ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<__no_val_copy_1_alter>:
  endbr64
  mov    D8(%rip),%rax
  lea    0x1(%rax),%rcx
  mov    %rax,(%rdx)
  mov    %rcx,D5(%rip)
  ret
```

assistant: ```c
void __no_val_copy_1_alter(void *cc, void *k, void *v, bool n) {
  static int64_t i = 0;
  *(int64_t *)v = i++;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__no_val_copy_1_alter>:
  endbr64
  mov    D16(%rip),%rax
  lea    0x1(%rax),%rcx
  mov    %rax,(%rdx)
  mov    %rcx,D8(%rip)
  ret
```

assistant: ```c
void __no_val_copy_1_alter(void *cc, void *k, void *v, bool n) {
  static int64_t i = 0;
  *(int64_t *)v = i++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<relax_jacobi_plusresidual>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  cmp    $0x1,%ebx
  jbe    L20
  mov    %rsi,%r8
  mov    %ecx,%r11d
  lea    -0x2(%rcx,%rcx,1),%ecx
  mov    %r11d,%eax
  neg    %eax
  pxor   %xmm1,%xmm1
  mov    $0x1,%r10d
  lea    -0x1(%r11),%r12d
  lea    0x2(%rax,%rax,1),%r13d
  mov    $0x2,%ebp
  sub    %r11d,%ebp
  lea    0x1(%r11),%r9d
  movsd  D4(%rip),%xmm2
  jmp    L51
L11:
  lea    0x0(%rbp,%rcx,1),%edx
  mov    %edx,%eax
  lea    0x1(%rcx,%r13,1),%esi
  sub    %edx,%esi
L0:
  lea    (%rsi,%rax,1),%r14d
  lea    (%r9,%rax,1),%edx
  movsd  (%rdi,%r14,8),%xmm0
  addsd  (%rdi,%rdx,8),%xmm0
  mov    %eax,%r14d
  add    $0x1,%eax
  mov    %eax,%edx
  mov    %r14d,%r15d
  addsd  (%rdi,%r15,8),%xmm0
  lea    0x2(%r14),%r14d
  addsd  (%rdi,%r14,8),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%r8,%rdx,8)
  subsd  (%rdi,%rdx,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %ecx,%eax
  jne    L0
L31:
  add    $0x1,%r10d
  add    %r11d,%ecx
  cmp    %ebx,%r10d
  je     L8
L51:
  cmp    $0x1,%r12d
  ja     L11
  jmp    L31
L20:
  pxor   %xmm1,%xmm1
L8:
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: f64

tool: D4: 0.25

assistant: ```c
double relax_jacobi_plusresidual(double *u, double *utmp, unsigned sizex, unsigned sizey) {
  int i, j;
  double diff, sum = 0.0;
  for (j = 1; j < sizex - 1; j++) {
    for (i = 1; i < sizey - 1; i++) {
      utmp[i + j * sizey] = 0.25 * (u[i + (j - 1) * sizey] + u[i + (j + 1) * sizey] + u[(i - 1) + j * sizey] + u[(i + 1) + j * sizey]);
      diff = utmp[i + j * sizey] - u[i + j * sizey];
      sum += diff * diff;
    }
  }
  double *temp = u;
  u = utmp;
  utmp = temp;
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<relax_jacobi_plusresidual>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  cmp    $0x1,%ebx
  jbe    L34
  mov    %ecx,%r11d
  mov    $0x2,%ebp
  lea    -0x1(%rcx),%r12d
  mov    %rsi,%r8
  mov    %r11d,%eax
  lea    -0x2(%rcx,%rcx,1),%ecx
  pxor   %xmm1,%xmm1
  sub    %r11d,%ebp
  neg    %eax
  movsd  D9(%rip),%xmm2
  mov    $0x1,%r10d
  lea    0x1(%r11),%r9d
  lea    0x2(%rax,%rax,1),%r13d
L15:
  add    $0x1,%r10d
  cmp    $0x1,%r12d
  jbe    L19
  lea    0x0(%rbp,%rcx,1),%eax
  lea    0x1(%rcx,%r13,1),%esi
  sub    %eax,%esi
  nopl   (%rax)
L37:
  lea    (%rsi,%rax,1),%r14d
  mov    %eax,%r15d
  lea    (%r9,%rax,1),%edx
  movsd  (%rdi,%r14,8),%xmm0
  mov    %r15,%r14
  addsd  (%rdi,%rdx,8),%xmm0
  lea    0x1(%rax),%edx
  add    $0x2,%r14d
  addsd  (%rdi,%r15,8),%xmm0
  mov    %rdx,%rax
  addsd  (%rdi,%r14,8),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%r8,%rdx,8)
  subsd  (%rdi,%rdx,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %ecx,%edx
  jne    L37
L19:
  add    %r11d,%ecx
  cmp    %r10d,%ebx
  jne    L15
  pop    %rbx
  movapd %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  pxor   %xmm1,%xmm1
  pop    %rbx
  pop    %rbp
  movapd %xmm1,%xmm0
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: f64

tool: D9: 0.25

assistant: ```c
double relax_jacobi_plusresidual(double *u, double *utmp, unsigned sizex, unsigned sizey) {
  int i, j;
  double diff, sum = 0.0;
  for (j = 1; j < sizex - 1; j++) {
    for (i = 1; i < sizey - 1; i++) {
      utmp[i + j * sizey] = 0.25 * (u[i + (j - 1) * sizey] + u[i + (j + 1) * sizey] + u[(i - 1) + j * sizey] + u[(i + 1) + j * sizey]);
      diff = utmp[i + j * sizey] - u[i + j * sizey];
      sum += diff * diff;
    }
  }
  double *temp = u;
  u = utmp;
  utmp = temp;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<relax_jacobi_plusresidual>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  cmp    $0x1,%ebx
  jbe    L19
  mov    %ecx,%r11d
  mov    $0x2,%ebp
  lea    -0x1(%rcx),%r12d
  mov    %rsi,%r8
  mov    %r11d,%eax
  lea    -0x2(%rcx,%rcx,1),%ecx
  pxor   %xmm1,%xmm1
  sub    %r11d,%ebp
  neg    %eax
  movsd  D4(%rip),%xmm2
  mov    $0x1,%r10d
  lea    0x1(%r11),%r9d
  lea    0x2(%rax,%rax,1),%r13d
L34:
  add    $0x1,%r10d
  cmp    $0x1,%r12d
  jbe    L3
  lea    0x0(%rbp,%rcx,1),%eax
  lea    0x1(%rcx,%r13,1),%esi
  sub    %eax,%esi
  nopl   (%rax)
L10:
  lea    (%rsi,%rax,1),%r14d
  mov    %eax,%r15d
  lea    (%r9,%rax,1),%edx
  movsd  (%rdi,%r14,8),%xmm0
  mov    %r15,%r14
  addsd  (%rdi,%rdx,8),%xmm0
  lea    0x1(%rax),%edx
  add    $0x2,%r14d
  addsd  (%rdi,%r15,8),%xmm0
  mov    %rdx,%rax
  addsd  (%rdi,%r14,8),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%r8,%rdx,8)
  subsd  (%rdi,%rdx,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %ecx,%edx
  jne    L10
L3:
  add    %r11d,%ecx
  cmp    %r10d,%ebx
  jne    L34
  pop    %rbx
  movapd %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  pxor   %xmm1,%xmm1
  pop    %rbx
  pop    %rbp
  movapd %xmm1,%xmm0
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: f64

tool: D4: 0.25

assistant: ```c
double relax_jacobi_plusresidual(double *u, double *utmp, unsigned sizex, unsigned sizey) {
  int i, j;
  double diff, sum = 0.0;
  for (j = 1; j < sizex - 1; j++) {
    for (i = 1; i < sizey - 1; i++) {
      utmp[i + j * sizey] = 0.25 * (u[i + (j - 1) * sizey] + u[i + (j + 1) * sizey] + u[(i - 1) + j * sizey] + u[(i + 1) + j * sizey]);
      diff = utmp[i + j * sizey] - u[i + j * sizey];
      sum += diff * diff;
    }
  }
  double *temp = u;
  u = utmp;
  utmp = temp;
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x2,-0x40(%rbp)
  movl   $0xffffffff,-0x3c(%rbp)
  lea    -0x40(%rbp),%rax
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <all_positive@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void main() {
  int array[11] = {2, -1};
  all_positive(&array, 11);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  movl   $0x2,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0xb,%esi
  call   <all_positive@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  int array[11] = {2, -1};
  all_positive(&array, 11);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  pxor   %xmm0,%xmm0
  mov    $0xb,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xffffffff00000002,%rax
  mov    %rsp,%rdi
  movl   $0x0,0x28(%rsp)
  movups %xmm0,0x8(%rsp)
  movups %xmm0,0x18(%rsp)
  mov    %rax,(%rsp)
  call   <all_positive@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  int array[11] = {2, -1};
  all_positive(&array, 11);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  pxor   %xmm0,%xmm0
  mov    $0xb,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %rsp,%rdi
  movups %xmm0,0x8(%rsp)
  movl   $0x0,0x28(%rsp)
  mov    %rax,(%rsp)
  movups %xmm0,0x18(%rsp)
  call   <all_positive@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x48,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: byte[8]

tool: {"D9": [0x02,0x00,0x00,0x00,0xff,0xff,0xff,0xff]}

assistant: ```c
void main() {
  int array[11] = {2, -1};
  all_positive(&array, 11);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <Line_create_with_text@plt>
  mov    %rax,-0x18(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <Line_create_with_text@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <Line_set_index@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <Line_set_index@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Line_print@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <Line_print@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Line_write@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Line_write@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Line_destory@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <Line_destory@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D37
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string

tool: D9: hello world


tool: D7: code is poetry


tool: D37: w

tool: D2: line_test.out

assistant: ```c
int main() {
  struct Line *line1 = Line_create_with_text("hello world\n");
  struct Line *line2 = Line_create_with_text("code is poetry\n");
  Line_set_index(line1, 1);
  Line_set_index(line2, 2);
  Line_print(line1);
  Line_print(line2);
  FILE *fp = fopen("line_test.out", "w");
  Line_write(line1, fp);
  Line_write(line2, fp);
  Line_destory(line1);
  Line_destory(line2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D30(%rip),%rdi
  call   <Line_create_with_text@plt>
  mov    %rax,%rbp
  lea    D35(%rip),%rdi
  call   <Line_create_with_text@plt>
  mov    %rax,%rbx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <Line_set_index@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <Line_set_index@plt>
  mov    %rbp,%rdi
  call   <Line_print@plt>
  mov    %rbx,%rdi
  call   <Line_print@plt>
  lea    D24(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <Line_write@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <Line_write@plt>
  mov    %rbp,%rdi
  call   <Line_destory@plt>
  mov    %rbx,%rdi
  call   <Line_destory@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D30
type: string
name: parse_data
arguments: data_tag: D35
type: string
name: parse_data
arguments: data_tag: D24
type: string
name: parse_data
arguments: data_tag: D4
type: string

tool: D30: hello world


tool: D35: code is poetry


tool: D24: w

tool: D4: line_test.out

assistant: ```c
int main() {
  struct Line *line1 = Line_create_with_text("hello world\n");
  struct Line *line2 = Line_create_with_text("code is poetry\n");
  Line_set_index(line1, 1);
  Line_set_index(line2, 2);
  Line_print(line1);
  Line_print(line2);
  FILE *fp = fopen("line_test.out", "w");
  Line_write(line1, fp);
  Line_write(line2, fp);
  Line_destory(line1);
  Line_destory(line2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D29(%rip),%rdi
  push   %r12
  push   %rbp
  call   <Line_create_with_text@plt>
  lea    D24(%rip),%rdi
  mov    %rax,%r12
  call   <Line_create_with_text@plt>
  mov    %r12,%rdi
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <Line_set_index@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <Line_set_index@plt>
  mov    %r12,%rdi
  call   <Line_print@plt>
  mov    %rbp,%rdi
  call   <Line_print@plt>
  lea    D8(%rip),%rsi
  lea    D22(%rip),%rdi
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  mov    %rax,%rsi
  call   <Line_write@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <Line_write@plt>
  mov    %r12,%rdi
  call   <Line_destory@plt>
  mov    %rbp,%rdi
  call   <Line_destory@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D29
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string
name: disassemble_data
arguments: data_label: D22
type_guessed: string

tool: D29: hello world


tool: D24: code is poetry


tool: D8: w

tool: D22: line_test.out

assistant: ```c
int main() {
  struct Line *line1 = Line_create_with_text("hello world\n");
  struct Line *line2 = Line_create_with_text("code is poetry\n");
  Line_set_index(line1, 1);
  Line_set_index(line2, 2);
  Line_print(line1);
  Line_print(line2);
  FILE *fp = fopen("line_test.out", "w");
  Line_write(line1, fp);
  Line_write(line2, fp);
  Line_destory(line1);
  Line_destory(line2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D27(%rip),%rdi
  push   %r12
  push   %rbp
  call   <Line_create_with_text@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%r12
  call   <Line_create_with_text@plt>
  mov    %r12,%rdi
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <Line_set_index@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <Line_set_index@plt>
  mov    %r12,%rdi
  call   <Line_print@plt>
  mov    %rbp,%rdi
  call   <Line_print@plt>
  lea    D36(%rip),%rsi
  lea    D24(%rip),%rdi
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  mov    %rax,%rsi
  call   <Line_write@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <Line_write@plt>
  mov    %r12,%rdi
  call   <Line_destory@plt>
  mov    %rbp,%rdi
  call   <Line_destory@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D27
datatype: string
name: unpack_data
arguments: label: D10
datatype: string
name: unpack_data
arguments: label: D36
datatype: string
name: unpack_data
arguments: label: D24
datatype: string

tool: D27: hello world


tool: D10: code is poetry


tool: D36: w

tool: D24: line_test.out

assistant: ```c
int main() {
  struct Line *line1 = Line_create_with_text("hello world\n");
  struct Line *line2 = Line_create_with_text("code is poetry\n");
  Line_set_index(line1, 1);
  Line_set_index(line2, 2);
  Line_print(line1);
  Line_print(line2);
  FILE *fp = fopen("line_test.out", "w");
  Line_write(line1, fp);
  Line_write(line2, fp);
  Line_destory(line1);
  Line_destory(line2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<check_unary_operators>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L57
  addl   $0x1,-0x4(%rbp)
L57:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x21,%al
  jne    L78
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L78
  mov    $0x1,%eax
  jmp    L21
L78:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L52
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L52
  mov    $0x1,%eax
  jmp    L21
L52:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L59
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L59
  mov    $0x1,%eax
  jmp    L21
L59:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L61
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L61
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L61
  mov    $0x1,%eax
  jmp    L21
L61:
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int check_unary_operators(char *input) {
  int i = 0;
  if (input[0] == ' ')
    i++;
  if (input[i] == '!' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '+' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '-' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '+' && input[i + 1] == '+' && input[i + 2] == ' ')
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_unary_operators>:
  endbr64
  cmpb   $0x20,(%rdi)
  sete   %dl
  movzbl %dl,%edx
  movzbl (%rdi,%rdx,1),%eax
  cmp    $0x21,%al
  je     L35
  cmp    $0x2b,%al
  je     L10
  cmp    $0x2d,%al
  jne    L39
  cmpb   $0x20,0x1(%rdi,%rdx,1)
  sete   %al
  movzbl %al,%eax
  ret
L35:
  cmpb   $0x20,0x1(%rdi,%rdx,1)
  sete   %al
  movzbl %al,%eax
  ret
L10:
  movzbl 0x1(%rdi,%rdx,1),%ecx
  mov    $0x1,%eax
  cmp    $0x20,%cl
  je     L41
  mov    $0x0,%eax
  cmp    $0x2b,%cl
  jne    L19
  cmpb   $0x20,0x2(%rdi,%rdx,1)
  sete   %al
  movzbl %al,%eax
  ret
L41:
  ret
L39:
  mov    $0x0,%eax
L19:
  ret
```

assistant: ```c
int check_unary_operators(char *input) {
  int i = 0;
  if (input[0] == ' ')
    i++;
  if (input[i] == '!' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '+' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '-' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '+' && input[i + 1] == '+' && input[i + 2] == ' ')
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_unary_operators>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x20,(%rdi)
  sete   %al
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x21,%dl
  je     L64
  cmp    $0x2b,%dl
  je     L27
  cmp    $0x2d,%dl
  jne    L34
L64:
  xor    %r8d,%r8d
  cmpb   $0x20,0x1(%rdi,%rax,1)
  sete   %r8b
L41:
  mov    %r8d,%eax
  ret
  nop
L27:
  movzbl 0x1(%rdi,%rax,1),%edx
  mov    $0x1,%r8d
  cmp    $0x20,%dl
  je     L41
  xor    %r8d,%r8d
  cmp    $0x2b,%dl
  jne    L41
  xor    %r8d,%r8d
  cmpb   $0x20,0x2(%rdi,%rax,1)
  sete   %r8b
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L34:
  xor    %r8d,%r8d
  jmp    L41
```

assistant: ```c
int check_unary_operators(char *input) {
  int i = 0;
  if (input[0] == ' ')
    i++;
  if (input[i] == '!' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '+' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '-' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '+' && input[i + 1] == '+' && input[i + 2] == ' ')
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_unary_operators>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x20,(%rdi)
  sete   %al
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x21,%dl
  je     L13
  cmp    $0x2b,%dl
  je     L22
  cmp    $0x2d,%dl
  jne    L21
L13:
  xor    %r8d,%r8d
  cmpb   $0x20,0x1(%rdi,%rax,1)
  sete   %r8b
L7:
  mov    %r8d,%eax
  ret
  nop
L22:
  movzbl 0x1(%rdi,%rax,1),%edx
  mov    $0x1,%r8d
  cmp    $0x20,%dl
  je     L7
  xor    %r8d,%r8d
  cmp    $0x2b,%dl
  jne    L7
  xor    %r8d,%r8d
  cmpb   $0x20,0x2(%rdi,%rax,1)
  sete   %r8b
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L21:
  xor    %r8d,%r8d
  jmp    L7
```

assistant: ```c
int check_unary_operators(char *input) {
  int i = 0;
  if (input[0] == ' ')
    i++;
  if (input[i] == '!' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '+' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '-' && input[i + 1] == ' ')
    return 1;
  else if (input[i] == '+' && input[i + 1] == '+' && input[i + 2] == ' ')
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  movsd  %xmm2,-0x50(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L1
L48:
  movl   $0x0,-0x18(%rbp)
  jmp    L72
L0:
  movl   $0x0,-0x14(%rbp)
  jmp    L31
L14:
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L36:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x40(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  -0x48(%rbp),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  subsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  -0x50(%rbp),%xmm1
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  subsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x10(%rbp)
L16:
  cmpl   $0x3,-0x10(%rbp)
  jle    L36
  addl   $0x1,-0x14(%rbp)
L31:
  cmpl   $0x0,-0x14(%rbp)
  jle    L14
  addl   $0x1,-0x18(%rbp)
L72:
  cmpl   $0x0,-0x18(%rbp)
  jle    L0
  addl   $0x1,-0x1c(%rbp)
L1:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L48
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(double (*__restrict p)[4], double (*__restrict q)[4], double *__restrict prim, double scale, double pp, double pq) {
  int md, mc, mb, ma, p_index = 0;
  for (md = 0; md < 1; md++)
    for (mc = 0; mc < 1; mc++)
      for (mb = 0; mb < 1; mb++)
        for (ma = 0; ma < 4; ma++) {
          double tmp = scale * prim[p_index++];
          p[md][ma] = p[md][ma] - tmp * pp;
          q[mc][ma] = q[mc][ma] - tmp * pq;
        }
}
```