ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stringcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L15
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  cmp    %al,%dl
  je     L57
  mov    $0x1,%eax
  jmp    L47
L57:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
L46:
  mov    $0x1,%eax
  jmp    L47
L12:
  mov    $0x0,%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int stringcasecmp(const char *s1, const char *s2) {
  for (; *s1 && *s2; s1++, s2++)
    if ((*s1 | 32) != (*s2 | 32))
      return 1;
  if (*s1 || *s2)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stringcasecmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
L4:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L35
  or     $0x20,%eax
  or     $0x20,%edx
  cmp    %dl,%al
  jne    L25
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L4
L15:
  cmpb   $0x0,(%rsi)
  setne  %al
  movzbl %al,%eax
  ret
L25:
  mov    $0x1,%eax
  ret
L35:
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int stringcasecmp(const char *s1, const char *s2) {
  for (; *s1 && *s2; s1++, s2++)
    if ((*s1 | 32) != (*s2 | 32))
      return 1;
  if (*s1 || *s2)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stringcasecmp>:
  endbr64
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L33:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L0
  or     $0x20,%eax
  or     $0x20,%edx
  cmp    %dl,%al
  jne    L0
  add    $0x1,%rdi
  add    $0x1,%rsi
L12:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L33
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  setne  %al
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int stringcasecmp(const char *s1, const char *s2) {
  for (; *s1 && *s2; s1++, s2++)
    if ((*s1 | 32) != (*s2 | 32))
      return 1;
  if (*s1 || *s2)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stringcasecmp>:
  endbr64
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L33:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L18
  or     $0x20,%eax
  or     $0x20,%edx
  cmp    %dl,%al
  jne    L18
  add    $0x1,%rdi
  add    $0x1,%rsi
L6:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L33
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  setne  %al
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int stringcasecmp(const char *s1, const char *s2) {
  for (; *s1 && *s2; s1++, s2++)
    if ((*s1 | 32) != (*s2 | 32))
      return 1;
  if (*s1 || *s2)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<putLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L6
L9:
  mov    -0x20(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L68
L18:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
L68:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L86
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L86
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  sub    $0x2,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L86
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movb   $0xd,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  add    %rcx,%rax
  movb   $0xa,(%rax)
L86:
  cmpl   $0x0,-0x24(%rbp)
  je     L73
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L73
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  add    %rcx,%rax
  movb   $0xd,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  add    %rcx,%rax
  movb   $0xa,(%rax)
L73:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int putLine(char **buffer, char *t, int addCRLF) {
  char *pos;
  int n, n1;
  if (!*t)
    return **buffer = 0;
  pos = strchr(t, '\n');
  if (pos)
    n = pos - t + 1;
  else
    n = strlen(t);
  memcpy(*buffer, t, n);
  n1 = n;
  t += n;
  if (n && (*buffer)[n - 1] == '\n' && (*buffer)[n - 2] != '\r') {
    (*buffer)[n - 1] = '\r';
    (*buffer)[n++] = '\n';
  }
  if (addCRLF && (*buffer)[n - 1] != '\n') {
    (*buffer)[n++] = '\r';
    (*buffer)[n++] = '\n';
  }
  (*buffer)[n] = 0;
  *buffer += n;
  return n1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<putLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  cmpb   $0x0,(%rsi)
  jne    L71
  mov    (%rdi),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%ebx
L69:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L67
  sub    %r12,%rax
  lea    0x1(%rax),%ebx
L54:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    0x0(%rbp),%rdi
  call   <memcpy@plt>
  test   %ebx,%ebx
  je     L22
  movslq %ebx,%rdx
  mov    0x0(%rbp),%rcx
  lea    -0x1(%rcx,%rdx,1),%rsi
  cmpb   $0xa,(%rsi)
  je     L23
  mov    %ebx,%eax
  test   %r13d,%r13d
  je     L13
  mov    %ebx,%eax
L7:
  lea    0x1(%rax),%esi
  movb   $0xd,(%rcx,%rdx,1)
  add    $0x2,%eax
  movslq %esi,%rdx
  mov    0x0(%rbp),%rcx
  movb   $0xa,(%rcx,%rdx,1)
L13:
  cltq
  mov    0x0(%rbp),%rdx
  movb   $0x0,(%rdx,%rax,1)
  add    %rax,0x0(%rbp)
  jmp    L69
L67:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L54
L23:
  mov    %ebx,%eax
  cmpb   $0xd,-0x2(%rcx,%rdx,1)
  je     L13
  movb   $0xd,(%rsi)
  lea    0x1(%rbx),%eax
  mov    0x0(%rbp),%rcx
  movb   $0xa,(%rcx,%rdx,1)
  jmp    L1
L22:
  mov    %ebx,%eax
L1:
  test   %r13d,%r13d
  je     L13
  mov    0x0(%rbp),%rcx
  movslq %eax,%rdx
  cmpb   $0xa,-0x1(%rcx,%rdx,1)
  jne    L7
  jmp    L13
```

assistant: ```c
int putLine(char **buffer, char *t, int addCRLF) {
  char *pos;
  int n, n1;
  if (!*t)
    return **buffer = 0;
  pos = strchr(t, '\n');
  if (pos)
    n = pos - t + 1;
  else
    n = strlen(t);
  memcpy(*buffer, t, n);
  n1 = n;
  t += n;
  if (n && (*buffer)[n - 1] == '\n' && (*buffer)[n - 2] != '\r') {
    (*buffer)[n - 1] = '\r';
    (*buffer)[n++] = '\n';
  }
  if (addCRLF && (*buffer)[n - 1] != '\n') {
    (*buffer)[n++] = '\r';
    (*buffer)[n++] = '\n';
  }
  (*buffer)[n] = 0;
  *buffer += n;
  return n1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<putLine>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  jne    L76
  mov    (%rdi),%rax
  xor    %r12d,%r12d
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L76:
  mov    %rsi,%rbp
  mov    $0xa,%esi
  mov    %edx,%ebx
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L74
  sub    %rbp,%rax
  lea    0x1(%rax),%r12d
L72:
  mov    0x0(%r13),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  test   %r12d,%r12d
  je     L57
  mov    0x0(%r13),%rdx
  movslq %r12d,%rax
  lea    -0x1(%rdx,%rax,1),%rcx
  cmpb   $0xa,(%rcx)
  je     L84
  test   %ebx,%ebx
  je     L51
  mov    %r12d,%ecx
L91:
  movb   $0xd,(%rdx,%rax,1)
  lea    0x1(%rcx),%eax
  mov    0x0(%r13),%rdx
  add    $0x2,%ecx
  cltq
  movb   $0xa,(%rdx,%rax,1)
  mov    0x0(%r13),%rdx
  movslq %ecx,%rax
L51:
  movb   $0x0,(%rdx,%rax,1)
  add    %rax,0x0(%r13)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L57:
  xor    %ecx,%ecx
  xor    %eax,%eax
L109:
  mov    0x0(%r13),%rdx
  test   %ebx,%ebx
  je     L51
  cmpb   $0xa,-0x1(%rdx,%rax,1)
  jne    L91
  jmp    L51
  nopl   (%rax)
L84:
  cmpb   $0xd,-0x2(%rdx,%rax,1)
  je     L51
  movb   $0xd,(%rcx)
  mov    0x0(%r13),%rdx
  lea    0x1(%r12),%ecx
  movb   $0xa,(%rdx,%rax,1)
  movslq %ecx,%rax
  jmp    L109
  nopl   0x0(%rax)
L74:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L72
```

assistant: ```c
int putLine(char **buffer, char *t, int addCRLF) {
  char *pos;
  int n, n1;
  if (!*t)
    return **buffer = 0;
  pos = strchr(t, '\n');
  if (pos)
    n = pos - t + 1;
  else
    n = strlen(t);
  memcpy(*buffer, t, n);
  n1 = n;
  t += n;
  if (n && (*buffer)[n - 1] == '\n' && (*buffer)[n - 2] != '\r') {
    (*buffer)[n - 1] = '\r';
    (*buffer)[n++] = '\n';
  }
  if (addCRLF && (*buffer)[n - 1] != '\n') {
    (*buffer)[n++] = '\r';
    (*buffer)[n++] = '\n';
  }
  (*buffer)[n] = 0;
  *buffer += n;
  return n1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<putLine>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  jne    L79
  mov    (%rdi),%rax
  xor    %r12d,%r12d
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L79:
  mov    %rsi,%rbp
  mov    $0xa,%esi
  mov    %edx,%ebx
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L102
  sub    %rbp,%rax
  lea    0x1(%rax),%r12d
L41:
  mov    0x0(%r13),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  test   %r12d,%r12d
  je     L28
  mov    0x0(%r13),%rdx
  movslq %r12d,%rax
  lea    -0x1(%rdx,%rax,1),%rcx
  cmpb   $0xa,(%rcx)
  je     L104
  test   %ebx,%ebx
  je     L11
  mov    %r12d,%ecx
L0:
  movb   $0xd,(%rdx,%rax,1)
  lea    0x1(%rcx),%eax
  mov    0x0(%r13),%rdx
  add    $0x2,%ecx
  cltq
  movb   $0xa,(%rdx,%rax,1)
  mov    0x0(%r13),%rdx
  movslq %ecx,%rax
L11:
  movb   $0x0,(%rdx,%rax,1)
  add    %rax,0x0(%r13)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L28:
  xor    %ecx,%ecx
  xor    %eax,%eax
L65:
  mov    0x0(%r13),%rdx
  test   %ebx,%ebx
  je     L11
  cmpb   $0xa,-0x1(%rdx,%rax,1)
  jne    L0
  jmp    L11
  nopl   (%rax)
L104:
  cmpb   $0xd,-0x2(%rdx,%rax,1)
  je     L11
  movb   $0xd,(%rcx)
  mov    0x0(%r13),%rdx
  lea    0x1(%r12),%ecx
  movb   $0xa,(%rdx,%rax,1)
  movslq %ecx,%rax
  jmp    L65
  nopl   0x0(%rax)
L102:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L41
```

assistant: ```c
int putLine(char **buffer, char *t, int addCRLF) {
  char *pos;
  int n, n1;
  if (!*t)
    return **buffer = 0;
  pos = strchr(t, '\n');
  if (pos)
    n = pos - t + 1;
  else
    n = strlen(t);
  memcpy(*buffer, t, n);
  n1 = n;
  t += n;
  if (n && (*buffer)[n - 1] == '\n' && (*buffer)[n - 2] != '\r') {
    (*buffer)[n - 1] = '\r';
    (*buffer)[n++] = '\n';
  }
  if (addCRLF && (*buffer)[n - 1] != '\n') {
    (*buffer)[n++] = '\r';
    (*buffer)[n++] = '\n';
  }
  (*buffer)[n] = 0;
  *buffer += n;
  return n1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<suinput_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <suinput_get_uinput_path@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L16
L10:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
int suinput_open(void) {
  int uinput_fd;
  char *uinput_path;
  if ((uinput_path = suinput_get_uinput_path()) == NULL) {
    return -1;
  }
  uinput_fd = open(uinput_path, O_WRONLY | O_NONBLOCK);
  free(uinput_path);
  return uinput_fd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<suinput_open>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <suinput_get_uinput_path@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  or     (%rax),%esi
  mov    %rbx,%rdi
  call   <open@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
L19:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    $0xffffffff,%ebp
  jmp    L19
```

assistant: ```c
int suinput_open(void) {
  int uinput_fd;
  char *uinput_path;
  if ((uinput_path = suinput_get_uinput_path()) == NULL) {
    return -1;
  }
  uinput_fd = open(uinput_path, O_WRONLY | O_NONBLOCK);
  free(uinput_path);
  return uinput_fd;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<suinput_open>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <suinput_get_uinput_path@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbp
  mov    D16(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L13:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    $0xffffffff,%r12d
  jmp    L13
```

assistant: ```c
int suinput_open(void) {
  int uinput_fd;
  char *uinput_path;
  if ((uinput_path = suinput_get_uinput_path()) == NULL) {
    return -1;
  }
  uinput_fd = open(uinput_path, O_WRONLY | O_NONBLOCK);
  free(uinput_path);
  return uinput_fd;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<suinput_open>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <suinput_get_uinput_path@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbp
  mov    D2(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  mov    D17(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L13:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0xffffffff,%r12d
  jmp    L13
```

assistant: ```c
int suinput_open(void) {
  int uinput_fd;
  char *uinput_path;
  if ((uinput_path = suinput_get_uinput_path()) == NULL) {
    return -1;
  }
  uinput_fd = open(uinput_path, O_WRONLY | O_NONBLOCK);
  free(uinput_path);
  return uinput_fd;
}
```
user: What is the c source code of the assembly code below:

```asm
<mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L45
L21:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L44
L58:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jbe    L58
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L34
L2:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  add    $0x20,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  imul   $0x26,%eax,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L34:
  cmpl   $0x1f,-0x8(%rbp)
  jbe    L2
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L45:
  cmpl   $0x1f,-0xc(%rbp)
  jbe    L21
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <squeeze@plt>
  nop
  leave
  ret
```

assistant: ```c
void mult(unsigned int out[32], const unsigned int a[32], const unsigned int b[32]) {
  unsigned int i;
  unsigned int j;
  unsigned int u;
  for (i = 0; i < 32; ++i) {
    u = 0;
    for (j = 0; j <= i; ++j)
      u += a[j] * b[i - j];
    for (j = i + 1; j < 32; ++j)
      u += 38 * a[j] * b[i + 32 - j];
    out[i] = u;
  }
  squeeze(out);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mult>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%rdi
  mov    %r8,%r10
  mov    $0x0,%r11d
L0:
  mov    %r9,%rsi
  mov    %r11d,%eax
  mov    $0x0,%ecx
L16:
  mov    %eax,%edx
  mov    (%rdi,%rdx,4),%edx
  imul   (%rsi),%edx
  add    %edx,%ecx
  add    $0x4,%rsi
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  jne    L16
  lea    0x1(%r11),%ebx
  cmp    $0x1f,%r11d
  je     L30
  mov    %ebx,%edx
  add    $0x20,%r11d
L26:
  mov    %r11d,%eax
  sub    %edx,%eax
  mov    %edx,%esi
  mov    (%rdi,%rax,4),%eax
  imul   (%r9,%rsi,4),%eax
  imul   $0x26,%eax,%eax
  add    %eax,%ecx
  add    $0x1,%edx
  cmp    $0x1f,%edx
  jbe    L26
  mov    %ecx,(%r10)
  add    $0x4,%r10
  mov    %ebx,%r11d
  jmp    L0
L30:
  mov    %ecx,0x7c(%r8)
  mov    %r8,%rdi
  call   <squeeze@plt>
  pop    %rbx
  ret
```

assistant: ```c
void mult(unsigned int out[32], const unsigned int a[32], const unsigned int b[32]) {
  unsigned int i;
  unsigned int j;
  unsigned int u;
  for (i = 0; i < 32; ++i) {
    u = 0;
    for (j = 0; j <= i; ++j)
      u += a[j] * b[i - j];
    for (j = i + 1; j < 32; ++j)
      u += 38 * a[j] * b[i + 32 - j];
    out[i] = u;
  }
  squeeze(out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mult>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    $0x1,%r10d
L17:
  lea    -0x1(%r10),%eax
  mov    %r8,%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L28:
  mov    %eax,%esi
  add    $0x4,%rdi
  mov    (%rdx,%rsi,4),%esi
  imul   -0x4(%rdi),%esi
  add    %esi,%ecx
  sub    $0x1,%eax
  jae    L28
  cmp    $0x20,%r10
  je     L19
  lea    0x7c(%rdx),%rdi
  mov    %r10,%rsi
  nopl   0x0(%rax)
L8:
  mov    (%r8,%rsi,4),%eax
  imul   (%rdi),%eax
  add    $0x1,%rsi
  sub    $0x4,%rdi
  imul   $0x26,%eax,%eax
  add    %eax,%ecx
  cmp    $0x20,%esi
  jne    L8
  mov    %ecx,-0x4(%r9,%r10,4)
  add    $0x1,%r10
  jmp    L17
  nopl   0x0(%rax)
L19:
  mov    %ecx,0x7c(%r9)
  mov    %r9,%rdi
  jmp    1050 <squeeze@plt>
```

assistant: ```c
void mult(unsigned int out[32], const unsigned int a[32], const unsigned int b[32]) {
  unsigned int i;
  unsigned int j;
  unsigned int u;
  for (i = 0; i < 32; ++i) {
    u = 0;
    for (j = 0; j <= i; ++j)
      u += a[j] * b[i - j];
    for (j = i + 1; j < 32; ++j)
      u += 38 * a[j] * b[i + 32 - j];
    out[i] = u;
  }
  squeeze(out);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<report_splitter_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4c0,%rsp
  mov    %rdi,-0x4b8(%rbp)
  mov    %rsi,-0x4c0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L34
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L34:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x4c0(%rbp),%rdx
  mov    -0x4a8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x4a8(%rbp),%ecx
  mov    -0x4c0(%rbp),%rdx
  lea    -0x4a0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0x4a4(%rbp)
  cmpl   $0x0,-0x4a4(%rbp)
  jle    L38
  mov    -0x4a4(%rbp),%eax
  lea    0x1(%rax),%edx
  lea    -0x4a0(%rbp),%rcx
  mov    -0x4b8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <set_parser_error@plt>
  jmp    L22
L38:
  mov    -0x4b8(%rbp),%rax
  mov    $0x42,%edx
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <set_parser_error@plt>
L22:
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: Unknown FIX message splitter error (Invalid error message format)

assistant: ```c
__attribute__((no)) void report_splitter_error(struct fix_parser *parser, const char *fmt, ...) {
  static const char def_msg[] = "Unknown FIX message splitter error (Invalid error message format)";
  int n;
  va_list args;
  char buff[1000];
  va_start(args, fmt);
  n = vsnprintf(buff, sizeof(buff), fmt, args);
  if (n > 0)
    set_parser_error(parser, buff, n + 1);
  else
    set_parser_error(parser, def_msg, sizeof(def_msg));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<report_splitter_error>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    $0x3e8,%esi
  call   <vsnprintf@plt>
  test   %eax,%eax
  jle    L28
  lea    0x1(%rax),%edx
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <set_parser_error@plt>
L2:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x3f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    $0x42,%edx
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <set_parser_error@plt>
  jmp    L2
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D8: Unknown FIX message splitter error (Invalid error message format)

assistant: ```c
__attribute__((no)) void report_splitter_error(struct fix_parser *parser, const char *fmt, ...) {
  static const char def_msg[] = "Unknown FIX message splitter error (Invalid error message format)";
  int n;
  va_list args;
  char buff[1000];
  va_start(args, fmt);
  n = vsnprintf(buff, sizeof(buff), fmt, args);
  if (n > 0)
    set_parser_error(parser, buff, n + 1);
  else
    set_parser_error(parser, def_msg, sizeof(def_msg));
}
```