ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0x190,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L36
  cmpl   $0x0,-0x10(%rbp)
  jne    L45
  cmpl   $0x0,-0xc(%rbp)
  jne    L7
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L7:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L45:
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L36:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D45
data_type: string
name: unpack_data
arguments: tag: D49
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string

tool: D45: %d

tool: D49: Leap Year

tool: D27: Not Leap Year

assistant: ```c
int main() {
  int y;
  int a, b, c;
  scanf("%d", &y);
  a = y % 4;
  b = y % 100;
  c = y % 400;
  if (a == 0) {
    if (b == 0) {
      if (c == 0)
        printf("Leap Year");
      else
        printf("Not Leap Year");
    } else
      printf("Leap Year");
  } else
    printf("Not Leap Year");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   $0x3,%al
  jne    L5
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  cmp    %edx,%eax
  jne    L16
  mov    $0x190,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L45
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L45:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L16:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L5:
  lea    D32(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string
name: parse_data
arguments: data_tag: D1
data_type: string
name: parse_data
arguments: data_tag: D32
data_type: string

tool: D6: %d

tool: D1: Leap Year

tool: D32: Not Leap Year

assistant: ```c
int main() {
  int y;
  int a, b, c;
  scanf("%d", &y);
  a = y % 4;
  b = y % 100;
  c = y % 400;
  if (a == 0) {
    if (b == 0) {
      if (c == 0)
        printf("Leap Year");
      else
        printf("Not Leap Year");
    } else
      printf("Leap Year");
  } else
    printf("Not Leap Year");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   $0x3,%al
  jne    L26
  imul   $0xc28f5c29,%eax,%edx
  add    $0x51eb850,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L0
  mov    $0x190,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L26
L0:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L47
L26:
  lea    D28(%rip),%rdi
  call   <printf@plt>
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D28
type: string

tool: D14: %d

tool: D19: Leap Year

tool: D28: Not Leap Year

assistant: ```c
int main() {
  int y;
  int a, b, c;
  scanf("%d", &y);
  a = y % 4;
  b = y % 100;
  c = y % 400;
  if (a == 0) {
    if (b == 0) {
      if (c == 0)
        printf("Leap Year");
      else
        printf("Not Leap Year");
    } else
      printf("Leap Year");
  } else
    printf("Not Leap Year");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   $0x3,%al
  jne    L30
  imul   $0xc28f5c29,%eax,%edx
  add    $0x51eb850,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L20
  mov    $0x190,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L30
L20:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L30:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D23
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D22: %d

tool: D23: Leap Year

tool: D5: Not Leap Year

assistant: ```c
int main() {
  int y;
  int a, b, c;
  scanf("%d", &y);
  a = y % 4;
  b = y % 100;
  c = y % 400;
  if (a == 0) {
    if (b == 0) {
      if (c == 0)
        printf("Leap Year");
      else
        printf("Not Leap Year");
    } else
      printf("Leap Year");
  } else
    printf("Not Leap Year");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_swap(char *p1, char *p2) {
  char tmp;
  tmp = *p1;
  *p1 = *p2;
  *p2 = tmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void ft_swap(char *p1, char *p2) {
  char tmp;
  tmp = *p1;
  *p1 = *p2;
  *p2 = tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void ft_swap(char *p1, char *p2) {
  char tmp;
  tmp = *p1;
  *p1 = *p2;
  *p2 = tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void ft_swap(char *p1, char *p2) {
  char tmp;
  tmp = *p1;
  *p1 = *p2;
  *p2 = tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<m_message_term>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <m_message_log_close@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int m_message_term() {
  m_message_log_close();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<m_message_term>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <m_message_log_close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int m_message_term() {
  m_message_log_close();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<m_message_term>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <m_message_log_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int m_message_term() {
  m_message_log_close();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<m_message_term>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <m_message_log_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int m_message_term() {
  m_message_log_close();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<curTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
char *curTime() {
  time_t t;
  t = time(NULL);
  return ctime(&t);
}
```
user: What is the c source code of the assembly code below:

```asm
<curTime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *curTime() {
  time_t t;
  t = time(NULL);
  return ctime(&t);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<curTime>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *curTime() {
  time_t t;
  t = time(NULL);
  return ctime(&t);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<curTime>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *curTime() {
  time_t t;
  t = time(NULL);
  return ctime(&t);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x44(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L23
L26:
  lea    -0x30(%rbp),%rax
  lea    0x8(%rax),%r8
  lea    -0x24(%rbp),%rax
  lea    0x4(%rax),%rdi
  lea    -0x30(%rbp),%rax
  lea    0x4(%rax),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x24(%rbp),%rsi
  add    $0x8,%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x10,%rsp
  movss  -0x30(%rbp),%xmm1
  movss  -0x2c(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x28(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  D0(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x3c(%rbp)
  movss  -0x24(%rbp),%xmm1
  movss  -0x20(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x1c(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  D0(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  -0x30(%rbp),%xmm0
  subss  -0x3c(%rbp),%xmm0
  movd   %xmm0,%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <powf@plt>
  mov    %rax,%rbx
  movss  -0x24(%rbp),%xmm0
  subss  -0x38(%rbp),%xmm0
  movd   %xmm0,%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <powf@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x34(%rbp)
  movss  -0x34(%rbp),%xmm1
  movss  -0x38(%rbp),%xmm0
  mov    -0x3c(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x40(%rbp)
L23:
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x40(%rbp)
  jl     L26
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
data_type: string
name: unpack_data
arguments: tag: D41
data_type: string
name: unpack_data
arguments: tag: D0
data_type: byte[4]
name: unpack_data
arguments: tag: D9
data_type: string

tool: D20: %d

tool: D41: %f %f %f %f %f %f

tool: {"D0": [0x00,0x00,0x40,0x40]}

tool: D9: %f %f %f


assistant: ```c
int main() {
  int i;
  int count;
  float x[3], y[3];
  float xpoint, ypoint;
  float r;
  scanf("%d", &count);
  for (i = 0; i < count; i++) {
    scanf("%f %f %f %f %f %f", &x[0], &y[0], &x[1], &y[1], &x[2], &y[2]);
    xpoint = (x[0] + x[1] + x[2]) / 3;
    ypoint = (y[0] + y[1] + y[2]) / 3;
    r = sqrt(powf(x[0] - xpoint, 2) + powf(y[0] - ypoint, 2));
    printf("%f %f %f\n", xpoint, ypoint, r);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x1c(%rsp)
  jle    L3
  mov    $0x0,%ebp
  lea    0x20(%rsp),%r14
  lea    D16(%rip),%r13
  lea    D24(%rip),%r12
L2:
  lea    0x2c(%rsp),%rdx
  lea    0x24(%rsp),%rcx
  sub    $0x8,%rsp
  lea    0x3c(%rsp),%rax
  push   %rax
  lea    0x38(%rsp),%r9
  lea    0x40(%rsp),%r8
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x30(%rsp),%xmm0
  movaps %xmm0,%xmm1
  addss  0x34(%rsp),%xmm1
  addss  0x38(%rsp),%xmm1
  movaps %xmm1,%xmm3
  divss  D28(%rip),%xmm3
  movss  0x3c(%rsp),%xmm1
  addss  0x40(%rsp),%xmm1
  addss  0x44(%rsp),%xmm1
  divss  D28(%rip),%xmm1
  movss  %xmm1,0x18(%rsp)
  movss  %xmm3,0x1c(%rsp)
  subss  %xmm3,%xmm0
  mov    $0x2,%edi
  call   <powf@plt>
  mov    %rax,%rbx
  movss  0x3c(%rsp),%xmm0
  subss  0x18(%rsp),%xmm0
  mov    $0x2,%edi
  call   <powf@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  movaps %xmm0,%xmm2
  movss  0x18(%rsp),%xmm1
  movss  0x1c(%rsp),%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x10,%rsp
  cmp    %ebp,0x1c(%rsp)
  jg     L2
L3:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D29
datatype: string
name: read_data
arguments: tag: D16
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D28
datatype: byte[4]

tool: D29: %d

tool: D16: %f %f %f %f %f %f

tool: D24: %f %f %f


tool: {"D28": [0x00,0x00,0x40,0x40]}

assistant: ```c
int main() {
  int i;
  int count;
  float x[3], y[3];
  float xpoint, ypoint;
  float r;
  scanf("%d", &count);
  for (i = 0; i < count; i++) {
    scanf("%f %f %f %f %f %f", &x[0], &y[0], &x[1], &y[1], &x[2], &y[2]);
    xpoint = (x[0] + x[1] + x[2]) / 3;
    ypoint = (y[0] + y[1] + y[2]) / 3;
    r = sqrt(powf(x[0] - xpoint, 2) + powf(y[0] - ypoint, 2));
    printf("%f %f %f\n", xpoint, ypoint, r);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D5(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x2c(%rsp),%ecx
  test   %ecx,%ecx
  jle    L29
  lea    0x44(%rsp),%rax
  xor    %ebp,%ebp
  lea    0x40(%rsp),%r13
  mov    %rax,0x18(%rsp)
  lea    0x38(%rsp),%r9
  mov    %r13,%r8
  lea    0x30(%rsp),%r15
  mov    %ebp,%r13d
  lea    0x3c(%rsp),%r14
  lea    0x34(%rsp),%r12
  mov    %r9,%rbp
  nopl   (%rax)
L11:
  sub    $0x8,%rsp
  mov    %r14,%rdx
  mov    %rbp,%r9
  mov    %r12,%rcx
  push   0x20(%rsp)
  mov    %r15,%rsi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  mov    %r8,0x20(%rsp)
  call   <scanf@plt>
  movss  0x40(%rsp),%xmm0
  mov    $0x2,%edi
  movss  0x44(%rsp),%xmm3
  movss  0x4c(%rsp),%xmm1
  addss  0x50(%rsp),%xmm1
  addss  %xmm0,%xmm3
  addss  0x48(%rsp),%xmm3
  divss  D0(%rip),%xmm3
  movss  %xmm3,0x1c(%rsp)
  subss  %xmm3,%xmm0
  addss  0x54(%rsp),%xmm1
  divss  D0(%rip),%xmm1
  movss  %xmm1,0x18(%rsp)
  call   <powf@plt>
  movss  0x18(%rsp),%xmm1
  movss  0x4c(%rsp),%xmm0
  mov    $0x2,%edi
  mov    %rax,%rbx
  subss  %xmm1,%xmm0
  call   <powf@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  movss  0x1c(%rsp),%xmm3
  movss  0x18(%rsp),%xmm1
  lea    D10(%rip),%rdi
  movaps %xmm0,%xmm2
  movaps %xmm3,%xmm0
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    %r13d,0x2c(%rsp)
  mov    0x10(%rsp),%r8
  jg     L11
L29:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D0
type_guessed: byte[4]
name: parse_data
arguments: tag: D10
type_guessed: string

tool: D5: %d

tool: D22: %f %f %f %f %f %f

tool: {"D0": [0x00,0x00,0x40,0x40]}

tool: D10: %f %f %f


assistant: ```c
int main() {
  int i;
  int count;
  float x[3], y[3];
  float xpoint, ypoint;
  float r;
  scanf("%d", &count);
  for (i = 0; i < count; i++) {
    scanf("%f %f %f %f %f %f", &x[0], &y[0], &x[1], &y[1], &x[2], &y[2]);
    xpoint = (x[0] + x[1] + x[2]) / 3;
    ypoint = (y[0] + y[1] + y[2]) / 3;
    r = sqrt(powf(x[0] - xpoint, 2) + powf(y[0] - ypoint, 2));
    printf("%f %f %f\n", xpoint, ypoint, r);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D44(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x2c(%rsp),%ecx
  test   %ecx,%ecx
  jle    L14
  lea    0x44(%rsp),%rax
  xor    %ebp,%ebp
  lea    0x40(%rsp),%r13
  mov    %rax,0x18(%rsp)
  lea    0x38(%rsp),%r9
  mov    %r13,%r8
  lea    0x30(%rsp),%r15
  mov    %ebp,%r13d
  lea    0x3c(%rsp),%r14
  lea    0x34(%rsp),%r12
  mov    %r9,%rbp
  nopl   (%rax)
L7:
  sub    $0x8,%rsp
  mov    %r14,%rdx
  mov    %rbp,%r9
  mov    %r12,%rcx
  push   0x20(%rsp)
  mov    %r15,%rsi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  mov    %r8,0x20(%rsp)
  call   <scanf@plt>
  movss  0x40(%rsp),%xmm0
  mov    $0x2,%edi
  movss  0x44(%rsp),%xmm3
  movss  0x4c(%rsp),%xmm1
  addss  0x50(%rsp),%xmm1
  addss  %xmm0,%xmm3
  addss  0x48(%rsp),%xmm3
  divss  D1(%rip),%xmm3
  movss  %xmm3,0x1c(%rsp)
  subss  %xmm3,%xmm0
  addss  0x54(%rsp),%xmm1
  divss  D1(%rip),%xmm1
  movss  %xmm1,0x18(%rsp)
  call   <powf@plt>
  movss  0x18(%rsp),%xmm1
  movss  0x4c(%rsp),%xmm0
  mov    $0x2,%edi
  mov    %rax,%rbx
  subss  %xmm1,%xmm0
  call   <powf@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  movss  0x1c(%rsp),%xmm3
  movss  0x18(%rsp),%xmm1
  lea    D32(%rip),%rdi
  movaps %xmm0,%xmm2
  movaps %xmm3,%xmm0
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    %r13d,0x2c(%rsp)
  mov    0x10(%rsp),%r8
  jg     L7
L14:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D44
type_guessed: string
name: extract_symbolic_data
arguments: label: D37
type_guessed: string
name: extract_symbolic_data
arguments: label: D1
type_guessed: byte[4]
name: extract_symbolic_data
arguments: label: D32
type_guessed: string

tool: D44: %d

tool: D37: %f %f %f %f %f %f

tool: {"D1": [0x00,0x00,0x40,0x40]}

tool: D32: %f %f %f


assistant: ```c
int main() {
  int i;
  int count;
  float x[3], y[3];
  float xpoint, ypoint;
  float r;
  scanf("%d", &count);
  for (i = 0; i < count; i++) {
    scanf("%f %f %f %f %f %f", &x[0], &y[0], &x[1], &y[1], &x[2], &y[2]);
    xpoint = (x[0] + x[1] + x[2]) / 3;
    ypoint = (y[0] + y[1] + y[2]) / 3;
    r = sqrt(powf(x[0] - xpoint, 2) + powf(y[0] - ypoint, 2));
    printf("%f %f %f\n", xpoint, ypoint, r);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<syscon_load_multprec_polynomial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  lea    -0x28(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <syscon_multprec_size_limit@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x6c,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L26
L8:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x20(%rbp)
L26:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jl     L8
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int syscon_load_multprec_polynomial(int k, int *nc, char *p) {
  int fail, i, szl;
  int *buffer;
  int size = k;
  double *c;
  fail = syscon_multprec_size_limit(k, &szl);
  buffer = (int *)calloc(szl, sizeof(int));
  fail = _ada_use_c2phc(108, &size, buffer, c);
  for (i = 0; i < size; i++)
    p[i] = (char)buffer[i];
  p[size] = '\0';
  free(buffer);
  return fail;
}
```