user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D62(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%r12d
  cmp    $0x1,%r12d
  je     L127
  cmp    $0x2,%r12d
  je     L125
L181:
  mov    $0xa,%edi
  call   <putchar@plt>
L138:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L119
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L127:
  cmpl   $0x0,0xc(%rsp)
  je     L94
  lea    0x10(%rsp),%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L78
  mov    %r12d,%ebp
  mov    $0x0,%ebx
  lea    0x14(%rsp),%r14
  lea    D25(%rip),%r13
  lea    D41(%rip),%r15
  jmp    L129
L94:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L138
L33:
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,0x10(%rsp)
  mov    %r12d,%ebp
L49:
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L189
L129:
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  cmp    0x14(%rsp),%edx
  jne    L33
  add    $0x1,%ebp
  jmp    L49
L78:
  mov    %r12d,%ebp
L189:
  mov    0x10(%rsp),%edx
  mov    %ebp,%esi
  lea    D62(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L181
L125:
  cmpl   $0x0,0xc(%rsp)
  jle    L181
  mov    $0x0,%ebp
  lea    D41(%rip),%r13
  lea    D66(%rip),%r12
  lea    D25(%rip),%r14
  jmp    L20
L167:
  mov    0x14(%rsp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L95:
  add    $0x1,%ebx
  mov    0x10(%rsp),%edx
  cmp    %ebx,%edx
  jle    L86
L132:
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jne    L167
  sub    $0x1,%edx
  cmp    %ebx,%edx
  jne    L167
  mov    0x14(%rsp),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L95
L86:
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jle    L181
L20:
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  jle    L86
  mov    $0x0,%ebx
  jmp    L132
L119:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D62
type_infered: string
name: retrieve_data
arguments: data_label: D25
type_infered: string
name: retrieve_data
arguments: data_label: D41
type_infered: string
name: retrieve_data
arguments: data_label: D66
type_infered: string

tool: D62: %d %d

tool: D25: %d

tool: D41: %d %d 

tool: D66: %d 

assistant: ```c
int main() {
  int mode, numInputs;
  scanf("%d %d", &mode, &numInputs);
  if (mode == 1) {
    if (numInputs == 0) {
      printf("\n");
      return 0;
    }
    int prevNum;
    scanf("%d", &prevNum);
    int prevNumCount = 1;
    for (int i = 0; i < numInputs - 1; i++) {
      int currentNum;
      scanf("%d", &currentNum);
      if (prevNum == currentNum) {
        prevNumCount++;
      } else {
        printf("%d %d ", prevNumCount, prevNum);
        prevNumCount = 1;
        prevNum = currentNum;
      }
    }
    printf("%d %d", prevNumCount, prevNum);
  } else if (mode == 2) {
    for (int i = 0; i < numInputs; i++) {
      int numCount;
      int currentNum;
      scanf("%d %d ", &numCount, &currentNum);
      for (int j = 0; j < numCount; j++) {
        if (i == numInputs - 1 && j == numCount - 1) {
          printf("%d", currentNum);
        } else {
          printf("%d ", currentNum);
        }
      }
    }
  }
  printf("\n");
  return 0;
}
```