user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ascii2int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r13
  mov    $0x1000,%edx
  mov    $0x0,%esi
  lea    D8(%rip),%rdi
  call   <memset@plt>
  test   %r13,%r13
  je     L19
  mov    $0x0,%edx
  mov    $0x0,%r12d
  mov    $0x0,%eax
  lea    D8(%rip),%rbx
  mov    $0x1000,%r15d
  lea    D25(%rip),%r14
  jmp    L105
L49:
  mov    %edx,%ecx
  movb   $0x5c,(%rbx,%rcx,1)
  lea    0x2(%rdx),%ebp
  lea    0x1(%rdx),%edx
  movb   $0x72,(%rbx,%rdx,1)
L53:
  mov    %ebp,%edx
  movb   $0x20,(%rbx,%rdx,1)
  lea    0x2(%rbp),%edi
  lea    0x1(%rbp),%edx
  movb   $0x28,(%rbx,%rdx,1)
  movsbl (%rax),%ecx
  mov    %r15d,%esi
  sub    %edi,%esi
  mov    %edi,%edi
  add    %rbx,%rdi
  mov    %r14,%rdx
  call   <snprintf@plt>
  lea    0x5(%rbp),%eax
  movb   $0x29,(%rbx,%rax,1)
  lea    0x7(%rbp),%edx
  lea    0x6(%rbp),%eax
  movb   $0x20,(%rbx,%rax,1)
  cmp    $0xfec,%edx
  ja     L1
  add    $0x1,%r12d
  mov    %r12d,%eax
  cmp    %r13,%rax
  jae    L1
L105:
  add    0x8(%rsp),%rax
  movzbl (%rax),%ecx
  cmp    $0xd,%cl
  je     L49
  cmp    $0xa,%cl
  je     L106
  cmp    $0x9,%cl
  je     L115
  cmp    $0x1f,%cl
  jg     L13
  movsbl %cl,%edi
  lea    0x1(%rdx),%esi
  mov    %edx,%r8d
  movb   $0x5c,(%rbx,%r8,1)
  cmp    $0x9,%cl
  jle    L12
  movslq %edi,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %edi,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%ecx
  lea    (%rcx,%rcx,4),%r8d
  add    %r8d,%r8d
  mov    %edi,%ecx
  sub    %r8d,%ecx
  mov    %esi,%esi
  lea    0x30(%rcx),%r8d
  mov    %r8b,(%rbx,%rsi,1)
  imul   $0xfffffff6,%ecx,%ecx
  add    %ecx,%edi
  lea    0x2(%rdx),%esi
L12:
  lea    0x1(%rsi),%ebp
  mov    %esi,%esi
  add    $0x30,%edi
  mov    %dil,(%rbx,%rsi,1)
  jmp    L53
L106:
  mov    %edx,%ecx
  movb   $0x5c,(%rbx,%rcx,1)
  lea    0x2(%rdx),%ebp
  lea    0x1(%rdx),%edx
  movb   $0x6e,(%rbx,%rdx,1)
  jmp    L53
L115:
  mov    %edx,%ecx
  movb   $0x5c,(%rbx,%rcx,1)
  lea    0x2(%rdx),%ebp
  lea    0x1(%rdx),%edx
  movb   $0x74,(%rbx,%rdx,1)
  jmp    L53
L13:
  lea    0x1(%rdx),%ebp
  mov    %edx,%edx
  mov    %cl,(%rbx,%rdx,1)
  jmp    L53
L19:
  mov    $0x0,%edx
L1:
  lea    D8(%rip),%rax
  mov    %edx,%edx
  movb   $0x0,(%rax,%rdx,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string

tool: D25: %3d

assistant: ```c
char *ascii2int(const char *string, size_t len) {
  static char buffer[4096];
  unsigned int idx, bufIdx = 0;
  memset(buffer, 0, sizeof(buffer));
  for (idx = 0; idx < len; ++idx) {
    if (string[idx] == '\r') {
      buffer[bufIdx++] = '\\';
      buffer[bufIdx++] = 'r';
    } else if (string[idx] == '\n') {
      buffer[bufIdx++] = '\\';
      buffer[bufIdx++] = 'n';
    } else if (string[idx] == '\t') {
      buffer[bufIdx++] = '\\';
      buffer[bufIdx++] = 't';
    } else if (string[idx] < 32) {
      int ascii = string[idx];
      buffer[bufIdx++] = '\\';
      if (ascii > 9) {
        buffer[bufIdx++] = (ascii % 10) + 48;
        ascii -= (ascii % 10) * 10;
      }
      buffer[bufIdx++] = ascii + 48;
    } else
      buffer[bufIdx++] = string[idx];
    buffer[bufIdx++] = ' ';
    buffer[bufIdx++] = '(';
    snprintf(buffer + bufIdx, sizeof(buffer) - bufIdx, "%3d", (unsigned int)string[idx]);
    bufIdx += 3;
    buffer[bufIdx++] = ')';
    buffer[bufIdx++] = ' ';
    if (bufIdx > (sizeof(buffer) - 20))
      break;
  }
  buffer[bufIdx] = '\0';
  return buffer;
}
```