ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: usage: i2p-ping [-amqv?] [-c count] [-h samhost] [-p samport] <b64dest|name>
	[b64dest|name] [b64dest|name] ...

assistant: ```c
void usage() {
  puts("usage: i2p-ping [-amqv?] [-c count] [-h samhost] [-p samport] "
       "<b64dest|name>\n\t[b64dest|name] [b64dest|name] ...");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string

tool: D5: usage: i2p-ping [-amqv?] [-c count] [-h samhost] [-p samport] <b64dest|name>
	[b64dest|name] [b64dest|name] ...

assistant: ```c
void usage() {
  puts("usage: i2p-ping [-amqv?] [-c count] [-h samhost] [-p samport] "
       "<b64dest|name>\n\t[b64dest|name] [b64dest|name] ...");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: usage: i2p-ping [-amqv?] [-c count] [-h samhost] [-p samport] <b64dest|name>
	[b64dest|name] [b64dest|name] ...

assistant: ```c
void usage() {
  puts("usage: i2p-ping [-amqv?] [-c count] [-h samhost] [-p samport] "
       "<b64dest|name>\n\t[b64dest|name] [b64dest|name] ...");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: usage: i2p-ping [-amqv?] [-c count] [-h samhost] [-p samport] <b64dest|name>
	[b64dest|name] [b64dest|name] ...

assistant: ```c
void usage() {
  puts("usage: i2p-ping [-amqv?] [-c count] [-h samhost] [-p samport] "
       "<b64dest|name>\n\t[b64dest|name] [b64dest|name] ...");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<abspath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L16
  mov    -0x8(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L9
L16:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: D3: /

assistant: ```c
void abspath(char *path, char *rel) {
  if (rel[0] != '/') {
    getcwd(path, 1024);
    strcat(path, "/");
    strcat(path, rel);
  } else {
    strcpy(path, rel);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<abspath>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x2f,(%rsi)
  je     L10
  mov    $0x400,%esi
  call   <getcwd@plt>
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <strcpy@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string

tool: D1: /

assistant: ```c
void abspath(char *path, char *rel) {
  if (rel[0] != '/') {
    getcwd(path, 1024);
    strcat(path, "/");
    strcat(path, rel);
  } else {
    strcpy(path, rel);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abspath>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmpb   $0x2f,(%rsi)
  je     L1
  mov    $0x400,%esi
  call   <getcwd@plt>
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <strcat@plt>
  nopl   0x0(%rax)
L1:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1070 <strcpy@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: /

assistant: ```c
void abspath(char *path, char *rel) {
  if (rel[0] != '/') {
    getcwd(path, 1024);
    strcat(path, "/");
    strcat(path, rel);
  } else {
    strcpy(path, rel);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<abspath>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmpb   $0x2f,(%rsi)
  je     L4
  mov    $0x400,%esi
  call   <getcwd@plt>
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <strcat@plt>
  nopl   0x0(%rax)
L4:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1070 <strcpy@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D7: /

assistant: ```c
void abspath(char *path, char *rel) {
  if (rel[0] != '/') {
    getcwd(path, 1024);
    strcat(path, "/");
    strcat(path, rel);
  } else {
    strcpy(path, rel);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x24(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x20(%rbp)
  lea    -0x24(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
type_infered: string
name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D29
type_infered: string

tool: D11: asldfkaslfdkjasl

tool: D16: testval

tool: D29: i = %d    j = %d


assistant: ```c
int main(void) {
  char *file1name = "asldfkaslfdkjasl";
  char *file2name = "testval";
  struct dirent *file1, *file2;
  struct stat status_buffer;
  int i = stat(file1name, &status_buffer);
  int j = stat(file2name, &status_buffer);
  printf("i = %d    j = %d\n", i, j);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <stat@plt>
  mov    %eax,%ebx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <stat@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string
name: disassemble_data
arguments: label: D0
type_infered: string
name: disassemble_data
arguments: label: D25
type_infered: string

tool: D4: asldfkaslfdkjasl

tool: D0: testval

tool: D25: i = %d    j = %d


assistant: ```c
int main(void) {
  char *file1name = "asldfkaslfdkjasl";
  char *file2name = "testval";
  struct dirent *file1, *file2;
  struct stat status_buffer;
  int i = stat(file1name, &status_buffer);
  int j = stat(file2name, &status_buffer);
  printf("i = %d    j = %d\n", i, j);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <stat@plt>
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  mov    %eax,%ebp
  call   <stat@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D5
type_guessed: string
name: read_data
arguments: label: D0
type_guessed: string

tool: D16: asldfkaslfdkjasl

tool: D5: testval

tool: D0: i = %d    j = %d


assistant: ```c
int main(void) {
  char *file1name = "asldfkaslfdkjasl";
  char *file2name = "testval";
  struct dirent *file1, *file2;
  struct stat status_buffer;
  int i = stat(file1name, &status_buffer);
  int j = stat(file2name, &status_buffer);
  printf("i = %d    j = %d\n", i, j);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D21(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <stat@plt>
  mov    %r12,%rsi
  lea    D17(%rip),%rdi
  mov    %eax,%ebp
  call   <stat@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D21
type_infered: string
name: parse_data
arguments: tag: D17
type_infered: string
name: parse_data
arguments: tag: D0
type_infered: string

tool: D21: asldfkaslfdkjasl

tool: D17: testval

tool: D0: i = %d    j = %d


assistant: ```c
int main(void) {
  char *file1name = "asldfkaslfdkjasl";
  char *file2name = "testval";
  struct dirent *file1, *file2;
  struct stat status_buffer;
  int i = stat(file1name, &status_buffer);
  int j = stat(file2name, &status_buffer);
  printf("i = %d    j = %d\n", i, j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<merge>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    %ecx,%r9d
  cmp    %ecx,%edx
  jge    L125
  cmp    %r8d,%ecx
  jg     L125
  lea    0x1(%rdx),%r11d
  movslq %edx,%rax
  lea    (%rsi,%rax,4),%rcx
  mov    %r9d,%eax
  mov    %edx,%esi
  mov    $0x0,%ebp
  jmp    L15
L129:
  add    $0x1,%eax
  mov    %r11d,%r13d
  mov    %ebx,(%rcx)
  mov    %r9d,%ebx
  sub    %esi,%ebx
  add    %ebx,%ebp
L98:
  add    $0x1,%r11d
  add    $0x4,%rcx
  cmp    %r9d,%esi
  jge    L102
  cmp    %r8d,%eax
  jg     L102
L15:
  movslq %esi,%rbx
  mov    (%rdi,%rbx,4),%r12d
  movslq %eax,%rbx
  mov    (%rdi,%rbx,4),%ebx
  cmp    %ebx,%r12d
  jg     L129
  add    $0x1,%esi
  mov    %r11d,%r13d
  mov    %r12d,(%rcx)
  jmp    L98
L125:
  mov    %edx,%r13d
  mov    %r9d,%eax
  mov    %edx,%esi
  mov    $0x0,%ebp
L102:
  cmp    %esi,%r9d
  jle    L12
  movslq %esi,%rcx
  movslq %r13d,%r11
  sub    %rcx,%r11
  lea    (%r10,%r11,4),%rbx
L26:
  mov    (%rdi,%rcx,4),%r11d
  mov    %r11d,(%rbx,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,%r9d
  jg     L26
  add    %r13d,%r9d
  sub    %esi,%r9d
  mov    %r9d,%r13d
L12:
  cmp    %eax,%r8d
  jl     L29
  cltq
  movslq %r13d,%r13
  sub    %rax,%r13
  lea    (%r10,%r13,4),%rsi
L34:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L34
L29:
  cmp    %r8d,%edx
  jg     L56
  movslq %edx,%rax
L96:
  mov    (%r10,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L96
L56:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int merge(int arr[], int temp[], int left, int mid, int right) {
  int i, j, k;
  int inv_count = 0;
  i = left;
  j = mid;
  k = left;
  while ((i <= mid - 1) && (j <= right)) {
    if (arr[i] <= arr[j]) {
      temp[k++] = arr[i++];
    } else {
      temp[k++] = arr[j++];
      inv_count = inv_count + (mid - i);
    }
  }
  while (i <= mid - 1)
    temp[k++] = arr[i++];
  while (j <= right)
    temp[k++] = arr[j++];
  for (i = left; i <= right; i++)
    arr[i] = temp[i];
  return inv_count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<merge>:
  endbr64
  push   %r12
  mov    %rsi,%r10
  mov    %edx,%r11d
  mov    %ecx,%esi
  push   %rbp
  push   %rbx
  cmp    %ecx,%edx
  jge    L25
  cmp    %r8d,%ecx
  jg     L25
  lea    0x1(%rdx),%edx
  mov    %ecx,%eax
  xor    %r12d,%r12d
  mov    %r11d,%ecx
  movslq %edx,%rdx
  jmp    L36
  nopl   0x0(%rax)
L136:
  add    $0x1,%ecx
  mov    %r9d,-0x4(%r10,%rdx,4)
  add    $0x1,%rdx
  cmp    %esi,%ecx
  jge    L13
L112:
  cmp    %r8d,%eax
  jg     L13
L36:
  movslq %ecx,%r9
  movslq %eax,%rbx
  movslq %edx,%rbp
  mov    (%rdi,%r9,4),%r9d
  mov    (%rdi,%rbx,4),%ebx
  cmp    %ebx,%r9d
  jle    L136
  mov    %esi,%r9d
  add    $0x1,%eax
  sub    %ecx,%r9d
  add    %r9d,%r12d
  mov    %ebx,%r9d
  mov    %r9d,-0x4(%r10,%rdx,4)
  add    $0x1,%rdx
  cmp    %esi,%ecx
  jl     L112
L13:
  cmp    %ecx,%esi
  jle    L4
  movslq %ecx,%rdx
  movslq %ebp,%r9
  sub    %rdx,%r9
  lea    (%r10,%r9,4),%rbx
  nop
L85:
  mov    (%rdi,%rdx,4),%r9d
  mov    %r9d,(%rbx,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L85
  add    %ebp,%esi
  sub    %ecx,%esi
  movslq %esi,%rbp
L4:
  cmp    %eax,%r8d
  jl     L27
  cltq
  sub    %rax,%rbp
  lea    (%r10,%rbp,4),%rcx
  nopl   (%rax)
L126:
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L126
L27:
  movslq %r11d,%rax
  cmp    %r8d,%r11d
  jg     L128
  nop
L86:
  mov    (%r10,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L86
L128:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  movslq %r11d,%rbp
  mov    %esi,%eax
  mov    %r11d,%ecx
  xor    %r12d,%r12d
  jmp    L13
```

assistant: ```c
int merge(int arr[], int temp[], int left, int mid, int right) {
  int i, j, k;
  int inv_count = 0;
  i = left;
  j = mid;
  k = left;
  while ((i <= mid - 1) && (j <= right)) {
    if (arr[i] <= arr[j]) {
      temp[k++] = arr[i++];
    } else {
      temp[k++] = arr[j++];
      inv_count = inv_count + (mid - i);
    }
  }
  while (i <= mid - 1)
    temp[k++] = arr[i++];
  while (j <= right)
    temp[k++] = arr[j++];
  for (i = left; i <= right; i++)
    arr[i] = temp[i];
  return inv_count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<roll_dice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L1
L5:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <random_range@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L5
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int roll_dice(int amount, int size) {
  int i;
  int result = 0;
  for (i = 1; i <= amount; i++) {
    result += random_range(1, size);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<roll_dice>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L14
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    $0x0,%ebp
  mov    $0x1,%ebx
L25:
  mov    %r13d,%esi
  mov    $0x1,%edi
  call   <random_range@plt>
  add    %eax,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L25
L18:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    $0x0,%ebp
  jmp    L18
```

assistant: ```c
int roll_dice(int amount, int size) {
  int i;
  int result = 0;
  for (i = 1; i <= amount; i++) {
    result += random_range(1, size);
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<roll_dice>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L4
  mov    %edi,%ebp
  mov    %esi,%r13d
  xor    %r12d,%r12d
  mov    $0x1,%ebx
  nop
L16:
  mov    %r13d,%esi
  mov    $0x1,%edi
  add    $0x1,%ebx
  call   <random_range@plt>
  add    %eax,%r12d
  cmp    %ebx,%ebp
  jge    L16
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int roll_dice(int amount, int size) {
  int i;
  int result = 0;
  for (i = 1; i <= amount; i++) {
    result += random_range(1, size);
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<roll_dice>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L10
  mov    %edi,%ebp
  mov    %esi,%r13d
  xor    %r12d,%r12d
  mov    $0x1,%ebx
  nop
L12:
  mov    %r13d,%esi
  mov    $0x1,%edi
  add    $0x1,%ebx
  call   <random_range@plt>
  add    %eax,%r12d
  cmp    %ebx,%ebp
  jge    L12
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L10:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int roll_dice(int amount, int size) {
  int i;
  int result = 0;
  for (i = 1; i <= amount; i++) {
    result += random_range(1, size);
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<bincoeff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L12
L7:
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sub    %edx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L7
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: bincoeff(%d) = %ld


assistant: ```c
void bincoeff(int k) {
  const int n = 2 * k;
  long ret = 1;
  for (int i = 1; i < k + 1; ++i) {
    ret *= n - (k - i);
    ret /= i;
  }
  printf("bincoeff(%d) = %ld\n", k, ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bincoeff>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  test   %edi,%edi
  jle    L4
  lea    (%rdi,%rdi,1),%r8d
  lea    0x1(%rdi),%r9d
  mov    $0x1,%ecx
  mov    $0x1,%eax
  movslq %r8d,%r8
  movslq %edi,%rdx
  sub    %rdx,%r8
L16:
  lea    (%r8,%rcx,1),%rdx
  imul   %rdx,%rax
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L16
L28:
  mov    %rax,%rdx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L4:
  mov    $0x1,%eax
  jmp    L28
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: bincoeff(%d) = %ld


assistant: ```c
void bincoeff(int k) {
  const int n = 2 * k;
  long ret = 1;
  for (int i = 1; i < k + 1; ++i) {
    ret *= n - (k - i);
    ret /= i;
  }
  printf("bincoeff(%d) = %ld\n", k, ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bincoeff>:
  endbr64
  mov    %edi,%esi
  lea    (%rdi,%rdi,1),%r8d
  test   %edi,%edi
  jle    L12
  movslq %r8d,%r8
  movslq %edi,%rdx
  lea    0x1(%rdi),%r9d
  mov    $0x1,%ecx
  mov    $0x1,%eax
  sub    %rdx,%r8
  nopl   (%rax)
L15:
  lea    (%r8,%rcx,1),%rdx
  imul   %rdx,%rax
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L15
  mov    %rax,%rdx
  lea    D16(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L12:
  mov    $0x1,%eax
  lea    D16(%rip),%rdi
  mov    %rax,%rdx
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D16: bincoeff(%d) = %ld


assistant: ```c
void bincoeff(int k) {
  const int n = 2 * k;
  long ret = 1;
  for (int i = 1; i < k + 1; ++i) {
    ret *= n - (k - i);
    ret /= i;
  }
  printf("bincoeff(%d) = %ld\n", k, ret);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bincoeff>:
  endbr64
  mov    %edi,%esi
  lea    (%rdi,%rdi,1),%r8d
  test   %edi,%edi
  jle    L18
  movslq %r8d,%r8
  movslq %edi,%rdx
  lea    0x1(%rdi),%r9d
  mov    $0x1,%ecx
  mov    $0x1,%eax
  sub    %rdx,%r8
  nopl   (%rax)
L1:
  lea    (%r8,%rcx,1),%rdx
  imul   %rdx,%rax
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L1
  mov    %rax,%rdx
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L18:
  mov    $0x1,%eax
  lea    D4(%rip),%rdi
  mov    %rax,%rdx
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: bincoeff(%d) = %ld


assistant: ```c
void bincoeff(int k) {
  const int n = 2 * k;
  long ret = 1;
  for (int i = 1; i < k + 1; ++i) {
    ret *= n - (k - i);
    ret /= i;
  }
  printf("bincoeff(%d) = %ld\n", k, ret);
}
```