ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rectangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L6
L27:
  movl   $0x1,-0xc(%rbp)
  jmp    L5
L7:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L7
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L27
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D51
type_guessed: string
name: unpack_data
arguments: data_label: D49
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string
name: unpack_data
arguments: data_label: D29
type_guessed: string
name: unpack_data
arguments: data_label: D26
type_guessed: string

tool: D51: ===========================================


tool: D49: rectangle!
 please input length and width:


tool: D3: %d %d

tool: D29: *

tool: D26: 


assistant: ```c
int rectangle() {
  int length, width;
  int row, colume;
  printf("===========================================\n");
  printf("rectangle!\n please input length and width:\n");
  scanf("%d %d", &length, &width);
  for (row = 1; row <= width; row++) {
    for (colume = 1; colume <= length; colume++) {
      printf("*");
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rectangle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%r12d
  lea    D22(%rip),%rbp
  lea    D7(%rip),%r13
  cmpl   $0x0,0x4(%rsp)
  jg     L1
L47:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L39
L6:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jl     L47
L1:
  mov    $0x1,%ebx
  cmpl   $0x0,(%rsp)
  jg     L39
  jmp    L6
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D40
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D38
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string

tool: D40: ===========================================


tool: D19: rectangle!
 please input length and width:


tool: D38: %d %d

tool: D22: *

tool: D7: 


assistant: ```c
int rectangle() {
  int length, width;
  int row, colume;
  printf("===========================================\n");
  printf("rectangle!\n please input length and width:\n");
  scanf("%d %d", &length, &width);
  for (row = 1; row <= width; row++) {
    for (colume = 1; colume <= length; colume++) {
      printf("*");
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rectangle>:
  endbr64
  push   %r13
  lea    D48(%rip),%rdi
  lea    D38(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L32
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    (%rsp),%eax
  mov    $0x1,%ebx
  test   %eax,%eax
  jle    L49
  nopl   0x0(%rax)
L15:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L15
L49:
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jge    L41
L32:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D48
type_infered: string
name: disassemble_data
arguments: tag: D38
type_infered: string
name: disassemble_data
arguments: tag: D26
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D20
type_infered: string

tool: D48: ===========================================


tool: D38: 


tool: D26: *

tool: D18: rectangle!
 please input length and width:


tool: D20: %d %d

assistant: ```c
int rectangle() {
  int length, width;
  int row, colume;
  printf("===========================================\n");
  printf("rectangle!\n please input length and width:\n");
  scanf("%d %d", &length, &width);
  for (row = 1; row <= width; row++) {
    for (colume = 1; colume <= length; colume++) {
      printf("*");
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<rectangle>:
  endbr64
  push   %r13
  lea    D11(%rip),%rdi
  lea    D33(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D45(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D44(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L15
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    (%rsp),%eax
  mov    $0x1,%ebx
  test   %eax,%eax
  jle    L1
  nopl   0x0(%rax)
L31:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L31
L1:
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jge    L46
L15:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
data_type: string
name: extract_symbolic_data
arguments: data_label: D33
data_type: string
name: extract_symbolic_data
arguments: data_label: D45
data_type: string
name: extract_symbolic_data
arguments: data_label: D30
data_type: string
name: extract_symbolic_data
arguments: data_label: D44
data_type: string

tool: D11: ===========================================


tool: D33: 


tool: D45: *

tool: D30: rectangle!
 please input length and width:


tool: D44: %d %d

assistant: ```c
int rectangle() {
  int length, width;
  int row, colume;
  printf("===========================================\n");
  printf("rectangle!\n please input length and width:\n");
  scanf("%d %d", &length, &width);
  for (row = 1; row <= width; row++) {
    for (colume = 1; colume <= length; colume++) {
      printf("*");
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memrmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L3
  cmpq   $0x0,-0x30(%rbp)
  jne    L109
L3:
  mov    $0x0,%eax
  jmp    L58
L109:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jae    L63
  mov    $0x0,%eax
  jmp    L58
L63:
  cmpq   $0x0,-0x18(%rbp)
  je     L17
  cmpq   $0x0,-0x28(%rbp)
  jne    L78
L17:
  mov    $0x0,%eax
  jmp    L58
L78:
  mov    -0x20(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L74:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L99
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  jmp    L58
L99:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  jne    L74
  mov    $0x0,%eax
L58:
  leave
  ret
```

assistant: ```c
void *memrmem(const void *mem1, size_t len1, const void *mem2, size_t len2) {
  size_t i;
  if (len1 == 0 || len2 == 0)
    return NULL;
  if (len1 < len2)
    return NULL;
  if (mem1 == NULL || mem2 == NULL)
    return NULL;
  i = len1 - len2;
  do {
    if (memcmp(mem1 + i, mem2, len2) == 0)
      return (void *)mem1 + i;
  } while (i-- != 0);
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memrmem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rsi,%rsi
  sete   %al
  test   %rcx,%rcx
  sete   %dl
  or     %dl,%al
  jne    L28
  mov    %rdi,%r12
  mov    %rcx,%rbp
  cmp    %rcx,%rsi
  jb     L28
  test   %rdi,%rdi
  je     L6
  test   %r13,%r13
  je     L6
  sub    %rcx,%rsi
  lea    (%rdi,%rsi,1),%rbx
  mov    $0x1,%r14d
L42:
  mov    %rbx,%r15
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L66
  sub    $0x1,%rbx
  mov    %r14,%rax
  sub    %r12,%rax
  add    %rbx,%rax
  jne    L42
  mov    $0x0,%r15d
  jmp    L66
L28:
  mov    $0x0,%r15d
L66:
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  mov    $0x0,%r15d
  jmp    L66
```

assistant: ```c
void *memrmem(const void *mem1, size_t len1, const void *mem2, size_t len2) {
  size_t i;
  if (len1 == 0 || len2 == 0)
    return NULL;
  if (len1 < len2)
    return NULL;
  if (mem1 == NULL || mem2 == NULL)
    return NULL;
  i = len1 - len2;
  do {
    if (memcmp(mem1 + i, mem2, len2) == 0)
      return (void *)mem1 + i;
  } while (i-- != 0);
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memrmem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  sete   %al
  test   %rcx,%rcx
  sete   %dl
  or     %dl,%al
  jne    L10
  mov    %rcx,%r14
  cmp    %rcx,%rsi
  jb     L10
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L10
  test   %r12,%r12
  je     L10
  sub    %rcx,%rsi
  mov    $0x1,%r13d
  lea    (%rdi,%rsi,1),%rbx
  jmp    L67
  nopl   0x0(%rax)
L34:
  mov    %r13,%rax
  sub    $0x1,%rbx
  sub    %rbp,%rax
  add    %rbx,%rax
  je     L10
L67:
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %rbx,%r15
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L34
L12:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r15d,%r15d
  jmp    L12
```

assistant: ```c
void *memrmem(const void *mem1, size_t len1, const void *mem2, size_t len2) {
  size_t i;
  if (len1 == 0 || len2 == 0)
    return NULL;
  if (len1 < len2)
    return NULL;
  if (mem1 == NULL || mem2 == NULL)
    return NULL;
  i = len1 - len2;
  do {
    if (memcmp(mem1 + i, mem2, len2) == 0)
      return (void *)mem1 + i;
  } while (i-- != 0);
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<memrmem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  sete   %al
  test   %rcx,%rcx
  sete   %dl
  or     %dl,%al
  jne    L79
  mov    %rcx,%r14
  cmp    %rcx,%rsi
  jb     L79
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L79
  test   %r12,%r12
  je     L79
  sub    %rcx,%rsi
  mov    $0x1,%r13d
  lea    (%rdi,%rsi,1),%rbx
  jmp    L66
  nopl   0x0(%rax)
L78:
  mov    %r13,%rax
  sub    $0x1,%rbx
  sub    %rbp,%rax
  add    %rbx,%rax
  je     L79
L66:
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %rbx,%r15
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L78
L74:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  xor    %r15d,%r15d
  jmp    L74
```

assistant: ```c
void *memrmem(const void *mem1, size_t len1, const void *mem2, size_t len2) {
  size_t i;
  if (len1 == 0 || len2 == 0)
    return NULL;
  if (len1 < len2)
    return NULL;
  if (mem1 == NULL || mem2 == NULL)
    return NULL;
  i = len1 - len2;
  do {
    if (memcmp(mem1 + i, mem2, len2) == 0)
      return (void *)mem1 + i;
  } while (i-- != 0);
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int a, b, i;
  float c;
  a = atoi(argv[1]);
  b = atoi(argv[2]);
  c = (float)a / b;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int a, b, i;
  float c;
  a = atoi(argv[1]);
  b = atoi(argv[2]);
  c = (float)a / b;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int a, b, i;
  float c;
  a = atoi(argv[1]);
  b = atoi(argv[2]);
  c = (float)a / b;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int a, b, i;
  float c;
  a = atoi(argv[1]);
  b = atoi(argv[2]);
  c = (float)a / b;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D7(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <f@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0xe,%rax
  cmp    %rax,-0x8(%rbp)
  je     L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
data_type: string

tool: D7: abcdefghijkl

assistant: ```c
main() {
  char *str = "abcdefghijkl";
  char *x2 = f(str, 12);
  if (str + 14 != x2)
    abort();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D1(%rip),%rdi
  call   <f@plt>
  lea    D11(%rip),%rdx
  cmp    %rax,%rdx
  je     L4
  mov    $0x0,%eax
  call   <abort@plt>
L4:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: abcdefghijkl

assistant: ```c
main() {
  char *str = "abcdefghijkl";
  char *x2 = f(str, 12);
  if (str + 14 != x2)
    abort();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D15(%rip),%rdi
  call   <f@plt>
  lea    D7(%rip),%rdx
  cmp    %rax,%rdx
  je     L5
  xor    %eax,%eax
  call   <abort@plt>
L5:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_infered: string

tool: D15: abcdefghijkl

assistant: ```c
main() {
  char *str = "abcdefghijkl";
  char *x2 = f(str, 12);
  if (str + 14 != x2)
    abort();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D14(%rip),%rdi
  call   <f@plt>
  lea    D16(%rip),%rdx
  cmp    %rax,%rdx
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
type_guessed: string

tool: D14: abcdefghijkl

assistant: ```c
main() {
  char *str = "abcdefghijkl";
  char *x2 = f(str, 12);
  if (str + 14 != x2)
    abort();
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<Primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L23
L27:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L15
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L27
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string
name: unpack_data
arguments: tag: D13
type_infered: string

tool: D0: false

tool: D13: true

assistant: ```c
void Primes(int num) {
  int limit = sqrt(num);
  for (int factor = 2; factor < limit; factor += 1) {
    if ((num % factor) == 0) {
      printf("false");
    }
  }
  printf("true");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Primes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <sqrt@plt>
  cmp    $0x2,%eax
  jle    L48
  mov    %eax,%r12d
  mov    $0x2,%ebx
  lea    D6(%rip),%r13
  jmp    L14
L39:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L48
L14:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L39
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L39
L48:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string
name: read_data
arguments: label: D1
type_guessed: string

tool: D6: false

tool: D1: true

assistant: ```c
void Primes(int num) {
  int limit = sqrt(num);
  for (int factor = 2; factor < limit; factor += 1) {
    if ((num % factor) == 0) {
      printf("false");
    }
  }
  printf("true");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Primes>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <sqrt@plt>
  cmp    $0x2,%eax
  jle    L24
  mov    %eax,%ebp
  mov    $0x2,%ebx
  lea    D4(%rip),%r13
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L24
L0:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L49
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L0
L24:
  add    $0x8,%rsp
  lea    D12(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D4: false

tool: D12: true

assistant: ```c
void Primes(int num) {
  int limit = sqrt(num);
  for (int factor = 2; factor < limit; factor += 1) {
    if ((num % factor) == 0) {
      printf("false");
    }
  }
  printf("true");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Primes>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <sqrt@plt>
  cmp    $0x2,%eax
  jle    L10
  mov    %eax,%ebp
  mov    $0x2,%ebx
  lea    D14(%rip),%r13
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L10
L18:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L25
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L18
L10:
  add    $0x8,%rsp
  lea    D3(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D3
type: string

tool: D14: false

tool: D3: true

assistant: ```c
void Primes(int num) {
  int limit = sqrt(num);
  for (int factor = 2; factor < limit; factor += 1) {
    if ((num % factor) == 0) {
      printf("false");
    }
  }
  printf("true");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <regtestNew@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
extern int main() {
  regtestNew();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <regtestNew@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern int main() {
  regtestNew();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <regtestNew@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern int main() {
  regtestNew();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <regtestNew@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern int main() {
  regtestNew();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<darm_bit_count_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L14:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jne    L27
  addl   $0x1,-0x8(%rbp)
L27:
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0xf,-0x4(%rbp)
  jle    L14
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int darm_bit_count_16(int bit_string) {
  int bitCount = 0;
  int i = 0;
  for (; i < 16; i++) {
    if ((bit_string & (0b1 << i)) == 1) {
      bitCount++;
    }
  }
  return bitCount;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<darm_bit_count_16>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
L7:
  mov    %esi,%eax
  shl    %cl,%eax
  and    %edi,%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%ecx
  cmp    $0x10,%ecx
  jne    L7
  mov    %edx,%eax
  ret
```

assistant: ```c
int darm_bit_count_16(int bit_string) {
  int bitCount = 0;
  int i = 0;
  for (; i < 16; i++) {
    if ((bit_string & (0b1 << i)) == 1) {
      bitCount++;
    }
  }
  return bitCount;
}
```