ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__ptsname_r>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D15(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rbx),%r14d
  test   %rsi,%rsi
  je     L19
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r13
  call   <__isatty@plt>
  test   %eax,%eax
  jne    L32
L82:
  mov    (%rbx),%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <strlen@plt>
  add    $0x3,%eax
  cltq
  cmp    %r13,%rax
  ja     L88
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <__ttyname_r@plt>
  test   %rax,%rax
  jne    L82
  movb   $0x74,0x3(%rbp)
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <__stat@plt>
  test   %rax,%rax
  js     L82
  mov    %r14d,%edi
  call   <__set_errno@plt>
  xor    %eax,%eax
  jmp    L34
  nopl   (%rax)
L19:
  mov    D22(%rip),%rbx
  mov    (%rbx),%edi
  call   <__set_errno@plt>
  mov    (%rbx),%eax
  jmp    L34
  nopl   (%rax)
L88:
  mov    D38(%rip),%rbx
  mov    (%rbx),%edi
  call   <__set_errno@plt>
  mov    (%rbx),%eax
  jmp    L34
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __ptsname_r(int fd, char *buf, size_t buflen) {
  int save_errno = errno;
  struct stat st;
  if (buf == NULL) {
    __set_errno(EINVAL);
    return EINVAL;
  }
  if (!__isatty(fd))
    return errno;
  if (buflen < strlen(_PATH_TTY) + 3) {
    __set_errno(ERANGE);
    return ERANGE;
  }
  if (__ttyname_r(fd, buf, buflen) != 0)
    return errno;
  buf[sizeof(_PATH_DEV) - 1] = 't';
  if (__stat(buf, &st) < 0)
    return errno;
  __set_errno(save_errno);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_fscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  movl   $0x0,-0xb8(%rbp)
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <_get_actual_fp@plt>
  mov    %eax,%ecx
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <vfscanf@plt>
  mov    %eax,-0xb8(%rbp)
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int my_fscanf(struct aFILE *fp, const char *fmt, ...) {
  int ret = 0;
  va_list args;
  va_start(args, fmt);
  ret = vfscanf(_get_actual_fp(fp), fmt, args);
  va_end(args);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<my_fscanf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %r12,%rdi
  call   <_get_actual_fp@plt>
  mov    %eax,%edi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <vfscanf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int my_fscanf(struct aFILE *fp, const char *fmt, ...) {
  int ret = 0;
  va_list args;
  va_start(args, fmt);
  ret = vfscanf(_get_actual_fp(fp), fmt, args);
  va_end(args);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_fscanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12,%rdi
  call   <_get_actual_fp@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <vfscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int my_fscanf(struct aFILE *fp, const char *fmt, ...) {
  int ret = 0;
  va_list args;
  va_start(args, fmt);
  ret = vfscanf(_get_actual_fp(fp), fmt, args);
  va_end(args);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_fscanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12,%rdi
  call   <_get_actual_fp@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <vfscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int my_fscanf(struct aFILE *fp, const char *fmt, ...) {
  int ret = 0;
  va_list args;
  va_start(args, fmt);
  ret = vfscanf(_get_actual_fp(fp), fmt, args);
  va_end(args);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_cin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x1d,%eax
  and    $0x20000000,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_cin(cin) {
  int r = ((cin & 1) ? (1 << 29) : 0);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gen_cin>:
  endbr64
  mov    %edi,%eax
  shl    $0x1d,%eax
  and    $0x20000000,%eax
  ret
```

assistant: ```c
int gen_cin(cin) {
  int r = ((cin & 1) ? (1 << 29) : 0);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gen_cin>:
  endbr64
  mov    %edi,%eax
  shl    $0x1d,%eax
  and    $0x20000000,%eax
  ret
```

assistant: ```c
int gen_cin(cin) {
  int r = ((cin & 1) ? (1 << 29) : 0);
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<gen_cin>:
  endbr64
  mov    %edi,%eax
  shl    $0x1d,%eax
  and    $0x20000000,%eax
  ret
```

assistant: ```c
int gen_cin(cin) {
  int r = ((cin & 1) ? (1 << 29) : 0);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fxn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    D22(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D32(%rip)
  addl   $0x1,-0x4(%rbp)
  mov    D32(%rip),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D32
datatype: string

tool: D32: 
		auto_var is %d, static _var is %d

assistant: ```c
void fxn() {
  auto int auto_var = 0;
  static int static_var = 0;
  static_var++;
  auto_var++;
  printf("\n\t\tauto_var is %d, static _var is %d", auto_var, static_var);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fxn>:
  endbr64
  sub    $0x8,%rsp
  mov    D18(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D17(%rip)
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type: string

tool: D17: 
		auto_var is %d, static _var is %d

assistant: ```c
void fxn() {
  auto int auto_var = 0;
  static int static_var = 0;
  static_var++;
  auto_var++;
  printf("\n\t\tauto_var is %d, static _var is %d", auto_var, static_var);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uninitvar_wscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wscanf@plt>
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wscanf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void uninitvar_wscanf(void) {
  wchar_t *format;
  int i;
  (void)wscanf(format);
  (void)wscanf(format, &i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uninitvar_wscanf>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    %rbx,%rdi
  call   <wscanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <wscanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_wscanf(void) {
  wchar_t *format;
  int i;
  (void)wscanf(format);
  (void)wscanf(format, &i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uninitvar_wscanf>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <wscanf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <wscanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_wscanf(void) {
  wchar_t *format;
  int i;
  (void)wscanf(format);
  (void)wscanf(format, &i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uninitvar_wscanf>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <wscanf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <wscanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_wscanf(void) {
  wchar_t *format;
  int i;
  (void)wscanf(format);
  (void)wscanf(format, &i);
}
```
user: What is the c source code of the assembly code below?

```asm
<dng_compress>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  call   <find_adobe_dng_converter@plt>
  test   %rax,%rax
  je     L26
  mov    %rax,%rbp
  mov    %rax,%rsi
  lea    D89(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D84(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%r12
  mov    %rbx,%rcx
  lea    D65(%rip),%rdx
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <rename@plt>
  test   %r13d,%r13d
  lea    D60(%rip),%r9
  lea    D56(%rip),%rax
  cmove  %rax,%r9
  lea    0x3f0(%rsp),%r12
  mov    %rsp,%rax
  push   %rax
  push   %rbx
  mov    %rbp,%r8
  lea    D56(%rip),%rcx
  lea    D29(%rip),%rdx
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <system@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  je     L18
  mov    %eax,%esi
  lea    D74(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <rename@plt>
L49:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  lea    D76(%rip),%rdi
  call   <puts@plt>
  jmp    L49
L18:
  mov    %rsp,%rdi
  call   <unlink@plt>
  jmp    L49
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D89
type_infered: string
name: disassemble_data
arguments: label: D84
type_infered: string
name: disassemble_data
arguments: label: D65
type_infered: string
name: disassemble_data
arguments: label: D60
type_infered: string
name: disassemble_data
arguments: label: D56
type_infered: string
name: disassemble_data
arguments: label: D29
type_infered: string
name: disassemble_data
arguments: label: D74
type_infered: string
name: disassemble_data
arguments: label: D76
type_infered: string

tool: D89: Found %s


tool: D84: Compressing %s...


tool: D65: %s.DNG

tool: D60: -lossy

tool: 

tool: D29: %s"%s" -dng1.4 %s -o "%s" "%s"

tool: D74: Adobe DNG Converter returned error(%d).


tool: D76: Adobe DNG Converter not found.

assistant: ```c
void dng_compress(const char *source, int lossy) {
  const char *adobe_dng = find_adobe_dng_converter();
  if (adobe_dng) {
    printf("Found %s\n", adobe_dng);
  } else {
    printf("Adobe DNG Converter not found.\n");
    return;
  }
  printf("Compressing %s...\n", source);
  char tmp[1000];
  snprintf(tmp, sizeof(tmp), "%s.DNG", source);
  rename(source, tmp);
  char compress_cmd[1000];
  char *start = "";
  snprintf(compress_cmd, sizeof(compress_cmd), "%s\"%s\" -dng1.4 %s -o \"%s\" \"%s\"", start, adobe_dng, lossy ? "-lossy" : "", source, tmp);
  printf("%s\n", compress_cmd);
  int r = system(compress_cmd);
  if (r != 0) {
    printf("Adobe DNG Converter returned error(%d).\n", r);
    rename(tmp, source);
  } else {
    unlink(tmp);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int add(int a, int b) {
  int add;
  add = a + b;
  return add;
}
```
user: Translate the below assembly code into C programming language:

```asm
<add>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int add(int a, int b) {
  int add;
  add = a + b;
  return add;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int add(int a, int b) {
  int add;
  add = a + b;
  return add;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int add(int a, int b) {
  int add;
  add = a + b;
  return add;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
  jmp    L39
L53:
  add    $0x1,%rbx
L39:
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L53
  movzbl (%rbx),%eax
  cmp    $0x9,%al
  je     L53
  movzbl (%rbx),%eax
  test   %al,%al
  je     L54
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  jne    L6
  lea    0x1(%rbx),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
L54:
  mov    $0x0,%ebx
L6:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ltrim(cp)
char *cp;
{
  register char *cp1;
  cp1 = cp;
  while ((*cp1 == ' ') || (*cp1 == '\t'))
    cp1++;
  if ((*cp1 == 0) || (*cp1 == '\n' && cp1[1] == 0))
    cp1 = 0;
  return (cp1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ltrim>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L47
  cmp    $0x9,%dl
  jne    L22
L47:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L47
  cmp    $0x9,%dl
  je     L47
L22:
  test   %dl,%dl
  je     L64
  cmp    $0xa,%dl
  je     L16
L53:
  ret
L16:
  cmpb   $0x0,0x1(%rax)
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
L64:
  mov    $0x0,%eax
  jmp    L53
```

assistant: ```c
char *ltrim(cp)
char *cp;
{
  register char *cp1;
  cp1 = cp;
  while ((*cp1 == ' ') || (*cp1 == '\t'))
    cp1++;
  if ((*cp1 == 0) || (*cp1 == '\n' && cp1[1] == 0))
    cp1 = 0;
  return (cp1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ltrim>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L16
  nop
L26:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L26
L16:
  cmp    $0x9,%dl
  je     L26
  test   %dl,%dl
  je     L20
  cmp    $0xa,%dl
  je     L41
  ret
  nopl   0x0(%rax)
L41:
  xor    %edx,%edx
  cmpb   $0x0,0x1(%rax)
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ltrim(cp)
char *cp;
{
  register char *cp1;
  cp1 = cp;
  while ((*cp1 == ' ') || (*cp1 == '\t'))
    cp1++;
  if ((*cp1 == 0) || (*cp1 == '\n' && cp1[1] == 0))
    cp1 = 0;
  return (cp1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ltrim>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L48
  nop
L49:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L49
L48:
  cmp    $0x9,%dl
  je     L49
  test   %dl,%dl
  je     L28
  cmp    $0xa,%dl
  je     L38
  ret
  nopl   0x0(%rax)
L38:
  xor    %edx,%edx
  cmpb   $0x0,0x1(%rax)
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ltrim(cp)
char *cp;
{
  register char *cp1;
  cp1 = cp;
  while ((*cp1 == ' ') || (*cp1 == '\t'))
    cp1++;
  if ((*cp1 == 0) || (*cp1 == '\n' && cp1[1] == 0))
    cp1 = 0;
  return (cp1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L46
L30:
  movl   $0x1,-0xc(%rbp)
  jmp    L49
L0:
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L49:
  cmpl   $0xa,-0xc(%rbp)
  jle    L0
  addl   $0x1,-0x10(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L30
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string

tool: D35: Este programa foi feito por Jessica Cristina Cacau Patricio.


tool: D9: Digite um numero inteiro:

tool: D10: %d

tool: D14: %d * %d = %d


assistant: ```c
void main() {
  printf("Este programa foi feito por Jessica Cristina Cacau Patricio.\n\n");
  int num, cont = 1, cont2;
  printf("Digite um numero inteiro:\n");
  scanf("%d", &num);
  while (cont <= num) {
    cont2 = 1;
    while (cont2 <= 10) {
      printf("%d * %d = %d\n", cont, cont2, cont * cont2);
      cont2++;
    }
    cont++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%r12d
  lea    D31(%rip),%r14
  cmpl   $0x0,0x4(%rsp)
  jle    L27
L37:
  mov    %r12d,%r13d
  mov    %r12d,%ebp
  mov    $0x1,%ebx
L23:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r13d,%ebp
  cmp    $0xb,%ebx
  jne    L23
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jge    L37
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D21
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D31
datatype: string

tool: D21: Este programa foi feito por Jessica Cristina Cacau Patricio.


tool: D17: Digite um numero inteiro:

tool: D0: %d

tool: D31: %d * %d = %d


assistant: ```c
void main() {
  printf("Este programa foi feito por Jessica Cristina Cacau Patricio.\n\n");
  int num, cont = 1, cont2;
  printf("Digite um numero inteiro:\n");
  scanf("%d", &num);
  while (cont <= num) {
    cont2 = 1;
    while (cont2 <= 10) {
      printf("%d * %d = %d\n", cont, cont2, cont * cont2);
      cont2++;
    }
    cont++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L15
  mov    $0x1,%r12d
  lea    D33(%rip),%r13
  nopl   0x0(%rax)
L6:
  mov    %r12d,%ebp
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %r12d,%ebp
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L11
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jge    L6
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D38
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string
name: read_data
arguments: label: D33
type_guessed: string

tool: D19: Este programa foi feito por Jessica Cristina Cacau Patricio.


tool: D38: Digite um numero inteiro:

tool: D26: %d

tool: D33: %d * %d = %d


assistant: ```c
void main() {
  printf("Este programa foi feito por Jessica Cristina Cacau Patricio.\n\n");
  int num, cont = 1, cont2;
  printf("Digite um numero inteiro:\n");
  scanf("%d", &num);
  while (cont <= num) {
    cont2 = 1;
    while (cont2 <= 10) {
      printf("%d * %d = %d\n", cont, cont2, cont * cont2);
      cont2++;
    }
    cont++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D39(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L34
  mov    $0x1,%r12d
  lea    D37(%rip),%r13
  nopl   0x0(%rax)
L38:
  mov    %r12d,%ebp
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %r12d,%ebp
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L5
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jge    L38
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D39
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string
name: read_data
arguments: data_tag: D7
data_type: string
name: read_data
arguments: data_tag: D37
data_type: string

tool: D39: Este programa foi feito por Jessica Cristina Cacau Patricio.


tool: D4: Digite um numero inteiro:

tool: D7: %d

tool: D37: %d * %d = %d


assistant: ```c
void main() {
  printf("Este programa foi feito por Jessica Cristina Cacau Patricio.\n\n");
  int num, cont = 1, cont2;
  printf("Digite um numero inteiro:\n");
  scanf("%d", &num);
  while (cont <= num) {
    cont2 = 1;
    while (cont2 <= 10) {
      printf("%d * %d = %d\n", cont, cont2, cont * cont2);
      cont2++;
    }
    cont++;
  }
}
```