ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L111:
  cmp    $0x3,%rbx
  je     L65
L18:
  mov    %rbx,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  jne    L102
L2:
  test   %bp,%bp
  jne    L98
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L18
L65:
  mov    $0x3,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  jne    L6
L98:
  mov    0x8(%rsp),%rdi
  add    $0x2,%rbx
  mov    %rdi,%rax
  shr    %rax
  cmp    %rax,%rbx
  jbe    L103
  call   <is_prime@plt>
  test   %rax,%rax
  jne    L69
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L102:
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    %rbx,%rsi
  call   <print_repetition@plt>
  jmp    L2
L69:
  mov    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rdi,%rsi
  call   <print_repetition@plt>
  jmp    L47
L6:
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    $0x3,%esi
  call   <print_repetition@plt>
  jmp    L98
L103:
  mov    $0x1,%ebp
  jmp    L111
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D12
type: string
name: disassemble_data
arguments: tag: D22
type: string

tool: D16: Please, enter a positive number to factorize:  

tool: D12: %lu

tool: D22: 

%lu: 

assistant: ```c
int main(void) {
  unsigned long int number, index, rep;
  short int two_flag = 0;
  printf("Please, enter a positive number to factorize:  ");
  scanf("%lu", &number);
  printf("\n\n%lu: ", number);
  index = 2;
  do {
    if (index == 3)
      two_flag = 1;
    if (is_prime(index)) {
      print_repetition(number, index, &rep);
    }
    if (two_flag == 0) {
      index++;
    } else {
      index += 2;
    }
  } while ((index <= (number / 2)) || !two_flag);
  if (is_prime(number)) {
    print_repetition(number, number, &rep);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L86:
  cmp    $0x3,%rbx
  je     L94
L73:
  mov    %rbx,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  jne    L15
L55:
  test   %bp,%bp
  jne    L118
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L73
L94:
  mov    $0x3,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  jne    L81
L118:
  mov    0x8(%rsp),%rdi
  add    $0x2,%rbx
  mov    %rdi,%rax
  shr    %rax
  cmp    %rax,%rbx
  jbe    L75
  call   <is_prime@plt>
  test   %rax,%rax
  jne    L32
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    %rbx,%rsi
  call   <print_repetition@plt>
  jmp    L55
L32:
  mov    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rdi,%rsi
  call   <print_repetition@plt>
  jmp    L20
L81:
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    $0x3,%esi
  call   <print_repetition@plt>
  jmp    L118
L75:
  mov    $0x1,%ebp
  jmp    L86
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string
name: retrieve_data
arguments: data_label: D21
data_type: string

tool: D16: Please, enter a positive number to factorize:  

tool: D23: %lu

tool: D21: 

%lu: 

assistant: ```c
int main(void) {
  unsigned long int number, index, rep;
  short int two_flag = 0;
  printf("Please, enter a positive number to factorize:  ");
  scanf("%lu", &number);
  printf("\n\n%lu: ", number);
  index = 2;
  do {
    if (index == 3)
      two_flag = 1;
    if (is_prime(index)) {
      print_repetition(number, index, &rep);
    }
    if (two_flag == 0) {
      index++;
    } else {
      index += 2;
    }
  } while ((index <= (number / 2)) || !two_flag);
  if (is_prime(number)) {
    print_repetition(number, number, &rep);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ff_get_fourcc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x4,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x18,%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int ff_get_fourcc(char *s) {
  assert(strlen(s) == 4);
  return (s[0]) + (s[1] << 8) + (s[2] << 16) + (s[3] << 24);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ff_get_fourcc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x4,%rax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  movsbl 0x1(%rbx),%eax
  shl    $0x8,%eax
  movsbl (%rbx),%edx
  add    %edx,%eax
  movsbl 0x2(%rbx),%edx
  shl    $0x10,%edx
  add    %edx,%eax
  movsbl 0x3(%rbx),%edx
  shl    $0x18,%edx
  add    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ff_get_fourcc(char *s) {
  assert(strlen(s) == 4);
  return (s[0]) + (s[1] << 8) + (s[2] << 16) + (s[3] << 24);
}
```
user: What is the c source code of the assembly code below:

```asm
<ff_get_fourcc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    $0x4,%rax
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  movsbl 0x1(%rbx),%eax
  movsbl (%rbx),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movsbl 0x2(%rbx),%edx
  shl    $0x10,%edx
  add    %edx,%eax
  movsbl 0x3(%rbx),%edx
  pop    %rbx
  shl    $0x18,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int ff_get_fourcc(char *s) {
  assert(strlen(s) == 4);
  return (s[0]) + (s[1] << 8) + (s[2] << 16) + (s[3] << 24);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ff_get_fourcc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    $0x4,%rax
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  movsbl 0x1(%rbx),%eax
  movsbl (%rbx),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movsbl 0x2(%rbx),%edx
  shl    $0x10,%edx
  add    %edx,%eax
  movsbl 0x3(%rbx),%edx
  pop    %rbx
  shl    $0x18,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int ff_get_fourcc(char *s) {
  assert(strlen(s) == 4);
  return (s[0]) + (s[1] << 8) + (s[2] << 16) + (s[3] << 24);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<long_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  shrq   -0x18(%rbp)
  jmp    L13
L17:
  addl   $0x1,-0x4(%rbp)
  shrq   -0x18(%rbp)
L13:
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int __attribute__((pure)) long_log2(unsigned long x) {
  int r = 0;
  for (x >>= 1; x > 0; x >>= 1)
    r++;
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<long_log2>:
  endbr64
  shr    %rdi
  je     L3
  mov    $0x0,%eax
L13:
  add    $0x1,%eax
  shr    %rdi
  jne    L13
  ret
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int __attribute__((pure)) long_log2(unsigned long x) {
  int r = 0;
  for (x >>= 1; x > 0; x >>= 1)
    r++;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<long_log2>:
  endbr64
  xor    %eax,%eax
  shr    %rdi
  je     L10
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%eax
  shr    %rdi
  jne    L8
  ret
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
__attribute__((always_)) int __attribute__((pure)) long_log2(unsigned long x) {
  int r = 0;
  for (x >>= 1; x > 0; x >>= 1)
    r++;
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<long_log2>:
  endbr64
  xor    %eax,%eax
  shr    %rdi
  je     L11
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%eax
  shr    %rdi
  jne    L17
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
__attribute__((always_)) int __attribute__((pure)) long_log2(unsigned long x) {
  int r = 0;
  for (x >>= 1; x > 0; x >>= 1)
    r++;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arr_min_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L27
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L4
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L4:
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int arr_min_i(int x[], int n) {
  int i;
  int y = x[0];
  for (i = 1; i < n; i++)
    if (x[i] < y)
      y = x[i];
  return y;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<arr_min_i>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x1,%esi
  jle    L6
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%ecx
  lea    0x8(%rdi,%rcx,4),%rsi
L7:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L7
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
int arr_min_i(int x[], int n) {
  int i;
  int y = x[0];
  for (i = 1; i < n; i++)
    if (x[i] < y)
      y = x[i];
  return y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arr_min_i>:
  endbr64
  mov    (%rdi),%r8d
  cmp    $0x1,%esi
  jle    L10
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  cmovg  %edx,%r8d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L5
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int arr_min_i(int x[], int n) {
  int i;
  int y = x[0];
  for (i = 1; i < n; i++)
    if (x[i] < y)
      y = x[i];
  return y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<arr_min_i>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rdx
  mov    %esi,%ecx
  cmp    $0x1,%esi
  jle    L67
  lea    -0x1(%rsi),%edi
  lea    -0x2(%rsi),%esi
  cmp    $0x2,%esi
  jbe    L50
  mov    %edi,%esi
  movd   %eax,%xmm4
  lea    0x4(%rdx),%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm4,%xmm0
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x14(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax)
L61:
  movdqu (%rax),%xmm1
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm3,%xmm1
  por    %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L61
  movdqa %xmm0,%xmm2
  mov    %edi,%r8d
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%r8d
  movdqa %xmm2,%xmm1
  lea    0x1(%r8),%esi
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %r8d,%edi
  je     L18
L55:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r8
  mov    (%rdx,%rdi,4),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  lea    0x1(%rsi),%edi
  cmp    %edi,%ecx
  jle    L67
  mov    0x4(%rdx,%r8,1),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L67
  mov    0x8(%rdx,%r8,1),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L67:
  ret
  nopl   (%rax)
L18:
  ret
L50:
  mov    $0x1,%esi
  jmp    L55
```

assistant: ```c
int arr_min_i(int x[], int n) {
  int i;
  int y = x[0];
  for (i = 1; i < n; i++)
    if (x[i] < y)
      y = x[i];
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movd   %eax,%xmm0
  call   <print@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: 


assistant: ```c
void print1(float *in, int x) {
  for (int i = 0; i < x; i++)
    print(in[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L5
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
L15:
  movss  (%rbx),%xmm0
  call   <print@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L15
L5:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D9: 


assistant: ```c
void print1(float *in, int x) {
  for (int i = 0; i < x; i++)
    print(in[i]);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print1>:
  endbr64
  test   %esi,%esi
  jle    L10
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L13:
  movss  (%rbx),%xmm0
  add    $0x4,%rbx
  call   <print@plt>
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  lea    D2(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L10:
  lea    D2(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: 


assistant: ```c
void print1(float *in, int x) {
  for (int i = 0; i < x; i++)
    print(in[i]);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print1>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  movss  (%rbx),%xmm0
  add    $0x4,%rbx
  call   <print@plt>
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  lea    D5(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L15:
  lea    D5(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: 


assistant: ```c
void print1(float *in, int x) {
  for (int i = 0; i < x; i++)
    print(in[i]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<voltea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L9
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  subq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L1
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *voltea(char *cadena) {
  int len;
  char *buffer;
  char *inicio = cadena;
  char *start;
  len = strlen(cadena);
  buffer = (char *)malloc(len);
  start = buffer;
  char *p = inicio + len - 1;
  while (inicio <= p) {
    *buffer = *p;
    p--;
    buffer++;
  }
  *buffer = '\0';
  return start;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<voltea>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  movslq %ebp,%rbp
  lea    -0x1(%rbx,%rbp,1),%r9
  cmp    %r9,%rbx
  ja     L22
  lea    -0x1(%rbx),%r8
  mov    %r9,%rdx
  lea    (%rax,%r9,1),%rdi
L2:
  movzbl (%rdx),%esi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  mov    %sil,(%rcx)
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L2
  sub    %rbx,%r9
  lea    0x1(%rax,%r9,1),%rdx
L13:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    %rax,%rdx
  jmp    L13
```

assistant: ```c
char *voltea(char *cadena) {
  int len;
  char *buffer;
  char *inicio = cadena;
  char *start;
  len = strlen(cadena);
  buffer = (char *)malloc(len);
  start = buffer;
  char *p = inicio + len - 1;
  while (inicio <= p) {
    *buffer = *p;
    p--;
    buffer++;
  }
  *buffer = '\0';
  return start;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<voltea>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbp
  mov    %ebp,%edi
  call   <malloc@plt>
  lea    -0x1(%rbx,%rbp,1),%r9
  cmp    %r9,%rbx
  ja     L13
  lea    -0x1(%rbx),%r8
  mov    %r9,%rdx
  lea    (%rax,%r9,1),%rdi
  nopl   0x0(%rax)
L4:
  movzbl (%rdx),%esi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  sub    $0x1,%rdx
  mov    %sil,(%rcx)
  cmp    %r8,%rdx
  jne    L4
  sub    %rbx,%r9
  lea    0x1(%rax,%r9,1),%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L13:
  mov    %rax,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *voltea(char *cadena) {
  int len;
  char *buffer;
  char *inicio = cadena;
  char *start;
  len = strlen(cadena);
  buffer = (char *)malloc(len);
  start = buffer;
  char *p = inicio + len - 1;
  while (inicio <= p) {
    *buffer = *p;
    p--;
    buffer++;
  }
  *buffer = '\0';
  return start;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<voltea>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbp
  mov    %ebp,%edi
  call   <malloc@plt>
  lea    -0x1(%rbx,%rbp,1),%r9
  cmp    %r9,%rbx
  ja     L3
  lea    -0x1(%rbx),%r8
  mov    %r9,%rdx
  lea    (%rax,%r9,1),%rdi
  nopl   0x0(%rax)
L17:
  movzbl (%rdx),%esi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  sub    $0x1,%rdx
  mov    %sil,(%rcx)
  cmp    %r8,%rdx
  jne    L17
  sub    %rbx,%r9
  lea    0x1(%rax,%r9,1),%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L3:
  mov    %rax,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *voltea(char *cadena) {
  int len;
  char *buffer;
  char *inicio = cadena;
  char *start;
  len = strlen(cadena);
  buffer = (char *)malloc(len);
  start = buffer;
  char *p = inicio + len - 1;
  while (inicio <= p) {
    *buffer = *p;
    p--;
    buffer++;
  }
  *buffer = '\0';
  return start;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ntt32_fft>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r15
  mov    %rcx,0x28(%rsp)
  mov    %rsi,%rdx
  shr    %rdx
  lea    -0x1(%rsi),%rsi
  cmp    $0x1,%rsi
  jbe    L59
  mov    $0x1,%ecx
  jmp    L1
L41:
  mov    %r13,%rax
L11:
  shr    %rax
  xor    %rax,%rdx
  test   %rdx,%rax
  je     L11
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  je     L59
L1:
  cmp    %rdx,%rcx
  jae    L41
  mov    0x0(%rbp,%rcx,8),%rdi
  lea    0x0(%rbp,%rdx,8),%rax
  mov    (%rax),%r8
  mov    %r8,0x0(%rbp,%rcx,8)
  mov    %rdi,(%rax)
  jmp    L41
L59:
  cmp    $0x1,%r13
  jbe    L13
  movq   $0x1,0x18(%rsp)
L113:
  mov    %r13,%rax
  mov    0x18(%rsp),%rcx
  mov    $0x0,%edx
  div    %rcx
  lea    (%rcx,%rcx,1),%rsi
  mov    %rsi,(%rsp)
  lea    0x0(%rbp,%rcx,8),%r12
  mov    $0x0,%edx
L39:
  mov    (%r12,%rdx,8),%rsi
  mov    0x0(%rbp,%rdx,8),%rcx
  sub    %rsi,%rcx
  mov    %rcx,(%r12,%rdx,8)
  add    %rsi,0x0(%rbp,%rdx,8)
  add    (%rsp),%rdx
  cmp    %rdx,%r13
  ja     L39
  cmpq   $0x1,0x18(%rsp)
  jbe    L31
  shl    $0x3,%rax
  mov    %rax,0x20(%rsp)
  mov    0x28(%rsp),%rcx
  add    %rax,%rcx
  mov    %rcx,0x10(%rsp)
  movq   $0x1,0x8(%rsp)
L112:
  mov    0x10(%rsp),%rax
  mov    (%rax),%r14
  mov    0x8(%rsp),%rax
  cmp    %rax,%r13
  jbe    L83
  mov    %rax,%rbx
L76:
  mov    (%r12,%rbx,8),%rdi
  mov    %r15,%rdx
  mov    %r14,%rsi
  call   <ntt32_muln@plt>
  mov    0x0(%rbp,%rbx,8),%rdx
  sub    %rax,%rdx
  mov    %rdx,(%r12,%rbx,8)
  add    %rax,0x0(%rbp,%rbx,8)
  add    (%rsp),%rbx
  cmp    %rbx,%r13
  ja     L76
L83:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  mov    0x20(%rsp),%rsi
  add    %rsi,0x10(%rsp)
  cmp    0x18(%rsp),%rax
  jne    L112
L31:
  shlq   0x18(%rsp)
  mov    0x18(%rsp),%rax
  cmp    %rax,%r13
  ja     L113
L13:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ntt32_fft(int32_t v[], size_t n, int32_t q, const int32_t w[]) {
  size_t i, j, k, l;
  int32_t x, y;
  j = n >> 1;
  for (i = 1; i < n - 1; i++) {
    if (i < j) {
      x = v[i];
      v[i] = v[j];
      v[j] = x;
    }
    k = n;
    do {
      k >>= 1;
      j ^= k;
    } while ((j & k) == 0);
  }
  for (i = 1; i < n; i <<= 1) {
    l = n / i;
    for (k = 0; k < n; k += i + i) {
      x = v[k + i];
      v[k + i] = v[k] - x;
      v[k] = v[k] + x;
    }
    for (j = 1; j < i; j++) {
      y = w[j * l];
      for (k = j; k < n; k += i + i) {
        x = ntt32_muln(v[k + i], y, q);
        v[k + i] = v[k] - x;
        v[k] = v[k] + x;
      }
    }
  }
}
```