ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <inverse@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L4
L7:
  mov    -0x14(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mod@plt>
L4:
  leave
  ret
```

assistant: ```c
int divide(int x, int y, int base) {
  int i;
  i = inverse(base, y);
  if (i == -1)
    return -1;
  return mod(x * i, base);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<divide>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %edx,%ebx
  mov    %edx,%edi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L2
  imul   %ebp,%eax
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <mod@plt>
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int divide(int x, int y, int base) {
  int i;
  i = inverse(base, y);
  if (i == -1)
    return -1;
  return mod(x * i, base);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %edx,%edi
  sub    $0x8,%rsp
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    %eax,%edi
  add    $0x8,%rsp
  mov    %ebp,%esi
  imul   %ebx,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <mod@plt>
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int divide(int x, int y, int base) {
  int i;
  i = inverse(base, y);
  if (i == -1)
    return -1;
  return mod(x * i, base);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %edx,%edi
  sub    $0x8,%rsp
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    %eax,%edi
  add    $0x8,%rsp
  mov    %ebp,%esi
  imul   %ebx,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <mod@plt>
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int divide(int x, int y, int base) {
  int i;
  i = inverse(base, y);
  if (i == -1)
    return -1;
  return mod(x * i, base);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<req_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0xa2,%esi
  mov    %eax,%edi
  call   <write_head@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int req_open(int sockfd, struct message_s *msg) {
  write_head(sockfd, 0xA2, 1, 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<req_open>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0xa2,%esi
  call   <write_head@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int req_open(int sockfd, struct message_s *msg) {
  write_head(sockfd, 0xA2, 1, 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<req_open>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    $0xa2,%esi
  call   <write_head@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int req_open(int sockfd, struct message_s *msg) {
  write_head(sockfd, 0xA2, 1, 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<req_open>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    $0xa2,%esi
  call   <write_head@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int req_open(int sockfd, struct message_s *msg) {
  write_head(sockfd, 0xA2, 1, 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<otrx_create_align>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  and    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L2
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x28(%rbp)
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <otrx_create_append_zeros@plt>
  jmp    L16
L2:
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
ssize_t otrx_create_align(FILE *trx, size_t curr_offset, size_t alignment) {
  if (curr_offset & (alignment - 1)) {
    size_t length = alignment - (curr_offset % alignment);
    return otrx_create_append_zeros(trx, length);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<otrx_create_align>:
  endbr64
  mov    %rsi,%rax
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%rsi
  mov    $0x0,%edx
  test   %rax,%rsi
  jne    L6
  mov    %edx,%eax
  ret
L6:
  sub    $0x8,%rsp
  mov    $0x0,%edx
  div    %rcx
  sub    %rdx,%rcx
  mov    %rcx,%rsi
  call   <otrx_create_append_zeros@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
ssize_t otrx_create_align(FILE *trx, size_t curr_offset, size_t alignment) {
  if (curr_offset & (alignment - 1)) {
    size_t length = alignment - (curr_offset % alignment);
    return otrx_create_append_zeros(trx, length);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<otrx_create_align>:
  endbr64
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%rdx
  test   %rsi,%rdx
  jne    L1
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rsi,%rax
  xor    %edx,%edx
  div    %rcx
  sub    %rdx,%rcx
  mov    %rcx,%rsi
  jmp    1050 <otrx_create_append_zeros@plt>
```

assistant: ```c
ssize_t otrx_create_align(FILE *trx, size_t curr_offset, size_t alignment) {
  if (curr_offset & (alignment - 1)) {
    size_t length = alignment - (curr_offset % alignment);
    return otrx_create_append_zeros(trx, length);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<otrx_create_align>:
  endbr64
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%rdx
  test   %rsi,%rdx
  jne    L2
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rsi,%rax
  xor    %edx,%edx
  div    %rcx
  sub    %rdx,%rcx
  mov    %rcx,%rsi
  jmp    1050 <otrx_create_append_zeros@plt>
```

assistant: ```c
ssize_t otrx_create_align(FILE *trx, size_t curr_offset, size_t alignment) {
  if (curr_offset & (alignment - 1)) {
    size_t length = alignment - (curr_offset % alignment);
    return otrx_create_append_zeros(trx, length);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <foo@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f4(void) {
  switch (foo())
    break;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f4>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f4(void) {
  switch (foo())
    break;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f4>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
void f4(void) {
  switch (foo())
    break;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f4>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
void f4(void) {
  switch (foo())
    break;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intersect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L55:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L35
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L50
L35:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L59
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L50
L59:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L50:
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L55
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sqd_distance@plt>
  cmp    %eax,-0x24(%rbp)
  setge  %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int intersect(int *hr_min, int *hr_max, int sqd_r, int *t, int k) {
  int *p = calloc(k, sizeof(int)), i = 0;
  int ret = 0;
  for (i = 0; i < k; i++) {
    if (t[i] <= hr_min[i])
      p[i] = hr_min[i];
    else if (t[i] >= hr_max[i])
      p[i] = hr_max[i];
    else
      p[i] = t[i];
  }
  ret = sqd_distance(p, t, k) <= sqd_r;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<intersect>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  mov    %rcx,%rbx
  mov    %r8d,%r13d
  mov    $0x4,%esi
  mov    %r8d,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  test   %r13d,%r13d
  jle    L4
  mov    %r13d,%eax
  mov    $0x0,%edx
  jmp    L16
L37:
  mov    (%r12,%rdx,4),%esi
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  mov    %esi,(%rdi,%rdx,4)
L17:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L4
L16:
  mov    (%rbx,%rdx,4),%ecx
  mov    0x0(%rbp,%rdx,4),%esi
  cmp    %esi,%ecx
  jg     L37
  mov    %esi,(%rdi,%rdx,4)
  jmp    L17
L4:
  mov    %r13d,%edx
  mov    %rbx,%rsi
  call   <sqd_distance@plt>
  cmp    %r14d,%eax
  setle  %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int intersect(int *hr_min, int *hr_max, int sqd_r, int *t, int k) {
  int *p = calloc(k, sizeof(int)), i = 0;
  int ret = 0;
  for (i = 0; i < k; i++) {
    if (t[i] <= hr_min[i])
      p[i] = hr_min[i];
    else if (t[i] >= hr_max[i])
      p[i] = hr_max[i];
    else
      p[i] = t[i];
  }
  ret = sqd_distance(p, t, k) <= sqd_r;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<intersect>:
  endbr64
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x4,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r8d,%edi
  push   %rbx
  mov    %edx,%ebx
  call   <calloc@plt>
  mov    %rax,%rdi
  test   %r14d,%r14d
  jle    L21
  movslq %r14d,%rax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L26:
  mov    0x0(%r13,%rcx,4),%r9d
  mov    0x0(%rbp,%rcx,4),%esi
  cmp    %esi,%r9d
  jle    L22
  mov    (%r12,%rcx,4),%esi
  cmp    %esi,%r9d
  cmovle %r9d,%esi
L22:
  mov    %esi,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L26
L21:
  mov    %r14d,%edx
  mov    %r13,%rsi
  call   <sqd_distance@plt>
  cmp    %ebx,%eax
  pop    %rbx
  pop    %rbp
  setle  %al
  pop    %r12
  pop    %r13
  movzbl %al,%eax
  pop    %r14
  ret
```

assistant: ```c
int intersect(int *hr_min, int *hr_max, int sqd_r, int *t, int k) {
  int *p = calloc(k, sizeof(int)), i = 0;
  int ret = 0;
  for (i = 0; i < k; i++) {
    if (t[i] <= hr_min[i])
      p[i] = hr_min[i];
    else if (t[i] >= hr_max[i])
      p[i] = hr_max[i];
    else
      p[i] = t[i];
  }
  ret = sqd_distance(p, t, k) <= sqd_r;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<intersect>:
  endbr64
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x4,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r8d,%edi
  push   %rbx
  mov    %edx,%ebx
  call   <calloc@plt>
  mov    %rax,%rdi
  test   %r14d,%r14d
  jle    L0
  movslq %r14d,%rax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L6:
  mov    0x0(%r13,%rcx,4),%r9d
  mov    0x0(%rbp,%rcx,4),%esi
  cmp    %esi,%r9d
  jle    L8
  mov    (%r12,%rcx,4),%esi
  cmp    %esi,%r9d
  cmovle %r9d,%esi
L8:
  mov    %esi,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jne    L6
L0:
  mov    %r14d,%edx
  mov    %r13,%rsi
  call   <sqd_distance@plt>
  cmp    %ebx,%eax
  pop    %rbx
  pop    %rbp
  setle  %al
  pop    %r12
  pop    %r13
  movzbl %al,%eax
  pop    %r14
  ret
```

assistant: ```c
int intersect(int *hr_min, int *hr_max, int sqd_r, int *t, int k) {
  int *p = calloc(k, sizeof(int)), i = 0;
  int ret = 0;
  for (i = 0; i < k; i++) {
    if (t[i] <= hr_min[i])
      p[i] = hr_min[i];
    else if (t[i] >= hr_max[i])
      p[i] = hr_max[i];
    else
      p[i] = t[i];
  }
  ret = sqd_distance(p, t, k) <= sqd_r;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<plainstring_sum_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <plainstring_new_plainstring@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  cmpq   $0x0,-0x20(%rbp)
  je     L12
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <plainstring_add@plt>
L12:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct plainstring *plainstring_sum_str(struct plainstring *this_string, const char *other) {
  struct plainstring *str = plainstring_new_plainstring(this_string);
  if ((str) && (other))
    plainstring_add(str, other);
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<plainstring_sum_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <plainstring_new_plainstring@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L25
  test   %rbp,%rbp
  jne    L3
L25:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <plainstring_add@plt>
  jmp    L25
```

assistant: ```c
struct plainstring *plainstring_sum_str(struct plainstring *this_string, const char *other) {
  struct plainstring *str = plainstring_new_plainstring(this_string);
  if ((str) && (other))
    plainstring_add(str, other);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<plainstring_sum_str>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <plainstring_new_plainstring@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  test   %rbp,%rbp
  jne    L19
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <plainstring_add@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct plainstring *plainstring_sum_str(struct plainstring *this_string, const char *other) {
  struct plainstring *str = plainstring_new_plainstring(this_string);
  if ((str) && (other))
    plainstring_add(str, other);
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<plainstring_sum_str>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <plainstring_new_plainstring@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  test   %rbp,%rbp
  jne    L12
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <plainstring_add@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct plainstring *plainstring_sum_str(struct plainstring *this_string, const char *other) {
  struct plainstring *str = plainstring_new_plainstring(this_string);
  if ((str) && (other))
    plainstring_add(str, other);
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vmake_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x64,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L2
L26:
  mov    -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L64
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L64
  mov    -0x10(%rbp),%rax
  jmp    L2
L64:
  cmpl   $0x0,-0x14(%rbp)
  js     L75
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L96
L75:
  shll   -0x1c(%rbp)
L96:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L2
L28:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L26
L2:
  leave
  ret
```

assistant: ```c
char *vmake_message(const char *fmt, va_list ap) {
  int n, size = 100;
  char *p;
  p = (char *)malloc(size);
  if (!p)
    return (NULL);
  while (1) {
    char *np;
    va_list apc;
    va_copy(apc, ap);
    n = vsnprintf(p, size, fmt, apc);
    if (n > -1 && n < size)
      return (p);
    if (n > -1)
      size = n + 1;
    else
      size *= 2;
    np = (char *)realloc(p, size);
    if (!np) {
      free(p);
      return (NULL);
    }
    p = np;
  }
  return (NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vmake_message>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    $0x64,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L57
  mov    %rax,%rbp
  mov    $0x64,%ebx
  jmp    L66
L54:
  lea    0x1(%rax),%edx
  add    %ebx,%ebx
  test   %eax,%eax
  cmovns %edx,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbp
L66:
  mov    %r13d,%esi
  mov    $0x0,%r14d
  mov    %r14d,%edi
  call   <va_copy@plt>
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  test   %eax,%eax
  js     L54
  cmp    %eax,%ebx
  jle    L54
L32:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%ebp
  jmp    L32
L57:
  mov    $0x0,%ebp
  jmp    L32
```

assistant: ```c
char *vmake_message(const char *fmt, va_list ap) {
  int n, size = 100;
  char *p;
  p = (char *)malloc(size);
  if (!p)
    return (NULL);
  while (1) {
    char *np;
    va_list apc;
    va_copy(apc, ap);
    n = vsnprintf(p, size, fmt, apc);
    if (n > -1 && n < size)
      return (p);
    if (n > -1)
      size = n + 1;
    else
      size *= 2;
    np = (char *)realloc(p, size);
    if (!np) {
      free(p);
      return (NULL);
    }
    p = np;
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vmake_message>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x64,%edi
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
  mov    $0x64,%ebx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L3:
  add    %ebx,%ebx
  lea    0x1(%rax),%edx
  test   %eax,%eax
  mov    %r12,%rdi
  cmovns %edx,%ebx
  mov    %ebx,%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%r12
L14:
  xor    %r14d,%r14d
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <va_copy@plt>
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  cmp    %eax,%ebx
  jbe    L3
L27:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *vmake_message(const char *fmt, va_list ap) {
  int n, size = 100;
  char *p;
  p = (char *)malloc(size);
  if (!p)
    return (NULL);
  while (1) {
    char *np;
    va_list apc;
    va_copy(apc, ap);
    n = vsnprintf(p, size, fmt, apc);
    if (n > -1 && n < size)
      return (p);
    if (n > -1)
      size = n + 1;
    else
      size *= 2;
    np = (char *)realloc(p, size);
    if (!np) {
      free(p);
      return (NULL);
    }
    p = np;
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vmake_message>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x64,%edi
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L22
  mov    $0x64,%ebx
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L11:
  add    %ebx,%ebx
  lea    0x1(%rax),%edx
  test   %eax,%eax
  mov    %r12,%rdi
  cmovns %edx,%ebx
  mov    %ebx,%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%r12
L31:
  xor    %r14d,%r14d
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <va_copy@plt>
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  cmp    %eax,%ebx
  jbe    L11
L22:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *vmake_message(const char *fmt, va_list ap) {
  int n, size = 100;
  char *p;
  p = (char *)malloc(size);
  if (!p)
    return (NULL);
  while (1) {
    char *np;
    va_list apc;
    va_copy(apc, ap);
    n = vsnprintf(p, size, fmt, apc);
    if (n > -1 && n < size)
      return (p);
    if (n > -1)
      size = n + 1;
    else
      size *= 2;
    np = (char *)realloc(p, size);
    if (!np) {
      free(p);
      return (NULL);
    }
    p = np;
  }
  return (NULL);
}
```