ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<zs_to_p>:
  endbr64
  subsd  D55(%rip),%xmm0
  divsd  D54(%rip),%xmm0
  comisd D18(%rip),%xmm0
  jbe    L16
  pxor   %xmm0,%xmm0
  ret
L16:
  sub    $0x8,%rsp
  mulsd  D5(%rip),%xmm0
  subsd  D69(%rip),%xmm0
  call   <exp@plt>
  comisd D62(%rip),%xmm0
  ja     L1
L24:
  add    $0x8,%rsp
  ret
L1:
  xorpd  D1(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movsd  D79(%rip),%xmm0
  subsd  %xmm1,%xmm0
  jmp    L24
```

tool_calls: name: unpack_data
arguments: label: D55
type_guessed: f64
name: unpack_data
arguments: label: D54
type_guessed: f64
name: unpack_data
arguments: label: D18
type_guessed: f64[2]
name: unpack_data
arguments: label: D5
type_guessed: byte[8]
name: unpack_data
arguments: label: D69
type_guessed: f64
name: unpack_data
arguments: label: D62
type_guessed: byte[16]
name: unpack_data
arguments: label: D1
type_guessed: f32[4]
name: unpack_data
arguments: label: D79
type_guessed: f64

tool: D55: 50

tool: D54: 10

tool: {"D18": [400.0,-1.282549830161864]}

tool: {"D5": [0xa8,0x91,0x80,0xf8,0x52,0x85,0xf4,0xbf]}

tool: D69: 0.5772156649015329

tool: {"D62": [0x7b,0x14,0xae,0x47,0xe1,0x7a,0x84,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D1": [0.0,-0.0,0.0,0.0]}

tool: D79: 1

assistant: ```c
double zs_to_p(double zs) {
  double e, z;
  z = (zs - 50.0) / 10.0;
  if (z > 400.0)
    return 0.0;
  e = exp(-1.28254983016186409554 * z - 0.57721566490153286060);
  return (e > .01 ? 1.0 - exp(-e) : e);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zs_to_p>:
  endbr64
  subsd  D45(%rip),%xmm0
  divsd  D32(%rip),%xmm0
  comisd D11(%rip),%xmm0
  jbe    L19
  pxor   %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  sub    $0x8,%rsp
  mulsd  D63(%rip),%xmm0
  subsd  D40(%rip),%xmm0
  call   <exp@plt>
  comisd D18(%rip),%xmm0
  ja     L18
  add    $0x8,%rsp
  ret
L18:
  xorpd  D8(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movsd  D51(%rip),%xmm0
  add    $0x8,%rsp
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D45
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D32
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D11
datatype: f64[2]
name: extract_symbolic_data
arguments: data_tag: D63
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D40
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D18
datatype: byte[16]
name: extract_symbolic_data
arguments: data_tag: D8
datatype: f32[4]
name: extract_symbolic_data
arguments: data_tag: D51
datatype: f64

tool: D45: 50

tool: D32: 10

tool: {"D11": [400.0,-1.282549830161864]}

tool: {"D63": [0xa8,0x91,0x80,0xf8,0x52,0x85,0xf4,0xbf]}

tool: D40: 0.5772156649015329

tool: {"D18": [0x7b,0x14,0xae,0x47,0xe1,0x7a,0x84,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D8": [0.0,-0.0,0.0,0.0]}

tool: D51: 1

assistant: ```c
double zs_to_p(double zs) {
  double e, z;
  z = (zs - 50.0) / 10.0;
  if (z > 400.0)
    return 0.0;
  e = exp(-1.28254983016186409554 * z - 0.57721566490153286060);
  return (e > .01 ? 1.0 - exp(-e) : e);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zs_to_p>:
  endbr64
  subsd  D28(%rip),%xmm0
  divsd  D24(%rip),%xmm0
  comisd D27(%rip),%xmm0
  jbe    L15
  pxor   %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  sub    $0x8,%rsp
  mulsd  D41(%rip),%xmm0
  subsd  D5(%rip),%xmm0
  call   <exp@plt>
  comisd D56(%rip),%xmm0
  ja     L10
  add    $0x8,%rsp
  ret
L10:
  xorpd  D37(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movsd  D15(%rip),%xmm0
  add    $0x8,%rsp
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
data_type: f64
name: extract_symbolic_data
arguments: data_label: D24
data_type: f64
name: extract_symbolic_data
arguments: data_label: D27
data_type: f64[2]
name: extract_symbolic_data
arguments: data_label: D41
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D5
data_type: f64
name: extract_symbolic_data
arguments: data_label: D56
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D37
data_type: f32[4]
name: extract_symbolic_data
arguments: data_label: D15
data_type: f64

tool: D28: 50

tool: D24: 10

tool: {"D27": [400.0,-1.282549830161864]}

tool: {"D41": [0xa8,0x91,0x80,0xf8,0x52,0x85,0xf4,0xbf]}

tool: D5: 0.5772156649015329

tool: {"D56": [0x7b,0x14,0xae,0x47,0xe1,0x7a,0x84,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D37": [0.0,-0.0,0.0,0.0]}

tool: D15: 1

assistant: ```c
double zs_to_p(double zs) {
  double e, z;
  z = (zs - 50.0) / 10.0;
  if (z > 400.0)
    return 0.0;
  e = exp(-1.28254983016186409554 * z - 0.57721566490153286060);
  return (e > .01 ? 1.0 - exp(-e) : e);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cmpfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L8
  mov    $0xffffffff,%eax
  jmp    L34
L8:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L33
  mov    $0x1,%eax
  jmp    L34
L33:
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int cmpfunc(const void *a, const void *b) {
  if (*(int *)b > *(int *)a) {
    return -1;
  } else if (*(int *)b < *(int *)a) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cmpfunc>:
  endbr64
  mov    (%rsi),%ecx
  mov    (%rdi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,%ecx
  jg     L7
  setl   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int cmpfunc(const void *a, const void *b) {
  if (*(int *)b > *(int *)a) {
    return -1;
  } else if (*(int *)b < *(int *)a) {
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmpfunc>:
  endbr64
  mov    (%rdi),%eax
  cmp    %eax,(%rsi)
  mov    $0xffffffff,%edx
  setl   %al
  movzbl %al,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int cmpfunc(const void *a, const void *b) {
  if (*(int *)b > *(int *)a) {
    return -1;
  } else if (*(int *)b < *(int *)a) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmpfunc>:
  endbr64
  mov    (%rdi),%eax
  cmp    %eax,(%rsi)
  mov    $0xffffffff,%edx
  setl   %al
  movzbl %al,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int cmpfunc(const void *a, const void *b) {
  if (*(int *)b > *(int *)a) {
    return -1;
  } else if (*(int *)b < *(int *)a) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str$position>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rdx
  lea    -0x2c(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   1080 <str$analyze_sdesc@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x2a(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   1080 <str$analyze_sdesc@plt>
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jns    11d2 <str$position+0x79>
  movq   $0x0,-0x10(%rbp)
  movzwl -0x2c(%rbp),%eax
  movzwl %ax,%eax
  cmp    %rax,-0x10(%rbp)
  jle    11ea <str$position+0x91>
  movzwl -0x2c(%rbp),%eax
  movzwl %ax,%eax
  mov    %rax,-0x10(%rbp)
  movzwl -0x2a(%rbp),%eax
  test   %ax,%ax
  jne    1201 <str$position+0xa8>
  movzwl -0x2c(%rbp),%eax
  movzwl %ax,%eax
  add    $0x1,%eax
  cltq
  jmp    1260 <str$position+0x107>
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    1243 <str$position+0xea>
  movzwl -0x2a(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  add    %rsi,%rcx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    123e <str$position+0xe5>
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  jmp    1260 <str$position+0x107>
  addq   $0x1,-0x18(%rbp)
  movzwl -0x2c(%rbp),%eax
  movzwl %ax,%eax
  movzwl -0x2a(%rbp),%edx
  movzwl %dx,%edx
  sub    %edx,%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jle    120f <str$position+0xb6>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     1274 <str$position+0x11b>
  call   <__stack_chk_fail@plt>
  leave
  ret
```

assistant: ```c
unsigned long str$position(const struct dsc$descriptor_s *first_source_string, const struct dsc$descriptor_s *second_source_string, const long *start_position) {
  char *s1_ptr;
  unsigned short s1_length;
  char *s2_ptr;
  unsigned short s2_length;
  long loop;
  long start_pos;
  str$analyze_sdesc(first_source_string, &s1_length, &s1_ptr);
  str$analyze_sdesc(second_source_string, &s2_length, &s2_ptr);
  start_pos = *start_position;
  if (start_pos < 0)
    start_pos = 0;
  if (start_pos > s1_length)
    start_pos = s1_length;
  if (s2_length == 0) {
    return s1_length + 1;
  }
  for (loop = start_pos - 1; loop <= s1_length - s2_length; loop++) {
    if (memcmp(s1_ptr + loop, s2_ptr, s2_length) == 0) {
      return loop + 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str$position>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  call   1080 <str$analyze_sdesc@plt>
  lea    0x10(%rsp),%rdx
  lea    0x6(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   1080 <str$analyze_sdesc@plt>
  mov    (%rbx),%rbx
  movzwl 0x4(%rsp),%edx
  movzwl 0x6(%rsp),%r12d
  test   %r12w,%r12w
  je     1219 <str$position+0xc0>
  test   %rbx,%rbx
  mov    $0x0,%eax
  cmovs  %rax,%rbx
  movzwl %dx,%eax
  cmp    %rax,%rbx
  cmovg  %rax,%rbx
  sub    $0x1,%rbx
  movzwl %r12w,%r12d
  movzwl %dx,%edx
  sub    %r12d,%edx
  movslq %edx,%rax
  cmp    %rax,%rbx
  jg     1243 <str$position+0xea>
  mov    0x10(%rsp),%r14
  mov    0x8(%rsp),%r13
  add    $0x1,%edx
  movslq %edx,%rbp
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  call   <memcmp@plt>
  test   %eax,%eax
  je     123d <str$position+0xe4>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    11f5 <str$position+0x9c>
  mov    $0x0,%eax
  jmp    1220 <str$position+0xc7>
  movzwl %dx,%edx
  lea    0x1(%rdx),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    124a <str$position+0xf1>
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  lea    0x1(%rbx),%rax
  jmp    1220 <str$position+0xc7>
  mov    $0x0,%eax
  jmp    1220 <str$position+0xc7>
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long str$position(const struct dsc$descriptor_s *first_source_string, const struct dsc$descriptor_s *second_source_string, const long *start_position) {
  char *s1_ptr;
  unsigned short s1_length;
  char *s2_ptr;
  unsigned short s2_length;
  long loop;
  long start_pos;
  str$analyze_sdesc(first_source_string, &s1_length, &s1_ptr);
  str$analyze_sdesc(second_source_string, &s2_length, &s2_ptr);
  start_pos = *start_position;
  if (start_pos < 0)
    start_pos = 0;
  if (start_pos > s1_length)
    start_pos = s1_length;
  if (s2_length == 0) {
    return s1_length + 1;
  }
  for (loop = start_pos - 1; loop <= s1_length - s2_length; loop++) {
    if (memcmp(s1_ptr + loop, s2_ptr, s2_length) == 0) {
      return loop + 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str$position>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  call   1080 <str$analyze_sdesc@plt>
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x6(%rsp),%rsi
  call   1080 <str$analyze_sdesc@plt>
  movzwl 0x4(%rsp),%edx
  movzwl 0x6(%rsp),%r12d
  mov    (%rbx),%rbx
  lea    0x1(%rdx),%rax
  test   %r12w,%r12w
  je     1218 <str$position+0xb8>
  xor    %eax,%eax
  test   %rbx,%rbx
  cmovs  %rax,%rbx
  movzwl %dx,%eax
  cmp    %rax,%rbx
  cmovg  %rax,%rbx
  sub    %r12d,%edx
  movslq %edx,%rax
  sub    $0x1,%rbx
  cmp    %rax,%rbx
  jg     1238 <str$position+0xd8>
  add    $0x1,%edx
  mov    0x10(%rsp),%r14
  mov    0x8(%rsp),%r13
  movslq %edx,%rbp
  jmp    11fd <str$position+0x9d>
  nopl   (%rax)
  cmp    %rbx,%rbp
  je     1238 <str$position+0xd8>
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  add    $0x1,%rbx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    11f8 <str$position+0x98>
  mov    %rbx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    123c <str$position+0xdc>
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
  xor    %eax,%eax
  jmp    1218 <str$position+0xb8>
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long str$position(const struct dsc$descriptor_s *first_source_string, const struct dsc$descriptor_s *second_source_string, const long *start_position) {
  char *s1_ptr;
  unsigned short s1_length;
  char *s2_ptr;
  unsigned short s2_length;
  long loop;
  long start_pos;
  str$analyze_sdesc(first_source_string, &s1_length, &s1_ptr);
  str$analyze_sdesc(second_source_string, &s2_length, &s2_ptr);
  start_pos = *start_position;
  if (start_pos < 0)
    start_pos = 0;
  if (start_pos > s1_length)
    start_pos = s1_length;
  if (s2_length == 0) {
    return s1_length + 1;
  }
  for (loop = start_pos - 1; loop <= s1_length - s2_length; loop++) {
    if (memcmp(s1_ptr + loop, s2_ptr, s2_length) == 0) {
      return loop + 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str$position>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  call   1080 <str$analyze_sdesc@plt>
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x6(%rsp),%rsi
  call   1080 <str$analyze_sdesc@plt>
  movzwl 0x4(%rsp),%edx
  movzwl 0x6(%rsp),%r12d
  mov    (%rbx),%rbx
  lea    0x1(%rdx),%rax
  test   %r12w,%r12w
  je     1218 <str$position+0xb8>
  xor    %eax,%eax
  test   %rbx,%rbx
  cmovs  %rax,%rbx
  movzwl %dx,%eax
  cmp    %rax,%rbx
  cmovg  %rax,%rbx
  sub    %r12d,%edx
  movslq %edx,%rax
  sub    $0x1,%rbx
  cmp    %rax,%rbx
  jg     1238 <str$position+0xd8>
  add    $0x1,%edx
  mov    0x10(%rsp),%r14
  mov    0x8(%rsp),%r13
  movslq %edx,%rbp
  jmp    11fd <str$position+0x9d>
  nopl   (%rax)
  cmp    %rbx,%rbp
  je     1238 <str$position+0xd8>
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  add    $0x1,%rbx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    11f8 <str$position+0x98>
  mov    %rbx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    123c <str$position+0xdc>
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
  xor    %eax,%eax
  jmp    1218 <str$position+0xb8>
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long str$position(const struct dsc$descriptor_s *first_source_string, const struct dsc$descriptor_s *second_source_string, const long *start_position) {
  char *s1_ptr;
  unsigned short s1_length;
  char *s2_ptr;
  unsigned short s2_length;
  long loop;
  long start_pos;
  str$analyze_sdesc(first_source_string, &s1_length, &s1_ptr);
  str$analyze_sdesc(second_source_string, &s2_length, &s2_ptr);
  start_pos = *start_position;
  if (start_pos < 0)
    start_pos = 0;
  if (start_pos > s1_length)
    start_pos = s1_length;
  if (s2_length == 0) {
    return s1_length + 1;
  }
  for (loop = start_pos - 1; loop <= s1_length - s2_length; loop++) {
    if (memcmp(s1_ptr + loop, s2_ptr, s2_length) == 0) {
      return loop + 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<max_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movsd  D7(%rip),%xmm0
  pxor   %xmm1,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L49
L50:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L8
L44:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L80
L54:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L80:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L54
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L5
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L5:
  movl   $0x0,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L44
  addl   $0x1,-0x14(%rbp)
L49:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L50
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L64
L47:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L64:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L47
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: f32[2]
name: disassemble_data
arguments: tag: D14
data_type: string

tool: {"D7": [0.0,-1.875]}

tool: D14: %d	

assistant: ```c
int max_sum(int *p, int n) {
  int max = -1.0 / 0.0;
  int sum = 0;
  int i, j, k;
  int flag_i, flag_k;
  for (i = 0; i < n; i++) {
    for (j = i; j < n; j++) {
      for (k = i; k <= j; k++) {
        sum = sum + p[k];
      }
      if (sum > max) {
        max = sum;
        flag_i = i;
        flag_k = k - 1;
      }
      sum = 0;
    }
  }
  for (i = flag_i; i <= flag_k; i++) {
    printf("%d\t", p[i]);
  }
  printf("\n");
  return max;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<max_sum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  movsd  D25(%rip),%xmm0
  divsd  D9(%rip),%xmm0
  cvttsd2si %xmm0,%ebx
  test   %esi,%esi
  jle    L29
  mov    %esi,%r8d
  mov    %esi,%r15d
  mov    $0x0,%r13d
  mov    $0x0,%r9d
  jmp    L8
L36:
  add    $0x1,%esi
  add    $0x4,%rcx
  cmp    %esi,%r8d
  je     L7
L87:
  mov    %rdi,%rax
  mov    %r9d,%edx
  cmp    %r10d,%esi
  jl     L25
L61:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L61
  lea    0x1(%rsi),%eax
L2:
  cmp    %edx,%ebx
  jge    L36
  lea    -0x1(%rax),%ebp
  mov    %r14d,%r11d
  mov    %edx,%ebx
  jmp    L36
L25:
  mov    %r14d,%eax
  jmp    L2
L7:
  add    $0x1,%r13
  add    $0x4,%rdi
  cmp    %r15,%r13
  je     L29
L8:
  mov    %r13d,%r14d
  mov    %r13d,%r10d
  cmp    %r13d,%r8d
  jle    L7
  lea    0x4(%rdi),%rcx
  mov    %r13d,%esi
  jmp    L87
L29:
  cmp    %ebp,%r11d
  jg     L16
  movslq %r11d,%r13
  lea    D27(%rip),%r14
L50:
  mov    (%r12,%r13,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r13
  cmp    %r13d,%ebp
  jge    L50
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D25
data_type: f32[2]
name: parse_data
arguments: data_tag: D9
data_type: f32[2]
name: parse_data
arguments: data_tag: D27
data_type: string

tool: {"D25": [0.0,-1.875]}

tool: {"D9": [0.0,0.0]}

tool: D27: %d	

assistant: ```c
int max_sum(int *p, int n) {
  int max = -1.0 / 0.0;
  int sum = 0;
  int i, j, k;
  int flag_i, flag_k;
  for (i = 0; i < n; i++) {
    for (j = i; j < n; j++) {
      for (k = i; k <= j; k++) {
        sum = sum + p[k];
      }
      if (sum > max) {
        max = sum;
        flag_i = i;
        flag_k = k - 1;
      }
      sum = 0;
    }
  }
  for (i = flag_i; i <= flag_k; i++) {
    printf("%d\t", p[i]);
  }
  printf("\n");
  return max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<max_sum>:
  endbr64
  push   %r14
  movsd  D13(%rip),%xmm0
  divsd  D3(%rip),%xmm0
  push   %r13
  push   %r12
  cvttsd2si %xmm0,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %esi,%esi
  jle    L64
  mov    %rdi,%r13
  mov    %esi,%r9d
  movslq %esi,%r14
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %r13,%r8
  add    $0x4,%r13
  mov    %edi,%r11d
  mov    %edi,%esi
  mov    %r13,%rcx
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %r8,%rax
  xor    %edx,%edx
  cmp    %edi,%esi
  jl     L48
  nopl   0x0(%rax)
L53:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L53
  add    $0x1,%esi
  mov    %esi,%eax
L11:
  cmp    %r12d,%edx
  jle    L7
  lea    -0x1(%rax),%ebx
  mov    %r11d,%r10d
  mov    %edx,%r12d
L7:
  add    $0x4,%rcx
  cmp    %esi,%r9d
  jg     L35
  add    $0x1,%rdi
  cmp    %r14,%rdi
  jne    L16
L64:
  cmp    %r10d,%ebx
  jl     L21
  movslq %r10d,%r13
  lea    D25(%rip),%r14
  nop
L1:
  mov    0x0(%rbp,%r13,4),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  cmp    %r13d,%ebx
  jge    L1
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L48:
  mov    %r11d,%eax
  add    $0x1,%esi
  jmp    L11
```

tool_calls: name: read_data
arguments: tag: D13
datatype: f32[2]
name: read_data
arguments: tag: D3
datatype: f32[2]
name: read_data
arguments: tag: D25
datatype: string

tool: {"D13": [0.0,-1.875]}

tool: {"D3": [0.0,0.0]}

tool: D25: %d	

assistant: ```c
int max_sum(int *p, int n) {
  int max = -1.0 / 0.0;
  int sum = 0;
  int i, j, k;
  int flag_i, flag_k;
  for (i = 0; i < n; i++) {
    for (j = i; j < n; j++) {
      for (k = i; k <= j; k++) {
        sum = sum + p[k];
      }
      if (sum > max) {
        max = sum;
        flag_i = i;
        flag_k = k - 1;
      }
      sum = 0;
    }
  }
  for (i = flag_i; i <= flag_k; i++) {
    printf("%d\t", p[i]);
  }
  printf("\n");
  return max;
}
```