ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L32
  lea    0x10(%rsp),%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L15:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x63,%eax
  ja     L15
  add    $0x1,%r12d
  add    $0x4,%rbx
  cmp    %r12d,0xc(%rsp)
  jg     L15
L32:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main() {
  int i, j, n = 0, Rudo[200];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &Rudo[i]);
    } while (Rudo[i] < 1 || Rudo[i] > 100);
  }
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (Rudo[i] == Rudo[j]) {
        Rudo[i] = 0;
        Rudo[j] = 0;
        break;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L28
  lea    0x10(%rsp),%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x63,%eax
  ja     L4
  add    $0x1,%r12d
  add    $0x4,%rbx
  cmp    %r12d,0xc(%rsp)
  jg     L4
L28:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
int main() {
  int i, j, n = 0, Rudo[200];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &Rudo[i]);
    } while (Rudo[i] < 1 || Rudo[i] > 100);
  }
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (Rudo[i] == Rudo[j]) {
        Rudo[i] = 0;
        Rudo[j] = 0;
        break;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fiducial120_id_from_symbol_sequence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x5c(%rbp)
  movl   $0x1,-0x50(%rbp)
  movl   $0x1,-0x4c(%rbp)
  movl   $0x2,-0x48(%rbp)
  movl   $0x6,-0x44(%rbp)
  movl   $0x18,-0x40(%rbp)
  movl   $0x78,-0x3c(%rbp)
  movl   $0x2d0,-0x38(%rbp)
  movl   $0x13b0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  mov    -0x68(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x8,-0x6c(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addq   $0x4,-0x68(%rbp)
  subl   $0x1,-0x6c(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L43
L28:
  mov    -0x58(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x6c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x58(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  imul   %edx,%eax
  add    %eax,-0x5c(%rbp)
  mov    -0x58(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x54(%rbp)
  jmp    L1
L37:
  mov    -0x54(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    -0x1(%rax),%edx
  mov    -0x54(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x54(%rbp)
L1:
  mov    -0x54(%rbp),%eax
  cmp    -0x6c(%rbp),%eax
  jl     L37
  addl   $0x1,-0x58(%rbp)
L43:
  mov    -0x58(%rbp),%eax
  cmp    -0x6c(%rbp),%eax
  jl     L28
  mov    -0x5c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

assistant: ```c
int fiducial120_id_from_symbol_sequence(int *sequence, int length) {
  int id = 0;
  int factorial[8] = {1, 1, 2, 6, 24, 120, 720, 5040};
  int mapping[8] = {0, 1, 2, 3, 4, 5, 6, 7};
  int i, j;
  assert(sequence[0] == 0);
  assert(length <= 8);
  sequence = sequence + 1;
  length = length - 1;
  for (i = 0; i < length; ++i) {
    id += mapping[(sequence[i] - 1)] * factorial[(length - 1) - i];
    for (j = (sequence[i] - 1) + 1; j < length; ++j) {
      mapping[j]--;
    }
  }
  return id;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fiducial120_id_from_symbol_sequence>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x18,0x10(%rsp)
  movl   $0x78,0x14(%rsp)
  movl   $0x2d0,0x18(%rsp)
  movl   $0x13b0,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x2,0x28(%rsp)
  movl   $0x3,0x2c(%rsp)
  movl   $0x4,0x30(%rsp)
  movl   $0x5,0x34(%rsp)
  movl   $0x6,0x38(%rsp)
  movl   $0x7,0x3c(%rsp)
  cmpl   $0x0,(%rdi)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x8,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    -0x1(%rbx),%r9d
  test   %r9d,%r9d
  jle    L37
  lea    0x4(%rbp),%rcx
  movslq %ebx,%rax
  lea    -0x8(%rsp,%rax,4),%rsi
  lea    -0x2(%rbx),%r8d
  mov    %r8d,%eax
  lea    0x8(%rbp,%rax,4),%r10
  mov    $0x0,%edi
  lea    0x20(%rsp),%rbx
  lea    0x24(%rsp),%r11
L2:
  mov    (%rcx),%edx
  lea    -0x1(%rdx),%eax
  cltq
  mov    0x20(%rsp,%rax,4),%eax
  imul   (%rsi),%eax
  add    %eax,%edi
  cmp    %r9d,%edx
  jge    L35
  movslq %edx,%r12
  lea    (%rbx,%r12,4),%rax
  mov    %r8d,%ebp
  sub    %edx,%ebp
  lea    0x0(%rbp,%r12,1),%rdx
  lea    (%r11,%rdx,4),%rdx
L55:
  subl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L55
L35:
  add    $0x4,%rcx
  sub    $0x4,%rsi
  cmp    %r10,%rcx
  jne    L2
L5:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    %edi,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    $0x0,%edi
  jmp    L5
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fiducial120_id_from_symbol_sequence(int *sequence, int length) {
  int id = 0;
  int factorial[8] = {1, 1, 2, 6, 24, 120, 720, 5040};
  int mapping[8] = {0, 1, 2, 3, 4, 5, 6, 7};
  int i, j;
  assert(sequence[0] == 0);
  assert(length <= 8);
  sequence = sequence + 1;
  length = length - 1;
  for (i = 0; i < length; ++i) {
    id += mapping[(sequence[i] - 1)] * factorial[(length - 1) - i];
    for (j = (sequence[i] - 1) + 1; j < length; ++j) {
      mapping[j]--;
    }
  }
  return id;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fiducial120_id_from_symbol_sequence>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x100000001,%rax
  mov    %rax,(%rsp)
  movabs $0x600000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x7800000018,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x13b0000002d0,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000000,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x38(%rsp)
  mov    (%rdi),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x8,%ebx
  setle  %dil
  call   <assert@plt>
  lea    -0x1(%rbx),%r9d
  test   %r9d,%r9d
  jle    L26
  movslq %ebx,%rax
  lea    0x4(%rbp),%rcx
  lea    0x24(%rsp),%r11
  xor    %r8d,%r8d
  lea    -0x8(%rsp,%rax,4),%rdi
  lea    -0x2(%rbx),%eax
  mov    %rax,%rsi
  lea    0x8(%rbp,%rax,4),%r10
  lea    0x20(%rsp),%rbx
  nopl   0x0(%rax)
L30:
  mov    (%rcx),%edx
  lea    -0x1(%rdx),%eax
  cltq
  mov    0x20(%rsp,%rax,4),%eax
  imul   (%rdi),%eax
  add    %eax,%r8d
  cmp    %r9d,%edx
  jge    L41
  mov    %esi,%ebp
  movslq %edx,%r12
  sub    %edx,%ebp
  lea    (%rbx,%r12,4),%rax
  lea    0x0(%rbp,%r12,1),%rdx
  lea    (%r11,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L55:
  subl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L55
L41:
  add    $0x4,%rcx
  sub    $0x4,%rdi
  cmp    %r10,%rcx
  jne    L30
L36:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x50,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  xor    %r8d,%r8d
  jmp    L36
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fiducial120_id_from_symbol_sequence(int *sequence, int length) {
  int id = 0;
  int factorial[8] = {1, 1, 2, 6, 24, 120, 720, 5040};
  int mapping[8] = {0, 1, 2, 3, 4, 5, 6, 7};
  int i, j;
  assert(sequence[0] == 0);
  assert(length <= 8);
  sequence = sequence + 1;
  length = length - 1;
  for (i = 0; i < length; ++i) {
    id += mapping[(sequence[i] - 1)] * factorial[(length - 1) - i];
    for (j = (sequence[i] - 1) + 1; j < length; ++j) {
      mapping[j]--;
    }
  }
  return id;
}
```
user: What is the c source code of the assembly code below:

```asm
<remove_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L22:
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L22
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  sub    $0x1,%rax
  add    %rax,-0x8(%rbp)
  jmp    L8
L38:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L38
  nop
  nop
  leave
  ret
```

assistant: ```c
void remove_space(char **pval) {
  unsigned char *p = (unsigned char *)*pval;
  while (isspace(*p))
    p++;
  *pval = (char *)p;
  p = p + strlen(*pval) - 1;
  while (isspace(*p))
    *p-- = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<remove_space>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rbx
  jmp    L39
L14:
  add    $0x1,%rbx
L39:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    %rbx,0x0(%rbp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbx
  jmp    L8
L1:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
L8:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_space(char **pval) {
  unsigned char *p = (unsigned char *)*pval;
  while (isspace(*p))
    p++;
  *pval = (char *)p;
  p = p + strlen(*pval) - 1;
  while (isspace(*p))
    *p-- = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<remove_space>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rbx
L35:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbx,0x0(%rbp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbx
  jmp    L36
  xchg   %ax,%ax
L1:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L36:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_space(char **pval) {
  unsigned char *p = (unsigned char *)*pval;
  while (isspace(*p))
    p++;
  *pval = (char *)p;
  p = p + strlen(*pval) - 1;
  while (isspace(*p))
    *p-- = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<remove_space>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rbx
L24:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
  mov    %rbx,0x0(%rbp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbx
  jmp    L38
  xchg   %ax,%ax
L22:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L38:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L22
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_space(char **pval) {
  unsigned char *p = (unsigned char *)*pval;
  while (isspace(*p))
    p++;
  *pval = (char *)p;
  p = p + strlen(*pval) - 1;
  while (isspace(*p))
    *p-- = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<escape>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L57
  cmp    $0x3,%rdx
  jbe    L117
  mov    $0x0,%r8d
  lea    D5(%rip),%r9
  jmp    L43
L125:
  cmp    $0x5c,%al
  jne    L93
  lea    0x1(%rsi),%rax
  movb   $0x5c,(%rsi)
  lea    0x1(%r8),%rcx
  movb   $0x5c,0x1(%rsi)
  jmp    L179
  lea    0x1(%rsi),%rax
  movb   $0x5c,(%rsi)
  lea    0x1(%r8),%rcx
  movb   $0x6e,0x1(%rsi)
L179:
  add    $0x1,%rdi
  lea    0x1(%rax),%rsi
  lea    0x1(%rcx),%r8
  movzbl (%rdi),%eax
  test   %al,%al
  je     L118
  add    $0x4,%rcx
  cmp    %rdx,%rcx
  jae    L118
L43:
  cmp    $0x3f,%al
  jg     L125
  cmp    $0x8,%al
  jle    L93
  lea    -0x9(%rax),%ecx
  cmp    $0x36,%cl
  ja     L93
  movzbl %cl,%ecx
  movslq (%r9,%rcx,4),%rcx
  add    %r9,%rcx
  notrack jmp *%rcx
  lea    0x1(%rsi),%rax
  movb   $0x5c,(%rsi)
  lea    0x1(%r8),%rcx
  movb   $0x72,0x1(%rsi)
  jmp    L179
  lea    0x1(%rsi),%rax
  movb   $0x5c,(%rsi)
  lea    0x1(%r8),%rcx
  movb   $0x74,0x1(%rsi)
  jmp    L179
  lea    0x1(%rsi),%rax
  movb   $0x5c,(%rsi)
  lea    0x1(%r8),%rcx
  movb   $0x22,0x1(%rsi)
  jmp    L179
  lea    0x1(%rsi),%rax
  movb   $0x5c,(%rsi)
  lea    0x1(%r8),%rcx
  movb   $0xb,0x1(%rsi)
  jmp    L179
  lea    0x1(%rsi),%rax
  movb   $0x5c,(%rsi)
  lea    0x1(%r8),%rcx
  movb   $0x3f,0x1(%rsi)
  jmp    L179
  lea    0x1(%rsi),%rax
  movb   $0x5c,(%rsi)
  lea    0x1(%r8),%rcx
  movb   $0xc,0x1(%rsi)
  jmp    L179
L93:
  mov    %al,(%rsi)
  mov    %r8,%rcx
  mov    %rsi,%rax
  jmp    L179
L57:
  mov    $0x0,%r8d
L118:
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  ret
L117:
  mov    $0x0,%r8d
  jmp    L118
```

assistant: ```c
size_t escape(char *in, char *out, size_t outsize) {
  size_t l = 0;
  while (*in && l + 3 < outsize) {
    switch (*in) {
    case '\n':
      *out++ = '\\';
      l++;
      *out = 'n';
      break;
    case '\r':
      *out++ = '\\';
      l++;
      *out = 'r';
      break;
    case '\t':
      *out++ = '\\';
      l++;
      *out = 't';
      break;
    case '\\':
      *out++ = '\\';
      l++;
      *out = '\\';
      break;
    case '"':
      *out++ = '\\';
      l++;
      *out = '"';
      break;
    case '\v':
      *out++ = '\\';
      l++;
      *out = '\v';
      break;
    case '\?':
      *out++ = '\\';
      l++;
      *out = '\?';
      break;
    case '\f':
      *out++ = '\\';
      l++;
      *out = '\f';
      break;
    default:
      *out = *in;
    }
    in++;
    out++;
    l++;
  }
  *out = 0;
  return l;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<escape>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  xor    %r9d,%r9d
  test   %al,%al
  je     L4
  cmp    $0x3,%rdx
  jbe    L4
  lea    D5(%rip),%r11
  xchg   %ax,%ax
L97:
  lea    0x1(%rsi),%r10
  lea    0x1(%r9),%rcx
  cmp    $0x3f,%al
  jg     L50
  cmp    $0x8,%al
  jle    L91
  lea    -0x9(%rax),%edi
  cmp    $0x36,%dil
  ja     L91
  movzbl %dil,%edi
  movslq (%r11,%rdi,4),%rdi
  add    %r11,%rdi
  notrack jmp *%rdi
  nopl   0x0(%rax,%rax,1)
L91:
  mov    %al,(%rsi)
  mov    %r9,%rcx
  mov    %rsi,%r10
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  lea    0x1(%r10),%rsi
  lea    0x1(%rcx),%r9
  test   %al,%al
  je     L4
  add    $0x4,%rcx
  cmp    %rdx,%rcx
  jb     L97
L4:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  ret
  nopl   (%rax)
  mov    $0x3f5c,%edi
  mov    %di,(%rsi)
  jmp    L21
  nopw   0x0(%rax,%rax,1)
  mov    $0x225c,%eax
  mov    %ax,(%rsi)
  jmp    L21
  nopw   0x0(%rax,%rax,1)
  mov    $0x725c,%eax
  mov    %ax,(%rsi)
  jmp    L21
  nopw   0x0(%rax,%rax,1)
  mov    $0xc5c,%eax
  mov    %ax,(%rsi)
  jmp    L21
  nopw   0x0(%rax,%rax,1)
  mov    $0xb5c,%r9d
  mov    %r9w,(%rsi)
  jmp    L21
  nopl   0x0(%rax)
  mov    $0x6e5c,%eax
  mov    %ax,(%rsi)
  jmp    L21
  nopl   (%rax)
  mov    $0x745c,%eax
  mov    %ax,(%rsi)
  jmp    L21
  nopl   (%rax)
L50:
  cmp    $0x5c,%al
  jne    L91
  mov    $0x5c5c,%eax
  mov    %ax,(%rsi)
  jmp    L21
```

assistant: ```c
size_t escape(char *in, char *out, size_t outsize) {
  size_t l = 0;
  while (*in && l + 3 < outsize) {
    switch (*in) {
    case '\n':
      *out++ = '\\';
      l++;
      *out = 'n';
      break;
    case '\r':
      *out++ = '\\';
      l++;
      *out = 'r';
      break;
    case '\t':
      *out++ = '\\';
      l++;
      *out = 't';
      break;
    case '\\':
      *out++ = '\\';
      l++;
      *out = '\\';
      break;
    case '"':
      *out++ = '\\';
      l++;
      *out = '"';
      break;
    case '\v':
      *out++ = '\\';
      l++;
      *out = '\v';
      break;
    case '\?':
      *out++ = '\\';
      l++;
      *out = '\?';
      break;
    case '\f':
      *out++ = '\\';
      l++;
      *out = '\f';
      break;
    default:
      *out = *in;
    }
    in++;
    out++;
    l++;
  }
  *out = 0;
  return l;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<escape>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  xor    %r9d,%r9d
  test   %al,%al
  je     L41
  cmp    $0x3,%rdx
  jbe    L41
  lea    D1(%rip),%r11
  xchg   %ax,%ax
L34:
  lea    0x1(%rsi),%r10
  lea    0x1(%r9),%rcx
  cmp    $0x3f,%al
  jg     L3
  cmp    $0x8,%al
  jle    L119
  lea    -0x9(%rax),%edi
  cmp    $0x36,%dil
  ja     L119
  movzbl %dil,%edi
  movslq (%r11,%rdi,4),%rdi
  add    %r11,%rdi
  notrack jmp *%rdi
  nopl   0x0(%rax,%rax,1)
L119:
  mov    %al,(%rsi)
  mov    %r9,%rcx
  mov    %rsi,%r10
  nopl   0x0(%rax,%rax,1)
L138:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  lea    0x1(%r10),%rsi
  lea    0x1(%rcx),%r9
  test   %al,%al
  je     L41
  add    $0x4,%rcx
  cmp    %rdx,%rcx
  jb     L34
L41:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  ret
  nopl   (%rax)
  mov    $0x3f5c,%edi
  mov    %di,(%rsi)
  jmp    L138
  nopw   0x0(%rax,%rax,1)
  mov    $0x225c,%eax
  mov    %ax,(%rsi)
  jmp    L138
  nopw   0x0(%rax,%rax,1)
  mov    $0x725c,%eax
  mov    %ax,(%rsi)
  jmp    L138
  nopw   0x0(%rax,%rax,1)
  mov    $0xc5c,%eax
  mov    %ax,(%rsi)
  jmp    L138
  nopw   0x0(%rax,%rax,1)
  mov    $0xb5c,%r9d
  mov    %r9w,(%rsi)
  jmp    L138
  nopl   0x0(%rax)
  mov    $0x6e5c,%eax
  mov    %ax,(%rsi)
  jmp    L138
  nopl   (%rax)
  mov    $0x745c,%eax
  mov    %ax,(%rsi)
  jmp    L138
  nopl   (%rax)
L3:
  cmp    $0x5c,%al
  jne    L119
  mov    $0x5c5c,%eax
  mov    %ax,(%rsi)
  jmp    L138
```

assistant: ```c
size_t escape(char *in, char *out, size_t outsize) {
  size_t l = 0;
  while (*in && l + 3 < outsize) {
    switch (*in) {
    case '\n':
      *out++ = '\\';
      l++;
      *out = 'n';
      break;
    case '\r':
      *out++ = '\\';
      l++;
      *out = 'r';
      break;
    case '\t':
      *out++ = '\\';
      l++;
      *out = 't';
      break;
    case '\\':
      *out++ = '\\';
      l++;
      *out = '\\';
      break;
    case '"':
      *out++ = '\\';
      l++;
      *out = '"';
      break;
    case '\v':
      *out++ = '\\';
      l++;
      *out = '\v';
      break;
    case '\?':
      *out++ = '\\';
      l++;
      *out = '\?';
      break;
    case '\f':
      *out++ = '\\';
      l++;
      *out = '\f';
      break;
    default:
      *out = *in;
    }
    in++;
    out++;
    l++;
  }
  *out = 0;
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_74_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_74_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | D;
  stk2 = T & stk3;
  stk1 = D ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_74_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  not    %edi
  and    %edi,%esi
  movzbl %sil,%eax
  xor    $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_74_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | D;
  stk2 = T & stk3;
  stk1 = D ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_74_1_0>:
  endbr64
  movzbl %dil,%edx
  movzbl %sil,%eax
  mov    %edx,%edi
  shl    $0x8,%edi
  or     %edx,%edi
  not    %edi
  and    %edi,%eax
  xor    $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_74_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | D;
  stk2 = T & stk3;
  stk1 = D ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_74_1_0>:
  endbr64
  movzbl %dil,%edx
  movzbl %sil,%eax
  mov    %edx,%edi
  shl    $0x8,%edi
  or     %edx,%edi
  not    %edi
  and    %edi,%eax
  xor    $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_74_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | D;
  stk2 = T & stk3;
  stk1 = D ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```