ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D59(%rip),%rdi
  lea    D61(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  mulss  D19(%rip),%xmm0
  comiss D55(%rip),%xmm0
  jb     L6
  lea    D26(%rip),%rdi
  call   <printf@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D59
type: string
name: parse_data
arguments: data_label: D61
type: string
name: parse_data
arguments: data_label: D44
type: string
name: parse_data
arguments: data_label: D19
type: byte[4]
name: parse_data
arguments: data_label: D55
type: f32
name: parse_data
arguments: data_label: D26
type: string
name: parse_data
arguments: data_label: D18
type: string

tool: D59: Digite a nota da primeira prova: 

tool: D61: %f

tool: D44: Digite a nota da segunda prova: 

tool: {"D19": [0x00,0x00,0x00,0x3f]}

tool: D55: 6

tool: D26: 
APROVADO!!!



tool: D18: 
REPROVADO!!!



assistant: ```c
int main() {
  float x, y, z;
  printf("Digite a nota da primeira prova: ");
  scanf("%f", &x);
  printf("Digite a nota da segunda prova: ");
  scanf("%f", &y);
  z = ((x + y) / 2);
  if (z >= 6.0) {
    printf("\nAPROVADO!!!\n\n");
  } else {
    printf("\nREPROVADO!!!\n\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  lea    D7(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  mulss  D54(%rip),%xmm0
  comiss D61(%rip),%xmm0
  jb     L5
  lea    D35(%rip),%rdi
  call   <printf@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D38
datatype: string
name: read_data
arguments: data_tag: D54
datatype: byte[4]
name: read_data
arguments: data_tag: D61
datatype: f32
name: read_data
arguments: data_tag: D35
datatype: string
name: read_data
arguments: data_tag: D0
datatype: string

tool: D10: Digite a nota da primeira prova: 

tool: D7: %f

tool: D38: Digite a nota da segunda prova: 

tool: {"D54": [0x00,0x00,0x00,0x3f]}

tool: D61: 6

tool: D35: 
APROVADO!!!



tool: D0: 
REPROVADO!!!



assistant: ```c
int main() {
  float x, y, z;
  printf("Digite a nota da primeira prova: ");
  scanf("%f", &x);
  printf("Digite a nota da segunda prova: ");
  scanf("%f", &y);
  z = ((x + y) / 2);
  if (z >= 6.0) {
    printf("\nAPROVADO!!!\n\n");
  } else {
    printf("\nREPROVADO!!!\n\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<match_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L1
  cmpq   $0x0,-0x10(%rbp)
  je     L1
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    $0x1,%eax
  jmp    L70
L1:
  mov    $0x0,%eax
L70:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L24
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L24
  mov    $0x1,%eax
  jmp    L49
L24:
  mov    $0x0,%eax
L49:
  leave
  ret
```

assistant: ```c
bool match_char(char **p, void *ch) {
  assert(p && *p && ch && *((char *)ch));
  return (**p == *((char *)ch)) && ++*p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<match_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%edi
  test   %rbx,%rbx
  je     L6
  cmpq   $0x0,(%rbx)
  je     L11
  test   %rsi,%rsi
  je     L11
  cmpb   $0x0,(%rsi)
  setne  %dil
  movzbl %dil,%edi
  jmp    L6
L11:
  mov    $0x0,%edi
L6:
  call   <assert@plt>
  mov    (%rbx),%rax
  mov    $0x0,%edx
  movzbl 0x0(%rbp),%ecx
  cmp    %cl,(%rax)
  je     L4
L44:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  add    $0x1,%rax
  mov    %rax,(%rbx)
  mov    $0x1,%edx
  jmp    L44
```

assistant: ```c
bool match_char(char **p, void *ch) {
  assert(p && *p && ch && *((char *)ch));
  return (**p == *((char *)ch)) && ++*p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<match_char>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbx,%rbx
  je     L48
  cmpq   $0x0,(%rbx)
  je     L19
  test   %rsi,%rsi
  je     L19
  xor    %edi,%edi
  cmpb   $0x0,(%rsi)
  setne  %dil
L48:
  call   <assert@plt>
  mov    (%rbx),%rax
  movzbl 0x0(%rbp),%edx
  xor    %r8d,%r8d
  cmp    %dl,(%rax)
  jne    L39
  add    $0x1,%rax
  mov    $0x1,%r8d
  mov    %rax,(%rbx)
L39:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L19:
  xor    %edi,%edi
  jmp    L48
```

assistant: ```c
bool match_char(char **p, void *ch) {
  assert(p && *p && ch && *((char *)ch));
  return (**p == *((char *)ch)) && ++*p;
}
```
user: What is the c source code of the assembly code below:

```asm
<match_char>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbx,%rbx
  je     L29
  cmpq   $0x0,(%rbx)
  je     L39
  test   %rsi,%rsi
  je     L39
  xor    %edi,%edi
  cmpb   $0x0,(%rsi)
  setne  %dil
L29:
  call   <assert@plt>
  mov    (%rbx),%rax
  movzbl 0x0(%rbp),%edx
  xor    %r8d,%r8d
  cmp    %dl,(%rax)
  jne    L35
  add    $0x1,%rax
  mov    $0x1,%r8d
  mov    %rax,(%rbx)
L35:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L39:
  xor    %edi,%edi
  jmp    L29
```

assistant: ```c
bool match_char(char **p, void *ch) {
  assert(p && *p && ch && *((char *)ch));
  return (**p == *((char *)ch)) && ++*p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<iw_filter_hermite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  movsd  D0(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L16
  movsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm2
  movsd  D3(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x10(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L13
L16:
  pxor   %xmm0,%xmm0
L13:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: f64
name: disassemble_data
arguments: label: D3
type_infered: f64

tool: D0: 1

tool: D3: 3

assistant: ```c
double iw_filter_hermite(struct iw_rr_ctx *rrctx, double x) {
  if (x < 1.0) {
    return 2.0 * x * x * x - 3.0 * x * x + 1.0;
  }
  return 0.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<iw_filter_hermite>:
  endbr64
  movsd  D25(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L9
  pxor   %xmm0,%xmm0
  ret
L9:
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm0,%xmm2
  mulsd  D24(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  addsd  D25(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
type_infered: f64
name: extract_symbolic_data
arguments: label: D24
type_infered: f64

tool: D25: 1

tool: D24: 3

assistant: ```c
double iw_filter_hermite(struct iw_rr_ctx *rrctx, double x) {
  if (x < 1.0) {
    return 2.0 * x * x * x - 3.0 * x * x + 1.0;
  }
  return 0.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iw_filter_hermite>:
  endbr64
  movsd  D9(%rip),%xmm2
  comisd %xmm0,%xmm2
  ja     L4
  pxor   %xmm0,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movapd %xmm0,%xmm1
  movsd  D0(%rip),%xmm3
  addsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm1
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D9
type: f64
name: read_data
arguments: label: D0
type: f64

tool: D9: 1

tool: D0: 3

assistant: ```c
double iw_filter_hermite(struct iw_rr_ctx *rrctx, double x) {
  if (x < 1.0) {
    return 2.0 * x * x * x - 3.0 * x * x + 1.0;
  }
  return 0.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iw_filter_hermite>:
  endbr64
  movsd  D19(%rip),%xmm2
  comisd %xmm0,%xmm2
  ja     L5
  pxor   %xmm0,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  movapd %xmm0,%xmm1
  movsd  D5(%rip),%xmm3
  addsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm1
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type_guessed: f64
name: parse_data
arguments: data_label: D5
type_guessed: f64

tool: D19: 1

tool: D5: 3

assistant: ```c
double iw_filter_hermite(struct iw_rr_ctx *rrctx, double x) {
  if (x < 1.0) {
    return 2.0 * x * x * x - 3.0 * x * x + 1.0;
  }
  return 0.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<simple_acts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L90
L73:
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl -0x15(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x2f,%eax
  je     L102
  cmp    $0x2f,%eax
  jg     L90
  cmp    $0x2d,%eax
  je     L11
  cmp    $0x2d,%eax
  jg     L90
  cmp    $0x2a,%eax
  je     L92
  cmp    $0x2b,%eax
  jne    L90
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L90
L11:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L90
L92:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L90
L102:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0x14(%rbp)
  nop
L90:
  movzbl -0x15(%rbp),%eax
  cmp    $0xa,%al
  jne    L73
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L93
  call   <__stack_chk_fail@plt>
L93:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D56
type_guessed: string
name: unpack_data
arguments: data_tag: D34
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string
name: unpack_data
arguments: data_tag: D42
type_guessed: string

tool: D56: Enter your function:

tool: D34: %d

tool: D7: %c

tool: D42: result is %d


assistant: ```c
void simple_acts(void) {
  int num_one, num_two;
  char ch;
  int sum = 0;
  printf("Enter your function:");
  scanf("%d", &num_one);
  while (ch != '\n') {
    scanf("%c", &ch);
    switch (ch) {
    case '+':
      scanf("%d", &num_two);
      num_one += num_two;
      break;
    case '-':
      scanf("%d", &num_two);
      num_one -= num_two;
      break;
    case '*':
      scanf("%d", &num_two);
      num_one *= num_two;
      break;
    case '/':
      scanf("%d", &num_two);
      num_one /= num_two;
      break;
    }
  }
  printf("result is %d\n", num_one);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<simple_acts>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D32(%rip),%rbp
  lea    0xf(%rsp),%rbx
  lea    D45(%rip),%r12
  jmp    L19
L71:
  cmp    $0x2f,%al
  jne    L19
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cltd
  idivl  0x14(%rsp)
  jmp    L12
L96:
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  sub    0x14(%rsp),%eax
L12:
  mov    %eax,0x10(%rsp)
L19:
  cmpb   $0xa,0xf(%rsp)
  je     L41
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x2d,%al
  je     L96
  jg     L71
  cmp    $0x2a,%al
  je     L56
  cmp    $0x2b,%al
  jne    L19
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  add    0x10(%rsp),%eax
  jmp    L12
L56:
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  imul   0x14(%rsp),%eax
  jmp    L12
L41:
  mov    0x10(%rsp),%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D45
type_guessed: string
name: unpack_data
arguments: data_label: D32
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D18: Enter your function:

tool: D45: %d

tool: D32: %c

tool: D4: result is %d


assistant: ```c
void simple_acts(void) {
  int num_one, num_two;
  char ch;
  int sum = 0;
  printf("Enter your function:");
  scanf("%d", &num_one);
  while (ch != '\n') {
    scanf("%c", &ch);
    switch (ch) {
    case '+':
      scanf("%d", &num_two);
      num_one += num_two;
      break;
    case '-':
      scanf("%d", &num_two);
      num_one -= num_two;
      break;
    case '*':
      scanf("%d", &num_two);
      num_one *= num_two;
      break;
    case '/':
      scanf("%d", &num_two);
      num_one /= num_two;
      break;
    }
  }
  printf("result is %d\n", num_one);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<simple_acts>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D6(%rip),%rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  jmp    L9
  nopl   (%rax)
L10:
  cmp    $0x2b,%al
  jne    L53
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  add    0x10(%rsp),%eax
L66:
  mov    %eax,0x10(%rsp)
L9:
  movzbl 0xf(%rsp),%eax
L53:
  cmp    $0xa,%al
  je     L21
  lea    0xf(%rsp),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x2d,%al
  je     L47
  jg     L89
  cmp    $0x2a,%al
  jne    L10
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  imul   0x14(%rsp),%eax
  jmp    L66
  nopl   0x0(%rax)
L89:
  cmp    $0x2f,%al
  jne    L53
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cltd
  idivl  0x14(%rsp)
  jmp    L66
  xchg   %ax,%ax
L47:
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  sub    0x14(%rsp),%eax
  jmp    L66
  nopl   0x0(%rax)
L21:
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D33
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string

tool: D0: Enter your function:

tool: D6: %d

tool: D33: %c

tool: D9: result is %d


assistant: ```c
void simple_acts(void) {
  int num_one, num_two;
  char ch;
  int sum = 0;
  printf("Enter your function:");
  scanf("%d", &num_one);
  while (ch != '\n') {
    scanf("%c", &ch);
    switch (ch) {
    case '+':
      scanf("%d", &num_two);
      num_one += num_two;
      break;
    case '-':
      scanf("%d", &num_two);
      num_one -= num_two;
      break;
    case '*':
      scanf("%d", &num_two);
      num_one *= num_two;
      break;
    case '/':
      scanf("%d", &num_two);
      num_one /= num_two;
      break;
    }
  }
  printf("result is %d\n", num_one);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<simple_acts>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  lea    D19(%rip),%rbp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  jmp    L22
  nopl   (%rax)
L83:
  cmp    $0x2b,%al
  jne    L85
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  add    0x10(%rsp),%eax
L91:
  mov    %eax,0x10(%rsp)
L22:
  movzbl 0xf(%rsp),%eax
L85:
  cmp    $0xa,%al
  je     L8
  lea    0xf(%rsp),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x2d,%al
  je     L24
  jg     L103
  cmp    $0x2a,%al
  jne    L83
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  imul   0x14(%rsp),%eax
  jmp    L91
  nopl   0x0(%rax)
L103:
  cmp    $0x2f,%al
  jne    L85
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cltd
  idivl  0x14(%rsp)
  jmp    L91
  xchg   %ax,%ax
L24:
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  sub    0x14(%rsp),%eax
  jmp    L91
  nopl   0x0(%rax)
L8:
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string
name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D37
type_guessed: string

tool: D3: Enter your function:

tool: D19: %d

tool: D11: %c

tool: D37: result is %d


assistant: ```c
void simple_acts(void) {
  int num_one, num_two;
  char ch;
  int sum = 0;
  printf("Enter your function:");
  scanf("%d", &num_one);
  while (ch != '\n') {
    scanf("%c", &ch);
    switch (ch) {
    case '+':
      scanf("%d", &num_two);
      num_one += num_two;
      break;
    case '-':
      scanf("%d", &num_two);
      num_one -= num_two;
      break;
    case '*':
      scanf("%d", &num_two);
      num_one *= num_two;
      break;
    case '/':
      scanf("%d", &num_two);
      num_one /= num_two;
      break;
    }
  }
  printf("result is %d\n", num_one);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<verifyInetVariable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jg     L6
  mov    -0x8(%rbp),%rax
  movl   $0x2328,(%rax)
L6:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <isValidIp4@plt>
  leave
  ret
```

assistant: ```c
int verifyInetVariable(int *port, const char *ip) {
  if (*port <= 0) {
    *port = 9000;
  } else {
  }
  return isValidIp4(ip);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<verifyInetVariable>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  cmpl   $0x0,(%rax)
  jle    L8
L18:
  call   <isValidIp4@plt>
  add    $0x8,%rsp
  ret
L8:
  movl   $0x2328,(%rax)
  jmp    L18
```

assistant: ```c
int verifyInetVariable(int *port, const char *ip) {
  if (*port <= 0) {
    *port = 9000;
  } else {
  }
  return isValidIp4(ip);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<verifyInetVariable>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    (%rax),%edx
  test   %edx,%edx
  jg     L8
  movl   $0x2328,(%rax)
L8:
  jmp    1050 <isValidIp4@plt>
```

assistant: ```c
int verifyInetVariable(int *port, const char *ip) {
  if (*port <= 0) {
    *port = 9000;
  } else {
  }
  return isValidIp4(ip);
}
```
user: Translate the below assembly code into C programming language:

```asm
<verifyInetVariable>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    (%rax),%edx
  test   %edx,%edx
  jg     L5
  movl   $0x2328,(%rax)
L5:
  jmp    1050 <isValidIp4@plt>
```

assistant: ```c
int verifyInetVariable(int *port, const char *ip) {
  if (*port <= 0) {
    *port = 9000;
  } else {
  }
  return isValidIp4(ip);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x118(%rbp),%rax
  mov    $0x270f,%esi
  mov    %rax,%rdi
  call   <CreateUdpSock@plt>
  movl   $0x100,-0x114(%rbp)
  jmp    L7
L27:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x100,-0x114(%rbp)
L7:
  mov    -0x118(%rbp),%eax
  lea    -0x114(%rbp),%rdx
  lea    -0x110(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <RecvMsgByUdp@plt>
  test   %rax,%rax
  je     L27
  mov    -0x118(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: Recv UDP Data:[%d][%s]


assistant: ```c
int main() {
  int nSock, nSize;
  char szBuf[256];
  CreateUdpSock(&nSock, 9999);
  nSize = sizeof(szBuf);
  while (RecvMsgByUdp(nSock, szBuf, &nSize) == 0) {
    printf("Recv UDP Data:[%d][%s]\n", strlen(szBuf), szBuf);
    nSize = sizeof(szBuf);
  }
  close(nSock);
}
```