user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xb0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x14,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x3,-0xb0(%rbp)
  movl   $0x2,-0xac(%rbp)
  movl   $0xa,-0xa8(%rbp)
  movl   $0x2,-0xa4(%rbp)
  movl   $0x4,-0xa0(%rbp)
  movl   $0x5,-0x9c(%rbp)
  movl   $0x7,-0x98(%rbp)
  movl   $0x6,-0x94(%rbp)
  movl   $0x9,-0x90(%rbp)
  movl   $0xa,-0x8c(%rbp)
  movl   $0x5,-0x88(%rbp)
  movl   $0x3,-0x84(%rbp)
  movl   $0x2,-0x80(%rbp)
  movl   $0x6,-0x7c(%rbp)
  movl   $0x3,-0x78(%rbp)
  movl   $0x5,-0x74(%rbp)
  movl   $0x3,-0x70(%rbp)
  movl   $0x7,-0x6c(%rbp)
  movl   $0x8,-0x68(%rbp)
  movl   $0x9,-0x64(%rbp)
  movl   $0x6,-0x60(%rbp)
  movl   $0x7,-0x5c(%rbp)
  movl   $0x8,-0x58(%rbp)
  movl   $0x9,-0x54(%rbp)
  movl   $0x4,-0x50(%rbp)
  movl   $0x5,-0x4c(%rbp)
  movl   $0x6,-0x48(%rbp)
  movl   $0x7,-0x44(%rbp)
  movl   $0x3,-0x40(%rbp)
  movl   $0x5,-0x3c(%rbp)
  movl   $0x6,-0x38(%rbp)
  movl   $0x3,-0x34(%rbp)
  movl   $0x4,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movl   $0x0,-0xb8(%rbp)
  movl   $0x0,-0xe8(%rbp)
  jmp    L4
L0:
  mov    -0xe8(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,4),%eax
  movslq %eax,%rdx
  mov    -0xe0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0xe0(%rbp,%rax,4)
  addl   $0x1,-0xe8(%rbp)
L4:
  cmpl   $0x27,-0xe8(%rbp)
  jle    L0
  lea    D19(%rip),%rax
  mov    %rax,%rdx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xe4(%rbp)
  jmp    L11
L39:
  mov    -0xe4(%rbp),%eax
  cltq
  mov    -0xe0(%rbp,%rax,4),%edx
  mov    -0xe4(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xe4(%rbp)
L11:
  cmpl   $0xa,-0xe4(%rbp)
  jle    L39
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D7
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string

tool: D19: Frequency

tool: D17: Rating

tool: D7: %s%17s


tool: D16: %6d%17d


assistant: ```c
int main(void) {
  int myAnswer, userRating;
  int userResponse[40] = {3, 2, 10, 2, 4, 5, 7, 6, 9, 10, 5, 3, 2, 6, 3, 5, 3, 7, 8, 9, 6, 7, 8, 9, 4, 5, 6, 7, 3, 5, 6, 3, 4, 5, 8, 9, 4, 1, 2};
  int myFreq[11] = {0};
  for (myAnswer = 0; myAnswer <= 40 - 1; myAnswer++) {
    ++myFreq[userResponse[myAnswer]];
  }
  printf("%s%17s\n", "Rating", "Frequency");
  for (userRating = 0; userRating <= 11 - 1; userRating++) {
    printf("%6d%17d\n", userRating, myFreq[userRating]);
  }
  return 0;
}
```