user: What would the C source look like for the assembly code provided here:

```asm
<setShortNameSequence>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L37
  movslq %esi,%r10
  xor    %edx,%edx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  jmp    L166
  nopl   0x0(%rax)
L121:
  test   %edx,%edx
  je     L61
  movzbl -0x1(%rdi,%rdx,1),%ecx
  mov    %ecx,%r11d
  and    $0x3,%r11d
  cmp    $0x2,%r11b
  jne    L119
  shl    $0x4,%ecx
  and    $0xfc0,%ecx
  add    %ecx,%eax
L119:
  cmp    %eax,%r9d
  cmovl  %eax,%r9d
L48:
  add    $0x1,%rdx
  add    $0x1,%r8d
  cmp    %rdx,%r10
  je     L106
L166:
  movzbl (%rdi,%rdx,1),%eax
  shr    $0x2,%al
  movzbl %al,%eax
  test   %eax,%eax
  jne    L121
L61:
  cmp    %eax,%r9d
  cmovl  %eax,%r9d
  test   %eax,%eax
  jne    L48
  add    $0x1,%rdx
  cmp    %rdx,%r10
  jne    L166
L106:
  lea    0x1(%r9),%r12d
  cmp    %r9d,%r8d
  jge    L32
  movzbl (%rdi),%r10d
  xor    %r12d,%r12d
  shr    $0x2,%r10b
  movzbl %r10b,%r10d
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %r10d,%ecx
  mov    $0x1,%edx
  jmp    L134
  nopw   0x0(%rax,%rax,1)
L122:
  movzbl -0x1(%rdi,%rdx,1),%eax
  mov    %eax,%r8d
  and    $0x3,%r8d
  cmp    $0x2,%r8b
  jne    L68
  shl    $0x4,%eax
  and    $0xfc0,%eax
  add    %eax,%ecx
  nopl   0x0(%rax)
L68:
  add    $0x1,%rdx
L134:
  cmp    %edx,%esi
  jle    L150
  cmp    %r12d,%ecx
  je     L115
  movzbl (%rdi,%rdx,1),%eax
  shr    $0x2,%al
  movzbl %al,%ecx
  jne    L122
  xor    %ecx,%ecx
  jmp    L68
  nopl   (%rax)
L115:
  add    $0x1,%r12d
  cmp    %r9d,%r12d
  jl     L33
  mov    %ecx,%r12d
  jmp    L32
  xchg   %ax,%ax
L150:
  cmp    %r12d,%ecx
  je     L115
L32:
  mov    %rsp,%rbp
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    D9(%rip),%rsi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  sub    %rdx,%rbx
  xor    %edx,%edx
  lea    0x7(%rbx),%rsi
  movb   $0x7e,(%rsi)
  test   %eax,%eax
  jle    L206
  nopl   0x0(%rax)
L105:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,0x1(%rsi,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L105
L206:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    $0x1,%r12d
  jmp    L32
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9: %d

assistant: ```c
int setShortNameSequence(unsigned char *entry, int maxEntry, unsigned char *sname) {
  char number[8];
  unsigned char *buf;
  int i, j;
  int maxSeq;
  int hit;
  int seq;
  int cont;
  seq = 0;
  maxSeq = 0;
  hit = 0;
  for (i = 0; i < maxEntry; i++) {
    seq = (entry[i] & 0xFC) >> 2;
    if (seq && i && (entry[i - 1] & 0x03) == 2) {
      seq += (entry[i - 1] & 0xFC) << 4;
    }
    if (seq > maxSeq)
      maxSeq = seq;
    if (seq)
      hit++;
  }
  if (hit < maxSeq) {
    cont = 1;
    for (j = 0; j < maxSeq && cont; j++) {
      for (i = 0; i < maxEntry && cont; i++) {
        seq = (entry[i] & 0xFC) >> 2;
        if (seq && i && (entry[i - 1] & 0x03) == 2) {
          seq += (entry[i - 1] & 0xFC) << 4;
        }
        if (seq == j)
          cont = 0;
      }
      if (cont == 1) {
        seq = j;
      }
      cont = 1 - cont;
    }
  } else {
    seq = maxSeq + 1;
  }
  memset(number, 0, 8);
  sprintf(number, "%d", seq);
  j = strlen(number);
  buf = sname + 7 - j;
  buf[0] = '~';
  buf++;
  for (i = 0; i < j; i++)
    buf[i] = number[i];
  return 0;
}
```