ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<filnamcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L87
  mov    $0x0,%ecx
  mov    $0x5c,%r10d
  jmp    L40
L82:
  movzbl (%rsi,%rcx,1),%edx
  mov    %edx,%r8d
  lea    -0x61(%rdx),%r9d
  cmp    $0x19,%r9b
  ja     L14
L70:
  lea    -0x20(%r8),%edx
  cmp    $0x2f,%al
  je     L81
L96:
  cmp    $0x2f,%dl
  cmove  %r10d,%edx
L69:
  cmp    %al,%dl
  jne    L34
L116:
  add    $0x1,%rcx
  mov    %rcx,%rdx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L60
L40:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L82
  sub    $0x20,%eax
  movzbl (%rsi,%rcx,1),%edx
  mov    %edx,%r8d
  lea    -0x61(%rdx),%r9d
  cmp    $0x19,%r9b
  jbe    L70
  cmp    $0x2f,%dl
  jne    L69
  mov    $0xffffffffffffffff,%rax
  ret
L14:
  cmp    $0x2f,%al
  jne    L96
  cmp    $0x2f,%dl
  je     L116
  mov    $0x5c,%eax
  jmp    L69
L81:
  mov    $0x5c,%eax
  jmp    L69
L87:
  mov    $0x0,%edx
L60:
  movzbl (%rsi,%rdx,1),%eax
  neg    %al
  sbb    %rax,%rax
  ret
L34:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long filnamcmp(const char *st0, const char *st1) {
  long i;
  char ch0, ch1;
  for (i = 0; st0[i]; i++) {
    ch0 = st0[i];
    if ((ch0 >= 'a') && (ch0 <= 'z'))
      ch0 -= 32;
    ch1 = st1[i];
    if ((ch1 >= 'a') && (ch1 <= 'z'))
      ch1 -= 32;
    if (ch0 == '/')
      ch0 = '\\';
    if (ch1 == '/')
      ch1 = '\\';
    if (ch0 != ch1)
      return (-1);
  }
  if (!st1[i])
    return (0);
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<filnamcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L62
  xor    %ecx,%ecx
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L46:
  sub    $0x20,%eax
  cmp    $0x19,%r9b
  ja     L12
  sub    $0x20,%edx
L47:
  cmp    %al,%dl
  jne    L83
L57:
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L129
L58:
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x61(%rax),%r8d
  lea    -0x61(%rdx),%r9d
  cmp    $0x19,%r8b
  jbe    L46
  cmp    $0x19,%r9b
  ja     L53
  sub    $0x20,%edx
  cmp    $0x2f,%al
  jne    L47
L83:
  mov    $0xffffffffffffffff,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  cmp    $0x2f,%dl
  jne    L47
  mov    $0xffffffffffffffff,%rax
  ret
  nopl   (%rax)
L53:
  cmp    $0x2f,%al
  je     L72
  cmp    $0x2f,%dl
  jne    L47
  mov    $0x5c,%edx
  jmp    L47
L72:
  cmp    $0x2f,%dl
  je     L57
  mov    $0x5c,%eax
  jmp    L47
  nopl   0x0(%rax)
L129:
  add    %rcx,%rsi
L62:
  movzbl (%rsi),%eax
  neg    %al
  sbb    %rax,%rax
  ret
```

assistant: ```c
long filnamcmp(const char *st0, const char *st1) {
  long i;
  char ch0, ch1;
  for (i = 0; st0[i]; i++) {
    ch0 = st0[i];
    if ((ch0 >= 'a') && (ch0 <= 'z'))
      ch0 -= 32;
    ch1 = st1[i];
    if ((ch1 >= 'a') && (ch1 <= 'z'))
      ch1 -= 32;
    if (ch0 == '/')
      ch0 = '\\';
    if (ch1 == '/')
      ch1 = '\\';
    if (ch0 != ch1)
      return (-1);
  }
  if (!st1[i])
    return (0);
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<filnamcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  xor    %ecx,%ecx
  jmp    L112
  nopl   0x0(%rax,%rax,1)
L26:
  sub    $0x20,%eax
  cmp    $0x19,%r9b
  ja     L104
  sub    $0x20,%edx
L7:
  cmp    %al,%dl
  jne    L114
L82:
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L133
L112:
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x61(%rax),%r8d
  lea    -0x61(%rdx),%r9d
  cmp    $0x19,%r8b
  jbe    L26
  cmp    $0x19,%r9b
  ja     L79
  sub    $0x20,%edx
  cmp    $0x2f,%al
  jne    L7
L114:
  mov    $0xffffffffffffffff,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L104:
  cmp    $0x2f,%dl
  jne    L7
  mov    $0xffffffffffffffff,%rax
  ret
  nopl   (%rax)
L79:
  cmp    $0x2f,%al
  je     L107
  cmp    $0x2f,%dl
  jne    L7
  mov    $0x5c,%edx
  jmp    L7
L107:
  cmp    $0x2f,%dl
  je     L82
  mov    $0x5c,%eax
  jmp    L7
  nopl   0x0(%rax)
L133:
  add    %rcx,%rsi
L19:
  movzbl (%rsi),%eax
  neg    %al
  sbb    %rax,%rax
  ret
```

assistant: ```c
long filnamcmp(const char *st0, const char *st1) {
  long i;
  char ch0, ch1;
  for (i = 0; st0[i]; i++) {
    ch0 = st0[i];
    if ((ch0 >= 'a') && (ch0 <= 'z'))
      ch0 -= 32;
    ch1 = st1[i];
    if ((ch1 >= 'a') && (ch1 <= 'z'))
      ch1 -= 32;
    if (ch0 == '/')
      ch0 = '\\';
    if (ch1 == '/')
      ch1 = '\\';
    if (ch0 != ch1)
      return (-1);
  }
  if (!st1[i])
    return (0);
  return (-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hash_plugin_detailed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: samsungpin - Samsung Android PIN lock plugin
-------------------------------
Use this module to crack Samsung PINs
Input should be in form: 'hash:salt'
Known software that uses this password hashing method:
Android OS

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("samsungpin - Samsung Android PIN lock plugin\n"
          "-------------------------------\n"
          "Use this module to crack Samsung PINs\n"
          "Input should be in form: \'hash:salt\'\n"
          "Known software that uses this password hashing method:\n"
          "Android OS\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: samsungpin - Samsung Android PIN lock plugin
-------------------------------
Use this module to crack Samsung PINs
Input should be in form: 'hash:salt'
Known software that uses this password hashing method:
Android OS

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("samsungpin - Samsung Android PIN lock plugin\n"
          "-------------------------------\n"
          "Use this module to crack Samsung PINs\n"
          "Input should be in form: \'hash:salt\'\n"
          "Known software that uses this password hashing method:\n"
          "Android OS\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string

tool: D8: samsungpin - Samsung Android PIN lock plugin
-------------------------------
Use this module to crack Samsung PINs
Input should be in form: 'hash:salt'
Known software that uses this password hashing method:
Android OS

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("samsungpin - Samsung Android PIN lock plugin\n"
          "-------------------------------\n"
          "Use this module to crack Samsung PINs\n"
          "Input should be in form: \'hash:salt\'\n"
          "Known software that uses this password hashing method:\n"
          "Android OS\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: samsungpin - Samsung Android PIN lock plugin
-------------------------------
Use this module to crack Samsung PINs
Input should be in form: 'hash:salt'
Known software that uses this password hashing method:
Android OS

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("samsungpin - Samsung Android PIN lock plugin\n"
          "-------------------------------\n"
          "Use this module to crack Samsung PINs\n"
          "Input should be in form: \'hash:salt\'\n"
          "Known software that uses this password hashing method:\n"
          "Android OS\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1f0,%rsp
  mov    %edi,-0x1e4(%rbp)
  mov    %rsi,-0x1f0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xa,%edi
  call   <putchar@plt>
  movb   $0x61,-0x1d5(%rbp)
  lea    -0x1d4(%rbp),%rdx
  lea    -0x1d0(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   $0x616e61,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movw   $0x0,-0xc0(%rbp)
  movb   $0x0,-0xbe(%rbp)
  lea    -0x1d0(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0xf0(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0xf0(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  movl   $0x0,-0x1c8(%rbp)
  movl   $0x0,-0x1cc(%rbp)
  jmp    L17
L0:
  addl   $0x1,-0x1c8(%rbp)
  addl   $0x1,-0x1cc(%rbp)
L17:
  mov    -0x1cc(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L0
  mov    -0x1c8(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c4(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D29
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D41
type_guessed: string
name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D29: %d %d

tool: D1: %d

tool: D4:  %[^
]s

tool: D41: %[^
]s

tool: D6: %s


tool: D9: Letras = %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int x;
  int v[50];
  printf("\n");
  char c = 'a';
  int n;
  scanf("%d %d", &n, &x);
  char nome[51] = "ana";
  char aluna[51];
  scanf("%d", &n);
  scanf(" %[^\n]s", nome);
  strcpy(aluna, nome);
  char pessoa[101];
  scanf("%[^\n]s", pessoa);
  print("%s\n", pessoa);
  int i;
  int letras = 0;
  for (i = 0; pessoa[i] != '\0'; i++) {
    letras++;
  }
  printf("Letras = %d", letras);
  int letraFuncao = strlen(pessoa);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x100,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   $0x616e61,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movw   $0x0,0x40(%rsp)
  movb   $0x0,0x42(%rsp)
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x50(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  lea    0x90(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D27(%rip),%rdi
  call   <print@plt>
  cmpb   $0x0,0x90(%rsp)
  je     L19
  mov    $0x1,%eax
  lea    0x8f(%rsp),%rdx
L33:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L33
L14:
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x90(%rsp),%rdi
  call   <strlen@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x100,%rsp
  pop    %rbx
  ret
L19:
  mov    $0x0,%esi
  jmp    L14
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D19
data_type: string
name: extract_symbolic_data
arguments: data_label: D58
data_type: string
name: extract_symbolic_data
arguments: data_label: D27
data_type: string
name: extract_symbolic_data
arguments: data_label: D36
data_type: string

tool: D6: %d %d

tool: D10: %d

tool: D19:  %[^
]s

tool: D58: %[^
]s

tool: D27: %s


tool: D36: Letras = %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int x;
  int v[50];
  printf("\n");
  char c = 'a';
  int n;
  scanf("%d %d", &n, &x);
  char nome[51] = "ana";
  char aluna[51];
  scanf("%d", &n);
  scanf(" %[^\n]s", nome);
  strcpy(aluna, nome);
  char pessoa[101];
  scanf("%[^\n]s", pessoa);
  print("%s\n", pessoa);
  int i;
  int letras = 0;
  for (i = 0; pessoa[i] != '\0'; i++) {
    letras++;
  }
  printf("Letras = %d", letras);
  int letraFuncao = strlen(pessoa);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  sub    $0x100,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <putchar@plt>
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  mov    %rbp,%rsi
  mov    %ax,0x40(%rsp)
  lea    0x10(%rsp),%rbp
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movq   $0x616e61,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movb   $0x0,0x42(%rsp)
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    0x50(%rsp),%rdi
  lea    0x90(%rsp),%rbp
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D26(%rip),%rdi
  call   <print@plt>
  cmpb   $0x0,0x90(%rsp)
  je     L3
  mov    $0x1,%eax
  lea    0x8f(%rsp),%rdx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L17
L13:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x100,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  xor    %esi,%esi
  jmp    L13
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D20
datatype: string
name: parse_data
arguments: data_tag: D55
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D26
datatype: string
name: parse_data
arguments: data_tag: D12
datatype: string

tool: D20: %d %d

tool: D55: %d

tool: D28:  %[^
]s

tool: D10: %[^
]s

tool: D26: %s


tool: D12: Letras = %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int x;
  int v[50];
  printf("\n");
  char c = 'a';
  int n;
  scanf("%d %d", &n, &x);
  char nome[51] = "ana";
  char aluna[51];
  scanf("%d", &n);
  scanf(" %[^\n]s", nome);
  strcpy(aluna, nome);
  char pessoa[101];
  scanf("%[^\n]s", pessoa);
  print("%s\n", pessoa);
  int i;
  int letras = 0;
  for (i = 0; pessoa[i] != '\0'; i++) {
    letras++;
  }
  printf("Letras = %d", letras);
  int letraFuncao = strlen(pessoa);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  sub    $0x100,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <putchar@plt>
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  mov    %rbp,%rsi
  mov    %ax,0x40(%rsp)
  lea    0x10(%rsp),%rbp
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movq   $0x616e61,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movb   $0x0,0x42(%rsp)
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    0x50(%rsp),%rdi
  lea    0x90(%rsp),%rbp
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D36(%rip),%rdi
  call   <print@plt>
  cmpb   $0x0,0x90(%rsp)
  je     L5
  mov    $0x1,%eax
  lea    0x8f(%rsp),%rdx
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L28
L7:
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x100,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  xor    %esi,%esi
  jmp    L7
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D32
type_guessed: string
name: disassemble_data
arguments: data_tag: D8
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: string
name: disassemble_data
arguments: data_tag: D21
type_guessed: string
name: disassemble_data
arguments: data_tag: D36
type_guessed: string
name: disassemble_data
arguments: data_tag: D38
type_guessed: string

tool: D32: %d %d

tool: D8: %d

tool: D26:  %[^
]s

tool: D21: %[^
]s

tool: D36: %s


tool: D38: Letras = %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int x;
  int v[50];
  printf("\n");
  char c = 'a';
  int n;
  scanf("%d %d", &n, &x);
  char nome[51] = "ana";
  char aluna[51];
  scanf("%d", &n);
  scanf(" %[^\n]s", nome);
  strcpy(aluna, nome);
  char pessoa[101];
  scanf("%[^\n]s", pessoa);
  print("%s\n", pessoa);
  int i;
  int letras = 0;
  for (i = 0; pessoa[i] != '\0'; i++) {
    letras++;
  }
  printf("Letras = %d", letras);
  int letraFuncao = strlen(pessoa);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vsyslog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void debug(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vsyslog(LOG_DEBUG, fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<debug>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void debug(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vsyslog(LOG_DEBUG, fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<debug>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vsyslog(LOG_DEBUG, fmt, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<debug>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vsyslog(LOG_DEBUG, fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L27:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L8
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L28
L8:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L27
L28:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(void *buf1, void *buf2, int size) {
  int equal = 0;
  for (int i = 0; i < size; i++) {
    if (*((unsigned char *)buf1 + i) != *((unsigned char *)buf2 + i)) {
      equal = i;
      break;
    }
  }
  return equal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcmp>:
  endbr64
  test   %edx,%edx
  jle    L24
  mov    %edx,%edx
  mov    $0x0,%eax
L8:
  mov    %eax,%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,(%rdi,%rax,1)
  jne    L21
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
  mov    $0x0,%ecx
L21:
  mov    %ecx,%eax
  ret
L24:
  mov    $0x0,%ecx
  jmp    L21
```

assistant: ```c
int memcmp(void *buf1, void *buf2, int size) {
  int equal = 0;
  for (int i = 0; i < size; i++) {
    if (*((unsigned char *)buf1 + i) != *((unsigned char *)buf2 + i)) {
      equal = i;
      break;
    }
  }
  return equal;
}
```
user: What is the c source code of the assembly code below:

```asm
<memcmp>:
  endbr64
  test   %edx,%edx
  jle    L34
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L36
  nop
L9:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L34
L36:
  movzbl (%rsi,%rax,1),%ecx
  mov    %eax,%r8d
  cmp    %cl,(%rdi,%rax,1)
  je     L9
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L34:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int memcmp(void *buf1, void *buf2, int size) {
  int equal = 0;
  for (int i = 0; i < size; i++) {
    if (*((unsigned char *)buf1 + i) != *((unsigned char *)buf2 + i)) {
      equal = i;
      break;
    }
  }
  return equal;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memcmp>:
  endbr64
  test   %edx,%edx
  jle    L26
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L24
  nop
L38:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L26
L24:
  movzbl (%rsi,%rax,1),%ecx
  mov    %eax,%r8d
  cmp    %cl,(%rdi,%rax,1)
  je     L38
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L26:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int memcmp(void *buf1, void *buf2, int size) {
  int equal = 0;
  for (int i = 0; i < size; i++) {
    if (*((unsigned char *)buf1 + i) != *((unsigned char *)buf2 + i)) {
      equal = i;
      break;
    }
  }
  return equal;
}
```