ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort>:
  endbr64
  push   %r15
  lea    -0x2(%rsi),%ecx
  mov    %rdi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  mov    %ecx,0x1c(%rsp)
  mov    %rcx,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L22
  mov    %r14d,%r12d
  lea    0x1(%r14),%eax
  cmp    0x18(%rsp),%eax
  jge    L69
  xchg   %ax,%ax
L38:
  lea    0x1(%r14),%rax
  lea    (%r15,%r14,4),%rbp
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  mov    0x1c(%rsp),%eax
  sub    %r14d,%eax
  lea    0x2(%r14,%rax,1),%rbx
  nopl   0x0(%rax)
L48:
  movslq %r12d,%rax
  mov    (%r15,%r13,4),%edx
  lea    (%r15,%rax,4),%rsi
  lea    (%r15,%r13,4),%rax
  cmp    %edx,(%rsi)
  cmovg  %r13d,%r12d
  cmovg  %rax,%rsi
  cmp    %r14d,%r12d
  je     L60
  mov    %rbp,%rdi
  call   <swap@plt>
L60:
  add    $0x1,%r13
  cmp    %r13,%rbx
  jne    L48
  cmp    0x10(%rsp),%r14
  je     L22
L6:
  mov    0x8(%rsp),%r14
  mov    %r14d,%r12d
  lea    0x1(%r14),%eax
  cmp    0x18(%rsp),%eax
  jl     L38
L69:
  lea    0x1(%r14),%rax
  mov    %rax,0x8(%rsp)
  cmp    0x10(%rsp),%r14
  jne    L6
L22:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sort(int a[], int length) {
  int i, j;
  int tmp;
  int min;
  for (i = 0; i < length - 1; i++) {
    min = i;
    for (j = i + 1; j < length; j++) {
      if (a[min] > a[j]) {
        min = j;
      }
      if (min != i) {
        swap(&a[i], &a[min]);
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ncrossprod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <normalize@plt>
  nop
  leave
  ret
```

assistant: ```c
void ncrossprod(float v1[3], float v2[3], float cp[3]) {
  cp[0] = v1[1] * v2[2] - v1[2] * v2[1];
  cp[1] = v1[2] * v2[0] - v1[0] * v2[2];
  cp[2] = v1[0] * v2[1] - v1[1] * v2[0];
  normalize(cp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ncrossprod>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rdx,%rdi
  movss  0x4(%rax),%xmm0
  mulss  0x8(%rsi),%xmm0
  movss  0x8(%rax),%xmm1
  mulss  0x4(%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x8(%rax),%xmm0
  mulss  (%rsi),%xmm0
  movss  (%rax),%xmm1
  mulss  0x8(%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  (%rax),%xmm0
  mulss  0x4(%rsi),%xmm0
  movss  0x4(%rax),%xmm1
  mulss  (%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  call   <normalize@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ncrossprod(float v1[3], float v2[3], float cp[3]) {
  cp[0] = v1[1] * v2[2] - v1[2] * v2[1];
  cp[1] = v1[2] * v2[0] - v1[0] * v2[2];
  cp[2] = v1[0] * v2[1] - v1[1] * v2[0];
  normalize(cp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ncrossprod>:
  endbr64
  mov    %rdi,%rax
  mov    %rdx,%rdi
  movss  0x4(%rax),%xmm0
  movss  0x8(%rax),%xmm1
  mulss  0x8(%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x8(%rax),%xmm0
  movss  (%rax),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x8(%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  (%rax),%xmm0
  movss  0x4(%rax),%xmm1
  mulss  0x4(%rsi),%xmm0
  mulss  (%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  jmp    1050 <normalize@plt>
```

assistant: ```c
void ncrossprod(float v1[3], float v2[3], float cp[3]) {
  cp[0] = v1[1] * v2[2] - v1[2] * v2[1];
  cp[1] = v1[2] * v2[0] - v1[0] * v2[2];
  cp[2] = v1[0] * v2[1] - v1[1] * v2[0];
  normalize(cp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ncrossprod>:
  endbr64
  mov    %rdi,%rax
  mov    %rdx,%rdi
  movss  0x4(%rax),%xmm0
  movss  0x8(%rax),%xmm1
  mulss  0x8(%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x8(%rax),%xmm0
  movss  (%rax),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x8(%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  (%rax),%xmm0
  movss  0x4(%rax),%xmm1
  mulss  0x4(%rsi),%xmm0
  mulss  (%rsi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  jmp    1050 <normalize@plt>
```

assistant: ```c
void ncrossprod(float v1[3], float v2[3], float cp[3]) {
  cp[0] = v1[1] * v2[2] - v1[2] * v2[1];
  cp[1] = v1[2] * v2[0] - v1[0] * v2[2];
  cp[2] = v1[0] * v2[1] - v1[1] * v2[0];
  normalize(cp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lookForEnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  lea    (%rax,%rax,1),%ebx
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  sub    $0x4,%eax
  cmp    %eax,%ebx
  jge    L27
  jmp    L4
L9:
  mov    $0x46,%esi
  mov    $0x1e,%edi
  call   <set_motors@plt>
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <checkWallAhead@plt>
L4:
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  lea    (%rax,%rax,1),%ebx
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  cmp    %eax,%ebx
  jl     L9
L27:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: UTURN SL%d FL%d


assistant: ```c
void lookForEnd() {
  if (2 * get_side_ir_dist(0) < get_front_ir_dist(0) - 4) {
    while (2 * get_side_ir_dist(0) < get_front_ir_dist(0)) {
      set_motors(30, 70);
      printf("UTURN SL%d FL%d\n", get_side_ir_dist(0), get_front_ir_dist(0));
      checkWallAhead();
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lookForEnd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  sub    $0x4,%eax
  lea    D8(%rip),%rbp
  cmp    %eax,%ebx
  jl     L6
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    $0x46,%esi
  mov    $0x1e,%edi
  call   <set_motors@plt>
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <checkWallAhead@plt>
L6:
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  cmp    %eax,%ebx
  jl     L21
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: UTURN SL%d FL%d


assistant: ```c
void lookForEnd() {
  if (2 * get_side_ir_dist(0) < get_front_ir_dist(0) - 4) {
    while (2 * get_side_ir_dist(0) < get_front_ir_dist(0)) {
      set_motors(30, 70);
      printf("UTURN SL%d FL%d\n", get_side_ir_dist(0), get_front_ir_dist(0));
      checkWallAhead();
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lookForEnd>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  call   <get_side_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  sub    $0x4,%eax
  cmp    %eax,%ebx
  jl     L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L10:
  mov    $0x46,%esi
  mov    $0x1e,%edi
  call   <set_motors@plt>
  xor    %edi,%edi
  call   <get_front_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <get_side_ir_dist@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <checkWallAhead@plt>
L16:
  xor    %edi,%edi
  call   <get_side_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  cmp    %eax,%ebx
  jl     L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string

tool: D8: UTURN SL%d FL%d


assistant: ```c
void lookForEnd() {
  if (2 * get_side_ir_dist(0) < get_front_ir_dist(0) - 4) {
    while (2 * get_side_ir_dist(0) < get_front_ir_dist(0)) {
      set_motors(30, 70);
      printf("UTURN SL%d FL%d\n", get_side_ir_dist(0), get_front_ir_dist(0));
      checkWallAhead();
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lookForEnd>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  call   <get_side_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  sub    $0x4,%eax
  cmp    %eax,%ebx
  jl     L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L0:
  mov    $0x46,%esi
  mov    $0x1e,%edi
  call   <set_motors@plt>
  xor    %edi,%edi
  call   <get_front_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <get_side_ir_dist@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <checkWallAhead@plt>
L10:
  xor    %edi,%edi
  call   <get_side_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  cmp    %eax,%ebx
  jl     L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: UTURN SL%d FL%d


assistant: ```c
void lookForEnd() {
  if (2 * get_side_ir_dist(0) < get_front_ir_dist(0) - 4) {
    while (2 * get_side_ir_dist(0) < get_front_ir_dist(0)) {
      set_motors(30, 70);
      printf("UTURN SL%d FL%d\n", get_side_ir_dist(0), get_front_ir_dist(0));
      checkWallAhead();
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<prb_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L21
  cmpq   $0x0,-0x10(%rbp)
  je     L21
  mov    $0x1,%eax
  jmp    L4
L21:
  mov    $0x0,%eax
L4:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  leave
  ret
```

assistant: ```c
void *prb_malloc(struct libavl_allocator *allocator, size_t size) {
  assert(allocator != NULL && size > 0);
  return malloc(size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prb_malloc>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <malloc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *prb_malloc(struct libavl_allocator *allocator, size_t size) {
  assert(allocator != NULL && size > 0);
  return malloc(size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<prb_malloc>:
  endbr64
  test   %rdi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <malloc@plt>
```

assistant: ```c
void *prb_malloc(struct libavl_allocator *allocator, size_t size) {
  assert(allocator != NULL && size > 0);
  return malloc(size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prb_malloc>:
  endbr64
  test   %rdi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <malloc@plt>
```

assistant: ```c
void *prb_malloc(struct libavl_allocator *allocator, size_t size) {
  assert(allocator != NULL && size > 0);
  return malloc(size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testTortureExecute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <func@plt>
  mov    $0x1,%edi
  call   <func@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void testTortureExecute(void) {
  func(0);
  func(1);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<testTortureExecute>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <func@plt>
  mov    $0x1,%edi
  call   <func@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void testTortureExecute(void) {
  func(0);
  func(1);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<testTortureExecute>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <func@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <func@plt>
```

assistant: ```c
void testTortureExecute(void) {
  func(0);
  func(1);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<testTortureExecute>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <func@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <func@plt>
```

assistant: ```c
void testTortureExecute(void) {
  func(0);
  func(1);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__libc_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <log_event@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *malloc(size_t size) {
  void *ptr = __libc_malloc(size);
  log_event(1, ptr, size);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <__libc_malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <log_event@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *malloc(size_t size) {
  void *ptr = __libc_malloc(size);
  log_event(1, ptr, size);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<malloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <__libc_malloc@plt>
  mov    %r13,%rdx
  mov    $0x1,%edi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <log_event@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *malloc(size_t size) {
  void *ptr = __libc_malloc(size);
  log_event(1, ptr, size);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<malloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <__libc_malloc@plt>
  mov    %r13,%rdx
  mov    $0x1,%edi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <log_event@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *malloc(size_t size) {
  void *ptr = __libc_malloc(size);
  log_event(1, ptr, size);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_alloca>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xd,%edi
  call   <size@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_alloca@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L8:
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <__builtin_object_size@plt>
  cmp    %eax,-0xc(%rbp)
  je     L16
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L16:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_alloca(void) {
  unsigned n = size(13);
  void *p = __builtin_alloca(n);
  if (!p)
    __builtin_abort();
  if (__builtin_object_size(p, 0) != n)
    __builtin_abort();
  sink(p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_alloca>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xd,%edi
  call   <size@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <__builtin_alloca@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L7:
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <__builtin_object_size@plt>
  cmp    %ebp,%eax
  jne    L37
L11:
  mov    %rbx,%rdi
  call   <sink@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
  jmp    L7
L37:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
  jmp    L11
```

assistant: ```c
void test_alloca(void) {
  unsigned n = size(13);
  void *p = __builtin_alloca(n);
  if (!p)
    __builtin_abort();
  if (__builtin_object_size(p, 0) != n)
    __builtin_abort();
  sink(p);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_alloca>:
  endbr64
  push   %rbp
  mov    $0xd,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <size@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <__builtin_alloca@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
L25:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <__builtin_object_size@plt>
  cmp    %ebx,%eax
  je     L29
  xor    %eax,%eax
  call   <__builtin_abort@plt>
L29:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10c0 <sink@plt>
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  call   <__builtin_abort@plt>
  jmp    L25
```

assistant: ```c
void test_alloca(void) {
  unsigned n = size(13);
  void *p = __builtin_alloca(n);
  if (!p)
    __builtin_abort();
  if (__builtin_object_size(p, 0) != n)
    __builtin_abort();
  sink(p);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_alloca>:
  endbr64
  push   %rbp
  mov    $0xd,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <size@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <__builtin_alloca@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
L0:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <__builtin_object_size@plt>
  cmp    %ebx,%eax
  je     L20
  xor    %eax,%eax
  call   <__builtin_abort@plt>
L20:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10c0 <sink@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <__builtin_abort@plt>
  jmp    L0
```

assistant: ```c
void test_alloca(void) {
  unsigned n = size(13);
  void *p = __builtin_alloca(n);
  if (!p)
    __builtin_abort();
  if (__builtin_object_size(p, 0) != n)
    __builtin_abort();
  sink(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matmult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x0,%edi
  call   <newmat@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L38:
  movl   $0x0,-0x10(%rbp)
  jmp    L34
L16:
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L55:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L39:
  cmpl   $0x3,-0xc(%rbp)
  jle    L55
  addl   $0x1,-0x10(%rbp)
L34:
  cmpl   $0x3,-0x10(%rbp)
  jle    L16
  addl   $0x1,-0x14(%rbp)
L15:
  cmpl   $0x3,-0x14(%rbp)
  jle    L38
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <matfree@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <matfree@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float **matmult(float **mat1, float **mat2) {
  float **mat = newmat(0);
  int i, j, k;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      for (k = 0; k < 4; k++)
        mat[i][j] += mat1[i][k] * mat2[k][j];
  matfree(mat1);
  matfree(mat2);
  return mat;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matmult>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%edi
  call   <newmat@plt>
  mov    %rax,%rbp
  mov    %rax,%r8
  mov    %r12,%r9
  lea    0x20(%rax),%r10
L19:
  mov    $0x0,%ecx
L2:
  mov    $0x0,%eax
L23:
  mov    %rcx,%rdx
  add    (%r8),%rdx
  mov    (%r9),%rdi
  mov    (%rbx,%rax,2),%rsi
  movss  (%rdi,%rax,1),%xmm0
  mulss  (%rsi,%rcx,1),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L23
  add    $0x4,%rcx
  cmp    $0x10,%rcx
  jne    L2
  add    $0x8,%r8
  add    $0x8,%r9
  cmp    %r10,%r8
  jne    L19
  mov    %r12,%rdi
  call   <matfree@plt>
  mov    %rbx,%rdi
  call   <matfree@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
float **matmult(float **mat1, float **mat2) {
  float **mat = newmat(0);
  int i, j, k;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      for (k = 0; k < 4; k++)
        mat[i][j] += mat1[i][k] * mat2[k][j];
  matfree(mat1);
  matfree(mat2);
  return mat;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matmult>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <newmat@plt>
  xor    %esi,%esi
  mov    %rax,%r12
L26:
  mov    (%r12,%rsi,1),%rdi
  mov    0x0(%r13,%rsi,1),%r8
  xor    %edx,%edx
L20:
  movss  (%rdi,%rdx,1),%xmm1
  xor    %eax,%eax
L10:
  mov    0x0(%rbp,%rax,8),%rcx
  movss  (%rcx,%rdx,1),%xmm0
  mulss  (%r8,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdi,%rdx,1)
  cmp    $0x4,%rax
  jne    L10
  add    $0x4,%rdx
  cmp    $0x10,%rdx
  jne    L20
  add    $0x8,%rsi
  cmp    $0x20,%rsi
  jne    L26
  mov    %r13,%rdi
  call   <matfree@plt>
  mov    %rbp,%rdi
  call   <matfree@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **matmult(float **mat1, float **mat2) {
  float **mat = newmat(0);
  int i, j, k;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      for (k = 0; k < 4; k++)
        mat[i][j] += mat1[i][k] * mat2[k][j];
  matfree(mat1);
  matfree(mat2);
  return mat;
}
```