ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<findfirstline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %ecx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L3
  mov    %r14d,%r9d
  mov    0x4(%rsp),%r8d
  mov    $0x0,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <__findline@plt>
  mov    %eax,%ebx
L30:
  test   %ebx,%ebx
  jle    L47
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  mov    $0x0,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <__findline@plt>
  cmp    $0xffffffff,%eax
  je     L47
  mov    %eax,%ebx
  jmp    L30
L3:
  mov    $0xffffffff,%ebx
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t findfirstline(int fd, int (*comp)(const char *, void *), void *param, int maxlen) {
  struct stat state;
  ssize_t pos;
  if (fstat(fd, &state))
    return -1;
  ssize_t init_pos = __findline(fd, comp, param, 0, state.st_size, maxlen);
  while (init_pos > 0) {
    pos = __findline(fd, comp, param, 0, init_pos, maxlen);
    if (pos == -1)
      break;
    init_pos = pos;
  }
  return init_pos;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findfirstline>:
  endbr64
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L1
  mov    0x4(%rsp),%r8d
  mov    %r13d,%r9d
  xor    %ecx,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <__findline@plt>
  mov    %eax,%r14d
  jmp    L46
  cs nopw 0x0(%rax,%rax,1)
L35:
  xor    %ecx,%ecx
  mov    %r13d,%r9d
  mov    %r14d,%r8d
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <__findline@plt>
  cmp    $0xffffffff,%eax
  je     L47
  mov    %eax,%r14d
L46:
  test   %r14d,%r14d
  jg     L35
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x10,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  mov    $0xffffffff,%r14d
  jmp    L47
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t findfirstline(int fd, int (*comp)(const char *, void *), void *param, int maxlen) {
  struct stat state;
  ssize_t pos;
  if (fstat(fd, &state))
    return -1;
  ssize_t init_pos = __findline(fd, comp, param, 0, state.st_size, maxlen);
  while (init_pos > 0) {
    pos = __findline(fd, comp, param, 0, init_pos, maxlen);
    if (pos == -1)
      break;
    init_pos = pos;
  }
  return init_pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findfirstline>:
  endbr64
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L6
  mov    0x4(%rsp),%r8d
  mov    %r13d,%r9d
  xor    %ecx,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <__findline@plt>
  mov    %eax,%r14d
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L15:
  xor    %ecx,%ecx
  mov    %r13d,%r9d
  mov    %r14d,%r8d
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <__findline@plt>
  cmp    $0xffffffff,%eax
  je     L40
  mov    %eax,%r14d
L5:
  test   %r14d,%r14d
  jg     L15
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x10,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    $0xffffffff,%r14d
  jmp    L40
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t findfirstline(int fd, int (*comp)(const char *, void *), void *param, int maxlen) {
  struct stat state;
  ssize_t pos;
  if (fstat(fd, &state))
    return -1;
  ssize_t init_pos = __findline(fd, comp, param, 0, state.st_size, maxlen);
  while (init_pos > 0) {
    pos = __findline(fd, comp, param, 0, init_pos, maxlen);
    if (pos == -1)
      break;
    init_pos = pos;
  }
  return init_pos;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L16
L10:
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0xc(%rbp)
  jg     L10
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  int z = __VERIFIER_nondet_int();
  while (x > 0) {
    x = x + y;
    y = y + z;
    z--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L18
L13:
  add    %ebp,%ebx
  add    %eax,%ebp
  sub    $0x1,%eax
  test   %ebx,%ebx
  jg     L13
L18:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  int z = __VERIFIER_nondet_int();
  while (x > 0) {
    x = x + y;
    y = y + z;
    z--;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  int z = __VERIFIER_nondet_int();
  while (x > 0) {
    x = x + y;
    y = y + z;
    z--;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gbk_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <prepare_data@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <ol_lrc_new@plt>
  mov    %rax,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <ol_lrc_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_free@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D10: /tmp/lrc_basic.lrc

tool: D1: /tmp/lrc_gbk.lrc

assistant: ```c
void gbk_test() {
  prepare_data();
  struct OlLrc *lrc = ol_lrc_new("/tmp/"
                                 "lrc_basic.lrc");
  struct OlLrc *gbklrc = ol_lrc_new("/tmp/"
                                    "lrc_gbk.lrc");
  ol_lrc_free(lrc);
  ol_lrc_free(gbklrc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gbk_test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <prepare_data@plt>
  lea    D5(%rip),%rdi
  call   <ol_lrc_new@plt>
  mov    %rax,%rbp
  lea    D3(%rip),%rdi
  call   <ol_lrc_new@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <ol_lrc_free@plt>
  mov    %rbx,%rdi
  call   <ol_lrc_free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string

tool: D5: /tmp/lrc_basic.lrc

tool: D3: /tmp/lrc_gbk.lrc

assistant: ```c
void gbk_test() {
  prepare_data();
  struct OlLrc *lrc = ol_lrc_new("/tmp/"
                                 "lrc_basic.lrc");
  struct OlLrc *gbklrc = ol_lrc_new("/tmp/"
                                    "lrc_gbk.lrc");
  ol_lrc_free(lrc);
  ol_lrc_free(gbklrc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gbk_test>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <prepare_data@plt>
  lea    D5(%rip),%rdi
  call   <ol_lrc_new@plt>
  lea    D18(%rip),%rdi
  mov    %rax,%r12
  call   <ol_lrc_new@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <ol_lrc_free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <ol_lrc_free@plt>
```

tool_calls: name: read_data
arguments: label: D5
data_type: string
name: read_data
arguments: label: D18
data_type: string

tool: D5: /tmp/lrc_basic.lrc

tool: D18: /tmp/lrc_gbk.lrc

assistant: ```c
void gbk_test() {
  prepare_data();
  struct OlLrc *lrc = ol_lrc_new("/tmp/"
                                 "lrc_basic.lrc");
  struct OlLrc *gbklrc = ol_lrc_new("/tmp/"
                                    "lrc_gbk.lrc");
  ol_lrc_free(lrc);
  ol_lrc_free(gbklrc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gbk_test>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <prepare_data@plt>
  lea    D11(%rip),%rdi
  call   <ol_lrc_new@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%r12
  call   <ol_lrc_new@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <ol_lrc_free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <ol_lrc_free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D11: /tmp/lrc_basic.lrc

tool: D6: /tmp/lrc_gbk.lrc

assistant: ```c
void gbk_test() {
  prepare_data();
  struct OlLrc *lrc = ol_lrc_new("/tmp/"
                                 "lrc_basic.lrc");
  struct OlLrc *gbklrc = ol_lrc_new("/tmp/"
                                    "lrc_gbk.lrc");
  ol_lrc_free(lrc);
  ol_lrc_free(gbklrc);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__console_tx_nibble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x39,-0x1(%rbp)
  jbe    L8
  addb   $0x27,-0x1(%rbp)
L8:
  movzbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <__console_tx_byte@plt>
  nop
  leave
  ret
```

assistant: ```c
void __console_tx_nibble(unsigned nibble) {
  unsigned char digit;
  digit = nibble + '0';
  if (digit > '9') {
    digit += 39;
  }
  __console_tx_byte(digit);
}
```
user: What is the c source code of the assembly code below?

```asm
<__console_tx_nibble>:
  endbr64
  sub    $0x8,%rsp
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x39,%al
  cmova  %edi,%eax
  movzbl %al,%edi
  call   <__console_tx_byte@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __console_tx_nibble(unsigned nibble) {
  unsigned char digit;
  digit = nibble + '0';
  if (digit > '9') {
    digit += 39;
  }
  __console_tx_byte(digit);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__console_tx_nibble>:
  endbr64
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x39,%al
  cmova  %edi,%eax
  movzbl %al,%edi
  jmp    1050 <__console_tx_byte@plt>
```

assistant: ```c
void __console_tx_nibble(unsigned nibble) {
  unsigned char digit;
  digit = nibble + '0';
  if (digit > '9') {
    digit += 39;
  }
  __console_tx_byte(digit);
}
```
user: What is the c source code of the assembly code below?

```asm
<__console_tx_nibble>:
  endbr64
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x39,%al
  cmova  %edi,%eax
  movzbl %al,%edi
  jmp    1050 <__console_tx_byte@plt>
```

assistant: ```c
void __console_tx_nibble(unsigned nibble) {
  unsigned char digit;
  digit = nibble + '0';
  if (digit > '9') {
    digit += 39;
  }
  __console_tx_byte(digit);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<psvec4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  movss  %xmm1,-0x10(%rbp)
  movss  %xmm2,-0x14(%rbp)
  movss  %xmm3,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <vec4@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4 *psvec4(struct vec4 *result, float x, float y, float z, float w) {
  vec4((float *)result, x, y, z, w);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<psvec4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec4@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4 *psvec4(struct vec4 *result, float x, float y, float z, float w) {
  vec4((float *)result, x, y, z, w);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<psvec4>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec4@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4 *psvec4(struct vec4 *result, float x, float y, float z, float w) {
  vec4((float *)result, x, y, z, w);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<psvec4>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec4@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4 *psvec4(struct vec4 *result, float x, float y, float z, float w) {
  vec4((float *)result, x, y, z, w);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ledge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <niceprint@plt>
  mov    $0x6,%edi
  call   <d@plt>
  mov    %eax,%ebx
  mov    $0x6,%edi
  call   <d@plt>
  lea    (%rbx,%rax,1),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
datatype: string
name: read_data
arguments: data_label: D1
datatype: string

tool: D19: The characters must walk along an 18"-wide ledge that skirts a ravine. The party's travel pace for the day is slowed by half, and each character must succeed on a DC 10 Dexterity saving throw to avoid a fall. Precautions such as roping everyone together let each character make the save with advantage. Increase the pursuit leve of the drow by 1.



tool: D1: Ravine Depth: %d feet



assistant: ```c
void ledge(void) {
  niceprint("The characters must walk along an 18\"-wide ledge that skirts a ravine. "
            "The party's travel pace for the day is slowed by half, "
            "and each character must succeed on a DC 10 Dexterity saving throw to "
            "avoid a fall. Precautions such as roping everyone together let each "
            "character make the save with advantage. Increase the pursuit leve of the "
            "drow by 1.\n\n");
  printf("Ravine Depth: %d feet\n\n", 10 * (d(6) + d(6)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ledge>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rdi
  call   <niceprint@plt>
  mov    $0x6,%edi
  call   <d@plt>
  mov    %eax,%ebx
  mov    $0x6,%edi
  call   <d@plt>
  add    %ebx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string
name: disassemble_data
arguments: tag: D9
datatype: string

tool: D8: The characters must walk along an 18"-wide ledge that skirts a ravine. The party's travel pace for the day is slowed by half, and each character must succeed on a DC 10 Dexterity saving throw to avoid a fall. Precautions such as roping everyone together let each character make the save with advantage. Increase the pursuit leve of the drow by 1.



tool: D9: Ravine Depth: %d feet



assistant: ```c
void ledge(void) {
  niceprint("The characters must walk along an 18\"-wide ledge that skirts a ravine. "
            "The party's travel pace for the day is slowed by half, "
            "and each character must succeed on a DC 10 Dexterity saving throw to "
            "avoid a fall. Precautions such as roping everyone together let each "
            "character make the save with advantage. Increase the pursuit leve of the "
            "drow by 1.\n\n");
  printf("Ravine Depth: %d feet\n\n", 10 * (d(6) + d(6)));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ledge>:
  endbr64
  push   %rbx
  lea    D17(%rip),%rdi
  call   <niceprint@plt>
  mov    $0x6,%edi
  call   <d@plt>
  mov    $0x6,%edi
  mov    %eax,%ebx
  call   <d@plt>
  lea    D6(%rip),%rdi
  add    %ebx,%eax
  pop    %rbx
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  jmp    1080 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type: string
name: unpack_data
arguments: data_label: D6
type: string

tool: D17: The characters must walk along an 18"-wide ledge that skirts a ravine. The party's travel pace for the day is slowed by half, and each character must succeed on a DC 10 Dexterity saving throw to avoid a fall. Precautions such as roping everyone together let each character make the save with advantage. Increase the pursuit leve of the drow by 1.



tool: D6: Ravine Depth: %d feet



assistant: ```c
void ledge(void) {
  niceprint("The characters must walk along an 18\"-wide ledge that skirts a ravine. "
            "The party's travel pace for the day is slowed by half, "
            "and each character must succeed on a DC 10 Dexterity saving throw to "
            "avoid a fall. Precautions such as roping everyone together let each "
            "character make the save with advantage. Increase the pursuit leve of the "
            "drow by 1.\n\n");
  printf("Ravine Depth: %d feet\n\n", 10 * (d(6) + d(6)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ledge>:
  endbr64
  push   %rbx
  lea    D15(%rip),%rdi
  call   <niceprint@plt>
  mov    $0x6,%edi
  call   <d@plt>
  mov    $0x6,%edi
  mov    %eax,%ebx
  call   <d@plt>
  lea    D1(%rip),%rdi
  add    %ebx,%eax
  pop    %rbx
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  jmp    1080 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D15: The characters must walk along an 18"-wide ledge that skirts a ravine. The party's travel pace for the day is slowed by half, and each character must succeed on a DC 10 Dexterity saving throw to avoid a fall. Precautions such as roping everyone together let each character make the save with advantage. Increase the pursuit leve of the drow by 1.



tool: D1: Ravine Depth: %d feet



assistant: ```c
void ledge(void) {
  niceprint("The characters must walk along an 18\"-wide ledge that skirts a ravine. "
            "The party's travel pace for the day is slowed by half, "
            "and each character must succeed on a DC 10 Dexterity saving throw to "
            "avoid a fall. Precautions such as roping everyone together let each "
            "character make the save with advantage. Increase the pursuit leve of the "
            "drow by 1.\n\n");
  printf("Ravine Depth: %d feet\n\n", 10 * (d(6) + d(6)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L40
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L50
L29:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  cmp    $0x1,%eax
  jne    L17
  addl   $0x1,-0xc(%rbp)
L17:
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L38
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  jmp    L64
L38:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    $0x1,%eax
L64:
  cmp    -0x4(%rbp),%eax
  jg     L29
  addl   $0x1,-0x8(%rbp)
L40:
  cmpl   $0x2ee0,-0x8(%rbp)
  jle    L16
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  int count = 0;
  for (int d = 2; d <= 12000; d++) {
    for (int n = d / 3 + 1; n < (d % 2 == 0 ? d / 2 : d / 2 + 1); n++) {
      if (gcd(d, n) == 1) {
        count++;
      }
    }
  }
  printf("%d\n", count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2,%r13d
  mov    $0x0,%r12d
  jmp    L23
L10:
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <gcd@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  add    $0x1,%ebx
L28:
  cmp    %ebp,%ebx
  jl     L10
  add    $0x1,%r13d
  cmp    $0x2ee1,%r13d
  je     L12
L23:
  movslq %r13d,%rbx
  imul   $0x55555556,%rbx,%rbx
  shr    $0x20,%rbx
  mov    %r13d,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  add    $0x1,%ebx
  mov    %r13d,%ebp
  shr    $0x1f,%ebp
  add    %r13d,%ebp
  sar    %ebp
  lea    0x1(%rbp),%eax
  test   $0x1,%r13b
  cmovne %eax,%ebp
  jmp    L28
L12:
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: %d


assistant: ```c
int main() {
  int count = 0;
  for (int d = 2; d <= 12000; d++) {
    for (int n = d / 3 + 1; n < (d % 2 == 0 ? d / 2 : d / 2 + 1); n++) {
      if (gcd(d, n) == 1) {
        count++;
      }
    }
  }
  printf("%d\n", count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x2,%r14d
  push   %r13
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r14d,%ebx
  mov    %r14d,%r13d
  imul   %r12,%rbx
  sar    %r13d
  lea    0x1(%r13),%eax
  shr    $0x21,%rbx
  add    $0x1,%ebx
  test   $0x1,%r14b
  cmovne %eax,%r13d
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <gcd@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
L13:
  cmp    %r13d,%ebx
  jl     L20
  add    $0x1,%r14d
  cmp    $0x2ee1,%r14d
  jne    L12
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string

tool: D0: %d


assistant: ```c
int main() {
  int count = 0;
  for (int d = 2; d <= 12000; d++) {
    for (int n = d / 3 + 1; n < (d % 2 == 0 ? d / 2 : d / 2 + 1); n++) {
      if (gcd(d, n) == 1) {
        count++;
      }
    }
  }
  printf("%d\n", count);
}
```