ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x1,-0x78(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L55
L76:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x74(%rbp),%eax
  sub    -0x7c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L48
  movl   $0x0,-0x78(%rbp)
  jmp    L8
L48:
  addl   $0x1,-0x7c(%rbp)
L55:
  mov    -0x74(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x7c(%rbp)
  jge    L8
  cmpl   $0x0,-0x78(%rbp)
  jne    L76
L8:
  cmpl   $0x0,-0x78(%rbp)
  je     L57
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L56
L57:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L56:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D22
data_type: string
name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D9
data_type: string
name: unpack_data
arguments: label: D20
data_type: string

tool: D22: Vuvedete duma:


tool: D12: %s

tool: D9:  1 


tool: D20:  0 


assistant: ```c
int main() {
  char Duma[100];
  int l, c;
  printf("Vuvedete duma:\n");
  scanf("%s", Duma);
  l = strlen(Duma);
  int f = 1;
  for (c = 0; c < l / 2 && f; c++) {
    if (Duma[c] != Duma[l - c - 1]) {
      f = 0;
      break;
    }
  }
  if (f) {
    printf(" 1 \n");
  } else {
    printf(" 0 \n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  cmp    $0x1,%eax
  jle    L18
  cltq
  lea    (%rsp,%rax,1),%rdx
  mov    $0x0,%eax
L41:
  movzbl -0x1(%rdx),%esi
  cmp    %sil,(%rsp,%rax,1)
  jne    L10
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%ecx
  jg     L41
L18:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L10:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: string
name: retrieve_data
arguments: tag: D26
type_infered: string
name: retrieve_data
arguments: tag: D33
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D14: Vuvedete duma:


tool: D26: %s

tool: D33:  1 


tool: D5:  0 


assistant: ```c
int main() {
  char Duma[100];
  int l, c;
  printf("Vuvedete duma:\n");
  scanf("%s", Duma);
  l = strlen(Duma);
  int f = 1;
  for (c = 0; c < l / 2 && f; c++) {
    if (Duma[c] != Duma[l - c - 1]) {
      f = 0;
      break;
    }
  }
  if (f) {
    printf(" 1 \n");
  } else {
    printf(" 0 \n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D18(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  cmp    $0x1,%eax
  jle    L38
  cltq
  xor    %edx,%edx
  add    %rbx,%rax
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %edx,%ecx
  jle    L38
L28:
  movzbl -0x1(%rax),%esi
  cmp    %sil,(%rbx,%rdx,1)
  je     L15
  lea    D5(%rip),%rdi
  call   <printf@plt>
L39:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L38:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D5
type_guessed: string
name: extract_symbolic_data
arguments: label: D39
type_guessed: string

tool: D18: Vuvedete duma:


tool: D15: %s

tool: D5:  0 


tool: D39:  1 


assistant: ```c
int main() {
  char Duma[100];
  int l, c;
  printf("Vuvedete duma:\n");
  scanf("%s", Duma);
  l = strlen(Duma);
  int f = 1;
  for (c = 0; c < l / 2 && f; c++) {
    if (Duma[c] != Duma[l - c - 1]) {
      f = 0;
      break;
    }
  }
  if (f) {
    printf(" 1 \n");
  } else {
    printf(" 0 \n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D34(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  cmp    $0x1,%eax
  jle    L1
  cltq
  xor    %edx,%edx
  add    %rbx,%rax
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L32:
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %edx,%ecx
  jle    L1
L3:
  movzbl -0x1(%rax),%esi
  cmp    %sil,(%rbx,%rdx,1)
  je     L32
  lea    D23(%rip),%rdi
  call   <printf@plt>
L35:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D34
datatype: string
name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D23
datatype: string
name: unpack_data
arguments: data_tag: D24
datatype: string

tool: D34: Vuvedete duma:


tool: D13: %s

tool: D23:  0 


tool: D24:  1 


assistant: ```c
int main() {
  char Duma[100];
  int l, c;
  printf("Vuvedete duma:\n");
  scanf("%s", Duma);
  l = strlen(Duma);
  int f = 1;
  for (c = 0; c < l / 2 && f; c++) {
    if (Duma[c] != Duma[l - c - 1]) {
      f = 0;
      break;
    }
  }
  if (f) {
    printf(" 1 \n");
  } else {
    printf(" 0 \n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L17
L2:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L15
L36:
  mov    -0x10(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x10(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  add    $0x13,%rax
  cmp    %rax,-0x10(%rbp)
  jle    L36
  mov    $0x0,%eax
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D13
data_type: string

tool: D5: argv[1] is not defined

tool: D13: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  long beginning = 0;
  if (argc >= 2) {
    beginning = strtol(argv[1], NULL, 10);
  } else {
    printf("argv[1] is not defined\n");
    return 1;
  }
  for (long i = beginning; i < beginning + 20; i++) {
    printf("%ld\n", i * i);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L1
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%rbx
  lea    0x13(%rax),%r12
  lea    D15(%rip),%rbp
L13:
  mov    %rbx,%rsi
  imul   %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jle    L13
  mov    $0x0,%eax
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L27
```

tool_calls: name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D4
type_guessed: string

tool: D15: %ld


tool: D4: argv[1] is not defined

assistant: ```c
int main(int argc, char *argv[]) {
  long beginning = 0;
  if (argc >= 2) {
    beginning = strtol(argv[1], NULL, 10);
  } else {
    printf("argv[1] is not defined\n");
    return 1;
  }
  for (long i = beginning; i < beginning + 20; i++) {
    printf("%ld\n", i * i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L16
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  lea    D13(%rip),%rbp
  call   <strtol@plt>
  mov    %rax,%rbx
  lea    0x13(%rax),%r12
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %rbx,%rsi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jle    L28
  xor    %eax,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L9
```

tool_calls: name: read_data
arguments: data_label: D13
type_infered: string
name: read_data
arguments: data_label: D16
type_infered: string

tool: D13: %ld


tool: D16: argv[1] is not defined

assistant: ```c
int main(int argc, char *argv[]) {
  long beginning = 0;
  if (argc >= 2) {
    beginning = strtol(argv[1], NULL, 10);
  } else {
    printf("argv[1] is not defined\n");
    return 1;
  }
  for (long i = beginning; i < beginning + 20; i++) {
    printf("%ld\n", i * i);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L2
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  lea    D4(%rip),%rbp
  call   <strtol@plt>
  mov    %rax,%rbx
  lea    0x13(%rax),%r12
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %rbx,%rsi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jle    L28
  xor    %eax,%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L16
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string
name: parse_data
arguments: tag: D10
data_type: string

tool: D4: %ld


tool: D10: argv[1] is not defined

assistant: ```c
int main(int argc, char *argv[]) {
  long beginning = 0;
  if (argc >= 2) {
    beginning = strtol(argv[1], NULL, 10);
  } else {
    printf("argv[1] is not defined\n");
    return 1;
  }
  for (long i = beginning; i < beginning + 20; i++) {
    printf("%ld\n", i * i);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sort_nbrs>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rdx,%rsi
  mov    %rcx,%rdi
  mov    $0x1,%ecx
  lea    -0x2(%r10),%rbx
  mov    $0x0,%r12d
  mov    $0x1,%ebp
  jmp    L57
L46:
  movsd  %xmm1,(%rsi,%rax,8)
  movsd  %xmm0,0x8(%rsi,%rax,8)
  movsd  (%rdx),%xmm0
  movsd  0x18(%rdx),%xmm1
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,0x18(%rdx)
  movsd  0x8(%rdx),%xmm0
  movsd  0x20(%rdx),%xmm1
  movsd  %xmm1,0x8(%rdx)
  movsd  %xmm0,0x20(%rdx)
  movsd  0x10(%rdx),%xmm0
  movsd  0x28(%rdx),%xmm1
  movsd  %xmm1,0x10(%rdx)
  movsd  %xmm0,0x28(%rdx)
  mov    (%rdi,%rax,8),%r9
  mov    0x8(%rdi,%rax,8),%r14
  mov    %r14,(%rdi,%rax,8)
  movslq %r9d,%r9
  mov    %r9,0x8(%rdi,%rax,8)
  mov    (%r8,%rax,8),%r9
  mov    0x8(%r8,%rax,8),%r14
  mov    %r14,(%r8,%rax,8)
  movslq %r9d,%r9
  mov    %r9,0x8(%r8,%rax,8)
  mov    %ebp,%r9d
L19:
  cmp    %rax,%rbx
  je     L13
  add    $0x1,%ecx
  add    $0x1,%rax
  add    $0x18,%rdx
  cmp    $0x3e9,%ecx
  je     L44
L83:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  0x8(%rsi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  jbe    L19
  jmp    L46
L13:
  test   %r9d,%r9d
  je     L44
  add    $0x1,%ecx
  cmp    $0x3e8,%ecx
  jg     L44
L57:
  cmp    $0x1,%r10
  jle    L44
  add    $0x1,%ecx
  cmp    $0x3e8,%ecx
  jg     L44
  mov    %r11,%rdx
  mov    $0x0,%eax
  mov    %r12d,%r9d
  jmp    L83
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
void sort_nbrs(long nba, double acens[8][3], double brads[8], long nbrs[8], long bnds[8]) {
  int j, k, change, n_iter;
  double temp;
  int itemp;
  change = 1;
  n_iter = 0;
  while (change) {
    n_iter++;
    if (n_iter > 1000)
      break;
    change = 0;
    for (j = 0; j < nba - 1; j++) {
      n_iter++;
      if (n_iter > 1000)
        break;
      if (brads[j] < brads[j + 1]) {
        change = 1;
        temp = brads[j];
        brads[j] = brads[j + 1];
        brads[j + 1] = temp;
        for (k = 0; k < 3; k++) {
          temp = acens[j][k];
          acens[j][k] = acens[j + 1][k];
          acens[j + 1][k] = temp;
        }
        itemp = nbrs[j];
        nbrs[j] = nbrs[j + 1];
        nbrs[j + 1] = itemp;
        itemp = bnds[j];
        bnds[j] = bnds[j + 1];
        bnds[j + 1] = itemp;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sort_nbrs>:
  endbr64
  push   %r14
  mov    %rcx,%r9
  mov    $0x1,%ecx
  push   %r13
  mov    $0x3e7,%r13d
  push   %r12
  lea    -0x1(%rdi),%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L13:
  cmp    $0x1,%rbx
  jle    L70
  cmp    $0x3e8,%ecx
  je     L70
  mov    %r13d,%edi
  mov    %rbp,%rdx
  mov    $0x1,%eax
  xor    %r11d,%r11d
  sub    %ecx,%edi
  add    $0x2,%rdi
  jmp    L14
  nopl   0x0(%rax)
L88:
  cmp    %rax,%r12
  je     L36
L50:
  add    $0x1,%rax
  add    $0x18,%rdx
  cmp    %rdi,%rax
  je     L70
L14:
  movsd  -0x8(%rsi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  lea    (%rcx,%rax,1),%r10d
  comisd %xmm0,%xmm1
  jbe    L88
  movsd  %xmm1,-0x8(%rsi,%rax,8)
  mov    -0x8(%r9,%rax,8),%r11
  mov    (%r9,%rax,8),%r14
  movsd  %xmm0,(%rsi,%rax,8)
  movsd  (%rdx),%xmm0
  movsd  0x18(%rdx),%xmm1
  movslq %r11d,%r11
  movsd  %xmm1,(%rdx)
  movsd  0x20(%rdx),%xmm1
  movsd  %xmm0,0x18(%rdx)
  movsd  0x8(%rdx),%xmm0
  movsd  %xmm1,0x8(%rdx)
  movsd  0x28(%rdx),%xmm1
  movsd  %xmm0,0x20(%rdx)
  movsd  0x10(%rdx),%xmm0
  movsd  %xmm1,0x10(%rdx)
  movsd  %xmm0,0x28(%rdx)
  mov    %r14,-0x8(%r9,%rax,8)
  mov    %r11,(%r9,%rax,8)
  mov    -0x8(%r8,%rax,8),%r11
  mov    (%r8,%rax,8),%r14
  movslq %r11d,%r11
  mov    %r11,(%r8,%rax,8)
  mov    $0x1,%r11d
  mov    %r14,-0x8(%r8,%rax,8)
  cmp    %rax,%r12
  jne    L50
L36:
  test   %r11d,%r11d
  je     L70
  lea    0x1(%r10),%ecx
  cmp    $0x3e8,%ecx
  jle    L13
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void sort_nbrs(long nba, double acens[8][3], double brads[8], long nbrs[8], long bnds[8]) {
  int j, k, change, n_iter;
  double temp;
  int itemp;
  change = 1;
  n_iter = 0;
  while (change) {
    n_iter++;
    if (n_iter > 1000)
      break;
    change = 0;
    for (j = 0; j < nba - 1; j++) {
      n_iter++;
      if (n_iter > 1000)
        break;
      if (brads[j] < brads[j + 1]) {
        change = 1;
        temp = brads[j];
        brads[j] = brads[j + 1];
        brads[j + 1] = temp;
        for (k = 0; k < 3; k++) {
          temp = acens[j][k];
          acens[j][k] = acens[j + 1][k];
          acens[j + 1][k] = temp;
        }
        itemp = nbrs[j];
        nbrs[j] = nbrs[j + 1];
        nbrs[j + 1] = itemp;
        itemp = bnds[j];
        bnds[j] = bnds[j + 1];
        bnds[j + 1] = itemp;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sort_nbrs>:
  endbr64
  push   %r13
  mov    %rcx,%r11
  lea    -0x1(%rdi),%r10
  mov    $0x1,%ecx
  push   %r12
  mov    $0x3e7,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L39:
  cmp    $0x1,%rbx
  jle    L28
  cmp    $0x3e8,%ecx
  je     L28
  mov    %r12d,%edi
  mov    %rbp,%rdx
  mov    $0x1,%eax
  xor    %r13d,%r13d
  sub    %ecx,%edi
  add    $0x2,%rdi
  jmp    L54
  nopl   0x0(%rax)
L23:
  cmp    %r10,%rax
  je     L35
L30:
  add    $0x1,%rax
  add    $0x18,%rdx
  cmp    %rax,%rdi
  je     L28
L54:
  movupd -0x8(%rsi,%rax,8),%xmm0
  lea    (%rcx,%rax,1),%r9d
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  shufpd $0x1,%xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L23
  movups %xmm2,-0x8(%rsi,%rax,8)
  movsd  (%rdx),%xmm0
  movsd  0x18(%rdx),%xmm1
  movslq -0x8(%r11,%rax,8),%r13
  movsd  %xmm0,0x18(%rdx)
  movsd  0x8(%rdx),%xmm0
  movsd  %xmm1,(%rdx)
  movsd  0x20(%rdx),%xmm1
  movsd  %xmm0,0x20(%rdx)
  movsd  0x10(%rdx),%xmm0
  movsd  %xmm1,0x8(%rdx)
  movsd  0x28(%rdx),%xmm1
  movsd  %xmm0,0x28(%rdx)
  movq   (%r11,%rax,8),%xmm0
  movsd  %xmm1,0x10(%rdx)
  movq   %r13,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,-0x8(%r11,%rax,8)
  movslq -0x8(%r8,%rax,8),%r13
  movq   (%r8,%rax,8),%xmm0
  movq   %r13,%xmm1
  mov    $0x1,%r13d
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,-0x8(%r8,%rax,8)
  cmp    %r10,%rax
  jne    L30
L35:
  test   %r13d,%r13d
  je     L28
  lea    0x1(%r9),%ecx
  cmp    $0x3e8,%ecx
  jle    L39
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sort_nbrs(long nba, double acens[8][3], double brads[8], long nbrs[8], long bnds[8]) {
  int j, k, change, n_iter;
  double temp;
  int itemp;
  change = 1;
  n_iter = 0;
  while (change) {
    n_iter++;
    if (n_iter > 1000)
      break;
    change = 0;
    for (j = 0; j < nba - 1; j++) {
      n_iter++;
      if (n_iter > 1000)
        break;
      if (brads[j] < brads[j + 1]) {
        change = 1;
        temp = brads[j];
        brads[j] = brads[j + 1];
        brads[j + 1] = temp;
        for (k = 0; k < 3; k++) {
          temp = acens[j][k];
          acens[j][k] = acens[j + 1][k];
          acens[j + 1][k] = temp;
        }
        itemp = nbrs[j];
        nbrs[j] = nbrs[j + 1];
        nbrs[j + 1] = itemp;
        itemp = bnds[j];
        bnds[j] = bnds[j + 1];
        bnds[j + 1] = itemp;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_mosquitto_send_disconnect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    $0xe0,%esi
  mov    %rax,%rdi
  call   <_mosquitto_send_simple_command@plt>
  leave
  ret
```

assistant: ```c
int _mosquitto_send_disconnect(struct mosquitto *mosq) {
  assert(mosq);
  return _mosquitto_send_simple_command(mosq, 0xE0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_mosquitto_send_disconnect>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    $0xe0,%esi
  mov    %rbx,%rdi
  call   <_mosquitto_send_simple_command@plt>
  pop    %rbx
  ret
```

assistant: ```c
int _mosquitto_send_disconnect(struct mosquitto *mosq) {
  assert(mosq);
  return _mosquitto_send_simple_command(mosq, 0xE0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_mosquitto_send_disconnect>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  mov    $0xe0,%esi
  pop    %rbp
  jmp    1060 <_mosquitto_send_simple_command@plt>
```

assistant: ```c
int _mosquitto_send_disconnect(struct mosquitto *mosq) {
  assert(mosq);
  return _mosquitto_send_simple_command(mosq, 0xE0);
}
```
user: What is the c source code of the assembly code below?

```asm
<_mosquitto_send_disconnect>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  mov    $0xe0,%esi
  pop    %rbp
  jmp    1060 <_mosquitto_send_simple_command@plt>
```

assistant: ```c
int _mosquitto_send_disconnect(struct mosquitto *mosq) {
  assert(mosq);
  return _mosquitto_send_simple_command(mosq, 0xE0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cprop_test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x4,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cprop_test2(int *data) {
  int j = 1;
  int k = 2;
  int m = 4;
  int n = k * m;
  j = n + j;
  data[0] = j;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cprop_test2>:
  endbr64
  movl   $0x9,(%rdi)
  ret
```

assistant: ```c
void cprop_test2(int *data) {
  int j = 1;
  int k = 2;
  int m = 4;
  int n = k * m;
  j = n + j;
  data[0] = j;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cprop_test2>:
  endbr64
  movl   $0x9,(%rdi)
  ret
```

assistant: ```c
void cprop_test2(int *data) {
  int j = 1;
  int k = 2;
  int m = 4;
  int n = k * m;
  j = n + j;
  data[0] = j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cprop_test2>:
  endbr64
  movl   $0x9,(%rdi)
  ret
```

assistant: ```c
void cprop_test2(int *data) {
  int j = 1;
  int k = 2;
  int m = 4;
  int n = k * m;
  j = n + j;
  data[0] = j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<merge_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L0
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <merge_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <merge_sort>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void merge_sort(int *A, int first, int last) {
  int middle = (first + last) / 2;
  if (first < last) {
    merge_sort(A, first, middle);
    merge_sort(A, middle + 1, last);
    merge(A, first, middle, last);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<merge_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L6
  ret
L6:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <merge_sort>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <merge_sort>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void merge_sort(int *A, int first, int last) {
  int middle = (first + last) / 2;
  if (first < last) {
    merge_sort(A, first, middle);
    merge_sort(A, middle + 1, last);
    merge(A, first, middle, last);
  }
}
```