ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<proto_encode>:
  endbr64
  cmp    %r8,%rdx
  jl     L0
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8,%rbx
  test   %rsi,%rsi
  je     L36
  mov    (%rsi),%rax
  lea    (%rax,%r8,1),%rcx
  cmp    %rdx,%rcx
  jg     L41
  lea    (%rdi,%rax,1),%r13
  mov    %r8,%rdi
  call   <htonl@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  add    $0x4,%rbx
  mov    %rax,0x0(%r13)
  mov    0x0(%rbp),%rax
  lea    0x4(%r12,%rax,1),%rdi
  call   <memcpy@plt>
  add    %rbx,0x0(%rbp)
  xor    %eax,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L36:
  cmp    $0x4,%r8
  jne    L41
  mov    (%rcx),%rdi
  call   <htonl@plt>
  mov    %rax,(%r12)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L41:
  mov    $0xffffffff,%eax
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int proto_encode(char *outbuf, off_t *offset, uint32_t outlen, const char *inbuf, uint32_t inlen) {
  if (outlen < inlen)
    return -1;
  if (offset) {
    if (outlen < *offset + inlen)
      return -1;
    *(uint32_t *)(outbuf + *offset) = htonl(inlen);
    memcpy(outbuf + *offset + 4, inbuf, inlen);
    *offset += inlen + 4;
  } else {
    if (inlen != 4)
      return -1;
    *(uint32_t *)outbuf = htonl(*(uint32_t *)inbuf);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BLSCheck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L59
L104:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L48
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L54
L48:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L54
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L54:
  addl   $0x1,-0x2c(%rbp)
  cmpl   $0x5c,-0x2c(%rbp)
  jne    L76
  movl   $0x0,-0x2c(%rbp)
L76:
  addl   $0x1,-0x8(%rbp)
L59:
  cmpl   $0x2b,-0x8(%rbp)
  jle    L104
  mov    -0x38(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  negl   -0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  cmp    %eax,-0x18(%rbp)
  jle    L60
  mov    -0x18(%rbp),%eax
  sar    $0x3,%eax
  cmp    %eax,-0x14(%rbp)
  jle    L60
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    $0xffffffe3,%eax
  jl     L60
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    $0x1d,%eax
  jg     L60
  mov    $0x0,%eax
  jmp    L100
L60:
  mov    $0x1,%eax
L100:
  pop    %rbp
  ret
```

assistant: ```c
int BLSCheck(int *dBuf, int dbPtr, int *maxder) {
  int max, min, maxt, mint, t, x;
  max = min = 0;
  for (t = 0; t < ((int)(220 / ((double)1000 / (double)200) + 0.5)); ++t) {
    x = dBuf[dbPtr];
    if (x > max) {
      maxt = t;
      max = x;
    } else if (x < min) {
      mint = t;
      min = x;
    }
    if (++dbPtr == ((int)(80 / ((double)1000 / (double)200) + 0.5)) + (int)(((double)((int)(10 / ((double)1000 / (double)200) + 0.5)) / 2) + ((double)((int)(2 * ((int)(25 / ((double)1000 / (double)200) + 0.5)))) / 2 - 1) + (((double)((int)(125 / ((double)1000 / (double)200) + 0.5)) - 1) / 2) + ((int)(195 / ((double)1000 / (double)200) + 0.5))) + ((int)(100 / ((double)1000 / (double)200) + 0.5)))
      dbPtr = 0;
  }
  *maxder = max;
  min = -min;
  if ((max > (min >> 3)) && (min > (max >> 3)) && (abs(maxt - mint) < ((int)(150 / ((double)1000 / (double)200) + 0.5))))
    return (0);
  else
    return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BLSCheck>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x0,%eax
  mov    $0x0,%edx
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  jmp    L32
L62:
  mov    %eax,%r10d
  mov    %ecx,%r8d
L59:
  add    $0x1,%esi
  cmp    $0x5c,%esi
  cmove  %r9d,%esi
  add    $0x1,%eax
  cmp    $0x2c,%eax
  je     L7
L32:
  movslq %esi,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %r8d,%ecx
  jg     L62
  cmp    %edx,%ecx
  jge    L59
  mov    %eax,%r11d
  mov    %ecx,%edx
  jmp    L59
L7:
  mov    %r8d,(%rbx)
  neg    %edx
  mov    %edx,%ecx
  sar    $0x3,%ecx
  mov    $0x1,%eax
  cmp    %r8d,%ecx
  jge    L21
  sar    $0x3,%r8d
  cmp    %edx,%r8d
  jge    L21
  sub    %r11d,%r10d
  lea    0x1d(%r10),%eax
  cmp    $0x3a,%eax
  seta   %al
  movzbl %al,%eax
L21:
  pop    %rbx
  ret
```

assistant: ```c
int BLSCheck(int *dBuf, int dbPtr, int *maxder) {
  int max, min, maxt, mint, t, x;
  max = min = 0;
  for (t = 0; t < ((int)(220 / ((double)1000 / (double)200) + 0.5)); ++t) {
    x = dBuf[dbPtr];
    if (x > max) {
      maxt = t;
      max = x;
    } else if (x < min) {
      mint = t;
      min = x;
    }
    if (++dbPtr == ((int)(80 / ((double)1000 / (double)200) + 0.5)) + (int)(((double)((int)(10 / ((double)1000 / (double)200) + 0.5)) / 2) + ((double)((int)(2 * ((int)(25 / ((double)1000 / (double)200) + 0.5)))) / 2 - 1) + (((double)((int)(125 / ((double)1000 / (double)200) + 0.5)) - 1) / 2) + ((int)(195 / ((double)1000 / (double)200) + 0.5))) + ((int)(100 / ((double)1000 / (double)200) + 0.5)))
      dbPtr = 0;
  }
  *maxder = max;
  min = -min;
  if ((max > (min >> 3)) && (min > (max >> 3)) && (abs(maxt - mint) < ((int)(150 / ((double)1000 / (double)200) + 0.5))))
    return (0);
  else
    return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<BLSCheck>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdx,%rbx
  xor    %r8d,%r8d
  xor    %edx,%edx
  xor    %r9d,%r9d
  jmp    L34
  nopl   0x0(%rax)
L32:
  cmp    %edx,%ecx
  jge    L20
  mov    %eax,%r11d
  mov    %ecx,%edx
L20:
  add    $0x1,%esi
  cmp    $0x5c,%esi
  cmove  %r9d,%esi
  add    $0x1,%eax
  cmp    $0x2c,%eax
  je     L17
L34:
  movslq %esi,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %r8d,%ecx
  jle    L32
  mov    %eax,%r10d
  mov    %ecx,%r8d
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L17:
  neg    %edx
  mov    %r8d,(%rbx)
  mov    $0x1,%eax
  mov    %edx,%ecx
  sar    $0x3,%ecx
  cmp    %r8d,%ecx
  jge    L8
  sar    $0x3,%r8d
  cmp    %edx,%r8d
  jge    L8
  sub    %r11d,%r10d
  lea    0x1d(%r10),%eax
  cmp    $0x3a,%eax
  seta   %al
  movzbl %al,%eax
L8:
  pop    %rbx
  ret
```

assistant: ```c
int BLSCheck(int *dBuf, int dbPtr, int *maxder) {
  int max, min, maxt, mint, t, x;
  max = min = 0;
  for (t = 0; t < ((int)(220 / ((double)1000 / (double)200) + 0.5)); ++t) {
    x = dBuf[dbPtr];
    if (x > max) {
      maxt = t;
      max = x;
    } else if (x < min) {
      mint = t;
      min = x;
    }
    if (++dbPtr == ((int)(80 / ((double)1000 / (double)200) + 0.5)) + (int)(((double)((int)(10 / ((double)1000 / (double)200) + 0.5)) / 2) + ((double)((int)(2 * ((int)(25 / ((double)1000 / (double)200) + 0.5)))) / 2 - 1) + (((double)((int)(125 / ((double)1000 / (double)200) + 0.5)) - 1) / 2) + ((int)(195 / ((double)1000 / (double)200) + 0.5))) + ((int)(100 / ((double)1000 / (double)200) + 0.5)))
      dbPtr = 0;
  }
  *maxder = max;
  min = -min;
  if ((max > (min >> 3)) && (min > (max >> 3)) && (abs(maxt - mint) < ((int)(150 / ((double)1000 / (double)200) + 0.5))))
    return (0);
  else
    return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BLSCheck>:
  endbr64
  xor    %eax,%eax
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L85:
  movslq %esi,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %r8d,%ecx
  jg     L89
  cmp    %r9d,%ecx
  jge    L51
  mov    %eax,%r11d
  mov    %ecx,%r9d
L51:
  add    $0x1,%esi
  add    $0x1,%eax
  cmp    $0x5c,%esi
  je     L52
L54:
  cmp    $0x2c,%eax
  jne    L85
L76:
  neg    %r9d
  mov    %r8d,(%rdx)
  mov    $0x1,%eax
  mov    %r9d,%edx
  sar    $0x3,%edx
  cmp    %r8d,%edx
  jge    L1
  sar    $0x3,%r8d
  cmp    %r9d,%r8d
  jge    L1
  sub    %r11d,%r10d
  lea    0x1d(%r10),%eax
  cmp    $0x3a,%eax
  seta   %al
  movzbl %al,%eax
L1:
  ret
  cs nopw 0x0(%rax,%rax,1)
L89:
  add    $0x1,%esi
  mov    %eax,%r10d
  mov    %ecx,%r8d
  add    $0x1,%eax
  cmp    $0x5c,%esi
  jne    L54
L52:
  cmp    $0x2c,%eax
  je     L76
  xor    %esi,%esi
  jmp    L85
```

assistant: ```c
int BLSCheck(int *dBuf, int dbPtr, int *maxder) {
  int max, min, maxt, mint, t, x;
  max = min = 0;
  for (t = 0; t < ((int)(220 / ((double)1000 / (double)200) + 0.5)); ++t) {
    x = dBuf[dbPtr];
    if (x > max) {
      maxt = t;
      max = x;
    } else if (x < min) {
      mint = t;
      min = x;
    }
    if (++dbPtr == ((int)(80 / ((double)1000 / (double)200) + 0.5)) + (int)(((double)((int)(10 / ((double)1000 / (double)200) + 0.5)) / 2) + ((double)((int)(2 * ((int)(25 / ((double)1000 / (double)200) + 0.5)))) / 2 - 1) + (((double)((int)(125 / ((double)1000 / (double)200) + 0.5)) - 1) / 2) + ((int)(195 / ((double)1000 / (double)200) + 0.5))) + ((int)(100 / ((double)1000 / (double)200) + 0.5)))
      dbPtr = 0;
  }
  *maxder = max;
  min = -min;
  if ((max > (min >> 3)) && (min > (max >> 3)) && (abs(maxt - mint) < ((int)(150 / ((double)1000 / (double)200) + 0.5))))
    return (0);
  else
    return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<heartbeat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <reb_output_check@plt>
  test   %rax,%rax
  je     L0
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <reb_output_timing@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void heartbeat(struct reb_simulation *r) {
  if (reb_output_check(r, 100.)) {
    reb_output_timing(r, INFINITY);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<heartbeat>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x64,%esi
  call   <reb_output_check@plt>
  test   %rax,%rax
  jne    L17
L2:
  pop    %rbx
  ret
L17:
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <reb_output_timing@plt>
  jmp    L2
```

assistant: ```c
void heartbeat(struct reb_simulation *r) {
  if (reb_output_check(r, 100.)) {
    reb_output_timing(r, INFINITY);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heartbeat>:
  endbr64
  push   %rbp
  mov    $0x64,%esi
  mov    %rdi,%rbp
  call   <reb_output_check@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  mov    D3(%rip),%rax
  mov    %rbp,%rdi
  pop    %rbp
  mov    (%rax),%esi
  jmp    1070 <reb_output_timing@plt>
```

assistant: ```c
void heartbeat(struct reb_simulation *r) {
  if (reb_output_check(r, 100.)) {
    reb_output_timing(r, INFINITY);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heartbeat>:
  endbr64
  push   %rbp
  mov    $0x64,%esi
  mov    %rdi,%rbp
  call   <reb_output_check@plt>
  test   %rax,%rax
  jne    L7
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  mov    D6(%rip),%rax
  mov    %rbp,%rdi
  pop    %rbp
  mov    (%rax),%esi
  jmp    1070 <reb_output_timing@plt>
```

assistant: ```c
void heartbeat(struct reb_simulation *r) {
  if (reb_output_check(r, 100.)) {
    reb_output_timing(r, INFINITY);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fitsBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  and    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  not    %eax
  mov    %eax,%edi
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  and    %edi,%eax
  or     %esi,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fitsBits(int x, int n) {
  int neg = x >> 31;
  int n_1 = n + (~0);
  return (neg & !((~x) >> n_1)) | (~neg & !(x >> n_1));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fitsBits>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    %edi,%eax
  sar    %cl,%eax
  test   %eax,%eax
  sete   %dl
  mov    %edi,%eax
  not    %eax
  sar    %cl,%eax
  test   %eax,%eax
  sete   %al
  xor    %edx,%eax
  movzbl %al,%eax
  sar    $0x1f,%edi
  and    %edi,%eax
  movzbl %dl,%edx
  xor    %edx,%eax
  ret
```

assistant: ```c
int fitsBits(int x, int n) {
  int neg = x >> 31;
  int n_1 = n + (~0);
  return (neg & !((~x) >> n_1)) | (~neg & !(x >> n_1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fitsBits>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    %edi,%eax
  sar    %cl,%eax
  test   %eax,%eax
  mov    %edi,%eax
  not    %eax
  sete   %dl
  sar    %cl,%eax
  test   %eax,%eax
  mov    %edi,%eax
  sete   %cl
  shr    $0x1f,%eax
  xor    %edx,%ecx
  movzbl %dl,%edx
  and    %ecx,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
int fitsBits(int x, int n) {
  int neg = x >> 31;
  int n_1 = n + (~0);
  return (neg & !((~x) >> n_1)) | (~neg & !(x >> n_1));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fitsBits>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    %edi,%eax
  sar    %cl,%eax
  test   %eax,%eax
  mov    %edi,%eax
  not    %eax
  sete   %dl
  sar    %cl,%eax
  test   %eax,%eax
  mov    %edi,%eax
  sete   %cl
  shr    $0x1f,%eax
  xor    %edx,%ecx
  movzbl %dl,%edx
  and    %ecx,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
int fitsBits(int x, int n) {
  int neg = x >> 31;
  int n_1 = n + (~0);
  return (neg & !((~x) >> n_1)) | (~neg & !(x >> n_1));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bmap2wday>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L10:
  addl   $0x1,-0x4(%rbp)
L13:
  shrb   -0x14(%rbp)
  cmpb   $0x0,-0x14(%rbp)
  jne    L10
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bmap2wday(unsigned char bmap) {
  int j;
  j = 0;
  while ((bmap = (bmap >> 1)) != 0)
    j++;
  return j;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bmap2wday>:
  endbr64
  shr    %dil
  je     L13
  mov    $0x0,%eax
L8:
  add    $0x1,%eax
  shr    %dil
  jne    L8
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int bmap2wday(unsigned char bmap) {
  int j;
  j = 0;
  while ((bmap = (bmap >> 1)) != 0)
    j++;
  return j;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bmap2wday>:
  endbr64
  xor    %eax,%eax
  shr    %dil
  je     L14
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%eax
  shr    %dil
  jne    L18
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
int bmap2wday(unsigned char bmap) {
  int j;
  j = 0;
  while ((bmap = (bmap >> 1)) != 0)
    j++;
  return j;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bmap2wday>:
  endbr64
  xor    %eax,%eax
  shr    %dil
  je     L4
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%eax
  shr    %dil
  jne    L5
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
int bmap2wday(unsigned char bmap) {
  int j;
  j = 0;
  while ((bmap = (bmap >> 1)) != 0)
    j++;
  return j;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_divisible_by_all_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x2,-0x8(%rbp)
  jmp    L17
L4:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  je     L11
  mov    $0x0,%eax
  jmp    L33
L11:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jle    L4
  mov    $0x1,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int is_divisible_by_all_to(long l, long num) {
  long i;
  for (i = 2; i <= num; i++)
    if (l % i != 0)
      return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_divisible_by_all_to>:
  endbr64
  cmp    $0x1,%rsi
  jle    L0
  test   $0x1,%dil
  jne    L21
  mov    $0x2,%ecx
L30:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jl     L31
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  je     L30
  mov    $0x0,%eax
  ret
L31:
  mov    $0x1,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
L21:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_divisible_by_all_to(long l, long num) {
  long i;
  for (i = 2; i <= num; i++)
    if (l % i != 0)
      return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_divisible_by_all_to>:
  endbr64
  cmp    $0x1,%rsi
  jle    L22
  test   $0x1,%dil
  jne    L16
  mov    $0x2,%ecx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L16
L14:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jge    L49
L22:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_divisible_by_all_to(long l, long num) {
  long i;
  for (i = 2; i <= num; i++)
    if (l % i != 0)
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_divisible_by_all_to>:
  endbr64
  cmp    $0x1,%rsi
  jle    L44
  test   $0x1,%dil
  jne    L33
  mov    $0x2,%ecx
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L33
L36:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jge    L26
L44:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_divisible_by_all_to(long l, long num) {
  long i;
  for (i = 2; i <= num; i++)
    if (l % i != 0)
      return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PathInPList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L93
L102:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L71
L37:
  addq   $0x1,-0x8(%rbp)
  jmp    L103
L70:
  addq   $0x1,-0x8(%rbp)
L103:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L70
  addq   $0x1,-0x10(%rbp)
  jmp    L16
L89:
  addq   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L89
L71:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L50
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L37
L50:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L93
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L93
  mov    $0x1,%eax
  jmp    L3
L93:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jg     L102
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int PathInPList(char *path, char **fplist, int listlen) {
  char *s, *t;
  while (listlen-- > 0) {
    for (s = path, t = fplist[listlen]; *s && (*s == *t);) {
      t++;
      while (*t == '/')
        t++;
      s++;
      while (*s == '/')
        s++;
    }
    if (!*s && !*t)
      return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PathInPList>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L36
  movzbl (%rdi),%edi
  cltq
  shl    $0x3,%rax
  lea    (%rsi,%rax,1),%rsi
  lea    -0x8(%rcx,%rax,1),%r9
  lea    -0x1(%rdx),%eax
  shl    $0x3,%rax
  sub    %rax,%r9
  jmp    L38
L133:
  mov    %rax,%rdx
  jmp    L67
L74:
  mov    %rax,%rcx
L2:
  movzbl (%rcx),%eax
  test   %al,%al
  je     L39
L64:
  cmp    %al,(%rdx)
  jne    L53
  lea    0x1(%rdx),%rax
  cmpb   $0x2f,0x1(%rdx)
  jne    L133
L101:
  add    $0x1,%rax
  cmpb   $0x2f,(%rax)
  je     L101
  mov    %rax,%rdx
L67:
  lea    0x1(%rcx),%rax
  cmpb   $0x2f,0x1(%rcx)
  jne    L74
L83:
  add    $0x1,%rax
  cmpb   $0x2f,(%rax)
  je     L83
  mov    %rax,%rcx
  jmp    L2
L53:
  test   %al,%al
  je     L39
L100:
  sub    $0x8,%rsi
  cmp    %r9,%rsi
  je     L8
L38:
  mov    (%rsi),%rdx
  mov    %r8,%rcx
  mov    %edi,%eax
  test   %dil,%dil
  jne    L64
L39:
  cmpb   $0x0,(%rdx)
  jne    L100
  mov    $0x1,%eax
  ret
L8:
  mov    $0x0,%eax
  ret
L36:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int PathInPList(char *path, char **fplist, int listlen) {
  char *s, *t;
  while (listlen-- > 0) {
    for (s = path, t = fplist[listlen]; *s && (*s == *t);) {
      t++;
      while (*t == '/')
        t++;
      s++;
      while (*s == '/')
        s++;
    }
    if (!*s && !*t)
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PathInPList>:
  endbr64
  mov    %rdi,%r10
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L76
  movslq %eax,%rdx
  mov    %eax,%eax
  movzbl (%rdi),%r9d
  shl    $0x3,%rdx
  shl    $0x3,%rax
  lea    -0x8(%rsi,%rdx,1),%r11
  lea    (%rsi,%rdx,1),%r8
  sub    %rax,%r11
  nop
L13:
  mov    (%r8),%rax
  mov    %r10,%rdx
  mov    %r9d,%ecx
  movzbl (%rax),%esi
  test   %r9b,%r9b
  je     L75
  nopl   0x0(%rax)
L14:
  cmp    %sil,%cl
  jne    L42
  movzbl 0x1(%rax),%esi
  lea    0x1(%rax),%rcx
  mov    %rcx,%rax
  cmp    $0x2f,%sil
  jne    L22
  xchg   %ax,%ax
L96:
  movzbl 0x1(%rax),%esi
  add    $0x1,%rax
  cmp    $0x2f,%sil
  je     L96
L22:
  movzbl 0x1(%rdx),%ecx
  lea    0x1(%rdx),%rdi
  mov    %rdi,%rdx
  cmp    $0x2f,%cl
  jne    L67
  xchg   %ax,%ax
L44:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  cmp    $0x2f,%cl
  je     L44
L67:
  test   %cl,%cl
  jne    L14
L75:
  test   %sil,%sil
  je     L23
L42:
  sub    $0x8,%r8
  cmp    %r11,%r8
  jne    L13
L76:
  xor    %eax,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int PathInPList(char *path, char **fplist, int listlen) {
  char *s, *t;
  while (listlen-- > 0) {
    for (s = path, t = fplist[listlen]; *s && (*s == *t);) {
      t++;
      while (*t == '/')
        t++;
      s++;
      while (*s == '/')
        s++;
    }
    if (!*s && !*t)
      return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PathInPList>:
  endbr64
  mov    %rdi,%r10
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L7
  movslq %eax,%rdx
  mov    %eax,%eax
  movzbl (%rdi),%r9d
  shl    $0x3,%rdx
  shl    $0x3,%rax
  lea    -0x8(%rsi,%rdx,1),%r11
  lea    (%rsi,%rdx,1),%r8
  sub    %rax,%r11
  nop
L56:
  mov    (%r8),%rax
  mov    %r10,%rdx
  mov    %r9d,%ecx
  movzbl (%rax),%esi
  test   %r9b,%r9b
  je     L39
  nopl   0x0(%rax)
L58:
  cmp    %sil,%cl
  jne    L43
  movzbl 0x1(%rax),%esi
  lea    0x1(%rax),%rcx
  mov    %rcx,%rax
  cmp    $0x2f,%sil
  jne    L79
  xchg   %ax,%ax
L30:
  movzbl 0x1(%rax),%esi
  add    $0x1,%rax
  cmp    $0x2f,%sil
  je     L30
L79:
  movzbl 0x1(%rdx),%ecx
  lea    0x1(%rdx),%rdi
  mov    %rdi,%rdx
  cmp    $0x2f,%cl
  jne    L72
  xchg   %ax,%ax
L91:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  cmp    $0x2f,%cl
  je     L91
L72:
  test   %cl,%cl
  jne    L58
L39:
  test   %sil,%sil
  je     L88
L43:
  sub    $0x8,%r8
  cmp    %r8,%r11
  jne    L56
L7:
  xor    %eax,%eax
  ret
L88:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int PathInPList(char *path, char **fplist, int listlen) {
  char *s, *t;
  while (listlen-- > 0) {
    for (s = path, t = fplist[listlen]; *s && (*s == *t);) {
      t++;
      while (*t == '/')
        t++;
      s++;
      while (*s == '/')
        s++;
    }
    if (!*s && !*t)
      return 1;
  }
  return 0;
}
```