ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <welcome_user@plt>
  mov    $0x0,%eax
  call   <initialize_locs@plt>
L3:
  mov    $0x0,%eax
  call   <inform_user@plt>
  mov    $0x0,%eax
  call   <accept_input@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <handle_input@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <move_ogre@plt>
  test   %ebp,%ebp
  je     L3
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char *input;
  int i = 0;
  welcome_user();
  initialize_locs();
  while (i == 0) {
    inform_user();
    input = accept_input();
    i = handle_input(input);
    free(input);
    move_ogre();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <welcome_user@plt>
  xor    %eax,%eax
  call   <initialize_locs@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <inform_user@plt>
  xor    %eax,%eax
  call   <accept_input@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <handle_input@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  xor    %eax,%eax
  call   <move_ogre@plt>
  test   %ebx,%ebx
  je     L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char *input;
  int i = 0;
  welcome_user();
  initialize_locs();
  while (i == 0) {
    inform_user();
    input = accept_input();
    i = handle_input(input);
    free(input);
    move_ogre();
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <welcome_user@plt>
  xor    %eax,%eax
  call   <initialize_locs@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <inform_user@plt>
  xor    %eax,%eax
  call   <accept_input@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <handle_input@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  xor    %eax,%eax
  call   <move_ogre@plt>
  test   %ebx,%ebx
  je     L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char *input;
  int i = 0;
  welcome_user();
  initialize_locs();
  while (i == 0) {
    inform_user();
    input = accept_input();
    i = handle_input(input);
    free(input);
    move_ogre();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L19
L28:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L12
  mov    -0x8(%rbp),%rax
  jmp    L5
L12:
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L28
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
void *memmem(const void *haystack, size_t haystacklen, const void *needle, size_t needlelen) {
  assert(needlelen > 0);
  while (haystacklen >= needlelen) {
    if (memcmp(haystack, needle, needlelen) == 0)
      return (void *)haystack;
    haystack++;
    haystacklen--;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memmem>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%rbp
  test   %rcx,%rcx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %r14,%rbp
  ja     L4
  mov    %r12,%rbx
  add    %r14,%r12
L15:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L2
  add    $0x1,%rbx
  mov    %r12,%rax
  sub    %rbx,%rax
  cmp    %rbp,%rax
  jae    L15
  mov    $0x0,%ebx
L2:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    $0x0,%ebx
  jmp    L2
```

assistant: ```c
void *memmem(const void *haystack, size_t haystacklen, const void *needle, size_t needlelen) {
  assert(needlelen > 0);
  while (haystacklen >= needlelen) {
    if (memcmp(haystack, needle, needlelen) == 0)
      return (void *)haystack;
    haystack++;
    haystacklen--;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memmem>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  setne  %dil
  call   <assert@plt>
  cmp    %r13,%rbx
  ja     L5
  add    %r12,%r13
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L31:
  add    $0x1,%r12
  mov    %r13,%rax
  sub    %r12,%rax
  cmp    %rbx,%rax
  jb     L5
L23:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L31
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memmem(const void *haystack, size_t haystacklen, const void *needle, size_t needlelen) {
  assert(needlelen > 0);
  while (haystacklen >= needlelen) {
    if (memcmp(haystack, needle, needlelen) == 0)
      return (void *)haystack;
    haystack++;
    haystacklen--;
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memmem>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  setne  %dil
  call   <assert@plt>
  cmp    %r13,%rbx
  ja     L27
  add    %r12,%r13
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r12
  mov    %r13,%rax
  sub    %r12,%rax
  cmp    %rbx,%rax
  jb     L27
L9:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L18
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memmem(const void *haystack, size_t haystacklen, const void *needle, size_t needlelen) {
  assert(needlelen > 0);
  while (haystacklen >= needlelen) {
    if (memcmp(haystack, needle, needlelen) == 0)
      return (void *)haystack;
    haystack++;
    haystacklen--;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cson_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cson_value_is_builtin@plt>
  test   %eax,%eax
  jne    L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void cson_free(void *p, char const *descr) {
  if (!cson_value_is_builtin(p)) {
    free(p);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cson_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <cson_value_is_builtin@plt>
  test   %eax,%eax
  je     L12
L10:
  pop    %rbx
  ret
L12:
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L10
```

assistant: ```c
void cson_free(void *p, char const *descr) {
  if (!cson_value_is_builtin(p)) {
    free(p);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cson_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <cson_value_is_builtin@plt>
  test   %eax,%eax
  je     L3
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void cson_free(void *p, char const *descr) {
  if (!cson_value_is_builtin(p)) {
    free(p);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cson_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <cson_value_is_builtin@plt>
  test   %eax,%eax
  je     L8
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void cson_free(void *p, char const *descr) {
  if (!cson_value_is_builtin(p)) {
    free(p);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wip_pwm_validate_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  je     L25
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
L25:
  mov    $0xffffffff,%eax
  jmp    L6
L28:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int wip_pwm_validate_map(volatile uint32_t *ptr) {
  if (((uint32_t *)-1 == ptr) || (NULL == ptr)) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wip_pwm_validate_map>:
  endbr64
  sub    $0x1,%rdi
  cmp    $0xfffffffffffffffd,%rdi
  seta   %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int wip_pwm_validate_map(volatile uint32_t *ptr) {
  if (((uint32_t *)-1 == ptr) || (NULL == ptr)) {
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wip_pwm_validate_map>:
  endbr64
  sub    $0x1,%rdi
  xor    %eax,%eax
  cmp    $0xfffffffffffffffd,%rdi
  seta   %al
  neg    %eax
  ret
```

assistant: ```c
int wip_pwm_validate_map(volatile uint32_t *ptr) {
  if (((uint32_t *)-1 == ptr) || (NULL == ptr)) {
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wip_pwm_validate_map>:
  endbr64
  sub    $0x1,%rdi
  xor    %eax,%eax
  cmp    $0xfffffffffffffffd,%rdi
  seta   %al
  neg    %eax
  ret
```

assistant: ```c
int wip_pwm_validate_map(volatile uint32_t *ptr) {
  if (((uint32_t *)-1 == ptr) || (NULL == ptr)) {
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__reloc_self>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xd4(%rbp)
  mov    %rsi,-0xe0(%rbp)
  mov    %rdx,-0xe8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x2e,-0xc2(%rbp)
  movb   $0x78,-0xc1(%rbp)
  mov    -0xd4(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x3,%rax
  add    %rax,-0xe0(%rbp)
  jmp    L58
L30:
  addq   $0x8,-0xe0(%rbp)
L58:
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L30
  addq   $0x8,-0xe0(%rbp)
  jmp    L51
L83:
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x13,%rax
  ja     L48
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xe0(%rbp),%rdx
  mov    0x8(%rdx),%rdx
  mov    %rdx,-0xb0(%rbp,%rax,8)
L48:
  addq   $0x10,-0xe0(%rbp)
L51:
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L83
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  mov    -0xb0(%rbp,%rax,8),%rax
  mov    %rax,-0xc0(%rbp)
  cmpq   $0x0,-0xc0(%rbp)
  jne    L7
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  mov    -0xb0(%rbp,%rax,8),%rdx
  mov    D48(%rip),%rax
  mov    (%rax),%rax
  mov    -0xb0(%rbp,%rax,8),%rax
  neg    %rax
  and    %rdx,%rax
  mov    %rax,-0xc0(%rbp)
L7:
  mov    -0xe8(%rbp),%rax
  mov    %rax,-0xe0(%rbp)
  jmp    L33
L98:
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x13,%rax
  ja     L11
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xe0(%rbp),%rdx
  mov    0x8(%rdx),%rdx
  mov    %rdx,-0xb0(%rbp,%rax,8)
L11:
  addq   $0x10,-0xe0(%rbp)
L33:
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L98
  mov    D31(%rip),%rax
  mov    (%rax),%rax
  mov    -0xb0(%rbp,%rax,8),%rax
  mov    %rax,-0xb8(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  mov    -0xb0(%rbp,%rax,8),%rdx
  mov    -0xc0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0xe0(%rbp)
  jmp    L114
L69:
  mov    -0xe0(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl %al,%edx
  mov    D56(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L61
  mov    -0xe0(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0xc0(%rbp),%rdx
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0xc0(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
L61:
  addq   $0x18,-0xe0(%rbp)
  subq   $0xc,-0xb8(%rbp)
L114:
  cmpq   $0x0,-0xb8(%rbp)
  jne    L69
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
void __reloc_self(int c, size_t *a, size_t *dynv) {
  char dot = '.', ex = 'x';
  char *base;
  size_t t[20], n;
  for (a += c + 1; *a; a++)
    ;
  for (a++; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  base = (char *)t[AT_BASE];
  if (!base)
    base = (char *)(t[AT_PHDR] & -t[AT_PAGESZ]);
  for (a = dynv; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  n = t[DT_RELASZ];
  for (a = (void *)(base + t[DT_RELA]); n; a += 3, n -= 12)
    if (a[1] % 256 == R_MICROBLAZE_REL)
      *(size_t *)(base + a[0]) = (size_t)base + a[2];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__reloc_self>:
  endbr64
  sub    $0xb8,%rsp
  mov    %rdx,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0xa8(%rsp)
  xor    %edx,%edx
  movslq %edi,%rdi
  lea    0x8(%rsi,%rdi,8),%rdx
  cmpq   $0x0,(%rdx)
  je     L147
L18:
  add    $0x8,%rdx
  cmpq   $0x0,(%rdx)
  jne    L18
L147:
  lea    0x8(%rdx),%rcx
  mov    0x8(%rdx),%rdx
  test   %rdx,%rdx
  jne    L2
L45:
  mov    D4(%rip),%rdx
  mov    (%rdx),%rdx
  mov    (%rsp,%rdx,8),%rdi
  test   %rdi,%rdi
  jne    L49
  mov    D46(%rip),%rdx
  mov    (%rdx),%rdx
  mov    (%rsp,%rdx,8),%rdi
  neg    %rdi
  mov    D16(%rip),%rdx
  mov    (%rdx),%rdx
  and    (%rsp,%rdx,8),%rdi
L49:
  mov    %rdi,%r9
  mov    (%rax),%rdx
  test   %rdx,%rdx
  jne    L54
L120:
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  mov    %r9,%rsi
  add    (%rsp,%rax,8),%rsi
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L27
  mov    D6(%rip),%rsi
  jmp    L74
L123:
  add    $0x10,%rcx
  mov    (%rcx),%rdx
  test   %rdx,%rdx
  je     L45
L2:
  cmp    $0x13,%rdx
  ja     L123
  mov    0x8(%rcx),%rsi
  mov    %rsi,(%rsp,%rdx,8)
  jmp    L123
L47:
  add    $0x10,%rax
  mov    (%rax),%rdx
  test   %rdx,%rdx
  je     L120
L54:
  cmp    $0x13,%rdx
  ja     L47
  mov    0x8(%rax),%rcx
  mov    %rcx,(%rsp,%rdx,8)
  jmp    L47
L124:
  add    $0x18,%rax
  sub    $0xc,%rdx
  je     L27
L74:
  movzbl 0x8(%rax),%ecx
  cmp    (%rsi),%rcx
  jne    L124
  mov    (%rax),%rcx
  mov    %rdi,%r8
  add    0x10(%rax),%r8
  mov    %r8,(%r9,%rcx,1)
  jmp    L124
L27:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xb8,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __reloc_self(int c, size_t *a, size_t *dynv) {
  char dot = '.', ex = 'x';
  char *base;
  size_t t[20], n;
  for (a += c + 1; *a; a++)
    ;
  for (a++; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  base = (char *)t[AT_BASE];
  if (!base)
    base = (char *)(t[AT_PHDR] & -t[AT_PAGESZ]);
  for (a = dynv; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  n = t[DT_RELASZ];
  for (a = (void *)(base + t[DT_RELA]); n; a += 3, n -= 12)
    if (a[1] % 256 == R_MICROBLAZE_REL)
      *(size_t *)(base + a[0]) = (size_t)base + a[2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<__reloc_self>:
  endbr64
  sub    $0xb8,%rsp
  movslq %edi,%rdi
  mov    %rdx,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0xa8(%rsp)
  xor    %edx,%edx
  lea    0x8(%rsi,%rdi,8),%rdx
  cmpq   $0x0,(%rdx)
  je     L101
  nop
L52:
  add    $0x8,%rdx
  cmpq   $0x0,(%rdx)
  jne    L52
L101:
  lea    0x8(%rdx),%rcx
  mov    0x8(%rdx),%rdx
  test   %rdx,%rdx
  je     L40
  nopw   0x0(%rax,%rax,1)
L22:
  cmp    $0x13,%rdx
  ja     L11
  mov    0x8(%rcx),%rsi
  mov    %rsi,(%rsp,%rdx,8)
L11:
  mov    0x10(%rcx),%rdx
  add    $0x10,%rcx
  test   %rdx,%rdx
  jne    L22
L40:
  mov    D14(%rip),%rdx
  mov    (%rdx),%rdx
  mov    (%rsp,%rdx,8),%rsi
  test   %rsi,%rsi
  jne    L109
  mov    D12(%rip),%rdx
  mov    (%rdx),%rdx
  mov    (%rsp,%rdx,8),%rsi
  mov    D6(%rip),%rdx
  mov    (%rdx),%rdx
  neg    %rsi
  and    (%rsp,%rdx,8),%rsi
  jmp    L109
  nop
L55:
  cmp    $0x13,%rdx
  ja     L99
  mov    0x8(%rax),%rcx
  mov    %rcx,(%rsp,%rdx,8)
L99:
  add    $0x10,%rax
L109:
  mov    (%rax),%rdx
  test   %rdx,%rdx
  jne    L55
  mov    D20(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdx
  mov    D41(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdi
  add    %rsi,%rdi
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L119
  mov    D23(%rip),%rdi
  nopl   0x0(%rax,%rax,1)
L88:
  movzbl 0x8(%rax),%ecx
  cmp    (%rdi),%rcx
  jne    L76
  mov    0x10(%rax),%r8
  mov    (%rax),%rcx
  add    %rsi,%r8
  mov    %r8,(%rsi,%rcx,1)
L76:
  add    $0x18,%rax
  sub    $0xc,%rdx
  jne    L88
L119:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0xb8,%rsp
  ret
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __reloc_self(int c, size_t *a, size_t *dynv) {
  char dot = '.', ex = 'x';
  char *base;
  size_t t[20], n;
  for (a += c + 1; *a; a++)
    ;
  for (a++; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  base = (char *)t[AT_BASE];
  if (!base)
    base = (char *)(t[AT_PHDR] & -t[AT_PAGESZ]);
  for (a = dynv; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  n = t[DT_RELASZ];
  for (a = (void *)(base + t[DT_RELA]); n; a += 3, n -= 12)
    if (a[1] % 256 == R_MICROBLAZE_REL)
      *(size_t *)(base + a[0]) = (size_t)base + a[2];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__reloc_self>:
  endbr64
  sub    $0xb8,%rsp
  movslq %edi,%rdi
  mov    %rdx,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0xa8(%rsp)
  xor    %edx,%edx
  lea    0x8(%rsi,%rdi,8),%rdx
  cmpq   $0x0,(%rdx)
  je     L75
  nop
L66:
  add    $0x8,%rdx
  cmpq   $0x0,(%rdx)
  jne    L66
L75:
  lea    0x8(%rdx),%rcx
  mov    0x8(%rdx),%rdx
  test   %rdx,%rdx
  je     L21
  nopw   0x0(%rax,%rax,1)
L27:
  cmp    $0x13,%rdx
  ja     L146
  mov    0x8(%rcx),%rsi
  add    $0x10,%rcx
  mov    %rsi,(%rsp,%rdx,8)
  mov    (%rcx),%rdx
  test   %rdx,%rdx
  jne    L27
L21:
  mov    D34(%rip),%rdx
  mov    (%rdx),%rdx
  mov    (%rsp,%rdx,8),%rsi
  test   %rsi,%rsi
  jne    L36
  mov    D59(%rip),%rdx
  mov    (%rdx),%rdx
  mov    (%rsp,%rdx,8),%rsi
  mov    D39(%rip),%rdx
  mov    (%rdx),%rdx
  neg    %rsi
  and    (%rsp,%rdx,8),%rsi
L36:
  mov    (%rax),%rdx
  test   %rdx,%rdx
  je     L88
L4:
  cmp    $0x13,%rdx
  ja     L41
  mov    0x8(%rax),%rcx
  add    $0x10,%rax
  mov    %rcx,(%rsp,%rdx,8)
  mov    (%rax),%rdx
  test   %rdx,%rdx
  jne    L4
L88:
  mov    D58(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdx
  mov    D49(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdi
  add    %rsi,%rdi
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L96
  mov    D15(%rip),%rdi
  nopl   0x0(%rax)
L63:
  movzbl 0x8(%rax),%ecx
  cmp    (%rdi),%rcx
  jne    L141
  mov    0x10(%rax),%r8
  mov    (%rax),%rcx
  add    %rsi,%r8
  mov    %r8,(%rsi,%rcx,1)
L141:
  add    $0x18,%rax
  sub    $0xc,%rdx
  jne    L63
L96:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L115
  add    $0xb8,%rsp
  ret
  nopl   0x0(%rax)
L146:
  mov    0x10(%rcx),%rdx
  add    $0x10,%rcx
  test   %rdx,%rdx
  jne    L27
  jmp    L21
  xchg   %ax,%ax
L41:
  add    $0x10,%rax
  jmp    L36
L115:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __reloc_self(int c, size_t *a, size_t *dynv) {
  char dot = '.', ex = 'x';
  char *base;
  size_t t[20], n;
  for (a += c + 1; *a; a++)
    ;
  for (a++; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  base = (char *)t[AT_BASE];
  if (!base)
    base = (char *)(t[AT_PHDR] & -t[AT_PAGESZ]);
  for (a = dynv; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  n = t[DT_RELASZ];
  for (a = (void *)(base + t[DT_RELA]); n; a += 3, n -= 12)
    if (a[1] % 256 == R_MICROBLAZE_REL)
      *(size_t *)(base + a[0]) = (size_t)base + a[2];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int v[], int i, int j) {
  int temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int v[], int i, int j) {
  int temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int v[], int i, int j) {
  int temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int v[], int i, int j) {
  int temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L30
L63:
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L14
L9:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
L34:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L34
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L9
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L73
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L63
L73:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string
name: unpack_data
arguments: tag: D12
type: string

tool: D5: %d


tool: D12: %d

assistant: ```c
int main() {
  int g, n, i, j;
  while (scanf("%d", &n) && n) {
    g = 0;
    for (i = 1; i < n; i++) {
      for (j = i + 1; j <= n; j++) {
        g += gcd(i, j);
      }
    }
    printf("%d\n", g);
  }
  return 0;
}
```