ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<_doc_normal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %rcx,-0x58(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D9(%rip),%rax
  movslq (%rax),%rax
  mov    %rax,%r15
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L27
L58:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L58
L27:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L69
L113:
  movq   $0x0,-0x48(%rbp)
  mov    %rsp,%r13
  jmp    L129
  nopl   (%rax)
L24:
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  cmp    %r12,%rax
  jne    L138
  add    %rax,-0x48(%rbp)
L129:
  mov    %r14,%rcx
  mov    %r15d,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L24
  mov    %r14,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L29
L44:
  mov    -0x48(%rbp),%r12
  mov    $0x200,%r13d
  and    $0x1ff,%r12d
  sub    %r12,%r13
  nop
L107:
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <fputc@plt>
  test   %al,%al
  jne    L37
  sub    $0x1,%r13
  jne    L107
  xor    %eax,%eax
L57:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L137
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L138:
  mov    -0x50(%rbp),%rdi
  mov    $0x1,%esi
  call   <_tar_error@plt>
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L37:
  mov    -0x50(%rbp),%rdi
  mov    $0x1,%esi
  call   <_tar_error@plt>
  jmp    L57
L69:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L113
L29:
  mov    -0x58(%rbp),%rdi
  mov    $0x1,%esi
  call   <_tar_error@plt>
  jmp    L57
L137:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _doc_normal(FILE *fp, char const *archive, FILE *fp2, char const *filename) {
  int ret = 0;
  size_t read;
  size_t cnt;
  char buf[BUFSIZ];
  for (cnt = 0; (read = fread(buf, sizeof(*buf), sizeof(buf), fp2)) != 0; cnt += read)
    if (fwrite(buf, sizeof(*buf), read, fp) != read) {
      ret = _tar_error(archive, 1);
      break;
    }
  if (ret == 0 && read == 0 && !feof(fp2))
    return _tar_error(filename, 1);
  for (cnt = 512 - (cnt % 512); cnt > 0 && fputc('\0', fp) == '\0'; cnt--)
    ;
  return (cnt == 0) ? 0 : _tar_error(archive, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<to_nit_file_stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  leave
  ret
```

assistant: ```c
void *to_nit_file_stat(struct stat *st) {
  struct stat *stat_element;
  stat_element = malloc(sizeof(struct stat));
  return memcpy(stat_element, st, sizeof(struct stat));
}
```
user: Translate the below assembly code into C programming language:

```asm
<to_nit_file_stat>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x4,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *to_nit_file_stat(struct stat *st) {
  struct stat *stat_element;
  stat_element = malloc(sizeof(struct stat));
  return memcpy(stat_element, st, sizeof(struct stat));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<to_nit_file_stat>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    $0x4,%edx
  pop    %rbp
  mov    %rax,%rdi
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void *to_nit_file_stat(struct stat *st) {
  struct stat *stat_element;
  stat_element = malloc(sizeof(struct stat));
  return memcpy(stat_element, st, sizeof(struct stat));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<to_nit_file_stat>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    $0x4,%edx
  pop    %rbp
  mov    %rax,%rdi
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void *to_nit_file_stat(struct stat *st) {
  struct stat *stat_element;
  stat_element = malloc(sizeof(struct stat));
  return memcpy(stat_element, st, sizeof(struct stat));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<handle_req>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    $0x400,%edi
  call   <safe_malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jns    L0
  mov    -0x1c(%rbp),%eax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <server_error@plt>
  jmp    L8
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_get@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  jmp    L31
L25:
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write_client@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L8:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L31:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string

tool: D14: reading from client

tool: D11: not a GET request


assistant: ```c
void *handle_req(void *socket) {
  int sock = *((int *)socket);
  char *buf = safe_malloc(1024);
  ssize_t bytes = read(sock, buf, 1024);
  if (bytes < 0)
    server_error(sock, "reading from client");
  else {
    char *file = parse_get(buf);
    if (file == NULL) {
      printf("not a GET request\n");
      free(file);
      close(sock);
      return NULL;
    }
    write_client(sock, file);
    free(file);
  }
  close(sock);
  free(buf);
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<handle_req>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%ebp
  mov    $0x400,%edi
  call   <safe_malloc@plt>
  mov    %rax,%rbx
  mov    $0x400,%edx
  mov    %rax,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  js     L9
  mov    %rbx,%rdi
  call   <parse_get@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rax,%rsi
  mov    %ebp,%edi
  call   <write_client@plt>
  mov    %r12,%rdi
  call   <free@plt>
L11:
  mov    %ebp,%edi
  call   <close@plt>
  mov    %rbx,%rdi
  call   <free@plt>
L22:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  lea    D19(%rip),%rsi
  mov    %ebp,%edi
  call   <server_error@plt>
  jmp    L11
L6:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <free@plt>
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L22
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D4
datatype: string

tool: D19: reading from client

tool: D4: not a GET request


assistant: ```c
void *handle_req(void *socket) {
  int sock = *((int *)socket);
  char *buf = safe_malloc(1024);
  ssize_t bytes = read(sock, buf, 1024);
  if (bytes < 0)
    server_error(sock, "reading from client");
  else {
    char *file = parse_get(buf);
    if (file == NULL) {
      printf("not a GET request\n");
      free(file);
      close(sock);
      return NULL;
    }
    write_client(sock, file);
    free(file);
  }
  close(sock);
  free(buf);
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<handle_req>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    (%rdi),%r12d
  mov    $0x400,%edi
  call   <safe_malloc@plt>
  mov    $0x400,%edx
  mov    %r12d,%edi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <read@plt>
  test   %rax,%rax
  js     L11
  mov    %rbp,%rdi
  call   <parse_get@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L10
  mov    %r12d,%edi
  mov    %rax,%rsi
  call   <write_client@plt>
  mov    %r13,%rdi
  call   <free@plt>
L4:
  mov    %r12d,%edi
  call   <close@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  lea    D11(%rip),%rsi
  mov    %r12d,%edi
  call   <server_error@plt>
  jmp    L4
  nopl   0x0(%rax)
L10:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <free@plt>
  mov    %r12d,%edi
  call   <close@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D11: reading from client

tool: D4: not a GET request


assistant: ```c
void *handle_req(void *socket) {
  int sock = *((int *)socket);
  char *buf = safe_malloc(1024);
  ssize_t bytes = read(sock, buf, 1024);
  if (bytes < 0)
    server_error(sock, "reading from client");
  else {
    char *file = parse_get(buf);
    if (file == NULL) {
      printf("not a GET request\n");
      free(file);
      close(sock);
      return NULL;
    }
    write_client(sock, file);
    free(file);
  }
  close(sock);
  free(buf);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<handle_req>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    (%rdi),%r12d
  mov    $0x400,%edi
  call   <safe_malloc@plt>
  mov    $0x400,%edx
  mov    %r12d,%edi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <read@plt>
  test   %rax,%rax
  js     L19
  mov    %rbp,%rdi
  call   <parse_get@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L11
  mov    %r12d,%edi
  mov    %rax,%rsi
  call   <write_client@plt>
  mov    %r13,%rdi
  call   <free@plt>
L10:
  mov    %r12d,%edi
  call   <close@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  lea    D5(%rip),%rsi
  mov    %r12d,%edi
  call   <server_error@plt>
  jmp    L10
  nopl   0x0(%rax)
L11:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <free@plt>
  mov    %r12d,%edi
  call   <close@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string

tool: D5: reading from client

tool: D9: not a GET request


assistant: ```c
void *handle_req(void *socket) {
  int sock = *((int *)socket);
  char *buf = safe_malloc(1024);
  ssize_t bytes = read(sock, buf, 1024);
  if (bytes < 0)
    server_error(sock, "reading from client");
  else {
    char *file = parse_get(buf);
    if (file == NULL) {
      printf("not a GET request\n");
      free(file);
      close(sock);
      return NULL;
    }
    write_client(sock, file);
    free(file);
  }
  close(sock);
  free(buf);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<allocate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <getparam@plt>
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <error@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D12: argv0

tool: D7: allocate in %s: not enuf memory (%d bytes)


assistant: ```c
void *allocate(int nb) {
  void *mem;
  mem = calloc(nb, 1);
  if (mem == 0L)
    error("allocate in %s: not enuf memory (%d bytes)\n", (getparam("argv0")), nb);
  return (mem);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<allocate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  movslq %edi,%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <getparam@plt>
  mov    %eax,%esi
  mov    %ebp,%edx
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L7
```

tool_calls: name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: string

tool: D13: argv0

tool: D12: allocate in %s: not enuf memory (%d bytes)


assistant: ```c
void *allocate(int nb) {
  void *mem;
  mem = calloc(nb, 1);
  if (mem == 0L)
    error("allocate in %s: not enuf memory (%d bytes)\n", (getparam("argv0")), nb);
  return (mem);
}
```
user: Translate the below assembly code into C programming language:

```asm
<allocate>:
  endbr64
  push   %r13
  movslq %edi,%rdi
  mov    $0x1,%esi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L0:
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <getparam@plt>
  mov    %r13d,%edx
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <error@plt>
  jmp    L13
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string
name: read_data
arguments: data_label: D9
datatype: string

tool: D8: argv0

tool: D9: allocate in %s: not enuf memory (%d bytes)


assistant: ```c
void *allocate(int nb) {
  void *mem;
  mem = calloc(nb, 1);
  if (mem == 0L)
    error("allocate in %s: not enuf memory (%d bytes)\n", (getparam("argv0")), nb);
  return (mem);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<allocate>:
  endbr64
  push   %r13
  movslq %edi,%rdi
  mov    $0x1,%esi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L2:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <getparam@plt>
  mov    %r13d,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <error@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D14: argv0

tool: D3: allocate in %s: not enuf memory (%d bytes)


assistant: ```c
void *allocate(int nb) {
  void *mem;
  mem = calloc(nb, 1);
  if (mem == 0L)
    error("allocate in %s: not enuf memory (%d bytes)\n", (getparam("argv0")), nb);
  return (mem);
}
```
user: What is the c source code of the assembly code below:

```asm
<update>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x38(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L16:
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movsd  (%rax),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x0,-0x4(%rbp)
  jne    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void update(double *vec1, int beg, int end, double *vec2, double fac, double *vec3) {
  int i;
  vec1 += beg;
  vec2 += beg;
  vec3 += beg;
  for (i = end - beg + 1; i; i--) {
    (*vec1++) = (*vec2++) + fac * (*vec3++);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<update>:
  endbr64
  movslq %esi,%rax
  shl    $0x3,%rax
  add    %rax,%rdi
  add    %rax,%rcx
  add    %rax,%r8
  sub    %esi,%edx
  cmp    $0xffffffff,%edx
  je     L2
  lea    0x1(%rdx),%edx
  shl    $0x3,%rdx
  mov    $0x0,%eax
L19:
  movapd %xmm0,%xmm1
  mulsd  (%r8,%rax,1),%xmm1
  addsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L19
L2:
  ret
```

assistant: ```c
void update(double *vec1, int beg, int end, double *vec2, double fac, double *vec3) {
  int i;
  vec1 += beg;
  vec2 += beg;
  vec3 += beg;
  for (i = end - beg + 1; i; i--) {
    (*vec1++) = (*vec2++) + fac * (*vec3++);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<update>:
  endbr64
  movslq %esi,%rax
  sub    %esi,%edx
  shl    $0x3,%rax
  add    %rax,%rdi
  add    %rax,%rcx
  add    %rax,%r8
  cmp    $0xffffffff,%edx
  je     L1
  add    $0x1,%edx
  xor    %eax,%eax
  shl    $0x3,%rdx
  nopl   0x0(%rax)
L12:
  movsd  (%r8,%rax,1),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L12
L1:
  ret
```

assistant: ```c
void update(double *vec1, int beg, int end, double *vec2, double fac, double *vec3) {
  int i;
  vec1 += beg;
  vec2 += beg;
  vec3 += beg;
  for (i = end - beg + 1; i; i--) {
    (*vec1++) = (*vec2++) + fac * (*vec3++);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<update>:
  endbr64
  movslq %esi,%rax
  mov    %rdi,%r9
  mov    %edx,%esi
  mov    %rcx,%r10
  mov    %rax,%rdi
  shl    $0x3,%rax
  sub    %edi,%esi
  lea    (%r9,%rax,1),%rdx
  lea    (%rcx,%rax,1),%rcx
  lea    (%r8,%rax,1),%r9
  cmp    $0xffffffff,%esi
  je     L12
  add    $0x8,%rax
  add    %rax,%r10
  cmp    %r10,%rdx
  setne  %dil
  add    %rax,%r8
  cmp    %r8,%rdx
  setne  %al
  test   %al,%dil
  je     L9
  cmp    $0x1,%esi
  jbe    L9
  add    $0x1,%esi
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  mov    %esi,%edi
  unpcklpd %xmm2,%xmm2
  shr    %edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L21:
  movupd (%r9,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm3
  mulpd  %xmm2,%xmm1
  addpd  %xmm3,%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L21
  mov    %esi,%edi
  and    $0xfffffffe,%edi
  mov    %edi,%eax
  shl    $0x3,%rax
  add    %rax,%rdx
  add    %rax,%rcx
  add    %r9,%rax
  cmp    %edi,%esi
  je     L12
  mulsd  (%rax),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rdx)
  ret
  nopl   (%rax)
L9:
  add    $0x1,%esi
  xor    %eax,%eax
  shl    $0x3,%rsi
  nopl   0x0(%rax)
L4:
  movsd  (%r9,%rax,1),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L4
L12:
  ret
```

assistant: ```c
void update(double *vec1, int beg, int end, double *vec2, double fac, double *vec3) {
  int i;
  vec1 += beg;
  vec2 += beg;
  vec3 += beg;
  for (i = end - beg + 1; i; i--) {
    (*vec1++) = (*vec2++) + fac * (*vec3++);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<change_to_lower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L14
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L14
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L14:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L38
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int change_to_lower(char *s, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (s[i] >= 'A' && s[i] <= 'Z')
      s[i] = s[i] - 'A' + 'a';
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<change_to_lower>:
  endbr64
  test   %esi,%esi
  jle    L11
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  jmp    L15
L31:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L11
L15:
  movzbl (%rax),%edx
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L31
  add    $0x20,%edx
  mov    %dl,(%rax)
  jmp    L31
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int change_to_lower(char *s, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (s[i] >= 'A' && s[i] <= 'Z')
      s[i] = s[i] - 'A' + 'a';
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<change_to_lower>:
  endbr64
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
L21:
  movzbl (%rdi),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L15
  add    $0x20,%eax
  mov    %al,(%rdi)
L15:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L21
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int change_to_lower(char *s, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (s[i] >= 'A' && s[i] <= 'Z')
      s[i] = s[i] - 'A' + 'a';
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<change_to_lower>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
L23:
  movzbl (%rdi),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L13
  add    $0x20,%eax
  mov    %al,(%rdi)
L13:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L23
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int change_to_lower(char *s, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (s[i] >= 'A' && s[i] <= 'Z')
      s[i] = s[i] - 'A' + 'a';
  }
  return 0;
}
```