ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0x4e,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D26
type: string
name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D11
type: string

tool: D26: Usage: demucc [-tc] FILENAME.pmd

tool: D8:     -c COLUMNS	wrap every COLUMNs (default: %d)


tool: D11:     -t		use %%ticks instead of beats


assistant: ```c
int usage() {
  printf("Usage: demucc [-tc] FILENAME.pmd\n");
  printf("    -c COLUMNS\twrap every COLUMNs (default: %d)\n", 78);
  printf("    -t\t\tuse %%ticks instead of beats\n");
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<UserMenu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D99(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x70(%rbp),%edx
  mov    -0x78(%rbp),%rax
  mov    %dl,(%rax)
  movzbl -0x70(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D33
type_guessed: string
name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D80
type_guessed: string
name: parse_data
arguments: tag: D56
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D77
type_guessed: string
name: parse_data
arguments: tag: D48
type_guessed: string
name: parse_data
arguments: tag: D99
type_guessed: string

tool: D33: 1) Exit


tool: D12: 2) Populate array


tool: D80: 3) Copy array


tool: D56: 4) Display array (first 10 items)


tool: D10: 5) Bubble Sort Ascending


tool: D19: 6) Insertion Sort Ascending


tool: D5: 7) Calculate Time for Bubble Sort


tool: D77: 8) Calculate Time for Insertion Sort


tool: D48: Enter Selection: 

tool: D99: %s

assistant: ```c
char UserMenu(char *opt) {
  char buffer[100];
  printf("1) Exit\n");
  printf("2) Populate array\n");
  printf("3) Copy array\n");
  printf("4) Display array (first 10 items)\n");
  printf("5) Bubble Sort Ascending\n");
  printf("6) Insertion Sort Ascending\n");
  printf("7) Calculate Time for Bubble Sort\n");
  printf("8) Calculate Time for Insertion Sort\n");
  printf("Enter Selection: ");
  scanf("%s", buffer);
  *opt = buffer[0];
  return buffer[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UserMenu>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D85(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  mov    %al,(%rbx)
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x70,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D44
data_type: string
name: extract_symbolic_data
arguments: tag: D46
data_type: string
name: extract_symbolic_data
arguments: tag: D53
data_type: string
name: extract_symbolic_data
arguments: tag: D43
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D58
data_type: string
name: extract_symbolic_data
arguments: tag: D85
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string
name: extract_symbolic_data
arguments: tag: D54
data_type: string

tool: D44: 1) Exit


tool: D46: 2) Populate array


tool: D53: 3) Copy array


tool: D43: 4) Display array (first 10 items)


tool: D18: 5) Bubble Sort Ascending


tool: D27: 6) Insertion Sort Ascending


tool: D58: 7) Calculate Time for Bubble Sort


tool: D85: 8) Calculate Time for Insertion Sort


tool: D24: Enter Selection: 

tool: D54: %s

assistant: ```c
char UserMenu(char *opt) {
  char buffer[100];
  printf("1) Exit\n");
  printf("2) Populate array\n");
  printf("3) Copy array\n");
  printf("4) Display array (first 10 items)\n");
  printf("5) Bubble Sort Ascending\n");
  printf("6) Insertion Sort Ascending\n");
  printf("7) Calculate Time for Bubble Sort\n");
  printf("8) Calculate Time for Insertion Sort\n");
  printf("Enter Selection: ");
  scanf("%s", buffer);
  *opt = buffer[0];
  return buffer[0];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UserMenu>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D89(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D91(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  lea    D94(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D51(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  mov    %al,(%rbx)
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x70,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D89
type_infered: string
name: disassemble_data
arguments: label: D44
type_infered: string
name: disassemble_data
arguments: label: D91
type_infered: string
name: disassemble_data
arguments: label: D31
type_infered: string
name: disassemble_data
arguments: label: D1
type_infered: string
name: disassemble_data
arguments: label: D47
type_infered: string
name: disassemble_data
arguments: label: D69
type_infered: string
name: disassemble_data
arguments: label: D94
type_infered: string
name: disassemble_data
arguments: label: D67
type_infered: string
name: disassemble_data
arguments: label: D51
type_infered: string

tool: D89: 1) Exit


tool: D44: 2) Populate array


tool: D91: 3) Copy array


tool: D31: 4) Display array (first 10 items)


tool: D1: 5) Bubble Sort Ascending


tool: D47: 6) Insertion Sort Ascending


tool: D69: 7) Calculate Time for Bubble Sort


tool: D94: 8) Calculate Time for Insertion Sort


tool: D67: Enter Selection: 

tool: D51: %s

assistant: ```c
char UserMenu(char *opt) {
  char buffer[100];
  printf("1) Exit\n");
  printf("2) Populate array\n");
  printf("3) Copy array\n");
  printf("4) Display array (first 10 items)\n");
  printf("5) Bubble Sort Ascending\n");
  printf("6) Insertion Sort Ascending\n");
  printf("7) Calculate Time for Bubble Sort\n");
  printf("8) Calculate Time for Insertion Sort\n");
  printf("Enter Selection: ");
  scanf("%s", buffer);
  *opt = buffer[0];
  return buffer[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UserMenu>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D79(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D84(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  mov    %al,(%rbx)
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x70,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D57
type_guessed: string
name: retrieve_data
arguments: label: D24
type_guessed: string
name: retrieve_data
arguments: label: D41
type_guessed: string
name: retrieve_data
arguments: label: D79
type_guessed: string
name: retrieve_data
arguments: label: D38
type_guessed: string
name: retrieve_data
arguments: label: D68
type_guessed: string
name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D84
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D6: 1) Exit


tool: D57: 2) Populate array


tool: D24: 3) Copy array


tool: D41: 4) Display array (first 10 items)


tool: D79: 5) Bubble Sort Ascending


tool: D38: 6) Insertion Sort Ascending


tool: D68: 7) Calculate Time for Bubble Sort


tool: D4: 8) Calculate Time for Insertion Sort


tool: D84: Enter Selection: 

tool: D0: %s

assistant: ```c
char UserMenu(char *opt) {
  char buffer[100];
  printf("1) Exit\n");
  printf("2) Populate array\n");
  printf("3) Copy array\n");
  printf("4) Display array (first 10 items)\n");
  printf("5) Bubble Sort Ascending\n");
  printf("6) Insertion Sort Ascending\n");
  printf("7) Calculate Time for Bubble Sort\n");
  printf("8) Calculate Time for Insertion Sort\n");
  printf("Enter Selection: ");
  scanf("%s", buffer);
  *opt = buffer[0];
  return buffer[0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<toOct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int toOct(char ch) {
  return ((unsigned int)(ch)) - ((unsigned int)('0'));
  __builtin_unreachable();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<toOct>:
  endbr64
  movsbl %dil,%eax
  sub    $0x30,%eax
  ret
```

assistant: ```c
unsigned int toOct(char ch) {
  return ((unsigned int)(ch)) - ((unsigned int)('0'));
  __builtin_unreachable();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<toOct>:
  endbr64
  movsbl %dil,%eax
  sub    $0x30,%eax
  ret
```

assistant: ```c
unsigned int toOct(char ch) {
  return ((unsigned int)(ch)) - ((unsigned int)('0'));
  __builtin_unreachable();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IntegerDigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0xa,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L14
L29:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L36
  cmpq   $0x0,-0x18(%rbp)
  jne    L36
  movq   $0x1,-0x18(%rbp)
L36:
  cmpq   $0x1,-0x18(%rbp)
  jne    L5
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BNCIO@plt>
L5:
  subq   $0x1,-0x20(%rbp)
L14:
  cmpq   $0x0,-0x20(%rbp)
  jns    L29
  nop
  nop
  leave
  ret
```

assistant: ```c
long int IntegerDigits(long int mm) {
  long int ii, jj, hi = 10, nflag = 0;
  for (ii = hi; ii >= 0; ii--) {
    jj = mm / (long int)pow(10, ii);
    if (jj != 0 && nflag == 0)
      nflag = 1;
    if (nflag == 1) {
      mm = mm - (jj * (long int)pow(10, ii));
      BNCIO(jj);
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<IntegerDigits>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%r14d
  mov    $0xa,%ebx
  mov    $0x1,%r13d
  jmp    L15
L58:
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   %r12,%rax
  sub    %rax,%rbp
  mov    %r12,%rdi
  call   <BNCIO@plt>
  mov    %r13,%r14
L22:
  sub    $0x1,%rbx
  cmp    $0xffffffffffffffff,%rbx
  je     L37
L15:
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%rcx
  mov    %rbp,%rax
  cqto
  idiv   %rcx
  mov    %rax,%r12
  test   %rax,%rax
  je     L20
  test   %r14,%r14
  je     L58
L20:
  cmp    $0x1,%r14
  jne    L22
  jmp    L58
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
long int IntegerDigits(long int mm) {
  long int ii, jj, hi = 10, nflag = 0;
  for (ii = hi; ii >= 0; ii--) {
    jj = mm / (long int)pow(10, ii);
    if (jj != 0 && nflag == 0)
      nflag = 1;
    if (nflag == 1) {
      mm = mm - (jj * (long int)pow(10, ii));
      BNCIO(jj);
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IntegerDigits>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %r13d,%eax
  xor    %r13d,%r13d
  and    $0x1,%eax
  test   %al,%al
  jne    L43
  sub    $0x1,%rbx
  jb     L23
L32:
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %rbp,%rax
  cqto
  idiv   %r8
  test   %rax,%rax
  mov    %rax,%r12
  mov    %r13d,%eax
  setne  %dl
  xor    $0x1,%eax
  test   %al,%dl
  je     L27
L43:
  mov    %rbx,%rsi
  mov    $0xa,%edi
  mov    $0x1,%r13d
  call   <pow@plt>
  mov    %r12,%rdi
  imul   %r12,%rax
  sub    %rax,%rbp
  call   <BNCIO@plt>
  sub    $0x1,%rbx
  jae    L32
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long int IntegerDigits(long int mm) {
  long int ii, jj, hi = 10, nflag = 0;
  for (ii = hi; ii >= 0; ii--) {
    jj = mm / (long int)pow(10, ii);
    if (jj != 0 && nflag == 0)
      nflag = 1;
    if (nflag == 1) {
      mm = mm - (jj * (long int)pow(10, ii));
      BNCIO(jj);
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IntegerDigits>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %r13d,%eax
  xor    %r13d,%r13d
  and    $0x1,%eax
  test   %al,%al
  jne    L23
  sub    $0x1,%rbx
  jb     L14
L25:
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %rbp,%rax
  cqto
  idiv   %r8
  test   %rax,%rax
  mov    %rax,%r12
  mov    %r13d,%eax
  setne  %dl
  xor    $0x1,%eax
  test   %al,%dl
  je     L15
L23:
  mov    %rbx,%rsi
  mov    $0xa,%edi
  mov    $0x1,%r13d
  call   <pow@plt>
  mov    %r12,%rdi
  imul   %r12,%rax
  sub    %rax,%rbp
  call   <BNCIO@plt>
  sub    $0x1,%rbx
  jae    L25
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long int IntegerDigits(long int mm) {
  long int ii, jj, hi = 10, nflag = 0;
  for (ii = hi; ii >= 0; ii--) {
    jj = mm / (long int)pow(10, ii);
    if (jj != 0 && nflag == 0)
      nflag = 1;
    if (nflag == 1) {
      mm = mm - (jj * (long int)pow(10, ii));
      BNCIO(jj);
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<equals_after_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0xc,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <test_equal@plt>
  test   %rax,%rax
  je     L8
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L8:
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: EQ!

assistant: ```c
int equals_after_free() {
  volatile int *x = malloc(sizeof(int));
  *x = 12;
  free((int *)x);
  if (test_equal((void *)x, (void *)x)) {
    puts("EQ!");
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<equals_after_free>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0xc,(%rax)
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <test_equal@plt>
  test   %rax,%rax
  jne    L18
L10:
  mov    $0x1,%eax
  pop    %rbx
  ret
L18:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: EQ!

assistant: ```c
int equals_after_free() {
  volatile int *x = malloc(sizeof(int));
  *x = 12;
  free((int *)x);
  if (test_equal((void *)x, (void *)x)) {
    puts("EQ!");
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<equals_after_free>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0xc,(%rax)
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <test_equal@plt>
  test   %rax,%rax
  jne    L7
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: EQ!

assistant: ```c
int equals_after_free() {
  volatile int *x = malloc(sizeof(int));
  *x = 12;
  free((int *)x);
  if (test_equal((void *)x, (void *)x)) {
    puts("EQ!");
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<equals_after_free>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0xc,(%rax)
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <test_equal@plt>
  test   %rax,%rax
  jne    L2
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: EQ!

assistant: ```c
int equals_after_free() {
  volatile int *x = malloc(sizeof(int));
  *x = 12;
  free((int *)x);
  if (test_equal((void *)x, (void *)x)) {
    puts("EQ!");
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hex_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  jmp    L4
L50:
  cmp    $0x1,%ebx
  jne    L14
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L14:
  movslq %r12d,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    -0x1c(%rbp),%ebx
  jne    L41
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
L41:
  add    $0x1,%r12d
  add    $0x1,%ebx
L4:
  cmp    -0x20(%rbp),%r12d
  jl     L50
  test   %r12d,%r12d
  je     L56
  cmp    $0x1,%ebx
  je     L56
  mov    $0xa,%edi
  call   <putchar@plt>
L56:
  nop
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D18: %s

tool: D6: %2.2X 

assistant: ```c
void hex_dump(char *pref, int width, unsigned char *buf, int len) {
  register int i, n;
  for (i = 0, n = 1; i < len; i++, n++) {
    if (n == 1)
      printf("%s", pref);
    printf("%2.2X ", buf[i]);
    if (n == width) {
      printf("\n");
      n = 0;
    }
  }
  if (i && n != 1)
    printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<hex_dump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %ecx,%ecx
  jle    L36
  mov    %esi,%r12d
  mov    %rdx,%rbp
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%r14
  mov    $0x1,%ebx
  lea    D15(%rip),%r15
  lea    D19(%rip),%r13
  jmp    L89
L50:
  movzbl 0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%r12d
  je     L1
L87:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r14,%rbp
  je     L11
L89:
  cmp    $0x1,%ebx
  jne    L50
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L50
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  jmp    L87
L11:
  cmp    $0x1,%ebx
  jne    L21
L36:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L36
```

tool_calls: name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D19
type_infered: string

tool: D15: %s

tool: D19: %2.2X 

assistant: ```c
void hex_dump(char *pref, int width, unsigned char *buf, int len) {
  register int i, n;
  for (i = 0, n = 1; i < len; i++, n++) {
    if (n == 1)
      printf("%s", pref);
    printf("%2.2X ", buf[i]);
    if (n == width) {
      printf("\n");
      n = 0;
    }
  }
  if (i && n != 1)
    printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hex_dump>:
  endbr64
  test   %ecx,%ecx
  jle    L68
  push   %r15
  lea    -0x1(%rcx),%eax
  mov    $0x1,%r15d
  push   %r14
  lea    0x1(%rdx,%rax,1),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L46
  nopl   0x0(%rax)
L26:
  add    $0x1,%rbx
  add    $0x1,%r15d
  cmp    %r14,%rbx
  je     L51
L46:
  cmp    $0x1,%r15d
  je     L30
L24:
  movzbl (%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %r15d,%ebp
  jne    L26
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %r14,%rbx
  je     L13
L30:
  mov    %r13,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  mov    $0x1,%r15d
  call   <printf@plt>
  jmp    L24
  nopl   0x0(%rax)
L51:
  cmp    $0x1,%r15d
  jne    L9
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L9:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L68:
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
datatype: string
name: read_data
arguments: data_label: D3
datatype: string

tool: D12: %2.2X 

tool: D3: %s

assistant: ```c
void hex_dump(char *pref, int width, unsigned char *buf, int len) {
  register int i, n;
  for (i = 0, n = 1; i < len; i++, n++) {
    if (n == 1)
      printf("%s", pref);
    printf("%2.2X ", buf[i]);
    if (n == width) {
      printf("\n");
      n = 0;
    }
  }
  if (i && n != 1)
    printf("\n");
}
```