ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  mov    $0x270f,%esi
  call   <CreateUdpSock@plt>
  lea    D0(%rip),%rbp
  jmp    L6
L24:
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
L6:
  movl   $0x100,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    0x8(%rsp),%edi
  call   <RecvMsgByUdp@plt>
  test   %rax,%rax
  je     L24
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: Recv UDP Data:[%d][%s]


assistant: ```c
int main() {
  int nSock, nSize;
  char szBuf[256];
  CreateUdpSock(&nSock, 9999);
  nSize = sizeof(szBuf);
  while (RecvMsgByUdp(nSock, szBuf, &nSize) == 0) {
    printf("Recv UDP Data:[%d][%s]\n", strlen(szBuf), szBuf);
    nSize = sizeof(szBuf);
  }
  close(nSock);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x270f,%esi
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0xc(%rsp),%rbp
  call   <CreateUdpSock@plt>
  lea    0x10(%rsp),%rbx
  jmp    L1
  nopl   0x0(%rax)
L16:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%edi
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  movl   $0x100,0xc(%rsp)
  call   <RecvMsgByUdp@plt>
  test   %rax,%rax
  je     L16
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: Recv UDP Data:[%d][%s]


assistant: ```c
int main() {
  int nSock, nSize;
  char szBuf[256];
  CreateUdpSock(&nSock, 9999);
  nSize = sizeof(szBuf);
  while (RecvMsgByUdp(nSock, szBuf, &nSize) == 0) {
    printf("Recv UDP Data:[%d][%s]\n", strlen(szBuf), szBuf);
    nSize = sizeof(szBuf);
  }
  close(nSock);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x270f,%esi
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0xc(%rsp),%rbp
  call   <CreateUdpSock@plt>
  lea    0x10(%rsp),%rbx
  jmp    L18
  nopl   0x0(%rax)
L12:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%edi
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  movl   $0x100,0xc(%rsp)
  call   <RecvMsgByUdp@plt>
  test   %rax,%rax
  je     L12
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string

tool: D3: Recv UDP Data:[%d][%s]


assistant: ```c
int main() {
  int nSock, nSize;
  char szBuf[256];
  CreateUdpSock(&nSock, 9999);
  nSize = sizeof(szBuf);
  while (RecvMsgByUdp(nSock, szBuf, &nSize) == 0) {
    printf("Recv UDP Data:[%d][%s]\n", strlen(szBuf), szBuf);
    nSize = sizeof(szBuf);
  }
  close(nSock);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eof_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  test   %rax,%rax
  je     L29
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_strdup@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L38
  mov    $0xffffffff,%eax
  jmp    L16
L38:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strdel@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strdel@plt>
  mov    $0x1,%eax
  jmp    L16
L29:
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int eof_exit(char **line_copy, char **buffer, char **line) {
  if (ft_strlen(*line_copy)) {
    if (!(*line = ft_strdup(*line_copy)))
      return (-1);
    ft_strdel(line_copy);
    ft_strdel(buffer);
    return (1);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eof_exit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    (%rdi),%rdi
  call   <ft_strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L14
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    (%rbx),%rdi
  call   <ft_strdup@plt>
  mov    %rax,%rdx
  mov    %rax,0x0(%rbp)
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  je     L15
  mov    %rbx,%rdi
  call   <ft_strdel@plt>
  mov    %r12,%rdi
  call   <ft_strdel@plt>
  mov    $0x1,%eax
  jmp    L15
```

assistant: ```c
int eof_exit(char **line_copy, char **buffer, char **line) {
  if (ft_strlen(*line_copy)) {
    if (!(*line = ft_strdup(*line_copy)))
      return (-1);
    ft_strdel(line_copy);
    ft_strdel(buffer);
    return (1);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eof_exit>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%rdi
  mov    %rdx,%rbx
  call   <ft_strlen@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L1
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp),%rdi
  call   <ft_strdup@plt>
  mov    %rax,%rdx
  mov    %rax,(%rbx)
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  je     L0
  mov    %rbp,%rdi
  call   <ft_strdel@plt>
  mov    %r12,%rdi
  call   <ft_strdel@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int eof_exit(char **line_copy, char **buffer, char **line) {
  if (ft_strlen(*line_copy)) {
    if (!(*line = ft_strdup(*line_copy)))
      return (-1);
    ft_strdel(line_copy);
    ft_strdel(buffer);
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<eof_exit>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%rdi
  mov    %rdx,%rbx
  call   <ft_strlen@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L8
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    0x0(%rbp),%rdi
  call   <ft_strdup@plt>
  mov    %rax,%rdx
  mov    %rax,(%rbx)
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  je     L9
  mov    %rbp,%rdi
  call   <ft_strdel@plt>
  mov    %r12,%rdi
  call   <ft_strdel@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int eof_exit(char **line_copy, char **buffer, char **line) {
  if (ft_strlen(*line_copy)) {
    if (!(*line = ft_strdup(*line_copy)))
      return (-1);
    ft_strdel(line_copy);
    ft_strdel(buffer);
    return (1);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <yyparse@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: > 

assistant: ```c
int main(int argc, const char **argv) {
  printf("> ");
  return yyparse();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <yyparse@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: > 

assistant: ```c
int main(int argc, const char **argv) {
  printf("> ");
  return yyparse();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <yyparse@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: > 

assistant: ```c
int main(int argc, const char **argv) {
  printf("> ");
  return yyparse();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <yyparse@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: > 

assistant: ```c
int main(int argc, const char **argv) {
  printf("> ");
  return yyparse();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <find_max@plt>
  mov    %eax,%r13d
  test   %r12d,%r12d
  jle    L107
  mov    %rbx,%r14
  mov    %r12d,%eax
  lea    (%rbx,%rax,8),%r15
L30:
  mov    $0x4,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rax,(%r14)
  add    $0x8,%r14
  cmp    %r15,%r14
  jne    L30
L107:
  mov    $0x4,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rax,%r9
  test   %r13d,%r13d
  jle    L63
  lea    -0x1(%r12),%eax
  shl    $0x2,%rax
  lea    0x4(%rbp,%rax,1),%r11
  lea    0x4(%r9,%rax,1),%r10
  mov    $0x1,%r8d
  jmp    L16
L40:
  movl   $0x0,(%r14)
  add    $0x4,%rsi
  add    $0x8,%rdi
  cmp    %r10,%rsi
  je     L31
L85:
  mov    %rsi,%r14
  cmpl   $0x0,(%rsi)
  jle    L40
  movslq %ecx,%rax
  lea    0x0(%rbp,%rax,4),%r15
  mov    $0x0,%eax
  lea    0x1(%rcx),%edx
L4:
  mov    (%rdi),%rcx
  mov    (%rcx,%rax,4),%ecx
  mov    %ecx,(%r15,%rax,4)
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %eax,(%r14)
  jg     L4
  jmp    L40
L31:
  lea    (%r8,%r8,4),%eax
  add    %eax,%eax
  mov    %eax,%r8d
  cmp    %eax,%r13d
  jl     L63
L16:
  mov    %rbp,%rcx
  test   %r12d,%r12d
  jle    L31
L62:
  mov    (%rcx),%esi
  mov    %esi,%eax
  cltd
  idiv   %r8d
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  lea    (%r9,%rax,4),%rdx
  movslq (%rdx),%rdi
  mov    (%rbx,%rax,8),%rax
  mov    %esi,(%rax,%rdi,4)
  addl   $0x1,(%rdx)
  add    $0x4,%rcx
  cmp    %r11,%rcx
  jne    L62
  mov    %rbx,%rdi
  mov    %r9,%rsi
  mov    $0x0,%ecx
  jmp    L85
L63:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *sort(int *number, int length) {
  int i, j;
  int k = 0, n = 1, max, lsd;
  int **temp = malloc(sizeof(int) * length);
  int *order;
  max = find_max(number, length);
  for (i = 0; i < length; i++)
    temp[i] = calloc(length, sizeof(int));
  order = calloc(length, sizeof(int));
  while (n <= max) {
    for (i = 0; i < length; i++) {
      lsd = (number[i] / n) % 10;
      temp[lsd][order[lsd]] = number[i];
      order[lsd] += 1;
    }
    for (i = 0; i < length; i++) {
      if (order[i] != 0) {
        for (j = 0; j < order[i]; j++) {
          number[k] = temp[i][j];
          k += 1;
        }
      }
      order[i] = 0;
    }
    n *= 10;
    k = 0;
  }
  return number;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    0x0(,%rsi,4),%edi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <find_max@plt>
  mov    %eax,%ebx
  test   %r13d,%r13d
  jle    L25
  mov    %r13d,%eax
  mov    %rbp,%r14
  lea    0x0(%rbp,%rax,8),%r15
  nopl   0x0(%rax)
L26:
  mov    $0x4,%esi
  mov    %r13d,%edi
  add    $0x8,%r14
  call   <calloc@plt>
  mov    %rax,-0x8(%r14)
  cmp    %r14,%r15
  jne    L26
L25:
  mov    $0x4,%esi
  mov    %r13d,%edi
  call   <calloc@plt>
  mov    %rax,%rcx
  test   %ebx,%ebx
  jle    L34
  lea    -0x1(%r13),%r8d
  mov    $0x1,%edi
  lea    0x4(%r12,%r8,4),%r9
  nopl   0x0(%rax,%rax,1)
L93:
  mov    %r12,%rsi
  test   %r13d,%r13d
  jle    L94
  nopl   0x0(%rax)
L90:
  mov    (%rsi),%r10d
  add    $0x4,%rsi
  mov    %r10d,%eax
  cltd
  idiv   %edi
  movslq %eax,%rdx
  mov    %eax,%r11d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r11d
  sar    $0x22,%rdx
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  lea    (%rcx,%rax,4),%rdx
  mov    0x0(%rbp,%rax,8),%rax
  movslq (%rdx),%r11
  mov    %r10d,(%rax,%r11,4)
  addl   $0x1,(%rdx)
  cmp    %rsi,%r9
  jne    L90
  xor    %edx,%edx
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L22:
  mov    (%rcx,%rdx,4),%eax
  test   %eax,%eax
  jle    L50
  movslq %esi,%rax
  mov    0x0(%rbp,%rdx,8),%r11
  lea    0x1(%rsi),%r14d
  lea    (%r12,%rax,4),%r10
  xor    %eax,%eax
L63:
  mov    (%r11,%rax,4),%esi
  mov    %esi,(%r10,%rax,4)
  lea    (%r14,%rax,1),%esi
  add    $0x1,%rax
  cmp    %eax,(%rcx,%rdx,4)
  jg     L63
L50:
  movl   $0x0,(%rcx,%rdx,4)
  lea    0x1(%rdx),%rax
  cmp    %rdx,%r8
  je     L94
  mov    %rax,%rdx
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L94:
  lea    (%rdi,%rdi,4),%edi
  add    %edi,%edi
  cmp    %edi,%ebx
  jge    L93
L34:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *sort(int *number, int length) {
  int i, j;
  int k = 0, n = 1, max, lsd;
  int **temp = malloc(sizeof(int) * length);
  int *order;
  max = find_max(number, length);
  for (i = 0; i < length; i++)
    temp[i] = calloc(length, sizeof(int));
  order = calloc(length, sizeof(int));
  while (n <= max) {
    for (i = 0; i < length; i++) {
      lsd = (number[i] / n) % 10;
      temp[lsd][order[lsd]] = number[i];
      order[lsd] += 1;
    }
    for (i = 0; i < length; i++) {
      if (order[i] != 0) {
        for (j = 0; j < order[i]; j++) {
          number[k] = temp[i][j];
          k += 1;
        }
      }
      order[i] = 0;
    }
    n *= 10;
    k = 0;
  }
  return number;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    0x0(,%rsi,4),%edi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <find_max@plt>
  mov    %eax,%ebx
  test   %r13d,%r13d
  jle    L70
  mov    %r13d,%eax
  mov    %rbp,%r14
  lea    0x0(%rbp,%rax,8),%r15
  nopl   0x0(%rax)
L6:
  mov    $0x4,%esi
  mov    %r13d,%edi
  add    $0x8,%r14
  call   <calloc@plt>
  mov    %rax,-0x8(%r14)
  cmp    %r14,%r15
  jne    L6
L70:
  mov    $0x4,%esi
  mov    %r13d,%edi
  call   <calloc@plt>
  mov    %rax,%rcx
  test   %ebx,%ebx
  jle    L99
  lea    -0x1(%r13),%r8d
  mov    $0x1,%edi
  lea    0x4(%r12,%r8,4),%r9
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r12,%rsi
  test   %r13d,%r13d
  jle    L98
  nopl   0x0(%rax)
L82:
  mov    (%rsi),%r10d
  add    $0x4,%rsi
  mov    %r10d,%eax
  cltd
  idiv   %edi
  movslq %eax,%rdx
  mov    %eax,%r11d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r11d
  sar    $0x22,%rdx
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  lea    (%rcx,%rax,4),%rdx
  mov    0x0(%rbp,%rax,8),%rax
  movslq (%rdx),%r11
  mov    %r10d,(%rax,%r11,4)
  addl   $0x1,(%rdx)
  cmp    %rsi,%r9
  jne    L82
  xor    %edx,%edx
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L31:
  mov    (%rcx,%rdx,4),%eax
  test   %eax,%eax
  jle    L75
  movslq %esi,%rax
  mov    0x0(%rbp,%rdx,8),%r11
  lea    0x1(%rsi),%r14d
  lea    (%r12,%rax,4),%r10
  xor    %eax,%eax
L66:
  mov    (%r11,%rax,4),%esi
  mov    %esi,(%r10,%rax,4)
  lea    (%r14,%rax,1),%esi
  add    $0x1,%rax
  cmp    %eax,(%rcx,%rdx,4)
  jg     L66
L75:
  movl   $0x0,(%rcx,%rdx,4)
  lea    0x1(%rdx),%rax
  cmp    %rdx,%r8
  je     L98
  mov    %rax,%rdx
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L98:
  lea    (%rdi,%rdi,4),%edi
  add    %edi,%edi
  cmp    %edi,%ebx
  jge    L7
L99:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *sort(int *number, int length) {
  int i, j;
  int k = 0, n = 1, max, lsd;
  int **temp = malloc(sizeof(int) * length);
  int *order;
  max = find_max(number, length);
  for (i = 0; i < length; i++)
    temp[i] = calloc(length, sizeof(int));
  order = calloc(length, sizeof(int));
  while (n <= max) {
    for (i = 0; i < length; i++) {
      lsd = (number[i] / n) % 10;
      temp[lsd][order[lsd]] = number[i];
      order[lsd] += 1;
    }
    for (i = 0; i < length; i++) {
      if (order[i] != 0) {
        for (j = 0; j < order[i]; j++) {
          number[k] = temp[i][j];
          k += 1;
        }
      }
      order[i] = 0;
    }
    n *= 10;
    k = 0;
  }
  return number;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mapred_tokenize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L13
L44:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mapred_forward_delim_len@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mapred_forward_token_len@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mapred_register_token@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L14
  mov    -0xc(%rbp),%eax
  jmp    L42
L14:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
L13:
  cmpq   $0x0,-0x28(%rbp)
  jne    L44
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mapred_flatten_token_store@plt>
L42:
  leave
  ret
```

assistant: ```c
int mapred_tokenize(struct mapred_token_store *store, const char *data, size_t size) {
  while (size) {
    size_t len;
    len = mapred_forward_delim_len(data, size);
    data += len;
    size -= len;
    len = mapred_forward_token_len(data, size);
    if (len) {
      int err;
      err = mapred_register_token(store, data, len);
      if (err)
        return err;
    }
    data += len;
    size -= len;
  }
  return mapred_flatten_token_store(store);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mapred_tokenize>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  test   %rdx,%rdx
  jne    L8
L2:
  mov    %r13,%rdi
  call   <mapred_flatten_token_store@plt>
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  add    %rbx,%r12
  sub    %rbx,%rbp
  je     L2
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mapred_forward_delim_len@plt>
  add    %rax,%r12
  sub    %rax,%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mapred_forward_token_len@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L30
  mov    %rax,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <mapred_register_token@plt>
  test   %eax,%eax
  je     L30
  jmp    L37
```

assistant: ```c
int mapred_tokenize(struct mapred_token_store *store, const char *data, size_t size) {
  while (size) {
    size_t len;
    len = mapred_forward_delim_len(data, size);
    data += len;
    size -= len;
    len = mapred_forward_token_len(data, size);
    if (len) {
      int err;
      err = mapred_register_token(store, data, len);
      if (err)
        return err;
    }
    data += len;
    size -= len;
  }
  return mapred_flatten_token_store(store);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mapred_tokenize>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L22
  mov    %rsi,%r13
  mov    %rdx,%rbp
  jmp    L27
  xchg   %ax,%ax
L37:
  add    %rbx,%r13
  sub    %rbx,%rbp
  je     L22
L27:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <mapred_forward_delim_len@plt>
  add    %rax,%r13
  sub    %rax,%rbp
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <mapred_forward_token_len@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
  mov    %rax,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <mapred_register_token@plt>
  test   %eax,%eax
  je     L37
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <mapred_flatten_token_store@plt>
```

assistant: ```c
int mapred_tokenize(struct mapred_token_store *store, const char *data, size_t size) {
  while (size) {
    size_t len;
    len = mapred_forward_delim_len(data, size);
    data += len;
    size -= len;
    len = mapred_forward_token_len(data, size);
    if (len) {
      int err;
      err = mapred_register_token(store, data, len);
      if (err)
        return err;
    }
    data += len;
    size -= len;
  }
  return mapred_flatten_token_store(store);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mapred_tokenize>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L48
  mov    %rsi,%r13
  mov    %rdx,%rbp
  jmp    L24
  xchg   %ax,%ax
L41:
  add    %rbx,%r13
  sub    %rbx,%rbp
  je     L48
L24:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <mapred_forward_delim_len@plt>
  add    %rax,%r13
  sub    %rax,%rbp
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <mapred_forward_token_len@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L41
  mov    %rax,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <mapred_register_token@plt>
  test   %eax,%eax
  je     L41
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L48:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <mapred_flatten_token_store@plt>
```

assistant: ```c
int mapred_tokenize(struct mapred_token_store *store, const char *data, size_t size) {
  while (size) {
    size_t len;
    len = mapred_forward_delim_len(data, size);
    data += len;
    size -= len;
    len = mapred_forward_token_len(data, size);
    if (len) {
      int err;
      err = mapred_register_token(store, data, len);
      if (err)
        return err;
    }
    data += len;
    size -= len;
  }
  return mapred_flatten_token_store(store);
}
```