ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L13
  xor    %r14d,%r14d
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D24(%rip),%rbp
  lea    D25(%rip),%rbx
  nopl   0x0(%rax)
L4:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  add    $0x1,%r14d
  call   <MDC@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %r14d,0xc(%rsp)
  jg     L4
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
datatype: string
name: disassemble_data
arguments: data_tag: D24
datatype: string
name: disassemble_data
arguments: data_tag: D25
datatype: string

tool: D22: %d

tool: D24: %d%d

tool: D25: %d


assistant: ```c
int main() {
  int N, Cont, Fig1, Fig2, Mdc;
  scanf("%d", &N);
  for (Cont = 0; Cont < N; Cont++) {
    scanf("%d%d", &Fig1, &Fig2);
    Mdc = MDC(Fig1, Fig2);
    printf("%d\n", Mdc);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L0
  mov    -0x14(%rbp),%eax
  jmp    L1
L0:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n) {
  if (n < 2)
    return n;
  else
    return (fib(n - 1) + fib(n - 2));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L1
L17:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  lea    0x0(%rbp,%rax,1),%ebx
  jmp    L17
```

assistant: ```c
int fib(int n) {
  if (n < 2)
    return n;
  else
    return (fib(n - 1) + fib(n - 2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1505,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L1:
  mov    -0x10(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  xor    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t string_hash(const char *str) {
  size_t hash = 5381;
  for (size_t i = 0; str[i] != '\0'; i++) {
    hash = ((hash << 5) + hash) ^ str[i];
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<string_hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L6
  add    $0x1,%rdi
  mov    $0x1505,%eax
L17:
  mov    %rax,%rcx
  shl    $0x5,%rcx
  add    %rcx,%rax
  movsbq %dl,%rdx
  xor    %rdx,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L17
  ret
L6:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
size_t string_hash(const char *str) {
  size_t hash = 5381;
  for (size_t i = 0; str[i] != '\0'; i++) {
    hash = ((hash << 5) + hash) ^ str[i];
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<string_hash>:
  endbr64
  movsbq (%rdi),%rdx
  test   %dl,%dl
  je     L16
  add    $0x1,%rdi
  mov    $0x1505,%eax
  nopl   (%rax)
L3:
  mov    %rax,%rcx
  add    $0x1,%rdi
  shl    $0x5,%rcx
  add    %rcx,%rax
  xor    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  jne    L3
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
size_t string_hash(const char *str) {
  size_t hash = 5381;
  for (size_t i = 0; str[i] != '\0'; i++) {
    hash = ((hash << 5) + hash) ^ str[i];
  }
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_hash>:
  endbr64
  movsbq (%rdi),%rdx
  test   %dl,%dl
  je     L9
  add    $0x1,%rdi
  mov    $0x1505,%eax
  nopl   (%rax)
L17:
  mov    %rax,%rcx
  add    $0x1,%rdi
  shl    $0x5,%rcx
  add    %rcx,%rax
  xor    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
size_t string_hash(const char *str) {
  size_t hash = 5381;
  for (size_t i = 0; str[i] != '\0'; i++) {
    hash = ((hash << 5) + hash) ^ str[i];
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_phone_number_letters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
  mov    -0x1c(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L38
L63:
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L31:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  movsbl %al,%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <get_char_key@plt>
  mov    -0x28(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <do_phone_number_letters>
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L60
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L60
  addl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0x2,-0x4(%rbp)
  jle    L31
  jmp    L38
L60:
  nop
L38:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
data_type: string

tool: D1: %s


assistant: ```c
void do_phone_number_letters(char *number, int len, char *buffer) {
  if (*buffer == '\0') {
    printf("%s\n", buffer - len);
    return;
  }
  for (int i = 0; i < 3; i++) {
    buffer[0] = get_char_key(number[0] - '0', i);
    do_phone_number_letters(number + 1, len, buffer + 1);
    if (number[0] == '0' || number[0] == '1') {
      return;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_phone_number_letters>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    $0x0,%ebx
  lea    0x1(%rdx),%r14
  cmpb   $0x0,(%rdx)
  jne    L37
  movslq %esi,%r13
  mov    %rdx,%rsi
  sub    %r13,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  add    $0x1,%ebx
  cmp    $0x3,%ebx
  je     L19
L37:
  movzbl (%r12),%eax
  lea    -0x30(%rax),%edi
  movsbl %dil,%edi
  mov    %ebx,%esi
  call   <get_char_key@plt>
  mov    %al,0x0(%rbp)
  lea    0x1(%r12),%rdi
  mov    %r14,%rdx
  mov    %r13d,%esi
  call   <do_phone_number_letters>
  movzbl (%r12),%eax
  sub    $0x30,%eax
  cmp    $0x1,%al
  ja     L24
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: %s


assistant: ```c
void do_phone_number_letters(char *number, int len, char *buffer) {
  if (*buffer == '\0') {
    printf("%s\n", buffer - len);
    return;
  }
  for (int i = 0; i < 3; i++) {
    buffer[0] = get_char_key(number[0] - '0', i);
    do_phone_number_letters(number + 1, len, buffer + 1);
    if (number[0] == '0' || number[0] == '1') {
      return;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_phone_number_letters>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdx)
  je     L21
  mov    %rdi,%r15
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%r12
  xor    %r13d,%r13d
  lea    0x1(%r15),%rbp
L20:
  sub    $0x30,%edi
  mov    %r13d,%esi
  movsbl %dil,%edi
  call   <get_char_key@plt>
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %al,(%r14)
  call   <do_phone_number_letters>
  movzbl (%r15),%edi
  lea    -0x30(%rdi),%eax
  cmp    $0x1,%al
  jbe    L25
  add    $0x1,%r13d
  cmp    $0x3,%r13d
  jne    L20
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  add    $0x8,%rsp
  mov    %rdx,%rsi
  lea    D1(%rip),%rdi
  sub    %rbx,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: %s


assistant: ```c
void do_phone_number_letters(char *number, int len, char *buffer) {
  if (*buffer == '\0') {
    printf("%s\n", buffer - len);
    return;
  }
  for (int i = 0; i < 3; i++) {
    buffer[0] = get_char_key(number[0] - '0', i);
    do_phone_number_letters(number + 1, len, buffer + 1);
    if (number[0] == '0' || number[0] == '1') {
      return;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0xa,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  lea    0x38(%rsp),%r12
  mov    %rbx,%rbp
  lea    D32(%rip),%r13
L19:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L19
  lea    D65(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rbp
  lea    D26(%rip),%r13
L0:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%esi
L17:
  add    (%rbx),%esi
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  divss  D17(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  subss  D57(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D74(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D32
type: string
name: parse_data
arguments: data_tag: D65
type: string
name: parse_data
arguments: data_tag: D26
type: string
name: parse_data
arguments: data_tag: D17
type: byte[4]
name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D57
type: byte[4]
name: parse_data
arguments: data_tag: D74
type: string

tool: D5: Enter %d golf scores: 


tool: D32: %d

tool: D65: The scores read in are as follows: 

tool: D26: %5d

tool: {"D17": [0x00,0x00,0x20,0x41]}

tool: D3: Sum of scores = %d, average = %.2f


tool: {"D57": [0x00,0x00,0x90,0x42]}

tool: D74: That's a handicap of %.0f.


assistant: ```c
int main(void) {
  int index, score[10];
  int sum = 0;
  float average;
  printf("Enter %d golf scores: \n", 10);
  for (index = 0; index < 10; index++)
    scanf("%d", &score[index]);
  printf("The scores read in are as follows: \n");
  for (index = 0; index < 10; index++)
    printf("%5d", score[index]);
  printf("\n");
  for (index = 0; index < 10; index++)
    sum += score[index];
  average = (float)sum / 10;
  printf("Sum of scores = %d, average = %.2f\n", sum, average);
  printf("That's a handicap of %.0f.\n", average - 72);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%esi
  lea    D62(%rip),%rdi
  lea    D68(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x38(%rsp),%r12
  mov    %rbx,%rbp
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L14
  lea    D36(%rip),%rdi
  mov    %rbx,%rbp
  lea    D4(%rip),%r13
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L0:
  add    (%rbx),%esi
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
  lea    D74(%rip),%rdi
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtsi2ss %esi,%xmm1
  divss  D16(%rip),%xmm1
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  subss  D1(%rip),%xmm1
  lea    D29(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D62
type: string
name: disassemble_data
arguments: label: D68
type: string
name: disassemble_data
arguments: label: D36
type: string
name: disassemble_data
arguments: label: D4
type: string
name: disassemble_data
arguments: label: D74
type: string
name: disassemble_data
arguments: label: D16
type: byte[4]
name: disassemble_data
arguments: label: D1
type: byte[4]
name: disassemble_data
arguments: label: D29
type: string

tool: D62: Enter %d golf scores: 


tool: D68: %d

tool: D36: The scores read in are as follows: 

tool: D4: %5d

tool: D74: Sum of scores = %d, average = %.2f


tool: {"D16": [0x00,0x00,0x20,0x41]}

tool: {"D1": [0x00,0x00,0x90,0x42]}

tool: D29: That's a handicap of %.0f.


assistant: ```c
int main(void) {
  int index, score[10];
  int sum = 0;
  float average;
  printf("Enter %d golf scores: \n", 10);
  for (index = 0; index < 10; index++)
    scanf("%d", &score[index]);
  printf("The scores read in are as follows: \n");
  for (index = 0; index < 10; index++)
    printf("%5d", score[index]);
  printf("\n");
  for (index = 0; index < 10; index++)
    sum += score[index];
  average = (float)sum / 10;
  printf("Sum of scores = %d, average = %.2f\n", sum, average);
  printf("That's a handicap of %.0f.\n", average - 72);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%esi
  lea    D6(%rip),%rdi
  lea    D48(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x38(%rsp),%r12
  mov    %rbx,%rbp
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L25
  lea    D29(%rip),%rdi
  lea    D39(%rip),%rbp
  call   <puts@plt>
  nop
L24:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L24
  mov    $0xa,%edi
  call   <putchar@plt>
  movdqa 0x10(%rsp),%xmm0
  mov    0x30(%rsp),%edx
  lea    D72(%rip),%rdi
  paddd  0x20(%rsp),%xmm0
  mov    0x34(%rsp),%eax
  movdqa %xmm0,%xmm1
  add    %edx,%eax
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  movd   %xmm0,%esi
  pxor   %xmm0,%xmm0
  add    %eax,%esi
  mov    $0x1,%eax
  cvtsi2ss %esi,%xmm1
  divss  D73(%rip),%xmm1
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  subss  D22(%rip),%xmm1
  lea    D52(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D48
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D39
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D72
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D73
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_tag: D52
type_infered: string

tool: D6: Enter %d golf scores: 


tool: D48: %d

tool: D29: The scores read in are as follows: 

tool: D39: %5d

tool: D72: Sum of scores = %d, average = %.2f


tool: {"D73": [0x00,0x00,0x20,0x41]}

tool: {"D22": [0x00,0x00,0x90,0x42]}

tool: D52: That's a handicap of %.0f.


assistant: ```c
int main(void) {
  int index, score[10];
  int sum = 0;
  float average;
  printf("Enter %d golf scores: \n", 10);
  for (index = 0; index < 10; index++)
    scanf("%d", &score[index]);
  printf("The scores read in are as follows: \n");
  for (index = 0; index < 10; index++)
    printf("%5d", score[index]);
  printf("\n");
  for (index = 0; index < 10; index++)
    sum += score[index];
  average = (float)sum / 10;
  printf("Sum of scores = %d, average = %.2f\n", sum, average);
  printf("That's a handicap of %.0f.\n", average - 72);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_current>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *get_current(void) {
  struct task_struct *current;
  return current;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_current>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
struct task_struct *get_current(void) {
  struct task_struct *current;
  return current;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_current>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
struct task_struct *get_current(void) {
  struct task_struct *current;
  return current;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_current>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
struct task_struct *get_current(void) {
  struct task_struct *current;
  return current;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ishex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L60
  cmpb   $0x39,-0x4(%rbp)
  jg     L60
  mov    $0x1,%eax
  jmp    L4
L60:
  cmpb   $0x60,-0x4(%rbp)
  jle    L83
  cmpb   $0x66,-0x4(%rbp)
  jg     L83
  mov    $0x1,%eax
  jmp    L4
L83:
  cmpb   $0x40,-0x4(%rbp)
  jle    L19
  cmpb   $0x46,-0x4(%rbp)
  jg     L19
  mov    $0x1,%eax
  jmp    L4
L19:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int ishex(char c) {
  if ('0' <= c && c <= '9')
    return 1;
  if ('a' <= c && c <= 'f')
    return 1;
  if ('A' <= c && c <= 'F')
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ishex>:
  endbr64
  lea    -0x30(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x9,%dl
  jbe    L5
  and    $0xffffffdf,%edi
  sub    $0x41,%edi
  cmp    $0x5,%dil
  setbe  %al
  movzbl %al,%eax
L5:
  ret
```

assistant: ```c
int ishex(char c) {
  if ('0' <= c && c <= '9')
    return 1;
  if ('a' <= c && c <= 'f')
    return 1;
  if ('A' <= c && c <= 'F')
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ishex>:
  endbr64
  lea    -0x30(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x9,%dl
  jbe    L3
  and    $0xffffffdf,%edi
  xor    %eax,%eax
  sub    $0x41,%edi
  cmp    $0x5,%dil
  setbe  %al
L3:
  ret
```

assistant: ```c
int ishex(char c) {
  if ('0' <= c && c <= '9')
    return 1;
  if ('a' <= c && c <= 'f')
    return 1;
  if ('A' <= c && c <= 'F')
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ishex>:
  endbr64
  lea    -0x30(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x9,%dl
  jbe    L4
  and    $0xffffffdf,%edi
  xor    %eax,%eax
  sub    $0x41,%edi
  cmp    $0x5,%dil
  setbe  %al
L4:
  ret
```

assistant: ```c
int ishex(char c) {
  if ('0' <= c && c <= '9')
    return 1;
  if ('a' <= c && c <= 'f')
    return 1;
  if ('A' <= c && c <= 'F')
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<R_Shutdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <TM_Shutdown@plt>
  mov    $0x0,%eax
  call   <GLimp_Shutdown@plt>
  mov    $0x0,%eax
  call   <OpenGL_Shutdown@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void R_Shutdown(void) {
  TM_Shutdown();
  GLimp_Shutdown();
  OpenGL_Shutdown();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<R_Shutdown>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <TM_Shutdown@plt>
  mov    $0x0,%eax
  call   <GLimp_Shutdown@plt>
  mov    $0x0,%eax
  call   <OpenGL_Shutdown@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void R_Shutdown(void) {
  TM_Shutdown();
  GLimp_Shutdown();
  OpenGL_Shutdown();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<R_Shutdown>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TM_Shutdown@plt>
  xor    %eax,%eax
  call   <GLimp_Shutdown@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <OpenGL_Shutdown@plt>
```

assistant: ```c
void R_Shutdown(void) {
  TM_Shutdown();
  GLimp_Shutdown();
  OpenGL_Shutdown();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<R_Shutdown>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TM_Shutdown@plt>
  xor    %eax,%eax
  call   <GLimp_Shutdown@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <OpenGL_Shutdown@plt>
```

assistant: ```c
void R_Shutdown(void) {
  TM_Shutdown();
  GLimp_Shutdown();
  OpenGL_Shutdown();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_strlowcase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L23
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L23
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L23:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strlowcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (65 <= str[i] && str[i] <= 90)
      str[i] = str[i] + 32;
    i++;
  }
  return (str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strlowcase>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L42
  mov    %rdi,%rcx
  jmp    L9
L41:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L42
L9:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L41
  add    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L41
L42:
  ret
```

assistant: ```c
char *ft_strlowcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (65 <= str[i] && str[i] <= 90)
      str[i] = str[i] + 32;
    i++;
  }
  return (str);
}
```