ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set_mode_str_from_prefix>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L71:
  cmp    $0x2b,%al
  jne    L11
  mov    $0x76,%edx
L55:
  lea    0x1(%rbp),%eax
  cmp    %r12d,%eax
  jae    L108
  mov    %dl,0x0(%r13,%rbp,1)
  mov    %eax,%ebp
L108:
  add    $0x1,%ebx
L49:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L69
  mov    %ebx,%eax
  movzbl (%r14,%rax,1),%eax
  cmp    $0x40,%al
  je     L90
  jg     L3
  cmp    $0x25,%al
  jne    L71
  mov    $0x68,%edx
  jmp    L55
  nop
L3:
  mov    $0x71,%edx
  cmp    $0x7e,%al
  je     L55
L11:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L108
  nopl   (%rax)
L90:
  mov    $0x6f,%edx
  jmp    L55
  nop
L69:
  pop    %rbx
  movb   $0x0,0x0(%r13,%rbp,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void set_mode_str_from_prefix(char *mode_str, const char *mode_prefix, unsigned int max_out_len) {
  unsigned int out_idx = 0;
  unsigned int idx;
  for (idx = 0; idx < strlen(mode_prefix); idx++) {
    char new_mode = '\0';
    switch (mode_prefix[idx]) {
    case '~':
      new_mode = 'q';
      break;
    case '@':
      new_mode = 'o';
      break;
    case '%':
      new_mode = 'h';
      break;
    case '+':
      new_mode = 'v';
      break;
    default:
      idx = strlen(mode_prefix);
      break;
    }
    if ((new_mode != '\0') && ((out_idx + 1) < max_out_len)) {
      mode_str[out_idx] = new_mode;
      out_idx++;
    }
  }
  mode_str[out_idx] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<float_ge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <f2u@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <f2u@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  test   %eax,%eax
  jne    L56
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  test   %eax,%eax
  je     L55
L56:
  cmpl   $0x0,-0x8(%rbp)
  jne    L79
  cmpl   $0x0,-0x4(%rbp)
  jne    L55
L79:
  cmpl   $0x0,-0x8(%rbp)
  jne    L52
  cmpl   $0x0,-0x4(%rbp)
  jne    L52
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jae    L55
L52:
  cmpl   $0x0,-0x8(%rbp)
  je     L54
  cmpl   $0x0,-0x4(%rbp)
  je     L54
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  ja     L54
L55:
  mov    $0x1,%eax
  jmp    L48
L54:
  mov    $0x0,%eax
L48:
  leave
  ret
```

assistant: ```c
int float_ge(float x, float y) {
  unsigned ux = f2u(x);
  unsigned uy = f2u(y);
  unsigned sx = ux >> 31;
  unsigned sy = uy >> 31;
  return ((ux << 1) == 0 && (uy << 1) == 0) || (!sx && sy) || (!sx && !sy && ux >= uy) || (sx && sy && ux <= uy);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<float_ge>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <f2u@plt>
  mov    %eax,%ebx
  movss  0xc(%rsp),%xmm0
  call   <f2u@plt>
  mov    %ebx,%esi
  shr    $0x1f,%esi
  mov    %eax,%edi
  shr    $0x1f,%edi
  mov    %eax,%ecx
  or     %ebx,%ecx
  mov    $0x1,%edx
  add    %ecx,%ecx
  je     L41
  mov    %edi,%ecx
  test   %esi,%esi
  jne    L33
  test   %dil,%dil
  je     L33
L41:
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L33:
  or     %esi,%edi
  jne    L36
  mov    $0x1,%edx
  cmp    %eax,%ebx
  jae    L41
L36:
  cmp    %eax,%ebx
  setbe  %dl
  and    %ecx,%esi
  and    %esi,%edx
  jmp    L41
```

assistant: ```c
int float_ge(float x, float y) {
  unsigned ux = f2u(x);
  unsigned uy = f2u(y);
  unsigned sx = ux >> 31;
  unsigned sy = uy >> 31;
  return ((ux << 1) == 0 && (uy << 1) == 0) || (!sx && sy) || (!sx && !sy && ux >= uy) || (sx && sy && ux <= uy);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<float_ge>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <f2u@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <f2u@plt>
  mov    %ebx,%ecx
  mov    $0x1,%r8d
  mov    %eax,%edx
  mov    %eax,%esi
  shr    $0x1f,%ecx
  or     %ebx,%edx
  shr    $0x1f,%esi
  add    %edx,%edx
  je     L9
  mov    %ecx,%edx
  xor    $0x1,%edx
  test   %esi,%edx
  je     L29
L9:
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L29:
  mov    %ecx,%edi
  or     %esi,%edi
  jne    L17
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  setae  %r8b
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  cmp    %eax,%ebx
  setbe  %r8b
  and    %esi,%ecx
  add    $0x10,%rsp
  and    %ecx,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int float_ge(float x, float y) {
  unsigned ux = f2u(x);
  unsigned uy = f2u(y);
  unsigned sx = ux >> 31;
  unsigned sy = uy >> 31;
  return ((ux << 1) == 0 && (uy << 1) == 0) || (!sx && sy) || (!sx && !sy && ux >= uy) || (sx && sy && ux <= uy);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<float_ge>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <f2u@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <f2u@plt>
  mov    %ebx,%ecx
  mov    $0x1,%r8d
  mov    %eax,%edx
  mov    %eax,%esi
  shr    $0x1f,%ecx
  or     %ebx,%edx
  shr    $0x1f,%esi
  add    %edx,%edx
  je     L8
  mov    %ecx,%edx
  xor    $0x1,%edx
  test   %esi,%edx
  je     L11
L8:
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L11:
  mov    %ecx,%edi
  or     %esi,%edi
  jne    L25
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  setae  %r8b
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  cmp    %eax,%ebx
  setbe  %r8b
  and    %esi,%ecx
  add    $0x10,%rsp
  and    %ecx,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int float_ge(float x, float y) {
  unsigned ux = f2u(x);
  unsigned uy = f2u(y);
  unsigned sx = ux >> 31;
  unsigned sy = uy >> 31;
  return ((ux << 1) == 0 && (uy << 1) == 0) || (!sx && sy) || (!sx && !sy && ux >= uy) || (sx && sy && ux <= uy);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<con_getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <con_flush@plt>
  lea    -0xc(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L13
  mov    $0xffffffff,%eax
  jmp    L5
L13:
  mov    -0xc(%rbp),%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int con_getch(void) {
  uint8_t c;
  con_flush();
  if (read(0, &c, 1) != 1)
    return -1;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<con_getch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <con_flush@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L21
  mov    0x4(%rsp),%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L21:
  mov    $0xffffffff,%eax
  jmp    L0
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int con_getch(void) {
  uint8_t c;
  con_flush();
  if (read(0, &c, 1) != 1)
    return -1;
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<con_getch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <con_flush@plt>
  xor    %edi,%edi
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L20
  mov    0x4(%rsp),%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L20:
  mov    $0xffffffff,%eax
  jmp    L18
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int con_getch(void) {
  uint8_t c;
  con_flush();
  if (read(0, &c, 1) != 1)
    return -1;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<con_getch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <con_flush@plt>
  xor    %edi,%edi
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L28
  mov    0x4(%rsp),%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L28:
  mov    $0xffffffff,%eax
  jmp    L2
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int con_getch(void) {
  uint8_t c;
  con_flush();
  if (read(0, &c, 1) != 1)
    return -1;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<debuglvl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0xa,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L25
  mov    $0x1,%edi
  call   <setDebugTracerLever@plt>
  jmp    L48
L25:
  mov    -0x10(%rbp),%rax
  add    $0xa,%rax
  movzbl (%rax),%eax
  cmp    $0x32,%al
  jne    L26
  mov    $0x2,%edi
  call   <setDebugTracerLever@plt>
  jmp    L48
L26:
  mov    -0x10(%rbp),%rax
  add    $0xa,%rax
  movzbl (%rax),%eax
  cmp    $0x33,%al
  jne    L48
  mov    $0x3,%edi
  call   <setDebugTracerLever@plt>
L48:
  nop
  leave
  ret
```

assistant: ```c
void debuglvl(unsigned int argc, unsigned char (*argv_pointer)[10]) {
  if (argv_pointer[1][0] == '1') {
    setDebugTracerLever(1);
  } else if (argv_pointer[1][0] == '2') {
    setDebugTracerLever(2);
  } else if (argv_pointer[1][0] == '3') {
    setDebugTracerLever(3);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<debuglvl>:
  endbr64
  sub    $0x8,%rsp
  movzbl 0xa(%rsi),%eax
  cmp    $0x31,%al
  je     L2
  cmp    $0x32,%al
  je     L23
  cmp    $0x33,%al
  je     L50
L33:
  add    $0x8,%rsp
  ret
L2:
  mov    $0x1,%edi
  call   <setDebugTracerLever@plt>
  jmp    L33
L23:
  mov    $0x2,%edi
  call   <setDebugTracerLever@plt>
  jmp    L33
L50:
  mov    $0x3,%edi
  call   <setDebugTracerLever@plt>
  jmp    L33
```

assistant: ```c
void debuglvl(unsigned int argc, unsigned char (*argv_pointer)[10]) {
  if (argv_pointer[1][0] == '1') {
    setDebugTracerLever(1);
  } else if (argv_pointer[1][0] == '2') {
    setDebugTracerLever(2);
  } else if (argv_pointer[1][0] == '3') {
    setDebugTracerLever(3);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<debuglvl>:
  endbr64
  movzbl 0xa(%rsi),%eax
  cmp    $0x31,%al
  je     L21
  cmp    $0x32,%al
  je     L27
  cmp    $0x33,%al
  je     L10
  ret
  nopl   (%rax)
L21:
  mov    $0x1,%edi
  jmp    1050 <setDebugTracerLever@plt>
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0x2,%edi
  jmp    1050 <setDebugTracerLever@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x3,%edi
  jmp    1050 <setDebugTracerLever@plt>
```

assistant: ```c
void debuglvl(unsigned int argc, unsigned char (*argv_pointer)[10]) {
  if (argv_pointer[1][0] == '1') {
    setDebugTracerLever(1);
  } else if (argv_pointer[1][0] == '2') {
    setDebugTracerLever(2);
  } else if (argv_pointer[1][0] == '3') {
    setDebugTracerLever(3);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<debuglvl>:
  endbr64
  movzbl 0xa(%rsi),%eax
  cmp    $0x31,%al
  je     L25
  cmp    $0x32,%al
  je     L14
  cmp    $0x33,%al
  je     L13
  ret
  nopl   (%rax)
L25:
  mov    $0x1,%edi
  jmp    1050 <setDebugTracerLever@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0x2,%edi
  jmp    1050 <setDebugTracerLever@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0x3,%edi
  jmp    1050 <setDebugTracerLever@plt>
```

assistant: ```c
void debuglvl(unsigned int argc, unsigned char (*argv_pointer)[10]) {
  if (argv_pointer[1][0] == '1') {
    setDebugTracerLever(1);
  } else if (argv_pointer[1][0] == '2') {
    setDebugTracerLever(2);
  } else if (argv_pointer[1][0] == '3') {
    setDebugTracerLever(3);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<urlencode_put_limit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <mbstowcs@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <urlencode_put@plt>
  leave
  ret
```

assistant: ```c
size_t urlencode_put_limit(const char *mb_input, char *output, size_t output_limit) {
  assert(NULL != mb_input);
  assert(NULL != output);
  size_t input_len = mbstowcs(NULL, mb_input, 0) + 1;
  memset(output, 0, output_limit);
  return urlencode_put(output, output_limit, mb_input, input_len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<urlencode_put_limit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edx
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <mbstowcs@plt>
  mov    %eax,%ebx
  mov    %r13,%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    0x1(%rbx),%ecx
  movslq %ecx,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <urlencode_put@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t urlencode_put_limit(const char *mb_input, char *output, size_t output_limit) {
  assert(NULL != mb_input);
  assert(NULL != output);
  size_t input_len = mbstowcs(NULL, mb_input, 0) + 1;
  memset(output, 0, output_limit);
  return urlencode_put(output, output_limit, mb_input, input_len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<urlencode_put_limit>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rsi
  xor    %edx,%edx
  xor    %edi,%edi
  call   <mbstowcs@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    %eax,%ebx
  call   <memset@plt>
  add    $0x8,%rsp
  lea    0x1(%rbx),%ecx
  mov    %r12,%rdx
  pop    %rbx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movslq %ecx,%rcx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <urlencode_put@plt>
```

assistant: ```c
size_t urlencode_put_limit(const char *mb_input, char *output, size_t output_limit) {
  assert(NULL != mb_input);
  assert(NULL != output);
  size_t input_len = mbstowcs(NULL, mb_input, 0) + 1;
  memset(output, 0, output_limit);
  return urlencode_put(output, output_limit, mb_input, input_len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fun2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
L22:
  movl   $0xffffffff,-0xc(%rbp)
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  je     L75
  cmp    $0x2,%eax
  jg     L36
  test   %eax,%eax
  je     L68
  cmp    $0x1,%eax
  je     L55
  jmp    L36
L68:
  mov    $0x0,%eax
  call   <main@plt>
L55:
  mov    $0x0,%eax
  call   <fun3@plt>
  jmp    L63
L75:
  mov    $0x0,%eax
  call   <fun4@plt>
  jmp    L63
L36:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L63:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L22
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L87
  call   <__stack_chk_fail@plt>
L87:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D58
type_infered: string
name: retrieve_data
arguments: data_tag: D41
type_infered: string
name: retrieve_data
arguments: data_tag: D34
type_infered: string
name: retrieve_data
arguments: data_tag: D26
type_infered: string
name: retrieve_data
arguments: data_tag: D48
type_infered: string
name: retrieve_data
arguments: data_tag: D83
type_infered: string
name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D23
type_infered: string

tool: D58: cls

tool: D41: Sub Menu


tool: D34: =========


tool: D26: 0-Exit to Main Menu


tool: D48: 1-Addition


tool: D83: 2-Subtraction


tool: D10: Choose your answer (0,1,2):  

tool: D4: %d

tool: D23: Error! you must choose (0 or 1 or 2)!


assistant: ```c
void fun2() {
  int ans1 = -1;
  do {
    ans1 = -1;
    system("cls");
    printf("Sub Menu\n");
    printf("=========\n");
    printf("0-Exit to Main Menu\n");
    printf("1-Addition\n");
    printf("2-Subtraction\n");
    printf("Choose your answer (0,1,2):  ");
    scanf("%d", &ans1);
    switch (ans1) {
    case 0:
      main();
    case 1:
      fun3();
      break;
    case 2:
      fun4();
      break;
    default:
      printf("Error! you must choose (0 or 1 or 2)!\n");
    }
  } while (ans1 != 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fun2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%r13
  lea    D33(%rip),%r12
  lea    D58(%rip),%rbp
  lea    D5(%rip),%rbx
  jmp    L71
L33:
  call   <main@plt>
L63:
  mov    $0x0,%eax
  call   <fun3@plt>
L9:
  cmpl   $0x0,0x4(%rsp)
  je     L42
L71:
  movl   $0xffffffff,0x4(%rsp)
  mov    %r13,%rdi
  call   <system@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D83(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L63
  cmp    $0x2,%eax
  je     L65
  test   %eax,%eax
  je     L33
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L65:
  mov    $0x0,%eax
  call   <fun4@plt>
  jmp    L9
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
datatype: string
name: retrieve_data
arguments: data_label: D33
datatype: string
name: retrieve_data
arguments: data_label: D58
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D55
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D83
datatype: string
name: retrieve_data
arguments: data_label: D30
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string

tool: D11: cls

tool: D33: Sub Menu


tool: D58: =========


tool: D5: 0-Exit to Main Menu


tool: D55: 1-Addition


tool: D12: 2-Subtraction


tool: D83: Choose your answer (0,1,2):  

tool: D30: %d

tool: D15: Error! you must choose (0 or 1 or 2)!


assistant: ```c
void fun2() {
  int ans1 = -1;
  do {
    ans1 = -1;
    system("cls");
    printf("Sub Menu\n");
    printf("=========\n");
    printf("0-Exit to Main Menu\n");
    printf("1-Addition\n");
    printf("2-Subtraction\n");
    printf("Choose your answer (0,1,2):  ");
    scanf("%d", &ans1);
    switch (ans1) {
    case 0:
      main();
    case 1:
      fun3();
      break;
    case 2:
      fun4();
      break;
    default:
      printf("Error! you must choose (0 or 1 or 2)!\n");
    }
  } while (ans1 != 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<fun2>:
  endbr64
  push   %r15
  lea    D79(%rip),%r15
  push   %r14
  lea    D63(%rip),%r14
  push   %r13
  lea    D64(%rip),%r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  lea    D44(%rip),%rbp
  push   %rbx
  lea    D32(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L64:
  test   %eax,%eax
  je     L19
  lea    D14(%rip),%rdi
  call   <printf@plt>
L69:
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L47
L61:
  mov    %r15,%rdi
  movl   $0xffffffff,0x14(%rsp)
  call   <system@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x1,%eax
  je     L9
  cmp    $0x2,%eax
  jne    L64
  xor    %eax,%eax
  call   <fun4@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L61
L47:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L19:
  call   <main@plt>
L9:
  xor    %eax,%eax
  call   <fun3@plt>
  jmp    L69
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D79
datatype: string
name: unpack_data
arguments: tag: D63
datatype: string
name: unpack_data
arguments: tag: D64
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string
name: unpack_data
arguments: tag: D44
datatype: string
name: unpack_data
arguments: tag: D32
datatype: string
name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D51
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string

tool: D79: cls

tool: D63: Sub Menu


tool: D64: =========


tool: D18: 0-Exit to Main Menu


tool: D44: 1-Addition


tool: D32: 2-Subtraction


tool: D14: Error! you must choose (0 or 1 or 2)!


tool: D51: Choose your answer (0,1,2):  

tool: D19: %d

assistant: ```c
void fun2() {
  int ans1 = -1;
  do {
    ans1 = -1;
    system("cls");
    printf("Sub Menu\n");
    printf("=========\n");
    printf("0-Exit to Main Menu\n");
    printf("1-Addition\n");
    printf("2-Subtraction\n");
    printf("Choose your answer (0,1,2):  ");
    scanf("%d", &ans1);
    switch (ans1) {
    case 0:
      main();
    case 1:
      fun3();
      break;
    case 2:
      fun4();
      break;
    default:
      printf("Error! you must choose (0 or 1 or 2)!\n");
    }
  } while (ans1 != 0);
}
```