user: 这段汇编代码用C语言表示是什么样的：

```asm
<nlogn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  cmp    $0x1,%eax
  jne    L92
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L72
L92:
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <nlogn>
  mov    %eax,-0x8(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <nlogn>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L82
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L82:
  movl   $0x0,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L0
L12:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L90
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L90:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  subl   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L12
  movl   $0x0,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L39
L21:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L35
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L35:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L21
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L91
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
L91:
  mov    -0x8(%rbp),%eax
L72:
  leave
  ret
```

assistant: ```c
int nlogn(int *A, int x, int y, int *tot) {
  int i, m, v, L, R, max;
  if (y - x == 1)
    return A[x];
  m = x + (y - x) / 2;
  max = nlogn(A, x, m, tot);
  v = nlogn(A, m, y, tot);
  if (v > max)
    max = v;
  v = 0;
  L = A[m - 1];
  for (i = m - 1; i >= x; i--) {
    v += A[i];
    if (v > L)
      L = v;
    (*tot)++;
  }
  v = 0;
  R = A[m];
  for (i = m; i < y; i++) {
    v += A[i];
    if (v > R)
      R = v;
    (*tot)++;
  }
  if (L + R > max)
    max = L + R;
  return max;
}
```