user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  movabs $0xc90000001f,%rax
  mov    %rsp,%r15
  lea    0x40(%rsp),%rdi
  lea    0x10(%rsp),%rbp
  mov    %r15,%rsi
  lea    0x50(%rsp),%r13
  mov    %rbp,%r12
  mov    %rax,0x40(%rsp)
  movabs $0x82000000fb,%rax
  mov    %rax,0x48(%rsp)
  movabs $0xd3000000aa,%rax
  mov    %rax,0x50(%rsp)
  movabs $0x8100000005,%rax
  mov    %rax,0x58(%rsp)
  movabs $0xe00000096,%rax
  mov    %rax,0x60(%rsp)
  movabs $0xf900000025,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x12000000ec,%rax
  mov    %rax,0x70(%rsp)
  movabs $0x8100000011,%rax
  mov    %rax,0x78(%rsp)
  call   <forward4x4@plt>
L12:
  lea    -0x10(%r12),%rbx
L22:
  mov    (%rbx),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L22
  mov    $0xa,%edi
  lea    0x10(%rbx),%r12
  call   <putchar@plt>
  cmp    %r13,%r12
  jne    L12
  lea    0x80(%rsp),%rdi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r15,%rsi
  movabs $0x22000007ba,%rax
  lea    D23(%rip),%r12
  mov    %rax,0x80(%rsp)
  movabs $0xfffffec2000001d6,%rax
  mov    %rax,0x88(%rsp)
  movabs $0xfffffe5f000001eb,%rax
  mov    %rax,0x90(%rsp)
  movabs $0xfffffdf2fffffa1d,%rax
  mov    %rax,0x98(%rsp)
  movabs $0xffffff9c00000030,%rax
  mov    %rax,0xa0(%rsp)
  movabs $0x212fffffe78,%rax
  mov    %rax,0xa8(%rsp)
  movabs $0xfffffa3700000053,%rax
  mov    %rax,0xb0(%rsp)
  movabs $0x214ffffffa5,%rax
  mov    %rax,0xb8(%rsp)
  call   <inverse4x4@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
L30:
  lea    -0x10(%rbp),%rbx
L42:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L42
  mov    $0xa,%edi
  lea    0x10(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L30
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: string
name: parse_data
arguments: data_tag: D12
type_infered: string

tool: D14: %2d 

tool: D23: %5d 

tool: D12: Inverse: 

assistant: ```c
int main(void) {
  int out[4][4];
  int in3[4][4] = {{31, 201, 251, 130}, {170, 211, 5, 129}, {150, 14, 37, 249}, {236, 18, 17, 129}};
  int in[4][4] = {{31, 201, 251, 130}, {170, 211, 5, 129}, {150, 14, 37, 249}, {236, 18, 17, 129}};
  int in2[4][4] = {{0, 1, 1, 0}, {2, 0, 0, 0}, {0, 0, 0, 0}, {0, 0, 0, 0}};
  forward4x4(in, out, 0, 0);
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      printf("%2d ", out[i][j]);
    }
    printf("\n");
  }
  int coeffs[4][4] = {{1978, 34, 470, -318}, {491, -417, -1507, -526}, {48, -100, -392, 530}, {83, -1481, -91, 532}};
  inverse4x4(coeffs, out, 0, 0);
  printf("Inverse: \n");
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      printf("%5d ", out[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```