ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ret_long>:
  endbr64
  push   %rbx
  lea    (%rdi,%rsi,1),%rbx
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: // return %ld, %lX


assistant: ```c
long ret_long(long a, long b) {
  long ret = a + b;
  unsigned long *ul;
  ul = (unsigned long *)&ret;
  printf("// return %ld, %lX\n", ret, *ul);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ret_long>:
  endbr64
  push   %r12
  lea    (%rdi,%rsi,1),%r12
  lea    D7(%rip),%rdi
  mov    %r12,%rdx
  mov    %r12,%rsi
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D7: // return %ld, %lX


assistant: ```c
long ret_long(long a, long b) {
  long ret = a + b;
  unsigned long *ul;
  ul = (unsigned long *)&ret;
  printf("// return %ld, %lX\n", ret, *ul);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ret_long>:
  endbr64
  push   %r12
  lea    (%rdi,%rsi,1),%r12
  lea    D2(%rip),%rdi
  mov    %r12,%rdx
  mov    %r12,%rsi
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: // return %ld, %lX


assistant: ```c
long ret_long(long a, long b) {
  long ret = a + b;
  unsigned long *ul;
  ul = (unsigned long *)&ret;
  printf("// return %ld, %lX\n", ret, *ul);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
```

assistant: ```c
int g(char *x) {
  asm("g_label: .globl g_label");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<g>:
  endbr64
```

assistant: ```c
int g(char *x) {
  asm("g_label: .globl g_label");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<g>:
  endbr64
```

assistant: ```c
int g(char *x) {
  asm("g_label: .globl g_label");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<g>:
  endbr64
```

assistant: ```c
int g(char *x) {
  asm("g_label: .globl g_label");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tm_to_beats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  movsd  0x8(%rax),%xmm2
  movsd  D2(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  movsd  0x10(%rax),%xmm2
  movsd  D7(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D2
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D7
type_guessed: byte[8]

tool: {"D3": [0x55,0x55,0x55,0x55,0x55,0xd5,0x44,0x40]}

tool: {"D2": [0x8e,0xe3,0x38,0x8e,0xe3,0x38,0xe6,0x3f]}

tool: {"D7": [0x42,0x7b,0x09,0xed,0x25,0xb4,0x87,0x3f]}

assistant: ```c
double tm_to_beats(struct tm *t) {
  double beats;
  beats = t->tm_hour * (1000.0 / 24.0) + t->tm_min * (1000.0 / (24.0 * 60.0)) + t->tm_sec * (1000.0 / (24.0 * 60.0 * 60.0));
  return beats;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tm_to_beats>:
  endbr64
  movsd  D25(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  movsd  D15(%rip),%xmm1
  mulsd  0x8(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  D14(%rip),%xmm1
  mulsd  0x10(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
type_infered: byte[8]
name: disassemble_data
arguments: label: D15
type_infered: byte[8]
name: disassemble_data
arguments: label: D14
type_infered: byte[8]

tool: {"D25": [0x55,0x55,0x55,0x55,0x55,0xd5,0x44,0x40]}

tool: {"D15": [0x8e,0xe3,0x38,0x8e,0xe3,0x38,0xe6,0x3f]}

tool: {"D14": [0x42,0x7b,0x09,0xed,0x25,0xb4,0x87,0x3f]}

assistant: ```c
double tm_to_beats(struct tm *t) {
  double beats;
  beats = t->tm_hour * (1000.0 / 24.0) + t->tm_min * (1000.0 / (24.0 * 60.0)) + t->tm_sec * (1000.0 / (24.0 * 60.0 * 60.0));
  return beats;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tm_to_beats>:
  endbr64
  movsd  D17(%rip),%xmm0
  movsd  D4(%rip),%xmm1
  mulsd  (%rdi),%xmm0
  mulsd  0x8(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  D11(%rip),%xmm1
  mulsd  0x10(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D4
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D11
type_guessed: byte[8]

tool: {"D17": [0x55,0x55,0x55,0x55,0x55,0xd5,0x44,0x40]}

tool: {"D4": [0x8e,0xe3,0x38,0x8e,0xe3,0x38,0xe6,0x3f]}

tool: {"D11": [0x42,0x7b,0x09,0xed,0x25,0xb4,0x87,0x3f]}

assistant: ```c
double tm_to_beats(struct tm *t) {
  double beats;
  beats = t->tm_hour * (1000.0 / 24.0) + t->tm_min * (1000.0 / (24.0 * 60.0)) + t->tm_sec * (1000.0 / (24.0 * 60.0 * 60.0));
  return beats;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tm_to_beats>:
  endbr64
  movsd  D22(%rip),%xmm0
  movsd  D2(%rip),%xmm1
  mulsd  (%rdi),%xmm0
  mulsd  0x8(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  D10(%rip),%xmm1
  mulsd  0x10(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D2
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D10
datatype: byte[8]

tool: {"D22": [0x55,0x55,0x55,0x55,0x55,0xd5,0x44,0x40]}

tool: {"D2": [0x8e,0xe3,0x38,0x8e,0xe3,0x38,0xe6,0x3f]}

tool: {"D10": [0x42,0x7b,0x09,0xed,0x25,0xb4,0x87,0x3f]}

assistant: ```c
double tm_to_beats(struct tm *t) {
  double beats;
  beats = t->tm_hour * (1000.0 / 24.0) + t->tm_min * (1000.0 / (24.0 * 60.0)) + t->tm_sec * (1000.0 / (24.0 * 60.0 * 60.0));
  return beats;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cp(char *in, char *out, int size) {
  for (int i = 0; i < size; ++i)
    out[i] = in[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cp>:
  endbr64
  test   %edx,%edx
  jle    L12
  mov    %edx,%edx
  mov    $0x0,%eax
L2:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L2
L12:
  ret
```

assistant: ```c
void cp(char *in, char *out, int size) {
  for (int i = 0; i < size; ++i)
    out[i] = in[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cp>:
  endbr64
  test   %edx,%edx
  jle    L16
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L3:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L16:
  ret
```

assistant: ```c
void cp(char *in, char *out, int size) {
  for (int i = 0; i < size; ++i)
    out[i] = in[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cp>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L48
  lea    0x1(%rdi),%r9
  mov    %rsi,%rdi
  lea    -0x1(%rdx),%eax
  mov    %edx,%r8d
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L11
  cmp    $0x6,%eax
  jbe    L11
  cmp    $0xe,%eax
  jbe    L78
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L99:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L99
  mov    %edx,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L48
  mov    %edx,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L44
L39:
  mov    (%rcx,%rdi,1),%r9
  mov    %r9,(%rsi,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%r8d
  je     L48
L44:
  movslq %eax,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L48
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jle    L48
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jle    L48
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jle    L48
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jle    L48
  movslq %edi,%rdi
  add    $0x6,%eax
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  cmp    %eax,%edx
  jle    L48
  cltq
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L47:
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L47
L48:
  ret
L78:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L39
```

assistant: ```c
void cp(char *in, char *out, int size) {
  for (int i = 0; i < size; ++i)
    out[i] = in[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_correct_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L37
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L10
L37:
  mov    $0x1,%eax
  jmp    L38
L10:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    $0x0,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int is_correct_input(char *egn) {
  int counter = 0;
  while (egn[counter] != '\0') {
    if (egn[counter] < 48 || egn[counter] > 57) {
      return 1;
    }
    counter++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_correct_input>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
  add    $0x1,%rdi
L9:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L23
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L9
  mov    $0x0,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_correct_input(char *egn) {
  int counter = 0;
  while (egn[counter] != '\0') {
    if (egn[counter] < 48 || egn[counter] > 57) {
      return 1;
    }
    counter++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_correct_input>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  add    $0x1,%rdi
  jmp    L27
  nopl   0x0(%rax)
L8:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L19
L27:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L8
  mov    $0x1,%eax
  ret
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_correct_input(char *egn) {
  int counter = 0;
  while (egn[counter] != '\0') {
    if (egn[counter] < 48 || egn[counter] > 57) {
      return 1;
    }
    counter++;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_correct_input>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L35
  add    $0x1,%rdi
  jmp    L15
  nopl   0x0(%rax)
L18:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L35
L15:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L18
  mov    $0x1,%eax
  ret
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_correct_input(char *egn) {
  int counter = 0;
  while (egn[counter] != '\0') {
    if (egn[counter] < 48 || egn[counter] > 57) {
      return 1;
    }
    counter++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<show_battery>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L6:
  mov    $0x0,%eax
  call   <adc_read@plt>
  imul   $0x3e8,%eax,%eax
  movslq %eax,%rdx
  imul   $0xc0784b3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <delay_ms@plt>
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D2: Battery: %d


assistant: ```c
void show_battery(int count, int delay) {
  int i;
  int val;
  for (i = 0; i < count; i++) {
    val = (adc_read() * 1000) / 681;
    printf("Battery: %d\n", val);
    delay_ms(delay);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<show_battery>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  lea    D4(%rip),%r13
L16:
  mov    $0x0,%eax
  call   <adc_read@plt>
  imul   $0x3e8,%eax,%eax
  movslq %eax,%rsi
  imul   $0xc0784b3,%rsi,%rsi
  sar    $0x25,%rsi
  sar    $0x1f,%eax
  sub    %eax,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <delay_ms@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: Battery: %d


assistant: ```c
void show_battery(int count, int delay) {
  int i;
  int val;
  for (i = 0; i < count; i++) {
    val = (adc_read() * 1000) / 681;
    printf("Battery: %d\n", val);
    delay_ms(delay);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<show_battery>:
  endbr64
  test   %edi,%edi
  jle    L1
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
L0:
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <adc_read@plt>
  mov    %r12,%rdi
  imul   $0x3e8,%eax,%eax
  movslq %eax,%rsi
  sar    $0x1f,%eax
  imul   $0xc0784b3,%rsi,%rsi
  sar    $0x25,%rsi
  sub    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <delay_ms@plt>
  cmp    %r13d,%ebx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: Battery: %d


assistant: ```c
void show_battery(int count, int delay) {
  int i;
  int val;
  for (i = 0; i < count; i++) {
    val = (adc_read() * 1000) / 681;
    printf("Battery: %d\n", val);
    delay_ms(delay);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<show_battery>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
L0:
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <adc_read@plt>
  mov    %r12,%rdi
  imul   $0x3e8,%eax,%eax
  movslq %eax,%rsi
  sar    $0x1f,%eax
  imul   $0xc0784b3,%rsi,%rsi
  sar    $0x25,%rsi
  sub    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <delay_ms@plt>
  cmp    %r13d,%ebx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: Battery: %d


assistant: ```c
void show_battery(int count, int delay) {
  int i;
  int val;
  for (i = 0; i < count; i++) {
    val = (adc_read() * 1000) / 681;
    printf("Battery: %d\n", val);
    delay_ms(delay);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<startend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L32
  cmpl   $0x0,-0x14(%rbp)
  je     L49
  mov    -0x20(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L27
L49:
  mov    -0x28(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L27
L32:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L38
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L31
  mov    -0x30(%rbp),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rax)
L31:
  mov    $0x1,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int startend(int myid, int nodes, int i, int totalsize, int *start, int *end) {
  int block_size;
  block_size = (totalsize - i) / nodes;
  if ((totalsize - i) <= nodes) {
    if (myid != 0) {
      *start = totalsize + 2;
      *end = totalsize + 1;
      return 1;
    } else {
      *start = i;
      *end = totalsize;
      return 1;
    }
  }
  if ((totalsize - i) % nodes != 0)
    block_size++;
  *start = myid * block_size + i;
  *end = *start + block_size;
  if (*end > totalsize)
    *end = totalsize;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<startend>:
  endbr64
  mov    %edx,%r10d
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    %esi,%eax
  jg     L22
  test   %edi,%edi
  je     L12
  lea    0x2(%rcx),%eax
  mov    %eax,(%r8)
  add    $0x1,%ecx
  mov    %ecx,(%r9)
  jmp    L24
L12:
  mov    %edx,(%r8)
  mov    %ecx,(%r9)
  jmp    L24
L22:
  cltd
  idiv   %esi
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  imul   %eax,%edi
  add    %r10d,%edi
  mov    %edi,(%r8)
  add    %edi,%eax
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%r9)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int startend(int myid, int nodes, int i, int totalsize, int *start, int *end) {
  int block_size;
  block_size = (totalsize - i) / nodes;
  if ((totalsize - i) <= nodes) {
    if (myid != 0) {
      *start = totalsize + 2;
      *end = totalsize + 1;
      return 1;
    } else {
      *start = i;
      *end = totalsize;
      return 1;
    }
  }
  if ((totalsize - i) % nodes != 0)
    block_size++;
  *start = myid * block_size + i;
  *end = *start + block_size;
  if (*end > totalsize)
    *end = totalsize;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<startend>:
  endbr64
  mov    %ecx,%eax
  mov    %edx,%r10d
  sub    %edx,%eax
  cmp    %esi,%eax
  jg     L16
  test   %edi,%edi
  je     L6
  lea    0x2(%rcx),%eax
  add    $0x1,%ecx
  mov    %eax,(%r8)
  mov    $0x1,%eax
  mov    %ecx,(%r9)
  ret
  nopl   (%rax)
L16:
  cltd
  idiv   %esi
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  imul   %eax,%edi
  add    %r10d,%edi
  add    %edi,%eax
  mov    %edi,(%r8)
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%r9)
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %edx,(%r8)
  mov    $0x1,%eax
  mov    %ecx,(%r9)
  ret
```

assistant: ```c
int startend(int myid, int nodes, int i, int totalsize, int *start, int *end) {
  int block_size;
  block_size = (totalsize - i) / nodes;
  if ((totalsize - i) <= nodes) {
    if (myid != 0) {
      *start = totalsize + 2;
      *end = totalsize + 1;
      return 1;
    } else {
      *start = i;
      *end = totalsize;
      return 1;
    }
  }
  if ((totalsize - i) % nodes != 0)
    block_size++;
  *start = myid * block_size + i;
  *end = *start + block_size;
  if (*end > totalsize)
    *end = totalsize;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<startend>:
  endbr64
  mov    %ecx,%eax
  mov    %edx,%r10d
  sub    %edx,%eax
  cmp    %esi,%eax
  jg     L19
  test   %edi,%edi
  je     L16
  lea    0x2(%rcx),%eax
  add    $0x1,%ecx
  mov    %eax,(%r8)
  mov    $0x1,%eax
  mov    %ecx,(%r9)
  ret
  nopl   (%rax)
L19:
  cltd
  idiv   %esi
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  imul   %eax,%edi
  add    %r10d,%edi
  add    %edi,%eax
  mov    %edi,(%r8)
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%r9)
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %edx,(%r8)
  mov    $0x1,%eax
  mov    %ecx,(%r9)
  ret
```

assistant: ```c
int startend(int myid, int nodes, int i, int totalsize, int *start, int *end) {
  int block_size;
  block_size = (totalsize - i) / nodes;
  if ((totalsize - i) <= nodes) {
    if (myid != 0) {
      *start = totalsize + 2;
      *end = totalsize + 1;
      return 1;
    } else {
      *start = i;
      *end = totalsize;
      return 1;
    }
  }
  if ((totalsize - i) % nodes != 0)
    block_size++;
  *start = myid * block_size + i;
  *end = *start + block_size;
  if (*end > totalsize)
    *end = totalsize;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<max_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L10
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L10:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max_right(int array[], int size, int pos) {
  int max = 0;
  for (int i = pos + 1; i < size; i++) {
    if (array[i] > max)
      max = array[i];
  }
  return max;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<max_right>:
  endbr64
  add    $0x1,%edx
  cmp    %esi,%edx
  jge    L14
  movslq %edx,%rdx
  mov    $0x0,%eax
L5:
  mov    (%rdi,%rdx,4),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L5
  ret
L14:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int max_right(int array[], int size, int pos) {
  int max = 0;
  for (int i = pos + 1; i < size; i++) {
    if (array[i] > max)
      max = array[i];
  }
  return max;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max_right>:
  endbr64
  add    $0x1,%edx
  cmp    %esi,%edx
  jge    L7
  movslq %edx,%rdx
  xor    %eax,%eax
L19:
  mov    (%rdi,%rdx,4),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L19
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int max_right(int array[], int size, int pos) {
  int max = 0;
  for (int i = pos + 1; i < size; i++) {
    if (array[i] > max)
      max = array[i];
  }
  return max;
}
```