ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_block_buffer>:
  endbr64
  imul   %r8,%rdi
  push   %r15
  mov    %rdx,%rax
  lea    0x0(,%r8,4),%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%rdx
  mov    %rax,%r12
  add    %r8,%rdi
  push   %rbp
  sub    %rdx,%r12
  push   %rbx
  shl    $0x2,%r12
  sub    $0x18,%rsp
  cmp    %rax,%rdi
  cmovle %r15,%r12
  imul   %r9,%r8
  mov    0x50(%rsp),%rbx
  imul   %rsi,%r9
  lea    (%rbx,%r8,4),%r14
  sub    %r9,%rcx
  cmp    %r14,%rbx
  jae    L20
  lea    -0x1(%rcx),%rbp
  test   %rcx,%rcx
  jle    L20
  mov    %rax,%r13
  imul   %rbp,%rax
  neg    %r13
  lea    0x0(,%r13,4),%rcx
  add    %rdx,%rax
  mov    0x58(%rsp),%rdx
  mov    %rcx,0x8(%rsp)
  lea    (%rdx,%rax,4),%r13
  jmp    L12
  nop
L32:
  sub    $0x1,%rbp
  add    0x8(%rsp),%r13
  cmp    $0xffffffffffffffff,%rbp
  je     L20
L12:
  mov    %rbx,%rsi
  mov    %r12,%rdx
  mov    %r13,%rdi
  add    %r15,%rbx
  call   <memcpy@plt>
  cmp    %rbx,%r14
  ja     L32
L20:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy_block_buffer(const long bx, const long by, const long w, const long h, const long bw, const long bh, const uint32_t *buffer, uint32_t *image) {
  long x = bw * bx;
  long xl = (bw * (bx + 1) > w ? w - bw * bx : bw) * 4;
  const uint32_t *buffer_end = buffer + bw * bh;
  for (long y = h - by * bh; buffer < buffer_end && y-- > 0; buffer += bw)
    memcpy(image + y * w + x, buffer, xl);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy_block_buffer>:
  endbr64
  imul   %r8,%rdi
  push   %r15
  mov    %rdx,%rax
  lea    0x0(,%r8,4),%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%rdx
  mov    %rax,%r12
  add    %r8,%rdi
  push   %rbp
  sub    %rdx,%r12
  push   %rbx
  shl    $0x2,%r12
  sub    $0x18,%rsp
  cmp    %rax,%rdi
  cmovle %r15,%r12
  imul   %r9,%r8
  mov    0x50(%rsp),%rbx
  imul   %rsi,%r9
  lea    (%rbx,%r8,4),%r14
  sub    %r9,%rcx
  cmp    %r14,%rbx
  jae    L14
  lea    -0x1(%rcx),%rbp
  test   %rcx,%rcx
  jle    L14
  mov    %rax,%r13
  imul   %rbp,%rax
  neg    %r13
  lea    0x0(,%r13,4),%rcx
  add    %rdx,%rax
  mov    0x58(%rsp),%rdx
  mov    %rcx,0x8(%rsp)
  lea    (%rdx,%rax,4),%r13
  jmp    L34
  nop
L37:
  sub    $0x1,%rbp
  add    0x8(%rsp),%r13
  cmp    $0xffffffffffffffff,%rbp
  je     L14
L34:
  mov    %rbx,%rsi
  mov    %r12,%rdx
  mov    %r13,%rdi
  add    %r15,%rbx
  call   <memcpy@plt>
  cmp    %rbx,%r14
  ja     L37
L14:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy_block_buffer(const long bx, const long by, const long w, const long h, const long bw, const long bh, const uint32_t *buffer, uint32_t *image) {
  long x = bw * bx;
  long xl = (bw * (bx + 1) > w ? w - bw * bx : bw) * 4;
  const uint32_t *buffer_end = buffer + bw * bh;
  for (long y = h - by * bh; buffer < buffer_end && y-- > 0; buffer += bw)
    memcpy(image + y * w + x, buffer, xl);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<inode_inc_link_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <inc_nlink@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mark_inode_dirty@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void inode_inc_link_count(struct inode *inode) {
  inc_nlink(inode);
  mark_inode_dirty(inode);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inode_inc_link_count>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <inc_nlink@plt>
  mov    %rbx,%rdi
  call   <mark_inode_dirty@plt>
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) void inode_inc_link_count(struct inode *inode) {
  inc_nlink(inode);
  mark_inode_dirty(inode);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inode_inc_link_count>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <inc_nlink@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <mark_inode_dirty@plt>
```

assistant: ```c
__attribute__((always_)) void inode_inc_link_count(struct inode *inode) {
  inc_nlink(inode);
  mark_inode_dirty(inode);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inode_inc_link_count>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <inc_nlink@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <mark_inode_dirty@plt>
```

assistant: ```c
__attribute__((always_)) void inode_inc_link_count(struct inode *inode) {
  inc_nlink(inode);
  mark_inode_dirty(inode);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<efp_get_pol_damp_tt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   D28(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movsd  -0x10(%rbp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  movsd  D27(%rip),%xmm1
  addsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D27(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_infered: byte[8]
name: parse_data
arguments: label: D27
type_infered: f64

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D27: 1

assistant: ```c
double efp_get_pol_damp_tt(double r, double pa, double pb) {
  double ab = sqrt(pa * pb);
  double r2 = r * r;
  return 1.0 - exp(-ab * r2) * (1.0 + ab * r2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<efp_get_pol_damp_tt>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L6
  sqrtsd %xmm1,%xmm1
L11:
  xorpd  D19(%rip),%xmm1
  movsd  0x8(%rsp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm2
  movsd  D13(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  add    $0x18,%rsp
  ret
L6:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: tag: D19
type: byte[16]
name: disassemble_data
arguments: tag: D13
type: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D13: 1

assistant: ```c
double efp_get_pol_damp_tt(double r, double pa, double pb) {
  double ab = sqrt(pa * pb);
  double r2 = r * r;
  return 1.0 - exp(-ab * r2) * (1.0 + ab * r2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<efp_get_pol_damp_tt>:
  endbr64
  mulsd  %xmm2,%xmm1
  movapd %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  sub    $0x18,%rsp
  ucomisd %xmm1,%xmm0
  ja     L3
  sqrtsd %xmm1,%xmm1
L11:
  mulsd  %xmm3,%xmm3
  xorpd  D3(%rip),%xmm1
  mulsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm3
  movsd  D1(%rip),%xmm0
  add    $0x18,%rsp
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  ret
L3:
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm1
  jmp    L11
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: byte[16]
name: unpack_data
arguments: tag: D1
type_guessed: f64

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D1: 1

assistant: ```c
double efp_get_pol_damp_tt(double r, double pa, double pb) {
  double ab = sqrt(pa * pb);
  double r2 = r * r;
  return 1.0 - exp(-ab * r2) * (1.0 + ab * r2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<efp_get_pol_damp_tt>:
  endbr64
  mulsd  %xmm2,%xmm1
  movapd %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  sub    $0x18,%rsp
  ucomisd %xmm1,%xmm0
  ja     L11
  sqrtsd %xmm1,%xmm1
L4:
  mulsd  %xmm3,%xmm3
  xorpd  D11(%rip),%xmm1
  mulsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm3
  movsd  D6(%rip),%xmm0
  add    $0x18,%rsp
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  ret
L11:
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm1
  jmp    L4
```

tool_calls: name: read_data
arguments: data_tag: D11
data_type: byte[16]
name: read_data
arguments: data_tag: D6
data_type: f64

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D6: 1

assistant: ```c
double efp_get_pol_damp_tt(double r, double pa, double pb) {
  double ab = sqrt(pa * pb);
  double r2 = r * r;
  return 1.0 - exp(-ab * r2) * (1.0 + ab * r2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hash_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    $0x811c9dc5,%eax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L0:
  mov    -0x8(%rbp),%rax
  imul   $0x1000193,%rax,%rdx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  xor    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t hash_func(char *key) {
  size_t h = 2166136261;
  int i;
  for (i = 0; key[i] != '\0'; ++i)
    h = (h * 16777619) ^ key[i];
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_func>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x811c9dc5,%eax
  test   %dl,%dl
  je     L9
  add    $0x1,%rdi
L16:
  imul   $0x1000193,%rax,%rax
  movsbq %dl,%rdx
  xor    %rdx,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L16
L9:
  ret
```

assistant: ```c
size_t hash_func(char *key) {
  size_t h = 2166136261;
  int i;
  for (i = 0; key[i] != '\0'; ++i)
    h = (h * 16777619) ^ key[i];
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_func>:
  endbr64
  movsbq (%rdi),%rdx
  mov    $0x811c9dc5,%eax
  test   %dl,%dl
  je     L18
  add    $0x1,%rdi
  nopl   (%rax)
L13:
  imul   $0x1000193,%rax,%rax
  add    $0x1,%rdi
  xor    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  jne    L13
L18:
  ret
```

assistant: ```c
size_t hash_func(char *key) {
  size_t h = 2166136261;
  int i;
  for (i = 0; key[i] != '\0'; ++i)
    h = (h * 16777619) ^ key[i];
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hash_func>:
  endbr64
  movsbq (%rdi),%rdx
  mov    $0x811c9dc5,%eax
  test   %dl,%dl
  je     L4
  add    $0x1,%rdi
  nopl   (%rax)
L3:
  imul   $0x1000193,%rax,%rax
  add    $0x1,%rdi
  xor    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  jne    L3
L4:
  ret
```

assistant: ```c
size_t hash_func(char *key) {
  size_t h = 2166136261;
  int i;
  for (i = 0; key[i] != '\0'; ++i)
    h = (h * 16777619) ^ key[i];
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isnumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2f,-0x4(%rbp)
  jle    L17
  cmpl   $0x39,-0x4(%rbp)
  jg     L17
  mov    $0x1,%eax
  jmp    L5
L17:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int isnumber(int ch) {
  if (ch >= '0' && ch <= '9')
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isnumber>:
  endbr64
  sub    $0x30,%edi
  cmp    $0x9,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isnumber(int ch) {
  if (ch >= '0' && ch <= '9')
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isnumber>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  ret
```

assistant: ```c
int isnumber(int ch) {
  if (ch >= '0' && ch <= '9')
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isnumber>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  ret
```

assistant: ```c
int isnumber(int ch) {
  if (ch >= '0' && ch <= '9')
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_float2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D30(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  and    $0x1,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzwl -0x4(%rbp),%eax
  shr    %ax
  and    $0xff,%ah
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  shr    $0x9,%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D30
datatype: byte[4]
name: retrieve_data
arguments: data_tag: D36
datatype: string
name: retrieve_data
arguments: data_tag: D33
datatype: string

tool: {"D30": [0x00,0x00,0x50,0xc1]}

tool: D36: %d


tool: D33: %x


assistant: ```c
void print_float2() {
  union {
    float f;
    struct {
      unsigned int sign : 1;
      unsigned int exp : 8;
      unsigned int coef : 23;
    } u;
  } p;
  p.f = -13.0;
  printf("%d\n", p.u.sign);
  printf("%d\n", p.u.exp);
  printf("%x\n", p.u.coef);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_float2>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x60a800,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D3
datatype: string

tool: D4: %d


tool: D3: %x


assistant: ```c
void print_float2() {
  union {
    float f;
    struct {
      unsigned int sign : 1;
      unsigned int exp : 8;
      unsigned int coef : 23;
    } u;
  } p;
  p.f = -13.0;
  printf("%d\n", p.u.sign);
  printf("%d\n", p.u.exp);
  printf("%x\n", p.u.coef);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_float2>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    $0x60a800,%esi
  lea    D9(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D9
data_type: string

tool: D5: %d


tool: D9: %x


assistant: ```c
void print_float2() {
  union {
    float f;
    struct {
      unsigned int sign : 1;
      unsigned int exp : 8;
      unsigned int coef : 23;
    } u;
  } p;
  p.f = -13.0;
  printf("%d\n", p.u.sign);
  printf("%d\n", p.u.exp);
  printf("%x\n", p.u.coef);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_float2>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    $0x60a800,%esi
  lea    D15(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string

tool: D7: %d


tool: D15: %x


assistant: ```c
void print_float2() {
  union {
    float f;
    struct {
      unsigned int sign : 1;
      unsigned int exp : 8;
      unsigned int coef : 23;
    } u;
  } p;
  p.f = -13.0;
  printf("%d\n", p.u.sign);
  printf("%d\n", p.u.exp);
  printf("%x\n", p.u.coef);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L45
L38:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L43
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L43
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  jmp    L34
L43:
  subl   $0x1,-0x10(%rbp)
L45:
  cmpl   $0x0,-0x10(%rbp)
  jns    L38
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L34
  movl   $0xffffffff,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  jmp    L34
L34:
  leave
  ret
```

assistant: ```c
int find(char str[], char ch, int k) {
  int i = 0, a = -1, b = 0, length;
  length = strlen(str);
  for (i = length - 1; i >= 0; i--)
    if (ch == str[i]) {
      b++;
      if (b == k) {
        return (i + 1);
        a = 1;
        break;
      }
    }
  if (a == -1) {
    i = -1;
    return i;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<find>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r12d
  mov    %esi,%ebp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L24
  cltq
  mov    $0x0,%ecx
  jmp    L63
L12:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L50
L63:
  cmp    %bpl,(%rbx,%rax,1)
  jne    L12
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jne    L12
  lea    0x1(%rax),%eax
  jmp    L29
L50:
  mov    $0xffffffff,%eax
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    $0xffffffff,%eax
  jmp    L29
```

assistant: ```c
int find(char str[], char ch, int k) {
  int i = 0, a = -1, b = 0, length;
  length = strlen(str);
  for (i = length - 1; i >= 0; i--)
    if (ch == str[i]) {
      b++;
      if (b == k) {
        return (i + 1);
        a = 1;
        break;
      }
    }
  if (a == -1) {
    i = -1;
    return i;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<find>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L4
  cltq
  xor    %esi,%esi
  jmp    L36
L22:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L4
L36:
  cmp    %bpl,(%rbx,%rax,1)
  jne    L22
  add    $0x1,%esi
  cmp    %r12d,%esi
  jne    L22
  pop    %rbx
  lea    0x1(%rax),%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L4:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int find(char str[], char ch, int k) {
  int i = 0, a = -1, b = 0, length;
  length = strlen(str);
  for (i = length - 1; i >= 0; i--)
    if (ch == str[i]) {
      b++;
      if (b == k) {
        return (i + 1);
        a = 1;
        break;
      }
    }
  if (a == -1) {
    i = -1;
    return i;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L13
  cltq
  xor    %esi,%esi
  jmp    L42
L35:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L13
L42:
  cmp    %bpl,(%rbx,%rax,1)
  jne    L35
  add    $0x1,%esi
  cmp    %r12d,%esi
  jne    L35
  pop    %rbx
  lea    0x1(%rax),%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L13:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int find(char str[], char ch, int k) {
  int i = 0, a = -1, b = 0, length;
  length = strlen(str);
  for (i = length - 1; i >= 0; i--)
    if (ch == str[i]) {
      b++;
      if (b == k) {
        return (i + 1);
        a = 1;
        break;
      }
    }
  if (a == -1) {
    i = -1;
    return i;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x14(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D45(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%edi
  call   <close@plt>
  mov    $0x1,%edi
  call   <close@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%ecx
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <bind@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x5,%esi
  mov    $0x0,%edi
  call   <listen@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    (%rax),%ecx
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  cmp    $0x1,%eax
  je     L35
  mov    $0x4d,%eax
  jmp    L17
L35:
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D45(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <send_query@plt>
  test   %rax,%rax
  je     L38
  mov    $0x1,%edi
  call   <check_responses@plt>
  test   %rax,%rax
  je     L38
  mov    $0x0,%eax
  jmp    L17
L38:
  mov    $0x4d,%eax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int main(void) {
  struct sockaddr_in addr;
  socklen_t len = sizeof(addr);
  memset(&addr, 0, sizeof(addr));
  addr.sin_family = AF_INET;
  addr.sin_addr.s_addr = htonl(INADDR_LOOPBACK);
  close(0);
  close(1);
  assert(socket(PF_INET, SOCK_STREAM, 0) == 0);
  assert(bind(0, (struct sockaddr *)&addr, len) == 0);
  assert(listen(0, 5) == 0);
  if (socket(AF_NETLINK, SOCK_RAW, NETLINK_INET_DIAG) != 1)
    return 77;
  return (send_query(1, AF_INET, IPPROTO_TCP) && check_responses(1)) ? 0 : 77;
}
```