ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string

tool: D0: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D2: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_quaddobl_start_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xf3,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_quaddobl_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(243, a, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_quaddobl_start_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xf3,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int read_quaddobl_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(243, a, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_quaddobl_start_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xf3,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int read_quaddobl_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(243, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_quaddobl_start_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xf3,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int read_quaddobl_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(243, a, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<maxextent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movss  D32(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L17
L9:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L42
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  D13(%rip),%xmm1
  xorps  %xmm1,%xmm0
  jmp    L18
L42:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
L18:
  movss  %xmm0,-0x4(%rbp)
  movss  -0xc(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L49
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L49:
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L9
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movsd  D34(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D16(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D32
type_infered: f32
name: disassemble_data
arguments: tag: D13
type_infered: byte[4]
name: disassemble_data
arguments: tag: D34
type_infered: f64
name: disassemble_data
arguments: tag: D16
type_infered: byte[8]

tool: D32: 9999999

tool: {"D13": [0x00,0x00,0x00,0x80]}

tool: D34: 1

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int maxextent(float *mat, int nstates) {
  int i;
  float min = 9999999.0, tn;
  int n2 = nstates * nstates;
  for (i = 0; i < n2; ++i) {
    tn = (mat[i] < 0) ? -mat[i] : mat[i];
    if (min > tn)
      min = tn;
  }
  return (int)(1. / min + .5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<maxextent>:
  endbr64
  imul   %esi,%esi
  test   %esi,%esi
  jle    L36
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  movss  D26(%rip),%xmm1
  pxor   %xmm2,%xmm2
  movss  D48(%rip),%xmm3
  jmp    L44
L41:
  minss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L17
L44:
  movss  (%rax),%xmm0
  comiss %xmm0,%xmm2
  jbe    L41
  xorps  %xmm3,%xmm0
  jmp    L41
L36:
  movss  D26(%rip),%xmm1
L17:
  cvtss2sd %xmm1,%xmm1
  movsd  D33(%rip),%xmm0
  divsd  %xmm1,%xmm0
  addsd  D13(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type_guessed: f32
name: extract_symbolic_data
arguments: tag: D48
type_guessed: byte[4]
name: extract_symbolic_data
arguments: tag: D33
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D13
type_guessed: byte[8]

tool: D26: 9999999

tool: {"D48": [0x00,0x00,0x00,0x80]}

tool: D33: 1

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int maxextent(float *mat, int nstates) {
  int i;
  float min = 9999999.0, tn;
  int n2 = nstates * nstates;
  for (i = 0; i < n2; ++i) {
    tn = (mat[i] < 0) ? -mat[i] : mat[i];
    if (min > tn)
      min = tn;
  }
  return (int)(1. / min + .5);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<maxextent>:
  endbr64
  mov    %esi,%eax
  imul   %esi,%eax
  test   %eax,%eax
  je     L2
  sub    $0x1,%eax
  movss  D2(%rip),%xmm1
  pxor   %xmm2,%xmm2
  movss  D15(%rip),%xmm3
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L11:
  movss  (%rdi),%xmm0
  comiss %xmm0,%xmm2
  jbe    L26
  xorps  %xmm3,%xmm0
L26:
  minss  %xmm1,%xmm0
  add    $0x4,%rdi
  movaps %xmm0,%xmm1
  cmp    %rdi,%rax
  jne    L11
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D10(%rip),%xmm0
  divsd  %xmm1,%xmm0
  addsd  D17(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L2:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: f32
name: unpack_data
arguments: data_tag: D15
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D10
type_guessed: f64
name: unpack_data
arguments: data_tag: D17
type_guessed: byte[8]

tool: D2: 9999999

tool: {"D15": [0x00,0x00,0x00,0x80]}

tool: D10: 1

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int maxextent(float *mat, int nstates) {
  int i;
  float min = 9999999.0, tn;
  int n2 = nstates * nstates;
  for (i = 0; i < n2; ++i) {
    tn = (mat[i] < 0) ? -mat[i] : mat[i];
    if (min > tn)
      min = tn;
  }
  return (int)(1. / min + .5);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maxextent>:
  endbr64
  mov    %esi,%eax
  imul   %esi,%eax
  test   %eax,%eax
  je     L14
  sub    $0x1,%eax
  movss  D5(%rip),%xmm1
  pxor   %xmm2,%xmm2
  movss  D19(%rip),%xmm3
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L27:
  movss  (%rdi),%xmm0
  comiss %xmm0,%xmm2
  jbe    L6
  xorps  %xmm3,%xmm0
L6:
  minss  %xmm1,%xmm0
  add    $0x4,%rdi
  movaps %xmm0,%xmm1
  cmp    %rdi,%rax
  jne    L27
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D30(%rip),%xmm0
  divsd  %xmm1,%xmm0
  addsd  D13(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L14:
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: f32
name: read_data
arguments: tag: D19
type_guessed: byte[4]
name: read_data
arguments: tag: D30
type_guessed: f64
name: read_data
arguments: tag: D13
type_guessed: byte[8]

tool: D5: 9999999

tool: {"D19": [0x00,0x00,0x00,0x80]}

tool: D30: 1

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int maxextent(float *mat, int nstates) {
  int i;
  float min = 9999999.0, tn;
  int n2 = nstates * nstates;
  for (i = 0; i < n2; ++i) {
    tn = (mat[i] < 0) ? -mat[i] : mat[i];
    if (min > tn)
      min = tn;
  }
  return (int)(1. / min + .5);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  bsr    -0x8(%rbp),%rax
  xor    $0x3f,%rax
  cltq
  jmp    L1
L8:
  mov    $0x40,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long clz(unsigned long x) {
  if (x != 0)
    return __builtin_clzl(x);
  return sizeof(unsigned long) * 8;
}
```
user: What is the c source code of the assembly code below:

```asm
<clz>:
  endbr64
  mov    $0x40,%eax
  test   %rdi,%rdi
  jne    L11
L2:
  ret
L11:
  bsr    %rdi,%rdi
  xor    $0x3f,%rdi
  movslq %edi,%rax
  jmp    L2
```

assistant: ```c
unsigned long clz(unsigned long x) {
  if (x != 0)
    return __builtin_clzl(x);
  return sizeof(unsigned long) * 8;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clz>:
  endbr64
  mov    $0x40,%eax
  test   %rdi,%rdi
  jne    L7
  ret
  nop
L7:
  bsr    %rdi,%rdi
  xor    $0x3f,%rdi
  movslq %edi,%rax
  ret
```

assistant: ```c
unsigned long clz(unsigned long x) {
  if (x != 0)
    return __builtin_clzl(x);
  return sizeof(unsigned long) * 8;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clz>:
  endbr64
  mov    $0x40,%eax
  test   %rdi,%rdi
  jne    L3
  ret
  nop
L3:
  bsr    %rdi,%rdi
  xor    $0x3f,%rdi
  movslq %edi,%rax
  ret
```

assistant: ```c
unsigned long clz(unsigned long x) {
  if (x != 0)
    return __builtin_clzl(x);
  return sizeof(unsigned long) * 8;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f77206f6c6c6568,%rax
  movabs $0x21212120646c72,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x10,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl -0x20(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D2: _____%d


tool: D1: %c


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[] = "hello world !!!";
  printf("_____%d\n", sizeof(buf) / sizeof(*buf));
  printf("%c\n", *buf);
  printf("%s\n", buf);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6f77206f6c6c6568,%rax
  movabs $0x21212120646c72,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    $0x10,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl (%rsp),%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D2
type: string

tool: D9: _____%d


tool: D2: %c


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[] = "hello world !!!";
  printf("_____%d\n", sizeof(buf) / sizeof(*buf));
  printf("%c\n", *buf);
  printf("%s\n", buf);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x10,%esi
  movdqa D18(%rip),%xmm0
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  movsbl (%rsp),%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: byte[16]
name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string

tool: {"D18": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x20,0x21,0x21,0x21,0x00]}

tool: D2: _____%d


tool: D12: %c


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[] = "hello world !!!";
  printf("_____%d\n", sizeof(buf) / sizeof(*buf));
  printf("%c\n", *buf);
  printf("%s\n", buf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x10,%esi
  movdqa D7(%rip),%xmm0
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  movsbl (%rsp),%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: byte[16]
name: disassemble_data
arguments: data_tag: D13
datatype: string
name: disassemble_data
arguments: data_tag: D29
datatype: string

tool: {"D7": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x20,0x21,0x21,0x21,0x00]}

tool: D13: _____%d


tool: D29: %c


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[] = "hello world !!!";
  printf("_____%d\n", sizeof(buf) / sizeof(*buf));
  printf("%c\n", *buf);
  printf("%s\n", buf);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x68746150,-0xc5(%rbp)
  movb   $0x0,-0xc1(%rbp)
  movabs $0x66752f656d6f682f,%rax
  movabs $0x6c697a6f6d2e2f6f,%rdx
  mov    %rax,-0xc0(%rbp)
  mov    %rdx,-0xb8(%rbp)
  movabs $0x66657269662f616c,%rax
  movabs $0x69666f72702f786f,%rdx
  mov    %rax,-0xb0(%rbp)
  mov    %rdx,-0xa8(%rbp)
  movabs $0x696e692e73656c,%rax
  mov    %rax,-0xa0(%rbp)
  lea    -0x90(%rbp),%rdx
  lea    -0xc5(%rbp),%rcx
  lea    -0xc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_conf_value@plt>
  mov    %eax,-0xcc(%rbp)
  cmpl   $0x0,-0xcc(%rbp)
  jne    L16
  lea    -0x90(%rbp),%rdx
  lea    -0xc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  mov    -0xcc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D7: get pathname_key's value from profile:%s is %s


assistant: ```c
int main() {
  char getva[128] = {0};
  char pathname_key[] = "Path";
  char profilename[] = "/home/ufo/.mozilla/firefox/profiles.ini";
  int ret = get_conf_value(profilename, pathname_key, getva);
  if (ret == 0)
    printf("get pathname_key's value from profile:%s is %s\n", profilename, getva);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movl   $0x68746150,0xb(%rsp)
  movb   $0x0,0xf(%rsp)
  movabs $0x66752f656d6f682f,%rax
  movabs $0x6c697a6f6d2e2f6f,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x66657269662f616c,%rax
  movabs $0x69666f72702f786f,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x696e692e73656c,%rax
  mov    %rax,0x30(%rsp)
  lea    0x40(%rsp),%rdx
  lea    0xb(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <get_conf_value@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L8
L26:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %ebx,%eax
  add    $0xd0,%rsp
  pop    %rbx
  ret
L8:
  lea    0x40(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: get pathname_key's value from profile:%s is %s


assistant: ```c
int main() {
  char getva[128] = {0};
  char pathname_key[] = "Path";
  char profilename[] = "/home/ufo/.mozilla/firefox/profiles.ini";
  int ret = get_conf_value(profilename, pathname_key, getva);
  if (ret == 0)
    printf("get pathname_key's value from profile:%s is %s\n", profilename, getva);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x40(%rsp)
  lea    0x40(%rsp),%r13
  lea    0x10(%rsp),%rbp
  movaps %xmm0,0x50(%rsp)
  lea    0xb(%rsp),%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  movaps %xmm0,0x60(%rsp)
  movabs $0x696e692e73656c,%rax
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movdqa D17(%rip),%xmm0
  movl   $0x68746150,0xb(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D5(%rip),%xmm0
  movb   $0x0,0xf(%rsp)
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <get_conf_value@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L15
L13:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0xd0,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
data_type: byte[16]
name: parse_data
arguments: tag: D5
data_type: byte[16]
name: parse_data
arguments: tag: D28
data_type: string

tool: {"D17": [0x2f,0x68,0x6f,0x6d,0x65,0x2f,0x75,0x66,0x6f,0x2f,0x2e,0x6d,0x6f,0x7a,0x69,0x6c]}

tool: {"D5": [0x6c,0x61,0x2f,0x66,0x69,0x72,0x65,0x66,0x6f,0x78,0x2f,0x70,0x72,0x6f,0x66,0x69]}

tool: D28: get pathname_key's value from profile:%s is %s


assistant: ```c
int main() {
  char getva[128] = {0};
  char pathname_key[] = "Path";
  char profilename[] = "/home/ufo/.mozilla/firefox/profiles.ini";
  int ret = get_conf_value(profilename, pathname_key, getva);
  if (ret == 0)
    printf("get pathname_key's value from profile:%s is %s\n", profilename, getva);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x40(%rsp)
  lea    0x40(%rsp),%r13
  lea    0x10(%rsp),%rbp
  movaps %xmm0,0x50(%rsp)
  lea    0xb(%rsp),%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  movaps %xmm0,0x60(%rsp)
  movabs $0x696e692e73656c,%rax
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movdqa D24(%rip),%xmm0
  movl   $0x68746150,0xb(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D2(%rip),%xmm0
  movb   $0x0,0xf(%rsp)
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <get_conf_value@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L9
L0:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xd0,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
data_type: byte[16]
name: retrieve_data
arguments: tag: D2
data_type: byte[16]
name: retrieve_data
arguments: tag: D19
data_type: string

tool: {"D24": [0x2f,0x68,0x6f,0x6d,0x65,0x2f,0x75,0x66,0x6f,0x2f,0x2e,0x6d,0x6f,0x7a,0x69,0x6c]}

tool: {"D2": [0x6c,0x61,0x2f,0x66,0x69,0x72,0x65,0x66,0x6f,0x78,0x2f,0x70,0x72,0x6f,0x66,0x69]}

tool: D19: get pathname_key's value from profile:%s is %s


assistant: ```c
int main() {
  char getva[128] = {0};
  char pathname_key[] = "Path";
  char profilename[] = "/home/ufo/.mozilla/firefox/profiles.ini";
  int ret = get_conf_value(profilename, pathname_key, getva);
  if (ret == 0)
    printf("get pathname_key's value from profile:%s is %s\n", profilename, getva);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glmSubtractVector2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void glmSubtractVector2d(double result[2], const double v1[2], const double v2[2]) {
  result[0] = v1[0] - v2[0];
  result[1] = v1[1] - v2[1];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<glmSubtractVector2d>:
  endbr64
  movsd  (%rsi),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  subsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void glmSubtractVector2d(double result[2], const double v1[2], const double v2[2]) {
  result[0] = v1[0] - v2[0];
  result[1] = v1[1] - v2[1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<glmSubtractVector2d>:
  endbr64
  movsd  (%rsi),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  subsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void glmSubtractVector2d(double result[2], const double v1[2], const double v2[2]) {
  result[0] = v1[0] - v2[0];
  result[1] = v1[1] - v2[1];
}
```