ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<search_first_hit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rdi,(%rsp)
  mov    %rsi,%r13
  mov    %rdx,0x8(%rsp)
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x1,%eax
  cmp    %r12d,%r14d
  jb     L111
  lea    0x1(%r14),%r15d
  sub    %r12d,%r15d
  je     L57
  mov    %r13,%rbp
  mov    $0x0,%ebx
L129:
  mov    %r12d,%edx
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  je     L107
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r15d,%ebx
  jne    L129
  mov    %r15d,%ebx
L107:
  lea    (%r12,%rbx,1),%esi
  lea    0xf(%rsi),%ecx
  cmp    %ecx,%esi
  jae    L28
  cmp    %esi,%r14d
  jb     L68
L88:
  mov    %esi,%edx
L2:
  mov    %edx,%eax
  cmpb   $0x20,0x0(%r13,%rax,1)
  je     L95
  add    $0x1,%edx
  cmp    %ecx,%edx
  jae    L95
  cmp    %edx,%r14d
  jae    L2
  mov    $0x1,%eax
  jmp    L111
L28:
  mov    %esi,%edx
L95:
  sub    %r12d,%edx
  sub    %ebx,%edx
  mov    %esi,%esi
  add    %r13,%rsi
  mov    0x8(%rsp),%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L111:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  mov    $0x1,%eax
  jmp    L111
L57:
  lea    0xf(%r12),%ecx
  mov    %r15d,%ebx
  mov    %r12d,%esi
  mov    %r12d,%edx
  cmp    %r12d,%ecx
  ja     L88
  jmp    L95
```

assistant: ```c
int search_first_hit(char *search, char *line, char *ret) {
  unsigned int searchLen;
  unsigned int i;
  unsigned int j;
  unsigned int lineLen;
  lineLen = strlen(line);
  searchLen = strlen(search);
  if (searchLen > lineLen) {
    return (1);
  }
  for (i = 0; i < lineLen - searchLen + 1; i++) {
    if (!strncasecmp((char *)&line[i], search, searchLen)) {
      break;
    }
  }
  for (j = i + searchLen; j < i + 15 + searchLen; j++) {
    if (j > lineLen) {
      return (1);
    }
    if (line[j] == ' ') {
      break;
    }
  }
  memcpy(ret, &line[i + searchLen], j - i - searchLen);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<search_first_hit>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %rsi,%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jb     L27
  mov    %eax,%r14d
  lea    0x1(%r13),%eax
  sub    %r14d,%eax
  mov    %eax,0x4(%rsp)
  je     L119
  mov    %rbp,%r12
  xor    %ebx,%ebx
  jmp    L116
  nopl   0x0(%rax)
L63:
  add    $0x1,%ebx
  add    $0x1,%r12
  cmp    0x4(%rsp),%ebx
  je     L106
L116:
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L63
L106:
  lea    (%r14,%rbx,1),%esi
  lea    0xf(%rsi),%edi
  cmp    %esi,%edi
  jbe    L86
  cmp    %esi,%r13d
  jb     L27
L114:
  mov    %esi,%eax
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L67:
  cmp    %eax,%r13d
  jb     L27
L13:
  mov    %eax,%ecx
  cmpb   $0x20,0x0(%rbp,%rcx,1)
  je     L91
  add    $0x1,%eax
  cmp    %edi,%eax
  jb     L67
L91:
  lea    (%r14,%rbx,1),%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
L70:
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%rdi
  add    %rbp,%rsi
  call   <memcpy@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L27:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L86:
  movl   $0x0,0x4(%rsp)
  jmp    L70
L119:
  lea    0xf(%r14),%edi
  mov    %r14d,%esi
  xor    %ebx,%ebx
  cmp    %esi,%edi
  ja     L114
  jmp    L70
```

assistant: ```c
int search_first_hit(char *search, char *line, char *ret) {
  unsigned int searchLen;
  unsigned int i;
  unsigned int j;
  unsigned int lineLen;
  lineLen = strlen(line);
  searchLen = strlen(search);
  if (searchLen > lineLen) {
    return (1);
  }
  for (i = 0; i < lineLen - searchLen + 1; i++) {
    if (!strncasecmp((char *)&line[i], search, searchLen)) {
      break;
    }
  }
  for (j = i + searchLen; j < i + 15 + searchLen; j++) {
    if (j > lineLen) {
      return (1);
    }
    if (line[j] == ' ') {
      break;
    }
  }
  memcpy(ret, &line[i + searchLen], j - i - searchLen);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<search_first_hit>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %rsi,%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jb     L5
  mov    %eax,%r14d
  lea    0x1(%r13),%eax
  sub    %r14d,%eax
  mov    %eax,0x4(%rsp)
  je     L124
  mov    %rbp,%r12
  xor    %ebx,%ebx
  jmp    L57
  nopl   0x0(%rax)
L90:
  add    $0x1,%ebx
  add    $0x1,%r12
  cmp    0x4(%rsp),%ebx
  je     L128
L57:
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L90
L128:
  lea    (%r14,%rbx,1),%esi
  lea    0xf(%rsi),%edi
  cmp    %esi,%edi
  jbe    L20
  cmp    %esi,%r13d
  jb     L5
L53:
  mov    %esi,%eax
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L51:
  cmp    %eax,%r13d
  jb     L5
L15:
  mov    %eax,%ecx
  cmpb   $0x20,0x0(%rbp,%rcx,1)
  je     L8
  add    $0x1,%eax
  cmp    %edi,%eax
  jb     L51
L8:
  lea    (%r14,%rbx,1),%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  mov    %eax,%edx
L117:
  mov    0x8(%rsp),%rdi
  add    %rbp,%rsi
  call   <memcpy@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L5:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  movl   $0x0,0x4(%rsp)
  mov    0x4(%rsp),%edx
  jmp    L117
L124:
  lea    0xf(%r14),%edi
  mov    %r14d,%esi
  xor    %ebx,%ebx
  mov    %eax,%edx
  cmp    %esi,%edi
  ja     L53
  jmp    L117
```

assistant: ```c
int search_first_hit(char *search, char *line, char *ret) {
  unsigned int searchLen;
  unsigned int i;
  unsigned int j;
  unsigned int lineLen;
  lineLen = strlen(line);
  searchLen = strlen(search);
  if (searchLen > lineLen) {
    return (1);
  }
  for (i = 0; i < lineLen - searchLen + 1; i++) {
    if (!strncasecmp((char *)&line[i], search, searchLen)) {
      break;
    }
  }
  for (j = i + searchLen; j < i + 15 + searchLen; j++) {
    if (j > lineLen) {
      return (1);
    }
    if (line[j] == ' ') {
      break;
    }
  }
  memcpy(ret, &line[i + searchLen], j - i - searchLen);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sock_getifaddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getifaddrs@plt>
  cmp    $0xffffffff,%eax
  jne    L156
  mov    $0x0,%eax
  jmp    L81
L156:
  movl   $0x0,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L154
L37:
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L70
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L68
  cmpl   $0x0,-0x30(%rbp)
  je     L86
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  and    -0x30(%rbp),%eax
  test   %eax,%eax
  je     L84
L86:
  cmpl   $0x0,-0x30(%rbp)
  jne    L61
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rdi
  call   <sock_addrlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x1,-0x1c(%rbp)
  jmp    L120
L61:
  nop
L120:
  jmp    L145
L29:
  nop
  jmp    L79
L70:
  nop
  jmp    L79
L68:
  nop
  jmp    L79
L84:
  nop
L79:
  mov    -0x10(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,-0x10(%rbp)
L154:
  cmpq   $0x0,-0x10(%rbp)
  jne    L37
L145:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <freeifaddrs@plt>
  mov    -0x1c(%rbp),%eax
L81:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
int sock_getifaddr(const char *ifname, int family, int type, struct sockaddr *sa) {
  struct ifaddrs *ifap, *ifa;
  int rc;
  if (getifaddrs(&ifap) == -1)
    return 0;
  rc = 0;
  for (ifa = ifap; ifa != NULL; ifa = ifa->ifa_next) {
    if (strcmp(ifname, ifa->ifa_name))
      continue;
    if (ifa->ifa_addr == NULL)
      continue;
    if (ifa->ifa_addr->sa_family != family)
      continue;
    if (type != 0)
      if (!(ifa->ifa_flags & type))
        continue;
    switch (type) {
    case 0:
      memcpy(sa, ifa->ifa_addr, sock_addrlen(ifa->ifa_addr));
      rc = 1;
      break;
    default:
      break;
    }
    break;
  }
  freeifaddrs(ifap);
  return rc;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sock_getifaddr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  mov    $0x0,%ebx
  cmp    $0xffffffff,%eax
  je     L48
  mov    (%rsp),%rbx
  test   %rbx,%rbx
  jne    L76
  mov    $0x0,%ebx
  jmp    L69
L62:
  call   <sock_addrlen@plt>
  mov    %eax,%edx
  mov    0x8(%rbx),%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    $0x1,%ebx
  jmp    L69
L38:
  mov    0x18(%rbx),%rbx
  test   %rbx,%rbx
  je     L69
L76:
  mov    0x10(%rbx),%esi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L38
  mov    0x8(%rbx),%rdi
  test   %rdi,%rdi
  je     L38
  cmp    %r13d,(%rdi)
  jne    L38
  test   %r12d,%r12d
  je     L62
  mov    %r12d,%eax
  and    (%rbx),%eax
  je     L38
  mov    $0x0,%ebx
L69:
  mov    (%rsp),%rdi
  call   <freeifaddrs@plt>
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_getifaddr(const char *ifname, int family, int type, struct sockaddr *sa) {
  struct ifaddrs *ifap, *ifa;
  int rc;
  if (getifaddrs(&ifap) == -1)
    return 0;
  rc = 0;
  for (ifa = ifap; ifa != NULL; ifa = ifa->ifa_next) {
    if (strcmp(ifname, ifa->ifa_name))
      continue;
    if (ifa->ifa_addr == NULL)
      continue;
    if (ifa->ifa_addr->sa_family != family)
      continue;
    if (type != 0)
      if (!(ifa->ifa_flags & type))
        continue;
    switch (type) {
    case 0:
      memcpy(sa, ifa->ifa_addr, sock_addrlen(ifa->ifa_addr));
      rc = 1;
      break;
    default:
      break;
    }
    break;
  }
  freeifaddrs(ifap);
  return rc;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sock_getifaddr>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  cmp    $0xffffffff,%eax
  je     L74
  mov    (%rsp),%rbp
  test   %rbp,%rbp
  je     L42
L108:
  mov    0x10(%rbp),%esi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L3
  mov    0x8(%rbp),%rdi
  test   %rdi,%rdi
  je     L3
  cmp    %r13d,(%rdi)
  jne    L3
  test   %r12d,%r12d
  je     L82
  mov    %r12d,%eax
  and    0x0(%rbp),%eax
  je     L3
L57:
  mov    (%rsp),%rbp
  xor    %r15d,%r15d
L42:
  mov    %rbp,%rdi
  call   <freeifaddrs@plt>
L74:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    0x18(%rbp),%rbp
  test   %rbp,%rbp
  jne    L108
  jmp    L57
L82:
  call   <sock_addrlen@plt>
  mov    0x8(%rbp),%rsi
  mov    %r14,%rdi
  mov    $0x1,%r15d
  mov    %eax,%edx
  call   <memcpy@plt>
  mov    (%rsp),%rbp
  jmp    L42
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_getifaddr(const char *ifname, int family, int type, struct sockaddr *sa) {
  struct ifaddrs *ifap, *ifa;
  int rc;
  if (getifaddrs(&ifap) == -1)
    return 0;
  rc = 0;
  for (ifa = ifap; ifa != NULL; ifa = ifa->ifa_next) {
    if (strcmp(ifname, ifa->ifa_name))
      continue;
    if (ifa->ifa_addr == NULL)
      continue;
    if (ifa->ifa_addr->sa_family != family)
      continue;
    if (type != 0)
      if (!(ifa->ifa_flags & type))
        continue;
    switch (type) {
    case 0:
      memcpy(sa, ifa->ifa_addr, sock_addrlen(ifa->ifa_addr));
      rc = 1;
      break;
    default:
      break;
    }
    break;
  }
  freeifaddrs(ifap);
  return rc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sock_getifaddr>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  cmp    $0xffffffff,%eax
  je     L35
  mov    (%rsp),%rbp
  test   %rbp,%rbp
  je     L50
  test   %r13d,%r13d
  je     L5
L22:
  mov    0x10(%rbp),%esi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L142
  mov    0x8(%rbp),%rax
  test   %rax,%rax
  je     L142
  cmp    %r12d,(%rax)
  jne    L142
  mov    %r13d,%eax
  and    0x0(%rbp),%eax
  je     L142
L29:
  mov    (%rsp),%rbp
  xor    %r15d,%r15d
L50:
  mov    %rbp,%rdi
  call   <freeifaddrs@plt>
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L147
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L142:
  mov    0x18(%rbp),%rbp
  test   %rbp,%rbp
  jne    L22
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L83:
  mov    0x18(%rbp),%rbp
  test   %rbp,%rbp
  je     L29
L5:
  mov    0x10(%rbp),%esi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L83
  mov    0x8(%rbp),%rdi
  test   %rdi,%rdi
  je     L83
  cmp    (%rdi),%r12d
  jne    L83
  call   <sock_addrlen@plt>
  mov    0x8(%rbp),%rsi
  mov    %r14,%rdi
  mov    $0x1,%r15d
  mov    %eax,%edx
  call   <memcpy@plt>
  mov    (%rsp),%rbp
  jmp    L50
L147:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_getifaddr(const char *ifname, int family, int type, struct sockaddr *sa) {
  struct ifaddrs *ifap, *ifa;
  int rc;
  if (getifaddrs(&ifap) == -1)
    return 0;
  rc = 0;
  for (ifa = ifap; ifa != NULL; ifa = ifa->ifa_next) {
    if (strcmp(ifname, ifa->ifa_name))
      continue;
    if (ifa->ifa_addr == NULL)
      continue;
    if (ifa->ifa_addr->sa_family != family)
      continue;
    if (type != 0)
      if (!(ifa->ifa_flags & type))
        continue;
    switch (type) {
    case 0:
      memcpy(sa, ifa->ifa_addr, sock_addrlen(ifa->ifa_addr));
      rc = 1;
      break;
    default:
      break;
    }
    break;
  }
  freeifaddrs(ifap);
  return rc;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L5:
  movsbl -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x4(%rbp)
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_char@plt>
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_str(char *str, char attr) {
  int i = 0;
  while (str[i])
    print_char(str[i++], attr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x1(%rdi),%rbx
  movsbl %sil,%ebp
L10:
  movsbl %al,%edi
  mov    %ebp,%esi
  call   <print_char@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  ret
```

assistant: ```c
void print_str(char *str, char attr) {
  int i = 0;
  while (str[i])
    print_char(str[i++], attr);
}
```
user: What is the c source code of the assembly code below?

```asm
<print_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L13
  push   %rbp
  movsbl %sil,%ebp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L18:
  movsbl %al,%edi
  mov    %ebp,%esi
  add    $0x1,%rbx
  call   <print_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L13:
  ret
```

assistant: ```c
void print_str(char *str, char attr) {
  int i = 0;
  while (str[i])
    print_char(str[i++], attr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  push   %rbp
  movsbl %sil,%ebp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  movsbl %al,%edi
  mov    %ebp,%esi
  add    $0x1,%rbx
  call   <print_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
void print_str(char *str, char attr) {
  int i = 0;
  while (str[i])
    print_char(str[i++], attr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<exit_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <report@plt>
  mov    $0x0,%eax
  call   <closelog@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: daemon exiting.

assistant: ```c
void exit_handler(void) {
  report("daemon exiting.", 0);
  closelog();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exit_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D0(%rip),%rdi
  call   <report@plt>
  mov    $0x0,%eax
  call   <closelog@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: daemon exiting.

assistant: ```c
void exit_handler(void) {
  report("daemon exiting.", 0);
  closelog();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<exit_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  call   <report@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <closelog@plt>
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: daemon exiting.

assistant: ```c
void exit_handler(void) {
  report("daemon exiting.", 0);
  closelog();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exit_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  call   <report@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <closelog@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: daemon exiting.

assistant: ```c
void exit_handler(void) {
  report("daemon exiting.", 0);
  closelog();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  movl   $0x1,-0x1c(%rbp)
  jmp    L14
L12:
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_ui_pow_ui@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_add@plt>
  addl   $0x1,-0x1c(%rbp)
L14:
  cmpl   $0x3e8,-0x1c(%rbp)
  jle    L12
  mov    -0x18(%rbp),%edx
  lea    -0x10(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <gmp_asprintf@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  sub    $0xa,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string
name: parse_data
arguments: label: D3
type_infered: string

tool: D6: %Zd

tool: D3: %s


assistant: ```c
int main(void) {
  int i;
  char *s = NULL;
  mpz_t n, temp;
  mpz_init(n);
  mpz_init(temp);
  for (i = 1; i <= 1000; i++) {
    mpz_ui_pow_ui(temp, i, i);
    mpz_add(n, n, temp);
  }
  i = gmp_asprintf(&s, "%Zd", n);
  printf("%s\n", s + i - 10);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%edi
  call   <mpz_init@plt>
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    $0x1,%ebx
L6:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_ui_pow_ui@plt>
  mov    %ebp,%edx
  mov    $0x0,%edi
  mov    %edi,%esi
  call   <mpz_add@plt>
  add    $0x1,%ebx
  cmp    $0x3e9,%ebx
  jne    L6
  mov    %rsp,%rax
  mov    $0x0,%edi
  mov    %edi,%edx
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  call   <gmp_asprintf@plt>
  cltq
  mov    (%rsp),%rdx
  lea    -0xa(%rdx,%rax,1),%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string

tool: D10: %Zd

tool: D16: %s


assistant: ```c
int main(void) {
  int i;
  char *s = NULL;
  mpz_t n, temp;
  mpz_init(n);
  mpz_init(temp);
  for (i = 1; i <= 1000; i++) {
    mpz_ui_pow_ui(temp, i, i);
    mpz_add(n, n, temp);
  }
  i = gmp_asprintf(&s, "%Zd", n);
  printf("%s\n", s + i - 10);
  return 0;
}
```