ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i386_cpuid>:
  endbr64
  mov    $0x0,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  mov    $0x0,%edx
  test   %eax,%eax
  je     L0
  mov    $0x1,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
L0:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  int fl1, fl2;
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=a"(fl1) : "0"(0) : "rdx", "cc");
  if (fl1 == 0)
    return (0);
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=d"(fl2), "=a"(fl1) : "1"(1) : "cc");
  return fl2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i386_cpuid>:
  endbr64
  xor    %eax,%eax
  xor    %r8d,%r8d
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  test   %eax,%eax
  je     L9
  mov    $0x1,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  mov    %edx,%r8d
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  int fl1, fl2;
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=a"(fl1) : "0"(0) : "rdx", "cc");
  if (fl1 == 0)
    return (0);
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=d"(fl2), "=a"(fl1) : "1"(1) : "cc");
  return fl2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<i386_cpuid>:
  endbr64
  xor    %eax,%eax
  xor    %r8d,%r8d
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  test   %eax,%eax
  je     L8
  mov    $0x1,%eax
  push   %rcx
  push   %rbx
  cpuid
  pop    %rbx
  pop    %rcx
  mov    %edx,%r8d
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  int fl1, fl2;
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=a"(fl1) : "0"(0) : "rdx", "cc");
  if (fl1 == 0)
    return (0);
  __asm__("pushq %%rcx; pushq %%rbx; cpuid; popq %%rbx; popq %%rcx" : "=d"(fl2), "=a"(fl1) : "1"(1) : "cc");
  return fl2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <getw@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D10: rb

tool: D20: abc.txt

tool: D1: %d

assistant: ```c
void main() {
  int n;
  FILE *fp;
  fp = fopen("abc.txt", "rb");
  n = getw(fp);
  printf("%d", n);
  fclose(fp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <getw@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string
name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D9: rb

tool: D10: abc.txt

tool: D7: %d

assistant: ```c
void main() {
  int n;
  FILE *fp;
  fp = fopen("abc.txt", "rb");
  n = getw(fp);
  printf("%d", n);
  fclose(fp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rsi
  lea    D17(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <getw@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <fclose@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string
name: disassemble_data
arguments: tag: D29
type_guessed: string

tool: D19: rb

tool: D17: abc.txt

tool: D29: %d

assistant: ```c
void main() {
  int n;
  FILE *fp;
  fp = fopen("abc.txt", "rb");
  n = getw(fp);
  printf("%d", n);
  fclose(fp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rsi
  lea    D7(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <getw@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <fclose@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
datatype: string
name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D29
datatype: string

tool: D18: rb

tool: D7: abc.txt

tool: D29: %d

assistant: ```c
void main() {
  int n;
  FILE *fp;
  fp = fopen("abc.txt", "rb");
  n = getw(fp);
  printf("%d", n);
  fclose(fp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L3
L37:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L34
  mov    $0x0,%eax
  jmp    L28
L34:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L37
  mov    $0x1,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L38
  test   $0x1,%dil
  je     L27
  mov    $0x2,%ecx
L25:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L47
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L25
L46:
  ret
L47:
  mov    $0x1,%eax
  ret
L38:
  mov    $0x1,%eax
  ret
L27:
  mov    $0x0,%eax
  jmp    L46
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L50
  test   $0x1,%dil
  je     L0
  mov    $0x2,%ecx
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L30
L4:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L5
L50:
  mov    $0x1,%edx
L30:
  mov    %edx,%eax
  ret
L0:
  xor    %edx,%edx
  jmp    L30
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L46
  test   $0x1,%dil
  je     L34
  mov    $0x2,%ecx
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L21
L4:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L57
L46:
  mov    $0x1,%edx
L21:
  mov    %edx,%eax
  ret
L34:
  xor    %edx,%edx
  jmp    L21
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i < num; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <umask@plt>
  mov    $0x7,%edi
  call   <umask@plt>
  mov    $0x3f,%edi
  call   <umask@plt>
  mov    $0x1b6,%edi
  call   <umask@plt>
  mov    $0x1ff,%edi
  call   <umask@plt>
  mov    $0x3ff,%edi
  call   <umask@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  umask(0);
  umask(7);
  umask(077);
  umask(0666);
  umask(0777);
  umask(01777);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <umask@plt>
  mov    $0x7,%edi
  call   <umask@plt>
  mov    $0x3f,%edi
  call   <umask@plt>
  mov    $0x1b6,%edi
  call   <umask@plt>
  mov    $0x1ff,%edi
  call   <umask@plt>
  mov    $0x3ff,%edi
  call   <umask@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  umask(0);
  umask(7);
  umask(077);
  umask(0666);
  umask(0777);
  umask(01777);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <umask@plt>
  mov    $0x7,%edi
  call   <umask@plt>
  mov    $0x3f,%edi
  call   <umask@plt>
  mov    $0x1b6,%edi
  call   <umask@plt>
  mov    $0x1ff,%edi
  call   <umask@plt>
  mov    $0x3ff,%edi
  call   <umask@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  umask(0);
  umask(7);
  umask(077);
  umask(0666);
  umask(0777);
  umask(01777);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <umask@plt>
  mov    $0x7,%edi
  call   <umask@plt>
  mov    $0x3f,%edi
  call   <umask@plt>
  mov    $0x1b6,%edi
  call   <umask@plt>
  mov    $0x1ff,%edi
  call   <umask@plt>
  mov    $0x3ff,%edi
  call   <umask@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  umask(0);
  umask(7);
  umask(077);
  umask(0666);
  umask(0777);
  umask(01777);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<perimt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D39
data_type: string
name: disassemble_data
arguments: data_label: D49
data_type: string
name: disassemble_data
arguments: data_label: D2
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: byte[8]
name: disassemble_data
arguments: data_label: D12
data_type: string

tool: D39: +-------*--------*--------*--------*-------+

tool: D49: Please input a round's radius:

tool: D2: %lf

tool: {"D0": [0x6e,0x86,0x1b,0xf0,0xf9,0x21,0x19,0x40]}

tool: D12: The round's perimeter is %lf


assistant: ```c
void perimt() {
  double radius, perimeter;
  printf("+-------*--------*--------*--------*-------+\n");
  printf("Please input a round's radius:");
  scanf("%lf", &radius);
  perimeter = 2 * 3.14159 * radius;
  printf("The round's perimeter is %lf\n", perimeter);
  printf("+-------*--------*--------*--------*-------+\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<perimt>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  movsd  D23(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  lea    D34(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D32
datatype: string
name: read_data
arguments: label: D1
datatype: string
name: read_data
arguments: label: D22
datatype: string
name: read_data
arguments: label: D23
datatype: byte[8]
name: read_data
arguments: label: D34
datatype: string

tool: D32: +-------*--------*--------*--------*-------+

tool: D1: Please input a round's radius:

tool: D22: %lf

tool: {"D23": [0x6e,0x86,0x1b,0xf0,0xf9,0x21,0x19,0x40]}

tool: D34: The round's perimeter is %lf


assistant: ```c
void perimt() {
  double radius, perimeter;
  printf("+-------*--------*--------*--------*-------+\n");
  printf("Please input a round's radius:");
  scanf("%lf", &radius);
  perimeter = 2 * 3.14159 * radius;
  printf("The round's perimeter is %lf\n", perimeter);
  printf("+-------*--------*--------*--------*-------+\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<perimt>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  movsd  D46(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  lea    D32(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D33
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D46
type_guessed: byte[8]
name: read_data
arguments: data_tag: D32
type_guessed: string

tool: D2: +-------*--------*--------*--------*-------+

tool: D33: Please input a round's radius:

tool: D6: %lf

tool: {"D46": [0x6e,0x86,0x1b,0xf0,0xf9,0x21,0x19,0x40]}

tool: D32: The round's perimeter is %lf


assistant: ```c
void perimt() {
  double radius, perimeter;
  printf("+-------*--------*--------*--------*-------+\n");
  printf("Please input a round's radius:");
  scanf("%lf", &radius);
  perimeter = 2 * 3.14159 * radius;
  printf("The round's perimeter is %lf\n", perimeter);
  printf("+-------*--------*--------*--------*-------+\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<perimt>:
  endbr64
  push   %rbp
  lea    D42(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  movsd  D23(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  lea    D15(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D42
datatype: string
name: disassemble_data
arguments: tag: D46
datatype: string
name: disassemble_data
arguments: tag: D36
datatype: string
name: disassemble_data
arguments: tag: D23
datatype: byte[8]
name: disassemble_data
arguments: tag: D15
datatype: string

tool: D42: +-------*--------*--------*--------*-------+

tool: D46: Please input a round's radius:

tool: D36: %lf

tool: {"D23": [0x6e,0x86,0x1b,0xf0,0xf9,0x21,0x19,0x40]}

tool: D15: The round's perimeter is %lf


assistant: ```c
void perimt() {
  double radius, perimeter;
  printf("+-------*--------*--------*--------*-------+\n");
  printf("Please input a round's radius:");
  scanf("%lf", &radius);
  perimeter = 2 * 3.14159 * radius;
  printf("The round's perimeter is %lf\n", perimeter);
  printf("+-------*--------*--------*--------*-------+\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mult32x16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  sar    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  imul   -0x18(%rbp),%eax
  add    %eax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t mult32x16(int32_t x, int16_t y) {
  int32_t z;
  z = ((int32_t)y * (uint16_t)x) >> 15;
  z += ((int32_t)(x >> 16) * y) << 1;
  return z;
}
```
user: What is the c source code of the assembly code below:

```asm
<mult32x16>:
  endbr64
  mov    %esi,%eax
  imul   %edi,%eax
  sar    $0xf,%eax
  sar    $0x10,%edi
  imul   %esi,%edi
  lea    (%rax,%rdi,2),%eax
  ret
```

assistant: ```c
int32_t mult32x16(int32_t x, int16_t y) {
  int32_t z;
  z = ((int32_t)y * (uint16_t)x) >> 15;
  z += ((int32_t)(x >> 16) * y) << 1;
  return z;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mult32x16>:
  endbr64
  mov    %esi,%eax
  imul   %edi,%eax
  sar    $0x10,%edi
  imul   %esi,%edi
  sar    $0xf,%eax
  lea    (%rax,%rdi,2),%eax
  ret
```

assistant: ```c
int32_t mult32x16(int32_t x, int16_t y) {
  int32_t z;
  z = ((int32_t)y * (uint16_t)x) >> 15;
  z += ((int32_t)(x >> 16) * y) << 1;
  return z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mult32x16>:
  endbr64
  mov    %esi,%eax
  imul   %edi,%eax
  sar    $0x10,%edi
  imul   %esi,%edi
  sar    $0xf,%eax
  lea    (%rax,%rdi,2),%eax
  ret
```

assistant: ```c
int32_t mult32x16(int32_t x, int16_t y) {
  int32_t z;
  z = ((int32_t)y * (uint16_t)x) >> 15;
  z += ((int32_t)(x >> 16) * y) << 1;
  return z;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mul_mtx33>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  movss  (%rdi),%xmm3
  movss  (%rsi),%xmm2
  movss  0x4(%rdi),%xmm8
  movss  0xc(%rsi),%xmm11
  movss  0x8(%rdi),%xmm7
  movss  0x18(%rsi),%xmm10
  movaps %xmm3,%xmm0
  mulss  %xmm2,%xmm0
  movaps %xmm8,%xmm1
  mulss  %xmm11,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm7,%xmm1
  mulss  %xmm10,%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  movss  0x4(%rsi),%xmm1
  movss  0x10(%rsi),%xmm9
  movss  0x1c(%rsi),%xmm6
  movaps %xmm3,%xmm0
  mulss  %xmm1,%xmm0
  movaps %xmm8,%xmm4
  mulss  %xmm9,%xmm4
  addss  %xmm4,%xmm0
  movaps %xmm7,%xmm4
  mulss  %xmm6,%xmm4
  addss  %xmm4,%xmm0
  movss  %xmm0,0x4(%rsp)
  movss  0x8(%rsi),%xmm0
  movss  0x14(%rsi),%xmm5
  movss  0x20(%rsi),%xmm4
  mulss  %xmm0,%xmm3
  mulss  %xmm5,%xmm8
  addss  %xmm8,%xmm3
  mulss  %xmm4,%xmm7
  addss  %xmm7,%xmm3
  movss  %xmm3,0x8(%rsp)
  movss  0xc(%rdi),%xmm3
  movss  0x10(%rdi),%xmm8
  movss  0x14(%rdi),%xmm7
  movaps %xmm2,%xmm12
  mulss  %xmm3,%xmm12
  movaps %xmm11,%xmm13
  mulss  %xmm8,%xmm13
  addss  %xmm13,%xmm12
  movaps %xmm10,%xmm13
  mulss  %xmm7,%xmm13
  addss  %xmm13,%xmm12
  movss  %xmm12,0xc(%rsp)
  movaps %xmm1,%xmm12
  mulss  %xmm3,%xmm12
  movaps %xmm9,%xmm13
  mulss  %xmm8,%xmm13
  addss  %xmm13,%xmm12
  movaps %xmm6,%xmm13
  mulss  %xmm7,%xmm13
  addss  %xmm13,%xmm12
  movss  %xmm12,0x10(%rsp)
  mulss  %xmm0,%xmm3
  mulss  %xmm5,%xmm8
  addss  %xmm8,%xmm3
  mulss  %xmm4,%xmm7
  addss  %xmm7,%xmm3
  movss  %xmm3,0x14(%rsp)
  movss  0x18(%rdi),%xmm8
  movss  0x1c(%rdi),%xmm7
  movss  0x20(%rdi),%xmm3
  mulss  %xmm8,%xmm2
  mulss  %xmm7,%xmm11
  addss  %xmm11,%xmm2
  mulss  %xmm3,%xmm10
  addss  %xmm10,%xmm2
  movss  %xmm2,0x18(%rsp)
  mulss  %xmm8,%xmm1
  mulss  %xmm7,%xmm9
  addss  %xmm9,%xmm1
  mulss  %xmm3,%xmm6
  addss  %xmm6,%xmm1
  movss  %xmm1,0x1c(%rsp)
  mulss  %xmm8,%xmm0
  mulss  %xmm7,%xmm5
  addss  %xmm5,%xmm0
  mulss  %xmm3,%xmm4
  addss  %xmm4,%xmm0
  movss  %xmm0,0x20(%rsp)
  movdqa (%rsp),%xmm5
  movups %xmm5,(%rdi)
  movdqa 0x10(%rsp),%xmm6
  movups %xmm6,0x10(%rdi)
  mov    0x20(%rsp),%edx
  mov    %edx,0x20(%rdi)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mul_mtx33(float *a, const float *b) {
  float res[9];
  res[0] = (a[0]) * (b[0]) + (a[1]) * (b[3]) + (a[2]) * (b[6]);
  res[1] = (a[0]) * (b[1]) + (a[1]) * (b[4]) + (a[2]) * (b[7]);
  res[2] = (a[0]) * (b[2]) + (a[1]) * (b[5]) + (a[2]) * (b[8]);
  res[3] = (a[3]) * (b[0]) + (a[4]) * (b[3]) + (a[5]) * (b[6]);
  res[4] = (a[3]) * (b[1]) + (a[4]) * (b[4]) + (a[5]) * (b[7]);
  res[5] = (a[3]) * (b[2]) + (a[4]) * (b[5]) + (a[5]) * (b[8]);
  res[6] = (a[6]) * (b[0]) + (a[7]) * (b[3]) + (a[8]) * (b[6]);
  res[7] = (a[6]) * (b[1]) + (a[7]) * (b[4]) + (a[8]) * (b[7]);
  res[8] = (a[6]) * (b[2]) + (a[7]) * (b[5]) + (a[8]) * (b[8]);
  memcpy(a, &res, 9 * sizeof(float));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mul_mtx33>:
  endbr64
  sub    $0x38,%rsp
  movss  (%rdi),%xmm3
  movss  0x4(%rdi),%xmm9
  movss  (%rsi),%xmm2
  movss  0xc(%rsi),%xmm11
  movaps %xmm3,%xmm0
  movaps %xmm9,%xmm1
  movss  0x10(%rsi),%xmm7
  movaps %xmm9,%xmm4
  mulss  %xmm11,%xmm1
  movss  0x8(%rdi),%xmm8
  movss  0x1c(%rsi),%xmm6
  movaps %xmm2,%xmm12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mulss  %xmm2,%xmm0
  movss  0x18(%rsi),%xmm10
  movaps %xmm11,%xmm13
  mulss  %xmm7,%xmm4
  movss  0x14(%rsi),%xmm5
  mulss  %xmm5,%xmm9
  addss  %xmm1,%xmm0
  movaps %xmm8,%xmm1
  mulss  %xmm10,%xmm1
  addss  %xmm1,%xmm0
  movss  0x4(%rsi),%xmm1
  movss  %xmm0,(%rsp)
  movaps %xmm3,%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm4,%xmm0
  movaps %xmm8,%xmm4
  mulss  %xmm6,%xmm4
  addss  %xmm4,%xmm0
  movss  0x20(%rsi),%xmm4
  mulss  %xmm4,%xmm8
  movss  %xmm0,0x4(%rsp)
  movss  0x8(%rsi),%xmm0
  mulss  %xmm0,%xmm3
  addss  %xmm9,%xmm3
  movss  0x10(%rdi),%xmm9
  mulss  %xmm9,%xmm13
  addss  %xmm8,%xmm3
  movss  0x14(%rdi),%xmm8
  movss  %xmm3,0x8(%rsp)
  movss  0xc(%rdi),%xmm3
  mulss  %xmm3,%xmm12
  addss  %xmm13,%xmm12
  movaps %xmm10,%xmm13
  mulss  %xmm8,%xmm13
  addss  %xmm13,%xmm12
  movaps %xmm7,%xmm13
  mulss  %xmm9,%xmm13
  mulss  %xmm5,%xmm9
  movss  %xmm12,0xc(%rsp)
  movaps %xmm1,%xmm12
  mulss  %xmm3,%xmm12
  mulss  %xmm0,%xmm3
  addss  %xmm13,%xmm12
  movaps %xmm6,%xmm13
  mulss  %xmm8,%xmm13
  addss  %xmm9,%xmm3
  movss  0x18(%rdi),%xmm9
  mulss  %xmm4,%xmm8
  mulss  %xmm9,%xmm2
  mulss  %xmm9,%xmm1
  mulss  %xmm9,%xmm0
  addss  %xmm13,%xmm12
  addss  %xmm8,%xmm3
  movss  0x1c(%rdi),%xmm8
  mulss  %xmm8,%xmm5
  movss  %xmm12,0x10(%rsp)
  mulss  %xmm8,%xmm11
  movss  %xmm3,0x14(%rsp)
  movss  0x20(%rdi),%xmm3
  mulss  %xmm8,%xmm7
  mulss  %xmm3,%xmm6
  mulss  %xmm3,%xmm10
  mulss  %xmm3,%xmm4
  addss  %xmm5,%xmm0
  movdqa (%rsp),%xmm5
  addss  %xmm11,%xmm2
  addss  %xmm7,%xmm1
  movups %xmm5,(%rdi)
  addss  %xmm10,%xmm2
  addss  %xmm6,%xmm1
  addss  %xmm4,%xmm0
  movss  %xmm2,0x18(%rsp)
  movss  %xmm1,0x1c(%rsp)
  movss  %xmm0,0x20(%rsp)
  movdqa 0x10(%rsp),%xmm6
  mov    0x20(%rsp),%eax
  mov    %eax,0x20(%rdi)
  movups %xmm6,0x10(%rdi)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mul_mtx33(float *a, const float *b) {
  float res[9];
  res[0] = (a[0]) * (b[0]) + (a[1]) * (b[3]) + (a[2]) * (b[6]);
  res[1] = (a[0]) * (b[1]) + (a[1]) * (b[4]) + (a[2]) * (b[7]);
  res[2] = (a[0]) * (b[2]) + (a[1]) * (b[5]) + (a[2]) * (b[8]);
  res[3] = (a[3]) * (b[0]) + (a[4]) * (b[3]) + (a[5]) * (b[6]);
  res[4] = (a[3]) * (b[1]) + (a[4]) * (b[4]) + (a[5]) * (b[7]);
  res[5] = (a[3]) * (b[2]) + (a[4]) * (b[5]) + (a[5]) * (b[8]);
  res[6] = (a[6]) * (b[0]) + (a[7]) * (b[3]) + (a[8]) * (b[6]);
  res[7] = (a[6]) * (b[1]) + (a[7]) * (b[4]) + (a[8]) * (b[7]);
  res[8] = (a[6]) * (b[2]) + (a[7]) * (b[5]) + (a[8]) * (b[8]);
  memcpy(a, &res, 9 * sizeof(float));
}
```