ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x20000(%rsp),%r11
L71:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L71
  sub    $0x30,%rsp
  mov    %edi,-0x20024(%rbp)
  mov    %esi,-0x20028(%rbp)
  mov    %edx,-0x2002c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20014(%rbp)
  movl   $0x0,-0x20020(%rbp)
  jmp    L36
L24:
  mov    $0x0,%eax
  call   <coord@plt>
  mov    -0x20020(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x20010(%rbp,%rdx,4)
  addl   $0x1,-0x20020(%rbp)
L36:
  cmpl   $0x7fff,-0x20020(%rbp)
  jle    L24
  mov    -0x20024(%rbp),%edx
  lea    -0x20010(%rbp),%rax
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x8000,%esi
  mov    %rax,%rdi
  call   <check@plt>
  or     %eax,-0x20014(%rbp)
  movl   $0x0,-0x2001c(%rbp)
  jmp    L25
L45:
  mov    $0x0,%eax
  call   <coord@plt>
  mov    -0x2001c(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x20010(%rbp,%rdx,4)
  addl   $0x1,-0x2001c(%rbp)
L25:
  cmpl   $0x7fff,-0x2001c(%rbp)
  jle    L45
  mov    -0x20028(%rbp),%edx
  lea    -0x20010(%rbp),%rax
  mov    $0x1,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x8000,%esi
  mov    %rax,%rdi
  call   <check@plt>
  or     %eax,-0x20014(%rbp)
  movl   $0x0,-0x20018(%rbp)
  jmp    L46
L9:
  mov    $0x0,%eax
  call   <coord@plt>
  mov    -0x20018(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x20010(%rbp,%rdx,4)
  addl   $0x1,-0x20018(%rbp)
L46:
  cmpl   $0x7fff,-0x20018(%rbp)
  jle    L9
  mov    -0x2002c(%rbp),%edx
  lea    -0x20010(%rbp),%rax
  mov    %edx,%r8d
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x8000,%esi
  mov    %rax,%rdi
  call   <check@plt>
  or     %eax,-0x20014(%rbp)
  mov    -0x20014(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int test_1(int gp, int wp, int vp) {
  int ary[(32 * 32 * 32)];
  int exit = 0;
#pragma acc parallel copyout(ary)
  {
#pragma acc loop gang(static : 1)
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), gp, 1, 1);
#pragma acc parallel copyout(ary)
  {
#pragma acc loop worker
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), 1, wp, 1);
#pragma acc parallel copyout(ary)
  {
#pragma acc loop vector
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), 1, 1, vp);
  return exit;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %esi,%r14d
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x20000(%rsp),%r12
  mov    %rbx,%rbp
L3:
  mov    $0x0,%eax
  call   <coord@plt>
  mov    %eax,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L3
  mov    %rsp,%rdi
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    %r15d,%edx
  mov    $0x8000,%esi
  call   <check@plt>
  mov    %eax,%r15d
  mov    %rbx,%rbp
L31:
  mov    $0x0,%eax
  call   <coord@plt>
  mov    %eax,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L31
  mov    %rsp,%rdi
  mov    $0x1,%r8d
  mov    %r14d,%ecx
  mov    $0x1,%edx
  mov    $0x8000,%esi
  call   <check@plt>
  or     %eax,%r15d
L44:
  mov    $0x0,%eax
  call   <coord@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L44
  mov    %rsp,%rdi
  mov    %r13d,%r8d
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x8000,%esi
  call   <check@plt>
  or     %r15d,%eax
  mov    0x20008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x20018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_1(int gp, int wp, int vp) {
  int ary[(32 * 32 * 32)];
  int exit = 0;
#pragma acc parallel copyout(ary)
  {
#pragma acc loop gang(static : 1)
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), gp, 1, 1);
#pragma acc parallel copyout(ary)
  {
#pragma acc loop worker
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), 1, wp, 1);
#pragma acc parallel copyout(ary)
  {
#pragma acc loop vector
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), 1, 1, vp);
  return exit;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0x28,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x10(%rsp),%r12
  mov    %edi,%r14d
  mov    %esi,%r15d
  mov    %r12,%rbx
  lea    0x20010(%rsp),%rbp
  mov    %r12,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x20018(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <coord@plt>
  mov    %eax,-0x4(%r13)
  cmp    %rbp,%r13
  jne    L49
  mov    %r14d,%edx
  mov    $0x1,%r8d
  mov    %r12,%rdi
  mov    %r12,%r14
  mov    $0x1,%ecx
  mov    $0x8000,%esi
  call   <check@plt>
  mov    %eax,%r13d
  nopl   (%rax)
L47:
  xor    %eax,%eax
  add    $0x4,%r14
  call   <coord@plt>
  mov    %eax,-0x4(%r14)
  cmp    %rbp,%r14
  jne    L47
  mov    $0x1,%r8d
  mov    %r15d,%ecx
  mov    %r12,%rdi
  mov    %r13d,%r14d
  mov    $0x1,%edx
  mov    $0x8000,%esi
  call   <check@plt>
  or     %eax,%r14d
  nopl   (%rax)
L25:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <coord@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L25
  mov    0xc(%rsp),%r8d
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    $0x8000,%esi
  call   <check@plt>
  or     %r14d,%eax
  mov    0x20018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x20028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_1(int gp, int wp, int vp) {
  int ary[(32 * 32 * 32)];
  int exit = 0;
#pragma acc parallel copyout(ary)
  {
#pragma acc loop gang(static : 1)
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), gp, 1, 1);
#pragma acc parallel copyout(ary)
  {
#pragma acc loop worker
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), 1, wp, 1);
#pragma acc parallel copyout(ary)
  {
#pragma acc loop vector
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), 1, 1, vp);
  return exit;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L13:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L13
  sub    $0x28,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x10(%rsp),%r12
  mov    %edi,%r14d
  mov    %esi,%r15d
  mov    %r12,%rbx
  lea    0x20010(%rsp),%rbp
  mov    %r12,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x20018(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <coord@plt>
  mov    %eax,-0x4(%r13)
  cmp    %rbp,%r13
  jne    L38
  mov    %r14d,%edx
  mov    $0x1,%r8d
  mov    %r12,%rdi
  mov    %r12,%r14
  mov    $0x1,%ecx
  mov    $0x8000,%esi
  call   <check@plt>
  mov    %eax,%r13d
  nopl   (%rax)
L44:
  xor    %eax,%eax
  add    $0x4,%r14
  call   <coord@plt>
  mov    %eax,-0x4(%r14)
  cmp    %rbp,%r14
  jne    L44
  mov    $0x1,%r8d
  mov    %r15d,%ecx
  mov    %r12,%rdi
  mov    %r13d,%r14d
  mov    $0x1,%edx
  mov    $0x8000,%esi
  call   <check@plt>
  or     %eax,%r14d
  nopl   (%rax)
L34:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <coord@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L34
  mov    0xc(%rsp),%r8d
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    $0x8000,%esi
  call   <check@plt>
  or     %r14d,%eax
  mov    0x20018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x20028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_1(int gp, int wp, int vp) {
  int ary[(32 * 32 * 32)];
  int exit = 0;
#pragma acc parallel copyout(ary)
  {
#pragma acc loop gang(static : 1)
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), gp, 1, 1);
#pragma acc parallel copyout(ary)
  {
#pragma acc loop worker
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), 1, wp, 1);
#pragma acc parallel copyout(ary)
  {
#pragma acc loop vector
    for (int ix = 0; ix < (32 * 32 * 32); ix++)
      ary[ix] = coord();
  }
  exit |= check(ary, (32 * 32 * 32), 1, 1, vp);
  return exit;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atcommand_who>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <map_who@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int atcommand_who(const int fd, struct map_session_data *sd, const char *command, const char *message) {
  map_who(fd);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atcommand_who>:
  endbr64
  sub    $0x8,%rsp
  call   <map_who@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int atcommand_who(const int fd, struct map_session_data *sd, const char *command, const char *message) {
  map_who(fd);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atcommand_who>:
  endbr64
  sub    $0x8,%rsp
  call   <map_who@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int atcommand_who(const int fd, struct map_session_data *sd, const char *command, const char *message) {
  map_who(fd);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<atcommand_who>:
  endbr64
  sub    $0x8,%rsp
  call   <map_who@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int atcommand_who(const int fd, struct map_session_data *sd, const char *command, const char *message) {
  map_who(fd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xcrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <xcmemcheck@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xcrealloc(void *ptr, size_t size) {
  void *mem;
  mem = realloc(ptr, size);
  xcmemcheck(mem);
  return (mem);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xcrealloc>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <xcmemcheck@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *xcrealloc(void *ptr, size_t size) {
  void *mem;
  mem = realloc(ptr, size);
  xcmemcheck(mem);
  return (mem);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xcrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <xcmemcheck@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *xcrealloc(void *ptr, size_t size) {
  void *mem;
  mem = realloc(ptr, size);
  xcmemcheck(mem);
  return (mem);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xcrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <xcmemcheck@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *xcrealloc(void *ptr, size_t size) {
  void *mem;
  mem = realloc(ptr, size);
  xcmemcheck(mem);
  return (mem);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<etr_area_high>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    $0x3,%edi
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  divss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float etr_area_high(float high) {
  float square_root_3 = sqrt(3);
  float area = (high * high) / square_root_3;
  return area;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<etr_area_high>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    $0x3,%edi
  call   <sqrt@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  mulss  %xmm0,%xmm0
  divss  %xmm1,%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
float etr_area_high(float high) {
  float square_root_3 = sqrt(3);
  float area = (high * high) / square_root_3;
  return area;
}
```
user: What is the c source code of the assembly code below:

```asm
<etr_area_high>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%edi
  movss  %xmm0,0xc(%rsp)
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  add    $0x18,%rsp
  mulss  %xmm1,%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float etr_area_high(float high) {
  float square_root_3 = sqrt(3);
  float area = (high * high) / square_root_3;
  return area;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<etr_area_high>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%edi
  movss  %xmm0,0xc(%rsp)
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  add    $0x18,%rsp
  mulss  %xmm1,%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float etr_area_high(float high) {
  float square_root_3 = sqrt(3);
  float area = (high * high) / square_root_3;
  return area;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen_get_indirect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %al,-0x4(%rbp)
  cmpb   $0x4,-0x4(%rbp)
  je     L23
  cmpb   $0x5,-0x4(%rbp)
  jne    L35
L23:
  mov    -0x8(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L25
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  jmp    L43
L25:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
L43:
  cmpb   $0x4,-0x4(%rbp)
  jne    L65
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  jmp    L65
L35:
  mov    -0x8(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L6
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  jmp    L65
L6:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  jmp    L65
L65:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D36
type_infered: string
name: unpack_data
arguments: data_label: D47
type_infered: string

tool: D27: ldb ,x

tool: D13: tfr d,x

tool: D36: sex

tool: D47: ldd ,x

assistant: ```c
void gen_get_indirect(char typeobj, int reg) {
  if (typeobj == (1 << 2) || typeobj == ((1 << 2) + 1)) {
    if (reg & 1 << 2)
      output_line("ldb ,x");
    else {
      output_line("tfr d,x");
      output_line("ldb ,x");
    }
    if (typeobj == (1 << 2))
      output_line("sex");
  } else {
    if (reg & 1 << 2)
      output_line("ldd ,x");
    else {
      output_line("tfr d,x");
      output_line("ldd ,x");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gen_get_indirect>:
  endbr64
  push   %rbx
  lea    -0x4(%rdi),%eax
  cmp    $0x1,%al
  jbe    L15
  test   $0x4,%sil
  je     L31
  lea    D27(%rip),%rdi
  call   <output_line@plt>
  jmp    L32
L15:
  mov    %edi,%ebx
  test   $0x4,%sil
  je     L0
  lea    D57(%rip),%rdi
  call   <output_line@plt>
L28:
  cmp    $0x4,%bl
  je     L2
L32:
  pop    %rbx
  ret
L0:
  lea    D33(%rip),%rdi
  call   <output_line@plt>
  lea    D57(%rip),%rdi
  call   <output_line@plt>
  jmp    L28
L2:
  lea    D66(%rip),%rdi
  call   <output_line@plt>
  jmp    L32
L31:
  lea    D33(%rip),%rdi
  call   <output_line@plt>
  lea    D27(%rip),%rdi
  call   <output_line@plt>
  jmp    L32
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D57
type_guessed: string
name: extract_symbolic_data
arguments: tag: D33
type_guessed: string
name: extract_symbolic_data
arguments: tag: D66
type_guessed: string

tool: D27: ldd ,x

tool: D57: ldb ,x

tool: D33: tfr d,x

tool: D66: sex

assistant: ```c
void gen_get_indirect(char typeobj, int reg) {
  if (typeobj == (1 << 2) || typeobj == ((1 << 2) + 1)) {
    if (reg & 1 << 2)
      output_line("ldb ,x");
    else {
      output_line("tfr d,x");
      output_line("ldb ,x");
    }
    if (typeobj == (1 << 2))
      output_line("sex");
  } else {
    if (reg & 1 << 2)
      output_line("ldd ,x");
    else {
      output_line("tfr d,x");
      output_line("ldd ,x");
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gen_get_indirect>:
  endbr64
  lea    -0x4(%rdi),%eax
  push   %rbx
  and    $0x4,%esi
  cmp    $0x1,%al
  jbe    L28
  test   %esi,%esi
  je     L7
  lea    D9(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
L7:
  lea    D16(%rip),%rdi
  call   <output_line@plt>
  lea    D9(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
  nopl   0x0(%rax)
L28:
  mov    %edi,%ebx
  test   %esi,%esi
  jne    L32
  lea    D16(%rip),%rdi
  call   <output_line@plt>
L32:
  lea    D27(%rip),%rdi
  call   <output_line@plt>
  cmp    $0x4,%bl
  je     L26
  pop    %rbx
  ret
  nopl   (%rax)
L26:
  lea    D32(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D27
type: string
name: retrieve_data
arguments: label: D32
type: string

tool: D9: ldd ,x

tool: D16: tfr d,x

tool: D27: ldb ,x

tool: D32: sex

assistant: ```c
void gen_get_indirect(char typeobj, int reg) {
  if (typeobj == (1 << 2) || typeobj == ((1 << 2) + 1)) {
    if (reg & 1 << 2)
      output_line("ldb ,x");
    else {
      output_line("tfr d,x");
      output_line("ldb ,x");
    }
    if (typeobj == (1 << 2))
      output_line("sex");
  } else {
    if (reg & 1 << 2)
      output_line("ldd ,x");
    else {
      output_line("tfr d,x");
      output_line("ldd ,x");
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gen_get_indirect>:
  endbr64
  lea    -0x4(%rdi),%eax
  push   %rbx
  and    $0x4,%esi
  cmp    $0x1,%al
  jbe    L31
  test   %esi,%esi
  je     L26
  lea    D2(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
L26:
  lea    D47(%rip),%rdi
  call   <output_line@plt>
  lea    D2(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
  nopl   0x0(%rax)
L31:
  mov    %edi,%ebx
  test   %esi,%esi
  jne    L33
  lea    D47(%rip),%rdi
  call   <output_line@plt>
L33:
  lea    D53(%rip),%rdi
  call   <output_line@plt>
  cmp    $0x4,%bl
  je     L6
  pop    %rbx
  ret
  nopl   (%rax)
L6:
  lea    D17(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D47
datatype: string
name: disassemble_data
arguments: data_tag: D53
datatype: string
name: disassemble_data
arguments: data_tag: D17
datatype: string

tool: D2: ldd ,x

tool: D47: tfr d,x

tool: D53: ldb ,x

tool: D17: sex

assistant: ```c
void gen_get_indirect(char typeobj, int reg) {
  if (typeobj == (1 << 2) || typeobj == ((1 << 2) + 1)) {
    if (reg & 1 << 2)
      output_line("ldb ,x");
    else {
      output_line("tfr d,x");
      output_line("ldb ,x");
    }
    if (typeobj == (1 << 2))
      output_line("sex");
  } else {
    if (reg & 1 << 2)
      output_line("ldd ,x");
    else {
      output_line("tfr d,x");
      output_line("ldd ,x");
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<addfilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %esi,-0x22c(%rbp)
  mov    %rdx,-0x238(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x238(%rbp),%rdx
  lea    -0x220(%rbp),%rax
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <getfilename@plt>
  mov    -0x22c(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    %rax,%rbx
  lea    -0x220(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  lea    -0x220(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  sub    %rax,%rdx
  mov    -0x228(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x220(%rbp),%rax
  mov    %rbx,%rdx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L36
  mov    -0x228(%rbp),%rax
  jmp    L14
L36:
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rdx
  mov    -0x228(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L28
  mov    -0x22c(%rbp),%edx
  mov    -0x228(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
L28:
  mov    -0x22c(%rbp),%edx
  lea    -0x220(%rbp),%rcx
  mov    -0x228(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x228(%rbp),%rax
L14:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  add    $0x230,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: /

assistant: ```c
char *addfilename(char *url, int size, char *pagefile) {
  char buff[512];
  getfilename(buff, 512, pagefile);
  if (!strncmp(url + strlen(url) - strlen(buff), buff, size - strlen(url) + strlen(buff)))
    return url;
  if (!(url[strlen(url) - 1] == '/'))
    strncat(url, "/", size);
  strncat(url, buff, size);
  return url;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addfilename>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    $0x200,%esi
  mov    %r13,%rdi
  call   <getfilename@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %r12d,%rdx
  add    %rax,%rdx
  sub    %rbp,%rdx
  mov    %rbp,%rdi
  sub    %rax,%rdi
  add    %rbx,%rdi
  mov    %r13,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L28
  cmpb   $0x2f,-0x1(%rbx,%rbp,1)
  jne    L0
L31:
  mov    %rsp,%rsi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <strncat@plt>
L28:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %rbx,%rax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %r12d,%edx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  jmp    L31
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: /

assistant: ```c
char *addfilename(char *url, int size, char *pagefile) {
  char buff[512];
  getfilename(buff, 512, pagefile);
  if (!strncmp(url + strlen(url) - strlen(buff), buff, size - strlen(url) + strlen(buff)))
    return url;
  if (!(url[strlen(url) - 1] == '/'))
    strncat(url, "/", size);
  strncat(url, buff, size);
  return url;
}
```