ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x4c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xd0(%rsp),%rsi
  call   <scanf@plt>
  mov    %rbp,%rbx
  mov    %rbp,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L63:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x8,%rdx
  movl   $0x0,-0x4(%rdx)
  cmp    $0x1a,%eax
  jne    L63
  movzbl 0xd0(%rsp),%eax
  test   %al,%al
  je     L20
  lea    0xd1(%rsp),%rcx
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L22:
  movsbq %dl,%rdx
  addl   $0x1,0x4(%rsp,%rdx,8)
L18:
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L20
L45:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  jbe    L22
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L18
  movsbq %al,%rax
  add    $0x1,%rcx
  addl   $0x1,0x4(%rsp,%rax,8)
  movzbl -0x1(%rcx),%eax
  test   %al,%al
  jne    L45
L20:
  mov    %rbp,%rdi
  lea    D15(%rip),%r12
  add    $0xd0,%rbp
  call   <sort_by_freeqence@plt>
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    (%rbx),%eax
  mov    0x4(%rbx),%edx
  mov    %r12,%rdi
  add    $0x8,%rbx
  lea    0x61(%rax),%esi
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L29
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x4c0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D4: %[^
]s

tool: D15: %c: %d


assistant: ```c
int main() {
  char input[1000];
  int meet_times[26][2];
  int counter;
  scanf("%[^\n]s", input);
  for (counter = 0; counter < 26; counter++) {
    meet_times[counter][0] = counter;
    meet_times[counter][1] = 0;
  }
  counter = 0;
  while (input[counter] != '\0') {
    if (input[counter] >= 'a' && input[counter] <= 'z') {
      meet_times[input[counter] - 'a'][1]++;
    } else if (input[counter] >= 'A' && input[counter] <= 'Z') {
      meet_times[input[counter] - 'A'][1]++;
    }
    counter++;
  }
  sort_by_freeqence(meet_times);
  for (counter = 0; counter < 26; counter++) {
    printf("%c: %d\n", meet_times[counter][0] + 'a', meet_times[counter][1]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L19:
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x6,-0x4(%rbp)
  jle    L39
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x6,-0x8(%rbp)
  jle    L19
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3: %2d, 

assistant: ```c
void printArray(int A[7][7]) {
  for (int i = 0; i < 7; i++) {
    for (int j = 0; j < 7; j++)
      printf("%2d, ", A[j][i]);
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printArray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0xc4(%rdi),%rbp
  lea    0xe0(%rdi),%r13
  lea    D3(%rip),%r12
L7:
  lea    -0xc4(%rbp),%rbx
L11:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1c,%rbx
  cmp    %rbp,%rbx
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: %2d, 

assistant: ```c
void printArray(int A[7][7]) {
  for (int i = 0; i < 7; i++) {
    for (int j = 0; j < 7; j++)
      printf("%2d, ", A[j][i]);
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printArray>:
  endbr64
  push   %r13
  lea    0xe0(%rdi),%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  lea    0xc4(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L13:
  lea    -0xc4(%rbp),%rbx
  nop
L5:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1c,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L5
  mov    $0xa,%edi
  lea    0x4(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: %2d, 

assistant: ```c
void printArray(int A[7][7]) {
  for (int i = 0; i < 7; i++) {
    for (int j = 0; j < 7; j++)
      printf("%2d, ", A[j][i]);
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printArray>:
  endbr64
  push   %r13
  lea    0xe0(%rdi),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    0xc4(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  lea    -0xc4(%rbp),%rbx
  nop
L6:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1c,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L6
  mov    $0xa,%edi
  lea    0x4(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: %2d, 

assistant: ```c
void printArray(int A[7][7]) {
  for (int i = 0; i < 7; i++) {
    for (int j = 0; j < 7; j++)
      printf("%2d, ", A[j][i]);
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D28(%rip),%r15
  mov    $0x0,%edx
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  mov    (%r15),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  mov    0x8(%rbx),%rdi
  call   <gethostbyname@plt>
  mov    %rax,%r13
  lea    -0x44(%rbp),%r14
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  mov    0x8(%r13),%rax
  lea    -0x3c(%rbp),%rdi
  mov    0x0(%r13),%edx
  mov    (%rax),%rsi
  call   <memcpy@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0x40(%rbp)
  mov    (%r15),%eax
  mov    %eax,-0x44(%rbp)
  mov    $0xc,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  mov    D30(%rip),%rax
  mov    (%rax),%edx
  movslq %edx,%rax
  add    $0xf,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L26:
  cmp    %rcx,%rsp
  je     L36
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L26
L36:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L2
  orq    $0x0,-0x8(%rsp,%rax,1)
L2:
  mov    %rsp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%edx
  mov    %rsp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %r12d,%edi
  call   <close@plt>
  mov    D36(%rip),%rax
  mov    (%rax),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct sockaddr_in saddr;
  int sock_id = socket(AF_INET, SOCK_STREAM, 0);
  struct hostent *hp = gethostbyname(argv[1]);
  memset((void *)&saddr, 0, sizeof(saddr));
  memcpy((void *)&saddr.sin_addr, (const void *)hp->h_addr_list[0], hp->h_length);
  saddr.sin_port = htons(atoi(argv[2]));
  saddr.sin_family = AF_INET;
  connect(sock_id, (struct sockaddr *)&saddr, sizeof(saddr));
  char message[BUFSIZ];
  int messlen = read(sock_id, message, BUFSIZ);
  write(1, message, messlen);
  close(sock_id);
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x44(%rbp),%r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    D39(%rip),%r15
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D10(%rip),%rax
  mov    (%r15),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%r12d
  call   <gethostbyname@plt>
  mov    $0xc,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  mov    0x8(%r13),%rax
  mov    0x0(%r13),%edx
  lea    -0x3c(%rbp),%rdi
  mov    (%rax),%rsi
  call   <memcpy@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  mov    %eax,-0x40(%rbp)
  mov    (%r15),%eax
  mov    %eax,-0x44(%rbp)
  call   <connect@plt>
  mov    D13(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  mov    %rax,%r8
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L19
L2:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L2
L19:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L39
L24:
  mov    %r8d,%edx
  mov    %rsp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rsp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    %r12d,%edi
  call   <close@plt>
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L39:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L24
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct sockaddr_in saddr;
  int sock_id = socket(AF_INET, SOCK_STREAM, 0);
  struct hostent *hp = gethostbyname(argv[1]);
  memset((void *)&saddr, 0, sizeof(saddr));
  memcpy((void *)&saddr.sin_addr, (const void *)hp->h_addr_list[0], hp->h_length);
  saddr.sin_port = htons(atoi(argv[2]));
  saddr.sin_family = AF_INET;
  connect(sock_id, (struct sockaddr *)&saddr, sizeof(saddr));
  char message[BUFSIZ];
  int messlen = read(sock_id, message, BUFSIZ);
  write(1, message, messlen);
  close(sock_id);
  return EXIT_SUCCESS;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x48(%rbp),%r15
  push   %r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    D33(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D23(%rip),%rax
  mov    (%r14),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%r12d
  call   <gethostbyname@plt>
  mov    $0xc,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  mov    0x8(%r13),%rax
  mov    0x0(%r13),%edx
  lea    -0x40(%rbp),%rdi
  mov    (%rax),%rsi
  call   <memcpy@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <htons@plt>
  movd   (%r14),%xmm0
  mov    %r15,%rsi
  mov    %r12d,%edi
  movd   %eax,%xmm1
  mov    $0xc,%edx
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x48(%rbp)
  call   <connect@plt>
  mov    D5(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  mov    %rax,%r8
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L49
L45:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L45
L49:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L39
L19:
  mov    %r8d,%edx
  mov    %rsp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rsp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    %r12d,%edi
  call   <close@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L39:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L19
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct sockaddr_in saddr;
  int sock_id = socket(AF_INET, SOCK_STREAM, 0);
  struct hostent *hp = gethostbyname(argv[1]);
  memset((void *)&saddr, 0, sizeof(saddr));
  memcpy((void *)&saddr.sin_addr, (const void *)hp->h_addr_list[0], hp->h_length);
  saddr.sin_port = htons(atoi(argv[2]));
  saddr.sin_family = AF_INET;
  connect(sock_id, (struct sockaddr *)&saddr, sizeof(saddr));
  char message[BUFSIZ];
  int messlen = read(sock_id, message, BUFSIZ);
  write(1, message, messlen);
  close(sock_id);
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D36
type: string
name: disassemble_data
arguments: label: D15
type: string
name: disassemble_data
arguments: label: D4
type: string

tool: D36: 1234567890

tool: D15: %d


tool: D4: 1234abc567890

assistant: ```c
main() {
  int a = atoi("1234567890");
  printf("%d\n", a);
  a = atoi("1234abc567890");
  printf("%d\n", a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D4
datatype: string
name: parse_data
arguments: label: D12
datatype: string

tool: D10: 1234567890

tool: D4: %d


tool: D12: 1234abc567890

assistant: ```c
main() {
  int a = atoi("1234567890");
  printf("%d\n", a);
  a = atoi("1234abc567890");
  printf("%d\n", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  lea    D15(%rip),%rbp
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string
name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D21
type: string

tool: D8: 1234567890

tool: D15: %d


tool: D21: 1234abc567890

assistant: ```c
main() {
  int a = atoi("1234567890");
  printf("%d\n", a);
  a = atoi("1234abc567890");
  printf("%d\n", a);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rdi
  lea    D25(%rip),%rbp
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string
name: retrieve_data
arguments: tag: D12
data_type: string

tool: D20: 1234567890

tool: D25: %d


tool: D12: 1234abc567890

assistant: ```c
main() {
  int a = atoi("1234567890");
  printf("%d\n", a);
  a = atoi("1234abc567890");
  printf("%d\n", a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_sum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  mov    %edx,%r11d
  test   %edx,%edx
  jle    L37
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rsi,%rdx,4),%rdx
L72:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L72
L37:
  movslq %r11d,%rax
  shl    $0x2,%rax
  movl   $0x1,-0x4(%rcx,%rax,1)
  lea    -0x1(%r11),%edx
  movslq %edx,%rsi
  lea    (%rcx,%rsi,4),%r10
  mov    %rcx,%rbx
  mov    %edx,%edx
  lea    0x0(,%rdx,4),%rbp
  lea    -0x8(%rcx,%rax,1),%rdi
  sub    %rbp,%rdi
  mov    $0x1,%esi
  lea    -0x1(%r11),%r9d
  mov    $0x0,%r8d
  jmp    L66
L16:
  cltq
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r13d
  sar    $0x1f,%r13d
  sub    %r13d,%eax
  lea    (%rax,%rax,4),%r13d
  add    %r13d,%r13d
  sub    %r13d,%edx
  mov    %edx,(%r12)
L119:
  sub    $0x4,%r12
  cmp    %rdi,%r12
  je     L21
L103:
  add    (%r12),%eax
  mov    %eax,%edx
  cmp    $0x9,%eax
  jg     L16
  mov    %eax,(%r12)
  mov    %r8d,%eax
  jmp    L119
L21:
  add    $0x1,%esi
  cmp    $0x65,%esi
  je     L76
L66:
  test   %r9d,%r9d
  js     L21
  movslq %r9d,%rax
L117:
  mov    %esi,%edx
  imul   (%rcx,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L117
  mov    %r10,%r12
  mov    %r8d,%eax
  jmp    L103
L76:
  test   %r11d,%r11d
  jle    L64
  lea    0x4(%rcx,%rbp,1),%r13
  mov    $0x0,%ebp
  lea    D6(%rip),%r12
L35:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    (%rbx),%ebp
  add    $0x4,%rbx
  cmp    %rbx,%r13
  jne    L35
L26:
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  mov    $0x0,%ebp
  jmp    L26
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D6: %d

tool: D2: 
%d


assistant: ```c
void find_sum(int n, int *fact, int size) {
  int i, count = 1, temp = 0;
  for (i = 0; i < size; i++) {
    fact[i] = 0;
  }
  fact[size - 1] = 1;
  while (count <= 100) {
    for (i = size - 1; i >= 0; i--) {
      fact[i] = fact[i] * count;
    }
    temp = 0;
    for (i = size - 1; i >= 0; i--) {
      fact[i] += temp;
      if (fact[i] > 9) {
        temp = fact[i] / 10;
        fact[i] = fact[i] % 10;
      } else {
        temp = 0;
      }
    }
    count++;
  }
  int sum = 0;
  for (i = 0; i < size; i++) {
    printf("%d", fact[i]);
    sum += fact[i];
  }
  printf("\n%d\n", sum);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<find_sum>:
  endbr64
  push   %r13
  mov    %rsi,%rcx
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L12
  mov    %rcx,%rdi
  lea    0x0(,%rbp,4),%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
L12:
  lea    0x0(,%rbp,4),%rax
  lea    -0x1(%rbx),%r8d
  mov    %rcx,%rbp
  mov    $0x1,%esi
  mov    %r8d,%r11d
  movl   $0x1,-0x4(%rcx,%rax,1)
  movslq %r8d,%r9
  lea    -0x8(%rcx,%rax,1),%rdi
  shl    $0x2,%r11
  lea    (%rcx,%r9,4),%r10
  sub    %r11,%rdi
  nopl   0x0(%rax)
L72:
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L92
L34:
  mov    (%rcx,%rax,4),%edx
  imul   %esi,%edx
  mov    %edx,(%rcx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L34
  mov    %r10,%r12
  xor    %eax,%eax
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %eax,(%r12)
  sub    $0x4,%r12
  xor    %eax,%eax
  cmp    %rdi,%r12
  je     L92
L75:
  add    (%r12),%eax
  mov    %eax,%edx
  cmp    $0x9,%eax
  jle    L27
  cltq
  mov    %edx,%r13d
  sub    $0x4,%r12
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%r13d
  sar    $0x22,%rax
  sub    %r13d,%eax
  lea    (%rax,%rax,4),%r13d
  add    %r13d,%r13d
  sub    %r13d,%edx
  mov    %edx,0x4(%r12)
  cmp    %rdi,%r12
  jne    L75
L92:
  add    $0x1,%esi
  cmp    $0x65,%esi
  jne    L72
  test   %ebx,%ebx
  jle    L5
  lea    0x4(%rcx,%r11,1),%r13
  xor    %r12d,%r12d
  lea    D12(%rip),%rbx
L39:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  add    -0x4(%rbp),%r12d
  cmp    %rbp,%r13
  jne    L39
L45:
  add    $0x8,%rsp
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
L5:
  xor    %r12d,%r12d
  jmp    L45
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D12: %d

tool: D1: 
%d


assistant: ```c
void find_sum(int n, int *fact, int size) {
  int i, count = 1, temp = 0;
  for (i = 0; i < size; i++) {
    fact[i] = 0;
  }
  fact[size - 1] = 1;
  while (count <= 100) {
    for (i = size - 1; i >= 0; i--) {
      fact[i] = fact[i] * count;
    }
    temp = 0;
    for (i = size - 1; i >= 0; i--) {
      fact[i] += temp;
      if (fact[i] > 9) {
        temp = fact[i] / 10;
        fact[i] = fact[i] % 10;
      } else {
        temp = 0;
      }
    }
    count++;
  }
  int sum = 0;
  for (i = 0; i < size; i++) {
    printf("%d", fact[i]);
    sum += fact[i];
  }
  printf("\n%d\n", sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stbi_loadf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stbi__fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L3
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <stbi__err@plt>
  mov    $0x0,%eax
  jmp    L11
L3:
  mov    -0x34(%rbp),%edi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <stbi_loadf_from_file@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D3
data_type: string

tool: D11: rb

tool: D3: can't fopen

assistant: ```c
float *stbi_loadf(char const *filename, int *x, int *y, int *comp, int req_comp) {
  float *result;
  FILE *f = stbi__fopen(filename, "rb");
  if (!f)
    return ((float *)(stbi__err("can't fopen") ? NULL : NULL));
  result = stbi_loadf_from_file(f, x, y, comp, req_comp);
  fclose(f);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stbi_loadf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8d,%r14d
  lea    D2(%rip),%rsi
  call   <stbi__fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %r14d,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <stbi_loadf_from_file@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <fclose@plt>
L4:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  lea    D16(%rip),%rdi
  call   <stbi__err@plt>
  mov    %rbx,%rbp
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string
name: unpack_data
arguments: data_tag: D16
type: string

tool: D2: rb

tool: D16: can't fopen

assistant: ```c
float *stbi_loadf(char const *filename, int *x, int *y, int *comp, int req_comp) {
  float *result;
  FILE *f = stbi__fopen(filename, "rb");
  if (!f)
    return ((float *)(stbi__err("can't fopen") ? NULL : NULL));
  result = stbi_loadf_from_file(f, x, y, comp, req_comp);
  fclose(f);
  return result;
}
```