ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pot_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %edi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L12
  movss  D5(%rip),%xmm0
  jmp    L23
L12:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%edi
  movd   %eax,%xmm0
  call   <pot_float>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L32
  movss  -0x4(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  jmp    L23
L32:
  cmpl   $0x0,-0x18(%rbp)
  jle    L59
  movss  -0x14(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  jmp    L23
L59:
  movss  -0x4(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  divss  -0x14(%rbp),%xmm0
L23:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: byte[4]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float pot_float(float x, int y) {
  if (y == 0)
    return 1;
  float temp = pot_float(x, y / 2);
  if (y % 2 == 0)
    return temp * temp;
  if (y > 0)
    return x * temp * temp;
  return (temp * temp) / x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pot_float>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  test   %edi,%edi
  jne    L11
  movss  D4(%rip),%xmm0
L3:
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  mov    %edi,%ebx
  shr    $0x1f,%edi
  add    %ebx,%edi
  sar    %edi
  call   <pot_float>
  test   $0x1,%bl
  je     L48
  test   %ebx,%ebx
  jg     L18
  mulss  %xmm0,%xmm0
  divss  0xc(%rsp),%xmm0
  jmp    L3
L48:
  mulss  %xmm0,%xmm0
  jmp    L3
L18:
  movss  0xc(%rsp),%xmm1
  mulss  %xmm0,%xmm1
  mulss  %xmm1,%xmm0
  jmp    L3
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float pot_float(float x, int y) {
  if (y == 0)
    return 1;
  float temp = pot_float(x, y / 2);
  if (y % 2 == 0)
    return temp * temp;
  if (y > 0)
    return x * temp * temp;
  return (temp * temp) / x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pot_float>:
  endbr64
  test   %edi,%edi
  jne    L136
  movss  D12(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L136:
  push   %r12
  mov    %edi,%eax
  movaps %xmm0,%xmm2
  push   %rbp
  shr    $0x1f,%eax
  push   %rbx
  add    %edi,%eax
  mov    %edi,%ebx
  sub    $0x10,%rsp
  sar    %eax
  movss  D12(%rip),%xmm0
  je     L125
  test   %edi,%edi
  lea    0x3(%rdi),%edx
  movaps %xmm0,%xmm3
  cmovns %edi,%edx
  sar    $0x2,%edx
  jne    L15
L105:
  test   $0x1,%al
  je     L63
  cmp    $0x1,%ebx
  jg     L70
  mulss  %xmm3,%xmm3
  divss  %xmm2,%xmm3
  movaps %xmm3,%xmm0
L125:
  test   $0x1,%bl
  je     L16
  test   %ebx,%ebx
  jg     L159
  mulss  %xmm0,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  divss  %xmm2,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  test   %edi,%edi
  lea    0x7(%rdi),%ecx
  cmovns %edi,%ecx
  and    $0x1,%edx
  mov    %edx,%ebp
  sar    $0x3,%ecx
  mov    %ecx,%r12d
  je     L91
  test   %ebx,%ebx
  lea    0xf(%rdi),%edi
  movaps %xmm2,%xmm0
  mov    %eax,0xc(%rsp)
  cmovns %ebx,%edi
  movss  %xmm2,0x8(%rsp)
  sar    $0x4,%edi
  call   <pot_float>
  and    $0x1,%r12d
  movss  0x8(%rsp),%xmm2
  mov    0xc(%rsp),%eax
  je     L188
  cmp    $0x7,%ebx
  jg     L163
  mulss  %xmm0,%xmm0
  divss  %xmm2,%xmm0
L91:
  test   %ebp,%ebp
  je     L64
  cmp    $0x3,%ebx
  jg     L148
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm3
  divss  %xmm2,%xmm3
  jmp    L105
L163:
  movaps %xmm2,%xmm1
  mulss  %xmm0,%xmm1
  mulss  %xmm1,%xmm0
  test   %ebp,%ebp
  je     L64
L148:
  movaps %xmm2,%xmm3
  mulss  %xmm0,%xmm3
  mulss  %xmm0,%xmm3
  test   $0x1,%al
  je     L63
L70:
  movaps %xmm2,%xmm1
  and    $0x1,%ebx
  mulss  %xmm3,%xmm1
  mulss  %xmm3,%xmm1
  movaps %xmm1,%xmm0
  je     L16
L159:
  mulss  %xmm0,%xmm2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  mulss  %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  mulss  %xmm3,%xmm3
  movaps %xmm3,%xmm0
  jmp    L125
  nopl   0x0(%rax)
L16:
  mulss  %xmm0,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L188:
  mulss  %xmm0,%xmm0
  jmp    L91
  nopl   0x0(%rax)
L64:
  movaps %xmm0,%xmm3
  mulss  %xmm0,%xmm3
  jmp    L105
```

tool_calls: name: parse_data
arguments: data_tag: D12
data_type: byte[4]

tool: {"D12": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float pot_float(float x, int y) {
  if (y == 0)
    return 1;
  float temp = pot_float(x, y / 2);
  if (y % 2 == 0)
    return temp * temp;
  if (y > 0)
    return x * temp * temp;
  return (temp * temp) / x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pot_float>:
  endbr64
  test   %edi,%edi
  jne    L40
  movss  D4(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L40:
  push   %r12
  mov    %edi,%eax
  movaps %xmm0,%xmm2
  push   %rbp
  shr    $0x1f,%eax
  push   %rbx
  add    %edi,%eax
  mov    %edi,%ebx
  sub    $0x10,%rsp
  sar    %eax
  movss  D4(%rip),%xmm0
  je     L101
  test   %edi,%edi
  lea    0x3(%rdi),%edx
  movaps %xmm0,%xmm3
  cmovns %edi,%edx
  sar    $0x2,%edx
  jne    L178
L158:
  test   $0x1,%al
  je     L59
  cmp    $0x1,%ebx
  jg     L137
  mulss  %xmm3,%xmm3
  divss  %xmm2,%xmm3
  movaps %xmm3,%xmm0
L101:
  test   $0x1,%bl
  je     L83
  test   %ebx,%ebx
  jg     L174
  mulss  %xmm0,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  divss  %xmm2,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L178:
  test   %edi,%edi
  lea    0x7(%rdi),%ecx
  cmovns %edi,%ecx
  and    $0x1,%edx
  mov    %edx,%ebp
  sar    $0x3,%ecx
  mov    %ecx,%r12d
  je     L86
  test   %ebx,%ebx
  lea    0xf(%rdi),%edi
  movaps %xmm2,%xmm0
  mov    %eax,0xc(%rsp)
  cmovns %ebx,%edi
  movss  %xmm2,0x8(%rsp)
  sar    $0x4,%edi
  call   <pot_float>
  and    $0x1,%r12d
  movss  0x8(%rsp),%xmm2
  mov    0xc(%rsp),%eax
  je     L165
  cmp    $0x7,%ebx
  jg     L164
  mulss  %xmm0,%xmm0
  divss  %xmm2,%xmm0
L86:
  test   %ebp,%ebp
  je     L60
  cmp    $0x3,%ebx
  jg     L96
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm3
  divss  %xmm2,%xmm3
  jmp    L158
L164:
  movaps %xmm2,%xmm1
  mulss  %xmm0,%xmm1
  mulss  %xmm1,%xmm0
  test   %ebp,%ebp
  je     L60
L96:
  movaps %xmm2,%xmm3
  mulss  %xmm0,%xmm3
  mulss  %xmm0,%xmm3
  test   $0x1,%al
  je     L59
L137:
  movaps %xmm2,%xmm1
  and    $0x1,%ebx
  mulss  %xmm3,%xmm1
  mulss  %xmm3,%xmm1
  movaps %xmm1,%xmm0
  je     L83
L174:
  mulss  %xmm0,%xmm2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  mulss  %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  mulss  %xmm3,%xmm3
  movaps %xmm3,%xmm0
  jmp    L101
  nopl   0x0(%rax)
L83:
  mulss  %xmm0,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L165:
  mulss  %xmm0,%xmm0
  jmp    L86
  nopl   0x0(%rax)
L60:
  movaps %xmm0,%xmm3
  mulss  %xmm0,%xmm3
  jmp    L158
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float pot_float(float x, int y) {
  if (y == 0)
    return 1;
  float temp = pot_float(x, y / 2);
  if (y % 2 == 0)
    return temp * temp;
  if (y > 0)
    return x * temp * temp;
  return (temp * temp) / x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<allocationMalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  leave
  ret
```

assistant: ```c
void *allocationMalloc(size_t size, int no, int requested_alignment) {
  (void)no;
  (void)requested_alignment;
  return (malloc(size));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<allocationMalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *allocationMalloc(size_t size, int no, int requested_alignment) {
  (void)no;
  (void)requested_alignment;
  return (malloc(size));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<allocationMalloc>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *allocationMalloc(size_t size, int no, int requested_alignment) {
  (void)no;
  (void)requested_alignment;
  return (malloc(size));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<allocationMalloc>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *allocationMalloc(size_t size, int no, int requested_alignment) {
  (void)no;
  (void)requested_alignment;
  return (malloc(size));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x80(%rbp)
  subl   $0x1,-0x84(%rbp)
  cmpl   $0x0,-0x84(%rbp)
  je     L78
  mov    -0x90(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L78
  mov    -0x90(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x7c(%rbp)
  jmp    L29
L78:
  movl   $0x6,-0x7c(%rbp)
L29:
  movq   $0x0,-0x78(%rbp)
  jmp    L14
L58:
  movzbl -0x70(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L26
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x7c(%rbp)
  jg     L26
  lea    -0x80(%rbp),%rcx
  mov    -0x7c(%rbp),%edx
  lea    -0x70(%rbp),%rsi
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <addtree@plt>
  mov    %rax,-0x78(%rbp)
L26:
  movl   $0x0,-0x80(%rbp)
L14:
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <getword@plt>
  mov    D1(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L58
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <printtree@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  struct tnode *root;
  char word[100];
  int found = 0;
  int num;
  if (--argc && (**argv == '-'))
    num = atoi(*argv + 1);
  else
    num = 6;
  root = NULL;
  while (getword(word, 100) != EOF) {
    if (isalpha(word[0]) && strlen(word) >= num)
      root = addtree(root, word, num, &found);
    found = 0;
  }
  printtree(root);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  mov    $0x6,%ebp
  cmp    $0x1,%edi
  je     L19
  mov    (%rsi),%rax
  cmpb   $0x2d,(%rax)
  je     L35
L19:
  mov    $0x0,%r12d
  lea    0x10(%rsp),%rbx
  jmp    L52
L35:
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  jmp    L19
L41:
  movl   $0x0,0xc(%rsp)
L52:
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <getword@plt>
  mov    D4(%rip),%rdx
  cmp    (%rdx),%rax
  je     L73
  movsbl 0x10(%rsp),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L41
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jl     L41
  lea    0xc(%rsp),%rcx
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <addtree@plt>
  mov    %rax,%r12
  jmp    L41
L73:
  mov    %r12,%rdi
  call   <printtree@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct tnode *root;
  char word[100];
  int found = 0;
  int num;
  if (--argc && (**argv == '-'))
    num = atoi(*argv + 1);
  else
    num = 6;
  root = NULL;
  while (getword(word, 100) != EOF) {
    if (isalpha(word[0]) && strlen(word) >= num)
      root = addtree(root, word, num, &found);
    found = 0;
  }
  printtree(root);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x6,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  cmp    $0x1,%edi
  je     L83
  mov    (%rsi),%rax
  cmpb   $0x2d,(%rax)
  je     L8
L83:
  mov    D0(%rip),%rbp
  xor    %r12d,%r12d
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%r14
  jmp    L79
  nopl   (%rax)
L70:
  movl   $0x0,0xc(%rsp)
L79:
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <getword@plt>
  cmp    0x0(%rbp),%rax
  je     L3
  movsbl 0x10(%rsp),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L70
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jl     L70
  mov    %r12,%rdi
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbx,%rsi
  call   <addtree@plt>
  mov    %rax,%r12
  jmp    L70
  nopl   (%rax)
L3:
  mov    %r12,%rdi
  call   <printtree@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  jmp    L83
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct tnode *root;
  char word[100];
  int found = 0;
  int num;
  if (--argc && (**argv == '-'))
    num = atoi(*argv + 1);
  else
    num = 6;
  root = NULL;
  while (getword(word, 100) != EOF) {
    if (isalpha(word[0]) && strlen(word) >= num)
      root = addtree(root, word, num, &found);
    found = 0;
  }
  printtree(root);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x6,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  cmp    $0x1,%edi
  je     L87
  mov    (%rsi),%rax
  cmpb   $0x2d,(%rax)
  je     L78
L87:
  mov    D6(%rip),%rbp
  xor    %r12d,%r12d
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%r14
  jmp    L76
  nopl   (%rax)
L21:
  movl   $0x0,0xc(%rsp)
L76:
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <getword@plt>
  cmp    0x0(%rbp),%rax
  je     L10
  movsbl 0x10(%rsp),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L21
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jl     L21
  mov    %r12,%rdi
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbx,%rsi
  call   <addtree@plt>
  mov    %rax,%r12
  jmp    L21
  nopl   (%rax)
L10:
  mov    %r12,%rdi
  call   <printtree@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L78:
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  jmp    L87
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct tnode *root;
  char word[100];
  int found = 0;
  int num;
  if (--argc && (**argv == '-'))
    num = atoi(*argv + 1);
  else
    num = 6;
  root = NULL;
  while (getword(word, 100) != EOF) {
    if (isalpha(word[0]) && strlen(word) >= num)
      root = addtree(root, word, num, &found);
    found = 0;
  }
  printtree(root);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str$copy_r_64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x1,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   10b0 <str$$is_string_class@plt>
  cltq
  mov    %rax,-0x18(%rbp)
  cmpq   $0x1,-0x18(%rbp)
  je     124d <str$copy_r_64+0x74>
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  jmp    12d0 <str$copy_r_64+0xf7>
  mov    -0x40(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   1100 <str$$resize@plt>
  cltq
  mov    %rax,-0x18(%rbp)
  cmpq   $0x1,-0x18(%rbp)
  jne    12cc <str$copy_r_64+0xf3>
  lea    -0x20(%rbp),%rdx
  lea    -0x26(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   10e0 <str$analyze_sdesc@plt>
  mov    -0x24(%rbp),%ecx
  movzwl -0x26(%rbp),%eax
  movzwl %ax,%esi
  mov    -0x20(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  mov    $0x20,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   10f0 <str$$copy_fill@plt>
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     12e4 <str$copy_r_64+0x10b>
  call   <__stack_chk_fail@plt>
  leave
  ret
```

assistant: ```c
unsigned long str$copy_r_64(struct dsc$descriptor_s *destination_string, const unsigned short *word_integer_source_length, const void *source_string_address) {
  unsigned short s1_length;
  unsigned long length;
  int s2_length;
  unsigned long result = 1;
  char *s1_ptr;
  s2_length = strlen(source_string_address);
  if ((result = str$$is_string_class(destination_string)) != 1) {
    assert(result && 0);
    return result;
  }
  length = *word_integer_source_length;
  result = str$$resize(destination_string, *word_integer_source_length);
  if (result == 1) {
    str$analyze_sdesc(destination_string, &s1_length, &s1_ptr);
    result = str$$copy_fill(s1_ptr, (unsigned int)s1_length, source_string_address, (unsigned int)s2_length, ' ');
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str$copy_r_64>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   10b0 <str$$is_string_class@plt>
  cmp    $0x1,%eax
  je     1251 <str$copy_r_64+0x78>
  movslq %eax,%r13
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    12a7 <str$copy_r_64+0xce>
  mov    %r13,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  movzwl (%r12),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   1100 <str$$resize@plt>
  movslq %eax,%r13
  cmp    $0x1,%eax
  jne    1231 <str$copy_r_64+0x58>
  lea    0x10(%rsp),%rdx
  lea    0xe(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   10e0 <str$analyze_sdesc@plt>
  movzwl 0xe(%rsp),%esi
  mov    $0x20,%r8d
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  mov    0x10(%rsp),%rdi
  mov    $0x0,%eax
  call   10f0 <str$$copy_fill@plt>
  movslq %eax,%r13
  jmp    1231 <str$copy_r_64+0x58>
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long str$copy_r_64(struct dsc$descriptor_s *destination_string, const unsigned short *word_integer_source_length, const void *source_string_address) {
  unsigned short s1_length;
  unsigned long length;
  int s2_length;
  unsigned long result = 1;
  char *s1_ptr;
  s2_length = strlen(source_string_address);
  if ((result = str$$is_string_class(destination_string)) != 1) {
    assert(result && 0);
    return result;
  }
  length = *word_integer_source_length;
  result = str$$resize(destination_string, *word_integer_source_length);
  if (result == 1) {
    str$analyze_sdesc(destination_string, &s1_length, &s1_ptr);
    result = str$$copy_fill(s1_ptr, (unsigned int)s1_length, source_string_address, (unsigned int)s2_length, ' ');
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str$copy_r_64>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  xor    %eax,%eax
  call   10b0 <str$$is_string_class@plt>
  cmp    $0x1,%eax
  je     1250 <str$copy_r_64+0x70>
  movslq %eax,%r13
  xor    %edi,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    129b <str$copy_r_64+0xbb>
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
  movzwl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   1100 <str$$resize@plt>
  movslq %eax,%r13
  cmp    $0x1,%eax
  jne    122f <str$copy_r_64+0x4f>
  lea    0x10(%rsp),%rdx
  lea    0xe(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   10e0 <str$analyze_sdesc@plt>
  movzwl 0xe(%rsp),%esi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    0x10(%rsp),%rdi
  mov    $0x20,%r8d
  xor    %eax,%eax
  call   10f0 <str$$copy_fill@plt>
  movslq %eax,%r13
  jmp    122f <str$copy_r_64+0x4f>
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long str$copy_r_64(struct dsc$descriptor_s *destination_string, const unsigned short *word_integer_source_length, const void *source_string_address) {
  unsigned short s1_length;
  unsigned long length;
  int s2_length;
  unsigned long result = 1;
  char *s1_ptr;
  s2_length = strlen(source_string_address);
  if ((result = str$$is_string_class(destination_string)) != 1) {
    assert(result && 0);
    return result;
  }
  length = *word_integer_source_length;
  result = str$$resize(destination_string, *word_integer_source_length);
  if (result == 1) {
    str$analyze_sdesc(destination_string, &s1_length, &s1_ptr);
    result = str$$copy_fill(s1_ptr, (unsigned int)s1_length, source_string_address, (unsigned int)s2_length, ' ');
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str$copy_r_64>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  xor    %eax,%eax
  call   10b0 <str$$is_string_class@plt>
  cmp    $0x1,%eax
  je     1250 <str$copy_r_64+0x70>
  movslq %eax,%r13
  xor    %edi,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    129b <str$copy_r_64+0xbb>
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
  movzwl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   1100 <str$$resize@plt>
  movslq %eax,%r13
  cmp    $0x1,%eax
  jne    122f <str$copy_r_64+0x4f>
  lea    0x10(%rsp),%rdx
  lea    0xe(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   10e0 <str$analyze_sdesc@plt>
  movzwl 0xe(%rsp),%esi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    0x10(%rsp),%rdi
  mov    $0x20,%r8d
  xor    %eax,%eax
  call   10f0 <str$$copy_fill@plt>
  movslq %eax,%r13
  jmp    122f <str$copy_r_64+0x4f>
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long str$copy_r_64(struct dsc$descriptor_s *destination_string, const unsigned short *word_integer_source_length, const void *source_string_address) {
  unsigned short s1_length;
  unsigned long length;
  int s2_length;
  unsigned long result = 1;
  char *s1_ptr;
  s2_length = strlen(source_string_address);
  if ((result = str$$is_string_class(destination_string)) != 1) {
    assert(result && 0);
    return result;
  }
  length = *word_integer_source_length;
  result = str$$resize(destination_string, *word_integer_source_length);
  if (result == 1) {
    str$analyze_sdesc(destination_string, &s1_length, &s1_ptr);
    result = str$$copy_fill(s1_ptr, (unsigned int)s1_length, source_string_address, (unsigned int)s2_length, ' ');
  }
  return result;
}
```