ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<fmax3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x18(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L18
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
L18:
  movss  -0x1c(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L10
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
L10:
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float fmax3(float f1, float f2, float f3) {
  float max = f1;
  if (f2 > max)
    max = f2;
  if (f3 > max)
    max = f3;
  return max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fmax3>:
  endbr64
  maxss  %xmm0,%xmm1
  maxss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float fmax3(float f1, float f2, float f3) {
  float max = f1;
  if (f2 > max)
    max = f2;
  if (f3 > max)
    max = f3;
  return max;
}
```
user: What is the c source code of the assembly code below:

```asm
<fmax3>:
  endbr64
  maxss  %xmm0,%xmm1
  maxss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float fmax3(float f1, float f2, float f3) {
  float max = f1;
  if (f2 > max)
    max = f2;
  if (f3 > max)
    max = f3;
  return max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fmax3>:
  endbr64
  maxss  %xmm0,%xmm1
  maxss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float fmax3(float f1, float f2, float f3) {
  float max = f1;
  if (f2 > max)
    max = f2;
  if (f3 > max)
    max = f3;
  return max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%r8
  lea    -0x18(%rbp),%rdi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x10(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  add    $0x10,%rsp
  mov    -0x18(%rbp),%eax
  imul   $0xe10,%eax,%edx
  mov    -0x14(%rbp),%eax
  imul   $0x3c,%eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  imul   $0xe10,%eax,%ecx
  mov    -0x20(%rbp),%eax
  imul   $0x3c,%eax,%eax
  add    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L16
  addl   $0x15180,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string
name: disassemble_data
arguments: label: D0
type: string

tool: D9: %d:%d:%d %d:%d:%d

tool: D0: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int hour1, minute1, second1, hour2, minute2, second2;
  scanf("%d:%d:%d %d:%d:%d", &hour1, &minute1, &second1, &hour2, &minute2, &second2);
  int interval = (hour2 * 3600 + minute2 * 60 + second2) - (hour1 * 3600 + minute1 * 60 + second1);
  if (interval < 0) {
    interval += 24 * 3600;
  }
  printf("%d\n", interval);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  imul   $0xe10,0x1c(%rsp),%esi
  imul   $0x3c,0x20(%rsp),%eax
  add    %eax,%esi
  add    0x24(%rsp),%esi
  imul   $0xe10,0x10(%rsp),%eax
  imul   $0x3c,0x14(%rsp),%edx
  add    %edx,%eax
  add    0x18(%rsp),%eax
  sub    %eax,%esi
  add    $0x10,%rsp
  lea    0x15180(%rsi),%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D10: %d:%d:%d %d:%d:%d

tool: D1: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int hour1, minute1, second1, hour2, minute2, second2;
  scanf("%d:%d:%d %d:%d:%d", &hour1, &minute1, &second1, &hour2, &minute2, &second2);
  int interval = (hour2 * 3600 + minute2 * 60 + second2) - (hour1 * 3600 + minute1 * 60 + second1);
  if (interval < 0) {
    interval += 24 * 3600;
  }
  printf("%d\n", interval);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rcx
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <scanf@plt>
  imul   $0x3c,0x20(%rsp),%eax
  lea    D16(%rip),%rdi
  imul   $0xe10,0x1c(%rsp),%esi
  imul   $0x3c,0x14(%rsp),%edx
  add    %eax,%esi
  imul   $0xe10,0x10(%rsp),%eax
  add    0x24(%rsp),%esi
  add    %edx,%eax
  add    0x18(%rsp),%eax
  sub    %eax,%esi
  pop    %rax
  pop    %rdx
  test   %esi,%esi
  lea    0x15180(%rsi),%eax
  cmovs  %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
type: string
name: unpack_data
arguments: label: D16
type: string

tool: D11: %d:%d:%d %d:%d:%d

tool: D16: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int hour1, minute1, second1, hour2, minute2, second2;
  scanf("%d:%d:%d %d:%d:%d", &hour1, &minute1, &second1, &hour2, &minute2, &second2);
  int interval = (hour2 * 3600 + minute2 * 60 + second2) - (hour1 * 3600 + minute1 * 60 + second1);
  if (interval < 0) {
    interval += 24 * 3600;
  }
  printf("%d\n", interval);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rcx
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <scanf@plt>
  imul   $0x3c,0x20(%rsp),%eax
  lea    D15(%rip),%rdi
  imul   $0xe10,0x1c(%rsp),%esi
  imul   $0x3c,0x14(%rsp),%edx
  add    %eax,%esi
  imul   $0xe10,0x10(%rsp),%eax
  add    0x24(%rsp),%esi
  add    %edx,%eax
  add    0x18(%rsp),%eax
  sub    %eax,%esi
  pop    %rax
  pop    %rdx
  test   %esi,%esi
  lea    0x15180(%rsi),%eax
  cmovs  %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D15
data_type: string

tool: D16: %d:%d:%d %d:%d:%d

tool: D15: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int hour1, minute1, second1, hour2, minute2, second2;
  scanf("%d:%d:%d %d:%d:%d", &hour1, &minute1, &second1, &hour2, &minute2, &second2);
  int interval = (hour2 * 3600 + minute2 * 60 + second2) - (hour1 * 3600 + minute1 * 60 + second1);
  if (interval < 0) {
    interval += 24 * 3600;
  }
  printf("%d\n", interval);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Swap4Bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x3(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Swap4Bytes(char *bytes) {
  char t;
  t = bytes[0];
  bytes[0] = bytes[3];
  bytes[3] = t;
  t = bytes[1];
  bytes[1] = bytes[2];
  bytes[2] = t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Swap4Bytes>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  mov    %dl,0x1(%rdi)
  mov    %al,0x2(%rdi)
  ret
```

assistant: ```c
void Swap4Bytes(char *bytes) {
  char t;
  t = bytes[0];
  bytes[0] = bytes[3];
  bytes[3] = t;
  t = bytes[1];
  bytes[1] = bytes[2];
  bytes[2] = t;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Swap4Bytes>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  rolw   $0x8,0x1(%rdi)
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void Swap4Bytes(char *bytes) {
  char t;
  t = bytes[0];
  bytes[0] = bytes[3];
  bytes[3] = t;
  t = bytes[1];
  bytes[1] = bytes[2];
  bytes[2] = t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Swap4Bytes>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  rolw   $0x8,0x1(%rdi)
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void Swap4Bytes(char *bytes) {
  char t;
  t = bytes[0];
  bytes[0] = bytes[3];
  bytes[3] = t;
  t = bytes[1];
  bytes[1] = bytes[2];
  bytes[2] = t;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    %eax,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L18
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L19
L18:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int *p, *q, i = nondet_int();
  p = &i;
  argc = nondet_int();
  if (argc > 1) {
    q = &i;
  } else {
    q = p;
  }
  assert(*(p) + *(q) == 2 * i);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int *p, *q, i = nondet_int();
  p = &i;
  argc = nondet_int();
  if (argc > 1) {
    q = &i;
  } else {
    q = p;
  }
  assert(*(p) + *(q) == 2 * i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nondet_int@plt>
  xor    %eax,%eax
  call   <nondet_int@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int *p, *q, i = nondet_int();
  p = &i;
  argc = nondet_int();
  if (argc > 1) {
    q = &i;
  } else {
    q = p;
  }
  assert(*(p) + *(q) == 2 * i);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nondet_int@plt>
  xor    %eax,%eax
  call   <nondet_int@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int *p, *q, i = nondet_int();
  p = &i;
  argc = nondet_int();
  if (argc > 1) {
    q = &i;
  } else {
    q = p;
  }
  assert(*(p) + *(q) == 2 * i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<tindx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L21:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L14:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L14
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  mov    -0xc(%rbp),%eax
  jmp    L95
L39:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L67
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L67
  mov    $0xffffffff,%eax
  jmp    L95
L67:
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L21
  mov    $0xffffffff,%eax
L95:
  pop    %rbp
  ret
```

assistant: ```c
tindx(s, t, l) char s[], t[];
int l;
{
  int i, j, k;
  for (i = 0; i <= l; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (t[k] == '\0')
      return (i);
    if ((s[i] != '\t') && (s[i] != ' '))
      return (-1);
  }
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tindx>:
  endbr64
  test   %edx,%edx
  js     L33
  movzbl (%rsi),%r9d
  mov    $0x0,%r8d
  jmp    L2
L112:
  test   %cl,%cl
  je     L32
  movzbl (%rdi,%r8,1),%eax
  cmp    $0x9,%al
  je     L43
  cmp    $0x20,%al
  jne    L26
L43:
  add    $0x1,%r8
  sub    $0x1,%rsi
  cmp    %r8d,%edx
  jl     L42
L2:
  mov    %r8d,%r10d
  test   %r9b,%r9b
  je     L32
  mov    %r8,%rax
  mov    %r9d,%ecx
L54:
  cmp    %cl,(%rdi,%rax,1)
  jne    L112
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L54
L32:
  mov    %r10d,%eax
  ret
L33:
  mov    $0xffffffff,%r10d
  jmp    L32
L26:
  mov    $0xffffffff,%r10d
  jmp    L32
L42:
  mov    $0xffffffff,%r10d
  jmp    L32
```

assistant: ```c
tindx(s, t, l) char s[], t[];
int l;
{
  int i, j, k;
  for (i = 0; i <= l; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (t[k] == '\0')
      return (i);
    if ((s[i] != '\t') && (s[i] != ' '))
      return (-1);
  }
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tindx>:
  endbr64
  test   %edx,%edx
  js     L27
  movzbl (%rsi),%r9d
  xor    %r8d,%r8d
  nop
L45:
  mov    %r8d,%r10d
  test   %r9b,%r9b
  je     L1
  mov    %r8,%rax
  mov    %r9d,%ecx
  jmp    L38
L25:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L1
L38:
  cmp    %cl,(%rdi,%rax,1)
  je     L25
  movzbl (%rdi,%r8,1),%eax
  cmp    $0x9,%al
  je     L51
  cmp    $0x20,%al
  jne    L27
L51:
  add    $0x1,%r8
  sub    $0x1,%rsi
  cmp    %r8d,%edx
  jge    L45
L27:
  mov    $0xffffffff,%r10d
L1:
  mov    %r10d,%eax
  ret
```

assistant: ```c
tindx(s, t, l) char s[], t[];
int l;
{
  int i, j, k;
  for (i = 0; i <= l; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (t[k] == '\0')
      return (i);
    if ((s[i] != '\t') && (s[i] != ' '))
      return (-1);
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<tindx>:
  endbr64
  test   %edx,%edx
  js     L28
  movzbl (%rsi),%r9d
  xor    %r8d,%r8d
  nop
L41:
  mov    %r8d,%r10d
  test   %r9b,%r9b
  je     L6
  mov    %r8,%rax
  mov    %r9d,%ecx
  jmp    L25
L58:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L6
L25:
  cmp    %cl,(%rdi,%rax,1)
  je     L58
  movzbl (%rdi,%r8,1),%eax
  cmp    $0x9,%al
  je     L30
  cmp    $0x20,%al
  jne    L28
L30:
  add    $0x1,%r8
  sub    $0x1,%rsi
  cmp    %r8d,%edx
  jge    L41
L28:
  mov    $0xffffffff,%r10d
L6:
  mov    %r10d,%eax
  ret
```

assistant: ```c
tindx(s, t, l) char s[], t[];
int l;
{
  int i, j, k;
  for (i = 0; i <= l; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (t[k] == '\0')
      return (i);
    if ((s[i] != '\t') && (s[i] != ' '))
      return (-1);
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<html_tablecontents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <html_string@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <html_tablealign@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L7
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <html_int@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L7:
  cmpl   $0x0,-0x24(%rbp)
  je     L23
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <html_int@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L23:
  cmpl   $0x0,-0x28(%rbp)
  je     L5
  lea    D40(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <html_string@plt>
  add    %eax,-0x4(%rbp)
L5:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <html_string@plt>
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <html_string@plt>
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D47
type: string
name: unpack_data
arguments: data_tag: D20
type: string
name: unpack_data
arguments: data_tag: D40
type: string
name: unpack_data
arguments: data_tag: D2
type: string
name: unpack_data
arguments: data_tag: D52
type: string
name: unpack_data
arguments: data_tag: D25
type: string

tool: D15: <%s

tool: D47:  COLSPAN="%d"

tool: D20:  ROWSPAN="%d"

tool: D40: NOWRAP

tool: D2:  %s

tool: D52: >%s

tool: D25: </%s>


assistant: ```c
int html_tablecontents(char *content, int align, int colspan, int rowspan, int nowrap, char *text) {
  int l = html_string("<%s", content);
  l += html_tablealign(align);
  if (colspan)
    l += html_int(" COLSPAN=\"%d\"", colspan);
  if (rowspan)
    l += html_int(" ROWSPAN=\"%d\"", rowspan);
  if (nowrap)
    l += html_string(" %s", "NOWRAP");
  l += html_string(">%s", text);
  l += html_string("</%s>\n", content);
  return l;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<html_tablecontents>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r15d
  mov    %edx,%r12d
  mov    %ecx,%ebp
  mov    %r8d,%r14d
  mov    %r9,%r13
  mov    %rdi,%rsi
  lea    D43(%rip),%rdi
  call   <html_string@plt>
  mov    %eax,0xc(%rsp)
  mov    %r15d,%edi
  call   <html_tablealign@plt>
  mov    0xc(%rsp),%r15d
  add    %eax,%r15d
  test   %r12d,%r12d
  jne    L23
L37:
  test   %ebp,%ebp
  jne    L50
L0:
  test   %r14d,%r14d
  jne    L22
L6:
  mov    %r13,%rsi
  lea    D57(%rip),%rdi
  call   <html_string@plt>
  lea    (%r15,%rax,1),%r12d
  mov    %rbx,%rsi
  lea    D66(%rip),%rdi
  call   <html_string@plt>
  add    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    %r12d,%esi
  lea    D29(%rip),%rdi
  call   <html_int@plt>
  add    %eax,%r15d
  jmp    L37
L50:
  mov    %ebp,%esi
  lea    D62(%rip),%rdi
  call   <html_int@plt>
  add    %eax,%r15d
  jmp    L0
L22:
  lea    D26(%rip),%rsi
  lea    D65(%rip),%rdi
  call   <html_string@plt>
  add    %eax,%r15d
  jmp    L6
```

tool_calls: name: unpack_data
arguments: data_tag: D43
datatype: string
name: unpack_data
arguments: data_tag: D57
datatype: string
name: unpack_data
arguments: data_tag: D66
datatype: string
name: unpack_data
arguments: data_tag: D29
datatype: string
name: unpack_data
arguments: data_tag: D62
datatype: string
name: unpack_data
arguments: data_tag: D26
datatype: string
name: unpack_data
arguments: data_tag: D65
datatype: string

tool: D43: <%s

tool: D57: >%s

tool: D66: </%s>


tool: D29:  COLSPAN="%d"

tool: D62:  ROWSPAN="%d"

tool: D26: NOWRAP

tool: D65:  %s

assistant: ```c
int html_tablecontents(char *content, int align, int colspan, int rowspan, int nowrap, char *text) {
  int l = html_string("<%s", content);
  l += html_tablealign(align);
  if (colspan)
    l += html_int(" COLSPAN=\"%d\"", colspan);
  if (rowspan)
    l += html_int(" ROWSPAN=\"%d\"", rowspan);
  if (nowrap)
    l += html_string(" %s", "NOWRAP");
  l += html_string(">%s", text);
  l += html_string("</%s>\n", content);
  return l;
}
```