ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D14(%rip),%r12
  jmp    L19
L37:
  mov    %eax,%ebx
L19:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L4
  cmp    %ebx,%eax
  jg     L37
  test   %ebp,%ebp
  je     L7
  cmp    %ebp,%eax
  jge    L19
L7:
  mov    %eax,%ebp
  jmp    L19
L4:
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D4: Enter array of numbers (press enter after each number | 0 Exists): 
-----------------------------------------------------------------

tool: D14: %d

tool: D7: MAX: %d
MIN: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int temp;
  int max = 0;
  int min = 0;
  printf("Enter array of numbers (press enter after each number | 0 Exists): \n"
         "-----------------------------------------------------------------\n");
  while (scanf("%d", &temp), temp != 0) {
    if (temp > max) {
      max = temp;
    } else if (temp < min || min == 0) {
      min = temp;
    }
  }
  printf("MAX: %d\nMIN: %d\n", max, min);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rdi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L14
  cmp    %ebp,%eax
  jg     L10
  test   %r12d,%r12d
  je     L56
  cmp    %r12d,%eax
  jge    L57
L56:
  mov    %eax,%r12d
  jmp    L57
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %eax,%ebp
  jmp    L57
  nopl   0x0(%rax)
L14:
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string
name: parse_data
arguments: data_label: D16
data_type: string
name: parse_data
arguments: data_label: D23
data_type: string

tool: D4: Enter array of numbers (press enter after each number | 0 Exists): 
-----------------------------------------------------------------

tool: D16: %d

tool: D23: MAX: %d
MIN: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int temp;
  int max = 0;
  int min = 0;
  printf("Enter array of numbers (press enter after each number | 0 Exists): \n"
         "-----------------------------------------------------------------\n");
  while (scanf("%d", &temp), temp != 0) {
    if (temp > max) {
      max = temp;
    } else if (temp < min || min == 0) {
      min = temp;
    }
  }
  printf("MAX: %d\nMIN: %d\n", max, min);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D24(%rip),%rdi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L23
  cmp    %ebp,%eax
  jg     L42
  test   %r12d,%r12d
  je     L5
  cmp    %r12d,%eax
  jge    L66
L5:
  mov    %eax,%r12d
  jmp    L66
  cs nopw 0x0(%rax,%rax,1)
L42:
  mov    %eax,%ebp
  jmp    L66
  nopl   0x0(%rax)
L23:
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D24
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string

tool: D24: Enter array of numbers (press enter after each number | 0 Exists): 
-----------------------------------------------------------------

tool: D11: %d

tool: D16: MAX: %d
MIN: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int temp;
  int max = 0;
  int min = 0;
  printf("Enter array of numbers (press enter after each number | 0 Exists): \n"
         "-----------------------------------------------------------------\n");
  while (scanf("%d", &temp), temp != 0) {
    if (temp > max) {
      max = temp;
    } else if (temp < min || min == 0) {
      min = temp;
    }
  }
  printf("MAX: %d\nMIN: %d\n", max, min);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getgrnam_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  jmp    L47
L34:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L5
L47:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <getgrent_r@plt>
  test   %eax,%eax
  je     L34
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L27
L5:
  nop
L27:
  mov    $0x0,%eax
  call   <endgrent@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L50
  mov    $0x0,%eax
  jmp    L31
L50:
  mov    $0xffffffff,%eax
L31:
  leave
  ret
```

assistant: ```c
int getgrnam_r(const char *name, struct group *res, char *buf, size_t buflen, struct group **res_sig) {
  while (!getgrent_r(res, buf, buflen, res_sig))
    if (!strcmp(name, res->gr_name))
      goto ok;
  *res_sig = 0;
ok:
  endgrent();
  return *res_sig ? 0 : -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getgrnam_r>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8,%rbp
L5:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <getgrent_r@plt>
  test   %eax,%eax
  jne    L24
  mov    (%rbx),%esi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L5
  jmp    L10
L24:
  movq   $0x0,0x0(%rbp)
L10:
  mov    $0x0,%eax
  call   <endgrent@plt>
  cmpq   $0x1,0x0(%rbp)
  sbb    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getgrnam_r(const char *name, struct group *res, char *buf, size_t buflen, struct group **res_sig) {
  while (!getgrent_r(res, buf, buflen, res_sig))
    if (!strcmp(name, res->gr_name))
      goto ok;
  *res_sig = 0;
ok:
  endgrent();
  return *res_sig ? 0 : -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getgrnam_r>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L22
  nopl   (%rax)
L28:
  mov    (%rbx),%esi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L1
L22:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <getgrent_r@plt>
  test   %eax,%eax
  je     L28
  movq   $0x0,0x0(%rbp)
L1:
  xor    %eax,%eax
  call   <endgrent@plt>
  cmpq   $0x1,0x0(%rbp)
  pop    %rbx
  sbb    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getgrnam_r(const char *name, struct group *res, char *buf, size_t buflen, struct group **res_sig) {
  while (!getgrent_r(res, buf, buflen, res_sig))
    if (!strcmp(name, res->gr_name))
      goto ok;
  *res_sig = 0;
ok:
  endgrent();
  return *res_sig ? 0 : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getgrnam_r>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L18
  nopl   (%rax)
L2:
  mov    (%rbx),%esi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L8
L18:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <getgrent_r@plt>
  test   %eax,%eax
  je     L2
  movq   $0x0,0x0(%rbp)
L8:
  xor    %eax,%eax
  call   <endgrent@plt>
  cmpq   $0x1,0x0(%rbp)
  pop    %rbx
  sbb    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getgrnam_r(const char *name, struct group *res, char *buf, size_t buflen, struct group **res_sig) {
  while (!getgrent_r(res, buf, buflen, res_sig))
    if (!strcmp(name, res->gr_name))
      goto ok;
  *res_sig = 0;
ok:
  endgrent();
  return *res_sig ? 0 : -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_fat_16_fs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x36,%esi
  mov    %rax,%rdi
  call   <contains_data@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: FAT16   

assistant: ```c
int is_fat_16_fs(FILE *fp) {
  char *szMagic = "FAT16   ";
  return contains_data(fp, 0x36, szMagic, strlen(szMagic));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_fat_16_fs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %rbp,%rdx
  mov    $0x36,%esi
  mov    %rbx,%rdi
  call   <contains_data@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: FAT16   

assistant: ```c
int is_fat_16_fs(FILE *fp) {
  char *szMagic = "FAT16   ";
  return contains_data(fp, 0x36, szMagic, strlen(szMagic));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_fat_16_fs>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  mov    $0x36,%esi
  pop    %r12
  jmp    1070 <contains_data@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: FAT16   

assistant: ```c
int is_fat_16_fs(FILE *fp) {
  char *szMagic = "FAT16   ";
  return contains_data(fp, 0x36, szMagic, strlen(szMagic));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_fat_16_fs>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  mov    $0x36,%esi
  pop    %r12
  jmp    1070 <contains_data@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: FAT16   

assistant: ```c
int is_fat_16_fs(FILE *fp) {
  char *szMagic = "FAT16   ";
  return contains_data(fp, 0x36, szMagic, strlen(szMagic));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_sbrk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D27(%rip),%rbp
  mov    %rsp,%rax
  mov    %rax,(%rsp)
  movslq %edi,%rbx
  lea    0x0(%rbp,%rbx,1),%rdx
  cmp    %rdx,%rax
  jb     L9
L12:
  add    %rbx,D0(%rip)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    $0x1a,%edx
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L12
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Heap and stack collision


assistant: ```c
char *_sbrk(int adj) {
  extern char end[];
  static char *heap = end;
  char *rv = heap;
  char *sp = (char *)&sp;
  if (heap + adj > sp) {
    write(1, "Heap and stack collision\n", sizeof "Heap and stack collision\n");
    abort();
  }
  heap += adj;
  return rv;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_sbrk>:
  endbr64
  push   %r12
  push   %rbx
  movslq %edi,%rbx
  sub    $0x18,%rsp
  mov    D2(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    (%r12,%rbx,1),%rax
  mov    %rdx,(%rsp)
  cmp    %rdx,%rax
  ja     L3
L17:
  mov    %rax,D21(%rip)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x1a,%edx
  lea    D21(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  call   <abort@plt>
  mov    D21(%rip),%rax
  add    %rbx,%rax
  jmp    L17
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type_infered: string

tool: D21: Heap and stack collision


assistant: ```c
char *_sbrk(int adj) {
  extern char end[];
  static char *heap = end;
  char *rv = heap;
  char *sp = (char *)&sp;
  if (heap + adj > sp) {
    write(1, "Heap and stack collision\n", sizeof "Heap and stack collision\n");
    abort();
  }
  heap += adj;
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_sbrk>:
  endbr64
  push   %r12
  push   %rbx
  movslq %edi,%rbx
  sub    $0x18,%rsp
  mov    D37(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    (%r12,%rbx,1),%rax
  mov    %rdx,(%rsp)
  cmp    %rdx,%rax
  ja     L4
L17:
  mov    %rax,D36(%rip)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1a,%edx
  lea    D36(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  call   <abort@plt>
  mov    D36(%rip),%rax
  add    %rbx,%rax
  jmp    L17
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D36
type_infered: string

tool: D36: Heap and stack collision


assistant: ```c
char *_sbrk(int adj) {
  extern char end[];
  static char *heap = end;
  char *rv = heap;
  char *sp = (char *)&sp;
  if (heap + adj > sp) {
    write(1, "Heap and stack collision\n", sizeof "Heap and stack collision\n");
    abort();
  }
  heap += adj;
  return rv;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x418(%rbp)
  jmp    L2
L15:
  movl   $0x0,-0x424(%rbp)
  movl   $0x0,-0x41c(%rbp)
  jmp    L53
L17:
  mov    -0x424(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  cmp    $0x9,%al
  jne    L49
  mov    -0x418(%rbp),%edx
  mov    -0x41c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CalculateNumberOfSpaces@plt>
  mov    %eax,-0x414(%rbp)
  movl   $0x0,-0x420(%rbp)
  jmp    L76
L10:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x41c(%rbp)
  addl   $0x1,-0x420(%rbp)
L76:
  mov    -0x420(%rbp),%eax
  cmp    -0x414(%rbp),%eax
  jl     L10
  jmp    L74
L49:
  mov    -0x424(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x41c(%rbp)
L74:
  addl   $0x1,-0x424(%rbp)
L53:
  mov    -0x424(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L17
L2:
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jg     L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

assistant: ```c
int main(void) {
  char Buffer[1024];
  int TabSize = 5;
  int i, j, k, l;
  while (getline(Buffer, 1024) > 0) {
    for (i = 0, l = 0; Buffer[i] != '\0'; i++) {
      if (Buffer[i] == '\t') {
        j = CalculateNumberOfSpaces(l, TabSize);
        for (k = 0; k < j; k++) {
          putchar(' ');
          l++;
        }
      } else {
        putchar(Buffer[i]);
        l++;
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
L51:
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jle    L49
  movzbl (%rsp),%edi
  lea    0x1(%rsp),%rbp
  mov    $0x0,%r12d
  test   %dil,%dil
  jne    L18
  jmp    L51
L64:
  mov    $0x5,%esi
  mov    %r12d,%edi
  call   <CalculateNumberOfSpaces@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L53
  mov    $0x0,%ebx
L66:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jne    L66
  add    %ebx,%r12d
L53:
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edi
  test   %dil,%dil
  je     L51
L18:
  cmp    $0x9,%dil
  je     L64
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  jmp    L53
L49:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char Buffer[1024];
  int TabSize = 5;
  int i, j, k, l;
  while (getline(Buffer, 1024) > 0) {
    for (i = 0, l = 0; Buffer[i] != '\0'; i++) {
      if (Buffer[i] == '\t') {
        j = CalculateNumberOfSpaces(l, TabSize);
        for (k = 0; k < j; k++) {
          putchar(' ');
          l++;
        }
      } else {
        putchar(Buffer[i]);
        l++;
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  nopl   0x0(%rax)
L79:
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jle    L77
  movsbl (%rsp),%edi
  lea    0x1(%rsp),%rbp
  xor    %r12d,%r12d
  test   %dil,%dil
  jne    L1
  jmp    L79
  nopl   (%rax)
L85:
  call   <putchar@plt>
  add    $0x1,%r12d
L26:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L79
L1:
  cmp    $0x9,%dil
  jne    L85
  mov    $0x5,%esi
  mov    %r12d,%edi
  call   <CalculateNumberOfSpaces@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L26
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L52:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r14d
  jne    L52
  add    %r14d,%r12d
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L77:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L89:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char Buffer[1024];
  int TabSize = 5;
  int i, j, k, l;
  while (getline(Buffer, 1024) > 0) {
    for (i = 0, l = 0; Buffer[i] != '\0'; i++) {
      if (Buffer[i] == '\t') {
        j = CalculateNumberOfSpaces(l, TabSize);
        for (k = 0; k < j; k++) {
          putchar(' ');
          l++;
        }
      } else {
        putchar(Buffer[i]);
        l++;
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  nopl   0x0(%rax)
L13:
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jle    L41
  movsbl (%rsp),%edi
  lea    0x1(%rsp),%rbp
  xor    %r12d,%r12d
  test   %dil,%dil
  jne    L55
  jmp    L13
  nopl   (%rax)
L6:
  call   <putchar@plt>
  add    $0x1,%r12d
L56:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L13
L55:
  cmp    $0x9,%dil
  jne    L6
  mov    $0x5,%esi
  mov    %r12d,%edi
  call   <CalculateNumberOfSpaces@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L56
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r14d
  jne    L12
  add    %r14d,%r12d
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L41:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char Buffer[1024];
  int TabSize = 5;
  int i, j, k, l;
  while (getline(Buffer, 1024) > 0) {
    for (i = 0, l = 0; Buffer[i] != '\0'; i++) {
      if (Buffer[i] == '\t') {
        j = CalculateNumberOfSpaces(l, TabSize);
        for (k = 0; k < j; k++) {
          putchar(' ');
          l++;
        }
      } else {
        putchar(Buffer[i]);
        l++;
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__syscall2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    %rdx,%rbx
  int    $0x95
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long __syscall2(long n, long a1, long a2) {
  long __ret;
  __asm("int $0x95" : "=a"(__ret) : "a"(n), "b"(a1), "c"(a2) : "memory");
  return __ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__syscall2>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %rdx,%rcx
  int    $0x95
  pop    %rbx
  ret
```

assistant: ```c
long __syscall2(long n, long a1, long a2) {
  long __ret;
  __asm("int $0x95" : "=a"(__ret) : "a"(n), "b"(a1), "c"(a2) : "memory");
  return __ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__syscall2>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %rdx,%rcx
  int    $0x95
  pop    %rbx
  ret
```

assistant: ```c
long __syscall2(long n, long a1, long a2) {
  long __ret;
  __asm("int $0x95" : "=a"(__ret) : "a"(n), "b"(a1), "c"(a2) : "memory");
  return __ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__syscall2>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %rdx,%rcx
  int    $0x95
  pop    %rbx
  ret
```

assistant: ```c
long __syscall2(long n, long a1, long a2) {
  long __ret;
  __asm("int $0x95" : "=a"(__ret) : "a"(n), "b"(a1), "c"(a2) : "memory");
  return __ret;
}
```