ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_save_file>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  lea    D9(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  test   %rbp,%rbp
  je     L9
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L9:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: wb

assistant: ```c
int _save_file(const char *path, const char *txt) {
  FILE *fp = 0;
  do {
    ((void)(path && txt));
    assert(path && txt);
  } while (0);
  fp = fopen(path, "wb");
  if (fp) {
    fwrite(txt, sizeof(char), strlen(txt), fp);
    fclose(fp);
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_exit_reason>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x1,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <pevent_get_field_val@plt>
  test   %rax,%rax
  jns    L19
  mov    $0xffffffff,%eax
  jmp    L45
L19:
  lea    -0x20(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r9d
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D28(%rip),%rdx
  mov    %rax,%rdi
  call   <pevent_get_field_val@plt>
  test   %rax,%rax
  jns    L44
  movq   $0x1,-0x20(%rbp)
L44:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <find_exit_reason@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L20
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <trace_seq_printf@plt>
  jmp    L29
L20:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <trace_seq_printf@plt>
L29:
  mov    $0x0,%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D28
data_type: string
name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D28: isa

tool: D7: reason %s

tool: D4: reason UNKNOWN (%llu)

assistant: ```c
int print_exit_reason(struct trace_seq *s, struct pevent_record *record, struct event_format *event, const char *field) {
  unsigned long long isa;
  unsigned long long val;
  const char *reason;
  if (pevent_get_field_val(s, event, field, record, &val, 1) < 0) {
    return -1;
  }
  if (pevent_get_field_val(s, event, "isa", record, &isa, 0) < 0) {
    isa = 1;
  }
  reason = find_exit_reason(isa, val);
  if (reason) {
    trace_seq_printf(s, "reason %s", reason);
  } else {
    trace_seq_printf(s, "reason UNKNOWN (%llu)", val);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_exit_reason>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%r9d
  lea    0x10(%rsp),%r8
  mov    %rsi,%rcx
  mov    %rbp,%rsi
  call   <pevent_get_field_val@plt>
  test   %rax,%rax
  js     L38
  mov    $0x0,%r9d
  lea    0x8(%rsp),%r8
  mov    %r12,%rcx
  lea    D13(%rip),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <pevent_get_field_val@plt>
  test   %rax,%rax
  js     L61
L58:
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <find_exit_reason@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L5
  lea    D27(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <trace_seq_printf@plt>
  mov    $0x0,%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L61:
  movq   $0x1,0x8(%rsp)
  jmp    L58
L5:
  mov    0x10(%rsp),%rdx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <trace_seq_printf@plt>
  mov    $0x0,%eax
  jmp    L1
L38:
  mov    $0xffffffff,%eax
  jmp    L1
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D13
datatype: string
name: read_data
arguments: data_label: D27
datatype: string
name: read_data
arguments: data_label: D2
datatype: string

tool: D13: isa

tool: D27: reason %s

tool: D2: reason UNKNOWN (%llu)

assistant: ```c
int print_exit_reason(struct trace_seq *s, struct pevent_record *record, struct event_format *event, const char *field) {
  unsigned long long isa;
  unsigned long long val;
  const char *reason;
  if (pevent_get_field_val(s, event, field, record, &val, 1) < 0) {
    return -1;
  }
  if (pevent_get_field_val(s, event, "isa", record, &isa, 0) < 0) {
    isa = 1;
  }
  reason = find_exit_reason(isa, val);
  if (reason) {
    trace_seq_printf(s, "reason %s", reason);
  } else {
    trace_seq_printf(s, "reason UNKNOWN (%llu)", val);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_exit_reason>:
  endbr64
  push   %r13
  mov    $0x1,%r9d
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  mov    %rcx,%rdx
  mov    %rsi,%rcx
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r8
  call   <pevent_get_field_val@plt>
  test   %rax,%rax
  js     L4
  xor    %r9d,%r9d
  lea    0x8(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rsi
  lea    D4(%rip),%rdx
  mov    %rbp,%rdi
  call   <pevent_get_field_val@plt>
  test   %rax,%rax
  js     L12
  mov    0x8(%rsp),%rdi
L21:
  mov    0x10(%rsp),%rsi
  call   <find_exit_reason@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L0
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <trace_seq_printf@plt>
  xor    %eax,%eax
L30:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L12:
  movq   $0x1,0x8(%rsp)
  mov    $0x1,%edi
  jmp    L21
L0:
  mov    0x10(%rsp),%rdx
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <trace_seq_printf@plt>
  xor    %eax,%eax
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%eax
  jmp    L30
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D1
type: string

tool: D4: isa

tool: D23: reason %s

tool: D1: reason UNKNOWN (%llu)

assistant: ```c
int print_exit_reason(struct trace_seq *s, struct pevent_record *record, struct event_format *event, const char *field) {
  unsigned long long isa;
  unsigned long long val;
  const char *reason;
  if (pevent_get_field_val(s, event, field, record, &val, 1) < 0) {
    return -1;
  }
  if (pevent_get_field_val(s, event, "isa", record, &isa, 0) < 0) {
    isa = 1;
  }
  reason = find_exit_reason(isa, val);
  if (reason) {
    trace_seq_printf(s, "reason %s", reason);
  } else {
    trace_seq_printf(s, "reason UNKNOWN (%llu)", val);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_exit_reason>:
  endbr64
  push   %r13
  mov    $0x1,%r9d
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  mov    %rcx,%rdx
  mov    %rsi,%rcx
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r8
  call   <pevent_get_field_val@plt>
  test   %rax,%rax
  js     L36
  xor    %r9d,%r9d
  lea    0x8(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rsi
  lea    D8(%rip),%rdx
  mov    %rbp,%rdi
  call   <pevent_get_field_val@plt>
  test   %rax,%rax
  js     L37
  mov    0x8(%rsp),%rdi
L18:
  mov    0x10(%rsp),%rsi
  call   <find_exit_reason@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L38
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <trace_seq_printf@plt>
  xor    %eax,%eax
L39:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L37:
  movq   $0x1,0x8(%rsp)
  mov    $0x1,%edi
  jmp    L18
L38:
  mov    0x10(%rsp),%rdx
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <trace_seq_printf@plt>
  xor    %eax,%eax
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L36:
  mov    $0xffffffff,%eax
  jmp    L39
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string

tool: D8: isa

tool: D28: reason %s

tool: D27: reason UNKNOWN (%llu)

assistant: ```c
int print_exit_reason(struct trace_seq *s, struct pevent_record *record, struct event_format *event, const char *field) {
  unsigned long long isa;
  unsigned long long val;
  const char *reason;
  if (pevent_get_field_val(s, event, field, record, &val, 1) < 0) {
    return -1;
  }
  if (pevent_get_field_val(s, event, "isa", record, &isa, 0) < 0) {
    isa = 1;
  }
  reason = find_exit_reason(isa, val);
  if (reason) {
    trace_seq_printf(s, "reason %s", reason);
  } else {
    trace_seq_printf(s, "reason UNKNOWN (%llu)", val);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setge  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int a = 1, b = 2;
  assert(b > a);
  assert(a < b);
  assert(b >= a);
  assert(b >= b);
  assert(a <= b);
  assert(b <= b);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 1, b = 2;
  assert(b > a);
  assert(a < b);
  assert(b >= a);
  assert(b >= b);
  assert(a <= b);
  assert(b <= b);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 1, b = 2;
  assert(b > a);
  assert(a < b);
  assert(b >= a);
  assert(b >= b);
  assert(a <= b);
  assert(b <= b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 1, b = 2;
  assert(b > a);
  assert(a < b);
  assert(b >= a);
  assert(b >= b);
  assert(a <= b);
  assert(b <= b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<panic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  jmp    L45
L17:
  mov    $0xc0220084,%edi
  mov    $0x0,%eax
  call   <port_on@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L23:
  nop
  nop
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x1fffff,-0x4(%rbp)
  jle    L23
  mov    $0xc0220084,%edi
  mov    $0x0,%eax
  call   <port_off@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L6:
  nop
  nop
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x1fffff,-0x4(%rbp)
  jle    L6
  subl   $0x1,-0x14(%rbp)
L45:
  cmpl   $0x0,-0x14(%rbp)
  jg     L17
  mov    $0x0,%eax
  call   <shutdown@plt>
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((noreturn)) panic(int cnt) {
  int i;
  for (; cnt > 0; cnt--) {
    port_on(0xc0220084);
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
    port_off(0xc0220084);
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
  }
  shutdown();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<panic>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jle    L31
L3:
  mov    $0xc0220084,%edi
  mov    $0x0,%eax
  call   <port_on@plt>
  mov    $0x200000,%eax
L27:
  nop
  nop
  sub    $0x1,%eax
  jne    L27
  mov    $0xc0220084,%edi
  mov    $0x0,%eax
  call   <port_off@plt>
  mov    $0x200000,%eax
L33:
  nop
  nop
  sub    $0x1,%eax
  jne    L33
  sub    $0x1,%ebx
  jne    L3
L31:
  mov    $0x0,%eax
  call   <shutdown@plt>
```

assistant: ```c
void __attribute__((noreturn)) panic(int cnt) {
  int i;
  for (; cnt > 0; cnt--) {
    port_on(0xc0220084);
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
    port_off(0xc0220084);
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
  }
  shutdown();
}
```
user: Translate the below assembly code into C programming language:

```asm
<panic>:
  endbr64
  push   %rbx
  test   %edi,%edi
  jle    L3
  mov    %edi,%ebx
L5:
  mov    $0xc0220084,%edi
  xor    %eax,%eax
  call   <port_on@plt>
  mov    $0x200000,%eax
  nopl   0x0(%rax)
L34:
  nop
  nop
  sub    $0x1,%eax
  jne    L34
  mov    $0xc0220084,%edi
  xor    %eax,%eax
  call   <port_off@plt>
  mov    $0x200000,%eax
  nopl   0x0(%rax,%rax,1)
L33:
  nop
  nop
  sub    $0x1,%eax
  jne    L33
  sub    $0x1,%ebx
  jne    L5
L3:
  xor    %eax,%eax
  call   <shutdown@plt>
```

assistant: ```c
void __attribute__((noreturn)) panic(int cnt) {
  int i;
  for (; cnt > 0; cnt--) {
    port_on(0xc0220084);
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
    port_off(0xc0220084);
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
  }
  shutdown();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<panic>:
  endbr64
  push   %rbx
  test   %edi,%edi
  jle    L8
  mov    %edi,%ebx
L32:
  mov    $0xc0220084,%edi
  xor    %eax,%eax
  call   <port_on@plt>
  mov    $0x200000,%eax
  nopl   0x0(%rax)
L39:
  nop
  nop
  sub    $0x1,%eax
  jne    L39
  mov    $0xc0220084,%edi
  xor    %eax,%eax
  call   <port_off@plt>
  mov    $0x200000,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  nop
  nop
  sub    $0x1,%eax
  jne    L13
  sub    $0x1,%ebx
  jne    L32
L8:
  xor    %eax,%eax
  call   <shutdown@plt>
```

assistant: ```c
void __attribute__((noreturn)) panic(int cnt) {
  int i;
  for (; cnt > 0; cnt--) {
    port_on(0xc0220084);
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
    port_off(0xc0220084);
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
  }
  shutdown();
}
```
user: What is the c source code of the assembly code below:

```asm
<dup_usvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  sub    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    D0(%rip),%rax
  imul   -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    -0x20(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void dup_usvector(ushort *src, long nl, long nh, ushort *dst) {
  long len = nh - nl + 1;
  static long size = sizeof(ushort);
  memcpy(dst + nl, src + nl, len * size);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dup_usvector>:
  endbr64
  sub    $0x8,%rsp
  lea    0x0(,%rsi,4),%rax
  sub    %rsi,%rdx
  lea    0x4(,%rdx,4),%rdx
  lea    (%rdi,%rax,1),%rsi
  lea    (%rcx,%rax,1),%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dup_usvector(ushort *src, long nl, long nh, ushort *dst) {
  long len = nh - nl + 1;
  static long size = sizeof(ushort);
  memcpy(dst + nl, src + nl, len * size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dup_usvector>:
  endbr64
  lea    0x0(,%rsi,4),%rax
  sub    %rsi,%rdx
  lea    0x4(,%rdx,4),%rdx
  lea    (%rdi,%rax,1),%rsi
  lea    (%rcx,%rax,1),%rdi
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void dup_usvector(ushort *src, long nl, long nh, ushort *dst) {
  long len = nh - nl + 1;
  static long size = sizeof(ushort);
  memcpy(dst + nl, src + nl, len * size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dup_usvector>:
  endbr64
  lea    0x0(,%rsi,4),%rax
  sub    %rsi,%rdx
  lea    0x4(,%rdx,4),%rdx
  lea    (%rdi,%rax,1),%rsi
  lea    (%rcx,%rax,1),%rdi
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void dup_usvector(ushort *src, long nl, long nh, ushort *dst) {
  long len = nh - nl + 1;
  static long size = sizeof(ushort);
  memcpy(dst + nl, src + nl, len * size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x60(%rbp)
  movl   $0x1,-0x5c(%rbp)
  movl   $0x5,-0x58(%rbp)
  movl   $0x8,-0x54(%rbp)
  movl   $0x9,-0x50(%rbp)
  movl   $0xa,-0x4c(%rbp)
  movl   $0x11,-0x48(%rbp)
  movl   $0x11,-0x44(%rbp)
  movl   $0x14,-0x40(%rbp)
  movl   $0x9,-0x78(%rbp)
  movl   $0x8,-0x74(%rbp)
  movl   $0x16,-0x70(%rbp)
  mov    -0x74(%rbp),%edx
  mov    -0x78(%rbp),%ecx
  lea    -0x60(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_max_profit_by_cutting_a_rod_v1@plt>
  cmp    %eax,-0x70(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x74(%rbp),%edx
  mov    -0x78(%rbp),%ecx
  lea    -0x60(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_max_profit_by_cutting_a_rod_v2@plt>
  cmp    %eax,-0x70(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x8,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0x11,-0x18(%rbp)
  movl   $0x11,-0x14(%rbp)
  movl   $0x14,-0x10(%rbp)
  movl   $0x9,-0x6c(%rbp)
  movl   $0x8,-0x68(%rbp)
  movl   $0x18,-0x64(%rbp)
  mov    -0x68(%rbp),%edx
  mov    -0x6c(%rbp),%ecx
  lea    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_max_profit_by_cutting_a_rod_v1@plt>
  cmp    %eax,-0x64(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x68(%rbp),%edx
  mov    -0x6c(%rbp),%ecx
  lea    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_max_profit_by_cutting_a_rod_v2@plt>
  cmp    %eax,-0x64(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main() {
  int array2[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  int len2 = sizeof(array2) / sizeof(int);
  int rod_length2 = 8;
  int max_profit2 = 22;
  assert(max_profit2 == find_max_profit_by_cutting_a_rod_v1(array2, len2, rod_length2));
  assert(max_profit2 == find_max_profit_by_cutting_a_rod_v2(array2, len2, rod_length2));
  int array3[] = {0, 3, 5, 8, 9, 10, 17, 17, 20};
  int len3 = sizeof(array3) / sizeof(int);
  int rod_length3 = 8;
  int max_profit3 = 24;
  assert(max_profit3 == find_max_profit_by_cutting_a_rod_v1(array3, len3, rod_length3));
  assert(max_profit3 == find_max_profit_by_cutting_a_rod_v2(array3, len3, rod_length3));
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  movl   $0xa,0x14(%rsp)
  movl   $0x11,0x18(%rsp)
  movl   $0x11,0x1c(%rsp)
  movl   $0x14,0x20(%rsp)
  mov    %rsp,%rbx
  mov    $0x8,%edx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <find_max_profit_by_cutting_a_rod_v1@plt>
  cmp    $0x16,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x8,%edx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <find_max_profit_by_cutting_a_rod_v2@plt>
  cmp    $0x16,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movl   $0x0,0x30(%rsp)
  movl   $0x3,0x34(%rsp)
  movl   $0x5,0x38(%rsp)
  movl   $0x8,0x3c(%rsp)
  movl   $0x9,0x40(%rsp)
  movl   $0xa,0x44(%rsp)
  movl   $0x11,0x48(%rsp)
  movl   $0x11,0x4c(%rsp)
  movl   $0x14,0x50(%rsp)
  lea    0x30(%rsp),%rbx
  mov    $0x8,%edx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <find_max_profit_by_cutting_a_rod_v1@plt>
  cmp    $0x18,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x8,%edx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <find_max_profit_by_cutting_a_rod_v2@plt>
  cmp    $0x18,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array2[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  int len2 = sizeof(array2) / sizeof(int);
  int rod_length2 = 8;
  int max_profit2 = 22;
  assert(max_profit2 == find_max_profit_by_cutting_a_rod_v1(array2, len2, rod_length2));
  assert(max_profit2 == find_max_profit_by_cutting_a_rod_v2(array2, len2, rod_length2));
  int array3[] = {0, 3, 5, 8, 9, 10, 17, 17, 20};
  int len3 = sizeof(array3) / sizeof(int);
  int rod_length3 = 8;
  int max_profit3 = 24;
  assert(max_profit3 == find_max_profit_by_cutting_a_rod_v1(array3, len3, rod_length3));
  assert(max_profit3 == find_max_profit_by_cutting_a_rod_v2(array3, len3, rod_length3));
  return (0);
}
```