ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<SHT1x_CalcDewpoint>:
  endbr64
  push   %rbx
  pxor   %xmm2,%xmm2
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  comiss %xmm1,%xmm2
  ja     L9
  movss  D17(%rip),%xmm2
  movss  D37(%rip),%xmm5
L15:
  movss  %xmm1,0xc(%rsp)
  divss  D43(%rip),%xmm0
  movss  %xmm2,0x8(%rsp)
  movss  %xmm5,0x4(%rsp)
  call   <log@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  movss  0x4(%rsp),%xmm5
  movaps %xmm0,%xmm4
  movaps %xmm2,%xmm3
  subss  %xmm4,%xmm2
  mulss  %xmm1,%xmm3
  addss  %xmm5,%xmm1
  divss  %xmm1,%xmm3
  addss  %xmm3,%xmm0
  subss  %xmm3,%xmm2
  divss  %xmm2,%xmm0
  mulss  %xmm5,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  movss  D39(%rip),%xmm2
  movss  D27(%rip),%xmm5
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D37
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D43
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D39
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: f32

tool: D17: 17.62

tool: D37: 243.12

tool: D43: 100

tool: D39: 22.46

tool: D27: 272.62

assistant: ```c
void SHT1x_CalcDewpoint(float fRH, float fTemp, float *fDP) {
  float Tn = 243.12;
  float m = 17.62;
  if (fTemp < 0) {
    Tn = 272.62;
    m = 22.46;
  }
  float lnRH = log(fRH / 100);
  float mTTnT = (m * fTemp) / (Tn + fTemp);
  *fDP = Tn * ((lnRH + mTTnT) / (m - lnRH - mTTnT));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_FBLogin_Request>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <send_to_user@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: $FBLoginReq 

assistant: ```c
void send_FBLogin_Request(struct user_t *user) {
  send_to_user("$FBLoginReq ", user);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<send_FBLogin_Request>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  call   <send_to_user@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: $FBLoginReq 

assistant: ```c
void send_FBLogin_Request(struct user_t *user) {
  send_to_user("$FBLoginReq ", user);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<send_FBLogin_Request>:
  endbr64
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  jmp    1050 <send_to_user@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D0: $FBLoginReq 

assistant: ```c
void send_FBLogin_Request(struct user_t *user) {
  send_to_user("$FBLoginReq ", user);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_FBLogin_Request>:
  endbr64
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  jmp    1050 <send_to_user@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: $FBLoginReq 

assistant: ```c
void send_FBLogin_Request(struct user_t *user) {
  send_to_user("$FBLoginReq ", user);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  cmpl   $0x74696445,-0x34(%rbp)
  jne    L23
  mov    $0x0,%eax
  call   <print_secr@plt>
  jmp    L14
L23:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string

tool: D9: No password to show


assistant: ```c
int main(int argc, char **argv) {
  int check = 0;
  char buffer[32];
  gets(buffer);
  if (check == 0x74696445) {
    print_secr();
  } else {
    printf("No password to show\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: No password to show


assistant: ```c
int main(int argc, char **argv) {
  int check = 0;
  char buffer[32];
  gets(buffer);
  if (check == 0x74696445) {
    print_secr();
  } else {
    printf("No password to show\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: No password to show


assistant: ```c
int main(int argc, char **argv) {
  int check = 0;
  char buffer[32];
  gets(buffer);
  if (check == 0x74696445) {
    print_secr();
  } else {
    printf("No password to show\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string

tool: D0: No password to show


assistant: ```c
int main(int argc, char **argv) {
  int check = 0;
  char buffer[32];
  gets(buffer);
  if (check == 0x74696445) {
    print_secr();
  } else {
    printf("No password to show\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pstrncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *pstrncpy(char *out, const char *in, size_t num) {
  memcpy(out, in, num);
  out[num] = '\0';
  return out;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pstrncpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *pstrncpy(char *out, const char *in, size_t num) {
  memcpy(out, in, num);
  out[num] = '\0';
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pstrncpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *pstrncpy(char *out, const char *in, size_t num) {
  memcpy(out, in, num);
  out[num] = '\0';
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pstrncpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *pstrncpy(char *out, const char *in, size_t num) {
  memcpy(out, in, num);
  out[num] = '\0';
  return out;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_ucRcAT1608_Read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %esi,%eax
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %edi,%edx
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movzbl -0x18(%rbp),%ecx
  movzbl -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x2520,%edx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L15
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <vWriteLogTxt@plt>
  mov    $0x1,%eax
  jmp    L28
L15:
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L22
  mov    $0x5,%edi
  call   <psGetParaBuf@plt>
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memcpy@plt>
L22:
  mov    -0xc(%rbp),%eax
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string
name: read_data
arguments: data_tag: D1
type_infered: string

tool: D5: %u(%u,%u,%u,b000)

tool: D1: _AT1608_Read iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_Read(unsigned char Level, unsigned char Addr, unsigned int Len, unsigned char *DataBuf) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(%u,%u,%u,b000)", 9504, Level, Addr, Len);
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 5);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_Read iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  uiRet = iGetParaInt(0);
  if (uiRet == 0)
    memcpy(DataBuf, psGetParaBuf(5), Len);
  return uiRet;
}
```
user: What is the c source code of the assembly code below?

```asm
<_ucRcAT1608_Read>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r14d
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movzbl %bpl,%ecx
  mov    %r12d,%r9d
  movzbl %r14b,%r8d
  mov    $0x2520,%edx
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %eax,%esi
  mov    $0x5,%edx
  mov    %rbx,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  test   %ebp,%ebp
  jne    L7
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L19
L36:
  mov    %ebx,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  call   <vWriteLogTxt@plt>
  mov    $0x1,%eax
  jmp    L9
L19:
  mov    $0x5,%edi
  call   <psGetParaBuf@plt>
  mov    %eax,%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  jmp    L36
```

tool_calls: name: unpack_data
arguments: data_label: D11
datatype: string
name: unpack_data
arguments: data_label: D13
datatype: string

tool: D11: %u(%u,%u,%u,b000)

tool: D13: _AT1608_Read iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_Read(unsigned char Level, unsigned char Addr, unsigned int Len, unsigned char *DataBuf) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(%u,%u,%u,b000)", 9504, Level, Addr, Len);
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 5);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_Read iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  uiRet = iGetParaInt(0);
  if (uiRet == 0)
    memcpy(DataBuf, psGetParaBuf(5), Len);
  return uiRet;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ucRcAT1608_Read>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x64,%edi
  call   <malloc@plt>
  movzbl %r14b,%r8d
  movzbl %bl,%ecx
  mov    %r12d,%r9d
  mov    $0x2520,%edx
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    %eax,%esi
  call   <iDoRemoteFunc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r14d
  call   <free@plt>
  test   %r14d,%r14d
  jne    L21
  xor    %edi,%edi
  call   <iGetParaInt@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L8
L16:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x5,%edi
  call   <psGetParaBuf@plt>
  mov    %r12d,%edx
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <memcpy@plt>
  jmp    L16
  nopl   0x0(%rax)
L21:
  mov    %r14d,%esi
  lea    D2(%rip),%rdi
  call   <vWriteLogTxt@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D14: %u(%u,%u,%u,b000)

tool: D2: _AT1608_Read iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_Read(unsigned char Level, unsigned char Addr, unsigned int Len, unsigned char *DataBuf) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(%u,%u,%u,b000)", 9504, Level, Addr, Len);
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 5);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_Read iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  uiRet = iGetParaInt(0);
  if (uiRet == 0)
    memcpy(DataBuf, psGetParaBuf(5), Len);
  return uiRet;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ucRcAT1608_Read>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x64,%edi
  call   <malloc@plt>
  movzbl %r14b,%r8d
  movzbl %bl,%ecx
  mov    %r12d,%r9d
  mov    $0x2520,%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    %eax,%esi
  call   <iDoRemoteFunc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r14d
  call   <free@plt>
  test   %r14d,%r14d
  jne    L3
  xor    %edi,%edi
  call   <iGetParaInt@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L6
L26:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L6:
  mov    $0x5,%edi
  call   <psGetParaBuf@plt>
  mov    %r12d,%edx
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <memcpy@plt>
  jmp    L26
  nopl   0x0(%rax)
L3:
  mov    %r14d,%esi
  lea    D11(%rip),%rdi
  call   <vWriteLogTxt@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string

tool: D6: %u(%u,%u,%u,b000)

tool: D11: _AT1608_Read iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_Read(unsigned char Level, unsigned char Addr, unsigned int Len, unsigned char *DataBuf) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(%u,%u,%u,b000)", 9504, Level, Addr, Len);
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 5);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_Read iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  uiRet = iGetParaInt(0);
  if (uiRet == 0)
    memcpy(DataBuf, psGetParaBuf(5), Len);
  return uiRet;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x10(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: f64

tool: D1: 3.14

assistant: ```c
float square(float *cir_rad, float *cir_ans) {
  *cir_ans = ((*cir_rad * *cir_rad) * 3.14);
  return (*cir_ans);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<square>:
  endbr64
  movss  (%rdi),%xmm0
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D9(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: f64

tool: D9: 3.14

assistant: ```c
float square(float *cir_rad, float *cir_ans) {
  *cir_ans = ((*cir_rad * *cir_rad) * 3.14);
  return (*cir_ans);
}
```
user: Translate the below assembly code into C programming language:

```asm
<square>:
  endbr64
  movss  (%rdi),%xmm0
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D3(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi)
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: f64

tool: D3: 3.14

assistant: ```c
float square(float *cir_rad, float *cir_ans) {
  *cir_ans = ((*cir_rad * *cir_rad) * 3.14);
  return (*cir_ans);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<square>:
  endbr64
  movss  (%rdi),%xmm0
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D2(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: f64

tool: D2: 3.14

assistant: ```c
float square(float *cir_rad, float *cir_ans) {
  *cir_ans = ((*cir_rad * *cir_rad) * 3.14);
  return (*cir_ans);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L25
L26:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L38
L39:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L38:
  cmpl   $0x2,-0x14(%rbp)
  jle    L39
  addl   $0x1,-0x18(%rbp)
L25:
  cmpl   $0x6,-0x18(%rbp)
  jle    L26
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_infered: string
name: unpack_data
arguments: data_tag: D3
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D13: sdssum

tool: D3: # c::%s:len=%d


tool: D2: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sdssum", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D29(%rip),%r15
  jmp    L25
L21:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L19
L25:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L23:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L23
  jmp    L21
L19:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D9
type: string
name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D29: sdssum

tool: D9: # c::%s:len=%d


tool: D7: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sdssum", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```