ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<computec>:
  endbr64
  push   %r15
  movq   %xmm1,%r15
  push   %r14
  movq   %xmm0,%r14
  movapd %xmm2,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  test   %sil,%sil
  jne    L6
  call   <cos@plt>
  movsd  %xmm0,(%rsp)
L3:
  test   %bl,%bl
  je     L0
  movq   %r14,%xmm0
  call   <cosh@plt>
  movsd  %xmm0,0x8(%rsp)
  movq   %r15,%xmm0
  call   <cosh@plt>
  movsd  %xmm0,0x10(%rsp)
  movq   %r14,%xmm0
  call   <sinh@plt>
  movsd  %xmm0,0x18(%rsp)
  movq   %r15,%xmm0
  call   <sinh@plt>
  movsd  0x8(%rsp),%xmm3
  mulsd  0x10(%rsp),%xmm3
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm1
  addsd  %xmm3,%xmm0
L4:
  divsd  %xmm1,%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  jmp    10d0 <acosh@plt>
  nopl   (%rax)
L0:
  lea    0x28(%rsp),%rbp
  lea    0x20(%rsp),%r12
  movq   %r15,%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sincos@plt>
  mov    0x20(%rsp),%rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x28(%rsp),%xmm1
  movq   %r14,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sincos@plt>
  movq   %rbx,%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  0x20(%rsp),%xmm0
  mulsd  0x28(%rsp),%xmm1
  addsd  (%rsp),%xmm0
  jmp    L4
  nopl   0x0(%rax)
L6:
  call   <cosh@plt>
  movsd  %xmm0,(%rsp)
  jmp    L3
```

assistant: ```c
double computec(double al, double be, char imag1, double ga, char imag2) {
  double t = imag2 ? cosh(ga) : cos(ga);
  if (imag1)
    return acosh((t + cosh(al) * cosh(be)) / (sinh(al) * sinh(be)));
  else
    return acosh((t + cos(al) * cos(be)) / (sin(al) * sin(be)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mymemcpy2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L50
  cmpq   $0x0,-0x20(%rbp)
  jne    L54
L50:
  mov    $0x0,%eax
  jmp    L24
L54:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L2
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  jae    L2
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L21
L72:
  mov    -0x8(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L21:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L72
  jmp    L49
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L95:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L3:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L95
L49:
  mov    -0x18(%rbp),%rax
L24:
  pop    %rbp
  ret
```

assistant: ```c
void *mymemcpy2(void *dest, const void *src, size_t count) {
  char *strdest = NULL;
  char *strsrc = NULL;
  if ((dest == NULL) || (src == NULL)) {
    return NULL;
  }
  if ((src < dest) && (((char *)src + count) > (char *)dest)) {
    strdest = (char *)dest + count - 1;
    strsrc = (char *)src + count - 1;
    while (count--) {
      *strdest-- = *strsrc--;
    }
  } else {
    strdest = (char *)dest;
    strsrc = (char *)src;
    while (count-- > 0) {
      *strdest++ = *strsrc++;
    }
  }
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mymemcpy2>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L29
  test   %rsi,%rsi
  je     L29
  cmp    %rsi,%rdi
  ja     L17
L15:
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L45
L1:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L1
  ret
L45:
  ret
L17:
  lea    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rdi
  jae    L15
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L63
L13:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L13
  ret
L29:
  mov    $0x0,%eax
L63:
  ret
```

assistant: ```c
void *mymemcpy2(void *dest, const void *src, size_t count) {
  char *strdest = NULL;
  char *strsrc = NULL;
  if ((dest == NULL) || (src == NULL)) {
    return NULL;
  }
  if ((src < dest) && (((char *)src + count) > (char *)dest)) {
    strdest = (char *)dest + count - 1;
    strsrc = (char *)src + count - 1;
    while (count--) {
      *strdest-- = *strsrc--;
    }
  } else {
    strdest = (char *)dest;
    strsrc = (char *)src;
    while (count-- > 0) {
      *strdest++ = *strsrc++;
    }
  }
  return dest;
}
```
user: What is the c source code of the assembly code below:

```asm
<mymemcpy2>:
  endbr64
  test   %rdi,%rdi
  je     L17
  test   %rsi,%rsi
  je     L17
  lea    -0x1(%rdx),%rax
  cmp    %rsi,%rdi
  jbe    L74
  lea    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rdi
  jae    L74
  test   %rdx,%rdx
  je     L38
  sub    $0x1,%rsi
  lea    -0x1(%rdi),%rcx
  nopl   (%rax)
L33:
  movzbl 0x1(%rsi,%rax,1),%edx
  mov    %dl,0x1(%rcx,%rax,1)
  sub    $0x1,%rax
  jae    L33
L38:
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  xor    %ecx,%ecx
  test   %rdx,%rdx
  je     L38
  nop
L50:
  movzbl (%rsi,%rcx,1),%eax
  mov    %al,(%rdi,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L50
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *mymemcpy2(void *dest, const void *src, size_t count) {
  char *strdest = NULL;
  char *strsrc = NULL;
  if ((dest == NULL) || (src == NULL)) {
    return NULL;
  }
  if ((src < dest) && (((char *)src + count) > (char *)dest)) {
    strdest = (char *)dest + count - 1;
    strsrc = (char *)src + count - 1;
    while (count--) {
      *strdest-- = *strsrc--;
    }
  } else {
    strdest = (char *)dest;
    strsrc = (char *)src;
    while (count-- > 0) {
      *strdest++ = *strsrc++;
    }
  }
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mymemcpy2>:
  endbr64
  mov    %rdi,%rax
  mov    %rdx,%r9
  test   %rdi,%rdi
  je     L195
  test   %rsi,%rsi
  je     L195
  lea    -0x1(%rdx),%rdx
  cmp    %rsi,%rdi
  jbe    L87
  lea    (%rsi,%r9,1),%rcx
  cmp    %rcx,%rdi
  jae    L87
  test   %r9,%r9
  je     L98
  lea    -0x1(%rsi),%rdi
  lea    -0x1(%rax),%rsi
  nop
L91:
  movzbl 0x1(%rdi,%rdx,1),%ecx
  mov    %cl,0x1(%rsi,%rdx,1)
  sub    $0x1,%rdx
  jae    L91
  ret
L87:
  test   %r9,%r9
  je     L141
  lea    0x1(%rsi),%rdi
  mov    %rax,%rcx
  sub    %rdi,%rcx
  cmp    $0xe,%rcx
  jbe    L42
  cmp    $0x6,%rdx
  jbe    L42
  cmp    $0xe,%rdx
  jbe    L184
  mov    %r9,%rdi
  xor    %ecx,%ecx
  and    $0xfffffffffffffff0,%rdi
  nopw   0x0(%rax,%rax,1)
L73:
  movdqu (%rsi,%rcx,1),%xmm0
  movups %xmm0,(%rax,%rcx,1)
  add    $0x10,%rcx
  cmp    %rdi,%rcx
  jne    L73
  mov    %r9,%rcx
  and    $0xfffffffffffffff0,%rcx
  lea    (%rax,%rcx,1),%rdi
  lea    (%rsi,%rcx,1),%r8
  sub    %rcx,%rdx
  cmp    %rcx,%r9
  je     L98
  sub    %rcx,%r9
  lea    -0x1(%r9),%r10
  cmp    $0x6,%r10
  jbe    L190
L197:
  mov    (%rsi,%rcx,1),%rsi
  mov    %rsi,(%rax,%rcx,1)
  mov    %r9,%rcx
  and    $0xfffffffffffffff8,%rcx
  add    %rcx,%rdi
  add    %rcx,%r8
  sub    %rcx,%rdx
  cmp    %rcx,%r9
  je     L98
L190:
  movzbl (%r8),%ecx
  mov    %cl,(%rdi)
  test   %rdx,%rdx
  je     L98
  movzbl 0x1(%r8),%ecx
  mov    %cl,0x1(%rdi)
  cmp    $0x1,%rdx
  je     L98
  movzbl 0x2(%r8),%ecx
  mov    %cl,0x2(%rdi)
  cmp    $0x2,%rdx
  je     L98
  movzbl 0x3(%r8),%ecx
  mov    %cl,0x3(%rdi)
  cmp    $0x3,%rdx
  je     L98
  movzbl 0x4(%r8),%ecx
  mov    %cl,0x4(%rdi)
  cmp    $0x4,%rdx
  je     L98
  movzbl 0x5(%r8),%ecx
  mov    %cl,0x5(%rdi)
  cmp    $0x5,%rdx
  je     L98
  movzbl 0x6(%r8),%edx
  mov    %dl,0x6(%rdi)
  ret
  nopl   0x0(%rax)
L195:
  xor    %eax,%eax
L98:
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L66:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%r9
  jne    L66
  ret
L184:
  mov    %rsi,%r8
  mov    %rax,%rdi
  xor    %ecx,%ecx
  jmp    L197
  cs nopw 0x0(%rax,%rax,1)
L141:
  ret
```

assistant: ```c
void *mymemcpy2(void *dest, const void *src, size_t count) {
  char *strdest = NULL;
  char *strsrc = NULL;
  if ((dest == NULL) || (src == NULL)) {
    return NULL;
  }
  if ((src < dest) && (((char *)src + count) > (char *)dest)) {
    strdest = (char *)dest + count - 1;
    strsrc = (char *)src + count - 1;
    while (count--) {
      *strdest-- = *strsrc--;
    }
  } else {
    strdest = (char *)dest;
    strsrc = (char *)src;
    while (count-- > 0) {
      *strdest++ = *strsrc++;
    }
  }
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<macpad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <get_num@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x27f6,-0x14(%rbp)
  jle    L68
  mov    $0x0,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <halt@plt>
L68:
  cmpl   $0x0,-0x18(%rbp)
  jne    L79
  mov    -0x28(%rbp),%rax
  jmp    L66
L79:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get_string@plt>
  mov    %eax,%edi
  call   <new_str@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <s_len@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L39
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L39:
  cmpl   $0x0,-0x18(%rbp)
  jle    L82
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L65
L43:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x20,(%rax)
  subl   $0x1,-0x20(%rbp)
L65:
  cmpl   $0x0,-0x20(%rbp)
  jg     L43
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <s_letn@plt>
  jmp    L13
L82:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <s_letn@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L63
L17:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x20,(%rax)
  subl   $0x1,-0x20(%rbp)
L63:
  cmpl   $0x0,-0x20(%rbp)
  jg     L17
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
L66:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D6
datatype: string

tool: D19: pad

tool: D6: Too long string.

assistant: ```c
char *macpad(char *arg) {
  int i, al, sl, l = get_num("pad", arg);
  char *ptr = arg, *buf;
  *arg = '\0';
  if ((al = abs(l)) > 10240 - 10)
    halt("Too long string.", NULL);
  if (l == 0)
    return arg;
  sl = s_len(buf = new_str(get_string(arg)));
  if (sl > al)
    sl = al;
  if (l > 0) {
    for (i = al - sl; i > 0; i--)
      *ptr++ = ' ';
    s_letn(buf, ptr, sl + 1);
  } else {
    s_letn(buf, ptr, sl + 1);
    ptr += sl;
    for (i = al - sl; i > 0; i--)
      *ptr++ = ' ';
    *ptr = '\0';
  }
  free(buf);
  return arg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<macpad>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  lea    D18(%rip),%rdi
  call   <get_num@plt>
  mov    %eax,%r14d
  movb   $0x0,0x0(%rbp)
  mov    %eax,%ebx
  neg    %ebx
  cmovs  %eax,%ebx
  cmp    $0x27f6,%ebx
  jg     L90
L42:
  test   %r14d,%r14d
  jne    L36
L79:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L90:
  mov    $0x0,%esi
  lea    D12(%rip),%rdi
  call   <halt@plt>
  jmp    L42
L36:
  mov    %rbp,%rdi
  call   <get_string@plt>
  mov    %eax,%edi
  call   <new_str@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <s_len@plt>
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  mov    %eax,%r13d
  test   %r14d,%r14d
  jle    L41
  sub    %eax,%ebx
  test   %ebx,%ebx
  jle    L20
  mov    %ebx,%edx
  add    %rbp,%rdx
  mov    %rbp,%rax
L104:
  add    $0x1,%rax
  movb   $0x20,-0x1(%rax)
  cmp    %rdx,%rax
  jne    L104
  mov    %ebx,%ebx
  lea    0x0(%rbp,%rbx,1),%rsi
L13:
  lea    0x1(%r13),%edx
  mov    %r12,%rdi
  call   <s_letn@plt>
L80:
  mov    %r12,%rdi
  call   <free@plt>
  jmp    L79
L20:
  mov    %rbp,%rsi
  jmp    L13
L41:
  lea    0x1(%rax),%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <s_letn@plt>
  movslq %r13d,%rcx
  add    %rbp,%rcx
  sub    %r13d,%ebx
  test   %ebx,%ebx
  jle    L3
  mov    %ebx,%edx
  add    %rcx,%rdx
  mov    %rcx,%rax
L48:
  add    $0x1,%rax
  movb   $0x20,-0x1(%rax)
  cmp    %rdx,%rax
  jne    L48
  mov    %ebx,%ebx
  add    %rbx,%rcx
L3:
  movb   $0x0,(%rcx)
  jmp    L80
```

tool_calls: name: retrieve_data
arguments: tag: D18
type_infered: string
name: retrieve_data
arguments: tag: D12
type_infered: string

tool: D18: pad

tool: D12: Too long string.

assistant: ```c
char *macpad(char *arg) {
  int i, al, sl, l = get_num("pad", arg);
  char *ptr = arg, *buf;
  *arg = '\0';
  if ((al = abs(l)) > 10240 - 10)
    halt("Too long string.", NULL);
  if (l == 0)
    return arg;
  sl = s_len(buf = new_str(get_string(arg)));
  if (sl > al)
    sl = al;
  if (l > 0) {
    for (i = al - sl; i > 0; i--)
      *ptr++ = ' ';
    s_letn(buf, ptr, sl + 1);
  } else {
    s_letn(buf, ptr, sl + 1);
    ptr += sl;
    for (i = al - sl; i > 0; i--)
      *ptr++ = ' ';
    *ptr = '\0';
  }
  free(buf);
  return arg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<macpad>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  push   %r13
  mov    %rdi,%r13
  lea    D3(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  call   <get_num@plt>
  movb   $0x0,0x0(%r13)
  mov    %eax,%ebx
  mov    %eax,%ebp
  neg    %ebx
  cmovs  %eax,%ebx
  cmp    $0x27f6,%ebx
  jg     L6
L10:
  test   %ebp,%ebp
  jne    L73
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %r13,%rdi
  call   <get_string@plt>
  mov    %eax,%edi
  call   <new_str@plt>
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <s_len@plt>
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  mov    %eax,%r12d
  test   %ebp,%ebp
  jle    L55
  sub    %eax,%ebx
  test   %ebx,%ebx
  jle    L51
  movslq %ebx,%rbx
  mov    $0x20,%esi
  mov    %r13,%rdi
  mov    %rbx,%rdx
  call   <memset@plt>
  lea    0x0(%r13,%rbx,1),%rsi
L32:
  lea    0x1(%r12),%edx
  mov    %r14,%rdi
  call   <s_letn@plt>
L61:
  mov    %r14,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L6:
  xor    %esi,%esi
  lea    D18(%rip),%rdi
  call   <halt@plt>
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L55:
  lea    0x1(%rax),%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  sub    %r12d,%ebx
  call   <s_letn@plt>
  movslq %r12d,%rcx
  add    %r13,%rcx
  test   %ebx,%ebx
  jle    L72
  movslq %ebx,%rbx
  mov    %rcx,%rdi
  mov    $0x20,%esi
  mov    %rbx,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
  add    %rbx,%rcx
L72:
  movb   $0x0,(%rcx)
  jmp    L61
  nopl   0x0(%rax)
L51:
  mov    %r13,%rsi
  jmp    L32
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D18
type: string

tool: D3: pad

tool: D18: Too long string.

assistant: ```c
char *macpad(char *arg) {
  int i, al, sl, l = get_num("pad", arg);
  char *ptr = arg, *buf;
  *arg = '\0';
  if ((al = abs(l)) > 10240 - 10)
    halt("Too long string.", NULL);
  if (l == 0)
    return arg;
  sl = s_len(buf = new_str(get_string(arg)));
  if (sl > al)
    sl = al;
  if (l > 0) {
    for (i = al - sl; i > 0; i--)
      *ptr++ = ' ';
    s_letn(buf, ptr, sl + 1);
  } else {
    s_letn(buf, ptr, sl + 1);
    ptr += sl;
    for (i = al - sl; i > 0; i--)
      *ptr++ = ' ';
    *ptr = '\0';
  }
  free(buf);
  return arg;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<macpad>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  push   %r13
  mov    %rdi,%r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  call   <get_num@plt>
  movb   $0x0,0x0(%r13)
  mov    %eax,%ebx
  mov    %eax,%ebp
  neg    %ebx
  cmovs  %eax,%ebx
  cmp    $0x27f6,%ebx
  jg     L27
L7:
  test   %ebp,%ebp
  jne    L78
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  mov    %r13,%rdi
  call   <get_string@plt>
  mov    %eax,%edi
  call   <new_str@plt>
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <s_len@plt>
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  mov    %eax,%r12d
  test   %ebp,%ebp
  jle    L5
  sub    %eax,%ebx
  test   %ebx,%ebx
  jle    L8
  movslq %ebx,%rbx
  mov    $0x20,%esi
  mov    %r13,%rdi
  mov    %rbx,%rdx
  call   <memset@plt>
  lea    0x0(%r13,%rbx,1),%rsi
L72:
  lea    0x1(%r12),%edx
  mov    %r14,%rdi
  call   <s_letn@plt>
L2:
  mov    %r14,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L27:
  xor    %esi,%esi
  lea    D15(%rip),%rdi
  call   <halt@plt>
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L5:
  lea    0x1(%rax),%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  sub    %r12d,%ebx
  call   <s_letn@plt>
  movslq %r12d,%rcx
  add    %r13,%rcx
  test   %ebx,%ebx
  jle    L52
  movslq %ebx,%rbx
  mov    %rcx,%rdi
  mov    $0x20,%esi
  mov    %rbx,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
  add    %rbx,%rcx
L52:
  movb   $0x0,(%rcx)
  jmp    L2
  nopl   0x0(%rax)
L8:
  mov    %r13,%rsi
  jmp    L72
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string

tool: D19: pad

tool: D15: Too long string.

assistant: ```c
char *macpad(char *arg) {
  int i, al, sl, l = get_num("pad", arg);
  char *ptr = arg, *buf;
  *arg = '\0';
  if ((al = abs(l)) > 10240 - 10)
    halt("Too long string.", NULL);
  if (l == 0)
    return arg;
  sl = s_len(buf = new_str(get_string(arg)));
  if (sl > al)
    sl = al;
  if (l > 0) {
    for (i = al - sl; i > 0; i--)
      *ptr++ = ' ';
    s_letn(buf, ptr, sl + 1);
  } else {
    s_letn(buf, ptr, sl + 1);
    ptr += sl;
    for (i = al - sl; i > 0; i--)
      *ptr++ = ' ';
    *ptr = '\0';
  }
  free(buf);
  return arg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %al,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <string_get_cstr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <string_get_size@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L36
L3:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  jne    L4
  mov    -0x18(%rbp),%rax
  jmp    L22
L4:
  addq   $0x1,-0x18(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L3
  mov    -0x8(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
size_t find(struct string *str, char c) {
  const char *cstr = string_get_cstr(str);
  size_t len = string_get_size(str);
  size_t i;
  for (i = 0; i < len; ++i) {
    if (cstr[i] == c) {
      return (i);
    }
  }
  return (len);
}
```
user: What is the c source code of the assembly code below:

```asm
<find>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  call   <string_get_cstr@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <string_get_size@plt>
  test   %rax,%rax
  je     L14
  mov    $0x0,%edx
L12:
  cmp    %bpl,(%rbx,%rdx,1)
  je     L16
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L12
  jmp    L14
L16:
  mov    %rdx,%rax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t find(struct string *str, char c) {
  const char *cstr = string_get_cstr(str);
  size_t len = string_get_size(str);
  size_t i;
  for (i = 0; i < len; ++i) {
    if (cstr[i] == c) {
      return (i);
    }
  }
  return (len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  call   <string_get_cstr@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <string_get_size@plt>
  test   %rax,%rax
  je     L33
  xor    %edx,%edx
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L26:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L33
L23:
  cmp    %bpl,(%rbx,%rdx,1)
  jne    L26
  mov    %rdx,%rax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t find(struct string *str, char c) {
  const char *cstr = string_get_cstr(str);
  size_t len = string_get_size(str);
  size_t i;
  for (i = 0; i < len; ++i) {
    if (cstr[i] == c) {
      return (i);
    }
  }
  return (len);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<find>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  call   <string_get_cstr@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <string_get_size@plt>
  test   %rax,%rax
  je     L19
  xor    %edx,%edx
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L38:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L19
L4:
  cmp    %bpl,(%rbx,%rdx,1)
  jne    L38
  mov    %rdx,%rax
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t find(struct string *str, char c) {
  const char *cstr = string_get_cstr(str);
  size_t len = string_get_size(str);
  size_t i;
  for (i = 0; i < len; ++i) {
    if (cstr[i] == c) {
      return (i);
    }
  }
  return (len);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Platform_ConnectionFailed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L17
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L17
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L17
  mov    D39(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L37
L17:
  mov    $0x1,%eax
  jmp    L1
L37:
  mov    $0x0,%eax
L1:
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char Platform_ConnectionFailed(int e) {
  char _o_result;
  _o_result = ((e == ECONNREFUSED || e == ECONNABORTED) || e == ENETUNREACH) || e == EHOSTUNREACH;
  return _o_result;
}
```
user: What is the c source code of the assembly code below:

```asm
<Platform_ConnectionFailed>:
  endbr64
  mov    $0x1,%eax
  mov    D8(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L1
  mov    D17(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L1
  mov    D30(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L1
  mov    D37(%rip),%rax
  cmp    %edi,(%rax)
  sete   %al
  movzbl %al,%eax
L1:
  ret
```

assistant: ```c
char Platform_ConnectionFailed(int e) {
  char _o_result;
  _o_result = ((e == ECONNREFUSED || e == ECONNABORTED) || e == ENETUNREACH) || e == EHOSTUNREACH;
  return _o_result;
}
```