ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<zipTryEncoding>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rsi),%eax
  cmp    $0x1e,%eax
  jbe    L25
L30:
  xor    %eax,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rdx,%rbp
  mov    %rsp,%rdx
  mov    %rcx,%rbx
  call   <string2ll@plt>
  test   %rax,%rax
  je     L30
  mov    D31(%rip),%rdx
  mov    (%rsp),%rax
  cmp    (%rdx),%rax
  jl     L47
  mov    D0(%rip),%rcx
  mov    $0xffffffc0,%edx
  cmp    (%rcx),%rax
  jle    L65
L47:
  mov    D35(%rip),%rcx
  mov    $0xffffffe0,%edx
  cmp    (%rcx),%rax
  jl     L65
  mov    D26(%rip),%rcx
  cmp    (%rcx),%rax
  mov    $0xffffffd0,%ecx
  cmovle %ecx,%edx
L65:
  mov    %dl,(%rbx)
  mov    %rax,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L12
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zipTryEncoding(unsigned char *entry, unsigned int entrylen, long long *v, unsigned char *encoding) {
  long long value;
  if (entrylen >= 32 || entrylen == 0)
    return 0;
  if (string2ll((char *)entry, entrylen, &value)) {
    if (value >= INT16_MIN && value <= INT16_MAX) {
      *encoding = (0xc0 | 0 << 4);
    } else if (value >= INT32_MIN && value <= INT32_MAX) {
      *encoding = (0xc0 | 1 << 4);
    } else {
      *encoding = (0xc0 | 2 << 4);
    }
    *v = value;
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nsfGet_4568>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x67,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t nsfGet_4568(uint16_t addr) {
  (void)addr;
  return 0x67;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nsfGet_4568>:
  endbr64
  mov    $0x67,%eax
  ret
```

assistant: ```c
uint8_t nsfGet_4568(uint16_t addr) {
  (void)addr;
  return 0x67;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nsfGet_4568>:
  endbr64
  mov    $0x67,%eax
  ret
```

assistant: ```c
uint8_t nsfGet_4568(uint16_t addr) {
  (void)addr;
  return 0x67;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nsfGet_4568>:
  endbr64
  mov    $0x67,%eax
  ret
```

assistant: ```c
uint8_t nsfGet_4568(uint16_t addr) {
  (void)addr;
  return 0x67;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<invalidFunctionArgBool_isupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  leave
  ret
```

assistant: ```c
bool invalidFunctionArgBool_isupper(bool b, int c) {
  (void)isupper(b);
  return isupper(c != 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<invalidFunctionArgBool_isupper>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  setne  %dil
  movzbl %dil,%edi
  call   <isupper@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool invalidFunctionArgBool_isupper(bool b, int c) {
  (void)isupper(b);
  return isupper(c != 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<invalidFunctionArgBool_isupper>:
  endbr64
  xor    %edi,%edi
  test   %esi,%esi
  setne  %dil
  jmp    1050 <isupper@plt>
```

assistant: ```c
bool invalidFunctionArgBool_isupper(bool b, int c) {
  (void)isupper(b);
  return isupper(c != 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<invalidFunctionArgBool_isupper>:
  endbr64
  xor    %edi,%edi
  test   %esi,%esi
  setne  %dil
  jmp    1050 <isupper@plt>
```

assistant: ```c
bool invalidFunctionArgBool_isupper(bool b, int c) {
  (void)isupper(b);
  return isupper(c != 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r14
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rdx,0x20(%rsp)
  mov    %rdx,%r13
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %rax,0x18(%rsp)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rax,(%rsp)
  test   %r15,%r15
  je     L62
  add    %r15,%r13
  mov    $0x0,%r12d
L45:
  mov    (%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  cmp    $0x1,%eax
  adc    $0x0,%r12
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L45
  test   %r12,%r12
  je     L62
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%rsp),%rbx
  sub    %rbx,%rax
  imul   %r12,%rax
  mov    0x18(%rsp),%rcx
  lea    0x1(%rcx,%rax,1),%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L20
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  lea    -0x1(%rbx),%rax
  mov    %rax,0x28(%rsp)
  jmp    L97
L62:
  mov    0x20(%rsp),%rdi
  call   <strdup@plt>
  mov    %rax,0x10(%rsp)
L20:
  mov    0x10(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r15,%rbx,1)
  add    $0x1,%rbx
L15:
  lea    (%rbx,%r12,1),%r14
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L17
  add    0x28(%rsp),%r13
  mov    %r14,%r12
L69:
  add    $0x1,%r13
  cmp    %r13,0x18(%rsp)
  jbe    L20
L97:
  mov    0x20(%rsp),%rax
  lea    (%rax,%r13,1),%rbx
  mov    (%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L40
  movzbl (%rbx),%eax
  mov    0x10(%rsp),%rcx
  mov    %al,(%rcx,%r12,1)
  lea    0x1(%r12),%r12
  jmp    L69
L40:
  mov    $0x0,%ebx
  mov    0x10(%rsp),%rax
  lea    (%rax,%r12,1),%r15
  jmp    L15
```

assistant: ```c
char *str_replace(char *search, char *replace, char *subject) {
  char *newstr;
  size_t oldlen, newlen, i, j, k, numreplacements, searchlen;
  newlen = oldlen = strlen(subject) + 1;
  searchlen = strlen(search);
  numreplacements = 0;
  for (i = 0; i < oldlen - 1; i++)
    if (!strncmp(subject + i, search, searchlen))
      numreplacements++;
  if (!numreplacements)
    return strdup(subject);
  newlen += (strlen(replace) * numreplacements) - (searchlen * numreplacements);
  newstr = calloc(1, newlen);
  if (!newstr)
    return NULL;
  for (i = 0, j = 0; i < oldlen - 1; i++) {
    if (!strncmp(subject + i, search, searchlen)) {
      for (k = 0; k < strlen(replace); k++)
        newstr[j++] = replace[k];
      i += searchlen - 1;
    } else
      newstr[j++] = subject[i];
  }
  return newstr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_replace>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %rdx,0x18(%rsp)
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,0x10(%rsp)
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L39
  add    %rbp,%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L68:
  mov    %r15,%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <strncmp@plt>
  cmp    $0x1,%eax
  adc    $0x0,%rbp
  add    $0x1,%r15
  cmp    %r12,%r15
  jne    L68
  test   %rbp,%rbp
  je     L39
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%rsi
  mov    $0x1,%edi
  sub    %r13,%rax
  imul   %rbp,%rax
  lea    0x1(%rsi,%rax,1),%rsi
  call   <calloc@plt>
  mov    %rax,0x20(%rsp)
  test   %rax,%rax
  je     L69
  lea    -0x1(%r13),%rax
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  mov    %rax,0x28(%rsp)
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L47:
  movzbl (%r15),%eax
  mov    0x20(%rsp),%rdx
  add    $0x1,%r12
  mov    %al,(%rdx,%rbp,1)
  add    $0x1,%rbp
  cmp    %r12,0x10(%rsp)
  jbe    L69
L64:
  mov    0x18(%rsp),%rax
  mov    %r13,%rdx
  mov    %r14,%rsi
  lea    (%rax,%r12,1),%r15
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L47
  mov    0x20(%rsp),%rax
  xor    %r15d,%r15d
  add    %rbp,%rax
  mov    %rax,0x8(%rsp)
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L32:
  movzbl (%rbx,%r15,1),%eax
  mov    0x8(%rsp),%rcx
  mov    %al,(%rcx,%r15,1)
  add    $0x1,%r15
L11:
  lea    (%r15,%rbp,1),%rax
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  call   <strlen@plt>
  cmp    %r15,%rax
  ja     L32
  add    0x28(%rsp),%r12
  mov    (%rsp),%rbp
  add    $0x1,%r12
  cmp    %r12,0x10(%rsp)
  ja     L64
L69:
  mov    0x20(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L39:
  mov    0x18(%rsp),%rdi
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <strdup@plt>
```

assistant: ```c
char *str_replace(char *search, char *replace, char *subject) {
  char *newstr;
  size_t oldlen, newlen, i, j, k, numreplacements, searchlen;
  newlen = oldlen = strlen(subject) + 1;
  searchlen = strlen(search);
  numreplacements = 0;
  for (i = 0; i < oldlen - 1; i++)
    if (!strncmp(subject + i, search, searchlen))
      numreplacements++;
  if (!numreplacements)
    return strdup(subject);
  newlen += (strlen(replace) * numreplacements) - (searchlen * numreplacements);
  newstr = calloc(1, newlen);
  if (!newstr)
    return NULL;
  for (i = 0, j = 0; i < oldlen - 1; i++) {
    if (!strncmp(subject + i, search, searchlen)) {
      for (k = 0; k < strlen(replace); k++)
        newstr[j++] = replace[k];
      i += searchlen - 1;
    } else
      newstr[j++] = subject[i];
  }
  return newstr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_replace>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %rdx,0x18(%rsp)
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,0x10(%rsp)
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L34
  add    %rbp,%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L79:
  mov    %r15,%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <strncmp@plt>
  cmp    $0x1,%eax
  adc    $0x0,%rbp
  add    $0x1,%r15
  cmp    %r12,%r15
  jne    L79
  test   %rbp,%rbp
  je     L34
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%rsi
  mov    $0x1,%edi
  sub    %r13,%rax
  imul   %rbp,%rax
  lea    0x1(%rsi,%rax,1),%rsi
  call   <calloc@plt>
  mov    %rax,0x20(%rsp)
  test   %rax,%rax
  je     L88
  lea    -0x1(%r13),%rax
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  mov    %rax,0x28(%rsp)
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%r15),%eax
  mov    0x20(%rsp),%rdx
  add    $0x1,%r12
  mov    %al,(%rdx,%rbp,1)
  add    $0x1,%rbp
  cmp    %r12,0x10(%rsp)
  jbe    L88
L53:
  mov    0x18(%rsp),%rax
  mov    %r13,%rdx
  mov    %r14,%rsi
  lea    (%rax,%r12,1),%r15
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L2
  mov    0x20(%rsp),%rax
  xor    %r15d,%r15d
  add    %rbp,%rax
  mov    %rax,0x8(%rsp)
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl (%rbx,%r15,1),%eax
  mov    0x8(%rsp),%rcx
  mov    %al,(%rcx,%r15,1)
  add    $0x1,%r15
L19:
  lea    (%r15,%rbp,1),%rax
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  call   <strlen@plt>
  cmp    %r15,%rax
  ja     L6
  add    0x28(%rsp),%r12
  mov    (%rsp),%rbp
  add    $0x1,%r12
  cmp    %r12,0x10(%rsp)
  ja     L53
L88:
  mov    0x20(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L34:
  mov    0x18(%rsp),%rdi
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <strdup@plt>
```

assistant: ```c
char *str_replace(char *search, char *replace, char *subject) {
  char *newstr;
  size_t oldlen, newlen, i, j, k, numreplacements, searchlen;
  newlen = oldlen = strlen(subject) + 1;
  searchlen = strlen(search);
  numreplacements = 0;
  for (i = 0; i < oldlen - 1; i++)
    if (!strncmp(subject + i, search, searchlen))
      numreplacements++;
  if (!numreplacements)
    return strdup(subject);
  newlen += (strlen(replace) * numreplacements) - (searchlen * numreplacements);
  newstr = calloc(1, newlen);
  if (!newstr)
    return NULL;
  for (i = 0, j = 0; i < oldlen - 1; i++) {
    if (!strncmp(subject + i, search, searchlen)) {
      for (k = 0; k < strlen(replace); k++)
        newstr[j++] = replace[k];
      i += searchlen - 1;
    } else
      newstr[j++] = subject[i];
  }
  return newstr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CharCountArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x100,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L13:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *CharCountArray(char *str) {
  int i;
  int *count;
  count = (int *)calloc(sizeof(int), 256);
  for (i = 0; *(str + i); i++) {
    count[*(str + i)]++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CharCountArray>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L4
  lea    0x1(%rbx),%rdi
L6:
  movsbq %dl,%rdx
  addl   $0x1,(%rax,%rdx,4)
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L6
L4:
  pop    %rbx
  ret
```

assistant: ```c
int *CharCountArray(char *str) {
  int i;
  int *count;
  count = (int *)calloc(sizeof(int), 256);
  for (i = 0; *(str + i); i++) {
    count[*(str + i)]++;
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CharCountArray>:
  endbr64
  push   %rbx
  mov    $0x100,%esi
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <calloc@plt>
  movsbq (%rbx),%rdx
  test   %dl,%dl
  je     L5
  lea    0x1(%rbx),%rdi
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rdi
  addl   $0x1,(%rax,%rdx,4)
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  jne    L10
L5:
  pop    %rbx
  ret
```

assistant: ```c
int *CharCountArray(char *str) {
  int i;
  int *count;
  count = (int *)calloc(sizeof(int), 256);
  for (i = 0; *(str + i); i++) {
    count[*(str + i)]++;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CharCountArray>:
  endbr64
  push   %rbx
  mov    $0x100,%esi
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <calloc@plt>
  movsbq (%rbx),%rdx
  test   %dl,%dl
  je     L17
  lea    0x1(%rbx),%rdi
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rdi
  addl   $0x1,(%rax,%rdx,4)
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  jne    L2
L17:
  pop    %rbx
  ret
```

assistant: ```c
int *CharCountArray(char *str) {
  int i;
  int *count;
  count = (int *)calloc(sizeof(int), 256);
  for (i = 0; *(str + i); i++) {
    count[*(str + i)]++;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fdp1_allocation_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fdp1_pool_allocation_test@plt>
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fdp1_allocation_tests(struct fdp1_context *fdp1) {
  unsigned int fail = 0;
  fail += fdp1_pool_allocation_test(fdp1);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fdp1_allocation_tests>:
  endbr64
  sub    $0x8,%rsp
  call   <fdp1_pool_allocation_test@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fdp1_allocation_tests(struct fdp1_context *fdp1) {
  unsigned int fail = 0;
  fail += fdp1_pool_allocation_test(fdp1);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<fdp1_allocation_tests>:
  endbr64
  sub    $0x8,%rsp
  call   <fdp1_pool_allocation_test@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fdp1_allocation_tests(struct fdp1_context *fdp1) {
  unsigned int fail = 0;
  fail += fdp1_pool_allocation_test(fdp1);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fdp1_allocation_tests>:
  endbr64
  sub    $0x8,%rsp
  call   <fdp1_pool_allocation_test@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fdp1_allocation_tests(struct fdp1_context *fdp1) {
  unsigned int fail = 0;
  fail += fdp1_pool_allocation_test(fdp1);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hexdump_helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L50
L9:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L21
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L21
L15:
  cmpl   $0x8,-0xc(%rbp)
  jne    L21
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L50:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L9
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D11
type_infered: string

tool: D2: %02X 

tool: D11: - 

assistant: ```c
int hexdump_helper(void *ptr, int len, int format_offset) {
  int i, newlined = 0, format_val;
  char *data = (char *)ptr;
  for (i = 0, format_val = format_offset; i < len; i++, format_val++) {
    printf("%02X ", (unsigned char)data[i]);
    newlined = 0;
    if (format_val > 0) {
      int mod = format_val % (16);
      if (mod == 0) {
        printf("\n");
        newlined = 1;
      } else if (mod == (16) / 2) {
        printf("- ");
      }
    }
  }
  return format_val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hexdump_helper>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  test   %esi,%esi
  jle    L34
  mov    %rdi,%rbp
  lea    (%rdx,%rsi,1),%r12d
  lea    D6(%rip),%r13
  lea    D17(%rip),%r14
  jmp    L31
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
L9:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  je     L34
L31:
  movzbl 0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L9
  test   $0xf,%bl
  je     L27
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cmp    $0x8,%eax
  jne    L9
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L34:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string
name: read_data
arguments: label: D17
type_guessed: string

tool: D6: %02X 

tool: D17: - 

assistant: ```c
int hexdump_helper(void *ptr, int len, int format_offset) {
  int i, newlined = 0, format_val;
  char *data = (char *)ptr;
  for (i = 0, format_val = format_offset; i < len; i++, format_val++) {
    printf("%02X ", (unsigned char)data[i]);
    newlined = 0;
    if (format_val > 0) {
      int mod = format_val % (16);
      if (mod == 0) {
        printf("\n");
        newlined = 1;
      } else if (mod == (16) / 2) {
        printf("- ");
      }
    }
  }
  return format_val;
}
```
user: What is the c source code of the assembly code below?

```asm
<hexdump_helper>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  test   %esi,%esi
  jle    L59
  mov    %rdi,%rbp
  lea    (%rdx,%rsi,1),%r12d
  lea    D16(%rip),%r13
  lea    D8(%rip),%r14
  jmp    L27
  nopl   0x0(%rax)
L4:
  cmp    $0x8,%eax
  je     L75
L61:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  je     L16
L27:
  movzbl 0x0(%rbp),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L61
  mov    %ebx,%eax
  and    $0xf,%eax
  jne    L4
  mov    $0xa,%edi
  add    $0x1,%ebx
  add    $0x1,%rbp
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L27
L16:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L75:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L61
  nopl   0x0(%rax)
L59:
  mov    %edx,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D16: %02X 

tool: D8: - 

assistant: ```c
int hexdump_helper(void *ptr, int len, int format_offset) {
  int i, newlined = 0, format_val;
  char *data = (char *)ptr;
  for (i = 0, format_val = format_offset; i < len; i++, format_val++) {
    printf("%02X ", (unsigned char)data[i]);
    newlined = 0;
    if (format_val > 0) {
      int mod = format_val % (16);
      if (mod == 0) {
        printf("\n");
        newlined = 1;
      } else if (mod == (16) / 2) {
        printf("- ");
      }
    }
  }
  return format_val;
}
```