user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xfffffffe,-0x10(%rbp)
  movl   $0xfffffffc,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xa,-0x10(%rbp)
  movl   $0xb,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xfffffff6,-0x10(%rbp)
  movl   $0xb,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xf000,-0x10(%rbp)
  movl   $0xf001,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x55555555,-0x10(%rbp)
  movl   $0x33333333,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x5353,-0x10(%rbp)
  movl   $0x8000,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xfffff000,-0x10(%rbp)
  movl   $0xfffff001,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x5555,-0x10(%rbp)
  movl   $0x33330000,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x53535353,-0x10(%rbp)
  movl   $0x80008000,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unsigned int a, b;
  unsigned long long int c;
  a = 0x00000002;
  b = 0x00000004;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0xFFFFFFFF;
  b = 0xFFFFFFFF;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0xFFFFFFFF;
  b = 0x00000001;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0xFFFFFFFF;
  b = 0x0000000A;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0xFFFFFFFE;
  b = 0xFFFFFFFC;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0x0000000A;
  b = 0x0000000B;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0xFFFFFFF6;
  b = 0x0000000B;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0x0000F000;
  b = 0x0000F001;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0x55555555;
  b = 0x33333333;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0x00005353;
  b = 0x00008000;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0xFFFFF000;
  b = 0xFFFFF001;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0x00005555;
  b = 0x33330000;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  a = 0x53535353;
  b = 0x80008000;
  c = (unsigned long long int)(a) * (unsigned long long int)(b);
  c = 0;
  return 0;
}
```