ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<relax_jacobi_optimized>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  cmp    $0x1,%ebx
  jbe    L12
  mov    %rsi,%r8
  mov    %ecx,%r11d
  lea    -0x2(%rcx,%rcx,1),%ecx
  mov    %r11d,%eax
  neg    %eax
  mov    $0x1,%r10d
  lea    -0x1(%r11),%r12d
  lea    0x2(%rax,%rax,1),%r13d
  mov    $0x2,%ebp
  sub    %r11d,%ebp
  lea    0x1(%r11),%r9d
  movsd  D8(%rip),%xmm1
  jmp    L55
L34:
  lea    0x0(%rbp,%rcx,1),%edx
  mov    %edx,%eax
  lea    0x1(%rcx,%r13,1),%esi
  sub    %edx,%esi
L18:
  lea    (%rsi,%rax,1),%r14d
  lea    (%r9,%rax,1),%edx
  movsd  (%rdi,%r14,8),%xmm0
  addsd  (%rdi,%rdx,8),%xmm0
  mov    %eax,%r14d
  add    $0x1,%eax
  mov    %eax,%edx
  mov    %r14d,%r15d
  addsd  (%rdi,%r15,8),%xmm0
  lea    0x2(%r14),%r14d
  addsd  (%rdi,%r14,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rdx,8)
  cmp    %ecx,%eax
  jne    L18
L50:
  add    $0x1,%r10d
  add    %r11d,%ecx
  cmp    %ebx,%r10d
  je     L12
L55:
  cmp    $0x1,%r12d
  ja     L34
  jmp    L50
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: f64

tool: D8: 0.25

assistant: ```c
void relax_jacobi_optimized(double *u, double *utmp, unsigned sizex, unsigned sizey) {
  int i, j;
  for (j = 1; j < sizex - 1; j++) {
    for (i = 1; i < sizey - 1; i++) {
      utmp[i + j * sizey] = 0.25 * (u[i + (j - 1) * sizey] + u[i + (j + 1) * sizey] + u[(i - 1) + j * sizey] + u[(i + 1) + j * sizey]);
    }
  }
  double *temp = u;
  u = utmp;
  utmp = temp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<relax_jacobi_optimized>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  cmp    $0x1,%ebx
  jbe    L19
  mov    %ecx,%r11d
  mov    $0x2,%ebp
  lea    -0x1(%rcx),%r12d
  mov    %rsi,%r8
  mov    %r11d,%eax
  lea    -0x2(%rcx,%rcx,1),%ecx
  mov    $0x1,%r10d
  sub    %r11d,%ebp
  neg    %eax
  movsd  D8(%rip),%xmm1
  lea    0x1(%r11),%r9d
  lea    0x2(%rax,%rax,1),%r13d
  nopl   0x0(%rax)
L31:
  add    $0x1,%r10d
  cmp    $0x1,%r12d
  jbe    L16
  lea    0x0(%rbp,%rcx,1),%eax
  lea    0x1(%rcx,%r13,1),%esi
  sub    %eax,%esi
  nopl   (%rax)
L0:
  lea    (%rsi,%rax,1),%r14d
  mov    %eax,%r15d
  lea    (%r9,%rax,1),%edx
  movsd  (%rdi,%r14,8),%xmm0
  mov    %r15,%r14
  addsd  (%rdi,%rdx,8),%xmm0
  lea    0x1(%rax),%edx
  add    $0x2,%r14d
  addsd  (%rdi,%r15,8),%xmm0
  mov    %rdx,%rax
  addsd  (%rdi,%r14,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rdx,8)
  cmp    %ecx,%edx
  jne    L0
L16:
  add    %r11d,%ecx
  cmp    %r10d,%ebx
  jne    L31
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: f64

tool: D8: 0.25

assistant: ```c
void relax_jacobi_optimized(double *u, double *utmp, unsigned sizex, unsigned sizey) {
  int i, j;
  for (j = 1; j < sizex - 1; j++) {
    for (i = 1; i < sizey - 1; i++) {
      utmp[i + j * sizey] = 0.25 * (u[i + (j - 1) * sizey] + u[i + (j + 1) * sizey] + u[(i - 1) + j * sizey] + u[(i + 1) + j * sizey]);
    }
  }
  double *temp = u;
  u = utmp;
  utmp = temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<relax_jacobi_optimized>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  cmp    $0x1,%ebx
  jbe    L3
  lea    -0x1(%rcx),%eax
  mov    %ecx,%r11d
  cmp    $0x1,%eax
  jbe    L3
  mov    %r11d,%eax
  mov    $0x2,%ebp
  lea    -0x2(%rcx,%rcx,1),%ecx
  mov    %rsi,%r8
  neg    %eax
  mov    $0x1,%r10d
  lea    0x1(%r11),%r9d
  sub    %r11d,%ebp
  movsd  D1(%rip),%xmm1
  lea    0x2(%rax,%rax,1),%r12d
  nopw   0x0(%rax,%rax,1)
L20:
  lea    0x0(%rbp,%rcx,1),%eax
  lea    0x1(%rcx,%r12,1),%esi
  add    $0x1,%r10d
  sub    %eax,%esi
  nopw   0x0(%rax,%rax,1)
L31:
  lea    (%rsi,%rax,1),%r13d
  mov    %eax,%r14d
  lea    (%r9,%rax,1),%edx
  movsd  (%rdi,%r13,8),%xmm0
  mov    %r14,%r13
  addsd  (%rdi,%rdx,8),%xmm0
  lea    0x1(%rax),%edx
  add    $0x2,%r13d
  addsd  (%rdi,%r14,8),%xmm0
  mov    %rdx,%rax
  addsd  (%rdi,%r13,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rdx,8)
  cmp    %ecx,%edx
  jne    L31
  add    %r11d,%ecx
  cmp    %r10d,%ebx
  jne    L20
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: f64

tool: D1: 0.25

assistant: ```c
void relax_jacobi_optimized(double *u, double *utmp, unsigned sizex, unsigned sizey) {
  int i, j;
  for (j = 1; j < sizex - 1; j++) {
    for (i = 1; i < sizey - 1; i++) {
      utmp[i + j * sizey] = 0.25 * (u[i + (j - 1) * sizey] + u[i + (j + 1) * sizey] + u[(i - 1) + j * sizey] + u[(i + 1) + j * sizey]);
    }
  }
  double *temp = u;
  u = utmp;
  utmp = temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L16
L8:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L29
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  int i;
  for (i = 0; i < strlen(s); i++)
    if (s[i] == c)
      return (char *)(s + i);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strchr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L23
  lea    0x0(%rbp,%rbx,1),%rdx
  movsbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    %r12d,%eax
  jne    L16
  jmp    L10
L23:
  mov    $0x0,%edx
L10:
  mov    %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  int i;
  for (i = 0; i < strlen(s); i++)
    if (s[i] == c)
      return (char *)(s + i);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strchr>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L16:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x0(%rbp,%rbx,1),%r8
  add    $0x1,%rbx
  cmp    %r12d,%eax
  je     L0
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  xor    %r8d,%r8d
L0:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  int i;
  for (i = 0; i < strlen(s); i++)
    if (s[i] == c)
      return (char *)(s + i);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strchr>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x0(%rbp,%rbx,1),%r8
  add    $0x1,%rbx
  cmp    %r12d,%eax
  je     L28
L23:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  xor    %r8d,%r8d
L28:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  int i;
  for (i = 0; i < strlen(s); i++)
    if (s[i] == c)
      return (char *)(s + i);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DeleteSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L144
L77:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x20,%eax
  seta   %dl
  test   %dl,%dl
  jne    L80
  movabs $0x100002600,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L80
  addl   $0x1,-0x14(%rbp)
  jmp    L144
L80:
  movl   $0x0,-0xc(%rbp)
L144:
  cmpl   $0x0,-0xc(%rbp)
  jne    L77
  movl   $0x1,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jne    L88
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L123
L3:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0xa,%eax
  jg     L37
  cmp    $0x9,%eax
  jge    L119
  jmp    L140
L37:
  cmp    $0x20,%eax
  jne    L140
L119:
  addl   $0x1,-0x10(%rbp)
  jmp    L88
L140:
  movl   $0x0,-0xc(%rbp)
  nop
L88:
  cmpl   $0x0,-0xc(%rbp)
  jne    L3
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jne    L84
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <GetSubString@plt>
  jmp    L123
L84:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <GetSubString@plt>
L123:
  leave
  ret
```

assistant: ```c
char *DeleteSpaces(const char *str) {
  int frontcounter = 0;
  int backcounter = 0;
  int goOn = 1;
  while (goOn) {
    switch (str[frontcounter]) {
    case ' ':
    case '\n':
    case '\t':
    case '\r':
      ++frontcounter;
      break;
    default:
      goOn = 0;
    }
  }
  goOn = 1;
  if (frontcounter == strlen(str)) {
    char *p = (char *)malloc(sizeof(char) * 1);
    p[0] = '\0';
    return p;
  }
  while (goOn) {
    switch (str[strlen(str) - 1 - backcounter]) {
    case ' ':
    case '\n':
    case '\t':
      ++backcounter;
      break;
    default:
      goOn = 0;
      break;
    }
  }
  if (frontcounter + backcounter == 0) {
    return GetSubString(str, 0, strlen(str));
  } else {
    return GetSubString(str, frontcounter, strlen(str) - frontcounter - backcounter);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<DeleteSpaces>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  movabs $0x100002600,%rcx
  jmp    L32
L3:
  add    $0x1,%rax
L32:
  mov    %eax,%r12d
  movzbl (%rbx,%rax,1),%edx
  cmp    $0x20,%dl
  ja     L54
  bt     %rdx,%rcx
  jb     L3
L54:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x0,%ebp
  cmp    %r12d,%eax
  jne    L5
  mov    $0x1,%edi
  call   <malloc@plt>
  movb   $0x0,(%rax)
  jmp    L31
L46:
  cmp    $0x20,%al
  jne    L60
L67:
  add    $0x1,%ebp
L5:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  sub    %ebp,%eax
  cltq
  movzbl (%rbx,%rax,1),%eax
  cmp    $0xa,%al
  jg     L46
  cmp    $0x8,%al
  jg     L67
L60:
  mov    %r12d,%eax
  add    %ebp,%eax
  je     L93
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    %r12d,%eax
  mov    %eax,%edx
  sub    %ebp,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <GetSubString@plt>
  jmp    L31
L93:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <GetSubString@plt>
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *DeleteSpaces(const char *str) {
  int frontcounter = 0;
  int backcounter = 0;
  int goOn = 1;
  while (goOn) {
    switch (str[frontcounter]) {
    case ' ':
    case '\n':
    case '\t':
    case '\r':
      ++frontcounter;
      break;
    default:
      goOn = 0;
    }
  }
  goOn = 1;
  if (frontcounter == strlen(str)) {
    char *p = (char *)malloc(sizeof(char) * 1);
    p[0] = '\0';
    return p;
  }
  while (goOn) {
    switch (str[strlen(str) - 1 - backcounter]) {
    case ' ':
    case '\n':
    case '\t':
      ++backcounter;
      break;
    default:
      goOn = 0;
      break;
    }
  }
  if (frontcounter + backcounter == 0) {
    return GetSubString(str, 0, strlen(str));
  } else {
    return GetSubString(str, frontcounter, strlen(str) - frontcounter - backcounter);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DeleteSpaces>:
  endbr64
  movabs $0x100002600,%rcx
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl (%r12,%rax,1),%edx
  mov    %eax,%ebp
  cmp    $0x20,%dl
  ja     L21
  bt     %rdx,%rcx
  jb     L54
L21:
  mov    %r12,%rdi
  xor    %ebx,%ebx
  call   <strlen@plt>
  cmp    %ebp,%eax
  je     L17
  nopl   0x0(%rax)
L51:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  sub    %ebx,%eax
  cltq
  movzbl (%r12,%rax,1),%eax
  cmp    $0xa,%al
  jg     L33
  cmp    $0x8,%al
  jg     L39
L36:
  mov    %ebp,%eax
  add    %ebx,%eax
  je     L40
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  sub    %ebp,%eax
  mov    %eax,%edx
  sub    %ebx,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <GetSubString@plt>
  cs nopw 0x0(%rax,%rax,1)
L54:
  add    $0x1,%rax
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L33:
  cmp    $0x20,%al
  jne    L36
L39:
  add    $0x1,%ebx
  jmp    L51
  nopl   0x0(%rax)
L40:
  mov    %r12,%rdi
  call   <strlen@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  xor    %esi,%esi
  pop    %r12
  jmp    1090 <GetSubString@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%edi
  call   <malloc@plt>
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *DeleteSpaces(const char *str) {
  int frontcounter = 0;
  int backcounter = 0;
  int goOn = 1;
  while (goOn) {
    switch (str[frontcounter]) {
    case ' ':
    case '\n':
    case '\t':
    case '\r':
      ++frontcounter;
      break;
    default:
      goOn = 0;
    }
  }
  goOn = 1;
  if (frontcounter == strlen(str)) {
    char *p = (char *)malloc(sizeof(char) * 1);
    p[0] = '\0';
    return p;
  }
  while (goOn) {
    switch (str[strlen(str) - 1 - backcounter]) {
    case ' ':
    case '\n':
    case '\t':
      ++backcounter;
      break;
    default:
      goOn = 0;
      break;
    }
  }
  if (frontcounter + backcounter == 0) {
    return GetSubString(str, 0, strlen(str));
  } else {
    return GetSubString(str, frontcounter, strlen(str) - frontcounter - backcounter);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DeleteSpaces>:
  endbr64
  movabs $0x100002600,%rcx
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl (%r12,%rax,1),%edx
  mov    %eax,%ebp
  cmp    $0x20,%dl
  ja     L29
  bt     %rdx,%rcx
  jb     L37
L29:
  mov    %r12,%rdi
  xor    %ebx,%ebx
  call   <strlen@plt>
  cmp    %ebp,%eax
  je     L23
  nopl   0x0(%rax)
L62:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  sub    %ebx,%eax
  cltq
  movzbl (%r12,%rax,1),%eax
  cmp    $0xa,%al
  jg     L42
  cmp    $0x8,%al
  jg     L69
L61:
  mov    %ebp,%eax
  add    %ebx,%eax
  je     L28
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  sub    %ebp,%eax
  mov    %eax,%edx
  sub    %ebx,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <GetSubString@plt>
  cs nopw 0x0(%rax,%rax,1)
L37:
  add    $0x1,%rax
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L42:
  cmp    $0x20,%al
  jne    L61
L69:
  add    $0x1,%ebx
  jmp    L62
  nopl   0x0(%rax)
L28:
  mov    %r12,%rdi
  call   <strlen@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  xor    %esi,%esi
  pop    %r12
  jmp    1090 <GetSubString@plt>
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x1,%edi
  call   <malloc@plt>
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *DeleteSpaces(const char *str) {
  int frontcounter = 0;
  int backcounter = 0;
  int goOn = 1;
  while (goOn) {
    switch (str[frontcounter]) {
    case ' ':
    case '\n':
    case '\t':
    case '\r':
      ++frontcounter;
      break;
    default:
      goOn = 0;
    }
  }
  goOn = 1;
  if (frontcounter == strlen(str)) {
    char *p = (char *)malloc(sizeof(char) * 1);
    p[0] = '\0';
    return p;
  }
  while (goOn) {
    switch (str[strlen(str) - 1 - backcounter]) {
    case ' ':
    case '\n':
    case '\t':
      ++backcounter;
      break;
    default:
      goOn = 0;
      break;
    }
  }
  if (frontcounter + backcounter == 0) {
    return GetSubString(str, 0, strlen(str));
  } else {
    return GetSubString(str, frontcounter, strlen(str) - frontcounter - backcounter);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L27:
  cmp    %rcx,%rsp
  je     L64
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L27
L64:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L60
  orq    $0x0,-0x8(%rsp,%rax,1)
L60:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L118
  mov    %rbx,%r13
  mov    $0x0,%r12d
  lea    D25(%rip),%r14
L17:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    -0x2c(%rbp),%esi
  add    $0x4,%r13
  cmp    %r12d,%esi
  jg     L17
  test   %esi,%esi
  jle    L118
  mov    $0x0,%r12d
  lea    D25(%rip),%r13
  jmp    L69
L118:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L138:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
L96:
  mov    -0x2c(%rbp),%esi
  add    $0x1,%r12
  cmp    %r12d,%esi
  jle    L118
L69:
  test   %esi,%esi
  jle    L138
  mov    (%rbx,%r12,4),%edi
  mov    %r12d,%r8d
  cmp    %edi,(%rbx)
  jne    L26
  test   %r12d,%r12d
  jne    L96
L26:
  mov    %esi,%esi
  mov    $0x1,%eax
L81:
  cmp    %rax,%rsi
  je     L138
  cmp    %edi,(%rbx,%rax,4)
  sete   %cl
  cmp    %eax,%r8d
  setne  %dl
  add    $0x1,%rax
  test   %dl,%cl
  je     L81
  jmp    L96
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
datatype: string

tool: D25: %d

assistant: ```c
int main() {
  int a, i, j;
  scanf("%d", &a);
  int arr[a];
  for (i = 0; i < a; i++) {
    scanf("%d", &arr[i]);
  }
  int k = 0;
  for (j = 0; j < a; j++) {
    int count = 0;
    for (k = 0; k < a; k++) {
      if (arr[j] == arr[k] && k != j) {
        count = count + 1;
        if (count >= 1) {
          break;
        }
      }
    }
    if (count == 0)
      printf("%d", arr[j]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  lea    D1(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L113
L96:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L96
L113:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L64
L7:
  mov    %rsp,%rbx
  xor    %r13d,%r13d
  mov    %rbx,%r14
  test   %edx,%edx
  jle    L76
L117:
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  cmp    %r13d,%edx
  jg     L117
  test   %edx,%edx
  jle    L76
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%rbx,%r13,4),%esi
  xor    %eax,%eax
  xchg   %ax,%ax
L91:
  cmp    %esi,(%rbx,%rax,4)
  jne    L109
  cmp    %eax,%r13d
  jne    L10
L109:
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L91
  mov    %r12,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
L10:
  add    $0x1,%r13
  cmp    %r13d,%edx
  jg     L21
L76:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L64:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L7
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type: string

tool: D1: %d

assistant: ```c
int main() {
  int a, i, j;
  scanf("%d", &a);
  int arr[a];
  for (i = 0; i < a; i++) {
    scanf("%d", &arr[i]);
  }
  int k = 0;
  for (j = 0; j < a; j++) {
    int count = 0;
    for (k = 0; k < a; k++) {
      if (arr[j] == arr[k] && k != j) {
        count = count + 1;
        if (count >= 1) {
          break;
        }
      }
    }
    if (count == 0)
      printf("%d", arr[j]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  lea    D0(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L67
L3:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L3
L67:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L18
L119:
  mov    %rsp,%rbx
  xor    %r13d,%r13d
  mov    %rbx,%r14
  test   %edx,%edx
  jle    L57
L5:
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  cmp    %r13d,%edx
  jg     L5
  test   %edx,%edx
  jle    L57
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L39:
  mov    (%rbx,%r13,4),%esi
  xor    %eax,%eax
  xchg   %ax,%ax
L52:
  cmp    %esi,(%rbx,%rax,4)
  jne    L76
  cmp    %eax,%r13d
  jne    L118
L76:
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L52
  mov    %r12,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
L118:
  add    $0x1,%r13
  cmp    %r13d,%edx
  jg     L39
L57:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L18:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L119
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: %d

assistant: ```c
int main() {
  int a, i, j;
  scanf("%d", &a);
  int arr[a];
  for (i = 0; i < a; i++) {
    scanf("%d", &arr[i]);
  }
  int k = 0;
  for (j = 0; j < a; j++) {
    int count = 0;
    for (k = 0; k < a; k++) {
      if (arr[j] == arr[k] && k != j) {
        count = count + 1;
        if (count >= 1) {
          break;
        }
      }
    }
    if (count == 0)
      printf("%d", arr[j]);
  }
  return 0;
}
```