ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%edx
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L13:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <val@plt>
  imul   -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  subl   $0x1,-0xc(%rbp)
L14:
  cmpl   $0x0,-0xc(%rbp)
  jns    L13
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D19
data_type: string

tool: D2: El numero es %s y su base es %d


tool: D19: El numero en base decimal es: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int base = atoi(argv[2]);
  printf("El numero es %s y su base es %d\n", argv[1], base);
  int len = strlen(argv[1]);
  int power = 1;
  int num = 0;
  int i;
  for (i = len - 1; i >= 0; i--) {
    num += val(argv[1][i]) * power;
    power *= base;
  }
  printf("El numero en base decimal es: %d\n", num);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r13
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r15d
  mov    0x8(%r13),%rsi
  mov    %eax,%edx
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%r13),%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L11
  movslq %ebx,%rbx
  movslq %eax,%r14
  sub    $0x2,%r14
  lea    -0x1(%rax),%eax
  sub    %rax,%r14
  mov    $0x0,%r12d
  mov    $0x1,%ebp
L6:
  mov    0x8(%r13),%rax
  movsbl (%rax,%rbx,1),%edi
  call   <val@plt>
  imul   %ebp,%eax
  add    %eax,%r12d
  imul   %r15d,%ebp
  sub    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L6
L1:
  mov    %r12d,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    $0x0,%r12d
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D19
datatype: string
name: read_data
arguments: label: D10
datatype: string

tool: D19: El numero es %s y su base es %d


tool: D10: El numero en base decimal es: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int base = atoi(argv[2]);
  printf("El numero es %s y su base es %d\n", argv[1], base);
  int len = strlen(argv[1]);
  int power = 1;
  int num = 0;
  int i;
  for (i = len - 1; i >= 0; i--) {
    num += val(argv[1][i]) * power;
    power *= base;
  }
  printf("El numero en base decimal es: %d\n", num);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    0x8(%r15),%rsi
  lea    D8(%rip),%rdi
  mov    %eax,%edx
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%r15),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L24
  movslq %eax,%r12
  movslq %edx,%rbx
  mov    %edx,%edx
  xor    %r14d,%r14d
  sub    $0x2,%r12
  mov    $0x1,%ebp
  sub    %rdx,%r12
  nopl   0x0(%rax)
L15:
  mov    0x8(%r15),%rax
  movsbl (%rax,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <val@plt>
  imul   %ebp,%eax
  imul   %r13d,%ebp
  add    %eax,%r14d
  cmp    %r12,%rbx
  jne    L15
L23:
  mov    %r14d,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  xor    %r14d,%r14d
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D8: El numero es %s y su base es %d


tool: D3: El numero en base decimal es: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int base = atoi(argv[2]);
  printf("El numero es %s y su base es %d\n", argv[1], base);
  int len = strlen(argv[1]);
  int power = 1;
  int num = 0;
  int i;
  for (i = len - 1; i >= 0; i--) {
    num += val(argv[1][i]) * power;
    power *= base;
  }
  printf("El numero en base decimal es: %d\n", num);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    0x8(%r15),%rsi
  lea    D12(%rip),%rdi
  mov    %eax,%edx
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%r15),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L13
  movslq %eax,%r12
  movslq %edx,%rbx
  mov    %edx,%edx
  xor    %r14d,%r14d
  sub    $0x2,%r12
  mov    $0x1,%ebp
  sub    %rdx,%r12
  nopl   0x0(%rax)
L27:
  mov    0x8(%r15),%rax
  movsbl (%rax,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <val@plt>
  imul   %ebp,%eax
  imul   %r13d,%ebp
  add    %eax,%r14d
  cmp    %r12,%rbx
  jne    L27
L22:
  mov    %r14d,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  xor    %r14d,%r14d
  jmp    L22
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D12: El numero es %s y su base es %d


tool: D9: El numero en base decimal es: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int base = atoi(argv[2]);
  printf("El numero es %s y su base es %d\n", argv[1], base);
  int len = strlen(argv[1]);
  int power = 1;
  int num = 0;
  int i;
  for (i = len - 1; i >= 0; i--) {
    num += val(argv[1][i]) * power;
    power *= base;
  }
  printf("El numero en base decimal es: %d\n", num);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<skip_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L4:
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void skip_space(const char **ptr) {
  const char *s = *ptr;
  while (isspace(*s)) {
    s++;
  }
  *ptr = s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skip_space>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rbx
  jmp    L19
L13:
  add    $0x1,%rbx
L19:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
  mov    %rbx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void skip_space(const char **ptr) {
  const char *s = *ptr;
  while (isspace(*s)) {
    s++;
  }
  *ptr = s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_space>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rbx
L16:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void skip_space(const char **ptr) {
  const char *s = *ptr;
  while (isspace(*s)) {
    s++;
  }
  *ptr = s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_space>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rbx
L1:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  mov    %rbx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void skip_space(const char **ptr) {
  const char *s = *ptr;
  while (isspace(*s)) {
    s++;
  }
  *ptr = s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<respond_with_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <fsize@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L21
  mov    %rbp,%rdi
  call   <readfile@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %ebx,%edi
  call   <numlength@plt>
  mov    %eax,%r13d
  mov    %ebx,%edi
  call   <numlength@plt>
  lea    0x12(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    -0x1(%rbx),%edx
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %r13d,%r13
  lea    0x10(%r14,%r13,1),%rdx
  lea    (%rax,%rdx,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D27(%rip),%rdx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L18
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%ecx
  mov    %r13,%rsi
  mov    %r15d,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  sete   %bl
  movzbl %bl,%ebx
  neg    %ebx
L18:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L21:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  mov    $0xffffffff,%ebx
  jmp    L21
```

tool_calls: name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D13
datatype: string

tool: D15: Content-Length:%d


tool: D27: HTTP/1.1 200 OK


tool: D13: %s%s
%s

assistant: ```c
int respond_with_file(int connfd, char *filename) {
  int rval = 0;
  long message_size;
  char *message;
  char *status;
  char *content_length;
  char *content;
  off_t filesize;
  message_size = 0;
  status = "HTTP/1.1 200 OK\n";
  message_size += strlen(status);
  if ((filesize = fsize(filename)) == -1) {
    return -1;
  }
  if ((content = readfile(filename)) == NULL) {
    return -1;
  }
  message_size += strlen(content);
  message_size += numlength(filesize);
  content_length = malloc((18 + numlength(filesize)) * sizeof(char));
  if (sprintf(content_length, "Content-Length:%d\n", (int)filesize - 1) == -1) {
    rval = -1;
    goto out;
  }
  message_size += strlen(content_length);
  message = malloc(message_size * sizeof(char));
  if (sprintf(message, "%s%s\n%s", status, content_length, content) == -1) {
    rval = -1;
    goto end;
  }
  if (send(connfd, message, strlen(message), 0) == -1) {
    rval = -1;
    goto end;
  }
end:
  free(message);
out:
  free(content_length);
  free(content);
  return rval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<respond_with_file>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fsize@plt>
  cmp    $0xffffffff,%eax
  je     L14
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <readfile@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %ebx,%edi
  mov    %rax,%r15
  call   <numlength@plt>
  mov    %ebx,%edi
  movslq %eax,%r13
  call   <numlength@plt>
  lea    0x12(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  lea    D7(%rip),%rsi
  lea    -0x1(%rbx),%edx
  mov    %rax,%r12
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x10(%r15,%r13,1),%rdx
  lea    (%rax,%rdx,1),%rdi
  call   <malloc@plt>
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D1(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r15
  lea    D16(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %eax,%r13d
  cmp    $0xffffffff,%eax
  je     L19
  mov    %r15,%rdi
  xor    %r13d,%r13d
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %r15,%rsi
  mov    %r14d,%edi
  mov    %rax,%rdx
  call   <send@plt>
  cmp    $0xffffffff,%eax
  sete   %r13b
  neg    %r13d
L19:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L24:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xffffffff,%r13d
  jmp    L24
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D16
data_type: string

tool: D7: Content-Length:%d


tool: D1: HTTP/1.1 200 OK


tool: D16: %s%s
%s

assistant: ```c
int respond_with_file(int connfd, char *filename) {
  int rval = 0;
  long message_size;
  char *message;
  char *status;
  char *content_length;
  char *content;
  off_t filesize;
  message_size = 0;
  status = "HTTP/1.1 200 OK\n";
  message_size += strlen(status);
  if ((filesize = fsize(filename)) == -1) {
    return -1;
  }
  if ((content = readfile(filename)) == NULL) {
    return -1;
  }
  message_size += strlen(content);
  message_size += numlength(filesize);
  content_length = malloc((18 + numlength(filesize)) * sizeof(char));
  if (sprintf(content_length, "Content-Length:%d\n", (int)filesize - 1) == -1) {
    rval = -1;
    goto out;
  }
  message_size += strlen(content_length);
  message = malloc(message_size * sizeof(char));
  if (sprintf(message, "%s%s\n%s", status, content_length, content) == -1) {
    rval = -1;
    goto end;
  }
  if (send(connfd, message, strlen(message), 0) == -1) {
    rval = -1;
    goto end;
  }
end:
  free(message);
out:
  free(content_length);
  free(content);
  return rval;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<respond_with_file>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fsize@plt>
  cmp    $0xffffffff,%eax
  je     L33
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <readfile@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L33
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %ebx,%edi
  mov    %rax,%r15
  call   <numlength@plt>
  mov    %ebx,%edi
  movslq %eax,%r13
  call   <numlength@plt>
  lea    0x12(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  lea    D1(%rip),%rsi
  lea    -0x1(%rbx),%edx
  mov    %rax,%r12
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x10(%r15,%r13,1),%rdx
  lea    (%rax,%rdx,1),%rdi
  call   <malloc@plt>
  mov    %rbp,%r8
  mov    %r12,%rcx
  lea    D23(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r15
  lea    D19(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %eax,%r13d
  cmp    $0xffffffff,%eax
  je     L15
  mov    %r15,%rdi
  xor    %r13d,%r13d
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %r15,%rsi
  mov    %r14d,%edi
  mov    %rax,%rdx
  call   <send@plt>
  cmp    $0xffffffff,%eax
  sete   %r13b
  neg    %r13d
L15:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L24:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    $0xffffffff,%r13d
  jmp    L24
```

tool_calls: name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D23
type: string
name: read_data
arguments: label: D19
type: string

tool: D1: Content-Length:%d


tool: D23: HTTP/1.1 200 OK


tool: D19: %s%s
%s

assistant: ```c
int respond_with_file(int connfd, char *filename) {
  int rval = 0;
  long message_size;
  char *message;
  char *status;
  char *content_length;
  char *content;
  off_t filesize;
  message_size = 0;
  status = "HTTP/1.1 200 OK\n";
  message_size += strlen(status);
  if ((filesize = fsize(filename)) == -1) {
    return -1;
  }
  if ((content = readfile(filename)) == NULL) {
    return -1;
  }
  message_size += strlen(content);
  message_size += numlength(filesize);
  content_length = malloc((18 + numlength(filesize)) * sizeof(char));
  if (sprintf(content_length, "Content-Length:%d\n", (int)filesize - 1) == -1) {
    rval = -1;
    goto out;
  }
  message_size += strlen(content_length);
  message = malloc(message_size * sizeof(char));
  if (sprintf(message, "%s%s\n%s", status, content_length, content) == -1) {
    rval = -1;
    goto end;
  }
  if (send(connfd, message, strlen(message), 0) == -1) {
    rval = -1;
    goto end;
  }
end:
  free(message);
out:
  free(content_length);
  free(content);
  return rval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<neg_deinterleave>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L11
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L34
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  sar    %eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L23
L34:
  mov    -0x4(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  jmp    L23
L11:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int neg_deinterleave(int x, int ref) {
  if (x < 2 * ref - 1) {
    if (x & 1)
      return ref - 1 - (x >> 1);
    else
      return ref + (x >> 1);
  } else
    return x + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<neg_deinterleave>:
  endbr64
  lea    -0x1(%rsi,%rsi,1),%edx
  lea    0x1(%rdi),%eax
  cmp    %edi,%edx
  jle    L3
  test   $0x1,%dil
  je     L16
  lea    -0x1(%rsi),%eax
  sar    %edi
  sub    %edi,%eax
  ret
L16:
  sar    %edi
  lea    (%rdi,%rsi,1),%eax
L3:
  ret
```

assistant: ```c
int neg_deinterleave(int x, int ref) {
  if (x < 2 * ref - 1) {
    if (x & 1)
      return ref - 1 - (x >> 1);
    else
      return ref + (x >> 1);
  } else
    return x + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<neg_deinterleave>:
  endbr64
  lea    -0x1(%rsi,%rsi,1),%edx
  lea    0x1(%rdi),%eax
  cmp    %edi,%edx
  jle    L6
  mov    %edi,%edx
  lea    -0x1(%rsi),%eax
  sar    %edx
  sub    %edx,%eax
  add    %edx,%esi
  and    $0x1,%edi
  cmove  %esi,%eax
L6:
  ret
```

assistant: ```c
int neg_deinterleave(int x, int ref) {
  if (x < 2 * ref - 1) {
    if (x & 1)
      return ref - 1 - (x >> 1);
    else
      return ref + (x >> 1);
  } else
    return x + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<neg_deinterleave>:
  endbr64
  lea    -0x1(%rsi,%rsi,1),%edx
  lea    0x1(%rdi),%eax
  cmp    %edi,%edx
  jle    L0
  mov    %edi,%edx
  lea    -0x1(%rsi),%eax
  sar    %edx
  sub    %edx,%eax
  add    %edx,%esi
  and    $0x1,%edi
  cmove  %esi,%eax
L0:
  ret
```

assistant: ```c
int neg_deinterleave(int x, int ref) {
  if (x < 2 * ref - 1) {
    if (x & 1)
      return ref - 1 - (x >> 1);
    else
      return ref + (x >> 1);
  } else
    return x + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unicode_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x10(%rbp)
  cmpl   $0x10ffff,-0x14(%rbp)
  jle    L53
  mov    $0xffffffff,%eax
  jmp    L1
L53:
  cmpl   $0xffff,-0x14(%rbp)
  jle    L56
  movl   $0x4,-0x10(%rbp)
  jmp    L85
L56:
  cmpl   $0x7ff,-0x14(%rbp)
  jle    L38
  movl   $0x3,-0x10(%rbp)
  jmp    L85
L38:
  cmpl   $0x7f,-0x14(%rbp)
  jle    L85
  movl   $0x2,-0x10(%rbp)
L85:
  cmpl   $0x1,-0x10(%rbp)
  jne    L49
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L16
L49:
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L44
L89:
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  sarl   $0x6,-0x14(%rbp)
  subl   $0x1,-0xc(%rbp)
L44:
  cmpl   $0x0,-0xc(%rbp)
  jg     L89
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x8,%eax
  sub    -0x10(%rbp),%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    $0xff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
L16:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int unicode_encode(int n, char *ptr) {
  int count = 1;
  if (n > 0x10ffff)
    return -1;
  if (n > 0xffff)
    count = 4;
  else if (n > 0x7ff)
    count = 3;
  else if (n > 0x7f)
    count = 2;
  if (count == 1)
    ptr[0] = n;
  else {
    for (int i = (count - 1); i > 0; i--) {
      ptr[i] = 0x80 | (0x3f & n);
      n >>= 6;
    }
    int mask = (0xff >> (1 + count));
    int code = (0xff << (8 - count)) & 0xff;
    ptr[0] = code | (mask & n);
  }
  ptr[count] = 0;
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unicode_encode>:
  endbr64
  cmp    $0x10ffff,%edi
  jg     L73
  cmp    $0xffff,%edi
  jg     L88
  cmp    $0x7ff,%edi
  jg     L66
  cmp    $0x7f,%edi
  jg     L8
  mov    %edi,%eax
  mov    $0x1,%r8d
  jmp    L58
L88:
  mov    $0x4,%r8d
L18:
  lea    -0x1(%r8),%eax
  cltq
L13:
  mov    %edi,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,(%rsi,%rax,1)
  sar    $0x6,%edi
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L13
  lea    0x1(%r8),%ecx
  mov    $0xff,%edx
  mov    %edx,%eax
  sar    %cl,%eax
  and    %edi,%eax
  mov    $0x8,%ecx
  sub    %r8d,%ecx
  shl    %cl,%edx
  or     %edx,%eax
L58:
  mov    %al,(%rsi)
  movslq %r8d,%rax
  movb   $0x0,(%rsi,%rax,1)
L63:
  mov    %r8d,%eax
  ret
L66:
  mov    $0x3,%r8d
  jmp    L18
L8:
  mov    $0x2,%r8d
  jmp    L18
L73:
  mov    $0xffffffff,%r8d
  jmp    L63
```

assistant: ```c
int unicode_encode(int n, char *ptr) {
  int count = 1;
  if (n > 0x10ffff)
    return -1;
  if (n > 0xffff)
    count = 4;
  else if (n > 0x7ff)
    count = 3;
  else if (n > 0x7f)
    count = 2;
  if (count == 1)
    ptr[0] = n;
  else {
    for (int i = (count - 1); i > 0; i--) {
      ptr[i] = 0x80 | (0x3f & n);
      n >>= 6;
    }
    int mask = (0xff >> (1 + count));
    int code = (0xff << (8 - count)) & 0xff;
    ptr[0] = code | (mask & n);
  }
  ptr[count] = 0;
  return count;
}
```