ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<check_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  movzbl (%rsi),%eax
  mov    %rdi,%rbx
  test   %al,%al
  je     L112
L68:
  cmp    %al,(%rbx)
  jne    L36
  add    $0x1,%rbx
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L68
L112:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L40
  cmpb   $0x3d,(%rbx)
  jne    L24
  jmp    L40
L36:
  test   %al,%al
  je     L112
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  add    $0x1,%rbx
L40:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L58
  cmpb   $0x3d,(%rbx)
  jne    L24
L65:
  add    $0x1,%rbx
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L65
  cmpb   $0x0,(%rbx)
  je     L24
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x5c,-0x1(%r12,%rax,1)
  jne    L24
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L24
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: 
setparams: Error in file make.def. Because of the way in which
           command line arguments are incorporated into the
           executable benchmark, you can't have any continued
           lines in the file make.def, that is, lines ending
           with the character "\". Although it may be ugly, 
           you should be able to reformat without continuation
           lines. The offending line is
  %s


assistant: ```c
void check_line(char *line, char *label, char *val) {
  char *original_line;
  original_line = line;
  while (*label != '\0' && *line == *label) {
    line++;
    label++;
  }
  if (*label != '\0')
    return;
  if (!isspace(*line) && *line != '=')
    return;
  while (isspace(*line))
    line++;
  if (*line != '=')
    return;
  while (isspace(*++line))
    ;
  if (*line == '\0')
    return;
  strcpy(val, line);
  val[strlen(val) - 1] = '\0';
  if (val[strlen(val) - 1] == '\\') {
    printf("\nsetparams: Error in file make.def. Because of the way in which\n           command line arguments are incorporated into the\n           executable benchmark, you can't have any continued\n           lines in the file make.def, that is, lines ending\n           with the character \"\\\". Although it may be ugly, \n           you should be able to reformat without continuation\n           lines. The offending line is\n  %s\n", original_line);
    exit(1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_line>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rsi),%eax
  mov    %rdx,%rbx
  test   %al,%al
  jne    L63
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L78:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  add    $0x1,%rbp
  test   %al,%al
  je     L27
L63:
  cmp    %al,0x0(%rbp)
  je     L78
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L105
  movsbl 0x0(%rbp),%edi
  cmp    $0x3d,%dil
  je     L77
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L7:
  add    $0x1,%rbp
L105:
  movsbl 0x0(%rbp),%edi
L77:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
  cmpb   $0x3d,0x0(%rbp)
  jne    L38
  nopl   0x0(%rax,%rax,1)
L5:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  cmpb   $0x0,0x0(%rbp)
  je     L38
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  call   <strlen@plt>
  cltq
  cmpb   $0x5c,-0x1(%rbx,%rax,1)
  jne    L38
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    10d0 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: 
setparams: Error in file make.def. Because of the way in which
           command line arguments are incorporated into the
           executable benchmark, you can't have any continued
           lines in the file make.def, that is, lines ending
           with the character "\". Although it may be ugly, 
           you should be able to reformat without continuation
           lines. The offending line is
  %s


assistant: ```c
void check_line(char *line, char *label, char *val) {
  char *original_line;
  original_line = line;
  while (*label != '\0' && *line == *label) {
    line++;
    label++;
  }
  if (*label != '\0')
    return;
  if (!isspace(*line) && *line != '=')
    return;
  while (isspace(*line))
    line++;
  if (*line != '=')
    return;
  while (isspace(*++line))
    ;
  if (*line == '\0')
    return;
  strcpy(val, line);
  val[strlen(val) - 1] = '\0';
  if (val[strlen(val) - 1] == '\\') {
    printf("\nsetparams: Error in file make.def. Because of the way in which\n           command line arguments are incorporated into the\n           executable benchmark, you can't have any continued\n           lines in the file make.def, that is, lines ending\n           with the character \"\\\". Although it may be ugly, \n           you should be able to reformat without continuation\n           lines. The offending line is\n  %s\n", original_line);
    exit(1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_line>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rsi),%eax
  mov    %rdx,%rbx
  test   %al,%al
  jne    L27
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L80:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  add    $0x1,%rbp
  test   %al,%al
  je     L22
L27:
  cmp    %al,0x0(%rbp)
  je     L80
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L36
  cmpb   $0x3d,0x0(%rbp)
  je     L36
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L91:
  add    $0x1,%rbp
L36:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L91
  cmpb   $0x3d,0x0(%rbp)
  jne    L53
  nopl   0x0(%rax,%rax,1)
L41:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
  cmpb   $0x0,0x0(%rbp)
  je     L53
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  call   <strlen@plt>
  cltq
  cmpb   $0x5c,-0x1(%rbx,%rax,1)
  jne    L53
  mov    %r12,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    10d0 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: 
setparams: Error in file make.def. Because of the way in which
           command line arguments are incorporated into the
           executable benchmark, you can't have any continued
           lines in the file make.def, that is, lines ending
           with the character "\". Although it may be ugly, 
           you should be able to reformat without continuation
           lines. The offending line is
  %s


assistant: ```c
void check_line(char *line, char *label, char *val) {
  char *original_line;
  original_line = line;
  while (*label != '\0' && *line == *label) {
    line++;
    label++;
  }
  if (*label != '\0')
    return;
  if (!isspace(*line) && *line != '=')
    return;
  while (isspace(*line))
    line++;
  if (*line != '=')
    return;
  while (isspace(*++line))
    ;
  if (*line == '\0')
    return;
  strcpy(val, line);
  val[strlen(val) - 1] = '\0';
  if (val[strlen(val) - 1] == '\\') {
    printf("\nsetparams: Error in file make.def. Because of the way in which\n           command line arguments are incorporated into the\n           executable benchmark, you can't have any continued\n           lines in the file make.def, that is, lines ending\n           with the character \"\\\". Although it may be ugly, \n           you should be able to reformat without continuation\n           lines. The offending line is\n  %s\n", original_line);
    exit(1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movb   $0x0,-0x11(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L27
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L11
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x38(%rbp)
L27:
  cmpq   $0x0,-0x38(%rbp)
  jne    L9
  jmp    L4
L11:
  nop
L4:
  movsbl -0x11(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *p1, const void *p2, size_t c) {
  const unsigned char *su1, *su2;
  signed char res = 0;
  for (su1 = p1, su2 = p2; 0 < c; ++su1, ++su2, c--) {
    if ((res = *su1 - *su2) != 0) {
      break;
    }
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L23
  mov    $0x0,%ecx
L19:
  movzbl (%rdi,%rcx,1),%eax
  sub    (%rsi,%rcx,1),%al
  jne    L3
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L19
L3:
  movsbl %al,%eax
  ret
L23:
  mov    $0x0,%eax
  jmp    L3
```

assistant: ```c
int memcmp(const void *p1, const void *p2, size_t c) {
  const unsigned char *su1, *su2;
  signed char res = 0;
  for (su1 = p1, su2 = p2; 0 < c; ++su1, ++su2, c--) {
    if ((res = *su1 - *su2) != 0) {
      break;
    }
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L19
  xor    %ecx,%ecx
  jmp    L32
  nopl   (%rax)
L11:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L19
L32:
  movzbl (%rdi,%rcx,1),%eax
  sub    (%rsi,%rcx,1),%al
  je     L11
  movsbl %al,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *p1, const void *p2, size_t c) {
  const unsigned char *su1, *su2;
  signed char res = 0;
  for (su1 = p1, su2 = p2; 0 < c; ++su1, ++su2, c--) {
    if ((res = *su1 - *su2) != 0) {
      break;
    }
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L27
  xor    %ecx,%ecx
  jmp    L30
  nopl   (%rax)
L5:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L27
L30:
  movzbl (%rdi,%rcx,1),%eax
  sub    (%rsi,%rcx,1),%al
  je     L5
  movsbl %al,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *p1, const void *p2, size_t c) {
  const unsigned char *su1, *su2;
  signed char res = 0;
  for (su1 = p1, su2 = p2; 0 < c; ++su1, ++su2, c--) {
    if ((res = *su1 - *su2) != 0) {
      break;
    }
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1234564e,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: %d	 0x%x	%c


assistant: ```c
int main() {
  int a, *ap;
  char *bp;
  a = 305419854;
  ap = &a;
  bp = (char *)ap;
  printf("%d\t 0x%x\t%c\n", a, *ap, *bp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4e,%ecx
  mov    $0x1234564e,%edx
  mov    $0x1234564e,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: %d	 0x%x	%c


assistant: ```c
int main() {
  int a, *ap;
  char *bp;
  a = 305419854;
  ap = &a;
  bp = (char *)ap;
  printf("%d\t 0x%x\t%c\n", a, *ap, *bp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4e,%ecx
  mov    $0x1234564e,%edx
  mov    $0x1234564e,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: %d	 0x%x	%c


assistant: ```c
int main() {
  int a, *ap;
  char *bp;
  a = 305419854;
  ap = &a;
  bp = (char *)ap;
  printf("%d\t 0x%x\t%c\n", a, *ap, *bp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4e,%ecx
  mov    $0x1234564e,%edx
  mov    $0x1234564e,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d	 0x%x	%c


assistant: ```c
int main() {
  int a, *ap;
  char *bp;
  a = 305419854;
  ap = &a;
  bp = (char *)ap;
  printf("%d\t 0x%x\t%c\n", a, *ap, *bp);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0x2cdb,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L13
L31:
  movw   $0x0,-0xe(%rbp)
  jmp    L25
L12:
  movzwl -0xa(%rbp),%edx
  movzwl -0xe(%rbp),%eax
  or     -0xc(%rbp),%ax
  cmp    %ax,%dx
  ja     L45
  movzwl -0xe(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  mov    %eax,%edx
  movzwl -0xe(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %eax,%edx
  movzwl -0xe(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  jmp    L4
L45:
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  shl    $0x4,%eax
  and    $0x3f0,%ax
  or     %eax,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
L4:
  movzwl -0xe(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xe(%rbp)
L25:
  cmpw   $0x0,-0xe(%rbp)
  je     L12
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L13:
  cmpw   $0x0,-0xc(%rbp)
  je     L31
  movzwl -0xa(%rbp),%eax
  shl    $0x5,%eax
  or     $0xc520,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] <= (local2 | local1)) {
          state[local2] |= (state[local2] & (unsigned short)15) << 2UL;
        } else {
          state[local1] |= (state[0UL] & (unsigned short)63) << 4UL;
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 608351785UL) << (unsigned short)5;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x2cdb,%ax
  je     L8
  mov    %eax,%edx
  shl    $0x4,%edx
  and    $0x3f0,%dx
  or     %edx,%eax
L8:
  shl    $0x5,%eax
  or     $0xc520,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] <= (local2 | local1)) {
          state[local2] |= (state[local2] & (unsigned short)15) << 2UL;
        } else {
          state[local1] |= (state[0UL] & (unsigned short)63) << 4UL;
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 608351785UL) << (unsigned short)5;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  add    $0x2cdb,%dx
  je     L6
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0x3f0,%ax
  or     %edx,%eax
  shl    $0x5,%eax
  or     $0xc520,%ax
  mov    %ax,(%rsi)
  ret
L6:
  mov    $0xffffc520,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] <= (local2 | local1)) {
          state[local2] |= (state[local2] & (unsigned short)15) << 2UL;
        } else {
          state[local1] |= (state[0UL] & (unsigned short)63) << 4UL;
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 608351785UL) << (unsigned short)5;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  add    $0x2cdb,%dx
  je     L3
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0x3f0,%ax
  or     %edx,%eax
  shl    $0x5,%eax
  or     $0xc520,%ax
  mov    %ax,(%rsi)
  ret
L3:
  mov    $0xffffc520,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] <= (local2 | local1)) {
          state[local2] |= (state[local2] & (unsigned short)15) << 2UL;
        } else {
          state[local1] |= (state[0UL] & (unsigned short)63) << 4UL;
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 608351785UL) << (unsigned short)5;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findPixelAcrossScales>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <conv1D2Drow@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <conv1D2Dcol@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x34(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x2c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <conv2D1D@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int findPixelAcrossScales(int ref_rowcol, int ref_nX, int tgt_nX, int ref_nX_o_tgt_nX, int ref_nY_o_tgt_nY) {
  int ref_row = conv1D2Drow(ref_nX, ref_rowcol);
  int ref_col = conv1D2Dcol(ref_row, ref_rowcol);
  int tgt_col = (int)(ref_col / ref_nX_o_tgt_nX);
  int tgt_row = (int)(ref_row / ref_nY_o_tgt_nY);
  int tgt_rowcol = conv2D1D(tgt_nX, tgt_col, tgt_row);
  return (tgt_rowcol);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<findPixelAcrossScales>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %esi,%edi
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    %r8d,%r13d
  mov    %r14d,%esi
  call   <conv1D2Drow@plt>
  mov    %eax,%ebx
  mov    %r14d,%esi
  mov    %eax,%edi
  call   <conv1D2Dcol@plt>
  mov    %eax,%esi
  mov    %ebx,%eax
  cltd
  idiv   %r13d
  mov    %eax,%ebx
  mov    %esi,%eax
  cltd
  idiv   %r12d
  mov    %eax,%esi
  mov    %ebx,%edx
  mov    %ebp,%edi
  call   <conv2D1D@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int findPixelAcrossScales(int ref_rowcol, int ref_nX, int tgt_nX, int ref_nX_o_tgt_nX, int ref_nY_o_tgt_nY) {
  int ref_row = conv1D2Drow(ref_nX, ref_rowcol);
  int ref_col = conv1D2Dcol(ref_row, ref_rowcol);
  int tgt_col = (int)(ref_col / ref_nX_o_tgt_nX);
  int tgt_row = (int)(ref_row / ref_nY_o_tgt_nY);
  int tgt_rowcol = conv2D1D(tgt_nX, tgt_col, tgt_row);
  return (tgt_rowcol);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findPixelAcrossScales>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %edi,%r13d
  mov    %esi,%edi
  push   %r12
  mov    %r13d,%esi
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <conv1D2Drow@plt>
  mov    %r13d,%esi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <conv1D2Dcol@plt>
  mov    %r14d,%edi
  mov    %eax,%r9d
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  mov    %eax,%r12d
  mov    %r9d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  mov    %r12d,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  mov    %eax,%esi
  jmp    1090 <conv2D1D@plt>
```

assistant: ```c
int findPixelAcrossScales(int ref_rowcol, int ref_nX, int tgt_nX, int ref_nX_o_tgt_nX, int ref_nY_o_tgt_nY) {
  int ref_row = conv1D2Drow(ref_nX, ref_rowcol);
  int ref_col = conv1D2Dcol(ref_row, ref_rowcol);
  int tgt_col = (int)(ref_col / ref_nX_o_tgt_nX);
  int tgt_row = (int)(ref_row / ref_nY_o_tgt_nY);
  int tgt_rowcol = conv2D1D(tgt_nX, tgt_col, tgt_row);
  return (tgt_rowcol);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findPixelAcrossScales>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %edi,%r13d
  mov    %esi,%edi
  push   %r12
  mov    %r13d,%esi
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <conv1D2Drow@plt>
  mov    %r13d,%esi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <conv1D2Dcol@plt>
  mov    %r14d,%edi
  mov    %eax,%r9d
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  mov    %eax,%r12d
  mov    %r9d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  mov    %r12d,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  mov    %eax,%esi
  jmp    1090 <conv2D1D@plt>
```

assistant: ```c
int findPixelAcrossScales(int ref_rowcol, int ref_nX, int tgt_nX, int ref_nX_o_tgt_nX, int ref_nY_o_tgt_nY) {
  int ref_row = conv1D2Drow(ref_nX, ref_rowcol);
  int ref_col = conv1D2Dcol(ref_row, ref_rowcol);
  int tgt_col = (int)(ref_col / ref_nX_o_tgt_nX);
  int tgt_row = (int)(ref_row / ref_nY_o_tgt_nY);
  int tgt_rowcol = conv2D1D(tgt_nX, tgt_col, tgt_row);
  return (tgt_rowcol);
}
```