ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<match_uni>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    $0x0,%r12d
  cmp    $0x6,%rax
  jbe    L18
  lea    -0x3(%rax),%rbx
  mov    %rbx,%r13
  and    $0x3,%r13d
  jne    L18
  mov    $0x3,%edx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L18
  add    $0x3,%rbp
  mov    %rbp,%rdi
  call   <string_is_hex@plt>
  test   %rax,%rax
  je     L18
  shr    $0x2,%rbx
  lea    0x4(,%rbx,4),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  mov    %ebx,(%rax)
  lea    0x3(%rsp),%r14
  jmp    L81
L19:
  mov    %eax,0x4(%r12,%r13,4)
  add    $0x1,%r13
  add    $0x4,%rbp
  cmp    %r13,%rbx
  jbe    L18
L81:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x7(%rsp)
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <strtoul@plt>
  lea    -0xe000(%rax),%edx
  cmp    $0x1fff,%edx
  jbe    L19
  cmp    $0xd7ff,%eax
  jbe    L19
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%r12d
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string

tool: D0: uni

assistant: ```c
unsigned int *match_uni(const char *name) {
  unsigned int *unicode_string;
  size_t name_length;
  unicode_string = NULL;
  name_length = strlen(name);
  if (7 <= name_length && (name_length - 3) % 4 == 0 && strncmp("uni", name, 3) == 0 && string_is_hex(name + 3)) {
    const size_t word_count = (name_length - 3) / 4;
    unicode_string = malloc((word_count + 1) * sizeof(*unicode_string));
    if (unicode_string != NULL) {
      size_t i;
      char substring[5];
      unicode_string[0] = word_count;
      i = 0;
      while (unicode_string != NULL && i < word_count) {
        unsigned int u;
        memcpy(substring, name + 3 + (4 * i), 4);
        substring[4] = '\0';
        u = (unsigned int)strtoul(substring, NULL, 16);
        if ((0x0000 <= u && u <= 0xD7FF) || (0xE000 <= u && u <= 0xFFFF)) {
          unicode_string[i + 1] = u;
        } else {
          free(unicode_string);
          unicode_string = NULL;
        }
        i++;
      }
    }
  }
  return unicode_string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<match_uni>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x6,%rax
  jbe    L93
  lea    -0x3(%rax),%rbx
  mov    %rbx,%r14
  and    $0x3,%r14d
  jne    L93
  mov    $0x3,%edx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L93
  add    $0x3,%rbp
  mov    %rbp,%rdi
  call   <string_is_hex@plt>
  test   %rax,%rax
  je     L93
  shr    $0x2,%rbx
  lea    0x4(,%rbx,4),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L93
  mov    %ebx,(%rax)
  lea    0x3(%rsp),%r13
  nopl   (%rax)
L1:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  movb   $0x0,0x7(%rsp)
  call   <strtoul@plt>
  lea    -0xe000(%rax),%edx
  cmp    $0x1fff,%edx
  jbe    L37
  cmp    $0xd7ff,%eax
  jbe    L37
  mov    %r12,%rdi
  call   <free@plt>
L93:
  xor    %r12d,%r12d
L82:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L37:
  add    $0x1,%r14
  add    $0x4,%rbp
  mov    %eax,(%r12,%r14,4)
  cmp    %rbx,%r14
  jb     L1
  jmp    L82
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
type: string

tool: D7: uni

assistant: ```c
unsigned int *match_uni(const char *name) {
  unsigned int *unicode_string;
  size_t name_length;
  unicode_string = NULL;
  name_length = strlen(name);
  if (7 <= name_length && (name_length - 3) % 4 == 0 && strncmp("uni", name, 3) == 0 && string_is_hex(name + 3)) {
    const size_t word_count = (name_length - 3) / 4;
    unicode_string = malloc((word_count + 1) * sizeof(*unicode_string));
    if (unicode_string != NULL) {
      size_t i;
      char substring[5];
      unicode_string[0] = word_count;
      i = 0;
      while (unicode_string != NULL && i < word_count) {
        unsigned int u;
        memcpy(substring, name + 3 + (4 * i), 4);
        substring[4] = '\0';
        u = (unsigned int)strtoul(substring, NULL, 16);
        if ((0x0000 <= u && u <= 0xD7FF) || (0xE000 <= u && u <= 0xFFFF)) {
          unicode_string[i + 1] = u;
        } else {
          free(unicode_string);
          unicode_string = NULL;
        }
        i++;
      }
    }
  }
  return unicode_string;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<match_uni>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x6,%rax
  jbe    L46
  lea    -0x3(%rax),%rbx
  mov    %rbx,%r14
  and    $0x3,%r14d
  jne    L46
  mov    $0x3,%edx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L46
  add    $0x3,%rbp
  mov    %rbp,%rdi
  call   <string_is_hex@plt>
  test   %rax,%rax
  je     L46
  shr    $0x2,%rbx
  lea    0x4(,%rbx,4),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L46
  mov    %ebx,(%rax)
  lea    0x3(%rsp),%r13
  nopl   (%rax)
L40:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  movb   $0x0,0x7(%rsp)
  call   <strtoul@plt>
  lea    -0xe000(%rax),%edx
  cmp    $0x1fff,%edx
  jbe    L64
  cmp    $0xd7ff,%eax
  jbe    L64
  mov    %r12,%rdi
  call   <free@plt>
L46:
  xor    %r12d,%r12d
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L64:
  add    $0x1,%r14
  add    $0x4,%rbp
  mov    %eax,(%r12,%r14,4)
  cmp    %rbx,%r14
  jb     L40
  jmp    L15
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: uni

assistant: ```c
unsigned int *match_uni(const char *name) {
  unsigned int *unicode_string;
  size_t name_length;
  unicode_string = NULL;
  name_length = strlen(name);
  if (7 <= name_length && (name_length - 3) % 4 == 0 && strncmp("uni", name, 3) == 0 && string_is_hex(name + 3)) {
    const size_t word_count = (name_length - 3) / 4;
    unicode_string = malloc((word_count + 1) * sizeof(*unicode_string));
    if (unicode_string != NULL) {
      size_t i;
      char substring[5];
      unicode_string[0] = word_count;
      i = 0;
      while (unicode_string != NULL && i < word_count) {
        unsigned int u;
        memcpy(substring, name + 3 + (4 * i), 4);
        substring[4] = '\0';
        u = (unsigned int)strtoul(substring, NULL, 16);
        if ((0x0000 <= u && u <= 0xD7FF) || (0xE000 <= u && u <= 0xFFFF)) {
          unicode_string[i + 1] = u;
        } else {
          free(unicode_string);
          unicode_string = NULL;
        }
        i++;
      }
    }
  }
  return unicode_string;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L15
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x0,%eax
  call   <abort@plt>
L15:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xrealloc(void *w, size_t n) {
  void *v;
  v = realloc(w, n);
  if (n != 0 && !v)
    abort();
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrealloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rbx,%rbx
  je     L21
  test   %rax,%rax
  je     L16
L21:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L21
```

assistant: ```c
void *xrealloc(void *w, size_t n) {
  void *v;
  v = realloc(w, n);
  if (n != 0 && !v)
    abort();
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrealloc>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L3
  test   %rax,%rax
  je     L0
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
void *xrealloc(void *w, size_t n) {
  void *v;
  v = realloc(w, n);
  if (n != 0 && !v)
    abort();
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrealloc>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L10
  test   %rax,%rax
  je     L4
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
void *xrealloc(void *w, size_t n) {
  void *v;
  v = realloc(w, n);
  if (n != 0 && !v)
    abort();
  return v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0xc(%rbp)
  movl   $0xf,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L9
  mov    -0xc(%rbp),%eax
  jmp    L6
L9:
  mov    -0x8(%rbp),%eax
L6:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  int i = 10, j = 15, k;
  k = 10 * (i) > (j) ? (i) : (j);
  printf("%d\n", k);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  int i = 10, j = 15, k;
  k = 10 * (i) > (j) ? (i) : (j);
  printf("%d\n", k);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: %d


assistant: ```c
int main() {
  int i = 10, j = 15, k;
  k = 10 * (i) > (j) ? (i) : (j);
  printf("%d\n", k);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0: %d


assistant: ```c
int main() {
  int i = 10, j = 15, k;
  k = 10 * (i) > (j) ? (i) : (j);
  printf("%d\n", k);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<QEIIntStatus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x4002c000,-0x4(%rbp)
  je     L4
  cmpl   $0x4002d000,-0x4(%rbp)
  jne    L6
L4:
  mov    $0x1,%eax
  jmp    L44
L6:
  mov    $0x0,%eax
L44:
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x0,-0x8(%rbp)
  je     L48
  mov    -0x4(%rbp),%eax
  add    $0x28,%eax
  cltq
  mov    (%rax),%eax
  jmp    L38
L48:
  mov    -0x4(%rbp),%eax
  add    $0x24,%eax
  cltq
  mov    (%rax),%eax
L38:
  leave
  ret
```

assistant: ```c
uint32_t QEIIntStatus(uint32_t ui32Base, bool bMasked) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  if (bMasked) {
    return ((*((volatile uint32_t *)(ui32Base + 0x00000028))));
  } else {
    return ((*((volatile uint32_t *)(ui32Base + 0x00000024))));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<QEIIntStatus>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edi,%eax
  and    $0xef,%ah
  cmp    $0x4002c000,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  test   %ebp,%ebp
  je     L13
  add    $0x28,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  add    $0x24,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  jmp    L0
```

assistant: ```c
uint32_t QEIIntStatus(uint32_t ui32Base, bool bMasked) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  if (bMasked) {
    return ((*((volatile uint32_t *)(ui32Base + 0x00000028))));
  } else {
    return ((*((volatile uint32_t *)(ui32Base + 0x00000024))));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<QEIIntStatus>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %esi,%ebp
  push   %rbx
  and    $0xef,%ah
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x4002c000,%eax
  sete   %dil
  call   <ASSERT@plt>
  test   %ebp,%ebp
  je     L6
  add    $0x28,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x24,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t QEIIntStatus(uint32_t ui32Base, bool bMasked) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  if (bMasked) {
    return ((*((volatile uint32_t *)(ui32Base + 0x00000028))));
  } else {
    return ((*((volatile uint32_t *)(ui32Base + 0x00000024))));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<QEIIntStatus>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %esi,%ebp
  push   %rbx
  and    $0xef,%ah
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x4002c000,%eax
  sete   %dil
  call   <ASSERT@plt>
  test   %ebp,%ebp
  je     L4
  add    $0x28,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x24,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t QEIIntStatus(uint32_t ui32Base, bool bMasked) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  if (bMasked) {
    return ((*((volatile uint32_t *)(ui32Base + 0x00000028))));
  } else {
    return ((*((volatile uint32_t *)(ui32Base + 0x00000024))));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<minimum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x7fffffff,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L28
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L28:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int minimum(int *arr, int n) {
  int r = 0x7fffffff;
  int i;
  for (i = 0; i < n; i++) {
    if (arr[i] < r)
      r = arr[i];
  }
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<minimum>:
  endbr64
  test   %esi,%esi
  jle    L11
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rsi
  mov    $0x7fffffff,%edx
L13:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L13
L25:
  mov    %edx,%eax
  ret
L11:
  mov    $0x7fffffff,%edx
  jmp    L25
```

assistant: ```c
int minimum(int *arr, int n) {
  int r = 0x7fffffff;
  int i;
  for (i = 0; i < n; i++) {
    if (arr[i] < r)
      r = arr[i];
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<minimum>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rcx
  mov    $0x7fffffff,%eax
  nopl   (%rax)
L13:
  mov    (%rdi),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L13
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x7fffffff,%eax
  ret
```

assistant: ```c
int minimum(int *arr, int n) {
  int r = 0x7fffffff;
  int i;
  for (i = 0; i < n; i++) {
    if (arr[i] < r)
      r = arr[i];
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<minimum>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L52
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L30
  mov    %esi,%ecx
  movdqa D6(%rip),%xmm0
  mov    %rdi,%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  cs nopw 0x0(%rax,%rax,1)
L19:
  movdqu (%rax),%xmm1
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm3,%xmm1
  por    %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L19
  movdqa %xmm0,%xmm2
  mov    %edx,%ecx
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%ecx
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%dl
  je     L17
L33:
  movslq %ecx,%rsi
  lea    0x0(,%rsi,4),%r8
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jle    L34
  mov    0x4(%rdi,%r8,1),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  add    $0x2,%ecx
  cmp    %ecx,%edx
  jle    L34
  mov    0x8(%rdi,%r8,1),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
  nop
L52:
  mov    $0x7fffffff,%eax
L34:
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  ret
L30:
  xor    %ecx,%ecx
  mov    $0x7fffffff,%eax
  jmp    L33
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: byte[16]

tool: {"D6": [0xff,0xff,0xff,0x7f,0xff,0xff,0xff,0x7f,0xff,0xff,0xff,0x7f,0xff,0xff,0xff,0x7f]}

assistant: ```c
int minimum(int *arr, int n) {
  int r = 0x7fffffff;
  int i;
  for (i = 0; i < n; i++) {
    if (arr[i] < r)
      r = arr[i];
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calccs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  subl   $0x1,-0x14(%rbp)
  jmp    L3
L16:
  addl   $0x1,-0x4(%rbp)
L3:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int calccs(int code) {
  int len = 1;
  code--;
  while (code >>= 1)
    len++;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calccs>:
  endbr64
  sub    $0x1,%edi
  sar    %edi
  je     L1
  mov    $0x1,%eax
L13:
  add    $0x1,%eax
  sar    %edi
  jne    L13
  ret
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int calccs(int code) {
  int len = 1;
  code--;
  while (code >>= 1)
    len++;
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calccs>:
  endbr64
  sub    $0x1,%edi
  mov    $0x1,%eax
  sar    %edi
  je     L8
L7:
  add    $0x1,%eax
  sar    %edi
  jne    L7
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
int calccs(int code) {
  int len = 1;
  code--;
  while (code >>= 1)
    len++;
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calccs>:
  endbr64
  sub    $0x1,%edi
  mov    $0x1,%eax
  sar    %edi
  je     L11
L17:
  add    $0x1,%eax
  sar    %edi
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
int calccs(int code) {
  int len = 1;
  code--;
  while (code >>= 1)
    len++;
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<halt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void halt(char *errstr) {
  assert(errstr);
  error(errstr);
  exit(EXIT_FAILURE);
}
```
user: What is the c source code of the assembly code below:

```asm
<halt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <error@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void halt(char *errstr) {
  assert(errstr);
  error(errstr);
  exit(EXIT_FAILURE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<halt>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <error@plt>
  mov    D1(%rip),%rax
  pop    %rbp
  mov    (%rax),%edi
  jmp    1090 <exit@plt>
```

assistant: ```c
void halt(char *errstr) {
  assert(errstr);
  error(errstr);
  exit(EXIT_FAILURE);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<halt>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <error@plt>
  mov    D2(%rip),%rax
  pop    %rbp
  mov    (%rax),%edi
  jmp    1090 <exit@plt>
```

assistant: ```c
void halt(char *errstr) {
  assert(errstr);
  error(errstr);
  exit(EXIT_FAILURE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<isr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <cdreg@plt>
  movw   $0xff,-0x12(%rbp)
  mov    -0x10(%rbp),%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x12(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x10,%edi
  call   <cssa@plt>
  movw   $0x0,-0x12(%rbp)
  mov    -0x10(%rbp),%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x12(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x10,%edi
  call   <cssa@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <cdlam@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <cclc@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ccrgl@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: ISR


assistant: ```c
void isr(void) {
  int ext, q;
  unsigned short d;
  cdreg(&ext, 0, 0, 1, 0);
  d = 0xFF;
  cssa(16, ext, &d, &q);
  d = 0;
  cssa(16, ext, &d, &q);
  cdlam(&ext, 0, 0, 1, 0, NULL);
  cclc(ext);
  ccrgl(ext);
  printf("ISR\n");
}
```