user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xa8(%rbp)
  jmp    L53
L44:
  movl   $0x0,-0xa4(%rbp)
  jmp    L30
L42:
  lea    -0xa0(%rbp),%rdx
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xa8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xa4(%rbp)
L30:
  cmpl   $0x3,-0xa4(%rbp)
  jle    L42
  addl   $0x1,-0xa8(%rbp)
L53:
  cmpl   $0x2,-0xa8(%rbp)
  jle    L44
  movl   $0x0,-0xa8(%rbp)
  jmp    L27
L129:
  movl   $0x0,-0xa4(%rbp)
  jmp    L32
L40:
  lea    -0x70(%rbp),%rdx
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xa8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <flushall@plt>
  addl   $0x1,-0xa4(%rbp)
L32:
  cmpl   $0x3,-0xa4(%rbp)
  jle    L40
  addl   $0x1,-0xa8(%rbp)
L27:
  cmpl   $0x2,-0xa8(%rbp)
  jle    L129
  movl   $0x0,-0xa8(%rbp)
  jmp    L58
L110:
  movl   $0x0,-0xa4(%rbp)
  jmp    L81
L69:
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0xa0(%rbp,%rax,4),%edx
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xa8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    -0x70(%rbp,%rax,4),%eax
  imul   %edx,%eax
  mov    -0xa4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0xa8(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    %eax,-0x40(%rbp,%rdx,4)
  addl   $0x1,-0xa4(%rbp)
L81:
  cmpl   $0x3,-0xa4(%rbp)
  jle    L69
  addl   $0x1,-0xa8(%rbp)
L58:
  cmpl   $0x2,-0xa8(%rbp)
  jle    L110
  movl   $0x0,-0xa8(%rbp)
  jmp    L65
L31:
  movl   $0x0,-0xa4(%rbp)
  jmp    L72
L12:
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xa4(%rbp)
L72:
  cmpl   $0x3,-0xa4(%rbp)
  jle    L12
  addl   $0x1,-0xa8(%rbp)
L65:
  cmpl   $0x2,-0xa8(%rbp)
  jle    L31
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D27
datatype: string
name: disassemble_data
arguments: tag: D29
datatype: string
name: disassemble_data
arguments: tag: D10
datatype: string

tool: D27: Please enter 24 values into the following array


tool: D29: %d

tool: D10: %d, 

assistant: ```c
main() {
  int matrix1[3][4];
  int matrix2[3][4];
  int matrix3[3][4];
  int i;
  int j;
  printf("Please enter 24 values into the following array\n\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrix1[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrix2[i][j]);
      flushall();
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      matrix3[i][j] = (matrix1[i][j] * matrix2[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      printf("%d, ", matrix3[i][j]);
    }
  }
  getchar();
}
```