ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x50(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x50(%rbp)
  movzbl -0x30(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x30(%rbp)
  lea    -0x30(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D6
type_guessed: string
name: parse_data
arguments: label: D16
type_guessed: string
name: parse_data
arguments: label: D15
type_guessed: string

tool: D18: Enter Your first name : 

tool: D6: %s

tool: D16: 
Enter Your Last name : 

tool: D15: 
Your name is now fixed and entered to database as : %s %s

assistant: ```c
int main(void) {
  char fname[20], lname[30];
  printf("Enter Your first name : ");
  scanf("%s", fname);
  printf("\nEnter Your Last name : ");
  scanf("%s", lname);
  fname[0] = toupper(fname[0]);
  lname[0] = toupper(lname[0]);
  printf("\nYour name is now fixed and entered to database as : %s %s", fname, lname);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D39(%rip),%r12
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movsbl (%rsp),%edi
  call   <toupper@plt>
  mov    %al,(%rsp)
  movsbl 0x20(%rsp),%edi
  call   <toupper@plt>
  mov    %al,0x20(%rsp)
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D39
type: string
name: extract_symbolic_data
arguments: label: D34
type: string
name: extract_symbolic_data
arguments: label: D11
type: string

tool: D21: Enter Your first name : 

tool: D39: %s

tool: D34: 
Enter Your Last name : 

tool: D11: 
Your name is now fixed and entered to database as : %s %s

assistant: ```c
int main(void) {
  char fname[20], lname[30];
  printf("Enter Your first name : ");
  scanf("%s", fname);
  printf("\nEnter Your Last name : ");
  scanf("%s", lname);
  fname[0] = toupper(fname[0]);
  lname[0] = toupper(lname[0]);
  printf("\nYour name is now fixed and entered to database as : %s %s", fname, lname);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%rdi
  lea    D23(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movsbl (%rsp),%edi
  call   <toupper@plt>
  movsbl 0x20(%rsp),%edi
  mov    %al,(%rsp)
  call   <toupper@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  mov    %al,0x20(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D2: Enter Your first name : 

tool: D23: %s

tool: D22: 
Enter Your Last name : 

tool: D0: 
Your name is now fixed and entered to database as : %s %s

assistant: ```c
int main(void) {
  char fname[20], lname[30];
  printf("Enter Your first name : ");
  scanf("%s", fname);
  printf("\nEnter Your Last name : ");
  scanf("%s", lname);
  fname[0] = toupper(fname[0]);
  lname[0] = toupper(lname[0]);
  printf("\nYour name is now fixed and entered to database as : %s %s", fname, lname);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D36(%rip),%rdi
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movsbl (%rsp),%edi
  call   <toupper@plt>
  movsbl 0x20(%rsp),%edi
  mov    %al,(%rsp)
  call   <toupper@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  mov    %al,0x20(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D27
type: string
name: parse_data
arguments: label: D4
type: string

tool: D36: Enter Your first name : 

tool: D1: %s

tool: D27: 
Enter Your Last name : 

tool: D4: 
Your name is now fixed and entered to database as : %s %s

assistant: ```c
int main(void) {
  char fname[20], lname[30];
  printf("Enter Your first name : ");
  scanf("%s", fname);
  printf("\nEnter Your Last name : ");
  scanf("%s", lname);
  fname[0] = toupper(fname[0]);
  lname[0] = toupper(lname[0]);
  printf("\nYour name is now fixed and entered to database as : %s %s", fname, lname);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stripext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L37
L28:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L4
  mov    -0x10(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L36
L4:
  subq   $0x1,-0x10(%rbp)
L37:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L28
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
char *stripext(char *dst, const char *filename) {
  const char *p = filename + strlen(filename) - 1;
  for (; p > filename; --p) {
    if (*p == '.') {
      size_t size = p - filename;
      memcpy(dst, filename, size - 1);
      dst[size - 1] = 0;
      return dst;
    }
  }
  strcpy(dst, filename);
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stripext>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jae    L14
L7:
  cmpb   $0x2e,(%rax)
  je     L15
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jne    L7
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  sub    %rbp,%rax
  mov    %rax,%rbx
  lea    -0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  jmp    L1
```

assistant: ```c
char *stripext(char *dst, const char *filename) {
  const char *p = filename + strlen(filename) - 1;
  for (; p > filename; --p) {
    if (*p == '.') {
      size_t size = p - filename;
      memcpy(dst, filename, size - 1);
      dst[size - 1] = 0;
      return dst;
    }
  }
  strcpy(dst, filename);
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<stripext>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jb     L7
  jmp    L3
  nopl   0x0(%rax)
L27:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  je     L3
L7:
  cmpb   $0x2e,(%rax)
  jne    L27
  sub    %rbp,%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  lea    -0x1(%rax),%rdx
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stripext(char *dst, const char *filename) {
  const char *p = filename + strlen(filename) - 1;
  for (; p > filename; --p) {
    if (*p == '.') {
      size_t size = p - filename;
      memcpy(dst, filename, size - 1);
      dst[size - 1] = 0;
      return dst;
    }
  }
  strcpy(dst, filename);
  return dst;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stripext>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jb     L4
  jmp    L2
  nopl   0x0(%rax)
L34:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  je     L2
L4:
  cmpb   $0x2e,(%rax)
  jne    L34
  sub    %rbp,%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  lea    -0x1(%rax),%rdx
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stripext(char *dst, const char *filename) {
  const char *p = filename + strlen(filename) - 1;
  for (; p > filename; --p) {
    if (*p == '.') {
      size_t size = p - filename;
      memcpy(dst, filename, size - 1);
      dst[size - 1] = 0;
      return dst;
    }
  }
  strcpy(dst, filename);
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <unitTest@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9: Run unit Test:


assistant: ```c
int main(int argc, char **argv) {
  printf("Run unit Test:\n");
  unitTest();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <unitTest@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: Run unit Test:


assistant: ```c
int main(int argc, char **argv) {
  printf("Run unit Test:\n");
  unitTest();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <unitTest@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: Run unit Test:


assistant: ```c
int main(int argc, char **argv) {
  printf("Run unit Test:\n");
  unitTest();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <unitTest@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: Run unit Test:


assistant: ```c
int main(int argc, char **argv) {
  printf("Run unit Test:\n");
  unitTest();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<image_paths_comparator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int image_paths_comparator(const void *__attribute__((nonnull)) const left, const void *__attribute__((nonnull)) const right) {
  const char *const left_path = *(const char **)left;
  const char *const right_path = *(const char **)right;
  return strcmp(left_path, right_path);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<image_paths_comparator>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int image_paths_comparator(const void *__attribute__((nonnull)) const left, const void *__attribute__((nonnull)) const right) {
  const char *const left_path = *(const char **)left;
  const char *const right_path = *(const char **)right;
  return strcmp(left_path, right_path);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<image_paths_comparator>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int image_paths_comparator(const void *__attribute__((nonnull)) const left, const void *__attribute__((nonnull)) const right) {
  const char *const left_path = *(const char **)left;
  const char *const right_path = *(const char **)right;
  return strcmp(left_path, right_path);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<image_paths_comparator>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int image_paths_comparator(const void *__attribute__((nonnull)) const left, const void *__attribute__((nonnull)) const right) {
  const char *const left_path = *(const char **)left;
  const char *const right_path = *(const char **)right;
  return strcmp(left_path, right_path);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<filename_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L28
L59:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L44
  subq   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L59
  jmp    L41
L44:
  nop
L41:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L0
  mov    -0x20(%rbp),%rax
  jmp    L20
L0:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L20:
  pop    %rbp
  ret
```

assistant: ```c
size_t filename_len(const char *str, size_t len) {
  const char *end;
  end = str + len - 1;
  while (end >= str) {
    if (*end == '.')
      break;
    end--;
  }
  if (str > end)
    return len;
  else
    return end - str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<filename_len>:
  endbr64
  mov    %rsi,%rax
  lea    -0x1(%rdi,%rsi,1),%rdx
  cmp    %rdx,%rdi
  ja     L32
L7:
  cmpb   $0x2e,(%rdx)
  je     L5
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  jbe    L7
  ret
L5:
  cmp    %rdx,%rdi
  ja     L32
  mov    %rdx,%rax
  sub    %rdi,%rax
L32:
  ret
```

assistant: ```c
size_t filename_len(const char *str, size_t len) {
  const char *end;
  end = str + len - 1;
  while (end >= str) {
    if (*end == '.')
      break;
    end--;
  }
  if (str > end)
    return len;
  else
    return end - str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<filename_len>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rdx
  mov    %rsi,%rax
  cmp    %rdx,%rdi
  jbe    L1
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L28:
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  ja     L44
L1:
  cmpb   $0x2e,(%rdx)
  jne    L28
  cmp    %rdx,%rdi
  ja     L40
  mov    %rdx,%rax
  sub    %rdi,%rax
L40:
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  ret
```

assistant: ```c
size_t filename_len(const char *str, size_t len) {
  const char *end;
  end = str + len - 1;
  while (end >= str) {
    if (*end == '.')
      break;
    end--;
  }
  if (str > end)
    return len;
  else
    return end - str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<filename_len>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rdx
  mov    %rsi,%rax
  cmp    %rdx,%rdi
  jbe    L0
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L38:
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  ja     L15
L0:
  cmpb   $0x2e,(%rdx)
  jne    L38
  cmp    %rdx,%rdi
  ja     L41
  mov    %rdx,%rax
  sub    %rdi,%rax
L41:
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
size_t filename_len(const char *str, size_t len) {
  const char *end;
  end = str + len - 1;
  while (end >= str) {
    if (*end == '.')
      break;
    end--;
  }
  if (str > end)
    return len;
  else
    return end - str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<x_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <x_vaprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void x_printf(char *format, ...) {
  va_list ap;
  va_start(ap, format);
  x_vaprintf(format, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<x_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <x_vaprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void x_printf(char *format, ...) {
  va_list ap;
  va_start(ap, format);
  x_vaprintf(format, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below?

```asm
<x_printf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <x_vaprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void x_printf(char *format, ...) {
  va_list ap;
  va_start(ap, format);
  x_vaprintf(format, ap);
  va_end(ap);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<x_printf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <x_vaprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void x_printf(char *format, ...) {
  va_list ap;
  va_start(ap, format);
  x_vaprintf(format, ap);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x1a4(%rbp)
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1a8(%rbp)
  jmp    L39
L34:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1a8(%rbp)
L39:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jl     L34
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1ac(%rbp),%rax
  mov    %rax,%rsi
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1ac(%rbp),%edx
  mov    -0x1b0(%rbp),%ecx
  lea    -0x1a0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <linearSearch@plt>
  mov    %eax,-0x1a4(%rbp)
  cmpl   $0xffffffff,-0x1a4(%rbp)
  je     L48
  mov    -0x1a4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L48:
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L7:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D37
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D82
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D93
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D85
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D89
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D37: cls

tool: D22: Enter array size: 

tool: D82: %d

tool: D93: 
Enter array elements: 

tool: D85: 
Enter element to search: 

tool: D13: 
Element found at postion: %d


tool: D89: 
Element not found.

tool: D6: pause

assistant: ```c
int main() {
  int a[100], i, num, item, loc = -1;
  system("cls");
  printf("Enter array size: ");
  scanf("%d", &num);
  printf("\nEnter array elements: ");
  for (i = 0; i < num; i++)
    scanf("%d", &a[i]);
  printf("\nEnter element to search: ");
  scanf("%d", &item);
  loc = linearSearch(a, num, item);
  if (loc != -1)
    printf("\nElement found at postion: %d\n", loc);
  else
    printf("\nElement not found.\n");
  system("pause");
  return 0;
}
```