user: What would the C source look like for the assembly code provided here?

```asm
<standard_interactive_input_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x368,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38c(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38c(%rbp),%eax
  mov    %eax,%edi
  call   <syscon_initialize_number_of_standard_polynomials@plt>
  mov    %eax,-0x374(%rbp)
  mov    -0x38c(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x388(%rbp)
  jmp    L34
L73:
  mov    -0x388(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x38d(%rbp)
  lea    -0x360(%rbp),%rdx
  lea    -0x384(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read_poly@plt>
  mov    -0x388(%rbp),%edx
  mov    -0x38c(%rbp),%esi
  mov    -0x384(%rbp),%eax
  lea    -0x360(%rbp),%rcx
  mov    %eax,%edi
  call   <syscon_store_standard_polynomial@plt>
  mov    %eax,-0x374(%rbp)
  mov    -0x388(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x388(%rbp)
L34:
  mov    -0x388(%rbp),%edx
  mov    -0x38c(%rbp),%eax
  cmp    %eax,%edx
  jle    L73
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <syscon_write_standard_system@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x378(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x378(%rbp),%edx
  lea    -0x380(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <solve_system@plt>
  mov    %eax,-0x374(%rbp)
  mov    -0x380(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L15:
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x388(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x388(%rbp),%eax
  test   %eax,%eax
  js     L29
  mov    -0x388(%rbp),%eax
  lea    -0x37c(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <solcon_length_standard_solution_string@plt>
  mov    %eax,-0x374(%rbp)
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x37c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x370(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%ecx
  mov    $0x0,%edx
  div    %rcx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L27:
  cmp    %rdx,%rsp
  je     L39
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L27
L39:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L35
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L35:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x368(%rbp)
  mov    -0x37c(%rbp),%ecx
  mov    -0x388(%rbp),%eax
  mov    -0x368(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <solcon_write_standard_solution_string@plt>
  mov    %eax,-0x374(%rbp)
  mov    -0x388(%rbp),%eax
  mov    -0x368(%rbp),%rdx
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsp
  mov    -0x388(%rbp),%eax
  test   %eax,%eax
  jns    L15
  jmp    L59
L29:
  nop
L59:
  mov    -0x374(%rbp),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string
name: disassemble_data
arguments: data_label: D61
datatype: string
name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D77
datatype: string
name: disassemble_data
arguments: data_label: D7
datatype: string
name: disassemble_data
arguments: data_label: D70
datatype: string
name: disassemble_data
arguments: data_label: D53
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: string
name: disassemble_data
arguments: data_label: D82
datatype: string
name: disassemble_data
arguments: data_label: D84
datatype: string
name: disassemble_data
arguments: data_label: D47
datatype: string

tool: D2: 
Give the number of polynomials in the system : 

tool: D61: %d

tool: D21: 
Reading %d polynomials, 

tool: D77: terminate each with ; (semicolon)...

tool: D7: -> polynomial %d : 

tool: D70: The system in the container : 

tool: D53: 
Give the number of tasks : 

tool: D27: 
The root count : %d


tool: D82: interactive selection of solutions... 

tool: D84: 
Give an index to a solution (-1 to exit) : 

tool: D47: 
Solution %d : 
%s

assistant: ```c
int standard_interactive_input_output(void) {
  int n, fail, k, nc, i, rc, len, nbtasks;
  char ch, p[800];
  printf("\nGive the number of polynomials in the system : ");
  scanf("%d", &n);
  fail = syscon_initialize_number_of_standard_polynomials(n);
  printf("\nReading %d polynomials, ", n);
  printf("terminate each with ; (semicolon)...\n");
  for (k = 1; k <= n; k++) {
    printf("-> polynomial %d : ", k);
    ch = getchar();
    read_poly(&nc, p);
    fail = syscon_store_standard_polynomial(nc, n, k, p);
  }
  printf("The system in the container : \n");
  syscon_write_standard_system();
  printf("\nGive the number of tasks : ");
  scanf("%d", &nbtasks);
  fail = solve_system(&rc, nbtasks);
  printf("\nThe root count : %d\n", rc);
  printf("interactive selection of solutions... \n");
  do {
    printf("\nGive an index to a solution (-1 to exit) : ");
    scanf("%d", &k);
    if (k < 0)
      break;
    fail = solcon_length_standard_solution_string(k, &len);
    {
      char s[len];
      fail = solcon_write_standard_solution_string(k, len, s);
      printf("\nSolution %d : \n%s", k, s);
    }
  } while (k >= 0);
  return fail;
}
```