ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D55(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L21
  mov    %edx,%eax
  lea    D25(%rip),%rbx
  lea    D16(%rip),%r12
  shr    $0x1f,%eax
  mov    %eax,%ebp
  nopl   0x0(%rax)
L74:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %eax,0x4(%rsp)
  add    %ecx,%ecx
  sub    %ecx,%edx
  mov    %edx,%esi
  neg    %esi
  cmovs  %edx,%esi
  test   %eax,%eax
  jne    L64
  test   %bpl,%bpl
  jne    L37
L64:
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L74
L0:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L37:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L74
  jmp    L0
L21:
  lea    D49(%rip),%rdi
  call   <puts@plt>
  jmp    L0
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D55
type: string
name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D16
type: string
name: read_data
arguments: data_tag: D10
type: string
name: read_data
arguments: data_tag: D49
type: string

tool: D55: 
Enter an integer > 

tool: D9: %d

tool: D25: %d


tool: D16: -%d


tool: D10: That's all, have a nice day!

tool: D49: 0

assistant: ```c
int main() {
  int n, t, d;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  printf("\n");
  t = n;
  if (n == 0)
    printf("0\n");
  else
    while (n != 0) {
      d = n % 10;
      n = n / 10;
      if ((t < 0) && (n == 0))
        printf("-%d\n", abs(d));
      else
        printf("%d\n", abs(d));
    }
  printf("That's all, have a nice day!\n");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L30
L2:
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x2d,-0x18(%rbp)
  je     L4
  cmpl   $0x2b,-0x18(%rbp)
  jne    L12
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x18(%rbp)
L12:
  movq   $0x0,-0x10(%rbp)
  jmp    L21
L26:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L26
  cmpl   $0x2d,-0x14(%rbp)
  jne    L1
  mov    -0x10(%rbp),%rax
  neg    %rax
  jmp    L47
L1:
  mov    -0x10(%rbp),%rax
L47:
  leave
  ret
```

assistant: ```c
long atol(const char *nptr) {
  int c;
  int sign;
  long total;
  const unsigned char *p = (const unsigned char *)nptr;
  while (isspace(*p))
    ++p;
  c = *p++;
  sign = c;
  if (c == '-' || c == '+')
    c = *p++;
  total = 0;
  while (isdigit(c)) {
    total = 10 * total + (c - '0');
    c = *p++;
  }
  if (sign == '-') {
    return -total;
  } else {
    return total;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  jmp    L55
L27:
  add    $0x1,%rbp
L55:
  movzbl 0x0(%rbp),%edi
  call   <isspace@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L27
  movzbl 0x0(%rbp),%eax
  movzbl %al,%r13d
  sub    $0x2b,%eax
  test   $0xfd,%al
  je     L53
  lea    0x1(%rbp),%r12
  mov    %r13d,%ebp
  jmp    L29
L53:
  lea    0x2(%rbp),%r12
  movzbl 0x1(%rbp),%ebp
  jmp    L29
L26:
  lea    (%rbx,%rbx,4),%rax
  sub    $0x30,%ebp
  movslq %ebp,%rbp
  lea    0x0(%rbp,%rax,2),%rbx
  add    $0x1,%r12
  movzbl -0x1(%r12),%ebp
L29:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L26
  mov    %rbx,%rax
  neg    %rax
  cmp    $0x2d,%r13d
  cmove  %rax,%rbx
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long atol(const char *nptr) {
  int c;
  int sign;
  long total;
  const unsigned char *p = (const unsigned char *)nptr;
  while (isspace(*p))
    ++p;
  c = *p++;
  sign = c;
  if (c == '-' || c == '+')
    c = *p++;
  total = 0;
  while (isdigit(c)) {
    total = 10 * total + (c - '0');
    c = *p++;
  }
  if (sign == '-') {
    return -total;
  } else {
    return total;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L10:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rax,%r12
  mov    %rbx,%rax
  add    $0x1,%rbx
  test   %r12,%r12
  jne    L10
  movzbl (%rax),%r13d
  mov    %r13d,%edx
  mov    %r13d,%ebp
  sub    $0x2b,%edx
  and    $0xfd,%edx
  jne    L13
  movzbl 0x1(%rax),%ebp
  lea    0x2(%rax),%rbx
  jmp    L13
  xchg   %ax,%ax
L1:
  sub    $0x30,%ebp
  lea    (%r12,%r12,4),%rax
  add    $0x1,%rbx
  movslq %ebp,%rbp
  lea    0x0(%rbp,%rax,2),%r12
  movzbl -0x1(%rbx),%ebp
L13:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L1
  mov    %r12,%rax
  neg    %rax
  cmp    $0x2d,%r13d
  cmove  %rax,%r12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long atol(const char *nptr) {
  int c;
  int sign;
  long total;
  const unsigned char *p = (const unsigned char *)nptr;
  while (isspace(*p))
    ++p;
  c = *p++;
  sign = c;
  if (c == '-' || c == '+')
    c = *p++;
  total = 0;
  while (isdigit(c)) {
    total = 10 * total + (c - '0');
    c = *p++;
  }
  if (sign == '-') {
    return -total;
  } else {
    return total;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L38:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rax,%r12
  mov    %rbx,%rax
  add    $0x1,%rbx
  test   %r12,%r12
  jne    L38
  movzbl (%rax),%r13d
  mov    %r13d,%edx
  mov    %r13d,%ebp
  sub    $0x2b,%edx
  and    $0xfd,%edx
  jne    L26
  movzbl 0x1(%rax),%ebp
  lea    0x2(%rax),%rbx
  jmp    L26
  xchg   %ax,%ax
L5:
  sub    $0x30,%ebp
  lea    (%r12,%r12,4),%rax
  add    $0x1,%rbx
  movslq %ebp,%rbp
  lea    0x0(%rbp,%rax,2),%r12
  movzbl -0x1(%rbx),%ebp
L26:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12,%rax
  neg    %rax
  cmp    $0x2d,%r13d
  cmove  %rax,%r12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long atol(const char *nptr) {
  int c;
  int sign;
  long total;
  const unsigned char *p = (const unsigned char *)nptr;
  while (isspace(*p))
    ++p;
  c = *p++;
  sign = c;
  if (c == '-' || c == '+')
    c = *p++;
  total = 0;
  while (isdigit(c)) {
    total = 10 * total + (c - '0');
    c = *p++;
  }
  if (sign == '-') {
    return -total;
  } else {
    return total;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fun1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <fun1>
  add    $0x1,%eax
  jmp    L17
L2:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
int fun1(char *a) {
  if (*a)
    return fun1(a + 1) + 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fun1>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  add    $0x1,%rdi
  call   <fun1>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fun1(char *a) {
  if (*a)
    return fun1(a + 1) + 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fun1>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  mov    $0x1,%eax
  xchg   %ax,%ax
L12:
  add    $0x1,%rdi
  mov    %eax,%r8d
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun1(char *a) {
  if (*a)
    return fun1(a + 1) + 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fun1>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L13
  mov    $0x1,%eax
  xchg   %ax,%ax
L10:
  add    $0x1,%rdi
  mov    %eax,%r8d
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L10
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun1(char *a) {
  if (*a)
    return fun1(a + 1) + 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<merge_free_blocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <merge_postfix@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <merge_prefix@plt>
  nop
  leave
  ret
```

assistant: ```c
void merge_free_blocks(struct allocate_info *head, struct allocate_info *current) {
  merge_postfix(head, current);
  merge_prefix(head, current);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<merge_free_blocks>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <merge_postfix@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <merge_prefix@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void merge_free_blocks(struct allocate_info *head, struct allocate_info *current) {
  merge_postfix(head, current);
  merge_prefix(head, current);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<merge_free_blocks>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <merge_postfix@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <merge_prefix@plt>
```

assistant: ```c
void merge_free_blocks(struct allocate_info *head, struct allocate_info *current) {
  merge_postfix(head, current);
  merge_prefix(head, current);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<merge_free_blocks>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <merge_postfix@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <merge_prefix@plt>
```

assistant: ```c
void merge_free_blocks(struct allocate_info *head, struct allocate_info *current) {
  merge_postfix(head, current);
  merge_prefix(head, current);
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *x, int *y) {
  int tmp;
  tmp = *x;
  *x = *y;
  *y = tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *x, int *y) {
  int tmp;
  tmp = *x;
  *x = *y;
  *y = tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *x, int *y) {
  int tmp;
  tmp = *x;
  *x = *y;
  *y = tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *x, int *y) {
  int tmp;
  tmp = *x;
  *x = *y;
  *y = tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vmbuf_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  jmp    L89
L58:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <vmbuf_rloc@plt>
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L79
  mov    D18(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L51
  mov    $0x0,%eax
  jmp    L61
L51:
  mov    $0xffffffff,%eax
  jmp    L61
L79:
  cmpq   $0x0,-0x8(%rbp)
  jle    L80
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vmbuf_rseek@plt>
  jmp    L89
L80:
  mov    D21(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L61
L89:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <vmbuf_ravail@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L58
  mov    $0x1,%eax
L61:
  leave
  ret
```

assistant: ```c
int vmbuf_write(struct vmbuf *vmbuf, int fd) {
  ssize_t res;
  size_t rav;
  while ((rav = vmbuf_ravail(vmbuf)) > 0) {
    res = write(fd, vmbuf_rloc(vmbuf), rav);
    if (res < 0)
      return (EAGAIN == errno ? 0 : -1);
    else if (res > 0)
      vmbuf_rseek(vmbuf, res);
    else
      return errno = ENODATA, -1;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vmbuf_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  jmp    L38
L40:
  mov    D21(%rip),%rdx
  mov    D31(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L23
L12:
  mov    %rbp,%rdi
  call   <vmbuf_rseek@plt>
L38:
  mov    %rbp,%rdi
  call   <vmbuf_ravail@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L52
  mov    %rbp,%rdi
  call   <vmbuf_rloc@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  mov    %r12d,%edi
  call   <write@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  js     L40
  jg     L12
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  mov    D31(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L23
L52:
  mov    $0x1,%eax
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vmbuf_write(struct vmbuf *vmbuf, int fd) {
  ssize_t res;
  size_t rav;
  while ((rav = vmbuf_ravail(vmbuf)) > 0) {
    res = write(fd, vmbuf_rloc(vmbuf), rav);
    if (res < 0)
      return (EAGAIN == errno ? 0 : -1);
    else if (res > 0)
      vmbuf_rseek(vmbuf, res);
    else
      return errno = ENODATA, -1;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vmbuf_write>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L22
  nop
L8:
  mov    %rbx,%rdi
  call   <vmbuf_rloc@plt>
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <write@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  js     L2
  je     L27
  mov    %rbx,%rdi
  call   <vmbuf_rseek@plt>
L22:
  mov    %rbx,%rdi
  call   <vmbuf_ravail@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L8
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    D14(%rip),%rdx
  mov    D6(%rip),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  pop    %r12
  movzbl %al,%eax
  neg    %eax
  ret
  nopl   0x0(%rax)
L27:
  mov    D28(%rip),%rax
  mov    (%rax),%rdx
  mov    D6(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vmbuf_write(struct vmbuf *vmbuf, int fd) {
  ssize_t res;
  size_t rav;
  while ((rav = vmbuf_ravail(vmbuf)) > 0) {
    res = write(fd, vmbuf_rloc(vmbuf), rav);
    if (res < 0)
      return (EAGAIN == errno ? 0 : -1);
    else if (res > 0)
      vmbuf_rseek(vmbuf, res);
    else
      return errno = ENODATA, -1;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vmbuf_write>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L38
  nop
L23:
  mov    %rbx,%rdi
  call   <vmbuf_rloc@plt>
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <write@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  js     L20
  je     L32
  mov    %rbx,%rdi
  call   <vmbuf_rseek@plt>
L38:
  mov    %rbx,%rdi
  call   <vmbuf_ravail@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L23
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    D9(%rip),%rdx
  mov    D10(%rip),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  pop    %r12
  movzbl %al,%eax
  neg    %eax
  ret
  nopl   0x0(%rax)
L32:
  mov    D4(%rip),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vmbuf_write(struct vmbuf *vmbuf, int fd) {
  ssize_t res;
  size_t rav;
  while ((rav = vmbuf_ravail(vmbuf)) > 0) {
    res = write(fd, vmbuf_rloc(vmbuf), rav);
    if (res < 0)
      return (EAGAIN == errno ? 0 : -1);
    else if (res > 0)
      vmbuf_rseek(vmbuf, res);
    else
      return errno = ENODATA, -1;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findInOutFilesAppend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L39:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L18
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string

tool: D17: >>

tool: D18: <

assistant: ```c
void findInOutFilesAppend(char **tokens, char *inputFile, char *outputFile) {
  int i;
  for (i = 0; tokens[i] != NULL; i++) {
    if (strcmp(tokens[i], ">>") == 0)
      strcpy(outputFile, tokens[i + 1]);
    if (strcmp(tokens[i], "<") == 0)
      strcpy(inputFile, tokens[i + 1]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findInOutFilesAppend>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L21
  mov    %rsi,%r13
  mov    %rdx,%r14
  add    $0x8,%rbx
  lea    D13(%rip),%r12
  lea    D15(%rip),%rbp
  jmp    L54
L65:
  mov    (%rbx),%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  jmp    L24
L31:
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  je     L21
L54:
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L65
L24:
  mov    -0x8(%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L31
  mov    (%rbx),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  jmp    L31
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
type_infered: string
name: disassemble_data
arguments: label: D15
type_infered: string

tool: D13: >>

tool: D15: <

assistant: ```c
void findInOutFilesAppend(char **tokens, char *inputFile, char *outputFile) {
  int i;
  for (i = 0; tokens[i] != NULL; i++) {
    if (strcmp(tokens[i], ">>") == 0)
      strcpy(outputFile, tokens[i + 1]);
    if (strcmp(tokens[i], "<") == 0)
      strcpy(inputFile, tokens[i + 1]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<findInOutFilesAppend>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L66
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    0x8(%rax),%rbx
  jmp    L29
  nopl   (%rax)
L2:
  mov    -0x8(%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L61
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L30
L29:
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  mov    (%rbx),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  jmp    L2
  nop
L61:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <strcpy@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L29
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L66:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
data_type: string
name: retrieve_data
arguments: data_label: D14
data_type: string

tool: D17: >>

tool: D14: <

assistant: ```c
void findInOutFilesAppend(char **tokens, char *inputFile, char *outputFile) {
  int i;
  for (i = 0; tokens[i] != NULL; i++) {
    if (strcmp(tokens[i], ">>") == 0)
      strcpy(outputFile, tokens[i + 1]);
    if (strcmp(tokens[i], "<") == 0)
      strcpy(inputFile, tokens[i + 1]);
  }
}
```