user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x20(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x20(%rbp)
  jmp    L81
L139:
  movl   $0x1,-0x1c(%rbp)
  jmp    L167
L42:
  movl   $0x1,-0x18(%rbp)
  jmp    L148
L89:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x18(%rbp)
  jge    L49
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L49
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jge    L49
  addl   $0x1,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L188
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L16
L188:
  mov    -0x20(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L27
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L16
L27:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L177
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L177
L16:
  addl   $0x1,-0x10(%rbp)
L177:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L49
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L49
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L49
  addl   $0x1,-0xc(%rbp)
L49:
  addl   $0x1,-0x18(%rbp)
L148:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L89
  addl   $0x1,-0x1c(%rbp)
L167:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L42
  addl   $0x1,-0x20(%rbp)
L81:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L139
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string
name: parse_data
arguments: data_tag: D1
data_type: string

tool: D0: %d

tool: D1: Number of possible triangles is %d

assistant: ```c
int main() {
  int N, i, j, k, x, y, m;
  x = 0;
  N = 0;
  y = 0;
  m = 0;
  i = 1;
  scanf("%d", &N);
  for (i = 1; i <= N; i++) {
    for (j = 1; j <= N; j++) {
      for (k = 1; k <= N; k++) {
        if ((i + j > k) && (i + k > j) && (j + k > i)) {
          x++;
          if (((i == j) && j != k) || ((i == k) && k != j) || ((j == k) && k != i))
            y++;
          if ((i != j) && (j != k) && (k != i))
            m++;
        }
      }
    }
  }
  printf("Number of possible triangles is %d", x - y + (y / 3) - m + (m / 6));
  return 0;
}
```