user: 这段汇编代码用C语言表示是什么样的？

```asm
<plfit_kolmogorov>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D97(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D15(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D18(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D14(%rip),%rax
  mov    %rax,0x28(%rsp)
  movapd %xmm0,%xmm3
  andpd  D103(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  movsd  D41(%rip),%xmm1
  movsd  D33(%rip),%xmm2
  comisd %xmm3,%xmm2
  ja     L29
  movsd  D121(%rip),%xmm1
  comisd %xmm3,%xmm1
  ja     L60
  movsd  D48(%rip),%xmm1
  comisd 0x8(%rsp),%xmm1
  ja     L18
  pxor   %xmm1,%xmm1
L29:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  movapd %xmm1,%xmm0
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L60:
  mulsd  %xmm0,%xmm0
  movsd  D41(%rip),%xmm5
  divsd  %xmm0,%xmm5
  movq   %xmm5,%rbp
  movapd %xmm5,%xmm0
  mulsd  D26(%rip),%xmm0
  call   <exp@plt>
  movq   %xmm0,%rbx
  movq   %rbp,%xmm0
  mulsd  D163(%rip),%xmm0
  call   <exp@plt>
  movq   %xmm0,%r12
  movq   %rbp,%xmm0
  mulsd  D4(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  movq   %r12,%xmm7
  addsd  %xmm7,%xmm0
  addsd  %xmm1,%xmm0
  mulsd  D101(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  movsd  D41(%rip),%xmm1
  subsd  %xmm0,%xmm1
  jmp    L29
L18:
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movsd  D88(%rip),%xmm1
  divsd  0x8(%rsp),%xmm1
  addsd  D100(%rip),%xmm1
  cvttsd2si %xmm1,%rbp
  test   %rbp,%rbp
  mov    $0x1,%eax
  cmovle %rax,%rbp
  mulsd  %xmm0,%xmm0
  movq   %xmm0,%r14
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r12
L15:
  movq   %r14,%xmm0
  mulsd  (%r12,%rbx,8),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x30(%rsp,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L15
  movsd  0x30(%rsp),%xmm1
  subsd  0x38(%rsp),%xmm1
  addsd  0x40(%rsp),%xmm1
  subsd  0x48(%rsp),%xmm1
  addsd  %xmm1,%xmm1
  jmp    L29
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D97
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D15
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D18
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D14
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D103
type_guessed: qword[2]
name: extract_symbolic_data
arguments: label: D41
type_guessed: f64
name: extract_symbolic_data
arguments: label: D33
type_guessed: f64
name: extract_symbolic_data
arguments: label: D121
type_guessed: f64
name: extract_symbolic_data
arguments: label: D48
type_guessed: f64
name: extract_symbolic_data
arguments: label: D26
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D163
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D4
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D101
type_guessed: f64
name: extract_symbolic_data
arguments: label: D88
type_guessed: f64
name: extract_symbolic_data
arguments: label: D100
type_guessed: f64

tool: {"D97": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0xc0]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x32,0xc0]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0xc0]}

tool: {"D103": [0x7fffffffffffffff,0x0000000000000000]}

tool: D41: 1

tool: D33: 0.2

tool: D121: 0.755

tool: D48: 6.8116

tool: {"D26": [0xde,0x45,0xbe,0xc9,0x3c,0xbd,0xf3,0xbf]}

tool: {"D163": [0x9a,0x0e,0xf6,0x62,0xe4,0x34,0x26,0xc0]}

tool: {"D4": [0x2b,0x4d,0x39,0xfb,0xae,0xd7,0x3e,0xc0]}

tool: D101: 2.50662827

tool: D88: 3

tool: D100: 0.5

assistant: ```c
double plfit_kolmogorov(double z) {
  const double fj[4] = {-2, -8, -18, -32};
  const double w = 2.50662827;
  const double c1 = -1.2337005501361697;
  const double c2 = -11.103304951225528;
  const double c3 = -30.842513753404244;
  double u = fabs(z);
  double v;
  if (u < 0.2)
    return 1;
  if (u < 0.755) {
    v = 1.0 / (u * u);
    return 1 - w * (exp(c1 * v) + exp(c2 * v) + exp(c3 * v)) / u;
  }
  if (u < 6.8116) {
    double r[4] = {0, 0, 0, 0};
    long int maxj = (long int)(3.0 / u + 0.5);
    long int j;
    if (maxj < 1)
      maxj = 1;
    v = u * u;
    for (j = 0; j < maxj; j++) {
      r[j] = exp(fj[j] * v);
    }
    return 2 * (r[0] - r[1] + r[2] - r[3]);
  }
  return 0;
}
```