ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L53:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L53
L38:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L68
  orq    $0x0,-0x8(%rsp,%rax,1)
L68:
  mov    %rsp,%r12
  test   %r13d,%r13d
  jle    L82
  mov    %r13d,%edx
  mov    $0x0,%eax
L64:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L64
L82:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r14d,%r14d
  jle    L56
  mov    $0x0,%ebx
L85:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <stdlib_strided_dminsorted@plt>
  ucomisd %xmm0,%xmm0
  jp     L2
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jne    L85
L56:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L5:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L2:
  lea    D6(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L5
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: string

tool: D6: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = i;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dminsorted(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  mov    %rsp,%rbp
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdx,8),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L52
L15:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L15
L52:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L10
L81:
  mov    %rsp,%r12
  test   %r13d,%r13d
  jle    L56
  xor    %eax,%eax
  nopl   0x0(%rax)
L39:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L39
L56:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x38(%rbp)
  test   %r14d,%r14d
  jle    L97
  xor    %ebx,%ebx
  jmp    L87
  nopl   0x0(%rax)
L49:
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  je     L97
L87:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <stdlib_strided_dminsorted@plt>
  ucomisd %xmm0,%xmm0
  jnp    L49
  lea    D6(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x38(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x38(%rbp)
  call   <printf@plt>
  movsd  -0x38(%rbp),%xmm0
L101:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L97:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x38(%rbp),%xmm0
  jmp    L101
  xchg   %ax,%ax
L10:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L81
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = i;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dminsorted(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L30
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L14
  jmp    L36
L30:
  nop
L36:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, size_t n) {
  int i;
  for (i = 0; i < n; i++) {
    dst[i] = src[i];
    if (src[i] == '\0')
      break;
  }
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L1
  mov    $0x0,%ecx
L12:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  test   %r8b,%r8b
  je     L1
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L12
L1:
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, size_t n) {
  int i;
  for (i = 0; i < n; i++) {
    dst[i] = src[i];
    if (src[i] == '\0')
      break;
  }
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L33
  xor    %ecx,%ecx
  jmp    L12
L5:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L33
L12:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  test   %r8b,%r8b
  jne    L5
L33:
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, size_t n) {
  int i;
  for (i = 0; i < n; i++) {
    dst[i] = src[i];
    if (src[i] == '\0')
      break;
  }
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L29
  xor    %ecx,%ecx
  jmp    L25
L13:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L29
L25:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  test   %r8b,%r8b
  jne    L13
L29:
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, size_t n) {
  int i;
  for (i = 0; i < n; i++) {
    dst[i] = src[i];
    if (src[i] == '\0')
      break;
  }
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L2
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <fatal_error@plt>
L2:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: Invalid number: %s

assistant: ```c
double parse_double(const char *string) {
  double val;
  char *parse_end;
  val = strtod(string, &parse_end);
  if (parse_end == string)
    fatal_error("Invalid number: %s", string);
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parse_double>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtod@plt>
  movq   %xmm0,%rbp
  cmp    %rbx,(%rsp)
  je     L1
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  movq   %rbp,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <fatal_error@plt>
  jmp    L21
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: Invalid number: %s

assistant: ```c
double parse_double(const char *string) {
  double val;
  char *parse_end;
  val = strtod(string, &parse_end);
  if (parse_end == string)
    fatal_error("Invalid number: %s", string);
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_double>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <strtod@plt>
  cmp    %rbp,0x10(%rsp)
  je     L24
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <fatal_error@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L19
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type: string

tool: D3: Invalid number: %s

assistant: ```c
double parse_double(const char *string) {
  double val;
  char *parse_end;
  val = strtod(string, &parse_end);
  if (parse_end == string)
    fatal_error("Invalid number: %s", string);
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_double>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <strtod@plt>
  cmp    %rbp,0x10(%rsp)
  je     L25
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <fatal_error@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L13
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D1: Invalid number: %s

assistant: ```c
double parse_double(const char *string) {
  double val;
  char *parse_end;
  val = strtod(string, &parse_end);
  if (parse_end == string)
    fatal_error("Invalid number: %s", string);
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_parameters_II>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_parameters_II(int num_parameters, char ***parameters) {
  int i = 0;
  for (i = 0; i < num_parameters; i++)
    free((*parameters)[i]);
  free((*parameters));
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_parameters_II>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  test   %edi,%edi
  jle    L3
  mov    %edi,%edi
  lea    0x0(,%rdi,8),%rbp
  mov    $0x0,%ebx
L5:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L5
L3:
  mov    (%r12),%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free_parameters_II(int num_parameters, char ***parameters) {
  int i = 0;
  for (i = 0; i < num_parameters; i++)
    free((*parameters)[i]);
  free((*parameters));
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_parameters_II>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L17
  movslq %edi,%rdi
  xor    %ebx,%ebx
  lea    0x0(,%rdi,8),%rbp
  nopl   0x0(%rax)
L3:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L3
L17:
  mov    (%r12),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_parameters_II(int num_parameters, char ***parameters) {
  int i = 0;
  for (i = 0; i < num_parameters; i++)
    free((*parameters)[i]);
  free((*parameters));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_parameters_II>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L17
  movslq %edi,%rdi
  xor    %ebx,%ebx
  lea    0x0(,%rdi,8),%rbp
  nopl   0x0(%rax)
L1:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L1
L17:
  mov    (%r12),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_parameters_II(int num_parameters, char ***parameters) {
  int i = 0;
  for (i = 0; i < num_parameters; i++)
    free((*parameters)[i]);
  free((*parameters));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_ts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  cmp    $0xffffffff,%eax
  jne    L18
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <gettext@plt>
  mov    %eax,%edi
  call   <error_exit@plt>
L18:
  mov    -0x18(%rbp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    -0x20(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  D10(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x24(%rbp),%eax
  imul   $0x3c,%eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D10
data_type: f64

tool: D19: gettimeofday failed

tool: D10: 1000000

assistant: ```c
double get_ts(void) {
  struct timeval ts;
  struct timezone tz;
  if (gettimeofday(&ts, &tz) == -1)
    error_exit(gettext("gettimeofday failed"));
  return (double)ts.tv_sec + ((double)ts.tv_usec) / 1000000.0 + (double)(tz.tz_minuteswest * 60);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_ts>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  cmp    $0xffffffff,%eax
  je     L2
L12:
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x10(%rsp),%xmm0
  divsd  D17(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x18(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  imul   $0x3c,0xc(%rsp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  ret
L2:
  lea    D3(%rip),%rdi
  call   <gettext@plt>
  mov    %eax,%edi
  call   <error_exit@plt>
  jmp    L12
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
datatype: f64
name: parse_data
arguments: label: D3
datatype: string

tool: D17: 1000000

tool: D3: gettimeofday failed

assistant: ```c
double get_ts(void) {
  struct timeval ts;
  struct timezone tz;
  if (gettimeofday(&ts, &tz) == -1)
    error_exit(gettext("gettimeofday failed"));
  return (double)ts.tv_sec + ((double)ts.tv_usec) / 1000000.0 + (double)(tz.tz_minuteswest * 60);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ts>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  cmp    $0xffffffff,%eax
  je     L25
L4:
  pxor   %xmm1,%xmm1
  imul   $0x3c,0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x18(%rsp),%xmm1
  cvtsi2sdq 0x10(%rsp),%xmm0
  divsd  D13(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L25:
  lea    D2(%rip),%rdi
  call   <gettext@plt>
  mov    %eax,%edi
  call   <error_exit@plt>
  jmp    L4
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: f64
name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D13: 1000000

tool: D2: gettimeofday failed

assistant: ```c
double get_ts(void) {
  struct timeval ts;
  struct timezone tz;
  if (gettimeofday(&ts, &tz) == -1)
    error_exit(gettext("gettimeofday failed"));
  return (double)ts.tv_sec + ((double)ts.tv_usec) / 1000000.0 + (double)(tz.tz_minuteswest * 60);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ts>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  cmp    $0xffffffff,%eax
  je     L3
L15:
  pxor   %xmm1,%xmm1
  imul   $0x3c,0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x18(%rsp),%xmm1
  cvtsi2sdq 0x10(%rsp),%xmm0
  divsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L3:
  lea    D18(%rip),%rdi
  call   <gettext@plt>
  mov    %eax,%edi
  call   <error_exit@plt>
  jmp    L15
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_infered: f64
name: read_data
arguments: label: D18
type_infered: string

tool: D0: 1000000

tool: D18: gettimeofday failed

assistant: ```c
double get_ts(void) {
  struct timeval ts;
  struct timezone tz;
  if (gettimeofday(&ts, &tz) == -1)
    error_exit(gettext("gettimeofday failed"));
  return (double)ts.tv_sec + ((double)ts.tv_usec) / 1000000.0 + (double)(tz.tz_minuteswest * 60);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<legal_move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L20
L73:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L75
L15:
  addl   $0x1,-0x10(%rbp)
L20:
  cmpl   $0x8,-0x10(%rbp)
  jle    L73
  movl   $0x0,-0x10(%rbp)
  jmp    L103
L40:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L91
  mov    $0x0,%eax
  jmp    L75
L91:
  addl   $0x1,-0x10(%rbp)
L103:
  cmpl   $0x8,-0x10(%rbp)
  jle    L40
  movl   $0x0,-0x10(%rbp)
  jmp    L99
L107:
  movl   $0x0,-0xc(%rbp)
  jmp    L102
L60:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L75
L31:
  addl   $0x1,-0xc(%rbp)
L102:
  cmpl   $0x2,-0xc(%rbp)
  jle    L60
  addl   $0x1,-0x10(%rbp)
L99:
  cmpl   $0x2,-0x10(%rbp)
  jle    L107
  mov    $0x1,%eax
L75:
  pop    %rbp
  ret
```

assistant: ```c
int legal_move(int pzl[][9], int n, int r, int c) {
  int i;
  int j;
  int kr;
  int kc;
  kr = r / 3;
  kc = c / 3;
  for (i = 0; i < 9; i++) {
    if (n == pzl[i][c]) {
      return 0;
    }
  }
  for (i = 0; i < 9; i++) {
    if (n == pzl[r][i]) {
      return 0;
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (n == pzl[3 * kr + i][3 * kc + j]) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<legal_move>:
  endbr64
  mov    %edx,%r8d
  movslq %ecx,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rax
  lea    0x144(%rdi,%rdx,1),%rdx
L44:
  cmp    %esi,(%rax)
  je     L28
  add    $0x24,%rax
  cmp    %rdx,%rax
  jne    L44
  movslq %r8d,%rax
  lea    (%rax,%rax,8),%rax
  lea    (%rdi,%rax,4),%rax
  lea    0x24(%rax),%rdx
L23:
  cmp    %esi,(%rax)
  je     L7
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L23
  movslq %r8d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%eax
  cltq
  lea    (%rax,%rax,8),%rdx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  cltq
  add    %rax,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rax
  lea    0x6c(%rdi,%rdx,1),%rcx
L49:
  mov    %rax,%rdx
  cmp    (%rax),%esi
  je     L62
  cmp    0x4(%rax),%esi
  je     L55
  cmp    %esi,0x8(%rdx)
  je     L57
  add    $0x24,%rax
  cmp    %rcx,%rax
  jne    L49
  mov    $0x1,%eax
  ret
L55:
  mov    $0x0,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
L57:
  mov    $0x0,%eax
  ret
L62:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int legal_move(int pzl[][9], int n, int r, int c) {
  int i;
  int j;
  int kr;
  int kc;
  kr = r / 3;
  kc = c / 3;
  for (i = 0; i < 9; i++) {
    if (n == pzl[i][c]) {
      return 0;
    }
  }
  for (i = 0; i < 9; i++) {
    if (n == pzl[r][i]) {
      return 0;
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (n == pzl[3 * kr + i][3 * kc + j]) {
        return 0;
      }
    }
  }
  return 1;
}
```