ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L37
  lea    D17(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L37:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0xb3,%sil
  je     L5
L2:
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L2
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
type: string
name: parse_data
arguments: tag: D3
type: string
name: parse_data
arguments: tag: D28
type: string

tool: D17: Call this program with %i arguments


tool: D3: %u


tool: D28: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 179) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lowceiling>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <niceprint@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5: The clearance of the cave or passage lowers suddenly to 3 feet above the water's surface. Each Medium character must succeed on a DC 10 Dexterity saving throw or take 1d4 bludgeoning damage from hitting the ceiling before the passage ends.



assistant: ```c
void lowceiling(void) {
  niceprint("The clearance of the cave or passage lowers suddenly to 3 feet above the water's surface. "
            "Each Medium character must succeed on a DC 10 Dexterity saving throw or take 1d4 "
            "bludgeoning damage from hitting the ceiling before the passage ends.\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lowceiling>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <niceprint@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: The clearance of the cave or passage lowers suddenly to 3 feet above the water's surface. Each Medium character must succeed on a DC 10 Dexterity saving throw or take 1d4 bludgeoning damage from hitting the ceiling before the passage ends.



assistant: ```c
void lowceiling(void) {
  niceprint("The clearance of the cave or passage lowers suddenly to 3 feet above the water's surface. "
            "Each Medium character must succeed on a DC 10 Dexterity saving throw or take 1d4 "
            "bludgeoning damage from hitting the ceiling before the passage ends.\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lowceiling>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <niceprint@plt>
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: The clearance of the cave or passage lowers suddenly to 3 feet above the water's surface. Each Medium character must succeed on a DC 10 Dexterity saving throw or take 1d4 bludgeoning damage from hitting the ceiling before the passage ends.



assistant: ```c
void lowceiling(void) {
  niceprint("The clearance of the cave or passage lowers suddenly to 3 feet above the water's surface. "
            "Each Medium character must succeed on a DC 10 Dexterity saving throw or take 1d4 "
            "bludgeoning damage from hitting the ceiling before the passage ends.\n\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lowceiling>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <niceprint@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: The clearance of the cave or passage lowers suddenly to 3 feet above the water's surface. Each Medium character must succeed on a DC 10 Dexterity saving throw or take 1d4 bludgeoning damage from hitting the ceiling before the passage ends.



assistant: ```c
void lowceiling(void) {
  niceprint("The clearance of the cave or passage lowers suddenly to 3 feet above the water's surface. "
            "Each Medium character must succeed on a DC 10 Dexterity saving throw or take 1d4 "
            "bludgeoning damage from hitting the ceiling before the passage ends.\n\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0xb,-0x4(%rbp)
  jmp    L17
L15:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x32,-0x4(%rbp)
  jle    L15
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: suma liczb od 11 do 50=%d


assistant: ```c
int main() {
  int suma, a;
  suma = 0;
  for (a = 11; a <= 50; a++) {
    suma = suma + a;
  }
  printf("suma liczb od 11 do 50=%d\n", suma);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%eax
L3:
  sub    $0x1,%eax
  jne    L3
  mov    $0x4c4,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: suma liczb od 11 do 50=%d


assistant: ```c
int main() {
  int suma, a;
  suma = 0;
  for (a = 11; a <= 50; a++) {
    suma = suma + a;
  }
  printf("suma liczb od 11 do 50=%d\n", suma);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4c4,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: suma liczb od 11 do 50=%d


assistant: ```c
int main() {
  int suma, a;
  suma = 0;
  for (a = 11; a <= 50; a++) {
    suma = suma + a;
  }
  printf("suma liczb od 11 do 50=%d\n", suma);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4c4,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string

tool: D7: suma liczb od 11 do 50=%d


assistant: ```c
int main() {
  int suma, a;
  suma = 0;
  for (a = 11; a <= 50; a++) {
    suma = suma + a;
  }
  printf("suma liczb od 11 do 50=%d\n", suma);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<psmat2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  movss  %xmm1,-0x10(%rbp)
  movss  %xmm2,-0x14(%rbp)
  movss  %xmm3,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <mat2@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct mat2 *psmat2(struct mat2 *result, float m11, float m12, float m21, float m22) {
  mat2((float *)result, m11, m12, m21, m22);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<psmat2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mat2@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct mat2 *psmat2(struct mat2 *result, float m11, float m12, float m21, float m22) {
  mat2((float *)result, m11, m12, m21, m22);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<psmat2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat2@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat2 *psmat2(struct mat2 *result, float m11, float m12, float m21, float m22) {
  mat2((float *)result, m11, m12, m21, m22);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<psmat2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat2@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat2 *psmat2(struct mat2 *result, float m11, float m12, float m21, float m22) {
  mat2((float *)result, m11, m12, m21, m22);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<mystrtok_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L38
  mov    -0x18(%rbp),%rax
  mov    %rax,D103(%rip)
L38:
  mov    D103(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L24
L34:
  mov    D103(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D105(%rip)
L24:
  mov    D105(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  mov    D105(%rip),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L34
L11:
  movq   $0x0,-0x10(%rbp)
  mov    D105(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    D105(%rip),%rax
  cmp    %rax,-0x8(%rbp)
  je     L54
L23:
  mov    D105(%rip),%rax
  sub    -0x8(%rbp),%rax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    D105(%rip),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    D105(%rip),%rdx
  mov    D105(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  add    %rdx,%rax
  mov    %rax,D105(%rip)
L54:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mystrtok_alloc(const char *str, int delim) {
  static const char *p;
  if (str) {
    p = str;
  }
  const char *s = p;
  while (*p && *p != delim) {
    p++;
  }
  char *ret = NULL;
  if (*p || p != s) {
    ret = calloc(p - s + 1, 1);
    memcpy(ret, s, p - s);
    p += !!*p;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mystrtok_alloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L89
  mov    %rdi,D68(%rip)
L89:
  mov    D68(%rip),%rbx
  movzbl (%rbx),%eax
  mov    %rbx,%rdi
  mov    $0x0,%ecx
  mov    $0x1,%r8d
  mov    $0x0,%ebp
  test   %al,%al
  je     L84
L52:
  movsbl %al,%edx
  cmp    %esi,%edx
  je     L8
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  mov    %r8d,%ecx
  test   %al,%al
  je     L97
  mov    %rdi,%r9
  jmp    L52
L97:
  mov    %rdi,D17(%rip)
L11:
  cmp    %rdi,%rbx
  jne    L3
  test   %al,%al
  je     L21
L3:
  sub    %rbx,%rdi
  add    $0x1,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    D17(%rip),%edx
  sub    %ebx,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    D17(%rip),%rax
  cmpb   $0x1,(%rax)
  sbb    $0xffffffffffffffff,%rax
  mov    %rax,D17(%rip)
L84:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  test   %cl,%cl
  je     L11
  mov    %r9,D17(%rip)
  jmp    L11
L21:
  mov    $0x0,%ebp
  jmp    L84
```

assistant: ```c
char *mystrtok_alloc(const char *str, int delim) {
  static const char *p;
  if (str) {
    p = str;
  }
  const char *s = p;
  while (*p && *p != delim) {
    p++;
  }
  char *ret = NULL;
  if (*p || p != s) {
    ret = calloc(p - s + 1, 1);
    memcpy(ret, s, p - s);
    p += !!*p;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mystrtok_alloc>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  mov    D68(%rip),%rbp
  test   %rdi,%rdi
  je     L31
  mov    %rdi,D6(%rip)
  mov    %rdi,%rbp
L31:
  movsbl 0x0(%rbp),%eax
  mov    %rbp,%rdi
  xor    %edx,%edx
  test   %al,%al
  jne    L14
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L47:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  mov    $0x1,%edx
  test   %al,%al
  je     L74
  mov    %rdi,%rcx
L14:
  cmp    %esi,%eax
  jne    L47
  test   %dl,%dl
  je     L52
  mov    %rcx,D6(%rip)
  jmp    L52
  nopl   (%rax)
L74:
  mov    %rdi,D6(%rip)
  cmp    %rbp,%rdi
  je     L58
L52:
  sub    %rbp,%rdi
  mov    $0x1,%esi
  add    $0x1,%edi
  call   <calloc@plt>
  mov    D6(%rip),%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  sub    %ebp,%edx
  call   <memcpy@plt>
  mov    D6(%rip),%rax
  cmpb   $0x1,(%rax)
  sbb    $0xffffffffffffffff,%rax
  mov    %rax,D6(%rip)
L81:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  xor    %r12d,%r12d
  jmp    L81
```

assistant: ```c
char *mystrtok_alloc(const char *str, int delim) {
  static const char *p;
  if (str) {
    p = str;
  }
  const char *s = p;
  while (*p && *p != delim) {
    p++;
  }
  char *ret = NULL;
  if (*p || p != s) {
    ret = calloc(p - s + 1, 1);
    memcpy(ret, s, p - s);
    p += !!*p;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mystrtok_alloc>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  mov    D11(%rip),%rbp
  test   %rdi,%rdi
  je     L84
  mov    %rdi,D1(%rip)
  mov    %rdi,%rbp
L84:
  movsbl 0x0(%rbp),%eax
  mov    %rbp,%rdi
  xor    %edx,%edx
  test   %al,%al
  jne    L44
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  mov    $0x1,%edx
  test   %al,%al
  je     L40
  mov    %rdi,%rcx
L44:
  cmp    %esi,%eax
  jne    L2
  test   %dl,%dl
  je     L64
  mov    %rcx,D1(%rip)
  jmp    L64
  nopl   (%rax)
L40:
  mov    %rdi,D1(%rip)
  cmp    %rbp,%rdi
  je     L11
L64:
  sub    %rbp,%rdi
  mov    $0x1,%esi
  add    $0x1,%edi
  call   <calloc@plt>
  mov    D1(%rip),%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  sub    %ebp,%edx
  call   <memcpy@plt>
  mov    D1(%rip),%rax
  cmpb   $0x1,(%rax)
  sbb    $0xffffffffffffffff,%rax
  mov    %rax,D1(%rip)
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r12d,%r12d
  jmp    L17
```

assistant: ```c
char *mystrtok_alloc(const char *str, int delim) {
  static const char *p;
  if (str) {
    p = str;
  }
  const char *s = p;
  while (*p && *p != delim) {
    p++;
  }
  char *ret = NULL;
  if (*p || p != s) {
    ret = calloc(p - s + 1, 1);
    memcpy(ret, s, p - s);
    p += !!*p;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    $0x7,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L47
L1:
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x38(%rbp)
L47:
  cmpl   $0x6,-0x38(%rbp)
  jle    L1
  lea    -0x30(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <quick_sort@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L16
L12:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L16:
  cmpl   $0x6,-0x34(%rbp)
  jle    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D25
type: string
name: read_data
arguments: tag: D22
type: string

tool: D12: Enter %d elements:


tool: D25: %d

tool: D22: %d, 

assistant: ```c
int main() {
  int32_t data[7] = {0};
  printf("Enter %d elements:\n", 7);
  for (int i = 0; i < 7; ++i) {
    scanf("%d", &data[i]);
  }
  quick_sort(data, 7);
  for (int i = 0; i < 7; ++i) {
    printf("%d, ", data[i]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  mov    $0x7,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  mov    %rbx,%rbp
  lea    D10(%rip),%r13
L25:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L25
  mov    %rsp,%rdi
  mov    $0x7,%esi
  call   <quick_sort@plt>
  lea    D25(%rip),%rbp
L27:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D10
type: string
name: retrieve_data
arguments: tag: D25
type: string

tool: D14: Enter %d elements:


tool: D10: %d

tool: D25: %d, 

assistant: ```c
int main() {
  int32_t data[7] = {0};
  printf("Enter %d elements:\n", 7);
  for (int i = 0; i < 7; ++i) {
    scanf("%d", &data[i]);
  }
  quick_sort(data, 7);
  for (int i = 0; i < 7; ++i) {
    printf("%d, ", data[i]);
  }
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  mov    $0x7,%esi
  lea    D24(%rip),%rdi
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  movaps %xmm0,(%rsp)
  lea    0x1c(%rsp),%r12
  movq   $0x0,0x10(%rsp)
  mov    %r14,%rbx
  mov    %r14,%rbp
  movl   $0x0,0x18(%rsp)
  call   <printf@plt>
  nop
L10:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L10
  mov    $0x7,%esi
  mov    %r14,%rdi
  lea    D23(%rip),%rbp
  call   <quick_sort@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
datatype: string
name: retrieve_data
arguments: tag: D12
datatype: string
name: retrieve_data
arguments: tag: D23
datatype: string

tool: D24: Enter %d elements:


tool: D12: %d

tool: D23: %d, 

assistant: ```c
int main() {
  int32_t data[7] = {0};
  printf("Enter %d elements:\n", 7);
  for (int i = 0; i < 7; ++i) {
    scanf("%d", &data[i]);
  }
  quick_sort(data, 7);
  for (int i = 0; i < 7; ++i) {
    printf("%d, ", data[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  mov    $0x7,%esi
  lea    D8(%rip),%rdi
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  movaps %xmm0,(%rsp)
  lea    0x1c(%rsp),%r12
  movq   $0x0,0x10(%rsp)
  mov    %r14,%rbx
  mov    %r14,%rbp
  movl   $0x0,0x18(%rsp)
  call   <printf@plt>
  nop
L2:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L2
  mov    $0x7,%esi
  mov    %r14,%rdi
  lea    D14(%rip),%rbp
  call   <quick_sort@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string
name: retrieve_data
arguments: data_label: D27
data_type: string
name: retrieve_data
arguments: data_label: D14
data_type: string

tool: D8: Enter %d elements:


tool: D27: %d

tool: D14: %d, 

assistant: ```c
int main() {
  int32_t data[7] = {0};
  printf("Enter %d elements:\n", 7);
  for (int i = 0; i < 7; ++i) {
    scanf("%d", &data[i]);
  }
  quick_sort(data, 7);
  for (int i = 0; i < 7; ++i) {
    printf("%d, ", data[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Com_Freeze_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L27
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <Com_Printf@plt>
  jmp    L10
L27:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%edi
  call   <atof@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <Com_Milliseconds@plt>
  mov    %eax,-0x8(%rbp)
L18:
  mov    $0x0,%eax
  call   <Com_Milliseconds@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D16(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  comisd %xmm1,%xmm0
  ja     L17
  jmp    L18
L17:
  nop
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: f64

tool: D15: freeze <seconds>


tool: D16: 0.001

assistant: ```c
void Com_Freeze_f(void) {
  float s;
  int start, now;
  if (Cmd_Argc() != 2) {
    Com_Printf("freeze <seconds>\n");
    return;
  }
  s = atof(Cmd_Argv(1));
  start = Com_Milliseconds();
  while (1) {
    now = Com_Milliseconds();
    if ((now - start) * 0.001 > s) {
      break;
    }
  }
}
```