ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<lsb_write>:
  endbr64
  sub    $0x18,%rsp
  bswap  %esi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <write@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lsb_write(int fh, int value) {
  char buffer[4];
  buffer[3] = value & 0xff;
  value >>= 8;
  buffer[2] = value & 0xff;
  value >>= 8;
  buffer[1] = value & 0xff;
  value >>= 8;
  buffer[0] = value & 0xff;
  return (write(fh, buffer, 4));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lsb_write>:
  endbr64
  sub    $0x18,%rsp
  bswap  %esi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <write@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lsb_write(int fh, int value) {
  char buffer[4];
  buffer[3] = value & 0xff;
  value >>= 8;
  buffer[2] = value & 0xff;
  value >>= 8;
  buffer[1] = value & 0xff;
  value >>= 8;
  buffer[0] = value & 0xff;
  return (write(fh, buffer, 4));
}
```
user: What is the c source code of the assembly code below:

```asm
<get_gpc_path>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,%r13
  mov    %edx,0xc(%rsp)
  mov    %ecx,%r12d
  mov    %r8,%r15
  mov    %r9d,%r14d
  mov    %fs:0x28,%rdx
  mov    %rdx,0x118(%rsp)
  xor    %edx,%edx
  lea    0x10(%rsp),%rdi
  mov    %rsi,%rdx
  lea    D15(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  test   %r14d,%r14d
  js     L17
  mov    $0x0,%ebx
  add    $0x5a,%r12d
L20:
  mov    (%r15,%rbx,4),%ecx
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  mov    %eax,%esi
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r8d
  mov    $0xffffffa6,%eax
  cltd
  idiv   %ecx
  add    %eax,%r8d
  imul   %ecx,%r8d
  lea    0x10(%rsp),%rbp
  sub    $0x8,%rsp
  lea    (%rcx,%r8,1),%eax
  push   %rax
  lea    (%rcx,%rsi,1),%r9d
  mov    %esi,%ecx
  mov    %rbp,%rdx
  lea    D12(%rip),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r13,%rdx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  add    $0x1,%rbx
  add    $0x10,%rsp
  cmp    %ebx,%r14d
  jge    L20
L17:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x1,%eax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D12
type_infered: string

tool: D15: %s

tool: D12: %s/%d_%d_to_%d_%d

assistant: ```c
int get_gpc_path(char *gpc_path, char *bd_path, int x, int y, int *pas, int level) {
  int xo, yo;
  int xe, ye;
  int nb_pas;
  char buffer[256];
  int i;
  nb_pas = (sizeof(pas) / sizeof(pas[0]));
  sprintf(buffer, "%s", bd_path);
  for (i = 0; i <= level; i++) {
    xo = (x / pas[i]) * pas[i];
    yo = ((y + 90) / pas[i] - (90 / pas[i])) * pas[i];
    xe = xo + pas[i];
    ye = yo + pas[i];
    sprintf(gpc_path, "%s/%d_%d_to_%d_%d", buffer, xo, yo, xe, ye);
    sprintf(buffer, "%s", gpc_path);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_gpc_path>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x128,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %rsi,%rdx
  mov    %r14,%rsi
  mov    %r9d,0x4(%rsp)
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    0x4(%rsp),%ecx
  lea    0x5a(%r15),%esi
  mov    %esi,0x8(%rsp)
  test   %ecx,%ecx
  js     L15
  xor    %r12d,%r12d
  mov    %rbp,%rax
  lea    D3(%rip),%r15
  mov    %r12,%rbp
  mov    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L14:
  mov    0xc(%rsp),%eax
  mov    0x0(%r13,%rbp,4),%ecx
  sub    $0x8,%rsp
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  mov    %eax,%r10d
  mov    0x10(%rsp),%eax
  lea    (%rcx,%r10,1),%r9d
  cltd
  idiv   %ecx
  mov    %eax,%r8d
  mov    $0xffffffa6,%eax
  cltd
  idiv   %ecx
  mov    %r12,%rdx
  add    %eax,%r8d
  imul   %ecx,%r8d
  lea    (%rcx,%r8,1),%eax
  mov    %r10d,%ecx
  push   %rax
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  pop    %rax
  pop    %rdx
  cmp    %ebp,0x4(%rsp)
  jge    L14
L15:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x128,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D3
data_type: string

tool: D7: %s

tool: D3: %s/%d_%d_to_%d_%d

assistant: ```c
int get_gpc_path(char *gpc_path, char *bd_path, int x, int y, int *pas, int level) {
  int xo, yo;
  int xe, ye;
  int nb_pas;
  char buffer[256];
  int i;
  nb_pas = (sizeof(pas) / sizeof(pas[0]));
  sprintf(buffer, "%s", bd_path);
  for (i = 0; i <= level; i++) {
    xo = (x / pas[i]) * pas[i];
    yo = ((y + 90) / pas[i] - (90 / pas[i])) * pas[i];
    xe = xo + pas[i];
    ye = yo + pas[i];
    sprintf(gpc_path, "%s/%d_%d_to_%d_%d", buffer, xo, yo, xe, ye);
    sprintf(buffer, "%s", gpc_path);
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_gpc_path>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x128,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %rsi,%rdx
  mov    %r14,%rsi
  mov    %r9d,0x4(%rsp)
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    0x4(%rsp),%ecx
  lea    0x5a(%r15),%esi
  mov    %esi,0x8(%rsp)
  test   %ecx,%ecx
  js     L11
  xor    %r12d,%r12d
  mov    %rbp,%rax
  lea    D13(%rip),%r15
  mov    %r12,%rbp
  mov    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0xc(%rsp),%eax
  mov    0x0(%r13,%rbp,4),%ecx
  sub    $0x8,%rsp
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  mov    %eax,%r10d
  mov    0x10(%rsp),%eax
  lea    (%rcx,%r10,1),%r9d
  cltd
  idiv   %ecx
  mov    %eax,%r8d
  mov    $0xffffffa6,%eax
  cltd
  idiv   %ecx
  mov    %r12,%rdx
  add    %eax,%r8d
  imul   %ecx,%r8d
  lea    (%rcx,%r8,1),%eax
  mov    %r10d,%ecx
  push   %rax
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  pop    %rax
  pop    %rdx
  cmp    %ebp,0x4(%rsp)
  jge    L2
L11:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x128,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D5: %s

tool: D13: %s/%d_%d_to_%d_%d

assistant: ```c
int get_gpc_path(char *gpc_path, char *bd_path, int x, int y, int *pas, int level) {
  int xo, yo;
  int xe, ye;
  int nb_pas;
  char buffer[256];
  int i;
  nb_pas = (sizeof(pas) / sizeof(pas[0]));
  sprintf(buffer, "%s", bd_path);
  for (i = 0; i <= level; i++) {
    xo = (x / pas[i]) * pas[i];
    yo = ((y + 90) / pas[i] - (90 / pas[i])) * pas[i];
    xe = xo + pas[i];
    ye = yo + pas[i];
    sprintf(gpc_path, "%s/%d_%d_to_%d_%d", buffer, xo, yo, xe, ye);
    sprintf(buffer, "%s", gpc_path);
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sc16q11_to_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L10:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  D18(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  D18(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x2,-0x4(%rbp)
L15:
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x4(%rbp)
  jb     L10
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
data_type: byte[4]

tool: {"D18": [0x00,0x00,0x00,0x3a]}

assistant: ```c
void sc16q11_to_float(const int16_t *in, float *out, unsigned int n) {
  unsigned int i;
  for (i = 0; i < (2 * n); i += 2) {
    out[i] = (float)in[i] * (1.0f / 2048.0f);
    out[i + 1] = (float)in[i + 1] * (1.0f / 2048.0f);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sc16q11_to_float>:
  endbr64
  add    %edx,%edx
  je     L5
  mov    $0x0,%eax
  movss  D2(%rip),%xmm1
L2:
  mov    %eax,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rdi,%rcx,8),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rsi,%rcx,4)
  lea    0x1(%rax),%ecx
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rdi,%rcx,8),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rsi,%rcx,4)
  add    $0x2,%eax
  cmp    %edx,%eax
  jb     L2
L5:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3a]}

assistant: ```c
void sc16q11_to_float(const int16_t *in, float *out, unsigned int n) {
  unsigned int i;
  for (i = 0; i < (2 * n); i += 2) {
    out[i] = (float)in[i] * (1.0f / 2048.0f);
    out[i + 1] = (float)in[i + 1] * (1.0f / 2048.0f);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sc16q11_to_float>:
  endbr64
  add    %edx,%edx
  je     L4
  movss  D4(%rip),%xmm1
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %eax,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rdi,%rcx,8),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rsi,%rcx,4)
  lea    0x1(%rax),%ecx
  pxor   %xmm0,%xmm0
  add    $0x2,%eax
  cvtsi2ssq (%rdi,%rcx,8),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rsi,%rcx,4)
  cmp    %edx,%eax
  jb     L0
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_infered: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x3a]}

assistant: ```c
void sc16q11_to_float(const int16_t *in, float *out, unsigned int n) {
  unsigned int i;
  for (i = 0; i < (2 * n); i += 2) {
    out[i] = (float)in[i] * (1.0f / 2048.0f);
    out[i + 1] = (float)in[i + 1] * (1.0f / 2048.0f);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sc16q11_to_float>:
  endbr64
  add    %edx,%edx
  je     L8
  movq   D7(%rip),%xmm2
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  lea    0x1(%rax),%r8d
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %eax,%ecx
  cvtsi2ssq (%rdi,%rcx,8),%xmm0
  add    $0x2,%eax
  cvtsi2ssq (%rdi,%r8,8),%xmm1
  unpcklps %xmm1,%xmm0
  mulps  %xmm2,%xmm0
  movlps %xmm0,(%rsi,%rcx,4)
  cmp    %edx,%eax
  jb     L19
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x3a,0x00,0x00,0x00,0x3a]}

assistant: ```c
void sc16q11_to_float(const int16_t *in, float *out, unsigned int n) {
  unsigned int i;
  for (i = 0; i < (2 * n); i += 2) {
    out[i] = (float)in[i] * (1.0f / 2048.0f);
    out[i + 1] = (float)in[i + 1] * (1.0f / 2048.0f);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flt_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jns    L39
  mov    -0x8(%rbp),%eax
  test   %eax,%eax
  jns    L16
  mov    -0x8(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%edi
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <flt_sum@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  xor    $0x80000000,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L46
L16:
  mov    -0x10(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edi
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <flt_difference@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L46
L39:
  mov    -0x8(%rbp),%eax
  test   %eax,%eax
  jns    L40
  mov    -0x8(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edi
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <flt_difference@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L46
L40:
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <flt_sum@plt>
  mov    %eax,-0x14(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int flt_add(a, b, c)
double *a;
double *b;
double *c;
{
  unsigned int bh = ((unsigned int *)b)[0];
  unsigned int bl = ((unsigned int *)b)[1];
  unsigned int ch = ((unsigned int *)c)[0];
  unsigned int cl = ((unsigned int *)c)[1];
  int ok;
  if (bh & 0x80000000) {
    if (ch & 0x80000000) {
      ok = flt_sum((unsigned int *)a, bh & 0x7fffffff, bl, ch & 0x7fffffff, cl);
      ((int *)a)[0] ^= 0x80000000;
    } else
      ok = flt_difference((unsigned int *)a, ch, cl, bh & 0x7fffffff, bl);
  } else if (ch & 0x80000000)
    ok = flt_difference((unsigned int *)a, bh, bl, ch & 0x7fffffff, cl);
  else
    ok = flt_sum((unsigned int *)a, bh, bl, ch, cl);
  return ok;
}
```
user: What is the c source code of the assembly code below:

```asm
<flt_add>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rsi),%edi
  mov    0x4(%rsi),%r9d
  mov    (%rdx),%esi
  mov    0x4(%rdx),%edx
  test   %edi,%edi
  js     L30
  test   %esi,%esi
  js     L48
  mov    %edx,%r8d
  mov    %esi,%ecx
  mov    %r9d,%edx
  mov    %edi,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <flt_sum@plt>
L14:
  pop    %rbx
  ret
L30:
  test   %esi,%esi
  js     L39
  mov    %edi,%ecx
  and    $0x7fffffff,%ecx
  mov    %r9d,%r8d
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <flt_difference@plt>
  jmp    L14
L39:
  mov    %esi,%ecx
  and    $0x7fffffff,%ecx
  and    $0x7fffffff,%edi
  mov    %edi,%esi
  mov    %edx,%r8d
  mov    %r9d,%edx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <flt_sum@plt>
  addl   $0x80000000,(%rbx)
  jmp    L14
L48:
  mov    %esi,%ecx
  and    $0x7fffffff,%ecx
  mov    %edx,%r8d
  mov    %r9d,%edx
  mov    %edi,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <flt_difference@plt>
  jmp    L14
```

assistant: ```c
int flt_add(a, b, c)
double *a;
double *b;
double *c;
{
  unsigned int bh = ((unsigned int *)b)[0];
  unsigned int bl = ((unsigned int *)b)[1];
  unsigned int ch = ((unsigned int *)c)[0];
  unsigned int cl = ((unsigned int *)c)[1];
  int ok;
  if (bh & 0x80000000) {
    if (ch & 0x80000000) {
      ok = flt_sum((unsigned int *)a, bh & 0x7fffffff, bl, ch & 0x7fffffff, cl);
      ((int *)a)[0] ^= 0x80000000;
    } else
      ok = flt_difference((unsigned int *)a, ch, cl, bh & 0x7fffffff, bl);
  } else if (ch & 0x80000000)
    ok = flt_difference((unsigned int *)a, bh, bl, ch & 0x7fffffff, cl);
  else
    ok = flt_sum((unsigned int *)a, bh, bl, ch, cl);
  return ok;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flt_add>:
  endbr64
  mov    (%rsi),%r9d
  mov    0x4(%rsi),%r10d
  mov    (%rdx),%esi
  mov    0x4(%rdx),%edx
  test   %r9d,%r9d
  js     L29
  test   %esi,%esi
  js     L18
  mov    %edx,%r8d
  mov    %esi,%ecx
  mov    %r10d,%edx
  mov    %r9d,%esi
  xor    %eax,%eax
  jmp    1060 <flt_sum@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %esi,%ecx
  mov    %edx,%r8d
  mov    %r9d,%esi
  mov    %r10d,%edx
  and    $0x7fffffff,%ecx
  xor    %eax,%eax
  jmp    1070 <flt_difference@plt>
  nopl   0x0(%rax,%rax,1)
L29:
  and    $0x7fffffff,%r9d
  test   %esi,%esi
  js     L8
  mov    %r10d,%r8d
  mov    %r9d,%ecx
  xor    %eax,%eax
  jmp    1070 <flt_difference@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %esi,%ecx
  sub    $0x18,%rsp
  mov    %edx,%r8d
  mov    %r9d,%esi
  and    $0x7fffffff,%ecx
  mov    %r10d,%edx
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  call   <flt_sum@plt>
  mov    0x8(%rsp),%rdi
  addl   $0x80000000,(%rdi)
  add    $0x18,%rsp
  ret
```

assistant: ```c
int flt_add(a, b, c)
double *a;
double *b;
double *c;
{
  unsigned int bh = ((unsigned int *)b)[0];
  unsigned int bl = ((unsigned int *)b)[1];
  unsigned int ch = ((unsigned int *)c)[0];
  unsigned int cl = ((unsigned int *)c)[1];
  int ok;
  if (bh & 0x80000000) {
    if (ch & 0x80000000) {
      ok = flt_sum((unsigned int *)a, bh & 0x7fffffff, bl, ch & 0x7fffffff, cl);
      ((int *)a)[0] ^= 0x80000000;
    } else
      ok = flt_difference((unsigned int *)a, ch, cl, bh & 0x7fffffff, bl);
  } else if (ch & 0x80000000)
    ok = flt_difference((unsigned int *)a, bh, bl, ch & 0x7fffffff, cl);
  else
    ok = flt_sum((unsigned int *)a, bh, bl, ch, cl);
  return ok;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flt_add>:
  endbr64
  mov    (%rsi),%r9d
  mov    0x4(%rsi),%r10d
  mov    (%rdx),%esi
  mov    0x4(%rdx),%edx
  test   %r9d,%r9d
  js     L23
  test   %esi,%esi
  js     L25
  mov    %edx,%r8d
  mov    %esi,%ecx
  mov    %r10d,%edx
  mov    %r9d,%esi
  xor    %eax,%eax
  jmp    1060 <flt_sum@plt>
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %esi,%ecx
  mov    %edx,%r8d
  mov    %r9d,%esi
  mov    %r10d,%edx
  and    $0x7fffffff,%ecx
  xor    %eax,%eax
  jmp    1070 <flt_difference@plt>
  nopl   0x0(%rax,%rax,1)
L23:
  and    $0x7fffffff,%r9d
  test   %esi,%esi
  js     L20
  mov    %r10d,%r8d
  mov    %r9d,%ecx
  xor    %eax,%eax
  jmp    1070 <flt_difference@plt>
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %esi,%ecx
  sub    $0x18,%rsp
  mov    %edx,%r8d
  mov    %r9d,%esi
  and    $0x7fffffff,%ecx
  mov    %r10d,%edx
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  call   <flt_sum@plt>
  mov    0x8(%rsp),%rdi
  addl   $0x80000000,(%rdi)
  add    $0x18,%rsp
  ret
```

assistant: ```c
int flt_add(a, b, c)
double *a;
double *b;
double *c;
{
  unsigned int bh = ((unsigned int *)b)[0];
  unsigned int bl = ((unsigned int *)b)[1];
  unsigned int ch = ((unsigned int *)c)[0];
  unsigned int cl = ((unsigned int *)c)[1];
  int ok;
  if (bh & 0x80000000) {
    if (ch & 0x80000000) {
      ok = flt_sum((unsigned int *)a, bh & 0x7fffffff, bl, ch & 0x7fffffff, cl);
      ((int *)a)[0] ^= 0x80000000;
    } else
      ok = flt_difference((unsigned int *)a, ch, cl, bh & 0x7fffffff, bl);
  } else if (ch & 0x80000000)
    ok = flt_difference((unsigned int *)a, bh, bl, ch & 0x7fffffff, cl);
  else
    ok = flt_sum((unsigned int *)a, bh, bl, ch, cl);
  return ok;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<outfloat2raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    -0x34(%rbp),%eax
  imul   -0x38(%rbp),%eax
  mov    -0x3c(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L18
L30:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss D0(%rip),%xmm0
  jbe    L20
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  D0(%rip),%xmm0
  movss  %xmm0,(%rax)
L20:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L34
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
L34:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movd   %eax,%xmm0
  call   <round@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L30
  mov    -0x28(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: byte[4]
name: read_data
arguments: data_tag: D7
data_type: string

tool: {"D0": [0x00,0x00,0x7f,0x43]}

tool: D7: wb

assistant: ```c
void outfloat2raw(char *fname, float *img, int ny, int nx, int dim) {
  FILE *fimg;
  int i, j, imagesize;
  unsigned char *tmp;
  imagesize = ny * nx * dim;
  tmp = (unsigned char *)malloc(imagesize * sizeof(unsigned char));
  for (i = 0; i < imagesize; i++) {
    if (img[i] > 255)
      img[i] = 255;
    if (img[i] < 0)
      img[i] = 0;
    tmp[i] = (unsigned char)round(img[i]);
  }
  fimg = fopen(fname, "wb");
  fwrite(tmp, sizeof(unsigned char), imagesize, fimg);
  fclose(fimg);
  free(tmp);
}
```