ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hex_qr2l>:
  endbr64
  mov    %esi,%edx
  mov    %edi,%esi
  mov    %edi,%eax
  mov    %edi,%ecx
  neg    %esi
  sub    %edx,%esi
  neg    %eax
  cmovs  %edi,%eax
  mov    %edx,%edi
  neg    %edi
  cmovs  %edx,%edi
  add    %edi,%eax
  mov    %esi,%edi
  neg    %edi
  cmovs  %esi,%edi
  add    %edi,%eax
  sar    %eax
  je     L33
  lea    -0x1(%rax),%edi
  imul   %eax,%edi
  lea    0x1(%rdi,%rdi,2),%edi
  cmp    %eax,%edx
  je     L38
  mov    %eax,%r8d
  neg    %r8d
  cmp    %ecx,%r8d
  je     L14
  cmp    %eax,%esi
  je     L9
  cmp    %edx,%r8d
  je     L34
  cmp    %eax,%ecx
  je     L69
  cmp    %esi,%r8d
  je     L7
  mov    %edi,%eax
L33:
  ret
  nopl   0x0(%rax)
L38:
  mov    %edi,%eax
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L9:
  lea    (%rdi,%rax,2),%eax
  sub    %edx,%eax
  ret
  xchg   %ax,%ax
L14:
  add    %edi,%eax
  add    %esi,%eax
  ret
  nopl   (%rax)
L34:
  lea    (%rax,%rax,2),%eax
  add    %edi,%eax
  add    %ecx,%eax
  ret
L69:
  lea    (%rdi,%rax,4),%eax
  sub    %esi,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  lea    (%rax,%rax,4),%eax
  add    %edi,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int hex_qr2l(int q, int r) {
  int s, R, l, i0;
  s = -q - r;
  R = (abs(q) + abs(r) + abs(s)) >> 1;
  if (R == 0)
    return 0;
  l = i0 = 3 * R * (R - 1) + 1;
  if (r == R)
    l = i0 - q;
  else if (q == -R)
    l = i0 + R + s;
  else if (s == R)
    l = i0 + 2 * R - r;
  else if (r == -R)
    l = i0 + 3 * R + q;
  else if (q == R)
    l = i0 + 4 * R - s;
  else if (s == -R)
    l = i0 + 5 * R + r;
  return l;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hex_qr2l>:
  endbr64
  mov    %esi,%edx
  mov    %edi,%esi
  mov    %edi,%eax
  mov    %edi,%ecx
  neg    %esi
  sub    %edx,%esi
  neg    %eax
  cmovs  %edi,%eax
  mov    %edx,%edi
  neg    %edi
  cmovs  %edx,%edi
  add    %edi,%eax
  mov    %esi,%edi
  neg    %edi
  cmovs  %esi,%edi
  add    %edi,%eax
  sar    %eax
  je     L13
  lea    -0x1(%rax),%edi
  imul   %eax,%edi
  lea    0x1(%rdi,%rdi,2),%edi
  cmp    %eax,%edx
  je     L21
  mov    %eax,%r8d
  neg    %r8d
  cmp    %ecx,%r8d
  je     L19
  cmp    %eax,%esi
  je     L56
  cmp    %edx,%r8d
  je     L63
  cmp    %eax,%ecx
  je     L59
  cmp    %esi,%r8d
  je     L6
  mov    %edi,%eax
L13:
  ret
  nopl   0x0(%rax)
L21:
  mov    %edi,%eax
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L56:
  lea    (%rdi,%rax,2),%eax
  sub    %edx,%eax
  ret
  xchg   %ax,%ax
L19:
  add    %edi,%eax
  add    %esi,%eax
  ret
  nopl   (%rax)
L63:
  lea    (%rax,%rax,2),%eax
  add    %edi,%eax
  add    %ecx,%eax
  ret
L59:
  lea    (%rdi,%rax,4),%eax
  sub    %esi,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    (%rax,%rax,4),%eax
  add    %edi,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int hex_qr2l(int q, int r) {
  int s, R, l, i0;
  s = -q - r;
  R = (abs(q) + abs(r) + abs(s)) >> 1;
  if (R == 0)
    return 0;
  l = i0 = 3 * R * (R - 1) + 1;
  if (r == R)
    l = i0 - q;
  else if (q == -R)
    l = i0 + R + s;
  else if (s == R)
    l = i0 + 2 * R - r;
  else if (r == -R)
    l = i0 + 3 * R + q;
  else if (q == R)
    l = i0 + 4 * R - s;
  else if (s == -R)
    l = i0 + 5 * R + r;
  return l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<location_manual_print_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1b,%edx
  mov    $0x1,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x25,%edx
  mov    $0x1,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x70,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D26
datatype: string
name: parse_data
arguments: label: D14
datatype: string
name: parse_data
arguments: label: D9
datatype: string

tool: D26: Specify location manually.


tool: D14:   lat=N		Latitude
  lon=N		Longitude


tool: D9: Both values are expected to be floating point numbers,
negative values representing west / south, respectively.


assistant: ```c
void location_manual_print_help(FILE *f) {
  fputs("Specify location manually.\n", f);
  fputs("\n", f);
  fputs("  lat=N\t\tLatitude\n"
        "  lon=N\t\tLongitude\n",
        f);
  fputs("\n", f);
  fputs("Both values are expected to be floating point numbers,\n"
        "negative values representing west / south, respectively.\n",
        f);
  fputs("\n", f);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<location_manual_print_help>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rcx
  mov    $0x1b,%edx
  mov    $0x1,%esi
  lea    D22(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %rbx,%rcx
  mov    $0x25,%edx
  mov    $0x1,%esi
  lea    D21(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %rbx,%rcx
  mov    $0x70,%edx
  mov    $0x1,%esi
  lea    D23(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D21
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string

tool: D22: Specify location manually.


tool: D21:   lat=N		Latitude
  lon=N		Longitude


tool: D23: Both values are expected to be floating point numbers,
negative values representing west / south, respectively.


assistant: ```c
void location_manual_print_help(FILE *f) {
  fputs("Specify location manually.\n", f);
  fputs("\n", f);
  fputs("  lat=N\t\tLatitude\n"
        "  lon=N\t\tLongitude\n",
        f);
  fputs("\n", f);
  fputs("Both values are expected to be floating point numbers,\n"
        "negative values representing west / south, respectively.\n",
        f);
  fputs("\n", f);
}
```
user: What is the c source code of the assembly code below?

```asm
<location_manual_print_help>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    %rdi,%rbp
  mov    $0x1b,%edx
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %rbp,%rcx
  mov    $0x25,%edx
  mov    $0x1,%esi
  lea    D0(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %rbp,%rcx
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  mov    $0x70,%edx
  call   <fwrite@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  pop    %rbp
  jmp    1060 <fputc@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D16
type_guessed: string

tool: D4: Specify location manually.


tool: D0:   lat=N		Latitude
  lon=N		Longitude


tool: D16: Both values are expected to be floating point numbers,
negative values representing west / south, respectively.


assistant: ```c
void location_manual_print_help(FILE *f) {
  fputs("Specify location manually.\n", f);
  fputs("\n", f);
  fputs("  lat=N\t\tLatitude\n"
        "  lon=N\t\tLongitude\n",
        f);
  fputs("\n", f);
  fputs("Both values are expected to be floating point numbers,\n"
        "negative values representing west / south, respectively.\n",
        f);
  fputs("\n", f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<location_manual_print_help>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    %rdi,%rbp
  mov    $0x1b,%edx
  mov    $0x1,%esi
  lea    D15(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %rbp,%rcx
  mov    $0x25,%edx
  mov    $0x1,%esi
  lea    D28(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %rbp,%rcx
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  mov    $0x70,%edx
  call   <fwrite@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  pop    %rbp
  jmp    1060 <fputc@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D28
type_guessed: string
name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D15: Specify location manually.


tool: D28:   lat=N		Latitude
  lon=N		Longitude


tool: D9: Both values are expected to be floating point numbers,
negative values representing west / south, respectively.


assistant: ```c
void location_manual_print_help(FILE *f) {
  fputs("Specify location manually.\n", f);
  fputs("\n", f);
  fputs("  lat=N\t\tLatitude\n"
        "  lon=N\t\tLongitude\n",
        f);
  fputs("\n", f);
  fputs("Both values are expected to be floating point numbers,\n"
        "negative values representing west / south, respectively.\n",
        f);
  fputs("\n", f);
}
```
user: What is the c source code of the assembly code below?

```asm
<fill_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    %eax,%edi
  call   <syscall@plt>
  leave
  ret
```

assistant: ```c
int fill_rand(void *buf, size_t buflen) {
  unsigned int flags;
  flags = 0;
  return syscall(SYS_getrandom, buf, buflen, flags);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fill_rand>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    $0x0,%ecx
  mov    %rdi,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fill_rand(void *buf, size_t buflen) {
  unsigned int flags;
  flags = 0;
  return syscall(SYS_getrandom, buf, buflen, flags);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill_rand>:
  endbr64
  mov    D7(%rip),%rax
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  mov    (%rax),%edi
  jmp    1050 <syscall@plt>
```

assistant: ```c
int fill_rand(void *buf, size_t buflen) {
  unsigned int flags;
  flags = 0;
  return syscall(SYS_getrandom, buf, buflen, flags);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fill_rand>:
  endbr64
  mov    D3(%rip),%rax
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  mov    (%rax),%edi
  jmp    1050 <syscall@plt>
```

assistant: ```c
int fill_rand(void *buf, size_t buflen) {
  unsigned int flags;
  flags = 0;
  return syscall(SYS_getrandom, buf, buflen, flags);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L19
L54:
  movl   $0x1,-0xc(%rbp)
  jmp    L16
L47:
  movl   $0x1,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L29
L21:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L21
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L47
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L54
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrix_multiply(float **a, float **b, float **c, int r1, int c1, int c2) {
  int i, j, k;
  float sum;
  for (i = 1; i <= r1; i++) {
    for (j = 1; j <= c2; j++) {
      for (k = 1, sum = 0.0; k <= c1; k++) {
        sum += a[i][k] * b[k][j];
      }
      c[i][j] = sum;
    }
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix_multiply>:
  endbr64
  test   %ecx,%ecx
  jle    L40
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %r8d,%r11d
  mov    %r9d,%r12d
  lea    0x1(%rcx),%r13d
  lea    -0x1(%r9),%eax
  lea    0x8(,%rax,4),%rbp
  mov    $0x1,%r9d
  lea    0x1(%r8),%r8d
  jmp    L15
L50:
  mov    (%r10,%r9,8),%rsi
  mov    $0x1,%eax
  pxor   %xmm1,%xmm1
L72:
  mov    (%rdi,%rax,8),%rdx
  movss  (%rdx,%rcx,1),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L72
L46:
  mov    (%rbx,%r9,8),%rax
  movss  %xmm1,(%rax,%rcx,1)
  add    $0x4,%rcx
  cmp    %rbp,%rcx
  je     L5
L31:
  pxor   %xmm1,%xmm1
  test   %r11d,%r11d
  jg     L50
  jmp    L46
L5:
  add    $0x1,%r9
  cmp    %r13,%r9
  je     L74
L15:
  mov    $0x4,%ecx
  test   %r12d,%r12d
  jg     L31
  jmp    L5
L74:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  ret
```

assistant: ```c
void matrix_multiply(float **a, float **b, float **c, int r1, int c1, int c2) {
  int i, j, k;
  float sum;
  for (i = 1; i <= r1; i++) {
    for (j = 1; j <= c2; j++) {
      for (k = 1, sum = 0.0; k <= c1; k++) {
        sum += a[i][k] * b[k][j];
      }
      c[i][j] = sum;
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix_multiply>:
  endbr64
  test   %ecx,%ecx
  jle    L5
  lea    -0x1(%r9),%eax
  push   %r14
  mov    %rdi,%r11
  lea    0x1(%rcx),%r14d
  push   %r13
  mov    %rsi,%rdi
  mov    %r9d,%r13d
  pxor   %xmm2,%xmm2
  push   %r12
  mov    $0x1,%r9d
  lea    0x8(,%rax,4),%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %r8d,%ebx
  lea    0x1(%r8),%r8d
  nopl   0x0(%rax)
L17:
  test   %r13d,%r13d
  jle    L31
  mov    0x0(%rbp,%r9,8),%r10
  mov    $0x4,%ecx
  nopw   0x0(%rax,%rax,1)
L26:
  movaps %xmm2,%xmm1
  test   %ebx,%ebx
  jle    L12
  mov    (%r11,%r9,8),%rsi
  mov    $0x1,%eax
  movaps %xmm2,%xmm1
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rdi,%rax,8),%rdx
  movss  (%rdx,%rcx,1),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L8
L12:
  movss  %xmm1,(%r10,%rcx,1)
  add    $0x4,%rcx
  cmp    %rcx,%r12
  jne    L26
L31:
  add    $0x1,%r9
  cmp    %r9,%r14
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  ret
```

assistant: ```c
void matrix_multiply(float **a, float **b, float **c, int r1, int c1, int c2) {
  int i, j, k;
  float sum;
  for (i = 1; i <= r1; i++) {
    for (j = 1; j <= c2; j++) {
      for (k = 1, sum = 0.0; k <= c1; k++) {
        sum += a[i][k] * b[k][j];
      }
      c[i][j] = sum;
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<matrix_multiply>:
  endbr64
  test   %ecx,%ecx
  jle    L55
  test   %r9d,%r9d
  jle    L55
  push   %r13
  mov    %rdi,%r11
  lea    0x1(%rcx),%r13d
  mov    %rsi,%rdi
  push   %r12
  lea    0x1(%r9),%r12d
  pxor   %xmm2,%xmm2
  mov    $0x1,%r9d
  push   %rbp
  shl    $0x2,%r12
  mov    %rdx,%rbp
  push   %rbx
  mov    %r8d,%ebx
  lea    0x1(%r8),%r8d
  nopl   0x0(%rax)
L1:
  mov    0x0(%rbp,%r9,8),%r10
  mov    $0x4,%ecx
  nopw   0x0(%rax,%rax,1)
L31:
  movaps %xmm2,%xmm1
  test   %ebx,%ebx
  jle    L23
  mov    (%r11,%r9,8),%rsi
  mov    $0x1,%eax
  movaps %xmm2,%xmm1
  nopl   0x0(%rax,%rax,1)
L34:
  mov    (%rdi,%rax,8),%rdx
  movss  (%rdx,%rcx,1),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L34
L23:
  movss  %xmm1,(%r10,%rcx,1)
  add    $0x4,%rcx
  cmp    %rcx,%r12
  jne    L31
  add    $0x1,%r9
  cmp    %r9,%r13
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L55:
  ret
```

assistant: ```c
void matrix_multiply(float **a, float **b, float **c, int r1, int c1, int c2) {
  int i, j, k;
  float sum;
  for (i = 1; i <= r1; i++) {
    for (j = 1; j <= c2; j++) {
      for (k = 1, sum = 0.0; k <= c1; k++) {
        sum += a[i][k] * b[k][j];
      }
      c[i][j] = sum;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rt_thread_set_self_cpuaffinity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rt_thread_set_self_cpuaffinity(int cpu) {
  int status = -1;
  return status;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rt_thread_set_self_cpuaffinity>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rt_thread_set_self_cpuaffinity(int cpu) {
  int status = -1;
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rt_thread_set_self_cpuaffinity>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rt_thread_set_self_cpuaffinity(int cpu) {
  int status = -1;
  return status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rt_thread_set_self_cpuaffinity>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rt_thread_set_self_cpuaffinity(int cpu) {
  int status = -1;
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test02>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  and    %edx,%eax
  test   %ax,%ax
  je     L18
  mov    -0x14(%rbp),%eax
  jmp    L16
L18:
  mov    -0x18(%rbp),%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int test02(short *a, short *b, int c, int d) {
  if (*a & *b)
    return c;
  return d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test02>:
  endbr64
  movzwl (%rdi),%eax
  and    (%rsi),%ax
  mov    %edx,%eax
  cmove  %ecx,%eax
  ret
```

assistant: ```c
int test02(short *a, short *b, int c, int d) {
  if (*a & *b)
    return c;
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test02>:
  endbr64
  movzwl (%rdi),%eax
  and    (%rsi),%ax
  mov    %edx,%eax
  cmove  %ecx,%eax
  ret
```

assistant: ```c
int test02(short *a, short *b, int c, int d) {
  if (*a & *b)
    return c;
  return d;
}
```
user: What is the c source code of the assembly code below:

```asm
<test02>:
  endbr64
  movzwl (%rdi),%eax
  and    (%rsi),%ax
  mov    %edx,%eax
  cmove  %ecx,%eax
  ret
```

assistant: ```c
int test02(short *a, short *b, int c, int d) {
  if (*a & *b)
    return c;
  return d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ar933x_uart_get_baud>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  shl    $0x11,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shr    %eax
  add    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long ar933x_uart_get_baud(unsigned int clk, unsigned int scale, unsigned int step) {
  uint64_t t;
  uint64_t div;
  div = (2 << 16) * (scale + 1);
  t = clk;
  t *= step;
  t += (div / 2);
  ({
    uint32_t __base = (div);
    uint32_t __rem;
    __rem = ((uint64_t)(t)) % __base;
    (t) = ((uint64_t)(t)) / __base;
    __rem;
  });
  return t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ar933x_uart_get_baud>:
  endbr64
  add    $0x1,%esi
  shl    $0x11,%esi
  imul   %edx,%edi
  mov    %esi,%eax
  shr    %eax
  add    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  ret
```

assistant: ```c
unsigned long ar933x_uart_get_baud(unsigned int clk, unsigned int scale, unsigned int step) {
  uint64_t t;
  uint64_t div;
  div = (2 << 16) * (scale + 1);
  t = clk;
  t *= step;
  t += (div / 2);
  ({
    uint32_t __base = (div);
    uint32_t __rem;
    __rem = ((uint64_t)(t)) % __base;
    (t) = ((uint64_t)(t)) / __base;
    __rem;
  });
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ar933x_uart_get_baud>:
  endbr64
  add    $0x1,%esi
  imul   %edx,%edi
  xor    %edx,%edx
  shl    $0x11,%esi
  mov    %esi,%eax
  shr    %eax
  add    %edi,%eax
  div    %esi
  ret
```

assistant: ```c
unsigned long ar933x_uart_get_baud(unsigned int clk, unsigned int scale, unsigned int step) {
  uint64_t t;
  uint64_t div;
  div = (2 << 16) * (scale + 1);
  t = clk;
  t *= step;
  t += (div / 2);
  ({
    uint32_t __base = (div);
    uint32_t __rem;
    __rem = ((uint64_t)(t)) % __base;
    (t) = ((uint64_t)(t)) / __base;
    __rem;
  });
  return t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ar933x_uart_get_baud>:
  endbr64
  add    $0x1,%esi
  imul   %edx,%edi
  xor    %edx,%edx
  shl    $0x11,%esi
  mov    %esi,%eax
  shr    %eax
  add    %edi,%eax
  div    %esi
  ret
```

assistant: ```c
unsigned long ar933x_uart_get_baud(unsigned int clk, unsigned int scale, unsigned int step) {
  uint64_t t;
  uint64_t div;
  div = (2 << 16) * (scale + 1);
  t = clk;
  t *= step;
  t += (div / 2);
  ({
    uint32_t __base = (div);
    uint32_t __rem;
    __rem = ((uint64_t)(t)) % __base;
    (t) = ((uint64_t)(t)) / __base;
    __rem;
  });
  return t;
}
```