ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fake_secret_peer>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D5(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  pop    %r12
  jmp    1070 <atoi@plt>
  nopl   0x0(%rax)
L3:
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: SSSD_INTG_SECRETS_PEER

assistant: ```c
uid_t fake_secret_peer(uid_t orig_id) {
  char *val;
  val = getenv("SSSD_INTG_SECRETS_PEER");
  if (val == NULL) {
    return orig_id;
  }
  return atoi(val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fake_secret_peer>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D3(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  pop    %r12
  jmp    1070 <atoi@plt>
  nopl   0x0(%rax)
L4:
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: SSSD_INTG_SECRETS_PEER

assistant: ```c
uid_t fake_secret_peer(uid_t orig_id) {
  char *val;
  val = getenv("SSSD_INTG_SECRETS_PEER");
  if (val == NULL) {
    return orig_id;
  }
  return atoi(val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sock_get_primary_if>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <getifaddrs@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L45
L18:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  jne    L22
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L84
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,%edi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L6
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L6
L22:
  nop
  jmp    L102
L84:
  nop
  jmp    L102
L3:
  nop
L102:
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x18(%rbp)
L45:
  cmpq   $0x0,-0x18(%rbp)
  jne    L18
  jmp    L43
L6:
  nop
L43:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <freeifaddrs@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
char *sock_get_primary_if(int family) {
  struct ifaddrs *ifap, *ifa;
  char *r = 0;
  getifaddrs(&ifap);
  for (ifa = ifap; ifa != NULL; ifa = ifa->ifa_next) {
    if (ifa->ifa_flags & IFF_LOOPBACK) {
      continue;
    }
    if (ifa->ifa_addr == NULL)
      continue;
    if (ifa->ifa_addr->sa_family != family)
      continue;
    r = malloc(strlen(ifa->ifa_name) + 1);
    if (r)
      strcpy(r, ifa->ifa_name);
    break;
  }
  freeifaddrs(ifap);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sock_get_primary_if>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  mov    (%rsp),%rbx
  test   %rbx,%rbx
  je     L83
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  jmp    L12
L55:
  mov    0x10(%rbx),%rbx
  test   %rbx,%rbx
  je     L85
L12:
  mov    %edx,%eax
  and    (%rbx),%eax
  jne    L55
  mov    0x8(%rbx),%rax
  test   %rax,%rax
  je     L55
  cmp    %ebp,(%rax)
  jne    L55
  mov    0x4(%rbx),%edi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L24
  mov    0x4(%rbx),%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
L24:
  mov    (%rsp),%rdi
  call   <freeifaddrs@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L85:
  mov    %rbx,%rbp
  jmp    L24
L83:
  mov    %rbx,%rbp
  jmp    L24
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *sock_get_primary_if(int family) {
  struct ifaddrs *ifap, *ifa;
  char *r = 0;
  getifaddrs(&ifap);
  for (ifa = ifap; ifa != NULL; ifa = ifa->ifa_next) {
    if (ifa->ifa_flags & IFF_LOOPBACK) {
      continue;
    }
    if (ifa->ifa_addr == NULL)
      continue;
    if (ifa->ifa_addr->sa_family != family)
      continue;
    r = malloc(strlen(ifa->ifa_name) + 1);
    if (r)
      strcpy(r, ifa->ifa_name);
    break;
  }
  freeifaddrs(ifap);
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<sock_get_primary_if>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L23
  mov    D5(%rip),%rax
  mov    %rdi,%rbx
  mov    (%rax),%edx
L6:
  mov    %edx,%eax
  and    (%rbx),%eax
  jne    L63
  mov    0x8(%rbx),%rax
  test   %rax,%rax
  je     L63
  cmp    %ebp,(%rax)
  je     L66
L63:
  mov    0x10(%rbx),%rbx
  test   %rbx,%rbx
  jne    L6
L23:
  xor    %r12d,%r12d
  jmp    L8
  nopl   0x0(%rax)
L66:
  mov    0x4(%rbx),%edi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
  mov    0x4(%rbx),%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
L15:
  mov    (%rsp),%rdi
L8:
  call   <freeifaddrs@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *sock_get_primary_if(int family) {
  struct ifaddrs *ifap, *ifa;
  char *r = 0;
  getifaddrs(&ifap);
  for (ifa = ifap; ifa != NULL; ifa = ifa->ifa_next) {
    if (ifa->ifa_flags & IFF_LOOPBACK) {
      continue;
    }
    if (ifa->ifa_addr == NULL)
      continue;
    if (ifa->ifa_addr->sa_family != family)
      continue;
    r = malloc(strlen(ifa->ifa_name) + 1);
    if (r)
      strcpy(r, ifa->ifa_name);
    break;
  }
  freeifaddrs(ifap);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sock_get_primary_if>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L64
  mov    D4(%rip),%rax
  mov    %rdi,%rbx
  mov    (%rax),%edx
L72:
  mov    %edx,%eax
  and    (%rbx),%eax
  jne    L14
  mov    0x8(%rbx),%rax
  test   %rax,%rax
  je     L14
  cmp    %ebp,(%rax)
  je     L35
L14:
  mov    0x10(%rbx),%rbx
  test   %rbx,%rbx
  jne    L72
L64:
  xor    %r12d,%r12d
  jmp    L49
  nopl   0x0(%rax)
L35:
  mov    0x4(%rbx),%edi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L30
  mov    0x4(%rbx),%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
L30:
  mov    (%rsp),%rdi
L49:
  call   <freeifaddrs@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *sock_get_primary_if(int family) {
  struct ifaddrs *ifap, *ifa;
  char *r = 0;
  getifaddrs(&ifap);
  for (ifa = ifap; ifa != NULL; ifa = ifa->ifa_next) {
    if (ifa->ifa_flags & IFF_LOOPBACK) {
      continue;
    }
    if (ifa->ifa_addr == NULL)
      continue;
    if (ifa->ifa_addr->sa_family != family)
      continue;
    r = malloc(strlen(ifa->ifa_name) + 1);
    if (r)
      strcpy(r, ifa->ifa_name);
    break;
  }
  freeifaddrs(ifap);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  jmp    L15
L12:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd>
L15:
  leave
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (b == 0) {
    return a;
  } else {
    return gcd(b, a % b);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  mov    %esi,%edi
  cltd
  idiv   %esi
  mov    %edx,%esi
  call   <gcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (b == 0) {
    return a;
  } else {
    return gcd(b, a % b);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%r8d
  test   %esi,%esi
  jne    L13
  jmp    L9
  nop
L6:
  mov    %edx,%r8d
L13:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (b == 0) {
    return a;
  } else {
    return gcd(b, a % b);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%r8d
  test   %esi,%esi
  jne    L7
  jmp    L12
  nop
L13:
  mov    %edx,%r8d
L7:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (b == 0) {
    return a;
  } else {
    return gcd(b, a % b);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skip_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L5
L9:
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_space(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<skip_space>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L4
L7:
  add    $0x1,%rbx
L4:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skip_space(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<skip_space>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%r12
L8:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_space(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_space>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%r12
L4:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_space(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D8
type_infered: string

tool: D11: %d%d

tool: D8: %d %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  a = a + b;
  b = a - b;
  a = a - b;
  printf("%d %d\n", a, b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %edx,0x4(%rsp)
  mov    %esi,(%rsp)
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string

tool: D0: %d%d

tool: D16: %d %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  a = a + b;
  b = a - b;
  a = a - b;
  printf("%d %d\n", a, b);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D18(%rip),%rdi
  mov    %edx,0x4(%rsp)
  mov    %esi,(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D18
type_guessed: string

tool: D12: %d%d

tool: D18: %d %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  a = a + b;
  b = a - b;
  a = a - b;
  printf("%d %d\n", a, b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D9(%rip),%rdi
  mov    %edx,0x4(%rsp)
  mov    %esi,(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D11: %d%d

tool: D9: %d %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  a = a + b;
  b = a - b;
  a = a - b;
  printf("%d %d\n", a, b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<util_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  mov    D18(%rip),%rax
  mov    (%rax),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L18
L9:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int util_read(int fd, void *p, int max) {
  int n;
  do {
    n = read(fd, p, max);
  } while (n < 0 && errno == EINTR);
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<util_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
L19:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L5
  mov    D17(%rip),%rcx
  mov    D9(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L19
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int util_read(int fd, void *p, int max) {
  int n;
  do {
    n = read(fd, p, max);
  } while (n < 0 && errno == EINTR);
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<util_read>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L11:
  mov    D17(%rip),%rdx
  mov    D11(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L7
L5:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L11
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int util_read(int fd, void *p, int max) {
  int n;
  do {
    n = read(fd, p, max);
  } while (n < 0 && errno == EINTR);
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<util_read>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L5:
  mov    D15(%rip),%rdx
  mov    D1(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L1
L15:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L5
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int util_read(int fd, void *p, int max) {
  int n;
  do {
    n = read(fd, p, max);
  } while (n < 0 && errno == EINTR);
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rs_rainflow_merge_cycles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L25
  cmpq   $0x0,-0x10(%rbp)
  je     L25
  mov    -0x18(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L25
  cmpq   $0x0,-0x20(%rbp)
  jne    L7
L25:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L36
L7:
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <merge_cycles@plt>
L36:
  leave
  ret
```

assistant: ```c
int rs_rainflow_merge_cycles(double *buffer, size_t *count, size_t size, int (*compare)(void const *, void const *)) {
  if (buffer == NULL || count == NULL || (size % sizeof(double)) != 0 || compare == NULL) {
    errno = EINVAL;
    return -1;
  }
  return merge_cycles(buffer, count, size, compare);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rs_rainflow_merge_cycles>:
  endbr64
  test   %rdi,%rdi
  je     L37
  test   %rsi,%rsi
  je     L37
  test   $0x7,%dl
  jne    L37
  test   %rcx,%rcx
  je     L37
  sub    $0x8,%rsp
  call   <merge_cycles@plt>
  add    $0x8,%rsp
  ret
L37:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rs_rainflow_merge_cycles(double *buffer, size_t *count, size_t size, int (*compare)(void const *, void const *)) {
  if (buffer == NULL || count == NULL || (size % sizeof(double)) != 0 || compare == NULL) {
    errno = EINVAL;
    return -1;
  }
  return merge_cycles(buffer, count, size, compare);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rs_rainflow_merge_cycles>:
  endbr64
  test   %rdi,%rdi
  je     L19
  test   %rsi,%rsi
  je     L19
  test   $0x7,%dl
  jne    L19
  test   %rcx,%rcx
  je     L19
  jmp    1050 <merge_cycles@plt>
  nopl   (%rax)
L19:
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rs_rainflow_merge_cycles(double *buffer, size_t *count, size_t size, int (*compare)(void const *, void const *)) {
  if (buffer == NULL || count == NULL || (size % sizeof(double)) != 0 || compare == NULL) {
    errno = EINVAL;
    return -1;
  }
  return merge_cycles(buffer, count, size, compare);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rs_rainflow_merge_cycles>:
  endbr64
  test   %rdi,%rdi
  je     L34
  test   %rsi,%rsi
  je     L34
  test   $0x7,%dl
  jne    L34
  test   %rcx,%rcx
  je     L34
  jmp    1050 <merge_cycles@plt>
  nopl   (%rax)
L34:
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rs_rainflow_merge_cycles(double *buffer, size_t *count, size_t size, int (*compare)(void const *, void const *)) {
  if (buffer == NULL || count == NULL || (size % sizeof(double)) != 0 || compare == NULL) {
    errno = EINVAL;
    return -1;
  }
  return merge_cycles(buffer, count, size, compare);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__gnu_uldivmod_helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__udivdi3@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  imul   -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long __gnu_uldivmod_helper(unsigned long long a, unsigned long long b, unsigned long long *remainder) {
  unsigned long long quotient;
  quotient = __udivdi3(a, b);
  *remainder = a - b * quotient;
  return quotient;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__gnu_uldivmod_helper>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <__udivdi3@plt>
  imul   %rax,%rbp
  sub    %rbp,%rbx
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long __gnu_uldivmod_helper(unsigned long long a, unsigned long long b, unsigned long long *remainder) {
  unsigned long long quotient;
  quotient = __udivdi3(a, b);
  *remainder = a - b * quotient;
  return quotient;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__gnu_uldivmod_helper>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <__udivdi3@plt>
  imul   %rax,%rbp
  sub    %rbp,%rbx
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long __gnu_uldivmod_helper(unsigned long long a, unsigned long long b, unsigned long long *remainder) {
  unsigned long long quotient;
  quotient = __udivdi3(a, b);
  *remainder = a - b * quotient;
  return quotient;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__gnu_uldivmod_helper>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <__udivdi3@plt>
  imul   %rax,%rbp
  sub    %rbp,%rbx
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long __gnu_uldivmod_helper(unsigned long long a, unsigned long long b, unsigned long long *remainder) {
  unsigned long long quotient;
  quotient = __udivdi3(a, b);
  *remainder = a - b * quotient;
  return quotient;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<order_of_magnitude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L11:
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int order_of_magnitude(unsigned long long int key) {
  int bucket = 0;
  while (key) {
    key /= 10;
    bucket++;
  }
  return bucket;
}
```