ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D17(%rip),%rbp
  mov    D20(%rip),%rbx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L0:
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <fputc@plt>
L19:
  mov    0x0(%rbp),%edi
  call   <fgetc@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c;
  while ((c = fgetc(stdin)) != EOF) {
    fputc(c, stdout);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rbp
  mov    D20(%rip),%rbx
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L14:
  mov    D25(%rip),%rax
  mov    (%rax),%esi
  call   <fputc@plt>
L10:
  mov    0x0(%rbp),%edi
  call   <fgetc@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L14
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c;
  while ((c = fgetc(stdin)) != EOF) {
    fputc(c, stdout);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_eol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L10
  mov    $0x1,%eax
  jmp    L12
L10:
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
bool is_eol(int c) {
  if (c == '\n') {
    return true;
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_eol>:
  endbr64
  cmp    $0xa,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_eol(int c) {
  if (c == '\n') {
    return true;
  }
  return false;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_eol>:
  endbr64
  xor    %eax,%eax
  cmp    $0xa,%edi
  sete   %al
  ret
```

assistant: ```c
bool is_eol(int c) {
  if (c == '\n') {
    return true;
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_eol>:
  endbr64
  xor    %eax,%eax
  cmp    $0xa,%edi
  sete   %al
  ret
```

assistant: ```c
bool is_eol(int c) {
  if (c == '\n') {
    return true;
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type: string
name: parse_data
arguments: data_label: D6
type: byte[8]
name: parse_data
arguments: data_label: D4
type: string

tool: D14: %lf

tool: {"D6": [0x49,0x04,0xbd,0x4a,0x51,0xc1,0x10,0x40]}

tool: D4: VOLUME = %.3f


assistant: ```c
int main(void) {
  double r;
  scanf("%lf", &r);
  printf("VOLUME = %.3f\n", 4.0 / 3.0 * 3.14159 * r * r * r);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movapd %xmm1,%xmm0
  mulsd  D25(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D25
data_type: byte[8]
name: parse_data
arguments: data_label: D10
data_type: string

tool: D7: %lf

tool: {"D25": [0x49,0x04,0xbd,0x4a,0x51,0xc1,0x10,0x40]}

tool: D10: VOLUME = %.3f


assistant: ```c
int main(void) {
  double r;
  scanf("%lf", &r);
  printf("VOLUME = %.3f\n", 4.0 / 3.0 * 3.14159 * r * r * r);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  D15(%rip),%xmm0
  lea    D12(%rip),%rdi
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: byte[8]
name: disassemble_data
arguments: data_label: D12
data_type: string

tool: D23: %lf

tool: {"D15": [0x49,0x04,0xbd,0x4a,0x51,0xc1,0x10,0x40]}

tool: D12: VOLUME = %.3f


assistant: ```c
int main(void) {
  double r;
  scanf("%lf", &r);
  printf("VOLUME = %.3f\n", 4.0 / 3.0 * 3.14159 * r * r * r);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  D8(%rip),%xmm0
  lea    D5(%rip),%rdi
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D14
data_type: string
name: read_data
arguments: tag: D8
data_type: byte[8]
name: read_data
arguments: tag: D5
data_type: string

tool: D14: %lf

tool: {"D8": [0x49,0x04,0xbd,0x4a,0x51,0xc1,0x10,0x40]}

tool: D5: VOLUME = %.3f


assistant: ```c
int main(void) {
  double r;
  scanf("%lf", &r);
  printf("VOLUME = %.3f\n", 4.0 / 3.0 * 3.14159 * r * r * r);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parsemetadata>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <isvalidkey@plt>
  test   %rax,%rax
  je     L4
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <trim@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <transformkey@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L36
L4:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <trim@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L36
L16:
  mov    $0x1,%eax
L36:
  leave
  ret
```

assistant: ```c
int parsemetadata(char *line, char **key, char **value) {
  char *colon;
  colon = strchr(line, ':');
  if (colon && isvalidkey(line)) {
    *colon = '\0';
    *value = trim(colon + 1);
    transformkey(line);
    *key = line;
    return 0;
  }
  colon = trim(line);
  if (*colon != '\0') {
    *key = NULL;
    *value = colon;
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parsemetadata>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    $0x3a,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L48
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <isvalidkey@plt>
  test   %rax,%rax
  jne    L15
L48:
  mov    %rbx,%rdi
  call   <trim@plt>
  mov    $0x1,%edx
  cmpb   $0x0,(%rax)
  jne    L3
L27:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  movb   $0x0,0x0(%rbp)
  lea    0x1(%rbp),%rdi
  call   <trim@plt>
  mov    %rax,(%r12)
  mov    %rbx,%rdi
  call   <transformkey@plt>
  mov    %rbx,0x0(%r13)
  mov    $0x0,%edx
  jmp    L27
L3:
  movq   $0x0,0x0(%r13)
  mov    %rax,(%r12)
  mov    $0x0,%edx
  jmp    L27
```

assistant: ```c
int parsemetadata(char *line, char **key, char **value) {
  char *colon;
  colon = strchr(line, ':');
  if (colon && isvalidkey(line)) {
    *colon = '\0';
    *value = trim(colon + 1);
    transformkey(line);
    *key = line;
    return 0;
  }
  colon = trim(line);
  if (*colon != '\0') {
    *key = NULL;
    *value = colon;
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parsemetadata>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x3a,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <isvalidkey@plt>
  test   %rax,%rax
  jne    L15
L7:
  mov    %rbp,%rdi
  call   <trim@plt>
  mov    $0x1,%r8d
  cmpb   $0x0,(%rax)
  je     L5
  movq   $0x0,0x0(%r13)
  xor    %r8d,%r8d
  mov    %rax,(%r12)
L5:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  movb   $0x0,(%rbx)
  lea    0x1(%rbx),%rdi
  call   <trim@plt>
  mov    %rbp,%rdi
  mov    %rax,(%r12)
  call   <transformkey@plt>
  mov    %rbp,0x0(%r13)
  xor    %r8d,%r8d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int parsemetadata(char *line, char **key, char **value) {
  char *colon;
  colon = strchr(line, ':');
  if (colon && isvalidkey(line)) {
    *colon = '\0';
    *value = trim(colon + 1);
    transformkey(line);
    *key = line;
    return 0;
  }
  colon = trim(line);
  if (*colon != '\0') {
    *key = NULL;
    *value = colon;
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<parsemetadata>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x3a,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L28
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <isvalidkey@plt>
  test   %rax,%rax
  jne    L4
L28:
  mov    %rbp,%rdi
  call   <trim@plt>
  mov    $0x1,%r8d
  cmpb   $0x0,(%rax)
  je     L21
  movq   $0x0,0x0(%r13)
  xor    %r8d,%r8d
  mov    %rax,(%r12)
L21:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  movb   $0x0,(%rbx)
  lea    0x1(%rbx),%rdi
  call   <trim@plt>
  mov    %rbp,%rdi
  mov    %rax,(%r12)
  call   <transformkey@plt>
  mov    %rbp,0x0(%r13)
  xor    %r8d,%r8d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int parsemetadata(char *line, char **key, char **value) {
  char *colon;
  colon = strchr(line, ':');
  if (colon && isvalidkey(line)) {
    *colon = '\0';
    *value = trim(colon + 1);
    transformkey(line);
    *key = line;
    return 0;
  }
  colon = trim(line);
  if (*colon != '\0') {
    *key = NULL;
    *value = colon;
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<d_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <d_instantiate@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <d_rehash@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void d_add(struct dentry *entry, struct inode *inode) {
  d_instantiate(entry, inode);
  d_rehash(entry);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<d_add>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <d_instantiate@plt>
  mov    %rbx,%rdi
  call   <d_rehash@plt>
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) void d_add(struct dentry *entry, struct inode *inode) {
  d_instantiate(entry, inode);
  d_rehash(entry);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<d_add>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <d_instantiate@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <d_rehash@plt>
```

assistant: ```c
__attribute__((always_)) void d_add(struct dentry *entry, struct inode *inode) {
  d_instantiate(entry, inode);
  d_rehash(entry);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<d_add>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <d_instantiate@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <d_rehash@plt>
```

assistant: ```c
__attribute__((always_)) void d_add(struct dentry *entry, struct inode *inode) {
  d_instantiate(entry, inode);
  d_rehash(entry);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aarch64_banked_spsr_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L20
  cmpl   $0x3,-0x4(%rbp)
  ja     L20
  mov    $0x1,%eax
  jmp    L29
L20:
  mov    $0x0,%eax
L29:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: 

assistant: ```c
unsigned int aarch64_banked_spsr_index(unsigned int el) {
  static const unsigned int map[4] = {
      0,
      0,
      6,
      7,
  };
  assert(el >= 1 && el <= 3);
  return map[el];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aarch64_banked_spsr_index>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%ebx
  lea    D4(%rip),%rax
  mov    (%rax,%rbx,4),%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: 

assistant: ```c
unsigned int aarch64_banked_spsr_index(unsigned int el) {
  static const unsigned int map[4] = {
      0,
      0,
      6,
      7,
  };
  assert(el >= 1 && el <= 3);
  return map[el];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aarch64_banked_spsr_index>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  setbe  %dil
  call   <assert@plt>
  lea    D8(%rip),%rax
  mov    (%rax,%rbx,4),%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: 

assistant: ```c
unsigned int aarch64_banked_spsr_index(unsigned int el) {
  static const unsigned int map[4] = {
      0,
      0,
      6,
      7,
  };
  assert(el >= 1 && el <= 3);
  return map[el];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aarch64_banked_spsr_index>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  setbe  %dil
  call   <assert@plt>
  lea    D0(%rip),%rax
  mov    (%rax,%rbx,4),%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: 

assistant: ```c
unsigned int aarch64_banked_spsr_index(unsigned int el) {
  static const unsigned int map[4] = {
      0,
      0,
      6,
      7,
  };
  assert(el >= 1 && el <= 3);
  return map[el];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<combination_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  je     L51
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x40(%rbp)
  jb     L65
L51:
  mov    $0x0,%eax
  jmp    L25
L65:
  movq   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
L20:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x40(%rbp)
  jae    L9
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L64
L9:
  mov    -0x8(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x40(%rbp)
  jbe    L72
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L64
L72:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L64:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L20
  mov    -0x38(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%rax
L25:
  pop    %rbp
  ret
```

assistant: ```c
size_t combination_size(size_t *pascal, size_t row_length, size_t L, size_t N) {
  if (N == 0 || pascal[L] <= N)
    return 0;
  size_t h = 0, l = L, mid = 0;
  do {
    mid = (h + l) / 2;
    if (N < pascal[mid * row_length + L])
      h = mid + 1;
    else if (pascal[mid * row_length + L] < N)
      l = mid;
    else
      h = l = mid;
  } while (h != l);
  return L - h + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<combination_size>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r10
  mov    %rcx,%rax
  test   %rcx,%rcx
  je     L48
  mov    $0x0,%eax
  cmp    %rcx,(%rdi,%rdx,8)
  jbe    L48
  mov    %rdx,%r8
  mov    $0x0,%edi
  jmp    L36
L50:
  jae    L1
  mov    %rsi,%r8
L5:
  cmp    %r8,%rdi
  je     L29
L36:
  lea    (%rdi,%r8,1),%rsi
  shr    %rsi
  mov    %rsi,%rax
  imul   %r10,%rax
  add    %rdx,%rax
  mov    (%r9,%rax,8),%rax
  cmp    %rcx,%rax
  jbe    L50
  lea    0x1(%rsi),%rdi
  jmp    L5
L29:
  mov    %r8,%rsi
L1:
  lea    0x1(%rdx),%rax
  sub    %rsi,%rax
L48:
  ret
```

assistant: ```c
size_t combination_size(size_t *pascal, size_t row_length, size_t L, size_t N) {
  if (N == 0 || pascal[L] <= N)
    return 0;
  size_t h = 0, l = L, mid = 0;
  do {
    mid = (h + l) / 2;
    if (N < pascal[mid * row_length + L])
      h = mid + 1;
    else if (pascal[mid * row_length + L] < N)
      l = mid;
    else
      h = l = mid;
  } while (h != l);
  return L - h + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<combination_size>:
  endbr64
  mov    %rdi,%r10
  xor    %eax,%eax
  test   %rcx,%rcx
  je     L76
  cmp    %rcx,(%rdi,%rdx,8)
  jbe    L76
  mov    %rdx,%r9
  xor    %r8d,%r8d
  jmp    L52
  nopl   0x0(%rax)
L47:
  lea    0x1(%rdi),%r8
L60:
  cmp    %r9,%r8
  je     L45
L52:
  lea    (%r8,%r9,1),%rdi
  shr    %rdi
  mov    %rdi,%rax
  imul   %rsi,%rax
  add    %rdx,%rax
  cmp    %rcx,(%r10,%rax,8)
  ja     L47
  jb     L51
L3:
  lea    0x1(%rdx),%rax
  sub    %rdi,%rax
L76:
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %rdi,%r9
  jmp    L60
L45:
  mov    %r8,%rdi
  jmp    L3
```

assistant: ```c
size_t combination_size(size_t *pascal, size_t row_length, size_t L, size_t N) {
  if (N == 0 || pascal[L] <= N)
    return 0;
  size_t h = 0, l = L, mid = 0;
  do {
    mid = (h + l) / 2;
    if (N < pascal[mid * row_length + L])
      h = mid + 1;
    else if (pascal[mid * row_length + L] < N)
      l = mid;
    else
      h = l = mid;
  } while (h != l);
  return L - h + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<combination_size>:
  endbr64
  mov    %rsi,%r9
  mov    %rdi,%r8
  mov    %rdx,%rsi
  xor    %eax,%eax
  test   %rcx,%rcx
  je     L17
  cmp    %rcx,(%rdi,%rdx,8)
  jbe    L17
  mov    %rdx,%rax
  xor    %edi,%edi
  cmp    $0x1,%r9
  je     L50
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L56:
  lea    0x1(%rdx),%rdi
L69:
  cmp    %rdi,%rax
  je     L137
L50:
  lea    (%rax,%rdi,1),%rdx
  shr    %rdx
  lea    (%rsi,%rdx,1),%r9
  cmp    (%r8,%r9,8),%rcx
  jb     L56
  ja     L43
L32:
  lea    0x1(%rsi),%rax
  sub    %rdx,%rax
L17:
  ret
  nopl   0x0(%rax)
L43:
  mov    %rdx,%rax
  jmp    L69
  nopl   (%rax)
L71:
  xor    %r10d,%r10d
  jmp    L64
  nopl   (%rax)
L129:
  lea    0x1(%rdx),%r10
L40:
  cmp    %rax,%r10
  je     L137
L64:
  lea    (%r10,%rax,1),%rdx
  shr    %rdx
  mov    %rdx,%rdi
  imul   %r9,%rdi
  add    %rsi,%rdi
  cmp    %rcx,(%r8,%rdi,8)
  ja     L129
  jae    L32
  mov    %rdx,%rax
  jmp    L40
L137:
  mov    %rax,%rdx
  jmp    L32
```

assistant: ```c
size_t combination_size(size_t *pascal, size_t row_length, size_t L, size_t N) {
  if (N == 0 || pascal[L] <= N)
    return 0;
  size_t h = 0, l = L, mid = 0;
  do {
    mid = (h + l) / 2;
    if (N < pascal[mid * row_length + L])
      h = mid + 1;
    else if (pascal[mid * row_length + L] < N)
      l = mid;
    else
      h = l = mid;
  } while (h != l);
  return L - h + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0xc(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D8
type: string

tool: D16: %d %d

tool: D8: %.2lf


assistant: ```c
int main() {
  int h, p;
  scanf("%d %d", &h, &p);
  printf("%.2lf\n", h / (double)p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x4(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D16
type_infered: string

tool: D4: %d %d

tool: D16: %.2lf


assistant: ```c
int main() {
  int h, p;
  scanf("%d %d", &h, &p);
  printf("%.2lf\n", h / (double)p);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D7(%rip),%rdi
  cvtsi2sdl (%rsp),%xmm0
  cvtsi2sdl 0x4(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string

tool: D1: %d %d

tool: D7: %.2lf


assistant: ```c
int main() {
  int h, p;
  scanf("%d %d", &h, &p);
  printf("%.2lf\n", h / (double)p);
  return 0;
}
```