ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<v_EepromWaitBusy>:
  endbr64
  push   %rbx
  lea    0x3f(%rdi),%ebx
  movzwl %bx,%ebx
L6:
  mov    %ebx,%edi
  call   <inb@plt>
  test   %al,%al
  js     L6
  pop    %rbx
  ret
```

assistant: ```c
void v_EepromWaitBusy(unsigned short w_PCIBoardEepromAddress) {
  unsigned char b_EepromBusy = 0;
  do {
    b_EepromBusy = inb(w_PCIBoardEepromAddress + 0x3F);
    b_EepromBusy = b_EepromBusy & 0x80;
  } while (b_EepromBusy == 0x80);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<v_EepromWaitBusy>:
  endbr64
  push   %rbx
  lea    0x3f(%rdi),%ebx
  movzwl %bx,%ebx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  call   <inb@plt>
  test   %al,%al
  js     L2
  pop    %rbx
  ret
```

assistant: ```c
void v_EepromWaitBusy(unsigned short w_PCIBoardEepromAddress) {
  unsigned char b_EepromBusy = 0;
  do {
    b_EepromBusy = inb(w_PCIBoardEepromAddress + 0x3F);
    b_EepromBusy = b_EepromBusy & 0x80;
  } while (b_EepromBusy == 0x80);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<v_EepromWaitBusy>:
  endbr64
  push   %rbx
  lea    0x3f(%rdi),%ebx
  movzwl %bx,%ebx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  call   <inb@plt>
  test   %al,%al
  js     L9
  pop    %rbx
  ret
```

assistant: ```c
void v_EepromWaitBusy(unsigned short w_PCIBoardEepromAddress) {
  unsigned char b_EepromBusy = 0;
  do {
    b_EepromBusy = inb(w_PCIBoardEepromAddress + 0x3F);
    b_EepromBusy = b_EepromBusy & 0x80;
  } while (b_EepromBusy == 0x80);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isjoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L162
  mov    $0xffffffff,%eax
  jmp    L8
L162:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L177
L48:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L91
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L91
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L163
L91:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L11
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L170
L11:
  cmpl   $0x0,-0x4(%rbp)
  jne    L101
  addl   $0x1,-0x4(%rbp)
  jmp    L101
L170:
  cmpl   $0x0,-0x4(%rbp)
  je     L20
  addl   $0x1,-0x4(%rbp)
  jmp    L73
L20:
  mov    $0x0,%eax
  jmp    L8
L101:
  jmp    L73
L163:
  mov    $0x0,%eax
  jmp    L8
L73:
  addl   $0x1,-0x8(%rbp)
L177:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jb     L48
  cmpl   $0x2,-0x4(%rbp)
  jne    L112
  mov    $0x1,%eax
  jmp    L8
L112:
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int isjoint(const char *line) {
  if (line == NULL) {
    return -1;
  }
  unsigned int i;
  unsigned int sign = 0;
  for (i = 0; i < strlen(line); i++) {
    if (line[i] == ' ' || line[i] == '\t' || line[i] == '\\') {
      if (line[i] == ' ' || line[i] == '\t') {
        if (sign < 1)
          sign++;
      } else {
        if (sign > 0)
          sign++;
        else
          return 0;
      }
    } else {
      return 0;
    }
  }
  if (sign == 2)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isjoint>:
  endbr64
  mov    $0xffffffff,%eax
  test   %rdi,%rdi
  jne    L93
  ret
L93:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L54
L59:
  test   %ebp,%ebp
  je     L27
  add    $0x1,%ebp
L28:
  add    $0x1,%ebx
L54:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L37
  mov    %ebx,%eax
  movzbl (%r12,%rax,1),%edx
  cmp    $0x20,%dl
  sete   %al
  cmp    $0x9,%dl
  sete   %cl
  or     %ecx,%eax
  cmp    $0x5c,%dl
  je     L1
  test   %al,%al
  je     L84
L1:
  test   %al,%al
  je     L59
  test   %ebp,%ebp
  mov    $0x1,%eax
  cmove  %eax,%ebp
  jmp    L28
L37:
  cmp    $0x2,%ebp
  sete   %al
  movzbl %al,%eax
L89:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L84:
  mov    $0x0,%eax
  jmp    L89
L27:
  mov    $0x0,%eax
  jmp    L89
```

assistant: ```c
int isjoint(const char *line) {
  if (line == NULL) {
    return -1;
  }
  unsigned int i;
  unsigned int sign = 0;
  for (i = 0; i < strlen(line); i++) {
    if (line[i] == ' ' || line[i] == '\t' || line[i] == '\\') {
      if (line[i] == ' ' || line[i] == '\t') {
        if (sign < 1)
          sign++;
      } else {
        if (sign > 0)
          sign++;
        else
          return 0;
      }
    } else {
      return 0;
    }
  }
  if (sign == 2)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isjoint>:
  endbr64
  mov    $0xffffffff,%eax
  test   %rdi,%rdi
  jne    L45
  ret
  nop
L45:
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L54
  nopl   (%rax)
L6:
  test   %ebp,%ebp
  je     L77
  cmp    $0x5c,%al
  jne    L77
  add    $0x1,%ebp
L0:
  add    $0x1,%ebx
L54:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L9
  mov    %ebx,%eax
  movzbl (%r12,%rax,1),%eax
  cmp    $0x20,%al
  je     L10
  cmp    $0x9,%al
  jne    L6
L10:
  test   %ebp,%ebp
  mov    $0x1,%eax
  cmove  %eax,%ebp
  jmp    L0
  nopl   (%rax)
L9:
  xor    %eax,%eax
  cmp    $0x2,%ebp
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
  nopl   (%rax)
L77:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int isjoint(const char *line) {
  if (line == NULL) {
    return -1;
  }
  unsigned int i;
  unsigned int sign = 0;
  for (i = 0; i < strlen(line); i++) {
    if (line[i] == ' ' || line[i] == '\t' || line[i] == '\\') {
      if (line[i] == ' ' || line[i] == '\t') {
        if (sign < 1)
          sign++;
      } else {
        if (sign > 0)
          sign++;
        else
          return 0;
      }
    } else {
      return 0;
    }
  }
  if (sign == 2)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isjoint>:
  endbr64
  mov    $0xffffffff,%eax
  test   %rdi,%rdi
  jne    L73
  ret
  nop
L73:
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L60
  nopl   (%rax)
L29:
  test   %ebp,%ebp
  je     L14
  cmp    $0x5c,%al
  jne    L14
  add    $0x1,%ebp
L61:
  add    $0x1,%ebx
L60:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L33
  mov    %ebx,%eax
  movzbl (%r12,%rax,1),%eax
  cmp    $0x20,%al
  je     L36
  cmp    $0x9,%al
  jne    L29
L36:
  test   %ebp,%ebp
  mov    $0x1,%eax
  cmove  %eax,%ebp
  jmp    L61
  nopl   (%rax)
L33:
  xor    %eax,%eax
  cmp    $0x2,%ebp
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
  nopl   (%rax)
L14:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int isjoint(const char *line) {
  if (line == NULL) {
    return -1;
  }
  unsigned int i;
  unsigned int sign = 0;
  for (i = 0; i < strlen(line); i++) {
    if (line[i] == ' ' || line[i] == '\t' || line[i] == '\\') {
      if (line[i] == ' ' || line[i] == '\t') {
        if (sign < 1)
          sign++;
      } else {
        if (sign > 0)
          sign++;
        else
          return 0;
      }
    } else {
      return 0;
    }
  }
  if (sign == 2)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_1st_atom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <num_strmatch@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L24
L14:
  cmpq   $0x1,-0x8(%rbp)
  jle    L0
  mov    -0x38(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
L0:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L3
L15:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
  addq   $0x1,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jle    L15
  jmp    L7
L22:
  nop
L7:
  mov    -0x10(%rbp),%rax
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: 

assistant: ```c
long find_1st_atom(char *str, char **strmat, long nb, long ne, char *idmsg) {
  long i, num;
  num = num_strmatch(str, strmat, nb, ne);
  if (!num) {
    return 0;
  }
  if (num > 1 && strcmp(idmsg, "")) {
  }
  for (i = nb; i <= ne; i++)
    if (!strcmp(str, strmat[i]))
      break;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_1st_atom>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %r8,%r14
  call   <num_strmatch@plt>
  test   %rax,%rax
  je     L29
  cmp    $0x1,%rax
  jg     L19
L31:
  cmp    %rbp,%rbx
  jg     L71
L63:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L37
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jge    L63
  mov    %rbx,%rax
  jmp    L29
L19:
  lea    D3(%rip),%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  jmp    L31
L71:
  mov    %rbx,%rax
  jmp    L29
L37:
  mov    %rbx,%rax
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: 

assistant: ```c
long find_1st_atom(char *str, char **strmat, long nb, long ne, char *idmsg) {
  long i, num;
  num = num_strmatch(str, strmat, nb, ne);
  if (!num) {
    return 0;
  }
  if (num > 1 && strcmp(idmsg, "")) {
  }
  for (i = nb; i <= ne; i++)
    if (!strcmp(str, strmat[i]))
      break;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_1st_atom>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <num_strmatch@plt>
  test   %rax,%rax
  je     L21
  cmp    $0x1,%rax
  jg     L51
L62:
  cmp    %rbp,%rbx
  jle    L63
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jl     L23
L63:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L30
L23:
  mov    %rbx,%rax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L51:
  lea    D9(%rip),%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  jmp    L62
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string

tool: 

assistant: ```c
long find_1st_atom(char *str, char **strmat, long nb, long ne, char *idmsg) {
  long i, num;
  num = num_strmatch(str, strmat, nb, ne);
  if (!num) {
    return 0;
  }
  if (num > 1 && strcmp(idmsg, "")) {
  }
  for (i = nb; i <= ne; i++)
    if (!strcmp(str, strmat[i]))
      break;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_1st_atom>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <num_strmatch@plt>
  test   %rax,%rax
  je     L28
  cmp    $0x1,%rax
  jg     L42
L24:
  cmp    %rbp,%rbx
  jle    L16
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jl     L41
L16:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L45
L41:
  mov    %rbx,%rax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L42:
  lea    D5(%rip),%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  jmp    L24
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: 

assistant: ```c
long find_1st_atom(char *str, char **strmat, long nb, long ne, char *idmsg) {
  long i, num;
  num = num_strmatch(str, strmat, nb, ne);
  if (!num) {
    return 0;
  }
  if (num > 1 && strcmp(idmsg, "")) {
  }
  for (i = nb; i <= ne; i++)
    if (!strcmp(str, strmat[i]))
      break;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cfb16_get_color>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x3,%eax
  shl    $0xb,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shr    $0x2,%eax
  shl    $0x5,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x3,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int cfb16_get_color(unsigned int color) {
  unsigned int r, g, b;
  r = (color >> 16) & 0xff;
  g = (color >> 8) & 0xff;
  b = (color)&0xff;
  return ((((r) >> 3) << 11) | (((g) >> 2) << 5) | ((b) >> 3));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cfb16_get_color>:
  endbr64
  mov    %edi,%eax
  shr    $0x8,%eax
  and    $0xf800,%eax
  mov    %edi,%edx
  shr    $0x5,%edx
  and    $0x7e0,%edx
  or     %edx,%eax
  shr    $0x3,%edi
  and    $0x1f,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned int cfb16_get_color(unsigned int color) {
  unsigned int r, g, b;
  r = (color >> 16) & 0xff;
  g = (color >> 8) & 0xff;
  b = (color)&0xff;
  return ((((r) >> 3) << 11) | (((g) >> 2) << 5) | ((b) >> 3));
}
```
user: What is the c source code of the assembly code below?

```asm
<cfb16_get_color>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  shr    $0x3,%edi
  shr    $0x8,%eax
  shr    $0x5,%edx
  and    $0x1f,%edi
  and    $0xf800,%eax
  and    $0x7e0,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned int cfb16_get_color(unsigned int color) {
  unsigned int r, g, b;
  r = (color >> 16) & 0xff;
  g = (color >> 8) & 0xff;
  b = (color)&0xff;
  return ((((r) >> 3) << 11) | (((g) >> 2) << 5) | ((b) >> 3));
}
```
user: Translate the below assembly code into C programming language:

```asm
<cfb16_get_color>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  shr    $0x3,%edi
  shr    $0x8,%eax
  shr    $0x5,%edx
  and    $0x1f,%edi
  and    $0xf800,%eax
  and    $0x7e0,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned int cfb16_get_color(unsigned int color) {
  unsigned int r, g, b;
  r = (color >> 16) & 0xff;
  g = (color >> 8) & 0xff;
  b = (color)&0xff;
  return ((((r) >> 3) << 11) | (((g) >> 2) << 5) | ((b) >> 3));
}
```
user: What is the c source code of the assembly code below:

```asm
<is_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L11
  cmpb   $0x39,-0x4(%rbp)
  jg     L11
  mov    $0x1,%eax
  jmp    L8
L11:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int is_num(const char c) {
  if (c >= '0' && c <= '9')
    return (1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_num>:
  endbr64
  sub    $0x30,%edi
  cmp    $0x9,%dil
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_num(const char c) {
  if (c >= '0' && c <= '9')
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_num>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_num(const char c) {
  if (c >= '0' && c <= '9')
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_num>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_num(const char c) {
  if (c >= '0' && c <= '9')
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2a,%edi
  call   <long_double_from_i32@plt>
  cmp    $0x2a,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0xffffffd6,%edi
  call   <long_double_from_i32@plt>
  cmp    $0xffffffffffffffd6,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  assert(long_double_from_i32(42) == 42.L);
  assert(long_double_from_i32(-42) == -42.L);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%edi
  call   <long_double_from_i32@plt>
  cmp    $0x2a,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xffffffd6,%edi
  call   <long_double_from_i32@plt>
  cmp    $0xffffffffffffffd6,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(long_double_from_i32(42) == 42.L);
  assert(long_double_from_i32(-42) == -42.L);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%edi
  call   <long_double_from_i32@plt>
  xor    %edi,%edi
  cmp    $0x2a,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0xffffffd6,%edi
  call   <long_double_from_i32@plt>
  xor    %edi,%edi
  cmp    $0xffffffffffffffd6,%rax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(long_double_from_i32(42) == 42.L);
  assert(long_double_from_i32(-42) == -42.L);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%edi
  call   <long_double_from_i32@plt>
  xor    %edi,%edi
  cmp    $0x2a,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0xffffffd6,%edi
  call   <long_double_from_i32@plt>
  xor    %edi,%edi
  cmp    $0xffffffffffffffd6,%rax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assert(long_double_from_i32(42) == 42.L);
  assert(long_double_from_i32(-42) == -42.L);
}
```
user: Translate the below assembly code into C programming language:

```asm
<tsub_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jne    L101
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
L101:
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L113
  cmpl   $0x0,-0x18(%rbp)
  jns    L113
  cmpl   $0x0,-0xc(%rbp)
  jns    L113
  mov    $0x1,%eax
  jmp    L0
L113:
  mov    $0x0,%eax
L0:
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L41
  cmpl   $0x0,-0x18(%rbp)
  jle    L41
  cmpl   $0x0,-0xc(%rbp)
  jle    L41
  mov    $0x1,%eax
  jmp    L107
L41:
  mov    $0x0,%eax
L107:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L51
  cmpl   $0x0,-0x8(%rbp)
  jne    L51
  cmpl   $0x0,-0x4(%rbp)
  jne    L51
  mov    $0x1,%eax
  jmp    L33
L51:
  mov    $0x0,%eax
L33:
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int tsub_ok(int x, int y) {
  int res = 1;
  (y == INT_MIN) && (res = 0);
  int sub = x - y;
  int pos_over = x > 0 && y < 0 && sub < 0;
  int neg_over = x < 0 && y > 0 && sub > 0;
  res = res && !(pos_over || neg_over);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tsub_ok>:
  endbr64
  mov    $0x0,%eax
  mov    D3(%rip),%rdx
  cmp    %esi,(%rdx)
  je     L5
  mov    %edi,%edx
  sub    %esi,%edx
  mov    %edi,%ecx
  shr    $0x1f,%ecx
  test   %esi,%esi
  setg   %al
  and    %ecx,%eax
  test   %edx,%edx
  setg   %cl
  and    %ecx,%eax
  and    %edx,%esi
  shr    $0x1f,%esi
  test   %edi,%edi
  setg   %dl
  and    %esi,%edx
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
L5:
  ret
```

assistant: ```c
int tsub_ok(int x, int y) {
  int res = 1;
  (y == INT_MIN) && (res = 0);
  int sub = x - y;
  int pos_over = x > 0 && y < 0 && sub < 0;
  int neg_over = x < 0 && y > 0 && sub > 0;
  res = res && !(pos_over || neg_over);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tsub_ok>:
  endbr64
  mov    %edi,%edx
  sub    %esi,%edx
  test   %edx,%esi
  jns    L3
  xor    %eax,%eax
  test   %edi,%edi
  jg     L24
L3:
  shr    $0x1f,%edi
  test   %esi,%esi
  setg   %al
  test   %dil,%al
  je     L34
  xor    %eax,%eax
  test   %edx,%edx
  jle    L34
L24:
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    D0(%rip),%rax
  cmp    %esi,(%rax)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int tsub_ok(int x, int y) {
  int res = 1;
  (y == INT_MIN) && (res = 0);
  int sub = x - y;
  int pos_over = x > 0 && y < 0 && sub < 0;
  int neg_over = x < 0 && y > 0 && sub > 0;
  res = res && !(pos_over || neg_over);
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tsub_ok>:
  endbr64
  mov    %edi,%edx
  sub    %esi,%edx
  test   %edx,%esi
  jns    L11
  xor    %eax,%eax
  test   %edi,%edi
  jg     L39
L11:
  shr    $0x1f,%edi
  test   %esi,%esi
  setg   %al
  test   %dil,%al
  je     L3
  xor    %eax,%eax
  test   %edx,%edx
  jle    L3
L39:
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    D9(%rip),%rax
  cmp    %esi,(%rax)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int tsub_ok(int x, int y) {
  int res = 1;
  (y == INT_MIN) && (res = 0);
  int sub = x - y;
  int pos_over = x > 0 && y < 0 && sub < 0;
  int neg_over = x < 0 && y > 0 && sub > 0;
  res = res && !(pos_over || neg_over);
  return res;
}
```