ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D14(%rip),%rdi
  lea    D46(%rip),%r15
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D56(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L7:
  movslq 0x4(%rsp),%rax
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %rax,%rdx
  imul   $0x5d9f7391,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x27,%rax
  sub    %ecx,%eax
  imul   $0x15e,%eax,%ecx
  cmp    %ecx,%edx
  mov    %r14,%rdx
  setne  %sil
  add    %eax,%esi
  cmp    $0x1,%esi
  cmove  %r15,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
L27:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L7
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D46
type: string
name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D25
type: string
name: extract_symbolic_data
arguments: label: D12
type: string
name: extract_symbolic_data
arguments: label: D56
type: string

tool: D14: Enter number of square feet to be painted:

tool: D46: can

tool: D21: cans

tool: D25: You need %d %s of paint.


tool: D12: Enter next value :

tool: D56: %d

assistant: ```c
int main() {
  int sq_feet;
  int cans;
  printf("Enter number of square feet to be painted:\n");
  while (scanf("%d", &sq_feet) == 1) {
    cans = sq_feet / 350;
    cans += ((sq_feet % 350 == 0)) ? 0 : 1;
    printf("You need %d %s of paint.\n", cans, cans == 1 ? "can" : "cans");
    printf("Enter next value :\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D3(%rip),%rdi
  lea    D38(%rip),%r15
  push   %r14
  lea    D51(%rip),%r14
  push   %r13
  lea    D42(%rip),%r13
  push   %r12
  lea    D47(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D43(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L10:
  movslq 0x4(%rsp),%rax
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %rax,%rdx
  imul   $0x5d9f7391,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x27,%rax
  sub    %ecx,%eax
  imul   $0x15e,%eax,%ecx
  cmp    %ecx,%edx
  mov    %r14,%rdx
  setne  %sil
  add    %eax,%esi
  cmp    $0x1,%esi
  cmove  %r15,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
L2:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string
name: disassemble_data
arguments: tag: D38
datatype: string
name: disassemble_data
arguments: tag: D51
datatype: string
name: disassemble_data
arguments: tag: D42
datatype: string
name: disassemble_data
arguments: tag: D47
datatype: string
name: disassemble_data
arguments: tag: D43
datatype: string

tool: D3: Enter number of square feet to be painted:

tool: D38: can

tool: D51: cans

tool: D42: You need %d %s of paint.


tool: D47: Enter next value :

tool: D43: %d

assistant: ```c
int main() {
  int sq_feet;
  int cans;
  printf("Enter number of square feet to be painted:\n");
  while (scanf("%d", &sq_feet) == 1) {
    cans = sq_feet / 350;
    cans += ((sq_feet % 350 == 0)) ? 0 : 1;
    printf("You need %d %s of paint.\n", cans, cans == 1 ? "can" : "cans");
    printf("Enter next value :\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_token_label>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jg     L11
  mov    $0x0,%eax
  jmp    L19
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  sete   %al
  movzbl %al,%eax
L19:
  leave
  ret
```

assistant: ```c
int is_token_label(const char *token) {
  if (strlen(token) < 2)
    return 0;
  return token[0] == ':';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_token_label>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  jle    L6
  cmpb   $0x3a,(%rbx)
  sete   %al
  movzbl %al,%eax
L6:
  pop    %rbx
  ret
```

assistant: ```c
int is_token_label(const char *token) {
  if (strlen(token) < 2)
    return 0;
  return token[0] == ':';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_token_label>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jle    L1
  xor    %eax,%eax
  cmpb   $0x3a,(%rbx)
  sete   %al
L1:
  pop    %rbx
  ret
```

assistant: ```c
int is_token_label(const char *token) {
  if (strlen(token) < 2)
    return 0;
  return token[0] == ':';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_token_label>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jle    L8
  xor    %eax,%eax
  cmpb   $0x3a,(%rbx)
  sete   %al
L8:
  pop    %rbx
  ret
```

assistant: ```c
int is_token_label(const char *token) {
  if (strlen(token) < 2)
    return 0;
  return token[0] == ':';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_sbrk_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    D53(%rip),%rax
  test   %rax,%rax
  jne    L1
  mov    D40(%rip),%rax
  mov    %rax,D5(%rip)
L1:
  mov    D5(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    D5(%rip),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    D5(%rip),%rax
  cmp    %rax,%rdx
  jbe    L28
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L29
L28:
  mov    D5(%rip),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,D2(%rip)
  mov    -0x8(%rbp),%rax
L29:
  pop    %rbp
  ret
```

assistant: ```c
caddr_t _sbrk_r(struct _reent *r, int incr) {
  (void)r;
  extern char end asm("end");
  extern char HeapLimit asm("__HeapLimit");
  static char *heap_end;
  char *prev_heap_end;
  if (heap_end == NULL)
    heap_end = &end;
  prev_heap_end = heap_end;
  if (heap_end + incr > &HeapLimit) {
    errno = ENOMEM;
    return (caddr_t)-1;
  }
  heap_end += incr;
  return (caddr_t)prev_heap_end;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_sbrk_r>:
  endbr64
  cmpq   $0x0,D27(%rip)
  je     L15
L13:
  mov    D27(%rip),%rax
  movslq %esi,%rsi
  add    %rax,%rsi
  cmp    D62(%rip),%rsi
  ja     L27
  mov    %rsi,D65(%rip)
  ret
L15:
  mov    D65(%rip),%rax
  mov    %rax,D31(%rip)
  jmp    L13
L27:
  mov    D31(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
caddr_t _sbrk_r(struct _reent *r, int incr) {
  (void)r;
  extern char end asm("end");
  extern char HeapLimit asm("__HeapLimit");
  static char *heap_end;
  char *prev_heap_end;
  if (heap_end == NULL)
    heap_end = &end;
  prev_heap_end = heap_end;
  if (heap_end + incr > &HeapLimit) {
    errno = ENOMEM;
    return (caddr_t)-1;
  }
  heap_end += incr;
  return (caddr_t)prev_heap_end;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_sbrk_r>:
  endbr64
  mov    D10(%rip),%rax
  test   %rax,%rax
  je     L29
L3:
  movslq %esi,%rsi
  add    %rax,%rsi
  cmp    D50(%rip),%rsi
  ja     L23
  mov    %rsi,D5(%rip)
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    D5(%rip),%rax
  mov    %rax,D25(%rip)
  jmp    L3
L23:
  mov    D25(%rip),%rax
  mov    (%rax),%edx
  mov    D36(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
caddr_t _sbrk_r(struct _reent *r, int incr) {
  (void)r;
  extern char end asm("end");
  extern char HeapLimit asm("__HeapLimit");
  static char *heap_end;
  char *prev_heap_end;
  if (heap_end == NULL)
    heap_end = &end;
  prev_heap_end = heap_end;
  if (heap_end + incr > &HeapLimit) {
    errno = ENOMEM;
    return (caddr_t)-1;
  }
  heap_end += incr;
  return (caddr_t)prev_heap_end;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_sbrk_r>:
  endbr64
  mov    D1(%rip),%rax
  test   %rax,%rax
  je     L19
L18:
  movslq %esi,%rsi
  add    %rax,%rsi
  cmp    D64(%rip),%rsi
  ja     L4
  mov    %rsi,D31(%rip)
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    D31(%rip),%rax
  mov    %rax,D4(%rip)
  jmp    L18
L4:
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
caddr_t _sbrk_r(struct _reent *r, int incr) {
  (void)r;
  extern char end asm("end");
  extern char HeapLimit asm("__HeapLimit");
  static char *heap_end;
  char *prev_heap_end;
  if (heap_end == NULL)
    heap_end = &end;
  prev_heap_end = heap_end;
  if (heap_end + incr > &HeapLimit) {
    errno = ENOMEM;
    return (caddr_t)-1;
  }
  heap_end += incr;
  return (caddr_t)prev_heap_end;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mus_char_to_ubshort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzwl -0x12(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned short mus_char_to_ubshort(const unsigned char *inp) {
  unsigned short o;
  unsigned char *outp = (unsigned char *)&o;
  outp[0] = inp[1];
  outp[1] = inp[0];
  return (o);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mus_char_to_ubshort>:
  endbr64
  mov    $0x0,%eax
  mov    0x1(%rdi),%al
  movzbl (%rdi),%edx
  mov    %dl,%ah
  ret
```

assistant: ```c
unsigned short mus_char_to_ubshort(const unsigned char *inp) {
  unsigned short o;
  unsigned char *outp = (unsigned char *)&o;
  outp[0] = inp[1];
  outp[1] = inp[0];
  return (o);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mus_char_to_ubshort>:
  endbr64
  movzwl (%rdi),%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short mus_char_to_ubshort(const unsigned char *inp) {
  unsigned short o;
  unsigned char *outp = (unsigned char *)&o;
  outp[0] = inp[1];
  outp[1] = inp[0];
  return (o);
}
```
user: What is the c source code of the assembly code below?

```asm
<mus_char_to_ubshort>:
  endbr64
  movzwl (%rdi),%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short mus_char_to_ubshort(const unsigned char *inp) {
  unsigned short o;
  unsigned char *outp = (unsigned char *)&o;
  outp[0] = inp[1];
  outp[1] = inp[0];
  return (o);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<base64_length_for_data_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x2,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  sub    %ecx,%eax
  add    $0x2,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  pop    %rbp
  ret
```

assistant: ```c
int base64_length_for_data_length(int n) {
  int numBlocks = (n - ((n + 2) % 3) + 2) / 3;
  return numBlocks * 4;
}
```
user: What is the c source code of the assembly code below:

```asm
<base64_length_for_data_length>:
  endbr64
  lea    0x2(%rdi),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  sub    %edx,%edi
  lea    0x2(%rdi,%rax,1),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
int base64_length_for_data_length(int n) {
  int numBlocks = (n - ((n + 2) % 3) + 2) / 3;
  return numBlocks * 4;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<base64_length_for_data_length>:
  endbr64
  lea    0x2(%rdi),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  sub    %edx,%edi
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  lea    0x2(%rdi,%rax,1),%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
int base64_length_for_data_length(int n) {
  int numBlocks = (n - ((n + 2) % 3) + 2) / 3;
  return numBlocks * 4;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<base64_length_for_data_length>:
  endbr64
  lea    0x2(%rdi),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  sub    %edx,%edi
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  lea    0x2(%rdi,%rax,1),%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
int base64_length_for_data_length(int n) {
  int numBlocks = (n - ((n + 2) % 3) + 2) / 3;
  return numBlocks * 4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
int func10() {
  if (1)
    return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<func10>:
  endbr64
  ret
```

assistant: ```c
int func10() {
  if (1)
    return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func10>:
  endbr64
  ret
```

assistant: ```c
int func10() {
  if (1)
    return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func10>:
  endbr64
  ret
```

assistant: ```c
int func10() {
  if (1)
    return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip_lead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L15
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L18
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strip_lead(char **str) {
  while (**str == ' ')
    (*str)++;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<strip_lead>:
  endbr64
  mov    (%rdi),%rax
  cmpb   $0x20,(%rax)
  jne    L1
  add    $0x1,%rax
L19:
  mov    %rax,(%rdi)
  add    $0x1,%rax
  cmpb   $0x20,-0x1(%rax)
  je     L19
L1:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strip_lead(char **str) {
  while (**str == ' ')
    (*str)++;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip_lead>:
  endbr64
  mov    (%rdi),%rax
  cmpb   $0x20,(%rax)
  jne    L12
  add    $0x1,%rax
L10:
  mov    %rax,(%rdi)
  add    $0x1,%rax
  cmpb   $0x20,-0x1(%rax)
  je     L10
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strip_lead(char **str) {
  while (**str == ' ')
    (*str)++;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strip_lead>:
  endbr64
  mov    (%rdi),%rax
  cmpb   $0x20,(%rax)
  jne    L13
  add    $0x1,%rax
L12:
  mov    %rax,(%rdi)
  add    $0x1,%rax
  cmpb   $0x20,-0x1(%rax)
  je     L12
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strip_lead(char **str) {
  while (**str == ' ')
    (*str)++;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checkDiagonal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L94
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,%edx
  jne    L94
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <checkAscending@plt>
  test   %rax,%rax
  je     L75
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <checkDescending@plt>
  test   %rax,%rax
  je     L75
  mov    $0x1,%eax
  jmp    L116
L94:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L34
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,%edx
  je     L34
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <checkDescending@plt>
  test   %rax,%rax
  je     L43
  mov    $0x1,%eax
  jmp    L116
L34:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L43
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,%edx
  jne    L43
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <checkAscending@plt>
  test   %rax,%rax
  je     L43
  mov    $0x1,%eax
  jmp    L116
L75:
  nop
L43:
  mov    $0x0,%eax
L116:
  leave
  ret
```

assistant: ```c
int checkDiagonal(int **board, int player, int row, int col, int board_size) {
  if (row == col && row + col == board_size - 1) {
    if (checkAscending(board, player, board_size) && checkDescending(board, player, board_size))
      return 1;
  } else if (row == col && row + col != board_size - 1) {
    if (checkDescending(board, player, board_size))
      return 1;
  } else if (row != col && row + col == board_size - 1) {
    if (checkAscending(board, player, board_size))
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<checkDiagonal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %r8d,%r12d
  cmp    %ecx,%edx
  je     L51
  add    %ecx,%edx
  lea    -0x1(%r8),%ecx
  mov    $0x0,%eax
  cmp    %ecx,%edx
  je     L50
L69:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  add    %ecx,%edx
  lea    -0x1(%r8),%eax
  cmp    %eax,%edx
  je     L35
  mov    %r8d,%edx
  call   <checkDescending@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L69
L35:
  mov    %r8d,%edx
  call   <checkAscending@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L69
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <checkDescending@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L69
L50:
  mov    %r8d,%edx
  call   <checkAscending@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L69
```

assistant: ```c
int checkDiagonal(int **board, int player, int row, int col, int board_size) {
  if (row == col && row + col == board_size - 1) {
    if (checkAscending(board, player, board_size) && checkDescending(board, player, board_size))
      return 1;
  } else if (row == col && row + col != board_size - 1) {
    if (checkDescending(board, player, board_size))
      return 1;
  } else if (row != col && row + col == board_size - 1) {
    if (checkAscending(board, player, board_size))
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<checkDiagonal>:
  endbr64
  mov    %edx,%eax
  sub    $0x18,%rsp
  mov    %r8d,%edx
  sub    $0x1,%r8d
  lea    (%rax,%rcx,1),%r9d
  cmp    %ecx,%eax
  je     L40
  cmp    %r8d,%r9d
  je     L11
L36:
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L40:
  cmp    %r8d,%r9d
  je     L39
L15:
  call   <checkDescending@plt>
  test   %rax,%rax
  setne  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  ret
L11:
  call   <checkAscending@plt>
  test   %rax,%rax
  setne  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %edx,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %rdi,(%rsp)
  call   <checkAscending@plt>
  mov    (%rsp),%rdi
  mov    0x8(%rsp),%esi
  test   %rax,%rax
  mov    0xc(%rsp),%edx
  je     L36
  jmp    L15
```

assistant: ```c
int checkDiagonal(int **board, int player, int row, int col, int board_size) {
  if (row == col && row + col == board_size - 1) {
    if (checkAscending(board, player, board_size) && checkDescending(board, player, board_size))
      return 1;
  } else if (row == col && row + col != board_size - 1) {
    if (checkDescending(board, player, board_size))
      return 1;
  } else if (row != col && row + col == board_size - 1) {
    if (checkAscending(board, player, board_size))
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<checkDiagonal>:
  endbr64
  mov    %edx,%eax
  sub    $0x18,%rsp
  mov    %r8d,%edx
  sub    $0x1,%r8d
  lea    (%rax,%rcx,1),%r9d
  cmp    %ecx,%eax
  je     L47
  cmp    %r8d,%r9d
  je     L44
L16:
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L47:
  cmp    %r8d,%r9d
  je     L37
L22:
  call   <checkDescending@plt>
  test   %rax,%rax
  setne  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  ret
L44:
  call   <checkAscending@plt>
  test   %rax,%rax
  setne  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %edx,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %rdi,(%rsp)
  call   <checkAscending@plt>
  mov    (%rsp),%rdi
  mov    0x8(%rsp),%esi
  test   %rax,%rax
  mov    0xc(%rsp),%edx
  je     L16
  jmp    L22
```

assistant: ```c
int checkDiagonal(int **board, int player, int row, int col, int board_size) {
  if (row == col && row + col == board_size - 1) {
    if (checkAscending(board, player, board_size) && checkDescending(board, player, board_size))
      return 1;
  } else if (row == col && row + col != board_size - 1) {
    if (checkDescending(board, player, board_size))
      return 1;
  } else if (row != col && row + col == board_size - 1) {
    if (checkAscending(board, player, board_size))
      return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x7,%eax
  jle    L33
  mov    $0xffffffff,%eax
  jmp    L16
L33:
  mov    -0xc(%rbp),%eax
  cmp    $0xc8,%eax
  jle    L15
  mov    $0xffffffff,%eax
  jmp    L16
L15:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type_infered: string
name: unpack_data
arguments: data_label: D18
type_infered: string

tool: D11: %d%d

tool: D18: %d

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  if (a > 7) {
    return -1;
  }
  if (b > 200) {
    return -1;
  }
  b = (b >> a) & 1;
  printf("%d", b);
  return 0;
}
```