ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<put_txt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L15
L28:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    $0x1,%edx
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <write@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L28
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *put_txt(const char *fr, int *ret) {
  while (*fr && *fr != '%') {
    write(1, fr++, 1);
    (*ret)++;
  }
  return (fr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<put_txt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  mov    %rsi,%rbp
  cmp    $0x25,%al
  je     L5
L13:
  add    $0x1,%rbx
  lea    -0x1(%rbx),%esi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  addl   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L5
  cmp    $0x25,%al
  jne    L13
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *put_txt(const char *fr, int *ret) {
  while (*fr && *fr != '%') {
    write(1, fr++, 1);
    (*ret)++;
  }
  return (fr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<put_txt>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  mov    %rsi,%rbx
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%r12
  mov    $0x1,%edx
  mov    $0x1,%edi
  lea    -0x1(%r12),%esi
  call   <write@plt>
  addl   $0x1,(%rbx)
  movzbl (%r12),%eax
  test   %al,%al
  je     L10
L31:
  cmp    $0x25,%al
  jne    L6
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *put_txt(const char *fr, int *ret) {
  while (*fr && *fr != '%') {
    write(1, fr++, 1);
    (*ret)++;
  }
  return (fr);
}
```
user: What is the c source code of the assembly code below:

```asm
<put_txt>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  mov    %rsi,%rbx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x1,%r12
  mov    $0x1,%edx
  mov    $0x1,%edi
  lea    -0x1(%r12),%esi
  call   <write@plt>
  addl   $0x1,(%rbx)
  movzbl (%r12),%eax
  test   %al,%al
  je     L9
L1:
  cmp    $0x25,%al
  jne    L38
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *put_txt(const char *fr, int *ret) {
  while (*fr && *fr != '%') {
    write(1, fr++, 1);
    (*ret)++;
  }
  return (fr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L22
L19:
  cmpl   $0x40,-0x4(%rbp)
  jle    L14
  cmpl   $0x5a,-0x4(%rbp)
  jg     L14
  addl   $0x20,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L22:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L19
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int ch;
  while ((ch = getchar()) != EOF) {
    if (ch >= 65 && ch <= 90)
      ch += ('a' - 'A');
    putchar(ch);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L2
L7:
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%edx
  cmovb  %eax,%edi
  call   <putchar@plt>
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    D2(%rip),%rax
  cmp    %edi,(%rax)
  jne    L7
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int ch;
  while ((ch = getchar()) != EOF) {
    if (ch >= 65 && ch <= 90)
      ch += ('a' - 'A');
    putchar(ch);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rbx
  jmp    L18
  xchg   %ax,%ax
L3:
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%edx
  cmovb  %eax,%edi
  call   <putchar@plt>
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int ch;
  while ((ch = getchar()) != EOF) {
    if (ch >= 65 && ch <= 90)
      ch += ('a' - 'A');
    putchar(ch);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
  jmp    L4
  xchg   %ax,%ax
L0:
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%edx
  cmovb  %eax,%edi
  call   <putchar@plt>
L4:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L0
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int ch;
  while ((ch = getchar()) != EOF) {
    if (ch >= 65 && ch <= 90)
      ch += ('a' - 'A');
    putchar(ch);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6867666564636261,%rax
  movabs $0x706f6e6d6c6b6a69,%rdx
  mov    %rax,-0x80(%rbp)
  mov    %rdx,-0x78(%rbp)
  movabs $0x4021767574737271,%rax
  movabs $0x29282a265e252423,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movabs $0x3e3f3a227d7b2b5f,%rax
  movabs $0x5d5b273b2f2e2c3c,%rdx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movl   $0x7c2d3d,-0x50(%rbp)
  movabs $0x4847464544434241,%rsi
  movabs $0x504f4e4d4c4b4a49,%rdi
  mov    %rsi,-0x40(%rbp)
  mov    %rdi,-0x38(%rbp)
  movabs $0x4021565554535251,%rsi
  movabs $0x29282a265e252423,%rdi
  mov    %rsi,-0x30(%rbp)
  mov    %rdi,-0x28(%rbp)
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x7c2d3d,-0x10(%rbp)
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main() {
  char lo[] = "abcdefghijklmnopqrstuv!@#$%^&*()_+{}\":?><,./;'[]=-|";
  char up[] = "ABCDEFGHIJKLMNOPQRSTUV!@#$%^&*()_+{}\":?><,./;'[]=-|";
  test(lo);
  test(up);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movabs $0x6867666564636261,%rax
  movabs $0x706f6e6d6c6b6a69,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x4021767574737271,%rax
  movabs $0x29282a265e252423,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x3e3f3a227d7b2b5f,%rax
  movabs $0x5d5b273b2f2e2c3c,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movl   $0x7c2d3d,0x30(%rsp)
  movabs $0x4847464544434241,%rsi
  movabs $0x504f4e4d4c4b4a49,%rdi
  mov    %rsi,0x40(%rsp)
  mov    %rdi,0x48(%rsp)
  movabs $0x4021565554535251,%rsi
  movabs $0x29282a265e252423,%rdi
  mov    %rsi,0x50(%rsp)
  mov    %rdi,0x58(%rsp)
  mov    %rax,0x60(%rsp)
  mov    %rdx,0x68(%rsp)
  movl   $0x7c2d3d,0x70(%rsp)
  mov    %rsp,%rdi
  call   <test@plt>
  lea    0x40(%rsp),%rdi
  call   <test@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x88,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char lo[] = "abcdefghijklmnopqrstuv!@#$%^&*()_+{}\":?><,./;'[]=-|";
  char up[] = "ABCDEFGHIJKLMNOPQRSTUV!@#$%^&*()_+{}\":?><,./;'[]=-|";
  test(lo);
  test(up);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  movdqa D43(%rip),%xmm0
  movdqa D23(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x7c2d3d,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D40(%rip),%xmm0
  movaps %xmm1,0x40(%rsp)
  movdqa D35(%rip),%xmm1
  movaps %xmm0,0x10(%rsp)
  movdqa D48(%rip),%xmm0
  movl   $0x7c2d3d,0x70(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm1,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  call   <test@plt>
  lea    0x40(%rsp),%rdi
  call   <test@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x88,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D43
datatype: byte[16]
name: parse_data
arguments: tag: D23
datatype: byte[16]
name: parse_data
arguments: tag: D40
datatype: byte[16]
name: parse_data
arguments: tag: D35
datatype: byte[16]
name: parse_data
arguments: tag: D48
datatype: byte[16]

tool: {"D43": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70]}

tool: {"D23": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D40": [0x71,0x72,0x73,0x74,0x75,0x76,0x21,0x40,0x23,0x24,0x25,0x5e,0x26,0x2a,0x28,0x29]}

tool: {"D35": [0x51,0x52,0x53,0x54,0x55,0x56,0x21,0x40,0x23,0x24,0x25,0x5e,0x26,0x2a,0x28,0x29]}

tool: {"D48": [0x5f,0x2b,0x7b,0x7d,0x22,0x3a,0x3f,0x3e,0x3c,0x2c,0x2e,0x2f,0x3b,0x27,0x5b,0x5d]}

assistant: ```c
int main() {
  char lo[] = "abcdefghijklmnopqrstuv!@#$%^&*()_+{}\":?><,./;'[]=-|";
  char up[] = "ABCDEFGHIJKLMNOPQRSTUV!@#$%^&*()_+{}\":?><,./;'[]=-|";
  test(lo);
  test(up);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  movdqa D25(%rip),%xmm0
  movdqa D41(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x7c2d3d,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D9(%rip),%xmm0
  movaps %xmm1,0x40(%rsp)
  movdqa D23(%rip),%xmm1
  movaps %xmm0,0x10(%rsp)
  movdqa D5(%rip),%xmm0
  movl   $0x7c2d3d,0x70(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm1,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  call   <test@plt>
  lea    0x40(%rsp),%rdi
  call   <test@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x88,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
data_type: byte[16]
name: retrieve_data
arguments: data_label: D41
data_type: byte[16]
name: retrieve_data
arguments: data_label: D9
data_type: byte[16]
name: retrieve_data
arguments: data_label: D23
data_type: byte[16]
name: retrieve_data
arguments: data_label: D5
data_type: byte[16]

tool: {"D25": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70]}

tool: {"D41": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D9": [0x71,0x72,0x73,0x74,0x75,0x76,0x21,0x40,0x23,0x24,0x25,0x5e,0x26,0x2a,0x28,0x29]}

tool: {"D23": [0x51,0x52,0x53,0x54,0x55,0x56,0x21,0x40,0x23,0x24,0x25,0x5e,0x26,0x2a,0x28,0x29]}

tool: {"D5": [0x5f,0x2b,0x7b,0x7d,0x22,0x3a,0x3f,0x3e,0x3c,0x2c,0x2e,0x2f,0x3b,0x27,0x5b,0x5d]}

assistant: ```c
int main() {
  char lo[] = "abcdefghijklmnopqrstuv!@#$%^&*()_+{}\":?><,./;'[]=-|";
  char up[] = "ABCDEFGHIJKLMNOPQRSTUV!@#$%^&*()_+{}\":?><,./;'[]=-|";
  test(lo);
  test(up);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cd_mat_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int cd_mat_memcpy(double *dst, const double *src, const int m, const int n) {
  memcpy(dst, src, m * n * sizeof(double));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cd_mat_memcpy>:
  endbr64
  sub    $0x8,%rsp
  imul   %ecx,%edx
  shl    $0x3,%edx
  call   <memcpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cd_mat_memcpy(double *dst, const double *src, const int m, const int n) {
  memcpy(dst, src, m * n * sizeof(double));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cd_mat_memcpy>:
  endbr64
  imul   %ecx,%edx
  sub    $0x8,%rsp
  shl    $0x3,%edx
  call   <memcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cd_mat_memcpy(double *dst, const double *src, const int m, const int n) {
  memcpy(dst, src, m * n * sizeof(double));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cd_mat_memcpy>:
  endbr64
  imul   %ecx,%edx
  sub    $0x8,%rsp
  shl    $0x3,%edx
  call   <memcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cd_mat_memcpy(double *dst, const double *src, const int m, const int n) {
  memcpy(dst, src, m * n * sizeof(double));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pms_change_wakeup_timers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%edi
  call   <pms_set_wakeup_timers@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pms_set_wakeup_timers@plt>
  leave
  ret
```

assistant: ```c
int pms_change_wakeup_timers(unsigned long long second) {
  pms_set_wakeup_timers(0);
  return pms_set_wakeup_timers(second);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pms_change_wakeup_timers>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <pms_set_wakeup_timers@plt>
  mov    %rbx,%rdi
  call   <pms_set_wakeup_timers@plt>
  pop    %rbx
  ret
```

assistant: ```c
int pms_change_wakeup_timers(unsigned long long second) {
  pms_set_wakeup_timers(0);
  return pms_set_wakeup_timers(second);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pms_change_wakeup_timers>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <pms_set_wakeup_timers@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <pms_set_wakeup_timers@plt>
```

assistant: ```c
int pms_change_wakeup_timers(unsigned long long second) {
  pms_set_wakeup_timers(0);
  return pms_set_wakeup_timers(second);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pms_change_wakeup_timers>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <pms_set_wakeup_timers@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <pms_set_wakeup_timers@plt>
```

assistant: ```c
int pms_change_wakeup_timers(unsigned long long second) {
  pms_set_wakeup_timers(0);
  return pms_set_wakeup_timers(second);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L15
L7:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L7
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  uint8_t *p = (uint8_t *)s;
  for (size_t m = 0; m < n; m++) {
    *p++ = c;
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L17
  mov    $0x0,%ecx
L0:
  mov    %esi,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L0
L17:
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  uint8_t *p = (uint8_t *)s;
  for (size_t m = 0; m < n; m++) {
    *p++ = c;
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L6
  xor    %ecx,%ecx
  xchg   %ax,%ax
L10:
  mov    %esi,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L10
L6:
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  uint8_t *p = (uint8_t *)s;
  for (size_t m = 0; m < n; m++) {
    *p++ = c;
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L38
  lea    -0x1(%rdx),%rcx
  cmp    $0x2,%rcx
  jbe    L22
  mov    %rdx,%r8
  movd   %esi,%xmm1
  xor    %ecx,%ecx
  shr    $0x2,%r8
  pshufd $0x0,%xmm1,%xmm0
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rcx,%rdi
  add    $0x1,%rcx
  shl    $0x4,%rdi
  movups %xmm0,(%rax,%rdi,1)
  cmp    %rcx,%r8
  jne    L11
  mov    %rdx,%rcx
  and    $0xfffffffffffffffc,%rcx
  lea    (%rax,%rcx,4),%rdi
  cmp    %rcx,%rdx
  je     L39
L52:
  lea    0x1(%rcx),%r8
  mov    %esi,(%rdi)
  cmp    %r8,%rdx
  jbe    L38
  add    $0x2,%rcx
  mov    %esi,0x4(%rdi)
  cmp    %rcx,%rdx
  jbe    L38
  mov    %esi,0x8(%rdi)
L38:
  ret
  nop
L39:
  ret
L22:
  xor    %ecx,%ecx
  jmp    L52
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  uint8_t *p = (uint8_t *)s;
  for (size_t m = 0; m < n; m++) {
    *p++ = c;
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtobignum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movzbl (%rdi),%eax
  cmp    $0x30,%al
  jne    L9
L24:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x30,%al
  je     L24
L9:
  test   %al,%al
  jne    L70
  movl   $0x1,0x0(%rbp)
  movl   $0x0,0x4(%rbp)
L81:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L70:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r10d
  lea    0x2(%rax),%eax
  mov    %r10d,%edx
  sub    $0x1,%edx
  cmovns %edx,%eax
  sar    $0x2,%eax
  add    $0x1,%eax
  mov    %eax,0x0(%rbp)
  cmp    $0x1,%eax
  jle    L3
  lea    0x4(%rbp),%r8
  mov    %r10d,%edi
  mov    $0x1,%r9d
  movslq %r10d,%r11
  add    %rbp,%r11
L43:
  mov    %r8,%rcx
  movl   $0x0,(%r8)
  mov    %r11,%rax
  sub    %r8,%rax
L95:
  mov    (%rcx),%edx
  lea    (%rdx,%rdx,4),%esi
  movsbl (%rbx,%rax,1),%edx
  lea    -0x30(%rdx,%rsi,2),%edx
  mov    %edx,(%rcx)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L95
  add    $0x1,%r9d
  add    $0x4,%r8
  sub    $0x4,%edi
  cmp    %r9d,0x0(%rbp)
  jg     L43
L17:
  movslq %r9d,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  movl   $0x0,(%rcx)
  lea    -0x4(,%r9,4),%eax
  sub    %eax,%r10d
  test   %r10d,%r10d
  jle    L81
  mov    %rbx,%rax
  lea    -0x1(%r10),%edx
  lea    0x1(%rbx,%rdx,1),%rdi
L54:
  mov    (%rcx),%edx
  lea    (%rdx,%rdx,4),%esi
  movsbl (%rax),%edx
  lea    -0x30(%rdx,%rsi,2),%edx
  mov    %edx,(%rcx)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L54
  jmp    L81
L3:
  mov    $0x1,%r9d
  jmp    L17
```

assistant: ```c
void strtobignum(char *s, int *d) {
  int a, l, t, i;
  while (*s == '0')
    s++;
  if (*s == '\0') {
    d[0] = 1;
    d[1] = 0;
    return;
  }
  l = strlen(s);
  d[0] = (l - 1) / 4 + 1;
  for (i = 1; i < d[0]; i++)
    for (d[i] = 0, a = l - 4 * i; a < l - 4 * (i - 1); a++)
      d[i] = d[i] * 10 + s[a] - '0';
  for (d[i] = 0, a = 0; a < l - 4 * (i - 1); a++)
    d[i] = d[i] * 10 + s[a] - '0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtobignum>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  cmp    $0x30,%al
  jne    L60
  nopw   0x0(%rax,%rax,1)
L27:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x30,%al
  je     L27
L60:
  test   %al,%al
  jne    L75
  movq   $0x1,0x0(%rbp)
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L75:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  lea    0x2(%rax),%edx
  sub    $0x1,%ecx
  cmovns %ecx,%edx
  sar    $0x2,%edx
  add    $0x1,%edx
  mov    %edx,0x0(%rbp)
  cmp    $0x1,%edx
  jle    L14
  movslq %eax,%r11
  lea    0x4(%rbp),%rdi
  mov    $0x1,%r9d
  add    %rbp,%r11
  nopl   (%rax)
L64:
  movl   $0x0,(%rdi)
  mov    %eax,%r8d
  mov    %r11,%rcx
  sub    $0x4,%eax
  mov    %eax,%r10d
  sub    %rdi,%rcx
  xor    %edx,%edx
  nop
L36:
  lea    (%rdx,%rdx,4),%esi
  movsbl (%rbx,%rcx,1),%edx
  add    $0x1,%rcx
  lea    -0x30(%rdx,%rsi,2),%edx
  mov    %edx,(%rdi)
  cmp    %ecx,%r8d
  jg     L36
  add    $0x1,%r9d
  add    $0x4,%rdi
  cmp    %r9d,0x0(%rbp)
  jg     L64
  movslq %r9d,%rax
  shl    $0x2,%rax
L10:
  add    %rax,%rbp
  movl   $0x0,0x0(%rbp)
  test   %r10d,%r10d
  jle    L67
  lea    -0x1(%r10),%eax
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L72:
  lea    (%rax,%rax,4),%edx
  movsbl (%rbx),%eax
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%eax
  mov    %eax,0x0(%rbp)
  cmp    %rbx,%rcx
  jne    L72
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    %eax,%r10d
  mov    $0x4,%eax
  jmp    L10
```

assistant: ```c
void strtobignum(char *s, int *d) {
  int a, l, t, i;
  while (*s == '0')
    s++;
  if (*s == '\0') {
    d[0] = 1;
    d[1] = 0;
    return;
  }
  l = strlen(s);
  d[0] = (l - 1) / 4 + 1;
  for (i = 1; i < d[0]; i++)
    for (d[i] = 0, a = l - 4 * i; a < l - 4 * (i - 1); a++)
      d[i] = d[i] * 10 + s[a] - '0';
  for (d[i] = 0, a = 0; a < l - 4 * (i - 1); a++)
    d[i] = d[i] * 10 + s[a] - '0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtobignum>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  cmp    $0x30,%al
  jne    L32
  nopw   0x0(%rax,%rax,1)
L21:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x30,%al
  je     L21
L32:
  test   %al,%al
  jne    L3
  mov    D8(%rip),%rax
  mov    %rax,0x0(%rbp)
L87:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  lea    0x2(%rax),%edx
  sub    $0x1,%ecx
  cmovns %ecx,%edx
  sar    $0x2,%edx
  add    $0x1,%edx
  mov    %edx,0x0(%rbp)
  cmp    $0x1,%edx
  jle    L77
  movslq %eax,%r11
  lea    0x4(%rbp),%rdi
  mov    $0x1,%r9d
  add    %rbp,%r11
  nopl   (%rax)
L27:
  movl   $0x0,(%rdi)
  mov    %eax,%r8d
  mov    %r11,%rcx
  sub    $0x4,%eax
  mov    %eax,%r10d
  sub    %rdi,%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L61:
  lea    (%rdx,%rdx,4),%esi
  movsbl (%rbx,%rcx,1),%edx
  add    $0x1,%rcx
  lea    -0x30(%rdx,%rsi,2),%edx
  mov    %edx,(%rdi)
  cmp    %ecx,%r8d
  jg     L61
  add    $0x1,%r9d
  add    $0x4,%rdi
  cmp    %r9d,0x0(%rbp)
  jg     L27
  movslq %r9d,%rax
  shl    $0x2,%rax
L25:
  add    %rax,%rbp
  movl   $0x0,0x0(%rbp)
  test   %r10d,%r10d
  jle    L87
  lea    -0x1(%r10),%eax
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L50:
  lea    (%rax,%rax,4),%edx
  movsbl (%rbx),%eax
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%eax
  mov    %eax,0x0(%rbp)
  cmp    %rbx,%rcx
  jne    L50
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L77:
  mov    %eax,%r10d
  mov    $0x4,%eax
  jmp    L25
```

tool_calls: name: read_data
arguments: label: D8
type_infered: byte[8]

tool: {"D8": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void strtobignum(char *s, int *d) {
  int a, l, t, i;
  while (*s == '0')
    s++;
  if (*s == '\0') {
    d[0] = 1;
    d[1] = 0;
    return;
  }
  l = strlen(s);
  d[0] = (l - 1) / 4 + 1;
  for (i = 1; i < d[0]; i++)
    for (d[i] = 0, a = l - 4 * i; a < l - 4 * (i - 1); a++)
      d[i] = d[i] * 10 + s[a] - '0';
  for (d[i] = 0, a = 0; a < l - 4 * (i - 1); a++)
    d[i] = d[i] * 10 + s[a] - '0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rta_getattr_s64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <RTA_DATA@plt>
  mov    %eax,%ecx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
__s64 rta_getattr_s64(const struct rtattr *rta) {
  __s64 tmp;
  memcpy(&tmp, RTA_DATA(rta), sizeof(tmp));
  return tmp;
}
```