ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Q_CleanStr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L56
  mov    %rdi,%rsi
  mov    %rdi,%r9
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L37:
  movsbl %dl,%r8d
  mov    %rsi,%rcx
  sub    $0x20,%r8d
  cmp    $0x5e,%r8d
  jbe    L54
L21:
  movzbl 0x1(%rcx),%edx
  lea    0x1(%rcx),%rsi
  test   %dl,%dl
  je     L3
L38:
  cmp    $0x5e,%dl
  jne    L37
  movzbl 0x1(%rsi),%ecx
  cmp    $0x5e,%cl
  je     L54
  test   %cl,%cl
  je     L54
  movzbl 0x2(%rsi),%edx
  lea    0x1(%rsi),%rcx
  lea    0x1(%rcx),%rsi
  test   %dl,%dl
  jne    L38
L3:
  movb   $0x0,(%r9)
  ret
  nopl   0x0(%rax)
L54:
  mov    %dl,(%r9)
  mov    %rsi,%rcx
  add    $0x1,%r9
  jmp    L21
  nopl   0x0(%rax)
L56:
  mov    %rdi,%r9
  movb   $0x0,(%r9)
  ret
```

assistant: ```c
char *Q_CleanStr(char *string) {
  char *d = string;
  char *s = string;
  int c;
  while ((c = *s) != 0) {
    if ((s && *(s) == '^' && *((s) + 1) && *((s) + 1) != '^')) {
      s++;
    } else if (c >= 0x20 && c <= 0x7E) {
      *d++ = c;
    }
    s++;
  }
  *d = '\0';
  return string;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mmul5>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x20(%rsp)
  mov    %rsi,-0x18(%rsp)
  mov    %rdx,-0x10(%rsp)
  mov    %ecx,-0x24(%rsp)
  mov    %r8d,-0x28(%rsp)
  test   %ecx,%ecx
  jle    L28
  lea    0x0(,%r8,4),%r9d
  movslq %r9d,%r9
  shl    $0x2,%r9
  lea    -0x1(%r8),%r12d
  mov    %r12d,%eax
  shr    $0x2,%eax
  movslq %r8d,%rdi
  lea    (%rdi,%rdi,2),%r10
  shl    $0x2,%r10
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    %r12d,%r12d
  add    $0x1,%eax
  mov    %eax,%eax
  shl    $0x4,%rax
  mov    %rax,-0x8(%rsp)
  jmp    L0
L4:
  add    $0x1,%r13d
  add    -0x28(%rsp),%r14d
  cmp    %r13d,-0x24(%rsp)
  je     L28
L0:
  cmpl   $0x0,-0x28(%rsp)
  jle    L4
  movslq %r14d,%rbp
  shl    $0x2,%rbp
  mov    -0x18(%rsp),%r11
  mov    -0x10(%rsp),%rax
  lea    (%rax,%rbp,1),%rsi
  add    -0x20(%rsp),%rbp
  mov    -0x8(%rsp),%rax
  lea    (%rax,%rbp,1),%r8
  mov    $0x0,%ebx
L62:
  mov    %r11,%r15
  mov    %rbp,%rax
L58:
  mov    (%rax),%edx
  imul   (%r15),%edx
  add    (%rsi),%edx
  mov    %edx,(%rsi)
  mov    0x4(%rax),%ecx
  imul   (%r15,%rdi,4),%ecx
  add    %edx,%ecx
  mov    %ecx,(%rsi)
  mov    0x8(%rax),%edx
  imul   (%r15,%rdi,8),%edx
  add    %ecx,%edx
  mov    %edx,(%rsi)
  mov    0xc(%rax),%ecx
  imul   (%r15,%r10,1),%ecx
  add    %ecx,%edx
  mov    %edx,(%rsi)
  add    $0x10,%rax
  add    %r9,%r15
  cmp    %r8,%rax
  jne    L58
  lea    0x1(%rbx),%rax
  add    $0x4,%r11
  add    $0x4,%rsi
  cmp    %r12,%rbx
  je     L4
  mov    %rax,%rbx
  jmp    L62
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mmul5(int *a, int *b, int *res, int h, int w) {
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < w; j++) {
      for (int k = 0; k < w; k += 4) {
        int *line = (a + i * w);
        int *res_pos = &(res + i * w)[j];
        *res_pos += (line)[k] * (b + k * w)[j];
        *res_pos += (line)[k + 1] * (b + (k + 1) * w)[j];
        *res_pos += (line)[k + 2] * (b + (k + 2) * w)[j];
        *res_pos += (line)[k + 3] * (b + (k + 3) * w)[j];
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mmul5>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x20(%rsp)
  mov    %rsi,-0x18(%rsp)
  mov    %rdx,-0x10(%rsp)
  mov    %ecx,-0x24(%rsp)
  mov    %r8d,-0x28(%rsp)
  test   %ecx,%ecx
  jle    L34
  lea    -0x1(%r8),%r12d
  movslq %r8d,%rdi
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  mov    %r12d,%eax
  lea    0x0(,%r8,4),%r9d
  lea    (%rdi,%rdi,2),%r10
  shr    $0x2,%eax
  movslq %r9d,%r9
  shl    $0x2,%r10
  add    $0x1,%eax
  shl    $0x2,%r9
  shl    $0x4,%rax
  mov    %rax,-0x8(%rsp)
  nopl   0x0(%rax)
L1:
  mov    -0x28(%rsp),%eax
  test   %eax,%eax
  jle    L49
  mov    -0x10(%rsp),%rax
  movslq %r14d,%rbp
  mov    -0x18(%rsp),%r11
  xor    %ebx,%ebx
  shl    $0x2,%rbp
  lea    (%rax,%rbp,1),%rsi
  mov    -0x8(%rsp),%rax
  add    -0x20(%rsp),%rbp
  lea    (%rax,%rbp,1),%r8
  nopl   0x0(%rax)
L17:
  mov    (%rsi),%eax
  mov    %r11,%rcx
  mov    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L48:
  mov    (%rdx),%r15d
  imul   (%rcx),%r15d
  add    $0x10,%rdx
  add    %eax,%r15d
  mov    %r15d,(%rsi)
  mov    -0xc(%rdx),%eax
  imul   (%rcx,%rdi,4),%eax
  add    %r15d,%eax
  mov    %eax,(%rsi)
  mov    -0x8(%rdx),%r15d
  imul   (%rcx,%rdi,8),%r15d
  add    %eax,%r15d
  mov    %r15d,(%rsi)
  mov    -0x4(%rdx),%eax
  imul   (%rcx,%r10,1),%eax
  add    %r9,%rcx
  add    %r15d,%eax
  mov    %eax,(%rsi)
  cmp    %r8,%rdx
  jne    L48
  lea    0x1(%rbx),%rax
  add    $0x4,%rsi
  add    $0x4,%r11
  cmp    %rbx,%r12
  je     L49
  mov    %rax,%rbx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x1,%r13d
  add    -0x28(%rsp),%r14d
  cmp    %r13d,-0x24(%rsp)
  jne    L1
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mmul5(int *a, int *b, int *res, int h, int w) {
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < w; j++) {
      for (int k = 0; k < w; k += 4) {
        int *line = (a + i * w);
        int *res_pos = &(res + i * w)[j];
        *res_pos += (line)[k] * (b + k * w)[j];
        *res_pos += (line)[k + 1] * (b + (k + 1) * w)[j];
        *res_pos += (line)[k + 2] * (b + (k + 2) * w)[j];
        *res_pos += (line)[k + 3] * (b + (k + 3) * w)[j];
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mmul5>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x18(%rsp)
  mov    %ecx,-0xc(%rsp)
  test   %ecx,%ecx
  jle    L5
  test   %r8d,%r8d
  jle    L5
  mov    %rdi,%rbp
  movslq %r8d,%rdi
  mov    %rdx,%r13
  xor    %r14d,%r14d
  lea    0x0(,%rdi,4),%rax
  mov    %rdi,%r10
  lea    (%rdi,%rdi,2),%r9
  mov    %r8d,%r12d
  mov    %rax,-0x20(%rsp)
  lea    -0x1(%r8),%eax
  shl    $0x4,%r10
  shl    $0x2,%r9
  shr    $0x2,%eax
  add    $0x1,%eax
  shl    $0x4,%rax
  mov    %rax,-0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    -0x8(%rsp),%rax
  mov    -0x18(%rsp),%rbx
  mov    %r13,%rsi
  xor    %r11d,%r11d
  lea    (%rax,%rbp,1),%r8
  nopl   0x0(%rax)
L33:
  mov    (%rsi),%eax
  mov    %rbx,%rcx
  mov    %rbp,%rdx
L14:
  mov    (%rdx),%r15d
  imul   (%rcx),%r15d
  add    $0x10,%rdx
  add    %eax,%r15d
  mov    %r15d,(%rsi)
  mov    -0xc(%rdx),%eax
  imul   (%rcx,%rdi,4),%eax
  add    %r15d,%eax
  mov    %eax,(%rsi)
  mov    -0x8(%rdx),%r15d
  imul   (%rcx,%rdi,8),%r15d
  add    %eax,%r15d
  mov    %r15d,(%rsi)
  mov    -0x4(%rdx),%eax
  imul   (%rcx,%r9,1),%eax
  add    %r10,%rcx
  add    %r15d,%eax
  mov    %eax,(%rsi)
  cmp    %r8,%rdx
  jne    L14
  add    $0x1,%r11
  add    $0x4,%rsi
  add    $0x4,%rbx
  cmp    %r11,%r12
  jne    L33
  mov    -0x20(%rsp),%rax
  add    $0x1,%r14d
  add    %rax,%rbp
  add    %rax,%r13
  cmp    %r14d,-0xc(%rsp)
  jne    L24
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mmul5(int *a, int *b, int *res, int h, int w) {
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < w; j++) {
      for (int k = 0; k < w; k += 4) {
        int *line = (a + i * w);
        int *res_pos = &(res + i * w)[j];
        *res_pos += (line)[k] * (b + k * w)[j];
        *res_pos += (line)[k + 1] * (b + (k + 1) * w)[j];
        *res_pos += (line)[k + 2] * (b + (k + 2) * w)[j];
        *res_pos += (line)[k + 3] * (b + (k + 3) * w)[j];
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<K256Length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L19
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L36
  addl   $0x1,-0xc(%rbp)
  jmp    L26
L36:
  subl   $0x1,-0xc(%rbp)
L26:
  addq   $0x1,-0x8(%rbp)
L19:
  cmpl   $0x0,-0xc(%rbp)
  jne    L39
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int K256Length(const char *K) {
  const char *p;
  int c0;
  p = K;
  c0 = 1;
  while (c0) {
    if (*p & 0x80) {
      c0++;
    } else {
      c0--;
    }
    p++;
  }
  return p - K;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<K256Length>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%edx
L0:
  lea    0x1(%rdx),%ecx
  sub    $0x1,%edx
  cmpb   $0x0,(%rax)
  cmovs  %ecx,%edx
  add    $0x1,%rax
  test   %edx,%edx
  jne    L0
  sub    %edi,%eax
  ret
```

assistant: ```c
int K256Length(const char *K) {
  const char *p;
  int c0;
  p = K;
  c0 = 1;
  while (c0) {
    if (*p & 0x80) {
      c0++;
    } else {
      c0--;
    }
    p++;
  }
  return p - K;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<K256Length>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%edx
  nopl   0x0(%rax)
L20:
  movzbl (%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  js     L17
  sub    $0x1,%edx
  jne    L20
  sub    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%edx
  jmp    L20
```

assistant: ```c
int K256Length(const char *K) {
  const char *p;
  int c0;
  p = K;
  c0 = 1;
  while (c0) {
    if (*p & 0x80) {
      c0++;
    } else {
      c0--;
    }
    p++;
  }
  return p - K;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<K256Length>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%edx
  nopl   0x0(%rax)
L10:
  movzbl (%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  js     L7
  sub    $0x1,%edx
  jne    L10
  sub    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x1,%edx
  jmp    L10
```

assistant: ```c
int K256Length(const char *K) {
  const char *p;
  int c0;
  p = K;
  c0 = 1;
  while (c0) {
    if (*p & 0x80) {
      c0++;
    } else {
      c0--;
    }
    p++;
  }
  return p - K;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getnames>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3c,%eax
  je     L63
  cmp    $0x3e,%eax
  jne    L58
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <getstring@plt>
  cltq
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L31
L63:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  jne    L47
  addq   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <getstring@plt>
  cltq
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L31
L58:
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void getnames(buf, file, word) char *buf, *file, *word;
{
  char *temp;
  temp = buf;
  while (*temp != 0) {
    switch (*temp) {
    case '>':
      strcpy(file, getstring(++temp));
      break;
    case '<':
      if (*(++temp) == '<')
        ++temp;
      strcpy(word, getstring(temp));
      break;
    default:
      temp++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getnames>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L46
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L65:
  cmpb   $0x3c,0x1(%rbx)
  je     L28
  add    $0x1,%rbx
L17:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <getstring@plt>
  movslq %eax,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
L23:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L44
L46:
  cmp    $0x3c,%al
  je     L65
  cmp    $0x3e,%al
  jne    L37
  add    $0x1,%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <getstring@plt>
  movslq %eax,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L23
L28:
  add    $0x2,%rbx
  jmp    L17
L37:
  add    $0x1,%rbx
  jmp    L23
```

assistant: ```c
void getnames(buf, file, word) char *buf, *file, *word;
{
  char *temp;
  temp = buf;
  while (*temp != 0) {
    switch (*temp) {
    case '>':
      strcpy(file, getstring(++temp));
      break;
    case '<':
      if (*(++temp) == '<')
        ++temp;
      strcpy(word, getstring(temp));
      break;
    default:
      temp++;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getnames>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L30
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L2
L54:
  mov    %rbx,%rbp
  cmp    $0x3e,%al
  jne    L11
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <getstring@plt>
  mov    %r13,%rdi
  movslq %eax,%rsi
  call   <strcpy@plt>
L11:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L49
L2:
  lea    0x1(%rbp),%rbx
  cmp    $0x3c,%al
  jne    L54
  cmpb   $0x3c,0x1(%rbp)
  jne    L14
  lea    0x2(%rbp),%rbx
L14:
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    %rbx,%rbp
  call   <getstring@plt>
  mov    %r12,%rdi
  movslq %eax,%rsi
  call   <strcpy@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L2
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L30:
  ret
```

assistant: ```c
void getnames(buf, file, word) char *buf, *file, *word;
{
  char *temp;
  temp = buf;
  while (*temp != 0) {
    switch (*temp) {
    case '>':
      strcpy(file, getstring(++temp));
      break;
    case '<':
      if (*(++temp) == '<')
        ++temp;
      strcpy(word, getstring(temp));
      break;
    default:
      temp++;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<getnames>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L52
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L19
L10:
  mov    %rbx,%rbp
  cmp    $0x3e,%al
  jne    L40
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <getstring@plt>
  mov    %r13,%rdi
  movslq %eax,%rsi
  call   <strcpy@plt>
L40:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L48
L19:
  lea    0x1(%rbp),%rbx
  cmp    $0x3c,%al
  jne    L10
  cmpb   $0x3c,0x1(%rbp)
  jne    L35
  lea    0x2(%rbp),%rbx
L35:
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    %rbx,%rbp
  call   <getstring@plt>
  mov    %r12,%rdi
  movslq %eax,%rsi
  call   <strcpy@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L19
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L52:
  ret
```

assistant: ```c
void getnames(buf, file, word) char *buf, *file, *word;
{
  char *temp;
  temp = buf;
  while (*temp != 0) {
    switch (*temp) {
    case '>':
      strcpy(file, getstring(++temp));
      break;
    case '<':
      if (*(++temp) == '<')
        ++temp;
      strcpy(word, getstring(temp));
      break;
    default:
      temp++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L13
  mov    $0x0,%eax
  call   <abort@plt>
L13:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L23
  nop
  nop
  leave
  ret
```

assistant: ```c
void check(int *a, int *b, int N) {
  int i;
  for (i = 0; i < N; i++)
    if (a[i] != b[i])
      abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L28
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
  jmp    L8
L37:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L38
L8:
  mov    0x0(%r13,%rbx,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  je     L37
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L37
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  ret
```

assistant: ```c
void check(int *a, int *b, int N) {
  int i;
  for (i = 0; i < N; i++)
    if (a[i] != b[i])
      abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L12
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L4:
  mov    0x0(%r13,%rbx,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  je     L11
  xor    %eax,%eax
  call   <abort@plt>
L11:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void check(int *a, int *b, int N) {
  int i;
  for (i = 0; i < N; i++)
    if (a[i] != b[i])
      abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L0
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L21:
  mov    0x0(%r13,%rbx,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  je     L18
  xor    %eax,%eax
  call   <abort@plt>
L18:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L21
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void check(int *a, int *b, int N) {
  int i;
  for (i = 0; i < N; i++)
    if (a[i] != b[i])
      abort();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sqrtllu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  nop
L18:
  addq   $0x1,-0x8(%rbp)
  shrq   -0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  shr    %rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L8
  mov    -0x10(%rbp),%rax
  shr    %rax
  add    %rax,-0x10(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x10(%rbp)
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  shr    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L8
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long unsigned sqrtllu(long long unsigned t) {
  long long unsigned s;
  long long unsigned b;
  for (b = 0, s = t; b++, (s >>= 1) != 0;)
    ;
  s = 1LL << (b >> 1);
  if (b & 1)
    s += s >> 1;
  do {
    b = t / s;
    s = (s + b) >> 1;
  } while (b < s);
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sqrtllu>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x0,%eax
L16:
  add    $0x1,%rax
  shr    %rdx
  jne    L16
  mov    %rax,%rcx
  shr    %rcx
  mov    $0x1,%edx
  shl    %cl,%rdx
  mov    %rdx,%rcx
  shr    %rdx
  add    %rcx,%rdx
  test   $0x1,%al
  cmovne %rdx,%rcx
L0:
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    %rax,%rcx
  shr    %rcx
  cmp    %rcx,%rax
  jb     L0
  mov    %rcx,%rax
  ret
```

assistant: ```c
long unsigned sqrtllu(long long unsigned t) {
  long long unsigned s;
  long long unsigned b;
  for (b = 0, s = t; b++, (s >>= 1) != 0;)
    ;
  s = 1LL << (b >> 1);
  if (b & 1)
    s += s >> 1;
  do {
    b = t / s;
    s = (s + b) >> 1;
  } while (b < s);
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sqrtllu>:
  endbr64
  mov    %rdi,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  add    $0x1,%rax
  shr    %rdx
  jne    L1
  mov    %rax,%rcx
  mov    $0x1,%r8d
  shr    %rcx
  shl    %cl,%r8
  mov    %r8,%rdx
  shr    %rdx
  add    %r8,%rdx
  test   $0x1,%al
  cmovne %rdx,%r8
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %r8
  add    %rax,%r8
  shr    %r8
  cmp    %r8,%rax
  jb     L11
  mov    %r8,%rax
  ret
```

assistant: ```c
long unsigned sqrtllu(long long unsigned t) {
  long long unsigned s;
  long long unsigned b;
  for (b = 0, s = t; b++, (s >>= 1) != 0;)
    ;
  s = 1LL << (b >> 1);
  if (b & 1)
    s += s >> 1;
  do {
    b = t / s;
    s = (s + b) >> 1;
  } while (b < s);
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqrtllu>:
  endbr64
  mov    %rdi,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  add    $0x1,%rax
  shr    %rdx
  jne    L16
  mov    %rax,%rcx
  mov    $0x1,%r8d
  shr    %rcx
  shl    %cl,%r8
  mov    %r8,%rdx
  shr    %rdx
  add    %r8,%rdx
  test   $0x1,%al
  cmovne %rdx,%r8
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %r8
  add    %rax,%r8
  shr    %r8
  cmp    %r8,%rax
  jb     L4
  mov    %r8,%rax
  ret
```

assistant: ```c
long unsigned sqrtllu(long long unsigned t) {
  long long unsigned s;
  long long unsigned b;
  for (b = 0, s = t; b++, (s >>= 1) != 0;)
    ;
  s = 1LL << (b >> 1);
  if (b & 1)
    s += s >> 1;
  do {
    b = t / s;
    s = (s + b) >> 1;
  } while (b < s);
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_coords_from_xyz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_coords_from_xyz(const double *xyz, double *x) {
  x[0] = xyz[0];
  x[1] = xyz[1];
  x[2] = xyz[2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_coords_from_xyz>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void get_coords_from_xyz(const double *xyz, double *x) {
  x[0] = xyz[0];
  x[1] = xyz[1];
  x[2] = xyz[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_coords_from_xyz>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void get_coords_from_xyz(const double *xyz, double *x) {
  x[0] = xyz[0];
  x[1] = xyz[1];
  x[2] = xyz[2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_coords_from_xyz>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void get_coords_from_xyz(const double *xyz, double *x) {
  x[0] = xyz[0];
  x[1] = xyz[1];
  x[2] = xyz[2];
}
```