ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<dotest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <game@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L2
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: D4: Error. Expected %s but got %s


assistant: ```c
void dotest(unsigned long long n, char *expr) {
  char *act = game(n);
  if (strcmp(act, expr) != 0)
    printf("Error. Expected %s but got %s\n", expr, act);
  assert(strcmp(act, expr) == 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<dotest>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <game@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L11
L3:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: Error. Expected %s but got %s


assistant: ```c
void dotest(unsigned long long n, char *expr) {
  char *act = game(n);
  if (strcmp(act, expr) != 0)
    printf("Error. Expected %s but got %s\n", expr, act);
  assert(strcmp(act, expr) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dotest>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <game@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
L5:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10a0 <assert@plt>
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string

tool: D2: Error. Expected %s but got %s


assistant: ```c
void dotest(unsigned long long n, char *expr) {
  char *act = game(n);
  if (strcmp(act, expr) != 0)
    printf("Error. Expected %s but got %s\n", expr, act);
  assert(strcmp(act, expr) == 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dotest>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <game@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
L6:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10a0 <assert@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: string

tool: D4: Error. Expected %s but got %s


assistant: ```c
void dotest(unsigned long long n, char *expr) {
  char *act = game(n);
  if (strcmp(act, expr) != 0)
    printf("Error. Expected %s but got %s\n", expr, act);
  assert(strcmp(act, expr) == 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test12>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <idc@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int test12(int *q) {
  int *p = q;
  idc(q);
  return *p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test12>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <idc@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int test12(int *q) {
  int *p = q;
  idc(q);
  return *p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test12>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <idc@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int test12(int *q) {
  int *p = q;
  idc(q);
  return *p;
}
```
user: What is the c source code of the assembly code below:

```asm
<test12>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <idc@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int test12(int *q) {
  int *p = q;
  idc(q);
  return *p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<S_validate_macro_sym>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L63
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L80
L63:
  mov    $0x0,%eax
  jmp    L92
L80:
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x0,-0x8(%rbp)
  je     L41
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  jne    L41
  mov    $0x0,%eax
  jmp    L92
L41:
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x0,%eax
  jmp    L92
L3:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L84
  mov    $0x1,%eax
  jmp    L92
L84:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L23
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L121
  mov    $0x0,%eax
  jmp    L92
L121:
  movl   $0x1,-0x8(%rbp)
L23:
  addq   $0x1,-0x18(%rbp)
  jmp    L5
L92:
  leave
  ret
```

assistant: ```c
int S_validate_macro_sym(const char *macro_sym) {
  if (!macro_sym || !strlen(macro_sym)) {
    return 0;
  }
  int need_upper = 1;
  int need_letter = 1;
  for (;; macro_sym++) {
    if (need_upper && !isupper(*macro_sym)) {
      return 0;
    }
    if (need_letter && !isalpha(*macro_sym)) {
      return 0;
    }
    need_upper = 0;
    need_letter = 0;
    if (!*macro_sym) {
      return 1;
    }
    if (!isalnum(*macro_sym)) {
      if (*macro_sym != '_') {
        return 0;
      }
      need_upper = 1;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<S_validate_macro_sym>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L118
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L107
  mov    $0x1,%r12d
  mov    $0x1,%eax
  mov    $0x0,%ebp
  jmp    L8
L119:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %eax,%eax
  jne    L110
  jmp    L107
L65:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L57
  jmp    L107
L82:
  mov    %ebp,%eax
L40:
  add    $0x1,%rbx
  mov    %ebp,%r12d
L8:
  test   %eax,%eax
  jne    L119
L110:
  test   %r12d,%r12d
  jne    L65
L57:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L7
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L82
  cmpb   $0x5f,(%rbx)
  jne    L107
  mov    $0x1,%eax
  jmp    L40
L7:
  mov    $0x1,%eax
L107:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L118:
  ret
```

assistant: ```c
int S_validate_macro_sym(const char *macro_sym) {
  if (!macro_sym || !strlen(macro_sym)) {
    return 0;
  }
  int need_upper = 1;
  int need_letter = 1;
  for (;; macro_sym++) {
    if (need_upper && !isupper(*macro_sym)) {
      return 0;
    }
    if (need_letter && !isalpha(*macro_sym)) {
      return 0;
    }
    need_upper = 0;
    need_letter = 0;
    if (!*macro_sym) {
      return 1;
    }
    if (!isalnum(*macro_sym)) {
      if (*macro_sym != '_') {
        return 0;
      }
      need_upper = 1;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<S_validate_macro_sym>:
  endbr64
  test   %rdi,%rdi
  je     L38
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L37
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L21:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L37
  movsbl (%rbx),%edi
  test   %ebp,%ebp
  je     L78
  call   <isalpha@plt>
  test   %eax,%eax
  je     L37
L78:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L90
L65:
  call   <isalnum@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L95
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L65
L90:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L37:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L95:
  cmpb   $0x5f,(%rbx)
  jne    L37
  add    $0x1,%rbx
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int S_validate_macro_sym(const char *macro_sym) {
  if (!macro_sym || !strlen(macro_sym)) {
    return 0;
  }
  int need_upper = 1;
  int need_letter = 1;
  for (;; macro_sym++) {
    if (need_upper && !isupper(*macro_sym)) {
      return 0;
    }
    if (need_letter && !isalpha(*macro_sym)) {
      return 0;
    }
    need_upper = 0;
    need_letter = 0;
    if (!*macro_sym) {
      return 1;
    }
    if (!isalnum(*macro_sym)) {
      if (*macro_sym != '_') {
        return 0;
      }
      need_upper = 1;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<S_validate_macro_sym>:
  endbr64
  test   %rdi,%rdi
  je     L31
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L14
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L30:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L14
  movsbl (%rbx),%edi
  test   %ebp,%ebp
  je     L57
  call   <isalpha@plt>
  test   %eax,%eax
  je     L14
L57:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L71
L46:
  call   <isalnum@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L15
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L46
L71:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L15:
  cmpb   $0x5f,(%rbx)
  jne    L14
  add    $0x1,%rbx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %eax,%eax
  ret
```

assistant: ```c
int S_validate_macro_sym(const char *macro_sym) {
  if (!macro_sym || !strlen(macro_sym)) {
    return 0;
  }
  int need_upper = 1;
  int need_letter = 1;
  for (;; macro_sym++) {
    if (need_upper && !isupper(*macro_sym)) {
      return 0;
    }
    if (need_letter && !isalpha(*macro_sym)) {
      return 0;
    }
    need_upper = 0;
    need_letter = 0;
    if (!*macro_sym) {
      return 1;
    }
    if (!isalnum(*macro_sym)) {
      if (*macro_sym != '_') {
        return 0;
      }
      need_upper = 1;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L8:
  subq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L12
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
L12:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void rtrim(char *string) {
  char *c = string + strlen(string);
  while (c > string && isspace(*(c - 1)))
    --c;
  *c = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rtrim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  cmp    %rbx,%rbp
  jae    L5
L26:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L5
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L26
  mov    %rbp,%rbx
L5:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rtrim(char *string) {
  char *c = string + strlen(string);
  while (c > string && isspace(*(c - 1)))
    --c;
  *c = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rtrim>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  cmp    %rbx,%rbp
  jb     L29
  jmp    L13
  nop
L26:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L13
L29:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L26
L13:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rtrim(char *string) {
  char *c = string + strlen(string);
  while (c > string && isspace(*(c - 1)))
    --c;
  *c = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rtrim>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  cmp    %rbx,%rbp
  jb     L34
  jmp    L31
  nop
L6:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L31
L34:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
L31:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rtrim(char *string) {
  char *c = string + strlen(string);
  while (c > string && isspace(*(c - 1)))
    --c;
  *c = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fstat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x8c004004,%eax
  mov    (%rax),%eax
  cmp    $0xdeadbeef,%eax
  jne    L6
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <dcloadsyscall@plt>
  jmp    L9
L6:
  mov    $0xffffffff,%eax
L9:
  leave
  ret
```

assistant: ```c
int fstat(int file, struct stat *st) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(10, file, st);
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fstat>:
  endbr64
  mov    $0x8c004004,%eax
  cmpl   $0xdeadbeef,(%rax)
  jne    L8
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <dcloadsyscall@plt>
  add    $0x8,%rsp
  ret
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fstat(int file, struct stat *st) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(10, file, st);
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fstat>:
  endbr64
  mov    $0x8c004004,%eax
  mov    %rsi,%rdx
  cmpl   $0xdeadbeef,(%rax)
  jne    L8
  mov    %edi,%esi
  mov    $0xa,%edi
  jmp    1050 <dcloadsyscall@plt>
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fstat(int file, struct stat *st) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(10, file, st);
  else
    return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<fstat>:
  endbr64
  mov    $0x8c004004,%eax
  mov    %rsi,%rdx
  cmpl   $0xdeadbeef,(%rax)
  jne    L8
  mov    %edi,%esi
  mov    $0xa,%edi
  jmp    1050 <dcloadsyscall@plt>
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fstat(int file, struct stat *st) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(10, file, st);
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ExtractI4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  shll   $0x8,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  shll   $0x8,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  shll   $0x8,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ExtractI4(const unsigned char *buf) {
  int x;
  x = buf[0];
  x <<= 8;
  x |= buf[1];
  x <<= 8;
  x |= buf[2];
  x <<= 8;
  x |= buf[3];
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ExtractI4>:
  endbr64
  movzbl (%rdi),%edx
  shl    $0x8,%edx
  movzbl 0x1(%rdi),%eax
  or     %edx,%eax
  shl    $0x8,%eax
  movzbl 0x2(%rdi),%edx
  or     %eax,%edx
  shl    $0x8,%edx
  movzbl 0x3(%rdi),%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int ExtractI4(const unsigned char *buf) {
  int x;
  x = buf[0];
  x <<= 8;
  x |= buf[1];
  x <<= 8;
  x |= buf[2];
  x <<= 8;
  x |= buf[3];
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ExtractI4>:
  endbr64
  mov    (%rdi),%eax
  bswap  %eax
  ret
```

assistant: ```c
int ExtractI4(const unsigned char *buf) {
  int x;
  x = buf[0];
  x <<= 8;
  x |= buf[1];
  x <<= 8;
  x |= buf[2];
  x <<= 8;
  x |= buf[3];
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ExtractI4>:
  endbr64
  mov    (%rdi),%eax
  bswap  %eax
  ret
```

assistant: ```c
int ExtractI4(const unsigned char *buf) {
  int x;
  x = buf[0];
  x <<= 8;
  x |= buf[1];
  x <<= 8;
  x |= buf[2];
  x <<= 8;
  x |= buf[3];
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  bar();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  bar();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  bar();
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  bar();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<init_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <init_writeOnce@plt>
  mov    $0x0,%eax
  call   <init_pta@plt>
  mov    $0x0,%eax
  call   <init_ptb@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_system() {
  init_writeOnce();
  init_pta();
  init_ptb();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<init_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_writeOnce@plt>
  mov    $0x0,%eax
  call   <init_pta@plt>
  mov    $0x0,%eax
  call   <init_ptb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_system() {
  init_writeOnce();
  init_pta();
  init_ptb();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init_system>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_writeOnce@plt>
  xor    %eax,%eax
  call   <init_pta@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <init_ptb@plt>
```

assistant: ```c
void init_system() {
  init_writeOnce();
  init_pta();
  init_ptb();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init_system>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_writeOnce@plt>
  xor    %eax,%eax
  call   <init_pta@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <init_ptb@plt>
```

assistant: ```c
void init_system() {
  init_writeOnce();
  init_pta();
  init_ptb();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0xffffffff,0x1c(%rsp)
  movl   $0xffffffff,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x1,0x28(%rsp)
  movl   $0xffffffff,0x2c(%rsp)
  movl   $0xffffffff,0x30(%rsp)
  movl   $0xffffffff,0x34(%rsp)
  movl   $0x1,0x38(%rsp)
  movl   $0xffffffff,0x3c(%rsp)
  mov    %rsp,%rdi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <net@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int andl[4][4] = {{1, 1, 1, 1}, {1, -1, 1, -1}, {-1, 1, 1, -1}, {-1, -1, 1, -1}};
  int orl[4][4] = {{1, 1, 1, 1}, {1, -1, 1, 1}, {-1, 1, 1, 1}, {-1, -1, 1, -1}};
  int nandl[4][4] = {{1, 1, 1, -1}, {1, -1, 1, 1}, {-1, 1, 1, 1}, {-1, -1, 1, 1}};
  int norl[4][4] = {{1, 1, 1, -1}, {1, -1, 1, -1}, {-1, 1, 1, -1}, {-1, -1, 1, 1}};
  int xorl[4][4] = {{1, 1, 1, -1}, {1, -1, 1, 1}, {-1, 1, 1, 1}, {-1, -1, 1, -1}};
  int i;
  net(andl, 1, 1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x1,%edx
  mov    $0x1,%esi
  movabs $0x1ffffffff,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x100000001,%rax
  mov    %rsp,%rdi
  mov    %rcx,0x20(%rsp)
  movq   $0xffffffffffffffff,0x30(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
  movabs $0xffffffff00000001,%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rax,0x28(%rsp)
  mov    %rax,0x38(%rsp)
  call   <net@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int andl[4][4] = {{1, 1, 1, 1}, {1, -1, 1, -1}, {-1, 1, 1, -1}, {-1, -1, 1, -1}};
  int orl[4][4] = {{1, 1, 1, 1}, {1, -1, 1, 1}, {-1, 1, 1, 1}, {-1, -1, 1, -1}};
  int nandl[4][4] = {{1, 1, 1, -1}, {1, -1, 1, 1}, {-1, 1, 1, 1}, {-1, -1, 1, 1}};
  int norl[4][4] = {{1, 1, 1, -1}, {1, -1, 1, -1}, {-1, 1, 1, -1}, {-1, -1, 1, 1}};
  int xorl[4][4] = {{1, 1, 1, -1}, {1, -1, 1, 1}, {-1, 1, 1, 1}, {-1, -1, 1, -1}};
  int i;
  net(andl, 1, 1);
  return 0;
}
```