ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<aes_mixColumns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    $0x0,%ebx
  jmp    L13
L14:
  movzbl %bl,%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%r15d
  movzbl %bl,%eax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%r13d
  movzbl %bl,%eax
  lea    0x2(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%r12d
  movzbl %bl,%eax
  lea    0x3(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%esi
  mov    %r15d,%eax
  xor    %r13d,%eax
  xor    %r12d,%eax
  mov    %sil,-0x39(%rbp)
  xor    -0x39(%rbp),%al
  mov    %eax,%r14d
  mov    %r15d,%eax
  xor    %r13d,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <rj_xtime@plt>
  xor    %r14d,%eax
  movzbl %al,%edx
  movzbl %bl,%ecx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  xor    %eax,%ecx
  movzbl %bl,%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    %r13d,%eax
  xor    %r12d,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <rj_xtime@plt>
  xor    %r14d,%eax
  movzbl %al,%edx
  movzbl %bl,%eax
  lea    0x1(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  xor    %eax,%ecx
  mov    %ecx,%edx
  movzbl %bl,%eax
  lea    0x1(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    %r12d,%eax
  movzbl -0x39(%rbp),%r13d
  xor    %r13d,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <rj_xtime@plt>
  xor    %r14d,%eax
  movzbl %al,%edx
  movzbl %bl,%eax
  lea    0x2(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  xor    %eax,%ecx
  mov    %ecx,%edx
  movzbl %bl,%eax
  lea    0x2(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    %r13d,%eax
  xor    %r15d,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <rj_xtime@plt>
  xor    %r14d,%eax
  movzbl %al,%edx
  movzbl %bl,%eax
  lea    0x3(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  xor    %eax,%ecx
  mov    %ecx,%edx
  movzbl %bl,%eax
  lea    0x3(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  add    $0x4,%ebx
L13:
  cmp    $0xf,%bl
  jbe    L14
  nop
  nop
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void aes_mixColumns(unsigned char *buf) {
  register unsigned char i, a, b, c, d, e;
  for (i = 0; i < 16; i += 4) {
    a = buf[i];
    b = buf[i + 1];
    c = buf[i + 2];
    d = buf[i + 3];
    e = a ^ b ^ c ^ d;
    buf[i] ^= e ^ rj_xtime(a ^ b);
    buf[i + 1] ^= e ^ rj_xtime(b ^ c);
    buf[i + 2] ^= e ^ rj_xtime(c ^ d);
    buf[i + 3] ^= e ^ rj_xtime(d ^ a);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aes_mixColumns>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  lea    0x10(%rdi),%rax
  mov    %rax,0x8(%rsp)
L6:
  movzbl (%rbx),%ebp
  movzbl 0x1(%rbx),%r12d
  movzbl 0x2(%rbx),%r15d
  movzbl 0x3(%rbx),%eax
  mov    %ebp,%edi
  xor    %r12d,%edi
  mov    %al,0x7(%rsp)
  mov    %eax,%r14d
  xor    %r15d,%r14d
  mov    %edi,%r13d
  xor    %r14d,%r13d
  movzbl %dil,%edi
  call   <rj_xtime@plt>
  xor    (%rbx),%al
  xor    %r13d,%eax
  mov    %al,(%rbx)
  xor    %r15d,%r12d
  movzbl %r12b,%edi
  call   <rj_xtime@plt>
  xor    0x1(%rbx),%al
  xor    %r13d,%eax
  mov    %al,0x1(%rbx)
  movzbl %r14b,%edi
  call   <rj_xtime@plt>
  xor    0x2(%rbx),%al
  xor    %r13d,%eax
  mov    %al,0x2(%rbx)
  xor    0x7(%rsp),%bpl
  movzbl %bpl,%edi
  call   <rj_xtime@plt>
  xor    0x3(%rbx),%al
  xor    %r13d,%eax
  mov    %al,0x3(%rbx)
  add    $0x4,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void aes_mixColumns(unsigned char *buf) {
  register unsigned char i, a, b, c, d, e;
  for (i = 0; i < 16; i += 4) {
    a = buf[i];
    b = buf[i + 1];
    c = buf[i + 2];
    d = buf[i + 3];
    e = a ^ b ^ c ^ d;
    buf[i] ^= e ^ rj_xtime(a ^ b);
    buf[i + 1] ^= e ^ rj_xtime(b ^ c);
    buf[i + 2] ^= e ^ rj_xtime(c ^ d);
    buf[i + 3] ^= e ^ rj_xtime(d ^ a);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<aes_mixColumns>:
  endbr64
  push   %r15
  lea    0x10(%rdi),%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
L4:
  movzbl (%rbx),%ebp
  movzbl 0x2(%rbx),%ecx
  add    $0x4,%rbx
  movzbl -0x3(%rbx),%r14d
  movzbl -0x1(%rbx),%r15d
  mov    %ebp,%edi
  mov    %ecx,%r13d
  mov    %cl,0x7(%rsp)
  xor    %r14d,%edi
  xor    %r15d,%r13d
  xor    %r15d,%ebp
  mov    %edi,%r12d
  movzbl %dil,%edi
  call   <rj_xtime@plt>
  xor    %r13d,%r12d
  xor    -0x4(%rbx),%al
  movzbl 0x7(%rsp),%ecx
  xor    %r12d,%eax
  mov    %al,-0x4(%rbx)
  xor    %ecx,%r14d
  movzbl %r14b,%edi
  call   <rj_xtime@plt>
  xor    -0x3(%rbx),%al
  movzbl %r13b,%edi
  xor    %r12d,%eax
  mov    %al,-0x3(%rbx)
  call   <rj_xtime@plt>
  xor    -0x2(%rbx),%al
  movzbl %bpl,%edi
  xor    %r12d,%eax
  mov    %al,-0x2(%rbx)
  call   <rj_xtime@plt>
  xor    -0x1(%rbx),%al
  xor    %r12d,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rbx,0x8(%rsp)
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void aes_mixColumns(unsigned char *buf) {
  register unsigned char i, a, b, c, d, e;
  for (i = 0; i < 16; i += 4) {
    a = buf[i];
    b = buf[i + 1];
    c = buf[i + 2];
    d = buf[i + 3];
    e = a ^ b ^ c ^ d;
    buf[i] ^= e ^ rj_xtime(a ^ b);
    buf[i + 1] ^= e ^ rj_xtime(b ^ c);
    buf[i + 2] ^= e ^ rj_xtime(c ^ d);
    buf[i + 3] ^= e ^ rj_xtime(d ^ a);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aes_mixColumns>:
  endbr64
  push   %r15
  lea    0x10(%rdi),%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
L4:
  movzbl (%rbx),%ebp
  movzbl 0x2(%rbx),%ecx
  add    $0x4,%rbx
  movzbl -0x3(%rbx),%r14d
  movzbl -0x1(%rbx),%r15d
  mov    %ebp,%edi
  mov    %ecx,%r13d
  mov    %cl,0x7(%rsp)
  xor    %r14d,%edi
  xor    %r15d,%r13d
  xor    %r15d,%ebp
  mov    %edi,%r12d
  movzbl %dil,%edi
  call   <rj_xtime@plt>
  xor    %r13d,%r12d
  xor    -0x4(%rbx),%al
  movzbl 0x7(%rsp),%ecx
  xor    %r12d,%eax
  mov    %al,-0x4(%rbx)
  xor    %ecx,%r14d
  movzbl %r14b,%edi
  call   <rj_xtime@plt>
  xor    -0x3(%rbx),%al
  movzbl %r13b,%edi
  xor    %r12d,%eax
  mov    %al,-0x3(%rbx)
  call   <rj_xtime@plt>
  xor    -0x2(%rbx),%al
  movzbl %bpl,%edi
  xor    %r12d,%eax
  mov    %al,-0x2(%rbx)
  call   <rj_xtime@plt>
  xor    -0x1(%rbx),%al
  xor    %r12d,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rbx,0x8(%rsp)
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void aes_mixColumns(unsigned char *buf) {
  register unsigned char i, a, b, c, d, e;
  for (i = 0; i < 16; i += 4) {
    a = buf[i];
    b = buf[i + 1];
    c = buf[i + 2];
    d = buf[i + 3];
    e = a ^ b ^ c ^ d;
    buf[i] ^= e ^ rj_xtime(a ^ b);
    buf[i + 1] ^= e ^ rj_xtime(b ^ c);
    buf[i + 2] ^= e ^ rj_xtime(c ^ d);
    buf[i + 3] ^= e ^ rj_xtime(d ^ a);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D93(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D93(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L0
L12:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D90(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <print_solution@plt>
  lea    D108(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L0:
  movsd  -0x18(%rbp),%xmm0
  movsd  D93(%rip),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L28
  movsd  D93(%rip),%xmm1
  ucomisd %xmm1,%xmm0
  je     L12
L28:
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D93
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D54
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D90
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D108
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D42
type_infered: string

tool: D93: 1

tool: D29: ----------------------------------------

tool: D54: 
Enter the values a, b and c: 

tool: D90: %lf %lf %lf

tool: D108: Made by Thuan



tool: D20: Try again 0(yes) or 1(no)


tool: D22: %d

tool: D42: ---------------------------------------------


assistant: ```c
int main(void) {
  double a, b, c, d = 1, f = 1;
  while (d == 1) {
    printf("----------------------------------------");
    printf("\nEnter the values a, b and c: ");
    scanf("%lf %lf %lf", &a, &b, &c);
    print_solution(a, b, c);
    printf("Made by Thuan\n\n");
    printf("Try again 0(yes) or 1(no)\n");
    scanf("%d", &d);
  }
  printf("---------------------------------------------\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D61(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D51(%rip),%r13
  lea    D0(%rip),%r12
  lea    D74(%rip),%rbp
  lea    D54(%rip),%rbx
L20:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <print_solution@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  lea    D86(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  D61(%rip),%xmm0
  ucomisd 0x20(%rsp),%xmm0
  jp     L28
  je     L20
L28:
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D61
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D51
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D74
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D54
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D86
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D59
type_infered: string

tool: D61: 1

tool: D51: ----------------------------------------

tool: D0: 
Enter the values a, b and c: 

tool: D74: %lf %lf %lf

tool: D54: Made by Thuan



tool: D25: Try again 0(yes) or 1(no)


tool: D86: %d

tool: D59: ---------------------------------------------


assistant: ```c
int main(void) {
  double a, b, c, d = 1, f = 1;
  while (d == 1) {
    printf("----------------------------------------");
    printf("\nEnter the values a, b and c: ");
    scanf("%lf %lf %lf", &a, &b, &c);
    print_solution(a, b, c);
    printf("Made by Thuan\n\n");
    printf("Try again 0(yes) or 1(no)\n");
    scanf("%d", &d);
  }
  printf("---------------------------------------------\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  lea    D52(%rip),%r15
  push   %r14
  lea    D46(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D66(%rip),%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%r13
  lea    0x20(%rsp),%r12
  mov    D21(%rip),%rax
  lea    0x18(%rsp),%rbp
  mov    %rax,0x30(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L29:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  call   <print_solution@plt>
  lea    D89(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movsd  D21(%rip),%xmm3
  ucomisd 0x30(%rsp),%xmm3
  jp     L9
  je     L29
L9:
  lea    D85(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D52
data_type: string
name: unpack_data
arguments: data_label: D46
data_type: string
name: unpack_data
arguments: data_label: D66
data_type: string
name: unpack_data
arguments: data_label: D21
data_type: f64
name: unpack_data
arguments: data_label: D89
data_type: string
name: unpack_data
arguments: data_label: D57
data_type: string
name: unpack_data
arguments: data_label: D26
data_type: string
name: unpack_data
arguments: data_label: D85
data_type: string

tool: D52: ----------------------------------------

tool: D46: 
Enter the values a, b and c: 

tool: D66: %lf %lf %lf

tool: D21: 1

tool: D89: Made by Thuan



tool: D57: Try again 0(yes) or 1(no)


tool: D26: %d

tool: D85: ---------------------------------------------


assistant: ```c
int main(void) {
  double a, b, c, d = 1, f = 1;
  while (d == 1) {
    printf("----------------------------------------");
    printf("\nEnter the values a, b and c: ");
    scanf("%lf %lf %lf", &a, &b, &c);
    print_solution(a, b, c);
    printf("Made by Thuan\n\n");
    printf("Try again 0(yes) or 1(no)\n");
    scanf("%d", &d);
  }
  printf("---------------------------------------------\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D41(%rip),%r15
  push   %r14
  lea    D57(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D34(%rip),%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%r13
  lea    0x20(%rsp),%r12
  mov    D7(%rip),%rax
  lea    0x18(%rsp),%rbp
  mov    %rax,0x30(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L23:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  call   <print_solution@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D61(%rip),%rdi
  call   <scanf@plt>
  movsd  D7(%rip),%xmm3
  ucomisd 0x30(%rsp),%xmm3
  jp     L29
  je     L23
L29:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D41
datatype: string
name: disassemble_data
arguments: data_label: D57
datatype: string
name: disassemble_data
arguments: data_label: D34
datatype: string
name: disassemble_data
arguments: data_label: D7
datatype: f64
name: disassemble_data
arguments: data_label: D39
datatype: string
name: disassemble_data
arguments: data_label: D24
datatype: string
name: disassemble_data
arguments: data_label: D61
datatype: string
name: disassemble_data
arguments: data_label: D11
datatype: string

tool: D41: ----------------------------------------

tool: D57: 
Enter the values a, b and c: 

tool: D34: %lf %lf %lf

tool: D7: 1

tool: D39: Made by Thuan



tool: D24: Try again 0(yes) or 1(no)


tool: D61: %d

tool: D11: ---------------------------------------------


assistant: ```c
int main(void) {
  double a, b, c, d = 1, f = 1;
  while (d == 1) {
    printf("----------------------------------------");
    printf("\nEnter the values a, b and c: ");
    scanf("%lf %lf %lf", &a, &b, &c);
    print_solution(a, b, c);
    printf("Made by Thuan\n\n");
    printf("Try again 0(yes) or 1(no)\n");
    scanf("%d", &d);
  }
  printf("---------------------------------------------\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<str_count_occurences>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L14
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int str_count_occurences(const char *str, char x) {
  int rv = 0;
  while (*str++) {
    if (*str == x)
      rv++;
  }
  return rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_count_occurences>:
  endbr64
  lea    0x1(%rdi),%rax
  cmpb   $0x0,(%rdi)
  je     L10
  mov    $0x0,%ecx
L23:
  movzbl (%rax),%edx
  cmp    %sil,%dl
  sete   %dil
  movzbl %dil,%edi
  add    %edi,%ecx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L23
L0:
  mov    %ecx,%eax
  ret
L10:
  mov    $0x0,%ecx
  jmp    L0
```

assistant: ```c
int str_count_occurences(const char *str, char x) {
  int rv = 0;
  while (*str++) {
    if (*str == x)
      rv++;
  }
  return rv;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_count_occurences>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L18
L6:
  movzbl (%rax),%edx
  xor    %ecx,%ecx
  cmp    %sil,%dl
  sete   %cl
  add    $0x1,%rax
  add    %ecx,%r8d
  test   %dl,%dl
  jne    L6
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str_count_occurences(const char *str, char x) {
  int rv = 0;
  while (*str++) {
    if (*str == x)
      rv++;
  }
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_count_occurences>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L8
L13:
  movzbl (%rax),%edx
  xor    %ecx,%ecx
  cmp    %sil,%dl
  sete   %cl
  add    $0x1,%rax
  add    %ecx,%r8d
  test   %dl,%dl
  jne    L13
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str_count_occurences(const char *str, char x) {
  int rv = 0;
  while (*str++) {
    if (*str == x)
      rv++;
  }
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<g>:
  endbr64
  push   %rbp
  cmp    $0x4,%edi
  jg     L5
  mov    %esi,%ebp
  cmp    $0x1,%edi
  jle    L8
L0:
  mov    %ebp,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1060 <f@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  test   %edi,%edi
  je     L21
  cmp    $0x1,%edi
  je     L0
L5:
  lea    D23(%rip),%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <abrt@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  lea    D3(%rip),%rdi
  lea    D23(%rip),%rsi
  xor    %eax,%eax
  call   <abrt@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1060 <f@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string

tool: D23: g

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/0x7F800000/gcc/refs/heads/arm-hot-cold/ARMToolChain/source/gcc-5.2.0/gcc/testsuite/gcc.dg/pr33676.c

assistant: ```c
__attribute__((no)) int g(int t, int k) {
  int b;
  switch (t) {
  case 0:
    abrt("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/0x7F800000/gcc/refs/heads/arm-hot-cold/ARMToolChain/source/gcc-5.2.0/gcc/testsuite/gcc.dg/pr33676.c", __FUNCTION__);
  case 1:
    b = f(k);
    break;
  case 2:
    b = f(k);
    break;
  case 3:
    b = f(k);
    break;
  case 4:
    b = f(k);
    break;
  default:
    abrt("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/0x7F800000/gcc/refs/heads/arm-hot-cold/ARMToolChain/source/gcc-5.2.0/gcc/testsuite/gcc.dg/pr33676.c", __FUNCTION__);
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<g>:
  endbr64
  push   %rbp
  cmp    $0x4,%edi
  jg     L13
  mov    %esi,%ebp
  cmp    $0x1,%edi
  jle    L24
L38:
  mov    %ebp,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1060 <f@plt>
  nopl   0x0(%rax,%rax,1)
L24:
  test   %edi,%edi
  je     L9
  cmp    $0x1,%edi
  je     L38
L13:
  lea    D30(%rip),%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <abrt@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D4(%rip),%rdi
  lea    D30(%rip),%rsi
  xor    %eax,%eax
  call   <abrt@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1060 <f@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D30: g

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/0x7F800000/gcc/refs/heads/arm-hot-cold/ARMToolChain/source/gcc-5.2.0/gcc/testsuite/gcc.dg/pr33676.c

assistant: ```c
__attribute__((no)) int g(int t, int k) {
  int b;
  switch (t) {
  case 0:
    abrt("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/0x7F800000/gcc/refs/heads/arm-hot-cold/ARMToolChain/source/gcc-5.2.0/gcc/testsuite/gcc.dg/pr33676.c", __FUNCTION__);
  case 1:
    b = f(k);
    break;
  case 2:
    b = f(k);
    break;
  case 3:
    b = f(k);
    break;
  case 4:
    b = f(k);
    break;
  default:
    abrt("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/0x7F800000/gcc/refs/heads/arm-hot-cold/ARMToolChain/source/gcc-5.2.0/gcc/testsuite/gcc.dg/pr33676.c", __FUNCTION__);
  }
  return b;
}
```