ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<funcAngCor_alpha1_2plus_2plus_15097_L0>:
  endbr64
  push   %rbx
  mov    (%rsi),%rbx
  movsd  (%rdi),%xmm0
  call   <EvalAngCor_alpha1_2plus_2plus_15097_L0@plt>
  movq   %rbx,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double funcAngCor_alpha1_2plus_2plus_15097_L0(double *x, double *par) {
  double result;
  result = par[0] * EvalAngCor_alpha1_2plus_2plus_15097_L0(x[0]);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<funcAngCor_alpha1_2plus_2plus_15097_L0>:
  endbr64
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm1
  movsd  (%rdi),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <EvalAngCor_alpha1_2plus_2plus_15097_L0@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double funcAngCor_alpha1_2plus_2plus_15097_L0(double *x, double *par) {
  double result;
  result = par[0] * EvalAngCor_alpha1_2plus_2plus_15097_L0(x[0]);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<funcAngCor_alpha1_2plus_2plus_15097_L0>:
  endbr64
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm1
  movsd  (%rdi),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <EvalAngCor_alpha1_2plus_2plus_15097_L0@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double funcAngCor_alpha1_2plus_2plus_15097_L0(double *x, double *par) {
  double result;
  result = par[0] * EvalAngCor_alpha1_2plus_2plus_15097_L0(x[0]);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ignore_exit2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L14
  cmpl   $0x2,-0x4(%rbp)
  je     L14
  mov    -0x4(%rbp),%eax
  jmp    L8
L14:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int ignore_exit2(int rc, char *stdoutbuf, char *stderrbuf) {
  if (rc && (rc != 2)) {
    return (rc);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ignore_exit2>:
  endbr64
  mov    %edi,%eax
  and    $0xfffffffd,%eax
  cmovne %edi,%eax
  ret
```

assistant: ```c
int ignore_exit2(int rc, char *stdoutbuf, char *stderrbuf) {
  if (rc && (rc != 2)) {
    return (rc);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ignore_exit2>:
  endbr64
  mov    %edi,%eax
  and    $0xfffffffd,%eax
  cmovne %edi,%eax
  ret
```

assistant: ```c
int ignore_exit2(int rc, char *stdoutbuf, char *stderrbuf) {
  if (rc && (rc != 2)) {
    return (rc);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ignore_exit2>:
  endbr64
  mov    %edi,%eax
  and    $0xfffffffd,%eax
  cmovne %edi,%eax
  ret
```

assistant: ```c
int ignore_exit2(int rc, char *stdoutbuf, char *stderrbuf) {
  if (rc && (rc != 2)) {
    return (rc);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RoundUp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd D14(%rip),%xmm0
  jbe    L44
  mov    $0xff,%eax
  jmp    L51
L44:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L4
  mov    $0x0,%eax
  jmp    L51
L4:
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  movsd  -0x8(%rbp),%xmm0
  movsd  D13(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  cmp    %eax,%edx
  jg     L13
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  add    $0x1,%eax
  jmp    L51
L13:
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
L51:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
data_type: f64[2]
name: retrieve_data
arguments: tag: D13
data_type: f32[2]

tool: {"D14": [255.0,0.5]}

tool: {"D13": [0.0,1.75]}

assistant: ```c
int RoundUp(double number) {
  if (number > 255.0l)
    return 255;
  if (number < 0.0l)
    return 0;
  if ((int)number <= (int)(number - 0.5f))
    return (int)number + 1;
  return (int)number;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RoundUp>:
  endbr64
  mov    $0xff,%eax
  comisd D18(%rip),%xmm0
  ja     L6
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L6
  cvttsd2si %xmm0,%eax
  subsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%edx
  cmp    %edx,%eax
  setle  %dl
  movzbl %dl,%edx
  add    %edx,%eax
L6:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
type_guessed: f64[2]
name: read_data
arguments: data_tag: D8
type_guessed: f32[2]

tool: {"D18": [255.0,0.5]}

tool: {"D8": [0.0,1.75]}

assistant: ```c
int RoundUp(double number) {
  if (number > 255.0l)
    return 255;
  if (number < 0.0l)
    return 0;
  if ((int)number <= (int)(number - 0.5f))
    return (int)number + 1;
  return (int)number;
}
```
user: Translate the below assembly code into C programming language:

```asm
<RoundUp>:
  endbr64
  comisd D3(%rip),%xmm0
  mov    $0xff,%eax
  ja     L18
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  ja     L18
  cvttsd2si %xmm0,%eax
  subsd  D12(%rip),%xmm0
  cvttsd2si %xmm0,%edx
  cmp    %edx,%eax
  setle  %dl
  movzbl %dl,%edx
  add    %edx,%eax
L18:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type: f64[2]
name: retrieve_data
arguments: label: D12
type: f32[2]

tool: {"D3": [255.0,0.5]}

tool: {"D12": [0.0,1.75]}

assistant: ```c
int RoundUp(double number) {
  if (number > 255.0l)
    return 255;
  if (number < 0.0l)
    return 0;
  if ((int)number <= (int)(number - 0.5f))
    return (int)number + 1;
  return (int)number;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RoundUp>:
  endbr64
  comisd D5(%rip),%xmm0
  mov    $0xff,%eax
  ja     L16
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  ja     L16
  cvttsd2si %xmm0,%eax
  subsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%edx
  cmp    %edx,%eax
  setle  %dl
  movzbl %dl,%edx
  add    %edx,%eax
L16:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: f64[2]
name: disassemble_data
arguments: data_label: D3
type_infered: f32[2]

tool: {"D5": [255.0,0.5]}

tool: {"D3": [0.0,1.75]}

assistant: ```c
int RoundUp(double number) {
  if (number > 255.0l)
    return 255;
  if (number < 0.0l)
    return 0;
  if ((int)number <= (int)(number - 0.5f))
    return (int)number + 1;
  return (int)number;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x136ff696,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L40
L18:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L16
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  add    $0x4,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L36
L16:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
L36:
  addq   $0x2,-0x18(%rbp)
L40:
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L18
  mov    -0x10(%rbp),%rax
  lea    0x60f19126(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] = state[local1] * state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1626444070UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L44
  mov    %rsp,%rdx
  mov    $0x0,%eax
L23:
  mov    (%rsp),%rcx
  cmp    %rax,%rcx
  jae    L35
  mov    0x4(%rdx),%ecx
  mov    (%rdx),%r8d
  mov    %r8d,0x4(%rdx)
  mov    %ecx,(%rdx)
L43:
  add    $0x2,%rax
  add    $0x10,%rdx
  cmp    %rdi,%rax
  jb     L23
L44:
  mov    (%rsp),%rax
  add    $0x60f19126,%rax
  mov    %rax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  ret
L35:
  imul   %rcx,%rcx
  mov    %rcx,(%rsp)
  jmp    L43
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] = state[local1] * state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1626444070UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rcx
  add    $0x136ff696,%rax
  test   %rcx,%rcx
  je     L22
  xor    %edx,%edx
L10:
  cmp    %rdx,%rax
  jb     L26
  imul   %rax,%rax
L26:
  add    $0x2,%rdx
  cmp    %rcx,%rdx
  jb     L10
L22:
  add    $0x60f19126,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] = state[local1] * state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1626444070UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdx
  add    $0x136ff696,%rax
  test   %rdx,%rdx
  je     L65
  imul   %rax,%rax
  cmp    $0x2,%rdx
  jbe    L65
  cmp    $0x1,%rax
  ja     L16
  cmp    $0x4,%rdx
  jbe    L65
L13:
  mov    $0x4,%ecx
L32:
  cmp    %rcx,%rax
  jb     L7
  imul   %rax,%rax
L7:
  add    $0x2,%rcx
  cmp    %rdx,%rcx
  jb     L32
L65:
  add    $0x60f19126,%rax
  mov    %rax,(%rsi)
  ret
  nopl   (%rax)
L16:
  imul   %rax,%rax
  cmp    $0x4,%rdx
  jbe    L65
  jmp    L13
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] = state[local1] * state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1626444070UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clear_rect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L47
L13:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L21
L32:
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    $0x20,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L2
  cmpl   $0x4f,-0x4(%rbp)
  jle    L32
L2:
  addl   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L18
  cmpl   $0x17,-0x8(%rbp)
  jle    L13
L18:
  nop
  leave
  ret
```

assistant: ```c
void clear_rect(int y1, int x1, int y2, int x2) {
  for (int y = y1; y < y2 && y < 24; ++y)
    for (int x = x1; x < x2 && x < 80; ++x)
      mvaddch(y, x, ' ');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear_rect>:
  endbr64
  cmp    %edx,%edi
  jge    L28
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %ecx,%r12d
  cmp    $0x17,%edi
  jle    L56
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  add    $0x1,%ebp
  cmp    %ebp,%r14d
  jle    L35
  cmp    $0x17,%ebp
  jg     L35
L56:
  cmp    %r12d,%r13d
  jge    L22
  mov    %r13d,%ebx
  cmp    $0x4f,%r13d
  jg     L22
L29:
  mov    $0x20,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mvaddch@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jle    L22
  cmp    $0x4f,%ebx
  jle    L29
  jmp    L22
L28:
  ret
```

assistant: ```c
void clear_rect(int y1, int x1, int y2, int x2) {
  for (int y = y1; y < y2 && y < 24; ++y)
    for (int x = x1; x < x2 && x < 80; ++x)
      mvaddch(y, x, ' ');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_rect>:
  endbr64
  cmp    $0x17,%edi
  jg     L48
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%edi
  jge    L34
  cmp    %ecx,%esi
  mov    %esi,%r13d
  mov    %ecx,%r12d
  setl   %r15b
  cmp    $0x4f,%esi
  setle  %al
  and    %eax,%r15d
  nopl   (%rax)
L62:
  mov    %r13d,%ebx
  test   %r15b,%r15b
  je     L28
L7:
  mov    %ebx,%esi
  mov    $0x20,%edx
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <mvaddch@plt>
  cmp    %ebx,%r12d
  jle    L28
  cmp    $0x4f,%ebx
  jle    L7
L28:
  add    $0x1,%ebp
  cmp    %ebp,%r14d
  jle    L34
  cmp    $0x17,%ebp
  jle    L62
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L48:
  ret
```

assistant: ```c
void clear_rect(int y1, int x1, int y2, int x2) {
  for (int y = y1; y < y2 && y < 24; ++y)
    for (int x = x1; x < x2 && x < 80; ++x)
      mvaddch(y, x, ' ');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clear_rect>:
  endbr64
  cmp    $0x17,%edi
  jg     L31
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  cmp    %edx,%edi
  jge    L49
  mov    %esi,%r13d
  mov    %ecx,%r12d
  cmp    %ecx,%esi
  jge    L49
  cmp    $0x4f,%esi
  jg     L49
  nopl   0x0(%rax)
L20:
  mov    %r13d,%ebx
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %ebx,%esi
  mov    $0x20,%edx
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <mvaddch@plt>
  cmp    %ebx,%r12d
  jle    L23
  cmp    $0x4f,%ebx
  jle    L34
L23:
  add    $0x1,%ebp
  cmp    %ebp,%r14d
  jle    L49
  cmp    $0x17,%ebp
  jle    L20
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  ret
```

assistant: ```c
void clear_rect(int y1, int x1, int y2, int x2) {
  for (int y = y1; y < y2 && y < 24; ++y)
    for (int x = x1; x < x2 && x < 80; ++x)
      mvaddch(y, x, ' ');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_cmdline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%ecx
  lea    D6(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: bnac

assistant: ```c
void clear_cmdline(int argc, char **argv) {
  int len = 0;
  int i;
  for (i = 0; i < argc; i++) {
    len += strlen(argv[i]) + 1;
  }
  memset(argv[0], 0, len);
  snprintf(argv[0], len, "bnac");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clear_cmdline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r13
  test   %edi,%edi
  jle    L16
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
  mov    $0x0,%ebp
L22:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%ebp
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L22
L24:
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    0x0(%r13),%rdi
  call   <memset@plt>
  lea    D0(%rip),%rdx
  mov    %ebp,%esi
  mov    0x0(%r13),%rdi
  call   <snprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    $0x0,%ebp
  jmp    L24
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: bnac

assistant: ```c
void clear_cmdline(int argc, char **argv) {
  int len = 0;
  int i;
  for (i = 0; i < argc; i++) {
    len += strlen(argv[i]) + 1;
  }
  memset(argv[0], 0, len);
  snprintf(argv[0], len, "bnac");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clear_cmdline>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L16
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  xor    %ebp,%ebp
  lea    0x8(%rsi,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%ebp
  cmp    %rbx,%r12
  jne    L4
L2:
  mov    0x0(%r13),%rdi
  mov    %ebp,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    0x0(%r13),%rdi
  add    $0x8,%rsp
  mov    %ebp,%esi
  pop    %rbx
  lea    D7(%rip),%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <snprintf@plt>
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %ebp,%ebp
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D7: bnac

assistant: ```c
void clear_cmdline(int argc, char **argv) {
  int len = 0;
  int i;
  for (i = 0; i < argc; i++) {
    len += strlen(argv[i]) + 1;
  }
  memset(argv[0], 0, len);
  snprintf(argv[0], len, "bnac");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clear_cmdline>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L16
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  xor    %ebp,%ebp
  lea    0x8(%rsi,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%ebp
  cmp    %rbx,%r12
  jne    L17
L19:
  mov    0x0(%r13),%rdi
  mov    %ebp,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    0x0(%r13),%rdi
  add    $0x8,%rsp
  mov    %ebp,%esi
  pop    %rbx
  lea    D4(%rip),%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <snprintf@plt>
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %ebp,%ebp
  jmp    L19
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: bnac

assistant: ```c
void clear_cmdline(int argc, char **argv) {
  int len = 0;
  int i;
  for (i = 0; i < argc; i++) {
    len += strlen(argv[i]) + 1;
  }
  memset(argv[0], 0, len);
  snprintf(argv[0], len, "bnac");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uint_to_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L25:
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    %edx,-0x14(%rbp)
  je     L34
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  lea    0x30(%rcx),%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L13
L34:
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  lea    0x30(%rcx),%edx
  mov    %dl,(%rax)
  movl   $0x0,-0x14(%rbp)
L13:
  subl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x4(%rbp)
  jns    L25
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uint_to_char(unsigned int val, unsigned char *buf, unsigned int len) {
  int i;
  for (i = (int)(len - 1); i >= 0; i--) {
    if ((val % 10) != val) {
      buf[i] = (unsigned char)((val % 10) + '0');
      val /= 10;
    } else {
      buf[i] = (unsigned char)(val + '0');
      val = 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uint_to_char>:
  endbr64
  mov    %edi,%ecx
  mov    %rsi,%r8
  sub    $0x1,%edx
  js     L44
  movslq %edx,%rdx
  mov    $0xcccccccd,%edi
  mov    $0x0,%r9d
  jmp    L40
L23:
  add    $0x30,%ecx
  mov    %cl,(%r8,%rdx,1)
  mov    %r9d,%ecx
L5:
  sub    $0x1,%rdx
  test   %edx,%edx
  js     L44
L40:
  mov    %ecx,%eax
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  cmp    %ecx,%eax
  je     L23
  add    $0x30,%eax
  mov    %al,(%r8,%rdx,1)
  mov    %ecx,%ecx
  imul   %rdi,%rcx
  shr    $0x23,%rcx
  jmp    L5
L44:
  ret
```

assistant: ```c
void uint_to_char(unsigned int val, unsigned char *buf, unsigned int len) {
  int i;
  for (i = (int)(len - 1); i >= 0; i--) {
    if ((val % 10) != val) {
      buf[i] = (unsigned char)((val % 10) + '0');
      val /= 10;
    } else {
      buf[i] = (unsigned char)(val + '0');
      val = 0;
    }
  }
}
```