ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%ebx
L59:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L59
  movslq %ebp,%rbp
  movb   $0x0,(%rsp,%rbp,1)
  movzbl (%rsp),%eax
  test   %al,%al
  je     L8
  lea    0x1(%rsp),%rdx
  mov    $0x0,%edi
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  movabs $0x8c00500200000000,%r10
  jmp    L17
L27:
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x1a,%al
  adc    $0x0,%r8d
  cmp    $0x3f,%cl
  ja     L76
L60:
  mov    %r10,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  add    %eax,%edi
L76:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L64
L17:
  mov    %eax,%ecx
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L27
  add    $0x1,%r9d
  jmp    L60
L8:
  mov    $0x0,%edi
  mov    $0x0,%r9d
  mov    $0x0,%r8d
L64:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r9d,%xmm0
  mulsd  D22(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  mulsd  D17(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
datatype: f64
name: read_data
arguments: data_label: D17
datatype: f64
name: read_data
arguments: data_label: D2
datatype: string

tool: D22: 0.5

tool: D17: 0.8

tool: D2: %.1f


assistant: ```c
int main(void) {
  char array[1024] = {};
  int i = 0;
  int count_char = 0, count_number = 0, count_symbol = 0;
  float sum = 0;
  while ('\n' != (array[i] = getchar()))
    i++;
  array[i] = '\0';
  for (i = 0; array[i] != '\0'; i++) {
    if (array[i] >= '0' && array[i] <= '9')
      count_number += 1;
    if ((array[i] >= 'a' && array[i] <= 'z') || (array[i] >= 'A' && array[i] <= 'Z'))
      count_char += 1;
    switch (array[i]) {
    case ',':
    case '.':
    case '?':
    case ':':
    case '!':
    case ';':
      count_symbol += 1;
      break;
    default:
      break;
    }
  }
  printf("%.1f\n", count_char * 1.0 + count_number * 0.5 + count_symbol * 0.8);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  mov    %rsp,%r12
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L28
  movb   $0x0,(%rsp,%rbp,1)
  movzbl (%rsp),%ecx
  test   %cl,%cl
  je     L80
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  xor    %r8d,%r8d
  xor    %edi,%edi
  movabs $0x8c00500200000000,%r9
  jmp    L7
  xchg   %ax,%ax
L22:
  add    $0x1,%r8d
L78:
  mov    %r9,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    $0xffffffff,%esi
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  je     L73
L7:
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%al
  jbe    L22
  mov    %ecx,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x1a,%al
  adc    $0x0,%edi
  cmp    $0x3f,%cl
  jbe    L78
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L7
  nopl   0x0(%rax)
L73:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm0
  mulsd  D7(%rip),%xmm0
  cvtsi2sd %edi,%xmm1
  lea    D23(%rip),%rdi
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  D12(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L80:
  xor    %esi,%esi
  xor    %r8d,%r8d
  xor    %edi,%edi
  jmp    L73
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: f64
name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: f64

tool: D7: 0.5

tool: D23: %.1f


tool: D12: 0.8

assistant: ```c
int main(void) {
  char array[1024] = {};
  int i = 0;
  int count_char = 0, count_number = 0, count_symbol = 0;
  float sum = 0;
  while ('\n' != (array[i] = getchar()))
    i++;
  array[i] = '\0';
  for (i = 0; array[i] != '\0'; i++) {
    if (array[i] >= '0' && array[i] <= '9')
      count_number += 1;
    if ((array[i] >= 'a' && array[i] <= 'z') || (array[i] >= 'A' && array[i] <= 'Z'))
      count_char += 1;
    switch (array[i]) {
    case ',':
    case '.':
    case '?':
    case ':':
    case '!':
    case ';':
      count_symbol += 1;
      break;
    default:
      break;
    }
  }
  printf("%.1f\n", count_char * 1.0 + count_number * 0.5 + count_symbol * 0.8);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  mov    %rsp,%r12
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L21
  movb   $0x0,(%rsp,%rbp,1)
  movzbl (%rsp),%ecx
  test   %cl,%cl
  je     L82
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  xor    %r8d,%r8d
  xor    %edi,%edi
  movabs $0x8c00500200000000,%r9
  jmp    L73
  xchg   %ax,%ax
L12:
  add    $0x1,%r8d
L85:
  mov    %r9,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    $0xffffffff,%esi
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  je     L84
L73:
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%al
  jbe    L12
  mov    %ecx,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x1a,%al
  adc    $0x0,%edi
  cmp    $0x3f,%cl
  jbe    L85
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L73
  nopl   0x0(%rax)
L84:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm0
  mulsd  D15(%rip),%xmm0
  cvtsi2sd %edi,%xmm1
  lea    D19(%rip),%rdi
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  D7(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L82:
  xor    %esi,%esi
  xor    %r8d,%r8d
  xor    %edi,%edi
  jmp    L84
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type: f64
name: disassemble_data
arguments: tag: D19
type: string
name: disassemble_data
arguments: tag: D7
type: f64

tool: D15: 0.5

tool: D19: %.1f


tool: D7: 0.8

assistant: ```c
int main(void) {
  char array[1024] = {};
  int i = 0;
  int count_char = 0, count_number = 0, count_symbol = 0;
  float sum = 0;
  while ('\n' != (array[i] = getchar()))
    i++;
  array[i] = '\0';
  for (i = 0; array[i] != '\0'; i++) {
    if (array[i] >= '0' && array[i] <= '9')
      count_number += 1;
    if ((array[i] >= 'a' && array[i] <= 'z') || (array[i] >= 'A' && array[i] <= 'Z'))
      count_char += 1;
    switch (array[i]) {
    case ',':
    case '.':
    case '?':
    case ':':
    case '!':
    case ';':
      count_symbol += 1;
      break;
    default:
      break;
    }
  }
  printf("%.1f\n", count_char * 1.0 + count_number * 0.5 + count_symbol * 0.8);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_notify_job>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x128(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%r8
  lea    D3(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <_xmit@plt>
  test   %rax,%rax
  je     L4
  mov    $0x1,%edi
  call   <exit@plt>
L4:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: TS=%u AUTH=root DT=CMD=NOTIFYJOB ARG=%ld MSG=this_is_a_test

assistant: ```c
void _notify_job(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[256];
  snprintf(out_msg, sizeof(out_msg),
           "TS=%u AUTH=root DT=CMD=NOTIFYJOB ARG=%ld "
           "MSG=this_is_a_test",
           (uint32_t)now, my_job_id);
  if (_xmit(out_msg))
    exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_notify_job>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rsp,%rbp
  mov    %rbx,%r8
  mov    %eax,%ecx
  lea    D6(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  test   %rax,%rax
  jne    L20
L27:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L27
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: TS=%u AUTH=root DT=CMD=NOTIFYJOB ARG=%ld MSG=this_is_a_test

assistant: ```c
void _notify_job(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[256];
  snprintf(out_msg, sizeof(out_msg),
           "TS=%u AUTH=root DT=CMD=NOTIFYJOB ARG=%ld "
           "MSG=this_is_a_test",
           (uint32_t)now, my_job_id);
  if (_xmit(out_msg))
    exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<_notify_job>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r8
  mov    $0x100,%esi
  mov    %eax,%ecx
  lea    D4(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  test   %rax,%rax
  jne    L15
L27:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L27
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: TS=%u AUTH=root DT=CMD=NOTIFYJOB ARG=%ld MSG=this_is_a_test

assistant: ```c
void _notify_job(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[256];
  snprintf(out_msg, sizeof(out_msg),
           "TS=%u AUTH=root DT=CMD=NOTIFYJOB ARG=%ld "
           "MSG=this_is_a_test",
           (uint32_t)now, my_job_id);
  if (_xmit(out_msg))
    exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_notify_job>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r8
  mov    $0x100,%esi
  mov    %eax,%ecx
  lea    D6(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  test   %rax,%rax
  jne    L19
L18:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: TS=%u AUTH=root DT=CMD=NOTIFYJOB ARG=%ld MSG=this_is_a_test

assistant: ```c
void _notify_job(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[256];
  snprintf(out_msg, sizeof(out_msg),
           "TS=%u AUTH=root DT=CMD=NOTIFYJOB ARG=%ld "
           "MSG=this_is_a_test",
           (uint32_t)now, my_job_id);
  if (_xmit(out_msg))
    exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jg     L6
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <usage@plt>
L6:
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <initLoganon@plt>
  mov    $0x1,%edi
  call   <loganonAnonymize@plt>
  mov    $0x0,%eax
  call   <terminateLoganon@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    usage(argv[0]);
  initLoganon(argv[1], argv[2]);
  loganonAnonymize(1);
  terminateLoganon();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jle    L9
L3:
  mov    0x10(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <initLoganon@plt>
  mov    $0x1,%edi
  call   <loganonAnonymize@plt>
  mov    $0x0,%eax
  call   <terminateLoganon@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L9:
  mov    (%rsi),%rdi
  call   <usage@plt>
  jmp    L3
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    usage(argv[0]);
  initLoganon(argv[1], argv[2]);
  loganonAnonymize(1);
  terminateLoganon();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jle    L14
L19:
  mov    0x10(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <initLoganon@plt>
  mov    $0x1,%edi
  call   <loganonAnonymize@plt>
  xor    %eax,%eax
  call   <terminateLoganon@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L14:
  mov    (%rsi),%rdi
  call   <usage@plt>
  jmp    L19
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    usage(argv[0]);
  initLoganon(argv[1], argv[2]);
  loganonAnonymize(1);
  terminateLoganon();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jle    L14
L13:
  mov    0x10(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <initLoganon@plt>
  mov    $0x1,%edi
  call   <loganonAnonymize@plt>
  xor    %eax,%eax
  call   <terminateLoganon@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L14:
  mov    (%rsi),%rdi
  call   <usage@plt>
  jmp    L13
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    usage(argv[0]);
  initLoganon(argv[1], argv[2]);
  loganonAnonymize(1);
  terminateLoganon();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prune_alias_exp2_CAF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void prune_alias_exp2_CAF(int x) {
  int a[1];
  if (x + 1 != 1 + x) {
    a[1] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prune_alias_exp2_CAF>:
  endbr64
  ret
```

assistant: ```c
void prune_alias_exp2_CAF(int x) {
  int a[1];
  if (x + 1 != 1 + x) {
    a[1] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prune_alias_exp2_CAF>:
  endbr64
  ret
```

assistant: ```c
void prune_alias_exp2_CAF(int x) {
  int a[1];
  if (x + 1 != 1 + x) {
    a[1] = 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<prune_alias_exp2_CAF>:
  endbr64
  ret
```

assistant: ```c
void prune_alias_exp2_CAF(int x) {
  int a[1];
  if (x + 1 != 1 + x) {
    a[1] = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_arglist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L26
L2:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L26:
  mov    -0x8(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sw_strchr@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L24
  cmpl   $0x6,-0xc(%rbp)
  jle    L2
L24:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_arglist(char *arg_list[], char *arg) {
  int count;
  char *p;
  p = arg;
  count = 0;
  arg_list[count++] = p;
  while ((p = sw_strchr(p, ' ')) != ((void *)0) && count < 7) {
    *p++ = '\0';
    arg_list[count++] = p;
  }
  *p = '\0';
  arg_list[count] = ((void *)0);
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_arglist>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rsi,0x0(%rbp)
  mov    $0x1,%ebx
  jmp    L27
L0:
  lea    0x1(%rdx),%rdi
  movb   $0x0,(%rdx)
  mov    %rdi,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
L27:
  mov    %ebx,%r12d
  mov    $0x20,%esi
  mov    $0x0,%eax
  call   <sw_strchr@plt>
  movslq %eax,%rdx
  cmp    $0x6,%ebx
  jg     L25
  test   %eax,%eax
  jne    L0
L25:
  movb   $0x0,(%rdx)
  movslq %r12d,%rax
  movq   $0x0,0x0(%rbp,%rax,8)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_arglist(char *arg_list[], char *arg) {
  int count;
  char *p;
  p = arg;
  count = 0;
  arg_list[count++] = p;
  while ((p = sw_strchr(p, ' ')) != ((void *)0) && count < 7) {
    *p++ = '\0';
    arg_list[count++] = p;
  }
  *p = '\0';
  arg_list[count] = ((void *)0);
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_arglist>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    $0x1,%ebx
  mov    %rsi,0x0(%rbp)
  jmp    L2
  nopl   0x0(%rax)
L31:
  lea    0x1(%rdx),%rdi
  movb   $0x0,(%rdx)
  mov    %rdi,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
L2:
  mov    $0x20,%esi
  xor    %eax,%eax
  mov    %ebx,%r12d
  call   <sw_strchr@plt>
  movslq %eax,%rdx
  test   %eax,%eax
  je     L30
  cmp    $0x7,%rbx
  jne    L31
  mov    $0x38,%eax
  mov    $0x7,%r12d
L14:
  movb   $0x0,(%rdx)
  pop    %rbx
  movq   $0x0,0x0(%rbp,%rax,1)
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  movslq %ebx,%rax
  shl    $0x3,%rax
  jmp    L14
```

assistant: ```c
int get_arglist(char *arg_list[], char *arg) {
  int count;
  char *p;
  p = arg;
  count = 0;
  arg_list[count++] = p;
  while ((p = sw_strchr(p, ' ')) != ((void *)0) && count < 7) {
    *p++ = '\0';
    arg_list[count++] = p;
  }
  *p = '\0';
  arg_list[count] = ((void *)0);
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_arglist>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    $0x1,%ebx
  mov    %rsi,0x0(%rbp)
  jmp    L25
  nopl   0x0(%rax)
L2:
  lea    0x1(%rdx),%rdi
  movb   $0x0,(%rdx)
  mov    %rdi,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
L25:
  mov    $0x20,%esi
  xor    %eax,%eax
  mov    %ebx,%r12d
  call   <sw_strchr@plt>
  movslq %eax,%rdx
  test   %eax,%eax
  je     L18
  cmp    $0x7,%rbx
  jne    L2
  mov    $0x38,%eax
  mov    $0x7,%r12d
L9:
  movb   $0x0,(%rdx)
  pop    %rbx
  movq   $0x0,0x0(%rbp,%rax,1)
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  movslq %ebx,%rax
  shl    $0x3,%rax
  jmp    L9
```

assistant: ```c
int get_arglist(char *arg_list[], char *arg) {
  int count;
  char *p;
  p = arg;
  count = 0;
  arg_list[count++] = p;
  while ((p = sw_strchr(p, ' ')) != ((void *)0) && count < 7) {
    *p++ = '\0';
    arg_list[count++] = p;
  }
  *p = '\0';
  arg_list[count] = ((void *)0);
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<next_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    D11(%rip),%eax
  cmp    $0x77359400,%eax
  jne    L38
  mov    $0x77359400,%eax
  jmp    L34
L38:
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    D11(%rip),%eax
  jmp    L34
L3:
  mov    D11(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D1(%rip)
L34:
  pop    %rbp
  ret
```

assistant: ```c
int next_id(int no_iterate_flag) {
  static int id = 0;
  if (id == 2000000000) {
    return 2000000000;
  } else {
    if (no_iterate_flag) {
      return id;
    } else {
      return id++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<next_id>:
  endbr64
  mov    D16(%rip),%eax
  cmp    $0x77359400,%eax
  je     L8
  test   %edi,%edi
  jne    L8
  lea    0x1(%rax),%edx
  mov    %edx,D13(%rip)
L8:
  ret
```

assistant: ```c
int next_id(int no_iterate_flag) {
  static int id = 0;
  if (id == 2000000000) {
    return 2000000000;
  } else {
    if (no_iterate_flag) {
      return id;
    } else {
      return id++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_id>:
  endbr64
  mov    D1(%rip),%eax
  cmp    $0x77359400,%eax
  je     L18
  test   %edi,%edi
  je     L7
L18:
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  lea    0x1(%rax),%edx
  mov    %edx,D13(%rip)
  ret
```

assistant: ```c
int next_id(int no_iterate_flag) {
  static int id = 0;
  if (id == 2000000000) {
    return 2000000000;
  } else {
    if (no_iterate_flag) {
      return id;
    } else {
      return id++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<next_id>:
  endbr64
  mov    D6(%rip),%eax
  cmp    $0x77359400,%eax
  je     L5
  test   %edi,%edi
  je     L2
L5:
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  lea    0x1(%rax),%edx
  mov    %edx,D18(%rip)
  ret
```

assistant: ```c
int next_id(int no_iterate_flag) {
  static int id = 0;
  if (id == 2000000000) {
    return 2000000000;
  } else {
    if (no_iterate_flag) {
      return id;
    } else {
      return id++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<izpis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L0:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L0
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

assistant: ```c
void izpis(char *besedilo, int poravnava) {
  besedilo[strlen(besedilo) - 1] = '\0';
  int zamik = (poravnava - strlen(besedilo)) / 2;
  for (int i = 0; i < zamik; ++i) {
    printf(" ");
  }
  printf("%s\n", besedilo);
}
```