user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L125:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L125
  sub    $0xe00,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9df0(%rbp),%rdx
  lea    -0x9df4(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x9dec(%rbp)
  jmp    L86
L111:
  mov    -0x9dec(%rbp),%eax
  cltq
  movl   $0x0,-0x9de0(%rbp,%rax,4)
  addl   $0x1,-0x9dec(%rbp)
L86:
  mov    -0x9df4(%rbp),%eax
  cmp    %eax,-0x9dec(%rbp)
  jl     L111
  movl   $0x0,-0x9de8(%rbp)
  jmp    L6
L139:
  lea    -0x9c50(%rbp),%rcx
  mov    -0x9de8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9dec(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x9dec(%rbp),%eax
  cltq
  mov    -0x9de0(%rbp,%rax,4),%ecx
  mov    -0x9de8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9dec(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  mov    -0x9c50(%rbp,%rax,4),%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x9dec(%rbp),%eax
  cltq
  mov    %edx,-0x9de0(%rbp,%rax,4)
  addl   $0x1,-0x9de8(%rbp)
L6:
  mov    -0x9df0(%rbp),%eax
  cmp    %eax,-0x9de8(%rbp)
  jl     L139
  mov    -0x9de0(%rbp),%edx
  mov    -0x9ddc(%rbp),%eax
  cmp    %eax,%edx
  jl     L106
  mov    -0x9de0(%rbp),%eax
  mov    %eax,-0x9de4(%rbp)
  jmp    L31
L106:
  mov    -0x9ddc(%rbp),%eax
  mov    %eax,-0x9de4(%rbp)
L31:
  movl   $0x2,-0x9dec(%rbp)
  jmp    L85
L10:
  mov    -0x9dec(%rbp),%eax
  cltq
  mov    -0x9de0(%rbp,%rax,4),%eax
  cmp    %eax,-0x9de4(%rbp)
  jg     L4
  mov    -0x9dec(%rbp),%eax
  cltq
  mov    -0x9de0(%rbp,%rax,4),%eax
  mov    %eax,-0x9de4(%rbp)
L4:
  addl   $0x1,-0x9dec(%rbp)
L85:
  mov    -0x9df4(%rbp),%eax
  cmp    %eax,-0x9dec(%rbp)
  jl     L10
  mov    -0x9de4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x9dec(%rbp)
  jmp    L9
L36:
  mov    -0x9dec(%rbp),%eax
  cltq
  mov    -0x9de0(%rbp,%rax,4),%eax
  cmp    %eax,-0x9de4(%rbp)
  jne    L81
  mov    -0x9dec(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L81:
  addl   $0x1,-0x9dec(%rbp)
L9:
  mov    -0x9df4(%rbp),%eax
  cmp    %eax,-0x9dec(%rbp)
  jl     L36
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D36
type_infered: string
name: read_data
arguments: label: D1
type_infered: string
name: read_data
arguments: label: D16
type_infered: string

tool: D36: %d %d

tool: D1: %d

tool: D16: %d 

assistant: ```c
int main() {
  int M[100][100];
  int i, j, n, m, sum[100];
  scanf("%d %d", &n, &m);
  for (i = 0; i < n; i++)
    sum[i] = 0;
  {
    for (j = 0; j < m; j++) {
      scanf("%d", &M[i][j]);
      sum[i] = sum[i] + M[i][j];
    }
  }
  int max;
  if (sum[0] >= sum[1])
    max = sum[0];
  else
    max = sum[1];
  for (i = 2; i < n; i++) {
    if (sum[i] >= max)
      max = sum[i];
  }
  printf("%d", max);
  for (i = 0; i < n; i++) {
    if (sum[i] == max)
      printf("%d ", i);
  }
  return 0;
}
```