ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<strlappendn>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L89
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L89
  mov    %rdi,%rbx
  mov    %rdx,%r14
  mov    %rcx,%r15
  xor    %r12d,%r12d
  jmp    L107
  nopl   (%rax)
L10:
  cmpb   $0x0,(%rbx,%r12,1)
  je     L145
  add    $0x1,%r12
L107:
  mov    %r13,%rdi
  call   <size_less_null@plt>
  lea    (%r12,%rbx,1),%rdx
  cmp    %r12,%rax
  ja     L10
L145:
  test   %r14,%r14
  je     L12
  test   %r15,%r15
  jne    L70
L12:
  movb   $0x0,(%rdx)
L157:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L89:
  xor    %r12d,%r12d
  jmp    L157
  nopl   (%rax)
L70:
  mov    %r15,%rdi
  call   <size_less_null@plt>
  add    %r14,%rax
  cmp    %rax,%rbx
  ja     L5
  lea    (%rbx,%r13,1),%rax
  cmp    %rax,%r14
  jb     L165
L5:
  mov    %r12,%rbp
  sub    %r12,%r14
  jmp    L139
  nopl   0x0(%rax)
L64:
  movzbl (%r14,%rbp,1),%eax
  test   %al,%al
  je     L34
  add    $0x1,%rbp
  mov    %al,-0x1(%rbx,%rbp,1)
  lea    (%r12,%r15,1),%rax
  cmp    %rax,%rbp
  je     L13
L139:
  mov    %r13,%rdi
  call   <size_less_null@plt>
  lea    (%rbx,%rbp,1),%rdx
  cmp    %rbp,%rax
  ja     L64
L34:
  mov    %rbp,%r12
  jmp    L12
L13:
  lea    (%rbx,%rbp,1),%rdx
  mov    %rbp,%r12
  jmp    L12
L165:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strllen@plt>
  mov    %rax,%r15
  jmp    L5
```

assistant: ```c
size_t strlappendn(char *dest, size_t dest_size, const char *src, size_t src_size) {
  size_t i;
  if (!dest)
    return 0;
  if (dest_size <= 0)
    return 0;
  for (i = 0; i < size_less_null(dest_size); ++i)
    if (!dest[i])
      break;
  if ((src) && (src_size >= 1)) {
    if ((dest <= src + size_less_null(src_size)) && (src < dest + dest_size)) {
      src_size = strllen(src, src_size);
    }
    while (i < size_less_null(dest_size)) {
      if (!*src)
        break;
      dest[i++] = *src++;
      if (--src_size <= 0)
        break;
    }
  }
  dest[i] = 0;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlappendn>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L15
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L15
  mov    %rdi,%rbx
  mov    %rdx,%r14
  mov    %rcx,%r15
  xor    %r12d,%r12d
  jmp    L66
  nopl   (%rax)
L57:
  cmpb   $0x0,(%rbx,%r12,1)
  je     L10
  add    $0x1,%r12
L66:
  mov    %r13,%rdi
  call   <size_less_null@plt>
  lea    (%r12,%rbx,1),%rdx
  cmp    %r12,%rax
  ja     L57
L10:
  test   %r14,%r14
  je     L20
  test   %r15,%r15
  jne    L65
L20:
  movb   $0x0,(%rdx)
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %r12d,%r12d
  jmp    L6
  nopl   (%rax)
L65:
  mov    %r15,%rdi
  call   <size_less_null@plt>
  add    %r14,%rax
  cmp    %rax,%rbx
  ja     L78
  lea    (%rbx,%r13,1),%rax
  cmp    %rax,%r14
  jb     L5
L78:
  mov    %r12,%rbp
  sub    %r12,%r14
  jmp    L35
  nopl   0x0(%rax)
L109:
  movzbl (%r14,%rbp,1),%eax
  test   %al,%al
  je     L41
  add    $0x1,%rbp
  mov    %al,-0x1(%rbx,%rbp,1)
  lea    (%r12,%r15,1),%rax
  cmp    %rax,%rbp
  je     L97
L35:
  mov    %r13,%rdi
  call   <size_less_null@plt>
  lea    (%rbx,%rbp,1),%rdx
  cmp    %rbp,%rax
  ja     L109
L41:
  mov    %rbp,%r12
  jmp    L20
L97:
  lea    (%rbx,%rbp,1),%rdx
  mov    %rbp,%r12
  jmp    L20
L5:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strllen@plt>
  mov    %rax,%r15
  jmp    L78
```

assistant: ```c
size_t strlappendn(char *dest, size_t dest_size, const char *src, size_t src_size) {
  size_t i;
  if (!dest)
    return 0;
  if (dest_size <= 0)
    return 0;
  for (i = 0; i < size_less_null(dest_size); ++i)
    if (!dest[i])
      break;
  if ((src) && (src_size >= 1)) {
    if ((dest <= src + size_less_null(src_size)) && (src < dest + dest_size)) {
      src_size = strllen(src, src_size);
    }
    while (i < size_less_null(dest_size)) {
      if (!*src)
        break;
      dest[i++] = *src++;
      if (--src_size <= 0)
        break;
    }
  }
  dest[i] = 0;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reed_sol_extended_vandermonde_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %esi,%r14d
  mov    %edx,%r12d
  cmp    $0x1d,%edx
  jg     L97
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L149
  cmp    %esi,%eax
  jl     L159
L97:
  mov    %ebx,%ebp
  imul   %r14d,%ebp
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L129
  movl   $0x1,(%rax)
  cmp    $0x1,%r14d
  jle    L8
  lea    0x4(%rax),%rax
  lea    -0x2(%r14),%edx
  lea    0x8(%r15,%rdx,4),%rdx
L82:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L82
  cmp    $0x1,%ebx
  je     L39
  lea    -0x1(%rbx),%eax
  mov    %eax,0x10(%rsp)
  sub    %r14d,%ebp
  lea    -0x1(%r14),%ecx
  movslq %ebp,%rax
  lea    (%r15,%rax,4),%rdx
  mov    $0x0,%eax
L145:
  movl   $0x0,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%ecx
  jg     L145
  test   %ecx,%ecx
  mov    $0x1,%eax
  cmovle %eax,%ecx
L48:
  add    %ecx,%ebp
  movslq %ebp,%rbp
  movl   $0x1,(%r15,%rbp,4)
  cmp    $0x2,%ebx
  je     L39
  cmpl   $0x1,0x10(%rsp)
  jle    L39
  mov    %r14d,0xc(%rsp)
  mov    $0x1,%ebp
  lea    -0x1(%r14),%eax
  mov    %eax,0x14(%rsp)
  jmp    L128
L8:
  cmp    $0x1,%ebx
  je     L39
  lea    -0x1(%rbx),%eax
  mov    %eax,0x10(%rsp)
  sub    %r14d,%ebp
  mov    $0x0,%ecx
  jmp    L48
L138:
  movslq 0xc(%rsp),%rdx
  lea    (%r15,%rdx,4),%rbx
  mov    0x14(%rsp),%eax
  add    %rdx,%rax
  lea    0x4(%r15,%rax,4),%r13
  mov    $0x1,%edi
L101:
  mov    %edi,(%rbx)
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <galois_single_multiply@plt>
  mov    %eax,%edi
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L101
L189:
  add    $0x1,%ebp
  add    %r14d,0xc(%rsp)
  cmp    %ebp,0x10(%rsp)
  je     L39
L128:
  test   %r14d,%r14d
  jg     L138
  jmp    L189
L149:
  movq   $0x0,0x18(%rsp)
  jmp    L39
L159:
  movq   $0x0,0x18(%rsp)
  jmp    L39
L129:
  movq   $0x0,0x18(%rsp)
L39:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *reed_sol_extended_vandermonde_matrix(int rows, int cols, int w) {
  int *vdm;
  int i, j, k;
  if (w < 30 && (1 << w) < rows)
    return NULL;
  if (w < 30 && (1 << w) < cols)
    return NULL;
  vdm = (int *)malloc(sizeof(int) * (rows * cols));
  if (vdm == NULL) {
    return NULL;
  }
  vdm[0] = 1;
  for (j = 1; j < cols; j++)
    vdm[j] = 0;
  if (rows == 1)
    return vdm;
  i = (rows - 1) * cols;
  for (j = 0; j < cols - 1; j++)
    vdm[i + j] = 0;
  vdm[i + j] = 1;
  if (rows == 2)
    return vdm;
  for (i = 1; i < rows - 1; i++) {
    k = 1;
    for (j = 0; j < cols; j++) {
      vdm[i * cols + j] = k;
      k = galois_single_multiply(k, i, w);
    }
  }
  return vdm;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reed_sol_extended_vandermonde_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  cmp    $0x1d,%edx
  jg     L52
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L76
  cmp    %esi,%eax
  jl     L76
L52:
  mov    %ebx,%r12d
  imul   %r13d,%r12d
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%r14
  test   %rax,%rax
  je     L76
  movl   $0x1,(%rax)
  cmp    $0x1,%r13d
  jle    L94
  lea    -0x1(%r13),%edx
  xor    %esi,%esi
  lea    0x4(%rax),%rdi
  mov    %rdx,%r15
  shl    $0x2,%rdx
  call   <memset@plt>
  cmp    $0x1,%ebx
  je     L120
  lea    -0x1(%rbx),%eax
  movslq %r15d,%rdx
  mov    %eax,0x10(%rsp)
  shl    $0x2,%rdx
  mov    $0x4,%eax
  test   %r15d,%r15d
  cmovle %rax,%rdx
  mov    %r12d,%eax
  xor    %esi,%esi
  sub    $0x1,%r12d
  sub    %r13d,%eax
  cltq
  lea    (%r14,%rax,4),%rdi
  call   <memset@plt>
L18:
  movslq %r12d,%r12
  movl   $0x1,(%r14,%r12,4)
  cmp    $0x2,%ebx
  je     L120
  cmpl   $0x1,0x10(%rsp)
  jle    L120
  lea    -0x1(%r13),%eax
  mov    %r13d,0xc(%rsp)
  mov    $0x1,%ebx
  mov    %eax,0x14(%rsp)
  nopl   (%rax)
L36:
  test   %r13d,%r13d
  jle    L133
  movslq 0xc(%rsp),%rdx
  mov    0x14(%rsp),%eax
  mov    $0x1,%edi
  add    %rdx,%rax
  lea    (%r14,%rdx,4),%r15
  lea    0x4(%r14,%rax,4),%r12
  nopw   0x0(%rax,%rax,1)
L68:
  mov    %edi,(%r15)
  mov    %ebp,%edx
  mov    %ebx,%esi
  add    $0x4,%r15
  call   <galois_single_multiply@plt>
  mov    %eax,%edi
  cmp    %r15,%r12
  jne    L68
L133:
  add    %r13d,0xc(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,0x10(%rsp)
  jne    L36
L120:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L76:
  movq   $0x0,0x18(%rsp)
  jmp    L120
L94:
  cmp    $0x1,%ebx
  je     L120
  lea    -0x1(%rbx),%eax
  sub    %r13d,%r12d
  mov    %eax,0x10(%rsp)
  jmp    L18
```

assistant: ```c
int *reed_sol_extended_vandermonde_matrix(int rows, int cols, int w) {
  int *vdm;
  int i, j, k;
  if (w < 30 && (1 << w) < rows)
    return NULL;
  if (w < 30 && (1 << w) < cols)
    return NULL;
  vdm = (int *)malloc(sizeof(int) * (rows * cols));
  if (vdm == NULL) {
    return NULL;
  }
  vdm[0] = 1;
  for (j = 1; j < cols; j++)
    vdm[j] = 0;
  if (rows == 1)
    return vdm;
  i = (rows - 1) * cols;
  for (j = 0; j < cols - 1; j++)
    vdm[i + j] = 0;
  vdm[i + j] = 1;
  if (rows == 2)
    return vdm;
  for (i = 1; i < rows - 1; i++) {
    k = 1;
    for (j = 0; j < cols; j++) {
      vdm[i * cols + j] = k;
      k = galois_single_multiply(k, i, w);
    }
  }
  return vdm;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reed_sol_extended_vandermonde_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    $0x1d,%edx
  jg     L41
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L63
  cmp    %esi,%eax
  jl     L63
L41:
  mov    %ebx,%ebp
  imul   %r13d,%ebp
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%rcx
  test   %rax,%rax
  je     L63
  movl   $0x1,(%rax)
  cmp    $0x1,%r13d
  jle    L57
  lea    -0x1(%r13),%edx
  xor    %esi,%esi
  lea    0x4(%rax),%rdi
  mov    %rax,(%rsp)
  mov    %rdx,%r15
  shl    $0x2,%rdx
  call   <memset@plt>
  cmp    $0x1,%ebx
  mov    (%rsp),%rcx
  je     L49
  movslq %r15d,%rdx
  mov    $0x4,%eax
  mov    %rcx,(%rsp)
  lea    -0x1(%rbx),%r14d
  shl    $0x2,%rdx
  test   %r15d,%r15d
  cmovle %rax,%rdx
  mov    %ebp,%eax
  xor    %esi,%esi
  sub    $0x1,%ebp
  sub    %r13d,%eax
  cltq
  lea    (%rcx,%rax,4),%rdi
  call   <memset@plt>
  mov    (%rsp),%rcx
L110:
  movslq %ebp,%rbp
  movl   $0x1,(%rcx,%rbp,4)
  cmp    $0x2,%ebx
  je     L49
  cmp    $0x1,%r14d
  jle    L49
  test   %r13d,%r13d
  jle    L49
  movslq %r13d,%rax
  lea    -0x1(%r13),%edx
  mov    %r13d,%r13d
  mov    $0x1,%ebx
  lea    0x0(,%rax,4),%r15
  neg    %r13
  lea    0x1(%rax,%rdx,1),%rax
  lea    (%rcx,%rax,4),%rbp
  lea    0x0(,%r13,4),%rax
  mov    %rax,(%rsp)
  nop
L1:
  mov    (%rsp),%rax
  mov    $0x1,%edi
  lea    (%rax,%rbp,1),%r13
  nopl   (%rax)
L62:
  mov    %edi,0x0(%r13)
  mov    %r12d,%edx
  mov    %ebx,%esi
  add    $0x4,%r13
  call   <galois_single_multiply@plt>
  mov    %eax,%edi
  cmp    %rbp,%r13
  jne    L62
  add    $0x1,%ebx
  add    %r15,%rbp
  cmp    %ebx,%r14d
  jne    L1
L49:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  movq   $0x0,0x8(%rsp)
  jmp    L49
L57:
  cmp    $0x1,%ebx
  je     L49
  lea    -0x1(%rbx),%r14d
  sub    %r13d,%ebp
  jmp    L110
```

assistant: ```c
int *reed_sol_extended_vandermonde_matrix(int rows, int cols, int w) {
  int *vdm;
  int i, j, k;
  if (w < 30 && (1 << w) < rows)
    return NULL;
  if (w < 30 && (1 << w) < cols)
    return NULL;
  vdm = (int *)malloc(sizeof(int) * (rows * cols));
  if (vdm == NULL) {
    return NULL;
  }
  vdm[0] = 1;
  for (j = 1; j < cols; j++)
    vdm[j] = 0;
  if (rows == 1)
    return vdm;
  i = (rows - 1) * cols;
  for (j = 0; j < cols - 1; j++)
    vdm[i + j] = 0;
  vdm[i + j] = 1;
  if (rows == 2)
    return vdm;
  for (i = 1; i < rows - 1; i++) {
    k = 1;
    for (j = 0; j < cols; j++) {
      vdm[i * cols + j] = k;
      k = galois_single_multiply(k, i, w);
    }
  }
  return vdm;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xb,-0x44(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0xfffffffc,-0x14(%rbp)
  lea    -0x40(%rbp),%rsi
  lea    -0x4c(%rbp),%rcx
  mov    -0x44(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rsi,%r8
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <fourSum@plt>
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L11
L16:
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0xc,%rax
  mov    (%rax),%esi
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x8,%rax
  mov    (%rax),%ecx
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdi
  mov    -0x38(%rbp),%rax
  add    %rdi,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x48(%rbp)
L11:
  mov    -0x4c(%rbp),%eax
  cmp    %eax,-0x48(%rbp)
  jl     L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d %d %d %d


assistant: ```c
int main(void) {
  int i, count, target = 11, *col_sizes;
  int nums[] = {0, 1, 5, 0, 1, 5, 5, -4};
  int **quadruplets = fourSum(nums, sizeof(nums) / sizeof(*nums), target, &count, &col_sizes);
  for (i = 0; i < count; i++) {
    printf("%d %d %d %d\n", quadruplets[i][0], quadruplets[i][1], quadruplets[i][2], quadruplets[i][3]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  movl   $0x5,0x28(%rsp)
  movl   $0xfffffffc,0x2c(%rsp)
  lea    0x4(%rsp),%rcx
  lea    0x10(%rsp),%rdi
  lea    0x8(%rsp),%r8
  mov    $0xb,%edx
  mov    $0x8,%esi
  call   <fourSum@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L12
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
L0:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    0xc(%rax),%r8d
  mov    (%rax),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  jg     L0
L12:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string

tool: D7: %d %d %d %d


assistant: ```c
int main(void) {
  int i, count, target = 11, *col_sizes;
  int nums[] = {0, 1, 5, 0, 1, 5, 5, -4};
  int **quadruplets = fourSum(nums, sizeof(nums) / sizeof(*nums), target, &count, &col_sizes);
  for (i = 0; i < count; i++) {
    printf("%d %d %d %d\n", quadruplets[i][0], quadruplets[i][1], quadruplets[i][2], quadruplets[i][3]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%edx
  mov    $0x8,%esi
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x100000000,%rax
  lea    0x4(%rsp),%rcx
  lea    0x10(%rsp),%rdi
  movq   $0x5,0x18(%rsp)
  lea    0x8(%rsp),%r8
  mov    %rax,0x10(%rsp)
  movabs $0x500000001,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xfffffffc00000005,%rax
  mov    %rax,0x28(%rsp)
  call   <fourSum@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L11
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D3(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L10:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %r12,%rdi
  add    $0x1,%rbx
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    0xc(%rax),%r8d
  mov    (%rax),%esi
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L10
L11:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: %d %d %d %d


assistant: ```c
int main(void) {
  int i, count, target = 11, *col_sizes;
  int nums[] = {0, 1, 5, 0, 1, 5, 5, -4};
  int **quadruplets = fourSum(nums, sizeof(nums) / sizeof(*nums), target, &count, &col_sizes);
  for (i = 0; i < count; i++) {
    printf("%d %d %d %d\n", quadruplets[i][0], quadruplets[i][1], quadruplets[i][2], quadruplets[i][3]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%edx
  mov    $0x8,%esi
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D25(%rip),%xmm0
  lea    0x8(%rsp),%r8
  movaps %xmm0,0x20(%rsp)
  call   <fourSum@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L3
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D17(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L23:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %r12,%rdi
  add    $0x1,%rbx
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    0xc(%rax),%r8d
  mov    (%rax),%esi
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L23
L3:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_guessed: byte[16]
name: unpack_data
arguments: tag: D25
type_guessed: byte[16]
name: unpack_data
arguments: tag: D17
type_guessed: string

tool: {"D11": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D25": [0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0xfc,0xff,0xff,0xff]}

tool: D17: %d %d %d %d


assistant: ```c
int main(void) {
  int i, count, target = 11, *col_sizes;
  int nums[] = {0, 1, 5, 0, 1, 5, 5, -4};
  int **quadruplets = fourSum(nums, sizeof(nums) / sizeof(*nums), target, &count, &col_sizes);
  for (i = 0; i < count; i++) {
    printf("%d %d %d %d\n", quadruplets[i][0], quadruplets[i][1], quadruplets[i][2], quadruplets[i][3]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<exif_put_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L15
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  jmp    L1
L15:
  mov    $0x0,%eax
L1:
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %rcx,%r9
  mov    $0x0,%r8d
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    %eax,%edi
  call   <exif_put_value@plt>
  nop
  leave
  ret
```

assistant: ```c
void exif_put_str(const int ifd_nr, const int tag_id, const char *val) {
  int len = (val) ? strlen(val) + 1 : 0;
  exif_put_value(ifd_nr, tag_id, 2, len, 0, val);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exif_put_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L1
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ecx
L1:
  mov    %rbx,%r9
  mov    $0x0,%r8d
  mov    $0x2,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <exif_put_value@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void exif_put_str(const int ifd_nr, const int tag_id, const char *val) {
  int len = (val) ? strlen(val) + 1 : 0;
  exif_put_value(ifd_nr, tag_id, 2, len, 0, val);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<exif_put_str>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L2
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ecx
L2:
  mov    %rbx,%r9
  mov    %r12d,%esi
  pop    %rbx
  mov    %ebp,%edi
  xor    %r8d,%r8d
  pop    %rbp
  mov    $0x2,%edx
  pop    %r12
  jmp    1070 <exif_put_value@plt>
```

assistant: ```c
void exif_put_str(const int ifd_nr, const int tag_id, const char *val) {
  int len = (val) ? strlen(val) + 1 : 0;
  exif_put_value(ifd_nr, tag_id, 2, len, 0, val);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<exif_put_str>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L7
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ecx
L7:
  mov    %rbx,%r9
  mov    %r12d,%esi
  pop    %rbx
  mov    %ebp,%edi
  xor    %r8d,%r8d
  pop    %rbp
  mov    $0x2,%edx
  pop    %r12
  jmp    1070 <exif_put_value@plt>
```

assistant: ```c
void exif_put_str(const int ifd_nr, const int tag_id, const char *val) {
  int len = (val) ? strlen(val) + 1 : 0;
  exif_put_value(ifd_nr, tag_id, 2, len, 0, val);
}
```