ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toto>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  lea    0x54(%rsp),%rcx
  mov    %rsp,%rax
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L1
  movslq %esi,%rax
  mov    (%rsp,%rax,4),%eax
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x1a8,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto() {
  int i, j, b;
  int a[100];
  if (i == 20) {
    for (j = 0; j <= 20; j++)
      a[j] = b + i;
    b = 3;
  } else {
    if (i == 30) {
      for (j = 0; j <= 20; j++)
        a[j] = b + i;
      b = 5;
    }
  }
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  return a[b];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<toto>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  mov    $0x3,%eax
  movd   %eax,%xmm1
  pshufd $0x0,%xmm1,%xmm0
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  mov    (%rsp,%rax,4),%eax
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x1a8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto() {
  int i, j, b;
  int a[100];
  if (i == 20) {
    for (j = 0; j <= 20; j++)
      a[j] = b + i;
    b = 3;
  } else {
    if (i == 30) {
      for (j = 0; j <= 20; j++)
        a[j] = b + i;
      b = 5;
    }
  }
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  return a[b];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ls_cost_nm9_name_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L19
  cmpl   $0x1,-0x4(%rbp)
  je     L18
  jmp    L10
L19:
  lea    D2(%rip),%rax
  jmp    L37
L18:
  lea    D9(%rip),%rax
  jmp    L37
L10:
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string

tool: D2: i0

tool: D9: i1

assistant: ```c
const char *ls_cost_nm9_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  case 1:
    return "i1";
  default:
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ls_cost_nm9_name_in>:
  endbr64
  lea    D10(%rip),%rax
  test   %edi,%edi
  je     L7
  cmp    $0x1,%edi
  lea    D6(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D10
type: string
name: disassemble_data
arguments: label: D6
type: string

tool: D10: i0

tool: D6: i1

assistant: ```c
const char *ls_cost_nm9_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  case 1:
    return "i1";
  default:
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ls_cost_nm9_name_in>:
  endbr64
  lea    D1(%rip),%rax
  test   %edi,%edi
  je     L0
  cmp    $0x1,%edi
  lea    D9(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string

tool: D1: i0

tool: D9: i1

assistant: ```c
const char *ls_cost_nm9_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  case 1:
    return "i1";
  default:
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ls_cost_nm9_name_in>:
  endbr64
  lea    D8(%rip),%rax
  test   %edi,%edi
  je     L8
  cmp    $0x1,%edi
  lea    D12(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D8: i0

tool: D12: i1

assistant: ```c
const char *ls_cost_nm9_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  case 1:
    return "i1";
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<add_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  cmp    $0xf4240,%eax
  jle    L3
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%edx
  movslq %edx,%rax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  sar    $0x12,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xf4240,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x8(%rbp),%rdx
  mov    %eax,0x4(%rdx)
L3:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_time(struct timeval *t1, struct timeval *t2) {
  t1->tv_sec += t2->tv_sec;
  t1->tv_usec += t2->tv_usec;
  if (t1->tv_usec > 1000000) {
    t1->tv_sec += (t1->tv_usec / 1000000);
    t1->tv_usec %= 1000000;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_time>:
  endbr64
  mov    %rdi,%rax
  mov    (%rsi),%edi
  add    (%rax),%edi
  mov    %edi,(%rax)
  mov    0x4(%rsi),%edx
  add    0x4(%rax),%edx
  mov    %edx,0x4(%rax)
  cmp    $0xf4240,%edx
  jle    L9
  movslq %edx,%rcx
  imul   $0x431bde83,%rcx,%rcx
  sar    $0x32,%rcx
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%ecx
  add    %ecx,%edi
  mov    %edi,(%rax)
  imul   $0xf4240,%ecx,%ecx
  sub    %ecx,%edx
  mov    %edx,0x4(%rax)
L9:
  ret
```

assistant: ```c
void add_time(struct timeval *t1, struct timeval *t2) {
  t1->tv_sec += t2->tv_sec;
  t1->tv_usec += t2->tv_usec;
  if (t1->tv_usec > 1000000) {
    t1->tv_sec += (t1->tv_usec / 1000000);
    t1->tv_usec %= 1000000;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add_time>:
  endbr64
  mov    %rdi,%rax
  mov    0x4(%rsi),%edx
  mov    (%rsi),%edi
  add    0x4(%rax),%edx
  add    (%rax),%edi
  mov    %edi,(%rax)
  mov    %edx,0x4(%rax)
  cmp    $0xf4240,%edx
  jle    L3
  movslq %edx,%rcx
  mov    %edx,%esi
  imul   $0x431bde83,%rcx,%rcx
  sar    $0x1f,%esi
  sar    $0x32,%rcx
  sub    %esi,%ecx
  add    %ecx,%edi
  imul   $0xf4240,%ecx,%ecx
  mov    %edi,(%rax)
  sub    %ecx,%edx
  mov    %edx,0x4(%rax)
L3:
  ret
```

assistant: ```c
void add_time(struct timeval *t1, struct timeval *t2) {
  t1->tv_sec += t2->tv_sec;
  t1->tv_usec += t2->tv_usec;
  if (t1->tv_usec > 1000000) {
    t1->tv_sec += (t1->tv_usec / 1000000);
    t1->tv_usec %= 1000000;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<add_time>:
  endbr64
  movq   (%rdi),%xmm0
  movq   (%rsi),%xmm1
  paddd  %xmm1,%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%edx
  movd   %xmm0,%ecx
  movq   %xmm0,(%rdi)
  cmp    $0xf4240,%edx
  jle    L4
  movslq %edx,%rax
  movd   %xmm2,%esi
  imul   $0x431bde83,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x32,%rax
  sub    %esi,%eax
  add    %eax,%ecx
  imul   $0xf4240,%eax,%eax
  movd   %ecx,%xmm0
  sub    %eax,%edx
  movd   %edx,%xmm3
  punpckldq %xmm3,%xmm0
  movq   %xmm0,(%rdi)
L4:
  ret
```

assistant: ```c
void add_time(struct timeval *t1, struct timeval *t2) {
  t1->tv_sec += t2->tv_sec;
  t1->tv_usec += t2->tv_usec;
  if (t1->tv_usec > 1000000) {
    t1->tv_sec += (t1->tv_usec / 1000000);
    t1->tv_usec %= 1000000;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movl   $0x4,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L1
L28:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L1:
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L53
L54:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L53:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L54
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L43
L45:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L43:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L45
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type: string

tool: D13: %d	

assistant: ```c
int main() {
  int i;
  int *vetor;
  int min = 4;
  int max = 10;
  int *v;
  int *aux;
  vetor = (int *)malloc(min * sizeof(int));
  for (i = 0; i < min; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
  aux = vetor;
  v = (int *)malloc(max * sizeof(int));
  memcpy(v, vetor, min * sizeof(int));
  vetor = v;
  free(aux);
  for (i = min; i < max; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
  for (i = 0; i < max; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L26:
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x4,%ebx
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x10,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rbp
  add    $0x10,%r12
  lea    D4(%rip),%r13
L27:
  mov    %ebx,(%r12)
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    $0xa,%ebx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L22:
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0xa,%ebx
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D4: %d	

assistant: ```c
int main() {
  int i;
  int *vetor;
  int min = 4;
  int max = 10;
  int *v;
  int *aux;
  vetor = (int *)malloc(min * sizeof(int));
  for (i = 0; i < min; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
  aux = vetor;
  v = (int *)malloc(max * sizeof(int));
  memcpy(v, vetor, min * sizeof(int));
  vetor = v;
  free(aux);
  for (i = min; i < max; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
  for (i = 0; i < max; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x10,%edi
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
L25:
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    $0x10,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  mov    %r13,%rdi
  lea    0x10(%rbp),%r13
  call   <free@plt>
  nopl   (%rax)
L13:
  mov    %ebx,0x0(%r13)
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L13
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
L8:
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: %d	

assistant: ```c
int main() {
  int i;
  int *vetor;
  int min = 4;
  int max = 10;
  int *v;
  int *aux;
  vetor = (int *)malloc(min * sizeof(int));
  for (i = 0; i < min; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
  aux = vetor;
  v = (int *)malloc(max * sizeof(int));
  memcpy(v, vetor, min * sizeof(int));
  vetor = v;
  free(aux);
  for (i = min; i < max; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
  for (i = 0; i < max; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x10,%edi
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
L26:
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    $0x10,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  mov    %r13,%rdi
  lea    0x10(%rbp),%r13
  call   <free@plt>
  nopl   (%rax)
L16:
  mov    %ebx,0x0(%r13)
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L16
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
L2:
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d	

assistant: ```c
int main() {
  int i;
  int *vetor;
  int min = 4;
  int max = 10;
  int *v;
  int *aux;
  vetor = (int *)malloc(min * sizeof(int));
  for (i = 0; i < min; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
  aux = vetor;
  v = (int *)malloc(max * sizeof(int));
  memcpy(v, vetor, min * sizeof(int));
  vetor = v;
  free(aux);
  for (i = min; i < max; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
  for (i = 0; i < max; ++i) {
    vetor[i] = i;
    printf("%d\t", vetor[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D27
type: string
name: retrieve_data
arguments: data_label: D20
type: string

tool: D16: pid : %d


tool: D27: uid: %d


tool: D20: euid: %d


assistant: ```c
int main() {
  pid_t pid;
  pid = getpid();
  printf("pid : %d\n", pid);
  uid_t uid;
  uid = getuid();
  printf("uid: %d\n", uid);
  uid_t euid;
  euid = geteuid();
  printf("euid: %d\n", euid);
  while (1)
    ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
L1:
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D28
datatype: string
name: extract_symbolic_data
arguments: data_tag: D19
datatype: string

tool: D29: pid : %d


tool: D28: uid: %d


tool: D19: euid: %d


assistant: ```c
int main() {
  pid_t pid;
  pid = getpid();
  printf("pid : %d\n", pid);
  uid_t uid;
  uid = getuid();
  printf("uid: %d\n", uid);
  uid_t euid;
  euid = geteuid();
  printf("euid: %d\n", euid);
  while (1)
    ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getuid@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <geteuid@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
L1:
  jmp    L1
```

tool_calls: name: read_data
arguments: tag: D21
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string

tool: D21: pid : %d


tool: D7: uid: %d


tool: D19: euid: %d


assistant: ```c
int main() {
  pid_t pid;
  pid = getpid();
  printf("pid : %d\n", pid);
  uid_t uid;
  uid = getuid();
  printf("uid: %d\n", uid);
  uid_t euid;
  euid = geteuid();
  printf("euid: %d\n", euid);
  while (1)
    ;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D25(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getuid@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <geteuid@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
L2:
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_label: D25
type_guessed: string
name: unpack_data
arguments: data_label: D19
type_guessed: string
name: unpack_data
arguments: data_label: D13
type_guessed: string

tool: D25: pid : %d


tool: D19: uid: %d


tool: D13: euid: %d


assistant: ```c
int main() {
  pid_t pid;
  pid = getpid();
  printf("pid : %d\n", pid);
  uid_t uid;
  uid = getuid();
  printf("uid: %d\n", uid);
  uid_t euid;
  euid = geteuid();
  printf("euid: %d\n", euid);
  while (1)
    ;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fexpecttoken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,-0x18(%rbp)
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <fnextc@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <fexpectstr@plt>
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fexpecttoken(register FILE *file, char *str) {
  (void)fnextc(file, 0);
  return fexpectstr(file, str);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fexpecttoken>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%esi
  call   <fnextc@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fexpectstr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fexpecttoken(register FILE *file, char *str) {
  (void)fnextc(file, 0);
  return fexpectstr(file, str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fexpecttoken>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fnextc@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <fexpectstr@plt>
```

assistant: ```c
int fexpecttoken(register FILE *file, char *str) {
  (void)fnextc(file, 0);
  return fexpectstr(file, str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fexpecttoken>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fnextc@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <fexpectstr@plt>
```

assistant: ```c
int fexpecttoken(register FILE *file, char *str) {
  (void)fnextc(file, 0);
  return fexpectstr(file, str);
}
```