ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x35,%edx
  lea    D37(%rip),%rdi
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %dx,0x20(%rsp)
  lea    0xa(%rsp),%rbx
  mov    %rbp,%rsi
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L11
  lea    0xa(%rsp),%rbx
  mov    %rax,%rdi
  mov    %rbx,%r13
L38:
  call   <atoi@plt>
  xor    %edi,%edi
  mov    %r12,%rsi
  add    $0x1,%r13
  mov    %al,-0x1(%r13)
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L38
L11:
  lea    D16(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L27:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D37
type_guessed: string
name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D16
type_guessed: string

tool: D37: Splitting string "%s" into tokens:


tool: D20: :

tool: {"D13": [0x30,0x30,0x3a,0x30,0x31,0x3a,0x30,0x32,0x3a,0x30,0x33,0x3a,0x30,0x34,0x3a,0x30]}

tool: D16: %02x:

assistant: ```c
int main() {
  unsigned char str[] = "00:01:02:03:04:05";
  unsigned char *pch;
  unsigned char mac[6];
  int i = 0;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok(str, ":");
  while (pch != NULL) {
    mac[i] = atoi(pch);
    pch = strtok(NULL, ":");
    i++;
  }
  for (i = 0; i < 6; i++)
    printf("%02x:", mac[i]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x35,%edx
  lea    D13(%rip),%rdi
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %dx,0x20(%rsp)
  lea    0xa(%rsp),%rbx
  mov    %rbp,%rsi
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L24
  lea    0xa(%rsp),%rbx
  mov    %rax,%rdi
  mov    %rbx,%r13
L9:
  call   <atoi@plt>
  xor    %edi,%edi
  mov    %r12,%rsi
  add    $0x1,%r13
  mov    %al,-0x1(%r13)
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L9
L24:
  lea    D20(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L33:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D19
type_infered: byte[16]
name: extract_symbolic_data
arguments: tag: D20
type_infered: string

tool: D13: Splitting string "%s" into tokens:


tool: D14: :

tool: {"D19": [0x30,0x30,0x3a,0x30,0x31,0x3a,0x30,0x32,0x3a,0x30,0x33,0x3a,0x30,0x34,0x3a,0x30]}

tool: D20: %02x:

assistant: ```c
int main() {
  unsigned char str[] = "00:01:02:03:04:05";
  unsigned char *pch;
  unsigned char mac[6];
  int i = 0;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok(str, ":");
  while (pch != NULL) {
    mac[i] = atoi(pch);
    pch = strtok(NULL, ":");
    i++;
  }
  for (i = 0; i < 6; i++)
    printf("%02x:", mac[i]);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D29
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D26: inode,parent-inode,directory-depth,"filename"

tool: D30: ,"fileExtension",UID,GID,st_size,st_dev,st_blocks

tool: D29: ,st_nlink,"st_mode",st_atime,st_mtime,st_ctime,pw_fcount

tool: D14: ,pw_dirsum


assistant: ```c
void printHeader() {
  printf("inode,parent-inode,directory-depth,\"filename\"");
  printf(",\"fileExtension\",UID,GID,st_size,st_dev,st_blocks");
  printf(",st_nlink,\"st_mode\",st_atime,st_mtime,st_ctime,pw_fcount");
  printf(",pw_dirsum\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<printHeader>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D39
type_infered: string
name: retrieve_data
arguments: data_tag: D37
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D28: inode,parent-inode,directory-depth,"filename"

tool: D39: ,"fileExtension",UID,GID,st_size,st_dev,st_blocks

tool: D37: ,st_nlink,"st_mode",st_atime,st_mtime,st_ctime,pw_fcount

tool: D12: ,pw_dirsum


assistant: ```c
void printHeader() {
  printf("inode,parent-inode,directory-depth,\"filename\"");
  printf(",\"fileExtension\",UID,GID,st_size,st_dev,st_blocks");
  printf(",st_nlink,\"st_mode\",st_atime,st_mtime,st_ctime,pw_fcount");
  printf(",pw_dirsum\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printHeader>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
data_type: string
name: read_data
arguments: data_label: D34
data_type: string
name: read_data
arguments: data_label: D14
data_type: string
name: read_data
arguments: data_label: D3
data_type: string

tool: D18: inode,parent-inode,directory-depth,"filename"

tool: D34: ,"fileExtension",UID,GID,st_size,st_dev,st_blocks

tool: D14: ,st_nlink,"st_mode",st_atime,st_mtime,st_ctime,pw_fcount

tool: D3: ,pw_dirsum


assistant: ```c
void printHeader() {
  printf("inode,parent-inode,directory-depth,\"filename\"");
  printf(",\"fileExtension\",UID,GID,st_size,st_dev,st_blocks");
  printf(",st_nlink,\"st_mode\",st_atime,st_mtime,st_ctime,pw_fcount");
  printf(",pw_dirsum\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<printHeader>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string

tool: D7: inode,parent-inode,directory-depth,"filename"

tool: D5: ,"fileExtension",UID,GID,st_size,st_dev,st_blocks

tool: D20: ,st_nlink,"st_mode",st_atime,st_mtime,st_ctime,pw_fcount

tool: D29: ,pw_dirsum


assistant: ```c
void printHeader() {
  printf("inode,parent-inode,directory-depth,\"filename\"");
  printf(",\"fileExtension\",UID,GID,st_size,st_dev,st_blocks");
  printf(",st_nlink,\"st_mode\",st_atime,st_mtime,st_ctime,pw_fcount");
  printf(",pw_dirsum\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test31>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cmpl   $0x1,-0x4(%rbp)
  jne    L9
  mov    $0x2,%eax
  jmp    L21
L9:
  cmpl   $0x2,-0x4(%rbp)
  jne    L1
  mov    $0x3,%eax
  jmp    L21
L1:
  mov    $0x1,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int test31(void) {
  int a;
  if (a == 1)
    return 2;
  else if (a == 2)
    return 3;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test31>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test31(void) {
  int a;
  if (a == 1)
    return 2;
  else if (a == 2)
    return 3;
  else
    return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test31>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test31(void) {
  int a;
  if (a == 1)
    return 2;
  else if (a == 2)
    return 3;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<S1f>:
  endbr64
  mov    %rdi,%rax
  notl   (%rdi)
  notl   (%rdx)
  mov    (%rdi),%edi
  mov    %edi,(%r8)
  and    (%rsi),%edi
  mov    %edi,(%rax)
  xor    %edi,(%rdx)
  mov    (%rcx),%edi
  or     %edi,(%rax)
  mov    (%rdx),%edi
  xor    %edi,(%rcx)
  mov    (%rax),%edi
  xor    %edi,(%rsi)
  mov    (%r8),%edi
  xor    %edi,(%rax)
  mov    (%rsi),%edi
  or     %edi,(%r8)
  mov    (%rcx),%ecx
  xor    %ecx,(%rsi)
  mov    (%rdx),%ecx
  or     (%rax),%ecx
  mov    %ecx,(%rdx)
  and    (%r8),%ecx
  mov    %ecx,(%rdx)
  mov    (%rsi),%ecx
  xor    %ecx,(%rax)
  mov    (%rsi),%ecx
  and    (%rdx),%ecx
  mov    %ecx,(%rsi)
  xor    (%rax),%ecx
  mov    %ecx,(%rsi)
  mov    (%rax),%ecx
  and    (%rdx),%ecx
  mov    %ecx,%edx
  mov    %ecx,(%rax)
  xor    (%r8),%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void S1f(unsigned int *r0, unsigned int *r1, unsigned int *r2, unsigned int *r3, unsigned int *r4) {
  *r0 = ~*r0;
  *r2 = ~*r2;
  *r4 = *r0;
  *r0 &= *r1;
  *r2 ^= *r0;
  *r0 |= *r3;
  *r3 ^= *r2;
  *r1 ^= *r0;
  *r0 ^= *r4;
  *r4 |= *r1;
  *r1 ^= *r3;
  *r2 |= *r0;
  *r2 &= *r4;
  *r0 ^= *r1;
  *r1 &= *r2;
  *r1 ^= *r0;
  *r0 &= *r2;
  *r0 ^= *r4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<S1f>:
  endbr64
  notl   (%rdi)
  mov    %rdi,%rax
  notl   (%rdx)
  mov    (%rdi),%edi
  mov    %edi,(%r8)
  and    (%rsi),%edi
  mov    %edi,(%rax)
  xor    %edi,(%rdx)
  mov    (%rcx),%edi
  or     %edi,(%rax)
  mov    (%rdx),%edi
  xor    %edi,(%rcx)
  mov    (%rax),%edi
  xor    %edi,(%rsi)
  mov    (%r8),%edi
  xor    %edi,(%rax)
  mov    (%rsi),%edi
  or     %edi,(%r8)
  mov    (%rcx),%ecx
  xor    %ecx,(%rsi)
  mov    (%rdx),%ecx
  or     (%rax),%ecx
  mov    %ecx,(%rdx)
  and    (%r8),%ecx
  mov    %ecx,(%rdx)
  mov    (%rsi),%ecx
  xor    %ecx,(%rax)
  mov    (%rsi),%ecx
  and    (%rdx),%ecx
  mov    %ecx,(%rsi)
  xor    (%rax),%ecx
  mov    %ecx,(%rsi)
  mov    (%rax),%ecx
  and    (%rdx),%ecx
  mov    %ecx,(%rax)
  mov    %ecx,%edx
  xor    (%r8),%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void S1f(unsigned int *r0, unsigned int *r1, unsigned int *r2, unsigned int *r3, unsigned int *r4) {
  *r0 = ~*r0;
  *r2 = ~*r2;
  *r4 = *r0;
  *r0 &= *r1;
  *r2 ^= *r0;
  *r0 |= *r3;
  *r3 ^= *r2;
  *r1 ^= *r0;
  *r0 ^= *r4;
  *r4 |= *r1;
  *r1 ^= *r3;
  *r2 |= *r0;
  *r2 &= *r4;
  *r0 ^= *r1;
  *r1 &= *r2;
  *r1 ^= *r0;
  *r0 &= *r2;
  *r0 ^= *r4;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_cursor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <disable_int@plt>
  mov    $0xe,%esi
  mov    $0x3d4,%edi
  call   <out_byte@plt>
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x3d5,%edi
  call   <out_byte@plt>
  mov    $0xf,%esi
  mov    $0x3d4,%edi
  call   <out_byte@plt>
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x3d5,%edi
  call   <out_byte@plt>
  mov    $0x0,%eax
  call   <enable_int@plt>
  nop
  leave
  ret
```

assistant: ```c
void set_cursor(unsigned int position) {
  disable_int();
  out_byte(0x3D4, 0xE);
  out_byte(0x3D5, (position >> 8) & 0xFF);
  out_byte(0x3D4, 0xF);
  out_byte(0x3D5, position & 0xFF);
  enable_int();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_cursor>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <disable_int@plt>
  mov    $0xe,%esi
  mov    $0x3d4,%edi
  call   <out_byte@plt>
  movzbl %bh,%esi
  mov    $0x3d5,%edi
  call   <out_byte@plt>
  mov    $0xf,%esi
  mov    $0x3d4,%edi
  call   <out_byte@plt>
  movzbl %bl,%esi
  mov    $0x3d5,%edi
  call   <out_byte@plt>
  mov    $0x0,%eax
  call   <enable_int@plt>
  pop    %rbx
  ret
```

assistant: ```c
void set_cursor(unsigned int position) {
  disable_int();
  out_byte(0x3D4, 0xE);
  out_byte(0x3D5, (position >> 8) & 0xFF);
  out_byte(0x3D4, 0xF);
  out_byte(0x3D5, position & 0xFF);
  enable_int();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_cursor>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <disable_int@plt>
  mov    $0xe,%esi
  mov    $0x3d4,%edi
  call   <out_byte@plt>
  movzbl %bh,%esi
  mov    $0x3d5,%edi
  call   <out_byte@plt>
  mov    $0xf,%esi
  mov    $0x3d4,%edi
  call   <out_byte@plt>
  movzbl %bl,%esi
  mov    $0x3d5,%edi
  call   <out_byte@plt>
  xor    %eax,%eax
  pop    %rbx
  jmp    1070 <enable_int@plt>
```

assistant: ```c
void set_cursor(unsigned int position) {
  disable_int();
  out_byte(0x3D4, 0xE);
  out_byte(0x3D5, (position >> 8) & 0xFF);
  out_byte(0x3D4, 0xF);
  out_byte(0x3D5, position & 0xFF);
  enable_int();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<set_cursor>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <disable_int@plt>
  mov    $0xe,%esi
  mov    $0x3d4,%edi
  call   <out_byte@plt>
  movzbl %bh,%esi
  mov    $0x3d5,%edi
  call   <out_byte@plt>
  mov    $0xf,%esi
  mov    $0x3d4,%edi
  call   <out_byte@plt>
  movzbl %bl,%esi
  mov    $0x3d5,%edi
  call   <out_byte@plt>
  xor    %eax,%eax
  pop    %rbx
  jmp    1070 <enable_int@plt>
```

assistant: ```c
void set_cursor(unsigned int position) {
  disable_int();
  out_byte(0x3D4, 0xE);
  out_byte(0x3D5, (position >> 8) & 0xFF);
  out_byte(0x3D4, 0xF);
  out_byte(0x3D5, position & 0xFF);
  enable_int();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L8
  movsd  D2(%rip),%xmm0
  jmp    L14
L8:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L0
  movsd  D11(%rip),%xmm0
  jmp    L14
L0:
  pxor   %xmm0,%xmm0
L14:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: byte[8]
name: unpack_data
arguments: tag: D11
type_guessed: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double sign(double x) {
  if (x > 0)
    return 1;
  if (x < 0)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sign>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L9
  comisd %xmm0,%xmm1
  ja     L11
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L9:
  movsd  D3(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L11:
  movsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D3
datatype: byte[8]
name: parse_data
arguments: label: D4
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double sign(double x) {
  if (x > 0)
    return 1;
  if (x < 0)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sign>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L14
  comisd %xmm0,%xmm1
  ja     L15
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L14:
  movsd  D18(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L15:
  movsd  D13(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D13
type_guessed: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
double sign(double x) {
  if (x > 0)
    return 1;
  if (x < 0)
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sendBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  jmp    L7
L6:
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  movzbl -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <sendByte@plt>
L7:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jg     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void sendBlock(unsigned char reg, int len, const unsigned char *buf) {
  buf += len;
  while (len-- > 0) {
    sendByte(reg, (*--buf));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sendBlock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rax
  lea    (%rdx,%rax,1),%rbx
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%r12d
  not    %r12
  add    %rbx,%r12
  movzbl %dil,%ebp
L14:
  sub    $0x1,%rbx
  movzbl (%rbx),%esi
  mov    %ebp,%edi
  call   <sendByte@plt>
  cmp    %r12,%rbx
  jne    L14
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sendBlock(unsigned char reg, int len, const unsigned char *buf) {
  buf += len;
  while (len-- > 0) {
    sendByte(reg, (*--buf));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sendBlock>:
  endbr64
  movslq %esi,%rax
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%rdx,%rax,1),%rbx
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%r12d
  movzbl %dil,%ebp
  not    %r12
  add    %rbx,%r12
  nopl   0x0(%rax)
L9:
  movzbl -0x1(%rbx),%esi
  sub    $0x1,%rbx
  mov    %ebp,%edi
  call   <sendByte@plt>
  cmp    %r12,%rbx
  jne    L9
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sendBlock(unsigned char reg, int len, const unsigned char *buf) {
  buf += len;
  while (len-- > 0) {
    sendByte(reg, (*--buf));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sendBlock>:
  endbr64
  movslq %esi,%rax
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%rdx,%rax,1),%rbx
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%r12d
  movzbl %dil,%ebp
  not    %r12
  add    %rbx,%r12
  nopl   0x0(%rax)
L5:
  movzbl -0x1(%rbx),%esi
  sub    $0x1,%rbx
  mov    %ebp,%edi
  call   <sendByte@plt>
  cmp    %rbx,%r12
  jne    L5
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sendBlock(unsigned char reg, int len, const unsigned char *buf) {
  buf += len;
  while (len-- > 0) {
    sendByte(reg, (*--buf));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x50(%rbp)
  movl   $0x6,-0x50(%rbp)
  movl   $0x5,-0x4c(%rbp)
  movss  D6(%rip),%xmm0
  movss  %xmm0,-0x48(%rbp)
  movss  D24(%rip),%xmm0
  movss  %xmm0,-0x44(%rbp)
  movss  D27(%rip),%xmm0
  movss  %xmm0,-0x44(%rbp)
  movl   $0x1,-0x40(%rbp)
  movl   $0x2,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x5,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: f32
name: extract_symbolic_data
arguments: data_label: D24
type: f32
name: extract_symbolic_data
arguments: data_label: D27
type: byte[4]

tool: D6: 5

tool: D24: 1

tool: {"D27": [0x00,0x00,0x40,0x40]}

assistant: ```c
void main() {
  int a = 5;
  a = 6;
  const int a_const = 5;
  const float b_const = 5.0;
  int a1[5];
  float f = 1.0;
  f = 1 + 2.0;
  int ar[2][3] = {1, 2, 3, 4, 5, 6};
  int br[2][3] = {1, 2, 3};
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int a = 5;
  a = 6;
  const int a_const = 5;
  const float b_const = 5.0;
  int a1[5];
  float f = 1.0;
  f = 1 + 2.0;
  int ar[2][3] = {1, 2, 3, 4, 5, 6};
  int br[2][3] = {1, 2, 3};
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int a = 5;
  a = 6;
  const int a_const = 5;
  const float b_const = 5.0;
  int a1[5];
  float f = 1.0;
  f = 1 + 2.0;
  int ar[2][3] = {1, 2, 3, 4, 5, 6};
  int br[2][3] = {1, 2, 3};
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int a = 5;
  a = 6;
  const int a_const = 5;
  const float b_const = 5.0;
  int a1[5];
  float f = 1.0;
  f = 1 + 2.0;
  int ar[2][3] = {1, 2, 3, 4, 5, 6};
  int br[2][3] = {1, 2, 3};
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ParseCommandLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x124(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x114(%rbp)
  jmp    L24
L23:
  mov    -0x114(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x130(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  subl   $0x1,-0x114(%rbp)
L24:
  cmpl   $0x0,-0x114(%rbp)
  jg     L23
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void ParseCommandLine(int argc, const char **argv) {
  int i;
  char buf[256];
  for (i = argc - 1; i >= 1; i--) {
    strcpy(buf, argv[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ParseCommandLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rdi),%ebx
  test   %ebx,%ebx
  jle    L20
  mov    %rsi,%rbp
  movslq %ebx,%rbx
  mov    %rsp,%r12
L2:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L2
L20:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ParseCommandLine(int argc, const char **argv) {
  int i;
  char buf[256];
  for (i = argc - 1; i >= 1; i--) {
    strcpy(buf, argv[i]);
  }
}
```