ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<trim>:
  endbr64
  test   %rdi,%rdi
  je     L109
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  je     L117
  movzbl 0x0(%rbp),%eax
  and    $0xfffffffd,%eax
  cmp    $0x20,%al
  jne    L122
  mov    $0x1,%eax
L88:
  mov    %eax,%r12d
  movzbl 0x0(%rbp,%rax,1),%edx
  and    $0xfffffffd,%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L88
  mov    $0x0,%ebx
  movslq %r12d,%r14
  test   %r12d,%r12d
  jne    L69
  jmp    L122
L33:
  lea    0x0(%rbp,%r14,1),%rax
  movzbl (%rax,%rbx,1),%eax
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L69:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    %r12d,%eax
  cmp    %ebx,%eax
  jg     L33
  movslq %ebx,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
L122:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  cmp    $0x1,%ebx
  jle    L45
  movslq %ebx,%rax
  add    %rbp,%rax
  movabs $0x500002400,%rcx
  jmp    L74
L72:
  bt     %rdx,%rcx
  jae    L45
  sub    $0x1,%ebx
  sub    $0x1,%rax
  cmp    $0x1,%ebx
  je     L45
L74:
  movzbl (%rax),%edx
  cmp    $0x22,%dl
  jbe    L72
L45:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  je     L117
  movslq %ebx,%rbx
  movb   $0x0,0x1(%rbp,%rbx,1)
L117:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L109:
  ret
```

assistant: ```c
void trim(char *str) {
  int i = 0, j = 0;
  if (str == 0)
    return;
  if (strlen(str) == 0)
    return;
  while ((str[i] == ' ') || (str[i] == '"'))
    i++;
  if (i != 0) {
    for (j = 0; j < strlen(str) - i; j++) {
      str[j] = str[i + j];
    }
    str[j] = 0;
  }
  i = strlen(str) - 1;
  while ((i > 1) && ((str[i] == ' ') || (str[i] == '"') || (str[i] == 10) || (str[i] == 13)))
    i--;
  if (i != strlen(str) - 1) {
    str[i + 1] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trim>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L5
  movzbl 0x0(%rbp),%eax
  and    $0xfffffffd,%eax
  cmp    $0x20,%al
  jne    L57
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L105:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %eax,%r12d
  add    $0x1,%rax
  and    $0xfffffffd,%edx
  cmp    $0x20,%dl
  je     L105
  mov    %rbp,%rbx
  movslq %r12d,%r13
  jmp    L89
  nopl   0x0(%rax)
L16:
  movzbl (%rbx,%r13,1),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
L89:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  sub    %r12d,%eax
  sub    %ebp,%edx
  cmp    %edx,%eax
  jg     L16
  movb   $0x0,(%rbx)
L57:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  cmp    $0x1,%ebx
  jle    L13
  movabs $0xfffffffaffffdbff,%rcx
  movslq %ebx,%rax
  add    %rbp,%rax
  nopw   0x0(%rax,%rax,1)
L61:
  movzbl (%rax),%edx
  cmp    $0x22,%dl
  jbe    L25
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  je     L5
  add    $0x1,%ebx
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L25:
  bt     %rdx,%rcx
  jb     L13
  sub    $0x1,%ebx
  sub    $0x1,%rax
  cmp    $0x1,%ebx
  jne    L61
  jmp    L13
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void trim(char *str) {
  int i = 0, j = 0;
  if (str == 0)
    return;
  if (strlen(str) == 0)
    return;
  while ((str[i] == ' ') || (str[i] == '"'))
    i++;
  if (i != 0) {
    for (j = 0; j < strlen(str) - i; j++) {
      str[j] = str[i + j];
    }
    str[j] = 0;
  }
  i = strlen(str) - 1;
  while ((i > 1) && ((str[i] == ' ') || (str[i] == '"') || (str[i] == 10) || (str[i] == 13)))
    i--;
  if (i != strlen(str) - 1) {
    str[i + 1] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trim>:
  endbr64
  test   %rdi,%rdi
  je     L55
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L28
  movzbl 0x0(%rbp),%eax
  and    $0xfffffffd,%eax
  cmp    $0x20,%al
  jne    L76
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L119:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %eax,%r12d
  add    $0x1,%rax
  and    $0xfffffffd,%edx
  cmp    $0x20,%dl
  je     L119
  mov    %rbp,%rbx
  movslq %r12d,%r13
  jmp    L39
  nopl   0x0(%rax)
L1:
  movzbl (%rbx,%r13,1),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
L39:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  sub    %r12d,%eax
  sub    %ebp,%edx
  cmp    %edx,%eax
  jg     L1
  movb   $0x0,(%rbx)
L76:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  cmp    $0x1,%ebx
  jle    L88
  movabs $0xfffffffaffffdbff,%rcx
  movslq %ebx,%rax
  add    %rbp,%rax
  nopw   0x0(%rax,%rax,1)
L96:
  movzbl (%rax),%edx
  cmp    $0x22,%dl
  jbe    L95
L88:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  je     L28
  add    $0x1,%ebx
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L95:
  bt     %rdx,%rcx
  jb     L88
  sub    $0x1,%ebx
  sub    $0x1,%rax
  cmp    $0x1,%ebx
  jne    L96
  jmp    L88
  nopl   0x0(%rax)
L55:
  ret
```

assistant: ```c
void trim(char *str) {
  int i = 0, j = 0;
  if (str == 0)
    return;
  if (strlen(str) == 0)
    return;
  while ((str[i] == ' ') || (str[i] == '"'))
    i++;
  if (i != 0) {
    for (j = 0; j < strlen(str) - i; j++) {
      str[j] = str[i + j];
    }
    str[j] = 0;
  }
  i = strlen(str) - 1;
  while ((i > 1) && ((str[i] == ' ') || (str[i] == '"') || (str[i] == 10) || (str[i] == 13)))
    i--;
  if (i != strlen(str) - 1) {
    str[i + 1] = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <get_argument_str@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string
name: unpack_data
arguments: label: D4
data_type: string

tool: 

tool: D4: callback

assistant: ```c
char *get_callback() {
  char *result = "";
  result = get_argument_str("callback");
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_callback>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <get_argument_str@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: callback

assistant: ```c
char *get_callback() {
  char *result = "";
  result = get_argument_str("callback");
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_callback>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <get_argument_str@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D4: callback

assistant: ```c
char *get_callback() {
  char *result = "";
  result = get_argument_str("callback");
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_callback>:
  endbr64
  lea    D8(%rip),%rdi
  jmp    1050 <get_argument_str@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: callback

assistant: ```c
char *get_callback() {
  char *result = "";
  result = get_argument_str("callback");
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<preBmGs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L71
  mov    $0xffffffff,%eax
  jmp    L57
L71:
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <suffixes@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L80
L34:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L80:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L66
L19:
  cmpl   $0xffffffff,-0x10(%rbp)
  je     L129
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  add    $0x1,%edx
  cmp    %edx,%eax
  jne    L1
  jmp    L129
L124:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L96
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  sub    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
L96:
  addl   $0x1,-0xc(%rbp)
L129:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L124
L1:
  subl   $0x1,-0x10(%rbp)
L66:
  cmpl   $0xffffffff,-0x10(%rbp)
  jge    L19
  movl   $0x0,-0x10(%rbp)
  jmp    L32
L98:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x1c(%rbp),%edx
  lea    -0x1(%rdx),%ecx
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    -0x8(%rbp),%rdx
  add    %rsi,%rdx
  mov    (%rdx),%esi
  sub    %esi,%ecx
  mov    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  sub    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L32:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L98
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L57:
  leave
  ret
```

assistant: ```c
int preBmGs(unsigned char *x, int m, int bmGs[]) {
  int *suff, i, j;
  suff = (int *)calloc(sizeof(int), m);
  if (suff == NULL)
    return -1;
  suffixes(x, m, suff);
  for (i = 0; i < m; ++i)
    bmGs[i] = m;
  j = 0;
  for (i = m - 1; i >= -1; --i)
    if (i == -1 || suff[i] == i + 1)
      for (; j < m - 1 - i; ++j)
        if (bmGs[j] == m)
          bmGs[j] = m - 1 - i;
  for (i = 0; i <= m - 2; ++i)
    bmGs[m - 1 - suff[i]] = m - 1 - i;
  free(suff);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<preBmGs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    $0x4,%edi
  call   <calloc@plt>
  test   %rax,%rax
  je     L178
  mov    %rax,%rbp
  mov    %rax,%rdx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <suffixes@plt>
  test   %r12d,%r12d
  jle    L33
  mov    %rbx,%rax
  lea    -0x1(%r12),%edx
  lea    0x4(%rbx,%rdx,4),%rdx
L89:
  mov    %r12d,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L89
  lea    -0x1(%r12),%r8d
L148:
  movslq %r8d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  mov    %r8d,%edx
  mov    $0x0,%edi
  mov    $0x0,%r9d
  mov    $0x0,%r10d
  jmp    L121
L33:
  lea    -0x1(%r12),%r8d
  cmp    $0xffffffff,%r8d
  jl     L101
  jmp    L148
L169:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jle    L161
L166:
  cmp    %r12d,(%rbx,%rax,4)
  jne    L169
  mov    %ecx,(%rbx,%rax,4)
  jmp    L169
L161:
  lea    -0x1(%rdi),%eax
  sub    %r9d,%eax
  cmp    %r9d,%ecx
  cmovle %r10d,%eax
  lea    0x1(%r9,%rax,1),%r9d
L106:
  sub    $0x1,%edx
  sub    $0x4,%rsi
  add    $0x1,%edi
  cmp    $0xffffffff,%edx
  jl     L16
L121:
  cmp    $0xffffffff,%edx
  je     L9
  lea    0x1(%rdx),%eax
  cmp    %eax,(%rsi)
  jne    L106
  mov    %edi,%ecx
  cmp    %r9d,%edi
  jle    L106
L37:
  movslq %r9d,%rax
  jmp    L166
L178:
  mov    $0xffffffff,%eax
  jmp    L125
L9:
  mov    %edi,%ecx
  cmp    %r9d,%edi
  jg     L37
L16:
  test   %r8d,%r8d
  jle    L101
  mov    %rbp,%rcx
  mov    %r8d,%eax
L167:
  mov    %r8d,%edx
  sub    (%rcx),%edx
  movslq %edx,%rdx
  mov    %eax,(%rbx,%rdx,4)
  add    $0x4,%rcx
  sub    $0x1,%eax
  jne    L167
L101:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L125:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int preBmGs(unsigned char *x, int m, int bmGs[]) {
  int *suff, i, j;
  suff = (int *)calloc(sizeof(int), m);
  if (suff == NULL)
    return -1;
  suffixes(x, m, suff);
  for (i = 0; i < m; ++i)
    bmGs[i] = m;
  j = 0;
  for (i = m - 1; i >= -1; --i)
    if (i == -1 || suff[i] == i + 1)
      for (; j < m - 1 - i; ++j)
        if (bmGs[j] == m)
          bmGs[j] = m - 1 - i;
  for (i = 0; i <= m - 2; ++i)
    bmGs[m - 1 - suff[i]] = m - 1 - i;
  free(suff);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<preBmGs>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x4,%edi
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <suffixes@plt>
  lea    -0x1(%rbp),%r8d
  test   %ebp,%ebp
  jle    L8
  mov    %r8d,%edx
  mov    %rbx,%rax
  lea    0x4(%rbx,%rdx,4),%rdx
L31:
  mov    %ebp,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L31
L95:
  movslq %r8d,%rax
  mov    %r8d,%edx
  xor    %edi,%edi
  xor    %r9d,%r9d
  lea    (%r12,%rax,4),%rsi
  xor    %r10d,%r10d
  jmp    L54
  nop
L70:
  sub    $0x1,%edx
  add    $0x1,%rdi
  sub    $0x4,%rsi
  cmp    $0xfffffffe,%edx
  je     L19
L54:
  cmp    $0xffffffff,%edx
  je     L141
  lea    0x1(%rdx),%eax
  cmp    %eax,(%rsi)
  jne    L70
  mov    %edi,%ecx
  cmp    %edi,%r9d
  jge    L70
L23:
  movslq %r9d,%rax
  nopw   0x0(%rax,%rax,1)
L169:
  cmp    %ebp,(%rbx,%rax,4)
  jne    L37
  mov    %ecx,(%rbx,%rax,4)
L37:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L169
  mov    %edi,%eax
  sub    %r9d,%eax
  sub    $0x1,%eax
  cmp    %r9d,%ecx
  cmovle %r10d,%eax
  sub    $0x1,%edx
  add    $0x1,%rdi
  sub    $0x4,%rsi
  lea    0x1(%r9,%rax,1),%r9d
  cmp    $0xfffffffe,%edx
  jne    L54
  nopl   0x0(%rax)
L19:
  test   %r8d,%r8d
  jle    L108
  mov    %r12,%rcx
  mov    %r8d,%eax
  nopl   0x0(%rax,%rax,1)
L160:
  mov    %r8d,%edx
  sub    (%rcx),%edx
  add    $0x4,%rcx
  movslq %edx,%rdx
  mov    %eax,(%rbx,%rdx,4)
  sub    $0x1,%eax
  jne    L160
L108:
  mov    %r12,%rdi
  call   <free@plt>
  xor    %eax,%eax
L158:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L141:
  mov    %edi,%ecx
  cmp    %edi,%r9d
  jl     L23
  jmp    L19
L8:
  cmp    $0xffffffff,%r8d
  jl     L108
  jmp    L95
L7:
  mov    $0xffffffff,%eax
  jmp    L158
```

assistant: ```c
int preBmGs(unsigned char *x, int m, int bmGs[]) {
  int *suff, i, j;
  suff = (int *)calloc(sizeof(int), m);
  if (suff == NULL)
    return -1;
  suffixes(x, m, suff);
  for (i = 0; i < m; ++i)
    bmGs[i] = m;
  j = 0;
  for (i = m - 1; i >= -1; --i)
    if (i == -1 || suff[i] == i + 1)
      for (; j < m - 1 - i; ++j)
        if (bmGs[j] == m)
          bmGs[j] = m - 1 - i;
  for (i = 0; i <= m - 2; ++i)
    bmGs[m - 1 - suff[i]] = m - 1 - i;
  free(suff);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<preBmGs>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x4,%edi
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %rax,%rax
  je     L79
  mov    %rax,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <suffixes@plt>
  lea    -0x1(%rbp),%r8d
  test   %ebp,%ebp
  jle    L194
  cmp    $0x2,%r8d
  jbe    L86
  mov    %ebp,%edx
  movd   %ebp,%xmm1
  mov    %rbx,%rax
  shr    $0x2,%edx
  pshufd $0x0,%xmm1,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rbx,%rdx,1),%rdx
  nopl   0x0(%rax)
L169:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L169
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bpl
  je     L7
L23:
  movslq %eax,%rdx
  mov    %ebp,(%rbx,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L7
  add    $0x2,%eax
  mov    %ebp,0x4(%rbx,%rcx,1)
  cmp    %eax,%ebp
  jle    L7
  mov    %ebp,0x8(%rbx,%rcx,1)
L7:
  movslq %r8d,%rax
  mov    %r8d,%edx
  xor    %edi,%edi
  xor    %r9d,%r9d
  lea    (%r12,%rax,4),%rsi
  xor    %r10d,%r10d
  jmp    L107
  nop
L87:
  sub    $0x1,%edx
  add    $0x1,%rdi
  sub    $0x4,%rsi
  cmp    $0xfffffffe,%edx
  je     L32
L107:
  cmp    $0xffffffff,%edx
  je     L1
  lea    0x1(%rdx),%eax
  cmp    %eax,(%rsi)
  jne    L87
  mov    %edi,%ecx
  cmp    %edi,%r9d
  jge    L87
L135:
  movslq %r9d,%rax
  nopw   0x0(%rax,%rax,1)
L51:
  cmp    %ebp,(%rbx,%rax,4)
  jne    L132
  mov    %ecx,(%rbx,%rax,4)
L132:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L51
  mov    %edi,%eax
  sub    %r9d,%eax
  sub    $0x1,%eax
  cmp    %r9d,%ecx
  cmovle %r10d,%eax
  sub    $0x1,%edx
  add    $0x1,%rdi
  sub    $0x4,%rsi
  lea    0x1(%r9,%rax,1),%r9d
  cmp    $0xfffffffe,%edx
  jne    L107
  nopl   0x0(%rax)
L32:
  test   %r8d,%r8d
  jle    L112
  mov    %r12,%rcx
  mov    %r8d,%eax
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %r8d,%edx
  sub    (%rcx),%edx
  add    $0x4,%rcx
  movslq %edx,%rdx
  mov    %eax,(%rbx,%rdx,4)
  sub    $0x1,%eax
  jne    L68
L112:
  mov    %r12,%rdi
  call   <free@plt>
  xor    %eax,%eax
L77:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  mov    %edi,%ecx
  cmp    %edi,%r9d
  jl     L135
  jmp    L32
L194:
  cmp    $0xffffffff,%r8d
  jl     L112
  jmp    L7
L86:
  xor    %eax,%eax
  jmp    L23
L79:
  mov    $0xffffffff,%eax
  jmp    L77
```

assistant: ```c
int preBmGs(unsigned char *x, int m, int bmGs[]) {
  int *suff, i, j;
  suff = (int *)calloc(sizeof(int), m);
  if (suff == NULL)
    return -1;
  suffixes(x, m, suff);
  for (i = 0; i < m; ++i)
    bmGs[i] = m;
  j = 0;
  for (i = m - 1; i >= -1; --i)
    if (i == -1 || suff[i] == i + 1)
      for (; j < m - 1 - i; ++j)
        if (bmGs[j] == m)
          bmGs[j] = m - 1 - i;
  for (i = 0; i <= m - 2; ++i)
    bmGs[m - 1 - suff[i]] = m - 1 - i;
  free(suff);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_factor>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%r9
  mov    %rdx,%r8
  movq   $0x0,(%rdx)
  test   $0x1,%dil
  jne    L57
L50:
  mov    (%r8),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r8)
  movq   $0x2,(%r9,%rax,8)
  mov    %rcx,%rax
  shr    $0x3f,%rax
  add    %rcx,%rax
  sar    %rax
  mov    %rax,%rcx
  test   $0x1,%al
  je     L50
L57:
  movabs $0x5555555555555556,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,2),%rax
  cmp    %rax,%rcx
  jne    L13
  movabs $0x5555555555555556,%rdi
L34:
  mov    (%r8),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r8)
  movq   $0x3,(%r9,%rax,8)
  mov    %rcx,%rax
  imul   %rdi
  sar    $0x3f,%rcx
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  mov    %rsi,%rcx
  mov    %rsi,%rax
  imul   %rdi
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,2),%rax
  cmp    %rax,%rsi
  je     L34
L13:
  mov    $0x5,%edi
  jmp    L19
L67:
  add    $0x6,%rdi
  imul   %rsi,%rsi
  cmp    %rcx,%rsi
  jg     L70
L19:
  mov    %rdi,%rsi
  mov    %rcx,%rax
  cqto
  idiv   %rdi
  test   %rdx,%rdx
  jne    L18
  mov    (%r8),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r8)
  mov    %rdi,(%r9,%rax,8)
  mov    %rcx,%rax
  cqto
  idiv   %rdi
  mov    %rax,%rcx
L18:
  imul   %rsi,%rsi
  cmp    %rcx,%rsi
  jg     L70
  lea    0x2(%rdi),%rsi
  mov    %rcx,%rax
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L67
  mov    (%r8),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r8)
  mov    %rsi,(%r9,%rax,8)
  mov    %rcx,%rax
  cqto
  idiv   %rsi
  mov    %rax,%rcx
  jmp    L67
L70:
  mov    (%r8),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r8)
  mov    %rcx,(%r9,%rax,8)
  ret
```

assistant: ```c
void int_factor(long n, long *divisors, long *nd) {
  long p, k, kmax;
  *nd = 0;
  while (n % 2 == 0) {
    divisors[(*nd)++] = 2;
    n /= 2;
  }
  while (n % 3 == 0) {
    divisors[(*nd)++] = 3;
    n /= 3;
  }
  for (k = 1;; k++) {
    p = 6 * k - 1;
    if (n % p == 0) {
      divisors[(*nd)++] = p;
      n /= p;
    }
    if (p * p > n)
      break;
    p = 6 * k + 1;
    if (n % p == 0) {
      divisors[(*nd)++] = p;
      n /= p;
    }
    if (p * p > n)
      break;
  }
  divisors[(*nd)++] = n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<int_factor>:
  endbr64
  mov    %rdi,%rcx
  and    $0x1,%edi
  push   %rbx
  mov    %rsi,%r10
  movq   $0x0,(%rdx)
  mov    %rdx,%r8
  jne    L85
  xor    %eax,%eax
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L41:
  mov    (%r8),%rax
L35:
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r8)
  movq   $0x2,(%r10,%rax,8)
  mov    %rcx,%rax
  shr    $0x3f,%rax
  add    %rcx,%rax
  mov    %rax,%rcx
  sar    %rcx
  test   $0x2,%al
  je     L41
  mov    (%r8),%r9
L11:
  movabs $0xaaaaaaaaaaaaaaab,%rsi
  mov    %rcx,%rax
  movabs $0x2aaaaaaaaaaaaaaa,%rdi
  movabs $0x5555555555555554,%r11
  imul   %rsi,%rax
  add    %rdi,%rax
  cmp    %r11,%rax
  ja     L86
  movabs $0x5555555555555556,%rbx
  nopl   0x0(%rax,%rax,1)
L104:
  lea    0x1(%r9),%rax
  mov    %rax,(%r8)
  mov    %rcx,%rax
  imul   %rbx
  mov    %rcx,%rax
  movq   $0x3,(%r10,%r9,8)
  mov    (%r8),%r9
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rax
  mov    %rdx,%rcx
  imul   %rsi,%rax
  add    %rdi,%rax
  cmp    %r11,%rax
  jbe    L104
L86:
  mov    $0x5,%esi
  jmp    L90
  nopl   0x0(%rax,%rax,1)
L89:
  mov    %rcx,%rax
  lea    0x2(%rsi),%rdi
  cqto
  idiv   %rdi
  test   %rdx,%rdx
  jne    L93
  lea    0x1(%r9),%rdx
  mov    %rax,%rcx
  mov    %rdx,(%r8)
  mov    %rdi,(%r10,%r9,8)
  mov    (%r8),%r9
L93:
  imul   %rdi,%rdi
  add    $0x6,%rsi
  cmp    %rcx,%rdi
  jg     L76
L90:
  mov    %rcx,%rax
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L97
  lea    0x1(%r9),%rdx
  mov    %rax,%rcx
  mov    %rdx,(%r8)
  mov    %rsi,(%r10,%r9,8)
  mov    (%r8),%r9
L97:
  mov    %rsi,%rax
  imul   %rsi,%rax
  cmp    %rcx,%rax
  jle    L89
L76:
  lea    0x1(%r9),%rax
  pop    %rbx
  mov    %rax,(%r8)
  mov    %rcx,(%r10,%r9,8)
  ret
  cs nopw 0x0(%rax,%rax,1)
L85:
  xor    %r9d,%r9d
  jmp    L11
```

assistant: ```c
void int_factor(long n, long *divisors, long *nd) {
  long p, k, kmax;
  *nd = 0;
  while (n % 2 == 0) {
    divisors[(*nd)++] = 2;
    n /= 2;
  }
  while (n % 3 == 0) {
    divisors[(*nd)++] = 3;
    n /= 3;
  }
  for (k = 1;; k++) {
    p = 6 * k - 1;
    if (n % p == 0) {
      divisors[(*nd)++] = p;
      n /= p;
    }
    if (p * p > n)
      break;
    p = 6 * k + 1;
    if (n % p == 0) {
      divisors[(*nd)++] = p;
      n /= p;
    }
    if (p * p > n)
      break;
  }
  divisors[(*nd)++] = n;
}
```