ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find_new_index>:
  endbr64
  mov    D4(%rip),%rax
  mov    %rsi,%r8
  mov    (%rax),%r9d
  test   %edx,%edx
  jle    L22
  movslq %edx,%rdx
  xor    %r10d,%r10d
  xor    %eax,%eax
  nopl   (%rax)
L37:
  movslq (%r8,%rax,4),%rsi
  test   %esi,%esi
  je     L8
  mov    (%rdi,%rsi,4),%esi
  cmp    %r9d,%esi
  jge    L8
  mov    %eax,%r10d
  mov    %esi,%r9d
L8:
  add    $0x1,%rax
  add    $0x1000,%rdi
  cmp    %rdx,%rax
  jne    L37
  subl   $0x1,(%rcx)
  mov    %r10d,%eax
  ret
  nopl   (%rax)
L22:
  xor    %r10d,%r10d
  subl   $0x1,(%rcx)
  mov    %r10d,%eax
  ret
```

assistant: ```c
int find_new_index(int c[][1024], int near[], int n, int *e) {
  int min = INT_MAX, index;
  int i;
  for (i = 0; i < n; ++i)
    if (near[i] != 0 && c[i][near[i]] < min) {
      min = c[i][near[i]];
      index = i;
    }
  *e = *e - 1;
  return (index);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_new_index>:
  endbr64
  mov    D0(%rip),%rax
  mov    %rsi,%r8
  mov    (%rax),%r9d
  test   %edx,%edx
  jle    L25
  movslq %edx,%rdx
  xor    %r10d,%r10d
  xor    %eax,%eax
  nopl   (%rax)
L12:
  movslq (%r8,%rax,4),%rsi
  test   %esi,%esi
  je     L3
  mov    (%rdi,%rsi,4),%esi
  cmp    %r9d,%esi
  jge    L3
  mov    %eax,%r10d
  mov    %esi,%r9d
L3:
  add    $0x1,%rax
  add    $0x1000,%rdi
  cmp    %rdx,%rax
  jne    L12
  subl   $0x1,(%rcx)
  mov    %r10d,%eax
  ret
  nopl   (%rax)
L25:
  xor    %r10d,%r10d
  subl   $0x1,(%rcx)
  mov    %r10d,%eax
  ret
```

assistant: ```c
int find_new_index(int c[][1024], int near[], int n, int *e) {
  int min = INT_MAX, index;
  int i;
  for (i = 0; i < n; ++i)
    if (near[i] != 0 && c[i][near[i]] < min) {
      min = c[i][near[i]];
      index = i;
    }
  *e = *e - 1;
  return (index);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x24,-0x20(%rbp)
  movl   $0x18,-0x1c(%rbp)
  movl   $0xa,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0xc,-0x10(%rbp)
  movl   $0x4,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rcx
  mov    $0x14,%eax
  mov    $0x0,%edx
  div    %rcx
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x2c(%rbp)
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L23
L0:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L23:
  mov    -0x2c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L0
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L12
L67:
  mov    -0x2c(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  addl   $0x1,-0x2c(%rbp)
L12:
  mov    -0x2c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L67
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L49
L2:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L49:
  mov    -0x2c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L2
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D39
type_infered: string
name: read_data
arguments: label: D51
type_infered: string
name: read_data
arguments: label: D42
type_infered: string
name: read_data
arguments: label: D53
type_infered: string

tool: D39: unsorted = {

tool: D51: %3d 

tool: D42: }

tool: D53: sorted   = {

assistant: ```c
void main() {
  int list[] = {36, 24, 10, 6, 12};
  int int_size = sizeof(int);
  int length = sizeof(list) / int_size;
  int i = 0;
  printf("unsorted = {");
  for (i = 0; i < length; i++) {
    printf("%3d ", list[i]);
  }
  printf("}\n");
  for (i = 0; i < length; i++)
    insert(list, 0, i);
  printf("sorted   = {");
  for (i = 0; i < length; i++) {
    printf("%3d ", list[i]);
  }
  printf("}\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x24,(%rsp)
  movl   $0x18,0x4(%rsp)
  movl   $0xa,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0xc,0x10(%rsp)
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  mov    %rbx,%rbp
  lea    D14(%rip),%r13
L24:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L24
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  mov    %rsp,%r13
L26:
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <insert@plt>
  add    $0x1,%ebp
  cmp    $0x5,%ebp
  jne    L26
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D14(%rip),%rbp
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L5
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D35
type_guessed: string

tool: D30: unsorted = {

tool: D14: %3d 

tool: D13: }

tool: D35: sorted   = {

assistant: ```c
void main() {
  int list[] = {36, 24, 10, 6, 12};
  int int_size = sizeof(int);
  int length = sizeof(list) / int_size;
  int i = 0;
  printf("unsorted = {");
  for (i = 0; i < length; i++) {
    printf("%3d ", list[i]);
  }
  printf("}\n");
  for (i = 0; i < length; i++)
    insert(list, 0, i);
  printf("sorted   = {");
  for (i = 0; i < length; i++) {
    printf("%3d ", list[i]);
  }
  printf("}\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%rdi
  push   %r14
  push   %r13
  lea    D33(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x1800000024,%rax
  mov    %rsp,%r14
  lea    0x14(%rsp),%r12
  movl   $0xc,0x10(%rsp)
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,(%rsp)
  movabs $0x60000000a,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
L21:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L21
  lea    D10(%rip),%r15
  xor    %ebp,%ebp
  mov    %r15,%rdi
  call   <puts@plt>
L15:
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <insert@plt>
  cmp    $0x5,%ebp
  jne    L15
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L37:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L37
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D33
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D37
data_type: string

tool: D9: unsorted = {

tool: D33: %3d 

tool: D10: }

tool: D37: sorted   = {

assistant: ```c
void main() {
  int list[] = {36, 24, 10, 6, 12};
  int int_size = sizeof(int);
  int length = sizeof(list) / int_size;
  int i = 0;
  printf("unsorted = {");
  for (i = 0; i < length; i++) {
    printf("%3d ", list[i]);
  }
  printf("}\n");
  for (i = 0; i < length; i++)
    insert(list, 0, i);
  printf("sorted   = {");
  for (i = 0; i < length; i++) {
    printf("%3d ", list[i]);
  }
  printf("}\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D34(%rip),%rdi
  push   %r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x14(%rsp),%r12
  movl   $0xc,0x10(%rsp)
  movaps %xmm0,(%rsp)
  mov    %r14,%rbx
  mov    %r14,%rbp
  call   <printf@plt>
L29:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L29
  lea    D8(%rip),%r15
  xor    %ebp,%ebp
  mov    %r15,%rdi
  call   <puts@plt>
L24:
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <insert@plt>
  cmp    $0x5,%ebp
  jne    L24
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L2:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D34
type_guessed: string
name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D19
type_guessed: byte[16]
name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D44
type_guessed: string

tool: D34: unsorted = {

tool: D17: %3d 

tool: {"D19": [0x24,0x00,0x00,0x00,0x18,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D8: }

tool: D44: sorted   = {

assistant: ```c
void main() {
  int list[] = {36, 24, 10, 6, 12};
  int int_size = sizeof(int);
  int length = sizeof(list) / int_size;
  int i = 0;
  printf("unsorted = {");
  for (i = 0; i < length; i++) {
    printf("%3d ", list[i]);
  }
  printf("}\n");
  for (i = 0; i < length; i++)
    insert(list, 0, i);
  printf("sorted   = {");
  for (i = 0; i < length; i++) {
    printf("%3d ", list[i]);
  }
  printf("}\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sendBlink>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %ecx,%eax
  mov    %esi,%ecx
  mov    %cx,-0x18(%rbp)
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movswl -0x18(%rbp),%edx
  lea    -0xf(%rbp),%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movswl -0x1c(%rbp),%edx
  lea    -0xf(%rbp),%rax
  add    $0x2,%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movswl -0x20(%rbp),%edx
  lea    -0xf(%rbp),%rax
  add    $0x4,%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0xf(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <sendCustom@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
type: string

tool: D26: %02x

assistant: ```c
void sendBlink(int sockfd, short ledIndex, short timeOn, short period) {
  char payload[7];
  sprintf(payload, "%02x", ledIndex);
  sprintf(payload + 2, "%02x", timeOn);
  sprintf(payload + 4, "%02x", period);
  sendCustom(sockfd, 0x02, payload);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sendBlink>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movswl %si,%edx
  lea    0x1(%rsp),%r14
  lea    D6(%rip),%r13
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  movswl %bp,%edx
  lea    0x3(%rsp),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  movswl %bx,%edx
  lea    0x5(%rsp),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  mov    %r14,%rdx
  mov    $0x2,%esi
  mov    %r12d,%edi
  call   <sendCustom@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: %02x

assistant: ```c
void sendBlink(int sockfd, short ledIndex, short timeOn, short period) {
  char payload[7];
  sprintf(payload, "%02x", ledIndex);
  sprintf(payload + 2, "%02x", timeOn);
  sprintf(payload + 4, "%02x", period);
  sendCustom(sockfd, 0x02, payload);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sendBlink>:
  endbr64
  push   %r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  movswl %si,%edx
  mov    %r13,%rsi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  movswl %bp,%edx
  lea    0x3(%rsp),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  movswl %bx,%edx
  lea    0x5(%rsp),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  mov    %r14,%rdx
  mov    $0x2,%esi
  mov    %r12d,%edi
  call   <sendCustom@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: %02x

assistant: ```c
void sendBlink(int sockfd, short ledIndex, short timeOn, short period) {
  char payload[7];
  sprintf(payload, "%02x", ledIndex);
  sprintf(payload + 2, "%02x", timeOn);
  sprintf(payload + 4, "%02x", period);
  sendCustom(sockfd, 0x02, payload);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sendBlink>:
  endbr64
  push   %r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  movswl %si,%edx
  mov    %r13,%rsi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  movswl %bp,%edx
  lea    0x3(%rsp),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  movswl %bx,%edx
  lea    0x5(%rsp),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  mov    %r14,%rdx
  mov    $0x2,%esi
  mov    %r12d,%edi
  call   <sendCustom@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string

tool: D6: %02x

assistant: ```c
void sendBlink(int sockfd, short ledIndex, short timeOn, short period) {
  char payload[7];
  sprintf(payload, "%02x", ledIndex);
  sprintf(payload + 2, "%02x", timeOn);
  sprintf(payload + 4, "%02x", period);
  sendCustom(sockfd, 0x02, payload);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xioctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
L0:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L2
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L0
L2:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int xioctl(int fh, unsigned long int request, void *arg) {
  int r;
  do {
    r = ioctl(fh, request, arg);
  } while (-1 == r && EINTR == errno);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xioctl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
L13:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  mov    D2(%rip),%rcx
  mov    D11(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L13
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int xioctl(int fh, unsigned long int request, void *arg) {
  int r;
  do {
    r = ioctl(fh, request, arg);
  } while (-1 == r && EINTR == errno);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xioctl>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L26:
  mov    D19(%rip),%rdx
  mov    D7(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L2
L5:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L26
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int xioctl(int fh, unsigned long int request, void *arg) {
  int r;
  do {
    r = ioctl(fh, request, arg);
  } while (-1 == r && EINTR == errno);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xioctl>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L14:
  mov    D17(%rip),%rdx
  mov    D3(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L28
L11:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L14
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int xioctl(int fh, unsigned long int request, void *arg) {
  int r;
  do {
    r = ioctl(fh, request, arg);
  } while (-1 == r && EINTR == errno);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L37
L47:
  addq   $0x1,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L47
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L54
  mov    -0x18(%rbp),%rax
  jmp    L50
L54:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L66
L14:
  subq   $0x1,-0x8(%rbp)
L66:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L49
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
L49:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L50:
  leave
  ret
```

assistant: ```c
char *trim(char *str) {
  char *end;
  while (isspace(*str))
    str++;
  if (*str == 0) {
    return str;
  }
  end = str + strlen(str) - 1;
  while (end > str && isspace(*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  jmp    L60
L57:
  add    $0x1,%rbx
L60:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L57
  cmpb   $0x0,(%rbx)
  jne    L11
L30:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jae    L67
L35:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L67
  sub    $0x1,%rbp
  cmp    %rbp,%rbx
  jne    L35
L67:
  movb   $0x0,0x1(%rbp)
  jmp    L30
```

assistant: ```c
char *trim(char *str) {
  char *end;
  while (isspace(*str))
    str++;
  if (*str == 0) {
    return str;
  }
  end = str + strlen(str) - 1;
  while (end > str && isspace(*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  jmp    L63
L28:
  add    $0x1,%r12
L63:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
  cmpb   $0x0,(%r12)
  jne    L22
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L22:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jb     L5
  jmp    L45
  xchg   %ax,%ax
L46:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L45
L5:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L46
L45:
  movb   $0x0,0x1(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *str) {
  char *end;
  while (isspace(*str))
    str++;
  if (*str == 0) {
    return str;
  }
  end = str + strlen(str) - 1;
  while (end > str && isspace(*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  jmp    L28
L15:
  add    $0x1,%r12
L28:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  cmpb   $0x0,(%r12)
  jne    L1
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jb     L62
  jmp    L43
  xchg   %ax,%ax
L41:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L43
L62:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
L43:
  movb   $0x0,0x1(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *str) {
  char *end;
  while (isspace(*str))
    str++;
  if (*str == 0) {
    return str;
  }
  end = str + strlen(str) - 1;
  while (end > str && isspace(*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```