user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x88,%rsp
  movw   $0x7fff,-0x74(%rbp)
  movzwl -0x74(%rbp),%eax
  add    $0xa,%eax
  mov    %ax,-0x72(%rbp)
  filds  -0x72(%rbp)
  filds  -0x74(%rbp)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movl   $0x77359400,-0x70(%rbp)
  mov    -0x70(%rbp),%eax
  add    $0x3b9aca00,%eax
  mov    %eax,-0x6c(%rbp)
  fildl  -0x6c(%rbp)
  fildl  -0x70(%rbp)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movabs $0x7ce66c50e2840000,%rbx
  mov    %rbx,-0x60(%rbp)
  movabs $0xde0b6b3a7640000,%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x58(%rbp)
  fildll -0x58(%rbp)
  fildll -0x60(%rbp)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  mov    %rbx,-0x50(%rbp)
  movabs $0xde0b6b3a7640000,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x48(%rbp)
  fildll -0x48(%rbp)
  fildll -0x50(%rbp)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movss  D98(%rip),%xmm0
  movss  %xmm0,-0x68(%rbp)
  movss  -0x68(%rbp),%xmm0
  movss  D105(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x64(%rbp)
  flds   -0x68(%rbp)
  flds   -0x64(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movsd  D68(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  D33(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  fldl   -0x40(%rbp)
  fldl   -0x38(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  fldt   0xe1e(%rip)        # 20f0 <_fini+0xdcc>
  fstpt  -0x30(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  D33(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x88(%rbp)
  fldl   -0x88(%rbp)
  fstpt  -0x20(%rbp)
  push   -0x18(%rbp)
  push   -0x20(%rbp)
  push   -0x28(%rbp)
  push   -0x30(%rbp)
  lea    D86(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D17
type_infered: string
name: parse_data
arguments: tag: D85
type_infered: string
name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D98
type_infered: f32
name: parse_data
arguments: tag: D105
type_infered: f32
name: parse_data
arguments: tag: D34
type_infered: string
name: parse_data
arguments: tag: D68
type_infered: f64
name: parse_data
arguments: tag: D33
type_infered: f64
name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D86
type_infered: string

tool: D31: Short: %i + 10 = %i


tool: D17: Int: %i + 1000000000 = %i


tool: D85: Long: %li + 1000000000000000000 = %li


tool: D4: Long long: %lli + 1000000000000000000 = %lli


tool: D98: 1e-06

tool: D105: 2

tool: D34: Float: %f / 2 = %f


tool: D68: 3e-06

tool: D33: 4

tool: D18: Double: %f / 4 = %f


tool: D86: Long double: %Lf / 4 = %Lf


assistant: ```c
int main() {
  short shr = 32767;
  short shr2 = shr + 10;
  printf("Short: %i + 10 = %i\n", shr, shr2);
  int in = 2000000000;
  int in2 = in + 1000000000;
  printf("Int: %i + 1000000000 = %i\n", in, in2);
  long lg = 9000000000000000000;
  long lg2 = lg + 1000000000000000000;
  printf("Long: %li + 1000000000000000000 = %li\n", lg, lg2);
  long long llg = 9000000000000000000;
  long long llg2 = llg + 1000000000000000000;
  printf("Long long: %lli + 1000000000000000000 = %lli\n", llg, llg2);
  float fl = 0.000001;
  float fl2 = fl / 2.0;
  printf("Float: %f / 2 = %f\n", fl, fl2);
  double dl = 0.000003;
  double dl2 = dl / 4.0;
  printf("Double: %f / 4 = %f\n", dl, dl2);
  long double ldl = 0.00000000000000005;
  long double ldl2 = dl / 4.0;
  printf("Long double: %Lf / 4 = %Lf\n", ldl, ldl2);
  return 0;
}
```