user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D32(%rip),%rsi
  lea    D58(%rip),%rdi
  push   %r14
  push   %r13
  lea    D40(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  call   <fopen@plt>
  mov    %rax,%r12
  jmp    L59
  xchg   %ax,%ax
L41:
  lea    (%r14,%rbx,4),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <fscanf@plt>
  cmp    $0x64,%rbx
  je     L2
L59:
  mov    %r12,%rdi
  mov    %ebx,%ebp
  call   <feof@plt>
  test   %eax,%eax
  je     L41
L85:
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%ebx
  test   %ebx,%ebx
  jle    L47
  lea    -0x2(%rbp),%eax
  lea    0x20(%rsp),%r13
  xor    %r14d,%r14d
  movslq %eax,%rcx
  lea    -0x3(%rbp),%eax
  lea    0x4(,%rax,4),%r15
  neg    %rax
  mov    %ecx,0x4(%rsp)
  shl    $0x2,%rax
  mov    %rcx,0x8(%rsp)
  lea    (%rax,%rcx,4),%rdi
  lea    -0x4(%rax,%rcx,4),%rax
  add    %r13,%rdi
  add    %rax,%r13
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    0x8(%rsp),%rax
  mov    0x20(%rsp,%rax,4),%r12d
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L12
  mov    %r15,%rdx
  mov    %r13,%rsi
  add    $0x1,%r14d
  call   <memmove@plt>
  mov    %r12d,0x20(%rsp)
  mov    %rax,%rdi
  cmp    %ebx,%r14d
  jne    L13
L47:
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L49
  lea    -0x2(%rbp),%eax
  lea    0x20(%rsp),%rbx
  lea    0x24(%rsp,%rax,4),%r12
  lea    D4(%rip),%rbp
  nopl   0x0(%rax)
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
L49:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  add    $0x1,%r14d
  mov    %r12d,0x20(%rsp)
  cmp    %ebx,%r14d
  jne    L13
  jmp    L47
L2:
  mov    $0x64,%ebp
  jmp    L85
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D32
datatype: string
name: unpack_data
arguments: data_label: D58
datatype: string
name: unpack_data
arguments: data_label: D40
datatype: string
name: unpack_data
arguments: data_label: D27
datatype: string
name: unpack_data
arguments: data_label: D20
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string

tool: D32: r

tool: D58: res/04_input.txt

tool: D40: %d

tool: D27: Enter k= 

tool: D20: Result is: 

tool: D4: %d 

assistant: ```c
int main(void) {
  int k, size, temp, i, j;
  int input[100];
  FILE *fp = fopen("res/04_input.txt", "r");
  {
    for (size = 0; size < 100 && !feof(fp); ++size)
      fscanf(fp, "%d", &input[size]);
    --size;
  }
  printf("Enter k= ");
  scanf("%d", &k);
  for (j = 0; j < k; ++j) {
    temp = input[size - 1];
    for (i = size - 1; i > 0; --i)
      input[i] = input[i - 1];
    input[0] = temp;
  }
  {
    printf("Result is: ");
    for (i = 0; i < size; ++i)
      printf("%d ", input[i]);
    printf("\n");
  }
}
```