ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dqawc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  movsd  %xmm1,-0x28(%rbp)
  movsd  %xmm2,-0x30(%rbp)
  movsd  %xmm3,-0x38(%rbp)
  movsd  %xmm4,-0x40(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    -0x58(%rbp),%rcx
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rsi
  movsd  -0x40(%rbp),%xmm3
  movsd  -0x38(%rbp),%xmm2
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mov    -0x20(%rbp),%rdi
  mov    -0x18(%rbp),%rax
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <dqawce@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double dqawc(double f(double), double a, double b, double c, double epsabs, double epsrel, double *abserr, int *neval, int *ier) {
  double result;
  result = dqawce(f, a, b, c, epsabs, epsrel, abserr, neval, ier);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dqawc>:
  endbr64
  sub    $0x8,%rsp
  call   <dqawce@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double dqawc(double f(double), double a, double b, double c, double epsabs, double epsrel, double *abserr, int *neval, int *ier) {
  double result;
  result = dqawce(f, a, b, c, epsabs, epsrel, abserr, neval, ier);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dqawc>:
  endbr64
  jmp    1050 <dqawce@plt>
```

assistant: ```c
double dqawc(double f(double), double a, double b, double c, double epsabs, double epsrel, double *abserr, int *neval, int *ier) {
  double result;
  result = dqawce(f, a, b, c, epsabs, epsrel, abserr, neval, ier);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dqawc>:
  endbr64
  jmp    1050 <dqawce@plt>
```

assistant: ```c
double dqawc(double f(double), double a, double b, double c, double epsabs, double epsrel, double *abserr, int *neval, int *ier) {
  double result;
  result = dqawce(f, a, b, c, epsabs, epsrel, abserr, neval, ier);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<TKEstimateBas64DecodedDataSize>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L19
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L27:
  mulsd  D17(%rip),%xmm0
  movsd  D12(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L14
  cvttsd2si %xmm0,%rdi
  call   <ceil@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,2),%eax
  cltq
  ret
L14:
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rdi
  btc    $0x3f,%rdi
  call   <ceil@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,2),%eax
  cltq
  ret
  nopl   (%rax)
L19:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L27
```

tool_calls: name: read_data
arguments: label: D17
type_infered: byte[8]
name: read_data
arguments: label: D12
type_infered: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

assistant: ```c
size_t TKEstimateBas64DecodedDataSize(size_t inDataSize) {
  size_t theDecodedDataSize = (int)ceil(inDataSize / 4.0) * 3;
  return (theDecodedDataSize);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<TKEstimateBas64DecodedDataSize>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L27
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L13:
  mulsd  D18(%rip),%xmm0
  movsd  D12(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L16
  cvttsd2si %xmm0,%rdi
  call   <ceil@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,2),%eax
  cltq
  ret
L16:
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rdi
  btc    $0x3f,%rdi
  call   <ceil@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,2),%eax
  cltq
  ret
  nopl   (%rax)
L27:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L13
```

tool_calls: name: read_data
arguments: data_tag: D18
type_guessed: byte[8]
name: read_data
arguments: data_tag: D12
type_guessed: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

assistant: ```c
size_t TKEstimateBas64DecodedDataSize(size_t inDataSize) {
  size_t theDecodedDataSize = (int)ceil(inDataSize / 4.0) * 3;
  return (theDecodedDataSize);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x14,-0x20(%rbp)
  movl   $0x28,-0x1c(%rbp)
  movl   $0x1e,-0x18(%rbp)
  movl   $0xa,-0x14(%rbp)
  movl   $0x3c,-0x10(%rbp)
  movl   $0x32,-0xc(%rbp)
  movl   $0x6,-0x24(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L19
L32:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L19:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L32
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insert_sort@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L14
L25:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L14:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L25
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D33
datatype: string
name: parse_data
arguments: label: D22
datatype: string
name: parse_data
arguments: label: D5
datatype: string

tool: D33: before sort:

tool: D22: %d 

tool: D5: after  sort:

assistant: ```c
void main() {
  int i;
  int a[] = {20, 40, 30, 10, 60, 50};
  int ilen = ((sizeof(a)) / (sizeof(a[0])));
  printf("before sort:");
  for (i = 0; i < ilen; i++)
    printf("%d ", a[i]);
  printf("\n");
  insert_sort(a, ilen);
  printf("after  sort:");
  for (i = 0; i < ilen; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x14,(%rsp)
  movl   $0x28,0x4(%rsp)
  movl   $0x1e,0x8(%rsp)
  movl   $0xa,0xc(%rsp)
  movl   $0x3c,0x10(%rsp)
  movl   $0x32,0x14(%rsp)
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  mov    %rbx,%rbp
  lea    D12(%rip),%r13
L16:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  mov    $0x6,%esi
  call   <insert_sort@plt>
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rbp
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type: string
name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D24
type: string

tool: D10: before sort:

tool: D12: %d 

tool: D24: after  sort:

assistant: ```c
void main() {
  int i;
  int a[] = {20, 40, 30, 10, 60, 50};
  int ilen = ((sizeof(a)) / (sizeof(a[0])));
  printf("before sort:");
  for (i = 0; i < ilen; i++)
    printf("%d ", a[i]);
  printf("\n");
  insert_sort(a, ilen);
  printf("after  sort:");
  for (i = 0; i < ilen; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%rdi
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2800000014,%rax
  mov    %rsp,%r14
  lea    0x18(%rsp),%r12
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,(%rsp)
  movabs $0xa0000001e,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x320000003c,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  nopl   (%rax)
L22:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r14,%rdi
  mov    $0x6,%esi
  call   <insert_sort@plt>
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D28
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D24
type_guessed: string

tool: D28: before sort:

tool: D14: %d 

tool: D24: after  sort:

assistant: ```c
void main() {
  int i;
  int a[] = {20, 40, 30, 10, 60, 50};
  int ilen = ((sizeof(a)) / (sizeof(a[0])));
  printf("before sort:");
  for (i = 0; i < ilen; i++)
    printf("%d ", a[i]);
  printf("\n");
  insert_sort(a, ilen);
  printf("after  sort:");
  for (i = 0; i < ilen; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  lea    D11(%rip),%rdi
  push   %r13
  lea    D34(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D47(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D23(%rip),%rax
  mov    %rsp,%r14
  lea    0x18(%rsp),%r12
  movaps %xmm0,(%rsp)
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L26:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r14,%rdi
  mov    $0x6,%esi
  call   <insert_sort@plt>
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: string
name: parse_data
arguments: data_tag: D34
type_infered: string
name: parse_data
arguments: data_tag: D47
type_infered: byte[16]
name: parse_data
arguments: data_tag: D23
type_infered: byte[8]
name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D11: before sort:

tool: D34: %d 

tool: {"D47": [0x14,0x00,0x00,0x00,0x28,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D23": [0x3c,0x00,0x00,0x00,0x32,0x00,0x00,0x00]}

tool: D3: after  sort:

assistant: ```c
void main() {
  int i;
  int a[] = {20, 40, 30, 10, 60, 50};
  int ilen = ((sizeof(a)) / (sizeof(a[0])));
  printf("before sort:");
  for (i = 0; i < ilen; i++)
    printf("%d ", a[i]);
  printf("\n");
  insert_sort(a, ilen);
  printf("after  sort:");
  for (i = 0; i < ilen; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L15:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0x64,-0x8(%rbp)
  jle    L15
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string
name: unpack_data
arguments: label: D3
data_type: string

tool: D5: i=%d


tool: D3: sum=%d


assistant: ```c
int main(void) {
  int i = 1;
  int sum = 0;
  while (i < 101) {
    printf("i=%d\n", i);
    sum = sum + i;
    i++;
  }
  printf("sum=%d\n", sum);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D8(%rip),%rbp
L6:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L6
  mov    $0x13ba,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string
name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D8: i=%d


tool: D0: sum=%d


assistant: ```c
int main(void) {
  int i = 1;
  int sum = 0;
  while (i < 101) {
    printf("i=%d\n", i);
    sum = sum + i;
    i++;
  }
  printf("sum=%d\n", sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x65,%ebx
  jne    L7
  mov    $0x13ba,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D2
datatype: string

tool: D0: i=%d


tool: D2: sum=%d


assistant: ```c
int main(void) {
  int i = 1;
  int sum = 0;
  while (i < 101) {
    printf("i=%d\n", i);
    sum = sum + i;
    i++;
  }
  printf("sum=%d\n", sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x65,%ebx
  jne    L9
  mov    $0x13ba,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D16
datatype: string

tool: D0: i=%d


tool: D16: sum=%d


assistant: ```c
int main(void) {
  int i = 1;
  int sum = 0;
  while (i < 101) {
    printf("i=%d\n", i);
    sum = sum + i;
    i++;
  }
  printf("sum=%d\n", sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strmalloccat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcat@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strmalloccat(char *str1, const char *str2) {
  int l = strlen(str1) + strlen(str2);
  str1 = strcat(realloc(str1, l + 1), str2);
  str1[l] = '\0';
  return str1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strmalloccat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  lea    0x1(%rbx),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <strcat@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strmalloccat(char *str1, const char *str2) {
  int l = strlen(str1) + strlen(str2);
  str1 = strcat(realloc(str1, l + 1), str2);
  str1[l] = '\0';
  return str1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strmalloccat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %r12,%rdi
  add    %eax,%ebx
  lea    0x1(%rbx),%esi
  movslq %ebx,%rbx
  call   <realloc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strcat@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strmalloccat(char *str1, const char *str2) {
  int l = strlen(str1) + strlen(str2);
  str1 = strcat(realloc(str1, l + 1), str2);
  str1[l] = '\0';
  return str1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strmalloccat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %r12,%rdi
  add    %eax,%ebx
  lea    0x1(%rbx),%esi
  movslq %ebx,%rbx
  call   <realloc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strcat@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strmalloccat(char *str1, const char *str2) {
  int l = strlen(str1) + strlen(str2);
  str1 = strcat(realloc(str1, l + 1), str2);
  str1[l] = '\0';
  return str1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unpack_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L18
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L19
L18:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <unpack_integer>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    -0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0xffffffff81020409,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x6,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x7,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x7,%rax
  sub    %rdx,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L19:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void unpack_integer(const unsigned char *s, unsigned long int *value, size_t *i) {
  if (s[*i] <= 0x7F) {
    *value = s[*i] - 1;
    (*i)++;
  } else {
    unsigned long int val;
    size_t j;
    j = *i + 1;
    unpack_integer(s, &val, &j);
    *value = ((s[*i] - 1) % 0x7F) + (0x7F * val);
    *i = j;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<unpack_integer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rdx),%rax
  movzbl (%rdi,%rax,1),%ebx
  test   %bl,%bl
  js     L14
  movzbl %bl,%ebx
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  mov    %rbx,(%rsi)
  addq   $0x1,(%rdx)
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  add    $0x1,%rax
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <unpack_integer>
  movzbl %bl,%ebx
  sub    $0x1,%ebx
  movslq %ebx,%rax
  imul   $0xffffffff81020409,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x6,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0x7,%edx
  sub    %eax,%edx
  sub    %edx,%ebx
  movslq %ebx,%rbx
  mov    0x8(%rsp),%rdx
  mov    %rdx,%rax
  shl    $0x7,%rax
  sub    %rdx,%rax
  add    %rax,%rbx
  mov    %rbx,(%r12)
  mov    0x10(%rsp),%rax
  mov    %rax,0x0(%rbp)
  jmp    L12
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unpack_integer(const unsigned char *s, unsigned long int *value, size_t *i) {
  if (s[*i] <= 0x7F) {
    *value = s[*i] - 1;
    (*i)++;
  } else {
    unsigned long int val;
    size_t j;
    j = *i + 1;
    unpack_integer(s, &val, &j);
    *value = ((s[*i] - 1) % 0x7F) + (0x7F * val);
    *i = j;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<unpack_integer>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    (%rdx),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl (%rdi,%rdx,1),%ebx
  mov    %ebx,%eax
  sub    $0x1,%ebx
  test   %al,%al
  js     L4
  movslq %ebx,%rbx
  mov    %rbx,(%rsi)
  addq   $0x1,0x0(%rbp)
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x1,%rdx
  lea    0x8(%rsp),%rsi
  mov    %rdx,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  call   <unpack_integer>
  mov    0x8(%rsp),%rcx
  mov    %rcx,%rax
  shl    $0x7,%rax
  sub    %rcx,%rax
  mov    %ebx,%ecx
  mov    %rax,%rdx
  movslq %ebx,%rax
  sar    $0x1f,%ecx
  imul   $0xffffffff81020409,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x6,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x7,%ecx
  sub    %eax,%ecx
  sub    %ecx,%ebx
  movslq %ebx,%rbx
  lea    (%rdx,%rbx,1),%rax
  mov    %rax,(%r12)
  mov    0x10(%rsp),%rax
  mov    %rax,0x0(%rbp)
  jmp    L15
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unpack_integer(const unsigned char *s, unsigned long int *value, size_t *i) {
  if (s[*i] <= 0x7F) {
    *value = s[*i] - 1;
    (*i)++;
  } else {
    unsigned long int val;
    size_t j;
    j = *i + 1;
    unpack_integer(s, &val, &j);
    *value = ((s[*i] - 1) % 0x7F) + (0x7F * val);
    *i = j;
  }
}
```