ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hufgencode>:
  endbr64
  sub    $0x108,%rsp
  mov    %rdx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0xf0(%rsp),%rax
L98:
  movq   $0x0,(%rax)
  sub    $0x8,%rax
  cmp    %rdx,%rax
  jne    L98
  mov    %rsi,%rax
  sub    $0x1,%rax
  js     L16
L6:
  mov    (%rdi,%rax,8),%rdx
  addq   $0x1,(%rsp,%rdx,8)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L6
L16:
  movq   $0x0,(%rcx)
  movq   $0x0,(%rsp)
  mov    $0x0,%eax
L81:
  mov    (%rsp,%rax,8),%rdx
  add    (%rcx,%rax,8),%rdx
  mov    %rdx,0x8(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    $0x1f,%rax
  jne    L81
  test   %rsi,%rsi
  jle    L78
  mov    $0x0,%eax
  jmp    L84
L85:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L78
L84:
  mov    (%rdi,%rax,8),%rdx
  test   %rdx,%rdx
  je     L85
  lea    (%rcx,%rdx,8),%r9
  mov    (%r9),%rdx
  lea    0x1(%rdx),%r10
  mov    %r10,(%r9)
  mov    %rax,(%r8,%rdx,8)
  jmp    L85
L78:
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x108,%rsp
  ret
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hufgencode(long *inbuf, long inum, long *hitab, long *hbmax) {
  long i, tbuf[31];
  for (i = 30; i; i--)
    tbuf[i] = 0;
  for (i = inum - 1; i >= 0; i--)
    tbuf[inbuf[i]]++;
  tbuf[0] = hbmax[0] = 0;
  for (i = 0; i < 31; i++)
    hbmax[i + 1] = hbmax[i] + tbuf[i];
  for (i = 0; i < inum; i++)
    if (inbuf[i])
      hitab[hbmax[inbuf[i]]++] = i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hufgencode>:
  endbr64
  sub    $0x108,%rsp
  mov    %rdx,%r10
  mov    %rsi,%r9
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  mov    %rcx,%rsi
  mov    $0x1e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r9,%rax
  sub    $0x1,%rax
  js     L49
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%r8,%rax,8),%rdx
  addq   $0x1,(%rsp,%rdx,8)
  sub    $0x1,%rax
  jae    L10
L49:
  movq   $0x0,(%rsi)
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    (%rsi,%rax,8),%rdx
  mov    (%rsp,%rax,8),%rcx
L31:
  add    %rcx,%rdx
  mov    %rdx,0x8(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x1f,%rax
  jne    L37
  xor    %eax,%eax
  test   %r9,%r9
  jle    L67
  nopl   0x0(%rax)
L38:
  mov    (%r8,%rax,8),%rdx
  test   %rdx,%rdx
  je     L59
  lea    (%rsi,%rdx,8),%rcx
  mov    (%rcx),%rdx
  lea    0x1(%rdx),%rdi
  mov    %rdi,(%rcx)
  mov    %rax,(%r10,%rdx,8)
L59:
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L38
L67:
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x108,%rsp
  ret
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hufgencode(long *inbuf, long inum, long *hitab, long *hbmax) {
  long i, tbuf[31];
  for (i = 30; i; i--)
    tbuf[i] = 0;
  for (i = inum - 1; i >= 0; i--)
    tbuf[inbuf[i]]++;
  tbuf[0] = hbmax[0] = 0;
  for (i = 0; i < 31; i++)
    hbmax[i + 1] = hbmax[i] + tbuf[i];
  for (i = 0; i < inum; i++)
    if (inbuf[i])
      hitab[hbmax[inbuf[i]]++] = i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hufgencode>:
  endbr64
  sub    $0x108,%rsp
  mov    %rdx,%r10
  mov    %rsi,%r9
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  mov    %rcx,%rsi
  mov    $0x1e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r9,%rax
  sub    $0x1,%rax
  js     L61
  nopl   0x0(%rax,%rax,1)
L32:
  mov    (%r8,%rax,8),%rdx
  addq   $0x1,(%rsp,%rdx,8)
  sub    $0x1,%rax
  jae    L32
L61:
  movq   $0x0,(%rsi)
  xor    %edx,%edx
  xor    %eax,%eax
  mov    %rsp,%rcx
  movq   $0x0,(%rsp)
  nopl   (%rax)
L12:
  add    (%rcx,%rax,8),%rdx
  mov    %rdx,0x8(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x1f,%rax
  jne    L12
  test   %r9,%r9
  jle    L7
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L31:
  mov    (%r8,%rax,8),%rdx
  test   %rdx,%rdx
  je     L5
  lea    (%rsi,%rdx,8),%rcx
  mov    (%rcx),%rdx
  lea    0x1(%rdx),%rdi
  mov    %rdi,(%rcx)
  mov    %rax,(%r10,%rdx,8)
L5:
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L31
L7:
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x108,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hufgencode(long *inbuf, long inum, long *hitab, long *hbmax) {
  long i, tbuf[31];
  for (i = 30; i; i--)
    tbuf[i] = 0;
  for (i = inum - 1; i >= 0; i--)
    tbuf[inbuf[i]]++;
  tbuf[0] = hbmax[0] = 0;
  for (i = 0; i < 31; i++)
    hbmax[i + 1] = hbmax[i] + tbuf[i];
  for (i = 0; i < inum; i++)
    if (inbuf[i])
      hitab[hbmax[inbuf[i]]++] = i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ParseIsEscaped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L7
  mov    -0x4(%rbp),%eax
  jmp    L39
L7:
  subq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L10
  mov    -0x4(%rbp),%eax
  jmp    L39
L10:
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L39:
  pop    %rbp
  ret
```

assistant: ```c
int ParseIsEscaped(const char *line, const char *c) {
  int active = 0;
  for (;;) {
    if (line == c)
      return active;
    if (*--c != '\\')
      return active;
    active = !active;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ParseIsEscaped>:
  endbr64
  cmp    %rdi,%rsi
  je     L24
  mov    $0x0,%eax
L3:
  sub    $0x1,%rsi
  cmpb   $0x5c,(%rsi)
  jne    L2
  xor    $0x1,%eax
  cmp    %rsi,%rdi
  jne    L3
  ret
L24:
  mov    $0x0,%eax
L2:
  ret
```

assistant: ```c
int ParseIsEscaped(const char *line, const char *c) {
  int active = 0;
  for (;;) {
    if (line == c)
      return active;
    if (*--c != '\\')
      return active;
    active = !active;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ParseIsEscaped>:
  endbr64
  xor    %eax,%eax
  cmp    %rdi,%rsi
  jne    L25
  jmp    L14
  nopl   (%rax)
L21:
  xor    $0x1,%eax
  cmp    %rsi,%rdi
  je     L35
L25:
  sub    $0x1,%rsi
  cmpb   $0x5c,(%rsi)
  je     L21
L14:
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  ret
```

assistant: ```c
int ParseIsEscaped(const char *line, const char *c) {
  int active = 0;
  for (;;) {
    if (line == c)
      return active;
    if (*--c != '\\')
      return active;
    active = !active;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ParseIsEscaped>:
  endbr64
  xor    %eax,%eax
  cmp    %rdi,%rsi
  jne    L2
  jmp    L28
  nopl   (%rax)
L10:
  xor    $0x1,%eax
  cmp    %rsi,%rdi
  je     L26
L2:
  sub    $0x1,%rsi
  cmpb   $0x5c,(%rsi)
  je     L10
L28:
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  ret
```

assistant: ```c
int ParseIsEscaped(const char *line, const char *c) {
  int active = 0;
  for (;;) {
    if (line == c)
      return active;
    if (*--c != '\\')
      return active;
    active = !active;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CANIntUnregister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <CANBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <CANIntNumberGet@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntUnregister@plt>
  nop
  leave
  ret
```

assistant: ```c
void CANIntUnregister(unsigned long ulBase) {
  unsigned long ulIntNumber;
  DEBUG_ASSERT(CANBaseValid(ulBase));
  ulIntNumber = CANIntNumberGet(ulBase);
  IntDisable(ulIntNumber);
  IntUnregister(ulIntNumber);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CANIntUnregister>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <CANBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbx,%rdi
  call   <CANIntNumberGet@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    %rbx,%rdi
  call   <IntUnregister@plt>
  pop    %rbx
  ret
```

assistant: ```c
void CANIntUnregister(unsigned long ulBase) {
  unsigned long ulIntNumber;
  DEBUG_ASSERT(CANBaseValid(ulBase));
  ulIntNumber = CANIntNumberGet(ulBase);
  IntDisable(ulIntNumber);
  IntUnregister(ulIntNumber);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CANIntUnregister>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <CANBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,%rdi
  call   <CANIntNumberGet@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10b0 <IntUnregister@plt>
```

assistant: ```c
void CANIntUnregister(unsigned long ulBase) {
  unsigned long ulIntNumber;
  DEBUG_ASSERT(CANBaseValid(ulBase));
  ulIntNumber = CANIntNumberGet(ulBase);
  IntDisable(ulIntNumber);
  IntUnregister(ulIntNumber);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CANIntUnregister>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <CANBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,%rdi
  call   <CANIntNumberGet@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10b0 <IntUnregister@plt>
```

assistant: ```c
void CANIntUnregister(unsigned long ulBase) {
  unsigned long ulIntNumber;
  DEBUG_ASSERT(CANBaseValid(ulBase));
  ulIntNumber = CANIntNumberGet(ulBase);
  IntDisable(ulIntNumber);
  IntUnregister(ulIntNumber);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Q_StrReplace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  movq   $0x0,0x400(%rsp)
  movq   $0x0,0x408(%rsp)
  lea    0x410(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  test   %rbx,%rbx
  je     L121
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  cmpb   $0x0,(%rbx)
  je     L121
  test   %rbp,%rbp
  je     L75
  cmpb   $0x0,0x0(%rbp)
  je     L75
  cmpb   $0x0,(%rdx)
  jne    L74
L55:
  movb   $0x0,(%rsp)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    0x400(%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  cmpb   $0x0,(%rbx)
  je     L131
  mov    %rsp,%r12
  mov    %rsp,%r14
  jmp    L125
L75:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <Q_strncpyz@plt>
  jmp    L121
L74:
  lea    0x400(%rsp),%rdi
  mov    $0x400,%edx
  mov    $0x0,%eax
  call   <Q_strncpyz@plt>
  jmp    L55
L7:
  lea    0x400(%rsp),%rdx
  mov    $0x400,%esi
  mov    %r14,%rdi
  call   <Q_strcat@plt>
  movslq %r13d,%rax
  add    %rax,%rbx
  movslq %r15d,%rax
  add    %rax,%r12
  jmp    L41
L79:
  add    $0x1,%rbx
L41:
  cmpb   $0x0,(%rbx)
  je     L131
L125:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <Q_stricmpn@plt>
  test   %eax,%eax
  je     L7
  mov    %r14,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  cmp    $0x3ff,%rax
  ja     L79
  movzbl (%rbx),%eax
  mov    %al,(%r12)
  movb   $0x0,0x1(%r12)
  lea    0x1(%r12),%r12
  jmp    L79
L131:
  mov    %rsp,%rsi
  mov    $0x400,%edx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <Q_strncpyz@plt>
L121:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  lea    D17(%rip),%rax
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *Q_StrReplace(char *haystack, char *needle, char *newp) {
  static char final[1024] = {""};
  char dest[1024] = {""};
  char new[1024] = {""};
  char *destp;
  int needle_len = 0;
  int new_len = 0;
  if (!haystack || !*haystack) {
    return final;
  }
  if (!needle || !*needle) {
    Q_strncpyz(final, haystack, sizeof(final));
    return final;
  }
  if (*newp) {
    Q_strncpyz(new, newp, sizeof(new));
  }
  dest[0] = '\0';
  needle_len = strlen(needle);
  new_len = strlen(new);
  destp = &dest[0];
  while (*haystack) {
    if (!Q_stricmpn(haystack, needle, needle_len)) {
      Q_strcat(dest, sizeof(dest), new);
      haystack += needle_len;
      destp += new_len;
      continue;
    }
    if (1024 > (strlen(dest) + 1)) {
      *destp = *haystack;
      *++destp = '\0';
    }
    haystack++;
  }
  Q_strncpyz(final, dest, sizeof(final));
  return final;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Q_StrReplace>:
  endbr64
  push   %r15
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x828,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x410(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x420(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  test   %r14,%r14
  je     L109
  cmpb   $0x0,(%r14)
  je     L109
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L110
  cmpb   $0x0,(%rsi)
  je     L110
  cmpb   $0x0,(%rdx)
  mov    %rdx,%rsi
  lea    0x410(%rsp),%r15
  jne    L68
L47:
  mov    %rbx,%rdi
  movb   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%r13
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmpb   $0x0,(%r14)
  mov    %rax,(%rsp)
  je     L71
  movslq %r12d,%rax
  mov    %r13,%rbp
  mov    %rax,0x8(%rsp)
  jmp    L105
L78:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x3ff,%rax
  je     L44
  movzbl (%r14),%eax
  movb   $0x0,0x1(%rbp)
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
L44:
  add    $0x1,%r14
  cmpb   $0x0,(%r14)
  je     L71
L105:
  xor    %eax,%eax
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <Q_stricmpn@plt>
  test   %eax,%eax
  jne    L78
  mov    %r15,%rdx
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <Q_strcat@plt>
  add    0x8(%rsp),%r14
  add    (%rsp),%rbp
  cmpb   $0x0,(%r14)
  jne    L105
  nopl   0x0(%rax)
L71:
  lea    D8(%rip),%r12
  mov    $0x400,%edx
  mov    %r13,%rsi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <Q_strncpyz@plt>
L109:
  mov    0x818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L121
  add    $0x828,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L110:
  lea    D8(%rip),%r12
  mov    $0x400,%edx
  mov    %r14,%rsi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <Q_strncpyz@plt>
  jmp    L109
  nopl   0x0(%rax,%rax,1)
L68:
  mov    $0x400,%edx
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <Q_strncpyz@plt>
  jmp    L47
L121:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *Q_StrReplace(char *haystack, char *needle, char *newp) {
  static char final[1024] = {""};
  char dest[1024] = {""};
  char new[1024] = {""};
  char *destp;
  int needle_len = 0;
  int new_len = 0;
  if (!haystack || !*haystack) {
    return final;
  }
  if (!needle || !*needle) {
    Q_strncpyz(final, haystack, sizeof(final));
    return final;
  }
  if (*newp) {
    Q_strncpyz(new, newp, sizeof(new));
  }
  dest[0] = '\0';
  needle_len = strlen(needle);
  new_len = strlen(new);
  destp = &dest[0];
  while (*haystack) {
    if (!Q_stricmpn(haystack, needle, needle_len)) {
      Q_strcat(dest, sizeof(dest), new);
      haystack += needle_len;
      destp += new_len;
      continue;
    }
    if (1024 > (strlen(dest) + 1)) {
      *destp = *haystack;
      *++destp = '\0';
    }
    haystack++;
  }
  Q_strncpyz(final, dest, sizeof(final));
  return final;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Q_StrReplace>:
  endbr64
  push   %r15
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x828,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x410(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x420(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  test   %r14,%r14
  je     L94
  cmpb   $0x0,(%r14)
  je     L94
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L128
  cmpb   $0x0,(%rsi)
  je     L128
  cmpb   $0x0,(%rdx)
  mov    %rdx,%rsi
  lea    0x410(%rsp),%r15
  jne    L138
L29:
  mov    %rbx,%rdi
  movb   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%r13
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmpb   $0x0,(%r14)
  mov    %rax,(%rsp)
  je     L9
  movslq %r12d,%rax
  mov    %r13,%rbp
  mov    %rax,0x8(%rsp)
  jmp    L7
L101:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x3ff,%rax
  je     L32
  movzbl (%r14),%eax
  movb   $0x0,0x1(%rbp)
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
L32:
  add    $0x1,%r14
  cmpb   $0x0,(%r14)
  je     L9
L7:
  xor    %eax,%eax
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <Q_stricmpn@plt>
  test   %eax,%eax
  jne    L101
  mov    %r15,%rdx
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <Q_strcat@plt>
  add    0x8(%rsp),%r14
  add    (%rsp),%rbp
  cmpb   $0x0,(%r14)
  jne    L7
  nopl   0x0(%rax)
L9:
  lea    D13(%rip),%r12
  mov    $0x400,%edx
  mov    %r13,%rsi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <Q_strncpyz@plt>
L94:
  mov    0x818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L120
  add    $0x828,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L128:
  lea    D13(%rip),%r12
  mov    $0x400,%edx
  mov    %r14,%rsi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <Q_strncpyz@plt>
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L138:
  mov    $0x400,%edx
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <Q_strncpyz@plt>
  jmp    L29
L120:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *Q_StrReplace(char *haystack, char *needle, char *newp) {
  static char final[1024] = {""};
  char dest[1024] = {""};
  char new[1024] = {""};
  char *destp;
  int needle_len = 0;
  int new_len = 0;
  if (!haystack || !*haystack) {
    return final;
  }
  if (!needle || !*needle) {
    Q_strncpyz(final, haystack, sizeof(final));
    return final;
  }
  if (*newp) {
    Q_strncpyz(new, newp, sizeof(new));
  }
  dest[0] = '\0';
  needle_len = strlen(needle);
  new_len = strlen(new);
  destp = &dest[0];
  while (*haystack) {
    if (!Q_stricmpn(haystack, needle, needle_len)) {
      Q_strcat(dest, sizeof(dest), new);
      haystack += needle_len;
      destp += new_len;
      continue;
    }
    if (1024 > (strlen(dest) + 1)) {
      *destp = *haystack;
      *++destp = '\0';
    }
    haystack++;
  }
  Q_strncpyz(final, dest, sizeof(final));
  return final;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<KaDisp_send_cache_all_pages>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movw   $0x0,-0x2(%rbp)
  jmp    L13
L11:
  movzwl -0x2(%rbp),%eax
  mov    %eax,%edi
  call   <KaDisp_send_page_cache@plt>
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L13:
  cmpw   $0x7,-0x2(%rbp)
  jbe    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void KaDisp_send_cache_all_pages(void) {
  unsigned short p;
  for (p = 0; p < 8; p++) {
    KaDisp_send_page_cache(p);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<KaDisp_send_cache_all_pages>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L5:
  mov    %ebx,%edi
  call   <KaDisp_send_page_cache@plt>
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void KaDisp_send_cache_all_pages(void) {
  unsigned short p;
  for (p = 0; p < 8; p++) {
    KaDisp_send_page_cache(p);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<KaDisp_send_cache_all_pages>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <KaDisp_send_page_cache@plt>
  cmp    $0x8,%ebx
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
void KaDisp_send_cache_all_pages(void) {
  unsigned short p;
  for (p = 0; p < 8; p++) {
    KaDisp_send_page_cache(p);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<KaDisp_send_cache_all_pages>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <KaDisp_send_page_cache@plt>
  cmp    $0x8,%ebx
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
void KaDisp_send_cache_all_pages(void) {
  unsigned short p;
  for (p = 0; p < 8; p++) {
    KaDisp_send_page_cache(p);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L10
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xaaaaaaab,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    %eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <Bad>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
L10:
  leave
  ret
```

assistant: ```c
int Bad(unsigned int N) {
  if (N == 0)
    return 0;
  else
    return Bad(N / 3 + 1) + N - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Bad>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  jne    L3
  ret
L3:
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%edi
  mov    $0xaaaaaaab,%eax
  imul   %rax,%rdi
  shr    $0x21,%rdi
  add    $0x1,%edi
  call   <Bad>
  lea    -0x1(%rbx,%rax,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
int Bad(unsigned int N) {
  if (N == 0)
    return 0;
  else
    return Bad(N / 3 + 1) + N - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Bad>:
  endbr64
  test   %edi,%edi
  je     L15
L17:
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Bad(unsigned int N) {
  if (N == 0)
    return 0;
  else
    return Bad(N / 3 + 1) + N - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Bad>:
  endbr64
  test   %edi,%edi
  je     L1
L15:
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Bad(unsigned int N) {
  if (N == 0)
    return 0;
  else
    return Bad(N / 3 + 1) + N - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fsg_get_gog_game_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fsg_get_gog_game_path(char *out, const char *app_id) {
  out[0] = '\0';
  (void)app_id;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fsg_get_gog_game_path>:
  endbr64
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void fsg_get_gog_game_path(char *out, const char *app_id) {
  out[0] = '\0';
  (void)app_id;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fsg_get_gog_game_path>:
  endbr64
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void fsg_get_gog_game_path(char *out, const char *app_id) {
  out[0] = '\0';
  (void)app_id;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fsg_get_gog_game_path>:
  endbr64
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void fsg_get_gog_game_path(char *out, const char *app_id) {
  out[0] = '\0';
  (void)app_id;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kmemcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int kmemcpy(addr, offset, size)
char *addr;
long offset;
int size;
{
  bcopy((char *)offset, addr, size);
  return 0;
}
```