ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_percent_arg>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x25,(%rdx)
  je     L32
L2:
  mov    $0x1,%edx
  cmp    $0x64,%rax
  ja     L23
  mov    (%rsp),%rcx
  cmpb   $0x0,(%rcx)
  jne    L23
  mov    %rax,(%rbx)
  mov    $0x0,%edx
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L32:
  add    $0x1,%rdx
  mov    %rdx,(%rsp)
  jmp    L2
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_percent_arg(const char *arg, unsigned long *value) {
  long t;
  char *suffix;
  t = strtol(arg, &suffix, 10);
  if (*suffix == '%') {
    suffix++;
  }
  if (t < 0 || t > 100 || *suffix != 0) {
    return 1;
  }
  *value = (unsigned long)t;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_percent_arg>:
  endbr64
  push   %rbx
  mov    $0xa,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x25,(%rdx)
  jne    L30
  add    $0x1,%rdx
  mov    %rdx,(%rsp)
L30:
  mov    $0x1,%r8d
  cmp    $0x64,%rax
  ja     L23
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L23
  mov    %rax,(%rbx)
  xor    %r8d,%r8d
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_percent_arg(const char *arg, unsigned long *value) {
  long t;
  char *suffix;
  t = strtol(arg, &suffix, 10);
  if (*suffix == '%') {
    suffix++;
  }
  if (t < 0 || t > 100 || *suffix != 0) {
    return 1;
  }
  *value = (unsigned long)t;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_percent_arg>:
  endbr64
  push   %rbx
  mov    $0xa,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x25,(%rdx)
  jne    L36
  add    $0x1,%rdx
  mov    %rdx,(%rsp)
L36:
  mov    $0x1,%r8d
  cmp    $0x64,%rax
  ja     L16
  cmpb   $0x0,(%rdx)
  jne    L16
  mov    %rax,(%rbx)
  xor    %r8d,%r8d
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_percent_arg(const char *arg, unsigned long *value) {
  long t;
  char *suffix;
  t = strtol(arg, &suffix, 10);
  if (*suffix == '%') {
    suffix++;
  }
  if (t < 0 || t > 100 || *suffix != 0) {
    return 1;
  }
  *value = (unsigned long)t;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<packet_recv_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movb   $0x0,-0xe(%rbp)
  movb   $0x0,-0xd(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,%rdi
  call   <driver_read_byte@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L29
  mov    -0xc(%rbp),%eax
  jmp    L40
L29:
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <driver_read_byte@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L41
  mov    -0xc(%rbp),%eax
  jmp    L40
L41:
  movzbl -0xe(%rbp),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0xd(%rbp),%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0xc(%rbp),%eax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
int packet_recv_short(unsigned short *s) {
  int r = 0;
  unsigned char u = 0;
  unsigned char l = 0;
  r = driver_read_byte(&u);
  if (r <= 0)
    return r;
  r = driver_read_byte(&l);
  if (r <= 0)
    return r;
  *s = (unsigned short)(u << 8) | l;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<packet_recv_short>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%rdi
  call   <driver_read_byte@plt>
  test   %eax,%eax
  jle    L24
  lea    0x7(%rsp),%rdi
  call   <driver_read_byte@plt>
  test   %eax,%eax
  jle    L24
  movzbl 0x6(%rsp),%edx
  shl    $0x8,%edx
  movzbl 0x7(%rsp),%ecx
  or     %ecx,%edx
  mov    %dx,(%rbx)
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int packet_recv_short(unsigned short *s) {
  int r = 0;
  unsigned char u = 0;
  unsigned char l = 0;
  r = driver_read_byte(&u);
  if (r <= 0)
    return r;
  r = driver_read_byte(&l);
  if (r <= 0)
    return r;
  *s = (unsigned short)(u << 8) | l;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<packet_recv_short>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  movb   $0x0,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <driver_read_byte@plt>
  test   %eax,%eax
  jle    L18
  lea    0x7(%rsp),%rdi
  call   <driver_read_byte@plt>
  test   %eax,%eax
  jle    L18
  movzbl 0x6(%rsp),%edx
  movzbl 0x7(%rsp),%ecx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %dx,(%rbx)
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int packet_recv_short(unsigned short *s) {
  int r = 0;
  unsigned char u = 0;
  unsigned char l = 0;
  r = driver_read_byte(&u);
  if (r <= 0)
    return r;
  r = driver_read_byte(&l);
  if (r <= 0)
    return r;
  *s = (unsigned short)(u << 8) | l;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<packet_recv_short>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  movb   $0x0,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <driver_read_byte@plt>
  test   %eax,%eax
  jle    L5
  lea    0x7(%rsp),%rdi
  call   <driver_read_byte@plt>
  test   %eax,%eax
  jle    L5
  movzbl 0x6(%rsp),%edx
  movzbl 0x7(%rsp),%ecx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %dx,(%rbx)
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbx
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int packet_recv_short(unsigned short *s) {
  int r = 0;
  unsigned char u = 0;
  unsigned char l = 0;
  r = driver_read_byte(&u);
  if (r <= 0)
    return r;
  r = driver_read_byte(&l);
  if (r <= 0)
    return r;
  *s = (unsigned short)(u << 8) | l;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<escape_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x6e,-0x30(%rbp)
  movb   $0xa,-0x2f(%rbp)
  movb   $0x74,-0x2e(%rbp)
  movb   $0x9,-0x2d(%rbp)
  movb   $0x62,-0x2c(%rbp)
  movb   $0x8,-0x2b(%rbp)
  movb   $0x72,-0x2a(%rbp)
  movb   $0xd,-0x29(%rbp)
  movb   $0x76,-0x28(%rbp)
  movb   $0xb,-0x27(%rbp)
  movb   $0x66,-0x26(%rbp)
  movb   $0xc,-0x25(%rbp)
  movb   $0x30,-0x24(%rbp)
  movb   $0x0,-0x23(%rbp)
  movb   $0x61,-0x22(%rbp)
  movb   $0x7,-0x21(%rbp)
  movb   $0x65,-0x20(%rbp)
  movb   $0x1b,-0x1f(%rbp)
  movb   $0x5c,-0x1e(%rbp)
  movb   $0x5c,-0x1d(%rbp)
  movb   $0x27,-0x1c(%rbp)
  movb   $0x27,-0x1b(%rbp)
  movb   $0x3f,-0x1a(%rbp)
  movb   $0x3f,-0x19(%rbp)
  movb   $0x22,-0x18(%rbp)
  movb   $0x22,-0x17(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L38
L6:
  mov    -0x34(%rbp),%eax
  movzbl -0x30(%rbp,%rax,2),%eax
  movsbl %al,%eax
  cmp    %eax,-0x44(%rbp)
  jne    L37
  mov    -0x34(%rbp),%eax
  movzbl -0x2f(%rbp,%rax,2),%eax
  movsbl %al,%eax
  jmp    L31
L37:
  addl   $0x1,-0x34(%rbp)
L38:
  cmpl   $0xc,-0x34(%rbp)
  jbe    L6
  mov    $0xffffffff,%eax
L31:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int escape_char(int c) {
  struct {
    char from, to;
  } escapechars[] = {{'n', '\n'}, {'t', '\t'}, {'b', '\b'}, {'r', '\r'}, {'v', '\v'}, {'f', '\f'}, {'0', '\0'}, {'a', '\a'}, {'e', '\33'}, {'\\', '\\'}, {'\'', '\''}, {'?', '?'}, {'"', '"'}};
  unsigned int i;
  for (i = 0; i < (sizeof(escapechars) / sizeof((escapechars)[0])); i++)
    if (escapechars[i].from == c)
      return escapechars[i].to;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<escape_char>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0x6e,(%rsp)
  movb   $0xa,0x1(%rsp)
  movb   $0x74,0x2(%rsp)
  movb   $0x9,0x3(%rsp)
  movb   $0x62,0x4(%rsp)
  movb   $0x8,0x5(%rsp)
  movb   $0x72,0x6(%rsp)
  movb   $0xd,0x7(%rsp)
  movb   $0x76,0x8(%rsp)
  movb   $0xb,0x9(%rsp)
  movb   $0x66,0xa(%rsp)
  movb   $0xc,0xb(%rsp)
  movb   $0x30,0xc(%rsp)
  movb   $0x0,0xd(%rsp)
  movb   $0x61,0xe(%rsp)
  movb   $0x7,0xf(%rsp)
  movb   $0x65,0x10(%rsp)
  movb   $0x1b,0x11(%rsp)
  movb   $0x5c,0x12(%rsp)
  movb   $0x5c,0x13(%rsp)
  movb   $0x27,0x14(%rsp)
  movb   $0x27,0x15(%rsp)
  movb   $0x3f,0x16(%rsp)
  movb   $0x3f,0x17(%rsp)
  movb   $0x22,0x18(%rsp)
  movb   $0x22,0x19(%rsp)
  mov    %rsp,%rsi
L5:
  movsbl (%rsi,%rax,2),%edx
  cmp    %edi,%edx
  je     L32
  add    $0x1,%rax
  cmp    $0xd,%rax
  jne    L5
  mov    $0xffffffff,%eax
L27:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x38,%rsp
  ret
L32:
  mov    %eax,%ecx
  movsbl 0x1(%rsp,%rcx,2),%eax
  jmp    L27
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int escape_char(int c) {
  struct {
    char from, to;
  } escapechars[] = {{'n', '\n'}, {'t', '\t'}, {'b', '\b'}, {'r', '\r'}, {'v', '\v'}, {'f', '\f'}, {'0', '\0'}, {'a', '\a'}, {'e', '\33'}, {'\\', '\\'}, {'\'', '\''}, {'?', '?'}, {'"', '"'}};
  unsigned int i;
  for (i = 0; i < (sizeof(escapechars) / sizeof((escapechars)[0])); i++)
    if (escapechars[i].from == c)
      return escapechars[i].to;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<escape_char>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xd72086209740a6e,%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  movabs $0x76100300c660b76,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x3f3f27275c5c1b65,%rax
  mov    %rax,0x10(%rsp)
  mov    $0x2222,%eax
  mov    %ax,0x18(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  movsbl (%rsi,%rax,2),%edx
  mov    %eax,%ecx
  cmp    %edi,%edx
  je     L6
  add    $0x1,%rax
  cmp    $0xd,%rax
  jne    L16
  mov    $0xffffffff,%eax
L13:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x38,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  movsbl 0x1(%rsp,%rcx,2),%eax
  jmp    L13
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int escape_char(int c) {
  struct {
    char from, to;
  } escapechars[] = {{'n', '\n'}, {'t', '\t'}, {'b', '\b'}, {'r', '\r'}, {'v', '\v'}, {'f', '\f'}, {'0', '\0'}, {'a', '\a'}, {'e', '\33'}, {'\\', '\\'}, {'\'', '\''}, {'?', '?'}, {'"', '"'}};
  unsigned int i;
  for (i = 0; i < (sizeof(escapechars) / sizeof((escapechars)[0])); i++)
    if (escapechars[i].from == c)
      return escapechars[i].to;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<escape_char>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0xa,0x1(%rsp)
  movb   $0x9,0x3(%rsp)
  movb   $0x8,0x5(%rsp)
  movb   $0xd,0x7(%rsp)
  movb   $0xb,0x9(%rsp)
  movb   $0xc,0xb(%rsp)
  movb   $0x0,0xd(%rsp)
  movb   $0x7,0xf(%rsp)
  movb   $0x1b,0x11(%rsp)
  movb   $0x5c,0x13(%rsp)
  movb   $0x27,0x15(%rsp)
  movb   $0x3f,0x17(%rsp)
  movb   $0x22,0x19(%rsp)
  cmp    $0x6e,%edi
  je     L91
  cmp    $0x74,%edi
  je     L54
  cmp    $0x62,%edi
  je     L163
  cmp    $0x72,%edi
  je     L7
  cmp    $0x76,%edi
  je     L171
  cmp    $0x66,%edi
  je     L247
  cmp    $0x30,%edi
  je     L5
  cmp    $0x61,%edi
  je     L9
  cmp    $0x65,%edi
  je     L139
  cmp    $0x5c,%edi
  je     L228
  cmp    $0x27,%edi
  je     L242
  cmp    $0x3f,%edi
  je     L262
  mov    $0xffffffff,%eax
  cmp    $0x22,%edi
  je     L173
L253:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L126
  add    $0x38,%rsp
  ret
L91:
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L113:
  movsbl 0x1(%rsp,%rax,2),%eax
  jmp    L253
L54:
  mov    $0x1,%eax
  jmp    L113
L173:
  mov    $0xc,%eax
  jmp    L113
L163:
  mov    $0x2,%eax
  jmp    L113
L7:
  mov    $0x3,%eax
  jmp    L113
L171:
  mov    $0x4,%eax
  jmp    L113
L247:
  mov    $0x5,%eax
  jmp    L113
L5:
  mov    $0x6,%eax
  jmp    L113
L9:
  mov    $0x7,%eax
  jmp    L113
L139:
  mov    $0x8,%eax
  jmp    L113
L228:
  mov    $0x9,%eax
  jmp    L113
L242:
  mov    $0xa,%eax
  jmp    L113
L262:
  mov    $0xb,%eax
  jmp    L113
L126:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int escape_char(int c) {
  struct {
    char from, to;
  } escapechars[] = {{'n', '\n'}, {'t', '\t'}, {'b', '\b'}, {'r', '\r'}, {'v', '\v'}, {'f', '\f'}, {'0', '\0'}, {'a', '\a'}, {'e', '\33'}, {'\\', '\\'}, {'\'', '\''}, {'?', '?'}, {'"', '"'}};
  unsigned int i;
  for (i = 0; i < (sizeof(escapechars) / sizeof((escapechars)[0])); i++)
    if (escapechars[i].from == c)
      return escapechars[i].to;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getPie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x8(%rbp),%xmm1
  movsd  D28(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm2
  movsd  D20(%rip),%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D28
type_infered: byte[8]
name: unpack_data
arguments: tag: D20
type_infered: byte[8]

tool: D10: insidecircle = %f, outsidecircle = %f, ratio = %f


tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double getPie(double insidecircle, double outsidecircle) {
  double ratio = insidecircle / outsidecircle;
  printf("insidecircle = %f, outsidecircle = %f, ratio = %f\n", insidecircle, outsidecircle, ratio);
  return (4 * ratio) / (1 + ratio);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getPie>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm4
  divsd  %xmm1,%xmm4
  movapd %xmm4,%xmm2
  movq   %xmm4,%rbx
  lea    D10(%rip),%rdi
  call   <printf@plt>
  movq   %rbx,%xmm3
  movq   %rbx,%xmm0
  mulsd  D0(%rip),%xmm0
  addsd  D9(%rip),%xmm3
  divsd  %xmm3,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D0
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D9
data_type: byte[8]

tool: D10: insidecircle = %f, outsidecircle = %f, ratio = %f


tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double getPie(double insidecircle, double outsidecircle) {
  double ratio = insidecircle / outsidecircle;
  printf("insidecircle = %f, outsidecircle = %f, ratio = %f\n", insidecircle, outsidecircle, ratio);
  return (4 * ratio) / (1 + ratio);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getPie>:
  endbr64
  movapd %xmm0,%xmm2
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  divsd  %xmm1,%xmm2
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  D9(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D1(%rip),%xmm2
  add    $0x18,%rsp
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string
name: disassemble_data
arguments: data_label: D9
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D1
type_guessed: byte[8]

tool: D4: insidecircle = %f, outsidecircle = %f, ratio = %f


tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double getPie(double insidecircle, double outsidecircle) {
  double ratio = insidecircle / outsidecircle;
  printf("insidecircle = %f, outsidecircle = %f, ratio = %f\n", insidecircle, outsidecircle, ratio);
  return (4 * ratio) / (1 + ratio);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getPie>:
  endbr64
  movapd %xmm0,%xmm2
  sub    $0x18,%rsp
  lea    D24(%rip),%rdi
  divsd  %xmm1,%xmm2
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  D4(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D2(%rip),%xmm2
  add    $0x18,%rsp
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D24
data_type: string
name: unpack_data
arguments: data_tag: D4
data_type: byte[8]
name: unpack_data
arguments: data_tag: D2
data_type: byte[8]

tool: D24: insidecircle = %f, outsidecircle = %f, ratio = %f


tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double getPie(double insidecircle, double outsidecircle) {
  double ratio = insidecircle / outsidecircle;
  printf("insidecircle = %f, outsidecircle = %f, ratio = %f\n", insidecircle, outsidecircle, ratio);
  return (4 * ratio) / (1 + ratio);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Find_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <safestrlen@plt>
  mov    %eax,-0x4(%rbp)
  nop
L20:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L27
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L20
L27:
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rax,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *Find_start(char *str, const char *key) {
  int n = safestrlen(key);
  while ((str = strstr(str, key)) && str[n] != '=')
    ;
  if (str)
    str += (n + 1);
  return (str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Find_start>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <safestrlen@plt>
  movslq %eax,%r12
L2:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  cmpb   $0x3d,(%rax,%r12,1)
  jne    L2
  lea    0x1(%rax,%r12,1),%rbx
L0:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *Find_start(char *str, const char *key) {
  int n = safestrlen(key);
  while ((str = strstr(str, key)) && str[n] != '=')
    ;
  if (str)
    str += (n + 1);
  return (str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Find_start>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <safestrlen@plt>
  movslq %eax,%r12
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L13:
  cmpb   $0x3d,(%rax,%r12,1)
  je     L10
L18:
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L13
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  lea    0x1(%rax,%r12,1),%rbp
  pop    %rbx
  mov    %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *Find_start(char *str, const char *key) {
  int n = safestrlen(key);
  while ((str = strstr(str, key)) && str[n] != '=')
    ;
  if (str)
    str += (n + 1);
  return (str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Find_start>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <safestrlen@plt>
  movslq %eax,%r12
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L28:
  cmpb   $0x3d,(%rax,%r12,1)
  je     L22
L10:
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L28
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  lea    0x1(%rax,%r12,1),%rbp
  pop    %rbx
  mov    %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *Find_start(char *str, const char *key) {
  int n = safestrlen(key);
  while ((str = strstr(str, key)) && str[n] != '=')
    ;
  if (str)
    str += (n + 1);
  return (str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D63
datatype: string
name: unpack_data
arguments: data_tag: D22
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D35
datatype: string

tool: D27: Insira o primeiro valor: 

tool: D63: %d

tool: D22: Insira o segundo valor: 

tool: D8: Insira o terceiro valor: 

tool: D35: Soma: %d


assistant: ```c
int main() {
  int valor1, valor2, valor3;
  printf("Insira o primeiro valor: ");
  scanf("%d", &valor1);
  printf("Insira o segundo valor: ");
  scanf("%d", &valor2);
  printf("Insira o terceiro valor: ");
  scanf("%d", &valor3);
  int soma = valor1 + valor2 + valor3;
  printf("Soma: %d\n", soma);
  return 0;
}
```