ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<lock_with_timeout>:
  endbr64
  push   %r13
  movabs $0x98968000000000,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  imul   $0x3e8,(%rsi),%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L38:
  mov    %rbp,%rdi
  call   <pthread_mutex_trylock@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L20
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L20:
  mov    %rsp,%rdi
  xor    %esi,%esi
  sub    $0xa,%ebx
  mov    %r13,(%rsp)
  call   <nanosleep@plt>
  test   %ebx,%ebx
  jg     L38
  jmp    L27
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lock_with_timeout(pthread_mutex_t *mutex, const struct timespec *ts) {
  int ret;
  int left, step;
  left = ts->tv_sec * 1000;
  step = 10;
  do {
    if ((ret = pthread_mutex_trylock(mutex)) != 0) {
      struct timespec dly;
      dly.tv_sec = 0;
      dly.tv_nsec = step * 1000000;
      nanosleep(&dly, NULL);
      left -= step;
    }
  } while (ret != 0 && left > 0);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lock_with_timeout>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  imul   $0x3e8,(%rsi),%ebx
  mov    D3(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xchg   %ax,%ax
L37:
  mov    %rbp,%rdi
  call   <pthread_mutex_trylock@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L6
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L6:
  mov    %rsp,%rdi
  xor    %esi,%esi
  sub    $0xa,%ebx
  mov    %r13,(%rsp)
  call   <nanosleep@plt>
  test   %ebx,%ebx
  jg     L37
  jmp    L3
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x80,0x96,0x98,0x00]}

assistant: ```c
int lock_with_timeout(pthread_mutex_t *mutex, const struct timespec *ts) {
  int ret;
  int left, step;
  left = ts->tv_sec * 1000;
  step = 10;
  do {
    if ((ret = pthread_mutex_trylock(mutex)) != 0) {
      struct timespec dly;
      dly.tv_sec = 0;
      dly.tv_nsec = step * 1000000;
      nanosleep(&dly, NULL);
      left -= step;
    }
  } while (ret != 0 && left > 0);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D66
type_infered: string
name: retrieve_data
arguments: label: D25
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string
name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D77
type_infered: string
name: retrieve_data
arguments: label: D37
type_infered: string
name: retrieve_data
arguments: label: D68
type_infered: string

tool: D66: 


			*** MAIN MENU ***			


tool: D25: >>> Select 1: to SELECT your 6 numbers from the range 1 to 42.


tool: D24: >>> Select 2: to DISPLAY your 6 chosen numbers.


tool: D29: >>> Select 3: to SORT your numbers in ascending order.


tool: D7: >>> Select 4: to CHECK if you are a winner.


tool: D77: >>> Select 5: to display the FREQUENCY of the numbers you have selected.


tool: D37: >>> Select 6: to EXIT the game.



tool: D68: 
>>> Please select a Menu Option: 

assistant: ```c
void print_menu(void) {
  printf("\n\n\n\t\t\t*** MAIN MENU ***\t\t\t\n");
  printf(">>> Select 1: to SELECT your 6 numbers from the range 1 to 42.\n");
  printf(">>> Select 2: to DISPLAY your 6 chosen numbers.\n");
  printf(">>> Select 3: to SORT your numbers in ascending order.\n");
  printf(">>> Select 4: to CHECK if you are a winner.\n");
  printf(">>> Select 5: to display the FREQUENCY of the numbers you have selected.\n");
  printf(">>> Select 6: to EXIT the game.\n\n");
  printf("\n>>> Please select a Menu Option: ");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D70(%rip),%rdi
  call   <printf@plt>
  lea    D77(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D70
type_guessed: string
name: unpack_data
arguments: data_tag: D77
type_guessed: string
name: unpack_data
arguments: data_tag: D41
type_guessed: string
name: unpack_data
arguments: data_tag: D11
type_guessed: string
name: unpack_data
arguments: data_tag: D51
type_guessed: string
name: unpack_data
arguments: data_tag: D35
type_guessed: string
name: unpack_data
arguments: data_tag: D53
type_guessed: string

tool: D15: 


			*** MAIN MENU ***			


tool: D70: >>> Select 1: to SELECT your 6 numbers from the range 1 to 42.


tool: D77: >>> Select 2: to DISPLAY your 6 chosen numbers.


tool: D41: >>> Select 3: to SORT your numbers in ascending order.


tool: D11: >>> Select 4: to CHECK if you are a winner.


tool: D51: >>> Select 5: to display the FREQUENCY of the numbers you have selected.


tool: D35: >>> Select 6: to EXIT the game.



tool: D53: 
>>> Please select a Menu Option: 

assistant: ```c
void print_menu(void) {
  printf("\n\n\n\t\t\t*** MAIN MENU ***\t\t\t\n");
  printf(">>> Select 1: to SELECT your 6 numbers from the range 1 to 42.\n");
  printf(">>> Select 2: to DISPLAY your 6 chosen numbers.\n");
  printf(">>> Select 3: to SORT your numbers in ascending order.\n");
  printf(">>> Select 4: to CHECK if you are a winner.\n");
  printf(">>> Select 5: to display the FREQUENCY of the numbers you have selected.\n");
  printf(">>> Select 6: to EXIT the game.\n\n");
  printf("\n>>> Please select a Menu Option: ");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D37
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D58
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D29
type: string

tool: D37: 


			*** MAIN MENU ***			


tool: D16: >>> Select 1: to SELECT your 6 numbers from the range 1 to 42.


tool: D58: >>> Select 2: to DISPLAY your 6 chosen numbers.


tool: D9: >>> Select 3: to SORT your numbers in ascending order.


tool: D21: >>> Select 4: to CHECK if you are a winner.


tool: D22: >>> Select 5: to display the FREQUENCY of the numbers you have selected.


tool: D0: >>> Select 6: to EXIT the game.



tool: D29: 
>>> Please select a Menu Option: 

assistant: ```c
void print_menu(void) {
  printf("\n\n\n\t\t\t*** MAIN MENU ***\t\t\t\n");
  printf(">>> Select 1: to SELECT your 6 numbers from the range 1 to 42.\n");
  printf(">>> Select 2: to DISPLAY your 6 chosen numbers.\n");
  printf(">>> Select 3: to SORT your numbers in ascending order.\n");
  printf(">>> Select 4: to CHECK if you are a winner.\n");
  printf(">>> Select 5: to display the FREQUENCY of the numbers you have selected.\n");
  printf(">>> Select 6: to EXIT the game.\n\n");
  printf("\n>>> Please select a Menu Option: ");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string
name: disassemble_data
arguments: label: D41
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D62
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string
name: disassemble_data
arguments: label: D54
data_type: string
name: disassemble_data
arguments: label: D7
data_type: string

tool: D15: 


			*** MAIN MENU ***			


tool: D8: >>> Select 1: to SELECT your 6 numbers from the range 1 to 42.


tool: D41: >>> Select 2: to DISPLAY your 6 chosen numbers.


tool: D26: >>> Select 3: to SORT your numbers in ascending order.


tool: D62: >>> Select 4: to CHECK if you are a winner.


tool: D19: >>> Select 5: to display the FREQUENCY of the numbers you have selected.


tool: D54: >>> Select 6: to EXIT the game.



tool: D7: 
>>> Please select a Menu Option: 

assistant: ```c
void print_menu(void) {
  printf("\n\n\n\t\t\t*** MAIN MENU ***\t\t\t\n");
  printf(">>> Select 1: to SELECT your 6 numbers from the range 1 to 42.\n");
  printf(">>> Select 2: to DISPLAY your 6 chosen numbers.\n");
  printf(">>> Select 3: to SORT your numbers in ascending order.\n");
  printf(">>> Select 4: to CHECK if you are a winner.\n");
  printf(">>> Select 5: to display the FREQUENCY of the numbers you have selected.\n");
  printf(">>> Select 6: to EXIT the game.\n\n");
  printf("\n>>> Please select a Menu Option: ");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calculate_number_of_nodes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jne    L11
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L5
L11:
  mov    -0x2c(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ipow@plt>
  imul   %eax,%ebx
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ipow@plt>
  sub    $0x1,%eax
  mov    -0x24(%rbp),%edx
  lea    -0x1(%rdx),%ecx
  cltd
  idiv   %ecx
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int calculate_number_of_nodes(int md, int Nr, int Nh) {
  int n_nodes;
  if (md == 1) {
    n_nodes = Nh + 1;
  } else {
    n_nodes = (Nh - Nr) * ipow(md, Nr) + (ipow(md, Nr + 1) - 1) / (md - 1);
  }
  return n_nodes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculate_number_of_nodes>:
  endbr64
  cmp    $0x1,%edi
  jne    L7
  lea    0x1(%rdx),%eax
  ret
L7:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  sub    %esi,%ebx
  call   <ipow@plt>
  imul   %eax,%ebx
  lea    0x1(%r12),%esi
  mov    %ebp,%edi
  call   <ipow@plt>
  sub    $0x1,%eax
  sub    $0x1,%ebp
  cltd
  idiv   %ebp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int calculate_number_of_nodes(int md, int Nr, int Nh) {
  int n_nodes;
  if (md == 1) {
    n_nodes = Nh + 1;
  } else {
    n_nodes = (Nh - Nr) * ipow(md, Nr) + (ipow(md, Nr + 1) - 1) / (md - 1);
  }
  return n_nodes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calculate_number_of_nodes>:
  endbr64
  cmp    $0x1,%edi
  jne    L2
  lea    0x1(%rdx),%eax
  ret
  nopl   (%rax)
L2:
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    %esi,%ebx
  call   <ipow@plt>
  lea    0x1(%r12),%esi
  mov    %ebp,%edi
  sub    $0x1,%ebp
  imul   %eax,%ebx
  call   <ipow@plt>
  sub    $0x1,%eax
  cltd
  idiv   %ebp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int calculate_number_of_nodes(int md, int Nr, int Nh) {
  int n_nodes;
  if (md == 1) {
    n_nodes = Nh + 1;
  } else {
    n_nodes = (Nh - Nr) * ipow(md, Nr) + (ipow(md, Nr + 1) - 1) / (md - 1);
  }
  return n_nodes;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calculate_number_of_nodes>:
  endbr64
  cmp    $0x1,%edi
  jne    L2
  lea    0x1(%rdx),%eax
  ret
  nopl   (%rax)
L2:
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    %esi,%ebx
  call   <ipow@plt>
  lea    0x1(%r12),%esi
  mov    %ebp,%edi
  sub    $0x1,%ebp
  imul   %eax,%ebx
  call   <ipow@plt>
  sub    $0x1,%eax
  cltd
  idiv   %ebp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int calculate_number_of_nodes(int md, int Nr, int Nh) {
  int n_nodes;
  if (md == 1) {
    n_nodes = Nh + 1;
  } else {
    n_nodes = (Nh - Nr) * ipow(md, Nr) + (ipow(md, Nr + 1) - 1) / (md - 1);
  }
  return n_nodes;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <handleNewServiceDiscoveryRequests@plt>
  mov    $0x0,%eax
  call   <handleNewConnections@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void run() {
  handleNewServiceDiscoveryRequests();
  handleNewConnections();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<run>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <handleNewServiceDiscoveryRequests@plt>
  mov    $0x0,%eax
  call   <handleNewConnections@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void run() {
  handleNewServiceDiscoveryRequests();
  handleNewConnections();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<run>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <handleNewServiceDiscoveryRequests@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <handleNewConnections@plt>
```

assistant: ```c
void run() {
  handleNewServiceDiscoveryRequests();
  handleNewConnections();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<run>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <handleNewServiceDiscoveryRequests@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <handleNewConnections@plt>
```

assistant: ```c
void run() {
  handleNewServiceDiscoveryRequests();
  handleNewConnections();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jle    L15
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L11
L15:
  cmpl   $0x2,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L52
L11:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <round@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x3,-0x8(%rbp)
  jmp    L40
L12:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L46
  mov    $0x0,%eax
  jmp    L52
L46:
  addl   $0x2,-0x8(%rbp)
L40:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L12
  mov    $0x1,%eax
L52:
  leave
  ret
```

assistant: ```c
int is_prime(uint64_t s) {
  if (s <= 2 || s % 2 == 0)
    return (s == 2);
  uint64_t top = (uint64_t)round((double)sqrt(s));
  for (uint64_t i = 3; i <= top; i += 2) {
    if (s % i == 0)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_prime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x2,%edi
  jle    L18
  test   $0x1,%dil
  jne    L84
L18:
  cmp    $0x2,%ebx
  sete   %al
  movzbl %al,%eax
L9:
  pop    %rbx
  ret
L84:
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  call   <round@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L50
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L9
  mov    $0x3,%ecx
L77:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jl     L0
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L77
  jmp    L9
L0:
  mov    $0x1,%eax
  jmp    L9
L50:
  mov    $0x1,%eax
  jmp    L9
```

assistant: ```c
int is_prime(uint64_t s) {
  if (s <= 2 || s % 2 == 0)
    return (s == 2);
  uint64_t top = (uint64_t)round((double)sqrt(s));
  for (uint64_t i = 3; i <= top; i += 2) {
    if (s % i == 0)
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_prime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  cmp    $0x2,%edi
  jle    L25
  test   $0x1,%dil
  jne    L19
L25:
  xor    %edx,%edx
  cmp    $0x2,%r12d
  sete   %dl
L65:
  mov    %edx,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  call   <round@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L54
  movslq %r12d,%rdx
  mov    %r12d,%eax
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %r12d,%edx
  sub    %eax,%edx
  je     L65
  mov    $0x3,%ecx
  jmp    L67
  nopl   0x0(%rax)
L62:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L65
L67:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jge    L62
L54:
  mov    $0x1,%edx
  pop    %r12
  mov    %edx,%eax
  ret
```

assistant: ```c
int is_prime(uint64_t s) {
  if (s <= 2 || s % 2 == 0)
    return (s == 2);
  uint64_t top = (uint64_t)round((double)sqrt(s));
  for (uint64_t i = 3; i <= top; i += 2) {
    if (s % i == 0)
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_prime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  cmp    $0x2,%edi
  jle    L68
  test   $0x1,%dil
  jne    L34
L68:
  xor    %edx,%edx
  cmp    $0x2,%r12d
  sete   %dl
L67:
  mov    %edx,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  call   <round@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L2
  movslq %r12d,%rdx
  mov    %r12d,%eax
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %r12d,%edx
  sub    %eax,%edx
  je     L67
  mov    $0x3,%ecx
  jmp    L55
  nopl   0x0(%rax)
L64:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L67
L55:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jge    L64
L2:
  mov    $0x1,%edx
  pop    %r12
  mov    %edx,%eax
  ret
```

assistant: ```c
int is_prime(uint64_t s) {
  if (s <= 2 || s % 2 == 0)
    return (s == 2);
  uint64_t top = (uint64_t)round((double)sqrt(s));
  for (uint64_t i = 3; i <= top; i += 2) {
    if (s % i == 0)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<IsNumeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L6
L19:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  jmp    L14
L6:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  jne    L19
  mov    $0x1,%eax
L14:
  leave
  ret
```

assistant: ```c
unsigned int IsNumeric(const char *str, size_t len) {
  while (len-- > 0) {
    if (!isdigit(str[len])) {
      return (0);
    }
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<IsNumeric>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rdi,%rsi,1),%rbx
  lea    -0x1(%rdi),%rbp
L28:
  cmp    %rbp,%rbx
  je     L14
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  sub    $0x1,%rbx
  test   %eax,%eax
  jne    L28
  mov    $0x0,%eax
  jmp    L26
L14:
  mov    $0x1,%eax
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int IsNumeric(const char *str, size_t len) {
  while (len-- > 0) {
    if (!isdigit(str[len])) {
      return (0);
    }
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<IsNumeric>:
  endbr64
  push   %rbp
  lea    -0x1(%rdi),%rbp
  push   %rbx
  lea    -0x1(%rdi,%rsi,1),%rbx
  sub    $0x8,%rsp
  jmp    L26
  nopl   (%rax)
L12:
  movsbl (%rbx),%edi
  sub    $0x1,%rbx
  call   <isdigit@plt>
  test   %eax,%eax
  je     L29
L26:
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int IsNumeric(const char *str, size_t len) {
  while (len-- > 0) {
    if (!isdigit(str[len])) {
      return (0);
    }
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<IsNumeric>:
  endbr64
  push   %rbp
  lea    -0x1(%rdi),%rbp
  push   %rbx
  lea    -0x1(%rdi,%rsi,1),%rbx
  sub    $0x8,%rsp
  jmp    L19
  nopl   (%rax)
L1:
  movsbl (%rbx),%edi
  sub    $0x1,%rbx
  call   <isdigit@plt>
  test   %eax,%eax
  je     L26
L19:
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int IsNumeric(const char *str, size_t len) {
  while (len-- > 0) {
    if (!isdigit(str[len])) {
      return (0);
    }
  }
  return (1);
}
```