ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<psmat4_assign_mat3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mat4_assign_mat3@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_assign_mat3(struct mat4 *result, struct mat3 *m) {
  mat4_assign_mat3((float *)result, (float *)m);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<psmat4_assign_mat3>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat4_assign_mat3@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_assign_mat3(struct mat4 *result, struct mat3 *m) {
  mat4_assign_mat3((float *)result, (float *)m);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<psmat4_assign_mat3>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat4_assign_mat3@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_assign_mat3(struct mat4 *result, struct mat3 *m) {
  mat4_assign_mat3((float *)result, (float *)m);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <f@plt>
  mov    %eax,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <f@plt>
  add    %ebx,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main(void) {
  int a[5];
  int *b = malloc(sizeof(int) * 5);
  return f(a) + f(b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rsp,%rdi
  call   <f@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <f@plt>
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a[5];
  int *b = malloc(sizeof(int) * 5);
  return f(a) + f(b);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x14,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rsp,%rdi
  mov    %rax,%rbp
  call   <f@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <f@plt>
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a[5];
  int *b = malloc(sizeof(int) * 5);
  return f(a) + f(b);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x14,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rsp,%rdi
  mov    %rax,%rbp
  call   <f@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <f@plt>
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a[5];
  int *b = malloc(sizeof(int) * 5);
  return f(a) + f(b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_libname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x2,%eax
  jne    L38
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L39
L38:
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x3,%eax
  jne    L8
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L39
L8:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L39:
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
data_type: string
name: retrieve_data
arguments: data_tag: D2
data_type: string
name: retrieve_data
arguments: data_tag: D27
data_type: string

tool: D25: loongson3a


tool: D2: loongson3b


tool: D27: mips32


assistant: ```c
void get_libname(void) {
  if (detect() == 2) {
    printf("loongson3a\n");
  } else if (detect() == 3) {
    printf("loongson3b\n");
  } else {
    printf("mips32\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_libname>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x2,%eax
  je     L23
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x3,%eax
  je     L4
  lea    D0(%rip),%rdi
  call   <printf@plt>
L27:
  add    $0x8,%rsp
  ret
L23:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L4:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L27
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D4
datatype: string
name: read_data
arguments: tag: D14
datatype: string

tool: D0: mips32


tool: D4: loongson3a


tool: D14: loongson3b


assistant: ```c
void get_libname(void) {
  if (detect() == 2) {
    printf("loongson3a\n");
  } else if (detect() == 3) {
    printf("loongson3b\n");
  } else {
    printf("mips32\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_libname>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x2,%eax
  je     L7
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x3,%eax
  je     L2
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L2:
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L7:
  lea    D22(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D22
type_infered: string

tool: D14: mips32


tool: D0: loongson3b


tool: D22: loongson3a


assistant: ```c
void get_libname(void) {
  if (detect() == 2) {
    printf("loongson3a\n");
  } else if (detect() == 3) {
    printf("loongson3b\n");
  } else {
    printf("mips32\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_libname>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x2,%eax
  je     L4
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x3,%eax
  je     L0
  lea    D23(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L0:
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L4:
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D23
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D23: mips32


tool: D17: loongson3b


tool: D8: loongson3a


assistant: ```c
void get_libname(void) {
  if (detect() == 2) {
    printf("loongson3a\n");
  } else if (detect() == 3) {
    printf("loongson3b\n");
  } else {
    printf("mips32\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_env_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L13
L16:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L13:
  leave
  ret
```

assistant: ```c
char *get_env_val(const char *env) {
  char *p_equal = strchr(env, '=');
  if (!p_equal) {
    return NULL;
  }
  int val_len = strlen(env) - (p_equal - env) - 1;
  char *val = (char *)malloc(val_len + 1);
  memcpy(val, p_equal + 1, val_len);
  val[val_len] = '\0';
  return val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_env_val>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  sub    %rbp,%rdx
  sub    %edx,%eax
  mov    %eax,%edi
  lea    -0x1(%rax),%r12d
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x1(%rbx),%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %r12d,%r12
  movb   $0x0,0x0(%rbp,%r12,1)
L1:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %rax,%rbp
  jmp    L1
```

assistant: ```c
char *get_env_val(const char *env) {
  char *p_equal = strchr(env, '=');
  if (!p_equal) {
    return NULL;
  }
  int val_len = strlen(env) - (p_equal - env) - 1;
  char *val = (char *)malloc(val_len + 1);
  memcpy(val, p_equal + 1, val_len);
  val[val_len] = '\0';
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_env_val>:
  endbr64
  push   %r12
  mov    $0x3d,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  sub    %rbp,%rdx
  sub    %edx,%eax
  mov    %eax,%edi
  lea    -0x1(%rax),%ebp
  call   <malloc@plt>
  lea    0x1(%rbx),%rsi
  mov    %ebp,%edx
  movslq %ebp,%rbp
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *get_env_val(const char *env) {
  char *p_equal = strchr(env, '=');
  if (!p_equal) {
    return NULL;
  }
  int val_len = strlen(env) - (p_equal - env) - 1;
  char *val = (char *)malloc(val_len + 1);
  memcpy(val, p_equal + 1, val_len);
  val[val_len] = '\0';
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_env_val>:
  endbr64
  push   %r12
  mov    $0x3d,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  sub    %rbp,%rdx
  sub    %edx,%eax
  mov    %eax,%edi
  lea    -0x1(%rax),%ebp
  call   <malloc@plt>
  lea    0x1(%rbx),%rsi
  mov    %ebp,%edx
  movslq %ebp,%rbp
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *get_env_val(const char *env) {
  char *p_equal = strchr(env, '=');
  if (!p_equal) {
    return NULL;
  }
  int val_len = strlen(env) - (p_equal - env) - 1;
  char *val = (char *)malloc(val_len + 1);
  memcpy(val, p_equal + 1, val_len);
  val[val_len] = '\0';
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,%rbx
  jmp    L13
L23:
  add    $0x1,%rbx
L13:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L23
  nop
L0:
  sub    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L0
  add    $0x1,%rbx
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0xa,(%rax)
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
trim(str) {
  register char *cp;
  cp = str;
  while (*cp)
    cp++;
  while (*--cp == ' ')
    ;
  cp++;
  *cp++ = '\n';
  *cp++ = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<trim>:
  endbr64
  movslq %edi,%rdi
  cmpb   $0x0,(%rdi)
  je     L13
L14:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L14
L13:
  mov    %rdi,%rax
  sub    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  je     L13
  movb   $0xa,(%rax)
  movb   $0x0,0x1(%rax)
  ret
```

assistant: ```c
trim(str) {
  register char *cp;
  cp = str;
  while (*cp)
    cp++;
  while (*--cp == ' ')
    ;
  cp++;
  *cp++ = '\n';
  *cp++ = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim>:
  endbr64
  movslq %edi,%rdi
  cmpb   $0x0,(%rdi)
  je     L16
  nopl   0x0(%rax)
L20:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L20
  nopl   0x0(%rax)
L16:
  mov    %rdi,%rax
  sub    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  je     L16
  mov    $0xa,%edx
  mov    %dx,(%rax)
  ret
```

assistant: ```c
trim(str) {
  register char *cp;
  cp = str;
  while (*cp)
    cp++;
  while (*--cp == ' ')
    ;
  cp++;
  *cp++ = '\n';
  *cp++ = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim>:
  endbr64
  movslq %edi,%rdi
  cmpb   $0x0,(%rdi)
  je     L10
  nopl   0x0(%rax)
L9:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L9
  nopl   0x0(%rax)
L10:
  mov    %rdi,%rax
  sub    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  je     L10
  mov    $0xa,%edx
  mov    %dx,(%rax)
  ret
```

assistant: ```c
trim(str) {
  register char *cp;
  cp = str;
  while (*cp)
    cp++;
  while (*--cp == ' ')
    ;
  cp++;
  *cp++ = '\n';
  *cp++ = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__tcgetattr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L4
L13:
  cmpq   $0x0,-0x10(%rbp)
  jne    L21
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L4
L21:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
L4:
  leave
  ret
```

assistant: ```c
int __tcgetattr(int fd, struct termios *termios_p) {
  if (fd < 0) {
    __set_errno(EBADF);
    return -1;
  }
  if (termios_p == NULL) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__tcgetattr>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L39
  test   %rsi,%rsi
  je     L19
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
L4:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
L39:
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  jmp    L4
L19:
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  jmp    L4
```

assistant: ```c
int __tcgetattr(int fd, struct termios *termios_p) {
  if (fd < 0) {
    __set_errno(EBADF);
    return -1;
  }
  if (termios_p == NULL) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__tcgetattr>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L16
  test   %rsi,%rsi
  je     L12
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L12:
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __tcgetattr(int fd, struct termios *termios_p) {
  if (fd < 0) {
    __set_errno(EBADF);
    return -1;
  }
  if (termios_p == NULL) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__tcgetattr>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L5
  test   %rsi,%rsi
  je     L18
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L18:
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __tcgetattr(int fd, struct termios *termios_p) {
  if (fd < 0) {
    __set_errno(EBADF);
    return -1;
  }
  if (termios_p == NULL) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strength_result4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L25
  movl   $0x2a,-0x4(%rbp)
  jmp    L12
L25:
  movl   $0x0,-0x4(%rbp)
L14:
  addl   $0x15,-0x4(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strength_result4(int *data) {
  int i;
  if (data[1]) {
    i = 42;
    goto here;
  }
  i = 0;
  do {
    i = i + 21;
  here:
    data[data[2]] = 2;
  } while (i < data[3]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strength_result4>:
  endbr64
  mov    0x4(%rdi),%eax
  test   %eax,%eax
  jne    L4
L27:
  add    $0x15,%eax
L26:
  movslq 0x8(%rdi),%rdx
  movl   $0x2,(%rdi,%rdx,4)
  cmp    %eax,0xc(%rdi)
  jg     L27
  ret
L4:
  mov    $0x2a,%eax
  jmp    L26
```

assistant: ```c
void strength_result4(int *data) {
  int i;
  if (data[1]) {
    i = 42;
    goto here;
  }
  i = 0;
  do {
    i = i + 21;
  here:
    data[data[2]] = 2;
  } while (i < data[3]);
}
```
user: What is the c source code of the assembly code below:

```asm
<strength_result4>:
  endbr64
  cmpl   $0x1,0x4(%rdi)
  movslq 0x8(%rdi),%rdx
  sbb    %eax,%eax
  and    $0xffffffeb,%eax
  movl   $0x2,(%rdi,%rdx,4)
  add    $0x2a,%eax
  cmp    %eax,0xc(%rdi)
  jle    L14
L1:
  movslq 0x8(%rdi),%rdx
  add    $0x15,%eax
  movl   $0x2,(%rdi,%rdx,4)
  cmp    %eax,0xc(%rdi)
  jg     L1
L14:
  ret
```

assistant: ```c
void strength_result4(int *data) {
  int i;
  if (data[1]) {
    i = 42;
    goto here;
  }
  i = 0;
  do {
    i = i + 21;
  here:
    data[data[2]] = 2;
  } while (i < data[3]);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strength_result4>:
  endbr64
  cmpl   $0x1,0x4(%rdi)
  movslq 0x8(%rdi),%rdx
  sbb    %eax,%eax
  and    $0xffffffeb,%eax
  movl   $0x2,(%rdi,%rdx,4)
  add    $0x2a,%eax
  cmp    %eax,0xc(%rdi)
  jle    L16
L5:
  movslq 0x8(%rdi),%rdx
  add    $0x15,%eax
  movl   $0x2,(%rdi,%rdx,4)
  cmp    %eax,0xc(%rdi)
  jg     L5
L16:
  ret
```

assistant: ```c
void strength_result4(int *data) {
  int i;
  if (data[1]) {
    i = 42;
    goto here;
  }
  i = 0;
  do {
    i = i + 21;
  here:
    data[data[2]] = 2;
  } while (i < data[3]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<overeniDat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  cmpl   $0x63f,-0x4(%rbp)
  jle    L75
  cmpl   $0x0,-0x8(%rbp)
  jle    L75
  cmpl   $0xc,-0x8(%rbp)
  jg     L75
  cmpl   $0x0,-0xc(%rbp)
  jle    L75
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pocetDniVMesici@plt>
  cmp    %eax,-0xc(%rbp)
  jg     L75
  cmpl   $0x0,-0x10(%rbp)
  js     L75
  cmpl   $0x17,-0x10(%rbp)
  jg     L75
  cmpl   $0x0,-0x14(%rbp)
  js     L75
  cmpl   $0x3b,-0x14(%rbp)
  jle    L47
L75:
  mov    $0x0,%eax
  jmp    L45
L47:
  mov    $0x1,%eax
L45:
  leave
  ret
```

assistant: ```c
int overeniDat(int y, int m, int d, int h, int i, int prestupny) {
  if (y < 1600 || m < 1 || m > 12 || d < 1 || d > pocetDniVMesici(m, prestupny) || h < 0 || h > 23 || i < 0 || i > 59)
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<overeniDat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  lea    -0x1(%rsi),%edx
  cmp    $0xb,%edx
  ja     L49
  mov    %edi,%eax
  mov    %esi,%edi
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  cmp    $0x63f,%eax
  jle    L49
  mov    $0x0,%eax
  test   %ebx,%ebx
  jle    L25
  mov    %r9d,%esi
  call   <pocetDniVMesici@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %ebx,%edx
  jl     L25
  cmp    $0x17,%r12d
  seta   %al
  cmp    $0x3b,%ebp
  seta   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  jmp    L25
L49:
  mov    $0x0,%eax
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int overeniDat(int y, int m, int d, int h, int i, int prestupny) {
  if (y < 1600 || m < 1 || m > 12 || d < 1 || d > pocetDniVMesici(m, prestupny) || h < 0 || h > 23 || i < 0 || i > 59)
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<overeniDat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  lea    -0x1(%rsi),%edx
  cmp    $0xb,%edx
  ja     L38
  cmp    $0x63f,%edi
  jle    L38
  test   %ebx,%ebx
  jg     L33
L38:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L33:
  mov    %esi,%edi
  mov    %r9d,%esi
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  call   <pocetDniVMesici@plt>
  cmp    %ebx,%eax
  jl     L38
  cmp    $0x17,%r12d
  pop    %rbx
  seta   %al
  cmp    $0x3b,%ebp
  pop    %rbp
  pop    %r12
  seta   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int overeniDat(int y, int m, int d, int h, int i, int prestupny) {
  if (y < 1600 || m < 1 || m > 12 || d < 1 || d > pocetDniVMesici(m, prestupny) || h < 0 || h > 23 || i < 0 || i > 59)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<overeniDat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  lea    -0x1(%rsi),%edx
  cmp    $0xb,%edx
  ja     L17
  cmp    $0x63f,%edi
  jle    L17
  test   %ebx,%ebx
  jg     L39
L17:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L39:
  mov    %esi,%edi
  mov    %r9d,%esi
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  call   <pocetDniVMesici@plt>
  cmp    %ebx,%eax
  jl     L17
  cmp    $0x17,%r12d
  pop    %rbx
  seta   %al
  cmp    $0x3b,%ebp
  pop    %rbp
  pop    %r12
  seta   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int overeniDat(int y, int m, int d, int h, int i, int prestupny) {
  if (y < 1600 || m < 1 || m > 12 || d < 1 || d > pocetDniVMesici(m, prestupny) || h < 0 || h > 23 || i < 0 || i > 59)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rdtsc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L0:
  rdtsc
  mov    %rax,-0x10(%rbp)
  rdtsc
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  cmp    $0x3e7,%rax
  ja     L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned long long int x, y;
  for (;;) {
    __asm__ volatile("rdtsc" : "=A"(x));
    __asm__ volatile("rdtsc" : "=A"(y));
    if (y - x < 1000)
      return y;
  }
}
```