ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D46(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  D35(%rip),%xmm0
  movsd  D58(%rip),%xmm1
  lea    D52(%rip),%rdi
  mulsd  0x10(%rsp),%xmm1
  movsd  D28(%rip),%xmm2
  mulsd  0x8(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  divsd  D57(%rip),%xmm0
  cmpnlesd %xmm0,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm2,%xmm1
  orpd   %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D46
datatype: string
name: read_data
arguments: tag: D35
datatype: f64
name: read_data
arguments: tag: D58
datatype: f64
name: read_data
arguments: tag: D52
datatype: string
name: read_data
arguments: tag: D28
datatype: f64
name: read_data
arguments: tag: D57
datatype: f64

tool: D46: %lf %lf

tool: D35: 3.5

tool: D58: 7.5

tool: D52: MEDIA = %.5f


tool: D28: 10

tool: D57: 11

assistant: ```c
int main(void) {
  double a, b;
  scanf("%lf %lf", &a, &b);
  double f = (a * 3.5 + b * 7.5) / 11.0;
  f = f >= 10.0 ? 10.0 : f;
  printf("MEDIA = %.5f\n", f);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  static int i;
  return !__builtin_constant_p(&i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  static int i;
  return !__builtin_constant_p(&i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  static int i;
  return !__builtin_constant_p(&i);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  static int i;
  return !__builtin_constant_p(&i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x15,-0x18(%rbp)
  movabs $0x61776f4e20617745,%rax
  mov    %rax,-0x13(%rbp)
  movw   $0x6172,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  mov    $0x15,%edx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%edx
  lea    -0x13(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x13(%rbp),%rax
  lea    D37(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x13(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x37,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D50
datatype: string
name: unpack_data
arguments: data_tag: D37
datatype: string
name: unpack_data
arguments: data_tag: D43
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D0: Ewa Nowara

tool: D50: %s is %d years old


tool: D37: bob

tool: D43: %s 


tool: D9: %d


assistant: ```c
int main() {
  int age = 21;
  char name[] = "Ewa Nowara";
  printf("%s is %d years old\n", "Ewa Nowara", 21);
  printf("%s is %d years old\n", name, age);
  strcpy(name, "bob");
  printf("%s \n", name);
  age = 55;
  printf("%d\n", age);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x61776f4e20617745,%rax
  mov    %rax,0xd(%rsp)
  movw   $0x6172,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    $0x15,%edx
  lea    D45(%rip),%rsi
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xd(%rsp),%rbx
  mov    $0x15,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D42(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x37,%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D45
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D42
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: string
name: disassemble_data
arguments: data_label: D32
type_infered: string

tool: D45: Ewa Nowara

tool: D19: %s is %d years old


tool: D42: bob

tool: D48: %s 


tool: D32: %d


assistant: ```c
int main() {
  int age = 21;
  char name[] = "Ewa Nowara";
  printf("%s is %d years old\n", "Ewa Nowara", 21);
  printf("%s is %d years old\n", name, age);
  strcpy(name, "bob");
  printf("%s \n", name);
  age = 55;
  printf("%d\n", age);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D20(%rip),%r12
  mov    $0x15,%edx
  lea    D29(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x61776f4e20617745,%rax
  lea    0xd(%rsp),%rbp
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x6172,%eax
  mov    %ax,0x15(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x15,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D44(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x37,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D20
type_guessed: string
name: read_data
arguments: data_tag: D29
type_guessed: string
name: read_data
arguments: data_tag: D44
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string

tool: D20: %s is %d years old


tool: D29: Ewa Nowara

tool: D44: bob

tool: D6: %s 


tool: D13: %d


assistant: ```c
int main() {
  int age = 21;
  char name[] = "Ewa Nowara";
  printf("%s is %d years old\n", "Ewa Nowara", 21);
  printf("%s is %d years old\n", name, age);
  strcpy(name, "bob");
  printf("%s \n", name);
  age = 55;
  printf("%d\n", age);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D38(%rip),%r12
  mov    $0x15,%edx
  lea    D33(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x61776f4e20617745,%rax
  lea    0xd(%rsp),%rbp
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x6172,%eax
  mov    %ax,0x15(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x15,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x37,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D38
type_guessed: string
name: read_data
arguments: data_tag: D33
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string
name: read_data
arguments: data_tag: D31
type_guessed: string
name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D38: %s is %d years old


tool: D33: Ewa Nowara

tool: D11: bob

tool: D31: %s 


tool: D4: %d


assistant: ```c
int main() {
  int age = 21;
  char name[] = "Ewa Nowara";
  printf("%s is %d years old\n", "Ewa Nowara", 21);
  printf("%s is %d years old\n", name, age);
  strcpy(name, "bob");
  printf("%s \n", name);
  age = 55;
  printf("%d\n", age);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_pawn_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L20
  cmpl   $0x7,-0xc(%rbp)
  jle    L47
L20:
  mov    $0x0,%eax
  jmp    L25
L47:
  cmpl   $0xffffffff,-0x10(%rbp)
  jne    L22
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  jmp    L25
L22:
  mov    -0x8(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int get_pawn_count(int cache_pawn_count[2][8], int file, int color) {
  if (file < 0 || file > 7) {
    return 0;
  }
  if (color == -1) {
    return cache_pawn_count[0][file];
  } else {
    return cache_pawn_count[1][file];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_pawn_count>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x7,%esi
  ja     L16
  cmp    $0xffffffff,%edx
  je     L3
  movslq %esi,%rsi
  mov    0x20(%rdi,%rsi,4),%eax
L16:
  ret
L3:
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int get_pawn_count(int cache_pawn_count[2][8], int file, int color) {
  if (file < 0 || file > 7) {
    return 0;
  }
  if (color == -1) {
    return cache_pawn_count[0][file];
  } else {
    return cache_pawn_count[1][file];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_pawn_count>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7,%esi
  ja     L18
  movslq %esi,%rsi
  cmp    $0xffffffff,%edx
  je     L4
  mov    0x20(%rdi,%rsi,4),%eax
L18:
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int get_pawn_count(int cache_pawn_count[2][8], int file, int color) {
  if (file < 0 || file > 7) {
    return 0;
  }
  if (color == -1) {
    return cache_pawn_count[0][file];
  } else {
    return cache_pawn_count[1][file];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_pawn_count>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7,%esi
  ja     L4
  movslq %esi,%rsi
  cmp    $0xffffffff,%edx
  je     L19
  mov    0x20(%rdi,%rsi,4),%eax
L4:
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int get_pawn_count(int cache_pawn_count[2][8], int file, int color) {
  if (file < 0 || file > 7) {
    return 0;
  }
  if (color == -1) {
    return cache_pawn_count[0][file];
  } else {
    return cache_pawn_count[1][file];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DecaPower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L4
L16:
  movsd  -0x8(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
data_type: f64
name: disassemble_data
arguments: data_tag: D8
data_type: byte[8]

tool: D15: 1

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double DecaPower(int power) {
  int i = 0;
  double output = 1;
  for (i = 1; i < power; i++) {
    output = output * 10;
  }
  return output;
}
```
user: Translate the below assembly code into C programming language:

```asm
<DecaPower>:
  endbr64
  cmp    $0x1,%edi
  jle    L12
  movsd  D23(%rip),%xmm0
  mov    $0x1,%eax
  movsd  D24(%rip),%xmm1
L5:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L5
  ret
L12:
  movsd  D23(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
type: f64
name: unpack_data
arguments: data_label: D24
type: byte[8]

tool: D23: 1

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double DecaPower(int power) {
  int i = 0;
  double output = 1;
  for (i = 1; i < power; i++) {
    output = output * 10;
  }
  return output;
}
```
user: What is the c source code of the assembly code below:

```asm
<DecaPower>:
  endbr64
  movsd  D11(%rip),%xmm0
  cmp    $0x1,%edi
  jle    L8
  movsd  D8(%rip),%xmm1
  mov    $0x1,%eax
  xchg   %ax,%ax
L7:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L7
  ret
  nopl   0x0(%rax)
L8:
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_guessed: f64
name: read_data
arguments: tag: D8
type_guessed: byte[8]

tool: D11: 1

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double DecaPower(int power) {
  int i = 0;
  double output = 1;
  for (i = 1; i < power; i++) {
    output = output * 10;
  }
  return output;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DecaPower>:
  endbr64
  movsd  D3(%rip),%xmm0
  cmp    $0x1,%edi
  jle    L19
  movsd  D1(%rip),%xmm1
  mov    $0x1,%eax
  xchg   %ax,%ax
L4:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L4
  ret
  nopl   0x0(%rax)
L19:
  ret
```

tool_calls: name: read_data
arguments: label: D3
data_type: f64
name: read_data
arguments: label: D1
data_type: byte[8]

tool: D3: 1

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double DecaPower(int power) {
  int i = 0;
  double output = 1;
  for (i = 1; i < power; i++) {
    output = output * 10;
  }
  return output;
}
```
user: What is the c source code of the assembly code below?

```asm
<ifn_array2wk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  shr    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L16:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  shrl   -0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jbe    L16
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ifn_array2wk(int *p2arr, const unsigned int const cuic_Nlwl, const unsigned int const cuic_N, int *a4p2k[]) {
  unsigned int ui_i;
  unsigned int ui_sum;
  unsigned int ui_sd;
  for (ui_i = 0, ui_sum = 0, ui_sd = (cuic_N >> 1); ui_i <= cuic_Nlwl; ui_i += 1) {
    a4p2k[ui_i] = &p2arr[ui_sum];
    ui_sum += ui_sd;
    ui_sd >>= 1;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ifn_array2wk>:
  endbr64
  shr    %edx
  mov    $0x0,%r8d
  mov    $0x0,%eax
L3:
  mov    %eax,%r9d
  mov    %r8d,%r10d
  lea    (%rdi,%r10,4),%r10
  mov    %r10,(%rcx,%r9,8)
  add    %edx,%r8d
  shr    %edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jae    L3
  ret
```

assistant: ```c
void ifn_array2wk(int *p2arr, const unsigned int const cuic_Nlwl, const unsigned int const cuic_N, int *a4p2k[]) {
  unsigned int ui_i;
  unsigned int ui_sum;
  unsigned int ui_sd;
  for (ui_i = 0, ui_sum = 0, ui_sd = (cuic_N >> 1); ui_i <= cuic_Nlwl; ui_i += 1) {
    a4p2k[ui_i] = &p2arr[ui_sum];
    ui_sum += ui_sd;
    ui_sd >>= 1;
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ifn_array2wk>:
  endbr64
  shr    %edx
  xor    %r8d,%r8d
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r8d,%r10d
  mov    %eax,%r9d
  add    $0x1,%eax
  add    %edx,%r8d
  lea    (%rdi,%r10,4),%r10
  shr    %edx
  mov    %r10,(%rcx,%r9,8)
  cmp    %eax,%esi
  jae    L1
  ret
```

assistant: ```c
void ifn_array2wk(int *p2arr, const unsigned int const cuic_Nlwl, const unsigned int const cuic_N, int *a4p2k[]) {
  unsigned int ui_i;
  unsigned int ui_sum;
  unsigned int ui_sd;
  for (ui_i = 0, ui_sum = 0, ui_sd = (cuic_N >> 1); ui_i <= cuic_Nlwl; ui_i += 1) {
    a4p2k[ui_i] = &p2arr[ui_sum];
    ui_sum += ui_sd;
    ui_sd >>= 1;
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<ifn_array2wk>:
  endbr64
  shr    %edx
  xor    %r8d,%r8d
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r8d,%r10d
  mov    %eax,%r9d
  add    $0x1,%eax
  add    %edx,%r8d
  lea    (%rdi,%r10,4),%r10
  shr    %edx
  mov    %r10,(%rcx,%r9,8)
  cmp    %eax,%esi
  jae    L0
  ret
```

assistant: ```c
void ifn_array2wk(int *p2arr, const unsigned int const cuic_Nlwl, const unsigned int const cuic_N, int *a4p2k[]) {
  unsigned int ui_i;
  unsigned int ui_sum;
  unsigned int ui_sd;
  for (ui_i = 0, ui_sum = 0, ui_sd = (cuic_N >> 1); ui_i <= cuic_Nlwl; ui_i += 1) {
    a4p2k[ui_i] = &p2arr[ui_sum];
    ui_sum += ui_sd;
    ui_sd >>= 1;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f_omp_target>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f_omp_target(void) {
#pragma omp target
  {
#pragma omp target
    ;
#pragma omp target data map(i)
    ;
#pragma omp target update to(i)
#pragma omp parallel
    {
#pragma omp target
      ;
#pragma omp target data map(i)
      ;
#pragma omp target update to(i)
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f_omp_target>:
  endbr64
  ret
```

assistant: ```c
void f_omp_target(void) {
#pragma omp target
  {
#pragma omp target
    ;
#pragma omp target data map(i)
    ;
#pragma omp target update to(i)
#pragma omp parallel
    {
#pragma omp target
      ;
#pragma omp target data map(i)
      ;
#pragma omp target update to(i)
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<f_omp_target>:
  endbr64
  ret
```

assistant: ```c
void f_omp_target(void) {
#pragma omp target
  {
#pragma omp target
    ;
#pragma omp target data map(i)
    ;
#pragma omp target update to(i)
#pragma omp parallel
    {
#pragma omp target
      ;
#pragma omp target data map(i)
      ;
#pragma omp target update to(i)
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f_omp_target>:
  endbr64
  ret
```

assistant: ```c
void f_omp_target(void) {
#pragma omp target
  {
#pragma omp target
    ;
#pragma omp target data map(i)
    ;
#pragma omp target update to(i)
#pragma omp parallel
    {
#pragma omp target
      ;
#pragma omp target data map(i)
      ;
#pragma omp target update to(i)
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parity_counter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L8:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  xor    %eax,-0x4(%rbp)
  sarl   -0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int parity_counter(int symbol, int length) {
  int counter;
  int temp_parity = 0;
  for (counter = 0; counter < length; counter++) {
    temp_parity = temp_parity ^ (symbol & 1);
    symbol = symbol >> 1;
  }
  return (temp_parity);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parity_counter>:
  endbr64
  test   %esi,%esi
  jle    L9
  mov    $0x0,%edx
  mov    $0x0,%eax
L7:
  mov    %edi,%ecx
  and    $0x1,%ecx
  xor    %ecx,%edx
  sar    %edi
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L7
L13:
  mov    %edx,%eax
  ret
L9:
  mov    $0x0,%edx
  jmp    L13
```

assistant: ```c
int parity_counter(int symbol, int length) {
  int counter;
  int temp_parity = 0;
  for (counter = 0; counter < length; counter++) {
    temp_parity = temp_parity ^ (symbol & 1);
    symbol = symbol >> 1;
  }
  return (temp_parity);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parity_counter>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L1
  xor    %eax,%eax
  nopl   (%rax)
L7:
  mov    %edi,%edx
  add    $0x1,%eax
  sar    %edi
  and    $0x1,%edx
  xor    %edx,%r8d
  cmp    %eax,%esi
  jne    L7
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity_counter(int symbol, int length) {
  int counter;
  int temp_parity = 0;
  for (counter = 0; counter < length; counter++) {
    temp_parity = temp_parity ^ (symbol & 1);
    symbol = symbol >> 1;
  }
  return (temp_parity);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parity_counter>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L2
  xor    %eax,%eax
  nopl   (%rax)
L4:
  mov    %edi,%edx
  add    $0x1,%eax
  sar    %edi
  and    $0x1,%edx
  xor    %edx,%r8d
  cmp    %eax,%esi
  jne    L4
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity_counter(int symbol, int length) {
  int counter;
  int temp_parity = 0;
  for (counter = 0; counter < length; counter++) {
    temp_parity = temp_parity ^ (symbol & 1);
    symbol = symbol >> 1;
  }
  return (temp_parity);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_in_str_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x38(%rbp)
  mov    %al,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L27
L7:
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L34
L27:
  movsbl -0x2c(%rbp),%ecx
  lea    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <split_and_get@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L7
  jmp    L18
L34:
  nop
L18:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int is_in_str_list(const char list[], char separator, const char needle[]) {
  char *list_copy = strdup(list);
  char *item = list_copy, *state = NULL;
  while ((item = split_and_get(item, separator, &state)) != NULL) {
    if (strcasecmp(item, needle) == 0) {
      break;
    }
  }
  free(list_copy);
  return (item != NULL);
}
```