user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<merge>:
  endbr64
  mov    %r8d,%eax
  push   %r15
  mov    %esi,%r15d
  sub    %edx,%eax
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  add    $0x1,%eax
  mov    %r8d,%r13d
  push   %r12
  imul   %esi,%eax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  lea    0x1(%rcx),%ebx
  sub    $0x38,%rsp
  mov    %rdi,(%rsp)
  mov    %eax,%edi
  mov    %edx,0x28(%rsp)
  mov    %r9,0x20(%rsp)
  mov    %eax,0x2c(%rsp)
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L74
  cmp    %r14d,%ebp
  jle    L63
  cmp    %r13d,%ebx
  jg     L43
L63:
  mov    %r14d,0x10(%rsp)
  mov    0x28(%rsp),%ebp
  xor    %r12d,%r12d
  mov    %r13d,0x14(%rsp)
L76:
  cmp    %ebp,0x10(%rsp)
  jl     L60
L15:
  mov    %r15d,%edx
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rcx
  imul   %ebp,%edx
  movslq %edx,%rdx
  lea    (%rax,%rdx,1),%r9
  mov    %r15d,%eax
  imul   %r12d,%eax
  add    $0x1,%r12d
  cltq
  lea    (%rcx,%rax,1),%r13
  cmp    %ebx,0x14(%rsp)
  jl     L96
  mov    %r15d,%esi
  mov    (%rsp),%rax
  mov    %r9,0x18(%rsp)
  mov    %r9,%rdi
  imul   %ebx,%esi
  movslq %esi,%rsi
  lea    (%rax,%rsi,1),%r14
  mov    0x20(%rsp),%rax
  mov    %r14,%rsi
  call   *%rax
  mov    %r15d,%edx
  test   %eax,%eax
  js     L17
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <memcpy@plt>
  cmp    %ebp,0x10(%rsp)
  jge    L15
L60:
  mov    0x14(%rsp),%r13d
  cmp    %ebx,%r13d
  jl     L43
  mov    %r15d,%edx
  imul   %r15d,%r12d
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%rbp
  imul   %ebx,%edx
  movslq %r15d,%r14
  sub    %rcx,%rbp
  movslq %r12d,%rax
  movslq %edx,%rdx
  lea    (%rcx,%rax,1),%r12
  add    %rdx,%rbp
  sub    %rax,%rbp
  nopl   0x0(%rax)
L83:
  lea    (%r12,%rbp,1),%rsi
  mov    %r12,%rdi
  mov    %r15d,%edx
  add    $0x1,%ebx
  call   <memcpy@plt>
  add    %r14,%r12
  cmp    %ebx,%r13d
  jge    L83
L43:
  mov    0x28(%rsp),%eax
  mov    0x8(%rsp),%rbx
  mov    (%rsp),%rdi
  mov    0x2c(%rsp),%edx
  imul   %r15d,%eax
  mov    %rbx,%rsi
  cltq
  add    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  xor    %eax,%eax
L95:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L17:
  mov    0x18(%rsp),%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <memcpy@plt>
  jmp    L76
  nopl   (%rax)
L96:
  mov    (%rsp),%rbx
  mov    0x10(%rsp),%r14d
  movslq %r15d,%r12
  sub    %rcx,%rbx
  add    %rdx,%rbx
  sub    %rax,%rbx
  nopl   (%rax)
L117:
  lea    0x0(%r13,%rbx,1),%rsi
  mov    %r13,%rdi
  mov    %r15d,%edx
  add    $0x1,%ebp
  call   <memcpy@plt>
  add    %r12,%r13
  cmp    %ebp,%r14d
  jge    L117
  jmp    L43
L74:
  mov    $0xffffffff,%eax
  jmp    L95
```

assistant: ```c
int merge(void *data, int esize, int i, int j, int k, int (*compare)(const void *key1, const void *key2)) {
  char *a = data, *m;
  int ipos, jpos, mpos;
  ipos = i;
  jpos = j + 1;
  mpos = 0;
  if ((m = (char *)malloc(esize * (k - i + 1))) == NULL)
    return -1;
  while (ipos <= j || jpos <= k) {
    if (ipos > j) {
      while (jpos <= k) {
        memcpy(&m[mpos * esize], &a[jpos * esize], esize);
        jpos++;
        mpos++;
      }
      continue;
    } else if (jpos > k) {
      while (ipos <= j) {
        memcpy(&m[mpos * esize], &a[ipos * esize], esize);
        ipos++;
        mpos++;
      }
      continue;
    }
    if (compare(&a[ipos * esize], &a[jpos * esize]) < 0) {
      memcpy(&m[mpos * esize], &a[ipos * esize], esize);
      ipos++;
      mpos++;
    } else {
      memcpy(&m[mpos * esize], &a[jpos * esize], esize);
      jpos++;
      mpos++;
    }
  }
  memcpy(&a[i * esize], m, esize * (k - i + 1));
  free(m);
  return 0;
}
```