ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<handle_writefd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  mov    $0x400,%edx
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x428,%rsp
  mov    %rdi,(%rsp)
  lea    0x10(%rsp),%r14
  mov    %esi,0xc(%rsp)
  mov    %r14,%rdi
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  test   %ebx,%ebx
  js     L26
  xor    %r15d,%r15d
  jmp    L89
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x1,%r15d
  cmp    %r15d,%ebx
  jl     L26
L89:
  cmp    %r15d,%ebp
  je     L22
  mov    %r13,%rsi
  mov    %r15d,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L22
  mov    (%rsp),%rcx
  mov    0xc(%rsp),%edx
  lea    D3(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  xor    %ecx,%ecx
  mov    $0x400,%edx
  mov    %r14,%rsi
  mov    %r15d,%edi
  call   <send@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L28
  mov    $0x400,%ecx
  mov    %r15d,%esi
  mov    %eax,%edx
  add    $0x1,%r15d
  sub    %eax,%ecx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  cmp    %r15d,%ebx
  jge    L89
  nop
L26:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x428,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    D7(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <perror@plt>
  jmp    L26
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D7
type_infered: string

tool: D3: [Remote socket %d says]: %s

tool: D4: (Socket %d): Written %d bytes, buffer available %d bytes.


tool: D7: send() failed

assistant: ```c
int handle_writefd(char *message, int sender_socket, int srv_socket, int max_fd, fd_set *active_fd_set) {
  char buf[1024];
  memset(buf, 0, sizeof(buf));
  int i, buf_written, buf_available = 0;
  for (i = 0; i <= max_fd; i++) {
    if (i == srv_socket) {
      continue;
    }
    if (FD_ISSET(i, active_fd_set)) {
      sprintf(buf, "[Remote socket %d says]: %s", sender_socket, message);
      buf_written = send(i, &buf, sizeof(buf), 0);
      if (buf_written < 0) {
        perror("send() failed");
        return -1;
      }
      buf_available = 1024 - buf_written;
      printf("(Socket %d): Written %d bytes, buffer available %d bytes.\n", i, buf_written, buf_available);
    }
  }
  return buf_written;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long int fn1(long long int x) {
  bar(x, 1);
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fn1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%esi
  call   <bar@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long long int fn1(long long int x) {
  bar(x, 1);
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn1>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    %rdi,%r12
  call   <bar@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long long int fn1(long long int x) {
  bar(x, 1);
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn1>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    %rdi,%r12
  call   <bar@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long long int fn1(long long int x) {
  bar(x, 1);
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<log_sys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <log_doit@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_sys(int level, const char *fmt, ...) {
  va_list arg;
  va_start(arg, fmt);
  log_doit(level, 0, 0, fmt, arg);
  va_end(arg);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<log_sys>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <log_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_sys(int level, const char *fmt, ...) {
  va_list arg;
  va_start(arg, fmt);
  log_doit(level, 0, 0, fmt, arg);
  va_end(arg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log_sys>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r13d,%edi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <log_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void log_sys(int level, const char *fmt, ...) {
  va_list arg;
  va_start(arg, fmt);
  log_doit(level, 0, 0, fmt, arg);
  va_end(arg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_sys>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r13d,%edi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <log_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void log_sys(int level, const char *fmt, ...) {
  va_list arg;
  va_start(arg, fmt);
  log_doit(level, 0, 0, fmt, arg);
  va_end(arg);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_skip_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L37
L34:
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L34
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L34
  mov    -0x8(%rbp),%rax
L37:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((pure)) char *str_skip_space(char *restrict str) {
  if (!str)
    return NULL;
  while ((*str == ' ') || (*str == '\t'))
    str++;
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_skip_space>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L37
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L43
  cmp    $0x9,%dl
  jne    L37
L43:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L43
  cmp    $0x9,%dl
  je     L43
L37:
  ret
```

assistant: ```c
__attribute__((pure)) char *str_skip_space(char *restrict str) {
  if (!str)
    return NULL;
  while ((*str == ' ') || (*str == '\t'))
    str++;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_skip_space>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  jne    L23
  jmp    L13
  xchg   %ax,%ax
L16:
  add    $0x1,%rax
L23:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L16
  cmp    $0x9,%dl
  je     L16
L13:
  ret
```

assistant: ```c
__attribute__((pure)) char *str_skip_space(char *restrict str) {
  if (!str)
    return NULL;
  while ((*str == ' ') || (*str == '\t'))
    str++;
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_skip_space>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  jne    L33
  jmp    L19
  xchg   %ax,%ax
L36:
  add    $0x1,%rax
L33:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L36
  cmp    $0x9,%dl
  je     L36
L19:
  ret
```

assistant: ```c
__attribute__((pure)) char *str_skip_space(char *restrict str) {
  if (!str)
    return NULL;
  while ((*str == ' ') || (*str == '\t'))
    str++;
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<binarize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  cmp    $0x28,%eax
  ja     L5
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%eax
  cmp    $0x28,%eax
  ja     L5
  mov    $0x107f107f,%eax
  jmp    L22
L5:
  mov    $0x10001000,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int binarize(unsigned int yCbCr422) {
  if (((yCbCr422 >> 24) & 0xff) <= 40 && ((yCbCr422 >> 8) & 0xff) <= 40)
    return 0x107F107F;
  else
    return 0x10001000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binarize>:
  endbr64
  mov    $0x10001000,%edx
  cmp    $0x28ffffff,%edi
  ja     L8
  mov    %edi,%eax
  movzbl %ah,%eax
  cmp    $0x29,%eax
  sbb    %edx,%edx
  and    $0x7f007f,%edx
  add    $0x10001000,%edx
L8:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int binarize(unsigned int yCbCr422) {
  if (((yCbCr422 >> 24) & 0xff) <= 40 && ((yCbCr422 >> 8) & 0xff) <= 40)
    return 0x107F107F;
  else
    return 0x10001000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binarize>:
  endbr64
  mov    $0x10001000,%r8d
  cmp    $0x28ffffff,%edi
  ja     L6
  mov    %edi,%eax
  movzbl %ah,%eax
  cmp    $0x29,%eax
  sbb    %r8d,%r8d
  and    $0x7f007f,%r8d
  add    $0x10001000,%r8d
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int binarize(unsigned int yCbCr422) {
  if (((yCbCr422 >> 24) & 0xff) <= 40 && ((yCbCr422 >> 8) & 0xff) <= 40)
    return 0x107F107F;
  else
    return 0x10001000;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binarize>:
  endbr64
  mov    $0x10001000,%r8d
  cmp    $0x28ffffff,%edi
  ja     L2
  mov    %edi,%eax
  movzbl %ah,%eax
  cmp    $0x29,%eax
  sbb    %r8d,%r8d
  and    $0x7f007f,%r8d
  add    $0x10001000,%r8d
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int binarize(unsigned int yCbCr422) {
  if (((yCbCr422 >> 24) & 0xff) <= 40 && ((yCbCr422 >> 8) & 0xff) <= 40)
    return 0x107F107F;
  else
    return 0x10001000;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scsi_status_is_good>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  andl   $0xfe,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L14
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L14:
  cmpl   $0x10,-0x14(%rbp)
  jne    L5
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L5:
  cmpl   $0x14,-0x14(%rbp)
  jne    L60
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L60:
  cmpl   $0x22,-0x14(%rbp)
  jne    L2
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L2:
  movl   $0x0,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int(scsi_status_is_good)(int status) {
  int tmp;
  {
    status &= 254;
    if (status == 0) {
      tmp = 1;
    } else {
      if (status == 16) {
        tmp = 1;
      } else {
        if (status == 20) {
          tmp = 1;
        } else {
          if (status == 34) {
            tmp = 1;
          } else {
            tmp = 0;
          }
        }
      }
    }
    return (tmp);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scsi_status_is_good>:
  endbr64
  mov    $0x1,%eax
  and    $0xfe,%edi
  je     L0
  cmp    $0x22,%edi
  ja     L1
  movabs $0x400110000,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L1:
  mov    $0x0,%eax
L0:
  ret
```

assistant: ```c
int(scsi_status_is_good)(int status) {
  int tmp;
  {
    status &= 254;
    if (status == 0) {
      tmp = 1;
    } else {
      if (status == 16) {
        tmp = 1;
      } else {
        if (status == 20) {
          tmp = 1;
        } else {
          if (status == 34) {
            tmp = 1;
          } else {
            tmp = 0;
          }
        }
      }
    }
    return (tmp);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<scsi_status_is_good>:
  endbr64
  mov    $0x1,%eax
  and    $0xfe,%edi
  je     L7
  sub    $0x10,%edi
  xor    %eax,%eax
  cmp    $0x12,%edi
  jbe    L18
L7:
  ret
  nopl   0x0(%rax)
L18:
  lea    D5(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: 

assistant: ```c
int(scsi_status_is_good)(int status) {
  int tmp;
  {
    status &= 254;
    if (status == 0) {
      tmp = 1;
    } else {
      if (status == 16) {
        tmp = 1;
      } else {
        if (status == 20) {
          tmp = 1;
        } else {
          if (status == 34) {
            tmp = 1;
          } else {
            tmp = 0;
          }
        }
      }
    }
    return (tmp);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scsi_status_is_good>:
  endbr64
  mov    $0x1,%eax
  and    $0xfe,%edi
  je     L9
  sub    $0x10,%edi
  xor    %eax,%eax
  cmp    $0x12,%edi
  jbe    L7
L9:
  ret
  nopl   0x0(%rax)
L7:
  lea    D8(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 

assistant: ```c
int(scsi_status_is_good)(int status) {
  int tmp;
  {
    status &= 254;
    if (status == 0) {
      tmp = 1;
    } else {
      if (status == 16) {
        tmp = 1;
      } else {
        if (status == 20) {
          tmp = 1;
        } else {
          if (status == 34) {
            tmp = 1;
          } else {
            tmp = 0;
          }
        }
      }
    }
    return (tmp);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4b,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <calculate_sec@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0xf,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void test2(void) {
  int input_sec = 75;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 0);
  assert(min == 1);
  assert(sec == 15);
}
```
user: What is the c source code of the assembly code below:

```asm
<test2>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x4b,%edi
  call   <calculate_sec@plt>
  cmpl   $0x0,0x14(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0xf,0xc(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test2(void) {
  int input_sec = 75;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 0);
  assert(min == 1);
  assert(sec == 15);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test2>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4b,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <calculate_sec@plt>
  mov    0x14(%rsp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0xf,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test2(void) {
  int input_sec = 75;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 0);
  assert(min == 1);
  assert(sec == 15);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test2>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4b,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <calculate_sec@plt>
  mov    0x14(%rsp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0xf,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test2(void) {
  int input_sec = 75;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 0);
  assert(min == 1);
  assert(sec == 15);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<coshfr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <mpfr_inits@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <mpfr_set_d@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpfr_cosh@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpfr_get_d@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <mpfr_clears@plt>
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double coshfr(double d) {
  mpfr_t frx;
  mpfr_inits(frx, NULL);
  mpfr_set_d(frx, d, GMP_RNDN);
  mpfr_cosh(frx, frx, GMP_RNDN);
  double ret = mpfr_get_d(frx, GMP_RNDN);
  mpfr_clears(frx, NULL);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<coshfr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%r12
  mov    $0x0,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpfr_inits@plt>
  mov    D1(%rip),%rbp
  mov    0x0(%rbp),%esi
  movq   %r12,%xmm0
  mov    %ebx,%edi
  call   <mpfr_set_d@plt>
  mov    0x0(%rbp),%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpfr_cosh@plt>
  mov    0x0(%rbp),%esi
  mov    %ebx,%edi
  call   <mpfr_get_d@plt>
  movq   %xmm0,%rbp
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <mpfr_clears@plt>
  movq   %rbp,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double coshfr(double d) {
  mpfr_t frx;
  mpfr_inits(frx, NULL);
  mpfr_set_d(frx, d, GMP_RNDN);
  mpfr_cosh(frx, frx, GMP_RNDN);
  double ret = mpfr_get_d(frx, GMP_RNDN);
  mpfr_clears(frx, NULL);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<coshfr>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %ebp,%edi
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <mpfr_inits@plt>
  mov    D3(%rip),%rbx
  movsd  0x8(%rsp),%xmm0
  mov    %ebp,%edi
  mov    (%rbx),%esi
  call   <mpfr_set_d@plt>
  mov    (%rbx),%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpfr_cosh@plt>
  mov    (%rbx),%esi
  mov    %ebp,%edi
  call   <mpfr_get_d@plt>
  mov    %ebp,%edi
  xor    %esi,%esi
  movsd  %xmm0,0x8(%rsp)
  call   <mpfr_clears@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double coshfr(double d) {
  mpfr_t frx;
  mpfr_inits(frx, NULL);
  mpfr_set_d(frx, d, GMP_RNDN);
  mpfr_cosh(frx, frx, GMP_RNDN);
  double ret = mpfr_get_d(frx, GMP_RNDN);
  mpfr_clears(frx, NULL);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<coshfr>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %ebp,%edi
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <mpfr_inits@plt>
  mov    D4(%rip),%rbx
  movsd  0x8(%rsp),%xmm0
  mov    %ebp,%edi
  mov    (%rbx),%esi
  call   <mpfr_set_d@plt>
  mov    (%rbx),%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpfr_cosh@plt>
  mov    (%rbx),%esi
  mov    %ebp,%edi
  call   <mpfr_get_d@plt>
  mov    %ebp,%edi
  xor    %esi,%esi
  movsd  %xmm0,0x8(%rsp)
  call   <mpfr_clears@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double coshfr(double d) {
  mpfr_t frx;
  mpfr_inits(frx, NULL);
  mpfr_set_d(frx, d, GMP_RNDN);
  mpfr_cosh(frx, frx, GMP_RNDN);
  double ret = mpfr_get_d(frx, GMP_RNDN);
  mpfr_clears(frx, NULL);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void(insw)(int port, void *addr, unsigned long count) {
  {
    ;
    return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insw>:
  endbr64
  ret
```

assistant: ```c
void(insw)(int port, void *addr, unsigned long count) {
  {
    ;
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insw>:
  endbr64
  ret
```

assistant: ```c
void(insw)(int port, void *addr, unsigned long count) {
  {
    ;
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<insw>:
  endbr64
  ret
```

assistant: ```c
void(insw)(int port, void *addr, unsigned long count) {
  {
    ;
    return;
  }
}
```