user: 这段汇编代码用C语言表示是什么样的?

```asm
<menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D128(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D150(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D145(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D121(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x7,%eax
  ja     L0
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D26(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D26(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x8(%rbp),%rax
  movl   $0x2,(%rax)
  jmp    L69
  mov    -0x8(%rbp),%rax
  movl   $0x3,(%rax)
  jmp    L69
  mov    -0x8(%rbp),%rax
  movl   $0x4,(%rax)
  jmp    L69
  mov    -0x8(%rbp),%rax
  movl   $0x6,(%rax)
  jmp    L69
  mov    -0x8(%rbp),%rax
  movl   $0x8,(%rax)
  jmp    L69
  mov    -0x8(%rbp),%rax
  movl   $0xa,(%rax)
  jmp    L69
  mov    -0x8(%rbp),%rax
  movl   $0x14,(%rax)
  jmp    L69
L0:
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L69:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D56
type_infered: string
name: retrieve_data
arguments: tag: D36
type_infered: string
name: retrieve_data
arguments: tag: D35
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D81
type_infered: string
name: retrieve_data
arguments: tag: D128
type_infered: string
name: retrieve_data
arguments: tag: D150
type_infered: string
name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D33
type_infered: string
name: retrieve_data
arguments: tag: D145
type_infered: string
name: retrieve_data
arguments: tag: D46
type_infered: string
name: retrieve_data
arguments: tag: D121
type_infered: string
name: retrieve_data
arguments: tag: D66
type_infered: string

tool: D56: 

-----LANCIO DADI-----



tool: D36: Selezionare il dado da lanciare:


tool: D35: 	1) D2 - Due facce


tool: D4: 	2) D3 - Tre facce


tool: D81: 	3) D4 - Quattro facce


tool: D128: 	4) D6 - Sei facce


tool: D150: 	5) D8 - Otto facce


tool: D2: 	6) D10- Dieci facce


tool: D33: 	7) D20- Venti facce


tool: D145: La tua scelta: 

tool: D46: %i

tool: D121: Quanti tiri? 

tool: D66: Dado non regolamentare. Terminato.



assistant: ```c
void menu(int *dado, int *tiri) {
  printf("\n\n-----LANCIO DADI-----\n\n");
  printf("Selezionare il dado da lanciare:\n");
  printf("\t1) D2 - Due facce\n");
  printf("\t2) D3 - Tre facce\n");
  printf("\t3) D4 - Quattro facce\n");
  printf("\t4) D6 - Sei facce\n");
  printf("\t5) D8 - Otto facce\n");
  printf("\t6) D10- Dieci facce\n");
  printf("\t7) D20- Venti facce\n");
  printf("La tua scelta: ");
  scanf("%i", dado);
  printf("Quanti tiri? ");
  scanf("%i", tiri);
  switch (*dado) {
  case 1:
    *dado = 2;
    break;
  case 2:
    *dado = 3;
    break;
  case 3:
    *dado = 4;
    break;
  case 4:
    *dado = 6;
    break;
  case 5:
    *dado = 8;
    break;
  case 6:
    *dado = 10;
    break;
  case 7:
    *dado = 20;
    break;
  default:
    printf("Dado non regolamentare. Terminato.\n\n");
    return;
    break;
  }
}
```