ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  shl    $0x7,%rax
  movabs $0x1b4334b500,%rdx
  and    %rdx,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rcx
  test   %rcx,%rcx
  je     L41
  mov    %rsp,%rax
  mov    $0x0,%edx
  jmp    L37
L27:
  movzbl (%rax),%esi
  movzbl 0x7(%rax),%edi
  mov    %dil,(%rax)
  mov    %sil,0x7(%rax)
  movzbl 0x2(%rax),%esi
  movzbl 0x4(%rax),%edi
  mov    %dil,0x2(%rax)
  mov    %sil,0x4(%rax)
L35:
  add    $0x1,%rdx
  add    $0x8,%rax
  cmp    %rcx,%rdx
  je     L41
L37:
  cmp    %rdx,(%rsp)
  jbe    L27
  movzwl 0x6(%rsp),%esi
  movzwl 0x2(%rsp),%edi
  mov    %di,0x6(%rsp)
  mov    %si,0x2(%rsp)
  jmp    L35
L41:
  mov    (%rsp),%rax
  shr    $0x7,%rax
  or     $0x7e4cac,%rax
  mov    %rax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned short copy12;
  char copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
          *((unsigned short *)(&state[local1]) + 2) = copy12;
        }
      } else if (state[0UL] <= local1) {
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy13;
        copy13 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 4);
        *((char *)(&state[local1]) + 4) = copy13;
      } else {
        copy14 = *((char *)(&state[local1]) + 6);
        *((char *)(&state[local1]) + 6) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy14;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 1059477100UL) >> 7UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%rcx
  mov    %rsi,%r8
  mov    0x8(%rdi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x1b4334b500,%rax
  shl    $0x7,%rcx
  and    %rax,%rcx
  mov    %rcx,(%rsp)
  test   %rsi,%rsi
  je     L56
  mov    %rsp,%rax
  xor    %edx,%edx
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L59:
  movzwl 0x6(%rsp),%ecx
  movzwl 0x2(%rsp),%edi
  mov    %cx,0x2(%rsp)
  mov    %di,0x6(%rsp)
L27:
  add    $0x1,%rdx
  mov    (%rsp),%rcx
  add    $0x8,%rax
  cmp    %rsi,%rdx
  je     L56
L41:
  cmp    %rcx,%rdx
  jb     L59
  movzbl (%rax),%ecx
  movzbl 0x7(%rax),%edi
  mov    %cl,0x7(%rax)
  movzbl 0x2(%rax),%ecx
  mov    %dil,(%rax)
  movzbl 0x4(%rax),%edi
  mov    %cl,0x4(%rax)
  mov    %dil,0x2(%rax)
  jmp    L27
L56:
  shr    $0x7,%rcx
  or     $0x7e4cac,%rcx
  mov    %rcx,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned short copy12;
  char copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
          *((unsigned short *)(&state[local1]) + 2) = copy12;
        }
      } else if (state[0UL] <= local1) {
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy13;
        copy13 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 4);
        *((char *)(&state[local1]) + 4) = copy13;
      } else {
        copy14 = *((char *)(&state[local1]) + 6);
        *((char *)(&state[local1]) + 6) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy14;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 1059477100UL) >> 7UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%rcx
  mov    %rsi,%r8
  mov    0x8(%rdi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x1b4334b500,%rax
  shl    $0x7,%rcx
  and    %rax,%rcx
  mov    %rcx,(%rsp)
  test   %rsi,%rsi
  je     L30
  mov    %rsp,%rax
  xor    %edx,%edx
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L21:
  movzwl 0x6(%rsp),%ecx
  movzwl 0x2(%rsp),%edi
  mov    %cx,0x2(%rsp)
  mov    %di,0x6(%rsp)
L8:
  add    $0x1,%rdx
  mov    (%rsp),%rcx
  add    $0x8,%rax
  cmp    %rsi,%rdx
  je     L30
L39:
  cmp    %rcx,%rdx
  jb     L21
  movzbl (%rax),%ecx
  movzbl 0x7(%rax),%edi
  mov    %cl,0x7(%rax)
  movzbl 0x2(%rax),%ecx
  mov    %dil,(%rax)
  movzbl 0x4(%rax),%edi
  mov    %cl,0x4(%rax)
  mov    %dil,0x2(%rax)
  jmp    L8
L30:
  shr    $0x7,%rcx
  or     $0x7e4cac,%rcx
  mov    %rcx,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned short copy12;
  char copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
          *((unsigned short *)(&state[local1]) + 2) = copy12;
        }
      } else if (state[0UL] <= local1) {
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy13;
        copy13 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 4);
        *((char *)(&state[local1]) + 4) = copy13;
      } else {
        copy14 = *((char *)(&state[local1]) + 6);
        *((char *)(&state[local1]) + 6) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy14;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 1059477100UL) >> 7UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fix_mpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x4(%rbp)
  mov    %ax,-0x8(%rbp)
  movswq -0x4(%rbp),%rdx
  movswq -0x8(%rbp),%rax
  imul   %rdx,%rax
  sar    $0xf,%rax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short fix_mpy(short a, short b) {
  a = ((long)(a) * (long)(b)) >> 15;
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fix_mpy>:
  endbr64
  movswq %di,%rdi
  movswq %si,%rsi
  imul   %rsi,%rdi
  mov    %rdi,%rax
  sar    $0xf,%rax
  ret
```

assistant: ```c
short fix_mpy(short a, short b) {
  a = ((long)(a) * (long)(b)) >> 15;
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<fix_mpy>:
  endbr64
  movswq %si,%rsi
  movswq %di,%rdi
  imul   %rsi,%rdi
  mov    %rdi,%rax
  sar    $0xf,%rax
  ret
```

assistant: ```c
short fix_mpy(short a, short b) {
  a = ((long)(a) * (long)(b)) >> 15;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fix_mpy>:
  endbr64
  movswq %si,%rsi
  movswq %di,%rdi
  imul   %rsi,%rdi
  mov    %rdi,%rax
  sar    $0xf,%rax
  ret
```

assistant: ```c
short fix_mpy(short a, short b) {
  a = ((long)(a) * (long)(b)) >> 15;
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L21
  mov    $0x0,%eax
  jmp    L35
L21:
  addq   $0x8,-0x10(%rbp)
  subl   $0x1,-0x4(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ft_str_sort@plt>
  jmp    L5
L13:
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%rax
  mov    %eax,%edi
  call   <ft_putline@plt>
L5:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L13
  mov    $0x0,%eax
L35:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2)
    return (0);
  ft_str_sort(--argc, ++argv);
  while (argc--)
    ft_putline(*argv++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    0x8(%rsi),%rbx
  lea    -0x1(%rdi),%edi
  mov    %rbx,%rsi
  call   <ft_str_sort@plt>
  mov    %ebp,%ebp
  lea    (%r12,%rbp,8),%rbp
L11:
  add    $0x8,%rbx
  mov    -0x8(%rbx),%edi
  call   <ft_putline@plt>
  cmp    %rbp,%rbx
  jne    L11
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2)
    return (0);
  ft_str_sort(--argc, ++argv);
  while (argc--)
    ft_putline(*argv++);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  cmp    $0x1,%ebp
  jle    L13
  lea    0x8(%rsi),%rbx
  mov    %rsi,%r12
  lea    -0x1(%rbp),%edi
  mov    %rbx,%rsi
  lea    (%r12,%rbp,8),%rbp
  call   <ft_str_sort@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%edi
  add    $0x8,%rbx
  call   <ft_putline@plt>
  cmp    %rbp,%rbx
  jne    L8
L13:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2)
    return (0);
  ft_str_sort(--argc, ++argv);
  while (argc--)
    ft_putline(*argv++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  cmp    $0x1,%ebp
  jle    L4
  lea    0x8(%rsi),%rbx
  mov    %rsi,%r12
  lea    -0x1(%rbp),%edi
  mov    %rbx,%rsi
  lea    (%r12,%rbp,8),%rbp
  call   <ft_str_sort@plt>
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%edi
  add    $0x8,%rbx
  call   <ft_putline@plt>
  cmp    %rbx,%rbp
  jne    L11
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2)
    return (0);
  ft_str_sort(--argc, ++argv);
  while (argc--)
    ft_putline(*argv++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    0x10(%rbp),%rcx
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f9(void *a, int b, long long c, long long d, long long e, char *f, int *g) {
  asm volatile("" : : "r"(a), "r"(b), "r"(c), "r"(d) : "memory");
  asm volatile("" : : "r"(e), "r"(f), "r"(g) : "memory");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f9>:
  endbr64
  mov    0x8(%rsp),%rax
  mov    $0x0,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f9(void *a, int b, long long c, long long d, long long e, char *f, int *g) {
  asm volatile("" : : "r"(a), "r"(b), "r"(c), "r"(d) : "memory");
  asm volatile("" : : "r"(e), "r"(f), "r"(g) : "memory");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f9>:
  endbr64
  mov    0x8(%rsp),%rax
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f9(void *a, int b, long long c, long long d, long long e, char *f, int *g) {
  asm volatile("" : : "r"(a), "r"(b), "r"(c), "r"(d) : "memory");
  asm volatile("" : : "r"(e), "r"(f), "r"(g) : "memory");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f9>:
  endbr64
  mov    0x8(%rsp),%rax
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f9(void *a, int b, long long c, long long d, long long e, char *f, int *g) {
  asm volatile("" : : "r"(a), "r"(b), "r"(c), "r"(d) : "memory");
  asm volatile("" : : "r"(e), "r"(f), "r"(g) : "memory");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dna_update_only_a>:
  endbr64
  mov    $0x54,%eax
L109:
  movss  (%rdi,%rax,1),%xmm0
  movss  %xmm0,(%rdx,%rax,1)
  sub    $0x4,%rax
  cmp    $0xfffffffffffffffc,%rax
  jne    L109
  lea    0x58(%rdi),%rsi
  lea    0x58(%rdx),%rax
  lea    0x4(%rcx),%r8
  mov    0x4(%rcx),%r9d
  cmp    $0x3,%r9d
  je     L63
  lea    0x54(%rdx),%rdi
  movss  D2(%rip),%xmm1
  jmp    L103
L0:
  mov    $0x54,%edx
L89:
  movss  (%rsi,%rdx,1),%xmm0
  movss  %xmm0,(%rax,%rdx,1)
  sub    $0x4,%rdx
  cmp    $0xfffffffffffffffc,%rdx
  jne    L89
  add    $0x58,%rsi
  jmp    L46
L128:
  lea    0x54(%rax),%rdx
L71:
  movl   $0x0,(%rdx)
  sub    $0x4,%rdx
  cmp    %rdx,%rdi
  jne    L71
  movss  %xmm1,0x14(%rax)
  movss  %xmm1,0x18(%rax)
  movss  %xmm1,0x1c(%rax)
  jmp    L1
L76:
  add    $0x58,%rsi
L20:
  add    $0x58,%rax
  add    $0x4,%r8
  mov    (%r8),%r9d
  add    $0x58,%rdi
  cmp    $0x3,%r9d
  je     L63
L103:
  test   %r9d,%r9d
  je     L0
L46:
  testb  $0x1,(%r8)
  jne    L128
L1:
  testb  $0x2,(%r8)
  je     L20
  mov    $0x54,%edx
L11:
  movss  (%rsi,%rdx,1),%xmm0
  movss  %xmm0,(%rax,%rdx,1)
  sub    $0x4,%rdx
  cmp    $0xfffffffffffffffc,%rdx
  jne    L11
  jmp    L76
L63:
  mov    $0x54,%edx
L79:
  movss  (%rsi,%rdx,1),%xmm0
  movss  %xmm0,(%rax,%rdx,1)
  sub    $0x4,%rdx
  cmp    $0xfffffffffffffffc,%rdx
  jne    L79
  mov    (%rcx),%edx
  add    $0x1,%edx
  imul   $0x16,%edx,%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  sub    %rdx,%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: byte[4]

tool: {"D2": [0x00,0x24,0x74,0x49]}

assistant: ```c
float *dna_update_only_a(const float *profa, const float *profb, float *newp, int *path, int sipa, int sipb) {
  int i, c;
  for (i = 22; i--;) {
    newp[i] = profa[i];
  }
  profa += 22;
  profb += 22;
  newp += 22;
  c = 1;
  while (path[c] != 3) {
    if (!path[c]) {
      for (i = 22; i--;) {
        newp[i] = profa[i];
      }
      profa += 22;
      profb += 22;
    }
    if (path[c] & 1) {
      for (i = 22; i--;) {
        newp[i] = 0.0f;
      }
      profb += 22;
      newp[5] = 1000000;
      newp[6] = 1000000;
      newp[7] = 1000000;
    }
    if (path[c] & 2) {
      for (i = 22; i--;) {
        newp[i] = profa[i];
      }
      profa += 22;
    }
    newp += 22;
    c++;
  }
  for (i = 22; i--;) {
    newp[i] = profa[i];
  }
  newp -= (path[0] + 1) * 22;
  return newp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dna_update_only_a>:
  endbr64
  mov    %rcx,%r10
  mov    $0x54,%ecx
  nopl   0x0(%rax)
L46:
  movss  (%rdi,%rcx,1),%xmm0
  movss  %xmm0,(%rdx,%rcx,1)
  sub    $0x4,%rcx
  cmp    $0xfffffffffffffffc,%rcx
  jne    L46
  lea    0x58(%rdx),%rsi
  mov    0x4(%r10),%edx
  lea    0x58(%rdi),%r8
  cmp    $0x3,%edx
  je     L17
  movss  D4(%rip),%xmm1
  lea    0x8(%r10),%r9
  xor    %eax,%eax
  jmp    L61
  nopl   0x0(%rax)
L28:
  test   $0x1,%dl
  je     L26
  lea    0x8(%rsi),%rdi
  mov    %rsi,%rcx
  movq   $0x0,(%rsi)
  and    $0xfffffffffffffff8,%rdi
  movq   $0x0,0x50(%rsi)
  sub    %rdi,%rcx
  add    $0x58,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  movss  %xmm1,0x14(%rsi)
  movss  %xmm1,0x18(%rsi)
  movss  %xmm1,0x1c(%rsi)
L26:
  and    $0x2,%edx
  jne    L117
L115:
  mov    (%r9),%edx
  add    $0x4,%r9
  add    $0x58,%rsi
  cmp    $0x3,%edx
  je     L17
L61:
  test   %edx,%edx
  jne    L28
  mov    $0x54,%edx
  nopl   0x0(%rax,%rax,1)
L62:
  movss  (%r8,%rdx,1),%xmm0
  movss  %xmm0,(%rsi,%rdx,1)
  sub    $0x4,%rdx
  cmp    $0xfffffffffffffffc,%rdx
  jne    L62
  add    $0x58,%r8
  jmp    L115
  nopl   0x0(%rax,%rax,1)
L117:
  mov    $0x54,%edx
  nopl   (%rax)
L55:
  movss  (%r8,%rdx,1),%xmm0
  movss  %xmm0,(%rsi,%rdx,1)
  sub    $0x4,%rdx
  cmp    $0xfffffffffffffffc,%rdx
  jne    L55
  add    $0x58,%r8
  jmp    L115
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x54,%eax
  nopl   (%rax)
L43:
  movss  (%r8,%rax,1),%xmm0
  movss  %xmm0,(%rsi,%rax,1)
  sub    $0x4,%rax
  cmp    $0xfffffffffffffffc,%rax
  jne    L43
  mov    (%r10),%edx
  mov    %rsi,%rax
  add    $0x1,%edx
  imul   $0x16,%edx,%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  sub    %rdx,%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: byte[4]

tool: {"D4": [0x00,0x24,0x74,0x49]}

assistant: ```c
float *dna_update_only_a(const float *profa, const float *profb, float *newp, int *path, int sipa, int sipb) {
  int i, c;
  for (i = 22; i--;) {
    newp[i] = profa[i];
  }
  profa += 22;
  profb += 22;
  newp += 22;
  c = 1;
  while (path[c] != 3) {
    if (!path[c]) {
      for (i = 22; i--;) {
        newp[i] = profa[i];
      }
      profa += 22;
      profb += 22;
    }
    if (path[c] & 1) {
      for (i = 22; i--;) {
        newp[i] = 0.0f;
      }
      profb += 22;
      newp[5] = 1000000;
      newp[6] = 1000000;
      newp[7] = 1000000;
    }
    if (path[c] & 2) {
      for (i = 22; i--;) {
        newp[i] = profa[i];
      }
      profa += 22;
    }
    newp += 22;
    c++;
  }
  for (i = 22; i--;) {
    newp[i] = profa[i];
  }
  newp -= (path[0] + 1) * 22;
  return newp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<oom_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L1
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L18
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: oom_malloc(): returning NULL at %s:%d


assistant: ```c
void *oom_malloc(char *file, int line, size_t size) {
  if ((rand() % 20) == 0) {
    printf("oom_malloc(): returning NULL at %s:%d\n", file, line);
    return NULL;
  }
  return malloc(size);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<oom_malloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  cmp    %edx,%eax
  je     L13
  mov    %rbx,%rdi
  call   <malloc@plt>
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L8
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: oom_malloc(): returning NULL at %s:%d


assistant: ```c
void *oom_malloc(char *file, int line, size_t size) {
  if ((rand() % 20) == 0) {
    printf("oom_malloc(): returning NULL at %s:%d\n", file, line);
    return NULL;
  }
  return malloc(size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<oom_malloc>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <rand@plt>
  imul   $0xcccccccd,%eax,%eax
  add    $0x19999998,%eax
  ror    $0x2,%eax
  cmp    $0xccccccc,%eax
  jbe    L5
  pop    %rbp
  mov    %r13,%rdi
  pop    %r12
  pop    %r13
  jmp    1080 <malloc@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: oom_malloc(): returning NULL at %s:%d


assistant: ```c
void *oom_malloc(char *file, int line, size_t size) {
  if ((rand() % 20) == 0) {
    printf("oom_malloc(): returning NULL at %s:%d\n", file, line);
    return NULL;
  }
  return malloc(size);
}
```
user: What is the c source code of the assembly code below:

```asm
<oom_malloc>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <rand@plt>
  imul   $0xcccccccd,%eax,%eax
  add    $0x19999998,%eax
  ror    $0x2,%eax
  cmp    $0xccccccc,%eax
  jbe    L5
  pop    %rbp
  mov    %r13,%rdi
  pop    %r12
  pop    %r13
  jmp    1080 <malloc@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: oom_malloc(): returning NULL at %s:%d


assistant: ```c
void *oom_malloc(char *file, int line, size_t size) {
  if ((rand() % 20) == 0) {
    printf("oom_malloc(): returning NULL at %s:%d\n", file, line);
    return NULL;
  }
  return malloc(size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitmap_and>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L5
  cmpl   $0x40,-0x1c(%rbp)
  jg     L5
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  and    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L19
L5:
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__bitmap_and@plt>
L19:
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 64))
    return (*dst = *src1 & *src2) != 0;
  return __bitmap_and(dst, src1, src2, nbits);
}
```