ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printGrid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1d,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L9
L86:
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L48
L56:
  mov    -0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1e,-0xc(%rbp)
  jmp    L69
L45:
  mov    -0xc(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L53
L8:
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L53:
  subl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x14(%rbp)
L69:
  cmpl   $0x0,-0xc(%rbp)
  je     L44
  cmpl   $0x0,-0x14(%rbp)
  jne    L45
L44:
  addl   $0x1,-0x10(%rbp)
L48:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L56
  addl   $0x1,-0x1c(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L86
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D30
datatype: string
name: parse_data
arguments: data_tag: D5
datatype: string

tool: D4: X

tool: D30: -

tool: D5: 


assistant: ```c
void printGrid(int *g, int M, int N) {
  int l, vstrips;
  l = 0;
  vstrips = (N + 29) / 30;
  for (int i = 0; i < M; i++) {
    int n = N;
    for (int j = 0; j < vstrips; j++) {
      int c = g[2 * (l + j * M)];
      for (int k = 30; k && n; k--, n--)
        if (c & (1 << k))
          printf("X");
        else
          printf("-");
    }
    l++;
    printf("\n");
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printGrid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %esi,0x24(%rsp)
  mov    %edx,0x20(%rsp)
  lea    0x1d(%rdx),%edx
  movslq %edx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x4,%eax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x18(%rsp)
  test   %esi,%esi
  jle    L59
  lea    (%rsi,%rsi,1),%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x0,0x1c(%rsp)
  lea    D37(%rip),%r14
  lea    D19(%rip),%r13
  jmp    L7
L3:
  mov    %r14,%rdi
  call   <printf@plt>
L46:
  sub    $0x1,%ebp
  sub    $0x1,%ebx
  je     L8
  test   %ebp,%ebp
  je     L8
L81:
  bt     %ebx,%r12d
  jae    L3
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L46
L8:
  add    $0x1,%r15d
  mov    0x10(%rsp),%rcx
  add    %rcx,0x8(%rsp)
  cmp    %r15d,0x18(%rsp)
  jle    L0
L114:
  mov    0x8(%rsp),%rax
  mov    (%rax),%r12d
  test   %ebp,%ebp
  je     L8
  mov    $0x1e,%ebx
  jmp    L81
L0:
  addl   $0x1,0x1c(%rsp)
  mov    0x1c(%rsp),%ebx
  lea    D38(%rip),%rdi
  call   <printf@plt>
  cmp    %ebx,0x24(%rsp)
  je     L59
L7:
  cmpl   $0x0,0x20(%rsp)
  jle    L0
  mov    0x1c(%rsp),%eax
  add    %eax,%eax
  cltq
  mov    0x28(%rsp),%rsi
  lea    (%rsi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  mov    0x20(%rsp),%ebp
  mov    $0x0,%r15d
  jmp    L114
L59:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D37
type_guessed: string
name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D38
type_guessed: string

tool: D37: -

tool: D19: X

tool: D38: 


assistant: ```c
void printGrid(int *g, int M, int N) {
  int l, vstrips;
  l = 0;
  vstrips = (N + 29) / 30;
  for (int i = 0; i < M; i++) {
    int n = N;
    for (int j = 0; j < vstrips; j++) {
      int c = g[2 * (l + j * M)];
      for (int k = 30; k && n; k--, n--)
        if (c & (1 << k))
          printf("X");
        else
          printf("-");
    }
    l++;
    printf("\n");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<printGrid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0x20(%rsp)
  add    $0x1d,%edx
  movslq %edx,%rax
  mov    %rdi,0x28(%rsp)
  imul   $0xffffffff88888889,%rax,%rax
  mov    %esi,0x24(%rsp)
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x1f,%edx
  sar    $0x4,%eax
  sub    %edx,%eax
  mov    %eax,0x18(%rsp)
  test   %esi,%esi
  jle    L59
  lea    (%rsi,%rsi,1),%r15d
  movl   $0x0,0x1c(%rsp)
  lea    D33(%rip),%r12
  movslq %r15d,%r15
  lea    D20(%rip),%rbp
  lea    0x0(,%r15,4),%rax
  mov    %rax,0x10(%rsp)
L12:
  mov    0x20(%rsp),%eax
  test   %eax,%eax
  jle    L87
  mov    0x1c(%rsp),%eax
  mov    0x28(%rsp),%rdx
  movl   $0x0,0xc(%rsp)
  mov    0x20(%rsp),%r15d
  add    %eax,%eax
  cltq
  lea    (%rdx,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L98:
  mov    (%r14),%ebx
  test   %r15d,%r15d
  je     L42
  mov    $0x1e,%r13d
  jmp    L52
  nopl   0x0(%rax)
L108:
  mov    %rbp,%rdi
  sub    $0x1,%r15d
  call   <printf@plt>
  sub    $0x1,%r13d
  je     L9
L104:
  test   %r15d,%r15d
  je     L9
L52:
  bt     %r13d,%ebx
  jb     L108
  mov    %r12,%rdi
  sub    $0x1,%r15d
  call   <printf@plt>
  sub    $0x1,%r13d
  jne    L104
L9:
  addl   $0x1,0xc(%rsp)
  add    0x10(%rsp),%r14
  mov    0xc(%rsp),%eax
  cmp    %eax,0x18(%rsp)
  jg     L98
L87:
  lea    D22(%rip),%rdi
  addl   $0x1,0x1c(%rsp)
  mov    0x1c(%rsp),%ebx
  call   <printf@plt>
  cmp    %ebx,0x24(%rsp)
  jne    L12
L59:
  add    $0x38,%rsp
  lea    D22(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
L42:
  addl   $0x1,0xc(%rsp)
  add    0x10(%rsp),%r14
  mov    0xc(%rsp),%eax
  cmp    0x18(%rsp),%eax
  jl     L9
  jmp    L87
```

tool_calls: name: unpack_data
arguments: tag: D33
type: string
name: unpack_data
arguments: tag: D20
type: string
name: unpack_data
arguments: tag: D22
type: string

tool: D33: -

tool: D20: X

tool: D22: 


assistant: ```c
void printGrid(int *g, int M, int N) {
  int l, vstrips;
  l = 0;
  vstrips = (N + 29) / 30;
  for (int i = 0; i < M; i++) {
    int n = N;
    for (int j = 0; j < vstrips; j++) {
      int c = g[2 * (l + j * M)];
      for (int k = 30; k && n; k--, n--)
        if (c & (1 << k))
          printf("X");
        else
          printf("-");
    }
    l++;
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printGrid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0x20(%rsp)
  add    $0x1d,%edx
  movslq %edx,%rax
  mov    %rdi,0x28(%rsp)
  imul   $0xffffffff88888889,%rax,%rax
  mov    %esi,0x24(%rsp)
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x1f,%edx
  sar    $0x4,%eax
  sub    %edx,%eax
  mov    %eax,0x18(%rsp)
  test   %esi,%esi
  jle    L80
  lea    (%rsi,%rsi,1),%r15d
  movl   $0x0,0x1c(%rsp)
  lea    D27(%rip),%r12
  movslq %r15d,%r15
  lea    D17(%rip),%rbp
  lea    0x0(,%r15,4),%rax
  mov    %rax,0x10(%rsp)
L1:
  mov    0x20(%rsp),%eax
  test   %eax,%eax
  jle    L89
  mov    0x1c(%rsp),%eax
  mov    0x28(%rsp),%rdx
  movl   $0x0,0xc(%rsp)
  mov    0x20(%rsp),%r15d
  add    %eax,%eax
  cltq
  lea    (%rdx,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L72:
  mov    (%r14),%ebx
  test   %r15d,%r15d
  je     L50
  mov    $0x1e,%r13d
  jmp    L103
  nopl   0x0(%rax)
L91:
  mov    %rbp,%rdi
  sub    $0x1,%r15d
  call   <printf@plt>
  sub    $0x1,%r13d
  je     L49
L36:
  test   %r15d,%r15d
  je     L49
L103:
  bt     %r13d,%ebx
  jb     L91
  mov    %r12,%rdi
  sub    $0x1,%r15d
  call   <printf@plt>
  sub    $0x1,%r13d
  jne    L36
L49:
  addl   $0x1,0xc(%rsp)
  add    0x10(%rsp),%r14
  mov    0xc(%rsp),%eax
  cmp    %eax,0x18(%rsp)
  jg     L72
L89:
  lea    D0(%rip),%rdi
  addl   $0x1,0x1c(%rsp)
  mov    0x1c(%rsp),%ebx
  call   <printf@plt>
  cmp    %ebx,0x24(%rsp)
  jne    L1
L80:
  add    $0x38,%rsp
  lea    D0(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
L50:
  addl   $0x1,0xc(%rsp)
  add    0x10(%rsp),%r14
  mov    0xc(%rsp),%eax
  cmp    0x18(%rsp),%eax
  jl     L49
  jmp    L89
```

tool_calls: name: unpack_data
arguments: tag: D27
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D27: -

tool: D17: X

tool: D0: 


assistant: ```c
void printGrid(int *g, int M, int N) {
  int l, vstrips;
  l = 0;
  vstrips = (N + 29) / 30;
  for (int i = 0; i < M; i++) {
    int n = N;
    for (int j = 0; j < vstrips; j++) {
      int c = g[2 * (l + j * M)];
      for (int k = 30; k && n; k--, n--)
        if (c & (1 << k))
          printf("X");
        else
          printf("-");
    }
    l++;
    printf("\n");
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<combinazioni_con_ripetizione>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  sub    $0x1,%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <fattoriale@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fattoriale@plt>
  mov    %rax,%r12
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <fattoriale@plt>
  mov    %r12,%rdx
  imul   %rax,%rdx
  mov    %rdx,%rcx
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rcx
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D1
type: string

tool: D23: fat 1: %llu


tool: D2: fat 2: %llu


tool: D1: fat 3: %llu


assistant: ```c
unsigned long long int combinazioni_con_ripetizione(unsigned long long int n, unsigned long long int k) {
  printf("fat 1: %llu\n", n + k - 1);
  printf("fat 2: %llu\n", k);
  printf("fat 3: %llu\n", n - 1);
  return fattoriale(n + k - 1) / (fattoriale(k) * fattoriale(n - 1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<combinazioni_con_ripetizione>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    -0x1(%rdi,%rsi,1),%r12
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <fattoriale@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <fattoriale@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <fattoriale@plt>
  mov    %rbp,%rcx
  imul   %rax,%rcx
  mov    %r12,%rax
  mov    $0x0,%edx
  div    %rcx
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D23
data_type: string
name: extract_symbolic_data
arguments: data_label: D28
data_type: string

tool: D6: fat 1: %llu


tool: D23: fat 2: %llu


tool: D28: fat 3: %llu


assistant: ```c
unsigned long long int combinazioni_con_ripetizione(unsigned long long int n, unsigned long long int k) {
  printf("fat 1: %llu\n", n + k - 1);
  printf("fat 2: %llu\n", k);
  printf("fat 3: %llu\n", n - 1);
  return fattoriale(n + k - 1) / (fattoriale(k) * fattoriale(n - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<combinazioni_con_ripetizione>:
  endbr64
  push   %r13
  lea    -0x1(%rdi,%rsi,1),%r13
  push   %r12
  mov    %rsi,%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D22(%rip),%rdi
  push   %rbx
  sub    $0x1,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <fattoriale@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <fattoriale@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fattoriale@plt>
  mov    %r12,%rcx
  add    $0x8,%rsp
  xor    %edx,%edx
  imul   %rax,%rcx
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  div    %rcx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D22
type: string
name: disassemble_data
arguments: tag: D20
type: string
name: disassemble_data
arguments: tag: D14
type: string

tool: D22: fat 1: %llu


tool: D20: fat 2: %llu


tool: D14: fat 3: %llu


assistant: ```c
unsigned long long int combinazioni_con_ripetizione(unsigned long long int n, unsigned long long int k) {
  printf("fat 1: %llu\n", n + k - 1);
  printf("fat 2: %llu\n", k);
  printf("fat 3: %llu\n", n - 1);
  return fattoriale(n + k - 1) / (fattoriale(k) * fattoriale(n - 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<combinazioni_con_ripetizione>:
  endbr64
  push   %r13
  lea    -0x1(%rdi,%rsi,1),%r13
  push   %r12
  mov    %rsi,%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D18(%rip),%rdi
  push   %rbx
  sub    $0x1,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <fattoriale@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <fattoriale@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fattoriale@plt>
  mov    %r12,%rcx
  add    $0x8,%rsp
  xor    %edx,%edx
  imul   %rax,%rcx
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  div    %rcx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D18
type: string
name: disassemble_data
arguments: label: D19
type: string
name: disassemble_data
arguments: label: D11
type: string

tool: D18: fat 1: %llu


tool: D19: fat 2: %llu


tool: D11: fat 3: %llu


assistant: ```c
unsigned long long int combinazioni_con_ripetizione(unsigned long long int n, unsigned long long int k) {
  printf("fat 1: %llu\n", n + k - 1);
  printf("fat 2: %llu\n", k);
  printf("fat 3: %llu\n", n - 1);
  return fattoriale(n + k - 1) / (fattoriale(k) * fattoriale(n - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_printf_o>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L26
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <ft_putstr_prntf@plt>
  mov    $0x1,%eax
  jmp    L5
L12:
  mov    -0x14(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x0,-0x14(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ft_putnbr_o@plt>
  mov    -0x8(%rbp),%eax
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string

tool: D8: 0

assistant: ```c
int ft_printf_o(unsigned int nbr) {
  int ret;
  int copy;
  copy = nbr;
  ret = 0;
  if (nbr <= 0) {
    ft_putstr_prntf("0");
    return (1);
  }
  while (nbr >= 1) {
    nbr = nbr / 8;
    ret++;
  }
  ft_putnbr_o(copy);
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_printf_o>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  mov    $0x0,%ebx
  test   %edi,%edi
  je     L17
L9:
  mov    %edi,%eax
  shr    $0x3,%edi
  add    $0x1,%ebx
  cmp    $0x7,%eax
  ja     L9
  mov    %edx,%edi
  call   <ft_putnbr_o@plt>
L22:
  mov    %ebx,%eax
  pop    %rbx
  ret
L17:
  lea    D7(%rip),%rdi
  call   <ft_putstr_prntf@plt>
  mov    $0x1,%ebx
  jmp    L22
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: 0

assistant: ```c
int ft_printf_o(unsigned int nbr) {
  int ret;
  int copy;
  copy = nbr;
  ret = 0;
  if (nbr <= 0) {
    ft_putstr_prntf("0");
    return (1);
  }
  while (nbr >= 1) {
    nbr = nbr / 8;
    ret++;
  }
  ft_putnbr_o(copy);
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_printf_o>:
  endbr64
  push   %r12
  mov    %edi,%r8d
  xor    %r12d,%r12d
  test   %edi,%edi
  je     L2
L8:
  add    $0x1,%r12d
  shr    $0x3,%edi
  jne    L8
  mov    %r8d,%edi
  call   <ft_putnbr_o@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%r12d
  lea    D2(%rip),%rdi
  call   <ft_putstr_prntf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: 0

assistant: ```c
int ft_printf_o(unsigned int nbr) {
  int ret;
  int copy;
  copy = nbr;
  ret = 0;
  if (nbr <= 0) {
    ft_putstr_prntf("0");
    return (1);
  }
  while (nbr >= 1) {
    nbr = nbr / 8;
    ret++;
  }
  ft_putnbr_o(copy);
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_printf_o>:
  endbr64
  push   %r12
  mov    %edi,%r8d
  xor    %r12d,%r12d
  test   %edi,%edi
  je     L4
L2:
  add    $0x1,%r12d
  shr    $0x3,%edi
  jne    L2
  mov    %r8d,%edi
  call   <ft_putnbr_o@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%r12d
  lea    D4(%rip),%rdi
  call   <ft_putstr_prntf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: 0

assistant: ```c
int ft_printf_o(unsigned int nbr) {
  int ret;
  int copy;
  copy = nbr;
  ret = 0;
  if (nbr <= 0) {
    ft_putstr_prntf("0");
    return (1);
  }
  while (nbr >= 1) {
    nbr = nbr / 8;
    ret++;
  }
  ft_putnbr_o(copy);
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<directory_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <directory_raw_add@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <directory_insert_sort@plt>
  nop
  leave
  ret
```

assistant: ```c
void directory_add(struct directory *self, struct directory_data *data) {
  assert(self);
  assert(data);
  directory_raw_add(self, data);
  directory_insert_sort(self);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<directory_add>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <directory_raw_add@plt>
  mov    %rbx,%rdi
  call   <directory_insert_sort@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void directory_add(struct directory *self, struct directory_data *data) {
  assert(self);
  assert(data);
  directory_raw_add(self, data);
  directory_insert_sort(self);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<directory_add>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <directory_raw_add@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <directory_insert_sort@plt>
```

assistant: ```c
void directory_add(struct directory *self, struct directory_data *data) {
  assert(self);
  assert(data);
  directory_raw_add(self, data);
  directory_insert_sort(self);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<directory_add>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <directory_raw_add@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <directory_insert_sort@plt>
```

assistant: ```c
void directory_add(struct directory *self, struct directory_data *data) {
  assert(self);
  assert(data);
  directory_raw_add(self, data);
  directory_insert_sort(self);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fMax5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int fMax5(int a, int b) {
  int c[2] = {a, b};
  int z = a - b;
  z = (z >> 31) & 1;
  return c[z];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fMax5>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  sub    %esi,%edi
  shr    $0x1f,%edi
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fMax5(int a, int b) {
  int c[2] = {a, b};
  int z = a - b;
  z = (z >> 31) & 1;
  return c[z];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fMax5>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  sub    %esi,%edi
  mov    %esi,0x4(%rsp)
  shr    $0x1f,%edi
  mov    (%rsp,%rdi,4),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fMax5(int a, int b) {
  int c[2] = {a, b};
  int z = a - b;
  z = (z >> 31) & 1;
  return c[z];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fMax5>:
  endbr64
  sub    $0x18,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  sub    %esi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  punpckldq %xmm1,%xmm0
  shr    $0x1f,%edi
  movq   %xmm0,(%rsp)
  mov    (%rsp,%rdi,4),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fMax5(int a, int b) {
  int c[2] = {a, b};
  int z = a - b;
  z = (z >> 31) & 1;
  return c[z];
}
```