ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<rt_modbus_read_registers>:
  endbr64
  push   %r14
  lea    0x8(%rdi),%rsi
  mov    $0x2,%edx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rbp
  call   <swap16@plt>
  lea    0x10(%r13),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <swap16@plt>
  mov    0x10(%rsp),%eax
  cmp    $0x78,%eax
  jg     L75
  lea    (%rax,%rax,1),%r14d
  lea    0xc(%r13),%rbp
  mov    %r14d,0x8(%r13)
  test   %eax,%eax
  jle    L61
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L72:
  mov    0xc(%rsp),%eax
  add    %ebx,%eax
  test   $0x1,%al
  je     L24
  mov    %r12,%rdi
  movl   $0xaaaa,0x14(%rsp)
  add    $0x1,%ebx
  call   <swap16@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  add    $0x8,%rbp
  cmp    0x10(%rsp),%ebx
  jl     L72
L61:
  add    $0x5,%r14d
  mov    $0xffff,%edx
  mov    %r13,%rdi
  mov    %r14d,%esi
  call   <add_CRC@plt>
L39:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x20,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %r12,%rdi
  movl   $0x5555,0x14(%rsp)
  add    $0x1,%ebx
  call   <swap16@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  add    $0x8,%rbp
  cmp    %ebx,0x10(%rsp)
  jg     L72
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L75:
  mov    D7(%rip),%rax
  mov    $0xffff,%edx
  mov    $0x5,%esi
  mov    %r13,%rdi
  mov    $0x5,%r14d
  mov    %rax,0x4(%r13)
  call   <add_CRC@plt>
  jmp    L39
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: byte[8]

tool: {"D7": [0x83,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int rt_modbus_read_registers(uint8_t *buf, int n) {
  uint16_t start_point;
  uint16_t num_points;
  int byte_count;
  uint8_t *p;
  int i;
  uint16_t tmp;
  memcpy(&start_point, buf + 2, 2);
  swap16(&start_point);
  memcpy(&num_points, buf + 4, 2);
  swap16(&num_points);
  if (num_points > 120) {
    buf[1] = 128 + (0x03);
    buf[2] = 4;
    add_CRC(buf, 5, 0xffff);
    return 5;
  }
  byte_count = num_points * 2;
  buf[2] = byte_count;
  p = buf + 3;
  for (i = 0; i < num_points; i++) {
    if ((start_point + i) % 2) {
      tmp = 0xAAAA;
    } else {
      tmp = 0x5555;
    }
    swap16(&tmp);
    memcpy(p, &tmp, 2);
    p += 2;
  }
  add_CRC(buf, 5 + byte_count, 0xffff);
  return (5 + byte_count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L21
L51:
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  test   %eax,%eax
  je     L56
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L70
L1:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jne    L54
  mov    -0x18(%rbp),%eax
  sub    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L54:
  addl   $0x1,-0x18(%rbp)
L70:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L1
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L21:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L51
  jmp    L52
L56:
  nop
L52:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D34
data_type: string

tool: D2: %d

tool: D34: %d


assistant: ```c
int main() {
  int N, S, D, i, j, w, ans;
  scanf("%d", &D);
  for (j = 0; j < D; j++) {
    scanf("%d", &N);
    if (N == 0)
      break;
    w = 0;
    ans = 0;
    for (i = 0; i < N; i++) {
      scanf("%d", &S);
      if (S == 0) {
        ans += (i - w);
        w++;
      }
    }
    printf("%d\n", ans);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x24(%rsp)
  jle    L34
  mov    $0x0,%r15d
  lea    0x1c(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D21(%rip),%r13
  lea    0x20(%rsp),%r14
  jmp    L63
L35:
  add    $0x1,%ebx
  cmp    %ebx,0x1c(%rsp)
  jle    L49
L5:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x20(%rsp)
  jne    L35
  mov    %ebx,%eax
  sub    %ebp,%eax
  add    %eax,%r12d
  add    $0x1,%ebp
  jmp    L35
L72:
  mov    $0x0,%r12d
L49:
  mov    %r12d,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r15d
  cmp    %r15d,0x24(%rsp)
  jle    L34
L63:
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L34
  jle    L72
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L5
L34:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
type_infered: string
name: read_data
arguments: tag: D27
type_infered: string

tool: D21: %d

tool: D27: %d


assistant: ```c
int main() {
  int N, S, D, i, j, w, ans;
  scanf("%d", &D);
  for (j = 0; j < D; j++) {
    scanf("%d", &N);
    if (N == 0)
      break;
    w = 0;
    ans = 0;
    for (i = 0; i < N; i++) {
      scanf("%d", &S);
      if (S == 0) {
        ans += (i - w);
        w++;
      }
    }
    printf("%d\n", ans);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rsi
  call   <scanf@plt>
  mov    0x24(%rsp),%ecx
  test   %ecx,%ecx
  jle    L65
  lea    0x1c(%rsp),%rax
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  nop
L18:
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  je     L65
  mov    $0x0,%ebp
  jle    L69
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r13
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  test   %eax,%eax
  jne    L53
  mov    %r15d,%eax
  sub    %ebx,%eax
  add    $0x1,%ebx
  add    %eax,%ebp
L53:
  add    $0x1,%r15d
  cmp    %r15d,0x1c(%rsp)
  jg     L52
L69:
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0x24(%rsp)
  jg     L18
L65:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D0: %d

tool: D1: %d


assistant: ```c
int main() {
  int N, S, D, i, j, w, ans;
  scanf("%d", &D);
  for (j = 0; j < D; j++) {
    scanf("%d", &N);
    if (N == 0)
      break;
    w = 0;
    ans = 0;
    for (i = 0; i < N; i++) {
      scanf("%d", &S);
      if (S == 0) {
        ans += (i - w);
        w++;
      }
    }
    printf("%d\n", ans);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rsi
  call   <scanf@plt>
  mov    0x24(%rsp),%ecx
  test   %ecx,%ecx
  jle    L33
  lea    0x1c(%rsp),%rax
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  nop
L24:
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  je     L33
  mov    $0x0,%ebp
  jle    L37
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r13
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  test   %eax,%eax
  jne    L28
  mov    %r15d,%eax
  sub    %ebx,%eax
  add    $0x1,%ebx
  add    %eax,%ebp
L28:
  add    $0x1,%r15d
  cmp    %r15d,0x1c(%rsp)
  jg     L23
L37:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0x24(%rsp)
  jg     L24
L33:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
data_type: string
name: read_data
arguments: label: D4
data_type: string

tool: D2: %d

tool: D4: %d


assistant: ```c
int main() {
  int N, S, D, i, j, w, ans;
  scanf("%d", &D);
  for (j = 0; j < D; j++) {
    scanf("%d", &N);
    if (N == 0)
      break;
    w = 0;
    ans = 0;
    for (i = 0; i < N; i++) {
      scanf("%d", &S);
      if (S == 0) {
        ans += (i - w);
        w++;
      }
    }
    printf("%d\n", ans);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <check_input@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <overwrite_prevent@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <open_output@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write_file@plt>
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write_file@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <shutdown_output@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int fileDescriptor;
  check_input(argc);
  overwrite_prevent(argc, argv);
  fileDescriptor = open_output(argc, argv);
  write_file(fileDescriptor, argv[1]);
  write_file(fileDescriptor, argv[2]);
  shutdown_output(fileDescriptor);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  call   <check_input@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <overwrite_prevent@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <open_output@plt>
  mov    %eax,%ebp
  mov    0x8(%rbx),%rsi
  mov    %eax,%edi
  call   <write_file@plt>
  mov    0x10(%rbx),%rsi
  mov    %ebp,%edi
  call   <write_file@plt>
  mov    %ebp,%edi
  call   <shutdown_output@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int fileDescriptor;
  check_input(argc);
  overwrite_prevent(argc, argv);
  fileDescriptor = open_output(argc, argv);
  write_file(fileDescriptor, argv[1]);
  write_file(fileDescriptor, argv[2]);
  shutdown_output(fileDescriptor);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <check_input@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <overwrite_prevent@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <open_output@plt>
  mov    0x8(%rbx),%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <write_file@plt>
  mov    0x10(%rbx),%rsi
  mov    %ebp,%edi
  call   <write_file@plt>
  mov    %ebp,%edi
  call   <shutdown_output@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int fileDescriptor;
  check_input(argc);
  overwrite_prevent(argc, argv);
  fileDescriptor = open_output(argc, argv);
  write_file(fileDescriptor, argv[1]);
  write_file(fileDescriptor, argv[2]);
  shutdown_output(fileDescriptor);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <check_input@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <overwrite_prevent@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <open_output@plt>
  mov    0x8(%rbx),%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <write_file@plt>
  mov    0x10(%rbx),%rsi
  mov    %ebp,%edi
  call   <write_file@plt>
  mov    %ebp,%edi
  call   <shutdown_output@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int fileDescriptor;
  check_input(argc);
  overwrite_prevent(argc, argv);
  fileDescriptor = open_output(argc, argv);
  write_file(fileDescriptor, argv[1]);
  write_file(fileDescriptor, argv[2]);
  shutdown_output(fileDescriptor);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lagrange_basis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %edx,-0x28(%rbp)
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L80
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L80
  mov    $0x1,%eax
  jmp    L75
L80:
  mov    $0x0,%eax
L75:
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x28(%rbp)
  je     L57
  cmpl   $0x1,-0x28(%rbp)
  jne    L2
L57:
  movsd  D6(%rip),%xmm0
  jmp    L56
L2:
  movl   $0x0,-0x14(%rbp)
  jmp    L54
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  je     L15
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x30(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L15:
  addl   $0x1,-0x14(%rbp)
L54:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L13
  movsd  -0x10(%rbp),%xmm0
L56:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: f64

tool: D6: 1

assistant: ```c
double lagrange_basis(int j, double x, const double x_values[], int num_x) {
  double l_j = 1;
  double r;
  assert(0 <= j && j < num_x && "j is in bounds");
  if (num_x == 0 || num_x == 1)
    return 1.;
  for (int m = 0; m < num_x; m++) {
    if (m != j) {
      r = (x - x_values[m]) / (x_values[j] - x_values[m]);
      l_j *= r;
    }
  }
  return l_j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lagrange_basis>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movq   %xmm0,%r12
  mov    %rsi,%rbp
  mov    %edx,%r13d
  not    %edi
  shr    $0x1f,%edi
  cmp    %edx,%ebx
  setl   %al
  and    %eax,%edi
  call   <assert@plt>
  cmp    $0x1,%r13d
  jle    L46
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,8),%rcx
  mov    %r13d,%edx
  mov    $0x0,%eax
  movsd  D19(%rip),%xmm3
  jmp    L32
L29:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L27
L32:
  cmp    %eax,%ebx
  je     L29
  movsd  0x0(%rbp,%rax,8),%xmm2
  movq   %r12,%xmm0
  subsd  %xmm2,%xmm0
  movsd  (%rcx),%xmm1
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm3
  jmp    L29
L46:
  movsd  D19(%rip),%xmm3
L27:
  movapd %xmm3,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type: f64

tool: D19: 1

assistant: ```c
double lagrange_basis(int j, double x, const double x_values[], int num_x) {
  double l_j = 1;
  double r;
  assert(0 <= j && j < num_x && "j is in bounds");
  if (num_x == 0 || num_x == 1)
    return 1.;
  for (int m = 0; m < num_x; m++) {
    if (m != j) {
      r = (x - x_values[m]) / (x_values[j] - x_values[m]);
      l_j *= r;
    }
  }
  return l_j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lagrange_basis>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  not    %edi
  push   %rbx
  shr    $0x1f,%edi
  mov    %edx,%ebx
  sub    $0x10,%rsp
  cmp    %edx,%ebp
  setl   %al
  movsd  %xmm0,0x8(%rsp)
  and    %eax,%edi
  call   <assert@plt>
  cmp    $0x1,%ebx
  jle    L22
  movslq %ebp,%rax
  movsd  D7(%rip),%xmm4
  movsd  0x8(%rsp),%xmm0
  movslq %ebx,%rdx
  lea    (%r12,%rax,8),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  cmp    %eax,%ebp
  je     L3
  movsd  (%r12,%rax,8),%xmm3
  movsd  (%rcx),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm3,%xmm1
  subsd  %xmm3,%xmm2
  divsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm4
L3:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
  add    $0x10,%rsp
  movapd %xmm4,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  movsd  D7(%rip),%xmm4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  movapd %xmm4,%xmm0
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: f64

tool: D7: 1

assistant: ```c
double lagrange_basis(int j, double x, const double x_values[], int num_x) {
  double l_j = 1;
  double r;
  assert(0 <= j && j < num_x && "j is in bounds");
  if (num_x == 0 || num_x == 1)
    return 1.;
  for (int m = 0; m < num_x; m++) {
    if (m != j) {
      r = (x - x_values[m]) / (x_values[j] - x_values[m]);
      l_j *= r;
    }
  }
  return l_j;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lagrange_basis>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  not    %edi
  push   %rbx
  shr    $0x1f,%edi
  mov    %edx,%ebx
  sub    $0x10,%rsp
  cmp    %edx,%ebp
  setl   %al
  movsd  %xmm0,0x8(%rsp)
  and    %eax,%edi
  call   <assert@plt>
  cmp    $0x1,%ebx
  jle    L16
  movslq %ebp,%rax
  movsd  D4(%rip),%xmm4
  movsd  0x8(%rsp),%xmm0
  movslq %ebx,%rdx
  lea    (%r12,%rax,8),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L25:
  cmp    %eax,%ebp
  je     L13
  movsd  (%r12,%rax,8),%xmm3
  movsd  (%rcx),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm3,%xmm1
  subsd  %xmm3,%xmm2
  divsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm4
L13:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L25
  add    $0x10,%rsp
  movapd %xmm4,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  movsd  D4(%rip),%xmm4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  movapd %xmm4,%xmm0
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type: f64

tool: D4: 1

assistant: ```c
double lagrange_basis(int j, double x, const double x_values[], int num_x) {
  double l_j = 1;
  double r;
  assert(0 <= j && j < num_x && "j is in bounds");
  if (num_x == 0 || num_x == 1)
    return 1.;
  for (int m = 0; m < num_x; m++) {
    if (m != j) {
      r = (x - x_values[m]) / (x_values[j] - x_values[m]);
      l_j *= r;
    }
  }
  return l_j;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<atnick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x2,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L5
L16:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: @%s,

assistant: ```c
char *atnick(const void *a) {
  size_t len;
  char *out;
  len = strlen((const char *)a) + 2;
  if (!(out = malloc(len + 1)))
    return NULL;
  sprintf(out, "@%s,", (const char *)a);
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<atnick>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  movslq %eax,%rdi
  add    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %rbp,%rdx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L6:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string

tool: D0: @%s,

assistant: ```c
char *atnick(const void *a) {
  size_t len;
  char *out;
  len = strlen((const char *)a) + 2;
  if (!(out = malloc(len + 1)))
    return NULL;
  sprintf(out, "@%s,", (const char *)a);
  return out;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atnick>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rdi
  add    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r13,%rdx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: @%s,

assistant: ```c
char *atnick(const void *a) {
  size_t len;
  char *out;
  len = strlen((const char *)a) + 2;
  if (!(out = malloc(len + 1)))
    return NULL;
  sprintf(out, "@%s,", (const char *)a);
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atnick>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rdi
  add    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: @%s,

assistant: ```c
char *atnick(const void *a) {
  size_t len;
  char *out;
  len = strlen((const char *)a) + 2;
  if (!(out = malloc(len + 1)))
    return NULL;
  sprintf(out, "@%s,", (const char *)a);
  return out;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x5,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ack@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: ack(%d,%d) = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int m, n;
  m = 5, n = 1;
  printf("ack(%d,%d) = %d\n", m, n, ack(m, n));
  return 0;
}
```