ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<aeron_number_of_leading_zeroes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0x20,%eax
  jmp    L14
L16:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_clz@plt>
L14:
  leave
  ret
```

assistant: ```c
int aeron_number_of_leading_zeroes(int32_t value) {
  if (0 == value) {
    return 32;
  }
  return __builtin_clz(value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<aeron_number_of_leading_zeroes>:
  endbr64
  mov    $0x20,%eax
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  call   <__builtin_clz@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
int aeron_number_of_leading_zeroes(int32_t value) {
  if (0 == value) {
    return 32;
  }
  return __builtin_clz(value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<aeron_number_of_leading_zeroes>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <__builtin_clz@plt>
  xchg   %ax,%ax
L3:
  mov    $0x20,%eax
  ret
```

assistant: ```c
int aeron_number_of_leading_zeroes(int32_t value) {
  if (0 == value) {
    return 32;
  }
  return __builtin_clz(value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aeron_number_of_leading_zeroes>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <__builtin_clz@plt>
  xchg   %ax,%ax
L7:
  mov    $0x20,%eax
  ret
```

assistant: ```c
int aeron_number_of_leading_zeroes(int32_t value) {
  if (0 == value) {
    return 32;
  }
  return __builtin_clz(value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<FnCompare_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L13
  mov    $0xffffffff,%eax
  jmp    L19
L13:
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  comiss %xmm1,%xmm0
  jbe    L33
  mov    $0x1,%eax
  jmp    L19
L33:
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int FnCompare_float(const void *v1, const void *v2) {
  const float *i1 = v1;
  const float *i2 = v2;
  if (*i1 < *i2)
    return (-1);
  else if (*i1 > *i2)
    return (1);
  else
    return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<FnCompare_float>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L3
  comiss %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
L3:
  ret
```

assistant: ```c
int FnCompare_float(const void *v1, const void *v2) {
  const float *i1 = v1;
  const float *i2 = v2;
  if (*i1 < *i2)
    return (-1);
  else if (*i1 > *i2)
    return (1);
  else
    return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FnCompare_float>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L1
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
L1:
  ret
```

assistant: ```c
int FnCompare_float(const void *v1, const void *v2) {
  const float *i1 = v1;
  const float *i2 = v2;
  if (*i1 < *i2)
    return (-1);
  else if (*i1 > *i2)
    return (1);
  else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FnCompare_float>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L6
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
L6:
  ret
```

assistant: ```c
int FnCompare_float(const void *v1, const void *v2) {
  const float *i1 = v1;
  const float *i2 = v2;
  if (*i1 < *i2)
    return (-1);
  else if (*i1 > *i2)
    return (1);
  else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<math_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <luaL_check_number@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    %eax,%edi
  call   <lua_pushnumber@plt>
  nop
  leave
  ret
```

assistant: ```c
void math_log(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(log(d));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<math_log>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <luaL_check_number@plt>
  call   <log@plt>
  mov    %eax,%edi
  call   <lua_pushnumber@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void math_log(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(log(d));
}
```
user: Translate the below assembly code into C programming language:

```asm
<math_log>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <luaL_check_number@plt>
  call   <log@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <lua_pushnumber@plt>
```

assistant: ```c
void math_log(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(log(d));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<math_log>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <luaL_check_number@plt>
  call   <log@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <lua_pushnumber@plt>
```

assistant: ```c
void math_log(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(log(d));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0: get package dependencies
Usage: depends [OPTION] [PACKAGE]
   -h              this usage message
   -d[path]        path to database file


assistant: ```c
void help() {
  puts("get package dependencies\n"
       "Usage: depends [OPTION] [PACKAGE]\n"
       "   -h              this usage message\n"
       "   -d[path]        path to database file\n");
  exit(-1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: get package dependencies
Usage: depends [OPTION] [PACKAGE]
   -h              this usage message
   -d[path]        path to database file


assistant: ```c
void help() {
  puts("get package dependencies\n"
       "Usage: depends [OPTION] [PACKAGE]\n"
       "   -h              this usage message\n"
       "   -d[path]        path to database file\n");
  exit(-1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: get package dependencies
Usage: depends [OPTION] [PACKAGE]
   -h              this usage message
   -d[path]        path to database file


assistant: ```c
void help() {
  puts("get package dependencies\n"
       "Usage: depends [OPTION] [PACKAGE]\n"
       "   -h              this usage message\n"
       "   -d[path]        path to database file\n");
  exit(-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: get package dependencies
Usage: depends [OPTION] [PACKAGE]
   -h              this usage message
   -d[path]        path to database file


assistant: ```c
void help() {
  puts("get package dependencies\n"
       "Usage: depends [OPTION] [PACKAGE]\n"
       "   -h              this usage message\n"
       "   -d[path]        path to database file\n");
  exit(-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy_rest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L53:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L53
  sub    $0x30,%rsp
  mov    %edi,-0x4024(%rbp)
  mov    %esi,-0x4028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L59
L52:
  mov    -0x4014(%rbp),%edx
  lea    -0x4010(%rbp),%rcx
  mov    -0x4028(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  cmp    %eax,-0x4014(%rbp)
  jne    L69
L59:
  lea    -0x4010(%rbp),%rcx
  mov    -0x4024(%rbp),%eax
  mov    $0x4000,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,-0x4014(%rbp)
  cmpl   $0x0,-0x4014(%rbp)
  jg     L52
  jmp    L19
L69:
  nop
L19:
  cmpl   $0x0,-0x4014(%rbp)
  je     L65
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L65:
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: Unable to copy the rest of the file

assistant: ```c
copy_rest(old, new) int new, old;
{
  int buffer[4096];
  int len;
  while ((len = read(old, buffer, sizeof(buffer))) > 0)
    if (write(new, buffer, len) != len)
      break;
  if (len != 0) {
    perror("Unable to copy the rest of the file");
    exit(1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_rest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L47:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L47
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
L36:
  mov    $0x4000,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L42
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    $0x0,%eax
  call   <write@plt>
  cmp    %ebx,%eax
  je     L36
L27:
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L42:
  jne    L27
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x4018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string

tool: D0: Unable to copy the rest of the file

assistant: ```c
copy_rest(old, new) int new, old;
{
  int buffer[4096];
  int len;
  while ((len = read(old, buffer, sizeof(buffer))) > 0)
    if (write(new, buffer, len) != len)
      break;
  if (len != 0) {
    perror("Unable to copy the rest of the file");
    exit(1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_rest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %rsp,%rbp
  jmp    L55
  nopl   (%rax)
L10:
  xor    %eax,%eax
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %ebx,%eax
  jne    L36
L55:
  mov    $0x4000,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L10
  jne    L36
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x4018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: Unable to copy the rest of the file

assistant: ```c
copy_rest(old, new) int new, old;
{
  int buffer[4096];
  int len;
  while ((len = read(old, buffer, sizeof(buffer))) > 0)
    if (write(new, buffer, len) != len)
      break;
  if (len != 0) {
    perror("Unable to copy the rest of the file");
    exit(1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_rest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L17:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L17
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %rsp,%rbp
  jmp    L48
  nopl   (%rax)
L29:
  xor    %eax,%eax
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %ebx,%eax
  jne    L6
L48:
  mov    $0x4000,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L29
  jne    L6
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x4018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: Unable to copy the rest of the file

assistant: ```c
copy_rest(old, new) int new, old;
{
  int buffer[4096];
  int len;
  while ((len = read(old, buffer, sizeof(buffer))) > 0)
    if (write(new, buffer, len) != len)
      break;
  if (len != 0) {
    perror("Unable to copy the rest of the file");
    exit(1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cel_next_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L19
  addl   $0x1,-0x4(%rbp)
  jmp    L19
L5:
  addl   $0x2,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <cel_is_prime@plt>
  test   %eax,%eax
  je     L5
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
extern int cel_next_prime(int n) {
  if (n % 2 == 0)
    n++;
  for (; !cel_is_prime(n); n = n + 2)
    ;
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cel_next_prime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0x0,%ebx
  jmp    L15
L6:
  add    $0x2,%ebx
L15:
  mov    %ebx,%edi
  call   <cel_is_prime@plt>
  test   %eax,%eax
  je     L6
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
extern int cel_next_prime(int n) {
  if (n % 2 == 0)
    n++;
  for (; !cel_is_prime(n); n = n + 2)
    ;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cel_next_prime>:
  endbr64
  mov    %edi,%eax
  push   %r12
  mov    %edi,%r12d
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0x0,%r12d
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x2,%r12d
L10:
  mov    %r12d,%edi
  call   <cel_is_prime@plt>
  test   %eax,%eax
  je     L7
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
extern int cel_next_prime(int n) {
  if (n % 2 == 0)
    n++;
  for (; !cel_is_prime(n); n = n + 2)
    ;
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cel_next_prime>:
  endbr64
  mov    %edi,%eax
  push   %r12
  mov    %edi,%r12d
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0x0,%r12d
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x2,%r12d
L10:
  mov    %r12d,%edi
  call   <cel_is_prime@plt>
  test   %eax,%eax
  je     L4
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
extern int cel_next_prime(int n) {
  if (n % 2 == 0)
    n++;
  for (; !cel_is_prime(n); n = n + 2)
    ;
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yas_cdrv_term>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <device_close@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int yas_cdrv_term(void) {
  device_close();
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<yas_cdrv_term>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <device_close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yas_cdrv_term(void) {
  device_close();
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yas_cdrv_term>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <device_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yas_cdrv_term(void) {
  device_close();
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<yas_cdrv_term>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <device_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yas_cdrv_term(void) {
  device_close();
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<endFrame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void endFrame() {
  if (1) {
    spiSendReceive(0xff);
    spiSendReceive(0xff);
    spiSendReceive(0xff);
    spiSendReceive(0xff);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<endFrame>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void endFrame() {
  if (1) {
    spiSendReceive(0xff);
    spiSendReceive(0xff);
    spiSendReceive(0xff);
    spiSendReceive(0xff);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<endFrame>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  add    $0x8,%rsp
  jmp    1050 <spiSendReceive@plt>
```

assistant: ```c
void endFrame() {
  if (1) {
    spiSendReceive(0xff);
    spiSendReceive(0xff);
    spiSendReceive(0xff);
    spiSendReceive(0xff);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<endFrame>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  call   <spiSendReceive@plt>
  mov    $0xff,%edi
  add    $0x8,%rsp
  jmp    1050 <spiSendReceive@plt>
```

assistant: ```c
void endFrame() {
  if (1) {
    spiSendReceive(0xff);
    spiSendReceive(0xff);
    spiSendReceive(0xff);
    spiSendReceive(0xff);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L46
L8:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L56
  movl   $0x1,-0x4(%rbp)
  jmp    L41
L56:
  addl   $0x1,-0x8(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jle    L8
L41:
  cmpl   $0x0,-0x4(%rbp)
  jne    L43
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L43:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string

tool: D9: 1

tool: D17: 0

assistant: ```c
int is_prime(int a) {
  int i, flag = 0;
  for (i = 2; i <= a / 2; ++i) {
    if (a % i == 0) {
      flag = 1;
      break;
    }
  }
  if (flag == 0)
    printf("1");
  else
    printf("0");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_prime>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L35
  test   $0x1,%dil
  je     L27
  mov    $0x2,%ecx
L36:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L35
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L36
L27:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L35:
  lea    D6(%rip),%rdi
  call   <printf@plt>
L13:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D19: 0

tool: D6: 1

assistant: ```c
int is_prime(int a) {
  int i, flag = 0;
  for (i = 2; i <= a / 2; ++i) {
    if (a % i == 0) {
      flag = 1;
      break;
    }
  }
  if (flag == 0)
    printf("1");
  else
    printf("0");
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_prime>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L9
  test   $0x1,%dil
  je     L22
  mov    $0x2,%ecx
  jmp    L23
  nop
L15:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L22
L23:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jle    L15
L9:
  lea    D17(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L22:
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D17
data_type: string
name: read_data
arguments: tag: D2
data_type: string

tool: D17: 1

tool: D2: 0

assistant: ```c
int is_prime(int a) {
  int i, flag = 0;
  for (i = 2; i <= a / 2; ++i) {
    if (a % i == 0) {
      flag = 1;
      break;
    }
  }
  if (flag == 0)
    printf("1");
  else
    printf("0");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_prime>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L25
  test   $0x1,%dil
  je     L0
  mov    $0x2,%ecx
  jmp    L7
  nop
L47:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L0
L7:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jle    L47
L25:
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L0:
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string
name: parse_data
arguments: tag: D3
data_type: string

tool: D2: 1

tool: D3: 0

assistant: ```c
int is_prime(int a) {
  int i, flag = 0;
  for (i = 2; i <= a / 2; ++i) {
    if (a % i == 0) {
      flag = 1;
      break;
    }
  }
  if (flag == 0)
    printf("1");
  else
    printf("0");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getBoolean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L25
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L25
  mov    $0x1,%eax
  jmp    L17
L25:
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: Yes

assistant: ```c
int getBoolean(char *value) {
  if (value != NULL && strncmp(value, "Yes", 3) == 0) {
    return 1;
  }
  return 0;
}
```