ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<hex2dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L1
L18:
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x1c(%rbp,%rax,1),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
  addl   $0x1,-0x38(%rbp)
L1:
  cmpl   $0x6,-0x38(%rbp)
  jle    L18
  movb   $0x0,-0xc(%rbp)
  lea    -0x12(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0xff,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  sar    $0x8,%rax
  and    $0xff,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  sar    $0x10,%rax
  and    $0xff,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string

tool: D3: %s

tool: D18: rgb(%d, %d, %d)

assistant: ```c
void hex2dec() {
  int i, r, g, b;
  char s[10], s1[10];
  long int col;
  scanf("%s", s);
  for (i = 0; i < 7; i++) {
    s1[i] = s[i + 1];
  }
  s1[6] = '\0';
  col = strtol(s1, NULL, 16);
  b = col & 0xff;
  g = (col >> 8) & 0xff;
  r = (col >> 16) & 0xff;
  printf("rgb(%d, %d, %d)", r, g, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hex2dec>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%eax
  lea    0xd(%rsp),%rcx
L0:
  movzbl 0x4(%rsp,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L0
  movb   $0x0,0x14(%rsp)
  lea    0xe(%rsp),%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  movzbl %al,%ecx
  movzbl %ah,%edx
  sar    $0x10,%rax
  movzbl %al,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D16: %s

tool: D19: rgb(%d, %d, %d)

assistant: ```c
void hex2dec() {
  int i, r, g, b;
  char s[10], s1[10];
  long int col;
  scanf("%s", s);
  for (i = 0; i < 7; i++) {
    s1[i] = s[i + 1];
  }
  s1[6] = '\0';
  col = strtol(s1, NULL, 16);
  b = col & 0xff;
  g = (col >> 8) & 0xff;
  r = (col >> 16) & 0xff;
  printf("rgb(%d, %d, %d)", r, g, b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2dec>:
  endbr64
  sub    $0x28,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x5(%rsp),%eax
  xor    %esi,%esi
  lea    0xe(%rsp),%rdi
  mov    $0x10,%edx
  movb   $0x0,0x14(%rsp)
  mov    %eax,0xe(%rsp)
  movzwl 0x9(%rsp),%eax
  mov    %ax,0x12(%rsp)
  call   <strtol@plt>
  lea    D11(%rip),%rdi
  movzbl %al,%ecx
  movzbl %ah,%edx
  sar    $0x10,%rax
  movzbl %al,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D11
datatype: string

tool: D15: %s

tool: D11: rgb(%d, %d, %d)

assistant: ```c
void hex2dec() {
  int i, r, g, b;
  char s[10], s1[10];
  long int col;
  scanf("%s", s);
  for (i = 0; i < 7; i++) {
    s1[i] = s[i + 1];
  }
  s1[6] = '\0';
  col = strtol(s1, NULL, 16);
  b = col & 0xff;
  g = (col >> 8) & 0xff;
  r = (col >> 16) & 0xff;
  printf("rgb(%d, %d, %d)", r, g, b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hex2dec>:
  endbr64
  sub    $0x28,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x5(%rsp),%eax
  xor    %esi,%esi
  lea    0xe(%rsp),%rdi
  mov    $0x10,%edx
  movb   $0x0,0x14(%rsp)
  mov    %eax,0xe(%rsp)
  movzwl 0x9(%rsp),%eax
  mov    %ax,0x12(%rsp)
  call   <strtol@plt>
  lea    D3(%rip),%rdi
  movzbl %al,%ecx
  movzbl %ah,%edx
  sar    $0x10,%rax
  movzbl %al,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_guessed: string
name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D10: %s

tool: D3: rgb(%d, %d, %d)

assistant: ```c
void hex2dec() {
  int i, r, g, b;
  char s[10], s1[10];
  long int col;
  scanf("%s", s);
  for (i = 0; i < 7; i++) {
    s1[i] = s[i + 1];
  }
  s1[6] = '\0';
  col = strtol(s1, NULL, 16);
  b = col & 0xff;
  g = (col >> 8) & 0xff;
  r = (col >> 16) & 0xff;
  printf("rgb(%d, %d, %d)", r, g, b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x7,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cmp    $0x7,%eax
  ja     L0
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D3(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D3(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L15:
  nop
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L15
L0:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cp(char *to, char *from, int count) {
  int n = (count + 7) / 8;
  switch (count % 8) {
  case 0:
    do {
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
    } while (--n > 0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cp>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  lea    0xe(%rdx),%esi
  mov    %edx,%edi
  add    $0x7,%edi
  cmovns %edi,%esi
  sar    $0x3,%esi
  mov    %edx,%edi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  add    %edi,%edx
  and    $0x7,%edx
  sub    %edi,%edx
  cmp    $0x7,%edx
  ja     L32
  mov    %edx,%edx
  lea    D4(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
L13:
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  lea    0x1(%rcx),%rcx
  lea    0x1(%rax),%rax
  lea    0x1(%rcx),%rdi
  lea    0x1(%rax),%rdx
  movzbl (%rcx),%ecx
  mov    %cl,(%rax)
L50:
  lea    0x1(%rdi),%rcx
  lea    0x1(%rdx),%rax
  movzbl (%rdi),%edi
  mov    %dil,(%rdx)
  lea    0x1(%rcx),%rdi
  lea    0x1(%rax),%rdx
  movzbl (%rcx),%ecx
  mov    %cl,(%rax)
L46:
  lea    0x1(%rdi),%rcx
  lea    0x1(%rdx),%rax
  movzbl (%rdi),%edi
  mov    %dil,(%rdx)
  lea    0x1(%rcx),%rdi
  lea    0x1(%rax),%rdx
  movzbl (%rcx),%ecx
  mov    %cl,(%rax)
L39:
  movzbl (%rdi),%eax
  mov    %al,(%rdx)
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L32
  lea    0x1(%rdi),%rcx
  lea    0x1(%rdx),%rax
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  lea    0x1(%rcx),%rcx
  lea    0x1(%rax),%rax
  jmp    L13
  mov    %rcx,%rdi
  mov    %rax,%rdx
  jmp    L50
  mov    %rcx,%rdi
  mov    %rax,%rdx
  jmp    L46
  mov    %rcx,%rdi
  mov    %rax,%rdx
  jmp    L39
L32:
  ret
```

assistant: ```c
void cp(char *to, char *from, int count) {
  int n = (count + 7) / 8;
  switch (count % 8) {
  case 0:
    do {
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
    } while (--n > 0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cp>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%edi
  mov    %rsi,%rcx
  add    $0x7,%edi
  lea    0xe(%rdx),%esi
  cmovns %edi,%esi
  mov    %edx,%edi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  sar    $0x3,%esi
  add    %edi,%edx
  and    $0x7,%edx
  sub    %edi,%edx
  cmp    $0x7,%edx
  ja     L7
  lea    D0(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
L35:
  lea    0x1(%rcx),%rdi
  movzbl (%rcx),%ecx
  lea    0x1(%rax),%rdx
  mov    %cl,(%rax)
L25:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  lea    0x1(%rcx),%r9
  lea    0x1(%rax),%r8
  mov    %dl,(%rax)
L55:
  movzbl (%r9),%eax
  lea    0x1(%r9),%rdi
  lea    0x1(%r8),%rdx
  mov    %al,(%r8)
L48:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  sub    $0x1,%esi
  mov    %dl,(%rax)
  test   %esi,%esi
  jle    L7
  add    $0x1,%rcx
  add    $0x1,%rax
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  mov    %dl,(%rax)
  add    $0x1,%rax
  jmp    L35
  nopl   0x0(%rax)
L7:
  ret
  nopl   0x0(%rax)
  mov    %rcx,%rdi
  mov    %rax,%rdx
  jmp    L25
  mov    %rcx,%rdi
  mov    %rax,%rdx
  jmp    L48
  nopl   0x0(%rax,%rax,1)
  mov    %rcx,%r9
  mov    %rax,%r8
  jmp    L55
```

assistant: ```c
void cp(char *to, char *from, int count) {
  int n = (count + 7) / 8;
  switch (count % 8) {
  case 0:
    do {
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
    } while (--n > 0);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cp>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%edi
  mov    %rsi,%rcx
  add    $0x7,%edi
  lea    0xe(%rdx),%esi
  cmovns %edi,%esi
  mov    %edx,%edi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  sar    $0x3,%esi
  add    %edi,%edx
  and    $0x7,%edx
  sub    %edi,%edx
  cmp    $0x7,%edx
  ja     L51
  lea    D8(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
L55:
  lea    0x1(%rcx),%rdi
  movzbl (%rcx),%ecx
  lea    0x1(%rax),%rdx
  mov    %cl,(%rax)
L30:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  lea    0x1(%rcx),%r9
  lea    0x1(%rax),%r8
  mov    %dl,(%rax)
L14:
  movzbl (%r9),%eax
  lea    0x1(%r9),%rdi
  lea    0x1(%r8),%rdx
  mov    %al,(%r8)
L7:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  sub    $0x1,%esi
  mov    %dl,(%rax)
  test   %esi,%esi
  jle    L51
  add    $0x1,%rcx
  add    $0x1,%rax
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  mov    %dl,(%rax)
  add    $0x1,%rax
  jmp    L55
  nopl   0x0(%rax)
L51:
  ret
  nopl   0x0(%rax)
  mov    %rcx,%rdi
  mov    %rax,%rdx
  jmp    L30
  mov    %rcx,%rdi
  mov    %rax,%rdx
  jmp    L7
  nopl   0x0(%rax,%rax,1)
  mov    %rcx,%r9
  mov    %rax,%r8
  jmp    L14
```

assistant: ```c
void cp(char *to, char *from, int count) {
  int n = (count + 7) / 8;
  switch (count % 8) {
  case 0:
    do {
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
    } while (--n > 0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L6:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <f@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x4,-0x8(%rbp)
  jle    L6
  cmpl   $0x19,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i, x = 0;
  for (i = 0; i < 5; ++i) {
    x += f(i) + i;
  }
#pragma omp taskwait
  assert(x == 25);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L2:
  mov    %ebx,%edi
  call   <f@plt>
  add    %rbx,%rax
  add    %eax,%ebp
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L2
  cmp    $0x19,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, x = 0;
  for (i = 0; i < 5; ++i) {
    x += f(i) + i;
  }
#pragma omp taskwait
  assert(x == 25);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L2:
  mov    %ebx,%edi
  call   <f@plt>
  add    %rbx,%rax
  add    $0x1,%rbx
  add    %eax,%ebp
  cmp    $0x5,%rbx
  jne    L2
  xor    %edi,%edi
  cmp    $0x19,%ebp
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, x = 0;
  for (i = 0; i < 5; ++i) {
    x += f(i) + i;
  }
#pragma omp taskwait
  assert(x == 25);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L9:
  mov    %ebx,%edi
  call   <f@plt>
  add    %rbx,%rax
  add    $0x1,%rbx
  add    %eax,%ebp
  cmp    $0x5,%rbx
  jne    L9
  xor    %edi,%edi
  cmp    $0x19,%ebp
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, x = 0;
  for (i = 0; i < 5; ++i) {
    x += f(i) + i;
  }
#pragma omp taskwait
  assert(x == 25);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L12
L32:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L10
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  cmpq   $0x0,-0x18(%rbp)
  jne    L32
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while (*s1 == *s2 && *s1 != '\0' && n > 0) {
    s1++;
    s2++;
    n--;
  }
  return (*s1 - *s2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strncmp>:
  endbr64
  mov    %rdi,%r10
  movzbl (%rdi),%eax
  movzbl (%rsi),%r8d
  test   %al,%al
  setne  %dil
  cmp    %r8b,%al
  sete   %cl
  test   %cl,%dil
  je     L13
  test   %rdx,%rdx
  je     L13
  mov    $0x1,%ecx
L14:
  movzbl (%r10,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  test   %al,%al
  setne  %dil
  cmp    %r8b,%al
  sete   %r9b
  and    %r9d,%edi
  cmp    %rdx,%rcx
  setne  %r9b
  add    $0x1,%rcx
  test   %r9b,%dil
  jne    L14
L13:
  movsbl %al,%eax
  movsbl %r8b,%r8d
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while (*s1 == *s2 && *s1 != '\0' && n > 0) {
    s1++;
    s2++;
    n--;
  }
  return (*s1 - *s2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%r8d
  add    $0x1,%rdx
  mov    $0x1,%ecx
  cmp    %al,%r8b
  je     L18
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L44:
  cmp    %rcx,%rdx
  je     L20
  movsbl (%rdi,%rcx,1),%eax
  add    $0x1,%rcx
  movsbl -0x1(%rsi,%rcx,1),%r8d
  cmp    %r8b,%al
  jne    L20
L18:
  test   %al,%al
  jne    L44
  xor    %eax,%eax
L20:
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while (*s1 == *s2 && *s1 != '\0' && n > 0) {
    s1++;
    s2++;
    n--;
  }
  return (*s1 - *s2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%r8d
  add    $0x1,%rdx
  mov    $0x1,%ecx
  cmp    %al,%r8b
  je     L47
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L45:
  cmp    %rcx,%rdx
  je     L39
  movsbl (%rdi,%rcx,1),%eax
  add    $0x1,%rcx
  movsbl -0x1(%rsi,%rcx,1),%r8d
  cmp    %r8b,%al
  jne    L39
L47:
  test   %al,%al
  jne    L45
  xor    %eax,%eax
L39:
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while (*s1 == *s2 && *s1 != '\0' && n > 0) {
    s1++;
    s2++;
    n--;
  }
  return (*s1 - *s2);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <repeticiones@plt>
  mov    %eax,%esi
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <repeticiones@plt>
  mov    %eax,%esi
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x2,-0x8(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <repeticiones@plt>
  mov    %eax,%esi
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x3,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  movl   $0x3,-0x4(%rbp)
  movl   $0x3,-0x8(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <repeticiones@plt>
  mov    %eax,%esi
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D5: El numero de numeros iguales en(%d,%d,%d,%d)==%d


assistant: ```c
int main() {
  int a, b, c, d;
  a = 1;
  b = 2;
  c = 3;
  d = 4;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  d = 1;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  c = 2;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  a = 3;
  b = 3;
  d = 3;
  c = 3;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <repeticiones@plt>
  mov    %eax,%r9d
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <repeticiones@plt>
  mov    %eax,%r9d
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <repeticiones@plt>
  mov    %eax,%r9d
  mov    $0x1,%r8d
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <repeticiones@plt>
  mov    %eax,%r9d
  mov    $0x3,%r8d
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D0: El numero de numeros iguales en(%d,%d,%d,%d)==%d


assistant: ```c
int main() {
  int a, b, c, d;
  a = 1;
  b = 2;
  c = 3;
  d = 4;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  d = 1;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  c = 2;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  a = 3;
  b = 3;
  d = 3;
  c = 3;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  return 0;
}
```