ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<threeWayQuickSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  cmp    %edx,%esi
  jl     L50
L53:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %r12d,%ecx
  sub    %ebx,%ecx
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  add    %ebx,%edx
  movslq %edx,%rdx
  mov    0x0(%rbp,%rdx,4),%r13d
  mov    %ebx,%r14d
  jmp    L59
L7:
  lea    0x1(%r14),%r15d
  lea    0x1(%rbx),%eax
  mov    %eax,0x4(%rsp)
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r15d,%r14d
  mov    0x4(%rsp),%ebx
L24:
  cmp    %r12d,%ebx
  jg     L70
L59:
  movslq %ebx,%rax
  mov    0x0(%rbp,%rax,4),%eax
  cmp    %r13d,%eax
  jl     L7
  jg     L20
  add    $0x1,%ebx
  jmp    L24
L20:
  lea    -0x1(%r12),%r15d
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r15d,%r12d
  jmp    L24
L70:
  lea    -0x1(%r14),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <threeWayQuickSort>
  lea    0x1(%r12),%esi
  mov    0xc(%rsp),%edx
  mov    %rbp,%rdi
  call   <threeWayQuickSort>
  jmp    L53
```

assistant: ```c
void threeWayQuickSort(int *inArray, int left, int right) {
  if (left >= right)
    return;
  int i = left, j = left, k = right;
  int pivot = inArray[left + rand() % (right - left + 1)];
  while (i <= k) {
    if (inArray[i] < pivot)
      swap(inArray, i++, j++);
    else if (inArray[i] > pivot)
      swap(inArray, i, k--);
    else
      i++;
  }
  threeWayQuickSort(inArray, left, j - 1);
  threeWayQuickSort(inArray, k + 1, right);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<threeWayQuickSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %edx,%esi
  jge    L55
  mov    %rdi,%r14
  mov    %esi,%r13d
L78:
  xor    %eax,%eax
  mov    %r13d,%ebp
  call   <rand@plt>
  mov    0xc(%rsp),%r12d
  mov    %r13d,%r8d
  cltd
  mov    %r12d,%esi
  sub    %r13d,%esi
  add    $0x1,%esi
  idiv   %esi
  add    %r13d,%edx
  movslq %edx,%rdx
  mov    (%r14,%rdx,4),%r15d
  jmp    L60
  xchg   %ax,%ax
L26:
  jg     L68
  add    $0x1,%ebp
L62:
  cmp    %r12d,%ebp
  jg     L46
L60:
  movslq %ebp,%rax
  cmp    %r15d,(%r14,%rax,4)
  jge    L26
  lea    0x1(%rbp),%ebx
  lea    0x1(%r8),%eax
  mov    %r8d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    %ebx,%ebp
  mov    %eax,0x8(%rsp)
  call   <swap@plt>
  mov    0x8(%rsp),%r8d
  cmp    %r12d,%ebp
  jle    L60
L46:
  mov    %r13d,%esi
  lea    -0x1(%r8),%edx
  lea    0x1(%r12),%r13d
  mov    %r14,%rdi
  call   <threeWayQuickSort>
  cmp    0xc(%rsp),%r13d
  jl     L78
L55:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L68:
  mov    %r12d,%edx
  lea    -0x1(%r12),%ebx
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    %r8d,0x8(%rsp)
  mov    %ebx,%r12d
  call   <swap@plt>
  mov    0x8(%rsp),%r8d
  jmp    L62
```

assistant: ```c
void threeWayQuickSort(int *inArray, int left, int right) {
  if (left >= right)
    return;
  int i = left, j = left, k = right;
  int pivot = inArray[left + rand() % (right - left + 1)];
  while (i <= k) {
    if (inArray[i] < pivot)
      swap(inArray, i++, j++);
    else if (inArray[i] > pivot)
      swap(inArray, i, k--);
    else
      i++;
  }
  threeWayQuickSort(inArray, left, j - 1);
  threeWayQuickSort(inArray, k + 1, right);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<threeWayQuickSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %edx,%esi
  jge    L58
  mov    %rdi,%r14
  mov    %esi,%r13d
L75:
  xor    %eax,%eax
  mov    %r13d,%ebp
  call   <rand@plt>
  mov    0xc(%rsp),%r12d
  mov    %r13d,%r8d
  cltd
  mov    %r12d,%esi
  sub    %r13d,%esi
  add    $0x1,%esi
  idiv   %esi
  add    %r13d,%edx
  movslq %edx,%rdx
  mov    (%r14,%rdx,4),%r15d
  jmp    L18
  xchg   %ax,%ax
L65:
  jg     L32
  add    $0x1,%ebp
L40:
  cmp    %r12d,%ebp
  jg     L13
L18:
  movslq %ebp,%rax
  cmp    %r15d,(%r14,%rax,4)
  jge    L65
  lea    0x1(%rbp),%ebx
  lea    0x1(%r8),%eax
  mov    %r8d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    %ebx,%ebp
  mov    %eax,0x8(%rsp)
  call   <swap@plt>
  mov    0x8(%rsp),%r8d
  cmp    %r12d,%ebp
  jle    L18
L13:
  mov    %r13d,%esi
  lea    -0x1(%r8),%edx
  lea    0x1(%r12),%r13d
  mov    %r14,%rdi
  call   <threeWayQuickSort>
  cmp    0xc(%rsp),%r13d
  jl     L75
L58:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L32:
  mov    %r12d,%edx
  lea    -0x1(%r12),%ebx
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    %r8d,0x8(%rsp)
  mov    %ebx,%r12d
  call   <swap@plt>
  mov    0x8(%rsp),%r8d
  jmp    L40
```

assistant: ```c
void threeWayQuickSort(int *inArray, int left, int right) {
  if (left >= right)
    return;
  int i = left, j = left, k = right;
  int pivot = inArray[left + rand() % (right - left + 1)];
  while (i <= k) {
    if (inArray[i] < pivot)
      swap(inArray, i++, j++);
    else if (inArray[i] > pivot)
      swap(inArray, i, k--);
    else
      i++;
  }
  threeWayQuickSort(inArray, left, j - 1);
  threeWayQuickSort(inArray, k + 1, right);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lcm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L26
  cmpl   $0x0,-0x8(%rbp)
  jle    L26
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L26
  mov    $0x1,%eax
  jmp    L46
L26:
  mov    $0x0,%eax
L46:
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L7
L0:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L7:
  cmpl   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
void lcm(int m, int n) {
  int a = m, b = n, gcd;
  assert(a > 0 && b > 0 && b > a);
  while (b != 0) {
    gcd = b;
    b = a % b;
    a = gcd;
  }
  printf("%d\n", m * n / gcd);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lcm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  test   %edi,%edi
  setg   %al
  cmp    %esi,%edi
  setl   %dl
  and    %edx,%eax
  test   %esi,%esi
  setg   %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  test   %r12d,%r12d
  je     L2
  mov    %r12d,%ecx
  mov    %ebp,%eax
L1:
  mov    %ecx,%ebx
  cltd
  idiv   %ecx
  mov    %edx,%ecx
  mov    %ebx,%eax
  test   %edx,%edx
  jne    L1
L2:
  mov    %ebp,%eax
  imul   %r12d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: %d


assistant: ```c
void lcm(int m, int n) {
  int a = m, b = n, gcd;
  assert(a > 0 && b > 0 && b > a);
  while (b != 0) {
    gcd = b;
    b = a % b;
    a = gcd;
  }
  printf("%d\n", m * n / gcd);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lcm>:
  endbr64
  test   %edi,%edi
  push   %r12
  mov    %esi,%r12d
  setg   %al
  cmp    %esi,%edi
  push   %rbp
  mov    %edi,%ebp
  setl   %dl
  push   %rbx
  xor    %edi,%edi
  and    %edx,%eax
  test   %esi,%esi
  setg   %dil
  and    %eax,%edi
  call   <assert@plt>
  test   %r12d,%r12d
  je     L15
  mov    %r12d,%edx
  mov    %ebp,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %edx,%ebx
  cltd
  idiv   %ebx
  mov    %ebx,%eax
  test   %edx,%edx
  jne    L16
L15:
  mov    %ebp,%eax
  lea    D6(%rip),%rdi
  imul   %r12d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6: %d


assistant: ```c
void lcm(int m, int n) {
  int a = m, b = n, gcd;
  assert(a > 0 && b > 0 && b > a);
  while (b != 0) {
    gcd = b;
    b = a % b;
    a = gcd;
  }
  printf("%d\n", m * n / gcd);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcm>:
  endbr64
  test   %edi,%edi
  push   %r12
  mov    %esi,%r12d
  setg   %al
  cmp    %esi,%edi
  push   %rbp
  mov    %edi,%ebp
  setl   %dl
  push   %rbx
  xor    %edi,%edi
  and    %edx,%eax
  test   %esi,%esi
  setg   %dil
  and    %eax,%edi
  call   <assert@plt>
  test   %r12d,%r12d
  je     L0
  mov    %r12d,%edx
  mov    %ebp,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %edx,%ebx
  cltd
  idiv   %ebx
  mov    %ebx,%eax
  test   %edx,%edx
  jne    L3
L0:
  mov    %ebp,%eax
  lea    D0(%rip),%rdi
  imul   %r12d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: %d


assistant: ```c
void lcm(int m, int n) {
  int a = m, b = n, gcd;
  assert(a > 0 && b > 0 && b > a);
  while (b != 0) {
    gcd = b;
    b = a % b;
    a = gcd;
  }
  printf("%d\n", m * n / gcd);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ReadIntFromString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%edi
  lea    -0x18(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <ReadInt64FromString@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
const char *ReadIntFromString(const char *szStr, const char *szValueTermination, const char *szAllowedPadding, int *pValue, int iTrimCount) {
  long long i64Val;
  const char *pRes = ReadInt64FromString(szStr, szValueTermination, szAllowedPadding, &i64Val, iTrimCount);
  (*pValue) = (int)i64Val;
  return pRes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ReadIntFromString>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <ReadInt64FromString@plt>
  mov    (%rsp),%rdx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *ReadIntFromString(const char *szStr, const char *szValueTermination, const char *szAllowedPadding, int *pValue, int iTrimCount) {
  long long i64Val;
  const char *pRes = ReadInt64FromString(szStr, szValueTermination, szAllowedPadding, &i64Val, iTrimCount);
  (*pValue) = (int)i64Val;
  return pRes;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ReadIntFromString>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <ReadInt64FromString@plt>
  mov    (%rsp),%rdx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *ReadIntFromString(const char *szStr, const char *szValueTermination, const char *szAllowedPadding, int *pValue, int iTrimCount) {
  long long i64Val;
  const char *pRes = ReadInt64FromString(szStr, szValueTermination, szAllowedPadding, &i64Val, iTrimCount);
  (*pValue) = (int)i64Val;
  return pRes;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ReadIntFromString>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <ReadInt64FromString@plt>
  mov    (%rsp),%rdx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *ReadIntFromString(const char *szStr, const char *szValueTermination, const char *szAllowedPadding, int *pValue, int iTrimCount) {
  long long i64Val;
  const char *pRes = ReadInt64FromString(szStr, szValueTermination, szAllowedPadding, &i64Val, iTrimCount);
  (*pValue) = (int)i64Val;
  return pRes;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strncpy_no_null_4_Bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7365742e74736574,%rax
  mov    %rax,-0x17(%rbp)
  movl   $0x65742e74,-0xf(%rbp)
  movw   $0x7473,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x17(%rbp),%rcx
  lea    -0x21(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x21(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movl   $0x0,-0x50(%rbp,%rax,4)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void strncpy_no_null_4_Bad() {
  char src[15] = "test.test.test";
  char dst[10];
  strncpy(dst, src, 10);
  int a[10];
  a[strlen(dst)] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strncpy_no_null_4_Bad>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x7365742e74736574,%rax
  mov    %rax,0x19(%rsp)
  movl   $0x65742e74,0x21(%rsp)
  movw   $0x7473,0x25(%rsp)
  movb   $0x0,0x27(%rsp)
  lea    0x19(%rsp),%rsi
  lea    0xf(%rsp),%rdi
  mov    $0xa,%edx
  call   <strncpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncpy_no_null_4_Bad() {
  char src[15] = "test.test.test";
  char dst[10];
  strncpy(dst, src, 10);
  int a[10];
  a[strlen(dst)] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strncpy_no_null_4_Bad>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x7365742e74736574,%rax
  lea    0x19(%rsp),%rsi
  lea    0xf(%rsp),%rdi
  movl   $0x65742e74,0x21(%rsp)
  movb   $0x0,0x27(%rsp)
  mov    %rax,0x19(%rsp)
  mov    $0x7473,%eax
  mov    %ax,0x25(%rsp)
  call   <strncpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncpy_no_null_4_Bad() {
  char src[15] = "test.test.test";
  char dst[10];
  strncpy(dst, src, 10);
  int a[10];
  a[strlen(dst)] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strncpy_no_null_4_Bad>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x7365742e74736574,%rax
  lea    0x19(%rsp),%rsi
  lea    0xf(%rsp),%rdi
  movl   $0x65742e74,0x21(%rsp)
  movb   $0x0,0x27(%rsp)
  mov    %rax,0x19(%rsp)
  mov    $0x7473,%eax
  mov    %ax,0x25(%rsp)
  call   <strncpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncpy_no_null_4_Bad() {
  char src[15] = "test.test.test";
  char dst[10];
  strncpy(dst, src, 10);
  int a[10];
  a[strlen(dst)] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main() {
  int n = 0, answr;
  scanf("%d", &n);
  answr = is_prime(n);
  printf("%d", answr);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d

assistant: ```c
int main() {
  int n = 0, answr;
  scanf("%d", &n);
  answr = is_prime(n);
  printf("%d", answr);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  int n = 0, answr;
  scanf("%d", &n);
  answr = is_prime(n);
  printf("%d", answr);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: %d

assistant: ```c
int main() {
  int n = 0, answr;
  scanf("%d", &n);
  answr = is_prime(n);
  printf("%d", answr);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<proc_status>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %edi,-0x224(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x224(%rbp),%eax
  mov    %eax,%edi
  call   <is_kernel_thread@plt>
  mov    %eax,-0x21c(%rbp)
  cmpl   $0x0,-0x21c(%rbp)
  jns    L68
  mov    -0x21c(%rbp),%eax
  jmp    L35
L68:
  cmpl   $0x0,-0x21c(%rbp)
  jle    L28
  mov    $0x0,%eax
  jmp    L35
L28:
  lea    -0x210(%rbp),%rdx
  mov    -0x224(%rbp),%eax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <get_file@plt>
  test   %rax,%rax
  jg     L47
  mov    $0xffffffff,%eax
  jmp    L35
L47:
  lea    -0x210(%rbp),%rax
  mov    $0x29,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  add    $0x2,%rax
  mov    %rax,-0x218(%rbp)
  lea    -0x21d(%rbp),%rdx
  mov    -0x218(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  movzbl -0x21d(%rbp),%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D4
type_infered: string

tool: D7: stat

tool: D4: %c

assistant: ```c
char proc_status(int pid) {
  char buf[512];
  char *s;
  char status;
  int kthread;
  kthread = is_kernel_thread(pid);
  if (kthread < 0)
    return kthread;
  if (kthread > 0)
    return 0;
  if (get_file(pid, "stat", buf) <= 0)
    return -1;
  s = strrchr(buf, ')') + 2;
  sscanf(s, "%c", &status);
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<proc_status>:
  endbr64
  push   %rbx
  sub    $0x220,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  call   <is_kernel_thread@plt>
  test   %eax,%eax
  mov    %eax,%edx
  js     L13
  mov    $0x0,%edx
  jle    L4
L13:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    %edx,%eax
  add    $0x220,%rsp
  pop    %rbx
  ret
L4:
  lea    0x10(%rsp),%rdx
  lea    D17(%rip),%rsi
  mov    %ebx,%edi
  call   <get_file@plt>
  test   %rax,%rax
  jle    L7
  lea    0x10(%rsp),%rdi
  mov    $0x29,%esi
  call   <strrchr@plt>
  lea    0xf(%rsp),%rdx
  lea    0x2(%rax),%rdi
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  movzbl 0xf(%rsp),%edx
  jmp    L13
L7:
  mov    $0xffffffff,%edx
  jmp    L13
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D17
data_type: string
name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D17: stat

tool: D3: %c

assistant: ```c
char proc_status(int pid) {
  char buf[512];
  char *s;
  char status;
  int kthread;
  kthread = is_kernel_thread(pid);
  if (kthread < 0)
    return kthread;
  if (kthread > 0)
    return 0;
  if (get_file(pid, "stat", buf) <= 0)
    return -1;
  s = strrchr(buf, ')') + 2;
  sscanf(s, "%c", &status);
  return status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<proc_status>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  call   <is_kernel_thread@plt>
  test   %eax,%eax
  js     L7
  mov    $0x0,%eax
  je     L13
L7:
  mov    0x218(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x228,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  lea    0x10(%rsp),%r12
  lea    D3(%rip),%rsi
  mov    %ebp,%edi
  mov    %r12,%rdx
  call   <get_file@plt>
  test   %rax,%rax
  jle    L58
  mov    $0x29,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  lea    0xf(%rsp),%rdx
  lea    D0(%rip),%rsi
  lea    0x2(%rax),%rdi
  call   <sscanf@plt>
  movzbl 0xf(%rsp),%eax
  jmp    L7
L58:
  mov    $0xffffffff,%eax
  jmp    L7
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string
name: read_data
arguments: label: D0
type_infered: string

tool: D3: stat

tool: D0: %c

assistant: ```c
char proc_status(int pid) {
  char buf[512];
  char *s;
  char status;
  int kthread;
  kthread = is_kernel_thread(pid);
  if (kthread < 0)
    return kthread;
  if (kthread > 0)
    return 0;
  if (get_file(pid, "stat", buf) <= 0)
    return -1;
  s = strrchr(buf, ')') + 2;
  sscanf(s, "%c", &status);
  return status;
}
```