ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x7,%eax
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void *ptr;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!(ptr = malloc(size)))
    errno = ENOMEM;
  ;
  return (ptr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x1,%edi
  call   <assert@plt>
  cmp    $0x7,%ebx
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    D12(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D3(%rip),%rdx
  mov    %ecx,(%rdx)
  jmp    L14
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void *ptr;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!(ptr = malloc(size)))
    errno = ENOMEM;
  ;
  return (ptr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebp
  seta   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    D6(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D4(%rip),%rdx
  mov    %ecx,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void *ptr;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!(ptr = malloc(size)))
    errno = ENOMEM;
  ;
  return (ptr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebp
  seta   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    D7(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D4(%rip),%rdx
  mov    %ecx,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void *ptr;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!(ptr = malloc(size)))
    errno = ENOMEM;
  ;
  return (ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%esi
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  sub    %eax,%esi
  mov    %esi,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void decrypt(char arr[], int key) {
  int i;
  for (i = 0; i < strlen(arr); i++) {
    arr[i] = arr[i] - key % 26;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<decrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  movslq %esi,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x23,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%r12d
  mov    $0x0,%ebx
  jmp    L18
L15:
  sub    %r12b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decrypt(char arr[], int key) {
  int i;
  for (i = 0; i < strlen(arr); i++) {
    arr[i] = arr[i] - key % 26;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<decrypt>:
  endbr64
  movslq %esi,%rax
  push   %r12
  mov    %rax,%r12
  imul   $0x4ec4ec4f,%rax,%rax
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edx
  push   %rbx
  xor    %ebx,%ebx
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%r12d
  jmp    L13
  xchg   %ax,%ax
L15:
  sub    %r12b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decrypt(char arr[], int key) {
  int i;
  for (i = 0; i < strlen(arr); i++) {
    arr[i] = arr[i] - key % 26;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<decrypt>:
  endbr64
  movslq %esi,%rax
  push   %r12
  mov    %rax,%r12
  imul   $0x4ec4ec4f,%rax,%rax
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edx
  push   %rbx
  xor    %ebx,%ebx
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%r12d
  jmp    L1
  xchg   %ax,%ax
L11:
  sub    %r12b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decrypt(char arr[], int key) {
  int i;
  for (i = 0; i < strlen(arr); i++) {
    arr[i] = arr[i] - key % 26;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L10:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  jne    L14
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x3,%eax
  jne    L14
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  cmp    $0x2,%edx
  jne    L14
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L10
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: [%i, %i]


assistant: ```c
int fun(int n) {
  int j = 0, i = n + 1;
  while (i--) {
    if (i % 3 == 2 && i % 5 == 3 && i % 7 == 2)
      ++j;
  }
  printf("[%i, %i]\n", n, j);
  return j;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fun>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  cmp    $0xffffffff,%edi
  je     L26
  mov    %edi,%edx
  mov    $0x0,%ebx
  jmp    L46
L29:
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  je     L52
L46:
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  jne    L29
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x3,%eax
  jne    L29
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  jmp    L29
L26:
  mov    $0x0,%ebx
L52:
  mov    %ebx,%edx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7: [%i, %i]


assistant: ```c
int fun(int n) {
  int j = 0, i = n + 1;
  while (i--) {
    if (i % 3 == 2 && i % 5 == 3 && i % 7 == 2)
      ++j;
  }
  printf("[%i, %i]\n", n, j);
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fun>:
  endbr64
  push   %r12
  mov    %edi,%r8d
  cmp    $0xffffffff,%edi
  je     L26
  mov    %edi,%edx
  xor    %r12d,%r12d
  jmp    L22
  nopl   0x0(%rax)
L36:
  sub    $0x1,%edx
  jb     L7
L22:
  movslq %edx,%rcx
  mov    %edx,%esi
  imul   $0x55555556,%rcx,%rax
  sar    $0x1f,%esi
  shr    $0x20,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,2),%edi
  mov    %edx,%eax
  sub    %edi,%eax
  cmp    $0x2,%eax
  jne    L36
  imul   $0x66666667,%rcx,%rax
  sar    $0x21,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  mov    %edx,%eax
  sub    %edi,%eax
  cmp    $0x3,%eax
  jne    L36
  imul   $0xffffffff92492493,%rcx,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sub    %esi,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  sub    $0x1,%edx
  jae    L22
L7:
  mov    %r12d,%edx
  mov    %r8d,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %r12d,%r12d
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: [%i, %i]


assistant: ```c
int fun(int n) {
  int j = 0, i = n + 1;
  while (i--) {
    if (i % 3 == 2 && i % 5 == 3 && i % 7 == 2)
      ++j;
  }
  printf("[%i, %i]\n", n, j);
  return j;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
L0:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string
name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D4: sleep 3

tool: D1: Tiempo= %d seg.


assistant: ```c
main() {
  int tid;
  time_t t1, t2;
#pragma omp parallel private(tid, t1, t2)
  {
    tid = 0;
    if (tid < 1 / 2)
      system("sleep 3");
    t1 = time(NULL);
#pragma omp barrier
    t2 = time(NULL) - t1;
    printf("Tiempo= %d seg.\n", (int)t2);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%esi
  sub    %ebx,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Tiempo= %d seg.


assistant: ```c
main() {
  int tid;
  time_t t1, t2;
#pragma omp parallel private(tid, t1, t2)
  {
    tid = 0;
    if (tid < 1 / 2)
      system("sleep 3");
    t1 = time(NULL);
#pragma omp barrier
    t2 = time(NULL) - t1;
    printf("Tiempo= %d seg.\n", (int)t2);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  call   <time@plt>
  xor    %edi,%edi
  mov    %rax,%rbx
  call   <time@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  sub    %ebx,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: Tiempo= %d seg.


assistant: ```c
main() {
  int tid;
  time_t t1, t2;
#pragma omp parallel private(tid, t1, t2)
  {
    tid = 0;
    if (tid < 1 / 2)
      system("sleep 3");
    t1 = time(NULL);
#pragma omp barrier
    t2 = time(NULL) - t1;
    printf("Tiempo= %d seg.\n", (int)t2);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  call   <time@plt>
  xor    %edi,%edi
  mov    %rax,%rbx
  call   <time@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  sub    %ebx,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: Tiempo= %d seg.


assistant: ```c
main() {
  int tid;
  time_t t1, t2;
#pragma omp parallel private(tid, t1, t2)
  {
    tid = 0;
    if (tid < 1 / 2)
      system("sleep 3");
    t1 = time(NULL);
#pragma omp barrier
    t2 = time(NULL) - t1;
    printf("Tiempo= %d seg.\n", (int)t2);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<execute_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %esi,-0xa8(%rbp)
  mov    %edx,-0xac(%rbp)
  mov    %ecx,-0xb0(%rbp)
  mov    %r8d,-0xb4(%rbp)
  mov    %r9d,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x0,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x0,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x30010,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x1c,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x1c,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xa8(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xac(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xb0(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xb4(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xb8(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    0x10(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    0x18(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x0,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,-0x90(%rbp)
  lea    -0x90(%rbp),%rdx
  mov    -0xa4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mbox_property@plt>
  mov    -0x7c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
unsigned int execute_code(int file_desc, unsigned int code, unsigned int r0, unsigned int r1, unsigned int r2, unsigned int r3, unsigned int r4, unsigned int r5) {
  int i = 0;
  unsigned int p[32];
  p[i++] = 0;
  p[i++] = 0x00000000;
  p[i++] = 0x30010;
  p[i++] = 28;
  p[i++] = 28;
  p[i++] = code;
  p[i++] = r0;
  p[i++] = r1;
  p[i++] = r2;
  p[i++] = r3;
  p[i++] = r4;
  p[i++] = r5;
  p[i++] = 0x00000000;
  p[0] = i * sizeof *p;
  mbox_property(file_desc, p);
  return p[5];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<execute_code>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x30010,0x8(%rsp)
  movl   $0x1c,0xc(%rsp)
  movl   $0x1c,0x10(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0x18(%rsp)
  mov    %ecx,0x1c(%rsp)
  mov    %r8d,0x20(%rsp)
  mov    %r9d,0x24(%rsp)
  mov    0xa0(%rsp),%eax
  mov    %eax,0x28(%rsp)
  mov    0xa8(%rsp),%eax
  mov    %eax,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x34,(%rsp)
  mov    %rsp,%rsi
  call   <mbox_property@plt>
  mov    0x14(%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x98,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int execute_code(int file_desc, unsigned int code, unsigned int r0, unsigned int r1, unsigned int r2, unsigned int r3, unsigned int r4, unsigned int r5) {
  int i = 0;
  unsigned int p[32];
  p[i++] = 0;
  p[i++] = 0x00000000;
  p[i++] = 0x30010;
  p[i++] = 28;
  p[i++] = 28;
  p[i++] = code;
  p[i++] = r0;
  p[i++] = r1;
  p[i++] = r2;
  p[i++] = r3;
  p[i++] = r4;
  p[i++] = r5;
  p[i++] = 0x00000000;
  p[0] = i * sizeof *p;
  mbox_property(file_desc, p);
  return p[5];
}
```
user: What is the c source code of the assembly code below?

```asm
<execute_code>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    0xa0(%rsp),%eax
  mov    %esi,0x14(%rsp)
  mov    %rsp,%rsi
  mov    %edx,0x18(%rsp)
  mov    %eax,0x28(%rsp)
  mov    0xa8(%rsp),%eax
  mov    %ecx,0x1c(%rsp)
  mov    %eax,0x2c(%rsp)
  movabs $0x1c00030010,%rax
  mov    %r8d,0x20(%rsp)
  mov    %r9d,0x24(%rsp)
  movl   $0x0,0x30(%rsp)
  movq   $0x34,(%rsp)
  mov    %rax,0x8(%rsp)
  movl   $0x1c,0x10(%rsp)
  call   <mbox_property@plt>
  mov    0x14(%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x98,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int execute_code(int file_desc, unsigned int code, unsigned int r0, unsigned int r1, unsigned int r2, unsigned int r3, unsigned int r4, unsigned int r5) {
  int i = 0;
  unsigned int p[32];
  p[i++] = 0;
  p[i++] = 0x00000000;
  p[i++] = 0x30010;
  p[i++] = 28;
  p[i++] = 28;
  p[i++] = code;
  p[i++] = r0;
  p[i++] = r1;
  p[i++] = r2;
  p[i++] = r3;
  p[i++] = r4;
  p[i++] = r5;
  p[i++] = 0x00000000;
  p[0] = i * sizeof *p;
  mbox_property(file_desc, p);
  return p[5];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<execute_code>:
  endbr64
  movd   %ecx,%xmm1
  movd   %r8d,%xmm2
  movd   %esi,%xmm0
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movd   %edx,%xmm3
  punpckldq %xmm2,%xmm1
  mov    %rsp,%rsi
  punpckldq %xmm3,%xmm0
  mov    0xa8(%rsp),%eax
  movd   0xa0(%rsp),%xmm4
  movl   $0x1c,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  movl   $0x0,0x30(%rsp)
  movups %xmm0,0x14(%rsp)
  movd   %r9d,%xmm0
  punpckldq %xmm4,%xmm0
  mov    %eax,0x2c(%rsp)
  movq   %xmm0,0x24(%rsp)
  movdqa D0(%rip),%xmm0
  movaps %xmm0,(%rsp)
  call   <mbox_property@plt>
  mov    0x14(%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x98,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: byte[16]

tool: {"D0": [0x34,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x00,0x03,0x00,0x1c,0x00,0x00,0x00]}

assistant: ```c
unsigned int execute_code(int file_desc, unsigned int code, unsigned int r0, unsigned int r1, unsigned int r2, unsigned int r3, unsigned int r4, unsigned int r5) {
  int i = 0;
  unsigned int p[32];
  p[i++] = 0;
  p[i++] = 0x00000000;
  p[i++] = 0x30010;
  p[i++] = 28;
  p[i++] = 28;
  p[i++] = code;
  p[i++] = r0;
  p[i++] = r1;
  p[i++] = r2;
  p[i++] = r3;
  p[i++] = r4;
  p[i++] = r5;
  p[i++] = 0x00000000;
  p[0] = i * sizeof *p;
  mbox_property(file_desc, p);
  return p[5];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_caesar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L36:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L21:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L22
  orq    $0x0,-0x8(%rsp,%rax,1)
L22:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <caesar@plt>
  lea    D6(%rip),%r14
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13d,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D46
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D39
type: string

tool: D6: -------------------

tool: D10: Shift: %d


tool: D46: Input: %s


tool: D15: Expected: %s


tool: D39: Result: %s


assistant: ```c
void test_caesar(char *input, char *expected, int shift) {
  char result[strlen(expected)];
  caesar(result, input, shift);
  if (1) {
    printf("-------------------\n");
    printf("Shift: %d\n", shift);
    printf("Input: %s\n", input);
    printf("Expected: %s\n", expected);
    printf("Result: %s\n", result);
    printf("-------------------\n");
  }
  assert(strcmp(result, expected) == 0);
}
```