ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<myvalgrad>:
  endbr64
  test   %edx,%edx
  jle    L30
  push   %r13
  pxor   %xmm3,%xmm3
  mov    $0x1,%r13d
  push   %r12
  lea    0x1(%rdx),%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  nopw   0x0(%rax,%rax,1)
L37:
  pxor   %xmm1,%xmm1
  pxor   %xmm5,%xmm5
  cvtsi2sd %r13d,%xmm1
  ucomisd %xmm1,%xmm5
  ja     L0
  sqrtsd %xmm1,%xmm1
L32:
  movsd  -0x8(%rbp,%r13,8),%xmm2
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm4
  movsd  0x18(%rsp),%xmm3
  mulsd  %xmm1,%xmm2
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbx,%r13,8)
  add    $0x1,%r13
  subsd  %xmm2,%xmm4
  addsd  %xmm4,%xmm3
  cmp    %r12,%r13
  jne    L37
  add    $0x28,%rsp
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L30:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  ret
L0:
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm1
  jmp    L32
```

assistant: ```c
double myvalgrad(double *g, double *x, int n) {
  double ex, f, t;
  int i;
  f = (double)0;
  for (i = 0; i < n; i++) {
    t = i + 1;
    t = sqrt(t);
    ex = exp(x[i]);
    f += ex - t * x[i];
    g[i] = ex - t;
  }
  return (f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<myvalgrad>:
  endbr64
  test   %edx,%edx
  jle    L7
  push   %r13
  pxor   %xmm3,%xmm3
  mov    $0x1,%r13d
  push   %r12
  lea    0x1(%rdx),%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  nopw   0x0(%rax,%rax,1)
L11:
  pxor   %xmm1,%xmm1
  pxor   %xmm5,%xmm5
  movsd  %xmm3,0x18(%rsp)
  cvtsi2sd %r13d,%xmm1
  ucomisd %xmm1,%xmm5
  ja     L25
  movsd  -0x8(%rbp,%r13,8),%xmm2
  sqrtsd %xmm1,%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm4
  movsd  0x18(%rsp),%xmm3
  mulsd  %xmm1,%xmm2
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbx,%r13,8)
  add    $0x1,%r13
  subsd  %xmm2,%xmm4
  addsd  %xmm4,%xmm3
  cmp    %r12,%r13
  jne    L11
L38:
  add    $0x28,%rsp
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L7:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  ret
L25:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movsd  -0x8(%rbp,%r13,8),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm4
  movsd  0x18(%rsp),%xmm3
  mulsd  %xmm1,%xmm2
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbx,%r13,8)
  add    $0x1,%r13
  subsd  %xmm2,%xmm4
  addsd  %xmm4,%xmm3
  cmp    %r13,%r12
  jne    L11
  jmp    L38
```

assistant: ```c
double myvalgrad(double *g, double *x, int n) {
  double ex, f, t;
  int i;
  f = (double)0;
  for (i = 0; i < n; i++) {
    t = i + 1;
    t = sqrt(t);
    ex = exp(x[i]);
    f += ex - t * x[i];
    g[i] = ex - t;
  }
  return (f);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wrapText>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xc38,%rsp
  mov    %rdi,%r12
  mov    %edx,%ebx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1c28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <strcpy@plt>
  movswl %bx,%esi
  mov    $0x1,%edx
  mov    %r13,%rdi
  call   <breakUpLongWordsIn@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  cmpb   $0x19,(%rsp)
  jne    L113
  mov    $0x0,%edi
L106:
  add    $0x4,%edi
  movswq %di,%rax
  cmpb   $0x19,(%rsp,%rax,1)
  je     L106
L74:
  cmp    %di,%si
  jle    L118
  mov    %ebx,%r8d
  mov    $0x1,%ebx
  mov    $0x0,%r9d
  jmp    L65
L113:
  mov    $0x0,%edi
  jmp    L74
L108:
  add    $0x1,%eax
  add    $0x1,%ecx
L20:
  cmp    %si,%ax
  jge    L24
L76:
  movswq %ax,%rdx
  movzbl (%rsp,%rdx,1),%edx
  cmp    $0xa,%dl
  je     L24
  cmp    $0x20,%dl
  je     L24
  cmp    $0x19,%dl
  jne    L108
  add    $0x4,%eax
  jmp    L20
L24:
  cmp    %cx,%r8w
  jle    L104
  movswq %di,%rdx
  sub    $0x1,%r8d
  sub    %ecx,%r8d
  cmpb   $0xa,(%rsp,%rdx,1)
  jne    L101
L104:
  movswq %di,%rdi
  movb   $0xa,(%rsp,%rdi,1)
  add    $0x1,%ebx
  mov    %ebp,%r8d
  sub    %ecx,%r8d
L101:
  cmp    %ax,%si
  jle    L125
  mov    %eax,%edi
L65:
  lea    0x1(%rdi),%eax
  mov    %r9d,%ecx
  cmp    %ax,%si
  jg     L76
  jmp    L24
L118:
  mov    $0x1,%ebx
L125:
  test   %r12,%r12
  je     L111
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L111:
  mov    0x1c28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    %ebx,%eax
  add    $0x1c38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short wrapText(char *to, const char *sourceText, short width) {
  short i, w, textLength, lineCount;
  char printString[100 * (31 + 5) * 2];
  short spaceLeftOnLine, wordWidth;
  strcpy(printString, sourceText);
  breakUpLongWordsIn(printString, width, 1);
  textLength = strlen(printString);
  lineCount = 1;
  for (i = 0; printString[i] == 25; i += 4)
    ;
  spaceLeftOnLine = width;
  while (i < textLength) {
    wordWidth = 0;
    for (w = i + 1; w < textLength && printString[w] != ' ' && printString[w] != '\n';) {
      if (printString[w] == 25) {
        w += 4;
      } else {
        w++;
        wordWidth++;
      }
    }
    if (1 + wordWidth > spaceLeftOnLine || printString[i] == '\n') {
      printString[i] = '\n';
      lineCount++;
      spaceLeftOnLine = width - wordWidth;
    } else {
      spaceLeftOnLine -= 1 + wordWidth;
    }
    i = w;
  }
  if (to) {
    strcpy(to, printString);
  }
  return lineCount;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wrapText>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xc38,%rsp
  mov    %rsp,%rbp
  mov    %edx,%r13d
  mov    %rdi,%r12
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1c28(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <strcpy@plt>
  movswl %r13w,%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <breakUpLongWordsIn@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmpb   $0x19,(%rsp)
  mov    %eax,%edi
  jne    L39
  nopw   0x0(%rax,%rax,1)
L76:
  add    $0x4,%r8d
  movswq %r8w,%rax
  cmpb   $0x19,(%rsp,%rax,1)
  je     L76
L39:
  cmp    %r8w,%di
  jle    L13
  mov    %r13d,%r9d
  mov    $0x1,%r13d
  nopl   0x0(%rax)
L57:
  lea    0x1(%r8),%eax
  xor    %ecx,%ecx
  xor    %esi,%esi
  cmp    %ax,%di
  jg     L169
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L108:
  lea    0x1(%rcx),%esi
  add    $0x1,%eax
  mov    %esi,%ecx
  cmp    %di,%ax
  jge    L56
L169:
  movswq %ax,%rdx
  mov    %ecx,%esi
  movzbl (%rsp,%rdx,1),%edx
  cmp    $0x20,%dl
  je     L56
  cmp    $0xa,%dl
  je     L56
  cmp    $0x19,%dl
  jne    L108
  add    $0x4,%eax
  cmp    %di,%ax
  jl     L169
  xchg   %ax,%ax
L56:
  movswq %r8w,%r8
  cmp    %cx,%r9w
  jle    L40
  sub    $0x1,%r9d
  sub    %esi,%r9d
  cmpb   $0xa,(%rsp,%r8,1)
  je     L40
  cmp    %ax,%di
  jle    L177
L103:
  mov    %eax,%r8d
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %ebx,%r9d
  movb   $0xa,(%rsp,%r8,1)
  add    $0x1,%r13d
  sub    %esi,%r9d
  cmp    %ax,%di
  jg     L103
L177:
  test   %r12,%r12
  je     L15
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L15:
  mov    0x1c28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L166
  add    $0x1c38,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    $0x1,%r13d
  jmp    L177
L166:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short wrapText(char *to, const char *sourceText, short width) {
  short i, w, textLength, lineCount;
  char printString[100 * (31 + 5) * 2];
  short spaceLeftOnLine, wordWidth;
  strcpy(printString, sourceText);
  breakUpLongWordsIn(printString, width, 1);
  textLength = strlen(printString);
  lineCount = 1;
  for (i = 0; printString[i] == 25; i += 4)
    ;
  spaceLeftOnLine = width;
  while (i < textLength) {
    wordWidth = 0;
    for (w = i + 1; w < textLength && printString[w] != ' ' && printString[w] != '\n';) {
      if (printString[w] == 25) {
        w += 4;
      } else {
        w++;
        wordWidth++;
      }
    }
    if (1 + wordWidth > spaceLeftOnLine || printString[i] == '\n') {
      printString[i] = '\n';
      lineCount++;
      spaceLeftOnLine = width - wordWidth;
    } else {
      spaceLeftOnLine -= 1 + wordWidth;
    }
    i = w;
  }
  if (to) {
    strcpy(to, printString);
  }
  return lineCount;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wrapText>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xc38,%rsp
  mov    %rsp,%rbp
  mov    %edx,%r13d
  mov    %rdi,%r12
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1c28(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <strcpy@plt>
  movswl %r13w,%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <breakUpLongWordsIn@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmpb   $0x19,(%rsp)
  mov    %eax,%edi
  jne    L55
  nopw   0x0(%rax,%rax,1)
L153:
  add    $0x4,%r8d
  movswq %r8w,%rax
  cmpb   $0x19,(%rsp,%rax,1)
  je     L153
L55:
  cmp    %r8w,%di
  jle    L30
  mov    %r13d,%r9d
  mov    $0x1,%r13d
  nopl   0x0(%rax)
L149:
  lea    0x1(%r8),%eax
  xor    %ecx,%ecx
  xor    %esi,%esi
  cmp    %ax,%di
  jle    L101
  nopl   (%rax)
L141:
  movswq %ax,%rdx
  mov    %ecx,%esi
  movzbl (%rsp,%rdx,1),%edx
  cmp    $0x20,%dl
  je     L101
  cmp    $0xa,%dl
  je     L101
  cmp    $0x19,%dl
  je     L108
  lea    0x1(%rcx),%esi
  add    $0x1,%eax
  mov    %esi,%ecx
  cmp    %ax,%di
  jg     L141
L101:
  movswq %r8w,%r8
  cmp    %cx,%r9w
  jle    L94
L43:
  sub    $0x1,%r9d
  sub    %esi,%r9d
  cmpb   $0xa,(%rsp,%r8,1)
  je     L94
  cmp    %ax,%di
  jle    L46
L24:
  mov    %eax,%r8d
  jmp    L149
L108:
  add    $0x4,%eax
  cmp    %ax,%di
  jg     L141
  movswq %r8w,%r8
  cmp    %cx,%r9w
  jg     L43
  nopw   0x0(%rax,%rax,1)
L94:
  mov    %ebx,%r9d
  movb   $0xa,(%rsp,%r8,1)
  add    $0x1,%r13d
  sub    %esi,%r9d
  cmp    %ax,%di
  jg     L24
L46:
  test   %r12,%r12
  je     L76
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L76:
  mov    0x1c28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x1c38,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  mov    $0x1,%r13d
  jmp    L46
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
short wrapText(char *to, const char *sourceText, short width) {
  short i, w, textLength, lineCount;
  char printString[100 * (31 + 5) * 2];
  short spaceLeftOnLine, wordWidth;
  strcpy(printString, sourceText);
  breakUpLongWordsIn(printString, width, 1);
  textLength = strlen(printString);
  lineCount = 1;
  for (i = 0; printString[i] == 25; i += 4)
    ;
  spaceLeftOnLine = width;
  while (i < textLength) {
    wordWidth = 0;
    for (w = i + 1; w < textLength && printString[w] != ' ' && printString[w] != '\n';) {
      if (printString[w] == 25) {
        w += 4;
      } else {
        w++;
        wordWidth++;
      }
    }
    if (1 + wordWidth > spaceLeftOnLine || printString[i] == '\n') {
      printString[i] = '\n';
      lineCount++;
      spaceLeftOnLine = width - wordWidth;
    } else {
      spaceLeftOnLine -= 1 + wordWidth;
    }
    i = w;
  }
  if (to) {
    strcpy(to, printString);
  }
  return lineCount;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hexdump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L52
  mov    %rdi,%rsi
  lea    D35(%rip),%rdi
  call   <printf@plt>
L52:
  test   %r13,%r13
  je     L19
  mov    $0x0,%ebx
  lea    D13(%rip),%r15
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D33(%rip),%r14
  jmp    L67
L14:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L70:
  movzbl (%r12,%rbx,1),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl (%r12,%rbx,1),%eax
  lea    -0x20(%rax),%edx
  cmp    $0x5f,%dl
  mov    $0x2e,%edx
  cmovae %edx,%eax
  mov    %al,0x10(%rsp,%rbp,1)
  movb   $0x0,0x11(%rsp,%rbp,1)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L74
L67:
  mov    %rbx,%rbp
  and    $0xf,%ebp
  jne    L70
  test   %rbx,%rbx
  je     L14
  mov    0x8(%rsp),%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L14
L74:
  test   $0xf,%bl
  je     L19
  lea    D40(%rip),%rbp
L84:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  test   $0xf,%bl
  jne    L84
L19:
  lea    0x10(%rsp),%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D33
datatype: string
name: extract_symbolic_data
arguments: label: D36
datatype: string
name: extract_symbolic_data
arguments: label: D40
datatype: string

tool: D35: %s:


tool: D13:   %04zx 

tool: D33:  %02x

tool: D36:   %s


tool: D40:    

assistant: ```c
void hexdump(const char *desc, const void *addr, size_t len) {
  size_t i;
  unsigned char buff[17];
  const unsigned char *pc = addr;
  if (desc != NULL)
    printf("%s:\n", desc);
  for (i = 0; i < len; i++) {
    if ((i % 16) == 0) {
      if (i != 0)
        printf("  %s\n", buff);
      printf("  %04zx ", i);
    }
    printf(" %02x", pc[i]);
    if ((pc[i] < 0x20) || (pc[i] > 0x7e))
      buff[i % 16] = '.';
    else
      buff[i % 16] = pc[i];
    buff[(i % 16) + 1] = '\0';
  }
  while ((i % 16) != 0) {
    printf("   ");
    i++;
  }
  printf("  %s\n", buff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hexdump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L59
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
L59:
  test   %r12,%r12
  je     L48
  lea    0x10(%rsp),%rax
  xor    %r15d,%r15d
  lea    D11(%rip),%r13
  mov    %rax,0x8(%rsp)
  lea    D52(%rip),%rax
  lea    D22(%rip),%r14
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r15,%rbx
  and    $0xf,%ebx
  jne    L63
  test   %r15,%r15
  je     L55
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L55:
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L63:
  movzbl 0x0(%rbp,%r15,1),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  movzbl 0x0(%rbp,%r15,1),%eax
  movb   $0x0,0x11(%rsp,%rbx,1)
  lea    -0x20(%rax),%ecx
  cmp    $0x5f,%cl
  mov    $0x2e,%ecx
  cmovae %ecx,%eax
  add    $0x1,%r15
  mov    %al,0x10(%rsp,%rbx,1)
  cmp    %r15,%r12
  jne    L13
  test   $0xf,%r15b
  je     L32
  lea    D50(%rip),%rbx
  nopl   (%rax)
L6:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  test   $0xf,%r15b
  jne    L6
L32:
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D52(%rip),%rax
  mov    %rax,(%rsp)
  jmp    L32
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string
name: disassemble_data
arguments: tag: D11
type: string
name: disassemble_data
arguments: tag: D52
type: string
name: disassemble_data
arguments: tag: D22
type: string
name: disassemble_data
arguments: tag: D50
type: string

tool: D2: %s:


tool: D11:  %02x

tool: D52:   %s


tool: D22:   %04zx 

tool: D50:    

assistant: ```c
void hexdump(const char *desc, const void *addr, size_t len) {
  size_t i;
  unsigned char buff[17];
  const unsigned char *pc = addr;
  if (desc != NULL)
    printf("%s:\n", desc);
  for (i = 0; i < len; i++) {
    if ((i % 16) == 0) {
      if (i != 0)
        printf("  %s\n", buff);
      printf("  %04zx ", i);
    }
    printf(" %02x", pc[i]);
    if ((pc[i] < 0x20) || (pc[i] > 0x7e))
      buff[i % 16] = '.';
    else
      buff[i % 16] = pc[i];
    buff[(i % 16) + 1] = '\0';
  }
  while ((i % 16) != 0) {
    printf("   ");
    i++;
  }
  printf("  %s\n", buff);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hexdump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L100
  mov    %rdi,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
L100:
  test   %rbx,%rbx
  je     L48
  lea    0x10(%rsp),%rax
  xor    %r15d,%r15d
  lea    D24(%rip),%r13
  mov    %rax,0x8(%rsp)
  lea    D38(%rip),%rax
  lea    D17(%rip),%r14
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L103:
  mov    %r15,%rbp
  and    $0xf,%ebp
  jne    L7
  test   %r15,%r15
  je     L39
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L39:
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L7:
  movzbl (%r12,%r15,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl (%r12,%r15,1),%eax
  lea    -0x20(%rax),%ecx
  cmp    $0x5e,%cl
  jbe    L20
  add    $0x1,%r15
  movb   $0x2e,0x10(%rsp,%rbp,1)
  movb   $0x0,0x11(%rsp,%rbp,1)
  cmp    %r15,%rbx
  jne    L103
L72:
  test   $0xf,%bl
  je     L18
  lea    D39(%rip),%rbp
  nopl   (%rax)
L71:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  test   $0xf,%bl
  jne    L71
L18:
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%r15
  mov    %al,0x10(%rsp,%rbp,1)
  movb   $0x0,0x11(%rsp,%rbp,1)
  cmp    %r15,%rbx
  jne    L103
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L48:
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D38(%rip),%rax
  mov    %rax,(%rsp)
  jmp    L18
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D38
type_infered: string
name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D39
type_infered: string

tool: D12: %s:


tool: D24:  %02x

tool: D38:   %s


tool: D17:   %04zx 

tool: D39:    

assistant: ```c
void hexdump(const char *desc, const void *addr, size_t len) {
  size_t i;
  unsigned char buff[17];
  const unsigned char *pc = addr;
  if (desc != NULL)
    printf("%s:\n", desc);
  for (i = 0; i < len; i++) {
    if ((i % 16) == 0) {
      if (i != 0)
        printf("  %s\n", buff);
      printf("  %04zx ", i);
    }
    printf(" %02x", pc[i]);
    if ((pc[i] < 0x20) || (pc[i] > 0x7e))
      buff[i % 16] = '.';
    else
      buff[i % 16] = pc[i];
    buff[(i % 16) + 1] = '\0';
  }
  while ((i % 16) != 0) {
    printf("   ");
    i++;
  }
  printf("  %s\n", buff);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Sinusoidal3D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  D18(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L3
L1:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L3:
  cmpl   $0x2,-0x1c(%rbp)
  jle    L1
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
data_type: f64
name: extract_symbolic_data
arguments: data_label: D17
data_type: f64

tool: D18: 1

tool: D17: 20

assistant: ```c
double Sinusoidal3D(double *coordinates) {
  double Lenght = 1;
  double Hight = 20;
  double Energy = 0.0;
  for (int i = 0; i < 3; i++) {
    Energy += Hight * sin(coordinates[i] / Lenght);
  }
  return Energy;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Sinusoidal3D>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x18(%rdi),%r12
  mov    D1(%rip),%rbp
L4:
  movsd  (%rbx),%xmm0
  call   <sin@plt>
  mulsd  D10(%rip),%xmm0
  movq   %rbp,%xmm1
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rbp
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L4
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: f64
name: parse_data
arguments: data_label: D10
type: f64

tool: D1: 0

tool: D10: 20

assistant: ```c
double Sinusoidal3D(double *coordinates) {
  double Lenght = 1;
  double Hight = 20;
  double Energy = 0.0;
  for (int i = 0; i < 3; i++) {
    Energy += Hight * sin(coordinates[i] / Lenght);
  }
  return Energy;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Sinusoidal3D>:
  endbr64
  push   %rbp
  pxor   %xmm1,%xmm1
  lea    0x18(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
L5:
  movsd  (%rbx),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <sin@plt>
  mulsd  D7(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L5
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: f64

tool: D7: 20

assistant: ```c
double Sinusoidal3D(double *coordinates) {
  double Lenght = 1;
  double Hight = 20;
  double Energy = 0.0;
  for (int i = 0; i < 3; i++) {
    Energy += Hight * sin(coordinates[i] / Lenght);
  }
  return Energy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Sinusoidal3D>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  (%rdi),%xmm0
  call   <sin@plt>
  mulsd  D23(%rip),%xmm0
  addsd  D21(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  0x8(%rbx),%xmm0
  call   <sin@plt>
  mulsd  D23(%rip),%xmm0
  movsd  0x8(%rsp),%xmm2
  addsd  %xmm0,%xmm2
  movsd  0x10(%rbx),%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <sin@plt>
  mulsd  D23(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_infered: f64
name: extract_symbolic_data
arguments: tag: D21
type_infered: f64

tool: D23: 20

tool: D21: 0

assistant: ```c
double Sinusoidal3D(double *coordinates) {
  double Lenght = 1;
  double Hight = 20;
  double Energy = 0.0;
  for (int i = 0; i < 3; i++) {
    Energy += Hight * sin(coordinates[i] / Lenght);
  }
  return Energy;
}
```