ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jb     L29
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L17
  nopl   (%rax)
L10:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L10
L17:
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void *memmove(void *dest, const void *src, size_t count) {
  if (dest < src) {
    return memcpy(dest, src, count);
  } else {
    char *p = (char *)dest + count;
    char *s = (char *)src + count;
    while (count--)
      *--p = *--s;
  }
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<i2c_read_beint16_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  imul   -0x50(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x3c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%eax
  cltq
  imul   -0x50(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%esi
  mov    -0x34(%rbp),%eax
  mov    %rcx,%r8
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <i2c_transact@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%eax
  cltq
  imul   -0x50(%rbp),%rax
  cmp    %rax,%rdx
  jne    L7
  movl   $0x0,-0x2c(%rbp)
  jmp    L20
L37:
  mov    -0x2c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x48(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <__rbeu16@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x2c(%rbp)
L20:
  mov    -0x2c(%rbp),%eax
  cltq
  cmp    %rax,-0x50(%rbp)
  ja     L37
  mov    -0x50(%rbp),%rax
  jmp    L43
L7:
  mov    -0x24(%rbp),%eax
L43:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int i2c_read_beint16_array(int fd, int chip_addr, int reg, int16_t *values, size_t count) {
  int sz = sizeof(uint16_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, count * sz);
  if (err == (count * sz)) {
    for (int i = 0; i < count; i++)
      values[i] = (uint16_t)__rbeu16(&data[i * sz]);
    return count;
  }
  return err;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<i2c_read_beint16_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %edx,%r15d
  mov    %rcx,%r13
  mov    %r8,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x0(,%r8,8),%r14
  lea    0x1(%r14),%rdi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    %r15d,(%rax)
  mov    %r14,%r8
  mov    $0x1,%ecx
  mov    %rax,%rdx
  mov    -0x48(%rbp),%esi
  mov    -0x44(%rbp),%edi
  call   <i2c_transact@plt>
  movslq %eax,%rdx
  cmp    %rdx,%r14
  je     L27
L39:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L27:
  test   %r12,%r12
  je     L7
  mov    $0x0,%r14d
L4:
  mov    %rbx,%rdi
  call   <__rbeu16@plt>
  mov    %rax,0x0(%r13,%r14,8)
  add    $0x1,%r14
  add    $0x20,%rbx
  cmp    %r12,%r14
  jne    L4
L7:
  mov    %r12d,%eax
  jmp    L39
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_beint16_array(int fd, int chip_addr, int reg, int16_t *values, size_t count) {
  int sz = sizeof(uint16_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, count * sz);
  if (err == (count * sz)) {
    for (int i = 0; i < count; i++)
      values[i] = (uint16_t)__rbeu16(&data[i * sz]);
    return count;
  }
  return err;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<i2c_read_beint16_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  lea    0x0(,%r8,8),%r12
  push   %rbx
  lea    0x1(%r12),%rdi
  sub    $0x28,%rsp
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    -0x44(%rbp),%edx
  mov    -0x48(%rbp),%esi
  mov    %r12,%r8
  mov    $0x1,%ecx
  mov    %r15d,%edi
  mov    %rax,%rbx
  mov    %edx,(%rax)
  mov    %rax,%rdx
  call   <i2c_transact@plt>
  movslq %eax,%rdx
  cmp    %rdx,%r12
  je     L23
L27:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L23:
  test   %r13,%r13
  je     L43
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %rbx,%rdi
  add    $0x20,%rbx
  call   <__rbeu16@plt>
  mov    %rax,(%r14,%r12,8)
  add    $0x1,%r12
  cmp    %r12,%r13
  jne    L37
L43:
  mov    %r13d,%eax
  jmp    L27
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_beint16_array(int fd, int chip_addr, int reg, int16_t *values, size_t count) {
  int sz = sizeof(uint16_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, count * sz);
  if (err == (count * sz)) {
    for (int i = 0; i < count; i++)
      values[i] = (uint16_t)__rbeu16(&data[i * sz]);
    return count;
  }
  return err;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<i2c_read_beint16_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  lea    0x0(,%r8,8),%r12
  push   %rbx
  lea    0x1(%r12),%rdi
  sub    $0x28,%rsp
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    -0x44(%rbp),%edx
  mov    -0x48(%rbp),%esi
  mov    %r12,%r8
  mov    $0x1,%ecx
  mov    %r15d,%edi
  mov    %rax,%rbx
  mov    %edx,(%rax)
  mov    %rax,%rdx
  call   <i2c_transact@plt>
  movslq %eax,%rdx
  cmp    %rdx,%r12
  je     L26
L4:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L26:
  test   %r13,%r13
  je     L35
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rbx,%rdi
  add    $0x20,%rbx
  call   <__rbeu16@plt>
  mov    %rax,(%r14,%r12,8)
  add    $0x1,%r12
  cmp    %r12,%r13
  jne    L40
L35:
  mov    %r13d,%eax
  jmp    L4
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_beint16_array(int fd, int chip_addr, int reg, int16_t *values, size_t count) {
  int sz = sizeof(uint16_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, count * sz);
  if (err == (count * sz)) {
    for (int i = 0; i < count; i++)
      values[i] = (uint16_t)__rbeu16(&data[i * sz]);
    return count;
  }
  return err;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prefix_Func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
int prefix_Func(int something) {
#pragma critTer : 3 :../../ test / resources / functionNaming.c:
  int i;
#pragma critTer : 4 :../../ test / resources / functionNaming.c:
#pragma critTer : 5 :../../ test / resources / functionNaming.c:
  i = 2;
#pragma critTer : 6 :../../ test / resources / functionNaming.c:
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prefix_Func>:
  endbr64
  ret
```

assistant: ```c
int prefix_Func(int something) {
#pragma critTer : 3 :../../ test / resources / functionNaming.c:
  int i;
#pragma critTer : 4 :../../ test / resources / functionNaming.c:
#pragma critTer : 5 :../../ test / resources / functionNaming.c:
  i = 2;
#pragma critTer : 6 :../../ test / resources / functionNaming.c:
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<prefix_Func>:
  endbr64
  ret
```

assistant: ```c
int prefix_Func(int something) {
#pragma critTer : 3 :../../ test / resources / functionNaming.c:
  int i;
#pragma critTer : 4 :../../ test / resources / functionNaming.c:
#pragma critTer : 5 :../../ test / resources / functionNaming.c:
  i = 2;
#pragma critTer : 6 :../../ test / resources / functionNaming.c:
}
```
user: Translate the below assembly code into C programming language:

```asm
<prefix_Func>:
  endbr64
  ret
```

assistant: ```c
int prefix_Func(int something) {
#pragma critTer : 3 :../../ test / resources / functionNaming.c:
  int i;
#pragma critTer : 4 :../../ test / resources / functionNaming.c:
#pragma critTer : 5 :../../ test / resources / functionNaming.c:
  i = 2;
#pragma critTer : 6 :../../ test / resources / functionNaming.c:
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_zero_padded>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L33
L29:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L29
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L3
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  jmp    L25
L3:
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int _zero_padded(unsigned long num, int width) {
  int n = 1;
  while (num /= 10L)
    n++;
  return width > n ? width - n : 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_zero_padded>:
  endbr64
  movabs $0xcccccccccccccccd,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x3,%rdx
  cmp    $0x9,%rdi
  jbe    L24
  mov    $0x1,%ecx
  movabs $0xcccccccccccccccd,%r8
L23:
  add    $0x1,%ecx
  mov    %rdx,%rdi
  mov    %rdx,%rax
  mul    %r8
  shr    $0x3,%rdx
  cmp    $0x9,%rdi
  ja     L23
L19:
  mov    %esi,%eax
  sub    %ecx,%eax
  cmp    %ecx,%esi
  mov    $0x0,%edx
  cmovle %edx,%eax
  ret
L24:
  mov    $0x1,%ecx
  jmp    L19
```

assistant: ```c
int _zero_padded(unsigned long num, int width) {
  int n = 1;
  while (num /= 10L)
    n++;
  return width > n ? width - n : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_zero_padded>:
  endbr64
  movabs $0xcccccccccccccccd,%r8
  mov    %rdi,%rax
  mul    %r8
  shr    $0x3,%rdx
  cmp    $0x9,%rdi
  mov    $0x1,%edi
  jbe    L8
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%edi
  mul    %r8
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  ja     L10
L8:
  mov    %esi,%eax
  xor    %edx,%edx
  sub    %edi,%eax
  cmp    %edi,%esi
  cmovle %edx,%eax
  ret
```

assistant: ```c
int _zero_padded(unsigned long num, int width) {
  int n = 1;
  while (num /= 10L)
    n++;
  return width > n ? width - n : 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_zero_padded>:
  endbr64
  movabs $0xcccccccccccccccd,%r8
  mov    %rdi,%rax
  mul    %r8
  shr    $0x3,%rdx
  cmp    $0x9,%rdi
  mov    $0x1,%edi
  jbe    L13
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%edi
  mul    %r8
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  ja     L3
L13:
  mov    %esi,%eax
  xor    %edx,%edx
  sub    %edi,%eax
  cmp    %edi,%esi
  cmovle %edx,%eax
  ret
```

assistant: ```c
int _zero_padded(unsigned long num, int width) {
  int n = 1;
  while (num /= 10L)
    n++;
  return width > n ? width - n : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<big_or_little_endian_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mus_char_to_ulint@plt>
  jmp    L12
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mus_char_to_ubint@plt>
L12:
  leave
  ret
```

assistant: ```c
unsigned int big_or_little_endian_uint(const unsigned char *n, int little) {
  if (little)
    return (mus_char_to_ulint(n));
  return (mus_char_to_ubint(n));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<big_or_little_endian_uint>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jne    L3
  call   <mus_char_to_ubint@plt>
L1:
  add    $0x8,%rsp
  ret
L3:
  call   <mus_char_to_ulint@plt>
  jmp    L1
```

assistant: ```c
unsigned int big_or_little_endian_uint(const unsigned char *n, int little) {
  if (little)
    return (mus_char_to_ulint(n));
  return (mus_char_to_ubint(n));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<big_or_little_endian_uint>:
  endbr64
  test   %esi,%esi
  jne    L2
  jmp    1070 <mus_char_to_ubint@plt>
  nopl   (%rax)
L2:
  jmp    1060 <mus_char_to_ulint@plt>
```

assistant: ```c
unsigned int big_or_little_endian_uint(const unsigned char *n, int little) {
  if (little)
    return (mus_char_to_ulint(n));
  return (mus_char_to_ubint(n));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<big_or_little_endian_uint>:
  endbr64
  test   %esi,%esi
  jne    L2
  jmp    1070 <mus_char_to_ubint@plt>
  nopl   (%rax)
L2:
  jmp    1060 <mus_char_to_ulint@plt>
```

assistant: ```c
unsigned int big_or_little_endian_uint(const unsigned char *n, int little) {
  if (little)
    return (mus_char_to_ulint(n));
  return (mus_char_to_ubint(n));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitmap_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L19
  cmpl   $0x40,-0x24(%rbp)
  jg     L19
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L17
L19:
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x3f,%rax
  shr    $0x6,%rax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
L17:
  nop
  leave
  ret
```

assistant: ```c
void bitmap_copy(unsigned long *dst, const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= ((int)((sizeof(long) * 8)))))
    *dst = *src;
  else {
    int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memcpy(dst, src, len);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitmap_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %edx,%edi
  call   <__builtin_constant_p@plt>
  cmp    $0x40,%ebx
  jg     L24
  test   %rax,%rax
  je     L24
  mov    (%r12),%rax
  mov    %rax,0x0(%rbp)
  jmp    L5
L24:
  movslq %ebx,%rdx
  add    $0x3f,%rdx
  shr    $0x6,%rdx
  shl    $0x3,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bitmap_copy(unsigned long *dst, const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= ((int)((sizeof(long) * 8)))))
    *dst = *src;
  else {
    int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memcpy(dst, src, len);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitmap_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %edx,%ebx
  call   <__builtin_constant_p@plt>
  cmp    $0x40,%ebx
  jg     L0
  test   %rax,%rax
  je     L0
  mov    (%r12),%rax
  pop    %rbx
  mov    %rax,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  movslq %ebx,%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  add    $0x3f,%rdx
  pop    %rbp
  pop    %r12
  shr    $0x6,%rdx
  shl    $0x3,%edx
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void bitmap_copy(unsigned long *dst, const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= ((int)((sizeof(long) * 8)))))
    *dst = *src;
  else {
    int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memcpy(dst, src, len);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitmap_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %edx,%ebx
  call   <__builtin_constant_p@plt>
  cmp    $0x40,%ebx
  jg     L4
  test   %rax,%rax
  je     L4
  mov    (%r12),%rax
  pop    %rbx
  mov    %rax,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L4:
  movslq %ebx,%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  add    $0x3f,%rdx
  pop    %rbp
  pop    %r12
  shr    $0x6,%rdx
  shl    $0x3,%edx
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void bitmap_copy(unsigned long *dst, const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= ((int)((sizeof(long) * 8)))))
    *dst = *src;
  else {
    int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memcpy(dst, src, len);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L6
L16:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D13: Enter your number:

tool: D18: %i

assistant: ```c
int main(void) {
  int number, right_digit;
  printf("Enter your number:\n");
  scanf("%i", &number);
  while (number != 0) {
    right_digit = number % 10;
    printf("%i", right_digit);
    number = number / 10;
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L10
  lea    D18(%rip),%rbx
L6:
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sar    $0x1f,%eax
  sub    %eax,%esi
  mov    %esi,0x4(%rsp)
  jne    L6
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D26
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string

tool: D26: Enter your number:

tool: D18: %i

assistant: ```c
int main(void) {
  int number, right_digit;
  printf("Enter your number:\n");
  scanf("%i", &number);
  while (number != 0) {
    right_digit = number % 10;
    printf("%i", right_digit);
    number = number / 10;
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D14(%rip),%rdi
  lea    D9(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L2
  nopl   0x0(%rax)
L14:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  sar    $0x1f,%eax
  sar    $0x22,%rsi
  sub    %eax,%esi
  mov    %esi,0x4(%rsp)
  jne    L14
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string

tool: D14: Enter your number:

tool: D9: %i

assistant: ```c
int main(void) {
  int number, right_digit;
  printf("Enter your number:\n");
  scanf("%i", &number);
  while (number != 0) {
    right_digit = number % 10;
    printf("%i", right_digit);
    number = number / 10;
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rdi
  lea    D6(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L7
  nopl   0x0(%rax)
L26:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  sar    $0x1f,%eax
  sar    $0x22,%rsi
  sub    %eax,%esi
  mov    %esi,0x4(%rsp)
  jne    L26
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D6
data_type: string

tool: D3: Enter your number:

tool: D6: %i

assistant: ```c
int main(void) {
  int number, right_digit;
  printf("Enter your number:\n");
  scanf("%i", &number);
  while (number != 0) {
    right_digit = number % 10;
    printf("%i", right_digit);
    number = number / 10;
  }
  printf("\n");
  return 0;
}
```