ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D36(%rip),%r15
  push   %r14
  lea    D31(%rip),%r14
  push   %r13
  lea    D39(%rip),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  sub    $0x8,%rsp
  jmp    L116
  nopl   0x0(%rax)
L70:
  mov    %ebx,%edi
  call   <u_ideographic@plt>
  test   %rax,%rax
  jne    L37
L58:
  mov    %ebx,%edi
  call   <u_combining_char@plt>
  test   %rax,%rax
  jne    L39
L110:
  mov    %ebx,%edi
  call   <u_extender@plt>
  test   %rax,%rax
  jne    L63
L102:
  mov    %ebx,%edi
  call   <u_digit@plt>
  test   %rax,%rax
  jne    L38
L89:
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x8000,%ebx
  je     L60
L116:
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_base_char@plt>
  test   %rax,%rax
  je     L70
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_ideographic@plt>
  test   %rax,%rax
  je     L58
L37:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_combining_char@plt>
  test   %rax,%rax
  je     L110
L39:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_extender@plt>
  test   %rax,%rax
  je     L102
L63:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_digit@plt>
  test   %rax,%rax
  je     L89
L38:
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L89
L60:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D36
datatype: string
name: disassemble_data
arguments: data_label: D31
datatype: string
name: disassemble_data
arguments: data_label: D39
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D3
datatype: string
name: disassemble_data
arguments: data_label: D56
datatype: string

tool: D36:  base

tool: D31:  ideographic

tool: D39:  combining

tool: D4:  extender

tool: D3: %#x is

tool: D56:  digit

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = -1; i != 32768; ++i) {
    printf("%#x is", i);
    if (u_base_char(i))
      printf(" base");
    if (u_ideographic(i))
      printf(" ideographic");
    if (u_combining_char(i))
      printf(" combining");
    if (u_extender(i))
      printf(" extender");
    if (u_digit(i))
      printf(" digit");
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D8(%rip),%r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    D40(%rip),%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  sub    $0x8,%rsp
  jmp    L57
  nopl   0x0(%rax)
L105:
  mov    %ebx,%edi
  call   <u_ideographic@plt>
  test   %rax,%rax
  jne    L93
L70:
  mov    %ebx,%edi
  call   <u_combining_char@plt>
  test   %rax,%rax
  jne    L67
L1:
  mov    %ebx,%edi
  call   <u_extender@plt>
  test   %rax,%rax
  jne    L42
L114:
  mov    %ebx,%edi
  call   <u_digit@plt>
  test   %rax,%rax
  jne    L27
L58:
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x8000,%ebx
  je     L56
L57:
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_base_char@plt>
  test   %rax,%rax
  je     L105
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_ideographic@plt>
  test   %rax,%rax
  je     L70
L93:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_combining_char@plt>
  test   %rax,%rax
  je     L1
L67:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_extender@plt>
  test   %rax,%rax
  je     L114
L42:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <u_digit@plt>
  test   %rax,%rax
  je     L58
L27:
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
L56:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string
name: unpack_data
arguments: data_tag: D18
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D40
datatype: string
name: unpack_data
arguments: data_tag: D43
datatype: string

tool: D8:  base

tool: D3:  ideographic

tool: D18:  combining

tool: D5:  extender

tool: D40: %#x is

tool: D43:  digit

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = -1; i != 32768; ++i) {
    printf("%#x is", i);
    if (u_base_char(i))
      printf(" base");
    if (u_ideographic(i))
      printf(" ideographic");
    if (u_combining_char(i))
      printf(" combining");
    if (u_extender(i))
      printf(" extender");
    if (u_digit(i))
      printf(" digit");
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bubbleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L8:
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L2:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L6
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L6:
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L2
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubbleSort(int *a, int size) {
  int i, j;
  for (i = 0; i < size - 1; i++)
    for (j = 0; j < size - i - 1; j++)
      if (a[j] > a[j + 1]) {
        int temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L62
  lea    0x4(%rdi),%r9
  jmp    L63
L77:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L29
L38:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L77
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L77
L29:
  sub    $0x1,%r8d
  je     L62
L63:
  test   %r8d,%r8d
  jle    L29
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L38
L62:
  ret
```

assistant: ```c
void bubbleSort(int *a, int size) {
  int i, j;
  for (i = 0; i < size - 1; i++)
    for (j = 0; j < size - i - 1; j++)
      if (a[j] > a[j + 1]) {
        int temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %edx,%edx
  jle    L3
  lea    0x4(%rdi),%r9
  nop
L31:
  sub    $0x1,%edx
  mov    %rdi,%rax
  mov    %rdx,%r8
  lea    (%r9,%rdx,4),%rsi
  nopl   (%rax)
L30:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L18
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L18:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L30
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L31
L3:
  ret
```

assistant: ```c
void bubbleSort(int *a, int size) {
  int i, j;
  for (i = 0; i < size - 1; i++)
    for (j = 0; j < size - i - 1; j++)
      if (a[j] > a[j + 1]) {
        int temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L13
  lea    0x4(%rdi),%r9
  nop
L4:
  sub    $0x1,%eax
  mov    %rdi,%rdx
  mov    %rax,%r8
  lea    (%r9,%rax,4),%rsi
  nopl   (%rax)
L9:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L0
  movq   %xmm1,(%rdx)
L0:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L9
  mov    %r8d,%eax
  test   %r8d,%r8d
  jne    L4
L13:
  ret
```

assistant: ```c
void bubbleSort(int *a, int size) {
  int i, j;
  for (i = 0; i < size - 1; i++)
    for (j = 0; j < size - i - 1; j++)
      if (a[j] > a[j + 1]) {
        int temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x8(%rbp)
  movl   $0x63,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: x = %d, y = %d


assistant: ```c
int main() {
  int x = 10;
  int y = 99;
  printf("x = %d, y = %d\n", x, y);
  do {
    x = x + y;
    y = x - y;
    x = x - y;
  } while (0);
  printf("x = %d, y = %d\n", x, y);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x63,%edx
  mov    $0xa,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    $0x63,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: x = %d, y = %d


assistant: ```c
int main() {
  int x = 10;
  int y = 99;
  printf("x = %d, y = %d\n", x, y);
  do {
    x = x + y;
    y = x - y;
    x = x - y;
  } while (0);
  printf("x = %d, y = %d\n", x, y);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0x63,%edx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xa,%edx
  mov    $0x63,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D0: x = %d, y = %d


assistant: ```c
int main() {
  int x = 10;
  int y = 99;
  printf("x = %d, y = %d\n", x, y);
  do {
    x = x + y;
    y = x - y;
    x = x - y;
  } while (0);
  printf("x = %d, y = %d\n", x, y);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    $0x63,%edx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xa,%edx
  mov    $0x63,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: x = %d, y = %d


assistant: ```c
int main() {
  int x = 10;
  int y = 99;
  printf("x = %d, y = %d\n", x, y);
  do {
    x = x + y;
    y = x - y;
    x = x - y;
  } while (0);
  printf("x = %d, y = %d\n", x, y);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decode_four_codes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  sar    $0x4,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  sar    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void decode_four_codes(uint8_t *out, const uint8_t *src) {
  out[0] = (src[0] << 2) | (src[1] >> 4);
  out[1] = (src[1] << 4) | (src[2] >> 2);
  out[2] = (src[2] << 6) | src[3];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decode_four_codes>:
  endbr64
  mov    (%rsi),%eax
  shl    $0x2,%eax
  mov    0x4(%rsi),%edx
  sar    $0x4,%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  shl    $0x4,%eax
  mov    0x8(%rsi),%edx
  sar    $0x2,%edx
  or     %edx,%eax
  mov    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  shl    $0x6,%eax
  or     0xc(%rsi),%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void decode_four_codes(uint8_t *out, const uint8_t *src) {
  out[0] = (src[0] << 2) | (src[1] >> 4);
  out[1] = (src[1] << 4) | (src[2] >> 2);
  out[2] = (src[2] << 6) | src[3];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<decode_four_codes>:
  endbr64
  mov    (%rsi),%eax
  mov    0x4(%rsi),%edx
  shl    $0x2,%eax
  sar    $0x4,%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  mov    0x8(%rsi),%edx
  shl    $0x4,%eax
  sar    $0x2,%edx
  or     %edx,%eax
  mov    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  shl    $0x6,%eax
  or     0xc(%rsi),%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void decode_four_codes(uint8_t *out, const uint8_t *src) {
  out[0] = (src[0] << 2) | (src[1] >> 4);
  out[1] = (src[1] << 4) | (src[2] >> 2);
  out[2] = (src[2] << 6) | src[3];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decode_four_codes>:
  endbr64
  mov    (%rsi),%eax
  mov    0x4(%rsi),%edx
  shl    $0x2,%eax
  sar    $0x4,%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  mov    0x8(%rsi),%edx
  shl    $0x4,%eax
  sar    $0x2,%edx
  or     %edx,%eax
  mov    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  shl    $0x6,%eax
  or     0xc(%rsi),%eax
  mov    %eax,0x8(%rdi)
  ret
```

assistant: ```c
void decode_four_codes(uint8_t *out, const uint8_t *src) {
  out[0] = (src[0] << 2) | (src[1] >> 4);
  out[1] = (src[1] << 4) | (src[2] >> 2);
  out[2] = (src[2] << 6) | src[3];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ifall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L1:
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L1
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ifall(int n, int k) {
  int prod = 1, t = n, j;
  for (j = 0; j < k; ++j) {
    prod *= t;
    --t;
  }
  return prod;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ifall>:
  endbr64
  test   %esi,%esi
  jle    L5
  mov    %edi,%edx
  sub    %esi,%edx
  mov    $0x1,%eax
L18:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    %edx,%edi
  jne    L18
  ret
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ifall(int n, int k) {
  int prod = 1, t = n, j;
  for (j = 0; j < k; ++j) {
    prod *= t;
    --t;
  }
  return prod;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ifall>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %edi,%edx
  mov    $0x1,%eax
  sub    %esi,%edx
  nopl   0x0(%rax)
L4:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    %edx,%edi
  jne    L4
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ifall(int n, int k) {
  int prod = 1, t = n, j;
  for (j = 0; j < k; ++j) {
    prod *= t;
    --t;
  }
  return prod;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ifall>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    %edi,%edx
  mov    $0x1,%eax
  sub    %esi,%edx
  nopl   0x0(%rax)
L1:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    %edx,%edi
  jne    L1
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ifall(int n, int k) {
  int prod = 1, t = n, j;
  for (j = 0; j < k; ++j) {
    prod *= t;
    --t;
  }
  return prod;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    -0x48(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double func1(double *X0, double *X, void (*vofx)(double *, double *)) {
  double V[(4)];
  vofx(X, V);
  return (sin(V[2]));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func1>:
  endbr64
  sub    $0x38,%rsp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   *%rdx
  movsd  0x10(%rsp),%xmm0
  call   <sin@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double func1(double *X0, double *X, void (*vofx)(double *, double *)) {
  double V[(4)];
  vofx(X, V);
  return (sin(V[2]));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func1>:
  endbr64
  sub    $0x38,%rsp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   *%rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  movsd  0x10(%rsp),%xmm0
  add    $0x38,%rsp
  jmp    1070 <sin@plt>
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double func1(double *X0, double *X, void (*vofx)(double *, double *)) {
  double V[(4)];
  vofx(X, V);
  return (sin(V[2]));
}
```
user: Translate the below assembly code into C programming language:

```asm
<func1>:
  endbr64
  sub    $0x38,%rsp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   *%rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  movsd  0x10(%rsp),%xmm0
  add    $0x38,%rsp
  jmp    1070 <sin@plt>
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double func1(double *X0, double *X, void (*vofx)(double *, double *)) {
  double V[(4)];
  vofx(X, V);
  return (sin(V[2]));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2a,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: %f

assistant: ```c
void test() {
  typedef signed long int ssize_t;
  printf("%f", (ssize_t)42);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: %f

assistant: ```c
void test() {
  typedef signed long int ssize_t;
  printf("%f", (ssize_t)42);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test>:
  endbr64
  mov    $0x2a,%esi
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: %f

assistant: ```c
void test() {
  typedef signed long int ssize_t;
  printf("%f", (ssize_t)42);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  mov    $0x2a,%esi
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %f

assistant: ```c
void test() {
  typedef signed long int ssize_t;
  printf("%f", (ssize_t)42);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_channelmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  jg     L11
  mov    -0x4(%rbp),%eax
  sar    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  and    %edx,%eax
  jmp    L16
L11:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int test_channelmap(u_int nr, u_char *map) {
  if (nr <= 127)
    return map[nr >> 3] & (1 << (nr & 7));
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_channelmap>:
  endbr64
  mov    %edi,%ecx
  mov    $0x0,%eax
  cmp    $0x7f,%edi
  jg     L7
  mov    %edi,%edx
  sar    $0x3,%edx
  movslq %edx,%rdx
  and    $0x7,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  and    (%rsi,%rdx,4),%eax
L7:
  ret
```

assistant: ```c
int test_channelmap(u_int nr, u_char *map) {
  if (nr <= 127)
    return map[nr >> 3] & (1 << (nr & 7));
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_channelmap>:
  endbr64
  mov    %edi,%ecx
  xor    %eax,%eax
  cmp    $0x7f,%edi
  jg     L7
  mov    %edi,%edx
  and    $0x7,%ecx
  mov    $0x1,%eax
  sar    $0x3,%edx
  shl    %cl,%eax
  movslq %edx,%rdx
  and    (%rsi,%rdx,4),%eax
L7:
  ret
```

assistant: ```c
int test_channelmap(u_int nr, u_char *map) {
  if (nr <= 127)
    return map[nr >> 3] & (1 << (nr & 7));
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_channelmap>:
  endbr64
  mov    %edi,%ecx
  xor    %eax,%eax
  cmp    $0x7f,%edi
  jg     L0
  mov    %edi,%edx
  and    $0x7,%ecx
  mov    $0x1,%eax
  sar    $0x3,%edx
  shl    %cl,%eax
  movslq %edx,%rdx
  and    (%rsi,%rdx,4),%eax
L0:
  ret
```

assistant: ```c
int test_channelmap(u_int nr, u_char *map) {
  if (nr <= 127)
    return map[nr >> 3] & (1 << (nr & 7));
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<delete_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  je     L4
  mov    $0xffffffff,%eax
  jmp    L14
L4:
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rec_delete_file@plt>
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int delete_file(const char *path) {
  struct stat b;
  if (lstat(path, &b)) {
    return -1;
  }
  return rec_delete_file(path, &b);
}
```