user: 请从给定的汇编指令推导出C源代码:

```asm
<handle_subtraction>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L15
L161:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L15:
  mov    %r14,%rdi
  call   <lookup_set@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L76
  mov    $0x6,%esi
  mov    %r14,%rdi
  call   <named_set@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L144
  xor    %eax,%eax
  call   <error@plt>
  test   %rax,%rax
  je     L76
L144:
  movdqa D28(%rip),%xmm0
  mov    %rsp,%rdi
  movabs $0x74696e6966656420,%rax
  movl   $0x6e6f69,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <set_error1@plt>
  jmp    L161
  nopl   (%rax)
L76:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
  mov    %r12,%rdi
  call   <lookup_set@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L152
  xor    %eax,%eax
  call   <error@plt>
  test   %rax,%rax
  jne    L152
  mov    %r13,%rdi
  call   <lookup_set@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L137
  xor    %eax,%eax
  call   <error@plt>
  test   %rax,%rax
  jne    L137
  call   <error@plt>
  test   %rax,%rax
  jne    L161
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <set_subtraction@plt>
  xor    %eax,%eax
  call   <error@plt>
  test   %rax,%rax
  je     L161
  movdqa D28(%rip),%xmm0
  mov    %rsp,%rdi
  movabs $0x6361727462757320,%rax
  movl   $0x6e6f6974,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  movb   $0x0,0x1c(%rsp)
  movaps %xmm0,(%rsp)
  call   <set_error2@plt>
  jmp    L161
  nopw   0x0(%rax,%rax,1)
L152:
  mov    %rsp,%rbp
  mov    %r12,%rdx
L45:
  mov    %rbp,%rdi
  lea    D25(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <set_error2@plt>
  jmp    L161
  nopl   0x0(%rax)
L137:
  mov    %rsp,%rbp
  mov    %r13,%rdx
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L22:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x118,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1140 <clear_set@plt>
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D28
data_type: byte[16]
name: parse_data
arguments: data_label: D25
data_type: string

tool: {"D28": [0x70,0x72,0x6f,0x62,0x6c,0x65,0x6d,0x20,0x77,0x69,0x74,0x68,0x20,0x73,0x65,0x74]}

tool: D25: invalid setname(%s) in -

assistant: ```c
void handle_subtraction(char *setname1, char *setname2, char *setname3) {
  int set1, set2, set3;
  char message[255];
  if (strcmp(setname2, setname3) == 0)
    return;
  set1 = lookup_set(setname1);
  if (set1 == 0) {
    set1 = named_set(setname1, 6);
    if (set1 == 0 || error()) {
      sprintf(message, "problem with set definition");
      set_error1(message);
      return;
    }
  }
  if (strcmp(setname2, setname3) == 0) {
    clear_set(set1);
    return;
  }
  set2 = lookup_set(setname2);
  if (set2 == 0 || error()) {
    sprintf(message, "invalid setname(%s) in -", setname2);
    set_error2(message);
    return;
  }
  set3 = lookup_set(setname3);
  if (set3 == 0 || error()) {
    sprintf(message, "invalid setname(%s) in -", setname3);
    set_error2(message);
    return;
  }
  if (error()) {
    return;
  }
  set_subtraction(set2, set3, set1);
  if (error()) {
    sprintf(message, "problem with set subtraction");
    set_error2(message);
    return;
  }
}
```