user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x170,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x16c(%rbp),%rdx
  lea    -0x170(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x168(%rbp)
  jmp    L28
L31:
  mov    -0x168(%rbp),%eax
  sub    $0x1,%eax
  lea    -0x150(%rbp),%rdx
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x168(%rbp)
L28:
  mov    -0x170(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x168(%rbp)
  jle    L31
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x164(%rbp)
  jmp    L61
L80:
  mov    -0x164(%rbp),%eax
  sub    $0x1,%eax
  lea    -0x100(%rbp),%rdx
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x164(%rbp)
L61:
  mov    -0x16c(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x164(%rbp)
  jle    L80
  mov    -0x170(%rbp),%edx
  mov    -0x16c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x160(%rbp)
  jmp    L66
L29:
  mov    -0x160(%rbp),%eax
  cltq
  movl   $0x0,-0xb0(%rbp,%rax,4)
  addl   $0x1,-0x160(%rbp)
L66:
  mov    -0x170(%rbp),%edx
  mov    -0x16c(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x160(%rbp)
  jle    L29
  movl   $0x0,-0x15c(%rbp)
  jmp    L127
L14:
  movl   $0x0,-0x158(%rbp)
  jmp    L88
L65:
  mov    -0x15c(%rbp),%edx
  mov    -0x158(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    -0xb0(%rbp,%rax,4),%ecx
  mov    -0x15c(%rbp),%eax
  cltq
  mov    -0x150(%rbp,%rax,4),%edx
  mov    -0x158(%rbp),%eax
  cltq
  mov    -0x100(%rbp,%rax,4),%eax
  imul   %eax,%edx
  mov    -0x15c(%rbp),%esi
  mov    -0x158(%rbp),%eax
  add    %esi,%eax
  add    %ecx,%edx
  cltq
  mov    %edx,-0xb0(%rbp,%rax,4)
  addl   $0x1,-0x158(%rbp)
L88:
  mov    -0x16c(%rbp),%eax
  cmp    %eax,-0x158(%rbp)
  jle    L65
  addl   $0x1,-0x15c(%rbp)
L127:
  mov    -0x170(%rbp),%eax
  cmp    %eax,-0x15c(%rbp)
  jle    L14
  movl   $0x0,-0x154(%rbp)
  jmp    L125
L91:
  mov    -0x154(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x154(%rbp)
L125:
  mov    -0x170(%rbp),%edx
  mov    -0x16c(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x154(%rbp)
  jle    L91
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L121
  call   <__stack_chk_fail@plt>
L121:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D39
data_type: string
name: parse_data
arguments: label: D25
data_type: string
name: parse_data
arguments: label: D50
data_type: string
name: parse_data
arguments: label: D7
data_type: string
name: parse_data
arguments: label: D56
data_type: string

tool: D39: %d %d


tool: D25: %d 

tool: D50: 


tool: D7: %d

tool: D56: %d


assistant: ```c
int main() {
  int n1, n2, a[20], b[20];
  scanf("%d %d\n", &n1, &n2);
  for (int i = 1; i <= n1 + 1; i++) {
    scanf("%d ", &a[i - 1]);
  }
  scanf("\n");
  for (int j = 1; j <= n2 + 1; j++) {
    scanf("%d", &b[j - 1]);
  }
  printf("%d\n", n1 + n2);
  int m[40];
  for (int q = 0; q <= n1 + n2; q++) {
    m[q] = 0;
  }
  for (int k = 0; k <= n1; k++) {
    for (int l = 0; l <= n2; l++) {
      m[k + l] = m[k + l] + (a[k] * b[l]);
    }
  }
  for (int z = 0; z <= n1 + n2; z++) {
    printf("%d ", m[z]);
  }
  return 0;
}
```