ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  xor    $0xffffffdb,%eax
  and    $0xffffffdd,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        if (state[0UL] == local2 << (((local1 >> (unsigned char)4) & (unsigned char)7) | 1UL)) {
          state[local2] = state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
          state[0UL] <<= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
        } else {
          state[0UL] = state[local1] | state[local2];
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 604758237UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  xor    $0xffffffdb,%eax
  and    $0xffffffdd,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        if (state[0UL] == local2 << (((local1 >> (unsigned char)4) & (unsigned char)7) | 1UL)) {
          state[local2] = state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
          state[0UL] <<= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
        } else {
          state[0UL] = state[local1] | state[local2];
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 604758237UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<metal_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L7
L19:
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  ja     L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long metal_log2(unsigned long in) {
  unsigned long result;
  assert((in & (in - 1)) == 0);
  for (result = 0; (1UL << result) < in; result++)
    ;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<metal_log2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rdi),%rax
  test   %rdi,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x1,%rbx
  jbe    L1
  mov    $0x0,%ecx
  mov    $0x1,%edx
L6:
  add    $0x1,%rcx
  mov    %rdx,%rax
  shl    %cl,%rax
  cmp    %rbx,%rax
  jb     L6
L7:
  mov    %rcx,%rax
  pop    %rbx
  ret
L1:
  mov    $0x0,%ecx
  jmp    L7
```

assistant: ```c
unsigned long metal_log2(unsigned long in) {
  unsigned long result;
  assert((in & (in - 1)) == 0);
  for (result = 0; (1UL << result) < in; result++)
    ;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<metal_log2>:
  endbr64
  lea    -0x1(%rdi),%rax
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %ecx,%ecx
  cmp    $0x1,%rbx
  jbe    L12
  mov    $0x1,%edx
  nopl   0x0(%rax)
L4:
  add    $0x1,%rcx
  mov    %rdx,%rax
  shl    %cl,%rax
  cmp    %rbx,%rax
  jb     L4
L12:
  mov    %rcx,%rax
  pop    %rbx
  ret
```

assistant: ```c
unsigned long metal_log2(unsigned long in) {
  unsigned long result;
  assert((in & (in - 1)) == 0);
  for (result = 0; (1UL << result) < in; result++)
    ;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<metal_log2>:
  endbr64
  lea    -0x1(%rdi),%rax
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %ecx,%ecx
  cmp    $0x1,%rbx
  jbe    L19
  mov    $0x1,%edx
  nopl   0x0(%rax)
L4:
  add    $0x1,%rcx
  mov    %rdx,%rax
  shl    %cl,%rax
  cmp    %rbx,%rax
  jb     L4
L19:
  mov    %rcx,%rax
  pop    %rbx
  ret
```

assistant: ```c
unsigned long metal_log2(unsigned long in) {
  unsigned long result;
  assert((in & (in - 1)) == 0);
  for (result = 0; (1UL << result) < in; result++)
    ;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cutext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L14:
  nop
  leave
  ret
```

assistant: ```c
void cutext(char *fid) {
  char *p;
  if ((p = strrchr(fid, '/')) == 0)
    p = fid;
  if ((p = strrchr(p, '.')) != 0)
    *p = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cutext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  cmove  %rbx,%rdi
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
L9:
  pop    %rbx
  ret
```

assistant: ```c
void cutext(char *fid) {
  char *p;
  if ((p = strrchr(fid, '/')) == 0)
    p = fid;
  if ((p = strrchr(p, '.')) != 0)
    *p = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<cutext>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  mov    %rax,%rdi
  cmove  %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax)
L4:
  pop    %rbx
  ret
```

assistant: ```c
void cutext(char *fid) {
  char *p;
  if ((p = strrchr(fid, '/')) == 0)
    p = fid;
  if ((p = strrchr(p, '.')) != 0)
    *p = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cutext>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  mov    %rax,%rdi
  cmove  %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax)
L8:
  pop    %rbx
  ret
```

assistant: ```c
void cutext(char *fid) {
  char *p;
  if ((p = strrchr(fid, '/')) == 0)
    p = fid;
  if ((p = strrchr(p, '.')) != 0)
    *p = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
datatype: string
name: unpack_data
arguments: data_tag: D14
datatype: string

tool: D16: Hello, Tokyo!


tool: D14: obs-worksohp for openSUSE.Asia Summit 2017


assistant: ```c
int main() {
  printf("Hello, Tokyo!\n");
  printf("obs-worksohp for openSUSE.Asia Summit 2017\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string

tool: D14: Hello, Tokyo!


tool: D11: obs-worksohp for openSUSE.Asia Summit 2017


assistant: ```c
int main() {
  printf("Hello, Tokyo!\n");
  printf("obs-worksohp for openSUSE.Asia Summit 2017\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D6
type: string

tool: D12: Hello, Tokyo!


tool: D6: obs-worksohp for openSUSE.Asia Summit 2017


assistant: ```c
int main() {
  printf("Hello, Tokyo!\n");
  printf("obs-worksohp for openSUSE.Asia Summit 2017\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string

tool: D5: Hello, Tokyo!


tool: D18: obs-worksohp for openSUSE.Asia Summit 2017


assistant: ```c
int main() {
  printf("Hello, Tokyo!\n");
  printf("obs-worksohp for openSUSE.Asia Summit 2017\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L60:
  cmp    %rdx,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L60
L12:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L23
  orq    $0x0,-0x8(%rsp,%rax,1)
L23:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L4
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,8),%r15
L72:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D8(%rip),%xmm0
  subsd  D20(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L72
L4:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L36
  mov    $0x0,%ebx
L97:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <c_dnrm2@plt>
  ucomisd %xmm0,%xmm0
  jp     L6
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L97
L36:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L87:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L91
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L6:
  lea    D1(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L87
L91:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: f64
name: unpack_data
arguments: label: D20
type_guessed: f64
name: unpack_data
arguments: label: D1
type_guessed: string

tool: D8: 20000

tool: D20: 10000

tool: D1: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double z;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  z = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    z = c_dnrm2(len, x, 1);
    if (z != z) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (z != z) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L48
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L38
L48:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L37
L28:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L117
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L73:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D17(%rip),%xmm0
  subsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L73
L117:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L45
  xor    %r14d,%r14d
  jmp    L4
  nopl   0x0(%rax)
L105:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L45
L4:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <c_dnrm2@plt>
  ucomisd %xmm0,%xmm0
  jnp    L105
  lea    D26(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L63:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L63
  cs nopw 0x0(%rax,%rax,1)
L37:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L28
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D26
type_guessed: string

tool: D17: 20000

tool: D15: 10000

tool: D26: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double z;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  z = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    z = c_dnrm2(len, x, 1);
    if (z != z) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (z != z) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L87
L102:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L102
L87:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L6
L56:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L49
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L114:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D29(%rip),%xmm0
  subsd  D21(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L114
L49:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L52
  xor    %r14d,%r14d
  jmp    L89
  nopl   0x0(%rax)
L86:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L52
L89:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <c_dnrm2@plt>
  ucomisd %xmm0,%xmm0
  jnp    L86
  lea    D12(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L33:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L52:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L6:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L56
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
datatype: f64
name: read_data
arguments: data_tag: D21
datatype: f64
name: read_data
arguments: data_tag: D12
datatype: string

tool: D29: 20000

tool: D21: 10000

tool: D12: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double z;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  z = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    z = c_dnrm2(len, x, 1);
    if (z != z) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (z != z) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hamming84_enc_symbol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0xd,%eax
  mov    %eax,%edi
  call   <count_ones@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0xb,%eax
  mov    %eax,%edi
  call   <count_ones@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0x8,%eax
  mov    %eax,%edi
  call   <count_ones@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%edi
  call   <count_ones@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0x4,%eax
  mov    %eax,%edi
  call   <count_ones@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0x2,%eax
  mov    %eax,%edi
  call   <count_ones@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edi
  call   <count_ones@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0xe,%eax
  mov    %eax,%edi
  call   <count_ones@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x7,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  shl    $0x6,%eax
  or     %eax,%edx
  mov    -0x1c(%rbp),%eax
  shl    $0x5,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%eax
  or     %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  or     %edx,%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int hamming84_enc_symbol(unsigned int _p) {
  unsigned int x0 = count_ones(_p & 0x0d) % 2;
  unsigned int x1 = count_ones(_p & 0x0b) % 2;
  unsigned int x2 = count_ones(_p & 0x08) % 2;
  unsigned int x3 = count_ones(_p & 0x07) % 2;
  unsigned int x4 = count_ones(_p & 0x04) % 2;
  unsigned int x5 = count_ones(_p & 0x02) % 2;
  unsigned int x6 = count_ones(_p & 0x01) % 2;
  unsigned int x7 = count_ones(_p & 0x0e) % 2;
  unsigned int x = (x0 << 7) | (x1 << 6) | (x2 << 5) | (x3 << 4) | (x4 << 3) | (x5 << 2) | (x6 << 1) | (x7);
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<hamming84_enc_symbol>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  and    $0xd,%edi
  call   <count_ones@plt>
  mov    %eax,%ebx
  mov    %r15d,%edi
  and    $0xb,%edi
  call   <count_ones@plt>
  mov    %eax,%r14d
  mov    %r15d,%edi
  and    $0x8,%edi
  call   <count_ones@plt>
  mov    %eax,%r13d
  mov    %r15d,%edi
  and    $0x7,%edi
  call   <count_ones@plt>
  mov    %eax,%r12d
  mov    %r15d,%edi
  and    $0x4,%edi
  call   <count_ones@plt>
  mov    %eax,%ebp
  mov    %r15d,%edi
  and    $0x2,%edi
  call   <count_ones@plt>
  mov    %eax,0x8(%rsp)
  mov    %r15d,%edi
  and    $0x1,%edi
  call   <count_ones@plt>
  mov    %eax,0xc(%rsp)
  mov    %r15d,%edi
  and    $0xe,%edi
  call   <count_ones@plt>
  mov    %eax,%edx
  mov    %ebx,%ecx
  shr    $0x1f,%ecx
  lea    (%rbx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  shl    $0x7,%eax
  mov    %r14d,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%r14d
  and    $0x1,%r14d
  sub    %ecx,%r14d
  shl    $0x6,%r14d
  or     %r14d,%eax
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  or     %edx,%eax
  mov    %r13d,%edx
  shr    $0x1f,%edx
  add    %edx,%r13d
  and    $0x1,%r13d
  sub    %edx,%r13d
  shl    $0x5,%r13d
  or     %r13d,%eax
  mov    %r12d,%edx
  shr    $0x1f,%edx
  add    %edx,%r12d
  and    $0x1,%r12d
  sub    %edx,%r12d
  shl    $0x4,%r12d
  or     %r12d,%eax
  mov    %ebp,%edx
  shr    $0x1f,%edx
  add    %edx,%ebp
  and    $0x1,%ebp
  sub    %edx,%ebp
  shl    $0x3,%ebp
  or     %ebp,%eax
  mov    0x8(%rsp),%esi
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%esi
  mov    %esi,%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  shl    $0x2,%edx
  or     %edx,%eax
  mov    0xc(%rsp),%ebx
  mov    %ebx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%ebx
  mov    %ebx,%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  add    %edx,%edx
  or     %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned int hamming84_enc_symbol(unsigned int _p) {
  unsigned int x0 = count_ones(_p & 0x0d) % 2;
  unsigned int x1 = count_ones(_p & 0x0b) % 2;
  unsigned int x2 = count_ones(_p & 0x08) % 2;
  unsigned int x3 = count_ones(_p & 0x07) % 2;
  unsigned int x4 = count_ones(_p & 0x04) % 2;
  unsigned int x5 = count_ones(_p & 0x02) % 2;
  unsigned int x6 = count_ones(_p & 0x01) % 2;
  unsigned int x7 = count_ones(_p & 0x0e) % 2;
  unsigned int x = (x0 << 7) | (x1 << 6) | (x2 << 5) | (x3 << 4) | (x4 << 3) | (x5 << 2) | (x6 << 1) | (x7);
  return x;
}
```