ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<touch_realloc>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <realloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L0
  movslq %ebx,%rdx
  mov    $0x61,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L0:
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *touch_realloc(char *ptr, int size) {
  char *result;
  int i;
  result = realloc(ptr, size);
  for (i = 0; i < size; i++)
    *(result + i) = 'a';
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CalcFlow>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,%r12
  mov    %rdx,0x8(%rsp)
  mov    %rcx,(%rsp)
  cmpq   $0x0,(%rsi)
  je     L85
L2:
  mov    0x8(%rsp),%rax
  cmp    $0x1,%rax
  jle    L54
  mov    0x18(%rsp),%rbp
  sub    $0x1,%rax
  mov    %rax,0x10(%rsp)
  mov    (%rsp),%rax
  lea    (%rax,%rax,1),%r14
  mov    $0x0,%r15d
  jmp    L95
L85:
  mov    $0x2,%ecx
  mov    $0x8,%edx
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <Get2DRowColMem@plt>
  mov    %rax,(%r12)
  jmp    L2
L57:
  mov    0x0(%rbp),%rdx
  mov    0x8(%rbp),%rax
  movss  (%rdx,%rbx,2),%xmm0
  subss  (%rax,%rbx,2),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D12(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <LRound@plt>
  mov    %rax,%rdx
  mov    (%r12),%rax
  mov    (%rax,%r13,1),%rax
  mov    %dx,(%rax,%rbx,1)
  add    $0x2,%rbx
  cmp    %r14,%rbx
  jne    L57
L62:
  add    $0x1,%r15
  add    $0x8,%rbp
  cmp    0x10(%rsp),%r15
  je     L54
L95:
  lea    0x0(,%r15,8),%r13
  mov    $0x0,%ebx
  cmpq   $0x0,(%rsp)
  jg     L57
  jmp    L62
L54:
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  jle    L64
  mov    0x18(%rsp),%rcx
  mov    %rcx,%rbp
  shl    $0x3,%rax
  sub    %rcx,%rax
  mov    %rax,0x10(%rsp)
  mov    (%rsp),%rax
  lea    -0x2(%rax,%rax,1),%r14
  mov    $0x0,%r15d
  jmp    L12
L69:
  mov    0x0(%rbp),%rax
  movss  0x4(%rax,%rbx,2),%xmm0
  subss  (%rax,%rbx,2),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D12(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <LRound@plt>
  mov    %rax,%rdx
  mov    (%r12),%rax
  mov    (%rax,%r13,1),%rax
  mov    %dx,(%rax,%rbx,1)
  add    $0x2,%rbx
  cmp    %r14,%rbx
  jne    L69
L58:
  add    $0x1,%r15
  add    $0x8,%rbp
  cmp    %r15,0x8(%rsp)
  je     L64
L12:
  mov    0x10(%rsp),%rax
  lea    -0x8(%rax,%rbp,1),%r13
  mov    $0x0,%ebx
  cmpq   $0x1,(%rsp)
  jg     L69
  jmp    L58
L64:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: f64

tool: D12: 6.283185307179586

assistant: ```c
void CalcFlow(float **phase, short ***flowsptr, long nrow, long ncol) {
  long row, col;
  if ((*flowsptr) == NULL) {
    (*flowsptr) = (short **)Get2DRowColMem(nrow, ncol, sizeof(short *), sizeof(short));
  }
  for (row = 0; row < nrow - 1; row++) {
    for (col = 0; col < ncol; col++) {
      (*flowsptr)[row][col] = (short)LRound((phase[row][col] - phase[row + 1][col]) / 6.28318530717958647692);
    }
  }
  for (row = 0; row < nrow; row++) {
    for (col = 0; col < ncol - 1; col++) {
      (*flowsptr)[nrow - 1 + row][col] = (short)LRound((phase[row][col + 1] - phase[row][col]) / 6.28318530717958647692);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CalcFlow>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmpq   $0x0,(%rsi)
  mov    %rdi,0x18(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rcx,(%rsp)
  je     L31
L66:
  mov    0x8(%rsp),%rax
  sub    $0x1,%rax
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  jle    L13
  mov    (%rsp),%rax
  mov    0x18(%rsp),%r14
  xor    %r12d,%r12d
  lea    (%rax,%rax,1),%rbp
L72:
  xor    %r15d,%r15d
  cmpq   $0x0,(%rsp)
  lea    0x0(,%r12,8),%rbx
  jle    L56
  nopw   0x0(%rax,%rax,1)
L94:
  mov    (%r14),%rsi
  mov    0x8(%r14),%rax
  movss  (%rsi,%r15,2),%xmm0
  subss  (%rax,%r15,2),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D18(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <LRound@plt>
  mov    %rax,%r9
  mov    0x0(%r13),%rax
  mov    (%rax,%rbx,1),%rax
  mov    %r9w,(%rax,%r15,1)
  add    $0x2,%r15
  cmp    %r15,%rbp
  jne    L94
L56:
  add    $0x1,%r12
  add    $0x8,%r14
  cmp    0x10(%rsp),%r12
  jne    L72
L13:
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  jle    L21
  mov    0x18(%rsp),%r14
  lea    0x0(,%rax,8),%r15
  xor    %r12d,%r12d
  mov    (%rsp),%rax
  sub    %r14,%r15
  lea    -0x2(%rax,%rax,1),%rbp
  mov    %r15,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L23:
  mov    0x10(%rsp),%rax
  xor    %r15d,%r15d
  cmpq   $0x1,(%rsp)
  lea    -0x8(%rax,%r14,1),%rbx
  jle    L7
  nopl   0x0(%rax)
L59:
  mov    (%r14),%rax
  movss  0x4(%rax,%r15,2),%xmm0
  subss  (%rax,%r15,2),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D18(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <LRound@plt>
  mov    %rax,%r9
  mov    0x0(%r13),%rax
  mov    (%rax,%rbx,1),%rax
  mov    %r9w,(%rax,%r15,1)
  add    $0x2,%r15
  cmp    %rbp,%r15
  jne    L59
L7:
  add    $0x1,%r12
  add    $0x8,%r14
  cmp    %r12,0x8(%rsp)
  jne    L23
L21:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  mov    $0x2,%ecx
  mov    $0x8,%edx
  call   <Get2DRowColMem@plt>
  mov    %rax,0x0(%r13)
  jmp    L66
```

tool_calls: name: unpack_data
arguments: label: D18
type: f64

tool: D18: 6.283185307179586

assistant: ```c
void CalcFlow(float **phase, short ***flowsptr, long nrow, long ncol) {
  long row, col;
  if ((*flowsptr) == NULL) {
    (*flowsptr) = (short **)Get2DRowColMem(nrow, ncol, sizeof(short *), sizeof(short));
  }
  for (row = 0; row < nrow - 1; row++) {
    for (col = 0; col < ncol; col++) {
      (*flowsptr)[row][col] = (short)LRound((phase[row][col] - phase[row + 1][col]) / 6.28318530717958647692);
    }
  }
  for (row = 0; row < nrow; row++) {
    for (col = 0; col < ncol - 1; col++) {
      (*flowsptr)[nrow - 1 + row][col] = (short)LRound((phase[row][col + 1] - phase[row][col]) / 6.28318530717958647692);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<CalcFlow>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  cmpq   $0x0,(%rsi)
  mov    %rdi,0x28(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x20(%rsp)
  je     L33
L32:
  mov    0x10(%rsp),%rax
  sub    $0x1,%rax
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  jle    L52
  mov    0x20(%rsp),%rax
  test   %rax,%rax
  jle    L52
  movsd  D7(%rip),%xmm3
  mov    0x28(%rsp),%r15
  lea    (%rax,%rax,1),%rbp
  xor    %r12d,%r12d
  movsd  %xmm3,0x8(%rsp)
  nopl   0x0(%rax)
L18:
  lea    0x0(,%r12,8),%rbx
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L78:
  mov    (%r15),%rsi
  mov    0x8(%r15),%rax
  movss  (%rsi,%r14,2),%xmm0
  subss  (%rax,%r14,2),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  0x8(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <LRound@plt>
  mov    %rax,%r9
  mov    0x0(%r13),%rax
  mov    (%rax,%rbx,1),%rax
  mov    %r9w,(%rax,%r14,1)
  add    $0x2,%r14
  cmp    %r14,%rbp
  jne    L78
  add    $0x1,%r12
  add    $0x8,%r15
  cmp    0x18(%rsp),%r12
  jne    L18
L52:
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  jle    L66
  mov    0x20(%rsp),%rdx
  cmp    $0x1,%rdx
  jle    L66
  mov    0x28(%rsp),%r14
  shl    $0x3,%rax
  lea    -0x2(%rdx,%rdx,1),%rbp
  xor    %r12d,%r12d
  movsd  D7(%rip),%xmm4
  sub    %r14,%rax
  sub    $0x8,%rax
  movsd  %xmm4,0x8(%rsp)
  mov    %rax,0x18(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    0x18(%rsp),%rax
  xor    %r15d,%r15d
  lea    (%rax,%r14,1),%rbx
  nopl   0x0(%rax)
L85:
  mov    (%r14),%rax
  movss  0x4(%rax,%r15,2),%xmm0
  subss  (%rax,%r15,2),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  0x8(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <LRound@plt>
  mov    %rax,%r9
  mov    0x0(%r13),%rax
  mov    (%rax,%rbx,1),%rax
  mov    %r9w,(%rax,%r15,1)
  add    $0x2,%r15
  cmp    %r15,%rbp
  jne    L85
  add    $0x1,%r12
  add    $0x8,%r14
  cmp    %r12,0x10(%rsp)
  jne    L24
L66:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  mov    $0x2,%ecx
  mov    $0x8,%edx
  call   <Get2DRowColMem@plt>
  mov    %rax,0x0(%r13)
  jmp    L32
```

tool_calls: name: read_data
arguments: tag: D7
datatype: f64

tool: D7: 6.283185307179586

assistant: ```c
void CalcFlow(float **phase, short ***flowsptr, long nrow, long ncol) {
  long row, col;
  if ((*flowsptr) == NULL) {
    (*flowsptr) = (short **)Get2DRowColMem(nrow, ncol, sizeof(short *), sizeof(short));
  }
  for (row = 0; row < nrow - 1; row++) {
    for (col = 0; col < ncol; col++) {
      (*flowsptr)[row][col] = (short)LRound((phase[row][col] - phase[row + 1][col]) / 6.28318530717958647692);
    }
  }
  for (row = 0; row < nrow; row++) {
    for (col = 0; col < ncol - 1; col++) {
      (*flowsptr)[nrow - 1 + row][col] = (short)LRound((phase[row][col + 1] - phase[row][col]) / 6.28318530717958647692);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<isdecint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L17
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L17
  movl   $0x1,-0xc(%rbp)
  jmp    L0
L17:
  addq   $0x1,-0x8(%rbp)
  jmp    L35
L50:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L15
  movl   $0x1,-0xc(%rbp)
L15:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
L0:
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int isdecint(char *s) {
  int badch = 0;
  char *c = s;
  if (!(isdigit(*c) || *c == '+' || *c == '-'))
    badch = 1;
  else
    for (c++; *c; c++)
      if (!isdigit(*c))
        badch = 1;
  return (!badch);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isdecint>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L22
  movzbl (%r12),%eax
  sub    $0x2b,%eax
  mov    $0x1,%ebp
  test   $0xfd,%al
  jne    L21
L22:
  lea    0x1(%r12),%rbx
  movzbl 0x1(%r12),%edi
  test   %dil,%dil
  je     L37
  mov    $0x0,%ebp
  mov    $0x1,%r12d
L29:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  cmove  %r12d,%ebp
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L29
L21:
  test   %ebp,%ebp
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    $0x0,%ebp
  jmp    L21
```

assistant: ```c
int isdecint(char *s) {
  int badch = 0;
  char *c = s;
  if (!(isdigit(*c) || *c == '+' || *c == '-'))
    badch = 1;
  else
    for (c++; *c; c++)
      if (!isdigit(*c))
        badch = 1;
  return (!badch);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isdecint>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L36
  movzbl 0x0(%rbp),%eax
  lea    -0x2b(%rax),%edx
  xor    %eax,%eax
  and    $0xfd,%edx
  jne    L1
L36:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rbx
  test   %dil,%dil
  je     L34
  xor    %ebp,%ebp
  mov    $0x1,%r12d
  xchg   %ax,%ax
L35:
  call   <isdigit@plt>
  test   %rax,%rax
  cmove  %r12d,%ebp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L35
  mov    %ebp,%eax
  xor    $0x1,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%eax
  jmp    L1
```

assistant: ```c
int isdecint(char *s) {
  int badch = 0;
  char *c = s;
  if (!(isdigit(*c) || *c == '+' || *c == '-'))
    badch = 1;
  else
    for (c++; *c; c++)
      if (!isdigit(*c))
        badch = 1;
  return (!badch);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isdecint>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L12
  movzbl 0x0(%rbp),%eax
  lea    -0x2b(%rax),%edx
  xor    %eax,%eax
  and    $0xfd,%edx
  jne    L35
L12:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rbx
  test   %dil,%dil
  je     L9
  xor    %ebp,%ebp
  mov    $0x1,%r12d
  xchg   %ax,%ax
L20:
  call   <isdigit@plt>
  test   %rax,%rax
  cmove  %r12d,%ebp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L20
  mov    %ebp,%eax
  xor    $0x1,%eax
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
  jmp    L35
```

assistant: ```c
int isdecint(char *s) {
  int badch = 0;
  char *c = s;
  if (!(isdigit(*c) || *c == '+' || *c == '-'))
    badch = 1;
  else
    for (c++; *c; c++)
      if (!isdigit(*c))
        badch = 1;
  return (!badch);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400,%edi
  call   <run_valid@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  run_valid(1024);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <run_valid@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  run_valid(1024);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <run_valid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  run_valid(1024);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <run_valid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  run_valid(1024);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arr_subdiagonal_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L9
L6:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <mat_to_arr@plt>
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jbe    L6
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long arr_subdiagonal_sum(int *arr, unsigned int dism, unsigned int length) {
  long long res = 0;
  for (unsigned int i = 1; i <= dism; i++)
    res += arr[mat_to_arr(dism - i + 1, i, dism)];
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arr_subdiagonal_sum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L7
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  lea    0x1(%rsi),%r14d
L23:
  mov    %r14d,%edi
  sub    %ebx,%edi
  mov    %ebp,%edx
  mov    %ebx,%esi
  call   <mat_to_arr@plt>
  movslq 0x0(%r13,%rax,4),%rax
  add    %rax,%r12
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jae    L23
L26:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    $0x0,%r12d
  jmp    L26
```

assistant: ```c
long long arr_subdiagonal_sum(int *arr, unsigned int dism, unsigned int length) {
  long long res = 0;
  for (unsigned int i = 1; i <= dism; i++)
    res += arr[mat_to_arr(dism - i + 1, i, dism)];
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arr_subdiagonal_sum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L11
  mov    %rdi,%r13
  mov    %esi,%ebp
  lea    0x1(%rsi),%r14d
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L2:
  mov    %r14d,%edi
  mov    %ebx,%esi
  mov    %ebp,%edx
  sub    %ebx,%edi
  add    $0x1,%ebx
  call   <mat_to_arr@plt>
  movslq 0x0(%r13,%rax,4),%rax
  add    %rax,%r12
  cmp    %ebx,%ebp
  jae    L2
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
long long arr_subdiagonal_sum(int *arr, unsigned int dism, unsigned int length) {
  long long res = 0;
  for (unsigned int i = 1; i <= dism; i++)
    res += arr[mat_to_arr(dism - i + 1, i, dism)];
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arr_subdiagonal_sum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L4
  mov    %rdi,%r13
  mov    %esi,%ebp
  lea    0x1(%rsi),%r14d
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L17:
  mov    %r14d,%edi
  mov    %ebx,%esi
  mov    %ebp,%edx
  sub    %ebx,%edi
  add    $0x1,%ebx
  call   <mat_to_arr@plt>
  movslq 0x0(%r13,%rax,4),%rax
  add    %rax,%r12
  cmp    %ebx,%ebp
  jae    L17
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L4:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
long long arr_subdiagonal_sum(int *arr, unsigned int dism, unsigned int length) {
  long long res = 0;
  for (unsigned int i = 1; i <= dism; i++)
    res += arr[mat_to_arr(dism - i + 1, i, dism)];
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_for_collision>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L31
L0:
  cmpl   $0x0,-0x8(%rbp)
  je     L39
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%edi
  call   <is_square_empty@plt>
  test   %eax,%eax
  jne    L53
  mov    $0x1,%eax
  jmp    L22
L39:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    -0x28(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <is_square_empty@plt>
  test   %eax,%eax
  jne    L53
  mov    $0x1,%eax
  jmp    L22
L53:
  addl   $0x1,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L0
  movl   $0x1,-0xc(%rbp)
  jmp    L19
L103:
  cmpl   $0x0,-0x4(%rbp)
  je     L52
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <is_square_empty@plt>
  test   %eax,%eax
  jne    L110
  mov    $0x1,%eax
  jmp    L22
L52:
  mov    -0x18(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <is_square_empty@plt>
  test   %eax,%eax
  jne    L110
  mov    $0x1,%eax
  jmp    L22
L110:
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L103
  mov    $0x0,%eax
L22:
  leave
  ret
```

assistant: ```c
int check_for_collision(int x1, int y1, int x2, int y2, int **board) {
  int deltaX = x2 - x1;
  int deltaY = y2 - y1;
  for (int i = 1; i <= deltaX; i++) {
    if (deltaX) {
      if (!(is_square_empty(x1 + i, y1 + (deltaY / deltaX) * i, board))) {
        return 1;
      }
    } else {
      if (!(is_square_empty(x1 - i, y1 + (deltaY / deltaX) * i, board))) {
        return 1;
      }
    }
  }
  for (int j = 1; j <= deltaY; j++) {
    if (deltaY) {
      if (!(is_square_empty(x1, y1 + j, board))) {
        return 1;
      }
    } else {
      if (!(is_square_empty(x1, y1 - j, board))) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_for_collision>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,0xc(%rsp)
  mov    %r8,%r13
  sub    %edi,%edx
  sub    %esi,%ecx
  mov    %ecx,%r15d
  test   %edx,%edx
  jle    L59
  mov    %edx,%r14d
  mov    %ecx,%eax
  cltd
  idiv   %r14d
  mov    %eax,0x8(%rsp)
  add    %esi,%eax
  mov    %eax,%ebp
  mov    $0x1,%ebx
L85:
  lea    (%rbx,%r12,1),%edi
  mov    %r13,%rdx
  mov    %ebp,%esi
  call   <is_square_empty@plt>
  test   %eax,%eax
  je     L45
  add    $0x1,%ebx
  add    0x8(%rsp),%ebp
  cmp    %ebx,%r14d
  jge    L85
L59:
  test   %r15d,%r15d
  jle    L62
  mov    $0x1,%ebx
L79:
  mov    0xc(%rsp),%eax
  lea    (%rax,%rbx,1),%esi
  mov    %r13,%rdx
  mov    %r12d,%edi
  call   <is_square_empty@plt>
  test   %eax,%eax
  je     L18
  add    $0x1,%ebx
  cmp    %ebx,%r15d
  jge    L79
  mov    $0x0,%eax
  jmp    L31
L45:
  mov    $0x1,%eax
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  mov    $0x0,%eax
  jmp    L31
L18:
  mov    $0x1,%eax
  jmp    L31
```

assistant: ```c
int check_for_collision(int x1, int y1, int x2, int y2, int **board) {
  int deltaX = x2 - x1;
  int deltaY = y2 - y1;
  for (int i = 1; i <= deltaX; i++) {
    if (deltaX) {
      if (!(is_square_empty(x1 + i, y1 + (deltaY / deltaX) * i, board))) {
        return 1;
      }
    } else {
      if (!(is_square_empty(x1 - i, y1 + (deltaY / deltaX) * i, board))) {
        return 1;
      }
    }
  }
  for (int j = 1; j <= deltaY; j++) {
    if (deltaY) {
      if (!(is_square_empty(x1, y1 + j, board))) {
        return 1;
      }
    } else {
      if (!(is_square_empty(x1, y1 - j, board))) {
        return 1;
      }
    }
  }
  return 0;
}
```