ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<make_daemon>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L36
  jne    L5
L45:
  xor    %edi,%edi
  call   <umask@plt>
  xor    %eax,%eax
  call   <setsid@plt>
  test   %rax,%rax
  js     L21
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L5:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L45
  nopl   (%rax)
L36:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L45
L21:
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    10c0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D12: Started daemon.

tool: D1: Error: can not fork

assistant: ```c
void make_daemon(void) {
  pid_t pid;
  pid_t sid;
  pid = fork();
  if (pid < 0) {
    printf("Error: can not fork");
    exit(-1);
  } else if (pid > 0) {
    printf("Started daemon.");
    exit(0);
  }
  umask(0);
  sid = setsid();
  if (sid < 0) {
    exit(-1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<make_daemon>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L23
  jne    L24
L16:
  xor    %edi,%edi
  call   <umask@plt>
  xor    %eax,%eax
  call   <setsid@plt>
  test   %rax,%rax
  js     L6
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L24:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L16
  nopl   (%rax)
L23:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L16
L6:
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    10c0 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string

tool: D12: Started daemon.

tool: D3: Error: can not fork

assistant: ```c
void make_daemon(void) {
  pid_t pid;
  pid_t sid;
  pid = fork();
  if (pid < 0) {
    printf("Error: can not fork");
    exit(-1);
  } else if (pid > 0) {
    printf("Started daemon.");
    exit(0);
  }
  umask(0);
  sid = setsid();
  if (sid < 0) {
    exit(-1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<svtParseInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <svtParseLong@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int svtParseInt(const char *str, int *val) {
  long l;
  int ret;
  ret = svtParseLong(str, &l);
  *val = (int)l;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<svtParseInt>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <svtParseLong@plt>
  mov    (%rsp),%rdx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int svtParseInt(const char *str, int *val) {
  long l;
  int ret;
  ret = svtParseLong(str, &l);
  *val = (int)l;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<svtParseInt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <svtParseLong@plt>
  mov    (%rsp),%rdx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int svtParseInt(const char *str, int *val) {
  long l;
  int ret;
  ret = svtParseLong(str, &l);
  *val = (int)l;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<svtParseInt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <svtParseLong@plt>
  mov    (%rsp),%rdx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int svtParseInt(const char *str, int *val) {
  long l;
  int ret;
  ret = svtParseLong(str, &l);
  *val = (int)l;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L79
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L65
L52:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L45
  addl   $0x1,-0x14(%rbp)
L45:
  addl   $0x1,-0x10(%rbp)
L65:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L52
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x65,%al
  jne    L39
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L97
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  jmp    L74
L97:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x31,(%rax)
  jmp    L74
L39:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L22
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x31,(%rax)
  jmp    L74
L22:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
L74:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L79:
  nop
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D23
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D20
type_guessed: string

tool: D23: %s

tool: D0: #

tool: D20: %s


assistant: ```c
int main() {
  char *input;
  while (1) {
    scanf("%s", input);
    if (strcmp(input, "#") == 0)
      break;
    int input_len = strlen(input);
    int ones = 0;
    for (int i = 0; i < input_len - 1; ++i) {
      if (input[i] == '1')
        ones++;
    }
    if (input[input_len - 1] == 'e') {
      if (ones % 2 == 0)
        input[input_len - 1] = '0';
      else
        input[input_len - 1] = '1';
    } else {
      if (ones % 2 == 0)
        input[input_len - 1] = '1';
      else
        input[input_len - 1] = '0';
    }
    printf("%s\n", input);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbp
  lea    D5(%rip),%rbx
  mov    $0x1,%r13d
  lea    D10(%rip),%r12
  jmp    L2
L18:
  test   $0x1,%cl
  je     L21
  movb   $0x31,(%rax)
  jmp    L86
L21:
  movb   $0x30,(%rax)
  jmp    L86
L15:
  cltq
  lea    -0x1(%rax),%rax
  cmpb   $0x65,(%rax)
  je     L21
L36:
  movb   $0x31,(%rax)
L86:
  mov    $0x0,%r14d
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%r14d
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L64
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L15
  mov    $0x0,%edx
  lea    -0x2(%rax),%edi
  add    %r13,%rdi
  mov    $0x0,%ecx
L30:
  cmpb   $0x31,(%rdx)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ecx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L30
  cltq
  lea    -0x1(%rax),%rax
  cmpb   $0x65,(%rax)
  je     L18
  test   $0x1,%cl
  je     L36
  movb   $0x30,(%rax)
  jmp    L86
L64:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string

tool: D6: %s

tool: D5: #

tool: D10: %s


assistant: ```c
int main() {
  char *input;
  while (1) {
    scanf("%s", input);
    if (strcmp(input, "#") == 0)
      break;
    int input_len = strlen(input);
    int ones = 0;
    for (int i = 0; i < input_len - 1; ++i) {
      if (input[i] == '1')
        ones++;
    }
    if (input[input_len - 1] == 'e') {
      if (ones % 2 == 0)
        input[input_len - 1] = '0';
      else
        input[input_len - 1] = '1';
    } else {
      if (ones % 2 == 0)
        input[input_len - 1] = '1';
      else
        input[input_len - 1] = '0';
    }
    printf("%s\n", input);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  lea    D28(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %r13d,%r13d
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L61
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L59
  lea    -0x2(%rax),%edi
  xor    %edx,%edx
  xor    %ecx,%ecx
  add    $0x1,%rdi
  xchg   %ax,%ax
L34:
  xor    %esi,%esi
  cmpb   $0x31,(%rdx)
  sete   %sil
  add    $0x1,%rdx
  add    %esi,%ecx
  cmp    %rdi,%rdx
  jne    L34
  cltq
  sub    $0x1,%rax
  cmpb   $0x65,(%rax)
  je     L5
  and    $0x1,%ecx
  je     L94
L40:
  movb   $0x30,(%rax)
L97:
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L5:
  and    $0x1,%ecx
  je     L40
L94:
  movb   $0x31,(%rax)
  jmp    L97
  nopw   0x0(%rax,%rax,1)
L61:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L59:
  cltq
  sub    $0x1,%rax
  cmpb   $0x65,(%rax)
  jne    L94
  jmp    L40
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string
name: extract_symbolic_data
arguments: data_tag: D28
data_type: string

tool: D21: %s


tool: D1: %s

tool: D28: #

assistant: ```c
int main() {
  char *input;
  while (1) {
    scanf("%s", input);
    if (strcmp(input, "#") == 0)
      break;
    int input_len = strlen(input);
    int ones = 0;
    for (int i = 0; i < input_len - 1; ++i) {
      if (input[i] == '1')
        ones++;
    }
    if (input[input_len - 1] == 'e') {
      if (ones % 2 == 0)
        input[input_len - 1] = '0';
      else
        input[input_len - 1] = '1';
    } else {
      if (ones % 2 == 0)
        input[input_len - 1] = '1';
      else
        input[input_len - 1] = '0';
    }
    printf("%s\n", input);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dump_epoll_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L36
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x1c(%rbp),%eax
  jmp    L18
L36:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L15
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <dump_unsigned_int_from_mem@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <dump_long_long_unsigned_int_from_mem@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L15:
  lea    -0x1c(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <copy_params@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <free_dumped_params@plt>
  mov    -0x1c(%rbp),%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int dump_epoll_event(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_events = addr;
  unsigned int arm_tracing_data = addr + 8;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(2 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_unsigned_int_from_mem(arm_tracing_events, &dumped_type_params[0], target);
    len += dump_long_long_unsigned_int_from_mem(arm_tracing_data, &dumped_type_params[1], target);
  }
  *dumped_params = copy_params(dumped_type_params, 2, &len);
  free_dumped_params(dumped_type_params, 2);
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_epoll_event>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L27
  mov    %esi,%ebx
  mov    %rcx,%r12
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rdx
  mov    %rax,%rsi
  mov    %ebx,%edi
  call   <dump_unsigned_int_from_mem@plt>
  add    %eax,0x4(%rsp)
  lea    0x8(%rbp),%rsi
  lea    0x8(%rbx),%edi
  mov    %r12,%rdx
  call   <dump_long_long_unsigned_int_from_mem@plt>
  add    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <copy_params@plt>
  mov    %rax,0x0(%r13)
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L4
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_epoll_event(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_events = addr;
  unsigned int arm_tracing_data = addr + 8;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(2 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_unsigned_int_from_mem(arm_tracing_events, &dumped_type_params[0], target);
    len += dump_long_long_unsigned_int_from_mem(arm_tracing_data, &dumped_type_params[1], target);
  }
  *dumped_params = copy_params(dumped_type_params, 2, &len);
  free_dumped_params(dumped_type_params, 2);
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dump_epoll_event>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L19
  mov    $0x10,%edi
  mov    %rcx,%r12
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %ebx,%edi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <dump_unsigned_int_from_mem@plt>
  lea    0x8(%rbp),%rsi
  lea    0x8(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_long_long_unsigned_int_from_mem@plt>
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %eax,0x4(%rsp)
  mov    $0x2,%esi
  call   <copy_params@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L19:
  xor    %edi,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L25
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_epoll_event(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_events = addr;
  unsigned int arm_tracing_data = addr + 8;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(2 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_unsigned_int_from_mem(arm_tracing_events, &dumped_type_params[0], target);
    len += dump_long_long_unsigned_int_from_mem(arm_tracing_data, &dumped_type_params[1], target);
  }
  *dumped_params = copy_params(dumped_type_params, 2, &len);
  free_dumped_params(dumped_type_params, 2);
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dump_epoll_event>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L25
  mov    $0x10,%edi
  mov    %rcx,%r12
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %ebx,%edi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <dump_unsigned_int_from_mem@plt>
  lea    0x8(%rbp),%rsi
  lea    0x8(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_long_long_unsigned_int_from_mem@plt>
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %eax,0x4(%rsp)
  mov    $0x2,%esi
  call   <copy_params@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L25:
  xor    %edi,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L10
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_epoll_event(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_events = addr;
  unsigned int arm_tracing_data = addr + 8;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(2 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_unsigned_int_from_mem(arm_tracing_events, &dumped_type_params[0], target);
    len += dump_long_long_unsigned_int_from_mem(arm_tracing_data, &dumped_type_params[1], target);
  }
  *dumped_params = copy_params(dumped_type_params, 2, &len);
  free_dumped_params(dumped_type_params, 2);
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<yrotatemat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  movss  %xmm0,-0x5c(%rbp)
  movss  %xmm1,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x60(%rbp),%xmm0
  movss  %xmm0,-0x50(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4c(%rbp)
  movss  -0x5c(%rbp),%xmm0
  movss  D6(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x48(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x44(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x40(%rbp)
  movss  D7(%rip),%xmm0
  movss  %xmm0,-0x3c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x34(%rbp)
  movss  -0x5c(%rbp),%xmm0
  movss  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movss  -0x60(%rbp),%xmm0
  movss  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  D7(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x58(%rbp),%rdx
  mov    -0x58(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matrixmult@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: byte[4]
name: parse_data
arguments: data_label: D7
type_guessed: f32

tool: {"D6": [0x00,0x00,0x00,0x80]}

tool: D7: 1

assistant: ```c
void yrotatemat(float mat[4][4], float rs, float rc) {
  float mmat[4][4];
  mmat[0][0] = rc;
  mmat[0][1] = 0.0;
  mmat[0][2] = -rs;
  mmat[0][3] = 0.0;
  mmat[1][0] = 0.0;
  mmat[1][1] = 1.0;
  mmat[1][2] = 0.0;
  mmat[1][3] = 0.0;
  mmat[2][0] = rs;
  mmat[2][1] = 0.0;
  mmat[2][2] = rc;
  mmat[2][3] = 0.0;
  mmat[3][0] = 0.0;
  mmat[3][1] = 0.0;
  mmat[3][2] = 0.0;
  mmat[3][3] = 1.0;
  matrixmult(mmat, mat, mat);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<yrotatemat>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movss  %xmm1,(%rsp)
  movl   $0x0,0x4(%rsp)
  movaps %xmm0,%xmm2
  xorps  D9(%rip),%xmm2
  movss  %xmm2,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movss  D5(%rip),%xmm2
  movss  %xmm2,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movss  %xmm0,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movss  %xmm1,0x28(%rsp)
  movl   $0x0,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x34(%rsp)
  movl   $0x0,0x38(%rsp)
  movss  %xmm2,0x3c(%rsp)
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  call   <matrixmult@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x58,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
type_infered: byte[16]
name: read_data
arguments: label: D5
type_infered: f32

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D5: 1

assistant: ```c
void yrotatemat(float mat[4][4], float rs, float rc) {
  float mmat[4][4];
  mmat[0][0] = rc;
  mmat[0][1] = 0.0;
  mmat[0][2] = -rs;
  mmat[0][3] = 0.0;
  mmat[1][0] = 0.0;
  mmat[1][1] = 1.0;
  mmat[1][2] = 0.0;
  mmat[1][3] = 0.0;
  mmat[2][0] = rs;
  mmat[2][1] = 0.0;
  mmat[2][2] = rc;
  mmat[2][3] = 0.0;
  mmat[3][0] = 0.0;
  mmat[3][1] = 0.0;
  mmat[3][2] = 0.0;
  mmat[3][3] = 1.0;
  matrixmult(mmat, mat, mat);
}
```