user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D48(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L144
  mov    $0x1,%ebx
  lea    D45(%rip),%r14
  mov    %rsp,%r13
  lea    D36(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  movdqa D6(%rip),%xmm3
  test   %esi,%esi
  jle    L165
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  jbe    L13
  mov    %esi,%edx
  movdqa D49(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  nopl   (%rax)
L4:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L4
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  lea    0x1(%rcx),%eax
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%edx
  cmp    %ecx,%esi
  je     L35
L12:
  lea    0x1(%rax),%ecx
  add    %eax,%edx
  cmp    %esi,%ecx
  jg     L35
  add    %ecx,%edx
  lea    0x2(%rax),%ecx
  cmp    %ecx,%esi
  jl     L35
  add    %ecx,%edx
  lea    0x3(%rax),%ecx
  cmp    %ecx,%esi
  jl     L35
  add    %ecx,%edx
  lea    0x4(%rax),%ecx
  cmp    %ecx,%esi
  jl     L35
  add    %ecx,%edx
  lea    0x5(%rax),%ecx
  cmp    %ecx,%esi
  jl     L35
  add    %ecx,%edx
  lea    0x6(%rax),%ecx
  cmp    %ecx,%esi
  jl     L35
  add    %ecx,%edx
  lea    0x7(%rax),%ecx
  cmp    %ecx,%esi
  jl     L35
  add    %ecx,%edx
  lea    0x8(%rax),%ecx
  cmp    %ecx,%esi
  jl     L35
  add    %ecx,%edx
  add    $0x9,%eax
  lea    (%rdx,%rax,1),%ecx
  cmp    %eax,%esi
  cmovge %ecx,%edx
L35:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L41
L144:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L165:
  xor    %edx,%edx
  jmp    L35
L13:
  xor    %edx,%edx
  mov    $0x1,%eax
  jmp    L12
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D48
datatype: string
name: parse_data
arguments: label: D28
datatype: string
name: parse_data
arguments: label: D45
datatype: string
name: parse_data
arguments: label: D36
datatype: string
name: parse_data
arguments: label: D6
datatype: byte[16]
name: parse_data
arguments: label: D49
datatype: byte[16]

tool: D48: Enter the number of triangular number you need: 

tool: D28: %i

tool: D45: What triangular number do you want?

tool: D36: Triangular number %i is %i


tool: {"D6": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D49": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int n, number, tri_num, count, counter;
  printf("Enter the number of triangular number you need: ");
  scanf("%i", &count);
  for (counter = 1; counter <= count; ++counter) {
    printf("What triangular number do you want?\n");
    scanf("%i", &number);
    tri_num = 0;
    for (n = 1; n <= number; ++n) {
      tri_num += n;
    }
    printf("Triangular number %i is %i\n", number, tri_num);
  }
  return 0;
}
```