ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L26
  lea    -0x1(%rsi),%edx
  mov    $0x1,%ecx
  mov    $0x2,%esi
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ecx,%eax
  mov    %esi,%ecx
  sub    $0x1,%edx
  imul   %esi,%eax
  movslq %eax,%rsi
  mov    %eax,%edi
  imul   $0x51eb851f,%rsi,%rsi
  sar    $0x1f,%edi
  sar    $0x25,%rsi
  sub    %edi,%esi
  imul   $0x64,%esi,%edi
  sub    %edi,%eax
  mov    %eax,%esi
  cmp    $0x1,%edx
  jne    L16
  movl   $0x1,0x4(%rsp)
L26:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d

assistant: ```c
int main() {
  int n, x = 1, y = 2, z;
  if (scanf("%d", &n), n < 3)
    return 0 * printf("%d", n);
  else
    while (n-- > 2)
      z = x * y % 100, x = y, y = z;
  printf("%d", z);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L47:
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%eax
  test   %eax,%eax
  js     L47
  mov    -0x34(%rbp),%eax
  cmp    $0x1,%eax
  jg     L47
L20:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  js     L20
  mov    -0x38(%rbp),%eax
  cmp    $0x7,%eax
  jg     L20
  mov    -0x3c(%rbp),%eax
  lea    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <decimal@plt>
  mov    -0x38(%rbp),%edx
  mov    $0x7,%eax
  sub    %edx,%eax
  mov    -0x34(%rbp),%edx
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <binary@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D28: %d

tool: D13: %d 


assistant: ```c
int main() {
  int n, p, v;
  int masive[8] = {0, 0, 0, 0, 0, 0, 0, 0};
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v < 0 || v > 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  decimal(n, masive);
  masive[7 - p] = v;
  printf("%d \n", binary(masive));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rbx
L9:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  ja     L9
  lea    D9(%rip),%rbx
L8:
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x7,0x8(%rsp)
  ja     L8
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  mov    0x4(%rsp),%edi
  call   <decimal@plt>
  mov    $0x7,%eax
  sub    0x8(%rsp),%eax
  cltq
  mov    0xc(%rsp),%edx
  mov    %edx,0x10(%rsp,%rax,4)
  mov    %rbx,%rdi
  call   <binary@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string
name: disassemble_data
arguments: data_label: D23
datatype: string

tool: D9: %d

tool: D23: %d 


assistant: ```c
int main() {
  int n, p, v;
  int masive[8] = {0, 0, 0, 0, 0, 0, 0, 0};
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v < 0 || v > 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  decimal(n, masive);
  masive[7 - p] = v;
  printf("%d \n", binary(masive));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  push   %rbx
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  lea    0xc(%rsp),%rbp
  movaps %xmm0,0x20(%rsp)
  call   <scanf@plt>
  nopl   0x0(%rax)
L19:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  ja     L19
  lea    0x8(%rsp),%rbp
  nop
L20:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x7,0x8(%rsp)
  ja     L20
  mov    0x4(%rsp),%edi
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  call   <decimal@plt>
  mov    0xc(%rsp),%edx
  mov    $0x7,%eax
  mov    %rbp,%rdi
  sub    0x8(%rsp),%eax
  cltq
  mov    %edx,0x10(%rsp,%rax,4)
  call   <binary@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: D18: %d

tool: D9: %d 


assistant: ```c
int main() {
  int n, p, v;
  int masive[8] = {0, 0, 0, 0, 0, 0, 0, 0};
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v < 0 || v > 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  decimal(n, masive);
  masive[7 - p] = v;
  printf("%d \n", binary(masive));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  lea    0xc(%rsp),%rbp
  movaps %xmm0,0x20(%rsp)
  call   <scanf@plt>
  nopl   0x0(%rax)
L12:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  ja     L12
  lea    0x8(%rsp),%rbp
  nop
L22:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x7,0x8(%rsp)
  ja     L22
  mov    0x4(%rsp),%edi
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  call   <decimal@plt>
  mov    0xc(%rsp),%edx
  mov    $0x7,%eax
  mov    %rbp,%rdi
  sub    0x8(%rsp),%eax
  cltq
  mov    %edx,0x10(%rsp,%rax,4)
  call   <binary@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string
name: parse_data
arguments: label: D7
datatype: string

tool: D4: %d

tool: D7: %d 


assistant: ```c
int main() {
  int n, p, v;
  int masive[8] = {0, 0, 0, 0, 0, 0, 0, 0};
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v < 0 || v > 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  decimal(n, masive);
  masive[7 - p] = v;
  printf("%d \n", binary(masive));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<num_procs_of_my_exe_no_children>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <get_my_exe@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <num_procs_of_exe_no_children@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int num_procs_of_my_exe_no_children(void) {
  char *myexe = get_my_exe();
  int ret = -1;
  if (myexe) {
    ret = num_procs_of_exe_no_children(myexe);
    free(myexe);
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_procs_of_my_exe_no_children>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_my_exe@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <num_procs_of_exe_no_children@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
L0:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    $0xffffffff,%ebp
  jmp    L0
```

assistant: ```c
int num_procs_of_my_exe_no_children(void) {
  char *myexe = get_my_exe();
  int ret = -1;
  if (myexe) {
    ret = num_procs_of_exe_no_children(myexe);
    free(myexe);
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<num_procs_of_my_exe_no_children>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <get_my_exe@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <num_procs_of_exe_no_children@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%r12d
  jmp    L7
```

assistant: ```c
int num_procs_of_my_exe_no_children(void) {
  char *myexe = get_my_exe();
  int ret = -1;
  if (myexe) {
    ret = num_procs_of_exe_no_children(myexe);
    free(myexe);
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<num_procs_of_my_exe_no_children>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <get_my_exe@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <num_procs_of_exe_no_children@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L3:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%r12d
  jmp    L3
```

assistant: ```c
int num_procs_of_my_exe_no_children(void) {
  char *myexe = get_my_exe();
  int ret = -1;
  if (myexe) {
    ret = num_procs_of_exe_no_children(myexe);
    free(myexe);
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wait_format_confirmation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x258,-0x4(%rbp)
L9:
  lea    D8(%rip),%rax
  mov    %rax,%rdx
  mov    $0x1e,%esi
  mov    $0x14,%edi
  mov    $0x0,%eax
  call   <_printf@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  lea    D9(%rip),%rax
  mov    %rax,%rdx
  mov    $0x28,%esi
  mov    $0x14,%edi
  mov    $0x0,%eax
  call   <_printf@plt>
  mov    $0xd8000e8,%esi
  mov    $0x1,%edi
  call   <svcCustomKernelCommand@plt>
  and    $0x1,%eax
  test   %eax,%eax
  jne    L4
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L16
  mov    $0x3e8,%edi
  mov    $0x1071d668,%eax
  call   *%rax
  mov    $0x1,%edi
  call   <svcShutdown@plt>
L16:
  mov    $0x64,%edi
  mov    $0x1071d668,%eax
  call   *%rax
  jmp    L9
L4:
  nop
  mov    $0xff,%esi
  mov    $0x1e,%edi
  call   <clearLine@plt>
  mov    $0xff,%esi
  mov    $0x28,%edi
  call   <clearLine@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D8: No NAND dump detected. SD Format and complete NAND dump required.

tool: D9: Press the POWER button to format SD card otherwise the console will reboot in %d seconds.

assistant: ```c
void wait_format_confirmation(void) {
  int timeout = 600;
  while (1) {
    _printf(20, 30, "No NAND dump detected. SD Format and complete NAND dump required.");
    _printf(20, 40, "Press the POWER button to format SD card otherwise the console will reboot in %d seconds.", timeout / 10);
    if (svcCustomKernelCommand(1, 0x0d8000e8) & 0x01) {
      break;
    }
    if (--timeout == 0) {
      ((void (*)(int))0x1071D668)(1000);
      svcShutdown(1);
    }
    ((void (*)(int))0x1071D668)(100);
  }
  clearLine(30, 0x000000FF);
  clearLine(40, 0x000000FF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<wait_format_confirmation>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x258,%ebx
  lea    D2(%rip),%r13
  lea    D17(%rip),%r12
  mov    $0x1071d668,%ebp
  jmp    L18
L10:
  mov    $0x64,%edi
  call   *%rbp
L18:
  mov    %r13,%rdx
  mov    $0x1e,%esi
  mov    $0x14,%edi
  mov    $0x0,%eax
  call   <_printf@plt>
  movslq %ebx,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%ecx
  mov    %r12,%rdx
  mov    $0x28,%esi
  mov    $0x14,%edi
  mov    $0x0,%eax
  call   <_printf@plt>
  mov    $0xd8000e8,%esi
  mov    $0x1,%edi
  call   <svcCustomKernelCommand@plt>
  test   $0x1,%al
  jne    L15
  sub    $0x1,%ebx
  jne    L10
  mov    $0x3e8,%edi
  call   *%rbp
  mov    $0x1,%edi
  call   <svcShutdown@plt>
  jmp    L10
L15:
  mov    $0xff,%esi
  mov    $0x1e,%edi
  call   <clearLine@plt>
  mov    $0xff,%esi
  mov    $0x28,%edi
  call   <clearLine@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D17
type: string

tool: D2: No NAND dump detected. SD Format and complete NAND dump required.

tool: D17: Press the POWER button to format SD card otherwise the console will reboot in %d seconds.

assistant: ```c
void wait_format_confirmation(void) {
  int timeout = 600;
  while (1) {
    _printf(20, 30, "No NAND dump detected. SD Format and complete NAND dump required.");
    _printf(20, 40, "Press the POWER button to format SD card otherwise the console will reboot in %d seconds.", timeout / 10);
    if (svcCustomKernelCommand(1, 0x0d8000e8) & 0x01) {
      break;
    }
    if (--timeout == 0) {
      ((void (*)(int))0x1071D668)(1000);
      svcShutdown(1);
    }
    ((void (*)(int))0x1071D668)(100);
  }
  clearLine(30, 0x000000FF);
  clearLine(40, 0x000000FF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wait_format_confirmation>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    $0x1071d668,%ebp
  push   %rbx
  mov    $0x258,%ebx
  sub    $0x8,%rsp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L24:
  sub    $0x1,%ebx
  jne    L27
  mov    $0x3e8,%edi
  call   *%rbp
  mov    $0x1,%edi
  call   <svcShutdown@plt>
L27:
  mov    $0x64,%edi
  call   *%rbp
L3:
  mov    %r13,%rdx
  mov    $0x1e,%esi
  mov    $0x14,%edi
  xor    %eax,%eax
  call   <_printf@plt>
  movslq %ebx,%rcx
  mov    %ebx,%eax
  mov    $0x28,%esi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%eax
  mov    $0x14,%edi
  mov    %r12,%rdx
  sar    $0x22,%rcx
  sub    %eax,%ecx
  xor    %eax,%eax
  call   <_printf@plt>
  mov    $0xd8000e8,%esi
  mov    $0x1,%edi
  call   <svcCustomKernelCommand@plt>
  test   $0x1,%al
  je     L24
  mov    $0xff,%esi
  mov    $0x1e,%edi
  call   <clearLine@plt>
  add    $0x8,%rsp
  mov    $0xff,%esi
  mov    $0x28,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <clearLine@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D15
type_guessed: string

tool: D19: No NAND dump detected. SD Format and complete NAND dump required.

tool: D15: Press the POWER button to format SD card otherwise the console will reboot in %d seconds.

assistant: ```c
void wait_format_confirmation(void) {
  int timeout = 600;
  while (1) {
    _printf(20, 30, "No NAND dump detected. SD Format and complete NAND dump required.");
    _printf(20, 40, "Press the POWER button to format SD card otherwise the console will reboot in %d seconds.", timeout / 10);
    if (svcCustomKernelCommand(1, 0x0d8000e8) & 0x01) {
      break;
    }
    if (--timeout == 0) {
      ((void (*)(int))0x1071D668)(1000);
      svcShutdown(1);
    }
    ((void (*)(int))0x1071D668)(100);
  }
  clearLine(30, 0x000000FF);
  clearLine(40, 0x000000FF);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wait_format_confirmation>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    $0x1071d668,%ebp
  push   %rbx
  mov    $0x258,%ebx
  sub    $0x8,%rsp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L27:
  sub    $0x1,%ebx
  jne    L25
  mov    $0x3e8,%edi
  call   *%rbp
  mov    $0x1,%edi
  call   <svcShutdown@plt>
L25:
  mov    $0x64,%edi
  call   *%rbp
L3:
  mov    %r13,%rdx
  mov    $0x1e,%esi
  mov    $0x14,%edi
  xor    %eax,%eax
  call   <_printf@plt>
  movslq %ebx,%rcx
  mov    %ebx,%eax
  mov    $0x28,%esi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%eax
  mov    $0x14,%edi
  mov    %r12,%rdx
  sar    $0x22,%rcx
  sub    %eax,%ecx
  xor    %eax,%eax
  call   <_printf@plt>
  mov    $0xd8000e8,%esi
  mov    $0x1,%edi
  call   <svcCustomKernelCommand@plt>
  test   $0x1,%al
  je     L27
  mov    $0xff,%esi
  mov    $0x1e,%edi
  call   <clearLine@plt>
  add    $0x8,%rsp
  mov    $0xff,%esi
  mov    $0x28,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <clearLine@plt>
```

tool_calls: name: parse_data
arguments: label: D19
type: string
name: parse_data
arguments: label: D7
type: string

tool: D19: No NAND dump detected. SD Format and complete NAND dump required.

tool: D7: Press the POWER button to format SD card otherwise the console will reboot in %d seconds.

assistant: ```c
void wait_format_confirmation(void) {
  int timeout = 600;
  while (1) {
    _printf(20, 30, "No NAND dump detected. SD Format and complete NAND dump required.");
    _printf(20, 40, "Press the POWER button to format SD card otherwise the console will reboot in %d seconds.", timeout / 10);
    if (svcCustomKernelCommand(1, 0x0d8000e8) & 0x01) {
      break;
    }
    if (--timeout == 0) {
      ((void (*)(int))0x1071D668)(1000);
      svcShutdown(1);
    }
    ((void (*)(int))0x1071D668)(100);
  }
  clearLine(30, 0x000000FF);
  clearLine(40, 0x000000FF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L27
  cmpl   $0x7ce,-0x8(%rbp)
  je     L12
  mov    $0x0,%eax
  call   <abort@plt>
L12:
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((no, noclone, optimize("-fno-tree-vectorize"))) check(unsigned *results) {
  unsigned sum = 0;
  for (int idx = 0; idx < (int)1000; idx++)
    sum += results[idx];
  if (sum != 1998)
    abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check>:
  endbr64
  lea    0xfa0(%rdi),%rdx
  mov    $0x0,%eax
L0:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L0
  cmp    $0x7ce,%eax
  jne    L2
  ret
L2:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __attribute__((no, noclone, optimize("-fno-tree-vectorize"))) check(unsigned *results) {
  unsigned sum = 0;
  for (int idx = 0; idx < (int)1000; idx++)
    sum += results[idx];
  if (sum != 1998)
    abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check>:
  endbr64
  lea    0xfa0(%rdi),%rdx
  xor    %eax,%eax
  nopl   (%rax)
L3:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L3
  cmp    $0x7ce,%eax
  jne    L15
  ret
L15:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no, noclone, optimize("-fno-tree-vectorize"))) check(unsigned *results) {
  unsigned sum = 0;
  for (int idx = 0; idx < (int)1000; idx++)
    sum += results[idx];
  if (sum != 1998)
    abort();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check>:
  endbr64
  lea    0xfa0(%rdi),%rdx
  xor    %eax,%eax
  nopl   (%rax)
L11:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdi,%rdx
  jne    L11
  cmp    $0x7ce,%eax
  jne    L4
  ret
L4:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no, noclone, optimize("-fno-tree-vectorize"))) check(unsigned *results) {
  unsigned sum = 0;
  for (int idx = 0; idx < (int)1000; idx++)
    sum += results[idx];
  if (sum != 1998)
    abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<allocstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *allocstring(int length) {
  char *str_ptr;
  str_ptr = (char *)malloc(length + 1);
  return (str_ptr);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<allocstring>:
  endbr64
  sub    $0x8,%rsp
  add    $0x1,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *allocstring(int length) {
  char *str_ptr;
  str_ptr = (char *)malloc(length + 1);
  return (str_ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<allocstring>:
  endbr64
  add    $0x1,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
char *allocstring(int length) {
  char *str_ptr;
  str_ptr = (char *)malloc(length + 1);
  return (str_ptr);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<allocstring>:
  endbr64
  add    $0x1,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
char *allocstring(int length) {
  char *str_ptr;
  str_ptr = (char *)malloc(length + 1);
  return (str_ptr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L16:
  addl   $0x1,-0x4(%rbp)
L8:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int log_2(int value) {
  int i = 0;
  while (value >>= 1)
    i++;
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_2>:
  endbr64
  sar    %edi
  je     L19
  mov    $0x0,%eax
L18:
  add    $0x1,%eax
  sar    %edi
  jne    L18
  ret
L19:
  mov    %edi,%eax
  ret
```

assistant: ```c
int log_2(int value) {
  int i = 0;
  while (value >>= 1)
    i++;
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log_2>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L18
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%eax
  sar    %edi
  jne    L6
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
int log_2(int value) {
  int i = 0;
  while (value >>= 1)
    i++;
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<log_2>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L17
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%eax
  sar    %edi
  jne    L6
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
int log_2(int value) {
  int i = 0;
  while (value >>= 1)
    i++;
  return (i);
}
```