ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  cmp    $0x1,%edi
  jg     L14
L17:
  xor    %eax,%eax
  call   <ginit@plt>
  xor    %esi,%esi
  lea    D12(%rip),%rdi
  call   <reader@plt>
  xor    %eax,%eax
  call   <gend@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L14:
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rdi
  call   <chdir@plt>
  add    $0x1,%eax
  jne    L17
  mov    $0x12,%esi
  mov    $0x14,%edi
  call   <gmove@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <gprintf@plt>
  xor    %eax,%eax
  call   <ggetch@plt>
  xor    %eax,%eax
  call   <gend@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D0
type_infered: string

tool: D12: news

tool: D0: Error Setting Directory %s


assistant: ```c
int main(int argc, char *argv[]) {
  struct stat st_buf;
  char *gamedir, *p;
  if (argc > 1) {
    gamedir = argv[1];
    if (chdir(gamedir) == -1) {
      gmove(20, 18);
      gprintf("Error Setting Directory %s\n", gamedir);
      ggetch();
      gend();
      exit(1);
    }
  }
  ginit();
  reader("news", 0);
  gend();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_nontemporal>:
  endbr64
  ret
```

assistant: ```c
void test_nontemporal() {
  int i;
#pragma omp taskloop simd nontemporal(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int x, y;
#pragma omp taskloop simd nontemporal(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd private(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y : 0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) lastprivate(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd lastprivate(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd order
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(none
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(concurrent
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(concurrent)
  for (int i = 0; i < 10; ++i)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_nontemporal>:
  endbr64
  ret
```

assistant: ```c
void test_nontemporal() {
  int i;
#pragma omp taskloop simd nontemporal(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int x, y;
#pragma omp taskloop simd nontemporal(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd private(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y : 0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) lastprivate(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd lastprivate(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd order
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(none
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(concurrent
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(concurrent)
  for (int i = 0; i < 10; ++i)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_nontemporal>:
  endbr64
  ret
```

assistant: ```c
void test_nontemporal() {
  int i;
#pragma omp taskloop simd nontemporal(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int x, y;
#pragma omp taskloop simd nontemporal(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd private(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x, y : 0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd nontemporal(x) lastprivate(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd lastprivate(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp taskloop simd order
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(none
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(concurrent
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp taskloop simd order(concurrent)
  for (int i = 0; i < 10; ++i)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yy_2_ListPrefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void yy_2_ListPrefix(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yy_2_ListPrefix>:
  endbr64
  ret
```

assistant: ```c
void yy_2_ListPrefix(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<yy_2_ListPrefix>:
  endbr64
  ret
```

assistant: ```c
void yy_2_ListPrefix(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<yy_2_ListPrefix>:
  endbr64
  ret
```

assistant: ```c
void yy_2_ListPrefix(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L50
L73:
  addl   $0x1,-0x14(%rbp)
L50:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L73
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L42:
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L22:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L22
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L36:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  mov    (%rdx),%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L36
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **split(char *seq) {
  char **res = (char **)malloc(sizeof(char *) * 2);
  int ll, lr, i;
  for (ll = 0; seq[ll] != '#'; ll++)
    ;
  res[0] = (char *)malloc(sizeof(char) * (ll + 1));
  for (lr = 0; seq[ll + lr + 1]; lr++)
    ;
  res[1] = (char *)malloc(sizeof(char) * (lr + 1));
  for (i = 0; i < ll; i++)
    res[0][i] = seq[i];
  res[0][i] = 0;
  for (i = 0; i < lr; i++)
    res[1][i] = seq[ll + 1 + i];
  res[1][i] = 0;
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<split>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  cmpb   $0x23,0x0(%rbp)
  je     L126
  mov    $0x1,%eax
L20:
  mov    %eax,%r14d
  add    $0x1,%rax
  cmpb   $0x23,-0x1(%rbp,%rax,1)
  jne    L20
L97:
  lea    0x1(%r14),%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movslq %r14d,%r13
  cmpb   $0x0,0x1(%rbp,%r13,1)
  je     L32
  mov    $0x1,%eax
  lea    0x0(%rbp,%r13,1),%rdx
L21:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L21
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  test   %r14d,%r14d
  jle    L23
L71:
  mov    %r14d,%esi
  mov    $0x0,%eax
L104:
  movzbl 0x0(%rbp,%rax,1),%ecx
  mov    (%rbx),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L104
L15:
  movslq %r14d,%r14
  mov    (%rbx),%rax
  movb   $0x0,(%rax,%r14,1)
  test   %r12d,%r12d
  jle    L57
  mov    %r12d,%esi
  mov    $0x0,%eax
  add    %rbp,%r13
L70:
  movzbl 0x1(%r13,%rax,1),%ecx
  mov    0x8(%rbx),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L70
L106:
  movslq %r12d,%r12
  mov    0x8(%rbx),%rax
  movb   $0x0,(%rax,%r12,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L126:
  mov    $0x0,%r14d
  jmp    L97
L23:
  mov    $0x0,%r14d
  jmp    L15
L57:
  mov    $0x0,%r12d
  jmp    L106
L32:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  mov    $0x0,%r12d
  test   %r14d,%r14d
  jg     L71
  mov    (%rbx),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%r12d
  jmp    L106
```

assistant: ```c
char **split(char *seq) {
  char **res = (char **)malloc(sizeof(char *) * 2);
  int ll, lr, i;
  for (ll = 0; seq[ll] != '#'; ll++)
    ;
  res[0] = (char *)malloc(sizeof(char) * (ll + 1));
  for (lr = 0; seq[ll + lr + 1]; lr++)
    ;
  res[1] = (char *)malloc(sizeof(char) * (lr + 1));
  for (i = 0; i < ll; i++)
    res[0][i] = seq[i];
  res[0][i] = 0;
  for (i = 0; i < lr; i++)
    res[1][i] = seq[ll + 1 + i];
  res[1][i] = 0;
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x10,%edi
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  cmpb   $0x23,0x0(%r13)
  mov    %rax,%r12
  je     L58
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %ebx,%r14d
  add    $0x1,%rbx
  cmpb   $0x23,-0x1(%r13,%rbx,1)
  jne    L40
  lea    0x1(%r14),%ebp
L109:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  cmpb   $0x0,0x0(%r13,%rbx,1)
  je     L51
  movslq %r14d,%r15
  mov    $0x1,%eax
  lea    0x0(%r13,%r15,1),%rdx
  nop
L25:
  movslq %eax,%rbx
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L25
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%r12)
  test   %r14d,%r14d
  je     L68
L0:
  xor    %eax,%eax
  nopl   0x0(%rax)
L66:
  movzbl 0x0(%r13,%rax,1),%ecx
  mov    (%r12),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%r15
  jne    L66
  mov    (%r12),%rax
  movb   $0x0,(%rax,%r15,1)
  test   %ebx,%ebx
  je     L116
L36:
  movslq %ebp,%rbp
  xor    %eax,%eax
  add    %r13,%rbp
  nopl   0x0(%rax,%rax,1)
L59:
  movzbl 0x0(%rbp,%rax,1),%ecx
  mov    0x8(%r12),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L59
L42:
  mov    0x8(%r12),%rdx
  movb   $0x0,(%rdx,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L68:
  mov    (%r12),%rax
  movb   $0x0,(%rax)
  jmp    L36
  nopl   0x0(%rax)
L51:
  mov    $0x1,%edi
  xor    %ebx,%ebx
  movslq %r14d,%r15
  call   <malloc@plt>
  mov    %rax,0x8(%r12)
  test   %r14d,%r14d
  jne    L0
  mov    (%r12),%rax
  movb   $0x0,(%rax)
  nopl   0x0(%rax)
L116:
  xor    %eax,%eax
  jmp    L42
  nopl   0x0(%rax)
L58:
  mov    $0x1,%ebp
  xor    %r14d,%r14d
  jmp    L109
```

assistant: ```c
char **split(char *seq) {
  char **res = (char **)malloc(sizeof(char *) * 2);
  int ll, lr, i;
  for (ll = 0; seq[ll] != '#'; ll++)
    ;
  res[0] = (char *)malloc(sizeof(char) * (ll + 1));
  for (lr = 0; seq[ll + lr + 1]; lr++)
    ;
  res[1] = (char *)malloc(sizeof(char) * (lr + 1));
  for (i = 0; i < ll; i++)
    res[0][i] = seq[i];
  res[0][i] = 0;
  for (i = 0; i < lr; i++)
    res[1][i] = seq[ll + 1 + i];
  res[1][i] = 0;
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x10,%edi
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  cmpb   $0x23,0x0(%r13)
  mov    %rax,%r12
  je     L36
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %ebx,%r14d
  add    $0x1,%rbx
  cmpb   $0x23,-0x1(%r13,%rbx,1)
  jne    L31
  lea    0x1(%r14),%ebp
L14:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  cmpb   $0x0,0x0(%r13,%rbx,1)
  je     L40
  movslq %r14d,%r15
  mov    $0x1,%eax
  lea    0x0(%r13,%r15,1),%rdx
  nop
L74:
  movslq %eax,%rbx
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L74
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%r12)
  test   %r14d,%r14d
  je     L115
L69:
  xor    %eax,%eax
  nopl   0x0(%rax)
L19:
  movzbl 0x0(%r13,%rax,1),%ecx
  mov    (%r12),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%r15
  jne    L19
  mov    (%r12),%rax
  movb   $0x0,(%rax,%r15,1)
  test   %ebx,%ebx
  je     L28
L22:
  movslq %ebp,%rbp
  xor    %eax,%eax
  add    %r13,%rbp
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl 0x0(%rbp,%rax,1),%ecx
  mov    0x8(%r12),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L2
L87:
  mov    0x8(%r12),%rdx
  movb   $0x0,(%rdx,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L115:
  mov    (%r12),%rax
  movb   $0x0,(%rax)
  jmp    L22
  nopl   0x0(%rax)
L40:
  mov    $0x1,%edi
  xor    %ebx,%ebx
  movslq %r14d,%r15
  call   <malloc@plt>
  mov    %rax,0x8(%r12)
  test   %r14d,%r14d
  jne    L69
  mov    (%r12),%rax
  movb   $0x0,(%rax)
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  jmp    L87
  nopl   0x0(%rax)
L36:
  mov    $0x1,%ebp
  xor    %r14d,%r14d
  jmp    L14
```

assistant: ```c
char **split(char *seq) {
  char **res = (char **)malloc(sizeof(char *) * 2);
  int ll, lr, i;
  for (ll = 0; seq[ll] != '#'; ll++)
    ;
  res[0] = (char *)malloc(sizeof(char) * (ll + 1));
  for (lr = 0; seq[ll + lr + 1]; lr++)
    ;
  res[1] = (char *)malloc(sizeof(char) * (lr + 1));
  for (i = 0; i < ll; i++)
    res[0][i] = seq[i];
  res[0][i] = 0;
  for (i = 0; i < lr; i++)
    res[1][i] = seq[ll + 1 + i];
  res[1][i] = 0;
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <atoll@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  atoll();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <atoll@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  atoll();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <atoll@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  atoll();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <atoll@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  atoll();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: malloc() failed

assistant: ```c
void *wm(void *result) {
  if (!result)
    err(1, "malloc() failed");
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L13
L7:
  mov    %rbx,%rax
  pop    %rbx
  ret
L13:
  lea    D3(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: malloc() failed

assistant: ```c
void *wm(void *result) {
  if (!result)
    err(1, "malloc() failed");
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wm>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L0
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: malloc() failed

assistant: ```c
void *wm(void *result) {
  if (!result)
    err(1, "malloc() failed");
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wm>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L7
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  lea    D5(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: malloc() failed

assistant: ```c
void *wm(void *result) {
  if (!result)
    err(1, "malloc() failed");
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AONRTCCompareValueGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L19
  mov    $0x40092018,%eax
  mov    (%rax),%rax
  mov    %eax,-0x4(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L25
  mov    $0x4009201c,%eax
  mov    (%rax),%rax
  mov    %eax,-0x4(%rbp)
L25:
  mov    -0x14(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L24
  mov    $0x40092020,%eax
  mov    (%rax),%rax
  mov    %eax,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t AONRTCCompareValueGet(uint32_t ui32Channel) {
  uint32_t ui32Value = 0;

  ;
  if (ui32Channel & 0x1) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x00000018)));
  }
  if (ui32Channel & 0x2) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x0000001C)));
  }
  if (ui32Channel & 0x4) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x00000020)));
  }
  return (ui32Value);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AONRTCCompareValueGet>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  je     L11
  mov    0x40092018,%rax
L11:
  test   $0x2,%dil
  je     L7
  mov    0x4009201c,%rax
L7:
  test   $0x4,%dil
  je     L9
  mov    0x40092020,%rax
L9:
  ret
```

assistant: ```c
uint32_t AONRTCCompareValueGet(uint32_t ui32Channel) {
  uint32_t ui32Value = 0;

  ;
  if (ui32Channel & 0x1) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x00000018)));
  }
  if (ui32Channel & 0x2) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x0000001C)));
  }
  if (ui32Channel & 0x4) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x00000020)));
  }
  return (ui32Value);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<AONRTCCompareValueGet>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  je     L24
  mov    0x40092018,%rax
L24:
  test   $0x2,%dil
  je     L11
  mov    0x4009201c,%rax
L11:
  and    $0x4,%edi
  je     L20
  mov    0x40092020,%rax
L20:
  ret
```

assistant: ```c
uint32_t AONRTCCompareValueGet(uint32_t ui32Channel) {
  uint32_t ui32Value = 0;

  ;
  if (ui32Channel & 0x1) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x00000018)));
  }
  if (ui32Channel & 0x2) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x0000001C)));
  }
  if (ui32Channel & 0x4) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x00000020)));
  }
  return (ui32Value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AONRTCCompareValueGet>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  je     L18
  mov    0x40092018,%rax
L18:
  test   $0x2,%dil
  je     L7
  mov    0x4009201c,%rax
L7:
  and    $0x4,%edi
  je     L17
  mov    0x40092020,%rax
L17:
  ret
```

assistant: ```c
uint32_t AONRTCCompareValueGet(uint32_t ui32Channel) {
  uint32_t ui32Value = 0;

  ;
  if (ui32Channel & 0x1) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x00000018)));
  }
  if (ui32Channel & 0x2) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x0000001C)));
  }
  if (ui32Channel & 0x4) {
    ui32Value = (*((volatile unsigned long *)(0x40092000 + 0x00000020)));
  }
  return (ui32Value);
}
```