user: 请从给定的汇编指令推导出C源代码：

```asm
<diff_long>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rsi,%r14
  mov    %edx,%esi
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x88(%rsp)
  xor    %edx,%edx
  cmp    $0x3,%esi
  jbe    L24
  mov    %rdi,%rbx
  mov    %ecx,%eax
  shr    $0x2,%eax
  mov    %eax,0x14(%rsp)
  lea    -0x1(%rax),%eax
  lea    (%rax,%rax,8),%rdx
  lea    0x42(%rsp,%rdx,1),%rcx
  mov    %rcx,0x20(%rsp)
  lea    0x9(%rax,%rax,8),%rax
  lea    0x30(%rsp,%rax,1),%rax
  mov    %rax,0x28(%rsp)
  mov    $0x20,%r15d
  jmp    L148
L32:
  mov    0x14(%rsp),%eax
  mov    %eax,0x8(%rsp)
  lea    0x30(%rsp),%r8
  jmp    L179
L61:
  lea    0x2(%r8),%rax
  movb   $0x20,0x1(%r8)
  jmp    L109
L118:
  add    $0x1,%rax
  mov    %sil,-0x1(%rax)
  shl    $0x4,%edx
  shl    $0x4,%ecx
  cmp    %rax,%r8
  je     L64
L102:
  mov    %r15d,%esi
  mov    %edx,%edi
  and    $0xf0000000,%edi
  je     L118
  mov    %r11d,%esi
  mov    %edi,%r10d
  and    %ecx,%r10d
  je     L118
  cmp    %edi,%r10d
  mov    %ebp,%esi
  cmove  %r12d,%esi
  jmp    L118
L64:
  lea    0x1(%r9),%rax
  cmp    %r9,%r13
  je     L83
  mov    %rax,%r9
L166:
  mov    (%rbx,%r9,4),%ecx
  mov    %ecx,%edx
  xor    (%r14,%r9,4),%edx
  lea    0x1(%r8),%rax
  movb   $0x20,(%r8)
  mov    0x8(%rsp),%esi
  add    %r9d,%esi
  cmp    $0x4,%esi
  je     L61
L109:
  lea    0x8(%rax),%r8
  jmp    L102
L83:
  mov    0x18(%rsp),%rax
  shl    $0x2,%rax
  add    %rax,%rbx
  add    %rax,%r14
L66:
  movb   $0x0,(%r8)
  lea    0x30(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  shl    $0x2,%eax
  sub    %eax,0xc(%rsp)
  mov    0xc(%rsp),%ecx
  cmp    $0x3,%ecx
  jbe    L24
L148:
  mov    0xc(%rsp),%ecx
  shr    $0x2,%ecx
  mov    $0x8,%eax
  cmp    %eax,%ecx
  cmovbe %ecx,%eax
  mov    %eax,0x10(%rsp)
  cmpl   $0x0,0x14(%rsp)
  je     L32
  lea    0x39(%rsp),%rdx
  mov    0x20(%rsp),%rcx
L11:
  lea    -0x9(%rdx),%rax
L169:
  add    $0x1,%rax
  movb   $0x20,-0x1(%rax)
  cmp    %rdx,%rax
  jne    L169
  add    $0x9,%rdx
  cmp    %rcx,%rdx
  jne    L11
  mov    0x28(%rsp),%r8
  mov    0x14(%rsp),%eax
  mov    %eax,0x8(%rsp)
L179:
  mov    0x10(%rsp),%eax
  mov    0x8(%rsp),%ecx
  cmp    %ecx,%eax
  jbe    L66
  lea    -0x1(%rax),%r13d
  sub    %ecx,%r13d
  lea    0x1(%r13),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%r9d
  mov    $0x5e,%r11d
  mov    $0x76,%r12d
  mov    $0x2d,%ebp
  jmp    L166
L24:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string

tool: D7:          %s


assistant: ```c
void diff_long(unsigned char *src1, unsigned char *src2, unsigned cnt, unsigned skip) {
  unsigned char buf[8 * 9 + 2];
  unsigned *s1 = (unsigned *)src1;
  unsigned *s2 = (unsigned *)src2;
  unsigned i, j;
  while (cnt >= 4) {
    char *p = buf;
    unsigned max = (((cnt >> 2) < (8)) ? (cnt >> 2) : (8));
    for (i = 0; i < (skip >> 2); i++) {
      for (j = 0; j < 9; j++)
        *p++ = ' ';
    }
    for (; i < max; i++) {
      unsigned s1v = *s1++;
      unsigned diff = s1v ^ *s2++;
      unsigned c;
      *p++ = ' ';
      if (i == 4)
        *p++ = ' ';
      for (j = 0; j < 8; j++) {
        unsigned changed = diff & 0xf0000000;
        c = ' ';
        if (changed) {
          if ((s1v & changed) == 0)
            c = '^';
          else if ((s1v & changed) == changed)
            c = 'v';
          else
            c = '-';
        }
        *p++ = c;
        diff <<= 4;
        s1v <<= 4;
      }
    }
    *p = 0;
    printf("         %s\n", buf);
    cnt -= max << 2;
  }
}
```