ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  mov    $0x2,%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L20
  nopl   (%rax)
L3:
  mov    $0x1,%ecx
  lea    0x10(%rsp),%rsi
  test   %ebx,%ebx
  je     L30
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12d,%eax
  cltd
  idivl  -0x4(%rsi,%rcx,4)
  cmp    %ecx,%ebx
  setg   %dil
  test   %edx,%edx
  setne  %al
  add    $0x1,%rcx
  test   %al,%dil
  jne    L19
  test   %edx,%edx
  jne    L31
L18:
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jge    L3
L20:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L31:
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3e7,%ebx
  jg     L18
  movslq %ebx,%rax
  add    $0x1,%ebx
  mov    %r12d,0x10(%rsp,%rax,4)
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  add    $0x1,%ebx
  mov    %r12d,0x10(%rsp,%rax,4)
  jmp    L18
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D24
type_guessed: string

tool: D5: Enter value of N > 

tool: D2: %12d


tool: D24: %d

assistant: ```c
int main(void) {
  int n;
  int i, j;
  int flag;
  int primes[1000];
  int level;
  printf("Enter value of N > ");
  scanf("%d", &n);
  level = 0;
  for (i = 2; i <= n; i++) {
    for (j = 0, flag = 1; j < level && flag; j++)
      flag = (i % primes[j]);
    if (flag) {
      printf("%12d\n", i);
      if (level < 1000)
        primes[level++] = i;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  mov    $0x2,%r12d
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  cmp    $0x1,%r8d
  jle    L73
  nopl   0x0(%rax)
L8:
  mov    $0x1,%ecx
  lea    0x10(%rsp),%rsi
  test   %ebx,%ebx
  je     L42
  xchg   %ax,%ax
L65:
  mov    %r12d,%eax
  cltd
  idivl  -0x4(%rsi,%rcx,4)
  cmp    %ecx,%ebx
  setg   %dil
  test   %edx,%edx
  setne  %al
  add    $0x1,%rcx
  test   %al,%dil
  jne    L65
  test   %edx,%edx
  jne    L71
L35:
  add    $0x1,%r12d
  cmp    %r8d,%r12d
  jle    L8
L73:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3e7,%ebx
  jle    L88
  mov    0xc(%rsp),%r8d
  jmp    L35
  nopl   0x0(%rax)
L42:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L88:
  movslq %ebx,%rax
  mov    0xc(%rsp),%r8d
  add    $0x1,%ebx
  mov    %r12d,0x10(%rsp,%rax,4)
  jmp    L35
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string
name: unpack_data
arguments: data_tag: D3
data_type: string
name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D0: Enter value of N > 

tool: D3: %12d


tool: D6: %d

assistant: ```c
int main(void) {
  int n;
  int i, j;
  int flag;
  int primes[1000];
  int level;
  printf("Enter value of N > ");
  scanf("%d", &n);
  level = 0;
  for (i = 2; i <= n; i++) {
    for (j = 0, flag = 1; j < level && flag; j++)
      flag = (i % primes[j]);
    if (flag) {
      printf("%12d\n", i);
      if (level < 1000)
        primes[level++] = i;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<load_noinstall_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0xa,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x14(%rbp),%eax
  add    $0x5,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: .libs

assistant: ```c
char *load_noinstall_path(const char *arg, int pathlen) {
  char *newarg, *expanded_path;
  int newpathlen;
  newarg = (char *)malloc(strlen(arg) + 10);
  strcpy(newarg, arg);
  newarg[pathlen] = 0;
  newpathlen = pathlen;
  strcat(newarg, ".libs");
  newpathlen += sizeof(".libs") - 1;
  newarg[newpathlen] = 0;
  expanded_path = newarg;
  return expanded_path;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<load_noinstall_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  call   <strlen@plt>
  lea    0xa(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movslq %ebx,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    $0x5,%ebx
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: .libs

assistant: ```c
char *load_noinstall_path(const char *arg, int pathlen) {
  char *newarg, *expanded_path;
  int newpathlen;
  newarg = (char *)malloc(strlen(arg) + 10);
  strcpy(newarg, arg);
  newarg[pathlen] = 0;
  newpathlen = pathlen;
  strcat(newarg, ".libs");
  newpathlen += sizeof(".libs") - 1;
  newarg[newpathlen] = 0;
  expanded_path = newarg;
  return expanded_path;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<load_noinstall_path>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <strlen@plt>
  lea    0xa(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movslq %ebx,%rax
  add    $0x5,%ebx
  mov    %r12,%rdi
  movb   $0x0,(%r12,%rax,1)
  movslq %ebx,%rbx
  lea    D2(%rip),%rsi
  call   <strcat@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: .libs

assistant: ```c
char *load_noinstall_path(const char *arg, int pathlen) {
  char *newarg, *expanded_path;
  int newpathlen;
  newarg = (char *)malloc(strlen(arg) + 10);
  strcpy(newarg, arg);
  newarg[pathlen] = 0;
  newpathlen = pathlen;
  strcat(newarg, ".libs");
  newpathlen += sizeof(".libs") - 1;
  newarg[newpathlen] = 0;
  expanded_path = newarg;
  return expanded_path;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<load_noinstall_path>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <strlen@plt>
  lea    0xa(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  movslq %ebx,%rax
  add    $0x5,%ebx
  mov    %r12,%rdi
  movb   $0x0,(%r12,%rax,1)
  movslq %ebx,%rbx
  lea    D3(%rip),%rsi
  call   <strcat@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: .libs

assistant: ```c
char *load_noinstall_path(const char *arg, int pathlen) {
  char *newarg, *expanded_path;
  int newpathlen;
  newarg = (char *)malloc(strlen(arg) + 10);
  strcpy(newarg, arg);
  newarg[pathlen] = 0;
  newpathlen = pathlen;
  strcat(newarg, ".libs");
  newpathlen += sizeof(".libs") - 1;
  newarg[newpathlen] = 0;
  expanded_path = newarg;
  return expanded_path;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  jmp    L23
L18:
  mov    $0x0,%eax
  call   <clr@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L23:
  cmpl   $0x5,-0xc(%rbp)
  jle    L18
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D2
type: string
name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D19
type: string

tool: D2: Enter any two values! 

tool: D12: %d%d

tool: D19: The addition of two numbers is %d 

assistant: ```c
int main() {
  int a, b, x;
  x = 1;
  while (x <= 5) {
    clr();
    gotoxy(10, 10);
    printf("Enter any two values! ");
    scanf("%d%d", &a, &b);
    a = a + b;
    printf("The addition of two numbers is %d ", a);
    x++;
  }
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x5,%ebx
  lea    D27(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D1(%rip),%r12
  lea    D0(%rip),%rbp
L15:
  mov    $0x0,%eax
  call   <clr@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  add    (%rsp),%esi
  mov    %esi,(%rsp)
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L15
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D27
type: string
name: retrieve_data
arguments: tag: D1
type: string
name: retrieve_data
arguments: tag: D0
type: string

tool: D27: Enter any two values! 

tool: D1: %d%d

tool: D0: The addition of two numbers is %d 

assistant: ```c
int main() {
  int a, b, x;
  x = 1;
  while (x <= 5) {
    clr();
    gotoxy(10, 10);
    printf("Enter any two values! ");
    scanf("%d%d", &a, &b);
    a = a + b;
    printf("The addition of two numbers is %d ", a);
    x++;
  }
  getchar();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  lea    D6(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  mov    %rsp,%r13
L1:
  xor    %eax,%eax
  call   <clr@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %r14,%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  mov    %rbp,%rdi
  mov    %esi,(%rsp)
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D25
type_infered: string
name: extract_symbolic_data
arguments: label: D28
type_infered: string

tool: D6: Enter any two values! 

tool: D25: %d%d

tool: D28: The addition of two numbers is %d 

assistant: ```c
int main() {
  int a, b, x;
  x = 1;
  while (x <= 5) {
    clr();
    gotoxy(10, 10);
    printf("Enter any two values! ");
    scanf("%d%d", &a, &b);
    a = a + b;
    printf("The addition of two numbers is %d ", a);
    x++;
  }
  getchar();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D19(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  mov    %rsp,%r13
L18:
  xor    %eax,%eax
  call   <clr@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %r14,%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  mov    %rbp,%rdi
  mov    %esi,(%rsp)
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L18
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D5
type: string
name: retrieve_data
arguments: tag: D8
type: string

tool: D19: Enter any two values! 

tool: D5: %d%d

tool: D8: The addition of two numbers is %d 

assistant: ```c
int main() {
  int a, b, x;
  x = 1;
  while (x <= 5) {
    clr();
    gotoxy(10, 10);
    printf("Enter any two values! ");
    scanf("%d%d", &a, &b);
    a = a + b;
    printf("The addition of two numbers is %d ", a);
    x++;
  }
  getchar();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mouseMove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <XOpenDisplay@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  neg    %eax
  mov    %eax,%edi
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,%ecx
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   %rdi
  push   %rcx
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <XWarpPointer@plt>
  add    $0x20,%rsp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <XCloseDisplay@plt>
  nop
  leave
  ret
```

assistant: ```c
void mouseMove(int x, int y) {
  Display *displayMain = XOpenDisplay(NULL);
  XWarpPointer(displayMain, None, None, 0, 0, 0, 0, -x, -y);
  XCloseDisplay(displayMain);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mouseMove>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%edi
  call   <XOpenDisplay@plt>
  mov    %rax,%r12
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  sub    $0x8,%rsp
  neg    %ebp
  push   %rbp
  neg    %ebx
  push   %rbx
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %esi,%edx
  mov    %r12,%rdi
  call   <XWarpPointer@plt>
  add    $0x20,%rsp
  mov    %r12,%rdi
  call   <XCloseDisplay@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mouseMove(int x, int y) {
  Display *displayMain = XOpenDisplay(NULL);
  XWarpPointer(displayMain, None, None, 0, 0, 0, 0, -x, -y);
  XCloseDisplay(displayMain);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mouseMove>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  neg    %ebp
  neg    %ebx
  call   <XOpenDisplay@plt>
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %rax,%r12
  mov    D1(%rip),%rax
  xor    %ecx,%ecx
  mov    %r12,%rdi
  mov    (%rax),%esi
  push   %rbp
  push   %rbx
  push   $0x0
  mov    %esi,%edx
  call   <XWarpPointer@plt>
  add    $0x20,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <XCloseDisplay@plt>
```

assistant: ```c
void mouseMove(int x, int y) {
  Display *displayMain = XOpenDisplay(NULL);
  XWarpPointer(displayMain, None, None, 0, 0, 0, 0, -x, -y);
  XCloseDisplay(displayMain);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mouseMove>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  neg    %ebp
  neg    %ebx
  call   <XOpenDisplay@plt>
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %rax,%r12
  mov    D4(%rip),%rax
  xor    %ecx,%ecx
  mov    %r12,%rdi
  mov    (%rax),%esi
  push   %rbp
  push   %rbx
  push   $0x0
  mov    %esi,%edx
  call   <XWarpPointer@plt>
  add    $0x20,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <XCloseDisplay@plt>
```

assistant: ```c
void mouseMove(int x, int y) {
  Display *displayMain = XOpenDisplay(NULL);
  XWarpPointer(displayMain, None, None, 0, 0, 0, 0, -x, -y);
  XCloseDisplay(displayMain);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L0
L13:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pot(int b, int e) {
  int i, res;
  res = 1;
  for (i = 1; i <= e; i++) {
    res *= b;
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pot>:
  endbr64
  test   %esi,%esi
  jle    L12
  add    $0x1,%esi
  mov    $0x1,%edx
  mov    $0x1,%eax
L29:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L29
L28:
  mov    %edx,%eax
  ret
L12:
  mov    $0x1,%edx
  jmp    L28
```

assistant: ```c
int pot(int b, int e) {
  int i, res;
  res = 1;
  for (i = 1; i <= e; i++) {
    res *= b;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pot>:
  endbr64
  test   %esi,%esi
  jle    L16
  add    $0x1,%esi
  mov    $0x1,%r8d
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L19
  mov    %r8d,%eax
  ret
  nop
L16:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int pot(int b, int e) {
  int i, res;
  res = 1;
  for (i = 1; i <= e; i++) {
    res *= b;
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pot>:
  endbr64
  test   %esi,%esi
  jle    L2
  add    $0x1,%esi
  mov    $0x1,%r8d
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L1
  mov    %r8d,%eax
  ret
  nop
L2:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int pot(int b, int e) {
  int i, res;
  res = 1;
  for (i = 1; i <= e; i++) {
    res *= b;
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_http_version@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L57
L27:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L44
  mov    0x28(%rbp),%rax
  movl   $0xffffffff,(%rax)
  mov    $0x0,%eax
  jmp    L57
L44:
  mov    0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_int@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L57
L9:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L85
  mov    0x28(%rbp),%rax
  movl   $0xffffffff,(%rax)
  mov    $0x0,%eax
  jmp    L57
L85:
  mov    0x28(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <get_token_to_eol@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L57
L38:
  mov    0x28(%rbp),%rdi
  mov    0x20(%rbp),%rcx
  mov    0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   <parse_headers@plt>
L57:
  leave
  ret
```

assistant: ```c
const char *parse_response(const char *buf, const char *buf_end, int *minor_version, int *status, const char **msg, size_t *msg_len, struct phr_header *headers, size_t *num_headers, size_t max_headers, int *ret) {
  if ((buf = parse_http_version(buf, buf_end, minor_version, ret)) == NULL) {
    return NULL;
  }
  if (*buf++ != ' ') {
    *ret = -1;
    return NULL;
  }
  if ((buf = parse_int(buf, buf_end, status, ret)) == NULL) {
    return NULL;
  }
  if (*buf++ != ' ') {
    *ret = -1;
    return NULL;
  }
  if ((buf = get_token_to_eol(buf, buf_end, msg, msg_len, ret)) == NULL) {
    return NULL;
  }
  return parse_headers(buf, buf_end, headers, num_headers, max_headers, ret);
}
```