ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1e,%ecx
  mov    $0x5,%edx
  mov    $0x6,%esi
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x36,%ecx
  mov    $0x9,%edx
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xb4,%ecx
  mov    $0x1e,%edx
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xfffffeb0,%ecx
  mov    $0xffffffc8,%edx
  mov    $0x6,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D5: %d * %d = %d


assistant: ```c
int main(void) {
  int x = 6;
  int t;
  t = (x << 2) + x;
  printf("%d * %d = %d\n", x, 5, t);
  t = (x << 3) + x;
  printf("%d * %d = %d\n", x, 9, t);
  t = (x << 5) - (x << 1);
  printf("%d * %d = %d\n", x, 30, t);
  t = (x << 3) - (x << 6);
  printf("%d * %d = %d\n", x, -56, t);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1e,%ecx
  mov    $0x5,%edx
  mov    $0x6,%esi
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x36,%ecx
  mov    $0x9,%edx
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xb4,%ecx
  mov    $0x1e,%edx
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xfffffeb0,%ecx
  mov    $0xffffffc8,%edx
  mov    $0x6,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D4: %d * %d = %d


assistant: ```c
int main(void) {
  int x = 6;
  int t;
  t = (x << 2) + x;
  printf("%d * %d = %d\n", x, 5, t);
  t = (x << 3) + x;
  printf("%d * %d = %d\n", x, 9, t);
  t = (x << 5) - (x << 1);
  printf("%d * %d = %d\n", x, 30, t);
  t = (x << 3) - (x << 6);
  printf("%d * %d = %d\n", x, -56, t);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  add    %eax,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[0UL] &= state[local1];
      local1++;
    }
    output[0UL] = (state[0UL] << (unsigned char)1) >> (unsigned char)1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[0UL] &= state[local1];
      local1++;
    }
    output[0UL] = (state[0UL] << (unsigned char)1) >> (unsigned char)1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[0UL] &= state[local1];
      local1++;
    }
    output[0UL] = (state[0UL] << (unsigned char)1) >> (unsigned char)1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[0UL] &= state[local1];
      local1++;
    }
    output[0UL] = (state[0UL] << (unsigned char)1) >> (unsigned char)1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int m = 0;
  m = 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int m = 0;
  m = 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int m = 0;
  m = 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int m = 0;
  m = 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L17:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L4
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *s, int c, unsigned n) {
  char *p = s;
  while (n--)
    *p++ = c;
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%ecx
  test   %edx,%edx
  je     L11
  mov    %ecx,%ecx
  lea    0x1(%rdi,%rcx,1),%rcx
  mov    %rdi,%rdx
L2:
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L2
L11:
  ret
```

assistant: ```c
void *memset(void *s, int c, unsigned n) {
  char *p = s;
  while (n--)
    *p++ = c;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  je     L9
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *s, int c, unsigned n) {
  char *p = s;
  while (n--)
    *p++ = c;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  je     L9
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *s, int c, unsigned n) {
  char *p = s;
  while (n--)
    *p++ = c;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unity_putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <log_write_console_char@plt>
  cmpl   $0xa,-0x4(%rbp)
  jne    L6
  mov    $0xd,%edi
  call   <log_write_console_char@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void unity_putchar(int c) {
  log_write_console_char((unsigned char)c);
  if (c == '\n') {
    log_write_console_char('\r');
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unity_putchar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <log_write_console_char@plt>
  cmp    $0xa,%ebx
  je     L13
L7:
  pop    %rbx
  ret
L13:
  mov    $0xd,%edi
  call   <log_write_console_char@plt>
  jmp    L7
```

assistant: ```c
void unity_putchar(int c) {
  log_write_console_char((unsigned char)c);
  if (c == '\n') {
    log_write_console_char('\r');
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unity_putchar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <log_write_console_char@plt>
  cmp    $0xa,%ebx
  je     L7
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xd,%edi
  pop    %rbx
  jmp    1050 <log_write_console_char@plt>
```

assistant: ```c
void unity_putchar(int c) {
  log_write_console_char((unsigned char)c);
  if (c == '\n') {
    log_write_console_char('\r');
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unity_putchar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <log_write_console_char@plt>
  cmp    $0xa,%ebx
  je     L7
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xd,%edi
  pop    %rbx
  jmp    1050 <log_write_console_char@plt>
```

assistant: ```c
void unity_putchar(int c) {
  log_write_console_char((unsigned char)c);
  if (c == '\n') {
    log_write_console_char('\r');
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uartinit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  mov    $0xfe215004,%edi
  call   <outw@plt>
  mov    $0x0,%esi
  mov    $0xfe215060,%edi
  call   <outw@plt>
  mov    $0x3,%esi
  mov    $0xfe21504c,%edi
  call   <outw@plt>
  mov    $0x0,%esi
  mov    $0xfe215050,%edi
  call   <outw@plt>
  mov    $0x1,%esi
  mov    $0xfe215044,%edi
  call   <outw@plt>
  mov    $0xc7,%esi
  mov    $0xfe215048,%edi
  call   <outw@plt>
  mov    $0x10e,%esi
  mov    $0xfe215068,%edi
  call   <outw@plt>
  mov    $0x2,%esi
  mov    $0xe,%edi
  call   <setgpiofunc@plt>
  mov    $0x2,%esi
  mov    $0xf,%edi
  call   <setgpiofunc@plt>
  mov    $0x0,%esi
  mov    $0xfe200094,%edi
  call   <outw@plt>
  mov    $0xa,%edi
  call   <delay@plt>
  mov    $0xc000,%esi
  mov    $0xfe200098,%edi
  call   <outw@plt>
  mov    $0xa,%edi
  call   <delay@plt>
  mov    $0x0,%esi
  mov    $0xfe200098,%edi
  call   <outw@plt>
  mov    $0x3,%esi
  mov    $0xfe215060,%edi
  call   <outw@plt>
  mov    $0x0,%eax
  call   <enableirqminiuart@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uartinit(void) {
  outw(0xFE215004, 1);
  outw(0xFE215060, 0);
  outw(0xFE21504C, 0x3);
  outw(0xFE215050, 0);
  outw(0xFE215044, 0x1);
  outw(0xFE215048, 0xC7);
  outw(0xFE215068, 270);
  setgpiofunc(14, 2);
  setgpiofunc(15, 2);
  outw(0xFE200094, 0);
  delay(10);
  outw(0xFE200098, (1 << 14) | (1 << 15));
  delay(10);
  outw(0xFE200098, 0);
  outw(0xFE215060, 3);
  enableirqminiuart();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uartinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xfe215004,%edi
  call   <outw@plt>
  mov    $0x0,%esi
  mov    $0xfe215060,%edi
  call   <outw@plt>
  mov    $0x3,%esi
  mov    $0xfe21504c,%edi
  call   <outw@plt>
  mov    $0x0,%esi
  mov    $0xfe215050,%edi
  call   <outw@plt>
  mov    $0x1,%esi
  mov    $0xfe215044,%edi
  call   <outw@plt>
  mov    $0xc7,%esi
  mov    $0xfe215048,%edi
  call   <outw@plt>
  mov    $0x10e,%esi
  mov    $0xfe215068,%edi
  call   <outw@plt>
  mov    $0x2,%esi
  mov    $0xe,%edi
  call   <setgpiofunc@plt>
  mov    $0x2,%esi
  mov    $0xf,%edi
  call   <setgpiofunc@plt>
  mov    $0x0,%esi
  mov    $0xfe200094,%edi
  call   <outw@plt>
  mov    $0xa,%edi
  call   <delay@plt>
  mov    $0xc000,%esi
  mov    $0xfe200098,%edi
  call   <outw@plt>
  mov    $0xa,%edi
  call   <delay@plt>
  mov    $0x0,%esi
  mov    $0xfe200098,%edi
  call   <outw@plt>
  mov    $0x3,%esi
  mov    $0xfe215060,%edi
  call   <outw@plt>
  mov    $0x0,%eax
  call   <enableirqminiuart@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uartinit(void) {
  outw(0xFE215004, 1);
  outw(0xFE215060, 0);
  outw(0xFE21504C, 0x3);
  outw(0xFE215050, 0);
  outw(0xFE215044, 0x1);
  outw(0xFE215048, 0xC7);
  outw(0xFE215068, 270);
  setgpiofunc(14, 2);
  setgpiofunc(15, 2);
  outw(0xFE200094, 0);
  delay(10);
  outw(0xFE200098, (1 << 14) | (1 << 15));
  delay(10);
  outw(0xFE200098, 0);
  outw(0xFE215060, 3);
  enableirqminiuart();
}
```
user: What is the c source code of the assembly code below:

```asm
<uartinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xfe215004,%edi
  call   <outw@plt>
  xor    %esi,%esi
  mov    $0xfe215060,%edi
  call   <outw@plt>
  mov    $0x3,%esi
  mov    $0xfe21504c,%edi
  call   <outw@plt>
  xor    %esi,%esi
  mov    $0xfe215050,%edi
  call   <outw@plt>
  mov    $0x1,%esi
  mov    $0xfe215044,%edi
  call   <outw@plt>
  mov    $0xc7,%esi
  mov    $0xfe215048,%edi
  call   <outw@plt>
  mov    $0x10e,%esi
  mov    $0xfe215068,%edi
  call   <outw@plt>
  mov    $0x2,%esi
  mov    $0xe,%edi
  call   <setgpiofunc@plt>
  mov    $0x2,%esi
  mov    $0xf,%edi
  call   <setgpiofunc@plt>
  xor    %esi,%esi
  mov    $0xfe200094,%edi
  call   <outw@plt>
  mov    $0xa,%edi
  call   <delay@plt>
  mov    $0xc000,%esi
  mov    $0xfe200098,%edi
  call   <outw@plt>
  mov    $0xa,%edi
  call   <delay@plt>
  xor    %esi,%esi
  mov    $0xfe200098,%edi
  call   <outw@plt>
  mov    $0x3,%esi
  mov    $0xfe215060,%edi
  call   <outw@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <enableirqminiuart@plt>
```

assistant: ```c
void uartinit(void) {
  outw(0xFE215004, 1);
  outw(0xFE215060, 0);
  outw(0xFE21504C, 0x3);
  outw(0xFE215050, 0);
  outw(0xFE215044, 0x1);
  outw(0xFE215048, 0xC7);
  outw(0xFE215068, 270);
  setgpiofunc(14, 2);
  setgpiofunc(15, 2);
  outw(0xFE200094, 0);
  delay(10);
  outw(0xFE200098, (1 << 14) | (1 << 15));
  delay(10);
  outw(0xFE200098, 0);
  outw(0xFE215060, 3);
  enableirqminiuart();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uartinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xfe215004,%edi
  call   <outw@plt>
  xor    %esi,%esi
  mov    $0xfe215060,%edi
  call   <outw@plt>
  mov    $0x3,%esi
  mov    $0xfe21504c,%edi
  call   <outw@plt>
  xor    %esi,%esi
  mov    $0xfe215050,%edi
  call   <outw@plt>
  mov    $0x1,%esi
  mov    $0xfe215044,%edi
  call   <outw@plt>
  mov    $0xc7,%esi
  mov    $0xfe215048,%edi
  call   <outw@plt>
  mov    $0x10e,%esi
  mov    $0xfe215068,%edi
  call   <outw@plt>
  mov    $0x2,%esi
  mov    $0xe,%edi
  call   <setgpiofunc@plt>
  mov    $0x2,%esi
  mov    $0xf,%edi
  call   <setgpiofunc@plt>
  xor    %esi,%esi
  mov    $0xfe200094,%edi
  call   <outw@plt>
  mov    $0xa,%edi
  call   <delay@plt>
  mov    $0xc000,%esi
  mov    $0xfe200098,%edi
  call   <outw@plt>
  mov    $0xa,%edi
  call   <delay@plt>
  xor    %esi,%esi
  mov    $0xfe200098,%edi
  call   <outw@plt>
  mov    $0x3,%esi
  mov    $0xfe215060,%edi
  call   <outw@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <enableirqminiuart@plt>
```

assistant: ```c
void uartinit(void) {
  outw(0xFE215004, 1);
  outw(0xFE215060, 0);
  outw(0xFE21504C, 0x3);
  outw(0xFE215050, 0);
  outw(0xFE215044, 0x1);
  outw(0xFE215048, 0xC7);
  outw(0xFE215068, 270);
  setgpiofunc(14, 2);
  setgpiofunc(15, 2);
  outw(0xFE200094, 0);
  delay(10);
  outw(0xFE200098, (1 << 14) | (1 << 15));
  delay(10);
  outw(0xFE200098, 0);
  outw(0xFE215060, 3);
  enableirqminiuart();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pbnumbase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x24,-0x18(%rbp)
  jle    L24
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <m4errx@plt>
L24:
  cmpl   $0x1,-0x18(%rbp)
  jg     L42
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <m4errx@plt>
L42:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x8(%rbp)
L68:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  cltq
  lea    D3(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <pushback@plt>
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jg     L68
  cmpl   $0x0,-0x14(%rbp)
  jns    L61
  addl   $0x1,-0x4(%rbp)
  jmp    L61
L32:
  mov    $0x30,%edi
  call   <pushback@plt>
L61:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cmp    %eax,-0x1c(%rbp)
  jg     L32
  cmpl   $0x0,-0x14(%rbp)
  jns    L40
  mov    $0x2d,%edi
  call   <pushback@plt>
L40:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D29
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string

tool: D29: base %d > 36: not supported.

tool: D7: bad base %d for conversion.

assistant: ```c
void pbnumbase(int n, int base, int d) {
  static char digits[36] = "0123456789abcdefghijklmnopqrstuvwxyz";
  int num;
  int printed = 0;
  if (base > 36)
    m4errx(1, "base %d > 36: not supported.", base);
  if (base < 2)
    m4errx(1, "bad base %d for conversion.", base);
  num = (n < 0) ? -n : n;
  do {
    pushback(digits[num % base]);
    printed++;
  } while ((num /= base) > 0);
  if (n < 0)
    printed++;
  while (printed++ < d)
    pushback('0');
  if (n < 0)
    pushback('-');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pbnumbase>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %esi,%r12d
  mov    %edx,%r13d
  cmp    $0x24,%esi
  jg     L8
  cmp    $0x1,%esi
  jle    L103
L45:
  mov    %r15d,%eax
  neg    %eax
  cmovs  %r15d,%eax
  mov    $0x0,%ebx
  lea    D17(%rip),%r14
L86:
  cltd
  idiv   %r12d
  mov    %eax,%ebp
  movslq %edx,%rdx
  movsbl (%r14,%rdx,1),%edi
  call   <pushback@plt>
  mov    %ebx,%edx
  add    $0x1,%ebx
  mov    %ebp,%eax
  test   %ebp,%ebp
  jg     L86
  test   %r15d,%r15d
  js     L6
  lea    0x2(%rdx),%ebp
  cmp    %r13d,%ebx
  jge    L85
L22:
  mov    $0x30,%edi
  call   <pushback@plt>
  mov    %ebp,%eax
  add    $0x1,%ebp
  cmp    %eax,%r13d
  jg     L22
  test   %r15d,%r15d
  js     L53
L85:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    %esi,%edx
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <m4errx@plt>
  jmp    L45
L103:
  mov    %esi,%edx
  lea    D25(%rip),%rsi
  mov    $0x1,%edi
  call   <m4errx@plt>
  jmp    L45
L6:
  lea    0x3(%rdx),%ebp
  add    $0x2,%edx
  cmp    %r13d,%edx
  jl     L22
L53:
  mov    $0x2d,%edi
  call   <pushback@plt>
  jmp    L85
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D25
type: string

tool: D1: base %d > 36: not supported.

tool: D25: bad base %d for conversion.

assistant: ```c
void pbnumbase(int n, int base, int d) {
  static char digits[36] = "0123456789abcdefghijklmnopqrstuvwxyz";
  int num;
  int printed = 0;
  if (base > 36)
    m4errx(1, "base %d > 36: not supported.", base);
  if (base < 2)
    m4errx(1, "bad base %d for conversion.", base);
  num = (n < 0) ? -n : n;
  do {
    pushback(digits[num % base]);
    printed++;
  } while ((num /= base) > 0);
  if (n < 0)
    printed++;
  while (printed++ < d)
    pushback('0');
  if (n < 0)
    pushback('-');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pbnumbase>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x24,%esi
  jg     L54
  cmp    $0x1,%esi
  jle    L46
L60:
  mov    %r13d,%eax
  lea    D4(%rip),%r14
  neg    %eax
  cmovs  %r13d,%eax
  xor    %r15d,%r15d
  mov    %eax,%ebx
  nopl   (%rax)
L62:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  movslq %edx,%rdx
  mov    %eax,%ebx
  movsbl (%r14,%rdx,1),%edi
  call   <pushback@plt>
  mov    %r15d,%edx
  add    $0x1,%r15d
  test   %ebx,%ebx
  jg     L62
  lea    0x2(%rdx),%ebx
  test   %r13d,%r13d
  js     L106
  cmp    %r12d,%r15d
  jge    L15
  nopl   0x0(%rax)
L42:
  mov    $0x30,%edi
  call   <pushback@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%r12d
  jg     L42
  test   %r13d,%r13d
  js     L95
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %esi,%edx
  mov    $0x1,%edi
  lea    D14(%rip),%rsi
  call   <m4errx@plt>
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L106:
  add    $0x3,%edx
  cmp    %ebx,%r12d
  jle    L95
  mov    %edx,%ebx
  jmp    L42
  nopl   0x0(%rax)
L54:
  mov    %esi,%edx
  mov    $0x1,%edi
  lea    D13(%rip),%rsi
  call   <m4errx@plt>
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L95:
  add    $0x8,%rsp
  mov    $0x2d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <pushback@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D13
type: string

tool: D14: bad base %d for conversion.

tool: D13: base %d > 36: not supported.

assistant: ```c
void pbnumbase(int n, int base, int d) {
  static char digits[36] = "0123456789abcdefghijklmnopqrstuvwxyz";
  int num;
  int printed = 0;
  if (base > 36)
    m4errx(1, "base %d > 36: not supported.", base);
  if (base < 2)
    m4errx(1, "bad base %d for conversion.", base);
  num = (n < 0) ? -n : n;
  do {
    pushback(digits[num % base]);
    printed++;
  } while ((num /= base) > 0);
  if (n < 0)
    printed++;
  while (printed++ < d)
    pushback('0');
  if (n < 0)
    pushback('-');
}
```
user: Translate the below assembly code into C programming language:

```asm
<pbnumbase>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x24,%esi
  jg     L99
  cmp    $0x1,%esi
  jle    L67
L94:
  mov    %r13d,%eax
  lea    D15(%rip),%r14
  neg    %eax
  cmovs  %r13d,%eax
  xor    %r15d,%r15d
  mov    %eax,%ebx
  nopl   (%rax)
L14:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  movslq %edx,%rdx
  mov    %eax,%ebx
  movsbl (%r14,%rdx,1),%edi
  call   <pushback@plt>
  mov    %r15d,%edx
  add    $0x1,%r15d
  test   %ebx,%ebx
  jg     L14
  lea    0x2(%rdx),%ebx
  test   %r13d,%r13d
  js     L88
  cmp    %r12d,%r15d
  jge    L55
  nopl   0x0(%rax)
L63:
  mov    $0x30,%edi
  call   <pushback@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%r12d
  jg     L63
  test   %r13d,%r13d
  js     L72
L55:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  mov    %esi,%edx
  mov    $0x1,%edi
  lea    D24(%rip),%rsi
  call   <m4errx@plt>
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L88:
  add    $0x3,%edx
  cmp    %ebx,%r12d
  jle    L72
  mov    %edx,%ebx
  jmp    L63
  nopl   0x0(%rax)
L99:
  mov    %esi,%edx
  mov    $0x1,%edi
  lea    D6(%rip),%rsi
  call   <m4errx@plt>
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L72:
  add    $0x8,%rsp
  mov    $0x2d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <pushback@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D6
type: string

tool: D24: bad base %d for conversion.

tool: D6: base %d > 36: not supported.

assistant: ```c
void pbnumbase(int n, int base, int d) {
  static char digits[36] = "0123456789abcdefghijklmnopqrstuvwxyz";
  int num;
  int printed = 0;
  if (base > 36)
    m4errx(1, "base %d > 36: not supported.", base);
  if (base < 2)
    m4errx(1, "bad base %d for conversion.", base);
  num = (n < 0) ? -n : n;
  do {
    pushback(digits[num % base]);
    printed++;
  } while ((num /= base) > 0);
  if (n < 0)
    printed++;
  while (printed++ < d)
    pushback('0');
  if (n < 0)
    pushback('-');
}
```