ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_siginterrupt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    $0x0,%esi
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  je     L39
  test   %ebp,%ebp
  je     L20
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    0x4(%rsp),%eax
L34:
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  mov    %ebx,%edi
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    D15(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  jmp    L34
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _siginterrupt(int signal, int flag) {
  struct sigaction actbuff;
  if (sigaction(signal, NULL, &actbuff) == -1) {
    return -1;
  }
  if (flag) {
    actbuff.sa_flags &= ~SA_RESTART;
  } else {
    actbuff.sa_flags &= SA_RESTART;
  }
  if (sigaction(signal, &actbuff, NULL) == -1) {
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_siginterrupt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  je     L17
  mov    D8(%rip),%rax
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    (%rax),%eax
  mov    %eax,%edx
  and    0x4(%rsp),%eax
  not    %edx
  and    0x4(%rsp),%edx
  test   %ebx,%ebx
  cmovne %edx,%eax
  xor    %edx,%edx
  mov    %eax,0x4(%rsp)
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _siginterrupt(int signal, int flag) {
  struct sigaction actbuff;
  if (sigaction(signal, NULL, &actbuff) == -1) {
    return -1;
  }
  if (flag) {
    actbuff.sa_flags &= ~SA_RESTART;
  } else {
    actbuff.sa_flags &= SA_RESTART;
  }
  if (sigaction(signal, &actbuff, NULL) == -1) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_siginterrupt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  je     L13
  mov    D1(%rip),%rax
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    (%rax),%eax
  mov    %eax,%edx
  and    0x4(%rsp),%eax
  not    %edx
  and    0x4(%rsp),%edx
  test   %ebx,%ebx
  cmovne %edx,%eax
  xor    %edx,%edx
  mov    %eax,0x4(%rsp)
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _siginterrupt(int signal, int flag) {
  struct sigaction actbuff;
  if (sigaction(signal, NULL, &actbuff) == -1) {
    return -1;
  }
  if (flag) {
    actbuff.sa_flags &= ~SA_RESTART;
  } else {
    actbuff.sa_flags &= SA_RESTART;
  }
  if (sigaction(signal, &actbuff, NULL) == -1) {
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ptree_search_data_exact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L1
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L3
L1:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%r8
  mov    -0x20(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <ptree_search_data_r_x@plt>
L3:
  leave
  ret
```

assistant: ```c
int ptree_search_data_exact(void *str, size_t sstr, struct sockaddr_storage *addr, size_t *alen, struct patricia_node *root) {
  if (!root)
    return -ENOENT;
  return ptree_search_data_r_x(root, str, sstr, addr, alen, sstr * 8);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ptree_search_data_exact>:
  endbr64
  test   %r8,%r8
  je     L1
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %r8,%rdi
  lea    0x0(,%rsi,8),%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    %rax,%rsi
  call   <ptree_search_data_r_x@plt>
  add    $0x8,%rsp
  ret
L1:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int ptree_search_data_exact(void *str, size_t sstr, struct sockaddr_storage *addr, size_t *alen, struct patricia_node *root) {
  if (!root)
    return -ENOENT;
  return ptree_search_data_r_x(root, str, sstr, addr, alen, sstr * 8);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ptree_search_data_exact>:
  endbr64
  mov    %rdi,%r11
  mov    %r8,%rdi
  test   %r8,%r8
  je     L1
  lea    0x0(,%rsi,8),%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    %r11,%rsi
  jmp    1050 <ptree_search_data_r_x@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int ptree_search_data_exact(void *str, size_t sstr, struct sockaddr_storage *addr, size_t *alen, struct patricia_node *root) {
  if (!root)
    return -ENOENT;
  return ptree_search_data_r_x(root, str, sstr, addr, alen, sstr * 8);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ptree_search_data_exact>:
  endbr64
  mov    %rdi,%r11
  mov    %r8,%rdi
  test   %r8,%r8
  je     L2
  lea    0x0(,%rsi,8),%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    %r11,%rsi
  jmp    1050 <ptree_search_data_r_x@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int ptree_search_data_exact(void *str, size_t sstr, struct sockaddr_storage *addr, size_t *alen, struct patricia_node *root) {
  if (!root)
    return -ENOENT;
  return ptree_search_data_r_x(root, str, sstr, addr, alen, sstr * 8);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GenerateMagic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <arc4random@plt>
  pop    %rbp
  ret
```

assistant: ```c
u_int32_t GenerateMagic(void) {
  ;
  return arc4random();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GenerateMagic>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <arc4random@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
u_int32_t GenerateMagic(void) {
  ;
  return arc4random();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GenerateMagic>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <arc4random@plt>
```

assistant: ```c
u_int32_t GenerateMagic(void) {
  ;
  return arc4random();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GenerateMagic>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <arc4random@plt>
```

assistant: ```c
u_int32_t GenerateMagic(void) {
  ;
  return arc4random();
}
```
user: Translate the below assembly code into C programming language:

```asm
<dupstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *dupstr(const char *s) {
  char *p = malloc(strlen(s) + 1);
  if (p != NULL)
    strcpy(p, s);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dupstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *dupstr(const char *s) {
  char *p = malloc(strlen(s) + 1);
  if (p != NULL)
    strcpy(p, s);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dupstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *dupstr(const char *s) {
  char *p = malloc(strlen(s) + 1);
  if (p != NULL)
    strcpy(p, s);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dupstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *dupstr(const char *s) {
  char *p = malloc(strlen(s) + 1);
  if (p != NULL)
    strcpy(p, s);
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<popcnt_words0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L6
L24:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__builtin_popcountll@plt>
  mov    %rax,%rbx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__builtin_popcountll@plt>
  lea    (%rbx,%rax,1),%r12
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__builtin_popcountll@plt>
  mov    %rax,%rbx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__builtin_popcountll@plt>
  add    %rbx,%rax
  add    %r12,%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x4,-0x14(%rbp)
L6:
  mov    -0x2c(%rbp),%eax
  and    $0xfffffffc,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L24
  jmp    L17
L15:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__builtin_popcountll@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L15
  mov    -0x18(%rbp),%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
uint64_t popcnt_words0(uint64_t *buf, int64_t n) {
  uint64_t cnt = 0;
  uint64_t i;
  for (i = 0; i < (n & ~3); i += 4) {
    cnt += (__builtin_popcountll(buf[i + 0]) + __builtin_popcountll(buf[i + 1])) + (__builtin_popcountll(buf[i + 2]) + __builtin_popcountll(buf[i + 3]));
  }
  for (; i < n; ++i) {
    cnt += __builtin_popcountll(buf[i]);
  }
  return cnt;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<popcnt_words0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,%eax
  mov    %esi,0x8(%rsp)
  and    $0xfffffffc,%eax
  jle    L32
  mov    %rdi,%rbp
  sub    $0x1,%eax
  shr    $0x2,%eax
  mov    %eax,0xc(%rsp)
  mov    %eax,%eax
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%r14
  mov    $0x0,%r13d
L27:
  mov    0x0(%rbp),%edi
  call   <__builtin_popcountll@plt>
  mov    %rax,%r12
  mov    0x4(%rbp),%edi
  call   <__builtin_popcountll@plt>
  add    %rax,%r12
  mov    0x8(%rbp),%edi
  call   <__builtin_popcountll@plt>
  mov    %rax,%rbx
  mov    0xc(%rbp),%edi
  call   <__builtin_popcountll@plt>
  add    %rax,%rbx
  add    %r12,%rbx
  add    %ebx,%r13d
  add    $0x10,%rbp
  cmp    %r14,%rbp
  jne    L27
  mov    0xc(%rsp),%eax
  lea    0x4(,%rax,4),%edx
L26:
  mov    0x8(%rsp),%eax
  cmp    %edx,%eax
  jle    L15
  movslq %edx,%rcx
  lea    (%r15,%rcx,4),%rbx
  sub    $0x1,%eax
  sub    %edx,%eax
  add    %rcx,%rax
  lea    0x4(%r15,%rax,4),%rbp
L35:
  mov    (%rbx),%edi
  call   <__builtin_popcountll@plt>
  add    %eax,%r13d
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L35
L15:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    $0x0,%edx
  mov    $0x0,%r13d
  jmp    L26
```

assistant: ```c
uint64_t popcnt_words0(uint64_t *buf, int64_t n) {
  uint64_t cnt = 0;
  uint64_t i;
  for (i = 0; i < (n & ~3); i += 4) {
    cnt += (__builtin_popcountll(buf[i + 0]) + __builtin_popcountll(buf[i + 1])) + (__builtin_popcountll(buf[i + 2]) + __builtin_popcountll(buf[i + 3]));
  }
  for (; i < n; ++i) {
    cnt += __builtin_popcountll(buf[i]);
  }
  return cnt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<popcnt_words0>:
  endbr64
  push   %r15
  mov    %esi,%eax
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  and    $0xfffffffc,%eax
  jle    L49
  sub    $0x1,%eax
  mov    %rdi,%r13
  xor    %r12d,%r12d
  shr    $0x2,%eax
  mov    %eax,0xc(%rsp)
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%r14
  nopl   (%rax)
L10:
  mov    0x0(%r13),%edi
  add    $0x10,%r13
  call   <__builtin_popcountll@plt>
  mov    -0xc(%r13),%edi
  mov    %rax,%rbp
  call   <__builtin_popcountll@plt>
  mov    -0x8(%r13),%edi
  add    %rax,%rbp
  call   <__builtin_popcountll@plt>
  mov    -0x4(%r13),%edi
  mov    %rax,%rbx
  call   <__builtin_popcountll@plt>
  add    %rax,%rbx
  add    %rbp,%rbx
  add    %ebx,%r12d
  cmp    %r14,%r13
  jne    L10
  mov    0xc(%rsp),%eax
  lea    0x4(,%rax,4),%eax
L30:
  mov    0x8(%rsp),%ecx
  cmp    %eax,%ecx
  jle    L15
  sub    $0x1,%ecx
  movslq %eax,%rdx
  mov    %ecx,%r13d
  lea    (%r15,%rdx,4),%rbx
  sub    %eax,%r13d
  add    %rdx,%r13
  lea    0x4(%r15,%r13,4),%rbp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <__builtin_popcountll@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L2
L15:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L49:
  xor    %eax,%eax
  xor    %r12d,%r12d
  jmp    L30
```

assistant: ```c
uint64_t popcnt_words0(uint64_t *buf, int64_t n) {
  uint64_t cnt = 0;
  uint64_t i;
  for (i = 0; i < (n & ~3); i += 4) {
    cnt += (__builtin_popcountll(buf[i + 0]) + __builtin_popcountll(buf[i + 1])) + (__builtin_popcountll(buf[i + 2]) + __builtin_popcountll(buf[i + 3]));
  }
  for (; i < n; ++i) {
    cnt += __builtin_popcountll(buf[i]);
  }
  return cnt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<popcnt_words0>:
  endbr64
  push   %r15
  mov    %esi,%eax
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  and    $0xfffffffc,%eax
  jle    L2
  sub    $0x1,%eax
  mov    %rdi,%r13
  xor    %r12d,%r12d
  shr    $0x2,%eax
  mov    %eax,0xc(%rsp)
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%r14
  nopl   (%rax)
L49:
  mov    0x0(%r13),%edi
  add    $0x10,%r13
  call   <__builtin_popcountll@plt>
  mov    -0xc(%r13),%edi
  mov    %rax,%rbp
  call   <__builtin_popcountll@plt>
  mov    -0x8(%r13),%edi
  add    %rax,%rbp
  call   <__builtin_popcountll@plt>
  mov    -0x4(%r13),%edi
  mov    %rax,%rbx
  call   <__builtin_popcountll@plt>
  add    %rax,%rbx
  add    %rbp,%rbx
  add    %ebx,%r12d
  cmp    %r14,%r13
  jne    L49
  mov    0xc(%rsp),%eax
  lea    0x4(,%rax,4),%eax
L10:
  mov    0x8(%rsp),%ecx
  cmp    %eax,%ecx
  jle    L0
  sub    $0x1,%ecx
  movslq %eax,%rdx
  mov    %ecx,%r13d
  lea    (%r15,%rdx,4),%rbx
  sub    %eax,%r13d
  add    %rdx,%r13
  lea    0x4(%r15,%r13,4),%rbp
  nopw   0x0(%rax,%rax,1)
L44:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <__builtin_popcountll@plt>
  add    %eax,%r12d
  cmp    %rbx,%rbp
  jne    L44
L0:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L2:
  xor    %eax,%eax
  xor    %r12d,%r12d
  jmp    L10
```

assistant: ```c
uint64_t popcnt_words0(uint64_t *buf, int64_t n) {
  uint64_t cnt = 0;
  uint64_t i;
  for (i = 0; i < (n & ~3); i += 4) {
    cnt += (__builtin_popcountll(buf[i + 0]) + __builtin_popcountll(buf[i + 1])) + (__builtin_popcountll(buf[i + 2]) + __builtin_popcountll(buf[i + 3]));
  }
  for (; i < n; ++i) {
    cnt += __builtin_popcountll(buf[i]);
  }
  return cnt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<close_pipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  nop
  leave
  ret
```

assistant: ```c
void close_pipe(int fd, fd_set *p_rset) {
  (void)close(fd);
  FD_ZERO(p_rset);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<close_pipe>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <close@plt>
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  pop    %rbx
  ret
```

assistant: ```c
void close_pipe(int fd, fd_set *p_rset) {
  (void)close(fd);
  FD_ZERO(p_rset);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<close_pipe>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <close@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <FD_ZERO@plt>
```

assistant: ```c
void close_pipe(int fd, fd_set *p_rset) {
  (void)close(fd);
  FD_ZERO(p_rset);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<close_pipe>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <close@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <FD_ZERO@plt>
```

assistant: ```c
void close_pipe(int fd, fd_set *p_rset) {
  (void)close(fd);
  FD_ZERO(p_rset);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<arquiteto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L48
L12:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  movslq %eax,%rdx
  imul   $0xffffffff80010003,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xe,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0xf,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,(%rsi)
  addl   $0x1,-0x4(%rbp)
L48:
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L12
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L31:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L21
  cmpl   $0x0,-0x4(%rbp)
  je     L21
  mov    $0xa,%edi
  call   <putchar@plt>
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L31
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D2: 
Sua matriz preenchida com numeros aleatorios eh a seguinte:


tool: D5: %5i	

assistant: ```c
void arquiteto(int m, int n, int *ponteiro) {
  int i;
  for (i = 0; i < m * n; i++)
    ponteiro[i] = rand() % 32767;
  printf("\nSua matriz preenchida com numeros aleatorios eh a seguinte:\n\n");
  for (i = 0; i < m * n; i++) {
    if (((i % n) == 0) && (i != 0)) {
      printf("\n");
    }
    printf("%5i\t", ponteiro[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<arquiteto>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  imul   %esi,%edi
  test   %edi,%edi
  jle    L54
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %edi,%r12d
  mov    %rdx,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rdx,%rax,4),%r14
L11:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff80010003,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xe,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0xf,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L11
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    %r12d,%r12d
  mov    $0x0,%ebx
  lea    D1(%rip),%r14
  jmp    L62
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
L44:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L1
L62:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L44
  test   %ebx,%ebx
  je     L44
  jmp    L7
L54:
  lea    D26(%rip),%rdi
  call   <puts@plt>
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D26
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string

tool: D26: 
Sua matriz preenchida com numeros aleatorios eh a seguinte:


tool: D1: %5i	

assistant: ```c
void arquiteto(int m, int n, int *ponteiro) {
  int i;
  for (i = 0; i < m * n; i++)
    ponteiro[i] = rand() % 32767;
  printf("\nSua matriz preenchida com numeros aleatorios eh a seguinte:\n\n");
  for (i = 0; i < m * n; i++) {
    if (((i % n) == 0) && (i != 0)) {
      printf("\n");
    }
    printf("%5i\t", ponteiro[i]);
  }
}
```