ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_comma>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L6
  cmpq   $0x0,(%rdx)
  mov    %rsi,%rbp
  je     L1
  call   <my_comma_point@plt>
L21:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rdx,%rsi
  mov    %rdi,0x8(%rsp)
  call   <checker@plt>
  mov    0x8(%rsp),%rdi
  test   %eax,%eax
  je     L69
L49:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <checker@plt>
  test   %eax,%eax
  jne    L21
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <slash@plt>
  test   %eax,%eax
  je     L21
  lea    D6(%rip),%rdi
  call   <my_putstr@plt>
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rdi),%rsi
  mov    %rdi,%rdx
  mov    %r12,%rdi
  call   <my_exec@plt>
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L69:
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <slash@plt>
  test   %eax,%eax
  je     L49
  lea    D6(%rip),%rdi
  call   <my_putstr@plt>
  jmp    L49
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6: Env is empty


assistant: ```c
int my_comma(char **s1, char **s2, char **env, int point) {
  if (s2 == NULL) {
    my_exec(env, s1[0], s1);
    return (0);
  }
  if (env[0] == NULL) {
    if (!(checker(s1, env)) == 1)
      if (!(slash(env, s1)) == 0)
        my_putstr("Env is empty\n");
    if (!(checker(s2, env)) == 1)
      if (!(slash(env, s2)) == 0)
        my_putstr("Env is empty\n");
    return (0);
  } else
    my_comma_point(s1, s2, env, point);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_comma>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L19
  cmpq   $0x0,(%rdx)
  mov    %rsi,%rbp
  je     L15
  call   <my_comma_point@plt>
L43:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rdx,%rsi
  mov    %rdi,0x8(%rsp)
  call   <checker@plt>
  mov    0x8(%rsp),%rdi
  test   %eax,%eax
  je     L80
L6:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <checker@plt>
  test   %eax,%eax
  jne    L43
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <slash@plt>
  test   %eax,%eax
  je     L43
  lea    D19(%rip),%rdi
  call   <my_putstr@plt>
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rdi),%rsi
  mov    %rdi,%rdx
  mov    %r12,%rdi
  call   <my_exec@plt>
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L80:
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <slash@plt>
  test   %eax,%eax
  je     L6
  lea    D19(%rip),%rdi
  call   <my_putstr@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type: string

tool: D19: Env is empty


assistant: ```c
int my_comma(char **s1, char **s2, char **env, int point) {
  if (s2 == NULL) {
    my_exec(env, s1[0], s1);
    return (0);
  }
  if (env[0] == NULL) {
    if (!(checker(s1, env)) == 1)
      if (!(slash(env, s1)) == 0)
        my_putstr("Env is empty\n");
    if (!(checker(s2, env)) == 1)
      if (!(slash(env, s2)) == 0)
        my_putstr("Env is empty\n");
    return (0);
  } else
    my_comma_point(s1, s2, env, point);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inverse_mat3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <determinant3x3@plt>
  ucomisd D7(%rip),%xmm0
  jp     L11
  mov    $0x1,%eax
  je     L17
L11:
  movsd  D18(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movsd  0x20(%rbx),%xmm0
  mulsd  0x40(%rbx),%xmm0
  movsd  0x38(%rbx),%xmm2
  mulsd  0x28(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x38(%rbx),%xmm0
  mulsd  0x10(%rbx),%xmm0
  movsd  0x40(%rbx),%xmm2
  mulsd  0x8(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rbp)
  movsd  0x8(%rbx),%xmm0
  mulsd  0x28(%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  mulsd  0x20(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp)
  movsd  0x28(%rbx),%xmm0
  mulsd  0x30(%rbx),%xmm0
  movsd  0x18(%rbx),%xmm2
  mulsd  0x40(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rbp)
  movsd  0x40(%rbx),%xmm0
  mulsd  (%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  mulsd  0x30(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x20(%rbp)
  movsd  0x10(%rbx),%xmm0
  mulsd  0x18(%rbx),%xmm0
  movsd  (%rbx),%xmm2
  mulsd  0x28(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rbp)
  movsd  0x18(%rbx),%xmm0
  mulsd  0x38(%rbx),%xmm0
  movsd  0x30(%rbx),%xmm2
  mulsd  0x20(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x30(%rbp)
  movsd  0x8(%rbx),%xmm0
  mulsd  0x30(%rbx),%xmm0
  movsd  (%rbx),%xmm2
  mulsd  0x38(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x38(%rbp)
  movsd  (%rbx),%xmm0
  mulsd  0x20(%rbx),%xmm0
  movsd  0x18(%rbx),%xmm2
  mulsd  0x8(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x40(%rbp)
  mov    $0x0,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: f64
name: extract_symbolic_data
arguments: tag: D18
data_type: f64

tool: D7: 0

tool: D18: 1

assistant: ```c
int inverse_mat3(double m[9], double r[9]) {
  double d;
  d = determinant3x3(m);
  if (fabs(d) == 0.0) {
    return 1;
  }
  d = 1.0 / d;
  r[0] = d * (m[4] * m[8] - m[7] * m[5]);
  r[1] = d * (m[7] * m[2] - m[8] * m[1]);
  r[2] = d * (m[1] * m[5] - m[2] * m[4]);
  r[3] = d * (m[5] * m[6] - m[3] * m[8]);
  r[4] = d * (m[8] * m[0] - m[2] * m[6]);
  r[5] = d * (m[2] * m[3] - m[0] * m[5]);
  r[6] = d * (m[3] * m[7] - m[6] * m[4]);
  r[7] = d * (m[1] * m[6] - m[0] * m[7]);
  r[8] = d * (m[0] * m[4] - m[3] * m[1]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<inverse_mat3>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <determinant3x3@plt>
  ucomisd D9(%rip),%xmm0
  jp     L8
  mov    $0x1,%eax
  je     L18
L8:
  movsd  D10(%rip),%xmm1
  movsd  0x38(%rbx),%xmm2
  xor    %eax,%eax
  mulsd  0x28(%rbx),%xmm2
  divsd  %xmm0,%xmm1
  movsd  0x20(%rbx),%xmm0
  mulsd  0x40(%rbx),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x38(%rbx),%xmm0
  movsd  0x40(%rbx),%xmm2
  mulsd  0x10(%rbx),%xmm0
  mulsd  0x8(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rbp)
  movsd  0x8(%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  mulsd  0x28(%rbx),%xmm0
  mulsd  0x20(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp)
  movsd  0x28(%rbx),%xmm0
  movsd  0x18(%rbx),%xmm2
  mulsd  0x30(%rbx),%xmm0
  mulsd  0x40(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rbp)
  movsd  0x40(%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  mulsd  (%rbx),%xmm0
  mulsd  0x30(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x20(%rbp)
  movsd  0x10(%rbx),%xmm0
  movsd  (%rbx),%xmm2
  mulsd  0x18(%rbx),%xmm0
  mulsd  0x28(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rbp)
  movsd  0x18(%rbx),%xmm0
  mulsd  0x38(%rbx),%xmm0
  movsd  0x30(%rbx),%xmm2
  mulsd  0x20(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x30(%rbp)
  movsd  0x8(%rbx),%xmm0
  movsd  (%rbx),%xmm2
  mulsd  0x30(%rbx),%xmm0
  mulsd  0x38(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x38(%rbp)
  movsd  (%rbx),%xmm0
  movsd  0x18(%rbx),%xmm2
  mulsd  0x20(%rbx),%xmm0
  mulsd  0x8(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x40(%rbp)
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: f64
name: extract_symbolic_data
arguments: tag: D10
data_type: f64

tool: D9: 0

tool: D10: 1

assistant: ```c
int inverse_mat3(double m[9], double r[9]) {
  double d;
  d = determinant3x3(m);
  if (fabs(d) == 0.0) {
    return 1;
  }
  d = 1.0 / d;
  r[0] = d * (m[4] * m[8] - m[7] * m[5]);
  r[1] = d * (m[7] * m[2] - m[8] * m[1]);
  r[2] = d * (m[1] * m[5] - m[2] * m[4]);
  r[3] = d * (m[5] * m[6] - m[3] * m[8]);
  r[4] = d * (m[8] * m[0] - m[2] * m[6]);
  r[5] = d * (m[2] * m[3] - m[0] * m[5]);
  r[6] = d * (m[3] * m[7] - m[6] * m[4]);
  r[7] = d * (m[1] * m[6] - m[0] * m[7]);
  r[8] = d * (m[0] * m[4] - m[3] * m[1]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inverse_mat3>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <determinant3x3@plt>
  ucomisd D6(%rip),%xmm0
  jp     L9
  mov    $0x1,%eax
  je     L15
L9:
  movsd  D1(%rip),%xmm1
  movsd  0x38(%rbx),%xmm2
  xor    %eax,%eax
  mulsd  0x28(%rbx),%xmm2
  divsd  %xmm0,%xmm1
  movsd  0x20(%rbx),%xmm0
  mulsd  0x40(%rbx),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x38(%rbx),%xmm0
  movsd  0x40(%rbx),%xmm2
  mulsd  0x10(%rbx),%xmm0
  mulsd  0x8(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rbp)
  movsd  0x8(%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  mulsd  0x28(%rbx),%xmm0
  mulsd  0x20(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp)
  movsd  0x28(%rbx),%xmm0
  movsd  0x18(%rbx),%xmm2
  mulsd  0x30(%rbx),%xmm0
  mulsd  0x40(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rbp)
  movsd  0x40(%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  mulsd  (%rbx),%xmm0
  mulsd  0x30(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x20(%rbp)
  movsd  0x10(%rbx),%xmm0
  movsd  (%rbx),%xmm2
  mulsd  0x18(%rbx),%xmm0
  mulsd  0x28(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rbp)
  movsd  0x18(%rbx),%xmm0
  mulsd  0x38(%rbx),%xmm0
  movsd  0x30(%rbx),%xmm2
  mulsd  0x20(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x30(%rbp)
  movsd  0x8(%rbx),%xmm0
  movsd  (%rbx),%xmm2
  mulsd  0x30(%rbx),%xmm0
  mulsd  0x38(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x38(%rbp)
  movsd  (%rbx),%xmm0
  movsd  0x18(%rbx),%xmm2
  mulsd  0x20(%rbx),%xmm0
  mulsd  0x8(%rbx),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x40(%rbp)
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: f64
name: retrieve_data
arguments: data_tag: D1
type_infered: f64

tool: D6: 0

tool: D1: 1

assistant: ```c
int inverse_mat3(double m[9], double r[9]) {
  double d;
  d = determinant3x3(m);
  if (fabs(d) == 0.0) {
    return 1;
  }
  d = 1.0 / d;
  r[0] = d * (m[4] * m[8] - m[7] * m[5]);
  r[1] = d * (m[7] * m[2] - m[8] * m[1]);
  r[2] = d * (m[1] * m[5] - m[2] * m[4]);
  r[3] = d * (m[5] * m[6] - m[3] * m[8]);
  r[4] = d * (m[8] * m[0] - m[2] * m[6]);
  r[5] = d * (m[2] * m[3] - m[0] * m[5]);
  r[6] = d * (m[3] * m[7] - m[6] * m[4]);
  r[7] = d * (m[1] * m[6] - m[0] * m[7]);
  r[8] = d * (m[0] * m[4] - m[3] * m[1]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L16
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int puts(const char *s) {
  while (*s) {
    putchar(*s);
    s++;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L8
L16:
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L16
L8:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *s) {
  while (*s) {
    putchar(*s);
    s++;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L3
L7:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L3:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *s) {
  while (*s) {
    putchar(*s);
    s++;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L12
L3:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
L12:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *s) {
  while (*s) {
    putchar(*s);
    s++;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L22:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L17
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L22
L17:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type: string
name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D7
type: string

tool: D13: input a number, negative to quit:

tool: D28: %lf

tool: D7: the sqrt(%.2lf)=%.2lf


assistant: ```c
int main(void) {
  double value;
  do {
    printf("input a number, negative to quit:");
    scanf("%lf", &value);
    if (value < 0)
      break;
    printf("the sqrt(%.2lf)=%.2lf\n", value, sqrt(value));
  } while (1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rbp
  lea    D19(%rip),%rbx
  lea    D29(%rip),%r12
  jmp    L16
L4:
  call   <sqrt@plt>
  mov    %eax,%esi
  movsd  (%rsp),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L16:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L4
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D29
data_type: string

tool: D17: input a number, negative to quit:

tool: D19: %lf

tool: D29: the sqrt(%.2lf)=%.2lf


assistant: ```c
int main(void) {
  double value;
  do {
    printf("input a number, negative to quit:");
    scanf("%lf", &value);
    if (value < 0)
      break;
    printf("the sqrt(%.2lf)=%.2lf\n", value, sqrt(value));
  } while (1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D28(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L21:
  call   <sqrt@plt>
  movsd  (%rsp),%xmm0
  mov    %r13,%rdi
  mov    %eax,%esi
  mov    $0x1,%eax
  call   <printf@plt>
L6:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L21
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string

tool: D14: the sqrt(%.2lf)=%.2lf


tool: D7: input a number, negative to quit:

tool: D28: %lf

assistant: ```c
int main(void) {
  double value;
  do {
    printf("input a number, negative to quit:");
    scanf("%lf", &value);
    if (value < 0)
      break;
    printf("the sqrt(%.2lf)=%.2lf\n", value, sqrt(value));
  } while (1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D26(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L15:
  call   <sqrt@plt>
  movsd  (%rsp),%xmm0
  mov    %r13,%rdi
  mov    %eax,%esi
  mov    $0x1,%eax
  call   <printf@plt>
L3:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L15
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D11
datatype: string
name: disassemble_data
arguments: data_label: D26
datatype: string

tool: D29: the sqrt(%.2lf)=%.2lf


tool: D11: input a number, negative to quit:

tool: D26: %lf

assistant: ```c
int main(void) {
  double value;
  do {
    printf("input a number, negative to quit:");
    scanf("%lf", &value);
    if (value < 0)
      break;
    printf("the sqrt(%.2lf)=%.2lf\n", value, sqrt(value));
  } while (1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <sum_row_max@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <sum_matrix@plt>
  mov    %eax,-0x40(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <string_length@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D37
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D4
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string

tool: D37: Sum of max from each row is: %d


tool: D0: Sum of all elements is: %d


tool: D4: Hello World

tool: D15: Length of '%s' is %d


assistant: ```c
int main() {
  int x[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
  int sum_max = sum_row_max(x);
  printf("Sum of max from each row is: %d\n", sum_max);
  int sum_elements = sum_matrix(x);
  printf("Sum of all elements is: %d\n", sum_elements);
  char *s = "Hello World";
  int length = string_length(s);
  printf("Length of '%s' is %d\n", s, length);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <sum_row_max@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <sum_matrix@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <string_length@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D23
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string

tool: D5: Sum of max from each row is: %d


tool: D23: Sum of all elements is: %d


tool: D9: Hello World

tool: D7: Length of '%s' is %d


assistant: ```c
int main() {
  int x[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
  int sum_max = sum_row_max(x);
  printf("Sum of max from each row is: %d\n", sum_max);
  int sum_elements = sum_matrix(x);
  printf("Sum of all elements is: %d\n", sum_elements);
  char *s = "Hello World";
  int length = string_length(s);
  printf("Length of '%s' is %d\n", s, length);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbp
  movl   $0x9,0x20(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  call   <sum_row_max@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D24(%rip),%rbp
  call   <sum_matrix@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <string_length@plt>
  mov    %rbp,%rsi
  lea    D30(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string
name: retrieve_data
arguments: label: D30
type_infered: string

tool: D21: Sum of max from each row is: %d


tool: D24: Hello World

tool: D6: Sum of all elements is: %d


tool: D30: Length of '%s' is %d


assistant: ```c
int main() {
  int x[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
  int sum_max = sum_row_max(x);
  printf("Sum of max from each row is: %d\n", sum_max);
  int sum_elements = sum_matrix(x);
  printf("Sum of all elements is: %d\n", sum_elements);
  char *s = "Hello World";
  int length = string_length(s);
  printf("Length of '%s' is %d\n", s, length);
  return 0;
}
```