ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<close_pipe>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fclose@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int close_pipe(FILE *fp) {
  fclose(fp);
  int status;
  wait(&status);
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<close_pipe>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fclose@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int close_pipe(FILE *fp) {
  fclose(fp);
  int status;
  wait(&status);
  return status;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<close_pipe>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fclose@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int close_pipe(FILE *fp) {
  fclose(fp);
  int status;
  wait(&status);
  return status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<connect_room>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdx,%rdx
  js     L21
  jg     L1
  test   %rcx,%rcx
  js     L62
  jle    L24
  mov    $0xf,%edi
  call   <randm@plt>
  lea    0x0(%rbp,%rbp,4),%rdx
  lea    0x1(%rax,%rdx,4),%rbp
  lea    0x5(%rbx,%rbx,4),%rbx
  shl    $0x2,%rbx
  lea    -0x1(%rbx),%rsi
  mov    $0xffffffff,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <finish_path@plt>
  lea    -0x2(%rbx),%rsi
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <finish_path@plt>
  jmp    L24
L21:
  mov    $0xf,%edi
  call   <randm@plt>
  lea    (%rbx,%rbx,4),%rdx
  lea    0x1(%rax,%rdx,4),%r12
  lea    0x0(%rbp,%rbp,4),%rbx
  shl    $0x2,%rbx
  lea    -0x1(%rbx),%rdi
  mov    $0x0,%ecx
  mov    $0xffffffff,%edx
  mov    %r12,%rsi
  call   <finish_path@plt>
  lea    -0x2(%rbx),%rdi
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %r12,%rsi
  call   <finish_path@plt>
  jmp    L24
L1:
  mov    $0xf,%edi
  call   <randm@plt>
  lea    (%rbx,%rbx,4),%rdx
  lea    0x1(%rax,%rdx,4),%r12
  lea    0x5(%rbp,%rbp,4),%rbx
  shl    $0x2,%rbx
  lea    -0x1(%rbx),%rdi
  mov    $0x0,%ecx
  mov    $0xffffffff,%edx
  mov    %r12,%rsi
  call   <finish_path@plt>
  lea    -0x2(%rbx),%rdi
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %r12,%rsi
  call   <finish_path@plt>
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L62:
  mov    $0xf,%edi
  call   <randm@plt>
  lea    0x0(%rbp,%rbp,4),%rdx
  lea    0x1(%rax,%rdx,4),%rbp
  lea    (%rbx,%rbx,4),%rbx
  shl    $0x2,%rbx
  lea    -0x1(%rbx),%rsi
  mov    $0xffffffff,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <finish_path@plt>
  lea    -0x2(%rbx),%rsi
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <finish_path@plt>
  jmp    L24
```

assistant: ```c
void connect_room(long ax, long ay, long dx, long dy) {
  long mx, my;
  if (dx < 0) {
    my = ay * 20 + 1 + randm(20 - 3 - 2);
    mx = ax * 20 - 1;
    finish_path(mx, my, -1, 0);
    mx = ax * 20 - 3 + 1;
    finish_path(mx, my, +1, 0);
  } else if (dx > 0) {
    my = ay * 20 + 1 + randm(20 - 3 - 2);
    mx = ax * 20 + 20 - 1;
    finish_path(mx, my, -1, 0);
    mx = ax * 20 + 20 - 3 + 1;
    finish_path(mx, my, +1, 0);
  } else if (dy < 0) {
    mx = ax * 20 + 1 + randm(20 - 3 - 2);
    my = ay * 20 - 1;
    finish_path(mx, my, 0, -1);
    my = ay * 20 - 3 + 1;
    finish_path(mx, my, 0, +1);
  } else if (dy > 0) {
    mx = ax * 20 + 1 + randm(20 - 3 - 2);
    my = ay * 20 + 20 - 1;
    finish_path(mx, my, 0, -1);
    my = ay * 20 + 20 - 3 + 1;
    finish_path(mx, my, 0, +1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<connect_room>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rdx,%rdx
  js     L16
  jne    L12
  test   %rcx,%rcx
  js     L38
  jne    L44
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L12:
  mov    $0xf,%edi
  call   <randm@plt>
  lea    (%rbx,%rbx,4),%rdx
  lea    0x5(%rbp,%rbp,4),%rbx
  lea    0x1(%rax,%rdx,4),%r12
L14:
  shl    $0x2,%rbx
  mov    %r12,%rsi
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  lea    -0x1(%rbx),%rdi
  call   <finish_path@plt>
  lea    -0x2(%rbx),%rdi
  mov    %r12,%rsi
  pop    %rbx
  xor    %ecx,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <finish_path@plt>
  xchg   %ax,%ax
L16:
  mov    $0xf,%edi
  call   <randm@plt>
  lea    (%rbx,%rbx,4),%rdx
  lea    0x0(%rbp,%rbp,4),%rbx
  lea    0x1(%rax,%rdx,4),%r12
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0xf,%edi
  lea    (%rbx,%rbx,4),%rbx
  call   <randm@plt>
  lea    0x0(%rbp,%rbp,4),%rdx
  lea    0x1(%rax,%rdx,4),%rbp
L13:
  shl    $0x2,%rbx
  mov    %rbp,%rdi
  mov    $0xffffffff,%ecx
  xor    %edx,%edx
  lea    -0x1(%rbx),%rsi
  call   <finish_path@plt>
  lea    -0x2(%rbx),%rsi
  mov    %rbp,%rdi
  pop    %rbx
  mov    $0x1,%ecx
  pop    %rbp
  xor    %edx,%edx
  pop    %r12
  jmp    1070 <finish_path@plt>
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    $0xf,%edi
  lea    0x5(%rbx,%rbx,4),%rbx
  call   <randm@plt>
  lea    0x0(%rbp,%rbp,4),%rdx
  lea    0x1(%rax,%rdx,4),%rbp
  jmp    L13
```

assistant: ```c
void connect_room(long ax, long ay, long dx, long dy) {
  long mx, my;
  if (dx < 0) {
    my = ay * 20 + 1 + randm(20 - 3 - 2);
    mx = ax * 20 - 1;
    finish_path(mx, my, -1, 0);
    mx = ax * 20 - 3 + 1;
    finish_path(mx, my, +1, 0);
  } else if (dx > 0) {
    my = ay * 20 + 1 + randm(20 - 3 - 2);
    mx = ax * 20 + 20 - 1;
    finish_path(mx, my, -1, 0);
    mx = ax * 20 + 20 - 3 + 1;
    finish_path(mx, my, +1, 0);
  } else if (dy < 0) {
    mx = ax * 20 + 1 + randm(20 - 3 - 2);
    my = ay * 20 - 1;
    finish_path(mx, my, 0, -1);
    my = ay * 20 - 3 + 1;
    finish_path(mx, my, 0, +1);
  } else if (dy > 0) {
    mx = ax * 20 + 1 + randm(20 - 3 - 2);
    my = ay * 20 + 20 - 1;
    finish_path(mx, my, 0, -1);
    my = ay * 20 + 20 - 3 + 1;
    finish_path(mx, my, 0, +1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<connect_room>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rdx,%rdx
  js     L38
  jne    L54
  test   %rcx,%rcx
  js     L50
  jne    L53
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L54:
  mov    $0xf,%edi
  call   <randm@plt>
  lea    (%rbx,%rbx,4),%rdx
  lea    0x5(%rbp,%rbp,4),%rbx
  lea    0x1(%rax,%rdx,4),%r12
L59:
  shl    $0x2,%rbx
  mov    %r12,%rsi
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  lea    -0x1(%rbx),%rdi
  call   <finish_path@plt>
  lea    -0x2(%rbx),%rdi
  mov    %r12,%rsi
  pop    %rbx
  xor    %ecx,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <finish_path@plt>
  xchg   %ax,%ax
L38:
  mov    $0xf,%edi
  call   <randm@plt>
  lea    (%rbx,%rbx,4),%rdx
  lea    0x0(%rbp,%rbp,4),%rbx
  lea    0x1(%rax,%rdx,4),%r12
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L50:
  mov    $0xf,%edi
  lea    (%rbx,%rbx,4),%rbx
  call   <randm@plt>
  lea    0x0(%rbp,%rbp,4),%rdx
  lea    0x1(%rax,%rdx,4),%rbp
L33:
  shl    $0x2,%rbx
  mov    %rbp,%rdi
  mov    $0xffffffff,%ecx
  xor    %edx,%edx
  lea    -0x1(%rbx),%rsi
  call   <finish_path@plt>
  lea    -0x2(%rbx),%rsi
  mov    %rbp,%rdi
  pop    %rbx
  mov    $0x1,%ecx
  pop    %rbp
  xor    %edx,%edx
  pop    %r12
  jmp    1070 <finish_path@plt>
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    $0xf,%edi
  lea    0x5(%rbx,%rbx,4),%rbx
  call   <randm@plt>
  lea    0x0(%rbp,%rbp,4),%rdx
  lea    0x1(%rax,%rdx,4),%rbp
  jmp    L33
```

assistant: ```c
void connect_room(long ax, long ay, long dx, long dy) {
  long mx, my;
  if (dx < 0) {
    my = ay * 20 + 1 + randm(20 - 3 - 2);
    mx = ax * 20 - 1;
    finish_path(mx, my, -1, 0);
    mx = ax * 20 - 3 + 1;
    finish_path(mx, my, +1, 0);
  } else if (dx > 0) {
    my = ay * 20 + 1 + randm(20 - 3 - 2);
    mx = ax * 20 + 20 - 1;
    finish_path(mx, my, -1, 0);
    mx = ax * 20 + 20 - 3 + 1;
    finish_path(mx, my, +1, 0);
  } else if (dy < 0) {
    mx = ax * 20 + 1 + randm(20 - 3 - 2);
    my = ay * 20 - 1;
    finish_path(mx, my, 0, -1);
    my = ay * 20 - 3 + 1;
    finish_path(mx, my, 0, +1);
  } else if (dy > 0) {
    mx = ax * 20 + 1 + randm(20 - 3 - 2);
    my = ay * 20 + 20 - 1;
    finish_path(mx, my, 0, -1);
    my = ay * 20 + 20 - 3 + 1;
    finish_path(mx, my, 0, +1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L4:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L13:
  cmpl   $0x2,-0x8(%rbp)
  jg     L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
L28:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hash(const char str[], int mod) {
  int i, h;
  i = 1;
  h = str[0];
  while ((i < 3) && (str[i] != '\0')) {
    h = (h * 256 + (unsigned char)str[i]) % mod;
    i++;
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%ecx
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L10
  shl    $0x8,%ecx
  movzbl %al,%eax
  add    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%ecx
  movzbl 0x2(%rdi),%eax
  test   %al,%al
  je     L10
  shl    $0x8,%edx
  movzbl %al,%eax
  add    %edx,%eax
  cltd
  idiv   %esi
  mov    %edx,%ecx
L10:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int hash(const char str[], int mod) {
  int i, h;
  i = 1;
  h = str[0];
  while ((i < 3) && (str[i] != '\0')) {
    h = (h * 256 + (unsigned char)str[i]) % mod;
    i++;
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movsbl (%rdi),%edx
  test   %al,%al
  je     L12
  shl    $0x8,%edx
  add    %edx,%eax
  cltd
  idiv   %esi
  movzbl 0x2(%rdi),%eax
  test   %al,%al
  je     L12
  shl    $0x8,%edx
  add    %edx,%eax
  cltd
  idiv   %esi
L12:
  mov    %edx,%eax
  ret
```

assistant: ```c
int hash(const char str[], int mod) {
  int i, h;
  i = 1;
  h = str[0];
  while ((i < 3) && (str[i] != '\0')) {
    h = (h * 256 + (unsigned char)str[i]) % mod;
    i++;
  }
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movsbl (%rdi),%edx
  test   %al,%al
  je     L5
  shl    $0x8,%edx
  add    %edx,%eax
  cltd
  idiv   %esi
  movzbl 0x2(%rdi),%eax
  test   %al,%al
  je     L5
  shl    $0x8,%edx
  add    %edx,%eax
  cltd
  idiv   %esi
L5:
  mov    %edx,%eax
  ret
```

assistant: ```c
int hash(const char str[], int mod) {
  int i, h;
  i = 1;
  h = str[0];
  while ((i < 3) && (str[i] != '\0')) {
    h = (h * 256 + (unsigned char)str[i]) % mod;
    i++;
  }
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L77
L39:
  movq   $0x0,-0x28(%rbp)
  movq   $0x1,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x3,-0x18(%rbp)
  movq   $0x3,-0x38(%rbp)
  jmp    L85
L2:
  movq   $0x1,-0x20(%rbp)
  movq   $0x2,-0x30(%rbp)
  jmp    L12
L10:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x30(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L88
  addq   $0x1,-0x20(%rbp)
L88:
  addq   $0x1,-0x30(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  shr    %rax
  cmp    %rax,-0x30(%rbp)
  jbe    L10
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L81
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L81:
  mov    -0x38(%rbp),%rax
  add    %rax,-0x18(%rbp)
  addq   $0x1,-0x38(%rbp)
L85:
  mov    -0x48(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jb     L2
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L77:
  mov    -0x40(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  test   %rax,%rax
  jne    L39
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
datatype: string
name: parse_data
arguments: tag: D7
datatype: string

tool: D12: %Lu

tool: D7: %Lu


assistant: ```c
int main() {
  unsigned long long N, T;
  scanf("%Lu", &T);
  while (T--) {
    unsigned long long i, j;
    unsigned long long answer = 0, divisor = 1, n;
    unsigned long long high_divisor = 0;
    scanf("%Lu", &N);
    for (n = 3, i = 3; high_divisor < N; n += i, i++) {
      divisor = 1;
      for (j = 2; j <= n / 2; j++) {
        if (n % j == 0) {
          divisor++;
        }
      }
      if (high_divisor < divisor) {
        answer = n;
        high_divisor = divisor;
      }
    }
    printf("%Lu\n", answer);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L51
  lea    0x8(%rsp),%r12
  lea    D22(%rip),%rbp
  mov    $0x1,%r13d
  lea    D25(%rip),%rbx
  jmp    L19
L78:
  mov    $0x1,%edi
  jmp    L67
L107:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L51
L19:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%r11
  mov    %r11,%r14
  test   %r11,%r11
  je     L107
  mov    $0x3,%esi
  mov    $0x3,%r9d
  mov    %r13,%r10
  mov    $0x3,%r14d
L24:
  add    %r9,%rsi
  add    $0x1,%r9
  cmp    %r11,%r10
  jae    L107
  mov    %rsi,%r8
  shr    %r8
  cmp    $0x3,%rsi
  jbe    L78
  mov    $0x1,%edi
  mov    $0x2,%ecx
L50:
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  cmp    $0x1,%rdx
  adc    $0x0,%rdi
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jbe    L50
L67:
  cmp    %r10,%rdi
  jbe    L24
  mov    %rdi,%r10
  mov    %rsi,%r14
  jmp    L24
L51:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D25
type: string

tool: D22: %Lu

tool: D25: %Lu


assistant: ```c
int main() {
  unsigned long long N, T;
  scanf("%Lu", &T);
  while (T--) {
    unsigned long long i, j;
    unsigned long long answer = 0, divisor = 1, n;
    unsigned long long high_divisor = 0;
    scanf("%Lu", &N);
    for (n = 3, i = 3; high_divisor < N; n += i, i++) {
      divisor = 1;
      for (j = 2; j <= n / 2; j++) {
        if (n % j == 0) {
          divisor++;
        }
      }
      if (high_divisor < divisor) {
        answer = n;
        high_divisor = divisor;
      }
    }
    printf("%Lu\n", answer);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L65
  lea    0x8(%rsp),%r12
  lea    D9(%rip),%rbp
  nopl   (%rax)
L52:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %r13d,%r13d
  call   <scanf@plt>
  mov    0x8(%rsp),%r11
  test   %r11,%r11
  je     L62
  xor    %r10d,%r10d
  mov    $0x3,%esi
  xor    %r13d,%r13d
  mov    $0x3,%r9d
L85:
  mov    $0x1,%edi
  cs nopw 0x0(%rax,%rax,1)
L14:
  cmp    %rdi,%r10
  jae    L69
  mov    %rdi,%r10
  mov    %rsi,%r13
L69:
  add    %r9,%rsi
  add    $0x1,%r9
  cmp    %r11,%r10
  jae    L62
  mov    %rsi,%r8
  shr    %r8
  cmp    $0x3,%rsi
  jbe    L85
  mov    $0x1,%edi
  mov    $0x2,%ecx
  nopl   (%rax)
L71:
  xor    %edx,%edx
  mov    %rsi,%rax
  div    %rcx
  lea    0x1(%rcx),%rax
  cmp    $0x1,%rdx
  adc    $0x0,%rdi
  cmp    %rcx,%r8
  je     L14
  mov    %rax,%rcx
  jmp    L71
  xchg   %ax,%ax
L62:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L52
L65:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
datatype: string
name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D16: %Lu

tool: D9: %Lu


assistant: ```c
int main() {
  unsigned long long N, T;
  scanf("%Lu", &T);
  while (T--) {
    unsigned long long i, j;
    unsigned long long answer = 0, divisor = 1, n;
    unsigned long long high_divisor = 0;
    scanf("%Lu", &N);
    for (n = 3, i = 3; high_divisor < N; n += i, i++) {
      divisor = 1;
      for (j = 2; j <= n / 2; j++) {
        if (n % j == 0) {
          divisor++;
        }
      }
      if (high_divisor < divisor) {
        answer = n;
        high_divisor = divisor;
      }
    }
    printf("%Lu\n", answer);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L86
  lea    0x8(%rsp),%r12
  lea    D14(%rip),%rbp
  nopl   (%rax)
L38:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %r13d,%r13d
  call   <scanf@plt>
  mov    0x8(%rsp),%r11
  test   %r11,%r11
  je     L25
  xor    %r10d,%r10d
  mov    $0x3,%esi
  xor    %r13d,%r13d
  mov    $0x3,%r9d
L28:
  mov    $0x1,%edi
  cs nopw 0x0(%rax,%rax,1)
L82:
  cmp    %rdi,%r10
  jae    L32
  mov    %rdi,%r10
  mov    %rsi,%r13
L32:
  add    %r9,%rsi
  add    $0x1,%r9
  cmp    %r11,%r10
  jae    L25
  mov    %rsi,%r8
  shr    %r8
  cmp    $0x3,%rsi
  jbe    L28
  mov    $0x1,%edi
  mov    $0x2,%ecx
  nopl   (%rax)
L18:
  xor    %edx,%edx
  mov    %rsi,%rax
  div    %rcx
  lea    0x1(%rcx),%rax
  cmp    $0x1,%rdx
  adc    $0x0,%rdi
  cmp    %r8,%rcx
  je     L82
  mov    %rax,%rcx
  jmp    L18
  xchg   %ax,%ax
L25:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L38
L86:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D14
type: string

tool: D18: %Lu

tool: D14: %Lu


assistant: ```c
int main() {
  unsigned long long N, T;
  scanf("%Lu", &T);
  while (T--) {
    unsigned long long i, j;
    unsigned long long answer = 0, divisor = 1, n;
    unsigned long long high_divisor = 0;
    scanf("%Lu", &N);
    for (n = 3, i = 3; high_divisor < N; n += i, i++) {
      divisor = 1;
      for (j = 2; j <= n / 2; j++) {
        if (n % j == 0) {
          divisor++;
        }
      }
      if (high_divisor < divisor) {
        answer = n;
        high_divisor = divisor;
      }
    }
    printf("%Lu\n", answer);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D63
type: string
name: read_data
arguments: label: D67
type: string
name: read_data
arguments: label: D49
type: string
name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D8
type: string
name: read_data
arguments: label: D57
type: string
name: read_data
arguments: label: D1
type: string

tool: D63: 1. Fill array with numbers


tool: D67: 2. Find number in array


tool: D49: 3. Print array


tool: D3: 4. Find element closest to the average sum


tool: D8: 5. Load array from file


tool: D57: 6. Save array to file


tool: D1: 7. Exit


assistant: ```c
void print_menu() {
  printf("1. Fill array with numbers\n");
  printf("2. Find number in array\n");
  printf("3. Print array\n");
  printf("4. Find element closest to the average sum\n");
  printf("5. Load array from file\n");
  printf("6. Save array to file\n");
  printf("7. Exit\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D28
type_guessed: string
name: unpack_data
arguments: data_tag: D67
type_guessed: string
name: unpack_data
arguments: data_tag: D58
type_guessed: string
name: unpack_data
arguments: data_tag: D56
type_guessed: string
name: unpack_data
arguments: data_tag: D61
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D66
type_guessed: string

tool: D28: 1. Fill array with numbers


tool: D67: 2. Find number in array


tool: D58: 3. Print array


tool: D56: 4. Find element closest to the average sum


tool: D61: 5. Load array from file


tool: D12: 6. Save array to file


tool: D66: 7. Exit


assistant: ```c
void print_menu() {
  printf("1. Fill array with numbers\n");
  printf("2. Find number in array\n");
  printf("3. Print array\n");
  printf("4. Find element closest to the average sum\n");
  printf("5. Load array from file\n");
  printf("6. Save array to file\n");
  printf("7. Exit\n");
}
```