ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<primeFactors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L45
L4:
  addq   $0x2,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  shr    %rax
  mov    %rax,-0x18(%rbp)
L45:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L4
  movl   $0x3,-0xc(%rbp)
  jmp    L26
L13:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x18(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  je     L13
  addl   $0x2,-0xc(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  cmp    %eax,-0xc(%rbp)
  jle    L28
  cmpq   $0x2,-0x18(%rbp)
  jbe    L42
  mov    -0x18(%rbp),%rax
  add    %rax,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long primeFactors(unsigned long long n) {
  unsigned long long sum = 0;
  int i = 0;
  while (n % 2 == 0) {
    sum += 2;
    n = n / 2;
  }
  for (i = 3; i <= sqrt(n); i = i + 2) {
    while (n % i == 0) {
      sum += i;
      n = n / i;
    }
  }
  if (n > 2)
    sum += n;
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<primeFactors>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%r12
  and    $0x1,%r12d
  jne    L7
L17:
  add    $0x2,%r12
  mov    %rbx,%rax
  shr    %rax
  mov    %rax,%rbx
  test   $0x1,%al
  je     L17
L41:
  mov    $0x3,%ebp
  jmp    L10
L7:
  mov    $0x0,%r12d
  jmp    L41
L46:
  add    %rbp,%r12
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rbp
  mov    %rax,%rbx
  mov    $0x0,%edx
  div    %rbp
  test   %rdx,%rdx
  je     L46
L29:
  add    $0x2,%rbp
L10:
  mov    %rbx,%rdi
  call   <sqrt@plt>
  cmp    %ebp,%eax
  jl     L44
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rbp
  test   %rdx,%rdx
  je     L46
  jmp    L29
L44:
  lea    (%r12,%rbx,1),%rax
  cmp    $0x2,%rbx
  cmova  %rax,%r12
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long primeFactors(unsigned long long n) {
  unsigned long long sum = 0;
  int i = 0;
  while (n % 2 == 0) {
    sum += 2;
    n = n / 2;
  }
  for (i = 3; i <= sqrt(n); i = i + 2) {
    while (n % i == 0) {
      sum += i;
      n = n / i;
    }
  }
  if (n > 2)
    sum += n;
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<primeFactors>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  and    $0x1,%r13d
  jne    L15
  nopl   (%rax)
L30:
  shr    %r12
  add    $0x2,%r13
  test   $0x1,%r12b
  je     L30
L29:
  mov    %r12,%rdi
  mov    $0x3,%ebx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L45
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbx
  test   %rdx,%rdx
  jne    L2
  nopl   (%rax)
L68:
  mov    %r12,%rax
  xor    %edx,%edx
  add    %rbx,%r13
  div    %rbx
  xor    %edx,%edx
  mov    %rax,%r12
  div    %rbx
  test   %rdx,%rdx
  je     L68
L2:
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L9
L45:
  lea    0x0(%r13,%r12,1),%rax
  cmp    $0x2,%r12
  pop    %rbx
  pop    %r12
  cmova  %rax,%r13
  mov    %r13,%rax
  pop    %r13
  ret
L15:
  xor    %r13d,%r13d
  jmp    L29
```

assistant: ```c
unsigned long long primeFactors(unsigned long long n) {
  unsigned long long sum = 0;
  int i = 0;
  while (n % 2 == 0) {
    sum += 2;
    n = n / 2;
  }
  for (i = 3; i <= sqrt(n); i = i + 2) {
    while (n % i == 0) {
      sum += i;
      n = n / i;
    }
  }
  if (n > 2)
    sum += n;
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<primeFactors>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  and    $0x1,%r13d
  jne    L6
  nopl   (%rax)
L32:
  shr    %r12
  add    $0x2,%r13
  test   $0x1,%r12b
  je     L32
L18:
  mov    %r12,%rdi
  mov    $0x3,%ebx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L47
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbx
  test   %rdx,%rdx
  jne    L62
  nopl   (%rax)
L26:
  mov    %r12,%rax
  xor    %edx,%edx
  add    %rbx,%r13
  div    %rbx
  xor    %edx,%edx
  mov    %rax,%r12
  div    %rbx
  test   %rdx,%rdx
  je     L26
L62:
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L0
L47:
  lea    0x0(%r13,%r12,1),%rax
  cmp    $0x2,%r12
  pop    %rbx
  pop    %r12
  cmova  %rax,%r13
  mov    %r13,%rax
  pop    %r13
  ret
L6:
  xor    %r13d,%r13d
  jmp    L18
```

assistant: ```c
unsigned long long primeFactors(unsigned long long n) {
  unsigned long long sum = 0;
  int i = 0;
  while (n % 2 == 0) {
    sum += 2;
    n = n / 2;
  }
  for (i = 3; i <= sqrt(n); i = i + 2) {
    while (n % i == 0) {
      sum += i;
      n = n / i;
    }
  }
  if (n > 2)
    sum += n;
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pl_endswith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L50
  cmpq   $0x0,-0x30(%rbp)
  je     L50
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L72
  cmpl   $0x0,-0xc(%rbp)
  je     L72
  mov    -0x10(%rbp),%eax
  cltq
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L8
  movl   $0x1,-0x14(%rbp)
  jmp    L11
L8:
  movl   $0x0,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  jmp    L5
L50:
  nop
  jmp    L35
L72:
  nop
L35:
  mov    -0x14(%rbp),%eax
L5:
  leave
  ret
```

assistant: ```c
int pl_endswith(char *string, char *postfix) {
  char *pch = NULL;
  int ret_val = -1;
  int string_length = 0, postfix_length = 0;
  if (string == NULL || postfix == NULL) {
    goto error_exit;
  }
  string_length = strlen(string);
  postfix_length = strlen(postfix);
  if (string_length == 0 || postfix_length == 0) {
    goto error_exit;
  }
  pch = string + string_length - postfix_length;
  if (!strcmp(pch, postfix)) {
    ret_val = 1;
  } else {
    ret_val = 0;
  }
  return ret_val;
error_exit:
  return ret_val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pl_endswith>:
  endbr64
  test   %rdi,%rdi
  je     L30
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0xffffffff,%eax
  test   %rsi,%rsi
  je     L15
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L5
  test   %eax,%eax
  je     L5
  movslq %r12d,%r12
  cltq
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0xffffffff,%eax
  jmp    L15
L30:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pl_endswith(char *string, char *postfix) {
  char *pch = NULL;
  int ret_val = -1;
  int string_length = 0, postfix_length = 0;
  if (string == NULL || postfix == NULL) {
    goto error_exit;
  }
  string_length = strlen(string);
  postfix_length = strlen(postfix);
  if (string_length == 0 || postfix_length == 0) {
    goto error_exit;
  }
  pch = string + string_length - postfix_length;
  if (!strcmp(pch, postfix)) {
    ret_val = 1;
  } else {
    ret_val = 0;
  }
  return ret_val;
error_exit:
  return ret_val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pl_endswith>:
  endbr64
  test   %rdi,%rdi
  je     L24
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %rsi,%rsi
  je     L25
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L25
  test   %eax,%eax
  je     L25
  cltq
  mov    %rbp,%rsi
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rdi
  call   <strcmp@plt>
  pop    %rbx
  pop    %rbp
  test   %eax,%eax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  ret
  nop
L25:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pl_endswith(char *string, char *postfix) {
  char *pch = NULL;
  int ret_val = -1;
  int string_length = 0, postfix_length = 0;
  if (string == NULL || postfix == NULL) {
    goto error_exit;
  }
  string_length = strlen(string);
  postfix_length = strlen(postfix);
  if (string_length == 0 || postfix_length == 0) {
    goto error_exit;
  }
  pch = string + string_length - postfix_length;
  if (!strcmp(pch, postfix)) {
    ret_val = 1;
  } else {
    ret_val = 0;
  }
  return ret_val;
error_exit:
  return ret_val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pl_endswith>:
  endbr64
  test   %rdi,%rdi
  je     L38
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %rsi,%rsi
  je     L10
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L10
  test   %eax,%eax
  je     L10
  cltq
  mov    %rbp,%rsi
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rdi
  call   <strcmp@plt>
  pop    %rbx
  pop    %rbp
  test   %eax,%eax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  ret
  nop
L10:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pl_endswith(char *string, char *postfix) {
  char *pch = NULL;
  int ret_val = -1;
  int string_length = 0, postfix_length = 0;
  if (string == NULL || postfix == NULL) {
    goto error_exit;
  }
  string_length = strlen(string);
  postfix_length = strlen(postfix);
  if (string_length == 0 || postfix_length == 0) {
    goto error_exit;
  }
  pch = string + string_length - postfix_length;
  if (!strcmp(pch, postfix)) {
    ret_val = 1;
  } else {
    ret_val = 0;
  }
  return ret_val;
error_exit:
  return ret_val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x1c(%rbp)
  movl   $0x258,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L47
  mov    $0xb9,%edi
  call   <exit@plt>
L47:
  mov    $0x0,%eax
  call   <show_alloc_mem@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L13
L46:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  mov    %rdx,(%rax)
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L65
  mov    $0xc5,%edi
  call   <exit@plt>
L65:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%esi
  mov    $0x1,%r8d
  mov    %edx,%ecx
  lea    D4(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    $0x0,%eax
  call   <show_alloc_mem@plt>
  addl   $0x1,-0x20(%rbp)
L13:
  mov    -0x20(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L46
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L7
L1:
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  mov    %rax,%rdi
  call   <ft_memdel@plt>
L7:
  mov    -0x20(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L1
  mov    $0x0,%eax
  call   <show_alloc_mem@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_memdel@plt>
  mov    $0x0,%eax
  call   <show_alloc_mem@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: %0*d

assistant: ```c
int test_max(void) {
  char **ptr;
  int i;
  int len;
  int min = 1;
  int max = 600;
  if (!(ptr = (char **)malloc(max * sizeof(char **)))) {
    exit(185);
  }
  show_alloc_mem();
  i = min;
  while (i < max) {
    len = i;
    if (!(ptr[i] = (char *)malloc(len))) {
      exit(197);
    }
    snprintf(ptr[i], len, "%0*d", len, 1);
    show_alloc_mem();
    ++i;
  }
  i = min;
  while (i < max) {
    ft_memdel((void **)&ptr[i++]);
  }
  show_alloc_mem();
  ft_memdel((void **)&ptr);
  show_alloc_mem();
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_max>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x12c0,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L7
L4:
  mov    $0x0,%eax
  call   <show_alloc_mem@plt>
  mov    $0x8,%ebp
  mov    $0x1,%ebx
  lea    D4(%rip),%r12
  jmp    L2
L7:
  mov    $0xb9,%edi
  call   <exit@plt>
  jmp    L4
L24:
  mov    (%rsp),%rax
  mov    (%rax,%rbp,1),%rdi
  mov    $0x1,%r8d
  mov    %ebx,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <snprintf@plt>
  mov    $0x0,%eax
  call   <show_alloc_mem@plt>
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    $0x258,%ebx
  je     L67
L2:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    (%rsp),%rdx
  mov    %rax,(%rdx,%rbp,1)
  test   %rax,%rax
  jne    L24
  mov    $0xc5,%edi
  call   <exit@plt>
  jmp    L24
L67:
  mov    $0x8,%ebx
L74:
  mov    %rbx,%rdi
  add    (%rsp),%rdi
  call   <ft_memdel@plt>
  add    $0x8,%rbx
  cmp    $0x12c0,%rbx
  jne    L74
  mov    $0x0,%eax
  call   <show_alloc_mem@plt>
  mov    %rsp,%rdi
  call   <ft_memdel@plt>
  mov    $0x0,%eax
  call   <show_alloc_mem@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: %0*d

assistant: ```c
int test_max(void) {
  char **ptr;
  int i;
  int len;
  int min = 1;
  int max = 600;
  if (!(ptr = (char **)malloc(max * sizeof(char **)))) {
    exit(185);
  }
  show_alloc_mem();
  i = min;
  while (i < max) {
    len = i;
    if (!(ptr[i] = (char *)malloc(len))) {
      exit(197);
    }
    snprintf(ptr[i], len, "%0*d", len, 1);
    show_alloc_mem();
    ++i;
  }
  i = min;
  while (i < max) {
    ft_memdel((void **)&ptr[i++]);
  }
  show_alloc_mem();
  ft_memdel((void **)&ptr);
  show_alloc_mem();
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_max>:
  endbr64
  push   %r12
  mov    $0x12c0,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L10
L67:
  xor    %eax,%eax
  mov    $0x8,%ebp
  mov    $0x1,%ebx
  call   <show_alloc_mem@plt>
  lea    D1(%rip),%r12
  jmp    L63
  nopl   (%rax)
L11:
  mov    %ebx,%ecx
  mov    %ebx,%esi
  mov    $0x1,%r8d
  mov    %r12,%rdx
  call   <snprintf@plt>
  add    $0x1,%ebx
  xor    %eax,%eax
  add    $0x8,%rbp
  call   <show_alloc_mem@plt>
  cmp    $0x258,%ebx
  je     L18
L63:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    (%rsp),%rax
  mov    %rdi,(%rax,%rbp,1)
  test   %rdi,%rdi
  jne    L11
  mov    $0xc5,%edi
  call   <exit@plt>
  mov    (%rsp),%rax
  mov    (%rax,%rbp,1),%rdi
  jmp    L11
L18:
  mov    $0x8,%ebx
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rsp),%rdi
  add    %rbx,%rdi
  add    $0x8,%rbx
  call   <ft_memdel@plt>
  cmp    $0x12c0,%rbx
  jne    L19
  xor    %eax,%eax
  call   <show_alloc_mem@plt>
  mov    %rsp,%rdi
  call   <ft_memdel@plt>
  xor    %eax,%eax
  call   <show_alloc_mem@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    $0xb9,%edi
  call   <exit@plt>
  jmp    L67
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D1: %0*d

assistant: ```c
int test_max(void) {
  char **ptr;
  int i;
  int len;
  int min = 1;
  int max = 600;
  if (!(ptr = (char **)malloc(max * sizeof(char **)))) {
    exit(185);
  }
  show_alloc_mem();
  i = min;
  while (i < max) {
    len = i;
    if (!(ptr[i] = (char *)malloc(len))) {
      exit(197);
    }
    snprintf(ptr[i], len, "%0*d", len, 1);
    show_alloc_mem();
    ++i;
  }
  i = min;
  while (i < max) {
    ft_memdel((void **)&ptr[i++]);
  }
  show_alloc_mem();
  ft_memdel((void **)&ptr);
  show_alloc_mem();
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_max>:
  endbr64
  push   %r12
  mov    $0x12c0,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L46
L32:
  xor    %eax,%eax
  mov    $0x8,%ebp
  mov    $0x1,%ebx
  call   <show_alloc_mem@plt>
  lea    D6(%rip),%r12
  jmp    L42
  nopl   (%rax)
L20:
  mov    %ebx,%ecx
  mov    %ebx,%esi
  mov    $0x1,%r8d
  mov    %r12,%rdx
  call   <snprintf@plt>
  add    $0x1,%ebx
  xor    %eax,%eax
  add    $0x8,%rbp
  call   <show_alloc_mem@plt>
  cmp    $0x258,%ebx
  je     L12
L42:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    (%rsp),%rax
  mov    %rdi,(%rax,%rbp,1)
  test   %rdi,%rdi
  jne    L20
  mov    $0xc5,%edi
  call   <exit@plt>
  mov    (%rsp),%rax
  mov    (%rax,%rbp,1),%rdi
  jmp    L20
L12:
  mov    $0x8,%ebx
  nopl   0x0(%rax,%rax,1)
L58:
  mov    (%rsp),%rdi
  add    %rbx,%rdi
  add    $0x8,%rbx
  call   <ft_memdel@plt>
  cmp    $0x12c0,%rbx
  jne    L58
  xor    %eax,%eax
  call   <show_alloc_mem@plt>
  mov    %rsp,%rdi
  call   <ft_memdel@plt>
  xor    %eax,%eax
  call   <show_alloc_mem@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  mov    $0xb9,%edi
  call   <exit@plt>
  jmp    L32
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %0*d

assistant: ```c
int test_max(void) {
  char **ptr;
  int i;
  int len;
  int min = 1;
  int max = 600;
  if (!(ptr = (char **)malloc(max * sizeof(char **)))) {
    exit(185);
  }
  show_alloc_mem();
  i = min;
  while (i < max) {
    len = i;
    if (!(ptr[i] = (char *)malloc(len))) {
      exit(197);
    }
    snprintf(ptr[i], len, "%0*d", len, 1);
    show_alloc_mem();
    ++i;
  }
  i = min;
  while (i < max) {
    ft_memdel((void **)&ptr[i++]);
  }
  show_alloc_mem();
  ft_memdel((void **)&ptr);
  show_alloc_mem();
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<expValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L30
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L4
L30:
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isNum@plt>
  test   %eax,%eax
  jne    L37
  mov    $0x0,%eax
  jmp    L23
L37:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <goNum@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L23:
  leave
  ret
```

assistant: ```c
char *expValue(char *ptr) {
  if (*ptr == '-' || *ptr == '+')
    ++ptr;
  if (!isNum(*ptr))
    return 0;
  ptr = goNum(++ptr);
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<expValue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%rbx
  movsbl (%rbx),%edi
  call   <isNum@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L1
  lea    0x1(%rbx),%rdi
  call   <goNum@plt>
L1:
  pop    %rbx
  ret
```

assistant: ```c
char *expValue(char *ptr) {
  if (*ptr == '-' || *ptr == '+')
    ++ptr;
  if (!isNum(*ptr))
    return 0;
  ptr = goNum(++ptr);
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expValue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L6
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L6:
  call   <isNum@plt>
  test   %eax,%eax
  je     L9
  lea    0x1(%rbx),%rdi
  pop    %rbx
  jmp    1060 <goNum@plt>
  nopl   (%rax)
L9:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *expValue(char *ptr) {
  if (*ptr == '-' || *ptr == '+')
    ++ptr;
  if (!isNum(*ptr))
    return 0;
  ptr = goNum(++ptr);
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<expValue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L3
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L3:
  call   <isNum@plt>
  test   %eax,%eax
  je     L18
  lea    0x1(%rbx),%rdi
  pop    %rbx
  jmp    1060 <goNum@plt>
  nopl   (%rax)
L18:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *expValue(char *ptr) {
  if (*ptr == '-' || *ptr == '+')
    ++ptr;
  if (!isNum(*ptr))
    return 0;
  ptr = goNum(++ptr);
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<copiar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L4:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copiar(int *origen, int *destino, unsigned int tope) {
  unsigned int i;
  for (i = 0; i < tope; i++) {
    destino[i] = origen[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copiar>:
  endbr64
  test   %edx,%edx
  je     L17
  mov    %edx,%edx
  mov    $0x0,%eax
L15:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L15
L17:
  ret
```

assistant: ```c
void copiar(int *origen, int *destino, unsigned int tope) {
  unsigned int i;
  for (i = 0; i < tope; i++) {
    destino[i] = origen[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copiar>:
  endbr64
  test   %edx,%edx
  je     L1
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L9:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
L1:
  ret
```

assistant: ```c
void copiar(int *origen, int *destino, unsigned int tope) {
  unsigned int i;
  for (i = 0; i < tope; i++) {
    destino[i] = origen[i];
  }
}
```