ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L33:
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L27:
  cmpl   $0x2,-0x4(%rbp)
  jle    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L35:
  cmpl   $0x4,-0x8(%rbp)
  jle    L33
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string

tool: D6: %d 

assistant: ```c
void print(int a[][3]) {
  int i, j;
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 3; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x3c(%rdi),%r12
  lea    D9(%rip),%rbp
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0xc,%rbx
  cmp    %rbx,%r12
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: %d 

assistant: ```c
void print(int a[][3]) {
  int i, j;
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 3; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print>:
  endbr64
  push   %r12
  lea    0x3c(%rdi),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0xc,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbx,%r12
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d 

assistant: ```c
void print(int a[][3]) {
  int i, j;
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 3; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print>:
  endbr64
  push   %r12
  lea    0x3c(%rdi),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0xc,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbx,%r12
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string

tool: D1: %d 

assistant: ```c
void print(int a[][3]) {
  int i, j;
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 3; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<recRateUpperBound>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movss  %xmm0,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x30(%rbp),%xmm0
  mulss  -0x34(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L20
L34:
  movl   $0x0,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L47
L37:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L47:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L13
  cmpl   $0x0,-0x14(%rbp)
  jns    L37
L13:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x18(%rbp)
L20:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L34
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *recRateUpperBound(int **hist, int numSubjects, int iterations, float boundingProb) {
  int rank, rr, stopCount, cum;
  int *ub = (int *)malloc(sizeof(int) * (numSubjects + 1));
  assert(ub);
  stopCount = (int)(boundingProb * (float)iterations);
  for (rank = 1; rank <= numSubjects; rank++) {
    cum = 0;
    rr = numSubjects;
    while ((cum < stopCount) && (rr >= 0)) {
      cum = cum + hist[rank][rr];
      rr--;
    }
    ub[rank] = rr + 1;
  }
  return ub;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recRateUpperBound>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%r13d
  movss  %xmm0,0xc(%rsp)
  lea    0x4(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %r13d,%xmm0
  mulss  0xc(%rsp),%xmm0
  test   %ebp,%ebp
  jle    L19
  cvttss2si %xmm0,%edi
  lea    0x4(%rbx),%r9
  lea    -0x1(%rbp),%eax
  lea    0x8(%rbx,%rax,4),%r10
  mov    %rbx,%rax
  neg    %rax
  lea    (%r12,%rax,2),%r13
  lea    -0x1(%rbp),%r12d
  mov    $0x0,%r11d
  jmp    L47
L13:
  mov    0x0(%r13,%r9,2),%r8
  movslq %r12d,%rax
  mov    %r11d,%ecx
L39:
  add    0x4(%r8,%rax,4),%ecx
  mov    %eax,%esi
  cmp    %ecx,%edi
  setg   %r14b
  mov    %eax,%edx
  not    %edx
  shr    $0x1f,%edx
  sub    $0x1,%rax
  test   %dl,%r14b
  jne    L39
L6:
  add    $0x1,%esi
  mov    %esi,(%r9)
  add    $0x4,%r9
  cmp    %r10,%r9
  je     L19
L47:
  mov    %ebp,%esi
  test   %edi,%edi
  jg     L13
  jmp    L6
L19:
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *recRateUpperBound(int **hist, int numSubjects, int iterations, float boundingProb) {
  int rank, rr, stopCount, cum;
  int *ub = (int *)malloc(sizeof(int) * (numSubjects + 1));
  assert(ub);
  stopCount = (int)(boundingProb * (float)iterations);
  for (rank = 1; rank <= numSubjects; rank++) {
    cum = 0;
    rr = numSubjects;
    while ((cum < stopCount) && (rr >= 0)) {
      cum = cum + hist[rank][rr];
      rr--;
    }
    ub[rank] = rr + 1;
  }
  return ub;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<recRateUpperBound>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%r12,4),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <assert@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %r14d,%xmm0
  mulss  0xc(%rsp),%xmm0
  test   %ebx,%ebx
  jle    L45
  lea    -0x1(%rbx),%eax
  movslq %ebx,%r9
  lea    0x4(%r13),%r8
  cvttss2si %xmm0,%esi
  lea    0x8(%r13,%rax,4),%r10
  mov    %r13,%rax
  shl    $0x2,%r9
  neg    %rax
  lea    0x0(%rbp,%rax,2),%r11
  nop
L35:
  mov    %r12d,%edi
  test   %esi,%esi
  jle    L17
  mov    (%r11,%r8,2),%rcx
  mov    %ebx,%eax
  xor    %edx,%edx
  add    %r9,%rcx
  nopw   0x0(%rax,%rax,1)
L32:
  add    (%rcx),%edx
  mov    %eax,%edi
  sub    $0x4,%rcx
  sub    $0x1,%eax
  cmp    %edx,%esi
  jle    L17
  test   %eax,%eax
  jns    L32
L17:
  mov    %edi,(%r8)
  add    $0x4,%r8
  cmp    %r8,%r10
  jne    L35
L45:
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *recRateUpperBound(int **hist, int numSubjects, int iterations, float boundingProb) {
  int rank, rr, stopCount, cum;
  int *ub = (int *)malloc(sizeof(int) * (numSubjects + 1));
  assert(ub);
  stopCount = (int)(boundingProb * (float)iterations);
  for (rank = 1; rank <= numSubjects; rank++) {
    cum = 0;
    rr = numSubjects;
    while ((cum < stopCount) && (rr >= 0)) {
      cum = cum + hist[rank][rr];
      rr--;
    }
    ub[rank] = rr + 1;
  }
  return ub;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<recRateUpperBound>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%r12,4),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <assert@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %r14d,%xmm0
  mulss  0xc(%rsp),%xmm0
  test   %ebx,%ebx
  jle    L17
  lea    -0x1(%rbx),%eax
  movslq %ebx,%r9
  lea    0x4(%r13),%r8
  cvttss2si %xmm0,%esi
  lea    0x8(%r13,%rax,4),%r10
  mov    %r13,%rax
  shl    $0x2,%r9
  neg    %rax
  lea    0x0(%rbp,%rax,2),%r11
  nop
L24:
  mov    %r12d,%edi
  test   %esi,%esi
  jle    L43
  mov    (%r11,%r8,2),%rcx
  mov    %ebx,%eax
  xor    %edx,%edx
  add    %r9,%rcx
  nopw   0x0(%rax,%rax,1)
L49:
  add    (%rcx),%edx
  mov    %eax,%edi
  sub    $0x4,%rcx
  sub    $0x1,%eax
  cmp    %edx,%esi
  jle    L43
  test   %eax,%eax
  jns    L49
L43:
  mov    %edi,(%r8)
  add    $0x4,%r8
  cmp    %r8,%r10
  jne    L24
L17:
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *recRateUpperBound(int **hist, int numSubjects, int iterations, float boundingProb) {
  int rank, rr, stopCount, cum;
  int *ub = (int *)malloc(sizeof(int) * (numSubjects + 1));
  assert(ub);
  stopCount = (int)(boundingProb * (float)iterations);
  for (rank = 1; rank <= numSubjects; rank++) {
    cum = 0;
    rr = numSubjects;
    while ((cum < stopCount) && (rr >= 0)) {
      cum = cum + hist[rank][rr];
      rr--;
    }
    ub[rank] = rr + 1;
  }
  return ub;
}
```
user: What is the c source code of the assembly code below:

```asm
<f_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x1f000(%rsp),%r11
L16:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L16
  sub    $0xc20,%rsp
  mov    %edi,-0x1fc14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1fc14(%rbp),%eax
  cltq
  movzbl -0x1fc10(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int f_test(int x) {
  char arr[127 * 1024];
  return arr[x];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f_test>:
  endbr64
  lea    -0x1f000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0xc18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1fc08(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  movsbl (%rsp,%rdi,1),%eax
  mov    0x1fc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x1fc18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f_test(int x) {
  char arr[127 * 1024];
  return arr[x];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f_test>:
  endbr64
  lea    -0x1f000(%rsp),%r11
L16:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L16
  sub    $0xc18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1fc08(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  movsbl (%rsp,%rdi,1),%eax
  mov    0x1fc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x1fc18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f_test(int x) {
  char arr[127 * 1024];
  return arr[x];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f_test>:
  endbr64
  lea    -0x1f000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0xc18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1fc08(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  movsbl (%rsp,%rdi,1),%eax
  mov    0x1fc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x1fc18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f_test(int x) {
  char arr[127 * 1024];
  return arr[x];
}
```
user: Translate the below assembly code into C programming language:

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L42
L35:
  addq   $0x1,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0xc(%rbp),%edx
  cmp    %dl,%al
  jne    L35
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L15
  mov    -0x8(%rbp),%rax
  jmp    L1
L15:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
L24:
  cmp    %sil,%al
  je     L3
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L24
L3:
  movsbl %al,%eax
  cmp    %esi,%eax
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
  mov    %esi,%edx
  jmp    L36
  nop
L35:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L33
L36:
  cmp    %al,%dl
  jne    L35
  movsbl %sil,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L33:
  xor    %eax,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L25
  mov    %esi,%edx
  jmp    L19
  nop
L33:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L25
L19:
  cmp    %al,%dl
  jne    L33
  movsbl %sil,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L25:
  xor    %eax,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<useXCBProperly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xfd8,%rsp
  mov    %rdi,-0xfd8(%rbp)
  mov    %rsi,-0xfe0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfd0(%rbp)
  jmp    L2
L40:
  mov    -0xfd0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xfd8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rbx
  mov    -0xfd0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xfd8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0xfe0(%rbp),%rax
  mov    %rbx,%rcx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <xcb_intern_atom@plt>
  mov    -0xfd0(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x7f0(%rbp,%rdx,4)
  addl   $0x1,-0xfd0(%rbp)
L2:
  cmpl   $0x1f3,-0xfd0(%rbp)
  jle    L40
  movl   $0x0,-0xfcc(%rbp)
  jmp    L35
L6:
  mov    -0xfcc(%rbp),%eax
  cltq
  mov    -0x7f0(%rbp,%rax,4),%ecx
  mov    -0xfe0(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <xcb_intern_atom_reply@plt>
  mov    %rax,-0xfc8(%rbp)
  cmpq   $0x0,-0xfc8(%rbp)
  je     L48
  mov    -0xfc8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xfcc(%rbp),%eax
  cltq
  mov    %edx,-0xfc0(%rbp,%rax,4)
  mov    -0xfc8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L48:
  addl   $0x1,-0xfcc(%rbp)
L35:
  cmpl   $0x1f3,-0xfcc(%rbp)
  jle    L6
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void useXCBProperly(char **names, xcb_connection_t *connection) {
  xcb_atom_t atoms[500];
  xcb_intern_atom_cookie_t cookies[500];
  for (int i = 0; i < 500; ++i) {
    cookies[i] = xcb_intern_atom(connection, 0, strlen(names[i]), names[i]);
  }
  for (int i = 0; i < 500; ++i) {
    xcb_intern_atom_reply_t *reply = xcb_intern_atom_reply(connection, cookies[i], NULL);
    if (reply) {
      atoms[i] = reply->atom;
      free(reply);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<useXCBProperly>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
L39:
  mov    0x0(%r13,%rbx,8),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rcx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <xcb_intern_atom@plt>
  mov    %eax,(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x1f4,%rbx
  jne    L39
  mov    %rsp,%rbx
  lea    0x7d0(%rsp),%r12
  jmp    L5
L28:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L23
L5:
  mov    $0x0,%edx
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <xcb_intern_atom_reply@plt>
  test   %rax,%rax
  je     L28
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L28
L23:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void useXCBProperly(char **names, xcb_connection_t *connection) {
  xcb_atom_t atoms[500];
  xcb_intern_atom_cookie_t cookies[500];
  for (int i = 0; i < 500; ++i) {
    cookies[i] = xcb_intern_atom(connection, 0, strlen(names[i]), names[i]);
  }
  for (int i = 0; i < 500; ++i) {
    xcb_intern_atom_reply_t *reply = xcb_intern_atom_reply(connection, cookies[i], NULL);
    if (reply) {
      atoms[i] = reply->atom;
      free(reply);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<useXCBProperly>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L14:
  mov    0x0(%r13,%rbp,8),%r14
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rcx
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <xcb_intern_atom@plt>
  mov    %eax,(%rbx,%rbp,4)
  add    $0x1,%rbp
  cmp    $0x1f4,%rbp
  jne    L14
  lea    0x7d0(%rsp),%rbp
  nopl   0x0(%rax)
L35:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %edx,%edx
  call   <xcb_intern_atom_reply@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L17
  call   <free@plt>
L17:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L35
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void useXCBProperly(char **names, xcb_connection_t *connection) {
  xcb_atom_t atoms[500];
  xcb_intern_atom_cookie_t cookies[500];
  for (int i = 0; i < 500; ++i) {
    cookies[i] = xcb_intern_atom(connection, 0, strlen(names[i]), names[i]);
  }
  for (int i = 0; i < 500; ++i) {
    xcb_intern_atom_reply_t *reply = xcb_intern_atom_reply(connection, cookies[i], NULL);
    if (reply) {
      atoms[i] = reply->atom;
      free(reply);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<useXCBProperly>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L13:
  mov    0x0(%r13,%rbp,8),%r14
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rcx
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <xcb_intern_atom@plt>
  mov    %eax,(%rbx,%rbp,4)
  add    $0x1,%rbp
  cmp    $0x1f4,%rbp
  jne    L13
  lea    0x7d0(%rsp),%rbp
  nopl   0x0(%rax)
L14:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %edx,%edx
  call   <xcb_intern_atom_reply@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L0
  call   <free@plt>
L0:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L14
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void useXCBProperly(char **names, xcb_connection_t *connection) {
  xcb_atom_t atoms[500];
  xcb_intern_atom_cookie_t cookies[500];
  for (int i = 0; i < 500; ++i) {
    cookies[i] = xcb_intern_atom(connection, 0, strlen(names[i]), names[i]);
  }
  for (int i = 0; i < 500; ++i) {
    xcb_intern_atom_reply_t *reply = xcb_intern_atom_reply(connection, cookies[i], NULL);
    if (reply) {
      atoms[i] = reply->atom;
      free(reply);
    }
  }
}
```