ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<searchN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jbe    L4
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L20
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  jmp    L51
L20:
  shll   -0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  add    %eax,-0x4(%rbp)
  jmp    L6
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L6
  shll   -0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  sub    %eax,-0x4(%rbp)
  jmp    L6
L51:
  pop    %rbp
  ret
```

assistant: ```c
int searchN(unsigned int *a, int x) {
  int divider = 2;
  int mid = x + x / divider;
  while (1) {
    if (a[mid] > a[mid + 1]) {
      if (a[mid + 1] == 0) {
        return mid - 1;
      } else {
        divider = divider * 2;
        mid = mid + x / divider;
      }
    } else if (a[mid] == 0) {
      divider = divider * 2;
      mid = mid - x / divider;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<searchN>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%r9d
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  add    %esi,%ecx
  mov    $0x2,%esi
  jmp    L16
L30:
  test   %edi,%edi
  jne    L16
  add    %esi,%esi
  mov    %r9d,%eax
  cltd
  idiv   %esi
  sub    %eax,%ecx
L16:
  movslq %ecx,%rdx
  mov    (%r8,%rdx,4),%edi
  mov    0x4(%r8,%rdx,4),%edx
  cmp    %edx,%edi
  jbe    L30
  test   %edx,%edx
  je     L49
  add    %esi,%esi
  mov    %r9d,%eax
  cltd
  idiv   %esi
  add    %eax,%ecx
  jmp    L16
L49:
  lea    -0x1(%rcx),%eax
  ret
```

assistant: ```c
int searchN(unsigned int *a, int x) {
  int divider = 2;
  int mid = x + x / divider;
  while (1) {
    if (a[mid] > a[mid + 1]) {
      if (a[mid + 1] == 0) {
        return mid - 1;
      } else {
        divider = divider * 2;
        mid = mid + x / divider;
      }
    } else if (a[mid] == 0) {
      divider = divider * 2;
      mid = mid - x / divider;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<searchN>:
  endbr64
  mov    %esi,%r10d
  shr    $0x1f,%esi
  mov    %rdi,%r9
  mov    $0x2,%ecx
  add    %r10d,%esi
  sar    %esi
  add    %r10d,%esi
  movslq %esi,%rdx
  nopl   (%rax)
L22:
  mov    (%r9,%rdx,4),%edi
  mov    0x4(%r9,%rdx,4),%r8d
  cmp    %r8d,%edi
  jbe    L10
L48:
  test   %r8d,%r8d
  je     L14
  mov    %r10d,%eax
  add    %ecx,%ecx
  cltd
  idiv   %ecx
  add    %eax,%esi
  movslq %esi,%rdx
  mov    (%r9,%rdx,4),%edi
  mov    0x4(%r9,%rdx,4),%r8d
  cmp    %r8d,%edi
  ja     L48
L10:
  test   %edi,%edi
  jne    L22
  mov    %r10d,%eax
  add    %ecx,%ecx
  cltd
  idiv   %ecx
  sub    %eax,%esi
  movslq %esi,%rdx
  jmp    L22
  nopl   0x0(%rax)
L14:
  lea    -0x1(%rsi),%eax
  ret
```

assistant: ```c
int searchN(unsigned int *a, int x) {
  int divider = 2;
  int mid = x + x / divider;
  while (1) {
    if (a[mid] > a[mid + 1]) {
      if (a[mid + 1] == 0) {
        return mid - 1;
      } else {
        divider = divider * 2;
        mid = mid + x / divider;
      }
    } else if (a[mid] == 0) {
      divider = divider * 2;
      mid = mid - x / divider;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<searchN>:
  endbr64
  mov    %esi,%r10d
  shr    $0x1f,%esi
  mov    %rdi,%r9
  mov    $0x2,%ecx
  add    %r10d,%esi
  sar    %esi
  add    %r10d,%esi
  movslq %esi,%rdx
  nopl   (%rax)
L8:
  mov    (%r9,%rdx,4),%edi
  mov    0x4(%r9,%rdx,4),%r8d
  cmp    %r8d,%edi
  jbe    L49
L15:
  test   %r8d,%r8d
  je     L7
  mov    %r10d,%eax
  add    %ecx,%ecx
  cltd
  idiv   %ecx
  add    %eax,%esi
  movslq %esi,%rdx
  mov    (%r9,%rdx,4),%edi
  mov    0x4(%r9,%rdx,4),%r8d
  cmp    %r8d,%edi
  ja     L15
L49:
  test   %edi,%edi
  jne    L8
  mov    %r10d,%eax
  add    %ecx,%ecx
  cltd
  idiv   %ecx
  sub    %eax,%esi
  movslq %esi,%rdx
  jmp    L8
  nopl   0x0(%rax)
L7:
  lea    -0x1(%rsi),%eax
  ret
```

assistant: ```c
int searchN(unsigned int *a, int x) {
  int divider = 2;
  int mid = x + x / divider;
  while (1) {
    if (a[mid] > a[mid + 1]) {
      if (a[mid + 1] == 0) {
        return mid - 1;
      } else {
        divider = divider * 2;
        mid = mid + x / divider;
      }
    } else if (a[mid] == 0) {
      divider = divider * 2;
      mid = mid - x / divider;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ns_initparse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%r13
  mov    $0x40,%edx
  mov    $0x5e,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,0x38(%r12)
  mov    %r13,0x30(%r12)
  mov    D27(%rip),%rax
  movslq (%rax),%rax
  lea    0x0(%rbp,%rax,4),%rax
  cmp    %rax,%r13
  jb     L38
  mov    %rbp,%rsi
  mov    (%r12),%rdi
  call   <NS_GET16@plt>
  mov    D27(%rip),%rax
  movslq (%rax),%rax
  lea    0x0(%rbp,%rax,4),%rax
  cmp    %rax,%r13
  jb     L38
  mov    0x8(%r12),%rdi
  mov    %rbp,%rsi
  call   <NS_GET16@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L66
  mov    $0x0,%ebx
  mov    D27(%rip),%r14
L54:
  movslq (%r14),%rax
  lea    0x0(%rbp,%rax,4),%rax
  cmp    %rax,%r13
  jb     L38
  mov    0x10(%r12),%rax
  mov    (%rax,%rbx,8),%rdi
  mov    %rbp,%rsi
  call   <NS_GET16@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L54
  test   %eax,%eax
  jle    L66
  mov    $0x0,%ebx
  jmp    L9
L108:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <skiprr@plt>
  test   %eax,%eax
  js     L124
  mov    0x28(%r12),%rdx
  mov    %rbp,(%rdx,%r14,1)
  cltq
  lea    0x0(%rbp,%rax,4),%rbp
L82:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jle    L66
L9:
  mov    %ebx,%edx
  lea    0x0(,%rbx,8),%r14
  mov    0x10(%r12),%rax
  mov    (%rax,%rbx,8),%rcx
  test   %rcx,%rcx
  jne    L108
  mov    0x28(%r12),%rax
  movq   $0x0,(%rax,%rbx,8)
  jmp    L82
L66:
  cmp    %rbp,%r13
  jne    L38
  mov    %eax,0x18(%r12)
  movl   $0xffffffff,0x1c(%r12)
  movq   $0x0,0x20(%r12)
  mov    $0x0,%eax
  jmp    L78
L38:
  mov    D40(%rip),%rax
  mov    (%rax),%edx
  mov    D28(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
L78:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L124:
  mov    $0xffffffff,%eax
  jmp    L78
```

assistant: ```c
int ns_initparse(const u_char *msg, int msglen, ns_msg *handle) {
  const u_char *eom = msg + msglen;
  int i;
  memset(handle, 0x5e, sizeof *handle);
  handle->_msg = msg;
  handle->_eom = eom;
  if (msg + NS_INT16SZ > eom)
    goto emsgsize;
  NS_GET16(handle->_id, msg);
  if (msg + NS_INT16SZ > eom)
    goto emsgsize;
  NS_GET16(handle->_flags, msg);
  for (i = 0; i < ns_s_max; i++) {
    if (msg + NS_INT16SZ > eom)
      goto emsgsize;
    NS_GET16(handle->_counts[i], msg);
  }
  for (i = 0; i < ns_s_max; i++)
    if (handle->_counts[i] == 0)
      handle->_sections[i] = NULL;
    else {
      int b = skiprr(msg, eom, (ns_sect)i, handle->_counts[i]);
      if (b < 0)
        return (-1);
      handle->_sections[i] = msg;
      msg += b;
    }
  if (msg != eom)
    goto emsgsize;
  handle->_sect = ns_s_max;
  handle->_rrnum = -1;
  handle->_msg_ptr = NULL;
  return (0);
emsgsize:
  errno = EMSGSIZE;
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sigaddset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L12
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L16
L12:
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L29
L16:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__SIGADDSET@plt>
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
int sigaddset(sigset_t *set, int signo) {
  if (signo <= 0 || signo >= NSIG) {
    errno = EINVAL;
    return -1;
  }
  __SIGADDSET(set, signo);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sigaddset>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    D7(%rip),%rax
  cmp    %esi,(%rax)
  jle    L17
  sub    $0x8,%rsp
  call   <__SIGADDSET@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L17:
  mov    D25(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sigaddset(sigset_t *set, int signo) {
  if (signo <= 0 || signo >= NSIG) {
    errno = EINVAL;
    return -1;
  }
  __SIGADDSET(set, signo);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sigaddset>:
  endbr64
  test   %esi,%esi
  jle    L19
  mov    D4(%rip),%rax
  cmp    %esi,(%rax)
  jle    L19
  sub    $0x8,%rsp
  call   <__SIGADDSET@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sigaddset(sigset_t *set, int signo) {
  if (signo <= 0 || signo >= NSIG) {
    errno = EINVAL;
    return -1;
  }
  __SIGADDSET(set, signo);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sigaddset>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    D4(%rip),%rax
  cmp    %esi,(%rax)
  jle    L16
  sub    $0x8,%rsp
  call   <__SIGADDSET@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sigaddset(sigset_t *set, int signo) {
  if (signo <= 0 || signo >= NSIG) {
    errno = EINVAL;
    return -1;
  }
  __SIGADDSET(set, signo);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sync_pipe_notify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x41,-0xd(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L22
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x18(%rbp),%rax
  movl   $0xffffffff,(%rax)
L22:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  lea    -0xd(%rbp),%rcx
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L5
  mov    $0xffffffff,%eax
  jmp    L14
L5:
  mov    $0x0,%eax
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int sync_pipe_notify(int fd[]) {
  char buf = 'A';
  int r;
  if (fd[0] != -1) {
    close(fd[0]);
    fd[0] = -1;
  }
  r = write(fd[1], &buf, 1);
  if (r != 1)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sync_pipe_notify>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x41,0x7(%rsp)
  mov    (%rdi),%edi
  cmp    $0xffffffff,%edi
  jne    L0
L15:
  lea    0x7(%rsp),%rsi
  mov    0x4(%rbx),%edi
  mov    $0x1,%edx
  call   <write@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <close@plt>
  movl   $0xffffffff,(%rbx)
  jmp    L15
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sync_pipe_notify(int fd[]) {
  char buf = 'A';
  int r;
  if (fd[0] != -1) {
    close(fd[0]);
    fd[0] = -1;
  }
  r = write(fd[1], &buf, 1);
  if (r != 1)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sync_pipe_notify>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x41,0x7(%rsp)
  cmp    $0xffffffff,%edi
  je     L6
  call   <close@plt>
  movl   $0xffffffff,(%rbx)
L6:
  mov    0x4(%rbx),%edi
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sync_pipe_notify(int fd[]) {
  char buf = 'A';
  int r;
  if (fd[0] != -1) {
    close(fd[0]);
    fd[0] = -1;
  }
  r = write(fd[1], &buf, 1);
  if (r != 1)
    return -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sync_pipe_notify>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x41,0x7(%rsp)
  cmp    $0xffffffff,%edi
  je     L15
  call   <close@plt>
  movl   $0xffffffff,(%rbx)
L15:
  mov    0x4(%rbx),%edi
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sync_pipe_notify(int fd[]) {
  char buf = 'A';
  int r;
  if (fd[0] != -1) {
    close(fd[0]);
    fd[0] = -1;
  }
  r = write(fd[1], &buf, 1);
  if (r != 1)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stringscan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L50
  mov    $0x0,%eax
  jmp    L21
L50:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x18(%rbp)
  jmp    L9
L96:
  addq   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L22
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L96
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L96
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L96
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L96
L22:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L86
  mov    $0x0,%eax
  jmp    L21
L86:
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L51
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L51:
  mov    -0x18(%rbp),%rax
L21:
  leave
  ret
```

assistant: ```c
char *stringscan(char *str, char *needle) {
  char *a, *e;
  char *end = str + strlen(str);
  a = strstr(str, needle);
  if (!a)
    return NULL;
  a += strlen(needle);
  while (a < end && (*a == ' ' || *a == '\r' || *a == '\t' || *a == '\r'))
    a++;
  if (a >= end)
    return NULL;
  e = strchr(a, ' ');
  if (e)
    *e = 0;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stringscan>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  movslq %eax,%rbp
  add    %rbx,%rbp
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L24
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L30
  mov    $0x0,%ebx
  jmp    L24
L28:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L64
L30:
  movzbl (%rbx),%eax
  mov    %eax,%edx
  and    $0xfffffffb,%edx
  cmp    $0x9,%dl
  je     L28
  cmp    $0x20,%al
  je     L28
  cmp    %rbx,%rbp
  jbe    L29
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L24
  movb   $0x0,(%rax)
  jmp    L24
L64:
  mov    $0x0,%ebx
L24:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    $0x0,%ebx
  jmp    L24
```

assistant: ```c
char *stringscan(char *str, char *needle) {
  char *a, *e;
  char *end = str + strlen(str);
  a = strstr(str, needle);
  if (!a)
    return NULL;
  a += strlen(needle);
  while (a < end && (*a == ' ' || *a == '\r' || *a == '\t' || *a == '\r'))
    a++;
  if (a >= end)
    return NULL;
  e = strchr(a, ' ');
  if (e)
    *e = 0;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stringscan>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movslq %eax,%rbx
  add    %r12,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L25
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  add    %rax,%r12
  cmp    %r12,%rbx
  jbe    L25
  xchg   %ax,%ax
L55:
  movzbl (%r12),%eax
  mov    %eax,%edx
  and    $0xfffffffb,%edx
  cmp    $0x9,%dl
  je     L53
  cmp    $0x20,%al
  jne    L35
L53:
  add    $0x1,%r12
  cmp    %r12,%rbx
  jne    L55
L25:
  xor    %r12d,%r12d
L46:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  cmp    %r12,%rbx
  jbe    L25
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L46
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stringscan(char *str, char *needle) {
  char *a, *e;
  char *end = str + strlen(str);
  a = strstr(str, needle);
  if (!a)
    return NULL;
  a += strlen(needle);
  while (a < end && (*a == ' ' || *a == '\r' || *a == '\t' || *a == '\r'))
    a++;
  if (a >= end)
    return NULL;
  e = strchr(a, ' ');
  if (e)
    *e = 0;
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stringscan>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movslq %eax,%rbx
  add    %r12,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L55
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  add    %rax,%r12
  cmp    %r12,%rbx
  jbe    L55
  xchg   %ax,%ax
L14:
  movzbl (%r12),%eax
  mov    %eax,%edx
  and    $0xfffffffb,%edx
  cmp    $0x9,%dl
  je     L0
  cmp    $0x20,%al
  jne    L48
L0:
  add    $0x1,%r12
  cmp    %r12,%rbx
  jne    L14
L55:
  xor    %r12d,%r12d
L12:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  cmp    %r12,%rbx
  jbe    L55
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stringscan(char *str, char *needle) {
  char *a, *e;
  char *end = str + strlen(str);
  a = strstr(str, needle);
  if (!a)
    return NULL;
  a += strlen(needle);
  while (a < end && (*a == ' ' || *a == '\r' || *a == '\t' || *a == '\r'))
    a++;
  if (a >= end)
    return NULL;
  e = strchr(a, ' ');
  if (e)
    *e = 0;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x4c(%rbp)
  jmp    L59
L58:
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L41:
  cmp    %rdx,%rsp
  je     L25
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L41
L25:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L19
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L19:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x4c(%rbp),%edx
  mov    -0x60(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsp
  addl   $0x1,-0x4c(%rbp)
L59:
  mov    -0x4c(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L58
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void bar(int a, char buffer[a]) {
  for (int i = 1; i < a; ++i) {
    char copy[i];
    memcpy(copy, buffer, i);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L25
  mov    %rsi,%r15
  mov    %edi,%r14d
  mov    $0x1,%ebx
  mov    $0x10,%r12d
  jmp    L61
L27:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L63
  orq    $0x0,-0x8(%rsp,%rdx,1)
L63:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r13,%rsp
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L25
L61:
  mov    %rsp,%r13
  lea    0xf(%rbx),%rax
  mov    $0x0,%edx
  div    %r12
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L48:
  cmp    %rdx,%rsp
  je     L27
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L48
L25:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar(int a, char buffer[a]) {
  for (int i = 1; i < a; ++i) {
    char copy[i];
    memcpy(copy, buffer, i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L15
  mov    %rsi,%r14
  movslq %edi,%rbx
  mov    $0x1,%r12d
L12:
  lea    0xf(%r12),%rax
  mov    %rsp,%rcx
  mov    %rsp,%r13
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L56
L41:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L41
L56:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L5
  orq    $0x0,-0x8(%rsp,%rdx,1)
L5:
  mov    %r12d,%edx
  mov    %rsp,%rdi
  mov    %r14,%rsi
  add    $0x1,%r12
  call   <memcpy@plt>
  mov    %r13,%rsp
  cmp    %rbx,%r12
  jne    L12
L15:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar(int a, char buffer[a]) {
  for (int i = 1; i < a; ++i) {
    char copy[i];
    memcpy(copy, buffer, i);
  }
}
```