ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L7
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D18(%rip),%r12
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%edx
  add    $0x4,%rbp
  cmp    %ebx,%edx
  jg     L23
L7:
  sub    $0x1,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <findMin@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D18: %d

tool: D1: 
%d


assistant: ```c
int main() {
  int low = 0, high = 0;
  scanf("%d", &high);
  int i, *arr;
  arr = (int *)malloc(high * sizeof(int));
  for (i = 0; i < high; i++)
    scanf("%d", &arr[i]);
  printf("\n%d\n", findMin(arr, 0, high - 1));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  mov    %rax,%r13
  test   %edx,%edx
  jle    L21
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L3
L21:
  xor    %esi,%esi
  sub    $0x1,%edx
  mov    %r13,%rdi
  call   <findMin@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type_guessed: string
name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D17: %d

tool: D8: 
%d


assistant: ```c
int main() {
  int low = 0, high = 0;
  scanf("%d", &high);
  int i, *arr;
  arr = (int *)malloc(high * sizeof(int));
  for (i = 0; i < high; i++)
    scanf("%d", &arr[i]);
  printf("\n%d\n", findMin(arr, 0, high - 1));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  mov    %rax,%r13
  test   %edx,%edx
  jle    L25
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L14
L25:
  xor    %esi,%esi
  sub    $0x1,%edx
  mov    %r13,%rdi
  call   <findMin@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D12
datatype: string
name: read_data
arguments: tag: D1
datatype: string

tool: D12: %d

tool: D1: 
%d


assistant: ```c
int main() {
  int low = 0, high = 0;
  scanf("%d", &high);
  int i, *arr;
  arr = (int *)malloc(high * sizeof(int));
  for (i = 0; i < high; i++)
    scanf("%d", &arr[i]);
  printf("\n%d\n", findMin(arr, 0, high - 1));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gen_brune_stf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %ecx,%r13d
  mov    %r8,%r15
  mov    %ecx,%esi
  mov    %rdx,%rdi
  call   <zapit@plt>
  mov    $0x1,%edi
  call   <exp@plt>
  movss  (%r12),%xmm1
  movss  (%r15),%xmm2
  cvtss2sd %xmm0,%xmm0
  mulsd  D25(%rip),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm1,%xmm3
  mulsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  D14(%rip),%xmm0
  divss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  D1(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  cmp    %r13d,%r12d
  cmovg  %r13d,%r12d
  test   %r12d,%r12d
  je     L34
  movss  (%rbx),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rsp)
  divss  %xmm1,%xmm2
  movss  %xmm2,0xc(%rsp)
  jle    L17
  lea    -0x1(%r12),%r14d
  mov    %r12d,%r13d
  mov    $0x0,%ebx
L49:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  movss  0xc(%rsp),%xmm4
  mulss  %xmm4,%xmm0
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  mov    %ebx,%eax
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%edi
  call   <exp@plt>
  mulss  0x4(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L49
  movss  (%r15),%xmm2
  mov    %rbp,%rax
  lea    0x4(%rbp,%r14,4),%rdx
  pxor   %xmm0,%xmm0
L18:
  movaps %xmm2,%xmm1
  mulss  (%rax),%xmm1
  addss  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L18
  pxor   %xmm1,%xmm1
  ucomiss %xmm0,%xmm1
  mov    $0x0,%eax
  cmovae %eax,%r12d
L34:
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    $0x0,%r12d
  jmp    L34
```

tool_calls: name: retrieve_data
arguments: label: D25
datatype: f64
name: retrieve_data
arguments: label: D14
datatype: f32
name: retrieve_data
arguments: label: D1
datatype: f64

tool: D25: 1.745

tool: D14: 3

tool: D1: 0.5

assistant: ```c
int gen_brune_stf(float *slip, float *t0, float *stf, int nt, float *dt) {
  int it, nstf;
  float t95, tend, sfac, tfac;
  float sum;
  zapit(stf, nt);
  t95 = 1.745 * exp(1.0) * (*t0);
  tend = 3.0 * t95;
  nstf = (int)((tend) / (*dt) + 0.5);
  if (nstf > nt)
    nstf = nt;
  if (nstf == 0)
    return (0);
  sfac = (*slip) / (*t0);
  tfac = (*dt) / (*t0);
  for (it = 0; it < nstf; it++)
    stf[it] = sfac * (it * tfac) * exp(-it * tfac);
  sum = 0.0;
  for (it = 0; it < nstf; it++)
    sum = sum + (*dt) * stf[it];
  if (sum <= 0.0)
    return (0);
  return (nstf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_brune_stf>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    %ecx,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x18,%rsp
  call   <zapit@plt>
  mov    $0x1,%edi
  call   <exp@plt>
  movss  (%r12),%xmm1
  pxor   %xmm3,%xmm3
  movss  (%r15),%xmm2
  cvtss2sd %xmm0,%xmm0
  mulsd  D20(%rip),%xmm0
  cvtss2sd %xmm1,%xmm3
  mulsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  D17(%rip),%xmm0
  divss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  D26(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  cmp    %r13d,%r12d
  cmovg  %r13d,%r12d
  test   %r12d,%r12d
  je     L22
  movss  (%rbx),%xmm0
  divss  %xmm1,%xmm2
  divss  %xmm1,%xmm0
  movss  %xmm2,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  jle    L22
  lea    -0x1(%r12),%r14d
  mov    %r12d,%r13d
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L6:
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm4
  mov    %ebx,%eax
  cvtsi2ss %ebx,%xmm0
  neg    %eax
  mulss  %xmm4,%xmm0
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%edi
  call   <exp@plt>
  mulss  0x4(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L6
  pxor   %xmm3,%xmm3
  movss  (%r15),%xmm2
  mov    %rbp,%rax
  lea    0x4(%rbp,%r14,4),%rdx
  movaps %xmm3,%xmm0
  nopl   0x0(%rax,%rax,1)
L13:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L13
  comiss %xmm0,%xmm3
  jae    L22
L8:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L22:
  xor    %r12d,%r12d
  jmp    L8
```

tool_calls: name: read_data
arguments: data_tag: D20
type: f64
name: read_data
arguments: data_tag: D17
type: f32
name: read_data
arguments: data_tag: D26
type: f64

tool: D20: 1.745

tool: D17: 3

tool: D26: 0.5

assistant: ```c
int gen_brune_stf(float *slip, float *t0, float *stf, int nt, float *dt) {
  int it, nstf;
  float t95, tend, sfac, tfac;
  float sum;
  zapit(stf, nt);
  t95 = 1.745 * exp(1.0) * (*t0);
  tend = 3.0 * t95;
  nstf = (int)((tend) / (*dt) + 0.5);
  if (nstf > nt)
    nstf = nt;
  if (nstf == 0)
    return (0);
  sfac = (*slip) / (*t0);
  tfac = (*dt) / (*t0);
  for (it = 0; it < nstf; it++)
    stf[it] = sfac * (it * tfac) * exp(-it * tfac);
  sum = 0.0;
  for (it = 0; it < nstf; it++)
    sum = sum + (*dt) * stf[it];
  if (sum <= 0.0)
    return (0);
  return (nstf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max_steps@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string

tool: D2: %d %d

tool: D5: %d


assistant: ```c
void main() {
  int rows, cols;
  scanf("%d %d", &rows, &cols);
  printf("%d\n", max_steps(rows, cols));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <max_steps@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D0: %d %d

tool: D4: %d


assistant: ```c
void main() {
  int rows, cols;
  scanf("%d %d", &rows, &cols);
  printf("%d\n", max_steps(rows, cols));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <max_steps@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D19
data_type: string

tool: D3: %d %d

tool: D19: %d


assistant: ```c
void main() {
  int rows, cols;
  scanf("%d %d", &rows, &cols);
  printf("%d\n", max_steps(rows, cols));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <max_steps@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D3: %d %d

tool: D1: %d


assistant: ```c
void main() {
  int rows, cols;
  scanf("%d %d", &rows, &cols);
  printf("%d\n", max_steps(rows, cols));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<matrix_mult>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%r8
  mov    %r8,%rax
  imul   %r8,%rax
  imul   %r8,%rax
  add    %rax,%rax
  mov    %rax,-0x8(%rsp)
  test   %edi,%edi
  jle    L18
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%r15
  shl    $0x3,%r8
  lea    -0x1(%rdi),%eax
  lea    0x8(%rdx,%rax,8),%rcx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %edi,%r9d
  neg    %r9
  shl    $0x3,%r9
L15:
  lea    (%r9,%rcx,1),%rax
  mov    %rsi,%rdx
L23:
  movsd  (%rax),%xmm0
  movsd  (%rdx),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  add    %r8,%rdx
  cmp    %rcx,%rax
  jne    L23
  lea    0x1(%rbp),%eax
  add    $0x8,%rsi
  add    %r8,%rcx
  cmp    %eax,%edi
  je     L49
  mov    %eax,%ebp
  jmp    L15
L49:
  cltq
  mov    %rax,-0x10(%rsp)
  mov    %ebp,%eax
  lea    0x8(%r13,%rax,8),%r11
  mov    %ebp,%eax
  shr    $0x2,%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  mov    %rax,-0x18(%rsp)
  mov    %r14,%r10
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  add    $0x20,%r14
L74:
  lea    0x0(%r13,%rbx,8),%rsi
  mov    %r15,%rdi
  mov    -0x18(%rsp),%rax
  add    %rbx,%rax
  lea    (%r14,%rax,8),%rcx
L73:
  mov    %rsi,%r9
  movsd  (%rsi),%xmm0
  mov    %rdi,%rdx
  mov    %r10,%rax
L1:
  movsd  (%rax),%xmm1
  mulsd  (%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x8(%rax),%xmm1
  mulsd  0x8(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rax),%xmm1
  mulsd  0x10(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x18(%rax),%xmm1
  mulsd  0x18(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x20,%rax
  add    $0x20,%rdx
  cmp    %rcx,%rax
  jne    L1
  movsd  %xmm0,(%r9)
  add    $0x8,%rsi
  add    %r8,%rdi
  cmp    %r11,%rsi
  jne    L73
  lea    0x1(%r12),%eax
  add    %r8,%r11
  add    %r8,%r10
  add    -0x10(%rsp),%rbx
  cmp    %r12d,%ebp
  je     L18
  mov    %eax,%r12d
  jmp    L74
L18:
  mov    -0x8(%rsp),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
size_t matrix_mult(int len, double *restrict a, double *restrict b, double *restrict c) {
  int i, j, k, l, m;
  size_t fpops;
  double temp;
  fpops = (size_t)2 * len * len * len;
  for (i = 0; i < len; i++) {
    for (j = 0; j < len; j++) {
      temp = b[i * len + j];
      b[i * len + j] = b[j * len + i];
      b[j * len + i] = temp;
    }
  }
  for (i = 0; i < len; i++) {
    for (j = 0; j < len; j++) {
      for (k = 0; k < len; k += 4) {
        a[i * len + j] += b[i * len + k] * c[j * len + k];
        a[i * len + j] += b[i * len + k + 1] * c[j * len + k + 1];
        a[i * len + j] += b[i * len + k + 2] * c[j * len + k + 2];
        a[i * len + j] += b[i * len + k + 3] * c[j * len + k + 3];
      }
    }
  }
  return fpops;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<matrix_mult>:
  endbr64
  push   %r15
  push   %r14
  movslq %edi,%r14
  mov    %r14,%rax
  push   %r13
  imul   %r14,%rax
  push   %r12
  push   %rbp
  push   %rbx
  imul   %r14,%rax
  mov    %rcx,-0x10(%rsp)
  add    %rax,%rax
  mov    %rax,-0x8(%rsp)
  test   %edi,%edi
  jle    L78
  lea    -0x1(%rdi),%ebp
  mov    $0xfffffffffffffff8,%r10
  mov    %rsi,%r13
  mov    %rdx,%r9
  mov    %rbp,%r11
  shl    $0x3,%rbp
  mov    %rdx,%rsi
  xor    %ebx,%ebx
  lea    0x0(,%r14,8),%r8
  lea    0x8(%rdx,%rbp,1),%rcx
  sub    %rbp,%r10
  nopl   0x0(%rax)
L1:
  lea    (%r10,%rcx,1),%rax
  mov    %rsi,%rdx
  nopw   0x0(%rax,%rax,1)
L66:
  movsd  (%rdx),%xmm1
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  %xmm1,-0x8(%rax)
  movsd  %xmm0,(%rdx)
  add    %r8,%rdx
  cmp    %rax,%rcx
  jne    L66
  lea    0x1(%rbx),%eax
  add    $0x8,%rsi
  add    %r8,%rcx
  cmp    %eax,%edi
  je     L6
  mov    %eax,%ebx
  jmp    L1
L78:
  mov    -0x8(%rsp),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  shr    $0x2,%r11d
  lea    0x8(%r13,%rbp,1),%r10
  lea    0x20(%r9),%r15
  xor    %ebp,%ebp
  mov    %r11d,%r12d
  xor    %r11d,%r11d
  shl    $0x2,%r12
  nopl   0x0(%rax,%rax,1)
L39:
  lea    (%r11,%r12,1),%rax
  mov    -0x10(%rsp),%rdi
  lea    0x0(%r13,%r11,8),%rsi
  lea    (%r15,%rax,8),%rcx
  nopw   0x0(%rax,%rax,1)
L46:
  movsd  (%rsi),%xmm0
  mov    %rdi,%rdx
  mov    %r9,%rax
  nopw   0x0(%rax,%rax,1)
L73:
  movsd  (%rax),%xmm1
  mulsd  (%rdx),%xmm1
  add    $0x20,%rax
  add    $0x20,%rdx
  addsd  %xmm1,%xmm0
  movsd  -0x18(%rax),%xmm1
  mulsd  -0x18(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  -0x10(%rax),%xmm1
  mulsd  -0x10(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  mulsd  -0x8(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L73
  movsd  %xmm0,(%rsi)
  add    $0x8,%rsi
  add    %r8,%rdi
  cmp    %rsi,%r10
  jne    L46
  lea    0x1(%rbp),%eax
  add    %r8,%r10
  add    %r8,%r9
  add    %r14,%r11
  cmp    %ebx,%ebp
  je     L78
  mov    %eax,%ebp
  jmp    L39
```

assistant: ```c
size_t matrix_mult(int len, double *restrict a, double *restrict b, double *restrict c) {
  int i, j, k, l, m;
  size_t fpops;
  double temp;
  fpops = (size_t)2 * len * len * len;
  for (i = 0; i < len; i++) {
    for (j = 0; j < len; j++) {
      temp = b[i * len + j];
      b[i * len + j] = b[j * len + i];
      b[j * len + i] = temp;
    }
  }
  for (i = 0; i < len; i++) {
    for (j = 0; j < len; j++) {
      for (k = 0; k < len; k += 4) {
        a[i * len + j] += b[i * len + k] * c[j * len + k];
        a[i * len + j] += b[i * len + k + 1] * c[j * len + k + 1];
        a[i * len + j] += b[i * len + k + 2] * c[j * len + k + 2];
        a[i * len + j] += b[i * len + k + 3] * c[j * len + k + 3];
      }
    }
  }
  return fpops;
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix_mult>:
  endbr64
  movslq %edi,%r9
  push   %r14
  push   %r13
  push   %r12
  mov    %r9,%r12
  imul   %r9,%r12
  push   %rbp
  push   %rbx
  imul   %r9,%r12
  add    %r12,%r12
  test   %r9d,%r9d
  jle    L28
  mov    %r9,%r8
  mov    $0xfffffffffffffff8,%r11
  mov    %rsi,%rbp
  mov    %rcx,%rbx
  lea    -0x1(%r8),%r14d
  mov    %rdx,%rsi
  shl    $0x3,%r9
  mov    %rdx,%r13
  mov    %r14,%rax
  shl    $0x3,%r14
  xor    %r10d,%r10d
  lea    0x8(%rdx,%r14,1),%rdi
  sub    %r14,%r11
  nopw   0x0(%rax,%rax,1)
L37:
  lea    (%rdi,%r11,1),%rdx
  mov    %r13,%rcx
  nop
L25:
  movsd  (%rcx),%xmm1
  movsd  (%rdx),%xmm0
  add    $0x8,%rdx
  movsd  %xmm1,-0x8(%rdx)
  movsd  %xmm0,(%rcx)
  add    %r9,%rcx
  cmp    %rdx,%rdi
  jne    L25
  lea    0x1(%r10),%edx
  add    $0x8,%r13
  add    %r9,%rdi
  cmp    %edx,%r8d
  je     L11
  mov    %edx,%r10d
  jmp    L37
L28:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  shr    $0x2,%eax
  lea    0x8(%rbp,%r14,1),%rbp
  xor    %r13d,%r13d
  lea    0x1(%rax),%edi
  nopl   0x0(%rax)
L14:
  lea    0x0(%rbp,%r11,1),%r8
  mov    %rbx,%rcx
  nopl   0x0(%rax,%rax,1)
L45:
  movsd  (%r8),%xmm1
  xor    %eax,%eax
  xor    %edx,%edx
  nopl   0x0(%rax)
L7:
  movupd (%rcx,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm4
  add    $0x1,%edx
  movupd 0x10(%rcx,%rax,1),%xmm2
  movupd 0x10(%rsi,%rax,1),%xmm5
  add    $0x20,%rax
  mulpd  %xmm4,%xmm0
  mulpd  %xmm5,%xmm2
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  unpckhpd %xmm2,%xmm2
  addsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  cmp    %edx,%edi
  ja     L7
  movsd  %xmm1,(%r8)
  add    $0x8,%r8
  add    %r9,%rcx
  cmp    %rbp,%r8
  jne    L45
  lea    0x1(%r13),%eax
  add    %r9,%rbp
  add    %r9,%rsi
  cmp    %r10d,%r13d
  je     L28
  mov    %eax,%r13d
  jmp    L14
```

assistant: ```c
size_t matrix_mult(int len, double *restrict a, double *restrict b, double *restrict c) {
  int i, j, k, l, m;
  size_t fpops;
  double temp;
  fpops = (size_t)2 * len * len * len;
  for (i = 0; i < len; i++) {
    for (j = 0; j < len; j++) {
      temp = b[i * len + j];
      b[i * len + j] = b[j * len + i];
      b[j * len + i] = temp;
    }
  }
  for (i = 0; i < len; i++) {
    for (j = 0; j < len; j++) {
      for (k = 0; k < len; k += 4) {
        a[i * len + j] += b[i * len + k] * c[j * len + k];
        a[i * len + j] += b[i * len + k + 1] * c[j * len + k + 1];
        a[i * len + j] += b[i * len + k + 2] * c[j * len + k + 2];
        a[i * len + j] += b[i * len + k + 3] * c[j * len + k + 3];
      }
    }
  }
  return fpops;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_and_clear_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
L9:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  not    %rax
  and    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <atomic_cmpset_long@plt>
  test   %rax,%rax
  je     L9
  mov    -0x8(%rbp),%rax
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
long test_and_clear_bit(long bit, long *var) {
  long val;
  bit = 1 << bit;
  do {
    val = *(volatile long *)var;
  } while (atomic_cmpset_long(var, val, val & ~bit) == 0);
  return !!(val & bit);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_and_clear_bit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    $0x1,%r13d
  mov    %edi,%ecx
  shl    %cl,%r13d
  movslq %r13d,%r13
  mov    %r13,%r12
  not    %r12
L2:
  mov    0x0(%rbp),%rbx
  mov    %r12,%rdx
  and    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <atomic_cmpset_long@plt>
  test   %rax,%rax
  je     L2
  test   %rbx,%r13
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long test_and_clear_bit(long bit, long *var) {
  long val;
  bit = 1 << bit;
  do {
    val = *(volatile long *)var;
  } while (atomic_cmpset_long(var, val, val & ~bit) == 0);
  return !!(val & bit);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_and_clear_bit>:
  endbr64
  push   %r13
  mov    %edi,%ecx
  mov    $0x1,%r13d
  push   %r12
  shl    %cl,%r13d
  push   %rbp
  movslq %r13d,%r13
  mov    %rsi,%rbp
  push   %rbx
  mov    %r13,%r12
  not    %r12
  sub    $0x8,%rsp
  nopl   (%rax)
L8:
  mov    0x0(%rbp),%rbx
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  and    %r12,%rdx
  call   <atomic_cmpset_long@plt>
  test   %rax,%rax
  je     L8
  xor    %eax,%eax
  test   %rbx,%r13
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long test_and_clear_bit(long bit, long *var) {
  long val;
  bit = 1 << bit;
  do {
    val = *(volatile long *)var;
  } while (atomic_cmpset_long(var, val, val & ~bit) == 0);
  return !!(val & bit);
}
```