ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<fill_icsi_log_table>:
  endbr64
  push   %r13
  mov    $0x17,%ecx
  push   %r12
  sub    %edi,%ecx
  mov    $0x1,%r12d
  push   %rbp
  shl    %cl,%r12d
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  mov    $0x2,%edi
  sub    $0x18,%rsp
  movss  D7(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <pow@plt>
  test   %eax,%eax
  jle    L10
  sub    $0x1,%eax
  movss  0xc(%rsp),%xmm0
  mov    $0x3f800000,%ebp
  lea    0x4(%rbx,%rax,4),%r13
  nopw   0x0(%rax,%rax,1)
L0:
  call   <log2@plt>
  add    %r12d,%ebp
  add    $0x4,%rbx
  movss  %xmm0,-0x4(%rbx)
  movd   %ebp,%xmm0
  cmp    %r13,%rbx
  jne    L0
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void fill_icsi_log_table(const int n, float *lookup_table) {
  float numlog;
  int incr, i, p;
  int *const exp_ptr = ((int *)&numlog);
  int x = *exp_ptr;
  x = 0x3F800000;
  *exp_ptr = x;
  incr = 1 << (23 - n);
  p = pow(2, n);
  for (i = 0; i < p; i++) {
    lookup_table[i] = log2(numlog);
    x += incr;
    *exp_ptr = x;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pid_is_user>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%edx
  lea    -0x30(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L16
  mov    $0x0,%eax
  jmp    L7
L16:
  mov    -0x38(%rbp),%rax
  cmp    %rax,-0x50(%rbp)
  sete   %al
  movzbl %al,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: /proc/%d

assistant: ```c
bool pid_is_user(pid_t pid, uid_t uid) {
  struct stat sb;
  char buf[32];
  sprintf(buf, "/proc/%d", pid);
  if (stat(buf, &sb) != 0)
    return false;
  return (sb.st_uid == uid);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pid_is_user>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%edx
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L3
  cmp    %rbx,0x8(%rsp)
  sete   %al
  movzbl %al,%eax
L3:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: /proc/%d

assistant: ```c
bool pid_is_user(pid_t pid, uid_t uid) {
  struct stat sb;
  char buf[32];
  sprintf(buf, "/proc/%d", pid);
  if (stat(buf, &sb) != 0)
    return false;
  return (sb.st_uid == uid);
}
```
user: What is the c source code of the assembly code below?

```asm
<pid_is_user>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  push   %rbx
  mov    %rsi,%rbx
  lea    D3(%rip),%rsi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L2
  xor    %eax,%eax
  cmp    %rbx,0x8(%rsp)
  sete   %al
L2:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string

tool: D3: /proc/%d

assistant: ```c
bool pid_is_user(pid_t pid, uid_t uid) {
  struct stat sb;
  char buf[32];
  sprintf(buf, "/proc/%d", pid);
  if (stat(buf, &sb) != 0)
    return false;
  return (sb.st_uid == uid);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pid_is_user>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  push   %rbx
  mov    %rsi,%rbx
  lea    D5(%rip),%rsi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L5
  xor    %eax,%eax
  cmp    %rbx,0x8(%rsp)
  sete   %al
L5:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: /proc/%d

assistant: ```c
bool pid_is_user(pid_t pid, uid_t uid) {
  struct stat sb;
  char buf[32];
  sprintf(buf, "/proc/%d", pid);
  if (stat(buf, &sb) != 0)
    return false;
  return (sb.st_uid == uid);
}
```
user: Translate the below assembly code into C programming language:

```asm
<failed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void failed(const char *s) {
  perror(s);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<failed>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void failed(const char *s) {
  perror(s);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<failed>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void failed(const char *s) {
  perror(s);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<failed>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void failed(const char *s) {
  perror(s);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<refreshContents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L8:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  0x10(%rax),%xmm3
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  0x8(%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  0x18(%rax),%xmm0
  cvttsd2si %xmm0,%esi
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  0x20(%rax),%xmm0
  cvttsd2si %xmm0,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  0x30(%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x24(%rbp),%xmm1
  movapd %xmm0,%xmm4
  subsd  %xmm1,%xmm4
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  0x28(%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x20(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  mov    %ecx,%edi
  movapd %xmm4,%xmm1
  movq   %rax,%xmm0
  mov    $0x4,%eax
  call   <cymplt@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int refreshContents(plotdt, countt, offsetX, offsetY)
double plotdt[100][8];
int countt;
int offsetX, offsetY;
{
  int i;

  for (i = 0; i < countt; i++) {

    cymplt(plotdt[i][5] - offsetX, plotdt[i][6] - offsetY, (int)plotdt[i][4], (int)plotdt[i][3], plotdt[i][1], plotdt[i][2], plotdt);
  }
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<refreshContents>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %edx,%r12d
  lea    0x8(%rdi),%rbx
  lea    -0x1(%rsi),%eax
  shl    $0x6,%rax
  lea    0x48(%rdi,%rax,1),%r13
  pxor   %xmm5,%xmm5
  cvtsi2sd %ecx,%xmm5
  movsd  %xmm5,0x8(%rsp)
L0:
  cvttsd2si 0x10(%rbx),%esi
  cvttsd2si 0x18(%rbx),%edi
  movsd  0x28(%rbx),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %r12d,%xmm2
  movsd  0x20(%rbx),%xmm0
  subsd  %xmm2,%xmm0
  mov    %rbp,%rdx
  movsd  0x8(%rbx),%xmm3
  movsd  (%rbx),%xmm2
  subsd  0x8(%rsp),%xmm1
  mov    $0x4,%eax
  call   <cymplt@plt>
  add    $0x40,%rbx
  cmp    %r13,%rbx
  jne    L0
  mov    $0x1,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int refreshContents(plotdt, countt, offsetX, offsetY)
double plotdt[100][8];
int countt;
int offsetX, offsetY;
{
  int i;

  for (i = 0; i < countt; i++) {

    cymplt(plotdt[i][5] - offsetX, plotdt[i][6] - offsetY, (int)plotdt[i][4], (int)plotdt[i][3], plotdt[i][1], plotdt[i][2], plotdt);
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<refreshContents>:
  endbr64
  test   %esi,%esi
  jle    L16
  pxor   %xmm6,%xmm6
  pxor   %xmm7,%xmm7
  push   %r12
  lea    -0x1(%rsi),%eax
  push   %rbp
  cvtsi2sd %ecx,%xmm6
  shl    $0x6,%rax
  mov    %rdi,%rbp
  push   %rbx
  cvtsi2sd %edx,%xmm7
  lea    0x8(%rdi),%rbx
  lea    0x48(%rdi,%rax,1),%r12
  sub    $0x10,%rsp
  movsd  %xmm6,(%rsp)
  movsd  %xmm7,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L14:
  cvttsd2si 0x10(%rbx),%esi
  movsd  (%rbx),%xmm2
  mov    %rbp,%rdx
  add    $0x40,%rbx
  cvttsd2si -0x28(%rbx),%edi
  movsd  -0x18(%rbx),%xmm1
  mov    $0x4,%eax
  movsd  -0x20(%rbx),%xmm0
  subsd  (%rsp),%xmm1
  subsd  0x8(%rsp),%xmm0
  movsd  -0x38(%rbx),%xmm3
  call   <cymplt@plt>
  cmp    %r12,%rbx
  jne    L14
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int refreshContents(plotdt, countt, offsetX, offsetY)
double plotdt[100][8];
int countt;
int offsetX, offsetY;
{
  int i;

  for (i = 0; i < countt; i++) {

    cymplt(plotdt[i][5] - offsetX, plotdt[i][6] - offsetY, (int)plotdt[i][4], (int)plotdt[i][3], plotdt[i][1], plotdt[i][2], plotdt);
  }
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<refreshContents>:
  endbr64
  test   %esi,%esi
  jle    L10
  pxor   %xmm6,%xmm6
  pxor   %xmm7,%xmm7
  push   %r12
  lea    -0x1(%rsi),%eax
  push   %rbp
  cvtsi2sd %ecx,%xmm6
  shl    $0x6,%rax
  mov    %rdi,%rbp
  push   %rbx
  cvtsi2sd %edx,%xmm7
  lea    0x8(%rdi),%rbx
  lea    0x48(%rdi,%rax,1),%r12
  sub    $0x10,%rsp
  movsd  %xmm6,(%rsp)
  movsd  %xmm7,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L19:
  cvttsd2si 0x10(%rbx),%esi
  movsd  (%rbx),%xmm2
  mov    %rbp,%rdx
  add    $0x40,%rbx
  cvttsd2si -0x28(%rbx),%edi
  movsd  -0x18(%rbx),%xmm1
  mov    $0x4,%eax
  movsd  -0x20(%rbx),%xmm0
  subsd  (%rsp),%xmm1
  subsd  0x8(%rsp),%xmm0
  movsd  -0x38(%rbx),%xmm3
  call   <cymplt@plt>
  cmp    %rbx,%r12
  jne    L19
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int refreshContents(plotdt, countt, offsetX, offsetY)
double plotdt[100][8];
int countt;
int offsetX, offsetY;
{
  int i;

  for (i = 0; i < countt; i++) {

    cymplt(plotdt[i][5] - offsetX, plotdt[i][6] - offsetY, (int)plotdt[i][4], (int)plotdt[i][3], plotdt[i][1], plotdt[i][2], plotdt);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L16
L6:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L20
  addl   $0x1,-0xc(%rbp)
L20:
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L6
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_guessed: string

tool: D18: %i

assistant: ```c
int main(int argc, const char *argv[]) {
  int x, i, shit = 0;
  scanf("%i", &x);
  for (i = 1; i <= x; ++i) {
    if (!(x % i)) {
      ++shit;
    }
  }
  printf("%i", shit);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L16
  lea    0x1(%rsi),%r8d
  mov    $0x0,%edi
  mov    $0x1,%ecx
L27:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%edi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L27
L11:
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L16:
  mov    $0x0,%edi
  jmp    L11
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: %i

assistant: ```c
int main(int argc, const char *argv[]) {
  int x, i, shit = 0;
  scanf("%i", &x);
  for (i = 1; i <= x; ++i) {
    if (!(x % i)) {
      ++shit;
    }
  }
  printf("%i", shit);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L6
  lea    0x1(%rsi),%edi
  xor    %r8d,%r8d
  mov    $0x1,%ecx
L18:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L18
L37:
  mov    %r8d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  xor    %r8d,%r8d
  jmp    L37
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: %i

assistant: ```c
int main(int argc, const char *argv[]) {
  int x, i, shit = 0;
  scanf("%i", &x);
  for (i = 1; i <= x; ++i) {
    if (!(x % i)) {
      ++shit;
    }
  }
  printf("%i", shit);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L29
  lea    0x1(%rsi),%edi
  xor    %r8d,%r8d
  mov    $0x1,%ecx
L30:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L30
L37:
  mov    %r8d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L29:
  xor    %r8d,%r8d
  jmp    L37
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: %i

assistant: ```c
int main(int argc, const char *argv[]) {
  int x, i, shit = 0;
  scanf("%i", &x);
  for (i = 1; i <= x; ++i) {
    if (!(x % i)) {
      ++shit;
    }
  }
  printf("%i", shit);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loadavg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <getloadavg@plt>
  test   %rax,%rax
  jns    L8
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <smprintf@plt>
  jmp    L4
L8:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <smprintf@plt>
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string

tool: 

tool: D9: %.2f

assistant: ```c
char *loadavg(void) {
  double avgs[1];
  if (getloadavg(avgs, 1) < 0)
    return smprintf("");
  return smprintf("%.2f", avgs[0]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<loadavg>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1,%esi
  call   <getloadavg@plt>
  test   %rax,%rax
  js     L4
  movsd  (%rsp),%xmm0
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  call   <smprintf@plt>
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L4:
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <smprintf@plt>
  jmp    L0
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D17
type: string

tool: D6: %.2f

tool: 

assistant: ```c
char *loadavg(void) {
  double avgs[1];
  if (getloadavg(avgs, 1) < 0)
    return smprintf("");
  return smprintf("%.2f", avgs[0]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<loadavg>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getloadavg@plt>
  test   %rax,%rax
  js     L0
  movsd  (%rsp),%xmm0
  lea    D2(%rip),%rdi
  mov    $0x1,%eax
  call   <smprintf@plt>
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L0:
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <smprintf@plt>
  jmp    L7
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string

tool: D2: %.2f

tool: 

assistant: ```c
char *loadavg(void) {
  double avgs[1];
  if (getloadavg(avgs, 1) < 0)
    return smprintf("");
  return smprintf("%.2f", avgs[0]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loadavg>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getloadavg@plt>
  test   %rax,%rax
  js     L4
  movsd  (%rsp),%xmm0
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  call   <smprintf@plt>
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L4:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <smprintf@plt>
  jmp    L3
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D17
type: string
name: read_data
arguments: tag: D10
type: string

tool: D17: %.2f

tool: 

assistant: ```c
char *loadavg(void) {
  double avgs[1];
  if (getloadavg(avgs, 1) < 0)
    return smprintf("");
  return smprintf("%.2f", avgs[0]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6a,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L4
L27:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl -0x9(%rbp),%edx
  imul   %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  addb   $0x2,-0xa(%rbp)
L4:
  cmpb   $0x0,-0xa(%rbp)
  je     L27
  movzbl -0x9(%rbp),%eax
  lea    0x5e(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] = state[local1] * state[0UL];
      state[local1] = state[0UL] + state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 838946365UL) - (unsigned char)223;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6a,%eax
  imul   %eax,%eax
  lea    0x5e(%rax,%rax,1),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] = state[local1] * state[0UL];
      state[local1] = state[0UL] + state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 838946365UL) - (unsigned char)223;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6a,%eax
  imul   %eax,%eax
  lea    0x5e(%rax,%rax,1),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] = state[local1] * state[0UL];
      state[local1] = state[0UL] + state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 838946365UL) - (unsigned char)223;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6a,%eax
  imul   %eax,%eax
  lea    0x5e(%rax,%rax,1),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] = state[local1] * state[0UL];
      state[local1] = state[0UL] + state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 838946365UL) - (unsigned char)223;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x8,%rsp
  push   $0x0
  push   $0x7
  push   $0x6
  mov    $0x5,%r9d
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <fct2@plt>
  add    $0x20,%rsp
  test   %rax,%rax
  je     L1
  mov    $0x0,%eax
  call   <abort@plt>
L1:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int __attribute__((sysv_abi)) main() {
  if (fct2(-1, 1ll, 2ll, 3ll, 4ll, 5ll, 6ll, 7ll, 0ll) != 0)
    abort();
  return 0;
}
```