ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<find>:
  endbr64
  mov    %rdi,%rax
  lea    0x190(%rdi),%rcx
  jmp    L31
L13:
  cmp    %sil,%dl
  je     L10
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L5
L31:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L13
L5:
  xor    %eax,%eax
L10:
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  int i;
  char *result = NULL;
  for (i = 0; i < 400 && haystack[i] != '\0'; i++) {
    if (haystack[i] == needle) {
      result = &haystack[i];
      break;
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find>:
  endbr64
  mov    %rdi,%rax
  lea    0x190(%rdi),%rcx
  jmp    L31
L3:
  cmp    %sil,%dl
  je     L12
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L1
L31:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L3
L1:
  xor    %eax,%eax
L12:
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  int i;
  char *result = NULL;
  for (i = 0; i < 400 && haystack[i] != '\0'; i++) {
    if (haystack[i] == needle) {
      result = &haystack[i];
      break;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<m_strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L4
  cmpq   $0x0,-0x20(%rbp)
  jne    L79
L4:
  mov    $0xffffffff,%eax
  jmp    L26
L79:
  movl   $0x0,-0xc(%rbp)
  jmp    L49
L51:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L117
  mov    -0x8(%rbp),%eax
  jmp    L26
L117:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L106
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L106
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L51
L106:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L127
  mov    $0x0,%eax
  jmp    L26
L127:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L83
  mov    -0x4(%rbp),%eax
  jmp    L26
L83:
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int m_strncmp(const char *s1, const char *s2, unsigned int max_len) {
  if (!s1 || !s2) {
    return -1;
  }
  unsigned int len = 0;
  while (*s1 && *s2 && len < max_len) {
    int diff = *s1 - *s2;
    if (diff != 0) {
      return diff;
    }
    s1++;
    s2++;
    len++;
  }
  if (len == max_len) {
    return 0;
  }
  int diff = *s1 - *s2;
  if (diff != 0) {
    return diff;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<m_strncmp>:
  endbr64
  test   %rdi,%rdi
  je     L82
  test   %rsi,%rsi
  je     L82
  movzbl (%rdi),%r9d
  test   %r9b,%r9b
  je     L91
  movzbl (%rsi),%ecx
  test   %edx,%edx
  je     L20
  test   %cl,%cl
  je     L20
  mov    $0x1,%r8d
L11:
  movsbl %r9b,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  jne    L114
  add    $0x1,%rsi
  mov    %r8d,%r10d
  movzbl (%rdi,%r8,1),%r9d
  test   %r9b,%r9b
  je     L56
  movzbl (%rsi),%ecx
  add    $0x1,%r8
  cmp    %r10d,%edx
  jbe    L56
  test   %cl,%cl
  jne    L11
L56:
  mov    $0x0,%eax
  cmp    %r10d,%edx
  je     L114
  movsbl %r9b,%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
L91:
  mov    $0x0,%r10d
  jmp    L56
L20:
  mov    $0x0,%r10d
  jmp    L56
L82:
  mov    $0xffffffff,%eax
L114:
  ret
```

assistant: ```c
int m_strncmp(const char *s1, const char *s2, unsigned int max_len) {
  if (!s1 || !s2) {
    return -1;
  }
  unsigned int len = 0;
  while (*s1 && *s2 && len < max_len) {
    int diff = *s1 - *s2;
    if (diff != 0) {
      return diff;
    }
    s1++;
    s2++;
    len++;
  }
  if (len == max_len) {
    return 0;
  }
  int diff = *s1 - *s2;
  if (diff != 0) {
    return diff;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<m_strncmp>:
  endbr64
  test   %rdi,%rdi
  je     L36
  test   %rsi,%rsi
  je     L36
  movzbl (%rdi),%r9d
  test   %r9b,%r9b
  je     L31
  movsbl (%rsi),%ecx
  test   %edx,%edx
  je     L31
  test   %cl,%cl
  je     L31
  mov    $0x1,%r8d
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl (%rdi,%r8,1),%r9d
  add    $0x1,%rsi
  mov    %r8d,%r10d
  test   %r9b,%r9b
  je     L81
  movsbl (%rsi),%ecx
  add    $0x1,%r8
  cmp    %r10d,%edx
  jbe    L81
  test   %cl,%cl
  je     L81
L51:
  movsbl %r9b,%eax
  sub    %ecx,%eax
  je     L26
L104:
  ret
L31:
  xor    %r10d,%r10d
  nopl   (%rax)
L81:
  xor    %eax,%eax
  cmp    %r10d,%edx
  je     L104
  movsbl (%rsi),%edx
  movsbl %r9b,%eax
  sub    %edx,%eax
  ret
L36:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int m_strncmp(const char *s1, const char *s2, unsigned int max_len) {
  if (!s1 || !s2) {
    return -1;
  }
  unsigned int len = 0;
  while (*s1 && *s2 && len < max_len) {
    int diff = *s1 - *s2;
    if (diff != 0) {
      return diff;
    }
    s1++;
    s2++;
    len++;
  }
  if (len == max_len) {
    return 0;
  }
  int diff = *s1 - *s2;
  if (diff != 0) {
    return diff;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<m_strncmp>:
  endbr64
  test   %rdi,%rdi
  je     L52
  test   %rsi,%rsi
  je     L52
  movzbl (%rdi),%r9d
  test   %r9b,%r9b
  je     L33
  movsbl (%rsi),%ecx
  test   %edx,%edx
  je     L33
  test   %cl,%cl
  je     L33
  mov    $0x1,%r8d
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L83:
  movzbl (%rdi,%r8,1),%r9d
  add    $0x1,%rsi
  mov    %r8d,%r10d
  test   %r9b,%r9b
  je     L63
  movsbl (%rsi),%ecx
  add    $0x1,%r8
  cmp    %r10d,%edx
  jbe    L63
  test   %cl,%cl
  je     L63
L57:
  movsbl %r9b,%eax
  sub    %ecx,%eax
  je     L83
L39:
  ret
L33:
  xor    %r10d,%r10d
  nopl   (%rax)
L63:
  xor    %eax,%eax
  cmp    %r10d,%edx
  je     L39
  movsbl (%rsi),%edx
  movsbl %r9b,%eax
  sub    %edx,%eax
  ret
L52:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int m_strncmp(const char *s1, const char *s2, unsigned int max_len) {
  if (!s1 || !s2) {
    return -1;
  }
  unsigned int len = 0;
  while (*s1 && *s2 && len < max_len) {
    int diff = *s1 - *s2;
    if (diff != 0) {
      return diff;
    }
    s1++;
    s2++;
    len++;
  }
  if (len == max_len) {
    return 0;
  }
  int diff = *s1 - *s2;
  if (diff != 0) {
    return diff;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D14(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D8(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0xc(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x8(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2ssl -0x4(%rbp),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: f32
name: read_data
arguments: data_tag: D8
datatype: f32
name: read_data
arguments: data_tag: D13
datatype: string

tool: D14: 1.5

tool: D8: 2

tool: D13: %f

assistant: ```c
int main(void) {
  float x, y;
  int i, j;
  x = 1.5;
  y = 2.0;
  i = 2;
  j = 4;
  x = x * y + (float)i / j;
  printf("%f", x);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D14(%rip),%xmm0
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_infered: byte[4]
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: {"D14": [0x00,0x00,0x60,0x40]}

tool: D10: %f

assistant: ```c
int main(void) {
  float x, y;
  int i, j;
  x = 1.5;
  y = 2.0;
  i = 2;
  j = 4;
  x = x * y + (float)i / j;
  printf("%f", x);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D13(%rip),%xmm0
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type: byte[4]
name: parse_data
arguments: label: D11
type: string

tool: {"D13": [0x00,0x00,0x60,0x40]}

tool: D11: %f

assistant: ```c
int main(void) {
  float x, y;
  int i, j;
  x = 1.5;
  y = 2.0;
  i = 2;
  j = 4;
  x = x * y + (float)i / j;
  printf("%f", x);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D10(%rip),%xmm0
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: byte[4]
name: parse_data
arguments: tag: D6
type_infered: string

tool: {"D10": [0x00,0x00,0x60,0x40]}

tool: D6: %f

assistant: ```c
int main(void) {
  float x, y;
  int i, j;
  x = 1.5;
  y = 2.0;
  i = 2;
  j = 4;
  x = x * y + (float)i / j;
  printf("%f", x);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L24
L46:
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L46
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x2b,%eax
  je     L5
  cmp    $0x2d,%eax
  jne    L57
  movl   $0x1,-0x4(%rbp)
L5:
  addq   $0x1,-0x18(%rbp)
L57:
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L29:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int atoi(const char *s) {
  int n, sign = -1;
  while (isspace(*s))
    ++s;
  switch (*s) {
  case '-':
    sign = 1;
  case '+':
    ++s;
  }
  for (n = 0; isdigit(*s); ++s)
    n = 10 * n - (*s - '0');
  return sign * n;
}
```
user: What is the c source code of the assembly code below:

```asm
<atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L60
L64:
  add    $0x1,%rbx
L60:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L64
  movzbl (%rbx),%eax
  cmp    $0x2b,%al
  je     L31
  mov    $0xffffffff,%r12d
  cmp    $0x2d,%al
  jne    L65
  mov    $0x1,%r12d
L40:
  add    $0x1,%rbx
L65:
  mov    $0x0,%ebp
  jmp    L66
L31:
  mov    $0xffffffff,%r12d
  jmp    L40
L39:
  lea    0x0(%rbp,%rbp,4),%ebp
  add    %ebp,%ebp
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  sub    %eax,%ebp
  add    $0x1,%rbx
L66:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
  mov    %ebp,%eax
  imul   %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int atoi(const char *s) {
  int n, sign = -1;
  while (isspace(*s))
    ++s;
  switch (*s) {
  case '-':
    sign = 1;
  case '+':
    ++s;
  }
  for (n = 0; isdigit(*s); ++s)
    n = 10 * n - (*s - '0');
  return sign * n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L21
  nopl   (%rax)
L41:
  add    $0x1,%rbx
L21:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
  movsbl (%rbx),%edi
  mov    $0xffffffff,%r12d
  cmp    $0x2b,%dil
  je     L7
  cmp    $0x2d,%dil
  jne    L11
  mov    $0x1,%r12d
L7:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L11:
  xor    %ebp,%ebp
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L35:
  movsbl (%rbx),%eax
  lea    0x0(%rbp,%rbp,4),%ebp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    %ebp,%ebp
  sub    $0x30,%eax
  sub    %eax,%ebp
L59:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L35
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  imul   %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int atoi(const char *s) {
  int n, sign = -1;
  while (isspace(*s))
    ++s;
  switch (*s) {
  case '-':
    sign = 1;
  case '+':
    ++s;
  }
  for (n = 0; isdigit(*s); ++s)
    n = 10 * n - (*s - '0');
  return sign * n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L27
  nopl   (%rax)
L11:
  add    $0x1,%rbx
L27:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L11
  movzbl (%rbx),%eax
  mov    $0xffffffff,%r12d
  cmp    $0x2b,%al
  je     L59
  cmp    $0x2d,%al
  jne    L22
  mov    $0x1,%r12d
L59:
  add    $0x1,%rbx
L22:
  xor    %ebp,%ebp
  jmp    L9
L14:
  movsbl (%rbx),%eax
  lea    0x0(%rbp,%rbp,4),%ebp
  add    $0x1,%rbx
  add    %ebp,%ebp
  sub    $0x30,%eax
  sub    %eax,%ebp
L9:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L14
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  imul   %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int atoi(const char *s) {
  int n, sign = -1;
  while (isspace(*s))
    ++s;
  switch (*s) {
  case '-':
    sign = 1;
  case '+':
    ++s;
  }
  for (n = 0; isdigit(*s); ++s)
    n = 10 * n - (*s - '0');
  return sign * n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf_s@plt>
  movl   $0x2,-0x18(%rbp)
  jmp    L61
L25:
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x10(%rbp)
  jmp    L24
L16:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L54
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L54:
  addl   $0x1,-0x10(%rbp)
L24:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x10(%rbp)
  jle    L16
L55:
  cmpl   $0x1,-0xc(%rbp)
  jne    L71
  mov    -0x18(%rbp),%eax
  add    %eax,-0x14(%rbp)
L71:
  addl   $0x1,-0x18(%rbp)
L61:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L25
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D18
type_infered: string
name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D1
type_infered: string
name: read_data
arguments: label: D13
type_infered: string

tool: D18: Enter the number : 

tool: D6: %d

tool: D1: Sum = %d



tool: D13: pause

assistant: ```c
int main() {
  int number, i, sum = 0, k, flag;
  printf("Enter the number : ");
  scanf_s("%d", &number);
  for (i = 2; i <= number; i++) {
    flag = 1;
    for (k = 2; k <= i / 2; k++) {
      if (i % k == 0) {
        flag = 0;
        break;
      }
    }
    if (flag == 1) {
      sum = sum + i;
    }
  }
  printf("Sum = %d\n\n", sum);
  system("pause");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%r8d
  cmp    $0x1,%r8d
  jle    L52
  add    $0x1,%r8d
  mov    $0x0,%r9d
  mov    $0x2,%esi
  jmp    L24
L52:
  mov    $0x0,%r9d
L6:
  mov    %r9d,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  add    %esi,%r9d
L33:
  add    $0x1,%esi
  cmp    %esi,%r8d
  je     L6
L24:
  mov    %esi,%edi
  shr    $0x1f,%edi
  add    %esi,%edi
  sar    %edi
  cmp    $0x3,%esi
  jle    L4
  test   $0x1,%sil
  je     L33
  mov    $0x2,%ecx
L42:
  add    $0x1,%ecx
  cmp    %edi,%ecx
  jg     L4
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L42
  jmp    L33
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
data_type: string
name: parse_data
arguments: data_tag: D34
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D24
data_type: string

tool: D26: Enter the number : 

tool: D34: %d

tool: D27: Sum = %d



tool: D24: pause

assistant: ```c
int main() {
  int number, i, sum = 0, k, flag;
  printf("Enter the number : ");
  scanf_s("%d", &number);
  for (i = 2; i <= number; i++) {
    flag = 1;
    for (k = 2; k <= i / 2; k++) {
      if (i % k == 0) {
        flag = 0;
        break;
      }
    }
    if (flag == 1) {
      sum = sum + i;
    }
  }
  printf("Sum = %d\n\n", sum);
  system("pause");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%r8d
  cmp    $0x1,%r8d
  jle    L86
  add    $0x1,%r8d
  xor    %r9d,%r9d
  mov    $0x2,%esi
  nopl   0x0(%rax)
L68:
  mov    %esi,%edi
  sar    %edi
  cmp    $0x1,%edi
  je     L5
  test   $0x1,%sil
  je     L31
  add    $0x1,%edi
  mov    $0x2,%ecx
  jmp    L11
  nopl   0x0(%rax)
L59:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L31
L11:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L59
L5:
  add    %esi,%r9d
L31:
  add    $0x1,%esi
  cmp    %r8d,%esi
  jne    L68
L29:
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  mov    %r9d,%esi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L86:
  xor    %r9d,%r9d
  jmp    L29
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D31
data_type: string
name: read_data
arguments: tag: D9
data_type: string
name: read_data
arguments: tag: D35
data_type: string
name: read_data
arguments: tag: D28
data_type: string

tool: D31: Enter the number : 

tool: D9: %d

tool: D35: Sum = %d



tool: D28: pause

assistant: ```c
int main() {
  int number, i, sum = 0, k, flag;
  printf("Enter the number : ");
  scanf_s("%d", &number);
  for (i = 2; i <= number; i++) {
    flag = 1;
    for (k = 2; k <= i / 2; k++) {
      if (i % k == 0) {
        flag = 0;
        break;
      }
    }
    if (flag == 1) {
      sum = sum + i;
    }
  }
  printf("Sum = %d\n\n", sum);
  system("pause");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%r8d
  cmp    $0x1,%r8d
  jle    L71
  add    $0x1,%r8d
  xor    %r9d,%r9d
  mov    $0x2,%esi
  nopl   0x0(%rax)
L53:
  mov    %esi,%edi
  sar    %edi
  cmp    $0x1,%edi
  je     L40
  test   $0x1,%sil
  je     L12
  add    $0x1,%edi
  mov    $0x2,%ecx
  jmp    L31
  nopl   0x0(%rax)
L57:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L12
L31:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L57
L40:
  add    %esi,%r9d
L12:
  add    $0x1,%esi
  cmp    %r8d,%esi
  jne    L53
L69:
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  mov    %r9d,%esi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L71:
  xor    %r9d,%r9d
  jmp    L69
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string
name: retrieve_data
arguments: data_tag: D30
type_infered: string
name: retrieve_data
arguments: data_tag: D38
type_infered: string

tool: D23: Enter the number : 

tool: D0: %d

tool: D30: Sum = %d



tool: D38: pause

assistant: ```c
int main() {
  int number, i, sum = 0, k, flag;
  printf("Enter the number : ");
  scanf_s("%d", &number);
  for (i = 2; i <= number; i++) {
    flag = 1;
    for (k = 2; k <= i / 2; k++) {
      if (i % k == 0) {
        flag = 0;
        break;
      }
    }
    if (flag == 1) {
      sum = sum + i;
    }
  }
  printf("Sum = %d\n\n", sum);
  system("pause");
}
```
user: What is the c source code of the assembly code below?

```asm
<gnu_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L5
L13:
  mov    -0x18(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
const char *gnu_basename(const char *filename) {
  char *p = strrchr(filename, '/');
  return p ? p + 1 : (char *)filename;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gnu_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *gnu_basename(const char *filename) {
  char *p = strrchr(filename, '/');
  return p ? p + 1 : (char *)filename;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gnu_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *gnu_basename(const char *filename) {
  char *p = strrchr(filename, '/');
  return p ? p + 1 : (char *)filename;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gnu_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *gnu_basename(const char *filename) {
  char *p = strrchr(filename, '/');
  return p ? p + 1 : (char *)filename;
}
```
user: Translate the below assembly code into C programming language:

```asm
<opentrace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
opentrace() {
  char s[100];
  char *p;
  char *getenv();
  int flags;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<opentrace>:
  endbr64
  ret
```

assistant: ```c
opentrace() {
  char s[100];
  char *p;
  char *getenv();
  int flags;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<opentrace>:
  endbr64
  ret
```

assistant: ```c
opentrace() {
  char s[100];
  char *p;
  char *getenv();
  int flags;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<opentrace>:
  endbr64
  ret
```

assistant: ```c
opentrace() {
  char s[100];
  char *p;
  char *getenv();
  int flags;
}
```