ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D62(%rip),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x70(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x68(%rbp)
  cmpq   $0x0,-0x70(%rbp)
  je     L48
  cmpq   $0x0,-0x68(%rbp)
  jne    L53
L48:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L14
L53:
  mov    -0x68(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x2b,%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
L7:
  lea    -0x60(%rbp),%rcx
  mov    -0x70(%rbp),%rax
  mov    $0x50,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fgetline@plt>
  movzbl -0x60(%rbp),%eax
  test   %al,%al
  je     L52
  lea    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L7
L52:
  nop
  mov    -0x68(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x5,%edx
  mov    $0x1,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x68(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D62
type_guessed: string
name: retrieve_data
arguments: tag: D61
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D67
type_guessed: string
name: retrieve_data
arguments: tag: D24
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D6
type_guessed: string
name: retrieve_data
arguments: tag: D23
type_guessed: string
name: retrieve_data
arguments: tag: D19
type_guessed: string

tool: D62: rb

tool: D61: keywords_constant

tool: D12: wb

tool: D67: keywords_constant.h

tool: D24: egads!


tool: D8: static const char *keywords_constant[] = {


tool: D6: 	"%s",


tool: D23: NULL


tool: D19: };



assistant: ```c
int main(void) {
  FILE *fpi, *fpo;
  char line[80];
  fpi = fopen("keywords_constant", "rb");
  fpo = fopen("keywords_constant.h", "wb");
  if (!fpi || !fpo) {
    printf("egads!\n");
    return 1;
  }
  fprintf(fpo, "static const char *keywords_constant[] = {\n");
  for (;;) {
    fgetline(fpi, line, sizeof(line));
    if (line[0] == 0)
      break;
    fprintf(fpo, "\t\"%s\",\n", line);
  }
  fprintf(fpo, "NULL\n");
  fprintf(fpo, "};\n\n");
  fclose(fpi);
  fclose(fpo);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  lea    D62(%rip),%rsi
  lea    D58(%rip),%rdi
  call   <fopen@plt>
  test   %r12,%r12
  je     L33
  mov    %rax,%rbx
  test   %rax,%rax
  je     L33
  mov    %rax,%rcx
  mov    $0x2b,%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  call   <fwrite@plt>
  lea    D61(%rip),%rbp
  jmp    L59
L33:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L43
L31:
  mov    %rsp,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L59:
  mov    %rsp,%rsi
  mov    $0x50,%edx
  mov    %r12,%rdi
  call   <fgetline@plt>
  cmpb   $0x0,(%rsp)
  jne    L31
  mov    %rbx,%rcx
  mov    $0x5,%edx
  mov    $0x1,%esi
  lea    D55(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L43:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D25
data_type: string
name: disassemble_data
arguments: label: D1
data_type: string
name: disassemble_data
arguments: label: D62
data_type: string
name: disassemble_data
arguments: label: D58
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string
name: disassemble_data
arguments: label: D61
data_type: string
name: disassemble_data
arguments: label: D7
data_type: string
name: disassemble_data
arguments: label: D55
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string

tool: D25: rb

tool: D1: keywords_constant

tool: D62: wb

tool: D58: keywords_constant.h

tool: D8: static const char *keywords_constant[] = {


tool: D61: 	"%s",


tool: D7: egads!


tool: D55: NULL


tool: D9: };



assistant: ```c
int main(void) {
  FILE *fpi, *fpo;
  char line[80];
  fpi = fopen("keywords_constant", "rb");
  fpo = fopen("keywords_constant.h", "wb");
  if (!fpi || !fpo) {
    printf("egads!\n");
    return 1;
  }
  fprintf(fpo, "static const char *keywords_constant[] = {\n");
  for (;;) {
    fgetline(fpi, line, sizeof(line));
    if (line[0] == 0)
      break;
    fprintf(fpo, "\t\"%s\",\n", line);
  }
  fprintf(fpo, "NULL\n");
  fprintf(fpo, "};\n\n");
  fclose(fpi);
  fclose(fpo);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D71(%rip),%rsi
  lea    D57(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    D23(%rip),%rsi
  lea    D83(%rip),%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  test   %r13,%r13
  je     L9
  mov    %rax,%rbp
  test   %rax,%rax
  je     L9
  mov    %rax,%rcx
  mov    $0x2b,%edx
  mov    $0x1,%esi
  mov    %rsp,%rbx
  lea    D86(%rip),%rdi
  lea    D21(%rip),%r12
  call   <fwrite@plt>
  jmp    L11
  nopl   0x0(%rax)
L53:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L11:
  mov    $0x50,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <fgetline@plt>
  cmpb   $0x0,(%rsp)
  jne    L53
  mov    %rbp,%rcx
  mov    $0x5,%edx
  mov    $0x1,%esi
  lea    D74(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D28(%rip),%rdi
  call   <fwrite@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L24:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  lea    D77(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L24
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D71
data_type: string
name: read_data
arguments: label: D57
data_type: string
name: read_data
arguments: label: D23
data_type: string
name: read_data
arguments: label: D83
data_type: string
name: read_data
arguments: label: D86
data_type: string
name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D74
data_type: string
name: read_data
arguments: label: D28
data_type: string
name: read_data
arguments: label: D77
data_type: string

tool: D71: rb

tool: D57: keywords_constant

tool: D23: wb

tool: D83: keywords_constant.h

tool: D86: static const char *keywords_constant[] = {


tool: D21: 	"%s",


tool: D74: NULL


tool: D28: };



tool: D77: egads!


assistant: ```c
int main(void) {
  FILE *fpi, *fpo;
  char line[80];
  fpi = fopen("keywords_constant", "rb");
  fpo = fopen("keywords_constant.h", "wb");
  if (!fpi || !fpo) {
    printf("egads!\n");
    return 1;
  }
  fprintf(fpo, "static const char *keywords_constant[] = {\n");
  for (;;) {
    fgetline(fpi, line, sizeof(line));
    if (line[0] == 0)
      break;
    fprintf(fpo, "\t\"%s\",\n", line);
  }
  fprintf(fpo, "NULL\n");
  fprintf(fpo, "};\n\n");
  fclose(fpi);
  fclose(fpo);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D85(%rip),%rsi
  lea    D66(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    D49(%rip),%rsi
  lea    D53(%rip),%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  test   %r13,%r13
  je     L19
  mov    %rax,%rbp
  test   %rax,%rax
  je     L19
  mov    %rax,%rcx
  mov    $0x2b,%edx
  mov    $0x1,%esi
  mov    %rsp,%rbx
  lea    D74(%rip),%rdi
  lea    D75(%rip),%r12
  call   <fwrite@plt>
  jmp    L55
  nopl   0x0(%rax)
L20:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L55:
  mov    $0x50,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <fgetline@plt>
  cmpb   $0x0,(%rsp)
  jne    L20
  mov    %rbp,%rcx
  mov    $0x5,%edx
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D43(%rip),%rdi
  call   <fwrite@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L30:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L30
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D85
type_guessed: string
name: parse_data
arguments: data_tag: D66
type_guessed: string
name: parse_data
arguments: data_tag: D49
type_guessed: string
name: parse_data
arguments: data_tag: D53
type_guessed: string
name: parse_data
arguments: data_tag: D74
type_guessed: string
name: parse_data
arguments: data_tag: D75
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D43
type_guessed: string
name: parse_data
arguments: data_tag: D41
type_guessed: string

tool: D85: rb

tool: D66: keywords_constant

tool: D49: wb

tool: D53: keywords_constant.h

tool: D74: static const char *keywords_constant[] = {


tool: D75: 	"%s",


tool: D11: NULL


tool: D43: };



tool: D41: egads!


assistant: ```c
int main(void) {
  FILE *fpi, *fpo;
  char line[80];
  fpi = fopen("keywords_constant", "rb");
  fpo = fopen("keywords_constant.h", "wb");
  if (!fpi || !fpo) {
    printf("egads!\n");
    return 1;
  }
  fprintf(fpo, "static const char *keywords_constant[] = {\n");
  for (;;) {
    fgetline(fpi, line, sizeof(line));
    if (line[0] == 0)
      break;
    fprintf(fpo, "\t\"%s\",\n", line);
  }
  fprintf(fpo, "NULL\n");
  fprintf(fpo, "};\n\n");
  fclose(fpi);
  fclose(fpo);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L12
L18:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  imul   -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    -0x48(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L51
  mov    -0x8(%rbp),%rax
  jmp    L48
L51:
  cmpl   $0x0,-0xc(%rbp)
  jns    L0
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L12
L0:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L18
  mov    $0x0,%eax
L48:
  leave
  ret
```

assistant: ```c
void *bsearch(const void *searchKey, const void *base, size_t num, size_t size, int (*compare)(const void *, const void *)) {
  int low = 0;
  int high = num - 1;
  while (low <= high) {
    int mid = (low + high) / 2;
    void *midKey = (char *)base + mid * size;
    int compVal = (*compare)(searchKey, midKey);
    if (compVal == 0)
      return midKey;
    else if (compVal < 0)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %edx,%r12d
  sub    $0x1,%r12d
  js     L34
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    $0x0,%r13d
  jmp    L60
L21:
  lea    -0x1(%rbx),%r12d
L26:
  cmp    %r12d,%r13d
  jg     L17
L60:
  lea    0x0(%r13,%r12,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  movslq %ebx,%rbp
  imul   %r14,%rbp
  add    0x8(%rsp),%rbp
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   *%r15
  test   %eax,%eax
  je     L12
  js     L21
  lea    0x1(%rbx),%r13d
  jmp    L26
L17:
  mov    $0x0,%ebp
L12:
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  mov    $0x0,%ebp
  jmp    L12
```

assistant: ```c
void *bsearch(const void *searchKey, const void *base, size_t num, size_t size, int (*compare)(const void *, const void *)) {
  int low = 0;
  int high = num - 1;
  while (low <= high) {
    int mid = (low + high) / 2;
    void *midKey = (char *)base + mid * size;
    int compVal = (*compare)(searchKey, midKey);
    if (compVal == 0)
      return midKey;
    else if (compVal < 0)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  mov    %rcx,0x8(%rsp)
  sub    $0x1,%ebp
  js     L28
  mov    %rdi,%rbx
  mov    %r8,%r14
  xor    %r13d,%r13d
  jmp    L29
  nopl   (%rax)
L53:
  lea    0x1(%r15),%r13d
  cmp    %r13d,%ebp
  jl     L28
L29:
  lea    0x0(%r13,%rbp,1),%r15d
  mov    %rbx,%rdi
  sar    %r15d
  movslq %r15d,%r12
  imul   0x8(%rsp),%r12
  add    (%rsp),%r12
  mov    %r12,%rsi
  call   *%r14
  test   %eax,%eax
  je     L42
  jns    L53
  lea    -0x1(%r15),%ebp
  cmp    %r13d,%ebp
  jge    L29
L28:
  xor    %r12d,%r12d
L42:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *bsearch(const void *searchKey, const void *base, size_t num, size_t size, int (*compare)(const void *, const void *)) {
  int low = 0;
  int high = num - 1;
  while (low <= high) {
    int mid = (low + high) / 2;
    void *midKey = (char *)base + mid * size;
    int compVal = (*compare)(searchKey, midKey);
    if (compVal == 0)
      return midKey;
    else if (compVal < 0)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<bsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  mov    %rcx,0x8(%rsp)
  sub    $0x1,%ebp
  js     L12
  mov    %rdi,%rbx
  mov    %r8,%r14
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L45:
  lea    0x0(%r13,%rbp,1),%r15d
  mov    %rbx,%rdi
  sar    %r15d
  movslq %r15d,%r12
  imul   0x8(%rsp),%r12
  add    (%rsp),%r12
  mov    %r12,%rsi
  call   *%r14
  test   %eax,%eax
  je     L20
  js     L58
  lea    0x1(%r15),%r13d
  cmp    %ebp,%r13d
  jle    L45
L12:
  xor    %r12d,%r12d
L20:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  lea    -0x1(%r15),%ebp
  cmp    %r13d,%ebp
  jge    L45
  jmp    L12
```

assistant: ```c
void *bsearch(const void *searchKey, const void *base, size_t num, size_t size, int (*compare)(const void *, const void *)) {
  int low = 0;
  int high = num - 1;
  while (low <= high) {
    int mid = (low + high) / 2;
    void *midKey = (char *)base + mid * size;
    int compVal = (*compare)(searchKey, midKey);
    if (compVal == 0)
      return midKey;
    else if (compVal < 0)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hd44780Goto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rax
  shr    $0x3f,%rax
  mov    %eax,%edx
  cmpq   $0xf,-0x50(%rbp)
  setg   %al
  or     %edx,%eax
  test   %al,%al
  je     L11
  mov    $0xffffffff,%eax
  jmp    L44
L11:
  mov    -0x48(%rbp),%rax
  shr    $0x3f,%rax
  mov    %eax,%edx
  cmpq   $0x1,-0x48(%rbp)
  setg   %al
  or     %edx,%eax
  test   %al,%al
  je     L41
  mov    $0xffffffff,%eax
  jmp    L44
L41:
  movq   $0x0,-0x30(%rbp)
  movq   $0x40,-0x28(%rbp)
  movq   $0x14,-0x20(%rbp)
  movq   $0x54,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  mov    -0x30(%rbp,%rax,8),%rax
  or     $0x80,%al
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <hd44780WriteByte@plt>
  mov    $0x0,%eax
L44:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int8_t hd44780Goto(struct mcp23017 *mcp23017, struct hd44780 *hd44780, uint8_t row, uint8_t pos) {
  if ((pos < 0) | (pos > 16 - 1))
    return -1;
  if ((row < 0) | (row > 2 - 1))
    return -1;
  uint8_t rows[4] = {0x00, 0x40, 0x14, 0x54};
  hd44780WriteByte(mcp23017, hd44780, (0x80 | rows[row]) + pos, 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hd44780Goto>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0xf,%rcx
  ja     L24
  cmp    $0x1,%rdx
  ja     L14
  movq   $0x0,(%rsp)
  movq   $0x40,0x8(%rsp)
  movq   $0x14,0x10(%rsp)
  movq   $0x54,0x18(%rsp)
  mov    (%rsp,%rdx,8),%rdx
  or     $0x80,%dl
  add    %rcx,%rdx
  mov    $0x0,%ecx
  call   <hd44780WriteByte@plt>
  mov    $0x0,%eax
L18:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x38,%rsp
  ret
L24:
  mov    $0xffffffff,%eax
  jmp    L18
L14:
  mov    $0xffffffff,%eax
  jmp    L18
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int8_t hd44780Goto(struct mcp23017 *mcp23017, struct hd44780 *hd44780, uint8_t row, uint8_t pos) {
  if ((pos < 0) | (pos > 16 - 1))
    return -1;
  if ((row < 0) | (row > 2 - 1))
    return -1;
  uint8_t rows[4] = {0x00, 0x40, 0x14, 0x54};
  hd44780WriteByte(mcp23017, hd44780, (0x80 | rows[row]) + pos, 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hd44780Goto>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0xf,%rcx
  ja     L9
  cmp    $0x1,%rdx
  ja     L9
  movq   $0x0,(%rsp)
  movq   $0x40,0x8(%rsp)
  movq   $0x14,0x10(%rsp)
  movq   $0x54,0x18(%rsp)
  mov    (%rsp,%rdx,8),%rdx
  or     $0x80,%dl
  add    %rcx,%rdx
  xor    %ecx,%ecx
  call   <hd44780WriteByte@plt>
  xor    %eax,%eax
L17:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x38,%rsp
  ret
  nop
L9:
  mov    $0xffffffff,%eax
  jmp    L17
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int8_t hd44780Goto(struct mcp23017 *mcp23017, struct hd44780 *hd44780, uint8_t row, uint8_t pos) {
  if ((pos < 0) | (pos > 16 - 1))
    return -1;
  if ((row < 0) | (row > 2 - 1))
    return -1;
  uint8_t rows[4] = {0x00, 0x40, 0x14, 0x54};
  hd44780WriteByte(mcp23017, hd44780, (0x80 | rows[row]) + pos, 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hd44780Goto>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0xf,%rcx
  ja     L18
  cmp    $0x1,%rdx
  ja     L18
  movdqa D14(%rip),%xmm0
  movaps %xmm0,(%rsp)
  movdqa D11(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  mov    (%rsp,%rdx,8),%rdx
  or     $0x80,%dl
  add    %rcx,%rdx
  xor    %ecx,%ecx
  call   <hd44780WriteByte@plt>
  xor    %eax,%eax
L4:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x38,%rsp
  ret
  nopl   (%rax)
L18:
  mov    $0xffffffff,%eax
  jmp    L4
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D11
data_type: byte[16]

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D11": [0x14,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x54,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int8_t hd44780Goto(struct mcp23017 *mcp23017, struct hd44780 *hd44780, uint8_t row, uint8_t pos) {
  if ((pos < 0) | (pos > 16 - 1))
    return -1;
  if ((row < 0) | (row > 2 - 1))
    return -1;
  uint8_t rows[4] = {0x00, 0x40, 0x14, 0x54};
  hd44780WriteByte(mcp23017, hd44780, (0x80 | rows[row]) + pos, 0);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L13:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  size_t index;
  for (index = 0; src[index]; index++)
    dest[index] = src[index];
  dest[index] = '\0';
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L25
  mov    $0x0,%edx
L14:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L14
L5:
  movb   $0x0,(%rax,%rdx,1)
  ret
L25:
  mov    $0x0,%edx
  jmp    L5
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  size_t index;
  for (index = 0; src[index]; index++)
    dest[index] = src[index];
  dest[index] = '\0';
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L11
  xor    %edx,%edx
L3:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L3
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  size_t index;
  for (index = 0; src[index]; index++)
    dest[index] = src[index];
  dest[index] = '\0';
  return dest;
}
```