ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<char_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L49
  cmpb   $0x39,-0x4(%rbp)
  jg     L49
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L3
L49:
  cmpb   $0x60,-0x4(%rbp)
  jle    L58
  cmpb   $0x66,-0x4(%rbp)
  jg     L58
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L3
L58:
  cmpb   $0x40,-0x4(%rbp)
  jle    L31
  cmpb   $0x46,-0x4(%rbp)
  jg     L31
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L3
L31:
  mov    $0xffffffff,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int char_value(char c) {
  if (c >= '0' && c <= '9')
    return c - '0';
  else if (c >= 'a' && c <= 'f')
    return c - 'a' + 10;
  else if (c >= 'A' && c <= 'F')
    return c - 'A' + 10;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<char_value>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L28
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L23
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  ja     L12
  movsbl %dil,%edi
  lea    -0x37(%rdi),%eax
  ret
L28:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L23:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
L12:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int char_value(char c) {
  if (c >= '0' && c <= '9')
    return c - '0';
  else if (c >= 'a' && c <= 'f')
    return c - 'a' + 10;
  else if (c >= 'A' && c <= 'F')
    return c - 'A' + 10;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<char_value>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L24
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L25
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  ja     L5
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax)
L25:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
L24:
  movsbl %al,%eax
  ret
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int char_value(char c) {
  if (c >= '0' && c <= '9')
    return c - '0';
  else if (c >= 'a' && c <= 'f')
    return c - 'a' + 10;
  else if (c >= 'A' && c <= 'F')
    return c - 'A' + 10;
  else
    return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<char_value>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L8
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L12
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  ja     L10
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax)
L12:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
L8:
  movsbl %al,%eax
  ret
L10:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int char_value(char c) {
  if (c >= '0' && c <= '9')
    return c - '0';
  else if (c >= 'a' && c <= 'f')
    return c - 'a' + 10;
  else if (c >= 'A' && c <= 'F')
    return c - 'A' + 10;
  else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dec_to_bin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    $0x0,%r14d
  cmpb   $0x5f,(%rsi)
  je     L50
L149:
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    0x1(%r13),%r12
  lea    0x7f(%rbx),%rbp
  movzbl 0x0(%r13),%eax
  sub    $0x30,%eax
  mov    %al,0x7f(%rbx)
  movzbl 0x1(%r13),%eax
  sub    $0x30,%eax
  lea    -0x1(%rbx),%rsi
  cmp    $0x9,%al
  ja     L43
L20:
  mov    %rbp,%rdx
L74:
  movzbl (%rdx),%ecx
  lea    (%rcx,%rcx,4),%ecx
  movzbl %al,%eax
  lea    (%rax,%rcx,2),%eax
  mov    %al,(%rdx)
  cltq
  movzbl %ah,%eax
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L74
  add    $0x1,%r12
  movzbl (%r12),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L20
L43:
  test   %r14b,%r14b
  je     L88
  lea    0x80(%rbx),%rdx
  mov    %rbx,%rax
L2:
  notb   (%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L2
  movzbl 0x7f(%rbx),%eax
  add    $0x1,%eax
  mov    %al,0x7f(%rbx)
  test   %al,%al
  jne    L88
  mov    %rbp,%rax
L107:
  sub    $0x1,%rax
  movzbl (%rax),%edi
  lea    0x1(%rdi),%edx
  mov    %dl,(%rax)
  test   %dl,%dl
  jne    L37
  cmp    %rax,%rbx
  jb     L107
L37:
  movzbl (%rbx),%eax
  jmp    L68
L50:
  add    $0x1,%r13
  mov    $0x5f,%r14d
  jmp    L149
L88:
  movzbl (%rbx),%eax
L68:
  mov    %rbx,%r13
L133:
  add    $0x1,%r13
  cmp    %al,0x0(%r13)
  jne    L99
  cmp    %r13,%rbp
  ja     L133
L99:
  cmp    %r13,%rbp
  jb     L31
L45:
  add    $0x1,%r13
  movzbl -0x1(%r13),%esi
  mov    %rbx,%rdi
  call   <putoct@plt>
  cltq
  add    %rax,%rbx
  cmp    %r13,%rbp
  jae    L45
L31:
  movb   $0x0,(%rbx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *dec_to_bin(unsigned char *to, char *from) {
  unsigned char *b, carryc, minus, *ebuf;
  long prod;
  if ((minus = *from) == '_')
    from++;
  else
    minus = 0;
  memset(to, 0, 128);
  for (*(ebuf = &to[128 - 1]) = *from++ - '0'; *from >= '0' && *from <= '9'; from++) {
    for (carryc = *from - '0', b = ebuf; b >= to; b--) {
      prod = (*b * 10) + carryc;
      *b = (prod & 0xFF);
      carryc = (unsigned char)(prod >> 8);
    }
  }
  if (minus) {
    for (b = to; b <= ebuf; *b = ~*b, b++)
      ;
    for (b = ebuf, (*b)++; !*b && b > to; b--, (*b)++)
      ;
  }
  for (b = to; *b == *to && b < ebuf; b++)
    ;
  while (b <= ebuf)
    to += putoct((char *)to, (long)*b++);
  *to = 0;
  return from;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dec_to_bin>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  cmpb   $0x5f,(%rsi)
  mov    %rdi,%rbx
  jne    L129
  add    $0x1,%r14
  mov    $0x5f,%r12d
L129:
  mov    $0x80,%edx
  xor    %esi,%esi
  lea    0x1(%r14),%r13
  mov    %rbx,%rdi
  call   <memset@plt>
  movzbl (%r14),%eax
  lea    0x7f(%rbx),%rbp
  lea    -0x1(%rbx),%rsi
  lea    -0x30(%rax),%edx
  mov    %dl,0x7f(%rbx)
  movzbl 0x1(%r14),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L81
L103:
  mov    %rbp,%rcx
  jmp    L136
  nopw   0x0(%rax,%rax,1)
L56:
  movzbl (%rcx),%edx
L136:
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    $0x1,%rcx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%eax
  mov    %al,0x1(%rcx)
  cltq
  movzbl %ah,%eax
  cmp    %rsi,%rcx
  jne    L56
  movzbl 0x1(%r13),%eax
  add    $0x1,%r13
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L81
  movzbl 0x7f(%rbx),%edx
  jmp    L103
L81:
  test   %r12b,%r12b
  je     L157
  lea    0x80(%rbx),%rdx
  mov    %rbx,%rax
  nopl   (%rax)
L159:
  notb   (%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L159
  addb   $0x1,0x7f(%rbx)
  jne    L157
  mov    %rbp,%rax
  jmp    L53
  xchg   %ax,%ax
L7:
  cmp    %rax,%rbx
  jae    L157
L53:
  sub    $0x1,%rax
  addb   $0x1,(%rax)
  je     L7
L157:
  movzbl (%rbx),%edx
  mov    %rbx,%r12
  jmp    L100
  cs nopw 0x0(%rax,%rax,1)
L11:
  cmp    %r12,%rbp
  jbe    L105
L100:
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  cmp    %dl,%al
  je     L11
L105:
  cmp    %r12,%rbp
  jae    L25
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L172:
  movzbl (%r12),%eax
L25:
  mov    %rbx,%rdi
  movzbl %al,%esi
  add    $0x1,%r12
  call   <putoct@plt>
  cltq
  add    %rax,%rbx
  cmp    %r12,%rbp
  jae    L172
L22:
  mov    %r13,%rax
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *dec_to_bin(unsigned char *to, char *from) {
  unsigned char *b, carryc, minus, *ebuf;
  long prod;
  if ((minus = *from) == '_')
    from++;
  else
    minus = 0;
  memset(to, 0, 128);
  for (*(ebuf = &to[128 - 1]) = *from++ - '0'; *from >= '0' && *from <= '9'; from++) {
    for (carryc = *from - '0', b = ebuf; b >= to; b--) {
      prod = (*b * 10) + carryc;
      *b = (prod & 0xFF);
      carryc = (unsigned char)(prod >> 8);
    }
  }
  if (minus) {
    for (b = to; b <= ebuf; *b = ~*b, b++)
      ;
    for (b = ebuf, (*b)++; !*b && b > to; b--, (*b)++)
      ;
  }
  for (b = to; *b == *to && b < ebuf; b++)
    ;
  while (b <= ebuf)
    to += putoct((char *)to, (long)*b++);
  *to = 0;
  return from;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dec_to_bin>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  cmpb   $0x5f,(%rsi)
  jne    L85
  add    $0x1,%r14
  mov    $0x5f,%r12d
L85:
  xor    %esi,%esi
  mov    $0x80,%edx
  lea    0x1(%r14),%r13
  mov    %rbx,%rdi
  call   <memset@plt>
  movzbl (%r14),%eax
  lea    0x7f(%rbx),%rbp
  lea    -0x1(%rbx),%rsi
  sub    $0x30,%eax
  mov    %al,0x7f(%rbx)
  movzbl 0x1(%r14),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L0
L111:
  mov    %rbp,%rdx
  nopl   0x0(%rax)
L105:
  movzbl (%rdx),%ecx
  movzbl %al,%eax
  sub    $0x1,%rdx
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rax,%rcx,2),%eax
  mov    %al,0x1(%rdx)
  cltq
  movzbl %ah,%eax
  cmp    %rsi,%rdx
  jne    L105
  movzbl 0x1(%r13),%eax
  add    $0x1,%r13
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L111
L0:
  test   %r12b,%r12b
  je     L22
  movdqu (%rbx),%xmm1
  pcmpeqd %xmm0,%xmm0
  movdqu 0x70(%rbx),%xmm2
  pxor   %xmm0,%xmm1
  movups %xmm1,(%rbx)
  movdqu 0x10(%rbx),%xmm1
  pxor   %xmm0,%xmm1
  movups %xmm1,0x10(%rbx)
  movdqu 0x20(%rbx),%xmm1
  pxor   %xmm0,%xmm1
  movups %xmm1,0x20(%rbx)
  movdqu 0x30(%rbx),%xmm1
  pxor   %xmm0,%xmm1
  movups %xmm1,0x30(%rbx)
  movdqu 0x40(%rbx),%xmm1
  pxor   %xmm0,%xmm1
  movups %xmm1,0x40(%rbx)
  movdqu 0x50(%rbx),%xmm1
  pxor   %xmm0,%xmm1
  movups %xmm1,0x50(%rbx)
  movdqu 0x60(%rbx),%xmm1
  pxor   %xmm0,%xmm1
  pxor   %xmm2,%xmm0
  movaps %xmm0,(%rsp)
  movzbl 0xf(%rsp),%eax
  movups %xmm0,0x70(%rbx)
  add    $0x1,%eax
  movups %xmm1,0x60(%rbx)
  mov    %al,0x7f(%rbx)
  test   %al,%al
  jne    L22
  mov    %rbp,%rax
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L98:
  cmp    %rax,%rbx
  jae    L22
L38:
  sub    $0x1,%rax
  addb   $0x1,(%rax)
  je     L98
L22:
  movzbl (%rbx),%eax
  mov    %rbx,%r12
  jmp    L88
  cs nopw 0x0(%rax,%rax,1)
L54:
  cmp    %r12,%rbp
  jbe    L90
L88:
  add    $0x1,%r12
  cmp    %al,(%r12)
  je     L54
  cmp    %r12,%rbp
  jb     L30
L76:
  movzbl (%r12),%esi
  mov    %rbx,%rdi
  add    $0x1,%r12
  call   <putoct@plt>
  cltq
  add    %rax,%rbx
L90:
  cmp    %r12,%rbp
  jae    L76
L30:
  movb   $0x0,(%rbx)
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *dec_to_bin(unsigned char *to, char *from) {
  unsigned char *b, carryc, minus, *ebuf;
  long prod;
  if ((minus = *from) == '_')
    from++;
  else
    minus = 0;
  memset(to, 0, 128);
  for (*(ebuf = &to[128 - 1]) = *from++ - '0'; *from >= '0' && *from <= '9'; from++) {
    for (carryc = *from - '0', b = ebuf; b >= to; b--) {
      prod = (*b * 10) + carryc;
      *b = (prod & 0xFF);
      carryc = (unsigned char)(prod >> 8);
    }
  }
  if (minus) {
    for (b = to; b <= ebuf; *b = ~*b, b++)
      ;
    for (b = ebuf, (*b)++; !*b && b > to; b--, (*b)++)
      ;
  }
  for (b = to; *b == *to && b < ebuf; b++)
    ;
  while (b <= ebuf)
    to += putoct((char *)to, (long)*b++);
  *to = 0;
  return from;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: %i 

assistant: ```c
int write_arr(FILE *f, int *arr, int size) {
  for (int i = 0; i < size; i++) {
    fprintf(f, "%i ", arr[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_arr>:
  endbr64
  test   %edx,%edx
  jle    L2
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x4(%rsi,%rax,4),%r13
  lea    D7(%rip),%r12
L19:
  mov    (%rbx),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L19
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: %i 

assistant: ```c
int write_arr(FILE *f, int *arr, int size) {
  for (int i = 0; i < size; i++) {
    fprintf(f, "%i ", arr[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_arr>:
  endbr64
  test   %edx,%edx
  jle    L13
  push   %r13
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r13
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <fprintf@plt>
  cmp    %r13,%rbx
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: %i 

assistant: ```c
int write_arr(FILE *f, int *arr, int size) {
  for (int i = 0; i < size; i++) {
    fprintf(f, "%i ", arr[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<write_arr>:
  endbr64
  test   %edx,%edx
  jle    L5
  push   %r13
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r13
  lea    D5(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <fprintf@plt>
  cmp    %r13,%rbx
  jne    L18
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: %i 

assistant: ```c
int write_arr(FILE *f, int *arr, int size) {
  for (int i = 0; i < size; i++) {
    fprintf(f, "%i ", arr[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L19
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strlwr(char *string) {
  int c;
  while ((c = *string) != 0) {
    *string++ = tolower(c);
  }
  return (string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlwr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %edi,%edi
  je     L2
L12:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %edi,%edi
  jne    L12
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *strlwr(char *string) {
  int c;
  while ((c = *string) != 0) {
    *string++ = tolower(c);
  }
  return (string);
}
```
user: What is the c source code of the assembly code below:

```asm
<strlwr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %edi,%edi
  je     L1
L12:
  call   <tolower@plt>
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
  test   %edi,%edi
  jne    L12
L1:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *string) {
  int c;
  while ((c = *string) != 0) {
    *string++ = tolower(c);
  }
  return (string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlwr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %edi,%edi
  je     L6
L11:
  call   <tolower@plt>
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
  test   %edi,%edi
  jne    L11
L6:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *string) {
  int c;
  while ((c = *string) != 0) {
    *string++ = tolower(c);
  }
  return (string);
}
```
user: What is the c source code of the assembly code below:

```asm
<binomial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L13
L18:
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jbe    L18
  movl   $0x1,-0xc(%rbp)
  jmp    L24
L10:
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jbe    L10
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long binomial(unsigned int n, unsigned int k) {
  long result = 1;
  for (unsigned int i = 1; i <= k; i++)
    result *= (n + 1 - i);
  for (unsigned int i = 1; i <= k; i++)
    result /= i;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<binomial>:
  endbr64
  test   %esi,%esi
  je     L27
  mov    $0x1,%edx
  mov    $0x1,%eax
  add    $0x1,%edi
L10:
  mov    %edi,%ecx
  sub    %edx,%ecx
  imul   %rcx,%rax
  add    $0x1,%edx
  cmp    %edx,%esi
  jae    L10
  lea    -0x1(%rsi),%esi
  add    $0x2,%rsi
  mov    $0x1,%ecx
L5:
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L5
  ret
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long binomial(unsigned int n, unsigned int k) {
  long result = 1;
  for (unsigned int i = 1; i <= k; i++)
    result *= (n + 1 - i);
  for (unsigned int i = 1; i <= k; i++)
    result /= i;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<binomial>:
  endbr64
  test   %esi,%esi
  je     L19
  add    $0x1,%edi
  mov    $0x1,%edx
  mov    $0x1,%eax
  nopl   (%rax)
L14:
  mov    %edi,%ecx
  sub    %edx,%ecx
  add    $0x1,%edx
  imul   %rcx,%rax
  cmp    %edx,%esi
  jae    L14
  sub    $0x1,%esi
  mov    $0x1,%ecx
  add    $0x2,%rsi
  nopl   0x0(%rax,%rax,1)
L27:
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L27
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long binomial(unsigned int n, unsigned int k) {
  long result = 1;
  for (unsigned int i = 1; i <= k; i++)
    result *= (n + 1 - i);
  for (unsigned int i = 1; i <= k; i++)
    result /= i;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<binomial>:
  endbr64
  test   %esi,%esi
  je     L24
  add    $0x1,%edi
  mov    $0x1,%edx
  mov    $0x1,%eax
  nopl   (%rax)
L3:
  mov    %edi,%ecx
  sub    %edx,%ecx
  add    $0x1,%edx
  imul   %rcx,%rax
  cmp    %edx,%esi
  jae    L3
  sub    $0x1,%esi
  mov    $0x1,%ecx
  add    $0x2,%rsi
  nopl   0x0(%rax,%rax,1)
L27:
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L27
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long binomial(unsigned int n, unsigned int k) {
  long result = 1;
  for (unsigned int i = 1; i <= k; i++)
    result *= (n + 1 - i);
  for (unsigned int i = 1; i <= k; i++)
    result /= i;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <system@plt>
  lea    D41(%rip),%rdi
  call   <puts@plt>
  movq   $0x0,0x8(%rsp)
  mov    $0x1,%r13d
  lea    D0(%rip),%r15
  lea    D47(%rip),%r14
L19:
  lea    0x10(%rsp),%r12
  mov    0x8(%rsp),%rax
  lea    (%r12,%rax,4),%rbp
  mov    $0x0,%ebx
L3:
  add    $0x1,%ebx
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    $0x5,%ebx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  addq   $0x5,0x8(%rsp)
  cmp    $0x6,%r13d
  jne    L19
  lea    D55(%rip),%rdi
  call   <system@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    0x64(%r12),%r13
  lea    D56(%rip),%rbp
L14:
  mov    $0x0,%ebx
L16:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x14,%r12
  cmp    %r13,%r12
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x10(%rsp),%rdi
  call   <tamKaremi@plt>
  mov    %eax,%esi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D55
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D41
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D47
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D26
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D56
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D54
type_infered: string

tool: D55: clear

tool: D41: 
Lutfen 5x5 matris elemanlarini giriniz!


tool: D0: %d satir, %d sutun elemani giriniz: 

tool: D47:  %d

tool: D26: ---Matris---


tool: D56: %d	

tool: D54: Sonuc=%d


assistant: ```c
int main() {
  system("clear");
  int i, j, sonuc;
  int dizi[5][5];
  printf("\nLutfen 5x5 matris elemanlarini giriniz!\n\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d satir, %d sutun elemani giriniz: ", i + 1, j + 1);
      scanf(" %d", &dizi[i][j]);
    }
    printf("\n");
  }
  system("clear");
  printf("---Matris---\n\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d\t", dizi[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  sonuc = tamKaremi(dizi);
  printf("Sonuc=%d\n", sonuc);
  return 0;
}
```