ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <omp_set_nested@plt>
  xor    %edi,%edi
  call   <omp_set_dynamic@plt>
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_max_threads@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_max_threads@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_max_threads@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D23(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D23
data_type: string

tool: D9: Master : Thread %d of %d (%d Max)



tool: D19: Outer  : Thread %d of %d (%d Max)



tool: D23: Inner  : Thread %d of %d (%d Max)


assistant: ```c
int main(int argc, char **argv) {
  omp_set_nested(1);
  omp_set_dynamic(0);
  int num = 0;
  int threads = 0;
  int max = 0;
  num = omp_get_thread_num();
  threads = omp_get_num_threads();
  max = omp_get_max_threads();
  printf("Master : Thread %d of %d (%d Max)\n\n", num, threads, max);
#pragma omp parallel num_threads(8)
  {
    num = omp_get_thread_num();
    threads = omp_get_num_threads();
    max = omp_get_max_threads();
    printf("Outer  : Thread %d of %d (%d Max)\n\n", num, threads, max);
#pragma omp parallel num_threads(4)
    {
      num = omp_get_thread_num();
      threads = omp_get_num_threads();
      max = omp_get_max_threads();
      printf("Inner  : Thread %d of %d (%d Max)\n", num, threads, max);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_r32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xa0,-0x4(%rbp)
  jg     L7
  cmpl   $0x9a,-0x4(%rbp)
  jge    L21
  jmp    L34
L7:
  cmpl   $0xa2,-0x4(%rbp)
  jne    L34
L21:
  mov    $0x1,%eax
  jmp    L24
L34:
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int is_r32(int id) {
  switch (id) {
  case 154:
  case 156:
  case 157:
  case 159:
  case 160:
  case 158:
  case 155:
  case 162:
    return (1);
  default:
    return (0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_r32>:
  endbr64
  cmp    $0xa0,%edi
  jg     L0
  cmp    $0x99,%edi
  setg   %al
  movzbl %al,%eax
  ret
L0:
  cmp    $0xa2,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_r32(int id) {
  switch (id) {
  case 154:
  case 156:
  case 157:
  case 159:
  case 160:
  case 158:
  case 155:
  case 162:
    return (1);
  default:
    return (0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_r32>:
  endbr64
  cmp    $0xa0,%edi
  jg     L2
  xor    %eax,%eax
  cmp    $0x99,%edi
  setg   %al
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  cmp    $0xa2,%edi
  sete   %al
  ret
```

assistant: ```c
int is_r32(int id) {
  switch (id) {
  case 154:
  case 156:
  case 157:
  case 159:
  case 160:
  case 158:
  case 155:
  case 162:
    return (1);
  default:
    return (0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_r32>:
  endbr64
  cmp    $0xa0,%edi
  jg     L0
  xor    %eax,%eax
  cmp    $0x99,%edi
  setg   %al
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  cmp    $0xa2,%edi
  sete   %al
  ret
```

assistant: ```c
int is_r32(int id) {
  switch (id) {
  case 154:
  case 156:
  case 157:
  case 159:
  case 160:
  case 158:
  case 155:
  case 162:
    return (1);
  default:
    return (0);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mus_wav_fadeout_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L2
  cmpl   $0x0,-0x10(%rbp)
  je     L2
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  mov    $0x0,%eax
  call   <muspcm_fadeout@plt>
  jmp    L22
L2:
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D15
datatype: string

tool: D13: mus_wav_fadeout_start

tool: D15: %s not implemented


assistant: ```c
int mus_wav_fadeout_start(int ch, int time, int volume, int stop) {
  if (volume == 0 && stop)
    return muspcm_fadeout(ch + 1, time);
  printf("%s not implemented\n", __func__);
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mus_wav_fadeout_start>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L4
  test   %ecx,%ecx
  je     L4
  add    $0x1,%edi
  mov    $0x0,%eax
  call   <muspcm_fadeout@plt>
L14:
  add    $0x8,%rsp
  ret
L4:
  lea    D14(%rip),%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: label: D14
type_guessed: string
name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D14: mus_wav_fadeout_start

tool: D5: %s not implemented


assistant: ```c
int mus_wav_fadeout_start(int ch, int time, int volume, int stop) {
  if (volume == 0 && stop)
    return muspcm_fadeout(ch + 1, time);
  printf("%s not implemented\n", __func__);
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mus_wav_fadeout_start>:
  endbr64
  test   %edx,%edx
  jne    L9
  test   %ecx,%ecx
  je     L9
  add    $0x1,%edi
  xor    %eax,%eax
  jmp    1070 <muspcm_fadeout@plt>
  cs nopw 0x0(%rax,%rax,1)
L9:
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string
name: read_data
arguments: data_label: D15
datatype: string

tool: D1: mus_wav_fadeout_start

tool: D15: %s not implemented


assistant: ```c
int mus_wav_fadeout_start(int ch, int time, int volume, int stop) {
  if (volume == 0 && stop)
    return muspcm_fadeout(ch + 1, time);
  printf("%s not implemented\n", __func__);
  return (-1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mus_wav_fadeout_start>:
  endbr64
  test   %edx,%edx
  jne    L17
  test   %ecx,%ecx
  je     L17
  add    $0x1,%edi
  xor    %eax,%eax
  jmp    1070 <muspcm_fadeout@plt>
  cs nopw 0x0(%rax,%rax,1)
L17:
  sub    $0x8,%rsp
  lea    D8(%rip),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string
name: read_data
arguments: label: D19
data_type: string

tool: D8: mus_wav_fadeout_start

tool: D19: %s not implemented


assistant: ```c
int mus_wav_fadeout_start(int ch, int time, int volume, int stop) {
  if (volume == 0 && stop)
    return muspcm_fadeout(ch + 1, time);
  printf("%s not implemented\n", __func__);
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unprotect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x2f26f3c0,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0xb979379e,-0x4(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L19
L15:
  mov    -0x1c(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  xor    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x1c(%rbp),%eax
  shr    $0x5,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  add    %ecx,%eax
  xor    %edx,%eax
  sub    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  xor    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x18(%rbp),%eax
  shr    $0x5,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  xor    %edx,%eax
  sub    %eax,-0x1c(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L19:
  cmpl   $0x1f,-0x24(%rbp)
  jbe    L15
  mov    -0x40(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unprotect(unsigned int *key, unsigned int *data) {
  unsigned int i, acc = 0x2f26f3c0;
  unsigned d0 = data[0], d1 = data[1];
  unsigned int k0 = key[0], k1 = key[1], k2 = key[2], k3 = key[3];
  unsigned int c = 0xb979379e;
  for (i = 0; i < 32; ++i) {
    d1 -= ((d0 << 4) + k2) ^ (d0 + acc) ^ ((d0 >> 5) + k3);
    d0 -= ((d1 << 4) + k0) ^ (d1 + acc) ^ ((d1 >> 5) + k1);
    acc -= c;
  }
  data[0] = d0;
  data[1] = d1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unprotect>:
  endbr64
  push   %rbx
  mov    %rsi,%r11
  mov    (%rsi),%ecx
  mov    0x4(%rsi),%edx
  mov    (%rdi),%r10d
  mov    0x4(%rdi),%r9d
  mov    0x8(%rdi),%r8d
  mov    0xc(%rdi),%edi
  mov    $0x2f26f3c0,%esi
L0:
  mov    %ecx,%eax
  shl    $0x4,%eax
  add    %r8d,%eax
  mov    %ecx,%ebx
  shr    $0x5,%ebx
  add    %edi,%ebx
  xor    %ebx,%eax
  lea    (%rsi,%rcx,1),%ebx
  xor    %ebx,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  add    %r10d,%eax
  mov    %edx,%ebx
  shr    $0x5,%ebx
  add    %r9d,%ebx
  xor    %ebx,%eax
  lea    (%rdx,%rsi,1),%ebx
  xor    %ebx,%eax
  sub    %eax,%ecx
  add    $0x4686c862,%esi
  jne    L0
  mov    %ecx,(%r11)
  mov    %edx,0x4(%r11)
  pop    %rbx
  ret
```

assistant: ```c
void unprotect(unsigned int *key, unsigned int *data) {
  unsigned int i, acc = 0x2f26f3c0;
  unsigned d0 = data[0], d1 = data[1];
  unsigned int k0 = key[0], k1 = key[1], k2 = key[2], k3 = key[3];
  unsigned int c = 0xb979379e;
  for (i = 0; i < 32; ++i) {
    d1 -= ((d0 << 4) + k2) ^ (d0 + acc) ^ ((d0 >> 5) + k3);
    d0 -= ((d1 << 4) + k0) ^ (d1 + acc) ^ ((d1 >> 5) + k1);
    acc -= c;
  }
  data[0] = d0;
  data[1] = d1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unprotect>:
  endbr64
  push   %rbx
  mov    (%rdi),%r10d
  mov    %rsi,%r11
  mov    0x4(%rdi),%r9d
  mov    0x8(%rdi),%r8d
  mov    0xc(%rdi),%edi
  mov    (%rsi),%ecx
  mov    0x4(%rsi),%edx
  mov    $0x2f26f3c0,%esi
L4:
  mov    %ecx,%eax
  mov    %ecx,%ebx
  shl    $0x4,%eax
  shr    $0x5,%ebx
  add    %edi,%ebx
  add    %r8d,%eax
  xor    %ebx,%eax
  lea    (%rsi,%rcx,1),%ebx
  xor    %ebx,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  mov    %edx,%ebx
  shl    $0x4,%eax
  shr    $0x5,%ebx
  add    %r9d,%ebx
  add    %r10d,%eax
  xor    %ebx,%eax
  lea    (%rdx,%rsi,1),%ebx
  xor    %ebx,%eax
  sub    %eax,%ecx
  add    $0x4686c862,%esi
  jne    L4
  mov    %ecx,(%r11)
  pop    %rbx
  mov    %edx,0x4(%r11)
  ret
```

assistant: ```c
void unprotect(unsigned int *key, unsigned int *data) {
  unsigned int i, acc = 0x2f26f3c0;
  unsigned d0 = data[0], d1 = data[1];
  unsigned int k0 = key[0], k1 = key[1], k2 = key[2], k3 = key[3];
  unsigned int c = 0xb979379e;
  for (i = 0; i < 32; ++i) {
    d1 -= ((d0 << 4) + k2) ^ (d0 + acc) ^ ((d0 >> 5) + k3);
    d0 -= ((d1 << 4) + k0) ^ (d1 + acc) ^ ((d1 >> 5) + k1);
    acc -= c;
  }
  data[0] = d0;
  data[1] = d1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unprotect>:
  endbr64
  push   %rbx
  mov    (%rdi),%r10d
  mov    %rsi,%r11
  mov    0x4(%rdi),%r9d
  mov    0x8(%rdi),%r8d
  mov    0xc(%rdi),%edi
  mov    (%rsi),%ecx
  mov    0x4(%rsi),%edx
  mov    $0x2f26f3c0,%esi
L5:
  mov    %ecx,%eax
  mov    %ecx,%ebx
  shl    $0x4,%eax
  shr    $0x5,%ebx
  add    %edi,%ebx
  add    %r8d,%eax
  xor    %ebx,%eax
  lea    (%rsi,%rcx,1),%ebx
  xor    %ebx,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  mov    %edx,%ebx
  shl    $0x4,%eax
  shr    $0x5,%ebx
  add    %r9d,%ebx
  add    %r10d,%eax
  xor    %ebx,%eax
  lea    (%rdx,%rsi,1),%ebx
  xor    %ebx,%eax
  sub    %eax,%ecx
  add    $0x4686c862,%esi
  jne    L5
  mov    %ecx,(%r11)
  pop    %rbx
  mov    %edx,0x4(%r11)
  ret
```

assistant: ```c
void unprotect(unsigned int *key, unsigned int *data) {
  unsigned int i, acc = 0x2f26f3c0;
  unsigned d0 = data[0], d1 = data[1];
  unsigned int k0 = key[0], k1 = key[1], k2 = key[2], k3 = key[3];
  unsigned int c = 0xb979379e;
  for (i = 0; i < 32; ++i) {
    d1 -= ((d0 << 4) + k2) ^ (d0 + acc) ^ ((d0 >> 5) + k3);
    d0 -= ((d1 << 4) + k0) ^ (d1 + acc) ^ ((d1 >> 5) + k1);
    acc -= c;
  }
  data[0] = d0;
  data[1] = d1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ja_rj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0x77,%edi
  call   <put8@plt>
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <put8@plt>
  nop
  leave
  ret
```

assistant: ```c
void ja_rj(unsigned char saut) {
  put8(0x77);
  put8(saut);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ja_rj>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x77,%edi
  call   <put8@plt>
  movzbl %bl,%edi
  call   <put8@plt>
  pop    %rbx
  ret
```

assistant: ```c
void ja_rj(unsigned char saut) {
  put8(0x77);
  put8(saut);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ja_rj>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x77,%edi
  call   <put8@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <put8@plt>
```

assistant: ```c
void ja_rj(unsigned char saut) {
  put8(0x77);
  put8(saut);
}
```
user: What is the c source code of the assembly code below?

```asm
<ja_rj>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x77,%edi
  call   <put8@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <put8@plt>
```

assistant: ```c
void ja_rj(unsigned char saut) {
  put8(0x77);
  put8(saut);
}
```
user: What is the c source code of the assembly code below?

```asm
<FibnoFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <MemAlloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L17
  mov    $0xffffffff,%eax
  jmp    L4
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  cmpl   $0x0,-0x24(%rbp)
  je     L30
  mov    -0x10(%rbp),%rax
  sub    $0x4,%rax
  movl   $0x1,(%rax)
  jmp    L30
L44:
  mov    -0x10(%rbp),%rax
  sub    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  sub    $0x8,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  subq   $0x4,-0x10(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  cmp    %rax,-0x10(%rbp)
  ja     L44
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <MemFree@plt>
  mov    -0x1c(%rbp),%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
unsigned int FibnoFunction(unsigned int ulNum) {
  unsigned int *pulStackBt;
  unsigned int *pulStackTop;
  unsigned int ulSumRet;
  pulStackBt = MemAlloc(sizeof(unsigned int) * (ulNum + 1));
  if (pulStackBt == 0) {
    return -1;
  }
  pulStackTop = pulStackBt + ulNum;
  pulStackTop[0] = 0;
  if (ulNum > 0) {
    pulStackTop[-1] = 1;
  }
  while (pulStackTop > pulStackBt + 1) {
    pulStackTop[-2] = pulStackTop[-1] + pulStackTop[0];
    pulStackTop--;
  }
  ulSumRet = *pulStackBt;
  MemFree(&pulStackBt);
  return ulSumRet;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<FibnoFunction>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(,%rdi,4),%edi
  call   <MemAlloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L7
  mov    %ebx,%edx
  lea    (%rax,%rdx,4),%rax
  movl   $0x0,(%rax)
  test   %ebx,%ebx
  je     L55
  movl   $0x1,-0x4(%rax)
L55:
  mov    (%rsp),%rdx
  lea    0x4(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L54
L23:
  mov    (%rax),%edx
  add    -0x4(%rax),%edx
  mov    %edx,-0x8(%rax)
  sub    $0x4,%rax
  mov    (%rsp),%rdx
  lea    0x4(%rdx),%rcx
  cmp    %rcx,%rax
  ja     L23
L54:
  mov    (%rdx),%ebx
  mov    %rsp,%rdi
  call   <MemFree@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  mov    $0xffffffff,%ebx
  jmp    L0
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int FibnoFunction(unsigned int ulNum) {
  unsigned int *pulStackBt;
  unsigned int *pulStackTop;
  unsigned int ulSumRet;
  pulStackBt = MemAlloc(sizeof(unsigned int) * (ulNum + 1));
  if (pulStackBt == 0) {
    return -1;
  }
  pulStackTop = pulStackBt + ulNum;
  pulStackTop[0] = 0;
  if (ulNum > 0) {
    pulStackTop[-1] = 1;
  }
  while (pulStackTop > pulStackBt + 1) {
    pulStackTop[-2] = pulStackTop[-1] + pulStackTop[0];
    pulStackTop--;
  }
  ulSumRet = *pulStackBt;
  MemFree(&pulStackBt);
  return ulSumRet;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FibnoFunction>:
  endbr64
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  lea    0x4(,%rdi,4),%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <MemAlloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L17
  mov    %ebx,%edx
  lea    (%rax,%rdx,4),%rdx
  movl   $0x0,(%rdx)
  test   %ebx,%ebx
  jne    L28
L34:
  lea    0x4(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L45
  xor    %ecx,%ecx
  jmp    L27
  nop
L36:
  mov    (%rdx),%ecx
L27:
  add    -0x4(%rdx),%ecx
  sub    $0x4,%rdx
  mov    %ecx,-0x4(%rdx)
  cmp    %rsi,%rdx
  ja     L36
L45:
  mov    %rsp,%rdi
  mov    (%rax),%r12d
  call   <MemFree@plt>
L65:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  movl   $0x1,-0x4(%rdx)
  jmp    L34
  nopl   0x0(%rax)
L17:
  mov    $0xffffffff,%r12d
  jmp    L65
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int FibnoFunction(unsigned int ulNum) {
  unsigned int *pulStackBt;
  unsigned int *pulStackTop;
  unsigned int ulSumRet;
  pulStackBt = MemAlloc(sizeof(unsigned int) * (ulNum + 1));
  if (pulStackBt == 0) {
    return -1;
  }
  pulStackTop = pulStackBt + ulNum;
  pulStackTop[0] = 0;
  if (ulNum > 0) {
    pulStackTop[-1] = 1;
  }
  while (pulStackTop > pulStackBt + 1) {
    pulStackTop[-2] = pulStackTop[-1] + pulStackTop[0];
    pulStackTop--;
  }
  ulSumRet = *pulStackBt;
  MemFree(&pulStackBt);
  return ulSumRet;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FibnoFunction>:
  endbr64
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  lea    0x4(,%rdi,4),%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <MemAlloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L89
  mov    %ebx,%edx
  lea    (%rax,%rdx,4),%rdx
  movl   $0x0,(%rdx)
  test   %ebx,%ebx
  jne    L73
L63:
  lea    0x4(%rax),%rdi
  cmp    %rdi,%rdx
  jbe    L104
  lea    0x8(%rax),%r9
  lea    -0x4(%rdx),%rcx
  cmp    %r9,%rcx
  jbe    L81
  cmp    $0xfffffffffffffffb,%rdi
  ja     L81
  mov    -0x4(%rdx),%esi
  xor    %ecx,%ecx
L93:
  add    %esi,%ecx
  mov    %rdx,%r8
  sub    $0x8,%rdx
  add    %ecx,%esi
  movd   %ecx,%xmm1
  sub    $0xc,%r8
  movd   %esi,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x4(%rdx)
  cmp    %r8,%r9
  jb     L93
  mov    (%rdx),%esi
  lea    -0x4(%rdx),%rcx
  add    -0x4(%rdx),%esi
  mov    %esi,-0x8(%rdx)
  mov    %rcx,%rdx
  cmp    %rcx,%rdi
  jae    L104
  nopl   0x0(%rax)
L39:
  sub    $0x4,%rcx
L81:
  mov    (%rdx),%esi
  add    -0x4(%rdx),%esi
  mov    %esi,-0x8(%rdx)
  mov    %rcx,%rdx
  cmp    %rcx,%rdi
  jb     L39
L104:
  mov    %rsp,%rdi
  mov    (%rax),%r12d
  call   <MemFree@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  movl   $0x1,-0x4(%rdx)
  jmp    L63
  nopl   0x0(%rax)
L89:
  mov    $0xffffffff,%r12d
  jmp    L5
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int FibnoFunction(unsigned int ulNum) {
  unsigned int *pulStackBt;
  unsigned int *pulStackTop;
  unsigned int ulSumRet;
  pulStackBt = MemAlloc(sizeof(unsigned int) * (ulNum + 1));
  if (pulStackBt == 0) {
    return -1;
  }
  pulStackTop = pulStackBt + ulNum;
  pulStackTop[0] = 0;
  if (ulNum > 0) {
    pulStackTop[-1] = 1;
  }
  while (pulStackTop > pulStackBt + 1) {
    pulStackTop[-2] = pulStackTop[-1] + pulStackTop[0];
    pulStackTop--;
  }
  ulSumRet = *pulStackBt;
  MemFree(&pulStackBt);
  return ulSumRet;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__console_tx_nibble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x39,-0x1(%rbp)
  jbe    L6
  addb   $0x27,-0x1(%rbp)
L6:
  movzbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <__console_tx_char@plt>
  nop
  leave
  ret
```

assistant: ```c
void __console_tx_nibble(unsigned nibble) {
  unsigned char digit;
  digit = nibble + '0';
  if (digit > '9') {
    digit += 39;
  }
  __console_tx_char(digit);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__console_tx_nibble>:
  endbr64
  sub    $0x8,%rsp
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x39,%al
  cmova  %edi,%eax
  movzbl %al,%edi
  call   <__console_tx_char@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __console_tx_nibble(unsigned nibble) {
  unsigned char digit;
  digit = nibble + '0';
  if (digit > '9') {
    digit += 39;
  }
  __console_tx_char(digit);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__console_tx_nibble>:
  endbr64
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x39,%al
  cmova  %edi,%eax
  movzbl %al,%edi
  jmp    1050 <__console_tx_char@plt>
```

assistant: ```c
void __console_tx_nibble(unsigned nibble) {
  unsigned char digit;
  digit = nibble + '0';
  if (digit > '9') {
    digit += 39;
  }
  __console_tx_char(digit);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__console_tx_nibble>:
  endbr64
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x39,%al
  cmova  %edi,%eax
  movzbl %al,%edi
  jmp    1050 <__console_tx_char@plt>
```

assistant: ```c
void __console_tx_nibble(unsigned nibble) {
  unsigned char digit;
  digit = nibble + '0';
  if (digit > '9') {
    digit += 39;
  }
  __console_tx_char(digit);
}
```