ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<initializeData>:
  endbr64
  mov    %esi,%r8d
  mov    %edx,%r9d
  test   %esi,%esi
  jle    L1
  mov    %edx,%eax
  imul   %edx,%eax
  cltd
  idiv   %esi
  mov    %edx,%r10d
  mov    %rdi,%rsi
  lea    -0x1(%r8),%eax
  lea    0x4(%rdi,%rax,4),%rdi
  mov    $0x0,%ecx
L8:
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  add    %r10d,%edx
  mov    %edx,(%rsi)
  add    %r9d,%ecx
  add    $0x4,%rsi
  cmp    %rdi,%rsi
  jne    L8
L1:
  ret
```

assistant: ```c
void initializeData(int *table, int size, int seed) {
  for (int i = 0; i < size; i++) {
    table[i] = (seed * seed) % size + (i * seed) % size;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<initializeData>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L15
  mov    %edx,%eax
  xor    %ecx,%ecx
  imul   %edx,%eax
  cltd
  idiv   %esi
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r9
  mov    %edx,%r10d
L13:
  mov    %ecx,%eax
  add    $0x4,%rdi
  add    %r8d,%ecx
  cltd
  idiv   %esi
  add    %r10d,%edx
  mov    %edx,-0x4(%rdi)
  cmp    %r9,%rdi
  jne    L13
L15:
  ret
```

assistant: ```c
void initializeData(int *table, int size, int seed) {
  for (int i = 0; i < size; i++) {
    table[i] = (seed * seed) % size + (i * seed) % size;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<initializeData>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L7
  mov    %edx,%eax
  xor    %ecx,%ecx
  imul   %edx,%eax
  cltd
  idiv   %esi
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r9
  mov    %edx,%r10d
L13:
  mov    %ecx,%eax
  add    $0x4,%rdi
  add    %r8d,%ecx
  cltd
  idiv   %esi
  add    %r10d,%edx
  mov    %edx,-0x4(%rdi)
  cmp    %r9,%rdi
  jne    L13
L7:
  ret
```

assistant: ```c
void initializeData(int *table, int size, int seed) {
  for (int i = 0; i < size; i++) {
    table[i] = (seed * seed) % size + (i * seed) % size;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gf_split_path_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L24
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    -0x28(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  je     L19
  addq   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strndup@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: \/

assistant: ```c
void gf_split_path_file(char **p, char **f, char *pf) {
  char *slash = pf, *next;
  while ((next = strpbrk(slash + 1, "\\/")))
    slash = next;
  if (pf != slash)
    slash++;
  *p = strndup(pf, slash - pf);
  *f = strdup(slash);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gf_split_path_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rdx,%rax
  lea    D1(%rip),%r12
L3:
  lea    0x1(%rax),%rbx
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L3
  cmp    %r13,%rbp
  cmove  %r13,%rbx
  mov    %ebx,%esi
  sub    %r13d,%esi
  mov    %r13,%rdi
  call   <strndup@plt>
  mov    %rax,(%r15)
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: \/

assistant: ```c
void gf_split_path_file(char **p, char **f, char *pf) {
  char *slash = pf, *next;
  while ((next = strpbrk(slash + 1, "\\/")))
    slash = next;
  if (pf != slash)
    slash++;
  *p = strndup(pf, slash - pf);
  *f = strdup(slash);
}
```
user: What is the c source code of the assembly code below?

```asm
<gf_split_path_file>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L2:
  lea    0x1(%rax),%r15
  mov    %rbp,%rsi
  mov    %rax,%rbx
  mov    %r15,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L2
  cmp    %r12,%rbx
  mov    %r12,%rdi
  cmove  %r12,%r15
  mov    %r15d,%esi
  sub    %r12d,%esi
  call   <strndup@plt>
  mov    %r15,%rdi
  mov    %rax,(%r14)
  call   <strdup@plt>
  mov    %rax,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: D8: \/

assistant: ```c
void gf_split_path_file(char **p, char **f, char *pf) {
  char *slash = pf, *next;
  while ((next = strpbrk(slash + 1, "\\/")))
    slash = next;
  if (pf != slash)
    slash++;
  *p = strndup(pf, slash - pf);
  *f = strdup(slash);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gf_split_path_file>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L5:
  lea    0x1(%rax),%r15
  mov    %rbp,%rsi
  mov    %rax,%rbx
  mov    %r15,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L5
  cmp    %r12,%rbx
  mov    %r12,%rdi
  cmove  %r12,%r15
  mov    %r15d,%esi
  sub    %r12d,%esi
  call   <strndup@plt>
  mov    %r15,%rdi
  mov    %rax,(%r14)
  call   <strdup@plt>
  mov    %rax,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0: \/

assistant: ```c
void gf_split_path_file(char **p, char **f, char *pf) {
  char *slash = pf, *next;
  while ((next = strpbrk(slash + 1, "\\/")))
    slash = next;
  if (pf != slash)
    slash++;
  *p = strndup(pf, slash - pf);
  *f = strdup(slash);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test23>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test23(int a, int b, int c, int d) {
  int x = a != b;
  int y = c != 0;
  return x + y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test23>:
  endbr64
  cmp    %esi,%edi
  setne  %al
  movzbl %al,%eax
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int test23(int a, int b, int c, int d) {
  int x = a != b;
  int y = c != 0;
  return x + y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test23>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  setne  %al
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int test23(int a, int b, int c, int d) {
  int x = a != b;
  int y = c != 0;
  return x + y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test23>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  setne  %al
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int test23(int a, int b, int c, int d) {
  int x = a != b;
  int y = c != 0;
  return x + y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L6
L23:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <prime@plt>
  cmp    $0x1,%eax
  jne    L36
  mov    -0x10(%rbp),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L36:
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L23
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string
name: retrieve_data
arguments: data_tag: D47
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D33
data_type: string

tool: D1: Input m: 

tool: D47: %d

tool: D19: Input n: 

tool: D33: count=%d, sum=%d

assistant: ```c
int main() {
  int m, n, sum, i, count;
  int prime(int i);
  printf("Input m: ");
  scanf("%d", &m);
  printf("Input n: ");
  scanf("%d", &n);
  sum = count = 0;
  for (i = m; i <= n; i++) {
    if (prime(i) == 1) {
      sum = sum + i;
      count++;
    }
  }
  printf("count=%d, sum=%d", count, sum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L28
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L26
L44:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L6
L26:
  mov    %ebx,%edi
  call   <prime@plt>
  cmp    $0x1,%eax
  jne    L44
  add    %ebx,%r12d
  add    $0x1,%ebp
  jmp    L44
L28:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L6:
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D34
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string
name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D10
type_guessed: string

tool: D34: Input m: 

tool: D12: %d

tool: D8: Input n: 

tool: D10: count=%d, sum=%d

assistant: ```c
int main() {
  int m, n, sum, i, count;
  int prime(int i);
  printf("Input m: ");
  scanf("%d", &m);
  printf("Input n: ");
  scanf("%d", &n);
  sum = count = 0;
  for (i = m; i <= n; i++) {
    if (prime(i) == 1) {
      sum = sum + i;
      count++;
    }
  }
  printf("count=%d, sum=%d", count, sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  xor    %ebp,%ebp
  call   <scanf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L7
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%edi
  call   <prime@plt>
  cmp    $0x1,%eax
  jne    L5
  add    %ebx,%r12d
  add    $0x1,%ebp
L5:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L13
L7:
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D15(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D32
datatype: string
name: extract_symbolic_data
arguments: label: D15
datatype: string

tool: D23: Input m: 

tool: D6: %d

tool: D32: Input n: 

tool: D15: count=%d, sum=%d

assistant: ```c
int main() {
  int m, n, sum, i, count;
  int prime(int i);
  printf("Input m: ");
  scanf("%d", &m);
  printf("Input n: ");
  scanf("%d", &n);
  sum = count = 0;
  for (i = m; i <= n; i++) {
    if (prime(i) == 1) {
      sum = sum + i;
      count++;
    }
  }
  printf("count=%d, sum=%d", count, sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  xor    %ebp,%ebp
  call   <scanf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L14
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edi
  call   <prime@plt>
  cmp    $0x1,%eax
  jne    L24
  add    %ebx,%r12d
  add    $0x1,%ebp
L24:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L0
L14:
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D21(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D28
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string

tool: D17: Input m: 

tool: D28: %d

tool: D5: Input n: 

tool: D21: count=%d, sum=%d

assistant: ```c
int main() {
  int m, n, sum, i, count;
  int prime(int i);
  printf("Input m: ");
  scanf("%d", &m);
  printf("Input n: ");
  scanf("%d", &n);
  sum = count = 0;
  for (i = m; i <= n; i++) {
    if (prime(i) == 1) {
      sum = sum + i;
      count++;
    }
  }
  printf("count=%d, sum=%d", count, sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<simple_socket_connect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  mov    %rdi,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <inet_pton@plt>
  cmp    $0x1,%eax
  je     L64
  lea    0x30(%rsp),%rdx
  mov    %rbx,%rsi
  mov    D67(%rip),%rax
  mov    (%rax),%edi
  call   <inet_pton@plt>
  cmp    $0x1,%eax
  jne    L91
  mov    D67(%rip),%rax
  mov    (%rax),%r12d
  mov    %r12d,0x20(%rsp)
  mov    %ebp,%edi
  call   <htons@plt>
  mov    %rax,0x28(%rsp)
L109:
  mov    $0x0,%edx
  mov    D26(%rip),%rax
  mov    (%rax),%esi
  mov    %r12d,%edi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L10
  mov    D6(%rip),%rax
  cmp    %r12d,(%rax)
  je     L36
  mov    D67(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L57
  lea    0x20(%rsp),%rsi
  mov    $0x18,%edx
  mov    %ebx,%edi
  call   <connect@plt>
L52:
  test   %eax,%eax
  jne    L57
L59:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    %ebx,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L64:
  mov    D6(%rip),%rax
  mov    (%rax),%r12d
  mov    %r12d,(%rsp)
  mov    %ebp,%edi
  call   <htons@plt>
  mov    %rax,0x8(%rsp)
  jmp    L109
L36:
  mov    %rsp,%rsi
  mov    $0x18,%edx
  mov    %ebx,%edi
  call   <connect@plt>
  jmp    L52
L57:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xfffffffd,%ebx
  jmp    L59
L91:
  mov    $0xffffffff,%ebx
  jmp    L59
L10:
  mov    $0xfffffffe,%ebx
  jmp    L59
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int simple_socket_connect(const char *address, int port) {
  int family;
  int sock;
  struct sockaddr_in host;
  struct sockaddr_in6 host6;
  if (inet_pton(AF_INET, address, &host.sin_addr.s_addr) == 1) {
    family = AF_INET;
    host.sin_family = family;
    host.sin_port = htons(port);
  } else if (inet_pton(AF_INET6, address, &host6.sin6_addr.s6_addr) == 1) {
    family = AF_INET6;
    host6.sin6_family = family;
    host6.sin6_port = htons(port);
  } else {
    return -1;
  }
  if ((sock = socket(family, SOCK_STREAM, 0)) == -1) {
    return -2;
  }
  int cr = -1;
  if (family == AF_INET) {
    cr = connect(sock, (struct sockaddr *)(&host), sizeof(struct sockaddr_in));
  } else if (family == AF_INET6) {
    cr = connect(sock, (struct sockaddr *)(&host6), sizeof(struct sockaddr_in6));
  }
  if (cr != 0) {
    close(sock);
    return -3;
  }
  return sock;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simple_socket_connect>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    D17(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  mov    0x0(%rbp),%edi
  call   <inet_pton@plt>
  cmp    $0x1,%eax
  je     L64
  mov    D0(%rip),%rbx
  lea    0x30(%rsp),%rdx
  mov    %r12,%rsi
  mov    (%rbx),%edi
  call   <inet_pton@plt>
  cmp    $0x1,%eax
  jne    L111
  mov    (%rbx),%ebx
  mov    %r13d,%edi
  mov    %ebx,0x20(%rsp)
  call   <htons@plt>
  mov    %rax,0x28(%rsp)
L20:
  mov    D10(%rip),%rax
  xor    %edx,%edx
  mov    %ebx,%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L15
  cmp    %ebx,0x0(%rbp)
  je     L116
  mov    D0(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L90
  lea    0x20(%rsp),%rsi
  mov    $0x18,%edx
  mov    %r12d,%edi
  call   <connect@plt>
L26:
  test   %eax,%eax
  jne    L90
L54:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x48,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  mov    0x0(%rbp),%ebx
  mov    %r13d,%edi
  mov    %ebx,(%rsp)
  call   <htons@plt>
  mov    %rax,0x8(%rsp)
  jmp    L20
  nopl   (%rax)
L116:
  mov    %rsp,%rsi
  mov    $0x18,%edx
  mov    %eax,%edi
  call   <connect@plt>
  jmp    L26
  nopl   0x0(%rax)
L90:
  mov    %r12d,%edi
  mov    $0xfffffffd,%r12d
  call   <close@plt>
  jmp    L54
L111:
  mov    $0xffffffff,%r12d
  jmp    L54
L15:
  mov    $0xfffffffe,%r12d
  jmp    L54
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int simple_socket_connect(const char *address, int port) {
  int family;
  int sock;
  struct sockaddr_in host;
  struct sockaddr_in6 host6;
  if (inet_pton(AF_INET, address, &host.sin_addr.s_addr) == 1) {
    family = AF_INET;
    host.sin_family = family;
    host.sin_port = htons(port);
  } else if (inet_pton(AF_INET6, address, &host6.sin6_addr.s6_addr) == 1) {
    family = AF_INET6;
    host6.sin6_family = family;
    host6.sin6_port = htons(port);
  } else {
    return -1;
  }
  if ((sock = socket(family, SOCK_STREAM, 0)) == -1) {
    return -2;
  }
  int cr = -1;
  if (family == AF_INET) {
    cr = connect(sock, (struct sockaddr *)(&host), sizeof(struct sockaddr_in));
  } else if (family == AF_INET6) {
    cr = connect(sock, (struct sockaddr *)(&host6), sizeof(struct sockaddr_in6));
  }
  if (cr != 0) {
    close(sock);
    return -3;
  }
  return sock;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simple_socket_connect>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    D9(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  mov    0x0(%rbp),%edi
  call   <inet_pton@plt>
  cmp    $0x1,%eax
  je     L57
  mov    D16(%rip),%rbx
  lea    0x30(%rsp),%rdx
  mov    %r12,%rsi
  mov    (%rbx),%edi
  call   <inet_pton@plt>
  cmp    $0x1,%eax
  jne    L1
  mov    (%rbx),%ebx
  mov    %r13d,%edi
  mov    %ebx,0x20(%rsp)
  call   <htons@plt>
  mov    %rax,0x28(%rsp)
L106:
  mov    D5(%rip),%rax
  xor    %edx,%edx
  mov    %ebx,%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L49
  cmp    %ebx,0x0(%rbp)
  je     L82
  mov    D16(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L35
  lea    0x20(%rsp),%rsi
  mov    $0x18,%edx
  mov    %r12d,%edi
  call   <connect@plt>
L95:
  test   %eax,%eax
  jne    L35
L90:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x48,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    0x0(%rbp),%ebx
  mov    %r13d,%edi
  mov    %ebx,(%rsp)
  call   <htons@plt>
  mov    %rax,0x8(%rsp)
  jmp    L106
  nopl   (%rax)
L82:
  mov    %rsp,%rsi
  mov    $0x18,%edx
  mov    %eax,%edi
  call   <connect@plt>
  jmp    L95
  nopl   0x0(%rax)
L35:
  mov    %r12d,%edi
  mov    $0xfffffffd,%r12d
  call   <close@plt>
  jmp    L90
L1:
  mov    $0xffffffff,%r12d
  jmp    L90
L49:
  mov    $0xfffffffe,%r12d
  jmp    L90
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int simple_socket_connect(const char *address, int port) {
  int family;
  int sock;
  struct sockaddr_in host;
  struct sockaddr_in6 host6;
  if (inet_pton(AF_INET, address, &host.sin_addr.s_addr) == 1) {
    family = AF_INET;
    host.sin_family = family;
    host.sin_port = htons(port);
  } else if (inet_pton(AF_INET6, address, &host6.sin6_addr.s6_addr) == 1) {
    family = AF_INET6;
    host6.sin6_family = family;
    host6.sin6_port = htons(port);
  } else {
    return -1;
  }
  if ((sock = socket(family, SOCK_STREAM, 0)) == -1) {
    return -2;
  }
  int cr = -1;
  if (family == AF_INET) {
    cr = connect(sock, (struct sockaddr *)(&host), sizeof(struct sockaddr_in));
  } else if (family == AF_INET6) {
    cr = connect(sock, (struct sockaddr *)(&host6), sizeof(struct sockaddr_in6));
  }
  if (cr != 0) {
    close(sock);
    return -3;
  }
  return sock;
}
```