ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    (%rax),%esi
  cmp    %esi,(%rbx)
  jge    L47
L9:
  movl   $0x0,(%r12)
  mov    (%rbx),%ecx
  test   %ecx,%ecx
  js     L26
  mov    $0x0,%edx
L28:
  add    $0x1,%edx
  mov    %edx,(%r12)
  mov    (%rbx),%ecx
  cmp    %ecx,%edx
  jle    L28
L26:
  add    $0x1,%ecx
  mov    %ecx,(%rbx)
  cmp    (%rax),%ecx
  jl     L9
L47:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  int *n = alloca(sizeof(int));
  while (*i < *n) {
    *j = 0;
    while (*j <= *i) {
      *j = *j + 1;
    }
    *i = *i + 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <alloca@plt>
  mov    (%rbx),%esi
  cmp    %esi,(%rax)
  jle    L23
  nopl   0x0(%rax,%rax,1)
L21:
  movl   $0x0,(%r12)
  mov    (%rbx),%ecx
  test   %ecx,%ecx
  js     L27
  xor    %edx,%edx
L32:
  add    $0x1,%edx
  mov    %edx,(%r12)
  mov    (%rbx),%ecx
  cmp    %ecx,%edx
  jle    L32
L27:
  add    $0x1,%ecx
  mov    %ecx,(%rbx)
  cmp    (%rax),%ecx
  jl     L21
L23:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  lea    -0x10(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  int *n = alloca(sizeof(int));
  while (*i < *n) {
    *j = 0;
    while (*j <= *i) {
      *j = *j + 1;
    }
    *i = *i + 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <alloca@plt>
  mov    (%rbx),%esi
  cmp    %esi,(%rax)
  jle    L21
  nopl   0x0(%rax,%rax,1)
L28:
  movl   $0x0,(%r12)
  mov    (%rbx),%ecx
  test   %ecx,%ecx
  js     L25
  xor    %edx,%edx
L13:
  add    $0x1,%edx
  mov    %edx,(%r12)
  mov    (%rbx),%ecx
  cmp    %ecx,%edx
  jle    L13
L25:
  add    $0x1,%ecx
  mov    %ecx,(%rbx)
  cmp    (%rax),%ecx
  jl     L28
L21:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  lea    -0x10(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  int *n = alloca(sizeof(int));
  while (*i < *n) {
    *j = 0;
    while (*j <= *i) {
      *j = *j + 1;
    }
    *i = *i + 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L5:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: %2lu: %#x


assistant: ```c
void print_words(size_t num_words, uint32_t buffer[num_words]) {
  size_t word_i;
  for (word_i = 0; word_i < num_words; word_i++) {
    printf("%2lu: %#x\n", word_i, buffer[word_i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_words>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
L3:
  mov    (%r12,%rbx,4),%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: %2lu: %#x


assistant: ```c
void print_words(size_t num_words, uint32_t buffer[num_words]) {
  size_t word_i;
  for (word_i = 0; word_i < num_words; word_i++) {
    printf("%2lu: %#x\n", word_i, buffer[word_i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_words>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%r12,%rbx,4),%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string

tool: D8: %2lu: %#x


assistant: ```c
void print_words(size_t num_words, uint32_t buffer[num_words]) {
  size_t word_i;
  for (word_i = 0; word_i < num_words; word_i++) {
    printf("%2lu: %#x\n", word_i, buffer[word_i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_words>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%r12,%rbx,4),%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: %2lu: %#x


assistant: ```c
void print_words(size_t num_words, uint32_t buffer[num_words]) {
  size_t word_i;
  for (word_i = 0; word_i < num_words; word_i++) {
    printf("%2lu: %#x\n", word_i, buffer[word_i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  lea    D16(%rip),%r9
  lea    D2(%rip),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <posix_spawn@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string

tool: D9: /tmp/nowhere

assistant: ```c
int main(void) {
  pid_t pid = 0;
  static char *argv_new[] = {NULL};
  static char *env_new[] = {NULL};
  return posix_spawn(&pid, "/tmp/nowhere", NULL, NULL, argv_new, env_new);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  lea    D24(%rip),%r9
  lea    D0(%rip),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  lea    D16(%rip),%rsi
  call   <posix_spawn@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
data_type: string

tool: D16: /tmp/nowhere

assistant: ```c
int main(void) {
  pid_t pid = 0;
  static char *argv_new[] = {NULL};
  static char *env_new[] = {NULL};
  return posix_spawn(&pid, "/tmp/nowhere", NULL, NULL, argv_new, env_new);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  lea    D6(%rip),%r9
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  lea    D29(%rip),%r8
  movl   $0x0,0x4(%rsp)
  lea    D21(%rip),%rsi
  call   <posix_spawn@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
type: string

tool: D21: /tmp/nowhere

assistant: ```c
int main(void) {
  pid_t pid = 0;
  static char *argv_new[] = {NULL};
  static char *env_new[] = {NULL};
  return posix_spawn(&pid, "/tmp/nowhere", NULL, NULL, argv_new, env_new);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  lea    D4(%rip),%r9
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  lea    D5(%rip),%r8
  movl   $0x0,0x4(%rsp)
  lea    D16(%rip),%rsi
  call   <posix_spawn@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
type_guessed: string

tool: D16: /tmp/nowhere

assistant: ```c
int main(void) {
  pid_t pid = 0;
  static char *argv_new[] = {NULL};
  static char *env_new[] = {NULL};
  return posix_spawn(&pid, "/tmp/nowhere", NULL, NULL, argv_new, env_new);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<battery_n810_attr_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  lea    D12(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sysfs_file_open@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L35
  mov    -0x8(%rbp),%rax
  jmp    L28
L35:
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  lea    D21(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sysfs_file_open@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L53
  mov    -0x8(%rbp),%rax
  jmp    L28
L53:
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  lea    D14(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sysfs_file_open@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  jmp    L28
L7:
  mov    $0x0,%eax
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string

tool: D12: /devices/platform/n810bm/%s

tool: D21: /devices/platform/tahvo/tahvo-n810bm/%s

tool: D14: /devices/platform/retu/retu-n810bm/%s

assistant: ```c
struct fileaccess *battery_n810_attr_open(int flags, const char *name) {
  struct fileaccess *fd;
  fd = sysfs_file_open(flags, "/devices/platform/n810bm/%s", name);
  if (fd)
    return fd;
  fd = sysfs_file_open(flags, "/devices/platform/tahvo/tahvo-n810bm/%s", name);
  if (fd)
    return fd;
  fd = sysfs_file_open(flags, "/devices/platform/retu/retu-n810bm/%s", name);
  if (fd)
    return fd;
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<battery_n810_attr_open>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rsi,%rdx
  lea    D24(%rip),%rsi
  call   <sysfs_file_open@plt>
  test   %rax,%rax
  je     L2
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    %rbp,%rdx
  lea    D2(%rip),%rsi
  mov    %ebx,%edi
  call   <sysfs_file_open@plt>
  test   %rax,%rax
  jne    L24
  mov    %rbp,%rdx
  lea    D10(%rip),%rsi
  mov    %ebx,%edi
  call   <sysfs_file_open@plt>
  jmp    L24
```

tool_calls: name: unpack_data
arguments: data_tag: D24
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D10
type_infered: string

tool: D24: /devices/platform/n810bm/%s

tool: D2: /devices/platform/tahvo/tahvo-n810bm/%s

tool: D10: /devices/platform/retu/retu-n810bm/%s

assistant: ```c
struct fileaccess *battery_n810_attr_open(int flags, const char *name) {
  struct fileaccess *fd;
  fd = sysfs_file_open(flags, "/devices/platform/n810bm/%s", name);
  if (fd)
    return fd;
  fd = sysfs_file_open(flags, "/devices/platform/tahvo/tahvo-n810bm/%s", name);
  if (fd)
    return fd;
  fd = sysfs_file_open(flags, "/devices/platform/retu/retu-n810bm/%s", name);
  if (fd)
    return fd;
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<battery_n810_attr_open>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  lea    D28(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <sysfs_file_open@plt>
  test   %rax,%rax
  je     L7
L6:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  mov    %r12,%rdx
  lea    D8(%rip),%rsi
  mov    %ebp,%edi
  call   <sysfs_file_open@plt>
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  mov    %r12,%rdx
  lea    D27(%rip),%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <sysfs_file_open@plt>
```

tool_calls: name: parse_data
arguments: tag: D28
type_infered: string
name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D27
type_infered: string

tool: D28: /devices/platform/n810bm/%s

tool: D8: /devices/platform/tahvo/tahvo-n810bm/%s

tool: D27: /devices/platform/retu/retu-n810bm/%s

assistant: ```c
struct fileaccess *battery_n810_attr_open(int flags, const char *name) {
  struct fileaccess *fd;
  fd = sysfs_file_open(flags, "/devices/platform/n810bm/%s", name);
  if (fd)
    return fd;
  fd = sysfs_file_open(flags, "/devices/platform/tahvo/tahvo-n810bm/%s", name);
  if (fd)
    return fd;
  fd = sysfs_file_open(flags, "/devices/platform/retu/retu-n810bm/%s", name);
  if (fd)
    return fd;
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<battery_n810_attr_open>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  lea    D20(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <sysfs_file_open@plt>
  test   %rax,%rax
  je     L8
L9:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    %r12,%rdx
  lea    D9(%rip),%rsi
  mov    %ebp,%edi
  call   <sysfs_file_open@plt>
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r12,%rdx
  lea    D29(%rip),%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <sysfs_file_open@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D20
type: string
name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D29
type: string

tool: D20: /devices/platform/n810bm/%s

tool: D9: /devices/platform/tahvo/tahvo-n810bm/%s

tool: D29: /devices/platform/retu/retu-n810bm/%s

assistant: ```c
struct fileaccess *battery_n810_attr_open(int flags, const char *name) {
  struct fileaccess *fd;
  fd = sysfs_file_open(flags, "/devices/platform/n810bm/%s", name);
  if (fd)
    return fd;
  fd = sysfs_file_open(flags, "/devices/platform/tahvo/tahvo-n810bm/%s", name);
  if (fd)
    return fd;
  fd = sysfs_file_open(flags, "/devices/platform/retu/retu-n810bm/%s", name);
  if (fd)
    return fd;
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_total>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <get_swap_info@plt>
  test   %rax,%rax
  je     L21
  mov    $0x0,%eax
  jmp    L3
L21:
  mov    -0x10(%rbp),%rax
  shl    $0xa,%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fmt_human@plt>
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
const char *swap_total(void) {
  long total;
  if (get_swap_info(&total, NULL, NULL)) {
    return NULL;
  }
  return fmt_human(total * 1024, 1024);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap_total>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <get_swap_info@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L15
  mov    (%rsp),%rdi
  shl    $0xa,%rdi
  mov    $0x400,%esi
  call   <fmt_human@plt>
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *swap_total(void) {
  long total;
  if (get_swap_info(&total, NULL, NULL)) {
    return NULL;
  }
  return fmt_human(total * 1024, 1024);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_total>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <get_swap_info@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L19
  mov    (%rsp),%rdi
  mov    $0x400,%esi
  shl    $0xa,%rdi
  call   <fmt_human@plt>
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *swap_total(void) {
  long total;
  if (get_swap_info(&total, NULL, NULL)) {
    return NULL;
  }
  return fmt_human(total * 1024, 1024);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap_total>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <get_swap_info@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L19
  mov    (%rsp),%rdi
  mov    $0x400,%esi
  shl    $0xa,%rdi
  call   <fmt_human@plt>
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *swap_total(void) {
  long total;
  if (get_swap_info(&total, NULL, NULL)) {
    return NULL;
  }
  return fmt_human(total * 1024, 1024);
}
```
user: What is the c source code of the assembly code below?

```asm
<sortData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L32:
  movl   $0x0,-0x4(%rbp)
  jmp    L44
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L49
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
L49:
  addl   $0x1,-0x4(%rbp)
L44:
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L22
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sortData(int *pData, int count) {
  int i, j;
  for (i = 0; i < count - 1; i++) {
    for (j = 0; j < (count - i - 1); j++) {
      if (pData[j] > pData[j + 1]) {
        do {
          pData[j] ^= pData[j + 1];
          pData[j + 1] ^= pData[j];
          pData[j] ^= pData[j + 1];
        } while (0);
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sortData>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L49
  lea    0x4(%rdi),%r9
  jmp    L40
L69:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L17
L77:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L69
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L69
L17:
  sub    $0x1,%r8d
  je     L49
L40:
  test   %r8d,%r8d
  jle    L17
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L77
L49:
  ret
```

assistant: ```c
void sortData(int *pData, int count) {
  int i, j;
  for (i = 0; i < count - 1; i++) {
    for (j = 0; j < (count - i - 1); j++) {
      if (pData[j] > pData[j + 1]) {
        do {
          pData[j] ^= pData[j + 1];
          pData[j + 1] ^= pData[j];
          pData[j] ^= pData[j + 1];
        } while (0);
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sortData>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %edx,%edx
  jle    L37
  lea    0x4(%rdi),%r9
  nop
L6:
  sub    $0x1,%edx
  mov    %rdi,%rax
  mov    %rdx,%r8
  lea    (%r9,%rdx,4),%rsi
  nopl   (%rax)
L26:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L15
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
L15:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L26
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L6
L37:
  ret
```

assistant: ```c
void sortData(int *pData, int count) {
  int i, j;
  for (i = 0; i < count - 1; i++) {
    for (j = 0; j < (count - i - 1); j++) {
      if (pData[j] > pData[j + 1]) {
        do {
          pData[j] ^= pData[j + 1];
          pData[j + 1] ^= pData[j];
          pData[j] ^= pData[j + 1];
        } while (0);
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sortData>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %edx,%edx
  jle    L32
  lea    0x4(%rdi),%r9
  nop
L37:
  sub    $0x1,%edx
  mov    %rdi,%rax
  mov    %rdx,%r8
  lea    (%r9,%rdx,4),%rsi
  nopl   (%rax)
L25:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L24
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
L24:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L25
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L37
L32:
  ret
```

assistant: ```c
void sortData(int *pData, int count) {
  int i, j;
  for (i = 0; i < count - 1; i++) {
    for (j = 0; j < (count - i - 1); j++) {
      if (pData[j] > pData[j + 1]) {
        do {
          pData[j] ^= pData[j + 1];
          pData[j + 1] ^= pData[j];
          pData[j] ^= pData[j + 1];
        } while (0);
      }
    }
  }
}
```