ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<squares>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L17
L12:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d 

assistant: ```c
void squares(int v) {
  for (int i = 1; i < v + 1; i++) {
    printf("%d ", i * i);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<squares>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L0
  mov    %edi,%ebp
  mov    $0x1,%ebx
  lea    D9(%rip),%r12
L7:
  mov    %ebx,%esi
  imul   %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L7
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string

tool: D9: %d 

assistant: ```c
void squares(int v) {
  for (int i = 1; i < v + 1; i++) {
    printf("%d ", i * i);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<squares>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  imul   %ebx,%esi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L5
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L3:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d 

assistant: ```c
void squares(int v) {
  for (int i = 1; i < v + 1; i++) {
    printf("%d ", i * i);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<squares>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  imul   %ebx,%esi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L2
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L7:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %d 

assistant: ```c
void squares(int v) {
  for (int i = 1; i < v + 1; i++) {
    printf("%d ", i * i);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clear_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <clear_evdev@plt>
  mov    $0x0,%eax
  call   <clear_uinput@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void clear_input() {
  clear_evdev();
  clear_uinput();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_input>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clear_evdev@plt>
  mov    $0x0,%eax
  call   <clear_uinput@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void clear_input() {
  clear_evdev();
  clear_uinput();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clear_input>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_evdev@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <clear_uinput@plt>
```

assistant: ```c
void clear_input() {
  clear_evdev();
  clear_uinput();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clear_input>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_evdev@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <clear_uinput@plt>
```

assistant: ```c
void clear_input() {
  clear_evdev();
  clear_uinput();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<padrightzeros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x7,-0x14(%rbp)
  jle    L16
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x7,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L23
L16:
  cmpl   $0x7,-0x14(%rbp)
  jne    L35
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x7,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L23
L35:
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    $0x7,%edx
  sub    %eax,%edx
  lea    -0xf(%rbp),%rax
  mov    $0x30,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    $0x7,%edx
  sub    %eax,%edx
  lea    -0xf(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
L23:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int padrightzeros(char *str_in, char *str_out) {
  char zerostr[7];
  int numstrsize = strlen(str_in);
  if (numstrsize > 7) {
    strncpy(str_out, str_in, 7);
  } else if (numstrsize == 7) {
    strncpy(str_out, str_in, 7);
  } else {
    strcpy(str_out, str_in);
    memset(zerostr, 0x30, 7 - strlen(str_in));
    strncat(str_out, zerostr, 7 - strlen(str_in));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<padrightzeros>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x7,%eax
  jg     L41
  je     L2
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x7,%r12d
  mov    %r12d,%edx
  sub    %eax,%edx
  lea    0x1(%rsp),%r13
  mov    $0x30,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12d,%edx
  sub    %eax,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  mov    $0x7,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  jmp    L35
L2:
  mov    $0x7,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  jmp    L35
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padrightzeros(char *str_in, char *str_out) {
  char zerostr[7];
  int numstrsize = strlen(str_in);
  if (numstrsize > 7) {
    strncpy(str_out, str_in, 7);
  } else if (numstrsize == 7) {
    strncpy(str_out, str_in, 7);
  } else {
    strcpy(str_out, str_in);
    memset(zerostr, 0x30, 7 - strlen(str_in));
    strncat(str_out, zerostr, 7 - strlen(str_in));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<padrightzeros>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x6,%eax
  jg     L14
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rsp),%r13
  mov    $0x7,%ebx
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    $0x30,%esi
  mov    %r13,%rdi
  sub    %eax,%edx
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  sub    %eax,%ebx
  mov    %ebx,%edx
  call   <strncat@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    $0x7,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  jmp    L26
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padrightzeros(char *str_in, char *str_out) {
  char zerostr[7];
  int numstrsize = strlen(str_in);
  if (numstrsize > 7) {
    strncpy(str_out, str_in, 7);
  } else if (numstrsize == 7) {
    strncpy(str_out, str_in, 7);
  } else {
    strcpy(str_out, str_in);
    memset(zerostr, 0x30, 7 - strlen(str_in));
    strncat(str_out, zerostr, 7 - strlen(str_in));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<padrightzeros>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x6,%eax
  jg     L29
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rsp),%r13
  mov    $0x7,%ebx
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    $0x30,%esi
  mov    %r13,%rdi
  sub    %eax,%edx
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  sub    %eax,%ebx
  mov    %ebx,%edx
  call   <strncat@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  mov    $0x7,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  jmp    L21
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padrightzeros(char *str_in, char *str_out) {
  char zerostr[7];
  int numstrsize = strlen(str_in);
  if (numstrsize > 7) {
    strncpy(str_out, str_in, 7);
  } else if (numstrsize == 7) {
    strncpy(str_out, str_in, 7);
  } else {
    strcpy(str_out, str_in);
    memset(zerostr, 0x30, 7 - strlen(str_in));
    strncat(str_out, zerostr, 7 - strlen(str_in));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<moveZeroes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L59
  addl   $0x1,-0x4(%rbp)
  jmp    L56
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L38
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  jmp    L56
L38:
  addl   $0x1,-0x4(%rbp)
L59:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
L56:
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void moveZeroes(int *nums, int numsSize) {
  int i, j;
  for (i = 0, j = 0; i < numsSize; i++) {
    if (nums[i]) {
      j++;
    } else {
      for (; j < numsSize; j++) {
        if (nums[j]) {
          nums[i] = nums[j];
          nums[j] = 0;
          break;
        }
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<moveZeroes>:
  endbr64
  test   %esi,%esi
  jle    L34
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r11
  mov    $0x0,%edx
  jmp    L70
L21:
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rax
  cmp    %edx,%esi
  jle    L42
L50:
  mov    (%rax),%r8d
  test   %r8d,%r8d
  jne    L62
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%esi
  jne    L50
  mov    %esi,%edx
  jmp    L42
L62:
  mov    %r8d,(%r10)
  movl   $0x0,(%rax)
L42:
  add    $0x4,%rcx
  cmp    %r11,%rcx
  je     L34
L70:
  mov    %rcx,%r10
  cmpl   $0x0,(%rcx)
  je     L21
  add    $0x1,%edx
  jmp    L42
L34:
  ret
```

assistant: ```c
void moveZeroes(int *nums, int numsSize) {
  int i, j;
  for (i = 0, j = 0; i < numsSize; i++) {
    if (nums[i]) {
      j++;
    } else {
      for (; j < numsSize; j++) {
        if (nums[j]) {
          nums[i] = nums[j];
          nums[j] = 0;
          break;
        }
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<moveZeroes>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r8
  lea    0x4(%rdi,%rax,4),%r9
  xor    %eax,%eax
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%eax
L53:
  add    $0x4,%r8
  cmp    %r9,%r8
  je     L21
L81:
  mov    (%r8),%edx
  test   %edx,%edx
  jne    L1
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rdx
  cmp    %eax,%esi
  jg     L75
  jmp    L53
L19:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%esi
  je     L53
L75:
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  je     L19
  mov    %ecx,(%r8)
  add    $0x4,%r8
  movl   $0x0,(%rdx)
  cmp    %r9,%r8
  jne    L81
L21:
  ret
```

assistant: ```c
void moveZeroes(int *nums, int numsSize) {
  int i, j;
  for (i = 0, j = 0; i < numsSize; i++) {
    if (nums[i]) {
      j++;
    } else {
      for (; j < numsSize; j++) {
        if (nums[j]) {
          nums[i] = nums[j];
          nums[j] = 0;
          break;
        }
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<moveZeroes>:
  endbr64
  test   %esi,%esi
  jle    L28
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r8
  lea    0x4(%rdi,%rax,4),%r9
  xor    %eax,%eax
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L33:
  add    $0x1,%eax
L49:
  add    $0x4,%r8
  cmp    %r9,%r8
  je     L28
L32:
  mov    (%r8),%edx
  test   %edx,%edx
  jne    L33
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rdx
  cmp    %eax,%esi
  jg     L3
  jmp    L49
L89:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%esi
  je     L49
L3:
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  je     L89
  mov    %ecx,(%r8)
  add    $0x4,%r8
  movl   $0x0,(%rdx)
  cmp    %r9,%r8
  jne    L32
L28:
  ret
```

assistant: ```c
void moveZeroes(int *nums, int numsSize) {
  int i, j;
  for (i = 0, j = 0; i < numsSize; i++) {
    if (nums[i]) {
      j++;
    } else {
      for (; j < numsSize; j++) {
        if (nums[j]) {
          nums[i] = nums[j];
          nums[j] = 0;
          break;
        }
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <alignedMalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <alignedFree@plt>
  addl   $0x1,-0x14(%rbp)
L1:
  cmpl   $0x63,-0x14(%rbp)
  jle    L3
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8: done


assistant: ```c
int main() {
  for (int i = 0; i < 100; i++) {
    unsigned int alignment = rand();
    unsigned int size = rand();
    char *buf = alignedMalloc(alignment, size);
    alignedFree(buf);
  }
  printf("done\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%ebp
L7:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <alignedMalloc@plt>
  mov    %rax,%rdi
  call   <alignedFree@plt>
  sub    $0x1,%ebp
  jne    L7
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string

tool: D7: done


assistant: ```c
int main() {
  for (int i = 0; i < 100; i++) {
    unsigned int alignment = rand();
    unsigned int size = rand();
    char *buf = alignedMalloc(alignment, size);
    alignedFree(buf);
  }
  printf("done\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  nop
L6:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <alignedMalloc@plt>
  mov    %rax,%rdi
  call   <alignedFree@plt>
  sub    $0x1,%ebx
  jne    L6
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: done


assistant: ```c
int main() {
  for (int i = 0; i < 100; i++) {
    unsigned int alignment = rand();
    unsigned int size = rand();
    char *buf = alignedMalloc(alignment, size);
    alignedFree(buf);
  }
  printf("done\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  nop
L5:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <alignedMalloc@plt>
  mov    %rax,%rdi
  call   <alignedFree@plt>
  sub    $0x1,%ebx
  jne    L5
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: done


assistant: ```c
int main() {
  for (int i = 0; i < 100; i++) {
    unsigned int alignment = rand();
    unsigned int size = rand();
    char *buf = alignedMalloc(alignment, size);
    alignedFree(buf);
  }
  printf("done\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copyout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jae    L23
  mov    -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L36:
  mov    -0x10(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jb     L36
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%eax
  jmp    L10
L23:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int copyout(char *buffer, unsigned int buffersize, char *s, unsigned int len, unsigned int offset) {
  unsigned int avail = buffersize - offset;
  if (len < avail) {
    char *out = buffer + offset;
    unsigned int i;
    for (i = 0; i < len; i++)
      out[i] = s[i];
    out[len] = '\0';
    return len;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copyout>:
  endbr64
  mov    %ecx,%r9d
  sub    %r8d,%esi
  mov    $0x0,%eax
  cmp    %ecx,%esi
  ja     L3
L21:
  ret
L3:
  mov    %r8d,%r8d
  add    %r8,%rdi
  test   %ecx,%ecx
  je     L34
  lea    -0x1(%rcx),%esi
  mov    $0x0,%eax
L4:
  movzbl (%rdx,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %rsi,%rcx
  jne    L4
L34:
  mov    %r9d,%eax
  movb   $0x0,(%rdi,%rax,1)
  mov    %r9d,%eax
  jmp    L21
```

assistant: ```c
unsigned int copyout(char *buffer, unsigned int buffersize, char *s, unsigned int len, unsigned int offset) {
  unsigned int avail = buffersize - offset;
  if (len < avail) {
    char *out = buffer + offset;
    unsigned int i;
    for (i = 0; i < len; i++)
      out[i] = s[i];
    out[len] = '\0';
    return len;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copyout>:
  endbr64
  sub    %r8d,%esi
  xor    %eax,%eax
  cmp    %ecx,%esi
  ja     L1
  ret
  xchg   %ax,%ax
L1:
  mov    %r8d,%r8d
  add    %r8,%rdi
  mov    %ecx,%r8d
  test   %ecx,%ecx
  je     L25
  xor    %eax,%eax
  nop
L13:
  movzbl (%rdx,%rax,1),%esi
  mov    %sil,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L13
L25:
  movb   $0x0,(%rdi,%r8,1)
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned int copyout(char *buffer, unsigned int buffersize, char *s, unsigned int len, unsigned int offset) {
  unsigned int avail = buffersize - offset;
  if (len < avail) {
    char *out = buffer + offset;
    unsigned int i;
    for (i = 0; i < len; i++)
      out[i] = s[i];
    out[len] = '\0';
    return len;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copyout>:
  endbr64
  sub    %r8d,%esi
  mov    %rdx,%r9
  mov    %ecx,%eax
  xor    %r10d,%r10d
  cmp    %ecx,%esi
  ja     L37
  mov    %r10d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %r8d,%r8d
  mov    %ecx,%ecx
  add    %r8,%rdi
  test   %eax,%eax
  je     L90
  lea    0x1(%r9),%rsi
  mov    %rdi,%rcx
  lea    -0x1(%rax),%edx
  sub    %rsi,%rcx
  cmp    $0xe,%rcx
  jbe    L111
  cmp    $0x6,%edx
  jbe    L111
  cmp    $0xe,%edx
  jbe    L28
  mov    %eax,%ecx
  xor    %edx,%edx
  shr    $0x4,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L85:
  movdqu (%r9,%rdx,1),%xmm0
  movups %xmm0,(%rdi,%rdx,1)
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jne    L85
  mov    %eax,%edx
  mov    %eax,%ecx
  and    $0xfffffff0,%edx
  test   $0xf,%al
  je     L90
  mov    %eax,%esi
  sub    %edx,%esi
  lea    -0x1(%rsi),%ecx
  cmp    $0x6,%ecx
  jbe    L115
L117:
  mov    %edx,%ecx
  mov    (%r9,%rcx,1),%r8
  mov    %r8,(%rdi,%rcx,1)
  mov    %esi,%r8d
  mov    %eax,%ecx
  and    $0xfffffff8,%r8d
  add    %r8d,%edx
  cmp    %r8d,%esi
  je     L90
L115:
  mov    %edx,%ecx
  movzbl (%r9,%rcx,1),%esi
  mov    %sil,(%rdi,%rcx,1)
  lea    0x1(%rdx),%esi
  mov    %eax,%ecx
  cmp    %esi,%eax
  jbe    L90
  movzbl (%r9,%rsi,1),%r8d
  mov    %r8b,(%rdi,%rsi,1)
  lea    0x2(%rdx),%esi
  cmp    %esi,%eax
  jbe    L90
  movzbl (%r9,%rsi,1),%r8d
  mov    %r8b,(%rdi,%rsi,1)
  lea    0x3(%rdx),%esi
  cmp    %esi,%eax
  jbe    L90
  movzbl (%r9,%rsi,1),%r8d
  mov    %r8b,(%rdi,%rsi,1)
  lea    0x4(%rdx),%esi
  cmp    %esi,%eax
  jbe    L90
  movzbl (%r9,%rsi,1),%r8d
  mov    %r8b,(%rdi,%rsi,1)
  lea    0x5(%rdx),%esi
  cmp    %esi,%eax
  jbe    L90
  movzbl (%r9,%rsi,1),%r8d
  add    $0x6,%edx
  mov    %r8b,(%rdi,%rsi,1)
  cmp    %edx,%eax
  jbe    L90
  movzbl (%r9,%rdx,1),%esi
  mov    %sil,(%rdi,%rdx,1)
L90:
  mov    %eax,%r10d
  movb   $0x0,(%rdi,%rcx,1)
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax)
L111:
  mov    %eax,%ecx
  xor    %edx,%edx
  nopl   0x0(%rax)
L166:
  movzbl (%r9,%rdx,1),%esi
  mov    %sil,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L166
  jmp    L90
L28:
  mov    %eax,%esi
  xor    %edx,%edx
  jmp    L117
```

assistant: ```c
unsigned int copyout(char *buffer, unsigned int buffersize, char *s, unsigned int len, unsigned int offset) {
  unsigned int avail = buffersize - offset;
  if (len < avail) {
    char *out = buffer + offset;
    unsigned int i;
    for (i = 0; i < len; i++)
      out[i] = s[i];
    out[len] = '\0';
    return len;
  }
  return 0;
}
```