user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D16(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x6(%rsp),%rbp
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  sub    %eax,%r13d
  js     L21
  movzbl 0x6(%rsp),%r14d
  mov    %rbx,%rdx
  mov    $0x3,%esi
  xor    %ecx,%ecx
  movzbl 0x7(%rsp),%r15d
  mov    $0x4,%edi
  mov    $0x5,%r8d
  mov    $0x6,%r9d
  mov    $0x7,%r10d
  mov    $0x8,%ebx
  mov    $0x9,%r12d
  nopl   0x0(%rax,%rax,1)
L156:
  lea    0x1(%rcx),%r11d
  cmp    %eax,%ecx
  jge    L190
  cmp    (%rdx),%r14b
  jne    L190
  cmp    %r11d,%eax
  jle    L66
  cmp    %r15b,0x1(%rdx)
  jne    L190
  lea    0x2(%rcx),%ebp
  cmp    %ebp,%eax
  jle    L66
  movzbl 0x8(%rsp),%ebp
  cmp    %bpl,0x2(%rdx)
  jne    L190
  cmp    %eax,%esi
  jge    L66
  mov    %esi,%ebp
  sub    %ecx,%ebp
  movslq %ebp,%rbp
  movzbl 0x6(%rsp,%rbp,1),%ebp
  cmp    %bpl,0x3(%rdx)
  jne    L190
  cmp    %eax,%edi
  jge    L66
  mov    %edi,%ebp
  sub    %ecx,%ebp
  movslq %ebp,%rbp
  movzbl 0x6(%rsp,%rbp,1),%ebp
  cmp    %bpl,0x4(%rdx)
  jne    L190
  cmp    %eax,%r8d
  jge    L66
  mov    %r8d,%ebp
  sub    %ecx,%ebp
  movslq %ebp,%rbp
  movzbl 0x6(%rsp,%rbp,1),%ebp
  cmp    %bpl,0x5(%rdx)
  jne    L190
  cmp    %eax,%r9d
  jge    L66
  mov    %r9d,%ebp
  sub    %ecx,%ebp
  movslq %ebp,%rbp
  movzbl 0x6(%rsp,%rbp,1),%ebp
  cmp    %bpl,0x6(%rdx)
  jne    L190
  cmp    %eax,%r10d
  jge    L66
  mov    %r10d,%ebp
  sub    %ecx,%ebp
  movslq %ebp,%rbp
  movzbl 0x6(%rsp,%rbp,1),%ebp
  cmp    %bpl,0x7(%rdx)
  jne    L190
  cmp    %eax,%ebx
  jge    L66
  mov    %ebx,%ebp
  sub    %ecx,%ebp
  movslq %ebp,%rbp
  movzbl 0x6(%rsp,%rbp,1),%ebp
  cmp    %bpl,0x8(%rdx)
  jne    L190
  cmp    %eax,%r12d
  jge    L66
  mov    %r12d,%ebp
  sub    %ecx,%ebp
  movslq %ebp,%rcx
  movzbl 0x6(%rsp,%rcx,1),%ecx
  cmp    %cl,0x9(%rdx)
  jne    L190
L66:
  lea    D39(%rip),%rdi
  call   <printf@plt>
L175:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L189
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L190:
  mov    %r11d,%ecx
  add    $0x1,%eax
  add    $0x1,%rdx
  add    $0x1,%r12d
  add    $0x1,%ebx
  add    $0x1,%r10d
  add    $0x1,%r9d
  add    $0x1,%r8d
  add    $0x1,%edi
  add    $0x1,%esi
  cmp    %r13d,%r11d
  jle    L156
L21:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L175
L189:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D39
datatype: string
name: retrieve_data
arguments: data_tag: D10
datatype: string

tool: D16: Enter a string:

tool: D3: Enter search substring:

tool: D39: SEARCH SUCCESSFUL!

tool: D10: SEARCH UNSUCCESSFUL!

assistant: ```c
int main() {
  char str[80], search[10];
  int count1 = 0, count2 = 0, i, j, flag;
  printf("Enter a string:");
  gets(str);
  printf("Enter search substring:");
  gets(search);
  count1 = strlen(str);
  count2 = strlen(search);
  for (i = 0; i <= count1 - count2; i++) {
    for (j = i; j < i + count2; j++) {
      flag = 1;
      if (str[j] != search[j - i]) {
        flag = 0;
        break;
      }
    }
    if (flag == 1)
      break;
  }
  if (flag == 1)
    printf("SEARCH SUCCESSFUL!");
  else
    printf("SEARCH UNSUCCESSFUL!");
  return 0;
}
```