ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <scanner_test@plt>
  xor    %eax,%eax
  call   <parser_test@plt>
  xor    %eax,%eax
  call   <random_messages_test@plt>
  xor    %eax,%eax
  call   <utils_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  scanner_test();
  parser_test();
  random_messages_test();
  utils_test();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<token_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L1:
  addl   $0x1,-0x4(%rbp)
  addq   $0x8,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int token_count(char **toklist) {
  unsigned int i = 0;
  while (0 != *toklist) {
    i++;
    toklist++;
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<token_count>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L2
  mov    $0x0,%eax
L12:
  add    $0x1,%eax
  add    $0x8,%rdi
  cmpq   $0x0,(%rdi)
  jne    L12
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int token_count(char **toklist) {
  unsigned int i = 0;
  while (0 != *toklist) {
    i++;
    toklist++;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<token_count>:
  endbr64
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L13
  nopl   0x0(%rax)
L8:
  add    $0x8,%rdi
  add    $0x1,%eax
  cmpq   $0x0,(%rdi)
  jne    L8
  ret
  xchg   %ax,%ax
L13:
  ret
```

assistant: ```c
unsigned int token_count(char **toklist) {
  unsigned int i = 0;
  while (0 != *toklist) {
    i++;
    toklist++;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<token_count>:
  endbr64
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L16
  nopl   0x0(%rax)
L15:
  add    $0x8,%rdi
  add    $0x1,%eax
  cmpq   $0x0,(%rdi)
  jne    L15
  ret
  xchg   %ax,%ax
L16:
  ret
```

assistant: ```c
unsigned int token_count(char **toklist) {
  unsigned int i = 0;
  while (0 != *toklist) {
    i++;
    toklist++;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x15(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x15(%rbp),%eax
  movsbl %al,%eax
  sub    $0x25,%eax
  cmp    $0xa,%eax
  ja     L71
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D35(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D35(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L18
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L18
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L18
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edi
  cltd
  idiv   %edi
  mov    %eax,-0xc(%rbp)
  jmp    L18
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  jmp    L18
L71:
  mov    $0x0,%eax
  jmp    L35
L18:
  mov    -0x10(%rbp),%ecx
  movzbl -0x15(%rbp),%eax
  movsbl %al,%edx
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%esi
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
datatype: string
name: retrieve_data
arguments: tag: D37
datatype: string

tool: D12: %d %d %c

tool: D37: %d %c %d = %d

assistant: ```c
int main() {
  int a, b, o;
  char c;
  scanf("%d %d %c", &a, &b, &c);
  switch (c) {
  case '+':
    o = a + b;
    break;
  case '-':
    o = a - b;
    break;
  case '*':
    o = a * b;
    break;
  case '/':
    o = a / b;
    break;
  case '%':
    o = a % b;
    break;
  default:
    return 0;
  }
  return 0 * printf("%d %c %d = %d", a, c, b, o);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  movsbl %al,%esi
  sub    $0x25,%eax
  cmp    $0xa,%al
  ja     L32
  movzbl %al,%eax
  lea    D24(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    0x14(%rsp),%r8d
  add    0x10(%rsp),%r8d
L50:
  mov    0x14(%rsp),%ecx
  mov    %esi,%edx
  mov    0x10(%rsp),%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
  mov    0x10(%rsp),%r8d
  sub    0x14(%rsp),%r8d
  jmp    L50
  mov    0x10(%rsp),%r8d
  imul   0x14(%rsp),%r8d
  jmp    L50
  mov    0x10(%rsp),%eax
  cltd
  idivl  0x14(%rsp)
  mov    %eax,%r8d
  jmp    L50
  mov    0x10(%rsp),%eax
  cltd
  idivl  0x14(%rsp)
  mov    %edx,%r8d
  jmp    L50
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D27
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string

tool: D27: %d %d %c

tool: D29: %d %c %d = %d

assistant: ```c
int main() {
  int a, b, o;
  char c;
  scanf("%d %d %c", &a, &b, &c);
  switch (c) {
  case '+':
    o = a + b;
    break;
  case '-':
    o = a - b;
    break;
  case '*':
    o = a * b;
    break;
  case '/':
    o = a / b;
    break;
  case '%':
    o = a % b;
    break;
  default:
    return 0;
  }
  return 0 * printf("%d %c %d = %d", a, c, b, o);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0x2cdb,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L48
L39:
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L48:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L39
  movw   $0x0,-0xc(%rbp)
  jmp    L9
L33:
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  add    %eax,%eax
  shl    $0x2,%eax
  and    $0x38,%eax
  or     %eax,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L33
  movzwl -0xa(%rbp),%eax
  or     $0xfbfd,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1++;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] |= ((state[0UL] + state[0UL]) & (unsigned short)15) << 2UL;
      local1++;
    }
    output[0UL] = (state[0UL] | 957911421UL) | (unsigned short)64421;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0x2cdb(%rax),%edx
  movzwl 0x2(%rdi),%edi
  test   %di,%di
  je     L8
  mov    $0x0,%eax
L28:
  add    $0x1,%eax
  cmp    %di,%ax
  jne    L28
  mov    $0x0,%ecx
L24:
  lea    0x0(,%rdx,8),%eax
  and    $0x38,%eax
  or     %eax,%edx
  add    $0x1,%ecx
  cmp    %di,%cx
  jne    L24
L8:
  or     $0xfbfd,%dx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1++;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] |= ((state[0UL] + state[0UL]) & (unsigned short)15) << 2UL;
      local1++;
    }
    output[0UL] = (state[0UL] | 957911421UL) | (unsigned short)64421;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edi
  lea    0x2cdb(%rax),%edx
  test   %di,%di
  je     L10
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L0:
  lea    0x0(,%rdx,8),%eax
  add    $0x1,%ecx
  and    $0x38,%eax
  or     %eax,%edx
  cmp    %di,%cx
  jne    L0
L10:
  or     $0xfbfd,%dx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1++;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] |= ((state[0UL] + state[0UL]) & (unsigned short)15) << 2UL;
      local1++;
    }
    output[0UL] = (state[0UL] | 957911421UL) | (unsigned short)64421;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edi
  lea    0x2cdb(%rax),%edx
  test   %di,%di
  je     L16
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L7:
  lea    0x0(,%rdx,8),%eax
  add    $0x1,%ecx
  and    $0x38,%eax
  or     %eax,%edx
  cmp    %di,%cx
  jne    L7
L16:
  or     $0xfbfd,%dx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1++;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] |= ((state[0UL] + state[0UL]) & (unsigned short)15) << 2UL;
      local1++;
    }
    output[0UL] = (state[0UL] | 957911421UL) | (unsigned short)64421;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ext_status_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ext_status_read(char **buffer, size_t *buffer_size, bool *needs_deallocation) {
  (void)buffer;
  (void)buffer_size;
  (void)needs_deallocation;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ext_status_read>:
  endbr64
  ret
```

assistant: ```c
void ext_status_read(char **buffer, size_t *buffer_size, bool *needs_deallocation) {
  (void)buffer;
  (void)buffer_size;
  (void)needs_deallocation;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ext_status_read>:
  endbr64
  ret
```

assistant: ```c
void ext_status_read(char **buffer, size_t *buffer_size, bool *needs_deallocation) {
  (void)buffer;
  (void)buffer_size;
  (void)needs_deallocation;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ext_status_read>:
  endbr64
  ret
```

assistant: ```c
void ext_status_read(char **buffer, size_t *buffer_size, bool *needs_deallocation) {
  (void)buffer;
  (void)buffer_size;
  (void)needs_deallocation;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x63,-0x4(%rbp)
  cmpl   $0x63,-0x4(%rbp)
  jne    L10
  cmpl   $0x62,-0x4(%rbp)
  je     L10
  mov    $0x2a,%eax
  jmp    L16
L10:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i = 99;
  if (i == 99 && i != 98) {
    return 42;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 99;
  if (i == 99 && i != 98) {
    return 42;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 99;
  if (i == 99 && i != 98) {
    return 42;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 99;
  if (i == 99 && i != 98) {
    return 42;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sensors_strip_of_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L24
L26:
  subl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0x0,-0x4(%rbp)
  js     L9
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L26
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void sensors_strip_of_spaces(char *name) {
  int i;
  for (i = strlen(name) - 1; (i >= 0) && (name[i] == ' '); i--)
    ;
  name[i + 1] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sensors_strip_of_spaces>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L28
  movslq %eax,%rdx
  add    %rbx,%rdx
L5:
  cmpb   $0x20,(%rdx)
  jne    L28
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  jne    L5
L28:
  cltq
  movb   $0x0,0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void sensors_strip_of_spaces(char *name) {
  int i;
  for (i = strlen(name) - 1; (i >= 0) && (name[i] == ' '); i--)
    ;
  name[i + 1] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sensors_strip_of_spaces>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L12
  movslq %edx,%rax
  add    %rbx,%rax
  jmp    L29
  nopl   0x0(%rax)
L25:
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  je     L5
L29:
  cmpb   $0x20,(%rax)
  mov    %rax,%rcx
  je     L25
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    (%rbx,%rdx,1),%rcx
L5:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
L12:
  cltq
  lea    (%rbx,%rax,1),%rcx
  jmp    L5
```

assistant: ```c
void sensors_strip_of_spaces(char *name) {
  int i;
  for (i = strlen(name) - 1; (i >= 0) && (name[i] == ' '); i--)
    ;
  name[i + 1] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sensors_strip_of_spaces>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L23
  movslq %edx,%rax
  add    %rbx,%rax
  jmp    L15
  nopl   0x0(%rax)
L10:
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  je     L36
L15:
  cmpb   $0x20,(%rax)
  mov    %rax,%rcx
  je     L10
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    (%rbx,%rdx,1),%rcx
L36:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
L23:
  cltq
  lea    (%rbx,%rax,1),%rcx
  jmp    L36
```

assistant: ```c
void sensors_strip_of_spaces(char *name) {
  int i;
  for (i = strlen(name) - 1; (i >= 0) && (name[i] == ' '); i--)
    ;
  name[i + 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dutch_national_flag_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L1
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L60
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L11
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ebx,(%rax)
L11:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
  jmp    L1
L60:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  jge    L55
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ebx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L1
L55:
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void dutch_national_flag_sort(int tab[], int *i, int *j, int piv) {
  int k = (*i);
  while (k <= (*j)) {
    if (tab[k] < piv) {
      if ((*i) != k)
        do {
          register int tmp_MACRO_IMPL_ = (tab)[(*i)];
          (tab)[(*i)] = (tab)[k];
          (tab)[(k)] = tmp_MACRO_IMPL_;
        } while (0);
      (*i)++;
      k++;
    } else if (tab[k] > piv) {
      do {
        register int tmp_MACRO_IMPL_ = (tab)[(*j)];
        (tab)[(*j)] = (tab)[k];
        (tab)[(k)] = tmp_MACRO_IMPL_;
      } while (0);
      (*j)--;
    } else {
      k++;
    }
  }
  (*i)--;
  (*j)++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dutch_national_flag_sort>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%rdi
  mov    %rdx,%r8
  mov    %ecx,%r10d
  mov    (%rsi),%eax
  mov    (%rdx),%ecx
  cmp    %ecx,%eax
  jle    L46
L14:
  subl   $0x1,(%rdi)
  addl   $0x1,(%r8)
  ret
L33:
  addl   $0x1,(%rdi)
  add    $0x1,%eax
L66:
  mov    (%r8),%ecx
  cmp    %ecx,%eax
  jg     L14
L46:
  movslq %eax,%rdx
  lea    (%r9,%rdx,4),%rsi
  mov    (%rsi),%edx
  cmp    %r10d,%edx
  jge    L28
  mov    (%rdi),%ecx
  cmp    %eax,%ecx
  je     L33
  movslq %ecx,%rcx
  lea    (%r9,%rcx,4),%rcx
  mov    (%rcx),%r11d
  mov    %edx,(%rcx)
  mov    %r11d,(%rsi)
  jmp    L33
L28:
  jle    L6
  movslq %ecx,%rcx
  lea    (%r9,%rcx,4),%rcx
  mov    (%rcx),%r11d
  mov    %edx,(%rcx)
  mov    %r11d,(%rsi)
  subl   $0x1,(%r8)
  jmp    L66
L6:
  add    $0x1,%eax
  jmp    L66
```

assistant: ```c
void dutch_national_flag_sort(int tab[], int *i, int *j, int piv) {
  int k = (*i);
  while (k <= (*j)) {
    if (tab[k] < piv) {
      if ((*i) != k)
        do {
          register int tmp_MACRO_IMPL_ = (tab)[(*i)];
          (tab)[(*i)] = (tab)[k];
          (tab)[(k)] = tmp_MACRO_IMPL_;
        } while (0);
      (*i)++;
      k++;
    } else if (tab[k] > piv) {
      do {
        register int tmp_MACRO_IMPL_ = (tab)[(*j)];
        (tab)[(*j)] = (tab)[k];
        (tab)[(k)] = tmp_MACRO_IMPL_;
      } while (0);
      (*j)--;
    } else {
      k++;
    }
  }
  (*i)--;
  (*j)++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dutch_national_flag_sort>:
  endbr64
  mov    %rdx,%r8
  mov    (%rsi),%eax
  mov    (%rdx),%edx
  mov    %rdi,%r10
  mov    %ecx,%r11d
  mov    %rsi,%rdi
  cmp    %edx,%eax
  jle    L22
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L55:
  movslq (%rdi),%r9
  mov    %eax,%edx
  cmp    %eax,%r9d
  je     L8
  lea    (%r10,%r9,4),%rdx
  mov    (%rdx),%r9d
  mov    %esi,(%rdx)
  mov    %r9d,(%rcx)
  mov    (%rdi),%edx
L8:
  add    $0x1,%edx
  add    $0x1,%eax
  mov    %edx,(%rdi)
  mov    (%r8),%edx
L40:
  cmp    %edx,%eax
  jg     L53
L22:
  movslq %eax,%rcx
  lea    (%r10,%rcx,4),%rcx
  mov    (%rcx),%esi
  cmp    %r11d,%esi
  jl     L55
  jle    L68
  movslq %edx,%rdx
  lea    (%r10,%rdx,4),%rdx
  mov    (%rdx),%r9d
  mov    %esi,(%rdx)
  mov    %r9d,(%rcx)
  mov    (%r8),%esi
  lea    -0x1(%rsi),%edx
  mov    %edx,(%r8)
  cmp    %edx,%eax
  jle    L22
L53:
  mov    (%rdi),%eax
L28:
  sub    $0x1,%eax
  mov    %eax,(%rdi)
  addl   $0x1,(%r8)
  ret
  nop
L68:
  mov    (%r8),%edx
  add    $0x1,%eax
  jmp    L40
```

assistant: ```c
void dutch_national_flag_sort(int tab[], int *i, int *j, int piv) {
  int k = (*i);
  while (k <= (*j)) {
    if (tab[k] < piv) {
      if ((*i) != k)
        do {
          register int tmp_MACRO_IMPL_ = (tab)[(*i)];
          (tab)[(*i)] = (tab)[k];
          (tab)[(k)] = tmp_MACRO_IMPL_;
        } while (0);
      (*i)++;
      k++;
    } else if (tab[k] > piv) {
      do {
        register int tmp_MACRO_IMPL_ = (tab)[(*j)];
        (tab)[(*j)] = (tab)[k];
        (tab)[(k)] = tmp_MACRO_IMPL_;
      } while (0);
      (*j)--;
    } else {
      k++;
    }
  }
  (*i)--;
  (*j)++;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dutch_national_flag_sort>:
  endbr64
  mov    %rdx,%r10
  mov    (%rsi),%eax
  mov    (%rdx),%edx
  mov    %rdi,%r9
  mov    %ecx,%r11d
  mov    %rsi,%rdi
  cmp    %edx,%eax
  jle    L12
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L65:
  movslq (%rdi),%r8
  mov    %eax,%edx
  cmp    %eax,%r8d
  je     L8
  lea    (%r9,%r8,4),%rdx
  mov    (%rdx),%r8d
  mov    %esi,(%rdx)
  mov    %r8d,(%rcx)
  mov    (%rdi),%edx
L8:
  add    $0x1,%edx
  add    $0x1,%eax
  mov    %edx,(%rdi)
  mov    (%r10),%edx
L16:
  cmp    %edx,%eax
  jg     L1
L12:
  movslq %eax,%rcx
  lea    (%r9,%rcx,4),%rcx
  mov    (%rcx),%esi
  cmp    %r11d,%esi
  jl     L65
  jle    L11
  movslq %edx,%rdx
  lea    (%r9,%rdx,4),%rdx
  mov    (%rdx),%r8d
  mov    %esi,(%rdx)
  mov    %r8d,(%rcx)
  mov    (%r10),%esi
  lea    -0x1(%rsi),%edx
  mov    %edx,(%r10)
  cmp    %edx,%eax
  jle    L12
L1:
  mov    (%rdi),%eax
L52:
  sub    $0x1,%eax
  mov    %eax,(%rdi)
  addl   $0x1,(%r10)
  ret
  nop
L11:
  add    $0x1,%eax
  jmp    L16
```

assistant: ```c
void dutch_national_flag_sort(int tab[], int *i, int *j, int piv) {
  int k = (*i);
  while (k <= (*j)) {
    if (tab[k] < piv) {
      if ((*i) != k)
        do {
          register int tmp_MACRO_IMPL_ = (tab)[(*i)];
          (tab)[(*i)] = (tab)[k];
          (tab)[(k)] = tmp_MACRO_IMPL_;
        } while (0);
      (*i)++;
      k++;
    } else if (tab[k] > piv) {
      do {
        register int tmp_MACRO_IMPL_ = (tab)[(*j)];
        (tab)[(*j)] = (tab)[k];
        (tab)[(k)] = tmp_MACRO_IMPL_;
      } while (0);
      (*j)--;
    } else {
      k++;
    }
  }
  (*i)--;
  (*j)++;
}
```