ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <rand@plt>
  cmp    $0x7,%eax
  ja     L2
  lea    D3(%rip),%rdx
  mov    %eax,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %rbx,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
L2:
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <assert@plt>
```

assistant: ```c
void main() {
  int x, y;
  int *p, *q, *r;
  int *a1, *a2;
  p = &x;
  q = &y;
  q = p;
  p = a1 = malloc(sizeof(int));
  r = q;
  r = a2 = malloc(sizeof(int));
  switch (rand()) {
  case 0:
    assert(p != a1);
  case 1:
    assert(p != &x);
  case 2:
    assert(q != a1);
  case 3:
    assert(q != &x);
  case 4:
    assert(q != &y);
  case 5:
    assert(r != a1);
  case 6:
    assert(r != a2);
  case 7:
    assert(r != &x);
  default:
    assert(r != &y);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <drand48@plt>
  movsd  -0x8(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jbe    L18
  mov    $0x1,%eax
  jmp    L15
L18:
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
long binary(double prob) {
  if (drand48() < prob)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <drand48@plt>
  movq   %rbx,%xmm1
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
long binary(double prob) {
  if (drand48() < prob)
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<binary>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <drand48@plt>
  movsd  0x8(%rsp),%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  add    $0x18,%rsp
  ret
```

assistant: ```c
long binary(double prob) {
  if (drand48() < prob)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <drand48@plt>
  movsd  0x8(%rsp),%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  add    $0x18,%rsp
  ret
```

assistant: ```c
long binary(double prob) {
  if (drand48() < prob)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<compute_percentile_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L14
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jg     L11
  movss  -0x4(%rbp),%xmm1
  movss  D7(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L11:
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L10
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x18(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float compute_percentile_i(int x, int *xv, int n) {
  int i;
  float p = 0.0;
  for (i = 1; i <= n; i++) {
    if (xv[i] >= x)
      p++;
  }
  p = p / (float)n;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compute_percentile_i>:
  endbr64
  test   %edx,%edx
  jle    L30
  lea    0x4(%rsi),%rax
  lea    -0x1(%rdx),%ecx
  lea    0x8(%rsi,%rcx,4),%rcx
  pxor   %xmm0,%xmm0
  movss  D9(%rip),%xmm1
  jmp    L44
L10:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L0
L44:
  cmp    %edi,(%rax)
  jl     L10
  addss  %xmm1,%xmm0
  jmp    L10
L30:
  pxor   %xmm0,%xmm0
L0:
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float compute_percentile_i(int x, int *xv, int n) {
  int i;
  float p = 0.0;
  for (i = 1; i <= n; i++) {
    if (xv[i] >= x)
      p++;
  }
  p = p / (float)n;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compute_percentile_i>:
  endbr64
  test   %edx,%edx
  jle    L18
  lea    -0x1(%rdx),%ecx
  movss  D8(%rip),%xmm1
  lea    0x4(%rsi),%rax
  pxor   %xmm0,%xmm0
  lea    0x8(%rsi,%rcx,4),%rcx
L24:
  cmp    %edi,(%rax)
  jl     L0
  addss  %xmm1,%xmm0
L0:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L24
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L18:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: byte[4]

tool: {"D8": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float compute_percentile_i(int x, int *xv, int n) {
  int i;
  float p = 0.0;
  for (i = 1; i <= n; i++) {
    if (xv[i] >= x)
      p++;
  }
  p = p / (float)n;
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<compute_percentile_i>:
  endbr64
  test   %edx,%edx
  jle    L12
  lea    -0x1(%rdx),%ecx
  movss  D7(%rip),%xmm1
  lea    0x4(%rsi),%rax
  pxor   %xmm0,%xmm0
  lea    0x8(%rsi,%rcx,4),%rcx
L5:
  cmp    %edi,(%rax)
  jl     L8
  addss  %xmm1,%xmm0
L8:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L5
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L12:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float compute_percentile_i(int x, int *xv, int n) {
  int i;
  float p = 0.0;
  for (i = 1; i <= n; i++) {
    if (xv[i] >= x)
      p++;
  }
  p = p / (float)n;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<a4_to_a3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x4,%eax
  and    $0x3,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x2,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  add    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  add    %ecx,%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void a4_to_a3(unsigned char *a3, unsigned char *a4) {
  a3[0] = (a4[0] << 2) + ((a4[1] & 0x30) >> 4);
  a3[1] = ((a4[1] & 0xf) << 4) + ((a4[2] & 0x3c) >> 2);
  a3[2] = ((a4[2] & 0x3) << 6) + a4[3];
}
```
user: What is the c source code of the assembly code below:

```asm
<a4_to_a3>:
  endbr64
  movzbl 0x1(%rsi),%eax
  sar    $0x4,%eax
  and    $0x3,%eax
  movzbl (%rsi),%ecx
  lea    (%rax,%rcx,4),%eax
  mov    %al,(%rdi)
  movzbl 0x2(%rsi),%eax
  sar    $0x2,%eax
  and    $0xf,%eax
  movzbl 0x1(%rsi),%ecx
  shl    $0x4,%ecx
  add    %ecx,%eax
  mov    %al,0x1(%rdi)
  movzbl 0x2(%rsi),%eax
  shl    $0x6,%eax
  add    0x3(%rsi),%al
  mov    %al,0x2(%rdi)
  ret
```

assistant: ```c
void a4_to_a3(unsigned char *a3, unsigned char *a4) {
  a3[0] = (a4[0] << 2) + ((a4[1] & 0x30) >> 4);
  a3[1] = ((a4[1] & 0xf) << 4) + ((a4[2] & 0x3c) >> 2);
  a3[2] = ((a4[2] & 0x3) << 6) + a4[3];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<a4_to_a3>:
  endbr64
  movzbl 0x1(%rsi),%eax
  movzbl (%rsi),%ecx
  sar    $0x4,%eax
  and    $0x3,%eax
  lea    (%rax,%rcx,4),%eax
  mov    %al,(%rdi)
  movzbl 0x2(%rsi),%eax
  movzbl 0x1(%rsi),%ecx
  sar    $0x2,%eax
  and    $0xf,%eax
  shl    $0x4,%ecx
  add    %ecx,%eax
  mov    %al,0x1(%rdi)
  movzbl 0x2(%rsi),%eax
  shl    $0x6,%eax
  add    0x3(%rsi),%al
  mov    %al,0x2(%rdi)
  ret
```

assistant: ```c
void a4_to_a3(unsigned char *a3, unsigned char *a4) {
  a3[0] = (a4[0] << 2) + ((a4[1] & 0x30) >> 4);
  a3[1] = ((a4[1] & 0xf) << 4) + ((a4[2] & 0x3c) >> 2);
  a3[2] = ((a4[2] & 0x3) << 6) + a4[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L45:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L45
  cmpl   $0x9,-0x10(%rbp)
  je     L45
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L24
  cmpl   $0x2e,-0x10(%rbp)
  je     L24
  mov    -0x10(%rbp),%eax
  jmp    L65
L24:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L49
  nop
L46:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L46
L49:
  cmpl   $0x2e,-0x10(%rbp)
  jne    L68
  nop
L53:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L53
L68:
  movq   $0x0,-0x8(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  je     L95
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L95:
  mov    $0x1,%eax
L65:
  leave
  ret
```

assistant: ```c
int getop(char *s) {
  int i, c;
  char *p;
  p = s;
  while ((*p = c = getch()) == ' ' || c == '\t')
    ;
  p++;
  *p = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  p = s;
  if (isdigit(c))
    while (isdigit(*p++ = c = getch()))
      ;
  if (c == '.')
    while (isdigit(*p++ = c = getch()))
      ;
  p = '\0';
  if (c != EOF)
    ungetch(c);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L98:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%eax
  je     L98
  cmp    $0x20,%al
  je     L98
  movb   $0x0,0x1(%rbp)
  mov    %eax,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%ebx
  je     L73
  test   %rax,%rax
  je     L97
L73:
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L33
L66:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L66
L33:
  cmp    $0x2e,%ebx
  je     L15
L74:
  mov    D1(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L17
  mov    $0x1,%ebx
L97:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L15
  jmp    L74
L17:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x1,%ebx
  jmp    L97
```

assistant: ```c
int getop(char *s) {
  int i, c;
  char *p;
  p = s;
  while ((*p = c = getch()) == ' ' || c == '\t')
    ;
  p++;
  *p = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  p = s;
  if (isdigit(c))
    while (isdigit(*p++ = c = getch()))
      ;
  if (c == '.')
    while (isdigit(*p++ = c = getch()))
      ;
  p = '\0';
  if (c != EOF)
    ungetch(c);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getop>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L73:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L73
  cmp    $0x20,%al
  je     L73
  movb   $0x0,0x1(%rbx)
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L107
  cmp    $0x2e,%r12d
  je     L99
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L99:
  mov    $0x2e,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L22
  nop
L106:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L106
  jmp    L34
L107:
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L72
  nopl   (%rax)
L22:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L22
L72:
  cmp    $0x2e,%r12d
  je     L106
L34:
  mov    D3(%rip),%rax
  cmp    %r12d,(%rax)
  je     L17
  mov    %r12d,%edi
  mov    $0x1,%r12d
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  mov    $0x1,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int getop(char *s) {
  int i, c;
  char *p;
  p = s;
  while ((*p = c = getch()) == ' ' || c == '\t')
    ;
  p++;
  *p = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  p = s;
  if (isdigit(c))
    while (isdigit(*p++ = c = getch()))
      ;
  if (c == '.')
    while (isdigit(*p++ = c = getch()))
      ;
  p = '\0';
  if (c != EOF)
    ungetch(c);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getop>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L47:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L47
  cmp    $0x20,%al
  je     L47
  movb   $0x0,0x1(%rbx)
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L83
  cmp    $0x2e,%r12d
  je     L13
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    $0x2e,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L66
  nop
L89:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L89
  jmp    L23
L83:
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L14
  nopl   (%rax)
L66:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L66
L14:
  cmp    $0x2e,%r12d
  je     L89
L23:
  mov    D0(%rip),%rax
  cmp    %r12d,(%rax)
  je     L4
  mov    %r12d,%edi
  mov    $0x1,%r12d
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int getop(char *s) {
  int i, c;
  char *p;
  p = s;
  while ((*p = c = getch()) == ' ' || c == '\t')
    ;
  p++;
  *p = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  p = s;
  if (isdigit(c))
    while (isdigit(*p++ = c = getch()))
      ;
  if (c == '.')
    while (isdigit(*p++ = c = getch()))
      ;
  p = '\0';
  if (c != EOF)
    ungetch(c);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pcapack_rowsums>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L14:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L19:
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  addl   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L14
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pcapack_rowsums(const int m, const int n, double *x, double *rowsums) {
  int i, j;
  double tmp;
  for (i = 0; i < n; i++) {
    tmp = 0.;
    for (j = 0; j < m; j++) {
      tmp += x[i + m * j];
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pcapack_rowsums>:
  endbr64
  mov    $0x0,%edx
  test   %esi,%esi
  jg     L27
L8:
  mov    $0x0,%eax
  ret
L43:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L43
L24:
  add    $0x1,%edx
  cmp    %edx,%esi
  je     L8
L27:
  mov    $0x0,%eax
  test   %edi,%edi
  jg     L43
  jmp    L24
```

assistant: ```c
int pcapack_rowsums(const int m, const int n, double *x, double *rowsums) {
  int i, j;
  double tmp;
  for (i = 0; i < n; i++) {
    tmp = 0.;
    for (j = 0; j < m; j++) {
      tmp += x[i + m * j];
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pcapack_rowsums>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int pcapack_rowsums(const int m, const int n, double *x, double *rowsums) {
  int i, j;
  double tmp;
  for (i = 0; i < n; i++) {
    tmp = 0.;
    for (j = 0; j < m; j++) {
      tmp += x[i + m * j];
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pcapack_rowsums>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int pcapack_rowsums(const int m, const int n, double *x, double *rowsums) {
  int i, j;
  double tmp;
  for (i = 0; i < n; i++) {
    tmp = 0.;
    for (j = 0; j < m; j++) {
      tmp += x[i + m * j];
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<native_save_fl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pushf
  pop    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long native_save_fl(void) {
  unsigned long flags;
  asm volatile("# __raw_save_flags\n\t"
               "pushf ; pop %0"
               : "=rm"(flags)
               :
               : "memory");
  return flags;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<native_save_fl>:
  endbr64
  pushf
  pop    %rax
  ret
```

assistant: ```c
unsigned long native_save_fl(void) {
  unsigned long flags;
  asm volatile("# __raw_save_flags\n\t"
               "pushf ; pop %0"
               : "=rm"(flags)
               :
               : "memory");
  return flags;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<native_save_fl>:
  endbr64
  pushf
  pop    %rax
  ret
```

assistant: ```c
unsigned long native_save_fl(void) {
  unsigned long flags;
  asm volatile("# __raw_save_flags\n\t"
               "pushf ; pop %0"
               : "=rm"(flags)
               :
               : "memory");
  return flags;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<native_save_fl>:
  endbr64
  pushf
  pop    %rax
  ret
```

assistant: ```c
unsigned long native_save_fl(void) {
  unsigned long flags;
  asm volatile("# __raw_save_flags\n\t"
               "pushf ; pop %0"
               : "=rm"(flags)
               :
               : "memory");
  return flags;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_02>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_02(float val) {
  union {
    int i;
    float f;
  } tmp;
  tmp.f = val;
  return tmp.i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_02>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
int test_02(float val) {
  union {
    int i;
    float f;
  } tmp;
  tmp.f = val;
  return tmp.i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_02>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
int test_02(float val) {
  union {
    int i;
    float f;
  } tmp;
  tmp.f = val;
  return tmp.i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_02>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
int test_02(float val) {
  union {
    int i;
    float f;
  } tmp;
  tmp.f = val;
  return tmp.i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L34
L26:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <shannon_entropy@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  D28(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L2
  lea    D6(%rip),%rax
  jmp    L38
L2:
  lea    D35(%rip),%rax
L38:
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rcx
  mov    %rax,%rdx
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L26
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
data_type: f64
name: extract_symbolic_data
arguments: label: D6
data_type: string
name: extract_symbolic_data
arguments: label: D35
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string

tool: D28: 3.5

tool: D6: bad

tool: D35: good

tool: D18: Shannon entropy of "%s" is %f (%s)


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  char *p;
  double e;
  for (i = 1; i < argc; i++) {
    p = argv[i];
    e = shannon_entropy((unsigned char *)p, strlen(p));
    printf("Shannon entropy of \"%s\" is %f (%s)\n", p, e, e < 3.5 ? "bad" : "good");
  }
  return 0;
}
```