ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encode4b6b>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  movl   $0x0,(%rcx)
  add    %esi,%esi
  je     L62
  mov    %rdi,%r15
  mov    %rcx,%r13
  mov    %esi,%r14d
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L65
L34:
  mov    %eax,%eax
  movzbl (%r15,%rax,1),%edi
  shr    $0x4,%dil
  jmp    L47
L13:
  mov    %eax,%r12d
L77:
  add    $0x1,%ebp
  cmp    %r14d,%ebp
  je     L2
L65:
  mov    %ebp,%eax
  shr    %eax
  test   $0x1,%bpl
  je     L34
  mov    %eax,%eax
  movzbl (%r15,%rax,1),%edi
  and    $0xf,%edi
L47:
  movsbl %dil,%edi
  call   <get4b6bsymbol@plt>
  shl    $0x6,%ebx
  movzwl %bx,%ebx
  movsbl %al,%eax
  or     %eax,%ebx
  lea    0x6(%r12),%eax
  cmp    $0x7,%eax
  jle    L13
  sub    $0x2,%r12d
  mov    0x0(%r13),%eax
  mov    %ebx,%edx
  mov    %r12d,%ecx
  sar    %cl,%edx
  mov    0x8(%rsp),%rsi
  mov    %dl,(%rsi,%rax,1)
  addl   $0x1,0x0(%r13)
  mov    $0x1,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  and    %eax,%ebx
  jmp    L77
L2:
  test   %r12d,%r12d
  je     L62
  mov    $0x1,%eax
  mov    %r12d,%ecx
  shl    %cl,%eax
  sub    $0x1,%eax
  and    %ebx,%eax
  mov    0x0(%r13),%edx
  mov    $0x8,%ecx
  sub    %r12d,%ecx
  shl    %cl,%eax
  mov    0x8(%rsp),%rsi
  mov    %al,(%rsi,%rdx,1)
  addl   $0x1,0x0(%r13)
L62:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void encode4b6b(char *messageIn, unsigned int bytesIn, char *messageOut, unsigned int *bytesOut) {
  unsigned int i, j;
  int intBuffer;
  int mask;
  int intBitsAvailable;
  char symbol;
  *bytesOut = 0;
  intBitsAvailable = 0;
  intBuffer = 0;
  for (i = 0; i < bytesIn * 2; i++) {
    j = i >> 1;
    if (j * 2 == i) {
      symbol = (messageIn[j] >> 4) & 0x0F;
    } else {
      symbol = messageIn[j] & 0x0F;
    }
    symbol = get4b6bsymbol(symbol);
    intBuffer = (intBuffer << 6) & 0xFFC0;
    intBuffer = intBuffer | symbol;
    intBitsAvailable += 6;
    if (intBitsAvailable >= 8) {
      symbol = intBuffer >> (intBitsAvailable - 8);
      messageOut[*bytesOut] = symbol;
      (*bytesOut)++;
      intBitsAvailable -= 8;
      mask = (1 << intBitsAvailable) - 1;
      intBuffer = intBuffer & mask;
    }
  }
  if (intBitsAvailable != 0) {
    mask = (1 << intBitsAvailable) - 1;
    intBuffer = intBuffer & mask;
    intBuffer = intBuffer << (8 - intBitsAvailable);
    symbol = intBuffer & 0x00FF;
    messageOut[*bytesOut] = symbol;
    (*bytesOut)++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encode4b6b>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,(%rcx)
  mov    %rdx,0x8(%rsp)
  add    %esi,%esi
  je     L23
  mov    %rdi,%r12
  mov    %rcx,%rbx
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  mov    %esi,%ebp
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L52:
  sub    $0x2,%r14d
  mov    (%rbx),%eax
  mov    %r15d,%esi
  mov    0x8(%rsp),%rdx
  mov    %r14d,%ecx
  add    $0x1,%r13d
  sar    %cl,%esi
  mov    %sil,(%rdx,%rax,1)
  mov    $0x1,%eax
  shl    %cl,%eax
  addl   $0x1,(%rbx)
  sub    $0x1,%eax
  and    %eax,%r15d
  cmp    %ebp,%r13d
  je     L3
L8:
  mov    %r13d,%eax
  shr    %eax
  mov    %eax,%esi
  add    %eax,%eax
  movzbl (%r12,%rsi,1),%edi
  mov    %edi,%esi
  and    $0xf,%edi
  shr    $0x4,%sil
  cmp    %r13d,%eax
  cmove  %esi,%edi
  shl    $0x6,%r15d
  movzwl %r15w,%r15d
  movsbl %dil,%edi
  call   <get4b6bsymbol@plt>
  movsbl %al,%eax
  or     %eax,%r15d
  lea    0x6(%r14),%eax
  cmp    $0x7,%eax
  jg     L52
  add    $0x1,%r13d
  mov    %eax,%r14d
  cmp    %ebp,%r13d
  jne    L8
L3:
  test   %r14d,%r14d
  je     L23
  mov    %r14d,%ecx
  mov    $0x1,%eax
  mov    $0x8,%edx
  mov    (%rbx),%esi
  shl    %cl,%eax
  sub    %r14d,%edx
  sub    $0x1,%eax
  mov    %edx,%ecx
  mov    0x8(%rsp),%rdx
  and    %r15d,%eax
  shl    %cl,%eax
  mov    %al,(%rdx,%rsi,1)
  addl   $0x1,(%rbx)
L23:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void encode4b6b(char *messageIn, unsigned int bytesIn, char *messageOut, unsigned int *bytesOut) {
  unsigned int i, j;
  int intBuffer;
  int mask;
  int intBitsAvailable;
  char symbol;
  *bytesOut = 0;
  intBitsAvailable = 0;
  intBuffer = 0;
  for (i = 0; i < bytesIn * 2; i++) {
    j = i >> 1;
    if (j * 2 == i) {
      symbol = (messageIn[j] >> 4) & 0x0F;
    } else {
      symbol = messageIn[j] & 0x0F;
    }
    symbol = get4b6bsymbol(symbol);
    intBuffer = (intBuffer << 6) & 0xFFC0;
    intBuffer = intBuffer | symbol;
    intBitsAvailable += 6;
    if (intBitsAvailable >= 8) {
      symbol = intBuffer >> (intBitsAvailable - 8);
      messageOut[*bytesOut] = symbol;
      (*bytesOut)++;
      intBitsAvailable -= 8;
      mask = (1 << intBitsAvailable) - 1;
      intBuffer = intBuffer & mask;
    }
  }
  if (intBitsAvailable != 0) {
    mask = (1 << intBitsAvailable) - 1;
    intBuffer = intBuffer & mask;
    intBuffer = intBuffer << (8 - intBitsAvailable);
    symbol = intBuffer & 0x00FF;
    messageOut[*bytesOut] = symbol;
    (*bytesOut)++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<encode4b6b>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,(%rcx)
  mov    %rdx,0x8(%rsp)
  add    %esi,%esi
  je     L55
  mov    %rdi,%r12
  mov    %rcx,%rbx
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  mov    %esi,%ebp
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L46:
  sub    $0x2,%r14d
  mov    (%rbx),%eax
  mov    %r15d,%esi
  mov    0x8(%rsp),%rdx
  mov    %r14d,%ecx
  add    $0x1,%r13d
  sar    %cl,%esi
  mov    %sil,(%rdx,%rax,1)
  mov    $0x1,%eax
  shl    %cl,%eax
  addl   $0x1,(%rbx)
  sub    $0x1,%eax
  and    %eax,%r15d
  cmp    %ebp,%r13d
  je     L47
L51:
  mov    %r13d,%eax
  shr    %eax
  mov    %eax,%esi
  add    %eax,%eax
  movzbl (%r12,%rsi,1),%edi
  mov    %edi,%esi
  and    $0xf,%edi
  shr    $0x4,%sil
  cmp    %r13d,%eax
  cmove  %esi,%edi
  shl    $0x6,%r15d
  movzwl %r15w,%r15d
  movsbl %dil,%edi
  call   <get4b6bsymbol@plt>
  movsbl %al,%eax
  or     %eax,%r15d
  lea    0x6(%r14),%eax
  cmp    $0x7,%eax
  jg     L46
  add    $0x1,%r13d
  mov    %eax,%r14d
  cmp    %ebp,%r13d
  jne    L51
L47:
  test   %r14d,%r14d
  je     L55
  mov    %r14d,%ecx
  mov    $0x1,%eax
  mov    $0x8,%edx
  mov    (%rbx),%esi
  shl    %cl,%eax
  sub    %r14d,%edx
  sub    $0x1,%eax
  mov    %edx,%ecx
  mov    0x8(%rsp),%rdx
  and    %r15d,%eax
  shl    %cl,%eax
  mov    %al,(%rdx,%rsi,1)
  addl   $0x1,(%rbx)
L55:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void encode4b6b(char *messageIn, unsigned int bytesIn, char *messageOut, unsigned int *bytesOut) {
  unsigned int i, j;
  int intBuffer;
  int mask;
  int intBitsAvailable;
  char symbol;
  *bytesOut = 0;
  intBitsAvailable = 0;
  intBuffer = 0;
  for (i = 0; i < bytesIn * 2; i++) {
    j = i >> 1;
    if (j * 2 == i) {
      symbol = (messageIn[j] >> 4) & 0x0F;
    } else {
      symbol = messageIn[j] & 0x0F;
    }
    symbol = get4b6bsymbol(symbol);
    intBuffer = (intBuffer << 6) & 0xFFC0;
    intBuffer = intBuffer | symbol;
    intBitsAvailable += 6;
    if (intBitsAvailable >= 8) {
      symbol = intBuffer >> (intBitsAvailable - 8);
      messageOut[*bytesOut] = symbol;
      (*bytesOut)++;
      intBitsAvailable -= 8;
      mask = (1 << intBitsAvailable) - 1;
      intBuffer = intBuffer & mask;
    }
  }
  if (intBitsAvailable != 0) {
    mask = (1 << intBitsAvailable) - 1;
    intBuffer = intBuffer & mask;
    intBuffer = intBuffer << (8 - intBitsAvailable);
    symbol = intBuffer & 0x00FF;
    messageOut[*bytesOut] = symbol;
    (*bytesOut)++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bsSignExpandArray64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L17:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  sub    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bsSignExpandArray64(int64_t val[], size_t numValues, unsigned numBits) {
  int64_t m = ((int64_t)1) << (numBits - 1);
  size_t i;
  for (i = 0; i < numValues; ++i)
    val[i] = (val[i] ^ m) - m;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bsSignExpandArray64>:
  endbr64
  lea    -0x1(%rdx),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%ecx
  test   %rsi,%rsi
  je     L19
  mov    %rdi,%rax
  lea    (%rdi,%rsi,4),%rsi
L18:
  mov    %ecx,%edx
  xor    (%rax),%edx
  sub    %ecx,%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L18
L19:
  ret
```

assistant: ```c
void bsSignExpandArray64(int64_t val[], size_t numValues, unsigned numBits) {
  int64_t m = ((int64_t)1) << (numBits - 1);
  size_t i;
  for (i = 0; i < numValues; ++i)
    val[i] = (val[i] ^ m) - m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bsSignExpandArray64>:
  endbr64
  lea    -0x1(%rdx),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  test   %rsi,%rsi
  je     L8
  lea    (%rdi,%rsi,4),%rcx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  xor    %edx,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rcx,%rdi
  jne    L1
L8:
  ret
```

assistant: ```c
void bsSignExpandArray64(int64_t val[], size_t numValues, unsigned numBits) {
  int64_t m = ((int64_t)1) << (numBits - 1);
  size_t i;
  for (i = 0; i < numValues; ++i)
    val[i] = (val[i] ^ m) - m;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bsSignExpandArray64>:
  endbr64
  lea    -0x1(%rdx),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%ecx
  test   %rsi,%rsi
  je     L22
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L44
  mov    %rsi,%rdx
  movd   %ecx,%xmm2
  mov    %rdi,%rax
  shr    $0x2,%rdx
  pshufd $0x0,%xmm2,%xmm1
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax)
L10:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pxor   %xmm1,%xmm0
  psubd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L10
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%sil
  je     L20
L6:
  lea    0x0(,%rax,4),%r8
  lea    (%rdi,%r8,1),%r9
  mov    (%r9),%edx
  xor    %ecx,%edx
  sub    %ecx,%edx
  mov    %edx,(%r9)
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rsi
  jbe    L22
  lea    0x4(%rdi,%r8,1),%r9
  add    $0x2,%rax
  mov    (%r9),%edx
  xor    %ecx,%edx
  sub    %ecx,%edx
  mov    %edx,(%r9)
  cmp    %rax,%rsi
  jbe    L22
  lea    0x8(%rdi,%r8,1),%rdx
  mov    (%rdx),%eax
  xor    %ecx,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdx)
L22:
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  ret
L44:
  xor    %eax,%eax
  jmp    L6
```

assistant: ```c
void bsSignExpandArray64(int64_t val[], size_t numValues, unsigned numBits) {
  int64_t m = ((int64_t)1) << (numBits - 1);
  size_t i;
  for (i = 0; i < numValues; ++i)
    val[i] = (val[i] ^ m) - m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L27
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L27:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L6
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <radixsort@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D25
type: string
name: read_data
arguments: label: D21
type: string
name: read_data
arguments: label: D48
type: string
name: read_data
arguments: label: D6
type: string
name: read_data
arguments: label: D11
type: string

tool: D25: Enter total elements: 

tool: D21: %d

tool: D48: Enter %d Elements: 

tool: D6: 
ARRAY  : 

tool: D11: 
SORTED : 

assistant: ```c
int main() {
  int i, n;
  printf("Enter total elements: ");
  scanf("%d", &n);
  int *arr = (int *)malloc(n * sizeof(int));
  printf("Enter %d Elements: ", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("\nARRAY  : ");
  print(arr, n);
  radixsort(arr, n);
  printf("\nSORTED : ");
  print(&arr[0], n);
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L25
  mov    %r13,%rbp
  mov    $0x0,%ebx
  lea    D25(%rip),%r12
L22:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jg     L22
L25:
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <print@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <radixsort@plt>
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <print@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D53
type_infered: string
name: retrieve_data
arguments: data_tag: D25
type_infered: string
name: retrieve_data
arguments: data_tag: D26
type_infered: string
name: retrieve_data
arguments: data_tag: D54
type_infered: string
name: retrieve_data
arguments: data_tag: D35
type_infered: string

tool: D53: Enter total elements: 

tool: D25: %d

tool: D26: Enter %d Elements: 

tool: D54: 
ARRAY  : 

tool: D35: 
SORTED : 

assistant: ```c
int main() {
  int i, n;
  printf("Enter total elements: ");
  scanf("%d", &n);
  int *arr = (int *)malloc(n * sizeof(int));
  printf("Enter %d Elements: ", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("\nARRAY  : ");
  print(arr, n);
  radixsort(arr, n);
  printf("\nSORTED : ");
  print(&arr[0], n);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%rdi
  push   %r12
  lea    D48(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L10
  mov    %r13,%rbp
  xor    %ebx,%ebx
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L14
L10:
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <print@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <radixsort@plt>
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <print@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D48
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string

tool: D15: Enter total elements: 

tool: D48: %d

tool: D4: Enter %d Elements: 

tool: D21: 
ARRAY  : 

tool: D36: 
SORTED : 

assistant: ```c
int main() {
  int i, n;
  printf("Enter total elements: ");
  scanf("%d", &n);
  int *arr = (int *)malloc(n * sizeof(int));
  printf("Enter %d Elements: ", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("\nARRAY  : ");
  print(arr, n);
  radixsort(arr, n);
  printf("\nSORTED : ");
  print(&arr[0], n);
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%rdi
  push   %r12
  lea    D37(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%esi
  lea    D30(%rip),%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L21
  mov    %r13,%rbp
  xor    %ebx,%ebx
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L8
L21:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <print@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <radixsort@plt>
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <print@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string
name: read_data
arguments: data_tag: D37
data_type: string
name: read_data
arguments: data_tag: D30
data_type: string
name: read_data
arguments: data_tag: D10
data_type: string
name: read_data
arguments: data_tag: D22
data_type: string

tool: D0: Enter total elements: 

tool: D37: %d

tool: D30: Enter %d Elements: 

tool: D10: 
ARRAY  : 

tool: D22: 
SORTED : 

assistant: ```c
int main() {
  int i, n;
  printf("Enter total elements: ");
  scanf("%d", &n);
  int *arr = (int *)malloc(n * sizeof(int));
  printf("Enter %d Elements: ", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("\nARRAY  : ");
  print(arr, n);
  radixsort(arr, n);
  printf("\nSORTED : ");
  print(&arr[0], n);
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L7
L9:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0x0,%eax
  jmp    L34
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x10(%rbp),%rdx
  sub    $0x1,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  sub    %edx,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 == *s2++)
    if (*s1++ == '\0')
      return (0);
  return (*(const unsigned char *)s1 - *(const unsigned char *)(s2 - 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  mov    $0x0,%eax
L13:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L2
  add    $0x1,%rax
  test   %dl,%dl
  jne    L13
  mov    $0x0,%eax
  ret
L2:
  movzbl %dl,%eax
  movzbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 == *s2++)
    if (*s1++ == '\0')
      return (0);
  return (*(const unsigned char *)s1 - *(const unsigned char *)(s2 - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rax
  test   %dl,%dl
  je     L25
L13:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L27
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 == *s2++)
    if (*s1++ == '\0')
      return (0);
  return (*(const unsigned char *)s1 - *(const unsigned char *)(s2 - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  test   %dl,%dl
  je     L14
L5:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L1
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 == *s2++)
    if (*s1++ == '\0')
      return (0);
  return (*(const unsigned char *)s1 - *(const unsigned char *)(s2 - 1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L18
L2:
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long strlen(const char *s) {
  unsigned long count = 0;
  for (; *s != '\0'; ++count) {
    ;
  }
  return count;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L16
L8:
  jmp    L8
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long strlen(const char *s) {
  unsigned long count = 0;
  for (; *s != '\0'; ++count) {
    ;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
L10:
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long strlen(const char *s) {
  unsigned long count = 0;
  for (; *s != '\0'; ++count) {
    ;
  }
  return count;
}
```