ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<textureRemoveAlphaChannel>:
  endbr64
  test   %rcx,%rcx
  je     L15
  mov    $0x0,%esi
  mov    $0x0,%eax
  jmp    L35
L2:
  cmp    %rcx,%rax
  je     L15
L35:
  add    $0x1,%rax
  test   $0x3,%al
  je     L2
  movzbl -0x1(%rdx,%rax,1),%r8d
  mov    %r8b,(%rdi,%rsi,1)
  add    $0x1,%rsi
  jmp    L2
L15:
  ret
```

assistant: ```c
void textureRemoveAlphaChannel(char *bufdest, unsigned long destsize, char *bufsrc, unsigned long srcsize) {
  unsigned long i = 0, j = 0;
  for (i = 0; i < srcsize; i++) {
    if ((i + 1) % 4 != 0) {
      bufdest[j] = bufsrc[i];
      ++j;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<textureRemoveAlphaChannel>:
  endbr64
  test   %rcx,%rcx
  je     L18
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   (%rax)
L8:
  add    $0x1,%rax
  test   $0x3,%al
  je     L27
  movzbl -0x1(%rdx,%rax,1),%r8d
  mov    %r8b,(%rdi,%rsi,1)
  add    $0x1,%rsi
L27:
  cmp    %rcx,%rax
  jne    L8
L18:
  ret
```

assistant: ```c
void textureRemoveAlphaChannel(char *bufdest, unsigned long destsize, char *bufsrc, unsigned long srcsize) {
  unsigned long i = 0, j = 0;
  for (i = 0; i < srcsize; i++) {
    if ((i + 1) % 4 != 0) {
      bufdest[j] = bufsrc[i];
      ++j;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<textureRemoveAlphaChannel>:
  endbr64
  test   %rcx,%rcx
  je     L6
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   (%rax)
L28:
  add    $0x1,%rax
  test   $0x3,%al
  je     L25
  movzbl -0x1(%rdx,%rax,1),%r8d
  mov    %r8b,(%rdi,%rsi,1)
  add    $0x1,%rsi
L25:
  cmp    %rcx,%rax
  jne    L28
L6:
  ret
```

assistant: ```c
void textureRemoveAlphaChannel(char *bufdest, unsigned long destsize, char *bufsrc, unsigned long srcsize) {
  unsigned long i = 0, j = 0;
  for (i = 0; i < srcsize; i++) {
    if ((i + 1) % 4 != 0) {
      bufdest[j] = bufsrc[i];
      ++j;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<preprocess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x4e24,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <haveDistinctDigit@plt>
  test   %rax,%rax
  je     L21
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
L21:
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x1388,-0x4(%rbp)
  jle    L5
  movl   $0x1,-0x4(%rbp)
  jmp    L39
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0x1388,-0x4(%rbp)
  jle    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void preprocess(int accumulateNumDistinctInt[]) {
  int n;
  memset(accumulateNumDistinctInt, 0, 5001 * sizeof(int));
  for (n = 0; n < 5001; n++)
    if (haveDistinctDigit(n))
      accumulateNumDistinctInt[n] = 1;
  for (n = 1; n < 5001; n++)
    accumulateNumDistinctInt[n] += accumulateNumDistinctInt[n - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<preprocess>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x4e24,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x0,%ebx
  jmp    L36
L43:
  add    $0x1,%rbx
  cmp    $0x1389,%rbx
  je     L19
L36:
  mov    %ebx,%edi
  call   <haveDistinctDigit@plt>
  test   %rax,%rax
  je     L43
  movl   $0x1,0x0(%rbp,%rbx,4)
  jmp    L43
L19:
  lea    0x4(%rbp),%rax
  lea    0x4e24(%rbp),%rcx
L37:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L37
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void preprocess(int accumulateNumDistinctInt[]) {
  int n;
  memset(accumulateNumDistinctInt, 0, 5001 * sizeof(int));
  for (n = 0; n < 5001; n++)
    if (haveDistinctDigit(n))
      accumulateNumDistinctInt[n] = 1;
  for (n = 1; n < 5001; n++)
    accumulateNumDistinctInt[n] += accumulateNumDistinctInt[n - 1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<preprocess>:
  endbr64
  push   %rbp
  mov    $0x4e24,%edx
  xor    %esi,%esi
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <memset@plt>
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %ebx,%edi
  call   <haveDistinctDigit@plt>
  test   %rax,%rax
  je     L14
  movl   $0x1,0x0(%rbp,%rbx,4)
L14:
  add    $0x1,%rbx
  cmp    $0x1389,%rbx
  jne    L27
  lea    0x4(%rbp),%rax
  lea    0x4e24(%rbp),%rcx
  nopl   0x0(%rax)
L2:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void preprocess(int accumulateNumDistinctInt[]) {
  int n;
  memset(accumulateNumDistinctInt, 0, 5001 * sizeof(int));
  for (n = 0; n < 5001; n++)
    if (haveDistinctDigit(n))
      accumulateNumDistinctInt[n] = 1;
  for (n = 1; n < 5001; n++)
    accumulateNumDistinctInt[n] += accumulateNumDistinctInt[n - 1];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<preprocess>:
  endbr64
  push   %rbp
  mov    $0x4e24,%edx
  xor    %esi,%esi
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <memset@plt>
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%edi
  call   <haveDistinctDigit@plt>
  test   %rax,%rax
  je     L28
  movl   $0x1,0x0(%rbp,%rbx,4)
L28:
  add    $0x1,%rbx
  cmp    $0x1389,%rbx
  jne    L11
  mov    0x0(%rbp),%edx
  lea    0x4(%rbp),%rax
  lea    0x4e24(%rbp),%rcx
  nop
L6:
  add    (%rax),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void preprocess(int accumulateNumDistinctInt[]) {
  int n;
  memset(accumulateNumDistinctInt, 0, 5001 * sizeof(int));
  for (n = 0; n < 5001; n++)
    if (haveDistinctDigit(n))
      accumulateNumDistinctInt[n] = 1;
  for (n = 1; n < 5001; n++)
    accumulateNumDistinctInt[n] += accumulateNumDistinctInt[n - 1];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: %ld


assistant: ```c
int main() {
  struct timeval tp;
  gettimeofday(&tp, NULL);
  printf("%ld\n", tp.tv_sec);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string

tool: D4: %ld


assistant: ```c
int main() {
  struct timeval tp;
  gettimeofday(&tp, NULL);
  printf("%ld\n", tp.tv_sec);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: %ld


assistant: ```c
int main() {
  struct timeval tp;
  gettimeofday(&tp, NULL);
  printf("%ld\n", tp.tv_sec);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D3: %ld


assistant: ```c
int main() {
  struct timeval tp;
  gettimeofday(&tp, NULL);
  printf("%ld\n", tp.tv_sec);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L45
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
L45:
  mov    $0x0,%eax
  jmp    L46
L16:
  movq   $0x0,-0x8(%rbp)
  jmp    L14
L51:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L51
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  je     L50
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L50:
  mov    -0x18(%rbp),%rax
L46:
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strncpy(char *s1, char const *s2, unsigned long n) {
  unsigned long i;
  if (s2 == NULL || s1 == NULL)
    return (NULL);
  i = 0x00;
  while (i < n) {
    s1[i] = s2[i];
    i++;
  }
  if (i != n)
    s1[i] = 0x00;
  return (s1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L16
  test   %rdi,%rdi
  je     L16
  test   %rdx,%rdx
  je     L4
  mov    $0x0,%ecx
L22:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L22
  ret
L16:
  mov    $0x0,%eax
L4:
  ret
```

assistant: ```c
char *ft_strncpy(char *s1, char const *s2, unsigned long n) {
  unsigned long i;
  if (s2 == NULL || s1 == NULL)
    return (NULL);
  i = 0x00;
  while (i < n) {
    s1[i] = s2[i];
    i++;
  }
  if (i != n)
    s1[i] = 0x00;
  return (s1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strncpy>:
  endbr64
  test   %rsi,%rsi
  je     L4
  test   %rdi,%rdi
  je     L4
  xor    %ecx,%ecx
  test   %rdx,%rdx
  je     L34
  nopl   (%rax)
L21:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rdi,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L21
L34:
  mov    %rdi,%rax
  ret
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ft_strncpy(char *s1, char const *s2, unsigned long n) {
  unsigned long i;
  if (s2 == NULL || s1 == NULL)
    return (NULL);
  i = 0x00;
  while (i < n) {
    s1[i] = s2[i];
    i++;
  }
  if (i != n)
    s1[i] = 0x00;
  return (s1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strncpy>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%rax
  mov    %rdx,%rsi
  test   %rcx,%rcx
  je     L27
  test   %rdi,%rdi
  je     L27
  test   %rdx,%rdx
  je     L166
  lea    0x1(%rcx),%r8
  lea    -0x1(%rdx),%rdx
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L62
  cmp    $0x6,%rdx
  jbe    L62
  mov    %rsi,%rdi
  cmp    $0xe,%rdx
  jbe    L147
  and    $0xfffffffffffffff0,%rdi
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L15:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rdi
  jne    L15
  mov    %rsi,%rdx
  and    $0xfffffffffffffff0,%rdx
  test   $0xf,%sil
  je     L166
  mov    %rsi,%rdi
  sub    %rdx,%rdi
  lea    -0x1(%rdi),%r8
  cmp    $0x6,%r8
  jbe    L41
L145:
  mov    (%rcx,%rdx,1),%r8
  mov    %r8,(%rax,%rdx,1)
  mov    %rdi,%r8
  and    $0xfffffffffffffff8,%r8
  add    %r8,%rdx
  cmp    %r8,%rdi
  je     L166
L41:
  movzbl (%rcx,%rdx,1),%edi
  mov    %dil,(%rax,%rdx,1)
  lea    0x1(%rdx),%rdi
  cmp    %rdi,%rsi
  jbe    L166
  movzbl 0x1(%rcx,%rdx,1),%edi
  mov    %dil,0x1(%rax,%rdx,1)
  lea    0x2(%rdx),%rdi
  cmp    %rdi,%rsi
  jbe    L166
  movzbl 0x2(%rcx,%rdx,1),%edi
  mov    %dil,0x2(%rax,%rdx,1)
  lea    0x3(%rdx),%rdi
  cmp    %rdi,%rsi
  jbe    L166
  movzbl 0x3(%rcx,%rdx,1),%edi
  mov    %dil,0x3(%rax,%rdx,1)
  lea    0x4(%rdx),%rdi
  cmp    %rdi,%rsi
  jbe    L166
  movzbl 0x4(%rcx,%rdx,1),%edi
  mov    %dil,0x4(%rax,%rdx,1)
  lea    0x5(%rdx),%rdi
  cmp    %rdi,%rsi
  jbe    L166
  movzbl 0x5(%rcx,%rdx,1),%edi
  mov    %dil,0x5(%rax,%rdx,1)
  lea    0x6(%rdx),%rdi
  cmp    %rdi,%rsi
  jbe    L166
  movzbl 0x6(%rcx,%rdx,1),%ecx
  mov    %cl,0x6(%rax,%rdx,1)
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
L166:
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L122:
  movzbl (%rcx,%rdx,1),%edi
  mov    %dil,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L122
  ret
L147:
  xor    %edx,%edx
  jmp    L145
```

assistant: ```c
char *ft_strncpy(char *s1, char const *s2, unsigned long n) {
  unsigned long i;
  if (s2 == NULL || s1 == NULL)
    return (NULL);
  i = 0x00;
  while (i < n) {
    s1[i] = s2[i];
    i++;
  }
  if (i != n)
    s1[i] = 0x00;
  return (s1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<emalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <eprintf@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: Can not allocate %zu bytes.


assistant: ```c
void *emalloc(size_t size) {
  void *ptr;
  if (!(ptr = malloc(size)))
    eprintf("Can not allocate %zu bytes.\n", size);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<emalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <eprintf@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D5: Can not allocate %zu bytes.


assistant: ```c
void *emalloc(size_t size) {
  void *ptr;
  if (!(ptr = malloc(size)))
    eprintf("Can not allocate %zu bytes.\n", size);
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<emalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <eprintf@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: Can not allocate %zu bytes.


assistant: ```c
void *emalloc(size_t size) {
  void *ptr;
  if (!(ptr = malloc(size)))
    eprintf("Can not allocate %zu bytes.\n", size);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<emalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <eprintf@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: Can not allocate %zu bytes.


assistant: ```c
void *emalloc(size_t size) {
  void *ptr;
  if (!(ptr = malloc(size)))
    eprintf("Can not allocate %zu bytes.\n", size);
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<LowestBitSet8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    $0xffffffff,%eax
  jmp    L16
L4:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <CountBits8@plt>
  sub    $0x1,%eax
L16:
  leave
  ret
```

assistant: ```c
int LowestBitSet8(uint8_t val) {
  if (val == 0)
    return -1;
  return CountBits8(val ^ val - 1) - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LowestBitSet8>:
  endbr64
  test   %edi,%edi
  je     L7
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%eax
  xor    %eax,%edi
  call   <CountBits8@plt>
  sub    $0x1,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int LowestBitSet8(uint8_t val) {
  if (val == 0)
    return -1;
  return CountBits8(val ^ val - 1) - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<LowestBitSet8>:
  endbr64
  test   %edi,%edi
  je     L0
  lea    -0x1(%rdi),%eax
  sub    $0x8,%rsp
  xor    %eax,%edi
  call   <CountBits8@plt>
  add    $0x8,%rsp
  sub    $0x1,%eax
  ret
  xchg   %ax,%ax
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int LowestBitSet8(uint8_t val) {
  if (val == 0)
    return -1;
  return CountBits8(val ^ val - 1) - 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LowestBitSet8>:
  endbr64
  test   %edi,%edi
  je     L5
  lea    -0x1(%rdi),%eax
  sub    $0x8,%rsp
  xor    %eax,%edi
  call   <CountBits8@plt>
  add    $0x8,%rsp
  sub    $0x1,%eax
  ret
  xchg   %ax,%ax
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int LowestBitSet8(uint8_t val) {
  if (val == 0)
    return -1;
  return CountBits8(val ^ val - 1) - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getDatagramSectionHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  and    $0xf00,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0xc,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getDatagramSectionHeader(unsigned int *slen, unsigned int *len, unsigned int offset, unsigned char *buf) {
  *slen = ((buf[offset + 1] & 0xF) << 8) | (buf[offset + 2]);
  *len = 12;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getDatagramSectionHeader>:
  endbr64
  lea    0x1(%rdx),%eax
  movzbl (%rcx,%rax,1),%eax
  shl    $0x8,%eax
  and    $0xf00,%eax
  lea    0x2(%rdx),%edx
  movzbl (%rcx,%rdx,1),%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  movl   $0xc,(%rsi)
  ret
```

assistant: ```c
void getDatagramSectionHeader(unsigned int *slen, unsigned int *len, unsigned int offset, unsigned char *buf) {
  *slen = ((buf[offset + 1] & 0xF) << 8) | (buf[offset + 2]);
  *len = 12;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getDatagramSectionHeader>:
  endbr64
  lea    0x1(%rdx),%eax
  add    $0x2,%edx
  movzbl (%rcx,%rax,1),%eax
  movzbl (%rcx,%rdx,1),%edx
  shl    $0x8,%eax
  and    $0xf00,%eax
  or     %edx,%eax
  mov    %eax,(%rdi)
  movl   $0xc,(%rsi)
  ret
```

assistant: ```c
void getDatagramSectionHeader(unsigned int *slen, unsigned int *len, unsigned int offset, unsigned char *buf) {
  *slen = ((buf[offset + 1] & 0xF) << 8) | (buf[offset + 2]);
  *len = 12;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getDatagramSectionHeader>:
  endbr64
  lea    0x1(%rdx),%eax
  add    $0x2,%edx
  movzbl (%rcx,%rax,1),%eax
  movzbl (%rcx,%rdx,1),%edx
  shl    $0x8,%eax
  and    $0xf00,%eax
  or     %edx,%eax
  mov    %eax,(%rdi)
  movl   $0xc,(%rsi)
  ret
```

assistant: ```c
void getDatagramSectionHeader(unsigned int *slen, unsigned int *len, unsigned int offset, unsigned char *buf) {
  *slen = ((buf[offset + 1] & 0xF) << 8) | (buf[offset + 2]);
  *len = 12;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<egSin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  movsd  D37(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  sar    $0xf,%ax
  shr    $0xf,%ax
  mov    %eax,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %ax,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  sar    $0xf,%ax
  shr    $0xf,%ax
  mov    %eax,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %ax,-0x2(%rbp)
  cmpw   $0x0,-0x4(%rbp)
  jne    L33
  movsd  D31(%rip),%xmm0
  mov    -0x14(%rbp),%eax
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <fmodf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  jmp    L11
L33:
  movsd  D31(%rip),%xmm0
  mov    -0x14(%rbp),%eax
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <fmodf@plt>
  mov    $0x1,%edx
  sub    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
L11:
  movss  %xmm0,-0x14(%rbp)
  cmpw   $0x0,-0x2(%rbp)
  je     L27
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <egSinZH@plt>
  movd   %xmm0,%eax
  movss  D10(%rip),%xmm0
  movd   %eax,%xmm2
  xorps  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  jmp    L2
L27:
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <egSinZH@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D37
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D18
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D31
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: byte[4]

tool: D37: 0.6366197723675814

tool: D18: 0.3183098861837907

tool: {"D31": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D10": [0x00,0x00,0x00,0x80]}

assistant: ```c
float egSin(float a) {
  short even = (short)(a * 0.63661977236758134307553505349006) % 2, negate = (short)(a * 0.31830988618379067153776752674503) % 2;
  a = (even == 0) ? fmodf(a, 3.14159265358979323846 * 0.5) : 1 - fmodf(a, 3.14159265358979323846 * 0.5);
  return (negate) ? egSinZH(a) * -1 : egSinZH(a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<egSin>:
  endbr64
  push   %rbx
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movapd %xmm1,%xmm2
  mulsd  D3(%rip),%xmm2
  cvttsd2si %xmm2,%ebx
  mulsd  D49(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  test   $0x1,%al
  jne    L0
  movsd  D1(%rip),%xmm1
  call   <fmodf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
L33:
  test   $0x1,%bl
  je     L14
  call   <egSinZH@plt>
  xorps  D27(%rip),%xmm0
L37:
  pop    %rbx
  ret
L0:
  movsd  D1(%rip),%xmm1
  call   <fmodf@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  jmp    L33
L14:
  call   <egSinZH@plt>
  jmp    L37
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: f64
name: parse_data
arguments: data_tag: D49
type: f64
name: parse_data
arguments: data_tag: D1
type: byte[8]
name: parse_data
arguments: data_tag: D27
type: byte[16]

tool: D3: 0.3183098861837907

tool: D49: 0.6366197723675814

tool: {"D1": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D27": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float egSin(float a) {
  short even = (short)(a * 0.63661977236758134307553505349006) % 2, negate = (short)(a * 0.31830988618379067153776752674503) % 2;
  a = (even == 0) ? fmodf(a, 3.14159265358979323846 * 0.5) : 1 - fmodf(a, 3.14159265358979323846 * 0.5);
  return (negate) ? egSinZH(a) * -1 : egSinZH(a);
}
```