user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x64,0x10(%rsp)
  movl   $0xc8,0x14(%rsp)
  movl   $0x12c,0x18(%rsp)
  movl   $0x190,0x1c(%rsp)
  movl   $0x1f4,0x20(%rsp)
  lea    0x10(%rsp),%rax
  mov    %rax,(%rsp)
  lea    0x18(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D124(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%rsi
  mov    %rsp,%r12
  mov    %r12,%rcx
  mov    (%rsi),%edx
  lea    D34(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%rbx
  lea    D98(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%rsi
  mov    0xc(%rsi),%edx
  add    $0x10,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x4,(%rsp)
  lea    D47(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%rsi
  mov    %r12,%rcx
  mov    (%rsi),%edx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subq   $0x4,0x8(%rsp)
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  lea    0x8(%rsp),%rcx
  mov    (%rsi),%edx
  lea    D126(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subq   $0x4,(%rsp)
  addq   $0x4,0x8(%rsp)
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdx
  mov    %rsi,%rcx
  sub    %rdx,%rcx
  sar    $0x2,%rcx
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D100(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rbx),%rdx
  lea    0x10(%rbx),%rsi
  lea    D51(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D124
type_infered: string
name: parse_data
arguments: tag: D34
type_infered: string
name: parse_data
arguments: tag: D98
type_infered: string
name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D47
type_infered: string
name: parse_data
arguments: tag: D35
type_infered: string
name: parse_data
arguments: tag: D126
type_infered: string
name: parse_data
arguments: tag: D7
type_infered: string
name: parse_data
arguments: tag: D46
type_infered: string
name: parse_data
arguments: tag: D39
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string
name: parse_data
arguments: tag: D100
type_infered: string
name: parse_data
arguments: tag: D51
type_infered: string

tool: D124: pointer value, dereferenced pointer, pointer address:

tool: D34: ptr1 = %p, *ptr1 = %d, &ptr1 = %p


tool: D98: 
adding an int to a pointer:

tool: D12: ptr1 + 4 = %p, *(ptr4+ 3) = %d


tool: D47: 
values after ptr1++

tool: D35: 
 values after ==ptr2

tool: D126: ptr2 = %p, *ptr2 = %d, &ptr2 = %p


tool: D7: 
Pointers reset to original values:

tool: D46: ptr1 = %p, ptr2 = %p


tool: D39: 
subtracting one pointer from another:

tool: D24: ptr2 = %p, ptr1 = %p, ptr2 - ptr1 = %d


tool: D100: 
subtracting an int from a pointer:

tool: D51: ptr3 = %p, ptr3 - 2 = %p


assistant: ```c
int main(void) {
  int urn[5] = {100, 200, 300, 400, 500};
  int *ptr1, *ptr2, *ptr3;
  ptr1 = urn;
  ptr2 = &urn[2];
  printf("pointer value, dereferenced pointer, pointer address:\n");
  printf("ptr1 = %p, *ptr1 = %d, &ptr1 = %p\n", ptr1, *ptr1, &ptr1);
  ptr3 = ptr1 + 4;
  printf("\nadding an int to a pointer:\n");
  printf("ptr1 + 4 = %p, *(ptr4+ 3) = %d\n", ptr1 + 4, *(ptr1 + 3));
  ptr1++;
  printf("\nvalues after ptr1++\n");
  printf("ptr1 = %p, *ptr1 = %d, &ptr1 = %p\n", ptr1, *ptr1, &ptr1);
  ptr2--;
  printf("\n values after ==ptr2\n");
  printf("ptr2 = %p, *ptr2 = %d, &ptr2 = %p\n", ptr2, *ptr2, &ptr2);
  --ptr1;
  ++ptr2;
  printf("\nPointers reset to original values:\n");
  printf("ptr1 = %p, ptr2 = %p\n", ptr1, ptr2);
  printf("\nsubtracting one pointer from another:\n");
  printf("ptr2 = %p, ptr1 = %p, ptr2 - ptr1 = %d\n", ptr2, ptr1, ptr2 - ptr1);
  printf("\nsubtracting an int from a pointer:\n");
  printf("ptr3 = %p, ptr3 - 2 = %p\n", ptr3, ptr3 - 2);
  return 0;
}
```