user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%r12
  movl   $0x24,-0x50(%rbp)
  movl   $0x24,-0x4c(%rbp)
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x40(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L97:
  cmp    %rdx,%rsp
  je     L96
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L97
L96:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L28
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L28:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rsi
  mov    $0x0,%edi
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L15:
  cmp    %rdx,%rsp
  je     L68
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L15
L68:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L85
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L85:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <fill_roll_counts@plt>
  mov    -0x28(%rbp),%rax
  mov    $0x6,%edx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <fill_roll_counts@plt>
  movq   $0x0,-0x48(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L101
L104:
  movl   $0x0,-0x58(%rbp)
  mov    -0x5c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x54(%rbp)
  jmp    L56
L106:
  mov    -0x38(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,-0x58(%rbp)
  addl   $0x1,-0x54(%rbp)
L56:
  mov    -0x54(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  jl     L106
  mov    -0x28(%rbp),%rax
  mov    -0x5c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  imul   -0x58(%rbp),%eax
  cltq
  add    %rax,-0x48(%rbp)
  addl   $0x1,-0x5c(%rbp)
L101:
  mov    -0x5c(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L104
  mov    $0x9,%esi
  mov    $0x4,%edi
  call   <power@plt>
  mov    %rax,%rbx
  mov    $0x6,%esi
  mov    $0x6,%edi
  call   <power@plt>
  imul   %rbx,%rax
  mov    %rax,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x48(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x20(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    %r12,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9: %.7f


assistant: ```c
int main(void) {
  int max_roll_a = 9 * 4;
  int max_roll_b = 6 * 6;
  int roll_counts_a[max_roll_a];
  int roll_counts_b[max_roll_b];
  fill_roll_counts(roll_counts_a, 9, 4);
  fill_roll_counts(roll_counts_b, 6, 6);
  long winning_rolls = 0;
  ;
  for (int i = 0; i < max_roll_b; i++) {
    int sum = 0;
    for (int j = i + 1; j < max_roll_a; j++)
      sum += roll_counts_a[j];
    winning_rolls += roll_counts_b[i] * sum;
  }
  long all_rolls = power(4, 9) * power(6, 6);
  printf("%.7f\n", winning_rolls / (double)all_rolls);
  return 0;
}
```