ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<modify_heap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L28
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L28
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L27
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L27
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <modify_heap>
L1:
  nop
  leave
  ret
```

assistant: ```c
void modify_heap(int a[], int n, int p) {
  int l = 2 * p + 1;
  int r = 2 * p + 2;
  int t = p;
  if (l < n && a[l] > a[t]) {
    t = l;
  }
  if (r < n && a[r] > a[t]) {
    t = r;
  }
  if (t != p) {
    swap(a + p, a + t);
    modify_heap(a, n, t);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<modify_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%eax
  lea    (%rdx,%rdx,1),%ebx
  lea    0x1(%rbx),%edx
  add    $0x2,%ebx
  cmp    %esi,%edx
  jge    L64
  movslq %edx,%rcx
  movslq %eax,%rsi
  mov    (%rdi,%rsi,4),%edi
  cmp    %edi,0x0(%rbp,%rcx,4)
  jle    L64
  cmp    %r12d,%ebx
  jge    L48
  movslq %ebx,%rsi
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rsi,4)
  cmovle %edx,%ebx
  jmp    L24
L48:
  mov    %edx,%ebx
  jmp    L24
L64:
  cmp    %r12d,%ebx
  jge    L41
  movslq %ebx,%rdx
  movslq %eax,%rcx
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rdx,4)
  jle    L41
L24:
  cmp    %eax,%ebx
  je     L41
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rdx,4),%rsi
  cltq
  lea    0x0(%rbp,%rax,4),%rdi
  call   <swap@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <modify_heap>
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void modify_heap(int a[], int n, int p) {
  int l = 2 * p + 1;
  int r = 2 * p + 2;
  int t = p;
  if (l < n && a[l] > a[t]) {
    t = l;
  }
  if (r < n && a[r] > a[t]) {
    t = r;
  }
  if (t != p) {
    swap(a + p, a + t);
    modify_heap(a, n, t);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<modify_heap>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L31
L69:
  movslq %edx,%rax
  movslq %ecx,%rsi
  mov    0x0(%rbp,%rax,4),%edi
  cmp    %edi,0x0(%rbp,%rsi,4)
  jle    L3
  cmp    %r12d,%ebx
  jl     L25
  mov    %ecx,%ebx
L5:
  cmp    %edx,%ebx
  je     L10
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rax,4),%rdi
  lea    0x0(%rbp,%rdx,4),%rsi
  call   <swap@plt>
  mov    %ebx,%edx
L31:
  lea    (%rdx,%rdx,1),%ebx
  lea    0x1(%rbx),%ecx
  add    $0x2,%ebx
  cmp    %r12d,%ecx
  jl     L69
L3:
  cmp    %r12d,%ebx
  jge    L10
  movslq %edx,%rax
  movslq %ebx,%rcx
  mov    0x0(%rbp,%rax,4),%esi
  cmp    %esi,0x0(%rbp,%rcx,4)
  jg     L5
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  movslq %ebx,%rdi
  mov    0x0(%rbp,%rsi,4),%esi
  cmp    %esi,0x0(%rbp,%rdi,4)
  cmovle %ecx,%ebx
  jmp    L5
```

assistant: ```c
void modify_heap(int a[], int n, int p) {
  int l = 2 * p + 1;
  int r = 2 * p + 2;
  int t = p;
  if (l < n && a[l] > a[t]) {
    t = l;
  }
  if (r < n && a[r] > a[t]) {
    t = r;
  }
  if (t != p) {
    swap(a + p, a + t);
    modify_heap(a, n, t);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<modify_heap>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    (%rdx,%rdx,1),%ebx
  lea    0x1(%rbx),%ecx
  add    $0x2,%ebx
  cmp    %r12d,%ecx
  jge    L53
  nopl   0x0(%rax)
L49:
  movslq %ecx,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %edx,%rax
  mov    0x0(%rbp,%rax,4),%edi
  cmp    %edi,(%rsi)
  jle    L53
  cmp    %r12d,%ebx
  jl     L61
L16:
  mov    %ecx,%ebx
L76:
  cmp    %edx,%ebx
  je     L45
  lea    0x0(%rbp,%rax,4),%rdi
  call   <swap@plt>
  mov    %ebx,%edx
  lea    (%rdx,%rdx,1),%ebx
  lea    0x1(%rbx),%ecx
  add    $0x2,%ebx
  cmp    %r12d,%ecx
  jl     L49
L53:
  cmp    %r12d,%ebx
  jge    L45
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %edx,%rax
  mov    (%rsi),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jl     L76
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L61:
  movslq %ebx,%rdi
  mov    (%rsi),%r8d
  lea    0x0(%rbp,%rdi,4),%rdi
  cmp    %r8d,(%rdi)
  jle    L16
  mov    %rdi,%rsi
  jmp    L76
```

assistant: ```c
void modify_heap(int a[], int n, int p) {
  int l = 2 * p + 1;
  int r = 2 * p + 2;
  int t = p;
  if (l < n && a[l] > a[t]) {
    t = l;
  }
  if (r < n && a[r] > a[t]) {
    t = r;
  }
  if (t != p) {
    swap(a + p, a + t);
    modify_heap(a, n, t);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dcf_decode_bcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t dcf_decode_bcd(uint8_t input) {
  uint8_t result;
  result = (input & 0x0F);
  result += ((input >> 4) & 0x0F) * 10;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dcf_decode_bcd>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  sar    $0x4,%edi
  and    $0xf,%edi
  lea    (%rdi,%rdi,4),%edx
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
uint8_t dcf_decode_bcd(uint8_t input) {
  uint8_t result;
  result = (input & 0x0F);
  result += ((input >> 4) & 0x0F) * 10;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dcf_decode_bcd>:
  endbr64
  mov    %edi,%eax
  sar    $0x4,%edi
  and    $0xf,%edi
  and    $0xf,%eax
  lea    (%rdi,%rdi,4),%edx
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
uint8_t dcf_decode_bcd(uint8_t input) {
  uint8_t result;
  result = (input & 0x0F);
  result += ((input >> 4) & 0x0F) * 10;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dcf_decode_bcd>:
  endbr64
  mov    %edi,%eax
  sar    $0x4,%edi
  and    $0xf,%edi
  and    $0xf,%eax
  lea    (%rdi,%rdi,4),%edx
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
uint8_t dcf_decode_bcd(uint8_t input) {
  uint8_t result;
  result = (input & 0x0F);
  result += ((input >> 4) & 0x0F) * 10;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D1: Hello World

tool: D5: 


assistant: ```c
int main() {
  printf("Hello World");
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string
name: unpack_data
arguments: label: D4
data_type: string

tool: D7: Hello World

tool: D4: 


assistant: ```c
int main() {
  printf("Hello World");
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
datatype: string
name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D12: Hello World

tool: D6: 


assistant: ```c
int main() {
  printf("Hello World");
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D15
type_guessed: string
name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D15: Hello World

tool: D9: 


assistant: ```c
int main() {
  printf("Hello World");
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<zgerand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L6:
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L22:
  mov    $0x0,%eax
  call   <rand@plt>
  movq   %xmm0,%rax
  mov    D14(%rip),%rdx
  mov    (%rdx),%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdx,%xmm1
  mov    -0x30(%rbp),%rdx
  mov    (%rdx),%edx
  mov    %edx,%ecx
  imul   -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  add    %edx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movq   %rax,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  mov    $0x0,%eax
  call   <rand@plt>
  movq   %xmm0,%rax
  mov    D14(%rip),%rdx
  mov    (%rdx),%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdx,%xmm1
  mov    -0x30(%rbp),%rdx
  mov    (%rdx),%edx
  mov    %edx,%ecx
  imul   -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  add    %edx,%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movq   %rax,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L22
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void zgerand(const int *m, const int *n, double *A, const int *ldA) {
  int i, j;
  for (j = 0; j < *n; j++)
    for (i = 0; i < *m; i++) {
      A[2 * (i + j * *ldA)] = rand() / (double)RAND_MAX;
      A[2 * (i + j * *ldA) + 1] = rand() / (double)RAND_MAX;
    }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<zgerand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    $0x0,%r12d
  cmpl   $0x0,(%rsi)
  jg     L24
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %r12d,%eax
  imul   0x0(%r13),%eax
  add    %ebx,%eax
  add    %eax,%eax
  cltq
  mov    D1(%rip),%rbp
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x0(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r14,%rax,8)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %r12d,%eax
  imul   0x0(%r13),%eax
  add    %ebx,%eax
  add    %eax,%eax
  cltq
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x0(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%r14,%rax,8)
  add    $0x1,%ebx
  cmp    %ebx,(%r15)
  jg     L45
L13:
  add    $0x1,%r12d
  mov    0x8(%rsp),%rax
  cmp    %r12d,(%rax)
  jle    L27
L24:
  mov    $0x0,%ebx
  cmpl   $0x0,(%r15)
  jg     L45
  jmp    L13
```

assistant: ```c
void zgerand(const int *m, const int *n, double *A, const int *ldA) {
  int i, j;
  for (j = 0; j < *n; j++)
    for (i = 0; i < *m; i++) {
      A[2 * (i + j * *ldA)] = rand() / (double)RAND_MAX;
      A[2 * (i + j * *ldA) + 1] = rand() / (double)RAND_MAX;
    }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<zgerand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    (%rsi),%esi
  test   %esi,%esi
  jle    L29
  mov    %rdi,%r14
  mov    %rdx,%r13
  mov    %rcx,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L7:
  mov    (%r14),%eax
  test   %eax,%eax
  jle    L39
  mov    D2(%rip),%rbp
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  mov    (%r12),%eax
  cvtsi2sdq 0x0(%rbp),%xmm1
  imul   %ebx,%eax
  divsd  %xmm1,%xmm0
  add    %r15d,%eax
  add    %eax,%eax
  cltq
  movsd  %xmm0,0x0(%r13,%rax,8)
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  mov    (%r12),%eax
  cvtsi2sdq 0x0(%rbp),%xmm1
  imul   %ebx,%eax
  divsd  %xmm1,%xmm0
  add    %r15d,%eax
  add    $0x1,%r15d
  add    %eax,%eax
  cltq
  movsd  %xmm0,0x8(%r13,%rax,8)
  cmp    %r15d,(%r14)
  jg     L18
L39:
  mov    0x8(%rsp),%rax
  add    $0x1,%ebx
  cmp    %ebx,(%rax)
  jg     L7
L29:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void zgerand(const int *m, const int *n, double *A, const int *ldA) {
  int i, j;
  for (j = 0; j < *n; j++)
    for (i = 0; i < *m; i++) {
      A[2 * (i + j * *ldA)] = rand() / (double)RAND_MAX;
      A[2 * (i + j * *ldA) + 1] = rand() / (double)RAND_MAX;
    }
}
```
user: Translate the below assembly code into C programming language:

```asm
<zgerand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%eax
  mov    %rsi,0x8(%rsp)
  test   %eax,%eax
  jle    L23
  mov    (%rdi),%eax
  mov    %rdi,%r14
  mov    %rdx,%r12
  mov    %rcx,%r13
  xor    %ebx,%ebx
  xchg   %ax,%ax
L6:
  test   %eax,%eax
  jle    L23
  mov    D0(%rip),%rbp
  xor    %r15d,%r15d
  xchg   %ax,%ax
L11:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  mov    0x0(%r13),%eax
  cvtsi2sdq 0x0(%rbp),%xmm1
  imul   %ebx,%eax
  divsd  %xmm1,%xmm0
  add    %r15d,%eax
  add    %eax,%eax
  cltq
  movsd  %xmm0,(%r12,%rax,8)
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  mov    0x0(%r13),%eax
  cvtsi2sdq 0x0(%rbp),%xmm1
  imul   %ebx,%eax
  divsd  %xmm1,%xmm0
  add    %r15d,%eax
  add    $0x1,%r15d
  add    %eax,%eax
  cltq
  movsd  %xmm0,0x8(%r12,%rax,8)
  mov    (%r14),%eax
  cmp    %r15d,%eax
  jg     L11
  mov    0x8(%rsp),%rdx
  add    $0x1,%ebx
  cmp    %ebx,(%rdx)
  jg     L6
L23:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void zgerand(const int *m, const int *n, double *A, const int *ldA) {
  int i, j;
  for (j = 0; j < *n; j++)
    for (i = 0; i < *m; i++) {
      A[2 * (i + j * *ldA)] = rand() / (double)RAND_MAX;
      A[2 * (i + j * *ldA) + 1] = rand() / (double)RAND_MAX;
    }
}
```
user: What is the c source code of the assembly code below:

```asm
<UartTxPutsf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L5
L2:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <UartTxPutChar@plt>
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void UartTxPutsf(const char *s) {
  while (*s) {
    UartTxPutChar(*s++);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UartTxPutsf>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L1
L6:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <UartTxPutChar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L6
L1:
  pop    %rbx
  ret
```

assistant: ```c
void UartTxPutsf(const char *s) {
  while (*s) {
    UartTxPutChar(*s++);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<UartTxPutsf>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L15:
  call   <UartTxPutChar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L15
L14:
  pop    %rbx
  ret
```

assistant: ```c
void UartTxPutsf(const char *s) {
  while (*s) {
    UartTxPutChar(*s++);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<UartTxPutsf>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L16
L10:
  call   <UartTxPutChar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L10
L16:
  pop    %rbx
  ret
```

assistant: ```c
void UartTxPutsf(const char *s) {
  while (*s) {
    UartTxPutChar(*s++);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L69
  mov    -0x18(%rbp),%rax
  mov    %rax,D112(%rip)
  jmp    L69
L81:
  mov    D112(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D104(%rip)
L69:
  mov    D104(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L61
  mov    D104(%rip),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L81
L61:
  mov    D104(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0x0,%eax
  jmp    L79
L7:
  mov    D104(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L1:
  mov    D104(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D104(%rip)
L8:
  mov    D104(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L85
  mov    D104(%rip),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
L85:
  mov    D104(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  mov    D104(%rip),%rax
  movb   $0x0,(%rax)
  mov    D104(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D104(%rip)
L53:
  mov    -0x8(%rbp),%rax
L79:
  leave
  ret
```

assistant: ```c
char *strtok(char *str, const char *delimiters) {
  static char *pos = NULL;
  char *start;
  if (str != NULL) {
    pos = str;
  }
  while (*pos != '\0' && strchr(delimiters, *pos) != NULL) {
    ++pos;
  }
  if (*pos == '\0') {
    return NULL;
  }
  start = pos;
  while (*pos != '\0' && strchr(delimiters, *pos) == NULL) {
    ++pos;
  }
  if (*pos != '\0') {
    *pos = '\0';
    ++pos;
  }
  return start;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strtok>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  test   %rdi,%rdi
  je     L48
  mov    %rdi,D35(%rip)
L48:
  mov    D35(%rip),%rax
  movzbl (%rax),%esi
  test   %sil,%sil
  je     L99
L5:
  movsbl %sil,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L74
  mov    D35(%rip),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,D7(%rip)
  movzbl 0x1(%rax),%esi
  test   %sil,%sil
  jne    L5
L99:
  mov    $0x0,%ebp
  jmp    L40
L74:
  mov    D7(%rip),%rbp
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L38
L60:
  movsbl %sil,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L103
  mov    D7(%rip),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,D7(%rip)
  movzbl 0x1(%rax),%esi
  test   %sil,%sil
  jne    L60
  jmp    L40
L103:
  mov    D7(%rip),%rax
  cmpb   $0x0,(%rax)
  je     L40
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,D7(%rip)
L40:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    %rax,%rbp
  jmp    L40
```

assistant: ```c
char *strtok(char *str, const char *delimiters) {
  static char *pos = NULL;
  char *start;
  if (str != NULL) {
    pos = str;
  }
  while (*pos != '\0' && strchr(delimiters, *pos) != NULL) {
    ++pos;
  }
  if (*pos == '\0') {
    return NULL;
  }
  start = pos;
  while (*pos != '\0' && strchr(delimiters, *pos) == NULL) {
    ++pos;
  }
  if (*pos != '\0') {
    *pos = '\0';
    ++pos;
  }
  return start;
}
```
user: What is the c source code of the assembly code below:

```asm
<strtok>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L50
  mov    %rdi,D21(%rip)
L93:
  movsbl (%rdi),%esi
  test   %sil,%sil
  jne    L78
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L108:
  mov    D21(%rip),%rax
  movsbl 0x1(%rax),%esi
  lea    0x1(%rax),%rdx
  mov    %rdx,D44(%rip)
  test   %sil,%sil
  je     L68
L78:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L108
  mov    D44(%rip),%r12
  movsbl (%r12),%esi
  test   %sil,%sil
  jne    L7
  jmp    L68
  nop
L60:
  movsbl 0x1(%rax),%esi
  lea    0x1(%rax),%rdx
  mov    %rdx,D44(%rip)
  test   %sil,%sil
  je     L104
L7:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  mov    D44(%rip),%rax
  je     L60
  cmpb   $0x0,(%rax)
  je     L104
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,D44(%rip)
L104:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    D44(%rip),%rdi
  jmp    L93
  nopl   0x0(%rax)
L68:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strtok(char *str, const char *delimiters) {
  static char *pos = NULL;
  char *start;
  if (str != NULL) {
    pos = str;
  }
  while (*pos != '\0' && strchr(delimiters, *pos) != NULL) {
    ++pos;
  }
  if (*pos == '\0') {
    return NULL;
  }
  start = pos;
  while (*pos != '\0' && strchr(delimiters, *pos) == NULL) {
    ++pos;
  }
  if (*pos != '\0') {
    *pos = '\0';
    ++pos;
  }
  return start;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strtok>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L16
  mov    %rdi,D26(%rip)
L95:
  movsbl (%rdi),%esi
  test   %sil,%sil
  jne    L50
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L36:
  mov    D26(%rip),%rax
  movsbl 0x1(%rax),%esi
  lea    0x1(%rax),%rdx
  mov    %rdx,D59(%rip)
  test   %sil,%sil
  je     L77
L50:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L36
  mov    D59(%rip),%r12
  movsbl (%r12),%esi
  test   %sil,%sil
  jne    L26
  jmp    L77
  nop
L98:
  movsbl 0x1(%rax),%esi
  lea    0x1(%rax),%rdx
  mov    %rdx,D59(%rip)
  test   %sil,%sil
  je     L79
L26:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  mov    D59(%rip),%rax
  je     L98
  cmpb   $0x0,(%rax)
  je     L79
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,D59(%rip)
L79:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    D59(%rip),%rdi
  jmp    L95
  nopl   0x0(%rax)
L77:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strtok(char *str, const char *delimiters) {
  static char *pos = NULL;
  char *start;
  if (str != NULL) {
    pos = str;
  }
  while (*pos != '\0' && strchr(delimiters, *pos) != NULL) {
    ++pos;
  }
  if (*pos == '\0') {
    return NULL;
  }
  start = pos;
  while (*pos != '\0' && strchr(delimiters, *pos) == NULL) {
    ++pos;
  }
  if (*pos != '\0') {
    *pos = '\0';
    ++pos;
  }
  return start;
}
```