ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D37(%rip),%r15
  push   %r14
  mov    %r15,%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x8(%rsp),%r14
  mov    %rbp,%rsi
  mov    %rbp,%r13
  lea    0x24(%rsp),%r12
  call   <printf@plt>
  mov    %r14,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D69(%rip),%rdi
  call   <puts@plt>
L24:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r13
  call   <scanf@plt>
  cmp    %r13,%r12
  jne    L24
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %rbp,0x8(%rsp)
  call   <printf@plt>
  mov    %r14,%rsi
  xor    %eax,%eax
  xor    %ebx,%ebx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  lea    D10(%rip),%rbp
  call   <putchar@plt>
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    0x8(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x18,%rbx
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D37
type_infered: string
name: unpack_data
arguments: tag: D2
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D61
type_infered: string
name: unpack_data
arguments: tag: D69
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string

tool: D37: array a'address is %p


tool: D2: %d

tool: D4: point idx'address is %p


tool: D61: the first member of the array is %p


tool: D69: input 5 numbers:

tool: D10: %d	

assistant: ```c
int main() {
  int a[5], *idx;
  printf("array a'address is %p\n", &a);
  printf("point idx'address is %p\n", &idx);
  printf("the first member of the array is %p\n", &a[0]);
  printf("input 5 numbers:\n");
  for (int i = 0; i < 5; i++) {
    scanf("%d", &a[i]);
  }
  idx = a;
  printf("array a'address is %p\n", &a);
  printf("point idx'address is %p\n", &idx);
  printf("the first member of the array is %p\n", &a[0]);
  putchar('\n');
  for (int i = 0; i <= 5; i++) {
    printf("%d\t", *(idx + i));
  }
  putchar('\n');
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Cnd_Lt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%eax
  call   <ArgNum@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <GetFlag@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <ArgNum@plt>
  cmp    %eax,%ebx
  setl   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int Cnd_Lt(void) {
  int v = ArgNum();
  return (GetFlag(v) < ArgNum());
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Cnd_Lt>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <ArgNum@plt>
  mov    %eax,%edi
  call   <GetFlag@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <ArgNum@plt>
  cmp    %eax,%ebx
  setl   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int Cnd_Lt(void) {
  int v = ArgNum();
  return (GetFlag(v) < ArgNum());
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cnd_Lt>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <ArgNum@plt>
  mov    %eax,%edi
  call   <GetFlag@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <ArgNum@plt>
  cmp    %eax,%ebx
  pop    %rbx
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int Cnd_Lt(void) {
  int v = ArgNum();
  return (GetFlag(v) < ArgNum());
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Cnd_Lt>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <ArgNum@plt>
  mov    %eax,%edi
  call   <GetFlag@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <ArgNum@plt>
  cmp    %eax,%ebx
  pop    %rbx
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int Cnd_Lt(void) {
  int v = ArgNum();
  return (GetFlag(v) < ArgNum());
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LeftIsWall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <TurnLeft@plt>
  mov    $0x0,%eax
  call   <IfFacingWall@plt>
  test   %rax,%rax
  je     L4
  mov    $0x0,%eax
  call   <TurnRight@plt>
  mov    $0x1,%eax
  jmp    L2
L4:
  mov    $0x0,%eax
  call   <TurnRight@plt>
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
char LeftIsWall(void) {
  TurnLeft();
  if (IfFacingWall()) {
    TurnRight();
    return 1;
  } else {
    TurnRight();
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LeftIsWall>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <TurnLeft@plt>
  mov    $0x0,%eax
  call   <IfFacingWall@plt>
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  call   <TurnRight@plt>
  mov    $0x1,%eax
L17:
  add    $0x8,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <TurnRight@plt>
  mov    $0x0,%eax
  jmp    L17
```

assistant: ```c
char LeftIsWall(void) {
  TurnLeft();
  if (IfFacingWall()) {
    TurnRight();
    return 1;
  } else {
    TurnRight();
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<LeftIsWall>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TurnLeft@plt>
  xor    %eax,%eax
  call   <IfFacingWall@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L9
  call   <TurnRight@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nop
L9:
  call   <TurnRight@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char LeftIsWall(void) {
  TurnLeft();
  if (IfFacingWall()) {
    TurnRight();
    return 1;
  } else {
    TurnRight();
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LeftIsWall>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TurnLeft@plt>
  xor    %eax,%eax
  call   <IfFacingWall@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L3
  call   <TurnRight@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nop
L3:
  call   <TurnRight@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char LeftIsWall(void) {
  TurnLeft();
  if (IfFacingWall()) {
    TurnRight();
    return 1;
  } else {
    TurnRight();
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L9
  cmpl   $0x4,-0x4(%rbp)
  jle    L27
L9:
  cmpl   $0x1,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L26
L27:
  mov    $0x1,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int foo(int i) {
  if (i < 0 || i >= 5)
    return i == 1;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  cmp    $0x4,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int foo(int i) {
  if (i < 0 || i >= 5)
    return i == 1;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  cmp    $0x4,%edi
  setbe  %al
  ret
```

assistant: ```c
int foo(int i) {
  if (i < 0 || i >= 5)
    return i == 1;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  cmp    $0x4,%edi
  setbe  %al
  ret
```

assistant: ```c
int foo(int i) {
  if (i < 0 || i >= 5)
    return i == 1;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <output_hashes@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string

tool: D14: 4534

tool: D13: passfile.dat

assistant: ```c
int main(int argc, char *argv[]) {
  output_hashes("passfile.dat", "4534");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <output_hashes@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D12
data_type: string

tool: D1: 4534

tool: D12: passfile.dat

assistant: ```c
int main(int argc, char *argv[]) {
  output_hashes("passfile.dat", "4534");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <output_hashes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D16
datatype: string

tool: D15: 4534

tool: D16: passfile.dat

assistant: ```c
int main(int argc, char *argv[]) {
  output_hashes("passfile.dat", "4534");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <output_hashes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D17
data_type: string
name: disassemble_data
arguments: tag: D14
data_type: string

tool: D17: 4534

tool: D14: passfile.dat

assistant: ```c
int main(int argc, char *argv[]) {
  output_hashes("passfile.dat", "4534");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L36
  mov    $0x0,%eax
  jmp    L10
L36:
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L31:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    -0x4(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int strlen(const char *s) {
  int len;
  if (!s)
    return 0;
  len = 0;
  while (*s++)
    len++;
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  test   %rdi,%rdi
  je     L5
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L0
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L11:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L11
L31:
  mov    %ecx,%eax
  ret
L5:
  mov    $0x0,%ecx
  jmp    L31
L0:
  mov    $0x0,%ecx
  jmp    L31
```

assistant: ```c
int strlen(const char *s) {
  int len;
  if (!s)
    return 0;
  len = 0;
  while (*s++)
    len++;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen>:
  endbr64
  test   %rdi,%rdi
  je     L21
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L21
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L18:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L18
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const char *s) {
  int len;
  if (!s)
    return 0;
  len = 0;
  while (*s++)
    len++;
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strlen>:
  endbr64
  test   %rdi,%rdi
  je     L14
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L14
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L9:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L9
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const char *s) {
  int len;
  if (!s)
    return 0;
  len = 0;
  while (*s++)
    len++;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<board_hp_dl165_g6_enable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x80,%ecx
  mov    $0x80,%edx
  mov    $0x44,%esi
  mov    $0xcd6,%edi
  call   <sio_mask@plt>
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x46,%esi
  mov    $0xcd6,%edi
  call   <sio_mask@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int board_hp_dl165_g6_enable(void) {
  sio_mask(0xcd6, 0x44, 0x80, 0x80);
  sio_mask(0xcd6, 0x46, 0x04, 0x04);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<board_hp_dl165_g6_enable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80,%ecx
  mov    $0x80,%edx
  mov    $0x44,%esi
  mov    $0xcd6,%edi
  call   <sio_mask@plt>
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x46,%esi
  mov    $0xcd6,%edi
  call   <sio_mask@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int board_hp_dl165_g6_enable(void) {
  sio_mask(0xcd6, 0x44, 0x80, 0x80);
  sio_mask(0xcd6, 0x46, 0x04, 0x04);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<board_hp_dl165_g6_enable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80,%ecx
  mov    $0x80,%edx
  mov    $0x44,%esi
  mov    $0xcd6,%edi
  call   <sio_mask@plt>
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x46,%esi
  mov    $0xcd6,%edi
  call   <sio_mask@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int board_hp_dl165_g6_enable(void) {
  sio_mask(0xcd6, 0x44, 0x80, 0x80);
  sio_mask(0xcd6, 0x46, 0x04, 0x04);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<board_hp_dl165_g6_enable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80,%ecx
  mov    $0x80,%edx
  mov    $0x44,%esi
  mov    $0xcd6,%edi
  call   <sio_mask@plt>
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x46,%esi
  mov    $0xcd6,%edi
  call   <sio_mask@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int board_hp_dl165_g6_enable(void) {
  sio_mask(0xcd6, 0x44, 0x80, 0x80);
  sio_mask(0xcd6, 0x46, 0x04, 0x04);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i2c_smbus_write_byte_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  lea    -0xc(%rbp),%rdi
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <i2c_smbus_access@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
__s32 i2c_smbus_write_byte_data(int file, __u8 command, __u8 value) {
  union i2c_smbus_data data;
  data.byte = value;
  return i2c_smbus_access(file, I2C_SMBUS_WRITE, command, I2C_SMBUS_BYTE_DATA, &data);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i2c_smbus_write_byte_data>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edx,0x4(%rsp)
  lea    0x4(%rsp),%r8
  mov    D11(%rip),%rax
  mov    (%rax),%ecx
  mov    %esi,%edx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  call   <i2c_smbus_access@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_write_byte_data(int file, __u8 command, __u8 value) {
  union i2c_smbus_data data;
  data.byte = value;
  return i2c_smbus_access(file, I2C_SMBUS_WRITE, command, I2C_SMBUS_BYTE_DATA, &data);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i2c_smbus_write_byte_data>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %edx,0x4(%rsp)
  mov    %esi,%edx
  lea    0x4(%rsp),%r8
  mov    (%rax),%ecx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  call   <i2c_smbus_access@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_write_byte_data(int file, __u8 command, __u8 value) {
  union i2c_smbus_data data;
  data.byte = value;
  return i2c_smbus_access(file, I2C_SMBUS_WRITE, command, I2C_SMBUS_BYTE_DATA, &data);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<i2c_smbus_write_byte_data>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %edx,0x4(%rsp)
  mov    %esi,%edx
  lea    0x4(%rsp),%r8
  mov    (%rax),%ecx
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  call   <i2c_smbus_access@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_write_byte_data(int file, __u8 command, __u8 value) {
  union i2c_smbus_data data;
  data.byte = value;
  return i2c_smbus_access(file, I2C_SMBUS_WRITE, command, I2C_SMBUS_BYTE_DATA, &data);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rop3_62_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x4(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_62_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: What is the c source code of the assembly code below?

```asm
<rop3_62_0_1>:
  endbr64
  mov    %edx,%eax
  mov    %esi,%r8d
  not    %r8d
  mov    %r8d,%ecx
  and    (%rdi),%cl
  or     %edx,%ecx
  xor    %esi,%ecx
  not    %edx
  or     %esi,%edx
  and    %ecx,%edx
  and    (%rdi),%al
  and    %eax,%r8d
  or     %r8d,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_62_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rop3_62_0_1>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %esi,%r8d
  mov    %edx,%eax
  and    (%rdi),%al
  not    %r8d
  and    %r8d,%ecx
  and    %eax,%r8d
  or     %edx,%ecx
  not    %edx
  xor    %esi,%ecx
  or     %esi,%edx
  and    %ecx,%edx
  or     %r8d,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_62_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_62_0_1>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %esi,%r8d
  mov    %edx,%eax
  and    (%rdi),%al
  not    %r8d
  and    %r8d,%ecx
  and    %eax,%r8d
  or     %edx,%ecx
  not    %edx
  xor    %esi,%ecx
  or     %esi,%edx
  and    %ecx,%edx
  or     %r8d,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_62_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_min_squence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L3:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L33
  addl   $0x1,-0x8(%rbp)
  jmp    L13
L33:
  cmpl   $0x0,-0x4(%rbp)
  jle    L67
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  add    %eax,-0x10(%rbp)
  jmp    L59
L67:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  add    %eax,-0xc(%rbp)
L59:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L79
  addl   $0x1,-0xc(%rbp)
L79:
  movl   $0x0,-0x8(%rbp)
L13:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L80
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L80
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
L80:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_min_squence(char *sequence, int sequence_length) {
  int i = 0, j = 1, k = 0, t;
  while (i < sequence_length && j < sequence_length && k < sequence_length) {
    t = sequence[i + k] - sequence[j + k];
    if (t == 0) {
      k++;
    } else {
      if (t > 0) {
        i += k + 1;
      } else {
        j += k + 1;
      }
      if (i == j)
        j++;
      k = 0;
    }
  }
  return i < j ? i : j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_min_squence>:
  endbr64
  mov    %rdi,%r9
  cmp    $0x1,%esi
  jle    L67
  mov    $0x0,%edx
  mov    $0x1,%edi
  mov    $0x0,%eax
  jmp    L51
L87:
  test   %ecx,%ecx
  jle    L36
  lea    0x1(%rax,%rdx,1),%eax
L14:
  mov    $0x0,%edx
  cmp    %edi,%eax
  je     L79
L58:
  cmp    %edi,%eax
  mov    %edi,%ecx
  cmovge %eax,%ecx
  cmp    %edx,%ecx
  cmovl  %edx,%ecx
  cmp    %ecx,%esi
  jle    L55
L51:
  lea    (%rax,%rdx,1),%ecx
  movslq %ecx,%rcx
  movsbl (%r9,%rcx,1),%ecx
  lea    (%rdi,%rdx,1),%r8d
  movslq %r8d,%r8
  movsbl (%r9,%r8,1),%r8d
  sub    %r8d,%ecx
  jne    L87
  add    $0x1,%edx
  jmp    L58
L36:
  lea    0x1(%rdi,%rdx,1),%edi
  jmp    L14
L79:
  add    $0x1,%edi
  jmp    L58
L67:
  mov    $0x1,%edi
  mov    $0x0,%eax
L55:
  cmp    %edi,%eax
  cmovg  %edi,%eax
  ret
```

assistant: ```c
int get_min_squence(char *sequence, int sequence_length) {
  int i = 0, j = 1, k = 0, t;
  while (i < sequence_length && j < sequence_length && k < sequence_length) {
    t = sequence[i + k] - sequence[j + k];
    if (t == 0) {
      k++;
    } else {
      if (t > 0) {
        i += k + 1;
      } else {
        j += k + 1;
      }
      if (i == j)
        j++;
      k = 0;
    }
  }
  return i < j ? i : j;
}
```