user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  lea    -0x48(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  nopw   0x0(%rax,%rax,1)
L103:
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rsi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L130
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%r8
  mov    %rsp,%rsi
  mov    %rsp,%r13
  lea    (%rcx,%r8,1),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L84
L131:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L131
L84:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L90
  orq    $0x0,-0x8(%rsp,%rdx,1)
L90:
  lea    0xf(,%r8,4),%rax
  mov    %rsp,%rsi
  mov    %rsp,%r12
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L30
L56:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L56
L30:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L98
L46:
  mov    %rsp,-0x58(%rbp)
  test   %rcx,%rcx
  je     L23
  mov    %r12,%r15
  xor    %r14d,%r14d
L97:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <scanf@plt>
  add    $0x4,%r15
  cmp    %r14,-0x48(%rbp)
  ja     L97
  mov    -0x40(%rbp),%r8
L23:
  test   %r8,%r8
  je     L53
  mov    -0x58(%rbp),%r14
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <scanf@plt>
  mov    -0x40(%rbp),%r8
  add    $0x4,%r14
  cmp    %r15,%r8
  ja     L10
L53:
  mov    -0x58(%rbp),%rdx
  mov    -0x48(%rbp),%rsi
  mov    %r8,%rcx
  mov    %r12,%rdi
  call   <merge@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    -0x40(%rbp),%rsi
  mov    %r12,%rdi
  add    -0x48(%rbp),%rsi
  call   <print_arr@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rsp
  jmp    L103
  nopl   0x0(%rax)
L130:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L98:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L46
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D20
type: string
name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D32
type: string
name: unpack_data
arguments: data_label: D33
type: string

tool: D20: Enter A's size, followed by B's size, followed by the elements of A and then the elements of B.


tool: D4: %d

tool: D19: %zu%zu

tool: D32: Merged:


tool: D33: 


assistant: ```c
int main(void) {
  printf("Enter A's size, followed by B's size, followed by the elements of A and then "
         "the elements of B.\n");
  size_t a_sz, b_sz;
  while (scanf("%zu%zu", &a_sz, &b_sz) == 2) {
    int A[a_sz + b_sz];
    int B[b_sz];
    size_t i;
    for (i = 0; i < a_sz; i++) {
      scanf("%d", &A[i]);
    }
    for (i = 0; i < b_sz; i++) {
      scanf("%d", &B[i]);
    }
    merge(A, a_sz, B, b_sz);
    printf("Merged:\n");
    print_arr(A, a_sz + b_sz);
    printf("\n");
  }
  return 0;
}
```