user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    $0x17,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movsd  D33(%rip),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm0,0x18(%rsp)
  mov    0xc(%rsp),%ebx
  cmp    $0x1,%ebx
  jle    L122
  lea    0x18(%rsp),%rdx
  lea    0x1(%rbx),%esi
  mov    $0x3,%ecx
  mov    $0x2,%eax
L124:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  mulsd  (%rdx),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  add    $0x1,%eax
  add    $0x2,%ecx
  add    $0x8,%rdx
  cmp    %esi,%eax
  jne    L124
L122:
  movsd  0x10(%rsp),%xmm0
  xorpd  D37(%rip),%xmm0
  mulsd  D44(%rip),%xmm0
  movsd  %xmm0,0x10(%rsp)
  lea    -0x2(%rbx),%r9d
  test   %r9d,%r9d
  jle    L46
  mov    $0x5,%r10d
  mov    $0x2,%r8d
  mov    $0x1,%r11d
L154:
  test   %r9d,%r9d
  jle    L7
  lea    0x18(%rsp),%rdx
  lea    (%r8,%r9,1),%edi
  mov    %r10d,%ecx
  mov    %r8d,%eax
L95:
  mov    %eax,%esi
  neg    %esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  (%rdx),%xmm1
  add    $0x1,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  mulsd  -0x8(%rdx),%xmm0
  divsd  %xmm2,%xmm0
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x2,%ecx
  add    $0x8,%rdx
  cmp    %edi,%eax
  jne    L95
L7:
  add    $0x2,%r8d
  mov    %r11d,%eax
  sub    %r8d,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rsp)
  sub    $0x2,%r9d
  add    $0x4,%r10d
  test   %r9d,%r9d
  jg     L154
L46:
  mov    %ebx,%edx
  shr    $0x1f,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L9
L142:
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  jne    L169
  test   %eax,%eax
  je     L159
  mov    $0x0,%ebx
  lea    D75(%rip),%rbp
  lea    D59(%rip),%r12
  js     L169
L113:
  movsd  0x10(%rsp,%rbx,8),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  je     L169
  mov    %r12,%rdi
  call   <puts@plt>
  add    $0x2,%rbx
  cmp    %ebx,0xc(%rsp)
  jge    L113
  jmp    L169
L9:
  test   %ebx,%ebx
  jle    L142
  mov    $0x1,%ebx
  lea    D12(%rip),%rbp
L4:
  movsd  0x10(%rsp,%rbx,8),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x2,%rbx
  cmp    %ebx,0xc(%rsp)
  jge    L4
  jmp    L142
L159:
  lea    D60(%rip),%rdi
  call   <puts@plt>
L169:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D33
type_infered: f64
name: retrieve_data
arguments: label: D37
type_infered: f32[4]
name: retrieve_data
arguments: label: D44
type_infered: f32[2]
name: retrieve_data
arguments: label: D75
type_infered: string
name: retrieve_data
arguments: label: D59
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string
name: retrieve_data
arguments: label: D60
type_infered: string

tool: D19: %d

tool: D33: 1

tool: {"D37": [0.0,-0.0,0.0,0.0]}

tool: {"D44": [0.0,1.75]}

tool: D75: %.2lf


tool: D59: 0.00

tool: D12: 0.00
%.2lf


tool: D60: 1.00

assistant: ```c
int main() {
  int order, i, ordern, j;
  double x[25] = {0.0};
  scanf("%d", &order);
  x[0] = 1.0;
  x[1] = 1.0;
  for (i = 2; i <= order; i++) {
    x[i] = (2 * i - 1) * x[i - 1] / i;
  }
  for (ordern = 2; 1 == 1; ordern += 2) {
    x[0] = x[0] * (-(ordern - 1)) / (ordern);
    if ((order - ordern) <= 0)
      break;
    for (i = 1, j = ordern; i <= (order - ordern); i++, j++) {
      x[i] = x[i] * (-(j)) / (j + 1) + (2 * (j) + 1) * x[i - 1] / (j + 1);
    }
  }
  if (order % 2 == 1) {
    for (i = 1; i <= order; i += 2) {
      printf("0.00\n%.2lf\n", x[i]);
    }
  }
  if (order % 2 == 0) {
    if (order == 0) {
      printf("1.00\n");
    } else {
      for (i = 0; i <= order; i += 2) {
        printf("%.2lf\n", x[i]);
        if (i == order)
          break;
        printf("0.00\n");
      }
    }
  }
}
```