ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x1,-0x20(%rbp)
  jmp    L48
L28:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L2
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <som@plt>
  movq   %xmm0,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fat@plt>
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  jmp    L47
L2:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <som@plt>
  movq   %xmm0,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fat@plt>
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
L47:
  addq   $0x1,-0x20(%rbp)
L48:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x20(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L28
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D28
type_guessed: string

tool: D17: Este programa foi escrito por Jessica Cristina Cacau Patricio.


tool: D27: Digite um inteiro positivo: 

tool: D1: %lf

tool: D28: 
Total = %.15lf


assistant: ```c
void main() {
  printf("Este programa foi escrito por Jessica Cristina Cacau Patricio.\n\n");
  double num, total = 0.0;
  long long int i;
  printf("Digite um inteiro positivo: ");
  scanf("%lf", &num);
  for (i = 1; i <= num; i++) {
    if (i % 2 == 0)
      total -= som(i) / fat(i);
    else
      total += som(i) / fat(i);
  }
  printf("\nTotal = %.15lf\n", total);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D43(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  comisd D7(%rip),%xmm0
  jb     L18
  mov    $0x1,%ebx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L57:
  call   <som@plt>
  mov    %rbx,%rdi
  movsd  %xmm0,(%rsp)
  call   <fat@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm0,%xmm1
  subsd  %xmm1,%xmm2
L23:
  add    $0x1,%rbx
  pxor   %xmm0,%xmm0
  movsd  0x10(%rsp),%xmm1
  cvtsi2sd %rbx,%xmm0
  comisd %xmm0,%xmm1
  jb     L18
L8:
  movsd  %xmm2,0x8(%rsp)
  mov    %rbx,%rdi
  test   $0x1,%bl
  je     L57
  call   <som@plt>
  mov    %rbx,%rdi
  movsd  %xmm0,(%rsp)
  call   <fat@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm2
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L18:
  movapd %xmm2,%xmm0
  lea    D25(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x20,%rsp
  pop    %rbx
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D43
datatype: string
name: retrieve_data
arguments: data_tag: D33
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string
name: retrieve_data
arguments: data_tag: D7
datatype: f32
name: retrieve_data
arguments: data_tag: D25
datatype: string

tool: D43: Este programa foi escrito por Jessica Cristina Cacau Patricio.


tool: D33: Digite um inteiro positivo: 

tool: D13: %lf

tool: D7: 0

tool: D25: 
Total = %.15lf


assistant: ```c
void main() {
  printf("Este programa foi escrito por Jessica Cristina Cacau Patricio.\n\n");
  double num, total = 0.0;
  long long int i;
  printf("Digite um inteiro positivo: ");
  scanf("%lf", &num);
  for (i = 1; i <= num; i++) {
    if (i % 2 == 0)
      total -= som(i) / fat(i);
    else
      total += som(i) / fat(i);
  }
  printf("\nTotal = %.15lf\n", total);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  mov    $0x1,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  comisd D32(%rip),%xmm0
  jae    L57
  jmp    L54
  nop
L4:
  call   <som@plt>
  mov    %rbx,%rdi
  movsd  %xmm0,(%rsp)
  call   <fat@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm0,%xmm1
  subsd  %xmm1,%xmm2
L9:
  add    $0x1,%rbx
  pxor   %xmm0,%xmm0
  movsd  0x10(%rsp),%xmm1
  cvtsi2sd %rbx,%xmm0
  comisd %xmm0,%xmm1
  jb     L54
L57:
  movsd  %xmm2,0x8(%rsp)
  mov    %rbx,%rdi
  test   $0x1,%bl
  je     L4
  call   <som@plt>
  mov    %rbx,%rdi
  movsd  %xmm0,(%rsp)
  call   <fat@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm2
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L54:
  movapd %xmm2,%xmm0
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D13
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D33
type_infered: string
name: read_data
arguments: data_label: D32
type_infered: f32
name: read_data
arguments: data_label: D30
type_infered: string

tool: D13: Este programa foi escrito por Jessica Cristina Cacau Patricio.


tool: D0: Digite um inteiro positivo: 

tool: D33: %lf

tool: D32: 0

tool: D30: 
Total = %.15lf


assistant: ```c
void main() {
  printf("Este programa foi escrito por Jessica Cristina Cacau Patricio.\n\n");
  double num, total = 0.0;
  long long int i;
  printf("Digite um inteiro positivo: ");
  scanf("%lf", &num);
  for (i = 1; i <= num; i++) {
    if (i % 2 == 0)
      total -= som(i) / fat(i);
    else
      total += som(i) / fat(i);
  }
  printf("\nTotal = %.15lf\n", total);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmp_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L7
  cmpl   $0x3,-0x4(%rbp)
  jg     L51
  cmpl   $0x2,-0x4(%rbp)
  je     L55
  cmpl   $0x2,-0x4(%rbp)
  jg     L51
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  cmpl   $0x1,-0x4(%rbp)
  je     L36
  jmp    L51
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <intcmp@plt>
  jmp    L8
L36:
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <fltcmp@plt>
  jmp    L8
L55:
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dblcmp@plt>
  jmp    L8
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  jmp    L8
L51:
  mov    $0xfffffffe,%eax
L8:
  leave
  ret
```

assistant: ```c
int cmp_values(int value_type, void *v1, void *v2) {
  switch (value_type) {
  case 0:
    return intcmp(*(int *)v1, *(int *)v2);
  case 1:
    return fltcmp(*(float *)v1, *(float *)v2);
  case 2:
    return dblcmp(*(double *)v1, *(double *)v2);
  case 3:
    return strcmp(v1, v2);
  default:
    return -2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmp_values>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x2,%eax
  je     L32
  jg     L55
  test   %eax,%eax
  je     L36
  cmp    $0x1,%eax
  jne    L43
  movss  (%rdx),%xmm1
  movss  (%rsi),%xmm0
  call   <fltcmp@plt>
  jmp    L92
L43:
  mov    $0xfffffffe,%eax
  jmp    L92
L55:
  cmp    $0x3,%eax
  jne    L72
  mov    %rdx,%rsi
  call   <strcmp@plt>
  jmp    L92
L72:
  mov    $0xfffffffe,%eax
L92:
  add    $0x8,%rsp
  ret
L36:
  mov    (%rdx),%esi
  mov    (%rdi),%edi
  call   <intcmp@plt>
  jmp    L92
L32:
  movsd  (%rdx),%xmm1
  movsd  (%rsi),%xmm0
  call   <dblcmp@plt>
  jmp    L92
```

assistant: ```c
int cmp_values(int value_type, void *v1, void *v2) {
  switch (value_type) {
  case 0:
    return intcmp(*(int *)v1, *(int *)v2);
  case 1:
    return fltcmp(*(float *)v1, *(float *)v2);
  case 2:
    return dblcmp(*(double *)v1, *(double *)v2);
  case 3:
    return strcmp(v1, v2);
  default:
    return -2;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmp_values>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x2,%eax
  je     L41
  jg     L19
  test   %eax,%eax
  je     L46
  cmp    $0x1,%eax
  jne    L44
  movss  (%rdx),%xmm1
  movss  (%rsi),%xmm0
  jmp    10b0 <fltcmp@plt>
  cs nopw 0x0(%rax,%rax,1)
L19:
  cmp    $0x3,%eax
  jne    L44
  mov    %rdx,%rsi
  jmp    10a0 <strcmp@plt>
  nopl   (%rax)
L41:
  movsd  (%rdx),%xmm1
  movsd  (%rsi),%xmm0
  jmp    1090 <dblcmp@plt>
  nopl   (%rax)
L44:
  mov    $0xfffffffe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    (%rdx),%esi
  mov    (%rdi),%edi
  jmp    1080 <intcmp@plt>
```

assistant: ```c
int cmp_values(int value_type, void *v1, void *v2) {
  switch (value_type) {
  case 0:
    return intcmp(*(int *)v1, *(int *)v2);
  case 1:
    return fltcmp(*(float *)v1, *(float *)v2);
  case 2:
    return dblcmp(*(double *)v1, *(double *)v2);
  case 3:
    return strcmp(v1, v2);
  default:
    return -2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp_values>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x2,%eax
  je     L10
  jg     L27
  test   %eax,%eax
  je     L16
  cmp    $0x1,%eax
  jne    L9
  movss  (%rdx),%xmm1
  movss  (%rsi),%xmm0
  jmp    10b0 <fltcmp@plt>
  cs nopw 0x0(%rax,%rax,1)
L27:
  cmp    $0x3,%eax
  jne    L9
  mov    %rdx,%rsi
  jmp    10a0 <strcmp@plt>
  nopl   (%rax)
L10:
  movsd  (%rdx),%xmm1
  movsd  (%rsi),%xmm0
  jmp    1090 <dblcmp@plt>
  nopl   (%rax)
L9:
  mov    $0xfffffffe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    (%rdx),%esi
  mov    (%rdi),%edi
  jmp    1080 <intcmp@plt>
```

assistant: ```c
int cmp_values(int value_type, void *v1, void *v2) {
  switch (value_type) {
  case 0:
    return intcmp(*(int *)v1, *(int *)v2);
  case 1:
    return fltcmp(*(float *)v1, *(float *)v2);
  case 2:
    return dblcmp(*(double *)v1, *(double *)v2);
  case 3:
    return strcmp(v1, v2);
  default:
    return -2;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_part>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x4,-0x4(%rbp)
  jle    L16
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string
name: read_data
arguments: label: D17
type_guessed: string

tool: D0: ----in func print_part----

tool: D17: array [ i = %d ] = %d;


assistant: ```c
void print_part(int *arr) {
  int i = 0;
  printf("----in func print_part----\n");
  for (i = 0; i < 5; i++) {
    printf("array [ i = %d ] = %d;\n", i, arr[i]);
  };
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_part>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D8(%rip),%r12
L4:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D14: ----in func print_part----

tool: D8: array [ i = %d ] = %d;


assistant: ```c
void print_part(int *arr) {
  int i = 0;
  printf("----in func print_part----\n");
  for (i = 0; i < 5; i++) {
    printf("array [ i = %d ] = %d;\n", i, arr[i]);
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_part>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D16(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
L0:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D16
type_guessed: string

tool: D4: array [ i = %d ] = %d;


tool: D16: ----in func print_part----

assistant: ```c
void print_part(int *arr) {
  int i = 0;
  printf("----in func print_part----\n");
  for (i = 0; i < 5; i++) {
    printf("array [ i = %d ] = %d;\n", i, arr[i]);
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_part>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D19(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
L0:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D19
type_infered: string

tool: D6: array [ i = %d ] = %d;


tool: D19: ----in func print_part----

assistant: ```c
void print_part(int *arr) {
  int i = 0;
  printf("----in func print_part----\n");
  for (i = 0; i < 5; i++) {
    printf("array [ i = %d ] = %d;\n", i, arr[i]);
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqUTF8ToUTF32Iterate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L72
  mov    -0x18(%rbp),%rax
  jmp    L83
L72:
  addq   $0x1,-0x18(%rbp)
  cmpl   $0x7f,-0x10(%rbp)
  ja     L45
  mov    -0x10(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L83
L45:
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L48:
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0x10(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L48
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shrl   %cl,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  subl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L50
  mov    -0x18(%rbp),%rax
  jmp    L83
L50:
  addq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x6,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    $0x3f,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jb     L38
  mov    -0x18(%rbp),%rax
L83:
  pop    %rbp
  ret
```

assistant: ```c
const char *sqUTF8ToUTF32Iterate(const char *string, int *dest) {
  unsigned int first;
  unsigned int sequenceSize;
  unsigned int i;
  unsigned int byte;
  *dest = 0;
  first = (*string) & 0xFF;
  if (first == 0)
    return string;
  ++string;
  if (first <= 127) {
    *dest = first;
    return string;
  }
  sequenceSize = 0;
  while (first & 0x80) {
    first = (first << 1) & 0xFF;
    ++sequenceSize;
  }
  first >>= sequenceSize;
  *dest = first;
  --sequenceSize;
  for (i = 0; i < sequenceSize; ++i) {
    byte = *string;
    if (!byte)
      return string;
    ++string;
    *dest = (*dest << 6) | (byte & 63);
  }
  return string;
}
```
user: What is the c source code of the assembly code below?

```asm
<sqUTF8ToUTF32Iterate>:
  endbr64
  movl   $0x0,(%rsi)
  movzbl (%rdi),%eax
  movzbl %al,%edx
  mov    %rdi,%r8
  test   %edx,%edx
  je     L51
  lea    0x1(%rdi),%r8
  mov    $0x0,%ecx
  test   %al,%al
  jns    L2
L62:
  lea    (%rdx,%rdx,1),%eax
  movzbl %al,%edx
  mov    %ecx,%edi
  add    $0x1,%ecx
  and    $0x80,%eax
  jne    L62
  shr    %cl,%edx
  mov    %edx,(%rsi)
  test   %edi,%edi
  je     L51
L33:
  movzbl (%r8),%ecx
  test   %cl,%cl
  je     L51
  add    $0x1,%r8
  mov    (%rsi),%edx
  shl    $0x6,%edx
  and    $0x3f,%ecx
  or     %ecx,%edx
  mov    %edx,(%rsi)
  add    $0x1,%eax
  cmp    %edi,%eax
  jb     L33
  jmp    L51
L2:
  mov    %edx,(%rsi)
L51:
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *sqUTF8ToUTF32Iterate(const char *string, int *dest) {
  unsigned int first;
  unsigned int sequenceSize;
  unsigned int i;
  unsigned int byte;
  *dest = 0;
  first = (*string) & 0xFF;
  if (first == 0)
    return string;
  ++string;
  if (first <= 127) {
    *dest = first;
    return string;
  }
  sequenceSize = 0;
  while (first & 0x80) {
    first = (first << 1) & 0xFF;
    ++sequenceSize;
  }
  first >>= sequenceSize;
  *dest = first;
  --sequenceSize;
  for (i = 0; i < sequenceSize; ++i) {
    byte = *string;
    if (!byte)
      return string;
    ++string;
    *dest = (*dest << 6) | (byte & 63);
  }
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sqUTF8ToUTF32Iterate>:
  endbr64
  movl   $0x0,(%rsi)
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %eax,%eax
  je     L67
  add    $0x1,%r8
  xor    %ecx,%ecx
  test   %al,%al
  jns    L41
  xchg   %ax,%ax
L17:
  lea    (%rax,%rax,1),%edx
  mov    %ecx,%r9d
  add    $0x1,%ecx
  movzbl %dl,%eax
  and    $0x80,%edx
  jne    L17
  shr    %cl,%eax
  mov    %eax,(%rsi)
  test   %r9d,%r9d
  je     L67
  lea    -0x1(%r9),%eax
  lea    0x2(%rdi,%rax,1),%rcx
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L23:
  mov    (%rsi),%eax
  and    $0x3f,%edx
  add    $0x1,%r8
  shl    $0x6,%eax
  or     %edx,%eax
  mov    %eax,(%rsi)
  cmp    %r8,%rcx
  je     L67
L65:
  movzbl (%r8),%edx
  test   %dl,%dl
  jne    L23
L67:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L41:
  mov    %eax,(%rsi)
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *sqUTF8ToUTF32Iterate(const char *string, int *dest) {
  unsigned int first;
  unsigned int sequenceSize;
  unsigned int i;
  unsigned int byte;
  *dest = 0;
  first = (*string) & 0xFF;
  if (first == 0)
    return string;
  ++string;
  if (first <= 127) {
    *dest = first;
    return string;
  }
  sequenceSize = 0;
  while (first & 0x80) {
    first = (first << 1) & 0xFF;
    ++sequenceSize;
  }
  first >>= sequenceSize;
  *dest = first;
  --sequenceSize;
  for (i = 0; i < sequenceSize; ++i) {
    byte = *string;
    if (!byte)
      return string;
    ++string;
    *dest = (*dest << 6) | (byte & 63);
  }
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqUTF8ToUTF32Iterate>:
  endbr64
  movl   $0x0,(%rsi)
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %eax,%eax
  je     L21
  add    $0x1,%r8
  xor    %ecx,%ecx
  test   %al,%al
  jns    L19
  xchg   %ax,%ax
L5:
  lea    (%rax,%rax,1),%edx
  mov    %ecx,%r9d
  add    $0x1,%ecx
  movzbl %dl,%eax
  and    $0x80,%edx
  jne    L5
  shr    %cl,%eax
  mov    %eax,(%rsi)
  test   %r9d,%r9d
  je     L21
  lea    -0x1(%r9),%eax
  lea    0x2(%rdi,%rax,1),%rcx
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L65:
  mov    (%rsi),%eax
  and    $0x3f,%edx
  add    $0x1,%r8
  shl    $0x6,%eax
  or     %edx,%eax
  mov    %eax,(%rsi)
  cmp    %rcx,%r8
  je     L21
L22:
  movzbl (%r8),%edx
  test   %dl,%dl
  jne    L65
L21:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L19:
  mov    %eax,(%rsi)
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *sqUTF8ToUTF32Iterate(const char *string, int *dest) {
  unsigned int first;
  unsigned int sequenceSize;
  unsigned int i;
  unsigned int byte;
  *dest = 0;
  first = (*string) & 0xFF;
  if (first == 0)
    return string;
  ++string;
  if (first <= 127) {
    *dest = first;
    return string;
  }
  sequenceSize = 0;
  while (first & 0x80) {
    first = (first << 1) & 0xFF;
    ++sequenceSize;
  }
  first >>= sequenceSize;
  *dest = first;
  --sequenceSize;
  for (i = 0; i < sequenceSize; ++i) {
    byte = *string;
    if (!byte)
      return string;
    ++string;
    *dest = (*dest << 6) | (byte & 63);
  }
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<aVeryBigSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L2
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long int aVeryBigSum(int n, int ar_size, long int *ar) {
  long int result = 0;
  for (int i = 0; i < ar_size; i++) {
    result += *(ar + i);
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<aVeryBigSum>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    %rdx,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x8(%rdx,%rcx,8),%rcx
  mov    $0x0,%edx
L2:
  add    (%rax),%rdx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L2
L3:
  mov    %rdx,%rax
  ret
L8:
  mov    $0x0,%edx
  jmp    L3
```

assistant: ```c
long int aVeryBigSum(int n, int ar_size, long int *ar) {
  long int result = 0;
  for (int i = 0; i < ar_size; i++) {
    result += *(ar + i);
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<aVeryBigSum>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdx,%rax,8),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  add    (%rdx),%rax
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L2
  ret
  nopl   (%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
long int aVeryBigSum(int n, int ar_size, long int *ar) {
  long int result = 0;
  for (int i = 0; i < ar_size; i++) {
    result += *(ar + i);
  }
  return result;
}
```