ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<in_cksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movw   $0x0,-0x1a(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L30
L37:
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x18(%rbp)
  subl   $0x2,-0x14(%rbp)
L30:
  cmpl   $0x1,-0x14(%rbp)
  jg     L37
  cmpl   $0x1,-0x14(%rbp)
  jne    L1
  lea    -0x1a(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzwl -0x1a(%rbp),%eax
  movzwl %ax,%eax
  add    %eax,-0x18(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int in_cksum(unsigned short *addr, int len) {
  int sum;
  int nleft;
  unsigned short ans;
  unsigned short *w;
  sum = 0;
  ans = 0;
  nleft = len;
  w = addr;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&ans) = *(unsigned char *)w;
    sum += ans;
  }
  return (sum);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<in_cksum>:
  endbr64
  mov    $0x0,%r9d
  cmp    $0x1,%esi
  jle    L47
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L0:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L0
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L1:
  cmp    $0x1,%esi
  je     L38
L32:
  ret
L47:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L1
L38:
  mov    (%rcx),%r9b
  movzwl %r9w,%r9d
  add    %r9d,%eax
  jmp    L32
```

assistant: ```c
int in_cksum(unsigned short *addr, int len) {
  int sum;
  int nleft;
  unsigned short ans;
  unsigned short *w;
  sum = 0;
  ans = 0;
  nleft = len;
  w = addr;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&ans) = *(unsigned char *)w;
    sum += ans;
  }
  return (sum);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<in_cksum>:
  endbr64
  xor    %r9d,%r9d
  cmp    $0x1,%esi
  jle    L11
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nop
L15:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L15
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L17:
  cmp    $0x1,%esi
  je     L3
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%rcx),%r9b
  movzwl %r9w,%r9d
  add    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L17
```

assistant: ```c
int in_cksum(unsigned short *addr, int len) {
  int sum;
  int nleft;
  unsigned short ans;
  unsigned short *w;
  sum = 0;
  ans = 0;
  nleft = len;
  w = addr;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&ans) = *(unsigned char *)w;
    sum += ans;
  }
  return (sum);
}
```
user: What is the c source code of the assembly code below:

```asm
<in_cksum>:
  endbr64
  mov    %rdi,%rdx
  xor    %r10d,%r10d
  cmp    $0x1,%esi
  jle    L79
  lea    -0x2(%rsi),%r9d
  mov    %r9d,%r11d
  shr    %r11d
  lea    0x1(%r11),%ecx
  cmp    $0xd,%r9d
  jbe    L24
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L28:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm3
  punpckhwd %xmm2,%xmm1
  punpcklwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L28
  movdqa %xmm0,%xmm1
  mov    %ecx,%r8d
  psrldq $0x8,%xmm1
  and    $0xfffffff8,%r8d
  paddd  %xmm1,%xmm0
  mov    %r8d,%edi
  movdqa %xmm0,%xmm1
  neg    %edi
  psrldq $0x4,%xmm1
  lea    (%rsi,%rdi,2),%esi
  mov    %r8d,%edi
  paddd  %xmm1,%xmm0
  lea    (%rdx,%rdi,2),%rdi
  movd   %xmm0,%eax
  cmp    %r8d,%ecx
  je     L114
L23:
  movzwl (%rdi),%r8d
  add    %r8d,%eax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L114
  movzwl 0x2(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L114
  movzwl 0x4(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L114
  movzwl 0x6(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L114
  movzwl 0x8(%rdi),%r8d
  add    %r8d,%eax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L114
  movzwl 0xa(%rdi),%r8d
  add    %r8d,%eax
  cmp    $0xd,%esi
  jle    L114
  movzwl 0xc(%rdi),%esi
  add    %esi,%eax
L114:
  mov    %ecx,%esi
  mov    %r11d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r9,%rcx,2),%esi
L20:
  cmp    $0x1,%esi
  je     L107
  ret
  nopl   0x0(%rax,%rax,1)
L107:
  mov    (%rdx),%r10b
  movzwl %r10w,%edx
  add    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  xor    %eax,%eax
  jmp    L20
L24:
  xor    %eax,%eax
  jmp    L23
```

assistant: ```c
int in_cksum(unsigned short *addr, int len) {
  int sum;
  int nleft;
  unsigned short ans;
  unsigned short *w;
  sum = 0;
  ans = 0;
  nleft = len;
  w = addr;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&ans) = *(unsigned char *)w;
    sum += ans;
  }
  return (sum);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<submm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0xf,-0x4(%rbp)
  jle    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void submm(float *result, const float *s) {
  int i;
  for (i = 0; i < 16; i++)
    result[i] -= s[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<submm>:
  endbr64
  mov    $0x0,%eax
L8:
  movss  (%rdi,%rax,1),%xmm0
  subss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x40,%rax
  jne    L8
  ret
```

assistant: ```c
void submm(float *result, const float *s) {
  int i;
  for (i = 0; i < 16; i++)
    result[i] -= s[i];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<submm>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L5:
  movss  (%rdi,%rax,1),%xmm0
  subss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x40,%rax
  jne    L5
  ret
```

assistant: ```c
void submm(float *result, const float *s) {
  int i;
  for (i = 0; i < 16; i++)
    result[i] -= s[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<submm>:
  endbr64
  mov    %rsi,%rdx
  mov    %rdi,%rcx
  lea    0x4(%rsi),%rsi
  sub    %rsi,%rcx
  cmp    $0x8,%rcx
  jbe    L2
  movups (%rdx),%xmm2
  movups (%rdi),%xmm0
  subps  %xmm2,%xmm0
  movups %xmm0,(%rdi)
  movups 0x10(%rdi),%xmm0
  movups 0x10(%rdx),%xmm3
  subps  %xmm3,%xmm0
  movups %xmm0,0x10(%rdi)
  movups 0x20(%rdi),%xmm0
  movups 0x20(%rdx),%xmm4
  subps  %xmm4,%xmm0
  movups %xmm0,0x20(%rdi)
  movups 0x30(%rdi),%xmm0
  movups 0x30(%rdx),%xmm1
  subps  %xmm1,%xmm0
  movups %xmm0,0x30(%rdi)
  ret
  nopl   0x0(%rax)
L2:
  movss  (%rdi),%xmm0
  subss  (%rdx),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdi),%xmm0
  subss  0xc(%rdx),%xmm0
  movss  %xmm0,0xc(%rdi)
  movss  0x10(%rdi),%xmm0
  subss  0x10(%rdx),%xmm0
  movss  %xmm0,0x10(%rdi)
  movss  0x14(%rdi),%xmm0
  subss  0x14(%rdx),%xmm0
  movss  %xmm0,0x14(%rdi)
  movss  0x18(%rdi),%xmm0
  subss  0x18(%rdx),%xmm0
  movss  %xmm0,0x18(%rdi)
  movss  0x1c(%rdi),%xmm0
  subss  0x1c(%rdx),%xmm0
  movss  %xmm0,0x1c(%rdi)
  movss  0x20(%rdi),%xmm0
  subss  0x20(%rdx),%xmm0
  movss  %xmm0,0x20(%rdi)
  movss  0x24(%rdi),%xmm0
  subss  0x24(%rdx),%xmm0
  movss  %xmm0,0x24(%rdi)
  movss  0x28(%rdi),%xmm0
  subss  0x28(%rdx),%xmm0
  movss  %xmm0,0x28(%rdi)
  movss  0x2c(%rdi),%xmm0
  subss  0x2c(%rdx),%xmm0
  movss  %xmm0,0x2c(%rdi)
  movss  0x30(%rdi),%xmm0
  subss  0x30(%rdx),%xmm0
  movss  %xmm0,0x30(%rdi)
  movss  0x34(%rdi),%xmm0
  subss  0x34(%rdx),%xmm0
  movss  %xmm0,0x34(%rdi)
  movss  0x38(%rdi),%xmm0
  subss  0x38(%rdx),%xmm0
  movss  %xmm0,0x38(%rdi)
  movss  0x3c(%rdi),%xmm0
  subss  0x3c(%rdx),%xmm0
  movss  %xmm0,0x3c(%rdi)
  ret
```

assistant: ```c
void submm(float *result, const float *s) {
  int i;
  for (i = 0; i < 16; i++)
    result[i] -= s[i];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lisp_atan2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jg     L19
  cmpq   $0x0,-0x18(%rbp)
  jle    L19
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <abs@plt>
  cmp    %rax,%rbx
  setle  %al
  movzbl %al,%eax
  jmp    L8
L19:
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
__attribute__((no)) int lisp_atan2(long dy, long dx) {
  if (dx <= 0)
    if (dy > 0)
      return abs(dx) <= abs(dy);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lisp_atan2>:
  endbr64
  test   %rdi,%rdi
  jle    L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%eax
  test   %rsi,%rsi
  jle    L3
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rsi,%rdi
  call   <abs@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <abs@plt>
  cmp    %rax,%rbp
  setle  %al
  movzbl %al,%eax
  jmp    L13
L19:
  mov    $0x0,%eax
  ret
```

assistant: ```c
__attribute__((no)) int lisp_atan2(long dy, long dx) {
  if (dx <= 0)
    if (dy > 0)
      return abs(dx) <= abs(dy);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lisp_atan2>:
  endbr64
  test   %rsi,%rsi
  jg     L19
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jg     L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rsi,%rdi
  call   <abs@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <abs@plt>
  cmp    %rax,%rbx
  setle  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) int lisp_atan2(long dy, long dx) {
  if (dx <= 0)
    if (dy > 0)
      return abs(dx) <= abs(dy);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lisp_atan2>:
  endbr64
  test   %rsi,%rsi
  jg     L2
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jg     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rsi,%rdi
  call   <abs@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <abs@plt>
  cmp    %rax,%rbx
  setle  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) int lisp_atan2(long dy, long dx) {
  if (dx <= 0)
    if (dy > 0)
      return abs(dx) <= abs(dy);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<absdiff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jge    L3
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L5
L3:
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long absdiff(long x, long y) {
  long result;
  if (x < y) {
    result = y - x;
  } else {
    result = x - y;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<absdiff>:
  endbr64
  mov    %rsi,%rdx
  sub    %rdi,%rdx
  mov    %rdi,%rax
  sub    %rsi,%rax
  cmp    %rsi,%rdi
  cmovl  %rdx,%rax
  ret
```

assistant: ```c
long absdiff(long x, long y) {
  long result;
  if (x < y) {
    result = y - x;
  } else {
    result = x - y;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<absdiff>:
  endbr64
  mov    %rsi,%rdx
  mov    %rdi,%rax
  sub    %rdi,%rdx
  sub    %rsi,%rax
  cmp    %rsi,%rdi
  cmovl  %rdx,%rax
  ret
```

assistant: ```c
long absdiff(long x, long y) {
  long result;
  if (x < y) {
    result = y - x;
  } else {
    result = x - y;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<absdiff>:
  endbr64
  mov    %rsi,%rdx
  mov    %rdi,%rax
  sub    %rdi,%rdx
  sub    %rsi,%rax
  cmp    %rsi,%rdi
  cmovl  %rdx,%rax
  ret
```

assistant: ```c
long absdiff(long x, long y) {
  long result;
  if (x < y) {
    result = y - x;
  } else {
    result = x - y;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    $0x0,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <halt@plt>
L18:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: Not enough memory.

assistant: ```c
void *get_mem(size_t nitems, size_t size) {
  void *tmp;
  if (((tmp = calloc(nitems, size)) == NULL) && (nitems != 0))
    halt("Not enough memory.", NULL);
  return (tmp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_mem>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rbx,%rbx
  je     L26
  test   %rax,%rax
  je     L4
L26:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    $0x0,%esi
  lea    D2(%rip),%rdi
  call   <halt@plt>
  jmp    L26
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string

tool: D2: Not enough memory.

assistant: ```c
void *get_mem(size_t nitems, size_t size) {
  void *tmp;
  if (((tmp = calloc(nitems, size)) == NULL) && (nitems != 0))
    halt("Not enough memory.", NULL);
  return (tmp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_mem>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L7
  test   %rax,%rax
  je     L22
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L22:
  xor    %esi,%esi
  lea    D0(%rip),%rdi
  call   <halt@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string

tool: D0: Not enough memory.

assistant: ```c
void *get_mem(size_t nitems, size_t size) {
  void *tmp;
  if (((tmp = calloc(nitems, size)) == NULL) && (nitems != 0))
    halt("Not enough memory.", NULL);
  return (tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_mem>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L1
  test   %rax,%rax
  je     L16
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L16:
  xor    %esi,%esi
  lea    D7(%rip),%rdi
  call   <halt@plt>
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: Not enough memory.

assistant: ```c
void *get_mem(size_t nitems, size_t size) {
  void *tmp;
  if (((tmp = calloc(nitems, size)) == NULL) && (nitems != 0))
    halt("Not enough memory.", NULL);
  return (tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<add_bias_and_relu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %esi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L23:
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L4:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  addss  -0x1c(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L45
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
L45:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L4
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_bias_and_relu(float **out, float bs, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      out[i][j] += bs;
      if (out[i][j] < 0)
        out[i][j] = 0.0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_bias_and_relu>:
  endbr64
  test   %esi,%esi
  jle    L53
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdi
  mov    %esi,%esi
  shl    $0x2,%rsi
  pxor   %xmm2,%xmm2
  jmp    L31
L0:
  add    $0x4,%rax
  cmp    %rax,%rsi
  je     L67
L30:
  mov    %rax,%rdx
  add    (%rcx),%rdx
  movaps %xmm0,%xmm1
  addss  (%rdx),%xmm1
  movss  %xmm1,(%rdx)
  mov    %rax,%rdx
  add    (%rcx),%rdx
  comiss (%rdx),%xmm2
  jbe    L0
  movl   $0x0,(%rdx)
  jmp    L0
L67:
  add    $0x8,%rcx
  cmp    %rdi,%rcx
  je     L53
L31:
  mov    $0x0,%eax
  jmp    L30
L53:
  ret
```

assistant: ```c
void add_bias_and_relu(float **out, float bs, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      out[i][j] += bs;
      if (out[i][j] < 0)
        out[i][j] = 0.0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add_bias_and_relu>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  mov    %esi,%ecx
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%rax,8),%r8
  shl    $0x2,%rcx
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rdi),%rdx
  movaps %xmm2,%xmm3
  add    %rax,%rdx
  add    $0x4,%rax
  movss  (%rdx),%xmm1
  addss  %xmm0,%xmm1
  maxss  %xmm1,%xmm3
  movss  %xmm3,(%rdx)
  cmp    %rax,%rcx
  jne    L0
  add    $0x8,%rdi
  cmp    %r8,%rdi
  jne    L3
L16:
  ret
```

assistant: ```c
void add_bias_and_relu(float **out, float bs, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      out[i][j] += bs;
      if (out[i][j] < 0)
        out[i][j] = 0.0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<add_bias_and_relu>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  mov    %esi,%ecx
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%rax,8),%r8
  shl    $0x2,%rcx
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rdi),%rdx
  movaps %xmm2,%xmm3
  add    %rax,%rdx
  add    $0x4,%rax
  movss  (%rdx),%xmm1
  addss  %xmm0,%xmm1
  maxss  %xmm1,%xmm3
  movss  %xmm3,(%rdx)
  cmp    %rax,%rcx
  jne    L19
  add    $0x8,%rdi
  cmp    %rdi,%r8
  jne    L7
L8:
  ret
```

assistant: ```c
void add_bias_and_relu(float **out, float bs, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      out[i][j] += bs;
      if (out[i][j] < 0)
        out[i][j] = 0.0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<float_to_32bit_integer_samples>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  movl   $0x8000000,-0x1c(%rbp)
  movl   $0x7fffffff,-0x18(%rbp)
  movss  D6(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  jmp    L41
L32:
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm0
  movss  D33(%rip),%xmm1
  comiss %xmm1,%xmm0
  jb     L25
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L66
L25:
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm1
  movss  D34(%rip),%xmm0
  comiss %xmm1,%xmm0
  jb     L42
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L66
L42:
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0x14(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <floor@plt>
  mov    %eax,-0x24(%rbp)
L66:
  cmpl   $0x0,-0x24(%rbp)
  je     L131
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L131
  movl   $0x1,-0x20(%rbp)
  jmp    L58
L132:
  addl   $0x1,-0x20(%rbp)
L58:
  sarl   -0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L132
  jmp    L8
L62:
  mov    -0x24(%rbp),%eax
  lea    (%rax,%rax,1),%ebx
  mov    $0x0,%eax
  call   <frandom@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  comisd D35(%rip),%xmm2
  jbe    L124
  mov    $0x1,%eax
  jmp    L20
L124:
  mov    $0x0,%eax
L20:
  add    %ebx,%eax
  mov    %eax,-0x24(%rbp)
L8:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L62
L131:
  mov    -0x38(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x38(%rbp)
L41:
  mov    -0x3c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  test   %eax,%eax
  jne    L32
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: f32
name: unpack_data
arguments: data_tag: D33
type: f32
name: unpack_data
arguments: data_tag: D34
type: byte[4]
name: unpack_data
arguments: data_tag: D35
type: f64

tool: D6: 2147483648

tool: D33: 1

tool: {"D34": [0x00,0x00,0x80,0xbf]}

tool: D35: 0.5

assistant: ```c
void float_to_32bit_integer_samples(float *samples, int num_samples) {
  int isample, imin = 0x8000000, imax = 0x7fffffff;
  float scalar = 2147483648.0;
  while (num_samples--) {
    if (*samples >= 1.0)
      isample = imax;
    else if (*samples <= -1.0)
      isample = imin;
    else
      isample = floor(*samples * scalar);
    if (isample && !(isample & 1)) {
      int tzeros = 1;
      while (!((isample >>= 1) & 1))
        tzeros++;
      while (tzeros--)
        isample = ((unsigned int)isample << 1) + ((frandom() > 0.5) ? 1 : 0);
    }
    *(int32_t *)samples = isample;
    samples++;
  }
}
```