ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fcitx_utils_align_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  mov    %rdx,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  sub    -0x8(%rbp),%rax
  jmp    L3
L4:
  mov    -0x18(%rbp),%rax
L3:
  pop    %rbp
  ret
```

assistant: ```c
uintptr_t fcitx_utils_align_to(uintptr_t len, uintptr_t align) {
  uintptr_t left;
  if ((left = len % align))
    return len + align - left;
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fcitx_utils_align_to>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rsi
  add    %rdi,%rsi
  sub    %rdx,%rsi
  test   %rdx,%rdx
  cmovne %rsi,%rdi
  mov    %rdi,%rax
  ret
```

assistant: ```c
uintptr_t fcitx_utils_align_to(uintptr_t len, uintptr_t align) {
  uintptr_t left;
  if ((left = len % align))
    return len + align - left;
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<fcitx_utils_align_to>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %rdi,%r8
  div    %rsi
  add    %rdi,%rsi
  sub    %rdx,%rsi
  test   %rdx,%rdx
  cmovne %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
uintptr_t fcitx_utils_align_to(uintptr_t len, uintptr_t align) {
  uintptr_t left;
  if ((left = len % align))
    return len + align - left;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fcitx_utils_align_to>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %rdi,%r8
  div    %rsi
  add    %rdi,%rsi
  sub    %rdx,%rsi
  test   %rdx,%rdx
  cmovne %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
uintptr_t fcitx_utils_align_to(uintptr_t len, uintptr_t align) {
  uintptr_t left;
  if ((left = len % align))
    return len + align - left;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TI_CC_SPIWriteReg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x18(%rbp)
  mov    %al,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x18(%rbp),%eax
  mov    %al,-0xa(%rbp)
  movzbl -0x1c(%rbp),%eax
  mov    %al,-0x9(%rbp)
  lea    -0xa(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x2,%ecx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <CC_SPI_Transfer@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void TI_CC_SPIWriteReg(int fd, char addr, char value) {
  uint8_t buf[2];
  buf[0] = addr;
  buf[1] = value;
  CC_SPI_Transfer(fd, buf, 0, 2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<TI_CC_SPIWriteReg>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  mov    %dl,0x7(%rsp)
  lea    0x6(%rsp),%rsi
  mov    $0x2,%ecx
  mov    $0x0,%edx
  call   <CC_SPI_Transfer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void TI_CC_SPIWriteReg(int fd, char addr, char value) {
  uint8_t buf[2];
  buf[0] = addr;
  buf[1] = value;
  CC_SPI_Transfer(fd, buf, 0, 2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TI_CC_SPIWriteReg>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  mov    %dl,0x7(%rsp)
  xor    %edx,%edx
  call   <CC_SPI_Transfer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void TI_CC_SPIWriteReg(int fd, char addr, char value) {
  uint8_t buf[2];
  buf[0] = addr;
  buf[1] = value;
  CC_SPI_Transfer(fd, buf, 0, 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TI_CC_SPIWriteReg>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,%al
  lea    0x6(%rsp),%rsi
  mov    %dl,%ah
  xor    %edx,%edx
  mov    %ax,0x6(%rsp)
  call   <CC_SPI_Transfer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void TI_CC_SPIWriteReg(int fd, char addr, char value) {
  uint8_t buf[2];
  buf[0] = addr;
  buf[1] = value;
  CC_SPI_Transfer(fd, buf, 0, 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
L25:
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  test   %eax,%eax
  je     L18
  movl   $0x1,-0x14(%rbp)
  jmp    L59
L76:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L69
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L47
L69:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jge    L47
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L47:
  addl   $0x1,-0x14(%rbp)
L59:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L76
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L25
L18:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D15
data_type: string
name: read_data
arguments: label: D27
data_type: string

tool: D15: %d

tool: D27: %d


assistant: ```c
int main() {
  int a = 0, b = 0, c = 0, m, n, min = 1, cou = 1;
  while (1) {
    scanf("%d", &a);
    if (a == 0) {
      break;
    }
    for (m = 1; m <= a; m++) {
      scanf("%d", &n);
      if (n > b) {
        c = b;
        b = n;
        min = cou;
        cou = m;
      } else if (n > c) {
        c = n;
        min = m;
      }
    }
    printf("%d\n", min);
    a = 0, b = 0, c = 0, m, n, min = 1, cou = 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D19(%rip),%r13
  jmp    L80
L67:
  mov    %r14d,%r15d
  mov    %ebx,%r14d
  mov    %ebp,%r12d
  mov    %eax,%ebp
L84:
  add    $0x1,%ebx
  cmp    %ebx,0x10(%rsp)
  jl     L65
L52:
  lea    0x14(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %ebp,%eax
  jg     L67
  cmp    %r12d,%eax
  jle    L84
  mov    %ebx,%r15d
  mov    %eax,%r12d
  jmp    L84
L37:
  mov    $0x1,%r15d
L65:
  mov    %r15d,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
L80:
  movl   $0x0,0x10(%rsp)
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  je     L11
  jle    L37
  mov    $0x1,%r14d
  mov    $0x1,%r15d
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L52
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D7
type: string

tool: D19: %d

tool: D7: %d


assistant: ```c
int main() {
  int a = 0, b = 0, c = 0, m, n, min = 1, cou = 1;
  while (1) {
    scanf("%d", &a);
    if (a == 0) {
      break;
    }
    for (m = 1; m <= a; m++) {
      scanf("%d", &n);
      if (n > b) {
        c = b;
        b = n;
        min = cou;
        cou = m;
      } else if (n > c) {
        c = n;
        min = m;
      }
    }
    printf("%d\n", min);
    a = 0, b = 0, c = 0, m, n, min = 1, cou = 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D29(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L97:
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  movl   $0x0,0x10(%rsp)
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  je     L71
  jle    L74
  mov    $0x1,%r15d
  mov    $0x1,%r14d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  movl   $0x1,0x4(%rsp)
  lea    0x14(%rsp),%r13
  jmp    L46
  xchg   %ax,%ax
L94:
  cmp    %ebp,%eax
  jle    L68
  mov    %r14d,%r15d
  mov    %eax,%ebp
L68:
  add    $0x1,%r14d
  cmp    %r14d,0x10(%rsp)
  jl     L70
L46:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %ebx,%eax
  jle    L94
  mov    0x4(%rsp),%r15d
  mov    %ebx,%ebp
  mov    %r14d,0x4(%rsp)
  mov    %eax,%ebx
  add    $0x1,%r14d
  cmp    %r14d,0x10(%rsp)
  jge    L46
L70:
  mov    %r15d,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L97
  nopl   0x0(%rax)
L71:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L74:
  mov    $0x1,%r15d
  lea    D26(%rip),%rdi
  mov    %r15d,%esi
  call   <printf@plt>
  jmp    L97
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D26
datatype: string

tool: D29: %d

tool: D26: %d


assistant: ```c
int main() {
  int a = 0, b = 0, c = 0, m, n, min = 1, cou = 1;
  while (1) {
    scanf("%d", &a);
    if (a == 0) {
      break;
    }
    for (m = 1; m <= a; m++) {
      scanf("%d", &n);
      if (n > b) {
        c = b;
        b = n;
        min = cou;
        cou = m;
      } else if (n > c) {
        c = n;
        min = m;
      }
    }
    printf("%d\n", min);
    a = 0, b = 0, c = 0, m, n, min = 1, cou = 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  movl   $0x0,0x10(%rsp)
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  je     L13
  jle    L96
  mov    $0x1,%r15d
  mov    $0x1,%r14d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  movl   $0x1,0x4(%rsp)
  lea    0x14(%rsp),%r13
  jmp    L28
  xchg   %ax,%ax
L94:
  cmp    %ebp,%eax
  jle    L24
  mov    %r14d,%r15d
  mov    %eax,%ebp
L24:
  add    $0x1,%r14d
  cmp    %r14d,0x10(%rsp)
  jl     L99
L28:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %ebx,%eax
  jle    L94
  mov    0x4(%rsp),%r15d
  mov    %ebx,%ebp
  mov    %r14d,0x4(%rsp)
  mov    %eax,%ebx
  add    $0x1,%r14d
  cmp    %r14d,0x10(%rsp)
  jge    L28
L99:
  mov    %r15d,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L10
  nopl   0x0(%rax)
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L96:
  mov    $0x1,%r15d
  lea    D29(%rip),%rdi
  mov    %r15d,%esi
  call   <printf@plt>
  jmp    L10
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D26
datatype: string
name: parse_data
arguments: tag: D29
datatype: string

tool: D26: %d

tool: D29: %d


assistant: ```c
int main() {
  int a = 0, b = 0, c = 0, m, n, min = 1, cou = 1;
  while (1) {
    scanf("%d", &a);
    if (a == 0) {
      break;
    }
    for (m = 1; m <= a; m++) {
      scanf("%d", &n);
      if (n > b) {
        c = b;
        b = n;
        min = cou;
        cou = m;
      } else if (n > c) {
        c = n;
        min = m;
      }
    }
    printf("%d\n", min);
    a = 0, b = 0, c = 0, m, n, min = 1, cou = 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmpStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L31
L6:
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  cmp    %eax,-0xc(%rbp)
  jle    L40
  addl   $0x1,-0x28(%rbp)
  lea    -0x11(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzbl -0x11(%rbp),%eax
  cmp    %al,%dl
  je     L32
  mov    $0x0,%eax
  jmp    L43
L40:
  mov    $0x1,%edi
  call   <exit@plt>
L32:
  addl   $0x1,-0x10(%rbp)
L31:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jl     L6
  mov    $0x1,%eax
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int cmpStr(int fd, int start, char str[]) {
  char bfr;
  int len, i;
  len = lseek(fd, 0L, 2);
  for (i = 1; i < strlen(str); i++) {
    if (lseek(fd, start, 0) < len) {
      start++;
      read(fd, &bfr, sizeof(char));
      if ((char)bfr != str[i])
        return 0;
    } else
      exit(1);
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cmpStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    $0x0,%esi
  call   <lseek@plt>
  mov    %eax,%r14d
  mov    $0x1,%ebx
  lea    0x7(%rsp),%r15
  jmp    L40
L55:
  mov    $0x1,%edi
  call   <exit@plt>
L4:
  add    $0x1,%rbx
L40:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L54
  mov    $0x0,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <lseek@plt>
  cmp    %r14d,%eax
  jge    L55
  add    $0x1,%ebp
  mov    $0x1,%edx
  mov    %r15,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  cmp    %al,0x0(%r13,%rbx,1)
  je     L4
  mov    $0x0,%eax
  jmp    L31
L54:
  mov    $0x1,%eax
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmpStr(int fd, int start, char str[]) {
  char bfr;
  int len, i;
  len = lseek(fd, 0L, 2);
  for (i = 1; i < strlen(str); i++) {
    if (lseek(fd, start, 0) < len) {
      start++;
      read(fd, &bfr, sizeof(char));
      if ((char)bfr != str[i])
        return 0;
    } else
      exit(1);
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmpStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    $0x2,%edx
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r15
  call   <lseek@plt>
  mov    %eax,%r14d
  jmp    L6
  nopl   (%rax)
L61:
  mov    $0x1,%edx
  mov    %r15,%rsi
  mov    %r12d,%edi
  add    $0x1,%ebp
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  cmp    %al,0x0(%r13,%rbx,1)
  jne    L0
L18:
  add    $0x1,%rbx
L6:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L64
  xor    %edx,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <lseek@plt>
  cmp    %r14d,%eax
  jl     L61
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
  nopl   0x0(%rax)
L64:
  mov    $0x1,%eax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L51
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  jmp    L23
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmpStr(int fd, int start, char str[]) {
  char bfr;
  int len, i;
  len = lseek(fd, 0L, 2);
  for (i = 1; i < strlen(str); i++) {
    if (lseek(fd, start, 0) < len) {
      start++;
      read(fd, &bfr, sizeof(char));
      if ((char)bfr != str[i])
        return 0;
    } else
      exit(1);
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmpStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    $0x2,%edx
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r15
  call   <lseek@plt>
  mov    %eax,%r14d
  jmp    L55
  nopl   (%rax)
L64:
  mov    $0x1,%edx
  mov    %r15,%rsi
  mov    %r12d,%edi
  add    $0x1,%ebp
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  cmp    %al,0x0(%r13,%rbx,1)
  jne    L49
L8:
  add    $0x1,%rbx
L55:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L42
  xor    %edx,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <lseek@plt>
  cmp    %r14d,%eax
  jl     L64
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
  nopl   0x0(%rax)
L42:
  mov    $0x1,%eax
L33:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L49:
  xor    %eax,%eax
  jmp    L33
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmpStr(int fd, int start, char str[]) {
  char bfr;
  int len, i;
  len = lseek(fd, 0L, 2);
  for (i = 1; i < strlen(str); i++) {
    if (lseek(fd, start, 0) < len) {
      start++;
      read(fd, &bfr, sizeof(char));
      if ((char)bfr != str[i])
        return 0;
    } else
      exit(1);
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GPIOPinTypeCIR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <GPIODirModeSet@plt>
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    $0x8,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <GPIOPadConfigSet@plt>
  nop
  leave
  ret
```

assistant: ```c
void GPIOPinTypeCIR(uint32_t ui32Port, uint8_t ui8Pins) {
  ;
  GPIODirModeSet(ui32Port, ui8Pins, 0x00000002);
  GPIOPadConfigSet(ui32Port, ui8Pins, 0x00000001, 0x00000008);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GPIOPinTypeCIR>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x2,%edx
  call   <GPIODirModeSet@plt>
  mov    $0x8,%ecx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <GPIOPadConfigSet@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void GPIOPinTypeCIR(uint32_t ui32Port, uint8_t ui8Pins) {
  ;
  GPIODirModeSet(ui32Port, ui8Pins, 0x00000002);
  GPIOPadConfigSet(ui32Port, ui8Pins, 0x00000001, 0x00000008);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GPIOPinTypeCIR>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <GPIODirModeSet@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x8,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <GPIOPadConfigSet@plt>
```

assistant: ```c
void GPIOPinTypeCIR(uint32_t ui32Port, uint8_t ui8Pins) {
  ;
  GPIODirModeSet(ui32Port, ui8Pins, 0x00000002);
  GPIOPadConfigSet(ui32Port, ui8Pins, 0x00000001, 0x00000008);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GPIOPinTypeCIR>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <GPIODirModeSet@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x8,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <GPIOPadConfigSet@plt>
```

assistant: ```c
void GPIOPinTypeCIR(uint32_t ui32Port, uint8_t ui8Pins) {
  ;
  GPIODirModeSet(ui32Port, ui8Pins, 0x00000002);
  GPIOPadConfigSet(ui32Port, ui8Pins, 0x00000001, 0x00000008);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fcitx_utils_set_str_with_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fcitx_utils_realloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L17
L13:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <fcitx_utils_malloc@plt>
  mov    %rax,-0x8(%rbp)
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utils_set_str_with_len(char *res, const char *str, size_t len) {
  if (res) {
    res = fcitx_utils_realloc(res, len + 1);
  } else {
    res = fcitx_utils_malloc(len + 1);
  }
  memcpy(res, str, len);
  res[len] = '\0';
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fcitx_utils_set_str_with_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  test   %rdi,%rdi
  je     L13
  lea    0x1(%rdx),%rsi
  call   <fcitx_utils_realloc@plt>
  mov    %rax,%rbx
L5:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    0x1(%rdx),%rdi
  call   <fcitx_utils_malloc@plt>
  mov    %rax,%rbx
  jmp    L5
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utils_set_str_with_len(char *res, const char *str, size_t len) {
  if (res) {
    res = fcitx_utils_realloc(res, len + 1);
  } else {
    res = fcitx_utils_malloc(len + 1);
  }
  memcpy(res, str, len);
  res[len] = '\0';
  return res;
}
```