ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdup(const char *str) {
  size_t n = strlen(str) + 1;
  char *dup = malloc(n);
  if (dup) {
    strcpy(dup, str);
  }
  return dup;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strdup(const char *str) {
  size_t n = strlen(str) + 1;
  char *dup = malloc(n);
  if (dup) {
    strcpy(dup, str);
  }
  return dup;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *str) {
  size_t n = strlen(str) + 1;
  char *dup = malloc(n);
  if (dup) {
    strcpy(dup, str);
  }
  return dup;
}
```
user: What is the c source code of the assembly code below?

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *str) {
  size_t n = strlen(str) + 1;
  char *dup = malloc(n);
  if (dup) {
    strcpy(dup, str);
  }
  return dup;
}
```
user: What is the c source code of the assembly code below:

```asm
<print_proc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <write_log_v@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int print_proc(const char *fmt, ...) {
  int ret;
  va_list arg;
  va_start(arg, fmt);
  ret = write_log_v(0, fmt, arg);
  va_end(arg);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_proc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <write_log_v@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int print_proc(const char *fmt, ...) {
  int ret;
  va_list arg;
  va_start(arg, fmt);
  ret = write_log_v(0, fmt, arg);
  va_end(arg);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_proc>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <write_log_v@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int print_proc(const char *fmt, ...) {
  int ret;
  va_list arg;
  va_start(arg, fmt);
  ret = write_log_v(0, fmt, arg);
  va_end(arg);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_proc>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <write_log_v@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int print_proc(const char *fmt, ...) {
  int ret;
  va_list arg;
  va_start(arg, fmt);
  ret = write_log_v(0, fmt, arg);
  va_end(arg);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_cut_both>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x5,-0x38(%rbp)
  movl   $0x8,-0x34(%rbp)
  movl   $0x9,-0x30(%rbp)
  movl   $0xa,-0x2c(%rbp)
  movl   $0x11,-0x28(%rbp)
  movl   $0x11,-0x24(%rbp)
  movl   $0x14,-0x20(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L31
L35:
  mov    -0x44(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <cut_rec@plt>
  mov    %rax,%rbx
  mov    -0x44(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <cut_dyn@plt>
  cmp    %rax,%rbx
  je     L17
  mov    $0x0,%eax
  jmp    L6
L17:
  addl   $0x1,-0x44(%rbp)
L31:
  cmpl   $0x13,-0x44(%rbp)
  jle    L35
  mov    $0x1,%eax
L6:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int test_cut_both() {
  int prices[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  for (int i = 0; i < 20; i++) {
    if (cut_rec(prices, 9, i) != cut_dyn(prices, 9, i))
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_cut_both>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  movl   $0xa,0x14(%rsp)
  movl   $0x11,0x18(%rsp)
  movl   $0x11,0x1c(%rsp)
  movl   $0x14,0x20(%rsp)
  mov    $0x0,%ebx
  mov    %rsp,%r12
L16:
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r12,%rdi
  call   <cut_rec@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r12,%rdi
  call   <cut_dyn@plt>
  cmp    %rax,%rbp
  jne    L19
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L16
  mov    $0x1,%eax
  jmp    L38
L19:
  mov    $0x0,%eax
L38:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_cut_both() {
  int prices[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  for (int i = 0; i < 20; i++) {
    if (cut_rec(prices, 9, i) != cut_dyn(prices, 9, i))
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_cut_both>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x100000000,%rax
  mov    %rsp,%r12
  movl   $0x14,0x20(%rsp)
  mov    %rax,(%rsp)
  movabs $0x800000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x1100000011,%rax
  mov    %rax,0x18(%rsp)
  jmp    L19
  nopl   0x0(%rax)
L7:
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  je     L12
L19:
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r12,%rdi
  call   <cut_rec@plt>
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <cut_dyn@plt>
  cmp    %rax,%rbp
  je     L7
  xor    %eax,%eax
L20:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x1,%eax
  jmp    L20
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_cut_both() {
  int prices[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  for (int i = 0; i < 20; i++) {
    if (cut_rec(prices, 9, i) != cut_dyn(prices, 9, i))
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_cut_both>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movl   $0x14,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  jmp    L29
  nopl   0x0(%rax)
L17:
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  je     L45
L29:
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r12,%rdi
  call   <cut_rec@plt>
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <cut_dyn@plt>
  cmp    %rax,%rbp
  je     L17
  xor    %eax,%eax
L22:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L45:
  mov    $0x1,%eax
  jmp    L22
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type: byte[16]
name: retrieve_data
arguments: label: D2
type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D2": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

assistant: ```c
int test_cut_both() {
  int prices[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  for (int i = 0; i < 20; i++) {
    if (cut_rec(prices, 9, i) != cut_dyn(prices, 9, i))
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  ror    $0x7,%eax
  or     $0x11b22fd8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else {
        state[local1] >>= ((state[local1] >> 4U) & 7U) | 1UL;
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy13;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] >> 7U) | (state[0UL] << 25U)) | 296890328U;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  ror    $0x7,%eax
  or     $0x11b22fd8,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else {
        state[local1] >>= ((state[local1] >> 4U) & 7U) | 1UL;
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy13;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] >> 7U) | (state[0UL] << 25U)) | 296890328U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  ror    $0x7,%eax
  or     $0x11b22fd8,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else {
        state[local1] >>= ((state[local1] >> 4U) & 7U) | 1UL;
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy13;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] >> 7U) | (state[0UL] << 25U)) | 296890328U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  ror    $0x7,%eax
  or     $0x11b22fd8,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else {
        state[local1] >>= ((state[local1] >> 4U) & 7U) | 1UL;
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy13;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] >> 7U) | (state[0UL] << 25U)) | 296890328U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_client_list_make_auth_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <rand16@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand16@plt>
  mov    %eax,%edx
  lea    -0x20(%rbp),%rax
  mov    %ebx,%ecx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <safe_asprintf@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: %04hx%04hx

assistant: ```c
char *_client_list_make_auth_token(const char ip[], const char mac[]) {
  char *token;
  safe_asprintf(&token, "%04hx%04hx", rand16(), rand16());
  return token;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_client_list_make_auth_token>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <rand16@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand16@plt>
  mov    %eax,%edx
  mov    %rsp,%rdi
  mov    %ebx,%ecx
  lea    D7(%rip),%rsi
  call   <safe_asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: %04hx%04hx

assistant: ```c
char *_client_list_make_auth_token(const char ip[], const char mac[]) {
  char *token;
  safe_asprintf(&token, "%04hx%04hx", rand16(), rand16());
  return token;
}
```
user: What is the c source code of the assembly code below?

```asm
<_client_list_make_auth_token>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <rand16@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <rand16@plt>
  mov    %rsp,%rdi
  mov    %r12d,%ecx
  lea    D3(%rip),%rsi
  mov    %eax,%edx
  call   <safe_asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: %04hx%04hx

assistant: ```c
char *_client_list_make_auth_token(const char ip[], const char mac[]) {
  char *token;
  safe_asprintf(&token, "%04hx%04hx", rand16(), rand16());
  return token;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_client_list_make_auth_token>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <rand16@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <rand16@plt>
  mov    %rsp,%rdi
  mov    %r12d,%ecx
  lea    D2(%rip),%rsi
  mov    %eax,%edx
  call   <safe_asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: %04hx%04hx

assistant: ```c
char *_client_list_make_auth_token(const char ip[], const char mac[]) {
  char *token;
  safe_asprintf(&token, "%04hx%04hx", rand16(), rand16());
  return token;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tmx_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tmx_alloc_func@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *tmx_strdup(const char *str) {
  char *res = (char *)tmx_alloc_func(NULL, strlen(str) + 1);
  strcpy(res, str);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tmx_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    $0x0,%edi
  call   <tmx_alloc_func@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *tmx_strdup(const char *str) {
  char *res = (char *)tmx_alloc_func(NULL, strlen(str) + 1);
  strcpy(res, str);
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<tmx_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edi,%edi
  lea    0x1(%rax),%rsi
  call   <tmx_alloc_func@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *tmx_strdup(const char *str) {
  char *res = (char *)tmx_alloc_func(NULL, strlen(str) + 1);
  strcpy(res, str);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tmx_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edi,%edi
  lea    0x1(%rax),%rsi
  call   <tmx_alloc_func@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *tmx_strdup(const char *str) {
  char *res = (char *)tmx_alloc_func(NULL, strlen(str) + 1);
  strcpy(res, str);
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GenerateString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L7
L18:
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x1c(%rbp),%eax
  lea    0x61(%rax),%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  mov    %ebx,%edx
  mov    %dl,(%rax)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addl   $0x1,-0x1c(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void GenerateString(int x, char *s1) {
  int i;
  char *s2;
  s2 = (char *)malloc(sizeof(char) * (1 << (x - 1)));
  for (i = 1; i < x; i++) {
    strcpy(s2, s1);
    s2[strlen(s1)] = 'a' + i;
    strcat(s2, s1);
    strcpy(s1, s2);
  }
  free(s2);
}
```