ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<MatMulC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L24:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L24
  movl   $0x0,-0x20(%rbp)
  jmp    L54
L79:
  movl   $0x0,-0x1c(%rbp)
  jmp    L53
L3:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L60
L23:
  mov    -0x20(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L60:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L23
  mov    -0x20(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L53:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  addl   $0x1,-0x20(%rbp)
L54:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L79
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void MatMulC(int rows, int len, double *a, double *bin, double *c) {
  int i, j, k;
  double *b = malloc(len * sizeof(double));
  for (int n = 0; n < len; n++) {
    b[n] = bin[rows * (n % rows) + (n / rows)];
  }
  for (i = 0; i < rows; i++) {
    for (j = 0; j < rows; j++) {
      double sum = 0.0;
      for (k = 0; k < rows; k++) {
        sum += a[i * rows + k] * b[j * rows + k];
      }
      c[i * rows + j] = sum;
    }
  }
  free(b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MatMulC>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    %rcx,%rbp
  mov    %r8,%r14
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r10
  test   %r12d,%r12d
  jle    L19
  mov    %r12d,%esi
  mov    $0x0,%ecx
L4:
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  imul   %ebx,%edx
  add    %eax,%edx
  movslq %edx,%rax
  movsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rcx,8)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L4
L19:
  test   %ebx,%ebx
  jle    L41
  movslq %ebx,%r9
  shl    $0x3,%r9
  lea    -0x1(%rbx),%eax
  lea    0x8(%r14,%rax,8),%r8
  mov    %r13,%rcx
  mov    $0x0,%r11d
  mov    %ebx,%esi
  mov    %rsi,%rbp
  neg    %rbp
  shl    $0x3,%rbp
L31:
  lea    0x0(%rbp,%r8,1),%rdi
  mov    %r10,%rdx
L46:
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L15:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L15
  movsd  %xmm1,(%rdi)
  add    $0x8,%rdi
  add    %r9,%rdx
  cmp    %r8,%rdi
  jne    L46
  add    $0x1,%r11d
  add    %r9,%r8
  add    %r9,%rcx
  cmp    %r11d,%ebx
  jne    L31
L41:
  mov    %r10,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void MatMulC(int rows, int len, double *a, double *bin, double *c) {
  int i, j, k;
  double *b = malloc(len * sizeof(double));
  for (int n = 0; n < len; n++) {
    b[n] = bin[rows * (n % rows) + (n / rows)];
  }
  for (i = 0; i < rows; i++) {
    for (j = 0; j < rows; j++) {
      double sum = 0.0;
      for (k = 0; k < rows; k++) {
        sum += a[i * rows + k] * b[j * rows + k];
      }
      c[i * rows + j] = sum;
    }
  }
  free(b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MatMulC>:
  endbr64
  push   %r15
  push   %r14
  movslq %esi,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    0x0(,%r14,8),%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %ecx,%ecx
  mov    %rax,%r10
  test   %r14d,%r14d
  jle    L52
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %ecx,%eax
  cltd
  idiv   %ebp
  imul   %ebp,%edx
  add    %eax,%edx
  movslq %edx,%rax
  movsd  (%r12,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rcx,8)
  add    $0x1,%rcx
  cmp    %r14,%rcx
  jne    L45
L52:
  test   %ebp,%ebp
  jle    L11
  lea    -0x1(%rbp),%eax
  movslq %ebp,%r9
  mov    %rbx,%rcx
  mov    $0xfffffffffffffff8,%rbx
  shl    $0x3,%rax
  shl    $0x3,%r9
  xor    %r11d,%r11d
  mov    %ebp,%esi
  lea    0x8(%r13,%rax,1),%r8
  pxor   %xmm2,%xmm2
  sub    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L39:
  lea    (%rbx,%r8,1),%rdi
  mov    %r10,%rdx
  nop
L43:
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  cs nopw 0x0(%rax,%rax,1)
L23:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L23
  movsd  %xmm1,(%rdi)
  add    $0x8,%rdi
  add    %r9,%rdx
  cmp    %rdi,%r8
  jne    L43
  add    $0x1,%r11d
  add    %r9,%r8
  add    %r9,%rcx
  cmp    %r11d,%ebp
  jne    L39
L11:
  add    $0x8,%rsp
  mov    %r10,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <free@plt>
```

assistant: ```c
void MatMulC(int rows, int len, double *a, double *bin, double *c) {
  int i, j, k;
  double *b = malloc(len * sizeof(double));
  for (int n = 0; n < len; n++) {
    b[n] = bin[rows * (n % rows) + (n / rows)];
  }
  for (i = 0; i < rows; i++) {
    for (j = 0; j < rows; j++) {
      double sum = 0.0;
      for (k = 0; k < rows; k++) {
        sum += a[i * rows + k] * b[j * rows + k];
      }
      c[i * rows + j] = sum;
    }
  }
  free(b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vec3_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *vec3_zero(float *result) {
  result[0] = 0.0f;
  result[1] = 0.0f;
  result[2] = 0.0f;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vec3_zero>:
  endbr64
  mov    %rdi,%rax
  movl   $0x0,(%rdi)
  movl   $0x0,0x4(%rdi)
  movl   $0x0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_zero(float *result) {
  result[0] = 0.0f;
  result[1] = 0.0f;
  result[2] = 0.0f;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec3_zero>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  movl   $0x0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_zero(float *result) {
  result[0] = 0.0f;
  result[1] = 0.0f;
  result[2] = 0.0f;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vec3_zero>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  movl   $0x0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_zero(float *result) {
  result[0] = 0.0f;
  result[1] = 0.0f;
  result[2] = 0.0f;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0xf,%eax
  jg     L12
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L12:
  mov    -0xc(%rbp),%eax
  cmp    $0x10,%eax
  je     L44
  mov    -0xc(%rbp),%eax
  cmp    $0x11,%eax
  je     L44
  mov    -0xc(%rbp),%eax
  cmp    $0x46,%eax
  jle    L20
L44:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L20:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D46
type: string
name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D40
type: string
name: disassemble_data
arguments: data_tag: D34
type: string
name: disassemble_data
arguments: data_tag: D16
type: string

tool: D46: 
Diga sua idade:

tool: D13: %d

tool: D40: 
Nao pode votar


tool: D34: 
Voto FACULTATIVO

tool: D16: 
Obrigado a votar

assistant: ```c
int main() {
  int idade;
  printf("\nDiga sua idade:");
  scanf("%d", &idade);
  if (idade <= 15) {
    printf("\nNao pode votar\n");
  } else if (idade == 16 || idade == 17 || idade > 70) {
    printf("\nVoto FACULTATIVO");
  } else {
    printf("\nObrigado a votar");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xf,%eax
  jle    L38
  lea    -0x10(%rax),%edx
  cmp    $0x1,%edx
  jbe    L11
  cmp    $0x46,%eax
  jg     L11
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L38:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L11:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string
name: retrieve_data
arguments: data_tag: D43
data_type: string
name: retrieve_data
arguments: data_tag: D21
data_type: string
name: retrieve_data
arguments: data_tag: D12
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D4: 
Diga sua idade:

tool: D43: %d

tool: D21: 
Obrigado a votar

tool: D12: 
Nao pode votar


tool: D8: 
Voto FACULTATIVO

assistant: ```c
int main() {
  int idade;
  printf("\nDiga sua idade:");
  scanf("%d", &idade);
  if (idade <= 15) {
    printf("\nNao pode votar\n");
  } else if (idade == 16 || idade == 17 || idade > 70) {
    printf("\nVoto FACULTATIVO");
  } else {
    printf("\nObrigado a votar");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xf,%eax
  jle    L11
  lea    -0x10(%rax),%edx
  cmp    $0x1,%edx
  jbe    L59
  cmp    $0x46,%eax
  jg     L59
  lea    D26(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L59:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L11:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D25
datatype: string
name: extract_symbolic_data
arguments: data_tag: D26
datatype: string
name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string

tool: D1: 
Diga sua idade:

tool: D25: %d

tool: D26: 
Obrigado a votar

tool: D39: 
Voto FACULTATIVO

tool: D29: 
Nao pode votar


assistant: ```c
int main() {
  int idade;
  printf("\nDiga sua idade:");
  scanf("%d", &idade);
  if (idade <= 15) {
    printf("\nNao pode votar\n");
  } else if (idade == 16 || idade == 17 || idade > 70) {
    printf("\nVoto FACULTATIVO");
  } else {
    printf("\nObrigado a votar");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xf,%eax
  jle    L46
  lea    -0x10(%rax),%edx
  cmp    $0x1,%edx
  jbe    L19
  cmp    $0x46,%eax
  jg     L19
  lea    D43(%rip),%rdi
  call   <printf@plt>
L58:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L58
L46:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L58
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D43
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D7: 
Diga sua idade:

tool: D20: %d

tool: D43: 
Obrigado a votar

tool: D19: 
Voto FACULTATIVO

tool: D15: 
Nao pode votar


assistant: ```c
int main() {
  int idade;
  printf("\nDiga sua idade:");
  scanf("%d", &idade);
  if (idade <= 15) {
    printf("\nNao pode votar\n");
  } else if (idade == 16 || idade == 17 || idade > 70) {
    printf("\nVoto FACULTATIVO");
  } else {
    printf("\nObrigado a votar");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<removeNewLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void removeNewLine(char *str) {
  int inputLenght = strlen(str);
  str[inputLenght - 1] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<removeNewLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void removeNewLine(char *str) {
  int inputLenght = strlen(str);
  str[inputLenght - 1] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<removeNewLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void removeNewLine(char *str) {
  int inputLenght = strlen(str);
  str[inputLenght - 1] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<removeNewLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void removeNewLine(char *str) {
  int inputLenght = strlen(str);
  str[inputLenght - 1] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Test20>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  lea    D22(%rip),%rbp
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movb   $0x61,D49(%rip)
  mov    $0x5,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D49(%rip),%rdi
  call   <__memcpy_chk@plt>
  mov    $0x4,%ecx
  mov    $0x5,%edx
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  call   <__memcpy_chk@plt>
  lea    D39(%rip),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
type: string

tool: D22: abcde

assistant: ```c
char *Test20(char *p, const char *in, unsigned n) {
  static char buf[10];
  __builtin___memcpy_chk(&buf[6], in, 5, __builtin_object_size(&buf[6], 0));
  __builtin___memcpy_chk(p, "abcde", n, __builtin_object_size(p, 0));
  __builtin___memcpy_chk(&buf[5], "abcde", 5, __builtin_object_size(&buf[5], 0));
  __builtin___memcpy_chk(&buf[5], "abcde", n, __builtin_object_size(&buf[5], 0));
  __builtin___memcpy_chk(&buf[6], "abcde", 5, __builtin_object_size(&buf[6], 0));
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Test20>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    D26(%rip),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x5,%ecx
  lea    D2(%rip),%rdi
  movb   $0x61,D2(%rip)
  call   <__memcpy_chk@plt>
  mov    %rbp,%rsi
  mov    $0x4,%ecx
  mov    $0x5,%edx
  lea    D19(%rip),%rdi
  call   <__memcpy_chk@plt>
  add    $0x8,%rsp
  lea    D31(%rip),%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D26
type_infered: string

tool: D26: abcde

assistant: ```c
char *Test20(char *p, const char *in, unsigned n) {
  static char buf[10];
  __builtin___memcpy_chk(&buf[6], in, 5, __builtin_object_size(&buf[6], 0));
  __builtin___memcpy_chk(p, "abcde", n, __builtin_object_size(p, 0));
  __builtin___memcpy_chk(&buf[5], "abcde", 5, __builtin_object_size(&buf[5], 0));
  __builtin___memcpy_chk(&buf[5], "abcde", n, __builtin_object_size(&buf[5], 0));
  __builtin___memcpy_chk(&buf[6], "abcde", 5, __builtin_object_size(&buf[6], 0));
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Test20>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    D20(%rip),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x5,%ecx
  lea    D1(%rip),%rdi
  movb   $0x61,D1(%rip)
  call   <__memcpy_chk@plt>
  mov    %rbp,%rsi
  mov    $0x4,%ecx
  mov    $0x5,%edx
  lea    D19(%rip),%rdi
  call   <__memcpy_chk@plt>
  add    $0x8,%rsp
  lea    D43(%rip),%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
type_guessed: string

tool: D20: abcde

assistant: ```c
char *Test20(char *p, const char *in, unsigned n) {
  static char buf[10];
  __builtin___memcpy_chk(&buf[6], in, 5, __builtin_object_size(&buf[6], 0));
  __builtin___memcpy_chk(p, "abcde", n, __builtin_object_size(p, 0));
  __builtin___memcpy_chk(&buf[5], "abcde", 5, __builtin_object_size(&buf[5], 0));
  __builtin___memcpy_chk(&buf[5], "abcde", n, __builtin_object_size(&buf[5], 0));
  __builtin___memcpy_chk(&buf[6], "abcde", 5, __builtin_object_size(&buf[6], 0));
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<block_Kbyte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x61a8000,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x61a8000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L5:
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x400,-0x8(%rbp)
  addq   $0x400,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L15:
  cmpl   $0x1869f,-0x14(%rbp)
  jle    L5
  nop
  leave
  ret
```

assistant: ```c
void *block_Kbyte() {
  int i;
  char *mem = (char *)malloc(100000 * 1024);
  char *mem1 = (char *)malloc(1024 * 100000);
  for (i = 0; i < 100000; i++) {
    memcpy(mem1, mem, 1024);
    mem1 = mem1 + 1024;
    mem = mem + 1024;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<block_Kbyte>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x61a8000,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x61a8000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x61a8000(%rax),%r12
  sub    %rax,%rbp
L8:
  lea    (%rbx,%rbp,1),%rsi
  mov    $0x400,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x400,%rbx
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *block_Kbyte() {
  int i;
  char *mem = (char *)malloc(100000 * 1024);
  char *mem1 = (char *)malloc(1024 * 100000);
  for (i = 0; i < 100000; i++) {
    memcpy(mem1, mem, 1024);
    mem1 = mem1 + 1024;
    mem = mem + 1024;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<block_Kbyte>:
  endbr64
  push   %r12
  mov    $0x61a8000,%edi
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0x61a8000,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x61a8000(%rax),%r12
  sub    %rax,%rbp
  nopl   0x0(%rax)
L8:
  lea    (%rbx,%rbp,1),%rsi
  mov    %rbx,%rdi
  mov    $0x400,%edx
  add    $0x400,%rbx
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *block_Kbyte() {
  int i;
  char *mem = (char *)malloc(100000 * 1024);
  char *mem1 = (char *)malloc(1024 * 100000);
  for (i = 0; i < 100000; i++) {
    memcpy(mem1, mem, 1024);
    mem1 = mem1 + 1024;
    mem = mem + 1024;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<block_Kbyte>:
  endbr64
  push   %r12
  mov    $0x61a8000,%edi
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0x61a8000,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x61a8000(%rax),%r12
  sub    %rax,%rbp
  nopl   0x0(%rax)
L3:
  lea    (%rbx,%rbp,1),%rsi
  mov    %rbx,%rdi
  mov    $0x400,%edx
  add    $0x400,%rbx
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *block_Kbyte() {
  int i;
  char *mem = (char *)malloc(100000 * 1024);
  char *mem1 = (char *)malloc(1024 * 100000);
  for (i = 0; i < 100000; i++) {
    memcpy(mem1, mem, 1024);
    mem1 = mem1 + 1024;
    mem = mem + 1024;
  }
}
```