ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skip_comment>:
  endbr64
  mov    $0x1,%eax
  jmp    L36
L43:
  cmp    $0x28,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
L24:
  add    $0x1,%rdi
  test   %eax,%eax
  jle    L64
L36:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L47
  cmp    $0x29,%dl
  je     L9
  cmp    $0x5c,%dl
  jne    L43
  cmpb   $0x1,0x1(%rdi)
  sbb    $0xffffffffffffffff,%rdi
  jmp    L24
L9:
  sub    $0x1,%eax
  jmp    L24
L47:
  mov    %rdi,%rax
  ret
L64:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *skip_comment(char *cp) {
  int nesting = 1;
  for (; nesting > 0 && *cp; cp++) {
    switch (*cp) {
    case '\\':
      if (cp[1])
        cp++;
      break;
    case '(':
      nesting++;
      break;
    case ')':
      nesting--;
      break;
    }
  }
  return (cp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_comment>:
  endbr64
  mov    $0x1,%esi
L28:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L2
L11:
  lea    0x1(%rdi),%rcx
  cmp    $0x29,%dl
  je     L74
  cmp    $0x5c,%dl
  je     L38
  cmp    $0x28,%dl
  je     L57
L76:
  mov    %rcx,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L11
L2:
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L74:
  mov    %rcx,%rax
  sub    $0x1,%esi
  jne    L76
  ret
  nopl   0x0(%rax)
L57:
  add    $0x1,%esi
  mov    %rcx,%rdi
  jmp    L28
L38:
  cmpb   $0x1,0x1(%rdi)
  sbb    $0xffffffffffffffff,%rcx
  jmp    L76
```

assistant: ```c
char *skip_comment(char *cp) {
  int nesting = 1;
  for (; nesting > 0 && *cp; cp++) {
    switch (*cp) {
    case '\\':
      if (cp[1])
        cp++;
      break;
    case '(':
      nesting++;
      break;
    case ')':
      nesting--;
      break;
    }
  }
  return (cp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<skip_comment>:
  endbr64
  mov    $0x1,%esi
L9:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L21
L15:
  lea    0x1(%rdi),%rcx
  cmp    $0x29,%dl
  je     L2
  cmp    $0x5c,%dl
  je     L66
  cmp    $0x28,%dl
  je     L17
L40:
  mov    %rcx,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L15
L21:
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L2:
  mov    %rcx,%rax
  sub    $0x1,%esi
  jne    L40
  ret
  nopl   0x0(%rax)
L17:
  add    $0x1,%esi
  mov    %rcx,%rdi
  jmp    L9
L66:
  cmpb   $0x1,0x1(%rdi)
  sbb    $0xffffffffffffffff,%rcx
  jmp    L40
```

assistant: ```c
char *skip_comment(char *cp) {
  int nesting = 1;
  for (; nesting > 0 && *cp; cp++) {
    switch (*cp) {
    case '\\':
      if (cp[1])
        cp++;
      break;
    case '(':
      nesting++;
      break;
    case ')':
      nesting--;
      break;
    }
  }
  return (cp);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<changepath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L39:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L19
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L15
L19:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5c,(%rax)
L15:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jb     L39
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *changepath(char *filename) {
  char *tmp;
  unsigned int i = 0;
  int j = 0;
  tmp = (char *)calloc(strlen(filename) + 1, sizeof(char));
  for (i = 0; i < strlen(filename); ++i) {
    if (filename[i] != '/')
      tmp[j] = filename[i];
    else
      tmp[j] = '\\';
    ++j;
  }
  tmp[j] = ('\0');
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<changepath>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  mov    $0x0,%ebx
  jmp    L32
L23:
  movb   $0x5c,0x0(%rbp)
L30:
  add    $0x1,%rbx
  add    $0x1,%rbp
L32:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L11
  movzbl (%r12,%rbx,1),%eax
  cmp    $0x2f,%al
  je     L23
  mov    %al,0x0(%rbp)
  jmp    L30
L11:
  movslq %ebx,%r14
  movb   $0x0,0x0(%r13,%r14,1)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *changepath(char *filename) {
  char *tmp;
  unsigned int i = 0;
  int j = 0;
  tmp = (char *)calloc(strlen(filename) + 1, sizeof(char));
  for (i = 0; i < strlen(filename); ++i) {
    if (filename[i] != '/')
      tmp[j] = filename[i];
    else
      tmp[j] = '\\';
    ++j;
  }
  tmp[j] = ('\0');
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<changepath>:
  endbr64
  push   %r13
  mov    $0x5c,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%edi
  call   <calloc@plt>
  mov    %rax,%r12
  jmp    L8
L16:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2f,%al
  cmove  %r13d,%eax
  add    $0x1,%rbx
  mov    %al,(%rdx)
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%r12,%rbx,1),%rdx
  cmp    %ebx,%eax
  ja     L16
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *changepath(char *filename) {
  char *tmp;
  unsigned int i = 0;
  int j = 0;
  tmp = (char *)calloc(strlen(filename) + 1, sizeof(char));
  for (i = 0; i < strlen(filename); ++i) {
    if (filename[i] != '/')
      tmp[j] = filename[i];
    else
      tmp[j] = '\\';
    ++j;
  }
  tmp[j] = ('\0');
  return tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<changepath>:
  endbr64
  push   %r13
  mov    $0x5c,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%edi
  call   <calloc@plt>
  mov    %rax,%r12
  jmp    L18
L1:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2f,%al
  cmove  %r13d,%eax
  add    $0x1,%rbx
  mov    %al,(%rdx)
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%r12,%rbx,1),%rdx
  cmp    %ebx,%eax
  ja     L1
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *changepath(char *filename) {
  char *tmp;
  unsigned int i = 0;
  int j = 0;
  tmp = (char *)calloc(strlen(filename) + 1, sizeof(char));
  for (i = 0; i < strlen(filename); ++i) {
    if (filename[i] != '/')
      tmp[j] = filename[i];
    else
      tmp[j] = '\\';
    ++j;
  }
  tmp[j] = ('\0');
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jg     L70
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L96
L70:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L94
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  jmp    L36
L94:
  mov    -0x8(%rbp),%eax
L36:
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L139
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L136
L139:
  mov    -0x4(%rbp),%eax
L136:
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <initarray@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L111
L101:
  movl   $0x3,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x3,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L104
L8:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L32
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isprime@plt>
  test   %rax,%rax
  jne    L64
L32:
  addl   $0x2,-0x10(%rbp)
  subl   $0x2,-0xc(%rbp)
L104:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L8
  jmp    L4
L64:
  nop
L4:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L80
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L80:
  addl   $0x2,-0x14(%rbp)
L111:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L101
  mov    $0x0,%eax
L96:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string

tool: D8: usage : goldbach2 min_n max_n

tool: D19: %d NG


assistant: ```c
int main(int ac, char *av[]) {
  int n, min_n, max_n, m1, m2;
  if (ac < 3) {
    printf("usage : goldbach2 min_n max_n\n");
    return (1);
  }
  min_n = strtol(av[1], NULL, 10);
  min_n = min_n % 2 == 1 ? min_n + 1 : min_n;
  max_n = strtol(av[2], NULL, 10);
  max_n = max_n % 2 == 1 ? max_n + 1 : max_n;
  initarray();
  for (n = min_n; n <= max_n; n += 2) {
    for (m1 = 3, m2 = n - 3; m1 <= m2; m1 += 2, m2 -= 2) {
      if (isprime(m1) && isprime(m2))
        break;
    }
    if (m1 > m2)
      printf("%d NG\n", n);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L83
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%r13d
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  je     L113
L123:
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%r14d
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  je     L14
L2:
  mov    $0x0,%eax
  call   <initarray@plt>
  cmp    %r14d,%r13d
  jg     L72
  lea    D10(%rip),%r15
  jmp    L172
L83:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L124
L113:
  add    $0x1,%r13d
  jmp    L123
L14:
  add    $0x1,%r14d
  jmp    L2
L46:
  add    $0x2,%ebx
  mov    %ebp,%eax
  sub    %ebx,%eax
  cmp    %ebx,%eax
  jl     L15
L19:
  mov    %ebp,%r12d
  sub    %ebx,%r12d
  mov    %ebx,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L46
  mov    %r12d,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L46
L26:
  cmp    %r12d,%ebx
  jg     L15
L114:
  add    $0x2,%r13d
  cmp    %r13d,%r14d
  jl     L162
L172:
  mov    %r13d,%ebp
  lea    -0x3(%r13),%r12d
  cmp    $0x2,%r12d
  jle    L82
  mov    $0x3,%ebx
  jmp    L19
L82:
  mov    $0x3,%ebx
  jmp    L26
L15:
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L114
L162:
  mov    $0x0,%eax
L124:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  mov    $0x0,%eax
  jmp    L124
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string

tool: D10: %d NG


tool: D11: usage : goldbach2 min_n max_n

assistant: ```c
int main(int ac, char *av[]) {
  int n, min_n, max_n, m1, m2;
  if (ac < 3) {
    printf("usage : goldbach2 min_n max_n\n");
    return (1);
  }
  min_n = strtol(av[1], NULL, 10);
  min_n = min_n % 2 == 1 ? min_n + 1 : min_n;
  max_n = strtol(av[2], NULL, 10);
  max_n = max_n % 2 == 1 ? max_n + 1 : max_n;
  initarray();
  for (n = min_n; n <= max_n; n += 2) {
    for (m1 = 3, m2 = n - 3; m1 <= m2; m1 += 2, m2 -= 2) {
      if (isprime(m1) && isprime(m2))
        break;
    }
    if (m1 > m2)
      printf("%d NG\n", n);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jle    L129
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    %rsi,%rbx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    $0x2,%ecx
  cltd
  mov    %eax,%ebp
  idiv   %ecx
  sub    $0x1,%edx
  je     L54
L131:
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    $0x2,%ecx
  cltd
  mov    %eax,%r12d
  idiv   %ecx
  sub    $0x1,%edx
  je     L56
L126:
  xor    %eax,%eax
  call   <initarray@plt>
  cmp    %r12d,%ebp
  jg     L146
  lea    D7(%rip),%r13
  xchg   %ax,%ax
L53:
  lea    -0x3(%rbp),%eax
  cmp    $0x2,%eax
  jle    L27
  mov    $0x3,%ebx
  jmp    L76
  nop
L141:
  add    $0x2,%ebx
  mov    %ebp,%edx
  sub    %ebx,%edx
  cmp    %edx,%ebx
  jg     L27
L76:
  mov    %ebp,%r14d
  mov    %ebx,%edi
  sub    %ebx,%r14d
  call   <isprime@plt>
  test   %rax,%rax
  je     L141
  mov    %r14d,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L141
  add    $0x2,%ebp
  cmp    %ebp,%r12d
  jge    L53
L146:
  xor    %eax,%eax
L75:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L27:
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x2,%ebp
  call   <printf@plt>
  cmp    %ebp,%r12d
  jge    L53
  jmp    L146
L56:
  add    $0x1,%r12d
  jmp    L126
L54:
  add    $0x1,%ebp
  jmp    L131
L129:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L75
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D7: %d NG


tool: D2: usage : goldbach2 min_n max_n

assistant: ```c
int main(int ac, char *av[]) {
  int n, min_n, max_n, m1, m2;
  if (ac < 3) {
    printf("usage : goldbach2 min_n max_n\n");
    return (1);
  }
  min_n = strtol(av[1], NULL, 10);
  min_n = min_n % 2 == 1 ? min_n + 1 : min_n;
  max_n = strtol(av[2], NULL, 10);
  max_n = max_n % 2 == 1 ? max_n + 1 : max_n;
  initarray();
  for (n = min_n; n <= max_n; n += 2) {
    for (m1 = 3, m2 = n - 3; m1 <= m2; m1 += 2, m2 -= 2) {
      if (isprime(m1) && isprime(m2))
        break;
    }
    if (m1 > m2)
      printf("%d NG\n", n);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jle    L46
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    %rsi,%rbx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    $0x2,%ecx
  cltd
  mov    %eax,%ebp
  idiv   %ecx
  sub    $0x1,%edx
  je     L53
L14:
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    $0x2,%ecx
  cltd
  mov    %eax,%r12d
  idiv   %ecx
  sub    $0x1,%edx
  je     L93
L33:
  xor    %eax,%eax
  call   <initarray@plt>
  cmp    %r12d,%ebp
  jg     L5
  lea    D8(%rip),%r13
  xchg   %ax,%ax
L50:
  lea    -0x3(%rbp),%eax
  cmp    $0x2,%eax
  jle    L39
  mov    $0x3,%ebx
  jmp    L72
  nop
L100:
  add    $0x2,%ebx
  mov    %ebp,%edx
  sub    %ebx,%edx
  cmp    %edx,%ebx
  jg     L39
L72:
  mov    %ebp,%r14d
  mov    %ebx,%edi
  sub    %ebx,%r14d
  call   <isprime@plt>
  test   %rax,%rax
  je     L100
  mov    %r14d,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L100
  add    $0x2,%ebp
  cmp    %ebp,%r12d
  jge    L50
L5:
  xor    %eax,%eax
L86:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L39:
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x2,%ebp
  call   <printf@plt>
  cmp    %ebp,%r12d
  jge    L50
  jmp    L5
L93:
  add    $0x1,%r12d
  jmp    L33
L53:
  add    $0x1,%ebp
  jmp    L14
L46:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L86
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string
name: read_data
arguments: data_label: D0
type_guessed: string

tool: D8: %d NG


tool: D0: usage : goldbach2 min_n max_n

assistant: ```c
int main(int ac, char *av[]) {
  int n, min_n, max_n, m1, m2;
  if (ac < 3) {
    printf("usage : goldbach2 min_n max_n\n");
    return (1);
  }
  min_n = strtol(av[1], NULL, 10);
  min_n = min_n % 2 == 1 ? min_n + 1 : min_n;
  max_n = strtol(av[2], NULL, 10);
  max_n = max_n % 2 == 1 ? max_n + 1 : max_n;
  initarray();
  for (n = min_n; n <= max_n; n += 2) {
    for (m1 = 3, m2 = n - 3; m1 <= m2; m1 += 2, m2 -= 2) {
      if (isprime(m1) && isprime(m2))
        break;
    }
    if (m1 > m2)
      printf("%d NG\n", n);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode_block>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  mov    $0x0,%esi
  mov    $0x0,%ecx
  lea    D3(%rip),%r8
  mov    $0x3f,%r11d
  mov    $0x0,%r10d
  mov    $0x3e,%ebx
  test   %rdi,%rdi
  jne    L59
L40:
  movzbl 0x5(%rsp),%edx
  mov    %edx,%ecx
  sar    $0x4,%cl
  movzbl 0x4(%rsp),%eax
  lea    (%rcx,%rax,4),%eax
  mov    %al,(%r9)
  movzbl 0x6(%rsp),%eax
  shl    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x2,%cl
  add    %ecx,%edx
  mov    %dl,0x1(%r9)
  shl    $0x6,%eax
  add    0x7(%rsp),%al
  mov    %al,0x2(%r9)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    %esi,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
  mov    %ebx,%eax
  jmp    L66
  mov    %r10d,%eax
L66:
  movslq %ecx,%rdx
  mov    %al,0x4(%rsp,%rdx,1)
  add    $0x1,%ecx
  add    $0x1,%esi
  add    $0x1,%rdi
  cmp    $0x3,%ecx
  jg     L40
L59:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L40
  lea    -0x20(%rdx),%eax
  cmp    $0x1d,%al
  ja     L92
  movzbl %al,%eax
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  lea    0x4(%rdx),%eax
  jmp    L66
L92:
  lea    -0x41(%rdx),%eax
  cmp    $0x19,%al
  jbe    L66
  lea    -0x61(%rdx),%eax
  cmp    $0x19,%al
  ja     L40
  lea    -0x47(%rdx),%eax
  jmp    L66
  mov    %r11d,%eax
  jmp    L66
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_block(unsigned char *in, unsigned char *out) {
  unsigned char *c = in;
  int i = 0, j = 0;
  char temp[4] = {0, 0, 0, 0};
  while (i < 4 && c && *c) {
    if (*c != ' ') {
      if (*c == '+') {
        temp[i] = 62;
      } else if (*c == '/') {
        temp[i] = 63;
      } else if (*c == '=') {
        temp[i] = 0;
      } else if (*c >= '0' && *c <= '9') {
        temp[i] = *c + 4;
      } else if (*c >= 'A' && *c <= 'Z') {
        temp[i] = *c - 65;
      } else if (*c >= 'a' && *c <= 'z') {
        temp[i] = *c - 71;
      } else if (*c == ' ') {
        j++;
      } else {
        break;
      }
      i++;
    }
    j++;
    c++;
  }
  out[0] = (temp[0] << 2) + (temp[1] >> 4);
  out[1] = (temp[1] << 4) + (temp[2] >> 2);
  out[2] = (temp[2] << 6) + (temp[3] >> 0);
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<decode_block>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r9
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %edx,%edx
  movl   $0x0,0x4(%rsp)
  test   %rdi,%rdi
  je     L72
  lea    D0(%rip),%rsi
  cs nopw 0x0(%rax,%rax,1)
L89:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L24
  lea    -0x20(%rdx),%eax
  cmp    $0x1d,%al
  ja     L28
  movzbl %al,%eax
  movslq (%rsi,%rax,4),%rax
  add    %rsi,%rax
  notrack jmp *%rax
  nop
  lea    0x4(%rdx),%eax
L102:
  movslq %ecx,%rdx
  add    $0x1,%ecx
  mov    %al,0x4(%rsp,%rdx,1)
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmp    $0x4,%ecx
  jne    L89
L24:
  movzbl 0x5(%rsp),%edx
  movzbl 0x4(%rsp),%ecx
  mov    %edx,%eax
  shl    $0x4,%edx
  sar    $0x4,%al
  lea    (%rax,%rcx,4),%ecx
  movzbl 0x6(%rsp),%eax
  mov    %eax,%esi
  shl    $0x6,%eax
  add    0x7(%rsp),%al
  sar    $0x2,%sil
  add    %esi,%edx
L72:
  mov    %cl,(%r9)
  mov    %dl,0x1(%r9)
  mov    %al,0x2(%r9)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  mov    %r8d,%eax
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  lea    -0x41(%rdx),%eax
  cmp    $0x19,%al
  jbe    L102
  lea    -0x61(%rdx),%eax
  cmp    $0x19,%al
  ja     L24
  lea    -0x47(%rdx),%eax
  jmp    L102
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  jmp    L102
  nop
  mov    $0x3f,%eax
  jmp    L102
  nopw   0x0(%rax,%rax,1)
  mov    $0x3e,%eax
  jmp    L102
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_block(unsigned char *in, unsigned char *out) {
  unsigned char *c = in;
  int i = 0, j = 0;
  char temp[4] = {0, 0, 0, 0};
  while (i < 4 && c && *c) {
    if (*c != ' ') {
      if (*c == '+') {
        temp[i] = 62;
      } else if (*c == '/') {
        temp[i] = 63;
      } else if (*c == '=') {
        temp[i] = 0;
      } else if (*c >= '0' && *c <= '9') {
        temp[i] = *c + 4;
      } else if (*c >= 'A' && *c <= 'Z') {
        temp[i] = *c - 65;
      } else if (*c >= 'a' && *c <= 'z') {
        temp[i] = *c - 71;
      } else if (*c == ' ') {
        j++;
      } else {
        break;
      }
      i++;
    }
    j++;
    c++;
  }
  out[0] = (temp[0] << 2) + (temp[1] >> 4);
  out[1] = (temp[1] << 4) + (temp[2] >> 2);
  out[2] = (temp[2] << 6) + (temp[3] >> 0);
  return j;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decode_block>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r9
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %edx,%edx
  movl   $0x0,0x4(%rsp)
  test   %rdi,%rdi
  je     L80
  lea    D5(%rip),%rsi
  cs nopw 0x0(%rax,%rax,1)
L57:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L44
  lea    -0x20(%rdx),%eax
  cmp    $0x1d,%al
  ja     L52
  movzbl %al,%eax
  movslq (%rsi,%rax,4),%rax
  add    %rsi,%rax
  notrack jmp *%rax
  nop
  lea    0x4(%rdx),%eax
L81:
  movslq %ecx,%rdx
  add    $0x1,%ecx
  mov    %al,0x4(%rsp,%rdx,1)
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmp    $0x4,%ecx
  jne    L57
L44:
  movzbl 0x5(%rsp),%edx
  movzbl 0x4(%rsp),%ecx
  mov    %edx,%eax
  shl    $0x4,%edx
  sar    $0x4,%al
  lea    (%rax,%rcx,4),%ecx
  movzbl 0x6(%rsp),%eax
  mov    %eax,%esi
  shl    $0x6,%eax
  add    0x7(%rsp),%al
  sar    $0x2,%sil
  add    %esi,%edx
L80:
  mov    %cl,(%r9)
  mov    %dl,0x1(%r9)
  mov    %al,0x2(%r9)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %r8d,%eax
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L52:
  lea    -0x41(%rdx),%eax
  cmp    $0x19,%al
  jbe    L81
  lea    -0x61(%rdx),%eax
  cmp    $0x19,%al
  ja     L44
  lea    -0x47(%rdx),%eax
  jmp    L81
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  jmp    L81
  nop
  mov    $0x3f,%eax
  jmp    L81
  nopw   0x0(%rax,%rax,1)
  mov    $0x3e,%eax
  jmp    L81
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_block(unsigned char *in, unsigned char *out) {
  unsigned char *c = in;
  int i = 0, j = 0;
  char temp[4] = {0, 0, 0, 0};
  while (i < 4 && c && *c) {
    if (*c != ' ') {
      if (*c == '+') {
        temp[i] = 62;
      } else if (*c == '/') {
        temp[i] = 63;
      } else if (*c == '=') {
        temp[i] = 0;
      } else if (*c >= '0' && *c <= '9') {
        temp[i] = *c + 4;
      } else if (*c >= 'A' && *c <= 'Z') {
        temp[i] = *c - 65;
      } else if (*c >= 'a' && *c <= 'z') {
        temp[i] = *c - 71;
      } else if (*c == ' ') {
        j++;
      } else {
        break;
      }
      i++;
    }
    j++;
    c++;
  }
  out[0] = (temp[0] << 2) + (temp[1] >> 4);
  out[1] = (temp[1] << 4) + (temp[2] >> 2);
  out[2] = (temp[2] << 6) + (temp[3] >> 0);
  return j;
}
```