ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<factors>:
  endbr64
  cmp    $0x3,%edi
  jle    L0
  mov    $0x2,%ecx
  xor    %esi,%esi
L13:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L5
  mov    %eax,%edi
  mov    %ecx,%eax
  add    $0x1,%esi
  imul   %ecx,%eax
  cmp    %eax,%edi
  jge    L13
  lea    0x1(%rsi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L13
  lea    0x1(%rsi),%eax
  ret
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int factors(int n) {
  int factors = 0;
  int factor = 2;
  while (factor * factor <= n) {
    if (n % factor == 0) {
      n /= factor;
      factors++;
    } else {
      factor++;
    }
  }
  return factors + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rbx
L102:
  lea    -0x1d4(%rbp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x1d4(%rbp),%edx
  test   $0x1,%dl
  je     L102
  cmp    $0xc8,%edx
  jg     L102
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rsi
  sub    %rax,%rsi
L76:
  cmp    %rsi,%rsp
  je     L93
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L76
L93:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L96
  orq    $0x0,-0x8(%rsp,%rax,1)
L96:
  mov    %rsp,%r13
  lea    -0x1d0(%rbp),%rdi
  mov    $0x32,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L81
  mov    $0x0,%r14d
  lea    D2(%rip),%r12
L17:
  mov    %r13,%rbx
L53:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  cmp    $0x64,%eax
  jg     L53
  sub    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x1d0(%rbp,%rdx,4),%edx
  cmp    $0x1,%edx
  jg     L53
  cltq
  add    $0x1,%edx
  mov    %edx,-0x1d0(%rbp,%rax,4)
  add    $0x1,%r14d
  add    $0x4,%r13
  cmp    %r14d,-0x1d4(%rbp)
  jg     L17
L81:
  mov    $0x0,%eax
  lea    -0x1d0(%rbp),%rdx
L6:
  cmpl   $0x1,(%rdx,%rax,4)
  je     L4
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L6
  jmp    L40
L4:
  lea    0x1(%rax),%r15d
L40:
  mov    %r15d,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  int num;
  do {
    scanf("%d", &num);
  } while (num % 2 == 0 || num > 200);
  int deer[num];
  int nums[100] = {0};
  int var = 0, helper, i;
  for (i = 0; i < num; i++) {
    do {
      scanf("%d", &deer[i]);
      if ((deer[i] - 1) < 100) {
        if (nums[deer[i] - 1] < 2) {
          nums[deer[i] - 1]++;
          var = 1;
        }
      }
    } while (!var);
    var = 0;
  }
  for (i = 0; i < 100; i++) {
    if (nums[i] == 1) {
      helper = i + 1;
      break;
    }
  }
  printf("%d", helper);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x1c4(%rbp),%rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    -0x1c4(%rbp),%edx
  cmp    $0xc8,%edx
  jg     L6
  test   $0x1,%dl
  je     L6
  movslq %edx,%rax
  mov    %rsp,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L70
L109:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L109
L70:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L59
L23:
  lea    -0x1c0(%rbp),%r12
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L16
  xor    %ebx,%ebx
  nopl   (%rax)
L41:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x0(%r13),%eax
  cmp    $0x64,%eax
  jg     L41
  sub    $0x1,%eax
  cltq
  mov    -0x1c0(%rbp,%rax,4),%edx
  cmp    $0x1,%edx
  jg     L41
  add    $0x1,%edx
  add    $0x1,%ebx
  add    $0x4,%r13
  mov    %edx,-0x1c0(%rbp,%rax,4)
  cmp    %ebx,-0x1c4(%rbp)
  jg     L41
L16:
  mov    $0x1,%eax
  jmp    L60
  nopl   (%rax)
L113:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L118
L60:
  cmpl   $0x1,-0x4(%r12,%rax,4)
  mov    %eax,%esi
  jne    L113
L118:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L59:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L23
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  int num;
  do {
    scanf("%d", &num);
  } while (num % 2 == 0 || num > 200);
  int deer[num];
  int nums[100] = {0};
  int var = 0, helper, i;
  for (i = 0; i < num; i++) {
    do {
      scanf("%d", &deer[i]);
      if ((deer[i] - 1) < 100) {
        if (nums[deer[i] - 1] < 2) {
          nums[deer[i] - 1]++;
          var = 1;
        }
      }
    } while (!var);
    var = 0;
  }
  for (i = 0; i < 100; i++) {
    if (nums[i] == 1) {
      helper = i + 1;
      break;
    }
  }
  printf("%d", helper);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x1c4(%rbp),%rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    -0x1c4(%rbp),%edx
  cmp    $0xc8,%edx
  jg     L15
  test   $0x1,%dl
  je     L15
  movslq %edx,%rax
  mov    %rsp,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L109
L9:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L9
L109:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L118
L56:
  lea    -0x1c0(%rbp),%r12
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L120
  xor    %ebx,%ebx
  nopl   (%rax)
L28:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x0(%r13),%eax
  cmp    $0x64,%eax
  jg     L28
  sub    $0x1,%eax
  cltq
  mov    -0x1c0(%rbp,%rax,4),%edx
  cmp    $0x1,%edx
  jg     L28
  add    $0x1,%edx
  add    $0x1,%ebx
  add    $0x4,%r13
  mov    %edx,-0x1c0(%rbp,%rax,4)
  cmp    %ebx,-0x1c4(%rbp)
  jg     L28
L120:
  mov    $0x1,%eax
  jmp    L111
  nopl   (%rax)
L95:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L94
L111:
  cmpl   $0x1,-0x4(%r12,%rax,4)
  mov    %eax,%esi
  jne    L95
L94:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L136
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L118:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L56
L136:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: %d

assistant: ```c
int main() {
  int num;
  do {
    scanf("%d", &num);
  } while (num % 2 == 0 || num > 200);
  int deer[num];
  int nums[100] = {0};
  int var = 0, helper, i;
  for (i = 0; i < num; i++) {
    do {
      scanf("%d", &deer[i]);
      if ((deer[i] - 1) < 100) {
        if (nums[deer[i] - 1] < 2) {
          nums[deer[i] - 1]++;
          var = 1;
        }
      }
    } while (!var);
    var = 0;
  }
  for (i = 0; i < 100; i++) {
    if (nums[i] == 1) {
      helper = i + 1;
      break;
    }
  }
  printf("%d", helper);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<multiply380>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L1
L21:
  movl   $0x0,-0x3c(%rbp)
  jmp    L37
L38:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L37:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L38
  addl   $0x1,-0x40(%rbp)
L1:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L21
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply380(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<multiply380>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L0:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L16:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L16
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  ret
```

assistant: ```c
void multiply380(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply380>:
  endbr64
  test   %edi,%edi
  jle    L14
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L15
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L10
  pop    %rbx
  ret
L14:
  ret
```

assistant: ```c
void multiply380(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply380>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L23
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L28:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L78
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L78
  nopl   0x0(%rax)
L74:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L74
  cmp    -0x24(%rsp),%r11d
  je     L83
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L83
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L83
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L83:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L28
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L78:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L45:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L45
  mov    -0x18(%rsp),%r8
  jmp    L83
```

assistant: ```c
void multiply380(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Rio_writen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <rio_writen@plt>
  cmp    %rax,-0x18(%rbp)
  je     L1
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <unix_error@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: Rio_writen error

assistant: ```c
void Rio_writen(int fd, void *usrbuf, size_t n) {
  if (rio_writen(fd, usrbuf, n) != n)
    unix_error("Rio_writen error");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Rio_writen>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <rio_writen@plt>
  cmp    %rbx,%rax
  jne    L6
L19:
  pop    %rbx
  ret
L6:
  lea    D7(%rip),%rdi
  call   <unix_error@plt>
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: Rio_writen error

assistant: ```c
void Rio_writen(int fd, void *usrbuf, size_t n) {
  if (rio_writen(fd, usrbuf, n) != n)
    unix_error("Rio_writen error");
}
```
user: Translate the below assembly code into C programming language:

```asm
<Rio_writen>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <rio_writen@plt>
  cmp    %rbx,%rax
  jne    L8
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  lea    D6(%rip),%rdi
  pop    %rbx
  jmp    1070 <unix_error@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: Rio_writen error

assistant: ```c
void Rio_writen(int fd, void *usrbuf, size_t n) {
  if (rio_writen(fd, usrbuf, n) != n)
    unix_error("Rio_writen error");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Rio_writen>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <rio_writen@plt>
  cmp    %rbx,%rax
  jne    L5
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  lea    D0(%rip),%rdi
  pop    %rbx
  jmp    1070 <unix_error@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: Rio_writen error

assistant: ```c
void Rio_writen(int fd, void *usrbuf, size_t n) {
  if (rio_writen(fd, usrbuf, n) != n)
    unix_error("Rio_writen error");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_lower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_length@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <galloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L23:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L26
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L26
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L41
L26:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L41:
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_length@plt>
  cmp    %eax,-0xc(%rbp)
  jbe    L23
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_lower(const char *s) {
  char *ret = galloc(str_length(s) + 1);
  for (unsigned i = 0; i <= str_length(s); i++)
    if (s[i] >= 'A' && s[i] <= 'Z')
      ret[i] = s[i] + 0x20;
    else
      ret[i] = s[i];
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str_lower>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <str_length@plt>
  lea    0x1(%rax),%edi
  call   <galloc@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <str_length@plt>
  mov    $0x0,%ebx
  jmp    L37
L38:
  mov    %al,(%r12,%rdx,1)
L6:
  add    $0x1,%ebx
  mov    %rbp,%rdi
  call   <str_length@plt>
  cmp    %ebx,%eax
  jb     L36
L37:
  mov    %ebx,%edx
  movzbl 0x0(%rbp,%rdx,1),%eax
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L38
  add    $0x20,%eax
  mov    %al,(%r12,%rdx,1)
  jmp    L6
L36:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_lower(const char *s) {
  char *ret = galloc(str_length(s) + 1);
  for (unsigned i = 0; i <= str_length(s); i++)
    if (s[i] >= 'A' && s[i] <= 'Z')
      ret[i] = s[i] + 0x20;
    else
      ret[i] = s[i];
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_lower>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <str_length@plt>
  lea    0x1(%rax),%edi
  call   <galloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <str_length@plt>
  nopl   (%rax)
L5:
  mov    %ebx,%edx
  mov    %rbp,%rdi
  movzbl 0x0(%rbp,%rdx,1),%eax
  lea    -0x41(%rax),%esi
  lea    0x20(%rax),%ecx
  cmp    $0x1a,%sil
  cmovb  %ecx,%eax
  add    $0x1,%ebx
  mov    %al,(%r12,%rdx,1)
  call   <str_length@plt>
  cmp    %ebx,%eax
  jae    L5
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_lower(const char *s) {
  char *ret = galloc(str_length(s) + 1);
  for (unsigned i = 0; i <= str_length(s); i++)
    if (s[i] >= 'A' && s[i] <= 'Z')
      ret[i] = s[i] + 0x20;
    else
      ret[i] = s[i];
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_lower>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <str_length@plt>
  lea    0x1(%rax),%edi
  call   <galloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <str_length@plt>
  nopl   (%rax)
L28:
  mov    %ebx,%eax
  movzbl 0x0(%rbp,%rax,1),%edx
  add    %r12,%rax
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L14
  add    $0x20,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %dl,(%rax)
  call   <str_length@plt>
  cmp    %eax,%ebx
  jbe    L28
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %dl,(%rax)
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <str_length@plt>
  cmp    %ebx,%eax
  jae    L28
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_lower(const char *s) {
  char *ret = galloc(str_length(s) + 1);
  for (unsigned i = 0; i <= str_length(s); i++)
    if (s[i] >= 'A' && s[i] <= 'Z')
      ret[i] = s[i] + 0x20;
    else
      ret[i] = s[i];
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PB_Cindxg2p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L14
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L14
  cmpl   $0x1,-0x18(%rbp)
  jne    L25
L14:
  mov    -0x14(%rbp),%eax
  jmp    L9
L25:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  add    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int PB_Cindxg2p(int IG, int INB, int NB, int PROC, int SRCPROC, int NPROCS) {
  if ((IG < INB) || (SRCPROC == -1) || (NPROCS == 1))
    return (SRCPROC);
  PROC = SRCPROC + 1 + (IG - INB) / NB;
  return (((PROC) - ((PROC) / (NPROCS)) * (NPROCS)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PB_Cindxg2p>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%ecx
  cmp    $0xffffffff,%r8d
  sete   %dl
  cmp    $0x1,%r9d
  sete   %dil
  or     %dil,%dl
  jne    L17
  cmp    %esi,%eax
  jl     L17
  sub    %esi,%eax
  cltd
  idiv   %ecx
  lea    0x1(%r8,%rax,1),%eax
  cltd
  idiv   %r9d
L6:
  mov    %edx,%eax
  ret
L17:
  mov    %r8d,%edx
  jmp    L6
```

assistant: ```c
int PB_Cindxg2p(int IG, int INB, int NB, int PROC, int SRCPROC, int NPROCS) {
  if ((IG < INB) || (SRCPROC == -1) || (NPROCS == 1))
    return (SRCPROC);
  PROC = SRCPROC + 1 + (IG - INB) / NB;
  return (((PROC) - ((PROC) / (NPROCS)) * (NPROCS)));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<PB_Cindxg2p>:
  endbr64
  cmp    $0xffffffff,%r8d
  mov    %edx,%ecx
  mov    %edi,%eax
  sete   %dl
  cmp    $0x1,%r9d
  sete   %dil
  or     %dil,%dl
  jne    L19
  cmp    %esi,%eax
  jl     L19
  sub    %esi,%eax
  cltd
  idiv   %ecx
  lea    0x1(%r8,%rax,1),%eax
  cltd
  idiv   %r9d
  mov    %edx,%r8d
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int PB_Cindxg2p(int IG, int INB, int NB, int PROC, int SRCPROC, int NPROCS) {
  if ((IG < INB) || (SRCPROC == -1) || (NPROCS == 1))
    return (SRCPROC);
  PROC = SRCPROC + 1 + (IG - INB) / NB;
  return (((PROC) - ((PROC) / (NPROCS)) * (NPROCS)));
}
```