ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<dvn>:
  endbr64
  divss  %xmm1,%xmm0
  comiss D4(%rip),%xmm0
  ja     L17
  movss  D0(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L10
L17:
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D0
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D31
type_guessed: string
name: disassemble_data
arguments: data_label: D12
type_guessed: string

tool: {"D4": [0x7f,0x96,0x18,0x4b]}

tool: {"D0": [0x7f,0x96,0x18,0xcb]}

tool: D31: ERROR 5

tool: D12: 


assistant: ```c
float dvn(float f, float s) {
  float t;
  t = f / s;
  if (t > 9999999 || t < -9999999) {
    printf("ERROR 5");
    printf("\n");
    exit(0);
  } else {
    return t;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dvn>:
  endbr64
  divss  %xmm1,%xmm0
  comiss D11(%rip),%xmm0
  ja     L5
  movss  D29(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L9
L5:
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
type_guessed: byte[4]
name: parse_data
arguments: tag: D29
type_guessed: byte[4]
name: parse_data
arguments: tag: D23
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: string

tool: {"D11": [0x7f,0x96,0x18,0x4b]}

tool: {"D29": [0x7f,0x96,0x18,0xcb]}

tool: D23: ERROR 5

tool: D27: 


assistant: ```c
float dvn(float f, float s) {
  float t;
  t = f / s;
  if (t > 9999999 || t < -9999999) {
    printf("ERROR 5");
    printf("\n");
    exit(0);
  } else {
    return t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <init@plt>
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L41
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <odd@plt>
  jmp    L0
L41:
  movzbl -0x9(%rbp),%eax
  and    $0x3,%eax
  test   %al,%al
  je     L4
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <odd_even@plt>
  jmp    L0
L4:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <even_even@plt>
L0:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <print@plt>
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <verify@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string

tool: D16: Please input a number:

tool: D18: %d

assistant: ```c
int main() {
  unsigned char number;
  printf("Please input a number:");
  scanf("%d", &number);
  init();
  if (number & 2)
    odd(1, 0, 0, number);
  else if (number % 4)
    odd_even(number);
  else
    even_even(number);
  print(number);
  verify(number);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <init@plt>
  movzbl 0x7(%rsp),%eax
  movzbl %al,%edi
  test   $0x2,%al
  jne    L26
  test   $0x3,%al
  je     L33
  call   <odd_even@plt>
L38:
  movzbl 0x7(%rsp),%edi
  call   <print@plt>
  movzbl 0x7(%rsp),%edi
  call   <verify@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L26:
  mov    %edi,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <odd@plt>
  jmp    L38
L33:
  call   <even_even@plt>
  jmp    L38
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
datatype: string
name: disassemble_data
arguments: label: D12
datatype: string

tool: D14: Please input a number:

tool: D12: %d

assistant: ```c
int main() {
  unsigned char number;
  printf("Please input a number:");
  scanf("%d", &number);
  init();
  if (number & 2)
    odd(1, 0, 0, number);
  else if (number % 4)
    odd_even(number);
  else
    even_even(number);
  print(number);
  verify(number);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <init@plt>
  movzbl 0x7(%rsp),%edi
  mov    %edi,%eax
  test   $0x2,%al
  jne    L35
  test   $0x3,%al
  jne    L0
  call   <even_even@plt>
L11:
  movzbl 0x7(%rsp),%edi
  call   <print@plt>
  movzbl 0x7(%rsp),%edi
  call   <verify@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <odd_even@plt>
  jmp    L11
L35:
  mov    %edi,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <odd@plt>
  jmp    L11
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D10
type: string

tool: D12: Please input a number:

tool: D10: %d

assistant: ```c
int main() {
  unsigned char number;
  printf("Please input a number:");
  scanf("%d", &number);
  init();
  if (number & 2)
    odd(1, 0, 0, number);
  else if (number % 4)
    odd_even(number);
  else
    even_even(number);
  print(number);
  verify(number);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <init@plt>
  movzbl 0x7(%rsp),%edi
  mov    %edi,%eax
  test   $0x2,%al
  jne    L26
  test   $0x3,%al
  jne    L17
  call   <even_even@plt>
L23:
  movzbl 0x7(%rsp),%edi
  call   <print@plt>
  movzbl 0x7(%rsp),%edi
  call   <verify@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L17:
  call   <odd_even@plt>
  jmp    L23
L26:
  mov    %edi,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <odd@plt>
  jmp    L23
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D16: Please input a number:

tool: D5: %d

assistant: ```c
int main() {
  unsigned char number;
  printf("Please input a number:");
  scanf("%d", &number);
  init();
  if (number & 2)
    odd(1, 0, 0, number);
  else if (number % 4)
    odd_even(number);
  else
    even_even(number);
  print(number);
  verify(number);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  foo(1, 2, 0);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  foo(1, 2, 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  foo(1, 2, 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  foo(1, 2, 0);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 1;
  int c = 2, d = 3;
  return a + b + c - d;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 1;
  int c = 2, d = 3;
  return a + b + c - d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 1;
  int c = 2, d = 3;
  return a + b + c - d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 1;
  int c = 2, d = 3;
  return a + b + c - d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  mov    $0x0,%eax
  call   <local@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: D4: 
La variable local x en main es: %d


assistant: ```c
int main() {
  int x = 5;
  local();
  printf("\nLa variable local x en main es: %d\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <local@plt>
  mov    $0x5,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: 
La variable local x en main es: %d


assistant: ```c
int main() {
  int x = 5;
  local();
  printf("\nLa variable local x en main es: %d\n", x);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <local@plt>
  mov    $0x5,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: 
La variable local x en main es: %d


assistant: ```c
int main() {
  int x = 5;
  local();
  printf("\nLa variable local x en main es: %d\n", x);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <local@plt>
  mov    $0x5,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D0: 
La variable local x en main es: %d


assistant: ```c
int main() {
  int x = 5;
  local();
  printf("\nLa variable local x en main es: %d\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hs_write_varint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L14
L11:
  mov    -0x20(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  or     $0xffffff80,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  shrq   $0x7,-0x20(%rbp)
L25:
  cmpq   $0x0,-0x20(%rbp)
  jne    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  and    $0x7f,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int hs_write_varint(unsigned char *buf, unsigned long long i) {
  int pos = 0;
  if (i == 0) {
    buf[pos] = 0;
    return 1;
  }
  while (i) {
    buf[pos++] = (i & 0x7F) | 0x80;
    i >>= 7;
  }
  buf[pos - 1] &= 0x7F;
  return pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hs_write_varint>:
  endbr64
  mov    $0x1,%eax
  test   %rsi,%rsi
  je     L28
L6:
  mov    %eax,%ecx
  mov    %esi,%edx
  or     $0xffffff80,%edx
  mov    %dl,-0x1(%rdi,%rax,1)
  add    $0x1,%rax
  shr    $0x7,%rsi
  jne    L6
  movslq %ecx,%rax
  andb   $0x7f,-0x1(%rdi,%rax,1)
L8:
  mov    %ecx,%eax
  ret
L28:
  movb   $0x0,(%rdi)
  mov    $0x1,%ecx
  jmp    L8
```

assistant: ```c
int hs_write_varint(unsigned char *buf, unsigned long long i) {
  int pos = 0;
  if (i == 0) {
    buf[pos] = 0;
    return 1;
  }
  while (i) {
    buf[pos++] = (i & 0x7F) | 0x80;
    i >>= 7;
  }
  buf[pos - 1] &= 0x7F;
  return pos;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hs_write_varint>:
  endbr64
  mov    $0x1,%ecx
  mov    %rdi,%rax
  sub    %edi,%ecx
  test   %rsi,%rsi
  je     L19
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %esi,%edx
  mov    %esi,%edi
  lea    (%rcx,%rax,1),%r8d
  mov    %rax,%r9
  or     $0xffffff80,%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  shr    $0x7,%rsi
  jne    L2
  and    $0x7f,%edi
  mov    %r8d,%eax
  mov    %dil,(%r9)
  ret
  nopl   (%rax)
L19:
  mov    $0x1,%r8d
  movb   $0x0,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hs_write_varint(unsigned char *buf, unsigned long long i) {
  int pos = 0;
  if (i == 0) {
    buf[pos] = 0;
    return 1;
  }
  while (i) {
    buf[pos++] = (i & 0x7F) | 0x80;
    i >>= 7;
  }
  buf[pos - 1] &= 0x7F;
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hs_write_varint>:
  endbr64
  mov    $0x1,%ecx
  mov    %rdi,%rax
  sub    %edi,%ecx
  test   %rsi,%rsi
  je     L4
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %esi,%edx
  mov    %esi,%edi
  lea    (%rcx,%rax,1),%r8d
  mov    %rax,%r9
  or     $0xffffff80,%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  shr    $0x7,%rsi
  jne    L16
  and    $0x7f,%edi
  mov    %r8d,%eax
  mov    %dil,(%r9)
  ret
  nopl   (%rax)
L4:
  mov    $0x1,%r8d
  movb   $0x0,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hs_write_varint(unsigned char *buf, unsigned long long i) {
  int pos = 0;
  if (i == 0) {
    buf[pos] = 0;
    return 1;
  }
  while (i) {
    buf[pos++] = (i & 0x7F) | 0x80;
    i >>= 7;
  }
  buf[pos - 1] &= 0x7F;
  return pos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1ac(%rbp)
  jmp    L126
L8:
  mov    -0x1ac(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1ac(%rbp)
L126:
  cmpl   $0x63,-0x1ac(%rbp)
  jle    L8
  movl   $0x0,-0x1a0(%rbp)
  movl   $0x1,-0x1ac(%rbp)
  jmp    L3
L12:
  mov    -0x1ac(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1a8(%rbp)
  jmp    L133
L43:
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L55
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L55
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    -0x1ac(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x1a0(%rbp,%rdx,4),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L55
  mov    -0x1a8(%rbp),%eax
  cltq
  movl   $0x0,-0x1a0(%rbp,%rax,4)
L55:
  addl   $0x1,-0x1a8(%rbp)
L133:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L43
  addl   $0x1,-0x1ac(%rbp)
L3:
  mov    $0x64,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x1ac(%rbp)
  jl     L12
  movl   $0x0,-0x1ac(%rbp)
  jmp    L45
L108:
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L138
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1a4(%rbp)
L138:
  mov    -0x1a4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x1a4(%rbp)
L16:
  addl   $0x1,-0x1ac(%rbp)
L45:
  cmpl   $0x63,-0x1ac(%rbp)
  jle    L108
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: %5d

assistant: ```c
void main() {
  int i, j, n;
  int a[100];
  for (i = 0; i < 100; i++)
    a[i] = i + 1;
  a[0] = 0;
  for (i = 1; i < sqrt(100); i++) {
    for (j = i + 1; j < 100; j++) {
      if (a[i] != 0 && a[j] != 0 && a[j] % a[i] == 0)
        a[j] = 0;
    }
  }
  for (i = 0; i < 100; i++) {
    if (a[i] != 0) {
      printf("%5d", a[i]);
      n++;
    }
    if (n % 10 == 0) {
      printf("\n");
      n = 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
L48:
  mov    %eax,-0x4(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x65,%rax
  jne    L48
  movl   $0x0,(%rsp)
  lea    0x4(%rsp),%rbx
  mov    $0x1,%r12d
  mov    $0x62,%r13d
  jmp    L158
L120:
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  je     L110
L132:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L120
  mov    0x4(%rcx),%eax
  test   %eax,%eax
  je     L120
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L120
  movl   $0x0,0x4(%rcx)
  jmp    L120
L110:
  add    $0x1,%r12
  add    $0x4,%rbx
L158:
  mov    $0x64,%edi
  call   <sqrt@plt>
  cmp    %r12d,%eax
  jle    L111
  lea    0x1(%r12),%eax
  cmp    $0x63,%eax
  jg     L110
  mov    %r13d,%eax
  sub    %r12d,%eax
  add    %r12,%rax
  lea    0x4(%rsp,%rax,4),%rdi
  mov    %rbx,%rcx
  jmp    L132
L111:
  mov    %rsp,%r12
  lea    0x190(%rsp),%r13
  lea    D2(%rip),%r14
  jmp    L27
L30:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  jmp    L16
L25:
  add    $0x4,%r12
  cmp    %r13,%r12
  je     L11
L27:
  mov    (%r12),%esi
  test   %esi,%esi
  jne    L30
L16:
  movslq %ebp,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %ebp,%ebx
  sub    %eax,%ebx
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%ebp
  jmp    L25
L11:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  add    $0x1a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %5d

assistant: ```c
void main() {
  int i, j, n;
  int a[100];
  for (i = 0; i < 100; i++)
    a[i] = i + 1;
  a[0] = 0;
  for (i = 1; i < sqrt(100); i++) {
    for (j = i + 1; j < 100; j++) {
      if (a[i] != 0 && a[j] != 0 && a[j] % a[i] == 0)
        a[j] = 0;
    }
  }
  for (i = 0; i < 100; i++) {
    if (a[i] != 0) {
      printf("%5d", a[i]);
      n++;
    }
    if (n % 10 == 0) {
      printf("\n");
      n = 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  mov    $0x1,%eax
  mov    %rsp,%rdx
  xchg   %ax,%ax
L64:
  mov    %eax,-0x4(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    $0x65,%rax
  jne    L64
  lea    0x4(%rsp),%rbx
  mov    $0x64,%edi
  mov    $0x1,%r15d
  mov    $0x62,%ebp
  mov    %rbx,%r13
  mov    %rbx,%r12
  call   <sqrt@plt>
  cmp    %r15d,%eax
  jle    L46
  nopl   0x0(%rax,%rax,1)
L99:
  lea    0x1(%r15),%eax
  cmp    $0x63,%eax
  jg     L112
  mov    %ebp,%eax
  mov    %r12,%rcx
  sub    %r15d,%eax
  add    %r15,%rax
  lea    (%rbx,%rax,4),%rdi
L108:
  mov    (%r12),%esi
  test   %esi,%esi
  je     L11
  mov    0x4(%rcx),%eax
  test   %eax,%eax
  je     L11
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L11
  movl   $0x0,0x4(%rcx)
  nopl   (%rax)
L11:
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L108
L112:
  mov    $0x64,%edi
  add    $0x1,%r15
  add    $0x4,%r12
  call   <sqrt@plt>
  cmp    %r15d,%eax
  jg     L99
L46:
  lea    0x190(%rsp),%rbp
  mov    $0xcccccccd,%ebx
  lea    D6(%rip),%r12
  jmp    L98
  cs nopw 0x0(%rax,%rax,1)
L29:
  cmp    %rbp,%r13
  je     L62
L39:
  mov    0x0(%r13),%esi
  test   %esi,%esi
  je     L121
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <printf@plt>
L121:
  add    $0x4,%r13
L98:
  mov    %r14d,%eax
  imul   %rbx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %eax,%r14d
  jne    L29
  mov    $0xa,%edi
  xor    %r14d,%r14d
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L39
L62:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: %5d

assistant: ```c
void main() {
  int i, j, n;
  int a[100];
  for (i = 0; i < 100; i++)
    a[i] = i + 1;
  a[0] = 0;
  for (i = 1; i < sqrt(100); i++) {
    for (j = i + 1; j < 100; j++) {
      if (a[i] != 0 && a[j] != 0 && a[j] % a[i] == 0)
        a[j] = 0;
    }
  }
  for (i = 0; i < 100; i++) {
    if (a[i] != 0) {
      printf("%5d", a[i]);
      n++;
    }
    if (n % 10 == 0) {
      printf("\n");
      n = 0;
    }
  }
}
```