user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  mov    $0x41,%esi
  lea    D100(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0x1a0(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0xf,0x8(%rsp)
  movl   $0x18,0xc(%rsp)
  lea    D25(%rip),%r12
  lea    D1(%rip),%rbp
  lea    D48(%rip),%r13
L12:
  lea    0x8(%rsp),%rbx
L63:
  cmpl   $0x9,0x8(%rsp)
  jle    L45
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x9,0x8(%rsp)
  jle    L63
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L12
L45:
  lea    D15(%rip),%r12
  lea    D1(%rip),%rbp
  lea    D48(%rip),%r13
L43:
  lea    0xc(%rsp),%rbx
L77:
  mov    0xc(%rsp),%edx
  cmp    $0x9,%edx
  jle    L16
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x9,0xc(%rsp)
  jle    L77
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L43
L16:
  lea    0x10(%rsp),%rdi
  mov    $0x32,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  movslq %edx,%rdx
  movslq 0x8(%rsp),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rdx,%rax,2),%rax
  movl   $0x1,0x10(%rsp,%rax,4)
  lea    0x38(%rsp),%rbp
  lea    0x1c8(%rsp),%r13
  lea    D1(%rip),%r12
L74:
  lea    -0x28(%rbp),%rbx
L34:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L34
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rbp
  cmp    %r13,%rbp
  jne    L74
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    $0x0,%eax
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D100
type_guessed: string
name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D48
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string

tool: D100: %c


tool: D7: Write a name:

tool: D8: %s

tool: D27: Hello %s


tool: D25: Chose a row 

tool: D1: %i

tool: D48: You can not chose more than 10

tool: D15: Chose a col

assistant: ```c
int main() {
  char letter = 'A';
  printf("%c\n", letter);
  char str[20];
  printf("Write a name:\n");
  scanf("%s", str);
  printf("Hello %s\n", str);
  int number = 15, number2 = 24;
  while (number >= 10) {
    printf("Chose a row ");
    scanf("%i", &number);
    if (number >= 10) {
      printf("You can not chose more than 10\n");
    }
  }
  while (number2 >= 10) {
    printf("Chose a col");
    scanf("%i", &number2);
    if (number2 >= 10) {
      printf("You can not chose more than 10\n");
    }
  }
  int matrix[10][10] = {0};
  matrix[number][number2] = 1;
  for (int row = 0; row < 10; row++) {
    for (int col = 0; col < 10; col++) {
      printf("%i", matrix[row][col]);
    }
    printf("\n");
  }
  return 0;
}
```