ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<task>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  jmp    L8
L19:
  mov    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int64_t task(int64_t a, int64_t b, int64_t p, int64_t m, int64_t n) {
  while (n-- > 0) {
    b = (a * p + b) % m;
    a = b;
  }
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<task>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r9d
  lea    -0x1(%r8),%edi
  test   %r8d,%r8d
  jg     L15
  ret
L5:
  mov    %edx,%esi
L15:
  imul   %r9d,%eax
  add    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  sub    $0x1,%edi
  cmp    $0xffffffff,%edi
  jne    L5
  ret
```

assistant: ```c
int64_t task(int64_t a, int64_t b, int64_t p, int64_t m, int64_t n) {
  while (n-- > 0) {
    b = (a * p + b) % m;
    a = b;
  }
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<task>:
  endbr64
  mov    %edi,%r9d
  mov    %edx,%r10d
  lea    -0x1(%r8),%edi
  test   %r8d,%r8d
  jg     L5
  jmp    L6
  nopl   (%rax)
L11:
  mov    %r9d,%esi
L5:
  mov    %r9d,%eax
  imul   %r10d,%eax
  add    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%r9d
  sub    $0x1,%edi
  jae    L11
L6:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int64_t task(int64_t a, int64_t b, int64_t p, int64_t m, int64_t n) {
  while (n-- > 0) {
    b = (a * p + b) % m;
    a = b;
  }
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<task>:
  endbr64
  mov    %edi,%r9d
  mov    %edx,%r10d
  lea    -0x1(%r8),%edi
  test   %r8d,%r8d
  jg     L20
  jmp    L21
  nopl   (%rax)
L15:
  mov    %r9d,%esi
L20:
  mov    %r9d,%eax
  imul   %r10d,%eax
  add    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%r9d
  sub    $0x1,%edi
  jae    L15
L21:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int64_t task(int64_t a, int64_t b, int64_t p, int64_t m, int64_t n) {
  while (n-- > 0) {
    b = (a * p + b) % m;
    a = b;
  }
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_08>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_08(unsigned char *x, int c) {
  int s = 0;
  int i;
  for (i = 0; i < c; ++i)
    s += x[i];
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_08>:
  endbr64
  test   %esi,%esi
  jle    L29
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    $0x0,%edx
L21:
  movzbl (%rax),%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L21
L4:
  mov    %edx,%eax
  ret
L29:
  mov    $0x0,%edx
  jmp    L4
```

assistant: ```c
int test_08(unsigned char *x, int c) {
  int s = 0;
  int i;
  for (i = 0; i < c; ++i)
    s += x[i];
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_08>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int test_08(unsigned char *x, int c) {
  int s = 0;
  int i;
  for (i = 0; i < c; ++i)
    s += x[i];
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_08>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%edx
  test   %esi,%esi
  jle    L91
  lea    -0x1(%rsi),%eax
  cmp    $0xe,%eax
  jbe    L150
  shr    $0x4,%esi
  pxor   %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  mov    %rdi,%rax
  sub    $0x1,%esi
  pxor   %xmm3,%xmm3
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   0x0(%rax,%rax,1)
L65:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm2
  punpckhbw %xmm4,%xmm1
  punpcklbw %xmm4,%xmm2
  movdqa %xmm2,%xmm5
  punpckhwd %xmm3,%xmm2
  punpcklwd %xmm3,%xmm5
  paddd  %xmm5,%xmm0
  paddd  %xmm2,%xmm0
  movdqa %xmm1,%xmm2
  punpckhwd %xmm3,%xmm1
  punpcklwd %xmm3,%xmm2
  paddd  %xmm2,%xmm0
  paddd  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L65
  movdqa %xmm0,%xmm1
  mov    %edx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffff0,%esi
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0xf,%dl
  je     L25
L62:
  movslq %esi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x1(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x2(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x3(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x4(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x5(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x6(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x7(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x8(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0x9(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0xa(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0xb(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0xc(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  lea    0xd(%rsi),%edi
  cmp    %edi,%edx
  jle    L131
  movslq %edi,%rdi
  add    $0xe,%esi
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%eax
  cmp    %esi,%edx
  jle    L131
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edx
  add    %edx,%eax
  ret
  nop
L91:
  xor    %eax,%eax
L131:
  ret
L150:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L62
L25:
  ret
```

assistant: ```c
int test_08(unsigned char *x, int c) {
  int s = 0;
  int i;
  for (i = 0; i < c; ++i)
    s += x[i];
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<u2f>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x538,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %edx,%ebx
  mov    %rcx,%r12
  mov    %r8,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x528(%rsp)
  xor    %eax,%eax
  mov    %r8,%r13
  test   %r8,%r8
  je     L100
L24:
  cmp    $0x8,%ebx
  jle    L7
  lea    0x30(%rsp),%r15
  lea    0x10(%rsp),%r14
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %ebx,%edx
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <normu@plt>
  mov    %r15,%r9
  mov    %r14,%r8
  mov    %ebx,%ecx
  mov    0x8(%rsp),%rdx
  mov    %r13,%rsi
  mov    (%rsp),%rdi
  call   <lin_fmN@plt>
  lea    0x2a0(%rsp),%r14
  mov    $0x9,%ecx
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <cov_mat@plt>
  lea    0x50(%rsp),%rsi
  mov    $0x9,%edx
  mov    %r14,%rdi
  call   <lap_eig@plt>
  mov    $0x9,%esi
  mov    %r14,%rdi
  call   <trnm@plt>
  mov    $0x1,%eax
  mov    $0x0,%edx
  lea    0x50(%rsp),%rsi
L94:
  movslq %edx,%rcx
  movsd  0x50(%rsp,%rcx,8),%xmm0
  ucomisd (%rsi,%rax,8),%xmm0
  cmova  %eax,%edx
  add    $0x1,%rax
  cmp    $0x9,%rax
  jne    L94
  movslq %edx,%rdx
  lea    0x2a0(%rsp,%rdx,8),%rax
  jmp    L45
L100:
  lea    (%rdx,%rdx,8),%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  jmp    L24
L7:
  mov    %ebx,%ecx
  mov    0x8(%rsp),%rdx
  mov    %r13,%rsi
  mov    (%rsp),%rdi
  call   <lin_fm@plt>
  lea    0x2a0(%rsp),%rdx
  lea    0x50(%rsp),%rdi
  mov    $0x8,%r9d
  lea    0xa0(%rsp),%r8
  mov    $0x9,%ecx
  mov    %r13,%rsi
  call   <svduv@plt>
  lea    0x2e0(%rsp),%rax
L45:
  mov    %r12,%rdx
  lea    0x288(%rax),%rcx
L65:
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x48,%rax
  add    $0x8,%rdx
  cmp    %rax,%rcx
  jne    L65
  mov    %r12,%rdi
  call   <singulF@plt>
  cmp    $0x8,%ebx
  jg     L104
L73:
  test   %rbp,%rbp
  je     L56
L66:
  mov    0x528(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x538,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L104:
  lea    0x30(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <denormF@plt>
  jmp    L73
L56:
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L66
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void u2f(const double *u, const int *inl, int len, double *F, double *buffer) {
  double A1[3], A2[3];
  double *Z, V[9 * 9], U[8 * 8], D[9], *p;
  int i, j;
  if (buffer == NULL)
    Z = (double *)malloc(sizeof(double) * 9 * len);
  else
    Z = buffer;
  if (len > 8) {
    normu(u, inl, len, A1, A2);
    lin_fmN(u, Z, inl, len, A1, A2);
    cov_mat(V, Z, len, 9);
    lap_eig(V, D, 9);
    trnm(V, 9);
  } else {
    lin_fm(u, Z, inl, len);
    svduv(D, Z, V, 9, U, 8);
  }
  if (len > 8) {
    j = 0;
    for (i = 1; i < 9; i++)
      if (D[i] < D[j])
        j = i;
    p = V + j;
  } else
    p = V + 8;
  for (i = 0; i < 9; i++) {
    F[i] = *p;
    p += 9;
  }
  singulF(F);
  if (len > 8)
    denormF(F, A1, A2);
  if (buffer == NULL)
    free(Z);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <init@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <ok@plt>
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: operators

assistant: ```c
int main() {
  init("operators");
  test();
  return ok();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <init@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <ok@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string

tool: D7: operators

assistant: ```c
int main() {
  init("operators");
  test();
  return ok();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <init@plt>
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <ok@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: operators

assistant: ```c
int main() {
  init("operators");
  test();
  return ok();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <init@plt>
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <ok@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: operators

assistant: ```c
int main() {
  init("operators");
  test();
  return ok();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prog_v8add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %ax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %ax,-0xe(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %ax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %ax,-0xa(%rbp)
  movzwl -0x10(%rbp),%eax
  cmp    $0xff,%ax
  jg     L70
  movzwl -0x10(%rbp),%eax
  mov    %eax,%edx
  jmp    L62
L70:
  mov    $0xffffffff,%edx
L62:
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  movzwl -0xe(%rbp),%eax
  cmp    $0xff,%ax
  jg     L52
  movzwl -0xe(%rbp),%eax
  mov    %eax,%edx
  jmp    L4
L52:
  mov    $0xffffffff,%edx
L4:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  movzwl -0xc(%rbp),%eax
  cmp    $0xff,%ax
  jg     L1
  movzwl -0xc(%rbp),%eax
  mov    %eax,%edx
  jmp    L60
L1:
  mov    $0xffffffff,%edx
L60:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  movzwl -0xa(%rbp),%eax
  cmp    $0xff,%ax
  jg     L26
  movzwl -0xa(%rbp),%eax
  mov    %eax,%edx
  jmp    L53
L26:
  mov    $0xffffffff,%edx
L53:
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x2c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

assistant: ```c
int prog_v8add(int A, int B) {
  int res = 0;
  short tmp[4];
  unsigned char *a = (unsigned char *)&A;
  unsigned char *b = (unsigned char *)&B;
  unsigned char *c = (unsigned char *)&res;
  tmp[0] = (short)a[0] + (short)b[0];
  tmp[1] = (short)a[1] + (short)b[1];
  tmp[2] = (short)a[2] + (short)b[2];
  tmp[3] = (short)a[3] + (short)b[3];
  c[0] = (tmp[0] > 0xFF) ? 0xFF : ((unsigned char)tmp[0]);
  c[1] = (tmp[1] > 0xFF) ? 0xFF : ((unsigned char)tmp[1]);
  c[2] = (tmp[2] > 0xFF) ? 0xFF : ((unsigned char)tmp[2]);
  c[3] = (tmp[3] > 0xFF) ? 0xFF : ((unsigned char)tmp[3]);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prog_v8add>:
  endbr64
  mov    %edi,%edx
  movzbl %dil,%ecx
  movzbl %sil,%eax
  add    %eax,%ecx
  mov    $0xff,%eax
  cmp    %ax,%cx
  cmovg  %eax,%ecx
  mov    $0x0,%eax
  mov    %cl,%al
  mov    %edi,%ecx
  shr    $0x8,%cx
  mov    %esi,%edi
  shr    $0x8,%di
  add    %edi,%ecx
  mov    $0xff,%edi
  cmp    %di,%cx
  cmovg  %edi,%ecx
  mov    %cl,%ah
  mov    %edx,%ecx
  shr    $0x10,%ecx
  movzbl %cl,%ecx
  mov    %esi,%edi
  shr    $0x10,%edi
  movzbl %dil,%edi
  add    %edi,%ecx
  mov    $0xff,%edi
  cmp    %di,%cx
  cmovg  %edi,%ecx
  movzbl %cl,%ecx
  shl    $0x10,%ecx
  movzwl %ax,%eax
  shr    $0x18,%edx
  shr    $0x18,%esi
  add    %esi,%edx
  mov    $0xff,%esi
  cmp    %si,%dx
  cmovg  %esi,%edx
  shl    $0x18,%edx
  or     %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int prog_v8add(int A, int B) {
  int res = 0;
  short tmp[4];
  unsigned char *a = (unsigned char *)&A;
  unsigned char *b = (unsigned char *)&B;
  unsigned char *c = (unsigned char *)&res;
  tmp[0] = (short)a[0] + (short)b[0];
  tmp[1] = (short)a[1] + (short)b[1];
  tmp[2] = (short)a[2] + (short)b[2];
  tmp[3] = (short)a[3] + (short)b[3];
  c[0] = (tmp[0] > 0xFF) ? 0xFF : ((unsigned char)tmp[0]);
  c[1] = (tmp[1] > 0xFF) ? 0xFF : ((unsigned char)tmp[1]);
  c[2] = (tmp[2] > 0xFF) ? 0xFF : ((unsigned char)tmp[2]);
  c[3] = (tmp[3] > 0xFF) ? 0xFF : ((unsigned char)tmp[3]);
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<prog_v8add>:
  endbr64
  mov    %edi,%ecx
  push   %r13
  mov    %esi,%eax
  mov    %esi,%edx
  push   %r12
  shr    $0x8,%dx
  mov    %edi,%r9d
  movzbl %dil,%r13d
  push   %rbp
  mov    %edi,%ebp
  shr    $0x18,%r9d
  push   %rbx
  movzbl %ch,%ebx
  shr    $0x8,%bp
  mov    %r9d,%r8d
  mov    %ebx,%r10d
  movzbl %ah,%ebx
  add    %edx,%ebp
  mov    %esi,%edx
  mov    %ebx,%r12d
  mov    %edi,%ebx
  shr    $0x10,%edx
  movzbl %al,%edi
  shr    $0x10,%ebx
  movzbl %dl,%esi
  add    %edi,%r13d
  mov    $0xffffffff,%edi
  movzbl %bl,%r11d
  add    %esi,%r11d
  mov    %eax,%esi
  add    %ecx,%eax
  shr    $0x18,%esi
  add    %esi,%r8d
  cmp    $0x100,%r13w
  cmovae %edi,%eax
  xor    %ecx,%ecx
  cmp    $0x100,%bp
  mov    %al,%cl
  lea    (%r10,%r12,1),%eax
  cmovae %edi,%eax
  add    %ebx,%edx
  cmp    $0x100,%r11w
  pop    %rbx
  cmovae %edi,%edx
  pop    %rbp
  pop    %r12
  mov    %al,%ch
  pop    %r13
  movzbl %dl,%edx
  movzwl %cx,%eax
  lea    (%rsi,%r9,1),%ecx
  shl    $0x10,%edx
  cmp    $0x100,%r8w
  cmovae %edi,%ecx
  or     %edx,%eax
  shl    $0x18,%ecx
  or     %ecx,%eax
  ret
```

assistant: ```c
int prog_v8add(int A, int B) {
  int res = 0;
  short tmp[4];
  unsigned char *a = (unsigned char *)&A;
  unsigned char *b = (unsigned char *)&B;
  unsigned char *c = (unsigned char *)&res;
  tmp[0] = (short)a[0] + (short)b[0];
  tmp[1] = (short)a[1] + (short)b[1];
  tmp[2] = (short)a[2] + (short)b[2];
  tmp[3] = (short)a[3] + (short)b[3];
  c[0] = (tmp[0] > 0xFF) ? 0xFF : ((unsigned char)tmp[0]);
  c[1] = (tmp[1] > 0xFF) ? 0xFF : ((unsigned char)tmp[1]);
  c[2] = (tmp[2] > 0xFF) ? 0xFF : ((unsigned char)tmp[2]);
  c[3] = (tmp[3] > 0xFF) ? 0xFF : ((unsigned char)tmp[3]);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prog_v8add>:
  endbr64
  mov    %edi,%ecx
  push   %r13
  mov    %esi,%eax
  mov    %esi,%edx
  push   %r12
  shr    $0x8,%dx
  mov    %edi,%r9d
  movzbl %dil,%r13d
  push   %rbp
  mov    %edi,%ebp
  shr    $0x18,%r9d
  push   %rbx
  movzbl %ch,%ebx
  shr    $0x8,%bp
  mov    %r9d,%r8d
  mov    %ebx,%r10d
  movzbl %ah,%ebx
  add    %edx,%ebp
  mov    %esi,%edx
  mov    %ebx,%r12d
  mov    %edi,%ebx
  shr    $0x10,%edx
  movzbl %al,%edi
  shr    $0x10,%ebx
  movzbl %dl,%esi
  add    %edi,%r13d
  mov    $0xffffffff,%edi
  movzbl %bl,%r11d
  add    %esi,%r11d
  mov    %eax,%esi
  add    %ecx,%eax
  shr    $0x18,%esi
  add    %esi,%r8d
  cmp    $0x100,%r13w
  cmovae %edi,%eax
  xor    %ecx,%ecx
  cmp    $0x100,%bp
  mov    %al,%cl
  lea    (%r10,%r12,1),%eax
  cmovae %edi,%eax
  add    %ebx,%edx
  cmp    $0x100,%r11w
  pop    %rbx
  cmovae %edi,%edx
  pop    %rbp
  pop    %r12
  mov    %al,%ch
  pop    %r13
  movzbl %dl,%edx
  movzwl %cx,%eax
  lea    (%rsi,%r9,1),%ecx
  shl    $0x10,%edx
  cmp    $0x100,%r8w
  cmovae %edi,%ecx
  or     %edx,%eax
  shl    $0x18,%ecx
  or     %ecx,%eax
  ret
```

assistant: ```c
int prog_v8add(int A, int B) {
  int res = 0;
  short tmp[4];
  unsigned char *a = (unsigned char *)&A;
  unsigned char *b = (unsigned char *)&B;
  unsigned char *c = (unsigned char *)&res;
  tmp[0] = (short)a[0] + (short)b[0];
  tmp[1] = (short)a[1] + (short)b[1];
  tmp[2] = (short)a[2] + (short)b[2];
  tmp[3] = (short)a[3] + (short)b[3];
  c[0] = (tmp[0] > 0xFF) ? 0xFF : ((unsigned char)tmp[0]);
  c[1] = (tmp[1] > 0xFF) ? 0xFF : ((unsigned char)tmp[1]);
  c[2] = (tmp[2] > 0xFF) ? 0xFF : ((unsigned char)tmp[2]);
  c[3] = (tmp[3] > 0xFF) ? 0xFF : ((unsigned char)tmp[3]);
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L27:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L6
  mov    $0x0,%eax
  jmp    L14
L6:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L27
  mov    $0x1,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int Check(char *A, char *B, int lenght) {
  int i;
  for (i = 0; i < lenght; ++i) {
    if (*(A + i) != *(B + i))
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Check>:
  endbr64
  test   %edx,%edx
  jle    L21
  mov    %edx,%edx
  mov    $0x0,%eax
L6:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jne    L10
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
  mov    $0x1,%eax
  ret
L21:
  mov    $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Check(char *A, char *B, int lenght) {
  int i;
  for (i = 0; i < lenght; ++i) {
    if (*(A + i) != *(B + i))
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Check>:
  endbr64
  test   %edx,%edx
  jle    L14
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L30
  nop
L15:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L14
L30:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L15
  xor    %eax,%eax
  ret
  nopl   (%rax)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int Check(char *A, char *B, int lenght) {
  int i;
  for (i = 0; i < lenght; ++i) {
    if (*(A + i) != *(B + i))
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Check>:
  endbr64
  test   %edx,%edx
  jle    L38
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L21
  nop
L0:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L38
L21:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L0
  xor    %eax,%eax
  ret
  nopl   (%rax)
L38:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int Check(char *A, char *B, int lenght) {
  int i;
  for (i = 0; i < lenght; ++i) {
    if (*(A + i) != *(B + i))
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jbe    L8
  cmpl   $0x4,-0x14(%rbp)
  jne    L67
L8:
  mov    $0x0,%eax
  jmp    L41
L67:
  cmpl   $0x3,-0x14(%rbp)
  ja     L74
  mov    $0x1,%eax
  jmp    L41
L64:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x14(%rbp),%edx
  lea    -0x4(%rdx),%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <power@plt>
  cmp    $0x1,%eax
  je     L69
  mov    $0x0,%eax
  jmp    L41
L69:
  subl   $0x1,-0x18(%rbp)
L74:
  cmpl   $0x0,-0x18(%rbp)
  jg     L64
  mov    $0x1,%eax
L41:
  leave
  ret
```

assistant: ```c
bool isPrime(unsigned int n, int k) {
  if (n <= 1 || n == 4)
    return false;
  if (n <= 3)
    return true;
  while (k > 0) {
    int a = 2 + rand() % (n - 4);
    if (power(a, n - 1, n) != 1)
      return false;
    k--;
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isPrime>:
  endbr64
  cmp    $0x1,%edi
  jbe    L61
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  cmp    $0x4,%edi
  je     L28
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jbe    L39
  test   %esi,%esi
  jle    L37
  lea    -0x1(%rdi),%r12d
L20:
  mov    $0x0,%eax
  call   <rand@plt>
  lea    -0x4(%rbp),%ecx
  mov    $0x0,%edx
  div    %ecx
  lea    0x2(%rdx),%edi
  mov    %ebp,%edx
  mov    %r12d,%esi
  call   <power@plt>
  cmp    $0x1,%eax
  jne    L30
  sub    $0x1,%ebx
  jne    L20
  jmp    L39
L28:
  mov    $0x0,%eax
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    $0x1,%eax
  jmp    L39
L30:
  mov    $0x0,%eax
  jmp    L39
L61:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool isPrime(unsigned int n, int k) {
  if (n <= 1 || n == 4)
    return false;
  if (n <= 3)
    return true;
  while (k > 0) {
    int a = 2 + rand() % (n - 4);
    if (power(a, n - 1, n) != 1)
      return false;
    k--;
  }
  return true;
}
```