ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x2c(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fastint@plt>
  mov    $0xf4241,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x7d4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L82
L25:
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <faststring@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x31(%rbp)
  jmp    L9
L14:
  cmpb   $0x3c,-0x31(%rbp)
  jne    L5
  cmpl   $0x7a120,-0x24(%rbp)
  jg     L89
  addl   $0x1,-0x28(%rbp)
  addl   $0x1,-0x24(%rbp)
  jmp    L124
L5:
  addl   $0x1,-0x28(%rbp)
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L102
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L124
L102:
  cmpl   $0x0,-0x24(%rbp)
  js     L35
L124:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x31(%rbp)
L9:
  cmpb   $0x0,-0x31(%rbp)
  jne    L14
  jmp    L67
L89:
  nop
  jmp    L67
L35:
  nop
L67:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
L82:
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  test   %eax,%eax
  jne    L25
  lea    -0x2c(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printresult@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L91
  call   <__stack_chk_fail@plt>
L91:
  leave
  ret
```

assistant: ```c
int main() {
  int tc, depth, result, T;
  char *arr;
  char c;
  int i = 0, *res, z = 0;
  fastint(&T);
  arr = (char *)malloc(1000001 * sizeof(char));
  res = (int *)malloc(501 * sizeof(int));
  while (T--) {
    tc = 0, depth = 0, result = 0, i = 0;
    faststring(arr);
    c = arr[i];
    for (; c;) {
      if (c == 60) {
        if (depth < 500001) {
          tc++;
          depth++;
        } else
          break;
      } else {
        tc++;
        depth--;
        if (depth == 0)
          result = tc;
        else if (depth < 0)
          break;
      }
      i++;
      c = arr[i];
    }
    res[z] = result;
    z++;
  }
  printresult(res, &z);
  free(arr);
  free(res);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  mov    %rsp,%rdi
  call   <fastint@plt>
  mov    $0xf4241,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x7d4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L55
  mov    $0x0,%r12d
  jmp    L41
L34:
  cmp    $0x7a120,%eax
  jg     L125
  add    $0x1,%eax
  jmp    L88
L59:
  mov    %edx,%esi
L88:
  add    $0x1,%rdx
  movzbl -0x1(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  je     L125
L48:
  cmp    $0x3c,%cl
  je     L34
  sub    $0x1,%eax
  je     L59
  test   %eax,%eax
  jns    L88
L125:
  mov    0x4(%rsp),%eax
  movslq %eax,%rdx
  mov    %esi,0x0(%rbp,%rdx,4)
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L55
L41:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <faststring@plt>
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L105
  mov    $0x1,%edx
  mov    %r12d,%esi
  mov    $0x0,%eax
  jmp    L48
L105:
  mov    %r12d,%esi
  jmp    L125
L55:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printresult@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int tc, depth, result, T;
  char *arr;
  char c;
  int i = 0, *res, z = 0;
  fastint(&T);
  arr = (char *)malloc(1000001 * sizeof(char));
  res = (int *)malloc(501 * sizeof(int));
  while (T--) {
    tc = 0, depth = 0, result = 0, i = 0;
    faststring(arr);
    c = arr[i];
    for (; c;) {
      if (c == 60) {
        if (depth < 500001) {
          tc++;
          depth++;
        } else
          break;
      } else {
        tc++;
        depth--;
        if (depth == 0)
          result = tc;
        else if (depth < 0)
          break;
      }
      i++;
      c = arr[i];
    }
    res[z] = result;
    z++;
  }
  printresult(res, &z);
  free(arr);
  free(res);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x0,0x4(%rsp)
  call   <fastint@plt>
  mov    $0xf4241,%edi
  call   <malloc@plt>
  mov    $0x7d4,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%r12
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L5
  cs nopw 0x0(%rax,%rax,1)
L129:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <faststring@plt>
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L73
  mov    $0x1,%eax
  xor    %esi,%esi
  xor    %ecx,%ecx
  jmp    L111
  nopl   0x0(%rax)
L35:
  sub    $0x1,%ecx
  je     L53
  js     L8
L0:
  movslq %eax,%rdx
  add    $0x1,%eax
  movzbl 0x0(%rbp,%rdx,1),%edx
  test   %dl,%dl
  je     L8
L111:
  cmp    $0x3c,%dl
  jne    L35
  cmp    $0x7a120,%ecx
  jg     L8
  movslq %eax,%rdx
  add    $0x1,%ecx
  add    $0x1,%eax
  movzbl 0x0(%rbp,%rdx,1),%edx
  test   %dl,%dl
  jne    L111
  nopl   0x0(%rax)
L8:
  movslq 0x4(%rsp),%rdx
  mov    %rdx,%rax
  mov    %esi,(%r12,%rdx,4)
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L129
L5:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printresult@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L53:
  mov    %eax,%esi
  jmp    L0
L73:
  xor    %esi,%esi
  jmp    L8
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int tc, depth, result, T;
  char *arr;
  char c;
  int i = 0, *res, z = 0;
  fastint(&T);
  arr = (char *)malloc(1000001 * sizeof(char));
  res = (int *)malloc(501 * sizeof(int));
  while (T--) {
    tc = 0, depth = 0, result = 0, i = 0;
    faststring(arr);
    c = arr[i];
    for (; c;) {
      if (c == 60) {
        if (depth < 500001) {
          tc++;
          depth++;
        } else
          break;
      } else {
        tc++;
        depth--;
        if (depth == 0)
          result = tc;
        else if (depth < 0)
          break;
      }
      i++;
      c = arr[i];
    }
    res[z] = result;
    z++;
  }
  printresult(res, &z);
  free(arr);
  free(res);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x0,0x4(%rsp)
  call   <fastint@plt>
  mov    $0xf4241,%edi
  call   <malloc@plt>
  mov    $0x7d4,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%r12
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L55
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <faststring@plt>
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L79
  mov    $0x1,%eax
  xor    %esi,%esi
  xor    %ecx,%ecx
  jmp    L128
  nopl   0x0(%rax)
L32:
  sub    $0x1,%ecx
  je     L2
  js     L38
L124:
  movslq %eax,%rdx
  add    $0x1,%eax
  movzbl 0x0(%rbp,%rdx,1),%edx
  test   %dl,%dl
  je     L38
L128:
  cmp    $0x3c,%dl
  jne    L32
  cmp    $0x7a120,%ecx
  jg     L38
  movslq %eax,%rdx
  add    $0x1,%ecx
  add    $0x1,%eax
  movzbl 0x0(%rbp,%rdx,1),%edx
  test   %dl,%dl
  jne    L128
  nopl   0x0(%rax)
L38:
  movslq 0x4(%rsp),%rdx
  mov    %rdx,%rax
  mov    %esi,(%r12,%rdx,4)
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L16
L55:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printresult@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L100
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L2:
  mov    %eax,%esi
  jmp    L124
L79:
  xor    %esi,%esi
  jmp    L38
L100:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int tc, depth, result, T;
  char *arr;
  char c;
  int i = 0, *res, z = 0;
  fastint(&T);
  arr = (char *)malloc(1000001 * sizeof(char));
  res = (int *)malloc(501 * sizeof(int));
  while (T--) {
    tc = 0, depth = 0, result = 0, i = 0;
    faststring(arr);
    c = arr[i];
    for (; c;) {
      if (c == 60) {
        if (depth < 500001) {
          tc++;
          depth++;
        } else
          break;
      } else {
        tc++;
        depth--;
        if (depth == 0)
          result = tc;
        else if (depth < 0)
          break;
      }
      i++;
      c = arr[i];
    }
    res[z] = result;
    z++;
  }
  printresult(res, &z);
  free(arr);
  free(res);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i2c_read_beint32_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  imul   -0x50(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x3c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%eax
  cltq
  imul   -0x50(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%esi
  mov    -0x34(%rbp),%eax
  mov    %rcx,%r8
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <i2c_transact@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%eax
  cltq
  imul   -0x50(%rbp),%rax
  cmp    %rax,%rdx
  jne    L27
  movl   $0x0,-0x2c(%rbp)
  jmp    L35
L43:
  mov    -0x2c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x48(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <__rbeu32@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x2c(%rbp)
L35:
  mov    -0x2c(%rbp),%eax
  cltq
  cmp    %rax,-0x50(%rbp)
  ja     L43
  mov    -0x50(%rbp),%rax
  jmp    L28
L27:
  mov    -0x24(%rbp),%eax
L28:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int i2c_read_beint32_array(int fd, int chip_addr, int reg, int32_t *values, size_t count) {
  int sz = sizeof(uint32_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, count * sz);
  if (err == (count * sz)) {
    for (int i = 0; i < count; i++)
      values[i] = (uint32_t)__rbeu32(&data[i * sz]);
    return count;
  }
  return err;
}
```
user: What is the c source code of the assembly code below?

```asm
<i2c_read_beint32_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %edx,%r15d
  mov    %rcx,%r13
  mov    %r8,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x0(,%r8,8),%r14
  lea    0x1(%r14),%rdi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    %r15d,(%rax)
  mov    %r14,%r8
  mov    $0x1,%ecx
  mov    %rax,%rdx
  mov    -0x48(%rbp),%esi
  mov    -0x44(%rbp),%edi
  call   <i2c_transact@plt>
  movslq %eax,%rdx
  cmp    %rdx,%r14
  je     L49
L27:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L49:
  test   %r12,%r12
  je     L34
  mov    $0x0,%r14d
L36:
  mov    %rbx,%rdi
  call   <__rbeu32@plt>
  mov    %rax,0x0(%r13,%r14,8)
  add    $0x1,%r14
  add    $0x20,%rbx
  cmp    %r12,%r14
  jne    L36
L34:
  mov    %r12d,%eax
  jmp    L27
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_beint32_array(int fd, int chip_addr, int reg, int32_t *values, size_t count) {
  int sz = sizeof(uint32_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, count * sz);
  if (err == (count * sz)) {
    for (int i = 0; i < count; i++)
      values[i] = (uint32_t)__rbeu32(&data[i * sz]);
    return count;
  }
  return err;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<i2c_read_beint32_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  lea    0x0(,%r8,8),%r12
  push   %rbx
  lea    0x1(%r12),%rdi
  sub    $0x28,%rsp
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    -0x44(%rbp),%edx
  mov    -0x48(%rbp),%esi
  mov    %r12,%r8
  mov    $0x1,%ecx
  mov    %r15d,%edi
  mov    %rax,%rbx
  mov    %edx,(%rax)
  mov    %rax,%rdx
  call   <i2c_transact@plt>
  movslq %eax,%rdx
  cmp    %rdx,%r12
  je     L48
L41:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  test   %r13,%r13
  je     L27
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  add    $0x20,%rbx
  call   <__rbeu32@plt>
  mov    %rax,(%r14,%r12,8)
  add    $0x1,%r12
  cmp    %r12,%r13
  jne    L3
L27:
  mov    %r13d,%eax
  jmp    L41
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_beint32_array(int fd, int chip_addr, int reg, int32_t *values, size_t count) {
  int sz = sizeof(uint32_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, count * sz);
  if (err == (count * sz)) {
    for (int i = 0; i < count; i++)
      values[i] = (uint32_t)__rbeu32(&data[i * sz]);
    return count;
  }
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i2c_read_beint32_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  lea    0x0(,%r8,8),%r12
  push   %rbx
  lea    0x1(%r12),%rdi
  sub    $0x28,%rsp
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    -0x44(%rbp),%edx
  mov    -0x48(%rbp),%esi
  mov    %r12,%r8
  mov    $0x1,%ecx
  mov    %r15d,%edi
  mov    %rax,%rbx
  mov    %edx,(%rax)
  mov    %rax,%rdx
  call   <i2c_transact@plt>
  movslq %eax,%rdx
  cmp    %rdx,%r12
  je     L25
L12:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L25:
  test   %r13,%r13
  je     L23
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  add    $0x20,%rbx
  call   <__rbeu32@plt>
  mov    %rax,(%r14,%r12,8)
  add    $0x1,%r12
  cmp    %r12,%r13
  jne    L8
L23:
  mov    %r13d,%eax
  jmp    L12
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_beint32_array(int fd, int chip_addr, int reg, int32_t *values, size_t count) {
  int sz = sizeof(uint32_t);
  uint8_t *data = (uint8_t *)alloca(count * sz + 1);
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, count * sz);
  if (err == (count * sz)) {
    for (int i = 0; i < count; i++)
      values[i] = (uint32_t)__rbeu32(&data[i * sz]);
    return count;
  }
  return err;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<debug_location>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L31
  addq   $0x1,-0x8(%rbp)
  jmp    L3
L31:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L3:
  cmpq   $0x0,-0x28(%rbp)
  je     L21
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r9
  mov    %edx,%r8d
  mov    %rax,%rcx
  lea    D4(%rip),%rax
  mov    %rax,%rdx
  mov    $0x400,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  jmp    L11
L21:
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%r8d
  mov    %rax,%rcx
  lea    D13(%rip),%rax
  mov    %rax,%rdx
  mov    $0x400,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
L11:
  lea    D49(%rip),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string

tool: D4: %s:%d:%s()

tool: D13: %s:%d

assistant: ```c
const char *debug_location(file, line, func) const char *file;
int line;
const char *func;
{
  static char buf[1024];
  const char *p;
  p = strrchr(file, '/');
  if (p)
    p++;
  else
    p = file;
  if (func)
    snprintf(buf, sizeof(buf), "%s:%d:%s()", p, line, func);
  else
    snprintf(buf, sizeof(buf), "%s:%d", p, line);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<debug_location>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  test   %rbp,%rbp
  je     L5
  mov    %rbp,%r9
  mov    %r12d,%r8d
  mov    %rbx,%rcx
  lea    D26(%rip),%rdx
  mov    $0x400,%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
L0:
  lea    D39(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    %r12d,%r8d
  mov    %rbx,%rcx
  lea    D15(%rip),%rdx
  mov    $0x400,%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: label: D26
type: string
name: unpack_data
arguments: label: D15
type: string

tool: D26: %s:%d:%s()

tool: D15: %s:%d

assistant: ```c
const char *debug_location(file, line, func) const char *file;
int line;
const char *func;
{
  static char buf[1024];
  const char *p;
  p = strrchr(file, '/');
  if (p)
    p++;
  else
    p = file;
  if (func)
    snprintf(buf, sizeof(buf), "%s:%d:%s()", p, line, func);
  else
    snprintf(buf, sizeof(buf), "%s:%d", p, line);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<debug_location>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0x2f,%esi
  push   %rbx
  mov    %rdx,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  test   %rbx,%rbx
  je     L1
  mov    %r12,%rcx
  lea    D8(%rip),%r12
  xor    %eax,%eax
  mov    %rbx,%r9
  mov    %ebp,%r8d
  mov    %r12,%rdi
  mov    $0x400,%esi
  lea    D30(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rcx
  lea    D8(%rip),%r12
  mov    %ebp,%r8d
  xor    %eax,%eax
  mov    %r12,%rdi
  lea    D4(%rip),%rdx
  mov    $0x400,%esi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D30
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: string

tool: D30: %s:%d:%s()

tool: D4: %s:%d

assistant: ```c
const char *debug_location(file, line, func) const char *file;
int line;
const char *func;
{
  static char buf[1024];
  const char *p;
  p = strrchr(file, '/');
  if (p)
    p++;
  else
    p = file;
  if (func)
    snprintf(buf, sizeof(buf), "%s:%d:%s()", p, line, func);
  else
    snprintf(buf, sizeof(buf), "%s:%d", p, line);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<debug_location>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0x2f,%esi
  push   %rbx
  mov    %rdx,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  test   %rbx,%rbx
  je     L0
  mov    %r12,%rcx
  lea    D38(%rip),%r12
  xor    %eax,%eax
  mov    %rbx,%r9
  mov    %ebp,%r8d
  mov    %r12,%rdi
  mov    $0x400,%esi
  lea    D39(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rcx
  lea    D38(%rip),%r12
  mov    %ebp,%r8d
  xor    %eax,%eax
  mov    %r12,%rdi
  lea    D16(%rip),%rdx
  mov    $0x400,%esi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_infered: string
name: unpack_data
arguments: data_label: D16
type_infered: string

tool: D39: %s:%d:%s()

tool: D16: %s:%d

assistant: ```c
const char *debug_location(file, line, func) const char *file;
int line;
const char *func;
{
  static char buf[1024];
  const char *p;
  p = strrchr(file, '/');
  if (p)
    p++;
  else
    p = file;
  if (func)
    snprintf(buf, sizeof(buf), "%s:%d:%s()", p, line, func);
  else
    snprintf(buf, sizeof(buf), "%s:%d", p, line);
  return buf;
}
```