user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x51e22cdb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L33
L19:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L56
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jbe    L20
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%esi
  mov    %edx,%eax
  sub    %esi,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
  jmp    L56
L20:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  shl    $0x3,%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  add    $0x3,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x2(%rax),%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x3,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x3(%rax),%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
L56:
  addl   $0x1,-0x10(%rbp)
L33:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L19
  mov    -0xc(%rbp),%eax
  and    $0x10e1eca9,%eax
  or     $0xa020002,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] == local1) {
        if (state[0UL] < local1) {
          state[local1] = state[0UL] + state[local1];
          state[local1] |= ((state[0UL] - state[local1]) & 31U) << 4UL;
        } else {
          state[local1] |= (state[local1] & 31U) << 3UL;
          copy11 = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = copy11;
        }
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 236851714UL) & 451144875U;
  }
}
```