user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D51(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L13
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L128
  pxor   %xmm7,%xmm7
  mov    %edi,%edx
  xor    %eax,%eax
  movdqa D63(%rip),%xmm9
  movdqa %xmm7,%xmm14
  movdqa %xmm7,%xmm13
  movdqa D22(%rip),%xmm8
  movdqa D16(%rip),%xmm12
  pcmpgtd %xmm9,%xmm14
  shr    $0x2,%edx
  movdqa %xmm7,%xmm10
  pcmpgtd %xmm8,%xmm13
  nopl   0x0(%rax)
L92:
  movdqa %xmm12,%xmm3
  movdqa %xmm10,%xmm5
  movdqa %xmm14,%xmm2
  add    $0x1,%eax
  movdqa %xmm3,%xmm0
  movdqa %xmm10,%xmm4
  movdqa %xmm14,%xmm15
  paddd  D0(%rip),%xmm12
  punpckldq %xmm3,%xmm0
  pcmpgtd %xmm0,%xmm5
  pmuludq %xmm0,%xmm2
  movdqa %xmm0,%xmm6
  pmuludq %xmm9,%xmm6
  movdqa %xmm5,%xmm1
  pmuludq %xmm8,%xmm5
  pmuludq %xmm9,%xmm1
  paddq  %xmm2,%xmm1
  movdqa %xmm3,%xmm2
  punpckhdq %xmm3,%xmm2
  psllq  $0x20,%xmm1
  pcmpgtd %xmm2,%xmm4
  paddq  %xmm1,%xmm6
  movdqa %xmm2,%xmm11
  pmuludq %xmm2,%xmm15
  pmuludq %xmm9,%xmm11
  movdqa %xmm4,%xmm1
  pmuludq %xmm8,%xmm4
  pmuludq %xmm9,%xmm1
  paddq  %xmm15,%xmm1
  psllq  $0x20,%xmm1
  paddq  %xmm11,%xmm1
  shufps $0xdd,%xmm1,%xmm6
  psrad  $0x1,%xmm6
  movdqa %xmm6,%xmm1
  pslld  $0x2,%xmm1
  paddd  %xmm6,%xmm1
  movdqa %xmm13,%xmm6
  pmuludq %xmm0,%xmm6
  pmuludq %xmm8,%xmm0
  pcmpeqd %xmm3,%xmm1
  pcmpeqd %xmm10,%xmm1
  paddq  %xmm6,%xmm5
  psllq  $0x20,%xmm5
  paddq  %xmm5,%xmm0
  movdqa %xmm13,%xmm5
  pmuludq %xmm2,%xmm5
  pmuludq %xmm8,%xmm2
  paddq  %xmm5,%xmm4
  psllq  $0x20,%xmm4
  paddq  %xmm4,%xmm2
  shufps $0xdd,%xmm2,%xmm0
  movdqa %xmm0,%xmm2
  pslld  $0x1,%xmm2
  paddd  %xmm2,%xmm0
  pcmpeqd %xmm3,%xmm0
  pcmpeqd %xmm10,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm3,%xmm1
  paddd  %xmm1,%xmm7
  cmp    %eax,%edx
  jne    L92
  movdqa %xmm7,%xmm0
  mov    %edi,%ecx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%ecx
  paddd  %xmm0,%xmm7
  movdqa %xmm7,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm7
  movd   %xmm7,%esi
  test   $0x3,%dil
  je     L23
  mov    %ecx,%eax
  mov    $0x3,%r8d
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L158
  mov    %ecx,%eax
  mov    $0x5,%r8d
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L119
L158:
  add    %ecx,%esi
L119:
  lea    0x1(%rcx),%r8d
  cmp    %edi,%r8d
  jge    L23
  mov    %r8d,%eax
  mov    $0x3,%r9d
  cltd
  idiv   %r9d
  test   %edx,%edx
  jne    L159
L31:
  add    %r8d,%esi
L108:
  add    $0x2,%ecx
  cmp    %ecx,%edi
  jle    L23
  mov    %ecx,%eax
  mov    $0x3,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L28
  mov    %ecx,%eax
  mov    $0x5,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L28
  nop
L23:
  xor    %eax,%eax
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L168
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L159:
  mov    %r8d,%eax
  mov    $0x5,%r9d
  cltd
  idiv   %r9d
  test   %edx,%edx
  je     L31
  jmp    L108
L28:
  add    %ecx,%esi
  jmp    L23
L13:
  xor    %esi,%esi
  jmp    L23
L128:
  xor    %esi,%esi
  xor    %ecx,%ecx
  jmp    L158
L168:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D51
data_type: string
name: read_data
arguments: label: D5
data_type: string
name: read_data
arguments: label: D63
data_type: byte[16]
name: read_data
arguments: label: D22
data_type: byte[16]
name: read_data
arguments: label: D16
data_type: byte[16]
name: read_data
arguments: label: D0
data_type: byte[16]
name: read_data
arguments: label: D59
data_type: string

tool: D51: Please insert an integer value: 

tool: D5: %d

tool: {"D63": [0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66]}

tool: {"D22": [0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D0": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D59: The answer is %d


assistant: ```c
int main() {
  int i;
  int sum = 0;
  int input;
  printf("Please insert an integer value: ");
  scanf("%d", &input);
  for (i = 0; i < input; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
      sum = sum + i;
    }
  }
  printf("The answer is %d\n", sum);
}
```