user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rcx
  mov    %rsp,%rdi
  lea    0xf(,%rcx,4),%rax
  mov    %rcx,%rsi
  mov    %rax,%r8
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%r8
  and    $0xfffffffffffffff0,%rdx
  sub    %r8,%rdi
  cmp    %rdi,%rsp
  je     L238
L151:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L151
L238:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L229
L29:
  mov    %rsp,-0x50(%rbp)
  mov    %rax,%rdx
  mov    %rsp,%rdi
  and    $0xfffffffffffff000,%rax
  and    $0xfffffffffffffff0,%rdx
  sub    %rax,%rdi
L138:
  cmp    %rdi,%rsp
  je     L179
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L138
L229:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L29
L179:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L98
L233:
  lea    (%rcx,%rcx,4),%rax
  mov    %rsp,-0x58(%rbp)
  mov    %rsp,%rcx
  lea    0xf(%rax,%rax,1),%rax
  mov    %rax,%rdi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rdx
  sub    %rdi,%rcx
L168:
  cmp    %rcx,%rsp
  je     L73
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L168
L98:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L233
L73:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L91
  orq    $0x0,-0x8(%rsp,%rdx,1)
L91:
  mov    %rax,%rdx
  mov    %rsp,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%r9
  and    $0xfffffffffffffff0,%rdx
  sub    %rax,%rcx
L176:
  cmp    %rcx,%rsp
  je     L173
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L176
L173:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L135
  orq    $0x0,-0x8(%rsp,%rax,1)
L135:
  test   %esi,%esi
  jle    L212
  mov    -0x50(%rbp),%rsi
  mov    -0x58(%rbp),%r14
  mov    %r9,%r12
  mov    %rsp,%r13
  mov    %r9,%r15
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %r13,%r8
  mov    %r15,%rcx
  mov    %r14,%rdx
  xor    %eax,%eax
  mov    %rsi,-0x48(%rbp)
  add    $0x1,%ebx
  add    $0x4,%r14
  add    $0xa,%r15
  lea    D10(%rip),%rdi
  add    $0xa,%r13
  call   <scanf@plt>
  mov    -0x48(%rbp),%rsi
  mov    -0x3c(%rbp),%eax
  add    $0x4,%rsi
  cmp    %ebx,%eax
  jg     L52
  test   %eax,%eax
  jle    L212
  xor    %ebx,%ebx
  lea    D19(%rip),%r15
  lea    D16(%rip),%r14
  nopl   (%rax)
L55:
  movzbl (%r12),%eax
  cmp    $0x51,%al
  je     L23
L185:
  cmp    $0x52,%al
  je     L223
  add    $0x1,%rbx
  add    $0xa,%r12
  cmp    %ebx,-0x3c(%rbp)
  jg     L55
L212:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L223:
  mov    -0x50(%rbp),%rax
  mov    -0x58(%rbp),%rcx
  mov    %r14,%rdi
  add    $0xa,%r12
  mov    (%rax,%rbx,4),%eax
  cltd
  idivl  (%rcx,%rbx,4)
  add    $0x1,%rbx
  mov    %edx,%esi
  mov    %eax,%edx
  call   <printf@plt>
  cmp    %ebx,-0x3c(%rbp)
  jle    L212
  movzbl (%r12),%eax
  cmp    $0x51,%al
  jne    L185
  nopl   0x0(%rax)
L23:
  mov    -0x50(%rbp),%rax
  mov    -0x58(%rbp),%rcx
  mov    %r15,%rdi
  mov    (%rax,%rbx,4),%eax
  cltd
  idivl  (%rcx,%rbx,4)
  mov    %eax,%esi
  call   <printf@plt>
  movzbl (%r12),%eax
  jmp    L185
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D10
type_infered: string
name: read_data
arguments: label: D19
type_infered: string
name: read_data
arguments: label: D16
type_infered: string

tool: D14: %d

tool: D10: %d %d %s %s

tool: D19: Q: %d R: %d


tool: D16: R: %d Q: %d


assistant: ```c
main() {
  int n, i;
  scanf("%d", &n);
  int n1[n], n2[n];
  char str[n][10], str1[n][10];
  for (i = 0; i < n; i++) {
    scanf("%d %d %s %s", &n1[i], &n2[i], &str[i], str1[i]);
  }
  for (i = 0; i < n; i++) {
    if (str[i][0] == 'Q')
      printf("Q: %d R: %d\n", (n1[i] / n2[i]), (n1[i] % n2[i]));
    if (str[i][0] == 'R')
      printf("R: %d Q: %d\n", (n1[i] % n2[i]), (n1[i] / n2[i]));
  }
  return 0;
}
```