ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<plot8>:
  endbr64
  sub    $0xd8,%rsp
  mov    %edi,%eax
  mov    %rdx,%rdi
  movslq %esi,%rsi
  mov    %fs:0x28,%rdx
  mov    %rdx,0xc8(%rsp)
  xor    %edx,%edx
  lea    0x2(%rax),%r11d
  lea    0x3(%rax),%r10d
  mov    %eax,0x74(%rsp)
  lea    0x4(%rax),%r9d
  lea    0x5(%rax),%r8d
  mov    %eax,0x7c(%rsp)
  movabs $0x100000001,%rcx
  movabs $0x300000003,%rdx
  mov    %rcx,0x14(%rsp)
  movabs $0x200000002,%rcx
  mov    %rcx,0x1c(%rsp)
  movabs $0x400000003,%rcx
  mov    %rcx,0x34(%rsp)
  movabs $0x500000004,%rcx
  mov    %rdx,0x24(%rsp)
  mov    %rdx,0x2c(%rsp)
  movabs $0x600000006,%rdx
  mov    %rcx,0x3c(%rsp)
  movabs $0x600000005,%rcx
  mov    %rcx,0x44(%rsp)
  lea    0x1(%rax),%ecx
  mov    %rdx,0x4c(%rsp)
  mov    %rdx,0x54(%rsp)
  lea    0x6(%rax),%edx
  mov    %edx,0x78(%rsp)
  mov    %edx,0x80(%rsp)
  mov    %eax,0x98(%rsp)
  mov    %edx,0x9c(%rsp)
  mov    %eax,0xa0(%rsp)
  xor    %eax,%eax
  mov    %edx,0xa4(%rsp)
  xor    %edx,%edx
  movq   $0x0,0x4(%rsp)
  movq   $0x0,0xc(%rsp)
  mov    %r11d,0x64(%rsp)
  mov    %r10d,0x68(%rsp)
  mov    %r9d,0x6c(%rsp)
  mov    %r8d,0x70(%rsp)
  mov    %ecx,0x84(%rsp)
  mov    %r11d,0x88(%rsp)
  mov    %r10d,0x8c(%rsp)
  mov    %r9d,0x90(%rsp)
  mov    %r8d,0x94(%rsp)
  mov    %ecx,0xa8(%rsp)
  mov    %r11d,0xac(%rsp)
  mov    %r10d,0xb0(%rsp)
  mov    %r9d,0xb4(%rsp)
  mov    %r8d,0xb8(%rsp)
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L8:
  movslq (%rsp,%rdx,1),%rax
  mov    0x60(%rsp,%rdx,1),%ecx
L12:
  imul   %rsi,%rax
  movslq %ecx,%rcx
  add    $0x4,%rdx
  add    %rdi,%rax
  movb   $0x38,(%rax,%rcx,1)
  cmp    $0x5c,%rdx
  jne    L8
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xd8,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void plot8(int posicao, int colunas, char matriz[7][colunas]) {
  int cx = 0;
  int cy = 0;
  int p = posicao;
  int x[] = {0, 0, 0, 0, 0, 1, 1, 2, 2, 3, 3, 3, 3, 3, 4, 4, 5, 5, 6, 6, 6, 6, 6};
  int y[] = {p + 1, p + 2, p + 3, p + 4, p + 5, p + 0, p + 6, p + 0, p + 6, p + 1, p + 2, p + 3, p + 4, p + 5, p + 0, p + 6, p + 0, p + 6, p + 1, p + 2, p + 3, p + 4, p + 5};
  int points = sizeof(x) / sizeof(int);
  for (cx = 0; cx < points; ++cx) {
    matriz[x[cx]][y[cx]] = '8';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x539,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: a: %d

assistant: ```c
void a(void) {
  int a = 1337;
  printf("a: %d", a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<a>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x539,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string

tool: D9: a: %d

assistant: ```c
void a(void) {
  int a = 1337;
  printf("a: %d", a);
}
```
user: What is the c source code of the assembly code below?

```asm
<a>:
  endbr64
  mov    $0x539,%esi
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: a: %d

assistant: ```c
void a(void) {
  int a = 1337;
  printf("a: %d", a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<a>:
  endbr64
  mov    $0x539,%esi
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: a: %d

assistant: ```c
void a(void) {
  int a = 1337;
  printf("a: %d", a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x51e22cdb,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L10
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0xe(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
  lea    -0xc(%rbp),%rax
  movzwl -0xe(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0xc(%rbp),%esi
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  shr    $0x2,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %esi,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L0
L10:
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  shl    $0x4,%eax
  and    $0x3e0,%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  mov    %al,-0xf(%rbp)
  lea    -0xc(%rbp),%rdx
  add    $0x2,%rdx
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzbl -0xf(%rbp),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xf(%rbp)
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  lea    -0xc(%rbp),%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  movzbl -0xf(%rbp),%edx
  mov    %dl,(%rax)
L0:
  mov    -0xc(%rbp),%eax
  shr    %eax
  or     $0x760802e2,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + 1373777115U;
    if (state[0UL] & 1U) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = copy11;
      state[0UL] |= ((state[0UL] << (((state[0UL] >> 2U) & 7U) | 1UL)) & 15U) << 2UL;
    } else {
      state[0UL] |= ((state[0UL] + state[0UL]) & 63U) << 4UL;
      copy12 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy12;
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy12;
    }
    output[0UL] = (state[0UL] >> 1U) | 1980236514U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x51e22cdb(%rax),%edx
  test   $0x1,%al
  jne    L16
  mov    %edx,%eax
  shl    $0x10,%eax
  shr    $0x10,%edx
  mov    %dx,%ax
  mov    %eax,%ecx
  shr    $0x2,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  mov    %eax,%edx
  shl    %cl,%edx
  shl    $0x2,%edx
  and    $0x3c,%edx
  or     %edx,%eax
L2:
  shr    %eax
  or     $0x760802e2,%eax
  mov    %eax,(%rsi)
  ret
L16:
  mov    %edx,%ecx
  shl    $0x5,%ecx
  and    $0x3e0,%ecx
  or     %edx,%ecx
  shr    $0x18,%edx
  shl    $0x10,%edx
  mov    %ecx,%eax
  and    $0xff00ffff,%eax
  or     %edx,%eax
  mov    %ecx,%edx
  shl    $0x8,%edx
  sar    $0x18,%edx
  mov    %dl,%al
  shl    $0x18,%ecx
  and    $0xffffff,%eax
  or     %ecx,%eax
  jmp    L2
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + 1373777115U;
    if (state[0UL] & 1U) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = copy11;
      state[0UL] |= ((state[0UL] << (((state[0UL] >> 2U) & 7U) | 1UL)) & 15U) << 2UL;
    } else {
      state[0UL] |= ((state[0UL] + state[0UL]) & 63U) << 4UL;
      copy12 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy12;
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy12;
    }
    output[0UL] = (state[0UL] >> 1U) | 1980236514U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x51e22cdb(%rax),%edx
  test   $0x1,%al
  jne    L9
  mov    %edx,%eax
  shr    $0x10,%edx
  shl    $0x10,%eax
  mov    %dx,%ax
  mov    %eax,%ecx
  mov    %eax,%edx
  shr    $0x2,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%edx
  shl    $0x2,%edx
  and    $0x3c,%edx
  or     %edx,%eax
  shr    %eax
  or     $0x760802e2,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L9:
  mov    %edx,%ecx
  shl    $0x5,%ecx
  and    $0x3e0,%ecx
  or     %edx,%ecx
  shr    $0x18,%edx
  mov    %ecx,%eax
  shl    $0x10,%edx
  and    $0xff00ffff,%eax
  or     %edx,%eax
  mov    %ecx,%edx
  shl    $0x18,%ecx
  shl    $0x8,%edx
  sar    $0x18,%edx
  mov    %dl,%al
  and    $0xffffff,%eax
  or     %ecx,%eax
  shr    %eax
  or     $0x760802e2,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + 1373777115U;
    if (state[0UL] & 1U) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = copy11;
      state[0UL] |= ((state[0UL] << (((state[0UL] >> 2U) & 7U) | 1UL)) & 15U) << 2UL;
    } else {
      state[0UL] |= ((state[0UL] + state[0UL]) & 63U) << 4UL;
      copy12 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy12;
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy12;
    }
    output[0UL] = (state[0UL] >> 1U) | 1980236514U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    0x51e22cdb(%rdx),%eax
  and    $0x1,%edx
  jne    L6
  rol    $0x10,%eax
  mov    %eax,%ecx
  mov    %eax,%edx
  shr    $0x2,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %edx,%eax
  shr    %eax
  or     $0x760802e2,%eax
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L6:
  mov    %eax,%edx
  shl    $0x5,%edx
  and    $0x3e0,%edx
  or     %eax,%edx
  mov    %edx,%ecx
  mov    %edx,%eax
  mov    %edx,%edi
  shl    $0x8,%ecx
  sar    $0x18,%edi
  sar    $0x18,%ecx
  mov    %cl,%al
  xor    %ecx,%ecx
  mov    %dil,%cl
  movzwl %ax,%eax
  mov    %dl,%ch
  shl    $0x10,%ecx
  or     %ecx,%eax
  shr    %eax
  or     $0x760802e2,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + 1373777115U;
    if (state[0UL] & 1U) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = copy11;
      state[0UL] |= ((state[0UL] << (((state[0UL] >> 2U) & 7U) | 1UL)) & 15U) << 2UL;
    } else {
      state[0UL] |= ((state[0UL] + state[0UL]) & 63U) << 4UL;
      copy12 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy12;
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy12;
    }
    output[0UL] = (state[0UL] >> 1U) | 1980236514U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_palindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L6:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  sub    %rcx,%rax
  lea    -0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L25
  mov    $0x0,%eax
  jmp    L3
L25:
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  shr    %rdx
  cmp    %rdx,%rax
  jb     L6
  mov    $0x1,%eax
L3:
  leave
  ret
```

assistant: ```c
bool is_palindrome(char *letters) {
  size_t len = strlen(letters);
  for (int i = 0; i < len / 2; i++) {
    if (letters[i] != letters[len - i - 1])
      return false;
  }
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_palindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rcx
  shr    %rcx
  cmp    $0x1,%rax
  jbe    L0
  lea    -0x1(%rbx,%rax,1),%rdx
  mov    $0x0,%eax
L31:
  movzbl (%rdx),%esi
  cmp    %sil,(%rbx,%rax,1)
  jne    L23
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %rcx,%rax
  jb     L31
  mov    $0x1,%eax
  jmp    L4
L0:
  mov    $0x1,%eax
  jmp    L4
L23:
  mov    $0x0,%eax
L4:
  pop    %rbx
  ret
```

assistant: ```c
bool is_palindrome(char *letters) {
  size_t len = strlen(letters);
  for (int i = 0; i < len / 2; i++) {
    if (letters[i] != letters[len - i - 1])
      return false;
  }
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_palindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rdx
  shr    %rdx
  je     L34
  mov    %rbx,%rdi
  lea    -0x1(%rbx,%rax,1),%rax
  add    %rbx,%rdx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rdi
  sub    $0x1,%rax
  cmp    %rdx,%rdi
  je     L34
L14:
  movzbl (%rax),%ecx
  cmp    %cl,(%rdi)
  je     L13
  xor    %eax,%eax
  pop    %rbx
  ret
L34:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool is_palindrome(char *letters) {
  size_t len = strlen(letters);
  for (int i = 0; i < len / 2; i++) {
    if (letters[i] != letters[len - i - 1])
      return false;
  }
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_palindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rdx
  shr    %rdx
  je     L11
  mov    %rbx,%rdi
  lea    -0x1(%rbx,%rax,1),%rax
  add    %rbx,%rdx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rdi
  sub    $0x1,%rax
  cmp    %rdx,%rdi
  je     L11
L8:
  movzbl (%rax),%ecx
  cmp    %cl,(%rdi)
  je     L10
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool is_palindrome(char *letters) {
  size_t len = strlen(letters);
  for (int i = 0; i < len / 2; i++) {
    if (letters[i] != letters[len - i - 1])
      return false;
  }
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L38
  movl   $0x1,-0xc(%rbp)
L38:
  cmpl   $0x0,-0xc(%rbp)
  je     L10
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L10:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getValue(char *keyvalue) {
  char *value;
  value = malloc(strlen(keyvalue));
  int found = 0;
  while (*keyvalue++) {
    if (*keyvalue == '=') {
      found = 1;
    }
    if (found) {
      *value++ = *keyvalue;
    }
  }
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getValue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  cmpb   $0x0,(%rbx)
  je     L16
  lea    0x1(%rbx),%rdx
  mov    $0x0,%esi
  mov    $0x1,%edi
  jmp    L31
L26:
  mov    %cl,(%rax)
  lea    0x1(%rax),%rax
  mov    %edi,%esi
L44:
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  je     L16
L31:
  movzbl (%rdx),%ecx
  cmp    $0x3d,%cl
  je     L26
  test   %esi,%esi
  je     L44
  jmp    L26
L16:
  pop    %rbx
  ret
```

assistant: ```c
char *getValue(char *keyvalue) {
  char *value;
  value = malloc(strlen(keyvalue));
  int found = 0;
  while (*keyvalue++) {
    if (*keyvalue == '=') {
      found = 1;
    }
    if (found) {
      *value++ = *keyvalue;
    }
  }
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getValue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  cmpb   $0x0,(%rbx)
  je     L0
  lea    0x1(%rbx),%rcx
  xor    %esi,%esi
  nop
L8:
  movzbl (%rcx),%edx
  cmp    $0x3d,%dl
  je     L3
  mov    %esi,%edi
  xor    %esi,%esi
  and    $0x1,%edi
  test   %dil,%dil
  je     L17
L3:
  mov    %dl,(%rax)
  mov    $0x1,%esi
  add    $0x1,%rax
L17:
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L8
L0:
  pop    %rbx
  ret
```

assistant: ```c
char *getValue(char *keyvalue) {
  char *value;
  value = malloc(strlen(keyvalue));
  int found = 0;
  while (*keyvalue++) {
    if (*keyvalue == '=') {
      found = 1;
    }
    if (found) {
      *value++ = *keyvalue;
    }
  }
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getValue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  cmpb   $0x0,(%rbx)
  je     L44
  lea    0x1(%rbx),%rcx
L13:
  xor    %esi,%esi
L53:
  movzbl (%rcx),%edx
  cmp    $0x3d,%dl
  je     L42
  test   %esi,%esi
  jne    L42
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L13
L44:
  mov    %rax,%r8
L29:
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %dl,(%rax)
  lea    0x1(%rax),%r8
  add    $0x1,%rcx
  test   %dl,%dl
  je     L29
  mov    %r8,%rax
  mov    $0x1,%esi
  jmp    L53
```

assistant: ```c
char *getValue(char *keyvalue) {
  char *value;
  value = malloc(strlen(keyvalue));
  int found = 0;
  while (*keyvalue++) {
    if (*keyvalue == '=') {
      found = 1;
    }
    if (found) {
      *value++ = *keyvalue;
    }
  }
  return value;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_did>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x4,-0x4(%rbp)
  jle    L5
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: %02x

assistant: ```c
void print_did(uint8_t *d) {
  for (uint8_t i = 0; i < 5; i++)
    printf("%02x", d[i]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_did>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x14(%rdi),%r12
  lea    D6(%rip),%rbp
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: %02x

assistant: ```c
void print_did(uint8_t *d) {
  for (uint8_t i = 0; i < 5; i++)
    printf("%02x", d[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_did>:
  endbr64
  push   %r12
  lea    0x14(%rdi),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: %02x

assistant: ```c
void print_did(uint8_t *d) {
  for (uint8_t i = 0; i < 5; i++)
    printf("%02x", d[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_did>:
  endbr64
  push   %r12
  lea    0x14(%rdi),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: %02x

assistant: ```c
void print_did(uint8_t *d) {
  for (uint8_t i = 0; i < 5; i++)
    printf("%02x", d[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<combine_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movsbl -0x1c(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    $0x9,%eax
  jle    L4
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <overflow@plt>
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void combine_char(char total[], char addy, int idx) {
  int add_in = addy - '0';
  int add_to = total[idx] - '0';
  if (add_to + add_in > 9)
    overflow(total, idx + 1);
  total[idx] = ((add_to + add_in) % 10) + '0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<combine_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %edx,%rbp
  add    %rdi,%rbp
  movsbl 0x0(%rbp),%eax
  movsbl %sil,%esi
  lea    -0x60(%rax,%rsi,1),%ebx
  cmp    $0x9,%ebx
  jg     L2
L8:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    0x1(%rdx),%esi
  call   <overflow@plt>
  jmp    L8
```

assistant: ```c
void combine_char(char total[], char addy, int idx) {
  int add_in = addy - '0';
  int add_to = total[idx] - '0';
  if (add_to + add_in > 9)
    overflow(total, idx + 1);
  total[idx] = ((add_to + add_in) % 10) + '0';
}
```