ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wcstoimax>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  jmp    L16
  nopl   0x0(%rax)
L5:
  add    $0x1,%rbp
L16:
  movsbl 0x0(%rbp),%edi
  call   <iswspace@plt>
  test   %rax,%rax
  jne    L5
  movzbl 0x0(%rbp),%eax
  cmp    $0x2d,%al
  je     L55
  cmp    $0x2b,%al
  mov    %r13d,%edx
  mov    %r12,%rsi
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbp
  mov    %rbp,%rdi
  call   <wcstoumax@plt>
  mov    D27(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jg     L36
L27:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L55:
  mov    %r13d,%edx
  lea    0x1(%rbp),%rdi
  mov    %r12,%rsi
  call   <wcstoumax@plt>
  mov    %eax,%edx
  mov    D27(%rip),%rax
  cmp    (%rax),%edx
  jg     L2
  mov    %edx,%eax
  pop    %rbp
  pop    %r12
  neg    %eax
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    D67(%rip),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  je     L27
  mov    D21(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D61(%rip),%rdx
  mov    %ecx,(%rdx)
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L36:
  mov    D21(%rip),%rax
  mov    (%rax),%ecx
  mov    D61(%rip),%rax
  mov    %ecx,(%rax)
  mov    %edx,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
intmax_t wcstoimax(const wchar_t *s, wchar_t **p, int base) {
  int sign = 0;
  uintmax_t x;
  for (; iswspace(*s); s++)
    ;
  if (*s == '-')
    sign = *s++;
  else if (*s == '+')
    s++;
  x = wcstoumax(s, p, base);
  if (x > INTMAX_MAX) {
    if (!sign || -x != INTMAX_MIN)
      errno = ERANGE;
    return sign ? INTMAX_MIN : INTMAX_MAX;
  }
  return sign ? -x : x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wcstoimax>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  jmp    L37
  nopl   0x0(%rax)
L28:
  add    $0x1,%rbp
L37:
  movsbl 0x0(%rbp),%edi
  call   <iswspace@plt>
  test   %rax,%rax
  jne    L28
  movzbl 0x0(%rbp),%eax
  cmp    $0x2d,%al
  je     L0
  cmp    $0x2b,%al
  mov    %r13d,%edx
  mov    %r12,%rsi
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbp
  mov    %rbp,%rdi
  call   <wcstoumax@plt>
  mov    D2(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jg     L18
L39:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L0:
  mov    %r13d,%edx
  lea    0x1(%rbp),%rdi
  mov    %r12,%rsi
  call   <wcstoumax@plt>
  mov    %eax,%edx
  mov    D2(%rip),%rax
  cmp    (%rax),%edx
  jg     L30
  mov    %edx,%eax
  pop    %rbp
  pop    %r12
  neg    %eax
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    D50(%rip),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  je     L39
  mov    D61(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D15(%rip),%rdx
  mov    %ecx,(%rdx)
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  mov    D61(%rip),%rax
  mov    (%rax),%ecx
  mov    D15(%rip),%rax
  mov    %ecx,(%rax)
  mov    %edx,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
intmax_t wcstoimax(const wchar_t *s, wchar_t **p, int base) {
  int sign = 0;
  uintmax_t x;
  for (; iswspace(*s); s++)
    ;
  if (*s == '-')
    sign = *s++;
  else if (*s == '+')
    s++;
  x = wcstoumax(s, p, base);
  if (x > INTMAX_MAX) {
    if (!sign || -x != INTMAX_MIN)
      errno = ERANGE;
    return sign ? INTMAX_MIN : INTMAX_MAX;
  }
  return sign ? -x : x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dc_diffmax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8d,-0x40(%rbp)
  mov    %r9d,-0x44(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L68
L30:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L32
L13:
  mov    -0x40(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L32:
  mov    -0x1c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L13
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jge    L59
  movsd  -0x10(%rbp),%xmm0
  movq   D8(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L59:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L19
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L19:
  addl   $0x1,-0x20(%rbp)
L68:
  mov    -0x20(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L30
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L66
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L66:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: qword

tool: D8: 9223372036854775807

assistant: ```c
double dc_diffmax(double *A, double *b, double *x, int neq, int m, int n) {
  double ax, d, dmax = 0;
  for (int i = 0; i < m; ++i) {
    ax = 0;
    for (int j = 0; j < n; ++j) {
      ax += A[i + m * j] * x[j];
    }
    d = ax - b[i];
    if (i < neq)
      d = fabs(d);
    if (d > dmax)
      dmax = d;
  }
  if (dmax < 0)
    dmax = 0;
  return dmax;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dc_diffmax>:
  endbr64
  test   %r8d,%r8d
  jle    L81
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  mov    %r8d,%r12d
  movslq %r8d,%rcx
  shl    $0x3,%rcx
  lea    -0x1(%r9),%eax
  lea    0x8(%rdx,%rax,8),%rsi
  mov    $0x0,%edi
  pxor   %xmm2,%xmm2
  movq   D3(%rip),%xmm3
  jmp    L6
L86:
  maxsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  add    $0x1,%rdi
  add    $0x8,%r10
  cmp    %r12,%rdi
  je     L82
L6:
  pxor   %xmm1,%xmm1
  test   %r9d,%r9d
  jle    L38
  mov    %rbx,%rax
  mov    %r10,%rdx
  pxor   %xmm1,%xmm1
L34:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  add    %rcx,%rdx
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L34
L38:
  subsd  (%r11,%rdi,8),%xmm1
  cmp    %edi,%ebp
  jle    L86
  andpd  %xmm3,%xmm1
  jmp    L86
L82:
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L10
L68:
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  movapd %xmm0,%xmm2
  jmp    L68
L81:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: qword

tool: D3: 9223372036854775807

assistant: ```c
double dc_diffmax(double *A, double *b, double *x, int neq, int m, int n) {
  double ax, d, dmax = 0;
  for (int i = 0; i < m; ++i) {
    ax = 0;
    for (int j = 0; j < n; ++j) {
      ax += A[i + m * j] * x[j];
    }
    d = ax - b[i];
    if (i < neq)
      d = fabs(d);
    if (d > dmax)
      dmax = d;
  }
  if (dmax < 0)
    dmax = 0;
  return dmax;
}
```
user: What is the c source code of the assembly code below?

```asm
<dc_diffmax>:
  endbr64
  test   %r8d,%r8d
  jle    L16
  movslq %r8d,%r8
  lea    -0x1(%r9),%eax
  pxor   %xmm3,%xmm3
  push   %rbp
  movq   D1(%rip),%xmm4
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %ecx,%ebp
  mov    %rdx,%rbx
  lea    0x0(,%r8,8),%rsi
  xor    %edi,%edi
  lea    0x8(%rdx,%rax,8),%rcx
  movapd %xmm3,%xmm2
L4:
  mov    %rbx,%rax
  mov    %r10,%rdx
  movapd %xmm3,%xmm1
  test   %r9d,%r9d
  jle    L49
  nop
L25:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L25
L49:
  subsd  (%r11,%rdi,8),%xmm1
  cmp    %edi,%ebp
  jle    L43
  andpd  %xmm4,%xmm1
L43:
  maxsd  %xmm2,%xmm1
  add    $0x1,%rdi
  add    $0x8,%r10
  movapd %xmm1,%xmm2
  cmp    %r8,%rdi
  jne    L4
  maxsd  %xmm1,%xmm3
  pop    %rbx
  pop    %rbp
  movapd %xmm3,%xmm0
  ret
L16:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: qword

tool: D1: 9223372036854775807

assistant: ```c
double dc_diffmax(double *A, double *b, double *x, int neq, int m, int n) {
  double ax, d, dmax = 0;
  for (int i = 0; i < m; ++i) {
    ax = 0;
    for (int j = 0; j < n; ++j) {
      ax += A[i + m * j] * x[j];
    }
    d = ax - b[i];
    if (i < neq)
      d = fabs(d);
    if (d > dmax)
      dmax = d;
  }
  if (dmax < 0)
    dmax = 0;
  return dmax;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dc_diffmax>:
  endbr64
  test   %r8d,%r8d
  jle    L68
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %ecx,%ecx
  jg     L23
  pxor   %xmm3,%xmm3
  xor    %r10d,%r10d
  lea    -0x1(%r9),%r14d
  movslq %r8d,%rcx
  movapd %xmm3,%xmm2
  lea    0x8(%rdx),%r15
L27:
  movslq %r10d,%r10
  shl    $0x3,%rcx
  lea    (%r15,%r14,8),%rsi
  lea    (%r12,%r10,8),%rdi
  nopl   (%rax)
L75:
  test   %r9d,%r9d
  jle    L40
  mov    %rbx,%rax
  mov    %rdi,%rdx
  movapd %xmm3,%xmm1
  nop
L4:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rcx,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L4
L54:
  subsd  0x0(%rbp,%r10,8),%xmm1
  add    $0x1,%r10
  add    $0x8,%rdi
  maxsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  cmp    %r10d,%r8d
  jg     L75
L63:
  maxsd  %xmm2,%xmm3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  movapd %xmm3,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  movapd %xmm3,%xmm1
  jmp    L54
  cs nopw 0x0(%rax,%rax,1)
L23:
  lea    -0x1(%r9),%r14d
  lea    0x8(%rdx),%r15
  pxor   %xmm3,%xmm3
  cmp    %ecx,%r8d
  cmovle %r8d,%ecx
  mov    %r14d,%eax
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  movq   D9(%rip),%xmm4
  lea    (%r15,%rax,8),%rsi
  movapd %xmm3,%xmm2
  mov    %ecx,%r13d
  movslq %r8d,%rcx
  lea    0x0(,%rcx,8),%rdi
  nopw   0x0(%rax,%rax,1)
L94:
  lea    (%r12,%r11,1),%rdx
  mov    %rbx,%rax
  movapd %xmm3,%xmm1
  test   %r9d,%r9d
  jle    L102
L7:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L7
L102:
  subsd  0x0(%rbp,%r11,1),%xmm1
  add    $0x1,%r10d
  add    $0x8,%r11
  andpd  %xmm4,%xmm1
  maxsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  cmp    %r13d,%r10d
  jl     L94
  cmp    %r10d,%r8d
  jg     L27
  jmp    L63
L68:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: qword

tool: D9: 9223372036854775807

assistant: ```c
double dc_diffmax(double *A, double *b, double *x, int neq, int m, int n) {
  double ax, d, dmax = 0;
  for (int i = 0; i < m; ++i) {
    ax = 0;
    for (int j = 0; j < n; ++j) {
      ax += A[i + m * j] * x[j];
    }
    d = ax - b[i];
    if (i < neq)
      d = fabs(d);
    if (d > dmax)
      dmax = d;
  }
  if (dmax < 0)
    dmax = 0;
  return dmax;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <top_show@plt>
  mov    $0x0,%eax
  call   <igetkey@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <clrtoeol@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ask(char *prompt) {
  int ch;
  top_show(prompt);
  ch = igetkey();
  move(0, 0);
  clrtoeol();
  return (ch);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ask>:
  endbr64
  push   %rbx
  call   <top_show@plt>
  mov    $0x0,%eax
  call   <igetkey@plt>
  mov    %eax,%ebx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <clrtoeol@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ask(char *prompt) {
  int ch;
  top_show(prompt);
  ch = igetkey();
  move(0, 0);
  clrtoeol();
  return (ch);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ask>:
  endbr64
  push   %r12
  call   <top_show@plt>
  xor    %eax,%eax
  call   <igetkey@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <move@plt>
  xor    %eax,%eax
  call   <clrtoeol@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ask(char *prompt) {
  int ch;
  top_show(prompt);
  ch = igetkey();
  move(0, 0);
  clrtoeol();
  return (ch);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ask>:
  endbr64
  push   %r12
  call   <top_show@plt>
  xor    %eax,%eax
  call   <igetkey@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <move@plt>
  xor    %eax,%eax
  call   <clrtoeol@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ask(char *prompt) {
  int ch;
  top_show(prompt);
  ch = igetkey();
  move(0, 0);
  clrtoeol();
  return (ch);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L51
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L16:
  subl   $0x1,-0xc(%rbp)
L50:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L53
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L16
L53:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L49
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
  jmp    L49
L67:
  addl   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L34
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  ja     L67
L34:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L2
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L50
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L51:
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(unsigned long long s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned long long x = s[l];
    while (i < j) {
      while (i < j && s[j] >= x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] < x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jge    L60
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r11d
  mov    %edx,%r12d
  movslq %esi,%rax
  mov    (%rdi,%rax,8),%r8
  movslq %edx,%rax
  lea    (%rdi,%rax,8),%rdx
  lea    -0x1(%r12),%ecx
  mov    %r12d,%esi
  mov    %r11d,%ebx
  jmp    L13
L65:
  mov    %esi,%r10d
  cmp    %esi,%ebx
  jge    L81
  lea    0x1(%rbx),%eax
  movslq %ebx,%rbx
  mov    %rdi,0x0(%rbp,%rbx,8)
  cmp    %esi,%eax
  jge    L107
  cltq
L43:
  mov    %eax,%ebx
  cmp    %r8,0x0(%rbp,%rax,8)
  jae    L82
  lea    0x1(%rax),%ebx
  add    $0x1,%rax
  cmp    %eax,%r10d
  jg     L43
L81:
  movslq %ebx,%rax
  mov    %r8,0x0(%rbp,%rax,8)
  lea    -0x1(%rbx),%edx
  mov    %r11d,%esi
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quick_sort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L82:
  cmp    %r10d,%eax
  jge    L81
  cltq
  mov    0x0(%rbp,%rax,8),%rax
  mov    %rax,(%r9)
  cmp    %ebx,%ecx
  jle    L81
L2:
  sub    $0x8,%rdx
  sub    $0x1,%ecx
  sub    $0x1,%esi
L13:
  mov    %rdx,%r9
  mov    (%rdx),%rdi
  cmp    %r8,%rdi
  jb     L65
  cmp    %ebx,%ecx
  jg     L2
  jmp    L81
L107:
  mov    %eax,%ebx
  jmp    L81
L60:
  ret
```

assistant: ```c
void quick_sort(unsigned long long s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned long long x = s[l];
    while (i < j) {
      while (i < j && s[j] >= x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] < x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quick_sort>:
  endbr64
  cmp    %esi,%edx
  jle    L69
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L4:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,8),%rdi
  nopw   0x0(%rax,%rax,1)
L2:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,8),%rcx
  nopl   0x0(%rax,%rax,1)
L70:
  mov    (%rcx),%rax
  cmp    %rdi,%rax
  jb     L103
  sub    $0x1,%edx
  sub    $0x8,%rcx
  cmp    %r8d,%edx
  jg     L70
L8:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L12:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %rdi,0x0(%rbp,%rax,8)
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L103:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,8),%rsi
  cmp    %edx,%r8d
  jge    L8
  mov    %rax,(%rsi)
  cmp    %edx,%ebx
  jge    L12
  movslq %ebx,%rax
  jmp    L97
  nopl   (%rax)
L83:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L12
L97:
  mov    0x0(%rbp,%rax,8),%rsi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %rdi,%rsi
  jb     L83
  sub    $0x1,%edx
  mov    %rsi,(%rcx)
  cmp    %edx,%eax
  jl     L2
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L12
  xchg   %ax,%ax
L69:
  ret
```

assistant: ```c
void quick_sort(unsigned long long s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned long long x = s[l];
    while (i < j) {
      while (i < j && s[j] >= x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] < x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quick_sort>:
  endbr64
  cmp    %esi,%edx
  jle    L106
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L80:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,8),%rdi
  nopw   0x0(%rax,%rax,1)
L88:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,8),%rcx
  nopl   0x0(%rax,%rax,1)
L34:
  mov    (%rcx),%rax
  cmp    %rdi,%rax
  jb     L14
  sub    $0x1,%edx
  sub    $0x8,%rcx
  cmp    %r8d,%edx
  jg     L34
L79:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L37:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %rdi,0x0(%rbp,%rax,8)
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L80
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L14:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,8),%rsi
  cmp    %edx,%r8d
  jge    L79
  mov    %rax,(%rsi)
  cmp    %edx,%ebx
  jge    L37
  movslq %ebx,%rax
  jmp    L24
  nopl   (%rax)
L107:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L37
L24:
  mov    0x0(%rbp,%rax,8),%rsi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %rdi,%rsi
  jb     L107
  sub    $0x1,%edx
  mov    %rsi,(%rcx)
  cmp    %edx,%eax
  jl     L88
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L37
  xchg   %ax,%ax
L106:
  ret
```

assistant: ```c
void quick_sort(unsigned long long s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned long long x = s[l];
    while (i < j) {
      while (i < j && s[j] >= x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] < x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <enqueue@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x9,-0x4(%rbp)
  jle    L7
  mov    $0x0,%eax
  call   <dequeue@plt>
  mov    $0x0,%eax
  call   <dequeue@plt>
  mov    $0xa,%edi
  call   <enqueue@plt>
  mov    $0xb,%edi
  call   <enqueue@plt>
  mov    $0x0,%eax
  call   <display@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  for (int i = 0; i < 10; i++) {
    enqueue(i);
  }
  dequeue();
  dequeue();
  enqueue(10);
  enqueue(11);
  display();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L3:
  mov    %ebx,%edi
  call   <enqueue@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L3
  mov    $0x0,%eax
  call   <dequeue@plt>
  mov    $0x0,%eax
  call   <dequeue@plt>
  mov    $0xa,%edi
  call   <enqueue@plt>
  mov    $0xb,%edi
  call   <enqueue@plt>
  mov    $0x0,%eax
  call   <display@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (int i = 0; i < 10; i++) {
    enqueue(i);
  }
  dequeue();
  dequeue();
  enqueue(10);
  enqueue(11);
  display();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <enqueue@plt>
  cmp    $0xa,%ebx
  jne    L9
  xor    %eax,%eax
  call   <dequeue@plt>
  xor    %eax,%eax
  call   <dequeue@plt>
  mov    $0xa,%edi
  call   <enqueue@plt>
  mov    $0xb,%edi
  call   <enqueue@plt>
  xor    %eax,%eax
  call   <display@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (int i = 0; i < 10; i++) {
    enqueue(i);
  }
  dequeue();
  dequeue();
  enqueue(10);
  enqueue(11);
  display();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <enqueue@plt>
  cmp    $0xa,%ebx
  jne    L6
  xor    %eax,%eax
  call   <dequeue@plt>
  xor    %eax,%eax
  call   <dequeue@plt>
  mov    $0xa,%edi
  call   <enqueue@plt>
  mov    $0xb,%edi
  call   <enqueue@plt>
  xor    %eax,%eax
  call   <display@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (int i = 0; i < 10; i++) {
    enqueue(i);
  }
  dequeue();
  dequeue();
  enqueue(10);
  enqueue(11);
  display();
}
```