ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%rdi
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L92
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,0x10(%rsp)
  mov    %edx,%eax
  sar    %eax
  je     L39
  and    $0x1,%eax
  mov    %eax,0x14(%rsp)
  mov    %edx,%eax
  sar    $0x2,%eax
  je     L198
  and    $0x1,%eax
  mov    %eax,0x18(%rsp)
  mov    %edx,%eax
  sar    $0x3,%eax
  je     L132
  and    $0x1,%eax
  mov    %eax,0x1c(%rsp)
  mov    %edx,%eax
  sar    $0x4,%eax
  je     L82
  and    $0x1,%eax
  mov    %eax,0x20(%rsp)
  mov    %edx,%eax
  sar    $0x5,%eax
  je     L58
  and    $0x1,%eax
  mov    %eax,0x24(%rsp)
  mov    %edx,%eax
  sar    $0x6,%eax
  je     L73
  and    $0x1,%eax
  mov    %eax,0x28(%rsp)
  mov    %edx,%eax
  sar    $0x7,%eax
  je     L165
  and    $0x1,%eax
  mov    %eax,0x2c(%rsp)
  mov    %edx,%eax
  sar    $0x8,%eax
  je     L100
  and    $0x1,%eax
  mov    %eax,0x30(%rsp)
  mov    %edx,%eax
  sar    $0x9,%eax
  je     L70
  and    $0x1,%eax
  mov    %eax,0x34(%rsp)
  mov    %edx,%eax
  mov    $0x9,%edx
  sar    $0xa,%eax
L54:
  mov    %eax,0xc(%rsp)
  movslq %edx,%rax
  lea    0x10(%rsp,%rax,4),%rbx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
L92:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L185
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  mov    $0x4,%edx
  jmp    L54
L39:
  xor    %edx,%edx
  jmp    L54
L198:
  mov    $0x1,%edx
  jmp    L54
L132:
  mov    $0x2,%edx
  jmp    L54
L82:
  mov    $0x3,%edx
  jmp    L54
L73:
  mov    $0x5,%edx
  jmp    L54
L165:
  mov    $0x6,%edx
  jmp    L54
L100:
  mov    $0x7,%edx
  jmp    L54
L70:
  mov    $0x8,%edx
  jmp    L54
L185:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
datatype: string
name: disassemble_data
arguments: label: D1
datatype: string

tool: D10: enter the number

tool: D1: %d

assistant: ```c
int main() {
  int a, i = 0, j;
  int rem[10];
  printf("enter the number\n");
  scanf("%d", &a);
  while (a > 0) {
    rem[i] = a % 2;
    a = a / 2;
    i++;
  }
  for (j = i - 1; j >= 0; j--) {
    printf("%d", rem[j]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %rdx,%r12
  mov    (%rdi),%rcx
  mov    %rcx,%rdx
  mov    $0x0,%ebx
L8:
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L55
  test   %al,%al
  je     L55
  add    $0x1,%ebx
  add    $0x1,%rdx
  cmp    $0x20,%ebx
  jne    L8
  cmpb   $0xa,0x20(%rcx)
  sete   %r14b
  movzbl %r14b,%r14d
  mov    (%r12),%eax
  lea    0x21(%rax),%esi
  mov    (%r15),%rdi
  call   <ft_memrealloc@plt>
  mov    %rax,(%r15)
  mov    $0x20,%r13d
  jmp    L60
L55:
  movslq %ebx,%r13
  cmpb   $0xa,(%rcx,%r13,1)
  sete   %r14b
  movzbl %r14b,%r14d
  mov    %ebx,%esi
  add    (%r12),%esi
  add    $0x1,%esi
  mov    (%r15),%rdi
  call   <ft_memrealloc@plt>
  mov    %rax,(%r15)
  test   %ebx,%ebx
  jle    L1
L60:
  mov    %ebx,%edi
  mov    $0x0,%eax
L53:
  mov    0x0(%rbp),%rdx
  movzbl (%rdx,%rax,1),%esi
  mov    %eax,%edx
  add    (%r12),%edx
  movslq %edx,%rdx
  mov    (%r15),%rcx
  mov    %sil,(%rcx,%rdx,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L53
L1:
  add    %ebx,(%r12)
  mov    $0x0,%edx
  cmp    $0x1e,%ebx
  jg     L3
  mov    $0x1e,%edi
  sub    %ebx,%edi
  mov    $0x0,%eax
L47:
  mov    %eax,%edx
  mov    0x0(%rbp),%rsi
  lea    (%rsi,%rax,1),%rcx
  movzbl 0x1(%r13,%rcx,1),%ecx
  test   %cl,%cl
  je     L107
  mov    %cl,(%rsi,%rax,1)
  lea    0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  cmp    %rdi,%rax
  je     L107
  mov    %rcx,%rax
  jmp    L47
L107:
  cmp    $0x1f,%edx
  jg     L63
L3:
  movslq %edx,%rcx
  mov    %rcx,%rax
  sub    %ecx,%edx
L82:
  mov    %rax,%rcx
  add    0x0(%rbp),%rcx
  cmpb   $0x0,(%rcx)
  je     L63
  movb   $0x0,(%rcx)
  add    $0x1,%rax
  lea    (%rdx,%rax,1),%ecx
  cmp    $0x1f,%ecx
  jle    L82
L63:
  mov    %r14d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int set_line(char **buff_p, char **line, int *size) {
  int i;
  int j;
  int nl;
  i = 0;
  while (i < 32 && (*buff_p)[i] != '\0' && (*buff_p)[i] != '\n')
    i++;
  nl = ((*buff_p)[i] == '\n');
  *line = ft_memrealloc(*line, *size + i + 1);
  j = 0;
  while (j < i) {
    (*line)[*size + j] = (*buff_p)[j];
    j++;
  }
  *size += i++;
  j = 0;
  while (j + i < 32 && (*buff_p)[j + i] != '\0') {
    (*buff_p)[j] = (*buff_p)[j + i];
    j++;
  }
  while (j < 32 && (*buff_p)[j] != '\0')
    (*buff_p)[j++] = '\0';
  return (nl);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_line>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    (%rdi),%rcx
  mov    %rcx,%rdx
  jmp    L40
  nopl   (%rax)
L74:
  test   %al,%al
  je     L75
  add    $0x1,%rdx
  cmp    $0x20,%ebx
  je     L5
L40:
  movzbl (%rdx),%eax
  mov    %ebx,%r13d
  add    $0x1,%ebx
  cmp    $0xa,%al
  jne    L74
L75:
  mov    (%r15),%esi
  xor    %r12d,%r12d
  cmp    $0xa,%al
  mov    (%r14),%rdi
  sete   %r12b
  add    %r13d,%esi
  add    $0x1,%esi
  call   <ft_memrealloc@plt>
  mov    %rax,(%r14)
  test   %r13d,%r13d
  je     L111
L118:
  xor    %edx,%edx
  jmp    L115
  nopl   0x0(%rax)
L2:
  mov    (%r14),%rax
L115:
  mov    0x0(%rbp),%rcx
  movzbl (%rcx,%rdx,1),%esi
  mov    (%r15),%ecx
  add    %edx,%ecx
  add    $0x1,%rdx
  movslq %ecx,%rcx
  mov    %sil,(%rax,%rcx,1)
  cmp    %edx,%r13d
  jg     L2
L111:
  mov    0x0(%rbp),%rax
  add    %r13d,(%r15)
  xor    %edi,%edi
  mov    %rax,%rcx
  cmp    $0x1f,%ebx
  jg     L99
  mov    $0x20,%r8d
  xor    %edx,%edx
  sub    %ebx,%r8d
  movslq %ebx,%rbx
  jmp    L123
  nopl   0x0(%rax)
L88:
  lea    0x1(%rdx),%edi
  add    $0x1,%rdx
  mov    %cl,(%rsi)
  cmp    %rdx,%r8
  je     L73
  mov    0x0(%rbp),%rcx
L123:
  lea    (%rcx,%rdx,1),%rsi
  mov    %rcx,%rax
  mov    %edx,%edi
  movzbl (%rsi,%rbx,1),%ecx
  test   %cl,%cl
  jne    L88
L99:
  mov    $0x1f,%ecx
  movslq %edi,%rdx
  sub    %edi,%ecx
  lea    0x1(%rdx,%rcx,1),%rcx
  jmp    L46
  nopl   0x0(%rax)
L13:
  mov    0x0(%rbp),%rax
L46:
  add    %rdx,%rax
  cmpb   $0x0,(%rax)
  je     L96
  add    $0x1,%rdx
  movb   $0x0,(%rax)
  cmp    %rdx,%rcx
  jne    L13
L96:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  mov    0x0(%rbp),%rax
  jmp    L99
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    (%r15),%eax
  mov    (%r14),%rdi
  xor    %r12d,%r12d
  mov    $0x20,%r13d
  cmpb   $0xa,0x20(%rcx)
  mov    $0x21,%ebx
  lea    0x21(%rax),%esi
  sete   %r12b
  call   <ft_memrealloc@plt>
  mov    %rax,(%r14)
  jmp    L118
```

assistant: ```c
int set_line(char **buff_p, char **line, int *size) {
  int i;
  int j;
  int nl;
  i = 0;
  while (i < 32 && (*buff_p)[i] != '\0' && (*buff_p)[i] != '\n')
    i++;
  nl = ((*buff_p)[i] == '\n');
  *line = ft_memrealloc(*line, *size + i + 1);
  j = 0;
  while (j < i) {
    (*line)[*size + j] = (*buff_p)[j];
    j++;
  }
  *size += i++;
  j = 0;
  while (j + i < 32 && (*buff_p)[j + i] != '\0') {
    (*buff_p)[j] = (*buff_p)[j + i];
    j++;
  }
  while (j < 32 && (*buff_p)[j] != '\0')
    (*buff_p)[j++] = '\0';
  return (nl);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_line>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    (%rdi),%rcx
  mov    %rcx,%rdx
  jmp    L102
  nopl   (%rax)
L41:
  test   %al,%al
  je     L123
  add    $0x1,%rdx
  cmp    $0x20,%ebx
  je     L45
L102:
  movzbl (%rdx),%eax
  mov    %ebx,%r15d
  add    $0x1,%ebx
  cmp    $0xa,%al
  jne    L41
L123:
  mov    0x0(%r13),%esi
  xor    %r12d,%r12d
  cmp    $0xa,%al
  mov    (%r14),%rdi
  sete   %r12b
  add    %r15d,%esi
  add    $0x1,%esi
  call   <ft_memrealloc@plt>
  mov    %rax,(%r14)
  test   %r15d,%r15d
  je     L22
  mov    0x0(%rbp),%rdx
  movzbl (%rdx),%ecx
  movslq 0x0(%r13),%rdx
  mov    %cl,(%rax,%rdx,1)
  cmp    $0x1,%r15d
  je     L22
L122:
  movslq %r15d,%rdi
  mov    $0x1,%eax
  nopl   (%rax)
L14:
  mov    0x0(%rbp),%rdx
  mov    (%r14),%rcx
  movzbl (%rdx,%rax,1),%esi
  mov    0x0(%r13),%edx
  add    %eax,%edx
  add    $0x1,%rax
  movslq %edx,%rdx
  mov    %sil,(%rcx,%rdx,1)
  cmp    %rax,%rdi
  jne    L14
L22:
  mov    0x0(%rbp),%rax
  add    %r15d,0x0(%r13)
  xor    %edi,%edi
  mov    %rax,%rcx
  cmp    $0x1f,%ebx
  jg     L149
  mov    $0x20,%r8d
  xor    %edx,%edx
  sub    %ebx,%r8d
  movslq %ebx,%rbx
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L65:
  lea    0x1(%rdx),%edi
  add    $0x1,%rdx
  mov    %cl,(%rsi)
  cmp    %rdx,%r8
  je     L143
  mov    0x0(%rbp),%rcx
L28:
  lea    (%rcx,%rdx,1),%rsi
  mov    %rcx,%rax
  mov    %edx,%edi
  movzbl (%rsi,%rbx,1),%ecx
  test   %cl,%cl
  jne    L65
L149:
  mov    $0x1f,%ecx
  movslq %edi,%rdx
  sub    %edi,%ecx
  lea    0x1(%rdx,%rcx,1),%rcx
  jmp    L119
  nopl   0x0(%rax)
L53:
  mov    0x0(%rbp),%rax
L119:
  add    %rdx,%rax
  cmpb   $0x0,(%rax)
  je     L10
  add    $0x1,%rdx
  movb   $0x0,(%rax)
  cmp    %rcx,%rdx
  jne    L53
L10:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L143:
  mov    0x0(%rbp),%rax
  jmp    L149
  xchg   %ax,%ax
L45:
  mov    0x0(%r13),%eax
  mov    (%r14),%rdi
  xor    %r12d,%r12d
  mov    $0x20,%r15d
  cmpb   $0xa,0x20(%rcx)
  mov    $0x21,%ebx
  lea    0x21(%rax),%esi
  sete   %r12b
  call   <ft_memrealloc@plt>
  mov    %rax,(%r14)
  mov    0x0(%rbp),%rdx
  movzbl (%rdx),%ecx
  movslq 0x0(%r13),%rdx
  mov    %cl,(%rax,%rdx,1)
  jmp    L122
```

assistant: ```c
int set_line(char **buff_p, char **line, int *size) {
  int i;
  int j;
  int nl;
  i = 0;
  while (i < 32 && (*buff_p)[i] != '\0' && (*buff_p)[i] != '\n')
    i++;
  nl = ((*buff_p)[i] == '\n');
  *line = ft_memrealloc(*line, *size + i + 1);
  j = 0;
  while (j < i) {
    (*line)[*size + j] = (*buff_p)[j];
    j++;
  }
  *size += i++;
  j = 0;
  while (j + i < 32 && (*buff_p)[j + i] != '\0') {
    (*buff_p)[j] = (*buff_p)[j + i];
    j++;
  }
  while (j < 32 && (*buff_p)[j] != '\0')
    (*buff_p)[j++] = '\0';
  return (nl);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x18(%rbp)
  jmp    L0
L14:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    $0x40,%eax
  jg     L12
  addl   $0x1,-0x10(%rbp)
L12:
  addl   $0x1,-0x18(%rbp)
L0:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L14
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  mov    -0x20(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D47
data_type: string
name: unpack_data
arguments: tag: D42
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D9
data_type: string

tool: D5: How many grades will you be entering? 

tool: D47: %i

tool: D42: Enter grade #%i: 

tool: D13: 
Grade average = %.2f


tool: D9: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter grade #%i: ", i);
    scanf("%i", &grade);
    gradeTotal += grade;
    if (grade < 65) {
      ++failureCount;
    }
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L15
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  lea    D12(%rip),%r15
  lea    0x4(%rsp),%r14
  lea    D10(%rip),%r13
L34:
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  movzbl %al,%eax
  add    %eax,%ebp
  add    $0x1,%ebx
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L34
L32:
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L32
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D20
type: string
name: read_data
arguments: data_label: D10
type: string
name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D24
type: string
name: read_data
arguments: data_label: D3
type: string

tool: D20: How many grades will you be entering? 

tool: D10: %i

tool: D12: Enter grade #%i: 

tool: D24: 
Grade average = %.2f


tool: D3: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter grade #%i: ", i);
    scanf("%i", &grade);
    gradeTotal += grade;
    if (grade < 65) {
      ++failureCount;
    }
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  lea    D8(%rip),%rdi
  push   %r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L15
  mov    $0x1,%ebx
  lea    D22(%rip),%r15
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L7:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L7
L15:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D34(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string
name: extract_symbolic_data
arguments: label: D22
data_type: string
name: extract_symbolic_data
arguments: label: D34
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D8: How many grades will you be entering? 

tool: D18: %i

tool: D22: Enter grade #%i: 

tool: D34: 
Grade average = %.2f


tool: D5: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter grade #%i: ", i);
    scanf("%i", &grade);
    gradeTotal += grade;
    if (grade < 65) {
      ++failureCount;
    }
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D12(%rip),%rdi
  push   %r14
  push   %r13
  lea    D28(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L2
  mov    $0x1,%ebx
  lea    D2(%rip),%r15
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L27:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L27
L2:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D30(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string
name: read_data
arguments: data_label: D2
type_infered: string
name: read_data
arguments: data_label: D30
type_infered: string
name: read_data
arguments: data_label: D35
type_infered: string

tool: D12: How many grades will you be entering? 

tool: D28: %i

tool: D2: Enter grade #%i: 

tool: D30: 
Grade average = %.2f


tool: D35: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter grade #%i: ", i);
    scanf("%i", &grade);
    gradeTotal += grade;
    if (grade < 65) {
      ++failureCount;
    }
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clear_stdin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L7:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L7
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int clear_stdin() {
  while (getchar() != '\n')
    ;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<clear_stdin>:
  endbr64
  sub    $0x8,%rsp
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int clear_stdin() {
  while (getchar() != '\n')
    ;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clear_stdin>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L6
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int clear_stdin() {
  while (getchar() != '\n')
    ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clear_stdin>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L6
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int clear_stdin() {
  while (getchar() != '\n')
    ;
  return 0;
}
```