ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <echoargs@plt>
  jmp    L11
L3:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <splitargs@plt>
  addq   $0x8,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L3
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: Split "%s"


assistant: ```c
int main(int argc, char *argv[5]) {
  echoargs(argc, argv);
  for (; *argv != NULL; argv++) {
    printf("Split \"%s\"\n", *argv);
    splitargs(*argv);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  call   <echoargs@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L13
  lea    D8(%rip),%rbp
L9:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%rdi
  call   <splitargs@plt>
  add    $0x8,%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L9
L13:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D8: Split "%s"


assistant: ```c
int main(int argc, char *argv[5]) {
  echoargs(argc, argv);
  for (; *argv != NULL; argv++) {
    printf("Split \"%s\"\n", *argv);
    splitargs(*argv);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <echoargs@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L12
  lea    D3(%rip),%rbp
  nopl   0x0(%rax)
L8:
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rdi
  call   <splitargs@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L8
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: Split "%s"


assistant: ```c
int main(int argc, char *argv[5]) {
  echoargs(argc, argv);
  for (; *argv != NULL; argv++) {
    printf("Split \"%s\"\n", *argv);
    splitargs(*argv);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <echoargs@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L8
  lea    D8(%rip),%rbp
  nopl   0x0(%rax)
L13:
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rdi
  call   <splitargs@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L13
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: Split "%s"


assistant: ```c
int main(int argc, char *argv[5]) {
  echoargs(argc, argv);
  for (; *argv != NULL; argv++) {
    printf("Split \"%s\"\n", *argv);
    splitargs(*argv);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_time_ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x20(%rbp),%rax
  imul   $0x3b9aca00,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
uint64_t get_time_ns() {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000000LL + ts.tv_nsec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_time_ns>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_time_ns() {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000000LL + ts.tv_nsec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_time_ns>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_time_ns() {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000000LL + ts.tv_nsec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_time_ns>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_time_ns() {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000000LL + ts.tv_nsec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<q_memchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x1c(%rbp),%eax
  movzbl %al,%eax
  cmp    %eax,%edx
  jne    L10
  mov    -0x18(%rbp),%rax
  jmp    L15
L10:
  addq   $0x1,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L37
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
char *q_memchr(char *p, int c, unsigned int size) {
  char *end;
  end = p + size;
  for (; p < end; p++) {
    if (*p == (unsigned char)c)
      return p;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<q_memchr>:
  endbr64
  mov    %edx,%edx
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  jae    L2
  movzbl %sil,%esi
L24:
  movsbl (%rdi),%eax
  cmp    %esi,%eax
  je     L23
  add    $0x1,%rdi
  cmp    %rdi,%rdx
  jne    L24
  mov    $0x0,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
L23:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *q_memchr(char *p, int c, unsigned int size) {
  char *end;
  end = p + size;
  for (; p < end; p++) {
    if (*p == (unsigned char)c)
      return p;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<q_memchr>:
  endbr64
  mov    %edx,%edx
  mov    %rdi,%rax
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  jae    L9
  movzbl %sil,%esi
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L9
L0:
  movsbl (%rax),%ecx
  cmp    %esi,%ecx
  jne    L18
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *q_memchr(char *p, int c, unsigned int size) {
  char *end;
  end = p + size;
  for (; p < end; p++) {
    if (*p == (unsigned char)c)
      return p;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<q_memchr>:
  endbr64
  mov    %edx,%edx
  mov    %rdi,%rax
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  jae    L3
  movzbl %sil,%esi
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L3
L12:
  movsbl (%rax),%ecx
  cmp    %esi,%ecx
  jne    L5
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *q_memchr(char *p, int c, unsigned int size) {
  char *end;
  end = p + size;
  for (; p < end; p++) {
    if (*p == (unsigned char)c)
      return p;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <Pass_by_reference@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type: string
name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D26
type: string
name: retrieve_data
arguments: data_tag: D5
type: string

tool: D14: Enter three ints

tool: D10: %d%d%d

tool: D26: In main, x = %d, y = %d, z = %d



tool: D5: In main, x = %d, y = %d, z = %d


assistant: ```c
int main(void) {
  int x, y, z;
  printf("Enter three ints\n");
  scanf("%d%d%d", &x, &y, &z);
  printf("In main, x = %d, y = %d, z = %d\n\n", x, y, z);
  Pass_by_reference(&x, &y, &z);
  printf("In main, x = %d, y = %d, z = %d\n", x, y, z);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rbx
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <Pass_by_reference@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string
name: unpack_data
arguments: label: D22
type_infered: string
name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D8: Enter three ints

tool: D22: %d%d%d

tool: D18: In main, x = %d, y = %d, z = %d



tool: D0: In main, x = %d, y = %d, z = %d


assistant: ```c
int main(void) {
  int x, y, z;
  printf("Enter three ints\n");
  scanf("%d%d%d", &x, &y, &z);
  printf("In main, x = %d, y = %d, z = %d\n\n", x, y, z);
  Pass_by_reference(&x, &y, &z);
  printf("In main, x = %d, y = %d, z = %d\n", x, y, z);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    0xc(%rsp),%rbp
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0xc(%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <Pass_by_reference@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0xc(%rsp),%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D37
type_infered: string

tool: D7: Enter three ints

tool: D3: %d%d%d

tool: D11: In main, x = %d, y = %d, z = %d



tool: D37: In main, x = %d, y = %d, z = %d


assistant: ```c
int main(void) {
  int x, y, z;
  printf("Enter three ints\n");
  scanf("%d%d%d", &x, &y, &z);
  printf("In main, x = %d, y = %d, z = %d\n\n", x, y, z);
  Pass_by_reference(&x, &y, &z);
  printf("In main, x = %d, y = %d, z = %d\n", x, y, z);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D28(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    0xc(%rsp),%rbp
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0xc(%rsp),%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <Pass_by_reference@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0xc(%rsp),%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D37
type_infered: string

tool: D28: Enter three ints

tool: D12: %d%d%d

tool: D19: In main, x = %d, y = %d, z = %d



tool: D37: In main, x = %d, y = %d, z = %d


assistant: ```c
int main(void) {
  int x, y, z;
  printf("Enter three ints\n");
  scanf("%d%d%d", &x, &y, &z);
  printf("In main, x = %d, y = %d, z = %d\n\n", x, y, z);
  Pass_by_reference(&x, &y, &z);
  printf("In main, x = %d, y = %d, z = %d\n", x, y, z);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Dev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L31:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  mov    %eax,(%rdx)
  jmp    L4
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L4
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    $0xa,%edx
  mov    %edx,(%rax)
L4:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L31
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Dev(int input[], int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (input[i] % 2 == 0)
      input[i] /= 2;
    else if (input[i] % 2 == 1) {
      input[i] /= 2;
      input[i + 1] += 10;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Dev>:
  endbr64
  test   %esi,%esi
  jle    L14
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%r8
  jmp    L66
L47:
  mov    %edx,%edi
  shr    $0x1f,%edi
  lea    (%rdx,%rdi,1),%ecx
  and    $0x1,%ecx
  sub    %edi,%ecx
  cmp    $0x1,%ecx
  je     L27
L16:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L14
L66:
  mov    (%rax),%edx
  test   $0x1,%dl
  jne    L47
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  sar    %edx
  mov    %edx,(%rax)
  jmp    L16
L27:
  add    %edi,%edx
  sar    %edx
  mov    %edx,(%rax)
  addl   $0xa,0x4(%rax)
  jmp    L16
L14:
  ret
```

assistant: ```c
void Dev(int input[], int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (input[i] % 2 == 0)
      input[i] /= 2;
    else if (input[i] % 2 == 1) {
      input[i] /= 2;
      input[i + 1] += 10;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Dev>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,(%rdi)
L55:
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  je     L10
L45:
  mov    (%rdi),%eax
  test   $0x1,%al
  je     L36
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  cmp    $0x1,%edx
  jne    L55
  sar    %eax
  addl   $0xa,0x4(%rdi)
  add    $0x4,%rdi
  mov    %eax,-0x4(%rdi)
  cmp    %rsi,%rdi
  jne    L45
L10:
  ret
```

assistant: ```c
void Dev(int input[], int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (input[i] % 2 == 0)
      input[i] /= 2;
    else if (input[i] % 2 == 1) {
      input[i] /= 2;
      input[i + 1] += 10;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Dev>:
  endbr64
  test   %esi,%esi
  jle    L35
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,(%rdi)
L18:
  add    $0x4,%rdi
  cmp    %rdi,%rsi
  je     L35
L55:
  mov    (%rdi),%eax
  test   $0x1,%al
  je     L48
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  cmp    $0x1,%edx
  jne    L18
  sar    %eax
  addl   $0xa,0x4(%rdi)
  add    $0x4,%rdi
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%rsi
  jne    L55
L35:
  ret
```

assistant: ```c
void Dev(int input[], int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (input[i] % 2 == 0)
      input[i] /= 2;
    else if (input[i] % 2 == 1) {
      input[i] /= 2;
      input[i + 1] += 10;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x39,%eax
  jg     L54
  cmp    $0x30,%eax
  jge    L55
  cmp    $0x2e,%eax
  jg     L54
  cmp    $0x2d,%eax
  jge    L49
  cmp    $0xa,%eax
  je     L69
  cmp    $0x2b,%eax
  jne    L54
L49:
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L54
L55:
  call   <real>
  jmp    L54
L69:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L54:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: Accepted by method 1


assistant: ```c
void real(void) {
  switch (getchar()) {
  case '+':
  case '-':
  case '.':
    error();
    return;
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    real();
    return;
  case '\n':
    printf("Accepted by method 1\n");
    return;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<real>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x2e,%eax
  jg     L14
  cmp    $0x2c,%eax
  jg     L61
  cmp    $0xa,%eax
  je     L43
  cmp    $0x2b,%eax
  jne    L12
L61:
  mov    $0x0,%eax
  call   <error@plt>
L12:
  add    $0x8,%rsp
  ret
L14:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L12
  call   <real>
  jmp    L12
L43:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: Accepted by method 1


assistant: ```c
void real(void) {
  switch (getchar()) {
  case '+':
  case '-':
  case '.':
    error();
    return;
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    real();
    return;
  case '\n':
    printf("Accepted by method 1\n");
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<real>:
  endbr64
  sub    $0x8,%rsp
L45:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x2e,%eax
  jg     L17
  cmp    $0x2c,%eax
  jg     L27
  cmp    $0xa,%eax
  jne    L2
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
  xchg   %ax,%ax
L17:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L45
L30:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L2:
  cmp    $0x2b,%eax
  jne    L30
L27:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <error@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D9: Accepted by method 1


assistant: ```c
void real(void) {
  switch (getchar()) {
  case '+':
  case '-':
  case '.':
    error();
    return;
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    real();
    return;
  case '\n':
    printf("Accepted by method 1\n");
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<real>:
  endbr64
  sub    $0x8,%rsp
L41:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x2e,%eax
  jg     L22
  cmp    $0x2c,%eax
  jg     L49
  cmp    $0xa,%eax
  jne    L10
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
  xchg   %ax,%ax
L22:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L41
L4:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L10:
  cmp    $0x2b,%eax
  jne    L4
L49:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <error@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: Accepted by method 1


assistant: ```c
void real(void) {
  switch (getchar()) {
  case '+':
  case '-':
  case '.':
    error();
    return;
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    real();
    return;
  case '\n':
    printf("Accepted by method 1\n");
    return;
  }
}
```