user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D153(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D143(%rip),%rdi
  call   <scanf@plt>
  movss  0x20(%rsp),%xmm2
  movss  D43(%rip),%xmm0
  mulss  0x1c(%rsp),%xmm0
  mulss  0x24(%rsp),%xmm0
  mulss  %xmm2,%xmm2
  subss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  comiss %xmm2,%xmm0
  ja     L13
  ucomiss %xmm0,%xmm2
  jp     L26
  jne    L26
  lea    D32(%rip),%rdi
  call   <puts@plt>
  movss  0x1c(%rsp),%xmm1
  movss  0x20(%rsp),%xmm0
  lea    D24(%rip),%rdi
  xorps  D150(%rip),%xmm0
  mov    $0x1,%eax
  addss  %xmm1,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L26:
  lea    D104(%rip),%rdi
  movss  %xmm2,0x4(%rsp)
  call   <puts@plt>
  movss  0x4(%rsp),%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <sqrt@plt>
  movss  0x20(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  movaps %xmm0,%xmm3
  movss  0x1c(%rsp),%xmm0
  subss  %xmm1,%xmm3
  movss  %xmm1,0x8(%rsp)
  addss  %xmm0,%xmm0
  divss  %xmm0,%xmm3
  movaps %xmm2,%xmm0
  movss  %xmm3,0x4(%rsp)
  call   <sqrt@plt>
  movss  0x8(%rsp),%xmm1
  movss  0x4(%rsp),%xmm3
  lea    D34(%rip),%rdi
  xorps  D150(%rip),%xmm1
  mov    $0x2,%eax
  subss  %xmm0,%xmm1
  movss  0x1c(%rsp),%xmm0
  addss  %xmm0,%xmm0
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  jmp    L1
L13:
  lea    D57(%rip),%rdi
  movss  %xmm2,0x4(%rsp)
  call   <puts@plt>
  lea    D94(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movss  0x4(%rsp),%xmm2
  movss  D150(%rip),%xmm5
  xorps  %xmm5,%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0x4(%rsp)
  call   <sqrt@plt>
  movss  0x1c(%rsp),%xmm4
  movss  0x20(%rsp),%xmm3
  movss  D150(%rip),%xmm5
  pxor   %xmm1,%xmm1
  lea    D112(%rip),%rdi
  mov    $0x2,%eax
  addss  %xmm4,%xmm4
  xorps  %xmm5,%xmm3
  divss  %xmm4,%xmm0
  divss  %xmm4,%xmm3
  cvtss2sd %xmm0,%xmm1
  cvtss2sd %xmm3,%xmm3
  movapd %xmm3,%xmm0
  call   <printf@plt>
  movss  0x4(%rsp),%xmm2
  movaps %xmm2,%xmm0
  call   <sqrt@plt>
  movss  0x1c(%rsp),%xmm3
  movss  0x20(%rsp),%xmm2
  movss  D150(%rip),%xmm5
  movaps %xmm0,%xmm1
  lea    D75(%rip),%rdi
  mov    $0x2,%eax
  addss  %xmm3,%xmm3
  xorps  %xmm5,%xmm2
  xorps  %xmm5,%xmm1
  movaps %xmm2,%xmm0
  divss  %xmm3,%xmm1
  divss  %xmm3,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L1
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D153
type_infered: string
name: parse_data
arguments: tag: D143
type_infered: string
name: parse_data
arguments: tag: D43
type_infered: byte[4]
name: parse_data
arguments: tag: D32
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string
name: parse_data
arguments: tag: D150
type_infered: byte[16]
name: parse_data
arguments: tag: D104
type_infered: string
name: parse_data
arguments: tag: D34
type_infered: string
name: parse_data
arguments: tag: D57
type_infered: string
name: parse_data
arguments: tag: D94
type_infered: string
name: parse_data
arguments: tag: D112
type_infered: string
name: parse_data
arguments: tag: D75
type_infered: string

tool: D153: Enter a, b and c of quadratic equation: 

tool: D143: %f %f %f

tool: {"D43": [0x00,0x00,0x80,0x40]}

tool: D32: Both roots are equal.

tool: D24: Root of quadratic equation is: %.3f 


tool: {"D150": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D104: Roots are real numbers.

tool: D34: Roots of quadratic equation are: %.3f , %.3f 


tool: D57: Roots are complex number.

tool: D94: Roots of quadratic equation are: 

tool: D112: %.3f + %.3fi

tool: D75: , %.3f + %.3fi 


assistant: ```c
int main(void) {
  float a, b, c;
  float discriminant, first_root, second_root;
  printf("Enter a, b and c of quadratic equation: ");
  scanf("%f %f %f", &a, &b, &c);
  discriminant = (b * b) - (4 * a * c);
  if (discriminant < 0) {
    printf("Roots are complex number.\n");
    printf("Roots of quadratic equation are: ");
    printf("%.3f + %.3fi", -b / (2 * a), sqrt(-discriminant) / (2 * a));
    printf(", %.3f + %.3fi \n", -b / (2 * a), -sqrt(-discriminant) / (2 * a));
  } else if (discriminant == 0) {
    printf("Both roots are equal.\n");
    first_root = -b / (2 * a);
    printf("Root of quadratic equation is: %.3f \n", first_root);
  } else {
    printf("Roots are real numbers.\n");
    first_root = (-b + sqrt(discriminant)) / (2 * a);
    second_root = (-b - sqrt(discriminant)) / (2 * a);
    printf("Roots of quadratic equation are: %.3f , %.3f \n", first_root, second_root);
  }
  return 0;
}
```