ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<defaultR>:
  endbr64
  mov    D13(%rip),%rax
  mov    %rax,(%rdi)
  mov    D14(%rip),%rax
  mov    %rax,0x8(%rdi)
  mov    D8(%rip),%rax
  mov    %rax,0x10(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
data_type: byte[8]
name: retrieve_data
arguments: data_label: D14
data_type: byte[8]
name: retrieve_data
arguments: data_label: D8
data_type: byte[8]

tool: {"D13": [0x33,0x33,0x33,0x33,0x33,0x33,0xd3,0x3f]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: {"D8": [0x9a,0x99,0x99,0x99,0x99,0x99,0xb9,0xbf]}

assistant: ```c
void defaultR(double *src) {
  src[0] = .3;
  src[1] = -.5;
  src[2] = -.1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<defaultR>:
  endbr64
  movapd D0(%rip),%xmm0
  mov    D13(%rip),%rax
  movups %xmm0,(%rdi)
  mov    %rax,0x10(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D13
type_infered: byte[8]

tool: {"D0": [0x33,0x33,0x33,0x33,0x33,0x33,0xd3,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: {"D13": [0x9a,0x99,0x99,0x99,0x99,0x99,0xb9,0xbf]}

assistant: ```c
void defaultR(double *src) {
  src[0] = .3;
  src[1] = -.5;
  src[2] = -.1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movabs $0x7720656220646f47,%rsi
  movabs $0x2c756f7920687469,%rdi
  mov    %rsi,(%rax)
  mov    %rdi,0x8(%rax)
  movabs $0x666977646f6f6720,%rsi
  movabs $0x63616c6c61572065,%rdi
  mov    %rsi,0x10(%rax)
  mov    %rdi,0x18(%rax)
  movl   $0xa2165,0x20(%rax)
  jmp    L17
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char *s;
  s = malloc((size_t)50);
  s = strcat(s, "God be with you, goodwife Wallace!\n");
  while (*s != '\0')
    putchar(*(s++));
  free(s);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  movabs $0x7720656220646f47,%rdx
  movabs $0x2c756f7920687469,%rcx
  mov    %rdx,(%rax)
  mov    %rcx,0x8(%rax)
  movabs $0x666977646f6f6720,%rsi
  movabs $0x63616c6c61572065,%rdi
  mov    %rsi,0x10(%rax)
  mov    %rdi,0x18(%rax)
  movl   $0xa2165,0x20(%rax)
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L2
L7:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L7
L2:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  char *s;
  s = malloc((size_t)50);
  s = strcat(s, "God be with you, goodwife Wallace!\n");
  while (*s != '\0')
    putchar(*(s++));
  free(s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  movdqa D0(%rip),%xmm0
  add    %rbp,%rax
  movups %xmm0,(%rax)
  movdqa D10(%rip),%xmm0
  movl   $0xa2165,0x20(%rax)
  movups %xmm0,0x10(%rax)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L0
  nopl   0x0(%rax)
L4:
  call   <putchar@plt>
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  jne    L4
L0:
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: byte[16]
name: parse_data
arguments: data_tag: D10
type: byte[16]

tool: {"D0": [0x47,0x6f,0x64,0x20,0x62,0x65,0x20,0x77,0x69,0x74,0x68,0x20,0x79,0x6f,0x75,0x2c]}

tool: {"D10": [0x20,0x67,0x6f,0x6f,0x64,0x77,0x69,0x66,0x65,0x20,0x57,0x61,0x6c,0x6c,0x61,0x63]}

assistant: ```c
int main(void) {
  char *s;
  s = malloc((size_t)50);
  s = strcat(s, "God be with you, goodwife Wallace!\n");
  while (*s != '\0')
    putchar(*(s++));
  free(s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  movdqa D11(%rip),%xmm0
  add    %rbp,%rax
  movups %xmm0,(%rax)
  movdqa D1(%rip),%xmm0
  movl   $0xa2165,0x20(%rax)
  movups %xmm0,0x10(%rax)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L16
  nopl   0x0(%rax)
L5:
  call   <putchar@plt>
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  jne    L5
L16:
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D1
type: byte[16]

tool: {"D11": [0x47,0x6f,0x64,0x20,0x62,0x65,0x20,0x77,0x69,0x74,0x68,0x20,0x79,0x6f,0x75,0x2c]}

tool: {"D1": [0x20,0x67,0x6f,0x6f,0x64,0x77,0x69,0x66,0x65,0x20,0x57,0x61,0x6c,0x6c,0x61,0x63]}

assistant: ```c
int main(void) {
  char *s;
  s = malloc((size_t)50);
  s = strcat(s, "God be with you, goodwife Wallace!\n");
  while (*s != '\0')
    putchar(*(s++));
  free(s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x1bc(%rbp)
  movl   $0x0,-0x1b8(%rbp)
  movl   $0x2,-0x1b4(%rbp)
  jmp    L50
L42:
  cmpl   $0x9,-0x1b4(%rbp)
  jle    L2
  mov    $0x7b,%eax
  jmp    L39
L2:
  mov    $0x4d2,%eax
L39:
  mov    %eax,-0x1ac(%rbp)
  mov    $0x2710,%eax
  cltd
  idivl  -0x1b4(%rbp)
  add    $0x1,%eax
  mov    %eax,-0x1a8(%rbp)
  mov    -0x1ac(%rbp),%eax
  mov    %eax,-0x1b0(%rbp)
  jmp    L59
L17:
  mov    -0x1b4(%rbp),%eax
  imul   -0x1b0(%rbp),%eax
  mov    %eax,-0x1a4(%rbp)
  mov    -0x1a4(%rbp),%edx
  mov    -0x1b0(%rbp),%ecx
  mov    -0x1b4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <pandigital@plt>
  test   %rax,%rax
  je     L89
  mov    -0x1a4(%rbp),%edx
  mov    -0x1bc(%rbp),%ecx
  lea    -0x1a0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <intable@plt>
  test   %eax,%eax
  jne    L89
  mov    -0x1bc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1bc(%rbp)
  cltq
  mov    -0x1a4(%rbp),%edx
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1a4(%rbp),%eax
  add    %eax,-0x1b8(%rbp)
L89:
  addl   $0x1,-0x1b0(%rbp)
L59:
  mov    -0x1b0(%rbp),%eax
  cmp    -0x1a8(%rbp),%eax
  jl     L17
  addl   $0x1,-0x1b4(%rbp)
L50:
  cmpl   $0x3e7,-0x1b4(%rbp)
  jle    L42
  mov    -0x1b8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: %d


assistant: ```c
int main(void) {
  int table[100] = {0};
  int tlen = 0;
  int sum = 0;
  int i, j;
  for (i = 2; i < 1000; ++i) {
    const int start = i > 9 ? 123 : 1234;
    const int end = 10000 / i + 1;
    for (j = start; j < end; ++j) {
      const int p = i * j;
      if (pandigital(i, j, p) && !intable(table, tlen, p)) {
        table[tlen++] = p;
        sum += p;
      }
    }
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x3,0x18(%rsp)
  mov    $0x2,%r12d
  movl   $0x0,0x1c(%rsp)
  mov    $0x0,%r15d
  lea    0x20(%rsp),%rax
  mov    %rax,0x10(%rsp)
  jmp    L14
L77:
  add    $0x1,%ebp
  add    %r12d,%ebx
  cmp    %ebp,%r14d
  jl     L10
L43:
  mov    %ebx,0xc(%rsp)
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <pandigital@plt>
  test   %rax,%rax
  je     L77
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    0x10(%rsp),%rdi
  call   <intable@plt>
  test   %eax,%eax
  jne    L77
  movslq %r15d,%rax
  mov    0xc(%rsp),%ecx
  mov    %ecx,0x20(%rsp,%rax,4)
  add    %ecx,0x1c(%rsp)
  lea    0x1(%r15),%r15d
  jmp    L77
L10:
  cmpl   $0x3e7,0x18(%rsp)
  jg     L0
L19:
  add    $0x1,%r12d
  addl   $0x1,0x18(%rsp)
L14:
  mov    %r12d,%r13d
  cmp    $0x9,%r12d
  jle    L74
  mov    $0x2710,%eax
  cltd
  idiv   %r12d
  mov    %eax,%r14d
  cmp    $0x7a,%eax
  jle    L10
  mov    $0x7b,%ebp
L24:
  mov    %ebp,%ebx
  imul   %r13d,%ebx
  jmp    L43
L0:
  mov    0x1c(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  mov    $0x2710,%eax
  cltd
  idiv   %r12d
  mov    %eax,%r14d
  mov    $0x4d2,%ebp
  cmp    $0x4d1,%eax
  jg     L24
  jmp    L19
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: %d


assistant: ```c
int main(void) {
  int table[100] = {0};
  int tlen = 0;
  int sum = 0;
  int i, j;
  for (i = 2; i < 1000; ++i) {
    const int start = i > 9 ? 123 : 1234;
    const int end = 10000 / i + 1;
    for (j = start; j < end; ++j) {
      const int p = i * j;
      if (pandigital(i, j, p) && !intable(table, tlen, p)) {
        table[tlen++] = p;
        sum += p;
      }
    }
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x32,%ecx
  mov    $0x2,%r15d
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x4d2,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  xchg   %ax,%ax
L71:
  mov    $0x2710,%eax
  cltd
  idiv   %r15d
  cmp    %ebx,%eax
  jl     L52
  mov    %ebx,%r14d
  lea    0x1(%rax),%ebp
  imul   %r15d,%r14d
  jmp    L1
  nopl   0x0(%rax)
L20:
  add    $0x1,%ebx
  add    %r15d,%r14d
  cmp    %ebp,%ebx
  je     L52
L1:
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r15d,%edi
  call   <pandigital@plt>
  test   %rax,%rax
  je     L20
  mov    %r14d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <intable@plt>
  test   %eax,%eax
  jne    L20
  movslq %r12d,%rax
  add    $0x1,%ebx
  add    %r14d,0xc(%rsp)
  add    $0x1,%r12d
  mov    %r14d,0x10(%rsp,%rax,4)
  add    %r15d,%r14d
  cmp    %ebp,%ebx
  jne    L1
  nopl   0x0(%rax)
L52:
  add    $0x1,%r15d
  cmp    $0x3e8,%r15d
  je     L23
  cmp    $0x9,%r15d
  mov    $0x7b,%ebx
  mov    $0x4d2,%eax
  cmovle %eax,%ebx
  jmp    L71
L23:
  mov    0xc(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string

tool: D7: %d


assistant: ```c
int main(void) {
  int table[100] = {0};
  int tlen = 0;
  int sum = 0;
  int i, j;
  for (i = 2; i < 1000; ++i) {
    const int start = i > 9 ? 123 : 1234;
    const int end = 10000 / i + 1;
    for (j = start; j < end; ++j) {
      const int p = i * j;
      if (pandigital(i, j, p) && !intable(table, tlen, p)) {
        table[tlen++] = p;
        sum += p;
      }
    }
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x32,%ecx
  mov    $0x2,%r15d
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x4d2,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  xchg   %ax,%ax
L27:
  mov    $0x2710,%eax
  cltd
  idiv   %r15d
  cmp    %ebx,%eax
  jl     L80
  mov    %ebx,%r14d
  lea    0x1(%rax),%ebp
  imul   %r15d,%r14d
  jmp    L10
  nopl   0x0(%rax)
L40:
  add    $0x1,%ebx
  add    %r15d,%r14d
  cmp    %ebp,%ebx
  je     L80
L10:
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r15d,%edi
  call   <pandigital@plt>
  test   %rax,%rax
  je     L40
  mov    %r14d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <intable@plt>
  test   %eax,%eax
  jne    L40
  movslq %r12d,%rax
  add    $0x1,%ebx
  add    %r14d,0xc(%rsp)
  add    $0x1,%r12d
  mov    %r14d,0x10(%rsp,%rax,4)
  add    %r15d,%r14d
  cmp    %ebp,%ebx
  jne    L10
  nopl   0x0(%rax)
L80:
  add    $0x1,%r15d
  cmp    $0x3e8,%r15d
  je     L4
  cmp    $0x9,%r15d
  mov    $0x7b,%ebx
  mov    $0x4d2,%eax
  cmovle %eax,%ebx
  jmp    L27
L4:
  mov    0xc(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: %d


assistant: ```c
int main(void) {
  int table[100] = {0};
  int tlen = 0;
  int sum = 0;
  int i, j;
  for (i = 2; i < 1000; ++i) {
    const int start = i > 9 ? 123 : 1234;
    const int end = 10000 / i + 1;
    for (j = start; j < end; ++j) {
      const int p = i * j;
      if (pandigital(i, j, p) && !intable(table, tlen, p)) {
        table[tlen++] = p;
        sum += p;
      }
    }
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L3
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L3
  mov    $0x0,%eax
  call   <link_error1@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void test5(int x, int y) {
  if ((x >= y) || (x < y)) {
  } else
    link_error1();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test5>:
  endbr64
  ret
```

assistant: ```c
void test5(int x, int y) {
  if ((x >= y) || (x < y)) {
  } else
    link_error1();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test5>:
  endbr64
  ret
```

assistant: ```c
void test5(int x, int y) {
  if ((x >= y) || (x < y)) {
  } else
    link_error1();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test5>:
  endbr64
  ret
```

assistant: ```c
void test5(int x, int y) {
  if ((x >= y) || (x < y)) {
  } else
    link_error1();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getrval2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0xffffffffffffffff,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long getrval2(tcp)
struct tcb *tcp;
{
  long val = -1;
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getrval2>:
  endbr64
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long getrval2(tcp)
struct tcb *tcp;
{
  long val = -1;
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getrval2>:
  endbr64
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long getrval2(tcp)
struct tcb *tcp;
{
  long val = -1;
  return val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getrval2>:
  endbr64
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long getrval2(tcp)
struct tcb *tcp;
{
  long val = -1;
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<prepAttackString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: Attack string at 0x%08x:

assistant: ```c
void prepAttackString(char *s, void *ptr) {
  unsigned len = strlen(s);
  printf("Attack string at 0x%08x:", (unsigned int)s);
  memcpy(&(s[len - 4]), (char *)(&ptr), 4);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prepAttackString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    -0x4(%rbp),%eax
  lea    (%rbx,%rax,1),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: Attack string at 0x%08x:

assistant: ```c
void prepAttackString(char *s, void *ptr) {
  unsigned len = strlen(s);
  printf("Attack string at 0x%08x:", (unsigned int)s);
  memcpy(&(s[len - 4]), (char *)(&ptr), 4);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prepAttackString>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%ebp
  call   <printf@plt>
  lea    -0x4(%rbp),%eax
  lea    0x8(%rsp),%rsi
  mov    $0x4,%edx
  lea    (%rbx,%rax,1),%rdi
  call   <memcpy@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: Attack string at 0x%08x:

assistant: ```c
void prepAttackString(char *s, void *ptr) {
  unsigned len = strlen(s);
  printf("Attack string at 0x%08x:", (unsigned int)s);
  memcpy(&(s[len - 4]), (char *)(&ptr), 4);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prepAttackString>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  mov    %eax,%ebp
  call   <printf@plt>
  lea    -0x4(%rbp),%eax
  lea    0x8(%rsp),%rsi
  mov    $0x4,%edx
  lea    (%rbx,%rax,1),%rdi
  call   <memcpy@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: Attack string at 0x%08x:

assistant: ```c
void prepAttackString(char *s, void *ptr) {
  unsigned len = strlen(s);
  printf("Attack string at 0x%08x:", (unsigned int)s);
  memcpy(&(s[len - 4]), (char *)(&ptr), 4);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binrpc_hdr_change_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdi
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  mov    %rdx,%rcx
  mov    %eax,%edx
  call   <binrpc_write_int@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int binrpc_hdr_change_len(unsigned char *hdr, int hdr_len, int new_len) {
  int len_len;
  binrpc_write_int(&hdr[2], hdr + hdr_len, new_len, &len_len);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binrpc_hdr_change_len>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  movslq %esi,%rsi
  add    %rdi,%rsi
  add    $0x2,%rdi
  call   <binrpc_write_int@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binrpc_hdr_change_len(unsigned char *hdr, int hdr_len, int new_len) {
  int len_len;
  binrpc_write_int(&hdr[2], hdr + hdr_len, new_len, &len_len);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<binrpc_hdr_change_len>:
  endbr64
  sub    $0x18,%rsp
  movslq %esi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  add    %rdi,%rsi
  lea    0x4(%rsp),%rcx
  add    $0x2,%rdi
  call   <binrpc_write_int@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binrpc_hdr_change_len(unsigned char *hdr, int hdr_len, int new_len) {
  int len_len;
  binrpc_write_int(&hdr[2], hdr + hdr_len, new_len, &len_len);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binrpc_hdr_change_len>:
  endbr64
  sub    $0x18,%rsp
  movslq %esi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  add    %rdi,%rsi
  lea    0x4(%rsp),%rcx
  add    $0x2,%rdi
  call   <binrpc_write_int@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binrpc_hdr_change_len(unsigned char *hdr, int hdr_len, int new_len) {
  int len_len;
  binrpc_write_int(&hdr[2], hdr + hdr_len, new_len, &len_len);
  return 0;
}
```