ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D51(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D61(%rip),%rdi
  call   <scanf@plt>
  lea    D85(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L117
  comiss %xmm0,%xmm1
  movss  0x8(%rsp),%xmm2
  jbe    L4
  comiss %xmm2,%xmm0
  jae    L128
L4:
  comiss %xmm0,%xmm2
  movss  0xc(%rsp),%xmm1
  ja     L36
L51:
  comiss %xmm0,%xmm1
  movss  0x10(%rsp),%xmm2
  jbe    L46
  comiss %xmm2,%xmm0
  jae    L93
L46:
  comiss %xmm0,%xmm2
  ja     L102
L52:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L36:
  comiss %xmm1,%xmm0
  jb     L51
  lea    D57(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L117:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L128:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L93:
  lea    D86(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L102:
  lea    D72(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D51
datatype: string
name: extract_symbolic_data
arguments: tag: D61
datatype: string
name: extract_symbolic_data
arguments: tag: D85
datatype: string
name: extract_symbolic_data
arguments: tag: D9
datatype: string
name: extract_symbolic_data
arguments: tag: D57
datatype: string
name: extract_symbolic_data
arguments: tag: D33
datatype: string
name: extract_symbolic_data
arguments: tag: D23
datatype: string
name: extract_symbolic_data
arguments: tag: D86
datatype: string
name: extract_symbolic_data
arguments: tag: D72
datatype: string

tool: D51: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D61: %f%f%f%f

tool: D85: Thank you. Now enter student score (percent) >

tool: D9: %f

tool: D57: Student has an C grade


tool: D33: Student has an A grade


tool: D23: Student has an B grade


tool: D86: Student has an D grade


tool: D72: Student has failed that course


assistant: ```c
int main(void) {
  float a, b, c, d;
  float percent;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &percent);
  if (percent >= a)
    printf("Student has an A grade\n");
  else if (percent < a && percent >= b)
    printf("Student has an B grade\n");
  else if (percent < b && percent >= c)
    printf("Student has an C grade\n");
  else if (percent < c && percent >= d)
    printf("Student has an D grade\n");
  else if (percent < d)
    printf("Student has failed that course\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L81
  comiss %xmm0,%xmm1
  movss  0x8(%rsp),%xmm2
  jbe    L127
  comiss %xmm2,%xmm0
  jae    L0
L127:
  comiss %xmm0,%xmm2
  movss  0xc(%rsp),%xmm1
  ja     L100
L94:
  comiss %xmm0,%xmm1
  movss  0x10(%rsp),%xmm2
  jbe    L29
  comiss %xmm2,%xmm0
  jae    L56
L29:
  comiss %xmm0,%xmm2
  ja     L32
L86:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L100:
  comiss %xmm1,%xmm0
  jb     L94
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L86
L81:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L86
L0:
  lea    D82(%rip),%rdi
  call   <printf@plt>
  jmp    L86
L56:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L86
L32:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L86
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string
name: retrieve_data
arguments: data_tag: D39
type: string
name: retrieve_data
arguments: data_tag: D28
type: string
name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D64
type: string
name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D82
type: string
name: retrieve_data
arguments: data_tag: D14
type: string
name: retrieve_data
arguments: data_tag: D26
type: string

tool: D7: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D39: %f%f%f%f

tool: D28: Thank you. Now enter student score (percent) >

tool: D0: %f

tool: D64: Student has an C grade


tool: D21: Student has an A grade


tool: D82: Student has an B grade


tool: D14: Student has an D grade


tool: D26: Student has failed that course


assistant: ```c
int main(void) {
  float a, b, c, d;
  float percent;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &percent);
  if (percent >= a)
    printf("Student has an A grade\n");
  else if (percent < a && percent >= b)
    printf("Student has an B grade\n");
  else if (percent < b && percent >= c)
    printf("Student has an C grade\n");
  else if (percent < c && percent >= d)
    printf("Student has an D grade\n");
  else if (percent < d)
    printf("Student has failed that course\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fill_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fill_word(__u32 src, __u8 *dst, int offset) {
  dst[offset] = (src >> 24) & 0xff;
  dst[offset + 1] = (src >> 16) & 0xff;
  dst[offset + 2] = (src >> 8) & 0xff;
  dst[offset + 3] = src & 0xff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fill_word>:
  endbr64
  mov    %edi,%eax
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  shr    $0x18,%edi
  mov    %edi,(%rsi,%rdx,4)
  mov    %eax,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x4(%rsi,%rcx,1)
  movzbl %ah,%edx
  mov    %edx,0x8(%rsi,%rcx,1)
  and    $0xff,%eax
  mov    %eax,0xc(%rsi,%rcx,1)
  ret
```

assistant: ```c
void fill_word(__u32 src, __u8 *dst, int offset) {
  dst[offset] = (src >> 24) & 0xff;
  dst[offset + 1] = (src >> 16) & 0xff;
  dst[offset + 2] = (src >> 8) & 0xff;
  dst[offset + 3] = src & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fill_word>:
  endbr64
  mov    %edi,%eax
  movslq %edx,%rdx
  shr    $0x18,%edi
  mov    %edi,(%rsi,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  mov    %eax,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x4(%rsi,%rcx,1)
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,0x8(%rsi,%rcx,1)
  mov    %eax,0xc(%rsi,%rcx,1)
  ret
```

assistant: ```c
void fill_word(__u32 src, __u8 *dst, int offset) {
  dst[offset] = (src >> 24) & 0xff;
  dst[offset + 1] = (src >> 16) & 0xff;
  dst[offset + 2] = (src >> 8) & 0xff;
  dst[offset + 3] = src & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fill_word>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  movslq %edx,%rdx
  shr    $0x18,%ecx
  movd   %ecx,%xmm0
  mov    %edi,%ecx
  movzbl %ah,%edi
  movzbl %al,%eax
  sar    $0x10,%ecx
  movd   %edi,%xmm1
  movd   %eax,%xmm2
  movzbl %cl,%ecx
  punpckldq %xmm2,%xmm1
  movd   %ecx,%xmm3
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rsi,%rdx,4)
  ret
```

assistant: ```c
void fill_word(__u32 src, __u8 *dst, int offset) {
  dst[offset] = (src >> 24) & 0xff;
  dst[offset + 1] = (src >> 16) & 0xff;
  dst[offset + 2] = (src >> 8) & 0xff;
  dst[offset + 3] = src & 0xff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jle    L121
  cmpq   $0x0,-0x30(%rbp)
  jne    L0
L121:
  mov    D15(%rip),%rax
  mov    (%rax),%rdx
  mov    D12(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L125
L0:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
L76:
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L116
  mov    D12(%rip),%rax
  mov    (%rax),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L101
  mov    $0xffffffff,%eax
  jmp    L125
L116:
  cmpl   $0x0,-0xc(%rbp)
  jne    L127
  cmpl   $0x0,-0x10(%rbp)
  jne    L58
  mov    $0x0,%eax
  jmp    L125
L127:
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L5
  addl   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
L5:
  cmpb   $0xa,-0x11(%rbp)
  je     L83
  jmp    L76
L101:
  nop
  jmp    L76
L58:
  nop
  jmp    L47
L83:
  nop
L47:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
L125:
  pop    %rbp
  ret
```

assistant: ```c
int readLine(int fd, void *buffer, int n) {
  int numRead;
  int totRead;
  char *buf;
  char ch;
  if (n <= 0 || buffer == NULL) {
    errno = EINVAL;
    return -1;
  }
  buf = buffer;
  totRead = 0;
  while (true) {
    if (numRead == -1) {
      if (errno == EINTR)
        continue;
      else
        return -1;
    } else if (numRead == 0) {
      if (totRead == 0)
        return 0;
      else
        break;
    } else {
      if (totRead < n - 1) {
        totRead++;
        *buf++ = ch;
      }
      if (ch == '\n')
        break;
    }
  }
  *buf = '\0';
  return totRead;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readLine>:
  endbr64
  test   %edx,%edx
  jle    L1
  test   %rsi,%rsi
  je     L1
  mov    $0x0,%eax
  test   %eax,%eax
  je     L4
  movb   $0x0,(%rsi)
L4:
  ret
L1:
  mov    D13(%rip),%rax
  mov    (%rax),%rdx
  mov    D1(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int readLine(int fd, void *buffer, int n) {
  int numRead;
  int totRead;
  char *buf;
  char ch;
  if (n <= 0 || buffer == NULL) {
    errno = EINVAL;
    return -1;
  }
  buf = buffer;
  totRead = 0;
  while (true) {
    if (numRead == -1) {
      if (errno == EINTR)
        continue;
      else
        return -1;
    } else if (numRead == 0) {
      if (totRead == 0)
        return 0;
      else
        break;
    } else {
      if (totRead < n - 1) {
        totRead++;
        *buf++ = ch;
      }
      if (ch == '\n')
        break;
    }
  }
  *buf = '\0';
  return totRead;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readLine>:
  endbr64
  test   %edx,%edx
  jle    L10
  test   %rsi,%rsi
  je     L10
  xor    %eax,%eax
  test   %eax,%eax
  je     L26
  movb   $0x0,(%rsi)
L26:
  ret
L10:
  mov    D19(%rip),%rax
  mov    (%rax),%rdx
  mov    D12(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int readLine(int fd, void *buffer, int n) {
  int numRead;
  int totRead;
  char *buf;
  char ch;
  if (n <= 0 || buffer == NULL) {
    errno = EINVAL;
    return -1;
  }
  buf = buffer;
  totRead = 0;
  while (true) {
    if (numRead == -1) {
      if (errno == EINTR)
        continue;
      else
        return -1;
    } else if (numRead == 0) {
      if (totRead == 0)
        return 0;
      else
        break;
    } else {
      if (totRead < n - 1) {
        totRead++;
        *buf++ = ch;
      }
      if (ch == '\n')
        break;
    }
  }
  *buf = '\0';
  return totRead;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readLine>:
  endbr64
  test   %edx,%edx
  jle    L2
  test   %rsi,%rsi
  je     L2
  xor    %eax,%eax
  test   %eax,%eax
  je     L15
  movb   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
L2:
  mov    D2(%rip),%rax
  mov    (%rax),%rdx
  mov    D6(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int readLine(int fd, void *buffer, int n) {
  int numRead;
  int totRead;
  char *buf;
  char ch;
  if (n <= 0 || buffer == NULL) {
    errno = EINVAL;
    return -1;
  }
  buf = buffer;
  totRead = 0;
  while (true) {
    if (numRead == -1) {
      if (errno == EINTR)
        continue;
      else
        return -1;
    } else if (numRead == 0) {
      if (totRead == 0)
        return 0;
      else
        break;
    } else {
      if (totRead < n - 1) {
        totRead++;
        *buf++ = ch;
      }
      if (ch == '\n')
        break;
    }
  }
  *buf = '\0';
  return totRead;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L0
L11:
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type: string
name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D13
type: string

tool: D16: %d

tool: D3: %d%d%d

tool: D13: %d


assistant: ```c
int main() {
  int t, n, a, d;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &n, &a, &d);
    printf("%d\n", (n * ((2 * a) + ((n - 1) * d))) / 2);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L10
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D6(%rip),%rbp
  lea    D3(%rip),%rbx
L12:
  lea    0xc(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  lea    -0x1(%rdx),%eax
  imul   0x14(%rsp),%eax
  mov    0x10(%rsp),%ecx
  lea    (%rax,%rcx,2),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L12
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D16
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D3
type_guessed: string

tool: D16: %d

tool: D6: %d%d%d

tool: D3: %d


assistant: ```c
int main() {
  int t, n, a, d;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &n, &a, &d);
    printf("%d\n", (n * ((2 * a) + ((n - 1) * d))) / 2);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L20
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D29(%rip),%rbp
  lea    D18(%rip),%rbx
  nopl   (%rax)
L9:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%ecx
  mov    %rbx,%rdi
  lea    -0x1(%rdx),%eax
  imul   0x14(%rsp),%eax
  lea    (%rax,%rcx,2),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L9
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D29
type: string
name: extract_symbolic_data
arguments: data_label: D18
type: string

tool: D6: %d

tool: D29: %d%d%d

tool: D18: %d


assistant: ```c
int main() {
  int t, n, a, d;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &n, &a, &d);
    printf("%d\n", (n * ((2 * a) + ((n - 1) * d))) / 2);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L6
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D2(%rip),%rbp
  lea    D16(%rip),%rbx
  nopl   (%rax)
L28:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%ecx
  mov    %rbx,%rdi
  lea    -0x1(%rdx),%eax
  imul   0x14(%rsp),%eax
  lea    (%rax,%rcx,2),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L28
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string

tool: D7: %d

tool: D2: %d%d%d

tool: D16: %d


assistant: ```c
int main() {
  int t, n, a, d;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &n, &a, &d);
    printf("%d\n", (n * ((2 * a) + ((n - 1) * d))) / 2);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<deallocate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L11:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: Deallocated memory for array

assistant: ```c
void deallocate(int ***array, int r) {
  int i;
  for (i = 0; i < r; i++)
    free((*array)[i]);
  free(*array);
  printf("Deallocated memory for array\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<deallocate>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L6
  mov    %esi,%esi
  lea    0x0(,%rsi,8),%rbp
  mov    $0x0,%ebx
L11:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L11
L6:
  mov    (%r12),%rdi
  call   <free@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: Deallocated memory for array

assistant: ```c
void deallocate(int ***array, int r) {
  int i;
  for (i = 0; i < r; i++)
    free((*array)[i]);
  free(*array);
  printf("Deallocated memory for array\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<deallocate>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L1
  movslq %esi,%rsi
  xor    %ebx,%ebx
  lea    0x0(,%rsi,8),%rbp
  nopl   0x0(%rax)
L10:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L10
L1:
  mov    (%r12),%rdi
  call   <free@plt>
  pop    %rbx
  lea    D9(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9: Deallocated memory for array

assistant: ```c
void deallocate(int ***array, int r) {
  int i;
  for (i = 0; i < r; i++)
    free((*array)[i]);
  free(*array);
  printf("Deallocated memory for array\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<deallocate>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  xor    %ebx,%ebx
  lea    0x0(,%rsi,8),%rbp
  nopl   0x0(%rax)
L19:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L19
L0:
  mov    (%r12),%rdi
  call   <free@plt>
  pop    %rbx
  lea    D6(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: Deallocated memory for array

assistant: ```c
void deallocate(int ***array, int r) {
  int i;
  for (i = 0; i < r; i++)
    free((*array)[i]);
  free(*array);
  printf("Deallocated memory for array\n");
}
```