ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cio_write>:
  endbr64
  sub    $0x1,%esi
  js     L13
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  lea    0x0(,%rbx,8),%ecx
  mov    %ebp,%edi
  shr    %cl,%edi
  movzbl %dil,%edi
  call   <cio_byteout@plt>
  sub    $0x1,%ebx
  jae    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
void cio_write(unsigned int v, int n) {
  int i;
  for (i = n - 1; i >= 0; i--) {
    cio_byteout((unsigned char)((v >> (i << 3)) & 0xff));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sha2_chain_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L7:
  cmpl   $0x1f,-0x8(%rbp)
  jbe    L1
  mov    -0x30(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sha2_chain@plt>
  movl   $0x0,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L7
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int sha2_chain_byte(unsigned char *output_bytes, unsigned output_size, unsigned *chain_status, unsigned char *chain) {
  unsigned counter = chain_status[0];
  for (unsigned i = 0; i < output_size; i++) {
    if ((32) <= counter) {
      sha2_chain(chain, chain);
      counter = 0;
    }
    output_bytes[i] = chain[counter++];
  }
  chain_status[0] = counter;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sha2_chain_byte>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r13
  mov    (%rdx),%edx
  test   %esi,%esi
  je     L1
  mov    %rcx,%rbp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    $0x0,%r14d
  jmp    L12
L11:
  lea    0x1(%rax),%edx
  mov    %eax,%eax
  movzbl 0x0(%rbp,%rax,1),%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L1
L12:
  mov    %edx,%eax
  cmp    $0x1f,%edx
  jbe    L11
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <sha2_chain@plt>
  mov    %r14d,%eax
  jmp    L11
L1:
  mov    %edx,0x0(%r13)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int sha2_chain_byte(unsigned char *output_bytes, unsigned output_size, unsigned *chain_status, unsigned char *chain) {
  unsigned counter = chain_status[0];
  for (unsigned i = 0; i < output_size; i++) {
    if ((32) <= counter) {
      sha2_chain(chain, chain);
      counter = 0;
    }
    output_bytes[i] = chain[counter++];
  }
  chain_status[0] = counter;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sha2_chain_byte>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdx),%eax
  test   %esi,%esi
  je     L40
  lea    -0x1(%rsi),%edx
  mov    %rcx,%r12
  mov    %rdi,%rbx
  lea    0x1(%rdi,%rdx,1),%r13
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %eax,%edx
  add    $0x1,%rbx
  add    $0x1,%eax
  add    %r12,%rdx
  movzbl (%rdx),%edx
  mov    %dl,-0x1(%rbx)
  cmp    %r13,%rbx
  je     L40
L42:
  cmp    $0x1f,%eax
  jbe    L9
  mov    %r12,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <sha2_chain@plt>
  mov    %r12,%rdx
  mov    $0x1,%eax
  movzbl (%rdx),%edx
  mov    %dl,-0x1(%rbx)
  cmp    %r13,%rbx
  jne    L42
L40:
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sha2_chain_byte(unsigned char *output_bytes, unsigned output_size, unsigned *chain_status, unsigned char *chain) {
  unsigned counter = chain_status[0];
  for (unsigned i = 0; i < output_size; i++) {
    if ((32) <= counter) {
      sha2_chain(chain, chain);
      counter = 0;
    }
    output_bytes[i] = chain[counter++];
  }
  chain_status[0] = counter;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sha2_chain_byte>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdx),%eax
  test   %esi,%esi
  je     L18
  lea    -0x1(%rsi),%edx
  mov    %rcx,%rbp
  mov    %rdi,%rbx
  lea    0x1(%rdi,%rdx,1),%r13
  nopl   (%rax)
L6:
  cmp    $0x1f,%eax
  jbe    L29
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <sha2_chain@plt>
  movzbl 0x0(%rbp),%eax
  mov    %al,-0x1(%rbx)
  mov    $0x1,%eax
  cmp    %rbx,%r13
  je     L18
L29:
  mov    %eax,%edx
  add    $0x1,%rbx
  add    $0x1,%eax
  movzbl 0x0(%rbp,%rdx,1),%edx
  mov    %dl,-0x1(%rbx)
  cmp    %rbx,%r13
  jne    L6
L18:
  mov    %eax,(%r12)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sha2_chain_byte(unsigned char *output_bytes, unsigned output_size, unsigned *chain_status, unsigned char *chain) {
  unsigned counter = chain_status[0];
  for (unsigned i = 0; i < output_size; i++) {
    if ((32) <= counter) {
      sha2_chain(chain, chain);
      counter = 0;
    }
    output_bytes[i] = chain[counter++];
  }
  chain_status[0] = counter;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<packsplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  sub    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void packsplit(int *strchr, int *firstpart, int *rest, int bitno_firstpart, int bitno_total) {
  int bitno_rest = bitno_total - bitno_firstpart;
  *firstpart = *strchr >> (bitno_rest);
  *rest = *strchr - (*firstpart << (bitno_rest));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<packsplit>:
  endbr64
  mov    %rsi,%r9
  mov    %rdx,%rsi
  mov    %ecx,%eax
  mov    %r8d,%ecx
  sub    %eax,%ecx
  mov    (%rdi),%eax
  sar    %cl,%eax
  mov    %eax,(%r9)
  shl    %cl,%eax
  mov    (%rdi),%edx
  sub    %eax,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void packsplit(int *strchr, int *firstpart, int *rest, int bitno_firstpart, int bitno_total) {
  int bitno_rest = bitno_total - bitno_firstpart;
  *firstpart = *strchr >> (bitno_rest);
  *rest = *strchr - (*firstpart << (bitno_rest));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<packsplit>:
  endbr64
  mov    (%rdi),%eax
  mov    %ecx,%r10d
  mov    %r8d,%ecx
  mov    %rdx,%r9
  sub    %r10d,%ecx
  sar    %cl,%eax
  mov    %eax,(%rsi)
  mov    (%rdi),%edx
  shl    %cl,%eax
  sub    %eax,%edx
  mov    %edx,(%r9)
  ret
```

assistant: ```c
void packsplit(int *strchr, int *firstpart, int *rest, int bitno_firstpart, int bitno_total) {
  int bitno_rest = bitno_total - bitno_firstpart;
  *firstpart = *strchr >> (bitno_rest);
  *rest = *strchr - (*firstpart << (bitno_rest));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<packsplit>:
  endbr64
  mov    (%rdi),%eax
  mov    %ecx,%r10d
  mov    %r8d,%ecx
  mov    %rdx,%r9
  sub    %r10d,%ecx
  sar    %cl,%eax
  mov    %eax,(%rsi)
  mov    (%rdi),%edx
  shl    %cl,%eax
  sub    %eax,%edx
  mov    %edx,(%r9)
  ret
```

assistant: ```c
void packsplit(int *strchr, int *firstpart, int *rest, int bitno_firstpart, int bitno_total) {
  int bitno_rest = bitno_total - bitno_firstpart;
  *firstpart = *strchr >> (bitno_rest);
  *rest = *strchr - (*firstpart << (bitno_rest));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pop(int xx, int y, int z) {
  unsigned x = xx;
  x = x - ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
  x = (x + (x >> 4)) & 0x0F0F0F0F;
  x = x + (x << 8);
  x = x + (x << 16);
  return x >> 24;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pop>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  shr    $0x18,%eax
  ret
```

assistant: ```c
int pop(int xx, int y, int z) {
  unsigned x = xx;
  x = x - ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
  x = (x + (x >> 4)) & 0x0F0F0F0F;
  x = x + (x << 8);
  x = x + (x << 16);
  return x >> 24;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pop>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  shr    $0x18,%eax
  ret
```

assistant: ```c
int pop(int xx, int y, int z) {
  unsigned x = xx;
  x = x - ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
  x = (x + (x >> 4)) & 0x0F0F0F0F;
  x = x + (x << 8);
  x = x + (x << 16);
  return x >> 24;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pop>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  shr    $0x18,%eax
  ret
```

assistant: ```c
int pop(int xx, int y, int z) {
  unsigned x = xx;
  x = x - ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
  x = (x + (x >> 4)) & 0x0F0F0F0F;
  x = x + (x << 8);
  x = x + (x << 16);
  return x >> 24;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decrease_bitmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  jne    L21
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movw   $0xffff,(%rax)
  subl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x0,-0x4(%rbp)
  jns    L18
  jmp    L22
L21:
  nop
L22:
  cmpl   $0x0,-0x4(%rbp)
  js     L1
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%edx
  sub    $0x1,%edx
  mov    %dx,(%rax)
L1:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void decrease_bitmap(unsigned short *buffer, int len) {
  int i = len - 1;
  for (; i >= 0; i--) {
    if (buffer[i] != 0)
      break;
    buffer[i] = ((unsigned short)-1);
  }
  if (i >= 0)
    buffer[i]--;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decrease_bitmap>:
  endbr64
  sub    $0x1,%esi
  js     L12
  movslq %esi,%rsi
L1:
  mov    %esi,%eax
  cmpw   $0x0,(%rdi,%rsi,2)
  jne    L4
  movw   $0xffff,(%rdi,%rsi,2)
  sub    $0x1,%rsi
  test   %esi,%esi
  jns    L1
  ret
L4:
  test   %esi,%esi
  js     L12
  cltq
  subw   $0x1,(%rdi,%rax,2)
L12:
  ret
```

assistant: ```c
void decrease_bitmap(unsigned short *buffer, int len) {
  int i = len - 1;
  for (; i >= 0; i--) {
    if (buffer[i] != 0)
      break;
    buffer[i] = ((unsigned short)-1);
  }
  if (i >= 0)
    buffer[i]--;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decrease_bitmap>:
  endbr64
  sub    $0x1,%esi
  js     L39
  movslq %esi,%rdx
  mov    %esi,%esi
  add    %rdx,%rdx
  add    %rsi,%rsi
  lea    -0x2(%rdi,%rdx,1),%rcx
  lea    (%rdi,%rdx,1),%rax
  sub    %rsi,%rcx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%edx
  sub    $0x2,%rax
  mov    %dx,0x2(%rax)
  cmp    %rcx,%rax
  je     L28
L30:
  movzwl (%rax),%edx
  test   %dx,%dx
  je     L27
  sub    $0x1,%edx
  mov    %dx,(%rax)
L39:
  ret
  nopl   0x0(%rax)
L28:
  ret
```

assistant: ```c
void decrease_bitmap(unsigned short *buffer, int len) {
  int i = len - 1;
  for (; i >= 0; i--) {
    if (buffer[i] != 0)
      break;
    buffer[i] = ((unsigned short)-1);
  }
  if (i >= 0)
    buffer[i]--;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decrease_bitmap>:
  endbr64
  sub    $0x1,%esi
  js     L28
  movslq %esi,%rdx
  mov    %esi,%esi
  add    %rdx,%rdx
  add    %rsi,%rsi
  lea    -0x2(%rdi,%rdx,1),%rcx
  lea    (%rdi,%rdx,1),%rax
  sub    %rsi,%rcx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%edx
  sub    $0x2,%rax
  mov    %dx,0x2(%rax)
  cmp    %rcx,%rax
  je     L20
L15:
  movzwl (%rax),%edx
  test   %dx,%dx
  je     L7
  sub    $0x1,%edx
  mov    %dx,(%rax)
L28:
  ret
  nopl   0x0(%rax)
L20:
  ret
```

assistant: ```c
void decrease_bitmap(unsigned short *buffer, int len) {
  int i = len - 1;
  for (; i >= 0; i--) {
    if (buffer[i] != 0)
      break;
    buffer[i] = ((unsigned short)-1);
  }
  if (i >= 0)
    buffer[i]--;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<randomizeArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L3:
  mov    $0x0,%eax
  call   <myrand@plt>
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%eax
  call   <myrand@plt>
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void randomizeArray(int numOfElements, int *array) {
  int i, p1, p2, temp;
  for (i = 0; i < numOfElements * numOfElements; i++) {
    p1 = myrand() % numOfElements;
    p2 = myrand() % numOfElements;
    temp = array[p1];
    array[p1] = array[p2];
    array[p2] = temp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<randomizeArray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  imul   %edi,%r13d
  test   %r13d,%r13d
  jle    L15
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    $0x0,%ebp
L17:
  mov    $0x0,%eax
  call   <myrand@plt>
  cltd
  idiv   %ebx
  mov    %edx,%r14d
  mov    $0x0,%eax
  call   <myrand@plt>
  movslq %r14d,%r14
  lea    (%r12,%r14,4),%rcx
  mov    (%rcx),%esi
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  add    $0x1,%ebp
  cmp    %r13d,%ebp
  jne    L17
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void randomizeArray(int numOfElements, int *array) {
  int i, p1, p2, temp;
  for (i = 0; i < numOfElements * numOfElements; i++) {
    p1 = myrand() % numOfElements;
    p2 = myrand() % numOfElements;
    temp = array[p1];
    array[p1] = array[p2];
    array[p2] = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<randomizeArray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  imul   %edi,%ebp
  push   %rbx
  test   %ebp,%ebp
  je     L13
  mov    %edi,%ebx
  mov    %rsi,%r14
  xor    %r13d,%r13d
  nopl   (%rax)
L3:
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <myrand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%r12
  call   <myrand@plt>
  lea    (%r14,%r12,4),%rcx
  cltd
  mov    (%rcx),%esi
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r14,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  cmp    %ebp,%r13d
  jne    L3
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void randomizeArray(int numOfElements, int *array) {
  int i, p1, p2, temp;
  for (i = 0; i < numOfElements * numOfElements; i++) {
    p1 = myrand() % numOfElements;
    p2 = myrand() % numOfElements;
    temp = array[p1];
    array[p1] = array[p2];
    array[p2] = temp;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<randomizeArray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  imul   %edi,%ebp
  push   %rbx
  test   %ebp,%ebp
  je     L16
  mov    %edi,%ebx
  mov    %rsi,%r14
  xor    %r13d,%r13d
  nopl   (%rax)
L15:
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <myrand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%r12
  call   <myrand@plt>
  lea    (%r14,%r12,4),%rcx
  cltd
  mov    (%rcx),%esi
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r14,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  cmp    %ebp,%r13d
  jne    L15
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void randomizeArray(int numOfElements, int *array) {
  int i, p1, p2, temp;
  for (i = 0; i < numOfElements * numOfElements; i++) {
    p1 = myrand() % numOfElements;
    p2 = myrand() % numOfElements;
    temp = array[p1];
    array[p1] = array[p2];
    array[p2] = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str$left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x1,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   1090 <str$analyze_sdesc@plt>
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  movzwl -0x28(%rbp),%eax
  movzwl %ax,%eax
  cmp    %rax,%rdx
  cmovle %rdx,%rax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    11d2 <str$left+0x79>
  movw   $0x0,-0x26(%rbp)
  movq   $0x248074,-0x18(%rbp)
  jmp    11d9 <str$left+0x80>
  mov    -0x24(%rbp),%eax
  mov    %ax,-0x26(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0x26(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   1070 <str$copy_r@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     1213 <str$left+0xba>
  call   <__stack_chk_fail@plt>
  leave
  ret
```

assistant: ```c
unsigned long str$left(struct dsc$descriptor_s *destination_string, const struct dsc$descriptor_s *source_string, const long *end_position) {
  char *s2_ptr;
  unsigned short s2_length;
  int final_length;
  unsigned short real_final_length;
  unsigned long result;
  unsigned long second_result = 1;
  str$analyze_sdesc(source_string, &s2_length, &s2_ptr);
  final_length = ((s2_length) < (*end_position) ? (s2_length) : (*end_position));
  if (final_length < 0) {
    real_final_length = 0;
    second_result = 2392180;
  } else {
    real_final_length = (unsigned short)final_length;
  }
  result = str$copy_r(destination_string, &real_final_length, s2_ptr);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str$left>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   1090 <str$analyze_sdesc@plt>
  movzwl 0xc(%rsp),%eax
  mov    0x0(%rbp),%rdx
  cmp    %rdx,%rax
  cmovg  %rdx,%rax
  test   %eax,%eax
  mov    $0x0,%edx
  cmovs  %rdx,%rax
  mov    %ax,0xe(%rsp)
  lea    0xe(%rsp),%rsi
  mov    0x10(%rsp),%rdx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   1070 <str$copy_r@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    11db <str$left+0x82>
  cltq
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long str$left(struct dsc$descriptor_s *destination_string, const struct dsc$descriptor_s *source_string, const long *end_position) {
  char *s2_ptr;
  unsigned short s2_length;
  int final_length;
  unsigned short real_final_length;
  unsigned long result;
  unsigned long second_result = 1;
  str$analyze_sdesc(source_string, &s2_length, &s2_ptr);
  final_length = ((s2_length) < (*end_position) ? (s2_length) : (*end_position));
  if (final_length < 0) {
    real_final_length = 0;
    second_result = 2392180;
  } else {
    real_final_length = (unsigned short)final_length;
  }
  result = str$copy_r(destination_string, &real_final_length, s2_ptr);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str$left>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   1090 <str$analyze_sdesc@plt>
  mov    (%rbx),%rdx
  movzwl 0xc(%rsp),%eax
  mov    %rbp,%rdi
  lea    0xe(%rsp),%rsi
  cmp    %rdx,%rax
  cmovg  %rdx,%rax
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %rdx,%rax
  mov    0x10(%rsp),%rdx
  mov    %ax,0xe(%rsp)
  xor    %eax,%eax
  call   1070 <str$copy_r@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    11db <str$left+0x7b>
  add    $0x28,%rsp
  cltq
  pop    %rbx
  pop    %rbp
  ret
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long str$left(struct dsc$descriptor_s *destination_string, const struct dsc$descriptor_s *source_string, const long *end_position) {
  char *s2_ptr;
  unsigned short s2_length;
  int final_length;
  unsigned short real_final_length;
  unsigned long result;
  unsigned long second_result = 1;
  str$analyze_sdesc(source_string, &s2_length, &s2_ptr);
  final_length = ((s2_length) < (*end_position) ? (s2_length) : (*end_position));
  if (final_length < 0) {
    real_final_length = 0;
    second_result = 2392180;
  } else {
    real_final_length = (unsigned short)final_length;
  }
  result = str$copy_r(destination_string, &real_final_length, s2_ptr);
  return result;
}
```