ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x63,%esi
  xor    %r8d,%r8d
  push   %rbp
  mov    %esi,%edi
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  sub    $0x1,%edi
  je     L75
  nopl   0x0(%rax)
L77:
  test   $0x1,%sil
  je     L84
  cmp    $0x2,%edi
  je     L11
  mov    $0x2,%ecx
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L28:
  cmp    %edi,%ecx
  je     L11
L42:
  mov    %esi,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L28
L84:
  mov    %edi,%esi
L57:
  mov    %esi,%edi
  sub    $0x1,%edi
  jne    L77
L75:
  movslq %r8d,%r8
  lea    -0x4(%rsp),%r12
  lea    D3(%rip),%rbp
  lea    (%rsp,%r8,4),%rbx
L41:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L41
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %esi,(%rsp,%rax,4)
  mov    %edi,%esi
  jmp    L57
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: %d 

assistant: ```c
int main() {
  int p[100];
  int z = 0;
  for (int x = 100; x > 1; x--) {
    for (int n = 2; x % n != 0; n++) {
      if (n == x - 1) {
        p[z++] = x;
        break;
      }
    }
  }
  while (z >= 0)
    printf("%d ", p[z--]);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x62,%edi
  mov    $0x63,%esi
  xor    %r8d,%r8d
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  nop
L78:
  test   $0x1,%sil
  je     L8
  cmp    $0x2,%edi
  je     L44
  mov    $0x2,%ecx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L13:
  cmp    %edi,%ecx
  je     L44
L17:
  mov    %esi,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L13
L8:
  sub    $0x1,%esi
  sub    $0x1,%edi
  jne    L78
L20:
  movslq %r8d,%r8
  lea    -0x4(%rsp),%r12
  lea    D4(%rip),%rbp
  lea    (%rsp,%r8,4),%rbx
L24:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L24
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %esi,(%rsp,%rax,4)
  sub    $0x1,%esi
  sub    $0x1,%edi
  jne    L78
  jmp    L20
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: %d 

assistant: ```c
int main() {
  int p[100];
  int z = 0;
  for (int x = 100; x > 1; x--) {
    for (int n = 2; x % n != 0; n++) {
      if (n == x - 1) {
        p[z++] = x;
        break;
      }
    }
  }
  while (z >= 0)
    printf("%d ", p[z--]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gdt_compare_sizet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L39
  mov    $0xffffffff,%eax
  jmp    L11
L39:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L8
  mov    $0x1,%eax
  jmp    L11
L8:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int gdt_compare_sizet(const void *p1, const void *p2) {
  size_t s1 = *((size_t *)p1);
  size_t s2 = *((size_t *)p2);
  if (s1 < s2) {
    return -1;
  } else if (s1 > s2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gdt_compare_sizet>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jb     L2
  seta   %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
int gdt_compare_sizet(const void *p1, const void *p2) {
  size_t s1 = *((size_t *)p1);
  size_t s2 = *((size_t *)p2);
  if (s1 < s2) {
    return -1;
  } else if (s1 > s2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gdt_compare_sizet>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int gdt_compare_sizet(const void *p1, const void *p2) {
  size_t s1 = *((size_t *)p1);
  size_t s2 = *((size_t *)p2);
  if (s1 < s2) {
    return -1;
  } else if (s1 > s2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x6,%esi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D29(%rip),%r14
  lea    D41(%rip),%r13
L29:
  add    $0x1,%ebp
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    0x4(%r12),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x8,%r12
  cmp    $0x3,%ebp
  jne    L29
  mov    $0x0,%ebp
  lea    D42(%rip),%r12
L8:
  add    $0x1,%ebp
  mov    (%rbx),%edx
  add    0x4(%rbx),%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    $0x3,%ebp
  jne    L8
  mov    0x8(%rsp),%edx
  add    (%rsp),%edx
  add    0x10(%rsp),%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  add    0x4(%rsp),%edx
  add    0x14(%rsp),%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x8(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D40
type: string
name: read_data
arguments: data_tag: D29
type: string
name: read_data
arguments: data_tag: D41
type: string
name: read_data
arguments: data_tag: D42
type: string
name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D12
type: string

tool: D40: Please input %d elements for 'arr':


tool: D29: Row %d:


tool: D41: %d

tool: D42: Sum of Row %d: %d


tool: D9: Sum of Column %d: %d


tool: D12: Highest element is: %d


assistant: ```c
int main() {
  int i, j, arr[3][2], tally;
  printf("Please input %d elements for 'arr':\n", 3 * 2);
  for (i = 0; i < 3; i++) {
    printf("Row %d:\n", i + 1);
    for (j = 0; j < 2; j++) {
      scanf("%d", &arr[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    tally = 0;
    for (j = 0; j < 2; j++) {
      tally += arr[i][j];
    }
    printf("Sum of Row %d: %d\n", i + 1, tally);
  }
  for (i = 0; i < 2; i++) {
    tally = 0;
    for (j = 0; j < 3; j++) {
      tally += arr[j][i];
    }
    printf("Sum of Column %d: %d\n", i + 1, tally);
  }
  tally = arr[0][0];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      if (tally < arr[i][j]) {
        tally = arr[i][j];
      }
    }
  }
  printf("Highest element is: %d\n", tally);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x6,%esi
  lea    D53(%rip),%rdi
  lea    D27(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r12
  call   <printf@plt>
L3:
  add    $0x1,%ebp
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    0x4(%r12),%rsi
  mov    %r13,%rdi
  add    $0x8,%r12
  call   <scanf@plt>
  cmp    $0x3,%ebp
  jne    L3
  xor    %ebp,%ebp
  lea    D14(%rip),%r12
L12:
  add    $0x1,%ebp
  mov    0x4(%rbx),%edx
  mov    %r12,%rdi
  add    (%rbx),%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    $0x3,%ebp
  jne    L12
  lea    D47(%rip),%rbp
  mov    0x8(%rsp),%edx
  mov    $0x1,%esi
  add    (%rsp),%edx
  mov    %rbp,%rdi
  add    0x10(%rsp),%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  add    0x4(%rsp),%edx
  mov    %rbp,%rdi
  add    0x14(%rsp),%edx
  call   <printf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  lea    D11(%rip),%rdi
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x8(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D53
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D14
type_infered: string
name: retrieve_data
arguments: tag: D47
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D53: Please input %d elements for 'arr':


tool: D27: Row %d:


tool: D5: %d

tool: D14: Sum of Row %d: %d


tool: D47: Sum of Column %d: %d


tool: D11: Highest element is: %d


assistant: ```c
int main() {
  int i, j, arr[3][2], tally;
  printf("Please input %d elements for 'arr':\n", 3 * 2);
  for (i = 0; i < 3; i++) {
    printf("Row %d:\n", i + 1);
    for (j = 0; j < 2; j++) {
      scanf("%d", &arr[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    tally = 0;
    for (j = 0; j < 2; j++) {
      tally += arr[i][j];
    }
    printf("Sum of Row %d: %d\n", i + 1, tally);
  }
  for (i = 0; i < 2; i++) {
    tally = 0;
    for (j = 0; j < 3; j++) {
      tally += arr[j][i];
    }
    printf("Sum of Column %d: %d\n", i + 1, tally);
  }
  tally = arr[0][0];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      if (tally < arr[i][j]) {
        tally = arr[i][j];
      }
    }
  }
  printf("Highest element is: %d\n", tally);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x6,%esi
  lea    D39(%rip),%rdi
  lea    D51(%rip),%r14
  push   %r13
  lea    D53(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r12
  call   <printf@plt>
L25:
  add    $0x1,%ebp
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    0x4(%r12),%rsi
  mov    %r13,%rdi
  add    $0x8,%r12
  call   <scanf@plt>
  cmp    $0x3,%ebp
  jne    L25
  xor    %ebp,%ebp
  lea    D19(%rip),%r12
L6:
  add    $0x1,%ebp
  mov    0x4(%rbx),%edx
  mov    %r12,%rdi
  add    (%rbx),%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    $0x3,%ebp
  jne    L6
  lea    D42(%rip),%rbp
  mov    0x8(%rsp),%edx
  mov    $0x1,%esi
  add    (%rsp),%edx
  mov    %rbp,%rdi
  add    0x10(%rsp),%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  add    0x4(%rsp),%edx
  mov    %rbp,%rdi
  add    0x14(%rsp),%edx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    (%rsp),%esi
  lea    D12(%rip),%rdi
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x8(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D39
type_guessed: string
name: read_data
arguments: tag: D51
type_guessed: string
name: read_data
arguments: tag: D53
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D42
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string

tool: D39: Please input %d elements for 'arr':


tool: D51: Row %d:


tool: D53: %d

tool: D19: Sum of Row %d: %d


tool: D42: Sum of Column %d: %d


tool: D12: Highest element is: %d


assistant: ```c
int main() {
  int i, j, arr[3][2], tally;
  printf("Please input %d elements for 'arr':\n", 3 * 2);
  for (i = 0; i < 3; i++) {
    printf("Row %d:\n", i + 1);
    for (j = 0; j < 2; j++) {
      scanf("%d", &arr[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    tally = 0;
    for (j = 0; j < 2; j++) {
      tally += arr[i][j];
    }
    printf("Sum of Row %d: %d\n", i + 1, tally);
  }
  for (i = 0; i < 2; i++) {
    tally = 0;
    for (j = 0; j < 3; j++) {
      tally += arr[j][i];
    }
    printf("Sum of Column %d: %d\n", i + 1, tally);
  }
  tally = arr[0][0];
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      if (tally < arr[i][j]) {
        tally = arr[i][j];
      }
    }
  }
  printf("Highest element is: %d\n", tally);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<allocArray3D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L3:
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <allocArray2D@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  cmp    %rax,-0x28(%rbp)
  ja     L3
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int ***allocArray3D(size_t rows, size_t cols, size_t lines) {
  unsigned int ***arr = (int ***)malloc(rows * sizeof(int **)), i;
  for (i = 0; i < rows; i++)
    arr[i] = allocArray2D(cols, lines);
  return arr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<allocArray3D>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r14
  lea    0x0(,%rdi,8),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L2
  mov    $0x0,%ebx
  mov    $0x0,%eax
L18:
  lea    (%r12,%rax,8),%r15
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <allocArray2D@plt>
  mov    %rax,(%r15)
  add    $0x1,%ebx
  mov    %ebx,%eax
  cmp    %rbp,%rax
  jb     L18
L2:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ***allocArray3D(size_t rows, size_t cols, size_t lines) {
  unsigned int ***arr = (int ***)malloc(rows * sizeof(int **)), i;
  for (i = 0; i < rows; i++)
    arr[i] = allocArray2D(cols, lines);
  return arr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<allocArray3D>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  shl    $0x3,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L8
  xor    %ebx,%ebx
  xor    %eax,%eax
L15:
  mov    %r14,%rsi
  mov    %r13,%rdi
  lea    (%r12,%rax,8),%r15
  call   <allocArray2D@plt>
  mov    %rax,(%r15)
  lea    0x1(%rbx),%eax
  mov    %rax,%rbx
  cmp    %rbp,%rax
  jb     L15
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ***allocArray3D(size_t rows, size_t cols, size_t lines) {
  unsigned int ***arr = (int ***)malloc(rows * sizeof(int **)), i;
  for (i = 0; i < rows; i++)
    arr[i] = allocArray2D(cols, lines);
  return arr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<allocArray3D>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  shl    $0x3,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L4
  xor    %ebx,%ebx
  xor    %eax,%eax
L6:
  mov    %r14,%rsi
  mov    %r13,%rdi
  lea    (%r12,%rax,8),%r15
  call   <allocArray2D@plt>
  mov    %rax,(%r15)
  lea    0x1(%rbx),%eax
  mov    %rax,%rbx
  cmp    %rbp,%rax
  jb     L6
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ***allocArray3D(size_t rows, size_t cols, size_t lines) {
  unsigned int ***arr = (int ***)malloc(rows * sizeof(int **)), i;
  for (i = 0; i < rows; i++)
    arr[i] = allocArray2D(cols, lines);
  return arr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L19:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L14
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  jne    L19
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  size_t p = n;
  while ((*s1++ != *s2++) && (*s1 && *s2) && p--)
    ;
  return ((int)((unsigned char)*s1 - (unsigned char)*s2));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncmp>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%r8d
L31:
  add    $0x1,%rax
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%ecx
  cmp    %cl,-0x1(%rax)
  je     L28
  cmpb   $0x0,(%rax)
  je     L28
  cmpb   $0x0,(%rsi)
  je     L28
  mov    %r8,%rcx
  sub    %rax,%rcx
  add    %rdx,%rcx
  add    %rdi,%rcx
  jne    L31
L28:
  movzbl (%rax),%eax
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  size_t p = n;
  while ((*s1++ != *s2++) && (*s1 && *s2) && p--)
    ;
  return ((int)((unsigned char)*s1 - (unsigned char)*s2));
}
```
user: What is the c source code of the assembly code below?

```asm
<strncmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%r9d
  mov    %rdi,%r8
  mov    $0x1,%r10d
  jmp    L34
  cs nopw 0x0(%rax,%rax,1)
L22:
  test   %al,%al
  je     L48
  movzbl (%rsi),%r9d
  test   %r9b,%r9b
  je     L48
  mov    %r10,%rcx
  sub    %r8,%rcx
  add    %rdx,%rcx
  add    %rdi,%rcx
  je     L48
L34:
  add    $0x1,%r8
  mov    %eax,%ecx
  add    $0x1,%rsi
  movzbl (%r8),%eax
  cmp    %r9b,%cl
  jne    L22
L48:
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  size_t p = n;
  while ((*s1++ != *s2++) && (*s1 && *s2) && p--)
    ;
  return ((int)((unsigned char)*s1 - (unsigned char)*s2));
}
```
user: What is the c source code of the assembly code below?

```asm
<strncmp>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  mov    $0x1,%r9d
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L21:
  test   %al,%al
  je     L26
  cmpb   $0x0,(%rsi)
  je     L26
  mov    %r9,%rcx
  sub    %r8,%rcx
  add    %rdx,%rcx
  add    %rdi,%rcx
  je     L26
L1:
  add    $0x1,%r8
  add    $0x1,%rsi
  mov    %eax,%ecx
  movzbl (%r8),%eax
  cmp    -0x1(%rsi),%cl
  jne    L21
L26:
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  size_t p = n;
  while ((*s1++ != *s2++) && (*s1 && *s2) && p--)
    ;
  return ((int)((unsigned char)*s1 - (unsigned char)*s2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__flock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __flock(int fd, int operation) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__flock>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __flock(int fd, int operation) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__flock>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __flock(int fd, int operation) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__flock>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __flock(int fd, int operation) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<fmt_convert_s8_to_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L3:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: f64

tool: D6: 128

assistant: ```c
void fmt_convert_s8_to_double(void *dest_v, void *src_v, int n) {
  double *dest = dest_v;
  int8_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = src[i] / 128.0;
}
```