ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timeval_subtract>:
  endbr64
  mov    0x8(%rdx),%rcx
  sub    0x8(%rsi),%rcx
  mov    %rcx,0x8(%rdi)
  mov    (%rdx),%eax
  mov    (%rsi),%r8d
  cmp    %r8d,%eax
  jl     L16
  sub    %r8d,%eax
L14:
  mov    %eax,(%rdi)
  ret
L16:
  sub    $0x1,%rcx
  mov    %rcx,0x8(%rdi)
  mov    $0xf4240,%eax
  sub    (%rsi),%eax
  add    (%rdx),%eax
  jmp    L14
```

assistant: ```c
void timeval_subtract(struct timeval *result, struct timeval *start, struct timeval *end) {
  result->tv_sec = end->tv_sec - start->tv_sec;
  if (end->tv_usec >= start->tv_usec) {
    result->tv_usec = end->tv_usec - start->tv_usec;
  } else {
    result->tv_sec -= 1;
    result->tv_usec = (1000000 - start->tv_usec) + end->tv_usec;
  };
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<timeval_subtract>:
  endbr64
  mov    0x8(%rdx),%rcx
  mov    (%rdx),%eax
  mov    (%rsi),%edx
  sub    0x8(%rsi),%rcx
  mov    %rcx,0x8(%rdi)
  cmp    %edx,%eax
  jl     L5
  sub    %edx,%eax
  mov    %eax,(%rdi)
  ret
  nopl   (%rax)
L5:
  sub    %edx,%eax
  sub    $0x1,%rcx
  add    $0xf4240,%eax
  mov    %rcx,0x8(%rdi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void timeval_subtract(struct timeval *result, struct timeval *start, struct timeval *end) {
  result->tv_sec = end->tv_sec - start->tv_sec;
  if (end->tv_usec >= start->tv_usec) {
    result->tv_usec = end->tv_usec - start->tv_usec;
  } else {
    result->tv_sec -= 1;
    result->tv_usec = (1000000 - start->tv_usec) + end->tv_usec;
  };
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<timeval_subtract>:
  endbr64
  mov    0x8(%rdx),%rcx
  mov    (%rdx),%eax
  mov    (%rsi),%edx
  sub    0x8(%rsi),%rcx
  mov    %rcx,0x8(%rdi)
  cmp    %edx,%eax
  jl     L4
  sub    %edx,%eax
  mov    %eax,(%rdi)
  ret
  nopl   (%rax)
L4:
  sub    %edx,%eax
  sub    $0x1,%rcx
  add    $0xf4240,%eax
  mov    %rcx,0x8(%rdi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void timeval_subtract(struct timeval *result, struct timeval *start, struct timeval *end) {
  result->tv_sec = end->tv_sec - start->tv_sec;
  if (end->tv_usec >= start->tv_usec) {
    result->tv_usec = end->tv_usec - start->tv_usec;
  } else {
    result->tv_sec -= 1;
    result->tv_usec = (1000000 - start->tv_usec) + end->tv_usec;
  };
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
data_type: string
name: extract_symbolic_data
arguments: data_label: D19
data_type: string

tool: D18: Hello world from C!


tool: D19: YES!

assistant: ```c
int main() {
  printf("Hello world from C!\n");
  printf("YES!");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string

tool: D9: Hello world from C!


tool: D19: YES!

assistant: ```c
int main() {
  printf("Hello world from C!\n");
  printf("YES!");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D16: Hello world from C!


tool: D9: YES!

assistant: ```c
int main() {
  printf("Hello world from C!\n");
  printf("YES!");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D14: Hello world from C!


tool: D1: YES!

assistant: ```c
int main() {
  printf("Hello world from C!\n");
  printf("YES!");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: hello 


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("hello \n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: hello 


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("hello \n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: hello 


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("hello \n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0: hello 


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("hello \n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<multiplication>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x5,-0x8(%rbp)
  jle    L2
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L2:
  cmpl   $0xfffffff6,-0x8(%rbp)
  jge    L18
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L18:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void multiplication(unsigned U, signed S) {
  if (S > 5)
    S = U * S;
  if (S < -10)
    S = U * S;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<multiplication>:
  endbr64
  ret
```

assistant: ```c
void multiplication(unsigned U, signed S) {
  if (S > 5)
    S = U * S;
  if (S < -10)
    S = U * S;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiplication>:
  endbr64
  ret
```

assistant: ```c
void multiplication(unsigned U, signed S) {
  if (S > 5)
    S = U * S;
  if (S < -10)
    S = U * S;
}
```
user: What is the c source code of the assembly code below?

```asm
<multiplication>:
  endbr64
  ret
```

assistant: ```c
void multiplication(unsigned U, signed S) {
  if (S > 5)
    S = U * S;
  if (S < -10)
    S = U * S;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sys$expreg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x24(%rbp)
  movsbq -0x24(%rbp),%rax
  mov    %rax,%r10
  mov    -0x18(%rbp),%eax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    -0x14(%rbp),%eax
  mov    %rax,%rdi
  mov    $0x31,%rax
  int    $0x81
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sys$expreg(unsigned int pagcnt, struct _va_range *retadr, unsigned int acmode, char region) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)((int)region);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(retadr);
    register long int _a1 asm("rdi") = (long)(pagcnt);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(49), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sys$expreg>:
  endbr64
  movsbq %cl,%r10
  mov    %edx,%edx
  mov    %edi,%edi
  mov    $0x31,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$expreg(unsigned int pagcnt, struct _va_range *retadr, unsigned int acmode, char region) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)((int)region);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(retadr);
    register long int _a1 asm("rdi") = (long)(pagcnt);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(49), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sys$expreg>:
  endbr64
  movsbq %cl,%r10
  mov    %edx,%edx
  mov    %edi,%edi
  mov    $0x31,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$expreg(unsigned int pagcnt, struct _va_range *retadr, unsigned int acmode, char region) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)((int)region);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(retadr);
    register long int _a1 asm("rdi") = (long)(pagcnt);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(49), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sys$expreg>:
  endbr64
  movsbq %cl,%r10
  mov    %edx,%edx
  mov    %edi,%edi
  mov    $0x31,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$expreg(unsigned int pagcnt, struct _va_range *retadr, unsigned int acmode, char region) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)((int)region);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(retadr);
    register long int _a1 asm("rdi") = (long)(pagcnt);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(49), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L20
L27:
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <inserePrimeiro@plt>
  addl   $0x1,-0x14(%rbp)
L20:
  cmpl   $0x9,-0x14(%rbp)
  jle    L27
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <imprime@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int main() {
  int i = 0;
  struct nodo *p = NULL;
  for (i = 0; i < 10; i++) {
    inserePrimeiro(&p, i);
  }
  imprime(&p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%ebx
  mov    %rsp,%rbp
L12:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <inserePrimeiro@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L12
  mov    %rsp,%rdi
  call   <imprime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i = 0;
  struct nodo *p = NULL;
  for (i = 0; i < 10; i++) {
    inserePrimeiro(&p, i);
  }
  imprime(&p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <inserePrimeiro@plt>
  cmp    $0xa,%ebx
  jne    L2
  mov    %rbp,%rdi
  call   <imprime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i = 0;
  struct nodo *p = NULL;
  for (i = 0; i < 10; i++) {
    inserePrimeiro(&p, i);
  }
  imprime(&p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <inserePrimeiro@plt>
  cmp    $0xa,%ebx
  jne    L5
  mov    %rbp,%rdi
  call   <imprime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i = 0;
  struct nodo *p = NULL;
  for (i = 0; i < 10; i++) {
    inserePrimeiro(&p, i);
  }
  imprime(&p);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  mov    %al,-0x1(%rbp)
  jmp    L18
L13:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x1,%eax
  xor    %al,-0x1(%rbp)
  subl   $0x1,-0x1c(%rbp)
L18:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L13
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char parity(char *buffer, int length, char start) {
  char result = start;
  for (; length > 0; length--) {
    result ^= (*buffer++ & 1);
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parity>:
  endbr64
  mov    %edx,%eax
  test   %esi,%esi
  jle    L7
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rdx
L3:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%ecx
  and    $0x1,%ecx
  xor    %ecx,%eax
  cmp    %rdx,%rdi
  jne    L3
L7:
  ret
```

assistant: ```c
char parity(char *buffer, int length, char start) {
  char result = start;
  for (; length > 0; length--) {
    result ^= (*buffer++ & 1);
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parity>:
  endbr64
  mov    %edx,%eax
  test   %esi,%esi
  jle    L8
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rdx
  nopl   0x0(%rax)
L5:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  and    $0x1,%ecx
  xor    %ecx,%eax
  cmp    %rdx,%rdi
  jne    L5
L8:
  ret
```

assistant: ```c
char parity(char *buffer, int length, char start) {
  char result = start;
  for (; length > 0; length--) {
    result ^= (*buffer++ & 1);
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <nhapchuoi@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  nhapchuoi();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nhapchuoi@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  nhapchuoi();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nhapchuoi@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  nhapchuoi();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nhapchuoi@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  nhapchuoi();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sort_strings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %esi,-0x42c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x418(%rbp)
  jmp    L54
L31:
  movl   $0x1,-0x414(%rbp)
  jmp    L4
L27:
  mov    -0x414(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x414(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x428(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L12
  mov    -0x414(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x414(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x414(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x428(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x414(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x410(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L12:
  addl   $0x1,-0x414(%rbp)
L4:
  mov    -0x414(%rbp),%eax
  cmp    -0x42c(%rbp),%eax
  jl     L27
  addl   $0x1,-0x418(%rbp)
L54:
  mov    -0x418(%rbp),%eax
  cmp    -0x42c(%rbp),%eax
  jl     L31
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void sort_strings(char *strings[], int c) {
  int i, j;
  char t[1024];
  for (i = 1; i < c; i++) {
    for (j = 1; j < c; j++) {
      if (strcmp(strings[j - 1], strings[j]) > 0) {
        strcpy(t, strings[j - 1]);
        strcpy(strings[j - 1], strings[j]);
        strcpy(strings[j], t);
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sort_strings>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L66
  mov    %rdi,%r15
  mov    %esi,%r14d
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
  mov    $0x1,%r13d
  mov    %rsp,%r12
  jmp    L71
L75:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L1
L52:
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L75
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  jmp    L75
L1:
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  je     L66
L71:
  mov    %r15,%rbx
  jmp    L52
L66:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sort_strings(char *strings[], int c) {
  int i, j;
  char t[1024];
  for (i = 1; i < c; i++) {
    for (j = 1; j < c; j++) {
      if (strcmp(strings[j - 1], strings[j]) > 0) {
        strcpy(t, strings[j - 1]);
        strcpy(strings[j - 1], strings[j]);
        strcpy(strings[j], t);
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sort_strings>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L3
  lea    -0x2(%rsi),%eax
  mov    %rdi,%r15
  mov    %esi,%r14d
  mov    $0x1,%r13d
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rsp,%r12
  nopl   0x0(%rax)
L15:
  mov    %r15,%rbx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L48
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
L48:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L16
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  jne    L15
L3:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sort_strings(char *strings[], int c) {
  int i, j;
  char t[1024];
  for (i = 1; i < c; i++) {
    for (j = 1; j < c; j++) {
      if (strcmp(strings[j - 1], strings[j]) > 0) {
        strcpy(t, strings[j - 1]);
        strcpy(strings[j - 1], strings[j]);
        strcpy(strings[j], t);
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort_strings>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L39
  lea    -0x2(%rsi),%eax
  mov    %rdi,%r15
  mov    %esi,%r14d
  mov    $0x1,%r13d
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rsp,%r12
  nopl   0x0(%rax)
L15:
  mov    %r15,%rbx
  nopl   0x0(%rax,%rax,1)
L35:
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L30
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
L30:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L35
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  jne    L15
L39:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sort_strings(char *strings[], int c) {
  int i, j;
  char t[1024];
  for (i = 1; i < c; i++) {
    for (j = 1; j < c; j++) {
      if (strcmp(strings[j - 1], strings[j]) > 0) {
        strcpy(t, strings[j - 1]);
        strcpy(strings[j - 1], strings[j]);
        strcpy(strings[j], t);
      }
    }
  }
}
```