ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x11b,%ecx
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  nopl   0x0(%rax)
L33:
  mov    %ebx,%edi
  cmp    $0x237,%rbx
  je     L64
L30:
  cmp    $0x59,%rbx
  je     L69
  nopl   0x0(%rax)
L59:
  call   <square_digits@plt>
  mov    %eax,%edi
  cmp    $0x59,%eax
  je     L69
  cmp    $0x1,%eax
  jne    L59
L69:
  add    $0x1,%rbx
  cmp    $0x59,%edi
  jne    L33
  movl   $0x1,-0x4(%rbp,%rbx,4)
  mov    %ebx,%edi
  cmp    $0x237,%rbx
  jne    L30
L64:
  xor    %ebp,%ebp
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L62:
  mov    %ebx,%edi
  call   <square_digits@plt>
  cltq
  cmpl   $0x1,(%rsp,%rax,4)
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    $0x989680,%ebx
  jne    L62
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x8f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int main(void) {
  int cache[567] = {0};
  int i;
  for (i = 1; i < 567; ++i) {
    int t = i;
    while (t != 89 && t != 1)
      t = square_digits(t);
    if (t == 89)
      cache[i] = 1;
  }
  int sum = 0;
  for (i = 1; i < 10000000; ++i) {
    int t = square_digits(i);
    if (cache[t])
      ++sum;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L12
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L12:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max(int num1, int num2) {
  int result;
  if (num1 > num2)
    result = num1;
  else
    result = num2;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int num1, int num2) {
  int result;
  if (num1 > num2)
    result = num1;
  else
    result = num2;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int num1, int num2) {
  int result;
  if (num1 > num2)
    result = num1;
  else
    result = num2;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int num1, int num2) {
  int result;
  if (num1 > num2)
    result = num1;
  else
    result = num2;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L27
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L20
L27:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <pat@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D19: %d

tool: D6: 0

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n == 0)
    printf("0");
  else
    pat(n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jne    L28
  lea    D15(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L28:
  call   <pat@plt>
  jmp    L20
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D15
type_infered: string

tool: D6: %d

tool: D15: 0

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n == 0)
    printf("0");
  else
    pat(n);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jne    L9
  lea    D14(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <pat@plt>
  jmp    L21
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D14
datatype: string

tool: D5: %d

tool: D14: 0

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n == 0)
    printf("0");
  else
    pat(n);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jne    L26
  lea    D17(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L26:
  call   <pat@plt>
  jmp    L13
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string

tool: D18: %d

tool: D17: 0

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n == 0)
    printf("0");
  else
    pat(n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L99:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L99
L13:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L3
  orq    $0x0,-0x8(%rsp,%rax,1)
L3:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L45
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,4),%r15
  jmp    L58
L105:
  mov    $0x0,%eax
  call   <rand_float@plt>
  mulss  D28(%rip),%xmm0
  subss  D2(%rip),%xmm0
L49:
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %r15,%rbx
  je     L45
L58:
  mov    $0x0,%eax
  call   <rand_float@plt>
  movss  D38(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L105
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  jmp    L49
L45:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L46
  mov    $0x0,%ebx
L60:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <stdlib_strided_snanmax@plt>
  ucomiss %xmm0,%xmm0
  jp     L95
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L60
L46:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
L69:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L95:
  lea    D30(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm3
  subsd  %xmm3,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L69
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D28
type_infered: byte[4]
name: unpack_data
arguments: data_tag: D2
type_infered: byte[4]
name: unpack_data
arguments: data_tag: D38
type_infered: byte[4]
name: unpack_data
arguments: data_tag: D30
type_infered: string

tool: {"D28": [0x00,0x40,0x9c,0x46]}

tool: {"D2": [0x00,0x40,0x1c,0x46]}

tool: {"D38": [0xcd,0xcc,0x4c,0x3e]}

tool: D30: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    if (rand_float() < 0.2f) {
      x[i] = 0.0f / 0.0f;
    } else {
      x[i] = (rand_float() * 20000.0f) - 10000.0f;
    }
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_snanmax(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L13
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L6
L13:
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string
name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D9: 2 args needed

tool: D5: strstr(%s,%s) : %s


tool: D6: strlen(%s) : %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("2 args needed\n");
    return 1;
  }
  printf("strstr(%s,%s) : %s\n", argv[1], argv[2], strstr(argv[1], argv[2]));
  ;
  printf("strlen(%s) : %d\n", argv[1], strlen(argv[1]));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x3,%edi
  je     L0
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    %rsi,%rbx
  mov    0x10(%rsi),%r12
  mov    0x8(%rsi),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    0x8(%rbx),%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D25
type: string

tool: D0: 2 args needed

tool: D17: strstr(%s,%s) : %s


tool: D25: strlen(%s) : %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("2 args needed\n");
    return 1;
  }
  printf("strstr(%s,%s) : %s\n", argv[1], argv[2], strstr(argv[1], argv[2]));
  ;
  printf("strlen(%s) : %d\n", argv[1], strlen(argv[1]));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x3,%edi
  je     L19
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%r12
  mov    %rsi,%rbx
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  mov    0x8(%rbx),%rsi
  lea    D10(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L13
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string

tool: D4: 2 args needed

tool: D1: strstr(%s,%s) : %s


tool: D10: strlen(%s) : %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("2 args needed\n");
    return 1;
  }
  printf("strstr(%s,%s) : %s\n", argv[1], argv[2], strstr(argv[1], argv[2]));
  ;
  printf("strlen(%s) : %d\n", argv[1], strlen(argv[1]));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x3,%edi
  je     L9
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%r12
  mov    %rsi,%rbx
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  mov    0x8(%rbx),%rsi
  lea    D16(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string

tool: D0: 2 args needed

tool: D4: strstr(%s,%s) : %s


tool: D16: strlen(%s) : %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("2 args needed\n");
    return 1;
  }
  printf("strstr(%s,%s) : %s\n", argv[1], argv[2], strstr(argv[1], argv[2]));
  ;
  printf("strlen(%s) : %d\n", argv[1], strlen(argv[1]));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rpl_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void rpl_free(void *p) {
  if (p)
    free(p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rpl_free>:
  endbr64
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
void rpl_free(void *p) {
  if (p)
    free(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rpl_free>:
  endbr64
  test   %rdi,%rdi
  je     L8
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void rpl_free(void *p) {
  if (p)
    free(p);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rpl_free>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L3:
  ret
```

assistant: ```c
void rpl_free(void *p) {
  if (p)
    free(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L13
L18:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L13:
  leave
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strnlen(s, n);
  char *new = malloc(len + 1);
  if (new == NULL)
    return NULL;
  new[len] = '\0';
  return memcpy(new, s, len);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strndup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strnlen@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  movb   $0x0,(%rax,%rbx,1)
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strnlen(s, n);
  char *new = malloc(len + 1);
  if (new == NULL)
    return NULL;
  new[len] = '\0';
  return memcpy(new, s, len);
}
```
user: What is the c source code of the assembly code below?

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strnlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
L4:
  pop    %rdx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strnlen(s, n);
  char *new = malloc(len + 1);
  if (new == NULL)
    return NULL;
  new[len] = '\0';
  return memcpy(new, s, len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strnlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
  call   <malloc@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
L5:
  pop    %rdx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strnlen(s, n);
  char *new = malloc(len + 1);
  if (new == NULL)
    return NULL;
  new[len] = '\0';
  return memcpy(new, s, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <nearly_main@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  nearly_main();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nearly_main@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  nearly_main();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nearly_main@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  nearly_main();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nearly_main@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  nearly_main();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insert_edge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insert_edge(unsigned edge[2], unsigned a, unsigned b) {
  edge[0] = a;
  edge[1] = b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_edge>:
  endbr64
  mov    %esi,(%rdi)
  mov    %edx,0x4(%rdi)
  ret
```

assistant: ```c
void insert_edge(unsigned edge[2], unsigned a, unsigned b) {
  edge[0] = a;
  edge[1] = b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insert_edge>:
  endbr64
  mov    %esi,(%rdi)
  mov    %edx,0x4(%rdi)
  ret
```

assistant: ```c
void insert_edge(unsigned edge[2], unsigned a, unsigned b) {
  edge[0] = a;
  edge[1] = b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<insert_edge>:
  endbr64
  movd   %esi,%xmm0
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  ret
```

assistant: ```c
void insert_edge(unsigned edge[2], unsigned a, unsigned b) {
  edge[0] = a;
  edge[1] = b;
}
```
user: What is the c source code of the assembly code below?

```asm
<systemInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <wdtInit@plt>
  mov    $0x0,%eax
  call   <cpuInit@plt>
  mov    $0x8ca0,%edi
  call   <systickInit@plt>
  mov    $0x0,%eax
  call   <gpioInit@plt>
  mov    $0x0,%eax
  call   <pmuInit@plt>
  mov    $0x0,%eax
  call   <adcInit@plt>
  mov    $0x1c200,%edi
  call   <uartInit@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <gpioSetDir@plt>
  mov    $0x1,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <gpioSetDir@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <gpioSetValue@plt>
  mov    $0x0,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <gpioSetValue@plt>
  mov    $0x0,%eax
  call   <mcp24aaInit@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdx
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <cmdInit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D24
type_infered: string

tool: D20: 


tool: D24: %sType '?' for a list of available commands%s

assistant: ```c
void systemInit() {
  wdtInit();
  cpuInit();
  systickInit(((36000000) / 1000) * (1));
  gpioInit();
  pmuInit();
  adcInit();
  uartInit((115200));
  gpioSetDir((1), (5) - 1, 1);
  gpioSetDir((1), (5), 1);
  gpioSetValue((1), (5) - 1, (1));
  gpioSetValue((1), (5), (0));
  mcp24aaInit();
  printf("%sType '?' for a list of available commands%s", "\r\n", "\r\n");
  cmdInit();
}
```