ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_print_help>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <parse_exename@plt>
  lea    D12(%rip),%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <fprintf@plt>
  test   %ebx,%ebx
  je     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    $0x163,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D7(%rip),%rdi
  pop    %r12
  jmp    1090 <fwrite@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
data_type: string
name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D12: Usage: %s [options] infile... 
  --help            print this help message
  --version         print the VTK version
  -o <file>         the output file
  -I <dir>          add an include directory
  -D <macro[=def]>  define a preprocessor macro
  -U <macro>        undefine a preprocessor macro
  @<file>           read arguments from a file


tool: D7:   --hints <file>    the hints file to use
  --types <file>    the type hierarchy file to use
  --concrete        force concrete class (ignored, deprecated)
  --abstract        force abstract class (ignored, deprecated)
  --vtkobject       vtkObjectBase-derived class (ignored, deprecated)
  --special         non-vtkObjectBase class (ignored, deprecated)


assistant: ```c
void parse_print_help(FILE *fp, const char *cmd, int multi) {
  fprintf(fp,
          "Usage: %s [options] infile... \n"
          "  --help            print this help message\n"
          "  --version         print the VTK version\n"
          "  -o <file>         the output file\n"
          "  -I <dir>          add an include directory\n"
          "  -D <macro[=def]>  define a preprocessor macro\n"
          "  -U <macro>        undefine a preprocessor macro\n"
          "  @<file>           read arguments from a file\n",
          parse_exename(cmd));
  if (!multi) {
    fprintf(fp, "  --hints <file>    the hints file to use\n"
                "  --types <file>    the type hierarchy file to use\n"
                "  --concrete        force concrete class (ignored, deprecated)\n"
                "  --abstract        force abstract class (ignored, deprecated)\n"
                "  --vtkobject       vtkObjectBase-derived class (ignored, deprecated)\n"
                "  --special         non-vtkObjectBase class (ignored, deprecated)\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_rho>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: 
Tr[rho] = %e



assistant: ```c
void check_rho(double **rho, int N) {
  int i;
  double sum = 0.0;
  for (i = 0; i < N; i++)
    sum += rho[i][i];
  printf("\nTr[rho] = %e\n\n", sum);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_rho>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L24
  mov    %esi,%esi
  lea    0x0(,%rsi,8),%rcx
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
L4:
  mov    (%rdi,%rax,1),%rdx
  addsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L4
L19:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L24:
  pxor   %xmm0,%xmm0
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: 
Tr[rho] = %e



assistant: ```c
void check_rho(double **rho, int N) {
  int i;
  double sum = 0.0;
  for (i = 0; i < N; i++)
    sum += rho[i][i];
  printf("\nTr[rho] = %e\n\n", sum);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_rho>:
  endbr64
  test   %esi,%esi
  jle    L18
  movslq %esi,%rsi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  lea    0x0(,%rsi,8),%rcx
  nopl   0x0(%rax)
L6:
  mov    (%rdi,%rax,1),%rdx
  addsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L6
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
L18:
  pxor   %xmm0,%xmm0
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 
Tr[rho] = %e



assistant: ```c
void check_rho(double **rho, int N) {
  int i;
  double sum = 0.0;
  for (i = 0; i < N; i++)
    sum += rho[i][i];
  printf("\nTr[rho] = %e\n\n", sum);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_rho>:
  endbr64
  test   %esi,%esi
  jle    L5
  movslq %esi,%rsi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  lea    0x0(,%rsi,8),%rcx
  nopl   0x0(%rax)
L10:
  mov    (%rdi,%rax,1),%rdx
  addsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L10
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
L5:
  pxor   %xmm0,%xmm0
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 
Tr[rho] = %e



assistant: ```c
void check_rho(double **rho, int N) {
  int i;
  double sum = 0.0;
  for (i = 0; i < N; i++)
    sum += rho[i][i];
  printf("\nTr[rho] = %e\n\n", sum);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  je     L84
  movl   $0x0,D50(%rip)
L84:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  mov    D50(%rip),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L75
L85:
  movl   $0x0,-0x1c(%rbp)
  jmp    L123
L29:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L114
  movl   $0x1,-0x20(%rbp)
  jmp    L116
L114:
  addl   $0x1,-0x1c(%rbp)
L123:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L29
L116:
  cmpl   $0x0,-0x20(%rbp)
  jne    L151
  addl   $0x1,-0x28(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L25
  jmp    L66
L151:
  cmpl   $0x0,-0x24(%rbp)
  je     L18
  mov    D50(%rip),%eax
  test   %eax,%eax
  je     L18
  addq   $0x1,-0x10(%rbp)
  mov    D50(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D86(%rip)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L75
L18:
  movl   $0x1,-0x14(%rbp)
  jmp    L66
L25:
  addq   $0x1,-0x10(%rbp)
L75:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L85
L66:
  cmpl   $0x0,-0x28(%rbp)
  jne    L94
  movl   $0x0,D86(%rip)
  mov    $0x0,%eax
  jmp    L152
L94:
  mov    -0x28(%rbp),%eax
  add    $0x2,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    D86(%rip),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    D86(%rip),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,D86(%rip)
  mov    -0x8(%rbp),%rax
L152:
  leave
  ret
```

assistant: ```c
char *split(char *str, char *delim, bool reset) {
  static int j = 0;
  if (reset)
    j = 0;
  int len = strlen(delim);
  int i = 0;
  char *tmp = str + j;
  bool one_delim = true, stop = false, got_delim = false;
  while (*tmp) {
    int k;
    for (k = 0; k < len; k++) {
      if (*(tmp) == delim[k]) {
        got_delim = true;
        break;
      }
    }
    if (!got_delim)
      i++;
    else if (one_delim && j) {
      tmp++;
      j++;
      one_delim = false;
      got_delim = false;
      continue;
    } else {
      stop = true;
      break;
    }
    if (stop)
      break;
    tmp++;
  }
  if (!i) {
    j = 0;
    return NULL;
  }
  char *substr = calloc(i + 2, sizeof(char));
  strncpy(substr, str + j, i);
  j += i;
  return substr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<split>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %edx,%edx
  je     L10
  movl   $0x0,D5(%rip)
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    D5(%rip),%r8d
  movslq %r8d,%rsi
  add    %r12,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L43
  add    $0x1,%rsi
  mov    $0x0,%r10d
  mov    $0x1,%r9d
  mov    $0x0,%ebx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rcx
  mov    $0x1,%r13d
  mov    $0x0,%r11d
  jmp    L96
L135:
  add    $0x1,%ebx
  mov    %rsi,%rax
L141:
  movzbl (%rax),%edx
  add    $0x1,%rsi
  test   %dl,%dl
  je     L19
L96:
  mov    %rbp,%rax
  test   %edi,%edi
  jle    L135
L87:
  cmp    %dl,(%rax)
  je     L66
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L87
  jmp    L135
L66:
  test   %r9d,%r9d
  je     L120
  test   %r8d,%r8d
  jne    L142
  test   %r10b,%r10b
  jne    L158
L161:
  test   %ebx,%ebx
  je     L43
  lea    0x2(%rbx),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  movslq D5(%rip),%rax
  lea    (%r12,%rax,1),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  add    D5(%rip),%ebx
L130:
  mov    %ebx,D74(%rip)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L120:
  test   %r10b,%r10b
  je     L161
  mov    %r8d,D74(%rip)
  jmp    L161
L158:
  movl   $0x0,D74(%rip)
  jmp    L161
L142:
  mov    %rsi,%rax
  add    $0x1,%r8d
  mov    %r13d,%r10d
  mov    %r11d,%r9d
  jmp    L141
L19:
  test   %r10b,%r10b
  je     L161
  mov    %r8d,D74(%rip)
  jmp    L161
L43:
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L130
```

assistant: ```c
char *split(char *str, char *delim, bool reset) {
  static int j = 0;
  if (reset)
    j = 0;
  int len = strlen(delim);
  int i = 0;
  char *tmp = str + j;
  bool one_delim = true, stop = false, got_delim = false;
  while (*tmp) {
    int k;
    for (k = 0; k < len; k++) {
      if (*(tmp) == delim[k]) {
        got_delim = true;
        break;
      }
    }
    if (!got_delim)
      i++;
    else if (one_delim && j) {
      tmp++;
      j++;
      one_delim = false;
      got_delim = false;
      continue;
    } else {
      stop = true;
      break;
    }
    if (stop)
      break;
    tmp++;
  }
  if (!i) {
    j = 0;
    return NULL;
  }
  char *substr = calloc(i + 2, sizeof(char));
  strncpy(substr, str + j, i);
  j += i;
  return substr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<split>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %edx,%edx
  je     L33
  movl   $0x0,D21(%rip)
L33:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq D21(%rip),%rdi
  mov    %rdi,%r8
  add    %rbx,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L119
  lea    -0x1(%rax),%edx
  add    $0x1,%rdi
  xor    %r10d,%r10d
  mov    $0x1,%r9d
  xor    %ebp,%ebp
  lea    0x1(%r12,%rdx,1),%rsi
L101:
  mov    %r12,%rdx
  test   %eax,%eax
  jg     L34
  jmp    L17
  nopl   0x0(%rax)
L104:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L17
L34:
  cmp    %cl,(%rdx)
  jne    L104
  test   %r9d,%r9d
  je     L58
  test   %r8d,%r8d
  jne    L47
  test   %r10b,%r10b
  jne    L44
L124:
  test   %ebp,%ebp
  je     L119
L67:
  lea    0x2(%rbp),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  movslq D21(%rip),%rsi
  mov    %ebp,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  add    %rbx,%rsi
  call   <strncpy@plt>
  add    D21(%rip),%ebp
  mov    %r12,%rax
  pop    %rbx
  mov    %ebp,D2(%rip)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  add    $0x1,%ebp
L3:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  jne    L101
L58:
  test   %r10b,%r10b
  je     L124
  mov    %r8d,D2(%rip)
  jmp    L124
  nopl   0x0(%rax)
L44:
  movl   $0x0,D2(%rip)
  test   %ebp,%ebp
  jne    L67
L119:
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  mov    %ebp,D2(%rip)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L47:
  add    $0x1,%r8d
  mov    $0x1,%r10d
  xor    %r9d,%r9d
  jmp    L3
```

assistant: ```c
char *split(char *str, char *delim, bool reset) {
  static int j = 0;
  if (reset)
    j = 0;
  int len = strlen(delim);
  int i = 0;
  char *tmp = str + j;
  bool one_delim = true, stop = false, got_delim = false;
  while (*tmp) {
    int k;
    for (k = 0; k < len; k++) {
      if (*(tmp) == delim[k]) {
        got_delim = true;
        break;
      }
    }
    if (!got_delim)
      i++;
    else if (one_delim && j) {
      tmp++;
      j++;
      one_delim = false;
      got_delim = false;
      continue;
    } else {
      stop = true;
      break;
    }
    if (stop)
      break;
    tmp++;
  }
  if (!i) {
    j = 0;
    return NULL;
  }
  char *substr = calloc(i + 2, sizeof(char));
  strncpy(substr, str + j, i);
  j += i;
  return substr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<split>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %edx,%edx
  je     L77
  movl   $0x0,D45(%rip)
L77:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq D45(%rip),%rdi
  mov    %rdi,%r8
  add    %rbx,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L33
  lea    -0x1(%rax),%edx
  add    $0x1,%rdi
  xor    %r10d,%r10d
  mov    $0x1,%r9d
  xor    %ebp,%ebp
  lea    0x1(%r12,%rdx,1),%rsi
L126:
  mov    %r12,%rdx
  test   %eax,%eax
  jg     L101
  jmp    L104
  nopl   0x0(%rax)
L13:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L104
L101:
  cmp    %cl,(%rdx)
  jne    L13
  test   %r9d,%r9d
  je     L107
  test   %r8d,%r8d
  jne    L16
  test   %r10b,%r10b
  jne    L41
L39:
  test   %ebp,%ebp
  je     L33
L66:
  lea    0x2(%rbp),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  movslq D45(%rip),%rsi
  mov    %ebp,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  add    %rbx,%rsi
  call   <strncpy@plt>
  add    D45(%rip),%ebp
  mov    %r12,%rax
  pop    %rbx
  mov    %ebp,D34(%rip)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L104:
  add    $0x1,%ebp
L142:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  jne    L126
L107:
  test   %r10b,%r10b
  je     L39
  mov    %r8d,D34(%rip)
  jmp    L39
  nopl   0x0(%rax)
L41:
  movl   $0x0,D34(%rip)
  test   %ebp,%ebp
  jne    L66
L33:
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  mov    %ebp,D34(%rip)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  add    $0x1,%r8d
  mov    $0x1,%r10d
  xor    %r9d,%r9d
  jmp    L142
```

assistant: ```c
char *split(char *str, char *delim, bool reset) {
  static int j = 0;
  if (reset)
    j = 0;
  int len = strlen(delim);
  int i = 0;
  char *tmp = str + j;
  bool one_delim = true, stop = false, got_delim = false;
  while (*tmp) {
    int k;
    for (k = 0; k < len; k++) {
      if (*(tmp) == delim[k]) {
        got_delim = true;
        break;
      }
    }
    if (!got_delim)
      i++;
    else if (one_delim && j) {
      tmp++;
      j++;
      one_delim = false;
      got_delim = false;
      continue;
    } else {
      stop = true;
      break;
    }
    if (stop)
      break;
    tmp++;
  }
  if (!i) {
    j = 0;
    return NULL;
  }
  char *substr = calloc(i + 2, sizeof(char));
  strncpy(substr, str + j, i);
  j += i;
  return substr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L6
  movl   $0x1,-0x4(%rbp)
L6:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 0;
  if (a == 0) {
    b = 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 0;
  if (a == 0) {
    b = 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 0;
  if (a == 0) {
    b = 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 0;
  if (a == 0) {
    b = 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<gint1_fn_pD>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x40,%rsp
  movsd  0x8(%rsi),%xmm4
  subsd  0x8(%rdi),%xmm4
  movsd  (%rsi),%xmm5
  subsd  (%rdi),%xmm5
  movsd  %xmm0,0x20(%rsp)
  movsd  0x10(%rsi),%xmm2
  subsd  0x10(%rdi),%xmm2
  movapd %xmm4,%xmm1
  movsd  %xmm4,0x38(%rsp)
  mulsd  %xmm4,%xmm1
  movapd %xmm5,%xmm4
  movsd  %xmm5,0x30(%rsp)
  mulsd  %xmm5,%xmm4
  movapd %xmm2,%xmm5
  movsd  %xmm2,0x28(%rsp)
  mulsd  %xmm2,%xmm5
  movsd  %xmm1,(%rsp)
  movsd  D49(%rip),%xmm1
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm5,0x10(%rsp)
  call   <pow@plt>
  movsd  (%rsp),%xmm7
  addsd  0x8(%rsp),%xmm7
  movsd  %xmm0,0x18(%rsp)
  movsd  0x10(%rsp),%xmm0
  movsd  0x20(%rsp),%xmm3
  xorpd  D35(%rip),%xmm3
  addsd  %xmm7,%xmm0
  mulsd  %xmm3,%xmm0
  call   <exp@plt>
  mulsd  0x18(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  movsd  D66(%rip),%xmm6
  movsd  D45(%rip),%xmm7
  movsd  0x28(%rsp),%xmm2
  movsd  0x38(%rsp),%xmm4
  movsd  0x30(%rsp),%xmm5
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  mulsd  %xmm1,%xmm7
  mulsd  %xmm3,%xmm6
  subsd  %xmm7,%xmm6
  movsd  D54(%rip),%xmm7
  mulsd  %xmm0,%xmm7
  mulsd  0x10(%rsp),%xmm7
  addsd  %xmm7,%xmm6
  movsd  %xmm6,(%rbx)
  movsd  D69(%rip),%xmm6
  mulsd  %xmm6,%xmm2
  mulsd  %xmm6,%xmm0
  movapd %xmm2,%xmm7
  mulsd  %xmm4,%xmm2
  mulsd  %xmm5,%xmm0
  mulsd  %xmm5,%xmm7
  movsd  %xmm2,0x10(%rbx)
  movsd  D8(%rip),%xmm2
  mulsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm1
  movsd  %xmm7,0x8(%rbx)
  mulsd  %xmm2,%xmm3
  movsd  %xmm0,0x20(%rbx)
  subsd  %xmm3,%xmm1
  movsd  %xmm1,0x18(%rbx)
  add    $0x40,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D49
type_infered: f64
name: parse_data
arguments: label: D35
type_infered: byte[16]
name: parse_data
arguments: label: D66
type_infered: byte[8]
name: parse_data
arguments: label: D45
type_infered: f64
name: parse_data
arguments: label: D54
type_infered: f64
name: parse_data
arguments: label: D69
type_infered: f64
name: parse_data
arguments: label: D8
type_infered: f64

tool: D49: 1.75

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D66": [0x56,0x18,0x2a,0x20,0xb3,0x55,0xea,0xbf]}

tool: D45: 0.822961390324745

tool: D54: 1.64592278064949

tool: D69: 2.85082188141996

tool: D8: 1.42541094070998

assistant: ```c
void gint1_fn_pD(double *a, double a_a, double *p, double *out) {
  double tmp10, tmp2, tmp3, tmp4, v_0, v_1, v_2;
  v_0 = p[0] - a[0];
  v_1 = p[1] - a[1];
  v_2 = p[2] - a[2];
  tmp2 = v_1 * v_1;
  tmp3 = v_0 * v_0;
  tmp4 = v_2 * v_2;
  tmp10 = pow(a_a, 1.75) * exp(-a_a * (tmp2 + tmp3 + tmp4));
  tmp3 = tmp10 * tmp3;
  tmp2 = tmp10 * tmp2;
  out[0] = -0.822961390324745 * tmp2 - 0.822961390324745 * tmp3 + 1.64592278064949 * tmp10 * tmp4;
  tmp4 = tmp10 * v_2;
  out[1] = 2.85082188141996 * tmp4 * v_0;
  out[2] = 2.85082188141996 * tmp4 * v_1;
  out[3] = 1.42541094070998 * tmp3 - 1.42541094070998 * tmp2;
  out[4] = 2.85082188141996 * tmp10 * v_0 * v_1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gint1_fn_pD>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x40,%rsp
  movsd  0x8(%rsi),%xmm4
  movsd  (%rsi),%xmm5
  subsd  0x8(%rdi),%xmm4
  subsd  (%rdi),%xmm5
  movsd  %xmm0,0x20(%rsp)
  movsd  0x10(%rsi),%xmm2
  subsd  0x10(%rdi),%xmm2
  movsd  D11(%rip),%xmm1
  movapd %xmm4,%xmm7
  movsd  %xmm4,0x38(%rsp)
  mulsd  %xmm4,%xmm7
  movapd %xmm5,%xmm4
  movsd  %xmm5,0x30(%rsp)
  mulsd  %xmm5,%xmm4
  movapd %xmm2,%xmm5
  movsd  %xmm2,0x28(%rsp)
  mulsd  %xmm2,%xmm5
  movsd  %xmm7,(%rsp)
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm5,0x10(%rsp)
  call   <pow@plt>
  movsd  (%rsp),%xmm1
  addsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x18(%rsp)
  movsd  0x10(%rsp),%xmm0
  movsd  0x20(%rsp),%xmm3
  xorpd  D58(%rip),%xmm3
  addsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  call   <exp@plt>
  mulsd  0x18(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm4
  movsd  (%rsp),%xmm3
  movsd  D12(%rip),%xmm6
  movsd  D0(%rip),%xmm8
  movsd  0x28(%rsp),%xmm2
  movsd  D47(%rip),%xmm7
  movsd  0x30(%rsp),%xmm5
  mulsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  mulsd  %xmm4,%xmm8
  movapd %xmm4,%xmm1
  movsd  0x38(%rsp),%xmm4
  mulsd  %xmm3,%xmm6
  mulsd  %xmm7,%xmm2
  subsd  %xmm8,%xmm6
  movsd  D43(%rip),%xmm8
  mulsd  %xmm0,%xmm8
  mulsd  0x10(%rsp),%xmm8
  mulsd  %xmm7,%xmm0
  addsd  %xmm8,%xmm6
  movapd %xmm2,%xmm8
  mulsd  %xmm5,%xmm8
  mulsd  %xmm5,%xmm0
  mulsd  %xmm4,%xmm2
  unpcklpd %xmm8,%xmm6
  movups %xmm6,(%rbx)
  movsd  D45(%rip),%xmm6
  mulsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm1
  mulsd  %xmm6,%xmm3
  movsd  %xmm0,0x20(%rbx)
  subsd  %xmm3,%xmm1
  unpcklpd %xmm1,%xmm2
  movups %xmm2,0x10(%rbx)
  add    $0x40,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
datatype: f64
name: disassemble_data
arguments: data_label: D58
datatype: byte[16]
name: disassemble_data
arguments: data_label: D12
datatype: byte[8]
name: disassemble_data
arguments: data_label: D0
datatype: f64
name: disassemble_data
arguments: data_label: D47
datatype: f64
name: disassemble_data
arguments: data_label: D43
datatype: f64
name: disassemble_data
arguments: data_label: D45
datatype: f64

tool: D11: 1.75

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D12": [0x56,0x18,0x2a,0x20,0xb3,0x55,0xea,0xbf]}

tool: D0: 0.822961390324745

tool: D47: 2.85082188141996

tool: D43: 1.64592278064949

tool: D45: 1.42541094070998

assistant: ```c
void gint1_fn_pD(double *a, double a_a, double *p, double *out) {
  double tmp10, tmp2, tmp3, tmp4, v_0, v_1, v_2;
  v_0 = p[0] - a[0];
  v_1 = p[1] - a[1];
  v_2 = p[2] - a[2];
  tmp2 = v_1 * v_1;
  tmp3 = v_0 * v_0;
  tmp4 = v_2 * v_2;
  tmp10 = pow(a_a, 1.75) * exp(-a_a * (tmp2 + tmp3 + tmp4));
  tmp3 = tmp10 * tmp3;
  tmp2 = tmp10 * tmp2;
  out[0] = -0.822961390324745 * tmp2 - 0.822961390324745 * tmp3 + 1.64592278064949 * tmp10 * tmp4;
  tmp4 = tmp10 * v_2;
  out[1] = 2.85082188141996 * tmp4 * v_0;
  out[2] = 2.85082188141996 * tmp4 * v_1;
  out[3] = 1.42541094070998 * tmp3 - 1.42541094070998 * tmp2;
  out[4] = 2.85082188141996 * tmp10 * v_0 * v_1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hputi4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%edx
  lea    -0x30(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <hputc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int hputi4(hstring, keyword, ival)
char *hstring;
char *keyword;
int ival;
{
  char value[30];
  sprintf(value, "%d", ival);
  return (hputc(hstring, keyword, value));
}
```