user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x350,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34c(%rbp),%rdx
  lea    -0x350(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34c(%rbp),%edx
  mov    -0x350(%rbp),%ecx
  lea    -0x330(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <read_into_matrix@plt>
  movl   $0x0,-0x348(%rbp)
  jmp    L84
L139:
  movl   $0x0,-0x344(%rbp)
  jmp    L98
L163:
  mov    -0x344(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x348(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0x330(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L0
  mov    -0x344(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x348(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  movl   $0x0,-0x1a0(%rbp,%rax,4)
  jmp    L110
L0:
  mov    -0x344(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x348(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  movl   $0x1,-0x1a0(%rbp,%rax,4)
  movl   $0x1,-0x340(%rbp)
  jmp    L109
L129:
  addl   $0x1,-0x340(%rbp)
L109:
  mov    -0x340(%rbp),%ecx
  mov    -0x344(%rbp),%edx
  mov    -0x348(%rbp),%esi
  lea    -0x330(%rbp),%rax
  mov    %rax,%rdi
  call   <goodness@plt>
  test   %rax,%rax
  jne    L129
  mov    -0x340(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x344(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x348(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  mov    %ecx,-0x1a0(%rbp,%rax,4)
L110:
  addl   $0x1,-0x344(%rbp)
L98:
  mov    -0x34c(%rbp),%eax
  cmp    %eax,-0x344(%rbp)
  jl     L163
  addl   $0x1,-0x348(%rbp)
L84:
  mov    -0x350(%rbp),%eax
  cmp    %eax,-0x348(%rbp)
  jl     L139
  mov    -0x34c(%rbp),%edx
  mov    -0x350(%rbp),%ecx
  lea    -0x1a0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <max_matrix@plt>
  mov    %eax,-0x334(%rbp)
  mov    -0x334(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x334(%rbp)
  jne    L95
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L67
L95:
  movl   $0x0,-0x33c(%rbp)
  jmp    L52
L148:
  movl   $0x0,-0x338(%rbp)
  jmp    L92
L47:
  mov    -0x338(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x33c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,-0x334(%rbp)
  jne    L87
  mov    -0x338(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x33c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L67
L87:
  addl   $0x1,-0x338(%rbp)
L92:
  mov    -0x34c(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L47
  addl   $0x1,-0x33c(%rbp)
L52:
  mov    -0x350(%rbp),%eax
  cmp    %eax,-0x33c(%rbp)
  jl     L148
  nop
L67:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L80
  call   <__stack_chk_fail@plt>
L80:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D25
type: string
name: unpack_data
arguments: data_label: D18
type: string
name: unpack_data
arguments: data_label: D28
type: string

tool: D25: %d %d

tool: D18: %d 

tool: D28: -1 -1

assistant: ```c
int main() {
  int a[10][10], m, n;
  int b[10][10];
  scanf("%d %d", &m, &n);
  read_into_matrix(a, m, n);
  for (int i = 0; i <= m - 1; i++) {
    for (int j = 0; j <= n - 1; j++) {
      if (a[i][j] == 0) {
        b[i][j] = 0;
      } else {
        b[i][j] = 1;
        int t = 1;
        while (goodness(a, i, j, t) != 0) {
          t++;
        }
        b[i][j] = t - 1;
      }
    }
  }
  int bmax = max_matrix(b, m, n);
  printf("%d ", bmax);
  if (bmax == 0) {
    printf("-1 -1");
  } else {
    for (int i = 0; i <= m - 1; i++) {
      for (int j = 0; j <= n - 1; j++) {
        if (b[i][j] == bmax) {
          printf("%d %d", i + 1, j + 1);
          goto end;
        }
      }
    }
  }
end:
  return 0;
}
```