ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atmos_press_adjust>:
  endbr64
  sub    $0x28,%rsp
  movss  %xmm0,0x14(%rsp)
  movaps %xmm1,%xmm0
  movss  %xmm2,0x8(%rsp)
  movss  %xmm3,0x10(%rsp)
  movss  %xmm1,0x1c(%rsp)
  call   <atmos_geopotential_alt@plt>
  movss  0x14(%rsp),%xmm6
  movss  %xmm0,0xc(%rsp)
  movaps %xmm6,%xmm0
  call   <atmos_geopotential_alt@plt>
  movss  0xc(%rsp),%xmm4
  movss  0x10(%rsp),%xmm3
  comiss D41(%rip),%xmm3
  subss  %xmm0,%xmm4
  movaps %xmm4,%xmm7
  divss  D20(%rip),%xmm7
  movaps %xmm7,%xmm2
  jb     L2
  movss  0x8(%rsp),%xmm1
  movaps %xmm3,%xmm0
  movss  %xmm4,0xc(%rsp)
  movss  %xmm7,0x10(%rsp)
  call   <dewpoint@plt>
  movss  0x1c(%rsp),%xmm5
  mov    %eax,%edi
  movaps %xmm5,%xmm0
  call   <correct@plt>
  movss  0x10(%rsp),%xmm2
  movss  0xc(%rsp),%xmm4
  movss  %xmm0,0x18(%rsp)
L2:
  addss  0x8(%rsp),%xmm2
  addss  0x18(%rsp),%xmm2
  cvtss2sd %xmm4,%xmm4
  pxor   %xmm1,%xmm1
  movsd  D41(%rip),%xmm0
  cvtss2sd %xmm2,%xmm2
  addsd  D25(%rip),%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  mulsd  D35(%rip),%xmm2
  add    $0x28,%rsp
  divsd  %xmm2,%xmm4
  cvtsd2ss %xmm4,%xmm1
  jmp    1090 <powf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D41
data_type: f64
name: disassemble_data
arguments: tag: D20
data_type: f32
name: disassemble_data
arguments: tag: D25
data_type: f64
name: disassemble_data
arguments: tag: D35
data_type: f64

tool: D41: 10

tool: D20: 400

tool: D25: 273.15

tool: D35: 67.442

assistant: ```c
float atmos_press_adjust(float Z2, float Z1, float T1, float RH1) {
  float C, L, Tmv, Hd;
  Hd = atmos_geopotential_alt(Z1) - atmos_geopotential_alt(Z2);
  L = Hd / 400.0;
  if (RH1 >= 0.0)
    C = correct(dewpoint(RH1, T1), Z1);
  Tmv = T1 + L + C + 273.15;
  return (powf(10.0, Hd / (67.442 * Tmv)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strndup(const char *string, size_t len) {
  char *result;
  result = (char *)malloc(len + 1);
  memcpy(result, string, len);
  result[len] = '\0';
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *string, size_t len) {
  char *result;
  result = (char *)malloc(len + 1);
  memcpy(result, string, len);
  result[len] = '\0';
  return (result);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *string, size_t len) {
  char *result;
  result = (char *)malloc(len + 1);
  memcpy(result, string, len);
  result[len] = '\0';
  return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *string, size_t len) {
  char *result;
  result = (char *)malloc(len + 1);
  memcpy(result, string, len);
  result[len] = '\0';
  return (result);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BMP_ShiftCal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L24
L7:
  cmpl   $0xff,-0x14(%rbp)
  jbe    L32
  jmp    L9
L11:
  shrl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0xff,-0x14(%rbp)
  ja     L11
  jmp    L35
L26:
  shll   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L26
L35:
  mov    -0x4(%rbp),%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int BMP_ShiftCal(unsigned int mask) {
  unsigned int shift = 0;
  if (mask == 0)
    return 0;
  if (mask > 255) {
    while (mask > 255) {
      mask >>= 1;
      shift++;
    }
  } else {
    while ((mask & 128) == 0) {
      mask <<= 1;
      shift++;
    }
  }
  return shift;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BMP_ShiftCal>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L27
  cmp    $0xff,%edi
  ja     L7
  and    $0x80,%eax
  jne    L39
L49:
  add    %edi,%edi
  add    $0x1,%eax
  test   $0x80,%dil
  je     L49
L27:
  ret
L39:
  mov    $0x0,%eax
  ret
L7:
  mov    $0x0,%eax
L6:
  shr    %edi
  add    $0x1,%eax
  cmp    $0xff,%edi
  ja     L6
  ret
```

assistant: ```c
unsigned int BMP_ShiftCal(unsigned int mask) {
  unsigned int shift = 0;
  if (mask == 0)
    return 0;
  if (mask > 255) {
    while (mask > 255) {
      mask >>= 1;
      shift++;
    }
  } else {
    while ((mask & 128) == 0) {
      mask <<= 1;
      shift++;
    }
  }
  return shift;
}
```
user: What is the c source code of the assembly code below:

```asm
<BMP_ShiftCal>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L15
  cmp    $0xff,%edi
  ja     L30
  mov    %edi,%eax
  and    $0x80,%eax
  jne    L17
  nopl   0x0(%rax,%rax,1)
L46:
  add    %edi,%edi
  add    $0x1,%eax
  test   $0x80,%dil
  je     L46
L15:
  ret
  nopl   0x0(%rax)
L30:
  shr    %edi
  add    $0x1,%eax
  cmp    $0xff,%edi
  ja     L30
  ret
  xchg   %ax,%ax
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int BMP_ShiftCal(unsigned int mask) {
  unsigned int shift = 0;
  if (mask == 0)
    return 0;
  if (mask > 255) {
    while (mask > 255) {
      mask >>= 1;
      shift++;
    }
  } else {
    while ((mask & 128) == 0) {
      mask <<= 1;
      shift++;
    }
  }
  return shift;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BMP_ShiftCal>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L4
  cmp    $0xff,%edi
  ja     L32
  mov    %edi,%eax
  and    $0x80,%eax
  jne    L34
  nopl   0x0(%rax,%rax,1)
L46:
  add    %edi,%edi
  add    $0x1,%eax
  test   $0x80,%dil
  je     L46
L4:
  ret
  nopl   0x0(%rax)
L32:
  shr    %edi
  add    $0x1,%eax
  cmp    $0xff,%edi
  ja     L32
  ret
  xchg   %ax,%ax
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int BMP_ShiftCal(unsigned int mask) {
  unsigned int shift = 0;
  if (mask == 0)
    return 0;
  if (mask > 255) {
    while (mask > 255) {
      mask >>= 1;
      shift++;
    }
  } else {
    while ((mask & 128) == 0) {
      mask <<= 1;
      shift++;
    }
  }
  return shift;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GetBitFromByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%esi
  mov    -0x8(%rbp),%eax
  cltq
  lea    D0(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    %esi,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int GetBitFromByte(unsigned char theByte, int index) {
  static unsigned char bitmask[8] = {1, 2, 4, 8, 16, 32, 64, 128};
  return theByte & bitmask[index] >> index;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GetBitFromByte>:
  endbr64
  mov    %esi,%ecx
  movslq %esi,%rax
  lea    D0(%rip),%rdx
  movzbl (%rdx,%rax,1),%eax
  sar    %cl,%eax
  movzbl %dil,%edi
  and    %edi,%eax
  ret
```

assistant: ```c
unsigned int GetBitFromByte(unsigned char theByte, int index) {
  static unsigned char bitmask[8] = {1, 2, 4, 8, 16, 32, 64, 128};
  return theByte & bitmask[index] >> index;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GetBitFromByte>:
  endbr64
  movslq %esi,%rax
  lea    D2(%rip),%rdx
  movzbl %dil,%edi
  mov    %rax,%rcx
  movzbl (%rdx,%rax,1),%eax
  sar    %cl,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
unsigned int GetBitFromByte(unsigned char theByte, int index) {
  static unsigned char bitmask[8] = {1, 2, 4, 8, 16, 32, 64, 128};
  return theByte & bitmask[index] >> index;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetBitFromByte>:
  endbr64
  movslq %esi,%rax
  lea    D9(%rip),%rdx
  movzbl %dil,%edi
  mov    %rax,%rcx
  movzbl (%rdx,%rax,1),%eax
  sar    %cl,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
unsigned int GetBitFromByte(unsigned char theByte, int index) {
  static unsigned char bitmask[8] = {1, 2, 4, 8, 16, 32, 64, 128};
  return theByte & bitmask[index] >> index;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_on_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x8040201008040201,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl -0x10(%rbp,%rax,1),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned char get_on_mask(unsigned int pos) {
  unsigned char array[] = {0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40, 0x80};
  return array[pos];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_on_mask>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x8040201008040201,%rax
  mov    %rax,(%rsp)
  mov    %edi,%edi
  movzbl (%rsp,%rdi,1),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char get_on_mask(unsigned int pos) {
  unsigned char array[] = {0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40, 0x80};
  return array[pos];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_on_mask>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x8040201008040201,%rax
  mov    %rax,(%rsp)
  movzbl (%rsp,%rdi,1),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char get_on_mask(unsigned int pos) {
  unsigned char array[] = {0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40, 0x80};
  return array[pos];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_on_mask>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x8040201008040201,%rax
  mov    %rax,(%rsp)
  movzbl (%rsp,%rdi,1),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char get_on_mask(unsigned int pos) {
  unsigned char array[] = {0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40, 0x80};
  return array[pos];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BrzUnaryFuncPush_ackdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <SEND_ACKDOWN_DELAYED@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <SEND_DATAOFF_DELAYED@plt>
  nop
  leave
  ret
```

assistant: ```c
void BrzUnaryFuncPush_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(1, 0);
  SEND_DATAOFF_DELAYED(0, 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<BrzUnaryFuncPush_ackdown>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <SEND_ACKDOWN_DELAYED@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <SEND_DATAOFF_DELAYED@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BrzUnaryFuncPush_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(1, 0);
  SEND_DATAOFF_DELAYED(0, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BrzUnaryFuncPush_ackdown>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <SEND_ACKDOWN_DELAYED@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <SEND_DATAOFF_DELAYED@plt>
```

assistant: ```c
void BrzUnaryFuncPush_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(1, 0);
  SEND_DATAOFF_DELAYED(0, 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<BrzUnaryFuncPush_ackdown>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <SEND_ACKDOWN_DELAYED@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <SEND_DATAOFF_DELAYED@plt>
```

assistant: ```c
void BrzUnaryFuncPush_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(1, 0);
  SEND_DATAOFF_DELAYED(0, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<createEndInstruction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x83d60,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <addInstructionToMemory@plt>
  cmp    $0xffffffff,%eax
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L13
L16:
  mov    $0x1,%eax
L13:
  leave
  ret
```

assistant: ```c
int createEndInstruction(char tokenArray[][20], int numberOfTokens) {
  int instruction = 54 * 10000;
  if (addInstructionToMemory(instruction) == -1)
    return -1;
  ;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<createEndInstruction>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x83d60,%edi
  call   <addInstructionToMemory@plt>
  cmp    $0xffffffff,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int createEndInstruction(char tokenArray[][20], int numberOfTokens) {
  int instruction = 54 * 10000;
  if (addInstructionToMemory(instruction) == -1)
    return -1;
  ;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<createEndInstruction>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x83d60,%edi
  call   <addInstructionToMemory@plt>
  mov    $0x1,%edx
  cmp    $0xffffffff,%eax
  cmovne %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int createEndInstruction(char tokenArray[][20], int numberOfTokens) {
  int instruction = 54 * 10000;
  if (addInstructionToMemory(instruction) == -1)
    return -1;
  ;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<createEndInstruction>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x83d60,%edi
  call   <addInstructionToMemory@plt>
  mov    $0x1,%edx
  cmp    $0xffffffff,%eax
  cmovne %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int createEndInstruction(char tokenArray[][20], int numberOfTokens) {
  int instruction = 54 * 10000;
  if (addInstructionToMemory(instruction) == -1)
    return -1;
  ;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xp_asprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xp_vasprintf@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *xp_asprintf(const char *format, ...) {
  char *ret;
  va_list va;
  va_start(va, format);
  ret = xp_vasprintf(format, va);
  va_end(va);
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xp_asprintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <xp_vasprintf@plt>
  mov    %rax,%rbx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *xp_asprintf(const char *format, ...) {
  char *ret;
  va_list va;
  va_start(va, format);
  ret = xp_vasprintf(format, va);
  va_end(va);
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xp_asprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <xp_vasprintf@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *xp_asprintf(const char *format, ...) {
  char *ret;
  va_list va;
  va_start(va, format);
  ret = xp_vasprintf(format, va);
  va_end(va);
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xp_asprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <xp_vasprintf@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *xp_asprintf(const char *format, ...) {
  char *ret;
  va_list va;
  va_start(va, format);
  ret = xp_vasprintf(format, va);
  va_end(va);
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x10(%rbp),%edx
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  sub    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string
name: parse_data
arguments: data_tag: D4
type: string

tool: D0: %d%d%d

tool: D4: %d %d %d

assistant: ```c
int main() {
  int x, y, z;
  int max, mid, min;
  scanf("%d%d%d", &x, &y, &z);
  max = x > y ? x : y;
  max = max > z ? max : z;
  min = x < y ? x : y;
  min = min < z ? min : z;
  mid = x + y + z - min - max;
  printf("%d %d %d", max, mid, min);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  mov    %edx,%esi
  cmovge %eax,%esi
  mov    0x14(%rsp),%edi
  cmp    %esi,%edi
  cmovge %edi,%esi
  cmp    %edx,%eax
  mov    %edx,%ecx
  cmovle %eax,%ecx
  cmp    %ecx,%edi
  cmovle %edi,%ecx
  add    %eax,%edx
  add    %edi,%edx
  sub    %ecx,%edx
  sub    %esi,%edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D1: %d%d%d

tool: D5: %d %d %d

assistant: ```c
int main() {
  int x, y, z;
  int max, mid, min;
  scanf("%d%d%d", &x, &y, &z);
  max = x > y ? x : y;
  max = max > z ? max : z;
  min = x < y ? x : y;
  min = min < z ? min : z;
  mid = x + y + z - min - max;
  printf("%d %d %d", max, mid, min);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    0x14(%rsp),%edi
  cmp    %edx,%eax
  mov    %edx,%esi
  mov    %edx,%ecx
  cmovge %eax,%esi
  cmp    %esi,%edi
  cmovge %edi,%esi
  cmp    %edx,%eax
  cmovle %eax,%ecx
  cmp    %ecx,%edi
  cmovle %edi,%ecx
  add    %eax,%edx
  add    %edi,%edx
  lea    D7(%rip),%rdi
  sub    %ecx,%edx
  sub    %esi,%edx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D7
type: string

tool: D6: %d%d%d

tool: D7: %d %d %d

assistant: ```c
int main() {
  int x, y, z;
  int max, mid, min;
  scanf("%d%d%d", &x, &y, &z);
  max = x > y ? x : y;
  max = max > z ? max : z;
  min = x < y ? x : y;
  min = min < z ? min : z;
  mid = x + y + z - min - max;
  printf("%d %d %d", max, mid, min);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    0x14(%rsp),%edi
  cmp    %edx,%eax
  mov    %edx,%esi
  mov    %edx,%ecx
  cmovge %eax,%esi
  cmp    %esi,%edi
  cmovge %edi,%esi
  cmp    %edx,%eax
  cmovle %eax,%ecx
  cmp    %ecx,%edi
  cmovle %edi,%ecx
  add    %eax,%edx
  add    %edi,%edx
  lea    D10(%rip),%rdi
  sub    %ecx,%edx
  sub    %esi,%edx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D10
type_infered: string

tool: D13: %d%d%d

tool: D10: %d %d %d

assistant: ```c
int main() {
  int x, y, z;
  int max, mid, min;
  scanf("%d%d%d", &x, &y, &z);
  max = x > y ? x : y;
  max = max > z ? max : z;
  min = x < y ? x : y;
  min = min < z ? min : z;
  mid = x + y + z - min - max;
  printf("%d %d %d", max, mid, min);
  return 0;
}
```