ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D3(%rip),%r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L35:
  lea    0x4(%rsp),%rbx
  mov    %rsp,%rbp
  mov    %r13d,%edx
  xor    %r13d,%r13d
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <print_tablero@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <change_pos@plt>
L57:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cmp    $0x45,%eax
  jg     L78
  cmp    $0x45,%edx
  jg     L78
L59:
  mov    %r14,%rdi
  call   <system@plt>
  test   %r12d,%r12d
  je     L35
  mov    %r12d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0x46,%ebx
  call   <printf@plt>
  xchg   %ax,%ax
L76:
  mov    $0x2d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L76
  mov    $0xa,%edi
  sub    $0x1,%r12d
  call   <putchar@plt>
  jmp    L57
L78:
  cmp    %edx,%eax
  jl     L83
  lea    D6(%rip),%rdi
  call   <puts@plt>
L89:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L83:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L89
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D1
datatype: string
name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D26
datatype: string

tool: D3: %d


tool: D1: clear

tool: D6: 

La tortuga ha ganado!

tool: D26: 

La liebre ha ganado!

assistant: ```c
int main() {
  srand(time(0));
  int tx = 0, lx = 0, i = 1, countdown = 3;
  while (tx < 70 && lx < 70) {
    system("clear");
    if (countdown == 0) {
      print_tablero(&tx, &lx, i);
      if (i == 1) {
        i = 0;
      }
      change_pos(&tx, &lx);
    } else {
      printf("%d\n", countdown);
      for (int i = 0; i < 70; i++)
        printf("-");
      printf("\n");
      countdown--;
    }
    sleep(1);
  }
  if (tx >= lx)
    printf("\n\nLa tortuga ha ganado!\n");
  else
    printf("\n\nLa liebre ha ganado!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D2(%rip),%r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L7:
  lea    0x4(%rsp),%rbx
  mov    %rsp,%rbp
  mov    %r13d,%edx
  xor    %r13d,%r13d
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <print_tablero@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <change_pos@plt>
L42:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cmp    $0x45,%eax
  jg     L59
  cmp    $0x45,%edx
  jg     L59
L40:
  mov    %r14,%rdi
  call   <system@plt>
  test   %r12d,%r12d
  je     L7
  mov    %r12d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0x46,%ebx
  call   <printf@plt>
  xchg   %ax,%ax
L25:
  mov    $0x2d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L25
  mov    $0xa,%edi
  sub    $0x1,%r12d
  call   <putchar@plt>
  jmp    L42
L59:
  cmp    %edx,%eax
  jl     L24
  lea    D36(%rip),%rdi
  call   <puts@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  jmp    L18
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string
name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D36
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string

tool: D2: %d


tool: D0: clear

tool: D36: 

La tortuga ha ganado!

tool: D28: 

La liebre ha ganado!

assistant: ```c
int main() {
  srand(time(0));
  int tx = 0, lx = 0, i = 1, countdown = 3;
  while (tx < 70 && lx < 70) {
    system("clear");
    if (countdown == 0) {
      print_tablero(&tx, &lx, i);
      if (i == 1) {
        i = 0;
      }
      change_pos(&tx, &lx);
    } else {
      printf("%d\n", countdown);
      for (int i = 0; i < 70; i++)
        printf("-");
      printf("\n");
      countdown--;
    }
    sleep(1);
  }
  if (tx >= lx)
    printf("\n\nLa tortuga ha ganado!\n");
  else
    printf("\n\nLa liebre ha ganado!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hextoString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x6665646362613938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L9
L15:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x2c(%rbp)
L9:
  mov    -0x2c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L15
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
char *hextoString(uint8_t *input, int inputlen) {
  char convert[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  char *result = malloc((inputlen * 2) + 1);
  int posInResult = 0;
  for (int posInInput = 0; posInInput < inputlen; ++posInInput) {
    result[posInResult++] = convert[input[posInInput] >> 4];
    result[posInResult++] = convert[input[posInInput] & 0xf];
  }
  result[posInResult] = 0x0;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hextoString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x6665646362613938,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  lea    (%rsi,%rsi,1),%ebp
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  jle    L18
  mov    %r12d,%esi
  mov    $0x0,%edx
L12:
  mov    (%rbx,%rdx,4),%ecx
  sar    $0x4,%ecx
  movslq %ecx,%rcx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,(%rax,%rdx,2)
  mov    (%rbx,%rdx,4),%ecx
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,0x1(%rax,%rdx,2)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L12
L30:
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    $0x0,%ebp
  jmp    L30
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *hextoString(uint8_t *input, int inputlen) {
  char convert[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  char *result = malloc((inputlen * 2) + 1);
  int posInResult = 0;
  for (int posInInput = 0; posInInput < inputlen; ++posInInput) {
    result[posInResult++] = convert[input[posInInput] >> 4];
    result[posInResult++] = convert[input[posInInput] & 0xf];
  }
  result[posInResult] = 0x0;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<hextoString>:
  endbr64
  push   %r12
  lea    (%rsi,%rsi,1),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%r12),%edi
  sub    $0x20,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L36
  movslq %ebp,%rsi
  xor    %edx,%edx
  nopl   0x0(%rax)
L13:
  mov    (%rbx,%rdx,4),%ecx
  sar    $0x4,%ecx
  movslq %ecx,%rcx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,(%rax,%rdx,2)
  mov    (%rbx,%rdx,4),%ecx
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,0x1(%rax,%rdx,2)
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L13
  movslq %r12d,%r12
  add    %rax,%r12
L21:
  movb   $0x0,(%r12)
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rax,%r12
  jmp    L21
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type: byte[16]

tool: {"D9": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x61,0x62,0x63,0x64,0x65,0x66]}

assistant: ```c
char *hextoString(uint8_t *input, int inputlen) {
  char convert[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  char *result = malloc((inputlen * 2) + 1);
  int posInResult = 0;
  for (int posInInput = 0; posInInput < inputlen; ++posInInput) {
    result[posInResult++] = convert[input[posInInput] >> 4];
    result[posInResult++] = convert[input[posInInput] & 0xf];
  }
  result[posInResult] = 0x0;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hextoString>:
  endbr64
  push   %r12
  lea    (%rsi,%rsi,1),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%r12),%edi
  sub    $0x20,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L22
  movslq %ebp,%rsi
  xor    %edx,%edx
  nopl   0x0(%rax)
L16:
  mov    (%rbx,%rdx,4),%ecx
  sar    $0x4,%ecx
  movslq %ecx,%rcx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,(%rax,%rdx,2)
  mov    (%rbx,%rdx,4),%ecx
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,0x1(%rax,%rdx,2)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L16
  movslq %r12d,%r12
  add    %rax,%r12
L10:
  movb   $0x0,(%r12)
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rax,%r12
  jmp    L10
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: byte[16]

tool: {"D7": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x61,0x62,0x63,0x64,0x65,0x66]}

assistant: ```c
char *hextoString(uint8_t *input, int inputlen) {
  char convert[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  char *result = malloc((inputlen * 2) + 1);
  int posInResult = 0;
  for (int posInInput = 0; posInInput < inputlen; ++posInInput) {
    result[posInResult++] = convert[input[posInInput] >> 4];
    result[posInResult++] = convert[input[posInInput] & 0xf];
  }
  result[posInResult] = 0x0;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ceph_unarmor>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rdx,%rsi
  jae    L62
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%r15
  movl   $0x0,0xc(%rsp)
  jmp    L64
L26:
  add    $0x1,%rbx
  jmp    L47
L43:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,0xc(%rsp)
  jmp    L39
L112:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,0xc(%rsp)
L39:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  addl   $0x1,0xc(%rsp)
  jmp    L39
L101:
  shl    $0x6,%r12d
  or     %edx,%r12d
  mov    %r12b,0x2(%r13)
  addl   $0x3,0xc(%rsp)
  mov    %r14,%rbx
  lea    0x3(%r13),%r13
L47:
  cmp    %rbx,%r15
  jbe    L39
L64:
  movzbl (%rbx),%edi
  cmp    $0xa,%dil
  je     L26
  lea    0x4(%rbx),%r14
  cmp    %r15,%r14
  ja     L43
  movsbl %dil,%edi
  call   <decode_bits@plt>
  mov    %eax,0x8(%rsp)
  movsbl 0x1(%rbx),%edi
  call   <decode_bits@plt>
  mov    %eax,%ebp
  movsbl 0x2(%rbx),%edi
  call   <decode_bits@plt>
  mov    %eax,%r12d
  movsbl 0x3(%rbx),%edi
  call   <decode_bits@plt>
  mov    %eax,%edx
  mov    0x8(%rsp),%eax
  or     %ebp,%eax
  or     %r12d,%eax
  or     %edx,%eax
  js     L112
  mov    0x8(%rsp),%eax
  shl    $0x2,%eax
  mov    %ebp,%ecx
  sar    $0x4,%ecx
  or     %ecx,%eax
  mov    %al,0x0(%r13)
  cmpb   $0x3d,0x2(%rbx)
  je     L34
  shl    $0x4,%ebp
  mov    %r12d,%eax
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r13)
  cmpb   $0x3d,0x3(%rbx)
  jne    L101
  addl   $0x2,0xc(%rsp)
  jmp    L39
L62:
  movl   $0x0,0xc(%rsp)
  jmp    L39
```

assistant: ```c
int ceph_unarmor(char *dst, const char *src, const char *end) {
  int olen = 0;
  while (src < end) {
    int a, b, c, d;
    if (src[0] == '\n') {
      src++;
      continue;
    }
    if (src + 4 > end)
      return -EINVAL;
    a = decode_bits(src[0]);
    b = decode_bits(src[1]);
    c = decode_bits(src[2]);
    d = decode_bits(src[3]);
    if (a < 0 || b < 0 || c < 0 || d < 0)
      return -EINVAL;
    *dst++ = (a << 2) | (b >> 4);
    if (src[2] == '=')
      return olen + 1;
    *dst++ = ((b & 15) << 4) | (c >> 2);
    if (src[3] == '=')
      return olen + 2;
    *dst++ = ((c & 3) << 6) | d;
    olen += 3;
    src += 4;
  }
  return olen;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ceph_unarmor>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rdx,%rsi
  jae    L78
  movl   $0x0,0xc(%rsp)
  mov    %rdi,%r15
  mov    %rsi,%rbx
  mov    %rdx,%r13
  jmp    L2
  nopl   0x0(%rax)
L22:
  lea    0x4(%rbx),%rdx
  cmp    %r13,%rdx
  ja     L52
  mov    %rdx,(%rsp)
  call   <decode_bits@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%r12d
  call   <decode_bits@plt>
  movsbl 0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <decode_bits@plt>
  movsbl 0x3(%rbx),%edi
  mov    %eax,%r14d
  call   <decode_bits@plt>
  mov    (%rsp),%rdx
  mov    %eax,%esi
  mov    %r12d,%eax
  or     %ebp,%eax
  or     %r14d,%eax
  or     %esi,%eax
  js     L52
  mov    %ebp,%eax
  shl    $0x2,%r12d
  sar    $0x4,%eax
  or     %eax,%r12d
  mov    %r12b,(%r15)
  cmpb   $0x3d,0x2(%rbx)
  je     L30
  mov    %r14d,%eax
  shl    $0x4,%ebp
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r15)
  cmpb   $0x3d,0x3(%rbx)
  je     L29
  shl    $0x6,%r14d
  mov    %rdx,%rbx
  addl   $0x3,0xc(%rsp)
  add    $0x3,%r15
  or     %esi,%r14d
  mov    %r14b,-0x1(%r15)
  cmp    %rbx,%r13
  jbe    L125
L2:
  movsbl (%rbx),%edi
  cmp    $0xa,%dil
  jne    L22
  add    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L2
L125:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    D7(%rip),%rax
  mov    (%rax),%r13d
  neg    %r13d
  mov    %r13d,0xc(%rsp)
  jmp    L125
  nopl   0x0(%rax)
L30:
  addl   $0x1,0xc(%rsp)
  jmp    L125
  nopw   0x0(%rax,%rax,1)
L29:
  addl   $0x2,0xc(%rsp)
  jmp    L125
L78:
  movl   $0x0,0xc(%rsp)
  jmp    L125
```

assistant: ```c
int ceph_unarmor(char *dst, const char *src, const char *end) {
  int olen = 0;
  while (src < end) {
    int a, b, c, d;
    if (src[0] == '\n') {
      src++;
      continue;
    }
    if (src + 4 > end)
      return -EINVAL;
    a = decode_bits(src[0]);
    b = decode_bits(src[1]);
    c = decode_bits(src[2]);
    d = decode_bits(src[3]);
    if (a < 0 || b < 0 || c < 0 || d < 0)
      return -EINVAL;
    *dst++ = (a << 2) | (b >> 4);
    if (src[2] == '=')
      return olen + 1;
    *dst++ = ((b & 15) << 4) | (c >> 2);
    if (src[3] == '=')
      return olen + 2;
    *dst++ = ((c & 3) << 6) | d;
    olen += 3;
    src += 4;
  }
  return olen;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ceph_unarmor>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rdx,%rsi
  jae    L68
  movl   $0x0,0xc(%rsp)
  mov    %rdi,%r15
  mov    %rsi,%rbx
  mov    %rdx,%r13
  jmp    L37
  nopl   0x0(%rax)
L38:
  lea    0x4(%rbx),%rdx
  cmp    %r13,%rdx
  ja     L84
  mov    %rdx,(%rsp)
  call   <decode_bits@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%r12d
  call   <decode_bits@plt>
  movsbl 0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <decode_bits@plt>
  movsbl 0x3(%rbx),%edi
  mov    %eax,%r14d
  call   <decode_bits@plt>
  mov    (%rsp),%rdx
  mov    %eax,%esi
  mov    %r12d,%eax
  or     %ebp,%eax
  or     %r14d,%eax
  or     %esi,%eax
  js     L84
  mov    %ebp,%eax
  shl    $0x2,%r12d
  sar    $0x4,%eax
  or     %eax,%r12d
  mov    %r12b,(%r15)
  cmpb   $0x3d,0x2(%rbx)
  je     L41
  mov    %r14d,%eax
  shl    $0x4,%ebp
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r15)
  cmpb   $0x3d,0x3(%rbx)
  je     L79
  shl    $0x6,%r14d
  mov    %rdx,%rbx
  addl   $0x3,0xc(%rsp)
  add    $0x3,%r15
  or     %esi,%r14d
  mov    %r14b,-0x1(%r15)
  cmp    %rbx,%r13
  jbe    L92
L37:
  movsbl (%rbx),%edi
  cmp    $0xa,%dil
  jne    L38
  add    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L37
L92:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L84:
  mov    D2(%rip),%rax
  mov    (%rax),%r13d
  neg    %r13d
  mov    %r13d,0xc(%rsp)
  jmp    L92
  nopl   0x0(%rax)
L41:
  addl   $0x1,0xc(%rsp)
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L79:
  addl   $0x2,0xc(%rsp)
  jmp    L92
L68:
  movl   $0x0,0xc(%rsp)
  jmp    L92
```

assistant: ```c
int ceph_unarmor(char *dst, const char *src, const char *end) {
  int olen = 0;
  while (src < end) {
    int a, b, c, d;
    if (src[0] == '\n') {
      src++;
      continue;
    }
    if (src + 4 > end)
      return -EINVAL;
    a = decode_bits(src[0]);
    b = decode_bits(src[1]);
    c = decode_bits(src[2]);
    d = decode_bits(src[3]);
    if (a < 0 || b < 0 || c < 0 || d < 0)
      return -EINVAL;
    *dst++ = (a << 2) | (b >> 4);
    if (src[2] == '=')
      return olen + 1;
    *dst++ = ((b & 15) << 4) | (c >> 2);
    if (src[3] == '=')
      return olen + 2;
    *dst++ = ((c & 3) << 6) | d;
    olen += 3;
    src += 4;
  }
  return olen;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cosine_sum_unsafe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %edi,-0x3c(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x38(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x10(%rax),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x3c(%rbp),%eax
  sub    $0x3,%eax
  mov    %eax,-0x2c(%rbp)
  jmp    L19
L13:
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  subl   $0x1,-0x2c(%rbp)
L19:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L13
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  subsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double cosine_sum_unsafe(double phase, int num_coefs, double *coefs) {
  double c = cos(2 * M_PI * phase);
  double c2 = c + c;
  double bk = coefs[num_coefs - 1];
  double bk1 = coefs[num_coefs - 2] + c2 * bk;
  double temp;
  for (int i = num_coefs - 3; i > 0; i--) {
    temp = bk1;
    bk1 = coefs[i] + c2 * bk1 - bk;
    bk = temp;
  }
  return coefs[0] + c * bk1 - bk;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cosine_sum_unsafe>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movapd %xmm0,%xmm1
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  movapd %xmm0,%xmm5
  addsd  %xmm0,%xmm5
  movslq %ebx,%rax
  shl    $0x3,%rax
  movsd  -0x8(%rbp,%rax,1),%xmm3
  movapd %xmm5,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  -0x10(%rbp,%rax,1),%xmm2
  lea    -0x3(%rbx),%eax
  test   %eax,%eax
  jle    L1
  cltq
L4:
  movapd %xmm5,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  0x0(%rbp,%rax,8),%xmm1
  movapd %xmm2,%xmm4
  movapd %xmm1,%xmm2
  subsd  %xmm3,%xmm2
  sub    $0x1,%rax
  movapd %xmm4,%xmm3
  test   %eax,%eax
  jg     L4
L12:
  mulsd  %xmm2,%xmm0
  addsd  0x0(%rbp),%xmm0
  subsd  %xmm4,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  movapd %xmm3,%xmm4
  jmp    L12
```

assistant: ```c
double cosine_sum_unsafe(double phase, int num_coefs, double *coefs) {
  double c = cos(2 * M_PI * phase);
  double c2 = c + c;
  double bk = coefs[num_coefs - 1];
  double bk1 = coefs[num_coefs - 2] + c2 * bk;
  double temp;
  for (int i = num_coefs - 3; i > 0; i--) {
    temp = bk1;
    bk1 = coefs[i] + c2 * bk1 - bk;
    bk = temp;
  }
  return coefs[0] + c * bk1 - bk;
}
```