ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<map_timeout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L12
  cmpl   $0x0,-0x14(%rbp)
  je     L26
  jmp    L17
L12:
  movq   $0x0,-0x8(%rbp)
  jmp    L28
L26:
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x0,0x4(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L28
L17:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x3e8,%eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L28:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct timeval *map_timeout(int poll_timeout, struct timeval *pSelTimeout) {
  struct timeval *pResult;
  assert(pSelTimeout != (struct timeval *)NULL);
  switch (poll_timeout) {
  case -1:
    pResult = (struct timeval *)NULL;
    break;
  case 0:
    pSelTimeout->tv_sec = 0;
    pSelTimeout->tv_usec = 0;
    pResult = pSelTimeout;
    break;
  default:
    pSelTimeout->tv_sec = poll_timeout / 1000;
    poll_timeout %= 1000;
    pSelTimeout->tv_usec = poll_timeout * 1000;
    pResult = pSelTimeout;
    break;
  }
  return pResult;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<map_timeout>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  cmp    $0xffffffff,%ebx
  je     L14
  test   %ebx,%ebx
  jne    L0
  movl   $0x0,0x0(%rbp)
  movl   $0x0,0x4(%rbp)
  mov    %rbp,%rax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  movslq %ebx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x0(%rbp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ebx
  imul   $0x3e8,%ebx,%ebx
  mov    %ebx,0x4(%rbp)
  mov    %rbp,%rax
  jmp    L14
```

assistant: ```c
struct timeval *map_timeout(int poll_timeout, struct timeval *pSelTimeout) {
  struct timeval *pResult;
  assert(pSelTimeout != (struct timeval *)NULL);
  switch (poll_timeout) {
  case -1:
    pResult = (struct timeval *)NULL;
    break;
  case 0:
    pSelTimeout->tv_sec = 0;
    pSelTimeout->tv_usec = 0;
    pResult = pSelTimeout;
    break;
  default:
    pSelTimeout->tv_sec = poll_timeout / 1000;
    poll_timeout %= 1000;
    pSelTimeout->tv_usec = poll_timeout * 1000;
    pResult = pSelTimeout;
    break;
  }
  return pResult;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<map_timeout>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  xor    %eax,%eax
  cmp    $0xffffffff,%ebx
  je     L19
  test   %ebx,%ebx
  jne    L15
  movq   $0x0,0x0(%rbp)
  mov    %rbp,%rax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %eax,0x0(%rbp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ebx
  mov    %rbp,%rax
  imul   $0x3e8,%ebx,%ebx
  mov    %ebx,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct timeval *map_timeout(int poll_timeout, struct timeval *pSelTimeout) {
  struct timeval *pResult;
  assert(pSelTimeout != (struct timeval *)NULL);
  switch (poll_timeout) {
  case -1:
    pResult = (struct timeval *)NULL;
    break;
  case 0:
    pSelTimeout->tv_sec = 0;
    pSelTimeout->tv_usec = 0;
    pResult = pSelTimeout;
    break;
  default:
    pSelTimeout->tv_sec = poll_timeout / 1000;
    poll_timeout %= 1000;
    pSelTimeout->tv_usec = poll_timeout * 1000;
    pResult = pSelTimeout;
    break;
  }
  return pResult;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<map_timeout>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  xor    %eax,%eax
  cmp    $0xffffffff,%ebx
  je     L1
  test   %ebx,%ebx
  jne    L4
  movq   $0x0,0x0(%rbp)
  mov    %rbp,%rax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  movd   %eax,%xmm0
  mov    %rbp,%rax
  sub    %edx,%ebx
  imul   $0x3e8,%ebx,%ebx
  movd   %ebx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct timeval *map_timeout(int poll_timeout, struct timeval *pSelTimeout) {
  struct timeval *pResult;
  assert(pSelTimeout != (struct timeval *)NULL);
  switch (poll_timeout) {
  case -1:
    pResult = (struct timeval *)NULL;
    break;
  case 0:
    pSelTimeout->tv_sec = 0;
    pSelTimeout->tv_usec = 0;
    pResult = pSelTimeout;
    break;
  default:
    pSelTimeout->tv_sec = poll_timeout / 1000;
    poll_timeout %= 1000;
    pSelTimeout->tv_usec = poll_timeout * 1000;
    pResult = pSelTimeout;
    break;
  }
  return pResult;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<piece_record>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    0x10(%rbp),%rdx
  mov    $0x5e,%esi
  mov    %rax,%rdi
  call   <piece@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x1,%ecx
  mov    0x10(%rbp),%rdx
  mov    $0x5e,%esi
  mov    %rax,%rdi
  call   <piece@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x2,%ecx
  mov    0x10(%rbp),%rdx
  mov    $0x5e,%esi
  mov    %rax,%rdi
  call   <piece@plt>
  mov    -0x20(%rbp),%rax
  mov    $0x3,%ecx
  mov    0x10(%rbp),%rdx
  mov    $0x5e,%esi
  mov    %rax,%rdi
  call   <piece@plt>
  mov    -0x28(%rbp),%rax
  mov    $0x4,%ecx
  mov    0x10(%rbp),%rdx
  mov    $0x5e,%esi
  mov    %rax,%rdi
  call   <piece@plt>
  mov    -0x30(%rbp),%rax
  mov    $0x5,%ecx
  mov    0x10(%rbp),%rdx
  mov    $0x5e,%esi
  mov    %rax,%rdi
  call   <piece@plt>
  nop
  leave
  ret
```

assistant: ```c
void piece_record(char *station, char *datatype, char *measurement_update_date, char *measurement_update_time, char *login_name, char *parameter_value, char *record) {
  piece(station, '^', record, 0);
  piece(datatype, '^', record, 1);
  piece(measurement_update_date, '^', record, 2);
  piece(measurement_update_time, '^', record, 3);
  piece(login_name, '^', record, 4);
  piece(parameter_value, '^', record, 5);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<piece_record>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r15
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %r8,%r12
  mov    %r9,%rbp
  mov    0x40(%rsp),%rbx
  mov    $0x0,%ecx
  mov    %rbx,%rdx
  mov    $0x5e,%esi
  call   <piece@plt>
  mov    $0x1,%ecx
  mov    %rbx,%rdx
  mov    $0x5e,%esi
  mov    %r15,%rdi
  call   <piece@plt>
  mov    $0x2,%ecx
  mov    %rbx,%rdx
  mov    $0x5e,%esi
  mov    %r14,%rdi
  call   <piece@plt>
  mov    $0x3,%ecx
  mov    %rbx,%rdx
  mov    $0x5e,%esi
  mov    %r13,%rdi
  call   <piece@plt>
  mov    $0x4,%ecx
  mov    %rbx,%rdx
  mov    $0x5e,%esi
  mov    %r12,%rdi
  call   <piece@plt>
  mov    $0x5,%ecx
  mov    %rbx,%rdx
  mov    $0x5e,%esi
  mov    %rbp,%rdi
  call   <piece@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void piece_record(char *station, char *datatype, char *measurement_update_date, char *measurement_update_time, char *login_name, char *parameter_value, char *record) {
  piece(station, '^', record, 0);
  piece(datatype, '^', record, 1);
  piece(measurement_update_date, '^', record, 2);
  piece(measurement_update_time, '^', record, 3);
  piece(login_name, '^', record, 4);
  piece(parameter_value, '^', record, 5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<piece_record>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  xor    %ecx,%ecx
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x5e,%esi
  sub    $0x8,%rsp
  mov    0x40(%rsp),%r12
  mov    %r12,%rdx
  call   <piece@plt>
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    $0x1,%ecx
  mov    $0x5e,%esi
  call   <piece@plt>
  mov    %r12,%rdx
  mov    %r15,%rdi
  mov    $0x2,%ecx
  mov    $0x5e,%esi
  call   <piece@plt>
  mov    %r12,%rdx
  mov    %r14,%rdi
  mov    $0x3,%ecx
  mov    $0x5e,%esi
  call   <piece@plt>
  mov    %r12,%rdx
  mov    %r13,%rdi
  mov    $0x4,%ecx
  mov    $0x5e,%esi
  call   <piece@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  pop    %rbx
  mov    $0x5,%ecx
  pop    %rbp
  mov    $0x5e,%esi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <piece@plt>
```

assistant: ```c
void piece_record(char *station, char *datatype, char *measurement_update_date, char *measurement_update_time, char *login_name, char *parameter_value, char *record) {
  piece(station, '^', record, 0);
  piece(datatype, '^', record, 1);
  piece(measurement_update_date, '^', record, 2);
  piece(measurement_update_time, '^', record, 3);
  piece(login_name, '^', record, 4);
  piece(parameter_value, '^', record, 5);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<piece_record>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  xor    %ecx,%ecx
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x5e,%esi
  sub    $0x8,%rsp
  mov    0x40(%rsp),%r12
  mov    %r12,%rdx
  call   <piece@plt>
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    $0x1,%ecx
  mov    $0x5e,%esi
  call   <piece@plt>
  mov    %r12,%rdx
  mov    %r15,%rdi
  mov    $0x2,%ecx
  mov    $0x5e,%esi
  call   <piece@plt>
  mov    %r12,%rdx
  mov    %r14,%rdi
  mov    $0x3,%ecx
  mov    $0x5e,%esi
  call   <piece@plt>
  mov    %r12,%rdx
  mov    %r13,%rdi
  mov    $0x4,%ecx
  mov    $0x5e,%esi
  call   <piece@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  pop    %rbx
  mov    $0x5,%ecx
  pop    %rbp
  mov    $0x5e,%esi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <piece@plt>
```

assistant: ```c
void piece_record(char *station, char *datatype, char *measurement_update_date, char *measurement_update_time, char *login_name, char *parameter_value, char *record) {
  piece(station, '^', record, 0);
  piece(datatype, '^', record, 1);
  piece(measurement_update_date, '^', record, 2);
  piece(measurement_update_time, '^', record, 3);
  piece(login_name, '^', record, 4);
  piece(parameter_value, '^', record, 5);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_empty_substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L24
L18:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isgraph@plt>
  test   %rax,%rax
  je     L24
  mov    $0x0,%eax
  jmp    L34
L24:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  jne    L18
  mov    $0x1,%eax
L34:
  leave
  ret
```

assistant: ```c
int is_empty_substr(const char *s, size_t count) {
  while (count--) {
    if (isgraph(*s++))
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_empty_substr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rbp
L5:
  cmp    %rbp,%rbx
  je     L18
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <isgraph@plt>
  test   %rax,%rax
  je     L5
  mov    $0x0,%eax
  jmp    L19
L18:
  mov    $0x1,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_empty_substr(const char *s, size_t count) {
  while (count--) {
    if (isgraph(*s++))
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_empty_substr>:
  endbr64
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L22:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <isgraph@plt>
  test   %rax,%rax
  jne    L1
L23:
  cmp    %rbp,%rbx
  jne    L22
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_empty_substr(const char *s, size_t count) {
  while (count--) {
    if (isgraph(*s++))
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_empty_substr>:
  endbr64
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <isgraph@plt>
  test   %rax,%rax
  jne    L17
L0:
  cmp    %rbp,%rbx
  jne    L4
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_empty_substr(const char *s, size_t count) {
  while (count--) {
    if (isgraph(*s++))
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4d,%al
  jne    L5
  mov    -0xc(%rbp),%eax
  jmp    L15
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x4d,%al
  jne    L10
  mov    -0xc(%rbp),%eax
  neg    %eax
  jmp    L15
L10:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
L15:
  leave
  ret
```

assistant: ```c
int readval(str, m)
char *str;
int m;
{
  if (str[0] == 'M')
    return (m);
  if (str[0] == '-' && str[1] == 'M')
    return (-m);
  return (atoi(str));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readval>:
  endbr64
  movzbl (%rdi),%edx
  mov    %esi,%eax
  cmp    $0x4d,%dl
  je     L22
  cmp    $0x2d,%dl
  jne    L23
  cmpb   $0x4d,0x1(%rdi)
  je     L5
L23:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <atoi@plt>
  add    $0x8,%rsp
  ret
L5:
  neg    %eax
  ret
L22:
  ret
```

assistant: ```c
int readval(str, m)
char *str;
int m;
{
  if (str[0] == 'M')
    return (m);
  if (str[0] == '-' && str[1] == 'M')
    return (-m);
  return (atoi(str));
}
```
user: What is the c source code of the assembly code below?

```asm
<readval>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x4d,%al
  je     L11
  cmp    $0x2d,%al
  jne    L22
  cmpb   $0x4d,0x1(%rdi)
  je     L13
L22:
  xor    %eax,%eax
  jmp    1050 <atoi@plt>
  nopl   0x0(%rax)
L11:
  mov    %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %esi,%eax
  neg    %eax
  ret
```

assistant: ```c
int readval(str, m)
char *str;
int m;
{
  if (str[0] == 'M')
    return (m);
  if (str[0] == '-' && str[1] == 'M')
    return (-m);
  return (atoi(str));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readval>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x4d,%al
  je     L10
  cmp    $0x2d,%al
  jne    L7
  cmpb   $0x4d,0x1(%rdi)
  je     L8
L7:
  xor    %eax,%eax
  jmp    1050 <atoi@plt>
  nopl   0x0(%rax)
L10:
  mov    %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %esi,%eax
  neg    %eax
  ret
```

assistant: ```c
int readval(str, m)
char *str;
int m;
{
  if (str[0] == 'M')
    return (m);
  if (str[0] == '-' && str[1] == 'M')
    return (-m);
  return (atoi(str));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initializeRandomizedBuffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L15:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  cltd
  idivl  -0x28(%rbp)
  mov    %edx,%eax
  mov    %eax,(%rcx)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int *initializeRandomizedBuffer(int bufferSize, int range) {
  time_t t;
  srand((unsigned)time(&t));
  int *buffer = (int *)malloc(sizeof(int) * bufferSize);
  for (int i = 0; i < bufferSize; ++i)
    buffer[i] = rand() % range;
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initializeRandomizedBuffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L22
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,4),%r12
L18:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L18
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *initializeRandomizedBuffer(int bufferSize, int range) {
  time_t t;
  srand((unsigned)time(&t));
  int *buffer = (int *)malloc(sizeof(int) * bufferSize);
  for (int i = 0; i < bufferSize; ++i)
    buffer[i] = rand() % range;
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<initializeRandomizedBuffer>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L29
  mov    %rax,%rbx
  lea    (%rax,%r12,4),%r12
L10:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L10
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *initializeRandomizedBuffer(int bufferSize, int range) {
  time_t t;
  srand((unsigned)time(&t));
  int *buffer = (int *)malloc(sizeof(int) * bufferSize);
  for (int i = 0; i < bufferSize; ++i)
    buffer[i] = rand() % range;
  return buffer;
}
```
user: What is the c source code of the assembly code below?

```asm
<initializeRandomizedBuffer>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L0
  mov    %rax,%rbx
  lea    (%rax,%r12,4),%r12
L21:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L21
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *initializeRandomizedBuffer(int bufferSize, int range) {
  time_t t;
  srand((unsigned)time(&t));
  int *buffer = (int *)malloc(sizeof(int) * bufferSize);
  for (int i = 0; i < bufferSize; ++i)
    buffer[i] = rand() % range;
  return buffer;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cvt_u8BGRA_u8BGR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L17:
  mov    -0x18(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cvt_u8BGRA_u8BGR(const uint8_t *src, uint8_t *dest, int w) {
  int x;
  for (x = 0; x < w; ++x) {
    *dest++ = *src++;
    *dest++ = *src++;
    *dest++ = *src++;
    ++src;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cvt_u8BGRA_u8BGR>:
  endbr64
  test   %edx,%edx
  jle    L16
  mov    %edx,%edx
  shl    $0x4,%rdx
  lea    (%rdi,%rdx,1),%rax
L19:
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    0x4(%rdi),%edx
  mov    %edx,0x4(%rsi)
  add    $0xc,%rsi
  mov    0x8(%rdi),%edx
  mov    %edx,-0x4(%rsi)
  add    $0x10,%rdi
  cmp    %rdi,%rax
  jne    L19
L16:
  ret
```

assistant: ```c
void cvt_u8BGRA_u8BGR(const uint8_t *src, uint8_t *dest, int w) {
  int x;
  for (x = 0; x < w; ++x) {
    *dest++ = *src++;
    *dest++ = *src++;
    *dest++ = *src++;
    ++src;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvt_u8BGRA_u8BGR>:
  endbr64
  test   %edx,%edx
  jle    L7
  movslq %edx,%rdx
  shl    $0x4,%rdx
  lea    (%rdi,%rdx,1),%rax
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rdi),%edx
  add    $0xc,%rsi
  add    $0x10,%rdi
  mov    %edx,-0xc(%rsi)
  mov    -0xc(%rdi),%edx
  mov    %edx,-0x8(%rsi)
  mov    -0x8(%rdi),%edx
  mov    %edx,-0x4(%rsi)
  cmp    %rdi,%rax
  jne    L0
L7:
  ret
```

assistant: ```c
void cvt_u8BGRA_u8BGR(const uint8_t *src, uint8_t *dest, int w) {
  int x;
  for (x = 0; x < w; ++x) {
    *dest++ = *src++;
    *dest++ = *src++;
    *dest++ = *src++;
    ++src;
  }
}
```