ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<skb_transport_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <skb_network_header@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <skb_ether_protocol@plt>
  mov    D12(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L28
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  shl    $0x2,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  jmp    L10
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <skb_ether_protocol@plt>
  mov    D2(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L7
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  jmp    L10
L7:
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
unsigned char *skb_transport_header(struct sk_buff *skb) {
  unsigned char *h = skb_network_header(skb);
  if (skb_ether_protocol(skb) == ETH_P_IP)
    return h + 4 * ((*h) & 0xF);
  if (skb_ether_protocol(skb) == ETH_P_IPV6)
    return h + 20;
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skb_transport_header>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <skb_network_header@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <skb_ether_protocol@plt>
  mov    D4(%rip),%rdx
  cmp    (%rdx),%rax
  je     L15
  mov    %rbp,%rdi
  call   <skb_ether_protocol@plt>
  add    $0x14,%rbx
  mov    D12(%rip),%rdx
  cmp    (%rdx),%rax
  mov    $0x0,%eax
  cmove  %rbx,%rax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  movzbl (%rbx),%eax
  shl    $0x2,%rax
  and    $0x3c,%eax
  add    %rbx,%rax
  jmp    L13
```

assistant: ```c
unsigned char *skb_transport_header(struct sk_buff *skb) {
  unsigned char *h = skb_network_header(skb);
  if (skb_ether_protocol(skb) == ETH_P_IP)
    return h + 4 * ((*h) & 0xF);
  if (skb_ether_protocol(skb) == ETH_P_IPV6)
    return h + 20;
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<skb_transport_header>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <skb_network_header@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <skb_ether_protocol@plt>
  mov    D3(%rip),%rdx
  cmp    (%rdx),%rax
  je     L2
  mov    %rbp,%rdi
  add    $0x14,%rbx
  call   <skb_ether_protocol@plt>
  mov    D11(%rip),%rdx
  cmp    (%rdx),%rax
  mov    $0x0,%eax
  cmove  %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L2:
  movzbl (%rbx),%eax
  add    $0x8,%rsp
  shl    $0x2,%rax
  and    $0x3c,%eax
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *skb_transport_header(struct sk_buff *skb) {
  unsigned char *h = skb_network_header(skb);
  if (skb_ether_protocol(skb) == ETH_P_IP)
    return h + 4 * ((*h) & 0xF);
  if (skb_ether_protocol(skb) == ETH_P_IPV6)
    return h + 20;
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skb_transport_header>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <skb_network_header@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <skb_ether_protocol@plt>
  mov    D14(%rip),%rdx
  cmp    (%rdx),%rax
  je     L3
  mov    %rbp,%rdi
  add    $0x14,%rbx
  call   <skb_ether_protocol@plt>
  mov    D5(%rip),%rdx
  cmp    (%rdx),%rax
  mov    $0x0,%eax
  cmove  %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L3:
  movzbl (%rbx),%eax
  add    $0x8,%rsp
  shl    $0x2,%rax
  and    $0x3c,%eax
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *skb_transport_header(struct sk_buff *skb) {
  unsigned char *h = skb_network_header(skb);
  if (skb_ether_protocol(skb) == ETH_P_IP)
    return h + 4 * ((*h) & 0xF);
  if (skb_ether_protocol(skb) == ETH_P_IPV6)
    return h + 20;
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrix_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L22:
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L5:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x8(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L5
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jb     L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrix_copy(int **dest, int **src, unsigned int cols, unsigned int rows) {
  unsigned int i, j;
  for (j = 0; j < rows; j++)
    for (i = 0; i < cols; i++)
      dest[j][i] = src[j][i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_copy>:
  endbr64
  mov    %edx,%r9d
  test   %ecx,%ecx
  je     L51
  mov    %rsi,%r8
  lea    -0x1(%rcx),%eax
  lea    0x8(%rsi,%rax,8),%r10
  lea    -0x1(%rdx),%eax
  lea    0x4(,%rax,4),%rsi
  jmp    L11
L15:
  mov    (%r8),%rdx
  mov    (%rdx,%rax,1),%ecx
  mov    (%rdi),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L15
L21:
  add    $0x8,%r8
  add    $0x8,%rdi
  cmp    %r10,%r8
  je     L51
L11:
  mov    $0x0,%eax
  test   %r9d,%r9d
  jne    L15
  jmp    L21
L51:
  ret
```

assistant: ```c
void matrix_copy(int **dest, int **src, unsigned int cols, unsigned int rows) {
  unsigned int i, j;
  for (j = 0; j < rows; j++)
    for (i = 0; i < cols; i++)
      dest[j][i] = src[j][i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<matrix_copy>:
  endbr64
  test   %ecx,%ecx
  je     L5
  push   %rbx
  mov    %ecx,%r11d
  mov    %rdi,%rbx
  xor    %r10d,%r10d
  mov    %edx,%r9d
  nopl   (%rax)
L27:
  test   %edx,%edx
  je     L12
  mov    (%rsi,%r10,8),%r8
  mov    (%rbx,%r10,8),%rdi
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    (%r8,%rax,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L9
L12:
  add    $0x1,%r10
  cmp    %r11,%r10
  jne    L27
  pop    %rbx
  ret
L5:
  ret
```

assistant: ```c
void matrix_copy(int **dest, int **src, unsigned int cols, unsigned int rows) {
  unsigned int i, j;
  for (j = 0; j < rows; j++)
    for (i = 0; i < cols; i++)
      dest[j][i] = src[j][i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_copy>:
  endbr64
  test   %ecx,%ecx
  je     L23
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  test   %edx,%edx
  je     L99
  mov    %edx,%eax
  mov    %ecx,%r11d
  mov    %edx,%r15d
  mov    %rsi,%r12
  shr    $0x2,%eax
  and    $0xfffffffc,%r15d
  xor    %esi,%esi
  mov    %edx,%r10d
  lea    -0x1(%rax),%ecx
  lea    -0x1(%rdx),%eax
  mov    %r15d,%ebx
  mov    %eax,-0x14(%rsp)
  lea    0x1(%r15),%r13d
  lea    0x2(%r15),%r14d
  add    $0x1,%rcx
  mov    %r13d,-0x10(%rsp)
  shl    $0x4,%rcx
  shl    $0x2,%rbx
  mov    %r14d,-0xc(%rsp)
  shl    $0x2,%r13
  shl    $0x2,%r14
  nopl   (%rax)
L58:
  mov    (%r12,%rsi,8),%rax
  mov    0x0(%rbp,%rsi,8),%rdx
  lea    0x4(%rax),%r9
  mov    %rdx,%r8
  sub    %r9,%r8
  cmp    $0x8,%r8
  jbe    L5
  xor    %r8d,%r8d
  cmpl   $0x2,-0x14(%rsp)
  jbe    L5
  nopl   0x0(%rax,%rax,1)
L73:
  movdqu (%rax,%r8,1),%xmm0
  movups %xmm0,(%rdx,%r8,1)
  add    $0x10,%r8
  cmp    %rcx,%r8
  jne    L73
  cmp    %r15d,%edi
  je     L69
  mov    (%rax,%rbx,1),%r8d
  mov    %r8d,(%rdx,%rbx,1)
  cmp    -0x10(%rsp),%edi
  jbe    L69
  mov    (%rax,%r13,1),%r8d
  mov    %r8d,(%rdx,%r13,1)
  cmp    -0xc(%rsp),%edi
  jbe    L69
  mov    (%rax,%r14,1),%eax
  mov    %eax,(%rdx,%r14,1)
L69:
  add    $0x1,%rsi
  cmp    %r11,%rsi
  jne    L58
L99:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L5:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rax,%r8,4),%r9d
  mov    %r9d,(%rdx,%r8,4)
  add    $0x1,%r8
  cmp    %r10,%r8
  jne    L0
  jmp    L69
L23:
  ret
```

assistant: ```c
void matrix_copy(int **dest, int **src, unsigned int cols, unsigned int rows) {
  unsigned int i, j;
  for (j = 0; j < rows; j++)
    for (i = 0; i < cols; i++)
      dest[j][i] = src[j][i];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<skip_non_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L23
L25:
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_non_whitespace(const char str[]) {
  while (!isspace(*str) && *str != '\0') {
    ++str;
  }
  return (char *)str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<skip_non_whitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L24
L13:
  add    $0x1,%rbx
L24:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L25
  cmpb   $0x0,(%rbx)
  jne    L13
L25:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skip_non_whitespace(const char str[]) {
  while (!isspace(*str) && *str != '\0') {
    ++str;
  }
  return (char *)str;
}
```
user: What is the c source code of the assembly code below?

```asm
<skip_non_whitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L26:
  cmpb   $0x0,(%r12)
  je     L5
  add    $0x1,%r12
L23:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L26
L5:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_non_whitespace(const char str[]) {
  while (!isspace(*str) && *str != '\0') {
    ++str;
  }
  return (char *)str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skip_non_whitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L24:
  cmpb   $0x0,(%r12)
  je     L22
  add    $0x1,%r12
L0:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L24
L22:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_non_whitespace(const char str[]) {
  while (!isspace(*str) && *str != '\0') {
    ++str;
  }
  return (char *)str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readMem16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <readMem8@plt>
  mov    %al,-0x2(%rbp)
  movzwl -0x14(%rbp),%eax
  add    $0x1,%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  call   <readMem8@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%edx
  movzbl -0x1(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  leave
  ret
```

assistant: ```c
unsigned short readMem16(unsigned short addr) {
  unsigned char lo = readMem8(addr + 0);
  unsigned char hi = readMem8(addr + 1);
  return lo | (hi << 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<readMem16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movzwl %di,%edi
  call   <readMem8@plt>
  mov    %eax,%ebp
  lea    0x1(%rbx),%edi
  movzwl %di,%edi
  call   <readMem8@plt>
  shl    $0x8,%eax
  movzbl %bpl,%ebp
  or     %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned short readMem16(unsigned short addr) {
  unsigned char lo = readMem8(addr + 0);
  unsigned char hi = readMem8(addr + 1);
  return lo | (hi << 8);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readMem16>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movzwl %di,%edi
  sub    $0x8,%rsp
  call   <readMem8@plt>
  lea    0x1(%rbx),%edi
  movzwl %di,%edi
  movzbl %al,%ebp
  call   <readMem8@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  pop    %rbx
  or     %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short readMem16(unsigned short addr) {
  unsigned char lo = readMem8(addr + 0);
  unsigned char hi = readMem8(addr + 1);
  return lo | (hi << 8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readMem16>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movzwl %di,%edi
  sub    $0x8,%rsp
  call   <readMem8@plt>
  lea    0x1(%rbx),%edi
  movzwl %di,%edi
  movzbl %al,%ebp
  call   <readMem8@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  pop    %rbx
  or     %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short readMem16(unsigned short addr) {
  unsigned char lo = readMem8(addr + 0);
  unsigned char hi = readMem8(addr + 1);
  return lo | (hi << 8);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<half_pyramid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf_s@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L13
L15:
  movl   $0x1,-0xc(%rbp)
  jmp    L35
L17:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L17
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L15
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
data_type: string
name: read_data
arguments: data_tag: D30
data_type: string
name: read_data
arguments: data_tag: D24
data_type: string
name: read_data
arguments: data_tag: D33
data_type: string

tool: D20: enter total number of roles: 

tool: D30: %d

tool: D24: *

tool: D33: 


assistant: ```c
void half_pyramid() {
  int n = 0;
  int row = 0;
  int star = 0;
  printf("enter total number of roles: ");
  scanf_s("%d", &n);
  for (row = 1; row <= n; row++) {
    for (star = 1; star <= row; star++) {
      printf("*");
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<half_pyramid>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf_s@plt>
  mov    $0x1,%ebp
  lea    D9(%rip),%r12
  lea    D34(%rip),%r13
  cmpl   $0x0,0x4(%rsp)
  jg     L38
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L43
L10:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jl     L18
L38:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L43
  jmp    L10
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string

tool: D18: enter total number of roles: 

tool: D14: %d

tool: D9: *

tool: D34: 


assistant: ```c
void half_pyramid() {
  int n = 0;
  int row = 0;
  int star = 0;
  printf("enter total number of roles: ");
  scanf_s("%d", &n);
  for (row = 1; row <= n; row++) {
    for (star = 1; star <= row; star++) {
      printf("*");
    }
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<half_pyramid>:
  endbr64
  push   %r13
  lea    D33(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L9
  mov    $0x1,%ebp
  lea    D16(%rip),%r12
  lea    D14(%rip),%r13
  xchg   %ax,%ax
L26:
  mov    $0x1,%ebx
  nopl   (%rax)
L29:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L29
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,0x4(%rsp)
  jge    L26
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D33
data_type: string
name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D16
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string

tool: D33: enter total number of roles: 

tool: D6: %d

tool: D16: *

tool: D14: 


assistant: ```c
void half_pyramid() {
  int n = 0;
  int row = 0;
  int star = 0;
  printf("enter total number of roles: ");
  scanf_s("%d", &n);
  for (row = 1; row <= n; row++) {
    for (star = 1; star <= row; star++) {
      printf("*");
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<half_pyramid>:
  endbr64
  push   %r13
  lea    D2(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L25
  mov    $0x1,%ebp
  lea    D6(%rip),%r12
  lea    D38(%rip),%r13
  xchg   %ax,%ax
L10:
  mov    $0x1,%ebx
  nopl   (%rax)
L16:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L16
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,0x4(%rsp)
  jge    L10
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D38
data_type: string

tool: D2: enter total number of roles: 

tool: D16: %d

tool: D6: *

tool: D38: 


assistant: ```c
void half_pyramid() {
  int n = 0;
  int row = 0;
  int star = 0;
  printf("enter total number of roles: ");
  scanf_s("%d", &n);
  for (row = 1; row <= n; row++) {
    for (star = 1; star <= row; star++) {
      printf("*");
    }
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<heap_extract_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L18
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L86
L49:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L85
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <is_gt@plt>
  test   %rax,%rax
  je     L85
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L86
L85:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L18
  cmpl   $0x0,-0xc(%rbp)
  je     L37
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <is_gt@plt>
  test   %rax,%rax
  je     L18
L37:
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L86:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L49
L18:
  mov    -0x10(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
long heap_extract_max(long *ary, int heap_len) {
  int ret;
  if (heap_len > 0) {
    ret = ary[0];
    int i = 0;
    while (i < heap_len) {
      int a = i * 2 + 1, b = i * 2 + 2;
      if (a < heap_len && is_gt(ary[a], ary[b])) {
        swap(ary, i, a);
        i = a;
      } else if (b < heap_len && (i == 0 || is_gt(ary[i], ary[b]))) {
        swap(ary, i, b);
        i = b;
      } else {
        break;
      }
    }
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heap_extract_max>:
  endbr64
  test   %esi,%esi
  jle    L67
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r14d
  mov    (%rdi),%r15d
  mov    $0x0,%ebp
  jmp    L45
L38:
  movslq %ebx,%rax
  mov    (%r12,%rax,8),%rsi
  movslq %r13d,%rax
  mov    (%r12,%rax,8),%rdi
  call   <is_gt@plt>
  test   %rax,%rax
  je     L10
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %r13d,%ebp
  jmp    L45
L5:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %ebx,%ebp
L45:
  lea    0x0(%rbp,%rbp,1),%ebx
  lea    0x1(%rbx),%r13d
  add    $0x2,%ebx
  cmp    %r13d,%r14d
  jg     L38
L10:
  cmp    %ebx,%r14d
  jle    L20
  test   %ebp,%ebp
  je     L5
  movslq %ebx,%rax
  mov    (%r12,%rax,8),%rsi
  movslq %ebp,%rax
  mov    (%r12,%rax,8),%rdi
  call   <is_gt@plt>
  test   %rax,%rax
  jne    L5
L20:
  movslq %r15d,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  movslq %r15d,%rax
  ret
```

assistant: ```c
long heap_extract_max(long *ary, int heap_len) {
  int ret;
  if (heap_len > 0) {
    ret = ary[0];
    int i = 0;
    while (i < heap_len) {
      int a = i * 2 + 1, b = i * 2 + 2;
      if (a < heap_len && is_gt(ary[a], ary[b])) {
        swap(ary, i, a);
        i = a;
      } else if (b < heap_len && (i == 0 || is_gt(ary[i], ary[b]))) {
        swap(ary, i, b);
        i = b;
      } else {
        break;
      }
    }
  }
  return ret;
}
```