ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L4
  mov    0x8(%rsi),%rsi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%rdi
  xor    %eax,%eax
  call   <eval_expr@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L17:
  xor    %eax,%eax
  pop    %rbx
  ret
L4:
  mov    (%rsi),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L17
```

tool_calls: name: unpack_data
arguments: label: D20
data_type: string
name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D19
data_type: string

tool: D20: %s = 

tool: D11: %d

Eval expr - Copyright (c) 2015 Romain Vermot


tool: D19: Usage: %s expr


assistant: ```c
int main(int ac, char **av) {
  if (ac > 1) {
    printf("%s = ", av[1]);
    printf("%d\n\nEval expr - Copyright (c) 2015 Romain Vermot\n", eval_expr(av[1]));
  } else
    printf("Usage: %s expr\n", av[0]);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<menu_clef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  jmp    L17
L47:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L32
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  jle    L17
L32:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L47
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  jg     L47
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string
name: parse_data
arguments: data_tag: D62
type_guessed: string
name: parse_data
arguments: data_tag: D27
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D60
type_guessed: string

tool: D34: cls

tool: D8: Veulliez entrer un choix :


tool: D62: 1- Entrez votre clef


tool: D27: 2- Retour au menu principal



tool: D9: %d

tool: D60: Erreur : vous n'avez pas entre un choix correct


assistant: ```c
int menu_clef(void) {
  int choix = 0;
  system("cls");
  while (choix < 1 || choix > 2) {
    printf("Veulliez entrer un choix :\n");
    printf("1- Entrez votre clef\n");
    printf("2- Retour au menu principal\n\n");
    scanf("%d", &choix);
    getchar();
    if (choix < 1 || choix > 2) {
      system("cls");
      printf("Erreur : vous n'avez pas entre un choix correct\n");
    }
  }
  return choix;
}
```
user: Translate the below assembly code into C programming language:

```asm
<menu_clef>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D65(%rip),%rdi
  call   <system@plt>
  lea    D60(%rip),%r13
  lea    D29(%rip),%r12
  lea    D62(%rip),%rbp
L2:
  lea    D16(%rip),%rbx
L6:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L11
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x1,%eax
  jbe    L6
  lea    D65(%rip),%rdi
  call   <system@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D65
datatype: string
name: disassemble_data
arguments: tag: D60
datatype: string
name: disassemble_data
arguments: tag: D29
datatype: string
name: disassemble_data
arguments: tag: D62
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string

tool: D65: cls

tool: D60: Veulliez entrer un choix :


tool: D29: 1- Entrez votre clef


tool: D62: 2- Retour au menu principal



tool: D16: %d

tool: D7: Erreur : vous n'avez pas entre un choix correct


assistant: ```c
int menu_clef(void) {
  int choix = 0;
  system("cls");
  while (choix < 1 || choix > 2) {
    printf("Veulliez entrer un choix :\n");
    printf("1- Entrez votre clef\n");
    printf("2- Retour au menu principal\n\n");
    scanf("%d", &choix);
    getchar();
    if (choix < 1 || choix > 2) {
      system("cls");
      printf("Erreur : vous n'avez pas entre un choix correct\n");
    }
  }
  return choix;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<menu_clef>:
  endbr64
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  lea    D37(%rip),%r12
  push   %rbp
  lea    D41(%rip),%rbp
  push   %rbx
  lea    D49(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <system@plt>
L32:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L11
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1,%edx
  ja     L2
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L2:
  mov    %r13,%rdi
  call   <system@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D11
type_infered: string
name: read_data
arguments: label: D37
type_infered: string
name: read_data
arguments: label: D41
type_infered: string
name: read_data
arguments: label: D49
type_infered: string
name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D58
type_infered: string

tool: D11: cls

tool: D37: Veulliez entrer un choix :


tool: D41: 1- Entrez votre clef


tool: D49: 2- Retour au menu principal



tool: D24: %d

tool: D58: Erreur : vous n'avez pas entre un choix correct


assistant: ```c
int menu_clef(void) {
  int choix = 0;
  system("cls");
  while (choix < 1 || choix > 2) {
    printf("Veulliez entrer un choix :\n");
    printf("1- Entrez votre clef\n");
    printf("2- Retour au menu principal\n\n");
    scanf("%d", &choix);
    getchar();
    if (choix < 1 || choix > 2) {
      system("cls");
      printf("Erreur : vous n'avez pas entre un choix correct\n");
    }
  }
  return choix;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<menu_clef>:
  endbr64
  push   %r13
  lea    D50(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  lea    D40(%rip),%r12
  push   %rbp
  lea    D56(%rip),%rbp
  push   %rbx
  lea    D23(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <system@plt>
L28:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L27
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1,%edx
  ja     L29
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L29:
  mov    %r13,%rdi
  call   <system@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D50
datatype: string
name: extract_symbolic_data
arguments: label: D40
datatype: string
name: extract_symbolic_data
arguments: label: D56
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D54
datatype: string
name: extract_symbolic_data
arguments: label: D53
datatype: string

tool: D50: cls

tool: D40: Veulliez entrer un choix :


tool: D56: 1- Entrez votre clef


tool: D23: 2- Retour au menu principal



tool: D54: %d

tool: D53: Erreur : vous n'avez pas entre un choix correct


assistant: ```c
int menu_clef(void) {
  int choix = 0;
  system("cls");
  while (choix < 1 || choix > 2) {
    printf("Veulliez entrer un choix :\n");
    printf("1- Entrez votre clef\n");
    printf("2- Retour au menu principal\n\n");
    scanf("%d", &choix);
    getchar();
    if (choix < 1 || choix > 2) {
      system("cls");
      printf("Erreur : vous n'avez pas entre un choix correct\n");
    }
  }
  return choix;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<chi_heap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <chi_recur@plt>
  movq   %xmm0,%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void chi_heap(int *i, int *j, int *n0, double *prob) {
  double chi_recur(int i, int j, int n0);
  *prob = chi_recur(*i, *j, *n0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<chi_heap>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  call   <chi_recur@plt>
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void chi_heap(int *i, int *j, int *n0, double *prob) {
  double chi_recur(int i, int j, int n0);
  *prob = chi_recur(*i, *j, *n0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<chi_heap>:
  endbr64
  push   %rbx
  mov    (%rdx),%edx
  mov    %rcx,%rbx
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  call   <chi_recur@plt>
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void chi_heap(int *i, int *j, int *n0, double *prob) {
  double chi_recur(int i, int j, int n0);
  *prob = chi_recur(*i, *j, *n0);
}
```
user: What is the c source code of the assembly code below?

```asm
<chi_heap>:
  endbr64
  push   %rbx
  mov    (%rdx),%edx
  mov    %rcx,%rbx
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  call   <chi_recur@plt>
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void chi_heap(int *i, int *j, int *n0, double *prob) {
  double chi_recur(int i, int j, int n0);
  *prob = chi_recur(*i, *j, *n0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L15
  movsbl -0x1(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L6
L15:
  mov    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int test4(int b, int c) {
  char x;
  if (b)
    return x == c;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test4>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L8
  test   %esi,%esi
  sete   %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int test4(int b, int c) {
  char x;
  if (b)
    return x == c;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<test4>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L4
  xor    %eax,%eax
  test   %esi,%esi
  sete   %al
L4:
  ret
```

assistant: ```c
int test4(int b, int c) {
  char x;
  if (b)
    return x == c;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test4>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L6
  xor    %eax,%eax
  test   %esi,%esi
  sete   %al
L6:
  ret
```

assistant: ```c
int test4(int b, int c) {
  char x;
  if (b)
    return x == c;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Q_gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L12
L10:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L12:
  cmpl   $0x0,-0x18(%rbp)
  jne    L10
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Q_gcd(int a, int b) {
  while (b != 0) {
    int t = b;
    b = a % b;
    a = t;
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Q_gcd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L9
L0:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L0
L11:
  mov    %ecx,%eax
  ret
L9:
  mov    %edi,%ecx
  jmp    L11
```

assistant: ```c
int Q_gcd(int a, int b) {
  while (b != 0) {
    int t = b;
    b = a % b;
    a = t;
  }
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Q_gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L0
  nopl   0x0(%rax)
L13:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Q_gcd(int a, int b) {
  while (b != 0) {
    int t = b;
    b = a % b;
    a = t;
  }
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Q_gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L3
  nopl   0x0(%rax)
L6:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Q_gcd(int a, int b) {
  while (b != 0) {
    int t = b;
    b = a % b;
    a = t;
  }
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<geom_J_sph_rtp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double geom_J_sph_rtp(double x[]) {
  double r = x[0];
  double st = sin(x[1]);
  return r * r * st;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<geom_J_sph_rtp>:
  endbr64
  push   %rbx
  mov    (%rdi),%rbx
  movsd  0x8(%rdi),%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double geom_J_sph_rtp(double x[]) {
  double r = x[0];
  double st = sin(x[1]);
  return r * r * st;
}
```
user: Translate the below assembly code into C programming language:

```asm
<geom_J_sph_rtp>:
  endbr64
  sub    $0x18,%rsp
  movsd  (%rdi),%xmm1
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double geom_J_sph_rtp(double x[]) {
  double r = x[0];
  double st = sin(x[1]);
  return r * r * st;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<geom_J_sph_rtp>:
  endbr64
  sub    $0x18,%rsp
  movsd  (%rdi),%xmm1
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double geom_J_sph_rtp(double x[]) {
  double r = x[0];
  double st = sin(x[1]);
  return r * r * st;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CSPL_Stats_IQR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x19,%esi
  mov    %rax,%rdi
  call   <CSPL_Stats_percentile@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x4b,%esi
  mov    %rax,%rdi
  call   <CSPL_Stats_percentile@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double CSPL_Stats_IQR(double *inval, long n) {
  double q25, q75;
  q25 = CSPL_Stats_percentile(inval, 25., n);
  q75 = CSPL_Stats_percentile(inval, 75., n);
  return (q75 - q25);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CSPL_Stats_IQR>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdx
  mov    $0x19,%esi
  call   <CSPL_Stats_percentile@plt>
  movq   %xmm0,%r14
  mov    %rbp,%rdx
  mov    $0x4b,%esi
  mov    %rbx,%rdi
  call   <CSPL_Stats_percentile@plt>
  movq   %r14,%xmm1
  subsd  %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
double CSPL_Stats_IQR(double *inval, long n) {
  double q25, q75;
  q25 = CSPL_Stats_percentile(inval, 25., n);
  q75 = CSPL_Stats_percentile(inval, 75., n);
  return (q75 - q25);
}
```
user: What is the c source code of the assembly code below:

```asm
<CSPL_Stats_IQR>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  mov    $0x19,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  call   <CSPL_Stats_percentile@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x4b,%esi
  movsd  %xmm0,0x8(%rsp)
  call   <CSPL_Stats_percentile@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double CSPL_Stats_IQR(double *inval, long n) {
  double q25, q75;
  q25 = CSPL_Stats_percentile(inval, 25., n);
  q75 = CSPL_Stats_percentile(inval, 75., n);
  return (q75 - q25);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CSPL_Stats_IQR>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  mov    $0x19,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  call   <CSPL_Stats_percentile@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x4b,%esi
  movsd  %xmm0,0x8(%rsp)
  call   <CSPL_Stats_percentile@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double CSPL_Stats_IQR(double *inval, long n) {
  double q25, q75;
  q25 = CSPL_Stats_percentile(inval, 25., n);
  q75 = CSPL_Stats_percentile(inval, 75., n);
  return (q75 - q25);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L52:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L73
L4:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L73:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L66
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L4
L66:
  cmpl   $0x0,-0x4(%rbp)
  jle    L65
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
  mov    -0xc(%rbp),%eax
  jmp    L22
L65:
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  mov    $0xffffffff,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  int i, j, k;
  for (i = 0; *(s + i) != '\0'; i++) {
    for (j = i, k = 0; *(t + k) != '\0' && *(s + j) == *(t + k); j++, k++)
      ;
    if (k > 0 && *(t + k) == '\0')
      return i;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L82
  movzbl (%rsi),%r9d
  mov    $0x0,%r8d
  jmp    L95
L66:
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  je     L40
L95:
  mov    %r9d,%edx
  mov    $0x0,%eax
  test   %r9b,%r9b
  je     L66
L62:
  mov    %eax,%ecx
  cmp    %dl,(%rdi,%rax,1)
  jne    L21
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L62
L21:
  test   %dl,%dl
  jne    L66
  test   %ecx,%ecx
  jle    L66
  jmp    L19
L82:
  mov    $0xffffffff,%r8d
  jmp    L19
L40:
  mov    $0xffffffff,%r8d
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  int i, j, k;
  for (i = 0; *(s + i) != '\0'; i++) {
    for (j = i, k = 0; *(t + k) != '\0' && *(s + j) == *(t + k); j++, k++)
      ;
    if (k > 0 && *(t + k) == '\0')
      return i;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L32
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  nop
L50:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L52
  jmp    L33
L35:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L13
L52:
  cmp    %dl,(%rdi,%rax,1)
  je     L35
L33:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L50
L32:
  mov    $0xffffffff,%r9d
L13:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  int i, j, k;
  for (i = 0; *(s + i) != '\0'; i++) {
    for (j = i, k = 0; *(t + k) != '\0' && *(s + j) == *(t + k); j++, k++)
      ;
    if (k > 0 && *(t + k) == '\0')
      return i;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  nop
L11:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L57
  jmp    L10
L18:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L2
L57:
  cmp    %dl,(%rdi,%rax,1)
  je     L18
L10:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L11
L19:
  mov    $0xffffffff,%r9d
L2:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  int i, j, k;
  for (i = 0; *(s + i) != '\0'; i++) {
    for (j = i, k = 0; *(t + k) != '\0' && *(s + j) == *(t + k); j++, k++)
      ;
    if (k > 0 && *(t + k) == '\0')
      return i;
  }
  return -1;
}
```