ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copyUC_DependencyNode>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  lea    D23(%rip),%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  mov    $0x0,%edi
  call   <show_stack@plt>
  mov    $0x0,%eax
  call   <breakpoint@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
data_type: string
name: extract_symbolic_data
arguments: tag: D23
data_type: string
name: extract_symbolic_data
arguments: tag: D11
data_type: string

tool: D22: Dependency management doesn't work yet


tool: D23: BUG

tool: D11: kgdb assertion failed: %s


assistant: ```c
struct UC_DependencyNode *copyUC_DependencyNode(struct UC_DependencyNode *sdep) {
  printk("Dependency management doesn't work yet\n");
  do {
    if (!(0)) {
      printk("kgdb assertion failed: %s\n", "BUG");
      show_stack(((void *)0));
      breakpoint();
    }
  } while (0);
  return ((void *)0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copyUC_DependencyNode>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printk@plt>
  lea    D9(%rip),%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printk@plt>
  xor    %edi,%edi
  call   <show_stack@plt>
  xor    %eax,%eax
  call   <breakpoint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D10
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string

tool: D10: Dependency management doesn't work yet


tool: D9: BUG

tool: D12: kgdb assertion failed: %s


assistant: ```c
struct UC_DependencyNode *copyUC_DependencyNode(struct UC_DependencyNode *sdep) {
  printk("Dependency management doesn't work yet\n");
  do {
    if (!(0)) {
      printk("kgdb assertion failed: %s\n", "BUG");
      show_stack(((void *)0));
      breakpoint();
    }
  } while (0);
  return ((void *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<copyUC_DependencyNode>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printk@plt>
  lea    D1(%rip),%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printk@plt>
  xor    %edi,%edi
  call   <show_stack@plt>
  xor    %eax,%eax
  call   <breakpoint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string
name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D17
type_infered: string

tool: D9: Dependency management doesn't work yet


tool: D1: BUG

tool: D17: kgdb assertion failed: %s


assistant: ```c
struct UC_DependencyNode *copyUC_DependencyNode(struct UC_DependencyNode *sdep) {
  printk("Dependency management doesn't work yet\n");
  do {
    if (!(0)) {
      printk("kgdb assertion failed: %s\n", "BUG");
      show_stack(((void *)0));
      breakpoint();
    }
  } while (0);
  return ((void *)0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *calloc(size_t count, size_t size) {
  void *block = malloc(count * size);
  if (block != NULL) {
    memset(block, 0, count * size);
  }
  return block;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *calloc(size_t count, size_t size) {
  void *block = malloc(count * size);
  if (block != NULL) {
    memset(block, 0, count * size);
  }
  return block;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t count, size_t size) {
  void *block = malloc(count * size);
  if (block != NULL) {
    memset(block, 0, count * size);
  }
  return block;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t count, size_t size) {
  void *block = malloc(count * size);
  if (block != NULL) {
    memset(block, 0, count * size);
  }
  return block;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fastUnsignedPower10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int fastUnsignedPower10(int power) {
  static unsigned int powers[10] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000};
  return powers[power];
}
```
user: What is the c source code of the assembly code below?

```asm
<fastUnsignedPower10>:
  endbr64
  movslq %edi,%rdi
  lea    D9(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: 

assistant: ```c
unsigned int fastUnsignedPower10(int power) {
  static unsigned int powers[10] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000};
  return powers[power];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fastUnsignedPower10>:
  endbr64
  movslq %edi,%rdi
  lea    D3(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D3: 

assistant: ```c
unsigned int fastUnsignedPower10(int power) {
  static unsigned int powers[10] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000};
  return powers[power];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fastUnsignedPower10>:
  endbr64
  movslq %edi,%rdi
  lea    D4(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string

tool: D4: 

assistant: ```c
unsigned int fastUnsignedPower10(int power) {
  static unsigned int powers[10] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000};
  return powers[power];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<minPathSum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L72
  mov    %rdi,%r14
  mov    %edx,%r13d
  test   %edx,%edx
  je     L72
  cmp    $0x1,%edx
  jle    L41
  mov    %edx,%esi
  shl    $0x2,%rsi
  mov    $0x4,%eax
L81:
  mov    (%r14),%rdx
  mov    -0x4(%rdx,%rax,1),%ecx
  add    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L81
L41:
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  jle    L22
  lea    -0x2(%rax),%edi
  shl    $0x3,%rdi
  lea    0x8(%r14,%rdi,1),%rsi
  mov    %r14,%rax
L87:
  mov    0x8(%rax),%rdx
  mov    (%rax),%rcx
  mov    (%rcx),%ecx
  add    %ecx,(%rdx)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L87
  lea    0x8(%r14),%rbp
  lea    0x10(%r14,%rdi,1),%r15
  lea    -0x2(%r13),%eax
  lea    0x8(,%rax,4),%r12
  jmp    L53
L115:
  mov    -0x8(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  mov    0x0(%rbp),%rax
  mov    -0x4(%rax,%rbx,1),%edi
  call   <min@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  add    0x0(%rbp),%rax
  add    %edx,(%rax)
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L115
L33:
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L22
L53:
  mov    $0x4,%ebx
  cmp    $0x1,%r13d
  jg     L115
  jmp    L33
L22:
  movslq 0xc(%rsp),%rax
  movslq %r13d,%r13
  mov    -0x8(%r14,%rax,8),%rax
  mov    -0x4(%rax,%r13,4),%eax
L44:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  mov    $0x0,%eax
  jmp    L44
```

assistant: ```c
int minPathSum(int **grid, int gridRowSize, int gridColSize) {
  int i, j;
  if (gridRowSize == 0 || gridColSize == 0)
    return 0;
  for (j = 1; j < gridColSize; j++)
    grid[0][j] += grid[0][j - 1];
  for (i = 1; i < gridRowSize; i++)
    grid[i][0] += grid[i - 1][0];
  for (i = 1; i < gridRowSize; i++) {
    for (j = 1; j < gridColSize; j++) {
      grid[i][j] += min(grid[i][j - 1], grid[i - 1][j]);
    }
  }
  return grid[gridRowSize - 1][gridColSize - 1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<minPathSum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L55
  movslq %edx,%r12
  test   %r12d,%r12d
  je     L55
  mov    %rdi,%r15
  cmp    $0x1,%r12d
  jle    L11
  mov    (%rdi),%rdx
  lea    -0x2(%r12),%ecx
  lea    0x4(%rdx),%rax
  lea    0x8(%rdx,%rcx,4),%rcx
  nopl   0x0(%rax)
L77:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L77
L11:
  cmpl   $0x1,0xc(%rsp)
  jle    L32
  mov    0xc(%rsp),%eax
  lea    0x8(%r15),%rdx
  lea    -0x2(%rax),%r8d
  mov    %r15,%rax
  shl    $0x3,%r8
  lea    (%rdx,%r8,1),%rdi
  nopl   0x0(%rax,%rax,1)
L76:
  mov    (%rax),%rsi
  mov    0x8(%rax),%rcx
  add    $0x8,%rax
  mov    (%rsi),%esi
  add    %esi,(%rcx)
  cmp    %rax,%rdi
  jne    L76
  lea    -0x2(%r12),%eax
  mov    %rdx,%r13
  lea    0x10(%r15,%r8,1),%r14
  lea    0x8(,%rax,4),%rbp
  nopl   0x0(%rax)
L65:
  cmp    $0x1,%r12d
  jle    L29
  mov    0x0(%r13),%rax
  mov    $0x4,%ebx
  nop
L47:
  mov    -0x8(%r13),%rcx
  mov    -0x4(%rax,%rbx,1),%edi
  mov    (%rcx,%rbx,1),%esi
  call   <min@plt>
  mov    %rax,%r8
  mov    0x0(%r13),%rax
  add    %r8d,(%rax,%rbx,1)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L47
L29:
  add    $0x8,%r13
  cmp    %r13,%r14
  jne    L65
L32:
  movslq 0xc(%rsp),%r13
  mov    -0x8(%r15,%r13,8),%rax
  mov    -0x4(%rax,%r12,4),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int minPathSum(int **grid, int gridRowSize, int gridColSize) {
  int i, j;
  if (gridRowSize == 0 || gridColSize == 0)
    return 0;
  for (j = 1; j < gridColSize; j++)
    grid[0][j] += grid[0][j - 1];
  for (i = 1; i < gridRowSize; i++)
    grid[i][0] += grid[i - 1][0];
  for (i = 1; i < gridRowSize; i++) {
    for (j = 1; j < gridColSize; j++) {
      grid[i][j] += min(grid[i][j - 1], grid[i - 1][j]);
    }
  }
  return grid[gridRowSize - 1][gridColSize - 1];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<minPathSum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L44
  movslq %edx,%r12
  test   %r12d,%r12d
  je     L44
  mov    %rdi,%r14
  cmp    $0x1,%r12d
  jle    L2
  mov    (%rdi),%rcx
  lea    -0x2(%r12),%esi
  mov    (%rcx),%edx
  lea    0x4(%rcx),%rax
  lea    0x8(%rcx,%rsi,4),%rcx
  cs nopw 0x0(%rax,%rax,1)
L87:
  add    (%rax),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L87
L2:
  cmpl   $0x1,0xc(%rsp)
  jle    L8
  mov    0xc(%rsp),%eax
  lea    0x8(%r14),%rdx
  lea    -0x2(%rax),%r8d
  mov    %r14,%rax
  shl    $0x3,%r8
  lea    (%rdx,%r8,1),%rdi
L7:
  mov    (%rax),%rsi
  mov    0x8(%rax),%rcx
  add    $0x8,%rax
  mov    (%rsi),%esi
  add    %esi,(%rcx)
  cmp    %rax,%rdi
  jne    L7
  cmp    $0x1,%r12d
  jle    L8
  mov    %rdx,%r13
  lea    0x10(%r14,%r8,1),%r15
  lea    0x0(,%r12,4),%rbp
  nopw   0x0(%rax,%rax,1)
L69:
  mov    0x0(%r13),%rax
  mov    $0x4,%ebx
  nopl   0x0(%rax)
L59:
  mov    -0x8(%r13),%rcx
  mov    -0x4(%rax,%rbx,1),%edi
  mov    (%rcx,%rbx,1),%esi
  call   <min@plt>
  mov    %rax,%r8
  mov    0x0(%r13),%rax
  add    %r8d,(%rax,%rbx,1)
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L59
  add    $0x8,%r13
  cmp    %r13,%r15
  jne    L69
L8:
  movslq 0xc(%rsp),%r13
  mov    -0x8(%r14,%r13,8),%rax
  mov    -0x4(%rax,%r12,4),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int minPathSum(int **grid, int gridRowSize, int gridColSize) {
  int i, j;
  if (gridRowSize == 0 || gridColSize == 0)
    return 0;
  for (j = 1; j < gridColSize; j++)
    grid[0][j] += grid[0][j - 1];
  for (i = 1; i < gridRowSize; i++)
    grid[i][0] += grid[i - 1][0];
  for (i = 1; i < gridRowSize; i++) {
    for (j = 1; j < gridColSize; j++) {
      grid[i][j] += min(grid[i][j - 1], grid[i - 1][j]);
    }
  }
  return grid[gridRowSize - 1][gridColSize - 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mpi_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x80,-0x4(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x20(%rbp)
  addq   $0x4,-0x18(%rbp)
  sarl   $0x10,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t mpi_add(uint16_t *dest, const uint16_t *src) {
  uint32_t c = 0;
  uint8_t count = 128;
  do {
    c += *dest + *src;
    *dest = c & 0xFFFF;
    src++;
    dest++;
    c >>= 16;
  } while (--count);
  return (uint8_t)(c & 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mpi_add>:
  endbr64
  mov    $0x0,%edx
  mov    $0x0,%eax
L8:
  mov    (%rsi,%rdx,1),%ecx
  add    (%rdi,%rdx,1),%ecx
  add    %ecx,%eax
  movzwl %ax,%ecx
  mov    %ecx,(%rdi,%rdx,1)
  sar    $0x10,%eax
  add    $0x4,%rdx
  cmp    $0x200,%rdx
  jne    L8
  and    $0x1,%eax
  ret
```

assistant: ```c
uint8_t mpi_add(uint16_t *dest, const uint16_t *src) {
  uint32_t c = 0;
  uint8_t count = 128;
  do {
    c += *dest + *src;
    *dest = c & 0xFFFF;
    src++;
    dest++;
    c >>= 16;
  } while (--count);
  return (uint8_t)(c & 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<mpi_add>:
  endbr64
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rdx,1),%ecx
  add    (%rdi,%rdx,1),%ecx
  add    %ecx,%eax
  movzwl %ax,%ecx
  sar    $0x10,%eax
  mov    %ecx,(%rdi,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x200,%rdx
  jne    L6
  and    $0x1,%eax
  ret
```

assistant: ```c
uint8_t mpi_add(uint16_t *dest, const uint16_t *src) {
  uint32_t c = 0;
  uint8_t count = 128;
  do {
    c += *dest + *src;
    *dest = c & 0xFFFF;
    src++;
    dest++;
    c >>= 16;
  } while (--count);
  return (uint8_t)(c & 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mpi_add>:
  endbr64
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rdx,1),%ecx
  add    (%rdi,%rdx,1),%ecx
  add    %ecx,%eax
  movzwl %ax,%ecx
  sar    $0x10,%eax
  mov    %ecx,(%rdi,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x200,%rdx
  jne    L6
  and    $0x1,%eax
  ret
```

assistant: ```c
uint8_t mpi_add(uint16_t *dest, const uint16_t *src) {
  uint32_t c = 0;
  uint8_t count = 128;
  do {
    c += *dest + *src;
    *dest = c & 0xFFFF;
    src++;
    dest++;
    c >>= 16;
  } while (--count);
  return (uint8_t)(c & 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<interpolatev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  D13(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  movsd  D13(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  movsd  D13(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type: f64

tool: D13: 1

assistant: ```c
void interpolatev(double *result, const double *s1, const double *s2, const double alpha) {
  result[0] = (float)(s1[0] * (1.0 - (double)alpha) + s2[0] * (double)alpha);
  result[1] = (float)(s1[1] * (1.0 - (double)alpha) + s2[1] * (double)alpha);
  result[2] = (float)(s1[2] * (1.0 - (double)alpha) + s2[2] * (double)alpha);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<interpolatev>:
  endbr64
  movsd  D1(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm2
  mulsd  (%rsi),%xmm2
  movapd %xmm0,%xmm3
  mulsd  (%rdx),%xmm3
  addsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  movsd  %xmm2,(%rdi)
  movapd %xmm1,%xmm2
  mulsd  0x8(%rsi),%xmm2
  movapd %xmm0,%xmm3
  mulsd  0x8(%rdx),%xmm3
  addsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  movsd  %xmm2,0x8(%rdi)
  mulsd  0x10(%rsi),%xmm1
  mulsd  0x10(%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  movsd  %xmm1,0x10(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: f64

tool: D1: 1

assistant: ```c
void interpolatev(double *result, const double *s1, const double *s2, const double alpha) {
  result[0] = (float)(s1[0] * (1.0 - (double)alpha) + s2[0] * (double)alpha);
  result[1] = (float)(s1[1] * (1.0 - (double)alpha) + s2[1] * (double)alpha);
  result[2] = (float)(s1[2] * (1.0 - (double)alpha) + s2[2] * (double)alpha);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<interpolatev>:
  endbr64
  movsd  D5(%rip),%xmm1
  movsd  (%rsi),%xmm2
  movsd  (%rdx),%xmm3
  subsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm3
  mulsd  %xmm1,%xmm2
  addsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  movsd  %xmm2,(%rdi)
  movsd  0x8(%rsi),%xmm2
  movsd  0x8(%rdx),%xmm3
  mulsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  movsd  %xmm2,0x8(%rdi)
  mulsd  0x10(%rsi),%xmm1
  mulsd  0x10(%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  movsd  %xmm1,0x10(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: f64

tool: D5: 1

assistant: ```c
void interpolatev(double *result, const double *s1, const double *s2, const double alpha) {
  result[0] = (float)(s1[0] * (1.0 - (double)alpha) + s2[0] * (double)alpha);
  result[1] = (float)(s1[1] * (1.0 - (double)alpha) + s2[1] * (double)alpha);
  result[2] = (float)(s1[2] * (1.0 - (double)alpha) + s2[2] * (double)alpha);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<interpolatev>:
  endbr64
  movsd  D2(%rip),%xmm1
  movsd  (%rsi),%xmm2
  movsd  (%rdx),%xmm3
  subsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm3
  mulsd  %xmm1,%xmm2
  addsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  movsd  %xmm2,(%rdi)
  movsd  0x8(%rsi),%xmm2
  movsd  0x8(%rdx),%xmm3
  mulsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  movsd  %xmm2,0x8(%rdi)
  mulsd  0x10(%rsi),%xmm1
  mulsd  0x10(%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  movsd  %xmm1,0x10(%rdi)
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: f64

tool: D2: 1

assistant: ```c
void interpolatev(double *result, const double *s1, const double *s2, const double alpha) {
  result[0] = (float)(s1[0] * (1.0 - (double)alpha) + s2[0] * (double)alpha);
  result[1] = (float)(s1[1] * (1.0 - (double)alpha) + s2[1] * (double)alpha);
  result[2] = (float)(s1[2] * (1.0 - (double)alpha) + s2[2] * (double)alpha);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printSubset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x7b,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L8:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L13
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0x7d,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: %d, 

assistant: ```c
void printSubset(int *binrep, int limit) {
  int i;
  printf("{");
  for (i = 0; i < limit; i++) {
    if (*(binrep + sizeof(int) * i) == 1) {
      printf("%d, ", i + 1);
    }
  }
  printf("}");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printSubset>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x7b,%edi
  call   <putchar@plt>
  test   %ebx,%ebx
  jle    L15
  lea    0x1(%rbx),%r12d
  mov    $0x1,%ebx
  lea    D2(%rip),%r13
  jmp    L3
L43:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L15
L3:
  mov    %rbx,%rax
  shl    $0x4,%rax
  cmpl   $0x1,-0x10(%rbp,%rax,1)
  jne    L43
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L43
L15:
  mov    $0x7d,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: %d, 

assistant: ```c
void printSubset(int *binrep, int limit) {
  int i;
  printf("{");
  for (i = 0; i < limit; i++) {
    if (*(binrep + sizeof(int) * i) == 1) {
      printf("%d, ", i + 1);
    }
  }
  printf("}");
}
```