user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x3b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x3a0(%rbp)
  jmp    L69
L212:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3a4(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x3a4(%rbp),%eax
  test   %eax,%eax
  je     L69
  mov    -0x3a4(%rbp),%eax
  cmp    $0xf,%eax
  jg     L69
  mov    -0x3a4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L69
  movl   $0x0,-0x3a0(%rbp)
L69:
  cmpl   $0x1,-0x3a0(%rbp)
  je     L212
  movl   $0x1,-0x39c(%rbp)
  jmp    L131
L24:
  movl   $0x1,-0x398(%rbp)
  jmp    L44
L15:
  mov    -0x398(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x39c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  add    %rcx,%rax
  movl   $0x0,-0x390(%rbp,%rax,4)
  addl   $0x1,-0x398(%rbp)
L44:
  mov    -0x3a4(%rbp),%eax
  cmp    %eax,-0x398(%rbp)
  jle    L15
  addl   $0x1,-0x39c(%rbp)
L131:
  mov    -0x3a4(%rbp),%eax
  cmp    %eax,-0x39c(%rbp)
  jle    L24
  mov    -0x3a4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    $0x1,%eax
  mov    %eax,-0x398(%rbp)
  mov    -0x398(%rbp),%eax
  cltq
  add    $0xf,%rax
  movl   $0x1,-0x390(%rbp,%rax,4)
  movl   $0x2,-0x394(%rbp)
  jmp    L109
L135:
  subl   $0x1,-0x39c(%rbp)
  addl   $0x1,-0x398(%rbp)
  cmpl   $0x0,-0x39c(%rbp)
  jg     L166
  mov    -0x3a4(%rbp),%eax
  cmp    %eax,-0x398(%rbp)
  jle    L166
  addl   $0x2,-0x39c(%rbp)
  subl   $0x1,-0x398(%rbp)
  jmp    L74
L166:
  cmpl   $0x0,-0x39c(%rbp)
  jg     L39
  mov    -0x3a4(%rbp),%eax
  mov    %eax,-0x39c(%rbp)
L39:
  mov    -0x3a4(%rbp),%eax
  cmp    %eax,-0x398(%rbp)
  jle    L74
  movl   $0x1,-0x398(%rbp)
L74:
  mov    -0x398(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x39c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  add    %rcx,%rax
  mov    -0x390(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L161
  mov    -0x398(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x39c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  lea    (%rax,%rcx,1),%rdx
  mov    -0x394(%rbp),%eax
  mov    %eax,-0x390(%rbp,%rdx,4)
  jmp    L189
L161:
  addl   $0x2,-0x39c(%rbp)
  subl   $0x1,-0x398(%rbp)
  mov    -0x398(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x39c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  lea    (%rax,%rcx,1),%rdx
  mov    -0x394(%rbp),%eax
  mov    %eax,-0x390(%rbp,%rdx,4)
L189:
  addl   $0x1,-0x394(%rbp)
L109:
  mov    -0x3a4(%rbp),%edx
  mov    -0x3a4(%rbp),%eax
  imul   %edx,%eax
  cmp    %eax,-0x394(%rbp)
  jle    L135
  movl   $0x1,-0x39c(%rbp)
  jmp    L112
L30:
  movl   $0x1,-0x398(%rbp)
  jmp    L173
L188:
  mov    -0x398(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x39c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  add    %rcx,%rax
  mov    -0x390(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x398(%rbp)
L173:
  mov    -0x3a4(%rbp),%eax
  cmp    %eax,-0x398(%rbp)
  jle    L188
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x39c(%rbp)
L112:
  mov    -0x3a4(%rbp),%eax
  cmp    %eax,-0x39c(%rbp)
  jle    L30
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L170
  call   <__stack_chk_fail@plt>
L170:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D23
datatype: string

tool: D8: enter n(n=1~15):

tool: D24: %d

tool: D23: %5d

assistant: ```c
int main() {
  int a[15][15], p, i, j, k, n;
  p = 1;
  while (p == 1) {
    printf("enter n(n=1~15):");
    scanf("%d", &n);
    if ((n != 0) && (n <= 15) && (n % 2 != 0))
      p = 0;
  }
  for (i = 1; i <= n; i++)
    for (j = 1; j <= n; j++)
      a[i][j] = 0;
  j = n / 2 + 1;
  a[1][j] = 1;
  for (k = 2; k <= n * n; k++) {
    i = i - 1;
    j = j + 1;
    if ((i < 1) && (j > n)) {
      i = i + 2;
      j = j - 1;
    } else {
      if (i < 1)
        i = n;
      if (j > n)
        j = 1;
    }
    if (a[i][j] == 0)
      a[i][j] = k;
    else {
      i = i + 2;
      j = j - 1;
      a[i][j] = k;
    }
  }
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++)
      printf("%5d", a[i][j]);
    printf("\n");
  }
  return 0;
}
```