ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_pipe>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <pfd@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <geti@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <geti@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    $0x1f,%edi
  mov    %eax,%ecx
  call   <syscall@plt>
  movslq %eax,%rbx
  test   %ebx,%ebx
  js     L27
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D33(%rip),%rdi
  mov    %ebx,%edx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  xor    %eax,%eax
  movb   $0x0,(%rsp,%rbx,1)
  lea    D29(%rip),%rdi
  call   <printf@plt>
L23:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L27:
  lea    D30(%rip),%rdi
  call   <puts@plt>
  jmp    L23
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type: string
name: parse_data
arguments: tag: D3
type: string
name: parse_data
arguments: tag: D33
type: string
name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D30
type: string

tool: D4: enter fd: 

tool: D3: nbytes: 

tool: D33: proc %d back to Umode, read %d bytes from pipe:


tool: D29: '%s'


tool: D30: read pipe failed

assistant: ```c
int read_pipe() {
  char fds[32], buf[1024];
  int fd, n, nbytes;
  pfd();
  printf("enter fd: ");
  fd = geti();
  printf("nbytes: ");
  nbytes = geti();
  n = syscall(31, fd, buf, nbytes);
  if (n >= 0) {
    printf("proc %d back to Umode, read %d bytes from pipe:\n", getpid(), n);
    buf[n] = 0;
    printf("'%s'\n", buf);
  } else {
    printf("read pipe failed\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scan2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xd8(%rbp)
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xd0(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0xd8(%rbp)
  cmpq   $0x0,-0xd8(%rbp)
  jne    L28
  lea    -0xd0(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L28
  movq   $0xffffffffffffffff,-0xd8(%rbp)
L28:
  mov    -0xd8(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string
name: read_data
arguments: label: D14
data_type: string

tool: D5: %s

tool: D14: 0

assistant: ```c
int scan2int() {
  char sss[200];
  long int ii = 0;
  scanf("%s", sss);
  ii = strtol(sss, NULL, 10);
  if ((ii == 0) && (strcmp(sss, "0") != 0))
    ii = -1;
  return ((int)ii);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scan2int>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strtol@plt>
  test   %rax,%rax
  je     L0
L21:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0xd0,%rsp
  pop    %rbx
  ret
L0:
  mov    %rsp,%rdi
  lea    D7(%rip),%rsi
  call   <strcmp@plt>
  neg    %rax
  sbb    %rax,%rax
  jmp    L21
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string

tool: D0: %s

tool: D7: 0

assistant: ```c
int scan2int() {
  char sss[200];
  long int ii = 0;
  scanf("%s", sss);
  ii = strtol(sss, NULL, 10);
  if ((ii == 0) && (strcmp(sss, "0") != 0))
    ii = -1;
  return ((int)ii);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scan2int>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  xor    %esi,%esi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  call   <strtol@plt>
  test   %rax,%rax
  je     L0
L21:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0xd0,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  neg    %rax
  sbb    %rax,%rax
  jmp    L21
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D10: %s

tool: D6: 0

assistant: ```c
int scan2int() {
  char sss[200];
  long int ii = 0;
  scanf("%s", sss);
  ii = strtol(sss, NULL, 10);
  if ((ii == 0) && (strcmp(sss, "0") != 0))
    ii = -1;
  return ((int)ii);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scan2int>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  xor    %esi,%esi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  call   <strtol@plt>
  test   %rax,%rax
  je     L20
L15:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0xd0,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  neg    %rax
  sbb    %rax,%rax
  jmp    L15
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D11
data_type: string

tool: D13: %s

tool: D11: 0

assistant: ```c
int scan2int() {
  char sss[200];
  long int ii = 0;
  scanf("%s", sss);
  ii = strtol(sss, NULL, 10);
  if ((ii == 0) && (strcmp(sss, "0") != 0))
    ii = -1;
  return ((int)ii);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<match_or>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L4
  mov    $0x1,%eax
  jmp    L19
L4:
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L23
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int match_or(const char *line, int termc, char *terms[]) {
  int i = 0;
  for (i = 0; i != termc; i++) {
    if (strstr(line, terms[i])) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<match_or>:
  endbr64
  test   %esi,%esi
  je     L27
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdx,%rax,8),%r12
L21:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L23
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L21
  jmp    L32
L27:
  mov    %esi,%eax
  ret
L23:
  mov    $0x1,%eax
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int match_or(const char *line, int termc, char *terms[]) {
  int i = 0;
  for (i = 0; i != termc; i++) {
    if (strstr(line, terms[i])) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<match_or>:
  endbr64
  test   %esi,%esi
  je     L16
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdx,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L19
  nopl   0x0(%rax)
L31:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L34
L19:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L31
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int match_or(const char *line, int termc, char *terms[]) {
  int i = 0;
  for (i = 0; i != termc; i++) {
    if (strstr(line, terms[i])) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<match_or>:
  endbr64
  test   %esi,%esi
  je     L9
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdx,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L5
  nopl   0x0(%rax)
L33:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L39
L5:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L33
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int match_or(const char *line, int termc, char *terms[]) {
  int i = 0;
  for (i = 0; i != termc; i++) {
    if (strstr(line, terms[i])) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  ja     L24
  mov    $0x0,%eax
  jmp    L52
L24:
  cmpl   $0x2,-0x14(%rbp)
  jbe    L32
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L32
  mov    $0x0,%eax
  jmp    L52
L32:
  movl   $0x3,-0x4(%rbp)
  jmp    L54
L10:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L35
  mov    $0x0,%eax
  jmp    L52
L35:
  addl   $0x2,-0x4(%rbp)
L54:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jb     L89
  cmpl   $0xffff,-0x4(%rbp)
  jbe    L10
L89:
  mov    $0x1,%eax
L52:
  pop    %rbp
  ret
```

assistant: ```c
int isprime(unsigned int n) {
  unsigned int i;
  if (n <= 1)
    return 0;
  if (n > 2 && n % 2 == 0)
    return 0;
  i = 3;
  while (i * i <= n && i < 0x10000) {
    if (n % i == 0)
      return 0;
    i += 2;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isprime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jbe    L22
  cmp    $0x2,%edi
  jbe    L13
  test   $0x1,%dil
  je     L22
L13:
  cmp    $0x8,%edi
  jbe    L69
  mov    %edi,%eax
  mov    $0xaaaaaaab,%edx
  imul   %rdx,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  je     L10
  mov    $0x3,%ecx
L16:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %eax,%edi
  jb     L68
  cmp    $0xffff,%ecx
  ja     L68
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  test   %edx,%edx
  jne    L16
  mov    $0x0,%eax
L22:
  ret
L68:
  mov    $0x1,%eax
  ret
L69:
  mov    $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isprime(unsigned int n) {
  unsigned int i;
  if (n <= 1)
    return 0;
  if (n > 2 && n % 2 == 0)
    return 0;
  i = 3;
  while (i * i <= n && i < 0x10000) {
    if (n % i == 0)
      return 0;
    i += 2;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isprime>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jbe    L2
  cmp    $0x2,%edi
  je     L43
  test   $0x1,%dil
  je     L18
  cmp    $0x8,%edi
  jbe    L43
  imul   $0xaaaaaaab,%edi,%edx
  cmp    $0x55555555,%edx
  jbe    L2
  mov    $0x3,%ecx
  xchg   %ax,%ax
L6:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %eax,%edi
  jb     L43
  cmp    $0xffff,%ecx
  ja     L43
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  jne    L6
  xor    %eax,%eax
L2:
  ret
  nopl   0x0(%rax)
L43:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L18:
  ret
```

assistant: ```c
int isprime(unsigned int n) {
  unsigned int i;
  if (n <= 1)
    return 0;
  if (n > 2 && n % 2 == 0)
    return 0;
  i = 3;
  while (i * i <= n && i < 0x10000) {
    if (n % i == 0)
      return 0;
    i += 2;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isprime>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jbe    L58
  cmp    $0x2,%edi
  je     L51
  test   $0x1,%dil
  je     L68
  cmp    $0x8,%edi
  jbe    L51
  imul   $0xaaaaaaab,%edi,%edx
  cmp    $0x55555555,%edx
  jbe    L58
  mov    $0x3,%ecx
  xchg   %ax,%ax
L15:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %eax,%edi
  jb     L51
  cmp    $0xffff,%ecx
  ja     L51
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  jne    L15
  xor    %eax,%eax
L58:
  ret
  nopl   0x0(%rax)
L51:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L68:
  ret
```

assistant: ```c
int isprime(unsigned int n) {
  unsigned int i;
  if (n <= 1)
    return 0;
  if (n > 2 && n % 2 == 0)
    return 0;
  i = 3;
  while (i * i <= n && i < 0x10000) {
    if (n % i == 0)
      return 0;
    i += 2;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zskip_svlv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L2
L15:
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L15
  addq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zskip_svlv(char **entry) {
  char *cursor = *entry;
  cursor++;
  while (*cursor < 0)
    cursor++;
  cursor++;
  *entry = cursor;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<zskip_svlv>:
  endbr64
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rax
  cmpb   $0x0,0x1(%rdx)
  jns    L15
L9:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  js     L9
L15:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void zskip_svlv(char **entry) {
  char *cursor = *entry;
  cursor++;
  while (*cursor < 0)
    cursor++;
  cursor++;
  *entry = cursor;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zskip_svlv>:
  endbr64
  mov    (%rdi),%rdx
  cmpb   $0x0,0x1(%rdx)
  lea    0x1(%rdx),%rax
  jns    L14
  nopl   0x0(%rax)
L8:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  js     L8
L14:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void zskip_svlv(char **entry) {
  char *cursor = *entry;
  cursor++;
  while (*cursor < 0)
    cursor++;
  cursor++;
  *entry = cursor;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zskip_svlv>:
  endbr64
  mov    (%rdi),%rdx
  cmpb   $0x0,0x1(%rdx)
  lea    0x1(%rdx),%rax
  jns    L12
  nopl   0x0(%rax)
L4:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  js     L4
L12:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void zskip_svlv(char **entry) {
  char *cursor = *entry;
  cursor++;
  while (*cursor < 0)
    cursor++;
  cursor++;
  *entry = cursor;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bam_swap_endian_2p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  call   <bam_swap_endian_2@plt>
  mov    -0x8(%rbp),%rdx
  mov    %ax,(%rdx)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *bam_swap_endian_2p(void *x) {
  *(unsigned short *)x = bam_swap_endian_2(*(unsigned short *)x);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bam_swap_endian_2p>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzwl (%rdi),%edi
  call   <bam_swap_endian_2@plt>
  mov    %ax,(%rbx)
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *bam_swap_endian_2p(void *x) {
  *(unsigned short *)x = bam_swap_endian_2(*(unsigned short *)x);
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bam_swap_endian_2p>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movzwl (%rdi),%edi
  call   <bam_swap_endian_2@plt>
  mov    %ax,(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *bam_swap_endian_2p(void *x) {
  *(unsigned short *)x = bam_swap_endian_2(*(unsigned short *)x);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bam_swap_endian_2p>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movzwl (%rdi),%edi
  call   <bam_swap_endian_2@plt>
  mov    %ax,(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *bam_swap_endian_2p(void *x) {
  *(unsigned short *)x = bam_swap_endian_2(*(unsigned short *)x);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FN_pointer_arith4_Bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ecx
  mov    $0xa,%eax
  sub    %ecx,%eax
  cltq
  add    %rax,%rdx
  lea    -0xd(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void FN_pointer_arith4_Bad(int *x) {
  int len = 5;
  char p[5];
  (p + *x)[10 - *x] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FN_pointer_arith4_Bad>:
  endbr64
  ret
```

assistant: ```c
void FN_pointer_arith4_Bad(int *x) {
  int len = 5;
  char p[5];
  (p + *x)[10 - *x] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<FN_pointer_arith4_Bad>:
  endbr64
  ret
```

assistant: ```c
void FN_pointer_arith4_Bad(int *x) {
  int len = 5;
  char p[5];
  (p + *x)[10 - *x] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<FN_pointer_arith4_Bad>:
  endbr64
  ret
```

assistant: ```c
void FN_pointer_arith4_Bad(int *x) {
  int len = 5;
  char p[5];
  (p + *x)[10 - *x] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D39
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D51
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: f64
name: retrieve_data
arguments: tag: D16
data_type: string
name: retrieve_data
arguments: tag: D17
data_type: string

tool: D39: 
 ** Conversor de polegadas para milimetros ** 

tool: D14: 
Digite o volume em polegadas: 

tool: D51: %f

tool: D19: 25.4

tool: D16: 
O Volume em milimetros e: %f.


tool: D17: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float Pol, Mm;
  printf("\n ** Conversor de polegadas para milimetros ** \n");
  printf("\nDigite o volume em polegadas: ");
  scanf("%f", &Pol);
  Mm = Pol * 25.4;
  printf("\nO Volume em milimetros e: %f.\n", Mm);
  printf("\n\n<< Marco_Tulio >>\n");
  getchar(), getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  mulsd  D40(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D32
type_guessed: string
name: unpack_data
arguments: data_label: D34
type_guessed: string
name: unpack_data
arguments: data_label: D22
type_guessed: string
name: unpack_data
arguments: data_label: D40
type_guessed: f64
name: unpack_data
arguments: data_label: D30
type_guessed: string
name: unpack_data
arguments: data_label: D55
type_guessed: string

tool: D32: 
 ** Conversor de polegadas para milimetros ** 

tool: D34: 
Digite o volume em polegadas: 

tool: D22: %f

tool: D40: 25.4

tool: D30: 
O Volume em milimetros e: %f.


tool: D55: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float Pol, Mm;
  printf("\n ** Conversor de polegadas para milimetros ** \n");
  printf("\nDigite o volume em polegadas: ");
  scanf("%f", &Pol);
  Mm = Pol * 25.4;
  printf("\nO Volume em milimetros e: %f.\n", Mm);
  printf("\n\n<< Marco_Tulio >>\n");
  getchar(), getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D51(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D21(%rip),%rdi
  cvtss2sd 0x4(%rsp),%xmm0
  mulsd  D14(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D51
type: string
name: disassemble_data
arguments: tag: D48
type: string
name: disassemble_data
arguments: tag: D38
type: string
name: disassemble_data
arguments: tag: D21
type: string
name: disassemble_data
arguments: tag: D14
type: f64
name: disassemble_data
arguments: tag: D39
type: string

tool: D51: 
 ** Conversor de polegadas para milimetros ** 

tool: D48: 
Digite o volume em polegadas: 

tool: D38: %f

tool: D21: 
O Volume em milimetros e: %f.


tool: D14: 25.4

tool: D39: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float Pol, Mm;
  printf("\n ** Conversor de polegadas para milimetros ** \n");
  printf("\nDigite o volume em polegadas: ");
  scanf("%f", &Pol);
  Mm = Pol * 25.4;
  printf("\nO Volume em milimetros e: %f.\n", Mm);
  printf("\n\n<< Marco_Tulio >>\n");
  getchar(), getchar();
}
```