ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  ja     L27
  lea    D13(%rip),%rbp
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jb     L27
L56:
  test   $0x1,%bl
  je     L34
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jae    L56
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string

tool: D0:  %u

tool: D13: %u


assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned int a, b, i = 0;
  scanf(" %u", &a);
  scanf(" %u", &b);
  for (i = a; i <= b; ++i) {
    if (i % 2 == 1)
      printf("%u\n", i);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rbp
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  ja     L50
  nopl   0x0(%rax,%rax,1)
L15:
  test   $0x1,%bl
  jne    L19
  add    $0x1,%ebx
  cmp    %ebx,%eax
  jae    L15
L50:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L19:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jae    L15
  jmp    L50
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D5
type: string

tool: D9:  %u

tool: D5: %u


assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned int a, b, i = 0;
  scanf(" %u", &a);
  scanf(" %u", &b);
  for (i = a; i <= b; ++i) {
    if (i % 2 == 1)
      printf("%u\n", i);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L18
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L11
L18:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <rescure@plt>
  mov    $0x64,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: the number of args is wrong!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("the number of args is wrong!\n");
    return -1;
  }
  int n = atoi(argv[1]);
  int deep = atoi(argv[1]);
  int *array = malloc(sizeof(int) * (pow(2, deep)));
  rescure(deep, array, n);
  sleep(100);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jne    L15
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  mov    %ebp,%edx
  mov    %ebx,%edi
  call   <rescure@plt>
  mov    $0x64,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: the number of args is wrong!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("the number of args is wrong!\n");
    return -1;
  }
  int n = atoi(argv[1]);
  int deep = atoi(argv[1]);
  int *array = malloc(sizeof(int) * (pow(2, deep)));
  rescure(deep, array, n);
  sleep(100);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jne    L4
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    $0x2,%edi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <pow@plt>
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    %rax,%rsi
  call   <rescure@plt>
  mov    $0x64,%edi
  call   <sleep@plt>
  xor    %eax,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L9
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: the number of args is wrong!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("the number of args is wrong!\n");
    return -1;
  }
  int n = atoi(argv[1]);
  int deep = atoi(argv[1]);
  int *array = malloc(sizeof(int) * (pow(2, deep)));
  rescure(deep, array, n);
  sleep(100);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jne    L2
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    $0x2,%edi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <pow@plt>
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    %rax,%rsi
  call   <rescure@plt>
  mov    $0x64,%edi
  call   <sleep@plt>
  xor    %eax,%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L16
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: the number of args is wrong!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("the number of args is wrong!\n");
    return -1;
  }
  int n = atoi(argv[1]);
  int deep = atoi(argv[1]);
  int *array = malloc(sizeof(int) * (pow(2, deep)));
  rescure(deep, array, n);
  sleep(100);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<naive_vcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) void naive_vcopy(double *dst, double *src, int n) {
  int i;
  for (i = 0; i < n; i++)
    dst[i] = src[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<naive_vcopy>:
  endbr64
  test   %edx,%edx
  jle    L13
  mov    %edx,%edx
  mov    $0x0,%eax
L3:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L13:
  ret
```

assistant: ```c
__attribute__((no)) void naive_vcopy(double *dst, double *src, int n) {
  int i;
  for (i = 0; i < n; i++)
    dst[i] = src[i];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<naive_vcopy>:
  endbr64
  test   %edx,%edx
  jle    L1
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L5:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L1:
  ret
```

assistant: ```c
__attribute__((no)) void naive_vcopy(double *dst, double *src, int n) {
  int i;
  for (i = 0; i < n; i++)
    dst[i] = src[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<naive_vcopy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L45
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L49
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L49
  mov    %edx,%edi
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L10:
  movupd (%rsi,%rax,1),%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L10
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L45
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L30:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L30
L45:
  ret
```

assistant: ```c
__attribute__((no)) void naive_vcopy(double *dst, double *src, int n) {
  int i;
  for (i = 0; i < n; i++)
    dst[i] = src[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0xffff,%edi
  call   <displayBits@plt>
  mov    $0x1,%edi
  call   <displayBits@plt>
  lea    D65(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <displayBits@plt>
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xf,%edi
  call   <displayBits@plt>
  mov    $0xf1,%edi
  call   <displayBits@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xff,%edi
  call   <displayBits@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8b,%edi
  call   <displayBits@plt>
  mov    $0xc7,%edi
  call   <displayBits@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x4c,%edi
  call   <displayBits@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  mov    $0x5555,%edi
  call   <displayBits@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffaaaa,%edi
  call   <displayBits@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D35
type_infered: string
name: unpack_data
arguments: label: D65
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string
name: unpack_data
arguments: label: D6
type_infered: string
name: unpack_data
arguments: label: D24
type_infered: string
name: unpack_data
arguments: label: D51
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D35: The result of combining the following


tool: D65: using the bitwise AND operator & is


tool: D17: 
The result of combining the following


tool: D6: using the bitwise inclusive OR operator | is


tool: D24: using the bitwise exclusive OR operator ^ is


tool: D51: 
The one's complement of


tool: D0: is


assistant: ```c
int main(void) {
  unsigned number1;
  unsigned number2;
  unsigned mask;
  unsigned setBits;
  number1 = 65535;
  mask = 1;
  printf("The result of combining the following\n");
  displayBits(number1);
  displayBits(mask);
  printf("using the bitwise AND operator & is\n");
  displayBits(number1 & mask);
  number1 = 15;
  setBits = 241;
  printf("\nThe result of combining the following\n");
  displayBits(number1);
  displayBits(setBits);
  printf("using the bitwise inclusive OR operator | is\n");
  displayBits(number1 | setBits);
  number1 = 139;
  number2 = 199;
  printf("\nThe result of combining the following\n");
  displayBits(number1);
  displayBits(number2);
  printf("using the bitwise exclusive OR operator ^ is\n");
  displayBits(number1 ^ number2);
  number1 = 21845;
  printf("\nThe one's complement of\n");
  displayBits(number1);
  printf("is\n");
  displayBits(~number1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  lea    D57(%rip),%rbp
  call   <printf@plt>
  mov    $0xffff,%edi
  call   <displayBits@plt>
  mov    $0x1,%edi
  call   <displayBits@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <displayBits@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xf,%edi
  call   <displayBits@plt>
  mov    $0xf1,%edi
  call   <displayBits@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    $0xff,%edi
  call   <displayBits@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x8b,%edi
  call   <displayBits@plt>
  mov    $0xc7,%edi
  call   <displayBits@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x4c,%edi
  call   <displayBits@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x5555,%edi
  call   <displayBits@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffaaaa,%edi
  call   <displayBits@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D39
datatype: string
name: unpack_data
arguments: tag: D57
datatype: string
name: unpack_data
arguments: tag: D43
datatype: string
name: unpack_data
arguments: tag: D42
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D0
datatype: string
name: unpack_data
arguments: tag: D20
datatype: string

tool: D39: The result of combining the following


tool: D57: 
The result of combining the following


tool: D43: using the bitwise AND operator & is


tool: D42: using the bitwise inclusive OR operator | is


tool: D17: using the bitwise exclusive OR operator ^ is


tool: D0: 
The one's complement of


tool: D20: is


assistant: ```c
int main(void) {
  unsigned number1;
  unsigned number2;
  unsigned mask;
  unsigned setBits;
  number1 = 65535;
  mask = 1;
  printf("The result of combining the following\n");
  displayBits(number1);
  displayBits(mask);
  printf("using the bitwise AND operator & is\n");
  displayBits(number1 & mask);
  number1 = 15;
  setBits = 241;
  printf("\nThe result of combining the following\n");
  displayBits(number1);
  displayBits(setBits);
  printf("using the bitwise inclusive OR operator | is\n");
  displayBits(number1 | setBits);
  number1 = 139;
  number2 = 199;
  printf("\nThe result of combining the following\n");
  displayBits(number1);
  displayBits(number2);
  printf("using the bitwise exclusive OR operator ^ is\n");
  displayBits(number1 ^ number2);
  number1 = 21845;
  printf("\nThe one's complement of\n");
  displayBits(number1);
  printf("is\n");
  displayBits(~number1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D68(%rip),%rdi
  lea    D14(%rip),%rbp
  call   <printf@plt>
  mov    $0xffff,%edi
  call   <displayBits@plt>
  mov    $0x1,%edi
  call   <displayBits@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <displayBits@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xf,%edi
  call   <displayBits@plt>
  mov    $0xf1,%edi
  call   <displayBits@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0xff,%edi
  call   <displayBits@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x8b,%edi
  call   <displayBits@plt>
  mov    $0xc7,%edi
  call   <displayBits@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x4c,%edi
  call   <displayBits@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x5555,%edi
  call   <displayBits@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffaaaa,%edi
  call   <displayBits@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D68
type: string
name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D57
type: string
name: disassemble_data
arguments: tag: D21
type: string
name: disassemble_data
arguments: tag: D30
type: string
name: disassemble_data
arguments: tag: D39
type: string
name: disassemble_data
arguments: tag: D28
type: string

tool: D68: The result of combining the following


tool: D14: 
The result of combining the following


tool: D57: using the bitwise AND operator & is


tool: D21: using the bitwise inclusive OR operator | is


tool: D30: using the bitwise exclusive OR operator ^ is


tool: D39: 
The one's complement of


tool: D28: is


assistant: ```c
int main(void) {
  unsigned number1;
  unsigned number2;
  unsigned mask;
  unsigned setBits;
  number1 = 65535;
  mask = 1;
  printf("The result of combining the following\n");
  displayBits(number1);
  displayBits(mask);
  printf("using the bitwise AND operator & is\n");
  displayBits(number1 & mask);
  number1 = 15;
  setBits = 241;
  printf("\nThe result of combining the following\n");
  displayBits(number1);
  displayBits(setBits);
  printf("using the bitwise inclusive OR operator | is\n");
  displayBits(number1 | setBits);
  number1 = 139;
  number2 = 199;
  printf("\nThe result of combining the following\n");
  displayBits(number1);
  displayBits(number2);
  printf("using the bitwise exclusive OR operator ^ is\n");
  displayBits(number1 ^ number2);
  number1 = 21845;
  printf("\nThe one's complement of\n");
  displayBits(number1);
  printf("is\n");
  displayBits(~number1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  cmpl   $0x1,-0x28(%rbp)
  jle    L20
  cmpl   $0x24,-0x28(%rbp)
  jle    L57
L20:
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  jmp    L0
L57:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L48:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  lea    0x23(%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movslq %ecx,%rdx
  lea    D1(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  cmpl   $0x0,-0x24(%rbp)
  jne    L48
  cmpl   $0x0,-0x14(%rbp)
  jns    L41
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2d,(%rax)
L41:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  jmp    L40
L54:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x15(%rbp),%edx
  mov    %dl,(%rax)
L40:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L54
  mov    -0x30(%rbp),%rax
L0:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int value, char *result, int base) {
  if (base < 2 || base > 36) {
    *result = '\0';
    return result;
  }
  char *ptr = result, *ptr1 = result, tmp_char;
  int tmp_value;
  do {
    tmp_value = value;
    value /= base;
    *ptr++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz"[35 + (tmp_value - value * base)];
  } while (value);
  if (tmp_value < 0) {
    *ptr++ = '-';
  }
  *ptr-- = '\0';
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itoa>:
  endbr64
  mov    %rsi,%r10
  mov    %edx,%ecx
  lea    -0x2(%rdx),%eax
  lea    D4(%rip),%r11
  cmp    $0x22,%eax
  ja     L29
  push   %rbx
L56:
  mov    %edi,%r8d
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r9d
  mov    %eax,%edi
  mov    %rsi,%rbx
  add    $0x1,%rsi
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  add    $0x23,%edx
  movslq %edx,%rdx
  movzbl (%r11,%rdx,1),%eax
  mov    %al,-0x1(%rsi)
  test   %r9d,%r9d
  jne    L56
  test   %r8d,%r8d
  js     L38
L0:
  lea    -0x1(%rsi),%rax
  movb   $0x0,(%rsi)
  cmp    %rax,%r10
  jae    L14
  mov    %r10,%rdx
L7:
  movzbl (%rax),%ecx
  sub    $0x1,%rax
  movzbl (%rdx),%esi
  mov    %sil,0x1(%rax)
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%rax
  ja     L7
L14:
  mov    %r10,%rax
  pop    %rbx
  ret
L29:
  movb   $0x0,(%rsi)
  mov    %rsi,%rax
  ret
L38:
  movb   $0x2d,(%rsi)
  lea    0x2(%rbx),%rsi
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D4: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int value, char *result, int base) {
  if (base < 2 || base > 36) {
    *result = '\0';
    return result;
  }
  char *ptr = result, *ptr1 = result, tmp_char;
  int tmp_value;
  do {
    tmp_value = value;
    value /= base;
    *ptr++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz"[35 + (tmp_value - value * base)];
  } while (value);
  if (tmp_value < 0) {
    *ptr++ = '-';
  }
  *ptr-- = '\0';
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%edi
  lea    -0x2(%rdx),%edx
  mov    %rsi,%r8
  lea    D0(%rip),%r9
  cmp    $0x22,%edx
  ja     L34
  nopw   0x0(%rax,%rax,1)
L32:
  cltd
  mov    %eax,%r10d
  mov    %rsi,%rcx
  add    $0x1,%rsi
  idiv   %edi
  add    $0x23,%edx
  movslq %edx,%rdx
  movzbl (%r9,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %eax,%eax
  jne    L32
  test   %r10d,%r10d
  js     L51
L57:
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  cmp    %r8,%rcx
  jbe    L37
  nop
L4:
  movzbl (%rcx),%edx
  movzbl (%rax),%esi
  sub    $0x1,%rcx
  add    $0x1,%rax
  mov    %sil,0x1(%rcx)
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  ja     L4
L37:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L51:
  lea    0x2(%rcx),%rax
  movb   $0x2d,(%rsi)
  mov    %rsi,%rcx
  mov    %rax,%rsi
  jmp    L57
  nop
L34:
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int value, char *result, int base) {
  if (base < 2 || base > 36) {
    *result = '\0';
    return result;
  }
  char *ptr = result, *ptr1 = result, tmp_char;
  int tmp_value;
  do {
    tmp_value = value;
    value /= base;
    *ptr++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz"[35 + (tmp_value - value * base)];
  } while (value);
  if (tmp_value < 0) {
    *ptr++ = '-';
  }
  *ptr-- = '\0';
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return result;
}
```