ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<stroperateur>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0xa8,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x30(%rsp),%r14
  lea    D2(%rip),%rsi
  mov    %rdx,0x10(%rsp)
  mov    %r14,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  call   <strcpy@plt>
  movslq %r12d,%rax
  add    %rax,%rbx
  movzbl (%rbx),%ecx
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%al
  jbe    L55
  cmp    $0x2f,%cl
  ja     L55
  movabs $0xaf0000000000,%rax
  shr    %cl,%rax
  mov    %eax,%edx
  and    $0x1,%edx
  test   $0x1,%al
  mov    $0x0,%eax
  cmove  %eax,%ecx
  jmp    L0
  nop
L55:
  xor    %ecx,%ecx
  xor    %edx,%edx
L0:
  mov    %cl,0x2c(%rsp)
  add    $0x1,%edx
  lea    -0x1(%r12),%ebp
  movabs $0x2b0000000000,%r13
  movb   $0x0,0x2d(%rsp)
  movslq %edx,%r15
  movb   $0x0,0x2f(%rsp)
  nopw   0x0(%rax,%rax,1)
L93:
  movzbl -0x1(%rbx,%r15,1),%eax
  lea    0x0(%rbp,%r15,1),%r8d
  mov    %al,0x2e(%rsp)
  cmp    $0x2a,%al
  je     L10
  cmp    $0x2f,%al
  je     L10
  cmp    $0x2d,%al
  ja     L90
  bt     %rax,%r13
  jae    L90
L10:
  movb   $0x0,0x2e(%rsp)
L84:
  mov    0x8(%rsp),%rdi
  mov    %r14,%rsi
  mov    %r8d,0x1c(%rsp)
  call   <strcpy@plt>
  mov    0x10(%rsp),%rdi
  lea    0x2c(%rsp),%rsi
  call   <strcpy@plt>
  mov    0x1c(%rsp),%r8d
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0xa8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L90:
  lea    0x2e(%rsp),%rsi
  mov    %r14,%rdi
  call   <strcat@plt>
  mov    %r15d,%r8d
  add    $0x1,%r15
  cmpb   $0x0,0x2e(%rsp)
  jne    L93
  add    %r12d,%r8d
  jmp    L84
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: 

assistant: ```c
int stroperateur(char chaine1[], char chaine2[], char chaineOP[], int ic) {
  char signe[2];
  char c[2];
  char strret[100];
  int ifunc;
  strcpy(strret, "");
  c[0] = chaine1[ic];
  if ((c[0] == '0') || (c[0] == '1') || (c[0] == '2') || (c[0] == '3') || (c[0] == '4') || (c[0] == '5') || (c[0] == '6') || (c[0] == '7') || (c[0] == '8') || (c[0] == '9')) {
    signe[0] = '\0';
    ifunc = 0;
  } else if ((c[0] == '*') || (c[0] == '/') || (c[0] == '+') || (c[0] == '-') || (c[0] == '(') || (c[0] == ')')) {
    signe[0] = c[0];
    ifunc = 1;
  } else {
    signe[0] = 0;
    ifunc = 0;
  }
  signe[1] = '\0';
  c[0] = 1;
  c[1] = 0;
  while (c[0] != 0) {
    c[0] = chaine1[ic + ifunc];
    if ((c[0] == '*') || (c[0] == '/') || (c[0] == '+') || (c[0] == '-') || (c[0] == '(') || (c[0] == ')')) {
      c[0] = 0;
    } else {
      strcat(strret, c);
      ifunc++;
    }
  }
  ifunc += ic;
  strcpy(chaine2, strret);
  strcpy(chaineOP, signe);
  return ifunc;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L8:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *sc = s;
  while (*sc != '\0') {
    sc++;
  }
  return sc - s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L14
  mov    %rdi,%rax
L7:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L7
L20:
  sub    %rdi,%rax
  ret
L14:
  mov    %rdi,%rax
  jmp    L20
```

assistant: ```c
size_t strlen(const char *s) {
  const char *sc = s;
  while (*sc != '\0') {
    sc++;
  }
  return sc - s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L14
  mov    %rdi,%rax
  nopl   0x0(%rax)
L11:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L11
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *sc = s;
  while (*sc != '\0') {
    sc++;
  }
  return sc - s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L5
  mov    %rdi,%rax
  nopl   0x0(%rax)
L15:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L15
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *sc = s;
  while (*sc != '\0') {
    sc++;
  }
  return sc - s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%r10d
  movslq %r10d,%rsi
  lea    0x0(,%rsi,4),%r13
  mov    %rsi,%rax
  imul   %rsi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L11:
  cmp    %rdx,%rsp
  je     L152
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L11
L152:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L114
  orq    $0x0,-0x8(%rsp,%rax,1)
L114:
  mov    %rsp,%rcx
  test   %r10d,%r10d
  jle    L171
  mov    %r13,%r11
  shr    $0x2,%r11
  lea    -0x1(%r10),%edi
  mov    %rcx,%r12
  mov    %rsi,%r9
  mov    $0x0,%r8d
  lea    0x4(%rcx),%rbx
  jmp    L8
L164:
  cmp    %edi,%r10d
  jle    L27
L50:
  mov    %r9,%rax
L122:
  mov    %eax,-0x4(%rcx,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rsi
  jne    L122
L27:
  sub    $0x1,%edi
  add    %r11,%r8
  sub    $0x1,%r9
  add    %r13,%rcx
  cmp    $0xffffffff,%edi
  je     L85
L8:
  lea    0x1(%rdi),%edx
  mov    %edi,%r15d
  test   %edi,%edi
  jle    L164
  lea    (%r12,%r8,4),%rax
  lea    -0x1(%rdi),%r14d
  add    %r8,%r14
  lea    (%rbx,%r14,4),%r14
L167:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r14,%rax
  jne    L167
  cmp    %r15d,%r10d
  jg     L50
  sub    $0x1,%edi
  add    %r11,%r8
  sub    $0x1,%r9
  add    %r13,%rcx
  jmp    L8
L99:
  mov    (%r12,%rbx,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,-0x3c(%rbp)
  jg     L99
L111:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r15d
  add    %r13,%r12
  cmp    %r15d,-0x3c(%rbp)
  jle    L171
L102:
  mov    $0x0,%ebx
  cmpl   $0x0,-0x3c(%rbp)
  jg     L99
  jmp    L111
L85:
  mov    $0x0,%r15d
  lea    D17(%rip),%r14
  jmp    L102
L171:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L112
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L112:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D13
type: string
name: retrieve_data
arguments: label: D17
type: string

tool: D13: %d

tool: D17: %d 

assistant: ```c
int main(void) {
  int n;
  scanf("%d", &n);
  int a[n][n];
  int i, j;
  for (i = 0; i < n; i++) {
    int t = n - i - 1;
    for (j = 0; j < t; j++) {
      a[i][j] = t + 1;
    }
    for (j = t; j < n; j++) {
      a[i][j] = j + 1;
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rsi
  mov    %rsp,%rcx
  mov    %rsi,%rax
  mov    %rsi,%r10
  lea    0x0(,%rsi,4),%r13
  imul   %rsi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L112
L124:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L124
L112:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L60
L86:
  mov    %rsp,%r12
  test   %r10d,%r10d
  jle    L94
  mov    %r13,%r11
  lea    -0x1(%r10),%r15d
  mov    %r12,%rcx
  mov    %rsi,%r8
  shr    $0x2,%r11
  xor    %edi,%edi
  lea    0x4(%r12),%rbx
  nopl   (%rax)
L26:
  lea    0x1(%r15),%edx
  mov    $0xffffffff,%r9d
  test   %r15d,%r15d
  je     L19
  lea    -0x1(%r15),%eax
  mov    %rax,%r9
  add    %rdi,%rax
  lea    (%rbx,%rax,4),%r14
  mov    %rcx,%rax
  nopl   0x0(%rax,%rax,1)
L126:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r14,%rax
  jne    L126
  cmp    %r15d,%r10d
  jle    L65
L19:
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %rax,%rdx
  mov    %eax,-0x4(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rsi
  jne    L39
L65:
  mov    %r9d,%r15d
  sub    $0x1,%r8
  add    %r13,%rcx
  add    %r11,%rdi
  cmp    $0xffffffff,%r9d
  jne    L26
  xor    %r15d,%r15d
  lea    D14(%rip),%r14
  nopl   (%rax)
L67:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L97:
  mov    (%r12,%rbx,4),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x3c(%rbp)
  jg     L97
  mov    $0xa,%edi
  add    $0x1,%r15d
  add    %r13,%r12
  call   <putchar@plt>
  cmp    %r15d,-0x3c(%rbp)
  jg     L67
L94:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L60:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L86
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string

tool: D13: %d

tool: D14: %d 

assistant: ```c
int main(void) {
  int n;
  scanf("%d", &n);
  int a[n][n];
  int i, j;
  for (i = 0; i < n; i++) {
    int t = n - i - 1;
    for (j = 0; j < t; j++) {
      a[i][j] = t + 1;
    }
    for (j = t; j < n; j++) {
      a[i][j] = j + 1;
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SetWaitTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  mov    $0x0,%esi
  mov    $0x468,%edi
  call   <RamWrite32A@plt>
  movzwl -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  cltq
  mov    %rax,%rsi
  mov    $0x46c,%edi
  call   <RamWrite32A@plt>
  nop
  leave
  ret
```

assistant: ```c
void SetWaitTime(unsigned short UsWaitTime) {
  RamWrite32A(0x0000 + 0x0468, 0);
  RamWrite32A(0x0004 + 0x0000 + 0x0468, (unsigned long)(20 * UsWaitTime));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SetWaitTime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%esi
  mov    $0x468,%edi
  call   <RamWrite32A@plt>
  movzwl %bx,%edi
  lea    (%rdi,%rdi,4),%esi
  shl    $0x2,%esi
  movslq %esi,%rsi
  mov    $0x46c,%edi
  call   <RamWrite32A@plt>
  pop    %rbx
  ret
```

assistant: ```c
void SetWaitTime(unsigned short UsWaitTime) {
  RamWrite32A(0x0000 + 0x0468, 0);
  RamWrite32A(0x0004 + 0x0000 + 0x0468, (unsigned long)(20 * UsWaitTime));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SetWaitTime>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %edi,%ebx
  mov    $0x468,%edi
  call   <RamWrite32A@plt>
  movzwl %bx,%edi
  pop    %rbx
  lea    (%rdi,%rdi,4),%esi
  mov    $0x46c,%edi
  shl    $0x2,%esi
  movslq %esi,%rsi
  jmp    1050 <RamWrite32A@plt>
```

assistant: ```c
void SetWaitTime(unsigned short UsWaitTime) {
  RamWrite32A(0x0000 + 0x0468, 0);
  RamWrite32A(0x0004 + 0x0000 + 0x0468, (unsigned long)(20 * UsWaitTime));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SetWaitTime>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %edi,%ebx
  mov    $0x468,%edi
  call   <RamWrite32A@plt>
  movzwl %bx,%edi
  pop    %rbx
  lea    (%rdi,%rdi,4),%esi
  mov    $0x46c,%edi
  shl    $0x2,%esi
  movslq %esi,%rsi
  jmp    1050 <RamWrite32A@plt>
```

assistant: ```c
void SetWaitTime(unsigned short UsWaitTime) {
  RamWrite32A(0x0000 + 0x0468, 0);
  RamWrite32A(0x0004 + 0x0000 + 0x0468, (unsigned long)(20 * UsWaitTime));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_hasht_insert_duplicate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <hasht_insert@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <hasht_insert@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_hasht_insert_duplicate(struct hasht *t, char *k, char *v) {
  hasht_insert(t, k, v);
  void *test_v = hasht_insert(t, k, v);
  assert(test_v == NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_hasht_insert_duplicate>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <hasht_insert@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <hasht_insert@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test_hasht_insert_duplicate(struct hasht *t, char *k, char *v) {
  hasht_insert(t, k, v);
  void *test_v = hasht_insert(t, k, v);
  assert(test_v == NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_hasht_insert_duplicate>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <hasht_insert@plt>
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <hasht_insert@plt>
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  sete   %dil
  jmp    1060 <assert@plt>
```

assistant: ```c
void test_hasht_insert_duplicate(struct hasht *t, char *k, char *v) {
  hasht_insert(t, k, v);
  void *test_v = hasht_insert(t, k, v);
  assert(test_v == NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_hasht_insert_duplicate>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <hasht_insert@plt>
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <hasht_insert@plt>
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  sete   %dil
  jmp    1060 <assert@plt>
```

assistant: ```c
void test_hasht_insert_duplicate(struct hasht *t, char *k, char *v) {
  hasht_insert(t, k, v);
  void *test_v = hasht_insert(t, k, v);
  assert(test_v == NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<output_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L56
L0:
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L50
  mov    $0x2e,%eax
  jmp    L32
L50:
  mov    $0x23,%eax
L32:
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x4f,-0x8(%rbp)
  jle    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L56:
  cmpl   $0x17,-0x4(%rbp)
  jle    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void output_map(unsigned map[24][80]) {
  int x, y;
  for (y = 0; y < 24; ++y) {
    for (x = 0; x < 80; ++x) {
      printf("%c", map[y][x] ? '.' : '#');
    }
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<output_map>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    0x140(%rdi),%rbp
  add    $0x1f40,%r12
L6:
  lea    -0x140(%rbp),%rbx
L14:
  cmpl   $0x1,(%rbx)
  sbb    %edi,%edi
  and    $0xfffffff5,%edi
  add    $0x2e,%edi
  call   <putchar@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x140,%rbp
  cmp    %r12,%rbp
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void output_map(unsigned map[24][80]) {
  int x, y;
  for (y = 0; y < 24; ++y) {
    for (x = 0; x < 80; ++x) {
      printf("%c", map[y][x] ? '.' : '#');
    }
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<output_map>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  add    $0x1f40,%r12
  lea    0x140(%rdi),%rbp
  push   %rbx
  nopl   0x0(%rax)
L4:
  lea    -0x140(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  cmpl   $0x1,(%rbx)
  sbb    %edi,%edi
  add    $0x4,%rbx
  and    $0xfffffff5,%edi
  add    $0x2e,%edi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L11
  mov    $0xa,%edi
  lea    0x140(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r12,%rbp
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void output_map(unsigned map[24][80]) {
  int x, y;
  for (y = 0; y < 24; ++y) {
    for (x = 0; x < 80; ++x) {
      printf("%c", map[y][x] ? '.' : '#');
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<output_map>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  add    $0x1f40,%r12
  lea    0x140(%rdi),%rbp
  push   %rbx
  nopl   0x0(%rax)
L3:
  lea    -0x140(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L39:
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L14
  mov    $0x2e,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L39
L41:
  mov    $0xa,%edi
  add    $0x140,%rbp
  call   <putchar@plt>
  cmp    %r12,%rbp
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  mov    $0x23,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L39
  jmp    L41
```

assistant: ```c
void output_map(unsigned map[24][80]) {
  int x, y;
  for (y = 0; y < 24; ++y) {
    for (x = 0; x < 80; ++x) {
      printf("%c", map[y][x] ? '.' : '#');
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<userlock_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  nop
L2:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void userlock_wait(volatile const int *userlock) {
  while (1 == *userlock)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<userlock_wait>:
  endbr64
L7:
  mov    (%rdi),%eax
  cmp    $0x1,%eax
  je     L7
  ret
```

assistant: ```c
void userlock_wait(volatile const int *userlock) {
  while (1 == *userlock)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<userlock_wait>:
  endbr64
  nopl   0x0(%rax)
L8:
  mov    (%rdi),%eax
  cmp    $0x1,%eax
  je     L8
  ret
```

assistant: ```c
void userlock_wait(volatile const int *userlock) {
  while (1 == *userlock)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<userlock_wait>:
  endbr64
  nopl   0x0(%rax)
L9:
  mov    (%rdi),%eax
  cmp    $0x1,%eax
  je     L9
  ret
```

assistant: ```c
void userlock_wait(volatile const int *userlock) {
  while (1 == *userlock)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<runTests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%ebx
  mov    %edi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <testList@plt>
  movq   $0x0,-0x68(%rbp)
  mov    $0x1,%r15d
  jmp    L42
L49:
  mov    -0x60(%rbp),%rsi
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L2
  mov    %rsi,%rax
  and    $0xfff,%eax
  orq    $0x0,-0x8(%rsp,%rax,1)
L2:
  mov    %rsp,%r13
  cmpl   $0x0,-0x44(%rbp)
  jle    L86
  mov    %r13,%rbx
  mov    -0x58(%rbp),%rax
  lea    0x4(%r13,%rax,1),%r12
L52:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L52
L86:
  mov    -0x48(%rbp),%edx
  mov    -0x44(%rbp),%esi
  mov    %r13,%rdi
  call   <testList@plt>
  mov    %r15,%rsp
  sub    $0x1,%r14d
  je     L61
L24:
  mov    %rsp,%r15
  mov    %rsp,%rax
  sub    -0x50(%rbp),%rax
L70:
  cmp    %rax,%rsp
  je     L49
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L70
L61:
  mov    -0x44(%rbp),%r15d
  mov    %r15d,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r15d
  cmp    $0xa,%r15d
  je     L64
L42:
  mov    %r15d,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  add    $0x4,%rax
  mov    %rax,-0x68(%rbp)
  mov    $0x5,%r14d
  add    $0xf,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  shl    $0x4,%rax
  mov    %rax,-0x60(%rbp)
  and    $0xfffffffffffff000,%rax
  mov    %rax,-0x50(%rbp)
  mov    %r15d,-0x44(%rbp)
  jmp    L24
L64:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D1
type: string
name: retrieve_data
arguments: data_label: D8
type: string

tool: D5: ** Testing no item list.

tool: D1: ** Passed all tests for %d item lists.


tool: D8: ** Testing %d item lists.


assistant: ```c
void runTests(int partTwo) {
  printf("** Testing no item list.\n");
  testList(NULL, 0, partTwo);
  int num;
  int t;
  for (num = 1; num < 10; num++) {
    printf("** Testing %d item lists.\n", num);
    for (t = 0; t < 5; t++) {
      int arr[num];
      int i;
      for (i = 0; i < num; i++) {
        arr[i] = rand() % 1000;
      }
      testList(arr, num, partTwo);
    }
    printf("** Passed all tests for %d item lists.\n", num);
  }
}
```