ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<initalizeMatrix>:
  endbr64
  test   %esi,%esi
  jle    L16
  test   %edx,%edx
  jle    L16
  movslq %esi,%r8
  xor    %r9d,%r9d
  shl    $0x2,%r8
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L11:
  add    $0x1,%eax
  movl   $0x0,(%rcx)
  add    %r8,%rcx
  cmp    %eax,%edx
  jne    L11
  add    $0x1,%r9d
  add    $0x4,%rdi
  cmp    %r9d,%esi
  jne    L5
L16:
  ret
```

assistant: ```c
void initalizeMatrix(unsigned int *M, int nrow, int ncol) {
  int i, j;
  for (i = 0; i < nrow; ++i) {
    for (j = 0; j < ncol; ++j) {
      M[i + j * nrow] = 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memset(void *dstv, int fill, int n) {
  char *dst = dstv;
  for (int i = 0; i < n; ++i) {
    *dst++ = fill;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  jle    L2
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%rax
L3:
  add    $0x1,%rdi
  mov    %sil,-0x1(%rdi)
  cmp    %rax,%rdi
  jne    L3
L2:
  ret
```

assistant: ```c
void memset(void *dstv, int fill, int n) {
  char *dst = dstv;
  for (int i = 0; i < n; ++i) {
    *dst++ = fill;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memset>:
  endbr64
  test   %edx,%edx
  jle    L6
  movslq %edx,%rdx
  movsbl %sil,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
void memset(void *dstv, int fill, int n) {
  char *dst = dstv;
  for (int i = 0; i < n; ++i) {
    *dst++ = fill;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  jle    L6
  movslq %edx,%rdx
  movsbl %sil,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
void memset(void *dstv, int fill, int n) {
  char *dst = dstv;
  for (int i = 0; i < n; ++i) {
    *dst++ = fill;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode_block1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L1:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %ax,-0x10(%rbp)
  addq   $0x2,-0x28(%rbp)
  movzwl -0x10(%rbp),%eax
  test   %ax,%ax
  js     L49
  movzwl -0x10(%rbp),%eax
  add    %eax,%eax
  and    $0xffffff80,%eax
  mov    %ax,-0x12(%rbp)
  andw   $0x3f,-0x10(%rbp)
  movzwl -0x12(%rbp),%eax
  or     %ax,-0x10(%rbp)
  movzwl -0x10(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  movzwl -0x10(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x2,-0x38(%rbp)
  addl   $0x2,-0xc(%rbp)
  subl   $0x2,-0x2c(%rbp)
  jmp    L55
L49:
  movzwl -0x10(%rbp),%eax
  and    $0x1f,%eax
  mov    %ax,-0x12(%rbp)
  movzwl -0x10(%rbp),%eax
  sar    $0x5,%eax
  and    $0x3ff,%ax
  mov    %ax,-0x10(%rbp)
  subl   $0x2,-0x2c(%rbp)
  movzwl -0x10(%rbp),%eax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L58:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %ax,-0xe(%rbp)
  addq   $0x2,-0x8(%rbp)
  addq   $0x2,-0x38(%rbp)
  addl   $0x2,-0xc(%rbp)
  subw   $0x1,-0x12(%rbp)
  movzwl -0xe(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  sub    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  movzwl -0xe(%rbp),%edx
  mov    %dl,(%rax)
L16:
  cmpw   $0x0,-0x12(%rbp)
  jne    L58
L55:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L1
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int decode_block1(unsigned char *in, int length, unsigned char *out) {
  unsigned short t0, t1, t3;
  unsigned char *t2;
  int len = 0;
  while (length != 0) {
    t0 = (((in)[0] << 8) + ((in)[1]));
    in += 2;
    if ((t0 & 0x8000) == 0) {
      t1 = (t0 & 0xFFC0) << 1;
      t0 &= 0x3F;
      t0 = t0 | t1;
      do {
        (out)[0] = ((t0) >> 8) & 0xFF;
        (out)[1] = ((t0)) & 0xFF;
      } while (0);
      out += 2;
      len += 2;
      length -= 2;
    } else {
      t1 = t0 & 0x1F;
      t0 = (t0 & 0x7FFF) >> 5;
      length -= 2;
      t2 = out - t0;
      while (t1 != 0) {
        t3 = (((t2)[0] << 8) + ((t2)[1]));
        t2 += 2;
        out += 2;
        len += 2;
        t1 -= 1;
        do {
          (out - 2)[0] = ((t3) >> 8) & 0xFF;
          (out - 2)[1] = ((t3)) & 0xFF;
        } while (0);
      }
    }
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<decode_block1>:
  endbr64
  test   %esi,%esi
  je     L38
  push   %rbx
  mov    %rdx,%rax
  sub    $0x2,%esi
  mov    $0x0,%r8d
  jmp    L48
L16:
  lea    (%rdx,%rdx,1),%r9d
  mov    %esi,%r11d
  shr    $0x6,%r9w
  movzwl %r9w,%r9d
  mov    %rax,%rcx
  sub    %r9,%rcx
  and    $0x1f,%dx
  je     L1
  lea    -0x1(%rdx),%ebx
  movzwl %dx,%edx
  lea    (%rax,%rdx,2),%r10
L22:
  movzbl (%rcx),%r9d
  movzbl 0x1(%rcx),%edx
  add    $0x2,%rcx
  add    $0x2,%rax
  mov    %r9b,-0x2(%rax)
  mov    %dl,-0x1(%rax)
  cmp    %r10,%rax
  jne    L22
  movzwl %bx,%eax
  lea    0x2(%r8,%rax,2),%r8d
  mov    %r10,%rax
L1:
  sub    $0x2,%esi
  test   %r11d,%r11d
  je     L37
L48:
  movzbl (%rdi),%edx
  shl    $0x8,%edx
  movzbl 0x1(%rdi),%ecx
  add    $0x2,%rdi
  add    %cx,%dx
  js     L16
  lea    (%rdx,%rdx,1),%ecx
  and    $0xffffff80,%ecx
  and    $0x3f,%edx
  or     %ecx,%edx
  movzbl %ch,%ebx
  mov    %bl,(%rax)
  mov    %dl,0x1(%rax)
  add    $0x2,%rax
  add    $0x2,%r8d
  mov    %esi,%r11d
  jmp    L1
L38:
  mov    %esi,%eax
  ret
L37:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
int decode_block1(unsigned char *in, int length, unsigned char *out) {
  unsigned short t0, t1, t3;
  unsigned char *t2;
  int len = 0;
  while (length != 0) {
    t0 = (((in)[0] << 8) + ((in)[1]));
    in += 2;
    if ((t0 & 0x8000) == 0) {
      t1 = (t0 & 0xFFC0) << 1;
      t0 &= 0x3F;
      t0 = t0 | t1;
      do {
        (out)[0] = ((t0) >> 8) & 0xFF;
        (out)[1] = ((t0)) & 0xFF;
      } while (0);
      out += 2;
      len += 2;
      length -= 2;
    } else {
      t1 = t0 & 0x1F;
      t0 = (t0 & 0x7FFF) >> 5;
      length -= 2;
      t2 = out - t0;
      while (t1 != 0) {
        t3 = (((t2)[0] << 8) + ((t2)[1]));
        t2 += 2;
        out += 2;
        len += 2;
        t1 -= 1;
        do {
          (out - 2)[0] = ((t3) >> 8) & 0xFF;
          (out - 2)[1] = ((t3)) & 0xFF;
        } while (0);
      }
    }
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decode_block1>:
  endbr64
  mov    %rdx,%rax
  test   %esi,%esi
  je     L7
  lea    -0x2(%rsi),%edx
  xor    %r8d,%r8d
  lea    0x2(%rdi,%rdx,1),%rsi
  jmp    L38
  nopl   0x0(%rax)
L17:
  add    %ecx,%ecx
  and    $0x3f,%edx
  add    $0x2,%rax
  add    $0x2,%r8d
  and    $0xffffff80,%ecx
  or     %edx,%ecx
  rol    $0x8,%cx
  mov    %cx,-0x2(%rax)
L67:
  cmp    %rdi,%rsi
  je     L43
L38:
  movzbl (%rdi),%edx
  movzbl 0x1(%rdi),%ecx
  add    $0x2,%rdi
  shl    $0x8,%edx
  add    %ecx,%edx
  movzwl %dx,%ecx
  test   %dx,%dx
  jns    L17
  sar    $0x5,%ecx
  mov    %rax,%r9
  and    $0x3ff,%ecx
  sub    %rcx,%r9
  and    $0x1f,%dx
  je     L67
  lea    -0x1(%rdx),%r11d
  movzwl %dx,%edx
  lea    (%rax,%rdx,2),%r10
  nopw   0x0(%rax,%rax,1)
L24:
  movzbl (%r9),%ecx
  movzbl 0x1(%r9),%edx
  add    $0x2,%rax
  add    $0x2,%r9
  mov    %cl,-0x2(%rax)
  mov    %dl,-0x1(%rax)
  cmp    %r10,%rax
  jne    L24
  movzwl %r11w,%edx
  lea    0x2(%r8,%rdx,2),%r8d
  cmp    %rdi,%rsi
  jne    L38
L43:
  mov    %r8d,%eax
  ret
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int decode_block1(unsigned char *in, int length, unsigned char *out) {
  unsigned short t0, t1, t3;
  unsigned char *t2;
  int len = 0;
  while (length != 0) {
    t0 = (((in)[0] << 8) + ((in)[1]));
    in += 2;
    if ((t0 & 0x8000) == 0) {
      t1 = (t0 & 0xFFC0) << 1;
      t0 &= 0x3F;
      t0 = t0 | t1;
      do {
        (out)[0] = ((t0) >> 8) & 0xFF;
        (out)[1] = ((t0)) & 0xFF;
      } while (0);
      out += 2;
      len += 2;
      length -= 2;
    } else {
      t1 = t0 & 0x1F;
      t0 = (t0 & 0x7FFF) >> 5;
      length -= 2;
      t2 = out - t0;
      while (t1 != 0) {
        t3 = (((t2)[0] << 8) + ((t2)[1]));
        t2 += 2;
        out += 2;
        len += 2;
        t1 -= 1;
        do {
          (out - 2)[0] = ((t3) >> 8) & 0xFF;
          (out - 2)[1] = ((t3)) & 0xFF;
        } while (0);
      }
    }
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<w_quick_sort_string_restore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void w_quick_sort_string_restore(void *data, int i, void *key) {
  char **k = (char **)key;
  char **str = (char **)data;
  str[i] = *k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<w_quick_sort_string_restore>:
  endbr64
  mov    (%rdx),%rax
  movslq %esi,%rsi
  mov    %rax,(%rdi,%rsi,8)
  ret
```

assistant: ```c
void w_quick_sort_string_restore(void *data, int i, void *key) {
  char **k = (char **)key;
  char **str = (char **)data;
  str[i] = *k;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<w_quick_sort_string_restore>:
  endbr64
  mov    (%rdx),%rax
  movslq %esi,%rsi
  mov    %rax,(%rdi,%rsi,8)
  ret
```

assistant: ```c
void w_quick_sort_string_restore(void *data, int i, void *key) {
  char **k = (char **)key;
  char **str = (char **)data;
  str[i] = *k;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<w_quick_sort_string_restore>:
  endbr64
  mov    (%rdx),%rax
  movslq %esi,%rsi
  mov    %rax,(%rdi,%rsi,8)
  ret
```

assistant: ```c
void w_quick_sort_string_restore(void *data, int i, void *key) {
  char **k = (char **)key;
  char **str = (char **)data;
  str[i] = *k;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L26
L12:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  jbe    L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string

tool: D28: Please enter positive integer: 

tool: D21: %d

tool: D15: %d 

assistant: ```c
int main() {
  size_t n;
  printf("Please enter positive integer: ");
  scanf("%d", &n);
  int i;
  for (i = 1; i <= n; i++) {
    printf("%d ", i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,(%rsp)
  je     L2
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
L29:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  add    $0x2,%rax
  cmp    %rax,(%rsp)
  jae    L29
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D3
type: string

tool: D12: Please enter positive integer: 

tool: D24: %d

tool: D3: %d 

assistant: ```c
int main() {
  size_t n;
  printf("Please enter positive integer: ");
  scanf("%d", &n);
  int i;
  for (i = 1; i <= n; i++) {
    printf("%d ", i);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,(%rsp)
  je     L21
  xor    %ebx,%ebx
  lea    D2(%rip),%rbp
  nopl   (%rax)
L18:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  add    $0x2,%rax
  cmp    %rax,(%rsp)
  jae    L18
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D1
type: string
name: retrieve_data
arguments: data_label: D2
type: string

tool: D5: Please enter positive integer: 

tool: D1: %d

tool: D2: %d 

assistant: ```c
int main() {
  size_t n;
  printf("Please enter positive integer: ");
  scanf("%d", &n);
  int i;
  for (i = 1; i <= n; i++) {
    printf("%d ", i);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,(%rsp)
  je     L1
  xor    %ebx,%ebx
  lea    D5(%rip),%rbp
  nopl   (%rax)
L7:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  add    $0x2,%rax
  cmp    %rax,(%rsp)
  jae    L7
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D1: Please enter positive integer: 

tool: D21: %d

tool: D5: %d 

assistant: ```c
int main() {
  size_t n;
  printf("Please enter positive integer: ");
  scanf("%d", &n);
  int i;
  for (i = 1; i <= n; i++) {
    printf("%d ", i);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<dinverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <dvector@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <lvector@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <dludcmp@plt>
  movq   $0x1,-0x20(%rbp)
  jmp    L2
L53:
  movq   $0x1,-0x28(%rbp)
  jmp    L25
L61:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x28(%rbp)
L25:
  mov    -0x28(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jle    L61
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <dlubksb@plt>
  movq   $0x1,-0x28(%rbp)
  jmp    L56
L7:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x28(%rbp)
L56:
  mov    -0x28(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jle    L7
  addq   $0x1,-0x20(%rbp)
L2:
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jle    L53
  mov    -0x40(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <free_lvector@plt>
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <free_dvector@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: f64

tool: D6: 1

assistant: ```c
void dinverse(double **a, long n, double **y) {
  double d, *col;
  long i, j, *indx;
  col = dvector(1, n);
  indx = lvector(1, n);
  dludcmp(a, n, indx, &d);
  for (j = 1; j <= n; j++) {
    for (i = 1; i <= n; i++)
      col[i] = 0.0;
    col[j] = 1.0;
    dlubksb(a, n, indx, col);
    for (i = 1; i <= n; i++)
      y[i][j] = col[i];
  }
  free_lvector(indx, 1, n);
  free_dvector(col, 1, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dinverse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r15
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <dvector@plt>
  mov    %rax,%rbx
  mov    %r15,%rsi
  mov    $0x1,%edi
  call   <lvector@plt>
  mov    %rax,(%rsp)
  lea    0x10(%rsp),%rcx
  mov    %rax,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <dludcmp@plt>
  test   %r15,%r15
  jle    L3
  lea    0x8(%rbx,%r15,8),%r13
  mov    $0x1,%r14d
L32:
  lea    0x8(%rbx),%rax
L21:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %r13,%rax
  jne    L21
  lea    0x0(,%r14,8),%rbp
  mov    D8(%rip),%rax
  mov    %rax,(%rbx,%r14,8)
  mov    %rbx,%rcx
  mov    (%rsp),%rdx
  mov    %r15,%rsi
  mov    0x8(%rsp),%rdi
  call   <dlubksb@plt>
  lea    0x1(%r15),%rcx
  mov    $0x1,%eax
L29:
  movsd  (%rbx,%rax,8),%xmm0
  mov    (%r12,%rax,8),%rdx
  movsd  %xmm0,(%rdx,%rbp,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L29
  add    $0x1,%r14
  cmp    %r14,%r15
  jge    L32
L3:
  mov    %r15,%rdx
  mov    $0x1,%esi
  mov    (%rsp),%rdi
  call   <free_lvector@plt>
  mov    %r15,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <free_dvector@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: f64

tool: D8: 1

assistant: ```c
void dinverse(double **a, long n, double **y) {
  double d, *col;
  long i, j, *indx;
  col = dvector(1, n);
  indx = lvector(1, n);
  dludcmp(a, n, indx, &d);
  for (j = 1; j <= n; j++) {
    for (i = 1; i <= n; i++)
      col[i] = 0.0;
    col[j] = 1.0;
    dlubksb(a, n, indx, col);
    for (i = 1; i <= n; i++)
      y[i][j] = col[i];
  }
  free_lvector(indx, 1, n);
  free_dvector(col, 1, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dinverse>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <dvector@plt>
  mov    %r12,%rsi
  mov    $0x1,%edi
  mov    %rax,%rbp
  call   <lvector@plt>
  lea    0x20(%rsp),%rcx
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %rax,%rdx
  mov    %rax,%r13
  call   <dludcmp@plt>
  test   %r12,%r12
  jle    L4
  lea    0x0(,%r12,8),%rax
  mov    $0x1,%r15d
  lea    0x1(%r12),%r14
  mov    %rax,0x10(%rsp)
  lea    0x8(%rbp),%rax
  mov    %rax,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x10(%rsp),%rdx
  mov    0x18(%rsp),%rdi
  xor    %esi,%esi
  call   <memset@plt>
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    D5(%rip),%rax
  lea    0x0(,%r15,8),%r8
  mov    %r12,%rsi
  mov    %r8,(%rsp)
  mov    %rax,0x0(%rbp,%r15,8)
  call   <dlubksb@plt>
  mov    (%rsp),%r8
  mov    $0x1,%eax
  nopl   (%rax)
L37:
  movsd  0x0(%rbp,%rax,8),%xmm0
  mov    (%rbx,%rax,8),%rdx
  add    $0x1,%rax
  movsd  %xmm0,(%rdx,%r8,1)
  cmp    %rax,%r14
  jne    L37
  add    $0x1,%r15
  cmp    %r15,%r12
  jge    L1
L4:
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <free_lvector@plt>
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <free_dvector@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: f64

tool: D5: 1

assistant: ```c
void dinverse(double **a, long n, double **y) {
  double d, *col;
  long i, j, *indx;
  col = dvector(1, n);
  indx = lvector(1, n);
  dludcmp(a, n, indx, &d);
  for (j = 1; j <= n; j++) {
    for (i = 1; i <= n; i++)
      col[i] = 0.0;
    col[j] = 1.0;
    dlubksb(a, n, indx, col);
    for (i = 1; i <= n; i++)
      y[i][j] = col[i];
  }
  free_lvector(indx, 1, n);
  free_dvector(col, 1, n);
}
```