ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_timeout>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timespec get_timeout() {
  struct timespec t;
  clock_gettime(CLOCK_REALTIME, &t);
  t.tv_sec++;
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AES_CMAC>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rdx
  lea    0x40(%rsp),%rsi
  call   <generate_subkey@plt>
  lea    0x1e(%rbx),%eax
  mov    %ebx,%edx
  add    $0xf,%edx
  cmovns %edx,%eax
  sar    $0x4,%eax
  je     L33
  mov    %eax,%r12d
  test   $0xf,%bl
  je     L58
L5:
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    (%rbx,%rax,1),%edx
  and    $0xf,%edx
  sub    %eax,%edx
  lea    0x30(%rsp),%rbx
  lea    -0x1(%r12),%edi
  shl    $0x4,%edi
  movslq %edi,%rdi
  add    %rbp,%rdi
  mov    %rbx,%rsi
  call   <padding@plt>
  lea    0x20(%rsp),%rdx
  lea    0x50(%rsp),%rsi
  mov    %rbx,%rdi
  call   <xor_128@plt>
L35:
  mov    %rsp,%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  cmp    $0x1,%r12d
  jle    L65
  mov    %rbp,%rbx
  lea    -0x2(%r12),%eax
  shl    $0x4,%rax
  lea    0x10(%rbp,%rax,1),%r15
  lea    0x10(%rsp),%r12
L52:
  mov    %rsp,%rbp
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <xor_128@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <AES_128_ENC@plt>
  add    $0x10,%rbx
  cmp    %r15,%rbx
  jne    L52
L65:
  lea    0x10(%rsp),%rbp
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rbx
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <xor_128@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <AES_128_ENC@plt>
  mov    $0x10,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  lea    0x20(%rsp),%rdx
  lea    0x40(%rsp),%rsi
  lea    -0x1(%rax),%edi
  shl    $0x4,%edi
  movslq %edi,%rdi
  add    %rbp,%rdi
  call   <xor_128@plt>
  jmp    L35
L33:
  mov    $0x1,%r12d
  jmp    L5
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void AES_CMAC(const unsigned char *key, const unsigned char *input, int length, unsigned char *mac) {
  unsigned char X[16], Y[16], M_last[16], padded[16];
  unsigned char K1[16], K2[16];
  int n, i, flag;
  generate_subkey(key, K1, K2);
  n = (length + (16 - 1)) / 16;
  if (n == 0) {
    n = 1;
    flag = 0;
  } else {
    if ((length % 16) == 0) {
      flag = 1;
    } else {
      flag = 0;
    }
  }
  if (flag) {
    xor_128(&input[16 * (n - 1)], K1, M_last);
  } else {
    padding(&input[16 * (n - 1)], padded, length % 16);
    xor_128(padded, K2, M_last);
  }
  memset(X, 0, 16);
  for (i = 0; i < n - 1; i++) {
    xor_128(X, &input[16 * i], Y);
    AES_128_ENC(key, Y, X);
  }
  xor_128(X, M_last, Y);
  AES_128_ENC(key, Y, X);
  memcpy(mac, X, 16);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<AES_CMAC>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  lea    0x1e(%rbp),%r15d
  sub    $0x88,%rsp
  mov    %rcx,(%rsp)
  lea    0x60(%rsp),%r13
  lea    0x50(%rsp),%rsi
  mov    %r13,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  call   <generate_subkey@plt>
  mov    %ebp,%eax
  add    $0xf,%eax
  cmovns %eax,%r15d
  sar    $0x4,%r15d
  je     L45
  sub    $0x1,%r15d
  mov    0x8(%rsp),%rsi
  mov    %r15d,%edi
  shl    $0x4,%edi
  movslq %edi,%rdi
  add    %rbx,%rdi
  test   $0xf,%bpl
  je     L68
L79:
  mov    %ebp,%eax
  lea    0x30(%rsp),%r14
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    0x0(%rbp,%rax,1),%edx
  lea    0x40(%rsp),%rbp
  and    $0xf,%edx
  mov    %rbp,%rsi
  sub    %eax,%edx
  call   <padding@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <xor_128@plt>
L67:
  lea    0x10(%rsp),%rbp
  xor    %esi,%esi
  mov    $0x10,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  test   %r15d,%r15d
  jle    L42
  lea    -0x1(%r15),%eax
  lea    0x20(%rsp),%r13
  shl    $0x4,%rax
  lea    0x10(%rbx,%rax,1),%r15
  xchg   %ax,%ax
L56:
  mov    %rbx,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  add    $0x10,%rbx
  call   <xor_128@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <AES_128_ENC@plt>
  cmp    %r15,%rbx
  jne    L56
L35:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <xor_128@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <AES_128_ENC@plt>
  mov    (%rsp),%rdi
  mov    $0x10,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L68:
  lea    0x30(%rsp),%r14
  mov    %r14,%rdx
  call   <xor_128@plt>
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %rbx,%rdi
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L42:
  lea    0x20(%rsp),%r13
  jmp    L35
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void AES_CMAC(const unsigned char *key, const unsigned char *input, int length, unsigned char *mac) {
  unsigned char X[16], Y[16], M_last[16], padded[16];
  unsigned char K1[16], K2[16];
  int n, i, flag;
  generate_subkey(key, K1, K2);
  n = (length + (16 - 1)) / 16;
  if (n == 0) {
    n = 1;
    flag = 0;
  } else {
    if ((length % 16) == 0) {
      flag = 1;
    } else {
      flag = 0;
    }
  }
  if (flag) {
    xor_128(&input[16 * (n - 1)], K1, M_last);
  } else {
    padding(&input[16 * (n - 1)], padded, length % 16);
    xor_128(padded, K2, M_last);
  }
  memset(X, 0, 16);
  for (i = 0; i < n - 1; i++) {
    xor_128(X, &input[16 * i], Y);
    AES_128_ENC(key, Y, X);
  }
  xor_128(X, M_last, Y);
  AES_128_ENC(key, Y, X);
  memcpy(mac, X, 16);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<AES_CMAC>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  lea    0x1e(%rbp),%r15d
  sub    $0x88,%rsp
  mov    %rcx,(%rsp)
  lea    0x60(%rsp),%r13
  lea    0x50(%rsp),%rsi
  mov    %r13,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  call   <generate_subkey@plt>
  mov    %ebp,%eax
  add    $0xf,%eax
  cmovns %eax,%r15d
  sar    $0x4,%r15d
  je     L41
  sub    $0x1,%r15d
  mov    0x8(%rsp),%rsi
  mov    %r15d,%edi
  shl    $0x4,%edi
  movslq %edi,%rdi
  add    %rbx,%rdi
  test   $0xf,%bpl
  je     L79
L57:
  mov    %ebp,%eax
  lea    0x30(%rsp),%r14
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    0x0(%rbp,%rax,1),%edx
  lea    0x40(%rsp),%rbp
  and    $0xf,%edx
  mov    %rbp,%rsi
  sub    %eax,%edx
  call   <padding@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <xor_128@plt>
L66:
  lea    0x10(%rsp),%rbp
  xor    %esi,%esi
  mov    $0x10,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  test   %r15d,%r15d
  jle    L59
  lea    -0x1(%r15),%eax
  lea    0x20(%rsp),%r13
  shl    $0x4,%rax
  lea    0x10(%rbx,%rax,1),%r15
  xchg   %ax,%ax
L26:
  mov    %rbx,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  add    $0x10,%rbx
  call   <xor_128@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <AES_128_ENC@plt>
  cmp    %rbx,%r15
  jne    L26
L7:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <xor_128@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <AES_128_ENC@plt>
  mov    (%rsp),%rdi
  mov    $0x10,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L79:
  lea    0x30(%rsp),%r14
  mov    %r14,%rdx
  call   <xor_128@plt>
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %rbx,%rdi
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L59:
  lea    0x20(%rsp),%r13
  jmp    L7
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void AES_CMAC(const unsigned char *key, const unsigned char *input, int length, unsigned char *mac) {
  unsigned char X[16], Y[16], M_last[16], padded[16];
  unsigned char K1[16], K2[16];
  int n, i, flag;
  generate_subkey(key, K1, K2);
  n = (length + (16 - 1)) / 16;
  if (n == 0) {
    n = 1;
    flag = 0;
  } else {
    if ((length % 16) == 0) {
      flag = 1;
    } else {
      flag = 0;
    }
  }
  if (flag) {
    xor_128(&input[16 * (n - 1)], K1, M_last);
  } else {
    padding(&input[16 * (n - 1)], padded, length % 16);
    xor_128(padded, K2, M_last);
  }
  memset(X, 0, 16);
  for (i = 0; i < n - 1; i++) {
    xor_128(X, &input[16 * i], Y);
    AES_128_ENC(key, Y, X);
  }
  xor_128(X, M_last, Y);
  AES_128_ENC(key, Y, X);
  memcpy(mac, X, 16);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ppmov3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  movsd  %xmm0,-0x48(%rbp)
  movsd  %xmm1,-0x50(%rbp)
  movsd  %xmm2,-0x58(%rbp)
  movsd  %xmm3,-0x60(%rbp)
  movsd  %xmm4,-0x68(%rbp)
  movsd  %xmm5,-0x70(%rbp)
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rsi
  lea    -0x38(%rbp),%rcx
  movsd  -0x58(%rbp),%xmm1
  movsd  -0x50(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rdi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <ptod3@plt>
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  lea    -0x20(%rbp),%rcx
  movsd  -0x70(%rbp),%xmm4
  movsd  -0x68(%rbp),%xmm3
  movsd  -0x60(%rbp),%xmm2
  mov    %rcx,%rdi
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dpmov3@plt>
  movsd  -0x10(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  mov    -0x88(%rbp),%rdx
  mov    -0x80(%rbp),%rsi
  mov    -0x78(%rbp),%rcx
  mov    %rcx,%rdi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dtop3@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int ppmov3(double pro, double peo, double ppo, double dx, double dy, double dz, double *pr, double *pe, double *pp) {
  double dxo, dyo, dzo, x, y, z;
  ptod3(pro, peo, ppo, &dxo, &dyo, &dzo);
  dpmov3(dxo, dyo, dzo, dx, dy, dz, &x, &y, &z);
  dtop3(x, y, z, pr, pe, pp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ppmov3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  movq   %xmm3,%r13
  movq   %xmm4,%r14
  movq   %xmm5,%r15
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <ptod3@plt>
  lea    0x30(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  movq   %r15,%xmm5
  movq   %r14,%xmm4
  movq   %r13,%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <dpmov3@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  movsd  0x30(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm0
  call   <dtop3@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ppmov3(double pro, double peo, double ppo, double dx, double dy, double dz, double *pr, double *pe, double *pp) {
  double dxo, dyo, dzo, x, y, z;
  ptod3(pro, peo, ppo, &dxo, &dyo, &dzo);
  dpmov3(dxo, dyo, dzo, dx, dy, dz, &x, &y, &z);
  dtop3(x, y, z, pr, pe, pp);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ppmov3>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x60,%rsp
  movsd  %xmm3,0x18(%rsp)
  lea    0x38(%rsp),%rdx
  lea    0x30(%rsp),%rsi
  movsd  %xmm4,0x10(%rsp)
  lea    0x28(%rsp),%rdi
  movsd  %xmm5,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <ptod3@plt>
  movsd  0x38(%rsp),%xmm2
  lea    0x50(%rsp),%rdx
  movsd  0x30(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm0
  lea    0x48(%rsp),%rsi
  lea    0x40(%rsp),%rdi
  movsd  0x8(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm3
  call   <dpmov3@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x50(%rsp),%xmm2
  movsd  0x48(%rsp),%xmm1
  movsd  0x40(%rsp),%xmm0
  call   <dtop3@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ppmov3(double pro, double peo, double ppo, double dx, double dy, double dz, double *pr, double *pe, double *pp) {
  double dxo, dyo, dzo, x, y, z;
  ptod3(pro, peo, ppo, &dxo, &dyo, &dzo);
  dpmov3(dxo, dyo, dzo, dx, dy, dz, &x, &y, &z);
  dtop3(x, y, z, pr, pe, pp);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ppmov3>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x60,%rsp
  movsd  %xmm3,0x18(%rsp)
  lea    0x38(%rsp),%rdx
  lea    0x30(%rsp),%rsi
  movsd  %xmm4,0x10(%rsp)
  lea    0x28(%rsp),%rdi
  movsd  %xmm5,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <ptod3@plt>
  movsd  0x38(%rsp),%xmm2
  lea    0x50(%rsp),%rdx
  movsd  0x30(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm0
  lea    0x48(%rsp),%rsi
  lea    0x40(%rsp),%rdi
  movsd  0x8(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm3
  call   <dpmov3@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x50(%rsp),%xmm2
  movsd  0x48(%rsp),%xmm1
  movsd  0x40(%rsp),%xmm0
  call   <dtop3@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ppmov3(double pro, double peo, double ppo, double dx, double dy, double dz, double *pr, double *pe, double *pp) {
  double dxo, dyo, dzo, x, y, z;
  ptod3(pro, peo, ppo, &dxo, &dyo, &dzo);
  dpmov3(dxo, dyo, dzo, dx, dy, dz, &x, &y, &z);
  dtop3(x, y, z, pr, pe, pp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Free_Config>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <DBG@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_Buttons@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_Motor@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_Sensor@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_Timings@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_MotorCurves@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_Motormoves@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_Scanmodes@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_Constrains@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Free_Chipset@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <DBG@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D8
data_type: string

tool: D5: + Free_Config


tool: D8: - Free_Config


assistant: ```c
void Free_Config(struct st_device *dev) {
  DBG(0x02, "+ Free_Config\n");
  Free_Buttons(dev);
  Free_Motor(dev);
  Free_Sensor(dev);
  Free_Timings(dev);
  Free_MotorCurves(dev);
  Free_Motormoves(dev);
  Free_Scanmodes(dev);
  Free_Constrains(dev);
  Free_Chipset(dev);
  DBG(0x02, "- Free_Config\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Free_Config>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rsi
  mov    $0x2,%edi
  call   <DBG@plt>
  mov    %rbx,%rdi
  call   <Free_Buttons@plt>
  mov    %rbx,%rdi
  call   <Free_Motor@plt>
  mov    %rbx,%rdi
  call   <Free_Sensor@plt>
  mov    %rbx,%rdi
  call   <Free_Timings@plt>
  mov    %rbx,%rdi
  call   <Free_MotorCurves@plt>
  mov    %rbx,%rdi
  call   <Free_Motormoves@plt>
  mov    %rbx,%rdi
  call   <Free_Scanmodes@plt>
  mov    %rbx,%rdi
  call   <Free_Constrains@plt>
  mov    %rbx,%rdi
  call   <Free_Chipset@plt>
  lea    D4(%rip),%rsi
  mov    $0x2,%edi
  call   <DBG@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D5: + Free_Config


tool: D4: - Free_Config


assistant: ```c
void Free_Config(struct st_device *dev) {
  DBG(0x02, "+ Free_Config\n");
  Free_Buttons(dev);
  Free_Motor(dev);
  Free_Sensor(dev);
  Free_Timings(dev);
  Free_MotorCurves(dev);
  Free_Motormoves(dev);
  Free_Scanmodes(dev);
  Free_Constrains(dev);
  Free_Chipset(dev);
  DBG(0x02, "- Free_Config\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Free_Config>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rsi
  mov    %rdi,%rbp
  mov    $0x2,%edi
  call   <DBG@plt>
  mov    %rbp,%rdi
  call   <Free_Buttons@plt>
  mov    %rbp,%rdi
  call   <Free_Motor@plt>
  mov    %rbp,%rdi
  call   <Free_Sensor@plt>
  mov    %rbp,%rdi
  call   <Free_Timings@plt>
  mov    %rbp,%rdi
  call   <Free_MotorCurves@plt>
  mov    %rbp,%rdi
  call   <Free_Motormoves@plt>
  mov    %rbp,%rdi
  call   <Free_Scanmodes@plt>
  mov    %rbp,%rdi
  call   <Free_Constrains@plt>
  mov    %rbp,%rdi
  call   <Free_Chipset@plt>
  lea    D9(%rip),%rsi
  mov    $0x2,%edi
  pop    %rbp
  jmp    1140 <DBG@plt>
```

tool_calls: name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D9
type: string

tool: D11: + Free_Config


tool: D9: - Free_Config


assistant: ```c
void Free_Config(struct st_device *dev) {
  DBG(0x02, "+ Free_Config\n");
  Free_Buttons(dev);
  Free_Motor(dev);
  Free_Sensor(dev);
  Free_Timings(dev);
  Free_MotorCurves(dev);
  Free_Motormoves(dev);
  Free_Scanmodes(dev);
  Free_Constrains(dev);
  Free_Chipset(dev);
  DBG(0x02, "- Free_Config\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Free_Config>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rsi
  mov    %rdi,%rbp
  mov    $0x2,%edi
  call   <DBG@plt>
  mov    %rbp,%rdi
  call   <Free_Buttons@plt>
  mov    %rbp,%rdi
  call   <Free_Motor@plt>
  mov    %rbp,%rdi
  call   <Free_Sensor@plt>
  mov    %rbp,%rdi
  call   <Free_Timings@plt>
  mov    %rbp,%rdi
  call   <Free_MotorCurves@plt>
  mov    %rbp,%rdi
  call   <Free_Motormoves@plt>
  mov    %rbp,%rdi
  call   <Free_Scanmodes@plt>
  mov    %rbp,%rdi
  call   <Free_Constrains@plt>
  mov    %rbp,%rdi
  call   <Free_Chipset@plt>
  lea    D19(%rip),%rsi
  mov    $0x2,%edi
  pop    %rbp
  jmp    1140 <DBG@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string

tool: D15: + Free_Config


tool: D19: - Free_Config


assistant: ```c
void Free_Config(struct st_device *dev) {
  DBG(0x02, "+ Free_Config\n");
  Free_Buttons(dev);
  Free_Motor(dev);
  Free_Sensor(dev);
  Free_Timings(dev);
  Free_MotorCurves(dev);
  Free_Motormoves(dev);
  Free_Scanmodes(dev);
  Free_Constrains(dev);
  Free_Chipset(dev);
  DBG(0x02, "- Free_Config\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x48,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type_infered: string
name: unpack_data
arguments: label: D12
type_infered: string

tool: D16: My age is %d 


tool: D12: I am %d inches tall 


assistant: ```c
int main() {
  int age;
  int height = 72;
  printf("My age is %d \n", age);
  printf("I am %d inches tall \n", height);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D5
type_infered: string

tool: D3: My age is %d 


tool: D5: I am %d inches tall 


assistant: ```c
int main() {
  int age;
  int height = 72;
  printf("My age is %d \n", age);
  printf("I am %d inches tall \n", height);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string
name: read_data
arguments: tag: D9
datatype: string

tool: D4: My age is %d 


tool: D9: I am %d inches tall 


assistant: ```c
int main() {
  int age;
  int height = 72;
  printf("My age is %d \n", age);
  printf("I am %d inches tall \n", height);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x48,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string
name: unpack_data
arguments: data_label: D10
type_guessed: string

tool: D0: My age is %d 


tool: D10: I am %d inches tall 


assistant: ```c
int main() {
  int age;
  int height = 72;
  printf("My age is %d \n", age);
  printf("I am %d inches tall \n", height);
  return 0;
}
```