ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r13,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <free@plt>
```

assistant: ```c
void swap(void *a, void *b, size_t size) {
  void *tmp = malloc(size);
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
  free(tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<swap>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r13,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <free@plt>
```

assistant: ```c
void swap(void *a, void *b, size_t size) {
  void *tmp = malloc(size);
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
  free(tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getCurLongestPalindrom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L41
L49:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L53
  mov    $0x1,%eax
  jmp    L17
L53:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <isPalindrome@plt>
  test   %rax,%rax
  je     L34
  mov    -0x4(%rbp),%eax
  jmp    L17
L34:
  subl   $0x1,-0x4(%rbp)
L41:
  cmpl   $0x1,-0x4(%rbp)
  jg     L49
  mov    -0x4(%rbp),%eax
L17:
  leave
  ret
```

assistant: ```c
int getCurLongestPalindrom(const char *s, const int length, const int lmax) {
  int i = length;
  while (i > 1) {
    if (i < lmax)
      return 1;
    if (isPalindrome(s, i))
      return i;
    i--;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getCurLongestPalindrom>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x1,%esi
  jle    L73
  mov    %rdi,%r12
  mov    %edx,%ebp
  cmp    %edx,%esi
  jl     L39
L8:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <isPalindrome@plt>
  test   %rax,%rax
  jne    L3
  sub    $0x1,%ebx
  cmp    $0x1,%ebx
  je     L57
  cmp    %ebx,%ebp
  jle    L8
  mov    $0x1,%eax
  jmp    L81
L57:
  mov    %ebx,%eax
  jmp    L81
L73:
  mov    %esi,%eax
  jmp    L81
L39:
  mov    $0x1,%eax
  jmp    L81
L3:
  mov    %ebx,%eax
L81:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getCurLongestPalindrom(const char *s, const int length, const int lmax) {
  int i = length;
  while (i > 1) {
    if (i < lmax)
      return 1;
    if (isPalindrome(s, i))
      return i;
    i--;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getCurLongestPalindrom>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x1,%esi
  jle    L15
  mov    %rdi,%r12
  mov    %edx,%ebp
  cmp    %edx,%esi
  jge    L4
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L59:
  sub    $0x1,%ebx
  cmp    $0x1,%ebx
  je     L30
  cmp    %ebx,%ebp
  jg     L30
L4:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <isPalindrome@plt>
  test   %rax,%rax
  je     L59
L15:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getCurLongestPalindrom(const char *s, const int length, const int lmax) {
  int i = length;
  while (i > 1) {
    if (i < lmax)
      return 1;
    if (isPalindrome(s, i))
      return i;
    i--;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getCurLongestPalindrom>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x1,%esi
  jle    L35
  mov    %rdi,%r12
  mov    %edx,%ebp
  cmp    %edx,%esi
  jge    L18
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L48:
  sub    $0x1,%ebx
  cmp    $0x1,%ebx
  je     L53
  cmp    %ebx,%ebp
  jg     L53
L18:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <isPalindrome@plt>
  test   %rax,%rax
  je     L48
L35:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L53:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getCurLongestPalindrom(const char *s, const int length, const int lmax) {
  int i = length;
  while (i > 1) {
    if (i < lmax)
      return 1;
    if (isPalindrome(s, i))
      return i;
    i--;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<full_fsync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L0
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fsync@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L8
L0:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fsync@plt>
  mov    %eax,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int full_fsync(int fd, int fullSync, int dataOnly) {
  int rc;
  if (dataOnly) {
    rc = fsync(fd);
  } else {
    rc = fsync(fd);
  }
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<full_fsync>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L6
  call   <fsync@plt>
L8:
  add    $0x8,%rsp
  ret
L6:
  call   <fsync@plt>
  jmp    L8
```

assistant: ```c
int full_fsync(int fd, int fullSync, int dataOnly) {
  int rc;
  if (dataOnly) {
    rc = fsync(fd);
  } else {
    rc = fsync(fd);
  }
  return rc;
}
```
user: What is the c source code of the assembly code below:

```asm
<full_fsync>:
  endbr64
  jmp    1050 <fsync@plt>
```

assistant: ```c
int full_fsync(int fd, int fullSync, int dataOnly) {
  int rc;
  if (dataOnly) {
    rc = fsync(fd);
  } else {
    rc = fsync(fd);
  }
  return rc;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<full_fsync>:
  endbr64
  jmp    1050 <fsync@plt>
```

assistant: ```c
int full_fsync(int fd, int fullSync, int dataOnly) {
  int rc;
  if (dataOnly) {
    rc = fsync(fd);
  } else {
    rc = fsync(fd);
  }
  return rc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L2:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L57:
  cmpl   $0xc,-0x8(%rbp)
  jle    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L51:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L42:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <lah@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L42
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L55:
  cmpl   $0xc,-0xc(%rbp)
  jle    L51
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: string
name: disassemble_data
arguments: data_label: D32
type_infered: string
name: disassemble_data
arguments: data_label: D20
type_infered: string
name: disassemble_data
arguments: data_label: D25
type_infered: string

tool: D26: Unsigned Lah numbers: L(n, k):

tool: D48: n/k 

tool: D32: %10d 

tool: D20: %-3d

tool: D25: %11lld

assistant: ```c
int main() {
  int row, i;
  printf("Unsigned Lah numbers: L(n, k):\n");
  printf("n/k ");
  for (i = 0; i < 13; i++) {
    printf("%10d ", i);
  }
  printf("\n");
  for (row = 0; row < 13; row++) {
    printf("%-3d", row);
    for (i = 0; i < row + 1; i++) {
      uint64_t l = lah(row, i);
      printf("%11lld", l);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
L42:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xd,%ebx
  jne    L42
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebp
  lea    D29(%rip),%r13
  lea    D2(%rip),%r12
  jmp    L38
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    $0xd,%ebp
  je     L54
L38:
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  js     L18
  mov    $0x0,%ebx
L1:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <lah@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L1
  jmp    L18
L54:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D30
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D29
data_type: string
name: unpack_data
arguments: tag: D2
data_type: string

tool: D46: Unsigned Lah numbers: L(n, k):

tool: D30: n/k 

tool: D4: %10d 

tool: D29: %-3d

tool: D2: %11lld

assistant: ```c
int main() {
  int row, i;
  printf("Unsigned Lah numbers: L(n, k):\n");
  printf("n/k ");
  for (i = 0; i < 13; i++) {
    printf("%10d ", i);
  }
  printf("\n");
  for (row = 0; row < 13; row++) {
    printf("%-3d", row);
    for (i = 0; i < row + 1; i++) {
      uint64_t l = lah(row, i);
      printf("%11lld", l);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D45(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nop
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xd,%ebx
  jne    L1
  mov    $0xa,%edi
  mov    $0x1,%ebp
  lea    D6(%rip),%r14
  call   <putchar@plt>
  lea    D0(%rip),%r13
  nopl   0x0(%rax)
L12:
  lea    -0x1(%rbp),%r12d
  mov    %r14,%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  mov    %r12d,%esi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %ebx,%esi
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <lah@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L17
  mov    $0xa,%edi
  lea    0x1(%rbx),%ebp
  call   <putchar@plt>
  cmp    $0xd,%ebx
  jne    L12
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D28
type_infered: string
name: unpack_data
arguments: label: D45
type_infered: string
name: unpack_data
arguments: label: D26
type_infered: string
name: unpack_data
arguments: label: D6
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D28: Unsigned Lah numbers: L(n, k):

tool: D45: %10d 

tool: D26: n/k 

tool: D6: %-3d

tool: D0: %11lld

assistant: ```c
int main() {
  int row, i;
  printf("Unsigned Lah numbers: L(n, k):\n");
  printf("n/k ");
  for (i = 0; i < 13; i++) {
    printf("%10d ", i);
  }
  printf("\n");
  for (row = 0; row < 13; row++) {
    printf("%-3d", row);
    for (i = 0; i < row + 1; i++) {
      uint64_t l = lah(row, i);
      printf("%11lld", l);
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D11(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nop
L17:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xd,%ebx
  jne    L17
  mov    $0xa,%edi
  mov    $0x1,%ebp
  lea    D45(%rip),%r14
  call   <putchar@plt>
  lea    D47(%rip),%r13
  nopl   0x0(%rax)
L2:
  lea    -0x1(%rbp),%r12d
  mov    %r14,%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  mov    %r12d,%esi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%esi
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <lah@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L18
  mov    $0xa,%edi
  lea    0x1(%rbx),%ebp
  call   <putchar@plt>
  cmp    $0xd,%ebx
  jne    L2
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D11
data_type: string
name: read_data
arguments: tag: D15
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D45
data_type: string
name: read_data
arguments: tag: D47
data_type: string

tool: D11: Unsigned Lah numbers: L(n, k):

tool: D15: %10d 

tool: D26: n/k 

tool: D45: %-3d

tool: D47: %11lld

assistant: ```c
int main() {
  int row, i;
  printf("Unsigned Lah numbers: L(n, k):\n");
  printf("n/k ");
  for (i = 0; i < 13; i++) {
    printf("%10d ", i);
  }
  printf("\n");
  for (row = 0; row < 13; row++) {
    printf("%-3d", row);
    for (i = 0; i < row + 1; i++) {
      uint64_t l = lah(row, i);
      printf("%11lld", l);
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xb(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x9,%eax
  jle    L54
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jg     L54
  movsbl 0xd(%rsp),%edx
  sub    $0x30,%edx
  movsbl 0xe(%rsp),%eax
  sub    $0x30,%eax
  imul   $0xa,%edx,%ecx
  add    %eax,%ecx
  cmp    $0x34,%ecx
  ja     L21
  movabs $0x1ffe01ffe01ffe,%rsi
  shr    %cl,%rsi
  test   $0x1,%sil
  je     L21
  movsbl 0xc(%rsp),%esi
  movsbl 0xb(%rsp),%ecx
  lea    -0x90(%rcx,%rsi,2),%ecx
  lea    (%rcx,%rdx,4),%edx
  imul   $0x5,%eax,%eax
  lea    (%rax,%rdx,2),%ecx
  movsbl 0xf(%rsp),%eax
  sub    $0x30,%eax
  imul   $0xa,%eax,%eax
  add    %eax,%ecx
  movsbl 0x10(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x9,%eax,%eax
  add    %eax,%ecx
  movsbl 0x11(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x7,%eax,%eax
  add    %eax,%ecx
  movsbl 0x12(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x3,%eax,%eax
  add    %eax,%ecx
  movsbl 0x13(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x6,%eax,%eax
  add    %eax,%ecx
  mov    $0xb,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  cmp    $0xa,%edx
  mov    $0x0,%eax
  cmove  %eax,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movsbl 0x14(%rsp),%eax
  sub    $0x30,%eax
  cmp    %eax,%edx
  je     L49
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L54:
  lea    D43(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L21:
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L49:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D43
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: string

tool: D29: %s

tool: D43: 0

tool: D10: 1

assistant: ```c
int main() {
  char EGN[13];
  int month, ld;
  scanf("%s", EGN);
  if (strlen(EGN) < 10 || strlen(EGN) > 10) {
    printf("0");
    return 0;
  }
  month = (EGN[2] - '0') * 10 + (EGN[3] - '0');
  if ((month >= 1 && month <= 12) || (month >= 21 && month <= 32) || (month >= 41 && month <= 52)) {
    ld = ((EGN[0] - '0') * 2 + (EGN[1] - '0') * 4 + (EGN[2] - '0') * 8 + (EGN[3] - '0') * 5 + (EGN[4] - '0') * 10 + (EGN[5] - '0') * 9 + (EGN[6] - '0') * 7 + (EGN[7] - '0') * 3 + (EGN[8] - '0') * 6);
    if (ld % 11 == 10) {
      ld = 0;
    }
    if (ld % 11 != EGN[9] - '0') {
      printf("0");
      return 0;
    }
    printf("1");
    return 0;
  }
  printf("0");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xb(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x9,%eax
  jle    L45
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jg     L45
  movsbl 0xd(%rsp),%edx
  movsbl 0xe(%rsp),%eax
  sub    $0x30,%edx
  sub    $0x30,%eax
  imul   $0xa,%edx,%ecx
  add    %eax,%ecx
  cmp    $0x34,%ecx
  ja     L45
  movabs $0xffe001fe001fe001,%rsi
  sar    %cl,%rsi
  and    $0x1,%sil
  jne    L45
  movsbl 0xc(%rsp),%esi
  movsbl 0xb(%rsp),%ecx
  lea    (%rax,%rax,4),%eax
  lea    -0x90(%rcx,%rsi,2),%ecx
  mov    $0xb,%esi
  lea    (%rcx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%ecx
  movsbl 0xf(%rsp),%eax
  sub    $0x30,%eax
  imul   $0xa,%eax,%eax
  add    %eax,%ecx
  movsbl 0x10(%rsp),%eax
  sub    $0x30,%eax
  lea    (%rax,%rax,8),%eax
  add    %eax,%ecx
  movsbl 0x11(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x7,%eax,%eax
  add    %eax,%ecx
  movsbl 0x12(%rsp),%eax
  sub    $0x30,%eax
  lea    (%rax,%rax,2),%eax
  add    %eax,%ecx
  movsbl 0x13(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x6,%eax,%eax
  add    %eax,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %esi
  xor    %eax,%eax
  cmp    $0xa,%edx
  cmove  %eax,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movsbl 0x14(%rsp),%eax
  sub    $0x30,%eax
  cmp    %eax,%edx
  je     L29
L45:
  lea    D0(%rip),%rdi
  call   <printf@plt>
L60:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L29:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L60
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string
name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D17
type: string

tool: D2: %s

tool: D0: 0

tool: D17: 1

assistant: ```c
int main() {
  char EGN[13];
  int month, ld;
  scanf("%s", EGN);
  if (strlen(EGN) < 10 || strlen(EGN) > 10) {
    printf("0");
    return 0;
  }
  month = (EGN[2] - '0') * 10 + (EGN[3] - '0');
  if ((month >= 1 && month <= 12) || (month >= 21 && month <= 32) || (month >= 41 && month <= 52)) {
    ld = ((EGN[0] - '0') * 2 + (EGN[1] - '0') * 4 + (EGN[2] - '0') * 8 + (EGN[3] - '0') * 5 + (EGN[4] - '0') * 10 + (EGN[5] - '0') * 9 + (EGN[6] - '0') * 7 + (EGN[7] - '0') * 3 + (EGN[8] - '0') * 6);
    if (ld % 11 == 10) {
      ld = 0;
    }
    if (ld % 11 != EGN[9] - '0') {
      printf("0");
      return 0;
    }
    printf("1");
    return 0;
  }
  printf("0");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xb(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x9,%eax
  jle    L3
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jg     L3
  movsbl 0xd(%rsp),%edx
  movsbl 0xe(%rsp),%eax
  sub    $0x30,%edx
  sub    $0x30,%eax
  imul   $0xa,%edx,%ecx
  add    %eax,%ecx
  cmp    $0x34,%ecx
  ja     L3
  movabs $0xffe001fe001fe001,%rsi
  sar    %cl,%rsi
  and    $0x1,%sil
  jne    L3
  movsbl 0xc(%rsp),%esi
  movsbl 0xb(%rsp),%ecx
  lea    (%rax,%rax,4),%eax
  lea    -0x90(%rcx,%rsi,2),%ecx
  mov    $0xb,%esi
  lea    (%rcx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%ecx
  movsbl 0xf(%rsp),%eax
  sub    $0x30,%eax
  imul   $0xa,%eax,%eax
  add    %eax,%ecx
  movsbl 0x10(%rsp),%eax
  sub    $0x30,%eax
  lea    (%rax,%rax,8),%eax
  add    %eax,%ecx
  movsbl 0x11(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x7,%eax,%eax
  add    %eax,%ecx
  movsbl 0x12(%rsp),%eax
  sub    $0x30,%eax
  lea    (%rax,%rax,2),%eax
  add    %eax,%ecx
  movsbl 0x13(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x6,%eax,%eax
  add    %eax,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %esi
  xor    %eax,%eax
  cmp    $0xa,%edx
  cmove  %eax,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movsbl 0x14(%rsp),%eax
  sub    $0x30,%eax
  cmp    %eax,%edx
  je     L24
L3:
  lea    D19(%rip),%rdi
  call   <printf@plt>
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L24:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string

tool: D23: %s

tool: D19: 0

tool: D11: 1

assistant: ```c
int main() {
  char EGN[13];
  int month, ld;
  scanf("%s", EGN);
  if (strlen(EGN) < 10 || strlen(EGN) > 10) {
    printf("0");
    return 0;
  }
  month = (EGN[2] - '0') * 10 + (EGN[3] - '0');
  if ((month >= 1 && month <= 12) || (month >= 21 && month <= 32) || (month >= 41 && month <= 52)) {
    ld = ((EGN[0] - '0') * 2 + (EGN[1] - '0') * 4 + (EGN[2] - '0') * 8 + (EGN[3] - '0') * 5 + (EGN[4] - '0') * 10 + (EGN[5] - '0') * 9 + (EGN[6] - '0') * 7 + (EGN[7] - '0') * 3 + (EGN[8] - '0') * 6);
    if (ld % 11 == 10) {
      ld = 0;
    }
    if (ld % 11 != EGN[9] - '0') {
      printf("0");
      return 0;
    }
    printf("1");
    return 0;
  }
  printf("0");
  return 0;
}
```