ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<IVisortDown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L17
L24:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L31
L15:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L31:
  cmpl   $0x0,-0x8(%rbp)
  jle    L38
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L15
L38:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L24
  nop
  pop    %rbp
  ret
```

assistant: ```c
void IVisortDown(int n, int ivec[]) {
  int i, itemp, j;
  for (i = 1; i < n; i++) {
    for (j = i; j > 0 && ivec[j - 1] < ivec[j]; j--) {
      {
        itemp = ivec[(j - 1)];
        ivec[(j - 1)] = ivec[(j)];
        ivec[(j)] = itemp;
      };
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<IVisortDown>:
  endbr64
  cmp    $0x1,%edi
  jle    L52
  lea    0x4(%rsi),%r9
  mov    $0x1,%r8d
  jmp    L5
L12:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%edi
  je     L52
L5:
  test   %r8d,%r8d
  jle    L12
  mov    %r9,%rax
L40:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jge    L12
  mov    %edx,-0x4(%rax)
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L40
  jmp    L12
L52:
  ret
```

assistant: ```c
void IVisortDown(int n, int ivec[]) {
  int i, itemp, j;
  for (i = 1; i < n; i++) {
    for (j = i; j > 0 && ivec[j - 1] < ivec[j]; j--) {
      {
        itemp = ivec[(j - 1)];
        ivec[(j - 1)] = ivec[(j)];
        ivec[(j)] = itemp;
      };
    }
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<IVisortDown>:
  endbr64
  lea    0x4(%rsi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jle    L18
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L7:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jge    L38
  mov    %edx,-0x4(%rax)
  sub    $0x4,%rax
  mov    %ecx,0x4(%rax)
  cmp    %rsi,%rax
  jne    L7
L38:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%edi
  jne    L39
  ret
L18:
  ret
```

assistant: ```c
void IVisortDown(int n, int ivec[]) {
  int i, itemp, j;
  for (i = 1; i < n; i++) {
    for (j = i; j > 0 && ivec[j - 1] < ivec[j]; j--) {
      {
        itemp = ivec[(j - 1)];
        ivec[(j - 1)] = ivec[(j)];
        ivec[(j)] = itemp;
      };
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<IVisortDown>:
  endbr64
  lea    0x4(%rsi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jle    L33
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r9,%rdx
  nopl   0x0(%rax,%rax,1)
L25:
  movq   -0x4(%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jge    L38
  movq   %xmm1,-0x4(%rdx)
  sub    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L25
L38:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%edi
  jne    L19
  ret
L33:
  ret
```

assistant: ```c
void IVisortDown(int n, int ivec[]) {
  int i, itemp, j;
  for (i = 1; i < n; i++) {
    for (j = i; j > 0 && ivec[j - 1] < ivec[j]; j--) {
      {
        itemp = ivec[(j - 1)];
        ivec[(j - 1)] = ivec[(j)];
        ivec[(j)] = itemp;
      };
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L50
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L50
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L40
L79:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L40:
  cmpl   $0x0,-0x4(%rbp)
  je     L68
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L79
L68:
  movl   $0x0,-0x4(%rbp)
  jmp    L64
L56:
  addl   $0x1,-0x4(%rbp)
L64:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L56
  cmpl   $0x0,-0x4(%rbp)
  je     L50
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L50:
  nop
  leave
  ret
```

assistant: ```c
void Trim(char *pszString) {
  if (pszString && *pszString) {
    int iIndex = strlen(pszString) - 1;
    while (iIndex && isspace(pszString[iIndex]))
      pszString[iIndex--] = '\0';
    iIndex = 0;
    while (isspace(pszString[iIndex]))
      iIndex++;
    if (iIndex)
      strcpy(pszString, &pszString[iIndex]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Trim>:
  endbr64
  test   %rdi,%rdi
  je     L53
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  cmpb   $0x0,(%rdi)
  jne    L45
L68:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  je     L22
  movslq %ebx,%rbx
  add    %rbp,%rbx
  movslq %eax,%rdx
  lea    -0x2(%rbp,%rdx,1),%r12
  lea    -0x2(%rax),%eax
  sub    %rax,%r12
L50:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L22
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L50
L22:
  mov    %rbp,%rbx
  mov    $0x0,%r12d
L14:
  mov    %rbx,%r13
  movsbl (%rbx),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  je     L49
  add    $0x1,%r12d
  jmp    L14
L49:
  test   %r12d,%r12d
  je     L68
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L68
L53:
  ret
```

assistant: ```c
void Trim(char *pszString) {
  if (pszString && *pszString) {
    int iIndex = strlen(pszString) - 1;
    while (iIndex && isspace(pszString[iIndex]))
      pszString[iIndex--] = '\0';
    iIndex = 0;
    while (isspace(pszString[iIndex]))
      iIndex++;
    if (iIndex)
      strcpy(pszString, &pszString[iIndex]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Trim>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L8
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  je     L80
  movslq %eax,%rdx
  movslq %ebx,%rbx
  sub    $0x2,%eax
  lea    -0x2(%rbp,%rdx,1),%r12
  add    %rbp,%rbx
  sub    %rax,%r12
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L33:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  je     L80
L47:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L33
L80:
  mov    %rbp,%rbx
  xor    %r12d,%r12d
  jmp    L89
  nopl   0x0(%rax)
L88:
  add    $0x1,%r12d
L89:
  movsbl (%rbx),%edi
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L88
  test   %r12d,%r12d
  je     L62
  add    $0x8,%rsp
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
L39:
  ret
```

assistant: ```c
void Trim(char *pszString) {
  if (pszString && *pszString) {
    int iIndex = strlen(pszString) - 1;
    while (iIndex && isspace(pszString[iIndex]))
      pszString[iIndex--] = '\0';
    iIndex = 0;
    while (isspace(pszString[iIndex]))
      iIndex++;
    if (iIndex)
      strcpy(pszString, &pszString[iIndex]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Trim>:
  endbr64
  test   %rdi,%rdi
  je     L80
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L11
L88:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  je     L72
  movslq %eax,%rdx
  movslq %ebx,%rbx
  sub    $0x2,%eax
  lea    -0x2(%rbp,%rdx,1),%r12
  add    %rbp,%rbx
  sub    %rax,%r12
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L25:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  je     L72
L6:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L25
L72:
  mov    %rbp,%rbx
  xor    %r12d,%r12d
  jmp    L1
  nopl   0x0(%rax)
L69:
  add    $0x1,%r12d
L1:
  movsbl (%rbx),%edi
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L69
  test   %r12d,%r12d
  je     L88
  add    $0x8,%rsp
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
L80:
  ret
```

assistant: ```c
void Trim(char *pszString) {
  if (pszString && *pszString) {
    int iIndex = strlen(pszString) - 1;
    while (iIndex && isspace(pszString[iIndex]))
      pszString[iIndex--] = '\0';
    iIndex = 0;
    while (isspace(pszString[iIndex]))
      iIndex++;
    if (iIndex)
      strcpy(pszString, &pszString[iIndex]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6b696c206d616441,%rax
  movabs $0x2e73676f64207365,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x8,-0x24(%rbp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    %rax,(%rcx)
  mov    %rdx,0x8(%rcx)
  movzbl -0x20(%rbp),%eax
  movsbq %al,%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L1
L16:
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L1:
  cmpl   $0x2,-0x44(%rbp)
  jle    L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D10: Rick

tool: D0: %i


assistant: ```c
int main() {
  char myString[] = "Adam likes dogs.";
  char *name = "Rick";
  int nums[] = {1, 6, 3, 8};
  int *newNums = malloc(sizeof(int) * 4);
  memcpy(newNums, nums, sizeof(int) * 4);
  memcpy(myString[0], name, sizeof(char) * 4);
  printf("%s\n", myString);
  for (int i = 0; i < 3; i++)
    printf("%i\n", newNums[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6b696c206d616441,%rax
  movabs $0x2e73676f64207365,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movb   $0x0,0x10(%rsp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movabs $0x600000001,%rax
  movabs $0x800000003,%rdx
  mov    %rax,(%rbx)
  mov    %rdx,0x8(%rbx)
  movl   $0x6b636952,0x41
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    (%rbx),%esi
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string

tool: D3: %i


assistant: ```c
int main() {
  char myString[] = "Adam likes dogs.";
  char *name = "Rick";
  int nums[] = {1, 6, 3, 8};
  int *newNums = malloc(sizeof(int) * 4);
  memcpy(newNums, nums, sizeof(int) * 4);
  memcpy(myString[0], name, sizeof(char) * 4);
  printf("%s\n", myString);
  for (int i = 0; i < 3; i++)
    printf("%i\n", newNums[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x10,%edi
  lea    D25(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  movdqa D6(%rip),%xmm0
  mov    %rsp,%rdi
  mov    %rax,%rbx
  movups %xmm0,(%rax)
  movl   $0x6b636952,0x41
  call   <puts@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: byte[16]

tool: D25: %i


tool: {"D4": [0x41,0x64,0x61,0x6d,0x20,0x6c,0x69,0x6b,0x65,0x73,0x20,0x64,0x6f,0x67,0x73,0x2e]}

tool: {"D6": [0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main() {
  char myString[] = "Adam likes dogs.";
  char *name = "Rick";
  int nums[] = {1, 6, 3, 8};
  int *newNums = malloc(sizeof(int) * 4);
  memcpy(newNums, nums, sizeof(int) * 4);
  memcpy(myString[0], name, sizeof(char) * 4);
  printf("%s\n", myString);
  for (int i = 0; i < 3; i++)
    printf("%i\n", newNums[i]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x10,%edi
  lea    D22(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  movdqa D29(%rip),%xmm0
  mov    %rsp,%rdi
  mov    %rax,%rbx
  movups %xmm0,(%rax)
  movl   $0x6b636952,0x41
  call   <puts@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
data_type: string
name: read_data
arguments: data_label: D11
data_type: byte[16]
name: read_data
arguments: data_label: D29
data_type: byte[16]

tool: D22: %i


tool: {"D11": [0x41,0x64,0x61,0x6d,0x20,0x6c,0x69,0x6b,0x65,0x73,0x20,0x64,0x6f,0x67,0x73,0x2e]}

tool: {"D29": [0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main() {
  char myString[] = "Adam likes dogs.";
  char *name = "Rick";
  int nums[] = {1, 6, 3, 8};
  int *newNums = malloc(sizeof(int) * 4);
  memcpy(newNums, nums, sizeof(int) * 4);
  memcpy(myString[0], name, sizeof(char) * 4);
  printf("%s\n", myString);
  for (int i = 0; i < 3; i++)
    printf("%i\n", newNums[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_reboot_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <pm_reboot@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int _reboot_handler(int argc, char **argv) {
  (void)argc;
  (void)argv;
  pm_reboot();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_reboot_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <pm_reboot@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _reboot_handler(int argc, char **argv) {
  (void)argc;
  (void)argv;
  pm_reboot();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_reboot_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pm_reboot@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _reboot_handler(int argc, char **argv) {
  (void)argc;
  (void)argv;
  pm_reboot();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_reboot_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pm_reboot@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _reboot_handler(int argc, char **argv) {
  (void)argc;
  (void)argv;
  pm_reboot();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jne    L77
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x30(%rbp)
  jmp    L77
L78:
  mov    -0x38(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%ecx
  movslq %edx,%rax
  mov    %ecx,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x38(%rbp)
L77:
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jg     L78
  movl   $0x0,-0x34(%rbp)
  jmp    L60
L88:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L11
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jle    L59
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L11
L59:
  mov    -0x34(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  addl   $0x1,-0x34(%rbp)
L60:
  cmpl   $0x9,-0x34(%rbp)
  jle    L88
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D18
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D0: %d

tool: D18: Digit %d --> %d times


tool: D2: Digit %d --> %d time


assistant: ```c
int main() {
  int number, i, digits[10] = {0};
  scanf("%d", &number);
  if (number == 0)
    digits[0]++;
  while (number > 0) {
    digits[number % 10]++;
    number /= 10;
  }
  for (i = 0; i < 10; i++) {
    if (digits[i] != 0) {
      digits[i] > 1 ? printf("Digit %d --> %d times\n", i, digits[i]) : printf("Digit %d --> %d time\n", i, 1);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  je     L28
  jle    L5
L16:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %edx,%eax
  mov    %esi,%edx
  cmp    $0x9,%eax
  jg     L16
  mov    %esi,0xc(%rsp)
L5:
  mov    $0x0,%ebx
  lea    D10(%rip),%r12
  lea    D1(%rip),%rbp
  jmp    L58
L30:
  mov    $0x1,%edx
  mov    %r12,%rdi
  call   <printf@plt>
L57:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  je     L20
L58:
  mov    %ebx,%esi
  mov    0x10(%rsp,%rbx,4),%edx
  test   %edx,%edx
  je     L57
  cmp    $0x1,%edx
  jle    L30
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L57
L20:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  movl   $0x1,0x10(%rsp)
  jmp    L5
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string

tool: D15: %d

tool: D10: Digit %d --> %d time


tool: D1: Digit %d --> %d times


assistant: ```c
int main() {
  int number, i, digits[10] = {0};
  scanf("%d", &number);
  if (number == 0)
    digits[0]++;
  while (number > 0) {
    digits[number % 10]++;
    number /= 10;
  }
  for (i = 0; i < 10; i++) {
    if (digits[i] != 0) {
      digits[i] > 1 ? printf("Digit %d --> %d times\n", i, digits[i]) : printf("Digit %d --> %d time\n", i, 1);
    }
  }
  return 0;
}
```