ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<to_utf8>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <u_is_valid@plt>
  test   %rax,%rax
  jne    L33
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <utf8_encode@plt>
  mov    %eax,%r8d
  mov    (%rsp),%rax
  test   %r8d,%r8d
  js     L33
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L33:
  mov    %rbp,%rdi
  call   <xstrdup@plt>
  jmp    L5
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *to_utf8(const char *str, const char *enc) {
  char *outbuf = NULL;
  int rc;
  if (u_is_valid(str)) {
    return xstrdup(str);
  } else {
    rc = utf8_encode(str, enc, &outbuf);
    return rc < 0 ? xstrdup(str) : outbuf;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<to_utf8>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <u_is_valid@plt>
  test   %rax,%rax
  jne    L15
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <utf8_encode@plt>
  mov    %eax,%r8d
  mov    (%rsp),%rax
  test   %r8d,%r8d
  js     L15
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L15:
  mov    %rbp,%rdi
  call   <xstrdup@plt>
  jmp    L17
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *to_utf8(const char *str, const char *enc) {
  char *outbuf = NULL;
  int rc;
  if (u_is_valid(str)) {
    return xstrdup(str);
  } else {
    rc = utf8_encode(str, enc, &outbuf);
    return rc < 0 ? xstrdup(str) : outbuf;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<CAS2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    -0x28(%rbp),%r8
  mov    -0x30(%rbp),%rcx
  mov    %rsi,%rdi
  mov    %r8,%rbx
  lock cmpxchg8b (%rdi)
  sete   %al
  mov    %eax,%ebx
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char CAS2(volatile void *addr, volatile void *v1, volatile long v2, void *n1, long n2) {
  register char ret;
  __asm__ __volatile__("# CAS2 \n\t"
                       "lock ; "
                       "cmpxchg8b (%1) \n\t"
                       "sete %0               \n\t"
                       : "=a"(ret)
                       : "D"(addr), "d"(v2), "a"(v1), "b"(n1), "c"(n2));
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CAS2>:
  endbr64
  push   %rbx
  mov    %rdx,-0x8(%rsp)
  mov    %rcx,%rbx
  mov    -0x8(%rsp),%rdx
  mov    %rsi,%rax
  mov    %r8,%rcx
  lock cmpxchg8b (%rdi)
  sete   %al
  pop    %rbx
  ret
```

assistant: ```c
char CAS2(volatile void *addr, volatile void *v1, volatile long v2, void *n1, long n2) {
  register char ret;
  __asm__ __volatile__("# CAS2 \n\t"
                       "lock ; "
                       "cmpxchg8b (%1) \n\t"
                       "sete %0               \n\t"
                       : "=a"(ret)
                       : "D"(addr), "d"(v2), "a"(v1), "b"(n1), "c"(n2));
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CAS2>:
  endbr64
  push   %rbx
  mov    %rsi,%rax
  mov    %rcx,%rbx
  mov    %r8,%rcx
  mov    %rdx,-0x8(%rsp)
  mov    -0x8(%rsp),%rdx
  lock cmpxchg8b (%rdi)
  sete   %al
  pop    %rbx
  ret
```

assistant: ```c
char CAS2(volatile void *addr, volatile void *v1, volatile long v2, void *n1, long n2) {
  register char ret;
  __asm__ __volatile__("# CAS2 \n\t"
                       "lock ; "
                       "cmpxchg8b (%1) \n\t"
                       "sete %0               \n\t"
                       : "=a"(ret)
                       : "D"(addr), "d"(v2), "a"(v1), "b"(n1), "c"(n2));
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mirror_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L32
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
L19:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <reverse@plt>
  jmp    L36
L59:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L36
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <reverse@plt>
  jmp    L45
L32:
  nop
L45:
  leave
  ret
```

assistant: ```c
void mirror_words(char *words) {
  if (!words) {
    return;
  }
  char *word_begin = words;
  char *tmp = words;
  while (*tmp) {
    tmp++;
    if (*tmp == '\0') {
      reverse(word_begin, tmp - 1);
    } else if (*tmp == ' ') {
      reverse(word_begin, tmp - 1);
      word_begin = tmp + 1;
    }
  }
  reverse(words, tmp - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mirror_words>:
  endbr64
  test   %rdi,%rdi
  je     L58
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  cmpb   $0x0,(%rdi)
  je     L68
  mov    %rdi,%rsi
  mov    %rdi,%r12
  jmp    L10
L33:
  mov    %r12,%rdi
  call   <reverse@plt>
L26:
  cmpb   $0x0,(%rbx)
  je     L41
L34:
  mov    %rbx,%rsi
L10:
  lea    0x1(%rsi),%rbx
  movzbl 0x1(%rsi),%eax
  test   %al,%al
  je     L33
  cmp    $0x20,%al
  jne    L34
  mov    %r12,%rdi
  call   <reverse@plt>
  lea    0x1(%rbx),%r12
  jmp    L26
L68:
  mov    %rdi,%rbx
L41:
  lea    -0x1(%rbx),%rsi
  mov    %rbp,%rdi
  call   <reverse@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  ret
```

assistant: ```c
void mirror_words(char *words) {
  if (!words) {
    return;
  }
  char *word_begin = words;
  char *tmp = words;
  while (*tmp) {
    tmp++;
    if (*tmp == '\0') {
      reverse(word_begin, tmp - 1);
    } else if (*tmp == ' ') {
      reverse(word_begin, tmp - 1);
      word_begin = tmp + 1;
    }
  }
  reverse(words, tmp - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mirror_words>:
  endbr64
  test   %rdi,%rdi
  je     L36
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L22
  mov    %rdi,%rbp
  mov    %rdi,%r13
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L73:
  cmp    $0x20,%al
  je     L57
L51:
  mov    %rbx,%rbp
L46:
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%rbx
  test   %al,%al
  jne    L73
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <reverse@plt>
L4:
  cmpb   $0x0,(%rbx)
  jne    L51
L6:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <reverse@plt>
L57:
  mov    %r13,%rdi
  mov    %rbp,%rsi
  lea    0x2(%rbp),%r13
  call   <reverse@plt>
  jmp    L4
  nopl   0x0(%rax)
L36:
  ret
  nopl   0x0(%rax)
L22:
  lea    -0x1(%rdi),%rbp
  jmp    L6
```

assistant: ```c
void mirror_words(char *words) {
  if (!words) {
    return;
  }
  char *word_begin = words;
  char *tmp = words;
  while (*tmp) {
    tmp++;
    if (*tmp == '\0') {
      reverse(word_begin, tmp - 1);
    } else if (*tmp == ' ') {
      reverse(word_begin, tmp - 1);
      word_begin = tmp + 1;
    }
  }
  reverse(words, tmp - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mirror_words>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L23
  mov    %rdi,%rbp
  mov    %rdi,%r13
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L44:
  cmp    $0x20,%al
  je     L12
L46:
  mov    %rbx,%rbp
L75:
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%rbx
  test   %al,%al
  jne    L44
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <reverse@plt>
L28:
  cmpb   $0x0,(%rbx)
  jne    L46
L30:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <reverse@plt>
L12:
  mov    %r13,%rdi
  mov    %rbp,%rsi
  lea    0x2(%rbp),%r13
  call   <reverse@plt>
  jmp    L28
  nopl   0x0(%rax)
L10:
  ret
  nopl   0x0(%rax)
L23:
  lea    -0x1(%rdi),%rbp
  jmp    L30
```

assistant: ```c
void mirror_words(char *words) {
  if (!words) {
    return;
  }
  char *word_begin = words;
  char *tmp = words;
  while (*tmp) {
    tmp++;
    if (*tmp == '\0') {
      reverse(word_begin, tmp - 1);
    } else if (*tmp == ' ') {
      reverse(word_begin, tmp - 1);
      word_begin = tmp + 1;
    }
  }
  reverse(words, tmp - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_dump_opcodes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string

tool: D8: %02x 

assistant: ```c
void _dump_opcodes(unsigned char *p, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%02x ", p[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<_dump_opcodes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L2
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D9(%rip),%rbp
L8:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L8
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: %02x 

assistant: ```c
void _dump_opcodes(unsigned char *p, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%02x ", p[i]);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_dump_opcodes>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L4:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L14:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %02x 

assistant: ```c
void _dump_opcodes(unsigned char *p, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%02x ", p[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_dump_opcodes>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L7:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L15:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: %02x 

assistant: ```c
void _dump_opcodes(unsigned char *p, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%02x ", p[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<greatestCommonDivisorLoop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jg     L12
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L12:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L29:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L66
  mov    -0x20(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  je     L56
L66:
  subq   $0x1,-0x8(%rbp)
L17:
  cmpq   $0x0,-0x8(%rbp)
  jg     L29
  jmp    L46
L56:
  nop
L46:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long greatestCommonDivisorLoop(long a, long b) {
  long i;
  if (a <= b)
    i = a;
  else
    i = b;
  for (i; i > 0; i--) {
    if (!(a % i) && !(b % i)) {
      break;
    }
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<greatestCommonDivisorLoop>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rcx
  cmovle %rdi,%rcx
  test   %rcx,%rcx
  jg     L42
  jmp    L9
L25:
  sub    $0x1,%rcx
  je     L9
L42:
  mov    %rdi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L25
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L25
L9:
  mov    %rcx,%rax
  ret
```

assistant: ```c
long greatestCommonDivisorLoop(long a, long b) {
  long i;
  if (a <= b)
    i = a;
  else
    i = b;
  for (i; i > 0; i--) {
    if (!(a % i) && !(b % i)) {
      break;
    }
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<greatestCommonDivisorLoop>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%r8
  cmovle %rdi,%r8
  test   %r8,%r8
  jle    L28
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rdi,%rax
  cqto
  idiv   %r8
  test   %rdx,%rdx
  jne    L6
  mov    %rsi,%rax
  cqto
  idiv   %r8
  test   %rdx,%rdx
  je     L28
L6:
  sub    $0x1,%r8
  jne    L25
L28:
  mov    %r8,%rax
  ret
```

assistant: ```c
long greatestCommonDivisorLoop(long a, long b) {
  long i;
  if (a <= b)
    i = a;
  else
    i = b;
  for (i; i > 0; i--) {
    if (!(a % i) && !(b % i)) {
      break;
    }
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<greatestCommonDivisorLoop>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%r8
  cmovle %rdi,%r8
  test   %r8,%r8
  jle    L32
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rdi,%rax
  cqto
  idiv   %r8
  test   %rdx,%rdx
  jne    L13
  mov    %rsi,%rax
  cqto
  idiv   %r8
  test   %rdx,%rdx
  je     L32
L13:
  sub    $0x1,%r8
  jne    L22
L32:
  mov    %r8,%rax
  ret
```

assistant: ```c
long greatestCommonDivisorLoop(long a, long b) {
  long i;
  if (a <= b)
    i = a;
  else
    i = b;
  for (i; i > 0; i--) {
    if (!(a % i) && !(b % i)) {
      break;
    }
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<floats_quat_slerp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  movss  %xmm0,0x4(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edx
  call   <floats_dot@plt>
  movss  %xmm0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x10,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm3
  comiss %xmm3,%xmm0
  ja     L12
L3:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  mov    $0x0,%eax
  comisd D45(%rip),%xmm0
  jbe    L53
  movss  D17(%rip),%xmm2
  subss  0x4(%rsp),%xmm2
  lea    0x10(%rsp),%rdx
L77:
  movaps %xmm2,%xmm0
  mulss  (%rbx,%rax,1),%xmm0
  movss  0x4(%rsp),%xmm1
  mulss  (%rax,%rdx,1),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x0(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L77
L17:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  xorps  D15(%rip),%xmm3
  movss  %xmm3,0x8(%rsp)
  lea    0x10(%rsp),%rax
  lea    0x20(%rsp),%rdx
  movss  D15(%rip),%xmm1
L36:
  movss  (%rax),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L36
  jmp    L3
L53:
  movss  0x8(%rsp),%xmm0
  call   <acos@plt>
  movaps %xmm0,%xmm5
  movss  D17(%rip),%xmm0
  subss  0x4(%rsp),%xmm0
  movss  %xmm5,0xc(%rsp)
  mulss  %xmm5,%xmm0
  call   <sin@plt>
  movss  %xmm0,0x8(%rsp)
  movss  0xc(%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  call   <sin@plt>
  mov    $0x0,%eax
  lea    0x10(%rsp),%rdx
L10:
  movss  0x8(%rsp),%xmm1
  mulss  (%rbx,%rax,1),%xmm1
  movaps %xmm0,%xmm2
  mulss  (%rax,%rdx,1),%xmm2
  addss  %xmm2,%xmm1
  movss  %xmm1,0x0(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L10
  mov    %rbp,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <floats_normalize@plt>
  jmp    L17
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D45
data_type: f64
name: disassemble_data
arguments: data_label: D17
data_type: f32
name: disassemble_data
arguments: data_label: D15
data_type: byte[16]

tool: D45: 0.95

tool: D17: 1

tool: {"D15": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void floats_quat_slerp(const float q0[4], const float _q1[4], float r[4], float w) {
  float dot = floats_dot(q0, _q1, 4);
  float q1[4];
  memcpy(q1, _q1, sizeof(float) * 4);
  if (dot < 0) {
    dot = -dot;
    for (int i = 0; i < 4; i++)
      q1[i] *= -1;
  }
  if (dot > 0.95) {
    for (int i = 0; i < 4; i++)
      r[i] = q0[i] * (1 - w) + q1[i] * w;
  } else {
    float angle = acos(dot);
    float w0 = sin(angle * (1 - w)), w1 = sin(angle * w);
    for (int i = 0; i < 4; i++)
      r[i] = q0[i] * w0 + q1[i] * w1;
    floats_normalize(r, 4, r);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<floats_quat_slerp>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x4,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  movss  %xmm0,0x8(%rsp)
  lea    0x10(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <floats_dot@plt>
  mov    $0x10,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  movss  %xmm0,0x4(%rsp)
  call   <memcpy@plt>
  movss  0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  movss  0x8(%rsp),%xmm2
  comiss %xmm0,%xmm1
  ja     L7
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  comisd D4(%rip),%xmm1
  jbe    L63
L48:
  movss  D33(%rip),%xmm3
  xor    %eax,%eax
  subss  %xmm2,%xmm3
L78:
  movss  (%rbx,%rax,1),%xmm1
  movss  (%r12,%rax,1),%xmm0
  mulss  %xmm3,%xmm1
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  %xmm1,0x0(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L78
L77:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  movss  D19(%rip),%xmm3
  mov    %r12,%rax
  lea    0x20(%rsp),%rdx
  xorps  %xmm3,%xmm0
L65:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  xorps  %xmm3,%xmm1
  movss  %xmm1,-0x4(%rax)
  cmp    %rax,%rdx
  jne    L65
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  comisd D4(%rip),%xmm1
  ja     L48
L63:
  movss  %xmm2,0x4(%rsp)
  call   <acos@plt>
  movss  0x4(%rsp),%xmm2
  movaps %xmm0,%xmm1
  movss  D33(%rip),%xmm0
  movss  %xmm2,0xc(%rsp)
  subss  %xmm2,%xmm0
  movss  %xmm1,0x8(%rsp)
  mulss  %xmm1,%xmm0
  call   <sin@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  movss  %xmm0,0x4(%rsp)
  movaps %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  call   <sin@plt>
  movss  0x4(%rsp),%xmm3
  xor    %eax,%eax
L19:
  movss  (%rbx,%rax,1),%xmm1
  movss  (%r12,%rax,1),%xmm2
  mulss  %xmm3,%xmm1
  mulss  %xmm0,%xmm2
  addss  %xmm2,%xmm1
  movss  %xmm1,0x0(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L19
  mov    %rbp,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <floats_normalize@plt>
  jmp    L77
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: f64
name: retrieve_data
arguments: tag: D33
datatype: f32
name: retrieve_data
arguments: tag: D19
datatype: byte[4]

tool: D4: 0.95

tool: D33: 1

tool: {"D19": [0x00,0x00,0x00,0x80]}

assistant: ```c
void floats_quat_slerp(const float q0[4], const float _q1[4], float r[4], float w) {
  float dot = floats_dot(q0, _q1, 4);
  float q1[4];
  memcpy(q1, _q1, sizeof(float) * 4);
  if (dot < 0) {
    dot = -dot;
    for (int i = 0; i < 4; i++)
      q1[i] *= -1;
  }
  if (dot > 0.95) {
    for (int i = 0; i < 4; i++)
      r[i] = q0[i] * (1 - w) + q1[i] * w;
  } else {
    float angle = acos(dot);
    float w0 = sin(angle * (1 - w)), w1 = sin(angle * w);
    for (int i = 0; i < 4; i++)
      r[i] = q0[i] * w0 + q1[i] * w1;
    floats_normalize(r, 4, r);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<get_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x2329,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D2
type_guessed: string

tool: D11: we got %d


tool: D2: we got a number

assistant: ```c
int get_number(void) {
  int x = 10;
  printf("we got %d\n", x);
  puts("we got a number");
  return 9001;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_number>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    $0x2329,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D18
type_guessed: string

tool: D14: we got %d


tool: D18: we got a number

assistant: ```c
int get_number(void) {
  int x = 10;
  printf("we got %d\n", x);
  puts("we got a number");
  return 9001;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_number>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    $0x2329,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type: string
name: disassemble_data
arguments: data_tag: D18
type: string

tool: D11: we got %d


tool: D18: we got a number

assistant: ```c
int get_number(void) {
  int x = 10;
  printf("we got %d\n", x);
  puts("we got a number");
  return 9001;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_number>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x2329,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D0
datatype: string

tool: D10: we got %d


tool: D0: we got a number

assistant: ```c
int get_number(void) {
  int x = 10;
  printf("we got %d\n", x);
  puts("we got a number");
  return 9001;
}
```