ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  sub    $0x17447d68,%rax
  mov    %rax,(%rsp)
  test   %rdi,%rdi
  je     L42
  xor    %ecx,%ecx
L0:
  lea    (%rcx,%rcx,1),%r10
  xor    %r9d,%r9d
  xor    %r8d,%r8d
L28:
  cmp    %r9,%rax
  je     L36
  mov    %rax,%rdx
  shl    $0x5,%rdx
  and    $0x1f0,%edx
  or     %rdx,%rax
  mov    %rax,%rdx
  mov    %rax,(%rsp,%rcx,8)
  shr    $0x20,%rdx
  mov    %ax,0x4(%rsp)
  shr    $0x10,%rax
  mov    %dx,0x2(%rsp)
  mov    %ax,(%rsp)
  mov    (%rsp),%rax
L36:
  add    $0x2,%r8
  add    %r10,%r9
  cmp    %rdi,%r8
  jb     L28
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L0
L42:
  movabs $0xa000000003b05c36,%rdx
  add    $0x2ecea54,%rax
  xor    %rdx,%rax
  mov    %rax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x18,%rsp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] == local2 * local1) {
          state[0UL] = state[local1] | state[0UL];
          copy11 = *((unsigned int *)(&state[local2]) + 1);
          *((unsigned int *)(&state[local2]) + 1) = *((unsigned int *)(&state[local2]) + 0);
          *((unsigned int *)(&state[local2]) + 0) = copy11;
          copy11 = *((unsigned int *)(&state[local2]) + 0);
          *((unsigned int *)(&state[local2]) + 0) = *((unsigned int *)(&state[local2]) + 1);
          *((unsigned int *)(&state[local2]) + 1) = copy11;
        } else {
          state[local1] |= ((state[local2] + state[local1]) & 31UL) << 4UL;
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 49080916UL) ^ 0xa000000003b05c36UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  sub    $0x17447d68,%rax
  mov    %rax,(%rsp)
  test   %rdi,%rdi
  je     L11
  xor    %ecx,%ecx
L12:
  lea    (%rcx,%rcx,1),%r10
  xor    %r9d,%r9d
  xor    %r8d,%r8d
L60:
  cmp    %r9,%rax
  je     L40
  mov    %rax,%rdx
  add    $0x2,%r8
  add    %r10,%r9
  shl    $0x5,%rdx
  and    $0x1f0,%edx
  or     %rdx,%rax
  mov    %rax,%rdx
  mov    %rax,(%rsp,%rcx,8)
  shr    $0x20,%rdx
  mov    %ax,0x4(%rsp)
  shr    $0x10,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  mov    %eax,(%rsp)
  mov    (%rsp),%rax
  cmp    %r8,%rdi
  ja     L60
L4:
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L12
L11:
  movabs $0xa000000003b05c36,%rdx
  add    $0x2ecea54,%rax
  xor    %rdx,%rax
  mov    %rax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L40:
  add    $0x2,%r8
  lea    (%rax,%r10,1),%r9
  cmp    %rdi,%r8
  jb     L60
  jmp    L4
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] == local2 * local1) {
          state[0UL] = state[local1] | state[0UL];
          copy11 = *((unsigned int *)(&state[local2]) + 1);
          *((unsigned int *)(&state[local2]) + 1) = *((unsigned int *)(&state[local2]) + 0);
          *((unsigned int *)(&state[local2]) + 0) = copy11;
          copy11 = *((unsigned int *)(&state[local2]) + 0);
          *((unsigned int *)(&state[local2]) + 0) = *((unsigned int *)(&state[local2]) + 1);
          *((unsigned int *)(&state[local2]) + 1) = copy11;
        } else {
          state[local1] |= ((state[local2] + state[local1]) & 31UL) << 4UL;
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 49080916UL) ^ 0xa000000003b05c36UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %edi,-0x3f4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3f4(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int foo(int len) {
  char array[1000];
  bzero(array, len);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  sub    $0x3f8,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <bzero@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int len) {
  char array[1000];
  bzero(array, len);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  sub    $0x3f8,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <bzero@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x3f8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int len) {
  char array[1000];
  bzero(array, len);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  sub    $0x3f8,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <bzero@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x3f8,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int len) {
  char array[1000];
  bzero(array, len);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x23,-0x19(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L57:
  lea    -0x19(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl -0x19(%rbp),%eax
  cmp    $0x2b,%al
  jne    L45
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L113
L45:
  movzbl -0x19(%rbp),%eax
  cmp    $0x2d,%al
  jne    L91
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L113
L91:
  movzbl -0x19(%rbp),%eax
  cmp    $0x2a,%al
  jne    L34
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L113
L34:
  movzbl -0x19(%rbp),%eax
  cmp    $0x2f,%al
  jne    L113
  movsd  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L86
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L86
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L113
L86:
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L113:
  movzbl -0x19(%rbp),%eax
  cmp    $0x26,%al
  jne    L57
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D61
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D57
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D61: %lf

tool: D29: %lf %c

tool: D57: %.3lf


tool: D4: operacao nao pode ser realizada

assistant: ```c
int main(int argc, char const *argv[]) {
  double a, b;
  char c = '#';
  scanf("%lf", &a);
  do {
    scanf("%lf %c", &b, &c);
    if (c == '+') {
      a += b;
      printf("%.3lf\n", a);
    } else if (c == '-') {
      a -= b;
      printf("%.3lf\n", a);
    } else if (c == '*') {
      a *= b;
      printf("%.3lf\n", a);
    } else if (c == '/') {
      if (b == 0) {
        printf("operacao nao pode ser realizada");
      } else {
        a /= b;
        printf("%.3lf\n", a);
      }
    }
  } while (c != '&');
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x23,0x7(%rsp)
  lea    0x8(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rbx
  lea    D13(%rip),%rbp
  jmp    L48
L2:
  movsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L62:
  cmpb   $0x26,0x7(%rsp)
  je     L106
L48:
  lea    0x7(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x2b,%al
  je     L2
  cmp    $0x2d,%al
  je     L90
  cmp    $0x2a,%al
  je     L53
  cmp    $0x2f,%al
  jne    L62
  movsd  0x10(%rsp),%xmm1
  ucomisd D7(%rip),%xmm1
  jp     L21
  jne    L21
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L62
L90:
  movsd  0x8(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L62
L53:
  movsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L62
L21:
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L62
L106:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L109:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D33
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D28
type_guessed: string

tool: D33: %lf

tool: D26: %lf %c

tool: D13: %.3lf


tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D28: operacao nao pode ser realizada

assistant: ```c
int main(int argc, char const *argv[]) {
  double a, b;
  char c = '#';
  scanf("%lf", &a);
  do {
    scanf("%lf %c", &b, &c);
    if (c == '+') {
      a += b;
      printf("%.3lf\n", a);
    } else if (c == '-') {
      a -= b;
      printf("%.3lf\n", a);
    } else if (c == '*') {
      a *= b;
      printf("%.3lf\n", a);
    } else if (c == '/') {
      if (b == 0) {
        printf("operacao nao pode ser realizada");
      } else {
        a /= b;
        printf("%.3lf\n", a);
      }
    }
  } while (c != '&');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D32(%rip),%rdi
  lea    D14(%rip),%r14
  push   %r13
  lea    D37(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  movb   $0x23,0x7(%rsp)
  lea    0x7(%rsp),%r12
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  jmp    L110
  nopw   0x0(%rax,%rax,1)
L126:
  cmp    $0x2d,%al
  je     L127
  cmp    $0x2a,%al
  je     L138
  cmp    $0x2f,%al
  je     L113
L31:
  cmp    $0x26,%al
  je     L116
L110:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x2b,%al
  jne    L126
  movsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
L98:
  mov    %r13,%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x26,%al
  jne    L110
L116:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L113:
  movsd  0x10(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm1
  jp     L135
  jne    L135
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x7(%rsp),%eax
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L127:
  movsd  0x8(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  jmp    L98
  nopl   0x0(%rax)
L138:
  movsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  jmp    L98
  nopl   0x0(%rax)
L135:
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L98
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D32
type: string
name: extract_symbolic_data
arguments: tag: D14
type: string
name: extract_symbolic_data
arguments: tag: D37
type: string
name: extract_symbolic_data
arguments: tag: D13
type: string

tool: D32: %lf

tool: D14: operacao nao pode ser realizada

tool: D37: %.3lf


tool: D13: %lf %c

assistant: ```c
int main(int argc, char const *argv[]) {
  double a, b;
  char c = '#';
  scanf("%lf", &a);
  do {
    scanf("%lf %c", &b, &c);
    if (c == '+') {
      a += b;
      printf("%.3lf\n", a);
    } else if (c == '-') {
      a -= b;
      printf("%.3lf\n", a);
    } else if (c == '*') {
      a *= b;
      printf("%.3lf\n", a);
    } else if (c == '/') {
      if (b == 0) {
        printf("operacao nao pode ser realizada");
      } else {
        a /= b;
        printf("%.3lf\n", a);
      }
    }
  } while (c != '&');
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D26(%rip),%rdi
  lea    D13(%rip),%r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D37(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  movb   $0x23,0x7(%rsp)
  lea    0x7(%rsp),%r12
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  jmp    L137
  nopw   0x0(%rax,%rax,1)
L34:
  cmp    $0x2d,%al
  je     L52
  cmp    $0x2a,%al
  je     L11
  cmp    $0x2f,%al
  je     L5
L61:
  cmp    $0x26,%al
  je     L116
L137:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x2b,%al
  jne    L34
  movsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
L97:
  mov    %r13,%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x26,%al
  jne    L137
L116:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L5:
  movsd  0x10(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm1
  jp     L15
  jne    L15
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x7(%rsp),%eax
  jmp    L61
  cs nopw 0x0(%rax,%rax,1)
L52:
  movsd  0x8(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  jmp    L97
  nopl   0x0(%rax)
L11:
  movsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  jmp    L97
  nopl   0x0(%rax)
L15:
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L97
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D26
type_infered: string
name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D37
type_infered: string

tool: D26: %lf

tool: D13: operacao nao pode ser realizada

tool: D25: %.3lf


tool: D37: %lf %c

assistant: ```c
int main(int argc, char const *argv[]) {
  double a, b;
  char c = '#';
  scanf("%lf", &a);
  do {
    scanf("%lf %c", &b, &c);
    if (c == '+') {
      a += b;
      printf("%.3lf\n", a);
    } else if (c == '-') {
      a -= b;
      printf("%.3lf\n", a);
    } else if (c == '*') {
      a *= b;
      printf("%.3lf\n", a);
    } else if (c == '/') {
      if (b == 0) {
        printf("operacao nao pode ser realizada");
      } else {
        a /= b;
        printf("%.3lf\n", a);
      }
    }
  } while (c != '&');
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L2
L18:
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
L2:
  leave
  ret
```

assistant: ```c
void *calloc(size_t n, size_t size) {
  char *ptr = malloc(n * size);
  if (!ptr)
    return NULL;
  memset(ptr, 0, n * size);
  return (void *)ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *calloc(size_t n, size_t size) {
  char *ptr = malloc(n * size);
  if (!ptr)
    return NULL;
  memset(ptr, 0, n * size);
  return (void *)ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t n, size_t size) {
  char *ptr = malloc(n * size);
  if (!ptr)
    return NULL;
  memset(ptr, 0, n * size);
  return (void *)ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t n, size_t size) {
  char *ptr = malloc(n * size);
  if (!ptr)
    return NULL;
  memset(ptr, 0, n * size);
  return (void *)ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  movl   $0x1,-0x30(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L65
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L65
L37:
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x30(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x38(%rbp)
L65:
  mov    -0x28(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L37
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L56
L28:
  mov    -0x38(%rbp),%eax
  and    -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  lea    D23(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  jns    L7
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L7:
  addl   $0x1,-0x34(%rbp)
L56:
  cmpl   $0xf423f,-0x34(%rbp)
  jbe    L28
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D42
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D22
type_guessed: string
name: disassemble_data
arguments: data_label: D28
type_guessed: string
name: disassemble_data
arguments: data_label: D23
type_guessed: string
name: disassemble_data
arguments: data_label: D30
type_guessed: string

tool: D5: r

tool: D42: out/testdata

tool: D24: read error

tool: D22: w

tool: D28: out/output_bit_array_sort

tool: D23: %07u


tool: D30: write error

assistant: ```c
int main() {
  unsigned int bit_array = 0;
  unsigned int a = 1;
  unsigned int result;
  FILE *fr;
  FILE *fw;
  char row[10];
  fr = fopen("out/testdata", "r");
  if (!fr) {
    puts("read error");
    exit(1);
  }
  while (fgets(row, sizeof(row), fr) != NULL) {
    int x = atoi(row);
    bit_array = bit_array | (a << x);
  }
  fclose(fr);
  fw = fopen("out/output_bit_array_sort", "w");
  unsigned i;
  for (i = 0; i < 1000000; i++) {
    if (fprintf(fw, "%07u\n", bit_array & i) < 0) {
      puts("write error");
      exit(1);
    }
  }
  fclose(fw);
  return 0;
}
```