ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<relacao_02>:
  endbr64
  sub    $0x48,%rsp
  mov    $0xa,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x323052,0x34(%rsp)
  movabs $0x100000001,%rax
  mov    %rax,(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x200000002,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000003,%rax
  mov    %rax,0x20(%rsp)
  call   <putchar@plt>
  mov    %rsp,%rdi
  call   <ehReflexiva@plt>
  cmp    $0x1,%eax
  je     L63
  lea    0x34(%rsp),%rsi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L63:
  xor    %eax,%eax
  call   <ehSimetrica@plt>
  cmp    $0x1,%eax
  je     L34
  lea    0x34(%rsp),%rsi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L34:
  xor    %eax,%eax
  call   <ehTransitiva@plt>
  cmp    $0x1,%eax
  je     L65
  lea    0x34(%rsp),%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L65:
  xor    %eax,%eax
  call   <ehAntiSimetrica@plt>
  test   %eax,%eax
  jne    L3
L8:
  xor    %eax,%eax
  call   <ehEquivalencia@plt>
  cmp    $0x1,%eax
  je     L50
  lea    0x34(%rsp),%rsi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L50:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x48,%rsp
  ret
  nopl   0x0(%rax)
L3:
  lea    0x34(%rsp),%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D37
type_infered: string
name: read_data
arguments: tag: D36
type_infered: string
name: read_data
arguments: tag: D8
type_infered: string
name: read_data
arguments: tag: D21
type_infered: string
name: read_data
arguments: tag: D31
type_infered: string

tool: D37: ERRO: [%s] - Problema na propriedade reflexiva!


tool: D36: ERRO: [%s] - Problema na propriedade simetrica!


tool: D8: ERRO: [%s] - Problema na propriedade transitiva!


tool: D21: ERRO: [%s] - Problema na verifiacao da equivalencia!


tool: D31: ERRO: [%s] - Problema na propriedade anti-simetrica!


assistant: ```c
void relacao_02() {
  char nome[4] = "R02";
  int conjS[3] = {1, 2, 3};
  int rho[5][2] = {{1, 1}, {1, 2}, {2, 1}, {2, 2}, {3, 3}};
  int reflexiva = 1;
  int simetrica = 1;
  int transitiva = 1;
  int anti_simetrica = 0;
  int equivalencia = 1;
  printf("\n");
  if (ehReflexiva(rho) != reflexiva) {
    printf("ERRO: [%s] - Problema na propriedade reflexiva!\n", nome);
  }
  if (ehSimetrica() != simetrica) {
    printf("ERRO: [%s] - Problema na propriedade simetrica!\n", nome);
  }
  if (ehTransitiva() != transitiva) {
    printf("ERRO: [%s] - Problema na propriedade transitiva!\n", nome);
  }
  if (ehAntiSimetrica() != anti_simetrica) {
    printf("ERRO: [%s] - Problema na propriedade anti-simetrica!\n", nome);
  }
  if (ehEquivalencia() != equivalencia) {
    printf("ERRO: [%s] - Problema na verifiacao da equivalencia!\n", nome);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fast_demul_10_large>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1000,-0x8(%rbp)
  movl   $0xa000,-0x4(%rbp)
  jmp    L6
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L3
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  or     %eax,-0xc(%rbp)
L3:
  sarl   -0x4(%rbp)
  sarl   -0x8(%rbp)
L6:
  cmpl   $0x0,-0x8(%rbp)
  jne    L24
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t fast_demul_10_large(uint32_t v) {
  uint32_t x = 0, b = 0x1000, b10 = 0xA000;
  while (b != 0) {
    if (b10 <= v) {
      v -= b10;
      x |= b;
    }
    b10 >>= 1;
    b >>= 1;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fast_demul_10_large>:
  endbr64
  mov    $0xd,%edx
  mov    $0xa000,%eax
  mov    $0x1000,%ecx
  mov    $0x0,%esi
  jmp    L1
L28:
  sar    %eax
  sar    %ecx
  sub    $0x1,%edx
  je     L5
L1:
  cmp    %eax,%edi
  jl     L28
  sub    %eax,%edi
  or     %ecx,%esi
  jmp    L28
L5:
  mov    %esi,%eax
  ret
```

assistant: ```c
uint32_t fast_demul_10_large(uint32_t v) {
  uint32_t x = 0, b = 0x1000, b10 = 0xA000;
  while (b != 0) {
    if (b10 <= v) {
      v -= b10;
      x |= b;
    }
    b10 >>= 1;
    b >>= 1;
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fast_demul_10_large>:
  endbr64
  mov    $0xd,%edx
  mov    $0xa000,%eax
  mov    $0x1000,%ecx
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L13:
  cmp    %eax,%edi
  jl     L17
  sub    %eax,%edi
  or     %ecx,%r8d
L17:
  sar    %eax
  sar    %ecx
  sub    $0x1,%edx
  jne    L13
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t fast_demul_10_large(uint32_t v) {
  uint32_t x = 0, b = 0x1000, b10 = 0xA000;
  while (b != 0) {
    if (b10 <= v) {
      v -= b10;
      x |= b;
    }
    b10 >>= 1;
    b >>= 1;
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fast_demul_10_large>:
  endbr64
  xor    %eax,%eax
  cmp    $0x9fff,%edi
  jle    L116
  sub    $0xa000,%edi
  mov    $0x1000,%eax
L116:
  cmp    $0x4fff,%edi
  jle    L77
  sub    $0x5000,%edi
  or     $0x8,%ah
L77:
  cmp    $0x27ff,%edi
  jle    L101
  sub    $0x2800,%edi
  or     $0x4,%ah
L101:
  cmp    $0x13ff,%edi
  jle    L119
  sub    $0x1400,%edi
  or     $0x2,%ah
L119:
  cmp    $0x9ff,%edi
  jle    L105
  sub    $0xa00,%edi
  or     $0x1,%ah
L105:
  cmp    $0x4ff,%edi
  jle    L102
  sub    $0x500,%edi
  or     $0x80,%al
L102:
  cmp    $0x27f,%edi
  jle    L18
  sub    $0x280,%edi
  or     $0x40,%eax
L18:
  cmp    $0x13f,%edi
  jle    L94
  sub    $0x140,%edi
  or     $0x20,%eax
L94:
  cmp    $0x9f,%edi
  jle    L107
  sub    $0xa0,%edi
  or     $0x10,%eax
L107:
  cmp    $0x4f,%edi
  jle    L78
  sub    $0x50,%edi
  or     $0x8,%eax
L78:
  cmp    $0x27,%edi
  jle    L84
  sub    $0x28,%edi
  or     $0x4,%eax
L84:
  cmp    $0x13,%edi
  jle    L74
  sub    $0x14,%edi
  or     $0x2,%eax
L74:
  mov    %eax,%edx
  or     $0x1,%edx
  cmp    $0x9,%edi
  cmovg  %edx,%eax
  ret
```

assistant: ```c
uint32_t fast_demul_10_large(uint32_t v) {
  uint32_t x = 0, b = 0x1000, b10 = 0xA000;
  while (b != 0) {
    if (b10 <= v) {
      v -= b10;
      x |= b;
    }
    b10 >>= 1;
    b >>= 1;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_pathconf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x8,%eax
  ja     L58
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D11(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xffff,%eax
  jmp    L8
  mov    $0x84,%eax
  jmp    L8
  mov    $0x1e,%eax
  jmp    L8
  mov    $0x200,%eax
  jmp    L8
  mov    $0x1000,%eax
  jmp    L8
  mov    $0x1,%eax
  jmp    L8
  mov    $0x0,%eax
  jmp    L8
  mov    $0x1,%eax
  jmp    L8
L58:
  mov    $0xffffffffffffffff,%rax
L8:
  pop    %rbp
  ret
```

assistant: ```c
long _pathconf(int name) {
  switch (name) {
  case _PC_LINK_MAX:
    return 65535L;
  case _PC_MAX_CANON:
  case _PC_MAX_INPUT:
    return 132;
  case _PC_NAME_MAX:
    return 30;
  case _PC_PATH_MAX:
    return 512;
  case _PC_PIPE_BUF:
    return 4096;
  case _PC_CHOWN_RESTRICTED:
    return 1;
  case _PC_NO_TRUNC:
    return 0;
  case _PC_VDISABLE:
    return 1;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_pathconf>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x8,%edi
  ja     L2
  mov    %edi,%edi
  lea    D9(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x84,%eax
  ret
  mov    $0x1e,%eax
  ret
  mov    $0x200,%eax
  ret
  mov    $0x1000,%eax
  ret
  mov    $0x1,%eax
  ret
  mov    $0x0,%eax
  ret
  mov    $0x1,%eax
  ret
L2:
  mov    $0xffffffffffffffff,%rax
  ret
  mov    $0xffff,%eax
  ret
```

assistant: ```c
long _pathconf(int name) {
  switch (name) {
  case _PC_LINK_MAX:
    return 65535L;
  case _PC_MAX_CANON:
  case _PC_MAX_INPUT:
    return 132;
  case _PC_NAME_MAX:
    return 30;
  case _PC_PATH_MAX:
    return 512;
  case _PC_PIPE_BUF:
    return 4096;
  case _PC_CHOWN_RESTRICTED:
    return 1;
  case _PC_NO_TRUNC:
    return 0;
  case _PC_VDISABLE:
    return 1;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_pathconf>:
  endbr64
  add    $0xffffff80,%edi
  mov    $0xffffffffffffffff,%rax
  cmp    $0x8,%edi
  ja     L5
  lea    D5(%rip),%rax
  mov    (%rax,%rdi,8),%rax
L5:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string

tool: D5: 

assistant: ```c
long _pathconf(int name) {
  switch (name) {
  case _PC_LINK_MAX:
    return 65535L;
  case _PC_MAX_CANON:
  case _PC_MAX_INPUT:
    return 132;
  case _PC_NAME_MAX:
    return 30;
  case _PC_PATH_MAX:
    return 512;
  case _PC_PIPE_BUF:
    return 4096;
  case _PC_CHOWN_RESTRICTED:
    return 1;
  case _PC_NO_TRUNC:
    return 0;
  case _PC_VDISABLE:
    return 1;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_pathconf>:
  endbr64
  add    $0xffffff80,%edi
  mov    $0xffffffffffffffff,%rax
  cmp    $0x8,%edi
  ja     L0
  lea    D4(%rip),%rax
  mov    (%rax,%rdi,8),%rax
L0:
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: string

tool: D4: 

assistant: ```c
long _pathconf(int name) {
  switch (name) {
  case _PC_LINK_MAX:
    return 65535L;
  case _PC_MAX_CANON:
  case _PC_MAX_INPUT:
    return 132;
  case _PC_NAME_MAX:
    return 30;
  case _PC_PATH_MAX:
    return 512;
  case _PC_PIPE_BUF:
    return 4096;
  case _PC_CHOWN_RESTRICTED:
    return 1;
  case _PC_NO_TRUNC:
    return 0;
  case _PC_VDISABLE:
    return 1;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<task10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  mov    $0x1e8480,%edi
  call   <sieveOfEratosthenes@plt>
  pop    %rbp
  ret
```

assistant: ```c
long task10() {
  if (64 == 32) {
    printf("INFO: This is a 32bit OS. Problem 10 can only be calculated under 64bit. =( \n");
    return -1;
  }
  return sieveOfEratosthenes(2000000, 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<task10>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1e8480,%edi
  call   <sieveOfEratosthenes@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long task10() {
  if (64 == 32) {
    printf("INFO: This is a 32bit OS. Problem 10 can only be calculated under 64bit. =( \n");
    return -1;
  }
  return sieveOfEratosthenes(2000000, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<task10>:
  endbr64
  mov    $0x1,%esi
  mov    $0x1e8480,%edi
  jmp    1050 <sieveOfEratosthenes@plt>
```

assistant: ```c
long task10() {
  if (64 == 32) {
    printf("INFO: This is a 32bit OS. Problem 10 can only be calculated under 64bit. =( \n");
    return -1;
  }
  return sieveOfEratosthenes(2000000, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<task10>:
  endbr64
  mov    $0x1,%esi
  mov    $0x1e8480,%edi
  jmp    1050 <sieveOfEratosthenes@plt>
```

assistant: ```c
long task10() {
  if (64 == 32) {
    printf("INFO: This is a 32bit OS. Problem 10 can only be calculated under 64bit. =( \n");
    return -1;
  }
  return sieveOfEratosthenes(2000000, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xtables_getportbyname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <getaddrinfo@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L16
  mov    $0xffffffff,%eax
  jmp    L1
L16:
  movl   $0xffffffff,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L58
L86:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L78
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L68
L78:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L51
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L68
L51:
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x10(%rbp)
L58:
  cmpq   $0x0,-0x10(%rbp)
  jne    L86
L68:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <freeaddrinfo@plt>
  cmpl   $0x0,-0x1c(%rbp)
  jns    L82
  mov    -0x1c(%rbp),%eax
  jmp    L1
L82:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int xtables_getportbyname(const char *name) {
  struct addrinfo *res = NULL, *p;
  int ret;
  ret = getaddrinfo(NULL, name, NULL, &res);
  if (ret < 0)
    return -1;
  ret = -1;
  for (p = res; p != NULL; p = p->ai_next) {
    if (p->ai_family == AF_INET6) {
      ret = ((struct sockaddr_in6 *)p->ai_addr)->sin6_port;
      break;
    } else if (p->ai_family == AF_INET) {
      ret = ((struct sockaddr_in *)p->ai_addr)->sin_port;
      break;
    }
  }
  freeaddrinfo(res);
  if (ret < 0)
    return ret;
  return ntohs(ret);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xtables_getportbyname>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rcx
  mov    $0x0,%edx
  mov    $0x0,%edi
  call   <getaddrinfo@plt>
  test   %eax,%eax
  js     L73
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L39
  mov    D18(%rip),%rax
  mov    (%rax),%rcx
  mov    D17(%rip),%rax
  mov    (%rax),%rsi
  mov    %rdi,%rax
L16:
  mov    (%rax),%rdx
  cmp    %rcx,%rdx
  je     L5
  cmp    %rsi,%rdx
  je     L93
  mov    0x10(%rax),%rax
  test   %rax,%rax
  jne    L16
L39:
  call   <freeaddrinfo@plt>
  mov    $0xffffffff,%ebx
  jmp    L65
L5:
  mov    0x8(%rax),%rax
  mov    (%rax),%ebx
L84:
  call   <freeaddrinfo@plt>
  test   %ebx,%ebx
  js     L65
  mov    %ebx,%edi
  call   <ntohs@plt>
  mov    %eax,%ebx
L65:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L93:
  mov    0x8(%rax),%rax
  mov    (%rax),%ebx
  jmp    L84
L73:
  mov    $0xffffffff,%ebx
  jmp    L65
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xtables_getportbyname(const char *name) {
  struct addrinfo *res = NULL, *p;
  int ret;
  ret = getaddrinfo(NULL, name, NULL, &res);
  if (ret < 0)
    return -1;
  ret = -1;
  for (p = res; p != NULL; p = p->ai_next) {
    if (p->ai_family == AF_INET6) {
      ret = ((struct sockaddr_in6 *)p->ai_addr)->sin6_port;
      break;
    } else if (p->ai_family == AF_INET) {
      ret = ((struct sockaddr_in *)p->ai_addr)->sin_port;
      break;
    }
  }
  freeaddrinfo(res);
  if (ret < 0)
    return ret;
  return ntohs(ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xtables_getportbyname>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  xor    %edx,%edx
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  movq   $0x0,(%rsp)
  call   <getaddrinfo@plt>
  test   %eax,%eax
  js     L37
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L50
  mov    D2(%rip),%rax
  mov    (%rax),%rcx
  mov    D10(%rip),%rax
  mov    (%rax),%rsi
  mov    %rdi,%rax
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L48:
  cmp    %rsi,%rdx
  je     L88
  mov    0x10(%rax),%rax
  test   %rax,%rax
  je     L50
L43:
  mov    (%rax),%rdx
  cmp    %rcx,%rdx
  jne    L48
L88:
  mov    0x8(%rax),%rax
  mov    (%rax),%r12d
  call   <freeaddrinfo@plt>
  test   %r12d,%r12d
  js     L23
  mov    %r12d,%edi
  call   <ntohs@plt>
  mov    %eax,%r12d
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L50:
  call   <freeaddrinfo@plt>
L37:
  mov    $0xffffffff,%r12d
  jmp    L23
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xtables_getportbyname(const char *name) {
  struct addrinfo *res = NULL, *p;
  int ret;
  ret = getaddrinfo(NULL, name, NULL, &res);
  if (ret < 0)
    return -1;
  ret = -1;
  for (p = res; p != NULL; p = p->ai_next) {
    if (p->ai_family == AF_INET6) {
      ret = ((struct sockaddr_in6 *)p->ai_addr)->sin6_port;
      break;
    } else if (p->ai_family == AF_INET) {
      ret = ((struct sockaddr_in *)p->ai_addr)->sin_port;
      break;
    }
  }
  freeaddrinfo(res);
  if (ret < 0)
    return ret;
  return ntohs(ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xtables_getportbyname>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  xor    %edx,%edx
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  movq   $0x0,(%rsp)
  call   <getaddrinfo@plt>
  test   %eax,%eax
  js     L22
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L32
  mov    D6(%rip),%rax
  mov    (%rax),%rcx
  mov    D10(%rip),%rax
  mov    (%rax),%rsi
  mov    %rdi,%rax
  jmp    L89
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    %rsi,%rdx
  je     L9
  mov    0x10(%rax),%rax
  test   %rax,%rax
  je     L32
L89:
  mov    (%rax),%rdx
  cmp    %rcx,%rdx
  jne    L7
L9:
  mov    0x8(%rax),%rax
  mov    (%rax),%r12d
  call   <freeaddrinfo@plt>
  test   %r12d,%r12d
  js     L78
  mov    %r12d,%edi
  call   <ntohs@plt>
  mov    %eax,%r12d
L78:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  call   <freeaddrinfo@plt>
L22:
  mov    $0xffffffff,%r12d
  jmp    L78
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xtables_getportbyname(const char *name) {
  struct addrinfo *res = NULL, *p;
  int ret;
  ret = getaddrinfo(NULL, name, NULL, &res);
  if (ret < 0)
    return -1;
  ret = -1;
  for (p = res; p != NULL; p = p->ai_next) {
    if (p->ai_family == AF_INET6) {
      ret = ((struct sockaddr_in6 *)p->ai_addr)->sin6_port;
      break;
    } else if (p->ai_family == AF_INET) {
      ret = ((struct sockaddr_in *)p->ai_addr)->sin_port;
      break;
    }
  }
  freeaddrinfo(res);
  if (ret < 0)
    return ret;
  return ntohs(ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
L29:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x19(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x18(%rbp)
  movzbl -0x19(%rbp),%eax
  cmp    $0x73,%al
  je     L34
  movzbl -0x19(%rbp),%eax
  cmp    $0x53,%al
  jne    L21
L34:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L29
L21:
  nop
  movl   $0x0,-0x14(%rbp)
  jmp    L22
L40:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L22:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L40
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D43
type: string
name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D16
type: string

tool: D24: Digite um valor para salvar no vetor: 

tool: D43: %d

tool: D14: Deseja cadastrar mais um numero? 

tool: D6:  %c

tool: D16:  (%d) 

assistant: ```c
int main() {
  int *vetor, contador = 0;
  char c;
  vetor = malloc(sizeof(int));
  while (1) {
    printf("Digite um valor para salvar no vetor: ");
    scanf("%d", &vetor[contador]);
    printf("Deseja cadastrar mais um numero? ");
    scanf(" %c", &c);
    contador++;
    if (c != 's' && c != 'S')
      break;
    vetor = realloc(vetor, sizeof(int) * (contador + 1));
  }
  for (int i = 0; i < contador; i++)
    printf(" (%d) ", vetor[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  lea    D4(%rip),%r15
  lea    D1(%rip),%r14
  jmp    L35
L44:
  lea    0x4(%rbp),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  mov    %r13d,%r12d
L35:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x1(%r12),%r13d
  add    $0x4,%rbp
  movzbl 0x7(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x53,%al
  je     L44
  mov    $0x0,%ebp
  lea    D30(%rip),%r14
  test   %r13d,%r13d
  jle    L15
L3:
  mov    (%rbx,%rbp,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbp
  lea    -0x1(%rbp),%eax
  cmp    %eax,%r12d
  jg     L3
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D1
type: string
name: retrieve_data
arguments: data_label: D28
type: string
name: retrieve_data
arguments: data_label: D46
type: string
name: retrieve_data
arguments: data_label: D30
type: string

tool: D4: Digite um valor para salvar no vetor: 

tool: D1: %d

tool: D28: Deseja cadastrar mais um numero? 

tool: D46:  %c

tool: D30:  (%d) 

assistant: ```c
int main() {
  int *vetor, contador = 0;
  char c;
  vetor = malloc(sizeof(int));
  while (1) {
    printf("Digite um valor para salvar no vetor: ");
    scanf("%d", &vetor[contador]);
    printf("Deseja cadastrar mais um numero? ");
    scanf(" %c", &c);
    contador++;
    if (c != 's' && c != 'S')
      break;
    vetor = realloc(vetor, sizeof(int) * (contador + 1));
  }
  for (int i = 0; i < contador; i++)
    printf(" (%d) ", vetor[i]);
}
```