user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D75(%rip),%rdi
  lea    D95(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D122(%rip),%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D168(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x20(%rsp),%xmm2
  movss  0x1c(%rsp),%xmm0
  lea    D51(%rip),%rdi
  movss  0x24(%rsp),%xmm4
  movss  D78(%rip),%xmm3
  mov    $0x1,%eax
  movaps %xmm2,%xmm1
  addss  %xmm2,%xmm1
  movaps %xmm4,%xmm5
  mulss  %xmm3,%xmm5
  addss  %xmm0,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm4,%xmm0
  addss  %xmm5,%xmm1
  divss  %xmm3,%xmm0
  addss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  divss  D87(%rip),%xmm1
  movss  %xmm1,0xc(%rsp)
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  comiss D28(%rip),%xmm1
  jae    L8
  comiss D26(%rip),%xmm1
  jae    L44
  comiss D77(%rip),%xmm1
  jae    L64
  comiss D151(%rip),%xmm1
  jb     L67
  lea    D83(%rip),%rdi
  call   <puts@plt>
  jmp    L65
L44:
  lea    D165(%rip),%rdi
  call   <puts@plt>
L65:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x30,%rsp
  pop    %rbp
  ret
L8:
  lea    D82(%rip),%rdi
  call   <puts@plt>
  jmp    L65
L67:
  lea    D103(%rip),%rdi
  call   <puts@plt>
  jmp    L65
L64:
  lea    D55(%rip),%rdi
  call   <puts@plt>
  jmp    L65
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D75
type_infered: string
name: retrieve_data
arguments: label: D95
type_infered: string
name: retrieve_data
arguments: label: D122
type_infered: string
name: retrieve_data
arguments: label: D43
type_infered: string
name: retrieve_data
arguments: label: D168
type_infered: string
name: retrieve_data
arguments: label: D51
type_infered: string
name: retrieve_data
arguments: label: D78
type_infered: f32
name: retrieve_data
arguments: label: D87
type_infered: f32
name: retrieve_data
arguments: label: D28
type_infered: byte[4]
name: retrieve_data
arguments: label: D26
type_infered: f32
name: retrieve_data
arguments: label: D77
type_infered: byte[4]
name: retrieve_data
arguments: label: D151
type_infered: byte[4]
name: retrieve_data
arguments: label: D83
type_infered: string
name: retrieve_data
arguments: label: D165
type_infered: string
name: retrieve_data
arguments: label: D82
type_infered: string
name: retrieve_data
arguments: label: D103
type_infered: string
name: retrieve_data
arguments: label: D55
type_infered: string

tool: D75: Digite a primeira nota: 

tool: D95:  %f

tool: D122: %f

tool: D43: Digite a segunda nota: 

tool: D168: Digite a terceira nota: 

tool: D51: 
Media de aproveitamento: %.2f.


tool: D78: 3

tool: D87: 7

tool: {"D28": [0x00,0x00,0x10,0x41]}

tool: D26: 7.5

tool: {"D77": [0x00,0x00,0xc0,0x40]}

tool: {"D151": [0x00,0x00,0x80,0x40]}

tool: D83: Conceito D.

tool: D165: Conceito B.

tool: D82: Conceito A.

tool: D103: Conceito E.

tool: D55: Conceito C.

assistant: ```c
void main() {
  float n1, n2, n3, me, ma;
  printf("Digite a primeira nota: ");
  scanf("%f", &n1);
  printf("Digite a segunda nota: ");
  scanf(" %f", &n2);
  printf("Digite a terceira nota: ");
  scanf(" %f", &n3);
  me = (n1 + n2 + n3) / 3.0;
  ma = (n1 + 2 * n2 + 3 * n3 + me) / 7.0;
  printf("\nMedia de aproveitamento: %.2f.\n", ma);
  if (ma >= 9)
    printf("Conceito A.\n");
  else if (ma >= 7.5)
    printf("Conceito B.\n");
  else if (ma >= 6)
    printf("Conceito C.\n");
  else if (ma >= 4)
    printf("Conceito D.\n");
  else
    printf("Conceito E.\n");
}
```