ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_audio_config>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <get_audio_bits@plt>
  mov    %rax,%r12
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  mov    $0x60045005,%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  cmp    0xc(%rsp),%r12d
  jne    L21
  mov    %rbp,%rdi
  call   <get_audio_frq@plt>
  mov    %eax,%r12d
  mov    %eax,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  mov    $0x60045002,%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  cmp    0x10(%rsp),%r12d
  jne    L59
  mov    %rbp,%rdi
  call   <get_audio_channels@plt>
  mov    %eax,%ebp
  mov    %eax,0x14(%rsp)
  lea    0x14(%rsp),%rdx
  mov    $0x60045006,%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%ebp
  jne    L4
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L65:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    $0xffffffff,%eax
  jmp    L65
L59:
  mov    $0xffffffff,%eax
  jmp    L65
L4:
  mov    $0xffffffff,%eax
  jmp    L65
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: Configuration : %d %d %d


assistant: ```c
int set_audio_config(int fd_audio, FILE *file) {
  int tmp, format, frequency, channels;
  tmp = format = (int)get_audio_bits(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 5)), &format);
  if (tmp != format)
    return -1;
  tmp = frequency = get_audio_frq(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 2)), &frequency);
  if (tmp != frequency)
    return -1;
  tmp = channels = get_audio_channels(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 6)), &channels);
  if (tmp != channels)
    return -1;
  printf("Configuration : %d %d %d\n", format, frequency, channels);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_audio_config>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <get_audio_bits@plt>
  lea    0xc(%rsp),%rdx
  mov    $0x60045005,%esi
  mov    %ebp,%edi
  mov    %rax,%rbx
  mov    %eax,0xc(%rsp)
  call   <ioctl@plt>
  cmp    0xc(%rsp),%ebx
  jne    L46
  mov    %r12,%rdi
  call   <get_audio_frq@plt>
  lea    0x10(%rsp),%rdx
  mov    $0x60045002,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  mov    %eax,0x10(%rsp)
  call   <ioctl@plt>
  cmp    0x10(%rsp),%ebx
  jne    L46
  mov    %r12,%rdi
  call   <get_audio_channels@plt>
  lea    0x14(%rsp),%rdx
  mov    $0x60045006,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    %eax,0x14(%rsp)
  call   <ioctl@plt>
  cmp    0x14(%rsp),%r12d
  jne    L46
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %r12d,%ecx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L17:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L46:
  mov    $0xffffffff,%eax
  jmp    L17
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: Configuration : %d %d %d


assistant: ```c
int set_audio_config(int fd_audio, FILE *file) {
  int tmp, format, frequency, channels;
  tmp = format = (int)get_audio_bits(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 5)), &format);
  if (tmp != format)
    return -1;
  tmp = frequency = get_audio_frq(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 2)), &frequency);
  if (tmp != frequency)
    return -1;
  tmp = channels = get_audio_channels(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 6)), &channels);
  if (tmp != channels)
    return -1;
  printf("Configuration : %d %d %d\n", format, frequency, channels);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_audio_config>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <get_audio_bits@plt>
  lea    0xc(%rsp),%rdx
  mov    $0x60045005,%esi
  mov    %ebp,%edi
  mov    %rax,%rbx
  mov    %eax,0xc(%rsp)
  call   <ioctl@plt>
  cmp    0xc(%rsp),%ebx
  jne    L12
  mov    %r12,%rdi
  call   <get_audio_frq@plt>
  lea    0x10(%rsp),%rdx
  mov    $0x60045002,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  mov    %eax,0x10(%rsp)
  call   <ioctl@plt>
  cmp    0x10(%rsp),%ebx
  jne    L12
  mov    %r12,%rdi
  call   <get_audio_channels@plt>
  lea    0x14(%rsp),%rdx
  mov    $0x60045006,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    %eax,0x14(%rsp)
  call   <ioctl@plt>
  cmp    0x14(%rsp),%r12d
  jne    L12
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %r12d,%ecx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L41:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  mov    $0xffffffff,%eax
  jmp    L41
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: Configuration : %d %d %d


assistant: ```c
int set_audio_config(int fd_audio, FILE *file) {
  int tmp, format, frequency, channels;
  tmp = format = (int)get_audio_bits(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 5)), &format);
  if (tmp != format)
    return -1;
  tmp = frequency = get_audio_frq(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 2)), &frequency);
  if (tmp != frequency)
    return -1;
  tmp = channels = get_audio_channels(file);
  ioctl(fd_audio, ((int)((0x40000000 | 0x20000000) | ((sizeof(int) & 0x1fff) << 16) | ('P' << 8) | 6)), &channels);
  if (tmp != channels)
    return -1;
  printf("Configuration : %d %d %d\n", format, frequency, channels);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: Hola a todos


assistant: ```c
void main(void) {
  printf("Hola a todos\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: Hola a todos


assistant: ```c
void main(void) {
  printf("Hola a todos\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: Hola a todos


assistant: ```c
void main(void) {
  printf("Hola a todos\n");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: Hola a todos


assistant: ```c
void main(void) {
  printf("Hola a todos\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gnulliver>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movb   $0x0,-0x11(%rbp)
  movzbl -0x10(%rbp),%eax
  test   %al,%al
  jne    L36
  movzbl -0xc(%rbp),%eax
  cmp    $0x10,%al
  jne    L25
  movb   $0xf,-0x11(%rbp)
  jmp    L18
L25:
  movb   $0xe,-0x11(%rbp)
  jmp    L18
L36:
  movb   $0x0,-0x11(%rbp)
L18:
  movzbl -0x11(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x10,0x20,0x30,0x40]}

assistant: ```c
unsigned char gnulliver() {
  unsigned char result;
  union {
    double d;
    unsigned char ch[8];
  } bytes;
  int i;
  bytes.d = (16.0 + (1.0 / 8.0 + 1.0 / 4096.0));
  result = 0;
  if (bytes.ch[0] == 0) {
    if (bytes.ch[4] == 0x10)
      result = (1 | 2 | 4 | 8);
    else
      result = (2 | 4 | 8);
  } else
    result = 0;
  return (result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gnulliver>:
  endbr64
  mov    $0xf,%eax
  ret
```

assistant: ```c
unsigned char gnulliver() {
  unsigned char result;
  union {
    double d;
    unsigned char ch[8];
  } bytes;
  int i;
  bytes.d = (16.0 + (1.0 / 8.0 + 1.0 / 4096.0));
  result = 0;
  if (bytes.ch[0] == 0) {
    if (bytes.ch[4] == 0x10)
      result = (1 | 2 | 4 | 8);
    else
      result = (2 | 4 | 8);
  } else
    result = 0;
  return (result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gnulliver>:
  endbr64
  mov    $0xf,%eax
  ret
```

assistant: ```c
unsigned char gnulliver() {
  unsigned char result;
  union {
    double d;
    unsigned char ch[8];
  } bytes;
  int i;
  bytes.d = (16.0 + (1.0 / 8.0 + 1.0 / 4096.0));
  result = 0;
  if (bytes.ch[0] == 0) {
    if (bytes.ch[4] == 0x10)
      result = (1 | 2 | 4 | 8);
    else
      result = (2 | 4 | 8);
  } else
    result = 0;
  return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gnulliver>:
  endbr64
  mov    $0xf,%eax
  ret
```

assistant: ```c
unsigned char gnulliver() {
  unsigned char result;
  union {
    double d;
    unsigned char ch[8];
  } bytes;
  int i;
  bytes.d = (16.0 + (1.0 / 8.0 + 1.0 / 4096.0));
  result = 0;
  if (bytes.ch[0] == 0) {
    if (bytes.ch[4] == 0x10)
      result = (1 | 2 | 4 | 8);
    else
      result = (2 | 4 | 8);
  } else
    result = 0;
  return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MotPassA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L2
L15:
  movl   $0x0,-0x2c(%rbp)
  jmp    L19
L35:
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  cmpl   $0x13,-0x30(%rbp)
  jg     L17
  addl   $0x1,-0x30(%rbp)
L17:
  addl   $0x1,-0x2c(%rbp)
L19:
  cmpl   $0x4,-0x2c(%rbp)
  jle    L35
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <BinaireToDecimalA@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x34(%rbp)
L2:
  cmpl   $0x3,-0x34(%rbp)
  jle    L15
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <DecimalToCharA@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *MotPassA(long *M) {
  long *m = malloc(5 * sizeof(long));
  long *ptr_m = malloc(4 * sizeof(long));
  int i;
  int j = 0;
  int k;
  for (i = 0; i < 4; ++i) {
    for (k = 0; k < 5; ++k) {
      m[k] = M[j];
      if (j <= 19) {
        j++;
      }
    }
    ptr_m[i] = BinaireToDecimalA(m);
  }
  char *c = DecimalToCharA(ptr_m);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<MotPassA>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  lea    0x20(%rax),%r15
  mov    $0x0,%ebx
  lea    0x28(%r14),%r12
L3:
  mov    %r14,%rax
L9:
  movslq %ebx,%rdx
  mov    0x0(%rbp,%rdx,8),%rdx
  mov    %rdx,(%rax)
  cmp    $0x14,%ebx
  setl   %dl
  movzbl %dl,%edx
  add    %edx,%ebx
  add    $0x8,%rax
  cmp    %rax,%r12
  jne    L9
  mov    %r14,%rdi
  call   <BinaireToDecimalA@plt>
  mov    %rax,0x0(%r13)
  add    $0x8,%r13
  cmp    %r15,%r13
  jne    L3
  mov    0x8(%rsp),%rdi
  call   <DecimalToCharA@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *MotPassA(long *M) {
  long *m = malloc(5 * sizeof(long));
  long *ptr_m = malloc(4 * sizeof(long));
  int i;
  int j = 0;
  int k;
  for (i = 0; i < 4; ++i) {
    for (k = 0; k < 5; ++k) {
      m[k] = M[j];
      if (j <= 19) {
        j++;
      }
    }
    ptr_m[i] = BinaireToDecimalA(m);
  }
  char *c = DecimalToCharA(ptr_m);
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MotPassA>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x28,%edi
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    $0x20,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  lea    0x28(%r12),%r14
  mov    %rax,%rbp
  mov    %rax,%r15
  add    $0x20,%rax
  mov    %rax,0x8(%rsp)
L4:
  mov    %r12,%rax
L10:
  movslq %ebx,%rdx
  mov    0x0(%r13,%rdx,8),%rdx
  mov    %rdx,(%rax)
  xor    %edx,%edx
  cmp    $0x14,%ebx
  setl   %dl
  add    $0x8,%rax
  add    %edx,%ebx
  cmp    %r14,%rax
  jne    L10
  mov    %r12,%rdi
  add    $0x8,%r15
  call   <BinaireToDecimalA@plt>
  mov    %rax,-0x8(%r15)
  cmp    %r15,0x8(%rsp)
  jne    L4
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <DecimalToCharA@plt>
```

assistant: ```c
char *MotPassA(long *M) {
  long *m = malloc(5 * sizeof(long));
  long *ptr_m = malloc(4 * sizeof(long));
  int i;
  int j = 0;
  int k;
  for (i = 0; i < 4; ++i) {
    for (k = 0; k < 5; ++k) {
      m[k] = M[j];
      if (j <= 19) {
        j++;
      }
    }
    ptr_m[i] = BinaireToDecimalA(m);
  }
  char *c = DecimalToCharA(ptr_m);
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MotPassA>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x28,%edi
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x20,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
L36:
  movslq %ebp,%rax
  shl    $0x3,%rax
  lea    (%r15,%rax,1),%rdx
  mov    (%rdx),%rcx
  mov    %rcx,(%rbx)
  cmp    $0x13,%ebp
  jg     L12
  lea    0x8(%r15,%rax,1),%rdx
  mov    (%rdx),%rcx
  mov    %rcx,0x8(%rbx)
  je     L48
  lea    0x10(%r15,%rax,1),%rdx
  mov    (%rdx),%rcx
  mov    %rcx,0x10(%rbx)
  cmp    $0x12,%ebp
  je     L111
  lea    0x18(%r15,%rax,1),%rdx
  mov    (%rdx),%rcx
  mov    %rcx,0x18(%rbx)
  cmp    $0x11,%ebp
  je     L17
  mov    0x20(%r15,%rax,1),%rax
  cmp    $0x10,%ebp
  je     L114
  lea    0x5(%rbp),%r14d
L0:
  mov    %rax,0x20(%rbx)
  mov    %rbx,%rdi
  call   <BinaireToDecimalA@plt>
  mov    %rax,-0x8(%r12,%r13,8)
  cmp    $0x4,%r13
  je     L5
  add    $0x1,%r13
L83:
  mov    %r14d,%ebp
  jmp    L36
  xchg   %ax,%ax
L12:
  mov    %rcx,0x8(%rbx)
  movslq %ebp,%r14
L55:
  mov    (%rdx),%rax
  mov    %rax,0x10(%rbx)
L134:
  mov    (%rdx),%rax
  mov    %rbx,%rdi
  mov    %rax,0x18(%rbx)
  mov    (%rdx),%rax
  mov    %rax,0x20(%rbx)
  call   <BinaireToDecimalA@plt>
  mov    %rax,-0x8(%r12,%r13,8)
  mov    %r13d,%eax
  cmp    $0x4,%r13
  je     L5
  add    $0x1,%r13
  cmp    $0x13,%ebp
  jg     10a0 <MotPassA.cold>
  jmp    L83
  nopl   0x0(%rax)
L5:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <DecimalToCharA@plt>
L48:
  mov    $0x14,%r14d
  jmp    L55
L114:
  mov    $0x14,%r14d
  jmp    L0
L17:
  mov    (%rdx),%rax
  mov    %rbx,%rdi
  mov    %rax,0x20(%rbx)
  call   <BinaireToDecimalA@plt>
  mov    %rax,-0x8(%r12,%r13,8)
  cmp    $0x4,%r13
  je     L5
  add    $0x1,%r13
  mov    $0x14,%r14d
  jmp    L83
L111:
  mov    $0x14,%r14d
  jmp    L134
```

assistant: ```c
char *MotPassA(long *M) {
  long *m = malloc(5 * sizeof(long));
  long *ptr_m = malloc(4 * sizeof(long));
  int i;
  int j = 0;
  int k;
  for (i = 0; i < 4; ++i) {
    for (k = 0; k < 5; ++k) {
      m[k] = M[j];
      if (j <= 19) {
        j++;
      }
    }
    ptr_m[i] = BinaireToDecimalA(m);
  }
  char *c = DecimalToCharA(ptr_m);
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L20
L27:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <maxima_distancia@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string

tool: D17: NUMERO DE TESTES: 

tool: D6: %d

tool: D8: 

> Caso %d: %d



assistant: ```c
main() {
  int t, i, maior_distancia;
  printf("NUMERO DE TESTES: ");
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    maior_distancia = maxima_distancia(i + 1);
    printf("\n\n> Caso %d: %d\n\n", i + 1, maior_distancia);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L10
  mov    $0x0,%ebx
  lea    D25(%rip),%rbp
L28:
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <maxima_distancia@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    0x4(%rsp),%ebx
  jl     L28
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D8
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string

tool: D18: NUMERO DE TESTES: 

tool: D8: %d

tool: D25: 

> Caso %d: %d



assistant: ```c
main() {
  int t, i, maior_distancia;
  printf("NUMERO DE TESTES: ");
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    maior_distancia = maxima_distancia(i + 1);
    printf("\n\n> Caso %d: %d\n\n", i + 1, maior_distancia);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L20
  xor    %ebx,%ebx
  lea    D16(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <maxima_distancia@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    0x4(%rsp),%ebx
  jl     L28
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D26
type_infered: string
name: unpack_data
arguments: tag: D16
type_infered: string

tool: D4: NUMERO DE TESTES: 

tool: D26: %d

tool: D16: 

> Caso %d: %d



assistant: ```c
main() {
  int t, i, maior_distancia;
  printf("NUMERO DE TESTES: ");
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    maior_distancia = maxima_distancia(i + 1);
    printf("\n\n> Caso %d: %d\n\n", i + 1, maior_distancia);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L28
  xor    %ebx,%ebx
  lea    D20(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <maxima_distancia@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    0x4(%rsp),%ebx
  jl     L27
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D20
type: string

tool: D18: NUMERO DE TESTES: 

tool: D16: %d

tool: D20: 

> Caso %d: %d



assistant: ```c
main() {
  int t, i, maior_distancia;
  printf("NUMERO DE TESTES: ");
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    maior_distancia = maxima_distancia(i + 1);
    printf("\n\n> Caso %d: %d\n\n", i + 1, maior_distancia);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x17,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  int test;
  test = 23;
  bar(&test);
  return test;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x17,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <bar@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int test;
  test = 23;
  bar(&test);
  return test;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x17,0x4(%rsp)
  call   <bar@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int test;
  test = 23;
  bar(&test);
  return test;
}
```