ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rte_hash_crc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L52
L31:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    -0x20(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <rte_hash_crc_4byte@plt>
  mov    %eax,-0x20(%rbp)
  addl   $0x1,-0x10(%rbp)
L52:
  mov    -0x1c(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  cmp    %eax,-0x10(%rbp)
  jb     L31
  mov    -0x1c(%rbp),%eax
  not    %eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L16
  cmp    $0x2,%eax
  jg     L15
  test   %eax,%eax
  je     L45
  cmp    $0x1,%eax
  je     L56
  jmp    L15
L45:
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  or     %eax,-0xc(%rbp)
L56:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %eax,-0xc(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  or     %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <rte_hash_crc_4byte@plt>
  mov    %eax,-0x20(%rbp)
L15:
  nop
  mov    -0x20(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t rte_hash_crc(const void *data, uint32_t data_len, uint32_t init_val) {
  unsigned i;
  uint32_t temp = 0;
  const uint32_t *p32 = (const uint32_t *)data;
  for (i = 0; i < data_len / 4; i++) {
    init_val = rte_hash_crc_4byte(*p32++, init_val);
  }
  switch (3 - (data_len & 0x03)) {
  case 0:
    temp |= *((const uint8_t *)p32 + 2) << 16;
  case 1:
    temp |= *((const uint8_t *)p32 + 1) << 8;
  case 2:
    temp |= *((const uint8_t *)p32);
    init_val = rte_hash_crc_4byte(temp, init_val);
  default:
    break;
  }
  return init_val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rte_hash_crc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%esi
  lea    0x3(%rbp),%eax
  test   %ebp,%ebp
  cmovns %ebp,%eax
  sar    $0x2,%eax
  je     L36
  lea    -0x1(%rax),%eax
  lea    0x4(%rdi,%rax,4),%r12
L29:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%edi
  call   <rte_hash_crc_4byte@plt>
  mov    %eax,%esi
  cmp    %r12,%rbx
  jne    L29
L65:
  not    %ebp
  and    $0x3,%ebp
  cmp    $0x1,%ebp
  je     L52
  cmp    $0x2,%ebp
  je     L73
  test   %ebp,%ebp
  jne    L3
  mov    0x8(%r12),%eax
  shl    $0x10,%eax
L17:
  mov    0x4(%r12),%edi
  shl    $0x8,%edi
  or     %eax,%edi
L47:
  or     (%r12),%edi
  call   <rte_hash_crc_4byte@plt>
  mov    %eax,%esi
L3:
  mov    %esi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    %rdi,%r12
  jmp    L65
L52:
  mov    $0x0,%eax
  jmp    L17
L73:
  mov    $0x0,%edi
  jmp    L47
```

assistant: ```c
uint32_t rte_hash_crc(const void *data, uint32_t data_len, uint32_t init_val) {
  unsigned i;
  uint32_t temp = 0;
  const uint32_t *p32 = (const uint32_t *)data;
  for (i = 0; i < data_len / 4; i++) {
    init_val = rte_hash_crc_4byte(*p32++, init_val);
  }
  switch (3 - (data_len & 0x03)) {
  case 0:
    temp |= *((const uint8_t *)p32 + 2) << 16;
  case 1:
    temp |= *((const uint8_t *)p32 + 1) << 8;
  case 2:
    temp |= *((const uint8_t *)p32);
    init_val = rte_hash_crc_4byte(temp, init_val);
  default:
    break;
  }
  return init_val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rte_hash_crc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    %edx,%esi
  test   %ebp,%ebp
  lea    0x3(%rbp),%eax
  push   %rbx
  mov    %rdi,%rbx
  cmovns %ebp,%eax
  sar    $0x2,%eax
  je     L59
  mov    %eax,%eax
  lea    (%rdi,%rax,4),%r12
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <rte_hash_crc_4byte@plt>
  mov    %eax,%esi
  cmp    %r12,%rbx
  jne    L12
L14:
  not    %ebp
  and    $0x3,%ebp
  cmp    $0x1,%ebp
  je     L34
  cmp    $0x2,%ebp
  je     L4
  test   %ebp,%ebp
  je     L45
  pop    %rbx
  mov    %esi,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  or     (%r12),%edi
  pop    %r12
  jmp    1050 <rte_hash_crc_4byte@plt>
  nop
L34:
  xor    %eax,%eax
L65:
  mov    0x4(%r12),%edi
  pop    %rbx
  pop    %rbp
  shl    $0x8,%edi
  or     %eax,%edi
  or     (%r12),%edi
  pop    %r12
  jmp    1050 <rte_hash_crc_4byte@plt>
  nopl   0x0(%rax)
L45:
  mov    0x8(%r12),%eax
  shl    $0x10,%eax
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L59:
  mov    %rdi,%r12
  jmp    L14
```

assistant: ```c
uint32_t rte_hash_crc(const void *data, uint32_t data_len, uint32_t init_val) {
  unsigned i;
  uint32_t temp = 0;
  const uint32_t *p32 = (const uint32_t *)data;
  for (i = 0; i < data_len / 4; i++) {
    init_val = rte_hash_crc_4byte(*p32++, init_val);
  }
  switch (3 - (data_len & 0x03)) {
  case 0:
    temp |= *((const uint8_t *)p32 + 2) << 16;
  case 1:
    temp |= *((const uint8_t *)p32 + 1) << 8;
  case 2:
    temp |= *((const uint8_t *)p32);
    init_val = rte_hash_crc_4byte(temp, init_val);
  default:
    break;
  }
  return init_val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rte_hash_crc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    %edx,%esi
  test   %ebp,%ebp
  lea    0x3(%rbp),%eax
  push   %rbx
  mov    %rdi,%rbx
  cmovns %ebp,%eax
  sar    $0x2,%eax
  je     L68
  mov    %eax,%eax
  lea    (%rdi,%rax,4),%r12
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <rte_hash_crc_4byte@plt>
  mov    %eax,%esi
  cmp    %rbx,%r12
  jne    L7
L42:
  not    %ebp
  and    $0x3,%ebp
  cmp    $0x1,%ebp
  je     L66
  cmp    $0x2,%ebp
  je     L4
  test   %ebp,%ebp
  je     L21
  pop    %rbx
  mov    %esi,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  or     (%r12),%edi
  pop    %r12
  jmp    1050 <rte_hash_crc_4byte@plt>
  nop
L66:
  xor    %eax,%eax
L48:
  mov    0x4(%r12),%edi
  pop    %rbx
  pop    %rbp
  shl    $0x8,%edi
  or     %eax,%edi
  or     (%r12),%edi
  pop    %r12
  jmp    1050 <rte_hash_crc_4byte@plt>
  nopl   0x0(%rax)
L21:
  mov    0x8(%r12),%eax
  shl    $0x10,%eax
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L68:
  mov    %rdi,%r12
  jmp    L42
```

assistant: ```c
uint32_t rte_hash_crc(const void *data, uint32_t data_len, uint32_t init_val) {
  unsigned i;
  uint32_t temp = 0;
  const uint32_t *p32 = (const uint32_t *)data;
  for (i = 0; i < data_len / 4; i++) {
    init_val = rte_hash_crc_4byte(*p32++, init_val);
  }
  switch (3 - (data_len & 0x03)) {
  case 0:
    temp |= *((const uint8_t *)p32 + 2) << 16;
  case 1:
    temp |= *((const uint8_t *)p32 + 1) << 8;
  case 2:
    temp |= *((const uint8_t *)p32);
    init_val = rte_hash_crc_4byte(temp, init_val);
  default:
    break;
  }
  return init_val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L10
L14:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L10:
  cmpl   $0x0,-0x18(%rbp)
  jne    L14
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  while (b != 0) {
    int t = b;
    b = a % b;
    a = t;
  }
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L14
L23:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L23
L27:
  mov    %ecx,%eax
  ret
L14:
  mov    %edi,%ecx
  jmp    L27
```

assistant: ```c
int gcd(int a, int b) {
  while (b != 0) {
    int t = b;
    b = a % b;
    a = t;
  }
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L11
  nopl   0x0(%rax)
L17:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L17
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  while (b != 0) {
    int t = b;
    b = a % b;
    a = t;
  }
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L15
  nopl   0x0(%rax)
L13:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  while (b != 0) {
    int t = b;
    b = a % b;
    a = t;
  }
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<zengl_Sym_Hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L0:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x4da637d,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  imul   $0xd3,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int zengl_Sym_Hash(void *VM_ARG, char *key) {
  int temp = 0;
  int i = 0;
  while (key[i] != '\0') {
    temp = ((temp << 4) + key[i]) % 211;
    ++i;
  }
  return temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zengl_Sym_Hash>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L11
  add    $0x1,%rsi
  mov    $0x0,%eax
L1:
  shl    $0x4,%eax
  movsbl %dl,%edx
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x4da637d,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xd3,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%edx
  test   %dl,%dl
  jne    L1
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int zengl_Sym_Hash(void *VM_ARG, char *key) {
  int temp = 0;
  int i = 0;
  while (key[i] != '\0') {
    temp = ((temp << 4) + key[i]) % 211;
    ++i;
  }
  return temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zengl_Sym_Hash>:
  endbr64
  movsbl (%rsi),%edx
  test   %dl,%dl
  je     L9
  add    $0x1,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L19:
  shl    $0x4,%eax
  add    $0x1,%rsi
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x4da637d,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  imul   $0xd3,%eax,%ecx
  mov    %edx,%eax
  movsbl -0x1(%rsi),%edx
  sub    %ecx,%eax
  test   %dl,%dl
  jne    L19
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int zengl_Sym_Hash(void *VM_ARG, char *key) {
  int temp = 0;
  int i = 0;
  while (key[i] != '\0') {
    temp = ((temp << 4) + key[i]) % 211;
    ++i;
  }
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<zengl_Sym_Hash>:
  endbr64
  movsbl (%rsi),%edx
  test   %dl,%dl
  je     L10
  add    $0x1,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L5:
  shl    $0x4,%eax
  add    $0x1,%rsi
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x4da637d,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  imul   $0xd3,%eax,%ecx
  mov    %edx,%eax
  movsbl -0x1(%rsi),%edx
  sub    %ecx,%eax
  test   %dl,%dl
  jne    L5
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int zengl_Sym_Hash(void *VM_ARG, char *key) {
  int temp = 0;
  int i = 0;
  while (key[i] != '\0') {
    temp = ((temp << 4) + key[i]) % 211;
    ++i;
  }
  return temp;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <h@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: foo

assistant: ```c
int main(void) {
  h(0, "foo");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  mov    $0x0,%edi
  call   <h@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: foo

assistant: ```c
int main(void) {
  h(0, "foo");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  xor    %edi,%edi
  call   <h@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: foo

assistant: ```c
int main(void) {
  h(0, "foo");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  xor    %edi,%edi
  call   <h@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string

tool: D4: foo

assistant: ```c
int main(void) {
  h(0, "foo");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<load_data_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <file_load@plt>
  test   %rax,%rax
  je     L25
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L18
L25:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x38(%rbp),%edi
  mov    -0x34(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <load_data_from_buf@plt>
  mov    $0x0,%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: Error opening dataset file

assistant: ```c
extern int load_data_from_file(struct data_set_t *data, char *filename, int shortname, int verbose) {
  char *filebuf;
  size_t fsize;
  if (file_load(filename, &filebuf, &fsize)) {
    perror("Error opening dataset file");
    return -1;
  }
  load_data_from_buf(data, filebuf, fsize, shortname, verbose);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<load_data_from_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <file_load@plt>
  test   %rax,%rax
  jne    L26
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <load_data_from_buf@plt>
  mov    $0x0,%eax
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L14
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: Error opening dataset file

assistant: ```c
extern int load_data_from_file(struct data_set_t *data, char *filename, int shortname, int verbose) {
  char *filebuf;
  size_t fsize;
  if (file_load(filename, &filebuf, &fsize)) {
    perror("Error opening dataset file");
    return -1;
  }
  load_data_from_buf(data, filebuf, fsize, shortname, verbose);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<load_data_from_file>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <file_load@plt>
  test   %rax,%rax
  jne    L13
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  call   <load_data_from_buf@plt>
  xor    %eax,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L13:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L6
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: Error opening dataset file

assistant: ```c
extern int load_data_from_file(struct data_set_t *data, char *filename, int shortname, int verbose) {
  char *filebuf;
  size_t fsize;
  if (file_load(filename, &filebuf, &fsize)) {
    perror("Error opening dataset file");
    return -1;
  }
  load_data_from_buf(data, filebuf, fsize, shortname, verbose);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<load_data_from_file>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <file_load@plt>
  test   %rax,%rax
  jne    L12
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  call   <load_data_from_buf@plt>
  xor    %eax,%eax
L23:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L12:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L23
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: Error opening dataset file

assistant: ```c
extern int load_data_from_file(struct data_set_t *data, char *filename, int shortname, int verbose) {
  char *filebuf;
  size_t fsize;
  if (file_load(filename, &filebuf, &fsize)) {
    perror("Error opening dataset file");
    return -1;
  }
  load_data_from_buf(data, filebuf, fsize, shortname, verbose);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Operand_xt_wbr18_label_ator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_xt_wbr18_label_ator(unsigned int *valp, unsigned int pc) {
  *valp -= pc;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Operand_xt_wbr18_label_ator>:
  endbr64
  sub    %esi,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Operand_xt_wbr18_label_ator(unsigned int *valp, unsigned int pc) {
  *valp -= pc;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Operand_xt_wbr18_label_ator>:
  endbr64
  sub    %esi,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_xt_wbr18_label_ator(unsigned int *valp, unsigned int pc) {
  *valp -= pc;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Operand_xt_wbr18_label_ator>:
  endbr64
  sub    %esi,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_xt_wbr18_label_ator(unsigned int *valp, unsigned int pc) {
  *valp -= pc;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mini_uart_getc_noblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x201018,%edi
  call   <bcm2835_read@plt>
  and    $0x10,%eax
  test   %eax,%eax
  je     L8
  mov    $0xffffffff,%eax
  jmp    L9
L8:
  mov    $0x201000,%edi
  call   <bcm2835_read@plt>
  movzbl %al,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int32_t mini_uart_getc_noblock(void) {
  if (bcm2835_read((0 + 0x201000 + 0x18)) & (1 << 4)) {
    return -1;
  }
  return (bcm2835_read((0 + 0x201000 + 0x00))) & 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mini_uart_getc_noblock>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x201018,%edi
  call   <bcm2835_read@plt>
  test   $0x10,%al
  jne    L11
  mov    $0x201000,%edi
  call   <bcm2835_read@plt>
  movzbl %al,%eax
L1:
  add    $0x8,%rsp
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
int32_t mini_uart_getc_noblock(void) {
  if (bcm2835_read((0 + 0x201000 + 0x18)) & (1 << 4)) {
    return -1;
  }
  return (bcm2835_read((0 + 0x201000 + 0x00))) & 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mini_uart_getc_noblock>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x201018,%edi
  call   <bcm2835_read@plt>
  test   $0x10,%al
  jne    L16
  mov    $0x201000,%edi
  call   <bcm2835_read@plt>
  movzbl %al,%eax
L18:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int32_t mini_uart_getc_noblock(void) {
  if (bcm2835_read((0 + 0x201000 + 0x18)) & (1 << 4)) {
    return -1;
  }
  return (bcm2835_read((0 + 0x201000 + 0x00))) & 0xff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mini_uart_getc_noblock>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x201018,%edi
  call   <bcm2835_read@plt>
  test   $0x10,%al
  jne    L10
  mov    $0x201000,%edi
  call   <bcm2835_read@plt>
  movzbl %al,%eax
L16:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int32_t mini_uart_getc_noblock(void) {
  if (bcm2835_read((0 + 0x201000 + 0x18)) & (1 << 4)) {
    return -1;
  }
  return (bcm2835_read((0 + 0x201000 + 0x00))) & 0xff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L21
L18:
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <binsearch2@plt>
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L21:
  cmpl   $0x6,-0x24(%rbp)
  jle    L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: binsearch2 for %d is %d


assistant: ```c
int main() {
  int foo[5] = {1, 2, 3, 5, 6};
  int i;
  for (i = 1; i < 7; i++) {
    printf("binsearch2 for %d is %d\n", i, binsearch2(i, foo, 5));
  }
}
```