ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<index>:
  endbr64
  xor    %eax,%eax
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rax
  cmp    $0x32,%rax
  je     L13
L5:
  mov    %eax,%r8d
  cmp    %sil,(%rdi,%rax,1)
  jne    L3
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int index(char a1[50], char b1) {
  int i;
  for (i = 0; i < 50; i++) {
    if (a1[i] == b1) {
      return i;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<index>:
  endbr64
  xor    %eax,%eax
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rax
  cmp    $0x32,%rax
  je     L8
L11:
  mov    %eax,%r8d
  cmp    %sil,(%rdi,%rax,1)
  jne    L5
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int index(char a1[50], char b1) {
  int i;
  for (i = 0; i < 50; i++) {
    if (a1[i] == b1) {
      return i;
    }
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x3,-0x4(%rbp)
  jmp    L19
L31:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L0
  mov    $0x0,%eax
  jmp    L9
L0:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L31
  mov    $0x1,%eax
L9:
  leave
  ret
```

assistant: ```c
int isprime(int n) {
  for (int d = 3; d < sqrt(n) + 1; d++) {
    if (n % d == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isprime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x3,%ebx
  jmp    L30
L32:
  add    $0x1,%ebx
L30:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L36
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L32
  jmp    L0
L36:
  mov    $0x1,%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int isprime(int n) {
  for (int d = 3; d < sqrt(n) + 1; d++) {
    if (n % d == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isprime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x8,%rsp
  jmp    L6
  nopl   (%rax)
L5:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L12
  add    $0x1,%ebx
L6:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L5
  mov    $0x1,%edx
L12:
  add    $0x8,%rsp
  mov    %edx,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int isprime(int n) {
  for (int d = 3; d < sqrt(n) + 1; d++) {
    if (n % d == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<isprime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nopl   (%rax)
L19:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L23
  add    $0x1,%ebx
L8:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L19
  mov    $0x1,%edx
L23:
  add    $0x8,%rsp
  mov    %edx,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int isprime(int n) {
  for (int d = 3; d < sqrt(n) + 1; d++) {
    if (n % d == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_prlog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void _prlog(int log_level __attribute__((unused)), const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_prlog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void _prlog(int log_level __attribute__((unused)), const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_prlog>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _prlog(int log_level __attribute__((unused)), const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_prlog>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _prlog(int log_level __attribute__((unused)), const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<elf_check_arch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L0
  mov    $0x0,%eax
  jmp    L35
L0:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L39
  mov    $0x0,%eax
  jmp    L35
L39:
  mov    $0x1,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int elf_check_arch(const struct elf32_hdr *x) {
  if (x->e_machine != EM_UNICORE)
    return 0;
  if (x->e_entry & 3)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<elf_check_arch>:
  endbr64
  mov    $0x0,%eax
  mov    D4(%rip),%rdx
  mov    (%rdx),%rcx
  cmp    %rcx,(%rdi)
  jne    L7
  testb  $0x3,0x8(%rdi)
  sete   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int elf_check_arch(const struct elf32_hdr *x) {
  if (x->e_machine != EM_UNICORE)
    return 0;
  if (x->e_entry & 3)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<elf_check_arch>:
  endbr64
  mov    D1(%rip),%rdx
  xor    %eax,%eax
  mov    (%rdx),%rcx
  cmp    %rcx,(%rdi)
  jne    L7
  xor    %eax,%eax
  testb  $0x3,0x8(%rdi)
  sete   %al
L7:
  ret
```

assistant: ```c
int elf_check_arch(const struct elf32_hdr *x) {
  if (x->e_machine != EM_UNICORE)
    return 0;
  if (x->e_entry & 3)
    return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<elf_check_arch>:
  endbr64
  mov    D3(%rip),%rdx
  xor    %eax,%eax
  mov    (%rdx),%rcx
  cmp    %rcx,(%rdi)
  jne    L4
  xor    %eax,%eax
  testb  $0x3,0x8(%rdi)
  sete   %al
L4:
  ret
```

assistant: ```c
int elf_check_arch(const struct elf32_hdr *x) {
  if (x->e_machine != EM_UNICORE)
    return 0;
  if (x->e_entry & 3)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__statfs64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __statfs64(const char *file, struct statfs64 *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__statfs64>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __statfs64(const char *file, struct statfs64 *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__statfs64>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __statfs64(const char *file, struct statfs64 *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__statfs64>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __statfs64(const char *file, struct statfs64 *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<x44_setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0x1,%edx
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x44_setup() {
  char cmd[256];
  sprintf(cmd, "iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<x44_setup>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x1,%edx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string

tool: D2: iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x44_setup() {
  char cmd[256];
  sprintf(cmd, "iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<x44_setup>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  lea    D6(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x44_setup() {
  char cmd[256];
  sprintf(cmd, "iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<x44_setup>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  lea    D9(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x44_setup() {
  char cmd[256];
  sprintf(cmd, "iptables -A INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_color_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%edx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <print_enum@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_guessed: string

tool: D12: color_matrix

assistant: ```c
void print_color_matrix() {
  static const char *COLOR_MATRIX_STRINGS[] = {
      "HDTV",
      "SDTV",
      "Reversible",
      "RGB",
  };
  print_enum("color_matrix", COLOR_MATRIX_STRINGS, (sizeof(COLOR_MATRIX_STRINGS) / sizeof((COLOR_MATRIX_STRINGS)[0])));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_color_matrix>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edx
  lea    D16(%rip),%rsi
  lea    D7(%rip),%rdi
  call   <print_enum@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: color_matrix

assistant: ```c
void print_color_matrix() {
  static const char *COLOR_MATRIX_STRINGS[] = {
      "HDTV",
      "SDTV",
      "Reversible",
      "RGB",
  };
  print_enum("color_matrix", COLOR_MATRIX_STRINGS, (sizeof(COLOR_MATRIX_STRINGS) / sizeof((COLOR_MATRIX_STRINGS)[0])));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_color_matrix>:
  endbr64
  mov    $0x4,%edx
  lea    D7(%rip),%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <print_enum@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: color_matrix

assistant: ```c
void print_color_matrix() {
  static const char *COLOR_MATRIX_STRINGS[] = {
      "HDTV",
      "SDTV",
      "Reversible",
      "RGB",
  };
  print_enum("color_matrix", COLOR_MATRIX_STRINGS, (sizeof(COLOR_MATRIX_STRINGS) / sizeof((COLOR_MATRIX_STRINGS)[0])));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_color_matrix>:
  endbr64
  mov    $0x4,%edx
  lea    D7(%rip),%rsi
  lea    D3(%rip),%rdi
  jmp    1050 <print_enum@plt>
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: color_matrix

assistant: ```c
void print_color_matrix() {
  static const char *COLOR_MATRIX_STRINGS[] = {
      "HDTV",
      "SDTV",
      "Reversible",
      "RGB",
  };
  print_enum("color_matrix", COLOR_MATRIX_STRINGS, (sizeof(COLOR_MATRIX_STRINGS) / sizeof((COLOR_MATRIX_STRINGS)[0])));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L31
  cmpq   $0x0,-0x40(%rbp)
  jne    L24
L31:
  mov    $0x0,%eax
  jmp    L55
L24:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L54
  mov    $0x0,%eax
  jmp    L55
L54:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L22
L1:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x28(%rbp),%rbx
  lea    0x1(%rbx),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  mov    %al,(%rbx)
L22:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x18(%rbp),%rax
L55:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strmap(char const *s, char (*f)(char)) {
  char *str;
  char *cp_str;
  size_t ct;
  if (!s || !f)
    return (NULL);
  ct = ft_strlen(s);
  if ((str = (char *)malloc((ct + 0x01) * sizeof(*str))) == NULL)
    return (NULL);
  cp_str = str;
  while (*s)
    *str++ = f(*s++);
  return (cp_str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strmap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L53
  mov    %rdi,%rbp
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L53
  call   <ft_strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L55
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L40
  mov    %rax,%rbx
  sub    %rax,%rbp
L24:
  mov    %rbx,%r12
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   *%r13
  mov    %al,(%r12)
  movzbl (%rbx,%rbp,1),%edi
  test   %dil,%dil
  jne    L24
L40:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L53:
  mov    $0x0,%r14d
  jmp    L40
L55:
  mov    $0x0,%r14d
  jmp    L40
```

assistant: ```c
char *ft_strmap(char const *s, char (*f)(char)) {
  char *str;
  char *cp_str;
  size_t ct;
  if (!s || !f)
    return (NULL);
  ct = ft_strlen(s);
  if ((str = (char *)malloc((ct + 0x01) * sizeof(*str))) == NULL)
    return (NULL);
  cp_str = str;
  while (*s)
    *str++ = f(*s++);
  return (cp_str);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strmap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L15
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L15
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L15
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L26
  mov    %rax,%rbx
  sub    %rax,%rbp
  nopl   0x0(%rax)
L36:
  call   *%r12
  mov    %rbx,%r14
  add    $0x1,%rbx
  mov    %al,(%r14)
  movsbl (%rbx,%rbp,1),%edi
  test   %dil,%dil
  jne    L36
L26:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ft_strmap(char const *s, char (*f)(char)) {
  char *str;
  char *cp_str;
  size_t ct;
  if (!s || !f)
    return (NULL);
  ct = ft_strlen(s);
  if ((str = (char *)malloc((ct + 0x01) * sizeof(*str))) == NULL)
    return (NULL);
  cp_str = str;
  while (*s)
    *str++ = f(*s++);
  return (cp_str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strmap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L7
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L7
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L7
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L48
  mov    %rax,%rbx
  sub    %rax,%rbp
  nopl   0x0(%rax)
L41:
  call   *%r12
  mov    %rbx,%r14
  add    $0x1,%rbx
  mov    %al,(%r14)
  movsbl (%rbx,%rbp,1),%edi
  test   %dil,%dil
  jne    L41
L48:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ft_strmap(char const *s, char (*f)(char)) {
  char *str;
  char *cp_str;
  size_t ct;
  if (!s || !f)
    return (NULL);
  ct = ft_strlen(s);
  if ((str = (char *)malloc((ct + 0x01) * sizeof(*str))) == NULL)
    return (NULL);
  cp_str = str;
  while (*s)
    *str++ = f(*s++);
  return (cp_str);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rot_r_asm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  ror    %cl,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rot_r_asm(int x, unsigned count) {
  asm("ror %%cl, %[x]" : [x] "+r"(x) : "c"(count) : "cc");
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rot_r_asm>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  ror    %cl,%eax
  ret
```

assistant: ```c
int rot_r_asm(int x, unsigned count) {
  asm("ror %%cl, %[x]" : [x] "+r"(x) : "c"(count) : "cc");
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rot_r_asm>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  ror    %cl,%eax
  ret
```

assistant: ```c
int rot_r_asm(int x, unsigned count) {
  asm("ror %%cl, %[x]" : [x] "+r"(x) : "c"(count) : "cc");
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void f5(char *source) {
  char *destination1 = 0;
  char *destination2 = destination1 + 0;
  memcpy(destination2, source, 10);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f5>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0xa,%edx
  mov    $0x0,%edi
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f5(char *source) {
  char *destination1 = 0;
  char *destination2 = destination1 + 0;
  memcpy(destination2, source, 10);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f5>:
  endbr64
  mov    %rdi,%rsi
  mov    $0xa,%edx
  xor    %edi,%edi
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void f5(char *source) {
  char *destination1 = 0;
  char *destination2 = destination1 + 0;
  memcpy(destination2, source, 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f5>:
  endbr64
  mov    %rdi,%rsi
  mov    $0xa,%edx
  xor    %edi,%edi
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void f5(char *source) {
  char *destination1 = 0;
  char *destination2 = destination1 + 0;
  memcpy(destination2, source, 10);
}
```