user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movl   $0xd,0x0(%r13)
  mov    0x4(%r13),%edx
  mov    $0xd,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  lea    D73(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  lea    D58(%rip),%r12
L43:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  movss  %xmm0,-0x4(%rbp,%rbx,4)
  cvtss2sd %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L43
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rbp),%xmm0
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %rax,0x8(%rsp)
  mov    %rax,(%rsp)
  mov    $0x0,%r12d
  lea    D11(%rip),%r14
L7:
  mov    0x0(%r13),%ebx
  movslq %ebx,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %r15,%rbp
  mov    %rax,(%r15)
  test   %ebx,%ebx
  jle    L18
  mov    $0x0,%ebx
L41:
  mov    0x0(%rbp),%rax
  lea    0x1(%r12,%rbx,1),%edx
  mov    %edx,(%rax,%rbx,4)
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x0(%r13)
  jg     L41
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  add    $0x8,%r15
  cmp    $0x5,%r12d
  jne    L7
  mov    0x8(%rsp),%rax
  lea    0x28(%rax),%rbx
L49:
  mov    (%rsp),%r15
  mov    (%r15),%rdi
  call   <free@plt>
  mov    %r15,%rax
  add    $0x8,%rax
  mov    %rax,(%rsp)
  cmp    %rbx,%rax
  jne    L49
  mov    0x8(%rsp),%rbx
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D60(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D35
type_infered: string
name: unpack_data
arguments: data_label: D73
type_infered: string
name: unpack_data
arguments: data_label: D63
type_infered: string
name: unpack_data
arguments: data_label: D58
type_infered: string
name: unpack_data
arguments: data_label: D30
type_infered: string
name: unpack_data
arguments: data_label: D64
type_infered: string
name: unpack_data
arguments: data_label: D11
type_infered: string
name: unpack_data
arguments: data_label: D60
type_infered: string

tool: D35: p = %d, p+1 = %f


tool: D73: %d 

tool: D63: 
malloc one-dimensional array:

tool: D58: %4.2f	

tool: D30: pm = %4.1f


tool: D64: 
malloc two-dimensional array:

tool: D11: %-4d

tool: D60: %ld %f

assistant: ```c
void main() {
  int *p = malloc(sizeof(int));
  float *array = (float *)malloc(5 * sizeof(float)), *pm;
  int **arr;
  *p = 13;
  int i, j;
  printf("p = %d, p+1 = %f\n", *p, *(p + 1));
  printf("%d ", p);
  printf("%d ", p);
  printf("\nmalloc one-dimensional array:\n");
  for (i = 0; i < 5; i++) {
    array[i] = i + 1;
    printf("%4.2f\t", array[i]);
  }
  pm = &array[5 - 3];
  printf("pm = %4.1f\n", *(pm + 1));
  free(array);
  printf("\nmalloc two-dimensional array:\n");
  arr = (int **)malloc(5 * sizeof(int *));
  for (i = 0; i < 5; i++) {
    arr[i] = (int *)malloc((*p) * sizeof(int));
    for (j = 0; j < (*p); j++) {
      arr[i][j] = i + j + 1;
      printf("%-4d", arr[i][j]);
    }
    printf("\n");
  }
  for (i = 0; i < 5; i++) {
    free(arr[i]);
  }
  free(arr);
  printf("%ld %f", arr, arr);
}
```