ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<int_copy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    (%rbx),%edx
  mov    %edx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void *int_copy(void *to_copy) {
  int *i = (int *)calloc(1, sizeof(int));
  *i = *(int *)to_copy;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<int_copy>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    (%rbx),%edx
  mov    %edx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void *int_copy(void *to_copy) {
  int *i = (int *)calloc(1, sizeof(int));
  *i = *(int *)to_copy;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int_copy>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    (%rbx),%edx
  mov    %edx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void *int_copy(void *to_copy) {
  int *i = (int *)calloc(1, sizeof(int));
  *i = *(int *)to_copy;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_numeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L41:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L18
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L42
L18:
  mov    $0x0,%eax
  jmp    L11
L42:
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L41
  mov    $0x1,%eax
L11:
  leave
  ret
```

assistant: ```c
int is_numeric(const char *string) {
  unsigned int i;
  unsigned int l;
  l = strlen(string);
  for (i = 0; i < l; i++) {
    if ((string[i] < '0') || (string[i] > '9')) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_numeric>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L5
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rcx
L22:
  movzbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L6
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L22
  mov    $0x1,%eax
  jmp    L49
L5:
  mov    $0x1,%eax
  jmp    L49
L6:
  mov    $0x0,%eax
L49:
  pop    %rbx
  ret
```

assistant: ```c
int is_numeric(const char *string) {
  unsigned int i;
  unsigned int l;
  l = strlen(string);
  for (i = 0; i < l; i++) {
    if ((string[i] < '0') || (string[i] > '9')) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_numeric>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L16
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rdx
  jmp    L21
  xchg   %ax,%ax
L34:
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  je     L16
L21:
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L34
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_numeric(const char *string) {
  unsigned int i;
  unsigned int l;
  l = strlen(string);
  for (i = 0; i < l; i++) {
    if ((string[i] < '0') || (string[i] > '9')) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_numeric>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L6
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rdx
  jmp    L13
  xchg   %ax,%ax
L4:
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  je     L6
L13:
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L4
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_numeric(const char *string) {
  unsigned int i;
  unsigned int l;
  l = strlen(string);
  for (i = 0; i < l; i++) {
    if ((string[i] < '0') || (string[i] > '9')) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kth_element_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <kth_element@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double kth_element_copy(int n, int k, double *arr) {
  double *arr_copy = (double *)malloc(sizeof(double) * n);
  double kth_best;
  memcpy(arr_copy, arr, sizeof(double) * n);
  kth_best = kth_element(n, k, arr_copy);
  free(arr_copy);
  return kth_best;
}
```
user: What is the c source code of the assembly code below?

```asm
<kth_element_copy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %rdx,%r13
  lea    0x0(,%rdi,8),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <kth_element@plt>
  movq   %xmm0,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  movq   %rbp,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double kth_element_copy(int n, int k, double *arr) {
  double *arr_copy = (double *)malloc(sizeof(double) * n);
  double kth_best;
  memcpy(arr_copy, arr, sizeof(double) * n);
  kth_best = kth_element(n, k, arr_copy);
  free(arr_copy);
  return kth_best;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kth_element_copy>:
  endbr64
  push   %r15
  lea    0x0(,%rdi,8),%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r15d,%edi
  push   %rbp
  sub    $0x10,%rsp
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <kth_element@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double kth_element_copy(int n, int k, double *arr) {
  double *arr_copy = (double *)malloc(sizeof(double) * n);
  double kth_best;
  memcpy(arr_copy, arr, sizeof(double) * n);
  kth_best = kth_element(n, k, arr_copy);
  free(arr_copy);
  return kth_best;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kth_element_copy>:
  endbr64
  push   %r15
  lea    0x0(,%rdi,8),%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r15d,%edi
  push   %rbp
  sub    $0x10,%rsp
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <kth_element@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double kth_element_copy(int n, int k, double *arr) {
  double *arr_copy = (double *)malloc(sizeof(double) * n);
  double kth_best;
  memcpy(arr_copy, arr, sizeof(double) * n);
  kth_best = kth_element(n, k, arr_copy);
  free(arr_copy);
  return kth_best;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int x = {{{1}}};
  int y = 2, k = 3;
  return x + y + k;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
main() {
  int x = {{{1}}};
  int y = 2, k = 3;
  return x + y + k;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
main() {
  int x = {{{1}}};
  int y = 2, k = 3;
  return x + y + k;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
main() {
  int x = {{{1}}};
  int y = 2, k = 3;
  return x + y + k;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<iresort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L72:
  cmp    %rdx,%rsp
  je     L94
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L72
L94:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L2
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L2:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L79
L29:
  mov    -0x34(%rbp),%eax
  imul   -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    -0x34(%rbp),%edx
  add    %edx,%edx
  movss  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  movss  %xmm0,(%rax,%rdx,4)
  addl   $0x1,-0x34(%rbp)
L79:
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <num_scale@plt>
  cmp    %eax,-0x34(%rbp)
  jl     L29
  movl   $0x0,-0x30(%rbp)
  jmp    L57
L18:
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <num_scale@plt>
  mov    -0x30(%rbp),%edx
  add    %edx,%eax
  imul   -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%edx
  add    %edx,%edx
  add    $0x1,%edx
  movss  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  movss  %xmm0,(%rax,%rdx,4)
  addl   $0x1,-0x30(%rbp)
L57:
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <num_coeff@plt>
  cmp    %eax,-0x30(%rbp)
  jl     L18
  movl   $0x0,-0x2c(%rbp)
  jmp    L42
L69:
  mov    -0x2c(%rbp),%eax
  imul   -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  movss  (%rax,%rdx,4),%xmm0
  movss  %xmm0,(%rcx)
  addl   $0x1,-0x2c(%rbp)
L42:
  mov    -0x2c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L69
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void iresort(int n, int str, float *src) {
  float tmp[n];
  for (int i = 0; i < num_scale(n); i++)
    tmp[i * 2 + 0] = src[i * str];
  for (int i = 0; i < num_coeff(n); i++)
    tmp[i * 2 + 1] = src[(num_scale(n) + i) * str];
  for (int i = 0; i < n; i++)
    src[i * str] = tmp[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<iresort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %esi,-0x4c(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L22:
  cmp    %rdx,%rsp
  je     L74
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L22
L74:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L6
  orq    $0x0,-0x8(%rsp,%rax,1)
L6:
  mov    %rsp,%r15
  movslq -0x4c(%rbp),%rax
  shl    $0x2,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x58(%rbp),%r14
  mov    %r14,%r13
  mov    $0x0,%r12d
  jmp    L25
L86:
  movss  (%r14),%xmm0
  movss  %xmm0,(%r15,%r12,8)
  add    $0x1,%r12
  add    -0x48(%rbp),%r14
L25:
  mov    %ebx,%edi
  call   <num_scale@plt>
  cmp    %r12d,%eax
  jg     L86
  mov    $0x0,%r12d
  jmp    L87
L29:
  mov    %ebx,%edi
  call   <num_scale@plt>
  add    %r12d,%eax
  imul   -0x4c(%rbp),%eax
  cltq
  mov    -0x58(%rbp),%rsi
  movss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,0x4(%r15,%r12,8)
  add    $0x1,%r12
L87:
  mov    %ebx,%edi
  call   <num_coeff@plt>
  cmp    %r12d,%eax
  jg     L29
  test   %ebx,%ebx
  jle    L4
  mov    %r15,%rax
  mov    %ebx,%ebx
  lea    (%r15,%rbx,4),%rdx
L82:
  movss  (%rax),%xmm0
  movss  %xmm0,0x0(%r13)
  add    $0x4,%rax
  add    -0x48(%rbp),%r13
  cmp    %rdx,%rax
  jne    L82
L4:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void iresort(int n, int str, float *src) {
  float tmp[n];
  for (int i = 0; i < num_scale(n); i++)
    tmp[i * 2 + 0] = src[i * str];
  for (int i = 0; i < num_coeff(n); i++)
    tmp[i * 2 + 1] = src[(num_scale(n) + i) * str];
  for (int i = 0; i < n; i++)
    src[i * str] = tmp[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<iresort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdx,-0x58(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L53
L5:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L5
L53:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L105
L26:
  movslq -0x4c(%rbp),%r14
  mov    -0x58(%rbp),%r15
  mov    %rsp,%rbx
  lea    0x0(,%r14,4),%rax
  mov    %r15,%r13
  xor    %r14d,%r14d
  mov    %rax,-0x48(%rbp)
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L15:
  movss  (%r15),%xmm0
  add    -0x48(%rbp),%r15
  movss  %xmm0,(%rbx,%r14,8)
  add    $0x1,%r14
L46:
  mov    %r12d,%edi
  call   <num_scale@plt>
  cmp    %r14d,%eax
  jg     L15
  xor    %r14d,%r14d
  jmp    L44
  nopl   (%rax)
L10:
  mov    %r12d,%edi
  call   <num_scale@plt>
  mov    -0x58(%rbp),%rsi
  add    %r14d,%eax
  imul   -0x4c(%rbp),%eax
  cltq
  movss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,0x4(%rbx,%r14,8)
  add    $0x1,%r14
L44:
  mov    %r12d,%edi
  call   <num_coeff@plt>
  cmp    %r14d,%eax
  jg     L10
  test   %r12d,%r12d
  jle    L64
  mov    %r12d,%r12d
  lea    (%rbx,%r12,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L109:
  movss  (%rbx),%xmm0
  add    $0x4,%rbx
  movss  %xmm0,0x0(%r13)
  add    -0x48(%rbp),%r13
  cmp    %rax,%rbx
  jne    L109
L64:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L105:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L26
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void iresort(int n, int str, float *src) {
  float tmp[n];
  for (int i = 0; i < num_scale(n); i++)
    tmp[i * 2 + 0] = src[i * str];
  for (int i = 0; i < num_coeff(n); i++)
    tmp[i * 2 + 1] = src[(num_scale(n) + i) * str];
  for (int i = 0; i < n; i++)
    src[i * str] = tmp[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<iresort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  sub    $0x38,%rsp
  mov    %esi,-0x44(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rax,-0x60(%rbp)
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L129
L51:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L51
L129:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L7
L65:
  movslq -0x44(%rbp),%r15
  mov    %r13,-0x58(%rbp)
  mov    %rsp,%r12
  xor    %r14d,%r14d
  lea    0x0(,%r15,4),%rax
  mov    %r13,%r15
  mov    %rax,-0x50(%rbp)
  jmp    L103
  nopl   0x0(%rax)
L16:
  movss  (%r15),%xmm0
  add    -0x50(%rbp),%r15
  movss  %xmm0,(%r12,%r14,8)
  add    $0x1,%r14
L103:
  mov    %ebx,%edi
  call   <num_scale@plt>
  cmp    %r14d,%eax
  jg     L16
  xor    %r14d,%r14d
  jmp    L78
  nopl   0x0(%rax)
L109:
  mov    %ebx,%edi
  call   <num_scale@plt>
  add    %r14d,%eax
  imul   -0x44(%rbp),%eax
  cltq
  movss  0x0(%r13,%rax,4),%xmm0
  movss  %xmm0,0x4(%r12,%r14,8)
  add    $0x1,%r14
L78:
  mov    %ebx,%edi
  call   <num_coeff@plt>
  cmp    %r14d,%eax
  jg     L109
  test   %ebx,%ebx
  jle    L94
  cmpl   $0x1,-0x44(%rbp)
  jne    L76
  mov    -0x60(%rbp),%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L94:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L76:
  mov    %ebx,%ebx
  lea    (%r12,%rbx,4),%rax
  xchg   %ax,%ax
L32:
  mov    -0x58(%rbp),%rsi
  movss  (%r12),%xmm0
  add    $0x4,%r12
  mov    -0x50(%rbp),%rdx
  movss  %xmm0,(%rsi)
  add    %rdx,%rsi
  mov    %rsi,-0x58(%rbp)
  cmp    %rax,%r12
  jne    L32
  jmp    L94
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void iresort(int n, int str, float *src) {
  float tmp[n];
  for (int i = 0; i < num_scale(n); i++)
    tmp[i * 2 + 0] = src[i * str];
  for (int i = 0; i < num_coeff(n); i++)
    tmp[i * 2 + 1] = src[(num_scale(n) + i) * str];
  for (int i = 0; i < n; i++)
    src[i * str] = tmp[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readWriteTerminalElement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <readCompilationEngineInput@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <writeTerminalElement@plt>
  nop
  leave
  ret
```

assistant: ```c
void readWriteTerminalElement(const int type, const char *model) {
  readCompilationEngineInput();
  writeTerminalElement(type, model);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readWriteTerminalElement>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <readCompilationEngineInput@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <writeTerminalElement@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void readWriteTerminalElement(const int type, const char *model) {
  readCompilationEngineInput();
  writeTerminalElement(type, model);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readWriteTerminalElement>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <readCompilationEngineInput@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <writeTerminalElement@plt>
```

assistant: ```c
void readWriteTerminalElement(const int type, const char *model) {
  readCompilationEngineInput();
  writeTerminalElement(type, model);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readWriteTerminalElement>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <readCompilationEngineInput@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <writeTerminalElement@plt>
```

assistant: ```c
void readWriteTerminalElement(const int type, const char *model) {
  readCompilationEngineInput();
  writeTerminalElement(type, model);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<max_dvector_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L20
L14:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L15
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L15:
  addl   $0x1,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L14
  mov    -0x30(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double max_dvector_pos(double *v, long nl, long nh, int *pos) {
  int i;
  double m = v[nl];
  int p = nl;
  for (i = nl + 1; i <= nh; i++) {
    if (v[i] > m) {
      m = v[i];
      p = i;
    }
  }
  *pos = p;
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max_dvector_pos>:
  endbr64
  movsd  (%rdi,%rsi,8),%xmm0
  mov    %esi,%r8d
  add    $0x1,%esi
  movslq %esi,%rax
  cmp    %rax,%rdx
  jge    L8
  jmp    L20
L17:
  mov    %rsi,%rax
L8:
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  cmova  %eax,%r8d
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  lea    0x1(%rax),%rsi
  cmp    %rdx,%rax
  jne    L17
L20:
  mov    %r8d,(%rcx)
  ret
```

assistant: ```c
double max_dvector_pos(double *v, long nl, long nh, int *pos) {
  int i;
  double m = v[nl];
  int p = nl;
  for (i = nl + 1; i <= nh; i++) {
    if (v[i] > m) {
      m = v[i];
      p = i;
    }
  }
  *pos = p;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<max_dvector_pos>:
  endbr64
  lea    0x1(%rsi),%eax
  movsd  (%rdi,%rsi,8),%xmm0
  mov    %esi,%r8d
  cltq
  cmp    %rax,%rdx
  jge    L9
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rsi,%rax
L9:
  movsd  (%rdi,%rax,8),%xmm1
  lea    0x1(%rax),%rsi
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L13
L3:
  mov    %r8d,(%rcx)
  ret
```

assistant: ```c
double max_dvector_pos(double *v, long nl, long nh, int *pos) {
  int i;
  double m = v[nl];
  int p = nl;
  for (i = nl + 1; i <= nh; i++) {
    if (v[i] > m) {
      m = v[i];
      p = i;
    }
  }
  *pos = p;
  return m;
}
```