ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_usage_and_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x25203a4547415355,%rax
  movabs $0x6f6974706f5b2073,%rdx
  mov    %rax,-0xb0(%rbp)
  mov    %rdx,-0xa8(%rbp)
  movabs $0x200a2e2e2e5d736e,%rax
  movabs $0x682d2d202c682d20,%rdx
  mov    %rax,-0xa0(%rbp)
  mov    %rdx,-0x98(%rbp)
  movabs $0x2020202020706c65,%rax
  movabs $0x79616c7073696420,%rdx
  mov    %rax,-0x90(%rbp)
  mov    %rdx,-0x88(%rbp)
  movabs $0x6568207369687420,%rax
  movabs $0x617373656d20706c,%rdx
  mov    %rax,-0x80(%rbp)
  mov    %rdx,-0x78(%rbp)
  movabs $0x2c712d20200a6567,%rax
  movabs $0x74656975712d2d20,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movabs $0x6c6e6f2020202020,%rax
  movabs $0x616c707369642079,%rdx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movabs $0x746c757365722079,%rax
  movabs $0x696166206e6f2073,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x2d20200a6572756c,%rax
  movabs $0x7265762d2d202c76,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x7020202065736f62,%rax
  movabs $0x63616520746e6972,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6320747365742068,%rax
  movabs $0x6e69656220657361,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x75722067,-0x10(%rbp)
  movw   $0xa6e,-0xc(%rbp)
  movb   $0x0,-0xa(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %eax,%edx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  lea    -0xb0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <fprintf@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void print_usage_and_exit(char *command_path) {
  char const usage_format[] = "USAGE: %s [options]...\n"
                              "  -h, --help      display this help message\n"
                              "  -q, --quiet     only display results on failure\n"
                              "  -v, --verbose   print each test case being run\n";
  fprintf(stderr, usage_format, basename(command_path));
  exit(EXIT_FAILURE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_usage_and_exit>:
  endbr64
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movabs $0x25203a4547415355,%rax
  movabs $0x6f6974706f5b2073,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x200a2e2e2e5d736e,%rax
  movabs $0x682d2d202c682d20,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x2020202020706c65,%rax
  movabs $0x79616c7073696420,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6568207369687420,%rax
  movabs $0x617373656d20706c,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x2c712d20200a6567,%rax
  movabs $0x74656975712d2d20,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x6c6e6f2020202020,%rax
  movabs $0x616c707369642079,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movabs $0x746c757365722079,%rax
  movabs $0x696166206e6f2073,%rdx
  mov    %rax,0x60(%rsp)
  mov    %rdx,0x68(%rsp)
  movabs $0x2d20200a6572756c,%rax
  movabs $0x7265762d2d202c76,%rdx
  mov    %rax,0x70(%rsp)
  mov    %rdx,0x78(%rsp)
  movabs $0x7020202065736f62,%rax
  movabs $0x63616520746e6972,%rdx
  mov    %rax,0x80(%rsp)
  mov    %rdx,0x88(%rsp)
  movabs $0x6320747365742068,%rax
  movabs $0x6e69656220657361,%rdx
  mov    %rax,0x90(%rsp)
  mov    %rdx,0x98(%rsp)
  movl   $0x75722067,0xa0(%rsp)
  movw   $0xa6e,0xa4(%rsp)
  movb   $0x0,0xa6(%rsp)
  call   <basename@plt>
  mov    %eax,%edx
  mov    %rsp,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fprintf@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xb8,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_usage_and_exit(char *command_path) {
  char const usage_format[] = "USAGE: %s [options]...\n"
                              "  -h, --help      display this help message\n"
                              "  -q, --quiet     only display results on failure\n"
                              "  -v, --verbose   print each test case being run\n";
  fprintf(stderr, usage_format, basename(command_path));
  exit(EXIT_FAILURE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D101(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x9,%eax
  ja     L16
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D37(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D37(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D120(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D107(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L16:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L100
  call   <__stack_chk_fail@plt>
L100:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D101
type: string
name: read_data
arguments: data_tag: D63
type: string
name: read_data
arguments: data_tag: D120
type: string
name: read_data
arguments: data_tag: D42
type: string
name: read_data
arguments: data_tag: D49
type: string
name: read_data
arguments: data_tag: D107
type: string
name: read_data
arguments: data_tag: D78
type: string
name: read_data
arguments: data_tag: D33
type: string
name: read_data
arguments: data_tag: D94
type: string
name: read_data
arguments: data_tag: D5
type: string
name: read_data
arguments: data_tag: D66
type: string

tool: D101: %d

tool: D63: zero


tool: D120: one


tool: D42: two


tool: D49: three


tool: D107: four


tool: D78: five


tool: D33: six


tool: D94: seven


tool: D5: eight


tool: D66: nine


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  switch (a) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L53
  mov    0x4(%rsp),%eax
  lea    D70(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D97(%rip),%rdi
  call   <printf@plt>
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D114(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D63(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L53
  lea    D57(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D97
type: string
name: parse_data
arguments: label: D25
type: string
name: parse_data
arguments: label: D114
type: string
name: parse_data
arguments: label: D63
type: string
name: parse_data
arguments: label: D46
type: string
name: parse_data
arguments: label: D30
type: string
name: parse_data
arguments: label: D35
type: string
name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D58
type: string
name: parse_data
arguments: label: D57
type: string

tool: D15: %d

tool: D97: zero


tool: D25: one


tool: D114: two


tool: D63: three


tool: D46: four


tool: D30: five


tool: D35: six


tool: D8: seven


tool: D58: eight


tool: D57: nine


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  switch (a) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D47(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L91
  mov    0x4(%rsp),%eax
  lea    D117(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D82(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L91:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L91
  lea    D65(%rip),%rdi
  call   <printf@plt>
  jmp    L91
  lea    D52(%rip),%rdi
  call   <printf@plt>
  jmp    L91
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L91
  lea    D70(%rip),%rdi
  call   <printf@plt>
  jmp    L91
  lea    D91(%rip),%rdi
  call   <printf@plt>
  jmp    L91
  lea    D84(%rip),%rdi
  call   <printf@plt>
  jmp    L91
  lea    D96(%rip),%rdi
  call   <printf@plt>
  jmp    L91
  lea    D59(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D47
data_type: string
name: retrieve_data
arguments: tag: D82
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D65
data_type: string
name: retrieve_data
arguments: tag: D52
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D70
data_type: string
name: retrieve_data
arguments: tag: D91
data_type: string
name: retrieve_data
arguments: tag: D84
data_type: string
name: retrieve_data
arguments: tag: D96
data_type: string
name: retrieve_data
arguments: tag: D59
data_type: string

tool: D47: %d

tool: D82: nine


tool: D19: eight


tool: D65: zero


tool: D52: one


tool: D1: two


tool: D70: three


tool: D91: four


tool: D84: five


tool: D96: six


tool: D59: seven


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  switch (a) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L5
  mov    0x4(%rsp),%eax
  lea    D102(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L5
  lea    D117(%rip),%rdi
  call   <printf@plt>
  jmp    L5
  lea    D52(%rip),%rdi
  call   <printf@plt>
  jmp    L5
  lea    D103(%rip),%rdi
  call   <printf@plt>
  jmp    L5
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L5
  lea    D77(%rip),%rdi
  call   <printf@plt>
  jmp    L5
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L5
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L5
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D33
data_type: string
name: read_data
arguments: tag: D37
data_type: string
name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D117
data_type: string
name: read_data
arguments: tag: D52
data_type: string
name: read_data
arguments: tag: D103
data_type: string
name: read_data
arguments: tag: D17
data_type: string
name: read_data
arguments: tag: D77
data_type: string
name: read_data
arguments: tag: D54
data_type: string
name: read_data
arguments: tag: D56
data_type: string
name: read_data
arguments: tag: D51
data_type: string

tool: D33: %d

tool: D37: nine


tool: D23: eight


tool: D117: zero


tool: D52: one


tool: D103: two


tool: D17: three


tool: D77: four


tool: D54: five


tool: D56: six


tool: D51: seven


assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  switch (a) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    $0x0,%r12d
  mov    %r12d,%r13d
  mov    -0x20(%rbp),%rbx
  jmp    L12
L9:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    %r12d,%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  xor    %eax,%r13d
  add    $0x3,%r12d
L12:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L9
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash(string)
char *string;
{
  register char *p;
  register unsigned i, sum;
  for (sum = i = 0, p = string; *p; i += 3)
    sum ^= (*p++) << (i & 07);
  return (sum);
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  mov    $0x0,%esi
  mov    $0x0,%edx
L16:
  add    $0x1,%rdi
  movsbl %al,%eax
  mov    %edx,%ecx
  and    $0x7,%ecx
  shl    %cl,%eax
  xor    %eax,%esi
  add    $0x3,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L16
L5:
  mov    %esi,%eax
  ret
L9:
  mov    $0x0,%esi
  jmp    L5
```

assistant: ```c
unsigned hash(string)
char *string;
{
  register char *p;
  register unsigned i, sum;
  for (sum = i = 0, p = string; *p; i += 3)
    sum ^= (*p++) << (i & 07);
  return (sum);
}
```
user: What is the c source code of the assembly code below:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L6
  xor    %edx,%edx
L11:
  mov    %edx,%ecx
  add    $0x1,%rdi
  add    $0x3,%edx
  and    $0x7,%ecx
  shl    %cl,%eax
  xor    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L11
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned hash(string)
char *string;
{
  register char *p;
  register unsigned i, sum;
  for (sum = i = 0, p = string; *p; i += 3)
    sum ^= (*p++) << (i & 07);
  return (sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L4
  xor    %edx,%edx
L17:
  mov    %edx,%ecx
  add    $0x1,%rdi
  add    $0x3,%edx
  and    $0x7,%ecx
  shl    %cl,%eax
  xor    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L17
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned hash(string)
char *string;
{
  register char *p;
  register unsigned i, sum;
  for (sum = i = 0, p = string; *p; i += 3)
    sum ^= (*p++) << (i & 07);
  return (sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L27
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L27:
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L24
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L24:
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L22
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fun(int a, int b, int c) {
  int max = 0;
  if (a > max) {
    max = a;
  }
  if (b > max) {
    max = b;
  }
  if (c > max) {
    max = c;
  }
  return max;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fun>:
  endbr64
  test   %edx,%edx
  mov    $0x0,%eax
  cmovs  %eax,%edx
  cmp    %esi,%edx
  cmovl  %esi,%edx
  cmp    %edi,%edx
  mov    %edi,%eax
  cmovge %edx,%eax
  ret
```

assistant: ```c
int fun(int a, int b, int c) {
  int max = 0;
  if (a > max) {
    max = a;
  }
  if (b > max) {
    max = b;
  }
  if (c > max) {
    max = c;
  }
  return max;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fun>:
  endbr64
  xor    %eax,%eax
  test   %edx,%edx
  cmovs  %eax,%edx
  mov    %edi,%eax
  cmp    %esi,%edx
  cmovl  %esi,%edx
  cmp    %edi,%edx
  cmovge %edx,%eax
  ret
```

assistant: ```c
int fun(int a, int b, int c) {
  int max = 0;
  if (a > max) {
    max = a;
  }
  if (b > max) {
    max = b;
  }
  if (c > max) {
    max = c;
  }
  return max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fun>:
  endbr64
  xor    %eax,%eax
  test   %edx,%edx
  cmovs  %eax,%edx
  mov    %edi,%eax
  cmp    %esi,%edx
  cmovl  %esi,%edx
  cmp    %edi,%edx
  cmovge %edx,%eax
  ret
```

assistant: ```c
int fun(int a, int b, int c) {
  int max = 0;
  if (a > max) {
    max = a;
  }
  if (b > max) {
    max = b;
  }
  if (c > max) {
    max = c;
  }
  return max;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_serial_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x44(%rbp)
  lea    -0x44(%rbp),%rax
  mov    %rax,%rdi
  call   <gmtime@plt>
  mov    (%rax),%rcx
  mov    0x8(%rax),%rbx
  mov    %rcx,-0x40(%rbp)
  mov    %rbx,-0x38(%rbp)
  mov    0x10(%rax),%rcx
  mov    0x18(%rax),%rbx
  mov    %rcx,-0x30(%rbp)
  mov    %rbx,-0x28(%rbp)
  mov    0x20(%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x40(%rbp),%eax
  add    $0x1,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x3c(%rbp),%eax
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %ax,-0x48(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x30(%rbp),%rax
  add    %edx,%eax
  add    $0x76c,%ax
  mov    %ax,-0x46(%rbp)
  movzwl -0x48(%rbp),%edx
  movzwl -0x46(%rbp),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int get_serial_id(void) {
  unsigned short lo, hi, mid;
  time_t now = time(NULL);
  struct tm tm = gmtime(&now)[0];
  lo = (unsigned short)(tm.tm_mday + ((tm.tm_mon + 1) << 8) + (tm.tm_sec << 8));
  hi = (unsigned short)(tm.tm_min + (tm.tm_hour << 8) + (tm.tm_year + 1900));
  return lo + (hi << 16);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_serial_id>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  movzwl 0x4(%rax),%edx
  shl    $0x8,%edx
  add    0x20(%rax),%dx
  movzwl (%rax),%esi
  lea    0x1(%rsi),%ecx
  shl    $0x8,%ecx
  add    %ecx,%edx
  movzwl %dx,%edx
  mov    0x10(%rax),%rcx
  add    0x18(%rax),%cx
  mov    0x8(%rax),%eax
  shl    $0x8,%eax
  lea    0x76c(%rcx,%rax,1),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_serial_id(void) {
  unsigned short lo, hi, mid;
  time_t now = time(NULL);
  struct tm tm = gmtime(&now)[0];
  lo = (unsigned short)(tm.tm_mday + ((tm.tm_mon + 1) << 8) + (tm.tm_sec << 8));
  hi = (unsigned short)(tm.tm_min + (tm.tm_hour << 8) + (tm.tm_year + 1900));
  return lo + (hi << 16);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_serial_id>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  movzwl (%rax),%esi
  movzwl 0x4(%rax),%edx
  lea    0x1(%rsi),%ecx
  shl    $0x8,%edx
  add    0x20(%rax),%dx
  shl    $0x8,%ecx
  add    %ecx,%edx
  mov    0x10(%rax),%rcx
  add    0x18(%rax),%cx
  mov    0x8(%rax),%eax
  movzwl %dx,%edx
  shl    $0x8,%eax
  lea    0x76c(%rcx,%rax,1),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_serial_id(void) {
  unsigned short lo, hi, mid;
  time_t now = time(NULL);
  struct tm tm = gmtime(&now)[0];
  lo = (unsigned short)(tm.tm_mday + ((tm.tm_mon + 1) << 8) + (tm.tm_sec << 8));
  hi = (unsigned short)(tm.tm_min + (tm.tm_hour << 8) + (tm.tm_year + 1900));
  return lo + (hi << 16);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_serial_id>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  movzwl (%rax),%esi
  movzwl 0x4(%rax),%edx
  lea    0x1(%rsi),%ecx
  shl    $0x8,%edx
  add    0x20(%rax),%dx
  shl    $0x8,%ecx
  add    %ecx,%edx
  mov    0x10(%rax),%rcx
  add    0x18(%rax),%cx
  mov    0x8(%rax),%eax
  movzwl %dx,%edx
  shl    $0x8,%eax
  lea    0x76c(%rcx,%rax,1),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_serial_id(void) {
  unsigned short lo, hi, mid;
  time_t now = time(NULL);
  struct tm tm = gmtime(&now)[0];
  lo = (unsigned short)(tm.tm_mday + ((tm.tm_mon + 1) << 8) + (tm.tm_sec << 8));
  hi = (unsigned short)(tm.tm_min + (tm.tm_hour << 8) + (tm.tm_year + 1900));
  return lo + (hi << 16);
}
```