ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf4000(%rsp),%r11
L37:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L37
  sub    $0x250,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf4248(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xf4241,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x1,%ebx
  lea    D7(%rip),%r12
  jmp    L7
L21:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L58
L15:
  add    $0x1,%rbx
  cmp    $0xf4241,%rbx
  je     L13
L7:
  mov    %ebx,%ebp
  cmpb   $0x0,(%rsp,%rbx,1)
  je     L21
L58:
  mov    %ebp,%edi
  call   <generate_next_num@plt>
  cmp    $0xf4240,%eax
  jg     L15
  cltq
  movb   $0x1,(%rsp,%rax,1)
  jmp    L15
L13:
  mov    0xf4248(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0xf4250,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: %u


assistant: ```c
int main() {
  char check_self_num[1000001];
  int i, next;
  memset(&check_self_num[0], 0x0, sizeof(char) * 1000001);
  for (i = 1; i < 1000001; i++) {
    if (check_self_num[i] == 0x0) {
      printf("%u\n", i);
    }
    next = generate_next_num(i);
    if (next < 1000001) {
      check_self_num[next] = 0x1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf4000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x258,%rsp
  mov    $0xf4241,%edx
  xor    %esi,%esi
  mov    $0x1,%ebx
  lea    D0(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0xf4248(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  jmp    L19
  nopl   (%rax)
L17:
  mov    %r13d,%edi
  call   <generate_next_num@plt>
  cmp    $0xf4240,%eax
  jg     L54
  cltq
  movb   $0x1,(%rsp,%rax,1)
L54:
  add    $0x1,%rbx
  cmp    $0xf4241,%rbx
  je     L22
L19:
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  mov    %ebx,%r13d
  jne    L17
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L17
L22:
  mov    0xf4248(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0xf4258,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: %u


assistant: ```c
int main() {
  char check_self_num[1000001];
  int i, next;
  memset(&check_self_num[0], 0x0, sizeof(char) * 1000001);
  for (i = 1; i < 1000001; i++) {
    if (check_self_num[i] == 0x0) {
      printf("%u\n", i);
    }
    next = generate_next_num(i);
    if (next < 1000001) {
      check_self_num[next] = 0x1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf4000(%rsp),%r11
L66:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L66
  sub    $0x258,%rsp
  mov    $0xf4241,%edx
  xor    %esi,%esi
  mov    $0x1,%ebx
  lea    D4(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0xf4248(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  jmp    L38
  nopl   (%rax)
L54:
  mov    %r13d,%edi
  call   <generate_next_num@plt>
  cmp    $0xf4240,%eax
  jg     L17
  cltq
  movb   $0x1,(%rsp,%rax,1)
L17:
  add    $0x1,%rbx
  cmp    $0xf4241,%rbx
  je     L62
L38:
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  mov    %ebx,%r13d
  jne    L54
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L54
L62:
  mov    0xf4248(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0xf4258,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string

tool: D4: %u


assistant: ```c
int main() {
  char check_self_num[1000001];
  int i, next;
  memset(&check_self_num[0], 0x0, sizeof(char) * 1000001);
  for (i = 1; i < 1000001; i++) {
    if (check_self_num[i] == 0x0) {
      printf("%u\n", i);
    }
    next = generate_next_num(i);
    if (next < 1000001) {
      check_self_num[next] = 0x1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isheader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L11
  mov    $0x1,%eax
  jmp    L10
L11:
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
int isheader(char *string) {
  if (string[0] == '[' && string[strlen(string) - 1] == ']') {
    return (1);
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isheader>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x5b,(%rdi)
  je     L9
  ret
L9:
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x5d,-0x1(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isheader(char *string) {
  if (string[0] == '[' && string[strlen(string) - 1] == ']') {
    return (1);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isheader>:
  endbr64
  cmpb   $0x5b,(%rdi)
  je     L4
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L4:
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x5d,-0x1(%rbx,%rax,1)
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isheader(char *string) {
  if (string[0] == '[' && string[strlen(string) - 1] == ']') {
    return (1);
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isheader>:
  endbr64
  cmpb   $0x5b,(%rdi)
  je     L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x5d,-0x1(%rbx,%rax,1)
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isheader(char *string) {
  if (string[0] == '[' && string[strlen(string) - 1] == ']') {
    return (1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mus_lfloat_to_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl 0x3(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mus_lfloat_to_char(unsigned char *j, float x) {
  unsigned char *ox;
  ox = (unsigned char *)&x;
  j[0] = ox[3];
  j[1] = ox[2];
  j[2] = ox[1];
  j[3] = ox[0];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mus_lfloat_to_char>:
  endbr64
  movd   %xmm0,%eax
  movd   %xmm0,%edx
  shr    $0x18,%edx
  mov    %dl,(%rdi)
  movd   %xmm0,%edx
  shr    $0x10,%edx
  mov    %dl,0x1(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void mus_lfloat_to_char(unsigned char *j, float x) {
  unsigned char *ox;
  ox = (unsigned char *)&x;
  j[0] = ox[3];
  j[1] = ox[2];
  j[2] = ox[1];
  j[3] = ox[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mus_lfloat_to_char>:
  endbr64
  movd   %xmm0,%edx
  movd   %xmm0,%eax
  shr    $0x18,%edx
  mov    %ah,0x2(%rdi)
  mov    %dl,(%rdi)
  movd   %xmm0,%edx
  shr    $0x10,%edx
  mov    %al,0x3(%rdi)
  mov    %dl,0x1(%rdi)
  ret
```

assistant: ```c
void mus_lfloat_to_char(unsigned char *j, float x) {
  unsigned char *ox;
  ox = (unsigned char *)&x;
  j[0] = ox[3];
  j[1] = ox[2];
  j[2] = ox[1];
  j[3] = ox[0];
}
```
user: What is the c source code of the assembly code below?

```asm
<mus_lfloat_to_char>:
  endbr64
  movd   %xmm0,%edx
  movd   %xmm0,%eax
  shr    $0x18,%edx
  mov    %ah,0x2(%rdi)
  mov    %dl,(%rdi)
  movd   %xmm0,%edx
  shr    $0x10,%edx
  mov    %al,0x3(%rdi)
  mov    %dl,0x1(%rdi)
  ret
```

assistant: ```c
void mus_lfloat_to_char(unsigned char *j, float x) {
  unsigned char *ox;
  ox = (unsigned char *)&x;
  j[0] = ox[3];
  j[1] = ox[2];
  j[2] = ox[1];
  j[3] = ox[0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x20(%rbp)
  jae    L4
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L6
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <u_strlcpy@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strlncpy(char *dest, const char *src, size_t l, size_t n) {
  if (n < (l - 1)) {
    strncpy(dest, src, n);
    dest[n] = '\0';
  } else
    u_strlcpy(dest, src, l);
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlncpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rdx),%rax
  cmp    %rcx,%rax
  jbe    L6
  mov    %rcx,%rbp
  mov    %rcx,%rdx
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
L19:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <u_strlcpy@plt>
  jmp    L19
```

assistant: ```c
char *strlncpy(char *dest, const char *src, size_t l, size_t n) {
  if (n < (l - 1)) {
    strncpy(dest, src, n);
    dest[n] = '\0';
  } else
    u_strlcpy(dest, src, l);
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlncpy>:
  endbr64
  push   %r12
  lea    -0x1(%rdx),%rax
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rcx,%rax
  jbe    L7
  mov    %rcx,%rbx
  mov    %rcx,%rdx
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  call   <u_strlcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strlncpy(char *dest, const char *src, size_t l, size_t n) {
  if (n < (l - 1)) {
    strncpy(dest, src, n);
    dest[n] = '\0';
  } else
    u_strlcpy(dest, src, l);
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strlncpy>:
  endbr64
  push   %r12
  lea    -0x1(%rdx),%rax
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rcx,%rax
  jbe    L8
  mov    %rcx,%rbx
  mov    %rcx,%rdx
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  call   <u_strlcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strlncpy(char *dest, const char *src, size_t l, size_t n) {
  if (n < (l - 1)) {
    strncpy(dest, src, n);
    dest[n] = '\0';
  } else
    u_strlcpy(dest, src, l);
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<select_resolved_host>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
L27:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L10
  cmpb   $0x0,-0x1c(%rbp)
  je     L10
  mov    -0x8(%rbp),%rax
  jmp    L60
L10:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L66
  mov    -0x8(%rbp),%rax
  jmp    L60
L66:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
L49:
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0x0,%eax
L60:
  pop    %rbp
  ret
```

assistant: ```c
struct addrinfo *select_resolved_host(struct addrinfo *ai, char use_ipv6) {
  struct addrinfo *p = ai;
  while (p) {
    if (p->ai_family == AF_INET6 && use_ipv6)
      return p;
    if (p->ai_family == AF_INET)
      return p;
    p = p->ai_next;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<select_resolved_host>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L10
  mov    D9(%rip),%rdx
  mov    (%rdx),%rdi
  mov    D12(%rip),%rdx
  mov    (%rdx),%rcx
  jmp    L31
L53:
  cmp    %rcx,%rdx
  je     L10
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L10
L31:
  mov    (%rax),%rdx
  test   %sil,%sil
  je     L53
  cmp    %rdi,%rdx
  jne    L53
L10:
  ret
```

assistant: ```c
struct addrinfo *select_resolved_host(struct addrinfo *ai, char use_ipv6) {
  struct addrinfo *p = ai;
  while (p) {
    if (p->ai_family == AF_INET6 && use_ipv6)
      return p;
    if (p->ai_family == AF_INET)
      return p;
    p = p->ai_next;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<select_resolved_host>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L42
  mov    D6(%rip),%rdx
  test   %sil,%sil
  setne  %sil
  mov    (%rdx),%rcx
  mov    D2(%rip),%rdx
  mov    (%rdx),%rdi
  jmp    L23
  nopl   0x0(%rax)
L32:
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L38
L23:
  mov    (%rax),%rdx
  cmp    %rcx,%rdx
  jne    L22
  test   %sil,%sil
  jne    L13
L22:
  cmp    %rdi,%rdx
  jne    L32
L13:
  ret
  nopl   0x0(%rax)
L38:
  ret
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct addrinfo *select_resolved_host(struct addrinfo *ai, char use_ipv6) {
  struct addrinfo *p = ai;
  while (p) {
    if (p->ai_family == AF_INET6 && use_ipv6)
      return p;
    if (p->ai_family == AF_INET)
      return p;
    p = p->ai_next;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<select_resolved_host>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L17
  mov    D14(%rip),%rdx
  test   %sil,%sil
  setne  %sil
  mov    (%rdx),%rcx
  mov    D0(%rip),%rdx
  mov    (%rdx),%rdi
  jmp    L53
  nopl   0x0(%rax)
L39:
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L34
L53:
  mov    (%rax),%rdx
  cmp    %rcx,%rdx
  jne    L3
  test   %sil,%sil
  jne    L50
L3:
  cmp    %rdi,%rdx
  jne    L39
L50:
  ret
  nopl   0x0(%rax)
L34:
  ret
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct addrinfo *select_resolved_host(struct addrinfo *ai, char use_ipv6) {
  struct addrinfo *p = ai;
  while (p) {
    if (p->ai_family == AF_INET6 && use_ipv6)
      return p;
    if (p->ai_family == AF_INET)
      return p;
    p = p->ai_next;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ipfw_new_chain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <add_command@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <ipfw_init@plt>
  mov    D0(%rip),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int ipfw_new_chain(int args, char **arglist, const char *chain) {
  unsigned int command = 0;
  add_command(&command, 0x0100u, 0x0000U);
  ipfw_init(args, arglist, command, chain, 0);
  optind = 0;
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<ipfw_new_chain>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x0,%edx
  mov    $0x100,%esi
  call   <add_command@plt>
  mov    $0x0,%r8d
  mov    %r12,%rcx
  mov    0x4(%rsp),%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <ipfw_init@plt>
  mov    D5(%rip),%rax
  movq   $0x0,(%rax)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipfw_new_chain(int args, char **arglist, const char *chain) {
  unsigned int command = 0;
  add_command(&command, 0x0100u, 0x0000U);
  ipfw_init(args, arglist, command, chain, 0);
  optind = 0;
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipfw_new_chain>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  xor    %edx,%edx
  push   %r12
  mov    %rsi,%r12
  mov    $0x100,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <add_command@plt>
  mov    0x4(%rsp),%edx
  xor    %r8d,%r8d
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <ipfw_init@plt>
  mov    D2(%rip),%rax
  movq   $0x0,(%rax)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipfw_new_chain(int args, char **arglist, const char *chain) {
  unsigned int command = 0;
  add_command(&command, 0x0100u, 0x0000U);
  ipfw_init(args, arglist, command, chain, 0);
  optind = 0;
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ipfw_new_chain>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  xor    %edx,%edx
  push   %r12
  mov    %rsi,%r12
  mov    $0x100,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <add_command@plt>
  mov    0x4(%rsp),%edx
  xor    %r8d,%r8d
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <ipfw_init@plt>
  mov    D2(%rip),%rax
  movq   $0x0,(%rax)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipfw_new_chain(int args, char **arglist, const char *chain) {
  unsigned int command = 0;
  add_command(&command, 0x0100u, 0x0000U);
  ipfw_init(args, arglist, command, chain, 0);
  optind = 0;
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vabsdiffu2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x0,%ax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  mov    $0x0,%ax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  or     %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int vabsdiffu2(unsigned int a, unsigned int b) {
  unsigned int r, s;
  unsigned int t, u, v;
  s = a & 0x0000ffff;
  r = b & 0x0000ffff;
  u = max(r, s);
  v = min(r, s);
  s = a & 0xffff0000;
  r = b & 0xffff0000;
  t = max(r, s);
  s = min(r, s);
  r = u | t;
  s = v | s;
  r = r - s;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vabsdiffu2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  movzwl %di,%r14d
  movzwl %si,%r13d
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <max@plt>
  mov    %eax,%ebx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <min@plt>
  mov    %eax,%r13d
  mov    $0x0,%r12w
  mov    $0x0,%bp
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <max@plt>
  mov    %eax,%r14d
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <min@plt>
  or     %r14d,%ebx
  or     %eax,%r13d
  mov    %ebx,%eax
  sub    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int vabsdiffu2(unsigned int a, unsigned int b) {
  unsigned int r, s;
  unsigned int t, u, v;
  s = a & 0x0000ffff;
  r = b & 0x0000ffff;
  u = max(r, s);
  v = min(r, s);
  s = a & 0xffff0000;
  r = b & 0xffff0000;
  t = max(r, s);
  s = min(r, s);
  r = u | t;
  s = v | s;
  r = r - s;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vabsdiffu2>:
  endbr64
  push   %r14
  movzwl %di,%r14d
  push   %r13
  movzwl %si,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %esi,%ebp
  mov    %r14d,%esi
  xor    %r12w,%r12w
  push   %rbx
  xor    %bp,%bp
  call   <max@plt>
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    %eax,%ebx
  call   <min@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <max@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <min@plt>
  or     %r14d,%ebx
  or     %eax,%r13d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int vabsdiffu2(unsigned int a, unsigned int b) {
  unsigned int r, s;
  unsigned int t, u, v;
  s = a & 0x0000ffff;
  r = b & 0x0000ffff;
  u = max(r, s);
  v = min(r, s);
  s = a & 0xffff0000;
  r = b & 0xffff0000;
  t = max(r, s);
  s = min(r, s);
  r = u | t;
  s = v | s;
  r = r - s;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vabsdiffu2>:
  endbr64
  push   %r14
  movzwl %di,%r14d
  push   %r13
  movzwl %si,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %esi,%ebp
  mov    %r14d,%esi
  xor    %r12w,%r12w
  push   %rbx
  xor    %bp,%bp
  call   <max@plt>
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    %eax,%ebx
  call   <min@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <max@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <min@plt>
  or     %r14d,%ebx
  or     %eax,%r13d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int vabsdiffu2(unsigned int a, unsigned int b) {
  unsigned int r, s;
  unsigned int t, u, v;
  s = a & 0x0000ffff;
  r = b & 0x0000ffff;
  u = max(r, s);
  v = min(r, s);
  s = a & 0xffff0000;
  r = b & 0xffff0000;
  t = max(r, s);
  s = min(r, s);
  r = u | t;
  s = v | s;
  r = r - s;
  return r;
}
```