user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D113(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0x68(%rbp)
  cmpl   $0x1,-0x68(%rbp)
  je     L4
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L12
L4:
  movsd  D99(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D68(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D124(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D122(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x40(%rbp),%xmm3
  movsd  -0x60(%rbp),%xmm1
  movsd  D118(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  lea    -0x50(%rbp),%rsi
  lea    -0x58(%rbp),%rcx
  mov    $0x1,%edx
  movapd %xmm3,%xmm1
  mov    %rcx,%rdi
  movq   %rax,%xmm0
  call   <exactM@plt>
  mov    %eax,-0x64(%rbp)
  cmpl   $0x0,-0x64(%rbp)
  je     L16
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L16:
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movsd  -0x50(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x48(%rbp),%xmm1
  movsd  -0x58(%rbp),%xmm0
  mulsd  -0x48(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D113
type_infered: f64
name: unpack_data
arguments: label: D64
type_infered: string
name: unpack_data
arguments: label: D41
type_infered: string
name: unpack_data
arguments: label: D67
type_infered: string
name: unpack_data
arguments: label: D99
type_infered: byte[8]
name: unpack_data
arguments: label: D68
type_infered: byte[8]
name: unpack_data
arguments: label: D10
type_infered: byte[8]
name: unpack_data
arguments: label: D124
type_infered: byte[8]
name: unpack_data
arguments: label: D122
type_infered: byte[8]
name: unpack_data
arguments: label: D118
type_infered: f64
name: unpack_data
arguments: label: D66
type_infered: string
name: unpack_data
arguments: label: D89
type_infered: string
name: unpack_data
arguments: label: D85
type_infered: string

tool: D113: 31556926

tool: D64: Enter  r  (in km; e.g. 600.0):   

tool: D41: %lf

tool: D67: ... input error; exiting

tool: {"D99": [0x11,0xea,0x2d,0x81,0x99,0x97,0x71,0x3d]}

tool: {"D68": [0x95,0xd6,0x26,0xe8,0x0b,0x2e,0x11,0x3e]}

tool: {"D10": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x7a,0x3e]}

tool: {"D124": [0x9b,0x2b,0xa1,0x86,0x9b,0x84,0x06,0x3d]}

tool: {"D122": [0x95,0x64,0x79,0xe1,0x7f,0xfd,0xa5,0x3d]}

tool: D118: 1000

tool: D66: 

FAILURE in evaluatine exactM() !!!!



tool: D89: Results from Test M:

tool: D85:      alpha = %8.5f (m/a),  D_rr = alpha' = %11.8f (1/a)


assistant: ```c
int main() {
  double r, alpha, strainrate;
  int scanret;
  const double secpera = 31556926.0;
  printf("Enter  r  (in km; e.g. 600.0):   ");
  scanret = scanf("%lf", &r);
  if (scanret != 1) {
    printf("... input error; exiting\n");
    return 1;
  }
  double EPS_ABS[] = {1.0e-12, 1.0e-9, 1.0e-7};
  double EPS_REL[] = {0.0, 1.0e-14, 1.0e-11};
  int eMresult;
  eMresult = exactM(r * 1000.0, &alpha, &strainrate, EPS_ABS[0], EPS_REL[0], 1);
  if (eMresult != 0) {
    printf("\n\nFAILURE in evaluatine exactM() !!!!\n\n\n");
  }
  printf("Results from Test M:\n");
  printf("     alpha = %8.5f (m/a),  D_rr = alpha' = %11.8f (1/a)\n", alpha * secpera, strainrate * secpera);
  return 0;
}
```