ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<SHA256_sodium_KAT_7>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x40000000,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movabs $0x6867666564636261,%rax
  movabs $0x6968676665646362,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x6a69686766656463,%rax
  movabs $0x6b6a696867666564,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movabs $0x6c6b6a6968676665,%rax
  movabs $0x6d6c6b6a69686766,%rdx
  mov    %rax,0x60(%rsp)
  mov    %rdx,0x68(%rsp)
  movabs $0x6e6d6c6b6a696867,%rax
  movabs $0x6f6e6d6c6b6a6968,%rdx
  mov    %rax,0x70(%rsp)
  mov    %rdx,0x78(%rsp)
  movb   $0x0,0x80(%rsp)
  mov    %r13,%rbx
  lea    0x40000000(%r13),%r12
  lea    0x40(%rsp),%rbp
L8:
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x40,%rbx
  cmp    %r12,%rbx
  jne    L8
  movabs $0xe22f44260e2ae750,%rax
  movabs $0x5886c58a93c32d55,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x87cad2b1bf0c8c22,%rax
  movabs $0x5e05cd6f2635e42a,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  mov    %rsp,%rbx
  mov    $0x40000000,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <SHA256_sodium@plt>
  lea    0x20(%rsp),%rsi
  lea    D4(%rip),%rcx
  mov    $0x20,%edx
  mov    %rbx,%rdi
  call   <check_KAT@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: SHA256_sodium_KAT_7

assistant: ```c
SHA256_sodium_KAT_7() {
  unsigned char *input = malloc(sizeof(char) * 1073741824);
  char to_repeat[] = "abcdefghbcdefghicdefghijdefghijkefghijklfghijklmghijklmnhijklmno";
  int i;
  for (i = 0; i < 16777216; i++) {
    memcpy(input + i * 64, to_repeat, 64);
  }
  unsigned char result[32];
  unsigned char expected_result[32] = {0x50, 0xe7, 0x2a, 0x0e, 0x26, 0x44, 0x2f, 0xe2, 0x55, 0x2d, 0xc3, 0x93, 0x8a, 0xc5, 0x86, 0x58, 0x22, 0x8c, 0x0c, 0xbf, 0xb1, 0xd2, 0xca, 0x87, 0x2a, 0xe4, 0x35, 0x26, 0x6f, 0xcd, 0x05, 0x5e};
  SHA256_sodium(input, result, 1073741824);
  check_KAT(result, expected_result, 32, "SHA256_sodium_KAT_7");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SHA256_sodium_KAT_7>:
  endbr64
  push   %r13
  mov    $0x40000000,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbp
  call   <malloc@plt>
  movdqa D35(%rip),%xmm0
  movb   $0x0,0x80(%rsp)
  mov    %rax,%r13
  mov    %rax,%rbx
  lea    0x40000000(%rax),%r12
  movaps %xmm0,0x40(%rsp)
  movdqa D34(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D30(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D16(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  nopl   0x0(%rax)
L14:
  mov    %rbx,%rdi
  mov    $0x40,%edx
  mov    %rbp,%rsi
  add    $0x40,%rbx
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L14
  movdqa D55(%rip),%xmm0
  mov    %rsp,%rbp
  mov    $0x40000000,%edx
  mov    %r13,%rdi
  mov    %rbp,%rsi
  movaps %xmm0,0x20(%rsp)
  movdqa D36(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <SHA256_sodium@plt>
  lea    0x20(%rsp),%rsi
  mov    $0x20,%edx
  mov    %rbp,%rdi
  lea    D21(%rip),%rcx
  call   <check_KAT@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D35
type: byte[16]
name: disassemble_data
arguments: data_label: D34
type: byte[16]
name: disassemble_data
arguments: data_label: D30
type: byte[16]
name: disassemble_data
arguments: data_label: D16
type: byte[16]
name: disassemble_data
arguments: data_label: D55
type: byte[16]
name: disassemble_data
arguments: data_label: D36
type: byte[16]
name: disassemble_data
arguments: data_label: D21
type: string

tool: {"D35": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69]}

tool: {"D34": [0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b]}

tool: {"D30": [0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d]}

tool: {"D16": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f]}

tool: {"D55": [0x50,0xe7,0x2a,0x0e,0x26,0x44,0x2f,0xe2,0x55,0x2d,0xc3,0x93,0x8a,0xc5,0x86,0x58]}

tool: {"D36": [0x22,0x8c,0x0c,0xbf,0xb1,0xd2,0xca,0x87,0x2a,0xe4,0x35,0x26,0x6f,0xcd,0x05,0x5e]}

tool: D21: SHA256_sodium_KAT_7

assistant: ```c
SHA256_sodium_KAT_7() {
  unsigned char *input = malloc(sizeof(char) * 1073741824);
  char to_repeat[] = "abcdefghbcdefghicdefghijdefghijkefghijklfghijklmghijklmnhijklmno";
  int i;
  for (i = 0; i < 16777216; i++) {
    memcpy(input + i * 64, to_repeat, 64);
  }
  unsigned char result[32];
  unsigned char expected_result[32] = {0x50, 0xe7, 0x2a, 0x0e, 0x26, 0x44, 0x2f, 0xe2, 0x55, 0x2d, 0xc3, 0x93, 0x8a, 0xc5, 0x86, 0x58, 0x22, 0x8c, 0x0c, 0xbf, 0xb1, 0xd2, 0xca, 0x87, 0x2a, 0xe4, 0x35, 0x26, 0x6f, 0xcd, 0x05, 0x5e};
  SHA256_sodium(input, result, 1073741824);
  check_KAT(result, expected_result, 32, "SHA256_sodium_KAT_7");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<SHA256_sodium_KAT_7>:
  endbr64
  push   %r13
  mov    $0x40000000,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbp
  call   <malloc@plt>
  movdqa D19(%rip),%xmm0
  movb   $0x0,0x80(%rsp)
  mov    %rax,%r13
  mov    %rax,%rbx
  lea    0x40000000(%rax),%r12
  movaps %xmm0,0x40(%rsp)
  movdqa D9(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D51(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  nopl   0x0(%rax)
L9:
  mov    %rbx,%rdi
  mov    $0x40,%edx
  mov    %rbp,%rsi
  add    $0x40,%rbx
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L9
  movdqa D68(%rip),%xmm0
  mov    %rsp,%rbp
  mov    $0x40000000,%edx
  mov    %r13,%rdi
  mov    %rbp,%rsi
  movaps %xmm0,0x20(%rsp)
  movdqa D44(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <SHA256_sodium@plt>
  lea    0x20(%rsp),%rsi
  mov    $0x20,%edx
  mov    %rbp,%rdi
  lea    D40(%rip),%rcx
  call   <check_KAT@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type: byte[16]
name: read_data
arguments: data_label: D9
type: byte[16]
name: read_data
arguments: data_label: D7
type: byte[16]
name: read_data
arguments: data_label: D51
type: byte[16]
name: read_data
arguments: data_label: D68
type: byte[16]
name: read_data
arguments: data_label: D44
type: byte[16]
name: read_data
arguments: data_label: D40
type: string

tool: {"D19": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69]}

tool: {"D9": [0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b]}

tool: {"D7": [0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d]}

tool: {"D51": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f]}

tool: {"D68": [0x50,0xe7,0x2a,0x0e,0x26,0x44,0x2f,0xe2,0x55,0x2d,0xc3,0x93,0x8a,0xc5,0x86,0x58]}

tool: {"D44": [0x22,0x8c,0x0c,0xbf,0xb1,0xd2,0xca,0x87,0x2a,0xe4,0x35,0x26,0x6f,0xcd,0x05,0x5e]}

tool: D40: SHA256_sodium_KAT_7

assistant: ```c
SHA256_sodium_KAT_7() {
  unsigned char *input = malloc(sizeof(char) * 1073741824);
  char to_repeat[] = "abcdefghbcdefghicdefghijdefghijkefghijklfghijklmghijklmnhijklmno";
  int i;
  for (i = 0; i < 16777216; i++) {
    memcpy(input + i * 64, to_repeat, 64);
  }
  unsigned char result[32];
  unsigned char expected_result[32] = {0x50, 0xe7, 0x2a, 0x0e, 0x26, 0x44, 0x2f, 0xe2, 0x55, 0x2d, 0xc3, 0x93, 0x8a, 0xc5, 0x86, 0x58, 0x22, 0x8c, 0x0c, 0xbf, 0xb1, 0xd2, 0xca, 0x87, 0x2a, 0xe4, 0x35, 0x26, 0x6f, 0xcd, 0x05, 0x5e};
  SHA256_sodium(input, result, 1073741824);
  check_KAT(result, expected_result, 32, "SHA256_sodium_KAT_7");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<math_cos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D14(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D17(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <lua_pushnumber@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
datatype: f64
name: parse_data
arguments: data_tag: D17
datatype: f64

tool: D14: 3.141592653589793

tool: D17: 180

assistant: ```c
void math_cos(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(cos(((d)*3.14159265358979323846 / 180.0)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<math_cos>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D1(%rip),%xmm0
  divsd  D7(%rip),%xmm0
  call   <cos@plt>
  mov    $0x1,%eax
  call   <lua_pushnumber@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: f64
name: read_data
arguments: data_label: D7
data_type: f64

tool: D1: 3.141592653589793

tool: D7: 180

assistant: ```c
void math_cos(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(cos(((d)*3.14159265358979323846 / 180.0)));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<math_cos>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D2(%rip),%xmm0
  divsd  D1(%rip),%xmm0
  call   <cos@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  jmp    1080 <lua_pushnumber@plt>
```

tool_calls: name: parse_data
arguments: label: D2
datatype: f64
name: parse_data
arguments: label: D1
datatype: f64

tool: D2: 3.141592653589793

tool: D1: 180

assistant: ```c
void math_cos(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(cos(((d)*3.14159265358979323846 / 180.0)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<math_cos>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D8(%rip),%xmm0
  divsd  D3(%rip),%xmm0
  call   <cos@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  jmp    1080 <lua_pushnumber@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: f64
name: parse_data
arguments: data_tag: D3
type_guessed: f64

tool: D8: 3.141592653589793

tool: D3: 180

assistant: ```c
void math_cos(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(cos(((d)*3.14159265358979323846 / 180.0)));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cov_serialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  fldt   0x10(%rbp)
  fstpt  -0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L4
L28:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x24(%rbp)
L4:
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L28
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void cov_serialize(long double f, unsigned char *buf, int length) {
  int i;
  union {
    unsigned char bytes[10];
    long double val;
  } bfconvert;
  bfconvert.val = f;
  for (i = 0; i < length; i++) {
    buf[i] = bfconvert.bytes[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cov_serialize>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  fldt   0x30(%rsp)
  fstpt  (%rsp)
  test   %esi,%esi
  jle    L3
  mov    %esi,%esi
L26:
  movzbl (%rsp,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L26
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cov_serialize(long double f, unsigned char *buf, int length) {
  int i;
  union {
    unsigned char bytes[10];
    long double val;
  } bfconvert;
  bfconvert.val = f;
  for (i = 0; i < length; i++) {
    buf[i] = bfconvert.bytes[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cov_serialize>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  fldt   0x30(%rsp)
  fstpt  (%rsp)
  test   %esi,%esi
  jle    L3
  movslq %esi,%rdx
  mov    %rsp,%rsi
  call   <memcpy@plt>
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cov_serialize(long double f, unsigned char *buf, int length) {
  int i;
  union {
    unsigned char bytes[10];
    long double val;
  } bfconvert;
  bfconvert.val = f;
  for (i = 0; i < length; i++) {
    buf[i] = bfconvert.bytes[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cov_serialize>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  fldt   0x30(%rsp)
  fstpt  (%rsp)
  test   %esi,%esi
  jle    L14
  movslq %esi,%rdx
  mov    %rsp,%rsi
  call   <memcpy@plt>
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cov_serialize(long double f, unsigned char *buf, int length) {
  int i;
  union {
    unsigned char bytes[10];
    long double val;
  } bfconvert;
  bfconvert.val = f;
  for (i = 0; i < length; i++) {
    buf[i] = bfconvert.bytes[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
L21:
  addl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L3
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    -0x1(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L3:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D8
datatype: string

tool: D7: %d

tool: D8: Teste %d
%.lf



assistant: ```c
int main() {
  int teste = 0, n = 0;
  while (1) {
    teste++;
    n = 0;
    scanf("%d", &n);
    if (n == 0)
      break;
    printf("Teste %d\n%.lf\n\n", teste, pow(2, n) - 1);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0x4(%rsp),%r12
  lea    D13(%rip),%rbp
  lea    D1(%rip),%r13
  jmp    L1
L6:
  mov    $0x2,%edi
  call   <pow@plt>
  lea    -0x1(%rax),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L1:
  add    $0x1,%ebx
  movl   $0x0,0x4(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jne    L6
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D1
datatype: string

tool: D13: %d

tool: D1: Teste %d
%.lf



assistant: ```c
int main() {
  int teste = 0, n = 0;
  while (1) {
    teste++;
    n = 0;
    scanf("%d", &n);
    if (n == 0)
      break;
    printf("Teste %d\n%.lf\n\n", teste, pow(2, n) - 1);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L29
  nopl   (%rax)
L20:
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  lea    -0x1(%rax),%rdx
  call   <printf@plt>
L29:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movl   $0x0,0x4(%rsp)
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jne    L20
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D9
type_infered: string

tool: D14: Teste %d
%.lf



tool: D9: %d

assistant: ```c
int main() {
  int teste = 0, n = 0;
  while (1) {
    teste++;
    n = 0;
    scanf("%d", &n);
    if (n == 0)
      break;
    printf("Teste %d\n%.lf\n\n", teste, pow(2, n) - 1);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L9
  nopl   (%rax)
L4:
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  lea    -0x1(%rax),%rdx
  call   <printf@plt>
L9:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movl   $0x0,0x4(%rsp)
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jne    L4
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D16: Teste %d
%.lf



tool: D0: %d

assistant: ```c
int main() {
  int teste = 0, n = 0;
  while (1) {
    teste++;
    n = 0;
    scanf("%d", &n);
    if (n == 0)
      break;
    printf("Teste %d\n%.lf\n\n", teste, pow(2, n) - 1);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L12
L26:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jg     L26
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D11
type_infered: string

tool: D16:  %d

tool: D11: %d


assistant: ```c
int main() {
  int N, i;
  scanf(" %d", &N);
  i = 1;
  while (N > 0) {
    i *= N;
    N--;
  }
  printf("%d\n", i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L24
  mov    $0x1,%esi
L12:
  imul   %eax,%esi
  sub    $0x1,%eax
  jne    L12
  movl   $0x0,0x4(%rsp)
L2:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L24:
  mov    $0x1,%esi
  jmp    L2
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D13:  %d

tool: D9: %d


assistant: ```c
int main() {
  int N, i;
  scanf(" %d", &N);
  i = 1;
  while (N > 0) {
    i *= N;
    N--;
  }
  printf("%d\n", i);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    $0x1,%esi
  test   %eax,%eax
  jle    L8
  cs nopw 0x0(%rax,%rax,1)
L27:
  imul   %eax,%esi
  sub    $0x1,%eax
  jne    L27
  movl   $0x0,0x4(%rsp)
L8:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string
name: extract_symbolic_data
arguments: label: D3
type: string

tool: D7:  %d

tool: D3: %d


assistant: ```c
int main() {
  int N, i;
  scanf(" %d", &N);
  i = 1;
  while (N > 0) {
    i *= N;
    N--;
  }
  printf("%d\n", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    $0x1,%esi
  test   %eax,%eax
  jle    L12
  cs nopw 0x0(%rax,%rax,1)
L5:
  imul   %eax,%esi
  sub    $0x1,%eax
  jne    L5
  movl   $0x0,0x4(%rsp)
L12:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string

tool: D10:  %d

tool: D8: %d


assistant: ```c
int main() {
  int N, i;
  scanf(" %d", &N);
  i = 1;
  while (N > 0) {
    i *= N;
    N--;
  }
  printf("%d\n", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<init_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int init_(void) {
  ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int init_(void) {
  ;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init_>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int init_(void) {
  ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int init_(void) {
  ;
  return 0;
}
```