ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<BubbleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L22
L12:
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L51
L66:
  mov    $0x14,%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jg     L70
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L69
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0x10(%rbp)
L69:
  addl   $0x1,-0xc(%rbp)
L51:
  cmpl   $0x13,-0xc(%rbp)
  jle    L66
  jmp    L47
L70:
  nop
L47:
  cmpl   $0x0,-0x10(%rbp)
  jne    L89
  addl   $0x1,-0x8(%rbp)
L22:
  cmpl   $0x13,-0x8(%rbp)
  jle    L12
  jmp    L65
L89:
  nop
L65:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BubbleSort(int Array[]) {
  int Sorted = 0;
  int Temp, LastIndex, Index, i;
  for (i = 1; i <= 20 - 1; i++) {
    Sorted = 1;
    for (Index = 1; Index <= 20 - 1; Index++) {
      if (Index > 20 - i)
        break;
      if (Array[Index] > Array[Index + 1]) {
        Temp = Array[Index];
        Array[Index] = Array[Index + 1];
        Array[Index + 1] = Temp;
        Sorted = 0;
      }
    }
    if (Sorted)
      break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BubbleSort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  mov    $0x13,%r9d
  mov    $0x1,%eax
  mov    $0x1,%r10d
  mov    $0x14,%r12d
  mov    $0x1,%ebp
  mov    $0x0,%r11d
  jmp    L44
L54:
  add    $0x1,%eax
  cmp    $0x13,%eax
  jg     L23
L49:
  cmp    %eax,%r9d
  jl     L23
L44:
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rsi
  mov    (%rsi),%ecx
  lea    0x4(%rdi,%rdx,1),%rdx
  mov    (%rdx),%r8d
  cmp    %r8d,%ecx
  jle    L54
  mov    %r8d,(%rsi)
  mov    %ecx,(%rdx)
  add    $0x1,%eax
  mov    %r11d,%r10d
  cmp    $0x13,%eax
  jle    L49
L55:
  add    $0x1,%ebx
  cmp    $0x13,%ebx
  jg     L37
  mov    %r12d,%r9d
  sub    %ebx,%r9d
  mov    $0x1,%eax
  mov    %ebp,%r10d
  jmp    L44
L23:
  test   %r10d,%r10d
  je     L55
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void BubbleSort(int Array[]) {
  int Sorted = 0;
  int Temp, LastIndex, Index, i;
  for (i = 1; i <= 20 - 1; i++) {
    Sorted = 1;
    for (Index = 1; Index <= 20 - 1; Index++) {
      if (Index > 20 - i)
        break;
      if (Array[Index] > Array[Index + 1]) {
        Temp = Array[Index];
        Array[Index] = Array[Index + 1];
        Array[Index + 1] = Temp;
        Sorted = 0;
      }
    }
    if (Sorted)
      break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BubbleSort>:
  endbr64
  mov    $0x13,%esi
  nopl   0x0(%rax)
L33:
  mov    $0x1,%eax
  mov    $0x1,%r8d
  jmp    L22
  nopl   (%rax)
L32:
  mov    (%rdi,%rax,4),%edx
  mov    0x4(%rdi,%rax,4),%ecx
  cmp    %ecx,%edx
  jle    L26
  mov    %ecx,(%rdi,%rax,4)
  xor    %r8d,%r8d
  mov    %edx,0x4(%rdi,%rax,4)
L26:
  add    $0x1,%rax
  cmp    $0x14,%rax
  je     L28
L22:
  cmp    %eax,%esi
  jge    L32
L28:
  test   %r8d,%r8d
  jne    L46
  sub    $0x1,%esi
  jne    L33
L46:
  ret
```

assistant: ```c
void BubbleSort(int Array[]) {
  int Sorted = 0;
  int Temp, LastIndex, Index, i;
  for (i = 1; i <= 20 - 1; i++) {
    Sorted = 1;
    for (Index = 1; Index <= 20 - 1; Index++) {
      if (Index > 20 - i)
        break;
      if (Array[Index] > Array[Index + 1]) {
        Temp = Array[Index];
        Array[Index] = Array[Index + 1];
        Array[Index + 1] = Temp;
        Sorted = 0;
      }
    }
    if (Sorted)
      break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BubbleSort>:
  endbr64
  mov    $0x13,%esi
  nopl   0x0(%rax)
L0:
  mov    $0x1,%edx
  mov    $0x1,%r8d
  jmp    L6
  nopl   (%rax)
L52:
  movq   (%rdi,%rdx,4),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L36
  movq   %xmm1,(%rdi,%rdx,4)
  xor    %r8d,%r8d
L36:
  add    $0x1,%rdx
  cmp    $0x14,%rdx
  je     L19
L6:
  cmp    %edx,%esi
  jge    L52
L19:
  test   %r8d,%r8d
  jne    L49
  sub    $0x1,%esi
  jne    L0
L49:
  ret
```

assistant: ```c
void BubbleSort(int Array[]) {
  int Sorted = 0;
  int Temp, LastIndex, Index, i;
  for (i = 1; i <= 20 - 1; i++) {
    Sorted = 1;
    for (Index = 1; Index <= 20 - 1; Index++) {
      if (Index > 20 - i)
        break;
      if (Array[Index] > Array[Index + 1]) {
        Temp = Array[Index];
        Array[Index] = Array[Index + 1];
        Array[Index + 1] = Temp;
        Sorted = 0;
      }
    }
    if (Sorted)
      break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getfstat1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <statvfs@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L13
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L23
L13:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D26
type_guessed: string
name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D24
type_guessed: string

tool: D26: /workspace

tool: D11: get fail:

tool: D24: fs size %ld blocks %ld 


assistant: ```c
void getfstat1(void) {
  int ret;
  struct statvfs sbuf;
  ret = statvfs("/workspace", &sbuf);
  if (ret < 0) {
    perror("get fail:");
    return;
  }
  printf("fs size %ld blocks %ld \n", sbuf.f_bsize, sbuf.f_blocks);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getfstat1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <statvfs@plt>
  test   %eax,%eax
  js     L5
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  ret
L5:
  lea    D27(%rip),%rdi
  call   <perror@plt>
  jmp    L12
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D28
data_type: string
name: disassemble_data
arguments: label: D27
data_type: string

tool: D0: /workspace

tool: D28: fs size %ld blocks %ld 


tool: D27: get fail:

assistant: ```c
void getfstat1(void) {
  int ret;
  struct statvfs sbuf;
  ret = statvfs("/workspace", &sbuf);
  if (ret < 0) {
    perror("get fail:");
    return;
  }
  printf("fs size %ld blocks %ld \n", sbuf.f_bsize, sbuf.f_blocks);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getfstat1>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <statvfs@plt>
  test   %eax,%eax
  js     L7
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  jmp    L14
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D2
type_infered: string

tool: D4: /workspace

tool: D1: fs size %ld blocks %ld 


tool: D2: get fail:

assistant: ```c
void getfstat1(void) {
  int ret;
  struct statvfs sbuf;
  ret = statvfs("/workspace", &sbuf);
  if (ret < 0) {
    perror("get fail:");
    return;
  }
  printf("fs size %ld blocks %ld \n", sbuf.f_bsize, sbuf.f_blocks);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getfstat1>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <statvfs@plt>
  test   %eax,%eax
  js     L25
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  jmp    L16
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D2
type: string

tool: D10: /workspace

tool: D19: fs size %ld blocks %ld 


tool: D2: get fail:

assistant: ```c
void getfstat1(void) {
  int ret;
  struct statvfs sbuf;
  ret = statvfs("/workspace", &sbuf);
  if (ret < 0) {
    perror("get fail:");
    return;
  }
  printf("fs size %ld blocks %ld \n", sbuf.f_bsize, sbuf.f_blocks);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xdr_authunix_parms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x14(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xdr_u_long@plt>
  test   %rax,%rax
  je     L52
  mov    D43(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <xdr_string@plt>
  test   %rax,%rax
  je     L52
  mov    -0x10(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xdr_int@plt>
  test   %rax,%rax
  je     L52
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xdr_int@plt>
  test   %rax,%rax
  je     L52
  mov    D44(%rip),%rax
  mov    %eax,%edi
  mov    D46(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r9d
  mov    $0x4,%r8d
  mov    %rax,%rdi
  call   <xdr_array@plt>
  test   %rax,%rax
  je     L52
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  jmp    L48
L52:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
L48:
  leave
  ret
```

assistant: ```c
bool_t xdr_authunix_parms(XDR *xdrs, struct authunix_parms *p) {
  if (xdr_u_long(xdrs, &(p->aup_time)) && xdr_string(xdrs, &(p->aup_machname), MAX_MACHINE_NAME) && xdr_int(xdrs, &(p->aup_uid)) && xdr_int(xdrs, &(p->aup_gid)) && xdr_array(xdrs, (caddr_t *)(void *)&(p->aup_gids), &(p->aup_len), NGRPS, sizeof(int), (xdrproc_t)xdr_int)) {
    return (TRUE);
  }
  return (FALSE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xdr_authunix_parms>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x14(%rsi),%rsi
  call   <xdr_u_long@plt>
  test   %rax,%rax
  jne    L9
L31:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    0x10(%rbx),%rsi
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    %rbp,%rdi
  call   <xdr_string@plt>
  test   %rax,%rax
  je     L31
  lea    0xc(%rbx),%rsi
  mov    %rbp,%rdi
  call   <xdr_int@plt>
  test   %rax,%rax
  je     L31
  lea    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  call   <xdr_int@plt>
  test   %rax,%rax
  je     L31
  lea    0x4(%rbx),%rsi
  mov    D12(%rip),%r9d
  mov    $0x4,%r8d
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <xdr_array@plt>
  test   %rax,%rax
  je     L31
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  jmp    L42
```

assistant: ```c
bool_t xdr_authunix_parms(XDR *xdrs, struct authunix_parms *p) {
  if (xdr_u_long(xdrs, &(p->aup_time)) && xdr_string(xdrs, &(p->aup_machname), MAX_MACHINE_NAME) && xdr_int(xdrs, &(p->aup_uid)) && xdr_int(xdrs, &(p->aup_gid)) && xdr_array(xdrs, (caddr_t *)(void *)&(p->aup_gids), &(p->aup_len), NGRPS, sizeof(int), (xdrproc_t)xdr_int)) {
    return (TRUE);
  }
  return (FALSE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xdr_authunix_parms>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  add    $0x14,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <xdr_u_long@plt>
  test   %rax,%rax
  jne    L39
L1:
  mov    D25(%rip),%rax
  mov    (%rax),%eax
L50:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L39:
  mov    D49(%rip),%rax
  lea    0x10(%r12),%rsi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <xdr_string@plt>
  test   %rax,%rax
  je     L1
  lea    0xc(%r12),%rsi
  mov    %rbp,%rdi
  call   <xdr_int@plt>
  test   %rax,%rax
  je     L1
  lea    0x8(%r12),%rsi
  mov    %rbp,%rdi
  call   <xdr_int@plt>
  test   %rax,%rax
  je     L1
  mov    D24(%rip),%rax
  mov    D0(%rip),%r9d
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    0x4(%r12),%rsi
  mov    $0x4,%r8d
  mov    (%rax),%ecx
  call   <xdr_array@plt>
  test   %rax,%rax
  je     L1
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  jmp    L50
```

assistant: ```c
bool_t xdr_authunix_parms(XDR *xdrs, struct authunix_parms *p) {
  if (xdr_u_long(xdrs, &(p->aup_time)) && xdr_string(xdrs, &(p->aup_machname), MAX_MACHINE_NAME) && xdr_int(xdrs, &(p->aup_uid)) && xdr_int(xdrs, &(p->aup_gid)) && xdr_array(xdrs, (caddr_t *)(void *)&(p->aup_gids), &(p->aup_len), NGRPS, sizeof(int), (xdrproc_t)xdr_int)) {
    return (TRUE);
  }
  return (FALSE);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xdr_authunix_parms>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  add    $0x14,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <xdr_u_long@plt>
  test   %rax,%rax
  jne    L37
L27:
  mov    D38(%rip),%rax
  mov    (%rax),%eax
L53:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    D36(%rip),%rax
  lea    0x10(%r12),%rsi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <xdr_string@plt>
  test   %rax,%rax
  je     L27
  lea    0xc(%r12),%rsi
  mov    %rbp,%rdi
  call   <xdr_int@plt>
  test   %rax,%rax
  je     L27
  lea    0x8(%r12),%rsi
  mov    %rbp,%rdi
  call   <xdr_int@plt>
  test   %rax,%rax
  je     L27
  mov    D16(%rip),%rax
  mov    D34(%rip),%r9d
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    0x4(%r12),%rsi
  mov    $0x4,%r8d
  mov    (%rax),%ecx
  call   <xdr_array@plt>
  test   %rax,%rax
  je     L27
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  jmp    L53
```

assistant: ```c
bool_t xdr_authunix_parms(XDR *xdrs, struct authunix_parms *p) {
  if (xdr_u_long(xdrs, &(p->aup_time)) && xdr_string(xdrs, &(p->aup_machname), MAX_MACHINE_NAME) && xdr_int(xdrs, &(p->aup_uid)) && xdr_int(xdrs, &(p->aup_gid)) && xdr_array(xdrs, (caddr_t *)(void *)&(p->aup_gids), &(p->aup_len), NGRPS, sizeof(int), (xdrproc_t)xdr_int)) {
    return (TRUE);
  }
  return (FALSE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_mul_u64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L1:
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rax
  mov    $0x0,%edx
  add    %rax,-0x10(%rbp)
  adc    %rdx,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rcx
  cmp    %rcx,-0x30(%rbp)
  ja     L1
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) unsigned __int128 calc_mul_u64(unsigned long long volatile a, unsigned long long b) {
  unsigned __int128 res = 0;
  int i;
  for (i = 0; i < b; ++i)
    res += (unsigned __int128)a;
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_mul_u64>:
  endbr64
  mov    %rdi,-0x10(%rsp)
  test   %rsi,%rsi
  je     L14
  mov    $0x0,%edx
  mov    $0x0,%r10d
  mov    $0x0,%r11d
L23:
  mov    -0x10(%rsp),%rax
  mov    $0x0,%r9d
  add    %rax,%r10
  adc    %r9,%r11
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L23
L10:
  mov    %r10,%rax
  mov    %r11,%rdx
  ret
L14:
  mov    $0x0,%r10d
  mov    $0x0,%r11d
  jmp    L10
```

assistant: ```c
__attribute__((no)) unsigned __int128 calc_mul_u64(unsigned long long volatile a, unsigned long long b) {
  unsigned __int128 res = 0;
  int i;
  for (i = 0; i < b; ++i)
    res += (unsigned __int128)a;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_mul_u64>:
  endbr64
  mov    %rdi,-0x10(%rsp)
  test   %rsi,%rsi
  je     L8
  xor    %edx,%edx
  xor    %r10d,%r10d
  xor    %r11d,%r11d
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    -0x10(%rsp),%r8
  xor    %r9d,%r9d
  add    %r8,%r10
  adc    %r9,%r11
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L14
  mov    %r10,%rax
  mov    %r11,%rdx
  ret
  nopl   0x0(%rax)
L8:
  xor    %r10d,%r10d
  xor    %r11d,%r11d
  mov    %r10,%rax
  mov    %r11,%rdx
  ret
```

assistant: ```c
__attribute__((no)) unsigned __int128 calc_mul_u64(unsigned long long volatile a, unsigned long long b) {
  unsigned __int128 res = 0;
  int i;
  for (i = 0; i < b; ++i)
    res += (unsigned __int128)a;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calc_mul_u64>:
  endbr64
  mov    %rdi,-0x10(%rsp)
  test   %rsi,%rsi
  je     L13
  xor    %edx,%edx
  xor    %r10d,%r10d
  xor    %r11d,%r11d
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    -0x10(%rsp),%r8
  xor    %r9d,%r9d
  add    %r8,%r10
  adc    %r9,%r11
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L15
  mov    %r10,%rax
  mov    %r11,%rdx
  ret
  nopl   0x0(%rax)
L13:
  xor    %r10d,%r10d
  xor    %r11d,%r11d
  mov    %r10,%rax
  mov    %r11,%rdx
  ret
```

assistant: ```c
__attribute__((no)) unsigned __int128 calc_mul_u64(unsigned long long volatile a, unsigned long long b) {
  unsigned __int128 res = 0;
  int i;
  for (i = 0; i < b; ++i)
    res += (unsigned __int128)a;
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_collapse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x10,%r13d
  jmp    L57
L8:
  sub    $0x1,%r13d
  je     L28
L57:
  mov    $0x10,%r12d
L4:
  mov    $0x10,%ebp
L26:
  mov    $0x10,%ebx
L2:
  mov    $0x0,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L2
  sub    $0x1,%ebp
  jne    L26
  sub    $0x1,%r12d
  jne    L4
  jmp    L8
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp target teams distribute collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp target teams distribute collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(2) firstprivate(i)
  for (i = 0; i < 16; ++i)
    for (int j = 0; j < 16; ++j)
#pragma omp parallel for reduction(+ : i, j)
      for (int k = 0; k < 16; ++k)
        i += j;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_collapse>:
  endbr64
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L36:
  mov    $0x10,%r12d
L13:
  mov    $0x10,%ebp
  nop
L24:
  mov    $0x10,%ebx
  nopl   (%rax)
L3:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L3
  sub    $0x1,%ebp
  jne    L24
  sub    $0x1,%r12d
  jne    L13
  sub    $0x1,%r13d
  jne    L36
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp target teams distribute collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp target teams distribute collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(2) firstprivate(i)
  for (i = 0; i < 16; ++i)
    for (int j = 0; j < 16; ++j)
#pragma omp parallel for reduction(+ : i, j)
      for (int k = 0; k < 16; ++k)
        i += j;
}
```