ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strtotime>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  call   <strptime@plt>
  mov    %rbp,%rdi
  call   <mktime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: %d/%m/%Y %H:%M:%S

assistant: ```c
time_t strtotime(const char *s) {
  struct tm mytm;
  time_t t;
  strptime(s, "%d/%m/%Y %H:%M:%S", &mytm);
  t = mktime(&mytm);
  return t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtotime>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  call   <strptime@plt>
  mov    %rbp,%rdi
  call   <mktime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d/%m/%Y %H:%M:%S

assistant: ```c
time_t strtotime(const char *s) {
  struct tm mytm;
  time_t t;
  strptime(s, "%d/%m/%Y %H:%M:%S", &mytm);
  t = mktime(&mytm);
  return t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<LCDRasterConfigSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shl    $0xc,%eax
  mov    -0x4(%rbp),%edx
  add    $0x28,%edx
  movslq %edx,%rdx
  or     -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LCDRasterConfigSet(uint32_t ui32Base, uint32_t ui32Config, uint8_t ui8PalLoadDelay) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000028))) = (ui32Config | ((uint32_t)ui8PalLoadDelay << 12));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<LCDRasterConfigSet>:
  endbr64
  add    $0x28,%edi
  movslq %edi,%rdi
  shl    $0xc,%edx
  or     %esi,%edx
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void LCDRasterConfigSet(uint32_t ui32Base, uint32_t ui32Config, uint8_t ui8PalLoadDelay) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000028))) = (ui32Config | ((uint32_t)ui8PalLoadDelay << 12));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<LCDRasterConfigSet>:
  endbr64
  add    $0x28,%edi
  shl    $0xc,%edx
  movslq %edi,%rdi
  or     %esi,%edx
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void LCDRasterConfigSet(uint32_t ui32Base, uint32_t ui32Config, uint8_t ui8PalLoadDelay) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000028))) = (ui32Config | ((uint32_t)ui8PalLoadDelay << 12));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<LCDRasterConfigSet>:
  endbr64
  add    $0x28,%edi
  shl    $0xc,%edx
  movslq %edi,%rdi
  or     %esi,%edx
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void LCDRasterConfigSet(uint32_t ui32Base, uint32_t ui32Config, uint8_t ui8PalLoadDelay) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000028))) = (ui32Config | ((uint32_t)ui8PalLoadDelay << 12));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_collapse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x10,%r13d
  jmp    L6
L59:
  sub    $0x1,%r13d
  je     L5
L6:
  mov    $0x10,%r12d
L0:
  mov    $0x10,%ebp
L48:
  mov    $0x10,%ebx
L45:
  mov    $0x0,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L45
  sub    $0x1,%ebp
  jne    L48
  sub    $0x1,%r12d
  jne    L0
  jmp    L59
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp parallel for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp parallel for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_collapse>:
  endbr64
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L5:
  mov    $0x10,%r12d
L14:
  mov    $0x10,%ebp
  nop
L13:
  mov    $0x10,%ebx
  nopl   (%rax)
L23:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L23
  sub    $0x1,%ebp
  jne    L13
  sub    $0x1,%r12d
  jne    L14
  sub    $0x1,%r13d
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp parallel for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp parallel for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_collapse>:
  endbr64
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L27:
  mov    $0x10,%r12d
L19:
  mov    $0x10,%ebp
  nop
L7:
  mov    $0x10,%ebx
  nopl   (%rax)
L26:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L26
  sub    $0x1,%ebp
  jne    L7
  sub    $0x1,%r12d
  jne    L19
  sub    $0x1,%r13d
  jne    L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp parallel for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp parallel for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xml_escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L100
L124:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  jne    L142
  addl   $0x5,-0x24(%rbp)
  jmp    L94
L142:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  je     L46
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L89
L46:
  addl   $0x4,-0x24(%rbp)
  jmp    L94
L89:
  addl   $0x1,-0x24(%rbp)
L94:
  addq   $0x1,-0x20(%rbp)
L100:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L124
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L61
L83:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  jne    L2
  mov    -0x18(%rbp),%rax
  lea    D20(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0x5,-0x18(%rbp)
  jmp    L43
L2:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  jne    L48
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0x4,-0x18(%rbp)
  jmp    L43
L48:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L120
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0x4,-0x18(%rbp)
  jmp    L43
L120:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L43:
  addq   $0x1,-0x10(%rbp)
L61:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L83
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D20
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string

tool: D20: &amp;

tool: D5: &lt;

tool: D3: &gt;

assistant: ```c
char *xml_escape(const char *str) {
  int len = 0;
  for (const char *cur = str; *cur; ++cur) {
    if (*cur == '&') {
      len += 5;
    } else if (*cur == '<' || *cur == '>') {
      len += 4;
    } else {
      len++;
    }
  }
  char *result = malloc(len + 1);
  char *end = result;
  for (const char *cur = str; *cur; ++cur) {
    if (*cur == '&') {
      strcpy(end, "&amp;");
      end += 5;
    } else if (*cur == '<') {
      strcpy(end, "&lt;");
      end += 4;
    } else if (*cur == '>') {
      strcpy(end, "&gt;");
      end += 4;
    } else {
      *end++ = *cur;
    }
  }
  *end = 0;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xml_escape>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L117
  mov    %rdi,%rdx
  mov    $0x0,%edi
  jmp    L63
L41:
  add    $0x5,%edi
L70:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L75
L63:
  cmp    $0x26,%al
  je     L41
  and    $0xfffffffd,%eax
  lea    0x4(%rdi),%ecx
  add    $0x1,%edi
  cmp    $0x3c,%al
  cmove  %ecx,%edi
  jmp    L70
L117:
  mov    $0x0,%edi
L75:
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  test   %al,%al
  je     L103
  mov    %r12,%rbp
  lea    D17(%rip),%r15
  lea    D10(%rip),%r14
  lea    D8(%rip),%r13
  jmp    L32
L84:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x5,%rbp
L46:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L138
L32:
  cmp    $0x26,%al
  je     L84
  cmp    $0x3c,%al
  je     L9
  cmp    $0x3e,%al
  je     L55
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L46
L9:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x4,%rbp
  jmp    L46
L55:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x4,%rbp
  jmp    L46
L103:
  mov    %r12,%rbp
L138:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D17: &gt;

tool: D10: &lt;

tool: D8: &amp;

assistant: ```c
char *xml_escape(const char *str) {
  int len = 0;
  for (const char *cur = str; *cur; ++cur) {
    if (*cur == '&') {
      len += 5;
    } else if (*cur == '<' || *cur == '>') {
      len += 4;
    } else {
      len++;
    }
  }
  char *result = malloc(len + 1);
  char *end = result;
  for (const char *cur = str; *cur; ++cur) {
    if (*cur == '&') {
      strcpy(end, "&amp;");
      end += 5;
    } else if (*cur == '<') {
      strcpy(end, "&lt;");
      end += 4;
    } else if (*cur == '>') {
      strcpy(end, "&gt;");
      end += 4;
    } else {
      *end++ = *cur;
    }
  }
  *end = 0;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xml_escape>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L102
  mov    %rdi,%rdx
  xor    %edi,%edi
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L45:
  and    $0xfffffffd,%eax
  lea    0x4(%rdi),%ecx
  add    $0x1,%edi
  cmp    $0x3c,%al
  cmove  %ecx,%edi
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L70
L26:
  cmp    $0x26,%al
  jne    L45
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  add    $0x5,%edi
  test   %al,%al
  jne    L26
L70:
  add    $0x1,%edi
L43:
  call   <malloc@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  mov    %r12,%r15
  test   %al,%al
  je     L119
  lea    D10(%rip),%r14
  lea    D3(%rip),%r13
  lea    D27(%rip),%rbp
  jmp    L92
  nopl   0x0(%rax)
L90:
  cmp    $0x3c,%al
  je     L36
  cmp    $0x3e,%al
  je     L49
  mov    %al,(%r15)
  add    $0x1,%r15
L8:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L119
L92:
  cmp    $0x26,%al
  jne    L90
  mov    %r15,%rdi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  add    $0x5,%r15
  call   <strcpy@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L92
L119:
  movb   $0x0,(%r15)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L36:
  mov    %r15,%rdi
  mov    %r13,%rsi
  add    $0x4,%r15
  call   <strcpy@plt>
  jmp    L8
  nopl   0x0(%rax)
L49:
  mov    %r15,%rdi
  mov    %r14,%rsi
  add    $0x4,%r15
  call   <strcpy@plt>
  jmp    L8
  nopl   0x0(%rax)
L102:
  mov    $0x1,%edi
  jmp    L43
```

tool_calls: name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D27
type_guessed: string

tool: D10: &gt;

tool: D3: &lt;

tool: D27: &amp;

assistant: ```c
char *xml_escape(const char *str) {
  int len = 0;
  for (const char *cur = str; *cur; ++cur) {
    if (*cur == '&') {
      len += 5;
    } else if (*cur == '<' || *cur == '>') {
      len += 4;
    } else {
      len++;
    }
  }
  char *result = malloc(len + 1);
  char *end = result;
  for (const char *cur = str; *cur; ++cur) {
    if (*cur == '&') {
      strcpy(end, "&amp;");
      end += 5;
    } else if (*cur == '<') {
      strcpy(end, "&lt;");
      end += 4;
    } else if (*cur == '>') {
      strcpy(end, "&gt;");
      end += 4;
    } else {
      *end++ = *cur;
    }
  }
  *end = 0;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xml_escape>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  mov    %rdi,%rdx
  xor    %edi,%edi
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L79:
  and    $0xfffffffd,%eax
  lea    0x4(%rdi),%ecx
  add    $0x1,%edi
  cmp    $0x3c,%al
  cmove  %ecx,%edi
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L28
L36:
  cmp    $0x26,%al
  jne    L79
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  add    $0x5,%edi
  test   %al,%al
  jne    L36
L28:
  add    $0x1,%edi
L2:
  call   <malloc@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  mov    %r12,%r15
  test   %al,%al
  je     L98
  lea    D17(%rip),%r14
  lea    D14(%rip),%r13
  lea    D9(%rip),%rbp
  jmp    L140
  nopl   0x0(%rax)
L136:
  cmp    $0x3c,%al
  je     L95
  cmp    $0x3e,%al
  je     L56
  mov    %al,(%r15)
  add    $0x1,%r15
L8:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L98
L140:
  cmp    $0x26,%al
  jne    L136
  mov    %r15,%rdi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  add    $0x5,%r15
  call   <strcpy@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L140
L98:
  movb   $0x0,(%r15)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L95:
  mov    %r15,%rdi
  mov    %r13,%rsi
  add    $0x4,%r15
  call   <strcpy@plt>
  jmp    L8
  nopl   0x0(%rax)
L56:
  mov    %r15,%rdi
  mov    %r14,%rsi
  add    $0x4,%r15
  call   <strcpy@plt>
  jmp    L8
  nopl   0x0(%rax)
L5:
  mov    $0x1,%edi
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D17: &gt;

tool: D14: &lt;

tool: D9: &amp;

assistant: ```c
char *xml_escape(const char *str) {
  int len = 0;
  for (const char *cur = str; *cur; ++cur) {
    if (*cur == '&') {
      len += 5;
    } else if (*cur == '<' || *cur == '>') {
      len += 4;
    } else {
      len++;
    }
  }
  char *result = malloc(len + 1);
  char *end = result;
  for (const char *cur = str; *cur; ++cur) {
    if (*cur == '&') {
      strcpy(end, "&amp;");
      end += 5;
    } else if (*cur == '<') {
      strcpy(end, "&lt;");
      end += 4;
    } else if (*cur == '>') {
      strcpy(end, "&gt;");
      end += 4;
    } else {
      *end++ = *cur;
    }
  }
  *end = 0;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<invShiftRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L2:
  mov    -0x18(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,-0x9(%rbp)
  movl   $0x3,-0x4(%rbp)
  jmp    L6
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x0,-0x4(%rbp)
  jg     L15
  mov    -0x18(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L1:
  movzbl -0x1c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void invShiftRow(unsigned char *state, unsigned char nbr) {
  int i, j;
  unsigned char tmp;
  for (i = 0; i < nbr; i++) {
    tmp = state[3];
    for (j = 3; j > 0; j--)
      state[j] = state[j - 1];
    state[0] = tmp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<invShiftRow>:
  endbr64
  and    $0xff,%esi
  je     L4
  mov    $0x0,%eax
L5:
  movzbl 0x3(%rdi),%edx
  movzbl 0x2(%rdi),%ecx
  mov    %cl,0x3(%rdi)
  movzbl 0x1(%rdi),%ecx
  mov    %cl,0x2(%rdi)
  movzbl (%rdi),%ecx
  mov    %cl,0x1(%rdi)
  mov    %dl,(%rdi)
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L5
L4:
  ret
```

assistant: ```c
void invShiftRow(unsigned char *state, unsigned char nbr) {
  int i, j;
  unsigned char tmp;
  for (i = 0; i < nbr; i++) {
    tmp = state[3];
    for (j = 3; j > 0; j--)
      state[j] = state[j - 1];
    state[0] = tmp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<invShiftRow>:
  endbr64
  and    $0xff,%esi
  je     L19
  movzbl 0x3(%rdi),%edx
  movzbl 0x2(%rdi),%r9d
  xor    %eax,%eax
  movzbl 0x1(%rdi),%r8d
  movzbl (%rdi),%ecx
  jmp    L16
  nopl   0x0(%rax)
L27:
  mov    %edx,%r10d
  mov    %r9d,%edx
  mov    %r8d,%r9d
  mov    %ecx,%r8d
  mov    %r10d,%ecx
L16:
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L27
  mov    %r9b,0x3(%rdi)
  mov    %r8b,0x2(%rdi)
  mov    %cl,0x1(%rdi)
  mov    %dl,(%rdi)
L19:
  ret
```

assistant: ```c
void invShiftRow(unsigned char *state, unsigned char nbr) {
  int i, j;
  unsigned char tmp;
  for (i = 0; i < nbr; i++) {
    tmp = state[3];
    for (j = 3; j > 0; j--)
      state[j] = state[j - 1];
    state[0] = tmp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<invShiftRow>:
  endbr64
  and    $0xff,%esi
  je     L18
  movzbl 0x3(%rdi),%edx
  movzbl 0x2(%rdi),%r9d
  xor    %eax,%eax
  movzbl 0x1(%rdi),%r8d
  movzbl (%rdi),%ecx
  jmp    L1
  nopl   0x0(%rax)
L10:
  mov    %edx,%r10d
  mov    %r9d,%edx
  mov    %r8d,%r9d
  mov    %ecx,%r8d
  mov    %r10d,%ecx
L1:
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L10
  mov    %r9b,0x3(%rdi)
  mov    %r8b,0x2(%rdi)
  mov    %cl,0x1(%rdi)
  mov    %dl,(%rdi)
L18:
  ret
```

assistant: ```c
void invShiftRow(unsigned char *state, unsigned char nbr) {
  int i, j;
  unsigned char tmp;
  for (i = 0; i < nbr; i++) {
    tmp = state[3];
    for (j = 3; j > 0; j--)
      state[j] = state[j - 1];
    state[0] = tmp;
  }
}
```