user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x18(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  -0x1c(%rbp),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  mov    -0x20(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x1c(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  D28(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  mov    -0x20(%rbp),%edx
  movss  -0x1c(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movss  -0x18(%rbp),%xmm2
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm3
  movq   %xmm3,%rcx
  mov    -0x24(%rbp),%eax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  pxor   %xmm4,%xmm4
  cvtss2sd -0x10(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm5,%xmm5
  cvtss2sd -0xc(%rbp),%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D68
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D28
datatype: f32
name: read_data
arguments: data_tag: D57
datatype: string
name: read_data
arguments: data_tag: D59
datatype: string
name: read_data
arguments: data_tag: D44
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string

tool: D68: [n00862133@osprey COP2220]$ ./project2

COP2220 Project 2 - Gary Frazier


tool: D21: Enter four numbers in the format nnn nnn nnn.nn nnn.nn<enter>:

tool: D11: %d %d %f %f

tool: D28: 4

tool: D57: 
The result of the calculation ((%d - %.2f) / %.2f) * %d is %.2f



tool: D59: The sum of the input numbers is:     %.2f


tool: D44: The average of the input numbers is: %.2f



tool: D20: Have a nice day!

assistant: ```c
int main(void) {
  printf("[n00862133@osprey COP2220]$ ./project2\n\nCOP2220 Project 2 - Gary Frazier\n\n");
  int number1;
  int number2;
  float number3;
  float number4;
  printf("Enter four numbers in the format nnn nnn nnn.nn nnn.nn<enter>:\n");
  scanf("%d %d %f %f", &number1, &number2, &number3, &number4);
  float result = ((number1 - number4) / number3) * number2;
  float sum = number1 + number2 + number3 + number4;
  float avg = sum / 4;
  printf("\nThe result of the calculation ((%d - %.2f) / %.2f) * %d is %.2f\n\n", number1, number4, number3, number2, result);
  printf("The sum of the input numbers is:     %.2f\n", sum);
  printf("The average of the input numbers is: %.2f\n\n", avg);
  printf("Have a nice day!\n");
}
```