ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D6(%rip),%r15
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L16:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L13:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L13
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L16
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D2
datatype: string

tool: D6: dsnansum

tool: D7: # c::%s:len=%d


tool: D2: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsnansum", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vec4_assign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movss  0x8(%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movss  0xc(%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *vec4_assign(float *result, float *a) {
  result[0] = a[0];
  result[1] = a[1];
  result[2] = a[2];
  result[3] = a[3];
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vec4_assign>:
  endbr64
  mov    %rdi,%rax
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
float *vec4_assign(float *result, float *a) {
  result[0] = a[0];
  result[1] = a[1];
  result[2] = a[2];
  result[3] = a[3];
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vec4_assign>:
  endbr64
  movss  (%rsi),%xmm0
  mov    %rdi,%rax
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
float *vec4_assign(float *result, float *a) {
  result[0] = a[0];
  result[1] = a[1];
  result[2] = a[2];
  result[3] = a[3];
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vec4_assign>:
  endbr64
  movss  (%rsi),%xmm0
  mov    %rdi,%rax
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
float *vec4_assign(float *result, float *a) {
  result[0] = a[0];
  result[1] = a[1];
  result[2] = a[2];
  result[3] = a[3];
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sinc_approx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  movsd  %xmm2,-0x40(%rbp)
  mov    D2(%rip),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x24(%rbp),%xmm1
  mulsd  -0x38(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  movq   %rax,%xmm0
  call   <asinh@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L15
L0:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <ftrans@plt>
  movsd  %xmm0,-0x48(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <S@plt>
  mulsd  -0x48(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <ftrans@plt>
  movsd  %xmm0,-0x48(%rbp)
  mov    -0x1c(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    %edx,%edi
  call   <S@plt>
  mulsd  -0x48(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  subl   $0x1,-0x1c(%rbp)
L15:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L0
  movsd  -0x10(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <ftrans@plt>
  movsd  %xmm0,-0x48(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x0,%edi
  call   <S@plt>
  mulsd  -0x48(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double sinc_approx(int N, double d, double mu, double t) {
  int k;
  double h = sqrt(M_PI * d / (mu * N));
  double x = asinh(t);
  double val = 0;
  for (k = N; k > 0; k--) {
    val += ftrans(k * h) * S(k, h, x);
    val += ftrans(-k * h) * S(-k, h, x);
  }
  val += ftrans(0 * h) * S(0, h, x);
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sinc_approx>:
  endbr64
  push   %rbp
  pxor   %xmm3,%xmm3
  pxor   %xmm7,%xmm7
  push   %rbx
  cvtsi2sd %edi,%xmm3
  mov    %edi,%ebx
  sub    $0x28,%rsp
  mov    D6(%rip),%rax
  mulsd  %xmm3,%xmm1
  mulsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm7
  ja     L4
  sqrtsd %xmm0,%xmm0
  movsd  %xmm0,(%rsp)
L22:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <asinh@plt>
  movq   $0x0,0x8(%rsp)
  movapd %xmm0,%xmm1
  test   %ebx,%ebx
  jle    L26
  movsd  0x10(%rsp),%xmm3
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L27:
  pxor   %xmm3,%xmm3
  cvtsi2sd %ebx,%xmm3
L17:
  mulsd  (%rsp),%xmm3
  movsd  %xmm1,0x18(%rsp)
  mov    %ebx,%ebp
  neg    %ebp
  movapd %xmm3,%xmm0
  call   <ftrans@plt>
  movsd  0x18(%rsp),%xmm1
  mov    %ebx,%edi
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rsp),%xmm0
  call   <S@plt>
  mulsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm5
  addsd  %xmm0,%xmm5
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm5,0x10(%rsp)
  call   <ftrans@plt>
  movsd  0x18(%rsp),%xmm1
  mov    %ebp,%edi
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rsp),%xmm0
  call   <S@plt>
  mulsd  0x8(%rsp),%xmm0
  sub    $0x1,%ebx
  movsd  0x18(%rsp),%xmm1
  addsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  jne    L27
L26:
  pxor   %xmm6,%xmm6
  movsd  %xmm1,0x18(%rsp)
  mulsd  (%rsp),%xmm6
  movapd %xmm6,%xmm0
  call   <ftrans@plt>
  movsd  0x18(%rsp),%xmm1
  xor    %edi,%edi
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rsp),%xmm0
  call   <S@plt>
  mulsd  0x10(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,(%rsp)
  jmp    L22
```

assistant: ```c
double sinc_approx(int N, double d, double mu, double t) {
  int k;
  double h = sqrt(M_PI * d / (mu * N));
  double x = asinh(t);
  double val = 0;
  for (k = N; k > 0; k--) {
    val += ftrans(k * h) * S(k, h, x);
    val += ftrans(-k * h) * S(-k, h, x);
  }
  val += ftrans(0 * h) * S(0, h, x);
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sinc_approx>:
  endbr64
  push   %rbp
  pxor   %xmm3,%xmm3
  pxor   %xmm7,%xmm7
  push   %rbx
  cvtsi2sd %edi,%xmm3
  mov    %edi,%ebx
  sub    $0x28,%rsp
  mov    D5(%rip),%rax
  mulsd  %xmm3,%xmm1
  mulsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm7
  ja     L23
  sqrtsd %xmm0,%xmm0
  movsd  %xmm0,(%rsp)
L0:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <asinh@plt>
  movq   $0x0,0x8(%rsp)
  movapd %xmm0,%xmm1
  test   %ebx,%ebx
  jle    L19
  movsd  0x10(%rsp),%xmm3
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L3:
  pxor   %xmm3,%xmm3
  cvtsi2sd %ebx,%xmm3
L12:
  mulsd  (%rsp),%xmm3
  movsd  %xmm1,0x18(%rsp)
  mov    %ebx,%ebp
  neg    %ebp
  movapd %xmm3,%xmm0
  call   <ftrans@plt>
  movsd  0x18(%rsp),%xmm1
  mov    %ebx,%edi
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rsp),%xmm0
  call   <S@plt>
  mulsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm5
  addsd  %xmm0,%xmm5
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm5,0x10(%rsp)
  call   <ftrans@plt>
  movsd  0x18(%rsp),%xmm1
  mov    %ebp,%edi
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rsp),%xmm0
  call   <S@plt>
  mulsd  0x8(%rsp),%xmm0
  sub    $0x1,%ebx
  movsd  0x18(%rsp),%xmm1
  addsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  jne    L3
L19:
  pxor   %xmm6,%xmm6
  movsd  %xmm1,0x18(%rsp)
  mulsd  (%rsp),%xmm6
  movapd %xmm6,%xmm0
  call   <ftrans@plt>
  movsd  0x18(%rsp),%xmm1
  xor    %edi,%edi
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rsp),%xmm0
  call   <S@plt>
  mulsd  0x10(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,(%rsp)
  jmp    L0
```

assistant: ```c
double sinc_approx(int N, double d, double mu, double t) {
  int k;
  double h = sqrt(M_PI * d / (mu * N));
  double x = asinh(t);
  double val = 0;
  for (k = N; k > 0; k--) {
    val += ftrans(k * h) * S(k, h, x);
    val += ftrans(-k * h) * S(-k, h, x);
  }
  val += ftrans(0 * h) * S(0, h, x);
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  lea    -0x20(%rbp),%rax
  mov    $0x15,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[20];
  fgets(buf, 21, stdin);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    $0x15,%esi
  call   <fgets@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[20];
  fgets(buf, 21, stdin);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x15,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[20];
  fgets(buf, 21, stdin);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x15,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %rsp,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char buf[20];
  fgets(buf, 21, stdin);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<array_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <array_errfunc@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int array_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  int len = array_errfunc(fmt, args);
  va_end(args);
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <array_errfunc@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int array_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  int len = array_errfunc(fmt, args);
  va_end(args);
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<array_error>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <array_errfunc@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int array_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  int len = array_errfunc(fmt, args);
  va_end(args);
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<array_error>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <array_errfunc@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int array_error(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  int len = array_errfunc(fmt, args);
  va_end(args);
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ancestrymap2lfmm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <nb_ind_ancestrymap@plt>
  mov    -0x38(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <nb_lines@plt>
  mov    %eax,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  ucomisd -0x10(%rbp),%xmm2
  jp     L10
  movq   %rax,%xmm3
  ucomisd -0x10(%rbp),%xmm3
  je     L2
L10:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <read_ancestrymap@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <write_data_int@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: Error: incorrect number of lines in %s.


assistant: ```c
void ancestrymap2lfmm(char *input_file, char *output_file, int *N, int *M) {
  int *data;
  int nb;
  double tmp;
  *N = nb_ind_ancestrymap(input_file);
  nb = nb_lines(input_file, 1000);
  tmp = (double)nb / (double)(*N);
  if (tmp != floor(tmp)) {
    printf("Error: incorrect number of lines in %s.\n", input_file);
    exit(1);
  }
  *M = (int)tmp;
  data = (int *)malloc((*N) * (*M) * sizeof(int));
  read_ancestrymap(input_file, *N, *M, data);
  write_data_int(output_file, *N, *M, data);
  free(data);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ancestrymap2lfmm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rcx,%r12
  call   <nb_ind_ancestrymap@plt>
  mov    %eax,(%rbx)
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <nb_lines@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rbx),%xmm0
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm5
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm2
  movsd  D21(%rip),%xmm1
  movapd %xmm5,%xmm0
  andpd  %xmm1,%xmm0
  movsd  D24(%rip),%xmm3
  ucomisd %xmm0,%xmm3
  jbe    L31
  cvttsd2si %xmm5,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movapd %xmm0,%xmm2
  cmpnlesd %xmm5,%xmm2
  movsd  D18(%rip),%xmm3
  andpd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  andnpd %xmm5,%xmm1
  movapd %xmm0,%xmm2
  orpd   %xmm1,%xmm2
L31:
  movsd  0x8(%rsp),%xmm6
  ucomisd %xmm6,%xmm2
  jp     L0
  jne    L0
L13:
  cvttsd2si 0x8(%rsp),%edi
  mov    %edi,(%r12)
  imul   (%rbx),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%rcx
  mov    (%r12),%edx
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <read_ancestrymap@plt>
  mov    %r14,%rcx
  mov    (%r12),%edx
  mov    (%rbx),%esi
  mov    %r13,%rdi
  call   <write_data_int@plt>
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  mov    %rbp,%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_label: D21
data_type: byte[8]
name: unpack_data
arguments: data_label: D24
data_type: byte[8]
name: unpack_data
arguments: data_label: D18
data_type: byte[8]
name: unpack_data
arguments: data_label: D26
data_type: string

tool: {"D21": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D26: Error: incorrect number of lines in %s.


assistant: ```c
void ancestrymap2lfmm(char *input_file, char *output_file, int *N, int *M) {
  int *data;
  int nb;
  double tmp;
  *N = nb_ind_ancestrymap(input_file);
  nb = nb_lines(input_file, 1000);
  tmp = (double)nb / (double)(*N);
  if (tmp != floor(tmp)) {
    printf("Error: incorrect number of lines in %s.\n", input_file);
    exit(1);
  }
  *M = (int)tmp;
  data = (int *)malloc((*N) * (*M) * sizeof(int));
  read_ancestrymap(input_file, *N, *M, data);
  write_data_int(output_file, *N, *M, data);
  free(data);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ancestrymap2lfmm>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  call   <nb_ind_ancestrymap@plt>
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  call   <nb_lines@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movsd  D2(%rip),%xmm2
  cvtsi2sdl (%rbx),%xmm1
  movsd  D25(%rip),%xmm4
  cvtsi2sd %eax,%xmm0
  divsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm3
  andpd  %xmm2,%xmm1
  ucomisd %xmm1,%xmm4
  jbe    L23
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  movsd  D10(%rip),%xmm4
  andnpd %xmm0,%xmm2
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm3
  cmpnlesd %xmm0,%xmm3
  andpd  %xmm4,%xmm3
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm3
  orpd   %xmm2,%xmm3
L23:
  ucomisd %xmm0,%xmm3
  jp     L1
  jne    L1
L32:
  cvttsd2si %xmm0,%edi
  mov    %edi,(%r12)
  imul   (%rbx),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    (%r12),%edx
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    %rax,%rcx
  mov    %rax,%r14
  call   <read_ancestrymap@plt>
  mov    (%r12),%edx
  mov    (%rbx),%esi
  mov    %r13,%rdi
  mov    %r14,%rcx
  call   <write_data_int@plt>
  add    $0x10,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <free@plt>
  nopl   (%rax)
L1:
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L32
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: byte[8]
name: unpack_data
arguments: data_tag: D25
datatype: byte[8]
name: unpack_data
arguments: data_tag: D10
datatype: byte[8]
name: unpack_data
arguments: data_tag: D14
datatype: string

tool: {"D2": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D14: Error: incorrect number of lines in %s.


assistant: ```c
void ancestrymap2lfmm(char *input_file, char *output_file, int *N, int *M) {
  int *data;
  int nb;
  double tmp;
  *N = nb_ind_ancestrymap(input_file);
  nb = nb_lines(input_file, 1000);
  tmp = (double)nb / (double)(*N);
  if (tmp != floor(tmp)) {
    printf("Error: incorrect number of lines in %s.\n", input_file);
    exit(1);
  }
  *M = (int)tmp;
  data = (int *)malloc((*N) * (*M) * sizeof(int));
  read_ancestrymap(input_file, *N, *M, data);
  write_data_int(output_file, *N, *M, data);
  free(data);
}
```