ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CfgDepBase_NEXT_SEQ_OBJ>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rdx),%ebp
  mov    %ebp,%ebx
  test   %ebp,%ebp
  jne    L57
L46:
  mov    %ebx,0x0(%r13)
  mov    %ebp,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  lea    -0x1(%rcx),%ebx
  lea    0x4(%rsp),%rdi
  mov    %ebx,%esi
  call   <CfgDepBase_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L46
  test   %ebx,%ebx
  je     L46
  lea    0x4(%rsp),%r14
L39:
  sub    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <CfgDepBase_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L46
  test   %ebx,%ebx
  jne    L39
  jmp    L46
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CfgDepBase_NEXT_SEQ_OBJ(cc, ss, oc, os) int *cc, *ss, oc, os;
{
  int c, i, b;
  c = oc - 1;
  if (c != 0) {
    i = os - 1;
    CfgDepBase_XST_SEQ_OBJ(&b, i);
    while (b != 1 && i != 0) {
      i = i - 1;
      CfgDepBase_XST_SEQ_OBJ(&b, i);
    }
    *ss = i;
    *cc = c;
  } else {
    *ss = 0;
    *cc = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CfgDepBase_NEXT_SEQ_OBJ>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sub    $0x1,%edx
  mov    %edx,%ebp
  jne    L36
L59:
  mov    %ebx,0x0(%r13)
  mov    %ebp,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L36:
  lea    -0x1(%rcx),%ebx
  lea    0x4(%rsp),%r14
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <CfgDepBase_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  jne    L26
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L53:
  sub    $0x1,%ebx
  xor    %eax,%eax
  mov    %r14,%rdi
  mov    %ebx,%esi
  call   <CfgDepBase_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L59
L26:
  test   %ebx,%ebx
  jne    L53
  xor    %ebx,%ebx
  jmp    L59
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CfgDepBase_NEXT_SEQ_OBJ(cc, ss, oc, os) int *cc, *ss, oc, os;
{
  int c, i, b;
  c = oc - 1;
  if (c != 0) {
    i = os - 1;
    CfgDepBase_XST_SEQ_OBJ(&b, i);
    while (b != 1 && i != 0) {
      i = i - 1;
      CfgDepBase_XST_SEQ_OBJ(&b, i);
    }
    *ss = i;
    *cc = c;
  } else {
    *ss = 0;
    *cc = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<CfgDepBase_NEXT_SEQ_OBJ>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sub    $0x1,%edx
  mov    %edx,%ebp
  jne    L30
L69:
  mov    %ebx,0x0(%r13)
  mov    %ebp,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L30:
  lea    -0x1(%rcx),%ebx
  lea    0x4(%rsp),%r14
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <CfgDepBase_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  jne    L8
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L60:
  sub    $0x1,%ebx
  xor    %eax,%eax
  mov    %r14,%rdi
  mov    %ebx,%esi
  call   <CfgDepBase_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L69
L8:
  test   %ebx,%ebx
  jne    L60
  xor    %ebx,%ebx
  jmp    L69
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CfgDepBase_NEXT_SEQ_OBJ(cc, ss, oc, os) int *cc, *ss, oc, os;
{
  int c, i, b;
  c = oc - 1;
  if (c != 0) {
    i = os - 1;
    CfgDepBase_XST_SEQ_OBJ(&b, i);
    while (b != 1 && i != 0) {
      i = i - 1;
      CfgDepBase_XST_SEQ_OBJ(&b, i);
    }
    *ss = i;
    *cc = c;
  } else {
    *ss = 0;
    *cc = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_magic_index_at_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <magic_index@plt>
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int test_magic_index_at_end() {
  int array[] = {-1, 0, 1, 2, 4};
  return 4 == magic_index(array, 0, 4);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_magic_index_at_end>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    $0x0,%esi
  call   <magic_index@plt>
  cmp    $0x4,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_magic_index_at_end() {
  int array[] = {-1, 0, 1, 2, 4};
  return 4 == magic_index(array, 0, 4);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_magic_index_at_end>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0xffffffff,%eax
  mov    %rsp,%rdi
  movl   $0x4,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x8(%rsp)
  call   <magic_index@plt>
  cmp    $0x4,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_magic_index_at_end() {
  int array[] = {-1, 0, 1, 2, 4};
  return 4 == magic_index(array, 0, 4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_magic_index_at_end>:
  endbr64
  sub    $0x28,%rsp
  movdqa D0(%rip),%xmm0
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x4,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <magic_index@plt>
  cmp    $0x4,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: byte[16]

tool: {"D0": [0xff,0xff,0xff,0xff,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int test_magic_index_at_end() {
  int array[] = {-1, 0, 1, 2, 4};
  return 4 == magic_index(array, 0, 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_div_mulhi64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    $0x20,%edx
  mov    -0x34(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    $0x20,%edx
  mov    -0x38(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    $0x20,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  add    %esi,%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x20,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    $0x20,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t _div_mulhi64(const uint64_t a, const uint64_t b) {
  const uint32_t a_lo = (const uint32_t)a;
  const uint32_t a_hi = (const uint32_t)(a >> 32);
  const uint32_t b_lo = (const uint32_t)b;
  const uint32_t b_hi = (const uint32_t)(b >> 32);
  const uint64_t a_x_b_mid = (const uint64_t)a_hi * b_lo;
  const uint64_t b_x_a_mid = (const uint64_t)b_hi * a_lo;
  const uint64_t a_x_b_lo = (const uint64_t)a_lo * b_lo;
  const uint64_t a_x_b_hi = (const uint64_t)a_hi * b_hi;
  const uint32_t carry_bits = ((uint64_t)(uint32_t)a_x_b_mid + (uint64_t)(uint32_t)b_x_a_mid + (a_x_b_lo >> 32)) >> 32;
  const uint64_t multhi = a_x_b_hi + (a_x_b_mid >> 32) + (b_x_a_mid >> 32) + carry_bits;
  return multhi;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_div_mulhi64>:
  endbr64
  mov    %edi,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  mov    %eax,%r11d
  mov    %esi,%r9d
  sar    %cl,%r9d
  mov    %eax,%edx
  imul   %esi,%edx
  mov    %edi,%r8d
  imul   %r9d,%r8d
  mov    %edx,%eax
  sar    %cl,%eax
  mov    %r11d,%ecx
  imul   %r9d,%ecx
  add    %ecx,%eax
  mov    %r8d,%r10d
  mov    $0x20,%ecx
  sar    %cl,%r10d
  add    %r10d,%eax
  imul   %esi,%edi
  mov    $0x20,%ecx
  sar    %cl,%edi
  add    %r8d,%edx
  add    %edx,%edi
  sar    %cl,%edi
  add    %edi,%eax
  ret
```

assistant: ```c
uint64_t _div_mulhi64(const uint64_t a, const uint64_t b) {
  const uint32_t a_lo = (const uint32_t)a;
  const uint32_t a_hi = (const uint32_t)(a >> 32);
  const uint32_t b_lo = (const uint32_t)b;
  const uint32_t b_hi = (const uint32_t)(b >> 32);
  const uint64_t a_x_b_mid = (const uint64_t)a_hi * b_lo;
  const uint64_t b_x_a_mid = (const uint64_t)b_hi * a_lo;
  const uint64_t a_x_b_lo = (const uint64_t)a_lo * b_lo;
  const uint64_t a_x_b_hi = (const uint64_t)a_hi * b_hi;
  const uint32_t carry_bits = ((uint64_t)(uint32_t)a_x_b_mid + (uint64_t)(uint32_t)b_x_a_mid + (a_x_b_lo >> 32)) >> 32;
  const uint64_t multhi = a_x_b_hi + (a_x_b_mid >> 32) + (b_x_a_mid >> 32) + carry_bits;
  return multhi;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_div_mulhi64>:
  endbr64
  mov    $0x20,%ecx
  mov    %edi,%eax
  mov    %esi,%r9d
  mov    %edi,%r8d
  sar    %cl,%eax
  sar    %cl,%r9d
  imul   %esi,%edi
  mov    %eax,%edx
  imul   %r9d,%r8d
  mov    %eax,%r11d
  imul   %esi,%edx
  mov    %r8d,%r10d
  mov    %edx,%eax
  add    %r8d,%edx
  sar    %cl,%eax
  mov    %r11d,%ecx
  imul   %r9d,%ecx
  add    %ecx,%eax
  mov    $0x20,%ecx
  sar    %cl,%r10d
  mov    $0x20,%ecx
  sar    %cl,%edi
  add    %r10d,%eax
  add    %edx,%edi
  sar    %cl,%edi
  add    %edi,%eax
  ret
```

assistant: ```c
uint64_t _div_mulhi64(const uint64_t a, const uint64_t b) {
  const uint32_t a_lo = (const uint32_t)a;
  const uint32_t a_hi = (const uint32_t)(a >> 32);
  const uint32_t b_lo = (const uint32_t)b;
  const uint32_t b_hi = (const uint32_t)(b >> 32);
  const uint64_t a_x_b_mid = (const uint64_t)a_hi * b_lo;
  const uint64_t b_x_a_mid = (const uint64_t)b_hi * a_lo;
  const uint64_t a_x_b_lo = (const uint64_t)a_lo * b_lo;
  const uint64_t a_x_b_hi = (const uint64_t)a_hi * b_hi;
  const uint32_t carry_bits = ((uint64_t)(uint32_t)a_x_b_mid + (uint64_t)(uint32_t)b_x_a_mid + (a_x_b_lo >> 32)) >> 32;
  const uint64_t multhi = a_x_b_hi + (a_x_b_mid >> 32) + (b_x_a_mid >> 32) + carry_bits;
  return multhi;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_div_mulhi64>:
  endbr64
  mov    $0x20,%ecx
  mov    %edi,%eax
  mov    %esi,%r9d
  mov    %edi,%r8d
  sar    %cl,%eax
  sar    %cl,%r9d
  imul   %esi,%edi
  mov    %eax,%edx
  imul   %r9d,%r8d
  mov    %eax,%r11d
  imul   %esi,%edx
  mov    %r8d,%r10d
  mov    %edx,%eax
  add    %r8d,%edx
  sar    %cl,%eax
  mov    %r11d,%ecx
  imul   %r9d,%ecx
  add    %ecx,%eax
  mov    $0x20,%ecx
  sar    %cl,%r10d
  mov    $0x20,%ecx
  sar    %cl,%edi
  add    %r10d,%eax
  add    %edx,%edi
  sar    %cl,%edi
  add    %edi,%eax
  ret
```

assistant: ```c
uint64_t _div_mulhi64(const uint64_t a, const uint64_t b) {
  const uint32_t a_lo = (const uint32_t)a;
  const uint32_t a_hi = (const uint32_t)(a >> 32);
  const uint32_t b_lo = (const uint32_t)b;
  const uint32_t b_hi = (const uint32_t)(b >> 32);
  const uint64_t a_x_b_mid = (const uint64_t)a_hi * b_lo;
  const uint64_t b_x_a_mid = (const uint64_t)b_hi * a_lo;
  const uint64_t a_x_b_lo = (const uint64_t)a_lo * b_lo;
  const uint64_t a_x_b_hi = (const uint64_t)a_hi * b_hi;
  const uint32_t carry_bits = ((uint64_t)(uint32_t)a_x_b_mid + (uint64_t)(uint32_t)b_x_a_mid + (a_x_b_lo >> 32)) >> 32;
  const uint64_t multhi = a_x_b_hi + (a_x_b_mid >> 32) + (b_x_a_mid >> 32) + carry_bits;
  return multhi;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mdb_index_swap_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L6
L3:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x8(%rbp)
L6:
  cmpl   $0x0,-0x8(%rbp)
  jns    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mdb_index_swap_n(unsigned char *src, int sz, unsigned char *dest) {
  int i, j = 0;
  for (i = sz - 1; i >= 0; i--) {
    dest[j++] = src[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mdb_index_swap_n>:
  endbr64
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L7
  cltq
  add    %rax,%rdi
  mov    %rdx,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x1(%rdx,%rcx,1),%rcx
L19:
  movzbl (%rdi),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rdi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L19
L7:
  ret
```

assistant: ```c
void mdb_index_swap_n(unsigned char *src, int sz, unsigned char *dest) {
  int i, j = 0;
  for (i = sz - 1; i >= 0; i--) {
    dest[j++] = src[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mdb_index_swap_n>:
  endbr64
  sub    $0x1,%esi
  js     L17
  movslq %esi,%rax
  mov    %esi,%esi
  add    %rax,%rdi
  lea    0x1(%rdx,%rsi,1),%rcx
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  sub    $0x1,%rdi
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L3
L17:
  ret
```

assistant: ```c
void mdb_index_swap_n(unsigned char *src, int sz, unsigned char *dest) {
  int i, j = 0;
  for (i = sz - 1; i >= 0; i--) {
    dest[j++] = src[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mdb_index_swap_n>:
  endbr64
  sub    $0x1,%esi
  js     L13
  movslq %esi,%rax
  mov    %esi,%esi
  add    %rax,%rdi
  lea    0x1(%rdx,%rsi,1),%rcx
  cs nopw 0x0(%rax,%rax,1)
L8:
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  sub    $0x1,%rdi
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L8
L13:
  ret
```

assistant: ```c
void mdb_index_swap_n(unsigned char *src, int sz, unsigned char *dest) {
  int i, j = 0;
  for (i = sz - 1; i >= 0; i--) {
    dest[j++] = src[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rsa_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L20
  mov    $0x0,%eax
  call   <RSA_new@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L57
  mov    $0x2,%eax
  jmp    L7
L57:
  mov    $0x0,%eax
  jmp    L7
L20:
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L56
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <RSA_free@plt>
  mov    -0x10(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x2,%eax
  jmp    L7
L56:
  mov    $0x1,%eax
L7:
  leave
  ret
```

assistant: ```c
int rsa_cb(int operation, ASN1_VALUE **pval, const ASN1_ITEM *it) {
  if (operation == ASN1_OP_NEW_PRE) {
    *pval = (ASN1_VALUE *)RSA_new();
    if (*pval)
      return 2;
    return 0;
  } else if (operation == ASN1_OP_FREE_PRE) {
    RSA_free((RSA *)*pval);
    *pval = NULL;
    return 2;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rsa_cb>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    D4(%rip),%rax
  cmp    %edi,(%rax)
  je     L5
  mov    $0x1,%eax
  mov    D17(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L31
L35:
  pop    %rbx
  ret
L5:
  mov    $0x0,%eax
  call   <RSA_new@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  jmp    L35
L31:
  mov    (%rsi),%rdi
  call   <RSA_free@plt>
  movq   $0x0,(%rbx)
  mov    $0x2,%eax
  jmp    L35
```

assistant: ```c
int rsa_cb(int operation, ASN1_VALUE **pval, const ASN1_ITEM *it) {
  if (operation == ASN1_OP_NEW_PRE) {
    *pval = (ASN1_VALUE *)RSA_new();
    if (*pval)
      return 2;
    return 0;
  } else if (operation == ASN1_OP_FREE_PRE) {
    RSA_free((RSA *)*pval);
    *pval = NULL;
    return 2;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rsa_cb>:
  endbr64
  mov    D10(%rip),%rax
  push   %rbx
  mov    %rsi,%rbx
  cmp    %edi,(%rax)
  je     L12
  mov    D7(%rip),%rdx
  mov    $0x1,%eax
  cmp    %edi,(%rdx)
  je     L15
  pop    %rbx
  ret
  nopl   (%rax)
L12:
  xor    %eax,%eax
  call   <RSA_new@plt>
  test   %rax,%rax
  mov    %rax,(%rbx)
  pop    %rbx
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
  nop
L15:
  mov    (%rsi),%rdi
  call   <RSA_free@plt>
  movq   $0x0,(%rbx)
  mov    $0x2,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rsa_cb(int operation, ASN1_VALUE **pval, const ASN1_ITEM *it) {
  if (operation == ASN1_OP_NEW_PRE) {
    *pval = (ASN1_VALUE *)RSA_new();
    if (*pval)
      return 2;
    return 0;
  } else if (operation == ASN1_OP_FREE_PRE) {
    RSA_free((RSA *)*pval);
    *pval = NULL;
    return 2;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rsa_cb>:
  endbr64
  mov    D10(%rip),%rax
  push   %rbx
  mov    %rsi,%rbx
  cmp    %edi,(%rax)
  je     L10
  mov    D11(%rip),%rdx
  mov    $0x1,%eax
  cmp    %edi,(%rdx)
  je     L15
  pop    %rbx
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  call   <RSA_new@plt>
  test   %rax,%rax
  mov    %rax,(%rbx)
  pop    %rbx
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
  nop
L15:
  mov    (%rsi),%rdi
  call   <RSA_free@plt>
  movq   $0x0,(%rbx)
  mov    $0x2,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rsa_cb(int operation, ASN1_VALUE **pval, const ASN1_ITEM *it) {
  if (operation == ASN1_OP_NEW_PRE) {
    *pval = (ASN1_VALUE *)RSA_new();
    if (*pval)
      return 2;
    return 0;
  } else if (operation == ASN1_OP_FREE_PRE) {
    RSA_free((RSA *)*pval);
    *pval = NULL;
    return 2;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  D13(%rip),%xmm0
  mov    D58(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dotest@plt>
  movsd  D8(%rip),%xmm0
  mov    D12(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dotest@plt>
  movsd  D36(%rip),%xmm0
  mov    D17(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dotest@plt>
  movsd  D16(%rip),%xmm0
  mov    D2(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dotest@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D13
type_infered: byte[8]
name: read_data
arguments: tag: D58
type_infered: byte[8]
name: read_data
arguments: tag: D8
type_infered: byte[8]
name: read_data
arguments: tag: D12
type_infered: byte[8]
name: read_data
arguments: tag: D36
type_infered: byte[8]
name: read_data
arguments: tag: D17
type_infered: byte[8]
name: read_data
arguments: tag: D16
type_infered: byte[8]
name: read_data
arguments: tag: D2
type_infered: byte[8]

tool: {"D13": [0xb6,0xbc,0x33,0x56,0xd3,0xea,0x4b,0x3e]}

tool: {"D58": [0xb2,0x1c,0x3f,0x59,0xd3,0xea,0x5b,0x3e]}

tool: {"D8": [0x2c,0x9e,0x78,0xde,0x43,0x0d,0x08,0x3e]}

tool: {"D12": [0x03,0xc6,0x9c,0xde,0x43,0x0d,0x18,0x3e]}

tool: {"D36": [0x61,0xb3,0x15,0xd1,0xb3,0xf8,0xc4,0x3e]}

tool: {"D17": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xd4,0x3e]}

tool: {"D16": [0xd6,0xe4,0x6d,0x19,0x2b,0x1b,0x80,0x3e]}

tool: {"D2": [0x2b,0x69,0xa4,0x29,0x2b,0x1b,0x90,0x3e]}

assistant: ```c
int main() {
  dotest(2.6e-08, 1.29999999155e-08);
  dotest(1.4e-09, 6.999999997549999e-10);
  dotest(5.0e-06, 2.499996875007812e-06);
  dotest(2.4e-07, 1.1999999280000085e-07);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D25(%rip),%xmm1
  movsd  D7(%rip),%xmm0
  call   <dotest@plt>
  movsd  D2(%rip),%xmm1
  movsd  D46(%rip),%xmm0
  call   <dotest@plt>
  movsd  D62(%rip),%xmm1
  movsd  D33(%rip),%xmm0
  call   <dotest@plt>
  movsd  D63(%rip),%xmm1
  movsd  D67(%rip),%xmm0
  call   <dotest@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
type_infered: byte[8]
name: parse_data
arguments: data_label: D7
type_infered: byte[8]
name: parse_data
arguments: data_label: D2
type_infered: byte[8]
name: parse_data
arguments: data_label: D46
type_infered: byte[8]
name: parse_data
arguments: data_label: D62
type_infered: byte[8]
name: parse_data
arguments: data_label: D33
type_infered: byte[8]
name: parse_data
arguments: data_label: D63
type_infered: byte[8]
name: parse_data
arguments: data_label: D67
type_infered: byte[8]

tool: {"D25": [0xb6,0xbc,0x33,0x56,0xd3,0xea,0x4b,0x3e]}

tool: {"D7": [0xb2,0x1c,0x3f,0x59,0xd3,0xea,0x5b,0x3e]}

tool: {"D2": [0x2c,0x9e,0x78,0xde,0x43,0x0d,0x08,0x3e]}

tool: {"D46": [0x03,0xc6,0x9c,0xde,0x43,0x0d,0x18,0x3e]}

tool: {"D62": [0x61,0xb3,0x15,0xd1,0xb3,0xf8,0xc4,0x3e]}

tool: {"D33": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xd4,0x3e]}

tool: {"D63": [0xd6,0xe4,0x6d,0x19,0x2b,0x1b,0x80,0x3e]}

tool: {"D67": [0x2b,0x69,0xa4,0x29,0x2b,0x1b,0x90,0x3e]}

assistant: ```c
int main() {
  dotest(2.6e-08, 1.29999999155e-08);
  dotest(1.4e-09, 6.999999997549999e-10);
  dotest(5.0e-06, 2.499996875007812e-06);
  dotest(2.4e-07, 1.1999999280000085e-07);
}
```