user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D24(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  test   %ebx,%ebx
  jle    L30
  lea    0xa8(%rsp),%rsi
  lea    0x1(%rbx),%r9d
  mov    $0x1,%ecx
  xor    %edi,%edi
  mov    $0xf423f,%r8d
  nopl   0x0(%rax,%rax,1)
L27:
  mov    $0x1,%eax
  nopl   (%rax)
L35:
  cmp    %eax,%ecx
  mov    %edi,%edx
  cmovne %r8d,%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jge    L35
  add    $0x1,%ecx
  add    $0x28,%rsi
  cmp    %r9d,%ecx
  jne    L27
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L114
L53:
  mov    $0x1,%ebx
  lea    0x1c(%rsp),%r15
  lea    0x18(%rsp),%r14
  lea    0x14(%rsp),%r13
  lea    D1(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r14,%rdx
  mov    %r15,%rcx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  movslq 0x14(%rsp),%rax
  movslq 0x18(%rsp),%rdx
  lea    (%rax,%rax,4),%rax
  lea    (%rdx,%rax,2),%rax
  mov    0x1c(%rsp),%edx
  mov    %edx,0x80(%rsp,%rax,4)
  cmp    %ebx,0x10(%rsp)
  jge    L10
  mov    0xc(%rsp),%ebx
  test   %ebx,%ebx
  jle    L168
L114:
  mov    %ebx,%r12d
  lea    0x24(%rsp),%rdi
  lea    0xac(%rsp),%rsi
  shl    $0x2,%r12
  mov    %r12,%rdx
  call   <memcpy@plt>
  lea    0x54(%rsp),%rdi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  movl   $0x1,0x54(%rsp)
  cmp    $0x1,%ebx
  jle    L90
  mov    $0x1,%edx
  mov    $0x1,%edi
  lea    0x20(%rsp),%r12
  lea    0x80(%rsp),%r8
L77:
  mov    $0x1,%eax
  mov    $0xf423f,%ecx
  jmp    L174
  nopl   0x0(%rax)
L111:
  mov    0x50(%rsp,%rax,4),%edx
L174:
  test   %edx,%edx
  jne    L142
  mov    (%r12,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L142
  mov    %edx,%ecx
  mov    %eax,%ebp
L142:
  add    $0x1,%rax
  cmp    %eax,%ebx
  jge    L111
  movslq %ebp,%rsi
  movl   $0x1,0x50(%rsp,%rsi,4)
  lea    (%rsi,%rsi,4),%rax
  lea    (%r8,%rax,8),%rcx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L85:
  mov    (%rcx,%rax,4),%edx
  cmp    $0xf423e,%edx
  jg     L143
  add    0x20(%rsp,%rsi,4),%edx
  cmp    %edx,(%r12,%rax,4)
  jle    L143
  mov    %edx,(%r12,%rax,4)
L143:
  add    $0x1,%rax
  cmp    %eax,%ebx
  jge    L85
  add    $0x1,%edi
  cmp    %ebx,%edi
  jge    L171
  mov    0x54(%rsp),%edx
  jmp    L77
L90:
  lea    0x20(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L171:
  mov    $0x1,%ebx
  lea    D14(%rip),%rbp
  nopl   0x0(%rax)
L86:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L86
L168:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  cmpl   $0x0,0x10(%rsp)
  jg     L53
  jmp    L168
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
type_infered: string
name: parse_data
arguments: label: D1
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string

tool: D24: %d %d

tool: D1: %d %d %d

tool: D14: %d 

assistant: ```c
int main() {
  int e[10][10], dis[10], book[10], n, m, u, v, w;
  scanf("%d %d", &n, &m);
  for (int i = 1; i <= n; i++)
    for (int j = 1; j <= n; j++)
      if (i == j)
        e[i][j] = 0;
      else
        e[i][j] = 999999;
  for (int i = 1; i <= m; i++) {
    scanf("%d %d %d", &u, &v, &w);
    e[u][v] = w;
  }
  for (int i = 1; i <= n; i++)
    dis[i] = e[1][i];
  for (int i = 1; i <= n; i++)
    book[i] = 0;
  book[1] = 1;
  for (int i = 1; i <= n - 1; i++) {
    int node;
    int min = 999999;
    for (int j = 1; j <= n; j++) {
      if (book[j] == 0 && dis[j] < min) {
        min = dis[j];
        node = j;
      }
    }
    book[node] = 1;
    for (int v = 1; v <= n; v++) {
      if (e[node][v] < 999999) {
        if (dis[v] > dis[node] + e[node][v])
          dis[v] = dis[node] + e[node][v];
      }
    }
  }
  for (int i = 1; i <= n; i++)
    printf("%d ", dis[i]);
  return 0;
}
```