ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dress>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,%r12
  lea    D3(%rip),%rax
  mov    %rax,(%rsp)
  lea    D27(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D47(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D54(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D14(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D22(%rip),%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,8),%rsi
  call   <strcpy@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x40,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string
name: unpack_data
arguments: data_tag: D27
type_infered: string
name: unpack_data
arguments: data_tag: D47
type_infered: string
name: unpack_data
arguments: data_tag: D54
type_infered: string
name: unpack_data
arguments: data_tag: D14
type_infered: string
name: unpack_data
arguments: data_tag: D22
type_infered: string

tool: D3: d++

tool: D27: d+

tool: D47: d

tool: D54: d-

tool: D14: d--

tool: D22: d---

assistant: ```c
char *dress() {
  int random_index;
  char *dress;
  dress = malloc(5 * sizeof(char));
  char *dresses[6] = {"d++", "d+", "d", "d-", "d--", "d---"};
  random_index = rand() % 6;
  strcpy(dress, dresses[random_index]);
  return dress;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dress>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    D47(%rip),%rdi
  lea    D53(%rip),%rsi
  mov    %rax,%r12
  lea    D13(%rip),%rax
  movq   %rdi,%xmm0
  movq   %rax,%xmm1
  lea    D3(%rip),%rax
  lea    D25(%rip),%rdi
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  lea    D28(%rip),%rax
  movaps %xmm0,(%rsp)
  movq   %rsi,%xmm0
  movq   %rax,%xmm3
  xor    %eax,%eax
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
  movq   %rdi,%xmm0
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,8),%rsi
  call   <strcpy@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x40,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D47
data_type: string
name: parse_data
arguments: label: D53
data_type: string
name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D25
data_type: string
name: parse_data
arguments: label: D28
data_type: string

tool: D47: d++

tool: D53: d

tool: D13: d+

tool: D3: d-

tool: D25: d--

tool: D28: d---

assistant: ```c
char *dress() {
  int random_index;
  char *dress;
  dress = malloc(5 * sizeof(char));
  char *dresses[6] = {"d++", "d+", "d", "d-", "d--", "d---"};
  random_index = rand() % 6;
  strcpy(dress, dresses[random_index]);
  return dress;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_rom_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x148,%edi
  call   <get_mem@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <id_to_rom_size@plt>
  leave
  ret
```

assistant: ```c
uint16_t get_rom_size() {
  uint8_t id = get_mem(0x0148);
  return id_to_rom_size(id);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_rom_size>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x148,%edi
  call   <get_mem@plt>
  mov    %eax,%edi
  call   <id_to_rom_size@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint16_t get_rom_size() {
  uint8_t id = get_mem(0x0148);
  return id_to_rom_size(id);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_rom_size>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x148,%edi
  call   <get_mem@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <id_to_rom_size@plt>
```

assistant: ```c
uint16_t get_rom_size() {
  uint8_t id = get_mem(0x0148);
  return id_to_rom_size(id);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_rom_size>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x148,%edi
  call   <get_mem@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <id_to_rom_size@plt>
```

assistant: ```c
uint16_t get_rom_size() {
  uint8_t id = get_mem(0x0148);
  return id_to_rom_size(id);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_232_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x2(%rbp),%eax
  and    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x3(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_232_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk2 = S ^ T;
  stk3 = *D ^ S;
  stk2 = stk2 & stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_232_0_1>:
  endbr64
  mov    %edx,%eax
  xor    %esi,%eax
  mov    %esi,%ecx
  xor    (%rdi),%cl
  and    %eax,%ecx
  xor    %esi,%ecx
  mov    %edx,%eax
  not    %eax
  or     %esi,%eax
  and    %ecx,%eax
  not    %esi
  and    (%rdi),%dl
  and    %edx,%esi
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_232_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk2 = S ^ T;
  stk3 = *D ^ S;
  stk2 = stk2 & stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_232_0_1>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %edx,%eax
  xor    %esi,%eax
  xor    %esi,%ecx
  and    %eax,%ecx
  mov    %edx,%eax
  and    (%rdi),%dl
  not    %eax
  xor    %esi,%ecx
  or     %esi,%eax
  not    %esi
  and    %ecx,%eax
  and    %edx,%esi
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_232_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk2 = S ^ T;
  stk3 = *D ^ S;
  stk2 = stk2 & stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rop3_232_0_1>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %edx,%eax
  xor    %esi,%eax
  xor    %esi,%ecx
  and    %eax,%ecx
  mov    %edx,%eax
  and    (%rdi),%dl
  not    %eax
  xor    %esi,%ecx
  or     %esi,%eax
  not    %esi
  and    %ecx,%eax
  and    %edx,%esi
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_232_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk2 = S ^ T;
  stk3 = *D ^ S;
  stk2 = stk2 & stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x4(%rbp),%eax
  and    $0x3f,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int getHash(const char *key) {
  unsigned int hash;
  for (hash = 0; *key != '\0'; key++)
    hash += *key + (hash << 5);
  return hash % 64;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getHash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L19
  mov    $0x0,%eax
L4:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  movsbl %dl,%edx
  add    %ecx,%edx
  add    %edx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L4
L10:
  and    $0x3f,%eax
  ret
L19:
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
unsigned int getHash(const char *key) {
  unsigned int hash;
  for (hash = 0; *key != '\0'; key++)
    hash += *key + (hash << 5);
  return hash % 64;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getHash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L1
  nopl   (%rax)
L9:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  add    %ecx,%edx
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L9
  and    $0x3f,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
unsigned int getHash(const char *key) {
  unsigned int hash;
  for (hash = 0; *key != '\0'; key++)
    hash += *key + (hash << 5);
  return hash % 64;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getHash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L11
  nopl   (%rax)
L1:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  add    %ecx,%edx
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L1
  and    $0x3f,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
unsigned int getHash(const char *key) {
  unsigned int hash;
  for (hash = 0; *key != '\0'; key++)
    hash += *key + (hash << 5);
  return hash % 64;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D84(%rip),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L23
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L23:
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L25
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L25:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D28
data_type: string
name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D66
data_type: string
name: disassemble_data
arguments: data_label: D84
data_type: string
name: disassemble_data
arguments: data_label: D22
data_type: string
name: disassemble_data
arguments: data_label: D73
data_type: string

tool: D29: Input two integers

tool: D28: Give the First integer: 

tool: D4: %s

tool: D66: %d

tool: D84: Give the Second integer: 

tool: D22: The first integer is a multiple of the second

tool: D73: The first integer is not a multiple of the second

assistant: ```c
int main() {
  int integerA = 0;
  int integerB = 0;
  puts("Input two integers");
  printf("%s", "Give the First integer: ");
  scanf("%d", &integerA);
  printf("%s", "Give the Second integer: ");
  scanf("%d", &integerB);
  if ((integerB % integerA) == 0)
    puts("The first integer is a multiple of the second");
  if ((integerB % integerA) != 0)
    puts("The first integer is not a multiple of the second");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D69(%rip),%rsi
  lea    D57(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D62(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idivl  (%rsp)
  test   %edx,%edx
  je     L32
L24:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L32:
  lea    D54(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  cltd
  idivl  (%rsp)
  test   %edx,%edx
  jne    L24
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D69
datatype: string
name: disassemble_data
arguments: data_label: D57
datatype: string
name: disassemble_data
arguments: data_label: D62
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D32
datatype: string
name: disassemble_data
arguments: data_label: D54
datatype: string

tool: D15: Input two integers

tool: D69: Give the First integer: 

tool: D57: %s

tool: D62: %d

tool: D1: Give the Second integer: 

tool: D32: The first integer is not a multiple of the second

tool: D54: The first integer is a multiple of the second

assistant: ```c
int main() {
  int integerA = 0;
  int integerB = 0;
  puts("Input two integers");
  printf("%s", "Give the First integer: ");
  scanf("%d", &integerA);
  printf("%s", "Give the Second integer: ");
  scanf("%d", &integerB);
  if ((integerB % integerA) == 0)
    puts("The first integer is a multiple of the second");
  if ((integerB % integerA) != 0)
    puts("The first integer is not a multiple of the second");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%rdi
  lea    D53(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    D50(%rip),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D56(%rip),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idivl  (%rsp)
  test   %edx,%edx
  je     L26
L25:
  lea    D43(%rip),%rdi
  call   <puts@plt>
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  lea    D40(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  cltd
  idivl  (%rsp)
  test   %edx,%edx
  je     L38
  jmp    L25
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D29
datatype: string
name: read_data
arguments: data_label: D53
datatype: string
name: read_data
arguments: data_label: D8
datatype: string
name: read_data
arguments: data_label: D50
datatype: string
name: read_data
arguments: data_label: D56
datatype: string
name: read_data
arguments: data_label: D43
datatype: string
name: read_data
arguments: data_label: D40
datatype: string

tool: D29: Input two integers

tool: D53: %s

tool: D8: %d

tool: D50: Give the First integer: 

tool: D56: Give the Second integer: 

tool: D43: The first integer is not a multiple of the second

tool: D40: The first integer is a multiple of the second

assistant: ```c
int main() {
  int integerA = 0;
  int integerB = 0;
  puts("Input two integers");
  printf("%s", "Give the First integer: ");
  scanf("%d", &integerA);
  printf("%s", "Give the Second integer: ");
  scanf("%d", &integerB);
  if ((integerB % integerA) == 0)
    puts("The first integer is a multiple of the second");
  if ((integerB % integerA) != 0)
    puts("The first integer is not a multiple of the second");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  lea    D68(%rip),%r12
  push   %rbp
  lea    D30(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    D39(%rip),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idivl  (%rsp)
  test   %edx,%edx
  je     L24
L17:
  lea    D21(%rip),%rdi
  call   <puts@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L24:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  cltd
  idivl  (%rsp)
  test   %edx,%edx
  je     L10
  jmp    L17
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D68
datatype: string
name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D39
datatype: string
name: parse_data
arguments: data_label: D9
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D0: Input two integers

tool: D68: %s

tool: D30: %d

tool: D39: Give the First integer: 

tool: D9: Give the Second integer: 

tool: D21: The first integer is not a multiple of the second

tool: D15: The first integer is a multiple of the second

assistant: ```c
int main() {
  int integerA = 0;
  int integerB = 0;
  puts("Input two integers");
  printf("%s", "Give the First integer: ");
  scanf("%d", &integerA);
  printf("%s", "Give the Second integer: ");
  scanf("%d", &integerB);
  if ((integerB % integerA) == 0)
    puts("The first integer is a multiple of the second");
  if ((integerB % integerA) != 0)
    puts("The first integer is not a multiple of the second");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ERR_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <err_get_state_int@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <err_get_slot@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <err_clear@plt>
  jmp    L19
L17:
  nop
L19:
  leave
  ret
```

assistant: ```c
void ERR_new(void) {
  ERR_STATE *es;
  es = err_get_state_int();
  if (es == NULL)
    return;
  err_get_slot(es);
  err_clear(es, es->top, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ERR_new>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <err_get_state_int@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <err_get_slot@plt>
  mov    $0x0,%edx
  mov    (%rbx),%esi
  mov    %rbx,%rdi
  call   <err_clear@plt>
L0:
  pop    %rbx
  ret
```

assistant: ```c
void ERR_new(void) {
  ERR_STATE *es;
  es = err_get_state_int();
  if (es == NULL)
    return;
  err_get_slot(es);
  err_clear(es, es->top, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ERR_new>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <err_get_state_int@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <err_get_slot@plt>
  mov    0x0(%rbp),%esi
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  jmp    1080 <err_clear@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  pop    %rbp
  ret
```

assistant: ```c
void ERR_new(void) {
  ERR_STATE *es;
  es = err_get_state_int();
  if (es == NULL)
    return;
  err_get_slot(es);
  err_clear(es, es->top, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ERR_new>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <err_get_state_int@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <err_get_slot@plt>
  mov    0x0(%rbp),%esi
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  jmp    1080 <err_clear@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  pop    %rbp
  ret
```

assistant: ```c
void ERR_new(void) {
  ERR_STATE *es;
  es = err_get_state_int();
  if (es == NULL)
    return;
  err_get_slot(es);
  err_clear(es, es->top, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<Power_law_no_hops>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    $0x0,%eax
  call   <drand48@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  D4(%rip),%xmm0
  divsd  -0x20(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  mulsd  -0x18(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <ceil@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
datatype: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int Power_law_no_hops(double delta, double H) {
  int hop;
  double ran;
  ran = drand48();
  hop = (int)ceil(delta * pow(ran, 1 / H));
  return (hop);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Power_law_no_hops>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  mov    $0x0,%eax
  call   <drand48@plt>
  movsd  D4(%rip),%xmm1
  movq   %r14,%xmm2
  divsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%edi
  call   <pow@plt>
  movq   %rbx,%xmm3
  mulsd  %xmm3,%xmm0
  call   <ceil@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int Power_law_no_hops(double delta, double H) {
  int hop;
  double ran;
  ran = drand48();
  hop = (int)ceil(delta * pow(ran, 1 / H));
  return (hop);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Power_law_no_hops>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <drand48@plt>
  movsd  D3(%rip),%xmm1
  divsd  0x8(%rsp),%xmm1
  cvttsd2si %xmm1,%edi
  call   <pow@plt>
  mulsd  (%rsp),%xmm0
  call   <ceil@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int Power_law_no_hops(double delta, double H) {
  int hop;
  double ran;
  ran = drand48();
  hop = (int)ceil(delta * pow(ran, 1 / H));
  return (hop);
}
```