ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<list_append_list>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L6
  nopl   (%rax)
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <list_get@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <list_append@plt>
L6:
  mov    %rbp,%rdi
  call   <list_size@plt>
  cmp    %ebx,%eax
  jae    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void list_append_list(struct list *l1, const struct list *l2) {
  for (unsigned int i = 1; i <= list_size(l2); ++i)
    list_append(l1, list_get(l2, i));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dt_array_remove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dt_array_find@plt>
  test   %rax,%rax
  jns    L0
  mov    $0xffffffff,%eax
  jmp    L11
L0:
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dt_array_remove_at@plt>
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int dt_array_remove(struct dt_array *a, void *data, void *ret) {
  size_t index;
  if (dt_array_find(a, data, &index) < 0) {
    return -1;
  }
  return dt_array_remove_at(a, index, ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dt_array_remove>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <dt_array_find@plt>
  test   %rax,%rax
  js     L4
  mov    %rbp,%rdx
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  call   <dt_array_remove_at@plt>
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    $0xffffffff,%eax
  jmp    L12
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dt_array_remove(struct dt_array *a, void *data, void *ret) {
  size_t index;
  if (dt_array_find(a, data, &index) < 0) {
    return -1;
  }
  return dt_array_remove_at(a, index, ret);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dt_array_remove>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <dt_array_find@plt>
  test   %rax,%rax
  js     L22
  mov    (%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <dt_array_remove_at@plt>
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L22:
  mov    $0xffffffff,%eax
  jmp    L8
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dt_array_remove(struct dt_array *a, void *data, void *ret) {
  size_t index;
  if (dt_array_find(a, data, &index) < 0) {
    return -1;
  }
  return dt_array_remove_at(a, index, ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dt_array_remove>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <dt_array_find@plt>
  test   %rax,%rax
  js     L4
  mov    (%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <dt_array_remove_at@plt>
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L4:
  mov    $0xffffffff,%eax
  jmp    L2
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dt_array_remove(struct dt_array *a, void *data, void *ret) {
  size_t index;
  if (dt_array_find(a, data, &index) < 0) {
    return -1;
  }
  return dt_array_remove_at(a, index, ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bdtrc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  ja     L84
  movsd  -0x20(%rbp),%xmm0
  movsd  D45(%rip),%xmm1
  comisd %xmm1,%xmm0
  ja     L84
  cmpl   $0x0,-0x14(%rbp)
  jns    L31
  movsd  D45(%rip),%xmm0
  jmp    L94
L31:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L34
  jmp    L92
L84:
  nop
L92:
  mov    $0x1,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
  jmp    L94
L34:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L101
  pxor   %xmm0,%xmm0
  jmp    L94
L101:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L57
  movsd  D11(%rip),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L96
  movsd  -0x20(%rbp),%xmm0
  movq   D44(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log1p@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm3
  mulsd  -0x8(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <expm1@plt>
  movq   %xmm0,%rax
  movq   D44(%rip),%xmm0
  movq   %rax,%xmm4
  xorpd  %xmm0,%xmm4
  movapd %xmm4,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L26
L96:
  movsd  D45(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  D45(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L26
L57:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x3,%eax
  call   <incbet@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L26:
  movsd  -0x10(%rbp),%xmm0
L94:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D45
type_guessed: f64
name: parse_data
arguments: data_tag: D7
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D44
type_guessed: f32[2]

tool: D45: 1

tool: D7: bdtrc

tool: {"D11": [0x7b,0x14,0xae,0x47,0xe1,0x7a,0x84,0x3f]}

tool: {"D44": [0.0,-0.0]}

assistant: ```c
double bdtrc(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if (k < 0)
    return (1.0);
  if (n < k) {
  domerr:
    mtherr("bdtrc", 1);
    return (0.0);
  }
  if (k == n)
    return (0.0);
  dn = n - k;
  if (k == 0) {
    if (p < .01)
      dk = -expm1(dn * log1p(-p));
    else
      dk = 1.0 - pow(1.0 - p, dn);
  } else {
    dk = k + 1;
    dk = incbet(dk, dn, p);
  }
  return (dk);
}
```
user: What is the c source code of the assembly code below?

```asm
<bdtrc>:
  endbr64
  sub    $0x18,%rsp
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  ja     L43
  comisd D48(%rip),%xmm2
  ja     L43
  test   %edi,%edi
  js     L62
  cmp    %esi,%edi
  jg     L43
  pxor   %xmm0,%xmm0
  je     L49
  sub    %edi,%esi
  pxor   %xmm3,%xmm3
  cvtsi2sd %esi,%xmm3
  movsd  %xmm3,0x8(%rsp)
  test   %edi,%edi
  jne    L29
  movsd  D67(%rip),%xmm0
  comisd %xmm2,%xmm0
  jbe    L8
  xorpd  D15(%rip),%xmm2
  movapd %xmm2,%xmm0
  call   <log1p@plt>
  mulsd  0x8(%rsp),%xmm0
  call   <expm1@plt>
  xorpd  D15(%rip),%xmm0
  jmp    L49
L43:
  mov    $0x1,%esi
  lea    D78(%rip),%rdi
  mov    $0x0,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
L49:
  add    $0x18,%rsp
  ret
L8:
  movsd  D48(%rip),%xmm0
  subsd  %xmm2,%xmm0
  movsd  0x8(%rsp),%xmm1
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  D48(%rip),%xmm0
  subsd  %xmm1,%xmm0
  jmp    L49
L29:
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  movsd  0x8(%rsp),%xmm1
  mov    $0x3,%eax
  call   <incbet@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L49
L62:
  movsd  D48(%rip),%xmm0
  jmp    L49
```

tool_calls: name: unpack_data
arguments: label: D48
data_type: f64[2]
name: unpack_data
arguments: label: D67
data_type: byte[8]
name: unpack_data
arguments: label: D15
data_type: f32[4]
name: unpack_data
arguments: label: D78
data_type: string

tool: {"D48": [1.0,0.01]}

tool: {"D67": [0x7b,0x14,0xae,0x47,0xe1,0x7a,0x84,0x3f]}

tool: {"D15": [0.0,-0.0,0.0,0.0]}

tool: D78: bdtrc

assistant: ```c
double bdtrc(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if (k < 0)
    return (1.0);
  if (n < k) {
  domerr:
    mtherr("bdtrc", 1);
    return (0.0);
  }
  if (k == n)
    return (0.0);
  dn = n - k;
  if (k == 0) {
    if (p < .01)
      dk = -expm1(dn * log1p(-p));
    else
      dk = 1.0 - pow(1.0 - p, dn);
  } else {
    dk = k + 1;
    dk = incbet(dk, dn, p);
  }
  return (dk);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bdtrc>:
  endbr64
  pxor   %xmm4,%xmm4
  sub    $0x18,%rsp
  comisd %xmm0,%xmm4
  ja     L37
  movsd  D41(%rip),%xmm3
  movapd %xmm0,%xmm2
  comisd %xmm3,%xmm0
  ja     L37
  movapd %xmm3,%xmm0
  test   %edi,%edi
  js     L84
  cmp    %esi,%edi
  jg     L37
  pxor   %xmm0,%xmm0
  je     L84
  sub    %edi,%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  test   %edi,%edi
  jne    L12
  movsd  D4(%rip),%xmm0
  comisd %xmm2,%xmm0
  jbe    L43
  movq   D56(%rip),%xmm3
  movsd  %xmm1,0x8(%rsp)
  xorpd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  call   <log1p@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  call   <expm1@plt>
  movq   D56(%rip),%xmm3
  xorpd  %xmm3,%xmm0
L84:
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L37:
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L12:
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  mov    $0x3,%eax
  cvtsi2sd %edi,%xmm0
  call   <incbet@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L84
  nop
L43:
  movapd %xmm3,%xmm0
  subsd  %xmm2,%xmm0
  call   <pow@plt>
  mov    D41(%rip),%rax
  movq   %rax,%xmm3
  subsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  jmp    L84
```

tool_calls: name: read_data
arguments: data_label: D41
data_type: f64
name: read_data
arguments: data_label: D4
data_type: byte[8]
name: read_data
arguments: data_label: D56
data_type: f32[2]
name: read_data
arguments: data_label: D11
data_type: string

tool: D41: 1

tool: {"D4": [0x7b,0x14,0xae,0x47,0xe1,0x7a,0x84,0x3f]}

tool: {"D56": [0.0,-0.0]}

tool: D11: bdtrc

assistant: ```c
double bdtrc(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if (k < 0)
    return (1.0);
  if (n < k) {
  domerr:
    mtherr("bdtrc", 1);
    return (0.0);
  }
  if (k == n)
    return (0.0);
  dn = n - k;
  if (k == 0) {
    if (p < .01)
      dk = -expm1(dn * log1p(-p));
    else
      dk = 1.0 - pow(1.0 - p, dn);
  } else {
    dk = k + 1;
    dk = incbet(dk, dn, p);
  }
  return (dk);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bdtrc>:
  endbr64
  pxor   %xmm4,%xmm4
  sub    $0x18,%rsp
  comisd %xmm0,%xmm4
  ja     L70
  movsd  D59(%rip),%xmm3
  movapd %xmm0,%xmm2
  comisd %xmm3,%xmm0
  ja     L70
  movapd %xmm3,%xmm0
  test   %edi,%edi
  js     L79
  cmp    %esi,%edi
  jg     L70
  pxor   %xmm0,%xmm0
  je     L79
  sub    %edi,%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  test   %edi,%edi
  jne    L56
  movsd  D4(%rip),%xmm0
  comisd %xmm2,%xmm0
  jbe    L8
  movq   D0(%rip),%xmm3
  movsd  %xmm1,0x8(%rsp)
  xorpd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  call   <log1p@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  call   <expm1@plt>
  movq   D0(%rip),%xmm3
  xorpd  %xmm3,%xmm0
L79:
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L70:
  mov    $0x1,%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L56:
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  mov    $0x3,%eax
  cvtsi2sd %edi,%xmm0
  call   <incbet@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L79
  nop
L8:
  movapd %xmm3,%xmm0
  subsd  %xmm2,%xmm0
  call   <pow@plt>
  mov    D59(%rip),%rax
  movq   %rax,%xmm3
  subsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  jmp    L79
```

tool_calls: name: unpack_data
arguments: data_label: D59
type: f64
name: unpack_data
arguments: data_label: D4
type: byte[8]
name: unpack_data
arguments: data_label: D0
type: f32[2]
name: unpack_data
arguments: data_label: D27
type: string

tool: D59: 1

tool: {"D4": [0x7b,0x14,0xae,0x47,0xe1,0x7a,0x84,0x3f]}

tool: {"D0": [0.0,-0.0]}

tool: D27: bdtrc

assistant: ```c
double bdtrc(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if (k < 0)
    return (1.0);
  if (n < k) {
  domerr:
    mtherr("bdtrc", 1);
    return (0.0);
  }
  if (k == n)
    return (0.0);
  dn = n - k;
  if (k == 0) {
    if (p < .01)
      dk = -expm1(dn * log1p(-p));
    else
      dk = 1.0 - pow(1.0 - p, dn);
  } else {
    dk = k + 1;
    dk = incbet(dk, dn, p);
  }
  return (dk);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotate_cw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L25
L28:
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L42
L38:
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x2c(%rbp),%eax
  sub    -0x10(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rbp,%rax
  add    %rdx,%rax
  sub    $0xc,%rax
  movzbl (%rax),%edx
  movslq %esi,%rax
  mov    %dl,(%rcx,%rax,1)
  subl   $0x1,-0x10(%rbp)
L42:
  cmpl   $0x0,-0x10(%rbp)
  jns    L38
  addl   $0x1,-0x14(%rbp)
L25:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L28
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void rotate_cw(char matrix[2][2], int width) {
  int i, j;
  char temp[2][2];
  memcpy(temp, matrix, width * width);
  for (i = 0; i < width; i++) {
    for (j = width; j >= 0; j--) {
      matrix[i][width - j - 1] = temp[j][i];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rotate_cw>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,%edx
  imul   %esi,%edx
  lea    0x4(%rsp),%rdi
  mov    %rbp,%rsi
  call   <memcpy@plt>
  test   %ebx,%ebx
  jle    L19
  movslq %ebx,%rax
  movzbl 0x4(%rsp,%rax,2),%eax
  mov    %al,-0x1(%rbp)
  lea    -0x1(%rbx),%eax
  movslq %eax,%rdx
  movzbl 0x4(%rsp,%rdx,2),%edx
  mov    %dl,0x0(%rbp)
  cmp    $0x1,%ebx
  jle    L19
  movslq %ebx,%rbx
  movzbl 0x5(%rsp,%rbx,2),%edx
  mov    %dl,0x1(%rbp)
  cltq
  movzbl 0x5(%rsp,%rax,2),%eax
  mov    %al,0x2(%rbp)
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotate_cw(char matrix[2][2], int width) {
  int i, j;
  char temp[2][2];
  memcpy(temp, matrix, width * width);
  for (i = 0; i < width; i++) {
    for (j = width; j >= 0; j--) {
      matrix[i][width - j - 1] = temp[j][i];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rotate_cw>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rdi,%rbp
  push   %rbx
  imul   %esi,%edx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  test   %ebx,%ebx
  jle    L2
  movslq %ebx,%rdx
  lea    -0x1(%rbx),%eax
  movzbl 0x4(%rsp,%rdx,2),%ecx
  cltq
  mov    %cl,-0x1(%rbp)
  movzbl 0x4(%rsp,%rax,2),%ecx
  mov    %cl,0x0(%rbp)
  cmp    $0x1,%ebx
  je     L2
  movzbl 0x5(%rsp,%rdx,2),%edx
  movzbl 0x5(%rsp,%rax,2),%eax
  mov    %dl,0x1(%rbp)
  mov    %al,0x2(%rbp)
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotate_cw(char matrix[2][2], int width) {
  int i, j;
  char temp[2][2];
  memcpy(temp, matrix, width * width);
  for (i = 0; i < width; i++) {
    for (j = width; j >= 0; j--) {
      matrix[i][width - j - 1] = temp[j][i];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rotate_cw>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rdi,%rbp
  push   %rbx
  imul   %esi,%edx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  test   %ebx,%ebx
  jle    L17
  movslq %ebx,%rdx
  movzbl 0x4(%rsp,%rdx,2),%eax
  mov    %al,-0x1(%rbp)
  lea    -0x1(%rbx),%eax
  cltq
  movzbl 0x4(%rsp,%rax,2),%ecx
  mov    %cl,0x0(%rbp)
  cmp    $0x1,%ebx
  je     L17
  movzbl 0x5(%rsp,%rdx,2),%edx
  movzbl 0x5(%rsp,%rax,2),%eax
  mov    %dl,0x1(%rbp)
  mov    %al,0x2(%rbp)
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotate_cw(char matrix[2][2], int width) {
  int i, j;
  char temp[2][2];
  memcpy(temp, matrix, width * width);
  for (i = 0; i < width; i++) {
    for (j = width; j >= 0; j--) {
      matrix[i][width - j - 1] = temp[j][i];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <entab@plt>
  mov    %al,-0x1(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  char i;
  i = entab();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <entab@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  char i;
  i = entab();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <entab@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  char i;
  i = entab();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <entab@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  char i;
  i = entab();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<filter_block2d_bil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x260,%rsp
  mov    %rdi,-0x238(%rbp)
  mov    %rsi,-0x240(%rbp)
  mov    %edx,-0x244(%rbp)
  mov    %ecx,-0x248(%rbp)
  mov    %r8,-0x250(%rbp)
  mov    %r9,-0x258(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    0x18(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x250(%rbp),%rdi
  mov    -0x244(%rbp),%edx
  lea    -0x230(%rbp),%rsi
  mov    -0x238(%rbp),%rax
  mov    %rdi,%r9
  mov    0x10(%rbp),%r8d
  mov    %rax,%rdi
  call   <filter_block2d_bil_first_pass@plt>
  mov    -0x258(%rbp),%rdi
  mov    0x18(%rbp),%ecx
  mov    -0x248(%rbp),%edx
  mov    -0x240(%rbp),%rsi
  lea    -0x230(%rbp),%rax
  mov    %rdi,%r9
  mov    0x10(%rbp),%r8d
  mov    %rax,%rdi
  call   <filter_block2d_bil_second_pass@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void filter_block2d_bil(unsigned char *src_ptr, unsigned char *dst_ptr, unsigned int src_pitch, unsigned int dst_pitch, const short *HFilter, const short *VFilter, int Width, int Height) {
  unsigned short FData[17 * 16];
  filter_block2d_bil_first_pass(src_ptr, FData, src_pitch, Height + 1, Width, HFilter);
  filter_block2d_bil_second_pass(FData, dst_ptr, dst_pitch, Height, Width, VFilter);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<filter_block2d_bil>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x238,%rsp
  mov    %rsi,%rbx
  mov    %ecx,%ebp
  mov    %r9,%r12
  mov    0x270(%rsp),%r15d
  mov    0x278(%rsp),%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x228(%rsp)
  xor    %eax,%eax
  lea    0x1(%r14),%ecx
  mov    %rsp,%r13
  mov    %r8,%r9
  mov    %r15d,%r8d
  mov    %r13,%rsi
  call   <filter_block2d_bil_first_pass@plt>
  mov    %r12,%r9
  mov    %r15d,%r8d
  mov    %r14d,%ecx
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <filter_block2d_bil_second_pass@plt>
  mov    0x228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x238,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filter_block2d_bil(unsigned char *src_ptr, unsigned char *dst_ptr, unsigned int src_pitch, unsigned int dst_pitch, const short *HFilter, const short *VFilter, int Width, int Height) {
  unsigned short FData[17 * 16];
  filter_block2d_bil_first_pass(src_ptr, FData, src_pitch, Height + 1, Width, HFilter);
  filter_block2d_bil_second_pass(FData, dst_ptr, dst_pitch, Height, Width, VFilter);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<filter_block2d_bil>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r9,%rbx
  mov    %r8,%r9
  sub    $0x238,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x228(%rsp)
  xor    %eax,%eax
  mov    0x270(%rsp),%r15d
  mov    0x278(%rsp),%r13d
  mov    %rsp,%r14
  mov    %r14,%rsi
  lea    0x1(%r13),%ecx
  mov    %r15d,%r8d
  call   <filter_block2d_bil_first_pass@plt>
  mov    %rbx,%r9
  mov    %r15d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <filter_block2d_bil_second_pass@plt>
  mov    0x228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x238,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filter_block2d_bil(unsigned char *src_ptr, unsigned char *dst_ptr, unsigned int src_pitch, unsigned int dst_pitch, const short *HFilter, const short *VFilter, int Width, int Height) {
  unsigned short FData[17 * 16];
  filter_block2d_bil_first_pass(src_ptr, FData, src_pitch, Height + 1, Width, HFilter);
  filter_block2d_bil_second_pass(FData, dst_ptr, dst_pitch, Height, Width, VFilter);
}
```