user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D54(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbx
  mov    %rbx,%rsi
  jmp    L33
  nopl   0x0(%rax)
L202:
  mov    %rbx,%rsi
L33:
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%ecx
  cmp    $0x14,%ecx
  ja     L202
  lea    0x20(%rsp),%rbx
  nopl   0x0(%rax)
L115:
  test   %ecx,%ecx
  jle    L200
  mov    %rbx,%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L154:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0x1c(%rsp),%ecx
  cmp    %ebp,%ecx
  jg     L154
L200:
  mov    0x20(%rsp),%r9d
  test   %r9d,%r9d
  jne    L115
  lea    -0x1(%rcx),%eax
  cltq
  mov    0x20(%rsp,%rax,4),%r8d
  test   %r8d,%r8d
  jne    L115
  movl   $0x3e8,0xc(%rsp)
  lea    D53(%rip),%r14
  lea    0x70(%rsp),%r15
  lea    D6(%rip),%r12
  lea    D7(%rip),%rbp
  nopl   (%rax)
L77:
  xor    %r13d,%r13d
  cmp    $0x1,%ecx
  jg     L58
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L180:
  mov    %rbp,%rdi
  add    $0x1,%r13
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r13d,%eax
  jle    L6
L58:
  mov    (%rbx,%r13,4),%edi
  test   %edi,%edi
  je     L180
  mov    %r12,%rdi
  add    $0x1,%r13
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r13d,%eax
  jg     L58
L6:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x1c(%rsp),%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <next_generation@plt>
  mov    0x1c(%rsp),%ecx
  cmp    $0x1,%ecx
  jle    L126
  lea    -0x2(%rcx),%edx
  mov    %rbx,%rax
  lea    0x24(%rsp,%rdx,4),%rdx
  jmp    L93
  nopl   0x0(%rax)
L75:
  add    $0x4,%rax
  cmp    %rax,%rdx
  je     L40
L93:
  mov    (%rax),%esi
  test   %esi,%esi
  je     L75
  subl   $0x1,0xc(%rsp)
  jne    L77
  nopw   0x0(%rax,%rax,1)
L145:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L40:
  xor    %ebp,%ebp
  lea    D6(%rip),%r13
  lea    D7(%rip),%r12
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jle    L126
L29:
  mov    (%rbx,%rbp,4),%eax
  test   %eax,%eax
  je     L64
  mov    %r13,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jg     L29
L126:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L145
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D54
type_guessed: string
name: unpack_data
arguments: tag: D53
type_guessed: string
name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D54: %d

tool: D53:  


tool: D6: *

tool: D7: .

assistant: ```c
int main() {
  int n, j, i, check, current[20], next[20];
  scanf("%d", &n);
  while (n < 0 || n > 20) {
    scanf("%d", &n);
  }
  do {
    for (i = 0; i < n; i++) {
      scanf("%d", &current[i]);
    }
  } while (current[0] != 0 || current[n - 1] != 0);
  for (j = 0; j < 1000; j++) {
    check = 0;
    for (i = 0; i < n - 1; i++) {
      if (current[i] == 0) {
        printf(".");
      } else {
        printf("*");
      }
    }
    printf(" \n");
    next_generation(&next[0], &current[0], n);
    for (i = 0; i < n - 1; i++) {
      if (current[i] != 0) {
        check = 1;
        break;
      }
    }
    if (check != 1) {
      for (i = 0; i < n - 1; i++) {
        if (current[i] == 0) {
          printf(".");
        } else {
          printf("*");
        }
      }
      printf(" \n");
      break;
    }
  }
}
```