ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<my_pthread_attr_getstacksize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pthread_attr_getstacksize@plt>
  leave
  ret
```

assistant: ```c
int my_pthread_attr_getstacksize(pthread_attr_t const *__attr, size_t *stack_size) {
  pthread_attr_t *realattr = (pthread_attr_t *)*(unsigned int *)__attr;
  return pthread_attr_getstacksize(realattr, stack_size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_pthread_attr_getstacksize>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <pthread_attr_getstacksize@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int my_pthread_attr_getstacksize(pthread_attr_t const *__attr, size_t *stack_size) {
  pthread_attr_t *realattr = (pthread_attr_t *)*(unsigned int *)__attr;
  return pthread_attr_getstacksize(realattr, stack_size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_pthread_attr_getstacksize>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <pthread_attr_getstacksize@plt>
```

assistant: ```c
int my_pthread_attr_getstacksize(pthread_attr_t const *__attr, size_t *stack_size) {
  pthread_attr_t *realattr = (pthread_attr_t *)*(unsigned int *)__attr;
  return pthread_attr_getstacksize(realattr, stack_size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_pthread_attr_getstacksize>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <pthread_attr_getstacksize@plt>
```

assistant: ```c
int my_pthread_attr_getstacksize(pthread_attr_t const *__attr, size_t *stack_size) {
  pthread_attr_t *realattr = (pthread_attr_t *)*(unsigned int *)__attr;
  return pthread_attr_getstacksize(realattr, stack_size);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_chrom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: 	

assistant: ```c
char *get_chrom(char *line) {
  char *tok;
  tok = strtok(line, "\t");
  tok = strtok(NULL, "\t");
  tok = strtok(NULL, "\t");
  return tok;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_chrom>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: 	

assistant: ```c
char *get_chrom(char *line) {
  char *tok;
  tok = strtok(line, "\t");
  tok = strtok(NULL, "\t");
  tok = strtok(NULL, "\t");
  return tok;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_chrom>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  pop    %rbp
  jmp    1050 <strtok@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: 	

assistant: ```c
char *get_chrom(char *line) {
  char *tok;
  tok = strtok(line, "\t");
  tok = strtok(NULL, "\t");
  tok = strtok(NULL, "\t");
  return tok;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_chrom>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  pop    %rbp
  jmp    1050 <strtok@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D7: 	

assistant: ```c
char *get_chrom(char *line) {
  char *tok;
  tok = strtok(line, "\t");
  tok = strtok(NULL, "\t");
  tok = strtok(NULL, "\t");
  return tok;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DS1302>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %al,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x100001c9,%eax
  movzbl (%rax),%eax
  mov    %eax,%edx
  movzbl -0x4(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    $0x100001c9,%eax
  mov    %dl,(%rax)
  jmp    L18
L6:
  mov    $0x100001c9,%eax
  movzbl (%rax),%eax
  mov    $0x100001c9,%edx
  or     -0x4(%rbp),%al
  mov    %al,(%rdx)
L18:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DS1302(unsigned char ds1302_bit, unsigned int logical_value) {
  if (!logical_value)
    *((volatile unsigned char *)(0x10000000 + 0x1c9)) = *((volatile unsigned char *)(0x10000000 + 0x1c9)) & (0xff - ds1302_bit);
  else
    *((volatile unsigned char *)(0x10000000 + 0x1c9)) = *((volatile unsigned char *)(0x10000000 + 0x1c9)) | ds1302_bit;
}
```
user: What is the c source code of the assembly code below?

```asm
<DS1302>:
  endbr64
  test   %esi,%esi
  jne    L7
  movzbl 0x100001c9,%eax
  not    %edi
  and    %eax,%edi
  mov    %dil,0x100001c9
  ret
L7:
  movzbl 0x100001c9,%eax
  or     %edi,%eax
  mov    %al,0x100001c9
  ret
```

assistant: ```c
void DS1302(unsigned char ds1302_bit, unsigned int logical_value) {
  if (!logical_value)
    *((volatile unsigned char *)(0x10000000 + 0x1c9)) = *((volatile unsigned char *)(0x10000000 + 0x1c9)) & (0xff - ds1302_bit);
  else
    *((volatile unsigned char *)(0x10000000 + 0x1c9)) = *((volatile unsigned char *)(0x10000000 + 0x1c9)) | ds1302_bit;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DS1302>:
  endbr64
  movzbl 0x100001c9,%eax
  test   %esi,%esi
  jne    L8
  not    %edi
  and    %eax,%edi
  mov    %dil,0x100001c9
  ret
  nopl   (%rax)
L8:
  or     %edi,%eax
  mov    %al,0x100001c9
  ret
```

assistant: ```c
void DS1302(unsigned char ds1302_bit, unsigned int logical_value) {
  if (!logical_value)
    *((volatile unsigned char *)(0x10000000 + 0x1c9)) = *((volatile unsigned char *)(0x10000000 + 0x1c9)) & (0xff - ds1302_bit);
  else
    *((volatile unsigned char *)(0x10000000 + 0x1c9)) = *((volatile unsigned char *)(0x10000000 + 0x1c9)) | ds1302_bit;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DS1302>:
  endbr64
  movzbl 0x100001c9,%eax
  test   %esi,%esi
  jne    L5
  not    %edi
  and    %eax,%edi
  mov    %dil,0x100001c9
  ret
  nopl   (%rax)
L5:
  or     %edi,%eax
  mov    %al,0x100001c9
  ret
```

assistant: ```c
void DS1302(unsigned char ds1302_bit, unsigned int logical_value) {
  if (!logical_value)
    *((volatile unsigned char *)(0x10000000 + 0x1c9)) = *((volatile unsigned char *)(0x10000000 + 0x1c9)) & (0xff - ds1302_bit);
  else
    *((volatile unsigned char *)(0x10000000 + 0x1c9)) = *((volatile unsigned char *)(0x10000000 + 0x1c9)) | ds1302_bit;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nextPerm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L33
L63:
  subl   $0x1,-0x10(%rbp)
L33:
  cmpl   $0x0,-0x10(%rbp)
  jle    L14
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jl     L63
L14:
  subl   $0x1,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  js     L69
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L6
L61:
  subl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L35
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jl     L61
L35:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L32
L81:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L81
L69:
  nop
  leave
  ret
```

assistant: ```c
void nextPerm(char *perm) {
  int x = strlen(perm) - 1;
  while (x > 0 && perm[x] < perm[x - 1])
    x--;
  x--;
  if (x >= 0) {
    int y = strlen(perm) - 1;
    while (y > x && perm[y] < perm[x])
      y--;
    char tmp = perm[x];
    perm[x] = perm[y];
    perm[y] = tmp;
    int k, m;
    for (k = x + 1, m = strlen(perm) - 1; k < m; k++, m--) {
      tmp = perm[k];
      perm[k] = perm[m];
      perm[m] = tmp;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nextPerm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  test   %ebx,%ebx
  jle    L89
  movslq %ebx,%rax
  add    %rbp,%rax
L59:
  movzbl -0x1(%rax),%esi
  cmp    %sil,(%rax)
  jge    L89
  sub    $0x1,%rax
  sub    $0x1,%ebx
  jne    L59
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L89:
  mov    %ebx,%r12d
  sub    $0x1,%r12d
  js     L25
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  cmp    %ebx,%eax
  jle    L33
  movslq %r12d,%rax
  movzbl 0x0(%rbp,%rax,1),%ecx
  movslq %edx,%rax
  add    %rbp,%rax
  mov    %r12d,%esi
L97:
  cmp    %cl,(%rax)
  jge    L33
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    %esi,%edx
  jne    L97
  mov    %esi,%edx
L33:
  movslq %r12d,%r12
  add    %rbp,%r12
  movzbl (%r12),%eax
  movslq %edx,%rdx
  add    %rbp,%rdx
  movzbl (%rdx),%ecx
  mov    %cl,(%r12)
  mov    %al,(%rdx)
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L25
  movslq %ebx,%rbx
  cltq
L11:
  movzbl 0x0(%rbp,%rbx,1),%edx
  movzbl 0x0(%rbp,%rax,1),%ecx
  mov    %cl,0x0(%rbp,%rbx,1)
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rbx
  sub    $0x1,%rax
  cmp    %eax,%ebx
  jl     L11
  jmp    L25
```

assistant: ```c
void nextPerm(char *perm) {
  int x = strlen(perm) - 1;
  while (x > 0 && perm[x] < perm[x - 1])
    x--;
  x--;
  if (x >= 0) {
    int y = strlen(perm) - 1;
    while (y > x && perm[y] < perm[x])
      y--;
    char tmp = perm[x];
    perm[x] = perm[y];
    perm[y] = tmp;
    int k, m;
    for (k = x + 1, m = strlen(perm) - 1; k < m; k++, m--) {
      tmp = perm[k];
      perm[k] = perm[m];
      perm[m] = tmp;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nextPerm>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L128
  movslq %eax,%rdx
  add    %rbp,%rdx
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L116:
  sub    $0x1,%rdx
  test   %eax,%eax
  je     L98
L3:
  mov    %eax,%ebx
  movzbl -0x1(%rdx),%edi
  sub    $0x1,%eax
  cmp    %dil,(%rdx)
  jl     L116
L126:
  mov    %ebx,%r12d
  sub    $0x1,%r12d
  js     L98
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %r12d,%rdi
  add    %rbp,%rdi
  lea    -0x1(%rax),%edx
  movzbl (%rdi),%esi
  cmp    %ebx,%eax
  jle    L133
  movslq %edx,%rax
  add    %rbp,%rax
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L23:
  lea    -0x1(%rdx),%ecx
  sub    $0x1,%rax
  cmp    %ebx,%edx
  je     L69
  mov    %ecx,%edx
L27:
  movzbl (%rax),%ecx
  cmp    %sil,%cl
  jl     L23
L62:
  mov    %cl,(%rdi)
  mov    %rbp,%rdi
  mov    %sil,(%rax)
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L98
  movslq %ebx,%rdx
  cltq
  xchg   %ax,%ax
L41:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  movzbl 0x0(%rbp,%rax,1),%esi
  mov    %sil,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,0x0(%rbp,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L41
L98:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L69:
  movslq %ecx,%rcx
  lea    0x0(%rbp,%rcx,1),%rax
  movzbl (%rax),%ecx
  jmp    L62
L128:
  mov    %eax,%ebx
  jmp    L126
L133:
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,1),%rax
  movzbl (%rax),%ecx
  jmp    L62
```

assistant: ```c
void nextPerm(char *perm) {
  int x = strlen(perm) - 1;
  while (x > 0 && perm[x] < perm[x - 1])
    x--;
  x--;
  if (x >= 0) {
    int y = strlen(perm) - 1;
    while (y > x && perm[y] < perm[x])
      y--;
    char tmp = perm[x];
    perm[x] = perm[y];
    perm[y] = tmp;
    int k, m;
    for (k = x + 1, m = strlen(perm) - 1; k < m; k++, m--) {
      tmp = perm[k];
      perm[k] = perm[m];
      perm[m] = tmp;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nextPerm>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  test   %edx,%edx
  jle    L37
  cltq
  movzbl -0x1(%rbp,%rax,1),%ecx
  movslq %edx,%rax
  add    %rbp,%rax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L69:
  sub    $0x1,%rax
  test   %edx,%edx
  je     L51
L67:
  mov    %ecx,%esi
  movzbl -0x1(%rax),%ecx
  mov    %edx,%ebx
  sub    $0x1,%edx
  cmp    %sil,%cl
  jg     L69
L79:
  mov    %ebx,%r12d
  sub    $0x1,%r12d
  js     L51
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %r12d,%rdi
  add    %rbp,%rdi
  lea    -0x1(%rax),%edx
  movzbl (%rdi),%esi
  cmp    %ebx,%eax
  jle    L81
  movslq %edx,%rax
  add    %rbp,%rax
  jmp    L46
  nopl   (%rax)
L11:
  lea    -0x1(%rdx),%ecx
  sub    $0x1,%rax
  cmp    %ebx,%edx
  je     L55
  mov    %ecx,%edx
L46:
  movzbl (%rax),%ecx
  cmp    %sil,%cl
  jl     L11
L139:
  mov    %cl,(%rdi)
  mov    %rbp,%rdi
  mov    %sil,(%rax)
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L51
  movslq %ebx,%rdx
  cltq
  cs nopw 0x0(%rax,%rax,1)
L73:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  movzbl 0x0(%rbp,%rax,1),%esi
  mov    %sil,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,0x0(%rbp,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L73
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L55:
  movslq %ecx,%rcx
  lea    0x0(%rbp,%rcx,1),%rax
  movzbl (%rax),%ecx
  jmp    L139
L37:
  mov    %edx,%ebx
  jmp    L79
L81:
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,1),%rax
  movzbl (%rax),%ecx
  jmp    L139
```

assistant: ```c
void nextPerm(char *perm) {
  int x = strlen(perm) - 1;
  while (x > 0 && perm[x] < perm[x - 1])
    x--;
  x--;
  if (x >= 0) {
    int y = strlen(perm) - 1;
    while (y > x && perm[y] < perm[x])
      y--;
    char tmp = perm[x];
    perm[x] = perm[y];
    perm[y] = tmp;
    int k, m;
    for (k = x + 1, m = strlen(perm) - 1; k < m; k++, m--) {
      tmp = perm[k];
      perm[k] = perm[m];
      perm[m] = tmp;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1b(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0xc,%r13d
  mov    $0x1,%r15d
  movl   $0x1,0xc(%rsp)
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  jmp    L80
L60:
  movslq %ebx,%rax
  movsbl 0x1b(%rsp,%rax,1),%edi
  call   <cardNumber@plt>
  movsbl %al,%r12d
  jmp    L62
L85:
  movslq %ebp,%rax
  movsbl 0x1b(%rsp,%rax,1),%edi
  call   <cardNumber@plt>
  movsbl %al,%eax
  jmp    L92
L1:
  cmp    %r13d,%ebp
  jge    L37
L65:
  mov    %ebp,%ebx
L80:
  movslq %ebx,%rax
  movsbl 0x1b(%rsp,%rax,1),%edi
  call   <cardNumber@plt>
  test   %al,%al
  jg     L60
  movslq %ebx,%rax
  movsbl 0x1b(%rsp,%rax,1),%r12d
  sub    $0x30,%r12d
L62:
  lea    0x1(%rbx),%ebp
  movslq %ebp,%rax
  movsbl 0x1b(%rsp,%rax,1),%edi
  call   <cardNumber@plt>
  test   %al,%al
  jg     L85
  movslq %ebp,%rax
  movsbl 0x1b(%rsp,%rax,1),%eax
  sub    $0x30,%eax
L92:
  cmp    %eax,%r12d
  jle    L1
  movslq %ebx,%rbx
  movzbl 0x1b(%rsp,%rbx,1),%edx
  movslq %ebp,%rax
  movzbl 0x1b(%rsp,%rax,1),%ecx
  mov    %cl,0x1b(%rsp,%rbx,1)
  mov    %dl,0x1b(%rsp,%rax,1)
  mov    %r14d,0xc(%rsp)
  cmp    %r13d,%ebp
  jl     L65
L110:
  add    $0x1,%r15d
  mov    $0xd,%r13d
  sub    %r15d,%r13d
  test   %r13d,%r13d
  jle    L90
  movl   $0x1,0xc(%rsp)
  mov    %r14d,%ebp
  jmp    L65
L37:
  cmpl   $0x0,0xc(%rsp)
  je     L110
L90:
  lea    0x1b(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string
name: parse_data
arguments: label: D27
type_guessed: string
name: parse_data
arguments: label: D21
type_guessed: string

tool: D7: %s

tool: D27: Original: %s


tool: D21: Sorted: %s


assistant: ```c
int main() {
  int i, j = 0, sorted = 0, n, m;
  char deck[13], temp;
  scanf("%s", deck);
  printf("Original: %s\n", deck);
  while (!sorted) {
    j++;
    sorted = 1;
    for (i = 0; i < 13 - j; i++) {
      n = cardNumber(deck[i]) > 0 ? cardNumber(deck[i]) : deck[i] - '0';
      m = cardNumber(deck[i + 1]) > 0 ? cardNumber(deck[i + 1]) : deck[i + 1] - '0';
      if (n > m) {
        temp = deck[i];
        deck[i] = deck[i + 1];
        deck[i + 1] = temp;
        sorted = 0;
      }
    }
  }
  printf("Sorted: %s\n", deck);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D13(%rip),%rdi
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    $0xc,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1b(%rsp),%rax
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rax,0x8(%rsp)
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  xor    %ebx,%ebx
  call   <printf@plt>
  movl   $0x1,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L65:
  movslq %ebx,%rbp
  movsbl 0x1b(%rsp,%rbp,1),%edi
  call   <cardNumber@plt>
  test   %al,%al
  jg     L34
  movsbl 0x1b(%rsp,%rbp,1),%r12d
  sub    $0x30,%r12d
L101:
  add    $0x1,%ebx
  movslq %ebx,%r15
  movsbl 0x1b(%rsp,%r15,1),%edi
  call   <cardNumber@plt>
  test   %al,%al
  jg     L58
  movsbl 0x1b(%rsp,%r15,1),%eax
  sub    $0x30,%eax
L72:
  cmp    %eax,%r12d
  jle    L24
  movzbl 0x1b(%rsp,%rbp,1),%eax
  movzbl 0x1b(%rsp,%r15,1),%ecx
  xor    %r14d,%r14d
  mov    %cl,0x1b(%rsp,%rbp,1)
  mov    %al,0x1b(%rsp,%r15,1)
  cmp    %r13d,%ebx
  jl     L65
L36:
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    $0xd,%r13d
  sub    %eax,%r13d
  test   %r13d,%r13d
  jle    L107
  mov    $0x1,%r14d
  xor    %ebx,%ebx
  jmp    L65
  xchg   %ax,%ax
L24:
  cmp    %r13d,%ebx
  jl     L65
  test   %r14d,%r14d
  je     L36
  xchg   %ax,%ax
L107:
  mov    0x8(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  movsbl 0x1b(%rsp,%r15,1),%edi
  call   <cardNumber@plt>
  movsbl %al,%eax
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L34:
  movsbl 0x1b(%rsp,%rbp,1),%edi
  call   <cardNumber@plt>
  movsbl %al,%r12d
  jmp    L101
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type: string
name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D5
type: string

tool: D13: %s

tool: D0: Original: %s


tool: D5: Sorted: %s


assistant: ```c
int main() {
  int i, j = 0, sorted = 0, n, m;
  char deck[13], temp;
  scanf("%s", deck);
  printf("Original: %s\n", deck);
  while (!sorted) {
    j++;
    sorted = 1;
    for (i = 0; i < 13 - j; i++) {
      n = cardNumber(deck[i]) > 0 ? cardNumber(deck[i]) : deck[i] - '0';
      m = cardNumber(deck[i + 1]) > 0 ? cardNumber(deck[i + 1]) : deck[i + 1] - '0';
      if (n > m) {
        temp = deck[i];
        deck[i] = deck[i + 1];
        deck[i + 1] = temp;
        sorted = 0;
      }
    }
  }
  printf("Sorted: %s\n", deck);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D1(%rip),%rdi
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    $0xc,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1b(%rsp),%rax
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rax,0x8(%rsp)
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D21(%rip),%rdi
  xor    %ebx,%ebx
  call   <printf@plt>
  movl   $0x1,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L56:
  movslq %ebx,%rbp
  movsbl 0x1b(%rsp,%rbp,1),%edi
  call   <cardNumber@plt>
  test   %al,%al
  jg     L33
  movsbl 0x1b(%rsp,%rbp,1),%r12d
  sub    $0x30,%r12d
L12:
  add    $0x1,%ebx
  movslq %ebx,%r15
  movsbl 0x1b(%rsp,%r15,1),%edi
  call   <cardNumber@plt>
  test   %al,%al
  jg     L9
  movsbl 0x1b(%rsp,%r15,1),%eax
  sub    $0x30,%eax
L62:
  cmp    %eax,%r12d
  jle    L92
  movzbl 0x1b(%rsp,%rbp,1),%eax
  movzbl 0x1b(%rsp,%r15,1),%ecx
  xor    %r14d,%r14d
  mov    %cl,0x1b(%rsp,%rbp,1)
  mov    %al,0x1b(%rsp,%r15,1)
  cmp    %r13d,%ebx
  jl     L56
L57:
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    $0xd,%r13d
  sub    %eax,%r13d
  test   %r13d,%r13d
  jle    L104
  mov    $0x1,%r14d
  xor    %ebx,%ebx
  jmp    L56
  xchg   %ax,%ax
L92:
  cmp    %r13d,%ebx
  jl     L56
  test   %r14d,%r14d
  je     L57
  xchg   %ax,%ax
L104:
  mov    0x8(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movsbl 0x1b(%rsp,%r15,1),%edi
  call   <cardNumber@plt>
  movsbl %al,%eax
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L33:
  movsbl 0x1b(%rsp,%rbp,1),%edi
  call   <cardNumber@plt>
  movsbl %al,%r12d
  jmp    L12
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string
name: extract_symbolic_data
arguments: data_tag: D21
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string

tool: D1: %s

tool: D21: Original: %s


tool: D10: Sorted: %s


assistant: ```c
int main() {
  int i, j = 0, sorted = 0, n, m;
  char deck[13], temp;
  scanf("%s", deck);
  printf("Original: %s\n", deck);
  while (!sorted) {
    j++;
    sorted = 1;
    for (i = 0; i < 13 - j; i++) {
      n = cardNumber(deck[i]) > 0 ? cardNumber(deck[i]) : deck[i] - '0';
      m = cardNumber(deck[i + 1]) > 0 ? cardNumber(deck[i + 1]) : deck[i + 1] - '0';
      if (n > m) {
        temp = deck[i];
        deck[i] = deck[i + 1];
        deck[i + 1] = temp;
        sorted = 0;
      }
    }
  }
  printf("Sorted: %s\n", deck);
  return 0;
}
```