ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L0
L62:
  movss  -0x68(%rbp),%xmm0
  comiss D17(%rip),%xmm0
  ja     L57
  jmp    L0
L57:
  movss  -0x68(%rbp),%xmm1
  movss  D41(%rip),%xmm0
  comiss %xmm1,%xmm0
  ja     L4
  jmp    L0
L4:
  movss  -0x64(%rbp),%xmm0
  comiss D43(%rip),%xmm0
  ja     L17
  jmp    L0
L17:
  movss  -0x64(%rbp),%xmm1
  movss  D23(%rip),%xmm0
  comiss %xmm1,%xmm0
  ja     L6
  jmp    L0
L6:
  movss  -0x64(%rbp),%xmm0
  mov    -0x68(%rbp),%eax
  lea    -0x60(%rbp),%rdx
  mov    %rdx,%rsi
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  lea    -0x60(%rbp),%rcx
  lea    -0x64(%rbp),%rdx
  lea    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  je     L62
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: byte[4]
name: retrieve_data
arguments: label: D41
data_type: byte[4]
name: retrieve_data
arguments: label: D43
data_type: byte[4]
name: retrieve_data
arguments: label: D23
data_type: byte[4]
name: retrieve_data
arguments: label: D33
data_type: string
name: retrieve_data
arguments: label: D49
data_type: string

tool: {"D17": [0x00,0x00,0xd0,0x41]}

tool: {"D41": [0x00,0x00,0x08,0x42]}

tool: {"D43": [0x00,0x00,0x98,0xc2]}

tool: {"D23": [0x00,0x00,0x80,0xc2]}

tool: D33: %f, %f, %s


tool: D49: %f, %f, %79[^
]

assistant: ```c
int main() {
  float latitude;
  float longitude;
  char info[80];
  while (scanf("%f, %f, %79[^\n]", &latitude, &longitude, info) == 3) {
    if ((latitude > 26) && (latitude < 34) && (longitude > -76) && (longitude < -64))
      printf("%f, %f, %s\n", latitude, longitude, info);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D50(%rip),%rbx
  lea    D40(%rip),%rbp
L15:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L20
  movss  0x8(%rsp),%xmm0
  comiss D39(%rip),%xmm0
  jbe    L15
  movss  D20(%rip),%xmm2
  comiss %xmm0,%xmm2
  jbe    L15
  movss  0xc(%rsp),%xmm1
  comiss D16(%rip),%xmm1
  jbe    L15
  movss  D3(%rip),%xmm3
  comiss %xmm1,%xmm3
  jbe    L15
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L15
L20:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D50
type_guessed: string
name: disassemble_data
arguments: data_tag: D40
type_guessed: string
name: disassemble_data
arguments: data_tag: D39
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D20
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D16
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D3
type_guessed: byte[4]

tool: D50: %f, %f, %79[^
]

tool: D40: %f, %f, %s


tool: {"D39": [0x00,0x00,0xd0,0x41]}

tool: {"D20": [0x00,0x00,0x08,0x42]}

tool: {"D16": [0x00,0x00,0x98,0xc2]}

tool: {"D3": [0x00,0x00,0x80,0xc2]}

assistant: ```c
int main() {
  float latitude;
  float longitude;
  char info[80];
  while (scanf("%f, %f, %79[^\n]", &latitude, &longitude, info) == 3) {
    if ((latitude > 26) && (latitude < 34) && (longitude > -76) && (longitude < -64))
      printf("%f, %f, %s\n", latitude, longitude, info);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D49(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r12
  nopl   (%rax)
L17:
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L33
  movss  0x8(%rsp),%xmm0
  comiss D51(%rip),%xmm0
  jbe    L17
  movss  D37(%rip),%xmm2
  comiss %xmm0,%xmm2
  jbe    L17
  movss  0xc(%rsp),%xmm1
  comiss D10(%rip),%xmm1
  jbe    L17
  movss  D56(%rip),%xmm3
  comiss %xmm1,%xmm3
  jbe    L17
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L33:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D49
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string
name: parse_data
arguments: data_label: D51
data_type: byte[4]
name: parse_data
arguments: data_label: D37
data_type: byte[4]
name: parse_data
arguments: data_label: D10
data_type: byte[4]
name: parse_data
arguments: data_label: D56
data_type: byte[4]

tool: D49: %f, %f, %s


tool: D4: %f, %f, %79[^
]

tool: {"D51": [0x00,0x00,0xd0,0x41]}

tool: {"D37": [0x00,0x00,0x08,0x42]}

tool: {"D10": [0x00,0x00,0x98,0xc2]}

tool: {"D56": [0x00,0x00,0x80,0xc2]}

assistant: ```c
int main() {
  float latitude;
  float longitude;
  char info[80];
  while (scanf("%f, %f, %79[^\n]", &latitude, &longitude, info) == 3) {
    if ((latitude > 26) && (latitude < 34) && (longitude > -76) && (longitude < -64))
      printf("%f, %f, %s\n", latitude, longitude, info);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D59(%rip),%rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r12
  nopl   (%rax)
L32:
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L56
  movss  0x8(%rsp),%xmm0
  comiss D14(%rip),%xmm0
  jbe    L32
  movss  D58(%rip),%xmm2
  comiss %xmm0,%xmm2
  jbe    L32
  movss  0xc(%rsp),%xmm1
  comiss D26(%rip),%xmm1
  jbe    L32
  movss  D2(%rip),%xmm3
  comiss %xmm1,%xmm3
  jbe    L32
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L56:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string
name: retrieve_data
arguments: tag: D59
type_infered: string
name: retrieve_data
arguments: tag: D14
type_infered: byte[4]
name: retrieve_data
arguments: tag: D58
type_infered: byte[4]
name: retrieve_data
arguments: tag: D26
type_infered: byte[4]
name: retrieve_data
arguments: tag: D2
type_infered: byte[4]

tool: D0: %f, %f, %s


tool: D59: %f, %f, %79[^
]

tool: {"D14": [0x00,0x00,0xd0,0x41]}

tool: {"D58": [0x00,0x00,0x08,0x42]}

tool: {"D26": [0x00,0x00,0x98,0xc2]}

tool: {"D2": [0x00,0x00,0x80,0xc2]}

assistant: ```c
int main() {
  float latitude;
  float longitude;
  char info[80];
  while (scanf("%f, %f, %79[^\n]", &latitude, &longitude, info) == 3) {
    if ((latitude > 26) && (latitude < 34) && (longitude > -76) && (longitude < -64))
      printf("%f, %f, %s\n", latitude, longitude, info);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clear_stdin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L18:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L1
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L18
L1:
  nop
  leave
  ret
```

assistant: ```c
void clear_stdin(void) {
  int c;
  do {
    c = getchar();
  } while (c != '\n' && c != EOF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear_stdin>:
  endbr64
  sub    $0x8,%rsp
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L1
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L0
L1:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void clear_stdin(void) {
  int c;
  do {
    c = getchar();
  } while (c != '\n' && c != EOF);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_stdin>:
  endbr64
  sub    $0x8,%rsp
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L1:
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L25
L20:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L1
L25:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void clear_stdin(void) {
  int c;
  do {
    c = getchar();
  } while (c != '\n' && c != EOF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clear_stdin>:
  endbr64
  sub    $0x8,%rsp
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L14:
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L16
L4:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L14
L16:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void clear_stdin(void) {
  int c;
  do {
    c = getchar();
  } while (c != '\n' && c != EOF);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cpu2norm_dd_in_c>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  test   %ebp,%ebp
  jle    L23
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  shl    $0x5,%rax
  lea    0x20(%r12,%rax,1),%r15
  lea    D1(%rip),%r14
L3:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <dd_write@plt>
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rbx),%r13
  mov    $0x20,%esi
  mov    %r13,%rdi
  call   <dd_write@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x20(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <dd_copy@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <dd_sqr@plt>
  lea    0x30(%rsp),%r12
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <dd_copy@plt>
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <dd_sqr@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <dd_inc@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <dd_inc@plt>
  add    $0x20,%rbx
  cmp    %r15,%rbx
  jne    L3
L23:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x20,%esi
  call   <dd_write@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  movsd  %xmm0,(%rax)
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D13
datatype: string
name: parse_data
arguments: data_tag: D1
datatype: string
name: parse_data
arguments: data_tag: D5
datatype: string

tool: D2: The C function received as dimension %d


tool: D13: The components of the vector :

tool: D1:   

tool: D5: The square of the 2-norm is 

assistant: ```c
int cpu2norm_dd_in_c(int n, double *x, double *nrm) {
  int i;
  double dd_nrm[2], re_acc[2], im_acc[2];
  printf("The C function received as dimension %d\n", n);
  printf("The components of the vector :\n");
  dd_nrm[0] = 0.0;
  dd_nrm[1] = 0.0;
  for (i = 0; i < n; i++) {
    dd_write(&x[4 * i], 32);
    printf("  ");
    dd_write(&x[4 * i + 2], 32);
    printf("\n");
    dd_copy(&x[4 * i], re_acc);
    dd_sqr(re_acc, re_acc);
    dd_copy(&x[4 * i + 2], im_acc);
    dd_sqr(im_acc, im_acc);
    dd_inc(re_acc, im_acc);
    dd_inc(dd_nrm, re_acc);
  }
  printf("The square of the 2-norm is ");
  dd_write(dd_nrm, 32);
  printf("\n");
  nrm[0] = dd_nrm[0];
  nrm[1] = dd_nrm[1];
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cpu2norm_dd_in_c>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  mov    %edi,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D23(%rip),%rdi
  sub    $0x58,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  test   %ebx,%ebx
  jle    L6
  lea    -0x1(%rbx),%eax
  lea    D21(%rip),%r13
  shl    $0x5,%rax
  lea    0x20(%rsp),%rbx
  lea    0x30(%rsp),%rbp
  lea    0x20(%r15,%rax,1),%rax
  lea    0x10(%rsp),%r12
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x20,%esi
  mov    %r15,%rdi
  lea    0x10(%r15),%r14
  call   <dd_write@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x20,%esi
  mov    %r14,%rdi
  call   <dd_write@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r15,%rdi
  mov    %rbx,%rsi
  add    $0x20,%r15
  call   <dd_copy@plt>
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <dd_sqr@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <dd_copy@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <dd_sqr@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <dd_inc@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <dd_inc@plt>
  cmp    (%rsp),%r15
  jne    L28
L6:
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <dd_write@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  movsd  %xmm0,(%rax)
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
datatype: string
name: extract_symbolic_data
arguments: data_label: D14
datatype: string
name: extract_symbolic_data
arguments: data_label: D21
datatype: string
name: extract_symbolic_data
arguments: data_label: D36
datatype: string

tool: D23: The C function received as dimension %d


tool: D14: The components of the vector :

tool: D21:   

tool: D36: The square of the 2-norm is 

assistant: ```c
int cpu2norm_dd_in_c(int n, double *x, double *nrm) {
  int i;
  double dd_nrm[2], re_acc[2], im_acc[2];
  printf("The C function received as dimension %d\n", n);
  printf("The components of the vector :\n");
  dd_nrm[0] = 0.0;
  dd_nrm[1] = 0.0;
  for (i = 0; i < n; i++) {
    dd_write(&x[4 * i], 32);
    printf("  ");
    dd_write(&x[4 * i + 2], 32);
    printf("\n");
    dd_copy(&x[4 * i], re_acc);
    dd_sqr(re_acc, re_acc);
    dd_copy(&x[4 * i + 2], im_acc);
    dd_sqr(im_acc, im_acc);
    dd_inc(re_acc, im_acc);
    dd_inc(dd_nrm, re_acc);
  }
  printf("The square of the 2-norm is ");
  dd_write(dd_nrm, 32);
  printf("\n");
  nrm[0] = dd_nrm[0];
  nrm[1] = dd_nrm[1];
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cpu2norm_dd_in_c>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  mov    %edi,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D30(%rip),%rdi
  sub    $0x58,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  test   %ebx,%ebx
  jle    L15
  lea    -0x1(%rbx),%eax
  lea    D11(%rip),%r13
  shl    $0x5,%rax
  lea    0x20(%rsp),%rbx
  lea    0x30(%rsp),%rbp
  lea    0x20(%r15,%rax,1),%rax
  lea    0x10(%rsp),%r12
  mov    %rax,(%rsp)
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0x20,%esi
  mov    %r15,%rdi
  lea    0x10(%r15),%r14
  call   <dd_write@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x20,%esi
  mov    %r14,%rdi
  call   <dd_write@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r15,%rdi
  mov    %rbx,%rsi
  add    $0x20,%r15
  call   <dd_copy@plt>
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <dd_sqr@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <dd_copy@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <dd_sqr@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <dd_inc@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <dd_inc@plt>
  cmp    %r15,(%rsp)
  jne    L24
L15:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <dd_write@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  movapd 0x10(%rsp),%xmm1
  movups %xmm1,(%rax)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D30
data_type: string
name: parse_data
arguments: tag: D33
data_type: string
name: parse_data
arguments: tag: D11
data_type: string
name: parse_data
arguments: tag: D14
data_type: string

tool: D30: The C function received as dimension %d


tool: D33: The components of the vector :

tool: D11:   

tool: D14: The square of the 2-norm is 

assistant: ```c
int cpu2norm_dd_in_c(int n, double *x, double *nrm) {
  int i;
  double dd_nrm[2], re_acc[2], im_acc[2];
  printf("The C function received as dimension %d\n", n);
  printf("The components of the vector :\n");
  dd_nrm[0] = 0.0;
  dd_nrm[1] = 0.0;
  for (i = 0; i < n; i++) {
    dd_write(&x[4 * i], 32);
    printf("  ");
    dd_write(&x[4 * i + 2], 32);
    printf("\n");
    dd_copy(&x[4 * i], re_acc);
    dd_sqr(re_acc, re_acc);
    dd_copy(&x[4 * i + 2], im_acc);
    dd_sqr(im_acc, im_acc);
    dd_inc(re_acc, im_acc);
    dd_inc(dd_nrm, re_acc);
  }
  printf("The square of the 2-norm is ");
  dd_write(dd_nrm, 32);
  printf("\n");
  nrm[0] = dd_nrm[0];
  nrm[1] = dd_nrm[1];
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L11:
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *sc;
  for (sc = s; *sc != '\0'; ++sc)
    ;
  return (size_t)(sc - s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L2
  mov    %rdi,%rax
L27:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L27
L1:
  sub    %rdi,%rax
  ret
L2:
  mov    %rdi,%rax
  jmp    L1
```

assistant: ```c
size_t strlen(const char *s) {
  const char *sc;
  for (sc = s; *sc != '\0'; ++sc)
    ;
  return (size_t)(sc - s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L2
  mov    %rdi,%rax
  nopl   0x0(%rax)
L13:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L13
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *sc;
  for (sc = s; *sc != '\0'; ++sc)
    ;
  return (size_t)(sc - s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  mov    %rdi,%rax
  nopl   0x0(%rax)
L18:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L18
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *sc;
  for (sc = s; *sc != '\0'; ++sc)
    ;
  return (size_t)(sc - s);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ConvertMotifAction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x4,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L25
  orl    $0x1,-0x4(%rbp)
  jmp    L12
L25:
  mov    -0x14(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  jne    L12
  mov    -0x14(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L18
  orl    $0x400,-0x4(%rbp)
  jmp    L12
L18:
  movl   $0x0,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
CARD32 ConvertMotifAction(CARD16 motif_action) {
  CARD32 olit_action;
  olit_action = (1 << 2);
  if (motif_action & (1 << 0))
    olit_action |= (1 << 0);
  else if (motif_action & (1 << 1))
    olit_action |= 0;
  else if (motif_action & (1 << 2))
    olit_action |= (1 << 10);
  else
    olit_action = 0;
  return olit_action;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ConvertMotifAction>:
  endbr64
  mov    $0x5,%eax
  test   $0x1,%dil
  jne    L18
  mov    $0x4,%eax
  test   $0x2,%dil
  jne    L18
  mov    %edi,%eax
  and    $0x4,%eax
  mov    $0x404,%edx
  cmovne %edx,%eax
L18:
  ret
```

assistant: ```c
CARD32 ConvertMotifAction(CARD16 motif_action) {
  CARD32 olit_action;
  olit_action = (1 << 2);
  if (motif_action & (1 << 0))
    olit_action |= (1 << 0);
  else if (motif_action & (1 << 1))
    olit_action |= 0;
  else if (motif_action & (1 << 2))
    olit_action |= (1 << 10);
  else
    olit_action = 0;
  return olit_action;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ConvertMotifAction>:
  endbr64
  mov    $0x5,%eax
  test   $0x1,%dil
  jne    L14
  mov    $0x4,%eax
  test   $0x2,%dil
  jne    L14
  mov    %edi,%eax
  mov    $0x404,%edx
  and    $0x4,%eax
  cmovne %edx,%eax
L14:
  ret
```

assistant: ```c
CARD32 ConvertMotifAction(CARD16 motif_action) {
  CARD32 olit_action;
  olit_action = (1 << 2);
  if (motif_action & (1 << 0))
    olit_action |= (1 << 0);
  else if (motif_action & (1 << 1))
    olit_action |= 0;
  else if (motif_action & (1 << 2))
    olit_action |= (1 << 10);
  else
    olit_action = 0;
  return olit_action;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ConvertMotifAction>:
  endbr64
  mov    $0x5,%eax
  test   $0x1,%dil
  jne    L5
  mov    $0x4,%eax
  test   $0x2,%dil
  jne    L5
  mov    %edi,%eax
  mov    $0x404,%edx
  and    $0x4,%eax
  cmovne %edx,%eax
L5:
  ret
```

assistant: ```c
CARD32 ConvertMotifAction(CARD16 motif_action) {
  CARD32 olit_action;
  olit_action = (1 << 2);
  if (motif_action & (1 << 0))
    olit_action |= (1 << 0);
  else if (motif_action & (1 << 1))
    olit_action |= 0;
  else if (motif_action & (1 << 2))
    olit_action |= (1 << 10);
  else
    olit_action = 0;
  return olit_action;
}
```