ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<OSRAM128x64x4DisplayOff>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  lea    D9(%rip),%rdi
  call   <OSRAMWriteCommand@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void OSRAM128x64x4DisplayOff(void) {
  static const unsigned char pucCommand1[] = {0xAE, 0xAD, 0x02};
  OSRAMWriteCommand(pucCommand1, sizeof(pucCommand1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<OSRAM128x64x4DisplayOff>:
  endbr64
  mov    $0x3,%esi
  lea    D5(%rip),%rdi
  jmp    1050 <OSRAMWriteCommand@plt>
```

assistant: ```c
void OSRAM128x64x4DisplayOff(void) {
  static const unsigned char pucCommand1[] = {0xAE, 0xAD, 0x02};
  OSRAMWriteCommand(pucCommand1, sizeof(pucCommand1));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<OSRAM128x64x4DisplayOff>:
  endbr64
  mov    $0x3,%esi
  lea    D5(%rip),%rdi
  jmp    1050 <OSRAMWriteCommand@plt>
```

assistant: ```c
void OSRAM128x64x4DisplayOff(void) {
  static const unsigned char pucCommand1[] = {0xAE, 0xAD, 0x02};
  OSRAMWriteCommand(pucCommand1, sizeof(pucCommand1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<drawString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L24
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L47
L51:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jle    L4
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  add    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <drawCharacter@plt>
L4:
  addl   $0x10,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L38
  movl   $0x0,-0x8(%rbp)
  subl   $0x10,-0x4(%rbp)
L38:
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  jmp    L58
L24:
  nop
L58:
  leave
  ret
```

assistant: ```c
void drawString(char *str, int x, int y) {
  if (!str)
    return;
  int k;
  int dx = 0, dy = 0;
  for (k = 0; str[k]; k++) {
    if (str[k] >= 32 && str[k] < 128)
      drawCharacter(str[k], x + dx, y + dy);
    dx += 8 * 2;
    if (str[k] == '\n') {
      dx = 0;
      dy -= 8 * 2;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drawString>:
  endbr64
  test   %rdi,%rdi
  je     L55
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %edx,%r14d
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L56
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L9
L78:
  lea    (%r14,%r12,1),%edx
  lea    0x0(%r13,%rbp,1),%esi
  movsbl %dil,%edi
  call   <drawCharacter@plt>
  jmp    L34
L66:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L56
L9:
  cmp    $0x1f,%dil
  jg     L78
L34:
  add    $0x10,%ebp
  cmpb   $0xa,(%rbx)
  jne    L66
  sub    $0x10,%r12d
  mov    $0x0,%ebp
  jmp    L66
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L55:
  ret
```

assistant: ```c
void drawString(char *str, int x, int y) {
  if (!str)
    return;
  int k;
  int dx = 0, dy = 0;
  for (k = 0; str[k]; k++) {
    if (str[k] >= 32 && str[k] < 128)
      drawCharacter(str[k], x + dx, y + dy);
    dx += 8 * 2;
    if (str[k] == '\n') {
      dx = 0;
      dy -= 8 * 2;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawString>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
  mov    %esi,%r12d
  mov    %edx,%r13d
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  jmp    L2
  nopl   0x0(%rax)
L26:
  add    $0x10,%ebp
  cmpb   $0xa,(%rbx)
  jne    L33
  sub    $0x10,%r14d
  xor    %ebp,%ebp
L33:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L10
L2:
  cmp    $0x1f,%dil
  jle    L26
  lea    0x0(%r13,%r14,1),%edx
  lea    (%r12,%rbp,1),%esi
  call   <drawCharacter@plt>
  jmp    L26
  nopl   0x0(%rax)
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
void drawString(char *str, int x, int y) {
  if (!str)
    return;
  int k;
  int dx = 0, dy = 0;
  for (k = 0; str[k]; k++) {
    if (str[k] >= 32 && str[k] < 128)
      drawCharacter(str[k], x + dx, y + dy);
    dx += 8 * 2;
    if (str[k] == '\n') {
      dx = 0;
      dy -= 8 * 2;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<drawString>:
  endbr64
  test   %rdi,%rdi
  je     L64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L45
  mov    %esi,%r12d
  mov    %edx,%r13d
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  jmp    L69
  nopl   0x0(%rax)
L56:
  add    $0x10,%ebp
  cmp    $0xa,%dil
  jne    L35
  sub    $0x10,%r14d
  xor    %ebp,%ebp
L35:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L45
L69:
  cmp    $0x1f,%dil
  jle    L56
  lea    0x0(%r13,%r14,1),%edx
  lea    (%r12,%rbp,1),%esi
  call   <drawCharacter@plt>
  movzbl (%rbx),%edi
  jmp    L56
  nopl   (%rax)
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L64:
  ret
```

assistant: ```c
void drawString(char *str, int x, int y) {
  if (!str)
    return;
  int k;
  int dx = 0, dy = 0;
  for (k = 0; str[k]; k++) {
    if (str[k] >= 32 && str[k] < 128)
      drawCharacter(str[k], x + dx, y + dy);
    dx += 8 * 2;
    if (str[k] == '\n') {
      dx = 0;
      dy -= 8 * 2;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<find_first_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L54
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L22
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x7,%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
L22:
  addl   $0x1,-0x4(%rbp)
L54:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  movl   $0x1,-0x4(%rbp)
  jmp    L48
L44:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L47
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L1
L47:
  addl   $0x1,-0x4(%rbp)
L48:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L44
  mov    $0x0,%eax
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string

tool: D5: -trunc=

assistant: ```c
char *find_first_arg(int argc, char **argv, long long int *truncation_location) {
  int i;
  for (i = 1; i < argc; ++i) {
    if (strstr(argv[i], "-trunc=") == argv[i]) {
      *truncation_location = strtoll(argv[i] + 7, NULL, 10);
    }
  }
  for (i = 1; i < argc; ++i) {
    if (argv[i][0] != '-') {
      return argv[i];
    }
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_first_arg>:
  endbr64
  cmp    $0x1,%edi
  jle    L36
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r15
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r13
  mov    %rbx,%rbp
  lea    D8(%rip),%r14
  jmp    L41
L30:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L40
L41:
  mov    0x0(%rbp),%r12
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  cmp    %rax,%r12
  jne    L30
  lea    0x7(%r12),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoll@plt>
  mov    %rax,(%r15)
  jmp    L30
L40:
  mov    (%rbx),%rax
  cmpb   $0x2d,(%rax)
  jne    L65
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L40
  mov    $0x0,%eax
L65:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string

tool: D8: -trunc=

assistant: ```c
char *find_first_arg(int argc, char **argv, long long int *truncation_location) {
  int i;
  for (i = 1; i < argc; ++i) {
    if (strstr(argv[i], "-trunc=") == argv[i]) {
      *truncation_location = strtoll(argv[i] + 7, NULL, 10);
    }
  }
  for (i = 1; i < argc; ++i) {
    if (argv[i][0] != '-') {
      return argv[i];
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_first_arg>:
  endbr64
  cmp    $0x1,%edi
  jle    L69
  push   %r15
  lea    -0x2(%rdi),%eax
  mov    %rdx,%r15
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  lea    0x10(%rsi,%rax,8),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  mov    %rbx,%rbp
  sub    $0x8,%rsp
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L7
L28:
  mov    0x0(%rbp),%r12
  mov    $0x7,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L15
  lea    0x7(%r12),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoll@plt>
  mov    %rax,(%r15)
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L68
L7:
  mov    (%rbx),%rax
  cmpb   $0x2d,(%rax)
  je     L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L69:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D6: -trunc=

assistant: ```c
char *find_first_arg(int argc, char **argv, long long int *truncation_location) {
  int i;
  for (i = 1; i < argc; ++i) {
    if (strstr(argv[i], "-trunc=") == argv[i]) {
      *truncation_location = strtoll(argv[i] + 7, NULL, 10);
    }
  }
  for (i = 1; i < argc; ++i) {
    if (argv[i][0] != '-') {
      return argv[i];
    }
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_first_arg>:
  endbr64
  cmp    $0x1,%edi
  jle    L9
  push   %r15
  lea    -0x2(%rdi),%eax
  mov    %rdx,%r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    0x10(%rsi,%rax,8),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  mov    %rbx,%rbp
  sub    $0x8,%rsp
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L2:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L7
L10:
  mov    0x0(%rbp),%r12
  mov    $0x7,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L2
  lea    0x7(%r12),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoll@plt>
  mov    %rax,(%r15)
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L69
L7:
  mov    (%rbx),%rax
  cmpb   $0x2d,(%rax)
  je     L22
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: D8: -trunc=

assistant: ```c
char *find_first_arg(int argc, char **argv, long long int *truncation_location) {
  int i;
  for (i = 1; i < argc; ++i) {
    if (strstr(argv[i], "-trunc=") == argv[i]) {
      *truncation_location = strtoll(argv[i] + 7, NULL, 10);
    }
  }
  for (i = 1; i < argc; ++i) {
    if (argv[i][0] != '-') {
      return argv[i];
    }
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pbl_mem2dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L44
  lea    D5(%rip),%rax
  mov    %rax,-0x18(%rbp)
L44:
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pbl_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L16
L1:
  cmpq   $0x0,-0x28(%rbp)
  je     L26
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L26:
  cmpq   $0x0,-0x38(%rbp)
  je     L34
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
L34:
  mov    -0x8(%rbp),%rax
L16:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: pbl_mem2dup

assistant: ```c
void *pbl_mem2dup(char *tag, void *mem1, size_t len1, void *mem2, size_t len2) {
  void *ret;
  if (!tag) {
    tag = "pbl_mem2dup";
  }
  ret = pbl_malloc(tag, len1 + len2);
  if (!ret) {
    return (0);
  }
  if (len1) {
    memcpy(ret, mem1, len1);
  }
  if (len2) {
    memcpy(((char *)ret) + len1, mem2, len2);
  }
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pbl_mem2dup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    %rcx,%r13
  mov    %r8,%r12
  test   %rdi,%rdi
  lea    D6(%rip),%rax
  cmove  %rax,%rdi
  lea    (%rdx,%r8,1),%rsi
  call   <pbl_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L10
  test   %rbx,%rbx
  jne    L36
L39:
  test   %r12,%r12
  jne    L17
L10:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L39
L17:
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: pbl_mem2dup

assistant: ```c
void *pbl_mem2dup(char *tag, void *mem1, size_t len1, void *mem2, size_t len2) {
  void *ret;
  if (!tag) {
    tag = "pbl_mem2dup";
  }
  ret = pbl_malloc(tag, len1 + len2);
  if (!ret) {
    return (0);
  }
  if (len1) {
    memcpy(ret, mem1, len1);
  }
  if (len2) {
    memcpy(((char *)ret) + len1, mem2, len2);
  }
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pbl_mem2dup>:
  endbr64
  push   %r14
  test   %rdi,%rdi
  lea    D6(%rip),%rax
  mov    %r8,%r14
  push   %r13
  cmove  %rax,%rdi
  mov    %rsi,%r13
  lea    (%rdx,%r8,1),%rsi
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <pbl_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L36
  test   %rbx,%rbx
  jne    L28
  test   %r14,%r14
  jne    L22
L36:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L28:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  test   %r14,%r14
  je     L36
L22:
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D6: pbl_mem2dup

assistant: ```c
void *pbl_mem2dup(char *tag, void *mem1, size_t len1, void *mem2, size_t len2) {
  void *ret;
  if (!tag) {
    tag = "pbl_mem2dup";
  }
  ret = pbl_malloc(tag, len1 + len2);
  if (!ret) {
    return (0);
  }
  if (len1) {
    memcpy(ret, mem1, len1);
  }
  if (len2) {
    memcpy(((char *)ret) + len1, mem2, len2);
  }
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pbl_mem2dup>:
  endbr64
  push   %r14
  test   %rdi,%rdi
  lea    D4(%rip),%rax
  mov    %r8,%r14
  push   %r13
  cmove  %rax,%rdi
  mov    %rsi,%r13
  lea    (%rdx,%r8,1),%rsi
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <pbl_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L38
  test   %rbx,%rbx
  jne    L29
  test   %r14,%r14
  jne    L11
L38:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L29:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  test   %r14,%r14
  je     L38
L11:
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: pbl_mem2dup

assistant: ```c
void *pbl_mem2dup(char *tag, void *mem1, size_t len1, void *mem2, size_t len2) {
  void *ret;
  if (!tag) {
    tag = "pbl_mem2dup";
  }
  ret = pbl_malloc(tag, len1 + len2);
  if (!ret) {
    return (0);
  }
  if (len1) {
    memcpy(ret, mem1, len1);
  }
  if (len2) {
    memcpy(((char *)ret) + len1, mem2, len2);
  }
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  fld1
  fstpt  -0x20(%rbp)
  fldz
  fstpt  -0x10(%rbp)
  fldz
  fldt   0x10(%rbp)
  fcomip %st(1),%st
  fstp   %st(0)
  jb     L13
  jmp    L2
L39:
  fstp   %st(0)
L8:
  fldt   -0x10(%rbp)
  fld    %st(0)
  fmulp  %st,%st(1)
  fldt   0x10(%rbp)
  fxch   %st(1)
  fcomip %st(1),%st
  fstp   %st(0)
  jbe    L30
  fldt   -0x10(%rbp)
  fldt   -0x20(%rbp)
  fsubrp %st,%st(1)
  fstpt  -0x10(%rbp)
  fldt   -0x20(%rbp)
  fldt   0xec0(%rip)        # 2000 <_fini+0xe94>
  fdivrp %st,%st(1)
  fstpt  -0x20(%rbp)
  jmp    L2
L30:
  fldt   -0x10(%rbp)
  fldt   -0x20(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x10(%rbp)
L2:
  fldt   -0x10(%rbp)
  fmul   %st(0),%st
  fldt   0x10(%rbp)
  fucomip %st(1),%st
  jp     L39
  fldt   0x10(%rbp)
  fucomip %st(1),%st
  fstp   %st(0)
  jne    L8
L13:
  fldt   -0x10(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
long double sqrt(long double x) {
  long double mod = 1, n = 0;
  if (x >= 0) {
    while (n * n != x) {
      if (n * n > x) {
        n -= mod;
        mod /= 10;
      } else {
        n += mod;
      }
    }
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sqrt>:
  endbr64
  fldz
  fldt   0x8(%rsp)
  fcomi  %st(1),%st
  jb     L58
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L93
  je     L26
L93:
  fldz
  fld    %st(0)
  fld1
  flds   0xee5(%rip)        # 2000 <_fini+0xeb4>
  fxch   %st(3)
  jmp    L86
L53:
  fadd   %st,%st(1)
L1:
  fld    %st(1)
  fmul   %st(2),%st
  fucomi %st(4),%st
  jp     L86
  je     L18
L86:
  fcomip %st(4),%st
  jbe    L53
  fsubr  %st,%st(1)
  fdiv   %st(2),%st
  jmp    L1
L58:
  fstp   %st(0)
  fstp   %st(0)
  fldz
  jmp    L57
L18:
  fstp   %st(0)
  fstp   %st(0)
  fstp   %st(1)
  fstp   %st(1)
L57:
  ret
L26:
  fstp   %st(0)
  fldz
  jmp    L57
```

assistant: ```c
long double sqrt(long double x) {
  long double mod = 1, n = 0;
  if (x >= 0) {
    while (n * n != x) {
      if (n * n > x) {
        n -= mod;
        mod /= 10;
      } else {
        n += mod;
      }
    }
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sqrt>:
  endbr64
  fldz
  fldt   0x8(%rsp)
  fcomi  %st(1),%st
  jb     L60
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L28
  je     L59
L28:
  fldz
  fld    %st(0)
  fld1
  fxch   %st(2)
  jmp    L1
L26:
  fsub   %st(1),%st
  fxch   %st(1)
  fdivs  0xed6(%rip)        # 2000 <_fini+0xe88>
L78:
  fld    %st(1)
  fmul   %st(2),%st
  fucomi %st(3),%st
  jp     L52
  je     L34
  fxch   %st(1)
  fxch   %st(2)
  fxch   %st(1)
  jmp    L1
L52:
  fxch   %st(1)
  fxch   %st(2)
  fxch   %st(1)
  nopw   0x0(%rax,%rax,1)
L1:
  fcomip %st(3),%st
  ja     L26
  fadd   %st(1),%st
  fxch   %st(1)
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L34:
  fstp   %st(0)
  fstp   %st(0)
  fstp   %st(1)
  ret
  nop
L60:
  fstp   %st(0)
  fstp   %st(0)
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L59:
  fstp   %st(0)
L32:
  fldz
  ret
```

assistant: ```c
long double sqrt(long double x) {
  long double mod = 1, n = 0;
  if (x >= 0) {
    while (n * n != x) {
      if (n * n > x) {
        n -= mod;
        mod /= 10;
      } else {
        n += mod;
      }
    }
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqrt>:
  endbr64
  fldz
  fldt   0x8(%rsp)
  fcomi  %st(1),%st
  jb     L70
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L65
  je     L61
L65:
  fldz
  fld    %st(0)
  fld1
  fxch   %st(2)
  jmp    L16
L37:
  fxch   %st(3)
  fxch   %st(1)
  fxch   %st(2)
  fxch   %st(1)
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L3:
  fxch   %st(3)
  fxch   %st(1)
  fxch   %st(2)
  fxch   %st(1)
L16:
  fcomip %st(3),%st
  jbe    L9
  fsub   %st(1),%st
  fxch   %st(1)
  fdivs  0xeba(%rip)        # 2000 <_fini+0xe78>
  fld    %st(1)
  fmul   %st(2),%st
  fxch   %st(3)
  fucomi %st(3),%st
  jp     L37
  jne    L3
  fstp   %st(0)
  fstp   %st(0)
  fstp   %st(1)
  ret
  nopl   0x0(%rax)
L9:
  fadd   %st(1),%st
  fld    %st(0)
  fmul   %st(1),%st
  fucomi %st(3),%st
  jp     L16
  jne    L16
  fstp   %st(0)
  fstp   %st(1)
  fstp   %st(1)
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  fstp   %st(0)
  fstp   %st(0)
  jmp    L23
  xchg   %ax,%ax
L61:
  fstp   %st(0)
L23:
  fldz
  ret
```

assistant: ```c
long double sqrt(long double x) {
  long double mod = 1, n = 0;
  if (x >= 0) {
    while (n * n != x) {
      if (n * n > x) {
        n -= mod;
        mod /= 10;
      } else {
        n += mod;
      }
    }
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gfx_enable_softvga>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x80009444,%edi
  call   <gfx_pci_config_read@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0xfffffffe,%eax
  mov    %rax,%rsi
  mov    $0x80009444,%edi
  call   <gfx_pci_config_write@plt>
  mov    $0x80009444,%edi
  call   <gfx_pci_config_read@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L10
  mov    $0x1,%eax
  jmp    L19
L10:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int gfx_enable_softvga(void) {
  unsigned long reg_val;
  reg_val = gfx_pci_config_read(0x80009444);
  gfx_pci_config_write(0x80009444, reg_val & 0xfffffffel);
  reg_val = gfx_pci_config_read(0x80009444);
  if ((reg_val & 0x1) == 0)
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gfx_enable_softvga>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80009444,%edi
  call   <gfx_pci_config_read@plt>
  and    $0xfffffffe,%eax
  mov    %rax,%rsi
  mov    $0x80009444,%edi
  call   <gfx_pci_config_write@plt>
  mov    $0x80009444,%edi
  call   <gfx_pci_config_read@plt>
  xor    $0x1,%rax
  and    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gfx_enable_softvga(void) {
  unsigned long reg_val;
  reg_val = gfx_pci_config_read(0x80009444);
  gfx_pci_config_write(0x80009444, reg_val & 0xfffffffel);
  reg_val = gfx_pci_config_read(0x80009444);
  if ((reg_val & 0x1) == 0)
    return (1);
  else
    return (0);
}
```