user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modtest>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  lea    D71(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L3
  xor    %ebx,%ebx
  lea    D73(%rip),%rbp
  nopl   (%rax)
L17:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %ebx,%r13d
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L17
  lea    D90(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
L56:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  add    $0x1,%r12d
  cmp    %eax,%r13d
  jne    L56
  mov    %ebx,%r12d
  xor    %r14d,%r14d
L67:
  mov    %r14d,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  mov    %r14d,%r15d
  call   <printf@plt>
  nopl   0x0(%rax)
L26:
  mov    %r15d,%eax
  mov    %rbp,%rdi
  add    $0x1,%r15d
  cltd
  idiv   %ebx
  xor    %eax,%eax
  mov    %edx,%esi
  call   <printf@plt>
  cmp    %r12d,%r15d
  jne    L26
  lea    0x1(%r14),%eax
  lea    0x1(%r15),%r12d
  cmp    %r14d,%r13d
  je     L21
  mov    %eax,%r14d
  jmp    L67
  nopl   (%rax)
L21:
  lea    D58(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   (%rax)
L98:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  add    $0x1,%r12d
  cmp    %eax,%r13d
  jne    L98
  lea    D90(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L62:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  add    $0x1,%r12d
  cmp    %eax,%r13d
  jne    L62
  mov    %ebx,%r13d
  neg    %r13d
  nopl   0x0(%rax,%rax,1)
L1:
  lea    0x0(%r13,%rbx,1),%r12d
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  mov    %r12d,%esi
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %r12d,%edi
  mov    %ebx,%esi
  sub    $0x1,%r12d
  call   <mod@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12d,%r13d
  jne    L24
  add    $0x1,%r13d
  jne    L1
L23:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
L3:
  lea    D90(%rip),%rbp
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: parse_data
arguments: label: D71
type: string
name: parse_data
arguments: label: D73
type: string
name: parse_data
arguments: label: D90
type: string
name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D21
type: string
name: parse_data
arguments: label: D58
type: string
name: parse_data
arguments: label: D14
type: string

tool: D71: Plus
L 

tool: D73:  %d

tool: D90: 
 -

tool: D1: - 

tool: D21: 
%d 

tool: D58: 


tool: D14: Minus
L 

assistant: ```c
void modtest(int players) {
  printf("Plus\nL ");
  for (int i = 0; i < players; i++) {
    printf(" %d", i);
  }
  printf("\n -");
  for (int i = 0; i < players; i++) {
    printf("- ");
  }
  for (int lead = 0; lead < players; lead++) {
    printf("\n%d ", lead);
    for (int loc = 0; loc < players; loc++) {
      printf(" %d", (lead + loc) % players);
    }
  }
  printf("\n\n");
  printf("Minus\nL ");
  for (int i = 0; i < players; i++) {
    printf(" %d", i);
  }
  printf("\n -");
  for (int i = 0; i < players; i++) {
    printf("- ");
  }
  for (int lead = 0; lead < players; lead++) {
    printf("\n%d ", lead);
    for (int loc = 0; loc < players; loc++) {
      printf(" %d", mod(lead - loc, players));
    }
  }
  printf("\n");
}
```