ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<file_size>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  cmp    $0x3ff,%rdi
  jle    L2
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  cmp    $0xfffff,%rdi
  jle    L6
  cmp    $0x3fffffff,%rdi
  jg     L26
  mulsd  D31(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x8,%esi
  lea    D4(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L6:
  mulsd  D51(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x8,%esi
  lea    D19(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  test   %rdi,%rdi
  js     L24
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L32:
  mov    %r12,%rdi
  lea    D65(%rip),%rdx
  mov    $0x8,%esi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
L26:
  mulsd  D17(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x8,%esi
  lea    D1(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L32
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D51
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D65
type_guessed: string
name: extract_symbolic_data
arguments: tag: D17
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0xb0,0x3e]}

tool: D4: %.1fM

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D19: %.1fK

tool: D65: %luB

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: D1: %.1fG

assistant: ```c
char *file_size(long long size, char *str) {
  if (size < 1024) {
    snprintf(str, sizeof(str), "%luB", (unsigned long)size);
  } else if (size < 0x100000) {
    snprintf(str, sizeof(str), "%.1fK", (double)size / 1024.0);
  } else if (size < 0x40000000) {
    snprintf(str, sizeof(str), "%.1fM", (double)size / 1048576);
  } else {
    snprintf(str, sizeof(str), "%.1fG", (double)size / 1073741824);
  }
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_positive@plt>
  test   %eax,%eax
  jne    L4
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    $0x0,%eax
  call   <test_negative@plt>
  test   %eax,%eax
  jne    L8
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D25: Power of ten test failed!

tool: D6: Not power of ten test failed!

tool: D3: %d tests failed.


assistant: ```c
int main() {
  int counter = 0;
  if (!test_positive()) {
    printf("Power of ten test failed!\n");
    counter++;
  }
  if (!test_negative()) {
    printf("Not power of ten test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <test_positive@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  je     L31
L0:
  mov    $0x0,%eax
  call   <test_negative@plt>
  test   %eax,%eax
  je     L13
L34:
  mov    %ebx,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L31:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  jmp    L0
L13:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%ebx
  jmp    L34
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
datatype: string
name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string

tool: D19: %d tests failed.


tool: D1: Power of ten test failed!

tool: D27: Not power of ten test failed!

assistant: ```c
int main() {
  int counter = 0;
  if (!test_positive()) {
    printf("Power of ten test failed!\n");
    counter++;
  }
  if (!test_negative()) {
    printf("Not power of ten test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <test_positive@plt>
  test   %eax,%eax
  je     L30
L16:
  xor    %eax,%eax
  call   <test_negative@plt>
  test   %eax,%eax
  je     L5
L26:
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L30:
  lea    D21(%rip),%rdi
  mov    $0x1,%ebp
  call   <puts@plt>
  jmp    L16
L5:
  lea    D19(%rip),%rdi
  add    $0x1,%ebp
  call   <puts@plt>
  jmp    L26
```

tool_calls: name: parse_data
arguments: tag: D14
type_infered: string
name: parse_data
arguments: tag: D21
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string

tool: D14: %d tests failed.


tool: D21: Power of ten test failed!

tool: D19: Not power of ten test failed!

assistant: ```c
int main() {
  int counter = 0;
  if (!test_positive()) {
    printf("Power of ten test failed!\n");
    counter++;
  }
  if (!test_negative()) {
    printf("Not power of ten test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <test_positive@plt>
  test   %eax,%eax
  je     L23
L9:
  xor    %eax,%eax
  call   <test_negative@plt>
  test   %eax,%eax
  je     L20
L7:
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L23:
  lea    D14(%rip),%rdi
  mov    $0x1,%ebp
  call   <puts@plt>
  jmp    L9
L20:
  lea    D23(%rip),%rdi
  add    $0x1,%ebp
  call   <puts@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_label: D16
data_type: string
name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string

tool: D16: %d tests failed.


tool: D14: Power of ten test failed!

tool: D23: Not power of ten test failed!

assistant: ```c
int main() {
  int counter = 0;
  if (!test_positive()) {
    printf("Power of ten test failed!\n");
    counter++;
  }
  if (!test_negative()) {
    printf("Not power of ten test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<imx_uart_putc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  mov    %rax,%rdi
  call   <readl@plt>
  and    $0x1,%eax
  test   %eax,%eax
  je     L20
  nop
L3:
  mov    -0x8(%rbp),%rax
  add    $0x98,%rax
  mov    %rax,%rdi
  call   <readl@plt>
  and    $0x8,%eax
  test   %eax,%eax
  je     L3
  mov    -0x8(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <writel@plt>
  jmp    L0
L20:
  nop
L0:
  leave
  ret
```

assistant: ```c
void imx_uart_putc(void *base, int c) {
  if (!(readl(base + 0x80) & (1 << 0)))
    return;
  while (!(readl(base + 0x98) & (1 << 3)))
    ;
  writel(c, base + 0x40);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<imx_uart_putc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    0x80(%rdi),%rdi
  call   <readl@plt>
  test   $0x1,%al
  je     L7
  lea    0x98(%rbp),%rbx
L14:
  mov    %rbx,%rdi
  call   <readl@plt>
  test   $0x8,%al
  je     L14
  lea    0x40(%rbp),%rsi
  mov    %r12d,%edi
  call   <writel@plt>
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void imx_uart_putc(void *base, int c) {
  if (!(readl(base + 0x80) & (1 << 0)))
    return;
  while (!(readl(base + 0x98) & (1 << 3)))
    ;
  writel(c, base + 0x40);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<imx_uart_putc>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0xffffffffffffff80,%rdi
  push   %rbx
  call   <readl@plt>
  test   $0x1,%al
  je     L18
  lea    0x98(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbx,%rdi
  call   <readl@plt>
  test   $0x8,%al
  je     L14
  pop    %rbx
  lea    0x40(%rbp),%rsi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <writel@plt>
  nopl   0x0(%rax)
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void imx_uart_putc(void *base, int c) {
  if (!(readl(base + 0x80) & (1 << 0)))
    return;
  while (!(readl(base + 0x98) & (1 << 3)))
    ;
  writel(c, base + 0x40);
}
```
user: What is the c source code of the assembly code below?

```asm
<imx_uart_putc>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0xffffffffffffff80,%rdi
  push   %rbx
  call   <readl@plt>
  test   $0x1,%al
  je     L19
  lea    0x98(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  call   <readl@plt>
  test   $0x8,%al
  je     L11
  pop    %rbx
  lea    0x40(%rbp),%rsi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <writel@plt>
  nopl   0x0(%rax)
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void imx_uart_putc(void *base, int c) {
  if (!(readl(base + 0x80) & (1 << 0)))
    return;
  while (!(readl(base + 0x98) & (1 << 3)))
    ;
  writel(c, base + 0x40);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcasechr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  jmp    L39
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <chrlcaps@plt>
  mov    %rax,%rbx
  movsbl -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <chrlcaps@plt>
  cmp    %rax,%rbx
  je     L22
  addq   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  jmp    L18
L22:
  nop
L18:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strcasechr(char *in, char c) {
  while (*in) {
    if (chrlcaps(*in) == chrlcaps(c))
      break;
    in++;
  }
  return in;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcasechr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L13
  movsbl %sil,%r12d
L28:
  movsbl %dil,%edi
  call   <chrlcaps@plt>
  mov    %rax,%rbx
  mov    %r12d,%edi
  call   <chrlcaps@plt>
  cmp    %rax,%rbx
  je     L25
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L28
  mov    %rbp,%rax
  jmp    L1
L13:
  mov    %rbp,%rax
  jmp    L1
L25:
  mov    %rbp,%rax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcasechr(char *in, char c) {
  while (*in) {
    if (chrlcaps(*in) == chrlcaps(c))
      break;
    in++;
  }
  return in;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcasechr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L34
  movsbl %sil,%ebp
  jmp    L30
  nopl   0x0(%rax)
L11:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L34
L30:
  call   <chrlcaps@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <chrlcaps@plt>
  cmp    %rax,%rbx
  jne    L11
L34:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcasechr(char *in, char c) {
  while (*in) {
    if (chrlcaps(*in) == chrlcaps(c))
      break;
    in++;
  }
  return in;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcasechr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L23
  movsbl %sil,%ebp
  jmp    L11
  nopl   0x0(%rax)
L7:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L23
L11:
  call   <chrlcaps@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <chrlcaps@plt>
  cmp    %rax,%rbx
  jne    L7
L23:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcasechr(char *in, char c) {
  while (*in) {
    if (chrlcaps(*in) == chrlcaps(c))
      break;
    in++;
  }
  return in;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lah>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  jne    L80
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  jmp    L0
L80:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L29
  mov    $0x1,%eax
  jmp    L0
L29:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L66
  mov    $0x0,%eax
  jmp    L0
L66:
  cmpl   $0x0,-0x18(%rbp)
  jle    L85
  cmpl   $0x0,-0x14(%rbp)
  jg     L77
L85:
  mov    $0x0,%eax
  jmp    L0
L77:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial@plt>
  imul   %eax,%ebx
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,%r12d
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %r12d,%edx
  imul   %eax,%edx
  mov    %edx,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  mov    %ebx,%eax
  cltd
  idiv   %esi
L0:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
uint64_t lah(uint64_t n, uint64_t k) {
  if (k == 1)
    return factorial(n);
  if (k == n)
    return 1;
  if (k > n)
    return 0;
  if (k < 1 || n < 1)
    return 0;
  return (factorial(n) * factorial(n - 1)) / (factorial(k) * factorial(k - 1)) / factorial(n - k);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lah>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  cmp    $0x1,%esi
  je     L14
  mov    %esi,%ebx
  mov    $0x1,%eax
  cmp    %edi,%esi
  je     L49
  mov    $0x0,%eax
  jg     L49
  test   %esi,%esi
  jle    L64
  test   %edi,%edi
  jle    L64
  call   <factorial@plt>
  mov    %eax,%ebp
  lea    -0x1(%r12),%edi
  call   <factorial@plt>
  imul   %eax,%ebp
  mov    %ebx,%edi
  call   <factorial@plt>
  mov    %eax,%r13d
  lea    -0x1(%rbx),%edi
  call   <factorial@plt>
  mov    %r13d,%ecx
  imul   %eax,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebp
  mov    %r12d,%edi
  sub    %ebx,%edi
  call   <factorial@plt>
  mov    %eax,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  jmp    L49
L14:
  call   <factorial@plt>
  jmp    L49
L64:
  mov    $0x0,%eax
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint64_t lah(uint64_t n, uint64_t k) {
  if (k == 1)
    return factorial(n);
  if (k == n)
    return 1;
  if (k > n)
    return 0;
  if (k < 1 || n < 1)
    return 0;
  return (factorial(n) * factorial(n - 1)) / (factorial(k) * factorial(k - 1)) / factorial(n - k);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lah>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L17
  mov    %esi,%ebx
  mov    $0x1,%eax
  cmp    %edi,%esi
  je     L47
  mov    $0x0,%eax
  jg     L47
  test   %esi,%esi
  jle    L29
  test   %edi,%edi
  jle    L29
  call   <factorial@plt>
  lea    -0x1(%r12),%edi
  mov    %eax,%ebp
  call   <factorial@plt>
  mov    %ebx,%edi
  imul   %eax,%ebp
  call   <factorial@plt>
  lea    -0x1(%rbx),%edi
  mov    %eax,%r13d
  call   <factorial@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edi
  imul   %eax,%ecx
  mov    %ebp,%eax
  sub    %ebx,%edi
  cltd
  idiv   %ecx
  mov    %eax,%ebp
  call   <factorial@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  cltd
  idiv   %r8d
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <factorial@plt>
```

assistant: ```c
uint64_t lah(uint64_t n, uint64_t k) {
  if (k == 1)
    return factorial(n);
  if (k == n)
    return 1;
  if (k > n)
    return 0;
  if (k < 1 || n < 1)
    return 0;
  return (factorial(n) * factorial(n - 1)) / (factorial(k) * factorial(k - 1)) / factorial(n - k);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lah>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L41
  mov    %esi,%ebx
  mov    $0x1,%eax
  cmp    %edi,%esi
  je     L26
  mov    $0x0,%eax
  jg     L26
  test   %esi,%esi
  jle    L35
  test   %edi,%edi
  jle    L35
  call   <factorial@plt>
  lea    -0x1(%r12),%edi
  mov    %eax,%ebp
  call   <factorial@plt>
  mov    %ebx,%edi
  imul   %eax,%ebp
  call   <factorial@plt>
  lea    -0x1(%rbx),%edi
  mov    %eax,%r13d
  call   <factorial@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edi
  imul   %eax,%ecx
  mov    %ebp,%eax
  sub    %ebx,%edi
  cltd
  idiv   %ecx
  mov    %eax,%ebp
  call   <factorial@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  cltd
  idiv   %r8d
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L35:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <factorial@plt>
```

assistant: ```c
uint64_t lah(uint64_t n, uint64_t k) {
  if (k == 1)
    return factorial(n);
  if (k == n)
    return 1;
  if (k > n)
    return 0;
  if (k < 1 || n < 1)
    return 0;
  return (factorial(n) * factorial(n - 1)) / (factorial(k) * factorial(k - 1)) / factorial(n - k);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy_aligned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x40,-0x28(%rbp)
  ja     L55
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L47
L55:
  cmpq   $0x80,-0x28(%rbp)
  ja     L41
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  lea    0x40(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    $0x40,%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L47
L41:
  movq   $0x0,-0x8(%rbp)
  jmp    L53
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x40,-0x8(%rbp)
L53:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L1
L47:
  nop
  leave
  ret
```

assistant: ```c
void memcpy_aligned(void *to, const void *from, size_t len) {
  if (len <= 64) {
    memcpy(to, from, 64);
  } else if (len <= 128) {
    memcpy(to, from, 64);
    memcpy((uint8_t *)to + 64, (uint8_t *)from + 64, 64);
  } else {
    size_t offset;
    for (offset = 0; offset < len; offset += 64)
      memcpy((uint8_t *)to + offset, (uint8_t *)from + offset, 64);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy_aligned>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  cmp    $0x40,%rdx
  jbe    L39
  mov    %rdx,%rbp
  mov    $0x0,%ebx
  cmp    $0x80,%rdx
  jbe    L4
L25:
  lea    0x0(%r13,%rbx,1),%rsi
  lea    (%r12,%rbx,1),%rdi
  mov    $0x40,%edx
  call   <memcpy@plt>
  add    $0x40,%rbx
  cmp    %rbx,%rbp
  ja     L25
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    $0x40,%edx
  call   <memcpy@plt>
  jmp    L6
L4:
  mov    $0x40,%edx
  call   <memcpy@plt>
  lea    0x40(%r13),%rsi
  lea    0x40(%r12),%rdi
  mov    $0x40,%edx
  call   <memcpy@plt>
  jmp    L6
```

assistant: ```c
void memcpy_aligned(void *to, const void *from, size_t len) {
  if (len <= 64) {
    memcpy(to, from, 64);
  } else if (len <= 128) {
    memcpy(to, from, 64);
    memcpy((uint8_t *)to + 64, (uint8_t *)from + 64, 64);
  } else {
    size_t offset;
    for (offset = 0; offset < len; offset += 64)
      memcpy((uint8_t *)to + offset, (uint8_t *)from + offset, 64);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcpy_aligned>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x40,%rdx
  jbe    L3
  mov    %rdx,%rbp
  xor    %ebx,%ebx
  cmp    $0x80,%rdx
  jbe    L13
  nopl   0x0(%rax,%rax,1)
L25:
  lea    0x0(%r13,%rbx,1),%rsi
  lea    (%r12,%rbx,1),%rdi
  mov    $0x40,%edx
  add    $0x40,%rbx
  call   <memcpy@plt>
  cmp    %rbx,%rbp
  ja     L25
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0x40,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    0x40(%r13),%rsi
  lea    0x40(%r12),%rdi
  pop    %rbx
  mov    $0x40,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <memcpy@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  mov    $0x40,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void memcpy_aligned(void *to, const void *from, size_t len) {
  if (len <= 64) {
    memcpy(to, from, 64);
  } else if (len <= 128) {
    memcpy(to, from, 64);
    memcpy((uint8_t *)to + 64, (uint8_t *)from + 64, 64);
  } else {
    size_t offset;
    for (offset = 0; offset < len; offset += 64)
      memcpy((uint8_t *)to + offset, (uint8_t *)from + offset, 64);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memcpy_aligned>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x40,%rdx
  jbe    L28
  mov    %rdx,%rbp
  xor    %ebx,%ebx
  cmp    $0x80,%rdx
  jbe    L2
  nopl   0x0(%rax,%rax,1)
L19:
  lea    0x0(%r13,%rbx,1),%rsi
  lea    (%r12,%rbx,1),%rdi
  mov    $0x40,%edx
  add    $0x40,%rbx
  call   <memcpy@plt>
  cmp    %rbx,%rbp
  ja     L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x40,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    0x40(%r13),%rsi
  lea    0x40(%r12),%rdi
  pop    %rbx
  mov    $0x40,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <memcpy@plt>
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x8,%rsp
  mov    $0x40,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void memcpy_aligned(void *to, const void *from, size_t len) {
  if (len <= 64) {
    memcpy(to, from, 64);
  } else if (len <= 128) {
    memcpy(to, from, 64);
    memcpy((uint8_t *)to + 64, (uint8_t *)from + 64, 64);
  } else {
    size_t offset;
    for (offset = 0; offset < len; offset += 64)
      memcpy((uint8_t *)to + offset, (uint8_t *)from + offset, 64);
  }
}
```