user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x350,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x350(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x34c(%rbp)
  jmp    L70
L69:
  lea    -0x340(%rbp),%rdx
  mov    -0x34c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34c(%rbp)
L70:
  mov    -0x350(%rbp),%eax
  cmp    %eax,-0x34c(%rbp)
  jle    L69
  mov    -0x350(%rbp),%eax
  mov    %eax,-0x344(%rbp)
  movl   $0x1,-0x34c(%rbp)
  jmp    L82
L56:
  mov    -0x350(%rbp),%eax
  cmp    %eax,-0x34c(%rbp)
  je     L98
  mov    -0x34c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x34c(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  jmp    L19
L98:
  mov    -0x34c(%rbp),%eax
  cltq
  movl   $0x0,-0x1a0(%rbp,%rax,4)
L19:
  addl   $0x1,-0x34c(%rbp)
L82:
  mov    -0x350(%rbp),%eax
  cmp    %eax,-0x34c(%rbp)
  jle    L56
  addl   $0x1,-0x344(%rbp)
  lea    -0x340(%rbp),%rdx
  mov    -0x344(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x348(%rbp)
  jmp    L9
L3:
  mov    -0x348(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cltq
  mov    -0x340(%rbp,%rax,4),%edx
  mov    -0x344(%rbp),%eax
  cltq
  mov    -0x340(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L5
  mov    -0x348(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x344(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x348(%rbp),%eax
  cltq
  mov    -0x344(%rbp),%edx
  mov    %edx,-0x1a0(%rbp,%rax,4)
  jmp    L42
L5:
  mov    -0x348(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x348(%rbp)
L9:
  cmpl   $0x0,-0x348(%rbp)
  jne    L3
L42:
  movl   $0x1,-0x348(%rbp)
  jmp    L6
L34:
  mov    -0x348(%rbp),%eax
  cltq
  mov    -0x340(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x348(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x348(%rbp)
L6:
  cmpl   $0x0,-0x348(%rbp)
  jne    L34
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D23
type_infered: string

tool: D20: %d

tool: D23: %d 

assistant: ```c
int main() {
  int data[101], right[101];
  int i, n, t, len;
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    scanf("%d", &data[i]);
  len = n;
  for (i = 1; i <= n; i++) {
    if (i != n)
      right[i] = i + 1;
    else
      right[i] = 0;
  }
  len++;
  scanf("%d", &data[len]);
  t = 1;
  while (t != 0) {
    if (data[right[t]] > data[len]) {
      right[len] = right[t];
      right[t] = len;
      break;
    }
    t = right[t];
  }
  t = 1;
  while (t != 0) {
    printf("%d ", data[t]);
    t = right[t];
  }
  getchar();
  getchar();
  return 0;
}
```