user: 下面的汇编指令对应的C源代码是什么:

```asm
<solve>:
  endbr64
  push   %r15
  mov    %edx,%eax
  push   %r14
  mov    %rdi,%r14
  lea    0x0(,%rax,4),%edi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    %ecx,0x18(%rsp)
  mov    %eax,0x1c(%rsp)
  call   <malloc@plt>
  mov    %rax,%r15
  mov    0xc(%rsp),%eax
  mov    %eax,0x20(%rsp)
  imul   %eax,%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    0xc(%rsp),%edi
  mov    %rax,%r12
  imul   %r13d,%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    0xc(%rsp),%r8d
  mov    %rax,%rbp
  test   %r8d,%r8d
  jle    L108
  lea    -0x1(%r8),%r11d
  movslq %r8d,%rcx
  mov    $0xfffffffffffffff8,%r9
  xor    %edi,%edi
  shl    $0x3,%r11
  mov    %r12,%r10
  shl    $0x3,%rcx
  lea    0x8(%r14,%r11,1),%rsi
  sub    %r11,%r9
  cs nopw 0x0(%rax,%rax,1)
L110:
  lea    (%r9,%rsi,1),%rax
  mov    %r10,%rdx
  nopw   0x0(%rax,%rax,1)
L9:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  %xmm0,(%rdx)
  add    %rcx,%rdx
  cmp    %rsi,%rax
  jne    L9
  add    $0x1,%edi
  add    $0x8,%r10
  lea    (%rax,%rcx,1),%rsi
  cmp    %edi,%r8d
  jne    L110
  cmp    $0x1,%r13d
  jle    L22
  mov    %rbp,%r10
  lea    0x8(%rbx,%r11,1),%rsi
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L8:
  lea    (%rsi,%r9,1),%rax
  mov    %r10,%rdx
  nopw   0x0(%rax,%rax,1)
L34:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  %xmm0,(%rdx)
  add    %rcx,%rdx
  cmp    %rsi,%rax
  jne    L34
  add    $0x1,%edi
  add    $0x8,%r10
  add    %rcx,%rsi
  cmp    %edi,%r8d
  jne    L8
L62:
  lea    0x24(%rsp),%rax
  lea    0x1c(%rsp),%rcx
  mov    %r15,%r8
  mov    %rbp,%r9
  lea    0x18(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  push   %rax
  mov    %r12,%rdx
  lea    0x28(%rsp),%rax
  push   %rax
  call   <dgesv_@plt>
  mov    0x1c(%rsp),%r8d
  pop    %rsi
  pop    %rdi
  test   %r8d,%r8d
  jle    L4
  lea    -0x1(%r8),%eax
  movslq %r8d,%rsi
  mov    $0xfffffffffffffff8,%r9
  xor    %edi,%edi
  shl    $0x3,%rax
  shl    $0x3,%rsi
  lea    0x8(%rbp,%rax,1),%rcx
  sub    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L70:
  lea    (%r9,%rcx,1),%rax
  mov    %rbx,%rdx
  nopw   0x0(%rax,%rax,1)
L122:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  %xmm0,(%rdx)
  add    %rsi,%rdx
  cmp    %rcx,%rax
  jne    L122
  add    $0x1,%edi
  add    $0x8,%rbx
  add    %rsi,%rcx
  cmp    %r8d,%edi
  jne    L70
L4:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    %rbx,%rdx
  lea    0x8(%rbp,%r11,1),%rcx
  mov    %rbp,%rax
  sub    %rbp,%rdx
  nopl   0x0(%rax)
L24:
  movsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L24
L131:
  lea    0x24(%rsp),%rax
  lea    0x1c(%rsp),%rcx
  mov    %r12,%rdx
  mov    %rbp,%r9
  lea    0x18(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  push   %rax
  mov    %r15,%r8
  lea    0x28(%rsp),%rax
  push   %rax
  call   <dgesv_@plt>
  mov    0x1c(%rsp),%eax
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  jle    L4
  lea    0x0(%rbp,%rax,8),%rdx
  sub    %rbp,%rbx
  mov    %rbp,%rax
  nopl   (%rax)
L14:
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rbx,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L14
  jmp    L4
L108:
  cmp    $0x1,%r13d
  jg     L62
  jmp    L131
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void solve(double *A, double *B, int nA, int nRHS) {
  int N = nA;
  int NRHS = nRHS;
  int LDA = nA;
  int *IPIV = (int *)malloc(sizeof(int) * nA);
  int LDB = nA;
  int INFO;
  double *AT = (double *)malloc(sizeof(double) * nA * nA);
  double *BT = (double *)malloc(sizeof(double) * nA * nRHS);
  int i, j;
  for (i = 0; i < nA; i++) {
    for (j = 0; j < nA; j++) {
      AT[i + nA * j] = A[j + nA * i];
    }
  }
  if (nRHS > 1) {
    for (i = 0; i < nA; i++) {
      for (j = 0; j < nA; j++) {
        BT[i + nA * j] = B[j + nA * i];
      }
    }
  } else {
    for (i = 0; i < nA; i++)
      BT[i] = B[i];
  }
  dgesv_(&nA, &NRHS, AT, &LDA, IPIV, BT, &LDB, &INFO);
  if (nRHS > 1) {
    for (i = 0; i < nA; i++) {
      for (j = 0; j < nA; j++) {
        B[i + nA * j] = BT[j + nA * i];
      }
    }
  } else {
    for (i = 0; i < nA; i++)
      B[i] = BT[i];
  }
  free(AT);
  free(BT);
  return;
}
```