ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <malloc@plt>
  lea    D8(%rip),%rdi
  movb   $0x11,-0x1(%rax)
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: 17


assistant: ```c
int main(void) {
  char *aa = malloc(8);
  aa[-1] = 17;
  if (aa[-1] == 17)
    printf("17\n");
  else
    printf("not 17\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <malloc@plt>
  lea    D0(%rip),%rdi
  movb   $0x11,-0x1(%rax)
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0: 17


assistant: ```c
int main(void) {
  char *aa = malloc(8);
  aa[-1] = 17;
  if (aa[-1] == 17)
    printf("17\n");
  else
    printf("not 17\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L16
L18:
  addq   $0x8,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <printfile@plt>
L16:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L18
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  while (--argc > 0) {
    printfile(*++argv);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
L10:
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  call   <printfile@plt>
  cmp    %rbp,%rbx
  jne    L10
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  while (--argc > 0) {
    printfile(*++argv);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L14
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  call   <printfile@plt>
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  while (--argc > 0) {
    printfile(*++argv);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L4
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  call   <printfile@plt>
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  while (--argc > 0) {
    printfile(*++argv);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_luminous_intensity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D8(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    D15(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: byte[8]
name: parse_data
arguments: tag: D15
datatype: f64

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0xc0]}

tool: D15: 10

assistant: ```c
double get_luminous_intensity(double magnitude) {
  double exp = magnitude / (-2.5);
  return pow(10.0, exp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_luminous_intensity>:
  endbr64
  sub    $0x8,%rsp
  movapd %xmm0,%xmm1
  divsd  D1(%rip),%xmm1
  movsd  D5(%rip),%xmm0
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: byte[8]
name: parse_data
arguments: data_tag: D5
type_infered: f64

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0xc0]}

tool: D5: 10

assistant: ```c
double get_luminous_intensity(double magnitude) {
  double exp = magnitude / (-2.5);
  return pow(10.0, exp);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_luminous_intensity>:
  endbr64
  movapd %xmm0,%xmm1
  movsd  D16(%rip),%xmm0
  divsd  D4(%rip),%xmm1
  jmp    1050 <pow@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D4
data_type: byte[8]

tool: D16: 10

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0xc0]}

assistant: ```c
double get_luminous_intensity(double magnitude) {
  double exp = magnitude / (-2.5);
  return pow(10.0, exp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_luminous_intensity>:
  endbr64
  movapd %xmm0,%xmm1
  movsd  D7(%rip),%xmm0
  divsd  D12(%rip),%xmm1
  jmp    1050 <pow@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: f64
name: parse_data
arguments: tag: D12
type_guessed: byte[8]

tool: D7: 10

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0xc0]}

assistant: ```c
double get_luminous_intensity(double magnitude) {
  double exp = magnitude / (-2.5);
  return pow(10.0, exp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_GeoIP_lookupaddress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <inet_addr@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x2c(%rbp)
  cmpq   $0xffffffffffffffff,-0x20(%rbp)
  jne    L38
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L2
  cmpl   $0x0,-0x2c(%rbp)
  je     L0
L2:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L7
L0:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
L38:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ntohl@plt>
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
unsigned long _GeoIP_lookupaddress(const char *host) {
  unsigned long addr = inet_addr(host);
  struct hostent phe2;
  struct hostent *phe = &phe2;
  char *buf = NULL;
  int result = 0;
  if (addr == -1) {
    phe = gethostbyname(host);
    if (!phe || result != 0) {
      free(buf);
      return 0;
    }
    addr = *((in_addr_t *)phe->h_addr_list[0]);
  }
  return ntohl(addr);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_GeoIP_lookupaddress>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <inet_addr@plt>
  mov    %rax,%rdi
  cmp    $0xffffffffffffffff,%rax
  je     L34
L21:
  call   <ntohl@plt>
L15:
  pop    %rbx
  ret
L34:
  mov    %rbx,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L12
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rdi
  jmp    L21
L12:
  mov    $0x0,%edi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L15
```

assistant: ```c
unsigned long _GeoIP_lookupaddress(const char *host) {
  unsigned long addr = inet_addr(host);
  struct hostent phe2;
  struct hostent *phe = &phe2;
  char *buf = NULL;
  int result = 0;
  if (addr == -1) {
    phe = gethostbyname(host);
    if (!phe || result != 0) {
      free(buf);
      return 0;
    }
    addr = *((in_addr_t *)phe->h_addr_list[0]);
  }
  return ntohl(addr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_GeoIP_lookupaddress>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <inet_addr@plt>
  mov    %rax,%rdi
  cmp    $0xffffffffffffffff,%rax
  je     L1
  pop    %rbp
  jmp    10b0 <ntohl@plt>
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L16
  mov    (%rax),%rax
  pop    %rbp
  mov    (%rax),%rax
  mov    (%rax),%rdi
  jmp    10b0 <ntohl@plt>
  nopl   0x0(%rax)
L16:
  xor    %edi,%edi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long _GeoIP_lookupaddress(const char *host) {
  unsigned long addr = inet_addr(host);
  struct hostent phe2;
  struct hostent *phe = &phe2;
  char *buf = NULL;
  int result = 0;
  if (addr == -1) {
    phe = gethostbyname(host);
    if (!phe || result != 0) {
      free(buf);
      return 0;
    }
    addr = *((in_addr_t *)phe->h_addr_list[0]);
  }
  return ntohl(addr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_GeoIP_lookupaddress>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <inet_addr@plt>
  mov    %rax,%rdi
  cmp    $0xffffffffffffffff,%rax
  je     L5
  pop    %rbp
  jmp    10b0 <ntohl@plt>
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L16
  mov    (%rax),%rax
  pop    %rbp
  mov    (%rax),%rax
  mov    (%rax),%rdi
  jmp    10b0 <ntohl@plt>
  nopl   0x0(%rax)
L16:
  xor    %edi,%edi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long _GeoIP_lookupaddress(const char *host) {
  unsigned long addr = inet_addr(host);
  struct hostent phe2;
  struct hostent *phe = &phe2;
  char *buf = NULL;
  int result = 0;
  if (addr == -1) {
    phe = gethostbyname(host);
    if (!phe || result != 0) {
      free(buf);
      return 0;
    }
    addr = *((in_addr_t *)phe->h_addr_list[0]);
  }
  return ntohl(addr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dest, char const *src) {
  char *x;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcpy>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strcpy(char *dest, char const *src) {
  char *x;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strcpy(char *dest, char const *src) {
  char *x;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcpy>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strcpy(char *dest, char const *src) {
  char *x;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x37362e3534333231,%rax
  mov    %rax,-0x11(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x24(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D7
type: string

tool: D10: i is %d


tool: D7: l is %d


assistant: ```c
int main() {
  char ch[] = "12345.67";
  int i = atoi(ch);
  long l = atol(ch);
  printf("i is %d\n", i);
  printf("l is %d\n", l);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x37362e3534333231,%rax
  mov    %rax,0xf(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0xf(%rsp),%rbp
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <atol@plt>
  mov    %rax,%rbp
  movslq %ebx,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
datatype: string
name: disassemble_data
arguments: label: D14
datatype: string

tool: D10: i is %d


tool: D14: l is %d


assistant: ```c
int main() {
  char ch[] = "12345.67";
  int i = atoi(ch);
  long l = atol(ch);
  printf("i is %d\n", i);
  printf("l is %d\n", l);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x37362e3534333231,%rax
  lea    0xf(%rsp),%rbp
  movb   $0x0,0x17(%rsp)
  mov    %rbp,%rdi
  mov    %rax,0xf(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <atol@plt>
  movslq %ebx,%rsi
  lea    D0(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D19
type: string

tool: D0: i is %d


tool: D19: l is %d


assistant: ```c
int main() {
  char ch[] = "12345.67";
  int i = atoi(ch);
  long l = atol(ch);
  printf("i is %d\n", i);
  printf("l is %d\n", l);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x37362e3534333231,%rax
  lea    0xf(%rsp),%rbp
  movb   $0x0,0x17(%rsp)
  mov    %rbp,%rdi
  mov    %rax,0xf(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <atol@plt>
  movslq %ebx,%rsi
  lea    D10(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D3
type: string

tool: D10: i is %d


tool: D3: l is %d


assistant: ```c
int main() {
  char ch[] = "12345.67";
  int i = atoi(ch);
  long l = atol(ch);
  printf("i is %d\n", i);
  printf("l is %d\n", l);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jle    L87
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L87
  mov    $0x1,%eax
  jmp    L33
L87:
  mov    $0x0,%eax
L33:
  mov    %eax,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  jmp    L69
L1:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x2,%eax
  add    %eax,-0x4(%rbp)
L69:
  cmpl   $0x0,-0x8(%rbp)
  je     L31
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L1
L31:
  cmpl   $0x0,-0x8(%rbp)
  jne    L2
  cmpl   $0x2,-0x14(%rbp)
  jne    L12
L2:
  mov    $0x1,%eax
  jmp    L47
L12:
  mov    $0x0,%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(uint32_t s) {
  uint32_t res = !(s <= 2 || (s & 0x1) != 1);
  for (uint32_t i = 3; res && i * i <= s; i += ((res = !(s % i == 0)), 2))
    ;
  return (res || s == 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime>:
  endbr64
  mov    $0x0,%esi
  cmp    $0x2,%edi
  jle    L57
  mov    %edi,%esi
  and    $0x1,%esi
  je     L57
  mov    $0x3,%ecx
  cmp    $0x8,%edi
  jle    L57
L52:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    $0x2,%ecx
  test   %edx,%edx
  je     L50
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L52
  jmp    L57
L50:
  mov    %edx,%esi
L57:
  test   %esi,%esi
  setne  %al
  cmp    $0x2,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_prime(uint32_t s) {
  uint32_t res = !(s <= 2 || (s & 0x1) != 1);
  for (uint32_t i = 3; res && i * i <= s; i += ((res = !(s % i == 0)), 2))
    ;
  return (res || s == 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_prime>:
  endbr64
  cmp    $0x2,%edi
  sete   %r8b
  sete   %sil
  movzbl %r8b,%r8d
  jle    L39
  mov    %edi,%r8d
  and    $0x1,%r8d
  je     L7
  cmp    $0x8,%edi
  jle    L39
  mov    $0x3,%ecx
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    $0x2,%ecx
  test   %edx,%edx
  je     L7
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L25
L39:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L7:
  movzbl %sil,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int is_prime(uint32_t s) {
  uint32_t res = !(s <= 2 || (s & 0x1) != 1);
  for (uint32_t i = 3; res && i * i <= s; i += ((res = !(s % i == 0)), 2))
    ;
  return (res || s == 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_prime>:
  endbr64
  cmp    $0x2,%edi
  sete   %r8b
  sete   %sil
  movzbl %r8b,%r8d
  jle    L2
  mov    %edi,%r8d
  and    $0x1,%r8d
  je     L10
  cmp    $0x8,%edi
  jle    L2
  mov    $0x3,%ecx
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    $0x2,%ecx
  test   %edx,%edx
  je     L10
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L21
L2:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L10:
  movzbl %sil,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int is_prime(uint32_t s) {
  uint32_t res = !(s <= 2 || (s & 0x1) != 1);
  for (uint32_t i = 3; res && i * i <= s; i += ((res = !(s % i == 0)), 2))
    ;
  return (res || s == 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lrand48_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0xffffffff,%eax
  jmp    L16
L9:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <nrand48_r@plt>
L16:
  leave
  ret
```

assistant: ```c
int lrand48_r(struct drand48_data *buffer, long int *result) {
  if (buffer == NULL)
    return -1;
  return nrand48_r(buffer->__x, buffer, result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lrand48_r>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  mov    (%rdi),%edi
  call   <nrand48_r@plt>
  add    $0x8,%rsp
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lrand48_r(struct drand48_data *buffer, long int *result) {
  if (buffer == NULL)
    return -1;
  return nrand48_r(buffer->__x, buffer, result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lrand48_r>:
  endbr64
  mov    %rsi,%rdx
  test   %rdi,%rdi
  je     L8
  mov    %rdi,%rsi
  mov    (%rdi),%edi
  jmp    1050 <nrand48_r@plt>
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lrand48_r(struct drand48_data *buffer, long int *result) {
  if (buffer == NULL)
    return -1;
  return nrand48_r(buffer->__x, buffer, result);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lrand48_r>:
  endbr64
  mov    %rsi,%rdx
  test   %rdi,%rdi
  je     L2
  mov    %rdi,%rsi
  mov    (%rdi),%edi
  jmp    1050 <nrand48_r@plt>
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lrand48_r(struct drand48_data *buffer, long int *result) {
  if (buffer == NULL)
    return -1;
  return nrand48_r(buffer->__x, buffer, result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3:   Error: %s


assistant: ```c
void error(const char *s) {
  printf("\n");
  printf("  Error: %s\n", s);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D9:   Error: %s


assistant: ```c
void error(const char *s) {
  printf("\n");
  printf("  Error: %s\n", s);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0:   Error: %s


assistant: ```c
void error(const char *s) {
  printf("\n");
  printf("  Error: %s\n", s);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4:   Error: %s


assistant: ```c
void error(const char *s) {
  printf("\n");
  printf("  Error: %s\n", s);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<writing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  movd   %edx,%xmm0
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: %f

assistant: ```c
int writing(FILE *f, float sredn) {
  fprintf(f, "%f", sredn);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writing>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <fprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: %f

assistant: ```c
int writing(FILE *f, float sredn) {
  fprintf(f, "%f", sredn);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<writing>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  call   <fprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: %f

assistant: ```c
int writing(FILE *f, float sredn) {
  fprintf(f, "%f", sredn);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writing>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <fprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: %f

assistant: ```c
int writing(FILE *f, float sredn) {
  fprintf(f, "%f", sredn);
  return 0;
}
```