user: 请从给定的汇编指令推导出C源代码:

```asm
<MMX_SUB_8b_AUTOTEST>:
  endbr64
  push   %r14
  lea    D53(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  shl    $0x10,%ebx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x10,%ecx
  lea    (%rax,%rcx,1),%edx
  xor    %eax,%eax
  movzwl %dx,%edx
  sub    %ecx,%edx
  and    %edx,%ebx
  call   <rand@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <rand@plt>
  shl    $0x10,%r12d
  mov    %ebx,%edi
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x10,%ecx
  lea    (%rax,%rcx,1),%edx
  movzwl %dx,%edx
  sub    %ecx,%edx
  and    %edx,%r12d
  mov    %r12d,%esi
  call   <instr_v8sub@plt>
  mov    %r12d,%esi
  mov    %ebx,%edi
  mov    %eax,%r14d
  call   <prog_v8sub@plt>
  mov    %eax,%r13d
  cmp    %eax,%r14d
  jne    L10
  add    $0x1,%ebp
  cmp    $0xa,%ebp
  jne    L0
  lea    D76(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L10:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  mov    %ebx,%esi
  xor    %r8d,%r8d
  sar    $0x10,%edx
  shr    $0x18,%esi
  xor    %ecx,%ecx
  lea    D45(%rip),%rdi
  movzbl %dl,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  xor    %r8d,%r8d
  sar    $0x10,%edx
  shr    $0x18,%esi
  xor    %ecx,%ecx
  lea    D58(%rip),%rdi
  movzbl %dl,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%edx
  mov    %r14d,%eax
  mov    %r14d,%esi
  sar    $0x10,%edx
  movzbl %ah,%ecx
  movzbl %r14b,%r8d
  shr    $0x18,%esi
  movzbl %dl,%edx
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%edx
  mov    %r13d,%eax
  mov    %r13d,%esi
  sar    $0x10,%edx
  movzbl %ah,%ecx
  movzbl %r13b,%r8d
  shr    $0x18,%esi
  movzbl %dl,%edx
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D53
data_type: string
name: parse_data
arguments: label: D76
data_type: string
name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D21
data_type: string
name: parse_data
arguments: label: D45
data_type: string
name: parse_data
arguments: label: D58
data_type: string
name: parse_data
arguments: label: D26
data_type: string
name: parse_data
arguments: label: D28
data_type: string

tool: D53: LAUNCHING THE (MMX_SUB) RESOURCE AUTOTEST...

tool: D76: - TEST OF THE MMX_SUB_8b RESOURCE => OK

tool: D1: - TEST OF THE (MMX_SUB) RESOURCE => FAILED !

tool: D21:   + %d COMPUTATION(s) BEFORE ERROR...


tool: D45:   + OPERANDE 1 [%.3d %.3d %.3d %.3d]


tool: D58:   + OPERANDE 2 [%.3d %.3d %.3d %.3d]


tool: D26:   + ASM INSTR. [%.3d %.3d %.3d %.3d]


tool: D28:   + REF C CODE [%.3d %.3d %.3d %.3d]


assistant: ```c
int MMX_SUB_8b_AUTOTEST() {
  printf("LAUNCHING THE (MMX_SUB) RESOURCE AUTOTEST...\n");
  int i, j;
  for (j = 0; j < 10; j++) {
    int op1 = ((rand() % 65536) << 16) & (rand() % 65536);
    int op2 = ((rand() % 65536) << 16) & (rand() % 65536);
    int op3 = instr_v8sub(op1, op2);
    int op4 = prog_v8sub(op1, op2);
    if (op3 != op4) {
      printf("- TEST OF THE (MMX_SUB) RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION(s) BEFORE ERROR...\n", j);
      printf("  + OPERANDE 1 [%.3d %.3d %.3d %.3d]\n", ((op1 & 0xFF000000) >> 24), ((op1 & 0x00FF0000) >> 16), ((op1 & 0x0000FF00) >> 8), ((op1 & 0x000000FF)));
      printf("  + OPERANDE 2 [%.3d %.3d %.3d %.3d]\n", ((op2 & 0xFF000000) >> 24), ((op2 & 0x00FF0000) >> 16), ((op2 & 0x0000FF00) >> 8), ((op2 & 0x000000FF)));
      printf("  + ASM INSTR. [%.3d %.3d %.3d %.3d]\n", ((op3 & 0xFF000000) >> 24), ((op3 & 0x00FF0000) >> 16), ((op3 & 0x0000FF00) >> 8), ((op3 & 0x000000FF)));
      printf("  + REF C CODE [%.3d %.3d %.3d %.3d]\n", ((op4 & 0xFF000000) >> 24), ((op4 & 0x00FF0000) >> 16), ((op4 & 0x0000FF00) >> 8), ((op4 & 0x000000FF)));
      return 0;
    }
  }
  printf("- TEST OF THE MMX_SUB_8b RESOURCE => OK\n");
  return 1;
}
```