ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<putbitchar>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r14
  movzbl %dil,%edi
  lea    0x0(,%rdi,8),%eax
  mov    %eax,0x4(%rsp)
  lea    0x8(%rdx),%r15
  mov    %rdx,%r13
  mov    $0xffa6e,%eax
  sub    %rdx,%rax
  mov    %rax,0x8(%rsp)
  jmp    L53
L3:
  add    $0x1,%rbx
  cmp    $0x8,%rbx
  je     L31
L17:
  mov    %ebp,%ecx
  sub    %ebx,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %al,%r12b
  je     L3
  lea    (%r14,%rbx,1),%rsi
  mov    %r13,%rdx
  mov    $0xdb,%edi
  call   <putasc@plt>
  jmp    L3
L31:
  add    $0x1,%r13
  cmp    %r15,%r13
  je     L51
L53:
  movslq 0x4(%rsp),%rax
  mov    0x8(%rsp),%rdi
  lea    0x0(%r13,%rdi,1),%rdx
  movzbl (%rdx,%rax,1),%r12d
  mov    $0x0,%ebx
  mov    $0x7,%ebp
  jmp    L17
L51:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void putbitchar(unsigned char c, long x, long y) {
  unsigned char *pbit;
  unsigned char tbit, cbit = *pbit;
  unsigned long i, j;
  i = c * 8;
  i += 0xFFA6E;
  pbit = (char *)i;
  for (j = 0; j < 8; j++) {
    cbit = *(pbit + j);
    for (i = 0; i < 8; i++) {
      tbit = cbit & (1 << (7 - i));
      if (tbit != 0) {
        putasc(219, x + i, y + j);
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putbitchar>:
  endbr64
  push   %r15
  lea    0x8(%rdx),%rax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    $0xffa6e,%r13d
  push   %r12
  lea    0x0(,%rdi,8),%r12
  sub    %rdx,%r13
  push   %rbp
  and    $0x7f8,%r12d
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,(%rsp)
  mov    %r12,0x8(%rsp)
  nopl   (%rax)
L25:
  mov    0x8(%rsp),%rdi
  lea    (%r14,%r13,1),%rax
  xor    %ebx,%ebx
  mov    $0x7,%r15d
  movzbl (%rax,%rdi,1),%r12d
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rbx
  cmp    $0x8,%rbx
  je     L45
L15:
  mov    %r15d,%ecx
  mov    $0x1,%eax
  sub    %ebx,%ecx
  shl    %cl,%eax
  test   %al,%r12b
  je     L16
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    %r14,%rdx
  mov    $0xdb,%edi
  add    $0x1,%rbx
  call   <putasc@plt>
  cmp    $0x8,%rbx
  jne    L15
L45:
  add    $0x1,%r14
  cmp    (%rsp),%r14
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void putbitchar(unsigned char c, long x, long y) {
  unsigned char *pbit;
  unsigned char tbit, cbit = *pbit;
  unsigned long i, j;
  i = c * 8;
  i += 0xFFA6E;
  pbit = (char *)i;
  for (j = 0; j < 8; j++) {
    cbit = *(pbit + j);
    for (i = 0; i < 8; i++) {
      tbit = cbit & (1 << (7 - i));
      if (tbit != 0) {
        putasc(219, x + i, y + j);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<putbitchar>:
  endbr64
  push   %r15
  lea    0x8(%rdx),%r15
  push   %r14
  mov    $0xffa6e,%r14d
  push   %r13
  lea    0x0(,%rdi,8),%r13
  sub    %rdx,%r14
  push   %r12
  and    $0x7f8,%r13d
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L171
  cs nopw 0x0(%rax,%rax,1)
L81:
  test   $0x40,%bl
  jne    L97
L165:
  test   $0x20,%bl
  jne    L135
L109:
  test   $0x10,%bl
  jne    L27
L17:
  test   $0x8,%bl
  jne    L92
L66:
  test   $0x4,%bl
  jne    L98
L145:
  test   $0x2,%bl
  jne    L65
L43:
  and    $0x1,%ebx
  jne    L121
L154:
  add    $0x1,%rbp
  cmp    %rbp,%r15
  je     L123
L171:
  lea    0x0(%rbp,%r14,1),%rax
  movzbl (%rax,%r13,1),%ebx
  test   %bl,%bl
  jns    L81
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0xdb,%edi
  call   <putasc@plt>
  test   $0x40,%bl
  je     L165
L97:
  lea    0x1(%r12),%rsi
  mov    %rbp,%rdx
  mov    $0xdb,%edi
  call   <putasc@plt>
  test   $0x20,%bl
  je     L109
L135:
  lea    0x2(%r12),%rsi
  mov    %rbp,%rdx
  mov    $0xdb,%edi
  call   <putasc@plt>
  test   $0x10,%bl
  je     L17
L27:
  lea    0x3(%r12),%rsi
  mov    %rbp,%rdx
  mov    $0xdb,%edi
  call   <putasc@plt>
  test   $0x8,%bl
  je     L66
L92:
  lea    0x4(%r12),%rsi
  mov    %rbp,%rdx
  mov    $0xdb,%edi
  call   <putasc@plt>
  test   $0x4,%bl
  je     L145
L98:
  lea    0x5(%r12),%rsi
  mov    %rbp,%rdx
  mov    $0xdb,%edi
  call   <putasc@plt>
  test   $0x2,%bl
  je     L43
L65:
  lea    0x6(%r12),%rsi
  mov    %rbp,%rdx
  mov    $0xdb,%edi
  call   <putasc@plt>
  and    $0x1,%ebx
  je     L154
L121:
  mov    %rbp,%rdx
  lea    0x7(%r12),%rsi
  mov    $0xdb,%edi
  add    $0x1,%rbp
  call   <putasc@plt>
  cmp    %rbp,%r15
  jne    L171
L123:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void putbitchar(unsigned char c, long x, long y) {
  unsigned char *pbit;
  unsigned char tbit, cbit = *pbit;
  unsigned long i, j;
  i = c * 8;
  i += 0xFFA6E;
  pbit = (char *)i;
  for (j = 0; j < 8; j++) {
    cbit = *(pbit + j);
    for (i = 0; i < 8; i++) {
      tbit = cbit & (1 << (7 - i));
      if (tbit != 0) {
        putasc(219, x + i, y + j);
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_trmread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xff,%edx
  lea    D26(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    D26(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D26(%rip),%rax
  jmp    L17
L3:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
char *ft_trmread(void) {
  int len;
  static char buffer[256];
  if ((len = read(0, buffer, 255))) {
    buffer[len] = '\0';
    return (buffer);
  }
  return (NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_trmread>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%edx
  lea    D2(%rip),%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    $0x0,%ecx
  test   %eax,%eax
  je     L4
  lea    D2(%rip),%rcx
  movslq %eax,%rdx
  movb   $0x0,(%rcx,%rdx,1)
L4:
  mov    %rcx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *ft_trmread(void) {
  int len;
  static char buffer[256];
  if ((len = read(0, buffer, 255))) {
    buffer[len] = '\0';
    return (buffer);
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_trmread>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  mov    $0xff,%edx
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <read@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  je     L3
  cltq
  mov    %rbx,%r8
  movb   $0x0,(%rbx,%rax,1)
L3:
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ft_trmread(void) {
  int len;
  static char buffer[256];
  if ((len = read(0, buffer, 255))) {
    buffer[len] = '\0';
    return (buffer);
  }
  return (NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_trmread>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  mov    $0xff,%edx
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <read@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  je     L5
  cltq
  mov    %rbx,%r8
  movb   $0x0,(%rbx,%rax,1)
L5:
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ft_trmread(void) {
  int len;
  static char buffer[256];
  if ((len = read(0, buffer, 255))) {
    buffer[len] = '\0';
    return (buffer);
  }
  return (NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <Welcome@plt>
  lea    -0x10(%rbp),%rdi
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <ParseArgs@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <Simulate@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  const char *inputFile = NULL;
  const char *pathlossFile = NULL;
  const char *logFile = NULL;
  Welcome();
  ParseArgs(argc, argv, &inputFile, &pathlossFile, &logFile);
  return Simulate(inputFile, pathlossFile, logFile);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <Welcome@plt>
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x10(%rsp),%r8
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <ParseArgs@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <Simulate@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  const char *inputFile = NULL;
  const char *pathlossFile = NULL;
  const char *logFile = NULL;
  Welcome();
  ParseArgs(argc, argv, &inputFile, &pathlossFile, &logFile);
  return Simulate(inputFile, pathlossFile, logFile);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <Welcome@plt>
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%r8
  call   <ParseArgs@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <Simulate@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  const char *inputFile = NULL;
  const char *pathlossFile = NULL;
  const char *logFile = NULL;
  Welcome();
  ParseArgs(argc, argv, &inputFile, &pathlossFile, &logFile);
  return Simulate(inputFile, pathlossFile, logFile);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <Welcome@plt>
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%r8
  call   <ParseArgs@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <Simulate@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  const char *inputFile = NULL;
  const char *pathlossFile = NULL;
  const char *logFile = NULL;
  Welcome();
  ParseArgs(argc, argv, &inputFile, &pathlossFile, &logFile);
  return Simulate(inputFile, pathlossFile, logFile);
}
```
user: Translate the below assembly code into C programming language:

```asm
<zipDecodeLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <zipEntryEncoding@plt>
  mov    %al,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  movzbl -0x5(%rbp),%eax
  and    $0xc0,%eax
  cmp    $0xbf,%eax
  jg     L88
  movzbl -0x5(%rbp),%eax
  cmp    $0x80,%eax
  je     L66
  cmp    $0x80,%eax
  jg     L163
  test   %eax,%eax
  je     L31
  cmp    $0x40,%eax
  je     L162
  jmp    L163
L31:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x3f,%eax
  mov    %eax,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L62
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L62
L162:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  and    $0x3f00,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L77
  mov    -0x20(%rbp),%rax
  movl   $0x2,(%rax)
  jmp    L77
L66:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L65
  mov    -0x20(%rbp),%rax
  movl   $0x5,(%rax)
  jmp    L65
L163:
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L164
L88:
  movzbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <zipIntSize@plt>
  mov    %eax,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L164
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L164
L62:
  nop
  jmp    L164
L77:
  nop
  jmp    L164
L65:
  nop
L164:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int zipDecodeLength(unsigned char *p, unsigned int *lensize) {
  unsigned char encoding = zipEntryEncoding(p);
  unsigned int len = 0;
  if ((((encoding)&0xc0) < 0xc0)) {
    switch (encoding) {
    case (0 << 6):
      len = p[0] & 0x3f;
      if (lensize)
        *lensize = 1;
      break;
    case (1 << 6):
      len = ((p[0] & 0x3f) << 8) | p[1];
      if (lensize)
        *lensize = 2;
      break;
    case (2 << 6):
      len = (p[1] << 24) | (p[2] << 16) | (p[3] << 8) | p[4];
      if (lensize)
        *lensize = 5;
      break;
    default:
      assert(NULL);
    }
  } else {
    len = zipIntSize(encoding);
    if (lensize)
      *lensize = 1;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<zipDecodeLength>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <zipEntryEncoding@plt>
  mov    %eax,%edx
  and    $0xffffffc0,%edx
  cmp    $0xbf,%dl
  ja     L53
  cmp    $0x40,%al
  je     L109
  cmp    $0x80,%al
  je     L42
  test   %al,%al
  je     L90
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  jmp    L38
L90:
  movzbl 0x0(%rbp),%eax
  and    $0x3f,%eax
  test   %rbx,%rbx
  je     L38
  movl   $0x1,(%rbx)
  jmp    L38
L109:
  movzbl 0x0(%rbp),%eax
  shl    $0x8,%eax
  and    $0x3f00,%eax
  movzbl 0x1(%rbp),%edx
  or     %edx,%eax
  test   %rbx,%rbx
  je     L38
  movl   $0x2,(%rbx)
  jmp    L38
L42:
  movzbl 0x1(%rbp),%eax
  shl    $0x18,%eax
  movzbl 0x2(%rbp),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  movzbl 0x4(%rbp),%edx
  or     %edx,%eax
  movzbl 0x3(%rbp),%edx
  shl    $0x8,%edx
  or     %edx,%eax
  test   %rbx,%rbx
  je     L38
  movl   $0x5,(%rbx)
  jmp    L38
L53:
  movzbl %al,%edi
  call   <zipIntSize@plt>
  test   %rbx,%rbx
  je     L38
  movl   $0x1,(%rbx)
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zipDecodeLength(unsigned char *p, unsigned int *lensize) {
  unsigned char encoding = zipEntryEncoding(p);
  unsigned int len = 0;
  if ((((encoding)&0xc0) < 0xc0)) {
    switch (encoding) {
    case (0 << 6):
      len = p[0] & 0x3f;
      if (lensize)
        *lensize = 1;
      break;
    case (1 << 6):
      len = ((p[0] & 0x3f) << 8) | p[1];
      if (lensize)
        *lensize = 2;
      break;
    case (2 << 6):
      len = (p[1] << 24) | (p[2] << 16) | (p[3] << 8) | p[4];
      if (lensize)
        *lensize = 5;
      break;
    default:
      assert(NULL);
    }
  } else {
    len = zipIntSize(encoding);
    if (lensize)
      *lensize = 1;
  }
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zipDecodeLength>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <zipEntryEncoding@plt>
  mov    %eax,%edx
  and    $0xffffffc0,%edx
  cmp    $0xc0,%dl
  je     L82
  cmp    $0x40,%al
  je     L85
  cmp    $0x80,%al
  je     L86
  test   %al,%al
  je     L70
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
L71:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L82:
  movzbl %al,%edi
  call   <zipIntSize@plt>
  test   %rbp,%rbp
  je     L71
  movl   $0x1,0x0(%rbp)
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  movzbl (%rbx),%eax
  and    $0x3f,%eax
  test   %rbp,%rbp
  je     L71
  movl   $0x1,0x0(%rbp)
  jmp    L20
  nopl   0x0(%rax)
L85:
  movzbl (%rbx),%eax
  movzbl 0x1(%rbx),%edx
  shl    $0x8,%eax
  and    $0x3f00,%eax
  or     %edx,%eax
  test   %rbp,%rbp
  je     L71
  movl   $0x2,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L86:
  mov    0x1(%rbx),%eax
  bswap  %eax
  test   %rbp,%rbp
  je     L71
  movl   $0x5,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zipDecodeLength(unsigned char *p, unsigned int *lensize) {
  unsigned char encoding = zipEntryEncoding(p);
  unsigned int len = 0;
  if ((((encoding)&0xc0) < 0xc0)) {
    switch (encoding) {
    case (0 << 6):
      len = p[0] & 0x3f;
      if (lensize)
        *lensize = 1;
      break;
    case (1 << 6):
      len = ((p[0] & 0x3f) << 8) | p[1];
      if (lensize)
        *lensize = 2;
      break;
    case (2 << 6):
      len = (p[1] << 24) | (p[2] << 16) | (p[3] << 8) | p[4];
      if (lensize)
        *lensize = 5;
      break;
    default:
      assert(NULL);
    }
  } else {
    len = zipIntSize(encoding);
    if (lensize)
      *lensize = 1;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zipDecodeLength>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <zipEntryEncoding@plt>
  mov    %eax,%edx
  and    $0xffffffc0,%edx
  cmp    $0xc0,%dl
  je     L89
  cmp    $0x40,%al
  je     L65
  cmp    $0x80,%al
  je     L53
  test   %al,%al
  je     L41
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L89:
  movzbl %al,%edi
  call   <zipIntSize@plt>
  test   %rbp,%rbp
  je     L43
  movl   $0x1,0x0(%rbp)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  movzbl (%rbx),%eax
  and    $0x3f,%eax
  test   %rbp,%rbp
  je     L43
  movl   $0x1,0x0(%rbp)
  jmp    L0
  nopl   0x0(%rax)
L65:
  movzbl (%rbx),%eax
  movzbl 0x1(%rbx),%edx
  shl    $0x8,%eax
  and    $0x3f00,%eax
  or     %edx,%eax
  test   %rbp,%rbp
  je     L43
  movl   $0x2,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L53:
  mov    0x1(%rbx),%eax
  bswap  %eax
  test   %rbp,%rbp
  je     L43
  movl   $0x5,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zipDecodeLength(unsigned char *p, unsigned int *lensize) {
  unsigned char encoding = zipEntryEncoding(p);
  unsigned int len = 0;
  if ((((encoding)&0xc0) < 0xc0)) {
    switch (encoding) {
    case (0 << 6):
      len = p[0] & 0x3f;
      if (lensize)
        *lensize = 1;
      break;
    case (1 << 6):
      len = ((p[0] & 0x3f) << 8) | p[1];
      if (lensize)
        *lensize = 2;
      break;
    case (2 << 6):
      len = (p[1] << 24) | (p[2] << 16) | (p[3] << 8) | p[4];
      if (lensize)
        *lensize = 5;
      break;
    default:
      assert(NULL);
    }
  } else {
    len = zipIntSize(encoding);
    if (lensize)
      *lensize = 1;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_upper_case>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpb   $0x40,-0x14(%rbp)
  jle    L18
  cmpb   $0x5a,-0x14(%rbp)
  jg     L18
  movl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_upper_case(char ch) {
  int flag = 0;
  if (ch >= 'A' && ch <= 'Z')
    flag = 1;
  return flag;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_upper_case>:
  endbr64
  sub    $0x41,%edi
  cmp    $0x19,%dil
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_upper_case(char ch) {
  int flag = 0;
  if (ch >= 'A' && ch <= 'Z')
    flag = 1;
  return flag;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_upper_case>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x19,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_upper_case(char ch) {
  int flag = 0;
  if (ch >= 'A' && ch <= 'Z')
    flag = 1;
  return flag;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_upper_case>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x19,%dil
  setbe  %al
  ret
```

assistant: ```c
int is_upper_case(char ch) {
  int flag = 0;
  if (ch >= 'A' && ch <= 'Z')
    flag = 1;
  return flag;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<padcon_get_quaddobl_series_step>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x18(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x375,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int padcon_get_quaddobl_series_step(double *step) {
  int fail;
  int precision = 2;
  int *b;
  fail = _ada_use_c2phc4c(885, &precision, b, step, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<padcon_get_quaddobl_series_step>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x2,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x375,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_quaddobl_series_step(double *step) {
  int fail;
  int precision = 2;
  int *b;
  fail = _ada_use_c2phc4c(885, &precision, b, step, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<padcon_get_quaddobl_series_step>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x375,%edi
  movl   $0x2,0x4(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_quaddobl_series_step(double *step) {
  int fail;
  int precision = 2;
  int *b;
  fail = _ada_use_c2phc4c(885, &precision, b, step, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<padcon_get_quaddobl_series_step>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x375,%edi
  movl   $0x2,0x4(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_quaddobl_series_step(double *step) {
  int fail;
  int precision = 2;
  int *b;
  fail = _ada_use_c2phc4c(885, &precision, b, step, 0);
  return fail;
}
```