ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L18
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L18:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L14
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int ch;
  while ((ch = getchar()) != EOF) {
    putchar(ch);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L6
L15:
  call   <putchar@plt>
L6:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    D6(%rip),%rax
  cmp    %edi,(%rax)
  jne    L15
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int ch;
  while ((ch = getchar()) != EOF) {
    putchar(ch);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    D1(%rip),%rbx
  jmp    L18
  xchg   %ax,%ax
L8:
  call   <putchar@plt>
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L8
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int ch;
  while ((ch = getchar()) != EOF) {
    putchar(ch);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    D0(%rip),%rbx
  jmp    L0
  xchg   %ax,%ax
L13:
  call   <putchar@plt>
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L13
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int ch;
  while ((ch = getchar()) != EOF) {
    putchar(ch);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<append_flag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
L13:
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L22
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D52(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L13
L22:
  mov    -0x8(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  or     -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L3:
  mov    D40(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L14
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D52(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L3
L14:
  mov    -0x8(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void append_flag(int fd, int flag) {
  int err;
  do {
    err = fcntl(fd, F_GETFL, 0);
  } while (err == -1 && errno == EINTR);
  assert(err >= 0);
  const int flags = err | flag;
  do {
    err = fcntl(fd, F_SETFL, flags);
  } while (err == -1 && errno == EINTR);
  assert(err >= 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<append_flag>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    D37(%rip),%r12
L35:
  mov    $0x0,%edx
  mov    (%r12),%esi
  mov    %ebp,%edi
  call   <fcntl@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L27
  mov    D33(%rip),%rdx
  mov    D46(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L35
L27:
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  or     %r13d,%ebx
  mov    D56(%rip),%r12
L30:
  mov    %ebx,%edx
  mov    (%r12),%esi
  mov    %ebp,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  jne    L33
  mov    D33(%rip),%rcx
  mov    D46(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L30
L33:
  not    %eax
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void append_flag(int fd, int flag) {
  int err;
  do {
    err = fcntl(fd, F_GETFL, 0);
  } while (err == -1 && errno == EINTR);
  assert(err >= 0);
  const int flags = err | flag;
  do {
    err = fcntl(fd, F_SETFL, flags);
  } while (err == -1 && errno == EINTR);
  assert(err >= 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<append_flag>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D38(%rip),%r12
  jmp    L49
  nopl   0x0(%rax)
L69:
  mov    D23(%rip),%rax
  mov    D16(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L19
L49:
  mov    (%r12),%esi
  xor    %edx,%edx
  mov    %ebp,%edi
  call   <fcntl@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L69
  mov    %eax,%edi
  or     %r13d,%ebx
  not    %edi
  shr    $0x1f,%edi
L55:
  call   <assert@plt>
  mov    D13(%rip),%r12
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L6:
  mov    D23(%rip),%rax
  mov    D16(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L47
L34:
  mov    (%r12),%esi
  mov    %ebx,%edx
  mov    %ebp,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L6
  not    %eax
  add    $0x8,%rsp
  shr    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  jmp    1070 <assert@plt>
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %edi,%edi
  jmp    L55
  nopl   0x0(%rax)
L47:
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <assert@plt>
```

assistant: ```c
void append_flag(int fd, int flag) {
  int err;
  do {
    err = fcntl(fd, F_GETFL, 0);
  } while (err == -1 && errno == EINTR);
  assert(err >= 0);
  const int flags = err | flag;
  do {
    err = fcntl(fd, F_SETFL, flags);
  } while (err == -1 && errno == EINTR);
  assert(err >= 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<append_flag>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D40(%rip),%r12
  jmp    L17
  nopl   0x0(%rax)
L1:
  mov    D2(%rip),%rax
  mov    D21(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L47
L17:
  mov    (%r12),%esi
  xor    %edx,%edx
  mov    %ebp,%edi
  call   <fcntl@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L1
  mov    %eax,%edi
  or     %r13d,%ebx
  not    %edi
  shr    $0x1f,%edi
L49:
  call   <assert@plt>
  mov    D58(%rip),%r12
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L62:
  mov    D2(%rip),%rax
  mov    D21(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L9
L64:
  mov    (%r12),%esi
  mov    %ebx,%edx
  mov    %ebp,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L62
  not    %eax
  add    $0x8,%rsp
  shr    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  jmp    1070 <assert@plt>
  cs nopw 0x0(%rax,%rax,1)
L47:
  xor    %edi,%edi
  jmp    L49
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <assert@plt>
```

assistant: ```c
void append_flag(int fd, int flag) {
  int err;
  do {
    err = fcntl(fd, F_GETFL, 0);
  } while (err == -1 && errno == EINTR);
  assert(err >= 0);
  const int flags = err | flag;
  do {
    err = fcntl(fd, F_SETFL, flags);
  } while (err == -1 && errno == EINTR);
  assert(err >= 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L3
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <printbits>
L3:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: %d

assistant: ```c
void printbits(int n) {
  if (n > 0) {
    printf("%d", n % 2);
    printbits(n / 2);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<printbits>:
  endbr64
  test   %edi,%edi
  jg     L3
  ret
L3:
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%eax
  shr    $0x1f,%eax
  lea    (%rdi,%rax,1),%esi
  and    $0x1,%esi
  sub    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  shr    $0x1f,%edi
  add    %ebx,%edi
  sar    %edi
  call   <printbits>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D0: %d

assistant: ```c
void printbits(int n) {
  if (n > 0) {
    printf("%d", n % 2);
    printbits(n / 2);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printbits>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  and    $0x1,%esi
  call   <printf@plt>
  sar    %ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: %d

assistant: ```c
void printbits(int n) {
  if (n > 0) {
    printf("%d", n % 2);
    printbits(n / 2);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printbits>:
  endbr64
  test   %edi,%edi
  jle    L16
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  and    $0x1,%esi
  call   <printf@plt>
  sar    %ebx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: %d

assistant: ```c
void printbits(int n) {
  if (n > 0) {
    printf("%d", n % 2);
    printbits(n / 2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  lea    -0x14(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <rect@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_guessed: string
name: extract_symbolic_data
arguments: label: D1
type_guessed: string
name: extract_symbolic_data
arguments: label: D6
type_guessed: string
name: extract_symbolic_data
arguments: label: D22
type_guessed: string

tool: D28: Enter width: 

tool: D1: %d

tool: D6: Enter height: 

tool: D22: Perimeter = %d


assistant: ```c
int main() {
  int perim, width, height;
  printf("Enter width: ");
  scanf("%d", &width);
  printf("Enter height: ");
  scanf("%d", &height);
  rect(&perim, width, height);
  printf("Perimeter = %d\n", perim);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D37(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rdi
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  call   <rect@plt>
  mov    0xc(%rsp),%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D31
data_type: string
name: extract_symbolic_data
arguments: data_label: D37
data_type: string
name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D35
data_type: string

tool: D31: Enter width: 

tool: D37: %d

tool: D13: Enter height: 

tool: D35: Perimeter = %d


assistant: ```c
int main() {
  int perim, width, height;
  printf("Enter width: ");
  scanf("%d", &width);
  printf("Enter height: ");
  scanf("%d", &height);
  rect(&perim, width, height);
  printf("Perimeter = %d\n", perim);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D38(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%edx
  lea    0xc(%rsp),%rdi
  call   <rect@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D38
type: string
name: disassemble_data
arguments: label: D18
type: string
name: disassemble_data
arguments: label: D36
type: string

tool: D0: Enter width: 

tool: D38: %d

tool: D18: Enter height: 

tool: D36: Perimeter = %d


assistant: ```c
int main() {
  int perim, width, height;
  printf("Enter width: ");
  scanf("%d", &width);
  printf("Enter height: ");
  scanf("%d", &height);
  rect(&perim, width, height);
  printf("Perimeter = %d\n", perim);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D12(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%edx
  lea    0xc(%rsp),%rdi
  call   <rect@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string

tool: D11: Enter width: 

tool: D12: %d

tool: D15: Enter height: 

tool: D26: Perimeter = %d


assistant: ```c
int main() {
  int perim, width, height;
  printf("Enter width: ");
  scanf("%d", &width);
  printf("Enter height: ");
  scanf("%d", &height);
  rect(&perim, width, height);
  printf("Perimeter = %d\n", perim);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L3
L5:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
char *nstrdup(const char *str) {
  if (str)
    return strdup(str);
  else
    return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nstrdup>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  call   <strdup@plt>
  add    $0x8,%rsp
  ret
L6:
  ret
```

assistant: ```c
char *nstrdup(const char *str) {
  if (str)
    return strdup(str);
  else
    return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nstrdup>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <strdup@plt>
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *nstrdup(const char *str) {
  if (str)
    return strdup(str);
  else
    return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nstrdup>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <strdup@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *nstrdup(const char *str) {
  if (str)
    return strdup(str);
  else
    return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L25
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L25
  mov    $0x1,%eax
  jmp    L20
L25:
  mov    $0x0,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
extern int is_dir(const char *path) {
  struct stat sr;
  if (!stat(path, &sr) && S_ISDIR(sr.st_mode)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_dir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L1
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L1:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L5
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int is_dir(const char *path) {
  struct stat sr;
  if (!stat(path, &sr) && S_ISDIR(sr.st_mode)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_dir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L9
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int is_dir(const char *path) {
  struct stat sr;
  if (!stat(path, &sr) && S_ISDIR(sr.st_mode)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_dir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L8
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int is_dir(const char *path) {
  struct stat sr;
  if (!stat(path, &sr) && S_ISDIR(sr.st_mode)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x20,-0xc(%rbp)
  jmp    L55
L1:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  or     %eax,-0x10(%rbp)
  sarl   -0x14(%rbp)
  subl   $0x1,-0xc(%rbp)
  shll   -0x10(%rbp)
L55:
  cmpl   $0x0,-0xc(%rbp)
  jg     L1
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L11:
  mov    $0x1f,%eax
  sub    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0xc(%rbp)
L23:
  cmpl   $0x1f,-0xc(%rbp)
  jle    L11
  movl   $0x20,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L48:
  shll   -0x10(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  or     %eax,-0x10(%rbp)
  sarl   -0x14(%rbp)
  subl   $0x1,-0xc(%rbp)
L24:
  cmpl   $0x0,-0xc(%rbp)
  jg     L48
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int input;
  int input_copy;
  int output;
  output = 0;
  input_copy = input;
  int count;
  count = 32;
  while (count > 0) {
    output = output | (input_copy & 1);
    input_copy = input_copy >> 1;
    count = count - 1;
    output = output << 1;
  }
  count = 0;
  int value;
  value = 0;
  while (count < 32) {
    value = (output >> (31 - count)) & 1;
    assert(((input >> count) & 1) == value);
    count = count + 1;
  }
  count = 32;
  input_copy = output;
  output = 0;
  while (count > 0) {
    output = output << 1;
    output = output | (input_copy & 1);
    input_copy = input_copy >> 1;
    count = count - 1;
  }
  assert(output == input);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x20,%edx
  mov    $0x0,%ebx
L23:
  mov    %r12d,%eax
  and    $0x1,%eax
  or     %ebx,%eax
  sar    %r12d
  lea    (%rax,%rax,1),%ebx
  sub    $0x1,%edx
  jne    L23
  mov    $0x0,%ebp
  mov    $0x1f,%r13d
L15:
  mov    %r13d,%ecx
  sub    %ebp,%ecx
  mov    %ebx,%eax
  sar    %cl,%eax
  mov    %r12d,%edx
  mov    %ebp,%ecx
  sar    %cl,%edx
  xor    %edx,%eax
  test   $0x1,%al
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x1,%ebp
  cmp    $0x20,%ebp
  jne    L15
  mov    $0x20,%edx
  mov    $0x0,%eax
L18:
  add    %eax,%eax
  mov    %ebx,%ecx
  and    $0x1,%ecx
  or     %ecx,%eax
  sar    %ebx
  sub    $0x1,%edx
  jne    L18
  cmp    %eax,%r12d
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  int input;
  int input_copy;
  int output;
  output = 0;
  input_copy = input;
  int count;
  count = 32;
  while (count > 0) {
    output = output | (input_copy & 1);
    input_copy = input_copy >> 1;
    count = count - 1;
    output = output << 1;
  }
  count = 0;
  int value;
  value = 0;
  while (count < 32) {
    value = (output >> (31 - count)) & 1;
    assert(((input >> count) & 1) == value);
    count = count + 1;
  }
  count = 32;
  input_copy = output;
  output = 0;
  while (count > 0) {
    output = output << 1;
    output = output | (input_copy & 1);
    input_copy = input_copy >> 1;
    count = count - 1;
  }
  assert(output == input);
  return 0;
}
```