user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L160:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L160
  sub    $0x138,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4128(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x15ac,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x15c0(%rsp),%rdi
  mov    $0x15ac,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x2b70(%rsp),%rdi
  mov    $0x15ac,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x0,%r15d
  mov    $0x0,%ebx
  mov    $0x64,%ebp
  jmp    L195
L43:
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L43
  mov    %ebp,%eax
  sub    %ecx,%eax
  lea    0x1(%rbx,%rax,1),%rbx
L261:
  add    $0x1,%ecx
  sub    $0x1,%edx
  cmp    $0x65,%ecx
  je     L91
L82:
  mov    $0x0,%eax
  cmp    $0x64,%ecx
  jle    L43
  jmp    L261
L91:
  add    $0x1,%esi
  cmp    $0x65,%esi
  je     L189
L9:
  cmp    $0x64,%esi
  jg     L91
  mov    %edi,%edx
  sub    %esi,%edx
  mov    %esi,%ecx
  jmp    L82
L189:
  add    $0x1,%r8d
  cmp    $0x65,%r8d
  je     L2
L32:
  mov    %r8d,%esi
  cmp    $0x64,%r8d
  jle    L9
  jmp    L189
L2:
  lea    0x1(%r10),%edx
  lea    0x1(%r12),%eax
  cmp    $0x64,%eax
  jg     L225
  mov    %edx,%r10d
  mov    %eax,%r12d
L262:
  cmp    $0x64,%r12d
  jg     L2
  mov    %r12d,%r8d
  jmp    L32
L225:
  sub    %r10d,%r12d
L218:
  lea    0x1(%r9),%edx
  lea    0x1(%r12),%eax
  cmp    $0x64,%eax
  jg     L172
  mov    %edx,%r9d
  mov    %eax,%r12d
L30:
  mov    %r11d,%r10d
  cmp    $0x64,%r12d
  jle    L262
  jmp    L218
L172:
  mov    %r12d,%eax
  sub    %r9d,%eax
L79:
  lea    0x1(%rax),%r12d
  add    $0x1,%r13
  cmp    $0x64,%r12d
  jg     L157
L227:
  mov    %r13d,0xc(%rsp)
  mov    %rbx,%rdx
  mov    %r13,%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%r9d
  mov    $0x0,%r11d
  mov    $0x65,%edi
  mov    %r12d,%eax
  cmp    $0x64,%r12d
  jle    L30
  jmp    L79
L157:
  sub    0xc(%rsp),%eax
  mov    %eax,%r12d
L197:
  add    $0x1,%r12d
  add    $0x1,%r14
  cmp    $0x64,%r12d
  jg     L129
L20:
  mov    %r14,%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x64,%r12d
  jg     L197
  mov    $0x0,%r13d
  jmp    L227
L129:
  add    $0x1,%r15
  cmp    $0x65,%r15
  je     L209
L195:
  mov    %r15d,%r12d
  mov    %r15,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x64,%r15d
  jg     L129
  mov    $0x0,%r14d
  jmp    L20
L209:
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L125
  mov    $0x0,%eax
  add    $0x4138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L125:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D36
type_guessed: string
name: unpack_data
arguments: data_label: D35
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string
name: unpack_data
arguments: data_label: D28
type_guessed: string

tool: D36:  kk = %d count %ld


tool: D35:  jj = %d


tool: D3: ii = %d


tool: D28: Looped %ld times


assistant: ```c
int main(int argc, char **argv) {
  int army_w[1387];
  int army_l[1387];
  int army_d[1387];
  memset(army_w, 0, sizeof(army_w));
  memset(army_l, 0, sizeof(army_l));
  memset(army_d, 0, sizeof(army_d));
  int ii = 0;
  int jj = 0;
  int kk = 0;
  int ll = 0;
  int mm = 0;
  int nn = 0;
  int oo = 0;
  int pp = 0;
  int qq = 0;
  int rr = 0;
  long long count = 0;
  for (ii = 0; ii < 101; ii++) {
    int arm = ii;
    printf("ii = %d\n", ii);
    for (jj = 0; jj + arm < 101; jj++) {
      printf(" jj = %d\n", jj);
      arm += jj;
      for (kk = 0; kk + arm < 101; kk++) {
        printf(" kk = %d count %ld\n", kk, count);
        arm += kk;
        for (ll = 0; ll + arm < 101; ll++) {
          arm += ll;
          for (mm = 0; mm + arm < 101; mm++) {
            arm += mm;
            for (nn = 0; nn + arm < 101; nn++) {
              arm += nn;
              for (oo = 0; oo + arm < 101; oo++) {
                arm += oo;
                for (pp = 0; pp + arm < 101; pp++) {
                  arm += pp;
                  for (qq = 0; qq + arm < 101; qq++) {
                    arm += qq;
                    rr = 100 - arm;
                    count++;
                    arm -= qq;
                  }
                  arm -= pp;
                }
                arm -= oo;
              }
              arm -= nn;
            }
            arm -= mm;
          }
          arm -= ll;
        }
        arm -= kk;
      }
      arm -= jj;
    }
  }
  printf("Looped %ld times\n", count);
}
```