ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<mywait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L47
  nop
L2:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wait@plt>
  cmp    %eax,-0x14(%rbp)
  jne    L2
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L48
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L48
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L48
L47:
  movl   $0xffffffff,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
int mywait(pid)
int pid;
{
  int status;
  if (pid != -1) {
    while (wait(&status) != pid) {
      ;
    }
    if (status != 0) {
      if ((status & 0xff) == 0) {
        status = status >> 8;
      }
    }
  } else {
    status = -1;
  }
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mywait>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0xffffffff,%edi
  je     L3
  mov    %edi,%ebx
  lea    0x4(%rsp),%rbp
L18:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <wait@plt>
  cmp    %ebx,%eax
  jne    L18
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L36
  test   %al,%al
  jne    L36
  sar    $0x8,%eax
  mov    %eax,0x4(%rsp)
  jmp    L36
L3:
  movl   $0xffffffff,0x4(%rsp)
L36:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mywait(pid)
int pid;
{
  int status;
  if (pid != -1) {
    while (wait(&status) != pid) {
      ;
    }
    if (status != 0) {
      if ((status & 0xff) == 0) {
        status = status >> 8;
      }
    }
  } else {
    status = -1;
  }
  return status;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mywait>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    $0xffffffff,%eax
  cmp    $0xffffffff,%edi
  je     L41
  mov    %edi,%ebx
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <wait@plt>
  cmp    %ebx,%eax
  jne    L20
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L18
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L18:
  mov    %eax,%edx
  sar    $0x8,%edx
  test   %al,%al
  cmove  %edx,%eax
  jmp    L41
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mywait(pid)
int pid;
{
  int status;
  if (pid != -1) {
    while (wait(&status) != pid) {
      ;
    }
    if (status != 0) {
      if ((status & 0xff) == 0) {
        status = status >> 8;
      }
    }
  } else {
    status = -1;
  }
  return status;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mywait>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    $0xffffffff,%eax
  cmp    $0xffffffff,%edi
  je     L24
  mov    %edi,%ebx
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax)
L44:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <wait@plt>
  cmp    %ebx,%eax
  jne    L44
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L7
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  mov    %eax,%edx
  sar    $0x8,%edx
  test   %al,%al
  cmove  %edx,%eax
  jmp    L24
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mywait(pid)
int pid;
{
  int status;
  if (pid != -1) {
    while (wait(&status) != pid) {
      ;
    }
    if (status != 0) {
      if ((status & 0xff) == 0) {
        status = status >> 8;
      }
    }
  } else {
    status = -1;
  }
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<IntArraySelSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L32:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L33
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L22
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swapInt@plt>
L22:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L32
  nop
  nop
  leave
  ret
```

assistant: ```c
void IntArraySelSort(int *a, int dim) {
  int i, j;
  for (i = 0; i < dim - 1; i++) {
    for (j = i + 1; j < dim; j++) {
      if (a[j] < a[i]) {
        swapInt(&a[j], &a[i]);
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<IntArraySelSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L19
  mov    %esi,%r15d
  lea    -0x2(%rsi),%eax
  add    $0x2,%rax
  mov    %rax,0x8(%rsp)
  mov    %rdi,%r14
  mov    $0x1,%r13d
  lea    -0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
  jmp    L32
L33:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L69
L23:
  mov    0x0(%rbp),%eax
  cmp    %eax,(%rbx)
  jge    L33
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <swapInt@plt>
  jmp    L33
L69:
  add    $0x1,%r13
  add    $0x4,%r14
  cmp    0x8(%rsp),%r13
  je     L19
L32:
  cmp    %r13d,%r15d
  jle    L69
  mov    %r14,%rbp
  lea    0x4(%r14),%rbx
  mov    0x1c(%rsp),%eax
  sub    %r13d,%eax
  lea    -0x1(%r13,%rax,1),%rax
  mov    0x10(%rsp),%rdx
  lea    0x8(%rdx,%rax,4),%r12
  jmp    L23
L19:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void IntArraySelSort(int *a, int dim) {
  int i, j;
  for (i = 0; i < dim - 1; i++) {
    for (j = i + 1; j < dim; j++) {
      if (a[j] < a[i]) {
        swapInt(&a[j], &a[i]);
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<IntArraySelSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L50
  lea    -0x2(%rsi),%r14d
  mov    %esi,%r12d
  mov    $0x1,%ebx
  lea    0x2(%r14),%rax
  mov    %rdi,%r14
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
  nop
L68:
  lea    0x4(%r14),%rbp
  cmp    %ebx,%r12d
  jle    L57
  mov    0x1c(%rsp),%eax
  mov    0x10(%rsp),%rdx
  mov    %rbp,%r13
  sub    %ebx,%eax
  lea    -0x1(%rbx,%rax,1),%rax
  lea    0x8(%rdx,%rax,4),%r15
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x4,%r13
  cmp    %r15,%r13
  je     L57
L49:
  mov    (%r14),%eax
  cmp    %eax,0x0(%r13)
  jge    L5
  mov    %r13,%rdi
  mov    %r14,%rsi
  add    $0x4,%r13
  call   <swapInt@plt>
  cmp    %r15,%r13
  jne    L49
L57:
  add    $0x1,%rbx
  mov    %rbp,%r14
  cmp    0x8(%rsp),%rbx
  jne    L68
L50:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void IntArraySelSort(int *a, int dim) {
  int i, j;
  for (i = 0; i < dim - 1; i++) {
    for (j = i + 1; j < dim; j++) {
      if (a[j] < a[i]) {
        swapInt(&a[j], &a[i]);
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IntArraySelSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L54
  lea    -0x2(%rsi),%r14d
  mov    %esi,%r12d
  mov    $0x1,%ebx
  lea    0x2(%r14),%rax
  mov    %rdi,%r14
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
  nop
L4:
  lea    0x4(%r14),%rbp
  cmp    %ebx,%r12d
  jle    L27
  mov    0x1c(%rsp),%eax
  mov    0x10(%rsp),%rdx
  mov    %rbp,%r13
  sub    %ebx,%eax
  lea    -0x1(%rbx,%rax,1),%rax
  lea    0x8(%rdx,%rax,4),%r15
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x4,%r13
  cmp    %r15,%r13
  je     L27
L52:
  mov    (%r14),%eax
  cmp    %eax,0x0(%r13)
  jge    L5
  mov    %r13,%rdi
  mov    %r14,%rsi
  add    $0x4,%r13
  call   <swapInt@plt>
  cmp    %r15,%r13
  jne    L52
L27:
  add    $0x1,%rbx
  mov    %rbp,%r14
  cmp    0x8(%rsp),%rbx
  jne    L4
L54:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void IntArraySelSort(int *a, int dim) {
  int i, j;
  for (i = 0; i < dim - 1; i++) {
    for (j = i + 1; j < dim; j++) {
      if (a[j] < a[i]) {
        swapInt(&a[j], &a[i]);
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rsi
  lea    D38(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    0x10(%rsp),%rcx
  lea    0xd(%rsp),%rdx
  lea    D35(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movsbq 0xd(%rsp),%rdi
  add    %edi,%edi
  movsbl %dil,%edi
  call   <malloc@plt>
  cmpb   $0x0,0xd(%rsp)
  jle    L36
  mov    %rax,%r12
  mov    $0x0,%ebx
  lea    D79(%rip),%r13
L8:
  movsbq %bl,%rax
  lea    (%r12,%rax,2),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  add    $0x1,%ebx
  movzbl 0xd(%rsp),%eax
  cmp    %bl,%al
  jg     L8
  test   %al,%al
  jle    L25
  mov    $0x0,%ebx
  lea    D79(%rip),%r13
L69:
  cmpq   $0x0,0x10(%rsp)
  jle    L7
  lea    0xe(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movswl 0xe(%rsp),%eax
  movsbq %bl,%rdx
  movswl (%r12,%rdx,2),%edx
  sub    %edx,%eax
  cltq
  sub    %rax,0x10(%rsp)
  add    $0x1,%ebx
  cmp    %bl,0xd(%rsp)
  jg     L69
L7:
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D26(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  cmp    %bl,0xd(%rsp)
  mov    $0xffffffff,%eax
  cmove  %eax,%ebx
  movsbl %bl,%edx
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  mov    $0x0,%ebx
  jmp    L7
L36:
  mov    $0x0,%ebx
  jmp    L7
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string
name: retrieve_data
arguments: label: D38
data_type: string
name: retrieve_data
arguments: label: D35
data_type: string
name: retrieve_data
arguments: label: D79
data_type: string
name: retrieve_data
arguments: label: D26
data_type: string
name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D5: r

tool: D38: INP.TXT

tool: D35: %hhd %ld

tool: D79: %hd

tool: D26: w

tool: D0: OUT.TXT

tool: D2: %hhd


assistant: ```c
int main() {
  FILE *f = fopen("INP.TXT", "r");
  char n, i;
  short *a, b;
  long k;
  fscanf(f, "%hhd %ld", &n, &k);
  a = malloc(n * sizeof(short));
  for (i = 0; i < n; i++)
    fscanf(f, "%hd", a + i);
  for (i = 0; i < n && k > 0; i++) {
    fscanf(f, "%hd", &b);
    k -= b - a[i];
  }
  fclose(f);
  f = fopen("OUT.TXT", "w");
  fprintf(f, "%hhd\n", (n - i) ? i : -1);
  fclose(f);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%rsi
  lea    D30(%rip),%rdi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x10(%rsp),%rcx
  lea    0xd(%rsp),%rdx
  mov    %rax,%rdi
  lea    D2(%rip),%rsi
  mov    %rax,%r14
  xor    %eax,%eax
  call   <fscanf@plt>
  movsbq 0xd(%rsp),%rdi
  add    %edi,%edi
  movsbl %dil,%edi
  call   <malloc@plt>
  cmpb   $0x0,0xd(%rsp)
  mov    %rax,%rbx
  jle    L41
  nopw   0x0(%rax,%rax,1)
L27:
  movsbq %r12b,%rax
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  lea    (%rbx,%rax,2),%rdx
  xor    %eax,%eax
  call   <fscanf@plt>
  movzbl 0xd(%rsp),%eax
  cmp    %r12b,%al
  jg     L27
  test   %al,%al
  jle    L41
  mov    0x10(%rsp),%rdx
  xor    %r13d,%r13d
  lea    0xe(%rsp),%r12
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  movsbq %r13b,%rdx
  movswl 0xe(%rsp),%eax
  add    $0x1,%r13d
  movswl (%rbx,%rdx,2),%edx
  sub    %edx,%eax
  mov    0x10(%rsp),%rdx
  cltq
  sub    %rax,%rdx
  mov    %rdx,0x10(%rsp)
  cmp    %r13b,0xd(%rsp)
  jle    L2
L23:
  test   %rdx,%rdx
  jg     L18
L2:
  mov    %r14,%rdi
  call   <fclose@plt>
  lea    D47(%rip),%rsi
  lea    D58(%rip),%rdi
  call   <fopen@plt>
  cmp    %r13b,0xd(%rsp)
  lea    D33(%rip),%rsi
  mov    %rax,%rbp
  mov    $0xffffffff,%eax
  cmove  %eax,%r13d
  mov    %rbp,%rdi
  movsbl %r13b,%edx
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  xor    %r13d,%r13d
  jmp    L2
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D30
type: string
name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D47
type: string
name: retrieve_data
arguments: data_label: D58
type: string
name: retrieve_data
arguments: data_label: D33
type: string

tool: D5: r

tool: D30: INP.TXT

tool: D16: %hd

tool: D2: %hhd %ld

tool: D47: w

tool: D58: OUT.TXT

tool: D33: %hhd


assistant: ```c
int main() {
  FILE *f = fopen("INP.TXT", "r");
  char n, i;
  short *a, b;
  long k;
  fscanf(f, "%hhd %ld", &n, &k);
  a = malloc(n * sizeof(short));
  for (i = 0; i < n; i++)
    fscanf(f, "%hd", a + i);
  for (i = 0; i < n && k > 0; i++) {
    fscanf(f, "%hd", &b);
    k -= b - a[i];
  }
  fclose(f);
  f = fopen("OUT.TXT", "w");
  fprintf(f, "%hhd\n", (n - i) ? i : -1);
  fclose(f);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D24(%rip),%rsi
  lea    D61(%rip),%rdi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D67(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x10(%rsp),%rcx
  lea    0xd(%rsp),%rdx
  mov    %rax,%rdi
  lea    D36(%rip),%rsi
  mov    %rax,%r14
  xor    %eax,%eax
  call   <fscanf@plt>
  movsbq 0xd(%rsp),%rdi
  add    %edi,%edi
  movsbl %dil,%edi
  call   <malloc@plt>
  cmpb   $0x0,0xd(%rsp)
  mov    %rax,%rbx
  jle    L63
  nopw   0x0(%rax,%rax,1)
L56:
  movsbq %r12b,%rax
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  lea    (%rbx,%rax,2),%rdx
  xor    %eax,%eax
  call   <fscanf@plt>
  movzbl 0xd(%rsp),%eax
  cmp    %r12b,%al
  jg     L56
  test   %al,%al
  jle    L63
  mov    0x10(%rsp),%rdx
  xor    %r13d,%r13d
  lea    0xe(%rsp),%r12
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  movsbq %r13b,%rdx
  movswl 0xe(%rsp),%eax
  add    $0x1,%r13d
  movswl (%rbx,%rdx,2),%edx
  sub    %edx,%eax
  mov    0x10(%rsp),%rdx
  cltq
  sub    %rax,%rdx
  mov    %rdx,0x10(%rsp)
  cmp    %r13b,0xd(%rsp)
  jle    L58
L76:
  test   %rdx,%rdx
  jg     L38
L58:
  mov    %r14,%rdi
  call   <fclose@plt>
  lea    D59(%rip),%rsi
  lea    D38(%rip),%rdi
  call   <fopen@plt>
  cmp    %r13b,0xd(%rsp)
  lea    D64(%rip),%rsi
  mov    %rax,%rbp
  mov    $0xffffffff,%eax
  cmove  %eax,%r13d
  mov    %rbp,%rdi
  movsbl %r13b,%edx
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  xor    %r13d,%r13d
  jmp    L58
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D24
type: string
name: parse_data
arguments: tag: D61
type: string
name: parse_data
arguments: tag: D67
type: string
name: parse_data
arguments: tag: D36
type: string
name: parse_data
arguments: tag: D59
type: string
name: parse_data
arguments: tag: D38
type: string
name: parse_data
arguments: tag: D64
type: string

tool: D24: r

tool: D61: INP.TXT

tool: D67: %hd

tool: D36: %hhd %ld

tool: D59: w

tool: D38: OUT.TXT

tool: D64: %hhd


assistant: ```c
int main() {
  FILE *f = fopen("INP.TXT", "r");
  char n, i;
  short *a, b;
  long k;
  fscanf(f, "%hhd %ld", &n, &k);
  a = malloc(n * sizeof(short));
  for (i = 0; i < n; i++)
    fscanf(f, "%hd", a + i);
  for (i = 0; i < n && k > 0; i++) {
    fscanf(f, "%hd", &b);
    k -= b - a[i];
  }
  fclose(f);
  f = fopen("OUT.TXT", "w");
  fprintf(f, "%hhd\n", (n - i) ? i : -1);
  fclose(f);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode_leb128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
L11:
  mov    -0x24(%rbp),%eax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  addl   $0x1,-0x24(%rbp)
  movzbl -0x11(%rbp),%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x7,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
  movzbl -0x11(%rbp),%eax
  test   %al,%al
  jns    L36
  jmp    L11
L36:
  nop
  movl   $0x20,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L6
  movzbl -0x11(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L6
  mov    -0xc(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
long decode_leb128(unsigned int offset, int *used) {
  unsigned char byte;
  int result, shift;
  int num_bits;
  int count;
  result = 0;
  shift = 0;
  count = 0;
  *used = 0;
  while (1) {
    byte = *(char *)(offset);
    offset += 1;
    result |= (byte & 0x7f) << shift;
    *used += 1;
    shift += 7;
    count++;
    if (!(byte & 0x80))
      break;
  }
  num_bits = 8 * sizeof(result);
  if ((shift < num_bits) && (byte & 0x40))
    result |= (-1 << shift);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<decode_leb128>:
  endbr64
  movl   $0x0,(%rsi)
  mov    $0x0,%ecx
  mov    $0x0,%eax
L23:
  movzbl (%edi),%r8d
  add    $0x1,%edi
  mov    %r8d,%edx
  and    $0x7f,%edx
  shl    %cl,%edx
  or     %edx,%eax
  addl   $0x1,(%rsi)
  add    $0x7,%ecx
  test   %r8b,%r8b
  js     L23
  cmp    $0x1f,%ecx
  jg     L22
  test   $0x40,%r8b
  je     L22
  mov    $0xffffffff,%edx
  shl    %cl,%edx
  or     %edx,%eax
L22:
  cltq
  ret
```

assistant: ```c
long decode_leb128(unsigned int offset, int *used) {
  unsigned char byte;
  int result, shift;
  int num_bits;
  int count;
  result = 0;
  shift = 0;
  count = 0;
  *used = 0;
  while (1) {
    byte = *(char *)(offset);
    offset += 1;
    result |= (byte & 0x7f) << shift;
    *used += 1;
    shift += 7;
    count++;
    if (!(byte & 0x80))
      break;
  }
  num_bits = 8 * sizeof(result);
  if ((shift < num_bits) && (byte & 0x40))
    result |= (-1 << shift);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<decode_leb128>:
  endbr64
  movl   $0x0,(%rsi)
  mov    $0x1,%edx
  xor    %ecx,%ecx
  xor    %eax,%eax
  lea    -0x1(%rdi),%r9d
  nopw   0x0(%rax,%rax,1)
L27:
  movzbl (%r9d,%edx,1),%r8d
  mov    %edx,(%rsi)
  add    $0x1,%edx
  mov    %r8d,%edi
  and    $0x7f,%edi
  shl    %cl,%edi
  add    $0x7,%ecx
  or     %edi,%eax
  test   %r8b,%r8b
  js     L27
  cmp    $0x1f,%ecx
  jg     L3
  and    $0x40,%r8d
  je     L3
  mov    $0xffffffff,%edx
  shl    %cl,%edx
  or     %edx,%eax
L3:
  cltq
  ret
```

assistant: ```c
long decode_leb128(unsigned int offset, int *used) {
  unsigned char byte;
  int result, shift;
  int num_bits;
  int count;
  result = 0;
  shift = 0;
  count = 0;
  *used = 0;
  while (1) {
    byte = *(char *)(offset);
    offset += 1;
    result |= (byte & 0x7f) << shift;
    *used += 1;
    shift += 7;
    count++;
    if (!(byte & 0x80))
      break;
  }
  num_bits = 8 * sizeof(result);
  if ((shift < num_bits) && (byte & 0x40))
    result |= (-1 << shift);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decode_leb128>:
  endbr64
  movl   $0x0,(%rsi)
  mov    $0x1,%edx
  xor    %ecx,%ecx
  xor    %eax,%eax
  lea    -0x1(%rdi),%r9d
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl (%r9d,%edx,1),%r8d
  mov    %edx,(%rsi)
  add    $0x1,%edx
  mov    %r8d,%edi
  and    $0x7f,%edi
  shl    %cl,%edi
  add    $0x7,%ecx
  or     %edi,%eax
  test   %r8b,%r8b
  js     L9
  cmp    $0x1f,%ecx
  jg     L14
  and    $0x40,%r8d
  je     L14
  mov    $0xffffffff,%edx
  shl    %cl,%edx
  or     %edx,%eax
L14:
  cltq
  ret
```

assistant: ```c
long decode_leb128(unsigned int offset, int *used) {
  unsigned char byte;
  int result, shift;
  int num_bits;
  int count;
  result = 0;
  shift = 0;
  count = 0;
  *used = 0;
  while (1) {
    byte = *(char *)(offset);
    offset += 1;
    result |= (byte & 0x7f) << shift;
    *used += 1;
    shift += 7;
    count++;
    if (!(byte & 0x80))
      break;
  }
  num_bits = 8 * sizeof(result);
  if ((shift < num_bits) && (byte & 0x40))
    result |= (-1 << shift);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ht_str_hash_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x2f693b52,%edi
  call   <UINT32_C@plt>
  xor    $0x1505,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  jmp    L17
L16:
  mov    -0x10(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  xor    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t ht_str_hash_function(const void *key, size_t len) {
  const unsigned char *str = key;
  size_t hash = 5381 ^ (UINT32_C(0x2f693b52));
  size_t c;
  (void)len;
  while ((c = (size_t)*str++))
    hash = ((hash << 5) + hash) ^ c;
  return hash;
}
```