ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scan_xml_urldecode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L149
  mov    %rax,%r15
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L74
  cmp    $0x1,%ebp
  sbb    %r14d,%r14d
  and    $0xb,%r14d
  add    $0x20,%r14d
  lea    0x1(%rax),%rbp
  mov    $0x0,%r13d
  jmp    L191
L10:
  movzbl 0x1(%rbx),%edi
  test   %dil,%dil
  jne    L97
  add    $0x1,%rbx
L121:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L169
  shl    $0x4,%r13d
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  ja     L138
  movsbl %dil,%edi
  lea    -0x30(%r13,%rdi,1),%r13d
L151:
  add    $0x1,%rbx
L169:
  mov    %rbp,%rax
  mov    %r13d,%edx
L184:
  mov    %dl,(%r12)
  movzbl (%rbx),%edx
  add    $0x1,%rbp
  test   %dl,%dl
  je     L74
L191:
  lea    -0x1(%rbp),%r12
  cmp    $0x25,%dl
  je     L10
  cmp    $0x2b,%dl
  jne    L93
  mov    %rbp,%rax
  add    $0x1,%rbx
  mov    %r14d,%edx
  jmp    L184
L97:
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  ja     L11
  movsbl %dil,%edi
  lea    -0x30(%rdi),%r13d
L26:
  add    $0x2,%rbx
  jmp    L121
L11:
  movsbl %dil,%edi
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L26
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  cmp    $0x60,%al
  jle    L26
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%r13d
  sub    $0x57,%r13d
  jmp    L26
L138:
  movsbl %dil,%edi
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L151
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    $0x60,%al
  jle    L151
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  lea    -0x57(%r13,%rax,1),%r13d
  jmp    L151
L93:
  add    $0x1,%rbx
  mov    %rbp,%rax
  jmp    L184
L74:
  movb   $0x0,(%rax)
L36:
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L149:
  mov    $0x0,%r15d
  jmp    L36
```

assistant: ```c
char *scan_xml_urldecode(char *string, int space_as_plus) {
  char *pnew;
  char *src, *dst;
  int val = 0;
  pnew = (char *)malloc(strlen(string) + 1);
  if (!pnew)
    return NULL;
  src = string;
  dst = pnew;
  while (*src) {
    switch (*src) {
    case '+':
      if (space_as_plus) {
        *dst++ = ' ';
      } else {
        *dst++ = *src;
      }
      src++;
      break;
    case '%':
      src++;
      if (*src) {
        if ((*src <= '9') && (*src >= '0'))
          val = (*src - '0');
        else if ((tolower(*src) <= 'f') && (tolower(*src) >= 'a'))
          val = 10 + (tolower(*src) - 'a');
        src++;
      }
      if (*src) {
        val *= 16;
        if ((*src <= '9') && (*src >= '0'))
          val += (*src - '0');
        else if ((tolower(*src) <= 'f') && (tolower(*src) >= 'a'))
          val += (10 + (tolower(*src) - 'a'));
        src++;
      }
      *dst++ = val;
      break;
    default:
      *dst++ = *src++;
      break;
    }
  }
  *dst = '\0';
  return pnew;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scan_xml_urldecode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L82
  movzbl (%rbx),%eax
  test   %al,%al
  je     L42
  cmp    $0x1,%ebp
  mov    %r15,%rbp
  sbb    %r14d,%r14d
  xor    %r13d,%r13d
  and    $0xb,%r14d
  add    $0x20,%r14d
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L1:
  cmp    $0x2b,%al
  jne    L104
  mov    %r14d,%eax
L104:
  mov    %rdx,%rbx
  mov    %al,(%r12)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L111
L36:
  mov    %rbp,%r12
  lea    0x1(%rbx),%rdx
  add    $0x1,%rbp
  cmp    $0x25,%al
  jne    L1
  movsbl 0x1(%rbx),%edi
  test   %dil,%dil
  je     L120
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  ja     L6
  movsbl %al,%r13d
L73:
  movsbl 0x2(%rbx),%edi
  lea    0x2(%rbx),%rax
  test   %dil,%dil
  je     L46
  lea    -0x30(%rdi),%eax
  shl    $0x4,%r13d
  cmp    $0x9,%al
  ja     L182
  movsbl %al,%eax
  add    %eax,%r13d
L60:
  add    $0x3,%rbx
L94:
  mov    %r13d,%eax
  mov    %al,(%r12)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L36
L111:
  movb   $0x0,0x0(%rbp)
L82:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L120:
  mov    %rdx,%rbx
  jmp    L94
  nopl   (%rax)
L6:
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L73
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  cmp    $0x60,%al
  jle    L73
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%r13d
  sub    $0x57,%r13d
  jmp    L73
  nopl   0x0(%rax)
L182:
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L60
  movsbl 0x2(%rbx),%edi
  call   <tolower@plt>
  cmp    $0x60,%al
  jle    L60
  movsbl 0x2(%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  lea    -0x57(%r13,%rax,1),%r13d
  jmp    L60
  nopl   0x0(%rax)
L42:
  mov    %r15,%rbp
  jmp    L111
L46:
  mov    %rax,%rbx
  jmp    L94
```

assistant: ```c
char *scan_xml_urldecode(char *string, int space_as_plus) {
  char *pnew;
  char *src, *dst;
  int val = 0;
  pnew = (char *)malloc(strlen(string) + 1);
  if (!pnew)
    return NULL;
  src = string;
  dst = pnew;
  while (*src) {
    switch (*src) {
    case '+':
      if (space_as_plus) {
        *dst++ = ' ';
      } else {
        *dst++ = *src;
      }
      src++;
      break;
    case '%':
      src++;
      if (*src) {
        if ((*src <= '9') && (*src >= '0'))
          val = (*src - '0');
        else if ((tolower(*src) <= 'f') && (tolower(*src) >= 'a'))
          val = 10 + (tolower(*src) - 'a');
        src++;
      }
      if (*src) {
        val *= 16;
        if ((*src <= '9') && (*src >= '0'))
          val += (*src - '0');
        else if ((tolower(*src) <= 'f') && (tolower(*src) >= 'a'))
          val += (10 + (tolower(*src) - 'a'));
        src++;
      }
      *dst++ = val;
      break;
    default:
      *dst++ = *src++;
      break;
    }
  }
  *dst = '\0';
  return pnew;
}
```
user: What is the c source code of the assembly code below:

```asm
<scan_xml_urldecode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L195
  movzbl (%rbx),%eax
  test   %al,%al
  je     L177
  cmp    $0x1,%ebp
  mov    %r15,%rbp
  sbb    %r14d,%r14d
  xor    %r13d,%r13d
  and    $0xb,%r14d
  add    $0x20,%r14d
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L99:
  cmp    $0x2b,%al
  jne    L53
  mov    %r14d,%eax
L53:
  mov    %rdx,%rbx
  mov    %al,(%r12)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L71
L60:
  mov    %rbp,%r12
  lea    0x1(%rbx),%rdx
  add    $0x1,%rbp
  cmp    $0x25,%al
  jne    L99
  movsbl 0x1(%rbx),%edi
  test   %dil,%dil
  je     L93
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  ja     L134
  movsbl %al,%r13d
L43:
  movsbl 0x2(%rbx),%edi
  lea    0x2(%rbx),%rax
  test   %dil,%dil
  je     L171
  lea    -0x30(%rdi),%eax
  shl    $0x4,%r13d
  cmp    $0x9,%al
  ja     L13
  movsbl %al,%eax
  add    %eax,%r13d
L120:
  add    $0x3,%rbx
L77:
  mov    %r13d,%eax
  mov    %al,(%r12)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L60
L71:
  movb   $0x0,0x0(%rbp)
L195:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L93:
  mov    %rdx,%rbx
  jmp    L77
  nopl   (%rax)
L134:
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L43
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  cmp    $0x60,%al
  jle    L43
  movsbl 0x1(%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%r13d
  sub    $0x57,%r13d
  jmp    L43
  nopl   0x0(%rax)
L13:
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L120
  movsbl 0x2(%rbx),%edi
  call   <tolower@plt>
  cmp    $0x60,%al
  jle    L120
  movsbl 0x2(%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  lea    -0x57(%r13,%rax,1),%r13d
  jmp    L120
  nopl   0x0(%rax)
L177:
  mov    %r15,%rbp
  jmp    L71
L171:
  mov    %rax,%rbx
  jmp    L77
```

assistant: ```c
char *scan_xml_urldecode(char *string, int space_as_plus) {
  char *pnew;
  char *src, *dst;
  int val = 0;
  pnew = (char *)malloc(strlen(string) + 1);
  if (!pnew)
    return NULL;
  src = string;
  dst = pnew;
  while (*src) {
    switch (*src) {
    case '+':
      if (space_as_plus) {
        *dst++ = ' ';
      } else {
        *dst++ = *src;
      }
      src++;
      break;
    case '%':
      src++;
      if (*src) {
        if ((*src <= '9') && (*src >= '0'))
          val = (*src - '0');
        else if ((tolower(*src) <= 'f') && (tolower(*src) >= 'a'))
          val = 10 + (tolower(*src) - 'a');
        src++;
      }
      if (*src) {
        val *= 16;
        if ((*src <= '9') && (*src >= '0'))
          val += (*src - '0');
        else if ((tolower(*src) <= 'f') && (tolower(*src) >= 'a'))
          val += (10 + (tolower(*src) - 'a'));
        src++;
      }
      *dst++ = val;
      break;
    default:
      *dst++ = *src++;
      break;
    }
  }
  *dst = '\0';
  return pnew;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<StringReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jns    L18
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void StringReverse(char *in, char *out) {
  int i;
  for (i = strlen(in) - 1; i >= 0; i--) {
    *out++ = in[i];
  }
  *out = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<StringReverse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L0
  movslq %edx,%rdx
  add    %rbp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rcx
L21:
  add    $0x1,%rbx
  movzbl (%rdx),%eax
  mov    %al,-0x1(%rbx)
  sub    $0x1,%rdx
  cmp    %rcx,%rbx
  jne    L21
L23:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbx,%rcx
  jmp    L23
```

assistant: ```c
void StringReverse(char *in, char *out) {
  int i;
  for (i = strlen(in) - 1; i >= 0; i--) {
    *out++ = in[i];
  }
  *out = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<StringReverse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L17
  movslq %eax,%rdx
  mov    %eax,%eax
  lea    0x0(%rbp,%rdx,1),%rdi
  lea    0x1(%rbx,%rax,1),%rdx
  nopl   0x0(%rax)
L7:
  movzbl (%rdi),%eax
  add    $0x1,%rbx
  sub    $0x1,%rdi
  mov    %al,-0x1(%rbx)
  cmp    %rdx,%rbx
  jne    L7
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L17:
  mov    %rbx,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void StringReverse(char *in, char *out) {
  int i;
  for (i = strlen(in) - 1; i >= 0; i--) {
    *out++ = in[i];
  }
  *out = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<StringReverse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L19
  movslq %eax,%rdx
  mov    %eax,%eax
  lea    0x0(%rbp,%rdx,1),%rdi
  lea    0x1(%rbx,%rax,1),%rdx
  nopl   0x0(%rax)
L14:
  movzbl (%rdi),%eax
  add    $0x1,%rbx
  sub    $0x1,%rdi
  mov    %al,-0x1(%rbx)
  cmp    %rdx,%rbx
  jne    L14
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L19:
  mov    %rbx,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void StringReverse(char *in, char *out) {
  int i;
  for (i = strlen(in) - 1; i >= 0; i--) {
    *out++ = in[i];
  }
  *out = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_from_str>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D49(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D68(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D47(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D110(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D74(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D56(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D103(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D69(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D35(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D33(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D59(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D113(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D49
type: string
name: parse_data
arguments: data_tag: D68
type: string
name: parse_data
arguments: data_tag: D47
type: string
name: parse_data
arguments: data_tag: D110
type: string
name: parse_data
arguments: data_tag: D74
type: string
name: parse_data
arguments: data_tag: D56
type: string
name: parse_data
arguments: data_tag: D103
type: string
name: parse_data
arguments: data_tag: D69
type: string
name: parse_data
arguments: data_tag: D35
type: string
name: parse_data
arguments: data_tag: D33
type: string
name: parse_data
arguments: data_tag: D59
type: string
name: parse_data
arguments: data_tag: D113
type: string

tool: 

tool: D68: AABBCC

tool: D47: #AAEEGG

tool: D110: #000000

tool: D74: #FFFFFF

tool: D56: #ffffff

tool: D103: #3377aA

tool: D69: #abcdef

tool: D35: #ABCDEF

tool: D33: #123456

tool: D59: #789aBc

tool: D113: #0a0B0c

assistant: ```c
void test_from_str() {
  print_color(ol_color_from_string(NULL));
  print_color(ol_color_from_string(""));
  print_color(ol_color_from_string("AABBCC"));
  print_color(ol_color_from_string("#AAEEGG"));
  print_color(ol_color_from_string("#000000"));
  print_color(ol_color_from_string("#FFFFFF"));
  print_color(ol_color_from_string("#ffffff"));
  print_color(ol_color_from_string("#3377aA"));
  print_color(ol_color_from_string("#abcdef"));
  print_color(ol_color_from_string("#ABCDEF"));
  print_color(ol_color_from_string("#123456"));
  print_color(ol_color_from_string("#789aBc"));
  print_color(ol_color_from_string("#0a0B0c"));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_from_str>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D101(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D105(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D41(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D74(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D66(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D40(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D79(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D119(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D51(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D60(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D90(%rip),%rdi
  call   <ol_color_from_string@plt>
  mov    %eax,%edi
  call   <print_color@plt>
  lea    D94(%rip),%rdi
  call   <ol_color_from_string@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <print_color@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D101
type: string
name: extract_symbolic_data
arguments: tag: D105
type: string
name: extract_symbolic_data
arguments: tag: D41
type: string
name: extract_symbolic_data
arguments: tag: D74
type: string
name: extract_symbolic_data
arguments: tag: D66
type: string
name: extract_symbolic_data
arguments: tag: D40
type: string
name: extract_symbolic_data
arguments: tag: D79
type: string
name: extract_symbolic_data
arguments: tag: D119
type: string
name: extract_symbolic_data
arguments: tag: D51
type: string
name: extract_symbolic_data
arguments: tag: D60
type: string
name: extract_symbolic_data
arguments: tag: D90
type: string
name: extract_symbolic_data
arguments: tag: D94
type: string

tool: 

tool: D105: AABBCC

tool: D41: #AAEEGG

tool: D74: #000000

tool: D66: #FFFFFF

tool: D40: #ffffff

tool: D79: #3377aA

tool: D119: #abcdef

tool: D51: #ABCDEF

tool: D60: #123456

tool: D90: #789aBc

tool: D94: #0a0B0c

assistant: ```c
void test_from_str() {
  print_color(ol_color_from_string(NULL));
  print_color(ol_color_from_string(""));
  print_color(ol_color_from_string("AABBCC"));
  print_color(ol_color_from_string("#AAEEGG"));
  print_color(ol_color_from_string("#000000"));
  print_color(ol_color_from_string("#FFFFFF"));
  print_color(ol_color_from_string("#ffffff"));
  print_color(ol_color_from_string("#3377aA"));
  print_color(ol_color_from_string("#abcdef"));
  print_color(ol_color_from_string("#ABCDEF"));
  print_color(ol_color_from_string("#123456"));
  print_color(ol_color_from_string("#789aBc"));
  print_color(ol_color_from_string("#0a0B0c"));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movb   $0x80,-0xc(%rbp)
  movb   $0x80,-0xb(%rbp)
  movsbl -0xc(%rbp),%edx
  movsbl -0xb(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  je     L37
  mov    $0x1,%eax
  jmp    L114
L37:
  movb   $0x61,-0xc(%rbp)
  movb   $0x62,-0xb(%rbp)
  movsbl -0xc(%rbp),%edx
  movsbl -0xb(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jle    L115
  mov    $0x2,%eax
  jmp    L114
L115:
  movw   $0x8000,-0x8(%rbp)
  movw   $0x8000,-0x6(%rbp)
  movswl -0x8(%rbp),%edx
  movswl -0x6(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  je     L22
  mov    $0x3,%eax
  jmp    L114
L22:
  movw   $0x4e20,-0x8(%rbp)
  movw   $0x4e20,-0x6(%rbp)
  movswl -0x8(%rbp),%edx
  movswl -0x6(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jle    L12
  mov    $0x4,%eax
  jmp    L114
L12:
  movb   $0x80,-0xa(%rbp)
  movb   $0x80,-0x9(%rbp)
  movzbl -0xa(%rbp),%edx
  movzbl -0x9(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jle    L29
  mov    $0x5,%eax
  jmp    L114
L29:
  movw   $0x9c40,-0x4(%rbp)
  movw   $0xc350,-0x2(%rbp)
  movzwl -0x4(%rbp),%edx
  movzwl -0x2(%rbp),%eax
  add    %edx,%eax
  cmp    $0x7530,%eax
  jle    L45
  mov    $0x6,%eax
  jmp    L114
L45:
  mov    $0x0,%eax
L114:
  pop    %rbp
  ret
```

assistant: ```c
int test() {
  char a = -128, b = -128;
  short c, d;
  unsigned char e, f;
  unsigned short g, h;
  if (a + b != 0)
    return 1;
  a = 'a', b = 'b';
  if (a + b > 0)
    return 2;
  c = 1 << 15;
  d = 1 << 15;
  if (c + d != 0)
    return 3;
  c = 20000, d = 20000;
  if (c + d > 0)
    return 4;
  e = 128, f = 128;
  if (e + f > 0)
    return 5;
  g = 40000, h = 50000;
  if (g + h > 30000 || g + h < 0)
    return 6;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test() {
  char a = -128, b = -128;
  short c, d;
  unsigned char e, f;
  unsigned short g, h;
  if (a + b != 0)
    return 1;
  a = 'a', b = 'b';
  if (a + b > 0)
    return 2;
  c = 1 << 15;
  d = 1 << 15;
  if (c + d != 0)
    return 3;
  c = 20000, d = 20000;
  if (c + d > 0)
    return 4;
  e = 128, f = 128;
  if (e + f > 0)
    return 5;
  g = 40000, h = 50000;
  if (g + h > 30000 || g + h < 0)
    return 6;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<test>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test() {
  char a = -128, b = -128;
  short c, d;
  unsigned char e, f;
  unsigned short g, h;
  if (a + b != 0)
    return 1;
  a = 'a', b = 'b';
  if (a + b > 0)
    return 2;
  c = 1 << 15;
  d = 1 << 15;
  if (c + d != 0)
    return 3;
  c = 20000, d = 20000;
  if (c + d > 0)
    return 4;
  e = 128, f = 128;
  if (e + f > 0)
    return 5;
  g = 40000, h = 50000;
  if (g + h > 30000 || g + h < 0)
    return 6;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test() {
  char a = -128, b = -128;
  short c, d;
  unsigned char e, f;
  unsigned short g, h;
  if (a + b != 0)
    return 1;
  a = 'a', b = 'b';
  if (a + b > 0)
    return 2;
  c = 1 << 15;
  d = 1 << 15;
  if (c + d != 0)
    return 3;
  c = 20000, d = 20000;
  if (c + d > 0)
    return 4;
  e = 128, f = 128;
  if (e + f > 0)
    return 5;
  g = 40000, h = 50000;
  if (g + h > 30000 || g + h < 0)
    return 6;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pega_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getch@plt>
  sub    $0x71,%eax
  cmp    $0x12,%eax
  ja     L35
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D8(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L53
  mov    $0x1,%eax
  jmp    L53
  mov    $0x2,%eax
  jmp    L53
  mov    $0x3,%eax
  jmp    L53
  mov    $0x4,%eax
  jmp    L53
L35:
  nop
L53:
  pop    %rbp
  ret
```

assistant: ```c
int pega_input() {
  switch (getch()) {
  case KEY_LEFT:
    return 0;
    break;
  case KEY_RIGHT:
    return 1;
    break;
  case KEY_DOWN:
    return 2;
    break;
  case KEY_UP:
    return 3;
    break;
  case 'q':
    return 4;
    break;
  default:
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<pega_input>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getch@plt>
  sub    $0x71,%eax
  cmp    $0x12,%eax
  ja     L48
  mov    %eax,%eax
  lea    D0(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  jmp    L48
  mov    $0x3,%eax
L48:
  add    $0x8,%rsp
  ret
  mov    $0x4,%eax
  jmp    L48
  mov    $0x0,%eax
  jmp    L48
  mov    $0x2,%eax
  jmp    L48
```

assistant: ```c
int pega_input() {
  switch (getch()) {
  case KEY_LEFT:
    return 0;
    break;
  case KEY_RIGHT:
    return 1;
    break;
  case KEY_DOWN:
    return 2;
    break;
  case KEY_UP:
    return 3;
    break;
  case 'q':
    return 4;
    break;
  default:
    break;
  }
}
```