ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<supcon_putui>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7e,-0x98(%rbp)
  mov    -0xa4(%rbp),%eax
  mov    %eax,-0x94(%rbp)
  cmpl   $0x0,-0xa4(%rbp)
  jne    L22
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <os_puts@plt>
  jmp    L36
L22:
  movb   $0x0,-0x11(%rbp)
  jmp    L9
L23:
  mov    -0x94(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x98(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x98(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x90(%rbp,%rax,1)
  mov    -0x94(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x94(%rbp)
L9:
  cmpl   $0x0,-0x94(%rbp)
  jne    L23
  mov    -0x98(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  lea    -0x90(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <os_puts@plt>
L36:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: 0

assistant: ```c
void supcon_putui(unsigned int num) {
  char buffer[128];
  int position = 126;
  unsigned int temp = num;
  if (num == 0) {
    os_puts("0");
    return;
  }
  buffer[127] = 0;
  while (temp > 0) {
    buffer[position--] = '0' + (temp % 10);
    temp = temp / 10;
  }
  os_puts(buffer + position + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<supcon_putui>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L0
  movb   $0x0,0x7f(%rsp)
  mov    $0x7e,%edx
  mov    $0xcccccccd,%r9d
L14:
  mov    %edx,%r8d
  mov    %edi,%eax
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edi,%ecx
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rsp,%rdx,1)
  mov    %edi,%ecx
  mov    %eax,%edi
  sub    $0x1,%rdx
  cmp    $0x9,%ecx
  ja     L14
  movslq %r8d,%r8
  lea    (%rsp,%r8,1),%rdi
  call   <os_puts@plt>
L5:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x98,%rsp
  ret
L0:
  lea    D7(%rip),%rdi
  call   <os_puts@plt>
  jmp    L5
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: 0

assistant: ```c
void supcon_putui(unsigned int num) {
  char buffer[128];
  int position = 126;
  unsigned int temp = num;
  if (num == 0) {
    os_puts("0");
    return;
  }
  buffer[127] = 0;
  while (temp > 0) {
    buffer[position--] = '0' + (temp % 10);
    temp = temp / 10;
  }
  os_puts(buffer + position + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<supcon_putui>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L31
  movb   $0x0,0x7f(%rsp)
  mov    $0x7e,%edx
  mov    %rsp,%r8
  mov    $0xcccccccd,%r10d
  nopl   (%rax)
L27:
  mov    %edi,%eax
  mov    %edi,%ecx
  movslq %edx,%r9
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%r8,%rdx,1)
  mov    %edi,%ecx
  sub    $0x1,%rdx
  mov    %eax,%edi
  cmp    $0x9,%ecx
  ja     L27
  lea    (%r8,%r9,1),%rdi
  call   <os_puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x98,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  lea    D0(%rip),%rdi
  add    $0x98,%rsp
  jmp    1070 <os_puts@plt>
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: 0

assistant: ```c
void supcon_putui(unsigned int num) {
  char buffer[128];
  int position = 126;
  unsigned int temp = num;
  if (num == 0) {
    os_puts("0");
    return;
  }
  buffer[127] = 0;
  while (temp > 0) {
    buffer[position--] = '0' + (temp % 10);
    temp = temp / 10;
  }
  os_puts(buffer + position + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<supcon_putui>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L17
  movb   $0x0,0x7f(%rsp)
  mov    $0x7e,%edx
  mov    %rsp,%r8
  mov    $0xcccccccd,%r10d
  nopl   (%rax)
L39:
  mov    %edi,%eax
  mov    %edi,%ecx
  movslq %edx,%r9
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%r8,%rdx,1)
  mov    %edi,%ecx
  sub    $0x1,%rdx
  mov    %eax,%edi
  cmp    $0x9,%ecx
  ja     L39
  lea    (%r8,%r9,1),%rdi
  call   <os_puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x98,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  lea    D0(%rip),%rdi
  add    $0x98,%rsp
  jmp    1070 <os_puts@plt>
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: 0

assistant: ```c
void supcon_putui(unsigned int num) {
  char buffer[128];
  int position = 126;
  unsigned int temp = num;
  if (num == 0) {
    os_puts("0");
    return;
  }
  buffer[127] = 0;
  while (temp > 0) {
    buffer[position--] = '0' + (temp % 10);
    temp = temp / 10;
  }
  os_puts(buffer + position + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a8(%rbp)
  jmp    L47
L42:
  mov    -0x1a8(%rbp),%eax
  add    $0x1,%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a8(%rbp)
L47:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L42
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x1a4(%rbp)
  jmp    L8
L19:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1a4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1a4(%rbp)
L8:
  cmpl   $0x63,-0x1a4(%rbp)
  jle    L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D0
type: string

tool: D18: Number	Value

tool: D0: %d	%d


assistant: ```c
int main(void) {
  int c[100];
  int i, j;
  for (i = 0; i <= 100 - 1; i++) {
    c[i] = 2 * i + 2;
  }
  printf("Number\tValue\n");
  for (j = 0; j <= 100 - 1; j++) {
    printf("%d\t%d\n", j, c[j]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x190(%rsp),%rcx
  mov    $0x2,%edx
L16:
  mov    %edx,(%rax)
  add    $0x2,%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L16
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L3:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  jne    L3
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D8
datatype: string

tool: D12: Number	Value

tool: D8: %d	%d


assistant: ```c
int main(void) {
  int c[100];
  int i, j;
  for (i = 0; i <= 100 - 1; i++) {
    c[i] = 2 * i + 2;
  }
  printf("Number\tValue\n");
  for (j = 0; j <= 100 - 1; j++) {
    printf("%d\t%d\n", j, c[j]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x190(%rsp),%rcx
  mov    %rbp,%rax
  nopl   (%rax)
L19:
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    $0x2,%edx
  cmp    %rcx,%rax
  jne    L19
  lea    D11(%rip),%rdi
  xor    %ebx,%ebx
  lea    D18(%rip),%r12
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L23:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L23
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D18
datatype: string

tool: D11: Number	Value

tool: D18: %d	%d


assistant: ```c
int main(void) {
  int c[100];
  int i, j;
  for (i = 0; i <= 100 - 1; i++) {
    c[i] = 2 * i + 2;
  }
  printf("Number\tValue\n");
  for (j = 0; j <= 100 - 1; j++) {
    printf("%d\t%d\n", j, c[j]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  movdqa D11(%rip),%xmm1
  movdqa D12(%rip),%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movdqa D33(%rip),%xmm2
  lea    0x190(%rsp),%rdx
  mov    %rbp,%rax
  nopl   0x0(%rax,%rax,1)
L16:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  pslld  $0x1,%xmm0
  movaps %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L16
  lea    D1(%rip),%rdi
  xor    %ebx,%ebx
  lea    D4(%rip),%r12
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L15
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_infered: byte[16]
name: disassemble_data
arguments: tag: D12
type_infered: byte[16]
name: disassemble_data
arguments: tag: D33
type_infered: byte[16]
name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string

tool: {"D11": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D12": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D33": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D1: Number	Value

tool: D4: %d	%d


assistant: ```c
int main(void) {
  int c[100];
  int i, j;
  for (i = 0; i <= 100 - 1; i++) {
    c[i] = 2 * i + 2;
  }
  printf("Number\tValue\n");
  for (j = 0; j <= 100 - 1; j++) {
    printf("%d\t%d\n", j, c[j]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x38(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <read_file_dentries@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L34
  mov    -0x14(%rbp),%eax
  jmp    L24
L34:
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <check_inode@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L38
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free_exfat_inode@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L24
L38:
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
int read_file(struct exfat_de_iter *de_iter, struct exfat_inode **new_node, int *dentry_count) {
  struct exfat_inode *node;
  int ret;
  *new_node = NULL;
  ret = read_file_dentries(de_iter, &node, dentry_count);
  if (ret)
    return ret;
  ret = check_inode(de_iter, node);
  if (ret < 0) {
    free_exfat_inode(node);
    return -EINVAL;
  }
  *new_node = node;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsi)
  mov    %rsp,%rsi
  call   <read_file_dentries@plt>
  test   %eax,%eax
  je     L14
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  call   <check_inode@plt>
  test   %eax,%eax
  js     L12
  mov    (%rsp),%rdx
  mov    %rdx,0x0(%rbp)
  jmp    L2
L12:
  mov    (%rsp),%rdi
  call   <free_exfat_inode@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L2
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_file(struct exfat_de_iter *de_iter, struct exfat_inode **new_node, int *dentry_count) {
  struct exfat_inode *node;
  int ret;
  *new_node = NULL;
  ret = read_file_dentries(de_iter, &node, dentry_count);
  if (ret)
    return ret;
  ret = check_inode(de_iter, node);
  if (ret < 0) {
    free_exfat_inode(node);
    return -EINVAL;
  }
  *new_node = node;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsi)
  mov    %rsp,%rsi
  call   <read_file_dentries@plt>
  test   %eax,%eax
  je     L19
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <check_inode@plt>
  test   %eax,%eax
  js     L31
  mov    (%rsp),%rdx
  mov    %rdx,(%rbx)
  jmp    L21
  nopl   0x0(%rax)
L31:
  mov    (%rsp),%rdi
  call   <free_exfat_inode@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L21
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_file(struct exfat_de_iter *de_iter, struct exfat_inode **new_node, int *dentry_count) {
  struct exfat_inode *node;
  int ret;
  *new_node = NULL;
  ret = read_file_dentries(de_iter, &node, dentry_count);
  if (ret)
    return ret;
  ret = check_inode(de_iter, node);
  if (ret < 0) {
    free_exfat_inode(node);
    return -EINVAL;
  }
  *new_node = node;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsi)
  mov    %rsp,%rsi
  call   <read_file_dentries@plt>
  test   %eax,%eax
  je     L46
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <check_inode@plt>
  test   %eax,%eax
  js     L39
  mov    (%rsp),%rdx
  mov    %rdx,(%rbx)
  jmp    L17
  nopl   0x0(%rax)
L39:
  mov    (%rsp),%rdi
  call   <free_exfat_inode@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L17
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_file(struct exfat_de_iter *de_iter, struct exfat_inode **new_node, int *dentry_count) {
  struct exfat_inode *node;
  int ret;
  *new_node = NULL;
  ret = read_file_dentries(de_iter, &node, dentry_count);
  if (ret)
    return ret;
  ret = check_inode(de_iter, node);
  if (ret < 0) {
    free_exfat_inode(node);
    return -EINVAL;
  }
  *new_node = node;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gammln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D49(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D14(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x40(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movsd  -0x40(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L19
L11:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D4(%rip),%rax
  movsd  (%rdx,%rax,1),%xmm0
  movsd  -0x20(%rbp),%xmm2
  movsd  D1(%rip),%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,-0x20(%rbp)
  divsd  -0x20(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x24(%rbp)
L19:
  cmpl   $0x5,-0x24(%rbp)
  jle    L11
  movsd  -0x18(%rbp),%xmm1
  movsd  D43(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D49
type_guessed: f64
name: disassemble_data
arguments: label: D14
type_guessed: f64
name: disassemble_data
arguments: label: D0
type_guessed: f64
name: disassemble_data
arguments: label: D1
type_guessed: byte[8]
name: disassemble_data
arguments: label: D43
type_guessed: f64

tool: D49: 5.5

tool: D14: 0.5

tool: D0: 1.000000000190015

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D43: 2.5066282746310007

assistant: ```c
double gammln(double xx) {
  double x, y, tmp, ser;
  static double cof[6] = {76.18009172947146, -86.50532032941677, 24.01409824083091, -1.231739572450155, 0.1208650973866179e-2, -0.5395239384953e-5};
  int j;
  y = x = xx;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * log(tmp);
  ser = 1.000000000190015;
  for (j = 0; j <= 5; j++)
    ser += cof[j] / ++y;
  return -tmp + log(2.5066282746310005 * ser / x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gammln>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  movapd %xmm0,%xmm4
  addsd  D47(%rip),%xmm4
  movq   %xmm4,%r14
  movapd %xmm4,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  addsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movq   %r14,%xmm5
  subsd  %xmm0,%xmm5
  movsd  %xmm5,0x8(%rsp)
  lea    D10(%rip),%rax
  lea    0x30(%rax),%rdx
  movq   %rbx,%xmm2
  movsd  D41(%rip),%xmm0
  movsd  D36(%rip),%xmm3
L5:
  addsd  %xmm3,%xmm2
  movsd  (%rax),%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L5
  mulsd  D56(%rip),%xmm0
  movq   %rbx,%xmm6
  divsd  %xmm6,%xmm0
  call   <log@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D47
type: f64
name: unpack_data
arguments: data_label: D4
type: f64
name: unpack_data
arguments: data_label: D10
type: f64
name: unpack_data
arguments: data_label: D41
type: f64
name: unpack_data
arguments: data_label: D36
type: byte[8]
name: unpack_data
arguments: data_label: D56
type: f64

tool: D47: 5.5

tool: D4: 0.5

tool: D10: 76.18009172947146

tool: D41: 1.000000000190015

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D56: 2.5066282746310007

assistant: ```c
double gammln(double xx) {
  double x, y, tmp, ser;
  static double cof[6] = {76.18009172947146, -86.50532032941677, 24.01409824083091, -1.231739572450155, 0.1208650973866179e-2, -0.5395239384953e-5};
  int j;
  y = x = xx;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * log(tmp);
  ser = 1.000000000190015;
  for (j = 0; j <= 5; j++)
    ser += cof[j] / ++y;
  return -tmp + log(2.5066282746310005 * ser / x);
}
```
user: What is the c source code of the assembly code below:

```asm
<gammln>:
  endbr64
  sub    $0x18,%rsp
  movapd %xmm0,%xmm1
  addsd  D36(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  movsd  0x8(%rsp),%xmm4
  movsd  (%rsp),%xmm1
  lea    D35(%rip),%rax
  movapd %xmm0,%xmm2
  movsd  D66(%rip),%xmm0
  movsd  D46(%rip),%xmm3
  lea    0x30(%rax),%rdx
  addsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm0
  movapd %xmm4,%xmm2
  subsd  %xmm0,%xmm1
  movsd  D49(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  movsd  D23(%rip),%xmm1
  jmp    L6
  nopl   0x0(%rax)
L16:
  movsd  (%rax),%xmm1
L6:
  addsd  %xmm3,%xmm2
  add    $0x8,%rax
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L16
  mulsd  D58(%rip),%xmm0
  divsd  %xmm4,%xmm0
  call   <log@plt>
  subsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
datatype: f64
name: extract_symbolic_data
arguments: data_label: D35
datatype: f64
name: extract_symbolic_data
arguments: data_label: D66
datatype: f64
name: extract_symbolic_data
arguments: data_label: D46
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D49
datatype: f64
name: extract_symbolic_data
arguments: data_label: D23
datatype: f64
name: extract_symbolic_data
arguments: data_label: D58
datatype: f64

tool: D36: 5.5

tool: D35: 76.18009172947146

tool: D66: 0.5

tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D49: 1.000000000190015

tool: D23: 76.18009172947146

tool: D58: 2.5066282746310007

assistant: ```c
double gammln(double xx) {
  double x, y, tmp, ser;
  static double cof[6] = {76.18009172947146, -86.50532032941677, 24.01409824083091, -1.231739572450155, 0.1208650973866179e-2, -0.5395239384953e-5};
  int j;
  y = x = xx;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * log(tmp);
  ser = 1.000000000190015;
  for (j = 0; j <= 5; j++)
    ser += cof[j] / ++y;
  return -tmp + log(2.5066282746310005 * ser / x);
}
```