ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_putblank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L8
  jmp    L5
L4:
  mov    $0x20,%edi
  call   <my_putchar@plt>
L5:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L4
  jmp    L31
L8:
  nop
L31:
  leave
  ret
```

assistant: ```c
void my_putblank(int nb) {
  int i;
  i = -1;
  if (nb < 0)
    return;
  while (++i < nb)
    my_putchar(' ');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_putblank>:
  endbr64
  test   %edi,%edi
  jle    L17
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L4:
  mov    $0x20,%edi
  call   <my_putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  ret
```

assistant: ```c
void my_putblank(int nb) {
  int i;
  i = -1;
  if (nb < 0)
    return;
  while (++i < nb)
    my_putchar(' ');
}
```
user: What is the c source code of the assembly code below:

```asm
<my_putblank>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <my_putchar@plt>
  cmp    %ebx,%ebp
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  ret
```

assistant: ```c
void my_putblank(int nb) {
  int i;
  i = -1;
  if (nb < 0)
    return;
  while (++i < nb)
    my_putchar(' ');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_putblank>:
  endbr64
  test   %edi,%edi
  jle    L16
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <my_putchar@plt>
  cmp    %ebx,%ebp
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  ret
```

assistant: ```c
void my_putblank(int nb) {
  int i;
  i = -1;
  if (nb < 0)
    return;
  while (++i < nb)
    my_putchar(' ');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_escaped_newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x5c,-0x14(%rbp)
  jne    L31
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xa,-0x14(%rbp)
  je     L2
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  jmp    L31
L2:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    $0x1,%eax
  jmp    L19
L31:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int is_escaped_newline(FILE *input, FILE *output, int c) {
  if (c == '\\') {
    c = fgetc(input);
    if (c != '\n') {
      fputc(c, output);
    } else {
      fseek(output, -1, SEEK_CUR);
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_escaped_newline>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x5c,%edx
  je     L1
  ret
L1:
  push   %rbx
  mov    %rsi,%rbx
  call   <fgetc@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L4
  mov    %rbx,%rsi
  call   <fputc@plt>
  mov    $0x0,%eax
L28:
  pop    %rbx
  ret
L4:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    $0x1,%eax
  jmp    L28
```

assistant: ```c
int is_escaped_newline(FILE *input, FILE *output, int c) {
  if (c == '\\') {
    c = fgetc(input);
    if (c != '\n') {
      fputc(c, output);
    } else {
      fseek(output, -1, SEEK_CUR);
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_escaped_newline>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x5c,%edx
  je     L23
L9:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L23:
  mov    %rsi,%rbp
  call   <fgetc@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L7
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    D5(%rip),%rax
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  mov    $0x1,%r12d
  mov    (%rax),%edx
  call   <fseek@plt>
  jmp    L9
```

assistant: ```c
int is_escaped_newline(FILE *input, FILE *output, int c) {
  if (c == '\\') {
    c = fgetc(input);
    if (c != '\n') {
      fputc(c, output);
    } else {
      fseek(output, -1, SEEK_CUR);
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_escaped_newline>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x5c,%edx
  je     L16
L15:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L16:
  mov    %rsi,%rbp
  call   <fgetc@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L14
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    D0(%rip),%rax
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  mov    $0x1,%r12d
  mov    (%rax),%edx
  call   <fseek@plt>
  jmp    L15
```

assistant: ```c
int is_escaped_newline(FILE *input, FILE *output, int c) {
  if (c == '\\') {
    c = fgetc(input);
    if (c != '\n') {
      fputc(c, output);
    } else {
      fseek(output, -1, SEEK_CUR);
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L8
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: argv[%d]=%s


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int i = 0;
  for (i = 0; i <= argc; i++)
    printf("argv[%d]=%s\n", i, argv[i]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  test   %edi,%edi
  js     L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  lea    D7(%rip),%r13
L12:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L12
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: argv[%d]=%s


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int i = 0;
  for (i = 0; i <= argc; i++)
    printf("argv[%d]=%s\n", i, argv[i]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  test   %edi,%edi
  js     L2
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L0:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: argv[%d]=%s


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int i = 0;
  for (i = 0; i <= argc; i++)
    printf("argv[%d]=%s\n", i, argv[i]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  test   %edi,%edi
  js     L4
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L8:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: argv[%d]=%s


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int i = 0;
  for (i = 0; i <= argc; i++)
    printf("argv[%d]=%s\n", i, argv[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7ec(%rbp)
  lea    -0x7f4(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x7e8(%rbp)
  jmp    L15
L5:
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7e8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7e8(%rbp)
L15:
  mov    -0x7f4(%rbp),%eax
  cmp    %eax,-0x7e8(%rbp)
  jl     L5
  mov    -0x7f4(%rbp),%esi
  lea    -0x7ec(%rbp),%rcx
  lea    -0x7f0(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    -0x7f0(%rbp),%edx
  mov    -0x7ec(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x7e4(%rbp)
  mov    -0x7e4(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D25
type: string

tool: D25: %d

assistant: ```c
int main() {
  int numbers[500];
  int length, count, min, max = 0, result;
  scanf("%d", &length);
  for (count = 0; count < length; count++) {
    scanf("%d", &numbers[count]);
  }
  minmax(numbers, length, &min, &max);
  result = min + max;
  printf("%d", result);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L2
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D9(%rip),%r12
L5:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L5
L2:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  add    0x8(%rsp),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x7f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D9: %d

assistant: ```c
int main() {
  int numbers[500];
  int length, count, min, max = 0, result;
  scanf("%d", &length);
  for (count = 0; count < length; count++) {
    scanf("%d", &numbers[count]);
  }
  minmax(numbers, length, &min, &max);
  result = min + max;
  printf("%d", result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L17
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L21
L17:
  mov    %r13,%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  add    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d

assistant: ```c
int main() {
  int numbers[500];
  int length, count, min, max = 0, result;
  scanf("%d", &length);
  for (count = 0; count < length; count++) {
    scanf("%d", &numbers[count]);
  }
  minmax(numbers, length, &min, &max);
  result = min + max;
  printf("%d", result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L4
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L21
L4:
  mov    %r13,%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  add    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int main() {
  int numbers[500];
  int length, count, min, max = 0, result;
  scanf("%d", &length);
  for (count = 0; count < length; count++) {
    scanf("%d", &numbers[count]);
  }
  minmax(numbers, length, &min, &max);
  result = min + max;
  printf("%d", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1f,-0x8(%rbp)
  jmp    L20
L1:
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x8(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %esi,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L16
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L16:
  subl   $0x1,-0x8(%rbp)
L20:
  cmpl   $0x0,-0x8(%rbp)
  jns    L1
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t int_sqrt(uint64_t a) {
  uint64_t ret = 0;
  uint64_t ret_sq = 0;
  int s;
  for (s = 31; s >= 0; s--) {
    uint64_t b = ret_sq + (1ULL << (s * 2)) + (ret << s) * 2;
    if (b <= a) {
      ret_sq = b;
      ret += 1ULL << s;
    }
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_sqrt>:
  endbr64
  mov    $0x1f,%eax
  mov    $0x0,%r9d
  mov    $0x0,%esi
  mov    $0x1,%r8d
  jmp    L31
L18:
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  je     L10
L31:
  mov    %esi,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  lea    (%r9,%rdx,2),%edx
  lea    (%rax,%rax,1),%ecx
  mov    %r8,%r10
  shl    %cl,%r10
  add    %r10d,%edx
  cmp    %edi,%edx
  jg     L18
  mov    %r8,%r11
  mov    %eax,%ecx
  shl    %cl,%r11
  add    %r11d,%esi
  mov    %edx,%r9d
  jmp    L18
L10:
  mov    %esi,%eax
  ret
```

assistant: ```c
uint64_t int_sqrt(uint64_t a) {
  uint64_t ret = 0;
  uint64_t ret_sq = 0;
  int s;
  for (s = 31; s >= 0; s--) {
    uint64_t b = ret_sq + (1ULL << (s * 2)) + (ret << s) * 2;
    if (b <= a) {
      ret_sq = b;
      ret += 1ULL << s;
    }
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int_sqrt>:
  endbr64
  mov    $0x1f,%eax
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%esi
  nopl   0x0(%rax)
L11:
  mov    %eax,%ecx
  mov    %r8d,%edx
  mov    %rsi,%r10
  shl    %cl,%edx
  lea    (%rax,%rax,1),%ecx
  lea    (%r9,%rdx,2),%edx
  shl    %cl,%r10
  add    %r10d,%edx
  cmp    %edi,%edx
  jg     L16
  mov    %rsi,%r11
  mov    %eax,%ecx
  mov    %edx,%r9d
  shl    %cl,%r11
  add    %r11d,%r8d
L16:
  sub    $0x1,%eax
  jae    L11
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t int_sqrt(uint64_t a) {
  uint64_t ret = 0;
  uint64_t ret_sq = 0;
  int s;
  for (s = 31; s >= 0; s--) {
    uint64_t b = ret_sq + (1ULL << (s * 2)) + (ret << s) * 2;
    if (b <= a) {
      ret_sq = b;
      ret += 1ULL << s;
    }
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<int_sqrt>:
  endbr64
  mov    $0x1f,%eax
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%esi
  nopl   0x0(%rax)
L12:
  mov    %eax,%ecx
  mov    %r8d,%edx
  mov    %rsi,%r10
  shl    %cl,%edx
  lea    (%rax,%rax,1),%ecx
  lea    (%r9,%rdx,2),%edx
  shl    %cl,%r10
  add    %r10d,%edx
  cmp    %edi,%edx
  jg     L7
  mov    %rsi,%r11
  mov    %eax,%ecx
  mov    %edx,%r9d
  shl    %cl,%r11
  add    %r11d,%r8d
L7:
  sub    $0x1,%eax
  jae    L12
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t int_sqrt(uint64_t a) {
  uint64_t ret = 0;
  uint64_t ret_sq = 0;
  int s;
  for (s = 31; s >= 0; s--) {
    uint64_t b = ret_sq + (1ULL << (s * 2)) + (ret << s) * 2;
    if (b <= a) {
      ret_sq = b;
      ret += 1ULL << s;
    }
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<general_help>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D107(%rip),%rdi
  call   <add_help_line@plt>
  mov    %rbx,%rsi
  lea    D59(%rip),%rdi
  call   <add_help_line@plt>
  addl   $0x1,0x4(%rsp)
  mov    %rbx,%rsi
  lea    D38(%rip),%rdi
  call   <add_help_line@plt>
  addl   $0x1,0x4(%rsp)
  mov    %rbx,%rsi
  lea    D46(%rip),%rdi
  call   <add_help_line@plt>
  mov    %rbx,%rsi
  lea    D116(%rip),%rdi
  call   <add_help_line@plt>
  addl   $0x1,0x4(%rsp)
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  call   <add_help_line@plt>
  mov    %rbx,%rsi
  lea    D58(%rip),%rdi
  call   <add_help_line@plt>
  mov    %rbx,%rsi
  lea    D78(%rip),%rdi
  call   <add_help_line@plt>
  mov    %rbx,%rsi
  lea    D20(%rip),%rdi
  call   <add_help_line@plt>
  mov    %rbx,%rsi
  lea    D40(%rip),%rdi
  call   <add_help_line@plt>
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  call   <add_help_line@plt>
  mov    %rbx,%rsi
  lea    D49(%rip),%rdi
  call   <add_help_line@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D107
data_type: string
name: unpack_data
arguments: label: D59
data_type: string
name: unpack_data
arguments: label: D38
data_type: string
name: unpack_data
arguments: label: D46
data_type: string
name: unpack_data
arguments: label: D116
data_type: string
name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D58
data_type: string
name: unpack_data
arguments: label: D78
data_type: string
name: unpack_data
arguments: label: D20
data_type: string
name: unpack_data
arguments: label: D40
data_type: string
name: unpack_data
arguments: label: D18
data_type: string
name: unpack_data
arguments: label: D49
data_type: string

tool: D107: [0-9] : Switch player view

tool: D59: Z[GHDPB] : Switch zone view

tool: D38: = : Load deck

tool: D46: p : Pass

tool: D116: d : Done

tool: D11: D : Draw

tool: D58: V : Show selected card

tool: D78: M[GDHPB] : Move card to zone

tool: D20: T : Tap selected card

tool: D40: c[0-9] : Transfer card control to player

tool: D18: S[0-9][0-9] : Put into play an x/x token

tool: D49: [+-] : Add/Remove a counter on a card

assistant: ```c
void general_help() {
  int i = 1;
  add_help_line("[0-9] : Switch player view", &i);
  add_help_line("Z[GHDPB] : Switch zone view", &i);
  i++;
  add_help_line("= : Load deck", &i);
  i++;
  add_help_line("p : Pass", &i);
  add_help_line("d : Done", &i);
  i++;
  add_help_line("D : Draw", &i);
  add_help_line("V : Show selected card", &i);
  add_help_line("M[GDHPB] : Move card to zone", &i);
  add_help_line("T : Tap selected card", &i);
  add_help_line("c[0-9] : Transfer card control to player", &i);
  add_help_line("S[0-9][0-9] : Put into play an x/x token", &i);
  add_help_line("[+-] : Add/Remove a counter on a card", &i);
}
```