ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D24(%rip),%r15
  jmp    L8
L0:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L28
L8:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L25:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L25
  jmp    L0
L28:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D24
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D24: dnanmskrange

tool: D7: # c::%s:len=%d


tool: D8: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanmskrange", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D21(%rip),%r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L0:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L8:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L8
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L0
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string

tool: D21: dnanmskrange

tool: D3: # c::%s:len=%d


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanmskrange", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D12(%rip),%r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L12:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L12
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L8
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D12: dnanmskrange

tool: D1: # c::%s:len=%d


tool: D6: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanmskrange", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movsd  D21(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L56:
  movl   $0x0,-0x20(%rbp)
  jmp    L71
L42:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L71:
  cmpl   $0x2,-0x20(%rbp)
  jle    L42
  movl   $0x0,-0x1c(%rbp)
  jmp    L15
L25:
  movl   $0x1,-0x18(%rbp)
  jmp    L45
L97:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x8(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L45:
  cmpl   $0x3,-0x18(%rbp)
  jle    L97
  movsd  -0x8(%rbp),%xmm1
  movsd  D21(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x1c(%rbp)
L15:
  cmpl   $0x3,-0x1c(%rbp)
  jle    L25
  addl   $0x1,-0x14(%rbp)
  movsd  D21(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
  subl   $0x2,-0x10(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L31
  jmp    L56
L31:
  nop
  movl   $0x0,-0x20(%rbp)
  jmp    L89
L60:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L89:
  cmpl   $0x2,-0x20(%rbp)
  jle    L60
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: byte[8]
name: read_data
arguments: data_label: D37
datatype: string
name: read_data
arguments: data_label: D48
datatype: string

tool: {"D21": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0x3f]}

tool: D37: I=%d J=%d


tool: D48: I=%.1lf J=%.1lf


assistant: ```c
int main() {
  int i, j, k = 1, l = 0, m = 1, n = 0;
  double a = .2;
  while (1) {
    for (i = 0; i < 3; i++) {
      printf("I=%d J=%d\n", l, m++);
    }
    for (j = 0; j < 4; j++) {
      for (k = 1; k <= 3; k++) {
        printf("I=%.1lf J=%.1lf\n", l + a, k + a + n);
      }
      a += .2;
    }
    l++;
    a = .2;
    n++;
    m = m - 2;
    if (l == 2) {
      break;
    }
  }
  for (i = 0; i < 3; i++) {
    printf("I=%d J=%d\n", l, m++);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x4,%r15d
  mov    $0x0,%r14d
  lea    D34(%rip),%r13
L19:
  lea    0x1(%r14),%ebx
L34:
  mov    %ebx,%edx
  add    $0x1,%ebx
  mov    %r14d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  cmp    %r15d,%ebx
  jne    L34
  mov    $0x4,%r12d
  movsd  D15(%rip),%xmm6
  movsd  %xmm6,(%rsp)
  pxor   %xmm7,%xmm7
  cvtsi2sd %r14d,%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L6
L53:
  movsd  D15(%rip),%xmm3
  addsd  (%rsp),%xmm3
  movsd  %xmm3,(%rsp)
  sub    $0x1,%r12d
  je     L27
L6:
  mov    $0x1,%ebx
  movsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  cvttsd2si %xmm0,%ebp
L20:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  addsd  (%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x4,%ebx
  jne    L20
  jmp    L53
L27:
  add    $0x1,%r14d
  add    $0x1,%r15d
  cmp    $0x2,%r14d
  jne    L19
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x5,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D34
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: byte[8]

tool: D34: I=%.1lf J=%.1lf


tool: D4: I=%d J=%d


tool: {"D15": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0x3f]}

assistant: ```c
int main() {
  int i, j, k = 1, l = 0, m = 1, n = 0;
  double a = .2;
  while (1) {
    for (i = 0; i < 3; i++) {
      printf("I=%d J=%d\n", l, m++);
    }
    for (j = 0; j < 4; j++) {
      for (k = 1; k <= 3; k++) {
        printf("I=%.1lf J=%.1lf\n", l + a, k + a + n);
      }
      a += .2;
    }
    l++;
    a = .2;
    n++;
    m = m - 2;
    if (l == 2) {
      break;
    }
  }
  for (i = 0; i < 3; i++) {
    printf("I=%d J=%d\n", l, m++);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  mov    $0x4,%r12d
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
L49:
  lea    -0x3(%r12),%ebx
L11:
  mov    %ebx,%edx
  mov    %r14d,%esi
  add    $0x1,%ebx
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L11
  pxor   %xmm6,%xmm6
  mov    D36(%rip),%rax
  mov    $0x4,%ebx
  cvtsi2sd %r14d,%xmm6
  mov    %rax,(%rsp)
  movsd  %xmm6,0x8(%rsp)
L36:
  movsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  mov    $0x1,%r14d
  cvttsd2si %xmm0,%r15d
L8:
  pxor   %xmm0,%xmm0
  mov    %r15d,%esi
  mov    %rbp,%rdi
  cvtsi2sd %r14d,%xmm0
  addsd  (%rsp),%xmm0
  add    $0x1,%r14d
  addsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edx
  call   <printf@plt>
  cmp    $0x4,%r14d
  jne    L8
  movsd  D36(%rip),%xmm3
  addsd  (%rsp),%xmm3
  movsd  %xmm3,(%rsp)
  sub    $0x1,%ebx
  jne    L36
  lea    -0x2(%r12),%ebx
  mov    $0x1,%r14d
  cmp    $0x5,%r12d
  je     L39
  mov    $0x5,%r12d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %ebx,%edx
  mov    $0x2,%esi
  add    $0x1,%ebx
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D36
type_guessed: byte[8]

tool: D15: I=%d J=%d


tool: D7: I=%.1lf J=%.1lf


tool: {"D36": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0x3f]}

assistant: ```c
int main() {
  int i, j, k = 1, l = 0, m = 1, n = 0;
  double a = .2;
  while (1) {
    for (i = 0; i < 3; i++) {
      printf("I=%d J=%d\n", l, m++);
    }
    for (j = 0; j < 4; j++) {
      for (k = 1; k <= 3; k++) {
        printf("I=%.1lf J=%.1lf\n", l + a, k + a + n);
      }
      a += .2;
    }
    l++;
    a = .2;
    n++;
    m = m - 2;
    if (l == 2) {
      break;
    }
  }
  for (i = 0; i < 3; i++) {
    printf("I=%d J=%d\n", l, m++);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    $0x4,%r12d
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
L44:
  lea    -0x3(%r12),%ebx
L48:
  mov    %ebx,%edx
  mov    %r14d,%esi
  add    $0x1,%ebx
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L48
  pxor   %xmm6,%xmm6
  mov    D27(%rip),%rax
  mov    $0x4,%ebx
  cvtsi2sd %r14d,%xmm6
  mov    %rax,(%rsp)
  movsd  %xmm6,0x8(%rsp)
L32:
  movsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  mov    $0x1,%r14d
  cvttsd2si %xmm0,%r15d
L4:
  pxor   %xmm0,%xmm0
  mov    %r15d,%esi
  mov    %rbp,%rdi
  cvtsi2sd %r14d,%xmm0
  addsd  (%rsp),%xmm0
  add    $0x1,%r14d
  addsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edx
  call   <printf@plt>
  cmp    $0x4,%r14d
  jne    L4
  movsd  D27(%rip),%xmm3
  addsd  (%rsp),%xmm3
  movsd  %xmm3,(%rsp)
  sub    $0x1,%ebx
  jne    L32
  lea    -0x2(%r12),%ebx
  mov    $0x1,%r14d
  cmp    $0x5,%r12d
  je     L22
  mov    $0x5,%r12d
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %ebx,%edx
  mov    $0x2,%esi
  add    $0x1,%ebx
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L22
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string
name: read_data
arguments: data_label: D28
data_type: string
name: read_data
arguments: data_label: D27
data_type: byte[8]

tool: D2: I=%d J=%d


tool: D28: I=%.1lf J=%.1lf


tool: {"D27": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0x3f]}

assistant: ```c
int main() {
  int i, j, k = 1, l = 0, m = 1, n = 0;
  double a = .2;
  while (1) {
    for (i = 0; i < 3; i++) {
      printf("I=%d J=%d\n", l, m++);
    }
    for (j = 0; j < 4; j++) {
      for (k = 1; k <= 3; k++) {
        printf("I=%.1lf J=%.1lf\n", l + a, k + a + n);
      }
      a += .2;
    }
    l++;
    a = .2;
    n++;
    m = m - 2;
    if (l == 2) {
      break;
    }
  }
  for (i = 0; i < 3; i++) {
    printf("I=%d J=%d\n", l, m++);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rescure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L52
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L37
L52:
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L13
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <rescure>
  mov    $0x64,%edi
  call   <sleep@plt>
  jmp    L37
L13:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L45
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <rescure>
  mov    $0x64,%edi
  call   <sleep@plt>
  jmp    L37
L45:
  mov    $0x64,%edi
  call   <sleep@plt>
  nop
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D54
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string
name: unpack_data
arguments: tag: D55
datatype: string
name: unpack_data
arguments: tag: D46
datatype: string

tool: D54: the leaf pid:%u


tool: D19: the left child pid:%u


tool: D13: %u's parent pid is:%u


tool: D55: the current pid:%u


tool: D46: the right child pid:%u


assistant: ```c
void rescure(int deep) {
  if (deep == 0) {
    printf("the leaf pid:%u\n", getpid());
    exit(0);
  } else {
    pid_t fpid = fork();
    if (fpid == 0) {
      printf("the left child pid:%u\n", getpid());
      printf("%u's parent pid is:%u\n", getpid(), getppid());
      rescure(deep - 1);
      sleep(100);
      return;
    } else {
      printf("the current pid:%u\n", getpid());
      pid_t pid = fork();
      if (pid == 0) {
        printf("the right child pid:%u\n", getpid());
        printf("%u's parent pid is:%u\n", getpid(), getppid());
        rescure(deep - 1);
        sleep(100);
        return;
      } else {
        sleep(100);
        return;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rescure>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L6
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L36
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L25
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebp,%edx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1(%rbx),%edi
  call   <rescure>
  mov    $0x64,%edi
  call   <sleep@plt>
  jmp    L44
L36:
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebp,%edx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1(%rbx),%edi
  call   <rescure>
  mov    $0x64,%edi
  call   <sleep@plt>
  jmp    L44
L25:
  mov    $0x64,%edi
  call   <sleep@plt>
  jmp    L44
```

tool_calls: name: disassemble_data
arguments: label: D56
type_infered: string
name: disassemble_data
arguments: label: D40
type_infered: string
name: disassemble_data
arguments: label: D37
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D53
type_infered: string

tool: D56: the leaf pid:%u


tool: D40: the current pid:%u


tool: D37: the right child pid:%u


tool: D17: %u's parent pid is:%u


tool: D53: the left child pid:%u


assistant: ```c
void rescure(int deep) {
  if (deep == 0) {
    printf("the leaf pid:%u\n", getpid());
    exit(0);
  } else {
    pid_t fpid = fork();
    if (fpid == 0) {
      printf("the left child pid:%u\n", getpid());
      printf("%u's parent pid is:%u\n", getpid(), getppid());
      rescure(deep - 1);
      sleep(100);
      return;
    } else {
      printf("the current pid:%u\n", getpid());
      pid_t pid = fork();
      if (pid == 0) {
        printf("the right child pid:%u\n", getpid());
        printf("%u's parent pid is:%u\n", getpid(), getppid());
        rescure(deep - 1);
        sleep(100);
        return;
      } else {
        sleep(100);
        return;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rescure>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L18
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbx
  pop    %r12
  jmp    10d0 <exit@plt>
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <fork@plt>
  test   %rax,%rax
  je     L7
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D34(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L12
  call   <getpid@plt>
  lea    D46(%rip),%rdi
  mov    %eax,%esi
  jmp    L27
  nopl   0x0(%rax)
L7:
  call   <getpid@plt>
  lea    D31(%rip),%rdi
  mov    %eax,%esi
L27:
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D29(%rip),%rdi
  mov    %r12d,%edx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x1(%rbx),%edi
  call   <rescure>
L12:
  add    $0x8,%rsp
  mov    $0x64,%edi
  pop    %rbx
  pop    %r12
  jmp    10e0 <sleep@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string
name: extract_symbolic_data
arguments: tag: D34
datatype: string
name: extract_symbolic_data
arguments: tag: D46
datatype: string
name: extract_symbolic_data
arguments: tag: D31
datatype: string
name: extract_symbolic_data
arguments: tag: D29
datatype: string

tool: D9: the leaf pid:%u


tool: D34: the current pid:%u


tool: D46: the right child pid:%u


tool: D31: the left child pid:%u


tool: D29: %u's parent pid is:%u


assistant: ```c
void rescure(int deep) {
  if (deep == 0) {
    printf("the leaf pid:%u\n", getpid());
    exit(0);
  } else {
    pid_t fpid = fork();
    if (fpid == 0) {
      printf("the left child pid:%u\n", getpid());
      printf("%u's parent pid is:%u\n", getpid(), getppid());
      rescure(deep - 1);
      sleep(100);
      return;
    } else {
      printf("the current pid:%u\n", getpid());
      pid_t pid = fork();
      if (pid == 0) {
        printf("the right child pid:%u\n", getpid());
        printf("%u's parent pid is:%u\n", getpid(), getppid());
        rescure(deep - 1);
        sleep(100);
        return;
      } else {
        sleep(100);
        return;
      }
    }
  }
}
```