ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dump_raw_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L119
L129:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x10,-0x1c(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L32
L88:
  movl   $0x0,-0x20(%rbp)
  jmp    L45
L11:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  ja     L106
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L44
L106:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L44:
  addl   $0x1,-0x20(%rbp)
L45:
  cmpl   $0x3,-0x20(%rbp)
  jle    L11
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x24(%rbp)
L32:
  cmpl   $0x3,-0x24(%rbp)
  jle    L88
  mov    $0x7c,%edi
  call   <putchar@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L105
L77:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  ja     L87
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jle    L121
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7f,%al
  je     L121
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L50
L121:
  mov    $0x2e,%edi
  call   <putchar@plt>
L50:
  addq   $0x1,-0x10(%rbp)
  jmp    L141
L87:
  mov    $0x20,%edi
  call   <putchar@plt>
L141:
  addl   $0x1,-0x24(%rbp)
L105:
  cmpl   $0xf,-0x24(%rbp)
  jle    L77
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L119:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L129
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D31
datatype: string
name: unpack_data
arguments: tag: D36
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D20
datatype: string

tool: D31: 0x%08x  

tool: D36: %02x

tool: D2:   

tool: D20: |

assistant: ```c
void dump_raw_data(char *data, int data_len) {
  int i, j;
  int offset = 0;
  char *h, *a;
  char *end = data + data_len;
  h = a = data;
  while (h < end) {
    printf("0x%08x  ", offset);
    offset += 16;
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4; j++) {
        if (h <= end)
          printf("%02x", *h++);
        else
          printf("  ");
      }
      printf(" ");
    }
    printf("|");
    for (i = 0; i < 16; i++) {
      if (a <= end) {
        if ((*a >= ' ') && (*a <= '~'))
          printf("%c", *a);
        else
          printf(".");
        a++;
      } else
        printf(" ");
    }
    printf("|\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<dump_raw_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movslq %esi,%r13
  add    %rdi,%r13
  cmp    %r13,%rdi
  jae    L31
  mov    %rdi,%r12
  mov    %rdi,%rbp
  movl   $0x0,0xc(%rsp)
  jmp    L61
L19:
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  sub    $0x1,%ebx
  je     L101
L117:
  cmp    %r12,%r13
  jb     L19
  lea    0x1(%r12),%r14
  movsbl (%r12),%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%r12
  jmp    L25
L101:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%r15d
  je     L107
L26:
  mov    $0x4,%ebx
  jmp    L117
L107:
  mov    $0x7c,%edi
  call   <putchar@plt>
  mov    $0x10,%ebx
  jmp    L121
L47:
  mov    $0x2e,%edi
  call   <putchar@plt>
L29:
  add    $0x1,%rbp
L145:
  sub    $0x1,%ebx
  je     L23
L121:
  cmp    %rbp,%r13
  jb     L149
  movzbl 0x0(%rbp),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%al
  ja     L47
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L29
L149:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L145
L23:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  cmp    %r13,%r12
  jae    L31
L61:
  mov    0xc(%rsp),%ebx
  mov    %ebx,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x10,%eax
  mov    %eax,0xc(%rsp)
  mov    $0x4,%r15d
  jmp    L26
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D32
datatype: string
name: extract_symbolic_data
arguments: data_label: D4
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D11
datatype: string

tool: D32:   

tool: D4: %02x

tool: D1: |

tool: D11: 0x%08x  

assistant: ```c
void dump_raw_data(char *data, int data_len) {
  int i, j;
  int offset = 0;
  char *h, *a;
  char *end = data + data_len;
  h = a = data;
  while (h < end) {
    printf("0x%08x  ", offset);
    offset += 16;
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4; j++) {
        if (h <= end)
          printf("%02x", *h++);
        else
          printf("  ");
      }
      printf(" ");
    }
    printf("|");
    for (i = 0; i < 16; i++) {
      if (a <= end) {
        if ((*a >= ' ') && (*a <= '~'))
          printf("%c", *a);
        else
          printf(".");
        a++;
      } else
        printf(" ");
    }
    printf("|\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dump_raw_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  add    %rdi,%r13
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r13,%rdi
  jae    L101
  movl   $0x0,0xc(%rsp)
  mov    %rdi,%r12
  mov    %rdi,%rbp
  lea    D23(%rip),%r15
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0xc(%rsp),%ebx
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %ebx,%eax
  movl   $0x4,0x8(%rsp)
  add    $0x10,%eax
  mov    %eax,0xc(%rsp)
L22:
  mov    $0x4,%ebx
L108:
  cmp    %r12,%r13
  jb     L12
  movsbl (%r12),%esi
  lea    0x1(%r12),%r14
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  mov    %r14,%r12
  call   <printf@plt>
L27:
  sub    $0x1,%ebx
  jne    L108
  mov    $0x20,%edi
  call   <putchar@plt>
  subl   $0x1,0x8(%rsp)
  jne    L22
  mov    $0x7c,%edi
  mov    $0x10,%ebx
  call   <putchar@plt>
  jmp    L48
  nopl   (%rax)
L19:
  movsbl 0x0(%rbp),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%al
  jbe    L99
  mov    $0x2e,%edi
L99:
  call   <putchar@plt>
  add    $0x1,%rbp
  sub    $0x1,%ebx
  je     L55
L48:
  cmp    %rbp,%r13
  jae    L19
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L48
L55:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  cmp    %r13,%r12
  jb     L5
L101:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L12:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L27
```

tool_calls: name: retrieve_data
arguments: tag: D23
type_guessed: string
name: retrieve_data
arguments: tag: D18
type_guessed: string
name: retrieve_data
arguments: tag: D31
type_guessed: string
name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D23:   

tool: D18: 0x%08x  

tool: D31: %02x

tool: D10: |

assistant: ```c
void dump_raw_data(char *data, int data_len) {
  int i, j;
  int offset = 0;
  char *h, *a;
  char *end = data + data_len;
  h = a = data;
  while (h < end) {
    printf("0x%08x  ", offset);
    offset += 16;
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4; j++) {
        if (h <= end)
          printf("%02x", *h++);
        else
          printf("  ");
      }
      printf(" ");
    }
    printf("|");
    for (i = 0; i < 16; i++) {
      if (a <= end) {
        if ((*a >= ' ') && (*a <= '~'))
          printf("%c", *a);
        else
          printf(".");
        a++;
      } else
        printf(" ");
    }
    printf("|\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dump_raw_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  add    %rdi,%r12
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r12,%rdi
  jae    L61
  movl   $0x0,0xc(%rsp)
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  lea    D35(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L119:
  mov    0xc(%rsp),%r15d
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  mov    %r15d,%esi
  call   <printf@plt>
  mov    %r15d,%eax
  movl   $0x4,0x8(%rsp)
  add    $0x10,%eax
  mov    %eax,0xc(%rsp)
L72:
  xor    %r15d,%r15d
L58:
  cmp    %rbp,%r12
  jb     L104
  movsbl 0x0(%rbp),%esi
  lea    0x1(%rbp),%r14
  xor    %eax,%eax
  add    $0x1,%r15d
  lea    D5(%rip),%rdi
  mov    %r14,%rbp
  call   <printf@plt>
  cmp    $0x4,%r15d
  jne    L58
L67:
  mov    $0x20,%edi
  call   <putchar@plt>
  subl   $0x1,0x8(%rsp)
  jne    L72
  mov    $0x7c,%edi
  xor    %r14d,%r14d
  call   <putchar@plt>
  nopl   (%rax)
L34:
  cmp    %rbx,%r12
  jb     L110
  movsbl (%rbx),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%al
  jbe    L36
  mov    $0x2e,%edi
L36:
  call   <putchar@plt>
  add    $0x1,%r14d
  add    $0x1,%rbx
  cmp    $0x10,%r14d
  jne    L34
L7:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  cmp    %rbp,%r12
  ja     L119
L61:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L104:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    $0x4,%r15d
  jne    L104
  jmp    L67
  nopl   0x0(%rax)
L110:
  mov    $0x20,%edi
  add    $0x1,%r14d
  call   <putchar@plt>
  cmp    $0x10,%r14d
  jne    L110
  jmp    L7
```

tool_calls: name: parse_data
arguments: label: D35
type_guessed: string
name: parse_data
arguments: label: D23
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string

tool: D35:   

tool: D23: 0x%08x  

tool: D5: %02x

tool: D0: |

assistant: ```c
void dump_raw_data(char *data, int data_len) {
  int i, j;
  int offset = 0;
  char *h, *a;
  char *end = data + data_len;
  h = a = data;
  while (h < end) {
    printf("0x%08x  ", offset);
    offset += 16;
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4; j++) {
        if (h <= end)
          printf("%02x", *h++);
        else
          printf("  ");
      }
      printf(" ");
    }
    printf("|");
    for (i = 0; i < 16; i++) {
      if (a <= end) {
        if ((*a >= ' ') && (*a <= '~'))
          printf("%c", *a);
        else
          printf(".");
        a++;
      } else
        printf(" ");
    }
    printf("|\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<char2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L21
L3:
  lea    -0xa(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0xa(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x1c(%rbp)
L21:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L3
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %2x

assistant: ```c
unsigned char *char2hex(char *chr, int nLen) {
  int i;
  unsigned char hex[2];
  unsigned char *retHex;
  unsigned int hex3;
  retHex = (unsigned char *)malloc(nLen);
  memset(retHex, 0, nLen);
  for (i = 0; i < nLen; i++) {
    memset(hex, 0, sizeof(hex));
    memcpy(hex, chr + i, 2);
    sscanf((char *)hex, "%2x", &hex3);
    retHex[i / 2] = hex3;
    i++;
  }
  return retHex;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<char2hex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %r12d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L29
  sub    $0x1,%r12d
  and    $0xfffffffe,%r12d
  add    $0x2,%r12d
  mov    $0x0,%ebx
  lea    D3(%rip),%r14
L25:
  lea    0x6(%rsp),%r15
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  mov    $0x2,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %rsp,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <sscanf@plt>
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  cltq
  mov    (%rsp),%edx
  mov    %dl,0x0(%r13,%rax,1)
  add    $0x2,%ebx
  add    $0x2,%rbp
  cmp    %r12d,%ebx
  jne    L25
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: %2x

assistant: ```c
unsigned char *char2hex(char *chr, int nLen) {
  int i;
  unsigned char hex[2];
  unsigned char *retHex;
  unsigned int hex3;
  retHex = (unsigned char *)malloc(nLen);
  memset(retHex, 0, nLen);
  for (i = 0; i < nLen; i++) {
    memset(hex, 0, sizeof(hex));
    memcpy(hex, chr + i, 2);
    sscanf((char *)hex, "%2x", &hex3);
    retHex[i / 2] = hex3;
    i++;
  }
  return retHex;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<char2hex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r12d,%edx
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L5
  sub    $0x1,%r12d
  lea    0x16(%rsp),%rbp
  lea    0x10(%rsp),%r15
  and    $0xfffffffe,%r12d
  lea    D0(%rip),%r14
  lea    0x2(%r12),%eax
  xor    %r12d,%r12d
  mov    %eax,0xc(%rsp)
  nopl   0x0(%rax)
L2:
  mov    $0x2,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    %r12d,%eax
  mov    0x10(%rsp),%edx
  add    $0x2,%r12d
  sar    %eax
  add    $0x2,%rbx
  cltq
  mov    %dl,0x0(%r13,%rax,1)
  cmp    0xc(%rsp),%r12d
  jne    L2
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %2x

assistant: ```c
unsigned char *char2hex(char *chr, int nLen) {
  int i;
  unsigned char hex[2];
  unsigned char *retHex;
  unsigned int hex3;
  retHex = (unsigned char *)malloc(nLen);
  memset(retHex, 0, nLen);
  for (i = 0; i < nLen; i++) {
    memset(hex, 0, sizeof(hex));
    memcpy(hex, chr + i, 2);
    sscanf((char *)hex, "%2x", &hex3);
    retHex[i / 2] = hex3;
    i++;
  }
  return retHex;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<char2hex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r12d,%edx
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L18
  sub    $0x1,%r12d
  lea    0x16(%rsp),%rbp
  lea    0x10(%rsp),%r15
  and    $0xfffffffe,%r12d
  lea    D3(%rip),%r14
  lea    0x2(%r12),%eax
  xor    %r12d,%r12d
  mov    %eax,0xc(%rsp)
  nopl   0x0(%rax)
L14:
  mov    $0x2,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    %r12d,%eax
  mov    0x10(%rsp),%edx
  add    $0x2,%r12d
  sar    %eax
  add    $0x2,%rbx
  cltq
  mov    %dl,0x0(%r13,%rax,1)
  cmp    %r12d,0xc(%rsp)
  jne    L14
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: %2x

assistant: ```c
unsigned char *char2hex(char *chr, int nLen) {
  int i;
  unsigned char hex[2];
  unsigned char *retHex;
  unsigned int hex3;
  retHex = (unsigned char *)malloc(nLen);
  memset(retHex, 0, nLen);
  for (i = 0; i < nLen; i++) {
    memset(hex, 0, sizeof(hex));
    memcpy(hex, chr + i, 2);
    sscanf((char *)hex, "%2x", &hex3);
    retHex[i / 2] = hex3;
    i++;
  }
  return retHex;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lcdputchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  movsbl -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <lcdsend@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int lcdputchar(int fd, char value) {
  lcdsend(fd, 1, value);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lcdputchar>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%edx
  mov    $0x1,%esi
  call   <lcdsend@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int lcdputchar(int fd, char value) {
  lcdsend(fd, 1, value);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lcdputchar>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%edx
  mov    $0x1,%esi
  call   <lcdsend@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int lcdputchar(int fd, char value) {
  lcdsend(fd, 1, value);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lcdputchar>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%edx
  mov    $0x1,%esi
  call   <lcdsend@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int lcdputchar(int fd, char value) {
  lcdsend(fd, 1, value);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HandleNewSimpleTok>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x408,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,0x8(%rsp)
  mov    %r8,(%rsp)
  mov    0x448(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%r9d
  je     L13
  cmpl   $0x0,0x440(%rsp)
  jle    L0
  movsbl %dil,%edx
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L38:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x408,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  mov    %ecx,%r12d
  lea    0x10(%rsp),%r14
  mov    %r14,%rsi
  mov    %ecx,%edi
  call   <indents@plt>
  mov    %eax,%esi
  mov    (%rsp),%rdx
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1(%r12),%r15d
  mov    %r14,%rsi
  mov    %r15d,%edi
  mov    $0x0,%eax
  call   <indents@plt>
  mov    %eax,%esi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r15d,%edi
  mov    $0x0,%eax
  call   <indents@plt>
  mov    %eax,%edx
  lea    D31(%rip),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <indents@plt>
  mov    %eax,%edx
  mov    (%rsp),%rcx
  lea    D58(%rip),%rsi
  mov    0x8(%rsp),%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  movsbl %bl,%edx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L38
L0:
  movsbl %dil,%edx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L38
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D37
type: string
name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D49
type: string
name: retrieve_data
arguments: data_tag: D31
type: string
name: retrieve_data
arguments: data_tag: D58
type: string
name: retrieve_data
arguments: data_tag: D7
type: string

tool: D37:  %c

tool: D0: %s<%s>


tool: D49: %s<box_subtext>

tool: D31: </box_subtext>

tool: D58: 
%s</%s>


tool: D7: %c

assistant: ```c
void HandleNewSimpleTok(char c, char *Spew, char *CloseTags, int CIL, const char *xmltag, int CommLevel, int p, char *InnerClose) {
  char Temp[1000];
  if (CommLevel == 4) {
    printf("%s<%s>\n", indents(CIL, Temp), xmltag);
    printf("%s<box_subtext>", indents(CIL + 1, Temp));
    sprintf(InnerClose, "</box_subtext>", indents(CIL + 1, Temp));
    sprintf(CloseTags, "\n%s</%s>\n", indents(CIL, Temp), xmltag);
    sprintf(Spew, "%c", c);
  } else if (p > 0) {
    sprintf(Spew, " %c", c);
  } else {
    sprintf(Spew, "%c", c);
  }
}
```