ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<display>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r14
  call   <gettimeofday@plt>
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r12,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L4:
  mov    %rbp,%rdi
  add    $0x8,%rbp
  call   <gpio_plane@plt>
  xor    %edi,%edi
  call   <gpio_oe@plt>
  xor    %edi,%edi
  call   <gpio_le@plt>
  mov    $0x1,%edi
  call   <gpio_le@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <gpio_layer@plt>
  mov    $0x1,%edi
  call   <gpio_oe@plt>
  cmp    $0x8,%ebx
  jne    L4
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%edx
  sub    0xc(%rsp),%edx
  movslq %edx,%rax
  mov    0x10(%rsp),%ecx
  sub    0x8(%rsp),%ecx
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  imul   $0x3e8,%ecx,%ecx
  sar    $0x26,%rax
  sub    %edx,%eax
  add    %ecx,%eax
  cmp    %r13d,%eax
  jl     L20
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void display(int duration, unsigned char *data) {
  struct timeval t0, now;
  int z, msec;
  gettimeofday(&t0, 0);
  z = 0;
  for (;;) {
    gpio_plane(data + z * 8);
    gpio_oe(0);
    gpio_le(0);
    gpio_le(1);
    gpio_layer(z);
    gpio_oe(1);
    z++;
    if (z >= 8) {
      z = 0;
      gettimeofday(&now, 0);
      msec = (now.tv_sec - t0.tv_sec) * 1000;
      msec += (now.tv_usec - t0.tv_usec) / 1000;
      if (msec >= duration)
        break;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L16
L15:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int tputs(char *string, int nlines, int (*outfun)(char)) {
  while (*string)
    outfun(*string++);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tputs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L18:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   *%rbp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L17:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tputs(char *string, int nlines, int (*outfun)(char)) {
  while (*string)
    outfun(*string++);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tputs>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L0
  mov    %rdx,%rbp
  nopl   0x0(%rax,%rax,1)
L2:
  call   *%rbp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L2
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tputs(char *string, int nlines, int (*outfun)(char)) {
  while (*string)
    outfun(*string++);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<tputs>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  mov    %rdx,%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  call   *%rbp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L18
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tputs(char *string, int nlines, int (*outfun)(char)) {
  while (*string)
    outfun(*string++);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D81(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L9
  movss  0x8(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L61
  comiss %xmm0,%xmm1
  ja     L26
L61:
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jb     L94
  comiss %xmm0,%xmm2
  ja     L63
L94:
  movss  0x10(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L129
  comiss %xmm0,%xmm1
  ja     L88
L129:
  comiss %xmm0,%xmm2
  jbe    L72
  lea    D92(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L9:
  lea    D44(%rip),%rdi
  call   <printf@plt>
L72:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L26:
  lea    D87(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L63:
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L88:
  lea    D79(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D81
type_guessed: string
name: extract_symbolic_data
arguments: label: D30
type_guessed: string
name: extract_symbolic_data
arguments: label: D64
type_guessed: string
name: extract_symbolic_data
arguments: label: D45
type_guessed: string
name: extract_symbolic_data
arguments: label: D53
type_guessed: string
name: extract_symbolic_data
arguments: label: D92
type_guessed: string
name: extract_symbolic_data
arguments: label: D44
type_guessed: string
name: extract_symbolic_data
arguments: label: D87
type_guessed: string
name: extract_symbolic_data
arguments: label: D54
type_guessed: string
name: extract_symbolic_data
arguments: label: D79
type_guessed: string

tool: D81: Enter thresholds for A, B, C, D

tool: D30: 
in that order, decreasing percentages > 

tool: D64: %f%f%f%f

tool: D45: Thank you. Now enter student score (percent) >

tool: D53: %f

tool: D92: Student has failed the course


tool: D44: Student has an A grade


tool: D87: Student has a B grade


tool: D54: Student has a C grade


tool: D79: Student has a D grade


assistant: ```c
int main() {
  float n1, n2, n3, n4;
  float perc;
  printf("Enter thresholds for A, B, C, D");
  printf("\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &n1, &n2, &n3, &n4);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &perc);
  if (perc >= n1)
    printf("Student has an A grade\n");
  else if (perc >= n2 && perc < n1)
    printf("Student has a B grade\n");
  else if (perc >= n3 && perc < n2)
    printf("Student has a C grade\n");
  else if (perc >= n4 && perc < n3)
    printf("Student has a D grade\n");
  else if (perc < n4)
    printf("Student has failed the course\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D52(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D71(%rip),%rdi
  call   <scanf@plt>
  lea    D81(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D57(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L128
  movss  0x8(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L123
  comiss %xmm0,%xmm1
  ja     L74
L123:
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L16
L58:
  movss  0x10(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L108
  comiss %xmm0,%xmm1
  ja     L94
L108:
  comiss %xmm0,%xmm2
  ja     L87
L109:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L16:
  comiss %xmm0,%xmm2
  jbe    L58
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L109
L128:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L109
L74:
  lea    D86(%rip),%rdi
  call   <printf@plt>
  jmp    L109
L94:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L109
L87:
  lea    D82(%rip),%rdi
  call   <printf@plt>
  jmp    L109
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D52
data_type: string
name: read_data
arguments: tag: D4
data_type: string
name: read_data
arguments: tag: D71
data_type: string
name: read_data
arguments: tag: D81
data_type: string
name: read_data
arguments: tag: D57
data_type: string
name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D29
data_type: string
name: read_data
arguments: tag: D86
data_type: string
name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D82
data_type: string

tool: D52: Enter thresholds for A, B, C, D

tool: D4: 
in that order, decreasing percentages > 

tool: D71: %f%f%f%f

tool: D81: Thank you. Now enter student score (percent) >

tool: D57: %f

tool: D7: Student has a C grade


tool: D29: Student has an A grade


tool: D86: Student has a B grade


tool: D13: Student has a D grade


tool: D82: Student has failed the course


assistant: ```c
int main() {
  float n1, n2, n3, n4;
  float perc;
  printf("Enter thresholds for A, B, C, D");
  printf("\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &n1, &n2, &n3, &n4);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &perc);
  if (perc >= n1)
    printf("Student has an A grade\n");
  else if (perc >= n2 && perc < n1)
    printf("Student has a B grade\n");
  else if (perc >= n3 && perc < n2)
    printf("Student has a C grade\n");
  else if (perc >= n4 && perc < n3)
    printf("Student has a D grade\n");
  else if (perc < n4)
    printf("Student has failed the course\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D56(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D82(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  lea    D92(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L131
  movss  0x8(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L92
  comiss %xmm0,%xmm1
  ja     L26
L92:
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L25
L125:
  movss  0x10(%rsp),%xmm2
  comiss %xmm2,%xmm0
  jb     L19
  comiss %xmm0,%xmm1
  ja     L102
L19:
  comiss %xmm0,%xmm2
  ja     L136
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L25:
  comiss %xmm0,%xmm2
  jbe    L125
  lea    D60(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L131:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L26:
  lea    D52(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L102:
  lea    D91(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L136:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D56
type_guessed: string
name: unpack_data
arguments: data_label: D82
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string
name: unpack_data
arguments: data_label: D92
type_guessed: string
name: unpack_data
arguments: data_label: D25
type_guessed: string
name: unpack_data
arguments: data_label: D60
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D52
type_guessed: string
name: unpack_data
arguments: data_label: D91
type_guessed: string
name: unpack_data
arguments: data_label: D19
type_guessed: string

tool: D56: Enter thresholds for A, B, C, D

tool: D82: 
in that order, decreasing percentages > 

tool: D12: %f%f%f%f

tool: D92: Thank you. Now enter student score (percent) >

tool: D25: %f

tool: D60: Student has a C grade


tool: D17: Student has an A grade


tool: D52: Student has a B grade


tool: D91: Student has a D grade


tool: D19: Student has failed the course


assistant: ```c
int main() {
  float n1, n2, n3, n4;
  float perc;
  printf("Enter thresholds for A, B, C, D");
  printf("\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &n1, &n2, &n3, &n4);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &perc);
  if (perc >= n1)
    printf("Student has an A grade\n");
  else if (perc >= n2 && perc < n1)
    printf("Student has a B grade\n");
  else if (perc >= n3 && perc < n2)
    printf("Student has a C grade\n");
  else if (perc >= n4 && perc < n3)
    printf("Student has a D grade\n");
  else if (perc < n4)
    printf("Student has failed the course\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_file_n_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L12
  mov    -0x30(%rbp),%rax
  movl   $0xffffffff,(%rax)
  jmp    L8
L12:
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
L8:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int write_file_n_(int *fd, char *buf, int *nbytes, int *ierr) {
  int bytes_written;
  bytes_written = write(*fd, buf, *nbytes);
  if (bytes_written != *nbytes) {
    *ierr = -1;
  } else {
    *ierr = 0;
  }
  return *ierr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_file_n_>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    (%rdx),%edx
  mov    (%rdi),%edi
  call   <write@plt>
  cmp    %eax,(%rbx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int write_file_n_(int *fd, char *buf, int *nbytes, int *ierr) {
  int bytes_written;
  bytes_written = write(*fd, buf, *nbytes);
  if (bytes_written != *nbytes) {
    *ierr = -1;
  } else {
    *ierr = 0;
  }
  return *ierr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_file_n_>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  mov    (%rdi),%edi
  call   <write@plt>
  cmp    %eax,(%rbx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int write_file_n_(int *fd, char *buf, int *nbytes, int *ierr) {
  int bytes_written;
  bytes_written = write(*fd, buf, *nbytes);
  if (bytes_written != *nbytes) {
    *ierr = -1;
  } else {
    *ierr = 0;
  }
  return *ierr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_file_n_>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  mov    (%rdi),%edi
  call   <write@plt>
  cmp    %eax,(%rbx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int write_file_n_(int *fd, char *buf, int *nbytes, int *ierr) {
  int bytes_written;
  bytes_written = write(*fd, buf, *nbytes);
  if (bytes_written != *nbytes) {
    *ierr = -1;
  } else {
    *ierr = 0;
  }
  return *ierr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L16
L8:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jle    L8
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ssq -0x20(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: array_total:%f


assistant: ```c
float mean(long long *array, long long array_length) {
  long long i = 0LL;
  float array_total = 0;
  float array_mean = 0;
  for (i = 0; i <= array_length; ++i) {
    array_total = array_total + array[i];
  }
  printf("array_total:%f\n", array_total);
  array_mean = array_total / array_length;
  return array_mean;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mean>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  js     L25
  mov    %rdi,%rax
  lea    0x8(%rdi,%rsi,8),%rdx
  pxor   %xmm3,%xmm3
  movss  %xmm3,0xc(%rsp)
L21:
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rax),%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L21
L27:
  movss  0xc(%rsp),%xmm0
  lea    D7(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %rbx,%xmm1
  movss  0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
L25:
  pxor   %xmm4,%xmm4
  movss  %xmm4,0xc(%rsp)
  jmp    L27
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: array_total:%f


assistant: ```c
float mean(long long *array, long long array_length) {
  long long i = 0LL;
  float array_total = 0;
  float array_mean = 0;
  for (i = 0; i <= array_length; ++i) {
    array_total = array_total + array[i];
  }
  printf("array_total:%f\n", array_total);
  array_mean = array_total / array_length;
  return array_mean;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mean>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  test   %rsi,%rsi
  js     L21
  lea    0x8(%rdi,%rsi,8),%rax
  pxor   %xmm0,%xmm0
  nopw   0x0(%rax,%rax,1)
L0:
  pxor   %xmm1,%xmm1
  add    $0x8,%rdi
  cvtsi2ssq -0x8(%rdi),%xmm1
  addss  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L0
L6:
  lea    D6(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  cvtsi2ss %rbx,%xmm1
  pop    %rbx
  divss  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  pxor   %xmm0,%xmm0
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D6: array_total:%f


assistant: ```c
float mean(long long *array, long long array_length) {
  long long i = 0LL;
  float array_total = 0;
  float array_mean = 0;
  for (i = 0; i <= array_length; ++i) {
    array_total = array_total + array[i];
  }
  printf("array_total:%f\n", array_total);
  array_mean = array_total / array_length;
  return array_mean;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mean>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  test   %rsi,%rsi
  js     L21
  lea    0x8(%rdi,%rsi,8),%rax
  pxor   %xmm0,%xmm0
  nopw   0x0(%rax,%rax,1)
L26:
  pxor   %xmm1,%xmm1
  add    $0x8,%rdi
  cvtsi2ssq -0x8(%rdi),%xmm1
  addss  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L26
L5:
  lea    D2(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  cvtsi2ss %rbx,%xmm1
  pop    %rbx
  divss  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  pxor   %xmm0,%xmm0
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D2: array_total:%f


assistant: ```c
float mean(long long *array, long long array_length) {
  long long i = 0LL;
  float array_total = 0;
  float array_mean = 0;
  for (i = 0; i <= array_length; ++i) {
    array_total = array_total + array[i];
  }
  printf("array_total:%f\n", array_total);
  array_mean = array_total / array_length;
  return array_mean;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<string_to_seconds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <string_to_milliseconds@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  jmp    L19
L5:
  mov    -0x8(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
L19:
  leave
  ret
```

assistant: ```c
long long string_to_seconds(const char *str) {
  long long ret = string_to_milliseconds(str);
  if (-1 == ret)
    return ret;
  return ret / 1000;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_to_seconds>:
  endbr64
  sub    $0x8,%rsp
  call   <string_to_milliseconds@plt>
  mov    %rax,%rcx
  cmp    $0xffffffffffffffff,%rax
  je     L2
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   %rdx
  sar    $0x7,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rcx
L2:
  mov    %rcx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long long string_to_seconds(const char *str) {
  long long ret = string_to_milliseconds(str);
  if (-1 == ret)
    return ret;
  return ret / 1000;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<string_to_seconds>:
  endbr64
  sub    $0x8,%rsp
  call   <string_to_milliseconds@plt>
  mov    %rax,%r8
  cmp    $0xffffffffffffffff,%rax
  je     L4
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   %rdx
  mov    %r8,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  mov    %rdx,%r8
L4:
  mov    %r8,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long long string_to_seconds(const char *str) {
  long long ret = string_to_milliseconds(str);
  if (-1 == ret)
    return ret;
  return ret / 1000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_to_seconds>:
  endbr64
  sub    $0x8,%rsp
  call   <string_to_milliseconds@plt>
  mov    %rax,%r8
  cmp    $0xffffffffffffffff,%rax
  je     L7
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   %rdx
  mov    %r8,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  mov    %rdx,%r8
L7:
  mov    %r8,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long long string_to_seconds(const char *str) {
  long long ret = string_to_milliseconds(str);
  if (-1 == ret)
    return ret;
  return ret / 1000;
}
```