user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  mov    $0xa,%esi
  mov    $0x5,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D65(%rip),%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x500000003,%rax
  movaps %xmm0,0x20(%rsp)
  lea    0x14(%rsp),%r14
  lea    0x20(%rsp),%r15
  movaps %xmm0,0x30(%rsp)
  mov    %r15,%rbx
  lea    0x44(%rsp),%r13
  mov    %r15,%r12
  movl   $0x14,0x1c(%rsp)
  movl   $0x0,0x40(%rsp)
  mov    %rax,0x14(%rsp)
  mov    D84(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <suma@plt>
  mov    $0xa,%ecx
  mov    $0x5,%edx
  lea    D87(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    $0x3,%edi
  call   <promedio@plt>
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x2,%esi
  lea    D51(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  lea    0x8(%rsp),%rdi
  call   <potencia@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D78(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
L4:
  mov    (%r12),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0xc,%r12
  call   <printf@plt>
  mov    -0x8(%r12),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x4(%r12),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12,%r13
  jne    L4
  mov    $0x3,%edi
  mov    %r15,%rdx
  mov    $0x3,%esi
  call   <inicializa@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0xc,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L8
  mov    $0x3,%edi
  mov    %r14,%rsi
  call   <mostrarVectorPuntero@plt>
  lea    D80(%rip),%rdi
  call   <system@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D65
type_guessed: string
name: read_data
arguments: label: D84
type_guessed: f64
name: read_data
arguments: label: D87
type_guessed: string
name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D51
type_guessed: string
name: read_data
arguments: label: D78
type_guessed: string
name: read_data
arguments: label: D33
type_guessed: string
name: read_data
arguments: label: D34
type_guessed: string
name: read_data
arguments: label: D80
type_guessed: string

tool: D65: %d 

tool: D84: 2

tool: D87: %d es el resultado de la suma de %d y %d


tool: D16: el promedio es: %6.2f


tool: D51: El resultado de %4.0f elevado a la %d es: 

tool: D78: %4.0f


tool: D33: antes

tool: D34: 
despues

tool: D80: pause

assistant: ```c
int main() {
  int valores[3] = {3, 5, 20};
  int a = 5, b = 10, exp = 2;
  int resultado = 0;
  double bas = 2.0;
  int matriz[3][3] = {0};
  int i, j;
  resultado = suma(a, b);
  printf("%d es el resultado de la suma de %d y %d\n", resultado, a, b);
  printf("el promedio es: %6.2f\n", promedio(3, valores));
  printf("El resultado de %4.0f elevado a la %d es: ", bas, exp);
  potencia(&bas, exp);
  printf("%4.0f\n", bas);
  printf("antes\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++)
      printf("%d ", matriz[i][j]);
    printf("\n");
  }
  inicializa(3, 3, matriz);
  printf("\ndespues\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++)
      printf("%d ", matriz[i][j]);
    printf("\n");
  }
  mostrarVectorPuntero(3, &valores);
  system("pause");
  return 0;
}
```