ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *p;
  (void)argc;
  (void)argv;
  p = (void *)(fmax);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *p;
  (void)argc;
  (void)argv;
  p = (void *)(fmax);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *p;
  (void)argc;
  (void)argv;
  p = (void *)(fmax);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *p;
  (void)argc;
  (void)argv;
  p = (void *)(fmax);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<puti16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  mov    $0x2d,%edi
  call   <dh_putc@plt>
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%edi
  call   <putu16@plt>
  jmp    L6
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putu16@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void puti16(int num) {
  if (num < 0) {
    dh_putc('-');
    putu16(-num);
  } else {
    putu16(num);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<puti16>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  js     L7
  call   <putu16@plt>
L17:
  pop    %rbx
  ret
L7:
  mov    $0x2d,%edi
  call   <dh_putc@plt>
  neg    %ebx
  mov    %ebx,%edi
  call   <putu16@plt>
  jmp    L17
```

assistant: ```c
void puti16(int num) {
  if (num < 0) {
    dh_putc('-');
    putu16(-num);
  } else {
    putu16(num);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<puti16>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  test   %edi,%edi
  js     L2
  pop    %rbp
  jmp    1070 <putu16@plt>
  nopl   0x0(%rax)
L2:
  mov    $0x2d,%edi
  call   <dh_putc@plt>
  mov    %ebp,%edi
  pop    %rbp
  neg    %edi
  jmp    1070 <putu16@plt>
```

assistant: ```c
void puti16(int num) {
  if (num < 0) {
    dh_putc('-');
    putu16(-num);
  } else {
    putu16(num);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<puti16>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  test   %edi,%edi
  js     L2
  pop    %rbp
  jmp    1070 <putu16@plt>
  nopl   0x0(%rax)
L2:
  mov    $0x2d,%edi
  call   <dh_putc@plt>
  mov    %ebp,%edi
  pop    %rbp
  neg    %edi
  jmp    1070 <putu16@plt>
```

assistant: ```c
void puti16(int num) {
  if (num < 0) {
    dh_putc('-');
    putu16(-num);
  } else {
    putu16(num);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_wctomb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L109
  mov    $0x0,%eax
  jmp    L118
L109:
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x10ffff,-0x1c(%rbp)
  jg     L42
  cmpl   $0xd7ff,-0x1c(%rbp)
  jle    L108
  cmpl   $0xdfff,-0x1c(%rbp)
  jg     L108
L42:
  mov    $0xffffffff,%eax
  jmp    L118
L108:
  cmpl   $0xffff,-0x1c(%rbp)
  jle    L111
  mov    -0x1c(%rbp),%eax
  sar    $0x12,%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  or     $0xfffffff0,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
L111:
  cmpl   $0x7ff,-0x1c(%rbp)
  jle    L153
  cmpl   $0xffff,-0x1c(%rbp)
  jg     L52
  mov    $0xffffffe0,%esi
  jmp    L25
L52:
  mov    $0xffffff80,%esi
L25:
  mov    -0x1c(%rbp),%eax
  sar    $0xc,%eax
  and    $0x3f,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
L153:
  cmpl   $0x7f,-0x1c(%rbp)
  jle    L110
  cmpl   $0x7ff,-0x1c(%rbp)
  jg     L92
  mov    $0xffffffc0,%esi
  jmp    L9
L92:
  mov    $0xffffff80,%esi
L9:
  mov    -0x1c(%rbp),%eax
  sar    $0x6,%eax
  and    $0x3f,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
L110:
  cmpl   $0x0,-0x1c(%rbp)
  js     L90
  cmpl   $0x7f,-0x1c(%rbp)
  jg     L60
  mov    -0x1c(%rbp),%eax
  and    $0x7f,%eax
  jmp    L23
L60:
  mov    -0x1c(%rbp),%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
L23:
  mov    -0x4(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x4(%rbp)
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
L90:
  mov    -0x4(%rbp),%eax
L118:
  pop    %rbp
  ret
```

assistant: ```c
int ft_wctomb(char *s, wchar_t wc) {
  int bytes;
  if (!s)
    return (0);
  bytes = 0;
  if (wc > 0x10FFFF || (wc >= 0xD800 && wc <= 0xDFFF))
    return (-1);
  if (wc > 0xFFFF)
    *(s + bytes++) = 0xF0 | ((wc & 0x1C0000) >> 18);
  if (wc > 0x7FF)
    *(s + bytes++) = (wc <= 0xFFFF ? 0xE0 : 0x80) | ((wc & 0x3F000) >> 12);
  if (wc > 0x7F)
    *(s + bytes++) = (wc <= 0x7FF ? 0xC0 : 0x80) | ((wc & 0xFC0) >> 6);
  if (wc >= 0x00)
    *(s + bytes++) = (wc <= 0x7F ? 0x0 | (wc & 0x7F) : 0x80 | (wc & 0x3F));
  return (bytes);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_wctomb>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%eax
  test   %rdi,%rdi
  je     L12
  lea    -0xd800(%rsi),%ecx
  cmp    $0x7ff,%ecx
  jbe    L42
  cmp    $0x10ffff,%esi
  jg     L42
  cmp    $0xffff,%esi
  jle    L5
  mov    %esi,%ecx
  sar    $0x12,%ecx
  or     $0xfffffff0,%ecx
  mov    %cl,(%rdi)
  mov    $0x1,%ecx
  mov    $0xffffff80,%r8d
L35:
  lea    0x1(%rcx),%esi
  movslq %ecx,%rdi
  mov    %eax,%ecx
  sar    $0xc,%ecx
  and    $0x3f,%ecx
  or     %r8d,%ecx
  mov    %cl,(%rdx,%rdi,1)
  mov    $0xffffff80,%r8d
L26:
  lea    0x1(%rsi),%ecx
  movslq %esi,%rdi
  mov    %eax,%esi
  sar    $0x6,%esi
  and    $0x3f,%esi
  or     %r8d,%esi
  mov    %sil,(%rdx,%rdi,1)
  and    $0x3f,%eax
  or     $0xffffff80,%eax
L30:
  lea    0x1(%rcx),%esi
  movslq %ecx,%rcx
  mov    %al,(%rdx,%rcx,1)
L36:
  mov    %esi,%eax
  ret
L23:
  mov    $0x0,%ecx
  mov    $0xffffffe0,%r8d
  jmp    L35
L2:
  mov    $0x0,%esi
  mov    $0xffffffc0,%r8d
  jmp    L26
L12:
  mov    $0x0,%esi
  jmp    L36
L42:
  mov    $0xffffffff,%esi
  jmp    L36
L5:
  cmp    $0x7ff,%esi
  jg     L23
  cmp    $0x7f,%eax
  jg     L2
  mov    $0x0,%esi
  test   %eax,%eax
  js     L36
  mov    $0x0,%ecx
  jmp    L30
```

assistant: ```c
int ft_wctomb(char *s, wchar_t wc) {
  int bytes;
  if (!s)
    return (0);
  bytes = 0;
  if (wc > 0x10FFFF || (wc >= 0xD800 && wc <= 0xDFFF))
    return (-1);
  if (wc > 0xFFFF)
    *(s + bytes++) = 0xF0 | ((wc & 0x1C0000) >> 18);
  if (wc > 0x7FF)
    *(s + bytes++) = (wc <= 0xFFFF ? 0xE0 : 0x80) | ((wc & 0x3F000) >> 12);
  if (wc > 0x7F)
    *(s + bytes++) = (wc <= 0x7FF ? 0xC0 : 0x80) | ((wc & 0xFC0) >> 6);
  if (wc >= 0x00)
    *(s + bytes++) = (wc <= 0x7F ? 0x0 | (wc & 0x7F) : 0x80 | (wc & 0x3F));
  return (bytes);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_wctomb>:
  endbr64
  mov    %esi,%eax
  test   %rdi,%rdi
  je     L25
  lea    -0xd800(%rsi),%edx
  cmp    $0x7ff,%edx
  jbe    L27
  cmp    $0x10ffff,%esi
  jg     L27
  cmp    $0xffff,%esi
  jg     L42
  cmp    $0x7ff,%esi
  jg     L107
  cmp    $0x7f,%eax
  jg     L91
  test   %eax,%eax
  jns    L63
L25:
  xor    %r8d,%r8d
L47:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L42:
  mov    %esi,%edx
  lea    0x1(%rdi),%r9
  mov    $0x3,%esi
  mov    $0x4,%r8d
  sar    $0x12,%edx
  mov    $0x2,%ecx
  mov    $0xffffff80,%r10d
  or     $0xfffffff0,%edx
  mov    %dl,(%rdi)
L7:
  mov    %eax,%edx
  add    %rdi,%rcx
  sar    $0xc,%edx
  and    $0x3f,%edx
  or     %r10d,%edx
  mov    %dl,(%r9)
  mov    $0xffffff80,%r9d
L0:
  mov    %eax,%edx
  and    $0x3f,%eax
  add    %rsi,%rdi
  sar    $0x6,%edx
  or     $0xffffff80,%eax
  and    $0x3f,%edx
  or     %r9d,%edx
  mov    %dl,(%rcx)
  mov    %al,(%rdi)
L84:
  mov    %r8d,%eax
  ret
  nop
L63:
  mov    %al,(%rdi)
  mov    $0x1,%r8d
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L107:
  mov    %rdi,%r9
  mov    $0x2,%esi
  mov    $0x1,%ecx
  mov    $0x3,%r8d
  mov    $0xffffffe0,%r10d
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L91:
  mov    %rdi,%rcx
  mov    $0x1,%esi
  mov    $0x2,%r8d
  mov    $0xffffffc0,%r9d
  jmp    L0
L27:
  mov    $0xffffffff,%r8d
  jmp    L47
```

assistant: ```c
int ft_wctomb(char *s, wchar_t wc) {
  int bytes;
  if (!s)
    return (0);
  bytes = 0;
  if (wc > 0x10FFFF || (wc >= 0xD800 && wc <= 0xDFFF))
    return (-1);
  if (wc > 0xFFFF)
    *(s + bytes++) = 0xF0 | ((wc & 0x1C0000) >> 18);
  if (wc > 0x7FF)
    *(s + bytes++) = (wc <= 0xFFFF ? 0xE0 : 0x80) | ((wc & 0x3F000) >> 12);
  if (wc > 0x7F)
    *(s + bytes++) = (wc <= 0x7FF ? 0xC0 : 0x80) | ((wc & 0xFC0) >> 6);
  if (wc >= 0x00)
    *(s + bytes++) = (wc <= 0x7F ? 0x0 | (wc & 0x7F) : 0x80 | (wc & 0x3F));
  return (bytes);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_wctomb>:
  endbr64
  mov    %esi,%eax
  test   %rdi,%rdi
  je     L84
  lea    -0xd800(%rsi),%edx
  cmp    $0x7ff,%edx
  jbe    L88
  cmp    $0x10ffff,%esi
  jg     L88
  cmp    $0xffff,%esi
  jg     L9
  cmp    $0x7ff,%esi
  jg     L95
  cmp    $0x7f,%eax
  jg     L30
  test   %eax,%eax
  jns    L55
L84:
  xor    %r8d,%r8d
L79:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L9:
  mov    %esi,%edx
  lea    0x1(%rdi),%r9
  mov    $0x3,%esi
  mov    $0x4,%r8d
  sar    $0x12,%edx
  mov    $0x2,%ecx
  mov    $0xffffff80,%r10d
  or     $0xfffffff0,%edx
  mov    %dl,(%rdi)
L49:
  mov    %eax,%edx
  add    %rdi,%rcx
  sar    $0xc,%edx
  and    $0x3f,%edx
  or     %r10d,%edx
  mov    %dl,(%r9)
  mov    $0xffffff80,%r9d
L80:
  mov    %eax,%edx
  and    $0x3f,%eax
  add    %rsi,%rdi
  sar    $0x6,%edx
  or     $0xffffff80,%eax
  and    $0x3f,%edx
  or     %r9d,%edx
  mov    %dl,(%rcx)
  mov    %al,(%rdi)
L91:
  mov    %r8d,%eax
  ret
  nop
L55:
  mov    %al,(%rdi)
  mov    $0x1,%r8d
  jmp    L91
  nopw   0x0(%rax,%rax,1)
L95:
  mov    %rdi,%r9
  mov    $0x2,%esi
  mov    $0x1,%ecx
  mov    $0x3,%r8d
  mov    $0xffffffe0,%r10d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %rdi,%rcx
  mov    $0x1,%esi
  mov    $0x2,%r8d
  mov    $0xffffffc0,%r9d
  jmp    L80
L88:
  mov    $0xffffffff,%r8d
  jmp    L79
```

assistant: ```c
int ft_wctomb(char *s, wchar_t wc) {
  int bytes;
  if (!s)
    return (0);
  bytes = 0;
  if (wc > 0x10FFFF || (wc >= 0xD800 && wc <= 0xDFFF))
    return (-1);
  if (wc > 0xFFFF)
    *(s + bytes++) = 0xF0 | ((wc & 0x1C0000) >> 18);
  if (wc > 0x7FF)
    *(s + bytes++) = (wc <= 0xFFFF ? 0xE0 : 0x80) | ((wc & 0x3F000) >> 12);
  if (wc > 0x7F)
    *(s + bytes++) = (wc <= 0x7FF ? 0xC0 : 0x80) | ((wc & 0xFC0) >> 6);
  if (wc >= 0x00)
    *(s + bytes++) = (wc <= 0x7F ? 0x0 | (wc & 0x7F) : 0x80 | (wc & 0x3F));
  return (bytes);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4e,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x7,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x6,-0x30(%rbp)
  jmp    L29
L71:
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  jmp    L49
L41:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L78
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x24(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x28(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  jmp    L61
L78:
  addl   $0x1,-0x3c(%rbp)
L61:
  addl   $0x1,-0x38(%rbp)
L49:
  mov    -0x38(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L41
L29:
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x3c(%rbp)
  jl     L71
  movl   $0x0,-0x34(%rbp)
  jmp    L30
L52:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L30:
  mov    -0x34(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L52
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: %i 

assistant: ```c
int main(void) {
  int arr[6] = {78, 2, 4, 1, 7, 6};
  int temp;
  int temp2;
  int check = 0;
  int arr_len = sizeof(arr) / sizeof(arr[0]);
  while (check < (arr_len - 1)) {
    check = 0;
    for (int i = 0, n = (arr_len - 1); i < n; i++) {
      if (arr[i] > arr[i + 1]) {
        temp = arr[i];
        temp2 = arr[i + 1];
        arr[i] = temp2;
        arr[i + 1] = temp;
      } else {
        check++;
      }
    }
  }
  for (int j = 0; j < arr_len; j++) {
    printf("%i ", arr[j]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x4e,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x7,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  lea    0x14(%rsp),%rdi
  jmp    L44
L69:
  add    $0x1,%esi
L78:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L76
L50:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L69
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L78
L76:
  cmp    $0x4,%esi
  jg     L24
L44:
  mov    %rsp,%rbx
  mov    %rbx,%rax
  mov    $0x0,%esi
  jmp    L50
L24:
  lea    0x18(%rbx),%r12
  lea    D6(%rip),%rbp
L71:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L71
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: %i 

assistant: ```c
int main(void) {
  int arr[6] = {78, 2, 4, 1, 7, 6};
  int temp;
  int temp2;
  int check = 0;
  int arr_len = sizeof(arr) / sizeof(arr[0]);
  while (check < (arr_len - 1)) {
    check = 0;
    for (int i = 0, n = (arr_len - 1); i < n; i++) {
      if (arr[i] > arr[i + 1]) {
        temp = arr[i];
        temp2 = arr[i + 1];
        arr[i] = temp2;
        arr[i + 1] = temp;
      } else {
        check++;
      }
    }
  }
  for (int j = 0; j < arr_len; j++) {
    printf("%i ", arr[j]);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%ecx
  mov    $0x4e,%edx
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x20000004e,%rax
  mov    %rsp,%r8
  lea    0x14(%rsp),%rdi
  mov    %rax,(%rsp)
  movabs $0x100000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000007,%rax
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L76:
  mov    %r8,%rbx
  mov    %r8,%rax
  xor    %esi,%esi
  cmp    %edx,%ecx
  jge    L24
L1:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  mov    %edx,(%rax)
  cmp    %rdi,%rax
  je     L53
L40:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %edx,%ecx
  jl     L1
L24:
  add    $0x4,%rax
  add    $0x1,%esi
  cmp    %rdi,%rax
  jne    L40
L53:
  mov    (%rsp),%edx
  cmp    $0x4,%esi
  jg     L26
  mov    0x4(%rsp),%ecx
  jmp    L76
  nopl   0x0(%rax)
L26:
  lea    0x18(%r8),%rbp
  lea    D3(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L41:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L41
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D3: %i 

assistant: ```c
int main(void) {
  int arr[6] = {78, 2, 4, 1, 7, 6};
  int temp;
  int temp2;
  int check = 0;
  int arr_len = sizeof(arr) / sizeof(arr[0]);
  while (check < (arr_len - 1)) {
    check = 0;
    for (int i = 0, n = (arr_len - 1); i < n; i++) {
      if (arr[i] > arr[i + 1]) {
        temp = arr[i];
        temp2 = arr[i + 1];
        arr[i] = temp2;
        arr[i + 1] = temp;
      } else {
        check++;
      }
    }
  }
  for (int j = 0; j < arr_len; j++) {
    printf("%i ", arr[j]);
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<islandPerimeter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L10
  mov    -0x14(%rbp),%eax
  jmp    L24
L10:
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L34
  mov    -0x14(%rbp),%eax
  jmp    L24
L34:
  movl   $0x0,-0x10(%rbp)
  jmp    L56
L152:
  movl   $0x0,-0xc(%rbp)
  jmp    L154
L128:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L44
  cmpl   $0x0,-0x10(%rbp)
  je     L20
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L31
L20:
  addl   $0x1,-0x14(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  je     L100
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L133
L100:
  addl   $0x1,-0x14(%rbp)
L133:
  cmpl   $0x0,-0xc(%rbp)
  je     L33
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L99
L33:
  addl   $0x1,-0x14(%rbp)
L99:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  je     L65
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L44
L65:
  addl   $0x1,-0x14(%rbp)
L44:
  addl   $0x1,-0xc(%rbp)
L154:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L128
  addl   $0x1,-0x10(%rbp)
L56:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L152
  mov    -0x14(%rbp),%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int islandPerimeter(int **grid, int gridRowSize, int gridColSize) {
  int res = 0;
  int h = gridRowSize;
  if (h == 0)
    return res;
  int w = gridColSize;
  if (w == 0)
    return res;
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < w; j++) {
      if (grid[i][j] == 1) {
        if (i == 0 || grid[i - 1][j] == 0)
          res++;
        if (i == h - 1 || grid[i + 1][j] == 0)
          res++;
        if (j == 0 || grid[i][j - 1] == 0)
          res++;
        if (j == w - 1 || grid[i][j + 1] == 0)
          res++;
      }
    }
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<islandPerimeter>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L123
L39:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L123:
  mov    %rdi,%r9
  test   %esi,%esi
  jle    L36
  mov    %esi,%ebp
  mov    $0x0,%edi
  mov    $0x0,%edx
  mov    %ebx,%r8d
  lea    -0x1(%rsi),%r10d
  lea    -0x1(%rbx),%r12d
  jmp    L186
L34:
  add    $0x1,%edx
L154:
  cmp    %esi,%r12d
  je     L116
  cmpl   $0x0,0x4(%rcx,%rax,4)
  jne    L167
L116:
  add    $0x1,%edx
L167:
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L77
L175:
  lea    0x0(,%rax,4),%rsi
  cmpl   $0x1,(%rcx,%rax,4)
  jne    L167
  test   %edi,%edi
  je     L14
  mov    -0x8(%r9,%rdi,8),%r14
  cmpl   $0x0,(%r14,%rsi,1)
  jne    L102
L14:
  add    $0x1,%edx
L102:
  cmp    %r11d,%r10d
  je     L2
  mov    0x8(%r9,%rdi,8),%r14
  cmpl   $0x0,(%r14,%rsi,1)
  jne    L13
L2:
  add    $0x1,%edx
L13:
  mov    %eax,%esi
  test   %eax,%eax
  je     L34
  cmpl   $0x0,-0x4(%rcx,%rax,4)
  jne    L154
  jmp    L34
L77:
  add    $0x1,%rdi
  cmp    %rbp,%rdi
  je     L26
L186:
  test   %ebx,%ebx
  jle    L77
  mov    (%r9,%rdi,8),%rcx
  mov    $0x0,%eax
  mov    %edi,%r11d
  jmp    L175
L36:
  mov    $0x0,%ebx
  jmp    L39
L26:
  mov    %edx,%ebx
  jmp    L39
```

assistant: ```c
int islandPerimeter(int **grid, int gridRowSize, int gridColSize) {
  int res = 0;
  int h = gridRowSize;
  if (h == 0)
    return res;
  int w = gridColSize;
  if (w == 0)
    return res;
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < w; j++) {
      if (grid[i][j] == 1) {
        if (i == 0 || grid[i - 1][j] == 0)
          res++;
        if (i == h - 1 || grid[i + 1][j] == 0)
          res++;
        if (j == 0 || grid[i][j - 1] == 0)
          res++;
        if (j == w - 1 || grid[i][j + 1] == 0)
          res++;
      }
    }
  }
  return res;
}
```