ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<integer_solve_quadratic_test>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x7,%edx
  mov    $0x2,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x8(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rbx,%r8
  mov    %r12,%rcx
  call   <integer_solve_quadratic@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x8,%edx
  mov    $0x2,%edi
  call   <integer_solve_quadratic@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0xfffffff8,%edx
  mov    $0x2,%edi
  call   <integer_solve_quadratic@plt>
  mov    %eax,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0xfffffffffffffffe,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x2,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0xfffffffe,%edx
  mov    $0x5,%esi
  mov    $0x2,%edi
  call   <integer_solve_quadratic@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x5,%edx
  mov    $0xfffffffa,%esi
  mov    $0x1,%edi
  call   <integer_solve_quadratic@plt>
  mov    %eax,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x1,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x5,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void integer_solve_quadratic_test(void) {
  long x1 = 0;
  long x2 = 0;
  assert(!integer_solve_quadratic(2, 0, 7, &x1, &x2));
  assert(!integer_solve_quadratic(2, 0, 8, &x1, &x2));
  assert(integer_solve_quadratic(2, 0, -8, &x1, &x2));
  assert(x1 == -2);
  assert(x2 == 2);
  assert(!integer_solve_quadratic(2, 5, -2, &x1, &x2));
  assert(integer_solve_quadratic(1, -6, 5, &x1, &x2));
  assert(x1 == 1);
  assert(x2 == 5);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<integer_solve_quadratic_test>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x7,%edx
  mov    $0x2,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x8(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rbx,%r8
  mov    %r12,%rcx
  call   <integer_solve_quadratic@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x8,%edx
  mov    $0x2,%edi
  call   <integer_solve_quadratic@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0xfffffff8,%edx
  mov    $0x2,%edi
  call   <integer_solve_quadratic@plt>
  mov    %eax,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0xfffffffffffffffe,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x2,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0xfffffffe,%edx
  mov    $0x5,%esi
  mov    $0x2,%edi
  call   <integer_solve_quadratic@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x5,%edx
  mov    $0xfffffffa,%esi
  mov    $0x1,%edi
  call   <integer_solve_quadratic@plt>
  mov    %eax,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x1,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x5,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void integer_solve_quadratic_test(void) {
  long x1 = 0;
  long x2 = 0;
  assert(!integer_solve_quadratic(2, 0, 7, &x1, &x2));
  assert(!integer_solve_quadratic(2, 0, 8, &x1, &x2));
  assert(integer_solve_quadratic(2, 0, -8, &x1, &x2));
  assert(x1 == -2);
  assert(x2 == 2);
  assert(!integer_solve_quadratic(2, 5, -2, &x1, &x2));
  assert(integer_solve_quadratic(1, -6, 5, &x1, &x2));
  assert(x1 == 1);
  assert(x2 == 5);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arrayInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jg     L28
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L33
L28:
  movl   $0x0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L11
L16:
  mov    -0x10(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L16
  mov    -0x8(%rbp),%rax
L33:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string

tool: D6: Step size too small

assistant: ```c
int *arrayInt(int lower, int step, int upper) {
  if (step <= 0) {
    perror("Step size too small");
  } else {
    int i = 0, numsteps = (upper - lower) / step + 1;
    int *someArray = malloc(numsteps * sizeof(int));
    while (i < numsteps) {
      someArray[i] = lower + i * step;
      i++;
    }
    return someArray;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arrayInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L19
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%eax
  sub    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%r12d
  lea    0x1(%rax),%r13d
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  test   %r13d,%r13d
  jle    L24
  mov    %ebx,%esi
  mov    %rax,%rcx
  mov    %r12d,%r12d
  lea    0x4(%rax,%r12,4),%rdx
L7:
  mov    %esi,(%rcx)
  add    %ebp,%esi
  add    $0x4,%rcx
  cmp    %rdx,%rcx
  jne    L7
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: Step size too small

assistant: ```c
int *arrayInt(int lower, int step, int upper) {
  if (step <= 0) {
    perror("Step size too small");
  } else {
    int i = 0, numsteps = (upper - lower) / step + 1;
    int *someArray = malloc(numsteps * sizeof(int));
    while (i < numsteps) {
      someArray[i] = lower + i * step;
      i++;
    }
    return someArray;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arrayInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L13
  mov    %edx,%eax
  mov    %edi,%ebx
  mov    %esi,%r12d
  sub    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%ebp
  lea    0x1(%rbp),%r13d
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  test   %r13d,%r13d
  jle    L23
  mov    %ebx,%esi
  mov    %rax,%rcx
  lea    0x4(%rax,%rbp,4),%rdx
L17:
  mov    %esi,(%rcx)
  add    $0x4,%rcx
  add    %r12d,%esi
  cmp    %rdx,%rcx
  jne    L17
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string

tool: D5: Step size too small

assistant: ```c
int *arrayInt(int lower, int step, int upper) {
  if (step <= 0) {
    perror("Step size too small");
  } else {
    int i = 0, numsteps = (upper - lower) / step + 1;
    int *someArray = malloc(numsteps * sizeof(int));
    while (i < numsteps) {
      someArray[i] = lower + i * step;
      i++;
    }
    return someArray;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arrayInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L77
  mov    %edx,%eax
  mov    %edi,%r12d
  mov    %esi,%ebx
  sub    %edi,%eax
  cltd
  idiv   %esi
  lea    0x1(%rax),%r13d
  mov    %eax,%ebp
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %r13d,%r13d
  jle    L64
  cmp    $0x2,%ebp
  jbe    L49
  movd   %ebx,%xmm7
  mov    %rax,%rcx
  mov    %r13d,%eax
  movdqa D29(%rip),%xmm2
  pshufd $0x0,%xmm7,%xmm3
  shr    $0x2,%eax
  movd   %r12d,%xmm7
  movdqa D14(%rip),%xmm5
  shl    $0x4,%rax
  movdqa %xmm3,%xmm4
  pshufd $0x0,%xmm7,%xmm6
  add    %r8,%rax
  psrlq  $0x20,%xmm4
  cs nopw 0x0(%rax,%rax,1)
L79:
  movdqa %xmm2,%xmm0
  add    $0x10,%rcx
  paddd  %xmm5,%xmm2
  movdqa %xmm0,%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm3,%xmm1
  pmuludq %xmm4,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  paddd  %xmm6,%xmm0
  movups %xmm0,-0x10(%rcx)
  cmp    %rax,%rcx
  jne    L79
  mov    %r13d,%edx
  and    $0xfffffffc,%edx
  and    $0x3,%r13d
  je     L64
L14:
  mov    %ebx,%eax
  movslq %edx,%rcx
  imul   %edx,%eax
  lea    0x0(,%rcx,4),%rsi
  lea    (%rax,%r12,1),%edi
  mov    %edi,(%r8,%rcx,4)
  lea    0x1(%rdx),%ecx
  cmp    %edx,%ebp
  jle    L64
  add    %ebx,%eax
  lea    (%r12,%rax,1),%edx
  mov    %edx,0x4(%r8,%rsi,1)
  cmp    %ecx,%ebp
  jle    L64
  add    %eax,%ebx
  add    %r12d,%ebx
  mov    %ebx,0x8(%r8,%rsi,1)
L64:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L77:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  add    $0x8,%rsp
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  xor    %edx,%edx
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D14
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: {"D29": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D14": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D3: Step size too small

assistant: ```c
int *arrayInt(int lower, int step, int upper) {
  if (step <= 0) {
    perror("Step size too small");
  } else {
    int i = 0, numsteps = (upper - lower) / step + 1;
    int *someArray = malloc(numsteps * sizeof(int));
    while (i < numsteps) {
      someArray[i] = lower + i * step;
      i++;
    }
    return someArray;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <change@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: 
In main, result = %d	number = %d

assistant: ```c
int main(void) {
  int number = 10;
  int result = 0;
  result = change(number);
  printf("\nIn main, result = %d\tnumber = %d", result, number);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <change@plt>
  mov    %eax,%esi
  mov    $0xa,%edx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D7: 
In main, result = %d	number = %d

assistant: ```c
int main(void) {
  int number = 10;
  int result = 0;
  result = change(number);
  printf("\nIn main, result = %d\tnumber = %d", result, number);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <change@plt>
  mov    $0xa,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: 
In main, result = %d	number = %d

assistant: ```c
int main(void) {
  int number = 10;
  int result = 0;
  result = change(number);
  printf("\nIn main, result = %d\tnumber = %d", result, number);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <change@plt>
  mov    $0xa,%edx
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: 
In main, result = %d	number = %d

assistant: ```c
int main(void) {
  int number = 10;
  int result = 0;
  result = change(number);
  printf("\nIn main, result = %d\tnumber = %d", result, number);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdx
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <set_table_default_action@plt>
  mov    $0x0,%eax
  call   <notify_controller_initialized@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D10
type_guessed: string
name: read_data
arguments: label: D18
type_guessed: string
name: read_data
arguments: label: D24
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string

tool: D10: Set default actions.


tool: D18: ingress.learn

tool: D24: ingress.t

tool: D29: t

assistant: ```c
void init() {
  printf("Set default actions.\n");
  set_table_default_action("t", "ingress.t", "ingress.learn");
  notify_controller_initialized();
}
```
user: What is the c source code of the assembly code below:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdx
  lea    D23(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <set_table_default_action@plt>
  mov    $0x0,%eax
  call   <notify_controller_initialized@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type: string
name: read_data
arguments: tag: D32
type: string
name: read_data
arguments: tag: D23
type: string
name: read_data
arguments: tag: D0
type: string

tool: D11: Set default actions.


tool: D32: ingress.learn

tool: D23: ingress.t

tool: D0: t

assistant: ```c
void init() {
  printf("Set default actions.\n");
  set_table_default_action("t", "ingress.t", "ingress.learn");
  notify_controller_initialized();
}
```
user: What is the c source code of the assembly code below:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdx
  lea    D16(%rip),%rsi
  lea    D31(%rip),%rdi
  call   <set_table_default_action@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <notify_controller_initialized@plt>
```

tool_calls: name: parse_data
arguments: tag: D33
data_type: string
name: parse_data
arguments: tag: D32
data_type: string
name: parse_data
arguments: tag: D16
data_type: string
name: parse_data
arguments: tag: D31
data_type: string

tool: D33: Set default actions.


tool: D32: ingress.learn

tool: D16: ingress.t

tool: D31: t

assistant: ```c
void init() {
  printf("Set default actions.\n");
  set_table_default_action("t", "ingress.t", "ingress.learn");
  notify_controller_initialized();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdx
  lea    D3(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <set_table_default_action@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <notify_controller_initialized@plt>
```

tool_calls: name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D33
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string

tool: D28: Set default actions.


tool: D33: ingress.learn

tool: D3: ingress.t

tool: D0: t

assistant: ```c
void init() {
  printf("Set default actions.\n");
  set_table_default_action("t", "ingress.t", "ingress.learn");
  notify_controller_initialized();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: ./pri-toolbox ud less|more [number in cm]


assistant: ```c
int usage(void) {
  printf("./pri-toolbox ud less|more [number in cm]\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D9: ./pri-toolbox ud less|more [number in cm]


assistant: ```c
int usage(void) {
  printf("./pri-toolbox ud less|more [number in cm]\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: ./pri-toolbox ud less|more [number in cm]


assistant: ```c
int usage(void) {
  printf("./pri-toolbox ud less|more [number in cm]\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: ./pri-toolbox ud less|more [number in cm]


assistant: ```c
int usage(void) {
  printf("./pri-toolbox ud less|more [number in cm]\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getSignedNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <pow@plt>
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L0
  mov    -0x8(%rbp),%rax
  not    %rax
  or     -0x18(%rbp),%rax
  jmp    L15
L0:
  mov    -0x18(%rbp),%rax
  and    -0x8(%rbp),%rax
L15:
  leave
  ret
```

assistant: ```c
long getSignedNumber(long number, long bitlength) {
  long mask;
  mask = (long)pow(2, bitlength) - 1;
  if (number & (1 << (bitlength - 1))) {
    return (number | (~mask));
  } else {
    return (number & mask);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<getSignedNumber>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x2,%edi
  call   <pow@plt>
  lea    -0x1(%rbp),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  movslq %edx,%rdx
  test   %rbx,%rdx
  je     L9
  neg    %rax
  or     %rbx,%rax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  sub    $0x1,%rax
  and    %rbx,%rax
  jmp    L7
```

assistant: ```c
long getSignedNumber(long number, long bitlength) {
  long mask;
  mask = (long)pow(2, bitlength) - 1;
  if (number & (1 << (bitlength - 1))) {
    return (number | (~mask));
  } else {
    return (number & mask);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getSignedNumber>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  sub    $0x8,%rsp
  call   <pow@plt>
  lea    -0x1(%rbp),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  movslq %edx,%rdx
  test   %rbx,%rdx
  je     L2
  add    $0x8,%rsp
  neg    %rax
  or     %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  add    $0x8,%rsp
  sub    $0x1,%rax
  and    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long getSignedNumber(long number, long bitlength) {
  long mask;
  mask = (long)pow(2, bitlength) - 1;
  if (number & (1 << (bitlength - 1))) {
    return (number | (~mask));
  } else {
    return (number & mask);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getSignedNumber>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  sub    $0x8,%rsp
  call   <pow@plt>
  lea    -0x1(%rbp),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  movslq %edx,%rdx
  test   %rbx,%rdx
  je     L1
  add    $0x8,%rsp
  neg    %rax
  or     %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  add    $0x8,%rsp
  sub    $0x1,%rax
  and    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long getSignedNumber(long number, long bitlength) {
  long mask;
  mask = (long)pow(2, bitlength) - 1;
  if (number & (1 << (bitlength - 1))) {
    return (number | (~mask));
  } else {
    return (number & mask);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
L60:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L88
  mov    %rbx,%rax
  sub    -0x10(%rbp),%rax
  jmp    L65
L88:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L68
  mov    %rbx,%rax
  sub    -0x10(%rbp),%rax
  jmp    L65
L68:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L31
  mov    %rbx,%rax
  sub    -0x10(%rbp),%rax
  jmp    L65
L31:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L3
  mov    %rbx,%rax
  sub    -0x10(%rbp),%rax
  jmp    L65
L3:
  add    $0x1,%rbx
  jmp    L60
L65:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int str_len(char *s) {
  register char *t;
  t = s;
  for (;;) {
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str_len>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L20
L36:
  cmpb   $0x0,0x1(%rax)
  je     L17
  cmpb   $0x0,0x2(%rax)
  je     L42
  cmpb   $0x0,0x3(%rax)
  je     L21
  add    $0x4,%rax
  cmpb   $0x0,(%rax)
  jne    L36
L20:
  sub    %edi,%eax
  ret
L17:
  add    $0x1,%rax
  sub    %edi,%eax
  ret
L42:
  add    $0x2,%rax
  sub    %edi,%eax
  ret
L21:
  add    $0x3,%rax
  sub    %edi,%eax
  ret
```

assistant: ```c
unsigned int str_len(char *s) {
  register char *t;
  t = s;
  for (;;) {
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
  }
}
```