ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sys_cpu_pstate>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  lea    D36(%rip),%rdi
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  mov    %r13,%rsi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <fopen@plt>
  test   %rax,%rax
  je     L4
  mov    %r14d,%edx
  lea    D4(%rip),%r14
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    %r14,%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rsi
  lea    D40(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rsi
  lea    D23(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
  xor    %edx,%edx
  test   %ebx,%ebx
  mov    %r14,%rsi
  mov    %rax,%rdi
  sete   %dl
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D40
type: string
name: parse_data
arguments: label: D23
type: string

tool: D36: /sys/devices/system/cpu/intel_pstate/min_perf_pct

tool: D0: w

tool: D4: %i


tool: D40: /sys/devices/system/cpu/intel_pstate/max_perf_pct

tool: D23: /sys/devices/system/cpu/intel_pstate/no_turbo

assistant: ```c
int sys_cpu_pstate(int min, int max, int turbo) {
  FILE *f;
  f = fopen("/sys/devices/system/cpu/intel_pstate/min_perf_pct", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", min);
  fclose(f);
  f = fopen("/sys/devices/system/cpu/intel_pstate/max_perf_pct", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", max);
  fclose(f);
  f = fopen("/sys/devices/system/cpu/intel_pstate/no_turbo", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", turbo ? 0 : 1);
  fclose(f);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sys_cpu_pstate>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  lea    D37(%rip),%rdi
  push   %r13
  lea    D36(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  mov    %r13,%rsi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <fopen@plt>
  test   %rax,%rax
  je     L8
  mov    %r14d,%edx
  lea    D38(%rip),%r14
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    %r14,%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rsi
  lea    D24(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rsi
  lea    D4(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
  xor    %edx,%edx
  test   %ebx,%ebx
  mov    %r14,%rsi
  mov    %rax,%rdi
  sete   %dl
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D37
data_type: string
name: unpack_data
arguments: data_label: D36
data_type: string
name: unpack_data
arguments: data_label: D38
data_type: string
name: unpack_data
arguments: data_label: D24
data_type: string
name: unpack_data
arguments: data_label: D4
data_type: string

tool: D37: /sys/devices/system/cpu/intel_pstate/min_perf_pct

tool: D36: w

tool: D38: %i


tool: D24: /sys/devices/system/cpu/intel_pstate/max_perf_pct

tool: D4: /sys/devices/system/cpu/intel_pstate/no_turbo

assistant: ```c
int sys_cpu_pstate(int min, int max, int turbo) {
  FILE *f;
  f = fopen("/sys/devices/system/cpu/intel_pstate/min_perf_pct", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", min);
  fclose(f);
  f = fopen("/sys/devices/system/cpu/intel_pstate/max_perf_pct", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", max);
  fclose(f);
  f = fopen("/sys/devices/system/cpu/intel_pstate/no_turbo", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", turbo ? 0 : 1);
  fclose(f);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_clog_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *_clog_basename(const char *path) {
  const char *slash = strrchr(path, '/');
  if (slash) {
    path = slash + 1;
  }
  return path;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_clog_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *_clog_basename(const char *path) {
  const char *slash = strrchr(path, '/');
  if (slash) {
    path = slash + 1;
  }
  return path;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_clog_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *_clog_basename(const char *path) {
  const char *slash = strrchr(path, '/');
  if (slash) {
    path = slash + 1;
  }
  return path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_clog_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *_clog_basename(const char *path) {
  const char *slash = strrchr(path, '/');
  if (slash) {
    path = slash + 1;
  }
  return path;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ebur128_get_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ebur128_get_version(int *major, int *minor, int *patch) {
  *major = 1;
  *minor = 0;
  *patch = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ebur128_get_version>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0x0,(%rsi)
  movl   $0x1,(%rdx)
  ret
```

assistant: ```c
void ebur128_get_version(int *major, int *minor, int *patch) {
  *major = 1;
  *minor = 0;
  *patch = 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ebur128_get_version>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0x0,(%rsi)
  movl   $0x1,(%rdx)
  ret
```

assistant: ```c
void ebur128_get_version(int *major, int *minor, int *patch) {
  *major = 1;
  *minor = 0;
  *patch = 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<ebur128_get_version>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0x0,(%rsi)
  movl   $0x1,(%rdx)
  ret
```

assistant: ```c
void ebur128_get_version(int *major, int *minor, int *patch) {
  *major = 1;
  *minor = 0;
  *patch = 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ReverseSegment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L6
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ReverseSegment(char *start, char *end) {
  char temp;
  while (start < end) {
    temp = *start;
    *start = *end;
    *end = temp;
    start++;
    end--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ReverseSegment>:
  endbr64
  cmp    %rsi,%rdi
  jae    L4
L3:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  add    $0x1,%rdi
  sub    $0x1,%rsi
  cmp    %rsi,%rdi
  jb     L3
L4:
  ret
```

assistant: ```c
void ReverseSegment(char *start, char *end) {
  char temp;
  while (start < end) {
    temp = *start;
    *start = *end;
    *end = temp;
    start++;
    end--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ReverseSegment>:
  endbr64
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L7:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  add    $0x1,%rdi
  sub    $0x1,%rsi
  mov    %dl,-0x1(%rdi)
  mov    %al,0x1(%rsi)
L8:
  cmp    %rsi,%rdi
  jb     L7
  ret
```

assistant: ```c
void ReverseSegment(char *start, char *end) {
  char temp;
  while (start < end) {
    temp = *start;
    *start = *end;
    *end = temp;
    start++;
    end--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ReverseSegment>:
  endbr64
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  add    $0x1,%rdi
  sub    $0x1,%rsi
  mov    %dl,-0x1(%rdi)
  mov    %al,0x1(%rsi)
L1:
  cmp    %rsi,%rdi
  jb     L19
  ret
```

assistant: ```c
void ReverseSegment(char *start, char *end) {
  char temp;
  while (start < end) {
    temp = *start;
    *start = *end;
    *end = temp;
    start++;
    end--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_get_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L12:
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L12
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L12
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <ft_str_space_dup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ft_get_word(char *str) {
  char *copy;
  int i;
  i = 0;
  while (str[i] == ' ' || str[i] == '\t')
    i++;
  copy = ft_str_space_dup(str + i);
  return (copy);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_get_word>:
  endbr64
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L12
  cmp    $0x9,%al
  jne    L27
L12:
  lea    0x1(%rdi),%rax
L28:
  mov    %rax,%rdi
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L28
  cmp    $0x9,%dl
  je     L28
L27:
  call   <ft_str_space_dup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *ft_get_word(char *str) {
  char *copy;
  int i;
  i = 0;
  while (str[i] == ' ' || str[i] == '\t')
    i++;
  copy = ft_str_space_dup(str + i);
  return (copy);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_get_word>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L35
  cmp    $0x9,%al
  jne    L32
L35:
  lea    0x1(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L36:
  movzbl (%rax),%edx
  mov    %rax,%rdi
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L36
  cmp    $0x9,%dl
  je     L36
L32:
  jmp    1050 <ft_str_space_dup@plt>
```

assistant: ```c
char *ft_get_word(char *str) {
  char *copy;
  int i;
  i = 0;
  while (str[i] == ' ' || str[i] == '\t')
    i++;
  copy = ft_str_space_dup(str + i);
  return (copy);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_get_word>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L36
  cmp    $0x9,%al
  jne    L34
L36:
  lea    0x1(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl (%rax),%edx
  mov    %rax,%rdi
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L4
  cmp    $0x9,%dl
  je     L4
L34:
  jmp    1050 <ft_str_space_dup@plt>
```

assistant: ```c
char *ft_get_word(char *str) {
  char *copy;
  int i;
  i = 0;
  while (str[i] == ' ' || str[i] == '\t')
    i++;
  copy = ft_str_space_dup(str + i);
  return (copy);
}
```
user: Translate the below assembly code into C programming language:

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L5
L10:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L34
  mov    $0x0,%eax
  jmp    L13
L34:
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L10
  mov    $0x1,%eax
L13:
  leave
  ret
```

assistant: ```c
int isprime(int number) {
  int sqr, l;
  sqr = sqrt(number);
  for (l = 2; l <= sqr; l++)
    if (number % l == 0)
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isprime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L69
  mov    %eax,%esi
  test   $0x1,%bl
  je     L26
  mov    $0x2,%ecx
L58:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jl     L41
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L58
  jmp    L38
L41:
  mov    $0x1,%eax
L38:
  pop    %rbx
  ret
L69:
  mov    $0x1,%eax
  jmp    L38
L26:
  mov    $0x0,%eax
  jmp    L38
```

assistant: ```c
int isprime(int number) {
  int sqr, l;
  sqr = sqrt(number);
  for (l = 2; l <= sqr; l++)
    if (number % l == 0)
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isprime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L5
  test   $0x1,%r12b
  je     L23
  mov    %eax,%esi
  mov    $0x2,%ecx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L43
L35:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L14
L5:
  mov    $0x1,%edx
L43:
  mov    %edx,%eax
  pop    %r12
  ret
L23:
  xor    %edx,%edx
  jmp    L43
```

assistant: ```c
int isprime(int number) {
  int sqr, l;
  sqr = sqrt(number);
  for (l = 2; l <= sqr; l++)
    if (number % l == 0)
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<isprime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L8
  test   $0x1,%r12b
  je     L54
  mov    %eax,%esi
  mov    $0x2,%ecx
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L40
L6:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L39
L8:
  mov    $0x1,%edx
L40:
  mov    %edx,%eax
  pop    %r12
  ret
L54:
  xor    %edx,%edx
  jmp    L40
```

assistant: ```c
int isprime(int number) {
  int sqr, l;
  sqr = sqrt(number);
  for (l = 2; l <= sqr; l++)
    if (number % l == 0)
      return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int alloc(int n) {
  (void)malloc(n);
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <malloc@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int alloc(int n) {
  (void)malloc(n);
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <malloc@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int alloc(int n) {
  (void)malloc(n);
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<matrix_eye>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L19:
  movl   $0x0,-0x4(%rbp)
  jmp    L44
L51:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L17
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  D6(%rip),%xmm0
  movss  %xmm0,(%rax)
  jmp    L1
L17:
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
L1:
  addl   $0x1,-0x4(%rbp)
L44:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L51
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void matrix_eye(float *A, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++) {
      if (i == j)
        A[n * i + j] = 1;
      else
        A[n * i + j] = 0;
    }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix_eye>:
  endbr64
  test   %esi,%esi
  jle    L37
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  movss  D9(%rip),%xmm0
  jmp    L63
L0:
  lea    (%rax,%r8,1),%edx
  movslq %edx,%rdx
  movss  %xmm0,(%rdi,%rdx,4)
L14:
  lea    0x1(%rax),%edx
  cmp    %edx,%esi
  je     L21
  mov    %edx,%eax
L2:
  cmp    %eax,%ecx
  je     L0
  lea    (%rax,%r8,1),%edx
  movslq %edx,%rdx
  movl   $0x0,(%rdi,%rdx,4)
  jmp    L14
L21:
  lea    0x1(%rcx),%edx
  add    %esi,%r8d
  cmp    %eax,%ecx
  je     L37
  mov    %edx,%ecx
L63:
  mov    %r9d,%eax
  jmp    L2
L37:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void matrix_eye(float *A, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++) {
      if (i == j)
        A[n * i + j] = 1;
      else
        A[n * i + j] = 0;
    }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matrix_eye>:
  endbr64
  test   %esi,%esi
  jle    L28
  movss  D5(%rip),%xmm1
  xor    %r9d,%r9d
  xor    %edx,%edx
  movslq %esi,%r8
  pxor   %xmm2,%xmm2
  nopl   0x0(%rax)
L12:
  movslq %r9d,%rax
  lea    (%rdi,%rax,4),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L4:
  movaps %xmm1,%xmm0
  cmp    %eax,%edx
  je     L9
  movaps %xmm2,%xmm0
L9:
  movss  %xmm0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L4
  add    $0x1,%edx
  add    %esi,%r9d
  cmp    %edx,%esi
  jne    L12
L28:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: byte[4]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void matrix_eye(float *A, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++) {
      if (i == j)
        A[n * i + j] = 1;
      else
        A[n * i + j] = 0;
    }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_eye>:
  endbr64
  test   %esi,%esi
  jle    L24
  mov    %esi,%eax
  mov    %esi,%r10d
  movss  D14(%rip),%xmm5
  push   %rbx
  shr    $0x2,%eax
  movdqa D26(%rip),%xmm4
  mov    %rdi,%r8
  xor    %ecx,%ecx
  lea    -0x1(%rax),%r11d
  movaps D14(%rip),%xmm3
  lea    -0x1(%rsi),%ebx
  xor    %edi,%edi
  add    $0x1,%r11
  and    $0xfffffffc,%r10d
  pxor   %xmm6,%xmm6
  shl    $0x4,%r11
  nopw   0x0(%rax,%rax,1)
L56:
  cmp    $0x2,%ebx
  jbe    L91
  movslq %edi,%rax
  movd   %ecx,%xmm7
  movdqa D29(%rip),%xmm1
  lea    (%r8,%rax,4),%rax
  pshufd $0x0,%xmm7,%xmm2
  lea    (%r11,%rax,1),%rdx
  nopl   (%rax)
L12:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm4,%xmm1
  pcmpeqd %xmm2,%xmm0
  andps  %xmm3,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L12
  mov    %r10d,%eax
  cmp    %r10d,%esi
  je     L85
L2:
  lea    (%rdi,%rax,1),%edx
  movaps %xmm5,%xmm0
  movslq %edx,%rdx
  lea    (%r8,%rdx,4),%rdx
  cmp    %eax,%ecx
  je     L6
  movaps %xmm6,%xmm0
L6:
  movss  %xmm0,(%rdx)
  lea    0x1(%rax),%edx
  cmp    %esi,%edx
  jge    L85
  lea    (%rdx,%rdi,1),%r9d
  movaps %xmm5,%xmm0
  movslq %r9d,%r9
  lea    (%r8,%r9,4),%r9
  cmp    %ecx,%edx
  je     L38
  movaps %xmm6,%xmm0
L38:
  add    $0x2,%eax
  movss  %xmm0,(%r9)
  cmp    %esi,%eax
  jge    L85
  lea    (%rax,%rdi,1),%edx
  movaps %xmm5,%xmm0
  movslq %edx,%rdx
  lea    (%r8,%rdx,4),%rdx
  cmp    %ecx,%eax
  je     L29
  movaps %xmm6,%xmm0
L29:
  movss  %xmm0,(%rdx)
L85:
  add    $0x1,%ecx
  add    %esi,%edi
  cmp    %esi,%ecx
  jne    L56
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L91:
  xor    %eax,%eax
  jmp    L2
L24:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
type_guessed: byte[16]
name: disassemble_data
arguments: label: D26
type_guessed: byte[16]
name: disassemble_data
arguments: label: D29
type_guessed: byte[16]

tool: {"D14": [0x00,0x00,0x80,0x3f,0x00,0x00,0x80,0x3f,0x00,0x00,0x80,0x3f,0x00,0x00,0x80,0x3f]}

tool: {"D26": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
void matrix_eye(float *A, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++) {
      if (i == j)
        A[n * i + j] = 1;
      else
        A[n * i + j] = 0;
    }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D12
type: string

tool: D3: Nr=

tool: D15: %d

tool: D12: New value: %d

assistant: ```c
int main() {
  int n;
  printf("Nr=");
  scanf("%d", &n);
  n = ~n;
  printf("New value: %d", n + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%eax
  not    %eax
  mov    %eax,0x4(%rsp)
  neg    %esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D21
data_type: string
name: unpack_data
arguments: label: D22
data_type: string

tool: D6: Nr=

tool: D21: %d

tool: D22: New value: %d

assistant: ```c
int main() {
  int n;
  printf("Nr=");
  scanf("%d", &n);
  n = ~n;
  printf("New value: %d", n + 1);
}
```