ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<minorm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rcx),%r14d
  test   %r14d,%r14d
  jle    L24
  lea    -0x2(%rcx),%eax
  mov    %edx,%r8d
  mov    %esi,%r11d
  mov    $0xfffffffffffffffc,%rbp
  mov    %rdi,%rbx
  lea    0x1(%r11),%r12d
  lea    0x1(%r8),%r9d
  xor    %r10d,%r10d
  lea    0x0(,%rax,4),%rdx
  imul   $0xcc,%rax,%rax
  lea    0x4(%rsp,%rdx,1),%rsi
  sub    %rdx,%rbp
  lea    0xcc(%rsp,%rax,1),%r13
  nopl   0x0(%rax,%rax,1)
L19:
  cmp    %r10d,%r11d
  lea    0x0(%rbp,%rsi,1),%rdx
  cmove  %r12d,%r10d
  movslq %r10d,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rbx,%rax,8),%rdi
  xor    %eax,%eax
  nopl   (%rax)
L13:
  cmp    %eax,%r8d
  cmove  %r9d,%eax
  add    $0x4,%rdx
  movslq %eax,%rcx
  add    $0x1,%eax
  movss  (%rdi,%rcx,4),%xmm0
  movss  %xmm0,-0x4(%rdx)
  cmp    %rsi,%rdx
  jne    L13
  add    $0xc8,%rsi
  add    $0x1,%r10d
  cmp    %r13,%rsi
  jne    L19
L24:
  mov    %rsp,%rdi
  mov    %r14d,%esi
  call   <determinant@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x2720,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float minorm(float arr[50][50], int row, int col, int order) {
  float result;
  int i, j, a, b;
  float auxarr[50][50];
  order = order - 1;
  i = j = 0;
  for (a = 0; a < order; a++) {
    j = 0;
    if (i == row)
      i++;
    for (b = 0; b < order; b++) {
      if (j == col)
        j++;
      auxarr[a][b] = arr[i][j];
      j++;
    }
    i++;
  }
  result = determinant(auxarr, order);
  return (result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<minorm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rcx),%r14d
  test   %r14d,%r14d
  jle    L26
  lea    -0x2(%rcx),%eax
  mov    %edx,%r8d
  mov    %esi,%r11d
  mov    $0xfffffffffffffffc,%rbp
  mov    %rdi,%rbx
  lea    0x1(%r11),%r12d
  lea    0x1(%r8),%r9d
  xor    %r10d,%r10d
  lea    0x0(,%rax,4),%rdx
  imul   $0xcc,%rax,%rax
  lea    0x4(%rsp,%rdx,1),%rsi
  sub    %rdx,%rbp
  lea    0xcc(%rsp,%rax,1),%r13
  nopl   0x0(%rax,%rax,1)
L37:
  cmp    %r10d,%r11d
  lea    0x0(%rbp,%rsi,1),%rdx
  cmove  %r12d,%r10d
  movslq %r10d,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rbx,%rax,8),%rdi
  xor    %eax,%eax
  nopl   (%rax)
L29:
  cmp    %eax,%r8d
  cmove  %r9d,%eax
  add    $0x4,%rdx
  movslq %eax,%rcx
  add    $0x1,%eax
  movss  (%rdi,%rcx,4),%xmm0
  movss  %xmm0,-0x4(%rdx)
  cmp    %rsi,%rdx
  jne    L29
  add    $0xc8,%rsi
  add    $0x1,%r10d
  cmp    %r13,%rsi
  jne    L37
L26:
  mov    %rsp,%rdi
  mov    %r14d,%esi
  call   <determinant@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x2720,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float minorm(float arr[50][50], int row, int col, int order) {
  float result;
  int i, j, a, b;
  float auxarr[50][50];
  order = order - 1;
  i = j = 0;
  for (a = 0; a < order; a++) {
    j = 0;
    if (i == row)
      i++;
    for (b = 0; b < order; b++) {
      if (j == col)
        j++;
      auxarr[a][b] = arr[i][j];
      j++;
    }
    i++;
  }
  result = determinant(auxarr, order);
  return (result);
}
```
user: What is the c source code of the assembly code below:

```asm
<string_equal_ignore_case>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <string_empty@plt>
  test   %eax,%eax
  jne    L14
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <string_empty@plt>
  test   %eax,%eax
  jne    L14
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L23
L14:
  mov    $0x1,%eax
L23:
  leave
  ret
```

assistant: ```c
int string_equal_ignore_case(const char *string, const char *other_string) {
  if (!string_empty(string) && !string_empty(other_string))
    return !strcasecmp(string, other_string);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<string_equal_ignore_case>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <string_empty@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L21
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    %rbp,%rdi
  call   <string_empty@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L25
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L25
```

assistant: ```c
int string_equal_ignore_case(const char *string, const char *other_string) {
  if (!string_empty(string) && !string_empty(other_string))
    return !strcasecmp(string, other_string);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_equal_ignore_case>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <string_empty@plt>
  test   %eax,%eax
  je     L1
L14:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdi
  call   <string_empty@plt>
  test   %eax,%eax
  jne    L14
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int string_equal_ignore_case(const char *string, const char *other_string) {
  if (!string_empty(string) && !string_empty(other_string))
    return !strcasecmp(string, other_string);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_equal_ignore_case>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <string_empty@plt>
  test   %eax,%eax
  je     L19
L3:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rdi
  call   <string_empty@plt>
  test   %eax,%eax
  jne    L3
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int string_equal_ignore_case(const char *string, const char *other_string) {
  if (!string_empty(string) && !string_empty(other_string))
    return !strcasecmp(string, other_string);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inner_password_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %ecx,-0x7c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x54(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x54(%rbp),%edx
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x50(%rbp)
  mov    -0x68(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x70(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L36:
  cmp    %rdx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L18:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L28
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L28:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <SHA512@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  mov    -0x7c(%rbp),%ecx
  mov    -0x78(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <base64_encode@plt>
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void inner_password_hash(const char *password, const char *salt, char *hash, int hash_len) {
  int pw_len = strlen(password);
  char *combined = (char *)malloc(pw_len + strlen(salt) + 1);
  strcpy(combined, password);
  strcpy(combined + pw_len, salt);
  unsigned char raw_hash[SHA512_DIGEST_LENGTH];
  SHA512((unsigned char *)combined, strlen(combined), raw_hash);
  base64_encode(raw_hash, SHA512_DIGEST_LENGTH, hash, hash_len);
  free(combined);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<inner_password_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movslq %ebx,%rdi
  add    %r12,%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  mov    D19(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L28:
  cmp    %rdx,%rsp
  je     L35
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L28
L35:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L23
  orq    $0x0,-0x8(%rsp,%rax,1)
L23:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rsp,%rdx
  mov    %r12,%rdi
  call   <SHA512@plt>
  mov    %r15d,%ecx
  mov    -0x48(%rbp),%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  mov    %rsp,%rdi
  call   <base64_encode@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void inner_password_hash(const char *password, const char *salt, char *hash, int hash_len) {
  int pw_len = strlen(password);
  char *combined = (char *)malloc(pw_len + strlen(salt) + 1);
  strcpy(combined, password);
  strcpy(combined + pw_len, salt);
  unsigned char raw_hash[SHA512_DIGEST_LENGTH];
  SHA512((unsigned char *)combined, strlen(combined), raw_hash);
  base64_encode(raw_hash, SHA512_DIGEST_LENGTH, hash, hash_len);
  free(combined);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inner_password_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movslq %ebx,%rdi
  mov    %r15,%rsi
  add    %r12,%rdi
  call   <strcpy@plt>
  mov    D1(%rip),%rbx
  mov    %rsp,%rcx
  movslq (%rbx),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L11
L2:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L2
L11:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L48
L30:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rsp,%rdx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <SHA512@plt>
  mov    -0x48(%rbp),%rdx
  mov    (%rbx),%esi
  mov    %rsp,%rdi
  mov    %r14d,%ecx
  call   <base64_encode@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L30
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void inner_password_hash(const char *password, const char *salt, char *hash, int hash_len) {
  int pw_len = strlen(password);
  char *combined = (char *)malloc(pw_len + strlen(salt) + 1);
  strcpy(combined, password);
  strcpy(combined + pw_len, salt);
  unsigned char raw_hash[SHA512_DIGEST_LENGTH];
  SHA512((unsigned char *)combined, strlen(combined), raw_hash);
  base64_encode(raw_hash, SHA512_DIGEST_LENGTH, hash, hash_len);
  free(combined);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inner_password_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movslq %ebx,%rdi
  mov    %r15,%rsi
  add    %r12,%rdi
  call   <strcpy@plt>
  mov    D0(%rip),%rbx
  mov    %rsp,%rcx
  movslq (%rbx),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L16
L44:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L44
L16:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L36
L8:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rsp,%rdx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <SHA512@plt>
  mov    -0x48(%rbp),%rdx
  mov    (%rbx),%esi
  mov    %rsp,%rdi
  mov    %r14d,%ecx
  call   <base64_encode@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L8
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void inner_password_hash(const char *password, const char *salt, char *hash, int hash_len) {
  int pw_len = strlen(password);
  char *combined = (char *)malloc(pw_len + strlen(salt) + 1);
  strcpy(combined, password);
  strcpy(combined + pw_len, salt);
  unsigned char raw_hash[SHA512_DIGEST_LENGTH];
  SHA512((unsigned char *)combined, strlen(combined), raw_hash);
  base64_encode(raw_hash, SHA512_DIGEST_LENGTH, hash, hash_len);
  free(combined);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x20(%rbp),%xmm0
  movss  -0x28(%rbp),%xmm1
  divss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%edi
  call   <log@plt>
  movd   %xmm0,%ebx
  movss  -0x24(%rbp),%xmm1
  movss  D30(%rip),%xmm0
  subss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%edi
  call   <log@plt>
  movaps %xmm0,%xmm1
  movd   %ebx,%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x24(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jbe    L10
  pxor   %xmm2,%xmm2
  cvtss2sd -0x1c(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L11
L10:
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L11:
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D33
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D30
type: byte[4]
name: retrieve_data
arguments: data_tag: D11
type: string
name: retrieve_data
arguments: data_tag: D40
type: string

tool: D33: Enter the Values of C D P: 

tool: D17: %f %f %f

tool: {"D30": [0x00,0x00,0x80,0x3f]}

tool: D11: N: %.4f 


tool: D40: Sry.. No such Value 

assistant: ```c
int main() {
  float c, d, n, p;
  printf("Enter the Values of C D P: ");
  scanf("%f %f %f", &c, &d, &p);
  n = log(p / c) / log(1 - d);
  if (d > 0)
    printf("N: %.4f \n", n);
  else
    printf("Sry.. No such Value \n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movss  0x24(%rsp),%xmm0
  divss  0x1c(%rsp),%xmm0
  cvttss2si %xmm0,%edi
  call   <log@plt>
  movss  %xmm0,0xc(%rsp)
  movss  D21(%rip),%xmm0
  subss  0x20(%rsp),%xmm0
  cvttss2si %xmm0,%edi
  call   <log@plt>
  movss  0x20(%rsp),%xmm1
  comiss D41(%rip),%xmm1
  jbe    L26
  movss  0xc(%rsp),%xmm1
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  lea    D1(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L8:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L26:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  jmp    L8
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D44
data_type: string
name: read_data
arguments: data_label: D15
data_type: string
name: read_data
arguments: data_label: D21
data_type: byte[4]
name: read_data
arguments: data_label: D41
data_type: byte[4]
name: read_data
arguments: data_label: D1
data_type: string
name: read_data
arguments: data_label: D5
data_type: string

tool: D44: Enter the Values of C D P: 

tool: D15: %f %f %f

tool: {"D21": [0x00,0x00,0x80,0x3f]}

tool: {"D41": [0x00,0x00,0x00,0x00]}

tool: D1: N: %.4f 


tool: D5: Sry.. No such Value 

assistant: ```c
int main() {
  float c, d, n, p;
  printf("Enter the Values of C D P: ");
  scanf("%f %f %f", &c, &d, &p);
  n = log(p / c) / log(1 - d);
  if (d > 0)
    printf("N: %.4f \n", n);
  else
    printf("Sry.. No such Value \n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D26(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  divss  0xc(%rsp),%xmm0
  cvttss2si %xmm0,%edi
  call   <log@plt>
  movd   %xmm0,%ebx
  movss  D49(%rip),%xmm0
  subss  0x10(%rsp),%xmm0
  cvttss2si %xmm0,%edi
  call   <log@plt>
  movaps %xmm0,%xmm1
  movss  0x10(%rsp),%xmm0
  comiss D56(%rip),%xmm0
  jbe    L26
  movd   %ebx,%xmm0
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L26:
  lea    D47(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D26
type: string
name: parse_data
arguments: tag: D35
type: string
name: parse_data
arguments: tag: D49
type: byte[4]
name: parse_data
arguments: tag: D56
type: byte[4]
name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D47
type: string

tool: D26: Enter the Values of C D P: 

tool: D35: %f %f %f

tool: {"D49": [0x00,0x00,0x80,0x3f]}

tool: {"D56": [0x00,0x00,0x00,0x00]}

tool: D16: N: %.4f 


tool: D47: Sry.. No such Value 

assistant: ```c
int main() {
  float c, d, n, p;
  printf("Enter the Values of C D P: ");
  scanf("%f %f %f", &c, &d, &p);
  n = log(p / c) / log(1 - d);
  if (d > 0)
    printf("N: %.4f \n", n);
  else
    printf("Sry.. No such Value \n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D51(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  divss  0xc(%rsp),%xmm0
  cvttss2si %xmm0,%edi
  call   <log@plt>
  movd   %xmm0,%ebx
  movss  D27(%rip),%xmm0
  subss  0x10(%rsp),%xmm0
  cvttss2si %xmm0,%edi
  call   <log@plt>
  movaps %xmm0,%xmm1
  movss  0x10(%rsp),%xmm0
  comiss D17(%rip),%xmm0
  jbe    L28
  movd   %ebx,%xmm0
  lea    D50(%rip),%rdi
  mov    $0x1,%eax
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L28:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L15
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D51
type_infered: string
name: read_data
arguments: tag: D24
type_infered: string
name: read_data
arguments: tag: D27
type_infered: byte[4]
name: read_data
arguments: tag: D17
type_infered: byte[4]
name: read_data
arguments: tag: D50
type_infered: string
name: read_data
arguments: tag: D18
type_infered: string

tool: D51: Enter the Values of C D P: 

tool: D24: %f %f %f

tool: {"D27": [0x00,0x00,0x80,0x3f]}

tool: {"D17": [0x00,0x00,0x00,0x00]}

tool: D50: N: %.4f 


tool: D18: Sry.. No such Value 

assistant: ```c
int main() {
  float c, d, n, p;
  printf("Enter the Values of C D P: ");
  scanf("%f %f %f", &c, &d, &p);
  n = log(p / c) / log(1 - d);
  if (d > 0)
    printf("N: %.4f \n", n);
  else
    printf("Sry.. No such Value \n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<putword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void putword(unsigned char *p, int a) {
  p[0] = a;
  p[1] = a >> 8;
}
```