ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x100,%edi
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %al,(%rax,%rbp,1)
  add    $0x1,%rax
  mov    %rbp,%rbx
  cmp    $0x100,%rax
  jne    L43
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <acc_copyin@plt>
  test   %rax,%rax
  je     L13
L26:
  movdqa D7(%rip),%xmm0
  mov    $0x100,%esi
  xor    %edi,%edi
  lea    0x100(%rbp),%r12
  movups %xmm0,0x0(%rbp)
  movups %xmm0,0x10(%rbp)
  movups %xmm0,0x20(%rbp)
  movups %xmm0,0x30(%rbp)
  movups %xmm0,0x40(%rbp)
  movups %xmm0,0x50(%rbp)
  movups %xmm0,0x60(%rbp)
  movups %xmm0,0x70(%rbp)
  movups %xmm0,0x80(%rbp)
  movups %xmm0,0x90(%rbp)
  movups %xmm0,0xa0(%rbp)
  movups %xmm0,0xb0(%rbp)
  movups %xmm0,0xc0(%rbp)
  movups %xmm0,0xd0(%rbp)
  movups %xmm0,0xe0(%rbp)
  movups %xmm0,0xf0(%rbp)
  call   <acc_update_device@plt>
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <acc_copyout@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  cmpb   $0xab,(%rbx)
  je     L49
  xor    %eax,%eax
  call   <abort@plt>
L49:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L1
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <abort@plt>
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: byte[16]

tool: {"D7": [0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab,0xab]}

assistant: ```c
int main(int argc, char **argv) {
  const int N = 256;
  int i;
  unsigned char *h;
  void *d;
  h = (unsigned char *)malloc(N);
  for (i = 0; i < N; i++) {
    h[i] = i;
  }
  d = acc_copyin(h, N);
  if (!d)
    abort();
  for (i = 0; i < N; i++) {
    h[i] = 0xab;
  }
  acc_update_device(0, N);
  acc_copyout(h, N);
  for (i = 0; i < N; i++) {
    if (h[i] != 0xab)
      abort();
  }
  free(h);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<repstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %rdx,-0x448(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x440(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x42c(%rbp)
  mov    -0x438(%rbp),%rax
  mov    %rax,-0x428(%rbp)
  lea    -0x410(%rbp),%rax
  mov    %rax,-0x420(%rbp)
  jmp    L3
L29:
  mov    -0x440(%rbp),%rdx
  mov    -0x428(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  je     L41
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  mov    %eax,%edx
  mov    -0x428(%rbp),%rcx
  mov    -0x420(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  add    %rax,-0x420(%rbp)
  mov    -0x448(%rbp),%rdx
  mov    -0x420(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  cltq
  add    %rax,-0x420(%rbp)
  mov    -0x42c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x418(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x428(%rbp)
L3:
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  jmp    L42
L41:
  nop
L42:
  mov    -0x428(%rbp),%rax
  cmp    -0x438(%rbp),%rax
  ja     L22
  mov    $0x0,%eax
  jmp    L45
L22:
  mov    -0x428(%rbp),%rdx
  mov    -0x420(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rdx
  mov    -0x438(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: %s

assistant: ```c
int repstr(char *str, const char *pat, const char *rep) {
  int len = strlen(pat);
  char buff[1024], *p, *q, *r;
  for (p = str, r = buff; *p; p = q + len) {
    if (!(q = strstr(p, pat))) {
      break;
    }
    strncpy(r, p, q - p);
    r += q - p;
    r += sprintf(r, "%s", rep);
  }
  if (p <= str) {
    return 0;
  }
  strcpy(r, p);
  strcpy(str, buff);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<repstr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rdi,%rbx
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r14
  mov    %rdx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L31
  mov    %eax,%r15d
  lea    0x10(%rsp),%rbp
L26:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L34
  mov    %rax,%r13
  sub    %rbx,%r13
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  add    %rbp,%r13
  mov    (%rsp),%rdx
  lea    D9(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  movslq %eax,%rbp
  add    %r13,%rbp
  movslq %r15d,%rbx
  add    %r12,%rbx
  cmpb   $0x0,(%rbx)
  jne    L26
L34:
  mov    $0x0,%eax
  mov    0x8(%rsp),%r15
  cmp    %rbx,%r15
  jae    L4
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    0x10(%rsp),%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
L4:
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  mov    $0x0,%eax
  jmp    L4
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: %s

assistant: ```c
int repstr(char *str, const char *pat, const char *rep) {
  int len = strlen(pat);
  char buff[1024], *p, *q, *r;
  for (p = str, r = buff; *p; p = q + len) {
    if (!(q = strstr(p, pat))) {
      break;
    }
    strncpy(r, p, q - p);
    r += q - p;
    r += sprintf(r, "%s", rep);
  }
  if (p <= str) {
    return 0;
  }
  strcpy(r, p);
  strcpy(str, buff);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<repstr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r14,%r15
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x438,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %rsi,%rdi
  lea    0x20(%rsp),%rbp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,0x18(%rsp)
  mov    %eax,0x4(%rsp)
  mov    %r14,%rax
  lea    D3(%rip),%r14
  cmpb   $0x0,(%rax)
  jne    L13
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %rax,%r13
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%r13
  mov    %r13d,%edx
  add    %r13,%rbp
  call   <strncpy@plt>
  mov    0x8(%rsp),%rdx
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <sprintf@plt>
  movslq 0x4(%rsp),%r8
  cltq
  lea    (%r12,%r8,1),%r15
  add    %rax,%rbp
  cmpb   $0x0,(%r15)
  je     L53
L13:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L33
L53:
  mov    0x10(%rsp),%rbx
  cmp    %r15,%rbx
  jae    L41
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L30
  nop
L41:
  xor    %eax,%eax
L30:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: %s

assistant: ```c
int repstr(char *str, const char *pat, const char *rep) {
  int len = strlen(pat);
  char buff[1024], *p, *q, *r;
  for (p = str, r = buff; *p; p = q + len) {
    if (!(q = strstr(p, pat))) {
      break;
    }
    strncpy(r, p, q - p);
    r += q - p;
    r += sprintf(r, "%s", rep);
  }
  if (p <= str) {
    return 0;
  }
  strcpy(r, p);
  strcpy(str, buff);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<repstr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r14,%r15
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x438,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %rsi,%rdi
  lea    0x20(%rsp),%rbp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,0x18(%rsp)
  mov    %eax,0x4(%rsp)
  mov    %r14,%rax
  lea    D2(%rip),%r14
  cmpb   $0x0,(%rax)
  jne    L8
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rax,%r13
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%r13
  mov    %r13d,%edx
  add    %r13,%rbp
  call   <strncpy@plt>
  mov    0x8(%rsp),%rdx
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <sprintf@plt>
  movslq 0x4(%rsp),%r8
  cltq
  lea    (%r12,%r8,1),%r15
  add    %rax,%rbp
  cmpb   $0x0,(%r15)
  je     L22
L8:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L11
L22:
  mov    0x10(%rsp),%rbx
  cmp    %r15,%rbx
  jae    L29
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L44
  nop
L29:
  xor    %eax,%eax
L44:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D2: %s

assistant: ```c
int repstr(char *str, const char *pat, const char *rep) {
  int len = strlen(pat);
  char buff[1024], *p, *q, *r;
  for (p = str, r = buff; *p; p = q + len) {
    if (!(q = strstr(p, pat))) {
      break;
    }
    strncpy(r, p, q - p);
    r += q - p;
    r += sprintf(r, "%s", rep);
  }
  if (p <= str) {
    return 0;
  }
  strcpy(r, p);
  strcpy(str, buff);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L85
  cmpl   $0x3,-0x4(%rbp)
  je     L85
  cmpl   $0x5,-0x4(%rbp)
  je     L85
  cmpl   $0x7,-0x4(%rbp)
  jne    L127
L85:
  mov    $0x1,%eax
  jmp    L49
L127:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L28
  mov    $0x0,%eax
  jmp    L49
L28:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L121
  mov    $0x0,%eax
  jmp    L49
L121:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L82
  mov    $0x0,%eax
  jmp    L49
L82:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L79
  mov    $0x0,%eax
  jmp    L49
L79:
  mov    $0x1,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
bool isPrime(int n) {
  if (n == 2 || n == 3 || n == 5 || n == 7) {
    return true;
  }
  if (n % 2 == 0) {
    return false;
  }
  if (n % 3 == 0) {
    return false;
  }
  if (n % 5 == 0) {
    return false;
  }
  if (n % 7 == 0) {
    return false;
  } else {
    return true;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPrime>:
  endbr64
  lea    -0x2(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L42
  mov    %edi,%eax
  and    $0xfffffffd,%eax
  cmp    $0x5,%eax
  je     L42
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L41
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edi,%eax
  sub    %ecx,%eax
  je     L41
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edi,%eax
  sub    %ecx,%eax
  je     L41
  movslq %edi,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x2,%eax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  cmp    %ecx,%edi
  setne  %al
  movzbl %al,%eax
  ret
L42:
  mov    $0x1,%eax
L41:
  ret
```

assistant: ```c
bool isPrime(int n) {
  if (n == 2 || n == 3 || n == 5 || n == 7) {
    return true;
  }
  if (n % 2 == 0) {
    return false;
  }
  if (n % 3 == 0) {
    return false;
  }
  if (n % 5 == 0) {
    return false;
  }
  if (n % 7 == 0) {
    return false;
  } else {
    return true;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPrime>:
  endbr64
  lea    -0x2(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L25
  mov    %edi,%eax
  and    $0xfffffffd,%eax
  cmp    $0x5,%eax
  je     L25
  xor    %eax,%eax
  test   $0x1,%dil
  je     L33
  movslq %edi,%rsi
  mov    %edi,%ecx
  imul   $0x55555556,%rsi,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L33
  imul   $0x66666667,%rsi,%rax
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L33
  imul   $0xb6db6db7,%edi,%edi
  xor    %eax,%eax
  add    $0x12492492,%edi
  cmp    $0x24924924,%edi
  seta   %al
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x1,%eax
L33:
  ret
```

assistant: ```c
bool isPrime(int n) {
  if (n == 2 || n == 3 || n == 5 || n == 7) {
    return true;
  }
  if (n % 2 == 0) {
    return false;
  }
  if (n % 3 == 0) {
    return false;
  }
  if (n % 5 == 0) {
    return false;
  }
  if (n % 7 == 0) {
    return false;
  } else {
    return true;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isPrime>:
  endbr64
  lea    -0x2(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L2
  mov    %edi,%eax
  and    $0xfffffffd,%eax
  cmp    $0x5,%eax
  je     L2
  xor    %eax,%eax
  test   $0x1,%dil
  je     L23
  movslq %edi,%rsi
  mov    %edi,%ecx
  imul   $0x55555556,%rsi,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L23
  imul   $0x66666667,%rsi,%rax
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L23
  imul   $0xb6db6db7,%edi,%edi
  xor    %eax,%eax
  add    $0x12492492,%edi
  cmp    $0x24924924,%edi
  seta   %al
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%eax
L23:
  ret
```

assistant: ```c
bool isPrime(int n) {
  if (n == 2 || n == 3 || n == 5 || n == 7) {
    return true;
  }
  if (n % 2 == 0) {
    return false;
  }
  if (n % 3 == 0) {
    return false;
  }
  if (n % 5 == 0) {
    return false;
  }
  if (n % 7 == 0) {
    return false;
  } else {
    return true;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x20000(%rsp),%r11
L2:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L2
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20050(%rbp),%rax
  mov    %rax,%rdi
  call   <Foo@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main() {
  int ary[(32 * 32 * 32 + 17)];
  Foo(ary);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  lea    -0x20000(%rsp),%r11
L7:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L7
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20048(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <Foo@plt>
  mov    0x20048(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x20058,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int ary[(32 * 32 * 32 + 17)];
  Foo(ary);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  lea    -0x20000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20048(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <Foo@plt>
  mov    0x20048(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x20058,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int ary[(32 * 32 * 32 + 17)];
  Foo(ary);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  lea    -0x20000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20048(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <Foo@plt>
  mov    0x20048(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x20058,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int ary[(32 * 32 * 32 + 17)];
  Foo(ary);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<interp_cubic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  movss  %xmm2,-0x2c(%rbp)
  movss  %xmm3,-0x30(%rbp)
  movss  %xmm4,-0x34(%rbp)
  movss  -0x34(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x24(%rbp),%xmm0
  movss  D13(%rip),%xmm1
  xorps  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x28(%rbp),%xmm2
  movsd  D8(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x2c(%rbp),%xmm2
  movsd  D8(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x30(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x24(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x28(%rbp),%xmm2
  movsd  D33(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x2c(%rbp),%xmm2
  movsd  D1(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0x30(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x2c(%rbp),%xmm0
  subss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x28(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x34(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x8(%rbp),%xmm0
  mulss  -0x34(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  addss  -0x4(%rbp),%xmm1
  movss  D7(%rip),%xmm0
  mulss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_guessed: byte[4]
name: extract_symbolic_data
arguments: label: D8
type_guessed: f64
name: extract_symbolic_data
arguments: label: D33
type_guessed: f64
name: extract_symbolic_data
arguments: label: D1
type_guessed: f64
name: extract_symbolic_data
arguments: label: D7
type_guessed: f32

tool: {"D13": [0x00,0x00,0x00,0x80]}

tool: D8: 3

tool: D33: 5

tool: D1: 4

tool: D7: 0.5

assistant: ```c
float interp_cubic(float a, float b, float c, float d, float t) {
  float x, y, z, w;
  float tsq = t * t;
  x = -a + 3.0 * b - 3.0 * c + d;
  y = 2.0 * a - 5.0 * b + 4.0 * c - d;
  z = c - a;
  w = 2.0 * b;
  return 0.5 * (x * tsq * t + y * tsq + z * t + w);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<interp_cubic>:
  endbr64
  movaps %xmm0,%xmm6
  movaps %xmm4,%xmm7
  mulss  %xmm4,%xmm7
  pxor   %xmm10,%xmm10
  cvtss2sd %xmm1,%xmm10
  pxor   %xmm9,%xmm9
  cvtss2sd %xmm2,%xmm9
  pxor   %xmm8,%xmm8
  cvtss2sd %xmm3,%xmm8
  movaps %xmm0,%xmm5
  xorps  D38(%rip),%xmm5
  cvtss2sd %xmm5,%xmm5
  movsd  D9(%rip),%xmm0
  movapd %xmm10,%xmm3
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm5
  mulsd  %xmm9,%xmm0
  subsd  %xmm0,%xmm5
  addsd  %xmm8,%xmm5
  cvtsd2ss %xmm5,%xmm5
  mulss  %xmm7,%xmm5
  movaps %xmm5,%xmm0
  mulss  %xmm4,%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd %xmm6,%xmm5
  addsd  %xmm5,%xmm5
  mulsd  D39(%rip),%xmm10
  subsd  %xmm10,%xmm5
  mulsd  D21(%rip),%xmm9
  movapd %xmm5,%xmm3
  addsd  %xmm9,%xmm3
  subsd  %xmm8,%xmm3
  cvtsd2ss %xmm3,%xmm3
  mulss  %xmm7,%xmm3
  addss  %xmm3,%xmm0
  movaps %xmm0,%xmm5
  subss  %xmm6,%xmm2
  mulss  %xmm4,%xmm2
  addss  %xmm2,%xmm5
  addss  %xmm1,%xmm1
  addss  %xmm1,%xmm5
  movaps %xmm5,%xmm0
  mulss  D45(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D38
datatype: byte[16]
name: disassemble_data
arguments: data_label: D9
datatype: f64
name: disassemble_data
arguments: data_label: D39
datatype: f64
name: disassemble_data
arguments: data_label: D21
datatype: f64
name: disassemble_data
arguments: data_label: D45
datatype: f32

tool: {"D38": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D9: 3

tool: D39: 5

tool: D21: 4

tool: D45: 0.5

assistant: ```c
float interp_cubic(float a, float b, float c, float d, float t) {
  float x, y, z, w;
  float tsq = t * t;
  x = -a + 3.0 * b - 3.0 * c + d;
  y = 2.0 * a - 5.0 * b + 4.0 * c - d;
  z = c - a;
  w = 2.0 * b;
  return 0.5 * (x * tsq * t + y * tsq + z * t + w);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interp_cubic>:
  endbr64
  movaps %xmm0,%xmm6
  movaps %xmm0,%xmm5
  pxor   %xmm9,%xmm9
  movsd  D34(%rip),%xmm0
  cvtss2sd %xmm1,%xmm9
  movapd %xmm9,%xmm10
  pxor   %xmm8,%xmm8
  movaps %xmm4,%xmm7
  mulsd  %xmm0,%xmm10
  cvtss2sd %xmm2,%xmm8
  cvtss2sd %xmm3,%xmm3
  subss  %xmm6,%xmm2
  mulsd  %xmm8,%xmm0
  xorps  D21(%rip),%xmm5
  addss  %xmm1,%xmm1
  mulss  %xmm4,%xmm7
  cvtss2sd %xmm5,%xmm5
  mulss  %xmm4,%xmm2
  mulsd  D47(%rip),%xmm9
  mulsd  D30(%rip),%xmm8
  addsd  %xmm10,%xmm5
  subsd  %xmm0,%xmm5
  addsd  %xmm3,%xmm5
  cvtsd2ss %xmm5,%xmm5
  mulss  %xmm7,%xmm5
  movaps %xmm5,%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd %xmm6,%xmm5
  addsd  %xmm5,%xmm5
  mulss  %xmm4,%xmm0
  subsd  %xmm9,%xmm5
  addsd  %xmm8,%xmm5
  subsd  %xmm3,%xmm5
  pxor   %xmm3,%xmm3
  cvtsd2ss %xmm5,%xmm3
  mulss  %xmm7,%xmm3
  addss  %xmm3,%xmm0
  movaps %xmm0,%xmm5
  movss  D15(%rip),%xmm0
  addss  %xmm2,%xmm5
  addss  %xmm1,%xmm5
  mulss  %xmm5,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
data_type: f64
name: extract_symbolic_data
arguments: tag: D21
data_type: byte[16]
name: extract_symbolic_data
arguments: tag: D47
data_type: f64
name: extract_symbolic_data
arguments: tag: D30
data_type: f64
name: extract_symbolic_data
arguments: tag: D15
data_type: f32

tool: D34: 3

tool: {"D21": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D47: 5

tool: D30: 4

tool: D15: 0.5

assistant: ```c
float interp_cubic(float a, float b, float c, float d, float t) {
  float x, y, z, w;
  float tsq = t * t;
  x = -a + 3.0 * b - 3.0 * c + d;
  y = 2.0 * a - 5.0 * b + 4.0 * c - d;
  z = c - a;
  w = 2.0 * b;
  return 0.5 * (x * tsq * t + y * tsq + z * t + w);
}
```