user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rbx
  lea    D48(%rip),%rbp
  lea    D5(%rip),%r12
  lea    D28(%rip),%r13
  jmp    L28
L198:
  cmp    %eax,%edx
  jle    L53
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%edx
  jg     L87
  mov    %ecx,0xc(%rsp)
  jmp    L17
L87:
  cmp    %ecx,%eax
  jg     L17
  mov    %ecx,0x10(%rsp)
  mov    %eax,0x14(%rsp)
  jmp    L17
L237:
  mov    %rbp,%rdi
  call   <printf@plt>
L28:
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L8
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  jne    L198
  cmpl   $0x0,0x14(%rsp)
  je     L8
  mov    %ecx,%eax
L53:
  mov    %eax,0xc(%rsp)
  mov    %edx,0x10(%rsp)
L17:
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%ecx
  mov    0x14(%rsp),%eax
  lea    (%rdx,%rcx,1),%esi
  cmp    %eax,%esi
  jle    L237
  lea    (%rdx,%rax,1),%esi
  cmp    %esi,%ecx
  jge    L237
  lea    (%rcx,%rax,1),%esi
  cmp    %esi,%edx
  jge    L237
  mov    %edx,%esi
  imul   %edx,%esi
  mov    %ecx,%edi
  imul   %ecx,%edi
  mov    %eax,%r8d
  imul   %eax,%r8d
  lea    (%rsi,%rdi,1),%r9d
  cmp    %r8d,%r9d
  je     L51
  lea    (%rdi,%r8,1),%r9d
  cmp    %r9d,%esi
  je     L51
  add    %r8d,%esi
  cmp    %esi,%edi
  je     L51
  cmp    %eax,%ecx
  sete   %sil
  cmp    %ecx,%edx
  sete   %cl
  cmp    %eax,%edx
  sete   %al
  test   %cl,%sil
  je     L68
  test   %al,%al
  jne    L110
L68:
  or     %cl,%sil
  jne    L81
  test   %al,%al
  je     L29
L81:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L28
L51:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L28
L110:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L29:
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L115
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L115:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D48
type: string
name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D28
type: string
name: retrieve_data
arguments: data_label: D53
type: string
name: retrieve_data
arguments: data_label: D44
type: string

tool: D10: %d%d%d

tool: D48: not a triangle


tool: D5: a right triangle


tool: D28: a isosceles triangle


tool: D53: a equileteral triangle


tool: D44: a triangle


assistant: ```c
int main() {
  int a, b, c, x, y;
  while (scanf("%d%d%d", &a, &b, &c)) {
    if (a == 0 && b == 0 && c == 0)
      break;
    else {
      if (a <= b)
        x = a, a = b, b = x;
      else if (a <= c)
        x = c, a = c, c = x;
      else if (b <= c)
        x = b, b = c, c = x;
      if (a + b <= c || a + c <= b || b + c <= a)
        printf("not a triangle\n");
      else if (a * a + b * b == c * c || b * b + c * c == a * a || a * a + c * c == b * b)
        printf("a right triangle\n");
      else if (a == b && b == c && c == a)
        printf("a equileteral triangle\n");
      else if (a == b || b == c || c == a)
        printf("a isosceles triangle\n");
      else
        printf("a triangle\n");
    }
  }
  return 0;
}
```