ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<proba_more_than>:
  endbr64
  cmp    %edi,%esi
  jg     L3
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x40,%rsp
  fnstcw 0x3e(%rsp)
  fldt   0x60(%rsp)
  movzwl 0x3e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x3c(%rsp)
  fldcw  0x3c(%rsp)
  fistpl (%rsp)
  fldcw  0x3e(%rsp)
  mov    (%rsp),%r12d
  fldz
  xchg   %ax,%ax
L18:
  fstpt  0x20(%rsp)
  mov    %ebx,%edi
  mov    %ebp,%esi
  call   <combination_eff@plt>
  mov    %ebx,%esi
  mov    %r12d,%edi
  fstpt  (%rsp)
  call   <powl@plt>
  fldt   (%rsp)
  mov    %ebp,%esi
  fnstcw 0x3e(%rsp)
  sub    %ebx,%esi
  add    $0x1,%ebx
  fmulp  %st,%st(1)
  movzwl 0x3e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x3c(%rsp)
  fstpt  0x10(%rsp)
  fld1
  fldt   0x60(%rsp)
  fsubrp %st,%st(1)
  fldcw  0x3c(%rsp)
  fistpl (%rsp)
  fldcw  0x3e(%rsp)
  mov    (%rsp),%edi
  call   <powl@plt>
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fldt   0x20(%rsp)
  faddp  %st,%st(1)
  cmp    %ebx,%ebp
  jge    L18
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L3:
  fldz
  ret
```

assistant: ```c
long double proba_more_than(int n, int k, long double proba) {
  long double result = 0.0;
  while (k <= n) {
    result += combination_eff(k, n) * powl(proba, k) * powl((1 - proba), (n - k));
    k++;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<proba_more_than>:
  endbr64
  cmp    %edi,%esi
  jg     L15
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x40,%rsp
  fnstcw 0x3e(%rsp)
  fldt   0x60(%rsp)
  movzwl 0x3e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x3c(%rsp)
  fldcw  0x3c(%rsp)
  fistpl (%rsp)
  fldcw  0x3e(%rsp)
  mov    (%rsp),%r12d
  fldz
  xchg   %ax,%ax
L2:
  fstpt  0x20(%rsp)
  mov    %ebx,%edi
  mov    %ebp,%esi
  call   <combination_eff@plt>
  mov    %ebx,%esi
  mov    %r12d,%edi
  fstpt  (%rsp)
  call   <powl@plt>
  fldt   (%rsp)
  mov    %ebp,%esi
  fnstcw 0x3e(%rsp)
  sub    %ebx,%esi
  add    $0x1,%ebx
  fmulp  %st,%st(1)
  movzwl 0x3e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x3c(%rsp)
  fstpt  0x10(%rsp)
  fld1
  fldt   0x60(%rsp)
  fsubrp %st,%st(1)
  fldcw  0x3c(%rsp)
  fistpl (%rsp)
  fldcw  0x3e(%rsp)
  mov    (%rsp),%edi
  call   <powl@plt>
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fldt   0x20(%rsp)
  faddp  %st,%st(1)
  cmp    %ebx,%ebp
  jge    L2
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L15:
  fldz
  ret
```

assistant: ```c
long double proba_more_than(int n, int k, long double proba) {
  long double result = 0.0;
  while (k <= n) {
    result += combination_eff(k, n) * powl(proba, k) * powl((1 - proba), (n - k));
    k++;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  movl   $0x1,-0x28(%rbp)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <strlwr@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  lea    -0x12(%rbp),%rdx
  cltq
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L38
L66:
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L53
  movl   $0x0,-0x28(%rbp)
  jmp    L55
L53:
  subq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x2c(%rbp)
L38:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x2c(%rbp)
  jl     L66
L55:
  cmpl   $0x1,-0x28(%rbp)
  jne    L9
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L6
L9:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L6:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D15
type: string

tool: D5: %s

tool: D19: Palindrom

tool: D15: bukan Palindrom

assistant: ```c
int main() {
  char input[10];
  scanf("%s", input);
  printf("%s", input);
  int len = strlen(input);
  int i, j;
  int status = 1;
  strlwr(input);
  char *p;
  p = input;
  p = &input[len - 1];
  for (j = 0; j < len / 2; j++) {
    if (input[j] != *p) {
      status = 0;
      break;
    }
    p--;
  }
  if (status == 1)
    printf("Palindrom\n");
  else
    printf("bukan Palindrom\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlwr@plt>
  lea    -0x1(%rbp),%eax
  cltq
  lea    (%rbx,%rax,1),%rdx
  mov    %ebp,%ecx
  shr    $0x1f,%ecx
  add    %ebp,%ecx
  sar    %ecx
  cmp    $0x1,%ebp
  jle    L3
  mov    $0x0,%eax
L41:
  movzbl (%rdx),%esi
  cmp    %sil,0xe(%rsp,%rax,1)
  jne    L6
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L41
L3:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L15
L6:
  lea    D28(%rip),%rdi
  call   <puts@plt>
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: string
name: read_data
arguments: data_label: D28
type_guessed: string

tool: D6: %s

tool: D12: Palindrom

tool: D28: bukan Palindrom

assistant: ```c
int main() {
  char input[10];
  scanf("%s", input);
  printf("%s", input);
  int len = strlen(input);
  int i, j;
  int status = 1;
  strlwr(input);
  char *p;
  p = input;
  p = &input[len - 1];
  for (j = 0; j < len / 2; j++) {
    if (input[j] != *p) {
      status = 0;
      break;
    }
    p--;
  }
  if (status == 1)
    printf("Palindrom\n");
  else
    printf("bukan Palindrom\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strlwr@plt>
  mov    %ebp,%ecx
  lea    -0x1(%rbp),%edx
  shr    $0x1f,%ecx
  movslq %edx,%rdx
  add    %ebp,%ecx
  add    %rbx,%rdx
  sar    %ecx
  cmp    $0x1,%ebp
  jle    L36
  xor    %eax,%eax
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L33:
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%ecx
  jle    L36
L10:
  movzbl (%rdx),%esi
  cmp    %sil,(%rbx,%rax,1)
  je     L33
  lea    D14(%rip),%rdi
  call   <puts@plt>
L59:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L36:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L59
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D29
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D9
data_type: string

tool: D29: %s

tool: D14: bukan Palindrom

tool: D9: Palindrom

assistant: ```c
int main() {
  char input[10];
  scanf("%s", input);
  printf("%s", input);
  int len = strlen(input);
  int i, j;
  int status = 1;
  strlwr(input);
  char *p;
  p = input;
  p = &input[len - 1];
  for (j = 0; j < len / 2; j++) {
    if (input[j] != *p) {
      status = 0;
      break;
    }
    p--;
  }
  if (status == 1)
    printf("Palindrom\n");
  else
    printf("bukan Palindrom\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strlwr@plt>
  mov    %ebp,%edx
  lea    -0x1(%rbp),%eax
  shr    $0x1f,%edx
  cltq
  add    %ebp,%edx
  add    %rbx,%rax
  sar    %edx
  cmp    $0x1,%ebp
  jle    L181
  movzbl 0xe(%rsp),%ecx
  cmp    %cl,(%rax)
  jne    L129
  cmp    $0x3,%ebp
  jle    L181
  movzbl -0x1(%rax),%ecx
  cmp    %cl,0xf(%rsp)
  jne    L129
  cmp    $0x2,%edx
  je     L181
  movzbl -0x2(%rax),%esi
  cmp    %sil,0x10(%rsp)
  jne    L129
  cmp    $0x3,%edx
  je     L181
  movzbl -0x3(%rax),%esi
  cmp    %sil,0x11(%rsp)
  jne    L129
  cmp    $0x4,%edx
  je     L181
  movzbl -0x4(%rax),%ecx
  cmp    %cl,0x12(%rsp)
  jne    L129
  cmp    $0x5,%edx
  je     L181
  movzbl -0x5(%rax),%ecx
  cmp    %cl,0x13(%rsp)
  jne    L129
  cmp    $0x6,%edx
  je     L181
  movzbl -0x6(%rax),%esi
  cmp    %sil,0x14(%rsp)
  jne    L129
  cmp    $0x7,%edx
  je     L181
  movzbl -0x7(%rax),%esi
  cmp    %sil,0x15(%rsp)
  jne    L129
  cmp    $0x8,%edx
  je     L181
  movzbl -0x8(%rax),%ecx
  cmp    %cl,0x16(%rsp)
  jne    L129
  cmp    $0x9,%edx
  je     L181
  movzbl -0x9(%rax),%eax
  cmp    %al,0x17(%rsp)
  jne    L129
L181:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L160
L129:
  lea    D1(%rip),%rdi
  call   <puts@plt>
L160:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_infered: string
name: extract_symbolic_data
arguments: label: D11
type_infered: string
name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D15: %s

tool: D11: Palindrom

tool: D1: bukan Palindrom

assistant: ```c
int main() {
  char input[10];
  scanf("%s", input);
  printf("%s", input);
  int len = strlen(input);
  int i, j;
  int status = 1;
  strlwr(input);
  char *p;
  p = input;
  p = &input[len - 1];
  for (j = 0; j < len / 2; j++) {
    if (input[j] != *p) {
      status = 0;
      break;
    }
    p--;
  }
  if (status == 1)
    printf("Palindrom\n");
  else
    printf("bukan Palindrom\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<UARTParityModeSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%rax
  and    $0xf9,%ah
  mov    -0x8(%rbp),%rdx
  add    $0xc,%rdx
  or     -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTParityModeSet(unsigned long ulBase, unsigned long ulParity) {
  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) = (((*((volatile unsigned long *)(ulBase + 0x0000000C))) & ~(0x00000400 | 0x00000200)) | ulParity);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<UARTParityModeSet>:
  endbr64
  mov    0xc(%rdi),%rax
  and    $0xf9,%ah
  or     %rsi,%rax
  mov    %rax,0xc(%rdi)
  ret
```

assistant: ```c
void UARTParityModeSet(unsigned long ulBase, unsigned long ulParity) {
  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) = (((*((volatile unsigned long *)(ulBase + 0x0000000C))) & ~(0x00000400 | 0x00000200)) | ulParity);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTParityModeSet>:
  endbr64
  mov    0xc(%rdi),%rax
  and    $0xf9,%ah
  or     %rsi,%rax
  mov    %rax,0xc(%rdi)
  ret
```

assistant: ```c
void UARTParityModeSet(unsigned long ulBase, unsigned long ulParity) {
  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) = (((*((volatile unsigned long *)(ulBase + 0x0000000C))) & ~(0x00000400 | 0x00000200)) | ulParity);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UARTParityModeSet>:
  endbr64
  mov    0xc(%rdi),%rax
  and    $0xf9,%ah
  or     %rsi,%rax
  mov    %rax,0xc(%rdi)
  ret
```

assistant: ```c
void UARTParityModeSet(unsigned long ulBase, unsigned long ulParity) {
  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) = (((*((volatile unsigned long *)(ulBase + 0x0000000C))) & ~(0x00000400 | 0x00000200)) | ulParity);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<re_match_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x34(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%r9d
  mov    -0x28(%rbp),%r8d
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    0x18(%rbp),%edi
  push   %rdi
  push   -0x40(%rbp)
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <re_match_2_internal@plt>
  add    $0x10,%rsp
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int re_match_2(bufp, string1, size1, string2, size2, pos, regs, stop)
struct re_pattern_buffer *bufp;
const char *string1, *string2;
int size1, size2;
int pos;
struct re_registers *regs;
int stop;
{
  int result = re_match_2_internal(bufp, string1, size1, string2, size2, pos, regs, stop);
  __builtin_alloca(0);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<re_match_2>:
  endbr64
  sub    $0x8,%rsp
  mov    0x18(%rsp),%eax
  push   %rax
  push   0x18(%rsp)
  mov    $0x0,%eax
  call   <re_match_2_internal@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int re_match_2(bufp, string1, size1, string2, size2, pos, regs, stop)
struct re_pattern_buffer *bufp;
const char *string1, *string2;
int size1, size2;
int pos;
struct re_registers *regs;
int stop;
{
  int result = re_match_2_internal(bufp, string1, size1, string2, size2, pos, regs, stop);
  __builtin_alloca(0);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<re_match_2>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <re_match_2_internal@plt>
```

assistant: ```c
int re_match_2(bufp, string1, size1, string2, size2, pos, regs, stop)
struct re_pattern_buffer *bufp;
const char *string1, *string2;
int size1, size2;
int pos;
struct re_registers *regs;
int stop;
{
  int result = re_match_2_internal(bufp, string1, size1, string2, size2, pos, regs, stop);
  __builtin_alloca(0);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<re_match_2>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <re_match_2_internal@plt>
```

assistant: ```c
int re_match_2(bufp, string1, size1, string2, size2, pos, regs, stop)
struct re_pattern_buffer *bufp;
const char *string1, *string2;
int size1, size2;
int pos;
struct re_registers *regs;
int stop;
{
  int result = re_match_2_internal(bufp, string1, size1, string2, size2, pos, regs, stop);
  __builtin_alloca(0);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<int2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    D37(%rip),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  lea    D34(%rip),%rdx
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    D37(%rip),%eax
  lea    0x1(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,D10(%rip)
  cmpl   $0x14,-0x18(%rbp)
  jle    L12
  movl   $0x14,-0x18(%rbp)
L12:
  cmpl   $0x0,-0x18(%rbp)
  jle    L0
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  jmp    L19
L0:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D49(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: string
name: disassemble_data
arguments: data_tag: D49
datatype: string

tool: D10:                     %09d

tool: D49: %d

assistant: ```c
char *int2str(int number, int size) {
  static char shift_array[10][40];
  static int shift_counter = 0;
  char *s = shift_array[shift_counter];
  shift_counter = (shift_counter + 1) % 10;
  if (size > 20)
    size = 20;
  if (size > 0) {
    sprintf(s, "                    %09d", number);
    return &s[strlen(s) - size];
  } else {
    sprintf(s, "%d", number);
    return s;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<int2str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    D3(%rip),%eax
  movslq %eax,%rdx
  lea    (%rdx,%rdx,4),%rsi
  lea    D15(%rip),%rdx
  lea    (%rdx,%rsi,8),%rbp
  add    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,D14(%rip)
  cmp    $0x14,%ebx
  jg     L31
  test   %ebx,%ebx
  jle    L37
L8:
  mov    %edi,%edx
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    %ebx,%eax
  cltq
  add    %rax,%rbp
L6:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    $0x14,%ebx
  jmp    L8
L37:
  mov    %edi,%edx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D14:                     %09d

tool: D9: %d

assistant: ```c
char *int2str(int number, int size) {
  static char shift_array[10][40];
  static int shift_counter = 0;
  char *s = shift_array[shift_counter];
  shift_counter = (shift_counter + 1) % 10;
  if (size > 20)
    size = 20;
  if (size > 0) {
    sprintf(s, "                    %09d", number);
    return &s[strlen(s) - size];
  } else {
    sprintf(s, "%d", number);
    return s;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<int2str>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  movslq D8(%rip),%rdx
  mov    %rdx,%rax
  lea    (%rdx,%rdx,4),%rcx
  lea    D29(%rip),%rdx
  add    $0x1,%eax
  lea    (%rdx,%rcx,8),%r12
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,D19(%rip)
  cmp    $0x14,%esi
  jg     L5
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L13
L29:
  mov    %edi,%edx
  lea    D19(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  sub    %ebx,%eax
  pop    %rbx
  cltq
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L13:
  mov    %edi,%edx
  lea    D22(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x14,%ebx
  jmp    L29
```

tool_calls: name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D22
type: string

tool: D19:                     %09d

tool: D22: %d

assistant: ```c
char *int2str(int number, int size) {
  static char shift_array[10][40];
  static int shift_counter = 0;
  char *s = shift_array[shift_counter];
  shift_counter = (shift_counter + 1) % 10;
  if (size > 20)
    size = 20;
  if (size > 0) {
    sprintf(s, "                    %09d", number);
    return &s[strlen(s) - size];
  } else {
    sprintf(s, "%d", number);
    return s;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<int2str>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  movslq D48(%rip),%rdx
  mov    %rdx,%rax
  lea    (%rdx,%rdx,4),%rcx
  lea    D43(%rip),%rdx
  add    $0x1,%eax
  lea    (%rdx,%rcx,8),%r12
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,D38(%rip)
  cmp    $0x14,%esi
  jg     L0
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L7
L19:
  mov    %edi,%edx
  lea    D38(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  sub    %ebx,%eax
  pop    %rbx
  cltq
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L7:
  mov    %edi,%edx
  lea    D9(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x14,%ebx
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: label: D38
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D38:                     %09d

tool: D9: %d

assistant: ```c
char *int2str(int number, int size) {
  static char shift_array[10][40];
  static int shift_counter = 0;
  char *s = shift_array[shift_counter];
  shift_counter = (shift_counter + 1) % 10;
  if (size > 20)
    size = 20;
  if (size > 0) {
    sprintf(s, "                    %09d", number);
    return &s[strlen(s) - size];
  } else {
    sprintf(s, "%d", number);
    return s;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_message_body>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <get_message_size@plt>
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L5
  mov    -0x30(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
L5:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <recv_all@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_message_body(int connected_socket, uint32_t *message_size) {
  uint32_t size = get_message_size(connected_socket);
  if (message_size) {
    *message_size = size;
  }
  char *buff = malloc(size + 1);
  char *msg_body = recv_all(connected_socket, size);
  memcpy(buff, msg_body, size);
  free(msg_body);
  buff[size] = '\0';
  return buff;
}
```