ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x20,%edx
  mov    $0x0,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x1f,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    D0(%rip),%rax
  leave
  ret
```

assistant: ```c
char *strTime(time_t tx, char *format) {
  static char tstr[32];
  struct tm *tl;
  memset(tstr, 0, sizeof(tstr));
  tl = localtime(&tx);
  strftime(tstr, (sizeof(tstr) - 1), format, tl);
  return tstr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strTime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rbp
  mov    $0x20,%edx
  mov    $0x0,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  mov    %rbp,%rdx
  mov    $0x1f,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strTime(time_t tx, char *format) {
  static char tstr[32];
  struct tm *tl;
  memset(tstr, 0, sizeof(tstr));
  tl = localtime(&tx);
  strftime(tstr, (sizeof(tstr) - 1), format, tl);
  return tstr;
}
```
user: What is the c source code of the assembly code below:

```asm
<strTime>:
  endbr64
  push   %r13
  mov    $0x20,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  lea    D2(%rip),%r12
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x1f,%esi
  mov    %rax,%rcx
  call   <strftime@plt>
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strTime(time_t tx, char *format) {
  static char tstr[32];
  struct tm *tl;
  memset(tstr, 0, sizeof(tstr));
  tl = localtime(&tx);
  strftime(tstr, (sizeof(tstr) - 1), format, tl);
  return tstr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strTime>:
  endbr64
  push   %r13
  mov    $0x20,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  lea    D5(%rip),%r12
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x1f,%esi
  mov    %rax,%rcx
  call   <strftime@plt>
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strTime(time_t tx, char *format) {
  static char tstr[32];
  struct tm *tl;
  memset(tstr, 0, sizeof(tstr));
  tl = localtime(&tx);
  strftime(tstr, (sizeof(tstr) - 1), format, tl);
  return tstr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<timesteps>:
  endbr64
  sub    $0xd8,%rsp
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rax
  mov    %rax,(%rsp)
  lea    D13(%rip),%rsi
  mov    %rsi,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  lea    D22(%rip),%rdx
  mov    %rdx,0x18(%rsp)
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %rax,0x30(%rsp)
  mov    %rax,0x38(%rsp)
  mov    %rdx,0x40(%rsp)
  mov    %rax,0x48(%rsp)
  mov    %rdx,0x50(%rsp)
  mov    %rax,0x58(%rsp)
  mov    %rax,0x60(%rsp)
  lea    D24(%rip),%rsi
  mov    %rsi,0x68(%rsp)
  mov    %rax,0x70(%rsp)
  mov    %rdx,0x78(%rsp)
  mov    %rax,0x80(%rsp)
  mov    %rdx,0x88(%rsp)
  mov    %rax,0x90(%rsp)
  mov    %rax,0x98(%rsp)
  mov    %rdx,0xa0(%rsp)
  mov    %rax,0xa8(%rsp)
  mov    %rdx,0xb0(%rsp)
  mov    %rax,0xb8(%rsp)
  test   $0x3,%dil
  jne    L3
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    0x60(%rsp,%rcx,8),%rdi
  call   <atoi@plt>
L8:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0xd8,%rsp
  ret
L3:
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,8),%rdi
  call   <atoi@plt>
  jmp    L8
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D33
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D24
data_type: string

tool: D33: 31

tool: D13: 28

tool: D22: 30

tool: D24: 29

assistant: ```c
int timesteps(int yy, int mt) {
  int val;
  char *regular[] = {"31", "28", "31", "30", "31", "30", "31", "31", "30", "31", "30", "31"};
  char *leap[] = {"31", "29", "31", "30", "31", "30", "31", "31", "30", "31", "30", "31"};
  if (yy % 4 != 0)
    val = atoi(regular[mt % 12]);
  if (yy % 4 == 0)
    val = atoi(leap[mt % 12]);
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<timesteps>:
  endbr64
  sub    $0xd8,%rsp
  lea    D2(%rip),%rdx
  lea    D33(%rip),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  lea    D9(%rip),%rax
  mov    %rdx,0x18(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %rdx,0x40(%rsp)
  mov    %rdx,0x50(%rsp)
  mov    %rdx,0x78(%rsp)
  mov    %rdx,0x88(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rax,0x20(%rsp)
  mov    %rax,0x30(%rsp)
  mov    %rax,0x38(%rsp)
  mov    %rax,0x48(%rsp)
  mov    %rax,0x58(%rsp)
  mov    %rax,0x60(%rsp)
  mov    %rax,0x70(%rsp)
  mov    %rax,0x80(%rsp)
  mov    %rax,0x90(%rsp)
  mov    %rax,0x98(%rsp)
  mov    %rax,0xa8(%rsp)
  mov    %rax,0xb8(%rsp)
  movslq %esi,%rax
  imul   $0x2aaaaaab,%rax,%rax
  mov    %rdx,0xa0(%rsp)
  mov    %rdx,0xb0(%rsp)
  mov    %esi,%edx
  sar    $0x1f,%edx
  mov    %rcx,0x8(%rsp)
  lea    D16(%rip),%rcx
  sar    $0x21,%rax
  mov    %rcx,0x68(%rsp)
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %esi,%eax
  shl    $0x2,%edx
  sub    %edx,%eax
  and    $0x3,%edi
  jne    L16
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  cltq
  mov    0x60(%rsp,%rax,8),%rdi
  add    $0xd8,%rsp
  jmp    1070 <atoi@plt>
  nopl   0x0(%rax)
L16:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  cltq
  mov    (%rsp,%rax,8),%rdi
  add    $0xd8,%rsp
  jmp    1070 <atoi@plt>
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D33
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D16
type_guessed: string

tool: D2: 30

tool: D33: 28

tool: D9: 31

tool: D16: 29

assistant: ```c
int timesteps(int yy, int mt) {
  int val;
  char *regular[] = {"31", "28", "31", "30", "31", "30", "31", "31", "30", "31", "30", "31"};
  char *leap[] = {"31", "29", "31", "30", "31", "30", "31", "31", "30", "31", "30", "31"};
  if (yy % 4 != 0)
    val = atoi(regular[mt % 12]);
  if (yy % 4 == 0)
    val = atoi(leap[mt % 12]);
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timesteps>:
  endbr64
  sub    $0xd8,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  lea    D33(%rip),%rax
  sar    $0x1f,%edx
  movq   %rax,%xmm1
  lea    D35(%rip),%rax
  movq   %rax,%xmm0
  lea    D24(%rip),%rax
  movdqa %xmm1,%xmm2
  movq   %rax,%xmm5
  lea    D38(%rip),%rax
  movdqa %xmm1,%xmm3
  movq   %rax,%xmm6
  movdqa %xmm1,%xmm4
  punpcklqdq %xmm0,%xmm2
  movslq %esi,%rax
  imul   $0x2aaaaaab,%rax,%rax
  punpcklqdq %xmm1,%xmm0
  punpcklqdq %xmm3,%xmm3
  movaps %xmm2,0x10(%rsp)
  punpcklqdq %xmm5,%xmm4
  punpcklqdq %xmm6,%xmm1
  movaps %xmm2,0x20(%rsp)
  movaps %xmm4,(%rsp)
  sar    $0x21,%rax
  movaps %xmm3,0x30(%rsp)
  sub    %edx,%eax
  movaps %xmm0,0x40(%rsp)
  lea    (%rax,%rax,2),%edx
  mov    %esi,%eax
  movaps %xmm0,0x50(%rsp)
  shl    $0x2,%edx
  movaps %xmm1,0x60(%rsp)
  sub    %edx,%eax
  and    $0x3,%edi
  movaps %xmm2,0x70(%rsp)
  movaps %xmm2,0x80(%rsp)
  movaps %xmm3,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  jne    L26
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  cltq
  mov    0x60(%rsp,%rax,8),%rdi
  add    $0xd8,%rsp
  jmp    1070 <atoi@plt>
  nopl   (%rax)
L26:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  cltq
  mov    (%rsp,%rax,8),%rdi
  add    $0xd8,%rsp
  jmp    1070 <atoi@plt>
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D33
type_guessed: string
name: unpack_data
arguments: label: D35
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D38
type_guessed: string

tool: D33: 31

tool: D35: 30

tool: D24: 28

tool: D38: 29

assistant: ```c
int timesteps(int yy, int mt) {
  int val;
  char *regular[] = {"31", "28", "31", "30", "31", "30", "31", "31", "30", "31", "30", "31"};
  char *leap[] = {"31", "29", "31", "30", "31", "30", "31", "31", "30", "31", "30", "31"};
  if (yy % 4 != 0)
    val = atoi(regular[mt % 12]);
  if (yy % 4 == 0)
    val = atoi(leap[mt % 12]);
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBHostSuspend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  or     $0x2,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBHostSuspend(uint32_t ui32Base) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000001))) |= 0x00000002;
}
```
user: What is the c source code of the assembly code below:

```asm
<USBHostSuspend>:
  endbr64
  mov    0x1(%rdi),%eax
  or     $0x2,%eax
  mov    %eax,0x1(%rdi)
  ret
```

assistant: ```c
void USBHostSuspend(uint32_t ui32Base) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000001))) |= 0x00000002;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<USBHostSuspend>:
  endbr64
  mov    0x1(%rdi),%eax
  or     $0x2,%eax
  mov    %eax,0x1(%rdi)
  ret
```

assistant: ```c
void USBHostSuspend(uint32_t ui32Base) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000001))) |= 0x00000002;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<USBHostSuspend>:
  endbr64
  mov    0x1(%rdi),%eax
  or     $0x2,%eax
  mov    %eax,0x1(%rdi)
  ret
```

assistant: ```c
void USBHostSuspend(uint32_t ui32Base) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000001))) |= 0x00000002;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sum_of_even_squares>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L9:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L7
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x8(%rbp)
L7:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum_of_even_squares(int *a, unsigned int length) {
  int total = 0;
  for (unsigned int i = 0; i < length; i++) {
    if (a[i] % 2 == 0) {
      total += a[i] * a[i];
    }
  }
  return total;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_of_even_squares>:
  endbr64
  test   %esi,%esi
  je     L32
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rsi
  mov    $0x0,%ecx
  jmp    L38
L35:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L3
L38:
  mov    (%rax),%edx
  test   $0x1,%dl
  jne    L35
  imul   %edx,%edx
  add    %edx,%ecx
  jmp    L35
L32:
  mov    $0x0,%ecx
L3:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int sum_of_even_squares(int *a, unsigned int length) {
  int total = 0;
  for (unsigned int i = 0; i < length; i++) {
    if (a[i] % 2 == 0) {
      total += a[i] * a[i];
    }
  }
  return total;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sum_of_even_squares>:
  endbr64
  test   %esi,%esi
  je     L12
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rdx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%rdi),%eax
  test   $0x1,%al
  jne    L13
  imul   %eax,%eax
  add    %eax,%r8d
L13:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L14
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_of_even_squares(int *a, unsigned int length) {
  int total = 0;
  for (unsigned int i = 0; i < length; i++) {
    if (a[i] % 2 == 0) {
      total += a[i] * a[i];
    }
  }
  return total;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sum_of_even_squares>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%edx
  test   %esi,%esi
  je     L93
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L54
  shr    $0x2,%esi
  pxor   %xmm3,%xmm3
  movdqa D3(%rip),%xmm5
  mov    %rdi,%rax
  sub    $0x1,%esi
  movdqa %xmm3,%xmm4
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nop
L33:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm2
  movdqa %xmm0,%xmm1
  pmuludq %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pand   %xmm5,%xmm1
  pmuludq %xmm0,%xmm0
  pcmpeqd %xmm4,%xmm1
  pshufd $0x8,%xmm2,%xmm2
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm2
  movdqa %xmm1,%xmm0
  pand   %xmm2,%xmm0
  paddd  %xmm0,%xmm3
  cmp    %rax,%rsi
  jne    L33
  movdqa %xmm3,%xmm0
  mov    %edx,%esi
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%esi
  paddd  %xmm0,%xmm3
  movdqa %xmm3,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm3
  movd   %xmm3,%eax
  test   $0x3,%dl
  je     L53
L39:
  mov    %esi,%edi
  mov    (%rcx,%rdi,4),%edi
  test   $0x1,%dil
  je     L116
L4:
  lea    0x1(%rsi),%edi
  cmp    %edx,%edi
  jae    L46
  mov    (%rcx,%rdi,4),%edi
  test   $0x1,%dil
  je     L81
L35:
  add    $0x2,%esi
  cmp    %esi,%edx
  jbe    L46
  mov    (%rcx,%rsi,4),%edx
  test   $0x1,%dl
  jne    L46
  imul   %edx,%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax)
L93:
  xor    %eax,%eax
L46:
  ret
  nopl   0x0(%rax,%rax,1)
L116:
  imul   %edi,%edi
  add    %edi,%eax
  jmp    L4
  nop
L81:
  imul   %edi,%edi
  add    %edi,%eax
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L53:
  ret
L54:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L39
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: byte[16]

tool: {"D3": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int sum_of_even_squares(int *a, unsigned int length) {
  int total = 0;
  for (unsigned int i = 0; i < length; i++) {
    if (a[i] % 2 == 0) {
      total += a[i] * a[i];
    }
  }
  return total;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sqlite3Delete83Name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L17
L5:
  subl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x0,-0x8(%rbp)
  jle    L36
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L36
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L5
L36:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L9
  mov    -0x8(%rbp),%eax
  add    $0x4,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L9
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x3(%rax),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void sqlite3Delete83Name(char *z) {
  int i, sz;
  sz = (int)strlen(z);
  for (i = sz - 1; i > 0 && z[i] != '/' && z[i] != '.'; i--) {
  }
  if (z[i] == '.' && (sz > i + 4))
    memmove(&z[i + 1], &z[sz - 3], 4);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sqlite3Delete83Name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L26
  movslq %ecx,%rsi
  add    %rbx,%rsi
L39:
  movzbl (%rsi),%edi
  lea    -0x2e(%rdi),%edx
  cmp    $0x1,%dl
  jbe    L26
  sub    $0x1,%rsi
  sub    $0x1,%ecx
  jne    L39
L26:
  movslq %ecx,%rdx
  cmpb   $0x2e,(%rbx,%rdx,1)
  je     L50
L37:
  pop    %rbx
  ret
L50:
  add    $0x4,%ecx
  cmp    %eax,%ecx
  jge    L37
  cltq
  lea    -0x3(%rbx,%rax,1),%rsi
  lea    0x1(%rbx,%rdx,1),%rdi
  mov    $0x4,%edx
  call   <memmove@plt>
  jmp    L37
```

assistant: ```c
void sqlite3Delete83Name(char *z) {
  int i, sz;
  sz = (int)strlen(z);
  for (i = sz - 1; i > 0 && z[i] != '/' && z[i] != '.'; i--) {
  }
  if (z[i] == '.' && (sz > i + 4))
    memmove(&z[i + 1], &z[sz - 3], 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sqlite3Delete83Name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rdx
  test   %ecx,%ecx
  jg     L39
  jmp    L4
  nopl   0x0(%rax)
L75:
  lea    -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  je     L61
L39:
  movzbl (%rbx,%rdx,1),%esi
  mov    %edx,%ecx
  lea    -0x2e(%rsi),%r8d
  cmp    $0x1,%r8b
  ja     L75
  cmp    $0x2e,%sil
  je     L56
L69:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L56:
  add    $0x4,%ecx
  cmp    %eax,%ecx
  jge    L69
  cltq
  lea    0x1(%rbx,%rdx,1),%rdi
  mov    $0x4,%edx
  lea    -0x3(%rbx,%rax,1),%rsi
  pop    %rbx
  jmp    1070 <memmove@plt>
  cs nopw 0x0(%rax,%rax,1)
L61:
  movslq %ecx,%rdx
L4:
  movzbl (%rbx,%rdx,1),%esi
  cmp    $0x2e,%sil
  jne    L69
  jmp    L56
```

assistant: ```c
void sqlite3Delete83Name(char *z) {
  int i, sz;
  sz = (int)strlen(z);
  for (i = sz - 1; i > 0 && z[i] != '/' && z[i] != '.'; i--) {
  }
  if (z[i] == '.' && (sz > i + 4))
    memmove(&z[i + 1], &z[sz - 3], 4);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqlite3Delete83Name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rdx
  test   %ecx,%ecx
  jg     L25
  jmp    L23
  nopl   0x0(%rax)
L14:
  lea    -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  je     L70
L25:
  movzbl (%rbx,%rdx,1),%esi
  mov    %edx,%ecx
  lea    -0x2e(%rsi),%r8d
  cmp    $0x1,%r8b
  ja     L14
  cmp    $0x2e,%sil
  je     L46
L13:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L46:
  add    $0x4,%ecx
  cmp    %eax,%ecx
  jge    L13
  cltq
  lea    0x1(%rbx,%rdx,1),%rdi
  mov    $0x4,%edx
  lea    -0x3(%rbx,%rax,1),%rsi
  pop    %rbx
  jmp    1070 <memmove@plt>
  cs nopw 0x0(%rax,%rax,1)
L70:
  movslq %ecx,%rdx
L23:
  movzbl (%rbx,%rdx,1),%esi
  cmp    $0x2e,%sil
  jne    L13
  jmp    L46
```

assistant: ```c
void sqlite3Delete83Name(char *z) {
  int i, sz;
  sz = (int)strlen(z);
  for (i = sz - 1; i > 0 && z[i] != '/' && z[i] != '.'; i--) {
  }
  if (z[i] == '.' && (sz > i + 4))
    memmove(&z[i + 1], &z[sz - 3], 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fn_ch_61>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <next_utf8@plt>
  cmp    $0x3d,%eax
  jne    L0
  mov    -0xc(%rbp),%eax
  jmp    L12
L0:
  mov    $0xffffffff,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int fn_ch_61(const char *text) {
  int pos = 0;
  if (next_utf8(text, &pos) == 61)
    return pos;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fn_ch_61>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <next_utf8@plt>
  cmp    $0x3d,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_ch_61(const char *text) {
  int pos = 0;
  if (next_utf8(text, &pos) == 61)
    return pos;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<fn_ch_61>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <next_utf8@plt>
  cmp    $0x3d,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_ch_61(const char *text) {
  int pos = 0;
  if (next_utf8(text, &pos) == 61)
    return pos;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fn_ch_61>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <next_utf8@plt>
  cmp    $0x3d,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_ch_61(const char *text) {
  int pos = 0;
  if (next_utf8(text, &pos) == 61)
    return pos;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rlstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L24:
  mov    -0x14(%rbp),%eax
  mov    -0x30(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L12
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    D6(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
L12:
  addl   $0x1,-0x14(%rbp)
L7:
  cmpl   $0xf,-0x14(%rbp)
  jg     L8
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L24
L8:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rlstr(char *str, int len, int mask) {
  char *p = str;
  char *end = str + len - 1;
  static char bits[16] = "0123456789abcdef";
  int i;
  for (i = 0; i < 16 && p < end; i++)
    if (mask & (1 << i))
      *(p++) = bits[i];
  *p = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rlstr>:
  endbr64
  movslq %esi,%rsi
  lea    -0x1(%rdi,%rsi,1),%rsi
  cmp    %rsi,%rdi
  jae    L45
  lea    D2(%rip),%rcx
  mov    $0x0,%eax
  jmp    L22
L40:
  add    $0x1,%eax
  add    $0x1,%rcx
  cmp    $0xf,%eax
  jg     L45
  cmp    %rsi,%rdi
  jae    L45
L22:
  bt     %eax,%edx
  jae    L40
  movzbl (%rcx),%r8d
  mov    %r8b,(%rdi)
  lea    0x1(%rdi),%rdi
  jmp    L40
L45:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void rlstr(char *str, int len, int mask) {
  char *p = str;
  char *end = str + len - 1;
  static char bits[16] = "0123456789abcdef";
  int i;
  for (i = 0; i < 16 && p < end; i++)
    if (mask & (1 << i))
      *(p++) = bits[i];
  *p = '\0';
}
```