ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jl     L14
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L14:
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L17
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L55
L17:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L34
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L55
L34:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L55:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
data_type: string
name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D14: Please enter 3 numbers separated by spaces > 

tool: D11: %d%d%d

tool: D0: %d is the median


assistant: ```c
int main(void) {
  int a, b, c, median, temp;
  median = 0;
  temp = 0;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if (a >= b) {
    temp = b;
    b = a;
    a = temp;
  }
  if (a < c)
    median = b;
  else if (b > c)
    median = a;
  else
    median = c;
  printf("%d is the median\n", median);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  cmp    %eax,%edx
  jl     L18
  mov    %edx,0x10(%rsp)
  mov    %eax,0xc(%rsp)
L18:
  mov    0xc(%rsp),%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  jge    L9
  mov    0x10(%rsp),%esi
L4:
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  cmp    0x10(%rsp),%eax
  cmovge %eax,%esi
  jmp    L4
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string
name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D13
datatype: string

tool: D2: Please enter 3 numbers separated by spaces > 

tool: D11: %d%d%d

tool: D13: %d is the median


assistant: ```c
int main(void) {
  int a, b, c, median, temp;
  median = 0;
  temp = 0;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if (a >= b) {
    temp = b;
    b = a;
    a = temp;
  }
  if (a < c)
    median = b;
  else if (b > c)
    median = a;
  else
    median = c;
  printf("%d is the median\n", median);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jl     L1
  mov    %eax,%edx
  mov    %eax,0x10(%rsp)
  mov    %esi,%eax
  mov    %esi,0xc(%rsp)
  mov    %edx,%esi
L1:
  mov    0x14(%rsp),%edx
  cmp    %edx,%eax
  jl     L12
  cmp    %esi,%edx
  cmovl  %eax,%edx
  mov    %edx,%esi
L12:
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string

tool: D29: Please enter 3 numbers separated by spaces > 

tool: D28: %d%d%d

tool: D23: %d is the median


assistant: ```c
int main(void) {
  int a, b, c, median, temp;
  median = 0;
  temp = 0;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if (a >= b) {
    temp = b;
    b = a;
    a = temp;
  }
  if (a < c)
    median = b;
  else if (b > c)
    median = a;
  else
    median = c;
  printf("%d is the median\n", median);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  cmp    %esi,%eax
  jl     L8
  mov    %eax,%edx
  mov    %eax,0x10(%rsp)
  mov    %esi,%eax
  mov    %esi,0xc(%rsp)
  mov    %edx,%esi
L8:
  mov    0x14(%rsp),%edx
  cmp    %edx,%eax
  jl     L26
  cmp    %esi,%edx
  cmovl  %eax,%edx
  mov    %edx,%esi
L26:
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_guessed: string
name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D25
type_guessed: string

tool: D18: Please enter 3 numbers separated by spaces > 

tool: D7: %d%d%d

tool: D25: %d is the median


assistant: ```c
int main(void) {
  int a, b, c, median, temp;
  median = 0;
  temp = 0;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if (a >= b) {
    temp = b;
    b = a;
    a = temp;
  }
  if (a < c)
    median = b;
  else if (b > c)
    median = a;
  else
    median = c;
  printf("%d is the median\n", median);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rdtsc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  rdtsc
  mov    %eax,-0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  shl    $0x20,%rax
  or     %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned a, d;
  __asm__ volatile("rdtsc" : "=a"(a), "=d"(d));
  return ((unsigned long long)a) | (((unsigned long long)d) << 32);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rdtsc>:
  endbr64
  rdtsc
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned a, d;
  __asm__ volatile("rdtsc" : "=a"(a), "=d"(d));
  return ((unsigned long long)a) | (((unsigned long long)d) << 32);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rdtsc>:
  endbr64
  rdtsc
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned a, d;
  __asm__ volatile("rdtsc" : "=a"(a), "=d"(d));
  return ((unsigned long long)a) | (((unsigned long long)d) << 32);
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rdtsc>:
  endbr64
  rdtsc
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned a, d;
  __asm__ volatile("rdtsc" : "=a"(a), "=d"(d));
  return ((unsigned long long)a) | (((unsigned long long)d) << 32);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DrawRect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%edi
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  call   <DrawLine@plt>
  movzbl -0x14(%rbp),%esi
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%edi
  mov    -0xc(%rbp),%eax
  add    %eax,%edi
  mov    -0x8(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  call   <DrawLine@plt>
  movzbl -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%esi
  mov    -0x10(%rbp),%eax
  add    %eax,%esi
  mov    -0x4(%rbp),%edi
  mov    -0xc(%rbp),%eax
  add    %eax,%edi
  mov    -0x4(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  call   <DrawLine@plt>
  movzbl -0x14(%rbp),%edi
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <DrawLine@plt>
  nop
  leave
  ret
```

assistant: ```c
void DrawRect(int x, int y, int width, int height, unsigned char color) {
  DrawLine(x, y, x + width, y, color);
  DrawLine(x + width, y, x + width, y + height, color);
  DrawLine(x + width, y + height, x, y + height, color);
  DrawLine(x, y + height, x, y, color);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DrawRect>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %ecx,%ebx
  movzbl %r8b,%r13d
  lea    (%rdi,%rdx,1),%r14d
  mov    %r13d,%r8d
  mov    %esi,%ecx
  mov    %r14d,%edx
  call   <DrawLine@plt>
  add    %r12d,%ebx
  mov    %r13d,%r8d
  mov    %ebx,%ecx
  mov    %r14d,%edx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <DrawLine@plt>
  mov    %r13d,%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <DrawLine@plt>
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <DrawLine@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void DrawRect(int x, int y, int width, int height, unsigned char color) {
  DrawLine(x, y, x + width, y, color);
  DrawLine(x + width, y, x + width, y + height, color);
  DrawLine(x + width, y + height, x, y + height, color);
  DrawLine(x, y + height, x, y, color);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DrawRect>:
  endbr64
  push   %r14
  lea    (%rdi,%rdx,1),%r14d
  push   %r13
  mov    %ecx,%r13d
  mov    %r14d,%edx
  mov    %esi,%ecx
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  add    %r12d,%r13d
  mov    %edi,%ebp
  push   %rbx
  movzbl %r8b,%ebx
  mov    %ebx,%r8d
  call   <DrawLine@plt>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r14d,%edx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <DrawLine@plt>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <DrawLine@plt>
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  pop    %rbx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <DrawLine@plt>
```

assistant: ```c
void DrawRect(int x, int y, int width, int height, unsigned char color) {
  DrawLine(x, y, x + width, y, color);
  DrawLine(x + width, y, x + width, y + height, color);
  DrawLine(x + width, y + height, x, y + height, color);
  DrawLine(x, y + height, x, y, color);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rotate60>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm2
  movsd  D12(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm2
  movsd  D12(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: f64
name: retrieve_data
arguments: tag: D12
type_guessed: f64

tool: D10: 0.5

tool: D12: 0.8660254037844386

assistant: ```c
void rotate60(double dx, double dy, double *rdx, double *rdy) {
  *rdx = 0.5 * dx - (0.86602540378443864676) * dy;
  *rdy = 0.5 * dy + (0.86602540378443864676) * dx;
}
```
user: What is the c source code of the assembly code below:

```asm
<rotate60>:
  endbr64
  movsd  D15(%rip),%xmm4
  movapd %xmm0,%xmm2
  mulsd  %xmm4,%xmm2
  movsd  D7(%rip),%xmm3
  movapd %xmm1,%xmm5
  mulsd  %xmm3,%xmm5
  subsd  %xmm5,%xmm2
  movsd  %xmm2,(%rdi)
  mulsd  %xmm4,%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
data_type: f64
name: disassemble_data
arguments: tag: D7
data_type: f64

tool: D15: 0.5

tool: D7: 0.8660254037844386

assistant: ```c
void rotate60(double dx, double dy, double *rdx, double *rdy) {
  *rdx = 0.5 * dx - (0.86602540378443864676) * dy;
  *rdy = 0.5 * dy + (0.86602540378443864676) * dx;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rotate60>:
  endbr64
  movsd  D10(%rip),%xmm4
  movsd  D16(%rip),%xmm3
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm5
  mulsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm5
  mulsd  %xmm4,%xmm1
  mulsd  %xmm3,%xmm0
  subsd  %xmm5,%xmm2
  addsd  %xmm0,%xmm1
  movsd  %xmm2,(%rdi)
  movsd  %xmm1,(%rsi)
  ret
```

tool_calls: name: read_data
arguments: tag: D10
type_infered: f64
name: read_data
arguments: tag: D16
type_infered: f64

tool: D10: 0.5

tool: D16: 0.8660254037844386

assistant: ```c
void rotate60(double dx, double dy, double *rdx, double *rdy) {
  *rdx = 0.5 * dx - (0.86602540378443864676) * dy;
  *rdy = 0.5 * dy + (0.86602540378443864676) * dx;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotate60>:
  endbr64
  movsd  D7(%rip),%xmm4
  movsd  D6(%rip),%xmm3
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm5
  mulsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm5
  mulsd  %xmm4,%xmm1
  mulsd  %xmm3,%xmm0
  subsd  %xmm5,%xmm2
  addsd  %xmm0,%xmm1
  movsd  %xmm2,(%rdi)
  movsd  %xmm1,(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: f64
name: parse_data
arguments: label: D6
data_type: f64

tool: D7: 0.5

tool: D6: 0.8660254037844386

assistant: ```c
void rotate60(double dx, double dy, double *rdx, double *rdy) {
  *rdx = 0.5 * dx - (0.86602540378443864676) * dy;
  *rdy = 0.5 * dy + (0.86602540378443864676) * dx;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L49
L29:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L30
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L3
  jmp    L20
L30:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L10
L3:
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x18(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L29
L20:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: readLine

assistant: ```c
int read_line(int clientfd, char *buf, int size) {
  int i = 0;
  for (i = 0; i < size - 2; ++i) {
    int n = recv(clientfd, buf + i, 1, 0);
    if (1 == n) {
      if (buf[i] == '\n')
        break;
    } else {
      perror("readLine");
      return -1;
    }
  }
  buf[++i] = '\0';
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r13
  cmp    $0x2,%edx
  jle    L20
  mov    %edi,%r14d
  mov    %rsi,%rbx
  lea    -0x2(%rdx),%r12d
  mov    $0x0,%ebp
L0:
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r14d,%edi
  call   <recv@plt>
  cmp    $0x1,%eax
  jne    L35
  cmpb   $0xa,(%rbx)
  je     L51
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  jne    L0
  mov    %r12d,%ebp
L51:
  lea    0x1(%rbp),%eax
  movslq %eax,%rdx
  movb   $0x0,0x0(%r13,%rdx,1)
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L15
L20:
  mov    $0x0,%ebp
  jmp    L51
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: readLine

assistant: ```c
int read_line(int clientfd, char *buf, int size) {
  int i = 0;
  for (i = 0; i < size - 2; ++i) {
    int n = recv(clientfd, buf + i, 1, 0);
    if (1 == n) {
      if (buf[i] == '\n')
        break;
    } else {
      perror("readLine");
      return -1;
    }
  }
  buf[++i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edx
  jle    L27
  lea    -0x3(%rdx),%eax
  mov    %edi,%ebp
  mov    %rsi,%r13
  lea    0x1(%rsi,%rax,1),%r12
  jmp    L38
  nopl   (%rax)
L43:
  sub    %ebx,%eax
  add    %r13d,%eax
  cmpb   $0xa,0x0(%r13)
  je     L9
  add    $0x1,%r13
  cmp    %r12,%r13
  je     L20
L38:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  cmp    $0x1,%eax
  je     L43
  lea    D3(%rip),%rdi
  call   <perror@plt>
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L20:
  add    $0x1,%eax
L9:
  movslq %eax,%rdx
L8:
  movb   $0x0,(%rbx,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    $0x1,%edx
  mov    $0x1,%eax
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: readLine

assistant: ```c
int read_line(int clientfd, char *buf, int size) {
  int i = 0;
  for (i = 0; i < size - 2; ++i) {
    int n = recv(clientfd, buf + i, 1, 0);
    if (1 == n) {
      if (buf[i] == '\n')
        break;
    } else {
      perror("readLine");
      return -1;
    }
  }
  buf[++i] = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edx
  jle    L1
  lea    -0x3(%rdx),%eax
  mov    %edi,%ebp
  mov    %rsi,%r13
  lea    0x1(%rsi,%rax,1),%r12
  jmp    L28
  nopl   (%rax)
L32:
  sub    %ebx,%eax
  add    %r13d,%eax
  cmpb   $0xa,0x0(%r13)
  je     L35
  add    $0x1,%r13
  cmp    %r12,%r13
  je     L7
L28:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  cmp    $0x1,%eax
  je     L32
  lea    D7(%rip),%rdi
  call   <perror@plt>
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L7:
  add    $0x1,%eax
L35:
  movslq %eax,%rdx
L8:
  movb   $0x0,(%rbx,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    $0x1,%edx
  mov    $0x1,%eax
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: readLine

assistant: ```c
int read_line(int clientfd, char *buf, int size) {
  int i = 0;
  for (i = 0; i < size - 2; ++i) {
    int n = recv(clientfd, buf + i, 1, 0);
    if (1 == n) {
      if (buf[i] == '\n')
        break;
    } else {
      perror("readLine");
      return -1;
    }
  }
  buf[++i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<concatn_doublenull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L25
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L17:
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L52
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L52:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L86
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L40
L86:
  cmpl   $0x0,-0x8(%rbp)
  jle    L57
  addl   $0x1,-0x8(%rbp)
L57:
  movl   $0x0,-0x4(%rbp)
  jmp    L128
L122:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L128:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L20
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L122
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L122
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L40
L25:
  nop
L40:
  pop    %rbp
  ret
```

assistant: ```c
void concatn_doublenull(int length, char *dst, const char *src) {
  int i, j;
  if (length <= 1)
    return;
  for (i = 0; i < length - 2 && (dst[i] || dst[i + 1]); i++)
    ;
  if (i == length - 2) {
    dst[i] = '\0';
    dst[i + 1] = '\0';
    return;
  }
  if (i > 0)
    i++;
  for (j = 0; i < length - 2 && (src[j] || src[j + 1]); i++, j++)
    dst[i] = src[j];
  dst[i] = '\0';
  dst[i + 1] = '\0';
}
```