ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<lc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    $0x3ff,%ebp
  cmp    %ebp,%eax
  cmovle %eax,%ebp
  test   %eax,%eax
  jle    L2
  mov    $0x0,%ebx
  lea    D13(%rip),%r13
L22:
  movsbl (%r12,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L22
  test   %ebp,%ebp
  mov    $0x1,%eax
  cmovle %eax,%ebp
L10:
  lea    D13(%rip),%rax
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    $0x0,%ebp
  jmp    L10
```

assistant: ```c
char *lc(const char *string) {
  static char out[1024];
  int ii, n = strlen(string);
  if (n > 1023)
    n = 1023;
  for (ii = 0; ii < n; ii++)
    out[ii] = tolower(string[ii]);
  out[ii] = '\0';
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    $0x3ff,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebp,%eax
  cmovle %eax,%ebp
  test   %eax,%eax
  jle    L5
  xor    %ebx,%ebx
  lea    D19(%rip),%r12
  nopl   (%rax)
L26:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L26
  test   %ebp,%ebp
  mov    $0x1,%eax
  cmovle %eax,%ebp
L4:
  movslq %ebp,%rbp
  mov    %r12,%rax
  movb   $0x0,(%r12,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %ebp,%ebp
  lea    D19(%rip),%r12
  jmp    L4
```

assistant: ```c
char *lc(const char *string) {
  static char out[1024];
  int ii, n = strlen(string);
  if (n > 1023)
    n = 1023;
  for (ii = 0; ii < n; ii++)
    out[ii] = tolower(string[ii]);
  out[ii] = '\0';
  return out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    $0x3ff,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebp,%eax
  cmovle %eax,%ebp
  test   %eax,%eax
  jle    L6
  xor    %ebx,%ebx
  lea    D17(%rip),%r12
  nopl   (%rax)
L28:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L28
  test   %ebp,%ebp
  mov    $0x1,%eax
  cmovle %eax,%ebp
L13:
  movslq %ebp,%rbp
  mov    %r12,%rax
  movb   $0x0,(%r12,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %ebp,%ebp
  lea    D17(%rip),%r12
  jmp    L13
```

assistant: ```c
char *lc(const char *string) {
  static char out[1024];
  int ii, n = strlen(string);
  if (n > 1023)
    n = 1023;
  for (ii = 0; ii < n; ii++)
    out[ii] = tolower(string[ii]);
  out[ii] = '\0';
  return out;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_isupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffff81,-0x8(%rbp)
  jmp    L5
L16:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  cmpl   $0xff,-0x8(%rbp)
  jle    L16
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D19: test_isupper

tool: D8: %s: %d -> %d


assistant: ```c
void test_isupper(void) {
  int i, j;
  for (i = -127; i < 256;)
    j = i, printf("%s: %d -> %d\n", __FUNCTION__, j, isupper(i++) ? 1 : 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_isupper>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xffffff81,%ebx
  lea    D12(%rip),%r13
  lea    D19(%rip),%r12
L9:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %eax,%eax
  setne  %cl
  movzbl %cl,%ecx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D19
datatype: string

tool: D12: test_isupper

tool: D19: %s: %d -> %d


assistant: ```c
void test_isupper(void) {
  int i, j;
  for (i = -127; i < 256;)
    j = i, printf("%s: %d -> %d\n", __FUNCTION__, j, isupper(i++) ? 1 : 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_isupper>:
  endbr64
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    $0xffffff81,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  mov    %ebx,%r12d
  add    $0x1,%ebx
  mov    %r12d,%edi
  call   <isupper@plt>
  xor    %ecx,%ecx
  mov    %r12d,%edx
  mov    %r13,%rsi
  test   %eax,%eax
  mov    %rbp,%rdi
  setne  %cl
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string

tool: D16: test_isupper

tool: D12: %s: %d -> %d


assistant: ```c
void test_isupper(void) {
  int i, j;
  for (i = -127; i < 256;)
    j = i, printf("%s: %d -> %d\n", __FUNCTION__, j, isupper(i++) ? 1 : 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_isupper>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    $0xffffff81,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  mov    %ebx,%r12d
  add    $0x1,%ebx
  mov    %r12d,%edi
  call   <isupper@plt>
  xor    %ecx,%ecx
  mov    %r12d,%edx
  mov    %r13,%rsi
  test   %eax,%eax
  mov    %rbp,%rdi
  setne  %cl
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: D5: test_isupper

tool: D16: %s: %d -> %d


assistant: ```c
void test_isupper(void) {
  int i, j;
  for (i = -127; i < 256;)
    j = i, printf("%s: %d -> %d\n", __FUNCTION__, j, isupper(i++) ? 1 : 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L53
  movl   $0x1,-0x10(%rbp)
L53:
  cmpl   $0x0,-0x4(%rbp)
  jns    L46
  movl   $0xffffffff,-0x10(%rbp)
L46:
  cmpl   $0x0,-0x4(%rbp)
  jne    L20
  movl   $0x0,-0x10(%rbp)
L20:
  cmpl   $0xffffffff,-0x10(%rbp)
  jl     L9
  cmpl   $0x1,-0x10(%rbp)
  jle    L45
L9:
  nop
  mov    $0xfffffff6,%eax
  jmp    L24
L45:
  mov    -0x10(%rbp),%eax
L24:
  leave
  ret
```

assistant: ```c
int main() {
  int a = __VERIFIER_nondet_int();
  int b = __VERIFIER_nondet_int();
  int diff = a - b;
  int returnValue;
  if (diff > 0) {
    returnValue = 1;
  }
  if (diff < 0) {
    returnValue = -1;
  }
  if (diff == 0) {
    returnValue = 0;
  }
  if (returnValue < -1 || returnValue > 1) {
  ERROR:
    return -10;
  } else {
    return returnValue;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    $0xffffffff,%edx
  sub    %eax,%ebx
  js     L4
  test   %ebx,%ebx
  setne  %dl
  movzbl %dl,%edx
L4:
  mov    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int a = __VERIFIER_nondet_int();
  int b = __VERIFIER_nondet_int();
  int diff = a - b;
  int returnValue;
  if (diff > 0) {
    returnValue = 1;
  }
  if (diff < 0) {
    returnValue = -1;
  }
  if (diff == 0) {
    returnValue = 0;
  }
  if (returnValue < -1 || returnValue > 1) {
  ERROR:
    return -10;
  } else {
    return returnValue;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%r8d
  or     $0xffffffff,%eax
  cmp    %r8d,%ebx
  js     L1
  setne  %al
  movzbl %al,%eax
L1:
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int a = __VERIFIER_nondet_int();
  int b = __VERIFIER_nondet_int();
  int diff = a - b;
  int returnValue;
  if (diff > 0) {
    returnValue = 1;
  }
  if (diff < 0) {
    returnValue = -1;
  }
  if (diff == 0) {
    returnValue = 0;
  }
  if (returnValue < -1 || returnValue > 1) {
  ERROR:
    return -10;
  } else {
    return returnValue;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%r8d
  or     $0xffffffff,%eax
  cmp    %r8d,%ebx
  js     L8
  setne  %al
  movzbl %al,%eax
L8:
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int a = __VERIFIER_nondet_int();
  int b = __VERIFIER_nondet_int();
  int diff = a - b;
  int returnValue;
  if (diff > 0) {
    returnValue = 1;
  }
  if (diff < 0) {
    returnValue = -1;
  }
  if (diff == 0) {
    returnValue = 0;
  }
  if (returnValue < -1 || returnValue > 1) {
  ERROR:
    return -10;
  } else {
    return returnValue;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x4d,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L12
L8:
  movb   $0x0,-0xb(%rbp)
  jmp    L7
L32:
  movzbl -0x9(%rbp),%ecx
  movzbl -0xb(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xb(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xb(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xb(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xb(%rbp)
  jb     L32
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L8
  movzbl -0x9(%rbp),%eax
  lea    -0x9(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] = state[0UL] + state[local2];
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned char)9;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x4d(%rax),%edx
  movzbl 0x1(%rdi),%ecx
  mov    $0x0,%edi
  test   %cl,%cl
  je     L0
L22:
  mov    $0x0,%eax
L4:
  add    %edx,%edx
  add    $0x1,%eax
  cmp    %cl,%al
  jne    L4
  add    $0x1,%edi
  cmp    %cl,%dil
  jne    L22
L0:
  sub    $0x9,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] = state[0UL] + state[local2];
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned char)9;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%ecx
  xor    %edi,%edi
  lea    -0x4d(%rax),%edx
  test   %cl,%cl
  je     L2
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%eax
  add    %edx,%edx
  cmp    %cl,%al
  jne    L8
  add    $0x1,%edi
  cmp    %cl,%dil
  jne    L4
L2:
  sub    $0x9,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] = state[0UL] + state[local2];
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned char)9;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%ecx
  lea    -0x4d(%rax),%edx
  test   %cl,%cl
  je     L16
  lea    -0x1(%rcx),%eax
  cmp    $0xe,%al
  jbe    L44
  movdqa D8(%rip),%xmm0
  movzbl %dl,%edx
  mov    %ecx,%edi
  or     $0x1,%dh
  shr    $0x4,%dil
  pinsrw $0x0,%edx,%xmm0
  xor    %edx,%edx
  nopl   0x0(%rax)
L48:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%eax
  paddb  %xmm0,%xmm0
  cmp    %cl,%al
  jne    L20
  add    $0x1,%edx
  cmp    %dl,%dil
  ja     L48
  movdqa %xmm0,%xmm2
  movdqa %xmm0,%xmm1
  mov    %ecx,%edi
  psrldq $0x8,%xmm2
  punpcklbw %xmm0,%xmm1
  punpckhbw %xmm0,%xmm0
  and    $0xfffffff0,%edi
  movdqa %xmm2,%xmm3
  punpcklbw %xmm2,%xmm3
  punpckhbw %xmm2,%xmm2
  pmullw %xmm3,%xmm1
  pmullw %xmm2,%xmm0
  movdqa D14(%rip),%xmm2
  pand   %xmm2,%xmm0
  pand   %xmm2,%xmm1
  packuswb %xmm0,%xmm1
  movdqa %xmm1,%xmm3
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm3
  punpcklbw %xmm1,%xmm0
  punpckhbw %xmm1,%xmm1
  movdqa %xmm3,%xmm4
  punpcklbw %xmm3,%xmm4
  punpckhbw %xmm3,%xmm3
  pmullw %xmm4,%xmm0
  pmullw %xmm3,%xmm1
  pand   %xmm2,%xmm0
  pand   %xmm2,%xmm1
  packuswb %xmm1,%xmm0
  movdqa %xmm0,%xmm3
  movdqa %xmm0,%xmm1
  psrldq $0x2,%xmm3
  punpcklbw %xmm0,%xmm1
  punpckhbw %xmm0,%xmm0
  movdqa %xmm3,%xmm4
  punpcklbw %xmm3,%xmm4
  punpckhbw %xmm3,%xmm3
  pmullw %xmm4,%xmm1
  pmullw %xmm3,%xmm0
  pand   %xmm2,%xmm1
  pand   %xmm2,%xmm0
  packuswb %xmm0,%xmm1
  movdqa %xmm1,%xmm3
  movdqa %xmm1,%xmm0
  psrldq $0x1,%xmm3
  punpcklbw %xmm1,%xmm0
  punpckhbw %xmm1,%xmm1
  movdqa %xmm3,%xmm4
  punpcklbw %xmm3,%xmm4
  punpckhbw %xmm3,%xmm3
  pmullw %xmm4,%xmm0
  pmullw %xmm3,%xmm1
  pand   %xmm2,%xmm0
  pand   %xmm1,%xmm2
  packuswb %xmm2,%xmm0
  movd   %xmm0,%edx
  test   $0xf,%cl
  je     L16
  nopl   (%rax)
L36:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L46:
  add    $0x1,%eax
  add    %edx,%edx
  cmp    %cl,%al
  jne    L46
  add    $0x1,%edi
  cmp    %cl,%dil
  jb     L36
L16:
  sub    $0x9,%edx
  mov    %dl,(%rsi)
  ret
L44:
  xor    %edi,%edi
  jmp    L36
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: byte[16]
name: disassemble_data
arguments: data_label: D14
data_type: byte[16]

tool: {"D8": [0x00,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01]}

tool: {"D14": [0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00]}

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] = state[0UL] + state[local2];
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned char)9;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D56(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <DMY2Jul@plt>
  mov    %eax,%esi
  mov    %eax,0xc(%rsp)
  lea    D63(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x76c(%rax),%r12d
  mov    %r12d,0x4(%rsp)
  movslq %r12d,%r12
  imul   $0x3e8,%r12,%r12
  movslq 0xc(%rsp),%rax
  add    %rax,%r12
  mov    %r12,%r13
  not    %r13
  mov    %r12,%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  mov    $0x19,%ebx
L1:
  mov    %r12,%rdi
  mov    %ebx,%ecx
  shr    %cl,%rdi
  call   <Int2Mime@plt>
  mov    %al,0x0(%rbp)
  mov    %r13,%rdi
  mov    %ebx,%ecx
  shr    %cl,%rdi
  call   <Int2Mime@plt>
  mov    %al,0x6(%rbp)
  sub    $0x5,%ebx
  add    $0x1,%rbp
  cmp    $0xfffffffb,%ebx
  jne    L1
  movb   $0x0,0x1c(%rsp)
  lea    0x10(%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string
name: disassemble_data
arguments: tag: D56
datatype: string
name: disassemble_data
arguments: tag: D9
datatype: string
name: disassemble_data
arguments: tag: D40
datatype: string
name: disassemble_data
arguments: tag: D63
datatype: string
name: disassemble_data
arguments: tag: D23
datatype: string
name: disassemble_data
arguments: tag: D15
datatype: string

tool: D8: Year:

tool: D56: %i

tool: D9: Month:

tool: D40: Date of month:

tool: D63: Julian day: %i


tool: D23: 
%li


tool: D15: 
%s


assistant: ```c
main() {
  int Year, Month, Day, Count;
  unsigned long Jul, InvJul;
  char Buffer[255];
  printf("Year:");
  scanf("%i", &Year);
  printf("Month:");
  scanf("%i", &Month);
  printf("Date of month:");
  scanf("%i", &Day);
  Day = DMY2Jul(Day, Month, Year);
  printf("Julian day: %i\n", Day);
  Year -= 1900;
  Jul = 1000 * (long)Year + (long)Day;
  InvJul = ~Jul;
  printf("\n%li\n", Jul);
  for (Count = 0; Count <= 5; Count++) {
    Buffer[Count] = Int2Mime(Jul >> ((5 - Count) * 5));
    Buffer[Count + 6] = Int2Mime(InvJul >> ((5 - Count) * 5));
  }
  Buffer[Count << 1] = 0;
  printf("\n%s\n", Buffer);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D49(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  mov    $0x19,%ebx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  mov    %r14,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <DMY2Jul@plt>
  lea    D56(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D61(%rip),%rdi
  lea    -0x76c(%rax),%r12d
  movslq 0xc(%rsp),%rax
  mov    %r12d,0x4(%rsp)
  movslq %r12d,%r12
  imul   $0x3e8,%r12,%r12
  add    %rax,%r12
  xor    %eax,%eax
  mov    %r12,%r13
  mov    %r12,%rsi
  call   <printf@plt>
  not    %r13
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%ecx
  mov    %r12,%rdi
  add    $0x1,%rbp
  shr    %cl,%rdi
  call   <Int2Mime@plt>
  mov    %ebx,%ecx
  mov    %r13,%rdi
  sub    $0x5,%ebx
  mov    %al,-0x1(%rbp)
  shr    %cl,%rdi
  call   <Int2Mime@plt>
  mov    %al,0x5(%rbp)
  cmp    $0xfffffffb,%ebx
  jne    L9
  xor    %eax,%eax
  mov    %r14,%rsi
  movb   $0x0,0x1c(%rsp)
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D49
type: string
name: read_data
arguments: data_tag: D24
type: string
name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D54
type: string
name: read_data
arguments: data_tag: D56
type: string
name: read_data
arguments: data_tag: D61
type: string
name: read_data
arguments: data_tag: D23
type: string

tool: D49: Year:

tool: D24: %i

tool: D9: Month:

tool: D54: Date of month:

tool: D56: Julian day: %i


tool: D61: 
%li


tool: D23: 
%s


assistant: ```c
main() {
  int Year, Month, Day, Count;
  unsigned long Jul, InvJul;
  char Buffer[255];
  printf("Year:");
  scanf("%i", &Year);
  printf("Month:");
  scanf("%i", &Month);
  printf("Date of month:");
  scanf("%i", &Day);
  Day = DMY2Jul(Day, Month, Year);
  printf("Julian day: %i\n", Day);
  Year -= 1900;
  Jul = 1000 * (long)Year + (long)Day;
  InvJul = ~Jul;
  printf("\n%li\n", Jul);
  for (Count = 0; Count <= 5; Count++) {
    Buffer[Count] = Int2Mime(Jul >> ((5 - Count) * 5));
    Buffer[Count + 6] = Int2Mime(InvJul >> ((5 - Count) * 5));
  }
  Buffer[Count << 1] = 0;
  printf("\n%s\n", Buffer);
}
```