ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<atoi_2>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L25
  nopl   0x0(%rax)
L13:
  add    $0x1,%r13d
L25:
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%r12
  add    $0x1,%rbp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
  movsbl (%r12),%edi
  cmp    $0x2d,%dil
  je     L8
  mov    $0x1,%r12d
  movslq %r13d,%rax
  cmp    $0x2b,%dil
  je     L1
L4:
  add    %rax,%rbx
  xor    %ebp,%ebp
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L46:
  movsbl -0x1(%rbx),%eax
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl (%rbx),%edi
  lea    -0x30(%rax,%rdx,2),%ebp
L55:
  call   <isdigit@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L46
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  imul   %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L8:
  mov    $0xffffffff,%r12d
L1:
  add    $0x1,%r13d
  movslq %r13d,%rax
  movsbl (%rbx,%rax,1),%edi
  jmp    L4
```

assistant: ```c
int atoi_2(char s[]) {
  int i = 0;
  int n = 0;
  int sign = 0;
  for (i = 0; isspace(s[i]); ++i)
    ;
  sign = (s[i] == '-') ? (-1) : 1;
  if (s[i] == '+' || s[i] == '-')
    ++i;
  for (n = 0; isdigit(s[i]); ++i)
    n = n * 10 + (s[i] - '0');
  return sign * n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atoi_2>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L45
  nopl   0x0(%rax)
L56:
  add    $0x1,%r12d
L45:
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%r13
  add    $0x1,%rbp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L56
  movzbl 0x0(%r13),%eax
  cmp    $0x2d,%al
  je     L3
  mov    $0x1,%r13d
  cmp    $0x2b,%al
  je     L5
L8:
  movslq %r12d,%r12
  xor    %ebp,%ebp
  add    %r12,%rbx
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L15:
  movsbl (%rbx),%eax
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
L18:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L15
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  imul   %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L3:
  mov    $0xffffffff,%r13d
L5:
  add    $0x1,%r12d
  jmp    L8
```

assistant: ```c
int atoi_2(char s[]) {
  int i = 0;
  int n = 0;
  int sign = 0;
  for (i = 0; isspace(s[i]); ++i)
    ;
  sign = (s[i] == '-') ? (-1) : 1;
  if (s[i] == '+' || s[i] == '-')
    ++i;
  for (n = 0; isdigit(s[i]); ++i)
    n = n * 10 + (s[i] - '0');
  return sign * n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heapSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L36:
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <heapify@plt>
  subl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x0,-0x4(%rbp)
  jns    L36
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L30
L25:
  mov    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <swap@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <heapify@plt>
  subl   $0x1,-0x4(%rbp)
L30:
  cmpl   $0x0,-0x4(%rbp)
  jns    L25
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapSort(int *numbers, int size) {
  int i, tmp;
  for (i = size / 2 - 1; i >= 0; i--) {
    heapify(numbers, size, i);
  }
  for (i = size - 1; i >= 0; i--) {
    swap(0, i, numbers);
    heapify(numbers, i, 0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<heapSort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  add    %esi,%ebp
  sar    %ebp
  sub    $0x1,%ebp
  js     L22
L3:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <heapify@plt>
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  jne    L3
L22:
  sub    $0x1,%ebx
  js     L4
L16:
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <swap@plt>
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <heapify@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L16
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapSort(int *numbers, int size) {
  int i, tmp;
  for (i = size / 2 - 1; i >= 0; i--) {
    heapify(numbers, size, i);
  }
  for (i = size - 1; i >= 0; i--) {
    swap(0, i, numbers);
    heapify(numbers, i, 0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heapSort>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  push   %rbx
  mov    %esi,%ebx
  add    %esi,%ebp
  sar    %ebp
  sub    $0x1,%ebp
  js     L22
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <heapify@plt>
  sub    $0x1,%ebp
  jae    L31
L22:
  sub    $0x1,%ebx
  js     L5
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %ebx,%esi
  xor    %edi,%edi
  mov    %r12,%rdx
  call   <swap@plt>
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <heapify@plt>
  sub    $0x1,%ebx
  jae    L33
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapSort(int *numbers, int size) {
  int i, tmp;
  for (i = size / 2 - 1; i >= 0; i--) {
    heapify(numbers, size, i);
  }
  for (i = size - 1; i >= 0; i--) {
    swap(0, i, numbers);
    heapify(numbers, i, 0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<heapSort>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  push   %rbx
  mov    %esi,%ebx
  add    %esi,%ebp
  sar    %ebp
  sub    $0x1,%ebp
  js     L0
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <heapify@plt>
  sub    $0x1,%ebp
  jae    L26
L0:
  sub    $0x1,%ebx
  js     L38
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %ebx,%esi
  xor    %edi,%edi
  mov    %r12,%rdx
  call   <swap@plt>
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <heapify@plt>
  sub    $0x1,%ebx
  jae    L17
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapSort(int *numbers, int size) {
  int i, tmp;
  for (i = size / 2 - 1; i >= 0; i--) {
    heapify(numbers, size, i);
  }
  for (i = size - 1; i >= 0; i--) {
    swap(0, i, numbers);
    heapify(numbers, i, 0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: f1(%d)


assistant: ```c
void *f1(void *arg) {
  printf("f1(%d)\n", (int)arg);
  return (void *)10;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f1>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: f1(%d)


assistant: ```c
void *f1(void *arg) {
  printf("f1(%d)\n", (int)arg);
  return (void *)10;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f1>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: f1(%d)


assistant: ```c
void *f1(void *arg) {
  printf("f1(%d)\n", (int)arg);
  return (void *)10;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f1>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: f1(%d)


assistant: ```c
void *f1(void *arg) {
  printf("f1(%d)\n", (int)arg);
  return (void *)10;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_pixel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdi
  lea    -0x18(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%esi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <XAllocNamedColor@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L1
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L3
L1:
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <WhitePixel@plt>
  mov    %rax,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
unsigned long get_pixel(Display *dpy, int screen, Colormap cmap, const char *colorstr) {
  XColor exact_fg, screen_fg;
  unsigned long pixel;
  int rc;
  rc = XAllocNamedColor(dpy, cmap, colorstr, &screen_fg, &exact_fg);
  if (rc > 0) {
    pixel = screen_fg.pixel;
  } else {
    pixel = WhitePixel(dpy, screen);
  }
  return pixel;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_pixel>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%esi
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%r8
  call   <XAllocNamedColor@plt>
  test   %eax,%eax
  jle    L21
  mov    0x10(%rsp),%rax
L7:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <WhitePixel@plt>
  jmp    L7
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_pixel(Display *dpy, int screen, Colormap cmap, const char *colorstr) {
  XColor exact_fg, screen_fg;
  unsigned long pixel;
  int rc;
  rc = XAllocNamedColor(dpy, cmap, colorstr, &screen_fg, &exact_fg);
  if (rc > 0) {
    pixel = screen_fg.pixel;
  } else {
    pixel = WhitePixel(dpy, screen);
  }
  return pixel;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_pixel>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    %edx,%esi
  mov    %rcx,%rdx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%r8
  call   <XAllocNamedColor@plt>
  test   %eax,%eax
  jle    L22
  mov    0x10(%rsp),%rax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <WhitePixel@plt>
  jmp    L1
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_pixel(Display *dpy, int screen, Colormap cmap, const char *colorstr) {
  XColor exact_fg, screen_fg;
  unsigned long pixel;
  int rc;
  rc = XAllocNamedColor(dpy, cmap, colorstr, &screen_fg, &exact_fg);
  if (rc > 0) {
    pixel = screen_fg.pixel;
  } else {
    pixel = WhitePixel(dpy, screen);
  }
  return pixel;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_pixel>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    %edx,%esi
  mov    %rcx,%rdx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%r8
  call   <XAllocNamedColor@plt>
  test   %eax,%eax
  jle    L7
  mov    0x10(%rsp),%rax
L22:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <WhitePixel@plt>
  jmp    L22
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_pixel(Display *dpy, int screen, Colormap cmap, const char *colorstr) {
  XColor exact_fg, screen_fg;
  unsigned long pixel;
  int rc;
  rc = XAllocNamedColor(dpy, cmap, colorstr, &screen_fg, &exact_fg);
  if (rc > 0) {
    pixel = screen_fg.pixel;
  } else {
    pixel = WhitePixel(dpy, screen);
  }
  return pixel;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<putshort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <putc@plt>
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void putshort(int val, FILE *f) {
  putc(val >> 8, f);
  putc(val & 0xff, f);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<putshort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  sar    $0x8,%edi
  call   <putc@plt>
  movzbl %bl,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void putshort(int val, FILE *f) {
  putc(val >> 8, f);
  putc(val & 0xff, f);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<putshort>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sar    $0x8,%edi
  sub    $0x8,%rsp
  call   <putc@plt>
  add    $0x8,%rsp
  movzbl %bl,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putc@plt>
```

assistant: ```c
void putshort(int val, FILE *f) {
  putc(val >> 8, f);
  putc(val & 0xff, f);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<putshort>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sar    $0x8,%edi
  sub    $0x8,%rsp
  call   <putc@plt>
  add    $0x8,%rsp
  movzbl %bl,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putc@plt>
```

assistant: ```c
void putshort(int val, FILE *f) {
  putc(val >> 8, f);
  putc(val & 0xff, f);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%rax
  mov    $0x0,%ebx
L6:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  mov    %edx,%r12d
  test   %r12b,%r12b
  je     L11
  add    %ebx,%ebx
  movzbl %r12b,%edx
  add    %edx,%ebx
  movzbl (%rax),%edx
  movsbl %dl,%edx
  shl    $0x8,%edx
  add    %edx,%ebx
  test   %ebx,%ebx
  jns    L48
  and    $0x7fffffff,%ebx
  add    $0x1,%ebx
L48:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  test   %dl,%dl
  je     L37
  jmp    L6
L11:
  nop
  jmp    L5
L37:
  nop
L5:
  mov    %ebx,%eax
  and    $0x7fff,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(p)
register char *p;
{
  register int acc = 0;
  register unsigned char b0;
  while (1) {
    if ((b0 = *p++) == 0)
      break;
    acc <<= 1;
    acc += b0;
    acc += (*p << 8);
    if (acc < 0) {
      acc &= (((unsigned)-1) >> 1);
      acc++;
    }
    if (*p++ == 0)
      break;
  }
  return (acc & 0x7fff);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash>:
  endbr64
  mov    $0x0,%eax
L2:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
  movzbl %dl,%edx
  lea    (%rdx,%rax,2),%edx
  movzbl 0x1(%rdi),%ecx
  movsbl %cl,%eax
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0x7fffffff,%edx
  add    $0x1,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x2,%rdi
  test   %cl,%cl
  jne    L2
L14:
  and    $0x7fff,%eax
  ret
```

assistant: ```c
unsigned int hash(p)
register char *p;
{
  register int acc = 0;
  register unsigned char b0;
  while (1) {
    if ((b0 = *p++) == 0)
      break;
    acc <<= 1;
    acc += b0;
    acc += (*p << 8);
    if (acc < 0) {
      acc &= (((unsigned)-1) >> 1);
      acc++;
    }
    if (*p++ == 0)
      break;
  }
  return (acc & 0x7fff);
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  xor    %eax,%eax
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L4:
  lea    (%rdx,%rax,2),%edx
  movsbl 0x1(%rdi),%eax
  mov    %eax,%ecx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0x7fffffff,%edx
  add    $0x1,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x2,%rdi
  test   %cl,%cl
  je     L19
L10:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L4
L19:
  and    $0x7fff,%eax
  ret
```

assistant: ```c
unsigned int hash(p)
register char *p;
{
  register int acc = 0;
  register unsigned char b0;
  while (1) {
    if ((b0 = *p++) == 0)
      break;
    acc <<= 1;
    acc += b0;
    acc += (*p << 8);
    if (acc < 0) {
      acc &= (((unsigned)-1) >> 1);
      acc++;
    }
    if (*p++ == 0)
      break;
  }
  return (acc & 0x7fff);
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  xor    %eax,%eax
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L6:
  lea    (%rdx,%rax,2),%edx
  movsbl 0x1(%rdi),%eax
  mov    %eax,%ecx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0x7fffffff,%edx
  add    $0x1,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x2,%rdi
  test   %cl,%cl
  je     L10
L9:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L6
L10:
  and    $0x7fff,%eax
  ret
```

assistant: ```c
unsigned int hash(p)
register char *p;
{
  register int acc = 0;
  register unsigned char b0;
  while (1) {
    if ((b0 = *p++) == 0)
      break;
    acc <<= 1;
    acc += b0;
    acc += (*p << 8);
    if (acc < 0) {
      acc &= (((unsigned)-1) >> 1);
      acc++;
    }
    if (*p++ == 0)
      break;
  }
  return (acc & 0x7fff);
}
```
user: What is the c source code of the assembly code below?

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: strdup

assistant: ```c
char *xstrdup(const char *str) {
  char *tmp;
  tmp = strdup(str);
  if (tmp == NULL) {
    perror("strdup");
    exit(1);
  }
  return tmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<xstrdup>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
L8:
  mov    %rbx,%rax
  pop    %rbx
  ret
L9:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: strdup

assistant: ```c
char *xstrdup(const char *str) {
  char *tmp;
  tmp = strdup(str);
  if (tmp == NULL) {
    perror("strdup");
    exit(1);
  }
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L3:
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: strdup

assistant: ```c
char *xstrdup(const char *str) {
  char *tmp;
  tmp = strdup(str);
  if (tmp == NULL) {
    perror("strdup");
    exit(1);
  }
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
L0:
  mov    %r12,%rax
  pop    %r12
  ret
L5:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: strdup

assistant: ```c
char *xstrdup(const char *str) {
  char *tmp;
  tmp = strdup(str);
  if (tmp == NULL) {
    perror("strdup");
    exit(1);
  }
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmd_zmovrel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xd(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L8
  lea    D37(%rip),%rax
  mov    %rax,%rsi
  mov    $0xfffffffe,%edi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L51
L8:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0xd(%rbp),%rdx
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L65
  lea    D38(%rip),%rax
  mov    %rax,%rsi
  mov    $0xfffffffe,%edi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L51
L65:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D39(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L87
  lea    D58(%rip),%rax
  mov    %rax,%rsi
  mov    $0xfffffffe,%edi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L51
L87:
  movzbl -0xd(%rbp),%eax
  test   %al,%al
  je     L75
  movzbl -0xd(%rbp),%eax
  cmp    $0x3,%al
  jbe    L70
L75:
  mov    $0x3,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0xfffffffe,%edi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L51
L70:
  mov    -0xc(%rbp),%edx
  movzbl -0xd(%rbp),%eax
  movzbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <zaber_move_rel@plt>
  mov    $0x0,%eax
L51:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D37
type_infered: string
name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D38
type_infered: string
name: read_data
arguments: tag: D39
type_infered: string
name: read_data
arguments: tag: D58
type_infered: string
name: read_data
arguments: tag: D6
type_infered: string

tool: D37: Usage: zmovrel [unit] [nsteps]

tool: D11: %hhu

tool: D38: Error parsing unit.

tool: D39: %d

tool: D58: Error parsing posn.

tool: D6: Unit between 1 and %d only.

assistant: ```c
int cmd_zmovrel(int argc, char *argv[]) {
  unsigned char unit = 0;
  int nsteps = 0;
  if (argc != 3)
    return error((-2), "Usage: zmovrel [unit] [nsteps]");
  if (sscanf(argv[1], "%hhu", &unit) != 1)
    return error((-2), "Error parsing unit.");
  if (sscanf(argv[2], "%d", &nsteps) != 1)
    return error((-2), "Error parsing posn.");
  if (unit < 1 || unit > 3)
    return error((-2), "Unit between 1 and %d only.", 3);
  zaber_move_rel(unit, nsteps);
  return 0;
}
```