ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D40(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1b(%rsp),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x2a(%rsp),%r13
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x39(%rsp),%r14
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D37
type_guessed: string
name: disassemble_data
arguments: label: D40
type_guessed: string
name: disassemble_data
arguments: label: D25
type_guessed: string
name: disassemble_data
arguments: label: D44
type_guessed: string
name: disassemble_data
arguments: label: D57
type_guessed: string
name: disassemble_data
arguments: label: D22
type_guessed: string
name: disassemble_data
arguments: label: D33
type_guessed: string

tool: D37: String 1: 

tool: D40: %s

tool: D25: String 2: 

tool: D44: String 3: 

tool: D57: String 4: 

tool: D22: ** "Output" **

tool: D33: %.3s
%.4s
%.5s
%.6s


assistant: ```c
int main(void) {
  char text1[15], text2[15], text3[15], text4[15];
  printf("String 1: ");
  scanf("%s", text1);
  printf("String 2: ");
  scanf("%s", text2);
  printf("String 3: ");
  scanf("%s", text3);
  printf("String 4: ");
  scanf("%s", text4);
  printf("** \"Output\" **\n");
  printf("%.3s\n%.4s\n%.5s\n%.6s\n", text1, text2, text3, text4);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D25(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D54(%rip),%rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x1b(%rsp),%r13
  lea    0x2a(%rsp),%r14
  lea    0x39(%rsp),%rbx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D30(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D54
type_infered: string
name: read_data
arguments: label: D57
type_infered: string
name: read_data
arguments: label: D42
type_infered: string
name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D30
type_infered: string
name: read_data
arguments: label: D23
type_infered: string

tool: D25: String 1: 

tool: D54: %s

tool: D57: String 2: 

tool: D42: String 3: 

tool: D5: String 4: 

tool: D30: ** "Output" **

tool: D23: %.3s
%.4s
%.5s
%.6s


assistant: ```c
int main(void) {
  char text1[15], text2[15], text3[15], text4[15];
  printf("String 1: ");
  scanf("%s", text1);
  printf("String 2: ");
  scanf("%s", text2);
  printf("String 3: ");
  scanf("%s", text3);
  printf("String 4: ");
  scanf("%s", text4);
  printf("** \"Output\" **\n");
  printf("%.3s\n%.4s\n%.5s\n%.6s\n", text1, text2, text3, text4);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D32(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x1b(%rsp),%r13
  lea    0x2a(%rsp),%r14
  lea    0x39(%rsp),%rbx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D32
data_type: string
name: parse_data
arguments: data_label: D1
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D42
data_type: string
name: parse_data
arguments: data_label: D41
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D53
data_type: string

tool: D32: String 1: 

tool: D1: %s

tool: D7: String 2: 

tool: D42: String 3: 

tool: D41: String 4: 

tool: D12: ** "Output" **

tool: D53: %.3s
%.4s
%.5s
%.6s


assistant: ```c
int main(void) {
  char text1[15], text2[15], text3[15], text4[15];
  printf("String 1: ");
  scanf("%s", text1);
  printf("String 2: ");
  scanf("%s", text2);
  printf("String 3: ");
  scanf("%s", text3);
  printf("String 4: ");
  scanf("%s", text4);
  printf("** \"Output\" **\n");
  printf("%.3s\n%.4s\n%.5s\n%.6s\n", text1, text2, text3, text4);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  xor    $0x29be1cdb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L36
L22:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  je     L76
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L6
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x1a(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
  lea    -0x10(%rbp),%rax
  movzwl -0x1a(%rbp),%edx
  mov    %dx,(%rax)
  jmp    L8
L6:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
  jmp    L8
L76:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L38
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  xor    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L8
L38:
  lea    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1b(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    -0x10(%rbp),%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl -0x1b(%rbp),%edx
  mov    %dl,(%rax)
L8:
  addq   $0x2,-0x18(%rbp)
L36:
  cmpq   $0x0,-0x18(%rbp)
  je     L22
  mov    -0x10(%rbp),%rax
  and    $0xea3a10e,%eax
  xor    $0x1603b040,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        if (state[0UL] == local1) {
          copy11 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
        } else {
          state[local1] <<= (state[local1] & 7UL) | 1UL;
        }
      } else if (state[0UL] <= local1) {
        state[0UL] = state[local1] ^ state[0UL];
      } else {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 245604622UL) ^ 369340480UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rdx,%rdi
  xor    $0x29be1cdb,%rdi
  mov    $0x0,%eax
  cmp    $0x29be1cdb,%rdx
  je     L7
  mov    %edi,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  mov    %rdi,%rax
  shl    %cl,%rax
L7:
  and    $0xea3a10e,%eax
  xor    $0x1603b040,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        if (state[0UL] == local1) {
          copy11 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
        } else {
          state[local1] <<= (state[local1] & 7UL) | 1UL;
        }
      } else if (state[0UL] <= local1) {
        state[0UL] = state[local1] ^ state[0UL];
      } else {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 245604622UL) ^ 369340480UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rdx,%rax
  xor    $0x29be1cdb,%rax
  cmp    $0x29be1cdb,%rdx
  je     L1
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L1:
  and    $0xea3a10e,%eax
  xor    $0x1603b040,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        if (state[0UL] == local1) {
          copy11 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
        } else {
          state[local1] <<= (state[local1] & 7UL) | 1UL;
        }
      } else if (state[0UL] <= local1) {
        state[0UL] = state[local1] ^ state[0UL];
      } else {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 245604622UL) ^ 369340480UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rdx,%rax
  xor    $0x29be1cdb,%rax
  cmp    $0x29be1cdb,%rdx
  je     L2
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L2:
  and    $0xea3a10e,%eax
  xor    $0x1603b040,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] != local1) {
        if (state[0UL] == local1) {
          copy11 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
        } else {
          state[local1] <<= (state[local1] & 7UL) | 1UL;
        }
      } else if (state[0UL] <= local1) {
        state[0UL] = state[local1] ^ state[0UL];
      } else {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 245604622UL) ^ 369340480UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <g@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void f() {
  void *i = &i;
  g(i);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rdi,(%rsp)
  call   <g@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f() {
  void *i = &i;
  g(i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rdi,(%rsp)
  call   <g@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f() {
  void *i = &i;
  g(i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rdi,(%rsp)
  call   <g@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f() {
  void *i = &i;
  g(i);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <getchar@plt>
  mov    D2(%rip),%rbx
  cmp    %eax,(%rbx)
  je     L247
L234:
  cmp    $0x2f,%eax
  je     L74
  cmp    $0x27,%eax
  je     L229
  mov    %eax,%edi
  cmp    $0x22,%eax
  je     L229
L87:
  call   <putchar@plt>
L162:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  jne    L234
L247:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L229:
  movsbl %al,%ebp
  mov    %eax,%edi
L204:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  je     L247
  cmp    $0x5c,%eax
  je     L84
  cmp    %eax,%ebp
  je     L119
  mov    %eax,%edi
  jmp    L204
L185:
  mov    $0x2f,%edi
  call   <putchar@plt>
L119:
  mov    %ebp,%edi
  jmp    L87
L84:
  mov    $0x5c,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  jne    L204
  jmp    L247
L74:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    (%rbx),%eax
  je     L247
  cmp    $0x2a,%eax
  je     L177
  cmp    $0x2f,%eax
  jne    L185
  cmp    $0x2a,%eax
  je     L177
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  je     L247
  mov    $0x1,%edx
L298:
  mov    %edx,%r12d
  mov    %edx,%ebp
  and    $0x1,%r12d
  xor    $0x1,%ebp
L123:
  cmp    $0xa,%eax
  jne    L81
  test   %r12b,%r12b
  je     L81
  mov    $0xa,%edi
  jmp    L87
  nopl   0x0(%rax,%rax,1)
L81:
  cmp    $0x2a,%eax
  jne    L83
  test   %bpl,%bpl
  je     L83
L92:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  je     L247
  cmp    $0x2f,%eax
  je     L162
  cmp    $0x2a,%eax
  je     L92
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %edx,%edx
  cmp    (%rbx),%eax
  jne    L298
  jmp    L247
L83:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  jne    L123
  jmp    L247
L177:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  je     L247
  xor    %edx,%edx
  jmp    L298
```

assistant: ```c
main() {
  int c, state;
  int slc;
  char quote;
  slc = 1;
  state = 0;
  while ((c = getchar()) != EOF) {
    if (state == 0) {
      if (c == '/') {
        state = 3;
      } else {
        if (c == '\'' || c == '"') {
          state = 1;
          quote = c;
        }
        putchar(c);
      }
    } else if (state == 1) {
      if (c == '\\')
        state = 2;
      else if (c == quote)
        state = 0;
      putchar(c);
    } else if (state == 2) {
      putchar(c);
      state = 1;
    } else if (state == 3) {
      if (c == '*' || c == '/') {
        state = 5;
        if (c == '*')
          slc = 0;
        else if (c == '/')
          slc = 1;
      } else {
        putchar('/');
        putchar(c);
        state = 0;
      }
    } else if (state == 4) {
      if (c == '/') {
        state = 0;
      } else if (c != '*')
        state = 5;
    } else if (state == 5) {
      if (c == '\n' && slc) {
        putchar(c);
        state = 0;
      } else if (c == '*' && slc == 0) {
        state = 4;
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <getchar@plt>
  mov    D9(%rip),%rbx
  cmp    %eax,(%rbx)
  je     L43
L95:
  cmp    $0x2f,%eax
  je     L186
  cmp    $0x27,%eax
  je     L84
  mov    %eax,%edi
  cmp    $0x22,%eax
  je     L84
L50:
  call   <putchar@plt>
L243:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  jne    L95
L43:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L84:
  movsbl %al,%ebp
  mov    %eax,%edi
L191:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  je     L43
  cmp    $0x5c,%eax
  je     L284
  cmp    %eax,%ebp
  je     L24
  mov    %eax,%edi
  jmp    L191
L172:
  mov    $0x2f,%edi
  call   <putchar@plt>
L24:
  mov    %ebp,%edi
  jmp    L50
L284:
  mov    $0x5c,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  jne    L191
  jmp    L43
L186:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    (%rbx),%eax
  je     L43
  cmp    $0x2a,%eax
  je     L129
  cmp    $0x2f,%eax
  jne    L172
  cmp    $0x2a,%eax
  je     L129
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  je     L43
  mov    $0x1,%edx
L265:
  mov    %edx,%r12d
  mov    %edx,%ebp
  and    $0x1,%r12d
  xor    $0x1,%ebp
L115:
  cmp    $0xa,%eax
  jne    L0
  test   %r12b,%r12b
  je     L0
  mov    $0xa,%edi
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    $0x2a,%eax
  jne    L126
  test   %bpl,%bpl
  je     L126
L63:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  je     L43
  cmp    $0x2f,%eax
  je     L243
  cmp    $0x2a,%eax
  je     L63
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %edx,%edx
  cmp    (%rbx),%eax
  jne    L265
  jmp    L43
L126:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  jne    L115
  jmp    L43
L129:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%eax
  je     L43
  xor    %edx,%edx
  jmp    L265
```

assistant: ```c
main() {
  int c, state;
  int slc;
  char quote;
  slc = 1;
  state = 0;
  while ((c = getchar()) != EOF) {
    if (state == 0) {
      if (c == '/') {
        state = 3;
      } else {
        if (c == '\'' || c == '"') {
          state = 1;
          quote = c;
        }
        putchar(c);
      }
    } else if (state == 1) {
      if (c == '\\')
        state = 2;
      else if (c == quote)
        state = 0;
      putchar(c);
    } else if (state == 2) {
      putchar(c);
      state = 1;
    } else if (state == 3) {
      if (c == '*' || c == '/') {
        state = 5;
        if (c == '*')
          slc = 0;
        else if (c == '/')
          slc = 1;
      } else {
        putchar('/');
        putchar(c);
        state = 0;
      }
    } else if (state == 4) {
      if (c == '/') {
        state = 0;
      } else if (c != '*')
        state = 5;
    } else if (state == 5) {
      if (c == '\n' && slc) {
        putchar(c);
        state = 0;
      } else if (c == '*' && slc == 0) {
        state = 4;
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Mem_FreadStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t Mem_FreadStr(char *str, size_t len, FILE *fp) {
  size_t nbytes;
  nbytes = fread(str, len, sizeof(*str), fp);
  return nbytes;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Mem_FreadStr>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  mov    $0x1,%edx
  call   <fread@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
size_t Mem_FreadStr(char *str, size_t len, FILE *fp) {
  size_t nbytes;
  nbytes = fread(str, len, sizeof(*str), fp);
  return nbytes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Mem_FreadStr>:
  endbr64
  mov    %rdx,%rcx
  mov    $0x1,%edx
  jmp    1050 <fread@plt>
```

assistant: ```c
size_t Mem_FreadStr(char *str, size_t len, FILE *fp) {
  size_t nbytes;
  nbytes = fread(str, len, sizeof(*str), fp);
  return nbytes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Mem_FreadStr>:
  endbr64
  mov    %rdx,%rcx
  mov    $0x1,%edx
  jmp    1050 <fread@plt>
```

assistant: ```c
size_t Mem_FreadStr(char *str, size_t len, FILE *fp) {
  size_t nbytes;
  nbytes = fread(str, len, sizeof(*str), fp);
  return nbytes;
}
```