user: What is the c source code of the assembly code below?

```asm
<flvsep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <flvlen@plt>
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L18
L75:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdelimiter@plt>
  test   %rax,%rax
  jne    L95
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x24(%rbp)
L83:
  addl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L56
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdelimiter@plt>
  test   %rax,%rax
  je     L83
L56:
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  addl   $0x1,-0x2c(%rbp)
  jmp    L29
L95:
  addl   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdelimiter@plt>
  test   %rax,%rax
  jne    L95
L29:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L88
  addl   $0x1,-0x28(%rbp)
L18:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
  jmp    L51
L88:
  nop
L51:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
const char **flvsep(const char *FORMULAV) {
  char **ret = malloc(sizeof(char *) * flvlen(FORMULAV));
  int k = 0;
  for (int i = 0; FORMULAV[i]; ++i) {
    if (!isdelimiter(FORMULAV[i])) {
      int j = i;
      do {
        ++j;
      } while (FORMULAV[j] && !isdelimiter(FORMULAV[j]));
      int len0 = j - i + 1;
      int len = j - i;
      ret[k] = malloc(sizeof(char) * len0);
      memcpy(ret[k], FORMULAV + i, len);
      ret[k][len] = '\0';
      i = j;
      k++;
    } else {
      do {
        ++i;
      } while (FORMULAV[i] && isdelimiter(FORMULAV[i]));
    }
    if (!FORMULAV[i])
      break;
  }
  return (const char **)ret;
}
```