ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_field_number>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %edx,%edx
  jle    L49
  movslq %edx,%rdx
  xor    %ebx,%ebx
  jmp    L35
  nopl   0x0(%rax)
L59:
  lea    0x1(%rbx),%r12d
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  je     L64
L35:
  cmpb   $0xa,0x0(%r13,%rbx,1)
  mov    %ebx,%r12d
  jne    L59
L66:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  xor    %r12d,%r12d
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r14,%rdi
  lea    D2(%rip),%rbx
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L47
  jmp    L65
  nopl   0x0(%rax)
L20:
  xor    %edi,%edi
  mov    %rbx,%rsi
  add    $0x1,%r12d
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L65
L47:
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L20
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  movslq %r12d,%rbx
  jmp    L66
L49:
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L66
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: ,

assistant: ```c
int get_field_number(const char *field_name, const char *buffer, int len) {
  int llen;
  char *line;
  char *token;
  for (llen = 0; llen < len; llen++)
    if (buffer[llen] == '\n')
      break;
  line = (char *)malloc(llen);
  memcpy(line, buffer, llen);
  line[llen] = '\0';
  for (token = strtok(line, ","), llen = 0; token; token = strtok(NULL, ","), llen++) {
    if (strcmp(token, field_name) == 0) {
      return llen;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_field_number>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %edx,%edx
  jle    L70
  movslq %edx,%rdx
  xor    %ebx,%ebx
  jmp    L37
  nopl   0x0(%rax)
L33:
  lea    0x1(%rbx),%r12d
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  je     L50
L37:
  cmpb   $0xa,0x0(%r13,%rbx,1)
  mov    %ebx,%r12d
  jne    L33
L94:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  xor    %r12d,%r12d
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r14,%rdi
  lea    D8(%rip),%rbx
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L15
  jmp    L69
  nopl   0x0(%rax)
L83:
  xor    %edi,%edi
  mov    %rbx,%rsi
  add    $0x1,%r12d
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L69
L15:
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L83
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  movslq %r12d,%rbx
  jmp    L94
L70:
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L94
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D8: ,

assistant: ```c
int get_field_number(const char *field_name, const char *buffer, int len) {
  int llen;
  char *line;
  char *token;
  for (llen = 0; llen < len; llen++)
    if (buffer[llen] == '\n')
      break;
  line = (char *)malloc(llen);
  memcpy(line, buffer, llen);
  line[llen] = '\0';
  for (token = strtok(line, ","), llen = 0; token; token = strtok(NULL, ","), llen++) {
    if (strcmp(token, field_name) == 0) {
      return llen;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<and_write_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  cmpl   $0x4,-0x18(%rbp)
  je     L37
  cmpl   $0x4,-0x18(%rbp)
  jg     L78
  cmpl   $0x1,-0x18(%rbp)
  je     L63
  cmpl   $0x2,-0x18(%rbp)
  je     L46
  jmp    L78
L14:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x20(%rbp),%rdx
  and    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
L63:
  cmpl   $0x0,-0x14(%rbp)
  jne    L14
  jmp    L78
L0:
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%edx
  mov    -0x20(%rbp),%rax
  and    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
L46:
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  jmp    L78
L19:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  and    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
L37:
  cmpl   $0x0,-0x14(%rbp)
  jne    L19
  nop
L78:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void and_write_memory(unsigned long phys_addr, void *addr, int len, int iosize, unsigned long value) {
  switch (iosize) {
  case 1:
    while (len) {
      *(unsigned char *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  case 2:
    while (len) {
      *(unsigned short *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  case 4:
    while (len) {
      *(unsigned long *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<and_write_memory>:
  endbr64
  mov    %rsi,%rax
  cmp    $0x2,%ecx
  je     L69
  cmp    $0x4,%ecx
  je     L51
  cmp    $0x1,%ecx
  je     L21
L74:
  ret
L51:
  lea    -0x4(%rdx),%ecx
  lea    0x4(%rsi,%rcx,1),%rcx
  test   %edx,%edx
  je     L53
L6:
  and    %r8,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L6
  jmp    L74
L53:
  ret
L69:
  lea    -0x2(%rdx),%ecx
  lea    0x2(%rsi,%rcx,1),%rcx
  test   %edx,%edx
  je     L65
L2:
  and    %r8w,(%rax)
  add    $0x2,%rax
  cmp    %rax,%rcx
  jne    L2
  ret
L65:
  ret
L21:
  test   %edx,%edx
  je     L74
  mov    %edx,%edx
  add    %rsi,%rdx
L75:
  and    %r8b,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L75
  ret
```

assistant: ```c
void and_write_memory(unsigned long phys_addr, void *addr, int len, int iosize, unsigned long value) {
  switch (iosize) {
  case 1:
    while (len) {
      *(unsigned char *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  case 2:
    while (len) {
      *(unsigned short *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  case 4:
    while (len) {
      *(unsigned long *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<and_write_memory>:
  endbr64
  mov    %rsi,%rax
  cmp    $0x2,%ecx
  je     L26
  cmp    $0x4,%ecx
  je     L37
  cmp    $0x1,%ecx
  je     L88
L50:
  ret
  nopw   0x0(%rax,%rax,1)
L88:
  test   %edx,%edx
  je     L50
  mov    %edx,%edx
  add    %rsi,%rdx
  nopl   0x0(%rax)
L10:
  and    %r8b,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L10
  ret
  nopl   (%rax)
L37:
  lea    -0x4(%rdx),%ecx
  lea    0x4(%rsi,%rcx,1),%rcx
  test   %edx,%edx
  je     L61
  nopl   0x0(%rax)
L28:
  and    %r8,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L28
  ret
  nopl   (%rax)
L26:
  test   %edx,%edx
  je     L76
  sub    $0x2,%edx
  lea    0x2(%rsi,%rdx,1),%rdx
  nopl   0x0(%rax)
L13:
  and    %r8w,(%rax)
  add    $0x2,%rax
  cmp    %rax,%rdx
  jne    L13
  ret
  xchg   %ax,%ax
L61:
  ret
  nopl   0x0(%rax)
L76:
  ret
```

assistant: ```c
void and_write_memory(unsigned long phys_addr, void *addr, int len, int iosize, unsigned long value) {
  switch (iosize) {
  case 1:
    while (len) {
      *(unsigned char *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  case 2:
    while (len) {
      *(unsigned short *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  case 4:
    while (len) {
      *(unsigned long *)addr &= value;
      len -= iosize;
      addr += iosize;
    }
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xdr_union>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xdr_enum@plt>
  test   %eax,%eax
  jne    L16
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  jmp    L63
L16:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L65
L6:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L56
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%r8
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0xffffffffffffffff,%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   *%r8
  jmp    L63
L56:
  addq   $0x10,-0x30(%rbp)
L65:
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    D21(%rip),%rdx
  cmp    %rdx,%rax
  jne    L6
  mov    D21(%rip),%rax
  cmp    %rax,-0x38(%rbp)
  je     L25
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    -0x38(%rbp),%r8
  mov    $0xffffffffffffffff,%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   *%r8
  jmp    L63
L25:
  mov    D38(%rip),%rax
  mov    (%rax),%eax
L63:
  leave
  ret
```

assistant: ```c
bool_t xdr_union(XDR *xdrs, enum_t *dscmp, char *unp, const struct xdr_discrim *choices, xdrproc_t dfault) {
  enum_t dscm;
  if (!xdr_enum(xdrs, dscmp)) {
    return (FALSE);
  }
  dscm = *dscmp;
  for (; choices->proc != NULL_xdrproc_t; choices++) {
    if (choices->value == dscm)
      return ((*(choices->proc))(xdrs, unp, ((u_int)0 - 1)));
  }
  return ((dfault == NULL_xdrproc_t) ? FALSE : (*dfault)(xdrs, unp, ((u_int)0 - 1)));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xdr_union>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%rbx
  mov    %r8,%r12
  call   <xdr_enum@plt>
  test   %eax,%eax
  je     L46
  mov    (%r14),%rdx
  mov    0x8(%rbx),%rax
  cmp    D7(%rip),%rax
  je     L37
L30:
  cmp    %rdx,(%rbx)
  je     L5
  add    $0x10,%rbx
  mov    0x8(%rbx),%rax
  cmp    D7(%rip),%rax
  jne    L30
L37:
  cmp    D7(%rip),%r12
  je     L53
  mov    $0xffffffffffffffff,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   *%r12
  jmp    L34
L46:
  mov    D39(%rip),%rax
  mov    (%rax),%eax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    $0xffffffffffffffff,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   *%rax
  jmp    L34
L53:
  mov    D39(%rip),%rax
  mov    (%rax),%eax
  jmp    L34
```

assistant: ```c
bool_t xdr_union(XDR *xdrs, enum_t *dscmp, char *unp, const struct xdr_discrim *choices, xdrproc_t dfault) {
  enum_t dscm;
  if (!xdr_enum(xdrs, dscmp)) {
    return (FALSE);
  }
  dscm = *dscmp;
  for (; choices->proc != NULL_xdrproc_t; choices++) {
    if (choices->value == dscm)
      return ((*(choices->proc))(xdrs, unp, ((u_int)0 - 1)));
  }
  return ((dfault == NULL_xdrproc_t) ? FALSE : (*dfault)(xdrs, unp, ((u_int)0 - 1)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdr_union>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <xdr_enum@plt>
  test   %eax,%eax
  je     L30
  mov    0x8(%rbx),%rax
  mov    D0(%rip),%rdx
  mov    0x0(%r13),%rcx
  cmp    %rdx,%rax
  jne    L29
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L26:
  mov    0x18(%rbx),%rax
  add    $0x10,%rbx
  cmp    %rdx,%rax
  je     L36
L29:
  cmp    %rcx,(%rbx)
  jne    L26
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  pop    %rbp
  mov    $0xffffffffffffffff,%rdx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    *%rax
  nopl   0x0(%rax)
L30:
  mov    D2(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %rdx,%r12
  je     L30
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  pop    %rbp
  mov    %r12,%rax
  mov    $0xffffffffffffffff,%rdx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    *%rax
```

assistant: ```c
bool_t xdr_union(XDR *xdrs, enum_t *dscmp, char *unp, const struct xdr_discrim *choices, xdrproc_t dfault) {
  enum_t dscm;
  if (!xdr_enum(xdrs, dscmp)) {
    return (FALSE);
  }
  dscm = *dscmp;
  for (; choices->proc != NULL_xdrproc_t; choices++) {
    if (choices->value == dscm)
      return ((*(choices->proc))(xdrs, unp, ((u_int)0 - 1)));
  }
  return ((dfault == NULL_xdrproc_t) ? FALSE : (*dfault)(xdrs, unp, ((u_int)0 - 1)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdr_union>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <xdr_enum@plt>
  test   %eax,%eax
  je     L19
  mov    0x8(%rbx),%rax
  mov    D9(%rip),%rdx
  mov    0x0(%r13),%rcx
  cmp    %rdx,%rax
  jne    L35
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L52:
  mov    0x18(%rbx),%rax
  add    $0x10,%rbx
  cmp    %rdx,%rax
  je     L26
L35:
  cmp    %rcx,(%rbx)
  jne    L52
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  pop    %rbp
  mov    $0xffffffffffffffff,%rdx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    *%rax
  nopl   0x0(%rax)
L19:
  mov    D19(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  cmp    %rdx,%r12
  je     L19
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  pop    %rbp
  mov    %r12,%rax
  mov    $0xffffffffffffffff,%rdx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    *%rax
```

assistant: ```c
bool_t xdr_union(XDR *xdrs, enum_t *dscmp, char *unp, const struct xdr_discrim *choices, xdrproc_t dfault) {
  enum_t dscm;
  if (!xdr_enum(xdrs, dscmp)) {
    return (FALSE);
  }
  dscm = *dscmp;
  for (; choices->proc != NULL_xdrproc_t; choices++) {
    if (choices->value == dscm)
      return ((*(choices->proc))(xdrs, unp, ((u_int)0 - 1)));
  }
  return ((dfault == NULL_xdrproc_t) ? FALSE : (*dfault)(xdrs, unp, ((u_int)0 - 1)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
char *addr() {
  char a;
  return &a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<addr>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *addr() {
  char a;
  return &a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<addr>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *addr() {
  char a;
  return &a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<addr>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *addr() {
  char a;
  return &a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L17
L28:
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L32
L4:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L32:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D7: %d %d

tool: D19: %02d 

assistant: ```c
int main() {
  int i, j, n, m, p;
  scanf("%d %d", &m, &n);
  for (j = 1; j <= m; j++) {
    p = 1;
    for (i = 1; i <= n; i++) {
      printf("%02d ", p);
      p = p + 2;
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%r13d
  lea    D15(%rip),%r12
  cmpl   $0x0,0x4(%rsp)
  jg     L16
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L32
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  cmp    %r13d,0x4(%rsp)
  jl     L2
L16:
  mov    $0x1,%ebp
  mov    $0x1,%ebx
  cmpl   $0x0,(%rsp)
  jg     L32
  jmp    L4
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string

tool: D13: %d %d

tool: D15: %02d 

assistant: ```c
int main() {
  int i, j, n, m, p;
  scanf("%d %d", &m, &n);
  for (j = 1; j <= m; j++) {
    p = 1;
    for (i = 1; i <= n; i++) {
      printf("%02d ", p);
      p = p + 2;
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rdi
  mov    $0x1,%r13d
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L3
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rsp),%eax
  mov    $0x1,%ebp
  mov    $0x1,%ebx
  test   %eax,%eax
  jle    L11
  nopl   0x0(%rax)
L42:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x2,%ebp
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L42
L11:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r13d,0x4(%rsp)
  jge    L2
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string

tool: D4: %d %d

tool: D18: %02d 

assistant: ```c
int main() {
  int i, j, n, m, p;
  scanf("%d %d", &m, &n);
  for (j = 1; j <= m; j++) {
    p = 1;
    for (i = 1; i <= n; i++) {
      printf("%02d ", p);
      p = p + 2;
    }
    printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rdi
  mov    $0x1,%r13d
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L19
  nopw   0x0(%rax,%rax,1)
L42:
  mov    (%rsp),%eax
  mov    $0x1,%ebp
  mov    $0x1,%ebx
  test   %eax,%eax
  jle    L24
  nopl   0x0(%rax)
L34:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x2,%ebp
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L34
L24:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r13d,0x4(%rsp)
  jge    L42
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string

tool: D5: %d %d

tool: D12: %02d 

assistant: ```c
int main() {
  int i, j, n, m, p;
  scanf("%d %d", &m, &n);
  for (j = 1; j <= m; j++) {
    p = 1;
    for (i = 1; i <= n; i++) {
      printf("%02d ", p);
      p = p + 2;
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L21
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L2
L21:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <raise@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L37
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L34
L37:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L34:
  mov    -0x4(%rbp),%eax
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D27: Usage: raise SIGNAL_NUMBER


tool: D6: raise

tool: D8: I'm alive!


assistant: ```c
int main(int argc, char *argv[]) {
  int res;
  if (argc == 1) {
    printf("Usage: raise SIGNAL_NUMBER\n");
    return 1;
  }
  res = raise(atoi(argv[1]));
  if (res != 0)
    perror("raise");
  else
    printf("I'm alive!\n");
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  je     L34
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <raise@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L15
  lea    D28(%rip),%rdi
  call   <perror@plt>
L32:
  mov    %ebx,%eax
  pop    %rbx
  ret
L34:
  mov    %edi,%ebx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L15:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L32
```

tool_calls: name: parse_data
arguments: data_label: D28
datatype: string
name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string

tool: D28: raise

tool: D13: Usage: raise SIGNAL_NUMBER


tool: D10: I'm alive!


assistant: ```c
int main(int argc, char *argv[]) {
  int res;
  if (argc == 1) {
    printf("Usage: raise SIGNAL_NUMBER\n");
    return 1;
  }
  res = raise(atoi(argv[1]));
  if (res != 0)
    perror("raise");
  else
    printf("I'm alive!\n");
  return res;
}
```