user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  lea    -0x38(%rbp),%rdx
  add    $0x8,%rdx
  lea    -0x38(%rbp),%rax
  add    $0x4,%rax
  lea    -0x38(%rbp),%rsi
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x2c(%rbp),%rdx
  add    $0x8,%rdx
  lea    -0x2c(%rbp),%rax
  add    $0x4,%rax
  lea    -0x2c(%rbp),%rsi
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L47
L77:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x38(%rbp,%rax,4),%edx
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x2c(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jge    L111
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x38(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x44(%rbp)
  addl   $0x1,-0x3c(%rbp)
  jmp    L47
L111:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x2c(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x40(%rbp)
  addl   $0x1,-0x3c(%rbp)
L47:
  cmpl   $0x2,-0x44(%rbp)
  jg     L118
  cmpl   $0x2,-0x40(%rbp)
  jle    L77
  jmp    L118
L84:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x38(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x3c(%rbp)
  addl   $0x1,-0x44(%rbp)
L118:
  cmpl   $0x2,-0x44(%rbp)
  jle    L84
  jmp    L90
L1:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x2c(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x3c(%rbp)
  addl   $0x1,-0x40(%rbp)
L90:
  cmpl   $0x2,-0x40(%rbp)
  jle    L1
  movl   $0x5,-0x44(%rbp)
  jmp    L98
L108:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x44(%rbp)
L98:
  cmpl   $0x0,-0x44(%rbp)
  jg     L108
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L101
  call   <__stack_chk_fail@plt>
L101:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string
name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D37
type_guessed: string

tool: D4: %d %d %d

tool: D6: %d 

tool: D37: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int x[3];
  int y[3];
  int answer[6];
  int i = 0;
  int j = 0;
  int k = 0;
  scanf("%d %d %d", x, (x + 1), (x + 2));
  scanf("%d %d %d", y, (y + 1), (y + 2));
  while (i < 3 && j < 3) {
    if (x[i] < y[j]) {
      answer[k] = x[i];
      i++;
      k++;
    } else {
      answer[k] = y[j];
      j++;
      k++;
    }
  }
  for (; i < 3; i++) {
    answer[k] = x[i];
    k++;
  }
  for (; j < 3; j++) {
    answer[k] = y[j];
    k++;
  }
  for (i = 5; i > 0; i--)
    printf("%d ", answer[i]);
  printf("%d\n", answer[0]);
}
```