ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<str_copy>:
  endbr64
  mov    %rdx,%rax
  movzbl (%rsi),%r8d
  cmp    $0x1,%rdx
  jbe    L8
  test   %r8b,%r8b
  je     L8
  mov    %rdx,%rcx
L49:
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %r8b,-0x1(%rdi)
  sub    $0x1,%rcx
  movzbl (%rsi),%r8d
  cmp    $0x1,%rcx
  jbe    L29
  test   %r8b,%r8b
  jne    L49
L29:
  movb   $0x0,(%rdi)
  sub    %rcx,%rax
  ret
L8:
  mov    %rax,%rcx
  jmp    L29
```

assistant: ```c
size_t str_copy(char *dst, const char *src, size_t size) {
  size_t len = size;
  while (*src && size > 1) {
    *dst++ = *src++;
    size--;
  }
  *dst = '\0';
  return len - size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_copy>:
  endbr64
  movzbl (%rsi),%ecx
  cmp    $0x1,%rdx
  jbe    L12
  test   %cl,%cl
  je     L12
  mov    %rdx,%r8
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L36:
  cmp    $0x1,%r8
  jbe    L0
L33:
  add    $0x1,%rsi
  mov    %cl,(%rdi)
  add    $0x1,%rdi
  sub    $0x1,%r8
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L36
L0:
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  sub    %r8,%rax
  ret
  nopl   (%rax)
L12:
  movb   $0x0,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t str_copy(char *dst, const char *src, size_t size) {
  size_t len = size;
  while (*src && size > 1) {
    *dst++ = *src++;
    size--;
  }
  *dst = '\0';
  return len - size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_copy>:
  endbr64
  movzbl (%rsi),%ecx
  cmp    $0x1,%rdx
  jbe    L11
  test   %cl,%cl
  je     L11
  mov    %rdx,%r8
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L38:
  cmp    $0x1,%r8
  jbe    L28
L45:
  add    $0x1,%rsi
  mov    %cl,(%rdi)
  add    $0x1,%rdi
  sub    $0x1,%r8
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L38
L28:
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  sub    %r8,%rax
  ret
  nopl   (%rax)
L11:
  movb   $0x0,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t str_copy(char *dst, const char *src, size_t size) {
  size_t len = size;
  while (*src && size > 1) {
    *dst++ = *src++;
    size--;
  }
  *dst = '\0';
  return len - size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scalar_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double scalar_product(const double *vector1, const double *vector2, int n) {
  double prod = 0;
  for (int i = 0; i < n; i++) {
    prod += vector1[i] * vector2[i];
  }
  return prod;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scalar_product>:
  endbr64
  test   %edx,%edx
  jle    L22
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L18:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
L15:
  movapd %xmm1,%xmm0
  ret
L22:
  pxor   %xmm1,%xmm1
  jmp    L15
```

assistant: ```c
double scalar_product(const double *vector1, const double *vector2, int n) {
  double prod = 0;
  for (int i = 0; i < n; i++) {
    prod += vector1[i] * vector2[i];
  }
  return prod;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scalar_product>:
  endbr64
  test   %edx,%edx
  jle    L0
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L8:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L8
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L0:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double scalar_product(const double *vector1, const double *vector2, int n) {
  double prod = 0;
  for (int i = 0; i < n; i++) {
    prod += vector1[i] * vector2[i];
  }
  return prod;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scalar_product>:
  endbr64
  test   %edx,%edx
  jle    L2
  cmp    $0x1,%edx
  je     L43
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L49:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L49
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L4
L7:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L4:
  ret
  nopl   0x0(%rax)
L2:
  pxor   %xmm0,%xmm0
  ret
L43:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L7
```

assistant: ```c
double scalar_product(const double *vector1, const double *vector2, int n) {
  double prod = 0;
  for (int i = 0; i < n; i++) {
    prod += vector1[i] * vector2[i];
  }
  return prod;
}
```
user: What is the c source code of the assembly code below?

```asm
<thread_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L10:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x2,-0x4(%rbp)
  jne    L26
  mov    $0x0,%edi
  call   <pthread_exit@plt>
L26:
  mov    $0x3,%edi
  call   <sleep@plt>
  addl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0x6,-0x4(%rbp)
  jle    L10
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: This is a pthread_1.


assistant: ```c
void thread_1(void) {
  int i = 0;
  for (i = 0; i <= 6; i++) {
    printf("This is a pthread_1.\n");
    if (i == 2)
      pthread_exit(0);
    sleep(3);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread_1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D0(%rip),%rbp
  jmp    L15
L5:
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
L19:
  add    $0x1,%ebx
L15:
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  je     L5
  mov    $0x3,%edi
  call   <sleep@plt>
  cmp    $0x6,%ebx
  jle    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: This is a pthread_1.


assistant: ```c
void thread_1(void) {
  int i = 0;
  for (i = 0; i <= 6; i++) {
    printf("This is a pthread_1.\n");
    if (i == 2)
      pthread_exit(0);
    sleep(3);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thread_1>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x3,%ebx
  je     L14
  mov    $0x3,%edi
  call   <sleep@plt>
  cmp    $0x7,%ebx
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L14:
  xor    %edi,%edi
  call   <pthread_exit@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D2: This is a pthread_1.


assistant: ```c
void thread_1(void) {
  int i = 0;
  for (i = 0; i <= 6; i++) {
    printf("This is a pthread_1.\n");
    if (i == 2)
      pthread_exit(0);
    sleep(3);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread_1>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x3,%ebx
  je     L19
  mov    $0x3,%edi
  call   <sleep@plt>
  cmp    $0x7,%ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L19:
  xor    %edi,%edi
  call   <pthread_exit@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: This is a pthread_1.


assistant: ```c
void thread_1(void) {
  int i = 0;
  for (i = 0; i <= 6; i++) {
    printf("This is a pthread_1.\n");
    if (i == 2)
      pthread_exit(0);
    sleep(3);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mul_matrices_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L52:
  movl   $0x0,-0x8(%rbp)
  jmp    L46
L10:
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L22:
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L22
  addl   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L10
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L52
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mul_matrices_(const double *A, int na1, int na2, const double *B, int nb1, int nb2, double *C) {
  int i, j, k;
  for (i = 0; i < na1; i++) {
    for (j = 0; j < nb2; j++) {
      C[i * na2 + j] = 0.0;
      for (k = 0; k < na2; k++) {
        C[i * na2 + j] += A[i * na2 + k] * B[k * nb2 + j];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mul_matrices_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x18(%rsp)
  mov    %rcx,-0x10(%rsp)
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rax
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    %r9d,%ebp
  movslq %r9d,%rdi
  shl    $0x3,%rdi
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    -0x1(%rdx),%esi
  mov    %rsi,-0x8(%rsp)
  lea    0x8(%rax),%r15
  jmp    L23
L18:
  movslq %r14d,%rax
  lea    0x0(,%rax,8),%r11
  mov    %r11,%r8
  add    0x38(%rsp),%r8
  mov    -0x10(%rsp),%r10
  add    -0x18(%rsp),%r11
  add    -0x8(%rsp),%rax
  lea    (%r15,%rax,8),%rsi
  mov    $0x0,%r9d
L12:
  mov    %r8,%rcx
  movq   $0x0,(%r8)
  test   %ebx,%ebx
  jle    L78
  mov    %r10,%rdx
  mov    %r11,%rax
L55:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  add    %rdi,%rdx
  cmp    %rsi,%rax
  jne    L55
L78:
  add    $0x1,%r9d
  add    $0x8,%r8
  add    $0x8,%r10
  cmp    %r9d,%ebp
  jne    L12
L1:
  add    $0x1,%r13d
  add    %ebx,%r14d
  cmp    %r13d,%r12d
  je     L16
L23:
  test   %ebp,%ebp
  jg     L18
  jmp    L1
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mul_matrices_(const double *A, int na1, int na2, const double *B, int nb1, int nb2, double *C) {
  int i, j, k;
  for (i = 0; i < na1; i++) {
    for (j = 0; j < nb2; j++) {
      C[i * na2 + j] = 0.0;
      for (k = 0; k < na2; k++) {
        C[i * na2 + j] += A[i * na2 + k] * B[k * nb2 + j];
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mul_matrices_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,-0xc(%rsp)
  mov    %rcx,-0x8(%rsp)
  test   %esi,%esi
  jle    L44
  mov    %rdi,%rbp
  movslq %r9d,%rdi
  mov    %edx,%r11d
  mov    %r9d,%ebx
  shl    $0x3,%rdi
  xor    %r13d,%r13d
  lea    -0x1(%rdx),%r15d
  xor    %r12d,%r12d
  lea    0x8(%rbp),%r14
  pxor   %xmm2,%xmm2
  nopl   0x0(%rax)
L1:
  test   %ebx,%ebx
  jle    L50
  movslq %r13d,%rax
  mov    0x38(%rsp),%rcx
  mov    -0x8(%rsp),%r9
  xor    %r8d,%r8d
  lea    0x0(,%rax,8),%r10
  add    %r15,%rax
  add    %r10,%rcx
  lea    (%r14,%rax,8),%rsi
  add    %rbp,%r10
  nopl   0x0(%rax)
L34:
  movq   $0x0,(%rcx)
  mov    %r9,%rdx
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  test   %r11d,%r11d
  jle    L13
  xchg   %ax,%ax
L30:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rsi
  jne    L30
L13:
  add    $0x1,%r8d
  add    $0x8,%rcx
  add    $0x8,%r9
  cmp    %r8d,%ebx
  jne    L34
L50:
  add    $0x1,%r12d
  add    %r11d,%r13d
  cmp    %r12d,-0xc(%rsp)
  jne    L1
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mul_matrices_(const double *A, int na1, int na2, const double *B, int nb1, int nb2, double *C) {
  int i, j, k;
  for (i = 0; i < na1; i++) {
    for (j = 0; j < nb2; j++) {
      C[i * na2 + j] = 0.0;
      for (k = 0; k < na2; k++) {
        C[i * na2 + j] += A[i * na2 + k] * B[k * nb2 + j];
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mul_matrices_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,-0x8(%rsp)
  test   %esi,%esi
  jle    L6
  mov    %r9d,%r11d
  test   %r9d,%r9d
  jle    L6
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r10
  mov    %esi,%r12d
  movslq %edx,%r15
  lea    0x8(%rdi,%rax,8),%rsi
  movslq %r9d,%rdi
  mov    %edx,%ebx
  xor    %r13d,%r13d
  lea    0x0(,%r15,8),%r14
  shl    $0x3,%rdi
  pxor   %xmm2,%xmm2
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L24:
  mov    0x38(%rsp),%rax
  mov    -0x8(%rsp),%r9
  xor    %r8d,%r8d
  lea    (%rax,%r13,8),%rcx
  nopl   0x0(%rax)
L11:
  movq   $0x0,(%rcx)
  mov    %r9,%rdx
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  test   %ebx,%ebx
  jle    L35
  nopl   (%rax)
L48:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rsi,%rax
  jne    L48
L35:
  add    $0x1,%r8d
  add    $0x8,%rcx
  add    $0x8,%r9
  cmp    %r8d,%r11d
  jne    L11
  add    $0x1,%ebp
  add    %r14,%r10
  add    %r14,%rsi
  add    %r15,%r13
  cmp    %ebp,%r12d
  jne    L24
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mul_matrices_(const double *A, int na1, int na2, const double *B, int nb1, int nb2, double *C) {
  int i, j, k;
  for (i = 0; i < na1; i++) {
    for (j = 0; j < nb2; j++) {
      C[i * na2 + j] = 0.0;
      for (k = 0; k < na2; k++) {
        C[i * na2 + j] += A[i * na2 + k] * B[k * nb2 + j];
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<file_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x3ff,-0x8(%rbp)
  jg     L24
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  js     L50
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movq   %xmm2,%rax
  jmp    L69
L50:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  movq   %xmm0,%rax
L69:
  mov    -0x10(%rbp),%rcx
  movq   %rax,%xmm0
  lea    D46(%rip),%rax
  mov    %rax,%rdx
  mov    $0x8,%esi
  mov    %rcx,%rdi
  call   <snprintf@plt>
  jmp    L19
L24:
  cmpq   $0xfffff,-0x8(%rbp)
  jg     L3
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x8(%rbp),%xmm0
  movsd  D2(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rdx
  mov    -0x10(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D0(%rip),%rdx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L19
L3:
  cmpq   $0x3fffffff,-0x8(%rbp)
  jg     L12
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x8(%rbp),%xmm0
  movsd  D50(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rdx
  mov    -0x10(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D9(%rip),%rdx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L19
L12:
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x8(%rbp),%xmm0
  movsd  D25(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rdx
  mov    -0x10(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D63(%rip),%rdx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
L19:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D2
data_type: f64
name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D50
data_type: byte[8]
name: unpack_data
arguments: tag: D9
data_type: string
name: unpack_data
arguments: tag: D25
data_type: byte[8]
name: unpack_data
arguments: tag: D63
data_type: string

tool: D46: %luB

tool: D2: 1024

tool: D0: %.1fK

tool: {"D50": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x41]}

tool: D9: %.1fM

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x41]}

tool: D63: %.1fG

assistant: ```c
char *file_size(long long size, char *str) {
  if (size < 1024) {
    snprintf(str, sizeof(str), "%luB", (unsigned long)size);
  } else if (size < 0x100000) {
    snprintf(str, sizeof(str), "%.1fK", (double)size / 1024.0);
  } else if (size < 0x40000000) {
    snprintf(str, sizeof(str), "%.1fM", (double)size / 1048576);
  } else {
    snprintf(str, sizeof(str), "%.1fG", (double)size / 1073741824);
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<file_size>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3ff,%rdi
  jle    L28
  cmp    $0xfffff,%rdi
  jle    L36
  cmp    $0x3fffffff,%rdi
  jg     L25
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  mulsd  D44(%rip),%xmm0
  lea    D63(%rip),%rdx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  jmp    L50
L28:
  test   %rdi,%rdi
  js     L17
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L15:
  lea    D5(%rip),%rdx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
L50:
  mov    %rbx,%rax
  pop    %rbx
  ret
L17:
  mov    %rdi,%rax
  shr    %rax
  and    $0x1,%edi
  or     %rdi,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L15
L36:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  mulsd  D68(%rip),%xmm0
  lea    D0(%rip),%rdx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  jmp    L50
L25:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  mulsd  D43(%rip),%xmm0
  lea    D7(%rip),%rdx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  jmp    L50
```

tool_calls: name: read_data
arguments: label: D44
type_infered: byte[8]
name: read_data
arguments: label: D63
type_infered: string
name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D68
type_infered: byte[8]
name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D43
type_infered: byte[8]
name: read_data
arguments: label: D7
type_infered: string

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0xb0,0x3e]}

tool: D63: %.1fM

tool: D5: %luB

tool: {"D68": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D0: %.1fK

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: D7: %.1fG

assistant: ```c
char *file_size(long long size, char *str) {
  if (size < 1024) {
    snprintf(str, sizeof(str), "%luB", (unsigned long)size);
  } else if (size < 0x100000) {
    snprintf(str, sizeof(str), "%.1fK", (double)size / 1024.0);
  } else if (size < 0x40000000) {
    snprintf(str, sizeof(str), "%.1fM", (double)size / 1048576);
  } else {
    snprintf(str, sizeof(str), "%.1fG", (double)size / 1073741824);
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_size>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  cmp    $0x3ff,%rdi
  jle    L37
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  cmp    $0xfffff,%rdi
  jle    L10
  cmp    $0x3fffffff,%rdi
  jg     L1
  mulsd  D22(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x8,%esi
  lea    D1(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L10:
  mulsd  D4(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x8,%esi
  lea    D2(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  test   %rdi,%rdi
  js     L41
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L20:
  mov    %r12,%rdi
  lea    D29(%rip),%rdx
  mov    $0x8,%esi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
L1:
  mulsd  D47(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x8,%esi
  lea    D52(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L20
```

tool_calls: name: read_data
arguments: data_tag: D22
type_infered: byte[8]
name: read_data
arguments: data_tag: D1
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: byte[8]
name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D29
type_infered: string
name: read_data
arguments: data_tag: D47
type_infered: byte[8]
name: read_data
arguments: data_tag: D52
type_infered: string

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0xb0,0x3e]}

tool: D1: %.1fM

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D2: %.1fK

tool: D29: %luB

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: D52: %.1fG

assistant: ```c
char *file_size(long long size, char *str) {
  if (size < 1024) {
    snprintf(str, sizeof(str), "%luB", (unsigned long)size);
  } else if (size < 0x100000) {
    snprintf(str, sizeof(str), "%.1fK", (double)size / 1024.0);
  } else if (size < 0x40000000) {
    snprintf(str, sizeof(str), "%.1fM", (double)size / 1048576);
  } else {
    snprintf(str, sizeof(str), "%.1fG", (double)size / 1073741824);
  }
  return str;
}
```