ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<m_cvt_hex>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r8d,%r8d
  cmp    $0x2d,%dl
  jne    L87
  movzbl 0x1(%rdi),%edx
  mov    $0x1,%r8d
  add    $0x1,%rdi
L87:
  cmp    $0x30,%dl
  je     L21
L59:
  lea    -0x30(%rdx),%eax
  cmp    $0x3f,%al
  ja     L70
L29:
  xor    %eax,%eax
  lea    D5(%rip),%rsi
  jmp    L0
  nopl   0x0(%rax)
L22:
  shl    $0x4,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x3f,%cl
  ja     L56
L0:
  sub    $0x30,%edx
  movsbq %dl,%rdx
  movsbq (%rsi,%rdx,1),%rdx
  cmp    $0xff,%dl
  jne    L22
L56:
  mov    %rax,%rdx
  neg    %rdx
  test   %r8d,%r8d
  cmovne %rdx,%rax
  ret
  nopl   (%rax)
L21:
  cmpb   $0x78,0x1(%rdi)
  jne    L29
  movzbl 0x2(%rdi),%edx
  add    $0x2,%rdi
  jmp    L59
L70:
  xor    %eax,%eax
  jmp    L56
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: 

assistant: ```c
unsigned long long m_cvt_hex(char *s) {
  static const signed char cvt_matrix[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, -1, -1, -1, -1, -1, -1, -1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1};
  unsigned long long ret;
  int neg = 0;
  if (*s == '-') {
    neg = 1;
    s++;
  }
  if (s[0] == '0' && s[1] == 'x')
    s += 2;
  for (ret = 0; *s >= 0x30 && *s <= 0x6f; s++) {
    int d;
    d = cvt_matrix[*s - 0x30];
    if (d == -1)
      break;
    ret = (ret << 4) + d;
  }
  return neg ? -ret : ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<m_cvt_hex>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r8d,%r8d
  cmp    $0x2d,%dl
  jne    L37
  movzbl 0x1(%rdi),%edx
  mov    $0x1,%r8d
  add    $0x1,%rdi
L37:
  cmp    $0x30,%dl
  je     L66
L26:
  lea    -0x30(%rdx),%eax
  cmp    $0x3f,%al
  ja     L49
L61:
  xor    %eax,%eax
  lea    D3(%rip),%rsi
  jmp    L45
  nopl   0x0(%rax)
L29:
  shl    $0x4,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x3f,%cl
  ja     L2
L45:
  sub    $0x30,%edx
  movsbq %dl,%rdx
  movsbq (%rsi,%rdx,1),%rdx
  cmp    $0xff,%dl
  jne    L29
L2:
  mov    %rax,%rdx
  neg    %rdx
  test   %r8d,%r8d
  cmovne %rdx,%rax
  ret
  nopl   (%rax)
L66:
  cmpb   $0x78,0x1(%rdi)
  jne    L61
  movzbl 0x2(%rdi),%edx
  add    $0x2,%rdi
  jmp    L26
L49:
  xor    %eax,%eax
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: 

assistant: ```c
unsigned long long m_cvt_hex(char *s) {
  static const signed char cvt_matrix[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, -1, -1, -1, -1, -1, -1, -1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1};
  unsigned long long ret;
  int neg = 0;
  if (*s == '-') {
    neg = 1;
    s++;
  }
  if (s[0] == '0' && s[1] == 'x')
    s += 2;
  for (ret = 0; *s >= 0x30 && *s <= 0x6f; s++) {
    int d;
    d = cvt_matrix[*s - 0x30];
    if (d == -1)
      break;
    ret = (ret << 4) + d;
  }
  return neg ? -ret : ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ad7799_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L5:
  mov    $0xff,%edi
  call   <spi_transfer@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x3,-0x4(%rbp)
  jle    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void ad7799_reset(void) {
  int i;
  for (i = 0; i < 4; i++)
    spi_transfer(0xff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ad7799_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%edi
  call   <spi_transfer@plt>
  mov    $0xff,%edi
  call   <spi_transfer@plt>
  mov    $0xff,%edi
  call   <spi_transfer@plt>
  mov    $0xff,%edi
  call   <spi_transfer@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ad7799_reset(void) {
  int i;
  for (i = 0; i < 4; i++)
    spi_transfer(0xff);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ad7799_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%edi
  call   <spi_transfer@plt>
  mov    $0xff,%edi
  call   <spi_transfer@plt>
  mov    $0xff,%edi
  call   <spi_transfer@plt>
  mov    $0xff,%edi
  add    $0x8,%rsp
  jmp    1050 <spi_transfer@plt>
```

assistant: ```c
void ad7799_reset(void) {
  int i;
  for (i = 0; i < 4; i++)
    spi_transfer(0xff);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  nop
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  lea    D8(%rip),%rdx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <getopt@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L44
  mov    $0x0,%eax
  call   <_uptime_usage@plt>
  jmp    L5
L44:
  cmpl   $0x1,-0x14(%rbp)
  je     L41
  mov    $0x0,%eax
  call   <_uptime_usage@plt>
  jmp    L5
L41:
  mov    $0x0,%eax
  call   <_uptime@plt>
  test   %rax,%rax
  jne    L54
  mov    $0x0,%eax
  jmp    L5
L54:
  mov    $0x2,%eax
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: 

assistant: ```c
int main(int argc, char *argv[]) {
  int o;
  while ((o = getopt(argc, argv, "")) != -1)
    return _uptime_usage();
  if (argc != 1)
    return _uptime_usage();
  return (_uptime() == 0) ? 0 : 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D8(%rip),%rdx
  call   <getopt@plt>
  cmp    $0xffffffff,%eax
  jne    L5
  cmp    $0x1,%ebx
  je     L8
  mov    $0x0,%eax
  call   <_uptime_usage@plt>
  jmp    L0
L5:
  mov    $0x0,%eax
  call   <_uptime_usage@plt>
L0:
  pop    %rbx
  ret
L8:
  mov    $0x0,%eax
  call   <_uptime@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: 

assistant: ```c
int main(int argc, char *argv[]) {
  int o;
  while ((o = getopt(argc, argv, "")) != -1)
    return _uptime_usage();
  if (argc != 1)
    return _uptime_usage();
  return (_uptime() == 0) ? 0 : 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rdx
  mov    %edi,%ebx
  call   <getopt@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  jne    L4
  sub    $0x1,%ebx
  je     L11
L4:
  pop    %rbx
  jmp    1090 <_uptime_usage@plt>
L11:
  call   <_uptime@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: 

assistant: ```c
int main(int argc, char *argv[]) {
  int o;
  while ((o = getopt(argc, argv, "")) != -1)
    return _uptime_usage();
  if (argc != 1)
    return _uptime_usage();
  return (_uptime() == 0) ? 0 : 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rdx
  mov    %edi,%ebx
  call   <getopt@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  jne    L0
  sub    $0x1,%ebx
  je     L16
L0:
  pop    %rbx
  jmp    1090 <_uptime_usage@plt>
L16:
  call   <_uptime@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: 

assistant: ```c
int main(int argc, char *argv[]) {
  int o;
  while ((o = getopt(argc, argv, "")) != -1)
    return _uptime_usage();
  if (argc != 1)
    return _uptime_usage();
  return (_uptime() == 0) ? 0 : 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L10
  mov    -0x4(%rbp),%eax
  and    $0x5f,%eax
  jmp    L16
L10:
  mov    -0x4(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    return c & 0x5f;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<toupper>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <islower@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  and    $0x5f,%eax
  test   %rdx,%rdx
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    return c & 0x5f;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<toupper>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <islower@plt>
  mov    %rax,%r8
  mov    %r12d,%eax
  and    $0x5f,%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    return c & 0x5f;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<toupper>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <islower@plt>
  mov    %rax,%r8
  mov    %r12d,%eax
  and    $0x5f,%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int toupper(int c) {
  if (islower(c))
    return c & 0x5f;
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x30(%rbp)
  mov    %al,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L47
L15:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  addl   $0x1,-0x1c(%rbp)
L47:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L15
  movl   $0x0,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L32
L46:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  movsbl -0x2c(%rbp),%eax
  sub    $0x30,%eax
  imul   %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  subl   $0x1,-0x14(%rbp)
L32:
  cmpl   $0x0,-0x14(%rbp)
  jns    L46
  cmpl   $0x0,-0x18(%rbp)
  je     L57
  mov    -0x18(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L28
L57:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L28:
  leave
  ret
```

assistant: ```c
char *_multiply(char *num1, char n, int digit) {
  int len1 = (strlen(num1));
  char *sum = (char *)malloc((len1 + 2 + digit) * sizeof(char));
  sum[len1 + 1 + digit] = '\0';
  for (int i = len1 + 1; i < len1 + 1 + digit; i++)
    sum[i] = '0';
  int carry = 0;
  for (int i = len1 - 1; i >= 0; i--) {
    int r = (num1[i] - '0') * (n - '0') + carry;
    sum[i + 1] = r % 10 + '0';
    carry = r / 10;
  }
  if (carry != 0) {
    sum[0] = '0' + carry;
    return sum;
  }
  return sum + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_multiply>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%r13d
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    0x2(%rax,%r13,1),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r8
  lea    0x1(%r12),%eax
  add    %eax,%r13d
  movslq %r13d,%rdx
  movb   $0x0,(%rdi,%rdx,1)
  cmp    %r13d,%eax
  jge    L19
  cltq
  add    %rdi,%rax
  movslq %r12d,%rdx
  lea    0x2(%rdi,%rdx,1),%rdx
  sub    %r12d,%r13d
  lea    -0x2(%r13),%ecx
  add    %rcx,%rdx
L38:
  movb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L38
L19:
  mov    %r12d,%eax
  sub    $0x1,%eax
  js     L4
  cltq
  lea    0x1(%rdi,%rax,1),%rcx
  movslq %r12d,%rax
  lea    -0x1(%rdi,%rax,1),%rsi
  lea    -0x1(%r12),%eax
  sub    %rax,%rsi
  mov    $0x0,%edx
  sub    %rdi,%rbp
  movsbl %bl,%ebx
  sub    $0x30,%ebx
L52:
  movsbl -0x1(%rbp,%rcx,1),%eax
  sub    $0x30,%eax
  imul   %ebx,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%eax
  add    $0x30,%eax
  mov    %al,(%rcx)
  sub    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L52
  test   %edx,%edx
  jne    L10
L4:
  lea    0x1(%rdi),%r8
L56:
  mov    %r8,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  add    $0x30,%edx
  mov    %dl,(%rdi)
  jmp    L56
```

assistant: ```c
char *_multiply(char *num1, char n, int digit) {
  int len1 = (strlen(num1));
  char *sum = (char *)malloc((len1 + 2 + digit) * sizeof(char));
  sum[len1 + 1 + digit] = '\0';
  for (int i = len1 + 1; i < len1 + 1 + digit; i++)
    sum[i] = '0';
  int carry = 0;
  for (int i = len1 - 1; i >= 0; i--) {
    int r = (num1[i] - '0') * (n - '0') + carry;
    sum[i + 1] = r % 10 + '0';
    carry = r / 10;
  }
  if (carry != 0) {
    sum[0] = '0' + carry;
    return sum;
  }
  return sum + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_multiply>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%r13
  lea    0x2(%r13,%r15,1),%edi
  call   <malloc@plt>
  lea    0x1(%r13),%edi
  mov    %rax,%rbx
  mov    %rax,%r12
  lea    (%rdi,%r15,1),%eax
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  cmp    %eax,%edi
  jge    L30
  sub    %r13d,%eax
  movslq %edi,%rdi
  mov    $0x30,%esi
  lea    -0x2(%rax),%edx
  add    %rbx,%rdi
  add    $0x1,%rdx
  call   <memset@plt>
L30:
  mov    %r13d,%eax
  lea    0x1(%rbx),%r8
  sub    $0x1,%eax
  js     L12
  movslq %eax,%rcx
  movsbl %r14b,%esi
  lea    0x1(%rbx),%r8
  mov    %eax,%eax
  lea    -0x1(%rbx,%r13,1),%rdi
  sub    $0x30,%esi
  add    %r8,%rcx
  xor    %edx,%edx
  sub    %rax,%rdi
  sub    %rbx,%rbp
  nopl   0x0(%rax)
L26:
  movsbl -0x1(%rbp,%rcx,1),%eax
  sub    $0x1,%rcx
  sub    $0x30,%eax
  imul   %esi,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%r9d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r9d
  sar    $0x22,%rdx
  sub    %r9d,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%eax
  add    $0x30,%eax
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rdi
  jne    L26
  test   %edx,%edx
  jne    L34
L12:
  mov    %r8,%r12
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x30,%edx
  mov    %dl,(%rbx)
  jmp    L5
```

assistant: ```c
char *_multiply(char *num1, char n, int digit) {
  int len1 = (strlen(num1));
  char *sum = (char *)malloc((len1 + 2 + digit) * sizeof(char));
  sum[len1 + 1 + digit] = '\0';
  for (int i = len1 + 1; i < len1 + 1 + digit; i++)
    sum[i] = '0';
  int carry = 0;
  for (int i = len1 - 1; i >= 0; i--) {
    int r = (num1[i] - '0') * (n - '0') + carry;
    sum[i + 1] = r % 10 + '0';
    carry = r / 10;
  }
  if (carry != 0) {
    sum[0] = '0' + carry;
    return sum;
  }
  return sum + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_multiply>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%r13
  lea    0x2(%r13,%r15,1),%edi
  call   <malloc@plt>
  lea    0x1(%r13),%edi
  mov    %rax,%rbx
  mov    %rax,%r12
  lea    (%rdi,%r15,1),%eax
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  cmp    %eax,%edi
  jge    L16
  sub    %r13d,%eax
  movslq %edi,%rdi
  mov    $0x30,%esi
  lea    -0x2(%rax),%edx
  add    %rbx,%rdi
  add    $0x1,%rdx
  call   <memset@plt>
L16:
  mov    %r13d,%eax
  lea    0x1(%rbx),%r8
  sub    $0x1,%eax
  js     L47
  movslq %eax,%rcx
  movsbl %r14b,%esi
  lea    0x1(%rbx),%r8
  mov    %eax,%eax
  lea    -0x1(%rbx,%r13,1),%rdi
  sub    $0x30,%esi
  add    %r8,%rcx
  xor    %edx,%edx
  sub    %rax,%rdi
  sub    %rbx,%rbp
  nopl   0x0(%rax)
L3:
  movsbl -0x1(%rbp,%rcx,1),%eax
  sub    $0x1,%rcx
  sub    $0x30,%eax
  imul   %esi,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%r9d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r9d
  sar    $0x22,%rdx
  sub    %r9d,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%eax
  add    $0x30,%eax
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rdi
  jne    L3
  test   %edx,%edx
  jne    L11
L47:
  mov    %r8,%r12
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x30,%edx
  mov    %dl,(%rbx)
  jmp    L12
```

assistant: ```c
char *_multiply(char *num1, char n, int digit) {
  int len1 = (strlen(num1));
  char *sum = (char *)malloc((len1 + 2 + digit) * sizeof(char));
  sum[len1 + 1 + digit] = '\0';
  for (int i = len1 + 1; i < len1 + 1 + digit; i++)
    sum[i] = '0';
  int carry = 0;
  for (int i = len1 - 1; i >= 0; i--) {
    int r = (num1[i] - '0') * (n - '0') + carry;
    sum[i + 1] = r % 10 + '0';
    carry = r / 10;
  }
  if (carry != 0) {
    sum[0] = '0' + carry;
    return sum;
  }
  return sum + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L3
  mov    -0x18(%rbp),%rax
  mov    $0x2a,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <my_strchr@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int check_filter(unsigned char *filter) {
  unsigned char *c;
  int ret = 1;
  if (filter != ((void *)0)) {
    c = my_strchr(filter, '*');
    if (c != ((void *)0)) {
      *c = '\0';
      ret = 0;
    }
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_filter>:
  endbr64
  mov    $0x1,%edx
  test   %rdi,%rdi
  je     L18
  sub    $0x8,%rsp
  mov    $0x2a,%esi
  mov    $0x0,%eax
  call   <my_strchr@plt>
  mov    $0x1,%edx
  test   %eax,%eax
  je     L19
  cltq
  movb   $0x0,(%rax)
  mov    $0x0,%edx
L19:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L18:
  mov    %edx,%eax
  ret
```

assistant: ```c
int check_filter(unsigned char *filter) {
  unsigned char *c;
  int ret = 1;
  if (filter != ((void *)0)) {
    c = my_strchr(filter, '*');
    if (c != ((void *)0)) {
      *c = '\0';
      ret = 0;
    }
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_filter>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  xor    %eax,%eax
  mov    $0x2a,%esi
  call   <my_strchr@plt>
  test   %eax,%eax
  jne    L18
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  cltq
  movb   $0x0,(%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_filter(unsigned char *filter) {
  unsigned char *c;
  int ret = 1;
  if (filter != ((void *)0)) {
    c = my_strchr(filter, '*');
    if (c != ((void *)0)) {
      *c = '\0';
      ret = 0;
    }
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_filter>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  xor    %eax,%eax
  mov    $0x2a,%esi
  call   <my_strchr@plt>
  test   %eax,%eax
  jne    L17
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  cltq
  movb   $0x0,(%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_filter(unsigned char *filter) {
  unsigned char *c;
  int ret = 1;
  if (filter != ((void *)0)) {
    c = my_strchr(filter, '*');
    if (c != ((void *)0)) {
      *c = '\0';
      ret = 0;
    }
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vector_equals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L32:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L0
  ucomisd %xmm1,%xmm0
  je     L14
L0:
  mov    $0x0,%eax
  jmp    L34
L14:
  addl   $0x1,-0x4(%rbp)
L38:
  cmpl   $0x1,-0x4(%rbp)
  jle    L32
  mov    $0x1,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int vector_equals(double *v_1, double *v_2) {
  int i;
  for (i = 0; i < 2; i++) {
    if (v_1[i] != v_2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vector_equals>:
  endbr64
  movsd  (%rdi),%xmm0
  ucomisd (%rsi),%xmm0
  jp     L19
  jne    L19
  movsd  0x8(%rdi),%xmm0
  ucomisd 0x8(%rsi),%xmm0
  setnp  %al
  movzbl %al,%eax
  mov    $0x0,%edx
  cmovne %edx,%eax
  ret
L19:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int vector_equals(double *v_1, double *v_2) {
  int i;
  for (i = 0; i < 2; i++) {
    if (v_1[i] != v_2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vector_equals>:
  endbr64
  movsd  (%rdi),%xmm0
  ucomisd (%rsi),%xmm0
  jp     L10
  jne    L10
  movsd  0x8(%rdi),%xmm0
  xor    %eax,%eax
  ucomisd 0x8(%rsi),%xmm0
  mov    $0x0,%edx
  setnp  %al
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int vector_equals(double *v_1, double *v_2) {
  int i;
  for (i = 0; i < 2; i++) {
    if (v_1[i] != v_2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector_equals>:
  endbr64
  movsd  (%rdi),%xmm0
  ucomisd (%rsi),%xmm0
  jp     L18
  jne    L18
  movsd  0x8(%rdi),%xmm0
  xor    %eax,%eax
  ucomisd 0x8(%rsi),%xmm0
  mov    $0x0,%edx
  setnp  %al
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int vector_equals(double *v_1, double *v_2) {
  int i;
  for (i = 0; i < 2; i++) {
    if (v_1[i] != v_2[i]) {
      return 0;
    }
  }
  return 1;
}
```