ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<user_dialogue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x42,%eax
  je     L77
  cmp    $0x42,%eax
  jg     L32
  cmp    $0x4,%eax
  je     L128
  cmp    $0x4,%eax
  jg     L32
  cmp    $0x3,%eax
  je     L58
  cmp    $0x3,%eax
  jg     L32
  cmp    $0x1,%eax
  je     L63
  cmp    $0x2,%eax
  je     L79
  jmp    L32
L63:
  mov    $0x0,%eax
  call   <new_arena@plt>
  jmp    L76
L79:
  mov    $0x0,%eax
  call   <view_stat@plt>
  jmp    L76
L58:
  mov    $0x0,%eax
  call   <view_late@plt>
  jmp    L76
L128:
  mov    $0x0,%eax
  call   <view_m_win@plt>
  jmp    L76
L77:
  mov    $0x0,%eax
  call   <reset@plt>
  jmp    L76
L32:
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  nop
L76:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string

tool: D4: 
 __________________________________ 
: What you want to do?             :
: -------------------------------- :
: New Arena                -> 1    :
: View Statistics          -> 2    :
: View Latest              -> 3    :
: View Most Wins           -> 4    :
: Quit                     -> 5    :
: RESET ALL STATS!!!!      -> 66   :
:__________________________________:



tool: D12: %d

tool: D20: cls

assistant: ```c
void user_dialogue(int *stop) {
  int i = 0;
  printf("\n __________________________________ \n"
         ": What you want to do?             :\n"
         ": -------------------------------- :\n"
         ": New Arena                -> 1    :\n"
         ": View Statistics          -> 2    :\n"
         ": View Latest              -> 3    :\n"
         ": View Most Wins           -> 4    :\n"
         ": Quit                     -> 5    :\n"
         ": RESET ALL STATS!!!!      -> 66   :\n"
         ":__________________________________:\n\n");
  scanf("%d", &i);
  system("cls");
  switch (i) {
  case 1:
    new_arena();
    break;
  case 2:
    view_stat();
    break;
  case 3:
    view_late();
    break;
  case 4:
    view_m_win();
    break;
  case 66:
    reset();
    break;
  default:
    *stop = 1;
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<user_dialogue>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rdi
  call   <system@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x3,%eax
  je     L28
  jle    L102
  cmp    $0x4,%eax
  je     L36
  cmp    $0x42,%eax
  jne    L99
  mov    $0x0,%eax
  call   <reset@plt>
  jmp    L24
L102:
  cmp    $0x1,%eax
  je     L34
  cmp    $0x2,%eax
  jne    L99
  mov    $0x0,%eax
  call   <view_stat@plt>
  jmp    L24
L34:
  mov    $0x0,%eax
  call   <new_arena@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  mov    $0x0,%eax
  call   <view_late@plt>
  jmp    L24
L36:
  mov    $0x0,%eax
  call   <view_m_win@plt>
  jmp    L24
L99:
  movl   $0x1,(%rbx)
  jmp    L24
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string
name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D22
data_type: string

tool: D9: 
 __________________________________ 
: What you want to do?             :
: -------------------------------- :
: New Arena                -> 1    :
: View Statistics          -> 2    :
: View Latest              -> 3    :
: View Most Wins           -> 4    :
: Quit                     -> 5    :
: RESET ALL STATS!!!!      -> 66   :
:__________________________________:



tool: D5: %d

tool: D22: cls

assistant: ```c
void user_dialogue(int *stop) {
  int i = 0;
  printf("\n __________________________________ \n"
         ": What you want to do?             :\n"
         ": -------------------------------- :\n"
         ": New Arena                -> 1    :\n"
         ": View Statistics          -> 2    :\n"
         ": View Latest              -> 3    :\n"
         ": View Most Wins           -> 4    :\n"
         ": Quit                     -> 5    :\n"
         ": RESET ALL STATS!!!!      -> 66   :\n"
         ":__________________________________:\n\n");
  scanf("%d", &i);
  system("cls");
  switch (i) {
  case 1:
    new_arena();
    break;
  case 2:
    view_stat();
    break;
  case 3:
    view_late();
    break;
  case 4:
    view_m_win();
    break;
  case 66:
    reset();
    break;
  default:
    *stop = 1;
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<user_dialogue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  call   <system@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x3,%eax
  je     L77
  jle    L105
  cmp    $0x4,%eax
  je     L45
  cmp    $0x42,%eax
  jne    L4
  xor    %eax,%eax
  call   <reset@plt>
  nopl   0x0(%rax)
L112:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L105:
  cmp    $0x1,%eax
  je     L119
  cmp    $0x2,%eax
  jne    L4
  xor    %eax,%eax
  call   <view_stat@plt>
  jmp    L112
  nopl   0x0(%rax,%rax,1)
L77:
  xor    %eax,%eax
  call   <view_late@plt>
  jmp    L112
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
  call   <view_m_win@plt>
  jmp    L112
L4:
  movl   $0x1,(%rbx)
  jmp    L112
  nopl   0x0(%rax)
L119:
  xor    %eax,%eax
  call   <new_arena@plt>
  jmp    L112
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D4
type_infered: string

tool: D5: 
 __________________________________ 
: What you want to do?             :
: -------------------------------- :
: New Arena                -> 1    :
: View Statistics          -> 2    :
: View Latest              -> 3    :
: View Most Wins           -> 4    :
: Quit                     -> 5    :
: RESET ALL STATS!!!!      -> 66   :
:__________________________________:



tool: D14: %d

tool: D4: cls

assistant: ```c
void user_dialogue(int *stop) {
  int i = 0;
  printf("\n __________________________________ \n"
         ": What you want to do?             :\n"
         ": -------------------------------- :\n"
         ": New Arena                -> 1    :\n"
         ": View Statistics          -> 2    :\n"
         ": View Latest              -> 3    :\n"
         ": View Most Wins           -> 4    :\n"
         ": Quit                     -> 5    :\n"
         ": RESET ALL STATS!!!!      -> 66   :\n"
         ":__________________________________:\n\n");
  scanf("%d", &i);
  system("cls");
  switch (i) {
  case 1:
    new_arena();
    break;
  case 2:
    view_stat();
    break;
  case 3:
    view_late();
    break;
  case 4:
    view_m_win();
    break;
  case 66:
    reset();
    break;
  default:
    *stop = 1;
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<user_dialogue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D21(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rdi
  call   <system@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x3,%eax
  je     L50
  jle    L117
  cmp    $0x4,%eax
  je     L25
  cmp    $0x42,%eax
  jne    L7
  xor    %eax,%eax
  call   <reset@plt>
  nopl   0x0(%rax)
L85:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L117:
  cmp    $0x1,%eax
  je     L63
  cmp    $0x2,%eax
  jne    L7
  xor    %eax,%eax
  call   <view_stat@plt>
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L50:
  xor    %eax,%eax
  call   <view_late@plt>
  jmp    L85
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  call   <view_m_win@plt>
  jmp    L85
L7:
  movl   $0x1,(%rbx)
  jmp    L85
  nopl   0x0(%rax)
L63:
  xor    %eax,%eax
  call   <new_arena@plt>
  jmp    L85
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D21
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string

tool: D21: 
 __________________________________ 
: What you want to do?             :
: -------------------------------- :
: New Arena                -> 1    :
: View Statistics          -> 2    :
: View Latest              -> 3    :
: View Most Wins           -> 4    :
: Quit                     -> 5    :
: RESET ALL STATS!!!!      -> 66   :
:__________________________________:



tool: D7: %d

tool: D20: cls

assistant: ```c
void user_dialogue(int *stop) {
  int i = 0;
  printf("\n __________________________________ \n"
         ": What you want to do?             :\n"
         ": -------------------------------- :\n"
         ": New Arena                -> 1    :\n"
         ": View Statistics          -> 2    :\n"
         ": View Latest              -> 3    :\n"
         ": View Most Wins           -> 4    :\n"
         ": Quit                     -> 5    :\n"
         ": RESET ALL STATS!!!!      -> 66   :\n"
         ":__________________________________:\n\n");
  scanf("%d", &i);
  system("cls");
  switch (i) {
  case 1:
    new_arena();
    break;
  case 2:
    view_stat();
    break;
  case 3:
    view_late();
    break;
  case 4:
    view_m_win();
    break;
  case 66:
    reset();
    break;
  default:
    *stop = 1;
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atomic>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  movb   $0x1,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  movl   $0x1,0xc(%rsp)
  lock addl $0x1,0x8(%rsp)
  lock subb $0x2,0x6(%rsp)
  lea    0x8(%rsp),%rbx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <__sync_fetch_and_min@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <__sync_fetch_and_max@plt>
  lea    0xc(%rsp),%rbp
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <__sync_fetch_and_umin@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <__sync_fetch_and_umax@plt>
  mov    $0x7,%eax
  xchg   %eax,0x8(%rsp)
  mov    $0x8,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <__sync_swap@plt>
  mov    $0x4,%edx
  mov    $0x7b8,%ecx
  mov    %edx,%eax
  lock cmpxchg %ecx,0x8(%rsp)
  mov    %edx,%eax
  lock cmpxchg %ecx,0x8(%rsp)
  lock andl $0x9,0x8(%rsp)
  lock orl $0xa,0x8(%rsp)
  lock xorl $0xb,0x8(%rsp)
  lock addl $0x1,0x8(%rsp)
  lock subl $0x2,0x8(%rsp)
  lock andb $0x3,0x6(%rsp)
  lock orb $0x4,0x6(%rsp)
  movzbl 0x6(%rsp),%eax
L3:
  mov    %eax,%edx
  xor    $0x5,%edx
  lock cmpxchg %dl,0x6(%rsp)
  jne    L3
  mov    $0x0,%eax
  lock cmpxchg %rax,0x0
  mov    $0x0,%eax
  mov    $0x1,%ecx
  lock cmpxchg %cl,0x7(%rsp)
  movsbl %dl,%edx
  test   %al,%al
  mov    $0x2a,%eax
  cmovne %eax,%edx
  mov    $0x0,%eax
  lock cmpxchg %rax,0x0
  movl   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lock orq $0x0,(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %edx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int atomic(void) {
  int old;
  int val = 1;
  char valc = 1;
  _Bool valb = 0;
  unsigned int uval = 1;
  int cmp = 0;
  int *ptrval;
  old = __sync_fetch_and_add(&val, 1);
  old = __sync_fetch_and_sub(&valc, 2);
  old = __sync_fetch_and_min(&val, 3);
  old = __sync_fetch_and_max(&val, 4);
  old = __sync_fetch_and_umin(&uval, 5u);
  old = __sync_fetch_and_umax(&uval, 6u);
  old = __sync_lock_test_and_set(&val, 7);
  old = __sync_swap(&val, 8);
  old = __sync_val_compare_and_swap(&val, 4, 1976);
  old = __sync_bool_compare_and_swap(&val, 4, 1976);
  old = __sync_fetch_and_and(&val, 0x9);
  old = __sync_fetch_and_or(&val, 0xa);
  old = __sync_fetch_and_xor(&val, 0xb);
  old = __sync_add_and_fetch(&val, 1);
  old = __sync_sub_and_fetch(&val, 2);
  old = __sync_and_and_fetch(&valc, 3);
  old = __sync_or_and_fetch(&valc, 4);
  old = __sync_xor_and_fetch(&valc, 5);
  __sync_val_compare_and_swap((void **)0, (void *)0, (void *)0);
  if (__sync_val_compare_and_swap(&valb, 0, 1)) {
    old = 42;
  }
  __sync_bool_compare_and_swap((void **)0, (void *)0, (void *)0);
  __sync_lock_release(&val);
  __sync_lock_release(&ptrval);
  __sync_synchronize();
  return old;
}
```
user: What is the c source code of the assembly code below:

```asm
<atomic>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  movb   $0x1,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  movl   $0x1,0xc(%rsp)
  lock addl $0x1,0x8(%rsp)
  lock subb $0x2,0x6(%rsp)
  mov    $0x3,%esi
  lea    0x8(%rsp),%rbp
  lea    0xc(%rsp),%r12
  mov    %rbp,%rdi
  call   <__sync_fetch_and_min@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  xor    %eax,%eax
  call   <__sync_fetch_and_max@plt>
  mov    %r12,%rdi
  mov    $0x5,%esi
  xor    %eax,%eax
  call   <__sync_fetch_and_umin@plt>
  mov    $0x6,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <__sync_fetch_and_umax@plt>
  mov    $0x7,%eax
  xchg   %eax,0x8(%rsp)
  mov    $0x8,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <__sync_swap@plt>
  mov    $0x4,%edx
  mov    $0x7b8,%ecx
  mov    %edx,%eax
  lock cmpxchg %ecx,0x8(%rsp)
  mov    %edx,%eax
  lock cmpxchg %ecx,0x8(%rsp)
  lock andl $0x9,0x8(%rsp)
  lock orl $0xa,0x8(%rsp)
  lock xorl $0xb,0x8(%rsp)
  lock addl $0x1,0x8(%rsp)
  lock subl $0x2,0x8(%rsp)
  lock andb $0x3,0x6(%rsp)
  lock orb $0x4,0x6(%rsp)
  movzbl 0x6(%rsp),%eax
L11:
  mov    %eax,%edx
  xor    $0x5,%edx
  lock cmpxchg %dl,0x6(%rsp)
  jne    L11
  xor    %ecx,%ecx
  mov    %rcx,%rax
  lock cmpxchg %rcx,0x0
  xor    %eax,%eax
  mov    $0x1,%esi
  lock cmpxchg %sil,0x7(%rsp)
  test   %al,%al
  movsbl %dl,%edx
  mov    $0x2a,%eax
  cmove  %edx,%eax
  mov    %eax,%r8d
  mov    %rcx,%rax
  lock cmpxchg %rcx,0x0
  movl   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lock orq $0x0,(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int atomic(void) {
  int old;
  int val = 1;
  char valc = 1;
  _Bool valb = 0;
  unsigned int uval = 1;
  int cmp = 0;
  int *ptrval;
  old = __sync_fetch_and_add(&val, 1);
  old = __sync_fetch_and_sub(&valc, 2);
  old = __sync_fetch_and_min(&val, 3);
  old = __sync_fetch_and_max(&val, 4);
  old = __sync_fetch_and_umin(&uval, 5u);
  old = __sync_fetch_and_umax(&uval, 6u);
  old = __sync_lock_test_and_set(&val, 7);
  old = __sync_swap(&val, 8);
  old = __sync_val_compare_and_swap(&val, 4, 1976);
  old = __sync_bool_compare_and_swap(&val, 4, 1976);
  old = __sync_fetch_and_and(&val, 0x9);
  old = __sync_fetch_and_or(&val, 0xa);
  old = __sync_fetch_and_xor(&val, 0xb);
  old = __sync_add_and_fetch(&val, 1);
  old = __sync_sub_and_fetch(&val, 2);
  old = __sync_and_and_fetch(&valc, 3);
  old = __sync_or_and_fetch(&valc, 4);
  old = __sync_xor_and_fetch(&valc, 5);
  __sync_val_compare_and_swap((void **)0, (void *)0, (void *)0);
  if (__sync_val_compare_and_swap(&valb, 0, 1)) {
    old = 42;
  }
  __sync_bool_compare_and_swap((void **)0, (void *)0, (void *)0);
  __sync_lock_release(&val);
  __sync_lock_release(&ptrval);
  __sync_synchronize();
  return old;
}
```
user: What is the c source code of the assembly code below:

```asm
<atomic>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  movb   $0x1,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  movl   $0x1,0xc(%rsp)
  lock addl $0x1,0x8(%rsp)
  lock subb $0x2,0x6(%rsp)
  mov    $0x3,%esi
  lea    0x8(%rsp),%rbp
  lea    0xc(%rsp),%r12
  mov    %rbp,%rdi
  call   <__sync_fetch_and_min@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  xor    %eax,%eax
  call   <__sync_fetch_and_max@plt>
  mov    %r12,%rdi
  mov    $0x5,%esi
  xor    %eax,%eax
  call   <__sync_fetch_and_umin@plt>
  mov    $0x6,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <__sync_fetch_and_umax@plt>
  mov    $0x7,%eax
  xchg   %eax,0x8(%rsp)
  mov    $0x8,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <__sync_swap@plt>
  mov    $0x4,%edx
  mov    $0x7b8,%ecx
  mov    %edx,%eax
  lock cmpxchg %ecx,0x8(%rsp)
  mov    %edx,%eax
  lock cmpxchg %ecx,0x8(%rsp)
  lock andl $0x9,0x8(%rsp)
  lock orl $0xa,0x8(%rsp)
  lock xorl $0xb,0x8(%rsp)
  lock addl $0x1,0x8(%rsp)
  lock subl $0x2,0x8(%rsp)
  lock andb $0x3,0x6(%rsp)
  lock orb $0x4,0x6(%rsp)
  movzbl 0x6(%rsp),%eax
L0:
  mov    %eax,%edx
  xor    $0x5,%edx
  lock cmpxchg %dl,0x6(%rsp)
  jne    L0
  xor    %ecx,%ecx
  mov    %rcx,%rax
  lock cmpxchg %rcx,0x0
  xor    %eax,%eax
  mov    $0x1,%esi
  lock cmpxchg %sil,0x7(%rsp)
  test   %al,%al
  movsbl %dl,%edx
  mov    $0x2a,%eax
  cmove  %edx,%eax
  mov    %eax,%r8d
  mov    %rcx,%rax
  lock cmpxchg %rcx,0x0
  movl   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lock orq $0x0,(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int atomic(void) {
  int old;
  int val = 1;
  char valc = 1;
  _Bool valb = 0;
  unsigned int uval = 1;
  int cmp = 0;
  int *ptrval;
  old = __sync_fetch_and_add(&val, 1);
  old = __sync_fetch_and_sub(&valc, 2);
  old = __sync_fetch_and_min(&val, 3);
  old = __sync_fetch_and_max(&val, 4);
  old = __sync_fetch_and_umin(&uval, 5u);
  old = __sync_fetch_and_umax(&uval, 6u);
  old = __sync_lock_test_and_set(&val, 7);
  old = __sync_swap(&val, 8);
  old = __sync_val_compare_and_swap(&val, 4, 1976);
  old = __sync_bool_compare_and_swap(&val, 4, 1976);
  old = __sync_fetch_and_and(&val, 0x9);
  old = __sync_fetch_and_or(&val, 0xa);
  old = __sync_fetch_and_xor(&val, 0xb);
  old = __sync_add_and_fetch(&val, 1);
  old = __sync_sub_and_fetch(&val, 2);
  old = __sync_and_and_fetch(&valc, 3);
  old = __sync_or_and_fetch(&valc, 4);
  old = __sync_xor_and_fetch(&valc, 5);
  __sync_val_compare_and_swap((void **)0, (void *)0, (void *)0);
  if (__sync_val_compare_and_swap(&valb, 0, 1)) {
    old = 42;
  }
  __sync_bool_compare_and_swap((void **)0, (void *)0, (void *)0);
  __sync_lock_release(&val);
  __sync_lock_release(&ptrval);
  __sync_synchronize();
  return old;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <ck@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <ck@plt>
  mov    %eax,-0x4(%rbp)
  andl   $0xff000000,-0x8(%rbp)
  andl   $0xff000000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x18,%eax
  or     -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t check(uint64_t z) {
  uint64_t ck1 = ck(3, 2, z);
  uint64_t ck2 = ck(3, 2, z << 24);
  ck1 &= 0x00000000FFFFFF000000;
  ck2 &= 0x00000000FFFFFF000000;
  return ck1 | ck2 >> 24;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %edi,%edx
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <ck@plt>
  mov    %eax,%ebx
  mov    %ebp,%edx
  shl    $0x18,%edx
  mov    $0x2,%esi
  mov    $0x3,%edi
  call   <ck@plt>
  and    $0xff000000,%ebx
  sar    $0x18,%eax
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t check(uint64_t z) {
  uint64_t ck1 = ck(3, 2, z);
  uint64_t ck2 = ck(3, 2, z << 24);
  ck1 &= 0x00000000FFFFFF000000;
  ck2 &= 0x00000000FFFFFF000000;
  return ck1 | ck2 >> 24;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  mov    %edi,%ebp
  mov    $0x2,%esi
  push   %rbx
  mov    $0x3,%edi
  sub    $0x8,%rsp
  call   <ck@plt>
  mov    %ebp,%edx
  mov    $0x2,%esi
  mov    $0x3,%edi
  shl    $0x18,%edx
  mov    %eax,%ebx
  call   <ck@plt>
  and    $0xff000000,%ebx
  add    $0x8,%rsp
  sar    $0x18,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t check(uint64_t z) {
  uint64_t ck1 = ck(3, 2, z);
  uint64_t ck2 = ck(3, 2, z << 24);
  ck1 &= 0x00000000FFFFFF000000;
  ck2 &= 0x00000000FFFFFF000000;
  return ck1 | ck2 >> 24;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  mov    %edi,%ebp
  mov    $0x2,%esi
  push   %rbx
  mov    $0x3,%edi
  sub    $0x8,%rsp
  call   <ck@plt>
  mov    %ebp,%edx
  mov    $0x2,%esi
  mov    $0x3,%edi
  shl    $0x18,%edx
  mov    %eax,%ebx
  call   <ck@plt>
  and    $0xff000000,%ebx
  add    $0x8,%rsp
  sar    $0x18,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t check(uint64_t z) {
  uint64_t ck1 = ck(3, 2, z);
  uint64_t ck2 = ck(3, 2, z << 24);
  ck1 &= 0x00000000FFFFFF000000;
  ck2 &= 0x00000000FFFFFF000000;
  return ck1 | ck2 >> 24;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fdimf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0x8(%rbp)
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L59
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L59
  pxor   %xmm0,%xmm0
  comiss -0x18(%rbp),%xmm0
  jbe    L2
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L2
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L2
L59:
  movss  -0x14(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  jmp    L50
L2:
  movss  -0x18(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jb     L79
  pxor   %xmm0,%xmm0
  jmp    L50
L79:
  movss  -0x14(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <fpclassify@plt>
  mov    D31(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jne    L88
  mov    D51(%rip),%rax
  mov    (%rax),%edx
  mov    D28(%rip),%rax
  mov    %edx,(%rax)
L88:
  movss  -0x4(%rbp),%xmm0
L50:
  leave
  ret
```

assistant: ```c
float fdimf(float x, float y) {
  int cx = fpclassify(x), cy = fpclassify(y);
  float r;
  if (cx == FP_NAN || cy == FP_NAN || (y < 0 && cx == FP_INFINITE && cy == FP_INFINITE))
    return x - y;
  if (x <= y)
    return 0.0f;
  r = x - y;
  if (fpclassify(r) == FP_INFINITE)
    errno = ERANGE;
  return r;
}
```