ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<strleft>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jl     L25
  test   %ebp,%ebp
  jle    L36
  lea    0x1(%r12),%rsi
  mov    %rbx,%rdx
  lea    -0x1(%rbp),%eax
  mov    %ebp,%ecx
  sub    %rsi,%rdx
  cmp    $0xe,%rdx
  jbe    L3
  cmp    $0x6,%eax
  jbe    L3
  cmp    $0xe,%eax
  jbe    L147
  mov    %ebp,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
  nop
L9:
  movdqu (%r12,%rax,1),%xmm0
  movups %xmm0,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L9
  mov    %ebp,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%ebp
  je     L63
  mov    %ebp,%ecx
  sub    %edx,%ecx
  lea    -0x1(%rcx),%esi
  cmp    $0x6,%esi
  jbe    L130
L15:
  mov    (%r12,%rdx,1),%rsi
  mov    %rsi,(%rbx,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L63
L130:
  movslq %eax,%rdx
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L63
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%ebp
  jle    L63
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%ebp
  jle    L63
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%ebp
  jle    L63
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%ebp
  jle    L63
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  cmp    %eax,%ebp
  jle    L63
  cltq
  movzbl (%r12,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
L63:
  movslq %ebp,%rbp
  add    %rbp,%rbx
L36:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movb   $0x0,(%rbx)
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L3:
  mov    %ebp,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L62:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L62
  movslq %ebp,%rbp
  add    %rbp,%rbx
  jmp    L36
L147:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
int strleft(char *dst, char *src, int chars) {
  int i, src_len;
  src_len = strlen(src);
  if (chars > src_len) {
    dst[0] = '\0';
    return (-1);
  }
  for (i = 0; i < chars; i++) {
    dst[i] = src[i];
  }
  dst[i] = '\0';
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<opposite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fits_k_bits@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <min_int@plt>
  cmp    %eax,-0x4(%rbp)
  sete   %al
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  neg    %eax
  leave
  ret
```

assistant: ```c
int64_t opposite(int64_t x, uint32_t k, bool *overflow) {
  assert(fits_k_bits(x, k));
  *overflow = (x == min_int(k));
  return -x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<opposite>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %rdx,%r12
  call   <fits_k_bits@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <min_int@plt>
  cmp    %ebx,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%r12)
  mov    %ebx,%eax
  neg    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int64_t opposite(int64_t x, uint32_t k, bool *overflow) {
  assert(fits_k_bits(x, k));
  *overflow = (x == min_int(k));
  return -x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<opposite>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  call   <fits_k_bits@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <min_int@plt>
  cmp    %ebx,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%r12)
  mov    %ebx,%eax
  pop    %rbx
  neg    %eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int64_t opposite(int64_t x, uint32_t k, bool *overflow) {
  assert(fits_k_bits(x, k));
  *overflow = (x == min_int(k));
  return -x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<opposite>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  call   <fits_k_bits@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <min_int@plt>
  cmp    %ebx,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%r12)
  mov    %ebx,%eax
  pop    %rbx
  neg    %eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int64_t opposite(int64_t x, uint32_t k, bool *overflow) {
  assert(fits_k_bits(x, k));
  *overflow = (x == min_int(k));
  return -x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adjust_blocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L32
  mov    -0x8(%rbp),%rax
  jmp    L27
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L24
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  cltq
  imul   -0x8(%rbp),%rax
  jmp    L27
L24:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  movslq %eax,%rsi
  mov    %rcx,%rax
  cqto
  idiv   %rsi
L27:
  pop    %rbp
  ret
```

assistant: ```c
long adjust_blocks(blocks, fromsize, tosize)
long blocks;
int fromsize, tosize;
{
  if (fromsize == tosize)
    return blocks;
  else if (fromsize > tosize)
    return blocks * (fromsize / tosize);
  else
    return (blocks + 1) / (tosize / fromsize);
}
```
user: Translate the below assembly code into C programming language:

```asm
<adjust_blocks>:
  endbr64
  mov    %edx,%ecx
  mov    %rdi,%rax
  cmp    %edx,%esi
  je     L4
  jle    L10
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cltq
  imul   %rdi,%rax
  ret
L10:
  add    $0x1,%rdi
  mov    %edx,%eax
  cltd
  idiv   %esi
  movslq %eax,%rcx
  mov    %rdi,%rax
  cqto
  idiv   %rcx
L4:
  ret
```

assistant: ```c
long adjust_blocks(blocks, fromsize, tosize)
long blocks;
int fromsize, tosize;
{
  if (fromsize == tosize)
    return blocks;
  else if (fromsize > tosize)
    return blocks * (fromsize / tosize);
  else
    return (blocks + 1) / (tosize / fromsize);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<adjust_blocks>:
  endbr64
  mov    %edx,%ecx
  mov    %rdi,%r8
  cmp    %edx,%esi
  je     L4
  jle    L6
  mov    %esi,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rsi
  imul   %rsi,%r8
L4:
  mov    %r8,%rax
  ret
  nop
L6:
  mov    %edx,%eax
  add    $0x1,%r8
  cltd
  idiv   %esi
  movslq %eax,%rcx
  mov    %r8,%rax
  cqto
  idiv   %rcx
  mov    %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long adjust_blocks(blocks, fromsize, tosize)
long blocks;
int fromsize, tosize;
{
  if (fromsize == tosize)
    return blocks;
  else if (fromsize > tosize)
    return blocks * (fromsize / tosize);
  else
    return (blocks + 1) / (tosize / fromsize);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<adjust_blocks>:
  endbr64
  mov    %edx,%ecx
  mov    %rdi,%r8
  cmp    %edx,%esi
  je     L2
  jle    L15
  mov    %esi,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rsi
  imul   %rsi,%r8
L2:
  mov    %r8,%rax
  ret
  nop
L15:
  mov    %edx,%eax
  add    $0x1,%r8
  cltd
  idiv   %esi
  movslq %eax,%rcx
  mov    %r8,%rax
  cqto
  idiv   %rcx
  mov    %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long adjust_blocks(blocks, fromsize, tosize)
long blocks;
int fromsize, tosize;
{
  if (fromsize == tosize)
    return blocks;
  else if (fromsize > tosize)
    return blocks * (fromsize / tosize);
  else
    return (blocks + 1) / (tosize / fromsize);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dm_msf_to_lba>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x3c,%eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  sub    %rax,%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  cmpl   $0x59,-0x14(%rbp)
  jle    L5
  cmpl   $0x0,-0x20(%rbp)
  je     L28
L5:
  subq   $0x96,-0x8(%rbp)
  jmp    L3
L28:
  subq   $0x6de66,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int dm_msf_to_lba(int m, int s, int f, int force_positive) {
  long ret = (m * 60 + s);
  ret *= 75;
  ret += f;
  if (m < 90 || force_positive)
    ret -= 150;
  else
    ret -= 450150;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dm_msf_to_lba>:
  endbr64
  imul   $0x3c,%edi,%eax
  add    %esi,%eax
  cltq
  lea    (%rax,%rax,4),%rsi
  mov    %rsi,%rax
  shl    $0x4,%rax
  sub    %rsi,%rax
  movslq %edx,%rdx
  add    %rax,%rdx
  cmp    $0x59,%edi
  jle    L6
  test   %ecx,%ecx
  setne  %cl
  lea    -0x6de66(%rdx),%rax
  test   %cl,%cl
  je     L18
L6:
  lea    -0x96(%rdx),%rax
L18:
  ret
```

assistant: ```c
int dm_msf_to_lba(int m, int s, int f, int force_positive) {
  long ret = (m * 60 + s);
  ret *= 75;
  ret += f;
  if (m < 90 || force_positive)
    ret -= 150;
  else
    ret -= 450150;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dm_msf_to_lba>:
  endbr64
  imul   $0x3c,%edi,%eax
  movslq %edx,%rdx
  add    %esi,%eax
  cltq
  lea    (%rax,%rax,4),%rsi
  mov    %rsi,%rax
  shl    $0x4,%rax
  sub    %rsi,%rax
  add    %rax,%rdx
  cmp    $0x59,%edi
  jle    L8
  test   %ecx,%ecx
  lea    -0x6de66(%rdx),%rax
  setne  %cl
  test   %cl,%cl
  jne    L8
  ret
  nopl   (%rax)
L8:
  lea    -0x96(%rdx),%rax
  ret
```

assistant: ```c
int dm_msf_to_lba(int m, int s, int f, int force_positive) {
  long ret = (m * 60 + s);
  ret *= 75;
  ret += f;
  if (m < 90 || force_positive)
    ret -= 150;
  else
    ret -= 450150;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<dm_msf_to_lba>:
  endbr64
  imul   $0x3c,%edi,%eax
  movslq %edx,%rdx
  add    %esi,%eax
  cltq
  lea    (%rax,%rax,4),%rsi
  mov    %rsi,%rax
  shl    $0x4,%rax
  sub    %rsi,%rax
  add    %rax,%rdx
  cmp    $0x59,%edi
  jle    L13
  test   %ecx,%ecx
  lea    -0x6de66(%rdx),%rax
  setne  %cl
  test   %cl,%cl
  jne    L13
  ret
  nopl   (%rax)
L13:
  lea    -0x96(%rdx),%rax
  ret
```

assistant: ```c
int dm_msf_to_lba(int m, int s, int f, int force_positive) {
  long ret = (m * 60 + s);
  ret *= 75;
  ret += f;
  if (m < 90 || force_positive)
    ret -= 150;
  else
    ret -= 450150;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clp_v>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L9:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <clip23@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L9
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void clp_v(int *input, int len) {
  for (int i = 0; i < len; i++)
    input[i] = clip23(input[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clp_v>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
L12:
  mov    (%rbx),%edi
  call   <clip23@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  ret
```

assistant: ```c
void clp_v(int *input, int len) {
  for (int i = 0; i < len; i++)
    input[i] = clip23(input[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clp_v>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <clip23@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
void clp_v(int *input, int len) {
  for (int i = 0; i < len; i++)
    input[i] = clip23(input[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clp_v>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L5:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <clip23@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void clp_v(int *input, int len) {
  for (int i = 0; i < len; i++)
    input[i] = clip23(input[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x989680,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0xf4240,-0x14(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string

tool: D15: katrina

tool: D19: %c

assistant: ```c
int main() {
  void *p = (void *)malloc(sizeof(void) * 10000000);
  char *q = "katrina";
  memcpy(p, q, 10);
  int cnt = 1000000;
  while (1) {
    printf("%c", (short)*(char *)p++);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x989680,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0xa,%edx
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    D16(%rip),%r12
L1:
  lea    0x1(%rbx),%rbp
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rbx
  jmp    L1
```

tool_calls: name: read_data
arguments: tag: D15
data_type: string
name: read_data
arguments: tag: D16
data_type: string

tool: D15: katrina

tool: D16: %c

assistant: ```c
int main() {
  void *p = (void *)malloc(sizeof(void) * 10000000);
  char *q = "katrina";
  memcpy(p, q, 10);
  int cnt = 1000000;
  while (1) {
    printf("%c", (short)*(char *)p++);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x989680,%edi
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0xa,%edx
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <memcpy@plt>
L2:
  movsbl (%rbx),%esi
  lea    0x1(%rbx),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rbx
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D18
type: string
name: read_data
arguments: data_label: D15
type: string

tool: D18: %c

tool: D15: katrina

assistant: ```c
int main() {
  void *p = (void *)malloc(sizeof(void) * 10000000);
  char *q = "katrina";
  memcpy(p, q, 10);
  int cnt = 1000000;
  while (1) {
    printf("%c", (short)*(char *)p++);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x989680,%edi
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0xa,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <memcpy@plt>
L4:
  movsbl (%rbx),%esi
  lea    0x1(%rbx),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rbx
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D7: %c

tool: D4: katrina

assistant: ```c
int main() {
  void *p = (void *)malloc(sizeof(void) * 10000000);
  char *q = "katrina";
  memcpy(p, q, 10);
  int cnt = 1000000;
  while (1) {
    printf("%c", (short)*(char *)p++);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L61
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next@plt>
L90:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <current@plt>
  test   %al,%al
  je     L73
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <current@plt>
  cmp    $0x20,%al
  jle    L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <current@plt>
  cmp    $0x2c,%al
  je     L8
L73:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <current@plt>
  cmp    $0x23,%al
  jne    L1
  jmp    L80
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <next@plt>
L80:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <current@plt>
  test   %al,%al
  je     L61
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <current@plt>
  cmp    $0xa,%al
  jne    L2
L61:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L90
  jmp    L64
L1:
  nop
L64:
  nop
  leave
  ret
```

assistant: ```c
void skip_whitespace(const char **input) {
  while (current(input)) {
    while (current(input) && (current(input) <= ' ' || current(input) == ','))
      next(input);
    if (current(input) == '#') {
      while (current(input) && current(input) != '\n')
        next(input);
    } else
      break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<skip_whitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L67
L9:
  mov    %rbx,%rdi
  call   <next@plt>
L74:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  je     L88
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x20,%al
  jle    L9
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x2c,%al
  je     L9
L88:
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x23,%al
  je     L38
  jmp    L0
L56:
  mov    %rbx,%rdi
  call   <next@plt>
L38:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  je     L67
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0xa,%al
  jne    L56
L67:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L74
L0:
  pop    %rbx
  ret
```

assistant: ```c
void skip_whitespace(const char **input) {
  while (current(input)) {
    while (current(input) && (current(input) <= ' ' || current(input) == ','))
      next(input);
    if (current(input) == '#') {
      while (current(input) && current(input) != '\n')
        next(input);
    } else
      break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_whitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L5
  jmp    L76
  xchg   %ax,%ax
L79:
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x20,%al
  jle    L46
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x2c,%al
  jne    L73
L46:
  mov    %rbx,%rdi
  call   <next@plt>
L5:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L79
L73:
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x23,%al
  je     L86
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0xa,%al
  je     L37
  mov    %rbx,%rdi
  call   <next@plt>
L86:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L64
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L5
L76:
  pop    %rbx
  ret
```

assistant: ```c
void skip_whitespace(const char **input) {
  while (current(input)) {
    while (current(input) && (current(input) <= ' ' || current(input) == ','))
      next(input);
    if (current(input) == '#') {
      while (current(input) && current(input) != '\n')
        next(input);
    } else
      break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skip_whitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L59
  jmp    L66
  xchg   %ax,%ax
L13:
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x20,%al
  jle    L55
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x2c,%al
  jne    L67
L55:
  mov    %rbx,%rdi
  call   <next@plt>
L59:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L13
L67:
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0x23,%al
  je     L41
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %rbx,%rdi
  call   <current@plt>
  cmp    $0xa,%al
  je     L46
  mov    %rbx,%rdi
  call   <next@plt>
L41:
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L53
  mov    %rbx,%rdi
  call   <current@plt>
  test   %al,%al
  jne    L59
L66:
  pop    %rbx
  ret
```

assistant: ```c
void skip_whitespace(const char **input) {
  while (current(input)) {
    while (current(input) && (current(input) <= ' ' || current(input) == ','))
      next(input);
    if (current(input) == '#') {
      while (current(input) && current(input) != '\n')
        next(input);
    } else
      break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: %d 

assistant: ```c
void print_array(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D2(%rip),%rbp
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: %d 

assistant: ```c
void print_array(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d ", a[i]);
  printf("\n");
}
```