user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x450,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D20(%rip),%rdx
  mov    $0x2580,%esi
  call   <initSerial@plt>
  movq   $0x0,0x10(%rsp)
  movq   $0x5,0x18(%rsp)
  movq   $0xff0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x80,0x30(%rsp)
  movq   $0xff0,0x38(%rsp)
  movl   $0xa3,0x4(%rsp)
  mov    (%rsp),%edi
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%eax
  call   <write@plt>
  lea    0x10(%rsp),%rbx
  lea    0x40(%rsp),%rbp
L0:
  mov    (%rsp),%edi
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    $0x0,%eax
  call   <write@plt>
  add    $0x8,%rbx
  cmp    %rbx,%rbp
  jne    L0
  movq   $0x0,0x8(%rsp)
  mov    (%rsp),%edi
  lea    0x8(%rsp),%rsi
  mov    $0x2,%edx
  call   <myReadfull@plt>
  mov    0x8(%rsp),%rdx
  test   %rdx,%rdx
  jle    L27
  mov    $0x0,%ebp
  lea    D28(%rip),%r12
L54:
  mov    (%rsp),%edi
  lea    0x40(%rsp),%rsi
  call   <myReadfull@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L42
  mov    $0x0,%ebx
L40:
  mov    0x44(%rsp,%rbx,4),%eax
  shl    $0x8,%eax
  or     0x40(%rsp,%rbx,4),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mov    %rbx,%rax
  imul   0x18(%rsp),%rax
  sar    %rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    %rbp,%rax
  imul   0x30(%rsp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D25(%rip),%xmm0
  mulsd  D23(%rip),%xmm2
  mulsd  D43(%rip),%xmm1
  mov    %r12,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  add    $0x2,%rbx
  cmp    %rbx,0x8(%rsp)
  jg     L40
L42:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%edi
  lea    0x8(%rsp),%rsi
  mov    $0x2,%edx
  call   <myReadfull@plt>
  mov    0x8(%rsp),%rdx
  add    $0x1,%rbp
  test   %rdx,%rdx
  jg     L54
L27:
  mov    0x448(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x450,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
data_type: string
name: extract_symbolic_data
arguments: label: D28
data_type: string
name: extract_symbolic_data
arguments: label: D25
data_type: f64
name: extract_symbolic_data
arguments: label: D23
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D43
data_type: f64
name: extract_symbolic_data
arguments: label: D22
data_type: string

tool: D20: /dev/ttyUSB0

tool: D28: %e	%e	%e


tool: D25: 0.0014716888142523364

tool: {"D23": [0x62,0xec,0x14,0x3b,0x76,0xb2,0xd3,0x3e]}

tool: D43: 0.0007326007326007326

tool: D22: 


assistant: ```c
int main(int argc, char **argv) {
  volatile int fd;
  initSerial(&fd, 9600, "/dev/ttyUSB0");
  uint16_t out[6];
  out[0] = 0x0000;
  out[1] = 0x0005;
  out[2] = 0x1000 - 0x0010;
  out[3] = 0x0000;
  out[4] = 0x0080;
  out[5] = 0x1000 - 0x0010;
  uint8_t magic = 0xA3;
  write(fd, &magic, 1);
  int i = 0;
  for (i = 0; i < 6; i++) {
    write(fd, &(out[i]), 2);
  }
  i = 0;
  uint16_t nBytes = 0;
  myReadfull(fd, (void *)&nBytes, 2);
  while (nBytes > 0) {
    uint8_t returnValues[129 * 2];
    myReadfull(fd, (void *)returnValues, nBytes);
    int j = 0;
    for (j = 0; j < nBytes; j += 2) {
      double VDS = 0.0, IDS = 0.0, VGS = 0.0;
      VDS = (double)(j * out[1] >> 1) * 0.0007326007326007326;
      VGS = (double)(i * out[4]) * 0.00147168881425233645;
      IDS = (double)((returnValues[j + 1] << 8) | (returnValues[j])) * 4.69615854231238846623e-6;
      printf("%e\t%e\t%e\n", VGS, VDS, IDS);
    }
    printf("\n\n");
    myReadfull(fd, (void *)&nBytes, 2);
    i++;
  }
  return 0;
}
```