ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<compat_strndup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %r12,%rax
  cmovbe %rax,%r12
  lea    0x1(%r12),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *compat_strndup(const char *s, size_t n) {
  char *result;
  size_t len = strlen(s);
  if (n < len)
    len = n;
  result = (char *)malloc(len + 1);
  if (!result)
    return 0;
  result[len] = '\0';
  return (char *)memcpy(result, s, len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compat_strndup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %r12,%rax
  cmovbe %rax,%r12
  lea    0x1(%r12),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *compat_strndup(const char *s, size_t n) {
  char *result;
  size_t len = strlen(s);
  if (n < len)
    len = n;
  result = (char *)malloc(len + 1);
  if (!result)
    return 0;
  result[len] = '\0';
  return (char *)memcpy(result, s, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aio_return>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
ssize_t aio_return(struct aiocb *cb) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<aio_return>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t aio_return(struct aiocb *cb) {
  errno = ENOSYS;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<aio_return>:
  endbr64
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t aio_return(struct aiocb *cb) {
  errno = ENOSYS;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aio_return>:
  endbr64
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t aio_return(struct aiocb *cb) {
  errno = ENOSYS;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get64bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x20(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    $0x38,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff000000,%eax
  or     %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  and    $0xff0000,%eax
  mov    %edx,%esi
  or     %eax,%esi
  mov    -0xc(%rbp),%eax
  mov    $0x28,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  and    $0xff00,%eax
  or     %eax,%esi
  mov    -0xc(%rbp),%eax
  mov    $0x38,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  movzbl %al,%eax
  or     %esi,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
uint64_t get64bit(const uint8_t **ptr) {
  uint64_t t64;
  memcpy(&t64, *ptr, 8);
  (*ptr) += 8;
  return ((((t64) << 56) & 0xFF00000000000000) | (((t64) << 40) & 0xFF000000000000) | (((t64) << 24) & 0xFF0000000000) | (((t64) << 8) & 0xFF00000000) | (((t64) >> 8) & 0xFF000000) | (((t64) >> 24) & 0xFF0000) | (((t64) >> 40) & 0xFF00) | (((t64) >> 56) & 0xFF));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get64bit>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x8,%edx
  mov    (%rbx),%rsi
  call   <memcpy@plt>
  addq   $0x20,(%rbx)
  mov    0x4(%rsp),%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  and    $0xff000000,%eax
  mov    %edx,%ecx
  sar    $0x18,%ecx
  and    $0xff0000,%ecx
  or     %ecx,%eax
  mov    %edx,%esi
  mov    $0x28,%ecx
  sar    %cl,%esi
  mov    %esi,%ecx
  and    $0xff00,%ecx
  or     %ecx,%eax
  mov    $0x38,%ecx
  sar    %cl,%edx
  movzbl %dl,%edx
  or     %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get64bit(const uint8_t **ptr) {
  uint64_t t64;
  memcpy(&t64, *ptr, 8);
  (*ptr) += 8;
  return ((((t64) << 56) & 0xFF00000000000000) | (((t64) << 40) & 0xFF000000000000) | (((t64) << 24) & 0xFF0000000000) | (((t64) << 8) & 0xFF00000000) | (((t64) >> 8) & 0xFF000000) | (((t64) >> 24) & 0xFF0000) | (((t64) >> 40) & 0xFF00) | (((t64) >> 56) & 0xFF));
}
```
user: Translate the below assembly code into C programming language:

```asm
<get64bit>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edx
  sub    $0x10,%rsp
  mov    (%rbx),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%edx
  addq   $0x20,(%rbx)
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x8,%eax
  sar    $0x18,%ecx
  and    $0xff0000,%ecx
  and    $0xff000000,%eax
  or     %ecx,%eax
  mov    $0x28,%ecx
  sar    %cl,%esi
  mov    %esi,%ecx
  and    $0xff00,%ecx
  or     %ecx,%eax
  mov    $0x38,%ecx
  sar    %cl,%edx
  movzbl %dl,%edx
  or     %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get64bit(const uint8_t **ptr) {
  uint64_t t64;
  memcpy(&t64, *ptr, 8);
  (*ptr) += 8;
  return ((((t64) << 56) & 0xFF00000000000000) | (((t64) << 40) & 0xFF000000000000) | (((t64) << 24) & 0xFF0000000000) | (((t64) << 8) & 0xFF00000000) | (((t64) >> 8) & 0xFF000000) | (((t64) >> 24) & 0xFF0000) | (((t64) >> 40) & 0xFF00) | (((t64) >> 56) & 0xFF));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get64bit>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edx
  sub    $0x10,%rsp
  mov    (%rbx),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%edx
  addq   $0x20,(%rbx)
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x8,%eax
  sar    $0x18,%ecx
  and    $0xff0000,%ecx
  and    $0xff000000,%eax
  or     %ecx,%eax
  mov    $0x28,%ecx
  sar    %cl,%esi
  mov    %esi,%ecx
  and    $0xff00,%ecx
  or     %ecx,%eax
  mov    $0x38,%ecx
  sar    %cl,%edx
  movzbl %dl,%edx
  or     %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get64bit(const uint8_t **ptr) {
  uint64_t t64;
  memcpy(&t64, *ptr, 8);
  (*ptr) += 8;
  return ((((t64) << 56) & 0xFF00000000000000) | (((t64) << 40) & 0xFF000000000000) | (((t64) << 24) & 0xFF0000000000) | (((t64) << 8) & 0xFF00000000) | (((t64) >> 8) & 0xFF000000) | (((t64) >> 24) & 0xFF0000) | (((t64) >> 40) & 0xFF00) | (((t64) >> 56) & 0xFF));
}
```
user: What is the c source code of the assembly code below?

```asm
<stbi__malloc_mad4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    -0x14(%rbp),%edi
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <stbi__mad4sizes_valid@plt>
  test   %eax,%eax
  jne    L13
  mov    $0x0,%eax
  jmp    L17
L13:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  imul   -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <stbi__malloc@plt>
L17:
  leave
  ret
```

assistant: ```c
void *stbi__malloc_mad4(int a, int b, int c, int d, int add) {
  if (!stbi__mad4sizes_valid(a, b, c, d, add))
    return NULL;
  return stbi__malloc(a * b * c * d + add);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stbi__malloc_mad4>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r14d
  mov    %edx,%r13d
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  call   <stbi__mad4sizes_valid@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L5
  imul   %r14d,%ebx
  mov    %ebx,%edi
  imul   %r13d,%edi
  imul   %r12d,%edi
  add    %ebp,%edi
  call   <stbi__malloc@plt>
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *stbi__malloc_mad4(int a, int b, int c, int d, int add) {
  if (!stbi__mad4sizes_valid(a, b, c, d, add))
    return NULL;
  return stbi__malloc(a * b * c * d + add);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi__malloc_mad4>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %edi,%ebx
  call   <stbi__mad4sizes_valid@plt>
  test   %eax,%eax
  je     L2
  imul   %r14d,%ebx
  imul   %r13d,%ebx
  imul   %r12d,%ebx
  lea    (%rbx,%rbp,1),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <stbi__malloc@plt>
  nop
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *stbi__malloc_mad4(int a, int b, int c, int d, int add) {
  if (!stbi__mad4sizes_valid(a, b, c, d, add))
    return NULL;
  return stbi__malloc(a * b * c * d + add);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stbi__malloc_mad4>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %edi,%ebx
  call   <stbi__mad4sizes_valid@plt>
  test   %eax,%eax
  je     L8
  imul   %r14d,%ebx
  imul   %r13d,%ebx
  imul   %r12d,%ebx
  lea    (%rbx,%rbp,1),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <stbi__malloc@plt>
  nop
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *stbi__malloc_mad4(int a, int b, int c, int d, int add) {
  if (!stbi__mad4sizes_valid(a, b, c, d, add))
    return NULL;
  return stbi__malloc(a * b * c * d + add);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strrlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L2:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int strrlen(char *s) {
  char *p = s;
  while (*p)
    p++;
  return p - s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  mov    %rdi,%rax
L17:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L17
L6:
  sub    %edi,%eax
  ret
L4:
  mov    %rdi,%rax
  jmp    L6
```

assistant: ```c
int strrlen(char *s) {
  char *p = s;
  while (*p)
    p++;
  return p - s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L13
  mov    %rdi,%rax
  nopl   0x0(%rax)
L2:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L2
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strrlen(char *s) {
  char *p = s;
  while (*p)
    p++;
  return p - s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  mov    %rdi,%rax
  nopl   0x0(%rax)
L10:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L10
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strrlen(char *s) {
  char *p = s;
  while (*p)
    p++;
  return p - s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<zero_to_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movsbq -0x14(%rbp),%rax
  and    $0xf,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string

tool: D4: 0123456789abcdef

assistant: ```c
char zero_to_f(char c) {
  const char *hex = "0123456789abcdef";
  return hex[c & 15];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zero_to_f>:
  endbr64
  and    $0xf,%edi
  lea    D5(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: 0123456789abcdef

assistant: ```c
char zero_to_f(char c) {
  const char *hex = "0123456789abcdef";
  return hex[c & 15];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zero_to_f>:
  endbr64
  and    $0xf,%edi
  lea    D3(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: 0123456789abcdef

assistant: ```c
char zero_to_f(char c) {
  const char *hex = "0123456789abcdef";
  return hex[c & 15];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zero_to_f>:
  endbr64
  and    $0xf,%edi
  lea    D4(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: 0123456789abcdef

assistant: ```c
char zero_to_f(char c) {
  const char *hex = "0123456789abcdef";
  return hex[c & 15];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<validate_tar_registers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x20(%rbp)
  je     L10
  movl   $0x0,-0x4(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  je     L15
  movl   $0x0,-0x4(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x30(%rbp)
  je     L23
  movl   $0x0,-0x4(%rbp)
L23:
  cmpl   $0x0,-0x4(%rbp)
  jne    L39
  mov    $0x1,%eax
  jmp    L44
L39:
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
int validate_tar_registers(unsigned long *reg, unsigned long tar, unsigned long ppr, unsigned long dscr) {
  int match = 1;
  if (reg[0] != tar)
    match = 0;
  if (reg[1] != ppr)
    match = 0;
  if (reg[2] != dscr)
    match = 0;
  if (!match)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<validate_tar_registers>:
  endbr64
  mov    %rdx,%rax
  mov    $0x0,%edx
  cmp    %rax,0x8(%rdi)
  je     L8
L0:
  cmp    %rcx,0x10(%rdi)
  setne  %al
  test   %edx,%edx
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
L8:
  cmp    %rsi,(%rdi)
  sete   %dl
  movzbl %dl,%edx
  jmp    L0
```

assistant: ```c
int validate_tar_registers(unsigned long *reg, unsigned long tar, unsigned long ppr, unsigned long dscr) {
  int match = 1;
  if (reg[0] != tar)
    match = 0;
  if (reg[1] != ppr)
    match = 0;
  if (reg[2] != dscr)
    match = 0;
  if (!match)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<validate_tar_registers>:
  endbr64
  mov    $0x1,%eax
  cmp    %rsi,(%rdi)
  je     L12
L5:
  ret
  nop
L12:
  cmp    0x8(%rdi),%rdx
  jne    L5
  xor    %eax,%eax
  cmp    %rcx,0x10(%rdi)
  setne  %al
  ret
```

assistant: ```c
int validate_tar_registers(unsigned long *reg, unsigned long tar, unsigned long ppr, unsigned long dscr) {
  int match = 1;
  if (reg[0] != tar)
    match = 0;
  if (reg[1] != ppr)
    match = 0;
  if (reg[2] != dscr)
    match = 0;
  if (!match)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<validate_tar_registers>:
  endbr64
  mov    $0x1,%eax
  cmp    %rsi,(%rdi)
  je     L2
L14:
  ret
  nop
L2:
  cmp    0x8(%rdi),%rdx
  jne    L14
  xor    %eax,%eax
  cmp    %rcx,0x10(%rdi)
  setne  %al
  ret
```

assistant: ```c
int validate_tar_registers(unsigned long *reg, unsigned long tar, unsigned long ppr, unsigned long dscr) {
  int match = 1;
  if (reg[0] != tar)
    match = 0;
  if (reg[1] != ppr)
    match = 0;
  if (reg[2] != dscr)
    match = 0;
  if (!match)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_sr_access>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1f,-0x4(%rbp)
  jbe    L4
  mov    $0x0,%eax
  call   <sim_internal_fail@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void check_sr_access(unsigned int regnum) {
  if (regnum > 31) {
    sim_internal_fail();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_sr_access>:
  endbr64
  cmp    $0x1f,%edi
  ja     L2
  ret
L2:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sim_internal_fail@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void check_sr_access(unsigned int regnum) {
  if (regnum > 31) {
    sim_internal_fail();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_sr_access>:
  endbr64
  cmp    $0x1f,%edi
  ja     L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  jmp    1050 <sim_internal_fail@plt>
```

assistant: ```c
void check_sr_access(unsigned int regnum) {
  if (regnum > 31) {
    sim_internal_fail();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_sr_access>:
  endbr64
  cmp    $0x1f,%edi
  ja     L3
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  jmp    1050 <sim_internal_fail@plt>
```

assistant: ```c
void check_sr_access(unsigned int regnum) {
  if (regnum > 31) {
    sim_internal_fail();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long f(int *a, int *b, int *c) {
  long long d = (((long long)*a) * *b);
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  movslq (%rdi),%rax
  movslq (%rsi),%rdx
  imul   %rdx,%rax
  ret
```

assistant: ```c
long long f(int *a, int *b, int *c) {
  long long d = (((long long)*a) * *b);
  return d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  movslq (%rdi),%rax
  movslq (%rsi),%rdx
  imul   %rdx,%rax
  ret
```

assistant: ```c
long long f(int *a, int *b, int *c) {
  long long d = (((long long)*a) * *b);
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  movslq (%rdi),%rax
  movslq (%rsi),%rdx
  imul   %rdx,%rax
  ret
```

assistant: ```c
long long f(int *a, int *b, int *c) {
  long long d = (((long long)*a) * *b);
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cacguard2l_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edi
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <cacguard2l@plt>
  nop
  leave
  ret
```

assistant: ```c
void cacguard2l_(float *cu, int *nx, int *ny, int *nxe, int *nye) {
  cacguard2l(cu, *nx, *ny, *nxe, *nye);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cacguard2l_>:
  endbr64
  sub    $0x8,%rsp
  mov    (%r8),%r8d
  mov    (%rcx),%ecx
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  call   <cacguard2l@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cacguard2l_(float *cu, int *nx, int *ny, int *nxe, int *nye) {
  cacguard2l(cu, *nx, *ny, *nxe, *nye);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cacguard2l_>:
  endbr64
  mov    (%r8),%r8d
  mov    (%rcx),%ecx
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  jmp    1050 <cacguard2l@plt>
```

assistant: ```c
void cacguard2l_(float *cu, int *nx, int *ny, int *nxe, int *nye) {
  cacguard2l(cu, *nx, *ny, *nxe, *nye);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cacguard2l_>:
  endbr64
  mov    (%r8),%r8d
  mov    (%rcx),%ecx
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  jmp    1050 <cacguard2l@plt>
```

assistant: ```c
void cacguard2l_(float *cu, int *nx, int *ny, int *nxe, int *nye) {
  cacguard2l(cu, *nx, *ny, *nxe, *nye);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0xffffffff,-0x30(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L55
L10:
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L55:
  cmpl   $0x7,-0x34(%rbp)
  jle    L10
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L56:
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  cmp    $0x1,%eax
  je     L64
  mov    -0x3c(%rbp),%eax
  test   %eax,%eax
  jne    L56
L64:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  js     L64
  mov    -0x38(%rbp),%eax
  cmp    $0x7,%eax
  jg     L64
  mov    -0x38(%rbp),%ecx
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%eax
  lea    -0x30(%rbp),%rsi
  mov    %eax,%edi
  call   <convert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D27
type: string

tool: D27: %d

assistant: ```c
int main() {
  int i, n, v, p;
  int bin[8] = {-1};
  for (i = 0; i < 8; i++) {
    bin[i] = (0);
  }
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v != 1 && v != 0);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  convert(n, bin, v, p);
  return 0;
}
```