ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jne    L83
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  cmp    $0x1,%eax
  jg     L23
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  js     L23
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  cmp    $0x5dc,%eax
  jg     L61
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  cmp    $0x3f,%eax
  jle    L61
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L8
  cmp    $0x1,%eax
  je     L31
L78:
  xor    %r12d,%r12d
L69:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L31:
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    $0x1f90,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%edx
  call   <tcp_traffic@plt>
  jmp    L78
L8:
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    $0x1f90,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%edx
  call   <udp_traffic@plt>
  jmp    L69
L61:
  lea    D49(%rip),%rdi
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L69
L23:
  lea    D7(%rip),%rdi
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L69
L83:
  lea    D17(%rip),%rdi
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L69
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string
name: extract_symbolic_data
arguments: data_tag: D49
datatype: string
name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D17
datatype: string

tool: D8: localhost

tool: D49:     Error: 64 <= PACKET_SIZE <= 1500


tool: D7:     Error: PROTOCOL = 0 (UDP) or 1 (TCP)


tool: D17:     Usage: web_client PROTOCOL PACKET_SIZE
       PROTOCOL = 0 (UDP) or 1 (TCP)
       PACKET_SIZE = n (packet size to send)


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("    Usage: web_client PROTOCOL PACKET_SIZE\n"
           "       PROTOCOL = 0 (UDP) or 1 (TCP)\n"
           "       PACKET_SIZE = n (packet size to send)\n");
    return -1;
  }
  if (atoi(argv[1]) > 1 || atoi(argv[1]) < 0) {
    printf("    Error: PROTOCOL = 0 (UDP) or 1 (TCP)\n");
    return -1;
  }
  if (atoi(argv[2]) > 1500 || atoi(argv[2]) < 64) {
    printf("    Error: 64 <= PACKET_SIZE <= 1500\n");
    return -1;
  }
  switch (atoi(argv[1])) {
  case 0:
    udp_traffic("localhost", 8080, atoi(argv[2]));
    break;
  case 1:
    tcp_traffic("localhost", 8080, atoi(argv[2]));
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jne    L5
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  cmp    $0x1,%eax
  jg     L114
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  js     L114
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  cmp    $0x5dc,%eax
  jg     L65
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  cmp    $0x3f,%eax
  jle    L65
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L86
  cmp    $0x1,%eax
  je     L44
L26:
  xor    %r12d,%r12d
L62:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L44:
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    $0x1f90,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%edx
  call   <tcp_traffic@plt>
  jmp    L26
L86:
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    $0x1f90,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%edx
  call   <udp_traffic@plt>
  jmp    L62
L65:
  lea    D18(%rip),%rdi
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L62
L114:
  lea    D10(%rip),%rdi
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L62
L5:
  lea    D24(%rip),%rdi
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L62
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string

tool: D11: localhost

tool: D18:     Error: 64 <= PACKET_SIZE <= 1500


tool: D10:     Error: PROTOCOL = 0 (UDP) or 1 (TCP)


tool: D24:     Usage: web_client PROTOCOL PACKET_SIZE
       PROTOCOL = 0 (UDP) or 1 (TCP)
       PACKET_SIZE = n (packet size to send)


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("    Usage: web_client PROTOCOL PACKET_SIZE\n"
           "       PROTOCOL = 0 (UDP) or 1 (TCP)\n"
           "       PACKET_SIZE = n (packet size to send)\n");
    return -1;
  }
  if (atoi(argv[1]) > 1 || atoi(argv[1]) < 0) {
    printf("    Error: PROTOCOL = 0 (UDP) or 1 (TCP)\n");
    return -1;
  }
  if (atoi(argv[2]) > 1500 || atoi(argv[2]) < 64) {
    printf("    Error: 64 <= PACKET_SIZE <= 1500\n");
    return -1;
  }
  switch (atoi(argv[1])) {
  case 0:
    udp_traffic("localhost", 8080, atoi(argv[2]));
    break;
  case 1:
    tcp_traffic("localhost", 8080, atoi(argv[2]));
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  je     L67
  cmpl   $0x5,-0x4(%rbp)
  jg     L89
  cmpl   $0x4,-0x4(%rbp)
  je     L35
  cmpl   $0x4,-0x4(%rbp)
  jg     L89
  cmpl   $0x1,-0x4(%rbp)
  je     L77
  cmpl   $0x2,-0x4(%rbp)
  je     L72
  jmp    L89
L77:
  movl   $0x1,-0x4(%rbp)
  jmp    L30
L72:
  movl   $0x1,-0x4(%rbp)
L35:
  movl   $0x1,-0x4(%rbp)
L67:
  movl   $0x1,-0x4(%rbp)
  jmp    L30
L89:
  movl   $0x1,-0x4(%rbp)
  nop
L30:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int a = 1;
  switch (a) {
  case 1:
    a = 1;
    break;
  case 2:
    a = 1;
  case 4:
    a = 1;
  case 5:
    a = 1;
    break;
  default:
    a = 1;
    break;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 1;
  switch (a) {
  case 1:
    a = 1;
    break;
  case 2:
    a = 1;
  case 4:
    a = 1;
  case 5:
    a = 1;
    break;
  default:
    a = 1;
    break;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 1;
  switch (a) {
  case 1:
    a = 1;
    break;
  case 2:
    a = 1;
  case 4:
    a = 1;
  case 5:
    a = 1;
    break;
  default:
    a = 1;
    break;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 1;
  switch (a) {
  case 1:
    a = 1;
    break;
  case 2:
    a = 1;
  case 4:
    a = 1;
  case 5:
    a = 1;
    break;
  default:
    a = 1;
    break;
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<accuracy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x24(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  leave
  ret
```

assistant: ```c
float accuracy(const float *b1, float *b2, const int len) {
  float err = 0.0;
  int i;
  for (i = 0; i < len; i++) {
    err += (b1[i] - b2[i]) * (b1[i] - b2[i]);
  }
  return (float)sqrt(err / len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<accuracy>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L6
  mov    %edx,%ecx
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
L17:
  movss  (%rdi,%rax,4),%xmm1
  subss  (%rsi,%rax,4),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L17
L15:
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  add    $0x8,%rsp
  ret
L6:
  pxor   %xmm0,%xmm0
  jmp    L15
```

assistant: ```c
float accuracy(const float *b1, float *b2, const int len) {
  float err = 0.0;
  int i;
  for (i = 0; i < len; i++) {
    err += (b1[i] - b2[i]) * (b1[i] - b2[i]);
  }
  return (float)sqrt(err / len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<accuracy>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L24
  movslq %edx,%rcx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  nopl   (%rax)
L26:
  movss  (%rdi,%rax,4),%xmm1
  subss  (%rsi,%rax,4),%xmm1
  add    $0x1,%rax
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L26
L12:
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2ss %rax,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  pxor   %xmm0,%xmm0
  jmp    L12
```

assistant: ```c
float accuracy(const float *b1, float *b2, const int len) {
  float err = 0.0;
  int i;
  for (i = 0; i < len; i++) {
    err += (b1[i] - b2[i]) * (b1[i] - b2[i]);
  }
  return (float)sqrt(err / len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<accuracy>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L78
  lea    -0x1(%rdx),%eax
  mov    %rsi,%rcx
  cmp    $0x2,%eax
  jbe    L62
  mov    %edx,%esi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%esi
  shl    $0x4,%rsi
  xchg   %ax,%ax
L39:
  movups (%rdi,%rax,1),%xmm1
  movups (%rcx,%rax,1),%xmm3
  add    $0x10,%rax
  subps  %xmm3,%xmm1
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L39
  mov    %edx,%esi
  and    $0xfffffffc,%esi
  mov    %esi,%eax
  cmp    %edx,%esi
  je     L20
L68:
  mov    %edx,%r8d
  sub    %esi,%r8d
  cmp    $0x1,%r8d
  je     L77
  movq   (%rdi,%rsi,4),%xmm1
  movq   (%rcx,%rsi,4),%xmm2
  mov    %r8d,%esi
  and    $0xfffffffe,%esi
  subps  %xmm2,%xmm1
  add    %esi,%eax
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  shufps $0xe5,%xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %esi,%r8d
  je     L20
L77:
  cltq
  movss  (%rdi,%rax,4),%xmm1
  subss  (%rcx,%rax,4),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
L20:
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2ss %rax,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  pxor   %xmm0,%xmm0
  jmp    L20
L62:
  xor    %esi,%esi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L68
```

assistant: ```c
float accuracy(const float *b1, float *b2, const int len) {
  float err = 0.0;
  int i;
  for (i = 0; i < len; i++) {
    err += (b1[i] - b2[i]) * (b1[i] - b2[i]);
  }
  return (float)sqrt(err / len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<module_spi_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x6,%edi
  call   <gpio_set_value@plt>
  mov    $0x6,%edi
  call   <gpio_free@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void module_spi_exit(void) {
  gpio_set_value(6, 0);
  gpio_free(6);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<module_spi_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x6,%edi
  call   <gpio_set_value@plt>
  mov    $0x6,%edi
  call   <gpio_free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void module_spi_exit(void) {
  gpio_set_value(6, 0);
  gpio_free(6);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<module_spi_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edi
  xor    %esi,%esi
  call   <gpio_set_value@plt>
  mov    $0x6,%edi
  add    $0x8,%rsp
  jmp    1060 <gpio_free@plt>
```

assistant: ```c
void module_spi_exit(void) {
  gpio_set_value(6, 0);
  gpio_free(6);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<module_spi_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edi
  xor    %esi,%esi
  call   <gpio_set_value@plt>
  mov    $0x6,%edi
  add    $0x8,%rsp
  jmp    1060 <gpio_free@plt>
```

assistant: ```c
void module_spi_exit(void) {
  gpio_set_value(6, 0);
  gpio_free(6);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D24(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D48(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D50(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D34(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  lea    -0x40(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <solve@plt>
  movsd  -0x38(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D27
datatype: byte[8]
name: unpack_data
arguments: label: D24
datatype: byte[8]
name: unpack_data
arguments: label: D48
datatype: f64
name: unpack_data
arguments: label: D50
datatype: byte[8]
name: unpack_data
arguments: label: D34
datatype: byte[8]
name: unpack_data
arguments: label: D15
datatype: byte[8]
name: unpack_data
arguments: label: D51
datatype: string

tool: {"D27": [0x61,0x32,0x55,0x30,0x2a,0xa9,0xcb,0x3f]}

tool: {"D24": [0xc4,0x42,0xad,0x69,0xde,0x71,0xc2,0x3f]}

tool: D48: 1.2969

tool: {"D50": [0xea,0x95,0xb2,0x0c,0x71,0xac,0xeb,0x3f]}

tool: {"D34": [0x3b,0xdf,0x4f,0x8d,0x97,0x6e,0xc2,0x3f]}

tool: {"D15": [0x9d,0x80,0x26,0xc2,0x86,0xa7,0xeb,0x3f]}

tool: D51: %.16e %.16e


assistant: ```c
int main(int argc, char *argv[]) {
  double A[4] = {.2161, .1441, 1.2969, .8648};
  double B[2] = {.1440, .8642};
  double C[2] = {0, 0};
  solve(A, B, C);
  printf("%.16e %.16e\n", C[0], C[1]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D10(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D8(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D15(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D37(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D34(%rip),%rax
  mov    %rax,(%rsp)
  mov    D25(%rip),%rax
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x20(%rsp),%rdi
  call   <solve@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D10
type: byte[8]
name: read_data
arguments: tag: D8
type: byte[8]
name: read_data
arguments: tag: D15
type: f64
name: read_data
arguments: tag: D37
type: byte[8]
name: read_data
arguments: tag: D34
type: byte[8]
name: read_data
arguments: tag: D25
type: byte[8]
name: read_data
arguments: tag: D24
type: string

tool: {"D10": [0x61,0x32,0x55,0x30,0x2a,0xa9,0xcb,0x3f]}

tool: {"D8": [0xc4,0x42,0xad,0x69,0xde,0x71,0xc2,0x3f]}

tool: D15: 1.2969

tool: {"D37": [0xea,0x95,0xb2,0x0c,0x71,0xac,0xeb,0x3f]}

tool: {"D34": [0x3b,0xdf,0x4f,0x8d,0x97,0x6e,0xc2,0x3f]}

tool: {"D25": [0x9d,0x80,0x26,0xc2,0x86,0xa7,0xeb,0x3f]}

tool: D24: %.16e %.16e


assistant: ```c
int main(int argc, char *argv[]) {
  double A[4] = {.2161, .1441, 1.2969, .8648};
  double B[2] = {.1440, .8642};
  double C[2] = {0, 0};
  solve(A, B, C);
  printf("%.16e %.16e\n", C[0], C[1]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rsi
  movq   $0x0,0x10(%rsp)
  mov    D20(%rip),%rax
  movq   $0x0,0x18(%rsp)
  mov    %rax,0x20(%rsp)
  mov    D38(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D35(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D49(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D2(%rip),%rax
  mov    %rax,(%rsp)
  mov    D47(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <solve@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D20
type_infered: byte[8]
name: parse_data
arguments: data_label: D38
type_infered: byte[8]
name: parse_data
arguments: data_label: D35
type_infered: f64
name: parse_data
arguments: data_label: D49
type_infered: byte[8]
name: parse_data
arguments: data_label: D2
type_infered: byte[8]
name: parse_data
arguments: data_label: D47
type_infered: byte[8]
name: parse_data
arguments: data_label: D22
type_infered: string

tool: {"D20": [0x61,0x32,0x55,0x30,0x2a,0xa9,0xcb,0x3f]}

tool: {"D38": [0xc4,0x42,0xad,0x69,0xde,0x71,0xc2,0x3f]}

tool: D35: 1.2969

tool: {"D49": [0xea,0x95,0xb2,0x0c,0x71,0xac,0xeb,0x3f]}

tool: {"D2": [0x3b,0xdf,0x4f,0x8d,0x97,0x6e,0xc2,0x3f]}

tool: {"D47": [0x9d,0x80,0x26,0xc2,0x86,0xa7,0xeb,0x3f]}

tool: D22: %.16e %.16e


assistant: ```c
int main(int argc, char *argv[]) {
  double A[4] = {.2161, .1441, 1.2969, .8648};
  double B[2] = {.1440, .8642};
  double C[2] = {0, 0};
  solve(A, B, C);
  printf("%.16e %.16e\n", C[0], C[1]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  movapd D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rsi
  movaps %xmm0,0x20(%rsp)
  movapd D13(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movapd D2(%rip),%xmm0
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <solve@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
type_guessed: byte[16]
name: read_data
arguments: data_label: D13
type_guessed: f64[2]
name: read_data
arguments: data_label: D2
type_guessed: byte[16]
name: read_data
arguments: data_label: D0
type_guessed: string

tool: {"D22": [0x61,0x32,0x55,0x30,0x2a,0xa9,0xcb,0x3f,0xc4,0x42,0xad,0x69,0xde,0x71,0xc2,0x3f]}

tool: {"D13": [1.2969,0.8648]}

tool: {"D2": [0x3b,0xdf,0x4f,0x8d,0x97,0x6e,0xc2,0x3f,0x9d,0x80,0x26,0xc2,0x86,0xa7,0xeb,0x3f]}

tool: D0: %.16e %.16e


assistant: ```c
int main(int argc, char *argv[]) {
  double A[4] = {.2161, .1441, 1.2969, .8648};
  double B[2] = {.1440, .8642};
  double C[2] = {0, 0};
  solve(A, B, C);
  printf("%.16e %.16e\n", C[0], C[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<rl_end_of_history>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rl_maybe_replace_line@plt>
  mov    $0x0,%eax
  call   <using_history@plt>
  mov    $0x0,%eax
  call   <rl_maybe_unsave_line@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int rl_end_of_history(count, key)
int count __attribute__((unused)), key __attribute__((unused));
{
  rl_maybe_replace_line();
  using_history();
  rl_maybe_unsave_line();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rl_end_of_history>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rl_maybe_replace_line@plt>
  mov    $0x0,%eax
  call   <using_history@plt>
  mov    $0x0,%eax
  call   <rl_maybe_unsave_line@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rl_end_of_history(count, key)
int count __attribute__((unused)), key __attribute__((unused));
{
  rl_maybe_replace_line();
  using_history();
  rl_maybe_unsave_line();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rl_end_of_history>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rl_maybe_replace_line@plt>
  xor    %eax,%eax
  call   <using_history@plt>
  xor    %eax,%eax
  call   <rl_maybe_unsave_line@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rl_end_of_history(count, key)
int count __attribute__((unused)), key __attribute__((unused));
{
  rl_maybe_replace_line();
  using_history();
  rl_maybe_unsave_line();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rl_end_of_history>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rl_maybe_replace_line@plt>
  xor    %eax,%eax
  call   <using_history@plt>
  xor    %eax,%eax
  call   <rl_maybe_unsave_line@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rl_end_of_history(count, key)
int count __attribute__((unused)), key __attribute__((unused));
{
  rl_maybe_replace_line();
  using_history();
  rl_maybe_unsave_line();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L1:
  shrl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int length(unsigned value) {
  int ret = 0;
  while (value != 0)
    value >>= 1, ret++;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<length>:
  endbr64
  test   %edi,%edi
  je     L8
  mov    $0x0,%eax
L18:
  add    $0x1,%eax
  shr    %edi
  jne    L18
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int length(unsigned value) {
  int ret = 0;
  while (value != 0)
    value >>= 1, ret++;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<length>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L7
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x1,%eax
  shr    %edi
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
int length(unsigned value) {
  int ret = 0;
  while (value != 0)
    value >>= 1, ret++;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<length>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L8
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%eax
  shr    %edi
  jne    L2
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
int length(unsigned value) {
  int ret = 0;
  while (value != 0)
    value >>= 1, ret++;
  return ret;
}
```