ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<isInOrigString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rdi,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r15d
  mov    %eax,0x8(%rsp)
  call   <strlen@plt>
  mov    %r15d,%esi
  lea    D13(%rip),%rdi
  mov    %eax,%ebx
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D20(%rip),%rdi
  sub    %r15d,%ebx
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D10(%rip),%rdi
  mov    %ebx,0xc(%rsp)
  call   <printf@plt>
  test   %ebx,%ebx
  js     L17
  lea    -0x1(%r15),%eax
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  lea    0x1(%rbp,%rax,1),%rbp
  nopl   (%rax)
L56:
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L53
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%r13
  lea    D18(%rip),%rbx
  lea    (%rax,%r12,1),%r15
  nopl   0x0(%rax)
L41:
  movzbl (%r15),%eax
  cmp    %al,0x0(%r13)
  je     L68
  xor    %esi,%esi
  mov    %rbx,%rdi
  add    $0x1,%r13
  add    $0x1,%r15
  call   <printf@plt>
  xor    %r14d,%r14d
  cmp    %rbp,%r13
  jne    L41
L9:
  add    $0x1,%r12
  cmp    %r12d,0xc(%rsp)
  jge    L56
L17:
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  add    $0x1,%r14d
  mov    %rbx,%rdi
  add    $0x1,%r13
  add    $0x1,%r15
  mov    %r14d,%esi
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L41
L53:
  cmp    %r14d,0x8(%rsp)
  jne    L9
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D10
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D13: replaceLength = %d 


tool: D20: origLength = %d 


tool: D10: difference = %d 


tool: D6: offset = %d 


tool: D18: index = %d 


assistant: ```c
bool isInOrigString(char replace[], char stringOrig[]) {
  bool isContained = false;
  int replaceLength = strlen(replace);
  int origLength = strlen(stringOrig);
  int offset = 0;
  int index = 0;
  printf("replaceLength = %d \n", replaceLength);
  printf("origLength = %d \n", origLength);
  printf("difference = %d \n", origLength - replaceLength);
  while (offset <= (origLength - replaceLength)) {
    printf("offset = %d \n", offset);
    for (int i = 0; i < replaceLength; i++) {
      if (replace[i] == stringOrig[i + offset]) {
        index++;
      } else {
        index = 0;
      }
      printf("index = %d \n", index);
    }
    if (replaceLength == index) {
      isContained = true;
      return isContained;
    }
    offset++;
  }
  return isContained;
}
```
user: What is the c source code of the assembly code below?

```asm
<udelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,-0x8(%rbp)
  nop
L9:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void udelay(unsigned long usec) {
  unsigned long count = 0;
  unsigned long utime = 200000000 / 1000000 * usec;
  while (++count < utime)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<udelay>:
  endbr64
  lea    (%rdi,%rdi,4),%rax
  lea    (%rax,%rax,4),%rdx
  shl    $0x3,%rdx
  mov    $0x0,%eax
L5:
  add    $0x1,%rax
  cmp    %rax,%rdx
  ja     L5
  ret
```

assistant: ```c
void udelay(unsigned long usec) {
  unsigned long count = 0;
  unsigned long utime = 200000000 / 1000000 * usec;
  while (++count < utime)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<udelay>:
  endbr64
  ret
```

assistant: ```c
void udelay(unsigned long usec) {
  unsigned long count = 0;
  unsigned long utime = 200000000 / 1000000 * usec;
  while (++count < utime)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<udelay>:
  endbr64
  ret
```

assistant: ```c
void udelay(unsigned long usec) {
  unsigned long count = 0;
  unsigned long utime = 200000000 / 1000000 * usec;
  while (++count < utime)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L71
  mov    $0x0,%eax
  jmp    L2
L71:
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L62
L53:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L12
  cmpl   $0x0,-0x1c(%rbp)
  jne    L13
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  sub    %edx,%eax
  jmp    L36
L13:
  mov    -0x1c(%rbp),%eax
L36:
  mov    %eax,-0x1c(%rbp)
  jmp    L29
L12:
  addl   $0x1,-0x20(%rbp)
L29:
  addq   $0x1,-0x18(%rbp)
L62:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L53
  mov    -0x20(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <instrumentUpdateCmpMap@plt>
  mov    -0x1c(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
int _memcmp(const void *m1, const void *m2, size_t n, void *addr) {
  if (n == 0) {
    return 0;
  }
  unsigned int v = 0;
  int ret = 0;
  const unsigned char *s1 = (const unsigned char *)m1;
  const unsigned char *s2 = (const unsigned char *)m2;
  for (size_t i = 0; i < n; i++) {
    if (s1[i] != s2[i]) {
      ret = ret ? ret : (s1[i] - s2[i]);
    } else {
      v++;
    }
  }
  instrumentUpdateCmpMap(addr, v);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_memcmp>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  test   %rdx,%rdx
  je     L45
  mov    %rdi,%r10
  mov    $0x0,%eax
  mov    $0x0,%r11d
  jmp    L13
L4:
  add    $0x1,%r11d
L29:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L54
L13:
  movzbl (%r10,%rax,1),%r9d
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%r9b
  je     L4
  test   %ebx,%ebx
  jne    L29
  movzbl %r9b,%r9d
  movzbl %r8b,%r8d
  mov    %r9d,%ebx
  sub    %r8d,%ebx
  jmp    L29
L54:
  mov    %r11d,%esi
  mov    %rcx,%rdi
  call   <instrumentUpdateCmpMap@plt>
L45:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int _memcmp(const void *m1, const void *m2, size_t n, void *addr) {
  if (n == 0) {
    return 0;
  }
  unsigned int v = 0;
  int ret = 0;
  const unsigned char *s1 = (const unsigned char *)m1;
  const unsigned char *s2 = (const unsigned char *)m2;
  for (size_t i = 0; i < n; i++) {
    if (s1[i] != s2[i]) {
      ret = ret ? ret : (s1[i] - s2[i]);
    } else {
      v++;
    }
  }
  instrumentUpdateCmpMap(addr, v);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_memcmp>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %rdx,%rdx
  je     L31
  mov    %rdi,%r10
  xor    %eax,%eax
  mov    %rcx,%rdi
  xor    %r11d,%r11d
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L1:
  test   %r12d,%r12d
  jne    L26
  movzbl %r9b,%r12d
  sub    %r8d,%r12d
L26:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L14
L39:
  movzbl (%r10,%rax,1),%r9d
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%r9b
  jne    L1
  add    $0x1,%rax
  add    $0x1,%r11d
  cmp    %rax,%rdx
  jne    L39
L14:
  mov    %r11d,%esi
  call   <instrumentUpdateCmpMap@plt>
L31:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int _memcmp(const void *m1, const void *m2, size_t n, void *addr) {
  if (n == 0) {
    return 0;
  }
  unsigned int v = 0;
  int ret = 0;
  const unsigned char *s1 = (const unsigned char *)m1;
  const unsigned char *s2 = (const unsigned char *)m2;
  for (size_t i = 0; i < n; i++) {
    if (s1[i] != s2[i]) {
      ret = ret ? ret : (s1[i] - s2[i]);
    } else {
      v++;
    }
  }
  instrumentUpdateCmpMap(addr, v);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_memcmp>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %rdx,%rdx
  je     L18
  mov    %rdi,%r10
  xor    %eax,%eax
  mov    %rcx,%rdi
  xor    %r11d,%r11d
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L38:
  test   %r12d,%r12d
  jne    L40
  movzbl %r9b,%r12d
  sub    %r8d,%r12d
L40:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L44
L5:
  movzbl (%r10,%rax,1),%r9d
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%r9b
  jne    L38
  add    $0x1,%rax
  add    $0x1,%r11d
  cmp    %rax,%rdx
  jne    L5
L44:
  mov    %r11d,%esi
  call   <instrumentUpdateCmpMap@plt>
L18:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int _memcmp(const void *m1, const void *m2, size_t n, void *addr) {
  if (n == 0) {
    return 0;
  }
  unsigned int v = 0;
  int ret = 0;
  const unsigned char *s1 = (const unsigned char *)m1;
  const unsigned char *s2 = (const unsigned char *)m2;
  for (size_t i = 0; i < n; i++) {
    if (s1[i] != s2[i]) {
      ret = ret ? ret : (s1[i] - s2[i]);
    } else {
      v++;
    }
  }
  instrumentUpdateCmpMap(addr, v);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RSA_padding_add_PKCS1_type_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0xa,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L39
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L22
L39:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2,(%rax)
  mov    -0x1c(%rbp),%eax
  sub    $0x3,%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <arc4random_buf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L12:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <arc4random_buf@plt>
L49:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L49
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x1,%eax
L22:
  leave
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_2(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > tlen - 11) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_2, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return 0;
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - flen;
  arc4random_buf(p, j);
  for (i = 0; i < j; i++) {
    while (*p == '\0')
      arc4random_buf(p, 1);
    p++;
  }
  *(p++) = '\0';
  memcpy(p, from, flen);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RSA_padding_add_PKCS1_type_2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0xa(%rsi),%eax
  cmp    %ecx,%eax
  jle    L76
  mov    %rdi,%rbx
  mov    %rdx,%r15
  mov    %ecx,%r14d
  movb   $0x0,(%rdi)
  lea    0x2(%rdi),%r13
  movb   $0x2,0x1(%rdi)
  lea    -0x3(%rsi),%ebp
  sub    %ecx,%ebp
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <arc4random_buf@plt>
  test   %ebp,%ebp
  jle    L5
  lea    -0x1(%rbp),%eax
  lea    0x3(%rbx,%rax,1),%r12
  mov    %r13,%rbx
  jmp    L35
L76:
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L51
L39:
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <arc4random_buf@plt>
  cmpb   $0x0,(%rbx)
  je     L39
L37:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L73
L35:
  cmpb   $0x0,(%rbx)
  je     L39
  jmp    L37
L73:
  mov    %ebp,%ebp
  add    %rbp,%r13
L5:
  movb   $0x0,0x0(%r13)
  lea    0x1(%r13),%rdi
  mov    %r14d,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  mov    $0x1,%eax
L51:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_2(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > tlen - 11) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_2, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return 0;
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - flen;
  arc4random_buf(p, j);
  for (i = 0; i < j; i++) {
    while (*p == '\0')
      arc4random_buf(p, 1);
    p++;
  }
  *(p++) = '\0';
  memcpy(p, from, flen);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<RSA_padding_add_PKCS1_type_2>:
  endbr64
  push   %r15
  lea    -0xa(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%eax
  jle    L17
  mov    $0x200,%eax
  lea    -0x3(%rsi),%ebp
  lea    0x2(%rdi),%r13
  mov    %rdi,%rbx
  mov    %ax,(%rdi)
  sub    %ecx,%ebp
  mov    %r13,%rdi
  mov    %rdx,%r15
  mov    %ebp,%esi
  mov    %ecx,%r14d
  call   <arc4random_buf@plt>
  test   %ebp,%ebp
  jle    L6
  lea    -0x1(%rbp),%eax
  lea    0x3(%rbx,%rax,1),%r12
  mov    %r13,%rbx
  jmp    L4
  xchg   %ax,%ax
L46:
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <arc4random_buf@plt>
L4:
  cmpb   $0x0,(%rbx)
  je     L46
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L4
  add    %rbp,%r13
L6:
  movb   $0x0,0x0(%r13)
  lea    0x1(%r13),%rdi
  mov    %r14d,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_2(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > tlen - 11) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_2, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return 0;
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - flen;
  arc4random_buf(p, j);
  for (i = 0; i < j; i++) {
    while (*p == '\0')
      arc4random_buf(p, 1);
    p++;
  }
  *(p++) = '\0';
  memcpy(p, from, flen);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RSA_padding_add_PKCS1_type_2>:
  endbr64
  push   %r15
  lea    -0xa(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%eax
  jle    L13
  mov    $0x200,%eax
  lea    -0x3(%rsi),%ebp
  lea    0x2(%rdi),%r13
  mov    %rdi,%rbx
  mov    %ax,(%rdi)
  sub    %ecx,%ebp
  mov    %r13,%rdi
  mov    %rdx,%r15
  mov    %ebp,%esi
  mov    %ecx,%r14d
  call   <arc4random_buf@plt>
  test   %ebp,%ebp
  jle    L35
  lea    -0x1(%rbp),%eax
  lea    0x3(%rbx,%rax,1),%r12
  mov    %r13,%rbx
  jmp    L41
  xchg   %ax,%ax
L43:
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <arc4random_buf@plt>
L41:
  cmpb   $0x0,(%rbx)
  je     L43
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L41
  add    %rbp,%r13
L35:
  movb   $0x0,0x0(%r13)
  lea    0x1(%r13),%rdi
  mov    %r14d,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int RSA_padding_add_PKCS1_type_2(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > tlen - 11) {
    RSAerr(RSA_F_RSA_PADDING_ADD_PKCS1_TYPE_2, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return 0;
  }
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - flen;
  arc4random_buf(p, j);
  for (i = 0; i < j; i++) {
    while (*p == '\0')
      arc4random_buf(p, 1);
    p++;
  }
  *(p++) = '\0';
  memcpy(p, from, flen);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<indents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L19:
  mov    -0x20(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  mov    -0x20(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: %s    

assistant: ```c
char *indents(int Num, char *OutStr) {
  int i;
  OutStr[0] = '\0';
  for (i = 0; i < Num; i++) {
    sprintf(OutStr, "%s    ", OutStr);
  }
  return (OutStr);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<indents>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  movb   $0x0,(%rsi)
  test   %edi,%edi
  jle    L14
  mov    %edi,%r12d
  mov    $0x0,%ebx
  lea    D2(%rip),%r13
L8:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L8
L14:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: %s    

assistant: ```c
char *indents(int Num, char *OutStr) {
  int i;
  OutStr[0] = '\0';
  for (i = 0; i < Num; i++) {
    sprintf(OutStr, "%s    ", OutStr);
  }
  return (OutStr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<indents>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movb   $0x0,(%rsi)
  test   %edi,%edi
  jle    L1
  mov    %edi,%ebp
  xor    %ebx,%ebx
  lea    D7(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <sprintf@plt>
  cmp    %ebx,%ebp
  jne    L11
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string

tool: D7: %s    

assistant: ```c
char *indents(int Num, char *OutStr) {
  int i;
  OutStr[0] = '\0';
  for (i = 0; i < Num; i++) {
    sprintf(OutStr, "%s    ", OutStr);
  }
  return (OutStr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<indents>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movb   $0x0,(%rsi)
  test   %edi,%edi
  jle    L13
  mov    %edi,%ebp
  xor    %ebx,%ebx
  lea    D0(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <sprintf@plt>
  cmp    %ebx,%ebp
  jne    L19
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: %s    

assistant: ```c
char *indents(int Num, char *OutStr) {
  int i;
  OutStr[0] = '\0';
  for (i = 0; i < Num; i++) {
    sprintf(OutStr, "%s    ", OutStr);
  }
  return (OutStr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InitUBlox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0xffff0024240662b5,%rax
  movabs $0x2710000000000306,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0xfa00fa00050000,%rax
  mov    $0x12c0064,%edx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0xdc160000,-0x18(%rbp)
  lea    -0x40(%rbp),%rcx
  mov    -0x44(%rbp),%eax
  mov    $0x2c,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <SendUBX@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void InitUBlox(int fd) {
  unsigned char setNav[] = {0xB5, 0x62, 0x06, 0x24, 0x24, 0x00, 0xFF, 0xFF, 0x06, 0x03, 0x00, 0x00, 0x00, 0x00, 0x10, 0x27, 0x00, 0x00, 0x05, 0x00, 0xFA, 0x00, 0xFA, 0x00, 0x64, 0x00, 0x2C, 0x01, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x16, 0xDC};
  SendUBX(fd, setNav, sizeof(setNav));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<InitUBlox>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0xffff0024240662b5,%rax
  movabs $0x2710000000000306,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0xfa00fa00050000,%rax
  mov    $0x12c0064,%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0xdc160000,0x28(%rsp)
  mov    %rsp,%rsi
  mov    $0x2c,%edx
  call   <SendUBX@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void InitUBlox(int fd) {
  unsigned char setNav[] = {0xB5, 0x62, 0x06, 0x24, 0x24, 0x00, 0xFF, 0xFF, 0x06, 0x03, 0x00, 0x00, 0x00, 0x00, 0x10, 0x27, 0x00, 0x00, 0x05, 0x00, 0xFA, 0x00, 0xFA, 0x00, 0x64, 0x00, 0x2C, 0x01, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x16, 0xDC};
  SendUBX(fd, setNav, sizeof(setNav));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<InitUBlox>:
  endbr64
  sub    $0x48,%rsp
  movdqa D0(%rip),%xmm0
  mov    $0x2c,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0xdc160000,0x28(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D19(%rip),%xmm0
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <SendUBX@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x48,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: byte[16]
name: retrieve_data
arguments: tag: D19
data_type: byte[16]

tool: {"D0": [0xb5,0x62,0x06,0x24,0x24,0x00,0xff,0xff,0x06,0x03,0x00,0x00,0x00,0x00,0x10,0x27]}

tool: {"D19": [0x00,0x00,0x05,0x00,0xfa,0x00,0xfa,0x00,0x64,0x00,0x2c,0x01,0x00,0x00,0x00,0x00]}

assistant: ```c
void InitUBlox(int fd) {
  unsigned char setNav[] = {0xB5, 0x62, 0x06, 0x24, 0x24, 0x00, 0xFF, 0xFF, 0x06, 0x03, 0x00, 0x00, 0x00, 0x00, 0x10, 0x27, 0x00, 0x00, 0x05, 0x00, 0xFA, 0x00, 0xFA, 0x00, 0x64, 0x00, 0x2C, 0x01, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x16, 0xDC};
  SendUBX(fd, setNav, sizeof(setNav));
}
```