ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<uname_main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  test   %rax,%rax
  je     L28
L12:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L28:
  mov    0x20(%rsp),%r9
  mov    0x18(%rsp),%r8
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: <p>%s, %s<br>
%s, %s, %s</p>


assistant: ```c
int uname_main() {
  struct utsname name;
  if (uname(&name) == 0)
    printf("<p>%s, %s<br>\n%s, %s, %s</p>\n", name.nodename, name.machine, name.sysname, name.release, name.version);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uname_main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  test   %rax,%rax
  je     L23
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L23:
  mov    0x20(%rsp),%r9
  mov    (%rsp),%rsi
  lea    D6(%rip),%rdi
  mov    0x18(%rsp),%r8
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  call   <printf@plt>
  jmp    L6
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: <p>%s, %s<br>
%s, %s, %s</p>


assistant: ```c
int uname_main() {
  struct utsname name;
  if (uname(&name) == 0)
    printf("<p>%s, %s<br>\n%s, %s, %s</p>\n", name.nodename, name.machine, name.sysname, name.release, name.version);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uname_main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  test   %rax,%rax
  je     L17
L27:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L17:
  mov    0x20(%rsp),%r9
  mov    (%rsp),%rsi
  lea    D9(%rip),%rdi
  mov    0x18(%rsp),%r8
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  call   <printf@plt>
  jmp    L27
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: <p>%s, %s<br>
%s, %s, %s</p>


assistant: ```c
int uname_main() {
  struct utsname name;
  if (uname(&name) == 0)
    printf("<p>%s, %s<br>\n%s, %s, %s</p>\n", name.nodename, name.machine, name.sysname, name.release, name.version);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fltLt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fltLt(const void *f1, const void *f2) {
  return (*((float *)f1) < *((float *)f2));
  ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fltLt>:
  endbr64
  movss  (%rsi),%xmm0
  comiss (%rdi),%xmm0
  seta   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int fltLt(const void *f1, const void *f2) {
  return (*((float *)f1) < *((float *)f2));
  ;
}
```
user: What is the c source code of the assembly code below?

```asm
<fltLt>:
  endbr64
  movss  (%rsi),%xmm0
  xor    %eax,%eax
  comiss (%rdi),%xmm0
  seta   %al
  ret
```

assistant: ```c
int fltLt(const void *f1, const void *f2) {
  return (*((float *)f1) < *((float *)f2));
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fltLt>:
  endbr64
  movss  (%rsi),%xmm0
  xor    %eax,%eax
  comiss (%rdi),%xmm0
  seta   %al
  ret
```

assistant: ```c
int fltLt(const void *f1, const void *f2) {
  return (*((float *)f1) < *((float *)f2));
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mcnet_write_int16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mcnet_write_int16(uint8_t *out, int16_t in) {
  out[0] = ((in >> 8) & 0xFF);
  out[1] = ((in >> 0) & 0xFF);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mcnet_write_int16>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  mov    %edx,(%rdi)
  and    $0xff,%eax
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void mcnet_write_int16(uint8_t *out, int16_t in) {
  out[0] = ((in >> 8) & 0xFF);
  out[1] = ((in >> 0) & 0xFF);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mcnet_write_int16>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,(%rdi)
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void mcnet_write_int16(uint8_t *out, int16_t in) {
  out[0] = ((in >> 8) & 0xFF);
  out[1] = ((in >> 0) & 0xFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mcnet_write_int16>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,(%rdi)
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void mcnet_write_int16(uint8_t *out, int16_t in) {
  out[0] = ((in >> 8) & 0xFF);
  out[1] = ((in >> 0) & 0xFF);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x80(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    $0x1a,%esi
  mov    %rax,%rdi
  call   <nullArray@plt>
  lea    -0x70(%rbp),%rcx
  mov    -0x80(%rbp),%rax
  mov    $0x1a,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <arrayScan@plt>
  lea    -0x70(%rbp),%rcx
  mov    -0x78(%rbp),%rax
  mov    $0x1a,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <printChar@plt>
  mov    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string
name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D23
type_infered: string

tool: D10: r

tool: D0: task.in

tool: D8: w

tool: D23: task.out

assistant: ```c
int main() {
  FILE *in = fopen("task.in", "r");
  FILE *out = fopen("task.out", "w");
  int arrayLetters[26];
  nullArray(arrayLetters, 26);
  arrayScan(in, arrayLetters, 26);
  printChar(out, arrayLetters, 26);
  fclose(in);
  fclose(out);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rsi
  lea    D11(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    D31(%rip),%rsi
  lea    D2(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rsp,%r12
  mov    $0x1a,%esi
  mov    %r12,%rdi
  call   <nullArray@plt>
  mov    $0x1a,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <arrayScan@plt>
  mov    $0x1a,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <printChar@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D35
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string
name: unpack_data
arguments: tag: D31
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string

tool: D35: r

tool: D11: task.in

tool: D31: w

tool: D2: task.out

assistant: ```c
int main() {
  FILE *in = fopen("task.in", "r");
  FILE *out = fopen("task.out", "w");
  int arrayLetters[26];
  nullArray(arrayLetters, 26);
  arrayScan(in, arrayLetters, 26);
  printChar(out, arrayLetters, 26);
  fclose(in);
  fclose(out);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rsi
  lea    D39(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <fopen@plt>
  lea    D22(%rip),%rsi
  lea    D35(%rip),%rdi
  mov    %rax,%r12
  call   <fopen@plt>
  mov    $0x1a,%esi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <nullArray@plt>
  mov    $0x1a,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <arrayScan@plt>
  mov    $0x1a,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printChar@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D39
type: string
name: disassemble_data
arguments: data_tag: D22
type: string
name: disassemble_data
arguments: data_tag: D35
type: string

tool: D4: r

tool: D39: task.in

tool: D22: w

tool: D35: task.out

assistant: ```c
int main() {
  FILE *in = fopen("task.in", "r");
  FILE *out = fopen("task.out", "w");
  int arrayLetters[26];
  nullArray(arrayLetters, 26);
  arrayScan(in, arrayLetters, 26);
  printChar(out, arrayLetters, 26);
  fclose(in);
  fclose(out);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D26(%rip),%rsi
  lea    D6(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <fopen@plt>
  lea    D12(%rip),%rsi
  lea    D38(%rip),%rdi
  mov    %rax,%r12
  call   <fopen@plt>
  mov    $0x1a,%esi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <nullArray@plt>
  mov    $0x1a,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <arrayScan@plt>
  mov    $0x1a,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printChar@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D12
data_type: string
name: extract_symbolic_data
arguments: tag: D38
data_type: string

tool: D26: r

tool: D6: task.in

tool: D12: w

tool: D38: task.out

assistant: ```c
int main() {
  FILE *in = fopen("task.in", "r");
  FILE *out = fopen("task.out", "w");
  int arrayLetters[26];
  nullArray(arrayLetters, 26);
  arrayScan(in, arrayLetters, 26);
  printChar(out, arrayLetters, 26);
  fclose(in);
  fclose(out);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rfft4pt>:
  endbr64
  movss  (%rdi),%xmm1
  movss  0x4(%rdi),%xmm4
  movss  0x10(%rdi),%xmm6
  movss  0x14(%rdi),%xmm0
  movss  0x8(%rdi),%xmm7
  movss  0xc(%rdi),%xmm5
  movss  0x18(%rdi),%xmm3
  movss  0x1c(%rdi),%xmm2
  movaps %xmm1,%xmm11
  addss  %xmm6,%xmm11
  movaps %xmm4,%xmm10
  addss  %xmm0,%xmm10
  subss  %xmm6,%xmm1
  subss  %xmm0,%xmm4
  movaps %xmm7,%xmm0
  subss  %xmm3,%xmm0
  movaps %xmm5,%xmm6
  subss  %xmm2,%xmm6
  addss  %xmm3,%xmm7
  addss  %xmm2,%xmm5
  movaps %xmm11,%xmm8
  addss  %xmm7,%xmm8
  movaps %xmm10,%xmm9
  addss  %xmm5,%xmm9
  movaps %xmm1,%xmm2
  subss  %xmm6,%xmm2
  movaps %xmm4,%xmm3
  addss  %xmm0,%xmm3
  addss  %xmm6,%xmm1
  subss  %xmm0,%xmm4
  movaps %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movaps %xmm4,%xmm6
  subss  %xmm3,%xmm6
  addss  %xmm4,%xmm3
  movss  D13(%rip),%xmm4
  mulss  %xmm4,%xmm3
  subss  %xmm1,%xmm2
  mulss  %xmm4,%xmm2
  movaps %xmm3,%xmm4
  addss  %xmm0,%xmm4
  addss  %xmm2,%xmm4
  movaps %xmm6,%xmm1
  subss  %xmm3,%xmm1
  addss  %xmm2,%xmm1
  subss  %xmm7,%xmm11
  movss  %xmm11,0x10(%rdi)
  subss  %xmm10,%xmm5
  movss  %xmm5,0x14(%rdi)
  movaps %xmm8,%xmm2
  addss  %xmm9,%xmm2
  movss  %xmm2,(%rdi)
  subss  %xmm9,%xmm8
  movss  %xmm8,0x4(%rdi)
  movss  D3(%rip),%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm2,%xmm3
  movss  %xmm3,0x8(%rdi)
  movaps %xmm1,%xmm3
  mulss  %xmm2,%xmm3
  movss  %xmm3,0xc(%rdi)
  addss  %xmm0,%xmm0
  subss  %xmm4,%xmm0
  mulss  %xmm2,%xmm0
  movss  %xmm0,0x18(%rdi)
  addss  %xmm6,%xmm6
  subss  %xmm6,%xmm1
  mulss  %xmm2,%xmm1
  movss  %xmm1,0x1c(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type: byte[4]
name: parse_data
arguments: data_label: D3
type: f32

tool: {"D13": [0xf3,0x04,0x35,0x3f]}

tool: D3: 0.5

assistant: ```c
void rfft4pt(float *ioptr) {
  float f0r, f0i, f1r, f1i, f2r, f2i, f3r, f3i;
  float t0r, t0i, t1r, t1i;
  float w0r = 1.0 / 1.414213562373095048801688724209698078569;
  const float Two = 2.0;
  const float scale = 0.5;
  f0r = ioptr[0];
  f0i = ioptr[1];
  f1r = ioptr[4];
  f1i = ioptr[5];
  f2r = ioptr[2];
  f2i = ioptr[3];
  f3r = ioptr[6];
  f3i = ioptr[7];
  t0r = f0r + f1r;
  t0i = f0i + f1i;
  f1r = f0r - f1r;
  f1i = f0i - f1i;
  t1r = f2r - f3r;
  t1i = f2i - f3i;
  f2r = f2r + f3r;
  f2i = f2i + f3i;
  f0r = t0r + f2r;
  f0i = t0i + f2i;
  f2r = t0r - f2r;
  f2i = f2i - t0i;
  f3r = f1r - t1i;
  f3i = f1i + t1r;
  f1r = f1r + t1i;
  f1i = f1i - t1r;
  t0r = f0r + f0i;
  t0i = f0r - f0i;
  t1r = f1r + f3r;
  t1i = f1i - f3i;
  f0r = f1i + f3i;
  f0i = f3r - f1r;
  f1r = t1r + w0r * f0r + w0r * f0i;
  f1i = t1i - w0r * f0r + w0r * f0i;
  f3r = Two * t1r - f1r;
  f3i = f1i - Two * t1i;
  ioptr[4] = f2r;
  ioptr[5] = f2i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
  ioptr[2] = scale * f1r;
  ioptr[3] = scale * f1i;
  ioptr[6] = scale * f3r;
  ioptr[7] = scale * f3i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rfft4pt>:
  endbr64
  movss  0x4(%rdi),%xmm4
  movss  0x14(%rdi),%xmm0
  movss  0x8(%rdi),%xmm7
  movss  0x18(%rdi),%xmm3
  movaps %xmm4,%xmm10
  movss  (%rdi),%xmm1
  subss  %xmm0,%xmm4
  movss  0x10(%rdi),%xmm6
  addss  %xmm0,%xmm10
  movaps %xmm7,%xmm0
  movss  0xc(%rdi),%xmm5
  movss  0x1c(%rdi),%xmm2
  subss  %xmm3,%xmm0
  movaps %xmm1,%xmm11
  subss  %xmm6,%xmm1
  addss  %xmm6,%xmm11
  movaps %xmm5,%xmm6
  addss  %xmm3,%xmm7
  subss  %xmm2,%xmm6
  movaps %xmm4,%xmm3
  addss  %xmm2,%xmm5
  subss  %xmm0,%xmm4
  addss  %xmm0,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm11,%xmm8
  movaps %xmm10,%xmm9
  subss  %xmm7,%xmm11
  addss  %xmm6,%xmm1
  subss  %xmm6,%xmm2
  movaps %xmm4,%xmm6
  addss  %xmm7,%xmm8
  addss  %xmm5,%xmm9
  subss  %xmm3,%xmm6
  addss  %xmm4,%xmm3
  movss  %xmm11,0x10(%rdi)
  movss  D16(%rip),%xmm4
  movaps %xmm2,%xmm0
  subss  %xmm1,%xmm2
  subss  %xmm10,%xmm5
  addss  %xmm1,%xmm0
  mulss  %xmm4,%xmm3
  movaps %xmm6,%xmm1
  addss  %xmm6,%xmm6
  mulss  %xmm4,%xmm2
  movss  %xmm5,0x14(%rdi)
  movaps %xmm3,%xmm4
  subss  %xmm3,%xmm1
  addss  %xmm0,%xmm4
  addss  %xmm0,%xmm0
  addss  %xmm2,%xmm1
  addss  %xmm2,%xmm4
  movaps %xmm8,%xmm2
  subss  %xmm9,%xmm8
  addss  %xmm9,%xmm2
  movaps %xmm4,%xmm3
  subss  %xmm4,%xmm0
  movss  %xmm8,0x4(%rdi)
  movss  %xmm2,(%rdi)
  movss  D8(%rip),%xmm2
  mulss  %xmm2,%xmm3
  mulss  %xmm2,%xmm0
  movss  %xmm3,0x8(%rdi)
  movaps %xmm1,%xmm3
  subss  %xmm6,%xmm1
  mulss  %xmm2,%xmm3
  movss  %xmm0,0x18(%rdi)
  mulss  %xmm2,%xmm1
  movss  %xmm3,0xc(%rdi)
  movss  %xmm1,0x1c(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D8
datatype: f32

tool: {"D16": [0xf3,0x04,0x35,0x3f]}

tool: D8: 0.5

assistant: ```c
void rfft4pt(float *ioptr) {
  float f0r, f0i, f1r, f1i, f2r, f2i, f3r, f3i;
  float t0r, t0i, t1r, t1i;
  float w0r = 1.0 / 1.414213562373095048801688724209698078569;
  const float Two = 2.0;
  const float scale = 0.5;
  f0r = ioptr[0];
  f0i = ioptr[1];
  f1r = ioptr[4];
  f1i = ioptr[5];
  f2r = ioptr[2];
  f2i = ioptr[3];
  f3r = ioptr[6];
  f3i = ioptr[7];
  t0r = f0r + f1r;
  t0i = f0i + f1i;
  f1r = f0r - f1r;
  f1i = f0i - f1i;
  t1r = f2r - f3r;
  t1i = f2i - f3i;
  f2r = f2r + f3r;
  f2i = f2i + f3i;
  f0r = t0r + f2r;
  f0i = t0i + f2i;
  f2r = t0r - f2r;
  f2i = f2i - t0i;
  f3r = f1r - t1i;
  f3i = f1i + t1r;
  f1r = f1r + t1i;
  f1i = f1i - t1r;
  t0r = f0r + f0i;
  t0i = f0r - f0i;
  t1r = f1r + f3r;
  t1i = f1i - f3i;
  f0r = f1i + f3i;
  f0i = f3r - f1r;
  f1r = t1r + w0r * f0r + w0r * f0i;
  f1i = t1i - w0r * f0r + w0r * f0i;
  f3r = Two * t1r - f1r;
  f3i = f1i - Two * t1i;
  ioptr[4] = f2r;
  ioptr[5] = f2i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
  ioptr[2] = scale * f1r;
  ioptr[3] = scale * f1i;
  ioptr[6] = scale * f3r;
  ioptr[7] = scale * f3i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rfft4pt>:
  endbr64
  movss  0x4(%rdi),%xmm8
  movss  0x14(%rdi),%xmm0
  movss  0x8(%rdi),%xmm7
  movss  0x18(%rdi),%xmm4
  movaps %xmm8,%xmm9
  movss  (%rdi),%xmm2
  subss  %xmm0,%xmm8
  movss  0x10(%rdi),%xmm6
  addss  %xmm0,%xmm9
  movaps %xmm7,%xmm0
  movss  0xc(%rdi),%xmm5
  movss  0x1c(%rdi),%xmm3
  subss  %xmm4,%xmm0
  movaps %xmm2,%xmm1
  subss  %xmm6,%xmm2
  addss  %xmm6,%xmm1
  movaps %xmm5,%xmm6
  addss  %xmm4,%xmm7
  subss  %xmm3,%xmm6
  movaps %xmm8,%xmm4
  addss  %xmm3,%xmm5
  subss  %xmm0,%xmm8
  addss  %xmm0,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm10
  movaps %xmm9,%xmm11
  subss  %xmm7,%xmm1
  addss  %xmm6,%xmm2
  subss  %xmm6,%xmm3
  movaps %xmm8,%xmm6
  addss  %xmm7,%xmm10
  addss  %xmm5,%xmm11
  subss  %xmm4,%xmm6
  addss  %xmm8,%xmm4
  movss  D19(%rip),%xmm8
  movaps %xmm3,%xmm0
  subss  %xmm2,%xmm3
  subss  %xmm9,%xmm5
  addss  %xmm2,%xmm0
  mulss  %xmm8,%xmm4
  movaps %xmm6,%xmm2
  addss  %xmm6,%xmm6
  mulss  %xmm8,%xmm3
  unpcklps %xmm5,%xmm1
  movaps %xmm4,%xmm8
  subss  %xmm4,%xmm2
  movss  D11(%rip),%xmm4
  addss  %xmm0,%xmm8
  addss  %xmm0,%xmm0
  addss  %xmm3,%xmm2
  addss  %xmm3,%xmm8
  movaps %xmm10,%xmm3
  subss  %xmm11,%xmm10
  addss  %xmm11,%xmm3
  movaps %xmm2,%xmm12
  subss  %xmm6,%xmm2
  subss  %xmm8,%xmm0
  mulss  %xmm4,%xmm12
  movaps %xmm8,%xmm11
  mulss  %xmm4,%xmm11
  unpcklps %xmm10,%xmm3
  mulss  %xmm4,%xmm2
  mulss  %xmm4,%xmm0
  unpcklps %xmm12,%xmm11
  movlhps %xmm11,%xmm3
  unpcklps %xmm2,%xmm0
  movups %xmm3,(%rdi)
  movlhps %xmm0,%xmm1
  movups %xmm1,0x10(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: f32

tool: {"D19": [0xf3,0x04,0x35,0x3f]}

tool: D11: 0.5

assistant: ```c
void rfft4pt(float *ioptr) {
  float f0r, f0i, f1r, f1i, f2r, f2i, f3r, f3i;
  float t0r, t0i, t1r, t1i;
  float w0r = 1.0 / 1.414213562373095048801688724209698078569;
  const float Two = 2.0;
  const float scale = 0.5;
  f0r = ioptr[0];
  f0i = ioptr[1];
  f1r = ioptr[4];
  f1i = ioptr[5];
  f2r = ioptr[2];
  f2i = ioptr[3];
  f3r = ioptr[6];
  f3i = ioptr[7];
  t0r = f0r + f1r;
  t0i = f0i + f1i;
  f1r = f0r - f1r;
  f1i = f0i - f1i;
  t1r = f2r - f3r;
  t1i = f2i - f3i;
  f2r = f2r + f3r;
  f2i = f2i + f3i;
  f0r = t0r + f2r;
  f0i = t0i + f2i;
  f2r = t0r - f2r;
  f2i = f2i - t0i;
  f3r = f1r - t1i;
  f3i = f1i + t1r;
  f1r = f1r + t1i;
  f1i = f1i - t1r;
  t0r = f0r + f0i;
  t0i = f0r - f0i;
  t1r = f1r + f3r;
  t1i = f1i - f3i;
  f0r = f1i + f3i;
  f0i = f3r - f1r;
  f1r = t1r + w0r * f0r + w0r * f0i;
  f1i = t1i - w0r * f0r + w0r * f0i;
  f3r = Two * t1r - f1r;
  f3i = f1i - Two * t1i;
  ioptr[4] = f2r;
  ioptr[5] = f2i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
  ioptr[2] = scale * f1r;
  ioptr[3] = scale * f1i;
  ioptr[6] = scale * f3r;
  ioptr[7] = scale * f3i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rpaligned_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x10,-0x18(%rbp)
  ja     L0
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <rpmalloc@plt>
  jmp    L23
L0:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <rpmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  and    %rdx,%rax
  test   %rax,%rax
  je     L7
  mov    -0x18(%rbp),%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  and    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
L23:
  leave
  ret
```

assistant: ```c
void *rpaligned_alloc(size_t alignment, size_t size) {
  void *ptr;
  if (alignment <= 16)
    return rpmalloc(size);
  ptr = rpmalloc(size + alignment);
  if ((uintptr_t)ptr & (alignment - 1))
    ptr = (void *)(((uintptr_t)ptr & ~((uintptr_t)alignment - 1)) + alignment);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rpaligned_alloc>:
  endbr64
  push   %rbx
  cmp    $0x10,%rdi
  jbe    L1
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rdi
  call   <rpmalloc@plt>
  lea    -0x1(%rbx),%rdx
  test   %rdx,%rax
  je     L23
  mov    %rbx,%rdx
  neg    %rdx
  and    %rdx,%rax
  add    %rbx,%rax
  jmp    L23
L1:
  mov    %rsi,%rdi
  call   <rpmalloc@plt>
L23:
  pop    %rbx
  ret
```

assistant: ```c
void *rpaligned_alloc(size_t alignment, size_t size) {
  void *ptr;
  if (alignment <= 16)
    return rpmalloc(size);
  ptr = rpmalloc(size + alignment);
  if ((uintptr_t)ptr & (alignment - 1))
    ptr = (void *)(((uintptr_t)ptr & ~((uintptr_t)alignment - 1)) + alignment);
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rpaligned_alloc>:
  endbr64
  cmp    $0x10,%rdi
  jbe    L1
  push   %rbx
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rdi
  call   <rpmalloc@plt>
  lea    -0x1(%rbx),%rdx
  test   %rdx,%rax
  je     L15
  mov    %rbx,%rdx
  neg    %rdx
  and    %rdx,%rax
  add    %rbx,%rax
L15:
  pop    %rbx
  ret
  xchg   %ax,%ax
L1:
  mov    %rsi,%rdi
  jmp    1050 <rpmalloc@plt>
```

assistant: ```c
void *rpaligned_alloc(size_t alignment, size_t size) {
  void *ptr;
  if (alignment <= 16)
    return rpmalloc(size);
  ptr = rpmalloc(size + alignment);
  if ((uintptr_t)ptr & (alignment - 1))
    ptr = (void *)(((uintptr_t)ptr & ~((uintptr_t)alignment - 1)) + alignment);
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rpaligned_alloc>:
  endbr64
  cmp    $0x10,%rdi
  jbe    L18
  push   %rbx
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rdi
  call   <rpmalloc@plt>
  lea    -0x1(%rbx),%rdx
  test   %rdx,%rax
  je     L1
  mov    %rbx,%rdx
  neg    %rdx
  and    %rdx,%rax
  add    %rbx,%rax
L1:
  pop    %rbx
  ret
  xchg   %ax,%ax
L18:
  mov    %rsi,%rdi
  jmp    1050 <rpmalloc@plt>
```

assistant: ```c
void *rpaligned_alloc(size_t alignment, size_t size) {
  void *ptr;
  if (alignment <= 16)
    return rpmalloc(size);
  ptr = rpmalloc(size + alignment);
  if ((uintptr_t)ptr & (alignment - 1))
    ptr = (void *)(((uintptr_t)ptr & ~((uintptr_t)alignment - 1)) + alignment);
  return ptr;
}
```