ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  D79(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D82(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movss  D104(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  D104(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D124(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D124(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cvtss2sd -0x18(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D124(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm3,%xmm3
  cvtss2sd -0x14(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D124(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x18(%rbp),%xmm1
  movss  D46(%rip),%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D122(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd -0x18(%rbp),%xmm1
  movsd  D106(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D10(%rip),%rax
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D79
type_guessed: f64
name: disassemble_data
arguments: tag: D82
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D104
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D124
type_guessed: string
name: disassemble_data
arguments: tag: D46
type_guessed: f32
name: disassemble_data
arguments: tag: D122
type_guessed: string
name: disassemble_data
arguments: tag: D106
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D83
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D29
type_guessed: string

tool: D79: 0.3

tool: {"D82": [0x00,0x00,0x00,0x40,0x33,0x33,0xd3,0x3f]}

tool: {"D104": [0x9a,0x99,0x99,0x3e]}

tool: D124: %.40f


tool: D46: 3.1

tool: D122: .3 (float)  * 3.1 (float)  = %.40f


tool: {"D106": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0x08,0x40]}

tool: D83: .3 (float)  * 3.1 (double) = %.40f


tool: {"D10": [0xc2,0xf5,0x28,0x5c,0x8f,0xc2,0xed,0x3f]}

tool: D29: .3 (double) * 3.1 (double) = %.40f


assistant: ```c
int main(void) {
  double d = .3;
  double df = .3f;
  float f = .3;
  float ff = .3f;
  printf("%.40f\n", d);
  printf("%.40f\n", df);
  printf("%.40f\n", f);
  printf("%.40f\n", ff);
  printf(".3 (float)  * 3.1 (float)  = %.40f\n", f * 3.1f);
  printf(".3 (float)  * 3.1 (double) = %.40f\n", f * 3.1);
  printf(".3 (double) * 3.1 (double) = %.40f\n", 0.3 * 3.1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  movsd  D57(%rip),%xmm0
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    D35(%rip),%rax
  movq   %rax,%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    D35(%rip),%rax
  movq   %rax,%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    D35(%rip),%rax
  movq   %rax,%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  movsd  D49(%rip),%xmm0
  lea    D69(%rip),%rdi
  call   <printf@plt>
  movsd  D61(%rip),%xmm0
  lea    D100(%rip),%rdi
  call   <printf@plt>
  movsd  D77(%rip),%xmm0
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D57
type_infered: f64
name: read_data
arguments: label: D29
type_infered: string
name: read_data
arguments: label: D35
type_infered: byte[8]
name: read_data
arguments: label: D49
type_infered: byte[8]
name: read_data
arguments: label: D69
type_infered: string
name: read_data
arguments: label: D61
type_infered: byte[8]
name: read_data
arguments: label: D100
type_infered: string
name: read_data
arguments: label: D77
type_infered: byte[8]
name: read_data
arguments: label: D38
type_infered: string

tool: D57: 0.3

tool: D29: %.40f


tool: {"D35": [0x00,0x00,0x00,0x40,0x33,0x33,0xd3,0x3f]}

tool: {"D49": [0x00,0x00,0x00,0x60,0x8f,0xc2,0xed,0x3f]}

tool: D69: .3 (float)  * 3.1 (float)  = %.40f


tool: {"D61": [0x00,0x00,0x00,0x70,0x8f,0xc2,0xed,0x3f]}

tool: D100: .3 (float)  * 3.1 (double) = %.40f


tool: {"D77": [0xc2,0xf5,0x28,0x5c,0x8f,0xc2,0xed,0x3f]}

tool: D38: .3 (double) * 3.1 (double) = %.40f


assistant: ```c
int main(void) {
  double d = .3;
  double df = .3f;
  float f = .3;
  float ff = .3f;
  printf("%.40f\n", d);
  printf("%.40f\n", df);
  printf("%.40f\n", f);
  printf("%.40f\n", ff);
  printf(".3 (float)  * 3.1 (float)  = %.40f\n", f * 3.1f);
  printf(".3 (float)  * 3.1 (double) = %.40f\n", f * 3.1);
  printf(".3 (double) * 3.1 (double) = %.40f\n", 0.3 * 3.1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  movsd  D28(%rip),%xmm0
  lea    D97(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D23(%rip),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    D23(%rip),%rax
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D23(%rip),%rax
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D72(%rip),%xmm0
  lea    D82(%rip),%rdi
  call   <printf@plt>
  movsd  D51(%rip),%xmm0
  lea    D69(%rip),%rdi
  call   <printf@plt>
  movsd  D5(%rip),%xmm0
  lea    D77(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D28
type: f64
name: unpack_data
arguments: label: D97
type: string
name: unpack_data
arguments: label: D23
type: byte[8]
name: unpack_data
arguments: label: D72
type: byte[8]
name: unpack_data
arguments: label: D82
type: string
name: unpack_data
arguments: label: D51
type: byte[8]
name: unpack_data
arguments: label: D69
type: string
name: unpack_data
arguments: label: D5
type: byte[8]
name: unpack_data
arguments: label: D77
type: string

tool: D28: 0.3

tool: D97: %.40f


tool: {"D23": [0x00,0x00,0x00,0x40,0x33,0x33,0xd3,0x3f]}

tool: {"D72": [0x00,0x00,0x00,0x60,0x8f,0xc2,0xed,0x3f]}

tool: D82: .3 (float)  * 3.1 (float)  = %.40f


tool: {"D51": [0x00,0x00,0x00,0x70,0x8f,0xc2,0xed,0x3f]}

tool: D69: .3 (float)  * 3.1 (double) = %.40f


tool: {"D5": [0xc2,0xf5,0x28,0x5c,0x8f,0xc2,0xed,0x3f]}

tool: D77: .3 (double) * 3.1 (double) = %.40f


assistant: ```c
int main(void) {
  double d = .3;
  double df = .3f;
  float f = .3;
  float ff = .3f;
  printf("%.40f\n", d);
  printf("%.40f\n", df);
  printf("%.40f\n", f);
  printf("%.40f\n", ff);
  printf(".3 (float)  * 3.1 (float)  = %.40f\n", f * 3.1f);
  printf(".3 (float)  * 3.1 (double) = %.40f\n", f * 3.1);
  printf(".3 (double) * 3.1 (double) = %.40f\n", 0.3 * 3.1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  movsd  D31(%rip),%xmm0
  lea    D90(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D102(%rip),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    D102(%rip),%rax
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D102(%rip),%rax
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D32(%rip),%xmm0
  lea    D87(%rip),%rdi
  call   <printf@plt>
  movsd  D109(%rip),%xmm0
  lea    D65(%rip),%rdi
  call   <printf@plt>
  movsd  D76(%rip),%xmm0
  lea    D52(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D31
type: f64
name: disassemble_data
arguments: label: D90
type: string
name: disassemble_data
arguments: label: D102
type: byte[8]
name: disassemble_data
arguments: label: D32
type: byte[8]
name: disassemble_data
arguments: label: D87
type: string
name: disassemble_data
arguments: label: D109
type: byte[8]
name: disassemble_data
arguments: label: D65
type: string
name: disassemble_data
arguments: label: D76
type: byte[8]
name: disassemble_data
arguments: label: D52
type: string

tool: D31: 0.3

tool: D90: %.40f


tool: {"D102": [0x00,0x00,0x00,0x40,0x33,0x33,0xd3,0x3f]}

tool: {"D32": [0x00,0x00,0x00,0x60,0x8f,0xc2,0xed,0x3f]}

tool: D87: .3 (float)  * 3.1 (float)  = %.40f


tool: {"D109": [0x00,0x00,0x00,0x70,0x8f,0xc2,0xed,0x3f]}

tool: D65: .3 (float)  * 3.1 (double) = %.40f


tool: {"D76": [0xc2,0xf5,0x28,0x5c,0x8f,0xc2,0xed,0x3f]}

tool: D52: .3 (double) * 3.1 (double) = %.40f


assistant: ```c
int main(void) {
  double d = .3;
  double df = .3f;
  float f = .3;
  float ff = .3f;
  printf("%.40f\n", d);
  printf("%.40f\n", df);
  printf("%.40f\n", f);
  printf("%.40f\n", ff);
  printf(".3 (float)  * 3.1 (float)  = %.40f\n", f * 3.1f);
  printf(".3 (float)  * 3.1 (double) = %.40f\n", f * 3.1);
  printf(".3 (double) * 3.1 (double) = %.40f\n", 0.3 * 3.1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hds_show_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cnfCreim@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <hdsShow@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cnfFree@plt>
  nop
  leave
  ret
```

assistant: ```c
void hds_show_(char *const topic, int *status, int topic_length) {
  char *topic_c;
  topic_c = cnfCreim(topic, topic_length);
  hdsShow(topic_c, status);
  cnfFree(topic_c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hds_show_>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %edx,%esi
  call   <cnfCreim@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <hdsShow@plt>
  mov    %rbx,%rdi
  call   <cnfFree@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void hds_show_(char *const topic, int *status, int topic_length) {
  char *topic_c;
  topic_c = cnfCreim(topic, topic_length);
  hdsShow(topic_c, status);
  cnfFree(topic_c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hds_show_>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edx,%esi
  push   %rbp
  sub    $0x8,%rsp
  call   <cnfCreim@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <hdsShow@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <cnfFree@plt>
```

assistant: ```c
void hds_show_(char *const topic, int *status, int topic_length) {
  char *topic_c;
  topic_c = cnfCreim(topic, topic_length);
  hdsShow(topic_c, status);
  cnfFree(topic_c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hds_show_>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edx,%esi
  push   %rbp
  sub    $0x8,%rsp
  call   <cnfCreim@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <hdsShow@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <cnfFree@plt>
```

assistant: ```c
void hds_show_(char *const topic, int *status, int topic_length) {
  char *topic_c;
  topic_c = cnfCreim(topic, topic_length);
  hdsShow(topic_c, status);
  cnfFree(topic_c);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Encuentra_Maximo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  comiss %xmm1,%xmm0
  jbe    L29
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L29:
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Encuentra_Maximo(int n, float S[10]) {
  int i, max;
  max = 0;
  for (i = 0; i < n; i++)
    if (S[i] > S[max])
      max = i;
  return max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Encuentra_Maximo>:
  endbr64
  test   %edi,%edi
  jle    L17
  mov    %edi,%edi
  mov    $0x0,%eax
  mov    $0x0,%edx
L16:
  movslq %edx,%rcx
  movss  (%rsi,%rax,4),%xmm0
  ucomiss (%rsi,%rcx,4),%xmm0
  cmova  %eax,%edx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L16
L18:
  mov    %edx,%eax
  ret
L17:
  mov    $0x0,%edx
  jmp    L18
```

assistant: ```c
int Encuentra_Maximo(int n, float S[10]) {
  int i, max;
  max = 0;
  for (i = 0; i < n; i++)
    if (S[i] > S[max])
      max = i;
  return max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Encuentra_Maximo>:
  endbr64
  test   %edi,%edi
  jle    L19
  movslq %edi,%rdi
  xor    %eax,%eax
  xor    %r8d,%r8d
L14:
  movslq %r8d,%rdx
  movss  (%rsi,%rax,4),%xmm0
  ucomiss (%rsi,%rdx,4),%xmm0
  cmova  %eax,%r8d
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L14
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Encuentra_Maximo(int n, float S[10]) {
  int i, max;
  max = 0;
  for (i = 0; i < n; i++)
    if (S[i] > S[max])
      max = i;
  return max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Encuentra_Maximo>:
  endbr64
  test   %edi,%edi
  jle    L9
  movss  (%rsi),%xmm0
  movslq %edi,%rdi
  xor    %eax,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L5:
  movss  (%rsi,%rax,4),%xmm1
  comiss %xmm0,%xmm1
  maxss  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movaps %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L5
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Encuentra_Maximo(int n, float S[10]) {
  int i, max;
  max = 0;
  for (i = 0; i < n; i++)
    if (S[i] > S[max])
      max = i;
  return max;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<most_significant_bit_u64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1f,-0xc(%rbp)
  movl   $0x10,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L29:
  mov    -0xc(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L27
  mov    -0x8(%rbp),%eax
  sub    %eax,-0xc(%rbp)
  jmp    L56
L27:
  mov    -0xc(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  cmp    $0x1,%rax
  je     L0
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
L56:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x5,-0x4(%rbp)
  jle    L29
  jmp    L18
L0:
  nop
L18:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int most_significant_bit_u64(unsigned long long int arg) {
  int msb_bit_ix = 31;
  int delta_shift_size = 16;
  int iteration;
  for (iteration = 0; iteration < 6; iteration++) {
    if (arg >> msb_bit_ix == 0)
      msb_bit_ix -= delta_shift_size;
    else if (arg >> msb_bit_ix == 1)
      break;
    else
      msb_bit_ix += delta_shift_size;
    delta_shift_size = (delta_shift_size + 1) >> 1;
  }
  return msb_bit_ix;
}
```
user: What is the c source code of the assembly code below?

```asm
<most_significant_bit_u64>:
  endbr64
  mov    $0x6,%edx
  mov    $0x10,%eax
  mov    $0x1f,%ecx
  jmp    L43
L37:
  cmp    $0x1,%rsi
  je     L10
  add    %eax,%ecx
L1:
  add    $0x1,%eax
  sar    %eax
  sub    $0x1,%edx
  je     L10
L43:
  mov    %rdi,%rsi
  shr    %cl,%rsi
  test   %rsi,%rsi
  jne    L37
  sub    %eax,%ecx
  jmp    L1
L10:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int most_significant_bit_u64(unsigned long long int arg) {
  int msb_bit_ix = 31;
  int delta_shift_size = 16;
  int iteration;
  for (iteration = 0; iteration < 6; iteration++) {
    if (arg >> msb_bit_ix == 0)
      msb_bit_ix -= delta_shift_size;
    else if (arg >> msb_bit_ix == 1)
      break;
    else
      msb_bit_ix += delta_shift_size;
    delta_shift_size = (delta_shift_size + 1) >> 1;
  }
  return msb_bit_ix;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<most_significant_bit_u64>:
  endbr64
  mov    $0x6,%edx
  mov    $0x10,%eax
  mov    $0x1f,%ecx
  jmp    L27
  nopl   (%rax)
L0:
  sub    %eax,%ecx
  add    $0x1,%eax
  sar    %eax
  sub    $0x1,%edx
  je     L21
L27:
  mov    %rdi,%rsi
  shr    %cl,%rsi
  test   %rsi,%rsi
  je     L0
  cmp    $0x1,%rsi
  je     L21
  add    %eax,%ecx
  add    $0x1,%eax
  sar    %eax
  sub    $0x1,%edx
  jne    L27
L21:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int most_significant_bit_u64(unsigned long long int arg) {
  int msb_bit_ix = 31;
  int delta_shift_size = 16;
  int iteration;
  for (iteration = 0; iteration < 6; iteration++) {
    if (arg >> msb_bit_ix == 0)
      msb_bit_ix -= delta_shift_size;
    else if (arg >> msb_bit_ix == 1)
      break;
    else
      msb_bit_ix += delta_shift_size;
    delta_shift_size = (delta_shift_size + 1) >> 1;
  }
  return msb_bit_ix;
}
```
user: What is the c source code of the assembly code below:

```asm
<most_significant_bit_u64>:
  endbr64
  mov    %rdi,%rax
  shr    $0x1f,%rax
  je     L160
  cmp    $0x1,%rax
  je     L38
  mov    $0x2f,%ecx
  mov    %rdi,%rax
  shr    %cl,%rax
  test   %rax,%rax
  je     L64
L43:
  cmp    $0x1,%rax
  je     L4
  add    $0x8,%ecx
  mov    %rdi,%rax
  shr    %cl,%rax
  test   %rax,%rax
  je     L5
L47:
  cmp    $0x1,%rax
  je     L4
  add    $0x4,%ecx
  mov    %rdi,%rax
  shr    %cl,%rax
  test   %rax,%rax
  je     L24
L1:
  cmp    $0x1,%rax
  je     L4
  add    $0x2,%ecx
  mov    %rdi,%rax
  shr    %cl,%rax
  test   %rax,%rax
  je     L40
L36:
  cmp    $0x1,%rax
  je     L4
  add    $0x1,%ecx
  shr    %cl,%rdi
  test   %rdi,%rdi
  jne    L71
L127:
  sub    $0x1,%ecx
L4:
  mov    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L160:
  mov    $0xf,%ecx
  mov    %rdi,%rax
  shr    %cl,%rax
  test   %rax,%rax
  jne    L43
L64:
  sub    $0x8,%ecx
  mov    %rdi,%rax
  shr    %cl,%rax
  test   %rax,%rax
  jne    L47
L5:
  sub    $0x4,%ecx
  mov    %rdi,%rax
  shr    %cl,%rax
  test   %rax,%rax
  jne    L1
L24:
  sub    $0x2,%ecx
  mov    %rdi,%rax
  shr    %cl,%rax
  test   %rax,%rax
  jne    L36
L40:
  sub    $0x1,%ecx
  shr    %cl,%rdi
  test   %rdi,%rdi
  je     L127
L71:
  xor    %eax,%eax
  cmp    $0x1,%rdi
  setne  %al
  add    %eax,%ecx
  mov    %ecx,%eax
  ret
L38:
  mov    $0x1f,%ecx
  jmp    L4
```

assistant: ```c
int most_significant_bit_u64(unsigned long long int arg) {
  int msb_bit_ix = 31;
  int delta_shift_size = 16;
  int iteration;
  for (iteration = 0; iteration < 6; iteration++) {
    if (arg >> msb_bit_ix == 0)
      msb_bit_ix -= delta_shift_size;
    else if (arg >> msb_bit_ix == 1)
      break;
    else
      msb_bit_ix += delta_shift_size;
    delta_shift_size = (delta_shift_size + 1) >> 1;
  }
  return msb_bit_ix;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<si_expect_yn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <si_receive_char@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  mov    $0xffffffff,%eax
  jmp    L7
L13:
  cmpl   $0x59,-0x4(%rbp)
  je     L36
  cmpl   $0x4e,-0x4(%rbp)
  je     L36
  mov    $0xffffffff,%eax
  jmp    L7
L36:
  cmpl   $0x59,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
L7:
  leave
  ret
```

assistant: ```c
int si_expect_yn(int fd) {
  int got;
  if ((got = si_receive_char(fd)) < 0)
    return -1;
  if (got != 'Y' && got != 'N')
    return -1;
  return (got == 'Y');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<si_expect_yn>:
  endbr64
  sub    $0x8,%rsp
  call   <si_receive_char@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  js     L13
  cmp    $0x59,%eax
  je     L18
  cmp    $0x4e,%eax
  jne    L13
L18:
  cmp    $0x59,%eax
  sete   %dl
  movzbl %dl,%edx
L13:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int si_expect_yn(int fd) {
  int got;
  if ((got = si_receive_char(fd)) < 0)
    return -1;
  if (got != 'Y' && got != 'N')
    return -1;
  return (got == 'Y');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<si_expect_yn>:
  endbr64
  sub    $0x8,%rsp
  call   <si_receive_char@plt>
  mov    $0xffffffff,%r8d
  test   %eax,%eax
  js     L12
  cmp    $0x59,%eax
  je     L0
  cmp    $0x4e,%eax
  jne    L12
L0:
  xor    %r8d,%r8d
  cmp    $0x59,%eax
  sete   %r8b
L12:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int si_expect_yn(int fd) {
  int got;
  if ((got = si_receive_char(fd)) < 0)
    return -1;
  if (got != 'Y' && got != 'N')
    return -1;
  return (got == 'Y');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<si_expect_yn>:
  endbr64
  sub    $0x8,%rsp
  call   <si_receive_char@plt>
  mov    $0xffffffff,%r8d
  test   %eax,%eax
  js     L16
  cmp    $0x59,%eax
  je     L12
  cmp    $0x4e,%eax
  jne    L16
L12:
  xor    %r8d,%r8d
  cmp    $0x59,%eax
  sete   %r8b
L16:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int si_expect_yn(int fd) {
  int got;
  if ((got = si_receive_char(fd)) < 0)
    return -1;
  if (got != 'Y' && got != 'N')
    return -1;
  return (got == 'Y');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<endian_big16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <endian_16hi8@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rbx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <endian_16lo8@plt>
  mov    %eax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void endian_big16(uint8_t ptr[2], uint_least16_t word) {
  ptr[0] = endian_16hi8(word);
  ptr[1] = endian_16lo8(word);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<endian_big16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <endian_16hi8@plt>
  mov    %eax,(%rbx)
  mov    %ebp,%edi
  call   <endian_16lo8@plt>
  mov    %eax,0x4(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void endian_big16(uint8_t ptr[2], uint_least16_t word) {
  ptr[0] = endian_16hi8(word);
  ptr[1] = endian_16lo8(word);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<endian_big16>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x8,%rsp
  call   <endian_16hi8@plt>
  mov    %ebp,%edi
  mov    %eax,(%rbx)
  call   <endian_16lo8@plt>
  mov    %eax,0x4(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void endian_big16(uint8_t ptr[2], uint_least16_t word) {
  ptr[0] = endian_16hi8(word);
  ptr[1] = endian_16lo8(word);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<endian_big16>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x8,%rsp
  call   <endian_16hi8@plt>
  mov    %ebp,%edi
  mov    %eax,(%rbx)
  call   <endian_16lo8@plt>
  mov    %eax,0x4(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void endian_big16(uint8_t ptr[2], uint_least16_t word) {
  ptr[0] = endian_16hi8(word);
  ptr[1] = endian_16lo8(word);
}
```