ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stripPs>:
  endbr64
  cmpb   $0x28,(%rdi)
  je     L42
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1,%eax
  jg     L28
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rbp
  cmpb   $0x29,-0x1(%rbx,%rbp,1)
  jne    L24
  cmp    $0x2,%eax
  jle    L26
  lea    -0x3(%rax),%edx
  lea    0x1(%rbx),%rsi
  mov    %rbx,%rdi
  add    $0x1,%rdx
  call   <memmove@plt>
L26:
  movb   $0x0,-0x2(%rbx,%rbp,1)
  jmp    L24
```

assistant: ```c
void stripPs(char *str) {
  if (str[0] == '(' && strlen(str) >= 2) {
    int count;
    int slen = strlen(str);
    if (str[slen - 1] == ')') {
      for (count = 0; count < slen - 2; count++) {
        str[count] = str[count + 1];
      }
      str[slen - 2] = '\0';
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stripPs>:
  endbr64
  cmpb   $0x28,(%rdi)
  je     L13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1,%eax
  jg     L45
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rbp
  cmpb   $0x29,-0x1(%rbx,%rbp,1)
  jne    L16
  cmp    $0x2,%eax
  jle    L29
  lea    -0x3(%rax),%edx
  lea    0x1(%rbx),%rsi
  mov    %rbx,%rdi
  add    $0x1,%rdx
  call   <memmove@plt>
L29:
  movb   $0x0,-0x2(%rbx,%rbp,1)
  jmp    L16
```

assistant: ```c
void stripPs(char *str) {
  if (str[0] == '(' && strlen(str) >= 2) {
    int count;
    int slen = strlen(str);
    if (str[slen - 1] == ')') {
      for (count = 0; count < slen - 2; count++) {
        str[count] = str[count + 1];
      }
      str[slen - 2] = '\0';
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clean_task>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void clean_task(void *data) {
  struct readTaskData *info = (struct readTaskData *)data;
  free(info);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clean_task>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void clean_task(void *data) {
  struct readTaskData *info = (struct readTaskData *)data;
  free(info);
}
```
user: Translate the below assembly code into C programming language:

```asm
<clean_task>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void clean_task(void *data) {
  struct readTaskData *info = (struct readTaskData *)data;
  free(info);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clean_task>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void clean_task(void *data) {
  struct readTaskData *info = (struct readTaskData *)data;
  free(info);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_intlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L5
L8:
  shrl   -0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_intlen() {
  int intlen = 0;
  unsigned all_ones = ~0;
  while (all_ones > 0) {
    all_ones >>= 1;
    intlen++;
  }
  return intlen;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_intlen>:
  endbr64
  mov    $0x0,%eax
L5:
  add    $0x1,%eax
  cmp    $0x20,%eax
  jne    L5
  ret
```

assistant: ```c
int get_intlen() {
  int intlen = 0;
  unsigned all_ones = ~0;
  while (all_ones > 0) {
    all_ones >>= 1;
    intlen++;
  }
  return intlen;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_intlen>:
  endbr64
  mov    $0x20,%eax
  ret
```

assistant: ```c
int get_intlen() {
  int intlen = 0;
  unsigned all_ones = ~0;
  while (all_ones > 0) {
    all_ones >>= 1;
    intlen++;
  }
  return intlen;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_intlen>:
  endbr64
  mov    $0x20,%eax
  ret
```

assistant: ```c
int get_intlen() {
  int intlen = 0;
  unsigned all_ones = ~0;
  while (all_ones > 0) {
    all_ones >>= 1;
    intlen++;
  }
  return intlen;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unmask_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long unmask_addr(long long *addr) {
  long long raddr, mask;
  raddr = *addr;
  return raddr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unmask_addr>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long long unmask_addr(long long *addr) {
  long long raddr, mask;
  raddr = *addr;
  return raddr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unmask_addr>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long long unmask_addr(long long *addr) {
  long long raddr, mask;
  raddr = *addr;
  return raddr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unmask_addr>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long long unmask_addr(long long *addr) {
  long long raddr, mask;
  raddr = *addr;
  return raddr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<builtIn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D34(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <bi_cd@plt>
  jmp    L27
L22:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D35(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L59
  mov    $0x0,%eax
  call   <bi_pwd@plt>
  jmp    L27
L59:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D49(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <bi_exit@plt>
  jmp    L27
L3:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L11
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <bi_fg@plt>
  jmp    L27
L11:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D41(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L28
  mov    $0x0,%eax
  call   <bi_jobs@plt>
  jmp    L27
L28:
  movl   $0x0,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D34
type: string
name: disassemble_data
arguments: data_tag: D35
type: string
name: disassemble_data
arguments: data_tag: D49
type: string
name: disassemble_data
arguments: data_tag: D15
type: string
name: disassemble_data
arguments: data_tag: D41
type: string

tool: D34: cd

tool: D35: pwd

tool: D49: exit

tool: D15: fg

tool: D41: jobs

assistant: ```c
int builtIn(char *args[]) {
  int result = 1;
  if (strcmp(args[1], "cd") == 0)
    bi_cd(args[2]);
  else if (strcmp(args[1], "pwd") == 0)
    bi_pwd();
  else if (strcmp(args[1], "exit") == 0)
    bi_exit(args[0]);
  else if (strcmp(args[1], "fg") == 0)
    bi_fg(args[2]);
  else if (strcmp(args[1], "jobs") == 0)
    bi_jobs();
  else
    result = 0;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<builtIn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x8(%rdi),%rdi
  lea    D27(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L81
  mov    0x10(%rbx),%rdi
  call   <bi_cd@plt>
  mov    $0x1,%eax
L57:
  pop    %rbx
  ret
L81:
  mov    0x8(%rbx),%rdi
  lea    D17(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  call   <bi_pwd@plt>
  mov    $0x1,%eax
  jmp    L57
L1:
  mov    0x8(%rbx),%rdi
  lea    D24(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L64
  mov    (%rbx),%rdi
  call   <bi_exit@plt>
  mov    $0x1,%eax
  jmp    L57
L64:
  mov    0x8(%rbx),%rdi
  lea    D22(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L41
  mov    0x10(%rbx),%rdi
  call   <bi_fg@plt>
  mov    $0x1,%eax
  jmp    L57
L41:
  mov    0x8(%rbx),%rdi
  lea    D10(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L57
  call   <bi_jobs@plt>
  mov    $0x1,%eax
  jmp    L57
```

tool_calls: name: read_data
arguments: data_label: D27
data_type: string
name: read_data
arguments: data_label: D17
data_type: string
name: read_data
arguments: data_label: D24
data_type: string
name: read_data
arguments: data_label: D22
data_type: string
name: read_data
arguments: data_label: D10
data_type: string

tool: D27: cd

tool: D17: pwd

tool: D24: exit

tool: D22: fg

tool: D10: jobs

assistant: ```c
int builtIn(char *args[]) {
  int result = 1;
  if (strcmp(args[1], "cd") == 0)
    bi_cd(args[2]);
  else if (strcmp(args[1], "pwd") == 0)
    bi_pwd();
  else if (strcmp(args[1], "exit") == 0)
    bi_exit(args[0]);
  else if (strcmp(args[1], "fg") == 0)
    bi_fg(args[2]);
  else if (strcmp(args[1], "jobs") == 0)
    bi_jobs();
  else
    result = 0;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<builtIn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x8(%rdi),%rdi
  lea    D9(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L34
  mov    0x10(%rbx),%rdi
  call   <bi_cd@plt>
  mov    $0x1,%eax
L32:
  pop    %rbx
  ret
  nopl   (%rax)
L34:
  mov    0x8(%rbx),%rdi
  lea    D26(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L17
  call   <bi_pwd@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L17:
  mov    0x8(%rbx),%rdi
  lea    D4(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
  mov    0x8(%rbx),%rdi
  lea    D49(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
  mov    0x10(%rbx),%rdi
  call   <bi_fg@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%rdi
  call   <bi_exit@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    0x8(%rbx),%rdi
  lea    D3(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L32
  call   <bi_jobs@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string
name: disassemble_data
arguments: label: D26
datatype: string
name: disassemble_data
arguments: label: D4
datatype: string
name: disassemble_data
arguments: label: D49
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string

tool: D9: cd

tool: D26: pwd

tool: D4: exit

tool: D49: fg

tool: D3: jobs

assistant: ```c
int builtIn(char *args[]) {
  int result = 1;
  if (strcmp(args[1], "cd") == 0)
    bi_cd(args[2]);
  else if (strcmp(args[1], "pwd") == 0)
    bi_pwd();
  else if (strcmp(args[1], "exit") == 0)
    bi_exit(args[0]);
  else if (strcmp(args[1], "fg") == 0)
    bi_fg(args[2]);
  else if (strcmp(args[1], "jobs") == 0)
    bi_jobs();
  else
    result = 0;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<builtIn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x8(%rdi),%rdi
  lea    D5(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L7
  mov    0x10(%rbx),%rdi
  call   <bi_cd@plt>
  mov    $0x1,%eax
L30:
  pop    %rbx
  ret
  nopl   (%rax)
L7:
  mov    0x8(%rbx),%rdi
  lea    D21(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  call   <bi_pwd@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  mov    0x8(%rbx),%rdi
  lea    D44(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L15
  mov    0x8(%rbx),%rdi
  lea    D13(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L35
  mov    0x10(%rbx),%rdi
  call   <bi_fg@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%rdi
  call   <bi_exit@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    0x8(%rbx),%rdi
  lea    D4(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L30
  call   <bi_jobs@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D44
datatype: string
name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string

tool: D5: cd

tool: D21: pwd

tool: D44: exit

tool: D13: fg

tool: D4: jobs

assistant: ```c
int builtIn(char *args[]) {
  int result = 1;
  if (strcmp(args[1], "cd") == 0)
    bi_cd(args[2]);
  else if (strcmp(args[1], "pwd") == 0)
    bi_pwd();
  else if (strcmp(args[1], "exit") == 0)
    bi_exit(args[0]);
  else if (strcmp(args[1], "fg") == 0)
    bi_fg(args[2]);
  else if (strcmp(args[1], "jobs") == 0)
    bi_jobs();
  else
    result = 0;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<djb_hash_original>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L17:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  lea    (%rdx,%rax,1),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int djb_hash_original(const void *key, int len) {
  const unsigned char *s = key;
  unsigned int h = 0;
  int i;
  for (i = 0; i < len; i++)
    h = (33 * h + s[i]);
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<djb_hash_original>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x0,%eax
L13:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  add    %ecx,%eax
  movzbl (%rdx),%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L13
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int djb_hash_original(const void *key, int len) {
  const unsigned char *s = key;
  unsigned int h = 0;
  int i;
  for (i = 0; i < len; i++)
    h = (33 * h + s[i]);
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<djb_hash_original>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  add    %edx,%eax
  movzbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L19
  ret
  nop
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int djb_hash_original(const void *key, int len) {
  const unsigned char *s = key;
  unsigned int h = 0;
  int i;
  for (i = 0; i < len; i++)
    h = (33 * h + s[i]);
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<djb_hash_original>:
  endbr64
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  add    %edx,%eax
  movzbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L6
  ret
  nop
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int djb_hash_original(const void *key, int len) {
  const unsigned char *s = key;
  unsigned int h = 0;
  int i;
  for (i = 0; i < len; i++)
    h = (33 * h + s[i]);
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strsep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L33
L16:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L74:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L57
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  movl   $0x1,-0x14(%rbp)
  jmp    L34
L57:
  addq   $0x1,-0x30(%rbp)
L23:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L74
L34:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L33:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  cmpl   $0x0,-0x14(%rbp)
  je     L16
L18:
  cmpl   $0x0,-0x14(%rbp)
  jne    L24
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
L24:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strsep(char **stringp, const char *delim) {
  char *old = *stringp;
  const char *s;
  int ok = 0;
  while (**stringp && !ok) {
    s = delim;
    while (*delim) {
      if (**stringp == *delim) {
        **stringp = 0;
        ok = 1;
        break;
      }
      delim++;
    }
    delim = s;
    *stringp += 1;
  }
  if (!ok)
    *stringp = NULL;
  return old;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strsep>:
  endbr64
  mov    (%rdi),%r9
  movzbl (%r9),%ecx
  mov    %r9,%r8
  test   %cl,%cl
  jne    L44
L23:
  movq   $0x0,(%rdi)
  jmp    L7
L37:
  movb   $0x0,(%r8)
  addq   $0x1,(%rdi)
L7:
  mov    %r9,%rax
  ret
L6:
  mov    (%rdi),%rax
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L23
L44:
  movzbl (%rsi),%eax
  mov    %rsi,%rdx
  test   %al,%al
  je     L6
L38:
  cmp    %cl,%al
  je     L37
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L38
  jmp    L6
```

assistant: ```c
char *strsep(char **stringp, const char *delim) {
  char *old = *stringp;
  const char *s;
  int ok = 0;
  while (**stringp && !ok) {
    s = delim;
    while (*delim) {
      if (**stringp == *delim) {
        **stringp = 0;
        ok = 1;
        break;
      }
      delim++;
    }
    delim = s;
    *stringp += 1;
  }
  if (!ok)
    *stringp = NULL;
  return old;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strsep>:
  endbr64
  mov    (%rdi),%r9
  movzbl (%r9),%ecx
  mov    %r9,%r8
  test   %cl,%cl
  je     L21
  nopw   0x0(%rax,%rax,1)
L42:
  movzbl (%rsi),%eax
  mov    %rsi,%rdx
  test   %al,%al
  jne    L47
  jmp    L37
  nopl   0x0(%rax)
L10:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L37
L47:
  cmp    %cl,%al
  jne    L10
  movb   $0x0,(%r8)
  mov    (%rdi),%rax
  add    $0x1,%rax
  mov    %rax,(%rdi)
  mov    %r9,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    (%rdi),%rax
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  jne    L42
L21:
  xor    %eax,%eax
  mov    %rax,(%rdi)
  mov    %r9,%rax
  ret
```

assistant: ```c
char *strsep(char **stringp, const char *delim) {
  char *old = *stringp;
  const char *s;
  int ok = 0;
  while (**stringp && !ok) {
    s = delim;
    while (*delim) {
      if (**stringp == *delim) {
        **stringp = 0;
        ok = 1;
        break;
      }
      delim++;
    }
    delim = s;
    *stringp += 1;
  }
  if (!ok)
    *stringp = NULL;
  return old;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strsep>:
  endbr64
  mov    (%rdi),%r9
  movzbl (%r9),%ecx
  mov    %r9,%r8
  test   %cl,%cl
  je     L36
  nopw   0x0(%rax,%rax,1)
L28:
  movzbl (%rsi),%eax
  mov    %rsi,%rdx
  test   %al,%al
  jne    L44
  jmp    L51
  nopl   0x0(%rax)
L10:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L51
L44:
  cmp    %cl,%al
  jne    L10
  movb   $0x0,(%r8)
  mov    (%rdi),%rax
  add    $0x1,%rax
  mov    %rax,(%rdi)
  mov    %r9,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  add    $0x1,%r8
  mov    %r8,(%rdi)
  movzbl (%r8),%ecx
  test   %cl,%cl
  jne    L28
L36:
  xor    %eax,%eax
  mov    %rax,(%rdi)
  mov    %r9,%rax
  ret
```

assistant: ```c
char *strsep(char **stringp, const char *delim) {
  char *old = *stringp;
  const char *s;
  int ok = 0;
  while (**stringp && !ok) {
    s = delim;
    while (*delim) {
      if (**stringp == *delim) {
        **stringp = 0;
        ok = 1;
        break;
      }
      delim++;
    }
    delim = s;
    *stringp += 1;
  }
  if (!ok)
    *stringp = NULL;
  return old;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    $0x3,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  int arr[2];
  arr[0] = 1;
  arr[1] = 2;
  return arr[0] + arr[1] - 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int arr[2];
  arr[0] = 1;
  arr[1] = 2;
  return arr[0] + arr[1] - 3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int arr[2];
  arr[0] = 1;
  arr[1] = 2;
  return arr[0] + arr[1] - 3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int arr[2];
  arr[0] = 1;
  arr[1] = 2;
  return arr[0] + arr[1] - 3;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sea_platform_buffer_construct_with_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sea_platform_buffer_construct_with_buffer_no_copy@plt>
  jmp    L10
L13:
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
void *sea_platform_buffer_construct_with_buffer(void *data, unsigned long size) {
  void *copy = malloc(size);
  if (copy) {
    memcpy(copy, data, size);
    return sea_platform_buffer_construct_with_buffer_no_copy(copy, size);
  } else {
    return NULL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sea_platform_buffer_construct_with_buffer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sea_platform_buffer_construct_with_buffer_no_copy@plt>
  mov    %rax,%rbx
L5:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *sea_platform_buffer_construct_with_buffer(void *data, unsigned long size) {
  void *copy = malloc(size);
  if (copy) {
    memcpy(copy, data, size);
    return sea_platform_buffer_construct_with_buffer_no_copy(copy, size);
  } else {
    return NULL;
  }
}
```