user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x114(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x114(%rbp)
  call   <scanf@plt>
  movslq -0x114(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x5,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  sub    %rsi,%rcx
  cmp    %rcx,%rsp
  je     L90
L110:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L110
L90:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L121
L35:
  mov    %rsp,%rbx
  mov    %rbx,-0x128(%rbp)
  test   %edx,%edx
  jle    L180
  xor    %r14d,%r14d
  lea    -0xa0(%rbp),%r12
  lea    D28(%rip),%r15
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %r12,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  xor    %r13d,%r13d
  call   <scanf@plt>
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L102:
  movsbq (%r12,%r13,1),%rax
  mov    %rax,(%rbx,%r13,8)
  add    $0x1,%r13
L71:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %r13,%rax
  ja     L102
  movslq %r14d,%rdx
  add    $0x1,%r14d
  add    $0x320,%rbx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,4),%rax
  mov    -0x128(%rbp),%rdx
  movq   $0x0,(%rdx,%rax,8)
  mov    -0x114(%rbp),%edx
  cmp    %r14d,%edx
  jg     L62
  lea    -0x110(%rbp),%r8
  mov    $0xd,%ecx
  xor    %eax,%eax
  mov    %r8,%rdi
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L100
  mov    -0x128(%rbp),%r13
  movslq %edx,%r9
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L115:
  mov    0x0(%r13),%rax
  lea    0x1(%rsi),%edi
  mov    %r13,%rcx
  test   %rax,%rax
  jne    L172
  jmp    L175
  nopl   0x0(%rax)
L182:
  cmp    %esi,-0x110(%rbp,%rax,4)
  jne    L92
  mov    %edi,-0x110(%rbp,%rax,4)
L92:
  mov    0x8(%rcx),%rax
  add    $0x8,%rcx
  test   %rax,%rax
  je     L175
L172:
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  test   %rsi,%rsi
  jne    L182
  movl   $0x1,-0x110(%rbp,%rax,4)
  mov    0x8(%rcx),%rax
  add    $0x8,%rcx
  test   %rax,%rax
  jne    L172
L175:
  add    $0x1,%rsi
  add    $0x320,%r13
  cmp    %r9,%rsi
  jne    L115
L100:
  mov    %r8,%rdi
  lea    -0xa8(%rbp),%rcx
  xor    %esi,%esi
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  sete   %al
  add    $0x4,%rdi
  add    %eax,%esi
  cmp    %rdi,%rcx
  jne    L8
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L121:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L35
L180:
  lea    -0x110(%rbp),%r8
  mov    $0x1a,%ecx
  xor    %eax,%eax
  mov    %r8,%rdi
  rep stos %eax,%es:(%rdi)
  jmp    L100
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string

tool: D5: %d


tool: D28: %s

assistant: ```c
int main() {
  int a = 0;
  scanf("%d\n", &a);
  char *s[a][100];
  int i = 0;
  int j = 0;
  int count = 0;
  int hashtable[26];
  for (; i < a; i++) {
    char word[100];
    scanf("%s", word);
    for (j = 0; j < strlen(word); j++)
      s[i][j] = word[j];
    s[i][strlen(word)] = '\0';
  }
  for (i = 0; i < 26; i++)
    hashtable[i] = 0;
  for (i = 0; i < a; i++) {
    for (j = 0; s[i][j] != '\0'; j++) {
      char c = s[i][j];
      int temp = ((int)c - 97);
      int t = i;
      if (t == 0)
        hashtable[temp] = t + 1;
      else {
        if (hashtable[temp] == t)
          hashtable[temp] = t + 1;
      }
    }
  }
  for (i = 0; i < 26; i++) {
    if (hashtable[i] == a) {
      count++;
    }
  }
  printf("%d\n", count);
  return 0;
}
```