ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D4: Usage: flat [options] GRAMMAR INPUT

Options:

  -b, --builtin   Use the built-in grammar instead of a user-supplied one
  -e, --exprtree  Print expressions as trees (only relevant if -g also given)
  -g, --grammar   Don't parse input; just show the grammar that would be used
  -h, --help      Print this message

Arguments:

  GRAMMAR         A file written in the Flat syntax that defines the syntax of
                  the language to be parsed. Should be omitted if -b is used.
  INPUT           A file written in the syntax of the language defined by
                  GRAMMAR. Should be omitted if -s is used.

Examples:

  flat -b -s      Print out the built-in grammar
  flat arithmetic.flat test.exp
                  Parse the file test.exp using the language defined in
                  arithmetic.flat


assistant: ```c
void usage(void) {
  printf("Usage: flat [options] GRAMMAR INPUT\n"
         "\n"
         "Options:\n"
         "\n"
         "  -b, --builtin   Use the built-in grammar instead of a user-supplied one\n"
         "  -e, --exprtree  Print expressions as trees (only relevant if -g also given)\n"
         "  -g, --grammar   Don't parse input; just show the grammar that would be used\n"
         "  -h, --help      Print this message\n"
         "\n"
         "Arguments:\n"
         "\n"
         "  GRAMMAR         A file written in the Flat syntax that defines the syntax of\n"
         "                  the language to be parsed. Should be omitted if -b is used.\n"
         "  INPUT           A file written in the syntax of the language defined by\n"
         "                  GRAMMAR. Should be omitted if -s is used.\n"
         "\n"
         "Examples:\n"
         "\n"
         "  flat -b -s      Print out the built-in grammar\n"
         "  flat arithmetic.flat test.exp\n"
         "                  Parse the file test.exp using the language defined in\n"
         "                  arithmetic.flat\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: Usage: flat [options] GRAMMAR INPUT

Options:

  -b, --builtin   Use the built-in grammar instead of a user-supplied one
  -e, --exprtree  Print expressions as trees (only relevant if -g also given)
  -g, --grammar   Don't parse input; just show the grammar that would be used
  -h, --help      Print this message

Arguments:

  GRAMMAR         A file written in the Flat syntax that defines the syntax of
                  the language to be parsed. Should be omitted if -b is used.
  INPUT           A file written in the syntax of the language defined by
                  GRAMMAR. Should be omitted if -s is used.

Examples:

  flat -b -s      Print out the built-in grammar
  flat arithmetic.flat test.exp
                  Parse the file test.exp using the language defined in
                  arithmetic.flat


assistant: ```c
void usage(void) {
  printf("Usage: flat [options] GRAMMAR INPUT\n"
         "\n"
         "Options:\n"
         "\n"
         "  -b, --builtin   Use the built-in grammar instead of a user-supplied one\n"
         "  -e, --exprtree  Print expressions as trees (only relevant if -g also given)\n"
         "  -g, --grammar   Don't parse input; just show the grammar that would be used\n"
         "  -h, --help      Print this message\n"
         "\n"
         "Arguments:\n"
         "\n"
         "  GRAMMAR         A file written in the Flat syntax that defines the syntax of\n"
         "                  the language to be parsed. Should be omitted if -b is used.\n"
         "  INPUT           A file written in the syntax of the language defined by\n"
         "                  GRAMMAR. Should be omitted if -s is used.\n"
         "\n"
         "Examples:\n"
         "\n"
         "  flat -b -s      Print out the built-in grammar\n"
         "  flat arithmetic.flat test.exp\n"
         "                  Parse the file test.exp using the language defined in\n"
         "                  arithmetic.flat\n");
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: Usage: flat [options] GRAMMAR INPUT

Options:

  -b, --builtin   Use the built-in grammar instead of a user-supplied one
  -e, --exprtree  Print expressions as trees (only relevant if -g also given)
  -g, --grammar   Don't parse input; just show the grammar that would be used
  -h, --help      Print this message

Arguments:

  GRAMMAR         A file written in the Flat syntax that defines the syntax of
                  the language to be parsed. Should be omitted if -b is used.
  INPUT           A file written in the syntax of the language defined by
                  GRAMMAR. Should be omitted if -s is used.

Examples:

  flat -b -s      Print out the built-in grammar
  flat arithmetic.flat test.exp
                  Parse the file test.exp using the language defined in
                  arithmetic.flat


assistant: ```c
void usage(void) {
  printf("Usage: flat [options] GRAMMAR INPUT\n"
         "\n"
         "Options:\n"
         "\n"
         "  -b, --builtin   Use the built-in grammar instead of a user-supplied one\n"
         "  -e, --exprtree  Print expressions as trees (only relevant if -g also given)\n"
         "  -g, --grammar   Don't parse input; just show the grammar that would be used\n"
         "  -h, --help      Print this message\n"
         "\n"
         "Arguments:\n"
         "\n"
         "  GRAMMAR         A file written in the Flat syntax that defines the syntax of\n"
         "                  the language to be parsed. Should be omitted if -b is used.\n"
         "  INPUT           A file written in the syntax of the language defined by\n"
         "                  GRAMMAR. Should be omitted if -s is used.\n"
         "\n"
         "Examples:\n"
         "\n"
         "  flat -b -s      Print out the built-in grammar\n"
         "  flat arithmetic.flat test.exp\n"
         "                  Parse the file test.exp using the language defined in\n"
         "                  arithmetic.flat\n");
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PrimeCounter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L21:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L15
  addl   $0x1,-0x8(%rbp)
L15:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int PrimeCounter(int arr[5], int size) {
  int count = 0;
  int i;
  for (i = 0; i < size; i++)
    if (isPrime(i))
      count++;
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PrimeCounter>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L13
  mov    %esi,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L4:
  mov    %ebx,%edi
  call   <isPrime@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L4
L21:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    $0x0,%ebp
  jmp    L21
```

assistant: ```c
int PrimeCounter(int arr[5], int size) {
  int count = 0;
  int i;
  for (i = 0; i < size; i++)
    if (isPrime(i))
      count++;
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PrimeCounter>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L10
  mov    %esi,%ebp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  call   <isPrime@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L4
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int PrimeCounter(int arr[5], int size) {
  int count = 0;
  int i;
  for (i = 0; i < size; i++)
    if (isPrime(i))
      count++;
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PrimeCounter>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L11
  mov    %esi,%ebp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  call   <isPrime@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L2
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int PrimeCounter(int arr[5], int size) {
  int count = 0;
  int i;
  for (i = 0; i < size; i++)
    if (isPrime(i))
      count++;
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L84
L41:
  addl   $0x1,-0xc(%rbp)
L84:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L41
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L21
  mov    $0xffffffff,%eax
  jmp    L60
L21:
  mov    $0x1,%eax
L60:
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L46
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L45
L46:
  addl   $0x1,-0xc(%rbp)
L45:
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L74:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L54
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L74
L54:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atoi(const char *s) {
  int i;
  for (i = 0; s[i] == ' '; i++)
    ;
  int sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  int n;
  for (n = 0; '0' <= s[i] && s[i] <= '9'; i++)
    n = 10 * n + (s[i] - '0');
  return sign * n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atoi>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  jne    L2
  mov    $0x1,%eax
L26:
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  je     L26
L18:
  cmp    $0x2d,%dl
  je     L10
  sub    $0x2b,%edx
  mov    $0x1,%eax
  test   $0xfd,%dl
  je     L71
L60:
  movslq %ecx,%rcx
  movzbl (%rdi,%rcx,1),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  ja     L48
  lea    0x1(%rdi,%rcx,1),%rsi
  mov    $0x0,%ecx
L22:
  lea    (%rcx,%rcx,4),%ecx
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rcx,2),%ecx
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  jbe    L22
L34:
  imul   %ecx,%eax
  ret
L2:
  mov    $0x0,%ecx
  jmp    L18
L10:
  mov    $0xffffffff,%eax
L71:
  add    $0x1,%ecx
  jmp    L60
L48:
  mov    $0x0,%ecx
  jmp    L34
```

assistant: ```c
int atoi(const char *s) {
  int i;
  for (i = 0; s[i] == ' '; i++)
    ;
  int sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  int n;
  for (n = 0; '0' <= s[i] && s[i] <= '9'; i++)
    n = 10 * n + (s[i] - '0');
  return sign * n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atoi>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  jne    L65
  mov    $0x1,%eax
  nopl   (%rax)
L55:
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  je     L55
L16:
  cmp    $0x2d,%dl
  je     L77
  mov    $0x1,%r8d
  cmp    $0x2b,%dl
  je     L14
  movslq %ecx,%rcx
  movzbl (%rdi,%rcx,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L51
L3:
  lea    0x1(%rdi,%rcx,1),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L34:
  sub    $0x30,%edx
  lea    (%rax,%rax,4),%eax
  add    $0x1,%rcx
  movsbl %dl,%edx
  lea    (%rdx,%rax,2),%eax
  movzbl -0x1(%rcx),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L34
  imul   %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L77:
  mov    $0xffffffff,%r8d
L14:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  movzbl (%rdi,%rcx,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L3
L51:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  xor    %ecx,%ecx
  jmp    L16
```

assistant: ```c
int atoi(const char *s) {
  int i;
  for (i = 0; s[i] == ' '; i++)
    ;
  int sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  int n;
  for (n = 0; '0' <= s[i] && s[i] <= '9'; i++)
    n = 10 * n + (s[i] - '0');
  return sign * n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<atoi>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  jne    L18
  mov    $0x1,%eax
  nopl   (%rax)
L9:
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  je     L9
L37:
  cmp    $0x2d,%dl
  je     L19
  mov    $0x1,%r8d
  cmp    $0x2b,%dl
  je     L5
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L60
L32:
  movslq %ecx,%rcx
  xor    %eax,%eax
  lea    0x1(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax)
L29:
  sub    $0x30,%edx
  lea    (%rax,%rax,4),%eax
  add    $0x1,%rcx
  movsbl %dl,%edx
  lea    (%rdx,%rax,2),%eax
  movzbl -0x1(%rcx),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L29
  imul   %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0xffffffff,%r8d
L5:
  add    $0x1,%ecx
  movslq %ecx,%rax
  movzbl (%rdi,%rax,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L32
L60:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %ecx,%ecx
  jmp    L37
```

assistant: ```c
int atoi(const char *s) {
  int i;
  for (i = 0; s[i] == ' '; i++)
    ;
  int sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  int n;
  for (n = 0; '0' <= s[i] && s[i] <= '9'; i++)
    n = 10 * n + (s[i] - '0');
  return sign * n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_proc_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int read_proc_table(int index) {
  int i, j, k, len, ret = 0;
  char *local_func, *local_proc;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_proc_table>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int read_proc_table(int index) {
  int i, j, k, len, ret = 0;
  char *local_func, *local_proc;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_proc_table>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int read_proc_table(int index) {
  int i, j, k, len, ret = 0;
  char *local_func, *local_proc;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_proc_table>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int read_proc_table(int index) {
  int i, j, k, len, ret = 0;
  char *local_func, *local_proc;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getupload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L60
L66:
  mov    -0x20(%rbp),%rax
  mov    $0x6,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strnccmp@plt>
  test   %eax,%eax
  jne    L60
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
L21:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L36:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L141
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L21
L141:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L8:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L142
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L8
L142:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L131
  jmp    L60
L187:
  addq   $0x1,-0x8(%rbp)
L131:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L187
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L187
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L185
  mov    -0x8(%rbp),%rax
  jmp    L87
L185:
  mov    $0x0,%eax
  jmp    L87
L60:
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L66
  mov    $0x0,%eax
L87:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: upload

assistant: ```c
char *getupload(FILE *fd, char *buf, int sz) {
  while (fgets(buf, sz, fd))
    if (!strnccmp(buf, "upload", 6)) {
      char *p;
      p = buf + strlen(buf);
      while (--p >= buf && (*p == ' ' || *p == '\r' || *p == '\n' || *p == '\t'))
        *p = 0;
      p = buf;
      while (*p && *p != ':')
        ++p;
      if (!*p++)
        continue;
      while (*p == ' ' || *p == '\t')
        ++p;
      return (*p ? p : 0);
    }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getupload>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  lea    D2(%rip),%r13
  movabs $0x100002600,%r14
L33:
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L165
  mov    $0x6,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strnccmp@plt>
  test   %eax,%eax
  jne    L33
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jbe    L158
  jmp    L140
L97:
  bt     %rdx,%r14
  jae    L140
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rax,%rbx
  ja     L140
L158:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jbe    L97
L140:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L41
  cmp    $0x3a,%al
  je     L41
  mov    %rbx,%rdx
L109:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L95
  cmp    $0x3a,%al
  jne    L109
L95:
  test   %al,%al
  je     L33
  lea    0x1(%rdx),%rax
  movzbl 0x1(%rdx),%edx
  cmp    $0x20,%dl
  je     L144
  cmp    $0x9,%dl
  jne    L151
L144:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L144
  cmp    $0x9,%dl
  je     L144
L151:
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %rdx,%rax
L165:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  mov    %rbx,%rdx
  jmp    L95
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: upload

assistant: ```c
char *getupload(FILE *fd, char *buf, int sz) {
  while (fgets(buf, sz, fd))
    if (!strnccmp(buf, "upload", 6)) {
      char *p;
      p = buf + strlen(buf);
      while (--p >= buf && (*p == ' ' || *p == '\r' || *p == '\n' || *p == '\t'))
        *p = 0;
      p = buf;
      while (*p && *p != ':')
        ++p;
      if (!*p++)
        continue;
      while (*p == ' ' || *p == '\t')
        ++p;
      return (*p ? p : 0);
    }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getupload>:
  endbr64
  push   %r14
  movabs $0xfffffffeffffd9ff,%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x6,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strnccmp@plt>
  test   %eax,%eax
  je     L27
L32:
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L12
L48:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L27:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  ja     L59
  nopl   0x0(%rax)
L24:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jbe    L2
L59:
  movzbl (%rbx),%eax
  cmp    $0x3a,%al
  je     L127
  mov    %rbx,%rdx
  test   %al,%al
  je     L127
  nopw   0x0(%rax,%rax,1)
L42:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L32
  cmp    $0x3a,%al
  jne    L42
L16:
  test   %al,%al
  je     L32
  lea    0x1(%rdx),%rax
  movzbl 0x1(%rdx),%edx
  cmp    $0x9,%dl
  je     L98
  cmp    $0x20,%dl
  jne    L21
  cs nopw 0x0(%rax,%rax,1)
L98:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L98
  cmp    $0x9,%dl
  je     L98
L21:
  test   %dl,%dl
  je     L48
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  bt     %rdx,%r14
  jb     L59
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jbe    L24
  jmp    L59
L127:
  mov    %rbx,%rdx
  jmp    L16
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: upload

assistant: ```c
char *getupload(FILE *fd, char *buf, int sz) {
  while (fgets(buf, sz, fd))
    if (!strnccmp(buf, "upload", 6)) {
      char *p;
      p = buf + strlen(buf);
      while (--p >= buf && (*p == ' ' || *p == '\r' || *p == '\n' || *p == '\t'))
        *p = 0;
      p = buf;
      while (*p && *p != ':')
        ++p;
      if (!*p++)
        continue;
      while (*p == ' ' || *p == '\t')
        ++p;
      return (*p ? p : 0);
    }
  return (0);
}
```