user: 请从给定的汇编指令推导出C源代码:

```asm
<strat_can_win>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L39:
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <board_get_position@plt>
  mov    $0x1,%esi
  mov    %ebx,%edi
  mov    %eax,%r15d
  call   <board_get_position@plt>
  xor    %esi,%esi
  mov    %ebx,%edi
  mov    %eax,%r14d
  call   <board_get_position@plt>
  mov    %r15d,%ecx
  mov    %r14d,%edx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <_strat_can_win_3@plt>
  cmp    $0xff,%al
  jne    L58
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <board_get_position@plt>
  mov    %ebx,%esi
  mov    $0x1,%edi
  mov    %eax,%r15d
  call   <board_get_position@plt>
  xor    %edi,%edi
  mov    %ebx,%esi
  mov    %eax,%r14d
  call   <board_get_position@plt>
  mov    %r15d,%ecx
  mov    %r14d,%edx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <_strat_can_win_3@plt>
  cmp    $0xff,%al
  jne    L27
  add    $0x1,%ebx
  cmp    $0x3,%ebx
  jne    L39
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <board_get_position@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    %eax,%r15d
  call   <board_get_position@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %eax,%r14d
  call   <board_get_position@plt>
  mov    %r15d,%ecx
  mov    %r14d,%edx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <_strat_can_win_3@plt>
  cmp    $0xffffffff,%eax
  je     L48
  mov    %al,0x0(%r13)
  mov    %al,(%r12)
  mov    $0x1,%eax
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x2,%esi
  xor    %edi,%edi
  call   <board_get_position@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    %eax,%r15d
  call   <board_get_position@plt>
  xor    %esi,%esi
  mov    $0x2,%edi
  mov    %eax,%r14d
  call   <board_get_position@plt>
  mov    %r14d,%edx
  mov    %r15d,%ecx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <_strat_can_win_3@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  cmp    $0xffffffff,%edx
  je     L29
  mov    $0x2,%eax
  sub    %edx,%eax
  mov    %al,0x0(%r13)
  mov    $0x1,%eax
  mov    %dl,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L58:
  mov    %bl,0x0(%r13)
  mov    %al,(%r12)
  mov    $0x1,%eax
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %al,0x0(%r13)
  mov    $0x1,%eax
  mov    %bl,(%r12)
  jmp    L29
```

assistant: ```c
char strat_can_win(const char pid, char *row, char *col) {
  char r;
  char c;
  int i;
  for (i = 0; i < 3; i++) {
    c = _strat_can_win_3(pid, board_get_position(i, 0), board_get_position(i, 1), board_get_position(i, 2));
    if (c != -1) {
      *row = i;
      *col = c;
      return 1;
    }
    r = _strat_can_win_3(pid, board_get_position(0, i), board_get_position(1, i), board_get_position(2, i));
    if (r != -1) {
      *row = r;
      *col = i;
      return 1;
    }
  }
  i = _strat_can_win_3(pid, board_get_position(0, 0), board_get_position(1, 1), board_get_position(2, 2));
  if (i != -1) {
    *row = i;
    *col = i;
    return 1;
  }
  i = _strat_can_win_3(pid, board_get_position(2, 0), board_get_position(1, 1), board_get_position(0, 2));
  if (i != -1) {
    *row = 2 - i;
    *col = i;
    return 1;
  }
  return 0;
}
```