ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jg     L10
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L4
L41:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  je     L21
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L39
L21:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L39:
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L41
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Min(int i, int j, int **r, int **c) {
  int sum = -1;
  int k;
  int left = r[i][j - 1];
  int right = r[i + 1][j];
  if (left <= i) {
    left = i + 1;
  }
  for (int l = left; l <= right; l++) {
    int currentSum = c[i][l - 1] + c[l][j];
    if (sum == -1 || currentSum < sum) {
      sum = currentSum;
      k = l;
    }
  }
  r[i][j] = k;
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Min>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%r8
  movslq %edi,%rcx
  mov    (%rdx,%rcx,8),%r12
  movslq %esi,%rbp
  lea    0x0(,%rbp,4),%r9
  mov    -0x4(%r12,%r9,1),%eax
  mov    0x8(%rdx,%rcx,8),%rdx
  mov    (%rdx,%rbp,4),%r10d
  lea    0x1(%rdi),%edx
  cmp    %eax,%edi
  cmovge %edx,%eax
  cmp    %r10d,%eax
  jg     L41
  mov    (%r8,%rcx,8),%rbx
  cltq
  mov    $0xffffffff,%ecx
  jmp    L54
L9:
  mov    %edi,%r11d
  mov    %edx,%ecx
L58:
  add    $0x1,%rax
  cmp    %eax,%r10d
  jl     L10
L54:
  mov    %eax,%edi
  mov    (%r8,%rax,8),%rsi
  mov    -0x4(%rbx,%rax,4),%edx
  add    (%rsi,%r9,1),%edx
  cmp    $0xffffffff,%ecx
  je     L9
  cmp    %ecx,%edx
  jge    L58
  jmp    L9
L41:
  mov    $0xffffffff,%ecx
L10:
  mov    %r11d,(%r12,%rbp,4)
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Min(int i, int j, int **r, int **c) {
  int sum = -1;
  int k;
  int left = r[i][j - 1];
  int right = r[i + 1][j];
  if (left <= i) {
    left = i + 1;
  }
  for (int l = left; l <= right; l++) {
    int currentSum = c[i][l - 1] + c[l][j];
    if (sum == -1 || currentSum < sum) {
      sum = currentSum;
      k = l;
    }
  }
  r[i][j] = k;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Min>:
  endbr64
  mov    %edi,%eax
  mov    %rcx,%rdi
  push   %r12
  movslq %eax,%rcx
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    (%rdx,%rcx,8),%r12
  lea    0x0(,%rbp,4),%r11
  mov    0x8(%rdx,%rcx,8),%rdx
  mov    -0x4(%r12,%r11,1),%r9d
  mov    (%rdx,%rbp,4),%r10d
  lea    0x1(%rax),%edx
  cmp    %r9d,%eax
  cmovge %edx,%r9d
  cmp    %r10d,%r9d
  jg     L42
  movslq %r9d,%rax
  mov    (%rdi,%rcx,8),%rbx
  mov    (%rdi,%rax,8),%rdx
  mov    -0x4(%rbx,%rax,4),%eax
  add    (%rdx,%rbp,4),%eax
  lea    0x1(%r9),%edx
  movslq %edx,%rdx
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L12:
  cmp    %ecx,%eax
  jg     L26
L28:
  add    $0x1,%rdx
L38:
  mov    %edx,%r8d
  cmp    %edx,%r10d
  jl     L25
  mov    (%rdi,%rdx,8),%rsi
  mov    -0x4(%rbx,%rdx,4),%ecx
  add    (%rsi,%r11,1),%ecx
  cmp    $0xffffffff,%eax
  jne    L12
L26:
  mov    %r8d,%r9d
  mov    %ecx,%eax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %r9d,%r9d
  mov    $0xffffffff,%eax
L25:
  mov    %r9d,(%r12,%rbp,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Min(int i, int j, int **r, int **c) {
  int sum = -1;
  int k;
  int left = r[i][j - 1];
  int right = r[i + 1][j];
  if (left <= i) {
    left = i + 1;
  }
  for (int l = left; l <= right; l++) {
    int currentSum = c[i][l - 1] + c[l][j];
    if (sum == -1 || currentSum < sum) {
      sum = currentSum;
      k = l;
    }
  }
  r[i][j] = k;
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Min>:
  endbr64
  mov    %edi,%eax
  mov    %rcx,%rdi
  push   %r12
  movslq %eax,%rcx
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    (%rdx,%rcx,8),%r12
  lea    0x0(,%rbp,4),%r11
  mov    0x8(%rdx,%rcx,8),%rdx
  mov    -0x4(%r12,%r11,1),%r8d
  mov    (%rdx,%rbp,4),%r10d
  lea    0x1(%rax),%edx
  cmp    %r8d,%eax
  cmovge %edx,%r8d
  cmp    %r10d,%r8d
  jg     L64
  movslq %r8d,%rax
  mov    (%rdi,%rcx,8),%rbx
  lea    0x1(%r8),%ecx
  mov    (%rdi,%rax,8),%rdx
  mov    -0x4(%rbx,%rax,4),%eax
  add    (%rdx,%rbp,4),%eax
  movslq %ecx,%rdx
  cmp    %ecx,%r10d
  jge    L26
  jmp    L41
  nopl   0x0(%rax)
L61:
  cmp    $0xffffffff,%eax
  je     L10
  add    $0x1,%rdx
  cmp    %edx,%r10d
  jl     L41
L26:
  mov    (%rdi,%rdx,8),%rsi
  mov    -0x4(%rbx,%rdx,4),%ecx
  mov    %edx,%r9d
  add    (%rsi,%r11,1),%ecx
  cmp    %eax,%ecx
  jge    L61
L10:
  add    $0x1,%rdx
  mov    %r9d,%r8d
  mov    %ecx,%eax
  cmp    %edx,%r10d
  jge    L26
L41:
  mov    %r8d,(%r12,%rbp,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %r8d,%r8d
  mov    $0xffffffff,%eax
  mov    %r8d,(%r12,%rbp,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Min(int i, int j, int **r, int **c) {
  int sum = -1;
  int k;
  int left = r[i][j - 1];
  int right = r[i + 1][j];
  if (left <= i) {
    left = i + 1;
  }
  for (int l = left; l <= right; l++) {
    int currentSum = c[i][l - 1] + c[l][j];
    if (sum == -1 || currentSum < sum) {
      sum = currentSum;
      k = l;
    }
  }
  r[i][j] = k;
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L16:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L7
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L39
L7:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L16
  mov    -0x18(%rbp),%rax
L39:
  leave
  ret
```

assistant: ```c
char *trim_extension(char *filename) {
  char *end;
  end = filename + strlen(filename);
  while (end != filename) {
    if (*--end == '.') {
      *end = '\0';
      return filename;
    }
  }
  return filename;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<trim_extension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
L16:
  cmp    %rbx,%rax
  je     L2
  sub    $0x1,%rax
  cmpb   $0x2e,(%rax)
  jne    L16
  movb   $0x0,(%rax)
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *trim_extension(char *filename) {
  char *end;
  end = filename + strlen(filename);
  while (end != filename) {
    if (*--end == '.') {
      *end = '\0';
      return filename;
    }
  }
  return filename;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trim_extension>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  jmp    L12
  nopl   (%rax)
L28:
  sub    $0x1,%rax
  cmpb   $0x2e,(%rax)
  je     L4
L12:
  cmp    %r12,%rax
  jne    L28
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trim_extension(char *filename) {
  char *end;
  end = filename + strlen(filename);
  while (end != filename) {
    if (*--end == '.') {
      *end = '\0';
      return filename;
    }
  }
  return filename;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trim_extension>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  jmp    L5
  nopl   (%rax)
L19:
  sub    $0x1,%rax
  cmpb   $0x2e,(%rax)
  je     L7
L5:
  cmp    %r12,%rax
  jne    L19
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trim_extension(char *filename) {
  char *end;
  end = filename + strlen(filename);
  while (end != filename) {
    if (*--end == '.') {
      *end = '\0';
      return filename;
    }
  }
  return filename;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<symbol_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L9:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %eax,%edx
  movsbl -0x5(%rbp),%eax
  xor    %edx,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L9
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int symbol_hash(char *name) {
  int hash = 0;
  char c;
  while (c = *name++) {
    hash = (hash * 9 ^ c) % 1000;
  }
  return hash % 1000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<symbol_hash>:
  endbr64
  lea    0x1(%rdi),%rsi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L19
  mov    $0x0,%edx
L0:
  lea    (%rdx,%rdx,8),%eax
  movsbl %cl,%ecx
  xor    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%ecx
  test   %cl,%cl
  jne    L0
L24:
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L19:
  mov    $0x0,%edx
  jmp    L24
```

assistant: ```c
int symbol_hash(char *name) {
  int hash = 0;
  char c;
  while (c = *name++) {
    hash = (hash * 9 ^ c) % 1000;
  }
  return hash % 1000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<symbol_hash>:
  endbr64
  movsbl (%rdi),%ecx
  lea    0x1(%rdi),%rsi
  xor    %eax,%eax
  test   %cl,%cl
  je     L0
  nopl   0x0(%rax)
L9:
  lea    (%rax,%rax,8),%edx
  add    $0x1,%rsi
  xor    %ecx,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movsbl -0x1(%rsi),%ecx
  test   %cl,%cl
  jne    L9
  ret
  nopl   0x0(%rax)
L0:
  ret
```

assistant: ```c
int symbol_hash(char *name) {
  int hash = 0;
  char c;
  while (c = *name++) {
    hash = (hash * 9 ^ c) % 1000;
  }
  return hash % 1000;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<symbol_hash>:
  endbr64
  movsbl (%rdi),%ecx
  lea    0x1(%rdi),%rsi
  xor    %eax,%eax
  test   %cl,%cl
  je     L3
  nopl   0x0(%rax)
L5:
  lea    (%rax,%rax,8),%edx
  add    $0x1,%rsi
  xor    %ecx,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movsbl -0x1(%rsi),%ecx
  test   %cl,%cl
  jne    L5
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
int symbol_hash(char *name) {
  int hash = 0;
  char c;
  while (c = *name++) {
    hash = (hash * 9 ^ c) % 1000;
  }
  return hash % 1000;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CalSorce>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L17
  mov    $0xa,%eax
  jmp    L26
L17:
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L1
  mov    $0xfffffff6,%eax
  jmp    L26
L1:
  mov    $0x0,%eax
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D13: right

tool: D1: wrong

assistant: ```c
int CalSorce(char a[]) {
  if (!strcmp(a, "right"))
    return 10;
  else if (!strcmp(a, "wrong"))
    return -10;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CalSorce>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0xa,%eax
  test   %edx,%edx
  je     L5
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0xfffffff6,%eax
L5:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D5: right

tool: D6: wrong

assistant: ```c
int CalSorce(char a[]) {
  if (!strcmp(a, "right"))
    return 10;
  else if (!strcmp(a, "wrong"))
    return -10;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CalSorce>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0xa,%eax
  test   %r8d,%r8d
  je     L2
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0xfffffff6,%eax
L2:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string

tool: D10: right

tool: D12: wrong

assistant: ```c
int CalSorce(char a[]) {
  if (!strcmp(a, "right"))
    return 10;
  else if (!strcmp(a, "wrong"))
    return -10;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CalSorce>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0xa,%eax
  test   %r8d,%r8d
  je     L9
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0xfffffff6,%eax
L9:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D6
type: string

tool: D8: right

tool: D6: wrong

assistant: ```c
int CalSorce(char a[]) {
  if (!strcmp(a, "right"))
    return 10;
  else if (!strcmp(a, "wrong"))
    return -10;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myMinmax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L25:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L35
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L35:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L29
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L29:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void myMinmax(int *arr, int size, int *min, int *max) {
  int i;
  for (i = 0; i < size; i++) {
    if (*min > arr[i])
      *min = arr[i];
    if (*max < arr[i])
      *max = arr[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<myMinmax>:
  endbr64
  test   %esi,%esi
  jle    L51
  mov    %rdi,%rax
  lea    -0x1(%rsi),%esi
  lea    0x4(%rdi,%rsi,4),%r8
  jmp    L50
L29:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L51
L50:
  mov    %rax,%rdi
  mov    (%rax),%esi
  cmp    %esi,(%rdx)
  jle    L8
  mov    %esi,(%rdx)
L8:
  mov    (%rdi),%esi
  cmp    %esi,(%rcx)
  jge    L29
  mov    %esi,(%rcx)
  jmp    L29
L51:
  ret
```

assistant: ```c
void myMinmax(int *arr, int size, int *min, int *max) {
  int i;
  for (i = 0; i < size; i++) {
    if (*min > arr[i])
      *min = arr[i];
    if (*max < arr[i])
      *max = arr[i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<myMinmax>:
  endbr64
  test   %esi,%esi
  jle    L34
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L17:
  mov    (%rdi),%eax
  cmp    %eax,(%rdx)
  jle    L30
  mov    %eax,(%rdx)
L30:
  cmp    (%rcx),%eax
  jle    L27
  mov    %eax,(%rcx)
L27:
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L17
L34:
  ret
```

assistant: ```c
void myMinmax(int *arr, int size, int *min, int *max) {
  int i;
  for (i = 0; i < size; i++) {
    if (*min > arr[i])
      *min = arr[i];
    if (*max < arr[i])
      *max = arr[i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<myMinmax>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L35:
  mov    (%rdi),%eax
  cmp    %eax,(%rdx)
  jle    L9
  mov    %eax,(%rdx)
L9:
  cmp    (%rcx),%eax
  jle    L22
  mov    %eax,(%rcx)
L22:
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L35
L8:
  ret
```

assistant: ```c
void myMinmax(int *arr, int size, int *min, int *max) {
  int i;
  for (i = 0; i < size; i++) {
    if (*min > arr[i])
      *min = arr[i];
    if (*max < arr[i])
      *max = arr[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x34(%rbp)
L5:
  lea    -0x30(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  cmp    $0x2,%eax
  jle    L23
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <getOuterCircleArea@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <getInnerCircleArea@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
  jmp    L5
L23:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D15: %d %lf

tool: D0: Case %d: %.5lf %.5lf


assistant: ```c
int main(void) {
  int numSide, caseId;
  double polygonArea;
  caseId = 1;
  while (1) {
    scanf("%d %lf", &numSide, &polygonArea);
    if (numSide < 3) {
      break;
    }
    double outerArea = getOuterCircleArea(numSide, polygonArea);
    double innerArea = getInnerCircleArea(numSide, polygonArea);
    double spectatorArea = outerArea - polygonArea;
    double officialArea = polygonArea - innerArea;
    printf("Case %d: %.5lf %.5lf\n", caseId, spectatorArea, officialArea);
    caseId++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebp
  lea    0x10(%rsp),%r14
  lea    0xc(%rsp),%r13
  lea    D4(%rip),%r12
  lea    D17(%rip),%r15
  jmp    L18
L9:
  movsd  0x10(%rsp),%xmm0
  call   <getOuterCircleArea@plt>
  movq   %xmm0,%rbx
  movsd  0x10(%rsp),%xmm0
  mov    0xc(%rsp),%edi
  call   <getInnerCircleArea@plt>
  movapd %xmm0,%xmm2
  movsd  0x10(%rsp),%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm1
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
L18:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  cmp    $0x2,%edi
  jg     L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D4: %d %lf

tool: D17: Case %d: %.5lf %.5lf


assistant: ```c
int main(void) {
  int numSide, caseId;
  double polygonArea;
  caseId = 1;
  while (1) {
    scanf("%d %lf", &numSide, &polygonArea);
    if (numSide < 3) {
      break;
    }
    double outerArea = getOuterCircleArea(numSide, polygonArea);
    double innerArea = getInnerCircleArea(numSide, polygonArea);
    double spectatorArea = outerArea - polygonArea;
    double officialArea = polygonArea - innerArea;
    printf("Case %d: %.5lf %.5lf\n", caseId, spectatorArea, officialArea);
    caseId++;
  }
  return 0;
}
```