ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<thread_function>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xc8,%ebx
  lea    D0(%rip),%rbp
L0:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: Thread says hi! ---> thread


assistant: ```c
void *thread_function(void *arg) {
  int i;
  for (i = 0; i < 200; i++) {
    printf("Thread says hi! ---> thread\n");
    sleep(1);
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread_function>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0xc8,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: Thread says hi! ---> thread


assistant: ```c
void *thread_function(void *arg) {
  int i;
  for (i = 0; i < 200; i++) {
    printf("Thread says hi! ---> thread\n");
    sleep(1);
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thread_function>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0xc8,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string

tool: D3: Thread says hi! ---> thread


assistant: ```c
void *thread_function(void *arg) {
  int i;
  for (i = 0; i < 200; i++) {
    printf("Thread says hi! ---> thread\n");
    sleep(1);
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_184_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_184_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D ^ T;
  stk2 = S & stk3;
  stk1 = T ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rop3_184_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  xor    (%rdi),%sil
  and    %eax,%esi
  xor    %edx,%esi
  mov    %eax,%edx
  not    %edx
  and    %edx,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_184_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D ^ T;
  stk2 = S & stk3;
  stk1 = T ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What is the c source code of the assembly code below?

```asm
<rop3_184_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  xor    %edx,%esi
  and    %eax,%esi
  xor    %edx,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_184_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D ^ T;
  stk2 = S & stk3;
  stk1 = T ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rop3_184_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  xor    %edx,%esi
  and    %eax,%esi
  xor    %edx,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_184_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D ^ T;
  stk2 = S & stk3;
  stk1 = T ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <test_cosup_poly_system@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: 
Calling the blackbox polynomial system solver of PHCpack


assistant: ```c
int main(void) {
  printf("\nCalling the blackbox polynomial system solver of PHCpack\n");
  test_cosup_poly_system();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <test_cosup_poly_system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: 
Calling the blackbox polynomial system solver of PHCpack


assistant: ```c
int main(void) {
  printf("\nCalling the blackbox polynomial system solver of PHCpack\n");
  test_cosup_poly_system();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <test_cosup_poly_system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string

tool: D8: 
Calling the blackbox polynomial system solver of PHCpack


assistant: ```c
int main(void) {
  printf("\nCalling the blackbox polynomial system solver of PHCpack\n");
  test_cosup_poly_system();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <test_cosup_poly_system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: 
Calling the blackbox polynomial system solver of PHCpack


assistant: ```c
int main(void) {
  printf("\nCalling the blackbox polynomial system solver of PHCpack\n");
  test_cosup_poly_system();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_assert_false>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <print_error@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_fail@plt>
L0:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7:                 expected '%s' to be false


assistant: ```c
void _assert_false(const unsigned long long result, const char *const expression, const char *const file, const int line) {
  if (!result) {
    print_error("                "
                "expected '%s' to be false\n",
                expression);
    _fail(file, line);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_assert_false>:
  endbr64
  test   %rdi,%rdi
  je     L7
  ret
L7:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  lea    D7(%rip),%rdi
  call   <print_error@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_fail@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D7
data_type: string

tool: D7:                 expected '%s' to be false


assistant: ```c
void _assert_false(const unsigned long long result, const char *const expression, const char *const file, const int line) {
  if (!result) {
    print_error("                "
                "expected '%s' to be false\n",
                expression);
    _fail(file, line);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_assert_false>:
  endbr64
  test   %rdi,%rdi
  je     L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  push   %r12
  lea    D7(%rip),%rdi
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <print_error@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7:                 expected '%s' to be false


assistant: ```c
void _assert_false(const unsigned long long result, const char *const expression, const char *const file, const int line) {
  if (!result) {
    print_error("                "
                "expected '%s' to be false\n",
                expression);
    _fail(file, line);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_assert_false>:
  endbr64
  test   %rdi,%rdi
  je     L3
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  push   %r12
  lea    D1(%rip),%rdi
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <print_error@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1:                 expected '%s' to be false


assistant: ```c
void _assert_false(const unsigned long long result, const char *const expression, const char *const file, const int line) {
  if (!result) {
    print_error("                "
                "expected '%s' to be false\n",
                expression);
    _fail(file, line);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<log_auth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rsi
  mov    %edx,%ecx
  mov    $0x41,%edx
  mov    %eax,%edi
  call   <log_entry@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_auth(char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  log_entry(stderr, msg, 'A', ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log_auth>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    $0x41,%edx
  mov    %rbx,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <log_entry@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void log_auth(char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  log_entry(stderr, msg, 'A', ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<log_auth>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%ecx
  mov    %rbp,%rsi
  mov    $0x41,%edx
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <log_entry@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_auth(char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  log_entry(stderr, msg, 'A', ap);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_auth>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%ecx
  mov    %rbp,%rsi
  mov    $0x41,%edx
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <log_entry@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_auth(char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  log_entry(stderr, msg, 'A', ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movss  D37(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D47(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x28(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %eax,-0x20(%rbp)
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  pxor   %xmm2,%xmm2
  cvtsi2ssl -0x20(%rbp),%xmm2
  movd   %xmm2,%eax
  movd   %eax,%xmm0
  call   <printid@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0x20(%rbp)
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  pxor   %xmm3,%xmm3
  cvtsi2ssl -0x20(%rbp),%xmm3
  movd   %xmm3,%eax
  movd   %eax,%xmm0
  call   <printid@plt>
  movss  -0x10(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <printid@plt>
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <printid@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D37
datatype: f32
name: disassemble_data
arguments: tag: D47
datatype: f32
name: disassemble_data
arguments: tag: D51
datatype: string
name: disassemble_data
arguments: tag: D40
datatype: string
name: disassemble_data
arguments: tag: D21
datatype: string
name: disassemble_data
arguments: tag: D15
datatype: string

tool: D37: 2.6

tool: D47: 1.3

tool: D51: c  0

tool: D40: c  2

tool: D21: k  1.300000

tool: D15: k  2.000000

assistant: ```c
int main() {
  int a = 2, b = 3, c;
  int d[2] = {4, 2};
  float k;
  float m[2] = {2.6, 1.3};
  c = a / b;
  print("c  0");
  printid(c);
  c = d[0] / d[1];
  print("c  2");
  printid(c);
  k = m[0] / d[1];
  print("k  1.300000");
  printid(k);
  k = m[0] / m[1];
  print("k  2.000000");
  printid(k);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D63(%rip),%rdi
  call   <print@plt>
  pxor   %xmm0,%xmm0
  call   <printid@plt>
  lea    D13(%rip),%rdi
  call   <print@plt>
  movss  D28(%rip),%xmm0
  call   <printid@plt>
  lea    D40(%rip),%rdi
  call   <print@plt>
  movss  D25(%rip),%xmm0
  call   <printid@plt>
  lea    D47(%rip),%rdi
  call   <print@plt>
  movss  D28(%rip),%xmm0
  call   <printid@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D63
data_type: string
name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D28
data_type: byte[4]
name: unpack_data
arguments: label: D40
data_type: string
name: unpack_data
arguments: label: D25
data_type: f32
name: unpack_data
arguments: label: D47
data_type: string

tool: D63: c  0

tool: D13: c  2

tool: {"D28": [0x00,0x00,0x00,0x40]}

tool: D40: k  1.300000

tool: D25: 1.3

tool: D47: k  2.000000

assistant: ```c
int main() {
  int a = 2, b = 3, c;
  int d[2] = {4, 2};
  float k;
  float m[2] = {2.6, 1.3};
  c = a / b;
  print("c  0");
  printid(c);
  c = d[0] / d[1];
  print("c  2");
  printid(c);
  k = m[0] / d[1];
  print("k  1.300000");
  printid(k);
  k = m[0] / m[1];
  print("k  2.000000");
  printid(k);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <print@plt>
  pxor   %xmm0,%xmm0
  call   <printid@plt>
  lea    D36(%rip),%rdi
  call   <print@plt>
  movss  D51(%rip),%xmm1
  movaps %xmm1,%xmm0
  call   <printid@plt>
  lea    D69(%rip),%rdi
  call   <print@plt>
  movss  D3(%rip),%xmm0
  call   <printid@plt>
  lea    D42(%rip),%rdi
  call   <print@plt>
  movss  D51(%rip),%xmm1
  movaps %xmm1,%xmm0
  call   <printid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D36
type_infered: string
name: read_data
arguments: data_label: D51
type_infered: byte[4]
name: read_data
arguments: data_label: D69
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: f32
name: read_data
arguments: data_label: D42
type_infered: string

tool: D21: c  0

tool: D36: c  2

tool: {"D51": [0x00,0x00,0x00,0x40]}

tool: D69: k  1.300000

tool: D3: 1.3

tool: D42: k  2.000000

assistant: ```c
int main() {
  int a = 2, b = 3, c;
  int d[2] = {4, 2};
  float k;
  float m[2] = {2.6, 1.3};
  c = a / b;
  print("c  0");
  printid(c);
  c = d[0] / d[1];
  print("c  2");
  printid(c);
  k = m[0] / d[1];
  print("k  1.300000");
  printid(k);
  k = m[0] / m[1];
  print("k  2.000000");
  printid(k);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D56(%rip),%rdi
  call   <print@plt>
  pxor   %xmm0,%xmm0
  call   <printid@plt>
  lea    D5(%rip),%rdi
  call   <print@plt>
  movss  D64(%rip),%xmm1
  movaps %xmm1,%xmm0
  call   <printid@plt>
  lea    D37(%rip),%rdi
  call   <print@plt>
  movss  D3(%rip),%xmm0
  call   <printid@plt>
  lea    D40(%rip),%rdi
  call   <print@plt>
  movss  D64(%rip),%xmm1
  movaps %xmm1,%xmm0
  call   <printid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D56
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D64
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_tag: D37
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D3
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D40
type_infered: string

tool: D56: c  0

tool: D5: c  2

tool: {"D64": [0x00,0x00,0x00,0x40]}

tool: D37: k  1.300000

tool: D3: 1.3

tool: D40: k  2.000000

assistant: ```c
int main() {
  int a = 2, b = 3, c;
  int d[2] = {4, 2};
  float k;
  float m[2] = {2.6, 1.3};
  c = a / b;
  print("c  0");
  printid(c);
  c = d[0] / d[1];
  print("c  2");
  printid(c);
  k = m[0] / d[1];
  print("k  1.300000");
  printid(k);
  k = m[0] / m[1];
  print("k  2.000000");
  printid(k);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L96
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L96:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L19
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L63
L55:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L80
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L29
L80:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L92
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L92
L29:
  addl   $0x1,-0x18(%rbp)
  addl   $0x2,-0x1c(%rbp)
  jmp    L63
L92:
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L63:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L55
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D20
type_infered: string

tool: D20: %d

assistant: ```c
int main() {
  int i, n, count;
  scanf("%d", &n);
  int *c = malloc(sizeof(int) * n);
  for (int c_i = 0; c_i < n; c_i++) {
    scanf("%d", &c[c_i]);
  }
  count = 0;
  i = 0;
  while (i <= n - 2) {
    if (c[i + 1] == 0 && c[i + 2] == 0 || c[i + 1] == 1 && c[i + 2] == 0) {
      count++;
      i = i + 2;
    } else {
      count++;
      i = i + 1;
    }
  }
  printf("%d", count);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L2
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D6(%rip),%r13
L1:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0x4(%rsp),%eax
  add    $0x4,%r12
  cmp    %ebp,%eax
  jg     L1
L2:
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L42
  mov    $0x1,%esi
  mov    $0x0,%edx
  jmp    L89
L54:
  mov    %esi,%eax
  add    $0x1,%edx
L72:
  add    $0x1,%esi
  cmp    %ecx,%edx
  jge    L85
L89:
  movslq %edx,%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdi
  cmpl   $0x1,(%rbx,%rax,4)
  ja     L54
  cmpl   $0x0,0x4(%rbx,%rdi,1)
  jne    L54
  mov    %esi,%eax
  add    $0x2,%edx
  jmp    L72
L42:
  mov    $0x0,%eax
L85:
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int main() {
  int i, n, count;
  scanf("%d", &n);
  int *c = malloc(sizeof(int) * n);
  for (int c_i = 0; c_i < n; c_i++) {
    scanf("%d", &c[c_i]);
  }
  count = 0;
  i = 0;
  while (i <= n - 2) {
    if (c[i + 1] == 0 && c[i + 2] == 0 || c[i + 1] == 1 && c[i + 2] == 0) {
      count++;
      i = i + 2;
    } else {
      count++;
      i = i + 1;
    }
  }
  printf("%d", count);
  return 0;
}
```