ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<make_class_name>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <kobject_name@plt>
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%edi
  xor    %r12d,%r12d
  call   <mallocnull@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%r12
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <kobject_name@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <strcat@plt>
L2:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: :

assistant: ```c
char *make_class_name(char const *name, struct kobject *kobj) {
  char *class_name;
  int size;
  unsigned long tmp;
  char const *tmp___0;
  unsigned long tmp___1;
  char const *tmp___2;
  tmp = strlen(name);
  tmp___0 = kobject_name((struct kobject const *)kobj);
  tmp___1 = strlen(tmp___0);
  size = (int)((tmp + tmp___1) + 2UL);
  class_name = (char *)mallocnull(size);
  if (!class_name) {
    return ((char *)((void *)0));
  }
  strcpy(class_name, name);
  strcat(class_name, ":");
  tmp___2 = kobject_name((struct kobject const *)kobj);
  strcat(class_name, tmp___2);
  return (class_name);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<make_class_name>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <kobject_name@plt>
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%edi
  xor    %r12d,%r12d
  call   <mallocnull@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%r12
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <kobject_name@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <strcat@plt>
L6:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D5: :

assistant: ```c
char *make_class_name(char const *name, struct kobject *kobj) {
  char *class_name;
  int size;
  unsigned long tmp;
  char const *tmp___0;
  unsigned long tmp___1;
  char const *tmp___2;
  tmp = strlen(name);
  tmp___0 = kobject_name((struct kobject const *)kobj);
  tmp___1 = strlen(tmp___0);
  size = (int)((tmp + tmp___1) + 2UL);
  class_name = (char *)mallocnull(size);
  if (!class_name) {
    return ((char *)((void *)0));
  }
  strcpy(class_name, name);
  strcat(class_name, ":");
  tmp___2 = kobject_name((struct kobject const *)kobj);
  strcat(class_name, tmp___2);
  return (class_name);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L33:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L0
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L0
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L33
L0:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int lcp(int *a, int N, int x, int y) {
  int l = 0;
  while (x + l < N && y + l < N && a[x + l] == a[y + l]) {
    l++;
  }
  return l;
}
```
user: What is the c source code of the assembly code below?

```asm
<lcp>:
  endbr64
  cmp    %esi,%edx
  jge    L31
  cmp    %ecx,%esi
  jle    L16
  movslq %edx,%r9
  lea    (%rdi,%r9,4),%rdi
  mov    %esi,%r8d
  sub    %ecx,%r8d
  sub    %edx,%esi
  mov    $0x0,%eax
  movslq %ecx,%rcx
  sub    %r9,%rcx
L42:
  mov    (%rdi,%rcx,4),%edx
  cmp    %edx,(%rdi)
  jne    L4
  add    $0x1,%eax
  cmp    %esi,%eax
  je     L33
  add    $0x4,%rdi
  cmp    %r8d,%eax
  jne    L42
  mov    %r8d,%eax
  ret
L4:
  ret
L31:
  mov    $0x0,%eax
  ret
L16:
  mov    $0x0,%eax
  ret
L33:
  mov    %esi,%eax
  ret
```

assistant: ```c
int lcp(int *a, int N, int x, int y) {
  int l = 0;
  while (x + l < N && y + l < N && a[x + l] == a[y + l]) {
    l++;
  }
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lcp>:
  endbr64
  cmp    %esi,%edx
  jge    L15
  cmp    %ecx,%esi
  jle    L15
  mov    %esi,%r8d
  movslq %edx,%r9
  sub    %edx,%esi
  xor    %eax,%eax
  sub    %ecx,%r8d
  movslq %ecx,%rcx
  lea    (%rdi,%r9,4),%rdi
  sub    %r9,%rcx
  jmp    L43
  nopl   (%rax)
L56:
  add    $0x1,%eax
  cmp    %esi,%eax
  je     L5
  add    $0x4,%rdi
  cmp    %r8d,%eax
  je     L5
L43:
  mov    (%rdi,%rcx,4),%edx
  cmp    %edx,(%rdi)
  je     L56
  ret
L15:
  xor    %eax,%eax
L5:
  ret
```

assistant: ```c
int lcp(int *a, int N, int x, int y) {
  int l = 0;
  while (x + l < N && y + l < N && a[x + l] == a[y + l]) {
    l++;
  }
  return l;
}
```
user: What is the c source code of the assembly code below?

```asm
<lcp>:
  endbr64
  cmp    %esi,%edx
  jge    L57
  cmp    %ecx,%esi
  jle    L57
  mov    %esi,%r8d
  movslq %edx,%r9
  sub    %edx,%esi
  xor    %eax,%eax
  sub    %ecx,%r8d
  movslq %ecx,%rcx
  lea    (%rdi,%r9,4),%rdi
  sub    %r9,%rcx
  jmp    L14
  nopl   (%rax)
L33:
  add    $0x1,%eax
  cmp    %esi,%eax
  je     L0
  add    $0x4,%rdi
  cmp    %r8d,%eax
  je     L0
L14:
  mov    (%rdi,%rcx,4),%edx
  cmp    %edx,(%rdi)
  je     L33
  ret
L57:
  xor    %eax,%eax
L0:
  ret
```

assistant: ```c
int lcp(int *a, int N, int x, int y) {
  int l = 0;
  while (x + l < N && y + l < N && a[x + l] == a[y + l]) {
    l++;
  }
  return l;
}
```
user: What is the c source code of the assembly code below:

```asm
<upb_encode_varint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x7f,-0x14(%rbp)
  jg     L42
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x1,%eax
  jmp    L32
L42:
  movq   $0x0,-0x8(%rbp)
  jmp    L47
L25:
  mov    -0x14(%rbp),%eax
  and    $0x7f,%eax
  mov    %eax,-0xc(%rbp)
  sarl   $0x7,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L31
  mov    -0xc(%rbp),%eax
  or     $0x80,%al
  mov    %eax,-0xc(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L47:
  cmpl   $0x0,-0x14(%rbp)
  jne    L25
  mov    -0x8(%rbp),%rax
L32:
  pop    %rbp
  ret
```

assistant: ```c
size_t upb_encode_varint(uint64_t val, char *buf) {
  size_t i;
  if (val < 128) {
    buf[0] = val;
    return 1;
  }
  i = 0;
  while (val) {
    uint8_t byte = val & 0x7fU;
    val >>= 7;
    if (val)
      byte |= 0x80U;
    buf[i++] = byte;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<upb_encode_varint>:
  endbr64
  cmp    $0x7f,%edi
  jle    L10
  mov    %edi,%edx
  and    $0x7f,%edx
  sar    $0x7,%edi
  mov    $0x0,%eax
  jmp    L1
L10:
  mov    %dil,(%rsi)
  mov    $0x1,%eax
  ret
L16:
  mov    %rcx,%rax
L1:
  lea    0x1(%rax),%rcx
  or     $0x80,%dl
  mov    %dl,-0x1(%rsi,%rcx,1)
  mov    %edi,%edx
  and    $0x7f,%edx
  sar    $0x7,%edi
  jne    L16
  add    $0x2,%rax
  mov    %dl,(%rsi,%rcx,1)
  ret
```

assistant: ```c
size_t upb_encode_varint(uint64_t val, char *buf) {
  size_t i;
  if (val < 128) {
    buf[0] = val;
    return 1;
  }
  i = 0;
  while (val) {
    uint8_t byte = val & 0x7fU;
    val >>= 7;
    if (val)
      byte |= 0x80U;
    buf[i++] = byte;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<upb_encode_varint>:
  endbr64
  cmp    $0x7f,%edi
  jle    L18
  mov    %edi,%edx
  xor    %eax,%eax
  sar    $0x7,%edi
  and    $0x7f,%edx
L16:
  or     $0x80,%dl
  lea    0x1(%rax),%rcx
  mov    %dl,-0x1(%rsi,%rcx,1)
  mov    %edi,%edx
  and    $0x7f,%edx
  sar    $0x7,%edi
  jne    L4
  mov    %dl,(%rsi,%rcx,1)
  add    $0x2,%rax
  ret
L4:
  mov    %rcx,%rax
  jmp    L16
  nopl   (%rax)
L18:
  mov    %dil,(%rsi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t upb_encode_varint(uint64_t val, char *buf) {
  size_t i;
  if (val < 128) {
    buf[0] = val;
    return 1;
  }
  i = 0;
  while (val) {
    uint8_t byte = val & 0x7fU;
    val >>= 7;
    if (val)
      byte |= 0x80U;
    buf[i++] = byte;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<upb_encode_varint>:
  endbr64
  cmp    $0x7f,%edi
  jle    L3
  mov    %edi,%edx
  xor    %eax,%eax
  sar    $0x7,%edi
  and    $0x7f,%edx
L15:
  or     $0x80,%dl
  lea    0x1(%rax),%rcx
  mov    %dl,-0x1(%rsi,%rcx,1)
  mov    %edi,%edx
  and    $0x7f,%edx
  sar    $0x7,%edi
  jne    L22
  mov    %dl,(%rsi,%rcx,1)
  add    $0x2,%rax
  ret
L22:
  mov    %rcx,%rax
  jmp    L15
  nopl   (%rax)
L3:
  mov    %dil,(%rsi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t upb_encode_varint(uint64_t val, char *buf) {
  size_t i;
  if (val < 128) {
    buf[0] = val;
    return 1;
  }
  i = 0;
  while (val) {
    uint8_t byte = val & 0x7fU;
    val >>= 7;
    if (val)
      byte |= 0x80U;
    buf[i++] = byte;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<timespec_subtract_ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L8
  mov    -0x8(%rbp),%rax
  add    $0x3b9aca00,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sub    $0x1,%eax
  imul   $0x3b9aca00,%eax,%eax
  cltq
  add    %rax,-0x10(%rbp)
  jmp    L1
L8:
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0x3b9aca00,%eax,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long timespec_subtract_ns(struct timespec *first, struct timespec *last) {
  signed long nsec;
  unsigned long time;
  nsec = last->tv_nsec - first->tv_nsec;
  if (nsec < 0) {
    time = 1000000000 + nsec;
    time += (last->tv_sec - first->tv_sec - 1) * 1000000000;
  } else
    time = nsec + (last->tv_sec - first->tv_sec) * 1000000000;
  return time;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timespec_subtract_ns>:
  endbr64
  mov    (%rsi),%rax
  sub    (%rdi),%rax
  mov    %rax,%rdx
  js     L2
  mov    0x8(%rsi),%eax
  sub    0x8(%rdi),%eax
  imul   $0x3b9aca00,%eax,%eax
  cltq
  add    %rdx,%rax
  ret
L2:
  mov    0x8(%rsi),%eax
  sub    0x8(%rdi),%eax
  sub    $0x1,%eax
  imul   $0x3b9aca00,%eax,%eax
  cltq
  lea    0x3b9aca00(%rdx,%rax,1),%rax
  ret
```

assistant: ```c
unsigned long timespec_subtract_ns(struct timespec *first, struct timespec *last) {
  signed long nsec;
  unsigned long time;
  nsec = last->tv_nsec - first->tv_nsec;
  if (nsec < 0) {
    time = 1000000000 + nsec;
    time += (last->tv_sec - first->tv_sec - 1) * 1000000000;
  } else
    time = nsec + (last->tv_sec - first->tv_sec) * 1000000000;
  return time;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<timespec_subtract_ns>:
  endbr64
  mov    0x8(%rsi),%eax
  mov    (%rsi),%rdx
  sub    0x8(%rdi),%eax
  sub    (%rdi),%rdx
  js     L7
  imul   $0x3b9aca00,%eax,%eax
  cltq
  add    %rdx,%rax
  ret
  xchg   %ax,%ax
L7:
  sub    $0x1,%eax
  imul   $0x3b9aca00,%eax,%eax
  cltq
  lea    0x3b9aca00(%rdx,%rax,1),%rax
  ret
```

assistant: ```c
unsigned long timespec_subtract_ns(struct timespec *first, struct timespec *last) {
  signed long nsec;
  unsigned long time;
  nsec = last->tv_nsec - first->tv_nsec;
  if (nsec < 0) {
    time = 1000000000 + nsec;
    time += (last->tv_sec - first->tv_sec - 1) * 1000000000;
  } else
    time = nsec + (last->tv_sec - first->tv_sec) * 1000000000;
  return time;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timespec_subtract_ns>:
  endbr64
  mov    0x8(%rsi),%eax
  mov    (%rsi),%rdx
  sub    0x8(%rdi),%eax
  sub    (%rdi),%rdx
  js     L9
  imul   $0x3b9aca00,%eax,%eax
  cltq
  add    %rdx,%rax
  ret
  xchg   %ax,%ax
L9:
  sub    $0x1,%eax
  imul   $0x3b9aca00,%eax,%eax
  cltq
  lea    0x3b9aca00(%rdx,%rax,1),%rax
  ret
```

assistant: ```c
unsigned long timespec_subtract_ns(struct timespec *first, struct timespec *last) {
  signed long nsec;
  unsigned long time;
  nsec = last->tv_nsec - first->tv_nsec;
  if (nsec < 0) {
    time = 1000000000 + nsec;
    time += (last->tv_sec - first->tv_sec - 1) * 1000000000;
  } else
    time = nsec + (last->tv_sec - first->tv_sec) * 1000000000;
  return time;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  movl   $0xa,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  movl   $0x64,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f() {
  int x;
  int y;
  x = 0;
  y = 1;
  {
    x = x + y;
    y = 10;
    {
      int y;
      x = x + y;
      y = 100;
      { x = x + y; }
    }
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  mov    $0x65,%eax
  ret
```

assistant: ```c
int f() {
  int x;
  int y;
  x = 0;
  y = 1;
  {
    x = x + y;
    y = 10;
    {
      int y;
      x = x + y;
      y = 100;
      { x = x + y; }
    }
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  mov    $0x65,%eax
  ret
```

assistant: ```c
int f() {
  int x;
  int y;
  x = 0;
  y = 1;
  {
    x = x + y;
    y = 10;
    {
      int y;
      x = x + y;
      y = 100;
      { x = x + y; }
    }
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  mov    $0x65,%eax
  ret
```

assistant: ```c
int f() {
  int x;
  int y;
  x = 0;
  y = 1;
  {
    x = x + y;
    y = 10;
    {
      int y;
      x = x + y;
      y = 100;
      { x = x + y; }
    }
  }
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<discardTag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L53
L29:
  cmpl   $0x1,-0x114(%rbp)
  jne    L53
  lea    -0x110(%rbp),%rdx
  mov    -0x128(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L44
L53:
  mov    -0x130(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nextEntity@plt>
  mov    %eax,-0x114(%rbp)
  cmpl   $0xffffffff,-0x114(%rbp)
  jne    L29
  jmp    L26
L44:
  nop
L26:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

assistant: ```c
void discardTag(const char *tagname, FILE *in) {
  char entity[256];
  int istag;
  while ((istag = nextEntity(entity, in)) != -1) {
    if (istag == 1 && strcmp(tagname, entity) == 0)
      break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<discardTag>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
L26:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <nextEntity@plt>
  cmp    $0xffffffff,%eax
  je     L7
  cmp    $0x1,%eax
  jne    L26
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
L7:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void discardTag(const char *tagname, FILE *in) {
  char entity[256];
  int istag;
  while ((istag = nextEntity(entity, in)) != -1) {
    if (istag == 1 && strcmp(tagname, entity) == 0)
      break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<discardTag>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L10
  nopl   (%rax)
L35:
  cmp    $0x1,%eax
  je     L4
L10:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <nextEntity@plt>
  cmp    $0xffffffff,%eax
  jne    L35
L36:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  jmp    L36
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void discardTag(const char *tagname, FILE *in) {
  char entity[256];
  int istag;
  while ((istag = nextEntity(entity, in)) != -1) {
    if (istag == 1 && strcmp(tagname, entity) == 0)
      break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<discardTag>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L38
  nopl   (%rax)
L32:
  cmp    $0x1,%eax
  je     L16
L38:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <nextEntity@plt>
  cmp    $0xffffffff,%eax
  jne    L32
L24:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L38
  jmp    L24
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void discardTag(const char *tagname, FILE *in) {
  char entity[256];
  int istag;
  while ((istag = nextEntity(entity, in)) != -1) {
    if (istag == 1 && strcmp(tagname, entity) == 0)
      break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L33
L19:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L33:
  cmpq   $0x0,-0x18(%rbp)
  je     L35
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L35
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
L35:
  cmpq   $0x0,-0x18(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L29
L13:
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while ((n > 0) && (*s1 == *s2) && (*s1 != '\0')) {
    s1++;
    s2++;
    n--;
  }
  return (n == 0) ? 0 : (*s1 - *s2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strncmp>:
  endbr64
  test   %rdx,%rdx
  je     L21
L2:
  movzbl (%rdi),%eax
  cmp    %al,(%rsi)
  jne    L26
  test   %al,%al
  je     L26
  add    $0x1,%rdi
  add    $0x1,%rsi
  sub    $0x1,%rdx
  jne    L2
  mov    $0x0,%eax
L24:
  ret
L21:
  mov    $0x0,%eax
  ret
L26:
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L24
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while ((n > 0) && (*s1 == *s2) && (*s1 != '\0')) {
    s1++;
    s2++;
    n--;
  }
  return (n == 0) ? 0 : (*s1 - *s2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L40
  jmp    L28
  nopl   (%rax)
L24:
  cmp    %r8b,%cl
  jne    L18
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L16
L40:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  test   %cl,%cl
  jne    L24
L18:
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
L28:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while ((n > 0) && (*s1 == *s2) && (*s1 != '\0')) {
    s1++;
    s2++;
    n--;
  }
  return (n == 0) ? 0 : (*s1 - *s2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L38
  jmp    L14
  nopl   (%rax)
L10:
  cmp    %r8b,%cl
  jne    L37
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L36
L38:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  test   %cl,%cl
  jne    L10
L37:
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  xor    %eax,%eax
  ret
L14:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while ((n > 0) && (*s1 == *s2) && (*s1 != '\0')) {
    s1++;
    s2++;
    n--;
  }
  return (n == 0) ? 0 : (*s1 - *s2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L11
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  jmp    L13
L11:
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
char *parse_text(char *line, char *cmd) {
  char *parsed_text = strstr(line, cmd);
  if (parsed_text == line) {
    return parsed_text + strlen(cmd);
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_text>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strstr@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  cmp    %rbp,%rbx
  je     L13
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %rbp,%rax
  jmp    L17
```

assistant: ```c
char *parse_text(char *line, char *cmd) {
  char *parsed_text = strstr(line, cmd);
  if (parsed_text == line) {
    return parsed_text + strlen(cmd);
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_text>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%rbx
  je     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  cltq
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *parse_text(char *line, char *cmd) {
  char *parsed_text = strstr(line, cmd);
  if (parsed_text == line) {
    return parsed_text + strlen(cmd);
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_text>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%rbx
  je     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  cltq
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *parse_text(char *line, char *cmd) {
  char *parsed_text = strstr(line, cmd);
  if (parsed_text == line) {
    return parsed_text + strlen(cmd);
  }
  return NULL;
}
```