ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *my_strdup(const char *s) {
  int len = strlen(s);
  char *ret = (char *)malloc(len + 1);
  strcpy(ret, s);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_strdup(const char *s) {
  int len = strlen(s);
  char *ret = (char *)malloc(len + 1);
  strcpy(ret, s);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_strdup(const char *s) {
  int len = strlen(s);
  char *ret = (char *)malloc(len + 1);
  strcpy(ret, s);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<AddHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%ecx
  lea    D6(%rip),%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%ecx
  lea    D6(%rip),%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *AddHex(char *S, unsigned Val) {
  static const char HexTab[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  *S++ = HexTab[(Val >> 4) & 0x0F];
  *S++ = HexTab[Val & 0x0F];
  return S;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<AddHex>:
  endbr64
  lea    D1(%rip),%rdx
  mov    %esi,%eax
  shr    $0x4,%eax
  and    $0xf,%eax
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdi)
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%eax
  mov    %al,0x1(%rdi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *AddHex(char *S, unsigned Val) {
  static const char HexTab[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  *S++ = HexTab[(Val >> 4) & 0x0F];
  *S++ = HexTab[Val & 0x0F];
  return S;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<AddHex>:
  endbr64
  mov    %esi,%eax
  lea    D9(%rip),%rdx
  and    $0xf,%esi
  shr    $0x4,%eax
  and    $0xf,%eax
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdi)
  movzbl (%rdx,%rsi,1),%eax
  mov    %al,0x1(%rdi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *AddHex(char *S, unsigned Val) {
  static const char HexTab[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  *S++ = HexTab[(Val >> 4) & 0x0F];
  *S++ = HexTab[Val & 0x0F];
  return S;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AddHex>:
  endbr64
  mov    %esi,%eax
  lea    D6(%rip),%rdx
  and    $0xf,%esi
  shr    $0x4,%eax
  and    $0xf,%eax
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdi)
  movzbl (%rdx,%rsi,1),%eax
  mov    %al,0x1(%rdi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *AddHex(char *S, unsigned Val) {
  static const char HexTab[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  *S++ = HexTab[(Val >> 4) & 0x0F];
  *S++ = HexTab[Val & 0x0F];
  return S;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<encode_cpr_lon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  cmpl   $0x0,-0x48(%rbp)
  je     L24
  mov    $0x80000,%eax
  jmp    L21
L24:
  mov    $0x20000,%eax
L21:
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  je     L11
  movsd  D19(%rip),%xmm0
  jmp    L10
L11:
  movsd  D15(%rip),%xmm0
L10:
  movsd  D5(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <cprMod@plt>
  imul   -0x24(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x18(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <floor@plt>
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x24(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  -0x38(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <floor@plt>
  addsd  -0x50(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x44(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <cprN@plt>
  movapd %xmm0,%xmm1
  movsd  D5(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <cprMod@plt>
  imul   -0x24(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x8(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <floor@plt>
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x1ffff,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D19
data_type: f64
name: read_data
arguments: label: D15
data_type: f64
name: read_data
arguments: label: D5
data_type: f64
name: read_data
arguments: label: D2
data_type: f64

tool: D19: 59

tool: D15: 60

tool: D5: 360

tool: D2: 0.5

assistant: ```c
int encode_cpr_lon(double lat, double lon, int odd, int surface) {
  int NbPow = (surface ? 1 << 19 : 1 << 17);
  double Dlat = 360.0 / (odd ? 59 : 60);
  int YZ = floor(NbPow * cprMod(lat, Dlat) / Dlat + 0.5);
  double Rlat = Dlat * (1.0 * YZ / NbPow + floor(lat / Dlat));
  double Dlon = (360.0 / cprN(Rlat, odd));
  int XZ = floor(NbPow * cprMod(lon, Dlon) / Dlon + 0.5);
  return XZ & 0x1FFFF;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<encode_cpr_lon>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbp
  movq   %xmm1,%r13
  mov    %edi,%r12d
  cmp    $0x1,%esi
  sbb    %ebx,%ebx
  and    $0xfffa0000,%ebx
  add    $0x80000,%ebx
  movsd  D52(%rip),%xmm0
  test   %edi,%edi
  jne    L7
  movsd  D12(%rip),%xmm0
L7:
  movsd  D51(%rip),%xmm2
  divsd  %xmm0,%xmm2
  movsd  %xmm2,(%rsp)
  movapd %xmm2,%xmm1
  movq   %rbp,%xmm0
  call   <cprMod@plt>
  imul   %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  (%rsp),%xmm0
  addsd  D25(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  movq   %rbp,%xmm0
  divsd  (%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  addsd  0x8(%rsp),%xmm0
  mulsd  (%rsp),%xmm0
  mov    %r12d,%edi
  call   <cprN@plt>
  movsd  D51(%rip),%xmm3
  divsd  %xmm0,%xmm3
  movsd  %xmm3,(%rsp)
  movapd %xmm3,%xmm1
  movq   %r13,%xmm0
  call   <cprMod@plt>
  imul   %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  (%rsp),%xmm0
  addsd  D25(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  cvttsd2si %xmm0,%eax
  and    $0x1ffff,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D52
type_guessed: f64
name: read_data
arguments: label: D12
type_guessed: f64
name: read_data
arguments: label: D51
type_guessed: f64
name: read_data
arguments: label: D25
type_guessed: f64

tool: D52: 59

tool: D12: 60

tool: D51: 360

tool: D25: 0.5

assistant: ```c
int encode_cpr_lon(double lat, double lon, int odd, int surface) {
  int NbPow = (surface ? 1 << 19 : 1 << 17);
  double Dlat = 360.0 / (odd ? 59 : 60);
  int YZ = floor(NbPow * cprMod(lat, Dlat) / Dlat + 0.5);
  double Rlat = Dlat * (1.0 * YZ / NbPow + floor(lat / Dlat));
  double Dlon = (360.0 / cprN(Rlat, odd));
  int XZ = floor(NbPow * cprMod(lon, Dlon) / Dlon + 0.5);
  return XZ & 0x1FFFF;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encode_cpr_lon>:
  endbr64
  push   %rbp
  movapd %xmm1,%xmm3
  movapd %xmm0,%xmm2
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  cmp    $0x1,%esi
  movsd  D2(%rip),%xmm1
  sbb    %ebx,%ebx
  and    $0xfffa0000,%ebx
  add    $0x80000,%ebx
  test   %edi,%edi
  jne    L9
  movsd  D18(%rip),%xmm1
L9:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,(%rsp)
  call   <cprMod@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  imul   %ebx,%eax
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %eax,%xmm0
  divsd  %xmm1,%xmm0
  addsd  D42(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
  pxor   %xmm4,%xmm4
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  divsd  %xmm1,%xmm2
  cvtsi2sd %ebx,%xmm0
  cvtsi2sd %eax,%xmm4
  divsd  %xmm0,%xmm4
  cvttsd2si %xmm2,%edi
  movsd  %xmm4,(%rsp)
  call   <floor@plt>
  addsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  mov    %ebp,%edi
  mulsd  %xmm1,%xmm0
  call   <cprN@plt>
  movsd  D0(%rip),%xmm2
  movsd  0x18(%rsp),%xmm3
  divsd  %xmm0,%xmm2
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm1
  movsd  %xmm2,(%rsp)
  call   <cprMod@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm2
  imul   %ebx,%eax
  cvtsi2sd %eax,%xmm0
  divsd  %xmm2,%xmm0
  addsd  D42(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  add    $0x28,%rsp
  cvttsd2si %xmm0,%eax
  pop    %rbx
  pop    %rbp
  and    $0x1ffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D18
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D42
data_type: f64
name: extract_symbolic_data
arguments: tag: D0
data_type: f64

tool: {"D2": [0xea,0xbe,0x3c,0xb6,0x22,0x68,0x18,0x40]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: D42: 0.5

tool: D0: 360

assistant: ```c
int encode_cpr_lon(double lat, double lon, int odd, int surface) {
  int NbPow = (surface ? 1 << 19 : 1 << 17);
  double Dlat = 360.0 / (odd ? 59 : 60);
  int YZ = floor(NbPow * cprMod(lat, Dlat) / Dlat + 0.5);
  double Rlat = Dlat * (1.0 * YZ / NbPow + floor(lat / Dlat));
  double Dlon = (360.0 / cprN(Rlat, odd));
  int XZ = floor(NbPow * cprMod(lon, Dlon) / Dlon + 0.5);
  return XZ & 0x1FFFF;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<encode_cpr_lon>:
  endbr64
  push   %rbp
  movapd %xmm1,%xmm3
  movapd %xmm0,%xmm2
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  cmp    $0x1,%esi
  movsd  D47(%rip),%xmm1
  sbb    %ebx,%ebx
  and    $0xfffa0000,%ebx
  add    $0x80000,%ebx
  test   %edi,%edi
  jne    L6
  movsd  D1(%rip),%xmm1
L6:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,(%rsp)
  call   <cprMod@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  imul   %ebx,%eax
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %eax,%xmm0
  divsd  %xmm1,%xmm0
  addsd  D10(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
  pxor   %xmm4,%xmm4
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  divsd  %xmm1,%xmm2
  cvtsi2sd %ebx,%xmm0
  cvtsi2sd %eax,%xmm4
  divsd  %xmm0,%xmm4
  cvttsd2si %xmm2,%edi
  movsd  %xmm4,(%rsp)
  call   <floor@plt>
  addsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  mov    %ebp,%edi
  mulsd  %xmm1,%xmm0
  call   <cprN@plt>
  movsd  D9(%rip),%xmm2
  movsd  0x18(%rsp),%xmm3
  divsd  %xmm0,%xmm2
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm1
  movsd  %xmm2,(%rsp)
  call   <cprMod@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm2
  imul   %ebx,%eax
  cvtsi2sd %eax,%xmm0
  divsd  %xmm2,%xmm0
  addsd  D10(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  add    $0x28,%rsp
  cvttsd2si %xmm0,%eax
  pop    %rbx
  pop    %rbp
  and    $0x1ffff,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D47
data_type: byte[8]
name: parse_data
arguments: data_label: D1
data_type: byte[8]
name: parse_data
arguments: data_label: D10
data_type: f64
name: parse_data
arguments: data_label: D9
data_type: f64

tool: {"D47": [0xea,0xbe,0x3c,0xb6,0x22,0x68,0x18,0x40]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: D10: 0.5

tool: D9: 360

assistant: ```c
int encode_cpr_lon(double lat, double lon, int odd, int surface) {
  int NbPow = (surface ? 1 << 19 : 1 << 17);
  double Dlat = 360.0 / (odd ? 59 : 60);
  int YZ = floor(NbPow * cprMod(lat, Dlat) / Dlat + 0.5);
  double Rlat = Dlat * (1.0 * YZ / NbPow + floor(lat / Dlat));
  double Dlon = (360.0 / cprN(Rlat, odd));
  int XZ = floor(NbPow * cprMod(lon, Dlon) / Dlon + 0.5);
  return XZ & 0x1FFFF;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aes_addRoundKey_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    $0x10,%ebx
  jmp    L2
L17:
  movzbl %bl,%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl %bl,%ecx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%ecx
  movzbl %bl,%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzbl %bl,%esi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  movzbl %bl,%eax
  add    $0x10,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl %bl,%edx
  add    $0x10,%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L2:
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  test   %al,%al
  jne    L17
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void aes_addRoundKey_cpy(unsigned char *buf, unsigned char *key, unsigned char *cpk) {
  register unsigned char i = 16;
  while (i--)
    buf[i] ^= (cpk[i] = key[i]), cpk[16 + i] = key[16 + i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<aes_addRoundKey_cpy>:
  endbr64
  mov    $0xf,%eax
L9:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  xor    %cl,(%rdi,%rax,1)
  movzbl 0x10(%rsi,%rax,1),%ecx
  mov    %cl,0x10(%rdx,%rax,1)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L9
  ret
```

assistant: ```c
void aes_addRoundKey_cpy(unsigned char *buf, unsigned char *key, unsigned char *cpk) {
  register unsigned char i = 16;
  while (i--)
    buf[i] ^= (cpk[i] = key[i]), cpk[16 + i] = key[16 + i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<aes_addRoundKey_cpy>:
  endbr64
  mov    $0xf,%eax
  nopl   0x0(%rax)
L3:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  xor    %cl,(%rdi,%rax,1)
  movzbl 0x10(%rsi,%rax,1),%ecx
  mov    %cl,0x10(%rdx,%rax,1)
  sub    $0x1,%rax
  jae    L3
  ret
```

assistant: ```c
void aes_addRoundKey_cpy(unsigned char *buf, unsigned char *key, unsigned char *cpk) {
  register unsigned char i = 16;
  while (i--)
    buf[i] ^= (cpk[i] = key[i]), cpk[16 + i] = key[16 + i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aes_addRoundKey_cpy>:
  endbr64
  mov    %rdx,%rax
  movzbl 0xf(%rsi),%edx
  mov    %dl,0xf(%rax)
  xor    %dl,0xf(%rdi)
  movzbl 0x1f(%rsi),%edx
  mov    %dl,0x1f(%rax)
  movzbl 0xe(%rsi),%edx
  mov    %dl,0xe(%rax)
  xor    %dl,0xe(%rdi)
  movzbl 0x1e(%rsi),%edx
  mov    %dl,0x1e(%rax)
  movzbl 0xd(%rsi),%edx
  mov    %dl,0xd(%rax)
  xor    %dl,0xd(%rdi)
  movzbl 0x1d(%rsi),%edx
  mov    %dl,0x1d(%rax)
  movzbl 0xc(%rsi),%edx
  mov    %dl,0xc(%rax)
  xor    %dl,0xc(%rdi)
  movzbl 0x1c(%rsi),%edx
  mov    %dl,0x1c(%rax)
  movzbl 0xb(%rsi),%edx
  mov    %dl,0xb(%rax)
  xor    %dl,0xb(%rdi)
  movzbl 0x1b(%rsi),%edx
  mov    %dl,0x1b(%rax)
  movzbl 0xa(%rsi),%edx
  mov    %dl,0xa(%rax)
  xor    %dl,0xa(%rdi)
  movzbl 0x1a(%rsi),%edx
  mov    %dl,0x1a(%rax)
  movzbl 0x9(%rsi),%edx
  mov    %dl,0x9(%rax)
  xor    %dl,0x9(%rdi)
  movzbl 0x19(%rsi),%edx
  mov    %dl,0x19(%rax)
  movzbl 0x8(%rsi),%edx
  mov    %dl,0x8(%rax)
  xor    %dl,0x8(%rdi)
  movzbl 0x18(%rsi),%edx
  mov    %dl,0x18(%rax)
  movzbl 0x7(%rsi),%edx
  mov    %dl,0x7(%rax)
  xor    %dl,0x7(%rdi)
  movzbl 0x17(%rsi),%edx
  mov    %dl,0x17(%rax)
  movzbl 0x6(%rsi),%edx
  mov    %dl,0x6(%rax)
  xor    %dl,0x6(%rdi)
  movzbl 0x16(%rsi),%edx
  mov    %dl,0x16(%rax)
  movzbl 0x5(%rsi),%edx
  mov    %dl,0x5(%rax)
  xor    %dl,0x5(%rdi)
  movzbl 0x15(%rsi),%edx
  mov    %dl,0x15(%rax)
  movzbl 0x4(%rsi),%edx
  mov    %dl,0x4(%rax)
  xor    %dl,0x4(%rdi)
  movzbl 0x14(%rsi),%edx
  mov    %dl,0x14(%rax)
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x3(%rax)
  xor    %dl,0x3(%rdi)
  movzbl 0x13(%rsi),%edx
  mov    %dl,0x13(%rax)
  movzbl 0x2(%rsi),%edx
  mov    %dl,0x2(%rax)
  xor    %dl,0x2(%rdi)
  movzbl 0x12(%rsi),%edx
  mov    %dl,0x12(%rax)
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  xor    %dl,0x1(%rdi)
  movzbl 0x11(%rsi),%edx
  mov    %dl,0x11(%rax)
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  xor    %dl,(%rdi)
  movzbl 0x10(%rsi),%edx
  mov    %dl,0x10(%rax)
  ret
```

assistant: ```c
void aes_addRoundKey_cpy(unsigned char *buf, unsigned char *key, unsigned char *cpk) {
  register unsigned char i = 16;
  while (i--)
    buf[i] ^= (cpk[i] = key[i]), cpk[16 + i] = key[16 + i];
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x7978,-0xb(%rbp)
  movb   $0x7a,-0x9(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  lea    -0xb(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D11
type_infered: string

tool: D17: rb+

tool: D11: ssh3

assistant: ```c
int main() {
  FILE *pFile;
  char buffer[] = {'x', 'y', 'z'};
  pFile = fopen("ssh3", "rb+");
  fwrite(buffer, sizeof(char), sizeof(buffer), pFile);
  rewind(pFile);
  fclose(pFile);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x7978,0x5(%rsp)
  movb   $0x7a,0x7(%rsp)
  lea    D16(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    0x5(%rsp),%rdi
  mov    %rax,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <rewind@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string

tool: D16: rb+

tool: D12: ssh3

assistant: ```c
int main() {
  FILE *pFile;
  char buffer[] = {'x', 'y', 'z'};
  pFile = fopen("ssh3", "rb+");
  fwrite(buffer, sizeof(char), sizeof(buffer), pFile);
  rewind(pFile);
  fclose(pFile);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rsi
  lea    D4(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x7978,%eax
  movb   $0x7a,0x7(%rsp)
  mov    %ax,0x5(%rsp)
  call   <fopen@plt>
  lea    0x5(%rsp),%rdi
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D4
type: string

tool: D5: rb+

tool: D4: ssh3

assistant: ```c
int main() {
  FILE *pFile;
  char buffer[] = {'x', 'y', 'z'};
  pFile = fopen("ssh3", "rb+");
  fwrite(buffer, sizeof(char), sizeof(buffer), pFile);
  rewind(pFile);
  fclose(pFile);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rsi
  lea    D12(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x7978,%eax
  movb   $0x7a,0x7(%rsp)
  mov    %ax,0x5(%rsp)
  call   <fopen@plt>
  lea    0x5(%rsp),%rdi
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string
name: retrieve_data
arguments: label: D12
data_type: string

tool: D4: rb+

tool: D12: ssh3

assistant: ```c
int main() {
  FILE *pFile;
  char buffer[] = {'x', 'y', 'z'};
  pFile = fopen("ssh3", "rb+");
  fwrite(buffer, sizeof(char), sizeof(buffer), pFile);
  rewind(pFile);
  fclose(pFile);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deleteService>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <destroyService@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void deleteService(struct Service *service) {
  destroyService(service);
  free(service);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<deleteService>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <destroyService@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void deleteService(struct Service *service) {
  destroyService(service);
  free(service);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<deleteService>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <destroyService@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void deleteService(struct Service *service) {
  destroyService(service);
  free(service);
}
```
user: What is the c source code of the assembly code below:

```asm
<deleteService>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <destroyService@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void deleteService(struct Service *service) {
  destroyService(service);
  free(service);
}
```