user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x34(%rbp)
  jg     L106
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L53
L106:
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x1c(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%edi
  call   <perror@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L75
L87:
  movl   $0x0,-0x2c(%rbp)
  jmp    L33
L93:
  movl   $0x0,-0x28(%rbp)
  jmp    L76
L26:
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x2c(%rbp)
  je     L80
  cmpl   $0x0,-0x2c(%rbp)
  jne    L103
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x28(%rbp)
  jne    L103
L80:
  movsd  D35(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L95
L103:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L95:
  mov    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  addl   $0x1,-0x28(%rbp)
L76:
  mov    -0x28(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L26
  addl   $0x1,-0x2c(%rbp)
L33:
  mov    -0x2c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L93
  addl   $0x1,-0x24(%rbp)
L75:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L87
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D36
data_type: string
name: read_data
arguments: data_label: D24
data_type: string
name: read_data
arguments: data_label: D54
data_type: string
name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D67
data_type: string
name: read_data
arguments: data_label: D35
data_type: byte[8]

tool: D36: 

This program generates the weights for the neural network.

tool: D24: You must specify the number of inputs and the number of layers.


tool: D54: %s number_of_inputs number_of_layers



tool: D5: For example: %s 10 3



tool: D0: wb

tool: D67: weights.dat

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int main(int argc, char **argv) {
  int i, j, l;
  int num_inputs, num_layers;
  double buf;
  FILE *f;
  if (argc < 3) {
    printf("\n\nThis program generates the weights for the neural network.\n");
    printf("You must specify the number of inputs and the number of layers.\n\n");
    printf("%s number_of_inputs number_of_layers\n\n");
    printf("For example: %s 10 3\n\n", argv[0]);
    return 0;
  }
  num_inputs = atoi(argv[1]);
  num_layers = atoi(argv[2]);
  f = fopen("weights.dat", "wb");
  perror(NULL);
  for (l = 0; l < num_layers; l++)
    for (i = 0; i < num_inputs; i++)
      for (j = 0; j < num_inputs; j++) {
        if (i == j + 1 || i == 0 && j == num_inputs - 1)
          buf = 1;
        else
          buf = 0;
        fwrite(&buf, sizeof(double), 1, f);
      }
  fclose(f);
  return 0;
}
```