ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L214
  lea    -0x1(%rdi),%edx
  mov    %rsi,%rax
  mov    $0x1,%edi
  lea    0x8(%rsi,%rdx,8),%rcx
  jmp    L148
  nopw   0x0(%rax,%rax,1)
L176:
  test   %dl,%dl
  je     L126
  add    $0x8,%rax
  cmp    %rax,%rcx
  je     L46
L148:
  mov    (%rax),%rdx
  movzbl (%rdx),%edx
  cmp    $0x2d,%dl
  jne    L176
L126:
  add    $0x8,%rax
  xor    %edi,%edi
  cmp    %rax,%rcx
  jne    L148
L46:
  test   %edi,%edi
  jne    L214
  mov    D2(%rip),%r13
  mov    %rsp,%rbp
  nopl   (%rax)
L163:
  mov    0x0(%r13),%edi
  mov    $0x1000,%edx
  mov    %rbp,%rsi
  mov    %r12d,%ebx
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L163
L15:
  lea    0x1(%rsp),%rsi
  test   $0x7,%bl
  je     L114
  nopl   0x0(%rax)
L160:
  movslq %ebx,%rcx
  mov    %rbp,%rax
  add    %rsi,%rcx
  test   %ebx,%ebx
  jns    L11
  jmp    L178
  nopw   0x0(%rax,%rax,1)
L100:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L178
L11:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L187
  cmp    $0xa,%dl
  jne    L100
L187:
  movb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L11
L178:
  add    $0x1,%ebx
  test   $0x7,%bl
  jne    L160
  xor    %edi,%edi
  call   <printHandler@plt>
  test   %ebx,%ebx
  jle    L12
  nopl   0x0(%rax)
L52:
  mov    %rbp,%rdi
  sub    $0x8,%ebx
  call   <conversionManager@plt>
  test   %ebx,%ebx
  jg     L52
L12:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L172
  add    $0x1018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L214:
  mov    D5(%rip),%rax
  mov    0x8(%rsi),%rdi
  mov    %rsp,%rbp
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%r13d
  nopw   0x0(%rax,%rax,1)
L180:
  mov    $0x1000,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    %r12d,%ebx
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L180
  mov    %r13d,%edi
  call   <close@plt>
  jmp    L15
L114:
  xor    %edi,%edi
  call   <printHandler@plt>
  jmp    L52
L172:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char buffer[4096];
  int charCount;
  int n;
  int status = 1;
  int i;
  for (i = 0; i < argc; i++) {
    if (*argv[i] == '-' || *argv[i] == '\0')
      status = 0;
  }
  if (status) {
    int file_descriptor = open(argv[1], O_RDONLY);
    while ((n = read(file_descriptor, buffer, 4096)) > 0) {
      charCount = n;
    }
    close(file_descriptor);
  } else {
    while ((n = read(STDIN_FILENO, buffer, 4096)) > 0) {
      charCount = n;
    }
  }
  while ((charCount % 8) != 0) {
    int i;
    for (i = 0; i <= charCount; i++) {
      if (buffer[i] == '\0' || buffer[i] == '\n')
        buffer[i] = '0';
    }
    charCount++;
  }
  printHandler(0);
  while (charCount >= 1) {
    conversionManager(buffer);
    charCount = charCount - 8;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L66
  lea    -0x1(%rdi),%edx
  mov    %rsi,%rax
  mov    $0x1,%edi
  lea    0x8(%rsi,%rdx,8),%rcx
  jmp    L212
  nopw   0x0(%rax,%rax,1)
L46:
  cmp    $0x2d,%dl
  je     L149
  add    $0x8,%rax
  cmp    %rax,%rcx
  je     L79
L212:
  mov    (%rax),%rdx
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L46
L149:
  add    $0x8,%rax
  xor    %edi,%edi
  cmp    %rax,%rcx
  jne    L212
L79:
  test   %edi,%edi
  jne    L66
  mov    D11(%rip),%r13
  mov    %rsp,%rbp
  nopl   (%rax)
L189:
  mov    0x0(%r13),%edi
  mov    $0x1000,%edx
  mov    %rbp,%rsi
  mov    %r12d,%ebx
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L189
L42:
  lea    0x1(%rsp),%rsi
  test   $0x7,%bl
  je     L163
  nopl   0x0(%rax)
L53:
  movslq %ebx,%rcx
  mov    %rbp,%rax
  add    %rsi,%rcx
  test   %ebx,%ebx
  jns    L176
  jmp    L207
  nopw   0x0(%rax,%rax,1)
L175:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L207
L176:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L118
  cmp    $0xa,%dl
  jne    L175
L118:
  movb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L176
L207:
  add    $0x1,%ebx
  test   $0x7,%bl
  jne    L53
  xor    %edi,%edi
  call   <printHandler@plt>
  test   %ebx,%ebx
  jle    L30
  nopl   0x0(%rax)
L72:
  mov    %rbp,%rdi
  sub    $0x8,%ebx
  call   <conversionManager@plt>
  test   %ebx,%ebx
  jg     L72
L30:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  add    $0x1018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  mov    D5(%rip),%rax
  mov    0x8(%rsi),%rdi
  mov    %rsp,%rbp
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%r13d
  nopw   0x0(%rax,%rax,1)
L206:
  mov    $0x1000,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    %r12d,%ebx
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L206
  mov    %r13d,%edi
  call   <close@plt>
  jmp    L42
L163:
  xor    %edi,%edi
  call   <printHandler@plt>
  jmp    L72
L92:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char buffer[4096];
  int charCount;
  int n;
  int status = 1;
  int i;
  for (i = 0; i < argc; i++) {
    if (*argv[i] == '-' || *argv[i] == '\0')
      status = 0;
  }
  if (status) {
    int file_descriptor = open(argv[1], O_RDONLY);
    while ((n = read(file_descriptor, buffer, 4096)) > 0) {
      charCount = n;
    }
    close(file_descriptor);
  } else {
    while ((n = read(STDIN_FILENO, buffer, 4096)) > 0) {
      charCount = n;
    }
  }
  while ((charCount % 8) != 0) {
    int i;
    for (i = 0; i <= charCount; i++) {
      if (buffer[i] == '\0' || buffer[i] == '\n')
        buffer[i] = '0';
    }
    charCount++;
  }
  printHandler(0);
  while (charCount >= 1) {
    conversionManager(buffer);
    charCount = charCount - 8;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <f@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main(void) {
  int p = 5;
  int q = 6;
  return f(&p, &q);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x6,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <f@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int p = 5;
  int q = 6;
  return f(&p, &q);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x5,(%rsp)
  movl   $0x6,0x4(%rsp)
  call   <f@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int p = 5;
  int q = 6;
  return f(&p, &q);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x5,(%rsp)
  movl   $0x6,0x4(%rsp)
  call   <f@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int p = 5;
  int q = 6;
  return f(&p, &q);
}
```
user: What is the c source code of the assembly code below?

```asm
<libkeccak_state_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <libkeccak_state_destroy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((__optimize__("-O0"))) void libkeccak_state_free(volatile struct libkeccak_state *restrict state) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wcast-qual"
  libkeccak_state_destroy(state);
  free((struct libkeccak_state *)state);
#pragma GCC diagnostic pop
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<libkeccak_state_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <libkeccak_state_destroy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((__optimize__("-O0"))) void libkeccak_state_free(volatile struct libkeccak_state *restrict state) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wcast-qual"
  libkeccak_state_destroy(state);
  free((struct libkeccak_state *)state);
#pragma GCC diagnostic pop
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<libkeccak_state_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <libkeccak_state_destroy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((__optimize__("-O0"))) void libkeccak_state_free(volatile struct libkeccak_state *restrict state) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wcast-qual"
  libkeccak_state_destroy(state);
  free((struct libkeccak_state *)state);
#pragma GCC diagnostic pop
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<libkeccak_state_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <libkeccak_state_destroy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((__optimize__("-O0"))) void libkeccak_state_free(volatile struct libkeccak_state *restrict state) {
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wcast-qual"
  libkeccak_state_destroy(state);
  free((struct libkeccak_state *)state);
#pragma GCC diagnostic pop
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_label>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L26
  mov    $0xffffffff,%eax
  jmp    L20
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L52
  mov    $0xffffffff,%eax
  jmp    L20
L52:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    $0x0,%eax
L20:
  leave
  ret
```

assistant: ```c
int check_label(char *str) {
  if (!isalpha(*str) && *str != '_')
    return -1;
  while (*str != '\0') {
    if (isspace(*str))
      return -1;
    str++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_label>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L28
  movzbl (%rbx),%edi
  mov    $0x0,%eax
  test   %dil,%dil
  jne    L47
  jmp    L10
L28:
  movzbl (%rbx),%edi
  cmp    $0x5f,%dil
  jne    L56
L47:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L53
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L47
  jmp    L10
L56:
  mov    $0xffffffff,%eax
  jmp    L10
L53:
  mov    $0xffffffff,%eax
L10:
  pop    %rbx
  ret
```

assistant: ```c
int check_label(char *str) {
  if (!isalpha(*str) && *str != '_')
    return -1;
  while (*str != '\0') {
    if (isspace(*str))
      return -1;
    str++;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_label>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  movsbl (%rbx),%edi
  test   %eax,%eax
  jne    L29
  cmp    $0x5f,%dil
  jne    L15
  nopl   (%rax)
L38:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L29:
  test   %dil,%dil
  jne    L38
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int check_label(char *str) {
  if (!isalpha(*str) && *str != '_')
    return -1;
  while (*str != '\0') {
    if (isspace(*str))
      return -1;
    str++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_label>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  movsbl (%rbx),%edi
  test   %eax,%eax
  jne    L6
  cmp    $0x5f,%dil
  jne    L16
  nopl   (%rax)
L13:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L16
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L6:
  test   %dil,%dil
  jne    L13
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int check_label(char *str) {
  if (!isalpha(*str) && *str != '_')
    return -1;
  while (*str != '\0') {
    if (isspace(*str))
      return -1;
    str++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BRBase58CheckEncode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,%r14
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x20(%rcx),%r15
  cmp    $0x1000,%r15
  jbe    L60
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x50(%rbp)
L30:
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r14,%r14
  setne  %r13b
  test   %rbx,%rbx
  sete   %al
  or     %eax,%r13d
  movzbl %r13b,%edi
  call   <assert@plt>
  movq   $0x0,-0x48(%rbp)
  test   %r13b,%r13b
  jne    L76
L25:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <mem_clean@plt>
  cmp    -0x50(%rbp),%r12
  je     L14
  mov    %r12,%rdi
  call   <free@plt>
L14:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    -0x48(%rbp),%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L76:
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,4),%rdi
  mov    %rbx,%rdx
  mov    %r14,%rsi
  call   <BRSHA256_2@plt>
  lea    0x4(%rbx),%rcx
  mov    %r12,%rdx
  mov    -0x60(%rbp),%rsi
  mov    -0x58(%rbp),%rdi
  call   <BRBase58Encode@plt>
  mov    %rax,-0x48(%rbp)
  jmp    L25
L60:
  lea    0xf(,%r15,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L28:
  cmp    %rdx,%rsp
  je     L2
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L28
L2:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L81
  orq    $0x0,-0x8(%rsp,%rax,1)
L81:
  mov    %rsp,%rax
  mov    %rax,%r12
  mov    %rax,-0x50(%rbp)
  jmp    L30
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t BRBase58CheckEncode(char *str, size_t strLen, const uint8_t *data, size_t dataLen) {
  size_t len = 0, bufLen = dataLen + 256 / 8;
  uint8_t _buf[(bufLen <= 0x1000) ? bufLen : 0], *buf = (bufLen <= 0x1000) ? _buf : malloc(bufLen);
  assert(buf != NULL);
  assert(data != NULL || dataLen == 0);
  if (data || dataLen == 0) {
    memcpy(buf, data, dataLen);
    BRSHA256_2(&buf[dataLen], data, dataLen);
    len = BRBase58Encode(str, strLen, buf, dataLen + 4);
  }
  mem_clean(buf, bufLen);
  if (buf != _buf)
    free(buf);
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BRBase58CheckEncode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    0x20(%rcx),%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  cmp    $0x1000,%r14
  jbe    L45
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x50(%rbp)
L33:
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  test   %r12,%r12
  setne  %dl
  test   %rbx,%rbx
  sete   %al
  xor    %r15d,%r15d
  or     %eax,%edx
  movzbl %dl,%edi
  mov    %dl,-0x41(%rbp)
  call   <assert@plt>
  movzbl -0x41(%rbp),%edx
  test   %dl,%dl
  jne    L0
L46:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <mem_clean@plt>
  cmp    -0x50(%rbp),%r13
  je     L62
  mov    %r13,%rdi
  call   <free@plt>
L62:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  lea    -0x28(%rbp),%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  lea    0xf(,%r14,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L10
L63:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L63
L10:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L38
  orq    $0x0,-0x8(%rsp,%rdx,1)
L38:
  mov    %rsp,%r13
  mov    %r13,-0x50(%rbp)
  jmp    L33
  nopl   (%rax)
L0:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  lea    0x0(%r13,%rbx,4),%rdi
  mov    %rbx,%rdx
  mov    %r12,%rsi
  call   <BRSHA256_2@plt>
  mov    -0x60(%rbp),%rsi
  mov    -0x58(%rbp),%rdi
  mov    %r13,%rdx
  lea    0x4(%rbx),%rcx
  call   <BRBase58Encode@plt>
  mov    %rax,%r15
  jmp    L46
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t BRBase58CheckEncode(char *str, size_t strLen, const uint8_t *data, size_t dataLen) {
  size_t len = 0, bufLen = dataLen + 256 / 8;
  uint8_t _buf[(bufLen <= 0x1000) ? bufLen : 0], *buf = (bufLen <= 0x1000) ? _buf : malloc(bufLen);
  assert(buf != NULL);
  assert(data != NULL || dataLen == 0);
  if (data || dataLen == 0) {
    memcpy(buf, data, dataLen);
    BRSHA256_2(&buf[dataLen], data, dataLen);
    len = BRBase58Encode(str, strLen, buf, dataLen + 4);
  }
  mem_clean(buf, bufLen);
  if (buf != _buf)
    free(buf);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BRBase58CheckEncode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    0x20(%rcx),%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  cmp    $0x1000,%r14
  jbe    L64
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x50(%rbp)
L7:
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  test   %r12,%r12
  setne  %dl
  test   %rbx,%rbx
  sete   %al
  xor    %r15d,%r15d
  or     %eax,%edx
  movzbl %dl,%edi
  mov    %dl,-0x41(%rbp)
  call   <assert@plt>
  movzbl -0x41(%rbp),%edx
  test   %dl,%dl
  jne    L19
L48:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <mem_clean@plt>
  cmp    -0x50(%rbp),%r13
  je     L60
  mov    %r13,%rdi
  call   <free@plt>
L60:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  lea    -0x28(%rbp),%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  lea    0xf(,%r14,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L63
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L4
L63:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L86
  orq    $0x0,-0x8(%rsp,%rdx,1)
L86:
  mov    %rsp,%r13
  mov    %r13,-0x50(%rbp)
  jmp    L7
  nopl   (%rax)
L19:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  lea    0x0(%r13,%rbx,4),%rdi
  mov    %rbx,%rdx
  mov    %r12,%rsi
  call   <BRSHA256_2@plt>
  mov    -0x60(%rbp),%rsi
  mov    -0x58(%rbp),%rdi
  mov    %r13,%rdx
  lea    0x4(%rbx),%rcx
  call   <BRBase58Encode@plt>
  mov    %rax,%r15
  jmp    L48
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t BRBase58CheckEncode(char *str, size_t strLen, const uint8_t *data, size_t dataLen) {
  size_t len = 0, bufLen = dataLen + 256 / 8;
  uint8_t _buf[(bufLen <= 0x1000) ? bufLen : 0], *buf = (bufLen <= 0x1000) ? _buf : malloc(bufLen);
  assert(buf != NULL);
  assert(data != NULL || dataLen == 0);
  if (data || dataLen == 0) {
    memcpy(buf, data, dataLen);
    BRSHA256_2(&buf[dataLen], data, dataLen);
    len = BRBase58Encode(str, strLen, buf, dataLen + 4);
  }
  mem_clean(buf, bufLen);
  if (buf != _buf)
    free(buf);
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timespec_subtract_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L9
  addq   $0x3b9aca00,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  imul   $0xf4240,%rax,%rsi
  mov    -0x8(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  add    %rsi,%rax
  pop    %rbp
  ret
```

assistant: ```c
long long timespec_subtract_us(struct timespec *x, struct timespec *y) {
  long long sec, nsec;
  sec = x->tv_sec - y->tv_sec;
  nsec = x->tv_nsec - y->tv_nsec;
  if (nsec < 0) {
    nsec += 1000000000;
    sec--;
  }
  return sec * 1000000 + nsec / 1000;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timespec_subtract_us>:
  endbr64
  mov    %rsi,%rax
  mov    (%rdi),%rdx
  sub    (%rsi),%rdx
  mov    0x8(%rdi),%rsi
  sub    0x8(%rax),%rsi
  js     L10
L12:
  imul   $0xf4240,%rdx,%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x7,%rdx
  sar    $0x3f,%rsi
  sub    %rsi,%rdx
  lea    (%rcx,%rdx,1),%rax
  ret
L10:
  add    $0x3b9aca00,%rsi
  sub    $0x1,%rdx
  jmp    L12
```

assistant: ```c
long long timespec_subtract_us(struct timespec *x, struct timespec *y) {
  long long sec, nsec;
  sec = x->tv_sec - y->tv_sec;
  nsec = x->tv_nsec - y->tv_nsec;
  if (nsec < 0) {
    nsec += 1000000000;
    sec--;
  }
  return sec * 1000000 + nsec / 1000;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<timespec_subtract_us>:
  endbr64
  mov    %rsi,%rax
  mov    (%rdi),%rdx
  sub    (%rsi),%rdx
  mov    0x8(%rdi),%rsi
  sub    0x8(%rax),%rsi
  jns    L9
  add    $0x3b9aca00,%rsi
  sub    $0x1,%rdx
L9:
  imul   $0xf4240,%rdx,%rcx
  mov    %rsi,%rax
  sar    $0x3f,%rsi
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   %rdx
  sar    $0x7,%rdx
  sub    %rsi,%rdx
  lea    (%rcx,%rdx,1),%rax
  ret
```

assistant: ```c
long long timespec_subtract_us(struct timespec *x, struct timespec *y) {
  long long sec, nsec;
  sec = x->tv_sec - y->tv_sec;
  nsec = x->tv_nsec - y->tv_nsec;
  if (nsec < 0) {
    nsec += 1000000000;
    sec--;
  }
  return sec * 1000000 + nsec / 1000;
}
```