ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g6_eq45_grad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  movsd  %xmm0,-0x48(%rbp)
  movsd  %xmm1,-0x50(%rbp)
  movsd  %xmm2,-0x58(%rbp)
  movsd  D7(%rip),%xmm0
  divsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x50(%rbp),%xmm0
  mulsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movl   $0x1,-0x3c(%rbp)
  jmp    L18
L11:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x3c(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x38(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x30(%rbp),%xmm0
  addsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  addl   $0x1,-0x3c(%rbp)
L18:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L11
  movsd  -0x58(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  D47(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  -0x50(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x68(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   D40(%rip),%xmm1
  movapd %xmm0,%xmm4
  xorpd  %xmm1,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  mulsd  -0x68(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm2
  movsd  D47(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  -0x60(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: f64
name: retrieve_data
arguments: tag: D47
data_type: f64
name: retrieve_data
arguments: tag: D40
data_type: byte[8]

tool: D7: 1

tool: D47: 6

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double g6_eq45_grad(double r, double a, double c) {
  double r1 = 1.0 / r;
  double r2 = r1 * r1;
  double r4 = r2 * r2;
  double r6 = r4 * r2;
  double ar = a * r;
  double t = 1.0;
  double s = t;
  for (int m = 1; m <= 9; m++) {
    t *= (ar / m);
    s += t;
  }
  return c * r6 * ((6.0 * r1 * s + a * t) * exp(-ar) - 6.0 * r1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<g6_eq45_grad>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x28,%rsp
  movapd %xmm1,%xmm7
  movsd  %xmm1,0x18(%rsp)
  movq   %xmm2,%r14
  movsd  D0(%rip),%xmm1
  movapd %xmm1,%xmm3
  divsd  %xmm0,%xmm3
  movapd %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  movapd %xmm2,%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  %xmm2,%xmm4
  movsd  %xmm4,0x10(%rsp)
  mulsd  %xmm7,%xmm0
  mov    $0x1,%eax
  movq   %xmm1,%rbx
  movsd  %xmm1,(%rsp)
L6:
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  mulsd  (%rsp),%xmm1
  movsd  %xmm1,(%rsp)
  movq   %rbx,%xmm5
  addsd  %xmm1,%xmm5
  movq   %xmm5,%rbx
  add    $0x1,%eax
  cmp    $0xa,%eax
  jne    L6
  mulsd  D13(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  xorpd  D14(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm0
  movsd  0x8(%rsp),%xmm7
  mulsd  %xmm7,%xmm0
  movsd  0x18(%rsp),%xmm1
  mulsd  (%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  subsd  %xmm7,%xmm0
  movsd  0x10(%rsp),%xmm1
  movq   %r14,%xmm3
  mulsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: f64
name: disassemble_data
arguments: tag: D13
type_guessed: f64
name: disassemble_data
arguments: tag: D14
type_guessed: byte[16]

tool: D0: 1

tool: D13: 6

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double g6_eq45_grad(double r, double a, double c) {
  double r1 = 1.0 / r;
  double r2 = r1 * r1;
  double r4 = r2 * r2;
  double r6 = r4 * r2;
  double ar = a * r;
  double t = 1.0;
  double s = t;
  for (int m = 1; m <= 9; m++) {
    t *= (ar / m);
    s += t;
  }
  return c * r6 * ((6.0 * r1 * s + a * t) * exp(-ar) - 6.0 * r1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<g6_eq45_grad>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x1,%eax
  movsd  %xmm2,0x8(%rsp)
  movsd  D29(%rip),%xmm2
  movapd %xmm2,%xmm6
  divsd  %xmm0,%xmm6
  mulsd  %xmm1,%xmm0
  movapd %xmm6,%xmm3
  mulsd  %xmm6,%xmm3
  movapd %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movsd  %xmm4,(%rsp)
  nopl   0x0(%rax)
L9:
  pxor   %xmm5,%xmm5
  movapd %xmm0,%xmm4
  cvtsi2sd %eax,%xmm5
  add    $0x1,%eax
  divsd  %xmm5,%xmm4
  mulsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm2
  cmp    $0xa,%eax
  jne    L9
  mulsd  D17(%rip),%xmm6
  xorpd  D4(%rip),%xmm0
  movsd  %xmm1,0x28(%rsp)
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm6,0x10(%rsp)
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm6
  movsd  0x20(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  movsd  0x28(%rsp),%xmm1
  mulsd  %xmm6,%xmm2
  mulsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  (%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  add    $0x38,%rsp
  subsd  %xmm6,%xmm2
  mulsd  %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: byte[16]

tool: D29: 1

tool: D17: 6

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double g6_eq45_grad(double r, double a, double c) {
  double r1 = 1.0 / r;
  double r2 = r1 * r1;
  double r4 = r2 * r2;
  double r6 = r4 * r2;
  double ar = a * r;
  double t = 1.0;
  double s = t;
  for (int m = 1; m <= 9; m++) {
    t *= (ar / m);
    s += t;
  }
  return c * r6 * ((6.0 * r1 * s + a * t) * exp(-ar) - 6.0 * r1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<g6_eq45_grad>:
  endbr64
  sub    $0x38,%rsp
  movsd  D8(%rip),%xmm6
  movsd  D76(%rip),%xmm7
  movsd  %xmm2,(%rsp)
  movsd  D74(%rip),%xmm2
  movsd  %xmm1,0x20(%rsp)
  movapd %xmm2,%xmm4
  divsd  %xmm0,%xmm4
  mulsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm6
  addsd  %xmm0,%xmm2
  movapd %xmm0,%xmm5
  divsd  D97(%rip),%xmm5
  mulsd  %xmm0,%xmm6
  mulsd  %xmm6,%xmm5
  addsd  %xmm6,%xmm2
  movsd  D51(%rip),%xmm6
  mulsd  %xmm0,%xmm6
  addsd  %xmm5,%xmm2
  mulsd  %xmm5,%xmm6
  movapd %xmm0,%xmm5
  divsd  D95(%rip),%xmm5
  addsd  %xmm6,%xmm2
  mulsd  %xmm6,%xmm5
  movapd %xmm0,%xmm6
  divsd  %xmm7,%xmm6
  movapd %xmm4,%xmm3
  mulsd  %xmm4,%xmm3
  mulsd  %xmm7,%xmm4
  addsd  %xmm5,%xmm2
  movsd  %xmm3,0x28(%rsp)
  movsd  %xmm4,0x8(%rsp)
  mulsd  %xmm5,%xmm6
  movapd %xmm0,%xmm5
  divsd  D17(%rip),%xmm5
  addsd  %xmm6,%xmm2
  mulsd  %xmm6,%xmm5
  movsd  D39(%rip),%xmm6
  mulsd  %xmm0,%xmm6
  addsd  %xmm5,%xmm2
  mulsd  %xmm5,%xmm6
  movapd %xmm0,%xmm5
  divsd  D49(%rip),%xmm5
  xorpd  D61(%rip),%xmm0
  mulsd  %xmm6,%xmm5
  addsd  %xmm6,%xmm2
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm5,0x10(%rsp)
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm5
  movsd  0x18(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm1
  addsd  %xmm5,%xmm2
  movsd  0x28(%rsp),%xmm3
  mulsd  %xmm5,%xmm1
  mulsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm4,%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x38,%rsp
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D8
data_type: byte[8]
name: parse_data
arguments: label: D76
data_type: f64
name: parse_data
arguments: label: D74
data_type: f64
name: parse_data
arguments: label: D97
data_type: byte[8]
name: parse_data
arguments: label: D51
data_type: byte[8]
name: parse_data
arguments: label: D95
data_type: byte[8]
name: parse_data
arguments: label: D17
data_type: byte[8]
name: parse_data
arguments: label: D39
data_type: byte[8]
name: parse_data
arguments: label: D49
data_type: byte[8]
name: parse_data
arguments: label: D61
data_type: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D76: 6

tool: D74: 1

tool: {"D97": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D95": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0xc0,0x3f]}

tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double g6_eq45_grad(double r, double a, double c) {
  double r1 = 1.0 / r;
  double r2 = r1 * r1;
  double r4 = r2 * r2;
  double r6 = r4 * r2;
  double ar = a * r;
  double t = 1.0;
  double s = t;
  for (int m = 1; m <= 9; m++) {
    t *= (ar / m);
    s += t;
  }
  return c * r6 * ((6.0 * r1 * s + a * t) * exp(-ar) - 6.0 * r1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L14
L11:
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  leave
  ret
```

assistant: ```c
int puts(const char *str) {
  int ch;
  while (ch = *str)
    putchar(ch);
  return putchar('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  movsbl %al,%edi
  test   %al,%al
  je     L5
L12:
  call   <putchar@plt>
  movzbl (%rbx),%eax
  movsbl %al,%edi
  test   %al,%al
  jne    L12
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *str) {
  int ch;
  while (ch = *str)
    putchar(ch);
  return putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L13
L18:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L13:
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
```

assistant: ```c
int puts(const char *str) {
  int ch;
  while (ch = *str)
    putchar(ch);
  return putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L15:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L15
L7:
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
```

assistant: ```c
int puts(const char *str) {
  int ch;
  while (ch = *str)
    putchar(ch);
  return putchar('\n');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DispenseAdd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    $0x1,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <Bank_GetAcctByName@plt>
  mov    %eax,%edi
  mov    -0x38(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  call   <Bank_Transfer@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L0
  mov    $0x2,%eax
  jmp    L4
L0:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <Bank_GetAcctName@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <Bank_GetAcctName@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <Bank_GetBalance@plt>
  mov    %eax,%esi
  mov    -0x38(%rbp),%rdi
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <Log_Info@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
type: string
name: read_data
arguments: data_label: D15
type: string

tool: D10: >additions

tool: D15: add %i to %s by %s [balance %i] - %s

assistant: ```c
int DispenseAdd(int ActualUser, int User, int Ammount, const char *ReasonGiven) {
  int ret;
  char *dstName, *byName;
  ret = Bank_Transfer(Bank_GetAcctByName(">additions", 1), User, Ammount, ReasonGiven);
  if (ret)
    return 2;
  byName = Bank_GetAcctName(ActualUser);
  dstName = Bank_GetAcctName(User);
  Log_Info("add %i to %s by %s [balance %i] - %s", Ammount, dstName, byName, Bank_GetBalance(User), ReasonGiven);
  free(byName);
  free(dstName);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DispenseAdd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    $0x1,%esi
  lea    D13(%rip),%rdi
  call   <Bank_GetAcctByName@plt>
  mov    %eax,%edi
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <Bank_Transfer@plt>
  mov    $0x2,%ebx
  test   %eax,%eax
  jne    L1
  mov    %eax,%ebx
  mov    %r14d,%edi
  call   <Bank_GetAcctName@plt>
  mov    %rax,%r15
  mov    %ebp,%edi
  call   <Bank_GetAcctName@plt>
  mov    %rax,%r14
  mov    %ebp,%edi
  call   <Bank_GetBalance@plt>
  mov    %eax,%r8d
  mov    %r13,%r9
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r12d,%esi
  lea    D17(%rip),%rdi
  call   <Log_Info@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
L1:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
type_guessed: string
name: retrieve_data
arguments: label: D17
type_guessed: string

tool: D13: >additions

tool: D17: add %i to %s by %s [balance %i] - %s

assistant: ```c
int DispenseAdd(int ActualUser, int User, int Ammount, const char *ReasonGiven) {
  int ret;
  char *dstName, *byName;
  ret = Bank_Transfer(Bank_GetAcctByName(">additions", 1), User, Ammount, ReasonGiven);
  if (ret)
    return 2;
  byName = Bank_GetAcctName(ActualUser);
  dstName = Bank_GetAcctName(User);
  Log_Info("add %i to %s by %s [balance %i] - %s", Ammount, dstName, byName, Bank_GetBalance(User), ReasonGiven);
  free(byName);
  free(dstName);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DispenseAdd>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  lea    D5(%rip),%rdi
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <Bank_GetAcctByName@plt>
  mov    %rbx,%rcx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <Bank_Transfer@plt>
  test   %eax,%eax
  jne    L7
  mov    %r14d,%edi
  mov    %eax,%r12d
  call   <Bank_GetAcctName@plt>
  mov    %ebp,%edi
  mov    %rax,%r15
  call   <Bank_GetAcctName@plt>
  mov    %ebp,%edi
  mov    %rax,%r14
  call   <Bank_GetBalance@plt>
  mov    %rbx,%r9
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %eax,%r8d
  mov    %r13d,%esi
  lea    D18(%rip),%rdi
  call   <Log_Info@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string

tool: D5: >additions

tool: D18: add %i to %s by %s [balance %i] - %s

assistant: ```c
int DispenseAdd(int ActualUser, int User, int Ammount, const char *ReasonGiven) {
  int ret;
  char *dstName, *byName;
  ret = Bank_Transfer(Bank_GetAcctByName(">additions", 1), User, Ammount, ReasonGiven);
  if (ret)
    return 2;
  byName = Bank_GetAcctName(ActualUser);
  dstName = Bank_GetAcctName(User);
  Log_Info("add %i to %s by %s [balance %i] - %s", Ammount, dstName, byName, Bank_GetBalance(User), ReasonGiven);
  free(byName);
  free(dstName);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DispenseAdd>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  lea    D5(%rip),%rdi
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <Bank_GetAcctByName@plt>
  mov    %rbx,%rcx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <Bank_Transfer@plt>
  test   %eax,%eax
  jne    L0
  mov    %r14d,%edi
  mov    %eax,%r12d
  call   <Bank_GetAcctName@plt>
  mov    %ebp,%edi
  mov    %rax,%r15
  call   <Bank_GetAcctName@plt>
  mov    %ebp,%edi
  mov    %rax,%r14
  call   <Bank_GetBalance@plt>
  mov    %rbx,%r9
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %eax,%r8d
  mov    %r13d,%esi
  lea    D9(%rip),%rdi
  call   <Log_Info@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
L0:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string

tool: D5: >additions

tool: D9: add %i to %s by %s [balance %i] - %s

assistant: ```c
int DispenseAdd(int ActualUser, int User, int Ammount, const char *ReasonGiven) {
  int ret;
  char *dstName, *byName;
  ret = Bank_Transfer(Bank_GetAcctByName(">additions", 1), User, Ammount, ReasonGiven);
  if (ret)
    return 2;
  byName = Bank_GetAcctName(ActualUser);
  dstName = Bank_GetAcctName(User);
  Log_Info("add %i to %s by %s [balance %i] - %s", Ammount, dstName, byName, Bank_GetBalance(User), ReasonGiven);
  free(byName);
  free(dstName);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_159_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_159_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk1 = T & stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_159_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%edx
  not    %edx
  and    (%rdi),%al
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_159_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk1 = T & stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: What is the c source code of the assembly code below?

```asm
<rop3_159_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_159_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk1 = T & stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_159_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_159_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk1 = T & stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<take_out_ip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L22
L31:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  je     L11
  subl   $0x1,-0x14(%rbp)
L22:
  cmpl   $0x0,-0x14(%rbp)
  jns    L31
  jmp    L16
L11:
  nop
L16:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void take_out_ip(char *pack) {
  char *ip = (char *)malloc(20);
  int i, flag = 0, j = 0;
  for (i = strlen(pack) - 1; i >= 0; i--) {
    if (pack[i] == '|')
      break;
  }
  pack[i] = '\0';
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<take_out_ip>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L23
  movslq %eax,%rdx
  add    %rbx,%rdx
L27:
  cmpb   $0x7c,(%rdx)
  je     L23
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  jne    L27
L23:
  cltq
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void take_out_ip(char *pack) {
  char *ip = (char *)malloc(20);
  int i, flag = 0, j = 0;
  for (i = strlen(pack) - 1; i >= 0; i--) {
    if (pack[i] == '|')
      break;
  }
  pack[i] = '\0';
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<take_out_ip>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L33
  movslq %eax,%rdx
  add    %rbx,%rdx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L2:
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  je     L10
L25:
  cmpb   $0x7c,(%rdx)
  jne    L2
L43:
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    -0x1(%rbx),%rdx
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
L33:
  cltq
  lea    (%rbx,%rax,1),%rdx
  jmp    L43
```

assistant: ```c
void take_out_ip(char *pack) {
  char *ip = (char *)malloc(20);
  int i, flag = 0, j = 0;
  for (i = strlen(pack) - 1; i >= 0; i--) {
    if (pack[i] == '|')
      break;
  }
  pack[i] = '\0';
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<take_out_ip>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L37
  movslq %eax,%rdx
  add    %rbx,%rdx
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L25:
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  je     L36
L40:
  cmpb   $0x7c,(%rdx)
  jne    L25
L32:
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L36:
  lea    -0x1(%rbx),%rdx
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
L37:
  cltq
  lea    (%rbx,%rax,1),%rdx
  jmp    L32
```

assistant: ```c
void take_out_ip(char *pack) {
  char *ip = (char *)malloc(20);
  int i, flag = 0, j = 0;
  for (i = strlen(pack) - 1; i >= 0; i--) {
    if (pack[i] == '|')
      break;
  }
  pack[i] = '\0';
  return;
}
```