ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D15(%rip),%rdi
  push   %r13
  lea    D47(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D49(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x24(%rsp),%r12
  movl   $0x4,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D36(%rip),%xmm0
  mov    %r14,%rbx
  mov    %r14,%rbp
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L29:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L29
  mov    %r14,%rdi
  mov    $0x9,%esi
  call   <heapsort@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L18:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D47
type_infered: string
name: retrieve_data
arguments: data_label: D49
type_infered: byte[16]
name: retrieve_data
arguments: data_label: D36
type_infered: byte[16]
name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D15: Before heapsort

tool: D47: %d 

tool: {"D49": [0x05,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x19,0x00,0x00,0x00]}

tool: {"D36": [0x07,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: D9: 
After heapsort

assistant: ```c
int main(void) {
  int array[] = {5, 13, 2, 25, 7, 17, 20, 8, 4};
  unsigned int i = 0;
  puts("Before heapsort");
  for (i = 0; i < sizeof(array) / sizeof(int); i++) {
    printf("%d ", array[i]);
  }
  heapsort(array, sizeof(array) / sizeof(int));
  puts("\nAfter heapsort");
  for (i = 0; i < sizeof(array) / sizeof(int); i++) {
    printf("%d ", array[i]);
  }
  getchar();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L18
L15:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string

tool: D8: %d, 

assistant: ```c
void print_arr(int *arr, int len) {
  while (len-- > 0) {
    printf("%d, ", *(arr++));
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_arr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L7
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%r12
  lea    D1(%rip),%rbp
L3:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d, 

assistant: ```c
void print_arr(int *arr, int len) {
  while (len-- > 0) {
    printf("%d, ", *(arr++));
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L14
  movslq %esi,%rsi
  push   %r12
  lea    (%rdi,%rsi,4),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L17:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: %d, 

assistant: ```c
void print_arr(int *arr, int len) {
  while (len-- > 0) {
    printf("%d, ", *(arr++));
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L1
  movslq %esi,%rsi
  push   %r12
  lea    (%rdi,%rsi,4),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L9:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: string

tool: D3: %d, 

assistant: ```c
void print_arr(int *arr, int len) {
  while (len-- > 0) {
    printf("%d, ", *(arr++));
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compare_and_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L38
  cmpl   $0x1,-0x1c(%rbp)
  jle    L38
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L61
L38:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L61
  cmpl   $0x2,-0x1c(%rbp)
  jle    L61
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L61:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  cmpl   $0x2,-0x1c(%rbp)
  jle    L34
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L34:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: %15s 

assistant: ```c
void compare_and_print(char *ip1, char *ip2, char *ip3, int i) {
  printf("%15s ", ip1);
  if (strcmp(ip1, ip2) && i > 1)
    printf("%15s ", ip2);
  else if (strcmp(ip1, ip3) && i > 2)
    printf("%15s ", ip3);
  if (strcmp(ip1, ip3) && strcmp(ip2, ip3) && i > 2)
    printf("%15s ", ip3);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compare_and_print>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  mov    %rdi,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%r12d
  jle    L30
  test   %rax,%rax
  jne    L45
L30:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x2,%r12d
  jle    L19
  test   %rax,%rax
  jne    L94
L19:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L7
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  mov    %r13,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L94:
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L7:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  cmp    $0x2,%r12d
  jle    L23
  test   %rax,%rax
  je     L23
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: read_data
arguments: data_tag: D29
type: string

tool: D29: %15s 

assistant: ```c
void compare_and_print(char *ip1, char *ip2, char *ip3, int i) {
  printf("%15s ", ip1);
  if (strcmp(ip1, ip2) && i > 1)
    printf("%15s ", ip2);
  else if (strcmp(ip1, ip3) && i > 2)
    printf("%15s ", ip3);
  if (strcmp(ip1, ip3) && strcmp(ip2, ip3) && i > 2)
    printf("%15s ", ip3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<compare_and_print>:
  endbr64
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r14,%rdi
  push   %rbx
  mov    %ecx,%ebx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%ebx
  jle    L85
  test   %rax,%rax
  jne    L41
L85:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x2,%ebx
  jle    L14
  test   %rax,%rax
  jne    L5
L14:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L37
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L41:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L57
L37:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  cmp    $0x2,%ebx
  jle    L57
  test   %rax,%rax
  je     L57
  pop    %rbx
  mov    %r12,%rsi
  pop    %rbp
  mov    %r14,%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string

tool: D4: %15s 

assistant: ```c
void compare_and_print(char *ip1, char *ip2, char *ip3, int i) {
  printf("%15s ", ip1);
  if (strcmp(ip1, ip2) && i > 1)
    printf("%15s ", ip2);
  else if (strcmp(ip1, ip3) && i > 2)
    printf("%15s ", ip3);
  if (strcmp(ip1, ip3) && strcmp(ip2, ip3) && i > 2)
    printf("%15s ", ip3);
}
```
user: What is the c source code of the assembly code below:

```asm
<compare_and_print>:
  endbr64
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r14,%rdi
  push   %rbx
  mov    %ecx,%ebx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%ebx
  jle    L18
  test   %rax,%rax
  jne    L67
L18:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x2,%ebx
  jle    L2
  test   %rax,%rax
  jne    L65
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L42
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L67:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
L42:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  cmp    $0x2,%ebx
  jle    L22
  test   %rax,%rax
  je     L22
  pop    %rbx
  mov    %r12,%rsi
  pop    %rbp
  mov    %r14,%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L65:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: %15s 

assistant: ```c
void compare_and_print(char *ip1, char *ip2, char *ip3, int i) {
  printf("%15s ", ip1);
  if (strcmp(ip1, ip2) && i > 1)
    printf("%15s ", ip2);
  else if (strcmp(ip1, ip3) && i > 2)
    printf("%15s ", ip3);
  if (strcmp(ip1, ip3) && strcmp(ip2, ip3) && i > 2)
    printf("%15s ", ip3);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<longitud_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L3:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int longitud_string(char *s) {
  int i = 0;
  while (*(s++) != '\0')
    i++;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<longitud_string>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L7
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L23:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L23
L17:
  mov    %ecx,%eax
  ret
L7:
  mov    $0x0,%ecx
  jmp    L17
```

assistant: ```c
int longitud_string(char *s) {
  int i = 0;
  while (*(s++) != '\0')
    i++;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<longitud_string>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L17
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L11:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L11
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int longitud_string(char *s) {
  int i = 0;
  while (*(s++) != '\0')
    i++;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<longitud_string>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L19
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L8:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L8
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int longitud_string(char *s) {
  int i = 0;
  while (*(s++) != '\0')
    i++;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L19:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0xb0(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strFind@plt>
  mov    %eax,-0xb4(%rbp)
  cmpl   $0xffffffff,-0xb4(%rbp)
  je     L18
  mov    -0xb4(%rbp),%edx
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
L18:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D25
type: string
name: extract_symbolic_data
arguments: label: D34
type: string

tool: D14: Text to find in: 

tool: D0: > 

tool: D25: Substring '%s' found at index %i.



tool: D34: Substring '%s' NOT found in text.



assistant: ```c
int main() {
  char text[80], substring[80];
  int i;
  printf("Text to find in: ");
  gets(text);
  printf("\n");
  while (true) {
    printf("> ");
    gets(substring);
    i = strFind(substring, text);
    if (i != -1)
      printf("Substring '%s' found at index %i.\n\n", substring, i);
    else
      printf("Substring '%s' NOT found in text.\n\n", substring);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <gets@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D28(%rip),%rbp
  lea    0x50(%rsp),%rbx
  lea    D7(%rip),%r13
  lea    D33(%rip),%r12
  jmp    L3
L25:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L3:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strFind@plt>
  mov    %eax,%edx
  cmp    $0xffffffff,%eax
  jne    L25
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: unpack_data
arguments: label: D27
type_infered: string
name: unpack_data
arguments: label: D28
type_infered: string
name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D33
type_infered: string

tool: D27: Text to find in: 

tool: D28: > 

tool: D7: Substring '%s' NOT found in text.



tool: D33: Substring '%s' found at index %i.



assistant: ```c
int main() {
  char text[80], substring[80];
  int i;
  printf("Text to find in: ");
  gets(text);
  printf("\n");
  while (true) {
    printf("> ");
    gets(substring);
    i = strFind(substring, text);
    if (i != -1)
      printf("Substring '%s' found at index %i.\n\n", substring, i);
    else
      printf("Substring '%s' NOT found in text.\n\n", substring);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D25(%rip),%rdi
  lea    D23(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x50(%rsp),%rbx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nopl   0x0(%rax)
L23:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strFind@plt>
  mov    %rbx,%rsi
  mov    %eax,%edx
  cmp    $0xffffffff,%eax
  je     L21
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D25: Text to find in: 

tool: D23: Substring '%s' NOT found in text.



tool: D0: Substring '%s' found at index %i.



tool: D6: > 

assistant: ```c
int main() {
  char text[80], substring[80];
  int i;
  printf("Text to find in: ");
  gets(text);
  printf("\n");
  while (true) {
    printf("> ");
    gets(substring);
    i = strFind(substring, text);
    if (i != -1)
      printf("Substring '%s' found at index %i.\n\n", substring, i);
    else
      printf("Substring '%s' NOT found in text.\n\n", substring);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D11(%rip),%rdi
  lea    D17(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x50(%rsp),%rbx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nopl   0x0(%rax)
L23:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strFind@plt>
  mov    %rbx,%rsi
  mov    %eax,%edx
  cmp    $0xffffffff,%eax
  je     L8
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_infered: string
name: disassemble_data
arguments: tag: D17
type_infered: string
name: disassemble_data
arguments: tag: D5
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string

tool: D11: Text to find in: 

tool: D17: Substring '%s' NOT found in text.



tool: D5: Substring '%s' found at index %i.



tool: D13: > 

assistant: ```c
int main() {
  char text[80], substring[80];
  int i;
  printf("Text to find in: ");
  gets(text);
  printf("\n");
  while (true) {
    printf("> ");
    gets(substring);
    i = strFind(substring, text);
    if (i != -1)
      printf("Substring '%s' found at index %i.\n\n", substring, i);
    else
      printf("Substring '%s' NOT found in text.\n\n", substring);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<index_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  neg    %eax
  and    %eax,-0x14(%rbp)
L0:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L24
  mov    -0x4(%rbp),%eax
  jmp    L7
L24:
  addl   $0x1,-0x4(%rbp)
  jmp    L0
L7:
  pop    %rbp
  ret
```

assistant: ```c
int index_of(int bitset) {
  int j = 0;
  bitset &= (-bitset);
  for (;;) {
    bitset >>= 1;
    if (bitset == 0)
      return j;
    ++j;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<index_of>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  and    %edi,%eax
  mov    $0x0,%edx
  sar    %eax
  je     L28
L20:
  add    $0x1,%edx
  sar    %eax
  jne    L20
L19:
  mov    %edx,%eax
  ret
L28:
  mov    %eax,%edx
  jmp    L19
```

assistant: ```c
int index_of(int bitset) {
  int j = 0;
  bitset &= (-bitset);
  for (;;) {
    bitset >>= 1;
    if (bitset == 0)
      return j;
    ++j;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<index_of>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  neg    %eax
  and    %edi,%eax
  sar    %eax
  je     L9
  nopl   0x0(%rax)
L0:
  add    $0x1,%r8d
  sar    %eax
  jne    L0
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int index_of(int bitset) {
  int j = 0;
  bitset &= (-bitset);
  for (;;) {
    bitset >>= 1;
    if (bitset == 0)
      return j;
    ++j;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<index_of>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  neg    %eax
  and    %edi,%eax
  sar    %eax
  je     L6
  nopl   0x0(%rax)
L18:
  add    $0x1,%r8d
  sar    %eax
  jne    L18
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int index_of(int bitset) {
  int j = 0;
  bitset &= (-bitset);
  for (;;) {
    bitset >>= 1;
    if (bitset == 0)
      return j;
    ++j;
  }
}
```