ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<shielddwarf>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdx
  lea    D2(%rip),%rsi
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <nicename@plt>
  test   %r12d,%r12d
  je     L3
  xor    %ebx,%ebx
  lea    D9(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x8,%edi
  add    $0x1,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  mov    %eax,%ebp
  call   <d@plt>
  mov    %r13,%rdi
  mov    %ebx,%esi
  lea    0x4(%rbp,%rax,1),%edx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L2
L3:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D2
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: 

tool: D2: shield dwarf (dwarf)

tool: D9: %d: %d hp

assistant: ```c
void shielddwarf(unsigned count) {
  int i;
  nicename(count, "shield dwarf (dwarf)", "");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp", i + 1, d(8) + d(8) + 4);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: What is the c source code of the assembly code below:

```asm
<WriteInt32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x0,%eax
  call   <CheckEnd@plt>
  test   %rax,%rax
  je     L6
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x1c(%rbp),%eax
  add    $0x4,%eax
  jmp    L9
L6:
  movq   $0x0,-0x8(%rbp)
  jmp    L7
L23:
  mov    -0x8(%rbp),%rax
  shl    $0x3,%eax
  mov    -0x20(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%ecx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x8(%rbp)
L7:
  cmpq   $0x3,-0x8(%rbp)
  jbe    L23
  mov    -0x1c(%rbp),%eax
  add    $0x4,%eax
L9:
  leave
  ret
```

assistant: ```c
int WriteInt32(uint8_t *ptr, int ofs, int32_t val) {
  if (CheckEnd()) {
    ptr[ofs] = val & 0xff;
    ptr[ofs + 1] = val << 8 & 0xff;
    ptr[ofs + 2] = val << 16 & 0xff;
    ptr[ofs + 3] = val << 24 & 0xff;
    return ofs + 4;
  } else {
    for (size_t i = 0; i < 4; i++) {
      ptr[ofs + i] = (val >> (8 * i)) & 0xff;
    }
    return (ofs + 4);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<WriteInt32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0x0,%eax
  call   <CheckEnd@plt>
  test   %rax,%rax
  je     L4
  movslq %ebx,%rdx
  lea    0x0(,%rdx,4),%rax
  and    $0xff,%r12d
  mov    %r12d,0x0(%rbp,%rdx,4)
  movl   $0x0,0x4(%rbp,%rax,1)
  movl   $0x0,0x8(%rbp,%rax,1)
  movl   $0x0,0xc(%rbp,%rax,1)
  lea    0x4(%rbx),%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  mov    $0x0,%eax
L17:
  lea    0x0(,%rax,8),%ecx
  mov    %r12d,%edx
  sar    %cl,%edx
  and    $0xff,%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L17
  lea    0x4(%rbx),%eax
  jmp    L3
```

assistant: ```c
int WriteInt32(uint8_t *ptr, int ofs, int32_t val) {
  if (CheckEnd()) {
    ptr[ofs] = val & 0xff;
    ptr[ofs + 1] = val << 8 & 0xff;
    ptr[ofs + 2] = val << 16 & 0xff;
    ptr[ofs + 3] = val << 24 & 0xff;
    return ofs + 4;
  } else {
    for (size_t i = 0; i < 4; i++) {
      ptr[ofs + i] = (val >> (8 * i)) & 0xff;
    }
    return (ofs + 4);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WriteInt32>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <CheckEnd@plt>
  movslq %ebx,%rdx
  mov    %rax,%r8
  lea    0x4(%rbx),%eax
  test   %r8,%r8
  je     L12
  lea    0x0(,%rdx,4),%rcx
  and    $0xff,%ebp
  mov    %ebp,(%r12,%rdx,4)
  movl   $0x0,0x4(%r12,%rcx,1)
  movl   $0x0,0x8(%r12,%rcx,1)
  movl   $0x0,0xc(%r12,%rcx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  lea    (%r12,%rdx,4),%rdx
  xor    %edi,%edi
L8:
  lea    0x0(,%rdi,8),%ecx
  mov    %ebp,%esi
  sar    %cl,%esi
  mov    %esi,%ecx
  and    $0xff,%ecx
  mov    %ecx,(%rdx,%rdi,4)
  add    $0x1,%rdi
  cmp    $0x4,%rdi
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int WriteInt32(uint8_t *ptr, int ofs, int32_t val) {
  if (CheckEnd()) {
    ptr[ofs] = val & 0xff;
    ptr[ofs + 1] = val << 8 & 0xff;
    ptr[ofs + 2] = val << 16 & 0xff;
    ptr[ofs + 3] = val << 24 & 0xff;
    return ofs + 4;
  } else {
    for (size_t i = 0; i < 4; i++) {
      ptr[ofs + i] = (val >> (8 * i)) & 0xff;
    }
    return (ofs + 4);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<WriteInt32>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <CheckEnd@plt>
  movslq %ebp,%rdx
  mov    %rax,%r8
  lea    0x4(%rbp),%eax
  test   %r8,%r8
  je     L5
  lea    0x0(,%rdx,4),%rcx
  and    $0xff,%ebx
  mov    %ebx,(%r12,%rdx,4)
  movl   $0x0,0x4(%r12,%rcx,1)
  movl   $0x0,0x8(%r12,%rcx,1)
  movl   $0x0,0xc(%r12,%rcx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %ebx,%ecx
  mov    %ebx,%edi
  movd   %ebx,%xmm0
  mov    %ebx,%esi
  sar    $0x8,%ecx
  sar    $0x10,%edi
  pop    %rbx
  pop    %rbp
  sar    $0x18,%esi
  movd   %edi,%xmm1
  movd   %ecx,%xmm3
  movd   %esi,%xmm2
  punpckldq %xmm3,%xmm0
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  pand   D4(%rip),%xmm0
  movups %xmm0,(%r12,%rdx,4)
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: byte[16]

tool: {"D4": [0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00]}

assistant: ```c
int WriteInt32(uint8_t *ptr, int ofs, int32_t val) {
  if (CheckEnd()) {
    ptr[ofs] = val & 0xff;
    ptr[ofs + 1] = val << 8 & 0xff;
    ptr[ofs + 2] = val << 16 & 0xff;
    ptr[ofs + 3] = val << 24 & 0xff;
    return ofs + 4;
  } else {
    for (size_t i = 0; i < 4; i++) {
      ptr[ofs + i] = (val >> (8 * i)) & 0xff;
    }
    return (ofs + 4);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L90
L91:
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <getop@plt>
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  cmp    $0x6e,%eax
  je     L13
  cmp    $0x6e,%eax
  jg     L131
  cmp    $0x2f,%eax
  je     L16
  cmp    $0x2f,%eax
  jg     L131
  cmp    $0x2d,%eax
  je     L14
  cmp    $0x2d,%eax
  jg     L131
  cmp    $0x2a,%eax
  je     L32
  cmp    $0x2b,%eax
  je     L39
  jmp    L131
L13:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L90
L39:
  mov    $0x0,%eax
  call   <pop@plt>
  movsd  %xmm0,-0x28(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movapd %xmm0,%xmm1
  addsd  -0x28(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L90
L14:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  subsd  -0x8(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L90
L32:
  mov    $0x0,%eax
  call   <pop@plt>
  movsd  %xmm0,-0x28(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movapd %xmm0,%xmm3
  mulsd  -0x28(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L90
L16:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm4
  divsd  -0x8(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L90
L131:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
L90:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L91
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D13
type_guessed: string

tool: D9: Error: unknown operator

tool: D13: final result is: %g


assistant: ```c
int main(int argc, char *argv[]) {
  double op2;
  char ch;
  while (--argc > 0) {
    ch = getop(*++argv);
    switch (ch) {
    case 'n':
      push(atof(*argv));
      break;
    case '+':
      push(pop() + pop());
      break;
    case '-':
      op2 = pop();
      push(pop() - op2);
      break;
    case '*':
      push(pop() * pop());
      break;
    case '/':
      op2 = pop();
      push(pop() / op2);
      break;
    default:
      printf("Error: unknown operator\n");
      break;
    }
  }
  printf("final result is: %g\n", pop());
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L49
  mov    %rsi,%rbx
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
  lea    D11(%rip),%r12
  jmp    L10
L51:
  cmp    $0x2a,%al
  je     L101
  cmp    $0x2b,%al
  jne    L121
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%r14
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %r14,%xmm1
  addsd  %xmm1,%xmm0
  call   <push@plt>
L57:
  cmp    %rbp,%rbx
  je     L49
L10:
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  call   <getop@plt>
  cmp    $0x2d,%al
  je     L31
  jle    L51
  cmp    $0x2f,%al
  je     L58
  cmp    $0x6e,%al
  jne    L121
  mov    (%rbx),%rdi
  call   <atof@plt>
  call   <push@plt>
  jmp    L57
L31:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%r14
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %r14,%xmm2
  subsd  %xmm2,%xmm0
  call   <push@plt>
  jmp    L57
L101:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%r14
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %r14,%xmm3
  mulsd  %xmm3,%xmm0
  call   <push@plt>
  jmp    L57
L58:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%r14
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %r14,%xmm4
  divsd  %xmm4,%xmm0
  call   <push@plt>
  jmp    L57
L121:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L57
L49:
  mov    $0x0,%eax
  call   <pop@plt>
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string

tool: D11: Error: unknown operator

tool: D6: final result is: %g


assistant: ```c
int main(int argc, char *argv[]) {
  double op2;
  char ch;
  while (--argc > 0) {
    ch = getop(*++argv);
    switch (ch) {
    case 'n':
      push(atof(*argv));
      break;
    case '+':
      push(pop() + pop());
      break;
    case '-':
      op2 = pop();
      push(pop() - op2);
      break;
    case '*':
      push(pop() * pop());
      break;
    case '/':
      op2 = pop();
      push(pop() / op2);
      break;
    default:
      printf("Error: unknown operator\n");
      break;
    }
  }
  printf("final result is: %g\n", pop());
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x1,%edi
  jle    L20
  lea    -0x2(%rdi),%eax
  mov    %rsi,%rbx
  lea    D6(%rip),%r12
  lea    0x8(%rsi,%rax,8),%rbp
  jmp    L125
  nopl   (%rax)
L97:
  cmp    $0x2a,%al
  je     L55
  cmp    $0x2b,%al
  jne    L50
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  addsd  0x8(%rsp),%xmm0
  call   <push@plt>
L49:
  cmp    %rbp,%rbx
  je     L20
L125:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  call   <getop@plt>
  cmp    $0x2d,%al
  je     L3
  jle    L97
  cmp    $0x2f,%al
  je     L4
  cmp    $0x6e,%al
  jne    L50
  mov    (%rbx),%rdi
  call   <atof@plt>
  call   <push@plt>
  cmp    %rbp,%rbx
  jne    L125
L20:
  xor    %eax,%eax
  call   <pop@plt>
  lea    D1(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  subsd  0x8(%rsp),%xmm0
  call   <push@plt>
  jmp    L49
L50:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L49
  xchg   %ax,%ax
L55:
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  mulsd  0x8(%rsp),%xmm0
  call   <push@plt>
  jmp    L49
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  divsd  0x8(%rsp),%xmm0
  call   <push@plt>
  jmp    L49
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D6: Error: unknown operator

tool: D1: final result is: %g


assistant: ```c
int main(int argc, char *argv[]) {
  double op2;
  char ch;
  while (--argc > 0) {
    ch = getop(*++argv);
    switch (ch) {
    case 'n':
      push(atof(*argv));
      break;
    case '+':
      push(pop() + pop());
      break;
    case '-':
      op2 = pop();
      push(pop() - op2);
      break;
    case '*':
      push(pop() * pop());
      break;
    case '/':
      op2 = pop();
      push(pop() / op2);
      break;
    default:
      printf("Error: unknown operator\n");
      break;
    }
  }
  printf("final result is: %g\n", pop());
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x1,%edi
  jle    L57
  lea    -0x2(%rdi),%eax
  mov    %rsi,%rbx
  lea    D19(%rip),%r12
  lea    0x8(%rsi,%rax,8),%rbp
  jmp    L97
  nopl   (%rax)
L79:
  cmp    $0x2a,%al
  je     L93
  cmp    $0x2b,%al
  jne    L122
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  addsd  0x8(%rsp),%xmm0
  call   <push@plt>
L8:
  cmp    %rbp,%rbx
  je     L57
L97:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  call   <getop@plt>
  cmp    $0x2d,%al
  je     L16
  jle    L79
  cmp    $0x2f,%al
  je     L33
  cmp    $0x6e,%al
  jne    L122
  mov    (%rbx),%rdi
  call   <atof@plt>
  call   <push@plt>
  cmp    %rbp,%rbx
  jne    L97
L57:
  xor    %eax,%eax
  call   <pop@plt>
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  subsd  0x8(%rsp),%xmm0
  call   <push@plt>
  jmp    L8
L122:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L8
  xchg   %ax,%ax
L93:
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  mulsd  0x8(%rsp),%xmm0
  call   <push@plt>
  jmp    L8
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  divsd  0x8(%rsp),%xmm0
  call   <push@plt>
  jmp    L8
```

tool_calls: name: read_data
arguments: data_label: D19
data_type: string
name: read_data
arguments: data_label: D11
data_type: string

tool: D19: Error: unknown operator

tool: D11: final result is: %g


assistant: ```c
int main(int argc, char *argv[]) {
  double op2;
  char ch;
  while (--argc > 0) {
    ch = getop(*++argv);
    switch (ch) {
    case 'n':
      push(atof(*argv));
      break;
    case '+':
      push(pop() + pop());
      break;
    case '-':
      op2 = pop();
      push(pop() - op2);
      break;
    case '*':
      push(pop() * pop());
      break;
    case '/':
      op2 = pop();
      push(pop() / op2);
      break;
    default:
      printf("Error: unknown operator\n");
      break;
    }
  }
  printf("final result is: %g\n", pop());
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dsi_get_pll_hsdiv_dispc_rate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <WARN@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_infered: string
name: read_data
arguments: data_label: D4
type_infered: string

tool: D17: dsi_get_pll_hsdiv_dispc_rate

tool: D4: %s: DSI not compiled in, returning rate as 0


assistant: ```c
unsigned long dsi_get_pll_hsdiv_dispc_rate(void) {
  WARN("%s: DSI not compiled in, returning rate as 0\n", __func__);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dsi_get_pll_hsdiv_dispc_rate>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <WARN@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: string
name: parse_data
arguments: label: D10
type: string

tool: D7: dsi_get_pll_hsdiv_dispc_rate

tool: D10: %s: DSI not compiled in, returning rate as 0


assistant: ```c
unsigned long dsi_get_pll_hsdiv_dispc_rate(void) {
  WARN("%s: DSI not compiled in, returning rate as 0\n", __func__);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dsi_get_pll_hsdiv_dispc_rate>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <WARN@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D14
type: string

tool: D19: dsi_get_pll_hsdiv_dispc_rate

tool: D14: %s: DSI not compiled in, returning rate as 0


assistant: ```c
unsigned long dsi_get_pll_hsdiv_dispc_rate(void) {
  WARN("%s: DSI not compiled in, returning rate as 0\n", __func__);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dsi_get_pll_hsdiv_dispc_rate>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <WARN@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string

tool: D6: dsi_get_pll_hsdiv_dispc_rate

tool: D12: %s: DSI not compiled in, returning rate as 0


assistant: ```c
unsigned long dsi_get_pll_hsdiv_dispc_rate(void) {
  WARN("%s: DSI not compiled in, returning rate as 0\n", __func__);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<receive_from_server>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0xfff9,%edx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L3:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: receive_from_server(): failure

assistant: ```c
int32_t receive_from_server(int sock, char *packet) {
  int32_t pktlen;
  if ((pktlen = recv(sock, packet, 65530 - 1, 0)) <= 0) {
    printf("receive_from_server(): failure");
    exit(1);
  }
  packet[pktlen] = 0;
  return pktlen;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<receive_from_server>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    $0x0,%ecx
  mov    $0xfff9,%edx
  call   <recv@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
L19:
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L19
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string

tool: D2: receive_from_server(): failure

assistant: ```c
int32_t receive_from_server(int sock, char *packet) {
  int32_t pktlen;
  if ((pktlen = recv(sock, packet, 65530 - 1, 0)) <= 0) {
    printf("receive_from_server(): failure");
    exit(1);
  }
  packet[pktlen] = 0;
  return pktlen;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<receive_from_server>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    $0xfff9,%edx
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <recv@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: string

tool: D6: receive_from_server(): failure

assistant: ```c
int32_t receive_from_server(int sock, char *packet) {
  int32_t pktlen;
  if ((pktlen = recv(sock, packet, 65530 - 1, 0)) <= 0) {
    printf("receive_from_server(): failure");
    exit(1);
  }
  packet[pktlen] = 0;
  return pktlen;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<receive_from_server>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    $0xfff9,%edx
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <recv@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: receive_from_server(): failure

assistant: ```c
int32_t receive_from_server(int sock, char *packet) {
  int32_t pktlen;
  if ((pktlen = recv(sock, packet, 65530 - 1, 0)) <= 0) {
    printf("receive_from_server(): failure");
    exit(1);
  }
  packet[pktlen] = 0;
  return pktlen;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<QEIDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  and    $0xfffffffe,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void QEIDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) &= ~(0x00000001);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<QEIDisable>:
  endbr64
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void QEIDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) &= ~(0x00000001);
}
```
user: Translate the below assembly code into C programming language:

```asm
<QEIDisable>:
  endbr64
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void QEIDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) &= ~(0x00000001);
}
```