ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fastfib>:
  endbr64
  sub    $0x28,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    %rsi,%rax
  lea    0x10(%rsp),%r9
  jmp    L23
  xchg   %ax,%ax
L33:
  cmp    %rsi,%rax
  je     L107
  mov    0xc(%rsp),%ecx
  cmp    %r9,%rax
  je     L43
  add    0x10(%rsp),%ecx
L95:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %r8,%rax
  cmova  %rsi,%rax
  add    $0x1,%edx
  cmp    %edx,%edi
  jb     L5
L23:
  cmp    $0x1,%edx
  ja     L33
  mov    %edx,%ecx
  jmp    L95
  nop
L107:
  mov    0x14(%rsp),%ecx
  add    0x10(%rsp),%ecx
  mov    %ecx,0xc(%rsp)
L20:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%edi
  jae    L23
L5:
  cmp    %rsi,%rax
  je     L55
  mov    -0x4(%rax),%eax
L29:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L43:
  add    0x14(%rsp),%ecx
  mov    %ecx,0x10(%rsp)
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L55:
  mov    0x14(%rsp),%eax
  jmp    L29
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int fastfib(unsigned int n) {
  unsigned int a[3];
  unsigned int *p = a;
  unsigned int i;
  for (i = 0; i <= n; ++i) {
    if (i < 2)
      *p = i;
    else {
      if (p == a)
        *p = *(a + 1) + *(a + 2);
      else if (p == a + 1)
        *p = *a + *(a + 2);
      else
        *p = *a + *(a + 1);
    }
    if (++p > a + 2)
      p = a;
  }
  return p == a ? *(p + 2) : *(p - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fastfib>:
  endbr64
  sub    $0x28,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    %rsi,%rax
  lea    0x10(%rsp),%r9
  jmp    L31
  xchg   %ax,%ax
L84:
  cmp    %rsi,%rax
  je     L2
  mov    0xc(%rsp),%ecx
  cmp    %r9,%rax
  je     L55
  add    0x10(%rsp),%ecx
L25:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %r8,%rax
  cmova  %rsi,%rax
  add    $0x1,%edx
  cmp    %edx,%edi
  jb     L15
L31:
  cmp    $0x1,%edx
  ja     L84
  mov    %edx,%ecx
  jmp    L25
  nop
L2:
  mov    0x14(%rsp),%ecx
  add    0x10(%rsp),%ecx
  mov    %ecx,0xc(%rsp)
L41:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%edi
  jae    L31
L15:
  cmp    %rsi,%rax
  je     L3
  mov    -0x4(%rax),%eax
L54:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L55:
  add    0x14(%rsp),%ecx
  mov    %ecx,0x10(%rsp)
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L3:
  mov    0x14(%rsp),%eax
  jmp    L54
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int fastfib(unsigned int n) {
  unsigned int a[3];
  unsigned int *p = a;
  unsigned int i;
  for (i = 0; i <= n; ++i) {
    if (i < 2)
      *p = i;
    else {
      if (p == a)
        *p = *(a + 1) + *(a + 2);
      else if (p == a + 1)
        *p = *a + *(a + 2);
      else
        *p = *a + *(a + 1);
    }
    if (++p > a + 2)
      p = a;
  }
  return p == a ? *(p + 2) : *(p - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<label_symlinkfile_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int label_symlinkfile_set(const char *path) {
  int r = 0;
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<label_symlinkfile_set>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int label_symlinkfile_set(const char *path) {
  int r = 0;
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<label_symlinkfile_set>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int label_symlinkfile_set(const char *path) {
  int r = 0;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<label_symlinkfile_set>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int label_symlinkfile_set(const char *path) {
  int r = 0;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdup(char *s) {
  char *p;
  p = (char *)malloc(strlen(s) + 1);
  if (p != NULL)
    strcpy(p, s);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L0
L6:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L6
```

assistant: ```c
char *strdup(char *s) {
  char *p;
  p = (char *)malloc(strlen(s) + 1);
  if (p != NULL)
    strcpy(p, s);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L0:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(char *s) {
  char *p;
  p = (char *)malloc(strlen(s) + 1);
  if (p != NULL)
    strcpy(p, s);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L9:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(char *s) {
  char *p;
  p = (char *)malloc(strlen(s) + 1);
  if (p != NULL)
    strcpy(p, s);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ttt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x6,-0x4(%rbp)
L7:
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ttt(int *wwp) {
  int xyz = 6;
  do {
  } while (!xyz);
}
```
user: What is the c source code of the assembly code below:

```asm
<ttt>:
  endbr64
  ret
```

assistant: ```c
void ttt(int *wwp) {
  int xyz = 6;
  do {
  } while (!xyz);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ttt>:
  endbr64
  ret
```

assistant: ```c
void ttt(int *wwp) {
  int xyz = 6;
  do {
  } while (!xyz);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ttt>:
  endbr64
  ret
```

assistant: ```c
void ttt(int *wwp) {
  int xyz = 6;
  do {
  } while (!xyz);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fill_next_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L24
L33:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addq   $0x1,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L33
  cmpl   $0x0,-0x24(%rbp)
  je     L54
  cmpq   $0x0,-0x38(%rbp)
  jne    L32
L54:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L76
L32:
  cmpl   $0x1,-0x24(%rbp)
  jne    L16
  jmp    L40
L34:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%rdx
  sub    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L40:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L34
  jmp    L89
L99:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x40(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L99
L76:
  jmp    L89
L19:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addq   $0x1,-0x10(%rbp)
L89:
  mov    -0x10(%rbp),%rax
  cmp    0x10(%rbp),%rax
  jb     L19
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long fill_next_count(size_t si, size_t ei, int repeats, unsigned long long sum, unsigned long long *current_count, unsigned long long *next_count, size_t len) {
  size_t i;
  unsigned long long nextsum = 0;
  for (i = 0; i < si; i++)
    next_count[i] = 0;
  if (repeats == 0 || current_count == NULL)
    nextsum = sum;
  else if (repeats == 1)
    for (; i <= ei; i++) {
      next_count[i] = sum - current_count[i];
      nextsum += next_count[i];
    }
  else
    for (; i <= ei; i++) {
      next_count[i] = current_count[i];
      nextsum += next_count[i];
    }
  for (; i < len; i++)
    next_count[i] = 0;
  return nextsum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fill_next_count>:
  endbr64
  mov    %rsi,%r10
  mov    0x8(%rsp),%r11
  test   %rdi,%rdi
  je     L81
  mov    %r9,%rax
  lea    (%r9,%rdi,8),%rsi
L72:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L72
L81:
  test   %edx,%edx
  je     L29
  test   %r8,%r8
  je     L29
  cmp    $0x1,%edx
  je     L22
  mov    $0x0,%ecx
  cmp    %rdi,%r10
  jb     L29
L76:
  mov    (%r8,%rdi,8),%rax
  mov    %rax,(%r9,%rdi,8)
  add    %rax,%rcx
  add    $0x1,%rdi
  cmp    %rdi,%r10
  jae    L76
L29:
  cmp    %rdi,%r11
  jbe    L124
  lea    (%r9,%rdi,8),%rax
  lea    (%r9,%r11,8),%rdx
L52:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L52
L124:
  mov    %rcx,%rax
  ret
L22:
  cmp    %rdi,%r10
  jb     L100
  mov    $0x0,%edx
L59:
  mov    %rcx,%rax
  sub    (%r8,%rdi,8),%rax
  mov    %rax,(%r9,%rdi,8)
  add    %rax,%rdx
  add    $0x1,%rdi
  cmp    %rdi,%r10
  jae    L59
  mov    %rdx,%rcx
  jmp    L29
L100:
  mov    $0x0,%ecx
  jmp    L29
```

assistant: ```c
unsigned long long fill_next_count(size_t si, size_t ei, int repeats, unsigned long long sum, unsigned long long *current_count, unsigned long long *next_count, size_t len) {
  size_t i;
  unsigned long long nextsum = 0;
  for (i = 0; i < si; i++)
    next_count[i] = 0;
  if (repeats == 0 || current_count == NULL)
    nextsum = sum;
  else if (repeats == 1)
    for (; i <= ei; i++) {
      next_count[i] = sum - current_count[i];
      nextsum += next_count[i];
    }
  else
    for (; i <= ei; i++) {
      next_count[i] = current_count[i];
      nextsum += next_count[i];
    }
  for (; i < len; i++)
    next_count[i] = 0;
  return nextsum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fill_next_count>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%rbp
  test   %rdi,%rdi
  je     L11
  lea    0x0(,%rdi,8),%rdx
  xor    %esi,%esi
  mov    %r9,%rdi
  call   <memset@plt>
  mov    %rax,%r9
L11:
  test   %r12d,%r12d
  je     L0
  test   %r14,%r14
  je     L0
  cmp    $0x1,%r12d
  mov    $0x0,%r12d
  jne    L77
  cmp    %rbx,%r13
  jb     L18
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %r15,%rax
  sub    (%r14,%rbx,8),%rax
  mov    %rax,(%r9,%rbx,8)
  add    $0x1,%rbx
  add    %rax,%r12
  cmp    %rbx,%r13
  jae    L16
  nop
L18:
  cmp    %rbx,%rbp
  jbe    L99
  mov    %rbp,%rdx
  lea    (%r9,%rbx,8),%rdi
  xor    %esi,%esi
  sub    %rbx,%rdx
  shl    $0x3,%rdx
  call   <memset@plt>
L99:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L22:
  mov    (%r14,%rbx,8),%rax
  mov    %rax,(%r9,%rbx,8)
  add    %rax,%r12
  add    $0x1,%rbx
L77:
  cmp    %rbx,%r13
  jae    L22
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %r15,%r12
  jmp    L18
```

assistant: ```c
unsigned long long fill_next_count(size_t si, size_t ei, int repeats, unsigned long long sum, unsigned long long *current_count, unsigned long long *next_count, size_t len) {
  size_t i;
  unsigned long long nextsum = 0;
  for (i = 0; i < si; i++)
    next_count[i] = 0;
  if (repeats == 0 || current_count == NULL)
    nextsum = sum;
  else if (repeats == 1)
    for (; i <= ei; i++) {
      next_count[i] = sum - current_count[i];
      nextsum += next_count[i];
    }
  else
    for (; i <= ei; i++) {
      next_count[i] = current_count[i];
      nextsum += next_count[i];
    }
  for (; i < len; i++)
    next_count[i] = 0;
  return nextsum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x1,-0x18(%rbp)
  jne    L0
  movsd  -0x20(%rbp),%xmm0
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L4
L0:
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  lea    D25(%rip),%rdx
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L4:
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D45
type_guessed: string
name: read_data
arguments: data_tag: D43
type_guessed: string
name: read_data
arguments: data_tag: D33
type_guessed: string
name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D53
type_guessed: string
name: read_data
arguments: data_tag: D47
type_guessed: string

tool: D45: 
	---------------%s----------------



tool: D43: 			SIZE	 TIME_SEC	 gflops 

tool: D33: 			%d	%f	 %lf	


tool: D25: ---

tool: D53: 			%d	%lf 	%s	


tool: D47: 
	-----------------------------------------------------------------------------------------

assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------------------------------");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_on_screen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %esi,%ebx
  movq   %xmm1,%r13
  mov    %edx,%r12d
  mov    %rdi,%rsi
  lea    D51(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%r12d
  je     L19
  lea    D40(%rip),%rdx
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D41(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L17:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  movq   %r13,%xmm1
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D48(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L17
```

tool_calls: name: unpack_data
arguments: label: D51
type_infered: string
name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D40
type_infered: string
name: unpack_data
arguments: label: D41
type_infered: string
name: unpack_data
arguments: label: D5
type_infered: string
name: unpack_data
arguments: label: D48
type_infered: string

tool: D51: 
	---------------%s----------------



tool: D7: 			SIZE	 TIME_SEC	 gflops 

tool: D40: ---

tool: D41: 			%d	%lf 	%s	


tool: D5: 
	-----------------------------------------------------------------------------------------

tool: D48: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------------------------------");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D4(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L1
  lea    D47(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D41(%rip),%rdi
  call   <printf@plt>
L6:
  add    $0x18,%rsp
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L1:
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D43
datatype: string
name: disassemble_data
arguments: data_label: D47
datatype: string
name: disassemble_data
arguments: data_label: D41
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string

tool: D4: 
	---------------%s----------------



tool: D43: 			SIZE	 TIME_SEC	 gflops 

tool: D47: ---

tool: D41: 			%d	%lf 	%s	


tool: D18: 
	-----------------------------------------------------------------------------------------

tool: D10: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------------------------------");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D56(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L0
  lea    D1(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
L1:
  add    $0x18,%rsp
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L0:
  mov    %ebp,%esi
  lea    D29(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_label: D56
type_guessed: string
name: retrieve_data
arguments: data_label: D22
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D44
type_guessed: string
name: retrieve_data
arguments: data_label: D40
type_guessed: string
name: retrieve_data
arguments: data_label: D29
type_guessed: string

tool: D56: 
	---------------%s----------------



tool: D22: 			SIZE	 TIME_SEC	 gflops 

tool: D1: ---

tool: D44: 			%d	%lf 	%s	


tool: D40: 
	-----------------------------------------------------------------------------------------

tool: D29: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------------------------------");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<psvec2_slide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vec2_slide@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_slide(struct vec2 *result, struct vec2 *a, struct vec2 *b) {
  vec2_slide((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<psvec2_slide>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec2_slide@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_slide(struct vec2 *result, struct vec2 *a, struct vec2 *b) {
  vec2_slide((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<psvec2_slide>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2_slide@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_slide(struct vec2 *result, struct vec2 *a, struct vec2 *b) {
  vec2_slide((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<psvec2_slide>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2_slide@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_slide(struct vec2 *result, struct vec2 *a, struct vec2 *b) {
  vec2_slide((float *)result, (float *)a, (float *)b);
  return result;
}
```