ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_nmea_checksum>:
  endbr64
  test   %rsi,%rsi
  je     L75
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L22
  call   <nmea_checksum@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L41
L84:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    $0x2a,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
  mov    $0x1,%eax
  cmpb   $0x2a,(%rbx)
  jne    L84
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L84
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L84
  lea    0x1(%rbx),%rdi
  call   <ahextobin@plt>
  shl    $0x4,%eax
  mov    %eax,%r12d
  lea    0x2(%rbx),%rdi
  call   <ahextobin@plt>
  add    %eax,%r12d
  cmp    %r12b,0x0(%rbp)
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  jmp    L84
L22:
  mov    $0x2,%eax
  jmp    L84
L37:
  mov    $0x2,%eax
  jmp    L84
L75:
  mov    $0x2,%eax
  ret
```

assistant: ```c
unsigned int check_nmea_checksum(char *buffer, unsigned char *checksum) {
  unsigned int rv;
  char *p;
  unsigned char ssum;
  if (!buffer)
    return 2;
  if (!checksum)
    return 2;
  if (!(rv = nmea_checksum(buffer, checksum))) {
    if ((p = strchr((char *)buffer, '*')) == NULL)
      return 2;
    if (*p == '*') {
      if (isxdigit(*(p + 1)) && isxdigit(*(p + 2))) {
        ssum = ahextobin(p + 1) << 4;
        ssum += ahextobin(p + 2);
        if (ssum == *checksum)
          return 0;
      } else {
        return 1;
      }
    } else {
      return 1;
    }
  }
  return 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_nmea_checksum>:
  endbr64
  test   %rdi,%rdi
  je     L52
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L15
  mov    %rdi,%rbp
  call   <nmea_checksum@plt>
  test   %eax,%eax
  je     L57
L15:
  mov    $0x2,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L57:
  mov    %rbp,%rdi
  mov    $0x2a,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
  cmpb   $0x2a,(%rax)
  je     L37
L8:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L37:
  movsbl 0x1(%rax),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L8
  movsbl 0x2(%rbp),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L8
  lea    0x1(%rbp),%rdi
  call   <ahextobin@plt>
  lea    0x2(%rbp),%rdi
  shl    $0x4,%eax
  mov    %eax,%r12d
  call   <ahextobin@plt>
  add    %eax,%r12d
  xor    %eax,%eax
  cmp    %r12b,(%rbx)
  setne  %al
  add    %eax,%eax
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L52:
  mov    $0x2,%eax
  ret
```

assistant: ```c
unsigned int check_nmea_checksum(char *buffer, unsigned char *checksum) {
  unsigned int rv;
  char *p;
  unsigned char ssum;
  if (!buffer)
    return 2;
  if (!checksum)
    return 2;
  if (!(rv = nmea_checksum(buffer, checksum))) {
    if ((p = strchr((char *)buffer, '*')) == NULL)
      return 2;
    if (*p == '*') {
      if (isxdigit(*(p + 1)) && isxdigit(*(p + 2))) {
        ssum = ahextobin(p + 1) << 4;
        ssum += ahextobin(p + 2);
        if (ssum == *checksum)
          return 0;
      } else {
        return 1;
      }
    } else {
      return 1;
    }
  }
  return 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_nmea_checksum>:
  endbr64
  test   %rdi,%rdi
  je     L28
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L60
  mov    %rdi,%rbp
  call   <nmea_checksum@plt>
  test   %eax,%eax
  je     L75
L60:
  mov    $0x2,%eax
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L75:
  mov    %rbp,%rdi
  mov    $0x2a,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L60
  cmpb   $0x2a,(%rax)
  je     L77
L67:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L77:
  movsbl 0x1(%rax),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L67
  movsbl 0x2(%rbp),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L67
  lea    0x1(%rbp),%rdi
  call   <ahextobin@plt>
  lea    0x2(%rbp),%rdi
  shl    $0x4,%eax
  mov    %eax,%r12d
  call   <ahextobin@plt>
  add    %eax,%r12d
  xor    %eax,%eax
  cmp    %r12b,(%rbx)
  setne  %al
  add    %eax,%eax
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x2,%eax
  ret
```

assistant: ```c
unsigned int check_nmea_checksum(char *buffer, unsigned char *checksum) {
  unsigned int rv;
  char *p;
  unsigned char ssum;
  if (!buffer)
    return 2;
  if (!checksum)
    return 2;
  if (!(rv = nmea_checksum(buffer, checksum))) {
    if ((p = strchr((char *)buffer, '*')) == NULL)
      return 2;
    if (*p == '*') {
      if (isxdigit(*(p + 1)) && isxdigit(*(p + 2))) {
        ssum = ahextobin(p + 1) << 4;
        ssum += ahextobin(p + 2);
        if (ssum == *checksum)
          return 0;
      } else {
        return 1;
      }
    } else {
      return 1;
    }
  }
  return 2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strpcbrknul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rax
  mov    %rax,-0x118(%rbp)
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L60
L3:
  movsbq -0x119(%rbp),%rax
  movb   $0x1,-0x110(%rbp,%rax,1)
L60:
  mov    -0x130(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x130(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x119(%rbp)
  cmpb   $0x0,-0x119(%rbp)
  jne    L3
  jmp    L22
L63:
  movsbq -0x119(%rbp),%rax
  movzbl -0x110(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L23
L22:
  mov    -0x118(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x118(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x119(%rbp)
  cmpb   $0x0,-0x119(%rbp)
  jne    L63
  jmp    L0
L23:
  nop
L0:
  mov    -0x118(%rbp),%rax
  sub    $0x1,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
char *(strpcbrknul)(const char *string, const char *skipset) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256 * sizeof(char));
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  while ((c = *s++))
    if (set[(size_t)c])
      break;
  return s - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strpcbrknul>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x100,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x1(%rbp),%rdx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L28
L35:
  movsbq %al,%rax
  movb   $0x1,(%rsp,%rax,1)
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L35
L28:
  mov    %rbx,%rdx
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L25
  movsbq %al,%rax
  cmpb   $0x0,(%rsp,%rax,1)
  je     L28
L25:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %rdx,%rax
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *(strpcbrknul)(const char *string, const char *skipset) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256 * sizeof(char));
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  while ((c = *s++))
    if (set[(size_t)c])
      break;
  return s - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strpcbrknul>:
  endbr64
  push   %rbp
  mov    $0x100,%edx
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movsbq 0x0(%rbp),%rax
  test   %al,%al
  je     L51
  lea    0x1(%rbp),%rdx
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rdx
  movb   $0x1,(%rsp,%rax,1)
  movsbq -0x1(%rdx),%rax
  test   %al,%al
  jne    L4
  mov    %rbx,%r8
  movsbq (%rbx),%rax
  add    $0x1,%rbx
  test   %al,%al
  je     L52
  nopl   0x0(%rax,%rax,1)
L5:
  cmpb   $0x0,(%rsp,%rax,1)
  jne    L52
L51:
  mov    %rbx,%r8
  movsbq (%rbx),%rax
  add    $0x1,%rbx
  test   %al,%al
  jne    L5
L52:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x118,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *(strpcbrknul)(const char *string, const char *skipset) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256 * sizeof(char));
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  while ((c = *s++))
    if (set[(size_t)c])
      break;
  return s - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strpcbrknul>:
  endbr64
  push   %rbp
  mov    $0x100,%edx
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movsbq 0x0(%rbp),%rax
  test   %al,%al
  je     L14
  lea    0x1(%rbp),%rdx
  nopw   0x0(%rax,%rax,1)
L52:
  add    $0x1,%rdx
  movb   $0x1,(%rsp,%rax,1)
  movsbq -0x1(%rdx),%rax
  test   %al,%al
  jne    L52
  mov    %rbx,%r8
  movsbq (%rbx),%rax
  add    $0x1,%rbx
  test   %al,%al
  je     L12
  nopl   0x0(%rax,%rax,1)
L16:
  cmpb   $0x0,(%rsp,%rax,1)
  jne    L12
L14:
  mov    %rbx,%r8
  movsbq (%rbx),%rax
  add    $0x1,%rbx
  test   %al,%al
  jne    L16
L12:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x118,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *(strpcbrknul)(const char *string, const char *skipset) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256 * sizeof(char));
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  while ((c = *s++))
    if (set[(size_t)c])
      break;
  return s - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int file_exists(char *path) {
  struct stat st;
  return (0 == stat(path, &st));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(char *path) {
  struct stat st;
  return (0 == stat(path, &st));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(char *path) {
  struct stat st;
  return (0 == stat(path, &st));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(char *path) {
  struct stat st;
  return (0 == stat(path, &st));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<softfloat_tryPropagateNaNF128M>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <softfloat_isNaNF128M@plt>
  test   %rax,%rax
  jne    L22
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <softfloat_isNaNF128M@plt>
  test   %rax,%rax
  je     L5
L22:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <softfloat_propagateNaNF128M@plt>
  mov    $0x1,%eax
  jmp    L26
L5:
  mov    $0x0,%eax
L26:
  leave
  ret
```

assistant: ```c
bool softfloat_tryPropagateNaNF128M(const uint32_t *aWPtr, const uint32_t *bWPtr, uint32_t *zWPtr) {
  if (softfloat_isNaNF128M(aWPtr) || softfloat_isNaNF128M(bWPtr)) {
    softfloat_propagateNaNF128M(aWPtr, bWPtr, zWPtr);
    return true;
  }
  return false;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<softfloat_tryPropagateNaNF128M>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <softfloat_isNaNF128M@plt>
  test   %rax,%rax
  jne    L10
  mov    %rbp,%rdi
  call   <softfloat_isNaNF128M@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L6
L10:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <softfloat_propagateNaNF128M@plt>
  mov    $0x1,%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool softfloat_tryPropagateNaNF128M(const uint32_t *aWPtr, const uint32_t *bWPtr, uint32_t *zWPtr) {
  if (softfloat_isNaNF128M(aWPtr) || softfloat_isNaNF128M(bWPtr)) {
    softfloat_propagateNaNF128M(aWPtr, bWPtr, zWPtr);
    return true;
  }
  return false;
}
```
user: What is the c source code of the assembly code below:

```asm
<softfloat_tryPropagateNaNF128M>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <softfloat_isNaNF128M@plt>
  test   %rax,%rax
  jne    L12
  mov    %r12,%rdi
  call   <softfloat_isNaNF128M@plt>
  test   %rax,%rax
  jne    L12
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L12:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <softfloat_propagateNaNF128M@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool softfloat_tryPropagateNaNF128M(const uint32_t *aWPtr, const uint32_t *bWPtr, uint32_t *zWPtr) {
  if (softfloat_isNaNF128M(aWPtr) || softfloat_isNaNF128M(bWPtr)) {
    softfloat_propagateNaNF128M(aWPtr, bWPtr, zWPtr);
    return true;
  }
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<softfloat_tryPropagateNaNF128M>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <softfloat_isNaNF128M@plt>
  test   %rax,%rax
  jne    L11
  mov    %r12,%rdi
  call   <softfloat_isNaNF128M@plt>
  test   %rax,%rax
  jne    L11
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L11:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <softfloat_propagateNaNF128M@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool softfloat_tryPropagateNaNF128M(const uint32_t *aWPtr, const uint32_t *bWPtr, uint32_t *zWPtr) {
  if (softfloat_isNaNF128M(aWPtr) || softfloat_isNaNF128M(bWPtr)) {
    softfloat_propagateNaNF128M(aWPtr, bWPtr, zWPtr);
    return true;
  }
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L9:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x4,-0x8(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  add    $0x24,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L9
  mov    -0x18(%rbp),%rax
  add    $0x24,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string

tool: D8: %d,

tool: D16: %d


assistant: ```c
void output(int array[]) {
  int *p;
  for (p = array; p < array + 9; p++)
    printf("%d,", *p);
  printf("%d\n", array[9]);
}
```
user: What is the c source code of the assembly code below:

```asm
<output>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  lea    0x24(%rdi),%r12
  mov    %rdi,%rbx
  lea    D18(%rip),%rbp
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  mov    0x24(%r13),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string

tool: D18: %d,

tool: D0: %d


assistant: ```c
void output(int array[]) {
  int *p;
  for (p = array; p < array + 9; p++)
    printf("%d,", *p);
  printf("%d\n", array[9]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x24(%rdi),%r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nop
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    0x24(%r13),%esi
  add    $0x8,%rsp
  lea    D10(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
type: string
name: disassemble_data
arguments: tag: D10
type: string

tool: D12: %d,

tool: D10: %d


assistant: ```c
void output(int array[]) {
  int *p;
  for (p = array; p < array + 9; p++)
    printf("%d,", *p);
  printf("%d\n", array[9]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<output>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x24(%rdi),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nop
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    0x24(%r13),%esi
  add    $0x8,%rsp
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D19: %d,

tool: D8: %d


assistant: ```c
void output(int array[]) {
  int *p;
  for (p = array; p < array + 9; p++)
    printf("%d,", *p);
  printf("%d\n", array[9]);
}
```
user: What is the c source code of the assembly code below:

```asm
<count_doubles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L54
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L13
L54:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L13
  addl   $0x1,-0xc(%rbp)
  jmp    L34
L13:
  movl   $0x0,-0x4(%rbp)
L34:
  addl   $0x2,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jbe    L22
  cmpl   $0x0,-0x4(%rbp)
  jne    L36
L22:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_doubles(const unsigned char source[], const int posn, const size_t src_len) {
  int c = 0;
  int i = posn;
  int cond = 1;
  do {
    if (((source[i] == '.') || (source[i] == ',')) && (source[i + 1] == ' ')) {
      c++;
    } else {
      cond = 0;
    }
    i += 2;
  } while ((i < src_len) && cond);
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<count_doubles>:
  endbr64
  movslq %esi,%rsi
  mov    $0x0,%ecx
  jmp    L30
L26:
  add    $0x1,%ecx
  add    $0x2,%rsi
  cmp    %rsi,%rdx
  jbe    L23
L30:
  movzbl (%rdi,%rsi,1),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  jne    L23
  cmpb   $0x20,0x1(%rdi,%rsi,1)
  je     L26
L23:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int count_doubles(const unsigned char source[], const int posn, const size_t src_len) {
  int c = 0;
  int i = posn;
  int cond = 1;
  do {
    if (((source[i] == '.') || (source[i] == ',')) && (source[i + 1] == ' ')) {
      c++;
    } else {
      cond = 0;
    }
    i += 2;
  } while ((i < src_len) && cond);
  return c;
}
```
user: What is the c source code of the assembly code below?

```asm
<count_doubles>:
  endbr64
  movslq %esi,%rsi
  xor    %r8d,%r8d
L28:
  movzbl (%rdi,%rsi,1),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  jne    L23
  cmpb   $0x20,0x1(%rdi,%rsi,1)
  jne    L23
  add    $0x2,%rsi
  add    $0x1,%r8d
  cmp    %rdx,%rsi
  jb     L28
L23:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_doubles(const unsigned char source[], const int posn, const size_t src_len) {
  int c = 0;
  int i = posn;
  int cond = 1;
  do {
    if (((source[i] == '.') || (source[i] == ',')) && (source[i + 1] == ' ')) {
      c++;
    } else {
      cond = 0;
    }
    i += 2;
  } while ((i < src_len) && cond);
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<count_doubles>:
  endbr64
  movslq %esi,%rsi
  xor    %r8d,%r8d
L8:
  movzbl (%rdi,%rsi,1),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  jne    L14
  cmpb   $0x20,0x1(%rdi,%rsi,1)
  jne    L14
  add    $0x2,%rsi
  add    $0x1,%r8d
  cmp    %rsi,%rdx
  ja     L8
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_doubles(const unsigned char source[], const int posn, const size_t src_len) {
  int c = 0;
  int i = posn;
  int cond = 1;
  do {
    if (((source[i] == '.') || (source[i] == ',')) && (source[i + 1] == ' ')) {
      c++;
    } else {
      cond = 0;
    }
    i += 2;
  } while ((i < src_len) && cond);
  return c;
}
```