ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<wpspinchecksum>:
  endbr64
  mov    D4(%rip),%r8d
  mov    %edi,%ecx
  test   %edi,%edi
  je     L6
  mov    $0xcccccccd,%r9d
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ecx,%eax
  mov    %ecx,%esi
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  mov    %eax,%edx
  imul   %r9,%rdx
  lea    (%rsi,%rsi,2),%esi
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edi
  add    %edi,%edi
  sub    %edi,%eax
  add    %esi,%eax
  add    %eax,%r8d
  mov    %ecx,%eax
  mov    %edx,%ecx
  cmp    $0x63,%eax
  ja     L0
  mov    %r8d,D14(%rip)
L6:
  movslq %r8d,%rax
  mov    %r8d,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    $0xcccccccd,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %r8d,%eax
  add    $0xa,%eax
  mov    %rax,%rcx
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  mov    %ecx,%eax
  add    %edx,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
unsigned int wpspinchecksum(unsigned int pin) {
  static int accum = 0;
  while (pin) {
    accum += 3 * (pin % 10);
    pin /= 10;
    accum += pin % 10;
    pin /= 10;
  }
  return (10 - accum % 10) % 10;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wpspinchecksum>:
  endbr64
  mov    D4(%rip),%r8d
  mov    %edi,%ecx
  test   %edi,%edi
  je     L5
  mov    $0xcccccccd,%r9d
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ecx,%eax
  mov    %ecx,%esi
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  mov    %eax,%edx
  imul   %r9,%rdx
  lea    (%rsi,%rsi,2),%esi
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edi
  add    %edi,%edi
  sub    %edi,%eax
  add    %esi,%eax
  add    %eax,%r8d
  mov    %ecx,%eax
  mov    %edx,%ecx
  cmp    $0x63,%eax
  ja     L10
  mov    %r8d,D8(%rip)
L5:
  movslq %r8d,%rax
  mov    %r8d,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    $0xcccccccd,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %r8d,%eax
  add    $0xa,%eax
  mov    %rax,%rcx
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  mov    %ecx,%eax
  add    %edx,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
unsigned int wpspinchecksum(unsigned int pin) {
  static int accum = 0;
  while (pin) {
    accum += 3 * (pin % 10);
    pin /= 10;
    accum += pin % 10;
    pin /= 10;
  }
  return (10 - accum % 10) % 10;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<generic_fls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x20,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L58
L15:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ax
  test   %eax,%eax
  jne    L11
  shll   $0x10,-0x14(%rbp)
  subl   $0x10,-0x4(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  and    $0xff000000,%eax
  test   %eax,%eax
  jne    L44
  shll   $0x8,-0x14(%rbp)
  subl   $0x8,-0x4(%rbp)
L44:
  mov    -0x14(%rbp),%eax
  and    $0xf0000000,%eax
  test   %eax,%eax
  jne    L43
  shll   $0x4,-0x14(%rbp)
  subl   $0x4,-0x4(%rbp)
L43:
  mov    -0x14(%rbp),%eax
  and    $0xc0000000,%eax
  test   %eax,%eax
  jne    L47
  shll   $0x2,-0x14(%rbp)
  subl   $0x2,-0x4(%rbp)
L47:
  cmpl   $0x0,-0x14(%rbp)
  js     L57
  shll   -0x14(%rbp)
  subl   $0x1,-0x4(%rbp)
L57:
  mov    -0x4(%rbp),%eax
L58:
  pop    %rbp
  ret
```

assistant: ```c
int generic_fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<generic_fls>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L17
  mov    $0x20,%eax
  test   $0xffff0000,%edi
  jne    L11
  shl    $0x10,%edi
  mov    $0x10,%eax
L11:
  test   $0xff000000,%edi
  jne    L28
  shl    $0x8,%edi
  sub    $0x8,%eax
L28:
  test   $0xf0000000,%edi
  jne    L44
  shl    $0x4,%edi
  sub    $0x4,%eax
L44:
  test   $0xc0000000,%edi
  jne    L9
  shl    $0x2,%edi
  sub    $0x2,%eax
L9:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L17:
  ret
```

assistant: ```c
int generic_fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<generic_fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L37
  mov    $0x20,%eax
  test   $0xffff0000,%edi
  jne    L0
  shl    $0x10,%edi
  mov    $0x10,%eax
L0:
  test   $0xff000000,%edi
  jne    L48
  shl    $0x8,%edi
  sub    $0x8,%eax
L48:
  test   $0xf0000000,%edi
  jne    L44
  shl    $0x4,%edi
  sub    $0x4,%eax
L44:
  test   $0xc0000000,%edi
  jne    L18
  shl    $0x2,%edi
  sub    $0x2,%eax
L18:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L37:
  ret
```

assistant: ```c
int generic_fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<generic_fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L17
  test   $0xffff0000,%edi
  je     L52
  mov    $0x18,%edx
  mov    $0x20,%eax
L55:
  test   $0xff000000,%edi
  jne    L36
  shl    $0x8,%edi
  mov    %edx,%eax
L36:
  test   $0xf0000000,%edi
  jne    L35
  shl    $0x4,%edi
  sub    $0x4,%eax
L35:
  test   $0xc0000000,%edi
  jne    L3
  shl    $0x2,%edi
  sub    $0x2,%eax
L3:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L17:
  ret
  nop
L52:
  shl    $0x10,%edi
  mov    $0x8,%edx
  mov    $0x10,%eax
  jmp    L55
```

assistant: ```c
int generic_fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<value_cmp_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int value_cmp_int(const void *pv1, const void *pv2) {
  int v1 = *(int *)pv1;
  int v2 = *(int *)pv2;
  return v1 - v2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<value_cmp_int>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int value_cmp_int(const void *pv1, const void *pv2) {
  int v1 = *(int *)pv1;
  int v2 = *(int *)pv2;
  return v1 - v2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<value_cmp_int>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int value_cmp_int(const void *pv1, const void *pv2) {
  int v1 = *(int *)pv1;
  int v2 = *(int *)pv2;
  return v1 - v2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<value_cmp_int>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int value_cmp_int(const void *pv1, const void *pv2) {
  int v1 = *(int *)pv1;
  int v2 = *(int *)pv2;
  return v1 - v2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inc_seq_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  movl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int inc_seq_num(unsigned int seq) {
  seq++;
  if (seq == 0)
    seq = 1;
  return (seq);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inc_seq_num>:
  endbr64
  lea    0x1(%rdi),%eax
  test   %eax,%eax
  mov    $0x1,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
unsigned int inc_seq_num(unsigned int seq) {
  seq++;
  if (seq == 0)
    seq = 1;
  return (seq);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inc_seq_num>:
  endbr64
  lea    0x1(%rdi),%eax
  mov    $0x1,%edx
  test   %eax,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
unsigned int inc_seq_num(unsigned int seq) {
  seq++;
  if (seq == 0)
    seq = 1;
  return (seq);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inc_seq_num>:
  endbr64
  lea    0x1(%rdi),%eax
  mov    $0x1,%edx
  test   %eax,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
unsigned int inc_seq_num(unsigned int seq) {
  seq++;
  if (seq == 0)
    seq = 1;
  return (seq);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SIM_power_transreson>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    %esi,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L4
  movsd  D11(%rip),%xmm0
  jmp    L16
L4:
  movsd  D4(%rip),%xmm0
L16:
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x20(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type: byte[8]
name: extract_symbolic_data
arguments: label: D4
type: byte[8]

tool: {"D11": [0x99,0x99,0x99,0x99,0x19,0x96,0x8a,0x40]}

tool: {"D4": [0xff,0xff,0xff,0xff,0xff,0x9f,0x9e,0x40]}

assistant: ```c
double SIM_power_transreson(width, nchannel, stack)
double width;
int nchannel;
int stack;
{
  double restrans;
  restrans = (nchannel) ? (9723 * 0.0875) : (22400 * 0.0875);
  return (stack * restrans / width);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SIM_power_transreson>:
  endbr64
  movsd  D12(%rip),%xmm2
  test   %edi,%edi
  je     L5
  movsd  D11(%rip),%xmm2
L5:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D11
type: byte[8]

tool: {"D12": [0xff,0xff,0xff,0xff,0xff,0x9f,0x9e,0x40]}

tool: {"D11": [0x99,0x99,0x99,0x99,0x19,0x96,0x8a,0x40]}

assistant: ```c
double SIM_power_transreson(width, nchannel, stack)
double width;
int nchannel;
int stack;
{
  double restrans;
  restrans = (nchannel) ? (9723 * 0.0875) : (22400 * 0.0875);
  return (stack * restrans / width);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SIM_power_transreson>:
  endbr64
  movsd  D3(%rip),%xmm2
  test   %edi,%edi
  je     L8
  movsd  D6(%rip),%xmm2
L8:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: byte[8]
name: disassemble_data
arguments: tag: D6
data_type: byte[8]

tool: {"D3": [0xff,0xff,0xff,0xff,0xff,0x9f,0x9e,0x40]}

tool: {"D6": [0x99,0x99,0x99,0x99,0x19,0x96,0x8a,0x40]}

assistant: ```c
double SIM_power_transreson(width, nchannel, stack)
double width;
int nchannel;
int stack;
{
  double restrans;
  restrans = (nchannel) ? (9723 * 0.0875) : (22400 * 0.0875);
  return (stack * restrans / width);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SIM_power_transreson>:
  endbr64
  movsd  D3(%rip),%xmm2
  test   %edi,%edi
  je     L9
  movsd  D8(%rip),%xmm2
L9:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: byte[8]
name: parse_data
arguments: tag: D8
datatype: byte[8]

tool: {"D3": [0xff,0xff,0xff,0xff,0xff,0x9f,0x9e,0x40]}

tool: {"D8": [0x99,0x99,0x99,0x99,0x19,0x96,0x8a,0x40]}

assistant: ```c
double SIM_power_transreson(width, nchannel, stack)
double width;
int nchannel;
int stack;
{
  double restrans;
  restrans = (nchannel) ? (9723 * 0.0875) : (22400 * 0.0875);
  return (stack * restrans / width);
}
```
user: Translate the below assembly code into C programming language:

```asm
<syscon_number_of_quaddobl_polynomials>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x17e,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_number_of_quaddobl_polynomials(int *length) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(382, length, b, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<syscon_number_of_quaddobl_polynomials>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x17e,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int syscon_number_of_quaddobl_polynomials(int *length) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(382, length, b, c);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<syscon_number_of_quaddobl_polynomials>:
  endbr64
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x17e,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int syscon_number_of_quaddobl_polynomials(int *length) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(382, length, b, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<syscon_number_of_quaddobl_polynomials>:
  endbr64
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x17e,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int syscon_number_of_quaddobl_polynomials(int *length) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(382, length, b, c);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sig_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D1
datatype: string

tool: D16: Called with signal %d


tool: D1: done handling signal %d


assistant: ```c
extern void sig_handler(int signum) {
  printf("Called with signal %d\n", signum);
  sleep(signum);
  printf("done handling signal %d\n", signum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sig_handler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string
name: unpack_data
arguments: tag: D14
type_infered: string

tool: D2: Called with signal %d


tool: D14: done handling signal %d


assistant: ```c
extern void sig_handler(int signum) {
  printf("Called with signal %d\n", signum);
  sleep(signum);
  printf("done handling signal %d\n", signum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sig_handler>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <sleep@plt>
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string

tool: D0: Called with signal %d


tool: D1: done handling signal %d


assistant: ```c
extern void sig_handler(int signum) {
  printf("Called with signal %d\n", signum);
  sleep(signum);
  printf("done handling signal %d\n", signum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sig_handler>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <sleep@plt>
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D1: Called with signal %d


tool: D2: done handling signal %d


assistant: ```c
extern void sig_handler(int signum) {
  printf("Called with signal %d\n", signum);
  sleep(signum);
  printf("done handling signal %d\n", signum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__make_mantissa_base10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L50:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x2f,-0x9(%rbp)
  jle    L57
  cmpb   $0x39,-0x9(%rbp)
  jg     L57
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  movsbq -0x9(%rbp),%rax
  add    %rdx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L9
L57:
  mov    $0x0,%eax
  jmp    L0
L9:
  cmpq   $0x0,-0x18(%rbp)
  jne    L50
  mov    -0x8(%rbp),%rax
L0:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long __make_mantissa_base10(const char *tagp) {
  unsigned long long r = 0;
  while (tagp) {
    char tmp = *tagp;
    if (tmp >= '0' && tmp <= '9')
      r = (r * 10u) + tmp - '0';
    else
      return 0;
    ++tagp;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<__make_mantissa_base10>:
  endbr64
  test   %rdi,%rdi
  jne    L5
  jmp    L17
L2:
  add    $0x1,%rdi
L5:
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L2
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long long __make_mantissa_base10(const char *tagp) {
  unsigned long long r = 0;
  while (tagp) {
    char tmp = *tagp;
    if (tmp >= '0' && tmp <= '9')
      r = (r * 10u) + tmp - '0';
    else
      return 0;
    ++tagp;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__make_mantissa_base10>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long long __make_mantissa_base10(const char *tagp) {
  unsigned long long r = 0;
  while (tagp) {
    char tmp = *tagp;
    if (tmp >= '0' && tmp <= '9')
      r = (r * 10u) + tmp - '0';
    else
      return 0;
    ++tagp;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__make_mantissa_base10>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long long __make_mantissa_base10(const char *tagp) {
  unsigned long long r = 0;
  while (tagp) {
    char tmp = *tagp;
    if (tmp >= '0' && tmp <= '9')
      r = (r * 10u) + tmp - '0';
    else
      return 0;
    ++tagp;
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%eax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L24
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
L24:
  movl   $0x0,-0x1c(%rbp)
  jmp    L0
L17:
  mov    -0x28(%rbp),%eax
  cltq
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L27
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <perror@plt>
L27:
  addl   $0x1,-0x1c(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type_infered: string
name: unpack_data
arguments: label: D13
type_infered: string

tool: D16: alloc error in cmatrix

tool: D13: alloc error in cmatric. 2

assistant: ```c
char **cmatrix(nsam, len)
int nsam, len;
{
  int i;
  char **m;
  if (!(m = (char **)malloc((unsigned)(nsam * sizeof(char *)))))
    perror("alloc error in cmatrix");
  for (i = 0; i < nsam; i++) {
    if (!(m[i] = (char *)malloc((unsigned)(len * sizeof(char)))))
      perror("alloc error in cmatric. 2");
  }
  return (m);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmatrix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x0(,%rdi,8),%edi
  mov    %edi,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L1
L7:
  test   %r12d,%r12d
  jle    L12
  mov    %r13,%rbx
  mov    %r12d,%r12d
  lea    0x0(%r13,%r12,8),%r12
  lea    D1(%rip),%r14
L11:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L19
L32:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L11
L12:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <perror@plt>
  jmp    L7
L19:
  mov    %r14,%rdi
  call   <perror@plt>
  jmp    L32
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string
name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D1: alloc error in cmatric. 2

tool: D4: alloc error in cmatrix

assistant: ```c
char **cmatrix(nsam, len)
int nsam, len;
{
  int i;
  char **m;
  if (!(m = (char **)malloc((unsigned)(nsam * sizeof(char *)))))
    perror("alloc error in cmatrix");
  for (i = 0; i < nsam; i++) {
    if (!(m[i] = (char *)malloc((unsigned)(len * sizeof(char)))))
      perror("alloc error in cmatric. 2");
  }
  return (m);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmatrix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L36
L11:
  test   %ebp,%ebp
  jle    L15
  mov    %r12,%r14
  lea    (%r12,%rbp,8),%rbp
  lea    D14(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  je     L40
L22:
  add    $0x8,%r14
  cmp    %rbp,%r14
  jne    L26
L15:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  mov    %r13,%rdi
  call   <perror@plt>
  jmp    L22
L36:
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <perror@plt>
  jmp    L11
```

tool_calls: name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D14: alloc error in cmatric. 2

tool: D11: alloc error in cmatrix

assistant: ```c
char **cmatrix(nsam, len)
int nsam, len;
{
  int i;
  char **m;
  if (!(m = (char **)malloc((unsigned)(nsam * sizeof(char *)))))
    perror("alloc error in cmatrix");
  for (i = 0; i < nsam; i++) {
    if (!(m[i] = (char *)malloc((unsigned)(len * sizeof(char)))))
      perror("alloc error in cmatric. 2");
  }
  return (m);
}
```