ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movl   $0x0,0xd0(%rsp)
  lea    0x70(%rsp),%rbx
  mov    %rsp,%rbp
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  lea    D2(%rip),%rsi
  lea    D36(%rip),%r12
  mov    %r12,%rdi
  call   <sscanf@plt>
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  lea    D11(%rip),%rsi
  mov    %r12,%rdi
  call   <sscanf@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string
name: extract_symbolic_data
arguments: data_tag: D36
datatype: string
name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D2: %[0-9,:] - %[0-9,:]

tool: D36: 2006:03:18 -2006:04:18

tool: D11: %[0-9,:]-%[0-9,:]

tool: D7: %s


assistant: ```c
int main() {
  char *p_time = "2006:03:18 -2006:04:18";
  char sz_time1[100] = {0};
  char sz_time2[100] = {0};
  sscanf(p_time, "%[0-9,:] - %[0-9,:]", sz_time1, sz_time2);
  sscanf(p_time, "%[0-9,:]-%[0-9,:]", sz_time1, sz_time2);
  printf("%s\n", sz_time1);
  printf("%s\n", sz_time2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  pxor   %xmm0,%xmm0
  lea    D36(%rip),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x70(%rsp),%rbp
  movaps %xmm0,(%rsp)
  mov    %r12,%rdx
  mov    %rbp,%rcx
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movl   $0x0,0x60(%rsp)
  movl   $0x0,0xd0(%rsp)
  call   <sscanf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rcx
  mov    %r13,%rdi
  lea    D28(%rip),%rsi
  call   <sscanf@plt>
  mov    %r12,%rsi
  lea    D21(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_guessed: string
name: unpack_data
arguments: data_label: D36
type_guessed: string
name: unpack_data
arguments: data_label: D28
type_guessed: string
name: unpack_data
arguments: data_label: D21
type_guessed: string

tool: D19: 2006:03:18 -2006:04:18

tool: D36: %[0-9,:] - %[0-9,:]

tool: D28: %[0-9,:]-%[0-9,:]

tool: D21: %s


assistant: ```c
int main() {
  char *p_time = "2006:03:18 -2006:04:18";
  char sz_time1[100] = {0};
  char sz_time2[100] = {0};
  sscanf(p_time, "%[0-9,:] - %[0-9,:]", sz_time1, sz_time2);
  sscanf(p_time, "%[0-9,:]-%[0-9,:]", sz_time1, sz_time2);
  printf("%s\n", sz_time1);
  printf("%s\n", sz_time2);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  pxor   %xmm0,%xmm0
  lea    D38(%rip),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x70(%rsp),%rbp
  movaps %xmm0,(%rsp)
  mov    %r12,%rdx
  mov    %rbp,%rcx
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movl   $0x0,0x60(%rsp)
  movl   $0x0,0xd0(%rsp)
  call   <sscanf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rcx
  mov    %r13,%rdi
  lea    D25(%rip),%rsi
  call   <sscanf@plt>
  mov    %r12,%rsi
  lea    D28(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D38
type_guessed: string
name: disassemble_data
arguments: tag: D25
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string

tool: D6: 2006:03:18 -2006:04:18

tool: D38: %[0-9,:] - %[0-9,:]

tool: D25: %[0-9,:]-%[0-9,:]

tool: D28: %s


assistant: ```c
int main() {
  char *p_time = "2006:03:18 -2006:04:18";
  char sz_time1[100] = {0};
  char sz_time2[100] = {0};
  sscanf(p_time, "%[0-9,:] - %[0-9,:]", sz_time1, sz_time2);
  sscanf(p_time, "%[0-9,:]-%[0-9,:]", sz_time1, sz_time2);
  printf("%s\n", sz_time1);
  printf("%s\n", sz_time2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memory_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  cmpq   $0x0,-0x10(%rbp)
  je     L8
  mov    $0x1,%eax
  jmp    L4
L8:
  mov    $0x0,%eax
L4:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void memory_copy(void *dst, const void *src, size_t size, size_t count) {
  assert(dst && src);
  memcpy(dst, src, size * count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memory_copy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%r13
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  imul   %r13,%rbx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void memory_copy(void *dst, const void *src, size_t size, size_t count) {
  assert(dst && src);
  memcpy(dst, src, size * count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memory_copy>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  imul   %r13,%rbx
  and    %eax,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <memcpy@plt>
```

assistant: ```c
void memory_copy(void *dst, const void *src, size_t size, size_t count) {
  assert(dst && src);
  memcpy(dst, src, size * count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memory_copy>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  imul   %r13,%rbx
  and    %eax,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <memcpy@plt>
```

assistant: ```c
void memory_copy(void *dst, const void *src, size_t size, size_t count) {
  assert(dst && src);
  memcpy(dst, src, size * count);
}
```
user: What is the c source code of the assembly code below:

```asm
<bee_flock_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L2:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: bee_flock_close: close

assistant: ```c
int bee_flock_close(int fd) {
  int res;
  res = close(fd);
  if (res < 0)
    perror("bee_flock_close: close");
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bee_flock_close>:
  endbr64
  push   %rbx
  call   <close@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L9
L14:
  mov    %ebx,%eax
  pop    %rbx
  ret
L9:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: bee_flock_close: close

assistant: ```c
int bee_flock_close(int fd) {
  int res;
  res = close(fd);
  if (res < 0)
    perror("bee_flock_close: close");
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bee_flock_close>:
  endbr64
  push   %r12
  call   <close@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L1
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D5: bee_flock_close: close

assistant: ```c
int bee_flock_close(int fd) {
  int res;
  res = close(fd);
  if (res < 0)
    perror("bee_flock_close: close");
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bee_flock_close>:
  endbr64
  push   %r12
  call   <close@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L7
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: bee_flock_close: close

assistant: ```c
int bee_flock_close(int fd) {
  int res;
  res = close(fd);
  if (res < 0)
    perror("bee_flock_close: close");
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <check_not_null@plt>
  leave
  ret
```

assistant: ```c
void *xmalloc(size_t size) {
  void *result = malloc(size);
  return (check_not_null(result));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xmalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <check_not_null@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *xmalloc(size_t size) {
  void *result = malloc(size);
  return (check_not_null(result));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xmalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <check_not_null@plt>
```

assistant: ```c
void *xmalloc(size_t size) {
  void *result = malloc(size);
  return (check_not_null(result));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xmalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <check_not_null@plt>
```

assistant: ```c
void *xmalloc(size_t size) {
  void *result = malloc(size);
  return (check_not_null(result));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gatsa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1f4,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: Hey gatsa


assistant: ```c
int gatsa() {
  printf("Hey gatsa\n");
  return 500;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gatsa>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1f4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: Hey gatsa


assistant: ```c
int gatsa() {
  printf("Hey gatsa\n");
  return 500;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gatsa>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1f4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: Hey gatsa


assistant: ```c
int gatsa() {
  printf("Hey gatsa\n");
  return 500;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gatsa>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1f4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: Hey gatsa


assistant: ```c
int gatsa() {
  printf("Hey gatsa\n");
  return 500;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  jmp    L17
L7:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  cmpl   $0x2bb,-0x4(%rbp)
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: hellooooo!

assistant: ```c
int main() {
  int x = 10;
  while (x < 700) {
    printf("hellooooo!");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
L6:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: hellooooo!

assistant: ```c
int main() {
  int x = 10;
  while (x < 700) {
    printf("hellooooo!");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  nopl   0x0(%rax)
L8:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: hellooooo!

assistant: ```c
int main() {
  int x = 10;
  while (x < 700) {
    printf("hellooooo!");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: hellooooo!

assistant: ```c
int main() {
  int x = 10;
  while (x < 700) {
    printf("hellooooo!");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <intro@plt>
L43:
  lea    -0x30(%rbp),%rdx
  lea    -0x1c0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <setup@plt>
  movb   $0x61,-0x1cd(%rbp)
  movl   $0x0,-0x1c8(%rbp)
  movl   $0x0,-0x1c4(%rbp)
L14:
  lea    -0x30(%rbp),%rcx
  lea    -0x1c0(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <drawbox@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1cc(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1cc(%rbp),%eax
  test   %eax,%eax
  je     L6
  mov    -0x1cc(%rbp),%eax
  cmp    $0x1f,%eax
  jg     L6
  mov    -0x1cc(%rbp),%eax
  lea    -0x1c0(%rbp),%rcx
  lea    -0x1cd(%rbp),%rdx
  lea    -0x30(%rbp),%rsi
  mov    %eax,%edi
  call   <shoot@plt>
  mov    %eax,%edx
  mov    -0x1c8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c8(%rbp)
L6:
  mov    -0x1cc(%rbp),%eax
  test   %eax,%eax
  jne    L41
  lea    -0x1c8(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  lea    -0x1c0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <endgame@plt>
  mov    %eax,-0x1c4(%rbp)
L41:
  cmpl   $0x0,-0x1c4(%rbp)
  je     L14
  mov    $0x0,%eax
  call   <playmore@plt>
  test   %rax,%rax
  jne    L43
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D14
datatype: string

tool: D11: Ray # ? 

tool: D4: %d

tool: D14: Goodbye!

assistant: ```c
int main(void) {
  int board[8 + 2][8 + 2], ray, score, done;
  char hints[8 * 4];
  char token;
  srand(time(NULL));
  intro();
  do {
    setup(board, hints);
    token = 'a';
    score = 0;
    done = 0;
    do {
      drawbox(board, hints, 1);
      printf("Ray # ? ");
      scanf("%d", &ray);
      if (ray && ray < 4 * 8)
        score += shoot(ray, hints, &token, board);
      if (!ray)
        done = endgame(board, hints, &score);
    } while (!done);
  } while (playmore());
  puts("Goodbye!");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1d8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <intro@plt>
  lea    0x1a0(%rsp),%rbp
  lea    0x10(%rsp),%rbx
  lea    D22(%rip),%r13
  lea    D29(%rip),%r12
  jmp    L7
L66:
  cmpl   $0x0,0x8(%rsp)
  je     L37
L49:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <drawbox@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  test   %edi,%edi
  je     L66
  cmp    $0x1f,%edi
  jg     L66
  lea    0x7(%rsp),%rdx
  mov    %rbx,%rcx
  mov    %rbp,%rsi
  call   <shoot@plt>
  add    %eax,0xc(%rsp)
  jmp    L66
L37:
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <endgame@plt>
  test   %eax,%eax
  je     L49
  mov    $0x0,%eax
  call   <playmore@plt>
  test   %rax,%rax
  je     L6
L7:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <setup@plt>
  movb   $0x61,0x7(%rsp)
  movl   $0x0,0xc(%rsp)
  jmp    L49
L6:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0x1d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D22
type_infered: string
name: disassemble_data
arguments: tag: D29
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D22: Ray # ? 

tool: D29: %d

tool: D9: Goodbye!

assistant: ```c
int main(void) {
  int board[8 + 2][8 + 2], ray, score, done;
  char hints[8 * 4];
  char token;
  srand(time(NULL));
  intro();
  do {
    setup(board, hints);
    token = 'a';
    score = 0;
    done = 0;
    do {
      drawbox(board, hints, 1);
      printf("Ray # ? ");
      scanf("%d", &ray);
      if (ray && ray < 4 * 8)
        score += shoot(ray, hints, &token, board);
      if (!ray)
        done = endgame(board, hints, &score);
    } while (!done);
  } while (playmore());
  puts("Goodbye!");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1d8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  lea    0x18(%rsp),%r13
  call   <time@plt>
  lea    0x1b0(%rsp),%rbp
  lea    0x1c(%rsp),%r15
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <intro@plt>
  lea    0x17(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L25:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <setup@plt>
  movb   $0x61,0x17(%rsp)
  movl   $0x0,0x1c(%rsp)
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <drawbox@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%edi
  test   %edi,%edi
  je     L50
  cmp    $0x1f,%edi
  jg     L58
  mov    0x8(%rsp),%rdx
  mov    %rbx,%rcx
  mov    %rbp,%rsi
  call   <shoot@plt>
  add    %eax,0x1c(%rsp)
  mov    0x18(%rsp),%edi
L58:
  test   %edi,%edi
  jne    L17
  nopl   0x0(%rax)
L50:
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <endgame@plt>
  test   %eax,%eax
  je     L17
  xor    %eax,%eax
  call   <playmore@plt>
  test   %rax,%rax
  jne    L25
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x1d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x1e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D17: Ray # ? 

tool: D15: %d

tool: D0: Goodbye!

assistant: ```c
int main(void) {
  int board[8 + 2][8 + 2], ray, score, done;
  char hints[8 * 4];
  char token;
  srand(time(NULL));
  intro();
  do {
    setup(board, hints);
    token = 'a';
    score = 0;
    done = 0;
    do {
      drawbox(board, hints, 1);
      printf("Ray # ? ");
      scanf("%d", &ray);
      if (ray && ray < 4 * 8)
        score += shoot(ray, hints, &token, board);
      if (!ray)
        done = endgame(board, hints, &score);
    } while (!done);
  } while (playmore());
  puts("Goodbye!");
  exit(0);
}
```