ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1b8,%rsp
  lea    0xe0(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  call   <carrega@plt>
  mov    0xc(%rsp),%r9d
  mov    0x8(%rsp),%edx
  xor    %esi,%esi
  xor    %r8d,%r8d
  mov    %rbp,%rdi
  mov    %r12,%rcx
  call   <busca@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: Ocorrencias de p em f: %d .


assistant: ```c
int main() {
  char f[200], p[200];
  int tf = 0, tp = 0;
  if (0)
    printf("Lendo as strings:  \n");
  carrega(f, &tf, p, &tp);
  if (0) {
    printf("tamanhos: f(%d) e p(%d)  \n", tf, tp);
    printf("F:  \n");
    mostra(f, 0, tf);
    printf("P:  \n");
    mostra(p, 0, tp);
  }
  printf("Ocorrencias de p em f: %d .\n", busca(f, 0, tf, p, 0, tp));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1b8,%rsp
  lea    0xe0(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  call   <carrega@plt>
  mov    0xc(%rsp),%r9d
  mov    0x8(%rsp),%edx
  xor    %esi,%esi
  xor    %r8d,%r8d
  mov    %rbp,%rdi
  mov    %r12,%rcx
  call   <busca@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: Ocorrencias de p em f: %d .


assistant: ```c
int main() {
  char f[200], p[200];
  int tf = 0, tp = 0;
  if (0)
    printf("Lendo as strings:  \n");
  carrega(f, &tf, p, &tp);
  if (0) {
    printf("tamanhos: f(%d) e p(%d)  \n", tf, tp);
    printf("F:  \n");
    mostra(f, 0, tf);
    printf("P:  \n");
    mostra(p, 0, tp);
  }
  printf("Ocorrencias de p em f: %d .\n", busca(f, 0, tf, p, 0, tp));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getKeyAndValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %rdi,-0xf8(%rbp)
  mov    %rsi,-0x100(%rbp)
  mov    %rdx,-0x108(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movl   $0x0,-0x80(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0xf8(%rbp)
  jne    L40
  mov    $0xffffffff,%eax
  jmp    L30
L40:
  movl   $0x0,-0xe8(%rbp)
  jmp    L2
L8:
  mov    -0xe8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xf8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xe8(%rbp),%eax
  cltq
  mov    %dl,-0xe0(%rbp,%rax,1)
  addl   $0x1,-0xe8(%rbp)
L2:
  mov    -0xe8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xf8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L43
  cmpl   $0x64,-0xe8(%rbp)
  jne    L8
L43:
  mov    -0xe8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xe8(%rbp)
  cltq
  movb   $0x0,-0xe0(%rbp,%rax,1)
  movl   $0x0,-0xe4(%rbp)
  jmp    L27
L71:
  mov    -0xe8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xf8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xe4(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0xe8(%rbp)
  addl   $0x1,-0xe4(%rbp)
L27:
  mov    -0xe8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xf8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L33
  cmpl   $0x64,-0xe8(%rbp)
  jne    L71
L33:
  mov    -0xe4(%rbp),%eax
  cltq
  movb   $0x0,-0x70(%rbp,%rax,1)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x108(%rbp),%rdx
  mov    %eax,(%rdx)
  lea    -0xe0(%rbp),%rdx
  mov    -0x100(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
int getKeyAndValue(char *line, char *key, int *value) {
  char nameBuffer[100] = {0};
  char valueBuffer[100] = {0};
  int i, j;
  if (line == NULL) {
    return (-1);
  }
  for (i = 0; line[i] != '=' && i != 100; i++) {
    nameBuffer[i] = line[i];
  }
  nameBuffer[i++] = '\0';
  for (j = 0; line[i] != '\n' && i != 100; i++, j++) {
    valueBuffer[j] = line[i];
  }
  valueBuffer[j] = '\0';
  *value = atoi(valueBuffer);
  strcpy(key, nameBuffer);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getKeyAndValue>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movl   $0x0,0xd0(%rsp)
  test   %rdi,%rdi
  je     L72
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  movzbl (%rdi),%edx
  cmp    $0x3d,%dl
  je     L62
  mov    $0x1,%eax
  lea    -0x1(%rsp),%r9
L10:
  mov    %dl,(%r9,%rax,1)
  mov    %eax,%r8d
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x64,%eax
  setne  %sil
  cmp    $0x3d,%dl
  setne  %cl
  add    $0x1,%rax
  test   %cl,%sil
  jne    L10
L97:
  lea    0x1(%r8),%eax
  movslq %r8d,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  movslq %eax,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  cmp    $0x64,%eax
  je     L24
  cmp    $0xa,%cl
  je     L24
  lea    0x2(%r8),%eax
  cltq
  lea    0x70(%rsp),%r10
  movslq %r8d,%rdx
  sub    %rdx,%r10
L81:
  mov    %cl,-0x2(%r10,%rax,1)
  mov    %eax,%edx
  sub    %r8d,%edx
  sub    $0x1,%edx
  movzbl (%rdi,%rax,1),%ecx
  cmp    $0x64,%eax
  setne  %r9b
  cmp    $0xa,%cl
  setne  %sil
  add    $0x1,%rax
  test   %sil,%r9b
  jne    L81
L6:
  movslq %edx,%rdx
  movb   $0x0,0x70(%rsp,%rdx,1)
  lea    0x70(%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,0x0(%rbp)
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
L0:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L62:
  mov    $0x0,%r8d
  jmp    L97
L24:
  mov    $0x0,%edx
  jmp    L6
L72:
  mov    $0xffffffff,%eax
  jmp    L0
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getKeyAndValue(char *line, char *key, int *value) {
  char nameBuffer[100] = {0};
  char valueBuffer[100] = {0};
  int i, j;
  if (line == NULL) {
    return (-1);
  }
  for (i = 0; line[i] != '=' && i != 100; i++) {
    nameBuffer[i] = line[i];
  }
  nameBuffer[i++] = '\0';
  for (j = 0; line[i] != '\n' && i != 100; i++, j++) {
    valueBuffer[j] = line[i];
  }
  valueBuffer[j] = '\0';
  *value = atoi(valueBuffer);
  strcpy(key, nameBuffer);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getKeyAndValue>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x60(%rsp)
  movl   $0x0,0xd0(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  test   %rdi,%rdi
  je     L44
  mov    %rdx,%rbx
  movzbl (%rdi),%edx
  mov    %rdi,%rcx
  mov    %rsi,%rbp
  cmp    $0x3d,%dl
  je     L61
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdi
  jmp    L129
  nopl   0x0(%rax,%rax,1)
L65:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L29
L129:
  mov    %dl,(%rdi,%rax,1)
  movzbl (%rcx,%rax,1),%edx
  movslq %eax,%rsi
  cmp    $0x3d,%dl
  jne    L65
  lea    0x1(%rsi),%edi
  cmp    $0x64,%edi
  movslq %edi,%rax
  setne  %r8b
L68:
  movzbl (%rcx,%rax,1),%edx
  movb   $0x0,(%rsp,%rsi,1)
  cmp    $0xa,%dl
  je     L72
  test   %r8b,%r8b
  je     L72
  lea    0x70(%rsp),%r10
  lea    0x1(%rdi),%eax
  movslq %edi,%rdi
  xor    %esi,%esi
  mov    %r10,%r9
  cltq
  sub    %rdi,%r9
  nopl   0x0(%rax)
L111:
  mov    %dl,-0x1(%r9,%rax,1)
  movzbl (%rcx,%rax,1),%edx
  add    $0x1,%esi
  cmp    $0x64,%eax
  setne  %r8b
  cmp    $0xa,%dl
  setne  %dil
  add    $0x1,%rax
  test   %dil,%r8b
  jne    L111
L45:
  movslq %esi,%rsi
  mov    %r10,%rdi
  movb   $0x0,0x70(%rsp,%rsi,1)
  call   <atoi@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  call   <strcpy@plt>
  xor    %eax,%eax
L7:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    $0x1,%r8d
  mov    $0x65,%edi
  mov    $0x64,%esi
  jmp    L68
L72:
  xor    %esi,%esi
  lea    0x70(%rsp),%r10
  jmp    L45
L61:
  mov    $0x1,%r8d
  mov    $0x1,%eax
  mov    $0x1,%edi
  xor    %esi,%esi
  jmp    L68
L44:
  mov    $0xffffffff,%eax
  jmp    L7
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getKeyAndValue(char *line, char *key, int *value) {
  char nameBuffer[100] = {0};
  char valueBuffer[100] = {0};
  int i, j;
  if (line == NULL) {
    return (-1);
  }
  for (i = 0; line[i] != '=' && i != 100; i++) {
    nameBuffer[i] = line[i];
  }
  nameBuffer[i++] = '\0';
  for (j = 0; line[i] != '\n' && i != 100; i++, j++) {
    valueBuffer[j] = line[i];
  }
  valueBuffer[j] = '\0';
  *value = atoi(valueBuffer);
  strcpy(key, nameBuffer);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getKeyAndValue>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x60(%rsp)
  movl   $0x0,0xd0(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  test   %rdi,%rdi
  je     L11
  mov    %rdx,%rbx
  movzbl (%rdi),%edx
  mov    %rdi,%rcx
  mov    %rsi,%rbp
  cmp    $0x3d,%dl
  je     L54
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdi
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L67
L22:
  mov    %dl,(%rdi,%rax,1)
  movzbl (%rcx,%rax,1),%edx
  movslq %eax,%rsi
  cmp    $0x3d,%dl
  jne    L30
  lea    0x1(%rsi),%edi
  cmp    $0x64,%edi
  movslq %edi,%rax
  setne  %r8b
L127:
  movzbl (%rcx,%rax,1),%edx
  movb   $0x0,(%rsp,%rsi,1)
  cmp    $0xa,%dl
  je     L109
  test   %r8b,%r8b
  je     L109
  lea    0x70(%rsp),%r10
  lea    0x1(%rdi),%eax
  movslq %edi,%rdi
  xor    %esi,%esi
  mov    %r10,%r9
  cltq
  sub    %rdi,%r9
  nopl   0x0(%rax)
L119:
  mov    %dl,-0x1(%r9,%rax,1)
  movzbl (%rcx,%rax,1),%edx
  add    $0x1,%esi
  cmp    $0x64,%eax
  setne  %r8b
  cmp    $0xa,%dl
  setne  %dil
  add    $0x1,%rax
  test   %dil,%r8b
  jne    L119
L70:
  movslq %esi,%rsi
  mov    %r10,%rdi
  movb   $0x0,0x70(%rsp,%rsi,1)
  call   <atoi@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  call   <strcpy@plt>
  xor    %eax,%eax
L38:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  mov    $0x1,%r8d
  mov    $0x65,%edi
  mov    $0x64,%esi
  jmp    L127
L109:
  xor    %esi,%esi
  lea    0x70(%rsp),%r10
  jmp    L70
L54:
  mov    $0x1,%r8d
  mov    $0x1,%eax
  mov    $0x1,%edi
  xor    %esi,%esi
  jmp    L127
L11:
  mov    $0xffffffff,%eax
  jmp    L38
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getKeyAndValue(char *line, char *key, int *value) {
  char nameBuffer[100] = {0};
  char valueBuffer[100] = {0};
  int i, j;
  if (line == NULL) {
    return (-1);
  }
  for (i = 0; line[i] != '=' && i != 100; i++) {
    nameBuffer[i] = line[i];
  }
  nameBuffer[i++] = '\0';
  for (j = 0; line[i] != '\n' && i != 100; i++, j++) {
    valueBuffer[j] = line[i];
  }
  valueBuffer[j] = '\0';
  *value = atoi(valueBuffer);
  strcpy(key, nameBuffer);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<expand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0xfff,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  lea    D20(%rip),%rcx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <doexp@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void expand(str) char *str;
{
  static char a[(4096)];
  static char b[(4096)];
  char *p = str;
  int len = (4096) - 1;
  strcpy(a, str);
  doexp(&p, a, &len, b);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<expand>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x10(%rsp)
  movl   $0xfff,0xc(%rsp)
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  lea    D11(%rip),%rcx
  mov    %rbx,%rsi
  mov    $0x0,%eax
  call   <doexp@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void expand(str) char *str;
{
  static char a[(4096)];
  static char b[(4096)];
  char *p = str;
  int len = (4096) - 1;
  strcpy(a, str);
  doexp(&p, a, &len, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<expand>:
  endbr64
  sub    $0x28,%rsp
  lea    D11(%rip),%r8
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x10(%rsp)
  mov    %r8,%rdi
  movl   $0xfff,0xc(%rsp)
  call   <strcpy@plt>
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %rax,%rsi
  lea    D8(%rip),%rcx
  xor    %eax,%eax
  call   <doexp@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void expand(str) char *str;
{
  static char a[(4096)];
  static char b[(4096)];
  char *p = str;
  int len = (4096) - 1;
  strcpy(a, str);
  doexp(&p, a, &len, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expand>:
  endbr64
  sub    $0x28,%rsp
  lea    D4(%rip),%r8
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x10(%rsp)
  mov    %r8,%rdi
  movl   $0xfff,0xc(%rsp)
  call   <strcpy@plt>
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %rax,%rsi
  lea    D1(%rip),%rcx
  xor    %eax,%eax
  call   <doexp@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void expand(str) char *str;
{
  static char a[(4096)];
  static char b[(4096)];
  char *p = str;
  int len = (4096) - 1;
  strcpy(a, str);
  doexp(&p, a, &len, b);
}
```
user: What is the c source code of the assembly code below:

```asm
<dump_ipmi_registers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x42,-0xc(%rbp)
  jmp    L41
L46:
  movl   $0x0,-0x4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <print_debug@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <print_debug@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <print_debug_hex8@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L42:
  mov    -0xc(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <smbus_read_byte@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <print_debug@plt>
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%edi
  call   <print_debug_hex8@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <print_debug@plt>
  jmp    L57
L16:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print_debug_hex8@plt>
  mov    $0x20,%edi
  call   <print_debug_char@plt>
  addl   $0x1,-0x8(%rbp)
L34:
  cmpl   $0x7,-0x8(%rbp)
  jle    L42
L57:
  addl   $0x1,-0xc(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <print_debug@plt>
L41:
  cmpl   $0x42,-0xc(%rbp)
  jbe    L46
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string
name: extract_symbolic_data
arguments: data_label: D43
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string

tool: D4: 


tool: D43: ipmi 

tool: D26: bad device: 

assistant: ```c
void dump_ipmi_registers(void) {
  unsigned device;
  device = 0x42;
  while (device <= 0x42) {
    int status = 0;
    int i;
    print_debug("\n");
    print_debug("ipmi ");
    print_debug_hex8(device);
    for (i = 0; (i < 8); i++) {
      unsigned char byte;
      status = smbus_read_byte(device, 2);
      if (status < 0) {
        print_debug("bad device: ");
        print_debug_hex8(-status);
        print_debug("\n");
        break;
      }
      print_debug_hex8(status);
      print_debug_char(' ');
    }
    device += 1;
    print_debug("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dump_ipmi_registers>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D32(%rip),%rdi
  call   <print_debug@plt>
  lea    D35(%rip),%rdi
  call   <print_debug@plt>
  mov    $0x42,%edi
  call   <print_debug_hex8@plt>
  mov    $0x8,%ebp
L11:
  mov    $0x2,%esi
  mov    $0x42,%edi
  call   <smbus_read_byte@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L1
  mov    %eax,%edi
  call   <print_debug_hex8@plt>
  mov    $0x20,%edi
  call   <print_debug_char@plt>
  sub    $0x1,%ebp
  jne    L11
L16:
  lea    D32(%rip),%rdi
  call   <print_debug@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    D42(%rip),%rdi
  call   <print_debug@plt>
  neg    %ebx
  mov    %ebx,%edi
  call   <print_debug_hex8@plt>
  lea    D32(%rip),%rdi
  call   <print_debug@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D32
datatype: string
name: extract_symbolic_data
arguments: data_tag: D35
datatype: string
name: extract_symbolic_data
arguments: data_tag: D42
datatype: string

tool: D32: 


tool: D35: ipmi 

tool: D42: bad device: 

assistant: ```c
void dump_ipmi_registers(void) {
  unsigned device;
  device = 0x42;
  while (device <= 0x42) {
    int status = 0;
    int i;
    print_debug("\n");
    print_debug("ipmi ");
    print_debug_hex8(device);
    for (i = 0; (i < 8); i++) {
      unsigned char byte;
      status = smbus_read_byte(device, 2);
      if (status < 0) {
        print_debug("bad device: ");
        print_debug_hex8(-status);
        print_debug("\n");
        break;
      }
      print_debug_hex8(status);
      print_debug_char(' ');
    }
    device += 1;
    print_debug("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dump_ipmi_registers>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  mov    $0x8,%ebx
  call   <print_debug@plt>
  lea    D13(%rip),%rdi
  call   <print_debug@plt>
  mov    $0x42,%edi
  call   <print_debug_hex8@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x2,%esi
  mov    $0x42,%edi
  call   <smbus_read_byte@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L7
  mov    %eax,%edi
  call   <print_debug_hex8@plt>
  mov    $0x20,%edi
  call   <print_debug_char@plt>
  sub    $0x1,%ebx
  jne    L4
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <print_debug@plt>
  nop
L7:
  lea    D8(%rip),%rdi
  call   <print_debug@plt>
  mov    %ebp,%edi
  neg    %edi
  call   <print_debug_hex8@plt>
  mov    %r12,%rdi
  call   <print_debug@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <print_debug@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D5: 


tool: D13: ipmi 

tool: D8: bad device: 

assistant: ```c
void dump_ipmi_registers(void) {
  unsigned device;
  device = 0x42;
  while (device <= 0x42) {
    int status = 0;
    int i;
    print_debug("\n");
    print_debug("ipmi ");
    print_debug_hex8(device);
    for (i = 0; (i < 8); i++) {
      unsigned char byte;
      status = smbus_read_byte(device, 2);
      if (status < 0) {
        print_debug("bad device: ");
        print_debug_hex8(-status);
        print_debug("\n");
        break;
      }
      print_debug_hex8(status);
      print_debug_char(' ');
    }
    device += 1;
    print_debug("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dump_ipmi_registers>:
  endbr64
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  mov    $0x8,%ebx
  call   <print_debug@plt>
  lea    D7(%rip),%rdi
  call   <print_debug@plt>
  mov    $0x42,%edi
  call   <print_debug_hex8@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0x2,%esi
  mov    $0x42,%edi
  call   <smbus_read_byte@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L16
  mov    %eax,%edi
  call   <print_debug_hex8@plt>
  mov    $0x20,%edi
  call   <print_debug_char@plt>
  sub    $0x1,%ebx
  jne    L8
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <print_debug@plt>
  nop
L16:
  lea    D3(%rip),%rdi
  call   <print_debug@plt>
  mov    %ebp,%edi
  neg    %edi
  call   <print_debug_hex8@plt>
  mov    %r12,%rdi
  call   <print_debug@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <print_debug@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D7
type: string
name: extract_symbolic_data
arguments: label: D3
type: string

tool: D21: 


tool: D7: ipmi 

tool: D3: bad device: 

assistant: ```c
void dump_ipmi_registers(void) {
  unsigned device;
  device = 0x42;
  while (device <= 0x42) {
    int status = 0;
    int i;
    print_debug("\n");
    print_debug("ipmi ");
    print_debug_hex8(device);
    for (i = 0; (i < 8); i++) {
      unsigned char byte;
      status = smbus_read_byte(device, 2);
      if (status < 0) {
        print_debug("bad device: ");
        print_debug_hex8(-status);
        print_debug("\n");
        break;
      }
      print_debug_hex8(status);
      print_debug_char(' ');
    }
    device += 1;
    print_debug("\n");
  }
}
```