ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x686a6f315a616974,%rax
  movabs $0x6c6d507554677748,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x45574132477a6453,%rax
  movabs $0x416550354a725a68,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x11,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <slice@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main(void) {
  char random[] = "tiaZ1ojhHwgTuPmlSdzG2AWEhZrJ5PeA";
  int length;
  length = sizeof(random) - 16;
  slice(random, length);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x686a6f315a616974,%rax
  movabs $0x6c6d507554677748,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x45574132477a6453,%rax
  movabs $0x416550354a725a68,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  mov    %rsp,%rdi
  mov    $0x11,%esi
  call   <slice@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char random[] = "tiaZ1ojhHwgTuPmlSdzG2AWEhZrJ5PeA";
  int length;
  length = sizeof(random) - 16;
  slice(random, length);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D2(%rip),%xmm0
  mov    $0x11,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movb   $0x0,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D8(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <slice@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: byte[16]
name: parse_data
arguments: data_label: D8
type: byte[16]

tool: {"D2": [0x74,0x69,0x61,0x5a,0x31,0x6f,0x6a,0x68,0x48,0x77,0x67,0x54,0x75,0x50,0x6d,0x6c]}

tool: {"D8": [0x53,0x64,0x7a,0x47,0x32,0x41,0x57,0x45,0x68,0x5a,0x72,0x4a,0x35,0x50,0x65,0x41]}

assistant: ```c
int main(void) {
  char random[] = "tiaZ1ojhHwgTuPmlSdzG2AWEhZrJ5PeA";
  int length;
  length = sizeof(random) - 16;
  slice(random, length);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D13(%rip),%xmm0
  mov    $0x11,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movb   $0x0,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <slice@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
data_type: byte[16]
name: disassemble_data
arguments: tag: D7
data_type: byte[16]

tool: {"D13": [0x74,0x69,0x61,0x5a,0x31,0x6f,0x6a,0x68,0x48,0x77,0x67,0x54,0x75,0x50,0x6d,0x6c]}

tool: {"D7": [0x53,0x64,0x7a,0x47,0x32,0x41,0x57,0x45,0x68,0x5a,0x72,0x4a,0x35,0x50,0x65,0x41]}

assistant: ```c
int main(void) {
  char random[] = "tiaZ1ojhHwgTuPmlSdzG2AWEhZrJ5PeA";
  int length;
  length = sizeof(random) - 16;
  slice(random, length);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fatalsig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    $0x0,%eax
  call   <reset@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <raise@plt>
  nop
  leave
  ret
```

assistant: ```c
void fatalsig(int sig) {
  signal(sig, SIG_DFL);
  reset();
  raise(sig);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fatalsig>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <signal@plt>
  mov    $0x0,%eax
  call   <reset@plt>
  mov    %ebx,%edi
  call   <raise@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fatalsig(int sig) {
  signal(sig, SIG_DFL);
  reset();
  raise(sig);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fatalsig>:
  endbr64
  mov    D9(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <signal@plt>
  xor    %eax,%eax
  call   <reset@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <raise@plt>
```

assistant: ```c
void fatalsig(int sig) {
  signal(sig, SIG_DFL);
  reset();
  raise(sig);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fatalsig>:
  endbr64
  mov    D1(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <signal@plt>
  xor    %eax,%eax
  call   <reset@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <raise@plt>
```

assistant: ```c
void fatalsig(int sig) {
  signal(sig, SIG_DFL);
  reset();
  raise(sig);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readable_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
L8:
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int readable_dir(const char *path) {
  DIR *dir = opendir(path);
  if (dir != NULL)
    closedir(dir);
  return dir != NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readable_dir>:
  endbr64
  push   %rbx
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %rax,%rdi
  call   <closedir@plt>
L6:
  test   %rbx,%rbx
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int readable_dir(const char *path) {
  DIR *dir = opendir(path);
  if (dir != NULL)
    closedir(dir);
  return dir != NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<readable_dir>:
  endbr64
  push   %rbx
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  call   <closedir@plt>
L8:
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  setne  %al
  ret
```

assistant: ```c
int readable_dir(const char *path) {
  DIR *dir = opendir(path);
  if (dir != NULL)
    closedir(dir);
  return dir != NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readable_dir>:
  endbr64
  push   %rbx
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <closedir@plt>
L0:
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  setne  %al
  ret
```

assistant: ```c
int readable_dir(const char *path) {
  DIR *dir = opendir(path);
  if (dir != NULL)
    closedir(dir);
  return dir != NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <intro@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L7:
  mov    $0x0,%eax
  call   <hunt@plt>
  mov    $0x0,%eax
  call   <again@plt>
  test   %rax,%rax
  jne    L7
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  intro();
  srand(time(NULL));
  do {
    hunt();
  } while (again());
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <intro@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L6:
  mov    $0x0,%eax
  call   <hunt@plt>
  mov    $0x0,%eax
  call   <again@plt>
  test   %rax,%rax
  jne    L6
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  intro();
  srand(time(NULL));
  do {
    hunt();
  } while (again());
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <intro@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   (%rax)
L4:
  xor    %eax,%eax
  call   <hunt@plt>
  xor    %eax,%eax
  call   <again@plt>
  test   %rax,%rax
  jne    L4
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  intro();
  srand(time(NULL));
  do {
    hunt();
  } while (again());
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <intro@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   (%rax)
L7:
  xor    %eax,%eax
  call   <hunt@plt>
  xor    %eax,%eax
  call   <again@plt>
  test   %rax,%rax
  jne    L7
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  intro();
  srand(time(NULL));
  do {
    hunt();
  } while (again());
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<int_cos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  andl   $0xff,-0x14(%rbp)
  cmpl   $0x7f,-0x14(%rbp)
  jle    L0
  mov    $0x100,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L0:
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x40,-0x14(%rbp)
  jle    L4
  movl   $0xffffffff,-0x8(%rbp)
  mov    $0x80,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    $0x100,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    -0x8(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int int_cos(int a) {
  int v, neg;
  a = a & ((1 << 8) - 1);
  if (a >= ((1 << 8) / 2))
    a = (1 << 8) - a;
  neg = 0;
  if (a > ((1 << 8) / 4)) {
    neg = -1;
    a = ((1 << 8) / 2) - a;
  }
  v = (1 << 8) - ((a * a) >> 4);
  v = (v ^ neg) - neg;
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<int_cos>:
  endbr64
  movzbl %dil,%eax
  mov    $0x100,%edx
  sub    %eax,%edx
  test   $0x80,%dil
  cmovne %edx,%eax
  mov    $0x0,%ecx
  cmp    $0x40,%eax
  jle    L6
  mov    $0x80,%edx
  sub    %eax,%edx
  mov    %edx,%eax
  mov    $0xffffffff,%ecx
L6:
  imul   %eax,%eax
  sar    $0x4,%eax
  mov    $0x100,%edx
  sub    %eax,%edx
  mov    %edx,%eax
  xor    %ecx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int int_cos(int a) {
  int v, neg;
  a = a & ((1 << 8) - 1);
  if (a >= ((1 << 8) / 2))
    a = (1 << 8) - a;
  neg = 0;
  if (a > ((1 << 8) / 4)) {
    neg = -1;
    a = ((1 << 8) / 2) - a;
  }
  v = (1 << 8) - ((a * a) >> 4);
  v = (v ^ neg) - neg;
  return v;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<int_cos>:
  endbr64
  movzbl %dil,%eax
  mov    $0x100,%edx
  sub    %eax,%edx
  and    $0x80,%edi
  cmovne %edx,%eax
  xor    %ecx,%ecx
  cmp    $0x40,%eax
  jle    L8
  mov    $0x80,%edx
  mov    $0xffffffff,%ecx
  sub    %eax,%edx
  mov    %edx,%eax
L8:
  imul   %eax,%eax
  mov    $0x100,%edx
  sar    $0x4,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  xor    %ecx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int int_cos(int a) {
  int v, neg;
  a = a & ((1 << 8) - 1);
  if (a >= ((1 << 8) / 2))
    a = (1 << 8) - a;
  neg = 0;
  if (a > ((1 << 8) / 4)) {
    neg = -1;
    a = ((1 << 8) / 2) - a;
  }
  v = (1 << 8) - ((a * a) >> 4);
  v = (v ^ neg) - neg;
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<int_cos>:
  endbr64
  movzbl %dil,%eax
  mov    $0x100,%edx
  sub    %eax,%edx
  and    $0x80,%edi
  cmovne %edx,%eax
  xor    %ecx,%ecx
  cmp    $0x40,%eax
  jle    L5
  mov    $0x80,%edx
  mov    $0xffffffff,%ecx
  sub    %eax,%edx
  mov    %edx,%eax
L5:
  imul   %eax,%eax
  mov    $0x100,%edx
  sar    $0x4,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  xor    %ecx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int int_cos(int a) {
  int v, neg;
  a = a & ((1 << 8) - 1);
  if (a >= ((1 << 8) / 2))
    a = (1 << 8) - a;
  neg = 0;
  if (a > ((1 << 8) / 4)) {
    neg = -1;
    a = ((1 << 8) / 2) - a;
  }
  v = (1 << 8) - ((a * a) >> 4);
  v = (v ^ neg) - neg;
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <MAIN__@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main_() {
  MAIN__();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main_>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <MAIN__@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main_() {
  MAIN__();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main_>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <MAIN__@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main_() {
  MAIN__();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main_>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <MAIN__@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main_() {
  MAIN__();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<zje_parse_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rax),%esi
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L132:
  cmp    %rdx,%rsp
  je     L129
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L132
L129:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L115
  orq    $0x0,-0x8(%rsp,%rax,1)
L115:
  mov    %rsp,%r12
  mov    %r13,%rcx
  lea    D6(%rip),%rdx
  mov    %rsp,%rdi
  call   <snprintf@plt>
  sub    $0x1,%ebx
  js     L163
  movslq %ebx,%rbx
L19:
  mov    %ebx,%r13d
  movsbl (%r12,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L152
  movb   $0x0,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L19
L163:
  mov    $0x0,%ebx
L90:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    %rbx,%rax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L152:
  test   %ebx,%ebx
  js     L141
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L90
  movslq %r13d,%rax
  movsbl (%r12,%rax,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L90
  movslq %r13d,%r13
  movzbl (%r12,%r13,1),%ecx
  sub    $0x42,%ecx
  cmp    $0x2b,%cl
  ja     L52
  mov    $0x1,%eax
  shl    %cl,%rax
  movabs $0x100000001,%rdx
  test   %rdx,%rax
  jne    L90
  movabs $0x80000000800,%rdx
  test   %rdx,%rax
  jne    L124
  movabs $0x20000000200,%rdx
  shl    $0xa,%rbx
  and    %rdx,%rax
  cmove  %rax,%rbx
  jmp    L90
L124:
  shl    $0x14,%rbx
  jmp    L90
L141:
  mov    $0x0,%ebx
  jmp    L90
L52:
  mov    $0x0,%ebx
  jmp    L90
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: %s

assistant: ```c
size_t zje_parse_bytes(const char *string) {
  int len = strlen(string);
  char str[len + 1];
  snprintf(str, len + 1, "%s", string);
  int pos = len - 1;
  for (; pos >= 0 && isspace(str[pos]); --pos) {
    str[pos] = '\0';
  }
  if (pos < 0) {
    return 0;
  }
  size_t bytes = strtol(str, NULL, 10);
  if (bytes == 0) {
    return 0;
  }
  if (isdigit(str[pos])) {
    return bytes;
  }
  switch (str[pos]) {
  case 'b':
  case 'B':
    break;
  case 'k':
  case 'K':
    bytes <<= 10;
    break;
  case 'm':
  case 'M':
    bytes <<= 20;
    break;
  default:
    return 0;
  }
  return bytes;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<zje_parse_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x1(%rax),%esi
  mov    %eax,%ebx
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L7
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L68
L7:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L100
L44:
  mov    %r13,%rcx
  lea    D4(%rip),%rdx
  mov    %rsp,%rdi
  mov    %rsp,%r12
  call   <snprintf@plt>
  lea    -0x1(%rbx),%eax
  movslq %eax,%rbx
  test   %eax,%eax
  jns    L146
  jmp    L131
  nopw   0x0(%rax,%rax,1)
L134:
  movb   $0x0,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  js     L131
L146:
  movsbl (%r12,%rbx,1),%edi
  movslq %ebx,%r13
  call   <isspace@plt>
  test   %rax,%rax
  jne    L134
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L131
  movsbl (%r12,%r13,1),%edi
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L152
  movzbl (%r12,%r13,1),%ecx
  sub    $0x42,%ecx
  cmp    $0x2b,%cl
  ja     L131
  mov    $0x1,%edx
  shl    %cl,%rdx
  movabs $0x100000001,%rcx
  test   %rcx,%rdx
  jne    L152
  movabs $0x80000000800,%rcx
  test   %rcx,%rdx
  jne    L15
  movabs $0x20000000200,%rax
  shl    $0xa,%rbx
  and    %rdx,%rax
  cmovne %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L152:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L85
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L131:
  xor    %eax,%eax
  jmp    L152
  nopl   0x0(%rax)
L100:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L44
L15:
  shl    $0x14,%rax
  jmp    L152
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %s

assistant: ```c
size_t zje_parse_bytes(const char *string) {
  int len = strlen(string);
  char str[len + 1];
  snprintf(str, len + 1, "%s", string);
  int pos = len - 1;
  for (; pos >= 0 && isspace(str[pos]); --pos) {
    str[pos] = '\0';
  }
  if (pos < 0) {
    return 0;
  }
  size_t bytes = strtol(str, NULL, 10);
  if (bytes == 0) {
    return 0;
  }
  if (isdigit(str[pos])) {
    return bytes;
  }
  switch (str[pos]) {
  case 'b':
  case 'B':
    break;
  case 'k':
  case 'K':
    bytes <<= 10;
    break;
  case 'm':
  case 'M':
    bytes <<= 20;
    break;
  default:
    return 0;
  }
  return bytes;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<zje_parse_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x1(%rax),%esi
  mov    %eax,%ebx
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L33
L98:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L98
L33:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L146
L91:
  mov    %r13,%rcx
  lea    D0(%rip),%rdx
  mov    %rsp,%rdi
  mov    %rsp,%r12
  call   <snprintf@plt>
  lea    -0x1(%rbx),%eax
  movslq %eax,%rbx
  test   %eax,%eax
  jns    L52
  jmp    L123
  nopw   0x0(%rax,%rax,1)
L14:
  movb   $0x0,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  js     L123
L52:
  movsbl (%r12,%rbx,1),%edi
  movslq %ebx,%r13
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L123
  movsbl (%r12,%r13,1),%edi
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L45
  movzbl (%r12,%r13,1),%ecx
  sub    $0x42,%ecx
  cmp    $0x2b,%cl
  ja     L123
  mov    $0x1,%edx
  shl    %cl,%rdx
  movabs $0x100000001,%rcx
  test   %rcx,%rdx
  jne    L45
  movabs $0x80000000800,%rcx
  test   %rcx,%rdx
  jne    L76
  movabs $0x20000000200,%rax
  shl    $0xa,%rbx
  and    %rdx,%rax
  cmovne %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L45:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L123:
  xor    %eax,%eax
  jmp    L45
  nopl   0x0(%rax)
L146:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L91
L76:
  shl    $0x14,%rax
  jmp    L45
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: %s

assistant: ```c
size_t zje_parse_bytes(const char *string) {
  int len = strlen(string);
  char str[len + 1];
  snprintf(str, len + 1, "%s", string);
  int pos = len - 1;
  for (; pos >= 0 && isspace(str[pos]); --pos) {
    str[pos] = '\0';
  }
  if (pos < 0) {
    return 0;
  }
  size_t bytes = strtol(str, NULL, 10);
  if (bytes == 0) {
    return 0;
  }
  if (isdigit(str[pos])) {
    return bytes;
  }
  switch (str[pos]) {
  case 'b':
  case 'B':
    break;
  case 'k':
  case 'K':
    bytes <<= 10;
    break;
  case 'm':
  case 'M':
    bytes <<= 20;
    break;
  default:
    return 0;
  }
  return bytes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd8(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int snprintf(char *str, size_t size, const char *format, ...) {
  int retval;
  va_list ap;
  va_start(ap, format);
  retval = vsprintf(str, format, ap);
  va_end(ap);
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<snprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int snprintf(char *str, size_t size, const char *format, ...) {
  int retval;
  va_list ap;
  va_start(ap, format);
  retval = vsprintf(str, format, ap);
  va_end(ap);
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<snprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rdx,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int snprintf(char *str, size_t size, const char *format, ...) {
  int retval;
  va_list ap;
  va_start(ap, format);
  retval = vsprintf(str, format, ap);
  va_end(ap);
  return retval;
}
```