ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fill_testfile>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  cmp    $0xc7ff,%esi
  jle    L58
  movslq %esi,%r14
  mov    %esi,%edx
  mov    %esi,%eax
  mov    $0x1,%esi
  imul   $0x51eb851f,%r14,%r14
  sar    $0x1f,%edx
  sar    $0x2e,%r14
  sub    %edx,%r14d
  cltd
  idiv   %r14d
  shl    $0xa,%eax
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <calloc@plt>
  mov    %rax,%r13
L29:
  movslq %ebp,%rdx
  test   %ebp,%ebp
  mov    $0x1,%eax
  mov    $0x41,%esi
  cmovle %rax,%rdx
  mov    %r13,%rdi
  call   <memset@plt>
L12:
  xor    %ebx,%ebx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  jge    L8
L1:
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jns    L34
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L58:
  shl    $0xa,%esi
  mov    $0x1,%r14d
  mov    %esi,%ebp
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jg     L29
  jmp    L12
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: write

assistant: ```c
int fill_testfile(int testfile_descriptor, int testfile_size) {
  char *zero;
  int i;
  int parts;
  parts = (testfile_size / 51200);
  if (parts < 1)
    parts = 1;
  zero = (char *)calloc((testfile_size / parts) * 1024, sizeof(char));
  for (i = 0; i < (testfile_size / parts) * 1024; i++)
    zero[i] = 'A';
  for (i = 0; i < parts; i++) {
    if (write(testfile_descriptor, (char *)zero, ((testfile_size / parts) * 1024) * sizeof(char)) < 0) {
      perror("write");
      free(zero);
      return -1;
    }
  }
  free(zero);
  return testfile_descriptor;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fill_testfile>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  cmp    $0xc7ff,%esi
  jle    L40
  movslq %esi,%r14
  mov    %esi,%edx
  mov    %esi,%eax
  mov    $0x1,%esi
  imul   $0x51eb851f,%r14,%r14
  sar    $0x1f,%edx
  sar    $0x2e,%r14
  sub    %edx,%r14d
  cltd
  idiv   %r14d
  shl    $0xa,%eax
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <calloc@plt>
  mov    %rax,%r13
L23:
  movslq %ebp,%rdx
  test   %ebp,%ebp
  mov    $0x1,%eax
  mov    $0x41,%esi
  cmovle %rax,%rdx
  mov    %r13,%rdi
  call   <memset@plt>
L34:
  xor    %ebx,%ebx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  jge    L47
L8:
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jns    L20
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L47:
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L40:
  shl    $0xa,%esi
  mov    $0x1,%r14d
  mov    %esi,%ebp
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jg     L23
  jmp    L34
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string

tool: D3: write

assistant: ```c
int fill_testfile(int testfile_descriptor, int testfile_size) {
  char *zero;
  int i;
  int parts;
  parts = (testfile_size / 51200);
  if (parts < 1)
    parts = 1;
  zero = (char *)calloc((testfile_size / parts) * 1024, sizeof(char));
  for (i = 0; i < (testfile_size / parts) * 1024; i++)
    zero[i] = 'A';
  for (i = 0; i < parts; i++) {
    if (write(testfile_descriptor, (char *)zero, ((testfile_size / parts) * 1024) * sizeof(char)) < 0) {
      perror("write");
      free(zero);
      return -1;
    }
  }
  free(zero);
  return testfile_descriptor;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x48,-0x8(%rbp)
  movb   $0x6f,-0x7(%rbp)
  movb   $0x6d,-0x6(%rbp)
  movb   $0x65,-0x5(%rbp)
  movb   $0x57,-0x4(%rbp)
  movb   $0x6f,-0x3(%rbp)
  movb   $0x72,-0x2(%rbp)
  movb   $0x6b,-0x1(%rbp)
  movsbl -0x1(%rbp),%r8d
  movsbl -0x2(%rbp),%edi
  movsbl -0x3(%rbp),%esi
  movsbl -0x4(%rbp),%r9d
  movsbl -0x5(%rbp),%r10d
  movsbl -0x6(%rbp),%ecx
  movsbl -0x7(%rbp),%edx
  movsbl -0x8(%rbp),%eax
  sub    $0x8,%rsp
  push   %r8
  push   %rdi
  push   %rsi
  mov    %r10d,%r8d
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: %c%c%c%c %c%c%c%c


assistant: ```c
int main() {
  char c1 = 'H';
  char c2 = 'o';
  char c3 = 'm';
  char c4 = 'e';
  char c5 = 'W';
  char c6 = 'o';
  char c7 = 'r';
  char c8 = 'k';
  printf("%c%c%c%c %c%c%c%c\n", c1, c2, c3, c4, c5, c6, c7, c8);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  push   $0x6b
  push   $0x72
  push   $0x6f
  mov    $0x57,%r9d
  mov    $0x65,%r8d
  mov    $0x6d,%ecx
  mov    $0x6f,%edx
  mov    $0x48,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: %c%c%c%c %c%c%c%c


assistant: ```c
int main() {
  char c1 = 'H';
  char c2 = 'o';
  char c3 = 'm';
  char c4 = 'e';
  char c5 = 'W';
  char c6 = 'o';
  char c7 = 'r';
  char c8 = 'k';
  printf("%c%c%c%c %c%c%c%c\n", c1, c2, c3, c4, c5, c6, c7, c8);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  mov    $0x57,%r9d
  mov    $0x65,%r8d
  mov    $0x6d,%ecx
  push   $0x6b
  mov    $0x6f,%edx
  mov    $0x48,%esi
  lea    D7(%rip),%rdi
  push   $0x72
  push   $0x6f
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: string

tool: D7: %c%c%c%c %c%c%c%c


assistant: ```c
int main() {
  char c1 = 'H';
  char c2 = 'o';
  char c3 = 'm';
  char c4 = 'e';
  char c5 = 'W';
  char c6 = 'o';
  char c7 = 'r';
  char c8 = 'k';
  printf("%c%c%c%c %c%c%c%c\n", c1, c2, c3, c4, c5, c6, c7, c8);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  mov    $0x57,%r9d
  mov    $0x65,%r8d
  mov    $0x6d,%ecx
  push   $0x6b
  mov    $0x6f,%edx
  mov    $0x48,%esi
  lea    D6(%rip),%rdi
  push   $0x72
  push   $0x6f
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: %c%c%c%c %c%c%c%c


assistant: ```c
int main() {
  char c1 = 'H';
  char c2 = 'o';
  char c3 = 'm';
  char c4 = 'e';
  char c5 = 'W';
  char c6 = 'o';
  char c7 = 'r';
  char c8 = 'k';
  printf("%c%c%c%c %c%c%c%c\n", c1, c2, c3, c4, c5, c6, c7, c8);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<list4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <newvec@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *list4(x, y, z, t)
int *y, *z, *t;
{
  int *p = newvec(3);
  p[0] = x;
  p[1] = (int)y;
  p[2] = (int)z;
  p[3] = (int)t;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list4>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <newvec@plt>
  cltq
  mov    %r13d,(%rax)
  mov    %r12d,0x4(%rax)
  mov    %ebp,0x8(%rax)
  mov    %ebx,0xc(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *list4(x, y, z, t)
int *y, *z, *t;
{
  int *p = newvec(3);
  p[0] = x;
  p[1] = (int)y;
  p[2] = (int)z;
  p[3] = (int)t;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list4>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edi,%r13d
  mov    $0x3,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <newvec@plt>
  cltq
  mov    %r13d,(%rax)
  mov    %r12d,0x4(%rax)
  mov    %ebp,0x8(%rax)
  mov    %ebx,0xc(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *list4(x, y, z, t)
int *y, *z, *t;
{
  int *p = newvec(3);
  p[0] = x;
  p[1] = (int)y;
  p[2] = (int)z;
  p[3] = (int)t;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<list4>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3,%edi
  sub    $0x8,%rsp
  call   <newvec@plt>
  movd   %ebp,%xmm1
  movd   %r13d,%xmm2
  movd   %ebx,%xmm0
  movd   %r12d,%xmm3
  punpckldq %xmm2,%xmm1
  cltq
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *list4(x, y, z, t)
int *y, *z, *t;
{
  int *p = newvec(3);
  p[0] = x;
  p[1] = (int)y;
  p[2] = (int)z;
  p[3] = (int)t;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<BUF_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L25
L33:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x28(%rbp)
L25:
  cmpq   $0x1,-0x28(%rbp)
  jbe    L19
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
L19:
  cmpq   $0x0,-0x28(%rbp)
  je     L24
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L24:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
size_t BUF_strlcpy(char *dst, const char *src, size_t size) {
  size_t l = 0;
  for (; size > 1 && *src; size--) {
    *dst++ = *src++;
    l++;
  }
  if (size)
    *dst = '\0';
  return l + strlen(src);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BUF_strlcpy>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rdi
  cmp    $0x1,%rdx
  jbe    L23
  lea    -0x1(%rdx),%rsi
  mov    $0x0,%ebx
L11:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L48
  add    $0x1,%rdi
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  add    $0x1,%rbx
  sub    $0x1,%rdx
  cmp    %rsi,%rbx
  jne    L11
  mov    %rsi,%rbx
L48:
  test   %rdx,%rdx
  je     L16
  movb   $0x0,(%rax)
L16:
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
L23:
  mov    $0x0,%ebx
  jmp    L48
```

assistant: ```c
size_t BUF_strlcpy(char *dst, const char *src, size_t size) {
  size_t l = 0;
  for (; size > 1 && *src; size--) {
    *dst++ = *src++;
    l++;
  }
  if (size)
    *dst = '\0';
  return l + strlen(src);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BUF_strlcpy>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rdx,%rbx
  mov    %rsi,%rdi
  cmp    $0x1,%rdx
  jbe    L52
  lea    -0x1(%rdx),%rcx
  xor    %ebx,%ebx
  jmp    L56
  nopl   0x0(%rax)
L45:
  add    $0x1,%rbx
  add    $0x1,%rax
  add    $0x1,%rdi
  mov    %dl,-0x1(%rax)
  cmp    %rbx,%rcx
  je     L15
L56:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L45
L15:
  movb   $0x0,(%rax)
L5:
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
L52:
  test   %rdx,%rdx
  je     L5
  xor    %ebx,%ebx
  jmp    L15
```

assistant: ```c
size_t BUF_strlcpy(char *dst, const char *src, size_t size) {
  size_t l = 0;
  for (; size > 1 && *src; size--) {
    *dst++ = *src++;
    l++;
  }
  if (size)
    *dst = '\0';
  return l + strlen(src);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BUF_strlcpy>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rdx,%rbx
  mov    %rsi,%rdi
  cmp    $0x1,%rdx
  jbe    L59
  lea    -0x1(%rdx),%rcx
  xor    %ebx,%ebx
  jmp    L20
  nopl   0x0(%rax)
L58:
  add    $0x1,%rbx
  add    $0x1,%rax
  add    $0x1,%rdi
  mov    %dl,-0x1(%rax)
  cmp    %rbx,%rcx
  je     L27
L20:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L58
L27:
  movb   $0x0,(%rax)
L8:
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
L59:
  test   %rdx,%rdx
  je     L8
  xor    %ebx,%ebx
  jmp    L27
```

assistant: ```c
size_t BUF_strlcpy(char *dst, const char *src, size_t size) {
  size_t l = 0;
  for (; size > 1 && *src; size--) {
    *dst++ = *src++;
    l++;
  }
  if (size)
    *dst = '\0';
  return l + strlen(src);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<emitWithFormat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %rdi,-0x1d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x1d8(%rbp),%rdx
  mov    -0x1c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x1c4(%rbp),%edx
  mov    -0x1d8(%rbp),%rcx
  lea    -0x1c0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0x1c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <Str_newWith@plt>
  mov    %eax,%edi
  call   <emit@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
void emitWithFormat(const char *_format, ...) {
  char buffer[256];
  va_list args;
  va_start(args, _format);
  vsprintf(buffer, _format, args);
  va_end(args);
  emit(Str_newWith(buffer));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emitWithFormat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rdi
  call   <Str_newWith@plt>
  mov    %eax,%edi
  call   <emit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void emitWithFormat(const char *_format, ...) {
  char buffer[256];
  va_list args;
  va_start(args, _format);
  vsprintf(buffer, _format, args);
  va_end(args);
  emit(Str_newWith(buffer));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emitWithFormat>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rdi
  call   <Str_newWith@plt>
  mov    %eax,%edi
  call   <emit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void emitWithFormat(const char *_format, ...) {
  char buffer[256];
  va_list args;
  va_start(args, _format);
  vsprintf(buffer, _format, args);
  va_end(args);
  emit(Str_newWith(buffer));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<emitWithFormat>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rdi
  call   <Str_newWith@plt>
  mov    %eax,%edi
  call   <emit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void emitWithFormat(const char *_format, ...) {
  char buffer[256];
  va_list args;
  va_start(args, _format);
  vsprintf(buffer, _format, args);
  va_end(args);
  emit(Str_newWith(buffer));
}
```
user: What is the c source code of the assembly code below?

```asm
<strzncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L49
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    $0x0,%eax
  jmp    L98
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L46
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  jne    L88
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L88
  mov    $0x0,%eax
  jmp    L98
L88:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L59
  mov    $0x1,%eax
  jmp    L98
L59:
  mov    $0xffffffff,%eax
  jmp    L98
L46:
  nop
  subl   $0x1,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L49:
  cmpl   $0x0,-0x14(%rbp)
  jne    L14
  mov    $0x0,%eax
L98:
  pop    %rbp
  ret
```

assistant: ```c
int strzncmp(char *s, char *d, int n) {
  for (; n; n--, s++, d++) {
    if (!*s && !*d)
      return 0;
    if (*s == *d)
      continue;
    if (*s == '?' && !*d)
      return 0;
    if (*s > *d)
      return 1;
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strzncmp>:
  endbr64
  test   %edx,%edx
  je     L17
  mov    %edx,%eax
  add    %rdi,%rax
L78:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L74
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L47
L59:
  cmp    %dl,%cl
  setl   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
L74:
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  je     L54
  test   %cl,%cl
  jne    L59
  mov    $0x0,%eax
  cmp    $0x3f,%dl
  jne    L59
L39:
  ret
L54:
  add    $0x1,%rdi
  add    $0x1,%rsi
  cmp    %rax,%rdi
  jne    L78
  mov    $0x0,%eax
  ret
L17:
  mov    %edx,%eax
  ret
L47:
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
int strzncmp(char *s, char *d, int n) {
  for (; n; n--, s++, d++) {
    if (!*s && !*d)
      return 0;
    if (*s == *d)
      continue;
    if (*s == '?' && !*d)
      return 0;
    if (*s > *d)
      return 1;
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strzncmp>:
  endbr64
  test   %edx,%edx
  je     L50
  mov    %edx,%edx
  xor    %eax,%eax
L29:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  test   %cl,%cl
  jne    L11
  test   %r8b,%r8b
  je     L50
L34:
  xor    %eax,%eax
  cmp    %cl,%r8b
  setl   %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  cmp    %r8b,%cl
  je     L14
  test   %r8b,%r8b
  jne    L34
  xor    %eax,%eax
  cmp    $0x3f,%cl
  jne    L34
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L29
L50:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strzncmp(char *s, char *d, int n) {
  for (; n; n--, s++, d++) {
    if (!*s && !*d)
      return 0;
    if (*s == *d)
      continue;
    if (*s == '?' && !*d)
      return 0;
    if (*s > *d)
      return 1;
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strzncmp>:
  endbr64
  test   %edx,%edx
  je     L14
  mov    %edx,%edx
  xor    %eax,%eax
L29:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  test   %cl,%cl
  jne    L37
  test   %r8b,%r8b
  je     L14
L39:
  xor    %eax,%eax
  cmp    %cl,%r8b
  setl   %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  cmp    %r8b,%cl
  je     L58
  test   %r8b,%r8b
  jne    L39
  xor    %eax,%eax
  cmp    $0x3f,%cl
  jne    L39
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L29
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strzncmp(char *s, char *d, int n) {
  for (; n; n--, s++, d++) {
    if (!*s && !*d)
      return 0;
    if (*s == *d)
      continue;
    if (*s == '?' && !*d)
      return 0;
    if (*s > *d)
      return 1;
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<encode_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void encode_16(u_int8_t *cp, u_int16_t x) {
  *cp++ = x >> 8;
  *cp = x & 0xff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<encode_16>:
  endbr64
  mov    %esi,%eax
  sar    $0x8,%eax
  mov    %eax,(%rdi)
  and    $0xff,%esi
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void encode_16(u_int8_t *cp, u_int16_t x) {
  *cp++ = x >> 8;
  *cp = x & 0xff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<encode_16>:
  endbr64
  mov    %esi,%eax
  and    $0xff,%esi
  sar    $0x8,%eax
  mov    %esi,0x4(%rdi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void encode_16(u_int8_t *cp, u_int16_t x) {
  *cp++ = x >> 8;
  *cp = x & 0xff;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<encode_16>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%esi
  sar    $0x8,%eax
  movd   %esi,%xmm1
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  ret
```

assistant: ```c
void encode_16(u_int8_t *cp, u_int16_t x) {
  *cp++ = x >> 8;
  *cp = x & 0xff;
}
```