ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<headers>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send@plt>
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send@plt>
  mov    %r12,%rdi
  call   <getMime@plt>
  mov    %rax,%rdx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send@plt>
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string
name: retrieve_data
arguments: label: D3
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D0: HTTP/1.0 200 OK


tool: D10: Server: jdbhttpd/0.1.0


tool: D3: Content-Type: %s


tool: D1: 


assistant: ```c
void headers(int client, const char *filename) {
  char buf[1024];
  (void)filename;
  strcpy(buf, "HTTP/1.0 200 OK\r\n");
  send(client, buf, strlen(buf), 0);
  strcpy(buf, "Server: jdbhttpd/0.1.0\r\n");
  send(client, buf, strlen(buf), 0);
  sprintf(buf, "Content-Type: %s\r\n", getMime(filename));
  send(client, buf, strlen(buf), 0);
  strcpy(buf, "\r\n");
  send(client, buf, strlen(buf), 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<headers>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  lea    D11(%rip),%rsi
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  mov    %r13,%rdi
  call   <getMime@plt>
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type: string
name: disassemble_data
arguments: data_tag: D27
type: string
name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D3
type: string

tool: D11: HTTP/1.0 200 OK


tool: D27: Server: jdbhttpd/0.1.0


tool: D6: Content-Type: %s


tool: D3: 


assistant: ```c
void headers(int client, const char *filename) {
  char buf[1024];
  (void)filename;
  strcpy(buf, "HTTP/1.0 200 OK\r\n");
  send(client, buf, strlen(buf), 0);
  strcpy(buf, "Server: jdbhttpd/0.1.0\r\n");
  send(client, buf, strlen(buf), 0);
  sprintf(buf, "Content-Type: %s\r\n", getMime(filename));
  send(client, buf, strlen(buf), 0);
  strcpy(buf, "\r\n");
  send(client, buf, strlen(buf), 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<headers>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  lea    D18(%rip),%rsi
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  mov    %r13,%rdi
  call   <getMime@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <send@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: string
name: extract_symbolic_data
arguments: label: D37
type_infered: string
name: extract_symbolic_data
arguments: label: D26
type_infered: string
name: extract_symbolic_data
arguments: label: D21
type_infered: string

tool: D18: HTTP/1.0 200 OK


tool: D37: Server: jdbhttpd/0.1.0


tool: D26: Content-Type: %s


tool: D21: 


assistant: ```c
void headers(int client, const char *filename) {
  char buf[1024];
  (void)filename;
  strcpy(buf, "HTTP/1.0 200 OK\r\n");
  send(client, buf, strlen(buf), 0);
  strcpy(buf, "Server: jdbhttpd/0.1.0\r\n");
  send(client, buf, strlen(buf), 0);
  sprintf(buf, "Content-Type: %s\r\n", getMime(filename));
  send(client, buf, strlen(buf), 0);
  strcpy(buf, "\r\n");
  send(client, buf, strlen(buf), 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_internet_address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,%edi
  call   <inet_ntoa@plt>
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int get_internet_address(char *host, int len, int *portp, struct sockaddr_in *addrp) {
  strncpy(host, inet_ntoa(addrp->sin_addr), len);
  *portp = ntohs(addrp->sin_port);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_internet_address>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    0x4(%rcx),%edi
  call   <inet_ntoa@plt>
  mov    %eax,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    (%rbx),%edi
  call   <ntohs@plt>
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_internet_address(char *host, int len, int *portp, struct sockaddr_in *addrp) {
  strncpy(host, inet_ntoa(addrp->sin_addr), len);
  *portp = ntohs(addrp->sin_port);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_internet_address>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  mov    0x4(%rcx),%edi
  call   <inet_ntoa@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <strncpy@plt>
  mov    (%rbx),%edi
  call   <ntohs@plt>
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_internet_address(char *host, int len, int *portp, struct sockaddr_in *addrp) {
  strncpy(host, inet_ntoa(addrp->sin_addr), len);
  *portp = ntohs(addrp->sin_port);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_internet_address>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  mov    0x4(%rcx),%edi
  call   <inet_ntoa@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <strncpy@plt>
  mov    (%rbx),%edi
  call   <ntohs@plt>
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_internet_address(char *host, int len, int *portp, struct sockaddr_in *addrp) {
  strncpy(host, inet_ntoa(addrp->sin_addr), len);
  *portp = ntohs(addrp->sin_port);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1f6c(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x1f64(%rbp)
  jmp    L20
L62:
  lea    -0x1f68(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1f5c(%rbp)
  movl   $0x1,-0x1f60(%rbp)
  jmp    L68
L51:
  lea    -0x1f50(%rbp),%rdx
  mov    -0x1f60(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1f60(%rbp),%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%eax
  add    %eax,-0x1f5c(%rbp)
  addl   $0x1,-0x1f60(%rbp)
L68:
  mov    -0x1f68(%rbp),%eax
  cmp    %eax,-0x1f60(%rbp)
  jle    L51
  mov    -0x1f68(%rbp),%ecx
  mov    -0x1f5c(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x1f54(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x1f58(%rbp)
  movl   $0x1,-0x1f60(%rbp)
  jmp    L10
L65:
  mov    -0x1f60(%rbp),%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%eax
  cmp    %eax,-0x1f54(%rbp)
  jge    L64
  movss  -0x1f58(%rbp),%xmm1
  movss  D26(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x1f58(%rbp)
L64:
  addl   $0x1,-0x1f60(%rbp)
L10:
  mov    -0x1f68(%rbp),%eax
  cmp    %eax,-0x1f60(%rbp)
  jle    L65
  movss  -0x1f58(%rbp),%xmm1
  movss  D49(%rip),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x1f68(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1f64(%rbp)
L20:
  mov    -0x1f6c(%rbp),%eax
  cmp    %eax,-0x1f64(%rbp)
  jle    L62
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D26
type: byte[4]
name: disassemble_data
arguments: label: D49
type: byte[4]
name: disassemble_data
arguments: label: D16
type: string

tool: D0: %d

tool: {"D26": [0x00,0x00,0x80,0x3f]}

tool: {"D49": [0x00,0x00,0xc8,0x42]}

tool: D16: %2.3f%


assistant: ```c
int main() {
  int a, i, j, s, C, N, g[2000];
  float k;
  scanf("%d", &C);
  for (i = 1; i <= C; i++) {
    scanf("%d", &N);
    s = 0;
    for (j = 1; j <= N; j++) {
      scanf("%d", &g[j]);
      s = s + g[j];
    }
    a = (int)(s / N);
    k = 0;
    for (j = 1; j <= N; j++)
      if (g[j] > a)
        k++;
    printf("%2.3f%\n", (float)(k * 100) / N);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L3
  mov    $0x1,%r14d
  lea    D12(%rip),%r13
  jmp    L64
L79:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  je     L28
L83:
  cmp    %eax,(%rdx)
  jle    L79
  addss  D41(%rip),%xmm0
  jmp    L79
L116:
  pxor   %xmm0,%xmm0
L28:
  mulss  D16(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  divss  %xmm1,%xmm0
  lea    D49(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  jl     L3
L64:
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L116
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L76:
  lea    0x10(%rsp),%r12
  lea    (%r12,%rbx,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    (%r12,%rbx,4),%ebp
  mov    0xc(%rsp),%ecx
  add    $0x1,%rbx
  cmp    %ebx,%ecx
  jge    L76
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  test   %ecx,%ecx
  jle    L36
  lea    0x14(%rsp),%rdx
  lea    -0x1(%rcx),%esi
  lea    0x8(%r12,%rsi,4),%rsi
  pxor   %xmm0,%xmm0
  jmp    L83
L36:
  pxor   %xmm0,%xmm0
  jmp    L28
L3:
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    $0x0,%eax
  add    $0x1f60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_guessed: string
name: unpack_data
arguments: data_label: D41
type_guessed: byte[4]
name: unpack_data
arguments: data_label: D16
type_guessed: byte[4]
name: unpack_data
arguments: data_label: D49
type_guessed: string

tool: D12: %d

tool: {"D41": [0x00,0x00,0x80,0x3f]}

tool: {"D16": [0x00,0x00,0xc8,0x42]}

tool: D49: %2.3f%


assistant: ```c
int main() {
  int a, i, j, s, C, N, g[2000];
  float k;
  scanf("%d", &C);
  for (i = 1; i <= C; i++) {
    scanf("%d", &N);
    s = 0;
    for (j = 1; j <= N; j++) {
      scanf("%d", &g[j]);
      s = s + g[j];
    }
    a = (int)(s / N);
    k = 0;
    for (j = 1; j <= N; j++)
      if (g[j] > a)
        k++;
    printf("%2.3f%\n", (float)(k * 100) / N);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf68,%rsp
  lea    D30(%rip),%rbp
  mov    $0x1,%r12d
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r14
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L19
  nop
L54:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L57
  mov    $0x1,%ebx
  xor    %r15d,%r15d
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax)
L46:
  lea    0x0(%r13,%rbx,4),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  add    0x0(%r13,%rbx,4),%r15d
  add    $0x1,%rbx
  cmp    %ebx,%ecx
  jge    L46
  mov    %r15d,%eax
  cltd
  idiv   %ecx
  test   %ecx,%ecx
  jle    L57
  lea    -0x1(%rcx),%esi
  lea    0x14(%rsp),%rdx
  pxor   %xmm0,%xmm0
  lea    0x18(%rsp,%rsi,4),%rsi
  nopl   (%rax)
L80:
  cmp    %eax,(%rdx)
  jle    L35
  addss  D4(%rip),%xmm0
L35:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L80
  mulss  D32(%rip),%xmm0
L5:
  pxor   %xmm1,%xmm1
  lea    D24(%rip),%rdi
  add    $0x1,%r12d
  cvtsi2ss %ecx,%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  cmp    %r12d,0x8(%rsp)
  jge    L54
L19:
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x1f68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  pxor   %xmm0,%xmm0
  jmp    L5
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D30
type_guessed: string
name: unpack_data
arguments: label: D4
type_guessed: byte[4]
name: unpack_data
arguments: label: D32
type_guessed: byte[4]
name: unpack_data
arguments: label: D24
type_guessed: string

tool: D30: %d

tool: {"D4": [0x00,0x00,0x80,0x3f]}

tool: {"D32": [0x00,0x00,0xc8,0x42]}

tool: D24: %2.3f%


assistant: ```c
int main() {
  int a, i, j, s, C, N, g[2000];
  float k;
  scanf("%d", &C);
  for (i = 1; i <= C; i++) {
    scanf("%d", &N);
    s = 0;
    for (j = 1; j <= N; j++) {
      scanf("%d", &g[j]);
      s = s + g[j];
    }
    a = (int)(s / N);
    k = 0;
    for (j = 1; j <= N; j++)
      if (g[j] > a)
        k++;
    printf("%2.3f%\n", (float)(k * 100) / N);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf68,%rsp
  lea    D5(%rip),%rbp
  mov    $0x1,%r12d
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r14
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L75
  nop
L63:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L5
  mov    $0x1,%ebx
  xor    %r15d,%r15d
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax)
L73:
  lea    0x0(%r13,%rbx,4),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  add    0x0(%r13,%rbx,4),%r15d
  add    $0x1,%rbx
  cmp    %ebx,%ecx
  jge    L73
  mov    %r15d,%eax
  cltd
  idiv   %ecx
  test   %ecx,%ecx
  jle    L5
  lea    -0x1(%rcx),%esi
  lea    0x14(%rsp),%rdx
  pxor   %xmm0,%xmm0
  lea    0x18(%rsp,%rsi,4),%rsi
  nopl   (%rax)
L52:
  cmp    %eax,(%rdx)
  jle    L8
  addss  D4(%rip),%xmm0
L8:
  add    $0x4,%rdx
  cmp    %rdx,%rsi
  jne    L52
  mulss  D18(%rip),%xmm0
L86:
  pxor   %xmm1,%xmm1
  lea    D31(%rip),%rdi
  add    $0x1,%r12d
  cvtsi2ss %ecx,%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  cmp    %r12d,0x8(%rsp)
  jge    L63
L75:
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x1f68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  pxor   %xmm0,%xmm0
  jmp    L86
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string
name: read_data
arguments: data_label: D4
type_guessed: byte[4]
name: read_data
arguments: data_label: D18
type_guessed: byte[4]
name: read_data
arguments: data_label: D31
type_guessed: string

tool: D5: %d

tool: {"D4": [0x00,0x00,0x80,0x3f]}

tool: {"D18": [0x00,0x00,0xc8,0x42]}

tool: D31: %2.3f%


assistant: ```c
int main() {
  int a, i, j, s, C, N, g[2000];
  float k;
  scanf("%d", &C);
  for (i = 1; i <= C; i++) {
    scanf("%d", &N);
    s = 0;
    for (j = 1; j <= N; j++) {
      scanf("%d", &g[j]);
      s = s + g[j];
    }
    a = (int)(s / N);
    k = 0;
    for (j = 1; j <= N; j++)
      if (g[j] > a)
        k++;
    printf("%2.3f%\n", (float)(k * 100) / N);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D21
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string

tool: D21: 
ab

tool: D5: si

tool: D15: ha

assistant: ```c
main() {
  printf("\nab");
  printf("\bsi");
  printf("\rha");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D24
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string

tool: D1: 
ab

tool: D24: si

tool: D13: ha

assistant: ```c
main() {
  printf("\nab");
  printf("\bsi");
  printf("\rha");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D26
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string

tool: D3: 
ab

tool: D26: si

tool: D14: ha

assistant: ```c
main() {
  printf("\nab");
  printf("\bsi");
  printf("\rha");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D9
type: string
name: read_data
arguments: tag: D26
type: string

tool: D0: 
ab

tool: D9: si

tool: D26: ha

assistant: ```c
main() {
  printf("\nab");
  printf("\bsi");
  printf("\rha");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<circleSinTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
double *circleSinTable(void) {
  static double theTable[33] = {0.0, 0.1950903220161282, 0.3826834323650897, 0.555570233019602, 0.707106781186547, 0.831469612302545, 0.923879532511287, 0.98078528040323, 1.0, 0.98078528040323, 0.923879532511287, 0.831469612302545, 0.7071067811865475, 0.555570233019602, 0.38268343236509, 0.1950903220161286, 0.0, -0.1950903220161283, -0.3826834323650896, -0.555570233019602, -0.707106781186547, -0.831469612302545, -0.9238795325112865, -0.98078528040323, -1.0, -0.98078528040323, -0.923879532511287, -0.831469612302545, -0.707106781186548, -0.555570233019602, -0.3826834323650903, -0.1950903220161287, 0.0};
  return theTable;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<circleSinTable>:
  endbr64
  lea    D5(%rip),%rax
  ret
```

assistant: ```c
double *circleSinTable(void) {
  static double theTable[33] = {0.0, 0.1950903220161282, 0.3826834323650897, 0.555570233019602, 0.707106781186547, 0.831469612302545, 0.923879532511287, 0.98078528040323, 1.0, 0.98078528040323, 0.923879532511287, 0.831469612302545, 0.7071067811865475, 0.555570233019602, 0.38268343236509, 0.1950903220161286, 0.0, -0.1950903220161283, -0.3826834323650896, -0.555570233019602, -0.707106781186547, -0.831469612302545, -0.9238795325112865, -0.98078528040323, -1.0, -0.98078528040323, -0.923879532511287, -0.831469612302545, -0.707106781186548, -0.555570233019602, -0.3826834323650903, -0.1950903220161287, 0.0};
  return theTable;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<circleSinTable>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

assistant: ```c
double *circleSinTable(void) {
  static double theTable[33] = {0.0, 0.1950903220161282, 0.3826834323650897, 0.555570233019602, 0.707106781186547, 0.831469612302545, 0.923879532511287, 0.98078528040323, 1.0, 0.98078528040323, 0.923879532511287, 0.831469612302545, 0.7071067811865475, 0.555570233019602, 0.38268343236509, 0.1950903220161286, 0.0, -0.1950903220161283, -0.3826834323650896, -0.555570233019602, -0.707106781186547, -0.831469612302545, -0.9238795325112865, -0.98078528040323, -1.0, -0.98078528040323, -0.923879532511287, -0.831469612302545, -0.707106781186548, -0.555570233019602, -0.3826834323650903, -0.1950903220161287, 0.0};
  return theTable;
}
```