ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<checkISBN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L48:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L45
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %eax,-0x10(%rbp)
  jmp    L36
L45:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,-0x10(%rbp)
L36:
  addl   $0x1,-0x8(%rbp)
L24:
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0xf,-0xc(%rbp)
  jle    L48
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    $0xa,%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int checkISBN(char *code) {
  int r, sum = 0;
  int i, k = 0;
  for (i = 0; i < 16; i++) {
    if (code[i] != 0) {
      if (k % 2 == 0) {
        sum += (code[i] - 48) * 1;
      } else {
        sum += (code[i] - 48) * 3;
      }
      k++;
    }
  }
  r = sum % 10;
  return 10 - r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checkISBN>:
  endbr64
  lea    0x10(%rdi),%rsi
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L16
L24:
  movsbl %al,%eax
  lea    -0x90(%rax,%rax,2),%eax
  add    %eax,%ecx
L11:
  add    $0x1,%edx
L31:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L41
L16:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
  test   $0x1,%dl
  jne    L24
  movsbl %al,%eax
  lea    -0x30(%rcx,%rax,1),%ecx
  jmp    L11
L41:
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %ecx,%eax
  lea    0xa(%rax),%eax
  ret
```

assistant: ```c
int checkISBN(char *code) {
  int r, sum = 0;
  int i, k = 0;
  for (i = 0; i < 16; i++) {
    if (code[i] != 0) {
      if (k % 2 == 0) {
        sum += (code[i] - 48) * 1;
      } else {
        sum += (code[i] - 48) * 3;
      }
      k++;
    }
  }
  r = sum % 10;
  return 10 - r;
}
```
user: What is the c source code of the assembly code below?

```asm
<checkISBN>:
  endbr64
  lea    0x10(%rdi),%rsi
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L21
  xchg   %ax,%ax
L18:
  lea    -0x30(%rcx,%rax,1),%ecx
L22:
  add    $0x1,%edx
L23:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L47
L21:
  movsbl (%rdi),%eax
  test   %al,%al
  je     L23
  test   $0x1,%dl
  je     L18
  lea    -0x90(%rax,%rax,2),%eax
  add    %eax,%ecx
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L47:
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %ecx,%eax
  add    $0xa,%eax
  ret
```

assistant: ```c
int checkISBN(char *code) {
  int r, sum = 0;
  int i, k = 0;
  for (i = 0; i < 16; i++) {
    if (code[i] != 0) {
      if (k % 2 == 0) {
        sum += (code[i] - 48) * 1;
      } else {
        sum += (code[i] - 48) * 3;
      }
      k++;
    }
  }
  r = sum % 10;
  return 10 - r;
}
```
user: What is the c source code of the assembly code below?

```asm
<point_in_polygon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x54(%rbp),%edx
  mov    -0x50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_maxim@plt>
  fstpt  -0x30(%rbp)
  mov    -0x48(%rbp),%rax
  fldt   0x10(%rax)
  fstpt  -0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L31
L26:
  mov    -0x34(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  lea    -0x30(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <segments_intersect@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L31:
  mov    -0x54(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x34(%rbp)
  jl     L26
  mov    -0x38(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L42
  mov    $0x0,%eax
  jmp    L2
L42:
  mov    $0x1,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
int point_in_polygon(long double *p, long double **poly, int Np) {
  int inter, i;
  long double M[] = {_maxim(poly, Np), p[1]};
  for (i = 0, inter = 0; i < (Np - 1); i++)
    inter += segments_intersect(p, M, poly[i], poly[i + 1]);
  if (inter % 2 == 0)
    return 0;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<point_in_polygon>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edx,%esi
  mov    %r13,%rdi
  call   <_maxim@plt>
  fstpt  (%rsp)
  fldt   0x10(%r12)
  fstpt  0x10(%rsp)
  cmp    $0x1,%ebp
  jle    L27
  mov    %r13,%rbx
  lea    -0x2(%rbp),%eax
  lea    0x8(%r13,%rax,8),%r14
  mov    $0x0,%ebp
  mov    %rsp,%r13
L32:
  mov    0x8(%rbx),%rcx
  mov    (%rbx),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <segments_intersect@plt>
  add    %eax,%ebp
  add    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L32
L7:
  mov    %ebp,%eax
  and    $0x1,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  mov    $0x0,%ebp
  jmp    L7
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int point_in_polygon(long double *p, long double **poly, int Np) {
  int inter, i;
  long double M[] = {_maxim(poly, Np), p[1]};
  for (i = 0, inter = 0; i < (Np - 1); i++)
    inter += segments_intersect(p, M, poly[i], poly[i + 1]);
  if (inter % 2 == 0)
    return 0;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<point_in_polygon>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    %rbx,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <_maxim@plt>
  fstpt  (%rsp)
  fldt   0x10(%r12)
  fstpt  0x10(%rsp)
  cmp    $0x1,%ebp
  jle    L36
  lea    -0x2(%rbp),%eax
  mov    %rsp,%r13
  xor    %ebp,%ebp
  lea    0x8(%rbx,%rax,8),%r14
L35:
  mov    0x8(%rbx),%rcx
  mov    (%rbx),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <segments_intersect@plt>
  add    %eax,%ebp
  cmp    %rbx,%r14
  jne    L35
  mov    %ebp,%eax
  and    $0x1,%eax
L37:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L36:
  xor    %eax,%eax
  jmp    L37
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int point_in_polygon(long double *p, long double **poly, int Np) {
  int inter, i;
  long double M[] = {_maxim(poly, Np), p[1]};
  for (i = 0, inter = 0; i < (Np - 1); i++)
    inter += segments_intersect(p, M, poly[i], poly[i + 1]);
  if (inter % 2 == 0)
    return 0;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<point_in_polygon>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    %rbx,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <_maxim@plt>
  fstpt  (%rsp)
  fldt   0x10(%r12)
  fstpt  0x10(%rsp)
  cmp    $0x1,%ebp
  jle    L34
  lea    -0x2(%rbp),%eax
  mov    %rsp,%r13
  xor    %ebp,%ebp
  lea    0x8(%rbx,%rax,8),%r14
L30:
  mov    0x8(%rbx),%rcx
  mov    (%rbx),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <segments_intersect@plt>
  add    %eax,%ebp
  cmp    %rbx,%r14
  jne    L30
  mov    %ebp,%eax
  and    $0x1,%eax
L32:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L34:
  xor    %eax,%eax
  jmp    L32
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int point_in_polygon(long double *p, long double **poly, int Np) {
  int inter, i;
  long double M[] = {_maxim(poly, Np), p[1]};
  for (i = 0, inter = 0; i < (Np - 1); i++)
    inter += segments_intersect(p, M, poly[i], poly[i + 1]);
  if (inter % 2 == 0)
    return 0;
  else
    return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<H5Aclose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__coverity_free__@plt>
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__coverity_mark_as_afm_freed__@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: H5Aclose

assistant: ```c
void H5Aclose(void *id) {
  __coverity_free__(id);
  __coverity_mark_as_afm_freed__(id, "H5Aclose");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<H5Aclose>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <__coverity_free__@plt>
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <__coverity_mark_as_afm_freed__@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: H5Aclose

assistant: ```c
void H5Aclose(void *id) {
  __coverity_free__(id);
  __coverity_mark_as_afm_freed__(id, "H5Aclose");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<H5Aclose>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <__coverity_free__@plt>
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  pop    %rbp
  jmp    1070 <__coverity_mark_as_afm_freed__@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string

tool: D1: H5Aclose

assistant: ```c
void H5Aclose(void *id) {
  __coverity_free__(id);
  __coverity_mark_as_afm_freed__(id, "H5Aclose");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<H5Aclose>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <__coverity_free__@plt>
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  pop    %rbp
  jmp    1070 <__coverity_mark_as_afm_freed__@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: H5Aclose

assistant: ```c
void H5Aclose(void *id) {
  __coverity_free__(id);
  __coverity_mark_as_afm_freed__(id, "H5Aclose");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L4
L19:
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,-0x14(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  je     L9
  cmpl   $0x4,-0x18(%rbp)
  jne    L11
L9:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x1c(%rbp)
L11:
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L19
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string
name: disassemble_data
arguments: label: D14
type_guessed: string
name: disassemble_data
arguments: label: D20
type_guessed: string

tool: D0: enter the 4 digit number: 

tool: D14: %ld

tool: D20: The sum is %d


assistant: ```c
int main() {
  long num;
  int sum, n;
  int i;
  printf("enter the 4 digit number: ");
  scanf("%ld", &num);
  i = 1;
  sum = 0;
  while (num != 0) {
    n = num % 10;
    if (i == 1 || i == 4)
      sum = sum + n;
    num = num / 10;
    i++;
  }
  printf("The sum is %d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  test   %rcx,%rcx
  je     L67
  mov    $0x1,%esi
  mov    $0x0,%r8d
  movabs $0x6666666666666667,%rdi
  jmp    L10
L40:
  mov    %rcx,%rax
  imul   %rdi
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  add    %edx,%r8d
L51:
  mov    %rcx,%rax
  imul   %rdi
  sar    $0x2,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  mov    %rdx,%rcx
  add    $0x1,%esi
  test   %rdx,%rdx
  je     L73
L10:
  cmp    $0x1,%esi
  je     L40
  cmp    $0x4,%esi
  jne    L51
  jmp    L40
L73:
  movq   $0x0,(%rsp)
L28:
  mov    %r8d,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L67:
  mov    $0x0,%r8d
  jmp    L28
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type_infered: string
name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D8
type_infered: string

tool: D19: enter the 4 digit number: 

tool: D12: %ld

tool: D8: The sum is %d


assistant: ```c
int main() {
  long num;
  int sum, n;
  int i;
  printf("enter the 4 digit number: ");
  scanf("%ld", &num);
  i = 1;
  sum = 0;
  while (num != 0) {
    n = num % 10;
    if (i == 1 || i == 4)
      sum = sum + n;
    num = num / 10;
    i++;
  }
  printf("The sum is %d\n", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  test   %rcx,%rcx
  je     L28
  mov    $0x1,%esi
  xor    %r8d,%r8d
  movabs $0x6666666666666667,%rdi
  jmp    L9
  nopl   0x0(%rax)
L32:
  mov    %rcx,%rax
  add    $0x1,%esi
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  je     L26
L9:
  cmp    $0x1,%esi
  je     L55
  cmp    $0x4,%esi
  jne    L32
L55:
  mov    %rcx,%rax
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rcx,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  add    %edx,%r8d
  jmp    L32
  nopl   0x0(%rax)
L26:
  movq   $0x0,(%rsp)
L75:
  xor    %eax,%eax
  mov    %r8d,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L28:
  xor    %r8d,%r8d
  jmp    L75
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string
name: unpack_data
arguments: data_label: D11
type: string
name: unpack_data
arguments: data_label: D19
type: string

tool: D9: enter the 4 digit number: 

tool: D11: %ld

tool: D19: The sum is %d


assistant: ```c
int main() {
  long num;
  int sum, n;
  int i;
  printf("enter the 4 digit number: ");
  scanf("%ld", &num);
  i = 1;
  sum = 0;
  while (num != 0) {
    n = num % 10;
    if (i == 1 || i == 4)
      sum = sum + n;
    num = num / 10;
    i++;
  }
  printf("The sum is %d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  test   %rcx,%rcx
  je     L8
  mov    $0x1,%esi
  xor    %r8d,%r8d
  movabs $0x6666666666666667,%rdi
  jmp    L65
  nopl   0x0(%rax)
L13:
  mov    %rcx,%rax
  add    $0x1,%esi
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  je     L32
L65:
  cmp    $0x4,%esi
  je     L68
  cmp    $0x1,%esi
  jne    L13
L68:
  mov    %rcx,%rax
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rcx,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  add    %edx,%r8d
  jmp    L13
  nopl   0x0(%rax)
L32:
  movq   $0x0,(%rsp)
L64:
  xor    %eax,%eax
  mov    %r8d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  xor    %r8d,%r8d
  jmp    L64
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D15
datatype: string
name: read_data
arguments: tag: D4
datatype: string

tool: D18: enter the 4 digit number: 

tool: D15: %ld

tool: D4: The sum is %d


assistant: ```c
int main() {
  long num;
  int sum, n;
  int i;
  printf("enter the 4 digit number: ");
  scanf("%ld", &num);
  i = 1;
  sum = 0;
  while (num != 0) {
    n = num % 10;
    if (i == 1 || i == 4)
      sum = sum + n;
    num = num / 10;
    i++;
  }
  printf("The sum is %d\n", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pXright>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L13
  cmpl   $0xc7,-0x14(%rbp)
  jg     L25
  mov    $0xc8,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    $0xc8,%eax
  sub    -0x14(%rbp),%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L23
L25:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  lea    0xc8(%rax),%edx
  mov    -0x14(%rbp),%eax
  sub    $0xc8,%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0xc8,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L23
L13:
  mov    -0x14(%rbp),%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int pXright(int x, int z) {
  int r;
  if (z) {
    if (x < 200) {
      return r = ((200 - z) * (200 - x)) / 200;
    } else {
      return r = 200 + ((200 + (z + z / 2)) * (x - 200)) / 200;
    }
  } else {
    return x;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pXright>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L14
  cmp    $0xc7,%edi
  jg     L16
  mov    $0xc8,%eax
  mov    %eax,%edx
  sub    %esi,%edx
  sub    %edi,%eax
  imul   %eax,%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  ret
L16:
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  lea    0xc8(%rsi,%rax,1),%edx
  sub    $0xc8,%edi
  imul   %edi,%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  add    $0xc8,%eax
L14:
  ret
```

assistant: ```c
int pXright(int x, int z) {
  int r;
  if (z) {
    if (x < 200) {
      return r = ((200 - z) * (200 - x)) / 200;
    } else {
      return r = 200 + ((200 + (z + z / 2)) * (x - 200)) / 200;
    }
  } else {
    return x;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pXright>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L8
  cmp    $0xc7,%edi
  jg     L9
  mov    $0xc8,%ecx
  mov    %ecx,%edx
  sub    %edi,%ecx
  sub    %esi,%edx
  imul   %ecx,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L9:
  mov    %esi,%edx
  sub    $0xc8,%eax
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  lea    0xc8(%rsi,%rdx,1),%edx
  imul   %eax,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  add    $0xc8,%eax
L8:
  ret
```

assistant: ```c
int pXright(int x, int z) {
  int r;
  if (z) {
    if (x < 200) {
      return r = ((200 - z) * (200 - x)) / 200;
    } else {
      return r = 200 + ((200 + (z + z / 2)) * (x - 200)) / 200;
    }
  } else {
    return x;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pXright>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L4
  cmp    $0xc7,%edi
  jg     L12
  mov    $0xc8,%ecx
  mov    %ecx,%edx
  sub    %edi,%ecx
  sub    %esi,%edx
  imul   %ecx,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L12:
  mov    %esi,%edx
  sub    $0xc8,%eax
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  lea    0xc8(%rsi,%rdx,1),%edx
  imul   %eax,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  add    $0xc8,%eax
L4:
  ret
```

assistant: ```c
int pXright(int x, int z) {
  int r;
  if (z) {
    if (x < 200) {
      return r = ((200 - z) * (200 - x)) / 200;
    } else {
      return r = 200 + ((200 + (z + z / 2)) * (x - 200)) / 200;
    }
  } else {
    return x;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<trackDbCloneTdbListToSharedMem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cloneTdbListToSharedMem@plt>
  nop
  leave
  ret
```

assistant: ```c
void trackDbCloneTdbListToSharedMem(char *db, struct trackDb *list, unsigned long size) {
  ;
  cloneTdbListToSharedMem(db, list, size, db);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trackDbCloneTdbListToSharedMem>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  call   <cloneTdbListToSharedMem@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void trackDbCloneTdbListToSharedMem(char *db, struct trackDb *list, unsigned long size) {
  ;
  cloneTdbListToSharedMem(db, list, size, db);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trackDbCloneTdbListToSharedMem>:
  endbr64
  mov    %rdi,%rcx
  jmp    1050 <cloneTdbListToSharedMem@plt>
```

assistant: ```c
void trackDbCloneTdbListToSharedMem(char *db, struct trackDb *list, unsigned long size) {
  ;
  cloneTdbListToSharedMem(db, list, size, db);
}
```