ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
L20:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %rbp,%r12
  jne    L20
  mov    0x24(%rsp),%eax
  mov    (%rsp),%edx
  movdqu 0x14(%rsp),%xmm1
  movdqu 0x4(%rsp),%xmm0
  mov    %eax,0x20(%rsp)
  mov    0x28(%rsp),%eax
  mov    %edx,0x28(%rsp)
  mov    %eax,0x24(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm1,0x10(%rsp)
L11:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L11
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: %d

assistant: ```c
int main(int argc, char **argv) {
  int a[10], t, *p;
  for (int i = 0; i < 10; i++)
    scanf("%d", a + i);
  for (p = a; p < (a + 10); p++) {
    *p += *(p + 1);
    *(p + 1) = *p - *(p + 1);
    *p -= *(p + 1);
  }
  for (int i = 0; i < 10; i++)
    printf("%d", a[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TrimCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L3
L0:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L0
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L11:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L11
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void TrimCopy(char *Trim, char *Line, int n) {
  int l;
  char *s;
  l = strlen(Line);
  Line[--l] = 0;
  while (Line[l - 1] == ' ')
    Line[--l] = 0;
  s = Line;
  while (*s == ' ')
    ++s;
  strncpy(Trim, s, n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TrimCopy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %rsi,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rbx,%rax,1)
  lea    -0x1(%rbx,%rax,1),%rdx
  cmpb   $0x20,(%rdx)
  jne    L30
  lea    -0x2(%rbx,%rax,1),%rax
L7:
  movb   $0x0,(%rdx)
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rax)
  je     L7
L30:
  cmpb   $0x20,(%rbx)
  jne    L26
L15:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L15
L26:
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void TrimCopy(char *Trim, char *Line, int n) {
  int l;
  char *s;
  l = strlen(Line);
  Line[--l] = 0;
  while (Line[l - 1] == ' ')
    Line[--l] = 0;
  s = Line;
  while (*s == ' ')
    ++s;
  strncpy(Trim, s, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TrimCopy>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
  movb   $0x0,0x0(%rbp,%rax,1)
  cmpb   $0x20,(%rcx)
  jne    L9
  lea    -0x2(%rbp,%rax,1),%rax
  nopl   0x0(%rax,%rax,1)
L11:
  movb   $0x0,(%rcx)
  mov    %rax,%rcx
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rax)
  je     L11
  cmpb   $0x20,0x0(%rbp)
  jne    L26
  xchg   %ax,%ax
L39:
  add    $0x1,%rbp
L9:
  cmpb   $0x20,0x0(%rbp)
  je     L39
L26:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <strncpy@plt>
```

assistant: ```c
void TrimCopy(char *Trim, char *Line, int n) {
  int l;
  char *s;
  l = strlen(Line);
  Line[--l] = 0;
  while (Line[l - 1] == ' ')
    Line[--l] = 0;
  s = Line;
  while (*s == ' ')
    ++s;
  strncpy(Trim, s, n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TrimCopy>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
  movb   $0x0,0x0(%rbp,%rax,1)
  cmpb   $0x20,(%rcx)
  jne    L3
  lea    -0x2(%rbp,%rax,1),%rax
  nopl   0x0(%rax,%rax,1)
L20:
  movb   $0x0,(%rcx)
  mov    %rax,%rcx
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rax)
  je     L20
  cmpb   $0x20,0x0(%rbp)
  jne    L18
  xchg   %ax,%ax
L38:
  add    $0x1,%rbp
L3:
  cmpb   $0x20,0x0(%rbp)
  je     L38
L18:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <strncpy@plt>
```

assistant: ```c
void TrimCopy(char *Trim, char *Line, int n) {
  int l;
  char *s;
  l = strlen(Line);
  Line[--l] = 0;
  while (Line[l - 1] == ' ')
    Line[--l] = 0;
  s = Line;
  while (*s == ' ')
    ++s;
  strncpy(Trim, s, n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strtoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    D16(%rip),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L104
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x14(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L19
  jmp    L75
L104:
  mov    D16(%rip),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  jmp    L5
L75:
  cmpl   $0x0,-0x14(%rbp)
  jne    L45
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  je     L19
L45:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
L19:
  mov    $0x1,%eax
  jmp    L72
L11:
  mov    $0x0,%eax
L72:
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L42
  mov    D16(%rip),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  jmp    L5
L42:
  mov    -0x14(%rbp),%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
int strtoint(char *str) {
  int ret;
  char *endptr = {0};
  errno = 0;
  if ((__builtin_expect(!!(*str), 1))) {
    ret = strtol(str, &endptr, 10);
  } else {
    errno = 1;
    return 0;
  }
  if ((__builtin_expect(!!(errno != 0 || (!ret && endptr == str) || (*endptr != '\0')), 0))) {
    errno = 1;
    return 0;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtoint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    D21(%rip),%rax
  movl   $0x0,(%rax)
  cmpb   $0x0,(%rdi)
  setne  %dil
  movzbl %dil,%edi
  mov    $0x1,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L67
  mov    D21(%rip),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%ebp
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    %eax,%ebp
  mov    $0x1,%edi
  mov    D21(%rip),%rax
  cmpl   $0x0,(%rax)
  jne    L58
  test   %ebp,%ebp
  jne    L3
  mov    $0x1,%edi
  cmp    %rbx,(%rsp)
  je     L58
L3:
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  setne  %dil
  movzbl %dil,%edi
L58:
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L33
  mov    D21(%rip),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%ebp
  jmp    L33
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strtoint(char *str) {
  int ret;
  char *endptr = {0};
  errno = 0;
  if ((__builtin_expect(!!(*str), 1))) {
    ret = strtol(str, &endptr, 10);
  } else {
    errno = 1;
    return 0;
  }
  if ((__builtin_expect(!!(errno != 0 || (!ret && endptr == str) || (*endptr != '\0')), 0))) {
    errno = 1;
    return 0;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtoint>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    D1(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movl   $0x0,0x0(%rbp)
  cmpb   $0x0,(%rdi)
  setne  %dil
  movzbl %dil,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L5
L39:
  movl   $0x1,0x0(%rbp)
  xor    %r12d,%r12d
L62:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L5:
  mov    %rbx,%rdi
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    $0x1,%edi
  mov    %eax,%r12d
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jne    L58
  mov    (%rsp),%rax
  test   %r12d,%r12d
  je     L2
L25:
  xor    %edi,%edi
  cmpb   $0x0,(%rax)
  setne  %dil
L58:
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L62
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L2:
  cmp    %rax,%rbx
  jne    L25
  jmp    L58
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strtoint(char *str) {
  int ret;
  char *endptr = {0};
  errno = 0;
  if ((__builtin_expect(!!(*str), 1))) {
    ret = strtol(str, &endptr, 10);
  } else {
    errno = 1;
    return 0;
  }
  if ((__builtin_expect(!!(errno != 0 || (!ret && endptr == str) || (*endptr != '\0')), 0))) {
    errno = 1;
    return 0;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtoint>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    D9(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movl   $0x0,0x0(%rbp)
  cmpb   $0x0,(%rdi)
  setne  %dil
  movzbl %dil,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L54
L17:
  movl   $0x1,0x0(%rbp)
  xor    %r12d,%r12d
L77:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L54:
  mov    %rbx,%rdi
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    $0x1,%edi
  mov    %eax,%r12d
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jne    L0
  mov    (%rsp),%rax
  test   %r12d,%r12d
  je     L36
L4:
  xor    %edi,%edi
  cmpb   $0x0,(%rax)
  setne  %dil
L0:
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L77
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %rax,%rbx
  jne    L4
  jmp    L0
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strtoint(char *str) {
  int ret;
  char *endptr = {0};
  errno = 0;
  if ((__builtin_expect(!!(*str), 1))) {
    ret = strtol(str, &endptr, 10);
  } else {
    errno = 1;
    return 0;
  }
  if ((__builtin_expect(!!(errno != 0 || (!ret && endptr == str) || (*endptr != '\0')), 0))) {
    errno = 1;
    return 0;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jacobi>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  test   %ecx,%ecx
  jle    L68
  mov    %rdi,%r15
  mov    %rsi,%r14
  lea    -0x1(%rdx),%edx
  lea    0x0(,%rdx,8),%rax
  lea    0x8(%rdi,%rax,1),%r12
  lea    0x10(,%rdx,8),%rbx
  lea    0x8(%rsi,%rax,1),%rbp
  mov    $0x0,%r13d
  jmp    L90
L26:
  mov    $0x8,%eax
L43:
  mov    0x8(%rdx),%rcx
  mov    (%rdx),%r8
  mov    0x10(%rdx),%rdi
  movsd  (%r8,%rax,1),%xmm0
  addsd  (%rdi,%rax,1),%xmm0
  addsd  -0x8(%rcx,%rax,1),%xmm0
  mov    %rax,%rdi
  add    $0x8,%rax
  mov    (%rsi),%r8
  addsd  (%rcx,%rax,1),%xmm0
  mulsd  D19(%rip),%xmm0
  movsd  %xmm0,(%r8,%rdi,1)
  cmp    %rbx,%rax
  jne    L43
  add    $0x8,%rdx
  add    $0x8,%rsi
  cmp    %rbp,%rdx
  jne    L26
L84:
  mov    $0x0,%eax
  call   <dissBarrier@plt>
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  je     L68
L90:
  cmpl   $0x0,0x8(%rsp)
  jle    L0
  lea    0x8(%r14),%rsi
  mov    %r15,%rdx
L51:
  mov    $0x8,%eax
L66:
  mov    0x8(%rdx),%rcx
  mov    (%rdx),%r8
  mov    0x10(%rdx),%rdi
  movsd  (%r8,%rax,1),%xmm0
  addsd  (%rdi,%rax,1),%xmm0
  addsd  -0x8(%rcx,%rax,1),%xmm0
  mov    %rax,%rdi
  add    $0x8,%rax
  mov    (%rsi),%r8
  addsd  (%rcx,%rax,1),%xmm0
  mulsd  D19(%rip),%xmm0
  movsd  %xmm0,(%r8,%rdi,1)
  cmp    %rbx,%rax
  jne    L66
  add    $0x8,%rdx
  add    $0x8,%rsi
  cmp    %r12,%rdx
  jne    L51
  mov    $0x0,%eax
  call   <dissBarrier@plt>
  lea    0x8(%r15),%rsi
  mov    %r14,%rdx
  jmp    L26
L0:
  mov    $0x0,%eax
  call   <dissBarrier@plt>
  jmp    L84
L68:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_infered: f64

tool: D19: 0.25

assistant: ```c
void jacobi(double **grid, double **new, int gridSize, int iter) {
  for (int k = 0; k < iter; k++) {
#pragma omp for nowait schedule(static)
    for (int i = 1; i < gridSize + 1; i++) {
      for (int j = 1; j < gridSize + 1; j++) {
        new[i][j] = (grid[i - 1][j] + grid[i + 1][j] + grid[i][j - 1] + grid[i][j + 1]) * 0.25;
      }
    }
    dissBarrier();
#pragma omp for nowait schedule(static)
    for (int i = 1; i < gridSize + 1; i++) {
      for (int j = 1; j < gridSize + 1; j++) {
        grid[i][j] = (new[i - 1][j] + new[i + 1][j] + new[i][j - 1] + new[i][j + 1]) * 0.25;
      }
    }
    dissBarrier();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<jacobi>:
  endbr64
  movsd  D6(%rip),%xmm1
  test   %ecx,%ecx
  jle    L53
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L36:
  test   %ebp,%ebp
  jle    L7
  lea    0x1(%rbp),%r13d
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L21:
  mov    -0x8(%r14,%r8,8),%rdi
  mov    0x8(%r14,%r8,8),%rsi
  mov    $0x1,%eax
  mov    (%r14,%r8,8),%rdx
  mov    (%r15,%r8,8),%rcx
  nop
L10:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  addsd  -0x8(%rdx,%rax,8),%xmm0
  addsd  0x8(%rdx,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L10
  add    $0x1,%r8
  cmp    %r8,%r13
  jne    L21
  xor    %eax,%eax
  call   <dissBarrier@plt>
  movsd  D6(%rip),%xmm1
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    -0x8(%r15,%r8,8),%rdi
  mov    0x8(%r15,%r8,8),%rsi
  mov    $0x1,%eax
  mov    (%r15,%r8,8),%rdx
  mov    (%r14,%r8,8),%rcx
  nopw   0x0(%rax,%rax,1)
L64:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  addsd  -0x8(%rdx,%rax,8),%xmm0
  addsd  0x8(%rdx,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L64
  add    $0x1,%r8
  cmp    %r8,%r13
  jne    L14
L63:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <dissBarrier@plt>
  cmp    %ebx,%r12d
  movsd  D6(%rip),%xmm1
  jne    L36
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  xor    %eax,%eax
  call   <dissBarrier@plt>
  jmp    L63
L53:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: f64

tool: D6: 0.25

assistant: ```c
void jacobi(double **grid, double **new, int gridSize, int iter) {
  for (int k = 0; k < iter; k++) {
#pragma omp for nowait schedule(static)
    for (int i = 1; i < gridSize + 1; i++) {
      for (int j = 1; j < gridSize + 1; j++) {
        new[i][j] = (grid[i - 1][j] + grid[i + 1][j] + grid[i][j - 1] + grid[i][j + 1]) * 0.25;
      }
    }
    dissBarrier();
#pragma omp for nowait schedule(static)
    for (int i = 1; i < gridSize + 1; i++) {
      for (int j = 1; j < gridSize + 1; j++) {
        grid[i][j] = (new[i - 1][j] + new[i + 1][j] + new[i][j - 1] + new[i][j + 1]) * 0.25;
      }
    }
    dissBarrier();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <set_size@plt>
  test   %eax,%eax
  jg     L20
  mov    $0x0,%eax
  jmp    L35
L20:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <set_first_element@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <set_next_element@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <set_remove@plt>
  test   %eax,%eax
  jne    L34
  mov    $0x0,%eax
  jmp    L35
L34:
  mov    -0x8(%rbp),%rax
L35:
  leave
  ret
```

assistant: ```c
void *set_pop(struct set *s) {
  if (set_size(s) < 1)
    return 0;
  void *element;
  set_first_element(s);
  element = set_next_element(s);
  if (!set_remove(s, element))
    return 0;
  else
    return element;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_pop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <set_size@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  jle    L3
  mov    %rbp,%rdi
  call   <set_first_element@plt>
  mov    %rbp,%rdi
  call   <set_next_element@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <set_remove@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %rax,%rbx
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *set_pop(struct set *s) {
  if (set_size(s) < 1)
    return 0;
  void *element;
  set_first_element(s);
  element = set_next_element(s);
  if (!set_remove(s, element))
    return 0;
  else
    return element;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_pop>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <set_size@plt>
  test   %eax,%eax
  jle    L1
  mov    %rbp,%rdi
  call   <set_first_element@plt>
  mov    %rbp,%rdi
  call   <set_next_element@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <set_remove@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *set_pop(struct set *s) {
  if (set_size(s) < 1)
    return 0;
  void *element;
  set_first_element(s);
  element = set_next_element(s);
  if (!set_remove(s, element))
    return 0;
  else
    return element;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_pop>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <set_size@plt>
  test   %eax,%eax
  jle    L4
  mov    %rbp,%rdi
  call   <set_first_element@plt>
  mov    %rbp,%rdi
  call   <set_next_element@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <set_remove@plt>
  test   %eax,%eax
  je     L4
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *set_pop(struct set *s) {
  if (set_size(s) < 1)
    return 0;
  void *element;
  set_first_element(s);
  element = set_next_element(s);
  if (!set_remove(s, element))
    return 0;
  else
    return element;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<low6_base64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L50
  cmpb   $0x5a,-0x4(%rbp)
  jg     L50
  movzbl -0x4(%rbp),%eax
  sub    $0x41,%eax
  jmp    L7
L50:
  cmpb   $0x60,-0x4(%rbp)
  jle    L61
  cmpb   $0x7a,-0x4(%rbp)
  jg     L61
  movzbl -0x4(%rbp),%eax
  sub    $0x47,%eax
  jmp    L7
L61:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L78
  cmpb   $0x39,-0x4(%rbp)
  jg     L78
  movzbl -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L7
L78:
  cmpb   $0x2b,-0x4(%rbp)
  jne    L19
  mov    $0x3e,%eax
  jmp    L7
L19:
  cmpb   $0x2f,-0x4(%rbp)
  jne    L16
  mov    $0x3f,%eax
  jmp    L7
L16:
  mov    $0xffffffc0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char low6_base64(char c) {
  if ('A' <= c && c <= 'Z') {
    return c - 'A';
  } else if ('a' <= c && c <= 'z') {
    return 26 + c - 'a';
  } else if ('0' <= c && c <= '9') {
    return 52 + c - '0';
  } else if (c == '+') {
    return 62;
  } else if (c == '/') {
    return 63;
  } else {
    return 0xC0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<low6_base64>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L10
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L23
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L15
  cmp    $0x2b,%dil
  je     L8
  cmp    $0x2f,%dil
  mov    $0x3f,%eax
  mov    $0xffffffc0,%edx
  cmovne %edx,%eax
  ret
L23:
  lea    -0x47(%rdi),%eax
  ret
L15:
  lea    0x4(%rdi),%eax
  ret
L8:
  mov    $0x3e,%eax
L10:
  ret
```

assistant: ```c
unsigned char low6_base64(char c) {
  if ('A' <= c && c <= 'Z') {
    return c - 'A';
  } else if ('a' <= c && c <= 'z') {
    return 26 + c - 'a';
  } else if ('0' <= c && c <= '9') {
    return 52 + c - '0';
  } else if (c == '+') {
    return 62;
  } else if (c == '/') {
    return 63;
  } else {
    return 0xC0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<low6_base64>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L28
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L10
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L35
  cmp    $0x2b,%dil
  je     L22
  cmp    $0x2f,%dil
  mov    $0xffffffc0,%edx
  mov    $0x3f,%eax
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L22:
  mov    $0x3e,%eax
L28:
  ret
  xchg   %ax,%ax
L10:
  lea    -0x47(%rdi),%eax
  ret
  nopl   0x0(%rax)
L35:
  lea    0x4(%rdi),%eax
  ret
```

assistant: ```c
unsigned char low6_base64(char c) {
  if ('A' <= c && c <= 'Z') {
    return c - 'A';
  } else if ('a' <= c && c <= 'z') {
    return 26 + c - 'a';
  } else if ('0' <= c && c <= '9') {
    return 52 + c - '0';
  } else if (c == '+') {
    return 62;
  } else if (c == '/') {
    return 63;
  } else {
    return 0xC0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<low6_base64>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L15
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L24
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L11
  cmp    $0x2b,%dil
  je     L26
  cmp    $0x2f,%dil
  mov    $0xffffffc0,%edx
  mov    $0x3f,%eax
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L26:
  mov    $0x3e,%eax
L15:
  ret
  xchg   %ax,%ax
L24:
  lea    -0x47(%rdi),%eax
  ret
  nopl   0x0(%rax)
L11:
  lea    0x4(%rdi),%eax
  ret
```

assistant: ```c
unsigned char low6_base64(char c) {
  if ('A' <= c && c <= 'Z') {
    return c - 'A';
  } else if ('a' <= c && c <= 'z') {
    return 26 + c - 'a';
  } else if ('0' <= c && c <= '9') {
    return 52 + c - '0';
  } else if (c == '+') {
    return 62;
  } else if (c == '/') {
    return 63;
  } else {
    return 0xC0;
  }
}
```