ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<vprint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void vprint(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stdout, fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vprint>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vprint(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stdout, fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vprint>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vprint(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stdout, fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    $0x1,%edi
  call   <testHashTable@plt>
  mov    %eax,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <test@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0xa,%esi
  mov    $0x14,%edi
  call   <testHashTable@plt>
  mov    %eax,%edx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <test@plt>
  or     %eax,-0x4(%rbp)
  mov    $0x96,%esi
  mov    $0x64,%edi
  call   <testHashTable@plt>
  mov    %eax,%edx
  lea    D34(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <test@plt>
  or     %eax,-0x4(%rbp)
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  call   <testHashTable@plt>
  mov    %eax,%edx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <test@plt>
  or     %eax,-0x4(%rbp)
  mov    $0x2710,%esi
  mov    $0x3e8,%edi
  call   <testHashTable@plt>
  mov    %eax,%edx
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <test@plt>
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D45
type_infered: string
name: unpack_data
arguments: label: D6
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D34
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string
name: unpack_data
arguments: label: D28
type_infered: string

tool: D45: 
Testing hash.c



tool: D6: HashTable with 1 bucket/ 100 entries

tool: D11: HashTable with 20 buckets/ 10 entries

tool: D34: HashTable with 100 buckets/ 150 entries

tool: D29: HashTable with 100 buckets/ 1000 entries

tool: D28: HashTable with 1000 buckets/ 10000 entries

assistant: ```c
int main(int argc, char **argv) {
  int res;
  printf("\nTesting "
         "hash.c"
         "\n\n");
  ;
  res = test(testHashTable(1, 100), "HashTable with 1 bucket/ 100 entries");
  res = res | test(testHashTable(20, 10), "HashTable with 20 buckets/ 10 entries");
  res = res | test(testHashTable(100, 150), "HashTable with 100 buckets/ 150 entries");
  res = res | test(testHashTable(100, 1000), "HashTable with 100 buckets/ 1000 entries");
  res = res | test(testHashTable(1000, 10000), "HashTable with 1000 buckets/ 10000 entries");
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    $0x1,%edi
  call   <testHashTable@plt>
  mov    %eax,%edi
  lea    D1(%rip),%rsi
  call   <test@plt>
  mov    %eax,%ebx
  mov    $0xa,%esi
  mov    $0x14,%edi
  call   <testHashTable@plt>
  mov    %eax,%edi
  lea    D7(%rip),%rsi
  call   <test@plt>
  or     %eax,%ebx
  mov    $0x96,%esi
  mov    $0x64,%edi
  call   <testHashTable@plt>
  mov    %eax,%edi
  lea    D32(%rip),%rsi
  call   <test@plt>
  or     %eax,%ebx
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  call   <testHashTable@plt>
  mov    %eax,%edi
  lea    D20(%rip),%rsi
  call   <test@plt>
  or     %eax,%ebx
  mov    $0x2710,%esi
  mov    $0x3e8,%edi
  call   <testHashTable@plt>
  mov    %eax,%edi
  lea    D4(%rip),%rsi
  call   <test@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D58
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string
name: read_data
arguments: tag: D32
type_guessed: string
name: read_data
arguments: tag: D20
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string

tool: D58: 
Testing hash.c



tool: D1: HashTable with 1 bucket/ 100 entries

tool: D7: HashTable with 20 buckets/ 10 entries

tool: D32: HashTable with 100 buckets/ 150 entries

tool: D20: HashTable with 100 buckets/ 1000 entries

tool: D4: HashTable with 1000 buckets/ 10000 entries

assistant: ```c
int main(int argc, char **argv) {
  int res;
  printf("\nTesting "
         "hash.c"
         "\n\n");
  ;
  res = test(testHashTable(1, 100), "HashTable with 1 bucket/ 100 entries");
  res = res | test(testHashTable(20, 10), "HashTable with 20 buckets/ 10 entries");
  res = res | test(testHashTable(100, 150), "HashTable with 100 buckets/ 150 entries");
  res = res | test(testHashTable(100, 1000), "HashTable with 100 buckets/ 1000 entries");
  res = res | test(testHashTable(1000, 10000), "HashTable with 1000 buckets/ 10000 entries");
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    $0x1,%edi
  call   <testHashTable@plt>
  lea    D14(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0xa,%esi
  mov    $0x14,%edi
  mov    %eax,%ebx
  call   <testHashTable@plt>
  lea    D23(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x96,%esi
  mov    $0x64,%edi
  or     %eax,%ebx
  call   <testHashTable@plt>
  lea    D21(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  or     %eax,%ebx
  call   <testHashTable@plt>
  lea    D41(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x2710,%esi
  mov    $0x3e8,%edi
  or     %eax,%ebx
  call   <testHashTable@plt>
  lea    D37(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D59
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D23
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D41
datatype: string
name: read_data
arguments: data_tag: D37
datatype: string

tool: D59: 
Testing hash.c



tool: D14: HashTable with 1 bucket/ 100 entries

tool: D23: HashTable with 20 buckets/ 10 entries

tool: D21: HashTable with 100 buckets/ 150 entries

tool: D41: HashTable with 100 buckets/ 1000 entries

tool: D37: HashTable with 1000 buckets/ 10000 entries

assistant: ```c
int main(int argc, char **argv) {
  int res;
  printf("\nTesting "
         "hash.c"
         "\n\n");
  ;
  res = test(testHashTable(1, 100), "HashTable with 1 bucket/ 100 entries");
  res = res | test(testHashTable(20, 10), "HashTable with 20 buckets/ 10 entries");
  res = res | test(testHashTable(100, 150), "HashTable with 100 buckets/ 150 entries");
  res = res | test(testHashTable(100, 1000), "HashTable with 100 buckets/ 1000 entries");
  res = res | test(testHashTable(1000, 10000), "HashTable with 1000 buckets/ 10000 entries");
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    $0x1,%edi
  call   <testHashTable@plt>
  lea    D43(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0xa,%esi
  mov    $0x14,%edi
  mov    %eax,%ebx
  call   <testHashTable@plt>
  lea    D14(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x96,%esi
  mov    $0x64,%edi
  or     %eax,%ebx
  call   <testHashTable@plt>
  lea    D5(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  or     %eax,%ebx
  call   <testHashTable@plt>
  lea    D27(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x2710,%esi
  mov    $0x3e8,%edi
  or     %eax,%ebx
  call   <testHashTable@plt>
  lea    D44(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D43
datatype: string
name: disassemble_data
arguments: label: D14
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D44
datatype: string

tool: D18: 
Testing hash.c



tool: D43: HashTable with 1 bucket/ 100 entries

tool: D14: HashTable with 20 buckets/ 10 entries

tool: D5: HashTable with 100 buckets/ 150 entries

tool: D27: HashTable with 100 buckets/ 1000 entries

tool: D44: HashTable with 1000 buckets/ 10000 entries

assistant: ```c
int main(int argc, char **argv) {
  int res;
  printf("\nTesting "
         "hash.c"
         "\n\n");
  ;
  res = test(testHashTable(1, 100), "HashTable with 1 bucket/ 100 entries");
  res = res | test(testHashTable(20, 10), "HashTable with 20 buckets/ 10 entries");
  res = res | test(testHashTable(100, 150), "HashTable with 100 buckets/ 150 entries");
  res = res | test(testHashTable(100, 1000), "HashTable with 100 buckets/ 1000 entries");
  res = res | test(testHashTable(1000, 10000), "HashTable with 1000 buckets/ 10000 entries");
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xec(%rbp)
  movl   $0x0,-0xe8(%rbp)
  lea    -0xf0(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0xe4(%rbp)
  jmp    L57
L61:
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L38
  addl   $0x3,-0xec(%rbp)
  jmp    L35
L38:
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L27
  addl   $0x3,-0xe8(%rbp)
  jmp    L35
L27:
  addl   $0x1,-0xec(%rbp)
  addl   $0x1,-0xe8(%rbp)
L35:
  addl   $0x1,-0xe4(%rbp)
L57:
  mov    -0xf0(%rbp),%eax
  cmp    %eax,-0xe4(%rbp)
  jl     L61
  mov    -0xe8(%rbp),%edx
  mov    -0xec(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D22
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string

tool: D22: %d


tool: D14: %s %s


tool: D0: %d %d


assistant: ```c
int main(void) {
  int num, tarou = 0, hanako = 0, i;
  char t[100], h[100];
  scanf("%d\n", &num);
  for (i = 0; i < num; i++) {
    scanf("%s %s\n", t, h);
    if (strcmp(t, h) > 0) {
      tarou += 3;
    } else if (strcmp(t, h) < 0) {
      hanako += 3;
    } else {
      tarou++;
      hanako++;
    }
  }
  printf("%d %d\n", tarou, hanako);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L29
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  lea    D24(%rip),%r14
  jmp    L69
L65:
  lea    0x80(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L41
  add    $0x1,%r13d
  add    $0x1,%r15d
L22:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L50
L69:
  lea    0x80(%rsp),%r12
  lea    0x10(%rsp),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L65
  add    $0x3,%r13d
  jmp    L22
L41:
  add    $0x3,%r15d
  jmp    L22
L29:
  mov    $0x0,%r15d
  mov    $0x0,%r13d
L50:
  mov    %r15d,%edx
  mov    %r13d,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0xf8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D24
data_type: string
name: unpack_data
arguments: tag: D11
data_type: string

tool: D2: %d


tool: D24: %s %s


tool: D11: %d %d


assistant: ```c
int main(void) {
  int num, tarou = 0, hanako = 0, i;
  char t[100], h[100];
  scanf("%d\n", &num);
  for (i = 0; i < num; i++) {
    scanf("%s %s\n", t, h);
    if (strcmp(t, h) > 0) {
      tarou += 3;
    } else if (strcmp(t, h) < 0) {
      hanako += 3;
    } else {
      tarou++;
      hanako++;
    }
  }
  printf("%d %d\n", tarou, hanako);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D5(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L13
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  lea    0x80(%rsp),%r12
  xor    %r13d,%r13d
  lea    0x10(%rsp),%rbp
  lea    D17(%rip),%r14
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L60:
  add    $0x3,%r13d
L50:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L9
L46:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r12,%rdx
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jg     L60
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L65
  add    $0x1,%r13d
  add    $0x1,%r15d
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L46
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %r15d,%edx
  mov    %r13d,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0xf8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L65:
  add    $0x3,%r15d
  jmp    L50
L13:
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  jmp    L9
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D21
type_infered: string

tool: D5: %d


tool: D17: %s %s


tool: D21: %d %d


assistant: ```c
int main(void) {
  int num, tarou = 0, hanako = 0, i;
  char t[100], h[100];
  scanf("%d\n", &num);
  for (i = 0; i < num; i++) {
    scanf("%s %s\n", t, h);
    if (strcmp(t, h) > 0) {
      tarou += 3;
    } else if (strcmp(t, h) < 0) {
      hanako += 3;
    } else {
      tarou++;
      hanako++;
    }
  }
  printf("%d %d\n", tarou, hanako);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D20(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L27
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  lea    0x80(%rsp),%r12
  xor    %r13d,%r13d
  lea    0x10(%rsp),%rbp
  lea    D8(%rip),%r14
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L80:
  add    $0x3,%r13d
L38:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L50
L54:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r12,%rdx
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jg     L80
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L21
  add    $0x1,%r13d
  add    $0x1,%r15d
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L54
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    %r15d,%edx
  mov    %r13d,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0xf8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  add    $0x3,%r15d
  jmp    L38
L27:
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  jmp    L50
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D20
type: string
name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D17
type: string

tool: D20: %d


tool: D8: %s %s


tool: D17: %d %d


assistant: ```c
int main(void) {
  int num, tarou = 0, hanako = 0, i;
  char t[100], h[100];
  scanf("%d\n", &num);
  for (i = 0; i < num; i++) {
    scanf("%s %s\n", t, h);
    if (strcmp(t, h) > 0) {
      tarou += 3;
    } else if (strcmp(t, h) < 0) {
      hanako += 3;
    } else {
      tarou++;
      hanako++;
    }
  }
  printf("%d %d\n", tarou, hanako);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <buildTree@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <swapNodes@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  struct node *root;
  int height;
  root = buildTree();
  swapNodes(root);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <buildTree@plt>
  mov    %rax,%rdi
  call   <swapNodes@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct node *root;
  int height;
  root = buildTree();
  swapNodes(root);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <buildTree@plt>
  mov    %rax,%rdi
  call   <swapNodes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct node *root;
  int height;
  root = buildTree();
  swapNodes(root);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <buildTree@plt>
  mov    %rax,%rdi
  call   <swapNodes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct node *root;
  int height;
  root = buildTree();
  swapNodes(root);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<qwerqwer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x18(%rbp)
  movabs $0x52545320656d6f73,%rax
  mov    %rax,-0x14(%rbp)
  movl   $0x474e49,-0xc(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x20(%rbp)
  jmp    L18
L22:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x14(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x24(%rbp),%eax
  add    $0x4,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x20(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
L18:
  mov    -0x1c(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  cltq
  movzbl -0x14(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L22
  movss  -0x20(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    -0x1c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <asdfasdf@plt>
  mov    %eax,-0x18(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x24(%rbp),%xmm1
  movss  -0x20(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x1c(%rbp),%eax
  imul   -0x18(%rbp),%eax
  shl    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
uint64_t qwerqwer(uint64_t x) {
  int i = x;
  int y = i * x + 4;
  char str[] = "some STRING";
  volatile float result = x + y;
  while (str[i + x]) {
    putchar(toupper(str[y]));
    result += x + 4;
    i++;
  }
  y = asdfasdf((int)result, i);
  putchar('\n');
  return result * x + (4 * i * y);
}
```
user: What is the c source code of the assembly code below:

```asm
<qwerqwer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%r12d
  imul   %edi,%r12d
  add    $0x4,%r12d
  movabs $0x52545320656d6f73,%rax
  mov    %rax,0xc(%rsp)
  movl   $0x474e49,0x14(%rsp)
  lea    (%rdi,%r12,1),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0x8(%rsp)
  lea    (%rdi,%rdi,1),%eax
  cltq
  cmpb   $0x0,0xc(%rsp,%rax,1)
  je     L24
  lea    0x1(%rdi),%eax
  cltq
  mov    %rax,%rbx
  lea    0xc(%rsp,%rax,1),%r13
L31:
  movslq %r12d,%rax
  movsbl 0xc(%rsp,%rax,1),%edi
  call   <toupper@plt>
  movsbl %al,%edi
  call   <putchar@plt>
  movss  0x8(%rsp),%xmm1
  lea    0x4(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rsp)
  mov    %ebx,%r14d
  add    $0x1,%rbx
  cmpb   $0x0,-0x2(%r13,%rbx,1)
  jne    L31
L14:
  movss  0x8(%rsp),%xmm0
  cvttss2si %xmm0,%edi
  mov    %r14d,%esi
  call   <asdfasdf@plt>
  mov    %eax,%ebx
  mov    $0xa,%edi
  call   <putchar@plt>
  movss  0x8(%rsp),%xmm2
  imul   %r14d,%ebx
  shl    $0x2,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebp,%xmm1
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  mov    %edi,%r14d
  jmp    L14
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t qwerqwer(uint64_t x) {
  int i = x;
  int y = i * x + 4;
  char str[] = "some STRING";
  volatile float result = x + y;
  while (str[i + x]) {
    putchar(toupper(str[y]));
    result += x + 4;
    i++;
  }
  y = asdfasdf((int)result, i);
  putchar('\n');
  return result * x + (4 * i * y);
}
```