ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<sorter_grail_sort_fixed_buffer>:
  endbr64
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x200,%ecx
  call   <sorter_grail_common_sort@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x818,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sorter_grail_sort_fixed_buffer(int64_t *arr, size_t Len) {
  int64_t ExtBuf[512];
  sorter_grail_common_sort(arr, Len, ExtBuf, 512);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sorter_grail_sort_fixed_buffer>:
  endbr64
  sub    $0x818,%rsp
  mov    $0x200,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <sorter_grail_common_sort@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x818,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sorter_grail_sort_fixed_buffer(int64_t *arr, size_t Len) {
  int64_t ExtBuf[512];
  sorter_grail_common_sort(arr, Len, ExtBuf, 512);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sorter_grail_sort_fixed_buffer>:
  endbr64
  sub    $0x818,%rsp
  mov    $0x200,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <sorter_grail_common_sort@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x818,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sorter_grail_sort_fixed_buffer(int64_t *arr, size_t Len) {
  int64_t ExtBuf[512];
  sorter_grail_common_sort(arr, Len, ExtBuf, 512);
}
```
user: What is the c source code of the assembly code below:

```asm
<fgt22>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xfffffff9,-0x4(%rbp)
  jne    L25
  mov    $0xffffffff,%eax
  jmp    L31
L25:
  cmpl   $0xfffffffc,-0x8(%rbp)
  jbe    L46
  mov    $0x0,%eax
  jmp    L31
L46:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jbe    L6
  mov    $0x0,%eax
  call   <unreachable@plt>
L6:
  mov    $0x1,%eax
L31:
  leave
  ret
```

assistant: ```c
int fgt22(int a) {
  unsigned i = a / 4;
  unsigned j = i + 2;
  if (j == -7)
    return -1;
  if (i >= -3)
    return 0;
  if (i > j)
    unreachable();
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fgt22>:
  endbr64
  lea    0x3(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x2,%eax
  mov    $0xffffffff,%edx
  cmp    $0xfffffff7,%eax
  je     L6
  cmp    $0xfffffffc,%eax
  setbe  %dl
  movzbl %dl,%edx
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
int fgt22(int a) {
  unsigned i = a / 4;
  unsigned j = i + 2;
  if (j == -7)
    return -1;
  if (i >= -3)
    return 0;
  if (i > j)
    unreachable();
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fgt22>:
  endbr64
  test   %edi,%edi
  lea    0x3(%rdi),%eax
  mov    $0xffffffff,%r8d
  cmovns %edi,%eax
  sar    $0x2,%eax
  cmp    $0xfffffff7,%eax
  je     L4
  xor    %r8d,%r8d
  cmp    $0xfffffffc,%eax
  setbe  %r8b
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fgt22(int a) {
  unsigned i = a / 4;
  unsigned j = i + 2;
  if (j == -7)
    return -1;
  if (i >= -3)
    return 0;
  if (i > j)
    unreachable();
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<fgt22>:
  endbr64
  test   %edi,%edi
  lea    0x3(%rdi),%eax
  mov    $0xffffffff,%r8d
  cmovns %edi,%eax
  sar    $0x2,%eax
  cmp    $0xfffffff7,%eax
  je     L5
  xor    %r8d,%r8d
  cmp    $0xfffffffc,%eax
  setbe  %r8b
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fgt22(int a) {
  unsigned i = a / 4;
  unsigned j = i + 2;
  if (j == -7)
    return -1;
  if (i >= -3)
    return 0;
  if (i > j)
    unreachable();
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x1388,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x40(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rdi
  mov    -0x18(%rbp),%r8
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  push   %rdi
  push   -0x38(%rbp)
  mov    %r8,%r9
  mov    $0x0,%r8d
  mov    %rax,%rdi
  call   <dfs@plt>
  add    $0x10,%rsp
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **permute(int *nums, int numsSize, int *returnSize, int **returnColumnSizes) {
  int count = 0, cap = 5000;
  int **results = malloc(cap * sizeof(int *));
  bool *used = malloc(numsSize * sizeof(bool));
  int *stack = malloc(numsSize * sizeof(int));
  *returnSize = 0;
  *returnColumnSizes = malloc(cap * sizeof(int));
  memset(used, false, numsSize * sizeof(bool));
  dfs(nums, numsSize, used, stack, 0, results, returnSize, *returnColumnSizes);
  return results;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    $0x9c40,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x0(,%rbp,4),%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  movl   $0x0,0x0(%r13)
  mov    $0x4e20,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  mov    %r15d,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  push   (%r14)
  push   %r13
  mov    %rbx,%r9
  mov    $0x0,%r8d
  mov    0x10(%rsp),%rcx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    0x18(%rsp),%rdi
  call   <dfs@plt>
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **permute(int *nums, int numsSize, int *returnSize, int **returnColumnSizes) {
  int count = 0, cap = 5000;
  int **results = malloc(cap * sizeof(int *));
  bool *used = malloc(numsSize * sizeof(bool));
  int *stack = malloc(numsSize * sizeof(int));
  *returnSize = 0;
  *returnColumnSizes = malloc(cap * sizeof(int));
  memset(used, false, numsSize * sizeof(bool));
  dfs(nums, numsSize, used, stack, 0, results, returnSize, *returnColumnSizes);
  return results;
}
```
user: What is the c source code of the assembly code below?

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0x0(,%rbp,4),%r15d
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x9c40,%edi
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  movl   $0x0,(%rbx)
  mov    $0x4e20,%edi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r13,%rdi
  xor    %esi,%esi
  mov    %rax,(%r14)
  call   <memset@plt>
  push   (%r14)
  mov    %r12,%r9
  mov    %r13,%rdx
  push   %rbx
  mov    %ebp,%esi
  xor    %r8d,%r8d
  mov    0x10(%rsp),%rcx
  mov    0x18(%rsp),%rdi
  call   <dfs@plt>
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **permute(int *nums, int numsSize, int *returnSize, int **returnColumnSizes) {
  int count = 0, cap = 5000;
  int **results = malloc(cap * sizeof(int *));
  bool *used = malloc(numsSize * sizeof(bool));
  int *stack = malloc(numsSize * sizeof(int));
  *returnSize = 0;
  *returnColumnSizes = malloc(cap * sizeof(int));
  memset(used, false, numsSize * sizeof(bool));
  dfs(nums, numsSize, used, stack, 0, results, returnSize, *returnColumnSizes);
  return results;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0x0(,%rbp,4),%r15d
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x9c40,%edi
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  movl   $0x0,(%rbx)
  mov    $0x4e20,%edi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r13,%rdi
  xor    %esi,%esi
  mov    %rax,(%r14)
  call   <memset@plt>
  push   (%r14)
  mov    %r12,%r9
  mov    %r13,%rdx
  push   %rbx
  mov    %ebp,%esi
  xor    %r8d,%r8d
  mov    0x10(%rsp),%rcx
  mov    0x18(%rsp),%rdi
  call   <dfs@plt>
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **permute(int *nums, int numsSize, int *returnSize, int **returnColumnSizes) {
  int count = 0, cap = 5000;
  int **results = malloc(cap * sizeof(int *));
  bool *used = malloc(numsSize * sizeof(bool));
  int *stack = malloc(numsSize * sizeof(int));
  *returnSize = 0;
  *returnColumnSizes = malloc(cap * sizeof(int));
  memset(used, false, numsSize * sizeof(bool));
  dfs(nums, numsSize, used, stack, 0, results, returnSize, *returnColumnSizes);
  return results;
}
```
user: Translate the below assembly code into C programming language:

```asm
<a2c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L5:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
L17:
  cmpl   $0x8,-0xc(%rbp)
  jle    L5
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **a2c(char ma[][10]) {
  char **res = (char **)malloc(sizeof(char *) * 9);
  int i;
  for (i = 0; i < 9; i++) {
    res[i] = ma[i];
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<a2c>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rax,%rcx
  lea    0x5a(%rbx),%rdi
L9:
  mov    %rdx,(%rcx)
  add    $0xa,%rdx
  add    $0x8,%rcx
  cmp    %rdi,%rdx
  jne    L9
  pop    %rbx
  ret
```

assistant: ```c
char **a2c(char ma[][10]) {
  char **res = (char **)malloc(sizeof(char *) * 9);
  int i;
  for (i = 0; i < 9; i++) {
    res[i] = ma[i];
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<a2c>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  lea    0x5a(%rbx),%rcx
  mov    %rax,%rdx
  nopl   0x0(%rax)
L5:
  mov    %rdi,(%rdx)
  add    $0xa,%rdi
  add    $0x8,%rdx
  cmp    %rcx,%rdi
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
char **a2c(char ma[][10]) {
  char **res = (char **)malloc(sizeof(char *) * 9);
  int i;
  for (i = 0; i < 9; i++) {
    res[i] = ma[i];
  }
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<a2c>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x48,%edi
  call   <malloc@plt>
  movq   %rbx,%xmm0
  movdqa D1(%rip),%xmm1
  add    $0x50,%rbx
  punpcklqdq %xmm0,%xmm0
  mov    %rbx,0x40(%rax)
  paddq  %xmm0,%xmm1
  movups %xmm1,(%rax)
  movdqa D39(%rip),%xmm1
  paddq  %xmm0,%xmm1
  movups %xmm1,0x10(%rax)
  movdqa D28(%rip),%xmm1
  paddq  %xmm0,%xmm1
  paddq  D34(%rip),%xmm0
  movups %xmm1,0x20(%rax)
  movups %xmm0,0x30(%rax)
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: byte[16]
name: retrieve_data
arguments: tag: D39
type_infered: byte[16]
name: retrieve_data
arguments: tag: D28
type_infered: byte[16]
name: retrieve_data
arguments: tag: D34
type_infered: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D39": [0x14,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D28": [0x28,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x32,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D34": [0x3c,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
char **a2c(char ma[][10]) {
  char **res = (char **)malloc(sizeof(char *) * 9);
  int i;
  for (i = 0; i < 9; i++) {
    res[i] = ma[i];
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x64,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int bar(int a) {
  int *ptr = &a;
  *ptr = 100;
  return a + *ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bar>:
  endbr64
  mov    $0xc8,%eax
  ret
```

assistant: ```c
int bar(int a) {
  int *ptr = &a;
  *ptr = 100;
  return a + *ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bar>:
  endbr64
  mov    $0xc8,%eax
  ret
```

assistant: ```c
int bar(int a) {
  int *ptr = &a;
  *ptr = 100;
  return a + *ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bar>:
  endbr64
  mov    $0xc8,%eax
  ret
```

assistant: ```c
int bar(int a) {
  int *ptr = &a;
  *ptr = 100;
  return a + *ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<dec2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xa4(%rbp),%eax
  mov    %eax,-0x98(%rbp)
  movl   $0x0,-0x94(%rbp)
  jmp    L37
L16:
  mov    -0x98(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x94(%rbp),%eax
  cltq
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x98(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x98(%rbp)
  addl   $0x1,-0x94(%rbp)
L37:
  cmpl   $0x1,-0x98(%rbp)
  jg     L16
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x98(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0xa4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L14:
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x94(%rbp)
L5:
  cmpl   $0x0,-0x94(%rbp)
  jns    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: string
name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D0: The decimal number %d in binary is: 

tool: D3: %d

assistant: ```c
void dec2bin(int decimal) {
  int remainder[32];
  int quocient = decimal, i = 0;
  while (quocient >= 2) {
    remainder[i] = quocient % 2;
    quocient = quocient / 2;
    i++;
  }
  remainder[i] = quocient;
  printf("The decimal number %d in binary is: ", decimal);
  while (i >= 0) {
    printf("%d", remainder[i]);
    i--;
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dec2bin>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L0
  mov    %edi,%eax
  mov    $0x1,%ecx
L31:
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  lea    (%rax,%r8,1),%edx
  and    $0x1,%edx
  sub    %r8d,%edx
  mov    %edx,-0x4(%rsp,%rcx,4)
  mov    %eax,%edx
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %r8d,%eax
  sar    %eax
  mov    %ecx,%ebx
  add    $0x1,%rcx
  cmp    $0x3,%edx
  jg     L31
  movslq %ebx,%rdx
  mov    %eax,(%rsp,%rdx,4)
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  js     L27
L24:
  movslq %ebx,%rbx
  lea    D6(%rip),%rbp
L11:
  mov    (%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L11
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %edi,(%rsp)
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L24
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D28: The decimal number %d in binary is: 

tool: D6: %d

assistant: ```c
void dec2bin(int decimal) {
  int remainder[32];
  int quocient = decimal, i = 0;
  while (quocient >= 2) {
    remainder[i] = quocient % 2;
    quocient = quocient / 2;
    i++;
  }
  remainder[i] = quocient;
  printf("The decimal number %d in binary is: ", decimal);
  while (i >= 0) {
    printf("%d", remainder[i]);
    i--;
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dec2bin>:
  endbr64
  push   %r12
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L36
  mov    $0x1,%eax
  mov    %rsp,%rcx
  nopw   0x0(%rax,%rax,1)
L56:
  mov    %ebp,%edx
  sar    %ebp
  mov    %eax,%ebx
  and    $0x1,%edx
  mov    %edx,-0x4(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    $0x1,%ebp
  jne    L56
L18:
  movslq %ebx,%rax
  lea    D11(%rip),%rdi
  sub    $0x1,%ebx
  mov    %ebp,(%rsp,%rax,4)
  xor    %eax,%eax
  movslq %ebx,%rbx
  lea    D1(%rip),%r12
  call   <printf@plt>
  jmp    L9
  nopl   0x0(%rax)
L7:
  mov    (%rsp,%rbx,4),%ebp
  sub    $0x1,%rbx
L9:
  xor    %eax,%eax
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xffffffff,%ebx
  jne    L7
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x90,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
L36:
  xor    %ebx,%ebx
  jmp    L18
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D1
type_infered: string

tool: D11: The decimal number %d in binary is: 

tool: D1: %d

assistant: ```c
void dec2bin(int decimal) {
  int remainder[32];
  int quocient = decimal, i = 0;
  while (quocient >= 2) {
    remainder[i] = quocient % 2;
    quocient = quocient / 2;
    i++;
  }
  remainder[i] = quocient;
  printf("The decimal number %d in binary is: ", decimal);
  while (i >= 0) {
    printf("%d", remainder[i]);
    i--;
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dec2bin>:
  endbr64
  push   %r12
  mov    %edi,%esi
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  mov    %edi,%eax
  cmp    $0x1,%edi
  jle    L47
  mov    $0x1,%edx
  mov    %rsp,%rbp
  nopl   (%rax)
L17:
  mov    %eax,%ecx
  sar    %eax
  and    $0x1,%ecx
  mov    %ecx,-0x4(%rbp,%rdx,4)
  mov    %edx,%ecx
  add    $0x1,%rdx
  cmp    $0x1,%eax
  jne    L17
L19:
  movslq %ecx,%rbx
  lea    D4(%rip),%rdi
  lea    -0x4(%rsp),%r12
  mov    %eax,(%rsp,%rbx,4)
  xor    %eax,%eax
  lea    0x0(%rbp,%rbx,4),%rbx
  lea    D6(%rip),%rbp
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x90,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
  nopl   (%rax)
L47:
  xor    %ecx,%ecx
  mov    %rsp,%rbp
  jmp    L19
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D4: The decimal number %d in binary is: 

tool: D6: %d

assistant: ```c
void dec2bin(int decimal) {
  int remainder[32];
  int quocient = decimal, i = 0;
  while (quocient >= 2) {
    remainder[i] = quocient % 2;
    quocient = quocient / 2;
    i++;
  }
  remainder[i] = quocient;
  printf("The decimal number %d in binary is: ", decimal);
  while (i >= 0) {
    printf("%d", remainder[i]);
    i--;
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_equal@plt>
  test   %eax,%eax
  jne    L27
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L27:
  mov    $0x0,%eax
  call   <test_reverse_empty@plt>
  test   %eax,%eax
  jne    L10
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    $0x0,%eax
  call   <test_reverse_single_char@plt>
  test   %eax,%eax
  jne    L19
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    $0x0,%eax
  call   <test_reverse_odd_chars@plt>
  test   %eax,%eax
  jne    L13
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    $0x0,%eax
  call   <test_reverse_even_chars@plt>
  test   %eax,%eax
  jne    L3
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D49
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string
name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D33
type_infered: string

tool: D29: String equality test failed!

tool: D14: Reverse empty string test failed!

tool: D49: Reverse single character string test failed!

tool: D15: Reverse odd characters string test failed!

tool: D37: Reverse even characters string test failed!

tool: D33: %d tests failed.


assistant: ```c
int main() {
  int counter = 0;
  if (!test_equal()) {
    printf("String equality test failed!\n");
    counter++;
  }
  if (!test_reverse_empty()) {
    printf("Reverse empty string test failed!\n");
    counter++;
  }
  if (!test_reverse_single_char()) {
    printf("Reverse single character string test failed!\n");
    counter++;
  }
  if (!test_reverse_odd_chars()) {
    printf("Reverse odd characters string test failed!\n");
    counter++;
  }
  if (!test_reverse_even_chars()) {
    printf("Reverse even characters string test failed!\n");
    counter++;
  }
  printf("%d tests failed.\n", counter);
}
```