ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<densearray_kernel_elem_postreduce_cm4_f32>:
  endbr64
  mov    %rdx,%r8
  mov    %rcx,%rdx
  test   %rsi,%rsi
  js     L12
  pxor   %xmm0,%xmm0
  cvtsi2ss %rsi,%xmm0
L30:
  movaps %xmm0,%xmm4
  subss  D14(%rip),%xmm4
  movaps %xmm0,%xmm3
  mulss  D16(%rip),%xmm3
  subss  D9(%rip),%xmm3
  movaps %xmm0,%xmm2
  mulss  %xmm0,%xmm2
  movss  D4(%rip),%xmm1
  movaps %xmm0,%xmm5
  mulss  %xmm1,%xmm5
  subss  %xmm5,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm4,%xmm1
  mulss  %xmm4,%xmm1
  mulss  %xmm4,%xmm1
  mulss  %xmm1,%xmm2
  movaps %xmm4,%xmm1
  mulss  %xmm0,%xmm1
  mulss  %xmm4,%xmm1
  addss  %xmm3,%xmm1
  mulss  %xmm0,%xmm1
  divss  %xmm2,%xmm1
  mulss  %xmm0,%xmm3
  divss  %xmm2,%xmm3
  test   %rdi,%rdi
  je     L22
  mov    $0x0,%eax
L16:
  movaps %xmm1,%xmm0
  mulss  (%rdx,%rax,4),%xmm0
  movaps %xmm3,%xmm2
  mulss  (%r8,%rax,4),%xmm2
  addss  %xmm2,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L16
L22:
  ret
L12:
  mov    %rsi,%rax
  shr    %rax
  and    $0x1,%esi
  or     %rsi,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm0
  jmp    L30
```

tool_calls: name: parse_data
arguments: tag: D14
datatype: byte[4]
name: parse_data
arguments: tag: D16
datatype: byte[4]
name: parse_data
arguments: tag: D9
datatype: byte[4]
name: parse_data
arguments: tag: D4
datatype: byte[4]

tool: {"D14": [0x00,0x00,0x80,0x3f]}

tool: {"D16": [0x00,0x00,0xc0,0x40]}

tool: {"D9": [0x00,0x00,0x10,0x41]}

tool: {"D4": [0x00,0x00,0x40,0x40]}

assistant: ```c
void densearray_kernel_elem_postreduce_cm4_f32(size_t dim, size_t count, const float *uvar, float *ucm4) {
  float n = (float)(count);
  float scale4 = (n * (n * (n - 1.0f) * (n - 1.0f) + (6.0f * n - 9.0f))) / ((n - 1.0f) * (n - 1.0f) * (n - 1.0f) * (n * n - 3.0f * n + 3.0f));
  float scale2 = (n * (6.0f * n - 9.0f)) / ((n - 1.0f) * (n - 1.0f) * (n - 1.0f) * (n * n - 3.0f * n + 3.0f));
  for (size_t idx = 0; idx < dim; idx++) {
    ucm4[idx] = scale4 * ucm4[idx] + scale2 * uvar[idx];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<densearray_kernel_elem_postreduce_cm4_f32>:
  endbr64
  mov    %rdx,%r8
  mov    %rcx,%rdx
  test   %rsi,%rsi
  js     L6
  pxor   %xmm0,%xmm0
  cvtsi2ss %rsi,%xmm0
L13:
  movss  D2(%rip),%xmm1
  movaps %xmm0,%xmm2
  movaps %xmm0,%xmm5
  movaps %xmm0,%xmm4
  mulss  %xmm0,%xmm2
  subss  D13(%rip),%xmm4
  movss  D33(%rip),%xmm3
  mulss  %xmm1,%xmm5
  mulss  %xmm0,%xmm3
  subss  D35(%rip),%xmm3
  subss  %xmm5,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm4,%xmm1
  mulss  %xmm4,%xmm1
  mulss  %xmm4,%xmm1
  mulss  %xmm1,%xmm2
  movaps %xmm4,%xmm1
  mulss  %xmm0,%xmm1
  mulss  %xmm4,%xmm1
  addss  %xmm3,%xmm1
  mulss  %xmm0,%xmm3
  mulss  %xmm0,%xmm1
  divss  %xmm2,%xmm3
  divss  %xmm2,%xmm1
  test   %rdi,%rdi
  je     L26
  xor    %eax,%eax
  xchg   %ax,%ax
L18:
  movss  (%rdx,%rax,4),%xmm0
  movss  (%r8,%rax,4),%xmm2
  mulss  %xmm1,%xmm0
  mulss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L18
L26:
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rsi,%rax
  and    $0x1,%esi
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rsi,%rax
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm0
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: byte[4]
name: unpack_data
arguments: data_tag: D13
data_type: byte[4]
name: unpack_data
arguments: data_tag: D33
data_type: byte[4]
name: unpack_data
arguments: data_tag: D35
data_type: byte[4]

tool: {"D2": [0x00,0x00,0x40,0x40]}

tool: {"D13": [0x00,0x00,0x80,0x3f]}

tool: {"D33": [0x00,0x00,0xc0,0x40]}

tool: {"D35": [0x00,0x00,0x10,0x41]}

assistant: ```c
void densearray_kernel_elem_postreduce_cm4_f32(size_t dim, size_t count, const float *uvar, float *ucm4) {
  float n = (float)(count);
  float scale4 = (n * (n * (n - 1.0f) * (n - 1.0f) + (6.0f * n - 9.0f))) / ((n - 1.0f) * (n - 1.0f) * (n - 1.0f) * (n * n - 3.0f * n + 3.0f));
  float scale2 = (n * (6.0f * n - 9.0f)) / ((n - 1.0f) * (n - 1.0f) * (n - 1.0f) * (n * n - 3.0f * n + 3.0f));
  for (size_t idx = 0; idx < dim; idx++) {
    ucm4[idx] = scale4 * ucm4[idx] + scale2 * uvar[idx];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <other@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D11
type_infered: string

tool: D3: Main.h message: %d

tool: D19: other.h message: %d

tool: D11: Main message: %d

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Main.h message: %d", 0);
  printf("other.h message: %d", 1);
  printf("Main message: %d", 2);
  other();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <other@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D24
type: string
name: read_data
arguments: label: D27
type: string
name: read_data
arguments: label: D1
type: string

tool: D24: Main.h message: %d

tool: D27: other.h message: %d

tool: D1: Main message: %d

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Main.h message: %d", 0);
  printf("other.h message: %d", 1);
  printf("Main message: %d", 2);
  other();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <other@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D15
datatype: string
name: disassemble_data
arguments: data_tag: D23
datatype: string

tool: D12: Main.h message: %d

tool: D15: other.h message: %d

tool: D23: Main message: %d

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Main.h message: %d", 0);
  printf("other.h message: %d", 1);
  printf("Main message: %d", 2);
  other();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <other@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D16
data_type: string
name: disassemble_data
arguments: data_label: D18
data_type: string

tool: D3: Main.h message: %d

tool: D16: other.h message: %d

tool: D18: Main message: %d

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Main.h message: %d", 0);
  printf("other.h message: %d", 1);
  printf("Main message: %d", 2);
  other();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<xor_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L26
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <xor_string_len@plt>
  jmp    L19
L33:
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <xor_string_len@plt>
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L33
  cmpl   $0x0,-0x1c(%rbp)
  jle    L19
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <xor_string_len@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
void xor_string(unsigned char *res, const unsigned char *s0, const unsigned char *s1, int s0_len, int s1_len) {
  if (s0_len <= s1_len)
    xor_string_len(res, s0, s1, s0_len);
  else {
    while (s0_len >= s1_len) {
      xor_string_len(res, s0, s1, s1_len);
      s0 += s1_len;
      res += s1_len;
      s0_len -= s1_len;
    }
    if (s0_len > 0)
      xor_string_len(res, s0, s1, s0_len);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xor_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %ecx,%ebx
  mov    %r8d,%ebp
  movslq %r8d,%r15
  cmp    %r8d,%ecx
  jle    L25
L39:
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <xor_string_len@plt>
  add    %r15,%r13
  add    %r15,%r12
  sub    %ebp,%ebx
  cmp    %ebx,%ebp
  jle    L39
  test   %ebx,%ebx
  jg     L27
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <xor_string_len@plt>
  jmp    L20
L27:
  mov    %ebx,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <xor_string_len@plt>
  jmp    L20
```

assistant: ```c
void xor_string(unsigned char *res, const unsigned char *s0, const unsigned char *s1, int s0_len, int s1_len) {
  if (s0_len <= s1_len)
    xor_string_len(res, s0, s1, s0_len);
  else {
    while (s0_len >= s1_len) {
      xor_string_len(res, s0, s1, s1_len);
      s0 += s1_len;
      res += s1_len;
      s0_len -= s1_len;
    }
    if (s0_len > 0)
      xor_string_len(res, s0, s1, s0_len);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xor_string>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  movslq %r8d,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r14,%rbx
  sub    $0x8,%rsp
  cmp    %r14d,%ecx
  jle    L9
  nopl   0x0(%rax)
L20:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %ebx,%ecx
  mov    %r15,%rdx
  call   <xor_string_len@plt>
  sub    %ebx,%r12d
  add    %r14,%r13
  add    %r14,%rbp
  cmp    %r12d,%ebx
  jle    L20
  test   %r12d,%r12d
  jg     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %r15,%rdx
  mov    %r13,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <xor_string_len@plt>
```

assistant: ```c
void xor_string(unsigned char *res, const unsigned char *s0, const unsigned char *s1, int s0_len, int s1_len) {
  if (s0_len <= s1_len)
    xor_string_len(res, s0, s1, s0_len);
  else {
    while (s0_len >= s1_len) {
      xor_string_len(res, s0, s1, s1_len);
      s0 += s1_len;
      res += s1_len;
      s0_len -= s1_len;
    }
    if (s0_len > 0)
      xor_string_len(res, s0, s1, s0_len);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xor_string>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  movslq %r8d,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r14,%rbx
  sub    $0x8,%rsp
  cmp    %r14d,%ecx
  jle    L27
  nopl   0x0(%rax)
L22:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %ebx,%ecx
  mov    %r15,%rdx
  call   <xor_string_len@plt>
  sub    %ebx,%r12d
  add    %r14,%r13
  add    %r14,%rbp
  cmp    %r12d,%ebx
  jle    L22
  test   %r12d,%r12d
  jg     L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %r15,%rdx
  mov    %r13,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <xor_string_len@plt>
```

assistant: ```c
void xor_string(unsigned char *res, const unsigned char *s0, const unsigned char *s1, int s0_len, int s1_len) {
  if (s0_len <= s1_len)
    xor_string_len(res, s0, s1, s0_len);
  else {
    while (s0_len >= s1_len) {
      xor_string_len(res, s0, s1, s1_len);
      s0 += s1_len;
      res += s1_len;
      s0_len -= s1_len;
    }
    if (s0_len > 0)
      xor_string_len(res, s0, s1, s0_len);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xb4(%rbp)
  lea    -0xb8(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L15
L28:
  lea    -0xb8(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L15:
  mov    -0xb8(%rbp),%eax
  cmp    $0x14,%eax
  jg     L28
  mov    -0xb8(%rbp),%eax
  test   %eax,%eax
  js     L28
  jmp    L41
L22:
  lea    -0xb0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xb4(%rbp)
L41:
  mov    -0xb8(%rbp),%eax
  cmp    %eax,-0xb4(%rbp)
  jne    L22
  mov    -0xb8(%rbp),%edx
  lea    -0x60(%rbp),%rcx
  lea    -0xb0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <next_generation@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D27
type_infered: string

tool: D27: %d

assistant: ```c
int main() {
  int length, current[20], next[20], count = 0;
  scanf("%d", &length);
  while (length > 20 || length < 0)
    scanf("%d", &length);
  while (count != length) {
    scanf("%d", &current[count]);
    count++;
  }
  next_generation(current, next, length);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x14,0xc(%rsp)
  jbe    L23
  lea    D23(%rip),%rbx
L40:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x14,0xc(%rsp)
  ja     L40
L23:
  mov    0xc(%rsp),%ebx
  test   %ebx,%ebx
  je     L7
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D23(%rip),%r12
L2:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jne    L2
L7:
  lea    0x60(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %ebx,%edx
  call   <next_generation@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D23
data_type: string

tool: D23: %d

assistant: ```c
int main() {
  int length, current[20], next[20], count = 0;
  scanf("%d", &length);
  while (length > 20 || length < 0)
    scanf("%d", &length);
  while (count != length) {
    scanf("%d", &current[count]);
    count++;
  }
  next_generation(current, next, length);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  jmp    L29
  nopl   (%rax)
L16:
  mov    %rbx,%rsi
L29:
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r12d
  cmp    $0x14,%r12d
  ja     L16
  lea    0x10(%rsp),%r13
  test   %r12d,%r12d
  je     L5
  mov    %r13,%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L40:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12d,0xc(%rsp)
  jne    L40
L5:
  lea    0x60(%rsp),%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <next_generation@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  int length, current[20], next[20], count = 0;
  scanf("%d", &length);
  while (length > 20 || length < 0)
    scanf("%d", &length);
  while (count != length) {
    scanf("%d", &current[count]);
    count++;
  }
  next_generation(current, next, length);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  jmp    L15
  nopl   (%rax)
L3:
  mov    %rbx,%rsi
L15:
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r12d
  cmp    $0x14,%r12d
  ja     L3
  lea    0x10(%rsp),%r13
  test   %r12d,%r12d
  je     L46
  mov    %r13,%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L24:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12d,0xc(%rsp)
  jne    L24
L46:
  lea    0x60(%rsp),%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <next_generation@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: %d

assistant: ```c
int main() {
  int length, current[20], next[20], count = 0;
  scanf("%d", &length);
  while (length > 20 || length < 0)
    scanf("%d", &length);
  while (count != length) {
    scanf("%d", &current[count]);
    count++;
  }
  next_generation(current, next, length);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pnx833x_gpio_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x1f,-0x8(%rbp)
  ja     L6
  cmpl   $0x0,-0x4(%rbp)
  je     L51
  mov    $0xb7e0f004,%eax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  movslq %eax,%rdx
  mov    $0xb7e0f004,%eax
  or     %rsi,%rdx
  mov    %rdx,(%rax)
  jmp    L25
L51:
  mov    $0xb7e0f004,%eax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  movslq %eax,%rdx
  mov    $0xb7e0f004,%eax
  and    %rsi,%rdx
  mov    %rdx,(%rax)
  jmp    L25
L6:
  cmpl   $0x0,-0x4(%rbp)
  je     L28
  mov    $0xb7e0f060,%eax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  movslq %eax,%rdx
  mov    $0xb7e0f060,%eax
  or     %rsi,%rdx
  mov    %rdx,(%rax)
  jmp    L25
L28:
  mov    $0xb7e0f060,%eax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  movslq %eax,%rdx
  mov    $0xb7e0f060,%eax
  and    %rsi,%rdx
  mov    %rdx,(%rax)
L25:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pnx833x_gpio_write(unsigned int val, unsigned int pin) {
  if (pin < 32) {
    if (val)
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF004))) |= (1 << (pin)));
      } while (0);
    else
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF004))) &= ~(1 << (pin)));
      } while (0);
  } else {
    if (val)
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF060))) |= (1 << (pin & 31)));
      } while (0);
    else
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF060))) &= ~(1 << (pin & 31)));
      } while (0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pnx833x_gpio_write>:
  endbr64
  mov    %esi,%ecx
  cmp    $0x1f,%esi
  ja     L29
  test   %edi,%edi
  je     L13
  mov    $0xb7e0f004,%edx
  mov    (%rdx),%rsi
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  or     %rsi,%rax
  mov    %rax,(%rdx)
  ret
L13:
  mov    $0xb7e0f004,%edx
  mov    (%rdx),%rsi
  mov    $0xfffffffe,%eax
  rol    %cl,%eax
  cltq
  and    %rsi,%rax
  mov    %rax,(%rdx)
  ret
L29:
  test   %edi,%edi
  je     L8
  mov    $0xb7e0f060,%edx
  mov    (%rdx),%rsi
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  or     %rsi,%rax
  mov    %rax,(%rdx)
  ret
L8:
  mov    $0xb7e0f060,%edx
  mov    (%rdx),%rsi
  mov    $0xfffffffe,%eax
  rol    %cl,%eax
  cltq
  and    %rsi,%rax
  mov    %rax,(%rdx)
  ret
```

assistant: ```c
void pnx833x_gpio_write(unsigned int val, unsigned int pin) {
  if (pin < 32) {
    if (val)
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF004))) |= (1 << (pin)));
      } while (0);
    else
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF004))) &= ~(1 << (pin)));
      } while (0);
  } else {
    if (val)
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF060))) |= (1 << (pin & 31)));
      } while (0);
    else
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF060))) &= ~(1 << (pin & 31)));
      } while (0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pnx833x_gpio_write>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  cmp    $0x1f,%esi
  ja     L14
  mov    $0xb7e0f004,%edx
  mov    (%rdx),%rcx
  test   %edi,%edi
  je     L24
L12:
  cltq
  or     %rcx,%rax
  mov    %rax,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0xb7e0f060,%edx
  mov    (%rdx),%rcx
  test   %edi,%edi
  jne    L12
L24:
  not    %eax
  cltq
  and    %rcx,%rax
  mov    %rax,(%rdx)
  ret
```

assistant: ```c
void pnx833x_gpio_write(unsigned int val, unsigned int pin) {
  if (pin < 32) {
    if (val)
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF004))) |= (1 << (pin)));
      } while (0);
    else
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF004))) &= ~(1 << (pin)));
      } while (0);
  } else {
    if (val)
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF060))) |= (1 << (pin & 31)));
      } while (0);
    else
      do {
        ((*((volatile unsigned long *)((0xa0000000ul + 0x17E00000ul) + 0xF060))) &= ~(1 << (pin & 31)));
      } while (0);
  }
}
```