ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <lst_create@plt>
  mov    $0xb,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <lst_insert@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <lst_append@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <lst_append@plt>
  mov    $0x8,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <lst_insert@plt>
  mov    $0x7,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <lst_insert@plt>
  mov    $0x2,%edx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <lst_insert@plt>
  mov    %r12,%rdx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <lst_get@plt>
  cmp    $0x1,%eax
  je     L29
L3:
  mov    %r12,%rdx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <lst_get@plt>
  cmp    $0x1,%eax
  je     L0
L16:
  mov    %rbp,%rdi
  call   <lst_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L0:
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string

tool: D8: v: %d


assistant: ```c
int main() {
  void *lst;
  int v;
  lst = lst_create();
  lst_insert(lst, 1, 11);
  lst_append(lst, 11);
  lst_append(lst, 5);
  lst_insert(lst, 2, 8);
  lst_insert(lst, 1, 7);
  lst_insert(lst, 10, 2);
  if (lst_get(lst, 3, &v) == 1)
    printf("v: %d\n", v);
  if (lst_get(lst, 6, &v) == 1)
    printf("v: %d\n", v);
  lst_destroy(lst);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x6,-0x20(%rbp,%rax,4)
  lea    -0x20(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int foo(int i) {
  volatile int v[4];
  int *p;
  v[i] = 6;
  p = (int *)&v[i];
  return *p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  movl   $0x6,(%rsp,%rdi,4)
  mov    (%rsp,%rdi,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int i) {
  volatile int v[4];
  int *p;
  v[i] = 6;
  p = (int *)&v[i];
  return *p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x6,(%rsp,%rdi,4)
  mov    (%rsp,%rdi,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int i) {
  volatile int v[4];
  int *p;
  v[i] = 6;
  p = (int *)&v[i];
  return *p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x6,(%rsp,%rdi,4)
  mov    (%rsp,%rdi,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int i) {
  volatile int v[4];
  int *p;
  v[i] = 6;
  p = (int *)&v[i];
  return *p;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: Length of array = %d


assistant: ```c
void print_length(int int_array[]) {
  int length = sizeof int_array / sizeof int_array[0];
  printf("Length of array = %d\n", length);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_length>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: Length of array = %d


assistant: ```c
void print_length(int int_array[]) {
  int length = sizeof int_array / sizeof int_array[0];
  printf("Length of array = %d\n", length);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_length>:
  endbr64
  mov    $0x2,%esi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: Length of array = %d


assistant: ```c
void print_length(int int_array[]) {
  int length = sizeof int_array / sizeof int_array[0];
  printf("Length of array = %d\n", length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_length>:
  endbr64
  mov    $0x2,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: Length of array = %d


assistant: ```c
void print_length(int int_array[]) {
  int length = sizeof int_array / sizeof int_array[0];
  printf("Length of array = %d\n", length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nilsimsa_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x138,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %rsi,-0x140(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x120(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x10,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0xa0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x10,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x12c(%rbp)
  jmp    L21
L1:
  mov    -0x12c(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x138(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <__hexchar_to_int@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x12c(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x138(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <__hexchar_to_int@plt>
  lea    (%rbx,%rax,1),%edx
  mov    -0x12c(%rbp),%eax
  cltq
  mov    %edx,-0x120(%rbp,%rax,4)
  mov    -0x12c(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x140(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <__hexchar_to_int@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x12c(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x140(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <__hexchar_to_int@plt>
  lea    (%rbx,%rax,1),%edx
  mov    -0x12c(%rbp),%eax
  cltq
  mov    %edx,-0xa0(%rbp,%rax,4)
  addl   $0x1,-0x12c(%rbp)
L21:
  cmpl   $0x1f,-0x12c(%rbp)
  jle    L1
  movl   $0x0,-0x128(%rbp)
  movl   $0x0,-0x124(%rbp)
  jmp    L22
L31:
  mov    -0x124(%rbp),%eax
  cltq
  mov    -0x120(%rbp,%rax,4),%edx
  mov    -0x124(%rbp),%eax
  cltq
  mov    -0xa0(%rbp,%rax,4),%eax
  xor    %edx,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__score@plt>
  mov    %eax,%edx
  mov    -0x128(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x128(%rbp)
  addl   $0x1,-0x124(%rbp)
L22:
  cmpl   $0x1f,-0x124(%rbp)
  jle    L31
  mov    $0x80,%eax
  sub    -0x128(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int nilsimsa_compare(const char *hash1, const char *hash2) {
  int digest1[32] = {0};
  int digest2[32] = {0};
  for (int i = 0; i < 32; ++i) {
    digest1[i] = (__hexchar_to_int(hash1[2 * i]) << 4) + __hexchar_to_int(hash1[2 * i + 1]);
    digest2[i] = (__hexchar_to_int(hash2[2 * i]) << 4) + __hexchar_to_int(hash2[2 * i + 1]);
  }
  int bits = 0;
  for (int i = 0; i < 32; i++)
    bits += __score(255 & (digest1[i] ^ digest2[i]));
  return 128 - bits;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nilsimsa_compare>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x10,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x80(%rsp),%rdi
  mov    $0x10,%ecx
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%ebx
L22:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <__hexchar_to_int@plt>
  mov    %eax,%ebp
  movsbl 0x1(%r13,%rbx,1),%edi
  call   <__hexchar_to_int@plt>
  shl    $0x4,%ebp
  add    %eax,%ebp
  mov    %ebp,(%rsp,%rbx,2)
  movsbl (%r12,%rbx,1),%edi
  call   <__hexchar_to_int@plt>
  mov    %eax,%ebp
  movsbl 0x1(%r12,%rbx,1),%edi
  call   <__hexchar_to_int@plt>
  shl    $0x4,%ebp
  add    %eax,%ebp
  mov    %ebp,0x80(%rsp,%rbx,2)
  add    $0x2,%rbx
  cmp    $0x40,%rbx
  jne    L22
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    0x80(%rsp),%r12
L8:
  mov    (%rsp,%rbx,1),%edi
  xor    (%rbx,%r12,1),%edi
  movzbl %dil,%edi
  call   <__score@plt>
  add    %eax,%ebp
  add    $0x4,%rbx
  cmp    $0x80,%rbx
  jne    L8
  mov    $0x80,%eax
  sub    %ebp,%eax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nilsimsa_compare(const char *hash1, const char *hash2) {
  int digest1[32] = {0};
  int digest2[32] = {0};
  for (int i = 0; i < 32; ++i) {
    digest1[i] = (__hexchar_to_int(hash1[2 * i]) << 4) + __hexchar_to_int(hash1[2 * i + 1]);
    digest2[i] = (__hexchar_to_int(hash2[2 * i]) << 4) + __hexchar_to_int(hash2[2 * i + 1]);
  }
  int bits = 0;
  for (int i = 0; i < 32; i++)
    bits += __score(255 & (digest1[i] ^ digest2[i]));
  return 128 - bits;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nilsimsa_compare>:
  endbr64
  push   %r15
  mov    $0x10,%ecx
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x80(%rsp),%r13
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0x10,%ecx
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L5:
  movsbl (%r15,%rbx,1),%edi
  call   <__hexchar_to_int@plt>
  movsbl 0x1(%r15,%rbx,1),%edi
  mov    %eax,%ebp
  call   <__hexchar_to_int@plt>
  shl    $0x4,%ebp
  movsbl (%r14,%rbx,1),%edi
  add    %eax,%ebp
  mov    %ebp,(%r12,%rbx,2)
  call   <__hexchar_to_int@plt>
  movsbl 0x1(%r14,%rbx,1),%edi
  mov    %eax,%ebp
  call   <__hexchar_to_int@plt>
  shl    $0x4,%ebp
  add    %eax,%ebp
  mov    %ebp,0x0(%r13,%rbx,2)
  add    $0x2,%rbx
  cmp    $0x40,%rbx
  jne    L5
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%r12,%rbp,1),%edi
  xor    0x0(%r13,%rbp,1),%edi
  add    $0x4,%rbp
  movzbl %dil,%edi
  call   <__score@plt>
  add    %eax,%ebx
  cmp    $0x80,%rbp
  jne    L29
  mov    $0x80,%eax
  sub    %ebx,%eax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nilsimsa_compare(const char *hash1, const char *hash2) {
  int digest1[32] = {0};
  int digest2[32] = {0};
  for (int i = 0; i < 32; ++i) {
    digest1[i] = (__hexchar_to_int(hash1[2 * i]) << 4) + __hexchar_to_int(hash1[2 * i + 1]);
    digest2[i] = (__hexchar_to_int(hash2[2 * i]) << 4) + __hexchar_to_int(hash2[2 * i + 1]);
  }
  int bits = 0;
  for (int i = 0; i < 32; i++)
    bits += __score(255 & (digest1[i] ^ digest2[i]));
  return 128 - bits;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nilsimsa_compare>:
  endbr64
  push   %r15
  mov    $0x10,%ecx
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x80(%rsp),%r13
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0x10,%ecx
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L2:
  movsbl (%r15,%rbx,1),%edi
  call   <__hexchar_to_int@plt>
  movsbl 0x1(%r15,%rbx,1),%edi
  mov    %eax,%ebp
  call   <__hexchar_to_int@plt>
  shl    $0x4,%ebp
  movsbl (%r14,%rbx,1),%edi
  add    %eax,%ebp
  mov    %ebp,(%r12,%rbx,2)
  call   <__hexchar_to_int@plt>
  movsbl 0x1(%r14,%rbx,1),%edi
  mov    %eax,%ebp
  call   <__hexchar_to_int@plt>
  shl    $0x4,%ebp
  add    %eax,%ebp
  mov    %ebp,0x0(%r13,%rbx,2)
  add    $0x2,%rbx
  cmp    $0x40,%rbx
  jne    L2
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%r12,%rbp,1),%edi
  xor    0x0(%r13,%rbp,1),%edi
  add    $0x4,%rbp
  movzbl %dil,%edi
  call   <__score@plt>
  add    %eax,%ebx
  cmp    $0x80,%rbp
  jne    L13
  mov    $0x80,%eax
  sub    %ebx,%eax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nilsimsa_compare(const char *hash1, const char *hash2) {
  int digest1[32] = {0};
  int digest2[32] = {0};
  for (int i = 0; i < 32; ++i) {
    digest1[i] = (__hexchar_to_int(hash1[2 * i]) << 4) + __hexchar_to_int(hash1[2 * i + 1]);
    digest2[i] = (__hexchar_to_int(hash2[2 * i]) << 4) + __hexchar_to_int(hash2[2 * i + 1]);
  }
  int bits = 0;
  for (int i = 0; i < 32; i++)
    bits += __score(255 & (digest1[i] ^ digest2[i]));
  return 128 - bits;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<digitrev_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movw   $0x0,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L1
L9:
  sarl   -0xc(%rbp)
  movzwl -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x18(%rbp)
L1:
  cmpl   $0x1,-0xc(%rbp)
  jg     L9
  mov    -0x30(%rbp),%eax
  sar    %eax
  mov    %ax,-0x16(%rbp)
  movswl -0x18(%rbp),%edx
  movswl -0x16(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %ax,-0x14(%rbp)
  movswl -0x14(%rbp),%edx
  movswl -0x16(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x18(%rbp),%eax
  and    -0x16(%rbp),%ax
  mov    %ax,-0x12(%rbp)
  movzwl -0x14(%rbp),%edx
  movzwl -0x12(%rbp),%eax
  add    %edx,%eax
  mov    %ax,-0x10(%rbp)
  movswl -0x10(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %ax,-0xe(%rbp)
  mov    -0x28(%rbp),%rax
  movw   $0x0,(%rax)
  movl   $0x1,-0xc(%rbp)
  movswl -0xe(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L21
L30:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  movswl -0xe(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %eax,-0x4(%rbp)
  jmp    L56
L42:
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %eax,-0x4(%rbp)
L56:
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x4(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L42
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L21:
  movswl -0xe(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L30
  movzwl -0xe(%rbp),%eax
  lea    -0x1(%rax),%edx
  movswq -0xe(%rbp),%rax
  add    %rax,%rax
  lea    -0x2(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void digitrev_index(short *index, int n, int radix) {
  int i, j, k;
  short nbits, nbot, ntop, ndiff, n2, raddiv2;
  nbits = 0;
  i = n;
  while (i > 1) {
    i = i >> 1;
    nbits++;
  }
  raddiv2 = radix >> 1;
  nbot = nbits >> raddiv2;
  nbot = nbot << raddiv2 - 1;
  ndiff = nbits & raddiv2;
  ntop = nbot + ndiff;
  n2 = 1 << ntop;
  index[0] = 0;
  for (i = 1, j = n2 / radix + 1; i < n2 - 1; i++) {
    index[i] = j - 1;
    for (k = n2 / radix; k * (radix - 1) < j; k /= radix)
      j -= k * (radix - 1);
    j += k;
  }
  index[n2 - 1] = n2 - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<digitrev_index>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %edx,%edi
  cmp    $0x1,%esi
  jle    L74
  mov    $0x0,%eax
L34:
  sar    %esi
  add    $0x1,%eax
  cmp    $0x1,%esi
  jg     L34
L36:
  mov    %edi,%esi
  sar    %esi
  movswl %ax,%edx
  mov    %esi,%ecx
  sar    %cl,%edx
  lea    -0x1(%rsi),%ecx
  shl    %cl,%edx
  and    %esi,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    $0x1,%r12d
  shl    %cl,%r12d
  movw   $0x0,(%r10)
  movswl %r12w,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %eax,%ebx
  lea    0x1(%rax),%esi
  cmp    $0x2,%ecx
  jle    L44
  lea    -0x1(%rdi),%r8d
  mov    %eax,%r11d
  imul   %r8d,%r11d
  lea    0x2(%r10),%r9
  lea    -0x3(%rcx),%eax
  lea    0x4(%r10,%rax,2),%rbp
L75:
  lea    -0x1(%rsi),%eax
  mov    %ax,(%r9)
  cmp    %esi,%r11d
  jge    L71
  mov    %ebx,%eax
  mov    %r11d,%edx
L4:
  sub    %edx,%esi
  cltd
  idiv   %edi
  mov    %eax,%ecx
  imul   %r8d,%ecx
  mov    %ecx,%edx
  cmp    %esi,%ecx
  jl     L4
L49:
  add    %eax,%esi
  add    $0x2,%r9
  cmp    %rbp,%r9
  jne    L75
L44:
  movswq %r12w,%rax
  sub    $0x1,%r12d
  mov    %r12w,-0x2(%r10,%rax,2)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L74:
  mov    $0x0,%eax
  jmp    L36
L71:
  mov    %ebx,%eax
  jmp    L49
```

assistant: ```c
void digitrev_index(short *index, int n, int radix) {
  int i, j, k;
  short nbits, nbot, ntop, ndiff, n2, raddiv2;
  nbits = 0;
  i = n;
  while (i > 1) {
    i = i >> 1;
    nbits++;
  }
  raddiv2 = radix >> 1;
  nbot = nbits >> raddiv2;
  nbot = nbot << raddiv2 - 1;
  ndiff = nbits & raddiv2;
  ntop = nbot + ndiff;
  n2 = 1 << ntop;
  index[0] = 0;
  for (i = 1, j = n2 / radix + 1; i < n2 - 1; i++) {
    index[i] = j - 1;
    for (k = n2 / radix; k * (radix - 1) < j; k /= radix)
      j -= k * (radix - 1);
    j += k;
  }
  index[n2 - 1] = n2 - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<digitrev_index>:
  endbr64
  mov    %edx,%r8d
  push   %r12
  mov    %rdi,%r10
  push   %rbp
  sar    %r8d
  push   %rbx
  cmp    $0x1,%esi
  jle    L58
  movswl %r8w,%ecx
  mov    %edx,%edi
  xor    %eax,%eax
  lea    -0x1(%rcx),%r9d
  cs nopw 0x0(%rax,%rax,1)
L22:
  sar    %esi
  add    $0x1,%eax
  cmp    $0x1,%esi
  jne    L22
  movswl %ax,%edx
  and    %r8d,%eax
  sar    %cl,%edx
  mov    %r9d,%ecx
  shl    %cl,%edx
  lea    (%rax,%rdx,1),%ecx
  shl    %cl,%esi
  movswq %si,%rax
  movswl %si,%r12d
  lea    -0x1(%rsi),%r8d
  lea    -0x2(%r10,%rax,2),%rbx
  xor    %eax,%eax
  mov    %ax,(%r10)
  mov    %r12d,%eax
  cltd
  idiv   %edi
  mov    %eax,%ebp
  lea    0x1(%rax),%ecx
  lea    -0x1(%r12),%eax
  cmp    $0x1,%eax
  jle    L38
  lea    -0x1(%rdi),%esi
  mov    %ebp,%r11d
  lea    -0x3(%r12),%eax
  imul   %esi,%r11d
  lea    0x2(%r10),%r9
  lea    0x4(%r10,%rax,2),%r10
L7:
  lea    -0x1(%rcx),%eax
  mov    %ax,(%r9)
  mov    %ebp,%eax
  cmp    %ecx,%r11d
  jge    L45
  mov    %r11d,%edx
  nopl   0x0(%rax)
L24:
  sub    %edx,%ecx
  cltd
  idiv   %edi
  mov    %eax,%edx
  imul   %esi,%edx
  cmp    %ecx,%edx
  jl     L24
L45:
  add    $0x2,%r9
  add    %eax,%ecx
  cmp    %r9,%r10
  jne    L7
L38:
  mov    %r8w,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  mov    %rdi,%rbx
  xor    %edx,%edx
  xor    %r8d,%r8d
  mov    %dx,(%rdi)
  mov    %r8w,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void digitrev_index(short *index, int n, int radix) {
  int i, j, k;
  short nbits, nbot, ntop, ndiff, n2, raddiv2;
  nbits = 0;
  i = n;
  while (i > 1) {
    i = i >> 1;
    nbits++;
  }
  raddiv2 = radix >> 1;
  nbot = nbits >> raddiv2;
  nbot = nbot << raddiv2 - 1;
  ndiff = nbits & raddiv2;
  ntop = nbot + ndiff;
  n2 = 1 << ntop;
  index[0] = 0;
  for (i = 1, j = n2 / radix + 1; i < n2 - 1; i++) {
    index[i] = j - 1;
    for (k = n2 / radix; k * (radix - 1) < j; k /= radix)
      j -= k * (radix - 1);
    j += k;
  }
  index[n2 - 1] = n2 - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<digitrev_index>:
  endbr64
  mov    %edx,%r8d
  push   %r12
  mov    %rdi,%r10
  push   %rbp
  sar    %r8d
  push   %rbx
  cmp    $0x1,%esi
  jle    L54
  movswl %r8w,%ecx
  mov    %edx,%edi
  xor    %eax,%eax
  lea    -0x1(%rcx),%r9d
  cs nopw 0x0(%rax,%rax,1)
L58:
  sar    %esi
  add    $0x1,%eax
  cmp    $0x1,%esi
  jne    L58
  movswl %ax,%edx
  and    %r8d,%eax
  sar    %cl,%edx
  mov    %r9d,%ecx
  shl    %cl,%edx
  lea    (%rax,%rdx,1),%ecx
  shl    %cl,%esi
  movswq %si,%rax
  movswl %si,%r12d
  lea    -0x1(%rsi),%r8d
  lea    -0x2(%r10,%rax,2),%rbx
  xor    %eax,%eax
  mov    %ax,(%r10)
  mov    %r12d,%eax
  cltd
  idiv   %edi
  mov    %eax,%ebp
  lea    0x1(%rax),%ecx
  lea    -0x1(%r12),%eax
  cmp    $0x1,%eax
  jle    L33
  lea    -0x1(%rdi),%esi
  mov    %ebp,%r11d
  lea    -0x3(%r12),%eax
  imul   %esi,%r11d
  lea    0x2(%r10),%r9
  lea    0x4(%r10,%rax,2),%r10
L52:
  lea    -0x1(%rcx),%eax
  mov    %ax,(%r9)
  mov    %ebp,%eax
  cmp    %ecx,%r11d
  jge    L36
  mov    %r11d,%edx
  nopl   0x0(%rax)
L31:
  sub    %edx,%ecx
  cltd
  idiv   %edi
  mov    %eax,%edx
  imul   %esi,%edx
  cmp    %ecx,%edx
  jl     L31
L36:
  add    $0x2,%r9
  add    %eax,%ecx
  cmp    %r9,%r10
  jne    L52
L33:
  mov    %r8w,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  mov    %rdi,%rbx
  xor    %edx,%edx
  xor    %r8d,%r8d
  mov    %dx,(%rdi)
  mov    %r8w,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void digitrev_index(short *index, int n, int radix) {
  int i, j, k;
  short nbits, nbot, ntop, ndiff, n2, raddiv2;
  nbits = 0;
  i = n;
  while (i > 1) {
    i = i >> 1;
    nbits++;
  }
  raddiv2 = radix >> 1;
  nbot = nbits >> raddiv2;
  nbot = nbot << raddiv2 - 1;
  ndiff = nbits & raddiv2;
  ntop = nbot + ndiff;
  n2 = 1 << ntop;
  index[0] = 0;
  for (i = 1, j = n2 / radix + 1; i < n2 - 1; i++) {
    index[i] = j - 1;
    for (k = n2 / radix; k * (radix - 1) < j; k /= radix)
      j -= k * (radix - 1);
    j += k;
  }
  index[n2 - 1] = n2 - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strVec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   $0x64,%eax,%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L17:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  movq   %rcx,%xmm0
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D9: %s %.17e

assistant: ```c
char *strVec(double a[], int n) {
  int i;
  char *string;
  string = (char *)calloc(sizeof(char), 100 * n);
  for (i = 0; i < n; i++)
    sprintf(string, "%s %.17e", string, a[i]);
  return string;
}
```