ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%edi
  jle    L29
  mov    0x8(%rsi),%rdi
  lea    D40(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L26
L29:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    (%rbx),%rsi
  add    $0x28,%rsp
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1110 <printf@plt>
L26:
  mov    0x18(%rbx),%rdi
  lea    D9(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
  mov    0x10(%rbx),%rsi
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x20(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L59
  xor    %eax,%eax
  call   <init_daemon@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <process@plt>
  jmp    L2
L59:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D40
data_type: string
name: parse_data
arguments: data_label: D29
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D3
data_type: string

tool: D40: -q

tool: D29: You should run program like:

tool: D15: %s -q queuename -t timespersec


tool: D9: -t

tool: D3: The -t(times per second) must be an int number & > 0

assistant: ```c
int main(int argc, char **argv) {
  char queuename[20];
  int loop;
  if (argc <= 4 || strcmp(argv[1], "-q") != 0 || strcmp(argv[3], "-t") != 0) {
    printf("You should run program like:\n");
    printf("%s -q queuename -t timespersec\n", argv[0]);
    return;
  }
  strcpy(queuename, argv[2]);
  loop = atoi(argv[4]);
  if (loop < 1) {
    printf("The -t(times per second) must be an int number & > 0\n");
    return;
  }
  init_daemon();
  while (1) {
    sleep(1);
    process(queuename, loop);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%edi
  jle    L12
  mov    0x8(%rsi),%rdi
  lea    D2(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L28
L12:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    (%rbx),%rsi
  add    $0x28,%rsp
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1110 <printf@plt>
L28:
  mov    0x18(%rbx),%rdi
  lea    D30(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  mov    0x10(%rbx),%rsi
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x20(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L26
  xor    %eax,%eax
  call   <init_daemon@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <process@plt>
  jmp    L17
L26:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D38
type_guessed: string
name: read_data
arguments: data_tag: D49
type_guessed: string
name: read_data
arguments: data_tag: D30
type_guessed: string
name: read_data
arguments: data_tag: D19
type_guessed: string

tool: D2: -q

tool: D38: You should run program like:

tool: D49: %s -q queuename -t timespersec


tool: D30: -t

tool: D19: The -t(times per second) must be an int number & > 0

assistant: ```c
int main(int argc, char **argv) {
  char queuename[20];
  int loop;
  if (argc <= 4 || strcmp(argv[1], "-q") != 0 || strcmp(argv[3], "-t") != 0) {
    printf("You should run program like:\n");
    printf("%s -q queuename -t timespersec\n", argv[0]);
    return;
  }
  strcpy(queuename, argv[2]);
  loop = atoi(argv[4]);
  if (loop < 1) {
    printf("The -t(times per second) must be an int number & > 0\n");
    return;
  }
  init_daemon();
  while (1) {
    sleep(1);
    process(queuename, loop);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<count_freq>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L78:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L78
  sub    $0x38,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,%r15
  mov    %edx,%r14d
  mov    %ecx,0x1c(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x4028(%rsp)
  xor    %eax,%eax
  sub    %edx,%ecx
  mov    %ecx,%r12d
  test   %ecx,%ecx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x20(%rsp),%rbp
  lea    0x4020(%rsp),%r13
  mov    %rbp,%rax
L65:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %r13,%rax
  jne    L65
  mov    $0x20000,%ebx
  jmp    L83
L22:
  sub    %r14d,%eax
  shl    $0xc,%eax
  cltd
  idiv   %r12d
  cltq
  addl   $0x1,0x20(%rsp,%rax,4)
L49:
  sub    $0x1,%ebx
  je     L76
L83:
  mov    0x4070(%rsp),%edx
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   *%r15
  cmp    %eax,%r14d
  jg     L49
  cmp    %eax,0x1c(%rsp)
  jge    L22
  jmp    L49
L76:
  pxor   %xmm3,%xmm3
  cvtsi2sd %r14d,%xmm3
  movsd  %xmm3,0x8(%rsp)
  lea    D27(%rip),%r14
L7:
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x0(%rbp),%xmm0
  mulsd  D8(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  mulsd  D28(%rip),%xmm1
  addsd  0x8(%rsp),%xmm1
  cvttsd2si %xmm1,%edx
  mov    %r14,%rsi
  mov    (%rsp),%rdi
  call   <fprintf@plt>
  add    $0x4,%rbp
  add    %r12d,%ebx
  cmp    %r13,%rbp
  jne    L7
  mov    0x4028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x4038,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type: string
name: extract_symbolic_data
arguments: tag: D8
type: f32[2]
name: extract_symbolic_data
arguments: tag: D28
type: f32[2]

tool: D27: %.12f %.12f


tool: {"D8": [0.0,0.4375]}

tool: {"D28": [0.0,0.6875]}

assistant: ```c
void count_freq(FILE *fout, int (*pdist)(double *, int *, int), int lcutoff, int rcutoff, double *prob_accum, int *energy, int nsample) {
  int i;
  int freq[(1 << 12)];
  int rand_nr;
  int range = rcutoff - lcutoff;
  assert(range > 0);
  srand(time(NULL));
  for (i = 0; i < (1 << 12); i++)
    freq[i] = 0.0;
  for (i = 0; i < (1 << 17); i++) {
    rand_nr = pdist(prob_accum, energy, nsample);
    if ((rand_nr < lcutoff) || (rand_nr > rcutoff))
      continue;
    freq[(rand_nr - lcutoff) * (1 << 12) / range]++;
  }
  for (i = 0; i < (1 << 12); i++) {
    fprintf(fout, "%.12f %.12f\n", lcutoff + (double)(range * i) / (double)(1 << 12), ((double)freq[i] / (double)(1 << 17)));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count_freq>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L39:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L39
  sub    $0x38,%rsp
  mov    $0x20000,%ebx
  mov    0x4070(%rsp),%r15d
  mov    %rsi,0x8(%rsp)
  mov    %rdi,%r12
  xor    %edi,%edi
  mov    %edx,%ebp
  mov    %ecx,0x14(%rsp)
  sub    %edx,%ecx
  mov    %r8,%r14
  mov    %r9,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x4028(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  mov    %ecx,0x10(%rsp)
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x4000,%edx
  xor    %esi,%esi
  mov    %rdi,0x18(%rsp)
  call   <memset@plt>
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    0x8(%rsp),%rax
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   *%rax
  cmp    %eax,%ebp
  jg     L38
  cmp    %eax,0x14(%rsp)
  jl     L38
  sub    %ebp,%eax
  shl    $0xc,%eax
  cltd
  idivl  0x10(%rsp)
  cltq
  addl   $0x1,0x20(%rsp,%rax,4)
L38:
  sub    $0x1,%ebx
  jne    L26
  pxor   %xmm3,%xmm3
  mov    0x18(%rsp),%r14
  lea    0x4020(%rsp),%r13
  cvtsi2sd %ebp,%xmm3
  lea    D6(%rip),%rbp
  movsd  %xmm3,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L58:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rsi
  mov    %r12,%rdi
  cvtsi2sd %ebx,%xmm1
  mulsd  D13(%rip),%xmm1
  add    $0x4,%r14
  cvtsi2sdl -0x4(%r14),%xmm0
  addsd  0x8(%rsp),%xmm1
  mulsd  D3(%rip),%xmm0
  cvttsd2si %xmm1,%edx
  call   <fprintf@plt>
  add    0x10(%rsp),%ebx
  cmp    %r14,%r13
  jne    L58
  mov    0x4028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x4038,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string
name: extract_symbolic_data
arguments: label: D13
type: f32[2]
name: extract_symbolic_data
arguments: label: D3
type: f32[2]

tool: D6: %.12f %.12f


tool: {"D13": [0.0,0.6875]}

tool: {"D3": [0.0,0.4375]}

assistant: ```c
void count_freq(FILE *fout, int (*pdist)(double *, int *, int), int lcutoff, int rcutoff, double *prob_accum, int *energy, int nsample) {
  int i;
  int freq[(1 << 12)];
  int rand_nr;
  int range = rcutoff - lcutoff;
  assert(range > 0);
  srand(time(NULL));
  for (i = 0; i < (1 << 12); i++)
    freq[i] = 0.0;
  for (i = 0; i < (1 << 17); i++) {
    rand_nr = pdist(prob_accum, energy, nsample);
    if ((rand_nr < lcutoff) || (rand_nr > rcutoff))
      continue;
    freq[(rand_nr - lcutoff) * (1 << 12) / range]++;
  }
  for (i = 0; i < (1 << 12); i++) {
    fprintf(fout, "%.12f %.12f\n", lcutoff + (double)(range * i) / (double)(1 << 12), ((double)freq[i] / (double)(1 << 17)));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_freq>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L58:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L58
  sub    $0x38,%rsp
  mov    $0x20000,%ebx
  mov    0x4070(%rsp),%r15d
  mov    %rsi,0x8(%rsp)
  mov    %rdi,%r12
  xor    %edi,%edi
  mov    %edx,%ebp
  mov    %ecx,0x14(%rsp)
  sub    %edx,%ecx
  mov    %r8,%r14
  mov    %r9,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x4028(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  mov    %ecx,0x10(%rsp)
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x4000,%edx
  xor    %esi,%esi
  mov    %rdi,0x18(%rsp)
  call   <memset@plt>
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    0x8(%rsp),%rax
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   *%rax
  cmp    %eax,%ebp
  jg     L2
  cmp    %eax,0x14(%rsp)
  jl     L2
  sub    %ebp,%eax
  shl    $0xc,%eax
  cltd
  idivl  0x10(%rsp)
  cltq
  addl   $0x1,0x20(%rsp,%rax,4)
L2:
  sub    $0x1,%ebx
  jne    L22
  pxor   %xmm3,%xmm3
  mov    0x18(%rsp),%r14
  lea    0x4020(%rsp),%r13
  cvtsi2sd %ebp,%xmm3
  lea    D6(%rip),%rbp
  movsd  %xmm3,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L34:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rsi
  mov    %r12,%rdi
  cvtsi2sd %ebx,%xmm1
  mulsd  D27(%rip),%xmm1
  add    $0x4,%r14
  cvtsi2sdl -0x4(%r14),%xmm0
  addsd  0x8(%rsp),%xmm1
  mulsd  D26(%rip),%xmm0
  cvttsd2si %xmm1,%edx
  call   <fprintf@plt>
  add    0x10(%rsp),%ebx
  cmp    %r13,%r14
  jne    L34
  mov    0x4028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x4038,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D27
data_type: f32[2]
name: unpack_data
arguments: label: D26
data_type: f32[2]

tool: D6: %.12f %.12f


tool: {"D27": [0.0,0.6875]}

tool: {"D26": [0.0,0.4375]}

assistant: ```c
void count_freq(FILE *fout, int (*pdist)(double *, int *, int), int lcutoff, int rcutoff, double *prob_accum, int *energy, int nsample) {
  int i;
  int freq[(1 << 12)];
  int rand_nr;
  int range = rcutoff - lcutoff;
  assert(range > 0);
  srand(time(NULL));
  for (i = 0; i < (1 << 12); i++)
    freq[i] = 0.0;
  for (i = 0; i < (1 << 17); i++) {
    rand_nr = pdist(prob_accum, energy, nsample);
    if ((rand_nr < lcutoff) || (rand_nr > rcutoff))
      continue;
    freq[(rand_nr - lcutoff) * (1 << 12) / range]++;
  }
  for (i = 0; i < (1 << 12); i++) {
    fprintf(fout, "%.12f %.12f\n", lcutoff + (double)(range * i) / (double)(1 << 12), ((double)freq[i] / (double)(1 << 17)));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_get_nline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_get_nline_rel@plt>
  leave
  ret
```

assistant: ```c
char *_get_nline(FILE *fp, size_t nline) {
  rewind(fp);
  return _get_nline_rel((fp), (size_t)nline);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_get_nline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <rewind@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <_get_nline_rel@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *_get_nline(FILE *fp, size_t nline) {
  rewind(fp);
  return _get_nline_rel((fp), (size_t)nline);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_get_nline>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <rewind@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_get_nline_rel@plt>
```

assistant: ```c
char *_get_nline(FILE *fp, size_t nline) {
  rewind(fp);
  return _get_nline_rel((fp), (size_t)nline);
}
```
user: Translate the below assembly code into C programming language:

```asm
<kek_wrap_key>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %rdx,%r14
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %r8,%rdi
  call   <EVP_CIPHER_CTX_block_size@plt>
  mov    %rax,%rcx
  lea    0x3(%rax,%r12,1),%rax
  mov    $0x0,%edx
  div    %rcx
  imul   %rcx,%rax
  add    %rcx,%rcx
  cmp    %rax,%rcx
  ja     L35
  mov    %rax,%rbx
  cmp    $0xff,%r12
  ja     L35
  test   %rbp,%rbp
  je     L15
  mov    %r12b,0x0(%rbp)
  movzbl (%r14),%eax
  not    %eax
  mov    %al,0x1(%rbp)
  movzbl 0x1(%r14),%eax
  not    %eax
  mov    %al,0x2(%rbp)
  movzbl 0x2(%r14),%eax
  not    %eax
  mov    %al,0x3(%rbp)
  lea    0x4(%rbp),%rdi
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  lea    0x4(%r12),%rdi
  cmp    %rbx,%rdi
  jb     L43
L11:
  lea    0x4(%rsp),%r12
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <EVP_EncryptUpdate@plt>
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <EVP_EncryptUpdate@plt>
L15:
  mov    %rbx,(%r15)
  mov    $0x1,%eax
  jmp    L54
L43:
  mov    %rbx,%rax
  sub    %r12,%rax
  lea    -0x4(%rax),%rsi
  add    %rbp,%rdi
  call   <RAND_pseudo_bytes@plt>
  jmp    L11
L35:
  mov    $0x0,%eax
L54:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kek_wrap_key(unsigned char *out, size_t *outlen, const unsigned char *in, size_t inlen, EVP_CIPHER_CTX *ctx) {
  size_t blocklen = EVP_CIPHER_CTX_block_size(ctx);
  size_t olen;
  int dummy;
  olen = (inlen + 4 + blocklen - 1) / blocklen;
  olen *= blocklen;
  if (olen < 2 * blocklen) {
    return 0;
  }
  if (inlen > 0xFF) {
    return 0;
  }
  if (out) {
    out[0] = (unsigned char)inlen;
    out[1] = in[0] ^ 0xFF;
    out[2] = in[1] ^ 0xFF;
    out[3] = in[2] ^ 0xFF;
    memcpy(out + 4, in, inlen);
    if (olen > inlen + 4)
      RAND_pseudo_bytes(out + 4 + inlen, olen - 4 - inlen);
    EVP_EncryptUpdate(ctx, out, &dummy, out, olen);
    EVP_EncryptUpdate(ctx, out, &dummy, out, olen);
  }
  *outlen = olen;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kek_wrap_key>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r8,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <EVP_CIPHER_CTX_block_size@plt>
  xor    %edx,%edx
  mov    %rax,%rcx
  lea    0x3(%rax,%r13,1),%rax
  div    %rcx
  imul   %rcx,%rax
  add    %rcx,%rcx
  cmp    %rax,%rcx
  ja     L5
  cmp    $0xff,%r13
  ja     L5
  mov    %rax,%rbx
  test   %r12,%r12
  je     L47
  mov    %r13b,(%r12)
  movzbl (%r15),%eax
  lea    0x4(%r12),%rdi
  mov    %r13,%rdx
  mov    %r15,%rsi
  not    %eax
  mov    %al,0x1(%r12)
  movzbl 0x1(%r15),%eax
  not    %eax
  mov    %al,0x2(%r12)
  movzbl 0x2(%r15),%eax
  not    %eax
  mov    %al,0x3(%r12)
  call   <memcpy@plt>
  lea    0x4(%r13),%rdi
  cmp    %rbx,%rdi
  jb     L35
L61:
  lea    0x4(%rsp),%r13
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r12,%rsi
  mov    %r13,%rdx
  mov    %r14,%rdi
  call   <EVP_EncryptUpdate@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <EVP_EncryptUpdate@plt>
L47:
  mov    %rbx,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L35:
  mov    %rbx,%rax
  add    %r12,%rdi
  sub    %r13,%rax
  lea    -0x4(%rax),%rsi
  call   <RAND_pseudo_bytes@plt>
  jmp    L61
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kek_wrap_key(unsigned char *out, size_t *outlen, const unsigned char *in, size_t inlen, EVP_CIPHER_CTX *ctx) {
  size_t blocklen = EVP_CIPHER_CTX_block_size(ctx);
  size_t olen;
  int dummy;
  olen = (inlen + 4 + blocklen - 1) / blocklen;
  olen *= blocklen;
  if (olen < 2 * blocklen) {
    return 0;
  }
  if (inlen > 0xFF) {
    return 0;
  }
  if (out) {
    out[0] = (unsigned char)inlen;
    out[1] = in[0] ^ 0xFF;
    out[2] = in[1] ^ 0xFF;
    out[3] = in[2] ^ 0xFF;
    memcpy(out + 4, in, inlen);
    if (olen > inlen + 4)
      RAND_pseudo_bytes(out + 4 + inlen, olen - 4 - inlen);
    EVP_EncryptUpdate(ctx, out, &dummy, out, olen);
    EVP_EncryptUpdate(ctx, out, &dummy, out, olen);
  }
  *outlen = olen;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kek_wrap_key>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r8,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <EVP_CIPHER_CTX_block_size@plt>
  xor    %edx,%edx
  mov    %rax,%rcx
  lea    0x3(%rax,%r13,1),%rax
  div    %rcx
  imul   %rcx,%rax
  add    %rcx,%rcx
  cmp    %rax,%rcx
  ja     L11
  cmp    $0xff,%r13
  ja     L11
  mov    %rax,%rbx
  test   %r12,%r12
  je     L43
  mov    %r13b,(%r12)
  movzbl (%r15),%eax
  lea    0x4(%r12),%rdi
  mov    %r13,%rdx
  mov    %r15,%rsi
  not    %eax
  mov    %al,0x1(%r12)
  movzbl 0x1(%r15),%eax
  not    %eax
  mov    %al,0x2(%r12)
  movzbl 0x2(%r15),%eax
  not    %eax
  mov    %al,0x3(%r12)
  call   <memcpy@plt>
  lea    0x4(%r13),%rdi
  cmp    %rbx,%rdi
  jb     L5
L57:
  lea    0x4(%rsp),%r13
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r12,%rsi
  mov    %r13,%rdx
  mov    %r14,%rdi
  call   <EVP_EncryptUpdate@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <EVP_EncryptUpdate@plt>
L43:
  mov    %rbx,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rax
  add    %r12,%rdi
  sub    %r13,%rax
  lea    -0x4(%rax),%rsi
  call   <RAND_pseudo_bytes@plt>
  jmp    L57
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kek_wrap_key(unsigned char *out, size_t *outlen, const unsigned char *in, size_t inlen, EVP_CIPHER_CTX *ctx) {
  size_t blocklen = EVP_CIPHER_CTX_block_size(ctx);
  size_t olen;
  int dummy;
  olen = (inlen + 4 + blocklen - 1) / blocklen;
  olen *= blocklen;
  if (olen < 2 * blocklen) {
    return 0;
  }
  if (inlen > 0xFF) {
    return 0;
  }
  if (out) {
    out[0] = (unsigned char)inlen;
    out[1] = in[0] ^ 0xFF;
    out[2] = in[1] ^ 0xFF;
    out[3] = in[2] ^ 0xFF;
    memcpy(out + 4, in, inlen);
    if (olen > inlen + 4)
      RAND_pseudo_bytes(out + 4 + inlen, olen - 4 - inlen);
    EVP_EncryptUpdate(ctx, out, &dummy, out, olen);
    EVP_EncryptUpdate(ctx, out, &dummy, out, olen);
  }
  *outlen = olen;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cip_avl_foreach>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x1,%eax
  jmp    L16
L0:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cip_avl_foreach_int@plt>
L16:
  leave
  ret
```

assistant: ```c
int cip_avl_foreach(struct cip_avl_node *tree, int (*callback_fn)(struct cip_avl_node *node, void *context), void *context) {
  if (tree == NULL)
    return 1;
  return cip_avl_foreach_int(tree, callback_fn, context);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cip_avl_foreach>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  call   <cip_avl_foreach_int@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
int cip_avl_foreach(struct cip_avl_node *tree, int (*callback_fn)(struct cip_avl_node *node, void *context), void *context) {
  if (tree == NULL)
    return 1;
  return cip_avl_foreach_int(tree, callback_fn, context);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cip_avl_foreach>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <cip_avl_foreach_int@plt>
  xchg   %ax,%ax
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cip_avl_foreach(struct cip_avl_node *tree, int (*callback_fn)(struct cip_avl_node *node, void *context), void *context) {
  if (tree == NULL)
    return 1;
  return cip_avl_foreach_int(tree, callback_fn, context);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cip_avl_foreach>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <cip_avl_foreach_int@plt>
  xchg   %ax,%ax
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cip_avl_foreach(struct cip_avl_node *tree, int (*callback_fn)(struct cip_avl_node *node, void *context), void *context) {
  if (tree == NULL)
    return 1;
  return cip_avl_foreach_int(tree, callback_fn, context);
}
```