ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r11d
  test   %r11d,%r11d
  jle    L57
  add    $0x1,%r11d
  mov    $0x2,%r10d
  mov    $0x0,%r9d
  mov    $0x1,%esi
  jmp    L80
L78:
  add    $0x1,%eax
  cmp    %edi,%eax
  je     L46
L112:
  lea    (%rdx,%rax,1),%ecx
  cmp    %esi,%ecx
  jle    L78
  lea    (%rsi,%rax,1),%ecx
  cmp    %ecx,%edx
  jge    L78
  cmp    %r8d,%eax
  setl   %cl
  movzbl %cl,%ecx
  add    %ecx,%r9d
  jmp    L78
L46:
  add    $0x1,%edx
  add    $0x1,%edi
  add    $0x1,%r8d
  cmp    %r10d,%edx
  je     L5
L67:
  mov    $0x1,%eax
  test   %edx,%edx
  jg     L112
  jmp    L46
L5:
  add    $0x1,%esi
  add    $0x1,%r10d
  cmp    %r11d,%esi
  je     L106
L80:
  mov    %r10d,%r8d
  mov    $0x2,%edi
  mov    $0x1,%edx
  test   %esi,%esi
  jg     L67
  jmp    L5
L57:
  mov    $0x0,%r9d
L106:
  mov    %r9d,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D10
type_guessed: string

tool: D3: %d

tool: D10: Number of possible triangle is %d

assistant: ```c
int main() {
  int i, j, k, N, count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i = i + 1) {
    for (j = 1; j <= i; j = j + 1) {
      for (k = 1; k <= j; k = k + 1) {
        if ((j + k > i) && (k + i > j) && (i + j > k))
          count++;
      }
    }
  }
  printf("Number of possible triangle is %d", count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%r11d
  test   %r11d,%r11d
  jle    L0
  add    $0x1,%r11d
  mov    $0x2,%r10d
  xor    %r9d,%r9d
  mov    $0x1,%esi
  nopl   0x0(%rax)
L17:
  mov    %r10d,%r8d
  mov    $0x2,%edi
  mov    $0x1,%ecx
  nopl   (%rax)
L48:
  mov    $0x1,%eax
  nopl   (%rax)
L49:
  lea    (%rcx,%rax,1),%edx
  cmp    %edx,%esi
  jge    L35
  lea    (%rsi,%rax,1),%edx
  cmp    %ecx,%edx
  jle    L35
  xor    %edx,%edx
  cmp    %r8d,%eax
  setl   %dl
  add    %edx,%r9d
L35:
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L49
  add    $0x1,%ecx
  lea    0x1(%rax),%edi
  add    $0x1,%r8d
  cmp    %r10d,%ecx
  jne    L48
  add    $0x1,%esi
  add    $0x1,%r10d
  cmp    %r11d,%esi
  jne    L17
L13:
  mov    %r9d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  xor    %r9d,%r9d
  jmp    L13
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string
name: disassemble_data
arguments: tag: D18
datatype: string

tool: D7: %d

tool: D18: Number of possible triangle is %d

assistant: ```c
int main() {
  int i, j, k, N, count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i = i + 1) {
    for (j = 1; j <= i; j = j + 1) {
      for (k = 1; k <= j; k = k + 1) {
        if ((j + k > i) && (k + i > j) && (i + j > k))
          count++;
      }
    }
  }
  printf("Number of possible triangle is %d", count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<tle_fld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x40(%rbp),%eax
  sub    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  lea    -0x30(%rbp),%rax
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: %.*s

assistant: ```c
double tle_fld(char *l, int from, int thru) {
  char buf[32];
  sprintf(buf, "%.*s", thru - from + 1, l + from - 1);
  return (atod(buf));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tle_fld>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    -0x1(%rax,%rdi,1),%rcx
  sub    %esi,%edx
  add    $0x1,%edx
  mov    %rsp,%rbx
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <atod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: %.*s

assistant: ```c
double tle_fld(char *l, int from, int thru) {
  char buf[32];
  sprintf(buf, "%.*s", thru - from + 1, l + from - 1);
  return (atod(buf));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tle_fld>:
  endbr64
  push   %rbp
  sub    %esi,%edx
  add    $0x1,%edx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movslq %esi,%rax
  lea    D5(%rip),%rsi
  lea    -0x1(%rax,%rdi,1),%rcx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <atod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: %.*s

assistant: ```c
double tle_fld(char *l, int from, int thru) {
  char buf[32];
  sprintf(buf, "%.*s", thru - from + 1, l + from - 1);
  return (atod(buf));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tle_fld>:
  endbr64
  push   %rbp
  sub    %esi,%edx
  add    $0x1,%edx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movslq %esi,%rax
  lea    D2(%rip),%rsi
  lea    -0x1(%rax,%rdi,1),%rcx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <atod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: %.*s

assistant: ```c
double tle_fld(char *l, int from, int thru) {
  char buf[32];
  sprintf(buf, "%.*s", thru - from + 1, l + from - 1);
  return (atod(buf));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ipow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L14:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ipow(int i1, int i2) {
  int i;
  int i3 = 1;
  for (i = 0; i < i2; ++i)
    i3 *= i1;
  return (i3);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ipow>:
  endbr64
  test   %esi,%esi
  jle    L27
  mov    $0x1,%edx
  mov    $0x0,%eax
L22:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L22
L23:
  mov    %edx,%eax
  ret
L27:
  mov    $0x1,%edx
  jmp    L23
```

assistant: ```c
int ipow(int i1, int i2) {
  int i;
  int i3 = 1;
  for (i = 0; i < i2; ++i)
    i3 *= i1;
  return (i3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ipow>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L15
  xor    %eax,%eax
L8:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L8
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ipow(int i1, int i2) {
  int i;
  int i3 = 1;
  for (i = 0; i < i2; ++i)
    i3 *= i1;
  return (i3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ipow>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L8
  xor    %eax,%eax
L13:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L13
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ipow(int i1, int i2) {
  int i;
  int i3 = 1;
  for (i = 0; i < i2; ++i)
    i3 *= i1;
  return (i3);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L49
L34:
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L17:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L12
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L15
L67:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L67
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rax,(%rdx)
L12:
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L17
  addl   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_sort(long long *arr, int n) {
  int i, j, k, temp;
  for (i = 1; i <= n; i++) {
    for (j = 0; j < i; j++) {
      if (arr[j] > arr[i]) {
        temp = arr[j];
        arr[j] = arr[i];
        for (k = i; k > j; k--)
          arr[k] = arr[k - 1];
        arr[k + 1] = temp;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<insertion_sort>:
  endbr64
  test   %esi,%esi
  jle    L67
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  lea    0x8(%rdi),%r9
  lea    0x1(%rsi),%r13d
  mov    $0x1,%r8d
  jmp    L81
L33:
  mov    %r12d,%eax
L0:
  cltq
  movslq %esi,%rsi
  mov    %rsi,0x8(%r10,%rax,8)
L10:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L16
L48:
  mov    (%r10,%rdx,8),%rsi
  mov    (%r9),%rax
  cmp    %rax,%rsi
  jle    L10
  mov    %rax,(%r10,%rdx,8)
  cmp    %edx,%ebx
  jle    L33
  mov    %r11d,%eax
  sub    %edx,%eax
  shl    $0x3,%rax
  mov    %rbp,%rdi
  sub    %rax,%rdi
  mov    %r9,%rax
L28:
  mov    -0x8(%rax),%rcx
  mov    %rcx,(%rax)
  sub    $0x8,%rax
  cmp    %rdi,%rax
  jne    L28
  mov    %edx,%eax
  jmp    L0
L16:
  add    $0x1,%r8
  add    $0x8,%r9
  cmp    %r13,%r8
  je     L19
L81:
  mov    %r8d,%r11d
  mov    %r8d,%r12d
  mov    %r8d,%ebx
  mov    $0x0,%edx
  lea    -0x8(%r9),%rbp
  sub    $0x1,%r11d
  test   %r8d,%r8d
  jg     L48
  jmp    L16
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  ret
```

assistant: ```c
void insertion_sort(long long *arr, int n) {
  int i, j, k, temp;
  for (i = 1; i <= n; i++) {
    for (j = 0; j < i; j++) {
      if (arr[j] > arr[i]) {
        temp = arr[j];
        arr[j] = arr[i];
        for (k = i; k > j; k--)
          arr[k] = arr[k - 1];
        arr[k + 1] = temp;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertion_sort>:
  endbr64
  test   %esi,%esi
  jle    L32
  push   %r15
  lea    0x1(%rsi),%eax
  mov    %rdi,%r15
  mov    $0x8,%r9d
  push   %r14
  lea    0x10(%rdi),%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L49:
  lea    -0x1(%r13),%r12d
  xor    %ebx,%ebx
  jmp    L14
L27:
  add    $0x1,%rbx
  sub    $0x1,%r12d
  cmp    %r13,%rbx
  je     L40
L14:
  mov    (%r15,%rbx,8),%rbp
  mov    -0x8(%r14),%rax
  mov    %r14,%rcx
  cmp    %rax,%rbp
  jle    L27
  mov    %rax,(%r15,%rbx,8)
  cmp    %r13d,%ebx
  jge    L37
  mov    %r12d,%edx
  mov    %r9,(%rsp)
  mov    %rdx,%rax
  lea    0x8(,%rdx,8),%rdx
  neg    %rax
  shl    $0x3,%rax
  lea    (%rax,%r9,1),%rcx
  lea    -0x8(%r9,%rax,1),%rsi
  add    %r15,%rcx
  add    %r15,%rsi
  mov    %rcx,%rdi
  call   <memmove@plt>
  mov    (%rsp),%r9
  mov    %rax,%rcx
L37:
  movslq %ebp,%rbp
  add    $0x1,%rbx
  sub    $0x1,%r12d
  mov    %rbp,(%rcx)
  cmp    %r13,%rbx
  jne    L14
L40:
  add    $0x1,%r13
  add    $0x8,%r14
  add    $0x8,%r9
  cmp    0x8(%rsp),%r13
  jne    L49
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  ret
```

assistant: ```c
void insertion_sort(long long *arr, int n) {
  int i, j, k, temp;
  for (i = 1; i <= n; i++) {
    for (j = 0; j < i; j++) {
      if (arr[j] > arr[i]) {
        temp = arr[j];
        arr[j] = arr[i];
        for (k = i; k > j; k--)
          arr[k] = arr[k - 1];
        arr[k + 1] = temp;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insertion_sort>:
  endbr64
  test   %esi,%esi
  jle    L8
  push   %r15
  lea    0x1(%rsi),%eax
  mov    $0x8,%r10d
  mov    $0x1,%r8d
  push   %r14
  lea    0x8(%rdi),%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rax,0x28(%rsp)
  nopl   (%rax)
L102:
  mov    %r14,%rcx
  mov    %r8d,0x24(%rsp)
  mov    %rbp,%r14
  lea    -0x1(%r8),%r15d
  xor    %ebx,%ebx
  mov    %r8d,%ebp
  jmp    L11
  xchg   %ax,%ax
L37:
  add    $0x1,%rbx
  add    $0x1,%r12d
  sub    $0x1,%r15d
  cmp    %r8,%rbx
  je     L17
L11:
  mov    (%r14,%rbx,8),%r13
  mov    (%rcx),%rax
  mov    %ebx,%r12d
  cmp    %rax,%r13
  jle    L37
  mov    %r15d,%edx
  mov    %rax,(%r14,%rbx,8)
  xor    %eax,%eax
  mov    $0x8,%esi
  mov    %rdx,%r9
  lea    0x8(,%rdx,8),%rdx
  mov    %rcx,0x18(%rsp)
  movslq %r13d,%r13
  neg    %r9
  mov    %r8,0x10(%rsp)
  shl    $0x3,%r9
  cmp    %ebx,%ebp
  mov    %r10,(%rsp)
  cmovg  %r9,%rax
  cmovle %rsi,%rdx
  mov    %r9,0x8(%rsp)
  lea    -0x8(%r10,%rax,1),%rsi
  add    %r10,%rax
  add    %r14,%rsi
  lea    (%r14,%rax,1),%rdi
  call   <memmove@plt>
  mov    0x8(%rsp),%r9
  mov    (%rsp),%r10
  mov    0x18(%rsp),%rcx
  mov    0x10(%rsp),%r8
  add    %r14,%r9
  mov    %r13,(%r9,%r10,1)
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L17:
  mov    0x24(%rsp),%r9d
  mov    %r14,%rbp
  movslq %r12d,%rax
  mov    %rcx,%r14
  cmp    %r9d,%r12d
  jl     L67
  jmp    L14
  nopl   (%rax)
L77:
  add    $0x1,%rax
  cmp    %eax,%r9d
  jle    L14
L67:
  mov    0x0(%rbp,%rax,8),%rdx
  mov    (%r14),%rcx
  cmp    %rdx,%rcx
  jge    L77
  mov    %rcx,0x0(%rbp,%rax,8)
  movslq %edx,%rdx
  add    $0x1,%rax
  mov    %rdx,0x8(%r14)
  cmp    %eax,%r9d
  jg     L67
L14:
  add    $0x1,%r8
  add    $0x8,%r14
  add    $0x8,%r10
  cmp    0x28(%rsp),%r8
  jne    L102
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  ret
```

assistant: ```c
void insertion_sort(long long *arr, int n) {
  int i, j, k, temp;
  for (i = 1; i <= n; i++) {
    for (j = 0; j < i; j++) {
      if (arr[j] > arr[i]) {
        temp = arr[j];
        arr[j] = arr[i];
        for (k = i; k > j; k--)
          arr[k] = arr[k - 1];
        arr[k + 1] = temp;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dos2unix_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L6:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L22
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L22:
  subq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x10(%rbp)
L18:
  cmpq   $0x0,-0x20(%rbp)
  jne    L6
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t dos2unix_buf(unsigned char *s, size_t size) {
  unsigned char *p = s, *q = s;
  for (; size; size--, p++) {
    if (*p != '\r')
      *q++ = *p;
  }
  *q = 0;
  return (size_t)(q - s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dos2unix_buf>:
  endbr64
  test   %rsi,%rsi
  je     L39
  add    %rdi,%rsi
  mov    %rdi,%rax
  mov    %rdi,%rdx
  jmp    L48
L22:
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  je     L42
L48:
  movzbl (%rdx),%ecx
  cmp    $0xd,%cl
  je     L22
  mov    %cl,(%rax)
  lea    0x1(%rax),%rax
  jmp    L22
L39:
  mov    %rdi,%rax
L42:
  movb   $0x0,(%rax)
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t dos2unix_buf(unsigned char *s, size_t size) {
  unsigned char *p = s, *q = s;
  for (; size; size--, p++) {
    if (*p != '\r')
      *q++ = *p;
  }
  *q = 0;
  return (size_t)(q - s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dos2unix_buf>:
  endbr64
  test   %rsi,%rsi
  je     L8
  add    %rdi,%rsi
  mov    %rdi,%rcx
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%rax),%edx
  cmp    $0xd,%dl
  je     L12
  mov    %dl,(%rcx)
  add    $0x1,%rcx
L12:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L15
  mov    %rcx,%rax
  movb   $0x0,(%rcx)
  sub    %rdi,%rax
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdi,%rcx
  xor    %eax,%eax
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
size_t dos2unix_buf(unsigned char *s, size_t size) {
  unsigned char *p = s, *q = s;
  for (; size; size--, p++) {
    if (*p != '\r')
      *q++ = *p;
  }
  *q = 0;
  return (size_t)(q - s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dos2unix_buf>:
  endbr64
  test   %rsi,%rsi
  je     L1
  add    %rdi,%rsi
  mov    %rdi,%rcx
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L20:
  movzbl (%rax),%edx
  cmp    $0xd,%dl
  je     L13
  mov    %dl,(%rcx)
  add    $0x1,%rcx
L13:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L20
  mov    %rcx,%rax
  movb   $0x0,(%rcx)
  sub    %rdi,%rax
  ret
  nopl   0x0(%rax)
L1:
  mov    %rdi,%rcx
  xor    %eax,%eax
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
size_t dos2unix_buf(unsigned char *s, size_t size) {
  unsigned char *p = s, *q = s;
  for (; size; size--, p++) {
    if (*p != '\r')
      *q++ = *p;
  }
  *q = 0;
  return (size_t)(q - s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gt_non_r_cmpfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int gt_non_r_cmpfunc(const void *a, const void *b, void *compar) {
  int (*cmpfunc)(const void *, const void *) = compar, rval;
  rval = (*cmpfunc)(a, b);
  return rval;
}
```
user: What is the c source code of the assembly code below:

```asm
<gt_non_r_cmpfunc>:
  endbr64
  sub    $0x8,%rsp
  call   *%rdx
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gt_non_r_cmpfunc(const void *a, const void *b, void *compar) {
  int (*cmpfunc)(const void *, const void *) = compar, rval;
  rval = (*cmpfunc)(a, b);
  return rval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gt_non_r_cmpfunc>:
  endbr64
  jmp    *%rdx
```

assistant: ```c
int gt_non_r_cmpfunc(const void *a, const void *b, void *compar) {
  int (*cmpfunc)(const void *, const void *) = compar, rval;
  rval = (*cmpfunc)(a, b);
  return rval;
}
```
user: What is the c source code of the assembly code below?

```asm
<gt_non_r_cmpfunc>:
  endbr64
  jmp    *%rdx
```

assistant: ```c
int gt_non_r_cmpfunc(const void *a, const void *b, void *compar) {
  int (*cmpfunc)(const void *, const void *) = compar, rval;
  rval = (*cmpfunc)(a, b);
  return rval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tailmatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L7
  mov    $0x0,%eax
  jmp    L3
L7:
  mov    -0x8(%rbp),%eax
  cltq
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L3:
  leave
  ret
```

assistant: ```c
int tailmatch(const char *s1, const char *tail) {
  int l1 = strlen(s1);
  int l2 = strlen(tail);
  if (l1 < l2)
    return 0;
  return strcmp(s1 + l1 - l2, tail) == 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tailmatch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%ebx
  jge    L10
L18:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  movslq %ebx,%rbx
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L18
```

assistant: ```c
int tailmatch(const char *s1, const char *tail) {
  int l1 = strlen(s1);
  int l2 = strlen(tail);
  if (l1 < l2)
    return 0;
  return strcmp(s1 + l1 - l2, tail) == 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tailmatch>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  jl     L1
  cltq
  mov    %r12,%rsi
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L1:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int tailmatch(const char *s1, const char *tail) {
  int l1 = strlen(s1);
  int l2 = strlen(tail);
  if (l1 < l2)
    return 0;
  return strcmp(s1 + l1 - l2, tail) == 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tailmatch>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  jl     L5
  cltq
  mov    %r12,%rsi
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L5:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int tailmatch(const char *s1, const char *tail) {
  int l1 = strlen(s1);
  int l2 = strlen(tail);
  if (l1 < l2)
    return 0;
  return strcmp(s1 + l1 - l2, tail) == 0;
}
```