ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L17
  mov    $0x0,%eax
L6:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L6
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t answer = 0;
  while (*str) {
    ++answer;
    ++str;
  }
  return answer;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L1
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L3
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t answer = 0;
  while (*str) {
    ++answer;
    ++str;
  }
  return answer;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L8
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L1
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t answer = 0;
  while (*str) {
    ++answer;
    ++str;
  }
  return answer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s16_to_alaw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L34
  movl   $0xd5,-0x8(%rbp)
  jmp    L47
L34:
  movl   $0x55,-0x8(%rbp)
  negl   -0x14(%rbp)
  cmpl   $0x7fff,-0x14(%rbp)
  jle    L47
  movl   $0x7fff,-0x14(%rbp)
L47:
  cmpl   $0xff,-0x14(%rbp)
  jg     L25
  mov    -0x14(%rbp),%eax
  sar    $0x4,%eax
  mov    %al,-0x9(%rbp)
  jmp    L44
L25:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <val_seg@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  or     %esi,%eax
  mov    %al,-0x9(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  xor    %edx,%eax
  leave
  ret
```

assistant: ```c
unsigned char s16_to_alaw(int pcm_val) {
  int mask;
  int seg;
  unsigned char aval;
  if (pcm_val >= 0) {
    mask = 0xD5;
  } else {
    mask = 0x55;
    pcm_val = -pcm_val;
    if (pcm_val > 0x7fff)
      pcm_val = 0x7fff;
  }
  if (pcm_val < 256)
    aval = pcm_val >> 4;
  else {
    seg = val_seg(pcm_val);
    aval = (seg << 4) | ((pcm_val >> (seg + 3)) & 0x0f);
  }
  return aval ^ mask;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<s16_to_alaw>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0xd5,%ebp
  test   %edi,%edi
  js     L48
L42:
  cmp    $0xff,%ebx
  jg     L15
  mov    %ebx,%eax
  sar    $0x4,%eax
  jmp    L41
L48:
  cmp    $0xffff8001,%edi
  jl     L45
  neg    %ebx
  mov    $0x55,%ebp
  jmp    L42
L45:
  mov    $0x55,%ebp
  mov    $0x7fff,%ebx
L15:
  mov    %ebx,%edi
  call   <val_seg@plt>
  mov    %eax,%edx
  lea    0x3(%rax),%ecx
  mov    %ebx,%eax
  sar    %cl,%eax
  and    $0xf,%eax
  shl    $0x4,%edx
  or     %edx,%eax
L41:
  xor    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char s16_to_alaw(int pcm_val) {
  int mask;
  int seg;
  unsigned char aval;
  if (pcm_val >= 0) {
    mask = 0xD5;
  } else {
    mask = 0x55;
    pcm_val = -pcm_val;
    if (pcm_val > 0x7fff)
      pcm_val = 0x7fff;
  }
  if (pcm_val < 256)
    aval = pcm_val >> 4;
  else {
    seg = val_seg(pcm_val);
    aval = (seg << 4) | ((pcm_val >> (seg + 3)) & 0x0f);
  }
  return aval ^ mask;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s16_to_alaw>:
  endbr64
  push   %rbp
  mov    $0xffffffd5,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L4
L5:
  cmp    $0xff,%ebx
  jle    L8
L32:
  mov    %ebx,%edi
  call   <val_seg@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  lea    0x3(%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  shl    $0x4,%edx
  and    $0xf,%eax
  or     %edx,%eax
  xor    %ebp,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L8:
  mov    %ebx,%eax
  add    $0x8,%rsp
  sar    $0x4,%eax
  pop    %rbx
  xor    %ebp,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L4:
  cmp    $0xffff8001,%edi
  jl     L16
  neg    %ebx
  mov    $0x55,%ebp
  jmp    L5
  nopl   0x0(%rax)
L16:
  mov    $0x55,%ebp
  mov    $0x7fff,%ebx
  jmp    L32
```

assistant: ```c
unsigned char s16_to_alaw(int pcm_val) {
  int mask;
  int seg;
  unsigned char aval;
  if (pcm_val >= 0) {
    mask = 0xD5;
  } else {
    mask = 0x55;
    pcm_val = -pcm_val;
    if (pcm_val > 0x7fff)
      pcm_val = 0x7fff;
  }
  if (pcm_val < 256)
    aval = pcm_val >> 4;
  else {
    seg = val_seg(pcm_val);
    aval = (seg << 4) | ((pcm_val >> (seg + 3)) & 0x0f);
  }
  return aval ^ mask;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<s16_to_alaw>:
  endbr64
  push   %rbp
  mov    $0xffffffd5,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L19
L41:
  cmp    $0xff,%ebx
  jle    L18
L8:
  mov    %ebx,%edi
  call   <val_seg@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  lea    0x3(%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  shl    $0x4,%edx
  and    $0xf,%eax
  or     %edx,%eax
  xor    %ebp,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L18:
  mov    %ebx,%eax
  add    $0x8,%rsp
  sar    $0x4,%eax
  pop    %rbx
  xor    %ebp,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L19:
  cmp    $0xffff8001,%edi
  jl     L33
  neg    %ebx
  mov    $0x55,%ebp
  jmp    L41
  nopl   0x0(%rax)
L33:
  mov    $0x55,%ebp
  mov    $0x7fff,%ebx
  jmp    L8
```

assistant: ```c
unsigned char s16_to_alaw(int pcm_val) {
  int mask;
  int seg;
  unsigned char aval;
  if (pcm_val >= 0) {
    mask = 0xD5;
  } else {
    mask = 0x55;
    pcm_val = -pcm_val;
    if (pcm_val > 0x7fff)
      pcm_val = 0x7fff;
  }
  if (pcm_val < 256)
    aval = pcm_val >> 4;
  else {
    seg = val_seg(pcm_val);
    aval = (seg << 4) | ((pcm_val >> (seg + 3)) & 0x0f);
  }
  return aval ^ mask;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x29,%esi
  mov    $0x29,%edi
  call   <reserva@plt>
  mov    %rax,%rbp
  mov    $0x29,%esi
  mov    $0x29,%edi
  call   <reserva@plt>
  mov    %rax,%rbx
  mov    $0x29,%esi
  mov    $0x29,%edi
  call   <reserva@plt>
  mov    %rax,%r14
  mov    $0x29,%esi
  mov    $0x29,%edi
  call   <reserva@plt>
  mov    %rax,%r13
  movss  D37(%rip),%xmm1
  movaps %xmm1,%xmm0
  mov    $0x29,%edx
  mov    $0x29,%esi
  mov    %rbp,%rdi
  call   <set_initial@plt>
  movss  D37(%rip),%xmm1
  movaps %xmm1,%xmm0
  mov    $0x29,%edx
  mov    $0x29,%esi
  mov    %rbx,%rdi
  call   <set_initial@plt>
  mov    $0x1f4,%r12d
L7:
  mov    $0x29,%edx
  mov    $0x29,%esi
  mov    %rbp,%rdi
  call   <print_matriz@plt>
  mov    $0x29,%edx
  mov    $0x29,%esi
  mov    %rbx,%rdi
  call   <print_matriz@plt>
  mov    $0x29,%ecx
  mov    $0x29,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <copy@plt>
  mov    $0x29,%ecx
  mov    $0x29,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <copy@plt>
  movss  D13(%rip),%xmm3
  movss  D32(%rip),%xmm2
  movss  D37(%rip),%xmm1
  movaps %xmm1,%xmm0
  mov    $0x29,%r9d
  mov    $0x29,%r8d
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <iteration@plt>
  sub    $0x1,%r12d
  jne    L7
  mov    $0x29,%esi
  mov    %rbp,%rdi
  call   <liberar@plt>
  mov    $0x29,%esi
  mov    %rbx,%rdi
  call   <liberar@plt>
  mov    $0x29,%esi
  mov    %r14,%rdi
  call   <liberar@plt>
  mov    $0x29,%esi
  mov    %r13,%rdi
  call   <liberar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D37
type_infered: byte[4]
name: disassemble_data
arguments: tag: D13
type_infered: f32
name: disassemble_data
arguments: tag: D32
type_infered: byte[4]

tool: {"D37": [0xcd,0xcc,0x4c,0x3d]}

tool: D13: 0.01

tool: {"D32": [0xfb,0xed,0x6b,0x39]}

assistant: ```c
int main() {
  int xpoints = 41;
  int ypoints = 41;
  int ntime = 500;
  float c = 1.0;
  float dx = 2.0 / (xpoints - 1);
  float dy = 2.0 / (ypoints - 1);
  float sigma = 0.0009;
  float nu = 0.01;
  float dt = sigma * dx * dy / nu;
  int i;
  int j;
  float **u;
  float **v;
  float **u_past;
  float **v_past;
  u = reserva(xpoints, ypoints);
  v = reserva(xpoints, ypoints);
  u_past = reserva(xpoints, ypoints);
  v_past = reserva(xpoints, ypoints);
  set_initial(u, xpoints, ypoints, dx, dy);
  set_initial(v, xpoints, ypoints, dx, dy);
  int t;
  for (t = 0; t < ntime; t++) {
    print_matriz(u, xpoints, ypoints);
    print_matriz(v, xpoints, ypoints);
    copy(u, u_past, xpoints, ypoints);
    copy(v, v_past, xpoints, ypoints);
    iteration(u, v, u_past, v_past, xpoints, ypoints, dx, dy, dt, nu);
  }
  liberar(u, xpoints);
  liberar(v, xpoints);
  liberar(u_past, xpoints);
  liberar(v_past, xpoints);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x29,%esi
  mov    $0x29,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1f4,%ebx
  call   <reserva@plt>
  mov    $0x29,%esi
  mov    $0x29,%edi
  mov    %rax,%r12
  call   <reserva@plt>
  mov    $0x29,%esi
  mov    $0x29,%edi
  mov    %rax,%rbp
  call   <reserva@plt>
  mov    $0x29,%esi
  mov    $0x29,%edi
  mov    %rax,%r14
  call   <reserva@plt>
  movss  D35(%rip),%xmm1
  mov    $0x29,%edx
  mov    %r12,%rdi
  mov    $0x29,%esi
  mov    %rax,%r13
  movaps %xmm1,%xmm0
  call   <set_initial@plt>
  movss  D35(%rip),%xmm1
  mov    $0x29,%edx
  mov    %rbp,%rdi
  mov    $0x29,%esi
  movaps %xmm1,%xmm0
  call   <set_initial@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x29,%edx
  mov    $0x29,%esi
  mov    %r12,%rdi
  call   <print_matriz@plt>
  mov    $0x29,%edx
  mov    $0x29,%esi
  mov    %rbp,%rdi
  call   <print_matriz@plt>
  mov    $0x29,%ecx
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x29,%edx
  call   <copy@plt>
  mov    $0x29,%ecx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x29,%edx
  call   <copy@plt>
  movss  D35(%rip),%xmm1
  mov    %r13,%rcx
  movss  D28(%rip),%xmm3
  mov    $0x29,%r9d
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movss  D34(%rip),%xmm2
  movaps %xmm1,%xmm0
  mov    $0x29,%r8d
  call   <iteration@plt>
  sub    $0x1,%ebx
  jne    L2
  mov    %r12,%rdi
  mov    $0x29,%esi
  call   <liberar@plt>
  mov    %rbp,%rdi
  mov    $0x29,%esi
  call   <liberar@plt>
  mov    %r14,%rdi
  mov    $0x29,%esi
  call   <liberar@plt>
  mov    %r13,%rdi
  mov    $0x29,%esi
  call   <liberar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D28
type_infered: f32
name: extract_symbolic_data
arguments: label: D34
type_infered: byte[4]

tool: {"D35": [0xcd,0xcc,0x4c,0x3d]}

tool: D28: 0.01

tool: {"D34": [0xfb,0xed,0x6b,0x39]}

assistant: ```c
int main() {
  int xpoints = 41;
  int ypoints = 41;
  int ntime = 500;
  float c = 1.0;
  float dx = 2.0 / (xpoints - 1);
  float dy = 2.0 / (ypoints - 1);
  float sigma = 0.0009;
  float nu = 0.01;
  float dt = sigma * dx * dy / nu;
  int i;
  int j;
  float **u;
  float **v;
  float **u_past;
  float **v_past;
  u = reserva(xpoints, ypoints);
  v = reserva(xpoints, ypoints);
  u_past = reserva(xpoints, ypoints);
  v_past = reserva(xpoints, ypoints);
  set_initial(u, xpoints, ypoints, dx, dy);
  set_initial(v, xpoints, ypoints, dx, dy);
  int t;
  for (t = 0; t < ntime; t++) {
    print_matriz(u, xpoints, ypoints);
    print_matriz(v, xpoints, ypoints);
    copy(u, u_past, xpoints, ypoints);
    copy(v, v_past, xpoints, ypoints);
    iteration(u, v, u_past, v_past, xpoints, ypoints, dx, dy, dt, nu);
  }
  liberar(u, xpoints);
  liberar(v, xpoints);
  liberar(u_past, xpoints);
  liberar(v_past, xpoints);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x29,%esi
  mov    $0x29,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1f4,%ebx
  call   <reserva@plt>
  mov    $0x29,%esi
  mov    $0x29,%edi
  mov    %rax,%r12
  call   <reserva@plt>
  mov    $0x29,%esi
  mov    $0x29,%edi
  mov    %rax,%rbp
  call   <reserva@plt>
  mov    $0x29,%esi
  mov    $0x29,%edi
  mov    %rax,%r14
  call   <reserva@plt>
  movss  D27(%rip),%xmm1
  mov    $0x29,%edx
  mov    %r12,%rdi
  mov    $0x29,%esi
  mov    %rax,%r13
  movaps %xmm1,%xmm0
  call   <set_initial@plt>
  movss  D27(%rip),%xmm1
  mov    $0x29,%edx
  mov    %rbp,%rdi
  mov    $0x29,%esi
  movaps %xmm1,%xmm0
  call   <set_initial@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x29,%edx
  mov    $0x29,%esi
  mov    %r12,%rdi
  call   <print_matriz@plt>
  mov    $0x29,%edx
  mov    $0x29,%esi
  mov    %rbp,%rdi
  call   <print_matriz@plt>
  mov    $0x29,%ecx
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x29,%edx
  call   <copy@plt>
  mov    $0x29,%ecx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x29,%edx
  call   <copy@plt>
  movss  D27(%rip),%xmm1
  mov    %r13,%rcx
  movss  D36(%rip),%xmm3
  mov    $0x29,%r9d
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movss  D11(%rip),%xmm2
  movaps %xmm1,%xmm0
  mov    $0x29,%r8d
  call   <iteration@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    %r12,%rdi
  mov    $0x29,%esi
  call   <liberar@plt>
  mov    %rbp,%rdi
  mov    $0x29,%esi
  call   <liberar@plt>
  mov    %r14,%rdi
  mov    $0x29,%esi
  call   <liberar@plt>
  mov    %r13,%rdi
  mov    $0x29,%esi
  call   <liberar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D27
type: byte[4]
name: retrieve_data
arguments: data_label: D36
type: f32
name: retrieve_data
arguments: data_label: D11
type: byte[4]

tool: {"D27": [0xcd,0xcc,0x4c,0x3d]}

tool: D36: 0.01

tool: {"D11": [0xfb,0xed,0x6b,0x39]}

assistant: ```c
int main() {
  int xpoints = 41;
  int ypoints = 41;
  int ntime = 500;
  float c = 1.0;
  float dx = 2.0 / (xpoints - 1);
  float dy = 2.0 / (ypoints - 1);
  float sigma = 0.0009;
  float nu = 0.01;
  float dt = sigma * dx * dy / nu;
  int i;
  int j;
  float **u;
  float **v;
  float **u_past;
  float **v_past;
  u = reserva(xpoints, ypoints);
  v = reserva(xpoints, ypoints);
  u_past = reserva(xpoints, ypoints);
  v_past = reserva(xpoints, ypoints);
  set_initial(u, xpoints, ypoints, dx, dy);
  set_initial(v, xpoints, ypoints, dx, dy);
  int t;
  for (t = 0; t < ntime; t++) {
    print_matriz(u, xpoints, ypoints);
    print_matriz(v, xpoints, ypoints);
    copy(u, u_past, xpoints, ypoints);
    copy(v, v_past, xpoints, ypoints);
    iteration(u, v, u_past, v_past, xpoints, ypoints, dx, dy, dt, nu);
  }
  liberar(u, xpoints);
  liberar(v, xpoints);
  liberar(u_past, xpoints);
  liberar(v_past, xpoints);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_nonb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  lea    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x8,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  jmp    L16
L48:
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L15
  mov    $0xffffffff,%eax
  jmp    L6
L15:
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x30(%rbp)
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x28(%rbp)
L16:
  cmpl   $0x0,-0x28(%rbp)
  jg     L48
  mov    -0x28(%rbp),%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int send_nonb(int sock, char *buff, int size) {
  struct timeval timeout = {5, 0};
  setsockopt(sock, SOL_SOCKET, SO_SNDTIMEO, (char *)&timeout, sizeof(struct timeval));
  while (size > 0) {
    int send_size = send(sock, buff, size, 0);
    if (send_size <= 0)
      return -1;
    buff += send_size;
    size -= send_size;
  }
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<send_nonb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    %rsp,%rcx
  mov    $0x8,%r8d
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  test   %ebx,%ebx
  jle    L9
L56:
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <send@plt>
  test   %eax,%eax
  jle    L13
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L56
  mov    %ebx,%eax
  jmp    L44
L9:
  mov    %ebx,%eax
  jmp    L44
L13:
  mov    $0xffffffff,%eax
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int send_nonb(int sock, char *buff, int size) {
  struct timeval timeout = {5, 0};
  setsockopt(sock, SOL_SOCKET, SO_SNDTIMEO, (char *)&timeout, sizeof(struct timeval));
  while (size > 0) {
    int send_size = send(sock, buff, size, 0);
    if (send_size <= 0)
      return -1;
    buff += send_size;
    size -= send_size;
  }
  return size;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_nonb>:
  endbr64
  push   %r12
  mov    $0x8,%r8d
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rcx
  movq   $0x5,(%rsp)
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  test   %ebx,%ebx
  jg     L56
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L55:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %rdx,%rbp
  test   %ebx,%ebx
  jle    L35
L56:
  xor    %ecx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <send@plt>
  test   %eax,%eax
  jg     L55
  mov    $0xffffffff,%eax
  jmp    L11
  xchg   %ax,%ax
L35:
  mov    %ebx,%eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int send_nonb(int sock, char *buff, int size) {
  struct timeval timeout = {5, 0};
  setsockopt(sock, SOL_SOCKET, SO_SNDTIMEO, (char *)&timeout, sizeof(struct timeval));
  while (size > 0) {
    int send_size = send(sock, buff, size, 0);
    if (send_size <= 0)
      return -1;
    buff += send_size;
    size -= send_size;
  }
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_UF_guard_brd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L75
L50:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L75:
  cmpl   $0x210,-0x4(%rbp)
  jle    L50
  movl   $0x1,-0x4(%rbp)
  jmp    L24
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1fa,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0x15,-0x4(%rbp)
  jle    L15
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L53:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L45:
  cmpl   $0x210,-0x4(%rbp)
  jle    L53
  movl   $0x1,-0x4(%rbp)
  jmp    L58
L73:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x4(%rbp)
L58:
  cmpl   $0x15,-0x4(%rbp)
  jle    L73
  movl   $0x1fb,-0x4(%rbp)
  jmp    L59
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x20f,(%rax)
  addl   $0x1,-0x4(%rbp)
L59:
  cmpl   $0x20f,-0x4(%rbp)
  jle    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_UF_guard_brd(int fV[((21 + 2) * (21 + 2))], int P[((21 + 2) * (21 + 2))]) {
  int j;
  for (j = 0; j < ((21 + 2) * (21 + 2)); j++)
    fV[j] = 0;
  for (j = 1; j < (21 + 1); j++) {
    fV[j] = 1;
    fV[j + (21 + 2) * (21 + 1)] = 1;
  }
  for (j = 0; j < ((21 + 2) * (21 + 2)); j++)
    P[j] = j;
  for (j = 1; j < (21 + 1); j++)
    P[j] = 1;
  for (j = (21 + 2) * (21 + 1) + 1; j < ((21 + 2) * (21 + 2)) - 1; j++)
    P[j] = (((21 + 2) * (21 + 2)) - 2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_UF_guard_brd>:
  endbr64
  lea    0x844(%rdi),%rdx
  mov    %rdi,%rax
L18:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L18
  lea    0x4(%rdi),%rax
  lea    0x58(%rdi),%rdx
L38:
  movl   $0x1,(%rax)
  movl   $0x1,0x7e8(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L38
  mov    $0x0,%eax
L44:
  mov    %eax,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    $0x211,%rax
  jne    L44
  lea    0x4(%rsi),%rax
  lea    0x58(%rsi),%rdx
L0:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L0
  lea    0x7ec(%rsi),%rax
  add    $0x840,%rsi
L2:
  movl   $0x20f,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L2
  ret
```

assistant: ```c
void init_UF_guard_brd(int fV[((21 + 2) * (21 + 2))], int P[((21 + 2) * (21 + 2))]) {
  int j;
  for (j = 0; j < ((21 + 2) * (21 + 2)); j++)
    fV[j] = 0;
  for (j = 1; j < (21 + 1); j++) {
    fV[j] = 1;
    fV[j + (21 + 2) * (21 + 1)] = 1;
  }
  for (j = 0; j < ((21 + 2) * (21 + 2)); j++)
    P[j] = j;
  for (j = 1; j < (21 + 1); j++)
    P[j] = 1;
  for (j = (21 + 2) * (21 + 1) + 1; j < ((21 + 2) * (21 + 2)) - 1; j++)
    P[j] = (((21 + 2) * (21 + 2)) - 2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init_UF_guard_brd>:
  endbr64
  mov    %rdi,%r8
  movq   $0x0,(%rdi)
  lea    0x8(%rdi),%rdi
  xor    %eax,%eax
  movq   $0x0,0x834(%rdi)
  mov    %r8,%rcx
  and    $0xfffffffffffffff8,%rdi
  mov    %rsi,%rdx
  sub    %rdi,%rcx
  add    $0x844,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x4(%r8),%rax
  lea    0x58(%r8),%rcx
L13:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  movl   $0x1,0x7e4(%rax)
  cmp    %rcx,%rax
  jne    L13
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %eax,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    $0x211,%rax
  jne    L23
  lea    0x4(%rdx),%rax
  lea    0x58(%rdx),%rcx
  nopw   0x0(%rax,%rax,1)
L14:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L14
  lea    0x7ec(%rdx),%rax
  add    $0x840,%rdx
  nopl   (%rax)
L36:
  movl   $0x20f,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L36
  ret
```

assistant: ```c
void init_UF_guard_brd(int fV[((21 + 2) * (21 + 2))], int P[((21 + 2) * (21 + 2))]) {
  int j;
  for (j = 0; j < ((21 + 2) * (21 + 2)); j++)
    fV[j] = 0;
  for (j = 1; j < (21 + 1); j++) {
    fV[j] = 1;
    fV[j + (21 + 2) * (21 + 1)] = 1;
  }
  for (j = 0; j < ((21 + 2) * (21 + 2)); j++)
    P[j] = j;
  for (j = 1; j < (21 + 1); j++)
    P[j] = 1;
  for (j = (21 + 2) * (21 + 1) + 1; j < ((21 + 2) * (21 + 2)) - 1; j++)
    P[j] = (((21 + 2) * (21 + 2)) - 2);
}
```