user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rbx)
  mov    $0x0,%eax
  jmp    L68
L36:
  mov    %rax,%rcx
  shr    %rcx
  mov    %rax,%rsi
  and    $0x1,%esi
  or     %rsi,%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rcx,%xmm0
  addsd  %xmm0,%xmm0
L88:
  movsd  %xmm0,(%rdx)
  mov    (%rbx,%rax,8),%rdx
  movsd  %xmm0,0x8(%rdx)
  mov    (%rbx,%rax,8),%rdx
  movsd  %xmm0,0x10(%rdx)
  add    $0x1,%rax
  cmp    $0x3,%rax
  je     L14
L68:
  mov    (%rbx,%rax,8),%rdx
  test   %rax,%rax
  js     L36
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L88
L14:
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbp)
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rbp)
  mov    $0x0,%eax
  jmp    L27
L23:
  mov    %rax,%rcx
  shr    %rcx
  mov    %rax,%rsi
  and    $0x1,%esi
  or     %rsi,%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rcx,%xmm0
  addsd  %xmm0,%xmm0
L89:
  movsd  %xmm0,(%rdx)
  mov    0x0(%rbp,%rax,8),%rdx
  movsd  %xmm0,0x8(%rdx)
  mov    0x0(%rbp,%rax,8),%rdx
  movsd  %xmm0,0x10(%rdx)
  add    $0x1,%rax
  cmp    $0x3,%rax
  je     L41
L27:
  mov    0x0(%rbp,%rax,8),%rdx
  test   %rax,%rax
  js     L23
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L89
L41:
  mov    $0x3,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printMat@plt>
  mov    $0x3,%edx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printMat@plt>
  mov    $0x3,%r8d
  movsd  D13(%rip),%xmm1
  movsd  D10(%rip),%xmm0
  mov    $0x3,%ecx
  mov    %rbp,%rdx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x2,%eax
  call   <kernel_perceptron@plt>
  mov    $0x0,%r12d
L73:
  mov    0x0(%rbp,%r12,8),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x1,%r12
  cmp    $0x3,%r12
  jne    L73
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: f64
name: unpack_data
arguments: data_tag: D10
type: f64

tool: D13: 0.1

tool: D10: 1

assistant: ```c
int main(int argc, char **argv) {
  unsigned long N = 3;
  double **weightVectors = (double **)malloc(N * sizeof(double *));
  unsigned long i = 0;
  unsigned long j = 0;
  for (i = 0; i < 3; i++)
    weightVectors[i] = (double *)malloc(3 * sizeof(double));
  for (i = 0; i < N; i++)
    for (j = 0; j < 3; weightVectors[i][j++] = i)
      ;
  double **learnSamples = (double **)malloc(N * sizeof(double *));
  for (i = 0; i < 3; i++)
    learnSamples[i] = (double *)malloc(3 * sizeof(double));
  for (i = 0; i < N; i++)
    for (j = 0; j < 3; learnSamples[i][j++] = i)
      ;
  printMat(weightVectors, N, 3);
  printMat(learnSamples, N, 3);
  double learnFactor = 1;
  double margin = 0.1;
  kernel_perceptron(weightVectors, N, learnSamples, N, learnFactor, margin, 3);
  for (i = 0; i < N; i++) {
    free(learnSamples[i]);
    free(weightVectors);
  }
  return 0;
}
```