ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_repblock>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,0xc(%rsp)
  mov    %edx,%ebx
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D7(%rip),%r15
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  movsbl %bl,%ebx
  movsbl 0xc(%rsp),%r15d
  mov    %ebx,%ecx
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <old_str_repblock@plt>
  mov    %r13,%rdx
  mov    $0x0,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <new_str_repblock@plt>
  mov    %r12,%rdx
  mov    $0x0,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <asm_str_repblock@plt>
  mov    %rbp,%rdx
  mov    $0x0,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D30
datatype: string

tool: D7: qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq

tool: D3: old - (%5llu cycles) %s


tool: D19: new - (%5llu cycles) %s


tool: D30: asm - (%5llu cycles) %s


assistant: ```c
void test_repblock(char *cmp, char find, char rep) {
  char *o1 = malloc(128);
  char *o2 = malloc(128);
  char *o3 = malloc(128);
  strcpy(o1, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  strcpy(o2, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  strcpy(o3, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  uint64_t t1, t2;
  0;
  old_str_repblock(o1, cmp, find, rep);
  0;
  printf("old - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o1);
  0;
  new_str_repblock(o2, cmp, find, rep);
  0;
  printf("new - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o2);
  0;
  asm_str_repblock(o3, cmp, find, rep);
  0;
  printf("asm - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o3);
  free(o1);
  free(o2);
  free(o3);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_repblock>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x80,%edi
  push   %rbx
  mov    %edx,%ebx
  movsbl %bl,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <malloc@plt>
  mov    $0x80,%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    $0x80,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  movsbl 0xc(%rsp),%r12d
  mov    %ebx,%ecx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  mov    %r12d,%edx
  call   <old_str_repblock@plt>
  xor    %r8d,%r8d
  mov    %r15,%rdx
  lea    D16(%rip),%rdi
  mov    %r8,%rsi
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <new_str_repblock@plt>
  mov    %r14,%rdx
  xor    %esi,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <asm_str_repblock@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <free@plt>
```

tool_calls: name: parse_data
arguments: tag: D28
datatype: string
name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D23
datatype: string
name: parse_data
arguments: tag: D24
datatype: string

tool: D28: qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq

tool: D16: old - (%5llu cycles) %s


tool: D23: new - (%5llu cycles) %s


tool: D24: asm - (%5llu cycles) %s


assistant: ```c
void test_repblock(char *cmp, char find, char rep) {
  char *o1 = malloc(128);
  char *o2 = malloc(128);
  char *o3 = malloc(128);
  strcpy(o1, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  strcpy(o2, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  strcpy(o3, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  uint64_t t1, t2;
  0;
  old_str_repblock(o1, cmp, find, rep);
  0;
  printf("old - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o1);
  0;
  new_str_repblock(o2, cmp, find, rep);
  0;
  printf("new - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o2);
  0;
  asm_str_repblock(o3, cmp, find, rep);
  0;
  printf("asm - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o3);
  free(o1);
  free(o2);
  free(o3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_repblock>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x80,%edi
  push   %rbx
  mov    %edx,%ebx
  movsbl %bl,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <malloc@plt>
  mov    $0x80,%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    $0x80,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  movsbl 0xc(%rsp),%r12d
  mov    %ebx,%ecx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  mov    %r12d,%edx
  call   <old_str_repblock@plt>
  xor    %r8d,%r8d
  mov    %r15,%rdx
  lea    D18(%rip),%rdi
  mov    %r8,%rsi
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <new_str_repblock@plt>
  mov    %r14,%rdx
  xor    %esi,%esi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <asm_str_repblock@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <free@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D34
data_type: string
name: parse_data
arguments: data_tag: D15
data_type: string

tool: D27: qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq

tool: D18: old - (%5llu cycles) %s


tool: D34: new - (%5llu cycles) %s


tool: D15: asm - (%5llu cycles) %s


assistant: ```c
void test_repblock(char *cmp, char find, char rep) {
  char *o1 = malloc(128);
  char *o2 = malloc(128);
  char *o3 = malloc(128);
  strcpy(o1, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  strcpy(o2, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  strcpy(o3, "qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq");
  uint64_t t1, t2;
  0;
  old_str_repblock(o1, cmp, find, rep);
  0;
  printf("old - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o1);
  0;
  new_str_repblock(o2, cmp, find, rep);
  0;
  printf("new - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o2);
  0;
  asm_str_repblock(o3, cmp, find, rep);
  0;
  printf("asm - (%5llu cycles) %s\n", (long long unsigned int)t2 - t1, o3);
  free(o1);
  free(o2);
  free(o3);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<between>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jb     L32
  movsd  -0x18(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L32
  mov    $0x1,%eax
  jmp    L13
L32:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L28
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L28
  mov    $0x1,%eax
  jmp    L13
L28:
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int between(double a, double p, double b) {
  if (a <= p && p <= b)
    return 1;
  if (b <= p && p <= a)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<between>:
  endbr64
  comisd %xmm0,%xmm1
  jb     L16
  mov    $0x1,%eax
  comisd %xmm1,%xmm2
  jae    L17
L16:
  comisd %xmm2,%xmm1
  jb     L5
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
  ret
L5:
  mov    $0x0,%eax
L17:
  ret
```

assistant: ```c
int between(double a, double p, double b) {
  if (a <= p && p <= b)
    return 1;
  if (b <= p && p <= a)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<between>:
  endbr64
  comisd %xmm0,%xmm1
  jb     L8
  comisd %xmm1,%xmm2
  mov    $0x1,%eax
  jae    L22
L8:
  comisd %xmm2,%xmm1
  jb     L23
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  setae  %al
  ret
  nopl   (%rax)
L23:
  xor    %eax,%eax
L22:
  ret
```

assistant: ```c
int between(double a, double p, double b) {
  if (a <= p && p <= b)
    return 1;
  if (b <= p && p <= a)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<between>:
  endbr64
  comisd %xmm0,%xmm1
  jb     L29
  comisd %xmm1,%xmm2
  mov    $0x1,%eax
  jae    L5
L29:
  comisd %xmm2,%xmm1
  jb     L20
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  setae  %al
  ret
  nopl   (%rax)
L20:
  xor    %eax,%eax
L5:
  ret
```

assistant: ```c
int between(double a, double p, double b) {
  if (a <= p && p <= b)
    return 1;
  if (b <= p && p <= a)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x43c(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x430(%rbp)
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0x434(%rbp)
  mov    $0xc351,%edi
  call   <htons@plt>
  mov    %eax,-0x438(%rbp)
  lea    -0x438(%rbp),%rcx
  mov    -0x43c(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
L4:
  movl   $0xc,-0x440(%rbp)
  lea    -0x440(%rbp),%rcx
  lea    -0x42c(%rbp),%rdx
  lea    -0x420(%rbp),%rsi
  mov    -0x43c(%rbp),%eax
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x400,%edx
  mov    %eax,%edi
  call   <recvfrom@plt>
  mov    -0x440(%rbp),%ebx
  lea    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x42c(%rbp),%rcx
  lea    -0x420(%rbp),%rsi
  mov    -0x43c(%rbp),%eax
  mov    %ebx,%r9d
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <sendto@plt>
  jmp    L4
```

assistant: ```c
int main() {
  int sock;
  struct sockaddr_in zerb_helb, bez_helb;
  socklen_t helb_tam;
  char buf[1024];
  sock = socket(AF_INET, SOCK_DGRAM, 0);
  zerb_helb.sin_family = AF_INET;
  zerb_helb.sin_addr.s_addr = htonl(INADDR_ANY);
  zerb_helb.sin_port = htons(50001);
  bind(sock, (struct sockaddr *)&zerb_helb, sizeof(zerb_helb));
  while (1) {
    helb_tam = sizeof(bez_helb);
    recvfrom(sock, buf, 1024, 0, (struct sockaddr *)&bez_helb, &helb_tam);
    sendto(sock, buf, strlen(buf), 0, (struct sockaddr *)&bez_helb, helb_tam);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x430,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rbx
  mov    $0x0,%edx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  mov    (%rbx),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  mov    (%rbx),%eax
  mov    %eax,0x10(%rsp)
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %eax,0xc(%rsp)
  mov    $0xc351,%edi
  call   <htons@plt>
  mov    %eax,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  mov    $0xc,%edx
  mov    %r12d,%edi
  call   <bind@plt>
  lea    0x4(%rsp),%r14
L9:
  movl   $0xc,0x4(%rsp)
  lea    0x14(%rsp),%rbp
  lea    0x20(%rsp),%rbx
  mov    %r14,%r9
  mov    %rbp,%r8
  mov    $0x0,%ecx
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <recvfrom@plt>
  mov    0x4(%rsp),%r13d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r13d,%r9d
  mov    %rbp,%r8
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <sendto@plt>
  jmp    L9
```

assistant: ```c
int main() {
  int sock;
  struct sockaddr_in zerb_helb, bez_helb;
  socklen_t helb_tam;
  char buf[1024];
  sock = socket(AF_INET, SOCK_DGRAM, 0);
  zerb_helb.sin_family = AF_INET;
  zerb_helb.sin_addr.s_addr = htonl(INADDR_ANY);
  zerb_helb.sin_port = htons(50001);
  bind(sock, (struct sockaddr *)&zerb_helb, sizeof(zerb_helb));
  while (1) {
    helb_tam = sizeof(bez_helb);
    recvfrom(sock, buf, 1024, 0, (struct sockaddr *)&bez_helb, &helb_tam);
    sendto(sock, buf, strlen(buf), 0, (struct sockaddr *)&bez_helb, helb_tam);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %edx,%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x430,%rsp
  mov    D24(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0x4(%rsp),%r13
  lea    0x14(%rsp),%r12
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%ebp
  mov    (%rbx),%eax
  lea    0x20(%rsp),%rbx
  mov    %eax,0x10(%rsp)
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0xc351,%edi
  mov    %eax,0xc(%rsp)
  call   <htons@plt>
  lea    0x8(%rsp),%rsi
  mov    $0xc,%edx
  mov    %ebp,%edi
  mov    %eax,0x8(%rsp)
  call   <bind@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r13,%r9
  mov    %r12,%r8
  xor    %ecx,%ecx
  mov    %rbx,%rsi
  mov    $0x400,%edx
  mov    %ebp,%edi
  movl   $0xc,0x4(%rsp)
  call   <recvfrom@plt>
  mov    0x4(%rsp),%r14d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12,%r8
  xor    %ecx,%ecx
  mov    %rbx,%rsi
  mov    %eax,%edx
  mov    %r14d,%r9d
  mov    %ebp,%edi
  call   <sendto@plt>
  jmp    L4
```

assistant: ```c
int main() {
  int sock;
  struct sockaddr_in zerb_helb, bez_helb;
  socklen_t helb_tam;
  char buf[1024];
  sock = socket(AF_INET, SOCK_DGRAM, 0);
  zerb_helb.sin_family = AF_INET;
  zerb_helb.sin_addr.s_addr = htonl(INADDR_ANY);
  zerb_helb.sin_port = htons(50001);
  bind(sock, (struct sockaddr *)&zerb_helb, sizeof(zerb_helb));
  while (1) {
    helb_tam = sizeof(bez_helb);
    recvfrom(sock, buf, 1024, 0, (struct sockaddr *)&bez_helb, &helb_tam);
    sendto(sock, buf, strlen(buf), 0, (struct sockaddr *)&bez_helb, helb_tam);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  xor    %edx,%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x430,%rsp
  mov    D5(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    D14(%rip),%rax
  lea    0x4(%rsp),%r13
  lea    0x14(%rsp),%r12
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%ebp
  mov    (%rbx),%eax
  lea    0x20(%rsp),%rbx
  mov    %eax,0x10(%rsp)
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0xc351,%edi
  mov    %eax,0xc(%rsp)
  call   <htons@plt>
  lea    0x8(%rsp),%rsi
  mov    $0xc,%edx
  mov    %ebp,%edi
  mov    %eax,0x8(%rsp)
  call   <bind@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r13,%r9
  mov    %r12,%r8
  xor    %ecx,%ecx
  mov    %rbx,%rsi
  mov    $0x400,%edx
  mov    %ebp,%edi
  movl   $0xc,0x4(%rsp)
  call   <recvfrom@plt>
  mov    0x4(%rsp),%r14d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12,%r8
  xor    %ecx,%ecx
  mov    %rbx,%rsi
  mov    %eax,%edx
  mov    %r14d,%r9d
  mov    %ebp,%edi
  call   <sendto@plt>
  jmp    L5
```

assistant: ```c
int main() {
  int sock;
  struct sockaddr_in zerb_helb, bez_helb;
  socklen_t helb_tam;
  char buf[1024];
  sock = socket(AF_INET, SOCK_DGRAM, 0);
  zerb_helb.sin_family = AF_INET;
  zerb_helb.sin_addr.s_addr = htonl(INADDR_ANY);
  zerb_helb.sin_port = htons(50001);
  bind(sock, (struct sockaddr *)&zerb_helb, sizeof(zerb_helb));
  while (1) {
    helb_tam = sizeof(bez_helb);
    recvfrom(sock, buf, 1024, 0, (struct sockaddr *)&bez_helb, &helb_tam);
    sendto(sock, buf, strlen(buf), 0, (struct sockaddr *)&bez_helb, helb_tam);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<gauss_solve_triangular>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%r10
  lea    -0x1(%rcx),%r15d
  test   %r15d,%r15d
  jle    L69
  mov    %rsi,%r13
  mov    %ecx,%r11d
  lea    0x8(%rdx),%r8
  mov    %r15d,%r12d
  movslq %ecx,%rcx
  shl    $0x3,%rcx
  mov    %r11d,%ebp
  mov    $0x0,%r9d
  mov    $0x0,%edi
  lea    0x10(%rdx),%r14
L9:
  movslq 0x0(%r13,%r9,4),%rax
  lea    (%r10,%rax,8),%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%r8),%xmm0
  movsd  %xmm0,(%rax)
  movsd  %xmm1,-0x8(%r8)
  add    $0x1,%edi
  cmp    %edi,%r11d
  jle    L36
  movslq %ebp,%rax
  add    %r9,%rax
  lea    (%rbx,%rax,8),%rdx
  mov    %r12d,%eax
  sub    %edi,%eax
  add    %r9,%rax
  lea    (%r14,%rax,8),%rsi
  mov    %r8,%rax
L60:
  movapd %xmm1,%xmm0
  mulsd  (%rdx),%xmm0
  addsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  add    %rcx,%rdx
  cmp    %rsi,%rax
  jne    L60
L36:
  add    $0x1,%r9
  add    $0x8,%r8
  add    %r11d,%ebp
  cmp    %r12d,%edi
  jne    L9
  movslq %r15d,%rdi
  mov    %r11d,%r8d
  not    %r8d
  movslq %r8d,%r8
  shl    $0x3,%r8
  imul   %r15d,%r11d
  movslq %r11d,%rax
  add    %rdi,%rax
  lea    (%rbx,%rax,8),%r9
  lea    0x8(%r10),%r11
L35:
  movsd  (%r10,%rdi,8),%xmm2
  divsd  (%r9),%xmm2
  movsd  %xmm2,(%r10,%rdi,8)
  test   %edi,%edi
  jle    L10
  mov    %r10,%rax
  lea    (%rbx,%rdi,8),%rdx
  lea    -0x1(%rdi),%esi
  lea    (%r11,%rsi,8),%rsi
L37:
  movapd %xmm2,%xmm1
  mulsd  (%rdx),%xmm1
  movsd  (%rax),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  add    %rcx,%rdx
  cmp    %rsi,%rax
  jne    L37
L10:
  sub    $0x1,%rdi
  add    %r8,%r9
  test   %edi,%edi
  jg     L35
L69:
  movsd  (%r10),%xmm0
  divsd  (%rbx),%xmm0
  movsd  %xmm0,(%r10)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void gauss_solve_triangular(const double *A, const int *p, double *b, int n) {
  for (int k = 0; k < n - 1; ++k) {
    int m = p[k];
    double t = b[m];
    b[m] = b[k];
    b[k] = t;
    for (int i = k + 1; i < n; ++i)
      b[i] += A[k + n * i] * t;
  }
  for (int k = n - 1; k > 0; --k) {
    b[k] /= A[k + n * k];
    double t = b[k];
    for (int i = 0; i < k; ++i)
      b[i] -= A[k + n * i] * t;
  }
  b[0] /= A[0 + 0 * n];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gauss_solve_triangular>:
  endbr64
  push   %r14
  mov    %rdi,%r11
  push   %r13
  lea    -0x1(%rcx),%r13d
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  push   %rbx
  test   %r13d,%r13d
  jle    L35
  mov    %ecx,%ebx
  movslq %ecx,%rcx
  lea    0x8(%rdx),%r9
  xor    %r10d,%r10d
  shl    $0x3,%rcx
  mov    %ebx,%ebp
  lea    0x10(%rdx),%r14
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L22:
  movslq (%r12,%r10,4),%rax
  movsd  -0x8(%r9),%xmm0
  add    $0x1,%r8d
  lea    (%rsi,%rax,8),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm0,(%rax)
  movsd  %xmm1,-0x8(%r9)
  cmp    %r8d,%ebx
  jle    L9
  movslq %ebp,%rax
  add    %r10,%rax
  lea    (%r11,%rax,8),%rdx
  mov    %r13d,%eax
  sub    %r8d,%eax
  add    %r10,%rax
  lea    (%r14,%rax,8),%rdi
  mov    %r9,%rax
  nop
L33:
  movsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rcx,%rdx
  mulsd  %xmm1,%xmm0
  addsd  -0x8(%rax),%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdi
  jne    L33
L9:
  add    $0x1,%r10
  add    $0x8,%r9
  add    %ebx,%ebp
  cmp    %r13d,%r8d
  jne    L22
  mov    %ebx,%r9d
  add    $0x1,%ebx
  movslq %r8d,%rdi
  imul   %r8d,%ebx
  not    %r9d
  movslq %r9d,%r9
  shl    $0x3,%r9
  movslq %ebx,%rax
  lea    (%r11,%rax,8),%r8
  nopl   0x0(%rax,%rax,1)
L19:
  movsd  (%rsi,%rdi,8),%xmm2
  lea    (%r11,%rdi,8),%rdx
  divsd  (%r8),%xmm2
  xor    %eax,%eax
  movsd  %xmm2,(%rsi,%rdi,8)
  nopl   (%rax)
L36:
  movsd  (%rdx),%xmm1
  movsd  (%rsi,%rax,8),%xmm0
  add    %rcx,%rdx
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L36
  sub    $0x1,%rdi
  add    %r9,%r8
  test   %edi,%edi
  jg     L19
L35:
  pop    %rbx
  movsd  (%rsi),%xmm0
  divsd  (%r11),%xmm0
  movsd  %xmm0,(%rsi)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void gauss_solve_triangular(const double *A, const int *p, double *b, int n) {
  for (int k = 0; k < n - 1; ++k) {
    int m = p[k];
    double t = b[m];
    b[m] = b[k];
    b[k] = t;
    for (int i = k + 1; i < n; ++i)
      b[i] += A[k + n * i] * t;
  }
  for (int k = n - 1; k > 0; --k) {
    b[k] /= A[k + n * k];
    double t = b[k];
    for (int i = 0; i < k; ++i)
      b[i] -= A[k + n * i] * t;
  }
  b[0] /= A[0 + 0 * n];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<core___core__Int___Object__hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long core___core__Int___Object__hash(long self) {
  long var;
  var = self;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<core___core__Int___Object__hash>:
  endbr64
  mov    %rdi,%rax
  ret
```

assistant: ```c
long core___core__Int___Object__hash(long self) {
  long var;
  var = self;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<core___core__Int___Object__hash>:
  endbr64
  mov    %rdi,%rax
  ret
```

assistant: ```c
long core___core__Int___Object__hash(long self) {
  long var;
  var = self;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fild_preg32_dword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0xdb,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <put8@plt>
  nop
  leave
  ret
```

assistant: ```c
void fild_preg32_dword(int reg32) {
  put8(0xDB);
  put8(reg32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fild_preg32_dword>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xdb,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put8@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fild_preg32_dword(int reg32) {
  put8(0xDB);
  put8(reg32);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fild_preg32_dword>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0xdb,%edi
  call   <put8@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1050 <put8@plt>
```

assistant: ```c
void fild_preg32_dword(int reg32) {
  put8(0xDB);
  put8(reg32);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fild_preg32_dword>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0xdb,%edi
  call   <put8@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1050 <put8@plt>
```

assistant: ```c
void fild_preg32_dword(int reg32) {
  put8(0xDB);
  put8(reg32);
}
```