ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<__aeabi_idiv>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  jl     L7
  nopw   0x0(%rax,%rax,1)
L13:
  sub    %esi,%edi
  add    $0x1,%eax
  cmp    %edi,%esi
  jle    L13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
int __aeabi_idiv(int num, int denom) {
  int q = 0;
  while (num >= denom) {
    num -= denom;
    q++;
  }
  return q;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bin_to_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L3
  mov    $0x7,%eax
  sub    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %al,-0x5(%rbp)
L3:
  addl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0x7,-0x4(%rbp)
  jle    L0
  movzbl -0x5(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char bin_to_char(const char *bin) {
  char c = 0x00;
  for (int i = 0; i <= 7; i++) {
    if (bin[i] == '1') {
      c |= 1 << (7 - i);
    }
  }
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bin_to_char>:
  endbr64
  lea    0x8(%rdi),%rdx
  mov    %rdi,%rax
  mov    $0x0,%esi
  add    $0x7,%edi
  mov    $0x1,%r8d
  jmp    L29
L35:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L36
L29:
  cmpb   $0x31,(%rax)
  jne    L35
  mov    %edi,%ecx
  sub    %eax,%ecx
  mov    %r8d,%r9d
  shl    %cl,%r9d
  or     %r9d,%esi
  jmp    L35
L36:
  mov    %esi,%eax
  ret
```

assistant: ```c
char bin_to_char(const char *bin) {
  char c = 0x00;
  for (int i = 0; i <= 7; i++) {
    if (bin[i] == '1') {
      c |= 1 << (7 - i);
    }
  }
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bin_to_char>:
  endbr64
  lea    0x8(%rdi),%rax
  xor    %r8d,%r8d
  lea    0x7(%rdi),%r9d
  mov    $0x1,%esi
  nopl   0x0(%rax)
L16:
  cmpb   $0x31,(%rdi)
  jne    L19
  mov    %r9d,%ecx
  mov    %esi,%edx
  sub    %edi,%ecx
  shl    %cl,%edx
  or     %edx,%r8d
L19:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L16
  mov    %r8d,%eax
  ret
```

assistant: ```c
char bin_to_char(const char *bin) {
  char c = 0x00;
  for (int i = 0; i <= 7; i++) {
    if (bin[i] == '1') {
      c |= 1 << (7 - i);
    }
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bin_to_char>:
  endbr64
  cmpb   $0x31,(%rdi)
  sete   %al
  shl    $0x7,%eax
  cmpb   $0x31,0x1(%rdi)
  jne    L33
  or     $0x40,%eax
L33:
  cmpb   $0x31,0x2(%rdi)
  jne    L14
  or     $0x20,%eax
L14:
  cmpb   $0x31,0x3(%rdi)
  jne    L23
  or     $0x10,%eax
L23:
  cmpb   $0x31,0x4(%rdi)
  jne    L38
  or     $0x8,%eax
L38:
  cmpb   $0x31,0x5(%rdi)
  jne    L3
  or     $0x4,%eax
L3:
  cmpb   $0x31,0x6(%rdi)
  jne    L64
  or     $0x2,%eax
L64:
  cmpb   $0x31,0x7(%rdi)
  je     L19
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  or     $0x1,%eax
  ret
```

assistant: ```c
char bin_to_char(const char *bin) {
  char c = 0x00;
  for (int i = 0; i <= 7; i++) {
    if (bin[i] == '1') {
      c |= 1 << (7 - i);
    }
  }
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<Union>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find@plt>
  cmp    %rax,%rbx
  je     L53
  cmpl   $0x0,-0x1c(%rbp)
  js     L23
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L19
L23:
  cmpl   $0x0,-0x20(%rbp)
  js     L48
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jg     L48
L19:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L41
L53:
  nop
  jmp    L41
L48:
  nop
L41:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void Union(int *S, int root1, int root2, int size) {
  if (find(S, size, root1) == find(S, size, root2))
    return;
  if ((root1 < 0 || root1 > size) && (root2 < 0 || root2 > size))
    return;
  S[root1] = root2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Union>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %ecx,%ebp
  mov    %esi,%edx
  mov    %ecx,%esi
  call   <find@plt>
  mov    %rax,%r14
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <find@plt>
  cmp    %rax,%r14
  je     L38
  test   %ebx,%ebx
  js     L34
  cmp    %ebx,%ebp
  jl     L34
L49:
  movslq %ebx,%rbx
  mov    %r13d,(%r12,%rbx,4)
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  test   %r13d,%r13d
  js     L38
  cmp    %r13d,%ebp
  jge    L49
  jmp    L38
```

assistant: ```c
void Union(int *S, int root1, int root2, int size) {
  if (find(S, size, root1) == find(S, size, root2))
    return;
  if ((root1 < 0 || root1 > size) && (root2 < 0 || root2 > size))
    return;
  S[root1] = root2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Union>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  movslq %esi,%rbx
  mov    %ecx,%esi
  mov    %ebx,%edx
  call   <find@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %rax,%r14
  call   <find@plt>
  cmp    %rax,%r14
  je     L53
  test   %ebx,%ebx
  js     L5
  cmp    %ebx,%ebp
  jl     L5
L58:
  mov    %r13d,(%r12,%rbx,4)
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  test   %r13d,%r13d
  js     L53
  cmp    %r13d,%ebp
  jge    L58
  jmp    L53
```

assistant: ```c
void Union(int *S, int root1, int root2, int size) {
  if (find(S, size, root1) == find(S, size, root2))
    return;
  if ((root1 < 0 || root1 > size) && (root2 < 0 || root2 > size))
    return;
  S[root1] = root2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Union>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  movslq %esi,%rbx
  mov    %ecx,%esi
  mov    %ebx,%edx
  call   <find@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %rax,%r14
  call   <find@plt>
  cmp    %rax,%r14
  je     L27
  test   %ebx,%ebx
  js     L24
  cmp    %ebx,%ebp
  jl     L24
L1:
  mov    %r13d,(%r12,%rbx,4)
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  test   %r13d,%r13d
  js     L27
  cmp    %r13d,%ebp
  jge    L1
  jmp    L27
```

assistant: ```c
void Union(int *S, int root1, int root2, int size) {
  if (find(S, size, root1) == find(S, size, root2))
    return;
  if ((root1 < 0 || root1 > size) && (root2 < 0 || root2 > size))
    return;
  S[root1] = root2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<snd_finishedProcess_msg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D7: dbus-send --type=method_call --dest=org.efg.Secapp /org/efg/secapp org.efg.Secapp.finishedProcess int32:

tool: D0: %d

assistant: ```c
int snd_finishedProcess_msg(int pid) {
  int val;
  char *command;
  char *str_pid;
  command = malloc(1024 * sizeof(char));
  str_pid = malloc(1024 * sizeof(char));
  strcpy(command, "dbus-send --type=method_call --dest=org.efg.Secapp /org/efg/secapp org.efg.Secapp.finishedProcess int32:");
  sprintf(str_pid, "%d", pid);
  strcat(command, str_pid);
  val = system(command);
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<snd_finishedProcess_msg>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %r12d,%edx
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D16: dbus-send --type=method_call --dest=org.efg.Secapp /org/efg/secapp org.efg.Secapp.finishedProcess int32:

tool: D13: %d

assistant: ```c
int snd_finishedProcess_msg(int pid) {
  int val;
  char *command;
  char *str_pid;
  command = malloc(1024 * sizeof(char));
  str_pid = malloc(1024 * sizeof(char));
  strcpy(command, "dbus-send --type=method_call --dest=org.efg.Secapp /org/efg/secapp org.efg.Secapp.finishedProcess int32:");
  sprintf(str_pid, "%d", pid);
  strcat(command, str_pid);
  val = system(command);
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<snd_finishedProcess_msg>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x400,%edi
  push   %r12
  push   %rbp
  call   <malloc@plt>
  mov    $0x400,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rdi
  lea    D16(%rip),%rsi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  lea    D17(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <system@plt>
```

tool_calls: name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D17
type_infered: string

tool: D16: dbus-send --type=method_call --dest=org.efg.Secapp /org/efg/secapp org.efg.Secapp.finishedProcess int32:

tool: D17: %d

assistant: ```c
int snd_finishedProcess_msg(int pid) {
  int val;
  char *command;
  char *str_pid;
  command = malloc(1024 * sizeof(char));
  str_pid = malloc(1024 * sizeof(char));
  strcpy(command, "dbus-send --type=method_call --dest=org.efg.Secapp /org/efg/secapp org.efg.Secapp.finishedProcess int32:");
  sprintf(str_pid, "%d", pid);
  strcat(command, str_pid);
  val = system(command);
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<snd_finishedProcess_msg>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x400,%edi
  push   %r12
  push   %rbp
  call   <malloc@plt>
  mov    $0x400,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  lea    D14(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <system@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D14
datatype: string

tool: D5: dbus-send --type=method_call --dest=org.efg.Secapp /org/efg/secapp org.efg.Secapp.finishedProcess int32:

tool: D14: %d

assistant: ```c
int snd_finishedProcess_msg(int pid) {
  int val;
  char *command;
  char *str_pid;
  command = malloc(1024 * sizeof(char));
  str_pid = malloc(1024 * sizeof(char));
  strcpy(command, "dbus-send --type=method_call --dest=org.efg.Secapp /org/efg/secapp org.efg.Secapp.finishedProcess int32:");
  sprintf(str_pid, "%d", pid);
  strcat(command, str_pid);
  val = system(command);
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L7
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L3
L7:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string
name: extract_symbolic_data
arguments: label: D1
type_guessed: string
name: extract_symbolic_data
arguments: label: D9
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D3: 
Entre com num:

tool: D1: %d

tool: D9: 
Este numero eh par


tool: D7: Este numero eh impar


assistant: ```c
int main() {
  int num;
  int resto;
  printf("\nEntre com num:");
  scanf("%d", &num);
  resto = num % 2;
  if (resto == 0) {
    printf("\nEste numero eh par\n");
  } else {
    printf("Este numero eh impar\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L9
  lea    D7(%rip),%rdi
  call   <printf@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D36
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D21
type_guessed: string

tool: D1: 
Entre com num:

tool: D36: %d

tool: D7: 
Este numero eh par


tool: D21: Este numero eh impar


assistant: ```c
int main() {
  int num;
  int resto;
  printf("\nEntre com num:");
  scanf("%d", &num);
  resto = num % 2;
  if (resto == 0) {
    printf("\nEste numero eh par\n");
  } else {
    printf("Este numero eh impar\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L25
  lea    D39(%rip),%rdi
  call   <printf@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L25:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
data_type: string
name: retrieve_data
arguments: data_tag: D9
data_type: string
name: retrieve_data
arguments: data_tag: D39
data_type: string
name: retrieve_data
arguments: data_tag: D32
data_type: string

tool: D31: 
Entre com num:

tool: D9: %d

tool: D39: 
Este numero eh par


tool: D32: Este numero eh impar


assistant: ```c
int main() {
  int num;
  int resto;
  printf("\nEntre com num:");
  scanf("%d", &num);
  resto = num % 2;
  if (resto == 0) {
    printf("\nEste numero eh par\n");
  } else {
    printf("Este numero eh impar\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L0
  lea    D31(%rip),%rdi
  call   <printf@plt>
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D31
type_guessed: string
name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D26: 
Entre com num:

tool: D14: %d

tool: D31: 
Este numero eh par


tool: D1: Este numero eh impar


assistant: ```c
int main() {
  int num;
  int resto;
  printf("\nEntre com num:");
  scanf("%d", &num);
  resto = num % 2;
  if (resto == 0) {
    printf("\nEste numero eh par\n");
  } else {
    printf("Este numero eh impar\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Q_PrintStrlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L49
L33:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
L70:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  je     L4
  addq   $0x2,-0x8(%rbp)
  jmp    L36
L4:
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L70
  mov    -0xc(%rbp),%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if ((*(p) == '^' && *((p) + 1) && *((p) + 1) != '^')) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Q_PrintStrlen>:
  endbr64
  test   %rdi,%rdi
  je     L19
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  mov    $0x0,%edx
  jmp    L68
L86:
  add    $0x1,%rdi
  add    $0x1,%edx
L34:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L42
L68:
  cmp    $0x5e,%al
  jne    L86
  movzbl 0x1(%rdi),%eax
  cmp    $0x5e,%al
  je     L86
  test   %al,%al
  je     L86
  add    $0x2,%rdi
  jmp    L34
L19:
  mov    $0x0,%edx
L42:
  mov    %edx,%eax
  ret
L3:
  mov    $0x0,%edx
  jmp    L42
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if ((*(p) == '^' && *((p) + 1) && *((p) + 1) != '^')) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Q_PrintStrlen>:
  endbr64
  test   %rdi,%rdi
  je     L19
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  jmp    L8
  nopl   0x0(%rax)
L44:
  add    $0x1,%rdi
  add    $0x1,%r8d
  mov    %edx,%eax
L8:
  test   %al,%al
  je     L56
L61:
  movzbl 0x1(%rdi),%edx
  cmp    $0x5e,%al
  jne    L44
  test   %dl,%dl
  je     L44
  cmp    $0x5e,%dl
  je     L44
  movzbl 0x2(%rdi),%eax
  add    $0x2,%rdi
  test   %al,%al
  jne    L61
L56:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if ((*(p) == '^' && *((p) + 1) && *((p) + 1) != '^')) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Q_PrintStrlen>:
  endbr64
  test   %rdi,%rdi
  je     L14
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  jmp    L2
  nopl   0x0(%rax)
L11:
  add    $0x1,%rdi
  add    $0x1,%r8d
  mov    %edx,%eax
L2:
  test   %al,%al
  je     L7
L3:
  movzbl 0x1(%rdi),%edx
  cmp    $0x5e,%al
  jne    L11
  test   %dl,%dl
  je     L11
  cmp    $0x5e,%dl
  je     L11
  movzbl 0x2(%rdi),%eax
  add    $0x2,%rdi
  test   %al,%al
  jne    L3
L7:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if ((*(p) == '^' && *((p) + 1) && *((p) + 1) != '^')) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mycos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L17:
  mov    -0xc(%rbp),%edx
  mov    D0(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <mypow@plt>
  movsd  %xmm0,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <mypow@plt>
  movapd %xmm0,%xmm2
  mulsd  -0x20(%rbp),%xmm2
  movsd  %xmm2,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edi
  call   <fact@plt>
  movsd  -0x20(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  cmpl   $0x9,-0xc(%rbp)
  jle    L17
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: f32[2]

tool: {"D0": [0.0,-1.875]}

assistant: ```c
double mycos(double x) {
  double e = 0.0;
  int i;
  for (i = 0; i < 10; i++) {
    e += mypow(-1, i) * mypow(x, 2 * i) / fact(2 * i);
  }
  return e;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mycos>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%r12
  mov    $0x0,%ebx
  pxor   %xmm4,%xmm4
  movsd  %xmm4,(%rsp)
L0:
  mov    %ebx,%edi
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <mypow@plt>
  movq   %xmm0,%r14
  lea    (%rbx,%rbx,1),%ebp
  mov    %ebp,%edi
  movq   %r12,%xmm0
  call   <mypow@plt>
  movq   %r14,%xmm2
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %ebp,%edi
  call   <fact@plt>
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D9
datatype: f32[2]

tool: {"D9": [0.0,-1.875]}

assistant: ```c
double mycos(double x) {
  double e = 0.0;
  int i;
  for (i = 0; i < 10; i++) {
    e += mypow(-1, i) * mypow(x, 2 * i) / fact(2 * i);
  }
  return e;
}
```