ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pubnub_uname>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: Windows%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "Windows"
         "%2F"
         "2.1-alpha";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pubnub_uname>:
  endbr64
  lea    D6(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Windows%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "Windows"
         "%2F"
         "2.1-alpha";
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pubnub_uname>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string

tool: D8: Windows%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "Windows"
         "%2F"
         "2.1-alpha";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<socket_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <create_file_name@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x6c,%eax
  jle    L0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
data_type: string
name: read_data
arguments: label: D17
data_type: string

tool: D3: socket2

tool: D17: Can't create socket name.

assistant: ```c
char *socket_name() {
  char *socket_name = create_file_name("socket2");
  if (strlen(socket_name) > 108)
    fatal("Can't create socket name.");
  return socket_name;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<socket_name>:
  endbr64
  push   %rbx
  lea    D16(%rip),%rdi
  call   <create_file_name@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x6c,%eax
  jg     L17
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
L17:
  lea    D4(%rip),%rdi
  call   <fatal@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D16: socket2

tool: D4: Can't create socket name.

assistant: ```c
char *socket_name() {
  char *socket_name = create_file_name("socket2");
  if (strlen(socket_name) > 108)
    fatal("Can't create socket name.");
  return socket_name;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<socket_name>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  call   <create_file_name@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    $0x6c,%eax
  jg     L1
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    D12(%rip),%rdi
  call   <fatal@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D12
datatype: string

tool: D11: socket2

tool: D12: Can't create socket name.

assistant: ```c
char *socket_name() {
  char *socket_name = create_file_name("socket2");
  if (strlen(socket_name) > 108)
    fatal("Can't create socket name.");
  return socket_name;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<socket_name>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  call   <create_file_name@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    $0x6c,%eax
  jg     L6
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D13(%rip),%rdi
  call   <fatal@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string

tool: D16: socket2

tool: D13: Can't create socket name.

assistant: ```c
char *socket_name() {
  char *socket_name = create_file_name("socket2");
  if (strlen(socket_name) > 108)
    fatal("Can't create socket name.");
  return socket_name;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L53
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L53:
  mov    %rax,%r12
  lea    D45(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,(%rsp)
  jle    L55
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D18(%rip),%r13
L11:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,(%rsp)
  jg     L11
L55:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L25
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L22
  mov    %r13,%rbp
  mov    $0x0,%ebx
  lea    D18(%rip),%r14
L39:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jg     L39
L22:
  mov    %r13,%rdx
  mov    (%rsp),%esi
  mov    %r12,%rdi
  call   <addtwo@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L25
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D20
type_infered: string
name: read_data
arguments: tag: D18
type_infered: string
name: read_data
arguments: tag: D45
type_infered: string
name: read_data
arguments: tag: D6
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string

tool: D20: Please input the 1st number:


tool: D18: %d

tool: D45: Please input the A:


tool: D6: Please input the 2st number:


tool: D16: Please input the B:


assistant: ```c
int main(int argc, int **argv) {
  int n, m, i, j;
  int *A, *B;
  printf("Please input the 1st number:\n");
  scanf("%d", &n);
  A = (int *)malloc(sizeof(int) * n);
  if (NULL == A)
    return 0;
  printf("Please input the A:\n");
  for (i = 0; i < n; i++) {
    scanf("%d", &A[i]);
  }
  printf("Please input the 2st number:\n");
  scanf("%d", &m);
  B = (int *)malloc(sizeof(int) * m);
  if (NULL == B)
    return 0;
  printf("Please input the B:\n");
  for (i = 0; i < m; i++) {
    scanf("%d", &B[i]);
  }
  addtwo(A, n, B, m);
  free(A);
  free(B);
  A = NULL;
  B = NULL;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D2(%rip),%rdi
  push   %r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L51
L72:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  lea    D41(%rip),%rdi
  mov    %rax,%r13
  call   <printf@plt>
  cmpl   $0x0,(%rsp)
  jle    L45
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nop
L31:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,(%rsp)
  jg     L31
L45:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L72
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L32
  mov    %r14,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L29:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L29
L32:
  mov    (%rsp),%esi
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <addtwo@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  jmp    L72
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string
name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D41
type_guessed: string
name: read_data
arguments: label: D23
type_guessed: string
name: read_data
arguments: label: D33
type_guessed: string

tool: D2: Please input the 1st number:


tool: D16: %d

tool: D41: Please input the A:


tool: D23: Please input the 2st number:


tool: D33: Please input the B:


assistant: ```c
int main(int argc, int **argv) {
  int n, m, i, j;
  int *A, *B;
  printf("Please input the 1st number:\n");
  scanf("%d", &n);
  A = (int *)malloc(sizeof(int) * n);
  if (NULL == A)
    return 0;
  printf("Please input the A:\n");
  for (i = 0; i < n; i++) {
    scanf("%d", &A[i]);
  }
  printf("Please input the 2st number:\n");
  scanf("%d", &m);
  B = (int *)malloc(sizeof(int) * m);
  if (NULL == B)
    return 0;
  printf("Please input the B:\n");
  for (i = 0; i < m; i++) {
    scanf("%d", &B[i]);
  }
  addtwo(A, n, B, m);
  free(A);
  free(B);
  A = NULL;
  B = NULL;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L67
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L67:
  lea    D29(%rip),%rdi
  mov    %rax,%r13
  call   <printf@plt>
  cmpl   $0x0,(%rsp)
  jle    L57
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nop
L45:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,(%rsp)
  jg     L45
L57:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L16
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L4
  mov    %r14,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L55:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L55
L4:
  mov    (%rsp),%esi
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <addtwo@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  jmp    L16
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D29
type_infered: string
name: read_data
arguments: label: D2
type_infered: string
name: read_data
arguments: label: D0
type_infered: string

tool: D6: Please input the 1st number:


tool: D5: %d

tool: D29: Please input the A:


tool: D2: Please input the 2st number:


tool: D0: Please input the B:


assistant: ```c
int main(int argc, int **argv) {
  int n, m, i, j;
  int *A, *B;
  printf("Please input the 1st number:\n");
  scanf("%d", &n);
  A = (int *)malloc(sizeof(int) * n);
  if (NULL == A)
    return 0;
  printf("Please input the A:\n");
  for (i = 0; i < n; i++) {
    scanf("%d", &A[i]);
  }
  printf("Please input the 2st number:\n");
  scanf("%d", &m);
  B = (int *)malloc(sizeof(int) * m);
  if (NULL == B)
    return 0;
  printf("Please input the B:\n");
  for (i = 0; i < m; i++) {
    scanf("%d", &B[i]);
  }
  addtwo(A, n, B, m);
  free(A);
  free(B);
  A = NULL;
  B = NULL;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L0
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  jmp    L4
L0:
  lea    D16(%rip),%rax
L4:
  lea    -0xb(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  lea    -0xb(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D0
datatype: string

tool: D16: exec("/bin/sh")

tool: D0: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[3];
  strcpy(buf, argv[1] ? argv[1] : "exec(\"/bin/sh\")");
  printf("%s\n", buf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rsi
  test   %rsi,%rsi
  lea    D0(%rip),%rax
  cmove  %rax,%rsi
  lea    0x5(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string

tool: D0: exec("/bin/sh")

tool: D16: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[3];
  strcpy(buf, argv[1] ? argv[1] : "exec(\"/bin/sh\")");
  printf("%s\n", buf);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  lea    0x5(%rsp),%rbp
  test   %rsi,%rsi
  mov    %rbp,%rdi
  cmove  %rax,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string
name: read_data
arguments: data_label: D15
data_type: string

tool: D9: exec("/bin/sh")

tool: D15: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[3];
  strcpy(buf, argv[1] ? argv[1] : "exec(\"/bin/sh\")");
  printf("%s\n", buf);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  lea    0x5(%rsp),%rbp
  test   %rsi,%rsi
  mov    %rbp,%rdi
  cmove  %rax,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string

tool: D15: exec("/bin/sh")

tool: D18: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[3];
  strcpy(buf, argv[1] ? argv[1] : "exec(\"/bin/sh\")");
  printf("%s\n", buf);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tg_big_score>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movw   $0x0,-0xa(%rbp)
  jmp    L7
L9:
  movzwl -0xa(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %rax,-0x8(%rbp)
  movzwl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xa(%rbp)
L7:
  cmpw   $0xfe00,-0xa(%rbp)
  jbe    L9
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long tg_big_score(unsigned short *big_table) {
  unsigned short i;
  unsigned long t;
  for (t = 0, i = 0; i < 255 * 255; i++)
    t += big_table[i];
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tg_big_score>:
  endbr64
  lea    0x1fc02(%rdi),%rcx
  mov    $0x0,%eax
L2:
  movzwl (%rdi),%edx
  add    %rdx,%rax
  add    $0x2,%rdi
  cmp    %rcx,%rdi
  jne    L2
  ret
```

assistant: ```c
unsigned long tg_big_score(unsigned short *big_table) {
  unsigned short i;
  unsigned long t;
  for (t = 0, i = 0; i < 255 * 255; i++)
    t += big_table[i];
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tg_big_score>:
  endbr64
  lea    0x1fc02(%rdi),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L4:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L4
  ret
```

assistant: ```c
unsigned long tg_big_score(unsigned short *big_table) {
  unsigned short i;
  unsigned long t;
  for (t = 0, i = 0; i < 255 * 255; i++)
    t += big_table[i];
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tg_big_score>:
  endbr64
  pxor   %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  lea    0x1fc00(%rdi),%rdx
  nopw   0x0(%rax,%rax,1)
L9:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm2
  punpckhwd %xmm4,%xmm1
  movdqa %xmm1,%xmm5
  punpcklwd %xmm4,%xmm2
  punpckhdq %xmm3,%xmm1
  punpckldq %xmm3,%xmm5
  paddq  %xmm5,%xmm1
  movdqa %xmm2,%xmm5
  punpckhdq %xmm3,%xmm2
  punpckldq %xmm3,%xmm5
  paddq  %xmm5,%xmm2
  paddq  %xmm2,%xmm1
  paddq  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L9
  movdqa %xmm0,%xmm1
  movzwl 0x1fc00(%rdi),%edx
  psrldq $0x8,%xmm1
  paddq  %xmm1,%xmm0
  movq   %xmm0,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
unsigned long tg_big_score(unsigned short *big_table) {
  unsigned short i;
  unsigned long t;
  for (t = 0, i = 0; i < 255 * 255; i++)
    t += big_table[i];
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type: string
name: parse_data
arguments: tag: D6
type: string

tool: D15: %d

tool: D6: 
%d

assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  printf("\n%d", a * a);
  printf("\n%d", a * a * a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  imul   %esi,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D14: %d

tool: D0: 
%d

assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  printf("\n%d", a * a);
  printf("\n%d", a * a * a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D17(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %rbp,%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type: string
name: disassemble_data
arguments: tag: D17
type: string

tool: D15: %d

tool: D17: 
%d

assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  printf("\n%d", a * a);
  printf("\n%d", a * a * a);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  lea    D1(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %rbp,%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D6: %d

tool: D1: 
%d

assistant: ```c
int main() {
  int a;
  scanf("%d", &a);
  printf("\n%d", a * a);
  printf("\n%d", a * a * a);
}
```