ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmp14>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L39
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L39
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L39
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L39
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L39:
  ret
```

assistant: ```c
int cmp14(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmp14>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L7
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L7
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L7
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L7
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L7:
  ret
```

assistant: ```c
int cmp14(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  mov    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
L19:
  mov    $0x0,%eax
  jmp    L28
L15:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L15
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L28:
  leave
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *r;
  size_t i;
  i = 0;
  if (!s || (r = (char *)malloc(sizeof(char) * (len + 1))) == NULL)
    return (NULL);
  while (i < len) {
    r[i] = s[start + i];
    i++;
  }
  r[i] = '\0';
  return (r);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_strsub>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L40
  mov    %esi,%ebx
  mov    %rdx,%rbp
  lea    0x1(%rdx),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L20
  test   %rbp,%rbp
  je     L16
  lea    (%rax,%rbp,1),%rdi
  mov    %rax,%rdx
  mov    %ebx,%ebx
  sub    %rax,%rbx
  lea    (%r12,%rbx,1),%rsi
L42:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L42
L16:
  movb   $0x0,(%rax,%rbp,1)
L54:
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  mov    %rdi,%r8
  jmp    L54
L20:
  mov    $0x0,%r8d
  jmp    L54
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *r;
  size_t i;
  i = 0;
  if (!s || (r = (char *)malloc(sizeof(char) * (len + 1))) == NULL)
    return (NULL);
  while (i < len) {
    r[i] = s[start + i];
    i++;
  }
  r[i] = '\0';
  return (r);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_strsub>:
  endbr64
  test   %rdi,%rdi
  je     L13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rdx),%edi
  push   %rbx
  mov    %rdx,%rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L47
  test   %rbx,%rbx
  je     L22
  mov    %r12d,%esi
  lea    (%rbx,%rax,1),%rdx
  mov    %rax,%rcx
  sub    %rax,%rsi
  lea    0x0(%rbp,%rsi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl (%rdi,%rcx,1),%esi
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L5
L42:
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L47:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %rax,%rcx
  jmp    L42
  nopl   (%rax)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *r;
  size_t i;
  i = 0;
  if (!s || (r = (char *)malloc(sizeof(char) * (len + 1))) == NULL)
    return (NULL);
  while (i < len) {
    r[i] = s[start + i];
    i++;
  }
  r[i] = '\0';
  return (r);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strsub>:
  endbr64
  test   %rdi,%rdi
  je     L55
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rdx),%edi
  push   %rbx
  mov    %rdx,%rbx
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L138
  test   %rbx,%rbx
  je     L153
  mov    %r12d,%edx
  mov    %r8,%rcx
  lea    -0x1(%rbx),%rax
  lea    0x1(%rbp,%rdx,1),%rsi
  sub    %rsi,%rcx
  cmp    $0xe,%rcx
  jbe    L45
  cmp    $0x6,%rax
  jbe    L45
  cmp    $0xe,%rax
  jbe    L179
  mov    %rbx,%rsi
  mov    %rdx,%rcx
  mov    %r8,%rax
  and    $0xfffffffffffffff0,%rsi
  sub    %r8,%rcx
  add    %r8,%rsi
  add    %rbp,%rcx
  nopl   (%rax)
L158:
  movdqu (%rax,%rcx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L158
  mov    %rbx,%rax
  and    $0xfffffffffffffff0,%rax
  test   $0xf,%bl
  je     L116
  mov    %rbx,%rcx
  sub    %rax,%rcx
  lea    -0x1(%rcx),%rsi
  cmp    $0x6,%rsi
  jbe    L120
L76:
  add    %rbp,%rdx
  mov    (%rdx,%rax,1),%rsi
  mov    %rsi,(%r8,%rax,1)
  mov    %rcx,%rsi
  and    $0xfffffffffffffff8,%rsi
  add    %rsi,%rax
  cmp    %rsi,%rcx
  je     L116
L143:
  movzbl (%rdx,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  lea    0x1(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L116
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x1(%r8,%rax,1)
  lea    0x2(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L116
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x2(%r8,%rax,1)
  lea    0x3(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L116
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x3(%r8,%rax,1)
  lea    0x4(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L116
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x4(%r8,%rax,1)
  lea    0x5(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L116
  movzbl (%rdx,%rcx,1),%ecx
  mov    %cl,0x5(%r8,%rax,1)
  lea    0x6(%rax),%rcx
  cmp    %rcx,%rbx
  jbe    L116
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,0x6(%r8,%rax,1)
L116:
  add    %r8,%rbx
L137:
  movb   $0x0,(%rbx)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L138:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  sub    %r8,%rdx
  add    %r8,%rbx
  mov    %r8,%rax
  add    %rbp,%rdx
  nopl   0x0(%rax)
L199:
  movzbl (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    %rbx,%rax
  jne    L199
  jmp    L137
  nopw   0x0(%rax,%rax,1)
L153:
  mov    %rax,%rbx
  jmp    L137
L179:
  mov    %rbx,%rcx
  xor    %eax,%eax
  jmp    L76
L120:
  add    %rbp,%rdx
  jmp    L143
  nopw   0x0(%rax,%rax,1)
L55:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *r;
  size_t i;
  i = 0;
  if (!s || (r = (char *)malloc(sizeof(char) * (len + 1))) == NULL)
    return (NULL);
  while (i < len) {
    r[i] = s[start + i];
    i++;
  }
  r[i] = '\0';
  return (r);
}
```
user: What is the c source code of the assembly code below?

```asm
<compareVersion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L22:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <parseInt@plt>
  mov    %eax,-0x8(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <parseInt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L10
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L1
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L9
  mov    $0x0,%eax
  jmp    L42
L9:
  mov    $0xffffffff,%eax
  jmp    L42
L1:
  mov    $0x1,%eax
L42:
  leave
  ret
```

assistant: ```c
int compareVersion(char *version1, char *version2) {
  int v1, v2;
  do {
    v1 = parseInt(&version1);
    v2 = parseInt(&version2);
  } while (v1 == v2 && (*version1 || *version2));
  return v1 > v2 ? 1 : (v1 == v2 ? 0 : -1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compareVersion>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,(%rsp)
  lea    0x8(%rsp),%rbp
L27:
  mov    %rbp,%rdi
  call   <parseInt@plt>
  mov    %eax,%ebx
  mov    %rsp,%rdi
  call   <parseInt@plt>
  cmp    %eax,%ebx
  jne    L6
  mov    0x8(%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L27
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L27
L35:
  cmp    %eax,%ebx
  setne  %dl
  movzbl %dl,%edx
  neg    %edx
  jmp    L43
L6:
  mov    $0x1,%edx
  jle    L35
L43:
  mov    %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int compareVersion(char *version1, char *version2) {
  int v1, v2;
  do {
    v1 = parseInt(&version1);
    v2 = parseInt(&version2);
  } while (v1 == v2 && (*version1 || *version2));
  return v1 > v2 ? 1 : (v1 == v2 ? 0 : -1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compareVersion>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%r12
  mov    %rsp,%rbp
  mov    %rsi,(%rsp)
  nopl   (%rax)
L10:
  mov    %r12,%rdi
  call   <parseInt@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <parseInt@plt>
  cmp    %eax,%ebx
  jne    L18
  mov    0x8(%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L10
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L10
L24:
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  setne  %r8b
  add    $0x10,%rsp
  neg    %r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x1,%r8d
  jle    L24
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int compareVersion(char *version1, char *version2) {
  int v1, v2;
  do {
    v1 = parseInt(&version1);
    v2 = parseInt(&version2);
  } while (v1 == v2 && (*version1 || *version2));
  return v1 > v2 ? 1 : (v1 == v2 ? 0 : -1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compareVersion>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%r12
  mov    %rsp,%rbp
  mov    %rsi,(%rsp)
  nopl   (%rax)
L16:
  mov    %r12,%rdi
  call   <parseInt@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <parseInt@plt>
  cmp    %eax,%ebx
  jne    L38
  mov    0x8(%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L16
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L16
L14:
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  setne  %r8b
  add    $0x10,%rsp
  neg    %r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L38:
  mov    $0x1,%r8d
  jle    L14
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int compareVersion(char *version1, char *version2) {
  int v1, v2;
  do {
    v1 = parseInt(&version1);
    v2 = parseInt(&version2);
  } while (v1 == v2 && (*version1 || *version2));
  return v1 > v2 ? 1 : (v1 == v2 ? 0 : -1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sendall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L0:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L15
  mov    $0x1,%eax
  jmp    L18
L15:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L0
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
int sendall(int sock, void *buf, unsigned long size) {
  int temp;
  unsigned long all = 0;
  while (all < (long)size) {
    temp = send(sock, buf + all, size - all, 0);
    if (temp <= 0) {
      return 1;
    }
    all += temp;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sendall>:
  endbr64
  test   %rdx,%rdx
  je     L29
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    $0x0,%ebx
L9:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    0x0(%r13,%rbx,1),%rsi
  mov    $0x0,%ecx
  mov    %r12d,%edi
  call   <send@plt>
  test   %eax,%eax
  jle    L8
  cltq
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L9
  mov    $0x0,%eax
  jmp    L7
L29:
  mov    $0x0,%eax
  ret
L8:
  mov    $0x1,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sendall(int sock, void *buf, unsigned long size) {
  int temp;
  unsigned long all = 0;
  while (all < (long)size) {
    temp = send(sock, buf + all, size - all, 0);
    if (temp <= 0) {
      return 1;
    }
    all += temp;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sendall>:
  endbr64
  test   %rdx,%rdx
  je     L23
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L26
L25:
  cltq
  add    %rax,%r13
  cmp    %r13,%rbx
  jbe    L0
L26:
  mov    %rbx,%rdx
  xor    %ecx,%ecx
  lea    (%r12,%r13,1),%rsi
  mov    %ebp,%edi
  sub    %r13,%rdx
  call   <send@plt>
  test   %eax,%eax
  jg     L25
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sendall(int sock, void *buf, unsigned long size) {
  int temp;
  unsigned long all = 0;
  while (all < (long)size) {
    temp = send(sock, buf + all, size - all, 0);
    if (temp <= 0) {
      return 1;
    }
    all += temp;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sendall>:
  endbr64
  test   %rdx,%rdx
  je     L8
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L6
L0:
  cltq
  add    %rax,%r13
  cmp    %r13,%rbx
  jbe    L11
L6:
  mov    %rbx,%rdx
  xor    %ecx,%ecx
  lea    (%r12,%r13,1),%rsi
  mov    %ebp,%edi
  sub    %r13,%rdx
  call   <send@plt>
  test   %eax,%eax
  jg     L0
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sendall(int sock, void *buf, unsigned long size) {
  int temp;
  unsigned long all = 0;
  while (all < (long)size) {
    temp = send(sock, buf + all, size - all, 0);
    if (temp <= 0) {
      return 1;
    }
    all += temp;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<secondary_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L144
  cmpl   $0x0,-0x8(%rbp)
  jne    L144
  mov    $0x0,%eax
  jmp    L76
L144:
  cmpl   $0x1,-0xc(%rbp)
  jne    L150
  cmpl   $0x0,-0x4(%rbp)
  je     L35
  cmpl   $0x0,-0x8(%rbp)
  jne    L27
L35:
  mov    $0x5,%eax
  jmp    L76
L27:
  cmpl   $0x4,-0x4(%rbp)
  jne    L50
  cmpl   $0x4,-0x8(%rbp)
  jne    L50
  mov    $0x4,%eax
  jmp    L76
L50:
  mov    $0x1,%eax
  jmp    L76
L150:
  cmpl   $0x4,-0x4(%rbp)
  je     L81
  cmpl   $0x4,-0x8(%rbp)
  jne    L136
L81:
  mov    $0x4,%eax
  jmp    L76
L136:
  cmpl   $0x1,-0x4(%rbp)
  je     L103
  cmpl   $0x1,-0x8(%rbp)
  jne    L134
L103:
  mov    $0x1,%eax
  jmp    L76
L134:
  mov    $0x5,%eax
L76:
  pop    %rbp
  ret
```

assistant: ```c
int secondary_state(int state, int other, int seclevel) {
  if (state == 0x0 && other == 0x0)
    return 0x0;
  if (seclevel == 0x01) {
    if (state == 0x0 || other == 0x0)
      return 0x5;
    if (state == 0x4 && other == 0x4)
      return 0x4;
    return 0x1;
  } else {
    if (state == 0x4 || other == 0x4)
      return 0x4;
    if (state == 0x1 || other == 0x1)
      return 0x1;
    return 0x5;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<secondary_state>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  je     L19
  cmp    $0x1,%edx
  je     L8
  cmp    $0x4,%edi
  je     L58
  cmp    $0x4,%esi
  je     L58
  cmp    $0x1,%edi
  je     L75
  cmp    $0x1,%esi
  je     L75
  mov    $0x5,%eax
  ret
L8:
  test   %edi,%edi
  je     L79
  test   %esi,%esi
  je     L79
  cmp    $0x4,%edi
  jne    L31
  mov    $0x4,%eax
  cmp    $0x4,%esi
  je     L19
L31:
  mov    %edx,%eax
  ret
L79:
  mov    $0x5,%eax
  ret
L58:
  mov    $0x4,%eax
  ret
L75:
  mov    $0x1,%eax
L19:
  ret
```

assistant: ```c
int secondary_state(int state, int other, int seclevel) {
  if (state == 0x0 && other == 0x0)
    return 0x0;
  if (seclevel == 0x01) {
    if (state == 0x0 || other == 0x0)
      return 0x5;
    if (state == 0x4 && other == 0x4)
      return 0x4;
    return 0x1;
  } else {
    if (state == 0x4 || other == 0x4)
      return 0x4;
    if (state == 0x1 || other == 0x1)
      return 0x1;
    return 0x5;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<secondary_state>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  je     L99
  cmp    $0x1,%edx
  je     L65
  cmp    $0x4,%edi
  je     L71
  cmp    $0x4,%esi
  je     L71
  cmp    $0x1,%edi
  je     L16
  mov    $0x5,%eax
  cmp    $0x1,%esi
  je     L16
L99:
  ret
  nopl   0x0(%rax)
L65:
  test   %edi,%edi
  je     L25
  test   %esi,%esi
  je     L25
  cmp    $0x4,%edi
  jne    L16
  cmp    $0x4,%esi
  jne    L16
L71:
  mov    $0x4,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    $0x5,%eax
  ret
```

assistant: ```c
int secondary_state(int state, int other, int seclevel) {
  if (state == 0x0 && other == 0x0)
    return 0x0;
  if (seclevel == 0x01) {
    if (state == 0x0 || other == 0x0)
      return 0x5;
    if (state == 0x4 && other == 0x4)
      return 0x4;
    return 0x1;
  } else {
    if (state == 0x4 || other == 0x4)
      return 0x4;
    if (state == 0x1 || other == 0x1)
      return 0x1;
    return 0x5;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<secondary_state>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  je     L16
  cmp    $0x1,%edx
  je     L19
  cmp    $0x4,%edi
  je     L7
  cmp    $0x4,%esi
  je     L7
  cmp    $0x1,%edi
  je     L53
  mov    $0x5,%eax
  cmp    $0x1,%esi
  je     L53
L16:
  ret
  nopl   0x0(%rax)
L19:
  test   %edi,%edi
  je     L2
  test   %esi,%esi
  je     L2
  cmp    $0x4,%edi
  jne    L53
  cmp    $0x4,%esi
  jne    L53
L7:
  mov    $0x4,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    $0x5,%eax
  ret
```

assistant: ```c
int secondary_state(int state, int other, int seclevel) {
  if (state == 0x0 && other == 0x0)
    return 0x0;
  if (seclevel == 0x01) {
    if (state == 0x0 || other == 0x0)
      return 0x5;
    if (state == 0x4 && other == 0x4)
      return 0x4;
    return 0x1;
  } else {
    if (state == 0x4 || other == 0x4)
      return 0x4;
    if (state == 0x1 || other == 0x1)
      return 0x1;
    return 0x5;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%r9d
  mov    $0x40000000,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <splice@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  splice(0, 0, 1, 0, 1 << 30, 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r9d
  mov    $0x40000000,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <splice@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  splice(0, 0, 1, 0, 1 << 30, 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  mov    $0x40000000,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <splice@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  splice(0, 0, 1, 0, 1 << 30, 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  mov    $0x40000000,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <splice@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  splice(0, 0, 1, 0, 1 << 30, 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<case_starts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%r14
  mov    -0x30(%rbp),%r13
L89:
  movzbl 0x0(%r13),%eax
  test   %al,%al
  jne    L64
  mov    $0x1,%eax
  jmp    L32
L64:
  movzbl (%r14),%eax
  lea    -0x41(%rax),%ebx
  cmp    $0x19,%bl
  ja     L61
  add    $0x61,%ebx
  jmp    L27
L61:
  add    $0x41,%ebx
L27:
  movzbl 0x0(%r13),%eax
  lea    -0x41(%rax),%r12d
  cmp    $0x19,%r12b
  ja     L71
  add    $0x61,%r12d
  jmp    L87
L71:
  add    $0x41,%r12d
L87:
  cmp    %r12b,%bl
  jne    L28
  test   %bl,%bl
  je     L33
  add    $0x1,%r14
  add    $0x1,%r13
  jmp    L89
L28:
  nop
  jmp    L82
L33:
  nop
L82:
  mov    $0x0,%eax
L32:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int case_starts(const char *a, const char *b) {
  register const char *s = a;
  register const char *t = b;
  for (;;) {
    register unsigned char x, y;
    if (!*t)
      return 1;
    x = *s - 'A';
    if (x <= 'Z' - 'A')
      x += 'a';
    else
      x += 'A';
    y = *t - 'A';
    if (y <= 'Z' - 'A')
      y += 'a';
    else
      y += 'A';
    if (x != y)
      break;
    if (!x)
      break;
    ++s;
    ++t;
  }
  return 0;
}
```