user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xd8(%rbp)
  movl   $0x0,-0xdc(%rbp)
  jmp    L192
L67:
  movl   $0x0,-0xe0(%rbp)
  jmp    L6
L163:
  mov    -0xe0(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xdc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  movl   $0x0,-0xb0(%rbp,%rax,4)
  addl   $0x1,-0xe0(%rbp)
L6:
  cmpl   $0x5,-0xe0(%rbp)
  jle    L163
  mov    -0xdc(%rbp),%eax
  cltq
  movl   $0x0,-0xd0(%rbp,%rax,4)
  addl   $0x1,-0xdc(%rbp)
L192:
  cmpl   $0x6,-0xdc(%rbp)
  jle    L67
L52:
  movl   $0x1,-0xd4(%rbp)
  jmp    L42
L133:
  mov    -0xd4(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xd8(%rbp)
  lea    -0xe4(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xe4(%rbp),%eax
  test   %eax,%eax
  js     L133
  mov    -0xe4(%rbp),%eax
  cmp    $0x6,%eax
  jg     L133
  mov    -0xe4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  cmp    $0x5,%eax
  jg     L133
  mov    -0xe4(%rbp),%edx
  mov    -0xe4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  lea    (%rax,%rcx,1),%rdx
  mov    -0xd4(%rbp),%eax
  mov    %eax,-0xb0(%rbp,%rdx,4)
  mov    -0xe4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xd0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0xd0(%rbp,%rax,4)
  movl   $0x5,-0xe0(%rbp)
  jmp    L205
L165:
  mov    $0x7c,%edi
  call   <putchar@plt>
  movl   $0x0,-0xdc(%rbp)
  jmp    L127
L214:
  mov    -0xe0(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xdc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0xb0(%rbp,%rax,4),%eax
  cmp    $0x2,%eax
  je     L72
  cmp    $0x2,%eax
  jg     L159
  test   %eax,%eax
  je     L56
  cmp    $0x1,%eax
  je     L11
  jmp    L159
L56:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L159
L11:
  mov    $0x78,%edi
  call   <putchar@plt>
  jmp    L159
L72:
  mov    $0x30,%edi
  call   <putchar@plt>
  nop
L159:
  addl   $0x1,-0xdc(%rbp)
L127:
  cmpl   $0x6,-0xdc(%rbp)
  jle    L214
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  subl   $0x1,-0xe0(%rbp)
L205:
  cmpl   $0x0,-0xe0(%rbp)
  jns    L165
  addl   $0x1,-0xd4(%rbp)
L42:
  cmpl   $0x2,-0xd4(%rbp)
  jle    L133
  cmpl   $0x29,-0xd8(%rbp)
  jle    L52
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L89
  call   <__stack_chk_fail@plt>
L89:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
data_type: string
name: retrieve_data
arguments: data_tag: D20
data_type: string
name: retrieve_data
arguments: data_tag: D14
data_type: string

tool: D25: joueur %d 
Entrez une colonne (0-6) :

tool: D20: %d

tool: D14: |

assistant: ```c
int main() {
  int colonne;
  int plateau[7][6];
  int i, j;
  int compteur = 0;
  int joueur;
  int hauteurs[7];
  for (j = 0; j < 7; j++) {
    for (i = 0; i < 6; i++) {
      plateau[j][i] = 0;
    }
    hauteurs[j] = 0;
  }
  do {
    for (joueur = 1; joueur <= 2; joueur++) {
      do {
        printf("joueur %d \nEntrez une colonne (0-6) :", joueur);
        compteur++;
        scanf("%d", &colonne);
      } while (colonne < 0 || colonne > 6 || hauteurs[colonne] >= 6);
      plateau[colonne][hauteurs[colonne]] = joueur;
      hauteurs[colonne]++;
      for (i = 5; i >= 0; i--) {
        printf("|");
        for (j = 0; j < 7; j++) {
          switch (plateau[j][i]) {
          case 0:
            printf(" ");
            break;
          case 1:
            printf("x");
            break;
          case 2:
            printf("0");
            break;
          }
        }
        printf("|\n");
      }
    }
  } while (compteur < 42);
  return 0;
}
```