ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<has_double_dots>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L53:
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L57
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L50
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L57
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L50
L57:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L51
L50:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L53
L51:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: ..

assistant: ```c
char *has_double_dots(path)
char *path;
{
  char *dots = 0;
  char *s = path;
  char *p;
  while (1) {
    p = strstr(s, "..");
    if (!p || *(p - 1) == '/' && ((*(p + 2) == '\0' || *(p + 2) == '/'))) {
      dots = p;
      break;
    }
    s = p + 2;
  }
  return dots;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<has_double_dots>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
  jmp    L45
L2:
  lea    0x2(%rax),%rdi
L45:
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L14
  cmpb   $0x2f,-0x1(%rax)
  jne    L2
  movzbl 0x2(%rax),%edx
  test   %dl,%dl
  je     L14
  cmp    $0x2f,%dl
  jne    L2
L14:
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: ..

assistant: ```c
char *has_double_dots(path)
char *path;
{
  char *dots = 0;
  char *s = path;
  char *p;
  while (1) {
    p = strstr(s, "..");
    if (!p || *(p - 1) == '/' && ((*(p + 2) == '\0' || *(p + 2) == '/'))) {
      dots = p;
      break;
    }
    s = p + 2;
  }
  return dots;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<has_double_dots>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  jmp    L37
  xchg   %ax,%ax
L47:
  lea    0x2(%rax),%rdi
L37:
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L10
  cmpb   $0x2f,-0x1(%rax)
  jne    L47
  movzbl 0x2(%rax),%edx
  test   %dl,%dl
  je     L10
  cmp    $0x2f,%dl
  jne    L47
L10:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: ..

assistant: ```c
char *has_double_dots(path)
char *path;
{
  char *dots = 0;
  char *s = path;
  char *p;
  while (1) {
    p = strstr(s, "..");
    if (!p || *(p - 1) == '/' && ((*(p + 2) == '\0' || *(p + 2) == '/'))) {
      dots = p;
      break;
    }
    s = p + 2;
  }
  return dots;
}
```
user: Translate the below assembly code into C programming language:

```asm
<has_double_dots>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  jmp    L21
  xchg   %ax,%ax
L16:
  lea    0x2(%rax),%rdi
L21:
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L18
  cmpb   $0x2f,-0x1(%rax)
  jne    L16
  movzbl 0x2(%rax),%edx
  test   %dl,%dl
  je     L18
  cmp    $0x2f,%dl
  jne    L16
L18:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: ..

assistant: ```c
char *has_double_dots(path)
char *path;
{
  char *dots = 0;
  char *s = path;
  char *p;
  while (1) {
    p = strstr(s, "..");
    if (!p || *(p - 1) == '/' && ((*(p + 2) == '\0' || *(p + 2) == '/'))) {
      dots = p;
      break;
    }
    s = p + 2;
  }
  return dots;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x1,%r12d
  mov    -0x18(%rbp),%rbx
  jmp    L1
L3:
  add    $0x1,%r12d
  add    $0x1,%rbx
L1:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L3
  mov    %r12d,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <allocate@plt>
  cltq
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *copys(s)
char *s;
{
  register int i;
  register char *cp;
  register char *result;
  i = 1;
  for (cp = s; *cp; cp++)
    i++;
  result = allocate((unsigned int)i);
  strcpy(result, s);
  return (result);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copys>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  je     L6
  mov    %rdi,%rax
  mov    $0x2,%edx
  sub    %edi,%edx
L9:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L9
L4:
  mov    $0x0,%eax
  call   <allocate@plt>
  movslq %eax,%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0x1,%edi
  jmp    L4
```

assistant: ```c
char *copys(s)
char *s;
{
  register int i;
  register char *cp;
  register char *result;
  i = 1;
  for (cp = s; *cp; cp++)
    i++;
  result = allocate((unsigned int)i);
  strcpy(result, s);
  return (result);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copys>:
  endbr64
  push   %rbp
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L6
  mov    $0x2,%edx
  mov    %rdi,%rax
  sub    %edi,%edx
  nopw   0x0(%rax,%rax,1)
L15:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L15
L21:
  xor    %eax,%eax
  call   <allocate@plt>
  mov    %rbp,%rsi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <strcpy@plt>
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%edi
  jmp    L21
```

assistant: ```c
char *copys(s)
char *s;
{
  register int i;
  register char *cp;
  register char *result;
  i = 1;
  for (cp = s; *cp; cp++)
    i++;
  result = allocate((unsigned int)i);
  strcpy(result, s);
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<copys>:
  endbr64
  push   %rbp
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L14
  mov    $0x2,%edx
  mov    %rdi,%rax
  sub    %edi,%edx
  nopw   0x0(%rax,%rax,1)
L7:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L7
L13:
  xor    %eax,%eax
  call   <allocate@plt>
  mov    %rbp,%rsi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <strcpy@plt>
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%edi
  jmp    L13
```

assistant: ```c
char *copys(s)
char *s;
{
  register int i;
  register char *cp;
  register char *result;
  i = 1;
  for (cp = s; *cp; cp++)
    i++;
  result = allocate((unsigned int)i);
  strcpy(result, s);
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ch_carrier_cycle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  add    $0x6,%eax
  mov    %eax,%edi
  call   <from_gps@plt>
  mov    %rax,-0x8(%rbp)
  shlq   $0x10,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <from_gps@plt>
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long ch_carrier_cycle(int ch) {
  long result;
  result = from_gps((ch << 3) + 6);
  result = result << 16;
  result = result + from_gps((ch << 3) + 2);
  return (result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ch_carrier_cycle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x0(,%rdi,8),%ebx
  lea    0x6(%rbx),%edi
  call   <from_gps@plt>
  shl    $0x10,%rax
  mov    %rax,%rbp
  lea    0x2(%rbx),%edi
  call   <from_gps@plt>
  add    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long ch_carrier_cycle(int ch) {
  long result;
  result = from_gps((ch << 3) + 6);
  result = result << 16;
  result = result + from_gps((ch << 3) + 2);
  return (result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ch_carrier_cycle>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0x0(,%rdi,8),%ebx
  lea    0x6(%rbx),%edi
  sub    $0x8,%rsp
  call   <from_gps@plt>
  lea    0x2(%rbx),%edi
  shl    $0x10,%rax
  mov    %rax,%rbp
  call   <from_gps@plt>
  add    $0x8,%rsp
  add    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long ch_carrier_cycle(int ch) {
  long result;
  result = from_gps((ch << 3) + 6);
  result = result << 16;
  result = result + from_gps((ch << 3) + 2);
  return (result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ch_carrier_cycle>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0x0(,%rdi,8),%ebx
  lea    0x6(%rbx),%edi
  sub    $0x8,%rsp
  call   <from_gps@plt>
  lea    0x2(%rbx),%edi
  shl    $0x10,%rax
  mov    %rax,%rbp
  call   <from_gps@plt>
  add    $0x8,%rsp
  add    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long ch_carrier_cycle(int ch) {
  long result;
  result = from_gps((ch << 3) + 6);
  result = result << 16;
  result = result + from_gps((ch << 3) + 2);
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<challenge1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <puts@plt>
  movabs $0x3032643637323934,%rax
  movabs $0x6336633639366236,%rdx
  mov    %rax,-0x80(%rbp)
  mov    %rdx,-0x78(%rbp)
  movabs $0x3032373665363936,%rax
  movabs $0x3237353766363937,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movabs $0x3136323732363032,%rax
  movabs $0x6336303265363936,%rdx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movabs $0x3032353662363936,%rax
  movabs $0x6636303730323136,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x6536663633373936,%rax
  movabs $0x3032333735376636,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x3836333735376436,%rax
  movabs $0x6436663666363237,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movb   $0x0,-0x20(%rbp)
  lea    -0x80(%rbp),%rdi
  call   <counthex@plt>
  mov    %eax,%ebx
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L35:
  cmp    %rdx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L15:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L63
  orq    $0x0,-0x8(%rsp,%rax,1)
L63:
  mov    %rsp,%r12
  lea    -0x80(%rbp),%rdi
  mov    %rsp,%rsi
  call   <str2hex@plt>
  mov    %ebx,%esi
  mov    %rsp,%rdi
  call   <printhex@plt>
  mov    %ebx,%edi
  call   <base64length@plt>
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L37:
  cmp    %rdx,%rsp
  je     L4
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L37
L4:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L2
  orq    $0x0,-0x8(%rsp,%rax,1)
L2:
  mov    %rsp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <hex2base64@plt>
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string

tool: D13: challenge 1:

tool: D16: base64 = '%s'


assistant: ```c
void challenge1() {
  printf("challenge 1:\n");
  char in[] = "49276d206b696c6c696e6720796f757220627261696e206c"
              "696b65206120706f69736f6e6f7573206d757368726f6f6d";
  int size = counthex(in);
  unsigned char hexarray[size];
  str2hex(in, hexarray);
  printhex(hexarray, size);
  char base64[base64length(size)];
  hex2base64(hexarray, size, base64);
  printf("base64 = '%s'\n", base64);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dot_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  shl    $0x2,%rax
  lea    0xf(%rax),%rcx
  mov    %rcx,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rsi
  sub    %rcx,%rsi
L2:
  cmp    %rsi,%rsp
  je     L52
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L2
L52:
  mov    %rdi,%rcx
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  je     L69
  orq    $0x0,-0x8(%rsp,%rcx,1)
L69:
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rsi
  sub    %rax,%rsi
L89:
  cmp    %rsi,%rsp
  je     L20
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L89
L20:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L101
  orq    $0x0,-0x8(%rsp,%rax,1)
L101:
  mov    %rsp,%rsi
  test   %edx,%edx
  jle    L65
  mov    %edx,%edx
  mov    $0x0,%eax
  movss  D1(%rip),%xmm0
  movaps %xmm0,%xmm2
  movss  D16(%rip),%xmm1
L100:
  movss  %xmm0,(%rcx,%rax,4)
  movss  %xmm2,(%rsi,%rax,4)
  addss  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L100
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L41:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L41
L1:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  movaps %xmm1,%xmm0
  leave
  ret
L65:
  pxor   %xmm1,%xmm1
  jmp    L1
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: f32
name: retrieve_data
arguments: data_label: D16
data_type: f32

tool: D1: 2

tool: D16: 1

assistant: ```c
float dot_product(int num_elems) {
  float a[num_elems];
  float b[num_elems];
  float init = 2.0;
  int i = 0;
  while (i < num_elems) {
    a[i] = init;
    b[i] = 2.0;
    init = init + 1.0;
    i = i + 1;
  }
  float res = 0.0;
  i = 0;
  while (i < num_elems) {
    res = res + (a[i] * b[i]);
    i = i + 1;
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dot_product>:
  endbr64
  push   %rbp
  movslq %edi,%rdx
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdx,4),%rax
  mov    %rsp,%rsi
  mov    %rax,%r8
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%r8
  and    $0xfffffffffffffff0,%rcx
  sub    %r8,%rsi
  cmp    %rsi,%rsp
  je     L30
L86:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L86
L30:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L25
L123:
  mov    %rax,%rsi
  mov    %rsp,%r8
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rsi
  cmp    %r8,%rsp
  je     L11
L96:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L96
L11:
  and    $0xfff,%esi
  sub    %rsi,%rsp
  test   %rsi,%rsi
  jne    L90
L121:
  mov    %rsp,%rsi
  test   %edi,%edi
  jle    L105
  movss  D2(%rip),%xmm1
  movss  D13(%rip),%xmm2
  xor    %eax,%eax
  movaps %xmm1,%xmm0
  nopw   0x0(%rax,%rax,1)
L2:
  movss  %xmm0,(%rcx,%rax,4)
  addss  %xmm2,%xmm0
  movss  %xmm1,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L2
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   (%rax)
L8:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rdx,%rax
  jne    L8
L115:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  leave
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L123
L105:
  pxor   %xmm1,%xmm1
  jmp    L115
L90:
  orq    $0x0,-0x8(%rsp,%rsi,1)
  jmp    L121
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: f32
name: retrieve_data
arguments: tag: D13
type_infered: f32

tool: D2: 2

tool: D13: 1

assistant: ```c
float dot_product(int num_elems) {
  float a[num_elems];
  float b[num_elems];
  float init = 2.0;
  int i = 0;
  while (i < num_elems) {
    a[i] = init;
    b[i] = 2.0;
    init = init + 1.0;
    i = i + 1;
  }
  float res = 0.0;
  i = 0;
  while (i < num_elems) {
    res = res + (a[i] * b[i]);
    i = i + 1;
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dot_product>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rdx
  sub    %rdi,%rcx
  cmp    %rcx,%rsp
  je     L90
L39:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L39
L90:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L113
L5:
  mov    %rax,%rcx
  mov    %rsp,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L50
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L4
L50:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L67
L9:
  mov    %rsp,%rcx
  test   %esi,%esi
  jle    L86
  movss  D1(%rip),%xmm1
  lea    -0x1(%rsi),%r8d
  mov    %esi,%edi
  xor    %eax,%eax
  movss  D11(%rip),%xmm2
  movaps %xmm1,%xmm0
  nopl   0x0(%rax,%rax,1)
L115:
  movss  %xmm0,(%rdx,%rax,4)
  addss  %xmm2,%xmm0
  movss  %xmm1,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L115
  cmp    $0x2,%r8d
  jbe    L146
  mov    %esi,%edi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L7:
  movups (%rdx,%rax,1),%xmm1
  movups (%rcx,%rax,1),%xmm3
  add    $0x10,%rax
  mulps  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L7
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L127
L117:
  movslq %eax,%rdi
  shl    $0x2,%rdi
  add    %rdi,%rdx
  add    %rdi,%rcx
  lea    0x1(%rax),%edi
  movss  (%rdx),%xmm1
  mulss  (%rcx),%xmm1
  addss  %xmm1,%xmm0
  cmp    %edi,%esi
  jle    L127
  movss  0x4(%rdx),%xmm1
  mulss  0x4(%rcx),%xmm1
  add    $0x2,%eax
  addss  %xmm1,%xmm0
  cmp    %eax,%esi
  jle    L127
  movss  0x8(%rcx),%xmm1
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
L127:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  leave
  ret
  nopl   0x0(%rax)
L113:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L5
L86:
  pxor   %xmm0,%xmm0
  jmp    L127
L146:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L117
L67:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L9
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: f32
name: unpack_data
arguments: label: D11
datatype: f32

tool: D1: 2

tool: D11: 1

assistant: ```c
float dot_product(int num_elems) {
  float a[num_elems];
  float b[num_elems];
  float init = 2.0;
  int i = 0;
  while (i < num_elems) {
    a[i] = init;
    b[i] = 2.0;
    init = init + 1.0;
    i = i + 1;
  }
  float res = 0.0;
  i = 0;
  while (i < num_elems) {
    res = res + (a[i] * b[i]);
    i = i + 1;
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<insertionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L47
L44:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L13
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L13:
  cmpl   $0x0,-0x8(%rbp)
  js     L17
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L3
L17:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L44
  nop
  nop
  leave
  ret
```

assistant: ```c
void insertionSort(int *as, int n) {
  int i, j, k;
  int key;
  printArray(as, n);
  for (i = 1; i < n; i++) {
    key = as[i];
    j = i - 1;
    while (j >= 0 && as[j] > key) {
      as[j + 1] = as[j];
      j--;
    }
    as[j + 1] = key;
    printArray(as, n);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertionSort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <printArray@plt>
  cmp    $0x1,%r12d
  jle    L12
  lea    -0x1(%r12),%r13d
  mov    $0x0,%ebx
  jmp    L17
L24:
  movslq %edx,%rdx
  mov    %esi,0x4(%rbp,%rdx,4)
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L12
L17:
  mov    0x4(%rbp,%rbx,4),%esi
  mov    %ebx,%edx
  test   %ebx,%ebx
  js     L24
  lea    0x0(%rbp,%rbx,4),%rax
L1:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L24
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L1
  jmp    L24
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void insertionSort(int *as, int n) {
  int i, j, k;
  int key;
  printArray(as, n);
  for (i = 1; i < n; i++) {
    key = as[i];
    j = i - 1;
    while (j >= 0 && as[j] > key) {
      as[j + 1] = as[j];
      j--;
    }
    as[j + 1] = key;
    printArray(as, n);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<insertionSort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <printArray@plt>
  cmp    $0x1,%ebp
  jle    L42
  lea    -0x1(%rbp),%r12d
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L21:
  mov    0x4(%rbx,%r13,4),%esi
  mov    %r13,%rax
L11:
  mov    (%rbx,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L0
  mov    %edx,0x4(%rbx,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L11
  mov    %rbx,%rax
L15:
  mov    %esi,(%rax)
  mov    %rbx,%rdi
  mov    %ebp,%esi
  add    $0x1,%r13
  call   <printArray@plt>
  cmp    %r13,%r12
  jne    L21
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rbx,%rcx,4),%rax
  jmp    L15
```

assistant: ```c
void insertionSort(int *as, int n) {
  int i, j, k;
  int key;
  printArray(as, n);
  for (i = 1; i < n; i++) {
    key = as[i];
    j = i - 1;
    while (j >= 0 && as[j] > key) {
      as[j + 1] = as[j];
      j--;
    }
    as[j + 1] = key;
    printArray(as, n);
  }
}
```