ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tracecmd_create_recorder_fd>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    $0x0,%eax
  call   <tracecmd_find_tracing_dir@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rcx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <tracecmd_create_buffer_recorder_fd@plt>
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    D2(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D13(%rip),%rdx
  mov    %ecx,(%rdx)
  jmp    L18
```

assistant: ```c
struct tracecmd_recorder *tracecmd_create_recorder_fd(int fd, int cpu, unsigned flags) {
  char *tracing;
  tracing = tracecmd_find_tracing_dir();
  if (!tracing) {
    errno = ENODEV;
    return NULL;
  }
  return tracecmd_create_buffer_recorder_fd(fd, cpu, flags, tracing);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tracecmd_create_recorder_fd>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <tracecmd_find_tracing_dir@plt>
  test   %rax,%rax
  je     L8
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %rax,%rcx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <tracecmd_create_buffer_recorder_fd@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct tracecmd_recorder *tracecmd_create_recorder_fd(int fd, int cpu, unsigned flags) {
  char *tracing;
  tracing = tracecmd_find_tracing_dir();
  if (!tracing) {
    errno = ENODEV;
    return NULL;
  }
  return tracecmd_create_buffer_recorder_fd(fd, cpu, flags, tracing);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tracecmd_create_recorder_fd>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <tracecmd_find_tracing_dir@plt>
  test   %rax,%rax
  je     L5
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %rax,%rcx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <tracecmd_create_buffer_recorder_fd@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct tracecmd_recorder *tracecmd_create_recorder_fd(int fd, int cpu, unsigned flags) {
  char *tracing;
  tracing = tracecmd_find_tracing_dir();
  if (!tracing) {
    errno = ENODEV;
    return NULL;
  }
  return tracecmd_create_buffer_recorder_fd(fd, cpu, flags, tracing);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x73,%esi
  lea    D67(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  lea    0xe0(%rsp),%rbp
  lea    0x70(%rsp),%r12
  mov    %rsp,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  mov    %r13,%rsi
  mov    %rbp,%rcx
  mov    %r12,%rdx
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %rax,%rbx
  call   <strlen@plt>
  movsbl (%rsp),%esi
  test   %sil,%sil
  je     L1
  lea    D35(%rip),%r8
  cmp    %rax,%rbx
  jne    L111
  lea    0x1(%rsp),%rbx
L114:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L21
  add    $0x1,%rbx
  movb   $0x2d,(%rax)
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L114
  movsbl 0x70(%rsp),%esi
  test   %sil,%sil
  jne    L118
L136:
  mov    $0x1,%r12d
L28:
  mov    %rbp,%rdi
  lea    D58(%rip),%rsi
  call   <strspn@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L21
  cmp    %rax,%rbx
  jne    L21
  lea    D51(%rip),%r8
  xchg   %ax,%ax
L111:
  mov    %r8,%rsi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x158,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  movsbl 0x70(%rsp),%esi
  xor    %r12d,%r12d
  cmp    %rax,%rbx
  sete   %r12b
  test   %sil,%sil
  je     L28
  cmp    %rax,%rbx
  jne    L21
L118:
  lea    0x71(%rsp),%rbx
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L128:
  add    $0x1,%rbx
  movb   $0x2d,(%rax)
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  je     L136
L47:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L128
L21:
  lea    D35(%rip),%r8
  jmp    L111
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D67
type: string
name: disassemble_data
arguments: data_tag: D7
type: string
name: disassemble_data
arguments: data_tag: D35
type: string
name: disassemble_data
arguments: data_tag: D58
type: string
name: disassemble_data
arguments: data_tag: D51
type: string
name: disassemble_data
arguments: data_tag: D45
type: string

tool: D67: dfgg

tool: D7: %s%s%s

tool: D35: NO

tool: D58: -

tool: D51: YES

tool: D45: %s

assistant: ```c
int main() {
  char str1[102], str2[102], strs[102];
  int count;
  int is = 1;
  strchr("dfgg", 's');
  scanf("%s%s%s", str1, str2, strs);
  if (strlen(str1) + strlen(str2) != strlen(strs))
    is = 0;
  for (count = 0; str1[count] != '\0' && is != 0; count++) {
    char *z = strchr(strs, str1[count]);
    if (z == NULL) {
      is = 0;
      break;
    } else
      *z = '-';
  }
  for (count = 0; str2[count] != '\0' && is != 0; count++) {
    char *z = strchr(strs, str2[count]);
    if (z == NULL) {
      is = 0;
      break;
    } else
      *z = '-';
  }
  if (strspn(strs, "-") != strlen(strs)) {
    is = 0;
  }
  printf("%s", ((is == 0) ? "NO" : "YES"));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x73,%esi
  lea    D23(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  lea    0xe0(%rsp),%rbp
  lea    0x70(%rsp),%r12
  mov    %rsp,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  mov    %r13,%rsi
  mov    %rbp,%rcx
  mov    %r12,%rdx
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %rax,%rbx
  call   <strlen@plt>
  movsbl (%rsp),%esi
  test   %sil,%sil
  je     L38
  lea    D36(%rip),%r8
  cmp    %rax,%rbx
  jne    L115
  lea    0x1(%rsp),%rbx
L21:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L108
  add    $0x1,%rbx
  movb   $0x2d,(%rax)
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L21
  movsbl 0x70(%rsp),%esi
  test   %sil,%sil
  jne    L109
L32:
  mov    $0x1,%r12d
L58:
  mov    %rbp,%rdi
  lea    D54(%rip),%rsi
  call   <strspn@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L108
  cmp    %rax,%rbx
  jne    L108
  lea    D5(%rip),%r8
  xchg   %ax,%ax
L115:
  mov    %r8,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x158,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  movsbl 0x70(%rsp),%esi
  xor    %r12d,%r12d
  cmp    %rax,%rbx
  sete   %r12b
  test   %sil,%sil
  je     L58
  cmp    %rax,%rbx
  jne    L108
L109:
  lea    0x71(%rsp),%rbx
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L53:
  add    $0x1,%rbx
  movb   $0x2d,(%rax)
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  je     L32
L20:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L53
L108:
  lea    D36(%rip),%r8
  jmp    L115
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D23
data_type: string
name: parse_data
arguments: label: D8
data_type: string
name: parse_data
arguments: label: D36
data_type: string
name: parse_data
arguments: label: D54
data_type: string
name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D29
data_type: string

tool: D23: dfgg

tool: D8: %s%s%s

tool: D36: NO

tool: D54: -

tool: D5: YES

tool: D29: %s

assistant: ```c
int main() {
  char str1[102], str2[102], strs[102];
  int count;
  int is = 1;
  strchr("dfgg", 's');
  scanf("%s%s%s", str1, str2, strs);
  if (strlen(str1) + strlen(str2) != strlen(strs))
    is = 0;
  for (count = 0; str1[count] != '\0' && is != 0; count++) {
    char *z = strchr(strs, str1[count]);
    if (z == NULL) {
      is = 0;
      break;
    } else
      *z = '-';
  }
  for (count = 0; str2[count] != '\0' && is != 0; count++) {
    char *z = strchr(strs, str2[count]);
    if (z == NULL) {
      is = 0;
      break;
    } else
      *z = '-';
  }
  if (strspn(strs, "-") != strlen(strs)) {
    is = 0;
  }
  printf("%s", ((is == 0) ? "NO" : "YES"));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L70:
  mov    -0x1c(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  sub    $0xa,%eax
  cmp    $0x5,%eax
  ja     L38
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D15(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D15(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x41,(%rax)
  jmp    L89
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x42,(%rax)
  jmp    L89
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x43,(%rax)
  jmp    L89
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x44,(%rax)
  jmp    L89
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x45,(%rax)
  jmp    L89
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x46,(%rax)
  jmp    L89
L38:
  mov    -0x1c(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L89:
  mov    -0x1c(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L70
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int convert_to_hex(char hex[], int n) {
  int i;
  for (i = 0; n > 0; i++) {
    switch (n % 16) {
    case 10:
      hex[i] = 'A';
      break;
    case 11:
      hex[i] = 'B';
      break;
    case 12:
      hex[i] = 'C';
      break;
    case 13:
      hex[i] = 'D';
      break;
    case 14:
      hex[i] = 'E';
      break;
    case 15:
      hex[i] = 'F';
      break;
    default:
      hex[i] = n % 16 + 48;
    }
    n = n / 16;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<convert_to_hex>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L80
  mov    %rdi,%rsi
  lea    D2(%rip),%r8
  mov    $0x1,%r9d
  sub    %edi,%r9d
  jmp    L62
  movb   $0x41,(%rsi)
L65:
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x4,%edx
  lea    (%r9,%rsi,1),%ecx
  add    $0x1,%rsi
  cmp    $0xf,%eax
  jle    L82
  mov    %edx,%eax
L62:
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0xf,%edx
  sub    %ecx,%edx
  lea    -0xa(%rdx),%ecx
  cmp    $0x5,%ecx
  ja     L59
  mov    %ecx,%ecx
  movslq (%r8,%rcx,4),%rdx
  add    %r8,%rdx
  notrack jmp *%rdx
  movb   $0x42,(%rsi)
  jmp    L65
  movb   $0x43,(%rsi)
  jmp    L65
  movb   $0x44,(%rsi)
  jmp    L65
  movb   $0x45,(%rsi)
  jmp    L65
  movb   $0x46,(%rsi)
  jmp    L65
L59:
  add    $0x30,%edx
  mov    %dl,(%rsi)
  jmp    L65
L80:
  mov    $0x0,%ecx
L82:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int convert_to_hex(char hex[], int n) {
  int i;
  for (i = 0; n > 0; i++) {
    switch (n % 16) {
    case 10:
      hex[i] = 'A';
      break;
    case 11:
      hex[i] = 'B';
      break;
    case 12:
      hex[i] = 'C';
      break;
    case 13:
      hex[i] = 'D';
      break;
    case 14:
      hex[i] = 'E';
      break;
    case 15:
      hex[i] = 'F';
      break;
    default:
      hex[i] = n % 16 + 48;
    }
    n = n / 16;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<convert_to_hex>:
  endbr64
  test   %esi,%esi
  jle    L2
  mov    $0x1,%ecx
  lea    D8(%rip),%r8
  nopl   0x0(%rax,%rax,1)
L60:
  mov    %esi,%edx
  and    $0xf,%edx
  lea    -0xa(%rdx),%eax
  cmp    $0x5,%eax
  ja     L79
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    $0x42,%edx
  nopl   (%rax)
L4:
  mov    %dl,-0x1(%rdi,%rcx,1)
  mov    %ecx,%eax
  add    $0x1,%rcx
  sar    $0x4,%esi
  jne    L60
  ret
  nopl   0x0(%rax,%rax,1)
  mov    $0x41,%edx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
  mov    $0x46,%edx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
  mov    $0x45,%edx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
  mov    $0x44,%edx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
  mov    $0x43,%edx
  jmp    L4
L79:
  add    $0x30,%edx
  jmp    L4
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int convert_to_hex(char hex[], int n) {
  int i;
  for (i = 0; n > 0; i++) {
    switch (n % 16) {
    case 10:
      hex[i] = 'A';
      break;
    case 11:
      hex[i] = 'B';
      break;
    case 12:
      hex[i] = 'C';
      break;
    case 13:
      hex[i] = 'D';
      break;
    case 14:
      hex[i] = 'E';
      break;
    case 15:
      hex[i] = 'F';
      break;
    default:
      hex[i] = n % 16 + 48;
    }
    n = n / 16;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convert_to_hex>:
  endbr64
  test   %esi,%esi
  jle    L10
  mov    $0x1,%ecx
  lea    D9(%rip),%r8
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %esi,%edx
  and    $0xf,%edx
  lea    -0xa(%rdx),%eax
  cmp    $0x5,%eax
  ja     L72
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    $0x42,%edx
  nopl   (%rax)
L8:
  mov    %dl,-0x1(%rdi,%rcx,1)
  mov    %ecx,%eax
  add    $0x1,%rcx
  sar    $0x4,%esi
  jne    L56
  ret
  nopl   0x0(%rax,%rax,1)
  mov    $0x41,%edx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
  mov    $0x46,%edx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
  mov    $0x45,%edx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
  mov    $0x44,%edx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
  mov    $0x43,%edx
  jmp    L8
L72:
  add    $0x30,%edx
  jmp    L8
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int convert_to_hex(char hex[], int n) {
  int i;
  for (i = 0; n > 0; i++) {
    switch (n % 16) {
    case 10:
      hex[i] = 'A';
      break;
    case 11:
      hex[i] = 'B';
      break;
    case 12:
      hex[i] = 'C';
      break;
    case 13:
      hex[i] = 'D';
      break;
    case 14:
      hex[i] = 'E';
      break;
    case 15:
      hex[i] = 'F';
      break;
    default:
      hex[i] = n % 16 + 48;
    }
    n = n / 16;
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D14: F1

tool: D7: %li


assistant: ```c
int main(int argc, char *argv[]) {
  char *col = "F1";
  printf("%li\n", strtol(col, NULL, 16));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%edx
  mov    $0x0,%esi
  lea    D17(%rip),%rdi
  call   <strtol@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D7
type: string

tool: D17: F1

tool: D7: %li


assistant: ```c
int main(int argc, char *argv[]) {
  char *col = "F1";
  printf("%li\n", strtol(col, NULL, 16));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%edx
  xor    %esi,%esi
  lea    D16(%rip),%rdi
  call   <strtol@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D14
data_type: string

tool: D16: F1

tool: D14: %li


assistant: ```c
int main(int argc, char *argv[]) {
  char *col = "F1";
  printf("%li\n", strtol(col, NULL, 16));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%edx
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  call   <strtol@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D12
datatype: string

tool: D5: F1

tool: D12: %li


assistant: ```c
int main(int argc, char *argv[]) {
  char *col = "F1";
  printf("%li\n", strtol(col, NULL, 16));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<setPercVolumeFromMIDI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpb   $0x3f,-0x1c(%rbp)
  seta   %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <setPercussionVolume@plt>
  nop
  leave
  ret
```

assistant: ```c
void setPercVolumeFromMIDI(void *d, unsigned char u) {
  struct b_tonegen *t = (struct b_tonegen *)d;
  setPercussionVolume(t, u < 64 ? 0 : 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setPercVolumeFromMIDI>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3f,%sil
  seta   %sil
  movzbl %sil,%esi
  call   <setPercussionVolume@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void setPercVolumeFromMIDI(void *d, unsigned char u) {
  struct b_tonegen *t = (struct b_tonegen *)d;
  setPercussionVolume(t, u < 64 ? 0 : 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setPercVolumeFromMIDI>:
  endbr64
  cmp    $0x3f,%sil
  seta   %sil
  movzbl %sil,%esi
  jmp    1050 <setPercussionVolume@plt>
```

assistant: ```c
void setPercVolumeFromMIDI(void *d, unsigned char u) {
  struct b_tonegen *t = (struct b_tonegen *)d;
  setPercussionVolume(t, u < 64 ? 0 : 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setPercVolumeFromMIDI>:
  endbr64
  cmp    $0x3f,%sil
  seta   %sil
  movzbl %sil,%esi
  jmp    1050 <setPercussionVolume@plt>
```

assistant: ```c
void setPercVolumeFromMIDI(void *d, unsigned char u) {
  struct b_tonegen *t = (struct b_tonegen *)d;
  setPercussionVolume(t, u < 64 ? 0 : 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zipwarn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zipwarn(msg1, msg2) char *msg1, *msg2;
{
  msg1 = msg1;
  msg2 = msg2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zipwarn>:
  endbr64
  ret
```

assistant: ```c
void zipwarn(msg1, msg2) char *msg1, *msg2;
{
  msg1 = msg1;
  msg2 = msg2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zipwarn>:
  endbr64
  ret
```

assistant: ```c
void zipwarn(msg1, msg2) char *msg1, *msg2;
{
  msg1 = msg1;
  msg2 = msg2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<zipwarn>:
  endbr64
  ret
```

assistant: ```c
void zipwarn(msg1, msg2) char *msg1, *msg2;
{
  msg1 = msg1;
  msg2 = msg2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<half_btf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <round_shift@plt>
  leave
  ret
```

assistant: ```c
int32_t half_btf(int32_t w0, int32_t in0, int32_t w1, int32_t in1, int bit) {
  int32_t result_32 = w0 * in0 + w1 * in1;
  return round_shift(result_32, bit);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<half_btf>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  mov    %r8d,%esi
  imul   %eax,%edi
  imul   %ecx,%edx
  add    %edx,%edi
  call   <round_shift@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int32_t half_btf(int32_t w0, int32_t in0, int32_t w1, int32_t in1, int bit) {
  int32_t result_32 = w0 * in0 + w1 * in1;
  return round_shift(result_32, bit);
}
```
user: What is the c source code of the assembly code below?

```asm
<half_btf>:
  endbr64
  mov    %esi,%r9d
  imul   %ecx,%edx
  mov    %r8d,%esi
  imul   %r9d,%edi
  add    %edx,%edi
  jmp    1050 <round_shift@plt>
```

assistant: ```c
int32_t half_btf(int32_t w0, int32_t in0, int32_t w1, int32_t in1, int bit) {
  int32_t result_32 = w0 * in0 + w1 * in1;
  return round_shift(result_32, bit);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<half_btf>:
  endbr64
  mov    %esi,%r9d
  imul   %ecx,%edx
  mov    %r8d,%esi
  imul   %r9d,%edi
  add    %edx,%edi
  jmp    1050 <round_shift@plt>
```

assistant: ```c
int32_t half_btf(int32_t w0, int32_t in0, int32_t w1, int32_t in1, int bit) {
  int32_t result_32 = w0 * in0 + w1 * in1;
  return round_shift(result_32, bit);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gg_debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xb8(%rbp)
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <gg_debug_common@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D14(%rip),%rax
  mov    -0xb8(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void gg_debug(int level, const char *format, ...) {
  va_list ap;
  int old_errno = errno;
  va_start(ap, format);
  gg_debug_common(NULL, level, format, ap);
  va_end(ap);
  errno = old_errno;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gg_debug>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    D1(%rip),%r13
  mov    0x0(%r13),%r14d
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    $0x0,%edi
  call   <gg_debug_common@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r14d,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void gg_debug(int level, const char *format, ...) {
  va_list ap;
  int old_errno = errno;
  va_start(ap, format);
  gg_debug_common(NULL, level, format, ap);
  va_end(ap);
  errno = old_errno;
}
```