ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<bigint_init_raw>:
  endbr64
  mov    %rdi,%rsi
  lea    -0x1(%rcx),%r9
  lea    (%rdx,%rcx,1),%rdi
  mov    %rcx,%r8
  test   %rcx,%rcx
  je     L87
  lea    0x0(,%rcx,4),%rcx
  mov    %r8,%rax
  sub    %rcx,%rax
  lea    (%rsi,%rcx,1),%r10
  add    %rdx,%rax
  cmp    %rax,%r10
  setbe  %al
  cmp    %rdi,%rsi
  setae  %r11b
  or     %r11b,%al
  je     L24
  cmp    $0x2,%r9
  jbe    L24
  mov    %r8,%r11
  lea    -0x10(%rdx,%r8,1),%rdx
  xor    %eax,%eax
  shr    $0x2,%r11
  xchg   %ax,%ax
L47:
  movdqu (%rdx),%xmm1
  mov    %rax,%rcx
  add    $0x1,%rax
  sub    $0x10,%rdx
  shl    $0x4,%rcx
  pshufd $0x1b,%xmm1,%xmm0
  movups %xmm0,(%rsi,%rcx,1)
  cmp    %r11,%rax
  jne    L47
  mov    %r8,%rax
  and    $0xfffffffffffffffc,%rax
  lea    0x0(,%rax,4),%rdx
  sub    %rax,%r9
  add    %rdx,%rsi
  cmp    %rax,%r8
  je     L89
  sub    %rdx,%rdi
  mov    -0x4(%rdi),%edx
  mov    %edx,(%rsi)
  test   %r9,%r9
  je     L89
  mov    -0x8(%rdi),%edx
  mov    %edx,0x4(%rsi)
  cmp    $0x1,%r9
  je     L89
  mov    -0xc(%rdi),%eax
  mov    %eax,0x8(%rsi)
L89:
  cmp    $0x4,%r8
  je     L44
L101:
  mov    $0x4,%edx
  xor    %esi,%esi
  mov    %r10,%rdi
  sub    %r8,%rdx
  shl    $0x2,%rdx
  jmp    1050 <memset@plt>
  cs nopw 0x0(%rax,%rax,1)
L24:
  sub    %rcx,%rdi
  nopl   0x0(%rax,%rax,1)
L97:
  mov    (%rdi,%r9,4),%eax
  sub    $0x1,%r9
  add    $0x4,%rsi
  mov    %eax,-0x4(%rsi)
  cmp    $0xffffffffffffffff,%r9
  jne    L97
  cmp    $0x4,%r8
  jne    L101
L44:
  ret
  nopl   0x0(%rax)
L87:
  mov    %rsi,%r10
  jmp    L101
```

assistant: ```c
__attribute__((always_)) void bigint_init_raw(uint32_t *value0, unsigned int size, const void *data, size_t len) {
  size_t pad_len = (sizeof(bigint_t(size)) - len);
  uint8_t *value_byte = ((void *)value0);
  const uint8_t *data_byte = (data + len);
  while (len--)
    *(value_byte++) = *(--data_byte);
  while (pad_len--)
    *(value_byte++) = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<G>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  movsd  %xmm4,-0x48(%rbp)
  movsd  %xmm5,-0x50(%rbp)
  movsd  %xmm6,-0x58(%rbp)
  mov    %rdi,-0x60(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  D55(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x28(%rbp),%xmm2
  movsd  D64(%rip),%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x30(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  -0x50(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  addsd  -0x48(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  addsd  -0x40(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D64(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x18(%rbp),%xmm1
  movsd  D64(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x28(%rbp),%xmm1
  movsd  -0x48(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x50(%rbp),%xmm2
  movsd  D24(%rip),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  -0x58(%rbp),%xmm3
  movsd  D76(%rip),%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  -0x28(%rbp),%xmm0
  addsd  %xmm2,%xmm0
  mulsd  -0x28(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x30(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  D55(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x38(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm3
  movsd  D64(%rip),%xmm2
  addsd  %xmm3,%xmm2
  mulsd  -0x18(%rbp),%xmm2
  divsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x60(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D55
datatype: byte[8]
name: disassemble_data
arguments: label: D64
datatype: f64
name: disassemble_data
arguments: label: D24
datatype: f64
name: disassemble_data
arguments: label: D76
datatype: f64

tool: {"D55": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D64: 1

tool: D24: 3

tool: D76: 4

assistant: ```c
double G(double rtrs, double A, double alpha1, double beta1, double beta2, double beta3, double beta4, double *dGdrs) {
  double Q0 = -2.0 * A * (1.0 + alpha1 * rtrs * rtrs);
  double Q1 = 2.0 * A * rtrs * (beta1 + rtrs * (beta2 + rtrs * (beta3 + rtrs * beta4)));
  double G1 = Q0 * log(1.0 + 1.0 / Q1);
  double dQ1drs = A * (beta1 / rtrs + 2.0 * beta2 + rtrs * (3.0 * beta3 + 4.0 * beta4 * rtrs));
  *dGdrs = -2.0 * A * alpha1 * G1 / Q0 - Q0 * dQ1drs / (Q1 * (Q1 + 1.0));
  return G1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<G>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  movapd %xmm0,%xmm7
  movsd  %xmm1,(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x18(%rsp)
  mov    %rdi,%rbx
  movapd %xmm1,%xmm5
  mulsd  D61(%rip),%xmm5
  movsd  %xmm2,0x40(%rsp)
  movapd %xmm2,%xmm0
  mulsd  %xmm7,%xmm0
  mulsd  %xmm7,%xmm0
  addsd  D16(%rip),%xmm0
  mulsd  %xmm5,%xmm0
  movsd  %xmm0,0x28(%rsp)
  movapd %xmm7,%xmm0
  mulsd  0x18(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  mulsd  %xmm7,%xmm0
  movsd  %xmm4,0x48(%rsp)
  addsd  %xmm4,%xmm0
  mulsd  %xmm7,%xmm0
  addsd  %xmm3,%xmm0
  movsd  %xmm5,0x20(%rsp)
  movapd %xmm5,%xmm1
  xorpd  D30(%rip),%xmm1
  movsd  %xmm7,0x38(%rsp)
  mulsd  %xmm7,%xmm1
  movapd %xmm0,%xmm3
  mulsd  %xmm1,%xmm3
  movsd  D16(%rip),%xmm10
  movsd  %xmm3,0x30(%rsp)
  divsd  %xmm3,%xmm10
  movapd %xmm10,%xmm0
  addsd  D16(%rip),%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm11
  movsd  0x28(%rsp),%xmm6
  mulsd  %xmm6,%xmm11
  movsd  0x20(%rsp),%xmm0
  mulsd  0x40(%rsp),%xmm0
  mulsd  %xmm11,%xmm0
  divsd  %xmm6,%xmm0
  movsd  0x18(%rsp),%xmm1
  mulsd  D72(%rip),%xmm1
  movsd  0x38(%rsp),%xmm7
  mulsd  %xmm7,%xmm1
  movsd  0x10(%rsp),%xmm2
  mulsd  D62(%rip),%xmm2
  addsd  %xmm2,%xmm1
  mulsd  %xmm7,%xmm1
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm7,%xmm2
  movsd  0x48(%rsp),%xmm4
  addsd  %xmm4,%xmm4
  addsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm1
  mulsd  (%rsp),%xmm1
  mulsd  %xmm6,%xmm1
  movsd  D16(%rip),%xmm2
  movsd  0x30(%rsp),%xmm5
  addsd  %xmm5,%xmm2
  mulsd  %xmm5,%xmm2
  divsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  movapd %xmm11,%xmm0
  add    $0x50,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D61
type_infered: byte[8]
name: read_data
arguments: data_tag: D16
type_infered: f64
name: read_data
arguments: data_tag: D30
type_infered: byte[16]
name: read_data
arguments: data_tag: D72
type_infered: f64
name: read_data
arguments: data_tag: D62
type_infered: f64

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D16: 1

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D72: 4

tool: D62: 3

assistant: ```c
double G(double rtrs, double A, double alpha1, double beta1, double beta2, double beta3, double beta4, double *dGdrs) {
  double Q0 = -2.0 * A * (1.0 + alpha1 * rtrs * rtrs);
  double Q1 = 2.0 * A * rtrs * (beta1 + rtrs * (beta2 + rtrs * (beta3 + rtrs * beta4)));
  double G1 = Q0 * log(1.0 + 1.0 / Q1);
  double dQ1drs = A * (beta1 / rtrs + 2.0 * beta2 + rtrs * (3.0 * beta3 + 4.0 * beta4 * rtrs));
  *dGdrs = -2.0 * A * alpha1 * G1 / Q0 - Q0 * dQ1drs / (Q1 * (Q1 + 1.0));
  return G1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<G>:
  endbr64
  movapd %xmm0,%xmm7
  push   %rbx
  movapd %xmm2,%xmm9
  movapd %xmm1,%xmm12
  mulsd  %xmm6,%xmm7
  movapd %xmm0,%xmm8
  mov    %rdi,%rbx
  mulsd  %xmm0,%xmm9
  sub    $0x50,%rsp
  movsd  D9(%rip),%xmm10
  mulsd  D59(%rip),%xmm12
  movsd  %xmm1,0x48(%rsp)
  movsd  %xmm2,0x40(%rsp)
  addsd  %xmm5,%xmm7
  movsd  %xmm6,0x30(%rsp)
  mulsd  %xmm0,%xmm9
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm4,0x20(%rsp)
  mulsd  %xmm0,%xmm7
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm12,0x10(%rsp)
  movsd  %xmm8,0x8(%rsp)
  addsd  %xmm10,%xmm9
  addsd  %xmm4,%xmm7
  mulsd  %xmm12,%xmm9
  mulsd  %xmm0,%xmm7
  movapd %xmm12,%xmm0
  xorpd  D11(%rip),%xmm0
  mulsd  %xmm8,%xmm0
  movsd  %xmm9,0x38(%rsp)
  addsd  %xmm3,%xmm7
  mulsd  %xmm0,%xmm7
  movapd %xmm10,%xmm0
  divsd  %xmm7,%xmm0
  movsd  %xmm7,(%rsp)
  addsd  %xmm10,%xmm0
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  (%rsp),%xmm7
  movsd  0x8(%rsp),%xmm8
  movsd  0x30(%rsp),%xmm6
  mulsd  D6(%rip),%xmm6
  movsd  0x28(%rsp),%xmm5
  divsd  %xmm8,%xmm3
  movsd  0x20(%rsp),%xmm4
  movsd  0x48(%rsp),%xmm1
  mulsd  D21(%rip),%xmm5
  movsd  0x38(%rsp),%xmm9
  addsd  %xmm4,%xmm4
  movsd  0x10(%rsp),%xmm12
  movsd  0x40(%rsp),%xmm2
  mov    D9(%rip),%rax
  mulsd  %xmm9,%xmm0
  mulsd  %xmm8,%xmm6
  mulsd  %xmm2,%xmm12
  movq   %rax,%xmm10
  addsd  %xmm7,%xmm10
  movapd %xmm0,%xmm11
  addsd  %xmm5,%xmm6
  mulsd  %xmm7,%xmm10
  mulsd  %xmm0,%xmm12
  mulsd  %xmm8,%xmm6
  divsd  %xmm9,%xmm12
  addsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm6
  mulsd  %xmm6,%xmm1
  mulsd  %xmm9,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm10,%xmm0
  subsd  %xmm0,%xmm12
  movapd %xmm11,%xmm0
  movsd  %xmm12,(%rbx)
  add    $0x50,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: f64
name: parse_data
arguments: tag: D59
type_infered: byte[8]
name: parse_data
arguments: tag: D11
type_infered: byte[16]
name: parse_data
arguments: tag: D6
type_infered: f64
name: parse_data
arguments: tag: D21
type_infered: f64

tool: D9: 1

tool: {"D59": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D6: 4

tool: D21: 3

assistant: ```c
double G(double rtrs, double A, double alpha1, double beta1, double beta2, double beta3, double beta4, double *dGdrs) {
  double Q0 = -2.0 * A * (1.0 + alpha1 * rtrs * rtrs);
  double Q1 = 2.0 * A * rtrs * (beta1 + rtrs * (beta2 + rtrs * (beta3 + rtrs * beta4)));
  double G1 = Q0 * log(1.0 + 1.0 / Q1);
  double dQ1drs = A * (beta1 / rtrs + 2.0 * beta2 + rtrs * (3.0 * beta3 + 4.0 * beta4 * rtrs));
  *dGdrs = -2.0 * A * alpha1 * G1 / Q0 - Q0 * dQ1drs / (Q1 * (Q1 + 1.0));
  return G1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<G>:
  endbr64
  movapd %xmm0,%xmm7
  push   %rbx
  movapd %xmm2,%xmm9
  movapd %xmm1,%xmm12
  mulsd  %xmm6,%xmm7
  movapd %xmm0,%xmm8
  mov    %rdi,%rbx
  mulsd  %xmm0,%xmm9
  sub    $0x50,%rsp
  movsd  D37(%rip),%xmm10
  mulsd  D1(%rip),%xmm12
  movsd  %xmm1,0x48(%rsp)
  movsd  %xmm2,0x40(%rsp)
  addsd  %xmm5,%xmm7
  movsd  %xmm6,0x30(%rsp)
  mulsd  %xmm0,%xmm9
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm4,0x20(%rsp)
  mulsd  %xmm0,%xmm7
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm12,0x10(%rsp)
  movsd  %xmm8,0x8(%rsp)
  addsd  %xmm10,%xmm9
  addsd  %xmm4,%xmm7
  mulsd  %xmm12,%xmm9
  mulsd  %xmm0,%xmm7
  movapd %xmm12,%xmm0
  xorpd  D23(%rip),%xmm0
  mulsd  %xmm8,%xmm0
  movsd  %xmm9,0x38(%rsp)
  addsd  %xmm3,%xmm7
  mulsd  %xmm0,%xmm7
  movapd %xmm10,%xmm0
  divsd  %xmm7,%xmm0
  movsd  %xmm7,(%rsp)
  addsd  %xmm10,%xmm0
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  (%rsp),%xmm7
  movsd  0x8(%rsp),%xmm8
  movsd  0x30(%rsp),%xmm6
  mulsd  D15(%rip),%xmm6
  movsd  0x28(%rsp),%xmm5
  divsd  %xmm8,%xmm3
  movsd  0x20(%rsp),%xmm4
  movsd  0x48(%rsp),%xmm1
  mulsd  D31(%rip),%xmm5
  movsd  0x38(%rsp),%xmm9
  addsd  %xmm4,%xmm4
  movsd  0x10(%rsp),%xmm12
  movsd  0x40(%rsp),%xmm2
  mov    D37(%rip),%rax
  mulsd  %xmm9,%xmm0
  mulsd  %xmm8,%xmm6
  mulsd  %xmm2,%xmm12
  movq   %rax,%xmm10
  addsd  %xmm7,%xmm10
  movapd %xmm0,%xmm11
  addsd  %xmm5,%xmm6
  mulsd  %xmm7,%xmm10
  mulsd  %xmm0,%xmm12
  mulsd  %xmm8,%xmm6
  divsd  %xmm9,%xmm12
  addsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm6
  mulsd  %xmm6,%xmm1
  mulsd  %xmm9,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm10,%xmm0
  subsd  %xmm0,%xmm12
  movapd %xmm11,%xmm0
  movsd  %xmm12,(%rbx)
  add    $0x50,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D37
type: f64
name: read_data
arguments: data_label: D1
type: byte[8]
name: read_data
arguments: data_label: D23
type: byte[16]
name: read_data
arguments: data_label: D15
type: f64
name: read_data
arguments: data_label: D31
type: f64

tool: D37: 1

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D15: 4

tool: D31: 3

assistant: ```c
double G(double rtrs, double A, double alpha1, double beta1, double beta2, double beta3, double beta4, double *dGdrs) {
  double Q0 = -2.0 * A * (1.0 + alpha1 * rtrs * rtrs);
  double Q1 = 2.0 * A * rtrs * (beta1 + rtrs * (beta2 + rtrs * (beta3 + rtrs * beta4)));
  double G1 = Q0 * log(1.0 + 1.0 / Q1);
  double dQ1drs = A * (beta1 / rtrs + 2.0 * beta2 + rtrs * (3.0 * beta3 + 4.0 * beta4 * rtrs));
  *dGdrs = -2.0 * A * alpha1 * G1 / Q0 - Q0 * dQ1drs / (Q1 * (Q1 + 1.0));
  return G1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L22
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  movq   $0x0,-0x8(%rbp)
  jmp    L26
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <factorial@plt>
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strtoull@plt>
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rax,-0x8(%rbp)
  jb     L8
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D18
type_guessed: string

tool: D15: Usage:
euler [count]
count - number of loops

tool: D18: %llu

assistant: ```c
void main(int argc, char **argv) {
  if (argc == 1) {
    printf("Usage:\neuler [count]\ncount - number of loops");
  }
  unsigned long long sum;
  unsigned long long i;
  for (i = 0; i < abs(strtoull(argv[1])); i++) {
    sum += factorial(i);
    printf("%llu", sum);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  cmp    $0x1,%edi
  je     L12
L11:
  mov    $0x0,%ebx
  lea    D3(%rip),%r13
  jmp    L33
L12:
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L15:
  mov    %rbx,%rdi
  call   <factorial@plt>
  add    %rax,%rbp
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
L33:
  mov    0x8(%r12),%rdi
  call   <strtoull@plt>
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rbx,%rax
  ja     L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D14
data_type: string

tool: D3: %llu

tool: D14: Usage:
euler [count]
count - number of loops

assistant: ```c
void main(int argc, char **argv) {
  if (argc == 1) {
    printf("Usage:\neuler [count]\ncount - number of loops");
  }
  unsigned long long sum;
  unsigned long long i;
  for (i = 0; i < abs(strtoull(argv[1])); i++) {
    sum += factorial(i);
    printf("%llu", sum);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L8
L25:
  xor    %ebx,%ebx
  lea    D8(%rip),%r13
  jmp    L3
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <factorial@plt>
  mov    %r13,%rdi
  add    %rax,%rbp
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
L3:
  mov    0x8(%r12),%rdi
  call   <strtoull@plt>
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rbx,%rax
  ja     L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
```

tool_calls: name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D4
type: string

tool: D8: %llu

tool: D4: Usage:
euler [count]
count - number of loops

assistant: ```c
void main(int argc, char **argv) {
  if (argc == 1) {
    printf("Usage:\neuler [count]\ncount - number of loops");
  }
  unsigned long long sum;
  unsigned long long i;
  for (i = 0; i < abs(strtoull(argv[1])); i++) {
    sum += factorial(i);
    printf("%llu", sum);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L29
L26:
  xor    %ebx,%ebx
  lea    D16(%rip),%r13
  jmp    L18
  nopl   0x0(%rax)
L17:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <factorial@plt>
  mov    %r13,%rdi
  add    %rax,%rbp
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
L18:
  mov    0x8(%r12),%rdi
  call   <strtoull@plt>
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rbx,%rax
  ja     L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
```

tool_calls: name: retrieve_data
arguments: data_label: D16
data_type: string
name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D16: %llu

tool: D6: Usage:
euler [count]
count - number of loops

assistant: ```c
void main(int argc, char **argv) {
  if (argc == 1) {
    printf("Usage:\neuler [count]\ncount - number of loops");
  }
  unsigned long long sum;
  unsigned long long i;
  for (i = 0; i < abs(strtoull(argv[1])); i++) {
    sum += factorial(i);
    printf("%llu", sum);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_quick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jae    L9
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_rearr@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_quick>
L8:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <_quick>
L9:
  nop
  leave
  ret
```

assistant: ```c
void _quick(unsigned lb, unsigned ub) {
  unsigned j;
  if (lb < ub) {
    if ((j = _rearr(lb, ub)))
      _quick(lb, j - 1);
    _quick(j + 1, ub);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_quick>:
  endbr64
  cmp    %esi,%edi
  jb     L17
  ret
L17:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  call   <_rearr@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L23
L3:
  lea    0x1(%r12),%edi
  mov    %ebx,%esi
  call   <_quick>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  lea    -0x1(%rax),%esi
  mov    %ebp,%edi
  call   <_quick>
  jmp    L3
```

assistant: ```c
void _quick(unsigned lb, unsigned ub) {
  unsigned j;
  if (lb < ub) {
    if ((j = _rearr(lb, ub)))
      _quick(lb, j - 1);
    _quick(j + 1, ub);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<quotes_in_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  jmp    L9
L45:
  movzbl (%rax),%edx
  cmp    $0x22,%dl
  je     L38
  movzbl (%rax),%edx
  cmp    $0x5c,%dl
  jne    L21
L38:
  mov    $0x1,%eax
  jmp    L31
L21:
  add    $0x1,%rax
L9:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L45
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int quotes_in_line(the_line)
register char *the_line;
{
  while (*the_line) {
    if (*the_line == '"' || *the_line == '\\')
      return 1;
    ++the_line;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<quotes_in_line>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
L35:
  cmp    $0x22,%al
  je     L27
  cmp    $0x5c,%al
  je     L27
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L35
  mov    $0x0,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int quotes_in_line(the_line)
register char *the_line;
{
  while (*the_line) {
    if (*the_line == '"' || *the_line == '\\')
      return 1;
    ++the_line;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quotes_in_line>:
  endbr64
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L37:
  cmp    $0x22,%al
  je     L27
  cmp    $0x5c,%al
  je     L27
  add    $0x1,%rdi
L21:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L37
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int quotes_in_line(the_line)
register char *the_line;
{
  while (*the_line) {
    if (*the_line == '"' || *the_line == '\\')
      return 1;
    ++the_line;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quotes_in_line>:
  endbr64
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L2:
  cmp    $0x22,%al
  je     L18
  cmp    $0x5c,%al
  je     L18
  add    $0x1,%rdi
L6:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int quotes_in_line(the_line)
register char *the_line;
{
  while (*the_line) {
    if (*the_line == '"' || *the_line == '\\')
      return 1;
    ++the_line;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmd_get_page>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L3:
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <_get_page@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <_get_page@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jne    L3
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
uint32_t cmd_get_page(int fd, uint32_t addr) {
  uint32_t page[2];
  do {
    page[0] = _get_page(fd, addr);
    page[1] = _get_page(fd, addr);
  } while (page[0] != page[1]);
  return page[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_get_page>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
L0:
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <_get_page@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <_get_page@plt>
  cmp    %rax,%rbx
  jne    L0
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t cmd_get_page(int fd, uint32_t addr) {
  uint32_t page[2];
  do {
    page[0] = _get_page(fd, addr);
    page[1] = _get_page(fd, addr);
  } while (page[0] != page[1]);
  return page[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd_get_page>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  nopl   (%rax)
L0:
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <_get_page@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <_get_page@plt>
  cmp    %rax,%r12
  jne    L0
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t cmd_get_page(int fd, uint32_t addr) {
  uint32_t page[2];
  do {
    page[0] = _get_page(fd, addr);
    page[1] = _get_page(fd, addr);
  } while (page[0] != page[1]);
  return page[0];
}
```