user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  movq   $0x0,(%rsp)
  mov    %rax,0x8(%rsp)
L28:
  add    $0x1,%r14d
  lea    D74(%rip),%rdi
  xor    %eax,%eax
  xor    %r15d,%r15d
  mov    %r14d,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  mov    (%rsp),%rdx
  mov    %rax,%rbp
  lea    (%rax,%rdx,4),%rbx
L48:
  add    $0x1,%r15d
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %r15d,%esi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    $0x5,%r15d
  jne    L48
  addq   $0x5,(%rsp)
  cmp    $0x3,%r14d
  jne    L28
  lea    D26(%rip),%rdi
  lea    D54(%rip),%r12
  call   <puts@plt>
  mov    0x8(%rsp),%rbx
  lea    0x14(%rbx),%r13
L62:
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  cvtss2sd -0x4(%rbx),%xmm0
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L62
  lea    D87(%rip),%r12
  lea    D97(%rip),%rdi
  xor    %r14d,%r14d
  call   <puts@plt>
  mov    %r12,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x20(%rsp),%xmm0
  call   <printf@plt>
  mov    %r12,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x34(%rsp),%xmm0
  lea    D65(%rip),%r15
  call   <printf@plt>
  mov    %r12,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x48(%rsp),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D94(%rip),%r12
L45:
  add    $0x1,%r14d
  mov    %r15,%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  mov    %r14d,%esi
  call   <printf@plt>
L5:
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  cvtss2sd 0x0(%rbp,%rbx,4),%xmm0
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L5
  mov    %r13,%rbp
  cmp    $0x3,%r14d
  je     L2
  add    $0x14,%r13
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D74
data_type: string
name: disassemble_data
arguments: tag: D26
data_type: string
name: disassemble_data
arguments: tag: D54
data_type: string
name: disassemble_data
arguments: tag: D87
data_type: string
name: disassemble_data
arguments: tag: D97
data_type: string
name: disassemble_data
arguments: tag: D65
data_type: string
name: disassemble_data
arguments: tag: D34
data_type: string
name: disassemble_data
arguments: tag: D94
data_type: string

tool: D11: 
 Entre com nota %d: 

tool: D2: %f

tool: D74: 
 Digite as notas da AV%d

tool: D26: 
 Notas da AV1

tool: D54: %.2f - 

tool: D87: %f - 

tool: D97: 
 Notas do ultimo aluno

tool: D65: 
 AV%d : 

tool: D34: 
 As notas digitadas foram:
 

tool: D94:  %.2f - 

assistant: ```c
int main() {
  float nota[3][5];
  int i, j;
  for (i = 0; i <= 2; i++) {
    printf("\n Digite as notas da AV%d", i + 1);
    for (j = 0; j <= 4; j++) {
      printf("\n Entre com nota %d: ", j + 1);
      scanf("%f", &nota[i][j]);
    }
  }
  printf("\n Notas da AV1\n");
  for (j = 0; j <= 4; j++) {
    printf("%.2f - ", nota[0][j]);
  }
  printf("\n Notas do ultimo aluno\n");
  for (i = 0; i <= 2; i++) {
    printf("%f - ", nota[i][4]);
  }
  printf("\n As notas digitadas foram:\n ");
  for (i = 0; i <= 2; i++) {
    printf("\n AV%d : ", i + 1);
    for (j = 0; j <= 4; j++) {
      printf(" %.2f - ", nota[i][j]);
    }
  }
  return 0;
}
```