ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<quicksortlib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <median@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort@plt>
  nop
  leave
  ret
```

assistant: ```c
void quicksortlib(int a[], int low, int high) {
  int median1, temp;
  int middle = (high - low) / 2;
  median1 = median(a[low], a[middle], a[high]);
  a[middle] = a[low];
  a[low] = median1;
  quicksort(a, low, high);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quicksortlib>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  sub    %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r14
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r13
  movslq %r12d,%rax
  mov    (%rdi,%rax,4),%edx
  mov    (%r14),%esi
  mov    0x0(%r13),%edi
  call   <median@plt>
  mov    0x0(%r13),%edx
  mov    %edx,(%r14)
  mov    %eax,0x0(%r13)
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <quicksort@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void quicksortlib(int a[], int low, int high) {
  int median1, temp;
  int middle = (high - low) / 2;
  median1 = median(a[low], a[middle], a[high]);
  a[middle] = a[low];
  a[low] = median1;
  quicksort(a, low, high);
}
```
user: Translate the below assembly code into C programming language:

```asm
<quicksortlib>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  sub    %esi,%edx
  mov    %edx,%eax
  push   %r12
  mov    %esi,%r12d
  shr    $0x1f,%eax
  push   %rbp
  mov    %rdi,%rbp
  add    %edx,%eax
  push   %rbx
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r14
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rbx
  movslq %r13d,%rax
  mov    (%r14),%esi
  mov    (%rdi,%rax,4),%edx
  mov    (%rbx),%edi
  call   <median@plt>
  mov    (%rbx),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %edx,(%r14)
  mov    %r13d,%edx
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <quicksort@plt>
```

assistant: ```c
void quicksortlib(int a[], int low, int high) {
  int median1, temp;
  int middle = (high - low) / 2;
  median1 = median(a[low], a[middle], a[high]);
  a[middle] = a[low];
  a[low] = median1;
  quicksort(a, low, high);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quicksortlib>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  sub    %esi,%edx
  mov    %edx,%eax
  push   %r12
  mov    %esi,%r12d
  shr    $0x1f,%eax
  push   %rbp
  mov    %rdi,%rbp
  add    %edx,%eax
  push   %rbx
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r14
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rbx
  movslq %r13d,%rax
  mov    (%r14),%esi
  mov    (%rdi,%rax,4),%edx
  mov    (%rbx),%edi
  call   <median@plt>
  mov    (%rbx),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %edx,(%r14)
  mov    %r13d,%edx
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <quicksort@plt>
```

assistant: ```c
void quicksortlib(int a[], int low, int high) {
  int median1, temp;
  int middle = (high - low) / 2;
  median1 = median(a[low], a[middle], a[high]);
  a[middle] = a[low];
  a[low] = median1;
  quicksort(a, low, high);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_invert_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L4
  lea    D36(%rip),%rax
  mov    %rax,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D21(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D33(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D34(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D29(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D36
type: string
name: retrieve_data
arguments: label: D21
type: string
name: retrieve_data
arguments: label: D33
type: string
name: retrieve_data
arguments: label: D34
type: string
name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D3
type: string

tool: 

tool: D21: %sApply an inversion filter;  arithmetic inversion preserving min and max.


tool: D33: %s


tool: D34: %susage: %s [<value>]


tool: D29: %s  <value>                  'middle value' to reflect values about


tool: D3: %s                           (by default we use (min+max)/2)


assistant: ```c
void op_invert_usage(char *name, FILE *f, char *indent) {
  if (indent == NULL)
    indent = "";
  fprintf(f, "%sApply an inversion filter;  arithmetic inversion preserving min and max.\n", indent);
  fprintf(f, "%s\n", indent);
  fprintf(f, "%susage: %s [<value>]\n", indent, name);
  fprintf(f, "%s  <value>                  'middle value' to reflect values about\n", indent);
  fprintf(f, "%s                           (by default we use (min+max)/2)\n", indent);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<op_invert_usage>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  test   %rdx,%rdx
  lea    D12(%rip),%rax
  cmove  %rax,%rbx
  mov    %rbx,%rdx
  lea    D35(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rdx
  lea    D58(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    %rbx,%rdx
  lea    D42(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rdx
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rdx
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D35
data_type: string
name: unpack_data
arguments: tag: D58
data_type: string
name: unpack_data
arguments: tag: D42
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string

tool: 

tool: D35: %sApply an inversion filter;  arithmetic inversion preserving min and max.


tool: D58: %s


tool: D42: %susage: %s [<value>]


tool: D27: %s  <value>                  'middle value' to reflect values about


tool: D16: %s                           (by default we use (min+max)/2)


assistant: ```c
void op_invert_usage(char *name, FILE *f, char *indent) {
  if (indent == NULL)
    indent = "";
  fprintf(f, "%sApply an inversion filter;  arithmetic inversion preserving min and max.\n", indent);
  fprintf(f, "%s\n", indent);
  fprintf(f, "%susage: %s [<value>]\n", indent, name);
  fprintf(f, "%s  <value>                  'middle value' to reflect values about\n", indent);
  fprintf(f, "%s                           (by default we use (min+max)/2)\n", indent);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<op_invert_usage>:
  endbr64
  test   %rdx,%rdx
  push   %r13
  lea    D37(%rip),%rax
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  cmove  %rax,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %eax,%eax
  mov    %rbp,%rdi
  lea    D12(%rip),%rsi
  mov    %r12,%rdx
  call   <fprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D56(%rip),%rsi
  call   <fprintf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D21(%rip),%rsi
  call   <fprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  lea    D45(%rip),%rsi
  pop    %r12
  pop    %r13
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D56
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D21
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D45
type_guessed: string

tool: 

tool: D12: %sApply an inversion filter;  arithmetic inversion preserving min and max.


tool: D56: %s


tool: D8: %susage: %s [<value>]


tool: D21: %s  <value>                  'middle value' to reflect values about


tool: D45: %s                           (by default we use (min+max)/2)


assistant: ```c
void op_invert_usage(char *name, FILE *f, char *indent) {
  if (indent == NULL)
    indent = "";
  fprintf(f, "%sApply an inversion filter;  arithmetic inversion preserving min and max.\n", indent);
  fprintf(f, "%s\n", indent);
  fprintf(f, "%susage: %s [<value>]\n", indent, name);
  fprintf(f, "%s  <value>                  'middle value' to reflect values about\n", indent);
  fprintf(f, "%s                           (by default we use (min+max)/2)\n", indent);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<op_invert_usage>:
  endbr64
  test   %rdx,%rdx
  push   %r13
  lea    D14(%rip),%rax
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  cmove  %rax,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %eax,%eax
  mov    %rbp,%rdi
  lea    D30(%rip),%rsi
  mov    %r12,%rdx
  call   <fprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D44(%rip),%rsi
  call   <fprintf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D31(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D2(%rip),%rsi
  call   <fprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  lea    D0(%rip),%rsi
  pop    %r12
  pop    %r13
  jmp    1050 <fprintf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D30
type: string
name: disassemble_data
arguments: label: D44
type: string
name: disassemble_data
arguments: label: D31
type: string
name: disassemble_data
arguments: label: D2
type: string
name: disassemble_data
arguments: label: D0
type: string

tool: 

tool: D30: %sApply an inversion filter;  arithmetic inversion preserving min and max.


tool: D44: %s


tool: D31: %susage: %s [<value>]


tool: D2: %s  <value>                  'middle value' to reflect values about


tool: D0: %s                           (by default we use (min+max)/2)


assistant: ```c
void op_invert_usage(char *name, FILE *f, char *indent) {
  if (indent == NULL)
    indent = "";
  fprintf(f, "%sApply an inversion filter;  arithmetic inversion preserving min and max.\n", indent);
  fprintf(f, "%s\n", indent);
  fprintf(f, "%susage: %s [<value>]\n", indent, name);
  fprintf(f, "%s  <value>                  'middle value' to reflect values about\n", indent);
  fprintf(f, "%s                           (by default we use (min+max)/2)\n", indent);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<indent_put2s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <do_indent@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <out_str@plt>
  mov    $0xa,%edi
  call   <outc@plt>
  nop
  leave
  ret
```

assistant: ```c
void indent_put2s(const char fmt[], const char arg[]) {
  do_indent();
  out_str(fmt, arg);
  outc('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<indent_put2s>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <do_indent@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <out_str@plt>
  mov    $0xa,%edi
  call   <outc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void indent_put2s(const char fmt[], const char arg[]) {
  do_indent();
  out_str(fmt, arg);
  outc('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<indent_put2s>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <do_indent@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <out_str@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <outc@plt>
```

assistant: ```c
void indent_put2s(const char fmt[], const char arg[]) {
  do_indent();
  out_str(fmt, arg);
  outc('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<indent_put2s>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <do_indent@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <out_str@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <outc@plt>
```

assistant: ```c
void indent_put2s(const char fmt[], const char arg[]) {
  do_indent();
  out_str(fmt, arg);
  outc('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<ltcmat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movq   D28(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x20(%rbp),%xmm0
  movq   D28(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,0x8(%rax)
  mov    -0x30(%rbp),%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,0x10(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  movsd  -0x10(%rbp),%xmm0
  movq   D28(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,0x10(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x30,%rax
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x30,%rax
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x30,%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,0x10(%rax)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D28
type: f32[2]

tool: {"D28": [0.0,-0.0]}

assistant: ```c
void ltcmat(double *llh, double t[3][3]) {
  double slat, clat;
  double slon, clon;
  slat = sin(llh[0]);
  clat = cos(llh[0]);
  slon = sin(llh[1]);
  clon = cos(llh[1]);
  t[0][0] = -slat * clon;
  t[0][1] = -slat * slon;
  t[0][2] = clat;
  t[1][0] = -slon;
  t[1][1] = clon;
  t[1][2] = 0.0;
  t[2][0] = clat * clon;
  t[2][1] = clat * slon;
  t[2][2] = slat;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ltcmat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  lea    0x8(%rsp),%r14
  mov    %rsp,%r15
  mov    %r15,%rsi
  mov    %r14,%rdi
  movsd  0x0(%r13),%xmm0
  call   <sincos@plt>
  mov    (%rsp),%rbp
  mov    0x8(%rsp),%r12
  movsd  0x8(%r13),%xmm0
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <sincos@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm3
  movq   D8(%rip),%xmm1
  movq   %r12,%xmm2
  xorpd  %xmm1,%xmm2
  movapd %xmm2,%xmm4
  mulsd  %xmm0,%xmm4
  movsd  %xmm4,(%rbx)
  mulsd  %xmm3,%xmm2
  movsd  %xmm2,0x8(%rbx)
  mov    %rbp,0x10(%rbx)
  xorpd  %xmm3,%xmm1
  movsd  %xmm1,0x18(%rbx)
  movsd  %xmm0,0x20(%rbx)
  movq   $0x0,0x28(%rbx)
  movq   %rbp,%xmm5
  mulsd  %xmm5,%xmm0
  movsd  %xmm0,0x30(%rbx)
  mulsd  %xmm5,%xmm3
  movsd  %xmm3,0x38(%rbx)
  mov    %r12,0x40(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: f32[2]

tool: {"D8": [0.0,-0.0]}

assistant: ```c
void ltcmat(double *llh, double t[3][3]) {
  double slat, clat;
  double slon, clon;
  slat = sin(llh[0]);
  clat = cos(llh[0]);
  slon = sin(llh[1]);
  clon = cos(llh[1]);
  t[0][0] = -slat * clon;
  t[0][1] = -slat * slon;
  t[0][2] = clat;
  t[1][0] = -slon;
  t[1][1] = clon;
  t[1][2] = 0.0;
  t[2][0] = clat * clon;
  t[2][1] = clat * slon;
  t[2][2] = slat;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ltcmat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  movsd  0x0(%rbp),%xmm0
  lea    0x18(%rsp),%r12
  lea    0x10(%rsp),%r13
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sincos@plt>
  movsd  0x8(%rbp),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm5
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm5,(%rsp)
  call   <sincos@plt>
  movsd  (%rsp),%xmm5
  movq   D4(%rip),%xmm2
  movq   $0x0,0x28(%rbx)
  movsd  0x10(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm4
  movapd %xmm5,%xmm3
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm5,0x40(%rbx)
  xorpd  %xmm2,%xmm3
  movsd  %xmm0,0x20(%rbx)
  xorpd  %xmm4,%xmm2
  movapd %xmm3,%xmm6
  movsd  %xmm1,0x10(%rbx)
  mulsd  %xmm0,%xmm6
  movsd  %xmm2,0x18(%rbx)
  mulsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm3
  mulsd  %xmm4,%xmm1
  movsd  %xmm6,(%rbx)
  movsd  %xmm0,0x30(%rbx)
  movsd  %xmm3,0x8(%rbx)
  movsd  %xmm1,0x38(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: f32[2]

tool: {"D4": [0.0,-0.0]}

assistant: ```c
void ltcmat(double *llh, double t[3][3]) {
  double slat, clat;
  double slon, clon;
  slat = sin(llh[0]);
  clat = cos(llh[0]);
  slon = sin(llh[1]);
  clon = cos(llh[1]);
  t[0][0] = -slat * clon;
  t[0][1] = -slat * slon;
  t[0][2] = clat;
  t[1][0] = -slon;
  t[1][1] = clon;
  t[1][2] = 0.0;
  t[2][0] = clat * clon;
  t[2][1] = clat * slon;
  t[2][2] = slat;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ltcmat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  movsd  0x0(%rbp),%xmm0
  lea    0x18(%rsp),%r12
  lea    0x10(%rsp),%r13
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sincos@plt>
  movsd  0x8(%rbp),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm5
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm5,(%rsp)
  call   <sincos@plt>
  movsd  (%rsp),%xmm5
  movsd  0x10(%rsp),%xmm0
  movq   $0x0,0x28(%rbx)
  movq   D8(%rip),%xmm3
  movsd  0x18(%rsp),%xmm4
  movapd %xmm5,%xmm2
  movapd %xmm0,%xmm6
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x20(%rbx)
  xorpd  %xmm3,%xmm2
  unpcklpd %xmm4,%xmm6
  xorpd  %xmm4,%xmm3
  movsd  %xmm5,0x40(%rbx)
  mulsd  %xmm1,%xmm0
  unpcklpd %xmm2,%xmm2
  mulpd  %xmm6,%xmm2
  movsd  %xmm0,0x30(%rbx)
  movups %xmm2,(%rbx)
  movapd %xmm1,%xmm2
  mulsd  %xmm4,%xmm1
  unpcklpd %xmm3,%xmm2
  movups %xmm2,0x10(%rbx)
  movsd  %xmm1,0x38(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: f32[2]

tool: {"D8": [0.0,-0.0]}

assistant: ```c
void ltcmat(double *llh, double t[3][3]) {
  double slat, clat;
  double slon, clon;
  slat = sin(llh[0]);
  clat = cos(llh[0]);
  slon = sin(llh[1]);
  clon = cos(llh[1]);
  t[0][0] = -slat * clon;
  t[0][1] = -slat * slon;
  t[0][2] = clat;
  t[1][0] = -slon;
  t[1][1] = clon;
  t[1][2] = 0.0;
  t[2][0] = clat * clon;
  t[2][1] = clat * slon;
  t[2][2] = slat;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decrypt_logo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  xor    -0x5(%rbp),%al
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x5,%al
  or     %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x5fff,-0x4(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void decrypt_logo(unsigned char *logo) {
  unsigned char key = logo[0];
  int i;
  for (i = 0; i < (12 * 2048); i++) {
    logo[i] ^= key;
    logo[i] = (logo[i] << 3) | (logo[i] >> 5);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decrypt_logo>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%rax
  lea    0x6000(%rdi),%rcx
L6:
  mov    %esi,%edx
  xor    (%rax),%dl
  rol    $0x3,%dl
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
  ret
```

assistant: ```c
void decrypt_logo(unsigned char *logo) {
  unsigned char key = logo[0];
  int i;
  for (i = 0; i < (12 * 2048); i++) {
    logo[i] ^= key;
    logo[i] = (logo[i] << 3) | (logo[i] >> 5);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<decrypt_logo>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x6000(%rdi),%rcx
  mov    %edx,%eax
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L13:
  movzbl (%rdi),%eax
L9:
  xor    %edx,%eax
  add    $0x1,%rdi
  rol    $0x3,%al
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rcx
  jne    L13
  ret
```

assistant: ```c
void decrypt_logo(unsigned char *logo) {
  unsigned char key = logo[0];
  int i;
  for (i = 0; i < (12 * 2048); i++) {
    logo[i] ^= key;
    logo[i] = (logo[i] << 3) | (logo[i] >> 5);
  }
}
```