ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D1(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <bead_sort@plt>
  nopl   0x0(%rax)
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L10
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D7
type_infered: byte[16]
name: retrieve_data
arguments: label: D1
type_infered: byte[16]

tool: D3: %d


tool: {"D7": [0x05,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D1": [0x04,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int i, x[] = {5, 3, 1, 7, 4, 1, 1, 20};
  int len = sizeof(x) / sizeof(x[0]);
  bead_sort(x, len);
  for (i = 0; i < len; i++)
    printf("%d\n", x[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shr    $0x3,%rax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <test@plt>
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%esi
  mov    D7(%rip),%rax
  mov    %rax,%rdi
  call   <fcyc2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  divsd  -0x20(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double run(int size, int stride, double Mhz) {
  double cycles;
  int elems = size / sizeof(double);
  test(elems, stride);
  cycles = fcyc2(test, elems, stride, 0);
  return (size / stride) / (cycles / Mhz);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  movq   %xmm0,%r14
  movslq %edi,%r12
  shr    $0x3,%r12
  mov    %r12d,%edi
  call   <test@plt>
  mov    $0x0,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    D5(%rip),%rdi
  call   <fcyc2@plt>
  movapd %xmm0,%xmm1
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %r14,%xmm2
  divsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
double run(int size, int stride, double Mhz) {
  double cycles;
  int elems = size / sizeof(double);
  test(elems, stride);
  cycles = fcyc2(test, elems, stride, 0);
  return (size / stride) / (cycles / Mhz);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<run>:
  endbr64
  push   %r12
  movslq %edi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %r12,%rbx
  shr    $0x3,%r12
  mov    %r12d,%edi
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <test@plt>
  mov    D3(%rip),%rdi
  mov    %ebp,%edx
  xor    %ecx,%ecx
  mov    %r12d,%esi
  call   <fcyc2@plt>
  mov    %ebx,%eax
  cltd
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  divsd  0x8(%rsp),%xmm1
  idiv   %ebp
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  cvtsi2sd %eax,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double run(int size, int stride, double Mhz) {
  double cycles;
  int elems = size / sizeof(double);
  test(elems, stride);
  cycles = fcyc2(test, elems, stride, 0);
  return (size / stride) / (cycles / Mhz);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<run>:
  endbr64
  push   %r12
  movslq %edi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %r12,%rbx
  shr    $0x3,%r12
  mov    %r12d,%edi
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <test@plt>
  mov    D9(%rip),%rdi
  mov    %ebp,%edx
  xor    %ecx,%ecx
  mov    %r12d,%esi
  call   <fcyc2@plt>
  mov    %ebx,%eax
  cltd
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  divsd  0x8(%rsp),%xmm1
  idiv   %ebp
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  cvtsi2sd %eax,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double run(int size, int stride, double Mhz) {
  double cycles;
  int elems = size / sizeof(double);
  test(elems, stride);
  cycles = fcyc2(test, elems, stride, 0);
  return (size / stride) / (cycles / Mhz);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mjd_dpm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x10(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rdi
  movq   %rax,%xmm0
  call   <mjd_cal@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x2,%eax
  jne    L24
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isleapyear@plt>
  test   %rax,%rax
  jne    L4
L24:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D7(%rip),%rax
  movzwl (%rdx,%rax,1),%eax
  cwtl
  jmp    L25
L4:
  mov    $0x1d,%eax
L25:
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void mjd_dpm(double mj, int *ndays) {
  static short dpm[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int m, y;
  double d;
  mjd_cal(mj, &m, &d, &y);
  *ndays = (m == 2 && isleapyear(y)) ? 29 : dpm[m - 1];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mjd_dpm>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <mjd_cal@plt>
  cmpl   $0x2,0x8(%rsp)
  je     L24
L18:
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  cltq
  lea    D2(%rip),%rdx
  movswl (%rdx,%rax,2),%eax
L26:
  mov    %eax,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x20,%rsp
  pop    %rbx
  ret
L24:
  mov    0xc(%rsp),%edi
  call   <isleapyear@plt>
  mov    %rax,%rdx
  mov    $0x1d,%eax
  test   %rdx,%rdx
  jne    L26
  jmp    L18
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D2: 

assistant: ```c
void mjd_dpm(double mj, int *ndays) {
  static short dpm[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int m, y;
  double d;
  mjd_cal(mj, &m, &d, &y);
  *ndays = (m == 2 && isleapyear(y)) ? 29 : dpm[m - 1];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mjd_dpm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <mjd_cal@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x2,%eax
  je     L1
L34:
  sub    $0x1,%eax
  lea    D2(%rip),%rdx
  cltq
  movswl (%rdx,%rax,2),%eax
L11:
  mov    %eax,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L1:
  mov    0xc(%rsp),%edi
  call   <isleapyear@plt>
  mov    %rax,%r8
  mov    $0x1d,%eax
  test   %r8,%r8
  jne    L11
  mov    0x8(%rsp),%eax
  jmp    L34
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: 

assistant: ```c
void mjd_dpm(double mj, int *ndays) {
  static short dpm[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int m, y;
  double d;
  mjd_cal(mj, &m, &d, &y);
  *ndays = (m == 2 && isleapyear(y)) ? 29 : dpm[m - 1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mjd_dpm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <mjd_cal@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x2,%eax
  je     L27
L33:
  sub    $0x1,%eax
  lea    D8(%rip),%rdx
  cltq
  movswl (%rdx,%rax,2),%eax
L5:
  mov    %eax,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L27:
  mov    0xc(%rsp),%edi
  call   <isleapyear@plt>
  mov    %rax,%r8
  mov    $0x1d,%eax
  test   %r8,%r8
  jne    L5
  mov    0x8(%rsp),%eax
  jmp    L33
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: D8: 

assistant: ```c
void mjd_dpm(double mj, int *ndays) {
  static short dpm[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int m, y;
  double d;
  mjd_cal(mj, &m, &d, &y);
  *ndays = (m == 2 && isleapyear(y)) ? 29 : dpm[m - 1];
}
```
user: What is the c source code of the assembly code below?

```asm
<sscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsscanf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sscanf(const char *str, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = vsscanf(str, fmt, args);
  va_end(args);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sscanf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsscanf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sscanf(const char *str, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = vsscanf(str, fmt, args);
  va_end(args);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sscanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sscanf(const char *str, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = vsscanf(str, fmt, args);
  va_end(args);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sscanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sscanf(const char *str, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = vsscanf(str, fmt, args);
  va_end(args);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: Error code: %d

assistant: ```c
void error(int n) {
  printf("Error code: %d", n);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string

tool: D9: Error code: %d

assistant: ```c
void error(int n) {
  printf("Error code: %d", n);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error>:
  endbr64
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: Error code: %d

assistant: ```c
void error(int n) {
  printf("Error code: %d", n);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<error>:
  endbr64
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: Error code: %d

assistant: ```c
void error(int n) {
  printf("Error code: %d", n);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L7:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swap_correct@plt>
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0xc(%rbp)
L0:
  cmpl   $0x63,-0xc(%rbp)
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  for (int i = 0; i < 100; i++) {
    uint32_t x = rand();
    uint32_t y = rand();
    assert(swap_correct(x, y));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%ebp
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <swap_correct@plt>
  mov    %eax,%edi
  call   <assert@plt>
  sub    $0x1,%ebp
  jne    L9
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  for (int i = 0; i < 100; i++) {
    uint32_t x = rand();
    uint32_t y = rand();
    assert(swap_correct(x, y));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  nop
L1:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <swap_correct@plt>
  mov    %eax,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  for (int i = 0; i < 100; i++) {
    uint32_t x = rand();
    uint32_t y = rand();
    assert(swap_correct(x, y));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  nop
L8:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <swap_correct@plt>
  mov    %eax,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  for (int i = 0; i < 100; i++) {
    uint32_t x = rand();
    uint32_t y = rand();
    assert(swap_correct(x, y));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<npix2nside64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <isqrt64@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L15
  mov    -0x4(%rbp),%eax
  cltq
  jmp    L8
L15:
  mov    $0xffffffffffffffff,%rax
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: f64

tool: D6: 12

assistant: ```c
long npix2nside64(int64_t npix) {
  int64_t res = isqrt64(npix / 12.);
  return (res * res * 12 == npix) ? (long)res : -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<npix2nside64>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <isqrt64@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  lea    (%rdx,%rdx,2),%edx
  shl    $0x2,%edx
  cmp    %ebx,%edx
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  cltq
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: f64

tool: D8: 12

assistant: ```c
long npix2nside64(int64_t npix) {
  int64_t res = isqrt64(npix / 12.);
  return (res * res * 12 == npix) ? (long)res : -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<npix2nside64>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %rbx
  mov    %edi,%ebx
  cvtsi2sd %edi,%xmm0
  divsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <isqrt64@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  lea    (%rdx,%rdx,2),%edx
  shl    $0x2,%edx
  cmp    %ebx,%edx
  mov    $0xffffffff,%edx
  pop    %rbx
  cmovne %edx,%eax
  cltq
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: f64

tool: D3: 12

assistant: ```c
long npix2nside64(int64_t npix) {
  int64_t res = isqrt64(npix / 12.);
  return (res * res * 12 == npix) ? (long)res : -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<npix2nside64>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %rbx
  mov    %edi,%ebx
  cvtsi2sd %edi,%xmm0
  divsd  D2(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <isqrt64@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  lea    (%rdx,%rdx,2),%edx
  shl    $0x2,%edx
  cmp    %ebx,%edx
  mov    $0xffffffff,%edx
  pop    %rbx
  cmovne %edx,%eax
  cltq
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: f64

tool: D2: 12

assistant: ```c
long npix2nside64(int64_t npix) {
  int64_t res = isqrt64(npix / 12.);
  return (res * res * 12 == npix) ? (long)res : -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pdf_buf_pack_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L10
L18:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L36:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  add    %edx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x30(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x7,-0x14(%rbp)
  jle    L36
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
extern void pdf_buf_pack_1(uint8_t *in, uint8_t *out, size_t in_len) {
  size_t i;
  size_t j = 0;
  for (i = 0; i < in_len; j++) {
    uint8_t k;
    out[j] = 0;
    for (k = 0; k < 8; k++) {
      out[j] <<= 1;
      out[j] += in[i++];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pdf_buf_pack_1>:
  endbr64
  test   %rdx,%rdx
  je     L44
  lea    0x20(%rdi),%r8
  mov    $0x0,%r9d
  jmp    L35
L43:
  add    $0x8,%r9
  add    $0x4,%rsi
  add    $0x20,%r8
  cmp    %r9,%rdx
  jbe    L44
L35:
  mov    %rsi,%rdi
  movl   $0x0,(%rsi)
  lea    -0x20(%r8),%rcx
L27:
  mov    (%rdi),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  add    (%rcx),%eax
  mov    %eax,(%rdi)
  add    $0x4,%rcx
  cmp    %r8,%rcx
  jne    L27
  jmp    L43
L44:
  ret
```

assistant: ```c
extern void pdf_buf_pack_1(uint8_t *in, uint8_t *out, size_t in_len) {
  size_t i;
  size_t j = 0;
  for (i = 0; i < in_len; j++) {
    uint8_t k;
    out[j] = 0;
    for (k = 0; k < 8; k++) {
      out[j] <<= 1;
      out[j] += in[i++];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pdf_buf_pack_1>:
  endbr64
  add    $0x20,%rdi
  xor    %r8d,%r8d
  test   %rdx,%rdx
  je     L9
L15:
  lea    -0x20(%rdi),%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    %eax,%eax
  add    $0x4,%rcx
  mov    %eax,(%rsi)
  add    -0x4(%rcx),%eax
  mov    %eax,(%rsi)
  cmp    %rdi,%rcx
  jne    L22
  add    $0x8,%r8
  add    $0x4,%rsi
  add    $0x20,%rdi
  cmp    %r8,%rdx
  ja     L15
L9:
  ret
```

assistant: ```c
extern void pdf_buf_pack_1(uint8_t *in, uint8_t *out, size_t in_len) {
  size_t i;
  size_t j = 0;
  for (i = 0; i < in_len; j++) {
    uint8_t k;
    out[j] = 0;
    for (k = 0; k < 8; k++) {
      out[j] <<= 1;
      out[j] += in[i++];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gt_cstr_array_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  jmp    L25
L37:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x68,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <gt_free_mem@plt>
L25:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L37
  mov    -0x18(%rbp),%rax
  mov    $0x69,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <gt_free_mem@plt>
  jmp    L36
L12:
  nop
L36:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bioh4x/NeatFreq/refs/heads/master/lib/genometools-1.4.1/src/core/cstr_array.c

assistant: ```c
void gt_cstr_array_delete(char **gt_cstr_array) {
  unsigned long i = 0;
  if (!gt_cstr_array)
    return;
  while (gt_cstr_array[i])
    gt_free_mem(gt_cstr_array[i++], "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bioh4x/NeatFreq/refs/heads/master/lib/genometools-1.4.1/src/core/cstr_array.c", 104);
  gt_free_mem(gt_cstr_array, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bioh4x/NeatFreq/refs/heads/master/lib/genometools-1.4.1/src/core/cstr_array.c", 105);
}
```