ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mfd_assert_grow>:
  endbr64
  push   %rbp
  mov    $0x4000,%esi
  mov    %edi,%ebp
  call   <ftruncate@plt>
  test   %eax,%eax
  js     L16
L13:
  mov    $0x4000,%esi
  mov    %ebp,%edi
  call   <mfd_assert_size@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x8000,%ecx
  mov    %ebp,%edi
  call   <fallocate@plt>
  test   %eax,%eax
  js     L26
  mov    %ebp,%edi
  mov    $0x8000,%esi
  pop    %rbp
  jmp    10d0 <mfd_assert_size@plt>
  nopw   0x0(%rax,%rax,1)
L16:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L13
  nopl   (%rax)
L26:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <abort@plt>
  mov    %ebp,%edi
  mov    $0x8000,%esi
  pop    %rbp
  jmp    10d0 <mfd_assert_size@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string

tool: D18: ftruncate(GROW) failed: %m


tool: D16: fallocate(ALLOC) failed: %m


assistant: ```c
void mfd_assert_grow(int fd) {
  int r;
  r = ftruncate(fd, 8192 * 2);
  if (r < 0) {
    printf("ftruncate(GROW) failed: %m\n");
    abort();
  }
  mfd_assert_size(fd, 8192 * 2);
  r = fallocate(fd, 0, 0, 8192 * 4);
  if (r < 0) {
    printf("fallocate(ALLOC) failed: %m\n");
    abort();
  }
  mfd_assert_size(fd, 8192 * 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mfd_assert_grow>:
  endbr64
  push   %rbp
  mov    $0x4000,%esi
  mov    %edi,%ebp
  call   <ftruncate@plt>
  test   %eax,%eax
  js     L1
L16:
  mov    $0x4000,%esi
  mov    %ebp,%edi
  call   <mfd_assert_size@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x8000,%ecx
  mov    %ebp,%edi
  call   <fallocate@plt>
  test   %eax,%eax
  js     L14
  mov    %ebp,%edi
  mov    $0x8000,%esi
  pop    %rbp
  jmp    10d0 <mfd_assert_size@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L16
  nopl   (%rax)
L14:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <abort@plt>
  mov    %ebp,%edi
  mov    $0x8000,%esi
  pop    %rbp
  jmp    10d0 <mfd_assert_size@plt>
```

tool_calls: name: read_data
arguments: data_label: D17
datatype: string
name: read_data
arguments: data_label: D8
datatype: string

tool: D17: ftruncate(GROW) failed: %m


tool: D8: fallocate(ALLOC) failed: %m


assistant: ```c
void mfd_assert_grow(int fd) {
  int r;
  r = ftruncate(fd, 8192 * 2);
  if (r < 0) {
    printf("ftruncate(GROW) failed: %m\n");
    abort();
  }
  mfd_assert_size(fd, 8192 * 2);
  r = fallocate(fd, 0, 0, 8192 * 4);
  if (r < 0) {
    printf("fallocate(ALLOC) failed: %m\n");
    abort();
  }
  mfd_assert_size(fd, 8192 * 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DoClearScreenBuffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <screenBlitStart@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void DoClearScreenBuffer(void) {
  int w, h;
  uint8_t *p = screenBlitStart(&w, &h);
  memset(p, 0, w * h * 4);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<DoClearScreenBuffer>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <screenBlitStart@plt>
  mov    %rax,%rdi
  mov    (%rsp),%edx
  imul   0x4(%rsp),%edx
  shl    $0x2,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DoClearScreenBuffer(void) {
  int w, h;
  uint8_t *p = screenBlitStart(&w, &h);
  memset(p, 0, w * h * 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<DoClearScreenBuffer>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <screenBlitStart@plt>
  mov    (%rsp),%edx
  imul   0x4(%rsp),%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  shl    $0x2,%edx
  call   <memset@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DoClearScreenBuffer(void) {
  int w, h;
  uint8_t *p = screenBlitStart(&w, &h);
  memset(p, 0, w * h * 4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DoClearScreenBuffer>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <screenBlitStart@plt>
  mov    (%rsp),%edx
  imul   0x4(%rsp),%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  shl    $0x2,%edx
  call   <memset@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DoClearScreenBuffer(void) {
  int w, h;
  uint8_t *p = screenBlitStart(&w, &h);
  memset(p, 0, w * h * 4);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L21
  cmpq   $0x0,-0x18(%rbp)
  je     L21
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <piece_char@plt>
  mov    %al,-0xd(%rbp)
  jmp    L7
L34:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xd(%rbp)
  je     L43
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  jmp    L51
L43:
  mov    $0x2e,%eax
L51:
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L46:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L34
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L46
  jmp    L35
L21:
  nop
L35:
  leave
  ret
```

assistant: ```c
void unplace(char **piece, char **map) {
  int i;
  int j;
  int map_root;
  char p_al;
  if (!map || !piece)
    return;
  i = 0;
  j = 0;
  map_root = ft_strlen(map[0]);
  p_al = piece_char(piece);
  while (j < map_root) {
    while (i < map_root) {
      map[j][i] = map[j][i] == p_al ? '.' : map[j][i];
      i++;
    }
    i = 0;
    j++;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unplace>:
  endbr64
  test   %rsi,%rsi
  je     L6
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L43
  mov    (%rsi),%rdi
  call   <ft_strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <piece_char@plt>
  test   %ebx,%ebx
  jle    L43
  mov    %rbp,%rdi
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%rdx,8),%r10
  mov    %ebx,%r8d
  mov    $0x2e,%r9d
L13:
  mov    $0x0,%ecx
L19:
  mov    %rcx,%rsi
  add    (%rdi),%rsi
  movzbl (%rsi),%edx
  cmp    %al,%dl
  cmove  %r9d,%edx
  mov    %dl,(%rsi)
  add    $0x1,%rcx
  cmp    %rcx,%r8
  jne    L19
  add    $0x8,%rdi
  cmp    %r10,%rdi
  jne    L13
L43:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  ret
```

assistant: ```c
void unplace(char **piece, char **map) {
  int i;
  int j;
  int map_root;
  char p_al;
  if (!map || !piece)
    return;
  i = 0;
  j = 0;
  map_root = ft_strlen(map[0]);
  p_al = piece_char(piece);
  while (j < map_root) {
    while (i < map_root) {
      map[j][i] = map[j][i] == p_al ? '.' : map[j][i];
      i++;
    }
    i = 0;
    j++;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unplace>:
  endbr64
  test   %rsi,%rsi
  je     L40
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L12
  mov    (%rsi),%rdi
  mov    %rsi,%rbx
  call   <ft_strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <piece_char@plt>
  test   %ebp,%ebp
  jle    L12
  lea    -0x1(%rbp),%edx
  mov    %rbx,%rsi
  mov    %ebp,%r8d
  mov    $0x2e,%r9d
  lea    0x8(%rbx,%rdx,8),%r10
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L48:
  mov    (%rsi),%rdi
  add    %rcx,%rdi
  movzbl (%rdi),%edx
  cmp    %al,%dl
  cmove  %r9d,%edx
  add    $0x1,%rcx
  mov    %dl,(%rdi)
  cmp    %rcx,%r8
  jne    L48
  add    $0x8,%rsi
  cmp    %r10,%rsi
  jne    L18
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  ret
```

assistant: ```c
void unplace(char **piece, char **map) {
  int i;
  int j;
  int map_root;
  char p_al;
  if (!map || !piece)
    return;
  i = 0;
  j = 0;
  map_root = ft_strlen(map[0]);
  p_al = piece_char(piece);
  while (j < map_root) {
    while (i < map_root) {
      map[j][i] = map[j][i] == p_al ? '.' : map[j][i];
      i++;
    }
    i = 0;
    j++;
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<unplace>:
  endbr64
  test   %rsi,%rsi
  je     L26
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L67
  mov    (%rsi),%rdi
  mov    %rsi,%rbp
  call   <ft_strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <piece_char@plt>
  test   %ebx,%ebx
  jle    L67
  lea    -0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %ebx,%r8d
  lea    0x8(%rbp,%rdx,8),%r9
  nopl   0x0(%rax)
L68:
  xor    %edx,%edx
L23:
  mov    (%rsi),%rdi
L44:
  lea    (%rdi,%rdx,1),%rcx
  cmp    (%rcx),%al
  je     L70
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L44
  add    $0x8,%rsi
  cmp    %rsi,%r9
  jne    L68
L67:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L70:
  add    $0x1,%rdx
  movb   $0x2e,(%rcx)
  cmp    %rdx,%r8
  jne    L23
  add    $0x8,%rsi
  cmp    %rsi,%r9
  jne    L68
  jmp    L67
L26:
  ret
```

assistant: ```c
void unplace(char **piece, char **map) {
  int i;
  int j;
  int map_root;
  char p_al;
  if (!map || !piece)
    return;
  i = 0;
  j = 0;
  map_root = ft_strlen(map[0]);
  p_al = piece_char(piece);
  while (j < map_root) {
    while (i < map_root) {
      map[j][i] = map[j][i] == p_al ? '.' : map[j][i];
      i++;
    }
    i = 0;
    j++;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <q1@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  q1(argc, argv);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <q1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  q1(argc, argv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <q1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  q1(argc, argv);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <q1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  q1(argc, argv);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L22
  subq   $0x1,-0x8(%rbp)
  jmp    L3
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  jne    L60
  addq   $0x1,-0x8(%rbp)
  jmp    L13
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L34
  jmp    L13
L60:
  nop
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  leave
  ret
```

assistant: ```c
int get_index(char *attribute_name) {
  char *end_ptr;
  end_ptr = attribute_name + strlen(attribute_name) - 1;
  while (end_ptr != attribute_name) {
    if (isdigit(*end_ptr)) {
      end_ptr--;
      continue;
    }
    if (*end_ptr == '_') {
      end_ptr++;
      break;
    } else
      break;
  }
  return atoi(end_ptr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_index>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  je     L5
L11:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L3
  cmpb   $0x5f,(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
L5:
  mov    %rbx,%rdi
  call   <atoi@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L11
  jmp    L5
```

assistant: ```c
int get_index(char *attribute_name) {
  char *end_ptr;
  end_ptr = attribute_name + strlen(attribute_name) - 1;
  while (end_ptr != attribute_name) {
    if (isdigit(*end_ptr)) {
      end_ptr--;
      continue;
    }
    if (*end_ptr == '_') {
      end_ptr++;
      break;
    } else
      break;
  }
  return atoi(end_ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_index>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  je     L22
L14:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L23
  xor    %eax,%eax
  cmpb   $0x5f,0x0(%rbp)
  sete   %al
  add    %rax,%rbp
L22:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1090 <atoi@plt>
  cs nopw 0x0(%rax,%rax,1)
L23:
  sub    $0x1,%rbp
  cmp    %rbp,%rbx
  jne    L14
  jmp    L22
```

assistant: ```c
int get_index(char *attribute_name) {
  char *end_ptr;
  end_ptr = attribute_name + strlen(attribute_name) - 1;
  while (end_ptr != attribute_name) {
    if (isdigit(*end_ptr)) {
      end_ptr--;
      continue;
    }
    if (*end_ptr == '_') {
      end_ptr++;
      break;
    } else
      break;
  }
  return atoi(end_ptr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_index>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  je     L17
L21:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L38
  xor    %eax,%eax
  cmpb   $0x5f,0x0(%rbp)
  sete   %al
  add    %rax,%rbp
L17:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1090 <atoi@plt>
  cs nopw 0x0(%rax,%rax,1)
L38:
  sub    $0x1,%rbp
  cmp    %rbp,%rbx
  jne    L21
  jmp    L17
```

assistant: ```c
int get_index(char *attribute_name) {
  char *end_ptr;
  end_ptr = attribute_name + strlen(attribute_name) - 1;
  while (end_ptr != attribute_name) {
    if (isdigit(*end_ptr)) {
      end_ptr--;
      continue;
    }
    if (*end_ptr == '_') {
      end_ptr++;
      break;
    } else
      break;
  }
  return atoi(end_ptr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aes_rcon_prev>:
  endbr64
  mov    %rdi,%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L25
  mov    %edx,%eax
  shr    %al
  and    $0x2,%eax
  mov    %edx,%esi
  shr    %sil
  and    $0x10,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    %sil
  xor    %edx,%esi
  and    $0x1,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    %sil
  and    $0x20,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    $0x3,%sil
  xor    %edx,%esi
  shl    $0x2,%esi
  and    $0x4,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    $0x4,%sil
  xor    %edx,%esi
  shl    $0x3,%esi
  and    $0x8,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    $0x7,%sil
  shl    $0x6,%esi
  shl    $0x7,%edx
  or     %esi,%edx
  or     %edx,%eax
L15:
  mov    %al,(%rcx)
  ret
L25:
  mov    $0x36,%eax
  cmp    $0x10,%esi
  je     L15
  cmp    $0x18,%esi
  mov    $0x40,%eax
  mov    $0xffffff80,%edx
  cmove  %edx,%eax
  jmp    L15
```

assistant: ```c
void aes_rcon_prev(unsigned char *rcon, int key_len) {
  unsigned char rcon_tmp;
  if (*rcon) {
    rcon_tmp = *rcon;
    *rcon = 0x0;
    *rcon |= (((rcon_tmp >> 1) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 0;
    *rcon |= (((rcon_tmp >> 2) & 0x1)) << 1;
    *rcon |= (((rcon_tmp >> 3) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 2;
    *rcon |= (((rcon_tmp >> 4) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 3;
    *rcon |= (((rcon_tmp >> 5) & 0x1)) << 4;
    *rcon |= (((rcon_tmp >> 6) & 0x1)) << 5;
    *rcon |= (((rcon_tmp >> 7) & 0x1)) << 6;
    *rcon |= (((rcon_tmp >> 0) & 0x1)) << 7;
  } else {
    if (key_len == 16) {
      *rcon = 0x36;
    } else if (key_len == 24) {
      *rcon = 0x80;
    } else {
      *rcon = 0x40;
    }
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aes_rcon_prev>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rcx
  test   %dl,%dl
  je     L19
  mov    %edx,%eax
  mov    %edx,%esi
  shr    %al
  shr    %sil
  and    $0x10,%esi
  and    $0x2,%eax
  or     %esi,%eax
  mov    %edx,%esi
  shr    %sil
  xor    %edx,%esi
  and    $0x1,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    %sil
  and    $0x20,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    $0x3,%sil
  xor    %edx,%esi
  shl    $0x2,%esi
  and    $0x4,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    $0x4,%sil
  xor    %edx,%esi
  shl    $0x3,%esi
  and    $0x8,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shl    $0x7,%edx
  shr    $0x7,%sil
  shl    $0x6,%esi
  or     %esi,%edx
  or     %edx,%eax
L2:
  mov    %al,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0x36,%eax
  cmp    $0x10,%esi
  je     L2
  cmp    $0x18,%esi
  mov    $0x40,%eax
  mov    $0xffffff80,%edx
  cmove  %edx,%eax
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void aes_rcon_prev(unsigned char *rcon, int key_len) {
  unsigned char rcon_tmp;
  if (*rcon) {
    rcon_tmp = *rcon;
    *rcon = 0x0;
    *rcon |= (((rcon_tmp >> 1) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 0;
    *rcon |= (((rcon_tmp >> 2) & 0x1)) << 1;
    *rcon |= (((rcon_tmp >> 3) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 2;
    *rcon |= (((rcon_tmp >> 4) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 3;
    *rcon |= (((rcon_tmp >> 5) & 0x1)) << 4;
    *rcon |= (((rcon_tmp >> 6) & 0x1)) << 5;
    *rcon |= (((rcon_tmp >> 7) & 0x1)) << 6;
    *rcon |= (((rcon_tmp >> 0) & 0x1)) << 7;
  } else {
    if (key_len == 16) {
      *rcon = 0x36;
    } else if (key_len == 24) {
      *rcon = 0x80;
    } else {
      *rcon = 0x40;
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<aes_rcon_prev>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rcx
  test   %dl,%dl
  je     L9
  mov    %edx,%eax
  mov    %edx,%esi
  shr    %al
  shr    %sil
  and    $0x10,%esi
  and    $0x2,%eax
  or     %esi,%eax
  mov    %edx,%esi
  shr    %sil
  xor    %edx,%esi
  and    $0x1,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    %sil
  and    $0x20,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    $0x3,%sil
  xor    %edx,%esi
  shl    $0x2,%esi
  and    $0x4,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shr    $0x4,%sil
  xor    %edx,%esi
  shl    $0x3,%esi
  and    $0x8,%esi
  or     %esi,%eax
  mov    %edx,%esi
  shl    $0x7,%edx
  shr    $0x7,%sil
  shl    $0x6,%esi
  or     %esi,%edx
  or     %edx,%eax
L12:
  mov    %al,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x36,%eax
  cmp    $0x10,%esi
  je     L12
  cmp    $0x18,%esi
  mov    $0x40,%eax
  mov    $0xffffff80,%edx
  cmove  %edx,%eax
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void aes_rcon_prev(unsigned char *rcon, int key_len) {
  unsigned char rcon_tmp;
  if (*rcon) {
    rcon_tmp = *rcon;
    *rcon = 0x0;
    *rcon |= (((rcon_tmp >> 1) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 0;
    *rcon |= (((rcon_tmp >> 2) & 0x1)) << 1;
    *rcon |= (((rcon_tmp >> 3) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 2;
    *rcon |= (((rcon_tmp >> 4) & 0x1) ^ ((rcon_tmp >> 0) & 0x1)) << 3;
    *rcon |= (((rcon_tmp >> 5) & 0x1)) << 4;
    *rcon |= (((rcon_tmp >> 6) & 0x1)) << 5;
    *rcon |= (((rcon_tmp >> 7) & 0x1)) << 6;
    *rcon |= (((rcon_tmp >> 0) & 0x1)) << 7;
  } else {
    if (key_len == 16) {
      *rcon = 0x36;
    } else if (key_len == 24) {
      *rcon = 0x80;
    } else {
      *rcon = 0x40;
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_getnbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L40
L74:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L76
L10:
  mov    $0x1,%eax
L76:
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L74
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L74
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L46:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L39
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L46
L39:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_getnbr(char *str) {
  int neg;
  int result;
  for (neg = 1; *str < '0' || *str > '9'; str++)
    neg = (*str == '-') ? -1 : 1;
  for (result = 0; *str >= '0' && *str <= '9'; ++str)
    result = (result * 10) + (*str - '0');
  return (result * neg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_getnbr>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L9
L3:
  cmp    $0x2d,%dl
  setne  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L3
L1:
  movzbl (%rdi),%edx
  mov    $0x0,%ecx
L38:
  lea    (%rcx,%rcx,4),%ecx
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rcx,2),%ecx
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L38
  imul   %ecx,%eax
  ret
L9:
  mov    $0x1,%eax
  jmp    L1
```

assistant: ```c
int my_getnbr(char *str) {
  int neg;
  int result;
  for (neg = 1; *str < '0' || *str > '9'; str++)
    neg = (*str == '-') ? -1 : 1;
  for (result = 0; *str >= '0' && *str <= '9'; ++str)
    result = (result * 10) + (*str - '0');
  return (result * neg);
}
```