ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rbx
  call   <scanf@plt>
  test   %rax,%rax
  jne    L39
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rsp),%eax
  cmp    %eax,0x4(%rsp)
  jl     L29
L39:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L13
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    %eax,0x4(%rsp)
  jmp    L39
L57:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L47
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type: string
name: parse_data
arguments: tag: D5
type: string

tool: D9: %d

tool: D5: Ne e vnesen broj.

assistant: ```c
int main() {
  int n, max;
  if (scanf("%d", &max)) {
    while (scanf("%d", &n)) {
      if (max < n) {
        max = n;
      }
    }
    printf("%d", max);
  } else {
    printf("Ne e vnesen broj.");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__aes_power_by_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L8:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <__aes_multiply_by_2@plt>
  mov    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L8
  movzbl -0x5(%rbp),%eax
  leave
  ret
```

assistant: ```c
char __aes_power_by_2(char a, int n) {
  int i;
  char t = a;
  for (i = 0; i < n; i++)
    t = __aes_multiply_by_2(t);
  return t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__aes_power_by_2>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jle    L17
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    $0x0,%ebx
L10:
  movsbl %al,%edi
  call   <__aes_multiply_by_2@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  ret
```

assistant: ```c
char __aes_power_by_2(char a, int n) {
  int i;
  char t = a;
  for (i = 0; i < n; i++)
    t = __aes_multiply_by_2(t);
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__aes_power_by_2>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jle    L9
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L10:
  movsbl %al,%edi
  add    $0x1,%ebx
  call   <__aes_multiply_by_2@plt>
  cmp    %ebx,%ebp
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L9:
  ret
```

assistant: ```c
char __aes_power_by_2(char a, int n) {
  int i;
  char t = a;
  for (i = 0; i < n; i++)
    t = __aes_multiply_by_2(t);
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__aes_power_by_2>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jle    L18
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L14:
  movsbl %al,%edi
  add    $0x1,%ebx
  call   <__aes_multiply_by_2@plt>
  cmp    %ebx,%ebp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L18:
  ret
```

assistant: ```c
char __aes_power_by_2(char a, int n) {
  int i;
  char t = a;
  for (i = 0; i < n; i++)
    t = __aes_multiply_by_2(t);
  return t;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rank2sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L42
L58:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  neg    %rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x28(%rbp)
L42:
  mov    -0x28(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jl     L58
  movq   $0x0,-0x28(%rbp)
  jmp    L33
L28:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jns    L30
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L26:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  neg    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  je     L29
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L26
L29:
  nop
L30:
  addq   $0x1,-0x28(%rbp)
L33:
  mov    -0x28(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jl     L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rank2sort(long nmax, double *x, long *list) {
  long n, ib, it;
  double hb, ht;
  for (n = 0; n < nmax; n++)
    list[n] = -list[n];
  for (n = 0; n < nmax; n++) {
    if (list[n] < 0) {
      ib = n;
      hb = x[n];
      while (1) {
        it = -list[ib];
        list[ib] = it;
        ht = x[it];
        x[it] = hb;
        if (it == n)
          break;
        ib = it;
        hb = ht;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rank2sort>:
  endbr64
  test   %rdi,%rdi
  jle    L45
  mov    %rdx,%rax
  lea    (%rdx,%rdi,8),%rcx
L51:
  negq   (%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L51
  mov    $0x0,%ecx
  jmp    L1
L25:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  je     L45
L1:
  cmpq   $0x0,(%rdx,%rcx,8)
  jns    L25
  movsd  (%rsi,%rcx,8),%xmm0
  mov    %rcx,%rax
L54:
  lea    (%rdx,%rax,8),%r8
  mov    (%r8),%rax
  neg    %rax
  mov    %rax,(%r8)
  lea    (%rsi,%rax,8),%r8
  movapd %xmm0,%xmm1
  movsd  (%r8),%xmm0
  movsd  %xmm1,(%r8)
  cmp    %rcx,%rax
  jne    L54
  jmp    L25
L45:
  ret
```

assistant: ```c
void rank2sort(long nmax, double *x, long *list) {
  long n, ib, it;
  double hb, ht;
  for (n = 0; n < nmax; n++)
    list[n] = -list[n];
  for (n = 0; n < nmax; n++) {
    if (list[n] < 0) {
      ib = n;
      hb = x[n];
      while (1) {
        it = -list[ib];
        list[ib] = it;
        ht = x[it];
        x[it] = hb;
        if (it == n)
          break;
        ib = it;
        hb = ht;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rank2sort>:
  endbr64
  mov    %rdi,%r9
  mov    %rdx,%rax
  lea    (%rdx,%rdi,8),%rcx
  test   %rdi,%rdi
  jle    L75
  nopl   0x0(%rax,%rax,1)
L28:
  negq   (%rax)
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L28
  xor    %ecx,%ecx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x1,%rcx
  cmp    %rcx,%r9
  je     L75
L20:
  mov    (%rdx,%rcx,8),%rdi
  test   %rdi,%rdi
  jns    L49
  movsd  (%rsi,%rcx,8),%xmm0
  mov    %rcx,%rax
  jmp    L33
  nopl   0x0(%rax)
L60:
  mov    (%rdx,%rax,8),%rdi
  movapd %xmm1,%xmm0
L33:
  lea    (%rdx,%rax,8),%r8
  mov    %rdi,%rax
  neg    %rax
  lea    (%rsi,%rax,8),%rdi
  mov    %rax,(%r8)
  movsd  (%rdi),%xmm1
  movsd  %xmm0,(%rdi)
  cmp    %rcx,%rax
  jne    L60
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L20
L75:
  ret
```

assistant: ```c
void rank2sort(long nmax, double *x, long *list) {
  long n, ib, it;
  double hb, ht;
  for (n = 0; n < nmax; n++)
    list[n] = -list[n];
  for (n = 0; n < nmax; n++) {
    if (list[n] < 0) {
      ib = n;
      hb = x[n];
      while (1) {
        it = -list[ib];
        list[ib] = it;
        ht = x[it];
        x[it] = hb;
        if (it == n)
          break;
        ib = it;
        hb = ht;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rank2sort>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  test   %r8,%r8
  jle    L17
  cmp    $0x1,%r8
  je     L0
  mov    %rdx,%rax
  mov    %r8,%rdx
  pxor   %xmm1,%xmm1
  shr    %rdx
  shl    $0x4,%rdx
  add    %rsi,%rdx
  nopl   0x0(%rax)
L62:
  movdqu (%rax),%xmm2
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  psubq  %xmm2,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L62
  mov    %r8,%rax
  and    $0xfffffffffffffffe,%rax
  test   $0x1,%r8b
  je     L73
L19:
  negq   (%rsi,%rax,8)
L73:
  xor    %edx,%edx
  jmp    L105
  cs nopw 0x0(%rax,%rax,1)
L7:
  add    $0x1,%rdx
  cmp    %rdx,%r8
  je     L17
L105:
  mov    (%rsi,%rdx,8),%rax
  test   %rax,%rax
  jns    L7
  movsd  (%rdi,%rdx,8),%xmm1
  neg    %rax
  lea    (%rdi,%rax,8),%rcx
  mov    %rax,(%rsi,%rdx,8)
  movsd  (%rcx),%xmm0
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rdx
  je     L7
  nop
L22:
  lea    (%rsi,%rax,8),%rcx
  movapd %xmm0,%xmm1
  mov    (%rcx),%rax
  neg    %rax
  mov    %rax,(%rcx)
  lea    (%rdi,%rax,8),%rcx
  movsd  (%rcx),%xmm0
  movsd  %xmm1,(%rcx)
  cmp    %rdx,%rax
  jne    L22
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L105
L17:
  ret
L0:
  xor    %eax,%eax
  jmp    L19
```

assistant: ```c
void rank2sort(long nmax, double *x, long *list) {
  long n, ib, it;
  double hb, ht;
  for (n = 0; n < nmax; n++)
    list[n] = -list[n];
  for (n = 0; n < nmax; n++) {
    if (list[n] < 0) {
      ib = n;
      hb = x[n];
      while (1) {
        it = -list[ib];
        list[ib] = it;
        ht = x[it];
        x[it] = hb;
        if (it == n)
          break;
        ib = it;
        hb = ht;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<udp_setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x20(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x44,%edi
  call   <htons@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x18(%rdx)
  mov    $0x43,%edi
  call   <htons@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x10(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <htons@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x8(%rdx)
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void udp_setup(struct udphdr *udp_header, size_t *len) {
  *len += sizeof(struct udphdr);
  udp_header->uh_sport = htons(68);
  udp_header->uh_dport = htons(67);
  udp_header->uh_ulen = htons(*len);
  udp_header->uh_sum = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<udp_setup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  addq   $0x20,(%rsi)
  mov    $0x44,%edi
  call   <htons@plt>
  mov    %rax,0x18(%rbx)
  mov    $0x43,%edi
  call   <htons@plt>
  mov    %rax,0x10(%rbx)
  mov    0x0(%rbp),%rdi
  call   <htons@plt>
  mov    %rax,0x8(%rbx)
  movq   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void udp_setup(struct udphdr *udp_header, size_t *len) {
  *len += sizeof(struct udphdr);
  udp_header->uh_sport = htons(68);
  udp_header->uh_dport = htons(67);
  udp_header->uh_ulen = htons(*len);
  udp_header->uh_sum = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<udp_setup>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x44,%edi
  sub    $0x8,%rsp
  addq   $0x20,(%rsi)
  call   <htons@plt>
  mov    $0x43,%edi
  mov    %rax,0x18(%rbx)
  call   <htons@plt>
  mov    0x0(%rbp),%rdi
  mov    %rax,0x10(%rbx)
  call   <htons@plt>
  movq   $0x0,(%rbx)
  mov    %rax,0x8(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void udp_setup(struct udphdr *udp_header, size_t *len) {
  *len += sizeof(struct udphdr);
  udp_header->uh_sport = htons(68);
  udp_header->uh_dport = htons(67);
  udp_header->uh_ulen = htons(*len);
  udp_header->uh_sum = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<udp_setup>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x44,%edi
  sub    $0x8,%rsp
  addq   $0x20,(%rsi)
  call   <htons@plt>
  mov    $0x43,%edi
  mov    %rax,0x18(%rbx)
  call   <htons@plt>
  mov    0x0(%rbp),%rdi
  mov    %rax,0x10(%rbx)
  call   <htons@plt>
  movq   $0x0,(%rbx)
  mov    %rax,0x8(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void udp_setup(struct udphdr *udp_header, size_t *len) {
  *len += sizeof(struct udphdr);
  udp_header->uh_sport = htons(68);
  udp_header->uh_dport = htons(67);
  udp_header->uh_ulen = htons(*len);
  udp_header->uh_sum = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Powerty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L8:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Powerty(int X, int Y) {
  int OutputInteger = 1;
  int CurrentInteger = 0;
  for (CurrentInteger = 0; CurrentInteger < Y; CurrentInteger++) {
    OutputInteger = OutputInteger * X;
  }
  return OutputInteger;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Powerty>:
  endbr64
  test   %esi,%esi
  jle    L19
  mov    $0x0,%eax
  mov    $0x1,%edx
L20:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L20
L2:
  mov    %edx,%eax
  ret
L19:
  mov    $0x1,%edx
  jmp    L2
```

assistant: ```c
int Powerty(int X, int Y) {
  int OutputInteger = 1;
  int CurrentInteger = 0;
  for (CurrentInteger = 0; CurrentInteger < Y; CurrentInteger++) {
    OutputInteger = OutputInteger * X;
  }
  return OutputInteger;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Powerty>:
  endbr64
  test   %esi,%esi
  jle    L2
  xor    %eax,%eax
  mov    $0x1,%r8d
L5:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L5
  mov    %r8d,%eax
  ret
  nop
L2:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Powerty(int X, int Y) {
  int OutputInteger = 1;
  int CurrentInteger = 0;
  for (CurrentInteger = 0; CurrentInteger < Y; CurrentInteger++) {
    OutputInteger = OutputInteger * X;
  }
  return OutputInteger;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Powerty>:
  endbr64
  test   %esi,%esi
  jle    L8
  xor    %eax,%eax
  mov    $0x1,%r8d
L6:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L6
  mov    %r8d,%eax
  ret
  nop
L8:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Powerty(int X, int Y) {
  int OutputInteger = 1;
  int CurrentInteger = 0;
  for (CurrentInteger = 0; CurrentInteger < Y; CurrentInteger++) {
    OutputInteger = OutputInteger * X;
  }
  return OutputInteger;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: Usage: %s [num-steps]


assistant: ```c
void __attribute__((noreturn)) usage(const char *argv[]) {
  printf("Usage: %s [num-steps]\n", argv[0]);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: Usage: %s [num-steps]


assistant: ```c
void __attribute__((noreturn)) usage(const char *argv[]) {
  printf("Usage: %s [num-steps]\n", argv[0]);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: Usage: %s [num-steps]


assistant: ```c
void __attribute__((noreturn)) usage(const char *argv[]) {
  printf("Usage: %s [num-steps]\n", argv[0]);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: Usage: %s [num-steps]


assistant: ```c
void __attribute__((noreturn)) usage(const char *argv[]) {
  printf("Usage: %s [num-steps]\n", argv[0]);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
L5:
  lea    -0x4(%rbp),%rax
  mov    %rax,%rdi
  call   <g@plt>
  mov    -0x4(%rbp),%eax
  cmp    $0x7,%eax
  jne    L9
  jmp    L5
L9:
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  leave
  ret
```

assistant: ```c
__attribute((always_)) int f(int i) {
a:
  g(&i);
  if (i == 7)
    goto a;
  return 3 + i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rbx
L6:
  mov    %rbx,%rdi
  call   <g@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x7,%eax
  je     L6
  add    $0x3,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
__attribute((always_)) int f(int i) {
a:
  g(&i);
  if (i == 7)
    goto a;
  return 3 + i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  call   <g@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x7,%eax
  je     L0
  add    $0x10,%rsp
  add    $0x3,%eax
  pop    %rbx
  ret
```

assistant: ```c
__attribute((always_)) int f(int i) {
a:
  g(&i);
  if (i == 7)
    goto a;
  return 3 + i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdi
  call   <g@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x7,%eax
  je     L9
  add    $0x10,%rsp
  add    $0x3,%eax
  pop    %rbx
  ret
```

assistant: ```c
__attribute((always_)) int f(int i) {
a:
  g(&i);
  if (i == 7)
    goto a;
  return 3 + i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rand_doubles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1(%rcx),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void rand_doubles(int size, double *rands) {
  int i;
  for (i = 0; i < size; i++) {
    rands[i] = rand() % 10 + 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rand_doubles>:
  endbr64
  test   %edi,%edi
  jle    L6
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
L14:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  ret
```

assistant: ```c
void rand_doubles(int size, double *rands) {
  int i;
  for (i = 0; i < size; i++) {
    rands[i] = rand() % 10 + 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rand_doubles>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %rbp
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbp
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  add    $0x8,%rbp
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmp    %rbx,%rbp
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
void rand_doubles(int size, double *rands) {
  int i;
  for (i = 0; i < size; i++) {
    rands[i] = rand() % 10 + 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rand_doubles>:
  endbr64
  test   %edi,%edi
  jle    L12
  push   %rbp
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbp
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  add    $0x8,%rbp
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmp    %rbx,%rbp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void rand_doubles(int size, double *rands) {
  int i;
  for (i = 0; i < size; i++) {
    rands[i] = rand() % 10 + 1;
  }
}
```