ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<poly_mul_sub1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x170,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %rsi,-0x140(%rbp)
  mov    %rdx,-0x148(%rbp)
  mov    %rcx,-0x150(%rbp)
  mov    %r8d,-0x154(%rbp)
  mov    %r9d,-0x158(%rbp)
  mov    0x20(%rbp),%rax
  mov    %rax,-0x160(%rbp)
  mov    0x28(%rbp),%rax
  mov    %rax,-0x168(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x128(%rbp),%r8
  lea    -0x120(%rbp),%rdi
  mov    -0x158(%rbp),%ecx
  mov    -0x154(%rbp),%edx
  mov    -0x140(%rbp),%rsi
  mov    -0x138(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <poly_mul1@plt>
  lea    -0x124(%rbp),%rdi
  lea    -0x90(%rbp),%rcx
  mov    0x18(%rbp),%edx
  mov    -0x150(%rbp),%rsi
  mov    -0x148(%rbp),%rax
  mov    %rdi,%r9
  mov    %rcx,%r8
  mov    %edx,%ecx
  mov    0x10(%rbp),%edx
  mov    %rax,%rdi
  call   <poly_mul1@plt>
  mov    -0x124(%rbp),%ecx
  mov    -0x128(%rbp),%edx
  mov    -0x168(%rbp),%r8
  mov    -0x160(%rbp),%rdi
  lea    -0x90(%rbp),%rsi
  lea    -0x120(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <poly_sub1@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void poly_mul_sub1(double u1[17], double u2[17], double u3[17], double u4[17], int p1, int p2, int p3, int p4, double u5[17], int *p5) {
  double d1[17], d2[17];
  int pd1, pd2;
  poly_mul1(u1, u2, p1, p2, d1, &pd1);
  poly_mul1(u3, u4, p3, p4, d2, &pd2);
  poly_sub1(d1, d2, pd1, pd2, u5, p5);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<poly_mul_sub1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x138,%rsp
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %r8d,%edx
  mov    %r9d,%ecx
  mov    0x180(%rsp),%r13
  mov    0x188(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%r9
  mov    %r12,%r8
  call   <poly_mul1@plt>
  lea    0xa0(%rsp),%r15
  lea    0xc(%rsp),%r9
  mov    %r15,%r8
  mov    0x178(%rsp),%ecx
  mov    0x170(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <poly_mul1@plt>
  mov    %r14,%r9
  mov    %r13,%r8
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <poly_sub1@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void poly_mul_sub1(double u1[17], double u2[17], double u3[17], double u4[17], int p1, int p2, int p3, int p4, double u5[17], int *p5) {
  double d1[17], d2[17];
  int pd1, pd2;
  poly_mul1(u1, u2, p1, p2, d1, &pd1);
  poly_mul1(u3, u4, p3, p4, d2, &pd2);
  poly_sub1(d1, d2, pd1, pd2, u5, p5);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<poly_mul_sub1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  mov    %r9d,%ecx
  push   %rbp
  mov    %rdx,%rbp
  mov    %r8d,%edx
  push   %rbx
  sub    $0x138,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r9
  mov    0x180(%rsp),%rbx
  mov    %r13,%r8
  mov    0x188(%rsp),%r14
  lea    0xa0(%rsp),%r15
  call   <poly_mul1@plt>
  lea    0xc(%rsp),%r9
  mov    %r15,%r8
  mov    %r12,%rsi
  mov    0x178(%rsp),%ecx
  mov    0x170(%rsp),%edx
  mov    %rbp,%rdi
  call   <poly_mul1@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <poly_sub1@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void poly_mul_sub1(double u1[17], double u2[17], double u3[17], double u4[17], int p1, int p2, int p3, int p4, double u5[17], int *p5) {
  double d1[17], d2[17];
  int pd1, pd2;
  poly_mul1(u1, u2, p1, p2, d1, &pd1);
  poly_mul1(u3, u4, p3, p4, d2, &pd2);
  poly_sub1(d1, d2, pd1, pd2, u5, p5);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<poly_mul_sub1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  mov    %r9d,%ecx
  push   %rbp
  mov    %rdx,%rbp
  mov    %r8d,%edx
  push   %rbx
  sub    $0x138,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r9
  mov    0x180(%rsp),%rbx
  mov    %r13,%r8
  mov    0x188(%rsp),%r14
  lea    0xa0(%rsp),%r15
  call   <poly_mul1@plt>
  lea    0xc(%rsp),%r9
  mov    %r15,%r8
  mov    %r12,%rsi
  mov    0x178(%rsp),%ecx
  mov    0x170(%rsp),%edx
  mov    %rbp,%rdi
  call   <poly_mul1@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <poly_sub1@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void poly_mul_sub1(double u1[17], double u2[17], double u3[17], double u4[17], int p1, int p2, int p3, int p4, double u5[17], int *p5) {
  double d1[17], d2[17];
  int pd1, pd2;
  poly_mul1(u1, u2, p1, p2, d1, &pd1);
  poly_mul1(u3, u4, p3, p4, d2, &pd2);
  poly_sub1(d1, d2, pd1, pd2, u5, p5);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trio_nzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   D4(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: f32[2]

tool: {"D4": [0.0,-0.0]}

assistant: ```c
double trio_nzero(void) {
  volatile double zero = 0.0;
  return -zero;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trio_nzero>:
  endbr64
  movq   $0x0,-0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  xorpd  D7(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: f32[4]

tool: {"D7": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double trio_nzero(void) {
  volatile double zero = 0.0;
  return -zero;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<trio_nzero>:
  endbr64
  movq   $0x0,-0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  xorpd  D5(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: f32[4]

tool: {"D5": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double trio_nzero(void) {
  volatile double zero = 0.0;
  return -zero;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trio_nzero>:
  endbr64
  movq   $0x0,-0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  xorpd  D6(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: f32[4]

tool: {"D6": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double trio_nzero(void) {
  volatile double zero = 0.0;
  return -zero;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RSA_padding_add_SSLv23>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0xa,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L37
  mov    $0x0,%eax
  jmp    L16
L37:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2,(%rax)
  mov    -0x1c(%rbp),%eax
  sub    $0xb,%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L63
L56:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L63:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L56
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
L13:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
L78:
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  addq   $0x8,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x1,%eax
L16:
  leave
  ret
```

assistant: ```c
int RSA_padding_add_SSLv23(unsigned char *to, int tlen, unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > (tlen - 11))
    return (0);
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - 8 - flen;
  for (i = 0; i < j; i++) {
    *p = rand() & 0xFF;
    p++;
  }
  for (i = 0; i < j; i++) {
    if (*p == '\0')
      do {
        *p = rand() & 0xFF;
        p++;
      } while (*p == '\0');
    p++;
  }
  memset(p, 3, 8);
  p += 8;
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RSA_padding_add_SSLv23>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  mov    %ecx,%r12d
  lea    -0xa(%rsi),%ecx
  mov    $0x0,%edx
  cmp    %r12d,%ecx
  jle    L12
  movb   $0x0,(%rdi)
  lea    0x2(%rdi),%rbx
  movb   $0x2,0x1(%rdi)
  lea    -0xb(%rsi),%r14d
  sub    %r12d,%r14d
  test   %r14d,%r14d
  jle    L2
  lea    -0x1(%r14),%edx
  lea    0x3(%rdi,%rdx,1),%r15
  mov    %rbx,%rbp
L41:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %r15,%rbp
  jne    L41
  mov    %r14d,%eax
  add    %rax,%rbx
  mov    $0x0,%ebp
  jmp    L48
L4:
  add    $0x1,%rbx
  add    $0x1,%ebp
  cmp    %ebp,%r14d
  je     L2
L48:
  cmpb   $0x0,(%rbx)
  jne    L4
L61:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L61
  jmp    L4
L2:
  mov    $0x8,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movb   $0x0,0x8(%rbx)
  lea    0x9(%rbx),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    $0x1,%edx
L12:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int RSA_padding_add_SSLv23(unsigned char *to, int tlen, unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > (tlen - 11))
    return (0);
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - 8 - flen;
  for (i = 0; i < j; i++) {
    *p = rand() & 0xFF;
    p++;
  }
  for (i = 0; i < j; i++) {
    if (*p == '\0')
      do {
        *p = rand() & 0xFF;
        p++;
      } while (*p == '\0');
    p++;
  }
  memset(p, 3, 8);
  p += 8;
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RSA_padding_add_SSLv23>:
  endbr64
  push   %r15
  xor    %r8d,%r8d
  push   %r14
  push   %r13
  mov    %rdx,%r13
  lea    -0xa(%rsi),%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%edx
  jle    L68
  lea    -0xb(%rsi),%r14d
  mov    $0x200,%edx
  lea    0x2(%rdi),%rbx
  mov    %ecx,%r12d
  sub    %ecx,%r14d
  mov    %dx,(%rdi)
  test   %r14d,%r14d
  jle    L78
  lea    -0x1(%r14),%edx
  mov    %rbx,%rbp
  lea    0x3(%rdi,%rdx,1),%r15
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <rand@plt>
  mov    %al,-0x1(%rbp)
  cmp    %r15,%rbp
  jne    L22
  mov    %r14d,%eax
  xor    %ebp,%ebp
  add    %rax,%rbx
  jmp    L30
  nopl   (%rax)
L71:
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r14d
  je     L78
L30:
  cmpb   $0x0,(%rbx)
  jne    L71
  nopl   0x0(%rax)
L41:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rand@plt>
  mov    %al,-0x1(%rbx)
  cmpb   $0x0,(%rbx)
  je     L41
  jmp    L71
  nopl   (%rax)
L78:
  mov    $0x8,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movb   $0x0,0x8(%rbx)
  lea    0x9(%rbx),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    $0x1,%r8d
L68:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int RSA_padding_add_SSLv23(unsigned char *to, int tlen, unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > (tlen - 11))
    return (0);
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - 8 - flen;
  for (i = 0; i < j; i++) {
    *p = rand() & 0xFF;
    p++;
  }
  for (i = 0; i < j; i++) {
    if (*p == '\0')
      do {
        *p = rand() & 0xFF;
        p++;
      } while (*p == '\0');
    p++;
  }
  memset(p, 3, 8);
  p += 8;
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RSA_padding_add_SSLv23>:
  endbr64
  push   %r15
  xor    %r8d,%r8d
  push   %r14
  push   %r13
  mov    %rdx,%r13
  lea    -0xa(%rsi),%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%edx
  jle    L32
  lea    -0xb(%rsi),%r14d
  mov    $0x200,%edx
  lea    0x2(%rdi),%rbx
  mov    %ecx,%r12d
  sub    %ecx,%r14d
  mov    %dx,(%rdi)
  test   %r14d,%r14d
  jle    L41
  lea    -0x1(%r14),%edx
  mov    %rbx,%rbp
  lea    0x3(%rdi,%rdx,1),%r15
  nopw   0x0(%rax,%rax,1)
L61:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <rand@plt>
  mov    %al,-0x1(%rbp)
  cmp    %r15,%rbp
  jne    L61
  mov    %r14d,%eax
  xor    %ebp,%ebp
  add    %rax,%rbx
  jmp    L7
  nopl   (%rax)
L12:
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r14d
  je     L41
L7:
  cmpb   $0x0,(%rbx)
  jne    L12
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rand@plt>
  mov    %al,-0x1(%rbx)
  cmpb   $0x0,(%rbx)
  je     L14
  jmp    L12
  nopl   (%rax)
L41:
  mov    $0x8,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movb   $0x0,0x8(%rbx)
  lea    0x9(%rbx),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    $0x1,%r8d
L32:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int RSA_padding_add_SSLv23(unsigned char *to, int tlen, unsigned char *from, int flen) {
  int i, j;
  unsigned char *p;
  if (flen > (tlen - 11))
    return (0);
  p = (unsigned char *)to;
  *(p++) = 0;
  *(p++) = 2;
  j = tlen - 3 - 8 - flen;
  for (i = 0; i < j; i++) {
    *p = rand() & 0xFF;
    p++;
  }
  for (i = 0; i < j; i++) {
    if (*p == '\0')
      do {
        *p = rand() & 0xFF;
        p++;
      } while (*p == '\0');
    p++;
  }
  memset(p, 3, 8);
  p += 8;
  *(p++) = '\0';
  memcpy(p, from, (unsigned int)flen);
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  mov    -0x1c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D28(%rip),%xmm2
  divsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm3,%xmm3
  cvtss2sd -0x14(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: f64
name: parse_data
arguments: label: D64
data_type: string
name: parse_data
arguments: label: D61
data_type: string
name: parse_data
arguments: label: D21
data_type: string
name: parse_data
arguments: label: D28
data_type: f64
name: parse_data
arguments: label: D54
data_type: string
name: parse_data
arguments: label: D22
data_type: string

tool: D2: 3.14

tool: D64: Yaricap deger giriniz      : 

tool: D61: %d

tool: D21: Merkez aci degerini giriniz: 

tool: D28: 360

tool: D54: 
==================================

tool: D22: 
Acinin taradigi alan %.3f cm-dir.

assistant: ```c
int main() {
  const double pi = 3.14;
  int r, X;
  float A;
  printf("Yaricap deger giriniz      : ");
  scanf("%d", &r);
  printf("Merkez aci degerini giriniz: ");
  scanf("%d", &X);
  A = pi * r * r * (X / 360.0);
  printf("\n==================================");
  printf("\nAcinin taradigi alan %.3f cm-dir.", A);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sdl 0x10(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x14(%rsp),%xmm0
  divsd  D65(%rip),%xmm0
  movapd %xmm2,%xmm1
  mulsd  D34(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm3,%xmm3
  cvtsd2ss %xmm0,%xmm3
  movss  %xmm3,0xc(%rsp)
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  lea    D66(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D65
type_infered: f64
name: parse_data
arguments: data_tag: D34
type_infered: f64
name: parse_data
arguments: data_tag: D12
type_infered: string
name: parse_data
arguments: data_tag: D66
type_infered: string

tool: D1: Yaricap deger giriniz      : 

tool: D26: %d

tool: D27: Merkez aci degerini giriniz: 

tool: D65: 360

tool: D34: 3.14

tool: D12: 
==================================

tool: D66: 
Acinin taradigi alan %.3f cm-dir.

assistant: ```c
int main() {
  const double pi = 3.14;
  int r, X;
  float A;
  printf("Yaricap deger giriniz      : ");
  scanf("%d", &r);
  printf("Merkez aci degerini giriniz: ");
  scanf("%d", &X);
  A = pi * r * r * (X / 360.0);
  printf("\n==================================");
  printf("\nAcinin taradigi alan %.3f cm-dir.", A);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D56(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  cvtsi2sdl 0x10(%rsp),%xmm2
  movsd  D62(%rip),%xmm1
  lea    D24(%rip),%rdi
  cvtsi2sdl 0x14(%rsp),%xmm0
  divsd  D57(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D51(%rip),%rdi
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
data_type: string
name: retrieve_data
arguments: data_tag: D56
data_type: string
name: retrieve_data
arguments: data_tag: D23
data_type: string
name: retrieve_data
arguments: data_tag: D62
data_type: f64
name: retrieve_data
arguments: data_tag: D24
data_type: string
name: retrieve_data
arguments: data_tag: D57
data_type: f64
name: retrieve_data
arguments: data_tag: D51
data_type: string

tool: D28: Yaricap deger giriniz      : 

tool: D56: %d

tool: D23: Merkez aci degerini giriniz: 

tool: D62: 3.14

tool: D24: 
==================================

tool: D57: 360

tool: D51: 
Acinin taradigi alan %.3f cm-dir.

assistant: ```c
int main() {
  const double pi = 3.14;
  int r, X;
  float A;
  printf("Yaricap deger giriniz      : ");
  scanf("%d", &r);
  printf("Merkez aci degerini giriniz: ");
  scanf("%d", &X);
  A = pi * r * r * (X / 360.0);
  printf("\n==================================");
  printf("\nAcinin taradigi alan %.3f cm-dir.", A);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D55(%rip),%rdi
  lea    D26(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  cvtsi2sdl 0x10(%rsp),%xmm2
  movsd  D34(%rip),%xmm1
  lea    D47(%rip),%rdi
  cvtsi2sdl 0x14(%rsp),%xmm0
  divsd  D41(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D18(%rip),%rdi
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D55
type_guessed: string
name: unpack_data
arguments: label: D26
type_guessed: string
name: unpack_data
arguments: label: D60
type_guessed: string
name: unpack_data
arguments: label: D34
type_guessed: f64
name: unpack_data
arguments: label: D47
type_guessed: string
name: unpack_data
arguments: label: D41
type_guessed: f64
name: unpack_data
arguments: label: D18
type_guessed: string

tool: D55: Yaricap deger giriniz      : 

tool: D26: %d

tool: D60: Merkez aci degerini giriniz: 

tool: D34: 3.14

tool: D47: 
==================================

tool: D41: 360

tool: D18: 
Acinin taradigi alan %.3f cm-dir.

assistant: ```c
int main() {
  const double pi = 3.14;
  int r, X;
  float A;
  printf("Yaricap deger giriniz      : ");
  scanf("%d", &r);
  printf("Merkez aci degerini giriniz: ");
  scanf("%d", &X);
  A = pi * r * r * (X / 360.0);
  printf("\n==================================");
  printf("\nAcinin taradigi alan %.3f cm-dir.", A);
}
```