user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%r14
  lea    0x34(%rsp),%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  mov    $0x0,%eax
  movl   $0x0,0x8(%rsp)
  lea    D57(%rip),%r15
  mov    %r14,0x18(%rsp)
  mov    %eax,%r14d
  jmp    L79
L14:
  add    $0x1,%r14d
L53:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L33
L106:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  lea    (%rbx,%rbp,1),%rax
  testb  $0x1,(%rax,%r13,1)
  jne    L14
  addl   $0x1,0x8(%rsp)
  jmp    L53
L33:
  add    $0x14,%r12
  sub    $0x14,%rbp
  add    $0x14,%r13
  cmp    $0xffffffffffffff9c,%rbp
  je     L100
L79:
  lea    -0x14(%r12),%rbx
  jmp    L106
L100:
  mov    %r14d,0xc(%rsp)
  mov    0x18(%rsp),%r14
  lea    0x64(%r14),%rsi
  mov    %rsi,%rdi
  mov    %r14,%rcx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
L11:
  mov    $0x0,%edx
L25:
  mov    (%rcx,%rdx,4),%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  cmp    %eax,%r12d
  cmovg  %eax,%r12d
  add    $0x1,%rdx
  cmp    $0x5,%rdx
  jne    L25
  add    $0x14,%rcx
  cmp    %rsi,%rcx
  jne    L11
  mov    %r14,%r15
  mov    %ebp,0x18(%rsp)
  mov    %rdi,%rbp
L16:
  lea    D41(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  mov    $0x0,%r13d
L48:
  mov    (%r15,%rbx,4),%esi
  add    %esi,%r13d
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L48
  mov    %r13d,%esi
  lea    D61(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x14,%r15
  cmp    %rbp,%r15
  jne    L16
  mov    0x18(%rsp),%ebp
  lea    D51(%rip),%rdi
  call   <puts@plt>
  lea    D2(%rip),%rbx
  mov    0x10(%rsp),%r13
L23:
  mov    (%r14),%esi
  add    0x14(%r14),%esi
  add    0x28(%r14),%esi
  add    0x3c(%r14),%esi
  add    0x50(%r14),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r14
  cmp    %r13,%r14
  jne    L23
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D24
data_type: string
name: parse_data
arguments: data_label: D57
data_type: string
name: parse_data
arguments: data_label: D41
data_type: string
name: parse_data
arguments: data_label: D39
data_type: string
name: parse_data
arguments: data_label: D61
data_type: string
name: parse_data
arguments: data_label: D51
data_type: string
name: parse_data
arguments: data_label: D2
data_type: string
name: parse_data
arguments: data_label: D32
data_type: string

tool: D24: Enter the array elements

tool: D57: %d

tool: D41: 


tool: D39: %d	

tool: D61: 	Sum:%d


tool: D51: -------------------------------------

tool: D2: Sum:%d	

tool: D32: 

There are %d even nos and  %d odd nos.
%d is big and %d is small


assistant: ```c
int main() {
  int a[5][5], i, j, k, even = 0, odd = 0, big = 0, small = 0, row, column;
  printf("Enter the array elements");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      scanf("%d", &a[i][j]);
      if (a[i][j] % 2 == 0) {
        even++;
      } else {
        odd++;
      }
    }
  }
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      if (a[i][j] > big) {
        big = a[i][j];
      }
      if (a[i][j] < small) {
        small = a[i][j];
      }
    }
  }
  for (i = 0; i < 5; i++) {
    row = 0;
    printf("\n\n");
    for (j = 0; j < 5; j++) {
      row += a[i][j];
      printf("%d\t", a[i][j]);
    }
    printf("\tSum:%d\n", row);
  }
  printf("-------------------------------------\n");
  for (j = 0; j < 5; j++) {
    column = 0;
    for (i = 0; i < 5; i++) {
      column += a[i][j];
    }
    printf("Sum:%d\t", column);
  }
  printf("\n\nThere are %d even nos and  %d odd nos.\n%d is big and %d is small\n", even, odd, big, small);
  return 0;
}
```