ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string
name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D13
type: string

tool: D2: x = %d


tool: D3: y = %d


tool: D13: z = %d


assistant: ```c
int main(char argc, char **argv) {
  unsigned int a = 3, b = 5, c = 7;
  unsigned int x, y, z;
  x = a == 3;
  y = (a << 1) & b;
  z = (a > 3) ? b : c;
  printf("x = %d\n", x);
  printf("y = %d\n", y);
  printf("z = %d\n", z);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  shr    %al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L15
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L5
L15:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
L5:
  movzbl -0x9(%rbp),%eax
  and    $0xffffffd1,%eax
  or     $0xc,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    if ((state[0UL] >> (unsigned char)1) & (unsigned char)1) {
      state[0UL] >>= (state[0UL] & (unsigned char)7) | 1UL;
    } else {
      state[0UL] >>= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
    }
    output[0UL] = (state[0UL] | 574800142UL) & (unsigned char)221;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movb   $0xc,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    if ((state[0UL] >> (unsigned char)1) & (unsigned char)1) {
      state[0UL] >>= (state[0UL] & (unsigned char)7) | 1UL;
    } else {
      state[0UL] >>= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
    }
    output[0UL] = (state[0UL] | 574800142UL) & (unsigned char)221;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movb   $0xc,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    if ((state[0UL] >> (unsigned char)1) & (unsigned char)1) {
      state[0UL] >>= (state[0UL] & (unsigned char)7) | 1UL;
    } else {
      state[0UL] >>= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
    }
    output[0UL] = (state[0UL] | 574800142UL) & (unsigned char)221;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movb   $0xc,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    if ((state[0UL] >> (unsigned char)1) & (unsigned char)1) {
      state[0UL] >>= (state[0UL] & (unsigned char)7) | 1UL;
    } else {
      state[0UL] >>= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
    }
    output[0UL] = (state[0UL] | 574800142UL) & (unsigned char)221;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movabs $0x7ffffffffffffffe,%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L2
  movabs $0x7fffffffffffffff,%rax
  mov    %rax,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long f3(unsigned long long x) {
  if (x >= 0x7fffffffffffffffULL)
    x = 0x7fffffffffffffffULL;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f3>:
  endbr64
  movabs $0x7fffffffffffffff,%rax
  cmp    %rax,%rdi
  cmovbe %rdi,%rax
  ret
```

assistant: ```c
unsigned long long f3(unsigned long long x) {
  if (x >= 0x7fffffffffffffffULL)
    x = 0x7fffffffffffffffULL;
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<f3>:
  endbr64
  movabs $0x7fffffffffffffff,%rax
  cmp    %rax,%rdi
  cmovbe %rdi,%rax
  ret
```

assistant: ```c
unsigned long long f3(unsigned long long x) {
  if (x >= 0x7fffffffffffffffULL)
    x = 0x7fffffffffffffffULL;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<heapify_node>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L25:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <check_child@plt>
  test   %rax,%rax
  je     L37
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L37:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <check_child@plt>
  test   %rax,%rax
  je     L36
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L36:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L14
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swap@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L14:
  cmpl   $0x0,-0x4(%rbp)
  jne    L25
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapify_node(int index, int last) {
  int highest = index;
  int left_child;
  int right_child;
  int need_to_swap;
  do {
    left_child = 2 * index + 1;
    if (check_child(left_child, highest, last)) {
      highest = left_child;
    }
    right_child = 2 * index + 2;
    if (check_child(right_child, highest, last)) {
      highest = right_child;
    }
    need_to_swap = index != highest;
    if (need_to_swap) {
      swap(index, highest);
      index = highest;
    }
  } while (need_to_swap);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<heapify_node>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %edi,%esi
L18:
  lea    (%r12,%r12,1),%ebp
  lea    0x1(%rbp),%ebx
  mov    %r13d,%edx
  mov    %ebx,%edi
  call   <check_child@plt>
  test   %rax,%rax
  je     L20
  add    $0x2,%ebp
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <check_child@plt>
  test   %rax,%rax
  cmovne %ebp,%ebx
L7:
  cmp    %ebx,%r12d
  je     L2
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <swap@plt>
  mov    %ebx,%r12d
  mov    %ebx,%esi
  jmp    L18
L20:
  lea    0x2(%rbp),%ebx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <check_child@plt>
  test   %rax,%rax
  jne    L7
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void heapify_node(int index, int last) {
  int highest = index;
  int left_child;
  int right_child;
  int need_to_swap;
  do {
    left_child = 2 * index + 1;
    if (check_child(left_child, highest, last)) {
      highest = left_child;
    }
    right_child = 2 * index + 2;
    if (check_child(right_child, highest, last)) {
      highest = right_child;
    }
    need_to_swap = index != highest;
    if (need_to_swap) {
      swap(index, highest);
      index = highest;
    }
  } while (need_to_swap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<heapify_node>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  lea    (%r12,%r12,1),%ebx
  mov    %r13d,%edx
  mov    %r12d,%esi
  lea    0x1(%rbx),%ebp
  add    $0x2,%ebx
  mov    %ebp,%edi
  call   <check_child@plt>
  mov    %r13d,%edx
  test   %rax,%rax
  je     L18
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <check_child@plt>
  test   %rax,%rax
  jne    L9
L40:
  cmp    %ebp,%r12d
  je     L11
  mov    %r12d,%edi
  mov    %ebp,%esi
  mov    %ebp,%r12d
  call   <swap@plt>
  jmp    L12
  nopl   0x0(%rax)
L9:
  mov    %ebx,%ebp
  jmp    L40
  nopl   0x0(%rax)
L18:
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <check_child@plt>
  test   %rax,%rax
  jne    L9
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void heapify_node(int index, int last) {
  int highest = index;
  int left_child;
  int right_child;
  int need_to_swap;
  do {
    left_child = 2 * index + 1;
    if (check_child(left_child, highest, last)) {
      highest = left_child;
    }
    right_child = 2 * index + 2;
    if (check_child(right_child, highest, last)) {
      highest = right_child;
    }
    need_to_swap = index != highest;
    if (need_to_swap) {
      swap(index, highest);
      index = highest;
    }
  } while (need_to_swap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<heapify_node>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L47:
  lea    (%r12,%r12,1),%ebx
  mov    %r13d,%edx
  mov    %r12d,%esi
  lea    0x1(%rbx),%ebp
  add    $0x2,%ebx
  mov    %ebp,%edi
  call   <check_child@plt>
  mov    %r13d,%edx
  test   %rax,%rax
  je     L29
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <check_child@plt>
  test   %rax,%rax
  jne    L58
L53:
  cmp    %ebp,%r12d
  je     L44
  mov    %r12d,%edi
  mov    %ebp,%esi
  mov    %ebp,%r12d
  call   <swap@plt>
  jmp    L47
  nopl   0x0(%rax)
L58:
  mov    %ebx,%ebp
  jmp    L53
  nopl   0x0(%rax)
L29:
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <check_child@plt>
  test   %rax,%rax
  jne    L58
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void heapify_node(int index, int last) {
  int highest = index;
  int left_child;
  int right_child;
  int need_to_swap;
  do {
    left_child = 2 * index + 1;
    if (check_child(left_child, highest, last)) {
      highest = left_child;
    }
    right_child = 2 * index + 2;
    if (check_child(right_child, highest, last)) {
      highest = right_child;
    }
    need_to_swap = index != highest;
    if (need_to_swap) {
      swap(index, highest);
      index = highest;
    }
  } while (need_to_swap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<WaitMs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  jmp    L1
L38:
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L7:
  nop
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0xccb,-0x4(%rbp)
  jle    L7
L1:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L38
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void WaitMs(unsigned int ms) {
  int i;
  while (ms-- > 0) {
    for (i = 0; i < 3276; ++i)
      asm("nop");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<WaitMs>:
  endbr64
  lea    -0x1(%rdi),%edx
  test   %edi,%edi
  je     L16
L4:
  mov    $0xccc,%eax
L25:
  nop
  sub    $0x1,%eax
  jne    L25
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  jne    L4
  ret
L16:
  ret
```

assistant: ```c
void WaitMs(unsigned int ms) {
  int i;
  while (ms-- > 0) {
    for (i = 0; i < 3276; ++i)
      asm("nop");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<WaitMs>:
  endbr64
  lea    -0x1(%rdi),%edx
  test   %edi,%edi
  je     L21
L1:
  mov    $0xccc,%eax
L9:
  nop
  sub    $0x1,%eax
  jne    L9
  sub    $0x1,%edx
  jae    L1
L21:
  ret
```

assistant: ```c
void WaitMs(unsigned int ms) {
  int i;
  while (ms-- > 0) {
    for (i = 0; i < 3276; ++i)
      asm("nop");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<WaitMs>:
  endbr64
  lea    -0x1(%rdi),%edx
  test   %edi,%edi
  je     L9
L19:
  mov    $0xccc,%eax
L14:
  nop
  sub    $0x1,%eax
  jne    L14
  sub    $0x1,%edx
  jae    L19
L9:
  ret
```

assistant: ```c
void WaitMs(unsigned int ms) {
  int i;
  while (ms-- > 0) {
    for (i = 0; i < 3276; ++i)
      asm("nop");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L51
L34:
  cmpl   $0x20,-0x4(%rbp)
  jne    L55
  cmpl   $0x0,-0x8(%rbp)
  jle    L55
  addl   $0x1,-0x8(%rbp)
  jmp    L51
L55:
  cmpl   $0x20,-0x4(%rbp)
  jne    L46
  addl   $0x1,-0x8(%rbp)
  jmp    L29
L46:
  movl   $0x0,-0x8(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L51:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L34
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int c;
  int blankStreak = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' && blankStreak >= 1)
      ++blankStreak;
    else {
      if (c == ' ')
        ++blankStreak;
      else
        blankStreak = 0;
      putchar(c);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L9
L16:
  add    $0x1,%ebx
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L18
  cmp    $0x20,%eax
  jne    L34
  test   %ebx,%ebx
  jg     L16
L34:
  add    $0x1,%ebx
  cmp    $0x20,%eax
  cmovne %ebp,%ebx
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L9
L18:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int c;
  int blankStreak = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' && blankStreak >= 1)
      ++blankStreak;
    else {
      if (c == ' ')
        ++blankStreak;
      else
        blankStreak = 0;
      putchar(c);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,0x0(%rbp)
  je     L30
L39:
  cmp    $0x20,%edi
  jne    L15
  test   %ebx,%ebx
  jle    L15
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,0x0(%rbp)
  jne    L39
L30:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x1,%ebx
  cmp    $0x20,%edi
  cmovne %r12d,%ebx
  call   <putchar@plt>
  jmp    L17
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int c;
  int blankStreak = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' && blankStreak >= 1)
      ++blankStreak;
    else {
      if (c == ' ')
        ++blankStreak;
      else
        blankStreak = 0;
      putchar(c);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,0x0(%rbp)
  je     L8
L17:
  cmp    $0x20,%edi
  jne    L21
  test   %ebx,%ebx
  jle    L21
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,0x0(%rbp)
  jne    L17
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x1,%ebx
  cmp    $0x20,%edi
  cmovne %r12d,%ebx
  call   <putchar@plt>
  jmp    L1
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int c;
  int blankStreak = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' && blankStreak >= 1)
      ++blankStreak;
    else {
      if (c == ' ')
        ++blankStreak;
      else
        blankStreak = 0;
      putchar(c);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L5
L48:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L16:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x0,-0x8(%rbp)
  js     L12
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L16
L12:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L48
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_sort(int arr[], int _arraySize) {
  int j, i, key;
  for (j = 1; j <= _arraySize - 1; j++) {
    key = arr[j];
    i = j - 1;
    while (i >= 0 && arr[i] > key) {
      arr[i + 1] = arr[i];
      i -= 1;
    }
    arr[i + 1] = key;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L57
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r10d
  mov    $0x0,%r8d
  jmp    L20
L14:
  movslq %edx,%rdx
  mov    %esi,0x4(%rdi,%rdx,4)
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  je     L57
L20:
  mov    0x4(%r9),%esi
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L14
L22:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L14
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L22
  jmp    L14
L57:
  ret
```

assistant: ```c
void insertion_sort(int arr[], int _arraySize) {
  int j, i, key;
  for (j = 1; j <= _arraySize - 1; j++) {
    key = arr[j];
    i = j - 1;
    while (i >= 0 && arr[i] > key) {
      arr[i + 1] = arr[i];
      i -= 1;
    }
    arr[i + 1] = key;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertion_sort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L17
L42:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L25:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L32
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L25
  mov    %rdi,%rax
L11:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L42
L17:
  ret
  nopl   (%rax)
L32:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L11
```

assistant: ```c
void insertion_sort(int arr[], int _arraySize) {
  int j, i, key;
  for (j = 1; j <= _arraySize - 1; j++) {
    key = arr[j];
    i = j - 1;
    while (i >= 0 && arr[i] > key) {
      arr[i + 1] = arr[i];
      i -= 1;
    }
    arr[i + 1] = key;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<insertion_sort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L1
L9:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L3
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L17
  mov    %rdi,%rax
L15:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L9
L1:
  ret
  nopl   (%rax)
L3:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L15
```

assistant: ```c
void insertion_sort(int arr[], int _arraySize) {
  int j, i, key;
  for (j = 1; j <= _arraySize - 1; j++) {
    key = arr[j];
    i = j - 1;
    while (i >= 0 && arr[i] > key) {
      arr[i + 1] = arr[i];
      i -= 1;
    }
    arr[i + 1] = key;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dofun>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,(%rsp)
  mov    %r9,0x8(%rsp)
  test   %r8d,%r8d
  je     L22
  mov    %rdi,%rbp
  mov    %esi,%r13d
  cmp    %r8d,(%rdi)
  jg     L58
  lea    0x1(%rcx),%ebx
  cmp    %esi,%ebx
  jge    L58
  mov    %r8d,0x1c(%rsp)
  mov    0x78(%rsp),%r15
  jmp    L78
L22:
  mov    0x78(%rsp),%rax
  mov    (%rax),%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    0x78(%rsp),%rax
  mov    (%rax),%edx
  mov    0x68(%rsp),%rax
  movslq (%rax),%rax
  mov    0x60(%rsp),%rdi
  mov    %edx,(%rdi,%rax,4)
  shl    $0x2,%edx
  mov    0x70(%rsp),%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    0x68(%rsp),%rax
  movslq (%rax),%rax
  mov    0x8(%rsp),%rcx
  mov    %rbx,(%rcx,%rax,8)
  mov    0x68(%rsp),%rax
  addl   $0x1,(%rax)
L58:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jle    L58
L78:
  movslq %ebx,%r12
  shl    $0x2,%r12
  mov    (%rsp),%rax
  lea    (%rax,%r12,1),%r14
  cmpl   $0x0,(%r14)
  jne    L44
  movl   $0x1,(%r14)
  lea    0x0(%rbp,%r12,1),%rax
  mov    %rax,%rsi
  mov    (%r15),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%r15)
  mov    %rsi,0x10(%rsp)
  mov    (%rsi),%edx
  cltq
  mov    0x70(%rsp),%rdi
  mov    %edx,(%rdi,%rax,4)
  push   %r15
  push   %rdi
  push   0x78(%rsp)
  push   0x78(%rsp)
  mov    0x28(%rsp),%r9
  mov    0x3c(%rsp),%r8d
  sub    %edx,%r8d
  mov    %ebx,%ecx
  mov    0x20(%rsp),%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <dofun>
  subl   $0x1,(%r15)
  movl   $0x0,(%r14)
  add    $0x20,%rsp
  mov    0x10(%rsp),%rsi
  mov    (%rsi),%eax
  cmp    %eax,0x4(%rbp,%r12,1)
  jne    L44
  add    $0x1,%ebx
  movslq %ebx,%rax
L39:
  mov    %eax,%ebx
  mov    0x4(%rbp,%rax,4),%edx
  add    $0x1,%rax
  cmp    -0x4(%rbp,%rax,4),%edx
  je     L39
  jmp    L44
```

assistant: ```c
void dofun(int *nlist, int nsize, int *nmark, int left, int target, int **ret, int *col, int *retsize, int *tmp, int *tmpsize) {
  int i;
  if (target == 0) {
    int *line = (int *)calloc(sizeof(int), *tmpsize);
    col[*retsize] = *tmpsize;
    memcpy(line, tmp, *tmpsize * sizeof(int));
    ret[*retsize] = line;
    (*retsize)++;
    return;
  }
  if (target < nlist[0])
    return;
  for (i = left + 1; i < nsize; i++) {
    if (nmark[i])
      continue;
    nmark[i] = 1;
    tmp[(*tmpsize)++] = nlist[i];
    int left = i;
    dofun(nlist, nsize, nmark, left, target - nlist[i], ret, col, retsize, tmp, tmpsize);
    (*tmpsize)--;
    nmark[i] = 0;
    while (nlist[i + 1] == nlist[i])
      i++;
  }
}
```