ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rdhead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <dskbor_@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L35
  mov    -0xc(%rbp),%eax
  jmp    L48
L35:
  movl   $0x1,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dskbwr_@plt>
  movl   $0x200,-0x20(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <dskbr_@plt>
  mov    -0x30(%rbp),%rax
  add    $0x200,%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L3
  mov    -0x30(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gethdl@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jg     L75
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L57
L75:
  mov    -0x18(%rbp),%eax
  sub    $0x200,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jle    L95
  mov    -0x30(%rbp),%rax
  lea    0x200(%rax),%rsi
  lea    -0xc(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <dskbr_@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jmp    L95
L3:
  nop
  jmp    L57
L95:
  nop
L57:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L51
  lea    -0xc(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dskbcr_@plt>
  jmp    L106
L51:
  lea    -0x1c(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dskbcr_@plt>
L106:
  mov    -0xc(%rbp),%eax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

assistant: ```c
int rdhead(char *filename, char *head) {
  int readl;
  int j;
  int lhead;
  int lun;
  int lflag;
  int istat;
  lun = 1;
  j = strlen(filename);
  dskbor_(&lun, filename, &j, &istat);
  if (istat != 0)
    return istat;
  lflag = (1 == 1);
  dskbwr_(&lun, &lflag);
  readl = 512;
  dskbr_(&lun, head, &readl, &istat);
  head[512] = 0;
  if (istat != 0)
    goto close;
  gethdl(&lhead, head);
  if (lhead <= 0) {
    istat = -1;
    goto close;
  }
  readl = lhead - 512;
  if (readl > 0) {
    dskbr_(&lun, head + 512, &readl, &istat);
    if (istat != 0)
      goto close;
  }
close:
  if (istat == 0)
    dskbcr_(&lun, &istat);
  else
    dskbcr_(&lun, &j);
  return istat;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rdhead>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  call   <strlen@plt>
  mov    %eax,0x4(%rsp)
  lea    0x14(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  lea    0xc(%rsp),%rdi
  mov    %rbx,%rsi
  call   <dskbor_@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L81
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L94
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L81:
  movl   $0x1,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <dskbwr_@plt>
  movl   $0x200,(%rsp)
  lea    0x14(%rsp),%rcx
  mov    %rsp,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <dskbr_@plt>
  movb   $0x0,0x200(%rbp)
  cmpl   $0x0,0x14(%rsp)
  je     L37
L59:
  lea    0x4(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <dskbcr_@plt>
  jmp    L76
L37:
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <gethdl@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L7
  sub    $0x200,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jg     L8
L33:
  cmpl   $0x0,0x14(%rsp)
  jne    L59
  lea    0x14(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <dskbcr_@plt>
L76:
  mov    0x14(%rsp),%eax
  jmp    L15
L7:
  movl   $0xffffffff,0x14(%rsp)
  jmp    L59
L8:
  lea    0x14(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x200(%rbp),%rsi
  lea    0xc(%rsp),%rdi
  call   <dskbr_@plt>
  jmp    L33
L94:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rdhead(char *filename, char *head) {
  int readl;
  int j;
  int lhead;
  int lun;
  int lflag;
  int istat;
  lun = 1;
  j = strlen(filename);
  dskbor_(&lun, filename, &j, &istat);
  if (istat != 0)
    return istat;
  lflag = (1 == 1);
  dskbwr_(&lun, &lflag);
  readl = 512;
  dskbr_(&lun, head, &readl, &istat);
  head[512] = 0;
  if (istat != 0)
    goto close;
  gethdl(&lhead, head);
  if (lhead <= 0) {
    istat = -1;
    goto close;
  }
  readl = lhead - 512;
  if (readl > 0) {
    dskbr_(&lun, head + 512, &readl, &istat);
    if (istat != 0)
      goto close;
  }
close:
  if (istat == 0)
    dskbcr_(&lun, &istat);
  else
    dskbcr_(&lun, &j);
  return istat;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rdhead>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r13
  lea    0x4(%rsp),%r14
  movl   $0x1,0xc(%rsp)
  call   <strlen@plt>
  lea    0xc(%rsp),%r12
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,0x4(%rsp)
  call   <dskbor_@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L48
L57:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L48:
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  mov    %rsp,%r15
  movl   $0x1,0x10(%rsp)
  call   <dskbwr_@plt>
  mov    %r15,%rdx
  mov    %r13,%rcx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  movl   $0x200,(%rsp)
  call   <dskbr_@plt>
  mov    0x14(%rsp),%edx
  movb   $0x0,0x200(%rbx)
  test   %edx,%edx
  jne    L49
  lea    0x8(%rsp),%rdi
  mov    %rbx,%rsi
  call   <gethdl@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L16
  sub    $0x200,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jle    L14
  lea    0x200(%rbx),%rsi
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    %r12,%rdi
  call   <dskbr_@plt>
L14:
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L49
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <dskbcr_@plt>
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L16:
  movl   $0xffffffff,0x14(%rsp)
L49:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <dskbcr_@plt>
L4:
  mov    0x14(%rsp),%eax
  jmp    L57
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rdhead(char *filename, char *head) {
  int readl;
  int j;
  int lhead;
  int lun;
  int lflag;
  int istat;
  lun = 1;
  j = strlen(filename);
  dskbor_(&lun, filename, &j, &istat);
  if (istat != 0)
    return istat;
  lflag = (1 == 1);
  dskbwr_(&lun, &lflag);
  readl = 512;
  dskbr_(&lun, head, &readl, &istat);
  head[512] = 0;
  if (istat != 0)
    goto close;
  gethdl(&lhead, head);
  if (lhead <= 0) {
    istat = -1;
    goto close;
  }
  readl = lhead - 512;
  if (readl > 0) {
    dskbr_(&lun, head + 512, &readl, &istat);
    if (istat != 0)
      goto close;
  }
close:
  if (istat == 0)
    dskbcr_(&lun, &istat);
  else
    dskbcr_(&lun, &j);
  return istat;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rdhead>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r13
  lea    0x4(%rsp),%r14
  movl   $0x1,0xc(%rsp)
  call   <strlen@plt>
  lea    0xc(%rsp),%r12
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,0x4(%rsp)
  call   <dskbor_@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L29
L43:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  mov    %rsp,%r15
  movl   $0x1,0x10(%rsp)
  call   <dskbwr_@plt>
  mov    %r15,%rdx
  mov    %r13,%rcx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  movl   $0x200,(%rsp)
  call   <dskbr_@plt>
  mov    0x14(%rsp),%edx
  movb   $0x0,0x200(%rbx)
  test   %edx,%edx
  jne    L40
  lea    0x8(%rsp),%rdi
  mov    %rbx,%rsi
  call   <gethdl@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L4
  sub    $0x200,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jle    L23
  lea    0x200(%rbx),%rsi
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    %r12,%rdi
  call   <dskbr_@plt>
L23:
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L40
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <dskbcr_@plt>
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L4:
  movl   $0xffffffff,0x14(%rsp)
L40:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <dskbcr_@plt>
L37:
  mov    0x14(%rsp),%eax
  jmp    L43
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rdhead(char *filename, char *head) {
  int readl;
  int j;
  int lhead;
  int lun;
  int lflag;
  int istat;
  lun = 1;
  j = strlen(filename);
  dskbor_(&lun, filename, &j, &istat);
  if (istat != 0)
    return istat;
  lflag = (1 == 1);
  dskbwr_(&lun, &lflag);
  readl = 512;
  dskbr_(&lun, head, &readl, &istat);
  head[512] = 0;
  if (istat != 0)
    goto close;
  gethdl(&lhead, head);
  if (lhead <= 0) {
    istat = -1;
    goto close;
  }
  readl = lhead - 512;
  if (readl > 0) {
    dskbr_(&lun, head + 512, &readl, &istat);
    if (istat != 0)
      goto close;
  }
close:
  if (istat == 0)
    dskbcr_(&lun, &istat);
  else
    dskbcr_(&lun, &j);
  return istat;
}
```
user: What is the c source code of the assembly code below:

```asm
<arccaesar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L14
  mov    $0xa,%eax
  jmp    L15
L14:
  cmpl   $0x1,-0x14(%rbp)
  jne    L21
  mov    $0x9,%eax
  jmp    L15
L21:
  addl   $0x1e,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
char arccaesar(int n) {
  int c;
  if (n == 0) {
    return '\n';
  } else if (n == 1) {
    return '\011';
  } else {
    n = n + 30;
    c = (char)n;
    return c;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<arccaesar>:
  endbr64
  mov    $0xa,%eax
  test   %edi,%edi
  je     L2
  lea    0x1e(%rdi),%edx
  cmp    $0x1,%edi
  mov    $0x9,%eax
  cmovne %edx,%eax
L2:
  ret
```

assistant: ```c
char arccaesar(int n) {
  int c;
  if (n == 0) {
    return '\n';
  } else if (n == 1) {
    return '\011';
  } else {
    n = n + 30;
    c = (char)n;
    return c;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<arccaesar>:
  endbr64
  mov    $0xa,%eax
  test   %edi,%edi
  je     L0
  lea    0x1e(%rdi),%edx
  cmp    $0x1,%edi
  mov    $0x9,%eax
  cmovne %edx,%eax
L0:
  ret
```

assistant: ```c
char arccaesar(int n) {
  int c;
  if (n == 0) {
    return '\n';
  } else if (n == 1) {
    return '\011';
  } else {
    n = n + 30;
    c = (char)n;
    return c;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<arccaesar>:
  endbr64
  mov    $0xa,%eax
  test   %edi,%edi
  je     L3
  lea    0x1e(%rdi),%edx
  cmp    $0x1,%edi
  mov    $0x9,%eax
  cmovne %edx,%eax
L3:
  ret
```

assistant: ```c
char arccaesar(int n) {
  int c;
  if (n == 0) {
    return '\n';
  } else if (n == 1) {
    return '\011';
  } else {
    n = n + 30;
    c = (char)n;
    return c;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<k_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L7:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void k_memcpy(void *dest, const void *src, int size) {
  int i;
  char *pDest = (char *)dest;
  char *pSrc = (char *)src;
  for (i = 0; i < size; i++) {
    *pDest++ = *pSrc++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<k_memcpy>:
  endbr64
  test   %edx,%edx
  jle    L0
  mov    %edx,%edx
  mov    $0x0,%eax
L5:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L0:
  ret
```

assistant: ```c
void k_memcpy(void *dest, const void *src, int size) {
  int i;
  char *pDest = (char *)dest;
  char *pSrc = (char *)src;
  for (i = 0; i < size; i++) {
    *pDest++ = *pSrc++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<k_memcpy>:
  endbr64
  test   %edx,%edx
  jle    L12
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L0:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
L12:
  ret
```

assistant: ```c
void k_memcpy(void *dest, const void *src, int size) {
  int i;
  char *pDest = (char *)dest;
  char *pSrc = (char *)src;
  for (i = 0; i < size; i++) {
    *pDest++ = *pSrc++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<k_memcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L0
  lea    0x1(%rsi),%r8
  mov    %edx,%r9d
  lea    -0x1(%rdx),%eax
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L20
  cmp    $0x6,%eax
  jbe    L20
  cmp    $0xe,%eax
  jbe    L123
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L63:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L63
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%r10d
  lea    (%rcx,%r10,1),%rdi
  lea    (%rsi,%r10,1),%r8
  cmp    %eax,%edx
  je     L0
  mov    %edx,%r9d
  sub    %eax,%r9d
  lea    -0x1(%r9),%r11d
  cmp    $0x6,%r11d
  jbe    L42
L4:
  mov    (%rsi,%r10,1),%rsi
  mov    %rsi,(%rcx,%r10,1)
  mov    %r9d,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%esi
  add    %ecx,%eax
  add    %rsi,%rdi
  add    %rsi,%r8
  cmp    %ecx,%r9d
  je     L0
L42:
  movzbl (%r8),%ecx
  mov    %cl,(%rdi)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jle    L0
  movzbl 0x1(%r8),%ecx
  mov    %cl,0x1(%rdi)
  lea    0x2(%rax),%ecx
  cmp    %ecx,%edx
  jle    L0
  movzbl 0x2(%r8),%ecx
  mov    %cl,0x2(%rdi)
  lea    0x3(%rax),%ecx
  cmp    %ecx,%edx
  jle    L0
  movzbl 0x3(%r8),%ecx
  mov    %cl,0x3(%rdi)
  lea    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L0
  movzbl 0x4(%r8),%ecx
  mov    %cl,0x4(%rdi)
  lea    0x5(%rax),%ecx
  cmp    %ecx,%edx
  jle    L0
  movzbl 0x5(%r8),%ecx
  add    $0x6,%eax
  mov    %cl,0x5(%rdi)
  cmp    %eax,%edx
  jle    L0
  movzbl 0x6(%r8),%eax
  mov    %al,0x6(%rdi)
  ret
L20:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L6:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L0:
  ret
L123:
  mov    %rsi,%r8
  mov    %rcx,%rdi
  xor    %eax,%eax
  xor    %r10d,%r10d
  jmp    L4
```

assistant: ```c
void k_memcpy(void *dest, const void *src, int size) {
  int i;
  char *pDest = (char *)dest;
  char *pSrc = (char *)src;
  for (i = 0; i < size; i++) {
    *pDest++ = *pSrc++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<close_link>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x20000008,%eax
  movl   $0x0,(%rax)
  mov    $0x1400000c,%eax
  movl   $0x100,(%rax)
  mov    $0x20000000,%eax
  movl   $0xa420,(%rax)
  mov    $0x0,%edi
  call   <phy_rst@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void close_link(void) {
  *(unsigned int *)(0x20000008) = 0x0;
  *(unsigned int *)(0x1400000c) = 0x100;
  *(unsigned int *)(0x20000000) = 0xa420;
  phy_rst(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<close_link>:
  endbr64
  sub    $0x8,%rsp
  movl   $0x0,0x20000008
  movl   $0x100,0x1400000c
  movl   $0xa420,0x20000000
  mov    $0x0,%edi
  call   <phy_rst@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void close_link(void) {
  *(unsigned int *)(0x20000008) = 0x0;
  *(unsigned int *)(0x1400000c) = 0x100;
  *(unsigned int *)(0x20000000) = 0xa420;
  phy_rst(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<close_link>:
  endbr64
  movl   $0x0,0x20000008
  xor    %edi,%edi
  movl   $0x100,0x1400000c
  movl   $0xa420,0x20000000
  jmp    1050 <phy_rst@plt>
```

assistant: ```c
void close_link(void) {
  *(unsigned int *)(0x20000008) = 0x0;
  *(unsigned int *)(0x1400000c) = 0x100;
  *(unsigned int *)(0x20000000) = 0xa420;
  phy_rst(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<close_link>:
  endbr64
  movl   $0x0,0x20000008
  xor    %edi,%edi
  movl   $0x100,0x1400000c
  movl   $0xa420,0x20000000
  jmp    1050 <phy_rst@plt>
```

assistant: ```c
void close_link(void) {
  *(unsigned int *)(0x20000008) = 0x0;
  *(unsigned int *)(0x1400000c) = 0x100;
  *(unsigned int *)(0x20000000) = 0xa420;
  phy_rst(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<free_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L19
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L19:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void free_words(char **arr, int wc) {
  while (wc--)
    free(arr[wc]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_words>:
  endbr64
  test   %esi,%esi
  je     L6
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%eax
  cltq
  shl    $0x3,%rax
  lea    (%rdi,%rax,1),%rbx
  lea    -0x8(%rdi,%rax,1),%rbp
  lea    -0x1(%rsi),%eax
  shl    $0x3,%rax
  sub    %rax,%rbp
L13:
  mov    (%rbx),%rdi
  call   <free@plt>
  sub    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  ret
```

assistant: ```c
void free_words(char **arr, int wc) {
  while (wc--)
    free(arr[wc]);
}
```
user: What is the c source code of the assembly code below?

```asm
<free_words>:
  endbr64
  test   %esi,%esi
  je     L18
  lea    -0x1(%rsi),%eax
  push   %rbp
  movslq %eax,%rdx
  push   %rbx
  mov    %eax,%eax
  shl    $0x3,%rdx
  shl    $0x3,%rax
  lea    -0x8(%rdi,%rdx,1),%rbp
  lea    (%rdi,%rdx,1),%rbx
  sub    $0x8,%rsp
  sub    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rbx),%rdi
  sub    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void free_words(char **arr, int wc) {
  while (wc--)
    free(arr[wc]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_words>:
  endbr64
  test   %esi,%esi
  je     L11
  lea    -0x1(%rsi),%eax
  push   %rbp
  movslq %eax,%rdx
  push   %rbx
  mov    %eax,%eax
  shl    $0x3,%rdx
  shl    $0x3,%rax
  lea    -0x8(%rdi,%rdx,1),%rbp
  lea    (%rdi,%rdx,1),%rbx
  sub    $0x8,%rsp
  sub    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rdi
  sub    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
void free_words(char **arr, int wc) {
  while (wc--)
    free(arr[wc]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i2st>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L28
  mov    -0x18(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L15
L23:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L28:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L23
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strrev@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
L15:
  leave
  ret
```

assistant: ```c
char *i2st(char *st, int n) {
  int i, x, ch;
  i = 0;
  if (n == 0) {
    st[0] = '0';
    st[1] = 0;
    return st;
  }
  while (n > 0) {
    x = n % 10;
    ch = x + 48;
    n = n / 10;
    st[i] = ch;
    i++;
  }
  st[i] = 0;
  st = strrev(st);
  return st;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<i2st>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  je     L20
  mov    $0x1,%ecx
  mov    $0x0,%edx
  jle    L17
L8:
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %esi,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%r8d
  add    %r8d,%r8d
  mov    %esi,%edi
  sub    %r8d,%edi
  add    $0x30,%edi
  mov    %esi,%r8d
  mov    %edx,%esi
  mov    %dil,-0x1(%rax,%rcx,1)
  mov    %ecx,%edx
  add    $0x1,%rcx
  cmp    $0x9,%r8d
  jg     L8
L17:
  sub    $0x8,%rsp
  movslq %edx,%rdx
  movb   $0x0,(%rax,%rdx,1)
  mov    %rax,%rdi
  call   <strrev@plt>
  add    $0x8,%rsp
  ret
L20:
  movb   $0x30,(%rdi)
  movb   $0x0,0x1(%rdi)
  ret
```

assistant: ```c
char *i2st(char *st, int n) {
  int i, x, ch;
  i = 0;
  if (n == 0) {
    st[0] = '0';
    st[1] = 0;
    return st;
  }
  while (n > 0) {
    x = n % 10;
    ch = x + 48;
    n = n / 10;
    st[i] = ch;
    i++;
  }
  st[i] = 0;
  st = strrev(st);
  return st;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<i2st>:
  endbr64
  mov    %rdi,%r8
  test   %esi,%esi
  je     L26
  mov    $0x1,%edx
  mov    $0xcccccccd,%r9d
  mov    %rdi,%rax
  jle    L14
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %esi,%eax
  mov    %esi,%ecx
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%ecx
  mov    %esi,%edi
  mov    %eax,%esi
  movslq %edx,%rax
  add    $0x30,%ecx
  mov    %cl,-0x1(%r8,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x9,%edi
  jg     L15
  add    %r8,%rax
L14:
  movb   $0x0,(%rax)
  mov    %r8,%rdi
  jmp    1050 <strrev@plt>
  nopl   0x0(%rax)
L26:
  mov    $0x30,%eax
  mov    %ax,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *i2st(char *st, int n) {
  int i, x, ch;
  i = 0;
  if (n == 0) {
    st[0] = '0';
    st[1] = 0;
    return st;
  }
  while (n > 0) {
    x = n % 10;
    ch = x + 48;
    n = n / 10;
    st[i] = ch;
    i++;
  }
  st[i] = 0;
  st = strrev(st);
  return st;
}
```