ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiply371>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L39
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L10:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L68
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L68
  nopl   0x0(%rax)
L61:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L61
  cmp    -0x24(%rsp),%r11d
  je     L24
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L24
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L24
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L24:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L10
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L68:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L55:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L55
  mov    -0x18(%rsp),%r8
  jmp    L24
```

assistant: ```c
void multiply371(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getHeadCommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getHeadCommand(char *input) {
  char *temp = (char *)malloc(sizeof(char) * 2);
  temp[0] = input[0];
  temp[1] = '\0';
  return temp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getHeadCommand>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  mov    %dl,(%rax)
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *getHeadCommand(char *input) {
  char *temp = (char *)malloc(sizeof(char) * 2);
  temp[0] = input[0];
  temp[1] = '\0';
  return temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getHeadCommand>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  movb   $0x0,0x1(%rax)
  mov    %dl,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *getHeadCommand(char *input) {
  char *temp = (char *)malloc(sizeof(char) * 2);
  temp[0] = input[0];
  temp[1] = '\0';
  return temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getHeadCommand>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  movb   $0x0,0x1(%rax)
  mov    %dl,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *getHeadCommand(char *input) {
  char *temp = (char *)malloc(sizeof(char) * 2);
  temp[0] = input[0];
  temp[1] = '\0';
  return temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <smallestFloat@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D24
type: string

tool: D3: Enter 3 floats separated by spaces: 

tool: D12: %f%f%f

tool: D24: The smallest number is = %f


assistant: ```c
int main() {
  float a, b, c;
  printf("Enter 3 floats separated by spaces: ");
  scanf("%f%f%f", &a, &b, &c);
  printf("The smallest number is = %f\n", smallestFloat(a, b, c));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <smallestFloat@plt>
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D25
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D17
type_infered: string

tool: D25: Enter 3 floats separated by spaces: 

tool: D18: %f%f%f

tool: D17: The smallest number is = %f


assistant: ```c
int main() {
  float a, b, c;
  printf("Enter 3 floats separated by spaces: ");
  scanf("%f%f%f", &a, &b, &c);
  printf("The smallest number is = %f\n", smallestFloat(a, b, c));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D12(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <smallestFloat@plt>
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D7
type: string

tool: D6: Enter 3 floats separated by spaces: 

tool: D12: %f%f%f

tool: D7: The smallest number is = %f


assistant: ```c
int main() {
  float a, b, c;
  printf("Enter 3 floats separated by spaces: ");
  scanf("%f%f%f", &a, &b, &c);
  printf("The smallest number is = %f\n", smallestFloat(a, b, c));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D6(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <smallestFloat@plt>
  lea    D2(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D21
datatype: string
name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string

tool: D21: Enter 3 floats separated by spaces: 

tool: D6: %f%f%f

tool: D2: The smallest number is = %f


assistant: ```c
int main() {
  float a, b, c;
  printf("Enter 3 floats separated by spaces: ");
  scanf("%f%f%f", &a, &b, &c);
  printf("The smallest number is = %f\n", smallestFloat(a, b, c));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6c6c654820212121,%rax
  movabs $0x726576696e55206f,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movabs $0x212121206573,%rax
  mov    $0x0,%edx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
char *getString() {
  char message[100] = "!!! Hello Universe !!!";
  char *ret = message;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getString>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  mov    %rsp,%rax
  add    $0x78,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *getString() {
  char message[100] = "!!! Hello Universe !!!";
  char *ret = message;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getString>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *getString() {
  char message[100] = "!!! Hello Universe !!!";
  char *ret = message;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getString>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *getString() {
  char message[100] = "!!! Hello Universe !!!";
  char *ret = message;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vflip1_uimatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  jmp    L38
L12:
  mov    -0x30(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L20
L8:
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L8
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vflip1_uimatrix(uint **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  uint t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vflip1_uimatrix>:
  endbr64
  movslq %esi,%rax
  cmp    %rax,%rdx
  jl     L7
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r8,%rbp
  mov    %edx,%r11d
  lea    (%rdi,%rax,8),%rsi
  lea    0x8(%rdi,%rdx,8),%r13
  movslq %ecx,%r12
  shl    $0x2,%r12
  lea    0x4(,%r8,4),%r10
  movslq %ecx,%r8
L16:
  cmp    %r8,%rbp
  jl     L4
  movslq %r11d,%rax
  lea    (%rbx,%rax,8),%r9
  mov    %r12,%rax
L14:
  mov    %rax,%rdx
  add    (%r9),%rdx
  mov    (%rdx),%ecx
  mov    (%rsi),%rdi
  mov    (%rdi,%rax,1),%edi
  mov    %edi,(%rdx)
  mov    (%rsi),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %r10,%rax
  jne    L14
L4:
  add    $0x8,%rsi
  sub    $0x1,%r11d
  cmp    %r13,%rsi
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  ret
```

assistant: ```c
void vflip1_uimatrix(uint **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  uint t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<vflip1_uimatrix>:
  endbr64
  movslq %esi,%r10
  push   %r13
  push   %r12
  lea    (%rsi,%rdx,1),%r12d
  push   %rbp
  push   %rbx
  cmp    %r10,%rdx
  jl     L5
  mov    %r8,%rbp
  movslq %ecx,%r8
  mov    %rdi,%r11
  mov    %rdx,%rbx
  lea    0x0(,%r8,4),%r13
  lea    0x4(,%rbp,4),%r9
  nopw   0x0(%rax,%rax,1)
L47:
  cmp    %r8,%rbp
  jl     L2
  mov    %r12d,%eax
  mov    (%r11,%r10,8),%rdx
  sub    %r10d,%eax
  cltq
  mov    (%r11,%rax,8),%rcx
  mov    %r13,%rax
L26:
  mov    (%rcx,%rax,1),%esi
  mov    (%rdx,%rax,1),%edi
  mov    %edi,(%rcx,%rax,1)
  mov    %esi,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%r9
  jne    L26
L2:
  lea    0x1(%r10),%rax
  cmp    %r10,%rbx
  je     L5
  mov    %rax,%r10
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void vflip1_uimatrix(uint **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  uint t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vflip1_uimatrix>:
  endbr64
  push   %r15
  mov    %rcx,%rax
  lea    (%rsi,%rdx,1),%ecx
  movslq %esi,%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8,-0x28(%rsp)
  cmp    %rsi,%rdx
  jl     L111
  movslq %eax,%r11
  mov    %eax,-0xc(%rsp)
  mov    %r8,%r15
  cmp    %r11,%r8
  jl     L111
  sub    %r11,%r15
  mov    %rdi,%rbp
  movslq %ecx,%rcx
  lea    0x1(%r15),%r14
  lea    0x8(%rbp,%rdx,8),%rbx
  mov    %r14,%rdx
  mov    %rbx,-0x30(%rsp)
  lea    0x0(,%rcx,8),%rbx
  lea    (%rdi,%rsi,8),%rdi
  and    $0xfffffffffffffffc,%rdx
  mov    %rbx,-0x38(%rsp)
  lea    0x0(,%r11,4),%rbx
  mov    %r8,%rsi
  add    %edx,%eax
  mov    %r14,%r8
  mov    %rdx,-0x20(%rsp)
  lea    0x10(,%r11,4),%r12
  mov    %eax,-0x10(%rsp)
  shr    $0x2,%r8
  lea    0x4(,%rsi,4),%r13
  mov    %rbx,-0x18(%rsp)
  shl    $0x4,%r8
  nopl   (%rax)
L10:
  mov    -0x38(%rsp),%rax
  mov    (%rdi),%rsi
  sub    %rdi,%rax
  lea    (%rsi,%r12,1),%r9
  lea    (%rsi,%rbx,1),%rcx
  mov    (%rax,%rbp,2),%rdx
  lea    (%rdx,%rbx,1),%rax
  cmp    %r9,%rax
  lea    (%rdx,%r12,1),%r9
  setae  %r10b
  cmp    %r9,%rcx
  setae  %r9b
  or     %r10b,%r9b
  je     L22
  cmp    %r11,-0x28(%rsp)
  je     L22
  cmp    $0x2,%r15
  jbe    L55
  xor    %r9d,%r9d
  xchg   %ax,%ax
L114:
  movdqu (%rax,%r9,1),%xmm0
  movdqu (%rcx,%r9,1),%xmm2
  movups %xmm2,(%rax,%r9,1)
  movups %xmm0,(%rcx,%r9,1)
  add    $0x10,%r9
  cmp    %r8,%r9
  jne    L114
  mov    -0x20(%rsp),%rax
  cmp    %rax,%r14
  je     L28
  mov    %rax,%rcx
  mov    -0x10(%rsp),%eax
L112:
  mov    %r14,%r10
  sub    %rcx,%r10
  cmp    %rcx,%r15
  je     L101
  add    %r11,%rcx
  shl    $0x2,%rcx
  lea    (%rdx,%rcx,1),%r9
  add    %rsi,%rcx
  movq   (%rcx),%xmm1
  movq   (%r9),%xmm0
  movq   %xmm1,(%r9)
  movq   %xmm0,(%rcx)
  mov    %r10,%rcx
  and    $0xfffffffffffffffe,%rcx
  add    %ecx,%eax
  cmp    %rcx,%r10
  je     L28
L101:
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  add    %rsi,%rax
  mov    (%rdx),%ecx
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
L28:
  add    $0x8,%rdi
  cmp    -0x30(%rsp),%rdi
  jne    L10
L111:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    -0x18(%rsp),%rax
  nopl   (%rax)
L72:
  mov    (%rdx,%rax,1),%ecx
  mov    (%rsi,%rax,1),%r9d
  mov    %r9d,(%rdx,%rax,1)
  mov    %ecx,(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%r13
  jne    L72
  jmp    L28
L55:
  mov    -0xc(%rsp),%eax
  xor    %ecx,%ecx
  jmp    L112
```

assistant: ```c
void vflip1_uimatrix(uint **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  uint t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D26
type_infered: string

tool: D6: test1

tool: D5: 
%s: 


tool: D26:  test lib

assistant: ```c
test1() {
  printf("\n%s: \n", __func__);
  printf(" test lib\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test1>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string
name: retrieve_data
arguments: data_label: D22
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string

tool: D5: test1

tool: D22: 
%s: 


tool: D12:  test lib

assistant: ```c
test1() {
  printf("\n%s: \n", __func__);
  printf(" test lib\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test1>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  lea    D20(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_infered: string
name: disassemble_data
arguments: tag: D20
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D15: 
%s: 


tool: D20: test1

tool: D2:  test lib

assistant: ```c
test1() {
  printf("\n%s: \n", __func__);
  printf(" test lib\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<test1>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  lea    D6(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D6
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D12: 
%s: 


tool: D6: test1

tool: D4:  test lib

assistant: ```c
test1() {
  printf("\n%s: \n", __func__);
  printf(" test lib\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_putnbr_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L30
  cmpl   $0x80000000,-0x14(%rbp)
  jne    L41
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
  jmp    L36
L41:
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  negl   -0x14(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L47
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <ft_putnbr_base>
  jmp    L36
L47:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L36:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: -2147483648

assistant: ```c
void ft_putnbr_base(int n, char *str) {
  int base;
  base = ft_strlen(str);
  if (n < 0) {
    if (n == -2147483648) {
      ft_putstr("-2147483648");
      return;
    } else {
      ft_putchar('-');
      n = n * -1;
    }
  }
  if (n >= base)
    ft_putnbr_base(n / base, str);
  else
    ft_putchar(str[(n % base)]);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_putnbr_base>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%ebp
  test   %ebx,%ebx
  js     L34
L38:
  cmp    %ebp,%ebx
  jl     L48
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %eax,%edi
  mov    %r12,%rsi
  call   <ft_putnbr_base>
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  cmp    $0x80000000,%ebx
  je     L50
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  neg    %ebx
  jmp    L38
L50:
  lea    D4(%rip),%rdi
  call   <ft_putstr@plt>
  jmp    L40
L48:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  movslq %edx,%rdx
  movsbl (%r12,%rdx,1),%edi
  call   <ft_putchar@plt>
  jmp    L40
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: -2147483648

assistant: ```c
void ft_putnbr_base(int n, char *str) {
  int base;
  base = ft_strlen(str);
  if (n < 0) {
    if (n == -2147483648) {
      ft_putstr("-2147483648");
      return;
    } else {
      ft_putchar('-');
      n = n * -1;
    }
  }
  if (n >= base)
    ft_putnbr_base(n / base, str);
  else
    ft_putchar(str[(n % base)]);
}
```