ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<harbol_hashmap_new_from_unilist>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L5
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <harbol_hashmap_new@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <harbol_hashmap_from_unilist@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct HarbolHashmap *harbol_hashmap_new_from_unilist(const struct HarbolUniList *const list) {
  if (!list)
    return NULL;
  struct HarbolHashmap *map = harbol_hashmap_new();
  harbol_hashmap_from_unilist(map, list);
  return map;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<harbol_hashmap_new_from_unilist>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L6
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <harbol_hashmap_new@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <harbol_hashmap_from_unilist@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct HarbolHashmap *harbol_hashmap_new_from_unilist(const struct HarbolUniList *const list) {
  if (!list)
    return NULL;
  struct HarbolHashmap *map = harbol_hashmap_new();
  harbol_hashmap_from_unilist(map, list);
  return map;
}
```
user: What is the c source code of the assembly code below:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L9
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L9:
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(int data[], int p, int r) {
  if (p < r) {
    int q = partition(data, p, r);
    quick_sort(data, p, q - 1);
    quick_sort(data, q + 1, r);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L7
  ret
L7:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quick_sort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quick_sort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quick_sort(int data[], int p, int r) {
  if (p < r) {
    int q = partition(data, p, r);
    quick_sort(data, p, q - 1);
    quick_sort(data, q + 1, r);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ap_utils_timespec_cmp_to_now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  jle    L17
  mov    $0x1,%eax
  jmp    L55
L17:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  jge    L58
  mov    $0xffffffff,%eax
  jmp    L55
L58:
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jle    L76
  mov    $0x1,%eax
  jmp    L55
L76:
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jge    L70
  mov    $0xffffffff,%eax
  jmp    L55
L70:
  mov    $0x0,%eax
L55:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int ap_utils_timespec_cmp_to_now(struct timespec *ts) {
  struct timespec now;
  clock_gettime(CLOCK_MONOTONIC_RAW, &now);
  if (ts->tv_sec > now.tv_sec)
    return 1;
  if (ts->tv_sec < now.tv_sec)
    return -1;
  if (ts->tv_nsec > now.tv_nsec)
    return 1;
  if (ts->tv_nsec < now.tv_nsec)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ap_utils_timespec_cmp_to_now>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    (%rbx),%rcx
  mov    (%rsp),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L29
  mov    $0xffffffff,%eax
  jl     L29
  mov    0x8(%rbx),%rcx
  mov    0x8(%rsp),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L29
  setl   %al
  movzbl %al,%eax
  neg    %eax
L29:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ap_utils_timespec_cmp_to_now(struct timespec *ts) {
  struct timespec now;
  clock_gettime(CLOCK_MONOTONIC_RAW, &now);
  if (ts->tv_sec > now.tv_sec)
    return 1;
  if (ts->tv_sec < now.tv_sec)
    return -1;
  if (ts->tv_nsec > now.tv_nsec)
    return 1;
  if (ts->tv_nsec < now.tv_nsec)
    return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ap_utils_timespec_cmp_to_now>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    (%rsp),%rcx
  mov    $0x1,%eax
  cmp    %rcx,(%rbx)
  jg     L14
  mov    $0xffffffff,%eax
  jl     L14
  mov    0x8(%rsp),%rdx
  mov    $0x1,%eax
  cmp    %rdx,0x8(%rbx)
  jg     L14
  setl   %al
  movzbl %al,%eax
  neg    %eax
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ap_utils_timespec_cmp_to_now(struct timespec *ts) {
  struct timespec now;
  clock_gettime(CLOCK_MONOTONIC_RAW, &now);
  if (ts->tv_sec > now.tv_sec)
    return 1;
  if (ts->tv_sec < now.tv_sec)
    return -1;
  if (ts->tv_nsec > now.tv_nsec)
    return 1;
  if (ts->tv_nsec < now.tv_nsec)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ap_utils_timespec_cmp_to_now>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    (%rsp),%rcx
  mov    $0x1,%eax
  cmp    %rcx,(%rbx)
  jg     L19
  mov    $0xffffffff,%eax
  jl     L19
  mov    0x8(%rsp),%rdx
  mov    $0x1,%eax
  cmp    %rdx,0x8(%rbx)
  jg     L19
  setl   %al
  movzbl %al,%eax
  neg    %eax
L19:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x20,%rsp
  pop    %rbx
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ap_utils_timespec_cmp_to_now(struct timespec *ts) {
  struct timespec now;
  clock_gettime(CLOCK_MONOTONIC_RAW, &now);
  if (ts->tv_sec > now.tv_sec)
    return 1;
  if (ts->tv_sec < now.tv_sec)
    return -1;
  if (ts->tv_nsec > now.tv_nsec)
    return 1;
  if (ts->tv_nsec < now.tv_nsec)
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tanh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  D7(%rip),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  subsd  -0x8(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: f64

tool: D7: 1

assistant: ```c
double tanh(double x) {
  double x0 = exp(x);
  double x1 = 1.0 / x0;
  return ((x0 + x1) / (x0 - x1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tanh>:
  endbr64
  sub    $0x8,%rsp
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movsd  D2(%rip),%xmm2
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: f64

tool: D2: 1

assistant: ```c
double tanh(double x) {
  double x0 = exp(x);
  double x1 = 1.0 / x0;
  return ((x0 + x1) / (x0 - x1));
}
```
user: What is the c source code of the assembly code below?

```asm
<tanh>:
  endbr64
  sub    $0x8,%rsp
  call   <exp@plt>
  movsd  D6(%rip),%xmm2
  add    $0x8,%rsp
  movapd %xmm0,%xmm1
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D6
datatype: f64

tool: D6: 1

assistant: ```c
double tanh(double x) {
  double x0 = exp(x);
  double x1 = 1.0 / x0;
  return ((x0 + x1) / (x0 - x1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tanh>:
  endbr64
  sub    $0x8,%rsp
  call   <exp@plt>
  movsd  D8(%rip),%xmm2
  add    $0x8,%rsp
  movapd %xmm0,%xmm1
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: f64

tool: D8: 1

assistant: ```c
double tanh(double x) {
  double x0 = exp(x);
  double x1 = 1.0 / x0;
  return ((x0 + x1) / (x0 - x1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L15
L12:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x38(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D45(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D45(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mulsd  -0x38(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L15:
  mov    -0x30(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D29
type_infered: string
name: parse_data
arguments: data_tag: D45
type_infered: f64
name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D1: %lf %lf %lf %d

tool: D29: %lf

tool: D45: 1

tool: D9: %.3f


assistant: ```c
int main() {
  double Vs, R, C, w;
  int num_examples;
  scanf("%lf %lf %lf %d", &Vs, &R, &C, &num_examples);
  for (int i = 0; i < num_examples; ++i) {
    scanf("%lf", &w);
    printf("%.3f\n", R * C * w * Vs * sqrt(1.0 / (R * R * C * C * w * w + 1)));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L7
  mov    $0x0,%ebx
  lea    D43(%rip),%r12
  lea    D38(%rip),%rbp
L6:
  lea    0x30(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm1
  movsd  0x30(%rsp),%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm1,%xmm3
  mulsd  %xmm2,%xmm3
  mulsd  0x18(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D1(%rip),%xmm1
  movsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm4,%xmm4
  ucomisd %xmm0,%xmm4
  ja     L10
  sqrtsd %xmm0,%xmm0
L28:
  mulsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jg     L6
L7:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <sqrt@plt>
  jmp    L28
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D43
type_infered: string
name: unpack_data
arguments: label: D38
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: f64

tool: D36: %lf %lf %lf %d

tool: D43: %lf

tool: D38: %.3f


tool: D1: 1

assistant: ```c
int main() {
  double Vs, R, C, w;
  int num_examples;
  scanf("%lf %lf %lf %d", &Vs, &R, &C, &num_examples);
  for (int i = 0; i < num_examples; ++i) {
    scanf("%lf", &w);
    printf("%.3f\n", R * C * w * Vs * sqrt(1.0 / (R * R * C * C * w * w + 1)));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L14
  xor    %ebx,%ebx
  lea    0x30(%rsp),%r13
  lea    D42(%rip),%r12
  lea    D27(%rip),%rbp
  nop
L9:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm3
  pxor   %xmm4,%xmm4
  movsd  0x30(%rsp),%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm2
  mulsd  0x18(%rsp),%xmm2
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D25(%rip),%xmm0
  addsd  D25(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L29
  sqrtsd %xmm0,%xmm0
L41:
  mulsd  %xmm2,%xmm0
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L9
L14:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  jmp    L41
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type: string
name: disassemble_data
arguments: data_label: D42
type: string
name: disassemble_data
arguments: data_label: D27
type: string
name: disassemble_data
arguments: data_label: D25
type: f64

tool: D16: %lf %lf %lf %d

tool: D42: %lf

tool: D27: %.3f


tool: D25: 1

assistant: ```c
int main() {
  double Vs, R, C, w;
  int num_examples;
  scanf("%lf %lf %lf %d", &Vs, &R, &C, &num_examples);
  for (int i = 0; i < num_examples; ++i) {
    scanf("%lf", &w);
    printf("%.3f\n", R * C * w * Vs * sqrt(1.0 / (R * R * C * C * w * w + 1)));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L42
  xor    %ebx,%ebx
  lea    0x30(%rsp),%r13
  lea    D38(%rip),%r12
  lea    D46(%rip),%rbp
  nop
L44:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm3
  pxor   %xmm4,%xmm4
  movsd  0x30(%rsp),%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm2
  mulsd  0x18(%rsp),%xmm2
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D1(%rip),%xmm0
  addsd  D1(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L11
  sqrtsd %xmm0,%xmm0
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mulsd  %xmm2,%xmm0
  call   <printf@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L44
L42:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  movsd  %xmm2,0x8(%rsp)
  add    $0x1,%ebx
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %rbp,%rdi
  mulsd  %xmm2,%xmm0
  call   <printf@plt>
  cmp    0x14(%rsp),%ebx
  jl     L44
  jmp    L42
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D38
type: string
name: extract_symbolic_data
arguments: label: D46
type: string
name: extract_symbolic_data
arguments: label: D1
type: f64

tool: D19: %lf %lf %lf %d

tool: D38: %lf

tool: D46: %.3f


tool: D1: 1

assistant: ```c
int main() {
  double Vs, R, C, w;
  int num_examples;
  scanf("%lf %lf %lf %d", &Vs, &R, &C, &num_examples);
  for (int i = 0; i < num_examples; ++i) {
    scanf("%lf", &w);
    printf("%.3f\n", R * C * w * Vs * sqrt(1.0 / (R * R * C * C * w * w + 1)));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<M909_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string
name: retrieve_data
arguments: tag: D17
data_type: string

tool: D8: M909_f(const char *s) is not yet implemented!


tool: D17: %s


assistant: ```c
int M909_f(char *s) {
  debug("M909_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<M909_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D15
datatype: string

tool: D4: M909_f(const char *s) is not yet implemented!


tool: D15: %s


assistant: ```c
int M909_f(char *s) {
  debug("M909_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<M909_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D10(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type_infered: string
name: unpack_data
arguments: data_tag: D12
type_infered: string

tool: D10: M909_f(const char *s) is not yet implemented!


tool: D12: %s


assistant: ```c
int M909_f(char *s) {
  debug("M909_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<M909_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D9
data_type: string

tool: D13: M909_f(const char *s) is not yet implemented!


tool: D9: %s


assistant: ```c
int M909_f(char *s) {
  debug("M909_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pp_sin>:
  endbr64
  movsd  D129(%rip),%xmm2
  movsd  D40(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L7
L35:
  addsd  %xmm2,%xmm0
  comisd %xmm0,%xmm1
  ja     L35
L7:
  movsd  D129(%rip),%xmm2
  movsd  D85(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L38
L8:
  subsd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  ja     L8
L38:
  comisd D184(%rip),%xmm0
  jbe    L49
  subsd  D13(%rip),%xmm0
  divsd  D161(%rip),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm2,%xmm1
  mulsd  D96(%rip),%xmm1
  subsd  D116(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D89(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  D2(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D104(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  xorpd  D41(%rip),%xmm0
  ret
L49:
  divsd  D161(%rip),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm2,%xmm1
  mulsd  D96(%rip),%xmm1
  subsd  D116(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D89(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  D2(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D104(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D129
type_guessed: f64
name: extract_symbolic_data
arguments: label: D40
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D85
type_guessed: f64
name: extract_symbolic_data
arguments: label: D184
type_guessed: f64[2]
name: extract_symbolic_data
arguments: label: D13
type_guessed: f64
name: extract_symbolic_data
arguments: label: D161
type_guessed: f64
name: extract_symbolic_data
arguments: label: D96
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D116
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D89
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D2
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D104
type_guessed: f64
name: extract_symbolic_data
arguments: label: D41
type_guessed: byte[16]

tool: D129: 6.283185307179586

tool: {"D40": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0xbf]}

tool: D85: 4.71238898038469

tool: {"D184": [1.5707963267948966,3.141592653589793]}

tool: D13: 3.141592653589793

tool: D161: 1.57079632679

tool: {"D96": [0xaf,0x90,0xa8,0x48,0xf7,0xda,0x23,0x3f]}

tool: {"D116": [0x0e,0x6d,0x5b,0x64,0xcc,0x24,0x73,0x3f]}

tool: {"D89": [0xa5,0x19,0x56,0xf6,0x8a,0x66,0xb4,0x3f]}

tool: {"D2": [0xcd,0xf9,0xac,0x16,0xbc,0xab,0xe4,0x3f]}

tool: D104: 1.57079631847

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double pp_sin(double x) {
  double xi, y, q, q2;
  int sign;
  xi = x;
  sign = 1;
  while (xi < -1.57079632679489661923)
    xi += 6.28318530717958647692;
  while (xi > 4.71238898038468985769)
    xi -= 6.28318530717958647692;
  if (xi > 1.57079632679489661923) {
    xi -= 3.141592653589793238462643;
    sign = -1;
  }
  q = xi / 1.57079632679;
  q2 = q * q;
  y = ((((.00015148419 * q2 - .00467376557) * q2 + .07968967928) * q2 - .64596371106) * q2 + 1.57079631847) * q;
  return (sign < 0 ? -y : y);
}
```