ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtolower>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L17
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L35
  movzbl (%rsi),%edi
  mov    $0x0,%ebx
  mov    $0x0,%eax
  test   %dil,%dil
  je     L41
L47:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  mov    %rbx,%rax
  movzbl (%r12,%rbx,1),%edi
  test   %dil,%dil
  jne    L47
L41:
  movb   $0x0,0x0(%rbp,%rax,1)
L17:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  movb   $0x0,(%rdi)
  jmp    L17
```

assistant: ```c
char *strtolower(char *target, char *source) {
  long i;
  if (target == NULL)
    return NULL;
  if (source == NULL)
    target[0] = '\0';
  else {
    for (i = 0; source[i] != '\0'; i++)
      target[i] = tolower(source[i]);
    target[i] = '\0';
  }
  return target;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtolower>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L46
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L34
  movsbl (%rsi),%edi
  xor    %ebx,%ebx
  test   %dil,%dil
  je     L9
  nopw   0x0(%rax,%rax,1)
L32:
  call   <tolower@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L32
  add    %r12,%rbx
L19:
  movb   $0x0,(%rbx)
L46:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L34:
  movb   $0x0,(%rdi)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rbx
  jmp    L19
```

assistant: ```c
char *strtolower(char *target, char *source) {
  long i;
  if (target == NULL)
    return NULL;
  if (source == NULL)
    target[0] = '\0';
  else {
    for (i = 0; source[i] != '\0'; i++)
      target[i] = tolower(source[i]);
    target[i] = '\0';
  }
  return target;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtolower>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L44
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L24
  movsbl (%rsi),%edi
  xor    %ebx,%ebx
  test   %dil,%dil
  je     L20
  nopw   0x0(%rax,%rax,1)
L8:
  call   <tolower@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L8
  add    %r12,%rbx
L40:
  movb   $0x0,(%rbx)
L44:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L24:
  movb   $0x0,(%rdi)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r12,%rbx
  jmp    L40
```

assistant: ```c
char *strtolower(char *target, char *source) {
  long i;
  if (target == NULL)
    return NULL;
  if (source == NULL)
    target[0] = '\0';
  else {
    for (i = 0; source[i] != '\0'; i++)
      target[i] = tolower(source[i]);
    target[i] = '\0';
  }
  return target;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bubble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L21:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L48
L39:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L41
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L41:
  addl   $0x1,-0x8(%rbp)
L48:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L39
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble(int c[], int d) {
  int x, i, j;
  for (i = 0; i < d; i++) {
    for (j = i; j < d - i - 1; j++) {
      if (c[j] > c[j + 1]) {
        x = c[j];
        c[j] = c[j + 1];
        c[j + 1] = x;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bubble>:
  endbr64
  test   %esi,%esi
  jle    L46
  push   %rbx
  lea    -0x2(%rsi),%r9d
  mov    $0xfffffffe,%ebx
  sub    %esi,%ebx
  mov    %rdi,%r10
  mov    $0x0,%r8d
  lea    -0x1(%rsi),%r11d
  add    $0x4,%rdi
  jmp    L7
L71:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L49
L8:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L71
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L71
L49:
  add    $0x1,%r8
  add    $0x4,%r10
  sub    $0x2,%r9d
  cmp    %ebx,%r9d
  je     L15
L7:
  mov    %r11d,%eax
  sub    %r8d,%eax
  cmp    %r8d,%eax
  jle    L49
  mov    %r9d,%eax
  add    %r8,%rax
  lea    (%rdi,%rax,4),%rsi
  mov    %r10,%rax
  jmp    L8
L15:
  pop    %rbx
  ret
L46:
  ret
```

assistant: ```c
void bubble(int c[], int d) {
  int x, i, j;
  for (i = 0; i < d; i++) {
    for (j = i; j < d - i - 1; j++) {
      if (c[j] > c[j + 1]) {
        x = c[j];
        c[j] = c[j + 1];
        c[j + 1] = x;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bubble>:
  endbr64
  test   %esi,%esi
  jle    L44
  mov    $0xfffffffe,%r10d
  push   %rbx
  lea    -0x2(%rsi),%r9d
  xor    %r8d,%r8d
  sub    %esi,%r10d
  lea    -0x1(%rsi),%r11d
  lea    0x4(%rdi),%rbx
  nopl   0x0(%rax)
L32:
  mov    %r11d,%eax
  sub    %r8d,%eax
  cmp    %r8d,%eax
  jle    L12
  mov    %r9d,%eax
  add    %r8,%rax
  lea    (%rbx,%rax,4),%rsi
  mov    %rdi,%rax
L19:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L36
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L36:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L19
L12:
  sub    $0x2,%r9d
  add    $0x1,%r8
  add    $0x4,%rdi
  cmp    %r10d,%r9d
  jne    L32
  pop    %rbx
  ret
L44:
  ret
```

assistant: ```c
void bubble(int c[], int d) {
  int x, i, j;
  for (i = 0; i < d; i++) {
    for (j = i; j < d - i - 1; j++) {
      if (c[j] > c[j + 1]) {
        x = c[j];
        c[j] = c[j + 1];
        c[j + 1] = x;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bubble>:
  endbr64
  test   %esi,%esi
  jle    L2
  mov    $0xfffffffe,%r10d
  push   %rbx
  lea    -0x2(%rsi),%r9d
  xor    %r8d,%r8d
  sub    %esi,%r10d
  lea    -0x1(%rsi),%r11d
  lea    0x4(%rdi),%rbx
  nopl   0x0(%rax)
L27:
  mov    %r11d,%eax
  sub    %r8d,%eax
  cmp    %r8d,%eax
  jle    L30
  mov    %r9d,%eax
  mov    %rdi,%rdx
  add    %r8,%rax
  lea    (%rbx,%rax,4),%rsi
L36:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L11
  movq   %xmm1,(%rdx)
L11:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L36
L30:
  sub    $0x2,%r9d
  add    $0x1,%r8
  add    $0x4,%rdi
  cmp    %r10d,%r9d
  jne    L27
  pop    %rbx
  ret
L2:
  ret
```

assistant: ```c
void bubble(int c[], int d) {
  int x, i, j;
  for (i = 0; i < d; i++) {
    for (j = i; j < d - i - 1; j++) {
      if (c[j] > c[j + 1]) {
        x = c[j];
        c[j] = c[j + 1];
        c[j + 1] = x;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<get_sample>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x20(%rbp)
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void get_sample(char *src, int src_len, char *dst, int dst_len) {
  assert(dst_len <= src_len);
  int segment_len = src_len / dst_len;
  int dst_index = 0;
  int i = 0;
  for (i = 0; i <= src_len; i += segment_len) {
    int offset = rand() % segment_len;
    dst[dst_index++] = src[i + offset];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_sample>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  cmp    %esi,%ecx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r13d,%eax
  cltd
  idiv   %ebx
  test   %r13d,%r13d
  js     L18
  mov    %eax,%r15d
  mov    %eax,%r12d
  mov    $0x0,%ebx
L5:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %r12d
  add    %ebx,%edx
  movslq %edx,%rdx
  movzbl (%r14,%rdx,1),%eax
  mov    %al,0x0(%rbp)
  add    %r15d,%ebx
  add    $0x1,%rbp
  cmp    %ebx,%r13d
  jge    L5
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void get_sample(char *src, int src_len, char *dst, int dst_len) {
  assert(dst_len <= src_len);
  int segment_len = src_len / dst_len;
  int dst_index = 0;
  int i = 0;
  for (i = 0; i <= src_len; i += segment_len) {
    int offset = rand() % segment_len;
    dst[dst_index++] = src[i + offset];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_sample>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  cmp    %esi,%ecx
  push   %rbp
  setle  %dil
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <assert@plt>
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %ebp,%ebp
  js     L16
  mov    %eax,%ebx
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  add    $0x1,%r14
  call   <rand@plt>
  cltd
  idiv   %ebx
  add    %r13d,%edx
  add    %ebx,%r13d
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%eax
  mov    %al,-0x1(%r14)
  cmp    %r13d,%ebp
  jge    L14
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void get_sample(char *src, int src_len, char *dst, int dst_len) {
  assert(dst_len <= src_len);
  int segment_len = src_len / dst_len;
  int dst_index = 0;
  int i = 0;
  for (i = 0; i <= src_len; i += segment_len) {
    int offset = rand() % segment_len;
    dst[dst_index++] = src[i + offset];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_sample>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  cmp    %esi,%ecx
  push   %rbp
  setle  %dil
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <assert@plt>
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %ebp,%ebp
  js     L4
  mov    %eax,%ebx
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  add    $0x1,%r14
  call   <rand@plt>
  cltd
  idiv   %ebx
  add    %r13d,%edx
  add    %ebx,%r13d
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%eax
  mov    %al,-0x1(%r14)
  cmp    %r13d,%ebp
  jge    L18
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void get_sample(char *src, int src_len, char *dst, int dst_len) {
  assert(dst_len <= src_len);
  int segment_len = src_len / dst_len;
  int dst_index = 0;
  int i = 0;
  for (i = 0; i <= src_len; i += segment_len) {
    int offset = rand() % segment_len;
    dst[dst_index++] = src[i + offset];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<serial_putc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0xa,-0x4(%rbp)
  jne    L5
  nop
L24:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  and    $0x200000,%eax
  test   %eax,%eax
  jne    L24
  mov    $0xf31004c0,%esi
  mov    $0xd,%edi
  call   <writel@plt>
L5:
  nop
L14:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  and    $0x200000,%eax
  test   %eax,%eax
  jne    L14
  movsbl -0x4(%rbp),%eax
  mov    $0xf31004c0,%esi
  mov    %eax,%edi
  call   <writel@plt>
  nop
  leave
  ret
```

assistant: ```c
void serial_putc(const char c) {
  if (c == '\n') {
    while ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 21)))
      ;
    writel('\r', (0xf3100000 + (((0x01 << 10) | (0x30 << 2)))));
  }
  while ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 21)))
    ;
  writel(c, (0xf3100000 + (((0x01 << 10) | (0x30 << 2)))));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<serial_putc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xa,%dil
  je     L26
L11:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x200000,%eax
  jne    L11
  movsbl %bl,%edi
  mov    $0xf31004c0,%esi
  call   <writel@plt>
  pop    %rbx
  ret
L26:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x200000,%eax
  jne    L26
  mov    $0xf31004c0,%esi
  mov    $0xd,%edi
  call   <writel@plt>
  jmp    L11
```

assistant: ```c
void serial_putc(const char c) {
  if (c == '\n') {
    while ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 21)))
      ;
    writel('\r', (0xf3100000 + (((0x01 << 10) | (0x30 << 2)))));
  }
  while ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 21)))
    ;
  writel(c, (0xf3100000 + (((0x01 << 10) | (0x30 << 2)))));
}
```
user: What is the c source code of the assembly code below?

```asm
<serial_putc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xa,%dil
  je     L16
  nopl   (%rax)
L18:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x200000,%eax
  jne    L18
  movsbl %bl,%edi
  mov    $0xf31004c0,%esi
  pop    %rbx
  jmp    1070 <writel@plt>
  nop
L16:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x200000,%eax
  jne    L16
  mov    $0xf31004c0,%esi
  mov    $0xd,%edi
  call   <writel@plt>
  jmp    L18
```

assistant: ```c
void serial_putc(const char c) {
  if (c == '\n') {
    while ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 21)))
      ;
    writel('\r', (0xf3100000 + (((0x01 << 10) | (0x30 << 2)))));
  }
  while ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 21)))
    ;
  writel(c, (0xf3100000 + (((0x01 << 10) | (0x30 << 2)))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serial_putc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xa,%dil
  je     L18
  nopl   (%rax)
L36:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x200000,%eax
  jne    L36
  movsbl %bl,%edi
  mov    $0xf31004c0,%esi
  pop    %rbx
  jmp    1070 <writel@plt>
  nop
L18:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x200000,%eax
  jne    L18
  mov    $0xf31004c0,%esi
  mov    $0xd,%edi
  call   <writel@plt>
  jmp    L36
```

assistant: ```c
void serial_putc(const char c) {
  if (c == '\n') {
    while ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 21)))
      ;
    writel('\r', (0xf3100000 + (((0x01 << 10) | (0x30 << 2)))));
  }
  while ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 21)))
    ;
  writel(c, (0xf3100000 + (((0x01 << 10) | (0x30 << 2)))));
}
```
user: What is the c source code of the assembly code below?

```asm
<getpwnam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: getpwnam: not implemented

assistant: ```c
struct passwd *getpwnam(const char *name) {
  (void)name;
  puts("getpwnam: not implemented");
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getpwnam>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: getpwnam: not implemented

assistant: ```c
struct passwd *getpwnam(const char *name) {
  (void)name;
  puts("getpwnam: not implemented");
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getpwnam>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: getpwnam: not implemented

assistant: ```c
struct passwd *getpwnam(const char *name) {
  (void)name;
  puts("getpwnam: not implemented");
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getpwnam>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: getpwnam: not implemented

assistant: ```c
struct passwd *getpwnam(const char *name) {
  (void)name;
  puts("getpwnam: not implemented");
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<caller>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <unknown_isa_trait@plt>
  mov    $0x0,%eax
  call   <unknown_isa_trait2@plt>
  mov    $0x0,%eax
  call   <ignored_isa_trait@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void caller() {
  unknown_isa_trait();
  unknown_isa_trait2();
  ignored_isa_trait();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<caller>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <unknown_isa_trait@plt>
  mov    $0x0,%eax
  call   <unknown_isa_trait2@plt>
  mov    $0x0,%eax
  call   <ignored_isa_trait@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void caller() {
  unknown_isa_trait();
  unknown_isa_trait2();
  ignored_isa_trait();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<caller>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <unknown_isa_trait@plt>
  xor    %eax,%eax
  call   <unknown_isa_trait2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <ignored_isa_trait@plt>
```

assistant: ```c
void caller() {
  unknown_isa_trait();
  unknown_isa_trait2();
  ignored_isa_trait();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<caller>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <unknown_isa_trait@plt>
  xor    %eax,%eax
  call   <unknown_isa_trait2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <ignored_isa_trait@plt>
```

assistant: ```c
void caller() {
  unknown_isa_trait();
  unknown_isa_trait2();
  ignored_isa_trait();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<idct_perform32_fixed>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdi,%r13
  lea    0x80(%rdi),%r14
  mov    %rdi,%rbx
  mov    $0x0,%r15d
L2:
  mov    (%rbx),%edi
  call   <abs@plt>
  add    %eax,%r15d
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L2
  cmp    $0x400000,%r15d
  setg   %bl
  movzbl %bl,%ebx
  add    %ebx,%ebx
L4:
  mov    %ebx,%eax
  add    0x0(%r13),%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  mov    %eax,0x0(%r13)
  add    $0x4,%r13
  cmp    %r14,%r13
  jne    L4
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <sum_a@plt>
  lea    0x40(%rbp),%r13
  mov    $0x10,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sum_b@plt>
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <clp_v@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sum_a@plt>
  lea    0x20(%r12),%r15
  mov    $0x8,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <sum_b@plt>
  lea    0x40(%r12),%r14
  mov    $0x8,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sum_c@plt>
  lea    0x60(%r12),%rax
  mov    $0x8,%edx
  mov    %rax,0x8(%rsp)
  mov    %rax,%rsi
  mov    %r13,%rdi
  call   <sum_d@plt>
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <clp_v@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <dct_a@plt>
  lea    0x20(%rbp),%rsi
  mov    %r15,%rdi
  call   <dct_b@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <dct_b@plt>
  lea    0x60(%rbp),%rsi
  mov    0x8(%rsp),%rdi
  call   <dct_b@plt>
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <clp_v@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mod_a@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <mod_b@plt>
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <clp_v@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mod_c@plt>
  mov    %rbp,%r12
  sub    $0xffffffffffffff80,%rbp
L18:
  mov    (%r12),%edi
  mov    %ebx,%ecx
  shl    %cl,%edi
  call   <clip23@plt>
  mov    %eax,(%r12)
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L18
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void idct_perform32_fixed(int *restrict input, int *restrict output) {
  int mag = 0;
  for (int i = 0; i < 32; i++)
    mag += abs(input[i]);
  int shift = mag > 0x400000 ? 2 : 0;
  int round = shift > 0 ? 1 << (shift - 1) : 0;
  for (int i = 0; i < 32; i++)
    input[i] = (input[i] + round) >> shift;
  sum_a(input, output + 0, 16);
  sum_b(input, output + 16, 16);
  clp_v(output, 32);
  sum_a(output + 0, input + 0, 8);
  sum_b(output + 0, input + 8, 8);
  sum_c(output + 16, input + 16, 8);
  sum_d(output + 16, input + 24, 8);
  clp_v(input, 32);
  dct_a(input + 0, output + 0);
  dct_b(input + 8, output + 8);
  dct_b(input + 16, output + 16);
  dct_b(input + 24, output + 24);
  clp_v(output, 32);
  mod_a(output + 0, input + 0);
  mod_b(output + 16, input + 16);
  clp_v(input, 32);
  mod_c(input, output);
  for (int i = 0; i < 32; i++)
    output[i] = clip23(output[i] * (1 << shift));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<free_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_image(void **image) {
  free(*image);
  free(image);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<free_image>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void free_image(void **image) {
  free(*image);
  free(image);
}
```
user: What is the c source code of the assembly code below?

```asm
<free_image>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_image(void **image) {
  free(*image);
  free(image);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_image>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_image(void **image) {
  free(*image);
  free(image);
}
```