ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sched_setaffinity>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sched_setaffinity(pid_t pid, size_t cpusetsize, const cpu_set_t *cpuset) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sched_setaffinity>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sched_setaffinity(pid_t pid, size_t cpusetsize, const cpu_set_t *cpuset) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<arr_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L24:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L25
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L25:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L24
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int arr_min(int *arr, unsigned int length) {
  int res = arr[0];
  for (unsigned int i = 0; i < length; i++)
    if (res > arr[i])
      res = arr[i];
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arr_min>:
  endbr64
  mov    (%rdi),%edx
  test   %esi,%esi
  je     L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rsi
L13:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L13
L3:
  mov    %edx,%eax
  ret
```

assistant: ```c
int arr_min(int *arr, unsigned int length) {
  int res = arr[0];
  for (unsigned int i = 0; i < length; i++)
    if (res > arr[i])
      res = arr[i];
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<arr_min>:
  endbr64
  mov    (%rdi),%eax
  test   %esi,%esi
  je     L19
  lea    -0x1(%rsi),%edx
  add    $0x4,%rdi
  lea    (%rdi,%rdx,4),%rcx
  mov    %eax,%edx
  jmp    L2
  nopl   0x0(%rax)
L21:
  mov    (%rdi),%edx
  add    $0x4,%rdi
L2:
  cmp    %edx,%eax
  cmovg  %edx,%eax
  cmp    %rcx,%rdi
  jne    L21
L19:
  ret
```

assistant: ```c
int arr_min(int *arr, unsigned int length) {
  int res = arr[0];
  for (unsigned int i = 0; i < length; i++)
    if (res > arr[i])
      res = arr[i];
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<arr_min>:
  endbr64
  mov    (%rdi),%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L25
  lea    -0x1(%rsi),%ecx
  cmp    $0x2,%ecx
  jbe    L10
  mov    %esi,%ecx
  movd   %eax,%xmm4
  mov    %rdi,%rax
  shr    $0x2,%ecx
  pshufd $0x0,%xmm4,%xmm0
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax)
L32:
  movdqu (%rax),%xmm1
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm3,%xmm1
  por    %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L32
  movdqa %xmm0,%xmm2
  mov    %edx,%ecx
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%ecx
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x3,%dl
  je     L65
L21:
  mov    %ecx,%esi
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jbe    L25
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  add    $0x2,%ecx
  cmp    %ecx,%edx
  jbe    L25
  mov    (%rdi,%rcx,4),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L25:
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  ret
L10:
  xor    %ecx,%ecx
  jmp    L21
```

assistant: ```c
int arr_min(int *arr, unsigned int length) {
  int res = arr[0];
  for (unsigned int i = 0; i < length; i++)
    if (res > arr[i])
      res = arr[i];
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    0x8(%rsp),%rdi
  call   <eingabe2@plt>
  mov    0x8(%rsp),%rdi
  call   <getlength@plt>
  mov    %eax,%esi
  lea    0x10(%rsp),%rdi
  mov    $0x20,%ecx
  mov    $0x5f,%edx
  call   <fillchar2@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L35
L44:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    0x10(%rsp),%rdi
  call   <puts@plt>
  mov    $0x5,%ebx
  lea    D31(%rip),%rbp
L55:
  mov    $0x0,%eax
  call   <einlesen_char@plt>
  movzbl %al,%edx
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <is_in2@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  call   <puts@plt>
  mov    $0x5f,%esi
  mov    0x10(%rsp),%rdi
  call   <is_in_check@plt>
  test   %rax,%rax
  je     L63
  test   %ebx,%ebx
  jg     L55
  mov    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L42:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L63:
  mov    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L42
  lea    D9(%rip),%rdi
  call   <puts@plt>
L7:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  movq   $0x0,0x10(%rsp)
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L44
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D31
data_type: string
name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D32
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string

tool: D31: Noch %i Versuche.


tool: D15: Das Wort war: %s


tool: D32: Der Sensenmann hat euch alle gep0wnt

tool: D9: Die Spieler haben gewonnen

assistant: ```c
int main() {
  int tries = 5;
  unsigned char x;
  unsigned char *eingabe_henker = NULL;
  unsigned char *eingabe_reveal = NULL;
  eingabe2(&eingabe_henker);
  if (fillchar2(&eingabe_reveal, getlength(eingabe_henker), '_', ' ') == 0)
    return 1;
  printf("%s\n", eingabe_reveal);
  while (tries > 0) {
    x = einlesen_char();
    if (is_in2(eingabe_henker, eingabe_reveal, x) == 0) {
      tries--;
    }
    printf("Noch %i Versuche.\n", tries);
    printf("%s\n", eingabe_reveal);
    if (is_in_check(eingabe_reveal, '_') == 0)
      break;
  }
  printf("Das Wort war: %s\n", eingabe_henker);
  if (tries >= 1)
    printf("Die Spieler haben gewonnen\n");
  else
    printf("Der Sensenmann hat euch alle gep0wnt\n");
  free(eingabe_reveal);
  eingabe_reveal = NULL;
  free(eingabe_henker);
  eingabe_henker = NULL;
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <eingabe2@plt>
  mov    0x8(%rsp),%rdi
  call   <getlength@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x20,%ecx
  mov    $0x5f,%edx
  mov    %eax,%esi
  call   <fillchar2@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L55
L31:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  mov    0x10(%rsp),%rdi
  mov    $0x5,%ebx
  lea    D6(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  call   <einlesen_char@plt>
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  movzbl %al,%edx
  call   <is_in2@plt>
  mov    %rbp,%rdi
  cmp    $0x1,%rax
  sbb    $0x0,%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rdi
  mov    $0x5f,%esi
  call   <is_in_check@plt>
  test   %rax,%rax
  je     L45
  test   %ebx,%ebx
  jne    L3
  mov    0x8(%rsp),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L16:
  lea    D41(%rip),%rdi
  call   <puts@plt>
L63:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  movq   $0x0,0x10(%rsp)
  call   <free@plt>
  xor    %eax,%eax
  jmp    L31
L45:
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  je     L16
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L63
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D41
type: string
name: parse_data
arguments: label: D38
type: string

tool: D6: Noch %i Versuche.


tool: D1: Das Wort war: %s


tool: D41: Der Sensenmann hat euch alle gep0wnt

tool: D38: Die Spieler haben gewonnen

assistant: ```c
int main() {
  int tries = 5;
  unsigned char x;
  unsigned char *eingabe_henker = NULL;
  unsigned char *eingabe_reveal = NULL;
  eingabe2(&eingabe_henker);
  if (fillchar2(&eingabe_reveal, getlength(eingabe_henker), '_', ' ') == 0)
    return 1;
  printf("%s\n", eingabe_reveal);
  while (tries > 0) {
    x = einlesen_char();
    if (is_in2(eingabe_henker, eingabe_reveal, x) == 0) {
      tries--;
    }
    printf("Noch %i Versuche.\n", tries);
    printf("%s\n", eingabe_reveal);
    if (is_in_check(eingabe_reveal, '_') == 0)
      break;
  }
  printf("Das Wort war: %s\n", eingabe_henker);
  if (tries >= 1)
    printf("Die Spieler haben gewonnen\n");
  else
    printf("Der Sensenmann hat euch alle gep0wnt\n");
  free(eingabe_reveal);
  eingabe_reveal = NULL;
  free(eingabe_henker);
  eingabe_henker = NULL;
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <eingabe2@plt>
  mov    0x8(%rsp),%rdi
  call   <getlength@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x20,%ecx
  mov    $0x5f,%edx
  mov    %eax,%esi
  call   <fillchar2@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L20
L62:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    0x10(%rsp),%rdi
  mov    $0x5,%ebx
  lea    D35(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L52:
  xor    %eax,%eax
  call   <einlesen_char@plt>
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  movzbl %al,%edx
  call   <is_in2@plt>
  mov    %rbp,%rdi
  cmp    $0x1,%rax
  sbb    $0x0,%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rdi
  mov    $0x5f,%esi
  call   <is_in_check@plt>
  test   %rax,%rax
  je     L32
  test   %ebx,%ebx
  jne    L52
  mov    0x8(%rsp),%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L35:
  lea    D26(%rip),%rdi
  call   <puts@plt>
L38:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  movq   $0x0,0x10(%rsp)
  call   <free@plt>
  xor    %eax,%eax
  jmp    L62
L32:
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  je     L35
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L38
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D35
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string
name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D35: Noch %i Versuche.


tool: D8: Das Wort war: %s


tool: D26: Der Sensenmann hat euch alle gep0wnt

tool: D9: Die Spieler haben gewonnen

assistant: ```c
int main() {
  int tries = 5;
  unsigned char x;
  unsigned char *eingabe_henker = NULL;
  unsigned char *eingabe_reveal = NULL;
  eingabe2(&eingabe_henker);
  if (fillchar2(&eingabe_reveal, getlength(eingabe_henker), '_', ' ') == 0)
    return 1;
  printf("%s\n", eingabe_reveal);
  while (tries > 0) {
    x = einlesen_char();
    if (is_in2(eingabe_henker, eingabe_reveal, x) == 0) {
      tries--;
    }
    printf("Noch %i Versuche.\n", tries);
    printf("%s\n", eingabe_reveal);
    if (is_in_check(eingabe_reveal, '_') == 0)
      break;
  }
  printf("Das Wort war: %s\n", eingabe_henker);
  if (tries >= 1)
    printf("Die Spieler haben gewonnen\n");
  else
    printf("Der Sensenmann hat euch alle gep0wnt\n");
  free(eingabe_reveal);
  eingabe_reveal = NULL;
  free(eingabe_henker);
  eingabe_henker = NULL;
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<allocateStringArgument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <vlmcsd_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *allocateStringArgument(const char *const argument) {
  char *result = (char *)vlmcsd_malloc(strlen(argument) + 1);
  strcpy(result, argument);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<allocateStringArgument>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <vlmcsd_malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *allocateStringArgument(const char *const argument) {
  char *result = (char *)vlmcsd_malloc(strlen(argument) + 1);
  strcpy(result, argument);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<allocateStringArgument>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <vlmcsd_malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *allocateStringArgument(const char *const argument) {
  char *result = (char *)vlmcsd_malloc(strlen(argument) + 1);
  strcpy(result, argument);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<allocateStringArgument>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <vlmcsd_malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *allocateStringArgument(const char *const argument) {
  char *result = (char *)vlmcsd_malloc(strlen(argument) + 1);
  strcpy(result, argument);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vec_mult_ref>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vec_mult_ref(double *p1, double *v3, double *v4, int N) {
  int i;
  for (i = 0; i < N; i++)
    p1[i] = v3[i] * v4[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vec_mult_ref>:
  endbr64
  test   %ecx,%ecx
  jle    L9
  mov    %ecx,%ecx
  mov    $0x0,%eax
L18:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L18
L9:
  ret
```

assistant: ```c
void vec_mult_ref(double *p1, double *v3, double *v4, int N) {
  int i;
  for (i = 0; i < N; i++)
    p1[i] = v3[i] * v4[i];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<vec_mult_ref>:
  endbr64
  test   %ecx,%ecx
  jle    L6
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L12:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L12
L6:
  ret
```

assistant: ```c
void vec_mult_ref(double *p1, double *v3, double *v4, int N) {
  int i;
  for (i = 0; i < N; i++)
    p1[i] = v3[i] * v4[i];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vec_mult_ref>:
  endbr64
  test   %ecx,%ecx
  jle    L21
  lea    0x8(%rdx),%rax
  cmp    %rax,%rdi
  lea    0x8(%rsi),%rax
  setne  %r8b
  cmp    %rax,%rdi
  setne  %al
  test   %al,%r8b
  je     L6
  lea    -0x1(%rcx),%eax
  cmp    $0x1,%eax
  jbe    L6
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    %r8d
  shl    $0x4,%r8
  nopw   0x0(%rax,%rax,1)
L51:
  movupd (%rsi,%rax,1),%xmm0
  movupd (%rdx,%rax,1),%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L51
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L21
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  ret
  nopl   (%rax)
L6:
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L26:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L26
L21:
  ret
```

assistant: ```c
void vec_mult_ref(double *p1, double *v3, double *v4, int N) {
  int i;
  for (i = 0; i < N; i++)
    p1[i] = v3[i] * v4[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<angle_diff_full>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %edi,-0x14(%rbp)
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L15
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L15
  movsd  -0x8(%rbp),%xmm1
  movsd  D13(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L15:
  cmpl   $0x2,-0x14(%rbp)
  jne    L47
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L0
  movsd  D13(%rip),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L47
L0:
  movsd  -0x8(%rbp),%xmm0
  movq   D8(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L47:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type: f64
name: retrieve_data
arguments: data_tag: D8
type: byte[8]

tool: D13: 6.28318530718

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double angle_diff_full(double a, double b, int sens) {
  a -= b;
  if (sens == 1 && a < 0)
    a += 6.28318530718;
  if (sens == 2) {
    if (a > 0)
      a = 6.28318530718 - a;
    else
      a = -a;
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_stats>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <SSL_CTX_sess_number@plt>
  mov    %eax,%edx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <SSL_CTX_sess_connect@plt>
  mov    %eax,%edx
  lea    D19(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <SSL_CTX_sess_connect_good@plt>
  mov    %eax,%edx
  lea    D53(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <SSL_CTX_sess_accept@plt>
  mov    %eax,%edx
  lea    D45(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <SSL_CTX_sess_accept_good@plt>
  mov    %eax,%edx
  lea    D30(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <SSL_CTX_sess_hits@plt>
  mov    %eax,%edx
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <SSL_CTX_sess_misses@plt>
  mov    %eax,%edx
  lea    D79(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <SSL_CTX_sess_timeouts@plt>
  mov    %eax,%edx
  lea    D48(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D53
type_guessed: string
name: extract_symbolic_data
arguments: tag: D45
type_guessed: string
name: extract_symbolic_data
arguments: tag: D30
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D79
type_guessed: string
name: extract_symbolic_data
arguments: tag: D48
type_guessed: string

tool: D6: %4ld items in the session cache


tool: D19: %4d client connects (SSL_connect())


tool: D53: %4d client connects that finished


tool: D45: %4d server connects (SSL_accept())


tool: D30: %4d server connects that finished


tool: D10: %4d session cache hits


tool: D79: %4d session cache misses


tool: D48: %4d session cache timeouts


assistant: ```c
void print_stats(FILE *fp, SSL_CTX *ctx) {
  fprintf(fp, "%4ld items in the session cache\n", SSL_CTX_sess_number(ctx));
  fprintf(fp, "%4d client connects (SSL_connect())\n", SSL_CTX_sess_connect(ctx));
  fprintf(fp, "%4d client connects that finished\n", SSL_CTX_sess_connect_good(ctx));
  fprintf(fp, "%4d server connects (SSL_accept())\n", SSL_CTX_sess_accept(ctx));
  fprintf(fp, "%4d server connects that finished\n", SSL_CTX_sess_accept_good(ctx));
  fprintf(fp, "%4d session cache hits\n", SSL_CTX_sess_hits(ctx));
  fprintf(fp, "%4d session cache misses\n", SSL_CTX_sess_misses(ctx));
  fprintf(fp, "%4d session cache timeouts\n", SSL_CTX_sess_timeouts(ctx));
}
```