ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<decipher3>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  pxor   %xmm0,%xmm0
  push   %r14
  mov    %rdx,%r14
  mov    $0x10,%edx
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r15d,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  add    %r15d,%ebp
  sar    %ebp
  sub    $0x448,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x10(%rsp),%r13
  mov    %rdi,%rsi
  lea    0x30(%rsp),%rbx
  mov    %r13,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x438(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <strncpy@plt>
  cmp    $0x1,%r15d
  jle    L26
  nop
L48:
  mov    %r14,%rdi
  add    $0x2,%r14
  call   <asc_bcd@plt>
  mov    %al,(%rbx,%r12,1)
  add    $0x1,%r12
  cmp    %r12d,%ebp
  jg     L48
  test   %r15d,%r15d
  lea    0xf(%r15),%r12d
  cmovns %r15d,%r12d
  sar    $0x4,%r12d
  cmp    $0xf,%r15d
  jle    L26
  mov    0x8(%rsp),%r14
  xor    %r15d,%r15d
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %r14,%rcx
  mov    %rbx,%rsi
  mov    %r13,%rdx
  mov    $0x1,%edi
  add    $0x1,%r15d
  add    $0x8,%rbx
  add    $0x8,%r14
  call   <TDes@plt>
  cmp    %r15d,%r12d
  jg     L2
L26:
  mov    0x8(%rsp),%rax
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
  mov    0x438(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x448,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decipher3(const unsigned char *key, unsigned char *plain_text, unsigned char *crypted_text, int length) {
  unsigned char t_crypt[1024];
  int i;
  unsigned char usekey[32];
  for (i = 0; i < 32; i++)
    usekey[i] = '\0';
  strncpy((char *)usekey, (char *)key, 16);
  for (i = 0; i < length / 2; i++)
    t_crypt[i] = asc_bcd(crypted_text + i * 2);
  for (i = 0; i < length / 16; i++)
    TDes(1, &t_crypt[8 * i], usekey, &plain_text[8 * i]);
  plain_text[length / 2] = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_no_hits_all_pseudo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x59424752,-0x10(%rbp)
  movl   $0x52594247,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <hits@plt>
  test   %rax,%rax
  jne    L5
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pseudo@plt>
  cmp    $0x4,%eax
  jne    L5
  mov    $0x1,%eax
  jmp    L28
L5:
  mov    $0x0,%eax
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int test_no_hits_all_pseudo() {
  char actual[] = {'R', 'G', 'B', 'Y'};
  char guess[] = {'G', 'B', 'Y', 'R'};
  return 0 == hits(actual, guess, 4) && 4 == pseudo(actual, guess, 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_no_hits_all_pseudo>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x59424752,(%rsp)
  movl   $0x52594247,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x4,%edx
  call   <hits@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L12
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
L12:
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x4,%edx
  call   <pseudo@plt>
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L13
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_no_hits_all_pseudo() {
  char actual[] = {'R', 'G', 'B', 'Y'};
  char guess[] = {'G', 'B', 'Y', 'R'};
  return 0 == hits(actual, guess, 4) && 4 == pseudo(actual, guess, 4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_no_hits_all_pseudo>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  movl   $0x59424752,(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movl   $0x52594247,0x4(%rsp)
  call   <hits@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L20
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pseudo@plt>
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L19
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_no_hits_all_pseudo() {
  char actual[] = {'R', 'G', 'B', 'Y'};
  char guess[] = {'G', 'B', 'Y', 'R'};
  return 0 == hits(actual, guess, 4) && 4 == pseudo(actual, guess, 4);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_no_hits_all_pseudo>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  movl   $0x59424752,(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movl   $0x52594247,0x4(%rsp)
  call   <hits@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L22
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L22:
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pseudo@plt>
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L16
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_no_hits_all_pseudo() {
  char actual[] = {'R', 'G', 'B', 'Y'};
  char guess[] = {'G', 'B', 'Y', 'R'};
  return 0 == hits(actual, guess, 4) && 4 == pseudo(actual, guess, 4);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tcc_v4l2_ioctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int tcc_v4l2_ioctl(int fd, int request, void *arg) {
  int ret;
  ret = ioctl(fd, request, arg);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tcc_v4l2_ioctl>:
  endbr64
  sub    $0x8,%rsp
  call   <ioctl@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int tcc_v4l2_ioctl(int fd, int request, void *arg) {
  int ret;
  ret = ioctl(fd, request, arg);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tcc_v4l2_ioctl>:
  endbr64
  jmp    1050 <ioctl@plt>
```

assistant: ```c
int tcc_v4l2_ioctl(int fd, int request, void *arg) {
  int ret;
  ret = ioctl(fd, request, arg);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tcc_v4l2_ioctl>:
  endbr64
  jmp    1050 <ioctl@plt>
```

assistant: ```c
int tcc_v4l2_ioctl(int fd, int request, void *arg) {
  int ret;
  ret = ioctl(fd, request, arg);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<epr_cut_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <epr_create_string@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void epr_cut_string(char **sub_str, const char *str, int start, int length) {
  *sub_str = epr_create_string(length);
  strncpy(*sub_str, str + start, length);
  *sub_str[length] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<epr_cut_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %ecx,%ebx
  mov    %ecx,%edi
  call   <epr_create_string@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%r13)
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %ebx,%edx
  call   <strncpy@plt>
  movslq %ebx,%rbx
  mov    0x0(%r13,%rbx,8),%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void epr_cut_string(char **sub_str, const char *str, int start, int length) {
  *sub_str = epr_create_string(length);
  strncpy(*sub_str, str + start, length);
  *sub_str[length] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<epr_cut_string>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %ecx,%rbx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <epr_create_string@plt>
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %ebx,%edx
  mov    %rax,0x0(%r13)
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    0x0(%r13,%rbx,8),%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void epr_cut_string(char **sub_str, const char *str, int start, int length) {
  *sub_str = epr_create_string(length);
  strncpy(*sub_str, str + start, length);
  *sub_str[length] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<epr_cut_string>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %ecx,%rbx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <epr_create_string@plt>
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %ebx,%edx
  mov    %rax,0x0(%r13)
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    0x0(%r13,%rbx,8),%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void epr_cut_string(char **sub_str, const char *str, int start, int length) {
  *sub_str = epr_create_string(length);
  strncpy(*sub_str, str + start, length);
  *sub_str[length] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<callee4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%r13d
  mov    %r13d,%edi
  call   <increment@plt>
  mov    %eax,%r12d
  mov    %r12d,%edi
  call   <increment@plt>
  mov    %eax,%ebx
  mov    %ebx,%edi
  call   <increment@plt>
  mov    %eax,%r14d
  lea    0x0(%r13,%r12,1),%eax
  add    %ebx,%eax
  add    %r14d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int callee4(int n) {
  register int l1 = increment(n);
  register int l2 = increment(l1);
  register int l3 = increment(l2);
  register int l4 = increment(l3);
  return l1 + l2 + l3 + l4;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<callee4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <increment@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%edx
  lea    (%rbx,%r12,1),%eax
  add    %ebp,%eax
  add    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int callee4(int n) {
  register int l1 = increment(n);
  register int l2 = increment(l1);
  register int l3 = increment(l2);
  register int l4 = increment(l3);
  return l1 + l2 + l3 + l4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<callee4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <increment@plt>
  mov    %eax,%r8d
  lea    (%rbx,%r12,1),%eax
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  add    %r8d,%eax
  ret
```

assistant: ```c
int callee4(int n) {
  register int l1 = increment(n);
  register int l2 = increment(l1);
  register int l3 = increment(l2);
  register int l4 = increment(l3);
  return l1 + l2 + l3 + l4;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<callee4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <increment@plt>
  mov    %eax,%r8d
  lea    (%rbx,%r12,1),%eax
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  add    %r8d,%eax
  ret
```

assistant: ```c
int callee4(int n) {
  register int l1 = increment(n);
  register int l2 = increment(l1);
  register int l3 = increment(l2);
  register int l4 = increment(l3);
  return l1 + l2 + l3 + l4;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5f5e100,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,-0x8(%rbp)
  jmp    L38
L7:
  mov    $0x0,%eax
  call   <xorshf96@plt>
  mov    $0x0,%eax
  call   <xorshf96@plt>
  subl   $0x1,-0x8(%rbp)
L38:
  cmpl   $0x0,-0x8(%rbp)
  jne    L7
  movl   $0x0,-0x8(%rbp)
  jmp    L51
L74:
  mov    $0x0,%eax
  call   <xorshf96@plt>
  test   %rax,%rax
  js     L67
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L58
L67:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L58:
  movsd  D20(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  D12(%rip),%xmm1
  subsd  %xmm1,%xmm0
  comisd D20(%rip),%xmm0
  jae    L76
  cvttsd2si %xmm0,%rax
  jmp    L48
L76:
  movsd  D20(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  movabs $0x8000000000000000,%rdx
  xor    %rdx,%rax
L48:
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L51:
  cmpl   $0x13,-0x8(%rbp)
  jbe    L74
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D20
type: byte[16]
name: read_data
arguments: data_label: D12
type: f64
name: read_data
arguments: data_label: D15
type: string

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D12: 1

tool: D15: %21.018lf


assistant: ```c
int main(void) {
  unsigned i, quantity = 100e6;
  float f;
  for (i = quantity / 2; i; i--) {
    xorshf96();
    xorshf96();
  }
  for (i = 0; i < 20; i++) {
    printf("%21.018lf\n", xorshf96() / ((~0UL >> 1) * 1.0) - 1.0);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<count_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L29:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L29
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L31
L4:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <rawmemchr@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L31:
  leave
  ret
```

assistant: ```c
void count_args(char *argv[], int *argc, size_t *arglen) {
  int i = 0;
  while (argv[i])
    i++;
  *argc = i;
  if (!i) {
    *arglen = 0;
    return;
  }
  *arglen = (size_t)rawmemchr(argv[i - 1], 0) - (size_t)argv[0] + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_args>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  cmpq   $0x0,(%rdi)
  je     L32
  mov    %rdi,%rbx
  mov    $0x1,%eax
L23:
  mov    %eax,%edx
  lea    0x0(,%rax,8),%rcx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rbx,%rax,8)
  jne    L23
  mov    %edx,(%rsi)
  test   %edx,%edx
  je     L5
  mov    -0x8(%rbx,%rcx,1),%rdi
  mov    $0x0,%esi
  call   <rawmemchr@plt>
  sub    (%rbx),%rax
  lea    0x1(%rax),%rax
  jmp    L18
L32:
  movl   $0x0,(%rsi)
L5:
  mov    $0x0,%eax
L18:
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void count_args(char *argv[], int *argc, size_t *arglen) {
  int i = 0;
  while (argv[i])
    i++;
  *argc = i;
  if (!i) {
    *arglen = 0;
    return;
  }
  *arglen = (size_t)rawmemchr(argv[i - 1], 0) - (size_t)argv[0] + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_args>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  je     L18
  mov    %rdi,%rbx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %eax,%edi
  lea    0x0(,%rax,8),%rcx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rbx,%rax,8)
  jne    L15
  mov    %edi,(%rsi)
  mov    -0x8(%rbx,%rcx,1),%rdi
  xor    %esi,%esi
  call   <rawmemchr@plt>
  sub    (%rbx),%rax
  add    $0x1,%rax
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  movl   $0x0,(%rsi)
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void count_args(char *argv[], int *argc, size_t *arglen) {
  int i = 0;
  while (argv[i])
    i++;
  *argc = i;
  if (!i) {
    *arglen = 0;
    return;
  }
  *arglen = (size_t)rawmemchr(argv[i - 1], 0) - (size_t)argv[0] + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<count_args>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  je     L19
  mov    %rdi,%rbx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%edi
  lea    0x0(,%rax,8),%rcx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rbx,%rax,8)
  jne    L5
  mov    %edi,(%rsi)
  mov    -0x8(%rbx,%rcx,1),%rdi
  xor    %esi,%esi
  call   <rawmemchr@plt>
  sub    (%rbx),%rax
  add    $0x1,%rax
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  movl   $0x0,(%rsi)
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void count_args(char *argv[], int *argc, size_t *arglen) {
  int i = 0;
  while (argv[i])
    i++;
  *argc = i;
  if (!i) {
    *arglen = 0;
    return;
  }
  *arglen = (size_t)rawmemchr(argv[i - 1], 0) - (size_t)argv[0] + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SrvCon_OFILM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  cmpb   $0x0,-0x8(%rbp)
  je     L2
  cmpb   $0x0,-0x4(%rbp)
  jne    L59
  mov    $0x3,%esi
  mov    $0x170,%edi
  call   <RegWriteA_Ofilm@plt>
  mov    $0x0,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_Ofilm@plt>
  jmp    L31
L59:
  mov    $0x3,%esi
  mov    $0x171,%edi
  call   <RegWriteA_Ofilm@plt>
  mov    $0x0,%esi
  mov    $0x11b5,%edi
  call   <RamWrite32A_Ofilm@plt>
  jmp    L31
L2:
  cmpb   $0x0,-0x4(%rbp)
  jne    L49
  mov    $0x2,%esi
  mov    $0x170,%edi
  call   <RegWriteA_Ofilm@plt>
  mov    $0x0,%esi
  mov    $0x1477,%edi
  call   <RamWrite32A_Ofilm@plt>
  jmp    L31
L49:
  mov    $0x2,%esi
  mov    $0x171,%edi
  call   <RegWriteA_Ofilm@plt>
  mov    $0x0,%esi
  mov    $0x14f7,%edi
  call   <RamWrite32A_Ofilm@plt>
L31:
  nop
  leave
  ret
```

assistant: ```c
void SrvCon_OFILM(unsigned char UcDirSel_OFILM, unsigned char UcSwcCon_OFILM) {
  if (UcSwcCon_OFILM) {
    if (!UcDirSel_OFILM) {
      RegWriteA_Ofilm(0x0170, 0x03);
      RamWrite32A_Ofilm(0x10B5, 0x00000000);
    } else {
      RegWriteA_Ofilm(0x0171, 0x03);
      RamWrite32A_Ofilm(0x11B5, 0x00000000);
    }
  } else {
    if (!UcDirSel_OFILM) {
      RegWriteA_Ofilm(0x0170, 0x02);
      RamWrite32A_Ofilm(0x1477, 0x00000000);
    } else {
      RegWriteA_Ofilm(0x0171, 0x02);
      RamWrite32A_Ofilm(0x14F7, 0x00000000);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SrvCon_OFILM>:
  endbr64
  sub    $0x8,%rsp
  test   %sil,%sil
  je     L7
  test   %dil,%dil
  jne    L9
  mov    $0x3,%esi
  mov    $0x170,%edi
  call   <RegWriteA_Ofilm@plt>
  mov    $0x0,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_Ofilm@plt>
L34:
  add    $0x8,%rsp
  ret
L9:
  mov    $0x3,%esi
  mov    $0x171,%edi
  call   <RegWriteA_Ofilm@plt>
  mov    $0x0,%esi
  mov    $0x11b5,%edi
  call   <RamWrite32A_Ofilm@plt>
  jmp    L34
L7:
  test   %dil,%dil
  jne    L41
  mov    $0x2,%esi
  mov    $0x170,%edi
  call   <RegWriteA_Ofilm@plt>
  mov    $0x0,%esi
  mov    $0x1477,%edi
  call   <RamWrite32A_Ofilm@plt>
  jmp    L34
L41:
  mov    $0x2,%esi
  mov    $0x171,%edi
  call   <RegWriteA_Ofilm@plt>
  mov    $0x0,%esi
  mov    $0x14f7,%edi
  call   <RamWrite32A_Ofilm@plt>
  jmp    L34
```

assistant: ```c
void SrvCon_OFILM(unsigned char UcDirSel_OFILM, unsigned char UcSwcCon_OFILM) {
  if (UcSwcCon_OFILM) {
    if (!UcDirSel_OFILM) {
      RegWriteA_Ofilm(0x0170, 0x03);
      RamWrite32A_Ofilm(0x10B5, 0x00000000);
    } else {
      RegWriteA_Ofilm(0x0171, 0x03);
      RamWrite32A_Ofilm(0x11B5, 0x00000000);
    }
  } else {
    if (!UcDirSel_OFILM) {
      RegWriteA_Ofilm(0x0170, 0x02);
      RamWrite32A_Ofilm(0x1477, 0x00000000);
    } else {
      RegWriteA_Ofilm(0x0171, 0x02);
      RamWrite32A_Ofilm(0x14F7, 0x00000000);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SrvCon_OFILM>:
  endbr64
  sub    $0x8,%rsp
  test   %sil,%sil
  je     L16
  mov    $0x3,%esi
  test   %dil,%dil
  jne    L4
  mov    $0x170,%edi
  call   <RegWriteA_Ofilm@plt>
  xor    %esi,%esi
  mov    $0x10b5,%edi
  add    $0x8,%rsp
  jmp    1070 <RamWrite32A_Ofilm@plt>
  nopl   0x0(%rax)
L16:
  mov    $0x2,%esi
  test   %dil,%dil
  jne    L0
  mov    $0x170,%edi
  call   <RegWriteA_Ofilm@plt>
  xor    %esi,%esi
  mov    $0x1477,%edi
  add    $0x8,%rsp
  jmp    1070 <RamWrite32A_Ofilm@plt>
  nopl   0x0(%rax)
L0:
  mov    $0x171,%edi
  call   <RegWriteA_Ofilm@plt>
  xor    %esi,%esi
  mov    $0x14f7,%edi
  add    $0x8,%rsp
  jmp    1070 <RamWrite32A_Ofilm@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x171,%edi
  call   <RegWriteA_Ofilm@plt>
  xor    %esi,%esi
  mov    $0x11b5,%edi
  add    $0x8,%rsp
  jmp    1070 <RamWrite32A_Ofilm@plt>
```

assistant: ```c
void SrvCon_OFILM(unsigned char UcDirSel_OFILM, unsigned char UcSwcCon_OFILM) {
  if (UcSwcCon_OFILM) {
    if (!UcDirSel_OFILM) {
      RegWriteA_Ofilm(0x0170, 0x03);
      RamWrite32A_Ofilm(0x10B5, 0x00000000);
    } else {
      RegWriteA_Ofilm(0x0171, 0x03);
      RamWrite32A_Ofilm(0x11B5, 0x00000000);
    }
  } else {
    if (!UcDirSel_OFILM) {
      RegWriteA_Ofilm(0x0170, 0x02);
      RamWrite32A_Ofilm(0x1477, 0x00000000);
    } else {
      RegWriteA_Ofilm(0x0171, 0x02);
      RamWrite32A_Ofilm(0x14F7, 0x00000000);
    }
  }
}
```