ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L48
  lea    -0x2(%rsi),%r11d
  push   %rbx
  lea    0x4(%rdi),%r8
  mov    $0x1,%r9d
  add    $0x2,%r11
  lea    -0x1(%rsi),%ebx
  lea    0x8(%rdi),%r10
  nopl   0x0(%rax,%rax,1)
L36:
  cmp    %r9d,%esi
  jle    L29
  mov    %ebx,%eax
  sub    %r9d,%eax
  lea    -0x1(%r9,%rax,1),%rax
  lea    (%r10,%rax,4),%rdi
  mov    %r8,%rax
  xchg   %ax,%ax
L9:
  mov    -0x4(%r8),%edx
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jle    L8
  mov    %ecx,-0x4(%r8)
  mov    %edx,(%rax)
L8:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L9
L29:
  add    $0x1,%r9
  add    $0x4,%r8
  cmp    %r11,%r9
  jne    L36
  pop    %rbx
  ret
L48:
  ret
```

assistant: ```c
void sort(int *a, int len) {
  int i, j, temp;
  for (i = 0; i < len - 1; i++)
    for (j = i + 1; j < len; j++) {
      if (a[i] > a[j]) {
        temp = a[i];
        a[i] = a[j];
        a[j] = temp;
      }
    }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trio_equal_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L25
  cmpq   $0x0,-0x18(%rbp)
  je     L25
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L29
L25:
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
int trio_equal_max(const char *first, size_t max, const char *second) {
  assert(first);
  assert(second);
  if ((first != 0) && (second != 0)) {
    return (0 == strncasecmp(first, second, max));
  }
  return (1 == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trio_equal_max>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L25
  test   %rbp,%rbp
  jne    L28
L25:
  mov    $0x0,%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L20
```

assistant: ```c
int trio_equal_max(const char *first, size_t max, const char *second) {
  assert(first);
  assert(second);
  if ((first != 0) && (second != 0)) {
    return (0 == strncasecmp(first, second, max));
  }
  return (1 == 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trio_equal_max>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  test   %rbp,%rbp
  je     L6
  test   %r12,%r12
  jne    L3
L6:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncasecmp@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int trio_equal_max(const char *first, size_t max, const char *second) {
  assert(first);
  assert(second);
  if ((first != 0) && (second != 0)) {
    return (0 == strncasecmp(first, second, max));
  }
  return (1 == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trio_equal_max>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  test   %rbp,%rbp
  je     L9
  test   %r12,%r12
  jne    L19
L9:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncasecmp@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int trio_equal_max(const char *first, size_t max, const char *second) {
  assert(first);
  assert(second);
  if ((first != 0) && (second != 0)) {
    return (0 == strncasecmp(first, second, max));
  }
  return (1 == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ui2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L29
L24:
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  cmp    %eax,-0x18(%rbp)
  jbe    L24
  jmp    L39
L71:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x18(%rbp)
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L21
  cmpl   $0x0,-0x4(%rbp)
  jg     L21
  cmpl   $0x0,-0x8(%rbp)
  jne    L39
L21:
  cmpl   $0x9,-0x4(%rbp)
  jle    L12
  cmpl   $0x0,-0x1c(%rbp)
  je     L83
  mov    $0x37,%edx
  jmp    L3
L83:
  mov    $0x57,%edx
  jmp    L3
L12:
  mov    $0x30,%edx
L3:
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L39:
  cmpl   $0x0,-0x8(%rbp)
  jne    L71
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ui2a(unsigned int num, unsigned int base, int uc, char *bf) {
  int n = 0;
  unsigned int d = 1;
  while (num / d >= base)
    d *= base;
  while (d != 0) {
    int dgt = num / d;
    num %= d;
    d /= base;
    if (n || dgt > 0 || d == 0) {
      *bf++ = dgt + (dgt < 10 ? '0' : (uc ? 'A' : 'a') - 10);
      ++n;
    }
  }
  *bf = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ui2a>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  mov    %rcx,%r10
  cmp    %esi,%edi
  jb     L15
  mov    $0x1,%ecx
L21:
  imul   %esi,%ecx
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  cmp    %esi,%eax
  jae    L21
  test   %ecx,%ecx
  je     L31
L43:
  mov    $0x0,%r9d
  jmp    L55
L15:
  mov    $0x1,%ecx
  jmp    L43
L26:
  lea    0x1(%r10),%r11
  add    %r8d,%edx
  mov    %dl,(%r10)
  add    $0x1,%r9d
  cmp    %ecx,%esi
  ja     L57
  mov    %r11,%r10
L19:
  mov    %eax,%ecx
L55:
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%edi
  mov    %eax,%r8d
  mov    %ecx,%eax
  mov    $0x0,%edx
  div    %esi
  test   %r9d,%r9d
  setne  %dl
  cmp    %ecx,%esi
  seta   %r11b
  or     %r11b,%dl
  jne    L70
  test   %r8d,%r8d
  jle    L42
L70:
  mov    $0x30,%edx
  cmp    $0x9,%r8d
  jle    L26
  cmp    $0x1,%ebx
  sbb    %edx,%edx
  and    $0x20,%edx
  add    $0x37,%edx
  jmp    L26
L42:
  mov    $0x0,%r9d
  jmp    L19
L31:
  mov    %r10,%r11
L57:
  movb   $0x0,(%r11)
  pop    %rbx
  ret
```

assistant: ```c
void ui2a(unsigned int num, unsigned int base, int uc, char *bf) {
  int n = 0;
  unsigned int d = 1;
  while (num / d >= base)
    d *= base;
  while (d != 0) {
    int dgt = num / d;
    num %= d;
    d /= base;
    if (n || dgt > 0 || d == 0) {
      *bf++ = dgt + (dgt < 10 ? '0' : (uc ? 'A' : 'a') - 10);
      ++n;
    }
  }
  *bf = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ui2a>:
  endbr64
  push   %rbx
  mov    %rcx,%r10
  mov    %edx,%ebx
  mov    $0x1,%ecx
  cmp    %esi,%edi
  jb     L65
  nopl   0x0(%rax,%rax,1)
L42:
  imul   %esi,%ecx
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  cmp    %esi,%eax
  jae    L42
  test   %ecx,%ecx
  je     L82
L65:
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L80:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %edx,%edi
  mov    %eax,%r8d
  xor    %edx,%edx
  mov    %ecx,%eax
  div    %esi
  test   %r9d,%r9d
  jne    L70
  test   %r8d,%r8d
  jg     L70
  cmp    %ecx,%esi
  jbe    L86
  add    $0x30,%r8d
  lea    0x1(%r10),%r11
  mov    %r8b,(%r10)
L55:
  movb   $0x0,(%r11)
  pop    %rbx
  ret
L70:
  mov    $0x30,%edx
  cmp    $0x9,%r8d
  jle    L21
  cmp    $0x1,%ebx
  sbb    %edx,%edx
  and    $0x20,%edx
  add    $0x37,%edx
L21:
  add    %r8d,%edx
  lea    0x1(%r10),%r11
  add    $0x1,%r9d
  mov    %dl,(%r10)
  cmp    %ecx,%esi
  ja     L55
  mov    %r11,%r10
L86:
  mov    %eax,%ecx
  jmp    L80
  nop
L82:
  mov    %r10,%r11
  movb   $0x0,(%r11)
  pop    %rbx
  ret
```

assistant: ```c
void ui2a(unsigned int num, unsigned int base, int uc, char *bf) {
  int n = 0;
  unsigned int d = 1;
  while (num / d >= base)
    d *= base;
  while (d != 0) {
    int dgt = num / d;
    num %= d;
    d /= base;
    if (n || dgt > 0 || d == 0) {
      *bf++ = dgt + (dgt < 10 ? '0' : (uc ? 'A' : 'a') - 10);
      ++n;
    }
  }
  *bf = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ui2a>:
  endbr64
  mov    %rcx,%r8
  mov    %edx,%r9d
  mov    $0x1,%ecx
  cmp    %esi,%edi
  jb     L22
  nopl   0x0(%rax,%rax,1)
L54:
  imul   %esi,%ecx
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  cmp    %esi,%eax
  jae    L54
  test   %ecx,%ecx
  je     L125
L22:
  push   %rbp
  xor    %r10d,%r10d
  push   %rbx
  test   %r9d,%r9d
  je     L46
  mov    $0x30,%ebp
  mov    $0x37,%ebx
  nopl   0x0(%rax)
L145:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %edx,%edi
  mov    %eax,%r9d
  xor    %edx,%edx
  mov    %ecx,%eax
  div    %esi
  test   %r10d,%r10d
  jne    L70
  test   %r9d,%r9d
  jg     L70
  cmp    %ecx,%esi
  jbe    L24
L91:
  add    $0x30,%r9d
  lea    0x1(%r8),%rdx
  mov    %r9b,(%r8)
L29:
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    $0x57,%ebp
  mov    $0x30,%ebx
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %edx,%edi
  mov    %eax,%r9d
  xor    %edx,%edx
  mov    %ecx,%eax
  div    %esi
  test   %r9d,%r9d
  jg     L74
  test   %r10d,%r10d
  jne    L74
  cmp    %ecx,%esi
  ja     L91
  xor    %r10d,%r10d
  mov    %eax,%ecx
  jmp    L60
  cs nopw 0x0(%rax,%rax,1)
L70:
  cmp    $0xa,%r9d
  mov    %ebx,%r11d
  lea    0x1(%r8),%rdx
  cmovl  %ebp,%r11d
  add    $0x1,%r10d
  add    %r11d,%r9d
  mov    %r9b,(%r8)
  cmp    %ecx,%esi
  ja     L29
  mov    %rdx,%r8
L24:
  mov    %eax,%ecx
  jmp    L145
  nopw   0x0(%rax,%rax,1)
L74:
  cmp    $0x9,%r9d
  mov    %ebx,%r11d
  lea    0x1(%r8),%rdx
  cmovg  %ebp,%r11d
  add    $0x1,%r10d
  add    %r11d,%r9d
  mov    %r9b,(%r8)
  cmp    %ecx,%esi
  ja     L29
  mov    %rdx,%r8
  mov    %eax,%ecx
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L125:
  movb   $0x0,(%r8)
  ret
```

assistant: ```c
void ui2a(unsigned int num, unsigned int base, int uc, char *bf) {
  int n = 0;
  unsigned int d = 1;
  while (num / d >= base)
    d *= base;
  while (d != 0) {
    int dgt = num / d;
    num %= d;
    d /= base;
    if (n || dgt > 0 || d == 0) {
      *bf++ = dgt + (dgt < 10 ? '0' : (uc ? 'A' : 'a') - 10);
      ++n;
    }
  }
  *bf = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <powerFor@plt>
  mov    %eax,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <powerWhile@plt>
  mov    %eax,%ecx
  mov    $0x5,%edx
  mov    $0x8,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string

tool: D4: %d ^ %d = %d


assistant: ```c
int main() {
  printf("%d ^ %d = %d\n", 2, 3, powerFor(2, 3));
  printf("%d ^ %d = %d\n", 8, 5, powerWhile(8, 5));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <powerFor@plt>
  mov    %eax,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <powerWhile@plt>
  mov    %eax,%ecx
  mov    $0x5,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: %d ^ %d = %d


assistant: ```c
int main() {
  printf("%d ^ %d = %d\n", 2, 3, powerFor(2, 3));
  printf("%d ^ %d = %d\n", 8, 5, powerWhile(8, 5));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%esi
  mov    $0x2,%edi
  lea    D9(%rip),%rbp
  call   <powerFor@plt>
  mov    $0x3,%edx
  mov    %rbp,%rdi
  mov    $0x2,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <powerWhile@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    $0x8,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: %d ^ %d = %d


assistant: ```c
int main() {
  printf("%d ^ %d = %d\n", 2, 3, powerFor(2, 3));
  printf("%d ^ %d = %d\n", 8, 5, powerWhile(8, 5));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%esi
  mov    $0x2,%edi
  lea    D6(%rip),%rbp
  call   <powerFor@plt>
  mov    $0x3,%edx
  mov    %rbp,%rdi
  mov    $0x2,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <powerWhile@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    $0x8,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: %d ^ %d = %d


assistant: ```c
int main() {
  printf("%d ^ %d = %d\n", 2, 3, powerFor(2, 3));
  printf("%d ^ %d = %d\n", 8, 5, powerWhile(8, 5));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CumSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm3
  mov    $0x0,%ebx
  jmp    L4
L1:
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  (%rax),%xmm0
  movapd %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm3
  add    $0x1,%ebx
L4:
  cmp    -0x14(%rbp),%ebx
  jl     L1
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double CumSum(double *xa, int n) {
  register int i;
  register double sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += *xa++;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CumSum>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    %esi,%esi
  lea    (%rdi,%rsi,8),%rax
  pxor   %xmm0,%xmm0
L5:
  add    $0x8,%rdi
  addsd  -0x8(%rdi),%xmm0
  cmp    %rax,%rdi
  jne    L5
  ret
L15:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double CumSum(double *xa, int n) {
  register int i;
  register double sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += *xa++;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CumSum>:
  endbr64
  test   %esi,%esi
  jle    L7
  movslq %esi,%rsi
  pxor   %xmm0,%xmm0
  lea    (%rdi,%rsi,8),%rax
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x8,%rdi
  addsd  -0x8(%rdi),%xmm0
  cmp    %rax,%rdi
  jne    L5
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double CumSum(double *xa, int n) {
  register int i;
  register double sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += *xa++;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CumSum>:
  endbr64
  test   %esi,%esi
  jle    L21
  cmp    $0x1,%esi
  je     L14
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L30:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L30
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  mov    %eax,%edx
  lea    (%rdi,%rdx,8),%rdi
  cmp    %eax,%esi
  je     L37
L2:
  addsd  (%rdi),%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L37:
  ret
  nopl   0x0(%rax)
L21:
  pxor   %xmm0,%xmm0
  ret
L14:
  pxor   %xmm0,%xmm0
  jmp    L2
```

assistant: ```c
double CumSum(double *xa, int n) {
  register int i;
  register double sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += *xa++;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<setToZero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movw   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  movw   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  movw   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movw   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  movw   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setToZero(short **t) {
  *(*t) = 0;
  *((*t) + 1) = 0;
  *((*t) + 2) = 0;
  *(*(t + 1)) = 0;
  *(*(t + 1) + 1) = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setToZero>:
  endbr64
  mov    (%rdi),%rax
  movw   $0x0,(%rax)
  mov    (%rdi),%rax
  movw   $0x0,0x2(%rax)
  mov    (%rdi),%rax
  movw   $0x0,0x4(%rax)
  mov    0x8(%rdi),%rax
  movw   $0x0,(%rax)
  mov    0x8(%rdi),%rax
  movw   $0x0,0x2(%rax)
  ret
```

assistant: ```c
void setToZero(short **t) {
  *(*t) = 0;
  *((*t) + 1) = 0;
  *((*t) + 2) = 0;
  *(*(t + 1)) = 0;
  *(*(t + 1) + 1) = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setToZero>:
  endbr64
  mov    (%rdi),%rax
  xor    %edx,%edx
  movl   $0x0,(%rax)
  mov    %dx,0x4(%rax)
  mov    0x8(%rdi),%rax
  movl   $0x0,(%rax)
  ret
```

assistant: ```c
void setToZero(short **t) {
  *(*t) = 0;
  *((*t) + 1) = 0;
  *((*t) + 2) = 0;
  *(*(t + 1)) = 0;
  *(*(t + 1) + 1) = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setToZero>:
  endbr64
  mov    (%rdi),%rax
  xor    %edx,%edx
  movl   $0x0,(%rax)
  mov    %dx,0x4(%rax)
  mov    0x8(%rdi),%rax
  movl   $0x0,(%rax)
  ret
```

assistant: ```c
void setToZero(short **t) {
  *(*t) = 0;
  *((*t) + 1) = 0;
  *((*t) + 2) = 0;
  *(*(t + 1)) = 0;
  *(*(t + 1) + 1) = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StrShuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L2
L13:
  mov    $0x0,%eax
  call   <sre_random@plt>
  mov    -0x8(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0x1,-0x8(%rbp)
  jg     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void StrShuffle(char *s1, char *s2) {
  int len;
  int pos;
  char c;
  strcpy(s1, s2);
  for (len = strlen(s1); len > 1; len--) {
    pos = ((int)(sre_random() * (len)));
    c = s1[pos];
    s1[pos] = s1[len - 1];
    s1[len - 1] = c;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<StrShuffle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L17
  movslq %eax,%rbx
L12:
  mov    $0x0,%eax
  call   <sre_random@plt>
  imul   %ebx,%eax
  cltq
  add    %rbp,%rax
  movzbl (%rax),%edx
  movzbl -0x1(%rbp,%rbx,1),%ecx
  mov    %cl,(%rax)
  mov    %dl,-0x1(%rbp,%rbx,1)
  sub    $0x1,%rbx
  cmp    $0x1,%ebx
  jg     L12
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void StrShuffle(char *s1, char *s2) {
  int len;
  int pos;
  char c;
  strcpy(s1, s2);
  for (len = strlen(s1); len > 1; len--) {
    pos = ((int)(sre_random() * (len)));
    c = s1[pos];
    s1[pos] = s1[len - 1];
    s1[len - 1] = c;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StrShuffle>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L0
  movslq %eax,%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <sre_random@plt>
  movzbl -0x1(%rbp,%rbx,1),%ecx
  imul   %ebx,%eax
  cltq
  add    %rbp,%rax
  movzbl (%rax),%edx
  mov    %cl,(%rax)
  mov    %dl,-0x1(%rbp,%rbx,1)
  sub    $0x1,%rbx
  cmp    $0x1,%ebx
  jg     L6
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void StrShuffle(char *s1, char *s2) {
  int len;
  int pos;
  char c;
  strcpy(s1, s2);
  for (len = strlen(s1); len > 1; len--) {
    pos = ((int)(sre_random() * (len)));
    c = s1[pos];
    s1[pos] = s1[len - 1];
    s1[len - 1] = c;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<StrShuffle>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L13
  movslq %eax,%rbx
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <sre_random@plt>
  movzbl -0x1(%rbp,%rbx,1),%ecx
  imul   %ebx,%eax
  cltq
  add    %rbp,%rax
  movzbl (%rax),%edx
  mov    %cl,(%rax)
  mov    %dl,-0x1(%rbp,%rbx,1)
  sub    $0x1,%rbx
  cmp    $0x1,%ebx
  jg     L1
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void StrShuffle(char *s1, char *s2) {
  int len;
  int pos;
  char c;
  strcpy(s1, s2);
  for (len = strlen(s1); len > 1; len--) {
    pos = ((int)(sre_random() * (len)));
    c = s1[pos];
    s1[pos] = s1[len - 1];
    s1[len - 1] = c;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delete_device>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_device@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L22
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <dprintf@plt>
  mov    $0x1,%eax
  jmp    L29
L22:
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x4c81,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  jns    L21
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L21:
  mov    $0x0,%eax
L29:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: ignoring illegal devicename '%s'


assistant: ```c
int delete_device(int fd, const char *devicename) {
  int dev = parse_device(devicename);
  if (dev < 0) {
    dprintf(2, "ignoring illegal devicename '%s'\n", devicename);
    return 1;
  }
  if (ioctl(fd, 0x4C81, dev) < 0)
    perror(devicename);
  return 0;
}
```