ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  lea    D80(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  lea    D70(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  lea    D74(%rip),%rdi
  xor    %eax,%eax
  call   <assertTrue@plt>
  mov    $0x1,%esi
  xor    %eax,%eax
  add    $0x8,%rsp
  lea    D91(%rip),%rdi
  jmp    1050 <assertTrue@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
datatype: string
name: extract_symbolic_data
arguments: label: D80
datatype: string
name: extract_symbolic_data
arguments: label: D70
datatype: string
name: extract_symbolic_data
arguments: label: D31
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D50
datatype: string
name: extract_symbolic_data
arguments: label: D69
datatype: string
name: extract_symbolic_data
arguments: label: D88
datatype: string
name: extract_symbolic_data
arguments: label: D74
datatype: string
name: extract_symbolic_data
arguments: label: D91
datatype: string

tool: D29: a[0][0] == 0

tool: D80: a[0][1] == 1

tool: D70: a[1][0] == 2

tool: D31: a[2][1] == 5

tool: D21: p[0] == 0

tool: D50: p[1] == 1

tool: D69: p[2] == 2

tool: D88: p[3] == 3

tool: D74: p[4] == 4

tool: D91: p[5] == 5

assistant: ```c
void test() {
  int a[3][2] = {{0, 1}, {2, 3}, {4, 5}};
  assertTrue("a[0][0] == 0", a[0][0] == 0);
  ;
  assertTrue("a[0][1] == 1", a[0][1] == 1);
  ;
  assertTrue("a[1][0] == 2", a[1][0] == 2);
  ;
  assertTrue("a[2][1] == 5", a[2][1] == 5);
  ;
  int *p = a;
  assertTrue("p[0] == 0", p[0] == 0);
  ;
  assertTrue("p[1] == 1", p[1] == 1);
  ;
  assertTrue("p[2] == 2", p[2] == 2);
  ;
  assertTrue("p[3] == 3", p[3] == 3);
  ;
  assertTrue("p[4] == 4", p[4] == 4);
  ;
  assertTrue("p[5] == 5", p[5] == 5);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L4
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L1
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *stolower(char *str) {
  int k, len;
  char *p;
  p = str;
  len = strlen(str);
  for (k = 0; k < len; k++, p++)
    *p = tolower(*p);
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stolower>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  mov    %eax,%eax
  lea    (%r12,%rax,1),%rbp
  mov    %r12,%rbx
L9:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stolower(char *str) {
  int k, len;
  char *p;
  p = str;
  len = strlen(str);
  for (k = 0; k < len; k++, p++)
    *p = tolower(*p);
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stolower>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  cltq
  mov    %r12,%rbx
  lea    (%r12,%rax,1),%rbp
  nopl   (%rax)
L12:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L12
L4:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stolower(char *str) {
  int k, len;
  char *p;
  p = str;
  len = strlen(str);
  for (k = 0; k < len; k++, p++)
    *p = tolower(*p);
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stolower>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L7
  cltq
  mov    %r12,%rbx
  lea    (%r12,%rax,1),%rbp
  nopl   (%rax)
L6:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%rbp
  jne    L6
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stolower(char *str) {
  int k, len;
  char *p;
  p = str;
  len = strlen(str);
  for (k = 0; k < len; k++, p++)
    *p = tolower(*p);
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wrong4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L3:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <work@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <work@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void wrong4(int n) {
#pragma omp parallel default(shared)
  {
    int i;
#pragma omp for
    for (i = 0; i < n; i++) {
      work(i, 0);
#pragma omp barrier
      work(i, 1);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wrong4>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L16:
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <work@plt>
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <work@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
void wrong4(int n) {
#pragma omp parallel default(shared)
  {
    int i;
#pragma omp for
    for (i = 0; i < n; i++) {
      work(i, 0);
#pragma omp barrier
      work(i, 1);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wrong4>:
  endbr64
  test   %edi,%edi
  jle    L17
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edi
  xor    %esi,%esi
  call   <work@plt>
  mov    %ebx,%edi
  mov    $0x1,%esi
  add    $0x1,%ebx
  call   <work@plt>
  cmp    %ebx,%ebp
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
void wrong4(int n) {
#pragma omp parallel default(shared)
  {
    int i;
#pragma omp for
    for (i = 0; i < n; i++) {
      work(i, 0);
#pragma omp barrier
      work(i, 1);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wrong4>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  xor    %esi,%esi
  call   <work@plt>
  mov    %ebx,%edi
  mov    $0x1,%esi
  add    $0x1,%ebx
  call   <work@plt>
  cmp    %ebx,%ebp
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void wrong4(int n) {
#pragma omp parallel default(shared)
  {
    int i;
#pragma omp for
    for (i = 0; i < n; i++) {
      work(i, 0);
#pragma omp barrier
      work(i, 1);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SerialSendData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <SerialDataBegin@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <SerialSendBytes@plt>
  mov    $0x0,%eax
  call   <SerialDataEnd@plt>
  nop
  leave
  ret
```

assistant: ```c
void SerialSendData(unsigned long *data, unsigned long len) {
  SerialDataBegin();
  SerialSendBytes(data, len);
  SerialDataEnd();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SerialSendData>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <SerialDataBegin@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <SerialSendBytes@plt>
  mov    $0x0,%eax
  call   <SerialDataEnd@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SerialSendData(unsigned long *data, unsigned long len) {
  SerialDataBegin();
  SerialSendBytes(data, len);
  SerialDataEnd();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SerialSendData>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <SerialDataBegin@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SerialSendBytes@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1090 <SerialDataEnd@plt>
```

assistant: ```c
void SerialSendData(unsigned long *data, unsigned long len) {
  SerialDataBegin();
  SerialSendBytes(data, len);
  SerialDataEnd();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SerialSendData>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <SerialDataBegin@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SerialSendBytes@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1090 <SerialDataEnd@plt>
```

assistant: ```c
void SerialSendData(unsigned long *data, unsigned long len) {
  SerialDataBegin();
  SerialSendBytes(data, len);
  SerialDataEnd();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <basic_test@plt>
  mov    $0x0,%eax
  call   <random_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  basic_test();
  random_test();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <basic_test@plt>
  mov    $0x0,%eax
  call   <random_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  basic_test();
  random_test();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <basic_test@plt>
  xor    %eax,%eax
  call   <random_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  basic_test();
  random_test();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <basic_test@plt>
  xor    %eax,%eax
  call   <random_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  basic_test();
  random_test();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<path_dirname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <path_remove_trailing_slashes@plt>
  mov    -0x20(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  jmp    L3
L7:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  subq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L31
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L7
L31:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    -0x20(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L51
L17:
  mov    -0x20(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L51:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D7: /

tool: D2: .

assistant: ```c
void path_dirname(const char *path, char *dir) {
  char *c;
  strcpy(dir, path);
  path_remove_trailing_slashes(dir);
  c = strrchr(dir, '/');
  if (c) {
    for (; c >= dir && *c == '/'; c--)
      *c = 0;
    if (dir[0] == 0)
      strcpy(dir, "/");
  } else {
    strcpy(dir, ".");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<path_dirname>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <path_remove_trailing_slashes@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L0
  cmp    %rax,%rbx
  ja     L2
L60:
  cmpb   $0x2f,(%rax)
  jne    L2
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jbe    L60
L2:
  cmpb   $0x0,(%rbx)
  je     L44
L9:
  pop    %rbx
  ret
L44:
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L9
L0:
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D16
type_infered: string

tool: D18: /

tool: D16: .

assistant: ```c
void path_dirname(const char *path, char *dir) {
  char *c;
  strcpy(dir, path);
  path_remove_trailing_slashes(dir);
  c = strrchr(dir, '/');
  if (c) {
    for (; c >= dir && *c == '/'; c--)
      *c = 0;
    if (dir[0] == 0)
      strcpy(dir, "/");
  } else {
    strcpy(dir, ".");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<path_dirname>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <path_remove_trailing_slashes@plt>
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L8
  jmp    L5
  nop
L41:
  cmpb   $0x2f,(%rax)
  jne    L44
  movb   $0x0,(%rax)
  sub    $0x1,%rax
L8:
  cmp    %rax,%rbp
  jbe    L41
L44:
  cmpb   $0x0,0x0(%rbp)
  je     L42
  pop    %rbp
  ret
  nopl   0x0(%rax)
L42:
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  pop    %rbp
  jmp    1070 <strcpy@plt>
L5:
  mov    %rbp,%rdi
  lea    D14(%rip),%rsi
  pop    %rbp
  jmp    1070 <strcpy@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D14
type: string

tool: D7: /

tool: D14: .

assistant: ```c
void path_dirname(const char *path, char *dir) {
  char *c;
  strcpy(dir, path);
  path_remove_trailing_slashes(dir);
  c = strrchr(dir, '/');
  if (c) {
    for (; c >= dir && *c == '/'; c--)
      *c = 0;
    if (dir[0] == 0)
      strcpy(dir, "/");
  } else {
    strcpy(dir, ".");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<path_dirname>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <path_remove_trailing_slashes@plt>
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L15
  jmp    L8
  nop
L2:
  cmpb   $0x2f,(%rax)
  jne    L27
  movb   $0x0,(%rax)
  sub    $0x1,%rax
L15:
  cmp    %rax,%rbp
  jbe    L2
L27:
  cmpb   $0x0,0x0(%rbp)
  je     L1
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  pop    %rbp
  jmp    1070 <strcpy@plt>
L8:
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  pop    %rbp
  jmp    1070 <strcpy@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type: string
name: disassemble_data
arguments: tag: D15
type: string

tool: D11: /

tool: D15: .

assistant: ```c
void path_dirname(const char *path, char *dir) {
  char *c;
  strcpy(dir, path);
  path_remove_trailing_slashes(dir);
  c = strrchr(dir, '/');
  if (c) {
    for (; c >= dir && *c == '/'; c--)
      *c = 0;
    if (dir[0] == 0)
      strcpy(dir, "/");
  } else {
    strcpy(dir, ".");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mul5div8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x2,%eax
  add    %eax,-0x14(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L4
  addl   $0x7,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mul5div8(int x) {
  x = (x << 2) + x;
  int sign = x & INT_MIN;
  sign && (x = x + (1 << 3) - 1);
  int result = x >> 3;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mul5div8>:
  endbr64
  lea    (%rdi,%rdi,4),%edx
  mov    D5(%rip),%rax
  mov    %edx,%ecx
  and    (%rax),%ecx
  lea    0x7(%rdx),%eax
  cmove  %edx,%eax
  sar    $0x3,%eax
  ret
```

assistant: ```c
int mul5div8(int x) {
  x = (x << 2) + x;
  int sign = x & INT_MIN;
  sign && (x = x + (1 << 3) - 1);
  int result = x >> 3;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mul5div8>:
  endbr64
  mov    D5(%rip),%rax
  lea    (%rdi,%rdi,4),%edx
  mov    %edx,%ecx
  and    (%rax),%ecx
  lea    0x7(%rdx),%eax
  cmove  %edx,%eax
  sar    $0x3,%eax
  ret
```

assistant: ```c
int mul5div8(int x) {
  x = (x << 2) + x;
  int sign = x & INT_MIN;
  sign && (x = x + (1 << 3) - 1);
  int result = x >> 3;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mul5div8>:
  endbr64
  mov    D9(%rip),%rax
  lea    (%rdi,%rdi,4),%edx
  mov    %edx,%ecx
  and    (%rax),%ecx
  lea    0x7(%rdx),%eax
  cmove  %edx,%eax
  sar    $0x3,%eax
  ret
```

assistant: ```c
int mul5div8(int x) {
  x = (x << 2) + x;
  int sign = x & INT_MIN;
  sign && (x = x + (1 << 3) - 1);
  int result = x >> 3;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_func_01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  cwtl
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  cwtl
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  cwtl
  add    %eax,-0x4(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_func_01(short *p, int c) {
  int r = 0;
  do {
    r += *p++;
    r += *p++;
    r += *p++;
  } while (--c);
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_func_01>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    0x3(%rax,%rax,2),%rax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L3:
  movswl (%rdi),%edx
  add    %edx,%eax
  movswl 0x2(%rdi),%edx
  add    %eax,%edx
  add    $0x6,%rdi
  movswl -0x2(%rdi),%eax
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L3
  ret
```

assistant: ```c
int test_func_01(short *p, int c) {
  int r = 0;
  do {
    r += *p++;
    r += *p++;
    r += *p++;
  } while (--c);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_func_01>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    0x3(%rax,%rax,2),%rax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  movswl (%rdi),%edx
  add    $0x6,%rdi
  add    %edx,%eax
  movswl -0x4(%rdi),%edx
  add    %eax,%edx
  movswl -0x2(%rdi),%eax
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L2
  ret
```

assistant: ```c
int test_func_01(short *p, int c) {
  int r = 0;
  do {
    r += *p++;
    r += *p++;
    r += *p++;
  } while (--c);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_func_01>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%r8d
  lea    -0x1(%rsi),%esi
  mov    %rdi,%rdx
  cmp    $0x6,%esi
  jbe    L73
  mov    %ecx,%esi
  pxor   %xmm6,%xmm6
  pxor   %xmm4,%xmm4
  mov    %rdi,%rax
  movdqa %xmm6,%xmm7
  shr    $0x3,%esi
  movdqa %xmm6,%xmm8
  movdqa %xmm6,%xmm0
  sub    $0x1,%esi
  movdqa %xmm6,%xmm9
  movdqa %xmm6,%xmm10
  lea    (%rsi,%rsi,2),%rsi
  shl    $0x4,%rsi
  lea    0x30(%rdi,%rsi,1),%rsi
  nop
L90:
  movdqu (%rax),%xmm3
  movdqa %xmm4,%xmm5
  movdqu 0x10(%rax),%xmm2
  add    $0x30,%rax
  movdqu -0x10(%rax),%xmm1
  pcmpgtw %xmm3,%xmm5
  movdqa %xmm3,%xmm11
  punpckhwd %xmm5,%xmm3
  punpcklwd %xmm5,%xmm11
  movdqa %xmm2,%xmm5
  paddd  %xmm3,%xmm10
  movdqa %xmm4,%xmm3
  paddd  %xmm11,%xmm0
  pcmpgtw %xmm2,%xmm3
  punpckhwd %xmm3,%xmm2
  punpcklwd %xmm3,%xmm5
  movdqa %xmm1,%xmm3
  paddd  %xmm2,%xmm8
  movdqa %xmm4,%xmm2
  paddd  %xmm5,%xmm9
  pcmpgtw %xmm1,%xmm2
  punpcklwd %xmm2,%xmm3
  punpckhwd %xmm2,%xmm1
  paddd  %xmm3,%xmm7
  paddd  %xmm1,%xmm6
  cmp    %rsi,%rax
  jne    L90
  paddd  %xmm10,%xmm0
  mov    %ecx,%esi
  paddd  %xmm9,%xmm0
  and    $0xfffffff8,%esi
  paddd  %xmm8,%xmm0
  mov    %esi,%edi
  sub    %esi,%ecx
  paddd  %xmm7,%xmm0
  lea    (%rdi,%rdi,2),%rdi
  paddd  %xmm6,%xmm0
  lea    (%rdx,%rdi,2),%rdx
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%r8d
  je     L78
  lea    -0x1(%rcx),%esi
L6:
  movswl (%rdx),%edi
  add    %edi,%eax
  movswl 0x2(%rdx),%edi
  add    %eax,%edi
  movswl 0x4(%rdx),%eax
  add    %edi,%eax
  test   %esi,%esi
  je     L78
  movswl 0x6(%rdx),%esi
  add    %esi,%eax
  movswl 0x8(%rdx),%esi
  add    %eax,%esi
  movswl 0xa(%rdx),%eax
  add    %esi,%eax
  cmp    $0x2,%ecx
  je     L78
  movswl 0xc(%rdx),%esi
  add    %esi,%eax
  movswl 0xe(%rdx),%esi
  add    %eax,%esi
  movswl 0x10(%rdx),%eax
  add    %esi,%eax
  cmp    $0x3,%ecx
  je     L78
  movswl 0x12(%rdx),%esi
  add    %esi,%eax
  movswl 0x14(%rdx),%esi
  add    %eax,%esi
  movswl 0x16(%rdx),%eax
  add    %esi,%eax
  cmp    $0x4,%ecx
  je     L78
  movswl 0x18(%rdx),%esi
  add    %esi,%eax
  movswl 0x1a(%rdx),%esi
  add    %eax,%esi
  movswl 0x1c(%rdx),%eax
  add    %esi,%eax
  cmp    $0x5,%ecx
  je     L78
  movswl 0x1e(%rdx),%esi
  add    %esi,%eax
  movswl 0x20(%rdx),%esi
  add    %eax,%esi
  movswl 0x22(%rdx),%eax
  add    %esi,%eax
  cmp    $0x6,%ecx
  je     L78
  movswl 0x24(%rdx),%ecx
  add    %ecx,%eax
  movswl 0x26(%rdx),%ecx
  add    %eax,%ecx
  movswl 0x28(%rdx),%eax
  add    %ecx,%eax
L78:
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  xor    %eax,%eax
  jmp    L6
```

assistant: ```c
int test_func_01(short *p, int c) {
  int r = 0;
  do {
    r += *p++;
    r += *p++;
    r += *p++;
  } while (--c);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L8
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L19
L8:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D5: 	Hola, mi nombre es Humberto :)

tool: D12: 	Hola, mi nombre es %s :)


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("\tHola, mi nombre es Humberto :)\n");
  } else {
    printf("\tHola, mi nombre es %s :)\n", argv[1]);
  }
  return 0;
}
```