ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<float_arr_init_2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L15:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <float_arr_init@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
float **float_arr_init_2d(int size_x, int size_y) {
  float **array = (float **)malloc(sizeof(float *) * size_x);
  int i;
  for (i = 0; i < size_x; i++) {
    array[i] = float_arr_init(size_y);
  }
  return array;
}
```
user: Translate the below assembly code into C programming language:

```asm
<float_arr_init_2d>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L15
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r12
L8:
  mov    %ebp,%edi
  call   <float_arr_init@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L8
L15:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **float_arr_init_2d(int size_x, int size_y) {
  float **array = (float **)malloc(sizeof(float *) * size_x);
  int i;
  for (i = 0; i < size_x; i++) {
    array[i] = float_arr_init(size_y);
  }
  return array;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<float_arr_init_2d>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L7
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nop
L17:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <float_arr_init@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L17
L7:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **float_arr_init_2d(int size_x, int size_y) {
  float **array = (float **)malloc(sizeof(float *) * size_x);
  int i;
  for (i = 0; i < size_x; i++) {
    array[i] = float_arr_init(size_y);
  }
  return array;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<float_arr_init_2d>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L11
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nop
L19:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <float_arr_init@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L19
L11:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **float_arr_init_2d(int size_x, int size_y) {
  float **array = (float **)malloc(sizeof(float *) * size_x);
  int i;
  for (i = 0; i < size_x; i++) {
    array[i] = float_arr_init(size_y);
  }
  return array;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__link@plt>
  test   %rax,%rax
  jns    L6
  mov    D32(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L21
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  js     L18
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__link@plt>
  test   %rax,%rax
  jns    L6
L18:
  mov    $0xffffffff,%eax
  jmp    L19
L21:
  mov    $0xffffffff,%eax
  jmp    L19
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  jns    L81
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  jne    L83
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
L83:
  mov    $0xffffffff,%eax
  jmp    L19
L81:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int rename(const char *old, const char *new) {
  int save = errno;
  if (__link(old, new) < 0) {
    if (errno == EEXIST) {
      __set_errno(save);
      if (__unlink(new) < 0 || __link(old, new) < 0)
        return -1;
    } else
      return -1;
  }
  if (__unlink(old) < 0) {
    save = errno;
    if (__unlink(new) == 0)
      __set_errno(save);
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rename>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    D0(%rip),%rax
  mov    (%rax),%r12d
  call   <__link@plt>
  test   %rax,%rax
  jns    L51
  mov    D0(%rip),%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  jne    L63
  mov    %r12d,%edi
  call   <__set_errno@plt>
  mov    %rbp,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  js     L0
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__link@plt>
  test   %rax,%rax
  js     L78
L51:
  mov    %rbx,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  js     L94
  mov    $0x0,%eax
L95:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L94:
  mov    D0(%rip),%rax
  mov    (%rax),%ebx
  mov    %rbp,%rdi
  call   <__unlink@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  jne    L95
  mov    %ebx,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L95
L63:
  mov    $0xffffffff,%eax
  jmp    L95
L0:
  mov    $0xffffffff,%eax
  jmp    L95
L78:
  mov    $0xffffffff,%eax
  jmp    L95
```

assistant: ```c
int rename(const char *old, const char *new) {
  int save = errno;
  if (__link(old, new) < 0) {
    if (errno == EEXIST) {
      __set_errno(save);
      if (__unlink(new) < 0 || __link(old, new) < 0)
        return -1;
    } else
      return -1;
  }
  if (__unlink(old) < 0) {
    save = errno;
    if (__unlink(new) == 0)
      __set_errno(save);
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rename>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D19(%rip),%rbx
  mov    (%rbx),%r13d
  call   <__link@plt>
  test   %rax,%rax
  jns    L48
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rbx)
  jne    L57
  mov    %r13d,%edi
  call   <__set_errno@plt>
  mov    %r12,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  js     L57
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__link@plt>
  test   %rax,%rax
  js     L57
L48:
  mov    %rbp,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  js     L28
  xor    %eax,%eax
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    %r12,%rdi
  mov    (%rbx),%ebp
  call   <__unlink@plt>
  test   %rax,%rax
  jne    L57
  mov    %ebp,%edi
  call   <__set_errno@plt>
  nopw   0x0(%rax,%rax,1)
L57:
  mov    $0xffffffff,%eax
  jmp    L39
```

assistant: ```c
int rename(const char *old, const char *new) {
  int save = errno;
  if (__link(old, new) < 0) {
    if (errno == EEXIST) {
      __set_errno(save);
      if (__unlink(new) < 0 || __link(old, new) < 0)
        return -1;
    } else
      return -1;
  }
  if (__unlink(old) < 0) {
    save = errno;
    if (__unlink(new) == 0)
      __set_errno(save);
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rename>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbx
  mov    (%rbx),%r13d
  call   <__link@plt>
  test   %rax,%rax
  jns    L7
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rbx)
  jne    L28
  mov    %r13d,%edi
  call   <__set_errno@plt>
  mov    %r12,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  js     L28
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__link@plt>
  test   %rax,%rax
  js     L28
L7:
  mov    %rbp,%rdi
  call   <__unlink@plt>
  test   %rax,%rax
  js     L31
  xor    %eax,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  mov    %r12,%rdi
  mov    (%rbx),%ebp
  call   <__unlink@plt>
  test   %rax,%rax
  jne    L28
  mov    %ebp,%edi
  call   <__set_errno@plt>
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0xffffffff,%eax
  jmp    L17
```

assistant: ```c
int rename(const char *old, const char *new) {
  int save = errno;
  if (__link(old, new) < 0) {
    if (errno == EEXIST) {
      __set_errno(save);
      if (__unlink(new) < 0 || __link(old, new) < 0)
        return -1;
    } else
      return -1;
  }
  if (__unlink(old) < 0) {
    save = errno;
    if (__unlink(new) == 0)
      __set_errno(save);
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<isArraySorted>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L37
  mov    $0x0,%eax
  jmp    L35
L37:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L28
  mov    $0x1,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int isArraySorted(int *array, int length) {
  int i = 0;
  for (i = 0; i < length - 1; i++) {
    if (array[i] > array[i + 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<isArraySorted>:
  endbr64
  cmp    $0x1,%esi
  jle    L8
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L15:
  mov    0x4(%rax),%ecx
  cmp    %ecx,(%rax)
  jg     L10
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L15
  mov    $0x1,%eax
  ret
L8:
  mov    $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isArraySorted(int *array, int length) {
  int i = 0;
  for (i = 0; i < length - 1; i++) {
    if (array[i] > array[i + 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<isArraySorted>:
  endbr64
  cmp    $0x1,%esi
  jle    L17
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L17
L38:
  mov    0x4(%rdi),%edx
  cmp    %edx,(%rdi)
  jle    L2
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isArraySorted(int *array, int length) {
  int i = 0;
  for (i = 0; i < length - 1; i++) {
    if (array[i] > array[i + 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isArraySorted>:
  endbr64
  cmp    $0x1,%esi
  jle    L13
  lea    -0x2(%rsi),%ecx
  mov    (%rdi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rcx,4),%rsi
  jmp    L12
  nopl   0x0(%rax)
L10:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L13
L12:
  mov    %edx,%ecx
  mov    (%rax),%edx
  cmp    %ecx,%edx
  jge    L10
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isArraySorted(int *array, int length) {
  int i = 0;
  for (i = 0; i < length - 1; i++) {
    if (array[i] > array[i + 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<AddrTools_parseMac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x20(%rbp)
  jmp    L32
L13:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  je     L44
  mov    $0xffffffff,%eax
  jmp    L63
L44:
  addl   $0x3,-0x20(%rbp)
L32:
  cmpl   $0xe,-0x20(%rbp)
  jle    L13
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L3
L57:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x14(%rbp,%rax,1)
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x14(%rbp,%rax,1)
  addl   $0x1,-0x18(%rbp)
L3:
  cmpl   $0x11,-0x18(%rbp)
  jle    L57
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0xc,%ecx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <Hex_decode@plt>
  cmp    $0x6,%eax
  je     L61
  mov    $0xffffffff,%eax
  jmp    L63
L61:
  mov    $0x0,%eax
L63:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
int AddrTools_parseMac(uint8_t out[6], const uint8_t hexAddr[17]) {
  for (int i = 2; i < 15; i += 3) {
    if (hexAddr[i] != ':') {
      return -1;
    }
  }
  uint8_t hex[12];
  int j = 0;
  for (int i = 0; i < 18; i++) {
    hex[j++] = hexAddr[i++];
    hex[j++] = hexAddr[i++];
  }
  if (Hex_decode(out, 6, hex, 12) != 6) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<AddrTools_parseMac>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsi),%rax
  mov    %rsi,%rdx
  add    $0x11,%rsi
L4:
  cmpb   $0x3a,(%rax)
  jne    L32
  add    $0x3,%rax
  cmp    %rsi,%rax
  jne    L4
  lea    0xc(%rsp),%rax
  lea    0x18(%rsp),%rsi
L40:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  movzbl 0x1(%rdx),%ecx
  mov    %cl,0x1(%rax)
  add    $0x3,%rdx
  add    $0x2,%rax
  cmp    %rsi,%rax
  jne    L40
  lea    0xc(%rsp),%rdx
  mov    $0xc,%ecx
  mov    $0x6,%esi
  call   <Hex_decode@plt>
  cmp    $0x6,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
L41:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  ret
L32:
  mov    $0xffffffff,%eax
  jmp    L41
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int AddrTools_parseMac(uint8_t out[6], const uint8_t hexAddr[17]) {
  for (int i = 2; i < 15; i += 3) {
    if (hexAddr[i] != ':') {
      return -1;
    }
  }
  uint8_t hex[12];
  int j = 0;
  for (int i = 0; i < 18; i++) {
    hex[j++] = hexAddr[i++];
    hex[j++] = hexAddr[i++];
  }
  if (Hex_decode(out, 6, hex, 12) != 6) {
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<AddrTools_parseMac>:
  endbr64
  sub    $0x28,%rsp
  lea    0x11(%rsi),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsi),%rax
L6:
  cmpb   $0x3a,(%rax)
  jne    L17
  add    $0x3,%rax
  cmp    %rdx,%rax
  jne    L6
  lea    0xc(%rsp),%rdx
  lea    0x18(%rsp),%rcx
  mov    %rdx,%rax
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl (%rsi),%r8d
  add    $0x2,%rax
  add    $0x3,%rsi
  mov    %r8b,-0x2(%rax)
  movzbl -0x2(%rsi),%r8d
  mov    %r8b,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L11
  mov    $0xc,%ecx
  mov    $0x6,%esi
  call   <Hex_decode@plt>
  cmp    $0x6,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
L49:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x28,%rsp
  ret
  nopl   (%rax)
L17:
  mov    $0xffffffff,%eax
  jmp    L49
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int AddrTools_parseMac(uint8_t out[6], const uint8_t hexAddr[17]) {
  for (int i = 2; i < 15; i += 3) {
    if (hexAddr[i] != ':') {
      return -1;
    }
  }
  uint8_t hex[12];
  int j = 0;
  for (int i = 0; i < 18; i++) {
    hex[j++] = hexAddr[i++];
    hex[j++] = hexAddr[i++];
  }
  if (Hex_decode(out, 6, hex, 12) != 6) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<AddrTools_parseMac>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0x3a,0x2(%rsi)
  jne    L4
  cmpb   $0x3a,0x5(%rsi)
  jne    L4
  cmpb   $0x3a,0x8(%rsi)
  jne    L4
  cmpb   $0x3a,0xb(%rsi)
  jne    L4
  cmpb   $0x3a,0xe(%rsi)
  jne    L4
  movzbl 0xa(%rsi),%eax
  movzbl 0x9(%rsi),%ecx
  lea    0x8(%rsp),%rdx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x7(%rsi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x6(%rsi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x4(%rsi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x3(%rsi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x1(%rsi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl (%rsi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  mov    $0xc,%ecx
  mov    %rax,0x8(%rsp)
  movzwl 0xc(%rsi),%eax
  mov    %ax,0x10(%rsp)
  movzwl 0xf(%rsi),%eax
  mov    $0x6,%esi
  mov    %ax,0x12(%rsp)
  call   <Hex_decode@plt>
  cmp    $0x6,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L53
  add    $0x28,%rsp
  ret
  nopl   (%rax)
L4:
  mov    $0xffffffff,%eax
  jmp    L16
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int AddrTools_parseMac(uint8_t out[6], const uint8_t hexAddr[17]) {
  for (int i = 2; i < 15; i += 3) {
    if (hexAddr[i] != ':') {
      return -1;
    }
  }
  uint8_t hex[12];
  int j = 0;
  for (int i = 0; i < 18; i++) {
    hex[j++] = hexAddr[i++];
    hex[j++] = hexAddr[i++];
  }
  if (Hex_decode(out, 6, hex, 12) != 6) {
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utils_reverse_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L46:
  cmp    %rdx,%rsp
  je     L54
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L46
L54:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L3
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L3:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L47
L4:
  mov    -0x3c(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  lea    -0x2(%rax),%esi
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rdx
  movslq %esi,%rax
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rcx)
  mov    -0x3c(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rdx
  movslq %esi,%rax
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rcx)
  addl   $0x2,-0x2c(%rbp)
L47:
  mov    -0x2c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L4
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void utils_reverse_hex(char *h, int len) {
  char copy[len];
  strncpy(copy, h, len);
  int i;
  for (i = 0; i < len; i += 2) {
    h[i] = copy[len - i - 2];
    h[i + 1] = copy[len - i - 1];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<utils_reverse_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%r13
  lea    0xf(%r13),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L36:
  cmp    %rdx,%rsp
  je     L5
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L5:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L11
  orq    $0x0,-0x8(%rsp,%rax,1)
L11:
  mov    %rsp,%r14
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <strncpy@plt>
  test   %ebx,%ebx
  jle    L7
  mov    %r12,%rax
  lea    -0x1(%r14,%r13,1),%rdx
  sub    $0x1,%ebx
  shr    %ebx
  mov    %ebx,%ebx
  lea    0x2(%r12,%rbx,2),%rsi
L20:
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rax)
  movzbl (%rdx),%ecx
  mov    %cl,0x1(%rax)
  add    $0x2,%rax
  sub    $0x2,%rdx
  cmp    %rsi,%rax
  jne    L20
L7:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void utils_reverse_hex(char *h, int len) {
  char copy[len];
  strncpy(copy, h, len);
  int i;
  for (i = 0; i < len; i += 2) {
    h[i] = copy[len - i - 2];
    h[i + 1] = copy[len - i - 1];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<utils_reverse_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  movslq %esi,%r13
  push   %r12
  mov    %r13,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%r13),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L54
L46:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L46
L54:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L19
L34:
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <strncpy@plt>
  test   %r12d,%r12d
  jle    L8
  sub    $0x1,%r12d
  mov    %rbx,%rdi
  lea    -0x1(%rsp,%r13,1),%rax
  shr    %r12d
  lea    0x2(%rbx,%r12,2),%rcx
  nop
L0:
  movzbl -0x1(%rax),%edx
  add    $0x2,%rdi
  sub    $0x2,%rax
  mov    %dl,-0x2(%rdi)
  movzbl 0x2(%rax),%edx
  mov    %dl,-0x1(%rdi)
  cmp    %rcx,%rdi
  jne    L0
L8:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L19:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L34
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void utils_reverse_hex(char *h, int len) {
  char copy[len];
  strncpy(copy, h, len);
  int i;
  for (i = 0; i < len; i += 2) {
    h[i] = copy[len - i - 2];
    h[i + 1] = copy[len - i - 1];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tx_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    D9(%rip),%rax
  movl   $0xffffffff,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int tx_close(void) {
  extern _tx_server;
  close(_tx_server);
  _tx_server = -1;
  return 0;
}
```