ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x18(%rsp),%r8
  lea    D60(%rip),%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm0
  comisd (%rsp),%xmm0
  jae    L14
  comisd 0x8(%rsp),%xmm0
  jae    L17
  comisd 0x10(%rsp),%xmm0
  jae    L53
  comisd 0x18(%rsp),%xmm0
  jb     L54
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L17:
  lea    D32(%rip),%rdi
  call   <printf@plt>
L19:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L14:
  lea    D84(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L54:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L53:
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D60
type_guessed: string
name: unpack_data
arguments: tag: D49
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D28
type_guessed: string
name: unpack_data
arguments: tag: D32
type_guessed: string
name: unpack_data
arguments: tag: D84
type_guessed: string
name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D56
type_guessed: string

tool: D18: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D60: %lf%lf%lf%lf

tool: D49: Thank you. Now enter student score (percent) >

tool: D9: %lf

tool: D28: Student has an D grade


tool: D32: Student has an B grade


tool: D84: Student has an A grade


tool: D20: Student has an F grade


tool: D56: Student has an C grade


assistant: ```c
int main(void) {
  double grade_a, grade_b, grade_c, grade_d, student_score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%lf%lf%lf%lf", &grade_a, &grade_b, &grade_c, &grade_d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &student_score);
  if (student_score >= grade_a) {
    printf("Student has an A grade\n");
  } else if (student_score >= grade_b) {
    printf("Student has an B grade\n");
  } else if (student_score >= grade_c) {
    printf("Student has an C grade\n");
  } else if (student_score >= grade_d) {
    printf("Student has an D grade\n");
  } else {
    printf("Student has an F grade\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_leak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void mem_leak() {
  int *i_leak = malloc(5 * sizeof(int));
  free(i_leak);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mem_leak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void mem_leak() {
  int *i_leak = malloc(5 * sizeof(int));
  free(i_leak);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_leak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void mem_leak() {
  int *i_leak = malloc(5 * sizeof(int));
  free(i_leak);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mem_leak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void mem_leak() {
  int *i_leak = malloc(5 * sizeof(int));
  free(i_leak);
}
```
user: Translate the below assembly code into C programming language:

```asm
<isValueEnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x20,-0x4(%rbp)
  je     L44
  cmpb   $0x3a,-0x4(%rbp)
  je     L44
  cmpb   $0x3b,-0x4(%rbp)
  je     L44
  cmpb   $0x5d,-0x4(%rbp)
  je     L44
  cmpb   $0xa,-0x4(%rbp)
  je     L44
  cmpb   $0x9,-0x4(%rbp)
  jne    L33
L44:
  mov    $0x1,%eax
  jmp    L0
L33:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int isValueEnd(char c) {
  if (c == ' ' || c == ':' || c == ';' || c == ']' || c == '\n' || c == '\t')
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isValueEnd>:
  endbr64
  cmp    $0xa,%dil
  jle    L12
  lea    -0x20(%rdi),%ecx
  movabs $0x200000000c000001,%rax
  shr    %cl,%rax
  mov    %eax,%esi
  and    $0x1,%esi
  cmp    $0x3e,%cl
  mov    $0x0,%edx
  cmovb  %esi,%edx
  jmp    L5
L12:
  cmp    $0x8,%dil
  setg   %dl
  movzbl %dl,%edx
L5:
  mov    %edx,%eax
  ret
```

assistant: ```c
int isValueEnd(char c) {
  if (c == ' ' || c == ':' || c == ';' || c == ']' || c == '\n' || c == '\t')
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isValueEnd>:
  endbr64
  cmp    $0xa,%dil
  jle    L1
  movabs $0x200000000c000001,%rax
  lea    -0x20(%rdi),%ecx
  xor    %r8d,%r8d
  shr    %cl,%rax
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x3e,%cl
  cmovb  %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L1:
  xor    %r8d,%r8d
  cmp    $0x8,%dil
  setg   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int isValueEnd(char c) {
  if (c == ' ' || c == ':' || c == ';' || c == ']' || c == '\n' || c == '\t')
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isValueEnd>:
  endbr64
  cmp    $0xa,%dil
  jle    L5
  movabs $0x200000000c000001,%rax
  lea    -0x20(%rdi),%ecx
  xor    %r8d,%r8d
  shr    %cl,%rax
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x3e,%cl
  cmovb  %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L5:
  xor    %r8d,%r8d
  cmp    $0x8,%dil
  setg   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int isValueEnd(char c) {
  if (c == ' ' || c == ':' || c == ';' || c == ']' || c == '\n' || c == '\t')
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <prt@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  prt(0, n, 0, 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    0x4(%rsp),%esi
  mov    $0x0,%edi
  call   <prt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  prt(0, n, 0, 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %edi,%edi
  call   <prt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  prt(0, n, 0, 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %edi,%edi
  call   <prt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  prt(0, n, 0, 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<call_timebox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <arg_rest@plt>
  mov    -0x38(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <optional_num@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <optional_num@plt>
  mov    %eax,%r14d
  mov    -0x30(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <optional_num@plt>
  mov    %eax,%r13d
  mov    -0x30(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <numeric_arg@plt>
  mov    %eax,%r12d
  mov    -0x30(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <numeric_arg@plt>
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rsi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  push   %rbx
  mov    %r14d,%r9d
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %rax,%rdi
  call   <dialog_timebox@plt>
  add    $0x10,%rsp
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int call_timebox(const char *t, char *av[], int *offset_add) {
  *offset_add = arg_rest(av);
  return dialog_timebox(t, av[1], numeric_arg(av, 2), numeric_arg(av, 3), optional_num(av, 4, -1), optional_num(av, 5, -1), optional_num(av, 6, -1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call_timebox>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rsi,%rdi
  call   <arg_rest@plt>
  mov    %eax,(%r12)
  mov    $0xffffffff,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <optional_num@plt>
  mov    %eax,%r15d
  mov    $0xffffffff,%edx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <optional_num@plt>
  mov    %eax,%r14d
  mov    $0xffffffff,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <optional_num@plt>
  mov    %eax,%r13d
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <numeric_arg@plt>
  mov    %eax,%r12d
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <numeric_arg@plt>
  mov    %eax,%edx
  mov    0x8(%rbx),%rsi
  sub    $0x8,%rsp
  push   %r15
  mov    %r14d,%r9d
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  call   <dialog_timebox@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int call_timebox(const char *t, char *av[], int *offset_add) {
  *offset_add = arg_rest(av);
  return dialog_timebox(t, av[1], numeric_arg(av, 2), numeric_arg(av, 3), optional_num(av, 4, -1), optional_num(av, 5, -1), optional_num(av, 6, -1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<call_timebox>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <arg_rest@plt>
  mov    %rbx,%rdi
  mov    $0xffffffff,%edx
  mov    $0x6,%esi
  mov    %eax,(%r12)
  call   <optional_num@plt>
  mov    %rbx,%rdi
  mov    $0xffffffff,%edx
  mov    $0x5,%esi
  mov    %eax,%r15d
  call   <optional_num@plt>
  mov    $0xffffffff,%edx
  mov    %rbx,%rdi
  mov    $0x4,%esi
  mov    %eax,%r14d
  call   <optional_num@plt>
  mov    %rbx,%rdi
  mov    $0x3,%esi
  mov    %eax,%r13d
  call   <numeric_arg@plt>
  mov    %rbx,%rdi
  mov    $0x2,%esi
  mov    %eax,%r12d
  call   <numeric_arg@plt>
  sub    $0x8,%rsp
  mov    0x8(%rbx),%rsi
  mov    %r14d,%r9d
  push   %r15
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <dialog_timebox@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int call_timebox(const char *t, char *av[], int *offset_add) {
  *offset_add = arg_rest(av);
  return dialog_timebox(t, av[1], numeric_arg(av, 2), numeric_arg(av, 3), optional_num(av, 4, -1), optional_num(av, 5, -1), optional_num(av, 6, -1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call_timebox>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <arg_rest@plt>
  mov    %rbx,%rdi
  mov    $0xffffffff,%edx
  mov    $0x6,%esi
  mov    %eax,(%r12)
  call   <optional_num@plt>
  mov    %rbx,%rdi
  mov    $0xffffffff,%edx
  mov    $0x5,%esi
  mov    %eax,%r15d
  call   <optional_num@plt>
  mov    $0xffffffff,%edx
  mov    %rbx,%rdi
  mov    $0x4,%esi
  mov    %eax,%r14d
  call   <optional_num@plt>
  mov    %rbx,%rdi
  mov    $0x3,%esi
  mov    %eax,%r13d
  call   <numeric_arg@plt>
  mov    %rbx,%rdi
  mov    $0x2,%esi
  mov    %eax,%r12d
  call   <numeric_arg@plt>
  sub    $0x8,%rsp
  mov    0x8(%rbx),%rsi
  mov    %r14d,%r9d
  push   %r15
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <dialog_timebox@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int call_timebox(const char *t, char *av[], int *offset_add) {
  *offset_add = arg_rest(av);
  return dialog_timebox(t, av[1], numeric_arg(av, 2), numeric_arg(av, 3), optional_num(av, 4, -1), optional_num(av, 5, -1), optional_num(av, 6, -1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<adpcm8_nodecode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L3
L0:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fputc@plt>
L3:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L0
  nop
  leave
  ret
```

assistant: ```c
int adpcm8_nodecode(FILE *fi, FILE *fo) {
  while (!feof(fi))
    fputc(fgetc(fi), fo);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adpcm8_nodecode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  jmp    L11
L6:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
L11:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int adpcm8_nodecode(FILE *fi, FILE *fo) {
  while (!feof(fi))
    fputc(fgetc(fi), fo);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<adpcm8_nodecode>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
L11:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int adpcm8_nodecode(FILE *fi, FILE *fo) {
  while (!feof(fi))
    fputc(fgetc(fi), fo);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<adpcm8_nodecode>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
L12:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int adpcm8_nodecode(FILE *fi, FILE *fo) {
  while (!feof(fi))
    fputc(fgetc(fi), fo);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L39
  cmpq   $0x0,-0x28(%rbp)
  jne    L9
L39:
  mov    $0x0,%eax
  jmp    L10
L9:
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,D18(%rip)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  lea    (%rax,%rdx,1),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rbx),%eax
  mov    %al,(%rdx)
L2:
  mov    D18(%rip),%rax
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *readline(char *line, int n, FILE *stream) {
  if (line == NULL || stream == NULL) {
    return NULL;
  }
  static char *rs;
  rs = fgets(line, n, stream);
  if (strlen(line) >= 1) {
    line[strlen(line) - 1] = line[strlen(line)];
  }
  return rs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L8
  mov    %rdi,%rbx
  test   %rdx,%rdx
  je     L8
  call   <fgets@plt>
  mov    %rax,%rbp
  cmpb   $0x0,(%rbx)
  je     L27
  mov    %rbx,%rdi
  call   <strlen@plt>
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,-0x1(%rbx,%rax,1)
L27:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x0,%ebp
  jmp    L27
```

assistant: ```c
char *readline(char *line, int n, FILE *stream) {
  if (line == NULL || stream == NULL) {
    return NULL;
  }
  static char *rs;
  rs = fgets(line, n, stream);
  if (strlen(line) >= 1) {
    line[strlen(line) - 1] = line[strlen(line)];
  }
  return rs;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readline>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L29
  test   %rdx,%rdx
  je     L29
  mov    %rdi,%rbx
  call   <fgets@plt>
  cmpb   $0x0,(%rbx)
  mov    %rax,%r12
  je     L18
  mov    %rbx,%rdi
  call   <strlen@plt>
  movb   $0x0,-0x1(%rbx,%rax,1)
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L29:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *readline(char *line, int n, FILE *stream) {
  if (line == NULL || stream == NULL) {
    return NULL;
  }
  static char *rs;
  rs = fgets(line, n, stream);
  if (strlen(line) >= 1) {
    line[strlen(line) - 1] = line[strlen(line)];
  }
  return rs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readline>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
  test   %rdx,%rdx
  je     L2
  mov    %rdi,%rbx
  call   <fgets@plt>
  cmpb   $0x0,(%rbx)
  mov    %rax,%r12
  je     L20
  mov    %rbx,%rdi
  call   <strlen@plt>
  movb   $0x0,-0x1(%rbx,%rax,1)
L20:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *readline(char *line, int n, FILE *stream) {
  if (line == NULL || stream == NULL) {
    return NULL;
  }
  static char *rs;
  rs = fgets(line, n, stream);
  if (strlen(line) >= 1) {
    line[strlen(line) - 1] = line[strlen(line)];
  }
  return rs;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<volatile_fetch_sub_u8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t volatile_fetch_sub_u8(volatile uint8_t *dest, uint8_t val) {
  uint8_t result = *dest;
  *dest = result - val;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<volatile_fetch_sub_u8>:
  endbr64
  mov    %rsi,-0x18(%rsp)
  mov    (%rdi),%rax
  mov    %rax,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    -0x18(%rsp),%rdx
  sub    %rdx,%rax
  mov    %rax,(%rdi)
  mov    -0x8(%rsp),%rax
  ret
```

assistant: ```c
uint8_t volatile_fetch_sub_u8(volatile uint8_t *dest, uint8_t val) {
  uint8_t result = *dest;
  *dest = result - val;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<volatile_fetch_sub_u8>:
  endbr64
  mov    %rsi,-0x18(%rsp)
  mov    (%rdi),%rax
  mov    %rax,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    -0x18(%rsp),%rdx
  sub    %rdx,%rax
  mov    %rax,(%rdi)
  mov    -0x8(%rsp),%rax
  ret
```

assistant: ```c
uint8_t volatile_fetch_sub_u8(volatile uint8_t *dest, uint8_t val) {
  uint8_t result = *dest;
  *dest = result - val;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<volatile_fetch_sub_u8>:
  endbr64
  mov    %rsi,-0x18(%rsp)
  mov    (%rdi),%rax
  mov    %rax,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    -0x18(%rsp),%rdx
  sub    %rdx,%rax
  mov    %rax,(%rdi)
  mov    -0x8(%rsp),%rax
  ret
```

assistant: ```c
uint8_t volatile_fetch_sub_u8(volatile uint8_t *dest, uint8_t val) {
  uint8_t result = *dest;
  *dest = result - val;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f@plt>
  cmp    $0x3,%eax
  je     L1
  mov    $0x0,%eax
  call   <abort@plt>
L1:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (f() != 3) {
    abort();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  cmp    $0x3,%eax
  jne    L11
L8:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L11:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L8
```

assistant: ```c
int main() {
  if (f() != 3) {
    abort();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  cmp    $0x3,%eax
  je     L6
  xor    %eax,%eax
  call   <abort@plt>
L6:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (f() != 3) {
    abort();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  cmp    $0x3,%eax
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (f() != 3) {
    abort();
  }
}
```