ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calcCourseGroundSpeed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  mov    %rdi,-0x48(%rbp)
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  mov    -0x38(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  add    %rbx,%rax
  pxor   %xmm4,%xmm4
  cvtsi2sd %rax,%xmm4
  movsd  %xmm4,-0x50(%rbp)
  movsd  -0x40(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x58(%rbp),%xmm0
  movsd  -0x50(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    -0x48(%rbp),%rdx
  mov    %rax,(%rdx)
  movsd  -0x38(%rbp),%xmm0
  comisd -0x40(%rbp),%xmm0
  jbe    L2
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x40(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm7
  mulsd  -0x50(%rbp),%xmm7
  movq   %xmm7,%rax
  movq   %rax,%xmm0
  call   <asin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L5
L2:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  mulsd  -0x40(%rbp),%xmm2
  movq   %xmm2,%rax
  movsd  -0x50(%rbp),%xmm1
  movq   %rax,%xmm0
  call   <atan2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
L5:
  movsd  -0x28(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <absAngle@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double calcCourseGroundSpeed(const double hd, const double wd, const double tas, const double ws, double *gs) {
  double diffAngle = hd - wd;
  *gs = sqrt(pow(ws, 2) + pow(tas, 2) - 2 * ws * tas * cos(diffAngle));
  double wca;
  if (ws < tas)
    wca = asin((ws / (*gs)) * sin(diffAngle));
  else
    wca = atan2(ws * sin(diffAngle), tas - ws * cos(diffAngle));
  return absAngle(hd + wca);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calcCourseGroundSpeed>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movq   %xmm0,%r14
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  mov    %rdi,%rbx
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  subsd  %xmm1,%xmm0
  call   <sincos@plt>
  mov    0x10(%rsp),%rbp
  mov    0x18(%rsp),%r12
  mov    $0x2,%edi
  movsd  (%rsp),%xmm0
  call   <pow@plt>
  mov    %rax,%r13
  mov    $0x2,%edi
  movsd  0x8(%rsp),%xmm0
  call   <pow@plt>
  add    %rax,%r13
  pxor   %xmm1,%xmm1
  cvtsi2sd %r13,%xmm1
  movsd  (%rsp),%xmm4
  movapd %xmm4,%xmm0
  addsd  %xmm4,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movq   %rbp,%xmm6
  mulsd  %xmm6,%xmm0
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rdi
  call   <sqrt@plt>
  movsd  %xmm0,(%rbx)
  movsd  0x8(%rsp),%xmm5
  movsd  (%rsp),%xmm4
  comisd %xmm4,%xmm5
  jbe    L16
  divsd  %xmm0,%xmm4
  movq   %r12,%xmm0
  mulsd  %xmm4,%xmm0
  call   <asin@plt>
L12:
  movq   %r14,%xmm7
  addsd  %xmm7,%xmm0
  call   <absAngle@plt>
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  movq   %rbp,%xmm1
  movsd  (%rsp),%xmm6
  mulsd  %xmm6,%xmm1
  movq   %r12,%xmm0
  mulsd  %xmm6,%xmm0
  movsd  0x8(%rsp),%xmm7
  subsd  %xmm1,%xmm7
  movapd %xmm7,%xmm1
  call   <atan2@plt>
  jmp    L12
```

assistant: ```c
double calcCourseGroundSpeed(const double hd, const double wd, const double tas, const double ws, double *gs) {
  double diffAngle = hd - wd;
  *gs = sqrt(pow(ws, 2) + pow(tas, 2) - 2 * ws * tas * cos(diffAngle));
  double wca;
  if (ws < tas)
    wca = asin((ws / (*gs)) * sin(diffAngle));
  else
    wca = atan2(ws * sin(diffAngle), tas - ws * cos(diffAngle));
  return absAngle(hd + wca);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calcCourseGroundSpeed>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x48,%rsp
  movsd  %xmm0,0x20(%rsp)
  subsd  %xmm1,%xmm0
  lea    0x30(%rsp),%rsi
  lea    0x38(%rsp),%rdi
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,0x28(%rsp)
  call   <sincos@plt>
  movsd  0x28(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm5
  mov    $0x2,%edi
  movsd  0x38(%rsp),%xmm6
  movapd %xmm3,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x18(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x2,%edi
  mov    %rax,%rbx
  call   <pow@plt>
  movsd  0x28(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  add    %rax,%rbx
  movapd %xmm3,%xmm7
  cvtsi2sd %rbx,%xmm1
  addsd  %xmm3,%xmm7
  mulsd  %xmm7,%xmm0
  mulsd  0x10(%rsp),%xmm0
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rdi
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm3
  movsd  %xmm0,0x0(%rbp)
  comisd %xmm3,%xmm4
  jbe    L11
  divsd  %xmm0,%xmm3
  movsd  0x18(%rsp),%xmm0
  mulsd  %xmm3,%xmm0
  call   <asin@plt>
L6:
  addsd  0x20(%rsp),%xmm0
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  jmp    10b0 <absAngle@plt>
  nopl   0x0(%rax)
L11:
  movsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  0x18(%rsp),%xmm3
  subsd  %xmm0,%xmm1
  movapd %xmm3,%xmm0
  call   <atan2@plt>
  jmp    L6
```

assistant: ```c
double calcCourseGroundSpeed(const double hd, const double wd, const double tas, const double ws, double *gs) {
  double diffAngle = hd - wd;
  *gs = sqrt(pow(ws, 2) + pow(tas, 2) - 2 * ws * tas * cos(diffAngle));
  double wca;
  if (ws < tas)
    wca = asin((ws / (*gs)) * sin(diffAngle));
  else
    wca = atan2(ws * sin(diffAngle), tas - ws * cos(diffAngle));
  return absAngle(hd + wca);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calcCourseGroundSpeed>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x48,%rsp
  movsd  %xmm0,0x20(%rsp)
  subsd  %xmm1,%xmm0
  lea    0x30(%rsp),%rsi
  lea    0x38(%rsp),%rdi
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,0x28(%rsp)
  call   <sincos@plt>
  movsd  0x28(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm5
  mov    $0x2,%edi
  movsd  0x38(%rsp),%xmm6
  movapd %xmm3,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x18(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x2,%edi
  mov    %rax,%rbx
  call   <pow@plt>
  movsd  0x28(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  add    %rax,%rbx
  movapd %xmm3,%xmm7
  cvtsi2sd %rbx,%xmm1
  addsd  %xmm3,%xmm7
  mulsd  %xmm7,%xmm0
  mulsd  0x10(%rsp),%xmm0
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rdi
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm3
  movsd  %xmm0,0x0(%rbp)
  comisd %xmm3,%xmm4
  jbe    L5
  divsd  %xmm0,%xmm3
  movsd  0x18(%rsp),%xmm0
  mulsd  %xmm3,%xmm0
  call   <asin@plt>
L10:
  addsd  0x20(%rsp),%xmm0
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  jmp    10b0 <absAngle@plt>
  nopl   0x0(%rax)
L5:
  movsd  0x10(%rsp),%xmm0
  movapd %xmm4,%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  0x18(%rsp),%xmm3
  subsd  %xmm0,%xmm1
  movapd %xmm3,%xmm0
  call   <atan2@plt>
  jmp    L10
```

assistant: ```c
double calcCourseGroundSpeed(const double hd, const double wd, const double tas, const double ws, double *gs) {
  double diffAngle = hd - wd;
  *gs = sqrt(pow(ws, 2) + pow(tas, 2) - 2 * ws * tas * cos(diffAngle));
  double wca;
  if (ws < tas)
    wca = asin((ws / (*gs)) * sin(diffAngle));
  else
    wca = atan2(ws * sin(diffAngle), tas - ws * cos(diffAngle));
  return absAngle(hd + wca);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L9:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x9c(%rbp)
  lea    -0x9c(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x98(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  lea    D16(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string

tool: D16: %Y-%m-%d %H:%M:%S

tool: D14: %s


assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    time_t t0 = time(NULL);
    struct tm *t = localtime(&t0);
    char buf[128] = {0};
    strftime(buf, sizeof(buf), "%Y-%m-%d %H:%M:%S", t);
    printf("%s\n", buf);
    sleep(60);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x10(%rsp),%rbx
  lea    D6(%rip),%r12
  lea    D0(%rip),%rbp
L6:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0xc(%rsp)
  mov    %r13,%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  mov    %r12,%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D6
type: string
name: read_data
arguments: label: D0
type: string

tool: D6: %Y-%m-%d %H:%M:%S

tool: D0: %s


assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    time_t t0 = time(NULL);
    struct tm *t = localtime(&t0);
    char buf[128] = {0};
    strftime(buf, sizeof(buf), "%Y-%m-%d %H:%M:%S", t);
    printf("%s\n", buf);
    sleep(60);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x10(%rsp),%rbx
  nopl   0x0(%rax)
L5:
  xor    %edi,%edi
  call   <time@plt>
  mov    %r13,%rdi
  mov    %eax,0xc(%rsp)
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    %rax,%rcx
  mov    $0x80,%esi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  call   <strftime@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <printf@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D6: %Y-%m-%d %H:%M:%S

tool: D0: %s


assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    time_t t0 = time(NULL);
    struct tm *t = localtime(&t0);
    char buf[128] = {0};
    strftime(buf, sizeof(buf), "%Y-%m-%d %H:%M:%S", t);
    printf("%s\n", buf);
    sleep(60);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x10(%rsp),%rbx
  nopl   0x0(%rax)
L8:
  xor    %edi,%edi
  call   <time@plt>
  mov    %r13,%rdi
  mov    %eax,0xc(%rsp)
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    %rax,%rcx
  mov    $0x80,%esi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  call   <strftime@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <printf@plt>
  mov    $0x3c,%edi
  call   <sleep@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string
name: disassemble_data
arguments: tag: D14
data_type: string

tool: D9: %Y-%m-%d %H:%M:%S

tool: D14: %s


assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    time_t t0 = time(NULL);
    struct tm *t = localtime(&t0);
    char buf[128] = {0};
    strftime(buf, sizeof(buf), "%Y-%m-%d %H:%M:%S", t);
    printf("%s\n", buf);
    sleep(60);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<svector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x2,%rax
  add    %rax,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <nerror@plt>
L6:
  mov    -0x18(%rbp),%rdx
  mov    $0x1,%eax
  sub    %rdx,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: allocation failure in svector()

assistant: ```c
unsigned short *svector(long nl, long nh) {
  unsigned short *v;
  v = (unsigned short *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned short)));
  if (!v)
    nerror("allocation failure in svector()");
  return v - nl + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<svector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  sub    %rdi,%rsi
  lea    0x4(%rsi,%rsi,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L8:
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    (%rbx,%rax,2),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  lea    D1(%rip),%rdi
  call   <nerror@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: allocation failure in svector()

assistant: ```c
unsigned short *svector(long nl, long nh) {
  unsigned short *v;
  v = (unsigned short *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned short)));
  if (!v)
    nerror("allocation failure in svector()");
  return v - nl + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<svector>:
  endbr64
  push   %rbp
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  push   %rbx
  lea    0x4(%rsi,%rsi,1),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L1:
  mov    $0x1,%eax
  add    $0x8,%rsp
  sub    %rbp,%rax
  lea    (%rbx,%rax,2),%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L17:
  lea    D0(%rip),%rdi
  call   <nerror@plt>
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: allocation failure in svector()

assistant: ```c
unsigned short *svector(long nl, long nh) {
  unsigned short *v;
  v = (unsigned short *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned short)));
  if (!v)
    nerror("allocation failure in svector()");
  return v - nl + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<svector>:
  endbr64
  push   %rbp
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  push   %rbx
  lea    0x4(%rsi,%rsi,1),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
L10:
  mov    $0x1,%eax
  add    $0x8,%rsp
  sub    %rbp,%rax
  lea    (%rbx,%rax,2),%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L12:
  lea    D4(%rip),%rdi
  call   <nerror@plt>
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: allocation failure in svector()

assistant: ```c
unsigned short *svector(long nl, long nh) {
  unsigned short *v;
  v = (unsigned short *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned short)));
  if (!v)
    nerror("allocation failure in svector()");
  return v - nl + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aom_vector_var_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    $0x4,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L8
L11:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L11
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int aom_vector_var_c(const int16_t *ref, const int16_t *src, const int bwl) {
  int i;
  int width = 4 << bwl;
  int sse = 0, mean = 0, var;
  for (i = 0; i < width; ++i) {
    int diff = ref[i] - src[i];
    mean += diff;
    sse += diff * diff;
  }
  var = sse - ((mean * mean) >> (bwl + 2));
  return var;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aom_vector_var_c>:
  endbr64
  mov    %rdi,%r11
  mov    %edx,%ecx
  mov    $0x4,%r10d
  shl    %cl,%r10d
  test   %r10d,%r10d
  jle    L21
  mov    %r10d,%r10d
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  mov    $0x0,%eax
L18:
  mov    (%r11,%r8,4),%edi
  sub    (%rsi,%r8,4),%edi
  add    %edi,%r9d
  imul   %edi,%edi
  add    %edi,%eax
  add    $0x1,%r8
  cmp    %r10,%r8
  jne    L18
L19:
  imul   %r9d,%r9d
  add    $0x2,%ecx
  sar    %cl,%r9d
  sub    %r9d,%eax
  ret
L21:
  mov    $0x0,%r9d
  mov    $0x0,%eax
  jmp    L19
```

assistant: ```c
int aom_vector_var_c(const int16_t *ref, const int16_t *src, const int bwl) {
  int i;
  int width = 4 << bwl;
  int sse = 0, mean = 0, var;
  for (i = 0; i < width; ++i) {
    int diff = ref[i] - src[i];
    mean += diff;
    sse += diff * diff;
  }
  var = sse - ((mean * mean) >> (bwl + 2));
  return var;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aom_vector_var_c>:
  endbr64
  mov    %edx,%ecx
  mov    $0x4,%r9d
  mov    %rdi,%r10
  mov    %rsi,%r11
  shl    %cl,%r9d
  add    $0x2,%ecx
  test   %r9d,%r9d
  jle    L7
  movslq %r9d,%r9
  xor    %edi,%edi
  xor    %r8d,%r8d
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%r10,%rdi,4),%esi
  sub    (%r11,%rdi,4),%esi
  add    $0x1,%rdi
  add    %esi,%r8d
  imul   %esi,%esi
  add    %esi,%eax
  cmp    %rdi,%r9
  jne    L5
  imul   %r8d,%r8d
  sar    %cl,%r8d
  sub    %r8d,%eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int aom_vector_var_c(const int16_t *ref, const int16_t *src, const int bwl) {
  int i;
  int width = 4 << bwl;
  int sse = 0, mean = 0, var;
  for (i = 0; i < width; ++i) {
    int diff = ref[i] - src[i];
    mean += diff;
    sse += diff * diff;
  }
  var = sse - ((mean * mean) >> (bwl + 2));
  return var;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aom_vector_var_c>:
  endbr64
  mov    %edx,%ecx
  mov    $0x4,%r8d
  shl    %cl,%r8d
  add    $0x2,%ecx
  test   %r8d,%r8d
  jle    L41
  lea    -0x1(%r8),%eax
  cmp    $0x2,%eax
  jbe    L44
  mov    %r8d,%edx
  pxor   %xmm2,%xmm2
  xor    %eax,%eax
  shr    $0x2,%edx
  movdqa %xmm2,%xmm3
  shl    $0x4,%rdx
  nopl   0x0(%rax)
L52:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm4
  add    $0x10,%rax
  psubd  %xmm4,%xmm0
  movdqa %xmm0,%xmm1
  paddd  %xmm0,%xmm2
  pmuludq %xmm0,%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  paddd  %xmm1,%xmm3
  cmp    %rdx,%rax
  jne    L52
  movdqa %xmm3,%xmm0
  mov    %r8d,%r10d
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%r10d
  paddd  %xmm0,%xmm3
  movdqa %xmm3,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm3
  movdqa %xmm2,%xmm0
  psrldq $0x8,%xmm0
  movd   %xmm3,%eax
  paddd  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movd   %xmm2,%edx
  test   $0x3,%r8b
  je     L30
L32:
  push   %rbx
  movslq %r10d,%rbx
  mov    (%rdi,%rbx,4),%r9d
  sub    (%rsi,%rbx,4),%r9d
  lea    0x0(,%rbx,4),%r11
  add    %r9d,%edx
  imul   %r9d,%r9d
  add    %r9d,%eax
  lea    0x1(%r10),%r9d
  cmp    %r9d,%r8d
  jle    L60
  mov    0x4(%rdi,%r11,1),%r9d
  sub    0x4(%rsi,%r11,1),%r9d
  add    $0x2,%r10d
  add    %r9d,%edx
  imul   %r9d,%r9d
  add    %r9d,%eax
  cmp    %r10d,%r8d
  jle    L60
  mov    0x8(%rdi,%r11,1),%edi
  sub    0x8(%rsi,%r11,1),%edi
  mov    %edi,%esi
  add    %edi,%edx
  imul   %edi,%esi
  add    %esi,%eax
L60:
  imul   %edx,%edx
  pop    %rbx
  sar    %cl,%edx
  sub    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  imul   %edx,%edx
  sar    %cl,%edx
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  xor    %eax,%eax
  ret
L44:
  xor    %edx,%edx
  xor    %eax,%eax
  xor    %r10d,%r10d
  jmp    L32
```

assistant: ```c
int aom_vector_var_c(const int16_t *ref, const int16_t *src, const int bwl) {
  int i;
  int width = 4 << bwl;
  int sse = 0, mean = 0, var;
  for (i = 0; i < width; ++i) {
    int diff = ref[i] - src[i];
    mean += diff;
    sse += diff * diff;
  }
  var = sse - ((mean * mean) >> (bwl + 2));
  return var;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<palindrome4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L5
L12:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    -0x74(%rbp),%edx
  add    %edx,%edx
  sub    -0x78(%rbp),%edx
  lea    -0x1(%rdx),%ecx
  movzbl (%rax),%edx
  movslq %ecx,%rax
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x78(%rbp)
L5:
  mov    -0x78(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L12
  mov    -0x74(%rbp),%eax
  add    %eax,%eax
  cltq
  movb   $0x0,-0x70(%rbp,%rax,1)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
char *palindrome4(char *s) {
  int n = strlen(s);
  char dest[100];
  for (int i = 0; i < n; i++) {
    dest[i] = s[i];
    dest[2 * n - i - 1] = s[i];
  }
  dest[2 * n] = 0;
  return strdup(dest);
}
```