ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<count_wordsandnum>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
  add    $0x1,%rdi
  mov    %eax,%edx
  xor    %r8d,%r8d
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L15:
  cmp    $0x20,%dl
  setne  %dl
  add    $0x1,%rcx
  movzbl %dl,%edx
  add    %edx,%r8d
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L15
  mov    $0x1,%esi
  nopl   (%rax)
L5:
  cmp    $0x20,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%esi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L5
  mov    %r8d,%edx
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L20:
  xor    %r8d,%r8d
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  mov    %r8d,%edx
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string

tool: D8: The number of of words and characters are %d and %d respectively.


assistant: ```c
void count_wordsandnum(char a[50]) {
  int i, j, count = 0, count2 = 1;
  for (i = 0; a[i] != '\0'; i++) {
    if (a[i] != 32)
      count++;
  }
  for (j = 0; a[j] != '\0'; j++) {
    if (a[j] == 32)
      count2++;
  }
  printf("The number of of words and characters are %d and %d respectively.\n", count2, count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count_wordsandnum>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L14
  add    $0x1,%rdi
  mov    %eax,%edx
  xor    %r8d,%r8d
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L13:
  cmp    $0x20,%dl
  setne  %dl
  add    $0x1,%rcx
  movzbl %dl,%edx
  add    %edx,%r8d
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L13
  mov    $0x1,%esi
  nopl   (%rax)
L22:
  cmp    $0x20,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%esi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L22
  mov    %r8d,%edx
  lea    D11(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L14:
  xor    %r8d,%r8d
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  mov    %r8d,%edx
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
data_type: string

tool: D11: The number of of words and characters are %d and %d respectively.


assistant: ```c
void count_wordsandnum(char a[50]) {
  int i, j, count = 0, count2 = 1;
  for (i = 0; a[i] != '\0'; i++) {
    if (a[i] != 32)
      count++;
  }
  for (j = 0; a[j] != '\0'; j++) {
    if (a[j] == 32)
      count2++;
  }
  printf("The number of of words and characters are %d and %d respectively.\n", count2, count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mp4tree_box_stsc_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,%rdi
  call   <get_u32@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%ebx
  mov    -0x44(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <indent@plt>
  mov    %ebx,%edx
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%r13d
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%r12d
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ebx
  mov    -0x44(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <indent@plt>
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x44(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <indent@plt>
  mov    %rax,%rcx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  add    $0x20,%rax
  mov    -0x24(%rbp),%ecx
  sub    $0x8,%rsp
  mov    -0x44(%rbp),%edx
  push   %rdx
  mov    %ecx,%r9d
  mov    $0x3,%r8d
  mov    $0x4,%ecx
  mov    %rax,%rdx
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <mp4tree_table_print@plt>
  add    $0x10,%rsp
  nop
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D43
type_infered: string
name: extract_symbolic_data
arguments: data_label: D41
type_infered: string
name: extract_symbolic_data
arguments: data_label: D27
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D11: %s  Version:     %u


tool: D43: %s  Flags:       0x%.2x%.2x%.2x


tool: D41: %s  Num Entries: %u


tool: D27: First chunk | Samples per chunk | Sample Description ID

tool: D6: Composition-offset table

assistant: ```c
void mp4tree_box_stsc_print(const uint8_t *p, size_t len, int depth) {
  const int num = get_u32(p + 4);
  printf("%s  Version:     %u\n", indent(depth, 0), p[0]);
  printf("%s  Flags:       0x%.2x%.2x%.2x\n", indent(depth, 0), p[1], p[2], p[3]);
  printf("%s  Num Entries: %u\n", indent(depth, 0), num);
  mp4tree_table_print("Composition-offset table", "First chunk | Samples per chunk | Sample Description ID", p + 8, 4, 3, num, depth);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mp4tree_box_stsc_print>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %edx,%ebp
  lea    0x10(%rdi),%rdi
  call   <get_u32@plt>
  mov    %eax,%r12d
  mov    (%rbx),%r13d
  mov    $0x0,%esi
  mov    %ebp,%edi
  call   <indent@plt>
  mov    %rax,%rsi
  mov    %r13d,%edx
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rbx),%r15d
  mov    0x8(%rbx),%r14d
  mov    0x4(%rbx),%r13d
  mov    $0x0,%esi
  mov    %ebp,%edi
  call   <indent@plt>
  mov    %rax,%rsi
  mov    %r15d,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %ebp,%edi
  call   <indent@plt>
  mov    %rax,%rsi
  mov    %r12d,%edx
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rbx),%rdx
  sub    $0x8,%rsp
  push   %rbp
  mov    %r12d,%r9d
  mov    $0x3,%r8d
  mov    $0x4,%ecx
  lea    D31(%rip),%rsi
  lea    D27(%rip),%rdi
  call   <mp4tree_table_print@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D33
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string
name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D31
data_type: string
name: retrieve_data
arguments: data_label: D27
data_type: string

tool: D33: %s  Version:     %u


tool: D23: %s  Flags:       0x%.2x%.2x%.2x


tool: D25: %s  Num Entries: %u


tool: D31: First chunk | Samples per chunk | Sample Description ID

tool: D27: Composition-offset table

assistant: ```c
void mp4tree_box_stsc_print(const uint8_t *p, size_t len, int depth) {
  const int num = get_u32(p + 4);
  printf("%s  Version:     %u\n", indent(depth, 0), p[0]);
  printf("%s  Flags:       0x%.2x%.2x%.2x\n", indent(depth, 0), p[1], p[2], p[3]);
  printf("%s  Num Entries: %u\n", indent(depth, 0), num);
  mp4tree_table_print("Composition-offset table", "First chunk | Samples per chunk | Sample Description ID", p + 8, 4, 3, num, depth);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mp4tree_box_stsc_print>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x10(%rdi),%rdi
  sub    $0x8,%rsp
  call   <get_u32@plt>
  mov    (%rbx),%r13d
  mov    %ebp,%edi
  xor    %esi,%esi
  mov    %eax,%r12d
  call   <indent@plt>
  mov    %r13d,%edx
  lea    D41(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rbx),%r15d
  mov    0x8(%rbx),%r14d
  mov    %ebp,%edi
  mov    0x4(%rbx),%r13d
  xor    %esi,%esi
  call   <indent@plt>
  mov    %r15d,%r8d
  mov    %r14d,%ecx
  lea    D31(%rip),%rdi
  mov    %r13d,%edx
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  xor    %esi,%esi
  call   <indent@plt>
  mov    %r12d,%edx
  lea    D37(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x8,%rsp
  lea    0x20(%rbx),%rdx
  mov    %r12d,%r9d
  push   %rbp
  mov    $0x3,%r8d
  mov    $0x4,%ecx
  lea    D19(%rip),%rsi
  lea    D17(%rip),%rdi
  call   <mp4tree_table_print@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D41
datatype: string
name: retrieve_data
arguments: tag: D31
datatype: string
name: retrieve_data
arguments: tag: D37
datatype: string
name: retrieve_data
arguments: tag: D19
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D41: %s  Version:     %u


tool: D31: %s  Flags:       0x%.2x%.2x%.2x


tool: D37: %s  Num Entries: %u


tool: D19: First chunk | Samples per chunk | Sample Description ID

tool: D17: Composition-offset table

assistant: ```c
void mp4tree_box_stsc_print(const uint8_t *p, size_t len, int depth) {
  const int num = get_u32(p + 4);
  printf("%s  Version:     %u\n", indent(depth, 0), p[0]);
  printf("%s  Flags:       0x%.2x%.2x%.2x\n", indent(depth, 0), p[1], p[2], p[3]);
  printf("%s  Num Entries: %u\n", indent(depth, 0), num);
  mp4tree_table_print("Composition-offset table", "First chunk | Samples per chunk | Sample Description ID", p + 8, 4, 3, num, depth);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mp4tree_box_stsc_print>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x10(%rdi),%rdi
  sub    $0x8,%rsp
  call   <get_u32@plt>
  mov    (%rbx),%r13d
  mov    %ebp,%edi
  xor    %esi,%esi
  mov    %eax,%r12d
  call   <indent@plt>
  mov    %r13d,%edx
  lea    D2(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rbx),%r15d
  mov    0x8(%rbx),%r14d
  mov    %ebp,%edi
  mov    0x4(%rbx),%r13d
  xor    %esi,%esi
  call   <indent@plt>
  mov    %r15d,%r8d
  mov    %r14d,%ecx
  lea    D27(%rip),%rdi
  mov    %r13d,%edx
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  xor    %esi,%esi
  call   <indent@plt>
  mov    %r12d,%edx
  lea    D49(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x8,%rsp
  lea    0x20(%rbx),%rdx
  mov    %r12d,%r9d
  push   %rbp
  mov    $0x3,%r8d
  mov    $0x4,%ecx
  lea    D41(%rip),%rsi
  lea    D43(%rip),%rdi
  call   <mp4tree_table_print@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D49
datatype: string
name: read_data
arguments: label: D41
datatype: string
name: read_data
arguments: label: D43
datatype: string

tool: D2: %s  Version:     %u


tool: D27: %s  Flags:       0x%.2x%.2x%.2x


tool: D49: %s  Num Entries: %u


tool: D41: First chunk | Samples per chunk | Sample Description ID

tool: D43: Composition-offset table

assistant: ```c
void mp4tree_box_stsc_print(const uint8_t *p, size_t len, int depth) {
  const int num = get_u32(p + 4);
  printf("%s  Version:     %u\n", indent(depth, 0), p[0]);
  printf("%s  Flags:       0x%.2x%.2x%.2x\n", indent(depth, 0), p[1], p[2], p[3]);
  printf("%s  Num Entries: %u\n", indent(depth, 0), num);
  mp4tree_table_print("Composition-offset table", "First chunk | Samples per chunk | Sample Description ID", p + 8, 4, 3, num, depth);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<libsndfile_str_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L26
L3:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  mov    $0x1,%eax
  jmp    L26
L25:
  mov    $0x2,%eax
L26:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
data_type: string

tool: D12: libsndfile

assistant: ```c
int libsndfile_str_count(const char *str) {
  const char *cptr;
  if ((cptr = strstr(str, "libsndfile")) == NULL)
    return 0;
  if ((cptr = strstr(cptr + 1, "libsndfile")) == NULL)
    return 1;
  return 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<libsndfile_str_count>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L4
  lea    0x1(%rax),%rdi
  lea    D9(%rip),%rsi
  call   <strstr@plt>
  cmp    $0x1,%rax
  mov    $0x1,%eax
  sbb    $0xffffffff,%eax
L6:
  add    $0x8,%rsp
  ret
L4:
  mov    $0x0,%eax
  jmp    L6
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: libsndfile

assistant: ```c
int libsndfile_str_count(const char *str) {
  const char *cptr;
  if ((cptr = strstr(str, "libsndfile")) == NULL)
    return 0;
  if ((cptr = strstr(cptr + 1, "libsndfile")) == NULL)
    return 1;
  return 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libsndfile_str_count>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L4
  mov    %rbp,%rsi
  lea    0x1(%rax),%rdi
  call   <strstr@plt>
  pop    %rbp
  cmp    $0x1,%rax
  mov    $0x1,%eax
  sbb    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D8: libsndfile

assistant: ```c
int libsndfile_str_count(const char *str) {
  const char *cptr;
  if ((cptr = strstr(str, "libsndfile")) == NULL)
    return 0;
  if ((cptr = strstr(cptr + 1, "libsndfile")) == NULL)
    return 1;
  return 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libsndfile_str_count>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  lea    0x1(%rax),%rdi
  call   <strstr@plt>
  pop    %rbp
  cmp    $0x1,%rax
  mov    $0x1,%eax
  sbb    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: libsndfile

assistant: ```c
int libsndfile_str_count(const char *str) {
  const char *cptr;
  if ((cptr = strstr(str, "libsndfile")) == NULL)
    return 0;
  if ((cptr = strstr(cptr + 1, "libsndfile")) == NULL)
    return 1;
  return 2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<num_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L36
  lea    D0(%rip),%rax
  jmp    L29
L36:
  mov    $0x14,%edi
  call   <malloc@plt>
  add    $0x13,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L37
L22:
  subq   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L37:
  cmpl   $0x0,-0x14(%rbp)
  jne    L22
  mov    -0x8(%rbp),%rax
L29:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: 0

assistant: ```c
char *num_to_string(int n) {
  if (!n)
    return "0";
  else {
    char *d = (char *)malloc(20) + 19;
    *d = 0;
    while (n) {
      d--;
      *d = (n % 10) + '0';
      n = n / 10;
    }
    return d;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<num_to_string>:
  endbr64
  lea    D8(%rip),%rcx
  test   %edi,%edi
  jne    L17
  mov    %rcx,%rax
  ret
L17:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x14,%edi
  call   <malloc@plt>
  lea    0x13(%rax),%rcx
  movb   $0x0,0x13(%rax)
L12:
  sub    $0x1,%rcx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  add    $0x30,%ebx
  mov    %bl,(%rcx)
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L12
  mov    %rcx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: 0

assistant: ```c
char *num_to_string(int n) {
  if (!n)
    return "0";
  else {
    char *d = (char *)malloc(20) + 19;
    *d = 0;
    while (n) {
      d--;
      *d = (n % 10) + '0';
      n = n / 10;
    }
    return d;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<num_to_string>:
  endbr64
  test   %edi,%edi
  jne    L1
  lea    D1(%rip),%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x14,%edi
  call   <malloc@plt>
  movb   $0x0,0x13(%rax)
  lea    0x13(%rax),%r8
  nopl   (%rax)
L6:
  movslq %ebx,%rax
  mov    %ebx,%edx
  sub    $0x1,%r8
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  add    $0x30,%ebx
  mov    %bl,(%r8)
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L6
  mov    %r8,%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: 0

assistant: ```c
char *num_to_string(int n) {
  if (!n)
    return "0";
  else {
    char *d = (char *)malloc(20) + 19;
    *d = 0;
    while (n) {
      d--;
      *d = (n % 10) + '0';
      n = n / 10;
    }
    return d;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_to_string>:
  endbr64
  test   %edi,%edi
  jne    L4
  lea    D7(%rip),%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x14,%edi
  call   <malloc@plt>
  movb   $0x0,0x13(%rax)
  lea    0x13(%rax),%r8
  nopl   (%rax)
L11:
  movslq %ebx,%rax
  mov    %ebx,%edx
  sub    $0x1,%r8
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  add    $0x30,%ebx
  mov    %bl,(%r8)
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L11
  mov    %r8,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: 0

assistant: ```c
char *num_to_string(int n) {
  if (!n)
    return "0";
  else {
    char *d = (char *)malloc(20) + 19;
    *d = 0;
    while (n) {
      d--;
      *d = (n % 10) + '0';
      n = n / 10;
    }
    return d;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<winding_triangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <triangle_area@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <triangle_area@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <triangle_area@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L8
  movsd  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L8
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L8
  movl   $0x1,-0x1c(%rbp)
L8:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L4
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L4
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L4
  movl   $0xffffffff,-0x1c(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int winding_triangle(double *A, double *B, double *C, double *X) {
  double v1 = triangle_area(A, B, X);
  double v2 = triangle_area(B, C, X);
  double v3 = triangle_area(C, A, X);
  int r = 0;
  if (v1 >= 0 && v2 >= 0 && v3 >= 0)
    r = 1;
  if (v1 < 0 && v2 < 0 && v3 < 0)
    r = -1;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<winding_triangle>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    %rcx,%rdx
  sub    $0x18,%rsp
  call   <triangle_area@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <triangle_area@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movsd  %xmm0,(%rsp)
  call   <triangle_area@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm1
  jb     L17
  movsd  (%rsp),%xmm3
  comisd %xmm2,%xmm3
  jb     L17
  xor    %eax,%eax
  comisd %xmm2,%xmm0
  setae  %al
  comisd %xmm1,%xmm2
  jbe    L9
L7:
  comisd (%rsp),%xmm2
  jbe    L9
  ucomisd %xmm0,%xmm2
  mov    $0xffffffff,%edx
  cmova  %edx,%eax
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  comisd %xmm1,%xmm2
  ja     L7
L9:
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int winding_triangle(double *A, double *B, double *C, double *X) {
  double v1 = triangle_area(A, B, X);
  double v2 = triangle_area(B, C, X);
  double v3 = triangle_area(C, A, X);
  int r = 0;
  if (v1 >= 0 && v2 >= 0 && v3 >= 0)
    r = 1;
  if (v1 < 0 && v2 < 0 && v3 < 0)
    r = -1;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<winding_triangle>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    %rcx,%rdx
  sub    $0x18,%rsp
  call   <triangle_area@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <triangle_area@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movsd  %xmm0,(%rsp)
  call   <triangle_area@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm1
  jb     L5
  movsd  (%rsp),%xmm3
  comisd %xmm2,%xmm3
  jb     L5
  xor    %eax,%eax
  comisd %xmm2,%xmm0
  setae  %al
  comisd %xmm1,%xmm2
  jbe    L17
L1:
  comisd (%rsp),%xmm2
  jbe    L17
  ucomisd %xmm0,%xmm2
  mov    $0xffffffff,%edx
  cmova  %edx,%eax
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  comisd %xmm1,%xmm2
  ja     L1
L17:
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int winding_triangle(double *A, double *B, double *C, double *X) {
  double v1 = triangle_area(A, B, X);
  double v2 = triangle_area(B, C, X);
  double v3 = triangle_area(C, A, X);
  int r = 0;
  if (v1 >= 0 && v2 >= 0 && v3 >= 0)
    r = 1;
  if (v1 < 0 && v2 < 0 && v3 < 0)
    r = -1;
  return r;
}
```