ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<ga_covar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ga_mean@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ga_mean@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L26:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  movss  -0xc(%rbp),%xmm0
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L26
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  js     L36
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L9
L36:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L9:
  movss  -0x14(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  leave
  ret
```

assistant: ```c
float ga_covar(float arr1[], float arr2[], unsigned long n) {
  unsigned long i;
  float dev = 0.0, ave1, ave2;
  ave1 = ga_mean(arr1, n);
  ave2 = ga_mean(arr2, n);
  for (i = 0; i < n; i++) {
    dev += (ave1 - arr1[i]) * (ave2 - arr2[i]);
  }
  return dev / n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ga_covar>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  call   <ga_mean@plt>
  movss  %xmm0,0xc(%rsp)
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <ga_mean@plt>
  test   %rbx,%rbx
  je     L29
  movaps %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  mov    $0x0,%eax
L2:
  movss  0xc(%rsp),%xmm1
  subss  0x0(%rbp,%rax,4),%xmm1
  movaps %xmm3,%xmm2
  subss  (%r12,%rax,4),%xmm2
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L2
L7:
  test   %rbx,%rbx
  js     L40
  pxor   %xmm1,%xmm1
  cvtsi2ss %rbx,%xmm1
L24:
  divss  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  pxor   %xmm0,%xmm0
  jmp    L7
L40:
  mov    %rbx,%rax
  shr    %rax
  and    $0x1,%ebx
  or     %rbx,%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm1
  jmp    L24
```

assistant: ```c
float ga_covar(float arr1[], float arr2[], unsigned long n) {
  unsigned long i;
  float dev = 0.0, ave1, ave2;
  ave1 = ga_mean(arr1, n);
  ave2 = ga_mean(arr2, n);
  for (i = 0; i < n; i++) {
    dev += (ave1 - arr1[i]) * (ave2 - arr2[i]);
  }
  return dev / n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ga_covar>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  call   <ga_mean@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <ga_mean@plt>
  pxor   %xmm2,%xmm2
  test   %rbx,%rbx
  je     L19
  movss  0xc(%rsp),%xmm4
  xor    %eax,%eax
  nop
L18:
  movaps %xmm4,%xmm1
  movaps %xmm0,%xmm3
  subss  0x0(%rbp,%rax,4),%xmm1
  subss  (%r12,%rax,4),%xmm3
  add    $0x1,%rax
  mulss  %xmm3,%xmm1
  addss  %xmm1,%xmm2
  cmp    %rax,%rbx
  jne    L18
L19:
  pxor   %xmm0,%xmm0
  add    $0x10,%rsp
  cvtsi2ss %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  divss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float ga_covar(float arr1[], float arr2[], unsigned long n) {
  unsigned long i;
  float dev = 0.0, ave1, ave2;
  ave1 = ga_mean(arr1, n);
  ave2 = ga_mean(arr2, n);
  for (i = 0; i < n; i++) {
    dev += (ave1 - arr1[i]) * (ave2 - arr2[i]);
  }
  return dev / n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ga_covar>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x10,%rsp
  call   <ga_mean@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <ga_mean@plt>
  test   %r12,%r12
  je     L28
  lea    -0x1(%r12),%rax
  movss  0xc(%rsp),%xmm2
  movaps %xmm0,%xmm6
  cmp    $0x2,%rax
  jbe    L68
  mov    %r12,%rdx
  movaps %xmm2,%xmm5
  movaps %xmm0,%xmm4
  xor    %eax,%eax
  shr    $0x2,%rdx
  pxor   %xmm3,%xmm3
  shufps $0x0,%xmm5,%xmm5
  shufps $0x0,%xmm4,%xmm4
  shl    $0x4,%rdx
  xchg   %ax,%ax
L74:
  movups 0x0(%rbp,%rax,1),%xmm7
  movaps %xmm5,%xmm1
  movaps %xmm4,%xmm0
  subps  %xmm7,%xmm1
  movups (%rbx,%rax,1),%xmm7
  add    $0x10,%rax
  subps  %xmm7,%xmm0
  mulps  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  addss  %xmm3,%xmm0
  movaps %xmm1,%xmm3
  shufps $0x55,%xmm1,%xmm3
  addss  %xmm3,%xmm0
  movaps %xmm1,%xmm3
  unpckhps %xmm1,%xmm3
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm3,%xmm0
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  cmp    %rdx,%rax
  jne    L74
  mov    %r12,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%r12b
  je     L32
L5:
  mov    %r12,%rdx
  sub    %rax,%rdx
  cmp    $0x1,%rdx
  je     L44
  movq   0x0(%rbp,%rax,4),%xmm1
  movq   (%rbx,%rax,4),%xmm4
  movaps %xmm2,%xmm0
  mov    %rdx,%rcx
  shufps $0xe0,%xmm0,%xmm0
  and    $0xfffffffffffffffe,%rcx
  subps  %xmm1,%xmm0
  movaps %xmm6,%xmm1
  add    %rcx,%rax
  shufps $0xe0,%xmm1,%xmm1
  subps  %xmm4,%xmm1
  mulps  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  shufps $0xe5,%xmm0,%xmm0
  addss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm0,%xmm3
  cmp    %rcx,%rdx
  je     L32
L44:
  subss  0x0(%rbp,%rax,4),%xmm2
  subss  (%rbx,%rax,4),%xmm6
  movaps %xmm2,%xmm1
  mulss  %xmm6,%xmm1
  addss  %xmm1,%xmm3
L32:
  pxor   %xmm0,%xmm0
  add    $0x10,%rsp
  cvtsi2ss %r12,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  divss  %xmm0,%xmm3
  movaps %xmm3,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  pxor   %xmm3,%xmm3
  jmp    L32
L68:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
float ga_covar(float arr1[], float arr2[], unsigned long n) {
  unsigned long i;
  float dev = 0.0, ave1, ave2;
  ave1 = ga_mean(arr1, n);
  ave2 = ga_mean(arr2, n);
  for (i = 0; i < n; i++) {
    dev += (ave1 - arr1[i]) * (ave2 - arr2[i]);
  }
  return dev / n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fz_colordodge_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xfe,-0x8(%rbp)
  jg     L18
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x8,%eax
  sub    %edx,%eax
  mov    $0xff,%edx
  mov    %edx,%ecx
  sub    -0x8(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    $0xff,%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  jmp    L3
L18:
  mov    $0xff,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int fz_colordodge_byte(int bd, int s) {
  if (s < 255)
    return ((255) < (255 * bd / (255 - s)) ? (255) : (255 * bd / (255 - s)));
  else
    return 255;
}
```
user: What is the c source code of the assembly code below:

```asm
<fz_colordodge_byte>:
  endbr64
  mov    $0xff,%eax
  cmp    $0xfe,%esi
  jg     L5
  mov    %edi,%eax
  shl    $0x8,%eax
  sub    %edi,%eax
  mov    $0xff,%ecx
  sub    %esi,%ecx
  cltd
  idiv   %ecx
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L5:
  ret
```

assistant: ```c
int fz_colordodge_byte(int bd, int s) {
  if (s < 255)
    return ((255) < (255 * bd / (255 - s)) ? (255) : (255 * bd / (255 - s)));
  else
    return 255;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fz_colordodge_byte>:
  endbr64
  mov    $0xff,%r8d
  cmp    $0xfe,%esi
  jg     L9
  mov    %edi,%eax
  sub    %esi,%r8d
  shl    $0x8,%eax
  sub    %edi,%eax
  cltd
  idiv   %r8d
  mov    $0xff,%r8d
  cmp    %r8d,%eax
  cmovle %eax,%r8d
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fz_colordodge_byte(int bd, int s) {
  if (s < 255)
    return ((255) < (255 * bd / (255 - s)) ? (255) : (255 * bd / (255 - s)));
  else
    return 255;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fz_colordodge_byte>:
  endbr64
  mov    $0xff,%r8d
  cmp    $0xfe,%esi
  jg     L3
  mov    %edi,%eax
  sub    %esi,%r8d
  shl    $0x8,%eax
  sub    %edi,%eax
  cltd
  idiv   %r8d
  mov    $0xff,%r8d
  cmp    %r8d,%eax
  cmovle %eax,%r8d
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fz_colordodge_byte(int bd, int s) {
  if (s < 255)
    return ((255) < (255 * bd / (255 - s)) ? (255) : (255 * bd / (255 - s)));
  else
    return 255;
}
```
user: What is the c source code of the assembly code below:

```asm
<solcon_standard_drop_coordinate_by_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L13:
  cmp    %rdx,%rsp
  je     L28
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L13
L28:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L34
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L34:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L37
L44:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x38(%rbp)
L37:
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L44
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x92,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int solcon_standard_drop_coordinate_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(146, &nc, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solcon_standard_drop_coordinate_by_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%ecx
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L41:
  cmp    %rdx,%rsp
  je     L17
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L41
L17:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L35
  orq    $0x0,-0x8(%rsp,%rax,1)
L35:
  mov    %rsp,%rdi
  test   %ecx,%ecx
  jle    L7
  mov    %ecx,%ecx
  mov    $0x0,%eax
L22:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L22
L7:
  lea    -0x14(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x92,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  leave
  ret
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_standard_drop_coordinate_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(146, &nc, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solcon_standard_drop_coordinate_by_name>:
  endbr64
  push   %rbp
  movslq %edi,%rcx
  mov    %rcx,%rdx
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsp,%r8
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rcx,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rdi
  cmp    %r8,%rsp
  je     L22
L26:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L26
L22:
  and    $0xfff,%edi
  sub    %rdi,%rsp
  test   %rdi,%rdi
  jne    L60
L64:
  mov    %rsp,%r9
  test   %edx,%edx
  jle    L38
  xor    %eax,%eax
L12:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L12
L38:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %r9,%rdx
  mov    $0x92,%edi
  lea    -0x14(%rbp),%rsi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  orq    $0x0,-0x8(%rsp,%rdi,1)
  jmp    L64
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_standard_drop_coordinate_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(146, &nc, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  imul   $0xe10,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3c,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D29
data_type: string
name: disassemble_data
arguments: label: D3
data_type: string

tool: D23: Please type in seconds: 

tool: D29: %d

tool: D3: %d time, %d minutter, %d sekunder


assistant: ```c
int main(void) {
  int total_seconds;
  printf("Please type in seconds: ");
  scanf("%d", &total_seconds);
  int hours = total_seconds / 3600;
  int secs_reminder = total_seconds % 3600;
  int mins = secs_reminder / 60;
  int secs = secs_reminder % 60;
  printf("%d time, %d minutter, %d sekunder\n", hours, mins, secs);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rsi
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0xb,%esi
  mov    %eax,%edi
  sar    $0x1f,%edi
  mov    %esi,%ecx
  sub    %edi,%ecx
  imul   $0xe10,%ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  imul   $0x3c,%edx,%eax
  sub    %eax,%ecx
  sub    %edi,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
data_type: string
name: disassemble_data
arguments: label: D21
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string

tool: D19: Please type in seconds: 

tool: D21: %d

tool: D0: %d time, %d minutter, %d sekunder


assistant: ```c
int main(void) {
  int total_seconds;
  printf("Please type in seconds: ");
  scanf("%d", &total_seconds);
  int hours = total_seconds / 3600;
  int secs_reminder = total_seconds % 3600;
  int mins = secs_reminder / 60;
  int secs = secs_reminder % 60;
  printf("%d time, %d minutter, %d sekunder\n", hours, mins, secs);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  mov    %eax,%edi
  sar    $0x1f,%edi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0xb,%esi
  mov    %esi,%ecx
  sub    %edi,%esi
  sub    %edi,%ecx
  lea    D8(%rip),%rdi
  imul   $0xe10,%ecx,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  mov    %rdx,%rcx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x5,%edx
  sub    %eax,%edx
  imul   $0x3c,%edx,%eax
  sub    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D8
data_type: string

tool: D2: Please type in seconds: 

tool: D10: %d

tool: D8: %d time, %d minutter, %d sekunder


assistant: ```c
int main(void) {
  int total_seconds;
  printf("Please type in seconds: ");
  scanf("%d", &total_seconds);
  int hours = total_seconds / 3600;
  int secs_reminder = total_seconds % 3600;
  int mins = secs_reminder / 60;
  int secs = secs_reminder % 60;
  printf("%d time, %d minutter, %d sekunder\n", hours, mins, secs);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  mov    %eax,%edi
  sar    $0x1f,%edi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0xb,%esi
  mov    %esi,%ecx
  sub    %edi,%esi
  sub    %edi,%ecx
  lea    D15(%rip),%rdi
  imul   $0xe10,%ecx,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  mov    %rdx,%rcx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x5,%edx
  sub    %eax,%edx
  imul   $0x3c,%edx,%eax
  sub    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D1
type: string
name: disassemble_data
arguments: data_tag: D15
type: string

tool: D0: Please type in seconds: 

tool: D1: %d

tool: D15: %d time, %d minutter, %d sekunder


assistant: ```c
int main(void) {
  int total_seconds;
  printf("Please type in seconds: ");
  scanf("%d", &total_seconds);
  int hours = total_seconds / 3600;
  int secs_reminder = total_seconds % 3600;
  int mins = secs_reminder / 60;
  int secs = secs_reminder % 60;
  printf("%d time, %d minutter, %d sekunder\n", hours, mins, secs);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vertice_na_solucao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L29:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L22
  mov    $0x1,%eax
  jmp    L7
L22:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int vertice_na_solucao(int a[], int k, int vertice) {
  int i;
  for (i = 0; i < k; i++) {
    if (a[i] == vertice) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vertice_na_solucao>:
  endbr64
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rcx
L12:
  cmp    %edx,(%rax)
  je     L8
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L12
  mov    $0x0,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int vertice_na_solucao(int a[], int k, int vertice) {
  int i;
  for (i = 0; i < k; i++) {
    if (a[i] == vertice) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<vertice_na_solucao>:
  endbr64
  test   %esi,%esi
  jle    L27
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L27
L39:
  cmp    %edx,(%rdi)
  jne    L18
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int vertice_na_solucao(int a[], int k, int vertice) {
  int i;
  for (i = 0; i < k; i++) {
    if (a[i] == vertice) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vertice_na_solucao>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L17
L19:
  cmp    %edx,(%rdi)
  jne    L37
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int vertice_na_solucao(int a[], int k, int vertice) {
  int i;
  for (i = 0; i < k; i++) {
    if (a[i] == vertice) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<db_tid_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    $0x0,%eax
  call   <opt_dblog@plt>
  test   %eax,%eax
  jne    L0
  mov    $0x0,%eax
  jmp    L1
L0:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
extern int db_tid_log(char *op, char *date, char *time, char *name, char *cwd, char *result) {
  if (!opt_dblog())
    return 0;
  return 0;
}
```