ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<multiply_pointer_array_by>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  imul   -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *multiply_pointer_array_by(int *array, int array_size, int multiplier) {
  for (int i = 0; i < array_size; i++) {
    array[i] *= multiplier;
  }
  return array;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<multiply_pointer_array_by>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L8
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%esi
  lea    0x4(%rdi,%rsi,4),%r8
L18:
  mov    %edx,%esi
  imul   (%rcx),%esi
  mov    %esi,(%rcx)
  add    $0x4,%rcx
  cmp    %r8,%rcx
  jne    L18
L8:
  ret
```

assistant: ```c
int *multiply_pointer_array_by(int *array, int array_size, int multiplier) {
  for (int i = 0; i < array_size; i++) {
    array[i] *= multiplier;
  }
  return array;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<multiply_pointer_array_by>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L14
  sub    $0x1,%esi
  mov    %rdi,%rcx
  lea    0x4(%rdi,%rsi,4),%r8
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    (%rcx),%esi
  add    $0x4,%rcx
  imul   %edx,%esi
  mov    %esi,-0x4(%rcx)
  cmp    %r8,%rcx
  jne    L18
L14:
  ret
```

assistant: ```c
int *multiply_pointer_array_by(int *array, int array_size, int multiplier) {
  for (int i = 0; i < array_size; i++) {
    array[i] *= multiplier;
  }
  return array;
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply_pointer_array_by>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L65
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L2
  movd   %edx,%xmm4
  shr    $0x2,%esi
  mov    %rdi,%rax
  pshufd $0x0,%xmm4,%xmm2
  sub    $0x1,%esi
  shl    $0x4,%rsi
  movdqa %xmm2,%xmm3
  lea    0x10(%rdi,%rsi,1),%rsi
  psrlq  $0x20,%xmm3
  nopl   0x0(%rax)
L46:
  movdqu (%rax),%xmm0
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L46
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%cl
  je     L65
L41:
  movslq %eax,%rsi
  shl    $0x2,%rsi
  lea    (%r8,%rsi,1),%rdi
  mov    (%rdi),%r9d
  imul   %edx,%r9d
  mov    %r9d,(%rdi)
  lea    0x1(%rax),%edi
  cmp    %edi,%ecx
  jle    L65
  lea    0x4(%r8,%rsi,1),%rdi
  add    $0x2,%eax
  mov    (%rdi),%r9d
  imul   %edx,%r9d
  mov    %r9d,(%rdi)
  cmp    %eax,%ecx
  jle    L65
  lea    0x8(%r8,%rsi,1),%rax
  imul   (%rax),%edx
  mov    %edx,(%rax)
L65:
  mov    %r8,%rax
  ret
L2:
  xor    %eax,%eax
  jmp    L41
```

assistant: ```c
int *multiply_pointer_array_by(int *array, int array_size, int multiplier) {
  for (int i = 0; i < array_size; i++) {
    array[i] *= multiplier;
  }
  return array;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<file_filter>:
  endbr64
  mov    (%rdi),%rax
  cmpb   $0x2e,(%rax)
  jne    L2
  cmpb   $0x2e,0x1(%rax)
  je     L0
L2:
  xor    %r8d,%r8d
  cmpb   $0x2e,(%rax)
  je     L46
  mov    D12(%rip),%rdx
  mov    0x8(%rdi),%rax
  mov    $0x1,%r8d
  cmp    (%rdx),%rax
  je     L46
  mov    D11(%rip),%rdx
  xor    %r8d,%r8d
  cmp    %rax,(%rdx)
  sete   %r8b
L46:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L0:
  movzbl 0x2(%rax),%r8d
  test   %r8d,%r8d
  jne    L2
  mov    %r8d,%eax
  ret
```

assistant: ```c
int file_filter(const struct dirent *entry) {
  if (!strcmp(entry->d_name, ".."))
    return 0;
  if (entry->d_name[0] == '.')
    return 0;
  if (entry->d_type == DT_DIR)
    return 1;
  if (entry->d_type == DT_REG)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<file_filter>:
  endbr64
  mov    (%rdi),%rax
  cmpb   $0x2e,(%rax)
  jne    L22
  cmpb   $0x2e,0x1(%rax)
  je     L25
L22:
  xor    %r8d,%r8d
  cmpb   $0x2e,(%rax)
  je     L36
  mov    D12(%rip),%rdx
  mov    0x8(%rdi),%rax
  mov    $0x1,%r8d
  cmp    (%rdx),%rax
  je     L36
  mov    D8(%rip),%rdx
  xor    %r8d,%r8d
  cmp    %rax,(%rdx)
  sete   %r8b
L36:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L25:
  movzbl 0x2(%rax),%r8d
  test   %r8d,%r8d
  jne    L22
  mov    %r8d,%eax
  ret
```

assistant: ```c
int file_filter(const struct dirent *entry) {
  if (!strcmp(entry->d_name, ".."))
    return 0;
  if (entry->d_name[0] == '.')
    return 0;
  if (entry->d_type == DT_DIR)
    return 1;
  if (entry->d_type == DT_REG)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L5
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <sleep@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void do_sleep(argc, argv) char **argv;
{
  if (argc > 1)
    sleep(atoi(argv[1]));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_sleep>:
  endbr64
  cmp    $0x1,%edi
  jg     L9
  ret
L9:
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <sleep@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void do_sleep(argc, argv) char **argv;
{
  if (argc > 1)
    sleep(atoi(argv[1]));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_sleep>:
  endbr64
  cmp    $0x1,%edi
  jg     L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  xor    %eax,%eax
  call   <atoi@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  xor    %eax,%eax
  jmp    1070 <sleep@plt>
```

assistant: ```c
void do_sleep(argc, argv) char **argv;
{
  if (argc > 1)
    sleep(atoi(argv[1]));
}
```
user: What is the c source code of the assembly code below?

```asm
<do_sleep>:
  endbr64
  cmp    $0x1,%edi
  jg     L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  xor    %eax,%eax
  call   <atoi@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  xor    %eax,%eax
  jmp    1070 <sleep@plt>
```

assistant: ```c
void do_sleep(argc, argv) char **argv;
{
  if (argc > 1)
    sleep(atoi(argv[1]));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmpxchg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    (%rdx),%rax
  mov    -0x28(%rbp),%rsi
  lock cmpxchg %rsi,(%rcx)
  sete   %cl
  test   %cl,%cl
  jne    L14
  mov    %rax,(%rdx)
L14:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
unsigned long cmpxchg(unsigned long *p, unsigned long expected, unsigned long desired) {
  unsigned long exp = expected;
  __atomic_compare_exchange_n(p, &exp, desired, 0, 5, 5);
  return exp;
}
```
user: What is the c source code of the assembly code below?

```asm
<cmpxchg>:
  endbr64
  mov    %rsi,%rax
  lock cmpxchg %rdx,(%rdi)
  ret
```

assistant: ```c
unsigned long cmpxchg(unsigned long *p, unsigned long expected, unsigned long desired) {
  unsigned long exp = expected;
  __atomic_compare_exchange_n(p, &exp, desired, 0, 5, 5);
  return exp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmpxchg>:
  endbr64
  mov    %rsi,%rax
  lock cmpxchg %rdx,(%rdi)
  ret
```

assistant: ```c
unsigned long cmpxchg(unsigned long *p, unsigned long expected, unsigned long desired) {
  unsigned long exp = expected;
  __atomic_compare_exchange_n(p, &exp, desired, 0, 5, 5);
  return exp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmpxchg>:
  endbr64
  mov    %rsi,%rax
  lock cmpxchg %rdx,(%rdi)
  ret
```

assistant: ```c
unsigned long cmpxchg(unsigned long *p, unsigned long expected, unsigned long desired) {
  unsigned long exp = expected;
  __atomic_compare_exchange_n(p, &exp, desired, 0, 5, 5);
  return exp;
}
```
user: What is the c source code of the assembly code below?

```asm
<cleanup_sctp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sn_reopen_asoc_streams@plt>
  nop
  leave
  ret
```

assistant: ```c
void *cleanup_sctp(void *args) {
  struct sn_context *snc = args;
  sleep(3);
  sn_reopen_asoc_streams(snc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cleanup_sctp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <sn_reopen_asoc_streams@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *cleanup_sctp(void *args) {
  struct sn_context *snc = args;
  sleep(3);
  sn_reopen_asoc_streams(snc);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cleanup_sctp>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <sn_reopen_asoc_streams@plt>
  pop    %rbp
  ret
```

assistant: ```c
void *cleanup_sctp(void *args) {
  struct sn_context *snc = args;
  sleep(3);
  sn_reopen_asoc_streams(snc);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cleanup_sctp>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <sn_reopen_asoc_streams@plt>
  pop    %rbp
  ret
```

assistant: ```c
void *cleanup_sctp(void *args) {
  struct sn_context *snc = args;
  sleep(3);
  sn_reopen_asoc_streams(snc);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mergeSortA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L5
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSortA>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSortA>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mergeA@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void mergeSortA(int *A, int lo, int hi) {
  int middle;
  if (lo < hi) {
    middle = (int)((lo + hi) / 2);
    mergeSortA(A, lo, middle);
    mergeSortA(A, middle + 1, hi);
    mergeA(A, lo, middle, hi);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mergeSortA>:
  endbr64
  cmp    %edx,%esi
  jl     L4
  ret
L4:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <mergeSortA>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <mergeSortA>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <mergeA@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mergeSortA(int *A, int lo, int hi) {
  int middle;
  if (lo < hi) {
    middle = (int)((lo + hi) / 2);
    mergeSortA(A, lo, middle);
    mergeSortA(A, middle + 1, hi);
    mergeA(A, lo, middle, hi);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<zlib_uncompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %ecx,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x60(%rbp),%eax
  mov    %eax,-0x40(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x5c(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  mov    D37(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    D37(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x38(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <inflateInit@plt>
  mov    %eax,-0x44(%rbp)
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x44(%rbp)
  jne    L14
  mov    D47(%rip),%rax
  mov    (%rax),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <inflate@plt>
  mov    %eax,-0x44(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x44(%rbp)
  jne    L2
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x44(%rbp)
L2:
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <inflateEnd@plt>
  mov    D65(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jne    L14
  mov    D65(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x44(%rbp)
L14:
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x44(%rbp)
  jne    L46
  mov    D65(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x44(%rbp)
L46:
  mov    -0x44(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int zlib_uncompress(void *dest, unsigned int destLen, const void *src, unsigned int srcLen) {
  z_stream zs;
  int ret;
  zs.next_in = (Bytef *)src;
  zs.avail_in = srcLen;
  zs.next_out = (Bytef *)dest;
  zs.avail_out = destLen;
  zs.zalloc = Z_NULL;
  zs.zfree = Z_NULL;
  zs.opaque = 0;
  ret = inflateInit(&zs);
  if (ret == Z_OK) {
    ret = inflate(&zs, Z_FINISH);
    if (ret == Z_STREAM_END)
      ret = Z_OK;
    if (inflateEnd(&zs) == Z_DATA_ERROR)
      ret = Z_DATA_ERROR;
  }
  if (ret == Z_BUF_ERROR)
    ret = Z_DATA_ERROR;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zlib_uncompress>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rdx,0x28(%rsp)
  mov    %ecx,(%rsp)
  mov    %rdi,0x20(%rsp)
  mov    %esi,0x4(%rsp)
  mov    D70(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rdi
  call   <inflateInit@plt>
  mov    %eax,%ebx
  mov    D32(%rip),%rax
  cmp    %ebx,(%rax)
  je     L12
L47:
  mov    D62(%rip),%rax
  cmp    %ebx,(%rax)
  je     L56
L63:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    %ebx,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L12:
  mov    %rsp,%rdi
  mov    D27(%rip),%rax
  mov    (%rax),%esi
  call   <inflate@plt>
  mov    %eax,%ebx
  mov    D34(%rip),%rax
  cmp    %ebx,(%rax)
  je     L48
L38:
  mov    %rsp,%rdi
  call   <inflateEnd@plt>
  mov    %eax,%edx
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmove  %eax,%ebx
  jmp    L47
L48:
  mov    D32(%rip),%rax
  mov    (%rax),%ebx
  jmp    L38
L56:
  mov    D35(%rip),%rax
  mov    (%rax),%ebx
  jmp    L63
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zlib_uncompress(void *dest, unsigned int destLen, const void *src, unsigned int srcLen) {
  z_stream zs;
  int ret;
  zs.next_in = (Bytef *)src;
  zs.avail_in = srcLen;
  zs.next_out = (Bytef *)dest;
  zs.avail_out = destLen;
  zs.zalloc = Z_NULL;
  zs.zfree = Z_NULL;
  zs.opaque = 0;
  ret = inflateInit(&zs);
  if (ret == Z_OK) {
    ret = inflate(&zs, Z_FINISH);
    if (ret == Z_STREAM_END)
      ret = Z_OK;
    if (inflateEnd(&zs) == Z_DATA_ERROR)
      ret = Z_DATA_ERROR;
  }
  if (ret == Z_BUF_ERROR)
    ret = Z_DATA_ERROR;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<zlib_uncompress>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  mov    %rsp,%rbp
  mov    %ecx,(%rsp)
  mov    %rdi,0x20(%rsp)
  mov    %rbp,%rdi
  mov    (%rax),%rax
  mov    %rdx,0x28(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <inflateInit@plt>
  mov    D58(%rip),%rbx
  mov    %eax,%r12d
  cmp    %eax,(%rbx)
  je     L30
L36:
  mov    D12(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L13
  mov    D4(%rip),%rax
  mov    (%rax),%r12d
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x40,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L30:
  mov    D22(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <inflate@plt>
  mov    %eax,%r12d
  mov    D44(%rip),%rax
  cmp    %r12d,(%rax)
  je     L15
L25:
  mov    %rbp,%rdi
  call   <inflateEnd@plt>
  mov    D4(%rip),%rdx
  cmp    (%rdx),%eax
  cmove  %eax,%r12d
  jmp    L36
  nop
L15:
  mov    (%rbx),%r12d
  jmp    L25
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zlib_uncompress(void *dest, unsigned int destLen, const void *src, unsigned int srcLen) {
  z_stream zs;
  int ret;
  zs.next_in = (Bytef *)src;
  zs.avail_in = srcLen;
  zs.next_out = (Bytef *)dest;
  zs.avail_out = destLen;
  zs.zalloc = Z_NULL;
  zs.zfree = Z_NULL;
  zs.opaque = 0;
  ret = inflateInit(&zs);
  if (ret == Z_OK) {
    ret = inflate(&zs, Z_FINISH);
    if (ret == Z_STREAM_END)
      ret = Z_OK;
    if (inflateEnd(&zs) == Z_DATA_ERROR)
      ret = Z_DATA_ERROR;
  }
  if (ret == Z_BUF_ERROR)
    ret = Z_DATA_ERROR;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zlib_uncompress>:
  endbr64
  push   %r12
  movd   %ecx,%xmm0
  movd   %esi,%xmm1
  movq   %rdx,%xmm2
  push   %rbp
  punpckldq %xmm1,%xmm0
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  movq   %xmm0,(%rsp)
  mov    %rsp,%rbp
  movq   $0x0,0x8(%rsp)
  movq   (%rax),%xmm0
  punpcklqdq %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movq   %rdi,%xmm0
  mov    %rbp,%rdi
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <inflateInit@plt>
  mov    D61(%rip),%rbx
  mov    %eax,%r12d
  cmp    %eax,(%rbx)
  je     L13
L36:
  mov    D38(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L33
  mov    D21(%rip),%rax
  mov    (%rax),%r12d
L33:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x40,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    D67(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <inflate@plt>
  mov    %eax,%r12d
  mov    D42(%rip),%rax
  cmp    %r12d,(%rax)
  je     L30
L34:
  mov    %rbp,%rdi
  call   <inflateEnd@plt>
  mov    D21(%rip),%rdx
  cmp    (%rdx),%eax
  cmove  %eax,%r12d
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L30:
  mov    (%rbx),%r12d
  jmp    L34
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zlib_uncompress(void *dest, unsigned int destLen, const void *src, unsigned int srcLen) {
  z_stream zs;
  int ret;
  zs.next_in = (Bytef *)src;
  zs.avail_in = srcLen;
  zs.next_out = (Bytef *)dest;
  zs.avail_out = destLen;
  zs.zalloc = Z_NULL;
  zs.zfree = Z_NULL;
  zs.opaque = 0;
  ret = inflateInit(&zs);
  if (ret == Z_OK) {
    ret = inflate(&zs, Z_FINISH);
    if (ret == Z_STREAM_END)
      ret = Z_OK;
    if (inflateEnd(&zs) == Z_DATA_ERROR)
      ret = Z_DATA_ERROR;
  }
  if (ret == Z_BUF_ERROR)
    ret = Z_DATA_ERROR;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L49
L76:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x40(%rbp)
L49:
  mov    -0x40(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L76
  movl   $0x0,-0x40(%rbp)
  jmp    L39
L91:
  movl   $0x0,-0x3c(%rbp)
  jmp    L71
L23:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L81
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
L81:
  addl   $0x1,-0x3c(%rbp)
L71:
  mov    -0x38(%rbp),%eax
  sub    -0x40(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x3c(%rbp)
  jl     L23
  addl   $0x1,-0x40(%rbp)
L39:
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x40(%rbp)
  jl     L91
  movl   $0x0,-0x40(%rbp)
  jmp    L79
L1:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x40(%rbp)
L79:
  mov    -0x40(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: %d	

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10, i, j, a[10];
  int temp = 0;
  for (i = 0; i < n; i++)
    a[i] = rand() % 100;
  for (i = 0; i < n - 1; i++)
    for (j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
  for (i = 0; i < n; i++)
    printf("%d\t", a[i]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%r12
L86:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%r12)
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L86
  lea    0x24(%rbx),%rsi
  mov    $0x9,%edi
  jmp    L10
L56:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L31
L49:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L56
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L56
L31:
  sub    $0x4,%rsi
  sub    $0x1,%edi
  je     L84
L10:
  mov    %rbx,%rax
  test   %edi,%edi
  jg     L49
  jmp    L31
L84:
  lea    D9(%rip),%r12
L62:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L62
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: %d	

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10, i, j, a[10];
  int temp = 0;
  for (i = 0; i < n; i++)
    a[i] = rand() % 100;
  for (i = 0; i < n - 1; i++)
    for (j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
  for (i = 0; i < n; i++)
    printf("%d\t", a[i]);
  return 0;
}
```