ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<match_here>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L67
  mov    $0x1,%eax
  jmp    L42
L67:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L76
  mov    $0x0,%eax
  jmp    L42
L76:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L9
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <match_star@plt>
  jmp    L42
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L83
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L83
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  jmp    L42
L83:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L2
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L26
L2:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <match_here>
  jmp    L42
L26:
  mov    $0x0,%eax
L42:
  leave
  ret
```

assistant: ```c
int match_here(const char *re, const char *s) {
  if (!*re)
    return 1;
  else if (!*s)
    return 0;
  if (re[1] == '*') {
    return match_star(re, s);
  } else if (*re == '$' && re[1] == 0) {
    return *s == 0;
  } else {
    if (*re == '.' || *s == *re) {
      return match_here(re + 1, s + 1);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<match_here>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  test   %dl,%dl
  je     L68
  movzbl (%rsi),%ecx
  mov    $0x0,%eax
  test   %cl,%cl
  je     L68
  sub    $0x8,%rsp
  movzbl 0x1(%rdi),%eax
  cmp    $0x2a,%al
  je     L65
  test   %al,%al
  jne    L21
  cmp    $0x24,%dl
  je     L18
L21:
  cmp    %cl,%dl
  je     L92
  mov    $0x0,%eax
  cmp    $0x2e,%dl
  je     L92
L67:
  add    $0x8,%rsp
  ret
L65:
  call   <match_star@plt>
  jmp    L67
L92:
  add    $0x1,%rsi
  add    $0x1,%rdi
  call   <match_here>
  jmp    L67
L18:
  mov    $0x0,%eax
  jmp    L67
L68:
  ret
```

assistant: ```c
int match_here(const char *re, const char *s) {
  if (!*re)
    return 1;
  else if (!*s)
    return 0;
  if (re[1] == '*') {
    return match_star(re, s);
  } else if (*re == '$' && re[1] == 0) {
    return *s == 0;
  } else {
    if (*re == '.' || *s == *re) {
      return match_here(re + 1, s + 1);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<match_here>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L25
  jmp    L62
  nopl   (%rax)
L59:
  movzbl 0x1(%rdi),%eax
  cmp    $0x2a,%al
  je     L77
  test   %al,%al
  jne    L60
  cmp    $0x24,%dl
  je     L71
L60:
  cmp    %dl,%cl
  je     L32
  cmp    $0x2e,%dl
  jne    L71
L32:
  add    $0x1,%rsi
  add    $0x1,%rdi
  test   %al,%al
  je     L62
  mov    %eax,%edx
L25:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L59
L71:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L62:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L77:
  jmp    1050 <match_star@plt>
```

assistant: ```c
int match_here(const char *re, const char *s) {
  if (!*re)
    return 1;
  else if (!*s)
    return 0;
  if (re[1] == '*') {
    return match_star(re, s);
  } else if (*re == '$' && re[1] == 0) {
    return *s == 0;
  } else {
    if (*re == '.' || *s == *re) {
      return match_here(re + 1, s + 1);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<match_here>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L18
  jmp    L30
  nopl   (%rax)
L42:
  movzbl 0x1(%rdi),%eax
  cmp    $0x2a,%al
  je     L72
  test   %al,%al
  jne    L1
  cmp    $0x24,%dl
  je     L60
L1:
  cmp    %dl,%cl
  je     L31
  cmp    $0x2e,%dl
  jne    L60
L31:
  add    $0x1,%rsi
  add    $0x1,%rdi
  test   %al,%al
  je     L30
  mov    %eax,%edx
L18:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L42
L60:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L72:
  jmp    1050 <match_star@plt>
```

assistant: ```c
int match_here(const char *re, const char *s) {
  if (!*re)
    return 1;
  else if (!*s)
    return 0;
  if (re[1] == '*') {
    return match_star(re, s);
  } else if (*re == '$' && re[1] == 0) {
    return *s == 0;
  } else {
    if (*re == '.' || *s == *re) {
      return match_here(re + 1, s + 1);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<VsocHomeAdbShellPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x73252f656d6f682f,%rax
  movabs $0x6264612f6e69622f,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x6c656873,-0x10(%rbp)
  movw   $0x6c,-0xc(%rbp)
  mov    $0x0,%eax
  call   <VsocUserName@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x16,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
char *VsocHomeAdbShellPath(void) {
  const char kVsocAdbShellFmt[] = "/home/%s/bin/adbshell";
  const char *vsoc_user_name = VsocUserName();
  size_t length = (sizeof kVsocAdbShellFmt) + strlen(vsoc_user_name);
  char *adb_shell_path = malloc(length);
  snprintf(adb_shell_path, length, kVsocAdbShellFmt, vsoc_user_name);
  return adb_shell_path;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<VsocHomeAdbShellPath>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x73252f656d6f682f,%rax
  movabs $0x6264612f6e69622f,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x6c656873,0x10(%rsp)
  movw   $0x6c,0x14(%rsp)
  mov    $0x0,%eax
  call   <VsocUserName@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x16(%rax),%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rsp,%rdx
  mov    %rbp,%rcx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %r12,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *VsocHomeAdbShellPath(void) {
  const char kVsocAdbShellFmt[] = "/home/%s/bin/adbshell";
  const char *vsoc_user_name = VsocUserName();
  size_t length = (sizeof kVsocAdbShellFmt) + strlen(vsoc_user_name);
  char *adb_shell_path = malloc(length);
  snprintf(adb_shell_path, length, kVsocAdbShellFmt, vsoc_user_name);
  return adb_shell_path;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VsocHomeAdbShellPath>:
  endbr64
  push   %r13
  mov    $0x6c,%edx
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %dx,0x14(%rsp)
  movaps %xmm0,(%rsp)
  movl   $0x6c656873,0x10(%rsp)
  call   <VsocUserName@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x16(%rax),%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rsp,%rdx
  mov    %r12,%rcx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <snprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: byte[16]

tool: {"D8": [0x2f,0x68,0x6f,0x6d,0x65,0x2f,0x25,0x73,0x2f,0x62,0x69,0x6e,0x2f,0x61,0x64,0x62]}

assistant: ```c
char *VsocHomeAdbShellPath(void) {
  const char kVsocAdbShellFmt[] = "/home/%s/bin/adbshell";
  const char *vsoc_user_name = VsocUserName();
  size_t length = (sizeof kVsocAdbShellFmt) + strlen(vsoc_user_name);
  char *adb_shell_path = malloc(length);
  snprintf(adb_shell_path, length, kVsocAdbShellFmt, vsoc_user_name);
  return adb_shell_path;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<VsocHomeAdbShellPath>:
  endbr64
  push   %r13
  mov    $0x6c,%edx
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %dx,0x14(%rsp)
  movaps %xmm0,(%rsp)
  movl   $0x6c656873,0x10(%rsp)
  call   <VsocUserName@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x16(%rax),%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rsp,%rdx
  mov    %r12,%rcx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <snprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: byte[16]

tool: {"D9": [0x2f,0x68,0x6f,0x6d,0x65,0x2f,0x25,0x73,0x2f,0x62,0x69,0x6e,0x2f,0x61,0x64,0x62]}

assistant: ```c
char *VsocHomeAdbShellPath(void) {
  const char kVsocAdbShellFmt[] = "/home/%s/bin/adbshell";
  const char *vsoc_user_name = VsocUserName();
  size_t length = (sizeof kVsocAdbShellFmt) + strlen(vsoc_user_name);
  char *adb_shell_path = malloc(length);
  snprintf(adb_shell_path, length, kVsocAdbShellFmt, vsoc_user_name);
  return adb_shell_path;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D18
type_guessed: string

tool: D6: ./stealer --stealer=n --punish-time=n


tool: D18: See README for more prarameters


assistant: ```c
void usage(void) {
  printf("./stealer --stealer=n --punish-time=n\n");
  printf("See README for more prarameters\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string

tool: D1: ./stealer --stealer=n --punish-time=n


tool: D13: See README for more prarameters


assistant: ```c
void usage(void) {
  printf("./stealer --stealer=n --punish-time=n\n");
  printf("See README for more prarameters\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type: string
name: retrieve_data
arguments: label: D14
type: string

tool: D18: ./stealer --stealer=n --punish-time=n


tool: D14: See README for more prarameters


assistant: ```c
void usage(void) {
  printf("./stealer --stealer=n --punish-time=n\n");
  printf("See README for more prarameters\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D14
datatype: string

tool: D18: ./stealer --stealer=n --punish-time=n


tool: D14: See README for more prarameters


assistant: ```c
void usage(void) {
  printf("./stealer --stealer=n --punish-time=n\n");
  printf("See README for more prarameters\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getInteger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0xf(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <getLine@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0xf(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: %d

assistant: ```c
int getInteger() {
  char str[7];
  int result = 0;
  getLine(str, 7);
  sscanf(str, "%d", &result);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getInteger>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0x11(%rsp),%rbx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <getLine@plt>
  lea    0xc(%rsp),%rdx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: %d

assistant: ```c
int getInteger() {
  char str[7];
  int result = 0;
  getLine(str, 7);
  sscanf(str, "%d", &result);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getInteger>:
  endbr64
  push   %rbp
  mov    $0x7,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x11(%rsp),%rbp
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%rdi
  call   <getLine@plt>
  lea    0xc(%rsp),%rdx
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D2: %d

assistant: ```c
int getInteger() {
  char str[7];
  int result = 0;
  getLine(str, 7);
  sscanf(str, "%d", &result);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getInteger>:
  endbr64
  push   %rbp
  mov    $0x7,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x11(%rsp),%rbp
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%rdi
  call   <getLine@plt>
  lea    0xc(%rsp),%rdx
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x20,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int getInteger() {
  char str[7];
  int result = 0;
  getLine(str, 7);
  sscanf(str, "%d", &result);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isTurn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  mov    $0x64,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L8
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <Crt_GetRandomPercent@plt>
  test   %rax,%rax
  je     L8
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x64(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L9
L8:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int isTurn(int *addup, int cur) {
  *addup += ((cur > 100) ? 100 : cur);
  if ((*addup > 0) && Crt_GetRandomPercent(*addup)) {
    *addup -= 100;
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isTurn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x64,%eax
  cmp    %eax,%esi
  cmovle %esi,%eax
  mov    %eax,%edi
  add    (%rbx),%edi
  mov    %edi,(%rbx)
  mov    $0x0,%eax
  test   %edi,%edi
  jle    L2
  call   <Crt_GetRandomPercent@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L2
  subl   $0x64,(%rbx)
  mov    $0x1,%eax
L2:
  pop    %rbx
  ret
```

assistant: ```c
int isTurn(int *addup, int cur) {
  *addup += ((cur > 100) ? 100 : cur);
  if ((*addup > 0) && Crt_GetRandomPercent(*addup)) {
    *addup -= 100;
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isTurn>:
  endbr64
  mov    $0x64,%eax
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  cmp    %eax,%esi
  cmovle %esi,%eax
  add    %eax,%edi
  mov    %edi,(%rbx)
  test   %edi,%edi
  jle    L1
  call   <Crt_GetRandomPercent@plt>
  test   %rax,%rax
  je     L1
  subl   $0x64,(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  ret
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isTurn(int *addup, int cur) {
  *addup += ((cur > 100) ? 100 : cur);
  if ((*addup > 0) && Crt_GetRandomPercent(*addup)) {
    *addup -= 100;
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isTurn>:
  endbr64
  mov    $0x64,%eax
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  cmp    %eax,%esi
  cmovle %esi,%eax
  add    %eax,%edi
  mov    %edi,(%rbx)
  test   %edi,%edi
  jle    L15
  call   <Crt_GetRandomPercent@plt>
  test   %rax,%rax
  je     L15
  subl   $0x64,(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  ret
L15:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isTurn(int *addup, int cur) {
  *addup += ((cur > 100) ? 100 : cur);
  if ((*addup > 0) && Crt_GetRandomPercent(*addup)) {
    *addup -= 100;
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<d_to_h>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x23,(%rsp)
  test   %edi,%edi
  je     L2
  mov    %rsp,%r8
L47:
  mov    %edi,%esi
  sar    $0x1f,%esi
  shr    $0x1c,%esi
  lea    (%rdi,%rsi,1),%eax
  and    $0xf,%eax
  sub    %esi,%eax
  lea    0x30(%rax),%r9d
  lea    0x57(%rax),%esi
  cmp    $0x9,%eax
  mov    %r9d,%eax
  cmovg  %esi,%eax
  mov    %eax,0x8(%r8)
  lea    0xf(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x4,%eax
  mov    %eax,%edi
  sub    $0x4,%r8
  test   %eax,%eax
  jne    L47
L2:
  test   %ecx,%ecx
  je     L25
  mov    %rsp,%rdi
L51:
  mov    %ecx,%esi
  sar    $0x1f,%esi
  shr    $0x1c,%esi
  lea    (%rcx,%rsi,1),%eax
  and    $0xf,%eax
  sub    %esi,%eax
  lea    0x30(%rax),%r8d
  lea    0x57(%rax),%esi
  cmp    $0x9,%eax
  mov    %r8d,%eax
  cmovg  %esi,%eax
  mov    %eax,0x10(%rdi)
  lea    0xf(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x4,%eax
  mov    %eax,%ecx
  sub    $0x4,%rdi
  test   %eax,%eax
  jne    L51
L25:
  test   %edx,%edx
  je     L61
  lea    0x18(%rsp),%rsi
L56:
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0xf,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%edi
  lea    0x57(%rax),%ecx
  cmp    $0x9,%eax
  mov    %edi,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%rsi)
  lea    0xf(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  sub    $0x4,%rsi
  test   %eax,%eax
  jne    L56
L61:
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%rbp
L28:
  mov    (%rbx),%edi
  call   <putchar@plt>
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L28
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: 


assistant: ```c
int d_to_h(int r, int g, int b) {
  int final[7];
  int i, temp, temp1;
  final[0] = '#';
  temp = r;
  i = 2;
  while (temp != 0) {
    temp1 = temp % 16;
    if (temp1 < 10)
      temp1 += 48;
    else
      temp1 += 87;
    final[i--] = temp1;
    temp = temp / 16;
  }
  temp = g;
  i = 4;
  while (temp != 0) {
    temp1 = temp % 16;
    if (temp1 < 10)
      temp1 += 48;
    else
      temp1 += 87;
    final[i--] = temp1;
    temp = temp / 16;
  }
  temp = b;
  i = 6;
  while (temp != 0) {
    temp1 = temp % 16;
    if (temp1 < 10)
      temp1 += 48;
    else
      temp1 += 87;
    final[i--] = temp1;
    temp = temp / 16;
  }
  for (i = 0; i < 7; i++) {
    printf("%c", final[i]);
  }
  printf("\n\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d_to_h>:
  endbr64
  push   %rbp
  mov    %esi,%ecx
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movl   $0x23,(%rsp)
  test   %edi,%edi
  je     L65
  mov    %rbx,%r8
L47:
  mov    %edi,%esi
  sar    $0x1f,%esi
  shr    $0x1c,%esi
  lea    (%rdi,%rsi,1),%eax
  and    $0xf,%eax
  sub    %esi,%eax
  lea    0x30(%rax),%r9d
  cmp    $0x9,%eax
  lea    0x57(%rax),%esi
  mov    %r9d,%eax
  cmovg  %esi,%eax
  test   %edi,%edi
  mov    %eax,0x8(%r8)
  lea    0xf(%rdi),%eax
  cmovns %edi,%eax
  sub    $0x4,%r8
  sar    $0x4,%eax
  mov    %eax,%edi
  jne    L47
L65:
  test   %ecx,%ecx
  je     L31
  mov    %rbx,%rdi
  nopl   0x0(%rax,%rax,1)
L63:
  mov    %ecx,%esi
  sar    $0x1f,%esi
  shr    $0x1c,%esi
  lea    (%rcx,%rsi,1),%eax
  and    $0xf,%eax
  sub    %esi,%eax
  lea    0x30(%rax),%r8d
  cmp    $0x9,%eax
  lea    0x57(%rax),%esi
  mov    %r8d,%eax
  cmovg  %esi,%eax
  test   %ecx,%ecx
  mov    %eax,0x10(%rdi)
  lea    0xf(%rcx),%eax
  cmovns %ecx,%eax
  sub    $0x4,%rdi
  sar    $0x4,%eax
  mov    %eax,%ecx
  jne    L63
L31:
  test   %edx,%edx
  je     L9
  lea    0x18(%rsp),%rsi
  nop
L30:
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0xf,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%edi
  cmp    $0x9,%eax
  lea    0x57(%rax),%ecx
  mov    %edi,%eax
  cmovg  %ecx,%eax
  test   %edx,%edx
  mov    %eax,(%rsi)
  lea    0xf(%rdx),%eax
  cmovns %edx,%eax
  sub    $0x4,%rsi
  sar    $0x4,%eax
  mov    %eax,%edx
  jne    L30
L9:
  lea    0x1c(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L17
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: 


assistant: ```c
int d_to_h(int r, int g, int b) {
  int final[7];
  int i, temp, temp1;
  final[0] = '#';
  temp = r;
  i = 2;
  while (temp != 0) {
    temp1 = temp % 16;
    if (temp1 < 10)
      temp1 += 48;
    else
      temp1 += 87;
    final[i--] = temp1;
    temp = temp / 16;
  }
  temp = g;
  i = 4;
  while (temp != 0) {
    temp1 = temp % 16;
    if (temp1 < 10)
      temp1 += 48;
    else
      temp1 += 87;
    final[i--] = temp1;
    temp = temp / 16;
  }
  temp = b;
  i = 6;
  while (temp != 0) {
    temp1 = temp % 16;
    if (temp1 < 10)
      temp1 += 48;
    else
      temp1 += 87;
    final[i--] = temp1;
    temp = temp / 16;
  }
  for (i = 0; i < 7; i++) {
    printf("%c", final[i]);
  }
  printf("\n\n");
  return 0;
}
```