ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<one_step_heun>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  movsd  %xmm0,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %rcx,%r14
  mov    (%rcx),%r15
  movq   %r15,%xmm1
  call   <set_wieners@plt>
  mov    %r13d,%edx
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  movq   %r15,%xmm0
  call   <my_rhs@plt>
  test   %r13d,%r13d
  jle    L25
  mov    %r13d,%r12d
  shl    $0x3,%r12
  mov    $0x0,%eax
L3:
  mov    %rax,%rdx
  add    (%rbx),%rdx
  movsd  0x8(%rsp),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  0x0(%rbp,%rax,1),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %r12,%rax
  jne    L3
  movq   %r15,%xmm3
  addsd  0x8(%rsp),%xmm3
  movq   %xmm3,%r15
  mov    0x8(%rbx),%rsi
  mov    %r13d,%edx
  mov    (%rbx),%rdi
  movapd %xmm3,%xmm0
  call   <my_rhs@plt>
  mov    $0x0,%eax
  movsd  D6(%rip),%xmm2
L33:
  mov    (%rbx),%rdx
  movsd  (%rdx,%rax,1),%xmm0
  addsd  0x0(%rbp,%rax,1),%xmm0
  mov    0x8(%rbx),%rdx
  movsd  0x8(%rsp),%xmm1
  mulsd  (%rdx,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,1)
  add    $0x8,%rax
  cmp    %r12,%rax
  jne    L33
L15:
  mov    %r15,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  movq   %r15,%xmm5
  addsd  0x8(%rsp),%xmm5
  movq   %xmm5,%r15
  mov    0x8(%rbx),%rsi
  mov    %r13d,%edx
  mov    (%rbx),%rdi
  movapd %xmm5,%xmm0
  call   <my_rhs@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void one_step_heun(double *y, double dt, double *yval[2], int neq, double *tim) {
  int i;
  double t = *tim, t1;
  set_wieners(dt, y, *tim);
  my_rhs(t, y, yval[0], neq);
  for (i = 0; i < neq; i++)
    yval[0][i] = dt * yval[0][i] + y[i];
  t1 = t + dt;
  my_rhs(t1, yval[0], yval[1], neq);
  for (i = 0; i < neq; i++)
    y[i] = .5 * (y[i] + yval[0][i] + dt * yval[1][i]);
  *tim = t1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<one_step_heun>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  movsd  (%rcx),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <set_wieners@plt>
  movsd  (%rsp),%xmm1
  mov    %r14d,%edx
  mov    %rbp,%rdi
  mov    0x0(%r13),%rsi
  movapd %xmm1,%xmm0
  call   <my_rhs@plt>
  test   %r14d,%r14d
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  jle    L24
  mov    0x0(%r13),%rdi
  movslq %r14d,%r12
  xor    %eax,%eax
  nopl   (%rax)
L13:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L13
  addsd  %xmm2,%xmm1
  mov    0x8(%r13),%rsi
  mov    %r14d,%edx
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <my_rhs@plt>
  mov    0x0(%r13),%rcx
  mov    0x8(%r13),%rdx
  xor    %eax,%eax
  movsd  D2(%rip),%xmm4
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  nopl   0x0(%rax)
L7:
  movsd  (%rdx,%rax,8),%xmm3
  movsd  0x0(%rbp,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm3
  addsd  %xmm3,%xmm0
  mulsd  %xmm4,%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L7
L15:
  movsd  %xmm1,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L24:
  addsd  %xmm2,%xmm1
  mov    0x8(%r13),%rsi
  mov    0x0(%r13),%rdi
  mov    %r14d,%edx
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <my_rhs@plt>
  movsd  (%rsp),%xmm1
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void one_step_heun(double *y, double dt, double *yval[2], int neq, double *tim) {
  int i;
  double t = *tim, t1;
  set_wieners(dt, y, *tim);
  my_rhs(t, y, yval[0], neq);
  for (i = 0; i < neq; i++)
    yval[0][i] = dt * yval[0][i] + y[i];
  t1 = t + dt;
  my_rhs(t1, yval[0], yval[1], neq);
  for (i = 0; i < neq; i++)
    y[i] = .5 * (y[i] + yval[0][i] + dt * yval[1][i]);
  *tim = t1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <countBits@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L15:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: %d 

assistant: ```c
int main() {
  int i, ret = 0, *res = countBits(5, &ret);
  for (i = 0; i < ret; i++) {
    printf("%d ", res[i]);
  }
  putchar('\n');
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x5,%edi
  call   <countBits@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L0
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D3(%rip),%r12
L9:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  jg     L9
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: %d 

assistant: ```c
int main() {
  int i, ret = 0, *res = countBits(5, &ret);
  for (i = 0; i < ret; i++) {
    printf("%d ", res[i]);
  }
  putchar('\n');
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <countBits@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L23
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D3(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L22:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L22
L23:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: %d 

assistant: ```c
int main() {
  int i, ret = 0, *res = countBits(5, &ret);
  for (i = 0; i < ret; i++) {
    printf("%d ", res[i]);
  }
  putchar('\n');
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <countBits@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L0
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D2(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L25:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L25
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
int main() {
  int i, ret = 0, *res = countBits(5, &ret);
  for (i = 0; i < ret; i++) {
    printf("%d ", res[i]);
  }
  putchar('\n');
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mygetline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L54:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L37
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L37:
  addl   $0x1,-0x8(%rbp)
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L10
  cmpl   $0xa,-0x4(%rbp)
  je     L10
  cmpl   $0x24,-0x4(%rbp)
  jne    L54
L10:
  cmpl   $0xa,-0x4(%rbp)
  jne    L58
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L58:
  cmpl   $0x24,-0x4(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L33
L38:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
L33:
  leave
  ret
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i;
  for (i = 0; (c = getchar()) != EOF && c != '\n' && c != '$'; ++i) {
    if (i < lim - 1)
      s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  if (c == '$')
    return 0;
  s[i] = '\0';
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mygetline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0x0,%ebx
  lea    -0x1(%rsi),%r12d
  jmp    L93
L77:
  add    $0x1,%rbx
L93:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L36
  cmp    $0xa,%eax
  je     L36
  cmp    $0x24,%eax
  je     L36
  cmp    %ebx,%r12d
  jle    L77
  mov    %al,0x0(%r13,%rbx,1)
  jmp    L77
L36:
  cmp    $0xa,%eax
  je     L46
  cmp    $0x24,%eax
  je     L91
L47:
  movslq %ebp,%rax
  movb   $0x0,0x0(%r13,%rax,1)
L89:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  movslq %ebp,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  add    $0x1,%ebp
  jmp    L47
L91:
  mov    $0x0,%ebp
  jmp    L89
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i;
  for (i = 0; (c = getchar()) != EOF && c != '\n' && c != '$'; ++i) {
    if (i < lim - 1)
      s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  if (c == '$')
    return 0;
  s[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mygetline>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    D8(%rip),%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  jmp    L62
  xchg   %ax,%ax
L64:
  cmp    $0xa,%eax
  je     L48
  cmp    $0x24,%eax
  je     L76
  cmp    %r14d,%ebx
  jle    L63
  mov    %al,0x0(%r13,%r14,1)
L63:
  add    $0x1,%r14
L62:
  xor    %eax,%eax
  mov    %r14d,%r12d
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L64
L76:
  cmp    $0xa,%eax
  je     L48
  cmp    $0x24,%eax
  je     L42
L41:
  movslq %r12d,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L42:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L48:
  movslq %r12d,%rax
  add    $0x1,%r12d
  movb   $0xa,0x0(%r13,%rax,1)
  jmp    L41
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i;
  for (i = 0; (c = getchar()) != EOF && c != '\n' && c != '$'; ++i) {
    if (i < lim - 1)
      s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  if (c == '$')
    return 0;
  s[i] = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mygetline>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    D1(%rip),%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  jmp    L2
  xchg   %ax,%ax
L17:
  cmp    $0xa,%eax
  je     L24
  cmp    $0x24,%eax
  je     L67
  cmp    %r14d,%ebx
  jle    L13
  mov    %al,0x0(%r13,%r14,1)
L13:
  add    $0x1,%r14
L2:
  xor    %eax,%eax
  mov    %r14d,%r12d
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L17
L67:
  cmp    $0xa,%eax
  je     L24
  cmp    $0x24,%eax
  je     L69
L9:
  movslq %r12d,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L69:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L24:
  movslq %r12d,%rax
  add    $0x1,%r12d
  movb   $0xa,0x0(%r13,%rax,1)
  jmp    L9
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i;
  for (i = 0; (c = getchar()) != EOF && c != '\n' && c != '$'; ++i) {
    if (i < lim - 1)
      s[i] = c;
  }
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  if (c == '$')
    return 0;
  s[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gmx_rdf@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_rdf(argc, argv);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_rdf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_rdf(argc, argv);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_rdf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_rdf(argc, argv);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_rdf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_rdf(argc, argv);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_phaddw_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L14:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %dx,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x24(%rbp),%eax
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L14
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L2:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%esi
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%edx
  mov    -0x24(%rbp),%eax
  mov    $0x2,%edi
  mov    %eax,%ecx
  shl    %cl,%edi
  mov    %edi,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    %esi,%edx
  mov    %dx,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x24(%rbp),%eax
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_phaddw_c(unsigned short *pDst, unsigned short *pSrc, int xmm) {
  int i;
  for (i = 0; i < (2 << xmm); i++)
    pDst[i] = pDst[i * 2] + pDst[i * 2 + 1];
  for (i = 0; i < (2 << xmm); i++)
    pDst[i + (2 << xmm)] = pSrc[i * 2] + pSrc[i * 2 + 1];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_phaddw_c>:
  endbr64
  mov    $0x2,%r8d
  mov    %edx,%ecx
  shl    %cl,%r8d
  test   %r8d,%r8d
  jle    L18
  mov    %r8d,%ecx
  mov    $0x0,%eax
L13:
  movzwl 0x2(%rdi,%rax,4),%edx
  add    (%rdi,%rax,4),%dx
  mov    %dx,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L13
  movslq %r8d,%r8
  lea    (%rdi,%r8,2),%rdi
  mov    $0x0,%eax
L16:
  movzwl 0x2(%rsi,%rax,4),%edx
  add    (%rsi,%rax,4),%dx
  mov    %dx,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L16
L18:
  ret
```

assistant: ```c
void test_phaddw_c(unsigned short *pDst, unsigned short *pSrc, int xmm) {
  int i;
  for (i = 0; i < (2 << xmm); i++)
    pDst[i] = pDst[i * 2] + pDst[i * 2 + 1];
  for (i = 0; i < (2 << xmm); i++)
    pDst[i + (2 << xmm)] = pSrc[i * 2] + pSrc[i * 2 + 1];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_phaddw_c>:
  endbr64
  mov    %edx,%ecx
  mov    $0x2,%eax
  shl    %cl,%eax
  movslq %eax,%rcx
  test   %ecx,%ecx
  jle    L29
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  movzwl 0x2(%rdi,%rax,4),%edx
  add    (%rdi,%rax,4),%dx
  mov    %dx,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L1
  lea    (%rdi,%rcx,2),%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L15:
  movzwl 0x2(%rsi,%rax,4),%edx
  add    (%rsi,%rax,4),%dx
  mov    %dx,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L15
L29:
  ret
```

assistant: ```c
void test_phaddw_c(unsigned short *pDst, unsigned short *pSrc, int xmm) {
  int i;
  for (i = 0; i < (2 << xmm); i++)
    pDst[i] = pDst[i * 2] + pDst[i * 2 + 1];
  for (i = 0; i < (2 << xmm); i++)
    pDst[i + (2 << xmm)] = pSrc[i * 2] + pSrc[i * 2 + 1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<two>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L32
  mov    $0x1,%eax
  jmp    L9
L32:
  cmpl   $0x2,-0x8(%rbp)
  je     L26
  mov    $0x1,%eax
  jmp    L9
L26:
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int two(int a, int b) {
  if (a != 1)
    return 1;
  if (b != 2)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<two>:
  endbr64
  cmp    $0x2,%esi
  setne  %al
  cmp    $0x1,%edi
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int two(int a, int b) {
  if (a != 1)
    return 1;
  if (b != 2)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<two>:
  endbr64
  cmp    $0x2,%esi
  setne  %al
  cmp    $0x1,%edi
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int two(int a, int b) {
  if (a != 1)
    return 1;
  if (b != 2)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<two>:
  endbr64
  cmp    $0x2,%esi
  setne  %al
  cmp    $0x1,%edi
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int two(int a, int b) {
  if (a != 1)
    return 1;
  if (b != 2)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glob_pattern_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rbx
  jmp    L69
L18:
  movsbl %r12b,%eax
  cmp    $0x5c,%eax
  je     L12
  cmp    $0x5c,%eax
  jg     L69
  cmp    $0x5b,%eax
  je     L11
  cmp    $0x5b,%eax
  jg     L69
  cmp    $0x2a,%eax
  je     L11
  cmp    $0x3f,%eax
  jne    L69
L11:
  mov    $0x1,%eax
  jmp    L40
L12:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  test   %al,%al
  jne    L69
  mov    $0x0,%eax
  jmp    L40
L69:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%r12d
  test   %r12b,%r12b
  jne    L18
  mov    $0x0,%eax
L40:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int glob_pattern_p(pattern)
char *pattern;
{
  register char *p = pattern;
  register char c;
  while ((c = *p++)) {
    switch (c) {
    case '?':
    case '[':
    case '*':
      return 1;
    case '\\':
      if (*p++ == 0)
        return 0;
    default:;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<glob_pattern_p>:
  endbr64
  movabs $0x2000000200001,%rcx
L40:
  mov    %rdi,%rdx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L34
  cmp    $0x5c,%al
  je     L0
  jg     L40
  sub    $0x2a,%eax
  cmp    $0x31,%al
  ja     L40
  bt     %rax,%rcx
  jae    L40
  mov    $0x1,%eax
  ret
L0:
  add    $0x2,%rdx
  cmpb   $0x0,(%rdi)
  je     L44
  mov    %rdx,%rdi
  jmp    L40
L34:
  mov    $0x0,%eax
  ret
L44:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int glob_pattern_p(pattern)
char *pattern;
{
  register char *p = pattern;
  register char c;
  while ((c = *p++)) {
    switch (c) {
    case '?':
    case '[':
    case '*':
      return 1;
    case '\\':
      if (*p++ == 0)
        return 0;
    default:;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glob_pattern_p>:
  endbr64
  movabs $0xfffdffffffdffffe,%rcx
L29:
  mov    %rdi,%rdx
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L56
  cmp    $0x5c,%al
  je     L35
  jg     L29
  sub    $0x2a,%eax
  cmp    $0x31,%al
  ja     L29
  bt     %rax,%rcx
  jb     L29
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L35:
  cmpb   $0x0,0x1(%rdx)
  lea    0x2(%rdx),%rdi
  jne    L29
L56:
  xor    %eax,%eax
  ret
```

assistant: ```c
int glob_pattern_p(pattern)
char *pattern;
{
  register char *p = pattern;
  register char c;
  while ((c = *p++)) {
    switch (c) {
    case '?':
    case '[':
    case '*':
      return 1;
    case '\\':
      if (*p++ == 0)
        return 0;
    default:;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<glob_pattern_p>:
  endbr64
  movabs $0xfffdffffffdffffe,%rcx
L10:
  mov    %rdi,%rdx
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L4
  cmp    $0x5c,%al
  je     L3
  jg     L10
  sub    $0x2a,%eax
  cmp    $0x31,%al
  ja     L10
  bt     %rax,%rcx
  jb     L10
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L3:
  cmpb   $0x0,0x1(%rdx)
  lea    0x2(%rdx),%rdi
  jne    L10
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int glob_pattern_p(pattern)
char *pattern;
{
  register char *p = pattern;
  register char c;
  while ((c = *p++)) {
    switch (c) {
    case '?':
    case '[':
    case '*':
      return 1;
    case '\\':
      if (*p++ == 0)
        return 0;
    default:;
    }
  }
  return 0;
}
```