ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<udp_checksum>:
  endbr64
  mov    %rdx,%rcx
  mov    D6(%rip),%rdx
  movslq %edi,%rax
  movzwl 0x2(%rcx),%r9d
  lea    0x1(%rax),%edi
  mov    (%rdx),%r8d
  movzwl (%rcx),%edx
  sar    %edi
  add    %r9d,%edx
  movzwl 0x4(%rcx),%r9d
  movzwl 0x6(%rcx),%ecx
  add    %eax,%r8d
  movslq %r8d,%r8
  add    %r9d,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  add    %r8,%rdx
  test   $0x1,%al
  je     L48
  movb   $0x0,(%rsi,%rax,1)
L48:
  xor    %eax,%eax
  mov    %ax,0x6(%rsi)
  test   %di,%di
  je     L49
  movzwl %di,%edi
  mov    %rsi,%rax
  lea    (%rsi,%rdi,2),%rdi
  nopl   0x0(%rax,%rax,1)
L38:
  movzwl (%rax),%ecx
  add    $0x2,%rax
  add    %rcx,%rdx
  cmp    %rax,%rdi
  jne    L38
  movzwl %dx,%eax
  shr    $0x10,%rdx
  je     L45
  nopl   0x0(%rax,%rax,1)
L3:
  add    %rax,%rdx
L49:
  movzwl %dx,%eax
  shr    $0x10,%rdx
  jne    L3
L45:
  not    %eax
  mov    %ax,0x6(%rsi)
  ret
```

assistant: ```c
unsigned short udp_checksum(int bytes, char *user_datagram, char *net_addresses) {
  unsigned short *p = (unsigned short *)net_addresses;
  unsigned short x = (bytes + 1) >> 1;
  unsigned long sum = bytes + IPPROTO_UDP;
  unsigned short carry;
  sum += *p + p[1] + p[2] + p[3];
  p = (unsigned short *)user_datagram;
  if (bytes & 1)
    user_datagram[bytes] = 0;
  p[3] = 0;
  while (x--)
    sum += *p++;
  carry = sum;
  while (sum >>= 16) {
    sum += carry;
    carry = sum;
  }
  p = (unsigned short *)user_datagram;
  carry ^= 65535;
  p[3] = carry;
  return carry;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<udp_checksum>:
  endbr64
  mov    %rdx,%rcx
  mov    D0(%rip),%rdx
  movslq %edi,%rax
  movzwl 0x2(%rcx),%r9d
  lea    0x1(%rax),%r8d
  mov    (%rdx),%edi
  movzwl (%rcx),%edx
  sar    %r8d
  add    %r9d,%edx
  movzwl 0x4(%rcx),%r9d
  movzwl 0x6(%rcx),%ecx
  add    %eax,%edi
  movslq %edi,%rdi
  add    %r9d,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  add    %rdi,%rdx
  test   $0x1,%al
  je     L35
  movb   $0x0,(%rsi,%rax,1)
L35:
  xor    %eax,%eax
  lea    -0x1(%r8),%r9d
  mov    %ax,0x6(%rsi)
  test   %r8w,%r8w
  je     L30
  cmp    $0x6,%r9w
  jbe    L8
  lea    -0x8(%r8),%ecx
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  xor    %eax,%eax
  shr    $0x3,%cx
  pxor   %xmm2,%xmm2
  add    $0x1,%ecx
  xchg   %ax,%ax
L124:
  mov    %rax,%rdi
  add    $0x1,%rax
  shl    $0x4,%rdi
  movdqu (%rsi,%rdi,1),%xmm0
  movdqa %xmm0,%xmm1
  punpckhwd %xmm4,%xmm0
  movdqa %xmm0,%xmm5
  punpcklwd %xmm4,%xmm1
  punpckhdq %xmm2,%xmm0
  punpckldq %xmm2,%xmm5
  paddq  %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  punpckhdq %xmm2,%xmm1
  punpckldq %xmm2,%xmm5
  paddq  %xmm5,%xmm1
  paddq  %xmm1,%xmm0
  paddq  %xmm0,%xmm3
  cmp    %ax,%cx
  ja     L124
  movdqa %xmm3,%xmm0
  shl    $0x3,%ecx
  psrldq $0x8,%xmm0
  sub    %ecx,%r9d
  paddq  %xmm0,%xmm3
  movq   %xmm3,%rax
  add    %rax,%rdx
  movzwl %cx,%eax
  lea    (%rsi,%rax,2),%rax
  cmp    %r8w,%cx
  je     L30
L122:
  movzwl (%rax),%ecx
  add    %rcx,%rdx
  test   %r9w,%r9w
  je     L30
  movzwl 0x2(%rax),%ecx
  add    %rcx,%rdx
  cmp    $0x1,%r9w
  je     L30
  movzwl 0x4(%rax),%ecx
  add    %rcx,%rdx
  cmp    $0x2,%r9w
  je     L30
  movzwl 0x6(%rax),%ecx
  add    %rcx,%rdx
  cmp    $0x3,%r9w
  je     L30
  movzwl 0x8(%rax),%ecx
  add    %rcx,%rdx
  cmp    $0x4,%r9w
  je     L30
  movzwl 0xa(%rax),%ecx
  add    %rcx,%rdx
  cmp    $0x5,%r9w
  je     L30
  movzwl 0xc(%rax),%eax
  nopw   0x0(%rax,%rax,1)
L18:
  add    %rax,%rdx
L30:
  movzwl %dx,%eax
  shr    $0x10,%rdx
  jne    L18
  not    %eax
  mov    %ax,0x6(%rsi)
  ret
L8:
  mov    %rsi,%rax
  jmp    L122
```

assistant: ```c
unsigned short udp_checksum(int bytes, char *user_datagram, char *net_addresses) {
  unsigned short *p = (unsigned short *)net_addresses;
  unsigned short x = (bytes + 1) >> 1;
  unsigned long sum = bytes + IPPROTO_UDP;
  unsigned short carry;
  sum += *p + p[1] + p[2] + p[3];
  p = (unsigned short *)user_datagram;
  if (bytes & 1)
    user_datagram[bytes] = 0;
  p[3] = 0;
  while (x--)
    sum += *p++;
  carry = sum;
  while (sum >>= 16) {
    sum += carry;
    carry = sum;
  }
  p = (unsigned short *)user_datagram;
  carry ^= 65535;
  p[3] = carry;
  return carry;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *pointer = 0;
  pointer = malloc(64);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *pointer = 0;
  pointer = malloc(64);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *pointer = 0;
  pointer = malloc(64);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *pointer = 0;
  pointer = malloc(64);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    D0(%rip),%rax
  movq   $0x0,(%rax)
  jmp    L40
L42:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L33
L50:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L69
  cmpl   $0x0,-0x14(%rbp)
  jne    L69
  mov    $0xffffffff,%eax
  jmp    L45
L69:
  cmpl   $0x0,-0xc(%rbp)
  jg     L59
  mov    -0x14(%rbp),%eax
  jmp    L45
L59:
  mov    D0(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L33:
  cmpl   $0x0,-0x10(%rbp)
  jg     L50
  addq   $0x10,-0x30(%rbp)
  addl   $0x1,-0x18(%rbp)
L40:
  mov    -0x18(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L42
  mov    -0x14(%rbp),%eax
L45:
  leave
  ret
```

assistant: ```c
ssize_t readv(int fd, const struct iovec *iov, int iovcnt) {
  int i = 0, ret = 0, n = 0, len = 0;
  char *base;
  errno = 0;
  while (i < iovcnt) {
    len = iov->iov_len;
    base = iov->iov_base;
    while (len > 0) {
      ret = read(fd, base, len);
      if (ret < 0 && n == 0)
        return -1;
      if (ret <= 0)
        return n;
      errno = 0;
      n += ret;
      len -= ret;
      base += ret;
    }
    iov++;
    i++;
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D18(%rip),%rax
  movq   $0x0,(%rax)
  test   %edx,%edx
  jle    L4
  mov    %edi,%r13d
  mov    %rsi,%r15
  mov    %edx,%edx
  shl    $0x4,%rdx
  lea    (%rsi,%rdx,1),%r14
  mov    $0x0,%r12d
L12:
  mov    (%r15),%ebx
  mov    0x8(%r15),%rbp
  test   %ebx,%ebx
  jg     L74
L14:
  add    $0x10,%r15
  cmp    %r14,%r15
  jne    L12
  jmp    L13
L72:
  test   %eax,%eax
  jle    L13
  mov    D18(%rip),%rdx
  movq   $0x0,(%rdx)
  add    %eax,%r12d
  sub    %eax,%ebx
  cltq
  add    %rax,%rbp
  test   %ebx,%ebx
  jle    L14
L74:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L72
  test   %r12d,%r12d
  jne    L72
  mov    $0xffffffff,%r12d
L13:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    $0x0,%r12d
  jmp    L13
```

assistant: ```c
ssize_t readv(int fd, const struct iovec *iov, int iovcnt) {
  int i = 0, ret = 0, n = 0, len = 0;
  char *base;
  errno = 0;
  while (i < iovcnt) {
    len = iov->iov_len;
    base = iov->iov_base;
    while (len > 0) {
      ret = read(fd, base, len);
      if (ret < 0 && n == 0)
        return -1;
      if (ret <= 0)
        return n;
      errno = 0;
      n += ret;
      len -= ret;
      base += ret;
    }
    iov++;
    i++;
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D4(%rip),%rbp
  movq   $0x0,0x0(%rbp)
  test   %edx,%edx
  jle    L85
  movslq %edx,%rdx
  mov    %edi,%ebx
  mov    %rsi,%r13
  xor    %r12d,%r12d
  shl    $0x4,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    %rax,0x8(%rsp)
L34:
  mov    0x0(%r13),%r14d
  mov    0x8(%r13),%r15
  test   %r14d,%r14d
  jg     L13
  jmp    L41
L54:
  test   %eax,%eax
  jle    L39
  add    %eax,%r12d
  sub    %eax,%r14d
  cltq
  movq   $0x0,0x0(%rbp)
  add    %rax,%r15
  test   %r14d,%r14d
  jle    L41
L13:
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L54
  test   %r12d,%r12d
  jne    L54
  mov    $0xffffffff,%r12d
L39:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  add    $0x10,%r13
  cmp    0x8(%rsp),%r13
  jne    L34
  jmp    L39
L85:
  xor    %r12d,%r12d
  jmp    L39
```

assistant: ```c
ssize_t readv(int fd, const struct iovec *iov, int iovcnt) {
  int i = 0, ret = 0, n = 0, len = 0;
  char *base;
  errno = 0;
  while (i < iovcnt) {
    len = iov->iov_len;
    base = iov->iov_base;
    while (len > 0) {
      ret = read(fd, base, len);
      if (ret < 0 && n == 0)
        return -1;
      if (ret <= 0)
        return n;
      errno = 0;
      n += ret;
      len -= ret;
      base += ret;
    }
    iov++;
    i++;
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D1(%rip),%rbp
  movq   $0x0,0x0(%rbp)
  test   %edx,%edx
  jle    L8
  movslq %edx,%rdx
  mov    %edi,%ebx
  mov    %rsi,%r13
  xor    %r12d,%r12d
  shl    $0x4,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    %rax,0x8(%rsp)
L92:
  mov    0x0(%r13),%r14d
  mov    0x8(%r13),%r15
  test   %r14d,%r14d
  jg     L14
  jmp    L6
L85:
  test   %eax,%eax
  jle    L98
  add    %eax,%r12d
  sub    %eax,%r14d
  cltq
  movq   $0x0,0x0(%rbp)
  add    %rax,%r15
  test   %r14d,%r14d
  jle    L6
L14:
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L85
  test   %r12d,%r12d
  jne    L85
  mov    $0xffffffff,%r12d
L98:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x10,%r13
  cmp    0x8(%rsp),%r13
  jne    L92
  jmp    L98
L8:
  xor    %r12d,%r12d
  jmp    L98
```

assistant: ```c
ssize_t readv(int fd, const struct iovec *iov, int iovcnt) {
  int i = 0, ret = 0, n = 0, len = 0;
  char *base;
  errno = 0;
  while (i < iovcnt) {
    len = iov->iov_len;
    base = iov->iov_base;
    while (len > 0) {
      ret = read(fd, base, len);
      if (ret < 0 && n == 0)
        return -1;
      if (ret <= 0)
        return n;
      errno = 0;
      n += ret;
      len -= ret;
      base += ret;
    }
    iov++;
    i++;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<delgshadow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rcx
  lea    D1(%rip),%rdx
  lea    D12(%rip),%rsi
  mov    %rax,%rdi
  call   <cm_delete_entry@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    -0x4(%rbp),%eax
  jmp    L2
L6:
  mov    $0x0,%eax
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string

tool: D16: /etc/.gshadow.cm

tool: D1: /etc/gshadow

tool: D12: %[^:]:%*[^:]:%*d:%*[^:]

assistant: ```c
int delgshadow(char *group) {
  int i;
  if ((i = cm_delete_entry(group, "%[^:]:%*[^:]:%*d:%*[^:]", "/etc/gshadow", "/etc/.gshadow.cm")) != 0) {
    return i;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<delgshadow>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rcx
  lea    D2(%rip),%rdx
  lea    D27(%rip),%rsi
  call   <cm_delete_entry@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D23
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string

tool: D23: /etc/.gshadow.cm

tool: D2: /etc/gshadow

tool: D27: %[^:]:%*[^:]:%*d:%*[^:]

assistant: ```c
int delgshadow(char *group) {
  int i;
  if ((i = cm_delete_entry(group, "%[^:]:%*[^:]:%*d:%*[^:]", "/etc/gshadow", "/etc/.gshadow.cm")) != 0) {
    return i;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delgshadow>:
  endbr64
  lea    D19(%rip),%rcx
  lea    D21(%rip),%rdx
  lea    D16(%rip),%rsi
  jmp    1050 <cm_delete_entry@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D16
type: string

tool: D19: /etc/.gshadow.cm

tool: D21: /etc/gshadow

tool: D16: %[^:]:%*[^:]:%*d:%*[^:]

assistant: ```c
int delgshadow(char *group) {
  int i;
  if ((i = cm_delete_entry(group, "%[^:]:%*[^:]:%*d:%*[^:]", "/etc/gshadow", "/etc/.gshadow.cm")) != 0) {
    return i;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<delgshadow>:
  endbr64
  lea    D20(%rip),%rcx
  lea    D28(%rip),%rdx
  lea    D16(%rip),%rsi
  jmp    1050 <cm_delete_entry@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D16
datatype: string

tool: D20: /etc/.gshadow.cm

tool: D28: /etc/gshadow

tool: D16: %[^:]:%*[^:]:%*d:%*[^:]

assistant: ```c
int delgshadow(char *group) {
  int i;
  if ((i = cm_delete_entry(group, "%[^:]:%*[^:]:%*d:%*[^:]", "/etc/gshadow", "/etc/.gshadow.cm")) != 0) {
    return i;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<emsMark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ems1Emark@plt>
  mov    $0x0,%eax
  call   <ems1Mpush@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void emsMark(void) {
  ;
  ems1Emark();
  ems1Mpush();
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emsMark>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ems1Emark@plt>
  mov    $0x0,%eax
  call   <ems1Mpush@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void emsMark(void) {
  ;
  ems1Emark();
  ems1Mpush();
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<emsMark>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ems1Emark@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ems1Mpush@plt>
```

assistant: ```c
void emsMark(void) {
  ;
  ems1Emark();
  ems1Mpush();
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emsMark>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ems1Emark@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ems1Mpush@plt>
```

assistant: ```c
void emsMark(void) {
  ;
  ems1Emark();
  ems1Mpush();
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  leave
  ret
```

assistant: ```c
size_t strLength(char *string) {
  assert(string != NULL);
  return strlen(string);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strLength>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  pop    %rbx
  ret
```

assistant: ```c
size_t strLength(char *string) {
  assert(string != NULL);
  return strlen(string);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strLength>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
size_t strLength(char *string) {
  assert(string != NULL);
  return strlen(string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strLength>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
size_t strLength(char *string) {
  assert(string != NULL);
  return strlen(string);
}
```
user: What is the c source code of the assembly code below?

```asm
<op_or>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <clearArray@plt>
  movl   $0x7,-0x4(%rbp)
  jmp    L1
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L5
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x31,(%rax)
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
L15:
  subl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <zsflagging@plt>
  nop
  leave
  ret
```

assistant: ```c
void op_or(char rega[], char regb[], char accumulator[], char flags[]) {
  clearArray(accumulator);
  int i;
  for (i = 8 - 1; i >= 0; i--) {
    if (rega[i] == '1' || regb[i] == '1')
      accumulator[i] = '1';
    else
      accumulator[i] = '0';
  }
  zsflagging(flags, accumulator);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<op_or>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%r13
  mov    %rdx,%rdi
  call   <clearArray@plt>
  mov    $0x7,%eax
  jmp    L18
L27:
  movb   $0x31,(%rbx,%rax,1)
L41:
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  je     L3
L18:
  cmpb   $0x31,0x0(%rbp,%rax,1)
  je     L27
  cmpb   $0x31,(%r12,%rax,1)
  je     L27
  movb   $0x30,(%rbx,%rax,1)
  jmp    L41
L3:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <zsflagging@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void op_or(char rega[], char regb[], char accumulator[], char flags[]) {
  clearArray(accumulator);
  int i;
  for (i = 8 - 1; i >= 0; i--) {
    if (rega[i] == '1' || regb[i] == '1')
      accumulator[i] = '1';
    else
      accumulator[i] = '0';
  }
  zsflagging(flags, accumulator);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<op_or>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <clearArray@plt>
  mov    $0x7,%eax
  mov    $0x30,%edx
  nopl   0x0(%rax)
L2:
  movzbl (%rbx,%rax,1),%edi
  cmp    $0x31,%dil
  je     L14
  movzbl (%r12,%rax,1),%edi
  cmp    $0x31,%dil
  cmovne %edx,%edi
L14:
  mov    %dil,0x0(%rbp,%rax,1)
  sub    $0x1,%rax
  jae    L2
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <zsflagging@plt>
```

assistant: ```c
void op_or(char rega[], char regb[], char accumulator[], char flags[]) {
  clearArray(accumulator);
  int i;
  for (i = 8 - 1; i >= 0; i--) {
    if (rega[i] == '1' || regb[i] == '1')
      accumulator[i] = '1';
    else
      accumulator[i] = '0';
  }
  zsflagging(flags, accumulator);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<op_or>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <clearArray@plt>
  movzbl 0x7(%rbx),%eax
  cmp    $0x31,%al
  je     L47
  movzbl 0x7(%r12),%eax
  mov    $0x30,%edx
  cmp    $0x31,%al
  cmovne %edx,%eax
L47:
  mov    %al,0x7(%rbp)
  movzbl 0x6(%rbx),%eax
  cmp    $0x31,%al
  je     L56
  movzbl 0x6(%r12),%eax
  mov    $0x30,%edx
  cmp    $0x31,%al
  cmovne %edx,%eax
L56:
  mov    %al,0x6(%rbp)
  movzbl 0x5(%rbx),%eax
  cmp    $0x31,%al
  je     L16
  movzbl 0x5(%r12),%eax
  mov    $0x30,%edx
  cmp    $0x31,%al
  cmovne %edx,%eax
L16:
  mov    %al,0x5(%rbp)
  movzbl 0x4(%rbx),%eax
  cmp    $0x31,%al
  je     L55
  movzbl 0x4(%r12),%eax
  mov    $0x30,%edx
  cmp    $0x31,%al
  cmovne %edx,%eax
L55:
  mov    %al,0x4(%rbp)
  movzbl 0x3(%rbx),%eax
  cmp    $0x31,%al
  je     L50
  movzbl 0x3(%r12),%eax
  mov    $0x30,%edx
  cmp    $0x31,%al
  cmovne %edx,%eax
L50:
  mov    %al,0x3(%rbp)
  movzbl 0x2(%rbx),%eax
  cmp    $0x31,%al
  je     L22
  movzbl 0x2(%r12),%eax
  mov    $0x30,%edx
  cmp    $0x31,%al
  cmovne %edx,%eax
L22:
  mov    %al,0x2(%rbp)
  movzbl 0x1(%rbx),%eax
  cmp    $0x31,%al
  je     L43
  movzbl 0x1(%r12),%eax
  mov    $0x30,%edx
  cmp    $0x31,%al
  cmovne %edx,%eax
L43:
  mov    %al,0x1(%rbp)
  movzbl (%rbx),%eax
  cmp    $0x31,%al
  je     L62
  movzbl (%r12),%eax
  mov    $0x30,%edx
  cmp    $0x31,%al
  cmovne %edx,%eax
L62:
  mov    %al,0x0(%rbp)
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <zsflagging@plt>
```

assistant: ```c
void op_or(char rega[], char regb[], char accumulator[], char flags[]) {
  clearArray(accumulator);
  int i;
  for (i = 8 - 1; i >= 0; i--) {
    if (rega[i] == '1' || regb[i] == '1')
      accumulator[i] = '1';
    else
      accumulator[i] = '0';
  }
  zsflagging(flags, accumulator);
}
```