ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<err_hash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <ERR_GET_LIB@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <ERR_GET_FUNC@plt>
  xor    %rax,%rbx
  mov    %rbx,%rcx
  xor    %rbp,%rcx
  movabs $0xd79435e50d79435f,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rdx,%rax,2),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  lea    (%rax,%rax,2),%rdx
  lea    (%rax,%rdx,4),%rax
  xor    %rcx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long err_hash(ERR_STRING_DATA *a) {
  unsigned long ret, l;
  l = a->error;
  ret = l ^ ERR_GET_LIB(l) ^ ERR_GET_FUNC(l);
  return (ret ^ ret % 19 * 13);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<err_hash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <ERR_GET_LIB@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <ERR_GET_FUNC@plt>
  add    $0x8,%rsp
  movabs $0xd79435e50d79435f,%rdx
  xor    %rax,%rbx
  mov    %rbx,%rcx
  pop    %rbx
  xor    %rbp,%rcx
  pop    %rbp
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rdx,%rax,2),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  lea    (%rax,%rax,2),%rdx
  lea    (%rax,%rdx,4),%rax
  xor    %rcx,%rax
  ret
```

assistant: ```c
unsigned long err_hash(ERR_STRING_DATA *a) {
  unsigned long ret, l;
  l = a->error;
  ret = l ^ ERR_GET_LIB(l) ^ ERR_GET_FUNC(l);
  return (ret ^ ret % 19 * 13);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<err_hash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <ERR_GET_LIB@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <ERR_GET_FUNC@plt>
  add    $0x8,%rsp
  movabs $0xd79435e50d79435f,%rdx
  xor    %rax,%rbx
  mov    %rbx,%rcx
  pop    %rbx
  xor    %rbp,%rcx
  pop    %rbp
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rdx,%rax,2),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  lea    (%rax,%rax,2),%rdx
  lea    (%rax,%rdx,4),%rax
  xor    %rcx,%rax
  ret
```

assistant: ```c
unsigned long err_hash(ERR_STRING_DATA *a) {
  unsigned long ret, l;
  l = a->error;
  ret = l ^ ERR_GET_LIB(l) ^ ERR_GET_FUNC(l);
  return (ret ^ ret % 19 * 13);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cleanCell>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L15
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x38(%rbp),%eax
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x31,%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x38(%rbp),%eax
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x31,%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x38(%rbp),%eax
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x31,%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x2e,(%rax)
  jmp    L17
L15:
  movl   $0x0,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cleanCell(char **board, int row[9][9], int col[9][9], int block[9][9], int i, int j) {
  int n;
  if (board[i][j] != '.') {
    n = board[i][j] - '0';
    row[i][board[i][j] - '1'] = 0;
    col[j][board[i][j] - '1'] = 0;
    block[i / 3 * 3 + j / 3][board[i][j] - '1'] = 0;
    board[i][j] = '.';
  } else {
    n = 0;
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cleanCell>:
  endbr64
  push   %rbx
  mov    %rsi,%r11
  mov    %rdx,%r10
  movslq %r8d,%rbx
  lea    (%rdi,%rbx,8),%rsi
  movslq %r9d,%rdx
  mov    (%rsi),%rax
  movzbl (%rax,%rdx,1),%eax
  mov    $0x0,%edi
  cmp    $0x2e,%al
  je     L3
  movsbl %al,%eax
  lea    -0x30(%rax),%edi
  lea    (%rbx,%rbx,8),%rbx
  lea    (%r11,%rbx,4),%r11
  sub    $0x31,%eax
  cltq
  movl   $0x0,(%r11,%rax,4)
  lea    (%rdx,%rdx,8),%rax
  lea    (%r10,%rax,4),%r10
  mov    (%rsi),%rax
  movsbl (%rax,%rdx,1),%eax
  sub    $0x31,%eax
  cltq
  movl   $0x0,(%r10,%rax,4)
  movslq %r8d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%r8d
  imul   $0x55555556,%rdx,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  add    %r8d,%eax
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%rcx,%rax,4),%rcx
  mov    (%rsi),%rax
  movsbl (%rax,%rdx,1),%eax
  sub    $0x31,%eax
  cltq
  movl   $0x0,(%rcx,%rax,4)
  mov    (%rsi),%rax
  movb   $0x2e,(%rax,%rdx,1)
L3:
  mov    %edi,%eax
  pop    %rbx
  ret
```

assistant: ```c
int cleanCell(char **board, int row[9][9], int col[9][9], int block[9][9], int i, int j) {
  int n;
  if (board[i][j] != '.') {
    n = board[i][j] - '0';
    row[i][board[i][j] - '1'] = 0;
    col[j][board[i][j] - '1'] = 0;
    block[i / 3 * 3 + j / 3][board[i][j] - '1'] = 0;
    board[i][j] = '.';
  } else {
    n = 0;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cleanCell>:
  endbr64
  movslq %r8d,%rax
  push   %rbp
  mov    %rdx,%r11
  movslq %r9d,%rdx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  mov    (%rdi,%rax,8),%rcx
  xor    %r10d,%r10d
  add    %rdx,%rcx
  mov    %rcx,%rdi
  movsbl (%rcx),%ecx
  cmp    $0x2e,%cl
  je     L8
  lea    (%rax,%rax,8),%rbp
  lea    -0x30(%rcx),%r10d
  sub    $0x31,%ecx
  sar    $0x1f,%r8d
  movslq %ecx,%rcx
  imul   $0x55555556,%rax,%rax
  lea    (%rbx,%rbp,4),%rbx
  sar    $0x1f,%r9d
  movl   $0x0,(%rbx,%rcx,4)
  lea    (%rdx,%rdx,8),%rcx
  imul   $0x55555556,%rdx,%rdx
  lea    (%r11,%rcx,4),%r11
  movsbl (%rdi),%ecx
  shr    $0x20,%rax
  sub    %r8d,%eax
  sub    $0x31,%ecx
  shr    $0x20,%rdx
  lea    (%rax,%rax,2),%eax
  movslq %ecx,%rcx
  sub    %r9d,%edx
  movl   $0x0,(%r11,%rcx,4)
  add    %edx,%eax
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%rsi,%rax,4),%rdx
  movsbl (%rdi),%eax
  sub    $0x31,%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  movb   $0x2e,(%rdi)
L8:
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cleanCell(char **board, int row[9][9], int col[9][9], int block[9][9], int i, int j) {
  int n;
  if (board[i][j] != '.') {
    n = board[i][j] - '0';
    row[i][board[i][j] - '1'] = 0;
    col[j][board[i][j] - '1'] = 0;
    block[i / 3 * 3 + j / 3][board[i][j] - '1'] = 0;
    board[i][j] = '.';
  } else {
    n = 0;
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cleanCell>:
  endbr64
  movslq %r8d,%rax
  push   %rbp
  mov    %rdx,%r11
  movslq %r9d,%rdx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  mov    (%rdi,%rax,8),%rcx
  xor    %r10d,%r10d
  add    %rdx,%rcx
  mov    %rcx,%rdi
  movsbl (%rcx),%ecx
  cmp    $0x2e,%cl
  je     L1
  lea    (%rax,%rax,8),%rbp
  lea    -0x30(%rcx),%r10d
  sub    $0x31,%ecx
  sar    $0x1f,%r8d
  movslq %ecx,%rcx
  imul   $0x55555556,%rax,%rax
  lea    (%rbx,%rbp,4),%rbx
  sar    $0x1f,%r9d
  movl   $0x0,(%rbx,%rcx,4)
  lea    (%rdx,%rdx,8),%rcx
  imul   $0x55555556,%rdx,%rdx
  lea    (%r11,%rcx,4),%r11
  movsbl (%rdi),%ecx
  shr    $0x20,%rax
  sub    %r8d,%eax
  sub    $0x31,%ecx
  shr    $0x20,%rdx
  lea    (%rax,%rax,2),%eax
  movslq %ecx,%rcx
  sub    %r9d,%edx
  movl   $0x0,(%r11,%rcx,4)
  add    %edx,%eax
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%rsi,%rax,4),%rdx
  movsbl (%rdi),%eax
  sub    $0x31,%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  movb   $0x2e,(%rdi)
L1:
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cleanCell(char **board, int row[9][9], int col[9][9], int block[9][9], int i, int j) {
  int n;
  if (board[i][j] != '.') {
    n = board[i][j] - '0';
    row[i][board[i][j] - '1'] = 0;
    col[j][board[i][j] - '1'] = 0;
    block[i / 3 * 3 + j / 3][board[i][j] - '1'] = 0;
    board[i][j] = '.';
  } else {
    n = 0;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_device>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <find_device_by_ifaddrs@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L20
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <find_device_by_sysfs@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <find_device_by_ioctl@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L28
L20:
  nop
  jmp    L28
L18:
  nop
L28:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int find_device(struct device *dev) {
  int rc;
  rc = find_device_by_ifaddrs(dev);
  if (rc >= 0)
    goto out;
  rc = find_device_by_sysfs(dev);
  if (rc >= 0)
    goto out;
  rc = find_device_by_ioctl(dev);
out:
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_device>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <find_device_by_ifaddrs@plt>
  test   %eax,%eax
  js     L5
L0:
  pop    %rbx
  ret
L5:
  mov    %rbx,%rdi
  call   <find_device_by_sysfs@plt>
  test   %eax,%eax
  jns    L0
  mov    %rbx,%rdi
  call   <find_device_by_ioctl@plt>
  jmp    L0
```

assistant: ```c
int find_device(struct device *dev) {
  int rc;
  rc = find_device_by_ifaddrs(dev);
  if (rc >= 0)
    goto out;
  rc = find_device_by_sysfs(dev);
  if (rc >= 0)
    goto out;
  rc = find_device_by_ioctl(dev);
out:
  return rc;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<find_device>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <find_device_by_ifaddrs@plt>
  test   %eax,%eax
  js     L6
L16:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  call   <find_device_by_sysfs@plt>
  test   %eax,%eax
  jns    L16
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <find_device_by_ioctl@plt>
```

assistant: ```c
int find_device(struct device *dev) {
  int rc;
  rc = find_device_by_ifaddrs(dev);
  if (rc >= 0)
    goto out;
  rc = find_device_by_sysfs(dev);
  if (rc >= 0)
    goto out;
  rc = find_device_by_ioctl(dev);
out:
  return rc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find_device>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <find_device_by_ifaddrs@plt>
  test   %eax,%eax
  js     L8
L5:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  call   <find_device_by_sysfs@plt>
  test   %eax,%eax
  jns    L5
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <find_device_by_ioctl@plt>
```

assistant: ```c
int find_device(struct device *dev) {
  int rc;
  rc = find_device_by_ifaddrs(dev);
  if (rc >= 0)
    goto out;
  rc = find_device_by_sysfs(dev);
  if (rc >= 0)
    goto out;
  rc = find_device_by_ioctl(dev);
out:
  return rc;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x3,-0x24(%rbp)
  je     L63
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  jmp    L82
L63:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jg     L21
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  jmp    L82
L21:
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L50
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L79
L50:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  jmp    L82
L79:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L78
L85:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L78:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L85
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <combine@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
L82:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 3) {
    return EXIT_FAILURE;
  }
  int num = (int)strtol(argv[1], NULL, 10);
  if (num <= 0) {
    return EXIT_FAILURE;
  }
  int sel = (int)strtol(argv[2], NULL, 10);
  if ((sel <= 0) || (sel > num)) {
    return EXIT_FAILURE;
  }
  int *arr;
  arr = malloc(sizeof(int) * num);
  int ind;
  for (ind = 0; ind < num; ind++) {
    arr[ind] = 0;
  }
  combine(arr, num, sel);
  free(arr);
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  cmp    $0x3,%edi
  je     L55
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  ret
L55:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%rbp
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L1
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L43
  cmp    %eax,%ebp
  jl     L43
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  lea    -0x1(%rbp),%edx
  lea    0x4(%rax,%rdx,4),%rdx
L38:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L38
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <combine@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  jmp    L13
L1:
  mov    D30(%rip),%rax
  mov    (%rax),%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  jmp    L13
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 3) {
    return EXIT_FAILURE;
  }
  int num = (int)strtol(argv[1], NULL, 10);
  if (num <= 0) {
    return EXIT_FAILURE;
  }
  int sel = (int)strtol(argv[2], NULL, 10);
  if ((sel <= 0) || (sel > num)) {
    return EXIT_FAILURE;
  }
  int *arr;
  arr = malloc(sizeof(int) * num);
  int ind;
  for (ind = 0; ind < num; ind++) {
    arr[ind] = 0;
  }
  combine(arr, num, sel);
  free(arr);
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  cmp    $0x3,%edi
  je     L20
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  ret
L20:
  push   %r14
  mov    $0xa,%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %rax,%rbp
  test   %eax,%eax
  jle    L41
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L41
  cmp    %eax,%ebp
  jl     L41
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rax,%r12
  lea    -0x1(%rbp),%eax
  lea    0x4(,%rax,4),%rdx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <combine@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  jmp    L12
L41:
  mov    D25(%rip),%rax
  mov    (%rax),%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 3) {
    return EXIT_FAILURE;
  }
  int num = (int)strtol(argv[1], NULL, 10);
  if (num <= 0) {
    return EXIT_FAILURE;
  }
  int sel = (int)strtol(argv[2], NULL, 10);
  if ((sel <= 0) || (sel > num)) {
    return EXIT_FAILURE;
  }
  int *arr;
  arr = malloc(sizeof(int) * num);
  int ind;
  for (ind = 0; ind < num; ind++) {
    arr[ind] = 0;
  }
  combine(arr, num, sel);
  free(arr);
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  cmp    $0x3,%edi
  je     L28
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  ret
L28:
  push   %r14
  mov    $0xa,%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %rax,%rbp
  test   %eax,%eax
  jle    L1
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L1
  cmp    %eax,%ebp
  jl     L1
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rax,%r12
  lea    -0x1(%rbp),%eax
  lea    0x4(,%rax,4),%rdx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <combine@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  jmp    L16
L1:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 3) {
    return EXIT_FAILURE;
  }
  int num = (int)strtol(argv[1], NULL, 10);
  if (num <= 0) {
    return EXIT_FAILURE;
  }
  int sel = (int)strtol(argv[2], NULL, 10);
  if ((sel <= 0) || (sel > num)) {
    return EXIT_FAILURE;
  }
  int *arr;
  arr = malloc(sizeof(int) * num);
  int ind;
  for (ind = 0; ind < num; ind++) {
    arr[ind] = 0;
  }
  combine(arr, num, sel);
  free(arr);
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<brackrange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3c,%eax
  je     L39
  cmp    $0x5e,%eax
  jne    L94
  mov    -0x28(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0xe(%rbp)
  lea    -0xe(%rbp),%rax
  add    $0x1,%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rax
  movl   $0x2,(%rax)
  movl   $0x1,-0x20(%rbp)
  jmp    L91
L39:
  lea    -0xe(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x1,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L91
L94:
  mov    $0x0,%eax
  jmp    L85
L91:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    %rax,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L93
L29:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  lea    -0xe(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcspn@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  jne    L97
  addl   $0x1,-0x1c(%rbp)
  jmp    L12
L97:
  subl   $0x1,-0x1c(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
L93:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L29
  mov    -0x38(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  cmpq   $0x0,-0x40(%rbp)
  je     L65
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
L65:
  mov    $0x1,%eax
L85:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L74
  call   <__stack_chk_fail@plt>
L74:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string

tool: D15: 


tool: D4: <>


assistant: ```c
int brackrange(char *cp, int *start, int *length, char **endp) {
  char endstr[6];
  int endlen;
  int nest;
  int len;
  switch (*cp) {
  case '^':
    endstr[0] = cp[1];
    strcpy(endstr + 1, "\n");
    *start = 2;
    endlen = 1;
    break;
  case '<':
    strcpy(endstr, "<>\n");
    endlen = 1;
    *start = 1;
    break;
  default:
    return 0;
  }
  cp += *start;
  len = 0;
  nest = 1;
  while (nest) {
    int sublen;
    sublen = strcspn(cp + len, endstr);
    if (cp[len + sublen] == '<')
      nest++;
    else
      nest--;
    len += sublen;
  }
  *length = len;
  if (endp)
    *endp = cp + len + endlen;
  return 1;
}
```