ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<pfork>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L35
  mov    %edi,%ebp
  mov    $0x1,%ebx
L37:
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L36
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L37
  mov    $0x0,%ebx
L36:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    $0x0,%ebx
  jmp    L36
```

assistant: ```c
int pfork(int x) {
  int j;
  for (j = 1; j < x; j++) {
    if (fork() == 0) {
      return j;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pfork>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L1
  mov    %edi,%ebx
  mov    $0x1,%r12d
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  je     L1
L0:
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L20
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L1:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int pfork(int x) {
  int j;
  for (j = 1; j < x; j++) {
    if (fork() == 0) {
      return j;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<pfork>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L5
  mov    %edi,%ebx
  mov    $0x1,%r12d
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L33:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  je     L5
L23:
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L33
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L5:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int pfork(int x) {
  int j;
  for (j = 1; j < x; j++) {
    if (fork() == 0) {
      return j;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TEA_encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r8
  mov    %esi,%r13d
  mov    %rdx,%rbx
  movslq %esi,%rax
  lea    -0x4(%rdi,%rax,4),%r12
  mov    (%r12),%ecx
  mov    $0x34,%eax
  cltd
  idiv   %esi
  imul   $0x9e3779b9,%eax,%eax
  lea    -0x4ab325aa(%rax),%r14d
  mov    $0x0,%r11d
  lea    -0x2(%rsi),%ebp
  lea    -0x1(%rsi),%r15d
L0:
  sub    $0x61c88647,%r11d
  mov    %r11d,%r9d
  sar    $0x2,%r9d
  cmp    $0x1,%r13d
  je     L7
  mov    $0x0,%edx
L4:
  mov    0x4(%r8,%rdx,4),%eax
  mov    %r9d,%esi
  xor    %edx,%esi
  and    $0x3,%esi
  mov    %ecx,%edi
  xor    (%rbx,%rsi,4),%edi
  mov    %edi,%esi
  mov    %eax,%edi
  xor    %r11d,%edi
  add    %edi,%esi
  mov    %ecx,%edi
  sar    $0x5,%edi
  lea    0x0(,%rax,4),%r10d
  xor    %r10d,%edi
  sar    $0x3,%eax
  shl    $0x4,%ecx
  xor    %ecx,%eax
  add    %eax,%edi
  xor    %edi,%esi
  mov    %esi,%ecx
  add    (%r8,%rdx,4),%ecx
  mov    %ecx,(%r8,%rdx,4)
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    %rbp,%rax
  jne    L4
  mov    %r15d,%edx
L17:
  mov    (%r8),%eax
  xor    %edx,%r9d
  and    $0x3,%r9d
  mov    %ecx,%edx
  xor    (%rbx,%r9,4),%edx
  mov    %eax,%esi
  xor    %r11d,%esi
  add    %esi,%edx
  mov    %ecx,%esi
  sar    $0x5,%esi
  lea    0x0(,%rax,4),%edi
  xor    %edi,%esi
  sar    $0x3,%eax
  shl    $0x4,%ecx
  xor    %ecx,%eax
  add    %esi,%eax
  xor    %eax,%edx
  add    (%r12),%edx
  mov    %edx,%ecx
  mov    %edx,(%r12)
  cmp    %r14d,%r11d
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    $0x0,%edx
  jmp    L17
```

assistant: ```c
void TEA_encrypt(uint32_t *v, int n, uint32_t const key[4]) {
  uint32_t y, z, sum;
  unsigned p, rounds, e;
  rounds = 6 + 52 / n;
  sum = 0;
  z = v[n - 1];
  do {
    sum += 0x9e3779b9;
    e = (sum >> 2) & 3;
    for (p = 0; p < n - 1; p++) {
      y = v[p + 1];
      z = v[p] += (((z >> 5 ^ y << 2) + (y >> 3 ^ z << 4)) ^ ((sum ^ y) + (key[(p & 3) ^ e] ^ z)));
    }
    y = v[0];
    z = v[n - 1] += (((z >> 5 ^ y << 2) + (y >> 3 ^ z << 4)) ^ ((sum ^ y) + (key[(p & 3) ^ e] ^ z)));
  } while (--rounds);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TEA_encrypt>:
  endbr64
  movslq %esi,%rax
  push   %r15
  mov    %rdi,%r8
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rax,%r13
  push   %r12
  lea    -0x4(%rdi,%rax,4),%r12
  mov    $0x34,%eax
  lea    -0x1(%r13),%r15d
  push   %rbp
  lea    -0x2(%r13),%ebp
  push   %rbx
  mov    %rdx,%rbx
  cltd
  mov    (%r12),%ecx
  idiv   %r13d
  imul   $0x9e3779b9,%eax,%eax
  sub    $0x4ab325aa,%eax
  mov    %eax,-0x4(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L20:
  lea    -0x61c88647(%r14),%r11d
  mov    %r11d,%r10d
  mov    %r11d,%r14d
  sar    $0x2,%r10d
  cmp    $0x1,%r13d
  je     L11
  xor    %edx,%edx
  nopl   0x0(%rax)
L6:
  mov    %r10d,%esi
  mov    0x4(%r8,%rdx,4),%eax
  xor    %edx,%esi
  and    $0x3,%esi
  lea    0x0(,%rax,4),%r9d
  mov    (%rbx,%rsi,4),%edi
  xor    %ecx,%edi
  mov    %edi,%esi
  mov    %eax,%edi
  sar    $0x3,%eax
  xor    %r11d,%edi
  add    %edi,%esi
  mov    %ecx,%edi
  shl    $0x4,%ecx
  sar    $0x5,%edi
  xor    %ecx,%eax
  mov    (%r8,%rdx,4),%ecx
  xor    %r9d,%edi
  add    %eax,%edi
  mov    %rdx,%rax
  xor    %edi,%esi
  add    %esi,%ecx
  mov    %ecx,(%r8,%rdx,4)
  add    $0x1,%rdx
  cmp    %rax,%rbp
  jne    L6
  xor    %r15d,%r10d
L11:
  mov    (%r8),%eax
  mov    %ecx,%edx
  mov    %ecx,%edi
  and    $0x3,%r10d
  sar    $0x5,%edx
  shl    $0x4,%edi
  xor    (%rbx,%r10,4),%ecx
  lea    0x0(,%rax,4),%esi
  xor    %esi,%edx
  mov    %eax,%esi
  xor    %r11d,%eax
  sar    $0x3,%esi
  add    %eax,%ecx
  xor    %edi,%esi
  add    %esi,%edx
  mov    %edx,%eax
  xor    %ecx,%eax
  add    (%r12),%eax
  mov    %eax,(%r12)
  mov    %eax,%ecx
  cmp    %r11d,-0x4(%rsp)
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void TEA_encrypt(uint32_t *v, int n, uint32_t const key[4]) {
  uint32_t y, z, sum;
  unsigned p, rounds, e;
  rounds = 6 + 52 / n;
  sum = 0;
  z = v[n - 1];
  do {
    sum += 0x9e3779b9;
    e = (sum >> 2) & 3;
    for (p = 0; p < n - 1; p++) {
      y = v[p + 1];
      z = v[p] += (((z >> 5 ^ y << 2) + (y >> 3 ^ z << 4)) ^ ((sum ^ y) + (key[(p & 3) ^ e] ^ z)));
    }
    y = v[0];
    z = v[n - 1] += (((z >> 5 ^ y << 2) + (y >> 3 ^ z << 4)) ^ ((sum ^ y) + (key[(p & 3) ^ e] ^ z)));
  } while (--rounds);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<matvec4_c>:
  endbr64
  movss  (%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x10(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x20(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x30(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x34(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x38(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  movss  0xc(%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x1c(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x2c(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x3c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdx)
  ret
```

assistant: ```c
void matvec4_c(float m[16], float v[4], float d[4]) {
  d[0] = m[0] * v[0] + m[4] * v[1] + m[8] * v[2] + m[12] * v[3];
  d[1] = m[1] * v[0] + m[5] * v[1] + m[9] * v[2] + m[13] * v[3];
  d[2] = m[2] * v[0] + m[6] * v[1] + m[10] * v[2] + m[14] * v[3];
  d[3] = m[3] * v[0] + m[7] * v[1] + m[11] * v[2] + m[15] * v[3];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<matvec4_c>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x10(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x20(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x30(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x34(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x38(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  movss  0xc(%rdi),%xmm0
  movss  0x1c(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x2c(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x3c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdx)
  ret
```

assistant: ```c
void matvec4_c(float m[16], float v[4], float d[4]) {
  d[0] = m[0] * v[0] + m[4] * v[1] + m[8] * v[2] + m[12] * v[3];
  d[1] = m[1] * v[0] + m[5] * v[1] + m[9] * v[2] + m[13] * v[3];
  d[2] = m[2] * v[0] + m[6] * v[1] + m[10] * v[2] + m[14] * v[3];
  d[3] = m[3] * v[0] + m[7] * v[1] + m[11] * v[2] + m[15] * v[3];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matvec4_c>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x10(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x20(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x30(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x34(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x38(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  movss  0xc(%rdi),%xmm0
  movss  0x1c(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x2c(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x3c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdx)
  ret
```

assistant: ```c
void matvec4_c(float m[16], float v[4], float d[4]) {
  d[0] = m[0] * v[0] + m[4] * v[1] + m[8] * v[2] + m[12] * v[3];
  d[1] = m[1] * v[0] + m[5] * v[1] + m[9] * v[2] + m[13] * v[3];
  d[2] = m[2] * v[0] + m[6] * v[1] + m[10] * v[2] + m[14] * v[3];
  d[3] = m[3] * v[0] + m[7] * v[1] + m[11] * v[2] + m[15] * v[3];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <exit_application@plt>
  mov    $0x0,%eax
  call   <__builtin_unreachable@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  exit_application();
  __builtin_unreachable();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <exit_application@plt>
  mov    $0x0,%eax
  call   <__builtin_unreachable@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  exit_application();
  __builtin_unreachable();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <exit_application@plt>
  xor    %eax,%eax
  call   <__builtin_unreachable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  exit_application();
  __builtin_unreachable();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <exit_application@plt>
  xor    %eax,%eax
  call   <__builtin_unreachable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  exit_application();
  __builtin_unreachable();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tinf_build_bits_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L40
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L40:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L14
  movl   $0x0,-0x8(%rbp)
  jmp    L59
L5:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L59:
  mov    $0x1e,%eax
  sub    -0x24(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L5
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L58
L30:
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L58:
  cmpl   $0x1d,-0x8(%rbp)
  jle    L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tinf_build_bits_base(unsigned char *bits, unsigned short *base, int delta, int first) {
  int i, sum;
  for (i = 0; i < delta; ++i)
    bits[i] = 0;
  for (i = 0; i < 30 - delta; ++i)
    bits[i + delta] = i / delta;
  for (sum = first, i = 0; i < 30; ++i) {
    base[i] = sum;
    sum += 1 << bits[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<tinf_build_bits_base>:
  endbr64
  mov    %rsi,%r8
  mov    %edx,%r9d
  mov    %ecx,%esi
  test   %edx,%edx
  jle    L42
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L2:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L2
L42:
  cmp    $0x1e,%r9d
  jge    L5
  mov    $0x1e,%r11d
  sub    %r9d,%r11d
  mov    $0x0,%ecx
  movslq %r9d,%r10
  add    %rdi,%r10
L47:
  mov    %ecx,%eax
  cltd
  idiv   %r9d
  mov    %al,(%r10,%rcx,1)
  add    $0x1,%rcx
  cmp    %r11,%rcx
  jne    L47
L5:
  mov    $0x0,%eax
  mov    $0x1,%r9d
L7:
  mov    %si,(%r8,%rax,2)
  movzbl (%rdi,%rax,1),%ecx
  mov    %r9d,%edx
  shl    %cl,%edx
  add    %edx,%esi
  add    $0x1,%rax
  cmp    $0x1e,%rax
  jne    L7
  ret
```

assistant: ```c
void tinf_build_bits_base(unsigned char *bits, unsigned short *base, int delta, int first) {
  int i, sum;
  for (i = 0; i < delta; ++i)
    bits[i] = 0;
  for (i = 0; i < 30 - delta; ++i)
    bits[i + delta] = i / delta;
  for (sum = first, i = 0; i < 30; ++i) {
    base[i] = sum;
    sum += 1 << bits[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tinf_build_bits_base>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  test   %edx,%edx
  jle    L1
  movslq %edx,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rdi
L1:
  mov    $0x1e,%esi
  sub    %r12d,%esi
  test   %esi,%esi
  jle    L34
  movslq %r12d,%rdx
  movslq %esi,%rsi
  xor    %ecx,%ecx
  lea    (%rdi,%rdx,1),%r8
  nopl   0x0(%rax)
L10:
  mov    %ecx,%eax
  cltd
  idiv   %r12d
  mov    %al,(%r8,%rcx,1)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L10
L34:
  xor    %eax,%eax
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %bx,0x0(%rbp,%rax,2)
  movzbl (%rdi,%rax,1),%ecx
  mov    %esi,%edx
  add    $0x1,%rax
  shl    %cl,%edx
  add    %edx,%ebx
  cmp    $0x1e,%rax
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void tinf_build_bits_base(unsigned char *bits, unsigned short *base, int delta, int first) {
  int i, sum;
  for (i = 0; i < delta; ++i)
    bits[i] = 0;
  for (i = 0; i < 30 - delta; ++i)
    bits[i + delta] = i / delta;
  for (sum = first, i = 0; i < 30; ++i) {
    base[i] = sum;
    sum += 1 << bits[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tinf_build_bits_base>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rdi
L2:
  mov    $0x1e,%esi
  sub    %r12d,%esi
  test   %esi,%esi
  jle    L12
  movslq %r12d,%rdx
  movslq %esi,%rsi
  xor    %ecx,%ecx
  lea    (%rdi,%rdx,1),%r8
  nopl   0x0(%rax)
L24:
  mov    %ecx,%eax
  cltd
  idiv   %r12d
  mov    %al,(%r8,%rcx,1)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L24
L12:
  xor    %eax,%eax
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %bx,0x0(%rbp,%rax,2)
  movzbl (%rdi,%rax,1),%ecx
  mov    %esi,%edx
  add    $0x1,%rax
  shl    %cl,%edx
  add    %edx,%ebx
  cmp    $0x1e,%rax
  jne    L39
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void tinf_build_bits_base(unsigned char *bits, unsigned short *base, int delta, int first) {
  int i, sum;
  for (i = 0; i < delta; ++i)
    bits[i] = 0;
  for (i = 0; i < 30 - delta; ++i)
    bits[i + delta] = i / delta;
  for (sum = first, i = 0; i < 30; ++i) {
    base[i] = sum;
    sum += 1 << bits[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clearDrivers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void clearDrivers(char **d) {
  int index = 0;
  while (d[index]) {
    free(d[index]);
    d[index++] = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clearDrivers>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L6
L12:
  call   <free@plt>
  movq   $0x0,(%rbx)
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L12
L6:
  pop    %rbx
  ret
```

assistant: ```c
void clearDrivers(char **d) {
  int index = 0;
  while (d[index]) {
    free(d[index]);
    d[index++] = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clearDrivers>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L2
L1:
  call   <free@plt>
  add    $0x8,%rbx
  movq   $0x0,-0x8(%rbx)
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L1
L2:
  pop    %rbx
  ret
```

assistant: ```c
void clearDrivers(char **d) {
  int index = 0;
  while (d[index]) {
    free(d[index]);
    d[index++] = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clearDrivers>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L13
L15:
  call   <free@plt>
  add    $0x8,%rbx
  movq   $0x0,-0x8(%rbx)
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L15
L13:
  pop    %rbx
  ret
```

assistant: ```c
void clearDrivers(char **d) {
  int index = 0;
  while (d[index]) {
    free(d[index]);
    d[index++] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<a52e_set_substreamid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  and    $0xffffffc7,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  and    $0x38,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void a52e_set_substreamid(uint8_t *p_a52, uint8_t i_substreamid) {
  p_a52[2] &= ~0x38;
  p_a52[2] |= (i_substreamid & 0x7) << 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<a52e_set_substreamid>:
  endbr64
  mov    0x8(%rdi),%eax
  and    $0xffffffc7,%eax
  shl    $0x3,%esi
  and    $0x38,%esi
  or     %esi,%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void a52e_set_substreamid(uint8_t *p_a52, uint8_t i_substreamid) {
  p_a52[2] &= ~0x38;
  p_a52[2] |= (i_substreamid & 0x7) << 3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<a52e_set_substreamid>:
  endbr64
  mov    0x8(%rdi),%eax
  shl    $0x3,%esi
  and    $0x38,%esi
  and    $0xffffffc7,%eax
  or     %esi,%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void a52e_set_substreamid(uint8_t *p_a52, uint8_t i_substreamid) {
  p_a52[2] &= ~0x38;
  p_a52[2] |= (i_substreamid & 0x7) << 3;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<a52e_set_substreamid>:
  endbr64
  mov    0x8(%rdi),%eax
  shl    $0x3,%esi
  and    $0x38,%esi
  and    $0xffffffc7,%eax
  or     %esi,%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void a52e_set_substreamid(uint8_t *p_a52, uint8_t i_substreamid) {
  p_a52[2] &= ~0x38;
  p_a52[2] |= (i_substreamid & 0x7) << 3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<opencurses>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <cbreak@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void opencurses(void) {
  initscr();
  cbreak();
  noecho();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<opencurses>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <cbreak@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void opencurses(void) {
  initscr();
  cbreak();
  noecho();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<opencurses>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <cbreak@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <noecho@plt>
```

assistant: ```c
void opencurses(void) {
  initscr();
  cbreak();
  noecho();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<opencurses>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <cbreak@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <noecho@plt>
```

assistant: ```c
void opencurses(void) {
  initscr();
  cbreak();
  noecho();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ffmodf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  jmp    L17
L14:
  movss  -0x4(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
L17:
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jae    L14
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float ffmodf(float a, float b) {
  while (a >= b)
    a -= b;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ffmodf>:
  endbr64
  comiss %xmm1,%xmm0
  jb     L10
L4:
  subss  %xmm1,%xmm0
  comiss %xmm1,%xmm0
  jae    L4
L10:
  ret
```

assistant: ```c
float ffmodf(float a, float b) {
  while (a >= b)
    a -= b;
  return a;
}
```