ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <is_prime@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char string[10];
  fgets(string, 10, stdin);
  is_prime(string);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findTilt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dfs@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int findTilt(struct TreeNode *root) {
  int tilt = 0;
  dfs(root, &tilt);
  return (tilt);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<findTilt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <dfs@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findTilt(struct TreeNode *root) {
  int tilt = 0;
  dfs(root, &tilt);
  return (tilt);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findTilt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <dfs@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findTilt(struct TreeNode *root) {
  int tilt = 0;
  dfs(root, &tilt);
  return (tilt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findTilt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <dfs@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findTilt(struct TreeNode *root) {
  int tilt = 0;
  dfs(root, &tilt);
  return (tilt);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x1c(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x1c(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x18(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm2
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm3
  movq   %xmm3,%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string
name: retrieve_data
arguments: label: D8
data_type: string
name: retrieve_data
arguments: label: D18
data_type: f64
name: retrieve_data
arguments: label: D20
data_type: string

tool: D5: Enter value for radius: 

tool: D8: %f

tool: D18: 3.14

tool: D20: Radius: %.2f
Diameter: %.2f
Area: %.2f


assistant: ```c
int main() {
  float radius, area, diam;
  float *ptr;
  ptr = &radius;
  printf("Enter value for radius: ");
  scanf("%f", ptr);
  diam = radius * 2;
  area = 3.14 * (radius * radius);
  printf("Radius: %.2f\nDiameter: %.2f\nArea: %.2f\n", radius, diam, area);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movaps %xmm0,%xmm2
  mulss  %xmm0,%xmm2
  cvtss2sd %xmm2,%xmm2
  mulsd  D34(%rip),%xmm2
  cvtsd2ss %xmm2,%xmm2
  movaps %xmm0,%xmm1
  addss  %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    D18(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
type_infered: string
name: extract_symbolic_data
arguments: label: D39
type_infered: string
name: extract_symbolic_data
arguments: label: D34
type_infered: f64
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D25: Enter value for radius: 

tool: D39: %f

tool: D34: 3.14

tool: D18: Radius: %.2f
Diameter: %.2f
Area: %.2f


assistant: ```c
int main() {
  float radius, area, diam;
  float *ptr;
  ptr = &radius;
  printf("Enter value for radius: ");
  scanf("%f", ptr);
  diam = radius * 2;
  area = 3.14 * (radius * radius);
  printf("Radius: %.2f\nDiameter: %.2f\nArea: %.2f\n", radius, diam, area);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x3,%eax
  lea    D28(%rip),%rdi
  movaps %xmm0,%xmm2
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm2
  addss  %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm2
  mulsd  D1(%rip),%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D28
type: string
name: read_data
arguments: label: D1
type: f64

tool: D29: Enter value for radius: 

tool: D16: %f

tool: D28: Radius: %.2f
Diameter: %.2f
Area: %.2f


tool: D1: 3.14

assistant: ```c
int main() {
  float radius, area, diam;
  float *ptr;
  ptr = &radius;
  printf("Enter value for radius: ");
  scanf("%f", ptr);
  diam = radius * 2;
  area = 3.14 * (radius * radius);
  printf("Radius: %.2f\nDiameter: %.2f\nArea: %.2f\n", radius, diam, area);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x3,%eax
  lea    D29(%rip),%rdi
  movaps %xmm0,%xmm2
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm2
  addss  %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm2
  mulsd  D1(%rip),%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D38
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D29
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: f64

tool: D38: Enter value for radius: 

tool: D26: %f

tool: D29: Radius: %.2f
Diameter: %.2f
Area: %.2f


tool: D1: 3.14

assistant: ```c
int main() {
  float radius, area, diam;
  float *ptr;
  ptr = &radius;
  printf("Enter value for radius: ");
  scanf("%f", ptr);
  diam = radius * 2;
  area = 3.14 * (radius * radius);
  printf("Radius: %.2f\nDiameter: %.2f\nArea: %.2f\n", radius, diam, area);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_destroy_bctx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void _destroy_bctx(struct s_bctx *b) {
  if (b) {
    free(b);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_destroy_bctx>:
  endbr64
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
void _destroy_bctx(struct s_bctx *b) {
  if (b) {
    free(b);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_destroy_bctx>:
  endbr64
  test   %rdi,%rdi
  je     L2
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L2:
  ret
```

assistant: ```c
void _destroy_bctx(struct s_bctx *b) {
  if (b) {
    free(b);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_destroy_bctx>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L5:
  ret
```

assistant: ```c
void _destroy_bctx(struct s_bctx *b) {
  if (b) {
    free(b);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memset16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L8:
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dx,(%rax)
L0:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memset16(void *s, int c, size_t n) {
  short *ptr = s;
  while (n--) {
    *ptr++ = c;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memset16>:
  endbr64
  test   %rdx,%rdx
  je     L9
  mov    $0x0,%eax
L10:
  mov    %si,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
L9:
  ret
```

assistant: ```c
void memset16(void *s, int c, size_t n) {
  short *ptr = s;
  while (n--) {
    *ptr++ = c;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memset16>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L3
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %si,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
L3:
  ret
```

assistant: ```c
void memset16(void *s, int c, size_t n) {
  short *ptr = s;
  while (n--) {
    *ptr++ = c;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memset16>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%r8
  test   %rdx,%rdx
  je     L9
  cmp    $0x6,%r8
  jbe    L7
  movd   %esi,%xmm0
  mov    %rdx,%r9
  xor    %eax,%eax
  punpcklwd %xmm0,%xmm0
  shr    $0x3,%r9
  pshufd $0x0,%xmm0,%xmm0
  nopl   0x0(%rax)
L76:
  mov    %rax,%rdi
  add    $0x1,%rax
  shl    $0x4,%rdi
  movups %xmm0,(%rcx,%rdi,1)
  cmp    %rax,%r9
  jne    L76
  mov    %rdx,%rax
  and    $0xfffffffffffffff8,%rax
  lea    (%rcx,%rax,2),%rdi
  sub    %rax,%r8
  cmp    %rax,%rdx
  je     L56
L80:
  sub    %rax,%rdx
  lea    -0x1(%rdx),%r9
  cmp    $0x2,%r9
  jbe    L24
  movd   %esi,%xmm1
  pshuflw $0x0,%xmm1,%xmm0
  movq   %xmm0,(%rcx,%rax,2)
  mov    %rdx,%rax
  and    $0xfffffffffffffffc,%rax
  lea    (%rdi,%rax,2),%rdi
  sub    %rax,%r8
  cmp    %rax,%rdx
  je     L9
L24:
  mov    %si,(%rdi)
  test   %r8,%r8
  je     L9
  mov    %si,0x2(%rdi)
  cmp    $0x1,%r8
  je     L9
  mov    %si,0x4(%rdi)
L9:
  ret
  nopl   0x0(%rax)
L56:
  ret
L7:
  xor    %eax,%eax
  jmp    L80
```

assistant: ```c
void memset16(void *s, int c, size_t n) {
  short *ptr = s;
  while (n--) {
    *ptr++ = c;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L133
  cmpq   $0x0,-0x30(%rbp)
  jne    L92
L133:
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L29
L92:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L119
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
L119:
  movq   $0x0,-0x20(%rbp)
L138:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L48
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L113
  cmpq   $0x0,-0x20(%rbp)
  je     L136
L113:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  sub    $0xffffffffffffff80,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L86
  mov    $0xffffffff,%eax
  jmp    L29
L86:
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L136:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L58
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L138
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L138
  jmp    L39
L48:
  nop
  jmp    L39
L58:
  nop
L39:
  cmpq   $0x0,-0x20(%rbp)
  jne    L44
  mov    $0xffffffff,%eax
  jmp    L29
L44:
  mov    -0x20(%rbp),%rax
L29:
  leave
  ret
```

assistant: ```c
ssize_t getline(char **__restrict buf, size_t *__restrict buflen, FILE *__restrict fp) {
  size_t bytes, newlen;
  char *newbuf, *p;
  if (buf == NULL || buflen == NULL) {
    errno = EINVAL;
    return -1;
  }
  if (*buf == NULL)
    *buflen = 0;
  bytes = 0;
  do {
    if (feof(fp))
      break;
    if (*buf == NULL || bytes != 0) {
      newlen = *buflen + 128;
      newbuf = realloc(*buf, newlen);
      if (newbuf == NULL)
        return -1;
      *buf = newbuf;
      *buflen = newlen;
    }
    p = *buf + bytes;
    memset(p, 0, 128);
    if (fgets(p, 128, fp) == NULL)
      break;
    bytes += strlen(p);
  } while (bytes == 0 || *(*buf + (bytes - 1)) != '\n');
  if (bytes == 0)
    return -1;
  return bytes;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L56
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rdx,%r13
  test   %rsi,%rsi
  je     L56
  cmpq   $0x0,(%rdi)
  je     L80
L51:
  mov    $0x0,%ebx
  jmp    L156
L56:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L123
L80:
  movq   $0x0,(%rsi)
  jmp    L51
L85:
  mov    (%r14),%rax
  lea    0x80(%rax),%rbp
  mov    %rbp,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L138
  mov    %rax,(%r12)
  mov    %rbp,(%r14)
L67:
  mov    %rbx,%rbp
  add    (%r12),%rbp
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r13,%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L142
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  je     L156
  mov    (%r12),%rax
  cmpb   $0xa,-0x1(%rax,%rbx,1)
  je     L42
L156:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L142
  mov    (%r12),%rdi
  test   %rbx,%rbx
  jne    L85
  test   %rdi,%rdi
  jne    L67
  jmp    L85
L142:
  test   %rbx,%rbx
  je     L149
L42:
  mov    %ebx,%eax
L123:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L138:
  mov    $0xffffffff,%eax
  jmp    L123
L149:
  mov    $0xffffffff,%eax
  jmp    L123
```

assistant: ```c
ssize_t getline(char **__restrict buf, size_t *__restrict buflen, FILE *__restrict fp) {
  size_t bytes, newlen;
  char *newbuf, *p;
  if (buf == NULL || buflen == NULL) {
    errno = EINVAL;
    return -1;
  }
  if (*buf == NULL)
    *buflen = 0;
  bytes = 0;
  do {
    if (feof(fp))
      break;
    if (*buf == NULL || bytes != 0) {
      newlen = *buflen + 128;
      newbuf = realloc(*buf, newlen);
      if (newbuf == NULL)
        return -1;
      *buf = newbuf;
      *buflen = newlen;
    }
    p = *buf + bytes;
    memset(p, 0, 128);
    if (fgets(p, 128, fp) == NULL)
      break;
    bytes += strlen(p);
  } while (bytes == 0 || *(*buf + (bytes - 1)) != '\n');
  if (bytes == 0)
    return -1;
  return bytes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L8
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L8
  cmpq   $0x0,(%rdi)
  mov    %rdi,%r12
  mov    %rdx,%r13
  je     L3
L31:
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L17
  mov    (%r12),%rdi
  test   %rdi,%rdi
  je     L135
  test   %rbx,%rbx
  jne    L135
L67:
  lea    (%rdi,%rbx,1),%rbp
  xor    %esi,%esi
  mov    $0x80,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r13,%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L17
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  je     L14
  mov    (%r12),%rax
  cmpb   $0xa,-0x1(%rax,%rbx,1)
  jne    L14
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%eax
L98:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L135:
  mov    (%r14),%rax
  lea    0x80(%rax),%rbp
  mov    %rbp,%rsi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L124
  mov    %rax,(%r12)
  mov    %rbp,(%r14)
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L17:
  test   %rbx,%rbx
  jne    L12
L124:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movq   $0x0,(%rsi)
  jmp    L31
L8:
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L98
```

assistant: ```c
ssize_t getline(char **__restrict buf, size_t *__restrict buflen, FILE *__restrict fp) {
  size_t bytes, newlen;
  char *newbuf, *p;
  if (buf == NULL || buflen == NULL) {
    errno = EINVAL;
    return -1;
  }
  if (*buf == NULL)
    *buflen = 0;
  bytes = 0;
  do {
    if (feof(fp))
      break;
    if (*buf == NULL || bytes != 0) {
      newlen = *buflen + 128;
      newbuf = realloc(*buf, newlen);
      if (newbuf == NULL)
        return -1;
      *buf = newbuf;
      *buflen = newlen;
    }
    p = *buf + bytes;
    memset(p, 0, 128);
    if (fgets(p, 128, fp) == NULL)
      break;
    bytes += strlen(p);
  } while (bytes == 0 || *(*buf + (bytes - 1)) != '\n');
  if (bytes == 0)
    return -1;
  return bytes;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L43
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L43
  cmpq   $0x0,(%rdi)
  mov    %rdi,%r12
  mov    %rdx,%r13
  je     L56
L35:
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L34
  mov    (%r12),%rdi
  test   %rdi,%rdi
  je     L18
  test   %rbx,%rbx
  jne    L18
L48:
  lea    (%rdi,%rbx,1),%rbp
  xor    %esi,%esi
  mov    $0x80,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r13,%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L34
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  je     L37
  mov    (%r12),%rax
  cmpb   $0xa,-0x1(%rax,%rbx,1)
  jne    L37
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %ebx,%eax
L124:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%r14),%rax
  lea    0x80(%rax),%rbp
  mov    %rbp,%rsi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L106
  mov    %rax,(%r12)
  mov    %rbp,(%r14)
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L34:
  test   %rbx,%rbx
  jne    L74
L106:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  movq   $0x0,(%rsi)
  jmp    L35
L43:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L124
```

assistant: ```c
ssize_t getline(char **__restrict buf, size_t *__restrict buflen, FILE *__restrict fp) {
  size_t bytes, newlen;
  char *newbuf, *p;
  if (buf == NULL || buflen == NULL) {
    errno = EINVAL;
    return -1;
  }
  if (*buf == NULL)
    *buflen = 0;
  bytes = 0;
  do {
    if (feof(fp))
      break;
    if (*buf == NULL || bytes != 0) {
      newlen = *buflen + 128;
      newbuf = realloc(*buf, newlen);
      if (newbuf == NULL)
        return -1;
      *buf = newbuf;
      *buflen = newlen;
    }
    p = *buf + bytes;
    memset(p, 0, 128);
    if (fgets(p, 128, fp) == NULL)
      break;
    bytes += strlen(p);
  } while (bytes == 0 || *(*buf + (bytes - 1)) != '\n');
  if (bytes == 0)
    return -1;
  return bytes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readlines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %rdi,-0x408(%rbp)
  mov    %esi,-0x40c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x400(%rbp)
  jmp    L26
L32:
  cmpl   $0x1387,-0x400(%rbp)
  jg     L20
  mov    -0x3fc(%rbp),%eax
  mov    %eax,%edi
  call   <alloc@plt>
  mov    %rax,-0x3f8(%rbp)
  cmpq   $0x0,-0x3f8(%rbp)
  jne    L19
L20:
  mov    $0xffffffff,%eax
  jmp    L34
L19:
  mov    -0x3fc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movb   $0x0,-0x3f0(%rbp,%rax,1)
  lea    -0x3f0(%rbp),%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x400(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x400(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x408(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rax,(%rdx)
L26:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <get_line@plt>
  mov    %eax,-0x3fc(%rbp)
  cmpl   $0x0,-0x3fc(%rbp)
  jg     L32
  mov    -0x400(%rbp),%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int readlines(char *lineptr[], int maxlines) {
  int len, nlines;
  char *p, line[1000];
  nlines = 0;
  while ((len = get_line(line, 1000)) > 0)
    if (nlines >= 5000 || (p = alloc(len)) == NULL)
      return -1;
    else {
      line[len - 1] = '\0';
      strcpy(p, line);
      lineptr[nlines++] = p;
    }
  return nlines;
}
```