ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  unsigned int a = 1, b = 1, i = 0, temp = 0;
  for (i = 0; i < 20; i++) {
    temp = a;
    a = b;
    b += temp;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_not_blk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L6
L13:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  or     %eax,-0x8(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int set_not_blk(int fd) {
  int oldfl, ret;
  if ((oldfl = fcntl(fd, F_GETFL)) == -1)
    return -1;
  oldfl |= O_NONBLOCK;
  ret = fcntl(fd, F_SETFL, oldfl);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_not_blk>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    D7(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D28(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
L1:
  pop    %rbx
  ret
```

assistant: ```c
int set_not_blk(int fd) {
  int oldfl, ret;
  if ((oldfl = fcntl(fd, F_GETFL)) == -1)
    return -1;
  oldfl |= O_NONBLOCK;
  ret = fcntl(fd, F_SETFL, oldfl);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_not_blk>:
  endbr64
  mov    D4(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L4
  mov    D7(%rip),%rdx
  mov    %ebp,%edi
  pop    %rbp
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  jmp    1050 <fcntl@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int set_not_blk(int fd) {
  int oldfl, ret;
  if ((oldfl = fcntl(fd, F_GETFL)) == -1)
    return -1;
  oldfl |= O_NONBLOCK;
  ret = fcntl(fd, F_SETFL, oldfl);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_not_blk>:
  endbr64
  mov    D10(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L7
  mov    D5(%rip),%rdx
  mov    %ebp,%edi
  pop    %rbp
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  jmp    1050 <fcntl@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int set_not_blk(int fd) {
  int oldfl, ret;
  if ((oldfl = fcntl(fd, F_GETFL)) == -1)
    return -1;
  oldfl |= O_NONBLOCK;
  ret = fcntl(fd, F_SETFL, oldfl);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testAll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <device@plt>
  mov    %rax,-0x28(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x28(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    $0x331,%esi
  mov    %rax,%rdi
  call   <eipa_free@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <buildString@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D14: Option -d -- device

tool: D15: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c

assistant: ```c
testAll() {
  char *deviceStr = device();
  char *str[2] = {"Option -d -- device", deviceStr};
  eipa_free((void **)(&(deviceStr)), 817, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c");
  return buildString(str, 2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<testAll>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <device@plt>
  mov    %rax,0x8(%rsp)
  lea    D8(%rip),%rcx
  mov    %rcx,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  lea    0x8(%rsp),%rdi
  lea    D5(%rip),%rdx
  mov    $0x331,%esi
  call   <eipa_free@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x2,%esi
  call   <buildString@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string

tool: D8: Option -d -- device

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c

assistant: ```c
testAll() {
  char *deviceStr = device();
  char *str[2] = {"Option -d -- device", deviceStr};
  eipa_free((void **)(&(deviceStr)), 817, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c");
  return buildString(str, 2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<testAll>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <device@plt>
  lea    0x8(%rsp),%rdi
  mov    $0x331,%esi
  lea    D0(%rip),%rcx
  lea    D18(%rip),%rdx
  mov    %rax,0x8(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  call   <eipa_free@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x2,%esi
  call   <buildString@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string
name: read_data
arguments: data_tag: D18
type: string

tool: D0: Option -d -- device

tool: D18: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c

assistant: ```c
testAll() {
  char *deviceStr = device();
  char *str[2] = {"Option -d -- device", deviceStr};
  eipa_free((void **)(&(deviceStr)), 817, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c");
  return buildString(str, 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<testAll>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <device@plt>
  lea    0x8(%rsp),%rdi
  mov    $0x331,%esi
  lea    D10(%rip),%rcx
  lea    D5(%rip),%rdx
  mov    %rax,0x8(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  call   <eipa_free@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x2,%esi
  call   <buildString@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string

tool: D10: Option -d -- device

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c

assistant: ```c
testAll() {
  char *deviceStr = device();
  char *str[2] = {"Option -d -- device", deviceStr};
  eipa_free((void **)(&(deviceStr)), 817, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/WikiDreams/CUDA-SAK/refs/heads/master/Cuda-SAK/functions.c");
  return buildString(str, 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<convert_yuv_to_gray0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L16:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x4,-0x10(%rbp)
L6:
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jb     L16
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int convert_yuv_to_gray0(unsigned char *yuv, unsigned char *gray, unsigned int width, unsigned int height) {
  unsigned int in, out = 0;
  int y0, y1;
  for (in = 0; in < width * height * 2; in += 4) {
    y0 = yuv[in + 0];
    y1 = yuv[in + 2];
    gray[out++] = y0;
    gray[out++] = y1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<convert_yuv_to_gray0>:
  endbr64
  mov    %rsi,%r8
  imul   %ecx,%edx
  add    %edx,%edx
  je     L4
  mov    $0x0,%ecx
  mov    $0x0,%eax
L0:
  mov    %eax,%esi
  movzbl (%rdi,%rsi,1),%r11d
  lea    0x2(%rax),%esi
  movzbl (%rdi,%rsi,1),%r9d
  lea    0x1(%rcx),%esi
  mov    %ecx,%r10d
  mov    %r11b,(%r8,%r10,1)
  add    $0x2,%ecx
  mov    %esi,%esi
  mov    %r9b,(%r8,%rsi,1)
  add    $0x4,%eax
  cmp    %edx,%eax
  jb     L0
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int convert_yuv_to_gray0(unsigned char *yuv, unsigned char *gray, unsigned int width, unsigned int height) {
  unsigned int in, out = 0;
  int y0, y1;
  for (in = 0; in < width * height * 2; in += 4) {
    y0 = yuv[in + 0];
    y1 = yuv[in + 2];
    gray[out++] = y0;
    gray[out++] = y1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<convert_yuv_to_gray0>:
  endbr64
  imul   %ecx,%edx
  mov    %rsi,%r8
  add    %edx,%edx
  je     L8
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %eax,%esi
  mov    %ecx,%r10d
  movzbl (%rdi,%rsi,1),%r11d
  lea    0x2(%rax),%esi
  add    $0x4,%eax
  movzbl (%rdi,%rsi,1),%r9d
  lea    0x1(%rcx),%esi
  add    $0x2,%ecx
  mov    %r11b,(%r8,%r10,1)
  mov    %r9b,(%r8,%rsi,1)
  cmp    %edx,%eax
  jb     L10
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int convert_yuv_to_gray0(unsigned char *yuv, unsigned char *gray, unsigned int width, unsigned int height) {
  unsigned int in, out = 0;
  int y0, y1;
  for (in = 0; in < width * height * 2; in += 4) {
    y0 = yuv[in + 0];
    y1 = yuv[in + 2];
    gray[out++] = y0;
    gray[out++] = y1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_yuv_to_gray0>:
  endbr64
  imul   %ecx,%edx
  mov    %rsi,%r8
  add    %edx,%edx
  je     L11
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %eax,%esi
  mov    %ecx,%r10d
  movzbl (%rdi,%rsi,1),%r11d
  lea    0x2(%rax),%esi
  add    $0x4,%eax
  movzbl (%rdi,%rsi,1),%r9d
  lea    0x1(%rcx),%esi
  add    $0x2,%ecx
  mov    %r11b,(%r8,%r10,1)
  mov    %r9b,(%r8,%rsi,1)
  cmp    %edx,%eax
  jb     L7
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int convert_yuv_to_gray0(unsigned char *yuv, unsigned char *gray, unsigned int width, unsigned int height) {
  unsigned int in, out = 0;
  int y0, y1;
  for (in = 0; in < width * height * 2; in += 4) {
    y0 = yuv[in + 0];
    y1 = yuv[in + 2];
    gray[out++] = y0;
    gray[out++] = y1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<Serial_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart0_putc@plt>
  test   %rax,%rax
  js     L32
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L39
  jmp    L34
L32:
  nop
L34:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Serial_write(char *buf, int len) {
  int i = 0;
  while (i < len) {
    if (uart0_putc(*buf) < 0)
      break;
    i++;
    buf++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Serial_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    $0x0,%ebp
L22:
  movsbl (%rbx),%edi
  call   <uart0_putc@plt>
  test   %rax,%rax
  js     L39
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r12d
  jne    L22
  mov    %r12d,%ebp
L39:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    $0x0,%ebp
  jmp    L39
```

assistant: ```c
int Serial_write(char *buf, int len) {
  int i = 0;
  while (i < len) {
    if (uart0_putc(*buf) < 0)
      break;
    i++;
    buf++;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Serial_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L25
  mov    %rdi,%rbx
  mov    %esi,%ebp
  xor    %r12d,%r12d
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L38:
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  je     L31
L14:
  movsbl (%rbx),%edi
  call   <uart0_putc@plt>
  test   %rax,%rax
  jns    L38
L31:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  xor    %r12d,%r12d
  jmp    L31
```

assistant: ```c
int Serial_write(char *buf, int len) {
  int i = 0;
  while (i < len) {
    if (uart0_putc(*buf) < 0)
      break;
    i++;
    buf++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Serial_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L28
  mov    %rdi,%rbx
  mov    %esi,%ebp
  xor    %r12d,%r12d
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L17:
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  je     L38
L18:
  movsbl (%rbx),%edi
  call   <uart0_putc@plt>
  test   %rax,%rax
  jns    L17
L38:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  xor    %r12d,%r12d
  jmp    L38
```

assistant: ```c
int Serial_write(char *buf, int len) {
  int i = 0;
  while (i < len) {
    if (uart0_putc(*buf) < 0)
      break;
    i++;
    buf++;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tutorial_if>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L8
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L8:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tutorial_if(char *p, char *q, int i) {
  char *s;
  if (i >= 0) {
    s = p;
  } else {
    s = q;
  }
  *s = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tutorial_if>:
  endbr64
  test   %edx,%edx
  cmovs  %rsi,%rdi
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void tutorial_if(char *p, char *q, int i) {
  char *s;
  if (i >= 0) {
    s = p;
  } else {
    s = q;
  }
  *s = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<tutorial_if>:
  endbr64
  test   %edx,%edx
  cmovs  %rsi,%rdi
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void tutorial_if(char *p, char *q, int i) {
  char *s;
  if (i >= 0) {
    s = p;
  } else {
    s = q;
  }
  *s = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tutorial_if>:
  endbr64
  test   %edx,%edx
  cmovs  %rsi,%rdi
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void tutorial_if(char *p, char *q, int i) {
  char *s;
  if (i >= 0) {
    s = p;
  } else {
    s = q;
  }
  *s = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <a@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char *s = a();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *s = a();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *s = a();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *s = a();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<New>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  call   <abort@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *New(int size) {
  void *m = malloc(size);
  if (!m)
    abort();
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<New>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
L14:
  mov    %rbx,%rax
  pop    %rbx
  ret
L6:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L14
```

assistant: ```c
void *New(int size) {
  void *m = malloc(size);
  if (!m)
    abort();
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<New>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *New(int size) {
  void *m = malloc(size);
  if (!m)
    abort();
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<New>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *New(int size) {
  void *m = malloc(size);
  if (!m)
    abort();
  return m;
}
```
user: What is the c source code of the assembly code below:

```asm
<atribui>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x9,-0x4(%rbp)
  jle    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void atribui(int destino[], int origem[]) {
  int q;
  for (q = 0; q < 10; q++) {
    destino[q] = origem[q];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<atribui>:
  endbr64
  mov    $0x0,%eax
L0:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x28,%rax
  jne    L0
  ret
```

assistant: ```c
void atribui(int destino[], int origem[]) {
  int q;
  for (q = 0; q < 10; q++) {
    destino[q] = origem[q];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<atribui>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x28,%rax
  jne    L1
  ret
```

assistant: ```c
void atribui(int destino[], int origem[]) {
  int q;
  for (q = 0; q < 10; q++) {
    destino[q] = origem[q];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atribui>:
  endbr64
  lea    0x4(%rsi),%rcx
  mov    %rdi,%rdx
  sub    %rcx,%rdx
  cmp    $0x8,%rdx
  jbe    L9
  movdqu (%rsi),%xmm0
  movups %xmm0,(%rdi)
  movdqu 0x10(%rsi),%xmm1
  movups %xmm1,0x10(%rdi)
  mov    0x20(%rsi),%rdx
  mov    %rdx,0x20(%rdi)
  ret
  nopl   (%rax)
L9:
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    0x4(%rsi),%edx
  mov    %edx,0x4(%rdi)
  mov    0x8(%rsi),%edx
  mov    %edx,0x8(%rdi)
  mov    0xc(%rsi),%edx
  mov    %edx,0xc(%rdi)
  mov    0x10(%rsi),%edx
  mov    %edx,0x10(%rdi)
  mov    0x14(%rsi),%edx
  mov    %edx,0x14(%rdi)
  mov    0x18(%rsi),%edx
  mov    %edx,0x18(%rdi)
  mov    0x1c(%rsi),%edx
  mov    %edx,0x1c(%rdi)
  mov    0x20(%rsi),%edx
  mov    %edx,0x20(%rdi)
  mov    0x24(%rsi),%edx
  mov    %edx,0x24(%rdi)
  ret
```

assistant: ```c
void atribui(int destino[], int origem[]) {
  int q;
  for (q = 0; q < 10; q++) {
    destino[q] = origem[q];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<caldays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jg     L209
  addl   $0xc,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L209:
  cmpl   $0xc,-0x8(%rbp)
  jle    L39
  subl   $0xc,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0xc,-0x8(%rbp)
  ja     L59
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D17(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1f,%eax
  jmp    L113
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L154
  mov    $0x1d,%eax
  jmp    L113
L154:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L129
  mov    $0x1c,%eax
  jmp    L113
L129:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L57
  mov    $0x1d,%eax
  jmp    L113
L57:
  mov    $0x1c,%eax
  jmp    L113
  mov    $0x1f,%eax
  jmp    L113
  mov    $0x1e,%eax
  jmp    L113
  mov    $0x1f,%eax
  jmp    L113
  mov    $0x1e,%eax
  jmp    L113
  mov    $0x1f,%eax
  jmp    L113
  mov    $0x1f,%eax
  jmp    L113
  mov    $0x1e,%eax
  jmp    L113
  mov    $0x1f,%eax
  jmp    L113
  mov    $0x1e,%eax
  jmp    L113
  mov    $0x1f,%eax
  jmp    L113
L59:
  mov    $0x0,%eax
L113:
  pop    %rbp
  ret
```

assistant: ```c
int caldays(year, month)
int year;
int month;
{
  if (month < 1) {
    month = month + 12;
    year = year + 1;
  }
  if (month > 12) {
    month = month - 12;
    year = year + 1;
  }
  switch (month) {
  case 1:
    return (31);
  case 2:
    if (year % 400 == 0)
      return (29);
    else if (year % 100 == 0)
      return (28);
    else if (year % 4 == 0)
      return (29);
    else
      return (28);
  case 3:
    return (31);
  case 4:
    return (30);
  case 5:
    return (31);
  case 6:
    return (30);
  case 7:
    return (31);
  case 8:
    return (31);
  case 9:
    return (30);
  case 10:
    return (31);
  case 11:
    return (30);
  case 12:
    return (31);
  default:
    return (0);
  }
}
```