ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<BitStream_writeNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L27:
  mov    -0x20(%rbp),%eax
  and    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x1,(%rax)
  jmp    L29
L3:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L29:
  addq   $0x1,-0x8(%rbp)
  shrl   -0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BitStream_writeNum(unsigned char *dest, int bits, unsigned int num) {
  unsigned int mask;
  int i;
  unsigned char *p;
  p = dest;
  mask = 1 << (bits - 1);
  for (i = 0; i < bits; i++) {
    if (num & mask) {
      *p = 1;
    } else {
      *p = 0;
    }
    p++;
    mask = mask >> 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<BitStream_writeNum>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %esi,%esi
  jle    L0
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rcx
L15:
  test   %eax,%edx
  setne  (%rdi)
  add    $0x1,%rdi
  shr    %eax
  cmp    %rcx,%rdi
  jne    L15
L0:
  ret
```

assistant: ```c
void BitStream_writeNum(unsigned char *dest, int bits, unsigned int num) {
  unsigned int mask;
  int i;
  unsigned char *p;
  p = dest;
  mask = 1 << (bits - 1);
  for (i = 0; i < bits; i++) {
    if (num & mask) {
      *p = 1;
    } else {
      *p = 0;
    }
    p++;
    mask = mask >> 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BitStream_writeNum>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %esi,%esi
  jle    L13
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rcx
  nopl   0x0(%rax)
L8:
  test   %eax,%edx
  setne  (%rdi)
  add    $0x1,%rdi
  shr    %eax
  cmp    %rdi,%rcx
  jne    L8
L13:
  ret
```

assistant: ```c
void BitStream_writeNum(unsigned char *dest, int bits, unsigned int num) {
  unsigned int mask;
  int i;
  unsigned char *p;
  p = dest;
  mask = 1 << (bits - 1);
  for (i = 0; i < bits; i++) {
    if (num & mask) {
      *p = 1;
    } else {
      *p = 0;
    }
    p++;
    mask = mask >> 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BitStream_writeNum>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %esi,%esi
  jle    L1
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rcx
  nopl   0x0(%rax)
L12:
  test   %eax,%edx
  setne  (%rdi)
  add    $0x1,%rdi
  shr    %eax
  cmp    %rcx,%rdi
  jne    L12
L1:
  ret
```

assistant: ```c
void BitStream_writeNum(unsigned char *dest, int bits, unsigned int num) {
  unsigned int mask;
  int i;
  unsigned char *p;
  p = dest;
  mask = 1 << (bits - 1);
  for (i = 0; i < bits; i++) {
    if (num & mask) {
      *p = 1;
    } else {
      *p = 0;
    }
    p++;
    mask = mask >> 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read32bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <to32bit@plt>
  leave
  ret
```

assistant: ```c
long read32bit() {
  int c1, c2, c3, c4;
  c1 = egetc();
  c2 = egetc();
  c3 = egetc();
  c4 = egetc();
  return to32bit(c1, c2, c3, c4);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read32bit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <to32bit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long read32bit() {
  int c1, c2, c3, c4;
  c1 = egetc();
  c2 = egetc();
  c3 = egetc();
  c4 = egetc();
  return to32bit(c1, c2, c3, c4);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read32bit>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  call   <egetc@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ecx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <to32bit@plt>
```

assistant: ```c
long read32bit() {
  int c1, c2, c3, c4;
  c1 = egetc();
  c2 = egetc();
  c3 = egetc();
  c4 = egetc();
  return to32bit(c1, c2, c3, c4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read32bit>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  call   <egetc@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ecx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <to32bit@plt>
```

assistant: ```c
long read32bit() {
  int c1, c2, c3, c4;
  c1 = egetc();
  c2 = egetc();
  c3 = egetc();
  c4 = egetc();
  return to32bit(c1, c2, c3, c4);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_dev_no_by_fd>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  mov    %rax,%rdx
  mov    0x4(%rsp),%eax
  test   %rdx,%rdx
  jne    L29
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L29:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L28
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: fstat:

assistant: ```c
dev_t get_dev_no_by_fd(int fd) {
  int err = 0;
  struct stat _stat;
  dev_t dev_no = 0;
  if (0 != fstat(fd, &_stat)) {
    err = errno;
    perror("fstat:");
  } else {
    dev_no = _stat.st_dev;
  }
  return dev_no;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_dev_no_by_fd>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  mov    %rax,%r8
  mov    0x4(%rsp),%eax
  test   %r8,%r8
  jne    L21
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  lea    D8(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  jmp    L11
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: fstat:

assistant: ```c
dev_t get_dev_no_by_fd(int fd) {
  int err = 0;
  struct stat _stat;
  dev_t dev_no = 0;
  if (0 != fstat(fd, &_stat)) {
    err = errno;
    perror("fstat:");
  } else {
    dev_no = _stat.st_dev;
  }
  return dev_no;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_dev_no_by_fd>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  mov    %rax,%r8
  mov    0x4(%rsp),%eax
  test   %r8,%r8
  jne    L8
L20:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  jmp    L20
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: fstat:

assistant: ```c
dev_t get_dev_no_by_fd(int fd) {
  int err = 0;
  struct stat _stat;
  dev_t dev_no = 0;
  if (0 != fstat(fd, &_stat)) {
    err = errno;
    perror("fstat:");
  } else {
    dev_no = _stat.st_dev;
  }
  return dev_no;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  movl   $0x5,-0x8(%rbp)
  jmp    L4
L6:
  movl   $0x0,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x;
  int unknown;
  if (unknown) {
    x = 5;
  } else {
    x = 0;
  }
  assert(x > -1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  int unknown;
  if (unknown) {
    x = 5;
  } else {
    x = 0;
  }
  assert(x > -1);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  int unknown;
  if (unknown) {
    x = 5;
  } else {
    x = 0;
  }
  assert(x > -1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  int unknown;
  if (unknown) {
    x = 5;
  } else {
    x = 0;
  }
  assert(x > -1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<assign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L36:
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L36
  jmp    L34
L0:
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  lea    -0x30(%rcx),%edx
  mov    %edx,(%rax)
L34:
  cmpl   $0x0,-0x8(%rbp)
  jg     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void assign(int *n, char *s) {
  int i = 0, j = 0;
  while (s[i] != '\n')
    ++i;
  while (i >= 1)
    n[j++] = s[--i] - '0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<assign>:
  endbr64
  cmpb   $0xa,(%rsi)
  je     L36
  mov    $0x1,%eax
L22:
  mov    %eax,%edx
  mov    %rax,%r8
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rsi,%rax,1)
  jne    L22
  test   %edx,%edx
  jle    L36
  movslq %edx,%rdx
  lea    -0x1(%rsi,%rdx,1),%rax
  lea    -0x2(%rsi,%rdx,1),%rcx
  lea    -0x1(%r8),%edx
  sub    %rdx,%rcx
L34:
  movsbl (%rax),%edx
  sub    $0x30,%edx
  mov    %edx,(%rdi)
  sub    $0x1,%rax
  add    $0x4,%rdi
  cmp    %rcx,%rax
  jne    L34
L36:
  ret
```

assistant: ```c
void assign(int *n, char *s) {
  int i = 0, j = 0;
  while (s[i] != '\n')
    ++i;
  while (i >= 1)
    n[j++] = s[--i] - '0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assign>:
  endbr64
  cmpb   $0xa,(%rsi)
  je     L3
  mov    $0x1,%eax
  xchg   %ax,%ax
L14:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rsi,%rax,1)
  jne    L14
  movslq %edx,%rcx
  sub    $0x1,%edx
  lea    -0x1(%rsi,%rcx,1),%rax
  lea    -0x2(%rsi,%rcx,1),%rcx
  sub    %rdx,%rcx
L15:
  movsbl (%rax),%edx
  sub    $0x1,%rax
  add    $0x4,%rdi
  sub    $0x30,%edx
  mov    %edx,-0x4(%rdi)
  cmp    %rcx,%rax
  jne    L15
L3:
  ret
```

assistant: ```c
void assign(int *n, char *s) {
  int i = 0, j = 0;
  while (s[i] != '\n')
    ++i;
  while (i >= 1)
    n[j++] = s[--i] - '0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assign>:
  endbr64
  cmpb   $0xa,(%rsi)
  je     L22
  mov    $0x1,%eax
  xchg   %ax,%ax
L6:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rsi,%rax,1)
  jne    L6
  movslq %edx,%rcx
  sub    $0x1,%edx
  lea    -0x1(%rsi,%rcx,1),%rax
  lea    -0x2(%rsi,%rcx,1),%rcx
  sub    %rdx,%rcx
L18:
  movsbl (%rax),%edx
  sub    $0x1,%rax
  add    $0x4,%rdi
  sub    $0x30,%edx
  mov    %edx,-0x4(%rdi)
  cmp    %rax,%rcx
  jne    L18
L22:
  ret
```

assistant: ```c
void assign(int *n, char *s) {
  int i = 0, j = 0;
  while (s[i] != '\n')
    ++i;
  while (i >= 1)
    n[j++] = s[--i] - '0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpya>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
char *memcpya(char *target, const void *source, uintptr_t ct) {
  memcpy(target, source, ct);
  return &(target[ct]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memcpya>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  call   <memcpy@plt>
  lea    (%rbx,%rbp,1),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *memcpya(char *target, const void *source, uintptr_t ct) {
  memcpy(target, source, ct);
  return &(target[ct]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<memcpya>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *memcpya(char *target, const void *source, uintptr_t ct) {
  memcpy(target, source, ct);
  return &(target[ct]);
}
```
user: What is the c source code of the assembly code below:

```asm
<memcpya>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *memcpya(char *target, const void *source, uintptr_t ct) {
  memcpy(target, source, ct);
  return &(target[ct]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bmp_free_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L0
L19:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <bmp_free@plt>
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void bmp_free_list(struct bmp_handle **bmp_list, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    bmp_free(bmp_list[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bmp_free_list>:
  endbr64
  test   %rsi,%rsi
  je     L16
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L1:
  mov    (%r12,%rbx,8),%rdi
  call   <bmp_free@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  ret
```

assistant: ```c
void bmp_free_list(struct bmp_handle **bmp_list, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    bmp_free(bmp_list[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bmp_free_list>:
  endbr64
  test   %rsi,%rsi
  je     L7
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L9:
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <bmp_free@plt>
  cmp    %rbx,%rbp
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L7:
  ret
```

assistant: ```c
void bmp_free_list(struct bmp_handle **bmp_list, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    bmp_free(bmp_list[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bmp_free_list>:
  endbr64
  test   %rsi,%rsi
  je     L12
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L8:
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <bmp_free@plt>
  cmp    %rbx,%rbp
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L12:
  ret
```

assistant: ```c
void bmp_free_list(struct bmp_handle **bmp_list, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    bmp_free(bmp_list[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calcDiagptableFlex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x238,%rsp
  movq   %xmm0,%r13
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%r15
  mov    %r8d,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x228(%rsp)
  xor    %eax,%eax
  cmp    $0x40,%r8d
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  D25(%rip),%xmm0
  movsd  D4(%rip),%xmm1
  movq   %r13,%xmm2
  comisd %xmm2,%xmm1
  jbe    L85
L56:
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  jle    L35
  lea    -0x2(%rax),%ecx
  mov    $0x0,%eax
L27:
  movapd %xmm0,%xmm1
  mulsd  0x0(%rbp,%rax,8),%xmm1
  movsd  %xmm1,0x20(%rsp,%rax,8)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L27
L35:
  test   %ebx,%ebx
  jle    L18
  movslq 0xc(%rsp),%rax
  shl    $0x3,%rax
  mov    %rax,0x10(%rsp)
  mov    %r12,%rbp
  lea    -0x1(%rbx),%eax
  lea    0x8(%r12,%rax,8),%rax
  mov    %rax,0x18(%rsp)
L23:
  mov    %r15,%r12
  mov    D6(%rip),%rax
  mov    %rax,(%r15)
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  jle    L81
  lea    -0x1(%rax),%r14d
  mov    $0x0,%ebx
  lea    0x20(%rsp),%r13
L67:
  movsd  0x0(%rbp),%xmm0
  mulsd  0x0(%r13,%rbx,8),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x8(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L67
L81:
  add    0x10(%rsp),%r15
  add    $0x8,%rbp
  cmp    0x18(%rsp),%rbp
  jne    L23
L18:
  mov    0x228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x238,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L85:
  movq   %r13,%xmm0
  call   <log@plt>
  jmp    L56
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D25
datatype: byte[8]
name: read_data
arguments: data_label: D4
datatype: byte[8]
name: read_data
arguments: data_label: D6
datatype: f64

tool: {"D25": [0xc4,0xff,0xf9,0x9f,0xf6,0x44,0x41,0xc0]}

tool: {"D4": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xd2,0x3c]}

tool: D6: 1

assistant: ```c
void calcDiagptableFlex(double z, int numberOfCategories, double *rptr, double *EIGN, double *diagptable, const int numStates) {
  int i, l;
  double lz, lza[64];
  const int rates = numStates - 1;
  assert(numStates <= 64);
  if (z < 1.0E-15)
    lz = log(1.0E-15);
  else
    lz = log(z);
  for (l = 0; l < rates; l++)
    lza[l] = EIGN[l] * lz;
  for (i = 0; i < numberOfCategories; i++) {
    diagptable[i * numStates] = 1.0;
    for (l = 1; l < numStates; l++)
      diagptable[i * numStates + l] = exp(rptr[i] * lza[l - 1]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calcDiagptableFlex>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  xor    %edi,%edi
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x238,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x228(%rsp)
  xor    %eax,%eax
  cmp    $0x40,%r8d
  setle  %dil
  call   <assert@plt>
  movsd  D13(%rip),%xmm2
  movsd  0x8(%rsp),%xmm1
  movsd  D22(%rip),%xmm0
  comisd %xmm1,%xmm2
  jbe    L6
L33:
  cmp    $0x1,%r13d
  jle    L34
  lea    -0x2(%r13),%ecx
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  nopl   (%rax)
L19:
  movsd  (%r14,%rax,8),%xmm1
  mov    %rax,%rdx
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L19
L34:
  test   %r15d,%r15d
  jle    L62
  movslq %r13d,%r14
  lea    0x0(,%r14,8),%rax
  mov    %r12,%r14
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r15),%eax
  lea    0x8(%r12,%rax,8),%rax
  mov    %rax,0x10(%rsp)
  lea    -0x2(%r13),%eax
  mov    %eax,0x1c(%rsp)
  xchg   %ax,%ax
L69:
  mov    D12(%rip),%rax
  mov    %rax,(%rbx)
  cmp    $0x1,%r13d
  jle    L9
  mov    0x1c(%rsp),%r12d
  xor    %r15d,%r15d
  lea    0x20(%rsp),%rbp
  nopl   (%rax)
L29:
  movsd  (%r14),%xmm0
  mulsd  0x0(%rbp,%r15,8),%xmm0
  call   <exp@plt>
  mov    %r15,%rdx
  movsd  %xmm0,0x8(%rbx,%r15,8)
  add    $0x1,%r15
  cmp    %r12,%rdx
  jne    L29
L9:
  add    0x8(%rsp),%rbx
  add    $0x8,%r14
  cmp    0x10(%rsp),%r14
  jne    L69
L62:
  mov    0x228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x238,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  movapd %xmm1,%xmm0
  call   <log@plt>
  jmp    L33
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_guessed: byte[8]
name: parse_data
arguments: data_label: D22
type_guessed: byte[8]
name: parse_data
arguments: data_label: D12
type_guessed: f64

tool: {"D13": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xd2,0x3c]}

tool: {"D22": [0xc4,0xff,0xf9,0x9f,0xf6,0x44,0x41,0xc0]}

tool: D12: 1

assistant: ```c
void calcDiagptableFlex(double z, int numberOfCategories, double *rptr, double *EIGN, double *diagptable, const int numStates) {
  int i, l;
  double lz, lza[64];
  const int rates = numStates - 1;
  assert(numStates <= 64);
  if (z < 1.0E-15)
    lz = log(1.0E-15);
  else
    lz = log(z);
  for (l = 0; l < rates; l++)
    lza[l] = EIGN[l] * lz;
  for (i = 0; i < numberOfCategories; i++) {
    diagptable[i * numStates] = 1.0;
    for (l = 1; l < numStates; l++)
      diagptable[i * numStates + l] = exp(rptr[i] * lza[l - 1]);
  }
}
```