ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<accept_connection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <accept@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int accept_connection(int s) {
  int client_fd;
  struct sockaddr_in client_sock;
  socklen_t sz = sizeof(struct sockaddr_in);
  client_fd = accept(s, (struct sockaddr *)&client_sock, &sz);
  return client_fd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<accept_connection>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <accept@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int accept_connection(int s) {
  int client_fd;
  struct sockaddr_in client_sock;
  socklen_t sz = sizeof(struct sockaddr_in);
  client_fd = accept(s, (struct sockaddr *)&client_sock, &sz);
  return client_fd;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<accept_connection>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  movl   $0x4,0x4(%rsp)
  call   <accept@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int accept_connection(int s) {
  int client_fd;
  struct sockaddr_in client_sock;
  socklen_t sz = sizeof(struct sockaddr_in);
  client_fd = accept(s, (struct sockaddr *)&client_sock, &sz);
  return client_fd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<accept_connection>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  movl   $0x4,0x4(%rsp)
  call   <accept@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int accept_connection(int s) {
  int client_fd;
  struct sockaddr_in client_sock;
  socklen_t sz = sizeof(struct sockaddr_in);
  client_fd = accept(s, (struct sockaddr *)&client_sock, &sz);
  return client_fd;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <ft_putnbr@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_add(int a, int b) {
  ft_putnbr(a + b);
  ft_putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_add>:
  endbr64
  sub    $0x8,%rsp
  add    %esi,%edi
  call   <ft_putnbr@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ft_add(int a, int b) {
  ft_putnbr(a + b);
  ft_putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_add>:
  endbr64
  sub    $0x8,%rsp
  add    %esi,%edi
  call   <ft_putnbr@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1060 <ft_putchar@plt>
```

assistant: ```c
void ft_add(int a, int b) {
  ft_putnbr(a + b);
  ft_putchar('\n');
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_add>:
  endbr64
  sub    $0x8,%rsp
  add    %esi,%edi
  call   <ft_putnbr@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1060 <ft_putchar@plt>
```

assistant: ```c
void ft_add(int a, int b) {
  ft_putnbr(a + b);
  ft_putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_quotes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r14d
  movzbl (%rdi),%eax
  cmp    $0x22,%al
  je     L55
  cmp    $0x27,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
L23:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L54
  mov    $0x0,%r12d
  jmp    L140
L55:
  add    $0x1,%rbx
  jmp    L23
L6:
  movb   $0x0,(%rbx)
  mov    %r12d,%eax
L68:
  add    $0x1,%rbx
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
L8:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L54
L140:
  cmp    $0x22,%al
  je     L6
  cmp    $0x27,%al
  je     L6
  movzbl (%rbx),%eax
  cmp    $0x24,%al
  jne    L68
  lea    0x1(%rbx),%r13
  movzbl 0x1(%rbx),%edi
  mov    %r13,%rbx
  test   %dil,%dil
  jne    L30
  jmp    L74
L113:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L74
L30:
  movsbl %dil,%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L113
  movsbl (%rbx),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L113
L74:
  movzbl (%rbx),%r15d
  movb   $0x0,(%rbx)
  mov    %r13,%rdi
  call   <getenv@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L143
  movb   $0x0,0x0(%rbp)
  mov    %r14d,%edx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strlcat@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  mov    %r15b,(%rbx)
  jmp    L8
L143:
  mov    %r15b,(%rbx)
  jmp    L8
L54:
  movb   $0x0,0x0(%rbp)
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int parse_quotes(char *input, char *buffer, int buf_len) {
  char *in = input;
  char *out = buffer;
  int mode = 0;
  if (*in == '"') {
    in++;
    mode = 1;
  } else if (*in == '\'') {
    in++;
    mode = 2;
  }
  while (*in) {
    if (*in == '"' || *in == '\'')
      *in = '\0';
    if (*in == '$') {
      int bak_char;
      char *envval, *val_start = ++in;
      while (*in && (isupper(*in) || islower(*in))) {
        in++;
      }
      bak_char = *in;
      *in = '\0';
      envval = getenv(val_start);
      if (envval == NULL) {
        *in = bak_char;
        continue;
      }
      *out = '\0';
      strlcat(out, envval, buf_len);
      out += strlen(envval);
      *in = bak_char;
    } else {
      *out++ = *in++;
    }
  }
  *out = '\0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_quotes>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%ebx
  cmp    $0x22,%bl
  je     L5
  cmp    $0x27,%bl
  je     L5
  nopw   0x0(%rax,%rax,1)
L73:
  test   %bl,%bl
  je     L57
L106:
  lea    0x1(%rbp),%r13
  cmp    $0x22,%bl
  je     L146
  cmp    $0x27,%bl
  je     L146
  movzbl 0x0(%rbp),%eax
  cmp    $0x24,%al
  je     L49
L34:
  mov    %al,(%r12)
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%r12
  mov    %r13,%rbp
  test   %bl,%bl
  jne    L106
L57:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  movb   $0x0,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L5:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  jmp    L73
  nopw   0x0(%rax,%rax,1)
L146:
  movb   $0x0,0x0(%rbp)
  xor    %eax,%eax
  jmp    L34
L49:
  movzbl 0x1(%rbp),%ebx
  mov    %r13,%rbp
  test   %bl,%bl
  jne    L83
  jmp    L132
  nopl   (%rax)
L41:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  test   %bl,%bl
  je     L132
L83:
  movsbl %bl,%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L41
  movsbl 0x0(%rbp),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L41
  movzbl 0x0(%rbp),%ebx
L132:
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rdi
  call   <getenv@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L143
  movb   $0x0,(%r12)
  mov    %r12,%rdi
  mov    %r14d,%edx
  mov    %rax,%rsi
  call   <strlcat@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%r12
L143:
  mov    %bl,0x0(%rbp)
  jmp    L73
```

assistant: ```c
int parse_quotes(char *input, char *buffer, int buf_len) {
  char *in = input;
  char *out = buffer;
  int mode = 0;
  if (*in == '"') {
    in++;
    mode = 1;
  } else if (*in == '\'') {
    in++;
    mode = 2;
  }
  while (*in) {
    if (*in == '"' || *in == '\'')
      *in = '\0';
    if (*in == '$') {
      int bak_char;
      char *envval, *val_start = ++in;
      while (*in && (isupper(*in) || islower(*in))) {
        in++;
      }
      bak_char = *in;
      *in = '\0';
      envval = getenv(val_start);
      if (envval == NULL) {
        *in = bak_char;
        continue;
      }
      *out = '\0';
      strlcat(out, envval, buf_len);
      out += strlen(envval);
      *in = bak_char;
    } else {
      *out++ = *in++;
    }
  }
  *out = '\0';
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_quotes>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%ebx
  cmp    $0x22,%bl
  je     L127
  cmp    $0x27,%bl
  je     L127
  nopw   0x0(%rax,%rax,1)
L28:
  test   %bl,%bl
  je     L1
L5:
  lea    0x1(%rbp),%r13
  cmp    $0x22,%bl
  je     L54
  cmp    $0x27,%bl
  je     L54
  cmp    $0x24,%bl
  je     L14
L6:
  mov    %bl,(%r12)
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%r12
  mov    %r13,%rbp
  test   %bl,%bl
  jne    L5
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  movb   $0x0,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L127:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L54:
  movb   $0x0,0x0(%rbp)
  xor    %ebx,%ebx
  jmp    L6
L14:
  movzbl 0x1(%rbp),%ebx
  mov    %r13,%rbp
  test   %bl,%bl
  jne    L113
  jmp    L111
  nopl   (%rax)
L57:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  test   %bl,%bl
  je     L111
L113:
  movsbl %bl,%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L57
  movsbl 0x0(%rbp),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L57
  movzbl 0x0(%rbp),%ebx
L111:
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rdi
  call   <getenv@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L141
  movb   $0x0,(%r12)
  mov    %r12,%rdi
  mov    %r14d,%edx
  mov    %rax,%rsi
  call   <strlcat@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%r12
L141:
  mov    %bl,0x0(%rbp)
  jmp    L28
```

assistant: ```c
int parse_quotes(char *input, char *buffer, int buf_len) {
  char *in = input;
  char *out = buffer;
  int mode = 0;
  if (*in == '"') {
    in++;
    mode = 1;
  } else if (*in == '\'') {
    in++;
    mode = 2;
  }
  while (*in) {
    if (*in == '"' || *in == '\'')
      *in = '\0';
    if (*in == '$') {
      int bak_char;
      char *envval, *val_start = ++in;
      while (*in && (isupper(*in) || islower(*in))) {
        in++;
      }
      bak_char = *in;
      *in = '\0';
      envval = getenv(val_start);
      if (envval == NULL) {
        *in = bak_char;
        continue;
      }
      *out = '\0';
      strlcat(out, envval, buf_len);
      out += strlen(envval);
      *in = bak_char;
    } else {
      *out++ = *in++;
    }
  }
  *out = '\0';
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: D4: %d


assistant: ```c
int main(void) {
  printf("%d\n", (long long int)(7));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main(void) {
  printf("%d\n", (long long int)(7));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(void) {
  printf("%d\n", (long long int)(7));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: %d


assistant: ```c
int main(void) {
  printf("%d\n", (long long int)(7));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x4e71,-0x84(%rbp)
  jne    L24
  mov    -0x84(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <begin_function@plt>
  mov    %eax,-0x74(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x84(%rbp),%edx
  mov    -0x74(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <add_opcode@plt>
  jmp    L10
L24:
  nop
L10:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D16
type: string

tool: D9: nop_%04X

tool: D16: 	FETCH_OPCODE;
}



assistant: ```c
void nop(int opcode) {
  char func_name[(100)];
  int func_id;
  if (opcode != 0x4E71)
    return;
  sprintf(func_name, "nop_%04X", opcode);
  func_id = begin_function(func_name);
  printf("\tFETCH_OPCODE;\n}\n\n");
  add_opcode(func_id, opcode);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nop>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x4e71,%edi
  je     L4
L22:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x70,%rsp
  pop    %rbx
  ret
L4:
  mov    %rsp,%rbx
  mov    $0x4e71,%edx
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <begin_function@plt>
  mov    %eax,%ebx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x4e71,%esi
  mov    %ebx,%edi
  call   <add_opcode@plt>
  jmp    L22
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D14: nop_%04X

tool: D8: 	FETCH_OPCODE;
}



assistant: ```c
void nop(int opcode) {
  char func_name[(100)];
  int func_id;
  if (opcode != 0x4E71)
    return;
  sprintf(func_name, "nop_%04X", opcode);
  func_id = begin_function(func_name);
  printf("\tFETCH_OPCODE;\n}\n\n");
  add_opcode(func_id, opcode);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nop>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x4e71,%edi
  je     L14
L1:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x70,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rsp,%rbp
  mov    $0x4e71,%edx
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <begin_function@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%ebp
  call   <printf@plt>
  mov    $0x4e71,%esi
  mov    %ebp,%edi
  call   <add_opcode@plt>
  jmp    L1
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string

tool: D19: nop_%04X

tool: D13: 	FETCH_OPCODE;
}



assistant: ```c
void nop(int opcode) {
  char func_name[(100)];
  int func_id;
  if (opcode != 0x4E71)
    return;
  sprintf(func_name, "nop_%04X", opcode);
  func_id = begin_function(func_name);
  printf("\tFETCH_OPCODE;\n}\n\n");
  add_opcode(func_id, opcode);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nop>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x4e71,%edi
  je     L9
L3:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x70,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rsp,%rbp
  mov    $0x4e71,%edx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <begin_function@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%ebp
  call   <printf@plt>
  mov    $0x4e71,%esi
  mov    %ebp,%edi
  call   <add_opcode@plt>
  jmp    L3
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
data_type: string
name: unpack_data
arguments: data_label: D13
data_type: string

tool: D15: nop_%04X

tool: D13: 	FETCH_OPCODE;
}



assistant: ```c
void nop(int opcode) {
  char func_name[(100)];
  int func_id;
  if (opcode != 0x4E71)
    return;
  sprintf(func_name, "nop_%04X", opcode);
  func_id = begin_function(func_name);
  printf("\tFETCH_OPCODE;\n}\n\n");
  add_opcode(func_id, opcode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<append_signed_long_katcl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <before_append_katcl@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L18
L7:
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <add_signed_long_parse_katcl@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <after_append_katcl@plt>
L18:
  leave
  ret
```

assistant: ```c
int append_signed_long_katcl(struct katcl_line *l, int flags, unsigned long v) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_signed_long_parse_katcl(p, flags, v);
  return after_append_katcl(l, flags, result);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<append_signed_long_katcl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <add_signed_long_parse_katcl@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <after_append_katcl@plt>
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int append_signed_long_katcl(struct katcl_line *l, int flags, unsigned long v) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_signed_long_parse_katcl(p, flags, v);
  return after_append_katcl(l, flags, result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<append_signed_long_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L2
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <add_signed_long_parse_katcl@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <after_append_katcl@plt>
L2:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int append_signed_long_katcl(struct katcl_line *l, int flags, unsigned long v) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_signed_long_parse_katcl(p, flags, v);
  return after_append_katcl(l, flags, result);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<append_signed_long_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L7
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <add_signed_long_parse_katcl@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <after_append_katcl@plt>
L7:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int append_signed_long_katcl(struct katcl_line *l, int flags, unsigned long v) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_signed_long_parse_katcl(p, flags, v);
  return after_append_katcl(l, flags, result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L6:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%eax
  imul   $0x2f684bdb,%rax,%rax
  shr    $0x20,%rax
  mov    %rax,%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    0x0(,%rax,8),%edx
  add    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int hash(char *symbol) {
  unsigned int sum;
  sum = 0;
  while (*symbol) {
    sum = sum * 31 + *symbol;
    symbol++;
  }
  return sum % 27;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  mov    $0x0,%ecx
L15:
  mov    %ecx,%edx
  shl    $0x5,%edx
  sub    %ecx,%edx
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%ecx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L15
L8:
  mov    %ecx,%edx
  imul   $0x2f684bdb,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x4,%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rax,8),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
L7:
  mov    $0x0,%ecx
  jmp    L8
```

assistant: ```c
int hash(char *symbol) {
  unsigned int sum;
  sum = 0;
  while (*symbol) {
    sum = sum * 31 + *symbol;
    symbol++;
  }
  return sum % 27;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L14
  xor    %ecx,%ecx
  nopl   (%rax)
L8:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L8
  mov    %ecx,%edx
  mov    %ecx,%eax
  imul   $0x2f684bdb,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x4,%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rax,8),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash(char *symbol) {
  unsigned int sum;
  sum = 0;
  while (*symbol) {
    sum = sum * 31 + *symbol;
    symbol++;
  }
  return sum % 27;
}
```