ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<use_up_memory>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D36(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  call   <getrlimit@plt>
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  movl   $0xa00000,0x4(%rsp)
  call   <setrlimit@plt>
  xor    %eax,%eax
  call   <getpagesize@plt>
  mov    D25(%rip),%r14
  mov    D11(%rip),%r13
  mov    D40(%rip),%r12
  mov    D0(%rip),%rbp
  mov    %eax,%ebx
  nopl   (%rax)
L16:
  mov    (%r12),%edx
  mov    (%r14),%ecx
  xor    %r9d,%r9d
  xor    %edi,%edi
  or     0x0(%r13),%ecx
  mov    $0xffffffff,%r8d
  mov    %ebx,%esi
  call   <mmap@plt>
  cmp    %rax,0x0(%rbp)
  jne    L16
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void use_up_memory(void) {
  struct rlimit rl;
  getrlimit(RLIMIT_AS, &rl);
  rl.rlim_cur = 10 * 1024 * 1024;
  setrlimit(RLIMIT_AS, &rl);
  char *c;
  int PAGESIZE = getpagesize();
  while (1) {
    c = mmap(NULL, PAGESIZE, PROT_NONE, MAP_ANON | MAP_PRIVATE, -1, 0);
    if (c == MAP_FAILED)
      break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<use_up_memory>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D13(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  call   <getrlimit@plt>
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  movl   $0xa00000,0x4(%rsp)
  call   <setrlimit@plt>
  xor    %eax,%eax
  call   <getpagesize@plt>
  mov    D30(%rip),%r14
  mov    D22(%rip),%r13
  mov    D9(%rip),%r12
  mov    D25(%rip),%rbp
  mov    %eax,%ebx
  nopl   (%rax)
L6:
  mov    (%r12),%edx
  mov    (%r14),%ecx
  xor    %r9d,%r9d
  xor    %edi,%edi
  or     0x0(%r13),%ecx
  mov    $0xffffffff,%r8d
  mov    %ebx,%esi
  call   <mmap@plt>
  cmp    %rax,0x0(%rbp)
  jne    L6
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void use_up_memory(void) {
  struct rlimit rl;
  getrlimit(RLIMIT_AS, &rl);
  rl.rlim_cur = 10 * 1024 * 1024;
  setrlimit(RLIMIT_AS, &rl);
  char *c;
  int PAGESIZE = getpagesize();
  while (1) {
    c = mmap(NULL, PAGESIZE, PROT_NONE, MAP_ANON | MAP_PRIVATE, -1, 0);
    if (c == MAP_FAILED)
      break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L34
L3:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L41
  mov    D14(%rip),%rax
  mov    (%rax),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L66
  jmp    L34
L41:
  cmpq   $0x0,-0x8(%rbp)
  jne    L59
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  sub    %rdx,%rax
  jmp    L14
L59:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x10(%rbp)
L34:
  cmpq   $0x0,-0x10(%rbp)
  jg     L3
  jmp    L76
L66:
  nop
L76:
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  sub    %rdx,%rax
L14:
  leave
  ret
```

assistant: ```c
ssize_t writen(int s, const void *buf, size_t count) {
  char *p = (char *)buf;
  ssize_t len = count;
  ssize_t rv = 0;
  while (len > 0) {
    rv = write(s, p, len);
    if (rv == -1) {
      if (errno == EINTR)
        continue;
      break;
    }
    if (rv == 0)
      return count - len;
    p += rv;
    len -= rv;
  }
  return count - len;
}
```
user: What is the c source code of the assembly code below?

```asm
<writen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jg     L4
  jmp    L18
L11:
  mov    D13(%rip),%rdx
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L42
L18:
  mov    %r12,%rax
  sub    %rbx,%rax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    %r12,%rax
  sub    %rbx,%rax
  jmp    L31
L42:
  test   %rbx,%rbx
  jle    L18
L4:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L11
  test   %rax,%rax
  je     L12
  add    %rax,%rbp
  sub    %rax,%rbx
  jmp    L42
```

assistant: ```c
ssize_t writen(int s, const void *buf, size_t count) {
  char *p = (char *)buf;
  ssize_t len = count;
  ssize_t rv = 0;
  while (len > 0) {
    rv = write(s, p, len);
    if (rv == -1) {
      if (errno == EINTR)
        continue;
      break;
    }
    if (rv == 0)
      return count - len;
    p += rv;
    len -= rv;
  }
  return count - len;
}
```
user: What is the c source code of the assembly code below?

```asm
<writen>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jle    L36
L3:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L7
  test   %rax,%rax
  je     L60
  sub    %rax,%rbx
  add    %rax,%rbp
  test   %rbx,%rbx
  jg     L3
  nopl   0x0(%rax,%rax,1)
L60:
  mov    %r12,%rax
  sub    %rbx,%rax
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    D8(%rip),%rax
  mov    D19(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L60
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L36:
  xor    %eax,%eax
  jmp    L40
```

assistant: ```c
ssize_t writen(int s, const void *buf, size_t count) {
  char *p = (char *)buf;
  ssize_t len = count;
  ssize_t rv = 0;
  while (len > 0) {
    rv = write(s, p, len);
    if (rv == -1) {
      if (errno == EINTR)
        continue;
      break;
    }
    if (rv == 0)
      return count - len;
    p += rv;
    len -= rv;
  }
  return count - len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<writen>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jle    L50
L34:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L57
  test   %rax,%rax
  je     L9
  sub    %rax,%rbx
  add    %rax,%rbp
  test   %rbx,%rbx
  jg     L34
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rax
  sub    %rbx,%rax
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L57:
  mov    D11(%rip),%rax
  mov    D12(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L9
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L50:
  xor    %eax,%eax
  jmp    L42
```

assistant: ```c
ssize_t writen(int s, const void *buf, size_t count) {
  char *p = (char *)buf;
  ssize_t len = count;
  ssize_t rv = 0;
  while (len > 0) {
    rv = write(s, p, len);
    if (rv == -1) {
      if (errno == EINTR)
        continue;
      break;
    }
    if (rv == 0)
      return count - len;
    p += rv;
    len -= rv;
  }
  return count - len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L17
L41:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x31,%eax
  jle    L4
  movl   $0x1,-0xc(%rbp)
  jmp    L17
L4:
  movl   $0x0,-0xc(%rbp)
L17:
  cmpl   $0x0,-0xc(%rbp)
  jne    L41
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
data_type: string
name: extract_symbolic_data
arguments: data_tag: D24
data_type: string
name: extract_symbolic_data
arguments: data_tag: D4
data_type: string
name: extract_symbolic_data
arguments: data_tag: D26
data_type: string

tool: D27:  :Program will stop if input value less than 50.

tool: D24:  :Please input number==>

tool: D4: %d

tool: D26: The square for this number is %d


assistant: ```c
void main() {
  int num;
  int again = 1;
  printf("\40:Program will stop if input value less than 50.\n");
  while (again) {
    printf("\40:Please input number==>");
    scanf("%d", &num);
    printf("The square for this number is %d\n", (num) * (num));
    if (num >= 50)
      again = 1;
    else
      again = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D24(%rip),%r13
  lea    0x4(%rsp),%r12
  lea    D19(%rip),%rbp
  lea    D17(%rip),%rbx
L1:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  imul   %esi,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x31,0x4(%rsp)
  jg     L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D24
type: string
name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D17
type: string

tool: D9:  :Program will stop if input value less than 50.

tool: D24:  :Please input number==>

tool: D19: %d

tool: D17: The square for this number is %d


assistant: ```c
void main() {
  int num;
  int again = 1;
  printf("\40:Program will stop if input value less than 50.\n");
  while (again) {
    printf("\40:Please input number==>");
    scanf("%d", &num);
    printf("The square for this number is %d\n", (num) * (num));
    if (num >= 50)
      again = 1;
    else
      again = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%rdi
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  lea    D27(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  nopl   0x0(%rax)
L12:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbx,%rdi
  imul   %esi,%esi
  call   <printf@plt>
  cmpl   $0x31,0x4(%rsp)
  jg     L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string
name: disassemble_data
arguments: tag: D27
type_guessed: string

tool: D16:  :Program will stop if input value less than 50.

tool: D4:  :Please input number==>

tool: D0: %d

tool: D27: The square for this number is %d


assistant: ```c
void main() {
  int num;
  int again = 1;
  printf("\40:Program will stop if input value less than 50.\n");
  while (again) {
    printf("\40:Please input number==>");
    scanf("%d", &num);
    printf("The square for this number is %d\n", (num) * (num));
    if (num >= 50)
      again = 1;
    else
      again = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%rdi
  lea    D22(%rip),%r13
  push   %r12
  push   %rbp
  lea    D31(%rip),%rbp
  push   %rbx
  lea    D23(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  nopl   0x0(%rax)
L1:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbx,%rdi
  imul   %esi,%esi
  call   <printf@plt>
  cmpl   $0x31,0x4(%rsp)
  jg     L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D31
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string

tool: D6:  :Program will stop if input value less than 50.

tool: D22:  :Please input number==>

tool: D31: %d

tool: D23: The square for this number is %d


assistant: ```c
void main() {
  int num;
  int again = 1;
  printf("\40:Program will stop if input value less than 50.\n");
  while (again) {
    printf("\40:Please input number==>");
    scanf("%d", &num);
    printf("The square for this number is %d\n", (num) * (num));
    if (num >= 50)
      again = 1;
    else
      again = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<USBLPMRemoteWakeEnabled>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40050000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x360,%eax
  cltq
  mov    (%rax),%eax
  and    $0x100,%eax
  test   %eax,%eax
  je     L0
  mov    $0x1,%eax
  jmp    L4
L0:
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
bool USBLPMRemoteWakeEnabled(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  if ((*((volatile uint16_t *)(ui32Base + 0x00000360))) & 0x00000100) {
    return (true);
  }
  return (false);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBLPMRemoteWakeEnabled>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x40050000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x360,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  shr    $0x8,%eax
  and    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool USBLPMRemoteWakeEnabled(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  if ((*((volatile uint16_t *)(ui32Base + 0x00000360))) & 0x00000100) {
    return (true);
  }
  return (false);
}
```
user: Translate the below assembly code into C programming language:

```asm
<USBLPMRemoteWakeEnabled>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x40050000,%ebx
  sete   %dil
  add    $0x360,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  pop    %rbx
  shr    $0x8,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool USBLPMRemoteWakeEnabled(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  if ((*((volatile uint16_t *)(ui32Base + 0x00000360))) & 0x00000100) {
    return (true);
  }
  return (false);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<USBLPMRemoteWakeEnabled>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x40050000,%ebx
  sete   %dil
  add    $0x360,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  pop    %rbx
  shr    $0x8,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool USBLPMRemoteWakeEnabled(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  if ((*((volatile uint16_t *)(ui32Base + 0x00000360))) & 0x00000100) {
    return (true);
  }
  return (false);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<length_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L4:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int length_of(char s[]) {
  int i;
  for (i = 0; s[i] != '\0'; ++i)
    ;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<length_of>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  mov    $0x1,%eax
L21:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L21
L6:
  mov    %edx,%eax
  ret
L3:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int length_of(char s[]) {
  int i;
  for (i = 0; s[i] != '\0'; ++i)
    ;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<length_of>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L16
  mov    $0x1,%eax
  xchg   %ax,%ax
L11:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L11
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int length_of(char s[]) {
  int i;
  for (i = 0; s[i] != '\0'; ++i)
    ;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<length_of>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  mov    $0x1,%eax
  xchg   %ax,%ax
L0:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L0
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int length_of(char s[]) {
  int i;
  for (i = 0; s[i] != '\0'; ++i)
    ;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<point>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <move_nasko@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <cont@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int point(int x, int y) {
  move_nasko(x, y);
  cont(x, y);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<point>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <move_nasko@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <cont@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int point(int x, int y) {
  move_nasko(x, y);
  cont(x, y);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<point>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <move_nasko@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <cont@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int point(int x, int y) {
  move_nasko(x, y);
  cont(x, y);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<point>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <move_nasko@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <cont@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int point(int x, int y) {
  move_nasko(x, y);
  cont(x, y);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rmse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L10:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L10
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x34(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: f64

tool: D0: 255

assistant: ```c
double rmse(double *x1, double *x2, int l) {
  double diff;
  double rmse = 0.0;
  for (int i = 0; i < l; i++) {
    diff = x1[i] - x2[i];
    rmse += diff * diff;
  }
  rmse = sqrt(rmse / (double)l) / 255.;
  return rmse;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rmse>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L12
  mov    %edx,%ecx
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
L22:
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L22
L27:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  divsd  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D3(%rip),%xmm0
  add    $0x8,%rsp
  ret
L12:
  pxor   %xmm0,%xmm0
  jmp    L27
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: f64

tool: D3: 255

assistant: ```c
double rmse(double *x1, double *x2, int l) {
  double diff;
  double rmse = 0.0;
  for (int i = 0; i < l; i++) {
    diff = x1[i] - x2[i];
    rmse += diff * diff;
  }
  rmse = sqrt(rmse / (double)l) / 255.;
  return rmse;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rmse>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L21
  movslq %edx,%rcx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  nopl   (%rax)
L25:
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  add    $0x1,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L25
L9:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  divsd  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D1(%rip),%xmm0
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L21:
  pxor   %xmm0,%xmm0
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: f64

tool: D1: 255

assistant: ```c
double rmse(double *x1, double *x2, int l) {
  double diff;
  double rmse = 0.0;
  for (int i = 0; i < l; i++) {
    diff = x1[i] - x2[i];
    rmse += diff * diff;
  }
  rmse = sqrt(rmse / (double)l) / 255.;
  return rmse;
}
```