ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<reader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: Reading node %d

assistant: ```c
void *reader(void *arg) {
  int i = 0;
  while (1) {
    printf("Reading node %d", i);
    i++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reader>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D5: Reading node %d

assistant: ```c
void *reader(void *arg) {
  int i = 0;
  while (1) {
    printf("Reading node %d", i);
    i++;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reader>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: Reading node %d

assistant: ```c
void *reader(void *arg) {
  int i = 0;
  while (1) {
    printf("Reading node %d", i);
    i++;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reader>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: Reading node %d

assistant: ```c
void *reader(void *arg) {
  int i = 0;
  while (1) {
    printf("Reading node %d", i);
    i++;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<convert_int_to_ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L6
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <tohex@plt>
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movsbl -0x5(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <tohex@plt>
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L6:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L15
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void convert_int_to_ascii(char *from, char *to, int n) {
  int nib;
  char ch;
  while (n--) {
    ch = *from++;
    nib = ((ch & 0xf0) >> 4) & 0x0f;
    *to++ = tohex(nib);
    nib = ch & 0x0f;
    *to++ = tohex(nib);
  }
  *to++ = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_int_to_ascii>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r14
  test   %edx,%edx
  je     L18
  mov    %rdi,%rbp
  lea    -0x1(%rdx),%r15d
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%r13
  mov    %rsi,%r12
L14:
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%ebx
  mov    %ebx,%edi
  shr    $0x4,%edi
  and    $0xf,%edi
  call   <tohex@plt>
  mov    %al,(%r12)
  mov    %ebx,%edi
  and    $0xf,%edi
  call   <tohex@plt>
  add    $0x2,%r12
  mov    %al,-0x1(%r12)
  cmp    %r13,%rbp
  jne    L14
  mov    %r15d,%r15d
  lea    0x2(%r14,%r15,2),%r14
L18:
  movb   $0x0,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void convert_int_to_ascii(char *from, char *to, int n) {
  int nib;
  char ch;
  while (n--) {
    ch = *from++;
    nib = ((ch & 0xf0) >> 4) & 0x0f;
    *to++ = tohex(nib);
    nib = ch & 0x0f;
    *to++ = tohex(nib);
  }
  *to++ = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_int_to_ascii>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L16
  mov    %edx,%r13d
  mov    %rdi,%r15
  mov    %rsi,%rbp
  lea    (%rdi,%r13,1),%r12
  cs nopw 0x0(%rax,%rax,1)
L13:
  movzbl (%r15),%ebx
  add    $0x1,%r15
  add    $0x2,%rbp
  mov    %ebx,%edi
  shr    $0x4,%edi
  and    $0xf,%edi
  call   <tohex@plt>
  mov    %ebx,%edi
  mov    %al,-0x2(%rbp)
  and    $0xf,%edi
  call   <tohex@plt>
  mov    %al,-0x1(%rbp)
  cmp    %r12,%r15
  jne    L13
  lea    (%r14,%r13,2),%r14
L16:
  movb   $0x0,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void convert_int_to_ascii(char *from, char *to, int n) {
  int nib;
  char ch;
  while (n--) {
    ch = *from++;
    nib = ((ch & 0xf0) >> 4) & 0x0f;
    *to++ = tohex(nib);
    nib = ch & 0x0f;
    *to++ = tohex(nib);
  }
  *to++ = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<convert_int_to_ascii>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L11
  mov    %edx,%r13d
  mov    %rdi,%r15
  mov    %rsi,%rbp
  lea    (%rdi,%r13,1),%r12
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%r15),%ebx
  add    $0x1,%r15
  add    $0x2,%rbp
  mov    %ebx,%edi
  shr    $0x4,%edi
  and    $0xf,%edi
  call   <tohex@plt>
  mov    %ebx,%edi
  mov    %al,-0x2(%rbp)
  and    $0xf,%edi
  call   <tohex@plt>
  mov    %al,-0x1(%rbp)
  cmp    %r12,%r15
  jne    L3
  lea    (%r14,%r13,2),%r14
L11:
  movb   $0x0,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void convert_int_to_ascii(char *from, char *to, int n) {
  int nib;
  char ch;
  while (n--) {
    ch = *from++;
    nib = ((ch & 0xf0) >> 4) & 0x0f;
    *to++ = tohex(nib);
    nib = ch & 0x0f;
    *to++ = tohex(nib);
  }
  *to++ = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<cast_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %esi,-0x68(%rbp)
  mov    %edx,-0x6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x58(%rbp)
  movw   $0x0,-0x5a(%rbp)
  movl   $0x0,-0x54(%rbp)
  cmpl   $0x3,-0x64(%rbp)
  je     L26
  cmpl   $0x20,-0x64(%rbp)
  je     L26
  cmpl   $0x40,-0x64(%rbp)
  jne    L104
L26:
  mov    -0x68(%rbp),%eax
  mov    %eax,-0x58(%rbp)
  jmp    L122
L104:
  cmpl   $0x10,-0x64(%rbp)
  jne    L105
  mov    -0x68(%rbp),%eax
  mov    %ax,-0x5a(%rbp)
  jmp    L122
L105:
  cmpl   $0x8,-0x64(%rbp)
  je     L37
  cmpl   $0x113,-0x64(%rbp)
  jne    L27
L37:
  mov    -0x68(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x54(%rbp)
  jmp    L122
L27:
  cmpl   $0x1,-0x64(%rbp)
  jne    L42
  mov    -0x68(%rbp),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  mov    %eax,-0x54(%rbp)
  jmp    L122
L42:
  cmpl   $0x5,-0x64(%rbp)
  jne    L122
  cmpl   $0x0,-0x6c(%rbp)
  jne    L146
  mov    $0x0,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L146:
  mov    -0x6c(%rbp),%edx
  mov    $0x20,%eax
  sub    %edx,%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    -0x68(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x54(%rbp)
L122:
  movswl -0x5a(%rbp),%edx
  mov    -0x58(%rbp),%eax
  add    %eax,%edx
  mov    -0x54(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x68(%rbp)
  je     L112
  movswl -0x5a(%rbp),%edx
  mov    -0x58(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x54(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  mov    -0x64(%rbp),%ecx
  mov    -0x68(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    %ecx,%r8d
  mov    %esi,%ecx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <non_fatal@plt>
L112:
  movswl -0x5a(%rbp),%edx
  mov    -0x58(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x54(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D17
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D11
type_guessed: string

tool: D17: cannot happen, cast_val

tool: D8: %d->%d (%d)

tool: D11: value (%s) truncated in assignment

assistant: ```c
int cast_val(int t, int v, int w) {
  int i = 0;
  short s = 0;
  unsigned int u = 0;
  if (t == 3 || t == 32 || t == 64)
    i = v;
  else if (t == 16)
    s = (short)v;
  else if (t == 8 || t == 275)
    u = (unsigned char)v;
  else if (t == 1)
    u = (unsigned char)(v & 1);
  else if (t == 5) {
    if (w == 0)
      fatal("cannot happen, cast_val", (char *)0);
    u = (unsigned)(v & (~0u >> (8 * sizeof(unsigned) - w)));
  }
  if (v != i + s + (int)u) {
    char buf[64];
    sprintf(buf, "%d->%d (%d)", v, i + s + u, t);
    non_fatal("value (%s) truncated in assignment", buf);
  }
  return (int)(i + s + u);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cast_val>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0x20,%edi
  jg     L45
  mov    %edx,%ebp
  test   %edi,%edi
  jle    L8
  cmp    $0x20,%edi
  ja     L93
  mov    %edi,%eax
  lea    D1(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L45:
  mov    %esi,%ebp
  cmp    $0x40,%edi
  je     L6
  cmp    $0x113,%edi
  jne    L109
  movzbl %r12b,%eax
  mov    $0x0,%ebp
  jmp    L143
L109:
  mov    $0x0,%eax
  mov    $0x0,%ebp
  jmp    L143
  mov    %esi,%ebp
  mov    $0x0,%eax
  jmp    L143
  mov    %esi,%eax
  and    $0x1,%eax
  mov    $0x0,%ebp
  jmp    L143
  test   %ebp,%ebp
  je     L121
L54:
  mov    $0x20,%ecx
  sub    %ebp,%ecx
  mov    $0xffffffff,%eax
  shr    %cl,%eax
  and    %r12d,%eax
  mov    $0x0,%ebp
  jmp    L143
L121:
  mov    $0x0,%esi
  lea    D9(%rip),%rdi
  call   <fatal@plt>
  jmp    L54
L8:
  mov    $0x0,%eax
  mov    $0x0,%ebp
  jmp    L143
L93:
  mov    $0x0,%eax
  mov    $0x0,%ebp
L143:
  movswl %bp,%ebp
  add    %eax,%ebp
  cmp    %r12d,%ebp
  je     L6
  mov    %rsp,%r13
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12d,%edx
  lea    D17(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rsi
  lea    D29(%rip),%rdi
  call   <non_fatal@plt>
L6:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  mov    %ebp,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  mov    %esi,%ebp
  jmp    L6
L95:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string
name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D29
datatype: string

tool: D9: cannot happen, cast_val

tool: D17: %d->%d (%d)

tool: D29: value (%s) truncated in assignment

assistant: ```c
int cast_val(int t, int v, int w) {
  int i = 0;
  short s = 0;
  unsigned int u = 0;
  if (t == 3 || t == 32 || t == 64)
    i = v;
  else if (t == 16)
    s = (short)v;
  else if (t == 8 || t == 275)
    u = (unsigned char)v;
  else if (t == 1)
    u = (unsigned char)(v & 1);
  else if (t == 5) {
    if (w == 0)
      fatal("cannot happen, cast_val", (char *)0);
    u = (unsigned)(v & (~0u >> (8 * sizeof(unsigned) - w)));
  }
  if (v != i + s + (int)u) {
    char buf[64];
    sprintf(buf, "%d->%d (%d)", v, i + s + u, t);
    non_fatal("value (%s) truncated in assignment", buf);
  }
  return (int)(i + s + u);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cast_val>:
  endbr64
  push   %r13
  mov    %edi,%r8d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  cmp    $0x20,%edi
  jg     L40
  test   %edi,%edi
  jle    L25
  cmp    $0x20,%edi
  ja     L25
  lea    D10(%rip),%rcx
  mov    %edi,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L25:
  xor    %r13d,%r13d
L42:
  cmp    %r13d,%r12d
  je     L79
  lea    0x10(%rsp),%rbp
  lea    D1(%rip),%rsi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  call   <non_fatal@plt>
L79:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L127
  add    $0x60,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %esi,%r13d
  cmp    $0x40,%edi
  je     L79
  cmp    $0x113,%edi
  jne    L25
  movzbl %r12b,%r13d
  jmp    L42
  cs nopw 0x0(%rax,%rax,1)
  mov    %esi,%r13d
  jmp    L79
  nopl   (%rax)
  mov    %esi,%r13d
  and    $0x1,%r13d
  jmp    L42
  nopl   0x0(%rax)
  test   %edx,%edx
  je     L94
L84:
  mov    $0x20,%ecx
  mov    $0xffffffff,%r13d
  sub    %edx,%ecx
  shr    %cl,%r13d
  and    %r12d,%r13d
  jmp    L42
  nopl   0x0(%rax)
  movswl %si,%r13d
  jmp    L42
  nopl   0x0(%rax)
L94:
  mov    %edi,0x8(%rsp)
  xor    %esi,%esi
  lea    D38(%rip),%rdi
  mov    %edx,0xc(%rsp)
  call   <fatal@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%r8d
  jmp    L84
L127:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D35
type_guessed: string
name: retrieve_data
arguments: label: D38
type_guessed: string

tool: D1: %d->%d (%d)

tool: D35: value (%s) truncated in assignment

tool: D38: cannot happen, cast_val

assistant: ```c
int cast_val(int t, int v, int w) {
  int i = 0;
  short s = 0;
  unsigned int u = 0;
  if (t == 3 || t == 32 || t == 64)
    i = v;
  else if (t == 16)
    s = (short)v;
  else if (t == 8 || t == 275)
    u = (unsigned char)v;
  else if (t == 1)
    u = (unsigned char)(v & 1);
  else if (t == 5) {
    if (w == 0)
      fatal("cannot happen, cast_val", (char *)0);
    u = (unsigned)(v & (~0u >> (8 * sizeof(unsigned) - w)));
  }
  if (v != i + s + (int)u) {
    char buf[64];
    sprintf(buf, "%d->%d (%d)", v, i + s + u, t);
    non_fatal("value (%s) truncated in assignment", buf);
  }
  return (int)(i + s + u);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cast_val>:
  endbr64
  push   %r13
  mov    %edi,%r8d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  cmp    $0x20,%edi
  jg     L134
  test   %edi,%edi
  jle    L98
  cmp    $0x20,%edi
  ja     L98
  lea    D24(%rip),%rcx
  mov    %edi,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L98:
  xor    %r13d,%r13d
L57:
  cmp    %r13d,%r12d
  je     L103
  lea    0x10(%rsp),%rbp
  lea    D33(%rip),%rsi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  call   <non_fatal@plt>
L103:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L132
  add    $0x60,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L134:
  mov    %esi,%r13d
  cmp    $0x40,%edi
  je     L103
  cmp    $0x113,%edi
  jne    L98
  movzbl %r12b,%r13d
  jmp    L57
  cs nopw 0x0(%rax,%rax,1)
  mov    %esi,%r13d
  jmp    L103
  nopl   (%rax)
  mov    %esi,%r13d
  and    $0x1,%r13d
  jmp    L57
  nopl   0x0(%rax)
  test   %edx,%edx
  je     L129
L117:
  mov    $0x20,%ecx
  mov    $0xffffffff,%r13d
  sub    %edx,%ecx
  shr    %cl,%r13d
  and    %r12d,%r13d
  jmp    L57
  nopl   0x0(%rax)
  movswl %si,%r13d
  jmp    L57
  nopl   0x0(%rax)
L129:
  mov    %edi,0x8(%rsp)
  xor    %esi,%esi
  lea    D8(%rip),%rdi
  mov    %edx,0xc(%rsp)
  call   <fatal@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%r8d
  jmp    L117
L132:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D33
data_type: string
name: retrieve_data
arguments: data_tag: D27
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D33: %d->%d (%d)

tool: D27: value (%s) truncated in assignment

tool: D8: cannot happen, cast_val

assistant: ```c
int cast_val(int t, int v, int w) {
  int i = 0;
  short s = 0;
  unsigned int u = 0;
  if (t == 3 || t == 32 || t == 64)
    i = v;
  else if (t == 16)
    s = (short)v;
  else if (t == 8 || t == 275)
    u = (unsigned char)v;
  else if (t == 1)
    u = (unsigned char)(v & 1);
  else if (t == 5) {
    if (w == 0)
      fatal("cannot happen, cast_val", (char *)0);
    u = (unsigned)(v & (~0u >> (8 * sizeof(unsigned) - w)));
  }
  if (v != i + s + (int)u) {
    char buf[64];
    sprintf(buf, "%d->%d (%d)", v, i + s + u, t);
    non_fatal("value (%s) truncated in assignment", buf);
  }
  return (int)(i + s + u);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<timespec_sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jns    L9
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x3b9aca00(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L9:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void timespec_sub(struct timespec *diff, const struct timespec *left, const struct timespec *right) {
  diff->tv_sec = left->tv_sec - right->tv_sec;
  diff->tv_nsec = left->tv_nsec - right->tv_nsec;
  if (diff->tv_nsec < 0) {
    --diff->tv_sec;
    diff->tv_nsec += 1000000000;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<timespec_sub>:
  endbr64
  mov    0x8(%rsi),%rcx
  sub    0x8(%rdx),%rcx
  mov    %rcx,0x8(%rdi)
  mov    (%rsi),%rax
  sub    (%rdx),%rax
  mov    %rax,(%rdi)
  js     L11
L4:
  ret
L11:
  sub    $0x1,%rcx
  mov    %rcx,0x8(%rdi)
  add    $0x3b9aca00,%rax
  mov    %rax,(%rdi)
  jmp    L4
```

assistant: ```c
void timespec_sub(struct timespec *diff, const struct timespec *left, const struct timespec *right) {
  diff->tv_sec = left->tv_sec - right->tv_sec;
  diff->tv_nsec = left->tv_nsec - right->tv_nsec;
  if (diff->tv_nsec < 0) {
    --diff->tv_sec;
    diff->tv_nsec += 1000000000;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timespec_sub>:
  endbr64
  mov    0x8(%rsi),%rcx
  mov    (%rsi),%rax
  sub    0x8(%rdx),%rcx
  sub    (%rdx),%rax
  mov    %rcx,0x8(%rdi)
  mov    %rax,(%rdi)
  js     L8
  ret
  nopl   0x0(%rax)
L8:
  sub    $0x1,%rcx
  add    $0x3b9aca00,%rax
  mov    %rcx,0x8(%rdi)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void timespec_sub(struct timespec *diff, const struct timespec *left, const struct timespec *right) {
  diff->tv_sec = left->tv_sec - right->tv_sec;
  diff->tv_nsec = left->tv_nsec - right->tv_nsec;
  if (diff->tv_nsec < 0) {
    --diff->tv_sec;
    diff->tv_nsec += 1000000000;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<timespec_sub>:
  endbr64
  movdqu (%rdx),%xmm1
  movdqu (%rsi),%xmm0
  psubq  %xmm1,%xmm0
  movhlps %xmm0,%xmm2
  movq   %xmm0,%rax
  movups %xmm0,(%rdi)
  movq   %xmm2,%rdx
  test   %rax,%rax
  js     L0
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  sub    $0x1,%rdx
  add    $0x3b9aca00,%rax
  mov    %rdx,0x8(%rdi)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void timespec_sub(struct timespec *diff, const struct timespec *left, const struct timespec *right) {
  diff->tv_sec = left->tv_sec - right->tv_sec;
  diff->tv_nsec = left->tv_nsec - right->tv_nsec;
  if (diff->tv_nsec < 0) {
    --diff->tv_sec;
    diff->tv_nsec += 1000000000;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fn1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L7:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fn1(const float *restrict *restrict a, float *restrict b, int n) {
  for (int i = 0; i < n; ++i)
    b[i] = a[0][i] + a[1][i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn1>:
  endbr64
  test   %edx,%edx
  jle    L18
  mov    (%rdi),%r8
  mov    0x8(%rdi),%rcx
  mov    %edx,%edx
  mov    $0x0,%eax
L16:
  movss  (%r8,%rax,4),%xmm0
  addss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
L18:
  ret
```

assistant: ```c
void fn1(const float *restrict *restrict a, float *restrict b, int n) {
  for (int i = 0; i < n; ++i)
    b[i] = a[0][i] + a[1][i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fn1>:
  endbr64
  test   %edx,%edx
  jle    L2
  mov    (%rdi),%r8
  mov    0x8(%rdi),%rcx
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L5:
  movss  (%r8,%rax,4),%xmm0
  addss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L5
L2:
  ret
```

assistant: ```c
void fn1(const float *restrict *restrict a, float *restrict b, int n) {
  for (int i = 0; i < n; ++i)
    b[i] = a[0][i] + a[1][i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn1>:
  endbr64
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L24
  lea    -0x1(%rdx),%eax
  mov    (%rdi),%r8
  mov    0x8(%rdi),%rsi
  cmp    $0x2,%eax
  jbe    L39
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopl   (%rax)
L60:
  movups (%r8,%rax,1),%xmm0
  movups (%rsi,%rax,1),%xmm2
  addps  %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L60
  mov    %edx,%edi
  and    $0xfffffffc,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L59
L34:
  sub    %edi,%edx
  cmp    $0x1,%edx
  je     L17
  movq   (%r8,%rdi,4),%xmm0
  movq   (%rsi,%rdi,4),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rcx,%rdi,4)
  mov    %edx,%edi
  and    $0xfffffffe,%edi
  add    %edi,%eax
  cmp    %edi,%edx
  je     L24
L17:
  cltq
  movss  (%r8,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rcx,%rax,4)
L24:
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  ret
L39:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L34
```

assistant: ```c
void fn1(const float *restrict *restrict a, float *restrict b, int n) {
  for (int i = 0; i < n; ++i)
    b[i] = a[0][i] + a[1][i];
}
```