ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<getch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D8(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    (%rbx),%edi
  mov    %r12,%rsi
  call   <tcgetattr@plt>
  mov    0x10(%rsp),%eax
  mov    D31(%rip),%rbp
  mov    D9(%rip),%rdx
  mov    (%rbx),%edi
  mov    %eax,0x14(%rsp)
  mov    D26(%rip),%rax
  mov    0x0(%rbp),%esi
  mov    (%rax),%eax
  or     (%rdx),%eax
  lea    0x14(%rsp),%rdx
  not    %eax
  and    %eax,0x14(%rsp)
  call   <tcsetattr@plt>
  mov    (%rbx),%edi
  lea    0xf(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L14
  movsbl 0xf(%rsp),%r13d
L2:
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  mov    %r12,%rdx
  call   <tcsetattr@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L14:
  mov    $0xffffffff,%r13d
  jmp    L2
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getch(void) {
  int ch;
  struct termios oldt;
  struct termios newt;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  char chr;
  if (read(STDIN_FILENO, &chr, 1) == 1)
    ch = chr;
  else
    ch = -1;
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  return ch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wcstombs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L15
L43:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jns    L45
  mov    $0xffffffffffffffff,%rax
  jmp    L14
L45:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    -0x8(%rbp),%rax
  jmp    L14
L38:
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x28(%rbp)
L15:
  cmpq   $0x0,-0x28(%rbp)
  jne    L43
  mov    -0x8(%rbp),%rax
L14:
  pop    %rbp
  ret
```

assistant: ```c
size_t wcstombs(char *s, const wchar_t *pwcs, size_t n) {
  size_t r = 0;
  for (; n != 0; n--) {
    wchar_t w = pwcs[r];
    if ((unsigned)w > (unsigned char)-1)
      return (size_t)-1;
    if ((s[r] = w) == 0)
      return r;
    r++;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wcstombs>:
  endbr64
  test   %rdx,%rdx
  je     L33
  mov    $0x0,%eax
L30:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  js     L35
  mov    %cl,(%rdi,%rax,1)
  je     L10
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L30
  mov    %rdx,%rax
  ret
L33:
  mov    %rdx,%rax
  ret
L35:
  mov    $0xffffffffffffffff,%rax
L10:
  ret
```

assistant: ```c
size_t wcstombs(char *s, const wchar_t *pwcs, size_t n) {
  size_t r = 0;
  for (; n != 0; n--) {
    wchar_t w = pwcs[r];
    if ((unsigned)w > (unsigned char)-1)
      return (size_t)-1;
    if ((s[r] = w) == 0)
      return r;
    r++;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wcstombs>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L15
  jmp    L16
  nopl   (%rax)
L3:
  mov    %cl,(%rdi,%rax,1)
  je     L7
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L17
L15:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jns    L3
  mov    $0xffffffffffffffff,%rax
L7:
  ret
  xchg   %ax,%ax
L17:
  ret
L16:
  ret
```

assistant: ```c
size_t wcstombs(char *s, const wchar_t *pwcs, size_t n) {
  size_t r = 0;
  for (; n != 0; n--) {
    wchar_t w = pwcs[r];
    if ((unsigned)w > (unsigned char)-1)
      return (size_t)-1;
    if ((s[r] = w) == 0)
      return r;
    r++;
  }
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wcstombs>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L34
  jmp    L14
  nopl   (%rax)
L16:
  mov    %cl,(%rdi,%rax,1)
  je     L23
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L8
L34:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jns    L16
  mov    $0xffffffffffffffff,%rax
L23:
  ret
  xchg   %ax,%ax
L8:
  ret
L14:
  ret
```

assistant: ```c
size_t wcstombs(char *s, const wchar_t *pwcs, size_t n) {
  size_t r = 0;
  for (; n != 0; n--) {
    wchar_t w = pwcs[r];
    if ((unsigned)w > (unsigned char)-1)
      return (size_t)-1;
    if ((s[r] = w) == 0)
      return r;
    r++;
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<varintWrite32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void varintWrite32(unsigned char *z, unsigned int y) {
  z[0] = (unsigned char)(y >> 24);
  z[1] = (unsigned char)(y >> 16);
  z[2] = (unsigned char)(y >> 8);
  z[3] = (unsigned char)(y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<varintWrite32>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  shr    $0x18,%edx
  mov    %dl,(%rdi)
  mov    %esi,%edx
  shr    $0x10,%edx
  mov    %dl,0x1(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdi)
  mov    %sil,0x3(%rdi)
  ret
```

assistant: ```c
void varintWrite32(unsigned char *z, unsigned int y) {
  z[0] = (unsigned char)(y >> 24);
  z[1] = (unsigned char)(y >> 16);
  z[2] = (unsigned char)(y >> 8);
  z[3] = (unsigned char)(y);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<varintWrite32>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void varintWrite32(unsigned char *z, unsigned int y) {
  z[0] = (unsigned char)(y >> 24);
  z[1] = (unsigned char)(y >> 16);
  z[2] = (unsigned char)(y >> 8);
  z[3] = (unsigned char)(y);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<varintWrite32>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void varintWrite32(unsigned char *z, unsigned int y) {
  z[0] = (unsigned char)(y >> 24);
  z[1] = (unsigned char)(y >> 16);
  z[2] = (unsigned char)(y >> 8);
  z[3] = (unsigned char)(y);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1b6,-0x8(%rbp)
  movl   $0x99,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int random(int range, int x) {
  int a = 438, b = 153;
  return (a * x + b) % range;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<random>:
  endbr64
  imul   $0x1b6,%esi,%eax
  add    $0x99,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  ret
```

assistant: ```c
int random(int range, int x) {
  int a = 438, b = 153;
  return (a * x + b) % range;
}
```
user: Translate the below assembly code into C programming language:

```asm
<random>:
  endbr64
  imul   $0x1b6,%esi,%eax
  add    $0x99,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  ret
```

assistant: ```c
int random(int range, int x) {
  int a = 438, b = 153;
  return (a * x + b) % range;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<random>:
  endbr64
  imul   $0x1b6,%esi,%eax
  add    $0x99,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  ret
```

assistant: ```c
int random(int range, int x) {
  int a = 438, b = 153;
  return (a * x + b) % range;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<invalid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    $0x1,%eax
  jmp    L23
L1:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L8
  mov    $0x0,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int invalid(char *msg, size_t size) {
  for (int i = 0; i < size; i++) {
    if (!msg[i])
      return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<invalid>:
  endbr64
  test   %rsi,%rsi
  je     L6
  mov    %rdi,%rax
  add    %rsi,%rdi
L11:
  cmpb   $0x0,(%rax)
  je     L5
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L11
  mov    $0x0,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int invalid(char *msg, size_t size) {
  for (int i = 0; i < size; i++) {
    if (!msg[i])
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<invalid>:
  endbr64
  test   %rsi,%rsi
  je     L36
  add    %rdi,%rsi
  jmp    L39
  xchg   %ax,%ax
L33:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L36
L39:
  cmpb   $0x0,(%rdi)
  jne    L33
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
int invalid(char *msg, size_t size) {
  for (int i = 0; i < size; i++) {
    if (!msg[i])
      return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<invalid>:
  endbr64
  test   %rsi,%rsi
  je     L6
  add    %rdi,%rsi
  jmp    L34
  xchg   %ax,%ax
L28:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L6
L34:
  cmpb   $0x0,(%rdi)
  jne    L28
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int invalid(char *msg, size_t size) {
  for (int i = 0; i < size; i++) {
    if (!msg[i])
      return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jle    L66
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L66:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L39
L44:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jg     L10
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jg     L10
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L10
  mov    $0x1,%eax
  jmp    L55
L10:
  mov    $0x0,%eax
L55:
  add    %eax,-0x14(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jg     L44
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string

tool: D24: %d %d

tool: D11: %d

assistant: ```c
int main() {
  int x, y, i = 1, c = 0, t, l;
  scanf("%d %d", &x, &y);
  if (x > y) {
    t = x;
    x = y;
    y = t;
  }
  l = (x < y) ? x : y;
  while (i > 0) {
    scanf("%d", &i);
    c += (x <= i && i <= y && i % l == 0) ? 1 : 0;
  }
  printf("%d", c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  cmp    %edx,%eax
  jle    L44
  mov    %edx,0xc(%rsp)
  mov    %eax,0x10(%rsp)
L44:
  mov    0x10(%rsp),%r12d
  mov    0xc(%rsp),%eax
  cmp    %eax,%r12d
  cmovg  %eax,%r12d
  cmpl   $0x0,0x14(%rsp)
  jle    L63
  mov    $0x0,%ebx
  lea    D24(%rip),%rbp
  jmp    L15
L10:
  add    %eax,%ebx
  test   %ecx,%ecx
  jle    L62
L15:
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    $0x0,%eax
  cmp    %ecx,0xc(%rsp)
  jg     L10
  cmp    0x10(%rsp),%ecx
  jg     L10
  mov    %ecx,%eax
  cltd
  idiv   %r12d
  test   %edx,%edx
  sete   %al
  movzbl %al,%eax
  jmp    L10
L63:
  mov    $0x0,%ebx
L62:
  mov    %ebx,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D24
datatype: string

tool: D3: %d %d

tool: D24: %d

assistant: ```c
int main() {
  int x, y, i = 1, c = 0, t, l;
  scanf("%d %d", &x, &y);
  if (x > y) {
    t = x;
    x = y;
    y = t;
  }
  l = (x < y) ? x : y;
  while (i > 0) {
    scanf("%d", &i);
    c += (x <= i && i <= y && i % l == 0) ? 1 : 0;
  }
  printf("%d", c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  movl   $0x1,0x14(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%ebx
  cmp    %ebx,%eax
  jle    L46
  mov    %eax,0x10(%rsp)
  mov    %ebx,0xc(%rsp)
  mov    %eax,%ebx
L46:
  mov    0xc(%rsp),%eax
  lea    D24(%rip),%rbp
  cmp    %eax,%ebx
  cmovg  %eax,%ebx
  mov    0x14(%rsp),%eax
  xor    %r13d,%r13d
  test   %eax,%eax
  jle    L34
  lea    0x14(%rsp),%r12
  lea    D24(%rip),%rbp
  nopl   0x0(%rax)
L26:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  cmp    %ecx,0xc(%rsp)
  jg     L42
  cmp    0x10(%rsp),%ecx
  jg     L42
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  cmp    $0x1,%edx
  adc    $0x0,%r13d
L42:
  test   %ecx,%ecx
  jg     L26
L34:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D24
type: string

tool: D17: %d %d

tool: D24: %d

assistant: ```c
int main() {
  int x, y, i = 1, c = 0, t, l;
  scanf("%d %d", &x, &y);
  if (x > y) {
    t = x;
    x = y;
    y = t;
  }
  l = (x < y) ? x : y;
  while (i > 0) {
    scanf("%d", &i);
    c += (x <= i && i <= y && i % l == 0) ? 1 : 0;
  }
  printf("%d", c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  movl   $0x1,0x14(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%ebx
  cmp    %ebx,%eax
  jle    L42
  mov    %eax,0x10(%rsp)
  mov    %ebx,0xc(%rsp)
  mov    %eax,%ebx
L42:
  mov    0xc(%rsp),%eax
  lea    D25(%rip),%rbp
  cmp    %eax,%ebx
  cmovg  %eax,%ebx
  mov    0x14(%rsp),%eax
  xor    %r13d,%r13d
  test   %eax,%eax
  jle    L9
  lea    0x14(%rsp),%r12
  lea    D25(%rip),%rbp
  nopl   0x0(%rax)
L16:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  cmp    %ecx,0xc(%rsp)
  jg     L20
  cmp    0x10(%rsp),%ecx
  jg     L20
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  cmp    $0x1,%edx
  adc    $0x0,%r13d
L20:
  test   %ecx,%ecx
  jg     L16
L9:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string
name: retrieve_data
arguments: label: D25
datatype: string

tool: D7: %d %d

tool: D25: %d

assistant: ```c
int main() {
  int x, y, i = 1, c = 0, t, l;
  scanf("%d %d", &x, &y);
  if (x > y) {
    t = x;
    x = y;
    y = t;
  }
  l = (x < y) ? x : y;
  while (i > 0) {
    scanf("%d", &i);
    c += (x <= i && i <= y && i % l == 0) ? 1 : 0;
  }
  printf("%d", c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L29
  mov    -0x18(%rbp),%rax
  mov    %rax,D45(%rip)
  jmp    L153
L29:
  mov    D45(%rip),%rax
  test   %rax,%rax
  jne    L116
  mov    $0x0,%eax
  jmp    L59
L116:
  mov    D45(%rip),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L153
L96:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L157
  addq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L153
L157:
  addq   $0x1,-0x8(%rbp)
L153:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L161
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L96
L161:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L85
  movq   $0x0,D45(%rip)
  mov    D45(%rip),%rax
  jmp    L59
L85:
  mov    -0x18(%rbp),%rax
  mov    %rax,D49(%rip)
  jmp    L28
L64:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L94
L114:
  mov    D49(%rip),%rax
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  jne    L94
  mov    D49(%rip),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,D49(%rip)
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L59
L94:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L114
  mov    D49(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D49(%rip)
L28:
  mov    D49(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  movq   $0x0,D49(%rip)
  mov    -0x18(%rbp),%rax
L59:
  pop    %rbp
  ret
```

assistant: ```c
char *strtok(char *restrict s1, const char *restrict s2) {
  static char *tmp = NULL;
  const char *p = s2;
  if (s1 != NULL) {
    tmp = s1;
  } else {
    if (tmp == NULL) {
      return NULL;
    }
    s1 = tmp;
  }
  while (*p && *s1) {
    if (*s1 == *p) {
      ++s1;
      p = s2;
      continue;
    }
    ++p;
  }
  if (!*s1) {
    return (tmp = NULL);
  }
  tmp = s1;
  while (*tmp) {
    p = s2;
    while (*p) {
      if (*tmp == *p++) {
        *tmp++ = '\0';
        return s1;
      }
    }
    ++tmp;
  }
  tmp = NULL;
  return s1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtok>:
  endbr64
  test   %rdi,%rdi
  je     L146
L9:
  movzbl (%rsi),%r8d
  mov    %rsi,%rcx
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L133
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L85
  mov    %rdi,%r8
  jmp    L63
L146:
  mov    D33(%rip),%rdi
  test   %rdi,%rdi
  jne    L9
  mov    %rdi,%r8
  jmp    L56
L69:
  add    $0x1,%rdi
  mov    %rsi,%rax
  mov    %r8d,%edx
L43:
  mov    %rax,%rcx
L133:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L85
  cmp    %dl,%al
  je     L69
  lea    0x1(%rcx),%rax
  movzbl 0x1(%rcx),%edx
  test   %dl,%dl
  jne    L43
  movzbl (%rdi),%ecx
  mov    %rdi,%r8
  jmp    L63
L85:
  movq   $0x0,D33(%rip)
  mov    $0x0,%r8d
  jmp    L56
L11:
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L5
L63:
  mov    %rsi,%rax
L47:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L11
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L47
  lea    0x1(%rdi),%rax
  mov    %rax,D30(%rip)
  movb   $0x0,(%rdi)
L56:
  mov    %r8,%rax
  ret
L5:
  movq   $0x0,D30(%rip)
  jmp    L56
```

assistant: ```c
char *strtok(char *restrict s1, const char *restrict s2) {
  static char *tmp = NULL;
  const char *p = s2;
  if (s1 != NULL) {
    tmp = s1;
  } else {
    if (tmp == NULL) {
      return NULL;
    }
    s1 = tmp;
  }
  while (*p && *s1) {
    if (*s1 == *p) {
      ++s1;
      p = s2;
      continue;
    }
    ++p;
  }
  if (!*s1) {
    return (tmp = NULL);
  }
  tmp = s1;
  while (*tmp) {
    p = s2;
    while (*p) {
      if (*tmp == *p++) {
        *tmp++ = '\0';
        return s1;
      }
    }
    ++tmp;
  }
  tmp = NULL;
  return s1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strtok>:
  endbr64
  test   %rdi,%rdi
  je     L139
L93:
  movzbl (%rsi),%r9d
  movzbl (%rdi),%ecx
  mov    %rsi,%rdx
  mov    %r9d,%eax
  test   %r9b,%r9b
  jne    L124
  jmp    L36
  nopl   0x0(%rax)
L131:
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%r8
  test   %al,%al
  je     L122
L89:
  mov    %r8,%rdx
L124:
  test   %cl,%cl
  je     L5
  cmp    %al,%cl
  jne    L131
  movzbl 0x1(%rdi),%ecx
  mov    %rsi,%r8
  add    $0x1,%rdi
  mov    %r9d,%eax
  jmp    L89
L36:
  test   %cl,%cl
  je     L5
L122:
  mov    %rdi,%r8
L27:
  mov    %r9d,%eax
  mov    %rsi,%rdx
  jmp    L78
  xchg   %ax,%ax
L67:
  add    $0x1,%rdx
  cmp    %cl,%al
  je     L14
  movzbl (%rdx),%eax
L78:
  test   %al,%al
  jne    L67
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  jne    L27
  movq   $0x0,D31(%rip)
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L14:
  lea    0x1(%rdi),%rax
  movb   $0x0,(%rdi)
  mov    %rax,D37(%rip)
L55:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  movq   $0x0,D37(%rip)
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L139:
  mov    D37(%rip),%rdi
  test   %rdi,%rdi
  jne    L93
  xor    %r8d,%r8d
  jmp    L55
```

assistant: ```c
char *strtok(char *restrict s1, const char *restrict s2) {
  static char *tmp = NULL;
  const char *p = s2;
  if (s1 != NULL) {
    tmp = s1;
  } else {
    if (tmp == NULL) {
      return NULL;
    }
    s1 = tmp;
  }
  while (*p && *s1) {
    if (*s1 == *p) {
      ++s1;
      p = s2;
      continue;
    }
    ++p;
  }
  if (!*s1) {
    return (tmp = NULL);
  }
  tmp = s1;
  while (*tmp) {
    p = s2;
    while (*p) {
      if (*tmp == *p++) {
        *tmp++ = '\0';
        return s1;
      }
    }
    ++tmp;
  }
  tmp = NULL;
  return s1;
}
```