ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movb   $0x0,-0x2d(%rbp)
  jmp    L20
L85:
  movl   $0x0,-0x28(%rbp)
  jmp    L59
L2:
  mov    -0x28(%rbp),%eax
  cltq
  movb   $0x0,-0x23(%rbp,%rax,1)
  addl   $0x1,-0x28(%rbp)
L59:
  cmpl   $0xa,-0x28(%rbp)
  jle    L2
  movl   $0x0,-0x28(%rbp)
L74:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x2d(%rbp)
  cmpb   $0x20,-0x2d(%rbp)
  je     L69
  cmpb   $0xa,-0x2d(%rbp)
  jne    L32
L69:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0x23(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  nop
  cmpb   $0xa,-0x2d(%rbp)
  jne    L72
  jmp    L46
L32:
  mov    -0x28(%rbp),%eax
  cltq
  movzbl -0x2d(%rbp),%edx
  mov    %dl,-0x23(%rbp,%rax,1)
  addl   $0x1,-0x28(%rbp)
  jmp    L74
L72:
  addl   $0x1,-0x2c(%rbp)
L20:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L85
L46:
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void get_input(int n, int num[]) {
  int i = 0, j = 0;
  char ch = 0;
  char str[11];
  for (; i < n; ++i) {
    for (j = 0; j < 11; ++j) {
      str[j] = '\0';
    }
    j = 0;
    while (1) {
      ch = getchar();
      if ((ch == ' ') || (ch == '\n')) {
        num[i] = atoi(str);
        break;
      }
      str[j] = ch;
      ++j;
    }
    if (ch == '\n') {
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_input>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L88
  mov    %rsi,%r13
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r14
  lea    0x18(%rsp),%r12
  jmp    L68
L6:
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
L67:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x20,%al
  je     L80
  cmp    $0xa,%al
  jne    L6
L80:
  lea    0xd(%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,0x0(%r13)
  cmp    $0xa,%bl
  je     L88
  add    $0x4,%r13
  cmp    %r14,%r13
  je     L88
L68:
  lea    0xd(%rsp),%rbp
  mov    %rbp,%rax
L76:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L76
  jmp    L67
L88:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_input(int n, int num[]) {
  int i = 0, j = 0;
  char ch = 0;
  char str[11];
  for (; i < n; ++i) {
    for (j = 0; j < 11; ++j) {
      str[j] = '\0';
    }
    j = 0;
    while (1) {
      ch = getchar();
      if ((ch == ' ') || (ch == '\n')) {
        num[i] = atoi(str);
        break;
      }
      str[j] = ch;
      ++j;
    }
    if (ch == '\n') {
      break;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_input>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L43
  lea    -0x1(%rdi),%eax
  mov    %rsi,%r13
  lea    0xd(%rsp),%r12
  lea    0x4(%rsi,%rax,4),%r14
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  movq   $0x0,(%r12)
  mov    %r12,%rbp
  mov    %ax,0x8(%r12)
  movb   $0x0,0xa(%r12)
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L65:
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
L40:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x20,%al
  je     L41
  cmp    $0xa,%al
  jne    L65
L41:
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,0x0(%r13)
  cmp    $0xa,%bl
  je     L43
  add    $0x4,%r13
  cmp    %r14,%r13
  jne    L23
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_input(int n, int num[]) {
  int i = 0, j = 0;
  char ch = 0;
  char str[11];
  for (; i < n; ++i) {
    for (j = 0; j < 11; ++j) {
      str[j] = '\0';
    }
    j = 0;
    while (1) {
      ch = getchar();
      if ((ch == ' ') || (ch == '\n')) {
        num[i] = atoi(str);
        break;
      }
      str[j] = ch;
      ++j;
    }
    if (ch == '\n') {
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_input>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L13
  lea    -0x1(%rdi),%eax
  mov    %rsi,%r12
  lea    0x8(%rsp),%r13
  lea    0x4(%rsi,%rax,4),%r14
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  movb   $0x0,0x12(%rsp)
  mov    %r13,%rbp
  movq   $0x0,0x8(%rsp)
  mov    %ax,0x10(%rsp)
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
L31:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x20,%al
  je     L42
  cmp    $0xa,%al
  jne    L65
L42:
  mov    %r13,%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  cmp    $0xa,%bl
  je     L13
  add    $0x4,%r12
  cmp    %r14,%r12
  jne    L4
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_input(int n, int num[]) {
  int i = 0, j = 0;
  char ch = 0;
  char str[11];
  for (; i < n; ++i) {
    for (j = 0; j < 11; ++j) {
      str[j] = '\0';
    }
    j = 0;
    while (1) {
      ch = getchar();
      if ((ch == ' ') || (ch == '\n')) {
        num[i] = atoi(str);
        break;
      }
      str[j] = ch;
      ++j;
    }
    if (ch == '\n') {
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bot_matrix_vector_multiply_2x2_2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bot_matrix_vector_multiply_2x2_2d(const double m[4], const double v[2], double result[2]) {
  result[0] = m[0] * v[0] + m[1] * v[1];
  result[1] = m[2] * v[0] + m[3] * v[1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bot_matrix_vector_multiply_2x2_2d>:
  endbr64
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x18(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void bot_matrix_vector_multiply_2x2_2d(const double m[4], const double v[2], double result[2]) {
  result[0] = m[0] * v[0] + m[1] * v[1];
  result[1] = m[2] * v[0] + m[3] * v[1];
}
```
user: What is the c source code of the assembly code below?

```asm
<bot_matrix_vector_multiply_2x2_2d>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  0x18(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void bot_matrix_vector_multiply_2x2_2d(const double m[4], const double v[2], double result[2]) {
  result[0] = m[0] * v[0] + m[1] * v[1];
  result[1] = m[2] * v[0] + m[3] * v[1];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bot_matrix_vector_multiply_2x2_2d>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  0x18(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void bot_matrix_vector_multiply_2x2_2d(const double m[4], const double v[2], double result[2]) {
  result[0] = m[0] * v[0] + m[1] * v[1];
  result[1] = m[2] * v[0] + m[3] * v[1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xe4d,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <calculate_sec@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void test5(void) {
  int input_sec = 3661;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 1);
  assert(min == 1);
  assert(sec == 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test5>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0xe4d,%edi
  call   <calculate_sec@plt>
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,0xc(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test5(void) {
  int input_sec = 3661;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 1);
  assert(min == 1);
  assert(sec == 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test5>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xe4d,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <calculate_sec@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test5(void) {
  int input_sec = 3661;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 1);
  assert(min == 1);
  assert(sec == 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test5>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xe4d,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <calculate_sec@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test5(void) {
  int input_sec = 3661;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 1);
  assert(min == 1);
  assert(sec == 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<group_std_branches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <Output_byte@plt>
  mov    $0x2,%edi
  call   <near_branch@plt>
  nop
  leave
  ret
```

assistant: ```c
void group_std_branches(int opcode) {
  Output_byte(opcode);
  near_branch(2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<group_std_branches>:
  endbr64
  sub    $0x8,%rsp
  call   <Output_byte@plt>
  mov    $0x2,%edi
  call   <near_branch@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void group_std_branches(int opcode) {
  Output_byte(opcode);
  near_branch(2);
}
```
user: What is the c source code of the assembly code below?

```asm
<group_std_branches>:
  endbr64
  sub    $0x8,%rsp
  call   <Output_byte@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <near_branch@plt>
```

assistant: ```c
void group_std_branches(int opcode) {
  Output_byte(opcode);
  near_branch(2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<group_std_branches>:
  endbr64
  sub    $0x8,%rsp
  call   <Output_byte@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <near_branch@plt>
```

assistant: ```c
void group_std_branches(int opcode) {
  Output_byte(opcode);
  near_branch(2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  imul   %eax,%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string
name: retrieve_data
arguments: tag: D47
type_infered: string
name: retrieve_data
arguments: tag: D24
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string

tool: D6: Enter first fraction: 

tool: D47: %d/%d

tool: D24: Eter second fraction: 

tool: D20: The sum is %d/%d


assistant: ```c
int main(void) {
  int num1, denom1, num2, denom2, result_num, result_denom;
  printf("Enter first fraction: ");
  scanf("%d/%d", &num1, &denom1);
  printf("Eter second fraction: ");
  scanf("%d/%d", &num2, &denom2);
  result_num = num1 * denom2 + num2 * denom1;
  result_denom = denom1 * denom2;
  printf("The sum is %d/%d\n", result_num, result_denom);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%eax
  mov    %esi,%edx
  imul   %eax,%edx
  imul   0x8(%rsp),%esi
  imul   0x10(%rsp),%eax
  add    %eax,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D23
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string

tool: D13: Enter first fraction: 

tool: D14: %d/%d

tool: D23: Eter second fraction: 

tool: D25: The sum is %d/%d


assistant: ```c
int main(void) {
  int num1, denom1, num2, denom2, result_num, result_denom;
  printf("Enter first fraction: ");
  scanf("%d/%d", &num1, &denom1);
  printf("Eter second fraction: ");
  scanf("%d/%d", &num2, &denom2);
  result_num = num1 * denom2 + num2 * denom1;
  result_denom = denom1 * denom2;
  printf("The sum is %d/%d\n", result_num, result_denom);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  lea    D35(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%eax
  lea    D36(%rip),%rdi
  mov    %esi,%edx
  imul   0x8(%rsp),%esi
  imul   %eax,%edx
  imul   0x10(%rsp),%eax
  add    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
data_type: string
name: extract_symbolic_data
arguments: data_tag: D35
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string
name: extract_symbolic_data
arguments: data_tag: D36
data_type: string

tool: D13: Enter first fraction: 

tool: D35: %d/%d

tool: D27: Eter second fraction: 

tool: D36: The sum is %d/%d


assistant: ```c
int main(void) {
  int num1, denom1, num2, denom2, result_num, result_denom;
  printf("Enter first fraction: ");
  scanf("%d/%d", &num1, &denom1);
  printf("Eter second fraction: ");
  scanf("%d/%d", &num2, &denom2);
  result_num = num1 * denom2 + num2 * denom1;
  result_denom = denom1 * denom2;
  printf("The sum is %d/%d\n", result_num, result_denom);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  lea    D22(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%eax
  lea    D0(%rip),%rdi
  mov    %esi,%edx
  imul   0x8(%rsp),%esi
  imul   %eax,%edx
  imul   0x10(%rsp),%eax
  add    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D22
type_infered: string
name: extract_symbolic_data
arguments: tag: D33
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D29: Enter first fraction: 

tool: D22: %d/%d

tool: D33: Eter second fraction: 

tool: D0: The sum is %d/%d


assistant: ```c
int main(void) {
  int num1, denom1, num2, denom2, result_num, result_denom;
  printf("Enter first fraction: ");
  scanf("%d/%d", &num1, &denom1);
  printf("Eter second fraction: ");
  scanf("%d/%d", &num2, &denom2);
  result_num = num1 * denom2 + num2 * denom1;
  result_denom = denom1 * denom2;
  printf("The sum is %d/%d\n", result_num, result_denom);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ExpressionStackPushDereference>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%r8
  lea    -0x20(%rbp),%rdi
  lea    -0x30(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  mov    -0x48(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <VariableDereferencePointer@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  mov    -0x38(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ProgramFail@plt>
L10:
  mov    -0x28(%rbp),%rdi
  mov    -0x2c(%rbp),%ecx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <VariableAllocValueFromExistingData@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ExpressionStackPushValueNode@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D8: NULL pointer dereference

assistant: ```c
void ExpressionStackPushDereference(struct ParseState *Parser, struct ExpressionStack **StackTop, struct Value *DereferenceValue) {
  struct Value *DerefVal;
  struct Value *ValueLoc;
  int Offset;
  struct ValueType *DerefType;
  int DerefIsLValue;
  void *DerefDataLoc = VariableDereferencePointer(Parser, DereferenceValue, &DerefVal, &Offset, &DerefType, &DerefIsLValue);
  if (DerefDataLoc == 0)
    ProgramFail(Parser, "NULL pointer dereference");
  ValueLoc = VariableAllocValueFromExistingData(Parser, DerefType, (union AnyValue *)DerefDataLoc, DerefIsLValue, DerefVal);
  ExpressionStackPushValueNode(Parser, StackTop, ValueLoc);
}
```