ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rmult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8d,-0x40(%rbp)
  mov    %r9d,-0x44(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  imul   -0x44(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%ebx
  jmp    L8
L10:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  add    $0x1,%ebx
L8:
  cmp    -0x14(%rbp),%ebx
  jl     L10
  mov    -0x44(%rbp),%r9d
  mov    -0x40(%rbp),%r8d
  mov    -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x18(%rbp),%edi
  push   %rdi
  mov    -0x1c(%rbp),%edi
  push   %rdi
  mov    -0x20(%rbp),%edi
  push   %rdi
  mov    %rax,%rdi
  call   <recmult@plt>
  add    $0x20,%rsp
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void rmult(float *A, float *B, float *C, int m, int n, int p) {
  int strA, strB, strC;
  int N;
  register int i;
  strA = m;
  strB = n;
  strC = p;
  N = m * p;
  for (i = 0; i < N; ++i) {
    C[i] = 0.;
  }
  recmult(A, B, C, m, n, p, strA, strB, strC);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rmult>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%r10
  mov    %rdx,%rsi
  mov    %ecx,%edx
  imul   %r9d,%edx
  test   %edx,%edx
  jle    L18
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rsi,%rdx,4),%rdx
L8:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L8
L18:
  sub    $0x8,%rsp
  push   %r9
  push   %r8
  push   %rcx
  mov    %rsi,%rdx
  mov    %r10,%rsi
  call   <recmult@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void rmult(float *A, float *B, float *C, int m, int n, int p) {
  int strA, strB, strC;
  int N;
  register int i;
  strA = m;
  strB = n;
  strC = p;
  N = m * p;
  for (i = 0; i < N; ++i) {
    C[i] = 0.;
  }
  recmult(A, B, C, m, n, p, strA, strB, strC);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rmult>:
  endbr64
  mov    %rdx,%r10
  mov    %ecx,%edx
  push   %r14
  mov    %r8d,%r14d
  imul   %r9d,%edx
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r9d,%ebx
  test   %edx,%edx
  jle    L0
  movslq %edx,%rdx
  mov    %r10,%rdi
  xor    %esi,%esi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rax,%r10
L0:
  sub    $0x8,%rsp
  mov    %ebx,%r9d
  mov    %r14d,%r8d
  mov    %r12d,%ecx
  push   %rbx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %r10,%rdx
  push   %r14
  push   %r12
  call   <recmult@plt>
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rmult(float *A, float *B, float *C, int m, int n, int p) {
  int strA, strB, strC;
  int N;
  register int i;
  strA = m;
  strB = n;
  strC = p;
  N = m * p;
  for (i = 0; i < N; ++i) {
    C[i] = 0.;
  }
  recmult(A, B, C, m, n, p, strA, strB, strC);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rmult>:
  endbr64
  mov    %rdx,%r10
  mov    %ecx,%edx
  push   %r14
  mov    %r8d,%r14d
  imul   %r9d,%edx
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r9d,%ebx
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  mov    %r10,%rdi
  xor    %esi,%esi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rax,%r10
L2:
  sub    $0x8,%rsp
  mov    %ebx,%r9d
  mov    %r14d,%r8d
  mov    %r12d,%ecx
  push   %rbx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %r10,%rdx
  push   %r14
  push   %r12
  call   <recmult@plt>
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rmult(float *A, float *B, float *C, int m, int n, int p) {
  int strA, strB, strC;
  int N;
  register int i;
  strA = m;
  strB = n;
  strC = p;
  N = m * p;
  for (i = 0; i < N; ++i) {
    C[i] = 0.;
  }
  recmult(A, B, C, m, n, p, strA, strB, strC);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cornet_debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <taskprintall@plt>
  mov    $0x0,%eax
  call   <fdprintfdpoll@plt>
  nop
  leave
  ret
```

assistant: ```c
void cornet_debug(int fd) {
  taskprintall(fd);
  fdprintfdpoll();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cornet_debug>:
  endbr64
  sub    $0x8,%rsp
  call   <taskprintall@plt>
  mov    $0x0,%eax
  call   <fdprintfdpoll@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cornet_debug(int fd) {
  taskprintall(fd);
  fdprintfdpoll();
}
```
user: What is the c source code of the assembly code below:

```asm
<cornet_debug>:
  endbr64
  sub    $0x8,%rsp
  call   <taskprintall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <fdprintfdpoll@plt>
```

assistant: ```c
void cornet_debug(int fd) {
  taskprintall(fd);
  fdprintfdpoll();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cornet_debug>:
  endbr64
  sub    $0x8,%rsp
  call   <taskprintall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <fdprintfdpoll@plt>
```

assistant: ```c
void cornet_debug(int fd) {
  taskprintall(fd);
  fdprintfdpoll();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<space_big_enough_q>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <getmaxyx@plt>
  cmpl   $0xb,-0x4(%rbp)
  jle    L8
  cmpl   $0x2f,-0x8(%rbp)
  jle    L8
  mov    $0x1,%eax
  jmp    L11
L8:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int space_big_enough_q() {
  int maxx = 0, maxy = 0;
  getmaxyx(stdscr, maxy, maxx);
  return ((maxy >= 12) && (maxx >= 48));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<space_big_enough_q>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int space_big_enough_q() {
  int maxx = 0, maxy = 0;
  getmaxyx(stdscr, maxy, maxx);
  return ((maxy >= 12) && (maxx >= 48));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<space_big_enough_q>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  xor    %edx,%edx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int space_big_enough_q() {
  int maxx = 0, maxy = 0;
  getmaxyx(stdscr, maxy, maxx);
  return ((maxy >= 12) && (maxx >= 48));
}
```
user: What is the c source code of the assembly code below?

```asm
<space_big_enough_q>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  xor    %edx,%edx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int space_big_enough_q() {
  int maxx = 0, maxy = 0;
  getmaxyx(stdscr, maxy, maxx);
  return ((maxy >= 12) && (maxx >= 48));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MixColumn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x101030201010302,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <DotProduct@plt>
  mov    %al,-0x14(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <DotProduct@plt>
  mov    %al,-0x13(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <DotProduct@plt>
  mov    %al,-0x12(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <DotProduct@plt>
  mov    %al,-0x11(%rbp)
  movzbl -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0x13(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x2(%rax),%rdx
  movzbl -0x12(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void MixColumn(unsigned char *column) {
  unsigned char row[8] = {0x02, 0x03, 0x01, 0x01, 0x02, 0x03, 0x01, 0x01};
  unsigned char result[4];
  result[0] = DotProduct(row + 0, column);
  result[1] = DotProduct(row + 3, column);
  result[2] = DotProduct(row + 2, column);
  result[3] = DotProduct(row + 1, column);
  column[0] = result[0];
  column[1] = result[1];
  column[2] = result[2];
  column[3] = result[3];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MixColumn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x101030201010302,%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <DotProduct@plt>
  mov    %eax,%r13d
  lea    0x3(%rsp),%rdi
  mov    %rbx,%rsi
  call   <DotProduct@plt>
  mov    %eax,%r12d
  lea    0x2(%rsp),%rdi
  mov    %rbx,%rsi
  call   <DotProduct@plt>
  mov    %eax,%ebp
  lea    0x1(%rsp),%rdi
  mov    %rbx,%rsi
  call   <DotProduct@plt>
  mov    %r13b,(%rbx)
  mov    %r12b,0x1(%rbx)
  mov    %bpl,0x2(%rbx)
  mov    %al,0x3(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void MixColumn(unsigned char *column) {
  unsigned char row[8] = {0x02, 0x03, 0x01, 0x01, 0x02, 0x03, 0x01, 0x01};
  unsigned char result[4];
  result[0] = DotProduct(row + 0, column);
  result[1] = DotProduct(row + 3, column);
  result[2] = DotProduct(row + 2, column);
  result[3] = DotProduct(row + 1, column);
  column[0] = result[0];
  column[1] = result[1];
  column[2] = result[2];
  column[3] = result[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MixColumn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x101030201010302,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <DotProduct@plt>
  lea    0x3(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %eax,%r13d
  call   <DotProduct@plt>
  lea    0x2(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %eax,%r12d
  call   <DotProduct@plt>
  lea    0x1(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %eax,%ebp
  call   <DotProduct@plt>
  mov    %r13b,(%rbx)
  mov    %r12b,0x1(%rbx)
  mov    %bpl,0x2(%rbx)
  mov    %al,0x3(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void MixColumn(unsigned char *column) {
  unsigned char row[8] = {0x02, 0x03, 0x01, 0x01, 0x02, 0x03, 0x01, 0x01};
  unsigned char result[4];
  result[0] = DotProduct(row + 0, column);
  result[1] = DotProduct(row + 3, column);
  result[2] = DotProduct(row + 2, column);
  result[3] = DotProduct(row + 1, column);
  column[0] = result[0];
  column[1] = result[1];
  column[2] = result[2];
  column[3] = result[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<MixColumn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x101030201010302,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <DotProduct@plt>
  lea    0x3(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %eax,%r13d
  call   <DotProduct@plt>
  lea    0x2(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %eax,%r12d
  call   <DotProduct@plt>
  lea    0x1(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %eax,%ebp
  call   <DotProduct@plt>
  mov    %r13b,(%rbx)
  mov    %r12b,0x1(%rbx)
  mov    %bpl,0x2(%rbx)
  mov    %al,0x3(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void MixColumn(unsigned char *column) {
  unsigned char row[8] = {0x02, 0x03, 0x01, 0x01, 0x02, 0x03, 0x01, 0x01};
  unsigned char result[4];
  result[0] = DotProduct(row + 0, column);
  result[1] = DotProduct(row + 3, column);
  result[2] = DotProduct(row + 2, column);
  result[3] = DotProduct(row + 1, column);
  column[0] = result[0];
  column[1] = result[1];
  column[2] = result[2];
  column[3] = result[3];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  nop
  movl   $0x0,-0x8(%rbp)
  nop
  jmp    L6
L0:
  nop
L6:
  nop
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x9,-0x8(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int res = 0;
  goto L1;
  for (i = 0; i < 10; i++) {
  L2:
    goto L3;
  L1:
    i = 0;
    goto L2;
  L3:
    res++;
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int res = 0;
  goto L1;
  for (i = 0; i < 10; i++) {
  L2:
    goto L3;
  L1:
    i = 0;
    goto L2;
  L3:
    res++;
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int res = 0;
  goto L1;
  for (i = 0; i < 10; i++) {
  L2:
    goto L3;
  L1:
    i = 0;
    goto L2;
  L3:
    res++;
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int res = 0;
  goto L1;
  for (i = 0; i < 10; i++) {
  L2:
    goto L3;
  L1:
    i = 0;
    goto L2;
  L3:
    res++;
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <exact_square@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D3: %d

tool: D8: %d


assistant: ```c
int main() {
  int number;
  int square;
  scanf("%d", &number);
  square = exact_square(number);
  printf("%d\n", square);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string

tool: D0: %d

tool: D13: %d


assistant: ```c
int main() {
  int number;
  int square;
  scanf("%d", &number);
  square = exact_square(number);
  printf("%d\n", square);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type: string
name: disassemble_data
arguments: label: D9
type: string

tool: D10: %d

tool: D9: %d


assistant: ```c
int main() {
  int number;
  int square;
  scanf("%d", &number);
  square = exact_square(number);
  printf("%d\n", square);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D16
type: string

tool: D11: %d

tool: D16: %d


assistant: ```c
int main() {
  int number;
  int square;
  scanf("%d", &number);
  square = exact_square(number);
  printf("%d\n", square);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1000,%edi
  call   <Mem_Init@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x8,%edi
  call   <Mem_Alloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Mem_Free@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  assert(Mem_Init(4096) == 0);
  void *ptr = Mem_Alloc(8);
  assert(ptr != NULL);
  ptr = NULL;
  assert(Mem_Free(ptr) == -1);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000,%edi
  call   <Mem_Init@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x8,%edi
  call   <Mem_Alloc@plt>
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <Mem_Free@plt>
  cmp    $0xffffffff,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(Mem_Init(4096) == 0);
  void *ptr = Mem_Alloc(8);
  assert(ptr != NULL);
  ptr = NULL;
  assert(Mem_Free(ptr) == -1);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000,%edi
  call   <Mem_Init@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x8,%edi
  call   <Mem_Alloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <Mem_Free@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(Mem_Init(4096) == 0);
  void *ptr = Mem_Alloc(8);
  assert(ptr != NULL);
  ptr = NULL;
  assert(Mem_Free(ptr) == -1);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000,%edi
  call   <Mem_Init@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x8,%edi
  call   <Mem_Alloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <Mem_Free@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(Mem_Init(4096) == 0);
  void *ptr = Mem_Alloc(8);
  assert(ptr != NULL);
  ptr = NULL;
  assert(Mem_Free(ptr) == -1);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<F_ConvertArrayFromAsciiToNumeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L24
L36:
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <F_ConvertAsciiToNumeric@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <F_ConvertAsciiToNumeric@plt>
  shl    $0x4,%eax
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0xff,-0x14(%rbp)
  jle    L23
  mov    $0x0,%eax
  jmp    L15
L23:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x2,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L36
  mov    $0x1,%eax
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int8_t F_ConvertArrayFromAsciiToNumeric(int8_t A_Data[], int VF_DataSize, int8_t A_ConvertedData[]) {
  int VF_ArrayPos = 0;
  int VF_Result = 0;
  for (VF_ArrayPos = 0; VF_ArrayPos < VF_DataSize; VF_ArrayPos = VF_ArrayPos + 2) {
    VF_Result = F_ConvertAsciiToNumeric(A_Data[VF_ArrayPos + 1]) + ((F_ConvertAsciiToNumeric(A_Data[VF_ArrayPos])) << 4);
    if (VF_Result > 0xFF) {
      return 0;
    }
    A_ConvertedData[VF_ArrayPos / 2] = VF_Result;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<F_ConvertArrayFromAsciiToNumeric>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  sub    $0x1,%esi
  shr    %esi
  lea    0x1(%rsi),%r13d
  add    %r13,%r13
  mov    $0x0,%ebx
L38:
  mov    0x4(%rbp,%rbx,4),%edi
  call   <F_ConvertAsciiToNumeric@plt>
  mov    %eax,%r14d
  mov    0x0(%rbp,%rbx,4),%edi
  call   <F_ConvertAsciiToNumeric@plt>
  shl    $0x4,%eax
  add    %r14d,%eax
  cmp    $0xff,%eax
  jg     L31
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  movslq %edx,%rdx
  mov    %eax,(%r12,%rdx,4)
  add    $0x2,%rbx
  cmp    %r13,%rbx
  jne    L38
  mov    $0x1,%eax
  jmp    L33
L3:
  mov    $0x1,%eax
  ret
L31:
  mov    $0x0,%eax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int8_t F_ConvertArrayFromAsciiToNumeric(int8_t A_Data[], int VF_DataSize, int8_t A_ConvertedData[]) {
  int VF_ArrayPos = 0;
  int VF_Result = 0;
  for (VF_ArrayPos = 0; VF_ArrayPos < VF_DataSize; VF_ArrayPos = VF_ArrayPos + 2) {
    VF_Result = F_ConvertAsciiToNumeric(A_Data[VF_ArrayPos + 1]) + ((F_ConvertAsciiToNumeric(A_Data[VF_ArrayPos])) << 4);
    if (VF_Result > 0xFF) {
      return 0;
    }
    A_ConvertedData[VF_ArrayPos / 2] = VF_Result;
  }
  return 1;
}
```