ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<chkcodedir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L22
  cmp    $0x3b,%bl
  je     L22
  mov    %rdi,%rbp
  lea    D1(%rip),%r12
  jmp    L38
L5:
  xor    %eax,%eax
  movsbl %bl,%edi
  call   <chkspace@plt>
  test   %eax,%eax
  je     L22
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  test   %bl,%bl
  je     L22
  cmp    $0x3b,%bl
  je     L22
L38:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L5
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string

tool: D1: CODE

assistant: ```c
int chkcodedir(buf)
char *buf;
{
  int codedirflg, i;
  for (i = codedirflg = 0; (buf[i]) && (buf[i] != ';'); i++)
    if (!strcmp(&(buf[i]), "CODE")) {
      codedirflg = 1;
      break;
    } else if (!chkspace(buf[i]))
      break;
  return codedirflg;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<chkcodedir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L26
  cmp    $0x3b,%bl
  je     L26
  mov    %rdi,%rbp
  lea    D0(%rip),%r12
  jmp    L30
L63:
  xor    %eax,%eax
  movsbl %bl,%edi
  call   <chkspace@plt>
  test   %eax,%eax
  je     L26
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  test   %bl,%bl
  je     L26
  cmp    $0x3b,%bl
  je     L26
L30:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L63
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: CODE

assistant: ```c
int chkcodedir(buf)
char *buf;
{
  int codedirflg, i;
  for (i = codedirflg = 0; (buf[i]) && (buf[i] != ';'); i++)
    if (!strcmp(&(buf[i]), "CODE")) {
      codedirflg = 1;
      break;
    } else if (!chkspace(buf[i]))
      break;
  return codedirflg;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4030201,-0x10(%rbp)
  movb   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int test(void) {
  char c[(5 < sizeof(int) ? sizeof(int) : 5)] __attribute__((aligned)) = {1, 2, 3, 4};
  return *(int *)c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  mov    $0x4030201,%eax
  ret
```

assistant: ```c
int test(void) {
  char c[(5 < sizeof(int) ? sizeof(int) : 5)] __attribute__((aligned)) = {1, 2, 3, 4};
  return *(int *)c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  mov    $0x4030201,%eax
  ret
```

assistant: ```c
int test(void) {
  char c[(5 < sizeof(int) ? sizeof(int) : 5)] __attribute__((aligned)) = {1, 2, 3, 4};
  return *(int *)c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<p_operate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <semop@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void p_operate(int semid, ushort semnum) {
  struct sembuf thesops;
  thesops.sem_num = semnum;
  thesops.sem_op = -1;
  thesops.sem_flg = SEM_UNDO;
  semop(semid, &thesops, 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<p_operate>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %esi,0x14(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  call   <semop@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void p_operate(int semid, ushort semnum) {
  struct sembuf thesops;
  thesops.sem_num = semnum;
  thesops.sem_op = -1;
  thesops.sem_flg = SEM_UNDO;
  semop(semid, &thesops, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<p_operate>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %esi,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  movl   $0xffffffff,0xc(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <semop@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void p_operate(int semid, ushort semnum) {
  struct sembuf thesops;
  thesops.sem_num = semnum;
  thesops.sem_op = -1;
  thesops.sem_flg = SEM_UNDO;
  semop(semid, &thesops, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<p_operate>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %esi,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  movl   $0xffffffff,0xc(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <semop@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void p_operate(int semid, ushort semnum) {
  struct sembuf thesops;
  thesops.sem_num = semnum;
  thesops.sem_op = -1;
  thesops.sem_flg = SEM_UNDO;
  semop(semid, &thesops, 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<findAreaMid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  sub    -0x30(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x38(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x30(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  movsd  D9(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L8
L1:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x24(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x28(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x2c(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L8:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x34(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  ja     L1
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: f32[2]

tool: {"D9": [0.0,2.0]}

assistant: ```c
double findAreaMid(int coeff_a, int coeff_b, int coeff_c, int initial, int final, int rectNum) {
  double x_var;
  double width;
  double area;
  x_var = 0.0;
  width = (double)(final - initial) / rectNum;
  area = 0.0;
  for (x_var = initial + width / 2; x_var < final; x_var += width)
    area += (coeff_a * (x_var * x_var) + coeff_b * x_var + coeff_c) * width;
  return area;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findAreaMid>:
  endbr64
  mov    %esi,%eax
  mov    %r8d,%esi
  sub    %ecx,%esi
  pxor   %xmm2,%xmm2
  cvtsi2sd %esi,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sd %r9d,%xmm0
  divsd  %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  movapd %xmm2,%xmm0
  mulsd  D8(%rip),%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm5,%xmm5
  cvtsi2sd %r8d,%xmm5
  pxor   %xmm3,%xmm3
  comisd %xmm1,%xmm5
  jbe    L17
  pxor   %xmm8,%xmm8
  cvtsi2sd %edi,%xmm8
  pxor   %xmm7,%xmm7
  cvtsi2sd %eax,%xmm7
  pxor   %xmm6,%xmm6
  cvtsi2sd %edx,%xmm6
L22:
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm8,%xmm0
  movapd %xmm7,%xmm4
  mulsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm3
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm5
  ja     L22
L24:
  movapd %xmm3,%xmm0
  ret
L17:
  pxor   %xmm3,%xmm3
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: f32[2]

tool: {"D8": [0.0,1.75]}

assistant: ```c
double findAreaMid(int coeff_a, int coeff_b, int coeff_c, int initial, int final, int rectNum) {
  double x_var;
  double width;
  double area;
  x_var = 0.0;
  width = (double)(final - initial) / rectNum;
  area = 0.0;
  for (x_var = initial + width / 2; x_var < final; x_var += width)
    area += (coeff_a * (x_var * x_var) + coeff_b * x_var + coeff_c) * width;
  return area;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findAreaMid>:
  endbr64
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %esi,%eax
  mov    %r8d,%esi
  cvtsi2sd %r9d,%xmm0
  pxor   %xmm5,%xmm5
  sub    %ecx,%esi
  cvtsi2sd %ecx,%xmm1
  cvtsi2sd %esi,%xmm2
  cvtsi2sd %r8d,%xmm5
  divsd  %xmm0,%xmm2
  movsd  D0(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  comisd %xmm1,%xmm5
  jbe    L11
  pxor   %xmm8,%xmm8
  pxor   %xmm7,%xmm7
  pxor   %xmm6,%xmm6
  cvtsi2sd %edi,%xmm8
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm7
  cvtsi2sd %edx,%xmm6
  nopl   (%rax)
L8:
  movapd %xmm1,%xmm0
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  mulsd  %xmm7,%xmm4
  comisd %xmm1,%xmm5
  mulsd  %xmm8,%xmm0
  addsd  %xmm4,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm3
  ja     L8
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L11:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: f32[2]

tool: {"D0": [0.0,1.75]}

assistant: ```c
double findAreaMid(int coeff_a, int coeff_b, int coeff_c, int initial, int final, int rectNum) {
  double x_var;
  double width;
  double area;
  x_var = 0.0;
  width = (double)(final - initial) / rectNum;
  area = 0.0;
  for (x_var = initial + width / 2; x_var < final; x_var += width)
    area += (coeff_a * (x_var * x_var) + coeff_b * x_var + coeff_c) * width;
  return area;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findAreaMid>:
  endbr64
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %esi,%eax
  mov    %r8d,%esi
  cvtsi2sd %r9d,%xmm0
  pxor   %xmm5,%xmm5
  sub    %ecx,%esi
  cvtsi2sd %ecx,%xmm1
  cvtsi2sd %esi,%xmm2
  cvtsi2sd %r8d,%xmm5
  divsd  %xmm0,%xmm2
  movsd  D1(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  comisd %xmm1,%xmm5
  jbe    L2
  pxor   %xmm8,%xmm8
  pxor   %xmm7,%xmm7
  pxor   %xmm6,%xmm6
  cvtsi2sd %edi,%xmm8
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm7
  cvtsi2sd %edx,%xmm6
  nopl   (%rax)
L0:
  movapd %xmm1,%xmm0
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  mulsd  %xmm7,%xmm4
  comisd %xmm1,%xmm5
  mulsd  %xmm8,%xmm0
  addsd  %xmm4,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm3
  ja     L0
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L2:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: f32[2]

tool: {"D1": [0.0,1.75]}

assistant: ```c
double findAreaMid(int coeff_a, int coeff_b, int coeff_c, int initial, int final, int rectNum) {
  double x_var;
  double width;
  double area;
  x_var = 0.0;
  width = (double)(final - initial) / rectNum;
  area = 0.0;
  for (x_var = initial + width / 2; x_var < final; x_var += width)
    area += (coeff_a * (x_var * x_var) + coeff_b * x_var + coeff_c) * width;
  return area;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<v4lconvert_decode_sq905c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x50,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  imul   -0x38(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sq905c_first_decompress@plt>
  mov    -0x38(%rbp),%ecx
  mov    -0x34(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <sq905c_second_decompress@plt>
  jmp    L9
L19:
  nop
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void v4lconvert_decode_sq905c(const unsigned char *src, unsigned char *dst, int width, int height) {
  int size;
  unsigned char *temp_data;
  const unsigned char *raw;
  raw = src + 0x50;
  size = width * height / 2;
  temp_data = malloc(size);
  if (!temp_data)
    goto out;
  sq905c_first_decompress(temp_data, raw, size);
  sq905c_second_decompress(dst, temp_data, width, height);
out:
  free(temp_data);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<v4lconvert_decode_sq905c>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %edx,%r13d
  mov    %ecx,%r14d
  mov    %edx,%eax
  imul   %ecx,%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
  lea    0x50(%r12),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  call   <sq905c_first_decompress@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <sq905c_second_decompress@plt>
L7:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void v4lconvert_decode_sq905c(const unsigned char *src, unsigned char *dst, int width, int height) {
  int size;
  unsigned char *temp_data;
  const unsigned char *raw;
  raw = src + 0x50;
  size = width * height / 2;
  temp_data = malloc(size);
  if (!temp_data)
    goto out;
  sq905c_first_decompress(temp_data, raw, size);
  sq905c_second_decompress(dst, temp_data, width, height);
out:
  free(temp_data);
}
```
user: What is the c source code of the assembly code below:

```asm
<v4lconvert_decode_sq905c>:
  endbr64
  mov    %edx,%eax
  push   %r15
  imul   %ecx,%eax
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %eax,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  shr    $0x1f,%r12d
  mov    %rdi,%rbx
  add    %eax,%r12d
  sar    %r12d
  sub    $0x8,%rsp
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L6
  lea    0x50(%rbx),%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  call   <sq905c_first_decompress@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <sq905c_second_decompress@plt>
L6:
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free@plt>
```

assistant: ```c
void v4lconvert_decode_sq905c(const unsigned char *src, unsigned char *dst, int width, int height) {
  int size;
  unsigned char *temp_data;
  const unsigned char *raw;
  raw = src + 0x50;
  size = width * height / 2;
  temp_data = malloc(size);
  if (!temp_data)
    goto out;
  sq905c_first_decompress(temp_data, raw, size);
  sq905c_second_decompress(dst, temp_data, width, height);
out:
  free(temp_data);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<v4lconvert_decode_sq905c>:
  endbr64
  mov    %edx,%eax
  push   %r15
  imul   %ecx,%eax
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %eax,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  shr    $0x1f,%r12d
  mov    %rdi,%rbx
  add    %eax,%r12d
  sar    %r12d
  sub    $0x8,%rsp
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L8
  lea    0x50(%rbx),%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  call   <sq905c_first_decompress@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <sq905c_second_decompress@plt>
L8:
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free@plt>
```

assistant: ```c
void v4lconvert_decode_sq905c(const unsigned char *src, unsigned char *dst, int width, int height) {
  int size;
  unsigned char *temp_data;
  const unsigned char *raw;
  raw = src + 0x50;
  size = width * height / 2;
  temp_data = malloc(size);
  if (!temp_data)
    goto out;
  sq905c_first_decompress(temp_data, raw, size);
  sq905c_second_decompress(dst, temp_data, width, height);
out:
  free(temp_data);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0xc(%rbp)
  movb   $0x0,-0xb(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L50
L31:
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L56:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %al,-0xa(%rbp)
  movzbl -0xc(%rbp),%eax
  cmp    -0xa(%rbp),%al
  je     L27
  call   <abort@plt>
L27:
  movzbl -0xa(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  mov    %al,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0xb(%rbp),%eax
  cmp    -0x9(%rbp),%al
  je     L51
  call   <abort@plt>
L51:
  movzbl -0x9(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  mov    %al,-0xb(%rbp)
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x63,-0x4(%rbp)
  jle    L56
  addl   $0x1,-0x8(%rbp)
L50:
  cmpl   $0x63,-0x8(%rbp)
  jle    L31
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char flagA = 0;
  unsigned char flagB = 0;
#pragma omp parallel shared(flagA, flagB)
  {
    int i;
    for (i = 0; i < 100; i++) {
      int j;
      for (j = 0; j < 100; j++) {
#pragma omp critical(A)
        {
          unsigned char val_of_flagA = j & 0x1;
          if (flagA != val_of_flagA)
            __builtin_abort();
          flagA = (~val_of_flagA) & 0x1;
        }
#pragma omp critical(B)
        {
          unsigned char val_of_flagB = j & 0x1;
          if (flagB != val_of_flagB)
            __builtin_abort();
          flagB = (~val_of_flagB) & 0x1;
        }
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x64,%esi
  mov    $0x1,%edi
  jmp    L21
L4:
  mov    %ecx,%edx
L31:
  mov    %eax,%ecx
  and    $0x1,%ecx
  cmp    %dl,%cl
  jne    L55
  test   %dl,%dl
  sete   %cl
  add    $0x1,%eax
  cmp    $0x64,%eax
  jne    L4
  sub    $0x1,%esi
  je     L36
  test   %dl,%dl
  je     L55
L21:
  mov    %edi,%edx
  mov    $0x1,%eax
  jmp    L31
L55:
  sub    $0x8,%rsp
  call   <abort@plt>
L36:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char flagA = 0;
  unsigned char flagB = 0;
#pragma omp parallel shared(flagA, flagB)
  {
    int i;
    for (i = 0; i < 100; i++) {
      int j;
      for (j = 0; j < 100; j++) {
#pragma omp critical(A)
        {
          unsigned char val_of_flagA = j & 0x1;
          if (flagA != val_of_flagA)
            __builtin_abort();
          flagA = (~val_of_flagA) & 0x1;
        }
#pragma omp critical(B)
        {
          unsigned char val_of_flagB = j & 0x1;
          if (flagB != val_of_flagB)
            __builtin_abort();
          flagB = (~val_of_flagB) & 0x1;
        }
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x64,%esi
  xor    %edx,%edx
L2:
  xor    %eax,%eax
  nopl   (%rax)
L14:
  mov    %eax,%ecx
  and    $0x1,%ecx
  cmp    %dl,%cl
  jne    1060 <main.cold>
  add    $0x1,%eax
  xor    $0x1,%edx
  cmp    $0x64,%eax
  jne    L14
  sub    $0x1,%esi
  jne    L2
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char flagA = 0;
  unsigned char flagB = 0;
#pragma omp parallel shared(flagA, flagB)
  {
    int i;
    for (i = 0; i < 100; i++) {
      int j;
      for (j = 0; j < 100; j++) {
#pragma omp critical(A)
        {
          unsigned char val_of_flagA = j & 0x1;
          if (flagA != val_of_flagA)
            __builtin_abort();
          flagA = (~val_of_flagA) & 0x1;
        }
#pragma omp critical(B)
        {
          unsigned char val_of_flagB = j & 0x1;
          if (flagB != val_of_flagB)
            __builtin_abort();
          flagB = (~val_of_flagB) & 0x1;
        }
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    $0x64,%esi
  xor    %edx,%edx
L6:
  xor    %eax,%eax
  nopl   (%rax)
L9:
  mov    %eax,%ecx
  and    $0x1,%ecx
  cmp    %dl,%cl
  jne    1060 <main.cold>
  add    $0x1,%eax
  xor    $0x1,%edx
  cmp    $0x64,%eax
  jne    L9
  sub    $0x1,%esi
  jne    L6
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char flagA = 0;
  unsigned char flagB = 0;
#pragma omp parallel shared(flagA, flagB)
  {
    int i;
    for (i = 0; i < 100; i++) {
      int j;
      for (j = 0; j < 100; j++) {
#pragma omp critical(A)
        {
          unsigned char val_of_flagA = j & 0x1;
          if (flagA != val_of_flagA)
            __builtin_abort();
          flagA = (~val_of_flagA) & 0x1;
        }
#pragma omp critical(B)
        {
          unsigned char val_of_flagB = j & 0x1;
          if (flagB != val_of_flagB)
            __builtin_abort();
          flagB = (~val_of_flagB) & 0x1;
        }
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L9
L0:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *parse(char *fileContents) {
  char *parsed;
  while (*fileContents != '\0') {
    if (*fileContents == '\n') {
    }
    *fileContents++;
  }
  return parsed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L0
L16:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L16
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *parse(char *fileContents) {
  char *parsed;
  while (*fileContents != '\0') {
    if (*fileContents == '\n') {
    }
    *fileContents++;
  }
  return parsed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse>:
  endbr64
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L13:
  add    $0x1,%rdi
L11:
  cmpb   $0x0,(%rdi)
  jne    L13
  xor    %eax,%eax
  ret
```

assistant: ```c
char *parse(char *fileContents) {
  char *parsed;
  while (*fileContents != '\0') {
    if (*fileContents == '\n') {
    }
    *fileContents++;
  }
  return parsed;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse>:
  endbr64
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x1,%rdi
L12:
  cmpb   $0x0,(%rdi)
  jne    L15
  xor    %eax,%eax
  ret
```

assistant: ```c
char *parse(char *fileContents) {
  char *parsed;
  while (*fileContents != '\0') {
    if (*fileContents == '\n') {
    }
    *fileContents++;
  }
  return parsed;
}
```