x8(%rsp),%xmm0
  call   <f@plt>
  movq   %r14,%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm6,%xmm6
  comisd %xmm0,%xmm6
  jbe    L85
  movss  0x8(%rsp),%xmm5
  movss  %xmm5,0x14(%rsp)
  jmp    L94
L70:
  movss  0x8(%rsp),%xmm5
  movss  %xmm5,0x10(%rsp)
  jmp    L94
L27:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  lea    D22(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movq   %r12,%xmm0
  lea    D4(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D79(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D50
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D58
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D32
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D56
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D40
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D79
type_guessed: string

tool: D50: Enter values of interval:

tool: D58: %f %f

tool: D32: mid = %f newmid = %f i= %d and f(mid) = %f


tool: D56: 0

tool: {"D40": [0x00,0x00,0x00,0x3f]}

tool: D22: The Interval is [%f, %f]


tool: D4: Root of f(x) is : %f


tool: D79: No of iterations: %d


assistant: ```c
void main() {
  int i = 0;
  float newmid = 0, mid = 0, a = 0, b = 0;
  do {
    printf("Enter values of interval:");
    scanf("%f %f", &a, &b);
  } while (f(a) * f(b) > 0);
  do {
    mid = (a + b) / 2;
    printf("mid = %f newmid = %f i= %d and f(mid) = %f\n", mid, newmid, i, f(mid));
    if (mid == newmid)
      break;
    else if (f(a) * f(mid) < 0)
      b = mid;
    else if (f(mid) * f(b) < 0)
      a = mid;
    newmid = mid;
    i++;
  } while (f(mid) != 0);
  printf("The Interval is [%f, %f]\n", a, b);
  printf("Root of f(x) is : %f\n", mid);
  printf("No of iterations: %d\n", i);
}
```