ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rsi
  lea    D34(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L3
L61:
  lea    D33(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
L27:
  mov    %rsp,%rbx
  jmp    L14
  nopl   (%rax)
L66:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
L14:
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L66
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L61
L12:
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L27
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D34
type: string
name: parse_data
arguments: tag: D33
type: string
name: parse_data
arguments: tag: D1
type: string

tool: D2: r

tool: D34: infile.txt

tool: D33: w

tool: D1: outfile.txt

assistant: ```c
int main(void) {
  FILE *src, *dst;
  char buf[256];
  if ((src = fopen("infile.txt", "r")) == NULL) {
    exit(1);
  }
  if ((dst = fopen("outfile.txt", "w")) == NULL) {
    exit(2);
  }
  while ((fgets(buf, 256, src)) != NULL) {
    fputs(buf, dst);
  }
  fclose(src);
  fclose(dst);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rsi
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L59
L36:
  lea    D9(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
L32:
  mov    %rsp,%rbx
  jmp    L7
  nopl   (%rax)
L2:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
L7:
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L2
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L36
L5:
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L32
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D12
type_guessed: string

tool: D16: r

tool: D7: infile.txt

tool: D9: w

tool: D12: outfile.txt

assistant: ```c
int main(void) {
  FILE *src, *dst;
  char buf[256];
  if ((src = fopen("infile.txt", "r")) == NULL) {
    exit(1);
  }
  if ((dst = fopen("outfile.txt", "w")) == NULL) {
    exit(2);
  }
  while ((fgets(buf, 256, src)) != NULL) {
    fputs(buf, dst);
  }
  fclose(src);
  fclose(dst);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L16:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dest, char *src) {
  unsigned int i;
  for (i = 0; src[i] != 0; i++) {
    dest[i] = src[i];
  }
  dest[i] = 0;
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L3
  mov    $0x0,%r8d
  mov    $0x0,%ecx
L25:
  mov    %dl,(%rax,%rcx,1)
  add    $0x1,%r8d
  mov    %r8d,%ecx
  movzbl (%rsi,%rcx,1),%edx
  test   %dl,%dl
  jne    L25
L16:
  movb   $0x0,(%rax,%rcx,1)
  ret
L3:
  mov    $0x0,%ecx
  jmp    L16
```

assistant: ```c
char *strcpy(char *dest, char *src) {
  unsigned int i;
  for (i = 0; src[i] != 0; i++) {
    dest[i] = src[i];
  }
  dest[i] = 0;
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L14
  xor    %r8d,%r8d
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %cl,(%rax,%rdx,1)
  lea    0x1(%r8),%edx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %rdx,%r8
  test   %cl,%cl
  jne    L16
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax)
L14:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcpy(char *dest, char *src) {
  unsigned int i;
  for (i = 0; src[i] != 0; i++) {
    dest[i] = src[i];
  }
  dest[i] = 0;
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L4
  xor    %r8d,%r8d
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %cl,(%rax,%rdx,1)
  lea    0x1(%r8),%edx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %rdx,%r8
  test   %cl,%cl
  jne    L3
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax)
L4:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcpy(char *dest, char *src) {
  unsigned int i;
  for (i = 0; src[i] != 0; i++) {
    dest[i] = src[i];
  }
  dest[i] = 0;
  return dest;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D18
type_infered: string

tool: D15: hello, 

tool: D26: world

tool: D18: 


assistant: ```c
int main() {
  printf("hello, ");
  printf("world");
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D28
datatype: string

tool: D19: hello, 

tool: D24: world

tool: D28: 


assistant: ```c
int main() {
  printf("hello, ");
  printf("world");
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string
name: unpack_data
arguments: tag: D23
data_type: string

tool: D0: hello, 

tool: D20: world

tool: D23: 


assistant: ```c
int main() {
  printf("hello, ");
  printf("world");
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string
name: extract_symbolic_data
arguments: tag: D19
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string

tool: D8: hello, 

tool: D19: world

tool: D22: 


assistant: ```c
int main() {
  printf("hello, ");
  printf("world");
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <atv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float *tv(float x, float y, float z) {
  float *v = atv();
  ((v)[0] = (x), (v)[1] = (y), (v)[2] = (z));
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movd   %xmm0,%r12d
  movd   %xmm1,%ebp
  movd   %xmm2,%ebx
  mov    $0x0,%eax
  call   <atv@plt>
  mov    %r12d,(%rax)
  mov    %ebp,0x4(%rax)
  mov    %ebx,0x8(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
float *tv(float x, float y, float z) {
  float *v = atv();
  ((v)[0] = (x), (v)[1] = (y), (v)[2] = (z));
  return v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tv>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  movss  %xmm2,0x4(%rsp)
  call   <atv@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  movss  0x4(%rsp),%xmm2
  movss  %xmm0,(%rax)
  movss  %xmm1,0x4(%rax)
  movss  %xmm2,0x8(%rax)
  add    $0x18,%rsp
  ret
```

assistant: ```c
float *tv(float x, float y, float z) {
  float *v = atv();
  ((v)[0] = (x), (v)[1] = (y), (v)[2] = (z));
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tv>:
  endbr64
  sub    $0x18,%rsp
  unpcklps %xmm1,%xmm0
  xor    %eax,%eax
  movss  %xmm2,0xc(%rsp)
  movlps %xmm0,(%rsp)
  call   <atv@plt>
  movq   (%rsp),%xmm0
  movss  0xc(%rsp),%xmm2
  movlps %xmm0,(%rax)
  movss  %xmm2,0x8(%rax)
  add    $0x18,%rsp
  ret
```

assistant: ```c
float *tv(float x, float y, float z) {
  float *v = atv();
  ((v)[0] = (x), (v)[1] = (y), (v)[2] = (z));
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x585858,-0x14(%rbp)
  movl   $0x584f58,-0x10(%rbp)
  movl   $0x585858,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <solve@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L13
L16:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L13:
  cmpl   $0x2,-0x34(%rbp)
  jle    L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string

tool: D2: %s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  char r1[] = "XXX";
  char r2[] = "XOX";
  char r3[] = "XXX";
  char *b[] = {r1, r2, r3};
  solve(b, 3, 3);
  for (i = 0; i < 3; i++)
    printf("%s\n", b[i]);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x585858,0x1c(%rsp)
  movl   $0x584f58,0x20(%rsp)
  movl   $0x585858,0x24(%rsp)
  lea    0x1c(%rsp),%rax
  mov    %rax,(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x24(%rsp),%rax
  mov    %rax,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x3,%edx
  mov    $0x3,%esi
  call   <solve@plt>
  mov    (%rsp),%rsi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: %s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  char r1[] = "XXX";
  char r2[] = "XOX";
  char r3[] = "XXX";
  char *b[] = {r1, r2, r3};
  solve(b, 3, 3);
  for (i = 0; i < 3; i++)
    printf("%s\n", b[i]);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D5(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rax
  mov    %rsp,%rdi
  movl   $0x585858,0x1c(%rsp)
  mov    %rax,(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x24(%rsp),%rax
  movl   $0x584f58,0x20(%rsp)
  movl   $0x585858,0x24(%rsp)
  mov    %rax,0x10(%rsp)
  call   <solve@plt>
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: %s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  char r1[] = "XXX";
  char r2[] = "XOX";
  char r3[] = "XXX";
  char *b[] = {r1, r2, r3};
  solve(b, 3, 3);
  for (i = 0; i < 3; i++)
    printf("%s\n", b[i]);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D0(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rax
  mov    %rsp,%rdi
  movl   $0x585858,0x1c(%rsp)
  movq   %rax,%xmm0
  lea    0x20(%rsp),%rax
  movl   $0x584f58,0x20(%rsp)
  movq   %rax,%xmm1
  lea    0x24(%rsp),%rax
  movl   $0x585858,0x24(%rsp)
  punpcklqdq %xmm1,%xmm0
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <solve@plt>
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: %s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  char r1[] = "XXX";
  char r2[] = "XOX";
  char r3[] = "XXX";
  char *b[] = {r1, r2, r3};
  solve(b, 3, 3);
  for (i = 0; i < 3; i++)
    printf("%s\n", b[i]);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_ucRcAT1604_ChkSC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x24bb,%edx
  lea    D27(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x2,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  addl   $0x2,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  add    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L15
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <vWriteLogTxt@plt>
  mov    $0x1,%eax
  jmp    L1
L15:
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D27
type_guessed: string
name: disassemble_data
arguments: data_label: D10
type_guessed: string
name: disassemble_data
arguments: data_label: D16
type_guessed: string

tool: D27: %u(b002

tool: D10: )

tool: D16: _AT1604_ChkSC iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1604_ChkSC(unsigned char *SC) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(50);
  uiDataLen = sprintf(psFunCall, "%u(b002", 9403);
  memcpy(psFunCall + uiDataLen, SC, 2);
  uiDataLen += 2;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1604_ChkSC iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_ucRcAT1604_ChkSC>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x24bb,%edx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0x9(%rbx),%rdi
  mov    $0x2,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movw   $0x29,0xb(%rbx)
  mov    $0x1,%edx
  mov    $0xc,%esi
  mov    %rbx,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  test   %ebp,%ebp
  jne    L7
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  call   <vWriteLogTxt@plt>
  mov    $0x1,%eax
  jmp    L11
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D8: %u(b002

tool: D12: _AT1604_ChkSC iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1604_ChkSC(unsigned char *SC) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(50);
  uiDataLen = sprintf(psFunCall, "%u(b002", 9403);
  memcpy(psFunCall + uiDataLen, SC, 2);
  uiDataLen += 2;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1604_ChkSC iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<_ucRcAT1604_ChkSC>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x32,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x24bb,%edx
  lea    D19(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rsi
  lea    0x9(%rbp),%rdi
  mov    $0x2,%edx
  call   <memcpy@plt>
  mov    $0x29,%eax
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    %ax,0xb(%rbp)
  mov    $0xc,%esi
  call   <iDoRemoteFunc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  test   %r12d,%r12d
  jne    L1
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <iGetParaInt@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12d,%esi
  lea    D13(%rip),%rdi
  call   <vWriteLogTxt@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D13
type_infered: string

tool: D19: %u(b002

tool: D13: _AT1604_ChkSC iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1604_ChkSC(unsigned char *SC) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(50);
  uiDataLen = sprintf(psFunCall, "%u(b002", 9403);
  memcpy(psFunCall + uiDataLen, SC, 2);
  uiDataLen += 2;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1604_ChkSC iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ucRcAT1604_ChkSC>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x32,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x24bb,%edx
  lea    D19(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rsi
  lea    0x9(%rbp),%rdi
  mov    $0x2,%edx
  call   <memcpy@plt>
  mov    $0x29,%eax
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    %ax,0xb(%rbp)
  mov    $0xc,%esi
  call   <iDoRemoteFunc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  test   %r12d,%r12d
  jne    L4
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <iGetParaInt@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r12d,%esi
  lea    D12(%rip),%rdi
  call   <vWriteLogTxt@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D12
data_type: string

tool: D19: %u(b002

tool: D12: _AT1604_ChkSC iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1604_ChkSC(unsigned char *SC) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(50);
  uiDataLen = sprintf(psFunCall, "%u(b002", 9403);
  memcpy(psFunCall + uiDataLen, SC, 2);
  uiDataLen += 2;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1604_ChkSC iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L18:
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x20(%rbp)
L6:
  cmpq   $0x0,-0x20(%rbp)
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
L16:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strnlen(const char *str, size_t maxlen) {
  const char *cp;
  for (cp = str; maxlen != 0 && *cp != '\0'; cp++, maxlen--)
    ;
  return (size_t)(cp - str);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strnlen>:
  endbr64
  test   %rsi,%rsi
  je     L28
  add    %rdi,%rsi
  mov    %rdi,%rax
L2:
  cmpb   $0x0,(%rax)
  je     L27
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L2
  mov    %rsi,%rax
L27:
  sub    %rdi,%rax
  ret
L28:
  mov    %rdi,%rax
  jmp    L27
```

assistant: ```c
size_t strnlen(const char *str, size_t maxlen) {
  const char *cp;
  for (cp = str; maxlen != 0 && *cp != '\0'; cp++, maxlen--)
    ;
  return (size_t)(cp - str);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strnlen>:
  endbr64
  lea    (%rdi,%rsi,1),%rdx
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L32
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L28
L32:
  cmpb   $0x0,(%rax)
  jne    L8
  sub    %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rdx,%rax
  sub    %rdi,%rax
  ret
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strnlen(const char *str, size_t maxlen) {
  const char *cp;
  for (cp = str; maxlen != 0 && *cp != '\0'; cp++, maxlen--)
    ;
  return (size_t)(cp - str);
}
```