ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<seek_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  xor    %ebx,%ebx
  mov    %rsi,0x8(%rsp)
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  lea    0x10(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x2018(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r14d
  call   <ftell@plt>
  mov    %eax,%r12d
  jmp    L44
  nopl   0x0(%rax)
L12:
  mov    %rbp,%rcx
  mov    $0x2000,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jle    L20
  mov    %r14d,%ecx
  movslq %ebx,%rdx
  mov    %eax,%esi
  add    0x8(%rsp),%rdx
  sub    %ebx,%ecx
  mov    %r13,%rdi
  call   <find_partial@plt>
  cmp    $0xffffffff,%eax
  je     L37
  mov    %r15d,%edx
  sub    %eax,%edx
  add    %ebx,%edx
  cmp    %r14d,%edx
  jge    L47
  mov    %edx,%ebx
L37:
  add    %r15d,%r12d
L44:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L12
L20:
  xor    %eax,%eax
L28:
  mov    0x2018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x2028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L47:
  lea    (%r12,%rax,1),%esi
  mov    D2(%rip),%rax
  mov    %rbp,%rdi
  sub    %ebx,%esi
  mov    (%rax),%edx
  lea    (%rsi,%r14,1),%esi
  call   <fseek@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L28
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int seek_string(FILE *fp, const char *str) {
  char block[8192];
  int str_at;
  int str_len;
  int size;
  int ret;
  int pos;
  str_len = strlen(str);
  str_at = 0;
  pos = ftell(fp);
  while (!feof(fp)) {
    size = fread(block, 1, 8192, fp);
    if (size < 1)
      break;
    ret = find_partial(block, size, str + str_at, str_len - str_at);
    if (ret != -1) {
      if (str_at + (size - ret) >= str_len) {
        if (fseek(fp, pos + ret - str_at + str_len, SEEK_SET) != 0)
          return 0;
        return 1;
      } else
        str_at += (size - ret);
    }
    pos += size;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D51(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D40(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x3,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <ldexp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  -0x8(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D26
type_guessed: f64
name: unpack_data
arguments: tag: D51
type_guessed: f64
name: unpack_data
arguments: tag: D40
type_guessed: f64
name: unpack_data
arguments: tag: D48
type_guessed: string
name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D23
type_guessed: string

tool: D26: 2

tool: D51: 8.6872

tool: D40: 100

tool: D48: The ldexp value is:%lf


tool: D6: The natural log of %lf is %lf


tool: D23: The common log of %lf is %lf


assistant: ```c
main() {
  double value, value1, value2;
  double x = 2, x1 = 8.6872, x2 = 100.00;
  int exponent = 3;
  value = ldexp(x, exponent);
  value1 = log(x1);
  value2 = log10(x2);
  printf("The ldexp value is:%lf\n", value);
  printf("The natural log of %lf is %lf\n", x1, value1);
  printf("The common log of %lf is %lf\n", x2, value2);
  getch();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D25(%rip),%xmm0
  lea    D46(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  D75(%rip),%xmm1
  movsd  D7(%rip),%xmm0
  lea    D2(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  D64(%rip),%xmm1
  movsd  D8(%rip),%xmm0
  lea    D34(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D25
datatype: byte[8]
name: unpack_data
arguments: data_label: D46
datatype: string
name: unpack_data
arguments: data_label: D75
datatype: byte[8]
name: unpack_data
arguments: data_label: D7
datatype: f64
name: unpack_data
arguments: data_label: D2
datatype: string
name: unpack_data
arguments: data_label: D64
datatype: f64
name: unpack_data
arguments: data_label: D8
datatype: f64
name: unpack_data
arguments: data_label: D34
datatype: string

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x40]}

tool: D46: The ldexp value is:%lf


tool: {"D75": [0x9e,0x08,0x44,0x5e,0x78,0x4b,0x01,0x40]}

tool: D7: 8.6872

tool: D2: The natural log of %lf is %lf


tool: D64: 2

tool: D8: 100

tool: D34: The common log of %lf is %lf


assistant: ```c
main() {
  double value, value1, value2;
  double x = 2, x1 = 8.6872, x2 = 100.00;
  int exponent = 3;
  value = ldexp(x, exponent);
  value1 = log(x1);
  value2 = log10(x2);
  printf("The ldexp value is:%lf\n", value);
  printf("The natural log of %lf is %lf\n", x1, value1);
  printf("The common log of %lf is %lf\n", x2, value2);
  getch();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  mov    $0x1,%eax
  movsd  D12(%rip),%xmm0
  call   <printf@plt>
  movsd  D59(%rip),%xmm1
  mov    $0x2,%eax
  movsd  D6(%rip),%xmm0
  lea    D62(%rip),%rdi
  call   <printf@plt>
  movsd  D79(%rip),%xmm1
  mov    $0x2,%eax
  movsd  D1(%rip),%xmm0
  lea    D33(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D12
type: byte[8]
name: parse_data
arguments: label: D59
type: byte[8]
name: parse_data
arguments: label: D6
type: f64
name: parse_data
arguments: label: D62
type: string
name: parse_data
arguments: label: D79
type: f64
name: parse_data
arguments: label: D1
type: f64
name: parse_data
arguments: label: D33
type: string

tool: D0: The ldexp value is:%lf


tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x40]}

tool: {"D59": [0x9e,0x08,0x44,0x5e,0x78,0x4b,0x01,0x40]}

tool: D6: 8.6872

tool: D62: The natural log of %lf is %lf


tool: D79: 2

tool: D1: 100

tool: D33: The common log of %lf is %lf


assistant: ```c
main() {
  double value, value1, value2;
  double x = 2, x1 = 8.6872, x2 = 100.00;
  int exponent = 3;
  value = ldexp(x, exponent);
  value1 = log(x1);
  value2 = log10(x2);
  printf("The ldexp value is:%lf\n", value);
  printf("The natural log of %lf is %lf\n", x1, value1);
  printf("The common log of %lf is %lf\n", x2, value2);
  getch();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  movsd  D19(%rip),%xmm0
  call   <printf@plt>
  movsd  D33(%rip),%xmm1
  mov    $0x2,%eax
  movsd  D68(%rip),%xmm0
  lea    D63(%rip),%rdi
  call   <printf@plt>
  movsd  D3(%rip),%xmm1
  mov    $0x2,%eax
  movsd  D2(%rip),%xmm0
  lea    D74(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D36
type_guessed: string
name: retrieve_data
arguments: data_label: D19
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D33
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D68
type_guessed: f64
name: retrieve_data
arguments: data_label: D63
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: f64
name: retrieve_data
arguments: data_label: D2
type_guessed: f64
name: retrieve_data
arguments: data_label: D74
type_guessed: string

tool: D36: The ldexp value is:%lf


tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x40]}

tool: {"D33": [0x9e,0x08,0x44,0x5e,0x78,0x4b,0x01,0x40]}

tool: D68: 8.6872

tool: D63: The natural log of %lf is %lf


tool: D3: 2

tool: D2: 100

tool: D74: The common log of %lf is %lf


assistant: ```c
main() {
  double value, value1, value2;
  double x = 2, x1 = 8.6872, x2 = 100.00;
  int exponent = 3;
  value = ldexp(x, exponent);
  value1 = log(x1);
  value2 = log10(x2);
  printf("The ldexp value is:%lf\n", value);
  printf("The natural log of %lf is %lf\n", x1, value1);
  printf("The common log of %lf is %lf\n", x2, value2);
  getch();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_skip_spaces@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  mov    -0x18(%rbp),%rax
  jmp    L40
L31:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L2
L41:
  subq   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L29
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
L29:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L40:
  leave
  ret
```

assistant: ```c
char *str_trim(char *s) {
  size_t size;
  char *end;
  s = str_skip_spaces(s);
  size = strlen(s);
  if (!size)
    return s;
  end = s + size - 1;
  while (end >= s && isspace(*end))
    end--;
  *(end + 1) = '\0';
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <str_skip_spaces@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L27
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  ja     L8
L37:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L8
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jbe    L37
L8:
  movb   $0x0,0x1(%rbx)
L27:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *str_trim(char *s) {
  size_t size;
  char *end;
  s = str_skip_spaces(s);
  size = strlen(s);
  if (!size)
    return s;
  end = s + size - 1;
  while (end >= s && isspace(*end))
    end--;
  *(end + 1) = '\0';
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_trim>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  call   <str_skip_spaces@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  test   %rax,%rax
  je     L0
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jbe    L31
  jmp    L13
  nopl   0x0(%rax)
L3:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  ja     L13
L31:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
L13:
  movb   $0x0,0x1(%rbx)
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *str_trim(char *s) {
  size_t size;
  char *end;
  s = str_skip_spaces(s);
  size = strlen(s);
  if (!size)
    return s;
  end = s + size - 1;
  while (end >= s && isspace(*end))
    end--;
  *(end + 1) = '\0';
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_trim>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  call   <str_skip_spaces@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  test   %rax,%rax
  je     L1
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jbe    L16
  jmp    L27
  nopl   0x0(%rax)
L48:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  ja     L27
L16:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
L27:
  movb   $0x0,0x1(%rbx)
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *str_trim(char *s) {
  size_t size;
  char *end;
  s = str_skip_spaces(s);
  size = strlen(s);
  if (!size)
    return s;
  end = s + size - 1;
  while (end >= s && isspace(*end))
    end--;
  *(end + 1) = '\0';
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <verify_empty_object@plt>
  mov    $0x0,%eax
  call   <verify_one_string@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  verify_empty_object();
  verify_one_string();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <verify_empty_object@plt>
  mov    $0x0,%eax
  call   <verify_one_string@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  verify_empty_object();
  verify_one_string();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <verify_empty_object@plt>
  xor    %eax,%eax
  call   <verify_one_string@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  verify_empty_object();
  verify_one_string();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <verify_empty_object@plt>
  xor    %eax,%eax
  call   <verify_one_string@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  verify_empty_object();
  verify_one_string();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<house>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <house_1@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double house(double *x, int N, double *v) {
  double beta;
  beta = house_1(x, N, v);
  return beta;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<house>:
  endbr64
  sub    $0x8,%rsp
  call   <house_1@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double house(double *x, int N, double *v) {
  double beta;
  beta = house_1(x, N, v);
  return beta;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<house>:
  endbr64
  jmp    1050 <house_1@plt>
```

assistant: ```c
double house(double *x, int N, double *v) {
  double beta;
  beta = house_1(x, N, v);
  return beta;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<house>:
  endbr64
  jmp    1050 <house_1@plt>
```

assistant: ```c
double house(double *x, int N, double *v) {
  double beta;
  beta = house_1(x, N, v);
  return beta;
}
```
user: What is the c source code of the assembly code below?

```asm
<i2c_write_beuint08_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  imul   -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  mov    %edx,(%rax)
  movl   $0x0,-0x18(%rbp)
  jmp    L17
L0:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  imul   -0x14(%rbp),%edx
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <__wbeu08@plt>
  addl   $0x1,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x40(%rbp)
  ja     L0
  mov    -0x14(%rbp),%eax
  cltq
  imul   -0x40(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <i2c_transact@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int i2c_write_beuint08_array(int fd, int chip_addr, int reg, uint8_t *values, size_t count) {
  int sz = sizeof(uint8_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  for (int i = 0; i < count; i++)
    __wbeu08(&data[1 + i * sz], (uint8_t)values[i]);
  return i2c_transact(fd, chip_addr, data, count * sz + 1, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<i2c_write_beuint08_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x4c(%rbp)
  mov    %esi,-0x50(%rbp)
  mov    %edx,%ebx
  mov    %rcx,%r14
  mov    %r8,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x1(,%r8,4),%rax
  mov    %rax,-0x48(%rbp)
  mov    %rax,%rdi
  call   <alloca@plt>
  mov    %rax,%r15
  mov    %ebx,(%rax)
  test   %r13,%r13
  je     L14
  lea    0x4(%rax),%r12
  mov    $0x0,%ebx
L27:
  mov    (%r14,%rbx,4),%esi
  mov    %r12,%rdi
  call   <__wbeu08@plt>
  add    $0x1,%rbx
  add    $0x10,%r12
  cmp    %r13,%rbx
  jne    L27
L14:
  mov    $0x0,%r8d
  mov    -0x48(%rbp),%rcx
  mov    %r15,%rdx
  mov    -0x50(%rbp),%esi
  mov    -0x4c(%rbp),%edi
  call   <i2c_transact@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_beuint08_array(int fd, int chip_addr, int reg, uint8_t *values, size_t count) {
  int sz = sizeof(uint8_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  for (int i = 0; i < count; i++)
    __wbeu08(&data[1 + i * sz], (uint8_t)values[i]);
  return i2c_transact(fd, chip_addr, data, count * sz + 1, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<i2c_write_beuint08_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %r8,%rbx
  sub    $0x28,%rsp
  mov    %edi,-0x4c(%rbp)
  mov    %esi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x1(,%r8,4),%rax
  mov    %rax,%rdi
  mov    %rax,-0x48(%rbp)
  call   <alloca@plt>
  mov    %r14d,(%rax)
  mov    %rax,%r13
  test   %rbx,%rbx
  je     L8
  lea    0x4(%rax),%r15
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L4:
  mov    (%r12,%r14,4),%esi
  mov    %r15,%rdi
  add    $0x1,%r14
  add    $0x10,%r15
  call   <__wbeu08@plt>
  cmp    %r14,%rbx
  jne    L4
L8:
  mov    -0x48(%rbp),%rcx
  mov    -0x50(%rbp),%esi
  xor    %r8d,%r8d
  mov    %r13,%rdx
  mov    -0x4c(%rbp),%edi
  call   <i2c_transact@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_beuint08_array(int fd, int chip_addr, int reg, uint8_t *values, size_t count) {
  int sz = sizeof(uint8_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  for (int i = 0; i < count; i++)
    __wbeu08(&data[1 + i * sz], (uint8_t)values[i]);
  return i2c_transact(fd, chip_addr, data, count * sz + 1, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i2c_write_beuint08_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %r8,%rbx
  sub    $0x28,%rsp
  mov    %edi,-0x4c(%rbp)
  mov    %esi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x1(,%r8,4),%rax
  mov    %rax,%rdi
  mov    %rax,-0x48(%rbp)
  call   <alloca@plt>
  mov    %r14d,(%rax)
  mov    %rax,%r13
  test   %rbx,%rbx
  je     L6
  lea    0x4(%rax),%r15
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L27:
  mov    (%r12,%r14,4),%esi
  mov    %r15,%rdi
  add    $0x1,%r14
  add    $0x10,%r15
  call   <__wbeu08@plt>
  cmp    %r14,%rbx
  jne    L27
L6:
  mov    -0x48(%rbp),%rcx
  mov    -0x50(%rbp),%esi
  xor    %r8d,%r8d
  mov    %r13,%rdx
  mov    -0x4c(%rbp),%edi
  call   <i2c_transact@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_beuint08_array(int fd, int chip_addr, int reg, uint8_t *values, size_t count) {
  int sz = sizeof(uint8_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  for (int i = 0; i < count; i++)
    __wbeu08(&data[1 + i * sz], (uint8_t)values[i]);
  return i2c_transact(fd, chip_addr, data, count * sz + 1, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<invert_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edx,%rax
  shl    $0x2,%rax
  mov    %rax,-0x50(%rbp)
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L36:
  cmp    %rdx,%rsp
  je     L89
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L89:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L30
  orq    $0x0,-0x8(%rsp,%rax,1)
L30:
  mov    %rsp,-0x48(%rbp)
  lea    0x0(,%r12,4),%eax
  mov    %eax,-0x54(%rbp)
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <get_identity_matrix@plt>
  test   %r12d,%r12d
  jle    L64
  mov    %r14,%r13
  mov    $0x0,%ebx
  jmp    L25
L55:
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <normalize_pivot_row@plt>
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <eliminate_by_row@plt>
  add    $0x1,%ebx
  add    -0x50(%rbp),%r13
  cmp    %ebx,%r12d
  je     L64
L25:
  mov    -0x54(%rbp),%edx
  mov    %r13,%rsi
  mov    -0x48(%rbp),%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    -0x48(%rbp),%rdi
  call   <get_pivot_index@plt>
  cmp    %ebx,%eax
  je     L55
  mov    %r12d,%r8d
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <switch_columns@plt>
  jmp    L55
L64:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L83:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void invert_matrix(uint8_t *matrix, uint8_t *result, int size) {
  int row;
  int pivotIndex;
  uint8_t currentRow[size];
  int currentRowSize = size * sizeof(uint8_t);
  get_identity_matrix(result, size);
  for (row = 0; row < size; row++) {
    int index = row;
    memcpy(&currentRow, matrix + row * size, currentRowSize);
    pivotIndex = get_pivot_index(currentRow, index, size);
    if (pivotIndex != row) {
      switch_columns(matrix, result, index, pivotIndex, size);
    }
    normalize_pivot_row(matrix, result, index, size);
    eliminate_by_row(matrix, result, row, size);
  }
}
```