ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fetch_skip_message_action_encrypted>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fetch_int@plt>
  cmp    $0xa1733aec,%eax
  je     L15
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <logprintf@plt>
  mov    $0x0,%edi
  call   <assert@plt>
L9:
  add    $0x8,%rsp
  ret
L15:
  mov    $0x1,%edi
  call   <fetch_skip@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: x = 0x%08x


assistant: ```c
void fetch_skip_message_action_encrypted(void) {
  unsigned x = fetch_int();
  switch (x) {
  case 0xa1733aec:
    fetch_skip(1);
    break;
  default:
    logprintf("x = 0x%08x\n", x);
    assert(0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fetch_skip_message_action_encrypted>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fetch_int@plt>
  cmp    $0xa1733aec,%eax
  je     L1
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <logprintf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1080 <assert@plt>
  nop
L1:
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <fetch_skip@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: x = 0x%08x


assistant: ```c
void fetch_skip_message_action_encrypted(void) {
  unsigned x = fetch_int();
  switch (x) {
  case 0xa1733aec:
    fetch_skip(1);
    break;
  default:
    logprintf("x = 0x%08x\n", x);
    assert(0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fetch_skip_message_action_encrypted>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fetch_int@plt>
  cmp    $0xa1733aec,%eax
  je     L4
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <logprintf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1080 <assert@plt>
  nop
L4:
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <fetch_skip@plt>
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: x = 0x%08x


assistant: ```c
void fetch_skip_message_action_encrypted(void) {
  unsigned x = fetch_int();
  switch (x) {
  case 0xa1733aec:
    fetch_skip(1);
    break;
  default:
    logprintf("x = 0x%08x\n", x);
    assert(0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copyline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L8
  mov    $0x1,%eax
  jmp    L29
L8:
  cmpl   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  mov    $0x1,%eax
  jmp    L29
L15:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L29
L22:
  cmpl   $0xd,-0x4(%rbp)
  jne    L20
  movl   $0x1,-0x8(%rbp)
  jmp    L26
L20:
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  jmp    L26
L29:
  leave
  ret
```

assistant: ```c
int copyline(FILE *in, FILE *out) {
  int state, flag, c;
  state = 0;
  for (;;) {
    c = getc(in);
    if (c == '\n')
      return 1;
    if (state) {
      ungetc(c, in);
      return 1;
    }
    if (c == EOF)
      return 0;
    if (c == '\r')
      state = 1;
    else
      putc(c, out);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copyline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    $0x1,%r12d
L2:
  mov    $0x0,%ebx
L57:
  mov    %rbp,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L0
  test   %ebx,%ebx
  jne    L25
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L18
  mov    %r12d,%ebx
  cmp    $0xd,%eax
  je     L57
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  jmp    L2
L25:
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  jmp    L18
L0:
  mov    $0x1,%ebx
L18:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int copyline(FILE *in, FILE *out) {
  int state, flag, c;
  state = 0;
  for (;;) {
    c = getc(in);
    if (c == '\n')
      return 1;
    if (state) {
      ungetc(c, in);
      return 1;
    }
    if (c == EOF)
      return 0;
    if (c == '\r')
      state = 1;
    else
      putc(c, out);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<copyline>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L4
L64:
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L22
  cmp    $0xd,%eax
  je     L16
  mov    %eax,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  mov    %rbp,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  jne    L64
L4:
  mov    $0x1,%eax
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L4
  mov    %rbp,%rsi
  call   <ungetc@plt>
  mov    $0x1,%eax
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  jmp    L62
```

assistant: ```c
int copyline(FILE *in, FILE *out) {
  int state, flag, c;
  state = 0;
  for (;;) {
    c = getc(in);
    if (c == '\n')
      return 1;
    if (state) {
      ungetc(c, in);
      return 1;
    }
    if (c == EOF)
      return 0;
    if (c == '\r')
      state = 1;
    else
      putc(c, out);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copyline>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L28
L4:
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L51
  cmp    $0xd,%eax
  je     L53
  mov    %eax,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  mov    %rbp,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  jne    L4
L28:
  mov    $0x1,%eax
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L53:
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L28
  mov    %rbp,%rsi
  call   <ungetc@plt>
  mov    $0x1,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  xor    %eax,%eax
  jmp    L2
```

assistant: ```c
int copyline(FILE *in, FILE *out) {
  int state, flag, c;
  state = 0;
  for (;;) {
    c = getc(in);
    if (c == '\n')
      return 1;
    if (state) {
      ungetc(c, in);
      return 1;
    }
    if (c == EOF)
      return 0;
    if (c == '\r')
      state = 1;
    else
      putc(c, out);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L38
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L38:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L20
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L20:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L36
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_data(int rrt[], int size, int *min, int *max, int *avg) {
  int sum = 0;
  int i;
  *min = rrt[0], *max = rrt[0];
  for (i = 0; i < size; i++) {
    sum += rrt[i];
    if (rrt[i] < *min)
      *min = rrt[i];
    if (rrt[i] > *max)
      *max = rrt[i];
  }
  *avg = sum / size;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_data>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%r11d
  mov    %rdx,%rdi
  mov    %rcx,%r9
  mov    (%r10),%eax
  mov    %eax,(%rdx)
  mov    %eax,(%rcx)
  test   %esi,%esi
  jle    L26
  mov    %r10,%rdx
  lea    -0x1(%rsi),%eax
  lea    (%r10,%rax,4),%r10
  mov    $0x0,%eax
  jmp    L14
L53:
  lea    0x4(%rdx),%rcx
  cmp    %r10,%rdx
  je     L54
  mov    %rcx,%rdx
L14:
  mov    %rdx,%rsi
  mov    (%rdx),%ecx
  add    %ecx,%eax
  cmp    (%rdi),%ecx
  jge    L52
  mov    %ecx,(%rdi)
L52:
  mov    (%rsi),%ecx
  cmp    (%r9),%ecx
  jle    L53
  mov    %ecx,(%r9)
  jmp    L53
L26:
  mov    $0x0,%eax
L54:
  cltd
  idiv   %r11d
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void get_data(int rrt[], int size, int *min, int *max, int *avg) {
  int sum = 0;
  int i;
  *min = rrt[0], *max = rrt[0];
  for (i = 0; i < size; i++) {
    sum += rrt[i];
    if (rrt[i] < *min)
      *min = rrt[i];
    if (rrt[i] > *max)
      *max = rrt[i];
  }
  *avg = sum / size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_data>:
  endbr64
  mov    (%rdi),%eax
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    %eax,(%rdx)
  mov    %eax,(%rcx)
  test   %r10d,%r10d
  jle    L32
  lea    -0x1(%r10),%eax
  lea    (%rdi,%rax,4),%r9
  xor    %eax,%eax
  jmp    L49
  nopl   0x0(%rax)
L5:
  mov    %rdx,%rdi
L49:
  mov    (%rdi),%edx
  add    %edx,%eax
  cmp    (%rsi),%edx
  jge    L23
  mov    %edx,(%rsi)
L23:
  cmp    (%rcx),%edx
  jle    L28
  mov    %edx,(%rcx)
L28:
  lea    0x4(%rdi),%rdx
  cmp    %r9,%rdi
  jne    L5
  cltd
  idiv   %r10d
  mov    %eax,(%r8)
  ret
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void get_data(int rrt[], int size, int *min, int *max, int *avg) {
  int sum = 0;
  int i;
  *min = rrt[0], *max = rrt[0];
  for (i = 0; i < size; i++) {
    sum += rrt[i];
    if (rrt[i] < *min)
      *min = rrt[i];
    if (rrt[i] > *max)
      *max = rrt[i];
  }
  *avg = sum / size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_data>:
  endbr64
  mov    (%rdi),%eax
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    %eax,(%rdx)
  mov    %eax,(%rcx)
  test   %r10d,%r10d
  jle    L18
  lea    -0x1(%r10),%eax
  lea    (%rdi,%rax,4),%r9
  xor    %eax,%eax
  jmp    L17
  nopl   0x0(%rax)
L0:
  mov    %rdx,%rdi
L17:
  mov    (%rdi),%edx
  add    %edx,%eax
  cmp    (%rsi),%edx
  jge    L1
  mov    %edx,(%rsi)
L1:
  cmp    (%rcx),%edx
  jle    L28
  mov    %edx,(%rcx)
L28:
  lea    0x4(%rdi),%rdx
  cmp    %r9,%rdi
  jne    L0
  cltd
  idiv   %r10d
  mov    %eax,(%r8)
  ret
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void get_data(int rrt[], int size, int *min, int *max, int *avg) {
  int sum = 0;
  int i;
  *min = rrt[0], *max = rrt[0];
  for (i = 0; i < size; i++) {
    sum += rrt[i];
    if (rrt[i] < *min)
      *min = rrt[i];
    if (rrt[i] > *max)
      *max = rrt[i];
  }
  *avg = sum / size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_job_will_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x98(%rbp)
  mov    -0x98(%rbp),%rax
  mov    %eax,%ecx
  mov    -0xa8(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  lea    D0(%rip),%r9
  mov    %rdx,%r8
  lea    D19(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <_xmit@plt>
  test   %rax,%rax
  je     L11
  mov    $0x1,%edi
  call   <exit@plt>
L11:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string
name: read_data
arguments: label: D19
type: string

tool: 

tool: D19: TS=%u AUTH=root DT=CMD=JOBWILLRUN ARG=JOBID=%ld,%s

assistant: ```c
void _job_will_run(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[128];
  snprintf(out_msg, sizeof(out_msg), "TS=%u AUTH=root DT=CMD=JOBWILLRUN ARG=JOBID=%ld,%s", (uint32_t)now, my_job_id, "");
  if (_xmit(out_msg))
    exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_job_will_run>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rsp,%rbp
  lea    D16(%rip),%r9
  mov    %rbx,%r8
  mov    %eax,%ecx
  lea    D2(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  test   %rax,%rax
  jne    L25
L9:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D2
type: string

tool: 

tool: D2: TS=%u AUTH=root DT=CMD=JOBWILLRUN ARG=JOBID=%ld,%s

assistant: ```c
void _job_will_run(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[128];
  snprintf(out_msg, sizeof(out_msg), "TS=%u AUTH=root DT=CMD=JOBWILLRUN ARG=JOBID=%ld,%s", (uint32_t)now, my_job_id, "");
  if (_xmit(out_msg))
    exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_job_will_run>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r8
  mov    $0x80,%esi
  lea    D11(%rip),%r9
  mov    %eax,%ecx
  lea    D16(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  test   %rax,%rax
  jne    L17
L18:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_guessed: string
name: parse_data
arguments: tag: D16
type_guessed: string

tool: 

tool: D16: TS=%u AUTH=root DT=CMD=JOBWILLRUN ARG=JOBID=%ld,%s

assistant: ```c
void _job_will_run(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[128];
  snprintf(out_msg, sizeof(out_msg), "TS=%u AUTH=root DT=CMD=JOBWILLRUN ARG=JOBID=%ld,%s", (uint32_t)now, my_job_id, "");
  if (_xmit(out_msg))
    exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_job_will_run>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r8
  mov    $0x80,%esi
  lea    D15(%rip),%r9
  mov    %eax,%ecx
  lea    D1(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  test   %rax,%rax
  jne    L15
L9:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D1
type: string

tool: 

tool: D1: TS=%u AUTH=root DT=CMD=JOBWILLRUN ARG=JOBID=%ld,%s

assistant: ```c
void _job_will_run(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[128];
  snprintf(out_msg, sizeof(out_msg), "TS=%u AUTH=root DT=CMD=JOBWILLRUN ARG=JOBID=%ld,%s", (uint32_t)now, my_job_id, "");
  if (_xmit(out_msg))
    exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Heap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%rbx
  mov    %r8,%rbp
  jmp    L40
L49:
  mov    %rbp,%rdi
  call   <RightChild@plt>
  cmp    %rax,%r13
  jle    L9
  mov    (%r12,%rbx,8),%rdx
  mov    (%r12,%rax,8),%rcx
  movsd  (%r14,%rcx,8),%xmm0
  ucomisd (%r14,%rdx,8),%xmm0
  cmova  %rax,%rbx
L9:
  cmp    %rbp,%rbx
  je     L3
  lea    (%r12,%rbp,8),%rdx
  mov    (%rdx),%rcx
  lea    (%r12,%rbx,8),%rax
  mov    (%rax),%rsi
  mov    %rsi,(%rdx)
  mov    %rcx,(%rax)
  mov    %rbx,%rbp
L40:
  mov    %rbp,%rdi
  call   <LeftChild@plt>
  cmp    %r13,%rax
  jge    L49
  mov    (%r12,%rbx,8),%rdx
  mov    (%r12,%rax,8),%rcx
  movsd  (%r14,%rcx,8),%xmm0
  ucomisd (%r14,%rdx,8),%xmm0
  cmova  %rax,%rbx
  jmp    L49
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Heap(double *Vector, long *TieBreaker, long *Rank, long ListSize, long start) {
  long notdone;
  long left, right, largest, current;
  long tmprank;
  current = start;
  notdone = 1;
  largest = current;
  while (notdone) {
    left = LeftChild(current);
    if (left < ListSize) {
      if (Vector[Rank[largest]] < Vector[Rank[left]])
        largest = left;
    }
    right = RightChild(current);
    if (right < ListSize) {
      if (Vector[Rank[largest]] < Vector[Rank[right]])
        largest = right;
    }
    if (largest == current)
      notdone = 0;
    else {
      tmprank = Rank[current];
      Rank[current] = Rank[largest];
      Rank[largest] = tmprank;
      current = largest;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Heap>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rbp,%rdi
  call   <LeftChild@plt>
  mov    %rax,%rbx
  cmp    %r12,%rax
  jge    L12
  nopl   0x0(%rax,%rax,1)
L16:
  mov    (%r14,%rbx,8),%rdx
  mov    (%r14,%rbp,8),%rax
  movsd  0x0(%r13,%rdx,8),%xmm0
  comisd 0x0(%r13,%rax,8),%xmm0
  cmovbe %rbp,%rbx
L38:
  mov    %rbp,%rdi
  call   <RightChild@plt>
  cmp    %rax,%r12
  jle    L10
  mov    (%r14,%rbx,8),%rdx
  mov    (%r14,%rax,8),%rcx
  movsd  0x0(%r13,%rcx,8),%xmm0
  ucomisd 0x0(%r13,%rdx,8),%xmm0
  cmova  %rax,%rbx
L10:
  cmp    %rbp,%rbx
  je     L39
  lea    (%r14,%rbp,8),%rdx
  lea    (%r14,%rbx,8),%rax
  mov    %rbx,%rbp
  mov    (%rdx),%rcx
  mov    (%rax),%rsi
  mov    %rbp,%rdi
  mov    %rsi,(%rdx)
  mov    %rcx,(%rax)
  call   <LeftChild@plt>
  mov    %rax,%rbx
  cmp    %r12,%rax
  jl     L16
L12:
  mov    %rbp,%rbx
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Heap(double *Vector, long *TieBreaker, long *Rank, long ListSize, long start) {
  long notdone;
  long left, right, largest, current;
  long tmprank;
  current = start;
  notdone = 1;
  largest = current;
  while (notdone) {
    left = LeftChild(current);
    if (left < ListSize) {
      if (Vector[Rank[largest]] < Vector[Rank[left]])
        largest = left;
    }
    right = RightChild(current);
    if (right < ListSize) {
      if (Vector[Rank[largest]] < Vector[Rank[right]])
        largest = right;
    }
    if (largest == current)
      notdone = 0;
    else {
      tmprank = Rank[current];
      Rank[current] = Rank[largest];
      Rank[largest] = tmprank;
      current = largest;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Heap>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rbp,%rdi
  call   <LeftChild@plt>
  mov    %rax,%rbx
  cmp    %r12,%rax
  jge    L23
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%r14,%rbx,8),%rdx
  mov    (%r14,%rbp,8),%rax
  movsd  0x0(%r13,%rdx,8),%xmm0
  comisd 0x0(%r13,%rax,8),%xmm0
  cmovbe %rbp,%rbx
L2:
  mov    %rbp,%rdi
  call   <RightChild@plt>
  cmp    %rax,%r12
  jle    L5
  mov    (%r14,%rbx,8),%rdx
  mov    (%r14,%rax,8),%rcx
  movsd  0x0(%r13,%rcx,8),%xmm0
  ucomisd 0x0(%r13,%rdx,8),%xmm0
  cmova  %rax,%rbx
L5:
  cmp    %rbp,%rbx
  je     L19
  lea    (%r14,%rbp,8),%rdx
  lea    (%r14,%rbx,8),%rax
  mov    %rbx,%rbp
  mov    (%rdx),%rcx
  mov    (%rax),%rsi
  mov    %rbp,%rdi
  mov    %rsi,(%rdx)
  mov    %rcx,(%rax)
  call   <LeftChild@plt>
  mov    %rax,%rbx
  cmp    %r12,%rax
  jl     L8
L23:
  mov    %rbp,%rbx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Heap(double *Vector, long *TieBreaker, long *Rank, long ListSize, long start) {
  long notdone;
  long left, right, largest, current;
  long tmprank;
  current = start;
  notdone = 1;
  largest = current;
  while (notdone) {
    left = LeftChild(current);
    if (left < ListSize) {
      if (Vector[Rank[largest]] < Vector[Rank[left]])
        largest = left;
    }
    right = RightChild(current);
    if (right < ListSize) {
      if (Vector[Rank[largest]] < Vector[Rank[right]])
        largest = right;
    }
    if (largest == current)
      notdone = 0;
    else {
      tmprank = Rank[current];
      Rank[current] = Rank[largest];
      Rank[largest] = tmprank;
      current = largest;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D29
type_guessed: string

tool: D18: ppm2png ppm_file_name



tool: D13:   reads ppm input file and


tool: D29:   writes simple png output to out.png file



assistant: ```c
int usage() {
  printf("ppm2png ppm_file_name\n\n");
  printf("  reads ppm input file and\n");
  printf("  writes simple png output to out.png file\n\n");
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D21: ppm2png ppm_file_name



tool: D20:   reads ppm input file and


tool: D10:   writes simple png output to out.png file



assistant: ```c
int usage() {
  printf("ppm2png ppm_file_name\n\n");
  printf("  reads ppm input file and\n");
  printf("  writes simple png output to out.png file\n\n");
  return 1;
}
```