ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <ipv4fromstring@plt>
  movzbl -0xc(%rbp),%eax
  cmp    $0xa,%al
  jne    L36
  movzbl -0xb(%rbp),%eax
  test   %al,%al
  jne    L36
  movzbl -0xa(%rbp),%eax
  test   %al,%al
  jne    L36
  movzbl -0x9(%rbp),%eax
  cmp    $0x1,%al
  je     L65
L36:
  mov    $0x0,%eax
  call   <abort@plt>
L65:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <ipv4fromstring@plt>
  movzbl -0xc(%rbp),%eax
  cmp    $0x80,%al
  jne    L16
  movzbl -0xb(%rbp),%eax
  cmp    $0xa,%al
  jne    L16
  movzbl -0xa(%rbp),%eax
  cmp    $0x14,%al
  jne    L16
  movzbl -0x9(%rbp),%eax
  cmp    $0x1f,%al
  je     L61
L16:
  mov    $0x0,%eax
  call   <abort@plt>
L61:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L89
  call   <__stack_chk_fail@plt>
L89:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string

tool: D15: 010.000.000.001

tool: D12: 128.010.020.031

assistant: ```c
int main(void) {
  unsigned char ip[4];
  ipv4fromstring("010.000.000.001", ip);
  do {
    if (!(ip[0] == 10 && ip[1] == 0 && ip[2] == 0 && ip[3] == 1))
      abort();
  } while (0);
  ipv4fromstring("128.010.020.031", ip);
  do {
    if (!(ip[0] == 128 && ip[1] == 10 && ip[2] == 20 && ip[3] == 31))
      abort();
  } while (0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <ipv4fromstring@plt>
  cmpb   $0xa,0x4(%rsp)
  jne    L17
  movzbl 0x5(%rsp),%eax
  or     0x6(%rsp),%al
  jne    L17
  cmpb   $0x1,0x7(%rsp)
  je     L65
L17:
  mov    $0x0,%eax
  call   <abort@plt>
L65:
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <ipv4fromstring@plt>
  cmpb   $0x80,0x4(%rsp)
  jne    L12
  cmpb   $0xa,0x5(%rsp)
  je     L27
L12:
  mov    $0x0,%eax
  call   <abort@plt>
L56:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L27:
  cmpb   $0x14,0x6(%rsp)
  jne    L12
  cmpb   $0x1f,0x7(%rsp)
  jne    L12
  jmp    L56
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string

tool: D7: 010.000.000.001

tool: D15: 128.010.020.031

assistant: ```c
int main(void) {
  unsigned char ip[4];
  ipv4fromstring("010.000.000.001", ip);
  do {
    if (!(ip[0] == 10 && ip[1] == 0 && ip[2] == 0 && ip[3] == 1))
      abort();
  } while (0);
  ipv4fromstring("128.010.020.031", ip);
  do {
    if (!(ip[0] == 128 && ip[1] == 10 && ip[2] == 20 && ip[3] == 31))
      abort();
  } while (0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <ipv4fromstring@plt>
  cmpb   $0xa,0x4(%rsp)
  jne    L8
  movzbl 0x5(%rsp),%eax
  or     0x6(%rsp),%al
  je     L36
L8:
  xor    %eax,%eax
  call   <abort@plt>
L43:
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <ipv4fromstring@plt>
  cmpb   $0x80,0x4(%rsp)
  jne    L47
  cmpb   $0xa,0x5(%rsp)
  je     L75
L47:
  xor    %eax,%eax
  call   <abort@plt>
L77:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L36:
  cmpb   $0x1,0x7(%rsp)
  jne    L8
  jmp    L43
L75:
  cmpb   $0x14,0x6(%rsp)
  jne    L47
  cmpb   $0x1f,0x7(%rsp)
  jne    L47
  jmp    L77
L92:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string

tool: D5: 010.000.000.001

tool: D11: 128.010.020.031

assistant: ```c
int main(void) {
  unsigned char ip[4];
  ipv4fromstring("010.000.000.001", ip);
  do {
    if (!(ip[0] == 10 && ip[1] == 0 && ip[2] == 0 && ip[3] == 1))
      abort();
  } while (0);
  ipv4fromstring("128.010.020.031", ip);
  do {
    if (!(ip[0] == 128 && ip[1] == 10 && ip[2] == 20 && ip[3] == 31))
      abort();
  } while (0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <ipv4fromstring@plt>
  cmpb   $0xa,0x4(%rsp)
  jne    L12
  movzbl 0x5(%rsp),%eax
  or     0x6(%rsp),%al
  je     L50
L12:
  xor    %eax,%eax
  call   <abort@plt>
L78:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <ipv4fromstring@plt>
  cmpb   $0x80,0x4(%rsp)
  jne    L71
  cmpb   $0xa,0x5(%rsp)
  je     L10
L71:
  xor    %eax,%eax
  call   <abort@plt>
L81:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L50:
  cmpb   $0x1,0x7(%rsp)
  jne    L12
  jmp    L78
L10:
  cmpb   $0x14,0x6(%rsp)
  jne    L71
  cmpb   $0x1f,0x7(%rsp)
  jne    L71
  jmp    L81
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string

tool: D10: 010.000.000.001

tool: D6: 128.010.020.031

assistant: ```c
int main(void) {
  unsigned char ip[4];
  ipv4fromstring("010.000.000.001", ip);
  do {
    if (!(ip[0] == 10 && ip[1] == 0 && ip[2] == 0 && ip[3] == 1))
      abort();
  } while (0);
  ipv4fromstring("128.010.020.031", ip);
  do {
    if (!(ip[0] == 128 && ip[1] == 10 && ip[2] == 20 && ip[3] == 31))
      abort();
  } while (0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x8,-0x34(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%ecx
  lea    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <rotate@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L10
L8:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L10:
  mov    -0x3c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: %d 

assistant: ```c
int main(void) {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
  int k = 3;
  int size = sizeof(arr) / sizeof(int);
  rotate(arr, size, k);
  for (int i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  mov    %rsp,%rbx
  mov    $0x3,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <rotate@plt>
  lea    0x20(%rsp),%r12
  lea    D6(%rip),%rbp
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L15
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: %d 

assistant: ```c
int main(void) {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
  int k = 3;
  int size = sizeof(arr) / sizeof(int);
  rotate(arr, size, k);
  for (int i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%edx
  mov    $0x8,%esi
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  call   <rotate@plt>
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: %d 

assistant: ```c
int main(void) {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
  int k = 3;
  int size = sizeof(arr) / sizeof(int);
  rotate(arr, size, k);
  for (int i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%edx
  mov    $0x8,%esi
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D14(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D27(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <rotate@plt>
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L7
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D14
type_guessed: byte[16]
name: parse_data
arguments: label: D27
type_guessed: byte[16]

tool: D17: %d 

tool: {"D14": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D27": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
  int k = 3;
  int size = sizeof(arr) / sizeof(int);
  rotate(arr, size, k);
  for (int i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convertCharToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L21
  cmpb   $0x39,-0x4(%rbp)
  jg     L21
  movzbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L25
L21:
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int32_t convertCharToInt(char ch) {
  if (ch >= '0' && ch <= '9')
    return ch - '0';
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convertCharToInt>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0xa,%al
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
```

assistant: ```c
int32_t convertCharToInt(char ch) {
  if (ch >= '0' && ch <= '9')
    return ch - '0';
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<convertCharToInt>:
  endbr64
  lea    -0x30(%rdi),%eax
  xor    %edx,%edx
  cmp    $0xa,%al
  cmovae %edx,%eax
  ret
```

assistant: ```c
int32_t convertCharToInt(char ch) {
  if (ch >= '0' && ch <= '9')
    return ch - '0';
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convertCharToInt>:
  endbr64
  lea    -0x30(%rdi),%eax
  xor    %edx,%edx
  cmp    $0xa,%al
  cmovae %edx,%eax
  ret
```

assistant: ```c
int32_t convertCharToInt(char ch) {
  if (ch >= '0' && ch <= '9')
    return ch - '0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_triangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D1(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D0(%rip)
  mov    D0(%rip),%edx
  add    %edx,%eax
  mov    %eax,D9(%rip)
  mov    D9(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int next_triangle() {
  static int acc = 0;
  static int n = 1;
  return acc += n++;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<next_triangle>:
  endbr64
  mov    D26(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D12(%rip)
  add    D12(%rip),%eax
  mov    %eax,D18(%rip)
  ret
```

assistant: ```c
int next_triangle() {
  static int acc = 0;
  static int n = 1;
  return acc += n++;
}
```
user: What is the c source code of the assembly code below?

```asm
<next_triangle>:
  endbr64
  mov    D30(%rip),%eax
  lea    0x1(%rax),%edx
  add    D18(%rip),%eax
  mov    %edx,D9(%rip)
  mov    %eax,D9(%rip)
  ret
```

assistant: ```c
int next_triangle() {
  static int acc = 0;
  static int n = 1;
  return acc += n++;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<next_triangle>:
  endbr64
  mov    D4(%rip),%eax
  lea    0x1(%rax),%edx
  add    D36(%rip),%eax
  mov    %edx,D2(%rip)
  mov    %eax,D2(%rip)
  ret
```

assistant: ```c
int next_triangle() {
  static int acc = 0;
  static int n = 1;
  return acc += n++;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <conceito@plt>
  cmp    $0x5,%eax
  ja     L6
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D11(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L6:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D78
data_type: string
name: parse_data
arguments: label: D0
data_type: string
name: parse_data
arguments: label: D74
data_type: string
name: parse_data
arguments: label: D42
data_type: string
name: parse_data
arguments: label: D87
data_type: string
name: parse_data
arguments: label: D57
data_type: string
name: parse_data
arguments: label: D33
data_type: string

tool: D78: Informe a media final do aluno: 

tool: D0: %f

tool: D74: Conceito D


tool: D42: Conceito C


tool: D87: Conceito B


tool: D57: Conceito A


tool: D33: O valor informado esta fora do intervalo![0 a 10]


assistant: ```c
int main() {
  float media;
  printf("Informe a media final do aluno: ");
  scanf("%f", &media);
  switch (conceito(media)) {
  case 1:
    printf("Conceito D\n");
    break;
  case 2:
    printf("Conceito C\n");
    break;
  case 3:
    printf("Conceito B\n");
    break;
  case 4:
    printf("Conceito A\n");
    break;
  case 5:
    printf("O valor informado esta fora do intervalo![0 a 10]\n");
    break;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D71(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  call   <conceito@plt>
  cmp    $0x5,%eax
  ja     L17
  mov    %eax,%eax
  lea    D32(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D45(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D79(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D27
datatype: string
name: parse_data
arguments: data_label: D71
datatype: string
name: parse_data
arguments: data_label: D45
datatype: string
name: parse_data
arguments: data_label: D64
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D43
datatype: string
name: parse_data
arguments: data_label: D79
datatype: string

tool: D27: Informe a media final do aluno: 

tool: D71: %f

tool: D45: Conceito D


tool: D64: Conceito C


tool: D10: Conceito B


tool: D43: Conceito A


tool: D79: O valor informado esta fora do intervalo![0 a 10]


assistant: ```c
int main() {
  float media;
  printf("Informe a media final do aluno: ");
  scanf("%f", &media);
  switch (conceito(media)) {
  case 1:
    printf("Conceito D\n");
    break;
  case 2:
    printf("Conceito C\n");
    break;
  case 3:
    printf("Conceito B\n");
    break;
  case 4:
    printf("Conceito A\n");
    break;
  case 5:
    printf("O valor informado esta fora do intervalo![0 a 10]\n");
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D48(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  call   <conceito@plt>
  cmp    $0x5,%eax
  ja     L17
  lea    D30(%rip),%rdx
  mov    %eax,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D72(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D48
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D72
type_infered: string
name: retrieve_data
arguments: label: D22
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string
name: retrieve_data
arguments: label: D46
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string

tool: D48: Informe a media final do aluno: 

tool: D15: %f

tool: D72: Conceito D


tool: D22: O valor informado esta fora do intervalo![0 a 10]


tool: D29: Conceito C


tool: D46: Conceito B


tool: D6: Conceito A


assistant: ```c
int main() {
  float media;
  printf("Informe a media final do aluno: ");
  scanf("%f", &media);
  switch (conceito(media)) {
  case 1:
    printf("Conceito D\n");
    break;
  case 2:
    printf("Conceito C\n");
    break;
  case 3:
    printf("Conceito B\n");
    break;
  case 4:
    printf("Conceito A\n");
    break;
  case 5:
    printf("O valor informado esta fora do intervalo![0 a 10]\n");
    break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D71(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D72(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  call   <conceito@plt>
  cmp    $0x5,%eax
  ja     L49
  lea    D12(%rip),%rdx
  mov    %eax,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D17(%rip),%rdi
  call   <printf@plt>
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L49
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L49
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L49
  lea    D65(%rip),%rdi
  call   <printf@plt>
  jmp    L49
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D71
type_infered: string
name: disassemble_data
arguments: label: D72
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D30
type_infered: string
name: disassemble_data
arguments: label: D39
type_infered: string
name: disassemble_data
arguments: label: D20
type_infered: string
name: disassemble_data
arguments: label: D65
type_infered: string

tool: D71: Informe a media final do aluno: 

tool: D72: %f

tool: D17: Conceito D


tool: D30: O valor informado esta fora do intervalo![0 a 10]


tool: D39: Conceito C


tool: D20: Conceito B


tool: D65: Conceito A


assistant: ```c
int main() {
  float media;
  printf("Informe a media final do aluno: ");
  scanf("%f", &media);
  switch (conceito(media)) {
  case 1:
    printf("Conceito D\n");
    break;
  case 2:
    printf("Conceito C\n");
    break;
  case 3:
    printf("Conceito B\n");
    break;
  case 4:
    printf("Conceito A\n");
    break;
  case 5:
    printf("O valor informado esta fora do intervalo![0 a 10]\n");
    break;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D13: Enter a value here: 

tool: D15: %d

assistant: ```c
int main() {
  int pass;
  printf("Enter a value here: ");
  scanf("%d", pass);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string
name: disassemble_data
arguments: tag: D15
type: string

tool: D9: Enter a value here: 

tool: D15: %d

assistant: ```c
int main() {
  int pass;
  printf("Enter a value here: ");
  scanf("%d", pass);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type: string
name: disassemble_data
arguments: label: D13
type: string

tool: D15: Enter a value here: 

tool: D13: %d

assistant: ```c
int main() {
  int pass;
  printf("Enter a value here: ");
  scanf("%d", pass);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D2: Enter a value here: 

tool: D1: %d

assistant: ```c
int main() {
  int pass;
  printf("Enter a value here: ");
  scanf("%d", pass);
}
```