ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parseFloatFromLine>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  test   %edx,%edx
  je     L16
  mov    %edx,%edx
  xor    %eax,%eax
L15:
  movzbl (%rsi,%rax,1),%ecx
  mov    %eax,%ebx
  test   $0xdf,%cl
  je     L45
  cmp    $0xa,%cl
  jne    L21
L45:
  sub    $0x1,%ebx
L16:
  lea    D0(%rip),%r12
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  movb   $0x0,(%r12,%rbx,1)
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L15
  jmp    L16
```

assistant: ```c
void parseFloatFromLine(float *inOutFloat, char *stringToParse, unsigned int length) {
  unsigned int startIndex = 0;
  unsigned int endIndex = 0;
  while (endIndex < length && stringToParse[endIndex] != ' ' && stringToParse[endIndex] != '\n' && stringToParse[endIndex] != '\0') {
    ++endIndex;
    continue;
  }
  {
    static char valueBuffer[64];
    unsigned int valueLength = endIndex - startIndex - 1;
    memcpy(valueBuffer, &stringToParse[startIndex], valueLength);
    valueBuffer[valueLength] = '\0';
    *inOutFloat = (float)atof(valueBuffer);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parseFloatFromLine>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  test   %edx,%edx
  je     L38
  mov    %edx,%edx
  xor    %eax,%eax
L36:
  movzbl (%rsi,%rax,1),%ecx
  mov    %eax,%ebx
  test   $0xdf,%cl
  je     L8
  cmp    $0xa,%cl
  jne    L19
L8:
  sub    $0x1,%ebx
L38:
  lea    D9(%rip),%r12
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  movb   $0x0,(%r12,%rbx,1)
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L36
  jmp    L38
```

assistant: ```c
void parseFloatFromLine(float *inOutFloat, char *stringToParse, unsigned int length) {
  unsigned int startIndex = 0;
  unsigned int endIndex = 0;
  while (endIndex < length && stringToParse[endIndex] != ' ' && stringToParse[endIndex] != '\n' && stringToParse[endIndex] != '\0') {
    ++endIndex;
    continue;
  }
  {
    static char valueBuffer[64];
    unsigned int valueLength = endIndex - startIndex - 1;
    memcpy(valueBuffer, &stringToParse[startIndex], valueLength);
    valueBuffer[valueLength] = '\0';
    *inOutFloat = (float)atof(valueBuffer);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strxcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  jmp    L38
L15:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L3
L7:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x4(%rbp),%eax
  jmp    L38
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  jmp    L32
L38:
  pop    %rbp
  ret
```

assistant: ```c
int strxcpy(char *dst, const char *src, int size) {
  int i = 0;
  while (1) {
    if (src[i] == '\0') {
      dst[i] = '\0';
      return i;
    }
    if (i == size - 1) {
      dst[i] = '\0';
      while (src[i] != '\0')
        i++;
      return i;
    }
    dst[i] = src[i];
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strxcpy>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L22
  mov    %edx,%r8d
  sub    $0x1,%r8d
  je     L82
  lea    -0x2(%rdx),%r9d
  add    $0x2,%r9
  mov    $0x1,%eax
L39:
  mov    %cl,-0x1(%rdi,%rax,1)
  mov    %eax,%edx
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L38
  lea    0x1(%rax),%rdx
  cmp    %r9,%rdx
  je     L67
  mov    %rdx,%rax
  jmp    L39
L22:
  mov    $0x0,%edx
  mov    $0x0,%eax
L38:
  movb   $0x0,(%rdi,%rax,1)
L54:
  mov    %edx,%eax
  ret
L82:
  mov    $0x0,%eax
L67:
  movb   $0x0,(%rdi,%rax,1)
  movslq %r8d,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  je     L3
  lea    0x1(%r8),%eax
  cltq
L29:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rsi,%rax,1)
  jne    L29
  jmp    L54
L3:
  mov    %r8d,%edx
  jmp    L54
```

assistant: ```c
int strxcpy(char *dst, const char *src, int size) {
  int i = 0;
  while (1) {
    if (src[i] == '\0') {
      dst[i] = '\0';
      return i;
    }
    if (i == size - 1) {
      dst[i] = '\0';
      while (src[i] != '\0')
        i++;
      return i;
    }
    dst[i] = src[i];
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strxcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%r8
  mov    %rsi,%rdi
  test   %cl,%cl
  je     L99
  mov    %edx,%esi
  sub    $0x1,%esi
  je     L63
  lea    -0x2(%rdx),%r10d
  mov    $0x1,%eax
  add    $0x2,%r10
  jmp    L10
  nop
L50:
  lea    0x1(%rax),%rdx
  cmp    %r10,%rdx
  je     L34
  mov    %rdx,%rax
L10:
  mov    %cl,-0x1(%r8,%rax,1)
  movzbl (%rdi,%rax,1),%ecx
  mov    %eax,%r9d
  test   %cl,%cl
  jne    L50
  add    %rax,%r8
L46:
  movb   $0x0,(%r8)
L2:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  add    %rax,%r8
  movslq %esi,%rax
  add    %rdi,%rax
L94:
  movb   $0x0,(%r8)
  cmpb   $0x0,(%rax)
  je     L72
  lea    0x1(%rsi),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %eax,%r9d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L42
  mov    %r9d,%eax
  ret
L99:
  xor    %r9d,%r9d
  jmp    L46
L72:
  mov    %esi,%r9d
  jmp    L2
L63:
  mov    %rdi,%rax
  jmp    L94
```

assistant: ```c
int strxcpy(char *dst, const char *src, int size) {
  int i = 0;
  while (1) {
    if (src[i] == '\0') {
      dst[i] = '\0';
      return i;
    }
    if (i == size - 1) {
      dst[i] = '\0';
      while (src[i] != '\0')
        i++;
      return i;
    }
    dst[i] = src[i];
    i++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strxcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%r8
  mov    %rsi,%rdi
  test   %cl,%cl
  je     L66
  mov    %edx,%esi
  sub    $0x1,%esi
  je     L39
  lea    -0x2(%rdx),%r10d
  mov    $0x1,%eax
  add    $0x2,%r10
  jmp    L40
  nop
L10:
  lea    0x1(%rax),%rdx
  cmp    %rdx,%r10
  je     L57
  mov    %rdx,%rax
L40:
  mov    %cl,-0x1(%r8,%rax,1)
  movzbl (%rdi,%rax,1),%ecx
  mov    %eax,%r9d
  test   %cl,%cl
  jne    L10
  add    %rax,%r8
L0:
  movb   $0x0,(%r8)
L53:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  add    %rax,%r8
  movslq %esi,%rax
  add    %rdi,%rax
L19:
  movb   $0x0,(%r8)
  cmpb   $0x0,(%rax)
  je     L61
  lea    0x1(%rsi),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %eax,%r9d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L30
  mov    %r9d,%eax
  ret
L66:
  xor    %r9d,%r9d
  jmp    L0
L61:
  mov    %esi,%r9d
  jmp    L53
L39:
  mov    %rdi,%rax
  jmp    L19
```

assistant: ```c
int strxcpy(char *dst, const char *src, int size) {
  int i = 0;
  while (1) {
    if (src[i] == '\0') {
      dst[i] = '\0';
      return i;
    }
    if (i == size - 1) {
      dst[i] = '\0';
      while (src[i] != '\0')
        i++;
      return i;
    }
    dst[i] = src[i];
    i++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  mov    $0x3,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10,%edx
  mov    $0x4,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x40,%edx
  mov    $0x6,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x100,%edx
  mov    $0x8,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x400,%edx
  mov    $0xa,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10000,%edx
  mov    $0x10,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D39
datatype: string
name: read_data
arguments: data_tag: D91
datatype: string
name: read_data
arguments: data_tag: D81
datatype: string
name: read_data
arguments: data_tag: D98
datatype: string

tool: D8: num1 = %d num2 = %d



tool: D39: Enter num1: 

tool: D91: %d

tool: D81: num1 = %d



tool: D98: 2^%2d = %5d


assistant: ```c
main() {
  int num1;
  int num2 = 2;
  printf("num1 = %d num2 = %d\n\n", num1, num2);
  printf("Enter num1: ");
  scanf("%d", &num1);
  printf("num1 = %d\n\n", num1);
  printf("2^%2d = %5d\n", 3, 8);
  printf("2^%2d = %5d\n", 4, 16);
  printf("2^%2d = %5d\n", 6, 64);
  printf("2^%2d = %5d\n", 8, 256);
  printf("2^%2d = %5d\n", 10, 1024);
  printf("2^%2d = %5d\n", 16, 65536);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  mov    $0x3,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x40,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x100,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x400,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10000,%edx
  mov    $0x10,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D20
data_type: string
name: parse_data
arguments: tag: D44
data_type: string
name: parse_data
arguments: tag: D45
data_type: string
name: parse_data
arguments: tag: D28
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D20: num1 = %d num2 = %d



tool: D44: Enter num1: 

tool: D45: %d

tool: D28: num1 = %d



tool: D4: 2^%2d = %5d


assistant: ```c
main() {
  int num1;
  int num2 = 2;
  printf("num1 = %d num2 = %d\n\n", num1, num2);
  printf("Enter num1: ");
  scanf("%d", &num1);
  printf("num1 = %d\n\n", num1);
  printf("2^%2d = %5d\n", 3, 8);
  printf("2^%2d = %5d\n", 4, 16);
  printf("2^%2d = %5d\n", 6, 64);
  printf("2^%2d = %5d\n", 8, 256);
  printf("2^%2d = %5d\n", 10, 1024);
  printf("2^%2d = %5d\n", 16, 65536);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2,%edx
  lea    D41(%rip),%rdi
  lea    D43(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%esi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x3,%esi
  call   <printf@plt>
  mov    $0x10,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  mov    $0x40,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x6,%esi
  call   <printf@plt>
  mov    $0x100,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x8,%esi
  call   <printf@plt>
  mov    $0x400,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0xa,%esi
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x10000,%edx
  mov    %rbp,%rdi
  mov    $0x10,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D41
type_guessed: string
name: retrieve_data
arguments: data_tag: D43
type_guessed: string
name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D27
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string

tool: D41: num1 = %d num2 = %d



tool: D43: 2^%2d = %5d


tool: D2: Enter num1: 

tool: D27: %d

tool: D23: num1 = %d



assistant: ```c
main() {
  int num1;
  int num2 = 2;
  printf("num1 = %d num2 = %d\n\n", num1, num2);
  printf("Enter num1: ");
  scanf("%d", &num1);
  printf("num1 = %d\n\n", num1);
  printf("2^%2d = %5d\n", 3, 8);
  printf("2^%2d = %5d\n", 4, 16);
  printf("2^%2d = %5d\n", 6, 64);
  printf("2^%2d = %5d\n", 8, 256);
  printf("2^%2d = %5d\n", 10, 1024);
  printf("2^%2d = %5d\n", 16, 65536);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2,%edx
  lea    D20(%rip),%rdi
  lea    D1(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%esi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x3,%esi
  call   <printf@plt>
  mov    $0x10,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  mov    $0x40,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x6,%esi
  call   <printf@plt>
  mov    $0x100,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x8,%esi
  call   <printf@plt>
  mov    $0x400,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0xa,%esi
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x10000,%edx
  mov    %rbp,%rdi
  mov    $0x10,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D4
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string
name: extract_symbolic_data
arguments: data_label: D36
type_infered: string

tool: D20: num1 = %d num2 = %d



tool: D1: 2^%2d = %5d


tool: D4: Enter num1: 

tool: D26: %d

tool: D36: num1 = %d



assistant: ```c
main() {
  int num1;
  int num2 = 2;
  printf("num1 = %d num2 = %d\n\n", num1, num2);
  printf("Enter num1: ");
  scanf("%d", &num1);
  printf("num1 = %d\n\n", num1);
  printf("2^%2d = %5d\n", 3, 8);
  printf("2^%2d = %5d\n", 4, 16);
  printf("2^%2d = %5d\n", 6, 64);
  printf("2^%2d = %5d\n", 8, 256);
  printf("2^%2d = %5d\n", 10, 1024);
  printf("2^%2d = %5d\n", 16, 65536);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_path_binary_extensions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <split_ext@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x47,%ecx
  lea    D14(%rip),%rdx
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <seatest_assert_string_equal@plt>
  mov    -0x1c(%rbp),%eax
  mov    $0x47,%ecx
  lea    D14(%rip),%rdx
  mov    %eax,%esi
  mov    $0x1b,%edi
  mov    $0x0,%eax
  call   <seatest_assert_int_equal@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D14
type: string
name: unpack_data
arguments: data_tag: D25
type: string

tool: D13: /home/user.name/file.double.ext

tool: D14: test_path_binary_extensions

tool: D25: ext

assistant: ```c
void test_path_binary_extensions(void) {
  int root_len;
  const char *ext;
  char *const name = strdup("/home/user.name/file.double.ext");
  split_ext(name, &root_len, &ext);
  do {
    seatest_assert_string_equal("ext", ext, __FUNCTION__, 71);
  } while (0);
  do {
    seatest_assert_int_equal((27), root_len, __FUNCTION__, 71);
  } while (0);
  free(name);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_path_binary_extensions>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <split_ext@plt>
  mov    $0x47,%ecx
  lea    D3(%rip),%rbp
  mov    %rbp,%rdx
  mov    0x10(%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <seatest_assert_string_equal@plt>
  mov    $0x47,%ecx
  mov    %rbp,%rdx
  mov    0xc(%rsp),%esi
  mov    $0x1b,%edi
  mov    $0x0,%eax
  call   <seatest_assert_int_equal@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D22
type: string

tool: D24: /home/user.name/file.double.ext

tool: D3: test_path_binary_extensions

tool: D22: ext

assistant: ```c
void test_path_binary_extensions(void) {
  int root_len;
  const char *ext;
  char *const name = strdup("/home/user.name/file.double.ext");
  split_ext(name, &root_len, &ext);
  do {
    seatest_assert_string_equal("ext", ext, __FUNCTION__, 71);
  } while (0);
  do {
    seatest_assert_int_equal((27), root_len, __FUNCTION__, 71);
  } while (0);
  free(name);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_path_binary_extensions>:
  endbr64
  push   %r12
  lea    D27(%rip),%rdi
  lea    D29(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <split_ext@plt>
  mov    0x10(%rsp),%rsi
  mov    %r12,%rdx
  xor    %eax,%eax
  mov    $0x47,%ecx
  lea    D19(%rip),%rdi
  call   <seatest_assert_string_equal@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  mov    $0x47,%ecx
  mov    %r12,%rdx
  mov    $0x1b,%edi
  call   <seatest_assert_int_equal@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <free@plt>
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D29
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string

tool: D27: /home/user.name/file.double.ext

tool: D29: test_path_binary_extensions

tool: D19: ext

assistant: ```c
void test_path_binary_extensions(void) {
  int root_len;
  const char *ext;
  char *const name = strdup("/home/user.name/file.double.ext");
  split_ext(name, &root_len, &ext);
  do {
    seatest_assert_string_equal("ext", ext, __FUNCTION__, 71);
  } while (0);
  do {
    seatest_assert_int_equal((27), root_len, __FUNCTION__, 71);
  } while (0);
  free(name);
  ;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_path_binary_extensions>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  lea    D28(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <split_ext@plt>
  mov    0x10(%rsp),%rsi
  mov    %r12,%rdx
  xor    %eax,%eax
  mov    $0x47,%ecx
  lea    D5(%rip),%rdi
  call   <seatest_assert_string_equal@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  mov    $0x47,%ecx
  mov    %r12,%rdx
  mov    $0x1b,%edi
  call   <seatest_assert_int_equal@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <free@plt>
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D3: /home/user.name/file.double.ext

tool: D28: test_path_binary_extensions

tool: D5: ext

assistant: ```c
void test_path_binary_extensions(void) {
  int root_len;
  const char *ext;
  char *const name = strdup("/home/user.name/file.double.ext");
  split_ext(name, &root_len, &ext);
  do {
    seatest_assert_string_equal("ext", ext, __FUNCTION__, 71);
  } while (0);
  do {
    seatest_assert_int_equal((27), root_len, __FUNCTION__, 71);
  } while (0);
  free(name);
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Thread_function2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
  mov    $0x2,%edi
  call   <sleep@plt>
  jmp    L4
L14:
  mov    $0x1,%edi
  call   <sleep@plt>
L4:
  cmpl   $0xa,-0x4(%rbp)
  jbe    L1
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: Child Thread 2 Iteration %d


assistant: ```c
void *Thread_function2(void *arg) {
  unsigned int i = 1;
  while (i < 11) {
    printf("Child Thread 2 Iteration %d\n", i);
    i++;
    if (i % 2)
      sleep(2);
    else
      sleep(1);
  }
  return arg;
}
```