ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L20
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D31(%rip),%r12
L22:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jg     L22
L32:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movd   %xmm2,%ebx
  lea    D30(%rip),%rdi
  call   <printf@plt>
  movd   %ebx,%xmm0
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    $0x0,%ebp
  jmp    L32
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D31
data_type: string
name: read_data
arguments: label: D30
data_type: string
name: read_data
arguments: label: D5
data_type: string

tool: D31: %d

tool: D30: Sum: %d


tool: D5: Avg: %.2f

assistant: ```c
int main() {
  int n, sum = 0, a;
  float avg;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &a);
    sum += a;
  }
  avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f", avg);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L32
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x14(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0x14(%rsp),%ebp
  cmp    %ebx,%eax
  jg     L20
L39:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  lea    D15(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  cvtsi2ss %eax,%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  lea    D2(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  xor    %ebp,%ebp
  jmp    L39
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D25: %d

tool: D15: Sum: %d


tool: D2: Avg: %.2f

assistant: ```c
int main() {
  int n, sum = 0, a;
  float avg;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &a);
    sum += a;
  }
  avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f", avg);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L38
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x14(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0x14(%rsp),%ebp
  cmp    %ebx,%eax
  jg     L33
L39:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  lea    D28(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  cvtsi2ss %eax,%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  lea    D9(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  xor    %ebp,%ebp
  jmp    L39
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D28
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D18: %d

tool: D28: Sum: %d


tool: D9: Avg: %.2f

assistant: ```c
int main() {
  int n, sum = 0, a;
  float avg;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &a);
    sum += a;
  }
  avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f", avg);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<s_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L19
  mov    -0x28(%rbp),%rax
  jmp    L40
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L2
L30:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L42
  mov    -0x10(%rbp),%rax
  jmp    L40
L42:
  addq   $0x1,-0x10(%rbp)
L2:
  mov    -0x30(%rbp),%rax
  sub    -0x8(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L30
  mov    -0x28(%rbp),%rax
L40:
  leave
  ret
```

assistant: ```c
off_t s_string(char *input, char *m, off_t offset, size_t i_l) {
  off_t i, m_l = strlen(m);
  if (!i_l) {
    return offset;
  }
  for (i = offset; i <= i_l - m_l; i++) {
    if (!strncmp(&input[i], m, m_l)) {
      return i;
    }
  }
  return offset;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r15
  test   %rcx,%rcx
  je     L2
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rcx,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  sub    %rax,%rbp
  cmp    %rbp,%r15
  ja     L2
  mov    %r15,%rbx
L5:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %r12,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L16
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jbe    L5
  jmp    L2
L16:
  mov    %rbx,%r15
L2:
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
off_t s_string(char *input, char *m, off_t offset, size_t i_l) {
  off_t i, m_l = strlen(m);
  if (!i_l) {
    return offset;
  }
  for (i = offset; i <= i_l - m_l; i++) {
    if (!strncmp(&input[i], m, m_l)) {
      return i;
    }
  }
  return offset;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<s_string>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L24
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %rcx,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  sub    %rax,%rbp
  mov    %rax,%r14
  cmp    %rbp,%r15
  ja     L24
  mov    %r15,%rbx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  ja     L24
L26:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %r12,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L34
  mov    %rbx,%r15
L24:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
off_t s_string(char *input, char *m, off_t offset, size_t i_l) {
  off_t i, m_l = strlen(m);
  if (!i_l) {
    return offset;
  }
  for (i = offset; i <= i_l - m_l; i++) {
    if (!strncmp(&input[i], m, m_l)) {
      return i;
    }
  }
  return offset;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<s_string>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L35
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %rcx,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  sub    %rax,%rbp
  mov    %rax,%r14
  cmp    %rbp,%r15
  ja     L35
  mov    %r15,%rbx
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  ja     L35
L48:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %r12,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L12
  mov    %rbx,%r15
L35:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
off_t s_string(char *input, char *m, off_t offset, size_t i_l) {
  off_t i, m_l = strlen(m);
  if (!i_l) {
    return offset;
  }
  for (i = offset; i <= i_l - m_l; i++) {
    if (!strncmp(&input[i], m, m_l)) {
      return i;
    }
  }
  return offset;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<spin_lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  nop
L7:
  mov    -0x8(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1,%ecx
  lock cmpxchg %ecx,(%rdx)
  sete   %al
  xor    $0x1,%eax
  test   %al,%al
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void spin_lock(int *p) {
  while (!__sync_bool_compare_and_swap(p, 0, 1))
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<spin_lock>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x1,%edx
L3:
  mov    %ecx,%eax
  lock cmpxchg %edx,(%rdi)
  jne    L3
  ret
```

assistant: ```c
void spin_lock(int *p) {
  while (!__sync_bool_compare_and_swap(p, 0, 1))
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<spin_lock>:
  endbr64
  xor    %ecx,%ecx
  mov    $0x1,%edx
L3:
  mov    %ecx,%eax
  lock cmpxchg %edx,(%rdi)
  jne    L3
  ret
```

assistant: ```c
void spin_lock(int *p) {
  while (!__sync_bool_compare_and_swap(p, 0, 1))
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<spin_lock>:
  endbr64
  xor    %ecx,%ecx
  mov    $0x1,%edx
L8:
  mov    %ecx,%eax
  lock cmpxchg %edx,(%rdi)
  jne    L8
  ret
```

assistant: ```c
void spin_lock(int *p) {
  while (!__sync_bool_compare_and_swap(p, 0, 1))
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%edi
  call   <recurse@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  recurse(0);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <recurse@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  recurse(0);
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <recurse@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  recurse(0);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <recurse@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  recurse(0);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x88(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L29
L49:
  lea    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x84(%rbp)
  cmpl   $0xa,-0x84(%rbp)
  jg     L0
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L9
L0:
  mov    -0x84(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x84(%rbp),%eax
  lea    -0x2(%rax),%esi
  movzbl -0x80(%rbp),%eax
  movsbl %al,%eax
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  lea    -0x80(%rbp),%rax
  mov    $0x6e,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L29:
  mov    -0x88(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x88(%rbp)
  test   %eax,%eax
  jne    L49
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D15: %d

tool: D14: %s

tool: D5: %c%d%c


assistant: ```c
int main() {
  int len, N;
  char s[110];
  scanf("%d", &N);
  while (N--) {
    scanf("%s", s);
    len = strlen(s);
    if (len <= 10)
      printf("%s\n", s);
    else
      printf("%c%d%c\n", s[0], len - 2, s[len - 1]);
    memset(s, 0, sizeof(s));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L48
  lea    0x10(%rsp),%rbx
  lea    D28(%rip),%rbp
  lea    D20(%rip),%r12
  jmp    L54
L18:
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  movsbl 0x10(%rsp,%rdx,1),%ecx
  lea    -0x2(%rax),%edx
  movsbl 0x10(%rsp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  mov    $0x6e,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L48
L54:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jg     L18
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L7
L48:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
type_infered: string
name: retrieve_data
arguments: tag: D28
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string

tool: D18: %d

tool: D28: %s

tool: D20: %c%d%c


assistant: ```c
int main() {
  int len, N;
  char s[110];
  scanf("%d", &N);
  while (N--) {
    scanf("%s", s);
    len = strlen(s);
    if (len <= 10)
      printf("%s\n", s);
    else
      printf("%c%d%c\n", s[0], len - 2, s[len - 1]);
    memset(s, 0, sizeof(s));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L6
  lea    0x10(%rsp),%rbx
  lea    D24(%rip),%rbp
  lea    D23(%rip),%r12
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdi
  call   <puts@plt>
L50:
  mov    $0x6e,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L6
L48:
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jle    L9
  lea    -0x1(%rax),%edx
  movsbl 0x10(%rsp),%esi
  mov    %r12,%rdi
  movslq %edx,%rdx
  movsbl 0x10(%rsp,%rdx,1),%ecx
  lea    -0x2(%rax),%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L50
  nop
L6:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D23
type_infered: string

tool: D0: %d

tool: D24: %s

tool: D23: %c%d%c


assistant: ```c
int main() {
  int len, N;
  char s[110];
  scanf("%d", &N);
  while (N--) {
    scanf("%s", s);
    len = strlen(s);
    if (len <= 10)
      printf("%s\n", s);
    else
      printf("%c%d%c\n", s[0], len - 2, s[len - 1]);
    memset(s, 0, sizeof(s));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L55
  lea    0x10(%rsp),%rbx
  lea    D24(%rip),%rbp
  lea    D20(%rip),%r12
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbx,%rdi
  call   <puts@plt>
L41:
  mov    $0x6e,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L55
L4:
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jle    L28
  lea    -0x1(%rax),%edx
  movsbl 0x10(%rsp),%esi
  mov    %r12,%rdi
  movslq %edx,%rdx
  movsbl 0x10(%rsp,%rdx,1),%ecx
  lea    -0x2(%rax),%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L41
  nop
L55:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D20
datatype: string

tool: D6: %d

tool: D24: %s

tool: D20: %c%d%c


assistant: ```c
int main() {
  int len, N;
  char s[110];
  scanf("%d", &N);
  while (N--) {
    scanf("%s", s);
    len = strlen(s);
    if (len <= 10)
      printf("%s\n", s);
    else
      printf("%c%d%c\n", s[0], len - 2, s[len - 1]);
    memset(s, 0, sizeof(s));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <usage@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D58
type: string
name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D21
type: string
name: retrieve_data
arguments: label: D37
type: string
name: retrieve_data
arguments: label: D14
type: string

tool: D58: OPTION


tool: D0:   -h, --help
  	Print this help screen.



tool: D16:   -a, --application <NAME>
  	Name of application process.



tool: D21:   -m, --middleware <NAME>
  	Name of middleware process.



tool: D37:   -t, --time <TIME>
  	Stop application after TIME.



tool: D14: AUTHOR
  Sebastian Meiling <sebastian.meiling (at) haw-hamburg.de>



assistant: ```c
void help(const char *program) {
  usage(program);
  printf("OPTION\n");
  printf("  -h, --help\n  \tPrint this help screen.\n\n");
  printf("  -a, --application <NAME>\n  \tName of application process.\n\n");
  printf("  -m, --middleware <NAME>\n  \tName of middleware process.\n\n");
  printf("  -t, --time <TIME>\n  \tStop application after TIME.\n\n");
  printf("AUTHOR\n  Sebastian Meiling <sebastian.meiling (at) haw-hamburg.de>\n\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  call   <usage@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D57
type: string
name: disassemble_data
arguments: label: D45
type: string
name: disassemble_data
arguments: label: D9
type: string
name: disassemble_data
arguments: label: D24
type: string

tool: D3: OPTION


tool: D25:   -h, --help
  	Print this help screen.



tool: D57:   -a, --application <NAME>
  	Name of application process.



tool: D45:   -m, --middleware <NAME>
  	Name of middleware process.



tool: D9:   -t, --time <TIME>
  	Stop application after TIME.



tool: D24: AUTHOR
  Sebastian Meiling <sebastian.meiling (at) haw-hamburg.de>



assistant: ```c
void help(const char *program) {
  usage(program);
  printf("OPTION\n");
  printf("  -h, --help\n  \tPrint this help screen.\n\n");
  printf("  -a, --application <NAME>\n  \tName of application process.\n\n");
  printf("  -m, --middleware <NAME>\n  \tName of middleware process.\n\n");
  printf("  -t, --time <TIME>\n  \tStop application after TIME.\n\n");
  printf("AUTHOR\n  Sebastian Meiling <sebastian.meiling (at) haw-hamburg.de>\n\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  call   <usage@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D30
type_infered: string
name: retrieve_data
arguments: label: D58
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D16: OPTION


tool: D3:   -h, --help
  	Print this help screen.



tool: D8:   -a, --application <NAME>
  	Name of application process.



tool: D30:   -m, --middleware <NAME>
  	Name of middleware process.



tool: D58:   -t, --time <TIME>
  	Stop application after TIME.



tool: D9: AUTHOR
  Sebastian Meiling <sebastian.meiling (at) haw-hamburg.de>



assistant: ```c
void help(const char *program) {
  usage(program);
  printf("OPTION\n");
  printf("  -h, --help\n  \tPrint this help screen.\n\n");
  printf("  -a, --application <NAME>\n  \tName of application process.\n\n");
  printf("  -m, --middleware <NAME>\n  \tName of middleware process.\n\n");
  printf("  -t, --time <TIME>\n  \tStop application after TIME.\n\n");
  printf("AUTHOR\n  Sebastian Meiling <sebastian.meiling (at) haw-hamburg.de>\n\n");
}
```