ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r12
  mov    %rbp,%rdi
  call   <pthread_mutex_init@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <pthread_cond_init@plt>
  mov    %rbp,%rdi
  call   <pthread_mutex_lock@plt>
  mov    %r12,%rdi
  call   <pthread_cond_broadcast@plt>
  mov    %rbp,%rdi
  call   <pthread_mutex_unlock@plt>
  mov    %r12,%rdi
  call   <pthread_cond_destroy@plt>
  mov    %rbp,%rdi
  call   <pthread_mutex_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  pthread_mutex_t mutex;
  pthread_cond_t cond;
  pthread_mutex_init(&mutex, NULL);
  pthread_cond_init(&cond, NULL);
  pthread_mutex_lock(&mutex);
  pthread_cond_broadcast(&cond);
  pthread_mutex_unlock(&mutex);
  pthread_cond_destroy(&cond);
  pthread_mutex_destroy(&mutex);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r12
  mov    %rbp,%rdi
  call   <pthread_mutex_init@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <pthread_cond_init@plt>
  mov    %rbp,%rdi
  call   <pthread_mutex_lock@plt>
  mov    %r12,%rdi
  call   <pthread_cond_broadcast@plt>
  mov    %rbp,%rdi
  call   <pthread_mutex_unlock@plt>
  mov    %r12,%rdi
  call   <pthread_cond_destroy@plt>
  mov    %rbp,%rdi
  call   <pthread_mutex_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  pthread_mutex_t mutex;
  pthread_cond_t cond;
  pthread_mutex_init(&mutex, NULL);
  pthread_cond_init(&cond, NULL);
  pthread_mutex_lock(&mutex);
  pthread_cond_broadcast(&cond);
  pthread_mutex_unlock(&mutex);
  pthread_cond_destroy(&cond);
  pthread_mutex_destroy(&mutex);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L34
  mov    -0x4(%rbp),%eax
  jmp    L5
L34:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L33
  mov    $0xffffffff,%eax
L5:
  leave
  ret
```

assistant: ```c
int findchar(const char *str, char c) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == c)
      return i;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findchar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L17:
  mov    %ebx,%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L6
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  jne    L17
  jmp    L25
L6:
  mov    $0xffffffff,%r13d
L25:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int findchar(const char *str, char c) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == c)
      return i;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findchar>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  je     L17
L11:
  mov    %rbp,%rdi
  mov    %ebx,%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  mov    $0xffffffff,%r13d
L17:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int findchar(const char *str, char c) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == c)
      return i;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<findchar>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  je     L28
L0:
  mov    %rbp,%rdi
  mov    %ebx,%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L29
  mov    $0xffffffff,%r13d
L28:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int findchar(const char *str, char c) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == c)
      return i;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  addl   $0x1,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test1(void) {
  int i;
  i++;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test1>:
  endbr64
  ret
```

assistant: ```c
void test1(void) {
  int i;
  i++;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test1>:
  endbr64
  ret
```

assistant: ```c
void test1(void) {
  int i;
  i++;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test1>:
  endbr64
  ret
```

assistant: ```c
void test1(void) {
  int i;
  i++;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<intToRoman>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,(%rsp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%r15
  movl   $0x4,0x4(%rsp)
  mov    $0x3e8,%ebp
  lea    D9(%rip),%r13
  jmp    L91
L97:
  mov    %ebp,%edi
  call   <numToChar@plt>
  lea    0x1(%r15),%rbx
  movsbl %al,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  lea    0x0(%rbp,%rbp,4),%edi
  add    %edi,%edi
  call   <numToChar@plt>
  add    $0x2,%r15
  movsbl %al,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  jmp    L79
L83:
  cmp    $0x4,%r14d
  je     L33
  test   %r14d,%r14d
  jle    L79
  mov    %r14d,%r12d
  add    %r15,%r12
  mov    %r15,%rbx
L62:
  mov    %ebp,%edi
  call   <numToChar@plt>
  mov    %rbx,%rdi
  add    $0x1,%rbx
  movsbl %al,%edx
  mov    %r13,%rsi
  call   <sprintf@plt>
  cmp    %rbx,%r12
  jne    L62
  mov    %r14d,%r14d
  add    %r14,%r15
L79:
  mov    (%rsp),%eax
  cltd
  idiv   %ebp
  mov    %edx,(%rsp)
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  subl   $0x1,0x4(%rsp)
  je     L52
L91:
  mov    (%rsp),%eax
  cltd
  idiv   %ebp
  mov    %eax,%ebx
  mov    %eax,%r14d
  cmp    $0x9,%eax
  je     L97
  cmp    $0x4,%eax
  jle    L83
  lea    0x0(%rbp,%rbp,4),%edi
  call   <numToChar@plt>
  lea    0x1(%r15),%r12
  movsbl %al,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  lea    -0x5(%rbx),%r14d
  mov    %r12,%r15
  jmp    L83
L33:
  mov    %ebp,%edi
  call   <numToChar@plt>
  lea    0x1(%r15),%rbx
  movsbl %al,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  lea    0x0(%rbp,%rbp,4),%edi
  call   <numToChar@plt>
  add    $0x2,%r15
  movsbl %al,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  jmp    L79
L52:
  mov    $0x0,%edx
  lea    D9(%rip),%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string

tool: D9: %c

assistant: ```c
char *intToRoman(int num) {
  char *result = malloc(100);
  int step = 1000;
  int count = 0;
  char *cur = result;
  while (step > 0) {
    count = num / step;
    if (count == 9) {
      sprintf(cur++, "%c", numToChar(step));
      sprintf(cur++, "%c", numToChar(step * 10));
      count -= 9;
    }
    if (count >= 5) {
      sprintf(cur++, "%c", numToChar(step * 5));
      count -= 5;
    }
    if (count == 4) {
      sprintf(cur++, "%c", numToChar(step));
      sprintf(cur++, "%c", numToChar(step * 5));
      count -= 4;
    }
    while (count > 0) {
      sprintf(cur++, "%c", numToChar(step));
      count--;
    }
    num %= step;
    step /= 10;
  }
  sprintf(cur, "%c", '\0');
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intToRoman>:
  endbr64
  push   %r15
  mov    $0x3e8,%r15d
  push   %r14
  mov    $0x4,%r14d
  push   %r13
  mov    %edi,%r13d
  mov    $0x64,%edi
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
L53:
  mov    %r13d,%eax
  cltd
  idiv   %r15d
  mov    %edx,%r13d
  mov    %eax,%r8d
  cmp    $0x9,%eax
  je     L38
  mov    %rbp,%rbx
  cmp    $0x4,%eax
  jle    L72
  lea    (%r15,%r15,4),%edi
  mov    %eax,0x4(%rsp)
  add    $0x1,%rbx
  call   <numToChar@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsbl %al,%edx
  call   <sprintf@plt>
  mov    0x4(%rsp),%r8d
  sub    $0x5,%r8d
L72:
  cmp    $0x4,%r8d
  je     L46
  movslq %r8d,%rbp
  add    %rbx,%rbp
  test   %r8d,%r8d
  jle    L58
  nopl   (%rax)
L36:
  mov    %r15d,%edi
  call   <numToChar@plt>
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x1,%rbx
  movsbl %al,%edx
  call   <sprintf@plt>
  cmp    %rbp,%rbx
  jne    L36
L2:
  movslq %r15d,%rdx
  mov    %r15d,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  mov    %edx,%r15d
  sub    $0x1,%r14d
  jne    L53
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %r15d,%edi
  lea    0x2(%rbx),%rbp
  call   <numToChar@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  movsbl %al,%edx
  call   <sprintf@plt>
  lea    (%r15,%r15,4),%edi
  call   <numToChar@plt>
  lea    0x1(%rbx),%rdi
  mov    %r12,%rsi
  movsbl %al,%edx
  call   <sprintf@plt>
  jmp    L2
  nopl   0x0(%rax)
L38:
  mov    %r15d,%edi
  lea    0x1(%rbp),%rbx
  call   <numToChar@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x2,%rbp
  movsbl %al,%edx
  call   <sprintf@plt>
  lea    (%r15,%r15,4),%edi
  add    %edi,%edi
  call   <numToChar@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  movsbl %al,%edx
  call   <sprintf@plt>
  jmp    L2
L58:
  mov    %rbx,%rbp
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0: %c

assistant: ```c
char *intToRoman(int num) {
  char *result = malloc(100);
  int step = 1000;
  int count = 0;
  char *cur = result;
  while (step > 0) {
    count = num / step;
    if (count == 9) {
      sprintf(cur++, "%c", numToChar(step));
      sprintf(cur++, "%c", numToChar(step * 10));
      count -= 9;
    }
    if (count >= 5) {
      sprintf(cur++, "%c", numToChar(step * 5));
      count -= 5;
    }
    if (count == 4) {
      sprintf(cur++, "%c", numToChar(step));
      sprintf(cur++, "%c", numToChar(step * 5));
      count -= 4;
    }
    while (count > 0) {
      sprintf(cur++, "%c", numToChar(step));
      count--;
    }
    num %= step;
    step /= 10;
  }
  sprintf(cur, "%c", '\0');
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<intToRoman>:
  endbr64
  push   %r15
  mov    $0x3e8,%r15d
  push   %r14
  mov    $0x4,%r14d
  push   %r13
  mov    %edi,%r13d
  mov    $0x64,%edi
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
L81:
  mov    %r13d,%eax
  cltd
  idiv   %r15d
  mov    %edx,%r13d
  mov    %eax,%r8d
  cmp    $0x9,%eax
  je     L40
  mov    %rbp,%rbx
  cmp    $0x4,%eax
  jle    L19
  lea    (%r15,%r15,4),%edi
  mov    %eax,0x4(%rsp)
  add    $0x1,%rbx
  call   <numToChar@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsbl %al,%edx
  call   <sprintf@plt>
  mov    0x4(%rsp),%r8d
  sub    $0x5,%r8d
L19:
  cmp    $0x4,%r8d
  je     L57
  movslq %r8d,%rbp
  add    %rbx,%rbp
  test   %r8d,%r8d
  jle    L13
  nopl   (%rax)
L10:
  mov    %r15d,%edi
  call   <numToChar@plt>
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x1,%rbx
  movsbl %al,%edx
  call   <sprintf@plt>
  cmp    %rbp,%rbx
  jne    L10
L6:
  movslq %r15d,%rdx
  mov    %r15d,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  mov    %edx,%r15d
  sub    $0x1,%r14d
  jne    L81
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %r15d,%edi
  lea    0x2(%rbx),%rbp
  call   <numToChar@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  movsbl %al,%edx
  call   <sprintf@plt>
  lea    (%r15,%r15,4),%edi
  call   <numToChar@plt>
  lea    0x1(%rbx),%rdi
  mov    %r12,%rsi
  movsbl %al,%edx
  call   <sprintf@plt>
  jmp    L6
  nopl   0x0(%rax)
L40:
  mov    %r15d,%edi
  lea    0x1(%rbp),%rbx
  call   <numToChar@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x2,%rbp
  movsbl %al,%edx
  call   <sprintf@plt>
  lea    (%r15,%r15,4),%edi
  add    %edi,%edi
  call   <numToChar@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  movsbl %al,%edx
  call   <sprintf@plt>
  jmp    L6
L13:
  mov    %rbx,%rbp
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: %c

assistant: ```c
char *intToRoman(int num) {
  char *result = malloc(100);
  int step = 1000;
  int count = 0;
  char *cur = result;
  while (step > 0) {
    count = num / step;
    if (count == 9) {
      sprintf(cur++, "%c", numToChar(step));
      sprintf(cur++, "%c", numToChar(step * 10));
      count -= 9;
    }
    if (count >= 5) {
      sprintf(cur++, "%c", numToChar(step * 5));
      count -= 5;
    }
    if (count == 4) {
      sprintf(cur++, "%c", numToChar(step));
      sprintf(cur++, "%c", numToChar(step * 5));
      count -= 4;
    }
    while (count > 0) {
      sprintf(cur++, "%c", numToChar(step));
      count--;
    }
    num %= step;
    step /= 10;
  }
  sprintf(cur, "%c", '\0');
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<list_shiftDown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    -0x38(%rbp),%rbx
  mov    %rbx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    %rbx,%r10
  mov    $0x0,%r11d
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L38
L68:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    %rbx,%rdx
  imul   -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    %rbx,%rdx
  imul   -0x28(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  call   *%rax
  test   %eax,%eax
  jns    L22
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L22:
  mov    -0x18(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  jae    L61
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  imul   %rbx,%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    %rbx,%rdx
  imul   -0x28(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  call   *%rax
  test   %eax,%eax
  jns    L61
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
L61:
  mov    -0x28(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  je     L42
  mov    %rbx,%rdx
  imul   -0x28(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    %rbx,%rdx
  imul   -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <swap_memory@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
L38:
  mov    -0x30(%rbp),%rax
  add    %rax,%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  jbe    L68
  jmp    L51
L42:
  nop
L51:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void list_shiftDown(size_t size, char (*data)[size], size_t start, size_t end, int (*compare)(const void *, const void *)) {
  size_t root = start;
  size_t child;
  while ((child = root * 2 + 1) <= end) {
    size_t swap = root;
    if (compare(data[swap], data[child]) < 0)
      swap = child;
    if (child < end && compare(data[swap], data[child + 1]) < 0)
      swap = child + 1;
    if (swap != root) {
      swap_memory(data[root], data[swap], size);
      root = swap;
    } else
      return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_shiftDown>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r14
  mov    %rcx,%r15
  mov    %r8,0x10(%rsp)
  lea    0x1(%rdx,%rdx,1),%r12
  cmp    %r12,%rcx
  jae    L86
L10:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  cmp    %r12,%r15
  ja     L52
  mov    %r12,%r13
L93:
  cmp    %r14,%r13
  je     L10
  mov    %r13,%rsi
  imul   %rbx,%rsi
  add    0x8(%rsp),%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <swap_memory@plt>
  lea    0x1(%r13,%r13,1),%r12
  cmp    %r15,%r12
  ja     L10
  mov    %r13,%r14
L86:
  mov    %rbx,%rbp
  imul   %r14,%rbp
  mov    0x8(%rsp),%rax
  add    %rax,%rbp
  mov    %rbx,%rsi
  imul   %r12,%rsi
  add    %rax,%rsi
  mov    %rbp,%rdi
  mov    0x10(%rsp),%rax
  call   *%rax
  test   %eax,%eax
  js     L27
  cmp    %r12,%r15
  jbe    L10
  lea    0x1(%r14),%rax
  mov    %rax,0x18(%rsp)
  imul   %rbx,%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,2),%rsi
  mov    %rbx,%rdi
  imul   %r14,%rdi
  add    %rcx,%rdi
  mov    0x10(%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jns    L10
L53:
  mov    0x18(%rsp),%r13
  add    %r13,%r13
  jmp    L93
L52:
  lea    0x1(%r14),%rax
  mov    %rax,0x18(%rsp)
  imul   %rbx,%rax
  add    %rax,%rax
  mov    0x8(%rsp),%rdx
  lea    (%rdx,%rax,1),%rsi
  mov    %rbx,%rdi
  imul   %r12,%rdi
  add    %rdx,%rdi
  mov    0x10(%rsp),%rax
  call   *%rax
  mov    %r12,%r13
  test   %eax,%eax
  jns    L93
  jmp    L53
```

assistant: ```c
void list_shiftDown(size_t size, char (*data)[size], size_t start, size_t end, int (*compare)(const void *, const void *)) {
  size_t root = start;
  size_t child;
  while ((child = root * 2 + 1) <= end) {
    size_t swap = root;
    if (compare(data[swap], data[child]) < 0)
      swap = child;
    if (child < end && compare(data[swap], data[child + 1]) < 0)
      swap = child + 1;
    if (swap != root) {
      swap_memory(data[root], data[swap], size);
      root = swap;
    } else
      return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_shiftDown>:
  endbr64
  push   %r15
  lea    0x1(%rdx,%rdx,1),%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %r8,0x10(%rsp)
  cmp    %r15,%rcx
  jae    L43
  jmp    L76
  nopl   0x0(%rax)
L71:
  cmp    %r15,0x8(%rsp)
  jbe    L76
  lea    0x1(%r14),%rax
  mov    %rbp,%rdi
  lea    (%rax,%rax,1),%r12
  imul   %rbx,%rax
  lea    0x0(%r13,%rax,2),%rsi
  mov    0x10(%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jns    L76
L74:
  cmp    %r14,%r12
  je     L76
  mov    %r12,%rsi
  mov    %rbx,%rdx
  lea    0x1(%r12,%r12,1),%r15
  mov    %rbp,%rdi
  imul   %rbx,%rsi
  add    %r13,%rsi
  call   <swap_memory@plt>
  cmp    0x8(%rsp),%r15
  ja     L76
  mov    %r12,%r14
L43:
  mov    %rbx,%r8
  mov    %rbx,%rbp
  mov    0x10(%rsp),%rax
  imul   %r15,%r8
  imul   %r14,%rbp
  lea    0x0(%r13,%r8,1),%r12
  add    %r13,%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   *%rax
  test   %eax,%eax
  jns    L71
  cmp    %r15,0x8(%rsp)
  ja     L5
  mov    %r15,%r12
  jmp    L74
  xchg   %ax,%ax
L76:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  lea    0x1(%r14),%rax
  mov    %r12,%rdi
  lea    (%rax,%rax,1),%rcx
  imul   %rbx,%rax
  mov    %rcx,0x18(%rsp)
  add    %rax,%rax
  lea    0x0(%r13,%rax,1),%rsi
  mov    0x10(%rsp),%rax
  call   *%rax
  mov    0x18(%rsp),%rcx
  test   %eax,%eax
  cmovns %r15,%rcx
  mov    %rcx,%r12
  jmp    L74
```

assistant: ```c
void list_shiftDown(size_t size, char (*data)[size], size_t start, size_t end, int (*compare)(const void *, const void *)) {
  size_t root = start;
  size_t child;
  while ((child = root * 2 + 1) <= end) {
    size_t swap = root;
    if (compare(data[swap], data[child]) < 0)
      swap = child;
    if (child < end && compare(data[swap], data[child + 1]) < 0)
      swap = child + 1;
    if (swap != root) {
      swap_memory(data[root], data[swap], size);
      root = swap;
    } else
      return;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<list_shiftDown>:
  endbr64
  push   %r15
  lea    0x1(%rdx,%rdx,1),%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %r8,0x10(%rsp)
  cmp    %r15,%rcx
  jae    L67
  jmp    L35
  nopl   0x0(%rax)
L90:
  cmp    %r15,0x8(%rsp)
  jbe    L35
  lea    0x1(%r14),%rax
  mov    %rbp,%rdi
  lea    (%rax,%rax,1),%r12
  imul   %rbx,%rax
  lea    0x0(%r13,%rax,2),%rsi
  mov    0x10(%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jns    L35
L12:
  cmp    %r14,%r12
  je     L35
  mov    %r12,%rsi
  mov    %rbx,%rdx
  lea    0x1(%r12,%r12,1),%r15
  mov    %rbp,%rdi
  imul   %rbx,%rsi
  add    %r13,%rsi
  call   <swap_memory@plt>
  cmp    0x8(%rsp),%r15
  ja     L35
  mov    %r12,%r14
L67:
  mov    %rbx,%r8
  mov    %rbx,%rbp
  mov    0x10(%rsp),%rax
  imul   %r15,%r8
  imul   %r14,%rbp
  lea    0x0(%r13,%r8,1),%r12
  add    %r13,%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   *%rax
  test   %eax,%eax
  jns    L90
  cmp    %r15,0x8(%rsp)
  ja     L14
  mov    %r15,%r12
  jmp    L12
  xchg   %ax,%ax
L35:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  lea    0x1(%r14),%rax
  mov    %r12,%rdi
  lea    (%rax,%rax,1),%rcx
  imul   %rbx,%rax
  mov    %rcx,0x18(%rsp)
  add    %rax,%rax
  lea    0x0(%r13,%rax,1),%rsi
  mov    0x10(%rsp),%rax
  call   *%rax
  mov    0x18(%rsp),%rcx
  test   %eax,%eax
  cmovns %r15,%rcx
  mov    %rcx,%r12
  jmp    L12
```

assistant: ```c
void list_shiftDown(size_t size, char (*data)[size], size_t start, size_t end, int (*compare)(const void *, const void *)) {
  size_t root = start;
  size_t child;
  while ((child = root * 2 + 1) <= end) {
    size_t swap = root;
    if (compare(data[swap], data[child]) < 0)
      swap = child;
    if (child < end && compare(data[swap], data[child + 1]) < 0)
      swap = child + 1;
    if (swap != root) {
      swap_memory(data[root], data[swap], size);
      root = swap;
    } else
      return;
  }
}
```