ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_cube_offset_float>:
  endbr64
  movss  (%rsi,%rdi,4),%xmm0
  movss  (%rdx,%rdi,8),%xmm1
  lea    0x0(,%rdi,8),%rax
  comiss %xmm0,%xmm1
  ja     L10
  movss  0x4(%rdx,%rax,1),%xmm1
  comiss %xmm1,%xmm0
  jbe    L18
L10:
  subss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float get_cube_offset_float(int8_t dim, float *point_coord, float *bbox) {
  float dim_coord = point_coord[dim];
  if (dim_coord < bbox[2 * dim]) {
    return dim_coord - bbox[2 * dim];
  } else if (dim_coord > bbox[2 * dim + 1]) {
    return dim_coord - bbox[2 * dim + 1];
  } else {
    return 0.;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_cube_offset_float>:
  endbr64
  movss  (%rsi,%rdi,4),%xmm0
  movss  (%rdx,%rdi,8),%xmm1
  lea    0x0(,%rdi,8),%rax
  comiss %xmm0,%xmm1
  ja     L4
  movss  0x4(%rdx,%rax,1),%xmm1
  comiss %xmm1,%xmm0
  jbe    L2
L4:
  subss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float get_cube_offset_float(int8_t dim, float *point_coord, float *bbox) {
  float dim_coord = point_coord[dim];
  if (dim_coord < bbox[2 * dim]) {
    return dim_coord - bbox[2 * dim];
  } else if (dim_coord > bbox[2 * dim + 1]) {
    return dim_coord - bbox[2 * dim + 1];
  } else {
    return 0.;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<evaluate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L36:
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  and    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L21
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  jmp    L7
L21:
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    %eax,-0xc(%rbp)
L7:
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L36
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int evaluate(int result, int digits[], long long signs, int signs_count) {
  int sum = digits[0];
  for (int i = 0; i < signs_count; ++i) {
    int sign = (signs & (1 << i)) >> i;
    if (sign == 1) {
      sum += digits[i + 1];
    } else if (sign == 0) {
      sum -= digits[i + 1];
    }
  }
  return sum == result ? 1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<evaluate>:
  endbr64
  mov    %edi,%r8d
  mov    %rsi,%r9
  mov    (%rsi),%edi
  test   %ecx,%ecx
  jle    L16
  mov    %ecx,%esi
  mov    $0x0,%ecx
  mov    $0x1,%r10d
  jmp    L21
L23:
  add    0x4(%r9,%rcx,4),%edi
L7:
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  je     L16
L21:
  mov    %r10d,%eax
  shl    %cl,%eax
  cltq
  and    %rdx,%rax
  sar    %cl,%rax
  cmp    $0x1,%eax
  je     L23
  test   %eax,%eax
  jne    L7
  sub    0x4(%r9,%rcx,4),%edi
  jmp    L7
L16:
  cmp    %edi,%r8d
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int evaluate(int result, int digits[], long long signs, int signs_count) {
  int sum = digits[0];
  for (int i = 0; i < signs_count; ++i) {
    int sign = (signs & (1 << i)) >> i;
    if (sign == 1) {
      sum += digits[i + 1];
    } else if (sign == 0) {
      sum -= digits[i + 1];
    }
  }
  return sum == result ? 1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<evaluate>:
  endbr64
  mov    %edi,%r8d
  mov    %rsi,%r9
  mov    (%rsi),%edi
  test   %ecx,%ecx
  jle    L34
  movslq %ecx,%rsi
  mov    $0x1,%r10d
  xor    %ecx,%ecx
  jmp    L28
  nopl   (%rax)
L53:
  test   %eax,%eax
  jne    L41
  sub    0x4(%r9,%rcx,4),%edi
L41:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  je     L34
L28:
  mov    %r10d,%eax
  shl    %cl,%eax
  cltq
  and    %rdx,%rax
  sar    %cl,%rax
  cmp    $0x1,%eax
  jne    L53
  add    0x4(%r9,%rcx,4),%edi
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L28
L34:
  xor    %eax,%eax
  cmp    %edi,%r8d
  sete   %al
  ret
```

assistant: ```c
int evaluate(int result, int digits[], long long signs, int signs_count) {
  int sum = digits[0];
  for (int i = 0; i < signs_count; ++i) {
    int sign = (signs & (1 << i)) >> i;
    if (sign == 1) {
      sum += digits[i + 1];
    } else if (sign == 0) {
      sum -= digits[i + 1];
    }
  }
  return sum == result ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<evaluate>:
  endbr64
  mov    %edi,%r8d
  mov    %rsi,%r9
  mov    (%rsi),%edi
  test   %ecx,%ecx
  jle    L4
  movslq %ecx,%rsi
  mov    $0x1,%r10d
  xor    %ecx,%ecx
  jmp    L21
  nopl   (%rax)
L57:
  test   %eax,%eax
  jne    L20
  sub    0x4(%r9,%rcx,4),%edi
L20:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  je     L4
L21:
  mov    %r10d,%eax
  shl    %cl,%eax
  cltq
  and    %rdx,%rax
  sar    %cl,%rax
  cmp    $0x1,%eax
  jne    L57
  add    0x4(%r9,%rcx,4),%edi
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L21
L4:
  xor    %eax,%eax
  cmp    %edi,%r8d
  sete   %al
  ret
```

assistant: ```c
int evaluate(int result, int digits[], long long signs, int signs_count) {
  int sum = digits[0];
  for (int i = 0; i < signs_count; ++i) {
    int sign = (signs & (1 << i)) >> i;
    if (sign == 1) {
      sum += digits[i + 1];
    } else if (sign == 0) {
      sum -= digits[i + 1];
    }
  }
  return sum == result ? 1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dbwt_sais>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L34
  cmpq   $0x0,-0x10(%rbp)
  je     L34
  cmpl   $0x0,-0x14(%rbp)
  jns    L30
L34:
  mov    $0xffffffff,%eax
  jmp    L56
L30:
  cmpl   $0x1,-0x14(%rbp)
  jg     L25
  cmpl   $0x1,-0x14(%rbp)
  jne    L40
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
L40:
  mov    $0x0,%eax
  jmp    L56
L25:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x1,%r9d
  mov    $0x100,%r8d
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <dbwt_sais_main@plt>
L56:
  leave
  ret
```

assistant: ```c
int dbwt_sais(const unsigned char *T, int *SA, int n) {
  if ((T == NULL) || (SA == NULL) || (n < 0)) {
    return -1;
  }
  if (n <= 1) {
    if (n == 1) {
      SA[0] = 0;
    }
    return 0;
  }
  return dbwt_sais_main(T, SA, 0, n, 256, sizeof(unsigned char));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dbwt_sais>:
  endbr64
  mov    %edx,%ecx
  test   %rsi,%rsi
  sete   %al
  shr    $0x1f,%edx
  or     %dl,%al
  jne    L29
  test   %rdi,%rdi
  je     L29
  cmp    $0x1,%ecx
  jle    L25
  sub    $0x8,%rsp
  mov    $0x1,%r9d
  mov    $0x100,%r8d
  mov    $0x0,%edx
  call   <dbwt_sais_main@plt>
  add    $0x8,%rsp
  ret
L25:
  mov    $0x0,%eax
  je     L16
  ret
L16:
  movl   $0x0,(%rsi)
  ret
L29:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dbwt_sais(const unsigned char *T, int *SA, int n) {
  if ((T == NULL) || (SA == NULL) || (n < 0)) {
    return -1;
  }
  if (n <= 1) {
    if (n == 1) {
      SA[0] = 0;
    }
    return 0;
  }
  return dbwt_sais_main(T, SA, 0, n, 256, sizeof(unsigned char));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dbwt_sais>:
  endbr64
  test   %rsi,%rsi
  mov    %edx,%ecx
  sete   %al
  shr    $0x1f,%edx
  or     %dl,%al
  jne    L36
  test   %rdi,%rdi
  je     L36
  cmp    $0x1,%ecx
  jle    L28
  mov    $0x1,%r9d
  mov    $0x100,%r8d
  xor    %edx,%edx
  jmp    1050 <dbwt_sais_main@plt>
L28:
  mov    $0x0,%eax
  je     L22
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  movl   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dbwt_sais(const unsigned char *T, int *SA, int n) {
  if ((T == NULL) || (SA == NULL) || (n < 0)) {
    return -1;
  }
  if (n <= 1) {
    if (n == 1) {
      SA[0] = 0;
    }
    return 0;
  }
  return dbwt_sais_main(T, SA, 0, n, 256, sizeof(unsigned char));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dbwt_sais>:
  endbr64
  test   %rsi,%rsi
  mov    %edx,%ecx
  sete   %al
  shr    $0x1f,%edx
  or     %dl,%al
  jne    L31
  test   %rdi,%rdi
  je     L31
  cmp    $0x1,%ecx
  jle    L14
  mov    $0x1,%r9d
  mov    $0x100,%r8d
  xor    %edx,%edx
  jmp    1050 <dbwt_sais_main@plt>
L14:
  mov    $0x0,%eax
  je     L11
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movl   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dbwt_sais(const unsigned char *T, int *SA, int n) {
  if ((T == NULL) || (SA == NULL) || (n < 0)) {
    return -1;
  }
  if (n <= 1) {
    if (n == 1) {
      SA[0] = 0;
    }
    return 0;
  }
  return dbwt_sais_main(T, SA, 0, n, 256, sizeof(unsigned char));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D78(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D71(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D91(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D94(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L12
  movss  0x8(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L14
  comiss %xmm0,%xmm1
  ja     L89
L14:
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jb     L24
  comiss %xmm0,%xmm2
  ja     L45
L24:
  comiss 0x10(%rsp),%xmm0
  jb     L92
  comiss %xmm0,%xmm1
  ja     L7
L92:
  lea    D23(%rip),%rdi
  call   <printf@plt>
L104:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L12:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L104
L89:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L104
L45:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L104
L7:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L104
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D78
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string
name: parse_data
arguments: data_tag: D71
data_type: string
name: parse_data
arguments: data_tag: D91
data_type: string
name: parse_data
arguments: data_tag: D94
data_type: string
name: parse_data
arguments: data_tag: D23
data_type: string
name: parse_data
arguments: data_tag: D39
data_type: string
name: parse_data
arguments: data_tag: D41
data_type: string
name: parse_data
arguments: data_tag: D36
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string

tool: D78: Enter thresholds for A, B, C, D


tool: D12: in that order, decreasing percentages > 

tool: D71: %f %f %f %f

tool: D91: Thank you. Now enter student score (percent) > 

tool: D94: %f

tool: D23: Student has failed the course


tool: D39: Student has an A grade


tool: D41: Student has a B grade


tool: D36: Student has a C grade


tool: D16: Student has a D grade


assistant: ```c
int main() {
  float grade1, grade2, grade3, grade4, score;
  printf("Enter thresholds for A, B, C, D\n");
  printf("in that order, decreasing percentages > ");
  scanf("%f %f %f %f", &grade1, &grade2, &grade3, &grade4);
  printf("Thank you. Now enter student score (percent) > ");
  scanf("%f", &score);
  if (score >= grade1)
    printf("Student has an A grade\n");
  else if (score >= grade2 && score < grade1)
    printf("Student has a B grade\n");
  else if (score >= grade3 && score < grade2)
    printf("Student has a C grade\n");
  else if (score >= grade4 && score < grade3)
    printf("Student has a D grade\n");
  else
    printf("Student has failed the course\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D54(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D70(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D99(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L16
  movss  0x8(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L52
  comiss %xmm0,%xmm1
  ja     L118
L52:
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L85
L115:
  comiss 0x10(%rsp),%xmm0
  jb     L119
  comiss %xmm0,%xmm1
  ja     L14
L119:
  lea    D63(%rip),%rdi
  call   <printf@plt>
L99:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L85:
  comiss %xmm0,%xmm2
  jbe    L115
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L99
L16:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L99
L118:
  lea    D57(%rip),%rdi
  call   <printf@plt>
  jmp    L99
L14:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L99
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D54
type_infered: string
name: read_data
arguments: data_tag: D70
type_infered: string
name: read_data
arguments: data_tag: D45
type_infered: string
name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D99
type_infered: string
name: read_data
arguments: data_tag: D63
type_infered: string
name: read_data
arguments: data_tag: D43
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string
name: read_data
arguments: data_tag: D57
type_infered: string
name: read_data
arguments: data_tag: D16
type_infered: string

tool: D54: Enter thresholds for A, B, C, D


tool: D70: in that order, decreasing percentages > 

tool: D45: %f %f %f %f

tool: D28: Thank you. Now enter student score (percent) > 

tool: D99: %f

tool: D63: Student has failed the course


tool: D43: Student has a C grade


tool: D4: Student has an A grade


tool: D57: Student has a B grade


tool: D16: Student has a D grade


assistant: ```c
int main() {
  float grade1, grade2, grade3, grade4, score;
  printf("Enter thresholds for A, B, C, D\n");
  printf("in that order, decreasing percentages > ");
  scanf("%f %f %f %f", &grade1, &grade2, &grade3, &grade4);
  printf("Thank you. Now enter student score (percent) > ");
  scanf("%f", &score);
  if (score >= grade1)
    printf("Student has an A grade\n");
  else if (score >= grade2 && score < grade1)
    printf("Student has a B grade\n");
  else if (score >= grade3 && score < grade2)
    printf("Student has a C grade\n");
  else if (score >= grade4 && score < grade3)
    printf("Student has a D grade\n");
  else
    printf("Student has failed the course\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D56(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  lea    D79(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L24
  movss  0x8(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L64
  comiss %xmm0,%xmm1
  ja     L49
L64:
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L1
L75:
  comiss 0x10(%rsp),%xmm0
  jb     L77
  comiss %xmm0,%xmm1
  ja     L67
L77:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L36:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  comiss %xmm0,%xmm2
  jbe    L75
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L24:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L49:
  lea    D86(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L67:
  lea    D80(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D56
type_infered: string
name: parse_data
arguments: data_tag: D22
type_infered: string
name: parse_data
arguments: data_tag: D40
type_infered: string
name: parse_data
arguments: data_tag: D79
type_infered: string
name: parse_data
arguments: data_tag: D42
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D64
type_infered: string
name: parse_data
arguments: data_tag: D38
type_infered: string
name: parse_data
arguments: data_tag: D86
type_infered: string
name: parse_data
arguments: data_tag: D80
type_infered: string

tool: D56: Enter thresholds for A, B, C, D


tool: D22: in that order, decreasing percentages > 

tool: D40: %f %f %f %f

tool: D79: Thank you. Now enter student score (percent) > 

tool: D42: %f

tool: D8: Student has failed the course


tool: D64: Student has a C grade


tool: D38: Student has an A grade


tool: D86: Student has a B grade


tool: D80: Student has a D grade


assistant: ```c
int main() {
  float grade1, grade2, grade3, grade4, score;
  printf("Enter thresholds for A, B, C, D\n");
  printf("in that order, decreasing percentages > ");
  scanf("%f %f %f %f", &grade1, &grade2, &grade3, &grade4);
  printf("Thank you. Now enter student score (percent) > ");
  scanf("%f", &score);
  if (score >= grade1)
    printf("Student has an A grade\n");
  else if (score >= grade2 && score < grade1)
    printf("Student has a B grade\n");
  else if (score >= grade3 && score < grade2)
    printf("Student has a C grade\n");
  else if (score >= grade4 && score < grade3)
    printf("Student has a D grade\n");
  else
    printf("Student has failed the course\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L20
  mov    $0x1,%eax
  jmp    L12
L20:
  movl   $0x1,-0x4(%rbp)
  jmp    L27
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <purge_file@plt>
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  if (argc < 2)
    return 1;
  for (i = 1; i < argc; ++i)
    purge_file(argv[i]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L4
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L2:
  mov    (%rbx),%rdi
  call   <purge_file@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  if (argc < 2)
    return 1;
  for (i = 1; i < argc; ++i)
    purge_file(argv[i]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L11
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <purge_file@plt>
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  if (argc < 2)
    return 1;
  for (i = 1; i < argc; ++i)
    purge_file(argv[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L8
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <purge_file@plt>
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  if (argc < 2)
    return 1;
  for (i = 1; i < argc; ++i)
    purge_file(argv[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_M_DRV_MC3610_ASC_ReadSensorData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x5,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xa(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdx
  mov    $0x10,%esi
  mov    $0x98,%edi
  call   <M_DRV_I2C_Write@plt>
  movb   $0x0,-0x9(%rbp)
  jmp    L44
L49:
  mov    $0x32,%edi
  call   <_M_DRV_MC3610_Delay@plt>
  lea    -0xa(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdx
  mov    $0x8,%esi
  mov    $0x99,%edi
  call   <M_DRV_I2C_Read@plt>
  movzbl -0xa(%rbp),%eax
  movzbl %al,%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L47
  movzbl -0x9(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x9(%rbp)
L44:
  cmpb   $0xf,-0x9(%rbp)
  jbe    L49
  jmp    L0
L47:
  nop
L0:
  mov    -0x18(%rbp),%rax
  mov    $0x6,%ecx
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x99,%edi
  call   <M_DRV_I2C_Read@plt>
  movb   $0x1,-0xa(%rbp)
  lea    -0xa(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdx
  mov    $0x10,%esi
  mov    $0x98,%edi
  call   <M_DRV_I2C_Write@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void _M_DRV_MC3610_ASC_ReadSensorData(unsigned char *pbData) {
  unsigned char _bRegData = 0x05;
  unsigned char _bCheckCount = 0x00;
  M_DRV_I2C_Write((((0x4C) << 1) | 0x00), 0x10, &_bRegData, 1);
  for (_bCheckCount = 0; _bCheckCount < 16; _bCheckCount++) {
    _M_DRV_MC3610_Delay(50);
    M_DRV_I2C_Read((((0x4C) << 1) | 0x01), 0x08, &_bRegData, 1);
    if (_bRegData & 0x08)
      break;
  }
  M_DRV_I2C_Read((((0x4C) << 1) | 0x01), 0x02, pbData, 6);
  _bRegData = 0x01;
  M_DRV_I2C_Write((((0x4C) << 1) | 0x00), 0x10, &_bRegData, 1);
}
```