ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bubble_sort>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    %esi,%r12d
  mov    $0x1,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   (%rax)
L26:
  cmp    %r12d,%eax
  jge    L3
L40:
  movslq %eax,%rbx
L31:
  mov    0x0(%rbp,%rbx,4),%edi
  mov    %ebx,%edx
  lea    0x1(%rbx),%eax
  cmp    %edi,-0x4(%rbp,%rbx,4)
  jle    L26
  lea    -0x1(%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  mov    $0x1,%ecx
  cmp    %ebx,%r12d
  jg     L31
  mov    $0x1,%eax
  xor    %ecx,%ecx
  cmp    %r12d,%eax
  jl     L40
  nopl   0x0(%rax)
L3:
  test   %ecx,%ecx
  je     L53
  cmp    $0x1,%r12d
  jle    L53
  mov    %ecx,%eax
  xor    %ecx,%ecx
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bubble_sort(int *array, int size) {
  int i;
  int swapped = 1;
  while (swapped) {
    swapped = 0;
    for (i = 1; i < size; i++) {
      if (array[i - 1] > array[i]) {
        swap(array, i - 1, i);
        swapped = 1;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bubble_sort>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    %esi,%r12d
  mov    $0x1,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   (%rax)
L8:
  cmp    %r12d,%eax
  jge    L67
L36:
  movslq %eax,%rbx
L57:
  mov    0x0(%rbp,%rbx,4),%edi
  mov    %ebx,%edx
  lea    0x1(%rbx),%eax
  cmp    %edi,-0x4(%rbp,%rbx,4)
  jle    L8
  lea    -0x1(%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  mov    $0x1,%ecx
  cmp    %ebx,%r12d
  jg     L57
  mov    $0x1,%eax
  xor    %ecx,%ecx
  cmp    %r12d,%eax
  jl     L36
  nopl   0x0(%rax)
L67:
  test   %ecx,%ecx
  je     L37
  cmp    $0x1,%r12d
  jle    L37
  mov    %ecx,%eax
  xor    %ecx,%ecx
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bubble_sort(int *array, int size) {
  int i;
  int swapped = 1;
  while (swapped) {
    swapped = 0;
    for (i = 1; i < size; i++) {
      if (array[i - 1] > array[i]) {
        swap(array, i - 1, i);
        swapped = 1;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<autoStructTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzwl -0x14(%rbp),%eax
  mov    %ax,-0x12(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %ax,-0x10(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %ax,-0xe(%rbp)
  lea    D3(%rip),%rax
  mov    %al,-0xc(%rbp)
  movb   $0x0,-0xb(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string

tool: D3: abc

assistant: ```c
void autoStructTest() {
  struct s1 {
    char a;
    char b;
  } t1;
  struct s2 {
    struct s1 c;
  } t2 = {t1};
  struct s1 t3[] = {t1, t1, "abc", 0};
  int t4[sizeof t3 == 6 ? 1 : -1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<autoStructTest>:
  endbr64
  ret
```

assistant: ```c
void autoStructTest() {
  struct s1 {
    char a;
    char b;
  } t1;
  struct s2 {
    struct s1 c;
  } t2 = {t1};
  struct s1 t3[] = {t1, t1, "abc", 0};
  int t4[sizeof t3 == 6 ? 1 : -1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<autoStructTest>:
  endbr64
  ret
```

assistant: ```c
void autoStructTest() {
  struct s1 {
    char a;
    char b;
  } t1;
  struct s2 {
    struct s1 c;
  } t2 = {t1};
  struct s1 t3[] = {t1, t1, "abc", 0};
  int t4[sizeof t3 == 6 ? 1 : -1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<autoStructTest>:
  endbr64
  ret
```

assistant: ```c
void autoStructTest() {
  struct s1 {
    char a;
    char b;
  } t1;
  struct s2 {
    struct s1 c;
  } t2 = {t1};
  struct s1 t3[] = {t1, t1, "abc", 0};
  int t4[sizeof t3 == 6 ? 1 : -1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<makeSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void makeSet(int *S, int size) {
  int i;
  for (i = 0; i < size; i++)
    S[i] = i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<makeSet>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %esi,%esi
  mov    $0x0,%eax
L8:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L8
L3:
  ret
```

assistant: ```c
void makeSet(int *S, int size) {
  int i;
  for (i = 0; i < size; i++)
    S[i] = i;
}
```
user: What is the c source code of the assembly code below?

```asm
<makeSet>:
  endbr64
  test   %esi,%esi
  jle    L5
  movslq %esi,%rsi
  xor    %eax,%eax
  nopl   (%rax)
L1:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L1
L5:
  ret
```

assistant: ```c
void makeSet(int *S, int size) {
  int i;
  for (i = 0; i < size; i++)
    S[i] = i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<makeSet>:
  endbr64
  test   %esi,%esi
  jle    L65
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L40
  mov    %esi,%edx
  movdqa D12(%rip),%xmm0
  movdqa D8(%rip),%xmm2
  mov    %rdi,%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L10:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L10
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L44
L21:
  movslq %eax,%rdx
  mov    %eax,(%rdi,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%esi
  jle    L65
  add    $0x2,%eax
  mov    %edx,0x4(%rdi,%rcx,1)
  cmp    %eax,%esi
  jle    L65
  mov    %eax,0x8(%rdi,%rcx,1)
L65:
  ret
  nopl   (%rax)
L44:
  ret
L40:
  xor    %eax,%eax
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: data_label: D12
datatype: byte[16]
name: disassemble_data
arguments: data_label: D8
datatype: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D8": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void makeSet(int *S, int size) {
  int i;
  for (i = 0; i < size; i++)
    S[i] = i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fileExists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L10
L13:
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: r

assistant: ```c
int fileExists(const char *path) {
  FILE *fd = fopen(path, "r");
  if (fd) {
    fclose(fd);
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fileExists>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L8
  call   <fclose@plt>
  mov    $0x1,%eax
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: r

assistant: ```c
int fileExists(const char *path) {
  FILE *fd = fopen(path, "r");
  if (fd) {
    fclose(fd);
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fileExists>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  call   <fclose@plt>
  mov    $0x1,%eax
L1:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: r

assistant: ```c
int fileExists(const char *path) {
  FILE *fd = fopen(path, "r");
  if (fd) {
    fclose(fd);
    return 1;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fileExists>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L4
  call   <fclose@plt>
  mov    $0x1,%eax
L4:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: r

assistant: ```c
int fileExists(const char *path) {
  FILE *fd = fopen(path, "r");
  if (fd) {
    fclose(fd);
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printAllInstalledProblems>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <numberOfInstalledProblems@plt>
  mov    %eax,-0x4(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L1:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <installedProblemName@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L1
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string

tool: D1: Installed optimization problems:

tool: D11: %3d: %s


assistant: ```c
void printAllInstalledProblems(void) {
  int i, n;
  n = numberOfInstalledProblems();
  printf("Installed optimization problems:\n");
  for (i = 0; i < n; i++)
    printf("%3d: %s\n", i, installedProblemName(i));
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printAllInstalledProblems>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <numberOfInstalledProblems@plt>
  mov    %eax,%ebp
  lea    D13(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L1
  mov    $0x0,%ebx
  lea    D11(%rip),%r12
L18:
  mov    %ebx,%edi
  call   <installedProblemName@plt>
  mov    %rax,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L18
L1:
  mov    $0x0,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D13
type: string
name: read_data
arguments: tag: D11
type: string

tool: D13: Installed optimization problems:

tool: D11: %3d: %s


assistant: ```c
void printAllInstalledProblems(void) {
  int i, n;
  n = numberOfInstalledProblems();
  printf("Installed optimization problems:\n");
  for (i = 0; i < n; i++)
    printf("%3d: %s\n", i, installedProblemName(i));
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printAllInstalledProblems>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <numberOfInstalledProblems@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%ebp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L19
  xor    %ebx,%ebx
  lea    D3(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  call   <installedProblemName@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L2
L19:
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10d0 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D8: Installed optimization problems:

tool: D3: %3d: %s


assistant: ```c
void printAllInstalledProblems(void) {
  int i, n;
  n = numberOfInstalledProblems();
  printf("Installed optimization problems:\n");
  for (i = 0; i < n; i++)
    printf("%3d: %s\n", i, installedProblemName(i));
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printAllInstalledProblems>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <numberOfInstalledProblems@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%ebp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L2
  xor    %ebx,%ebx
  lea    D4(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%edi
  call   <installedProblemName@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L14
L2:
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10d0 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string

tool: D13: Installed optimization problems:

tool: D4: %3d: %s


assistant: ```c
void printAllInstalledProblems(void) {
  int i, n;
  n = numberOfInstalledProblems();
  printf("Installed optimization problems:\n");
  for (i = 0; i < n; i++)
    printf("%3d: %s\n", i, installedProblemName(i));
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fopen_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fopen_s(FILE **pFile, const char *filename, const char *mode) {
  *pFile = fopen(filename, mode);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fopen_s>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <fopen@plt>
  mov    %rax,(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fopen_s(FILE **pFile, const char *filename, const char *mode) {
  *pFile = fopen(filename, mode);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fopen_s>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <fopen@plt>
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fopen_s(FILE **pFile, const char *filename, const char *mode) {
  *pFile = fopen(filename, mode);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fopen_s>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <fopen@plt>
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fopen_s(FILE **pFile, const char *filename, const char *mode) {
  *pFile = fopen(filename, mode);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0xc,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L40
L3:
  movl   $0x0,-0x38(%rbp)
  jmp    L43
L13:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,-0x34(%rbp)
  addl   $0x1,-0x38(%rbp)
L43:
  cmpl   $0x2,-0x38(%rbp)
  jle    L13
  addl   $0x1,-0x3c(%rbp)
L40:
  cmpl   $0x1,-0x3c(%rbp)
  jle    L3
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: sum: %d


assistant: ```c
int main(void) {
  int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
  int(*p2arr[2])[3];
  p2arr[0] = &arr[0];
  p2arr[1] = &arr[1];
  int i, j, sum = 0;
  for (i = 0; i < 2; ++i) {
    for (j = 0; j < 3; ++j) {
      sum += (*p2arr[i])[j];
    }
  }
  printf("sum: %d\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: sum: %d


assistant: ```c
int main(void) {
  int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
  int(*p2arr[2])[3];
  p2arr[0] = &arr[0];
  p2arr[1] = &arr[1];
  int i, j, sum = 0;
  for (i = 0; i < 2; ++i) {
    for (j = 0; j < 3; ++j) {
      sum += (*p2arr[i])[j];
    }
  }
  printf("sum: %d\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: sum: %d


assistant: ```c
int main(void) {
  int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
  int(*p2arr[2])[3];
  p2arr[0] = &arr[0];
  p2arr[1] = &arr[1];
  int i, j, sum = 0;
  for (i = 0; i < 2; ++i) {
    for (j = 0; j < 3; ++j) {
      sum += (*p2arr[i])[j];
    }
  }
  printf("sum: %d\n", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: sum: %d


assistant: ```c
int main(void) {
  int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
  int(*p2arr[2])[3];
  p2arr[0] = &arr[0];
  p2arr[1] = &arr[1];
  int i, j, sum = 0;
  for (i = 0; i < 2; ++i) {
    for (j = 0; j < 3; ++j) {
      sum += (*p2arr[i])[j];
    }
  }
  printf("sum: %d\n", sum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L30:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L30
  sub    $0xc70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,-0x9c60(%rbp)
  mov    -0x9c60(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x9c58(%rbp)
  cmpq   $0x0,-0x9c58(%rbp)
  jne    L19
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L46
L19:
  movl   $0x0,-0x9c64(%rbp)
  jmp    L18
L56:
  lea    -0x9c50(%rbp),%rdx
  mov    -0x9c64(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x9c58(%rbp),%rax
  lea    D32(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  addl   $0x1,-0x9c64(%rbp)
L18:
  cmpl   $0x270f,-0x9c64(%rbp)
  jle    L56
  mov    -0x9c58(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    -0x9c50(%rbp),%rax
  mov    $0x2710,%esi
  mov    %rax,%rdi
  call   <selectionSortInt@plt>
  lea    -0x9c50(%rbp),%rax
  mov    $0x2710,%esi
  mov    %rax,%rdi
  call   <testSortedInts@plt>
  lea    -0x9c50(%rbp),%rax
  mov    $0x2710,%esi
  mov    %rax,%rdi
  call   <selectionSortReverseInt@plt>
  lea    -0x9c50(%rbp),%rax
  mov    $0x2710,%esi
  mov    %rax,%rdi
  call   <testReverseSortedInts@plt>
L46:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D23
datatype: string
name: unpack_data
arguments: data_label: D32
datatype: string

tool: D0: randomInts.txt

tool: D1: r

tool: D23: Error opening file

tool: D32: %d

assistant: ```c
int main(void) {
  char *filename = "randomInts.txt";
  int values[10000];
  FILE *myfile = fopen(filename, "r");
  if (myfile == NULL) {
    perror("Error opening file");
  } else {
    for (int i = 0; i < 10000; ++i) {
      fscanf(myfile, "%d", &values[i]);
    }
    fclose(myfile);
    selectionSortInt(values, 10000);
    testSortedInts(values, 10000);
    selectionSortReverseInt(values, 10000);
    testReverseSortedInts(values, 10000);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L33:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L33
  sub    $0xc58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c48(%rsp)
  xor    %eax,%eax
  lea    D37(%rip),%rsi
  lea    D29(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rsp,%rbx
  lea    0x9c40(%rsp),%r13
  lea    D15(%rip),%r12
  test   %rax,%rax
  je     L27
L46:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L46
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rsp,%rbx
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <selectionSortInt@plt>
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <testSortedInts@plt>
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <selectionSortReverseInt@plt>
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <testReverseSortedInts@plt>
L39:
  mov    0x9c48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x9c58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  jmp    L39
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D37
data_type: string
name: disassemble_data
arguments: label: D29
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string

tool: D37: r

tool: D29: randomInts.txt

tool: D15: %d

tool: D9: Error opening file

assistant: ```c
int main(void) {
  char *filename = "randomInts.txt";
  int values[10000];
  FILE *myfile = fopen(filename, "r");
  if (myfile == NULL) {
    perror("Error opening file");
  } else {
    for (int i = 0; i < 10000; ++i) {
      fscanf(myfile, "%d", &values[i]);
    }
    fclose(myfile);
    selectionSortInt(values, 10000);
    testSortedInts(values, 10000);
    selectionSortReverseInt(values, 10000);
    testReverseSortedInts(values, 10000);
  }
  return 0;
}
```