ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<smartstrncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L15
L19:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L19
  jmp    L9
L2:
  nop
L9:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *smartstrncpy(char *dest, char *src, size_t max_chars) {
  size_t copied;
  for (copied = 0; copied < max_chars; copied++, dest++, src++) {
    *dest = *src;
    if (*dest == 0)
      break;
  }
  *dest = 0;
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<smartstrncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L24
  add    %rdi,%rdx
L14:
  movzbl (%rsi),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  je     L24
  add    $0x1,%rax
  add    $0x1,%rsi
  cmp    %rax,%rdx
  jne    L14
  mov    %rdx,%rax
L24:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *smartstrncpy(char *dest, char *src, size_t max_chars) {
  size_t copied;
  for (copied = 0; copied < max_chars; copied++, dest++, src++) {
    *dest = *src;
    if (*dest == 0)
      break;
  }
  *dest = 0;
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<smartstrncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L4
  add    %rdi,%rdx
  jmp    L38
  nopl   0x0(%rax)
L24:
  add    $0x1,%rax
  add    $0x1,%rsi
  cmp    %rax,%rdx
  je     L4
L38:
  movzbl (%rsi),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L24
L4:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *smartstrncpy(char *dest, char *src, size_t max_chars) {
  size_t copied;
  for (copied = 0; copied < max_chars; copied++, dest++, src++) {
    *dest = *src;
    if (*dest == 0)
      break;
  }
  *dest = 0;
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<smartstrncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L36
  add    %rdi,%rdx
  jmp    L23
  nopl   0x0(%rax)
L12:
  add    $0x1,%rax
  add    $0x1,%rsi
  cmp    %rax,%rdx
  je     L36
L23:
  movzbl (%rsi),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L12
L36:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *smartstrncpy(char *dest, char *src, size_t max_chars) {
  size_t copied;
  for (copied = 0; copied < max_chars; copied++, dest++, src++) {
    *dest = *src;
    if (*dest == 0)
      break;
  }
  *dest = 0;
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<list1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <newvec@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *list1(x) {
  int *p = newvec(0);
  p[0] = x;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<list1>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <newvec@plt>
  cltq
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *list1(x) {
  int *p = newvec(0);
  p[0] = x;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<list1>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  xor    %edi,%edi
  call   <newvec@plt>
  cltq
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *list1(x) {
  int *p = newvec(0);
  p[0] = x;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<list1>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  xor    %edi,%edi
  call   <newvec@plt>
  cltq
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *list1(x) {
  int *p = newvec(0);
  p[0] = x;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<EMIT1LAB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <EMIT1ATM@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: l%d

assistant: ```c
void EMIT1LAB(d) int d;
{
  char name[32];
  sprintf(name, "l%d", d);
  EMIT1ATM(name);
}
```
user: What is the c source code of the assembly code below?

```asm
<EMIT1LAB>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <EMIT1ATM@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: l%d

assistant: ```c
void EMIT1LAB(d) int d;
{
  char name[32];
  sprintf(name, "l%d", d);
  EMIT1ATM(name);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EMIT1LAB>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  lea    D2(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <EMIT1ATM@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string

tool: D2: l%d

assistant: ```c
void EMIT1LAB(d) int d;
{
  char name[32];
  sprintf(name, "l%d", d);
  EMIT1ATM(name);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EMIT1LAB>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  lea    D5(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <EMIT1ATM@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: l%d

assistant: ```c
void EMIT1LAB(d) int d;
{
  char name[32];
  sprintf(name, "l%d", d);
  EMIT1ATM(name);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<th>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  movl   $0x64,-0x8(%rbp)
  jmp    L15
L13:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x8(%rbp)
L15:
  cmpl   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: %d

assistant: ```c
void *th(void *param) {
  int n = (int)param;
  int cont = 100;
  while (cont) {
    printf("%d", n);
    --cont;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<th>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x64,%ebx
  lea    D1(%rip),%r12
L6:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: %d

assistant: ```c
void *th(void *param) {
  int n = (int)param;
  int cont = 100;
  while (cont) {
    printf("%d", n);
    --cont;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<th>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x64,%ebx
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D8
type: string

tool: D8: %d

assistant: ```c
void *th(void *param) {
  int n = (int)param;
  int cont = 100;
  while (cont) {
    printf("%d", n);
    --cont;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<th>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x64,%ebx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d

assistant: ```c
void *th(void *param) {
  int n = (int)param;
  int cont = 100;
  while (cont) {
    printf("%d", n);
    --cont;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1000000,-0x4(%rbp)
  nop
L3:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  test   %eax,%eax
  jne    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay(void) {
  volatile int i = 0x1000000;
  while (--i)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delay>:
  endbr64
  movl   $0x1000000,-0x4(%rsp)
L3:
  mov    -0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  jne    L3
  ret
```

assistant: ```c
void delay(void) {
  volatile int i = 0x1000000;
  while (--i)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<delay>:
  endbr64
  movl   $0x1000000,-0x4(%rsp)
  nopl   0x0(%rax)
L7:
  subl   $0x1,-0x4(%rsp)
  jne    L7
  ret
```

assistant: ```c
void delay(void) {
  volatile int i = 0x1000000;
  while (--i)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<delay>:
  endbr64
  movl   $0x1000000,-0x4(%rsp)
  nopl   0x0(%rax)
L6:
  subl   $0x1,-0x4(%rsp)
  jne    L6
  ret
```

assistant: ```c
void delay(void) {
  volatile int i = 0x1000000;
  while (--i)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x33c(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x338(%rbp)
  jmp    L87
L44:
  lea    -0x330(%rbp),%rdx
  mov    -0x338(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x338(%rbp)
L87:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L44
  movl   $0x0,-0x338(%rbp)
  jmp    L61
L83:
  movl   $0x0,-0x334(%rbp)
  jmp    L125
L56:
  mov    -0x334(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L47
  mov    -0x338(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L47
  mov    -0x338(%rbp),%eax
  cmp    -0x334(%rbp),%eax
  je     L47
  mov    -0x338(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%edx
  mov    -0x334(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L47
  mov    -0x338(%rbp),%eax
  cltq
  movl   $0x0,-0x330(%rbp,%rax,4)
  mov    -0x334(%rbp),%eax
  cltq
  movl   $0x0,-0x330(%rbp,%rax,4)
  jmp    L34
L47:
  addl   $0x1,-0x334(%rbp)
L125:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x334(%rbp)
  jl     L56
L34:
  addl   $0x1,-0x338(%rbp)
L61:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L83
  movl   $0x0,-0x338(%rbp)
  jmp    L14
L57:
  mov    -0x338(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L6
  mov    -0x338(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L6:
  addl   $0x1,-0x338(%rbp)
L14:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L57
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L78
  call   <__stack_chk_fail@plt>
L78:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
type_infered: string

tool: D25: %d

assistant: ```c
int main() {
  int many, index, index2;
  int deers[200];
  scanf("%d", &many);
  for (index = 0; index < many; index++) {
    scanf("%d", &deers[index]);
  }
  for (index = 0; index < many; index++) {
    for (index2 = 0; index2 < many; index2++) {
      if (deers[index2] != 0 && deers[index] != 0) {
        if (index != index2) {
          if (deers[index] == deers[index2]) {
            deers[index] = 0;
            deers[index2] = 0;
            break;
          }
        }
      }
    }
  }
  for (index = 0; index < many; index++) {
    if (deers[index] != 0)
      printf("%d", deers[index]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L115
  lea    0x10(%rsp),%rbx
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D16(%rip),%r13
L1:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0xc(%rsp),%r10d
  add    $0x4,%r12
  cmp    %ebp,%r10d
  jg     L1
  test   %r10d,%r10d
  jle    L115
  mov    $0x0,%r9d
  mov    %r10d,%r8d
  jmp    L22
L53:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L47
L148:
  mov    0x10(%rsp,%rax,4),%edx
  test   %edx,%edx
  je     L53
  mov    (%rbx),%ecx
  cmp    %eax,%r9d
  setne  %dil
  cmp    %ecx,%edx
  sete   %dl
  test   %dl,%dil
  je     L53
  test   %ecx,%ecx
  je     L53
  movl   $0x0,(%r11)
  movslq %eax,%rsi
  movl   $0x0,0x10(%rsp,%rsi,4)
L47:
  add    $0x1,%r9d
  add    $0x4,%rbx
  cmp    %r9d,%r10d
  je     L122
L22:
  mov    $0x0,%eax
  mov    %rbx,%r11
  jmp    L148
L122:
  mov    $0x0,%ebx
  lea    D16(%rip),%rbp
  jmp    L75
L62:
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jle    L115
L75:
  mov    0x10(%rsp,%rbx,4),%esi
  test   %esi,%esi
  je     L62
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L62
L115:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L127
  mov    $0x0,%eax
  add    $0x348,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L127:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string

tool: D16: %d

assistant: ```c
int main() {
  int many, index, index2;
  int deers[200];
  scanf("%d", &many);
  for (index = 0; index < many; index++) {
    scanf("%d", &deers[index]);
  }
  for (index = 0; index < many; index++) {
    for (index2 = 0; index2 < many; index2++) {
      if (deers[index2] != 0 && deers[index] != 0) {
        if (index != index2) {
          if (deers[index] == deers[index2]) {
            deers[index] = 0;
            deers[index2] = 0;
            break;
          }
        }
      }
    }
  }
  for (index = 0; index < many; index++) {
    if (deers[index] != 0)
      printf("%d", deers[index]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L58
  lea    0x10(%rsp),%rbx
  xor    %r13d,%r13d
  mov    %rbx,%r12
  mov    %rbx,%r14
  nopl   0x0(%rax)
L145:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    0xc(%rsp),%r10d
  cmp    %r13d,%r10d
  jg     L145
  test   %r10d,%r10d
  jle    L58
  xor    %r9d,%r9d
  movslq %r10d,%r8
L2:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L128:
  mov    (%rbx,%rax,4),%edx
  movslq %eax,%rsi
  test   %edx,%edx
  je     L144
  mov    (%r12),%ecx
  cmp    %eax,%r9d
  setne  %dil
  cmp    %ecx,%edx
  sete   %dl
  test   %dl,%dil
  je     L144
  test   %ecx,%ecx
  jne    L74
L144:
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L128
  add    $0x1,%r9d
  add    $0x4,%r12
  cmp    %r9d,%r10d
  jne    L2
L116:
  xor    %r12d,%r12d
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L70:
  add    $0x1,%r12
  cmp    %r12d,0xc(%rsp)
  jle    L58
L48:
  mov    (%rbx,%r12,4),%esi
  test   %esi,%esi
  je     L70
  mov    %rbp,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,0xc(%rsp)
  jg     L48
L58:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  add    $0x1,%r9d
  movl   $0x0,(%r12)
  add    $0x4,%r12
  movl   $0x0,0x10(%rsp,%rsi,4)
  cmp    %r9d,%r10d
  jne    L2
  jmp    L116
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: %d

assistant: ```c
int main() {
  int many, index, index2;
  int deers[200];
  scanf("%d", &many);
  for (index = 0; index < many; index++) {
    scanf("%d", &deers[index]);
  }
  for (index = 0; index < many; index++) {
    for (index2 = 0; index2 < many; index2++) {
      if (deers[index2] != 0 && deers[index] != 0) {
        if (index != index2) {
          if (deers[index] == deers[index2]) {
            deers[index] = 0;
            deers[index2] = 0;
            break;
          }
        }
      }
    }
  }
  for (index = 0; index < many; index++) {
    if (deers[index] != 0)
      printf("%d", deers[index]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L93
  lea    0x10(%rsp),%rbx
  xor    %r13d,%r13d
  mov    %rbx,%r12
  mov    %rbx,%r14
  nopl   0x0(%rax)
L111:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    0xc(%rsp),%r10d
  cmp    %r13d,%r10d
  jg     L111
  test   %r10d,%r10d
  jle    L93
  xor    %r9d,%r9d
  movslq %r10d,%r8
L92:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L106:
  mov    (%rbx,%rax,4),%edx
  movslq %eax,%rsi
  test   %edx,%edx
  je     L64
  mov    (%r12),%ecx
  cmp    %eax,%r9d
  setne  %dil
  cmp    %ecx,%edx
  sete   %dl
  test   %dl,%dil
  je     L64
  test   %ecx,%ecx
  jne    L26
L64:
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L106
  add    $0x1,%r9d
  add    $0x4,%r12
  cmp    %r9d,%r10d
  jne    L92
L42:
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L67:
  mov    (%rbx,%r12,4),%esi
  test   %esi,%esi
  jne    L44
  add    $0x1,%r12
  cmp    %r12d,%r9d
  jg     L67
L93:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L139
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L44:
  mov    %rbp,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  mov    0xc(%rsp),%r9d
  cmp    %r12d,%r9d
  jg     L67
  jmp    L93
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x1,%r9d
  movl   $0x0,(%r12)
  add    $0x4,%r12
  movl   $0x0,0x10(%rsp,%rsi,4)
  cmp    %r9d,%r10d
  jne    L92
  jmp    L42
L139:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: %d

assistant: ```c
int main() {
  int many, index, index2;
  int deers[200];
  scanf("%d", &many);
  for (index = 0; index < many; index++) {
    scanf("%d", &deers[index]);
  }
  for (index = 0; index < many; index++) {
    for (index2 = 0; index2 < many; index2++) {
      if (deers[index2] != 0 && deers[index] != 0) {
        if (index != index2) {
          if (deers[index] == deers[index2]) {
            deers[index] = 0;
            deers[index2] = 0;
            break;
          }
        }
      }
    }
  }
  for (index = 0; index < many; index++) {
    if (deers[index] != 0)
      printf("%d", deers[index]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L18:
  cmpl   $0x20,-0x8(%rbp)
  je     L10
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L10:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L18
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int c;
  int prev;
  prev = EOF;
  while ((c = getchar()) != EOF) {
    if (prev != ' ') {
      putchar(c);
    }
    prev = c;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D15(%rip),%rax
  mov    (%rax),%ebp
  jmp    L2
L13:
  mov    %ebx,%ebp
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D15(%rip),%rax
  cmp    %ebx,(%rax)
  je     L30
  cmp    $0x20,%ebp
  je     L13
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L13
L30:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int c;
  int prev;
  prev = EOF;
  while ((c = getchar()) != EOF) {
    if (prev != ' ') {
      putchar(c);
    }
    prev = c;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    D4(%rip),%r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  mov    (%r12),%ebp
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  je     L5
  nopw   0x0(%rax,%rax,1)
L16:
  cmp    $0x20,%ebp
  je     L11
  mov    %ebx,%edi
  call   <putchar@plt>
L11:
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L16
L5:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
main() {
  int c;
  int prev;
  prev = EOF;
  while ((c = getchar()) != EOF) {
    if (prev != ' ') {
      putchar(c);
    }
    prev = c;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    D3(%rip),%r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  mov    (%r12),%ebp
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  je     L14
  nopw   0x0(%rax,%rax,1)
L20:
  cmp    $0x20,%ebp
  je     L29
  mov    %ebx,%edi
  call   <putchar@plt>
L29:
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L20
L14:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
main() {
  int c;
  int prev;
  prev = EOF;
  while ((c = getchar()) != EOF) {
    if (prev != ' ') {
      putchar(c);
    }
    prev = c;
  }
}
```