ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_sync>:
  endbr64
  push   %r12
  mov    $0x18,%edx
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  pxor   %xmm0,%xmm0
  mov    $0x18,%edx
  mov    %ebp,%edi
  mov    D9(%rip),%rax
  mov    %r12,%rsi
  movaps %xmm0,(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_sync(struct i2c_client *cliente, int file) {
  struct input_event ev;
  memset(&ev, 0, sizeof(struct input_event));
  ev.type = EV_SYN;
  ev.code = 0;
  ev.value = 0;
  write(file, &ev, sizeof(struct input_event));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rcu_blocking_is_gp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <might_sleep@plt>
  mov    $0x0,%eax
  call   <num_online_cpus@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int rcu_blocking_is_gp(void) {
  might_sleep();
  return num_online_cpus() == 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rcu_blocking_is_gp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <might_sleep@plt>
  mov    $0x0,%eax
  call   <num_online_cpus@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rcu_blocking_is_gp(void) {
  might_sleep();
  return num_online_cpus() == 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rcu_blocking_is_gp>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <might_sleep@plt>
  xor    %eax,%eax
  call   <num_online_cpus@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int rcu_blocking_is_gp(void) {
  might_sleep();
  return num_online_cpus() == 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rcu_blocking_is_gp>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <might_sleep@plt>
  xor    %eax,%eax
  call   <num_online_cpus@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int rcu_blocking_is_gp(void) {
  might_sleep();
  return num_online_cpus() == 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<esprimo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L24
L7:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L28
  movl   $0x0,-0x8(%rbp)
L28:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L4
  cmpl   $0x1,-0x8(%rbp)
  je     L7
L4:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int esprimo(i) {
  int primo = 1;
  int a = 2;
  while (a < i && primo == 1) {
    if (i % a == 0) {
      primo = 0;
    }
    a++;
  }
  return primo;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<esprimo>:
  endbr64
  cmp    $0x2,%edi
  jle    L20
  mov    $0x2,%ecx
  jmp    L18
L30:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L12
L18:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L30
L14:
  ret
L12:
  mov    $0x1,%eax
  ret
L20:
  mov    $0x1,%eax
  jmp    L14
```

assistant: ```c
int esprimo(i) {
  int primo = 1;
  int a = 2;
  while (a < i && primo == 1) {
    if (i % a == 0) {
      primo = 0;
    }
    a++;
  }
  return primo;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<esprimo>:
  endbr64
  cmp    $0x2,%edi
  jle    L1
  mov    $0x2,%ecx
  xchg   %ax,%ax
L28:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  setne  %al
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jle    L13
  test   %al,%al
  jne    L28
L13:
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int esprimo(i) {
  int primo = 1;
  int a = 2;
  while (a < i && primo == 1) {
    if (i % a == 0) {
      primo = 0;
    }
    a++;
  }
  return primo;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<esprimo>:
  endbr64
  cmp    $0x2,%edi
  jle    L11
  mov    $0x2,%ecx
  xchg   %ax,%ax
L29:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  setne  %al
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jle    L12
  test   %al,%al
  jne    L29
L12:
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int esprimo(i) {
  int primo = 1;
  int a = 2;
  while (a < i && primo == 1) {
    if (i % a == 0) {
      primo = 0;
    }
    a++;
  }
  return primo;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<helper_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x4,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x6,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
type: string
name: disassemble_data
arguments: data_tag: D14
type: string

tool: D25: helper_function

tool: D14: %s(%d): a is %d


assistant: ```c
void helper_function(int a) {
  printf("%s(%d): a is %d\n", __func__, 4, a);
  a += 5;
  printf("%s(%d): a is %d\n", __func__, 6, a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<helper_function>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%ecx
  mov    $0x4,%edx
  lea    D14(%rip),%r12
  mov    %r12,%rsi
  lea    D11(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x5(%rbx),%ecx
  mov    $0x6,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D11
data_type: string

tool: D14: helper_function

tool: D11: %s(%d): a is %d


assistant: ```c
void helper_function(int a) {
  printf("%s(%d): a is %d\n", __func__, 4, a);
  a += 5;
  printf("%s(%d): a is %d\n", __func__, 6, a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<helper_function>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  mov    %edi,%ecx
  mov    $0x4,%edx
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %r12,%rsi
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x5(%rbx),%ecx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  mov    $0x6,%edx
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string

tool: D13: helper_function

tool: D7: %s(%d): a is %d


assistant: ```c
void helper_function(int a) {
  printf("%s(%d): a is %d\n", __func__, 4, a);
  a += 5;
  printf("%s(%d): a is %d\n", __func__, 6, a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<helper_function>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  mov    %edi,%ecx
  mov    $0x4,%edx
  push   %rbp
  lea    D19(%rip),%rbp
  mov    %r12,%rsi
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x5(%rbx),%ecx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  mov    $0x6,%edx
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string
name: extract_symbolic_data
arguments: tag: D19
type_infered: string

tool: D6: helper_function

tool: D19: %s(%d): a is %d


assistant: ```c
void helper_function(int a) {
  printf("%s(%d): a is %d\n", __func__, 4, a);
  a += 5;
  printf("%s(%d): a is %d\n", __func__, 6, a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Shell_Sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  jmp    L13
L67:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L40
L54:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L48
L36:
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L48:
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L36
L17:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L40:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L54
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
L13:
  cmpl   $0x0,-0x10(%rbp)
  jg     L67
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Shell_Sort(int array[], int size) {
  int gap, i, temp, j;
  for (gap = size / 2; gap > 0; gap /= 2) {
    for (i = gap; i < size; i++) {
      temp = array[i];
      for (j = i; j >= gap && array[j - gap] > temp; j -= gap)
        array[j] = array[j - gap];
      array[j] = temp;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Shell_Sort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  shr    $0x1f,%esi
  add    %ebp,%esi
  sar    %esi
  cmp    $0x1,%ebp
  jg     L37
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  movslq %edi,%rdi
  mov    %r8d,(%rbx,%rdi,4)
  add    $0x1,%r12d
  add    $0x4,%r11
  cmp    %r12d,%ebp
  je     L32
L4:
  mov    (%r11),%r8d
  mov    %r11,%rdx
  mov    %r12d,%eax
  mov    %r12d,%edi
  cmp    %r12d,%esi
  jg     L43
L8:
  mov    %eax,%edi
  sub    %esi,%eax
  mov    (%rdx,%r9,1),%ecx
  cmp    %r8d,%ecx
  jle    L43
  mov    %ecx,(%rdx)
  add    %r10,%rdx
  cmp    %esi,%eax
  jge    L8
  mov    %eax,%edi
  jmp    L43
L32:
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cmp    $0x1,%esi
  jle    L36
  mov    %eax,%esi
L37:
  cmp    %esi,%ebp
  jle    L32
  movslq %esi,%r9
  lea    (%rbx,%r9,4),%r11
  mov    %esi,%r10d
  neg    %r10d
  movslq %r10d,%r10
  shl    $0x2,%r10
  neg    %r9
  shl    $0x2,%r9
  mov    %esi,%r12d
  jmp    L4
```

assistant: ```c
void Shell_Sort(int array[], int size) {
  int gap, i, temp, j;
  for (gap = size / 2; gap > 0; gap /= 2) {
    for (i = gap; i < size; i++) {
      temp = array[i];
      for (j = i; j >= gap && array[j - gap] > temp; j -= gap)
        array[j] = array[j - gap];
      array[j] = temp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Shell_Sort>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L54
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L55:
  cmp    %r8d,%r13d
  jle    L4
  mov    %r8d,%r9d
  movslq %r8d,%rbp
  mov    %r8d,%r14d
  neg    %r9d
  shl    $0x2,%rbp
  movslq %r9d,%r9
  lea    (%r12,%rbp,1),%rbx
  shl    $0x2,%r9
L19:
  mov    %rbx,%rax
  mov    (%rbx),%r10d
  mov    %rbx,%rcx
  mov    %r14d,%edx
  sub    %rbp,%rax
  jmp    L57
  nopl   0x0(%rax)
L79:
  mov    %esi,(%rcx)
  add    %r9,%rax
  lea    (%rdi,%r9,1),%rcx
  cmp    %r8d,%edx
  jl     L42
L57:
  mov    (%rax),%esi
  sub    %r8d,%edx
  mov    %rax,%r11
  mov    %rcx,%rdi
  cmp    %r10d,%esi
  jg     L79
  add    $0x1,%r14d
  mov    %r10d,(%rdi)
  add    $0x4,%rbx
  cmp    %r14d,%r13d
  jne    L19
L4:
  sar    %r8d
  jne    L55
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L42:
  mov    %r11,%rdi
  add    $0x1,%r14d
  add    $0x4,%rbx
  mov    %r10d,(%rdi)
  cmp    %r14d,%r13d
  jne    L19
  jmp    L4
L54:
  ret
```

assistant: ```c
void Shell_Sort(int array[], int size) {
  int gap, i, temp, j;
  for (gap = size / 2; gap > 0; gap /= 2) {
    for (i = gap; i < size; i++) {
      temp = array[i];
      for (j = i; j >= gap && array[j - gap] > temp; j -= gap)
        array[j] = array[j - gap];
      array[j] = temp;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Shell_Sort>:
  endbr64
  mov    %esi,%r9d
  shr    $0x1f,%r9d
  add    %esi,%r9d
  sar    %r9d
  cmp    $0x1,%esi
  jle    L48
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cs nopw 0x0(%rax,%rax,1)
L19:
  cmp    %r9d,%r12d
  jle    L24
  movslq %r9d,%r8
  mov    %r9d,%r13d
  shl    $0x2,%r8
  lea    0x0(%rbp,%r8,1),%rbx
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rax
  mov    (%rbx),%r10d
  mov    %rbx,%rcx
  mov    %r13d,%edx
  sub    %r8,%rax
  jmp    L34
  nopl   0x0(%rax)
L88:
  sub    %r8,%rdi
  mov    %esi,(%rcx)
  sub    %r8,%rax
  mov    %rdi,%rcx
  cmp    %edx,%r9d
  jg     L84
L34:
  mov    (%rax),%esi
  sub    %r9d,%edx
  mov    %rax,%r11
  mov    %rcx,%rdi
  cmp    %r10d,%esi
  jg     L88
  add    $0x1,%r13d
  mov    %r10d,(%rdi)
  add    $0x4,%rbx
  cmp    %r13d,%r12d
  jne    L6
L24:
  sar    %r9d
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L84:
  mov    %r11,%rdi
  add    $0x1,%r13d
  add    $0x4,%rbx
  mov    %r10d,(%rdi)
  cmp    %r13d,%r12d
  jne    L6
  jmp    L24
L48:
  ret
```

assistant: ```c
void Shell_Sort(int array[], int size) {
  int gap, i, temp, j;
  for (gap = size / 2; gap > 0; gap /= 2) {
    for (i = gap; i < size; i++) {
      temp = array[i];
      for (j = i; j >= gap && array[j - gap] > temp; j -= gap)
        array[j] = array[j - gap];
      array[j] = temp;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x3,%eax
  or     $0x61bab5,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L48:
  movl   $0x0,-0x14(%rbp)
  jmp    L37
L1:
  addl   $0x2,-0x14(%rbp)
L37:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jb     L1
  addl   $0x2,-0x10(%rbp)
L28:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L48
  mov    -0xc(%rbp),%eax
  or     $0x1b57634e,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 458711886UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%r8d
  shr    $0x3,%r8d
  mov    0x4(%rdi),%edx
  mov    $0x0,%ecx
  test   %edx,%edx
  je     L3
L25:
  mov    $0x0,%eax
L15:
  add    $0x2,%eax
  cmp    %edx,%eax
  jb     L15
  add    $0x2,%ecx
  cmp    %edx,%ecx
  jb     L25
L3:
  mov    %r8d,%eax
  or     $0x1b77fbff,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 458711886UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%r8d
  mov    0x4(%rdi),%edx
  xor    %ecx,%ecx
  shr    $0x3,%r8d
  test   %edx,%edx
  je     L5
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x2,%eax
  cmp    %edx,%eax
  jb     L14
  add    $0x2,%ecx
  cmp    %edx,%ecx
  jb     L1
L5:
  mov    %r8d,%eax
  or     $0x1b77fbff,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 458711886UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%r8d
  mov    0x4(%rdi),%edx
  xor    %ecx,%ecx
  shr    $0x3,%r8d
  test   %edx,%edx
  je     L27
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x2,%eax
  cmp    %edx,%eax
  jb     L18
  add    $0x2,%ecx
  cmp    %edx,%ecx
  jb     L16
L27:
  mov    %r8d,%eax
  or     $0x1b77fbff,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 458711886UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<t1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void *t1(void *arg) {
  int a;
  a = *((int *)arg);
  assert(a == 10);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t1>:
  endbr64
  sub    $0x8,%rsp
  cmpl   $0xa,(%rdi)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *t1(void *arg) {
  int a;
  a = *((int *)arg);
  assert(a == 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<t1>:
  endbr64
  sub    $0x8,%rsp
  cmpl   $0xa,(%rdi)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *t1(void *arg) {
  int a;
  a = *((int *)arg);
  assert(a == 10);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<t1>:
  endbr64
  sub    $0x8,%rsp
  cmpl   $0xa,(%rdi)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *t1(void *arg) {
  int a;
  a = *((int *)arg);
  assert(a == 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calcular_fitness>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%r13d
  movslq %esi,%r12
  lea    (%rdi,%r12,1),%rbx
  movzbl (%rbx),%eax
  lea    -0x1(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  mov    %rax,%rbp
  add    %r12,%rbx
  movzbl (%rbx),%eax
  lea    -0x1(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%ebp
  movsbl %r13b,%r13d
  add    %r13d,%ebp
  add    %r12,%rbx
  movzbl (%rbx),%eax
  lea    -0x2(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%ebp
  add    %r12,%rbx
  movzbl (%rbx),%eax
  lea    -0x1(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%ebp
  add    %r12,%rbx
  movzbl (%rbx),%eax
  lea    -0x2(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%ebp
  add    %r12,%rbx
  movzbl (%rbx),%eax
  lea    -0x2(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%ebp
  movzbl (%rbx,%r12,1),%edi
  sub    $0x3,%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%ebp
  mov    $0xf4240,%eax
  sub    %ebp,%eax
  test   %ebp,%ebp
  mov    $0x3b9aca00,%edx
  cmove  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int calcular_fitness(char *results, int num_samples) {
  int soma_distancias = 0;
  soma_distancias += results[0];
  soma_distancias += absolute(results[1 * num_samples] - 1);
  soma_distancias += absolute(results[2 * num_samples] - 1);
  soma_distancias += absolute(results[3 * num_samples] - 2);
  soma_distancias += absolute(results[4 * num_samples] - 1);
  soma_distancias += absolute(results[5 * num_samples] - 2);
  soma_distancias += absolute(results[6 * num_samples] - 2);
  soma_distancias += absolute(results[7 * num_samples] - 3);
  if (soma_distancias == 0) {
    return 1000000000;
  }
  return 1000000 - soma_distancias;
}
```
user: What is the c source code of the assembly code below:

```asm
<calcular_fitness>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  add    %rbp,%rbx
  sub    $0x8,%rsp
  movzbl (%rbx),%eax
  movsbl (%rdi),%r13d
  add    %rbp,%rbx
  lea    -0x1(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  add    %rbp,%rbx
  lea    -0x1(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%r12d
  movzbl (%rbx),%eax
  add    %rbp,%rbx
  add    %r13d,%r12d
  lea    -0x2(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%r12d
  movzbl (%rbx),%eax
  add    %rbp,%rbx
  lea    -0x1(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%r12d
  movzbl (%rbx),%eax
  add    %rbp,%rbx
  lea    -0x2(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  add    %eax,%r12d
  movzbl (%rbx),%eax
  lea    -0x2(%rax),%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  movzbl (%rbx,%rbp,1),%edi
  add    %eax,%r12d
  sub    $0x3,%edi
  movsbl %dil,%edi
  call   <absolute@plt>
  mov    $0x3b9aca00,%edx
  add    %eax,%r12d
  mov    $0xf4240,%eax
  sub    %r12d,%eax
  test   %r12d,%r12d
  cmove  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int calcular_fitness(char *results, int num_samples) {
  int soma_distancias = 0;
  soma_distancias += results[0];
  soma_distancias += absolute(results[1 * num_samples] - 1);
  soma_distancias += absolute(results[2 * num_samples] - 1);
  soma_distancias += absolute(results[3 * num_samples] - 2);
  soma_distancias += absolute(results[4 * num_samples] - 1);
  soma_distancias += absolute(results[5 * num_samples] - 2);
  soma_distancias += absolute(results[6 * num_samples] - 2);
  soma_distancias += absolute(results[7 * num_samples] - 3);
  if (soma_distancias == 0) {
    return 1000000000;
  }
  return 1000000 - soma_distancias;
}
```