ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_current_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  mov    $0x1,%eax
  jmp    L6
L10:
  cmpq   $0x0,-0x20(%rbp)
  je     L28
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L43
L28:
  mov    $0x1,%eax
  jmp    L6
L43:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_current_val>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <get_current_val>
  add    %ebx,%eax
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint32_t get_current_val(uint8_t line, uint8_t index) {
  if (line == 0) {
    return 1;
  }
  if (index == 0 || index == line) {
    return 1;
  }
  return get_current_val(line - 1, index - 1) + get_current_val(line - 1, index);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_current_val>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L28
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L9
  cmp    %rsi,%rdi
  je     L9
  lea    -0x1(%rdi),%rbx
  lea    -0x1(%rsi),%rsi
  mov    %rbx,%rdi
  call   <get_current_val>
  mov    %eax,%r12d
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <get_current_val>
  add    %r12d,%eax
  jmp    L16
L9:
  mov    $0x1,%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  ret
```

assistant: ```c
uint32_t get_current_val(uint8_t line, uint8_t index) {
  if (line == 0) {
    return 1;
  }
  if (index == 0 || index == line) {
    return 1;
  }
  return get_current_val(line - 1, index - 1) + get_current_val(line - 1, index);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  movsd  %xmm1,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L9:
  subq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(double *p, double a, double b, int n) {
  double c = a + b;
  do
    *--p = c;
  while (n--);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  addsd  %xmm1,%xmm0
  mov    %esi,%esi
  not    %rsi
  lea    (%rdi,%rsi,8),%rax
L0:
  sub    $0x8,%rdi
  movsd  %xmm0,(%rdi)
  cmp    %rax,%rdi
  jne    L0
  ret
```

assistant: ```c
void foo(double *p, double a, double b, int n) {
  double c = a + b;
  do
    *--p = c;
  while (n--);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  mov    %esi,%esi
  addsd  %xmm1,%xmm0
  not    %rsi
  lea    (%rdi,%rsi,8),%rax
  nopl   0x0(%rax)
L8:
  sub    $0x8,%rdi
  movsd  %xmm0,(%rdi)
  cmp    %rax,%rdi
  jne    L8
  ret
```

assistant: ```c
void foo(double *p, double a, double b, int n) {
  double c = a + b;
  do
    *--p = c;
  while (n--);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  addsd  %xmm1,%xmm0
  lea    0x1(%rsi),%ecx
  test   %esi,%esi
  je     L0
  movapd %xmm0,%xmm1
  lea    -0x20(%rdi),%rdx
  lea    -0x10(%rdi),%rax
  mov    %ecx,%esi
  shr    %esi
  unpcklpd %xmm1,%xmm1
  sub    $0x1,%esi
  shl    $0x4,%rsi
  sub    %rsi,%rdx
  nopl   (%rax)
L19:
  movups %xmm1,(%rax)
  sub    $0x10,%rax
  cmp    %rdx,%rax
  jne    L19
  mov    %ecx,%edx
  and    $0xfffffffe,%edx
  mov    %edx,%eax
  neg    %rax
  lea    (%rdi,%rax,8),%rdi
  cmp    %edx,%ecx
  je     L15
L0:
  movsd  %xmm0,-0x8(%rdi)
L15:
  ret
```

assistant: ```c
void foo(double *p, double a, double b, int n) {
  double c = a + b;
  do
    *--p = c;
  while (n--);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fac@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D24
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string

tool: D16: Enter a number: 

tool: D24: %d

tool: D27: Factorial of %d is: %d

assistant: ```c
int main(void) {
  int num;
  printf("Enter a number: ");
  scanf("%d", &num);
  printf("Factorial of %d is: %d", num, fac(num));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fac@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string
name: unpack_data
arguments: tag: D22
datatype: string

tool: D29: Enter a number: 

tool: D19: %d

tool: D22: Factorial of %d is: %d

assistant: ```c
int main(void) {
  int num;
  printf("Enter a number: ");
  scanf("%d", &num);
  printf("Factorial of %d is: %d", num, fac(num));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fac@plt>
  mov    0x4(%rsp),%esi
  lea    D21(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D25
data_type: string
name: parse_data
arguments: data_label: D21
data_type: string

tool: D12: Enter a number: 

tool: D25: %d

tool: D21: Factorial of %d is: %d

assistant: ```c
int main(void) {
  int num;
  printf("Enter a number: ");
  scanf("%d", &num);
  printf("Factorial of %d is: %d", num, fac(num));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fac@plt>
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type: string
name: parse_data
arguments: data_label: D27
type: string
name: parse_data
arguments: data_label: D20
type: string

tool: D13: Enter a number: 

tool: D27: %d

tool: D20: Factorial of %d is: %d

assistant: ```c
int main(void) {
  int num;
  printf("Enter a number: ");
  scanf("%d", &num);
  printf("Factorial of %d is: %d", num, fac(num));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x11d,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <syscall@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: Process ID: %d


assistant: ```c
int main(void) {
  int syscallnum = 285;
  printf("Process ID: %d\n", syscall(syscallnum));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11d,%edi
  call   <syscall@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: Process ID: %d


assistant: ```c
int main(void) {
  int syscallnum = 285;
  printf("Process ID: %d\n", syscall(syscallnum));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11d,%edi
  call   <syscall@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: Process ID: %d


assistant: ```c
int main(void) {
  int syscallnum = 285;
  printf("Process ID: %d\n", syscall(syscallnum));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11d,%edi
  call   <syscall@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string

tool: D0: Process ID: %d


assistant: ```c
int main(void) {
  int syscallnum = 285;
  printf("Process ID: %d\n", syscall(syscallnum));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atoin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L11:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atoin(char s[]) {
  int temp = 0;
  for (int i = 0; s[i] != '\0'; i++) {
    temp = (temp * 10) + (s[i] - '0');
  }
  return temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atoin>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
  add    $0x1,%rdi
  mov    $0x0,%edx
L18:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L18
L9:
  mov    %edx,%eax
  ret
L23:
  mov    $0x0,%edx
  jmp    L9
```

assistant: ```c
int atoin(char s[]) {
  int temp = 0;
  for (int i = 0; s[i] != '\0'; i++) {
    temp = (temp * 10) + (s[i] - '0');
  }
  return temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atoin>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L15
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L13:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L13
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoin(char s[]) {
  int temp = 0;
  for (int i = 0; s[i] != '\0'; i++) {
    temp = (temp * 10) + (s[i] - '0');
  }
  return temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atoin>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L2
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L0:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L0
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoin(char s[]) {
  int temp = 0;
  for (int i = 0; s[i] != '\0'; i++) {
    temp = (temp * 10) + (s[i] - '0');
  }
  return temp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<feclearexcept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <fegetenv@plt>
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <fesetenv@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int feclearexcept(int __excepts) {
  fexcept_t __fpscr;
  fegetenv(&__fpscr);
  __fpscr &= ~__excepts;
  fesetenv(&__fpscr);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<feclearexcept>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <fegetenv@plt>
  not    %ebx
  and    %ebx,0x4(%rsp)
  mov    %rbp,%rdi
  call   <fesetenv@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int feclearexcept(int __excepts) {
  fexcept_t __fpscr;
  fegetenv(&__fpscr);
  __fpscr &= ~__excepts;
  fesetenv(&__fpscr);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<feclearexcept>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  not    %ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <fegetenv@plt>
  mov    %rbp,%rdi
  and    %ebx,0x4(%rsp)
  call   <fesetenv@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int feclearexcept(int __excepts) {
  fexcept_t __fpscr;
  fegetenv(&__fpscr);
  __fpscr &= ~__excepts;
  fesetenv(&__fpscr);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<feclearexcept>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  not    %ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <fegetenv@plt>
  mov    %rbp,%rdi
  and    %ebx,0x4(%rsp)
  call   <fesetenv@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int feclearexcept(int __excepts) {
  fexcept_t __fpscr;
  fegetenv(&__fpscr);
  __fpscr &= ~__excepts;
  fesetenv(&__fpscr);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_toUpperCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <str_len@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L0
L43:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L49
L44:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L49:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_toUpperCase(char *str) {
  char *buffer = (char *)malloc(str_len(str) + 1);
  char *it, *itr;
  it = str;
  itr = buffer;
  while (*it != '\0') {
    if (*it >= 'a' && *it <= 'z') {
      *itr = (*it - 'a') + 'A';
    } else {
      *itr = *it;
    }
    it++;
    itr++;
  }
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_toUpperCase>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <str_len@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L17
  mov    %rax,%rcx
  sub    %rax,%rbx
  mov    %rbx,%r8
L14:
  lea    -0x61(%rdx),%edi
  lea    -0x20(%rdx),%esi
  cmp    $0x1a,%dil
  cmovb  %esi,%edx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rcx,%r8,1),%edx
  test   %dl,%dl
  jne    L14
L17:
  pop    %rbx
  ret
```

assistant: ```c
char *str_toUpperCase(char *str) {
  char *buffer = (char *)malloc(str_len(str) + 1);
  char *it, *itr;
  it = str;
  itr = buffer;
  while (*it != '\0') {
    if (*it >= 'a' && *it <= 'z') {
      *itr = (*it - 'a') + 'A';
    } else {
      *itr = *it;
    }
    it++;
    itr++;
  }
  return buffer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_toUpperCase>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <str_len@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L3
  sub    %rax,%rbx
  mov    %rax,%rcx
  mov    %rbx,%rdi
  cs nopw 0x0(%rax,%rax,1)
L4:
  lea    -0x61(%rdx),%r8d
  lea    -0x20(%rdx),%esi
  cmp    $0x1a,%r8b
  cmovb  %esi,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx,%rdi,1),%edx
  test   %dl,%dl
  jne    L4
L3:
  pop    %rbx
  ret
```

assistant: ```c
char *str_toUpperCase(char *str) {
  char *buffer = (char *)malloc(str_len(str) + 1);
  char *it, *itr;
  it = str;
  itr = buffer;
  while (*it != '\0') {
    if (*it >= 'a' && *it <= 'z') {
      *itr = (*it - 'a') + 'A';
    } else {
      *itr = *it;
    }
    it++;
    itr++;
  }
  return buffer;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_toUpperCase>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <str_len@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L29
  sub    %rax,%rbx
  mov    %rax,%rcx
  mov    %rbx,%rdi
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L10
  sub    $0x20,%edx
L10:
  mov    %dl,(%rcx)
  movzbl 0x1(%rcx,%rdi,1),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L17
L29:
  pop    %rbx
  ret
```

assistant: ```c
char *str_toUpperCase(char *str) {
  char *buffer = (char *)malloc(str_len(str) + 1);
  char *it, *itr;
  it = str;
  itr = buffer;
  while (*it != '\0') {
    if (*it >= 'a' && *it <= 'z') {
      *itr = (*it - 'a') + 'A';
    } else {
      *itr = *it;
    }
    it++;
    itr++;
  }
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L46
L22:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <get_number@plt>
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x14(%rbp,%rdx,4)
  addl   $0x1,-0x18(%rbp)
L46:
  cmpl   $0x2,-0x18(%rbp)
  jle    L22
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L45
L16:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L45:
  cmpl   $0x2,-0x18(%rbp)
  jle    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D20
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D1: Valid digits are from 0 to 99

tool: D20: Enter digit #%d: 

tool: D4: The combination is: 

tool: D9:  %02d

assistant: ```c
int main() {
  int x, digit[3];
  puts("Valid digits are from 0 to 99");
  for (x = 0; x < 3; x++) {
    printf("Enter digit #%d: ", x + 1);
    digit[x] = get_number();
  }
  printf("The combination is: ");
  for (x = 0; x < 3; x++) {
    printf(" %02d", digit[x]);
  }
  putchar('\n');
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  lea    D30(%rip),%rbp
L15:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <get_number@plt>
  mov    %eax,0x8(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L15
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D30
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D17
datatype: string

tool: D18: Valid digits are from 0 to 99

tool: D30: Enter digit #%d: 

tool: D10: The combination is: 

tool: D17:  %02d

assistant: ```c
int main() {
  int x, digit[3];
  puts("Valid digits are from 0 to 99");
  for (x = 0; x < 3; x++) {
    printf("Enter digit #%d: ", x + 1);
    digit[x] = get_number();
  }
  printf("The combination is: ");
  for (x = 0; x < 3; x++) {
    printf(" %02d", digit[x]);
  }
  putchar('\n');
  return (0);
}
```