ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lastoccurence@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string
name: parse_data
arguments: label: D21
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string

tool: D1: Enter s1

tool: D21: enter s2

tool: D7: the last occurence is at %d


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  int pos;
  puts("Enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  pos = lastoccurence(s1, s2);
  printf("the last occurence is at %d\n", pos);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lastoccurence@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D24
type_guessed: string

tool: D9: Enter s1

tool: D7: enter s2

tool: D24: the last occurence is at %d


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  int pos;
  puts("Enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  pos = lastoccurence(s1, s2);
  printf("the last occurence is at %d\n", pos);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<LOG_MESSAGE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <open_logfile@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: [D] %s


assistant: ```c
void LOG_MESSAGE(char *msg) {
  FILE *f;
  f = open_logfile();
  fprintf(f, "[D] %s\n", msg);
  fclose(f);
}
```
user: What is the c source code of the assembly code below:

```asm
<LOG_MESSAGE>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <open_logfile@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: [D] %s


assistant: ```c
void LOG_MESSAGE(char *msg) {
  FILE *f;
  f = open_logfile();
  fprintf(f, "[D] %s\n", msg);
  fclose(f);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LOG_MESSAGE>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <open_logfile@plt>
  mov    %r12,%rdx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: [D] %s


assistant: ```c
void LOG_MESSAGE(char *msg) {
  FILE *f;
  f = open_logfile();
  fprintf(f, "[D] %s\n", msg);
  fclose(f);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<LOG_MESSAGE>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <open_logfile@plt>
  mov    %r12,%rdx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: [D] %s


assistant: ```c
void LOG_MESSAGE(char *msg) {
  FILE *f;
  f = open_logfile();
  fprintf(f, "[D] %s\n", msg);
  fclose(f);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x24(%rbp)
  je     L2
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L2:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L17
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L17:
  mov    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  jmp    L20
L7:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
L20:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L7
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
type_guessed: string
name: disassemble_data
arguments: label: D16
type_guessed: string
name: disassemble_data
arguments: label: D15
type_guessed: string
name: disassemble_data
arguments: label: D23
type_guessed: string

tool: D19: Usage:  dump filename

tool: D16: rb

tool: D15: main(), cannot open %s for input


tool: D23: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  FILE *inp;
  if (argc != 2) {
    printf("Usage:  dump filename\n");
    exit(0);
  }
  if ((inp = fopen(argv[1], "rb")) == NULL) {
    printf("main(), cannot open %s for input\n", argv[1]);
    exit(0);
  }
  fread(&i, sizeof(int), 1, inp);
  while (!feof(inp)) {
    printf("%d\n", i);
    fread(&i, sizeof(int), 1, inp);
  }
  fclose(inp);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L5
L12:
  mov    0x8(%rbp),%rdi
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
L56:
  lea    0x4(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  lea    D20(%rip),%rbp
  jmp    L11
L5:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L12
L28:
  mov    0x8(%rbp),%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L56
L15:
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
L11:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L15
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x1,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string
name: extract_symbolic_data
arguments: data_label: D20
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D35
data_type: string

tool: D0: rb

tool: D20: %d


tool: D2: Usage:  dump filename

tool: D35: main(), cannot open %s for input


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  FILE *inp;
  if (argc != 2) {
    printf("Usage:  dump filename\n");
    exit(0);
  }
  if ((inp = fopen(argv[1], "rb")) == NULL) {
    printf("main(), cannot open %s for input\n", argv[1]);
    exit(0);
  }
  fread(&i, sizeof(int), 1, inp);
  while (!feof(inp)) {
    printf("%d\n", i);
    fread(&i, sizeof(int), 1, inp);
  }
  fclose(inp);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L7
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
L7:
  mov    0x8(%rbx),%rdi
  lea    D34(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L54
L39:
  lea    0x4(%rsp),%rbx
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  lea    D24(%rip),%r12
  call   <fread@plt>
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L25:
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    %rbx,%rdi
  mov    $0x4,%esi
  call   <fread@plt>
L5:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L25
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  mov    0x8(%rbx),%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L39
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D34
type_guessed: string
name: unpack_data
arguments: data_tag: D24
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string

tool: D8: Usage:  dump filename

tool: D34: rb

tool: D24: %d


tool: D25: main(), cannot open %s for input


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  FILE *inp;
  if (argc != 2) {
    printf("Usage:  dump filename\n");
    exit(0);
  }
  if ((inp = fopen(argv[1], "rb")) == NULL) {
    printf("main(), cannot open %s for input\n", argv[1]);
    exit(0);
  }
  fread(&i, sizeof(int), 1, inp);
  while (!feof(inp)) {
    printf("%d\n", i);
    fread(&i, sizeof(int), 1, inp);
  }
  fclose(inp);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L44
  lea    D37(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
L44:
  mov    0x8(%rbx),%rdi
  lea    D35(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L26
L36:
  lea    0x4(%rsp),%rbx
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  lea    D2(%rip),%r12
  call   <fread@plt>
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    %rbx,%rdi
  mov    $0x4,%esi
  call   <fread@plt>
L45:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L0
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    0x8(%rbx),%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L36
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D37
datatype: string
name: disassemble_data
arguments: tag: D35
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string

tool: D37: Usage:  dump filename

tool: D35: rb

tool: D2: %d


tool: D0: main(), cannot open %s for input


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  FILE *inp;
  if (argc != 2) {
    printf("Usage:  dump filename\n");
    exit(0);
  }
  if ((inp = fopen(argv[1], "rb")) == NULL) {
    printf("main(), cannot open %s for input\n", argv[1]);
    exit(0);
  }
  fread(&i, sizeof(int), 1, inp);
  while (!feof(inp)) {
    printf("%d\n", i);
    fread(&i, sizeof(int), 1, inp);
  }
  fclose(inp);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  call   <fork@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <gettid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%edi
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string

tool: D1: [%d]: pid = %d, tid = %d, ppid = %d, forkret = %d


assistant: ```c
int main() {
  int fret = fork();
  int pid = getpid();
  int ppid = getppid();
  int tid = gettid();
  printf("[%d]: pid = %d, tid = %d, ppid = %d, forkret = %d\n", pid, pid, tid, ppid, fret);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <fork@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <gettid@plt>
  mov    %eax,%ecx
  mov    %r12d,%r9d
  mov    %ebp,%r8d
  mov    %ebx,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: [%d]: pid = %d, tid = %d, ppid = %d, forkret = %d


assistant: ```c
int main() {
  int fret = fork();
  int pid = getpid();
  int ppid = getppid();
  int tid = gettid();
  printf("[%d]: pid = %d, tid = %d, ppid = %d, forkret = %d\n", pid, pid, tid, ppid, fret);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <fork@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <gettid@plt>
  mov    %r12d,%r9d
  mov    %ebx,%r8d
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %eax,%ecx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: [%d]: pid = %d, tid = %d, ppid = %d, forkret = %d


assistant: ```c
int main() {
  int fret = fork();
  int pid = getpid();
  int ppid = getppid();
  int tid = gettid();
  printf("[%d]: pid = %d, tid = %d, ppid = %d, forkret = %d\n", pid, pid, tid, ppid, fret);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <fork@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <gettid@plt>
  mov    %r12d,%r9d
  mov    %ebx,%r8d
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %eax,%ecx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: [%d]: pid = %d, tid = %d, ppid = %d, forkret = %d


assistant: ```c
int main() {
  int fret = fork();
  int pid = getpid();
  int ppid = getppid();
  int tid = gettid();
  printf("[%d]: pid = %d, tid = %d, ppid = %d, forkret = %d\n", pid, pid, tid, ppid, fret);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<phex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <phex>
L7:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cltq
  lea    D0(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D18
data_type: string

tool: D0: 0123456789ABCDEF

tool: D18: %c

assistant: ```c
void phex(int v) {
  int t = v / 16;
  if (t != 0)
    phex(t);
  printf("%c", "0123456789ABCDEF"[v % 16]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<phex>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0xf(%rdi),%edi
  test   %ebx,%ebx
  cmovns %ebx,%edi
  sar    $0x4,%edi
  jne    L14
L10:
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  add    %eax,%ebx
  and    $0xf,%ebx
  sub    %eax,%ebx
  movslq %ebx,%rbx
  lea    D17(%rip),%rax
  movsbl (%rax,%rbx,1),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
L14:
  call   <phex>
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D17: 0123456789ABCDEF

tool: D4: %c

assistant: ```c
void phex(int v) {
  int t = v / 16;
  if (t != 0)
    phex(t);
  printf("%c", "0123456789ABCDEF"[v % 16]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<phex>:
  endbr64
  push   %r13
  lea    0xf(%rdi),%eax
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x4,%eax
  jne    L56
L33:
  mov    %ebx,%eax
  mov    %r12,%rdi
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  add    %eax,%ebx
  and    $0xf,%ebx
  sub    %eax,%ebx
  movslq %ebx,%rbx
  movsbl 0x0(%rbp,%rbx,1),%esi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L56:
  mov    %eax,%r13d
  lea    0xf(%rax),%eax
  test   %r13d,%r13d
  cmovns %r13d,%eax
  sar    $0x4,%eax
  jne    L31
L41:
  mov    %r13d,%edx
  mov    %r12,%rdi
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  lea    0x0(%r13,%rdx,1),%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cltq
  movsbl 0x0(%rbp,%rax,1),%esi
  call   <printf@plt>
  jmp    L33
  xchg   %ax,%ax
L31:
  test   %eax,%eax
  lea    0xf(%rax),%edi
  cmovns %eax,%edi
  sar    $0x4,%edi
  jne    L48
L53:
  cltd
  lea    D18(%rip),%rbp
  lea    D12(%rip),%r12
  shr    $0x1c,%edx
  mov    %r12,%rdi
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cltq
  movsbl 0x0(%rbp,%rax,1),%esi
  call   <printf@plt>
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %eax,0xc(%rsp)
  call   <phex>
  mov    0xc(%rsp),%eax
  jmp    L53
```

tool_calls: name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D18
type: string

tool: D12: %c

tool: D18: 0123456789ABCDEF

assistant: ```c
void phex(int v) {
  int t = v / 16;
  if (t != 0)
    phex(t);
  printf("%c", "0123456789ABCDEF"[v % 16]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<phex>:
  endbr64
  push   %r13
  lea    0xf(%rdi),%eax
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x4,%eax
  jne    L41
L26:
  mov    %ebx,%eax
  mov    %r12,%rdi
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  add    %eax,%ebx
  and    $0xf,%ebx
  sub    %eax,%ebx
  movslq %ebx,%rbx
  movsbl 0x0(%rbp,%rbx,1),%esi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L41:
  mov    %eax,%r13d
  lea    0xf(%rax),%eax
  test   %r13d,%r13d
  cmovns %r13d,%eax
  sar    $0x4,%eax
  jne    L6
L30:
  mov    %r13d,%edx
  mov    %r12,%rdi
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  lea    0x0(%r13,%rdx,1),%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cltq
  movsbl 0x0(%rbp,%rax,1),%esi
  call   <printf@plt>
  jmp    L26
  xchg   %ax,%ax
L6:
  test   %eax,%eax
  lea    0xf(%rax),%edi
  cmovns %eax,%edi
  sar    $0x4,%edi
  jne    L58
L15:
  cltd
  lea    D2(%rip),%rbp
  lea    D20(%rip),%r12
  shr    $0x1c,%edx
  mov    %r12,%rdi
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cltq
  movsbl 0x0(%rbp,%rax,1),%esi
  call   <printf@plt>
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %eax,0xc(%rsp)
  call   <phex>
  mov    0xc(%rsp),%eax
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
data_type: string
name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D20: %c

tool: D2: 0123456789ABCDEF

assistant: ```c
void phex(int v) {
  int t = v / 16;
  if (t != 0)
    phex(t);
  printf("%c", "0123456789ABCDEF"[v % 16]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_lex_look_ahead_n_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x6c(%rbp)
  movl   $0x0,-0x70(%rbp)
  lea    -0x60(%rbp),%rcx
  lea    -0x70(%rbp),%rdx
  mov    -0x6c(%rbp),%esi
  mov    -0x68(%rbp),%rax
  mov    $0x50,%r9d
  mov    %rcx,%r8
  mov    $0x2,%ecx
  mov    %rax,%rdi
  call   <lex_look_ahead_n@plt>
  lea    -0x60(%rbp),%rax
  lea    D20(%rip),%rdx
  lea    D23(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <check_strs@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D20
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string

tool: D3: foo= 2;int b;

tool: D20: test_lex_look_ahead_n_1

tool: D23: =

assistant: ```c
void test_lex_look_ahead_n_1() {
  const char *input = "foo= 2;int b;";
  unsigned int len, pos;
  char result[80];
  len = strlen(input);
  pos = 0;
  lex_look_ahead_n(input, len, &pos, 2, result, sizeof(result));
  check_strs(result, "=", "test_lex_look_ahead_n_1");
}
```