ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<arr_float_divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L5:
  mov    -0x8(%rbp),%rax
  imul   -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  imul   -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  divss  -0x1c(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void arr_float_divide(float *pDest, float fValue, unsigned long int num, unsigned long int stride) {
  unsigned long int i;
  for (i = 0; i < num; i++) {
    pDest[i * stride] /= fValue;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arr_float_divide>:
  endbr64
  test   %rsi,%rsi
  je     L13
  shl    $0x2,%rdx
  mov    $0x0,%eax
L15:
  movss  (%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  add    $0x1,%rax
  add    %rdx,%rdi
  cmp    %rax,%rsi
  jne    L15
L13:
  ret
```

assistant: ```c
void arr_float_divide(float *pDest, float fValue, unsigned long int num, unsigned long int stride) {
  unsigned long int i;
  for (i = 0; i < num; i++) {
    pDest[i * stride] /= fValue;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<arr_float_divide>:
  endbr64
  test   %rsi,%rsi
  je     L9
  shl    $0x2,%rdx
  xor    %eax,%eax
  nop
L4:
  movss  (%rdi),%xmm1
  add    $0x1,%rax
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  add    %rdx,%rdi
  cmp    %rax,%rsi
  jne    L4
L9:
  ret
```

assistant: ```c
void arr_float_divide(float *pDest, float fValue, unsigned long int num, unsigned long int stride) {
  unsigned long int i;
  for (i = 0; i < num; i++) {
    pDest[i * stride] /= fValue;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arr_float_divide>:
  endbr64
  mov    %rdi,%rcx
  test   %rsi,%rsi
  je     L42
  cmp    $0x1,%rdx
  jne    L81
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L20
  mov    %rsi,%rdx
  movaps %xmm0,%xmm2
  mov    %rdi,%rax
  shr    $0x2,%rdx
  shufps $0x0,%xmm2,%xmm2
  shl    $0x4,%rdx
  add    %rdi,%rdx
L52:
  movups (%rax),%xmm1
  add    $0x10,%rax
  divps  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L52
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%sil
  je     L39
L76:
  lea    0x0(,%rax,4),%rdx
  lea    (%rcx,%rdx,1),%rdi
  movss  (%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  lea    0x1(%rax),%rdi
  cmp    %rdi,%rsi
  jbe    L42
  lea    0x4(%rcx,%rdx,1),%rdi
  add    $0x2,%rax
  movss  (%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  cmp    %rax,%rsi
  jbe    L42
  lea    0x8(%rcx,%rdx,1),%rax
  movss  (%rax),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rax)
L42:
  ret
  nopl   (%rax)
L39:
  ret
  nopl   0x0(%rax)
L81:
  shl    $0x2,%rdx
  mov    %rdi,%rax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L29:
  movss  (%rax),%xmm1
  add    $0x1,%rcx
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rax)
  add    %rdx,%rax
  cmp    %rcx,%rsi
  jne    L29
  ret
L20:
  xor    %eax,%eax
  jmp    L76
```

assistant: ```c
void arr_float_divide(float *pDest, float fValue, unsigned long int num, unsigned long int stride) {
  unsigned long int i;
  for (i = 0; i < num; i++) {
    pDest[i * stride] /= fValue;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<suffixes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,%rax
  lea    -0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L89:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L25
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jge    L25
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  jmp    L55
L25:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L52
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L52:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L85:
  subl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x0,-0xc(%rbp)
  js     L43
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  add    %ecx,%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L85
L43:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  sub    %esi,%edx
  mov    %dx,(%rax)
L55:
  subl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x0,-0x8(%rbp)
  jns    L89
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void suffixes(char *x, int m, unsigned short *suff) {
  int g, i;
  int f = 0;
  suff[m - 1] = m;
  g = m - 1;
  for (i = m - 2; i >= 0; --i) {
    if (i > g && suff[i + m - 1 - f] < i - g)
      suff[i] = suff[i + m - 1 - f];
    else {
      if (i < g)
        g = i;
      f = i;
      while (g >= 0 && x[g] == x[g + m - 1 - f])
        --g;
      suff[i] = f - g;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<suffixes>:
  endbr64
  mov    %rdi,%r11
  movslq %esi,%r9
  mov    %si,-0x2(%rdx,%r9,2)
  mov    %esi,%edi
  sub    $0x2,%edi
  js     L80
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  lea    -0x1(%rsi),%edx
  movslq %edi,%r8
  lea    (%rbx,%r8,2),%r10
  neg    %r8
  mov    $0x0,%r12d
  mov    %edx,%esi
  jmp    L1
L15:
  cmp    %edi,%edx
  cmovg  %edi,%edx
  test   %edx,%edx
  js     L47
  movslq %edx,%rax
  add    %r11,%rax
L23:
  lea    (%r9,%rax,1),%rcx
  movzbl -0x1(%r8,%rcx,1),%ecx
  cmp    %cl,(%rax)
  jne    L47
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  jne    L23
L47:
  mov    %edi,%eax
  sub    %edx,%eax
  mov    %ax,(%r10)
  mov    %edi,%r12d
L44:
  sub    $0x1,%edi
  sub    $0x2,%r10
  add    $0x1,%r8
  cmp    $0xffffffff,%edi
  je     L53
L1:
  cmp    %edi,%edx
  jge    L15
  lea    (%rsi,%rdi,1),%eax
  sub    %r12d,%eax
  cltq
  movzwl (%rbx,%rax,2),%eax
  movzwl %ax,%ebp
  mov    %edi,%ecx
  sub    %edx,%ecx
  cmp    %ecx,%ebp
  jge    L15
  mov    %ax,(%r10)
  jmp    L44
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L80:
  ret
```

assistant: ```c
void suffixes(char *x, int m, unsigned short *suff) {
  int g, i;
  int f = 0;
  suff[m - 1] = m;
  g = m - 1;
  for (i = m - 2; i >= 0; --i) {
    if (i > g && suff[i + m - 1 - f] < i - g)
      suff[i] = suff[i + m - 1 - f];
    else {
      if (i < g)
        g = i;
      f = i;
      while (g >= 0 && x[g] == x[g + m - 1 - f])
        --g;
      suff[i] = f - g;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<suffixes>:
  endbr64
  movslq %esi,%r8
  mov    %rdx,%r11
  mov    %r8,%rcx
  mov    %r8w,-0x2(%rdx,%r8,2)
  sub    $0x2,%ecx
  js     L18
  push   %r12
  mov    %rdi,%r10
  movslq %ecx,%rdi
  xor    %r12d,%r12d
  push   %rbp
  lea    (%r11,%rdi,2),%r9
  neg    %rdi
  push   %rbx
  lea    -0x1(%r8),%ebx
  mov    %ebx,%edx
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L55:
  lea    (%rbx,%rcx,1),%eax
  mov    %ecx,%esi
  sub    %r12d,%eax
  sub    %edx,%esi
  cltq
  movzwl (%r11,%rax,2),%ebp
  mov    %ebp,%eax
  cmp    %esi,%ebp
  jge    L56
L53:
  sub    $0x1,%ecx
  mov    %ax,(%r9)
  add    $0x1,%rdi
  sub    $0x2,%r9
  cmp    $0xffffffff,%ecx
  je     L37
L35:
  cmp    %ecx,%edx
  jl     L55
L56:
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  test   %edx,%edx
  js     L83
  movslq %edx,%rax
  add    %r10,%rax
  jmp    L26
L20:
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  je     L83
L26:
  lea    (%r8,%rax,1),%rsi
  movzbl -0x1(%rdi,%rsi,1),%esi
  cmp    %sil,(%rax)
  je     L20
L83:
  mov    %ecx,%eax
  mov    %ecx,%r12d
  sub    %edx,%eax
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  ret
```

assistant: ```c
void suffixes(char *x, int m, unsigned short *suff) {
  int g, i;
  int f = 0;
  suff[m - 1] = m;
  g = m - 1;
  for (i = m - 2; i >= 0; --i) {
    if (i > g && suff[i + m - 1 - f] < i - g)
      suff[i] = suff[i + m - 1 - f];
    else {
      if (i < g)
        g = i;
      f = i;
      while (g >= 0 && x[g] == x[g + m - 1 - f])
        --g;
      suff[i] = f - g;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<suffixes>:
  endbr64
  movslq %esi,%r8
  mov    %rdx,%r11
  mov    %r8,%rcx
  mov    %r8w,-0x2(%rdx,%r8,2)
  sub    $0x2,%ecx
  js     L12
  push   %r12
  mov    %rdi,%r10
  movslq %ecx,%rdi
  xor    %r12d,%r12d
  push   %rbp
  lea    (%r11,%rdi,2),%r9
  neg    %rdi
  push   %rbx
  lea    -0x1(%r8),%ebx
  mov    %ebx,%edx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L4:
  lea    (%rbx,%rcx,1),%eax
  mov    %ecx,%esi
  sub    %r12d,%eax
  sub    %edx,%esi
  cltq
  movzwl (%r11,%rax,2),%ebp
  mov    %ebp,%eax
  cmp    %esi,%ebp
  jge    L36
L65:
  sub    $0x1,%ecx
  mov    %ax,(%r9)
  add    $0x1,%rdi
  sub    $0x2,%r9
  cmp    $0xffffffff,%ecx
  je     L79
L26:
  cmp    %ecx,%edx
  jl     L4
L36:
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  test   %edx,%edx
  js     L57
  movslq %edx,%rax
  add    %r10,%rax
  jmp    L64
L28:
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  je     L57
L64:
  lea    (%r8,%rax,1),%rsi
  movzbl -0x1(%rdi,%rsi,1),%esi
  cmp    %sil,(%rax)
  je     L28
L57:
  mov    %ecx,%eax
  mov    %ecx,%r12d
  sub    %edx,%eax
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L79:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  ret
```

assistant: ```c
void suffixes(char *x, int m, unsigned short *suff) {
  int g, i;
  int f = 0;
  suff[m - 1] = m;
  g = m - 1;
  for (i = m - 2; i >= 0; --i) {
    if (i > g && suff[i + m - 1 - f] < i - g)
      suff[i] = suff[i + m - 1 - f];
    else {
      if (i < g)
        g = i;
      f = i;
      while (g >= 0 && x[g] == x[g + m - 1 - f])
        --g;
      suff[i] = f - g;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fd2oft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%r9
  lea    -0x18(%rbp),%r8
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  push   $0x3
  lea    -0x10(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fd2i@plt>
  add    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <calloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x10(%rbp),%rsi
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x38(%rbp),%rax
  movq   %rsi,%xmm0
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <sprintf@plt>
  mov    -0x38(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D7: %02d:%02d:%06.3f

assistant: ```c
char *fd2oft(string)
char *string;
{
  int iyr, imon, iday, ihr, imn;
  double sec;
  fd2i(string, &iyr, &imon, &iday, &ihr, &imn, &sec, 3);
  string = (char *)calloc(32, sizeof(char));
  sprintf(string, "%02d:%02d:%06.3f", ihr, imn, sec);
  return (string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fd2oft>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  push   $0x3
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x2c(%rsp),%r9
  lea    0x28(%rsp),%r8
  mov    $0x0,%eax
  call   <fd2i@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  movsd  0x30(%rsp),%xmm0
  mov    0x2c(%rsp),%ecx
  mov    0x28(%rsp),%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <sprintf@plt>
  add    $0x10,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %rbx,%rax
  add    $0x30,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4: %02d:%02d:%06.3f

assistant: ```c
char *fd2oft(string)
char *string;
{
  int iyr, imon, iday, ihr, imn;
  double sec;
  fd2i(string, &iyr, &imon, &iday, &ihr, &imn, &sec, 3);
  string = (char *)calloc(32, sizeof(char));
  sprintf(string, "%02d:%02d:%06.3f", ihr, imn, sec);
  return (string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fd2oft>:
  endbr64
  push   %r12
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  push   $0x3
  lea    0x28(%rsp),%rax
  push   %rax
  xor    %eax,%eax
  lea    0x2c(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <fd2i@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <calloc@plt>
  movsd  0x30(%rsp),%xmm0
  mov    0x2c(%rsp),%ecx
  lea    D5(%rip),%rsi
  mov    0x28(%rsp),%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  mov    $0x1,%eax
  call   <sprintf@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: %02d:%02d:%06.3f

assistant: ```c
char *fd2oft(string)
char *string;
{
  int iyr, imon, iday, ihr, imn;
  double sec;
  fd2i(string, &iyr, &imon, &iday, &ihr, &imn, &sec, 3);
  string = (char *)calloc(32, sizeof(char));
  sprintf(string, "%02d:%02d:%06.3f", ihr, imn, sec);
  return (string);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fd2oft>:
  endbr64
  push   %r12
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  push   $0x3
  lea    0x28(%rsp),%rax
  push   %rax
  xor    %eax,%eax
  lea    0x2c(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <fd2i@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <calloc@plt>
  movsd  0x30(%rsp),%xmm0
  mov    0x2c(%rsp),%ecx
  lea    D5(%rip),%rsi
  mov    0x28(%rsp),%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  mov    $0x1,%eax
  call   <sprintf@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: %02d:%02d:%06.3f

assistant: ```c
char *fd2oft(string)
char *string;
{
  int iyr, imon, iday, ihr, imn;
  double sec;
  fd2i(string, &iyr, &imon, &iday, &ihr, &imn, &sec, 3);
  string = (char *)calloc(32, sizeof(char));
  sprintf(string, "%02d:%02d:%06.3f", ihr, imn, sec);
  return (string);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L15
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <panic@plt>
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <panic@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string

tool: D0: xmalloc: zero size


tool: D17: xmalloc: out of memory (allocating %zu bytes)


assistant: ```c
void *xmalloc(size_t size) {
  void *ptr;
  if (__builtin_expect(!!(size == 0), 0))
    panic("xmalloc: zero size\n");
  ptr = malloc(size);
  if (__builtin_expect(!!(ptr == NULL), 0))
    panic("xmalloc: out of memory (allocating %zu bytes)\n", size);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L14
L39:
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L11
L19:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <panic@plt>
  jmp    L39
L11:
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <panic@plt>
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D11: xmalloc: zero size


tool: D6: xmalloc: out of memory (allocating %zu bytes)


assistant: ```c
void *xmalloc(size_t size) {
  void *ptr;
  if (__builtin_expect(!!(size == 0), 0))
    panic("xmalloc: zero size\n");
  ptr = malloc(size);
  if (__builtin_expect(!!(ptr == NULL), 0))
    panic("xmalloc: out of memory (allocating %zu bytes)\n", size);
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xmalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  sete   %dil
  xor    %esi,%esi
  movzbl %dil,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L9
L6:
  mov    %rbp,%rdi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L16
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L9:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <panic@plt>
  jmp    L6
L16:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <panic@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D1
type: string

tool: D5: xmalloc: zero size


tool: D1: xmalloc: out of memory (allocating %zu bytes)


assistant: ```c
void *xmalloc(size_t size) {
  void *ptr;
  if (__builtin_expect(!!(size == 0), 0))
    panic("xmalloc: zero size\n");
  ptr = malloc(size);
  if (__builtin_expect(!!(ptr == NULL), 0))
    panic("xmalloc: out of memory (allocating %zu bytes)\n", size);
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  sete   %dil
  xor    %esi,%esi
  movzbl %dil,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L13
L4:
  mov    %rbp,%rdi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <panic@plt>
  jmp    L4
L7:
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <panic@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D18
type_infered: string

tool: D13: xmalloc: zero size


tool: D18: xmalloc: out of memory (allocating %zu bytes)


assistant: ```c
void *xmalloc(size_t size) {
  void *ptr;
  if (__builtin_expect(!!(size == 0), 0))
    panic("xmalloc: zero size\n");
  ptr = malloc(size);
  if (__builtin_expect(!!(ptr == NULL), 0))
    panic("xmalloc: out of memory (allocating %zu bytes)\n", size);
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_font>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <set_font_keyed@plt>
  jmp    L0
L7:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <set_font_named@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void set_font(char *opt) {
  if (opt[1] == ':')
    set_font_keyed(opt);
  else
    set_font_named(opt);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set_font>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x3a,0x1(%rdi)
  je     L14
  call   <set_font_named@plt>
L9:
  add    $0x8,%rsp
  ret
L14:
  call   <set_font_keyed@plt>
  jmp    L9
```

assistant: ```c
void set_font(char *opt) {
  if (opt[1] == ':')
    set_font_keyed(opt);
  else
    set_font_named(opt);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set_font>:
  endbr64
  cmpb   $0x3a,0x1(%rdi)
  je     L0
  jmp    1070 <set_font_named@plt>
  nop
L0:
  jmp    1060 <set_font_keyed@plt>
```

assistant: ```c
void set_font(char *opt) {
  if (opt[1] == ':')
    set_font_keyed(opt);
  else
    set_font_named(opt);
}
```
user: What is the c source code of the assembly code below:

```asm
<set_font>:
  endbr64
  cmpb   $0x3a,0x1(%rdi)
  je     L5
  jmp    1070 <set_font_named@plt>
  nop
L5:
  jmp    1060 <set_font_keyed@plt>
```

assistant: ```c
void set_font(char *opt) {
  if (opt[1] == ':')
    set_font_keyed(opt);
  else
    set_font_named(opt);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    -0x4(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <glutInit@plt>
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  glutInit(&argc, argv);
  init();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <glutInit@plt>
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  glutInit(&argc, argv);
  init();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <glutInit@plt>
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  glutInit(&argc, argv);
  init();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <glutInit@plt>
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  glutInit(&argc, argv);
  init();
  return 0;
}
```