user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hybrid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rsi,%rax
  sub    %rdi,%rax
  sar    $0x2,%rax
  add    $0x1,%eax
  cmp    $0x34,%eax
  jg     L45
L125:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%rbx
  mov    %rsi,%rdx
  mov    %rbx,%rsi
  call   <sort3@plt>
  lea    -0x4(%r14),%r15
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <stack_swap@plt>
  mov    -0x4(%r14),%ebp
  mov    %r15,0x8(%rsp)
  mov    %r12,0x10(%rsp)
  mov    %r15,%rbx
  mov    %r12,%r14
  jmp    L13
L35:
  cmp    %rbx,%r13
  jae    L140
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <stack_swap@plt>
  cmp    %ebp,0x0(%r13)
  je     L110
L111:
  cmp    %ebp,(%rbx)
  je     L107
L80:
  mov    %r13,%r14
L13:
  lea    0x4(%r14),%r13
  cmp    %ebp,0x4(%r14)
  jl     L80
L157:
  sub    $0x4,%rbx
  cmp    %ebp,(%rbx)
  jle    L35
  cmp    %rbx,%r12
  jne    L157
  jmp    L35
L110:
  addq   $0x4,0x10(%rsp)
  mov    0x10(%rsp),%rax
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <stack_swap@plt>
  jmp    L111
L107:
  subq   $0x4,0x8(%rsp)
  mov    0x8(%rsp),%rax
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <stack_swap@plt>
  jmp    L80
L140:
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <stack_swap@plt>
  lea    0x8(%r14),%r13
  cmp    %r12,0x10(%rsp)
  jbe    L145
  mov    %r14,%rbp
  mov    %r12,%rbx
L16:
  mov    %rbp,%rsi
  sub    $0x4,%rbp
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <stack_swap@plt>
  cmp    %rbx,0x10(%rsp)
  ja     L16
  mov    %r12,%rax
  sub    0x10(%rsp),%rax
  and    $0xfffffffffffffffc,%rax
  add    %rax,%r14
L145:
  cmp    0x8(%rsp),%r15
  jbe    L167
  mov    %r13,%rbx
L166:
  mov    %rbx,%rsi
  add    $0x4,%rbx
  mov    %r15,%rdi
  sub    $0x4,%r15
  call   <stack_swap@plt>
  cmp    %r15,0x8(%rsp)
  jb     L166
  mov    0x18(%rsp),%rax
  sub    $0x5,%rax
  sub    0x8(%rsp),%rax
  shr    $0x2,%rax
  lea    0x4(%r13,%rax,4),%r13
L167:
  mov    0x18(%rsp),%rbx
  mov    (%rbx),%eax
  cmp    %eax,(%r12)
  je     L125
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <hybrid>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <hybrid>
  jmp    L125
```

assistant: ```c
void hybrid(int *start, int *end) {
  int *left;
  int *mid;
  int *right;
  int *inner;
  int *outer;
  int n;
  int pivot;
  n = end - start + 1;
  if (n < 53)
    return;
  mid = start + (n / 2);
  sort3(start, mid, end);
  stack_swap(mid, end - 1);
  pivot = *(end - 1);
  inner = left = start;
  outer = right = end - 1;
  while (1) {
    while (*(++left) < pivot)
      ;
    while (*(--right) > pivot)
      if (right == start)
        break;
    if (left >= right)
      break;
    stack_swap(left, right);
    if (*left == pivot)
      stack_swap(++inner, left);
    if (*right == pivot)
      stack_swap(--outer, right);
  }
  stack_swap(left, end - 1);
  right = left++ - 1;
  for (mid = start; mid < inner;)
    stack_swap(mid++, right--);
  for (mid = end - 1; mid > outer;)
    stack_swap(mid--, left++);
  if (*start == *end)
    return;
  hybrid(start, right);
  hybrid(left, end);
}
```