user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D92(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L47
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D47(%rip),%r13
  lea    D92(%rip),%r12
L11:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L11
L47:
  lea    D57(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L39
  mov    $0x0,%ebx
  lea    D109(%rip),%rbp
L59:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L59
L39:
  lea    D89(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L60
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    0x10(%rsp,%rax,1),%rbx
  lea    0xc(%rsp,%rax,1),%rbp
  lea    -0x1(%rdx),%eax
  shl    $0x2,%rax
  sub    %rax,%rbp
  lea    D109(%rip),%r12
L17:
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L17
L60:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D29
data_type: string
name: retrieve_data
arguments: tag: D40
data_type: string
name: retrieve_data
arguments: tag: D92
data_type: string
name: retrieve_data
arguments: tag: D30
data_type: string
name: retrieve_data
arguments: tag: D47
data_type: string
name: retrieve_data
arguments: tag: D57
data_type: string
name: retrieve_data
arguments: tag: D109
data_type: string
name: retrieve_data
arguments: tag: D89
data_type: string
name: retrieve_data
arguments: tag: D24
data_type: string

tool: D3: 

Leer N valores en un arreglo e imprimirlo en orden inverso:

tool: D29: ------------------------------------------------------------------------

tool: D40: Numero de elementos (N) :

tool: D92: %d

tool: D30: Ingrese %d elementos en el arreglo :


tool: D47: element - %d : 

tool: D57: 
Arreglo original : 

tool: D109: % 5d

tool: D89: 

Los valores en orden inverso son :

tool: D24: 


assistant: ```c
void main() {
  int i, n, a[100];
  printf("\n\nLeer N valores en un arreglo e imprimirlo en orden inverso:\n");
  printf("------------------------------------------------------------------------\n");
  printf("Numero de elementos (N) :");
  scanf("%d", &n);
  printf("Ingrese %d elementos en el arreglo :\n", n);
  for (i = 0; i < n; i++) {
    printf("element - %d : ", i);
    scanf("%d", &a[i]);
  }
  printf("\nArreglo original : \n");
  for (i = 0; i < n; i++) {
    printf("% 5d", a[i]);
  }
  printf("\n\nLos valores en orden inverso son :\n");
  for (i = n - 1; i >= 0; i--) {
    printf("% 5d", a[i]);
  }
  printf("\n\n");
}
```