ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<BSP_UART_SendByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L53
  nop
L30:
  mov    $0x50000010,%eax
  mov    (%rax),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L30
  mov    $0x50000020,%edx
  movzbl -0x8(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L49
L53:
  cmpl   $0x1,-0x4(%rbp)
  jne    L18
  nop
L63:
  mov    $0x50004010,%eax
  mov    (%rax),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L63
  mov    $0x50004020,%edx
  movzbl -0x8(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L49
L18:
  nop
L39:
  mov    $0x50008010,%eax
  mov    (%rax),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L39
  mov    $0x50008020,%edx
  movzbl -0x8(%rbp),%eax
  mov    %al,(%rdx)
L49:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BSP_UART_SendByte(unsigned int port, unsigned char byte) {
  if (port == 0) {
    while (!((*(volatile unsigned *)0X50000010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50000020) = byte;
  } else if (port == 1) {
    while (!((*(volatile unsigned *)0X50004010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50004020) = byte;
  } else {
    while (!((*(volatile unsigned *)0X50008010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50008020) = byte;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<BSP_UART_SendByte>:
  endbr64
  test   %edi,%edi
  jne    L14
L43:
  mov    0x50000010,%eax
  test   $0x4,%al
  je     L43
  mov    %sil,0x50000020
  ret
L14:
  cmp    $0x1,%edi
  je     L48
L22:
  mov    0x50008010,%eax
  test   $0x4,%al
  je     L22
  mov    %sil,0x50008020
  ret
L48:
  mov    0x50004010,%eax
  test   $0x4,%al
  je     L48
  mov    %sil,0x50004020
  ret
```

assistant: ```c
void BSP_UART_SendByte(unsigned int port, unsigned char byte) {
  if (port == 0) {
    while (!((*(volatile unsigned *)0X50000010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50000020) = byte;
  } else if (port == 1) {
    while (!((*(volatile unsigned *)0X50004010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50004020) = byte;
  } else {
    while (!((*(volatile unsigned *)0X50008010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50008020) = byte;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BSP_UART_SendByte>:
  endbr64
  test   %edi,%edi
  je     L4
  cmp    $0x1,%edi
  je     L37
  nopl   (%rax)
L35:
  mov    0x50008010,%eax
  test   $0x4,%al
  je     L35
  mov    %sil,0x50008020
  ret
  nopl   0x0(%rax)
L4:
  mov    0x50000010,%eax
  test   $0x4,%al
  je     L4
  mov    %sil,0x50000020
  ret
  nopl   0x0(%rax)
L37:
  mov    0x50004010,%eax
  test   $0x4,%al
  je     L37
  mov    %sil,0x50004020
  ret
```

assistant: ```c
void BSP_UART_SendByte(unsigned int port, unsigned char byte) {
  if (port == 0) {
    while (!((*(volatile unsigned *)0X50000010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50000020) = byte;
  } else if (port == 1) {
    while (!((*(volatile unsigned *)0X50004010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50004020) = byte;
  } else {
    while (!((*(volatile unsigned *)0X50008010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50008020) = byte;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<BSP_UART_SendByte>:
  endbr64
  test   %edi,%edi
  je     L30
  cmp    $0x1,%edi
  je     L5
  nopl   (%rax)
L28:
  mov    0x50008010,%eax
  test   $0x4,%al
  je     L28
  mov    %sil,0x50008020
  ret
  nopl   0x0(%rax)
L30:
  mov    0x50000010,%eax
  test   $0x4,%al
  je     L30
  mov    %sil,0x50000020
  ret
  nopl   0x0(%rax)
L5:
  mov    0x50004010,%eax
  test   $0x4,%al
  je     L5
  mov    %sil,0x50004020
  ret
```

assistant: ```c
void BSP_UART_SendByte(unsigned int port, unsigned char byte) {
  if (port == 0) {
    while (!((*(volatile unsigned *)0X50000010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50000020) = byte;
  } else if (port == 1) {
    while (!((*(volatile unsigned *)0X50004010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50004020) = byte;
  } else {
    while (!((*(volatile unsigned *)0X50008010) & 0X04))
      ;
    (*(volatile unsigned char *)0X50008020) = byte;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x17447d68,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  add    $0x342de53e,%rax
  ror    $0xb,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          state[0UL] |= (state[0UL] & 15UL) << 3UL;
          state[local1] |= (state[local1] * state[0UL] & 15UL) << 3UL;
        } else {
          copy11 = *((unsigned int *)(&state[local1]) + 0);
          *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
          *((unsigned int *)(&state[local1]) + 1) = copy11;
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else if (state[0UL] > local1) {
        state[local1] = state[0UL] + state[local1];
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      } else {
        state[0UL] |= state[local1];
      }
      local1++;
    }
    output[0UL] = ((state[0UL] + 875423038UL) >> 11UL) | ((state[0UL] + 875423038UL) << 53UL);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x1ce967d6,%rax
  ror    $0xb,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          state[0UL] |= (state[0UL] & 15UL) << 3UL;
          state[local1] |= (state[local1] * state[0UL] & 15UL) << 3UL;
        } else {
          copy11 = *((unsigned int *)(&state[local1]) + 0);
          *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
          *((unsigned int *)(&state[local1]) + 1) = copy11;
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else if (state[0UL] > local1) {
        state[local1] = state[0UL] + state[local1];
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      } else {
        state[0UL] |= state[local1];
      }
      local1++;
    }
    output[0UL] = ((state[0UL] + 875423038UL) >> 11UL) | ((state[0UL] + 875423038UL) << 53UL);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x1ce967d6,%rax
  ror    $0xb,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          state[0UL] |= (state[0UL] & 15UL) << 3UL;
          state[local1] |= (state[local1] * state[0UL] & 15UL) << 3UL;
        } else {
          copy11 = *((unsigned int *)(&state[local1]) + 0);
          *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
          *((unsigned int *)(&state[local1]) + 1) = copy11;
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else if (state[0UL] > local1) {
        state[local1] = state[0UL] + state[local1];
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      } else {
        state[0UL] |= state[local1];
      }
      local1++;
    }
    output[0UL] = ((state[0UL] + 875423038UL) >> 11UL) | ((state[0UL] + 875423038UL) << 53UL);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x1ce967d6,%rax
  ror    $0xb,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          state[0UL] |= (state[0UL] & 15UL) << 3UL;
          state[local1] |= (state[local1] * state[0UL] & 15UL) << 3UL;
        } else {
          copy11 = *((unsigned int *)(&state[local1]) + 0);
          *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
          *((unsigned int *)(&state[local1]) + 1) = copy11;
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else if (state[0UL] > local1) {
        state[local1] = state[0UL] + state[local1];
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      } else {
        state[0UL] |= state[local1];
      }
      local1++;
    }
    output[0UL] = ((state[0UL] + 875423038UL) >> 11UL) | ((state[0UL] + 875423038UL) << 53UL);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cput_hex_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sar    $0x18,%rax
  mov    %rax,%rdi
  call   <cput_hex_byte@plt>
  mov    -0x8(%rbp),%rax
  sar    $0x10,%rax
  mov    %rax,%rdi
  call   <cput_hex_byte@plt>
  mov    -0x8(%rbp),%rax
  sar    $0x8,%rax
  mov    %rax,%rdi
  call   <cput_hex_byte@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cput_hex_byte@plt>
  nop
  leave
  ret
```

assistant: ```c
void cput_hex_long(long int n) {
  cput_hex_byte(n >> 24);
  cput_hex_byte(n >> 16);
  cput_hex_byte(n >> 8);
  cput_hex_byte(n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cput_hex_long>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sar    $0x18,%rdi
  call   <cput_hex_byte@plt>
  mov    %rbx,%rdi
  sar    $0x10,%rdi
  call   <cput_hex_byte@plt>
  mov    %rbx,%rdi
  sar    $0x8,%rdi
  call   <cput_hex_byte@plt>
  mov    %rbx,%rdi
  call   <cput_hex_byte@plt>
  pop    %rbx
  ret
```

assistant: ```c
void cput_hex_long(long int n) {
  cput_hex_byte(n >> 24);
  cput_hex_byte(n >> 16);
  cput_hex_byte(n >> 8);
  cput_hex_byte(n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cput_hex_long>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sar    $0x18,%rdi
  call   <cput_hex_byte@plt>
  mov    %rbp,%rdi
  sar    $0x10,%rdi
  call   <cput_hex_byte@plt>
  mov    %rbp,%rdi
  sar    $0x8,%rdi
  call   <cput_hex_byte@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <cput_hex_byte@plt>
```

assistant: ```c
void cput_hex_long(long int n) {
  cput_hex_byte(n >> 24);
  cput_hex_byte(n >> 16);
  cput_hex_byte(n >> 8);
  cput_hex_byte(n);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x5,-0x4(%rbp)
  jmp    L5
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  cmpl   $0x6,-0x4(%rbp)
  jle    L1
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string
name: extract_symbolic_data
arguments: label: D28
type: string
name: extract_symbolic_data
arguments: label: D0
type: string

tool: D6: n = %d


tool: D28: Now n = %d


tool: D0: The loop has finished.

assistant: ```c
int main(int argc, char const *argv[]) {
  int n = 5;
  while (n < 7) {
    printf("n = %d\n", n);
    n++;
    printf("Now n = %d\n", n);
  }
  printf("The loop has finished.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D21(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D21
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D29
type_guessed: string

tool: D14: n = %d


tool: D21: Now n = %d


tool: D29: The loop has finished.

assistant: ```c
int main(int argc, char const *argv[]) {
  int n = 5;
  while (n < 7) {
    printf("n = %d\n", n);
    n++;
    printf("Now n = %d\n", n);
  }
  printf("The loop has finished.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%r12
  mov    $0x5,%esi
  xor    %eax,%eax
  push   %rbp
  mov    %r12,%rdi
  lea    D19(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x6,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x7,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D25
type: string
name: parse_data
arguments: tag: D19
type: string
name: parse_data
arguments: tag: D24
type: string

tool: D25: n = %d


tool: D19: Now n = %d


tool: D24: The loop has finished.

assistant: ```c
int main(int argc, char const *argv[]) {
  int n = 5;
  while (n < 7) {
    printf("n = %d\n", n);
    n++;
    printf("Now n = %d\n", n);
  }
  printf("The loop has finished.\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  mov    $0x5,%esi
  xor    %eax,%eax
  push   %rbp
  mov    %r12,%rdi
  lea    D20(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x6,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x7,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string
name: extract_symbolic_data
arguments: tag: D26
type_infered: string

tool: D9: n = %d


tool: D20: Now n = %d


tool: D26: The loop has finished.

assistant: ```c
int main(int argc, char const *argv[]) {
  int n = 5;
  while (n < 7) {
    printf("n = %d\n", n);
    n++;
    printf("Now n = %d\n", n);
  }
  printf("The loop has finished.\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzbl %al,%ecx
  mov    $0x4,%eax
  mov    $0x0,%edx
  div    %ecx
  cmp    $0x5,%eax
  jne    L2
  mov    $0x0,%eax
  call   <link_error@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void f3(unsigned int a) {
  if (4 / (a & 0xff) == 5)
    link_error();
}
```
user: What is the c source code of the assembly code below:

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
void f3(unsigned int a) {
  if (4 / (a & 0xff) == 5)
    link_error();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
void f3(unsigned int a) {
  if (4 / (a & 0xff) == 5)
    link_error();
}
```
user: Translate the below assembly code into C programming language:

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
void f3(unsigned int a) {
  if (4 / (a & 0xff) == 5)
    link_error();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<blockfd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D24(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L9
L10:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int blockfd(int fd) {
  int flags = fcntl(fd, F_GETFL, 0);
  return fcntl(fd, F_SETFL, flags & ~O_NONBLOCK) == -1 ? -1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<blockfd>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    D18(%rip),%rdx
  mov    (%rdx),%edx
  not    %edx
  and    %eax,%edx
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  pop    %rbx
  ret
```

assistant: ```c
int blockfd(int fd) {
  int flags = fcntl(fd, F_GETFL, 0);
  return fcntl(fd, F_SETFL, flags & ~O_NONBLOCK) == -1 ? -1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<blockfd>:
  endbr64
  mov    D17(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    D22(%rip),%rdx
  mov    %ebp,%edi
  mov    (%rdx),%edx
  not    %edx
  and    %eax,%edx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  pop    %rbp
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int blockfd(int fd) {
  int flags = fcntl(fd, F_GETFL, 0);
  return fcntl(fd, F_SETFL, flags & ~O_NONBLOCK) == -1 ? -1 : 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<blockfd>:
  endbr64
  mov    D29(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    D1(%rip),%rdx
  mov    %ebp,%edi
  mov    (%rdx),%edx
  not    %edx
  and    %eax,%edx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  pop    %rbp
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int blockfd(int fd) {
  int flags = fcntl(fd, F_GETFL, 0);
  return fcntl(fd, F_SETFL, flags & ~O_NONBLOCK) == -1 ? -1 : 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bufferizeNeigh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L44:
  movl   $0x0,-0x10(%rbp)
  jmp    L53
L6:
  movl   $0x0,-0x14(%rbp)
  jmp    L60
L2:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L39
  mov    $0x1,%ecx
  jmp    L18
L39:
  mov    $0xffffffff,%ecx
L18:
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  add    %esi,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,(%rax)
  addl   $0x1,-0x14(%rbp)
L60:
  cmpl   $0x2,-0x14(%rbp)
  jle    L2
  addl   $0x1,-0x10(%rbp)
L53:
  cmpl   $0x2,-0x10(%rbp)
  jle    L6
  addl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x2,-0xc(%rbp)
  jle    L44
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bufferizeNeigh(unsigned char *vol, int idx, int nb[27], const int volNeigh[27]) {
  int nidx;
  int i, j, k, ii;
  ii = 0;
  for (k = 0; k < 3; k++)
    for (j = 0; j < 3; j++)
      for (i = 0; i < 3; i++) {
        nidx = idx + volNeigh[ii++];
        nb[((j) * (3) + (i) + (k) * (3) * (3))] = (vol[nidx] != 0) ? 1 : -1;
      }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bufferizeNeigh>:
  endbr64
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%r10d
  mov    $0x0,%ebx
  jmp    L44
L37:
  add    $0x3,%r9d
  add    $0xc,%r8
  add    $0xc,%rdi
  cmp    $0x9,%r9d
  je     L40
L42:
  mov    $0x0,%eax
L0:
  mov    %r10d,%esi
  add    (%rdi,%rax,1),%esi
  movslq %esi,%rsi
  cmpb   $0x1,(%r11,%rsi,1)
  sbb    %esi,%esi
  or     $0x1,%esi
  mov    %esi,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L0
  jmp    L37
L40:
  add    $0x9,%rbx
  cmp    $0x1b,%rbx
  je     L46
L44:
  lea    0x0(,%rbx,4),%rdi
  lea    (%rdx,%rdi,1),%r8
  add    %rcx,%rdi
  mov    $0x0,%r9d
  jmp    L42
L46:
  pop    %rbx
  ret
```

assistant: ```c
void bufferizeNeigh(unsigned char *vol, int idx, int nb[27], const int volNeigh[27]) {
  int nidx;
  int i, j, k, ii;
  ii = 0;
  for (k = 0; k < 3; k++)
    for (j = 0; j < 3; j++)
      for (i = 0; i < 3; i++) {
        nidx = idx + volNeigh[ii++];
        nb[((j) * (3) + (i) + (k) * (3) * (3))] = (vol[nidx] != 0) ? 1 : -1;
      }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bufferizeNeigh>:
  endbr64
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%r10d
  xor    %ebx,%ebx
L18:
  lea    0x0(,%rbx,4),%rdi
  xor    %r9d,%r9d
  lea    (%rdx,%rdi,1),%r8
  add    %rcx,%rdi
L1:
  xor    %eax,%eax
L0:
  mov    (%rdi,%rax,1),%esi
  add    %r10d,%esi
  movslq %esi,%rsi
  cmpb   $0x1,(%r11,%rsi,1)
  sbb    %esi,%esi
  or     $0x1,%esi
  mov    %esi,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L0
  add    $0x3,%r9d
  add    $0xc,%r8
  add    $0xc,%rdi
  cmp    $0x9,%r9d
  jne    L1
  add    $0x9,%rbx
  cmp    $0x1b,%rbx
  jne    L18
  pop    %rbx
  ret
```

assistant: ```c
void bufferizeNeigh(unsigned char *vol, int idx, int nb[27], const int volNeigh[27]) {
  int nidx;
  int i, j, k, ii;
  ii = 0;
  for (k = 0; k < 3; k++)
    for (j = 0; j < 3; j++)
      for (i = 0; i < 3; i++) {
        nidx = idx + volNeigh[ii++];
        nb[((j) * (3) + (i) + (k) * (3) * (3))] = (vol[nidx] != 0) ? 1 : -1;
      }
}
```