ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dist>:
  endbr64
  sub    %edx,%edi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  sub    %ecx,%esi
  imul   %edi,%edi
  imul   %esi,%esi
  add    %esi,%edi
  cvtsi2ss %edi,%xmm0
  ucomiss %xmm0,%xmm1
  ja     L8
  sqrtss %xmm0,%xmm0
  ret
L8:
  jmp    1050 <sqrtf@plt>
```

assistant: ```c
float dist(int ax, int ay, int bx, int by) {
  int x = ax - bx;
  int y = ay - by;
  return sqrtf((float)(x * x + y * y));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dist>:
  endbr64
  sub    %edx,%edi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  sub    %ecx,%esi
  imul   %edi,%edi
  imul   %esi,%esi
  add    %esi,%edi
  cvtsi2ss %edi,%xmm0
  ucomiss %xmm0,%xmm1
  ja     L8
  sqrtss %xmm0,%xmm0
  ret
L8:
  jmp    1050 <sqrtf@plt>
```

assistant: ```c
float dist(int ax, int ay, int bx, int by) {
  int x = ax - bx;
  int y = ay - by;
  return sqrtf((float)(x * x + y * y));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<il_child>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <alarm@plt>
  mov    $0x4,%edi
  call   <sleep@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D17
type: string

tool: D4:         child: I'm the child


tool: D17:         child: I'm exiting


assistant: ```c
void il_child(void) {
  printf("        child: I'm the child\n");
  alarm(2);
  sleep(4);
  printf("        child: I'm exiting\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<il_child>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <alarm@plt>
  mov    $0x4,%edi
  call   <sleep@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string
name: read_data
arguments: data_label: D11
type: string

tool: D8:         child: I'm the child


tool: D11:         child: I'm exiting


assistant: ```c
void il_child(void) {
  printf("        child: I'm the child\n");
  alarm(2);
  sleep(4);
  printf("        child: I'm exiting\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<il_child>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <alarm@plt>
  mov    $0x4,%edi
  call   <sleep@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
type: string
name: parse_data
arguments: data_label: D5
type: string

tool: D15:         child: I'm the child


tool: D5:         child: I'm exiting


assistant: ```c
void il_child(void) {
  printf("        child: I'm the child\n");
  alarm(2);
  sleep(4);
  printf("        child: I'm exiting\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<il_child>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <alarm@plt>
  mov    $0x4,%edi
  call   <sleep@plt>
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string

tool: D17:         child: I'm the child


tool: D19:         child: I'm exiting


assistant: ```c
void il_child(void) {
  printf("        child: I'm the child\n");
  alarm(2);
  sleep(4);
  printf("        child: I'm exiting\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  movl   $0xb,-0x10(%rbp)
  movl   $0xd,-0xc(%rbp)
  movl   $0x6,-0x24(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <showArray@plt>
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <modArray@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <showArray@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string

tool: D18: Original Array:

tool: D15: 

Modified Array:

assistant: ```c
int main(void) {
  int primes[] = {1, 3, 5, 7, 11, 13};
  int size = sizeof(primes) / 4;
  puts("Original Array:");
  showArray(primes, size);
  modArray(primes, size);
  puts("\n\nModified Array:");
  showArray(primes, size);
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0xb,0x10(%rsp)
  movl   $0xd,0x14(%rsp)
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <showArray@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <modArray@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <showArray@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D19
datatype: string

tool: D0: Original Array:

tool: D19: 

Modified Array:

assistant: ```c
int main(void) {
  int primes[] = {1, 3, 5, 7, 11, 13};
  int size = sizeof(primes) / 4;
  puts("Original Array:");
  showArray(primes, size);
  modArray(primes, size);
  puts("\n\nModified Array:");
  showArray(primes, size);
  getchar();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000001,%rax
  mov    %rsp,%rbp
  mov    %rax,(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xd0000000b,%rax
  mov    %rax,0x10(%rsp)
  call   <puts@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <showArray@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <modArray@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <showArray@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D0
type: string

tool: D3: Original Array:

tool: D0: 

Modified Array:

assistant: ```c
int main(void) {
  int primes[] = {1, 3, 5, 7, 11, 13};
  int size = sizeof(primes) / 4;
  puts("Original Array:");
  showArray(primes, size);
  modArray(primes, size);
  puts("\n\nModified Array:");
  showArray(primes, size);
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D37(%rip),%rdi
  sub    $0x20,%rsp
  movdqa D38(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <puts@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <showArray@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <modArray@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <showArray@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D37
type_guessed: string
name: unpack_data
arguments: tag: D38
type_guessed: byte[16]
name: unpack_data
arguments: tag: D2
type_guessed: byte[8]
name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D37: Original Array:

tool: {"D38": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D2": [0x0b,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

tool: D4: 

Modified Array:

assistant: ```c
int main(void) {
  int primes[] = {1, 3, 5, 7, 11, 13};
  int size = sizeof(primes) / 4;
  puts("Original Array:");
  showArray(primes, size);
  modArray(primes, size);
  puts("\n\nModified Array:");
  showArray(primes, size);
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xa,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int sum;
  int a, b;
  a = 10;
  b = 20;
  sum = a + b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int sum;
  int a, b;
  a = 10;
  b = 20;
  sum = a + b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int sum;
  int a, b;
  a = 10;
  b = 20;
  sum = a + b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int sum;
  int a, b;
  a = 10;
  b = 20;
  sum = a + b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vebsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    $0x20,%eax
  ja     L10
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <bytes@plt>
  jmp    L0
L10:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fls@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <highbits@plt>
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <ipow@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <bytes@plt>
  lea    (%rax,%rax,1),%ebx
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <vebsize>
  lea    (%rbx,%rax,1),%r12d
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <vebsize>
  imul   %ebx,%eax
  lea    (%r12,%rax,1),%ebx
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%edi
  call   <vebsize>
  add    %ebx,%eax
L0:
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
uint vebsize(uint M) {
  if (M <= sizeof(uint) * 8)
    return bytes(M);
  uint k = fls(M - 1);
  uint m = highbits(M - 1, k / 2) + 1;
  uint n = ipow(k / 2);
  return 2 * bytes(k) + vebsize(m) + (m - 1) * vebsize(n) + vebsize(M - (m - 1) * n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vebsize>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x20,%edi
  jbe    L0
  lea    -0x1(%rdi),%r12d
  mov    %r12d,%edi
  call   <fls@plt>
  mov    %eax,%r13d
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <highbits@plt>
  mov    %eax,%r12d
  mov    %ebp,%edi
  call   <ipow@plt>
  mov    %eax,%r14d
  mov    %r13d,%edi
  call   <bytes@plt>
  mov    %eax,%ebp
  lea    0x1(%r12),%edi
  call   <vebsize>
  lea    (%rax,%rbp,2),%ebp
  mov    %r14d,%edi
  call   <vebsize>
  imul   %r12d,%eax
  add    %eax,%ebp
  mov    %r12d,%eax
  imul   %r14d,%eax
  sub    %eax,%ebx
  mov    %ebx,%edi
  call   <vebsize>
  add    %ebp,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <bytes@plt>
  jmp    L4
```

assistant: ```c
uint vebsize(uint M) {
  if (M <= sizeof(uint) * 8)
    return bytes(M);
  uint k = fls(M - 1);
  uint m = highbits(M - 1, k / 2) + 1;
  uint n = ipow(k / 2);
  return 2 * bytes(k) + vebsize(m) + (m - 1) * vebsize(n) + vebsize(M - (m - 1) * n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vebsize>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x20,%edi
  jbe    L17
L15:
  lea    -0x1(%r14),%r15d
  mov    %r15d,%edi
  call   <fls@plt>
  mov    %r15d,%edi
  mov    %eax,%ebp
  mov    %eax,%r13d
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  mov    %ebp,%esi
  call   <highbits@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <ipow@plt>
  mov    %r13d,%edi
  mov    %eax,%ebp
  call   <bytes@plt>
  lea    0x1(%rbx),%edi
  mov    %eax,%r13d
  call   <vebsize>
  mov    %ebp,%edi
  imul   %ebx,%ebp
  lea    (%rax,%r13,2),%r13d
  call   <vebsize>
  imul   %eax,%ebx
  sub    %ebp,%r14d
  add    %r13d,%ebx
  add    %ebx,%r12d
  cmp    $0x20,%r14d
  ja     L15
L17:
  mov    %r14d,%edi
  call   <bytes@plt>
  add    $0x8,%rsp
  pop    %rbx
  add    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint vebsize(uint M) {
  if (M <= sizeof(uint) * 8)
    return bytes(M);
  uint k = fls(M - 1);
  uint m = highbits(M - 1, k / 2) + 1;
  uint n = ipow(k / 2);
  return 2 * bytes(k) + vebsize(m) + (m - 1) * vebsize(n) + vebsize(M - (m - 1) * n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vebsize>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x20,%edi
  jbe    L0
L1:
  lea    -0x1(%r14),%r15d
  mov    %r15d,%edi
  call   <fls@plt>
  mov    %r15d,%edi
  mov    %eax,%ebp
  mov    %eax,%r13d
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  mov    %ebp,%esi
  call   <highbits@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <ipow@plt>
  mov    %r13d,%edi
  mov    %eax,%ebp
  call   <bytes@plt>
  lea    0x1(%rbx),%edi
  mov    %eax,%r13d
  call   <vebsize>
  mov    %ebp,%edi
  imul   %ebx,%ebp
  lea    (%rax,%r13,2),%r13d
  call   <vebsize>
  imul   %eax,%ebx
  sub    %ebp,%r14d
  add    %r13d,%ebx
  add    %ebx,%r12d
  cmp    $0x20,%r14d
  ja     L1
L0:
  mov    %r14d,%edi
  call   <bytes@plt>
  add    $0x8,%rsp
  pop    %rbx
  add    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint vebsize(uint M) {
  if (M <= sizeof(uint) * 8)
    return bytes(M);
  uint k = fls(M - 1);
  uint m = highbits(M - 1, k / 2) + 1;
  uint n = ipow(k / 2);
  return 2 * bytes(k) + vebsize(m) + (m - 1) * vebsize(n) + vebsize(M - (m - 1) * n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x58(%rbp)
  jmp    L48
L15:
  mov    -0x58(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x58(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  addl   $0x1,-0x58(%rbp)
L48:
  cmpl   $0xe,-0x58(%rbp)
  jle    L15
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <printHeader@plt>
  mov    -0x5c(%rbp),%esi
  lea    -0x50(%rbp),%rax
  mov    $0xe,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <binarySearch@plt>
  mov    %eax,-0x54(%rbp)
  cmpl   $0xffffffff,-0x54(%rbp)
  je     L8
  mov    -0x5c(%rbp),%eax
  mov    -0x54(%rbp),%edx
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L8:
  mov    -0x5c(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D34
type_infered: string
name: retrieve_data
arguments: tag: D25
type_infered: string
name: retrieve_data
arguments: tag: D38
type_infered: string
name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D34: Enter a number between 0 and 28: 

tool: D25: %d

tool: D38: 
%d found in array element %d


tool: D2: 
%d not found


assistant: ```c
int main(void) {
  int a[15];
  int i;
  int key;
  int result;
  for (i = 0; i < 15; i++) {
    a[i] = 2 * i;
  }
  printf("Enter a number between 0 and 28: ");
  scanf("%d", &key);
  printHeader();
  result = binarySearch(a, key, 0, 15 - 1);
  if (result != -1) {
    printf("\n%d found in array element %d\n", key, result);
  } else {
    printf("\n%d not found\n", key);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x4c(%rsp),%rcx
  mov    $0x0,%edx
L10:
  mov    %edx,(%rax)
  add    $0x2,%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L10
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <printHeader@plt>
  lea    0x10(%rsp),%rdi
  mov    $0xe,%ecx
  mov    $0x0,%edx
  mov    0xc(%rsp),%esi
  call   <binarySearch@plt>
  cmp    $0xffffffff,%eax
  je     L25
  mov    %eax,%edx
  mov    0xc(%rsp),%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x68,%rsp
  ret
L25:
  mov    0xc(%rsp),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string
name: unpack_data
arguments: tag: D34
type_infered: string
name: unpack_data
arguments: tag: D31
type_infered: string
name: unpack_data
arguments: tag: D5
type_infered: string

tool: D2: Enter a number between 0 and 28: 

tool: D34: %d

tool: D31: 
%d found in array element %d


tool: D5: 
%d not found


assistant: ```c
int main(void) {
  int a[15];
  int i;
  int key;
  int result;
  for (i = 0; i < 15; i++) {
    a[i] = 2 * i;
  }
  printf("Enter a number between 0 and 28: ");
  scanf("%d", &key);
  printHeader();
  result = binarySearch(a, key, 0, 15 - 1);
  if (result != -1) {
    printf("\n%d found in array element %d\n", key, result);
  } else {
    printf("\n%d not found\n", key);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x4c(%rsp),%rcx
  mov    %rbp,%rax
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    $0x2,%edx
  cmp    %rcx,%rax
  jne    L2
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <printHeader@plt>
  mov    0xc(%rsp),%esi
  xor    %edx,%edx
  mov    $0xe,%ecx
  mov    %rbp,%rdi
  call   <binarySearch@plt>
  mov    0xc(%rsp),%esi
  mov    %eax,%edx
  cmp    $0xffffffff,%eax
  je     L7
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L34:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L34
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D31
type: string
name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D26
type: string

tool: D31: Enter a number between 0 and 28: 

tool: D23: %d

tool: D2: 
%d found in array element %d


tool: D26: 
%d not found


assistant: ```c
int main(void) {
  int a[15];
  int i;
  int key;
  int result;
  for (i = 0; i < 15; i++) {
    a[i] = 2 * i;
  }
  printf("Enter a number between 0 and 28: ");
  scanf("%d", &key);
  printHeader();
  result = binarySearch(a, key, 0, 15 - 1);
  if (result != -1) {
    printf("\n%d found in array element %d\n", key, result);
  } else {
    printf("\n%d not found\n", key);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  movdqa D27(%rip),%xmm0
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D44(%rip),%rax
  movl   $0x1c,0x48(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D34(%rip),%xmm0
  mov    %rax,0x40(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x20(%rsp)
  movdqa D41(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <printHeader@plt>
  mov    0xc(%rsp),%esi
  xor    %edx,%edx
  lea    0x10(%rsp),%rdi
  mov    $0xe,%ecx
  call   <binarySearch@plt>
  cmp    $0xffffffff,%eax
  je     L23
  mov    0xc(%rsp),%esi
  mov    %eax,%edx
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L4:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L23:
  mov    0xc(%rsp),%esi
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D27
type: byte[16]
name: read_data
arguments: data_label: D17
type: string
name: read_data
arguments: data_label: D44
type: byte[8]
name: read_data
arguments: data_label: D34
type: byte[16]
name: read_data
arguments: data_label: D41
type: byte[16]
name: read_data
arguments: data_label: D18
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D68
type: string

tool: {"D27": [0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D17: Enter a number between 0 and 28: 

tool: {"D44": [0x18,0x00,0x00,0x00,0x1a,0x00,0x00,0x00]}

tool: {"D34": [0x08,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x0e,0x00,0x00,0x00]}

tool: {"D41": [0x10,0x00,0x00,0x00,0x12,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x16,0x00,0x00,0x00]}

tool: D18: %d

tool: D23: 
%d found in array element %d


tool: D68: 
%d not found


assistant: ```c
int main(void) {
  int a[15];
  int i;
  int key;
  int result;
  for (i = 0; i < 15; i++) {
    a[i] = 2 * i;
  }
  printf("Enter a number between 0 and 28: ");
  scanf("%d", &key);
  printHeader();
  result = binarySearch(a, key, 0, 15 - 1);
  if (result != -1) {
    printf("\n%d found in array element %d\n", key, result);
  } else {
    printf("\n%d not found\n", key);
  }
  return 0;
}
```