ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ocsp_resp_cb>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <SSL_get_tlsext_status_ocsp_resp@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <BIO_puts@plt>
  cmpq   $0x0,(%rsp)
  je     L11
  mov    %r12,%rsi
  mov    %r13d,%edx
  xor    %edi,%edi
  call   <d2i_OCSP_RESPONSE@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <BIO_puts@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <OCSP_RESPONSE_print@plt>
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <BIO_puts@plt>
  mov    %r12,%rdi
  call   <OCSP_RESPONSE_free@plt>
  mov    $0x1,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <BIO_puts@plt>
  mov    $0x1,%eax
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    D43(%rip),%rsi
  mov    %rbp,%rdi
  call   <BIO_puts@plt>
  mov    (%rsp),%rsi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    $0x4,%ecx
  call   <BIO_dump_indent@plt>
  xor    %eax,%eax
  jmp    L9
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D26
datatype: string
name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D18
datatype: string
name: unpack_data
arguments: label: D39
datatype: string
name: unpack_data
arguments: label: D43
datatype: string

tool: D26: OCSP response: 

tool: D13: 
======================================


tool: D18: ======================================


tool: D39: no response sent


tool: D43: response parse error


assistant: ```c
int ocsp_resp_cb(SSL *s, void *arg) {
  const unsigned char *p;
  int len;
  OCSP_RESPONSE *rsp;
  len = SSL_get_tlsext_status_ocsp_resp(s, &p);
  BIO_puts(arg, "OCSP response: ");
  if (!p) {
    BIO_puts(arg, "no response sent\n");
    return 1;
  }
  rsp = d2i_OCSP_RESPONSE(NULL, &p, len);
  if (!rsp) {
    BIO_puts(arg, "response parse error\n");
    BIO_dump_indent(arg, (char *)p, len, 4);
    return 0;
  }
  BIO_puts(arg, "\n======================================\n");
  OCSP_RESPONSE_print(arg, rsp, 0);
  BIO_puts(arg, "======================================\n");
  OCSP_RESPONSE_free(rsp);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ocsp_resp_cb>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <SSL_get_tlsext_status_ocsp_resp@plt>
  lea    D41(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <BIO_puts@plt>
  cmpq   $0x0,(%rsp)
  je     L18
  mov    %r12,%rsi
  mov    %r13d,%edx
  xor    %edi,%edi
  call   <d2i_OCSP_RESPONSE@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L49
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <BIO_puts@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <OCSP_RESPONSE_print@plt>
  lea    D34(%rip),%rsi
  mov    %rbp,%rdi
  call   <BIO_puts@plt>
  mov    %r12,%rdi
  call   <OCSP_RESPONSE_free@plt>
  mov    $0x1,%eax
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  lea    D45(%rip),%rsi
  mov    %rbp,%rdi
  call   <BIO_puts@plt>
  mov    $0x1,%eax
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L49:
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <BIO_puts@plt>
  mov    (%rsp),%rsi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    $0x4,%ecx
  call   <BIO_dump_indent@plt>
  xor    %eax,%eax
  jmp    L48
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D41
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D45
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string

tool: D41: OCSP response: 

tool: D26: 
======================================


tool: D34: ======================================


tool: D45: no response sent


tool: D17: response parse error


assistant: ```c
int ocsp_resp_cb(SSL *s, void *arg) {
  const unsigned char *p;
  int len;
  OCSP_RESPONSE *rsp;
  len = SSL_get_tlsext_status_ocsp_resp(s, &p);
  BIO_puts(arg, "OCSP response: ");
  if (!p) {
    BIO_puts(arg, "no response sent\n");
    return 1;
  }
  rsp = d2i_OCSP_RESPONSE(NULL, &p, len);
  if (!rsp) {
    BIO_puts(arg, "response parse error\n");
    BIO_dump_indent(arg, (char *)p, len, 4);
    return 0;
  }
  BIO_puts(arg, "\n======================================\n");
  OCSP_RESPONSE_print(arg, rsp, 0);
  BIO_puts(arg, "======================================\n");
  OCSP_RESPONSE_free(rsp);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimerIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <TimerIntNumberGet@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl %al,%eax
  test   %rax,%rax
  je     L0
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <IntRegister@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntEnable@plt>
L0:
  mov    -0x10(%rbp),%rax
  and    $0xff00,%eax
  test   %rax,%rax
  je     L7
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <IntRegister@plt>
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <IntEnable@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void TimerIntRegister(unsigned long ulBase, unsigned long ulTimer, void (*pfnHandler)(void)) {
  ;

  ;
  ulBase = TimerIntNumberGet(ulBase);
  if (ulTimer & 0x000000ff) {
    IntRegister(ulBase, pfnHandler);
    IntEnable(ulBase);
  }
  if (ulTimer & 0x0000ff00) {
    IntRegister(ulBase + 1, pfnHandler);
    IntEnable(ulBase + 1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<TimerIntRegister>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%r12
  call   <TimerIntNumberGet@plt>
  mov    %rax,%rbp
  test   %bl,%bl
  jne    L29
L39:
  test   $0xff,%bh
  jne    L22
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <IntRegister@plt>
  mov    %rbp,%rdi
  call   <IntEnable@plt>
  jmp    L39
L22:
  add    $0x1,%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <IntRegister@plt>
  mov    %rbp,%rdi
  call   <IntEnable@plt>
  jmp    L35
```

assistant: ```c
void TimerIntRegister(unsigned long ulBase, unsigned long ulTimer, void (*pfnHandler)(void)) {
  ;

  ;
  ulBase = TimerIntNumberGet(ulBase);
  if (ulTimer & 0x000000ff) {
    IntRegister(ulBase, pfnHandler);
    IntEnable(ulBase);
  }
  if (ulTimer & 0x0000ff00) {
    IntRegister(ulBase + 1, pfnHandler);
    IntEnable(ulBase + 1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TimerIntRegister>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <TimerIntNumberGet@plt>
  mov    %rax,%rbp
  test   %bl,%bl
  jne    L8
  and    $0xff,%bh
  jne    L1
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    %rax,%rdi
  mov    %r12,%rsi
  call   <IntRegister@plt>
  mov    %rbp,%rdi
  call   <IntEnable@plt>
  and    $0xff,%bh
  je     L21
L1:
  add    $0x1,%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <IntRegister@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <IntEnable@plt>
```

assistant: ```c
void TimerIntRegister(unsigned long ulBase, unsigned long ulTimer, void (*pfnHandler)(void)) {
  ;

  ;
  ulBase = TimerIntNumberGet(ulBase);
  if (ulTimer & 0x000000ff) {
    IntRegister(ulBase, pfnHandler);
    IntEnable(ulBase);
  }
  if (ulTimer & 0x0000ff00) {
    IntRegister(ulBase + 1, pfnHandler);
    IntEnable(ulBase + 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<TimerIntRegister>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <TimerIntNumberGet@plt>
  mov    %rax,%rbp
  test   %bl,%bl
  jne    L9
  and    $0xff,%bh
  jne    L29
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    %rax,%rdi
  mov    %r12,%rsi
  call   <IntRegister@plt>
  mov    %rbp,%rdi
  call   <IntEnable@plt>
  and    $0xff,%bh
  je     L24
L29:
  add    $0x1,%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <IntRegister@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <IntEnable@plt>
```

assistant: ```c
void TimerIntRegister(unsigned long ulBase, unsigned long ulTimer, void (*pfnHandler)(void)) {
  ;

  ;
  ulBase = TimerIntNumberGet(ulBase);
  if (ulTimer & 0x000000ff) {
    IntRegister(ulBase, pfnHandler);
    IntEnable(ulBase);
  }
  if (ulTimer & 0x0000ff00) {
    IntRegister(ulBase + 1, pfnHandler);
    IntEnable(ulBase + 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<st_strhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%rax
  mov    %esi,-0x14(%rbp)
  mov    $0x0,%ebx
  jmp    L0
L18:
  imul   $0x3e5,%ebx,%edx
  lea    (%r12,%rdx,1),%ebx
L0:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  movsbl %dl,%r12d
  test   %r12d,%r12d
  jne    L18
  mov    %ebx,%eax
  neg    %eax
  cmovs  %ebx,%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int st_strhash(string, modulus)
register char *string;
int modulus;
{
  register int val = 0;
  register int c;
  while ((c = *string++) != '\0') {
    val = val * 997 + c;
  }
  return ((val < 0) ? -val : val) % modulus;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<st_strhash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movsbl (%rdi),%eax
  test   %eax,%eax
  je     L13
  mov    $0x0,%edx
L5:
  imul   $0x3e5,%edx,%edx
  add    %eax,%edx
  add    $0x1,%rcx
  movsbl -0x1(%rcx),%eax
  test   %eax,%eax
  jne    L5
L20:
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
L13:
  mov    %eax,%edx
  jmp    L20
```

assistant: ```c
int st_strhash(string, modulus)
register char *string;
int modulus;
{
  register int val = 0;
  register int c;
  while ((c = *string++) != '\0') {
    val = val * 997 + c;
  }
  return ((val < 0) ? -val : val) % modulus;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<st_strhash>:
  endbr64
  movsbl (%rdi),%r8d
  lea    0x1(%rdi),%rax
  test   %r8d,%r8d
  je     L9
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L15:
  imul   $0x3e5,%ecx,%ecx
  add    $0x1,%rax
  add    %r8d,%ecx
  movsbl -0x1(%rax),%r8d
  test   %r8d,%r8d
  jne    L15
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%r8d
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int st_strhash(string, modulus)
register char *string;
int modulus;
{
  register int val = 0;
  register int c;
  while ((c = *string++) != '\0') {
    val = val * 997 + c;
  }
  return ((val < 0) ? -val : val) % modulus;
}
```
user: What is the c source code of the assembly code below?

```asm
<st_strhash>:
  endbr64
  movsbl (%rdi),%r8d
  lea    0x1(%rdi),%rax
  test   %r8d,%r8d
  je     L11
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L16:
  imul   $0x3e5,%ecx,%ecx
  add    $0x1,%rax
  add    %r8d,%ecx
  movsbl -0x1(%rax),%r8d
  test   %r8d,%r8d
  jne    L16
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%r8d
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int st_strhash(string, modulus)
register char *string;
int modulus;
{
  register int val = 0;
  register int c;
  while ((c = *string++) != '\0') {
    val = val * 997 + c;
  }
  return ((val < 0) ? -val : val) % modulus;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_next_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_next_non_space_char@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L36
L2:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
L36:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L17
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L17
  mov    -0x8(%rbp),%eax
  cltq
  mov    -0x28(%rbp),%rdx
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  jb     L2
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_next_token(FILE *fp, char *buf, size_t size) {
  int i = 0;
  int c = get_next_non_space_char(fp);
  while (c != EOF && !isspace(c) && i < size - 1) {
    buf[i++] = c;
    c = getc(fp);
  }
  buf[i] = 0;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_next_token>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r15
  mov    %rdx,%r14
  call   <get_next_non_space_char@plt>
  mov    %eax,%ebx
  mov    D13(%rip),%rax
  cmp    (%rax),%ebx
  je     L17
  sub    $0x1,%r14
  mov    $0x0,%ebp
L40:
  mov    %ebp,%r13d
  mov    %ebp,%r12d
  mov    %ebx,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L39
  cmp    %r14,%rbp
  je     L39
  lea    0x1(%r13),%r12d
  mov    %bl,(%r15,%rbp,1)
  mov    0x8(%rsp),%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  mov    D13(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L40
L39:
  movslq %r12d,%rax
  movb   $0x0,(%r15,%rax,1)
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    $0x0,%r12d
  jmp    L39
```

assistant: ```c
int get_next_token(FILE *fp, char *buf, size_t size) {
  int i = 0;
  int c = get_next_non_space_char(fp);
  while (c != EOF && !isspace(c) && i < size - 1) {
    buf[i++] = c;
    c = getc(fp);
  }
  buf[i] = 0;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_next_token>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <get_next_non_space_char@plt>
  mov    D4(%rip),%r15
  mov    %rbp,%rcx
  mov    %eax,%ebx
  lea    -0x1(%r13),%rax
  mov    %rax,0x8(%rsp)
  cmp    (%r15),%ebx
  je     L14
  xor    %r13d,%r13d
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L1:
  cmp    0x8(%rsp),%r13
  je     L14
  mov    %bl,0x0(%rbp,%r13,1)
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x1,%r13
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r15)
  je     L11
L0:
  mov    %ebx,%edi
  mov    %r13d,%r12d
  call   <isspace@plt>
  lea    0x0(%rbp,%r13,1),%rcx
  test   %eax,%eax
  je     L1
L14:
  movb   $0x0,(%rcx)
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movslq %r12d,%rcx
  add    %rbp,%rcx
  jmp    L14
```

assistant: ```c
int get_next_token(FILE *fp, char *buf, size_t size) {
  int i = 0;
  int c = get_next_non_space_char(fp);
  while (c != EOF && !isspace(c) && i < size - 1) {
    buf[i++] = c;
    c = getc(fp);
  }
  buf[i] = 0;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_next_token>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <get_next_non_space_char@plt>
  mov    D7(%rip),%r15
  mov    %rbp,%rcx
  mov    %eax,%ebx
  lea    -0x1(%r13),%rax
  mov    %rax,0x8(%rsp)
  cmp    (%r15),%ebx
  je     L47
  xor    %r13d,%r13d
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L53:
  cmp    0x8(%rsp),%r13
  je     L47
  mov    %bl,0x0(%rbp,%r13,1)
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x1,%r13
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r15)
  je     L13
L6:
  mov    %ebx,%edi
  mov    %r13d,%r12d
  call   <isspace@plt>
  lea    0x0(%rbp,%r13,1),%rcx
  test   %eax,%eax
  je     L53
L47:
  movb   $0x0,(%rcx)
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %r12d,%rcx
  add    %rbp,%rcx
  jmp    L47
```

assistant: ```c
int get_next_token(FILE *fp, char *buf, size_t size) {
  int i = 0;
  int c = get_next_non_space_char(fp);
  while (c != EOF && !isspace(c) && i < size - 1) {
    buf[i++] = c;
    c = getc(fp);
  }
  buf[i] = 0;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D38
type_infered: string
name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D34
type_infered: string
name: read_data
arguments: data_tag: D11
type_infered: string

tool: D38: char is %i


tool: D9: int is %i


tool: D34: pointer is %i


tool: D11: double is %i


assistant: ```c
int main(void) {
  printf("char is %i\n", sizeof(char));
  printf("int is %i\n", sizeof(int));
  printf("pointer is %i\n", sizeof(void *));
  printf("double is %i\n", sizeof(double));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D33
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string

tool: D11: char is %i


tool: D19: int is %i


tool: D33: pointer is %i


tool: D20: double is %i


assistant: ```c
int main(void) {
  printf("char is %i\n", sizeof(char));
  printf("int is %i\n", sizeof(int));
  printf("pointer is %i\n", sizeof(void *));
  printf("double is %i\n", sizeof(double));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D27
data_type: string
name: unpack_data
arguments: label: D30
data_type: string
name: unpack_data
arguments: label: D1
data_type: string
name: unpack_data
arguments: label: D8
data_type: string

tool: D27: char is %i


tool: D30: int is %i


tool: D1: pointer is %i


tool: D8: double is %i


assistant: ```c
int main(void) {
  printf("char is %i\n", sizeof(char));
  printf("int is %i\n", sizeof(int));
  printf("pointer is %i\n", sizeof(void *));
  printf("double is %i\n", sizeof(double));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string
name: extract_symbolic_data
arguments: data_tag: D22
type: string
name: extract_symbolic_data
arguments: data_tag: D32
type: string

tool: D4: char is %i


tool: D16: int is %i


tool: D22: pointer is %i


tool: D32: double is %i


assistant: ```c
int main(void) {
  printf("char is %i\n", sizeof(char));
  printf("int is %i\n", sizeof(int));
  printf("pointer is %i\n", sizeof(void *));
  printf("double is %i\n", sizeof(double));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<WatchdogIntClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  cltq
  movl   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void WatchdogIntClear(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = 0x00000001;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<WatchdogIntClear>:
  endbr64
  add    $0xc,%edi
  movslq %edi,%rdi
  movl   $0x1,(%rdi)
  ret
```

assistant: ```c
void WatchdogIntClear(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = 0x00000001;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<WatchdogIntClear>:
  endbr64
  add    $0xc,%edi
  movslq %edi,%rdi
  movl   $0x1,(%rdi)
  ret
```

assistant: ```c
void WatchdogIntClear(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = 0x00000001;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<WatchdogIntClear>:
  endbr64
  add    $0xc,%edi
  movslq %edi,%rdi
  movl   $0x1,(%rdi)
  ret
```

assistant: ```c
void WatchdogIntClear(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = 0x00000001;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bytecode_push>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L21
  cmpl   $0x4,-0x8(%rbp)
  jg     L21
  mov    $0x1,%eax
  jmp    L10
L21:
  mov    $0x0,%eax
L10:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%r9d
  mov    %edx,%r8d
  mov    %eax,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <_bytecode_write@plt>
  leave
  ret
```

assistant: ```c
uint32_t bytecode_push(uint8_t r0, uint8_t r1) {
  assert(r1 > 0 && r1 <= 4);
  return _bytecode_write(1, 0, 0, r0, r1, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bytecode_push>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  lea    -0x1(%rsi),%eax
  cmp    $0x3,%eax
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%r9d
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <_bytecode_write@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t bytecode_push(uint8_t r0, uint8_t r1) {
  assert(r1 > 0 && r1 <= 4);
  return _bytecode_write(1, 0, 0, r0, r1, 0);
}
```