user: Translate the below assembly code into C programming language:

```asm
<do_nothing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  movsd  %xmm0,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D159(%rip),%xmm0
  movsd  %xmm0,-0x70(%rbp)
  movsd  D21(%rip),%xmm0
  movsd  %xmm0,-0x68(%rbp)
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  movsd  D18(%rip),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  D127(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D53(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  D23(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D29(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D122(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D46(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D118(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0xc,-0x84(%rbp)
  mov    -0x98(%rbp),%rax
  movq   %rax,%xmm0
  lea    D154(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movl   $0x0,-0x88(%rbp)
  jmp    L32
L42:
  mov    -0x88(%rbp),%eax
  cltq
  movsd  -0x70(%rbp,%rax,8),%xmm0
  movsd  %xmm0,-0x80(%rbp)
  movsd  -0x98(%rbp),%xmm0
  divsd  -0x80(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <trunc@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x78(%rbp)
  movsd  -0x78(%rbp),%xmm0
  mov    -0x80(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  -0x80(%rbp),%xmm0
  mov    -0x98(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fmod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x98(%rbp)
  addl   $0x1,-0x88(%rbp)
L32:
  mov    -0x88(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jl     L42
  movsd  -0x98(%rbp),%xmm0
  comisd D128(%rip),%xmm0
  ja     L24
  jmp    L40
L24:
  mov    -0x98(%rbp),%rax
  movq   %rax,%xmm0
  lea    D157(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L40:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D159
data_type: f64
name: read_data
arguments: tag: D21
data_type: f64
name: read_data
arguments: tag: D15
data_type: f64
name: read_data
arguments: tag: D18
data_type: f64
name: read_data
arguments: tag: D127
data_type: f64
name: read_data
arguments: tag: D53
data_type: f64
name: read_data
arguments: tag: D23
data_type: f64
name: read_data
arguments: tag: D29
data_type: f64
name: read_data
arguments: tag: D122
data_type: f64
name: read_data
arguments: tag: D46
data_type: f64
name: read_data
arguments: tag: D26
data_type: f64
name: read_data
arguments: tag: D118
data_type: f64
name: read_data
arguments: tag: D154
data_type: string
name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D128
data_type: f64
name: read_data
arguments: tag: D157
data_type: string

tool: D159: 100

tool: D21: 50

tool: D15: 20

tool: D18: 10

tool: D127: 5

tool: D53: 2

tool: D23: 1

tool: D29: 0.5

tool: D122: 0.25

tool: D46: 0.1

tool: D26: 0.05

tool: D118: 0.01

tool: D154: Calculating cash notes, amount: %.3f


tool: D1: Real value: %.2f, we'll give you %.0f cash notes


tool: D128: 0.001

tool: D157: 
Ow no, missed %.2f cents... Do you accept a lollipop?



assistant: ```c
void do_nothing(double value) {
  double brazilian_current[12] = {100.0, 50.0, 20.0, 10.0, 5.0, 2.0, 1.0, 0.50, 0.25, 0.10, 0.05, 0.01};
  int array_size = 12;
  printf("Calculating cash notes, amount: %.3f\n", value);
  int i = 0;
  for (; i < array_size; ++i) {
    double base = brazilian_current[i];
    double quotient = trunc(value / base);
    printf("Real value: %.2f, we'll give you %.0f cash notes\n", base, quotient);
    value = fmod(value, base);
  }
  if (value > 0.001) {
    printf("\nOw no, missed %.2f cents... Do you accept a lollipop?\n\n", value);
  }
}
```